diff --git "a/languages/cpp/test_in_distribution.jsonl" "b/languages/cpp/test_in_distribution.jsonl"
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@@ -0,0 +1,1000 @@
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s303282397", "group_id": "codeNet:p00005", "input_text": "#include<iostream>\n\nusing namespace std;\n\nint main() {\n\tlong long int a, b, c, d, m, i;\n\twhile (cin >> a >> b) {\n\t\tfor (i = 0;i < b;i++) {\n\t\t\tfor (m = 0;m < a;m++) {\n\t\t\t\tif (a*(i + 1) == b*(m + 1)) {\n\t\t\t\t\tc = a*(i + 1);\n\t\t\t\t\ti = -1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (i == -1) { break; }\n\t\t}\n\t\tif(a > b){\n\t\t\tfor (i = a;i > 0;i--) {\n\t\t\t\tif (a%i == 0 && b%i == 0) { break; }\n\t\t\t}\n\t\t}else{\n\t\t\tfor (i = b;i > 0;i--) {\n\t\t\t\tif (b%i == 0 && a%i == 0) { break; }\n\t\t\t}\n\t\t}\n\t\td = i;\n\t\tcout << d << ' ' << c << endl;\n\t} \n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1443893411, "filename_ext": "cpp", "original_language": "C++", "problem_description_relpath": "problem_descriptions/p00005.html", "problem_id": "p00005", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p00005/input.txt", "sample_output_relpath": "derived/input_output/data/p00005/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p00005/C++/s303282397.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s303282397", "user_id": "u256874901"}, "prompt_components": {"gold_output": "2 24\n10000000 150000000\n", "input_to_evaluate": "#include<iostream>\n\nusing namespace std;\n\nint main() {\n\tlong long int a, b, c, d, m, i;\n\twhile (cin >> a >> b) {\n\t\tfor (i = 0;i < b;i++) {\n\t\t\tfor (m = 0;m < a;m++) {\n\t\t\t\tif (a*(i + 1) == b*(m + 1)) {\n\t\t\t\t\tc = a*(i + 1);\n\t\t\t\t\ti = -1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (i == -1) { break; }\n\t\t}\n\t\tif(a > b){\n\t\t\tfor (i = a;i > 0;i--) {\n\t\t\t\tif (a%i == 0 && b%i == 0) { break; }\n\t\t\t}\n\t\t}else{\n\t\t\tfor (i = b;i > 0;i--) {\n\t\t\t\tif (b%i == 0 && a%i == 0) { break; }\n\t\t\t}\n\t\t}\n\t\td = i;\n\t\tcout << d << ' ' << c << endl;\n\t} \n\treturn 0;\n}", "problem_context": "GCD and LCM\n\nWrite a program which computes the greatest common divisor (GCD) and the least common multiple (LCM) of given a and b.\n\nInput\n\nInput consists of several data sets. Each data set contains a and b separated by a single space in a line. The input terminates with EOF.\n\nConstraints\n\n0 < a, b ≤ 2,000,000,000\n\nLCM(a, b) ≤ 2,000,000,000\n\nThe number of data sets ≤ 50\n\nOutput\n\nFor each data set, print GCD and LCM separated by a single space in a line.\n\nSample Input\n\n8 6\n50000000 30000000\n\nOutput for the Sample Input\n\n2 24\n10000000 150000000", "sample_input": "8 6\n50000000 30000000\n"}, "reference_outputs": ["2 24\n10000000 150000000\n"], "source_document_id": "p00005", "source_text": "GCD and LCM\n\nWrite a program which computes the greatest common divisor (GCD) and the least common multiple (LCM) of given a and b.\n\nInput\n\nInput consists of several data sets. Each data set contains a and b separated by a single space in a line. The input terminates with EOF.\n\nConstraints\n\n0 < a, b ≤ 2,000,000,000\n\nLCM(a, b) ≤ 2,000,000,000\n\nThe number of data sets ≤ 50\n\nOutput\n\nFor each data set, print GCD and LCM separated by a single space in a line.\n\nSample Input\n\n8 6\n50000000 30000000\n\nOutput for the Sample Input\n\n2 24\n10000000 150000000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 517, "cpu_time_ms": 5920, "memory_kb": 1156}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s368442390", "group_id": "codeNet:p00200", "input_text": "#include<iostream>\n#include<queue>\n#include<vector>\n#include<map>\nusing namespace std;\ntypedef pair<int,int> P;\ntypedef struct{\n\tint next;\n\tint cost[2];\n}edge;\n\nint n,m;\nvector<edge> mapp[111];\nint bfs(int now,int goal,int k);\n\nint main(){\n\twhile(1){\n\t\tcin >> n >> m;\n\t\tif(n == 0 && m == 0) break;\n\t\tfor(int i=0;i<m+1;i++){\n\t\t\tmapp[i].clear();\n\t\t}\n\t\tfor(int i=0;i<n;i++){\n\t\t\tint a,b,cost,tim;\n\t\t\tcin >> a >> b >> cost >> tim;\n\t\t\tedge x;\n\t\t\tx.next = a; x.cost[0] = cost; x.cost[1] = tim;\n\t\t\tmapp[b].push_back(x);\n\t\t\tx.next = b; x.cost[0] = cost; x.cost[1] = tim;\n\t\t\tmapp[a].push_back(x);\n\t\t}\n\t\tint k;\n\t\tcin >> k;\n\t\tint ans;\n\t\tfor(int i=0;i<k;i++){\n\t\t\tint p,q,r;\n\t\t\tcin >> p >> q >> r;\n\t\t\tif(r == 0) ans = bfs(p,q,r);\n\t\t\telse if(r == 1) ans = bfs(p,q,r);\n\t\t\tcout << ans << endl;\n\t\t}\n\t}\n}\n\nint bfs(int now,int goal,int k){\n\tvector<int> min_cost;\n\tmin_cost.resize(m+1,-1);\n\tpriority_queue<P, vector<P>,greater<P> > que;\n\tque.push(P(0,now));\n\tmin_cost[now] = 0;\n\twhile(!que.empty()){\n\t\tP p = que.top(); que.pop();\n\t\tint no = p.second;\n\t\tint co = p.first;\n\t\tif(no == goal) return co;\n\t\tif(co > min_cost[no]) continue;\n\t\tint len=mapp[no].size();\n\t\tfor(int i=0;i<len;i++){\n\t\t\tedge x = mapp[no][i];\n\t\t\tif(min_cost[x.next] == -1 || co+x.cost[k]<min_cost[x.next]){\n\t\t\t\tmin_cost[x.next] = co + x.cost[k];\n\t\t\t\tque.push(P(co+x.cost[k],x.next));\n\t\t\t}\n\t\t}\n\t}\n\treturn min_cost[goal];\n}", "language": "C++", "metadata": {"date": 1436539398, "filename_ext": "cpp", "original_language": "C++", "problem_description_relpath": "problem_descriptions/p00200.html", "problem_id": "p00200", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p00200/input.txt", "sample_output_relpath": "derived/input_output/data/p00200/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p00200/C++/s368442390.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s368442390", "user_id": "u645134403"}, "prompt_components": {"gold_output": "450\n35\n", "input_to_evaluate": "#include<iostream>\n#include<queue>\n#include<vector>\n#include<map>\nusing namespace std;\ntypedef pair<int,int> P;\ntypedef struct{\n\tint next;\n\tint cost[2];\n}edge;\n\nint n,m;\nvector<edge> mapp[111];\nint bfs(int now,int goal,int k);\n\nint main(){\n\twhile(1){\n\t\tcin >> n >> m;\n\t\tif(n == 0 && m == 0) break;\n\t\tfor(int i=0;i<m+1;i++){\n\t\t\tmapp[i].clear();\n\t\t}\n\t\tfor(int i=0;i<n;i++){\n\t\t\tint a,b,cost,tim;\n\t\t\tcin >> a >> b >> cost >> tim;\n\t\t\tedge x;\n\t\t\tx.next = a; x.cost[0] = cost; x.cost[1] = tim;\n\t\t\tmapp[b].push_back(x);\n\t\t\tx.next = b; x.cost[0] = cost; x.cost[1] = tim;\n\t\t\tmapp[a].push_back(x);\n\t\t}\n\t\tint k;\n\t\tcin >> k;\n\t\tint ans;\n\t\tfor(int i=0;i<k;i++){\n\t\t\tint p,q,r;\n\t\t\tcin >> p >> q >> r;\n\t\t\tif(r == 0) ans = bfs(p,q,r);\n\t\t\telse if(r == 1) ans = bfs(p,q,r);\n\t\t\tcout << ans << endl;\n\t\t}\n\t}\n}\n\nint bfs(int now,int goal,int k){\n\tvector<int> min_cost;\n\tmin_cost.resize(m+1,-1);\n\tpriority_queue<P, vector<P>,greater<P> > que;\n\tque.push(P(0,now));\n\tmin_cost[now] = 0;\n\twhile(!que.empty()){\n\t\tP p = que.top(); que.pop();\n\t\tint no = p.second;\n\t\tint co = p.first;\n\t\tif(no == goal) return co;\n\t\tif(co > min_cost[no]) continue;\n\t\tint len=mapp[no].size();\n\t\tfor(int i=0;i<len;i++){\n\t\t\tedge x = mapp[no][i];\n\t\t\tif(min_cost[x.next] == -1 || co+x.cost[k]<min_cost[x.next]){\n\t\t\t\tmin_cost[x.next] = co + x.cost[k];\n\t\t\t\tque.push(P(co+x.cost[k],x.next));\n\t\t\t}\n\t\t}\n\t}\n\treturn min_cost[goal];\n}", "problem_context": "青春の片道切符\n\n太郎君は夏休みに電車で長旅をする計画を立てています。しかし高校生の身である太郎君が一ヵ月しかない夏休みで可能な限り遠くに旅をするには、出来るだけ安い行き方と出来るだけ早い行き方をそれぞれ見つけなければうまく計画が立てられません。太郎君が素敵な旅を満喫できるように、太郎君の計画の助けになるプログラムを作ってあげましょう。\n\n線路の情報、駅の数を入力とし、問い合わせに応じて、最小金額または最短時間を出力するプログラムを作成してください。\n\nInput\n\n複数のデータセットの並びが入力として与えられます。入力の終わりはゼロふたつの行で示されます。各データセットは以下の形式で与えられます。\n\nn m\na1 b1 cost1 time1\na2 b2 cost2 time2\n:\nan bn costn timen\nk\np1 q1 r1\np2 q2 r2\n:\npk qk rk\n\n1 行目に線路の情報の数 n (1 ≤ n ≤ 3000)と駅の数 m (1 ≤ m ≤ 100) が与えられます。\n\n続く n 行に i 番目の路線の情報が与えられます。各路線の情報として、路線がつなぐ２つの駅の番号 ai, bi (1 ≤ ai, bi ≤ m)、料金 costi (1 ≤ costi ≤ 1000)、移動時間 timei (1 ≤ timei ≤ 1000) が与えられます。ただし、各駅は 1 から m まで順番に番号が付けられているものとします。\nなお、ai と bi が線路でつながっていれば、ai から bi、 bi からai の両方の移動が同じ料金と時間で可能とします。\n\n続く行に問い合わせの数 k (1 ≤ k ≤ 200) が与えられます。続く k 行に i 番目の問い合わせが与えられます。各問合わせとして、出発駅 pi 、到着駅 qi 、出力する値の種類 ri (0 または 1)が与えられます。なお、問い合わせには必ず経路があるものとします。\n\nデータセットの数は 50 を超えない。\n\nOutput\n\nデータセットごとに、最小金額もしくは最短時間を１行に出力します。ri が 0 の時は最小金額を、 1 の時は最短時間を出力します。\n\nSample Input\n\n6 5\n1 2 200 10\n1 4 400 15\n1 3 250 25\n2 4 100 10\n4 5 150 20\n3 5 300 20\n2\n1 5 0\n1 5 1\n0 0\n\nOutput for the Sample Input\n\n450\n35", "sample_input": "6 5\n1 2 200 10\n1 4 400 15\n1 3 250 25\n2 4 100 10\n4 5 150 20\n3 5 300 20\n2\n1 5 0\n1 5 1\n0 0\n"}, "reference_outputs": ["450\n35\n"], "source_document_id": "p00200", "source_text": "青春の片道切符\n\n太郎君は夏休みに電車で長旅をする計画を立てています。しかし高校生の身である太郎君が一ヵ月しかない夏休みで可能な限り遠くに旅をするには、出来るだけ安い行き方と出来るだけ早い行き方をそれぞれ見つけなければうまく計画が立てられません。太郎君が素敵な旅を満喫できるように、太郎君の計画の助けになるプログラムを作ってあげましょう。\n\n線路の情報、駅の数を入力とし、問い合わせに応じて、最小金額または最短時間を出力するプログラムを作成してください。\n\nInput\n\n複数のデータセットの並びが入力として与えられます。入力の終わりはゼロふたつの行で示されます。各データセットは以下の形式で与えられます。\n\nn m\na1 b1 cost1 time1\na2 b2 cost2 time2\n:\nan bn costn timen\nk\np1 q1 r1\np2 q2 r2\n:\npk qk rk\n\n1 行目に線路の情報の数 n (1 ≤ n ≤ 3000)と駅の数 m (1 ≤ m ≤ 100) が与えられます。\n\n続く n 行に i 番目の路線の情報が与えられます。各路線の情報として、路線がつなぐ２つの駅の番号 ai, bi (1 ≤ ai, bi ≤ m)、料金 costi (1 ≤ costi ≤ 1000)、移動時間 timei (1 ≤ timei ≤ 1000) が与えられます。ただし、各駅は 1 から m まで順番に番号が付けられているものとします。\nなお、ai と bi が線路でつながっていれば、ai から bi、 bi からai の両方の移動が同じ料金と時間で可能とします。\n\n続く行に問い合わせの数 k (1 ≤ k ≤ 200) が与えられます。続く k 行に i 番目の問い合わせが与えられます。各問合わせとして、出発駅 pi 、到着駅 qi 、出力する値の種類 ri (0 または 1)が与えられます。なお、問い合わせには必ず経路があるものとします。\n\nデータセットの数は 50 を超えない。\n\nOutput\n\nデータセットごとに、最小金額もしくは最短時間を１行に出力します。ri が 0 の時は最小金額を、 1 の時は最短時間を出力します。\n\nSample Input\n\n6 5\n1 2 200 10\n1 4 400 15\n1 3 250 25\n2 4 100 10\n4 5 150 20\n3 5 300 20\n2\n1 5 0\n1 5 1\n0 0\n\nOutput for the Sample Input\n\n450\n35", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1368, "cpu_time_ms": 100, "memory_kb": 1308}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s049135579", "group_id": "codeNet:p00274", "input_text": "# define _CRT_SECUREj_NO_WARNINGS 1\n# define _USE_MATH_DEFINES\n# include <iostream>\n# include <numeric>\n# include <string>\n# include <bitset>\n# include <vector>\n# include <algorithm>\n# include <cstdlib>\n# include <cstdio>\n# include <cstring>\n# include <cstdlib>\n# include <iomanip>\n# include <queue>\n# include <sstream>\n# include <climits>\n# include <cmath>\n# include <list>\n# include <functional>\n# include <string>\n# include <ctime>\n# include <set>\n# include <forward_list>\n# include <map>\n# include <stack>\nusing namespace std;\n# define INF ((int)(1<<25))\n# define REP(i,n) for(int i=0;i<(int)n;i++)\n# define FOR(i,n) REP(i,n)\n# define TORAD 2.0*M_PI/360.0\n# define INT(x) int x;cin>>x;\n# define ALL(x) (x).begin(),(x).end()\n# define RALL(x) (x).rbegin(),(x).rend()\n# define DEBUG(x) cout<<#x<<\" :\"<<x<<endl;\n# define EPS 1e-12\ntemplate<class T> void debug(T a) { for (auto iiiiiiiiii : a)cout << iiiiiiiiii << endl; }\ntypedef vector<int> vi;\ntypedef vector<string> vs;\ntypedef pair<int, int> pii;\ntypedef pair<int, pii> piii;\nint dx[4] = { 0,1,0,-1 }, dy[4] = { -1,0,1,0 };\n\nsigned main()\n{\n\tint n;\n\twhile (cin >> n&&n)\n\t{\n\t\tint ans = 0;\n\t\tbool ok = false;\n\t\tFOR(i, n)\n\t\t{\n\t\t\tINT(x);\n\t\t\tif (x > 1)ok = true;\n\t\t\tif(x)ans++;\n\t\t}\n\t\tif (ok)cout << ans+1 << endl;\n\t\telse cout << \"NA\" << endl;\n\t}\n}", "language": "C++", "metadata": {"date": 1470894371, "filename_ext": "cpp", "original_language": "C++14", "problem_description_relpath": "problem_descriptions/p00274.html", "problem_id": "p00274", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p00274/input.txt", "sample_output_relpath": "derived/input_output/data/p00274/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p00274/C++/s049135579.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s049135579", "user_id": "u195954908"}, "prompt_components": {"gold_output": "3\nNA\n2\n", "input_to_evaluate": "# define _CRT_SECUREj_NO_WARNINGS 1\n# define _USE_MATH_DEFINES\n# include <iostream>\n# include <numeric>\n# include <string>\n# include <bitset>\n# include <vector>\n# include <algorithm>\n# include <cstdlib>\n# include <cstdio>\n# include <cstring>\n# include <cstdlib>\n# include <iomanip>\n# include <queue>\n# include <sstream>\n# include <climits>\n# include <cmath>\n# include <list>\n# include <functional>\n# include <string>\n# include <ctime>\n# include <set>\n# include <forward_list>\n# include <map>\n# include <stack>\nusing namespace std;\n# define INF ((int)(1<<25))\n# define REP(i,n) for(int i=0;i<(int)n;i++)\n# define FOR(i,n) REP(i,n)\n# define TORAD 2.0*M_PI/360.0\n# define INT(x) int x;cin>>x;\n# define ALL(x) (x).begin(),(x).end()\n# define RALL(x) (x).rbegin(),(x).rend()\n# define DEBUG(x) cout<<#x<<\" :\"<<x<<endl;\n# define EPS 1e-12\ntemplate<class T> void debug(T a) { for (auto iiiiiiiiii : a)cout << iiiiiiiiii << endl; }\ntypedef vector<int> vi;\ntypedef vector<string> vs;\ntypedef pair<int, int> pii;\ntypedef pair<int, pii> piii;\nint dx[4] = { 0,1,0,-1 }, dy[4] = { -1,0,1,0 };\n\nsigned main()\n{\n\tint n;\n\twhile (cin >> n&&n)\n\t{\n\t\tint ans = 0;\n\t\tbool ok = false;\n\t\tFOR(i, n)\n\t\t{\n\t\t\tINT(x);\n\t\t\tif (x > 1)ok = true;\n\t\t\tif(x)ans++;\n\t\t}\n\t\tif (ok)cout << ans+1 << endl;\n\t\telse cout << \"NA\" << endl;\n\t}\n}", "problem_context": "おそろいの景品\n\nジョウ君とヤエさんは仲の良いカップルです。ジョウ君はカプセル玩具自販機(ガチャポン)の景品を集めており、二人で出かけたときも、ガチャポンを見つけると何度かやってみるほどの熱の入りようです。ヤエさんは楽しそうなジョウ君をそばで見ているだけでしたが、ジョウ君の今度の誕生日プレゼントにガチャポンの景品をひとつあげることにしました。ヤエさんはガチャポン自体にはあまり興味がわきませんでしたが、できればジョウ君とおそろいの景品が欲しいと思っています。\n\nヤエさんがやってみようと思うガチャポンは、１回のチャレンジで景品がひとつ出ます。品切れのものも含め景品が何種類あるのかと、それぞれの景品がいくつ残っているのかはわかります。しかし、1回のチャレンジでどの景品が出るかはわかりません。そこで、景品が出る順番にかかわらず、ヤエさんが同じ景品を必ず２つ得るために最低限必要なチャレンジの回数を出力するプログラムを作成してください。\n\n入力\n\n入力は複数のデータセットからなる。入力の終わりはゼロ1つの行で示される。各データセットは以下の形式で与えられる。\n\nN\nk1 k2 ... kN\n\n各データセットは2行であり、1行目に景品が何種類あるかを表す整数N(1 ≤ N ≤ 10000)が与えられる。続く1行に各景品がいくつ残っているのかを表す整数ki(0 ≤ ki ≤ 10000)が与えられる。\n\nデータセットの数は100を超えない。\n\n出力\n\nデータセットごとに、同じ景品を必ず２つ得るために最低限必要なチャレンジの回数を出力する。ただし、不可能な場合はNAと出力する。\n\n入力例\n\n2\n3 2\n3\n0 1 1\n1\n1000\n0\n\n出力例\n\n3\nNA\n2\n\n１つ目のデータセットでは、運良く１種類目か２種類目の景品が連続で出て２回で済む可能性はあるが、同じ種類の景品を必ず２つ得るためには３回チャレンジする必要がある。\n\n２つ目のデータセットでは、２つ以上残っている景品がもともと無いので不可能である。\n\n３つ目のデータセットでは、景品は１種類だけなので２回のチャレンジでその景品が必ず２つ得られる。", "sample_input": "2\n3 2\n3\n0 1 1\n1\n1000\n0\n"}, "reference_outputs": ["3\nNA\n2\n"], "source_document_id": "p00274", "source_text": "おそろいの景品\n\nジョウ君とヤエさんは仲の良いカップルです。ジョウ君はカプセル玩具自販機(ガチャポン)の景品を集めており、二人で出かけたときも、ガチャポンを見つけると何度かやってみるほどの熱の入りようです。ヤエさんは楽しそうなジョウ君をそばで見ているだけでしたが、ジョウ君の今度の誕生日プレゼントにガチャポンの景品をひとつあげることにしました。ヤエさんはガチャポン自体にはあまり興味がわきませんでしたが、できればジョウ君とおそろいの景品が欲しいと思っています。\n\nヤエさんがやってみようと思うガチャポンは、１回のチャレンジで景品がひとつ出ます。品切れのものも含め景品が何種類ある���かと、それぞれの景品がいくつ残っているのかはわかります。しかし、1回のチャレンジでどの景品が出るかはわかりません。そこで、景品が出る順番にかかわらず、ヤエさんが同じ景品を必ず２つ得るために最低限必要なチャレンジの回数を出力するプログラムを作成してください。\n\n入力\n\n入力は複数のデータセットからなる。入力の終わりはゼロ1つの行で示される。各データセットは以下の形式で与えられる。\n\nN\nk1 k2 ... kN\n\n各データセットは2行であり、1行目に景品が何種類あるかを表す整数N(1 ≤ N ≤ 10000)が与えられる。続く1行に各景品がいくつ残っているのかを表す整数ki(0 ≤ ki ≤ 10000)が与えられる。\n\nデータセットの数は100を超えない。\n\n出力\n\nデータセットごとに、同じ景品を必ず２つ得るために最低限必要なチャレンジの回数を出力する。ただし、不可能な場合はNAと出力する。\n\n入力例\n\n2\n3 2\n3\n0 1 1\n1\n1000\n0\n\n出力例\n\n3\nNA\n2\n\n１つ目のデータセットでは、運良く１種類目か２種類目の景品が連続で出て２回で済む可能性はあるが、同じ種類の景品を必ず２つ得るためには３回チャレンジする必要がある。\n\n２つ目のデータセットでは、２つ以上残っている景品がもともと無いので不可能である。\n\n３つ目のデータセットでは、景品は１種類だけなので２回のチャレンジでその景品が必ず２つ得られる。", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1296, "cpu_time_ms": 90, "memory_kb": 3124}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s781465824", "group_id": "codeNet:p00438", "input_text": "#include<cstdio>\n#include<cstring>\nint  hyou[16][16],A,B;\n\nint solve(int a,int b){\n\tif(hyou[a][b]==-1) return 0;\n\tif(a==0 || b==0) return 1;\n\treturn solve(a-1,b)+solve(a,b-1);\n}\nint main(){\n\tint n,a,b;\n\tscanf(\"%d%d\",&A,&B);\n\tif(A==0&&B==0)\treturn 0;\n\tmemset(hyou,0,sizeof(hyou));\n\tscanf(\"%d\",&n);\n\twhile(n--){\n\t\tscanf(\"%d%d\",&a,&b);\n\t\thyou[a-1][b-1]=-1;\n\t}\n\tprintf(\"%d\\n\",solve(A-1,B-1));\n\tmain();\n}", "language": "C++", "metadata": {"date": 1304931322, "filename_ext": "cpp", "original_language": "C++", "problem_description_relpath": "problem_descriptions/p00438.html", "problem_id": "p00438", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p00438/input.txt", "sample_output_relpath": "derived/input_output/data/p00438/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p00438/C++/s781465824.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s781465824", "user_id": "u611853667"}, "prompt_components": {"gold_output": "5\n5\n", "input_to_evaluate": "#include<cstdio>\n#include<cstring>\nint  hyou[16][16],A,B;\n\nint solve(int a,int b){\n\tif(hyou[a][b]==-1) return 0;\n\tif(a==0 || b==0) return 1;\n\treturn solve(a-1,b)+solve(a,b-1);\n}\nint main(){\n\tint n,a,b;\n\tscanf(\"%d%d\",&A,&B);\n\tif(A==0&&B==0)\treturn 0;\n\tmemset(hyou,0,sizeof(hyou));\n\tscanf(\"%d\",&n);\n\twhile(n--){\n\t\tscanf(\"%d%d\",&a,&b);\n\t\thyou[a-1][b-1]=-1;\n\t}\n\tprintf(\"%d\\n\",solve(A-1,B-1));\n\tmain();\n}", "problem_context": "通学経路\n\n問題\n\n太郎君の住んでいるJOI市は，南北方向にまっすぐに伸びる a 本の道路と，東西方向にまっすぐに伸びる b 本の道路により，碁盤の目の形に区分けされている．\n\n南北方向の a 本の道路には，西から順に 1, 2, ... , a の番号が付けられている．また，東西方向の b 本の道路には，南から順に 1, 2, ... , b の番号が付けられている．西から i 番目の南北方向の道路と，南から j 番目の東西方向の道路が交わる交差点を (i, j) で表す．\n\n太郎君は，交差点 (1, 1) の近くに住んでおり，交差点 (a, b) の近くのJOI高校に自転車で通っている．自転車は道路に沿ってのみ移動することができる．太郎君は，通学時間を短くするため，東または北にのみ向かって移動して通学している．\n\n現在， JOI市では， n 個の交差点 (x1, y1), (x2, y2), ... , (xn, yn) で工事を行っている．太郎君は工事中の交差点を通ることができない．\n\n太郎君が交差点 (1, 1) から交差点 (a, b) まで，工事中の交差点を避けながら，東または北にのみ向かっ���移動して通学する方法は何通りあるだろうか．太郎君の通学経路の個数 m を求めるプログラムを作成せよ．\n\n入力\n\n入力は複数のデータセットからなる．各データセットは以下の形式で与えられる．入力はゼロを２つ含む行で終了する．\n\n1行目には，空白を区切りとして2個の整数 a, b が書かれている．これは，南北方向の道路の本数と，東西方向の道路の本数を表す． a, b は 1 ≤ a, b ≤ 16 をみたす．\n\n2行目には, 工事中の交差点の個数を表す整数 n が書かれている． n は 1 ≤ n ≤ 40 をみたす．\n\n続く n 行 (3行目から n+2 行目) には，工事中の交差点の位置が書かれている． i+2 行目には空白で区切られた整数 xi, yi が書かれており，交差点 (xi, yi) が工事中であることを表す． xi, yi は 1 ≤ xi, yi ≤ 16 をみたす．\n\nデータセットの数は 5 を超えない．\n\n出力\n\nデータセットごとに, 太郎君の通学経路の個数 m を1行に出力する．\n\n入出力例\n\n入力例\n\n5 4\n3\n2 2\n2 3\n4 2\n5 4\n3\n2 2\n2 3\n4 2\n0 0\n\n出力例\n\n5\n5\n\n下図は a=5, b=4, n=3 で，工事中の交差点が (2,2), (2,3), (4,2) の場合を表している．\n\nこの場合，通学経路は m=5 通りある． 5通りの通学経路を全て図示すると，以下の通り．\n\n上記問題文と自動審判に使われるデータは、情報オリンピック日本委員会が作成し公開している問題文と採点用テストデータです。", "sample_input": "5 4\n3\n2 2\n2 3\n4 2\n5 4\n3\n2 2\n2 3\n4 2\n0 0\n"}, "reference_outputs": ["5\n5\n"], "source_document_id": "p00438", "source_text": "通学経路\n\n問題\n\n太郎君の住んでいるJOI市は，南北方向にまっすぐに伸びる a 本の道路と，東西方向にまっすぐに伸びる b 本の道路により，碁盤の目の形に区分けされている．\n\n南北方向の a 本の道路には，西から順に 1, 2, ... , a の番号が付けられている．また，東西方向の b 本の道路には，南から順に 1, 2, ... , b の番号が付けられている．西から i 番目の南北方向の道路と，南から j 番目の東西方向の道路が交わる交差点を (i, j) で表す．\n\n太郎君は，交差点 (1, 1) の近くに住んでおり，交差点 (a, b) の近くのJOI高校に自転車で通っている．自転車は道路に沿ってのみ移動することができる．太郎君は，通学時間を短くするため，東または北にのみ向かって移動して通学している．\n\n現在， JOI市では， n 個の交差点 (x1, y1), (x2, y2), ... , (xn, yn) で工事を行っている．太郎君は工事中の交差点を通ることができない．\n\n太郎君が交差点 (1, 1) から交差点 (a, b) まで，工事中の交差点を避けながら，東または北にのみ向かって移動して通学する方法は何通りあるだろうか．太郎君の通学経路の個数 m を求めるプログラムを作成せよ．\n\n入力\n\n入力は複数のデータセットからなる．各データセットは以下の形式で与えられる．入力はゼロを２つ含む行で終了する．\n\n1行目には，空白を区切りとして2個の整数 a, b が書かれている．これは，南北方向の道路の本数と，東西方向の道路の本数を表す． a, b は 1 ≤ a, b ≤ 16 をみたす．\n\n2行目には, 工事中の交差点の個数を表す整数 n が書かれている． n は 1 ≤ n ≤ 40 をみたす．\n\n続く n 行 (3行目から n+2 行目) には，工事中の交差点の位置が書かれている． i+2 行目には空白で区切られた整数 xi, yi が書かれており，交差点 (xi, yi) が工事中であることを表す． xi, yi は 1 ≤ xi, yi ≤ 16 をみたす．\n\nデータセットの数は 5 を超えない．\n\n出力\n\nデータセットごとに, 太郎君の通学経路の個数 m を1行に出力する．\n\n入出力例\n\n入力例\n\n5 4\n3\n2 2\n2 3\n4 2\n5 4\n3\n2 2\n2 3\n4 2\n0 0\n\n出力例\n\n5\n5\n\n下図は a=5, b=4, n=3 で，工事中の交差点が (2,2), (2,3), (4,2) の場合を表している．\n\nこの場合，通学経路は m=5 通りある． 5通りの通学経路を全て図示すると，以下の通り．\n\n上記問題文と自動審判に使われるデータは、情報オリンピック日本委員会が作成し公開している問題文と採点用テストデータです。", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 399, "cpu_time_ms": 20, "memory_kb": 756}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s640004265", "group_id": "codeNet:p00447", "input_text": "#include <iostream>\n#include <iomanip>\n#include <string>\n#include <vector>\n#include <array>\n#include <queue>\n#include <algorithm>\n#include <utility>\n#include <cmath>\n#include <map>\n\n#define INF_LL 9000000000000000000\n#define INF 2000000000\n\n#define REP(i, n) for(int i = 0;i < (n);i++)\n#define FOR(i, a, b) for(int i = (a);i < (b);i++)\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair<int, int> PII;\n\nclass Union_find{\nprivate:\n\tvector<int> par;\n\tvector<int> rank;\n\tint n;\n\npublic:\n\tUnion_find(int a){\n\t\tn = a;\n\t\tfor(int i = 0;i < n;i++){\n\t\t\tpar.push_back(i);\n\t\t\trank.push_back(0);\n\t\t}\n\t}\n\n\tint find(int x){\n\t\tif(par[x] == x){\n\t\t\treturn x;\n\t\t}else{\n\t\t\treturn par[x] = find(par[x]);\n\t\t}\n\t}\n\n\tvoid unite(int x, int y){\n\t\tx = find(x);\n\t\ty = find(y);\n\t\tif(x == y) return;\n\n\t\tif(rank[x] < rank[y]){\n\t\t\tpar[x] = y;\n\t\t}else{\n\t\t\tpar[y] = x;\n\t\t\tif(rank[x] == rank[y]) rank[x]++;\n\t\t}\n\t}\n\n\tbool same(int x, int y){\n\t\treturn find(x) == find(y);\n\t}\n};\n\nstruct edge{int to, cost; };\n\nint main(void){\n\tint m;\n\twhile(cin >> m && m){\n\tint tx[200], ty[200];\n\tint n;\n\tmap<int, vector<int> > S;\n\tREP(i, m){\n\t\tcin >> tx[i] >> ty[i];\n\t}\n\tcin >> n;\n\tREP(i, n){\n\t\tint x, y;\n\t\tcin >> x >> y;\n\t\tS[x].push_back(y);\n\t}\n\tREP(i, 1000000){\n\t\tREP(j, S[i].size()){\n\t\t\tbool flag;\n\t\t\tint diff_x, diff_y;\n\t\t\tdiff_x = i-tx[0];\n\t\t\tdiff_y = S[i][j]-ty[0];\n\t\t\tFOR(k, 1, m){\n\t\t\t\tflag = false;\n\t\t\t\tREP(l, S[tx[k]+diff_x].size()){\n\t\t\t\t\tif(S[tx[k]+diff_x][l] == ty[k]+diff_y){\n\t\t\t\t\t\tflag = true;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(!flag){\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(flag){\n\t\t\t\tcout << diff_x << \" \" << diff_y << endl;\n\t\t\t\tj = S[i].size();\n\t\t\t\ti = 1000000;\n\t\t\t}\n\t\t}\n\t}\n\t}\n\n}", "language": "C++", "metadata": {"date": 1480342496, "filename_ext": "cpp", "original_language": "C++11", "problem_description_relpath": "problem_descriptions/p00447.html", "problem_id": "p00447", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p00447/input.txt", "sample_output_relpath": "derived/input_output/data/p00447/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p00447/C++/s640004265.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s640004265", "user_id": "u379956761"}, "prompt_components": {"gold_output": "2 -3\n-384281 179674\n", "input_to_evaluate": "#include <iostream>\n#include <iomanip>\n#include <string>\n#include <vector>\n#include <array>\n#include <queue>\n#include <algorithm>\n#include <utility>\n#include <cmath>\n#include <map>\n\n#define INF_LL 9000000000000000000\n#define INF 2000000000\n\n#define REP(i, n) for(int i = 0;i < (n);i++)\n#define FOR(i, a, b) for(int i = (a);i < (b);i++)\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair<int, int> PII;\n\nclass Union_find{\nprivate:\n\tvector<int> par;\n\tvector<int> rank;\n\tint n;\n\npublic:\n\tUnion_find(int a){\n\t\tn = a;\n\t\tfor(int i = 0;i < n;i++){\n\t\t\tpar.push_back(i);\n\t\t\trank.push_back(0);\n\t\t}\n\t}\n\n\tint find(int x){\n\t\tif(par[x] == x){\n\t\t\treturn x;\n\t\t}else{\n\t\t\treturn par[x] = find(par[x]);\n\t\t}\n\t}\n\n\tvoid unite(int x, int y){\n\t\tx = find(x);\n\t\ty = find(y);\n\t\tif(x == y) return;\n\n\t\tif(rank[x] < rank[y]){\n\t\t\tpar[x] = y;\n\t\t}else{\n\t\t\tpar[y] = x;\n\t\t\tif(rank[x] == rank[y]) rank[x]++;\n\t\t}\n\t}\n\n\tbool same(int x, int y){\n\t\treturn find(x) == find(y);\n\t}\n};\n\nstruct edge{int to, cost; };\n\nint main(void){\n\tint m;\n\twhile(cin >> m && m){\n\tint tx[200], ty[200];\n\tint n;\n\tmap<int, vector<int> > S;\n\tREP(i, m){\n\t\tcin >> tx[i] >> ty[i];\n\t}\n\tcin >> n;\n\tREP(i, n){\n\t\tint x, y;\n\t\tcin >> x >> y;\n\t\tS[x].push_back(y);\n\t}\n\tREP(i, 1000000){\n\t\tREP(j, S[i].size()){\n\t\t\tbool flag;\n\t\t\tint diff_x, diff_y;\n\t\t\tdiff_x = i-tx[0];\n\t\t\tdiff_y = S[i][j]-ty[0];\n\t\t\tFOR(k, 1, m){\n\t\t\t\tflag = false;\n\t\t\t\tREP(l, S[tx[k]+diff_x].size()){\n\t\t\t\t\tif(S[tx[k]+diff_x][l] == ty[k]+diff_y){\n\t\t\t\t\t\tflag = true;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(!flag){\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(flag){\n\t\t\t\tcout << diff_x << \" \" << diff_y << endl;\n\t\t\t\tj = S[i].size();\n\t\t\t\ti = 1000000;\n\t\t\t}\n\t\t}\n\t}\n\t}\n\n}", "problem_context": "星座探し\n\n問題\n\nあなたは星空の写真の中から星座を探している．写真には必ず，探したい星座と同じ形・向き・大きさの図形がちょうど一つ含まれている．ただし，写真の中には星座を構成する星以外に余分な星が写っている可能性がある．\n\n例えば，図 1 の星座は図 2 の写真に含まれている（丸で囲んで示した）．与えられた星座��星の座標を x 方向に 2， y 方向に −3 だけ平行移動すると写真の中の位置になる．\n\n探したい星座の形と写真に写っている星の位置が与えられたとき，星座の座標を写真の中の座標に変換するために平行移動するべき量を答えるプログラムを書け．\n\n図 1: 探したい星座\n\n図 2: 星空の写真\n\n入力\n\n入力は複数のデータセットからなる．各データセットは以下の形式で与えられる．\n\n入力の 1 行目には探したい星座を構成する星の個数 m が書かれている．続く m 行には探したい星座を構成する m 個の星の x 座標と y 座標を示す整数が空白区切りで書かれている． m+2 行目には写真に写っている星の個数 n が書かれている．続く n 行には写真に写っている n 個の星の x 座標と y 座標を示す整数が空白区切りで書かれている．\n\n星座を構成する m 個の星の位置はすべて異なる．また，写真に写っている n 個の星の位置はすべて異なる． 1 ≤ m ≤ 200， 1 ≤ n ≤ 1000 である．星の x 座標と y 座標はすべて 0 以上 1000000 以下である．\n\nm が 0　のとき入力の終わりを示す. データセットの数は 5 を超えない．\n\n出力\n\n各データセットの出力は 1 行からなり， 2 個の整数を空白区切りで書く．これらは探したい星座の座標をどれだけ平行移動すれば写真の中の座標になるかを表す．最初の整数が x 方向に平行移動する量，次の整数が y 方向に平行移動する量である．\n\n入出力例\n\n入力例\n\n5\n8 5\n6 4\n4 3\n7 10\n0 10\n10\n10 5\n2 7\n9 7\n8 10\n10 2\n1 2\n8 1\n6 7\n6 0\n0 9\n5\n904207 809784\n845370 244806\n499091 59863\n638406 182509\n435076 362268\n10\n757559 866424\n114810 239537\n519926 989458\n461089 424480\n674361 448440\n81851 150384\n459107 795405\n299682 6700\n254125 362183\n50795 541942\n0\n\n出力例\n\n2 -3\n-384281 179674\n\n入出力例の１つ目は上の図に対応している．\n\n上記問題文と自動審判に使われるデータは、情報オリンピック日本委員会が作成し公開している問題文と採点用テストデータです。", "sample_input": "5\n8 5\n6 4\n4 3\n7 10\n0 10\n10\n10 5\n2 7\n9 7\n8 10\n10 2\n1 2\n8 1\n6 7\n6 0\n0 9\n5\n904207 809784\n845370 244806\n499091 59863\n638406 182509\n435076 362268\n10\n757559 866424\n114810 239537\n519926 989458\n461089 424480\n674361 448440\n81851 150384\n459107 795405\n299682 6700\n254125 362183\n50795 541942\n0\n"}, "reference_outputs": ["2 -3\n-384281 179674\n"], "source_document_id": "p00447", "source_text": "星座探し\n\n問題\n\nあなたは星空の写真の中から星座を探している．写真には必ず，探したい星座と同じ形・向き・大きさの図形がちょうど一つ含まれている．ただし，写真の中には星座を構成する星以外に余分な星が写っている可能性がある．\n\n例えば，図 1 の星座は図 2 の写真に含まれている（丸で囲んで示した）．与えられた星座の星の座標を x 方向に 2， y 方向に −3 だけ平行移動すると写真の中の位置になる．\n\n探したい星座の形と写真に写っている星の位置が与えられたとき，星座の座標を写真の中の座標に変換するために平行移動するべき量を答えるプログラムを書け．\n\n図 1: 探したい星座\n\n図 2: 星空の写真\n\n入力\n\n入力は複数のデータセットからなる．各データセットは以下の形式で与えられる．\n\n入力の 1 行目には探したい星座を構成する星の個数 m が書かれている．続く m 行には探したい星座を構成する m 個の星の x 座標と y 座標を示す整数が空白区切りで書かれている． m+2 行目には写真に写っている星の個数 n が書かれている．続く n 行には写真に写っている n 個の星の x 座標と y 座標を示す整数が空白区切りで書かれている．\n\n星座を構成する m 個の星の位置はすべて異なる．また，写真に写っている n 個の星の位置はすべて異なる． 1 ≤ m ≤ 200， 1 ≤ n ≤ 1000 である．星の x 座標と y 座標はすべて 0 以上 1000000 以下である．\n\nm が 0　のとき入力の終わりを示す. データセットの数は 5 を超えない．\n\n出力\n\n各データセットの出力は 1 行からなり， 2 個の整数を空白区切りで書く．これらは探したい星座の座標をどれだけ平行移動すれば写真の中の座標になるかを表す．最初の整数が x 方向に平行移動する量，次の整数が y 方向に平行移動する量である．\n\n入出力例\n\n入力例\n\n5\n8 5\n6 4\n4 3\n7 10\n0 10\n10\n10 5\n2 7\n9 7\n8 10\n10 2\n1 2\n8 1\n6 7\n6 0\n0 9\n5\n904207 809784\n845370 244806\n499091 59863\n638406 182509\n435076 362268\n10\n757559 866424\n114810 239537\n519926 989458\n461089 424480\n674361 448440\n81851 150384\n459107 795405\n299682 6700\n254125 362183\n50795 541942\n0\n\n出力例\n\n2 -3\n-384281 179674\n\n入出力例の１つ目は上の図に対応している．\n\n上記問題文と自動審判に使われるデータは、情報オリンピック日本委員会が作成し公開している問題文と採点用テストデータです。", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1625, "cpu_time_ms": 220, "memory_kb": 57728}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s781731732", "group_id": "codeNet:p00451", "input_text": "//JOI 0528 Common Sub-String\n#include <iostream>\n#include <string>\n#include <algorithm>\nusing namespace std;\nint main() {\n\tstring s, t;\n\tfor(int o=0;o<4;o++){\n                cin>>s>>t;\n\t\tint roop1=0, save=0, ans = 0;\n\tfor (int i = 0; i<s.size(); i++){\n\t\tfor (int j = 0; j<t.size(); j++){\n\t\t\tif (s[i] == t[j]){\n\t\t\t\troop1 = 0;\n\t\t\t\tsave= 0;\n\t\t\t\twhile (1){\n\t\t\t\t\t\tif (s[i + roop1] == t[j + roop1]){\n\t\t\t\t\t\t\tsave += 1;\n\t\t\t\t\t\t\troop1++;\n\t\t\t\t\t\t}\n\t\t\t\t\telse if (s[i + roop1] != t[j + roop1]){\n\t\t\t\t\t\t\tans=max(ans,save);\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tcout<<ans<<endl;\n\t}\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1436279185, "filename_ext": "cpp", "original_language": "C++11", "problem_description_relpath": "problem_descriptions/p00451.html", "problem_id": "p00451", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p00451/input.txt", "sample_output_relpath": "derived/input_output/data/p00451/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p00451/C++/s781731732.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s781731732", "user_id": "u367336587"}, "prompt_components": {"gold_output": "5\n0\n", "input_to_evaluate": "//JOI 0528 Common Sub-String\n#include <iostream>\n#include <string>\n#include <algorithm>\nusing namespace std;\nint main() {\n\tstring s, t;\n\tfor(int o=0;o<4;o++){\n                cin>>s>>t;\n\t\tint roop1=0, save=0, ans = 0;\n\tfor (int i = 0; i<s.size(); i++){\n\t\tfor (int j = 0; j<t.size(); j++){\n\t\t\tif (s[i] == t[j]){\n\t\t\t\troop1 = 0;\n\t\t\t\tsave= 0;\n\t\t\t\twhile (1){\n\t\t\t\t\t\tif (s[i + roop1] == t[j + roop1]){\n\t\t\t\t\t\t\tsave += 1;\n\t\t\t\t\t\t\troop1++;\n\t\t\t\t\t\t}\n\t\t\t\t\telse if (s[i + roop1] != t[j + roop1]){\n\t\t\t\t\t\t\tans=max(ans,save);\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tcout<<ans<<endl;\n\t}\n\treturn 0;\n}", "problem_context": "共通部分文字列\n\n問題\n\n2 個の文字列が与えられたとき, 両方の文字列に含まれる文字列のうち最も長いものを探し, その長さを答えるプログラムを作成せよ.\n\nここで, 文字列 s が文字列 t に含まれるとは, t の中に s が連続して現れることをいう. 空文字列, すなわち長さ 0 の文字列は, どんな文字列にも含まれる. 例えば, 文字列 ABRACADABRA には次の文字列が含まれる: ABRA, RAC, D, ACADABRA, ABRACADABRA,空文字列など. 一方, 文字列 ABRACADABRA には次の文字列は含まれない: ABRC, RAA,BA, K など.\n\n例\n\n例 1: 文字列として ABRACADABRA と ECADADABRBCRDARA が与えられた場合, 両方に含まれる文字列には CA や CADA や ADABR や空文字列などがある. そのうち最も長いのは ADABR であり, その長さは 5 である. 2 個の文字列の中に含まれる ADABR\nの位置を以下に示す.\n\nABRACADABRA\n\nECADADABRBCRDARA\n\n例 2: 文字列として UPWJCIRUCAXIIRGL と SBQNYBSBZDFNEV が与えられた場合, 両方に含まれる文字列は空文字列のみであり, その長さは 0 である.\n\n入力\n\n入力は複数のデータセットからなる．各データセットは以下の形式で与えられる．\n\n入力は 2 行からなり, 1 行目に 1 個目の文字列が, 2 行目に 2 個目の文字列が与えられる. 文字列は英大文字からなり, 各々の文字列の長さは 1 以上 4000 以下である.\n\n採点用データのうち, 配点の 30% 分については, 各々の文字列の長さは 1 以上 50以下である.\n\n入力の終わりは EOF で示される. データセットの数は 10 を超えない．\n\n出力\n\nデータセットごとに与えられた 2 個の文字列の両方に含まれる文字列のうち最も長いものの長さを 1 行に出力する.\n\n入出力例\n\n入力例\n\nABRACADABRA\nECADADABRBCRDARA\nUPWJCIRUCAXIIRGL\nSBQNYBSBZDFNEV\n\n出力例\n\n5\n0\n\n上記問題文と自動審判に使われるデータは、情報オリンピック日本委員会が作成し公開している問題文と採点用テストデータです。", "sample_input": "ABRACADABRA\nECADADABRBCRDARA\nUPWJCIRUCAXIIRGL\nSBQNYBSBZDFNEV\n"}, "reference_outputs": ["5\n0\n"], "source_document_id": "p00451", "source_text": "共通部分文字列\n\n問題\n\n2 個の文字列が与えられたとき, 両方の文字列に含まれる文字列のうち最も長いものを探し, その長さを答えるプログラムを作成せよ.\n\nここで, 文字列 s が文字列 t に含まれるとは, t の中に s が連続して現れることをいう. 空文字列, すなわち長さ 0 の文字列は, どんな文字列にも含まれる. 例えば, 文字列 ABRACADABRA には次の文字列が含まれる: ABRA, RAC, D, ACADABRA, ABRACADABRA,空文字列など. 一方, 文字列 ABRACADABRA には次の文字列は含まれない: ABRC, RAA,BA, K など.\n\n例\n\n例 1: 文字列として ABRACADABRA と ECADADABRBCRDARA が与えられた場合, 両方に含まれる文字列には CA や CADA や ADABR や空文字列などがある. そのうち最も長いのは ADABR であり, その長さは 5 である. 2 個の文字列の中に含まれる ADABR\nの位置を以下に示す.\n\nABRACADABRA\n\nECADADABRBCRDARA\n\n例 2: 文字列として UPWJCIRUCAXIIRGL と SBQNYBSBZDFNEV が与えられた場合, 両方に含まれる文字列は空文字列のみであり, その長さは 0 である.\n\n入力\n\n入力は複数のデータセットからなる．各データセットは以下の形式で与えられる．\n\n入力は 2 行からなり, 1 行目に 1 個目の文字列が, 2 行目に 2 個目の文字列が与えられる. 文字列は英大文字からなり, 各々の文字列の長さは 1 以上 4000 以下である.\n\n採点用データのうち, 配点の 30% 分については, 各々の文字列の長さは 1 以上 50以下である.\n\n入力の終わりは EOF で示される. データセットの数は 10 を超えない．\n\n出力\n\nデータセットごとに与えられた 2 個の文字列の両方に含まれる文字列のうち最も長いものの長さを 1 行に出力する.\n\n入出力例\n\n入力例\n\nABRACADABRA\nECADADABRBCRDARA\nUPWJCIRUCAXIIRGL\nSBQNYBSBZDFNEV\n\n出力例\n\n5\n0\n\n上記問題文と自動審判に使われるデータは、情報オリンピック日本委員会が作成し公開している問題文と採点用テストデータです。", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 580, "cpu_time_ms": 40, "memory_kb": 1208}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s417335278", "group_id": "codeNet:p00463", "input_text": "#include \"stdio.h\"\n#include \"stdlib.h\"\n\nint s[1000];\n\ntypedef struct\n{\n\tint a;\n\tint b;\n\tint w1;\n\tint w2;\n}yoko;\n\nyoko w[100000];\n\nint z[1000];\n\nint ten[1000];\n\nint sortw(const void* a,const void* b)\n{\n\tif(((yoko*)a)[0].a < ((yoko*)b)[0].a)\n\t{\n\t\treturn -1;\n\t}\n\telse if(((yoko*)a)[0].a == ((yoko*)b)[0].a)\n\t{\n\t\treturn 0;\n\t}\n\telse\n\t{\n\t\treturn 1;\n\t}\n}\n\nint ans[1000];\n\nint main()\n{\n\tint nww = 0;\n\twhile(1)\n\t{\n\t\tint n,m,h,k;\n\t\tscanf(\"%d %d %d %d\",&n,&m,&h,&k);\n\t\tif(n == 0 && m == 0 && h == 0 && k == 0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t\tfor(int i = 0; i < n; i++)\n\t\t{\n\t\t\tscanf(\"%d\",&(s[i]));\n\t\t}\n\t\tfor(int i = 0; i < m; i++)\n\t\t{\n\t\t\tscanf(\"%d %d\",&(w[i].b),&(w[i].a));\n\t\t}\n\t\tqsort(w,m,sizeof(yoko),sortw);\n\t\tfor(int i = 0; i < n; i++)\n\t\t{\n\t\t\tz[i] = i;\n\t\t}\n\t\tint d;\n\t\tfor(int i = 0; i < m; i++)\n\t\t{\n\t\t\tw[i].w1 = z[w[i].b];\n\t\t\tw[i].w2 = z[w[i].b - 1];\n\t\t\td = z[w[i].b];\n\t\t\tz[w[i].b] = z[w[i].b - 1];\n\t\t\tz[w[i].b - 1] = d;\n\t\t}\n\t\tfor(int i = 0; i < n; i++)\n\t\t{\n\t\t\tten[z[i]] = s[i];\n\t\t}\n\t\tint min;\n\t\tint www = 0;\n\t\tfor(int i = 0; i < k; i++)\n\t\t{\n\t\t\twww = www + ten[i];\n\t\t}\n\t\tmin = www;\n\t\tfor(int i = 0; i < m; i++)\n\t\t{\n\t\t\td = ten[w[i].w1];\n\t\t\tten[w[i].w1] = ten[w[i].w2];\n\t\t\tten[w[i].w2] = d;\n\t\t\twww = 0;\n\t\t\tfor(int i = 0; i < k; i++)\n\t\t\t{\n\t\t\t\twww = www + ten[i];\n\t\t\t}\n\t\t\tif(www < min)\n\t\t\t{\n\t\t\t\tmin = www;\n\t\t\t}\n\t\t\td = ten[w[i].w1];\n\t\t\tten[w[i].w1] = ten[w[i].w2];\n\t\t\tten[w[i].w2] = d;\n\t\t}\n\t\tans[nww] = min;\n\t\tnww++;\n\t}\n\tfor(int i = 0; i < nww; i++)\n\t{\n\t\tprintf(\"%d\\n\",ans[i]);\n\t}\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1391666579, "filename_ext": "cpp", "original_language": "C++", "problem_description_relpath": "problem_descriptions/p00463.html", "problem_id": "p00463", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p00463/input.txt", "sample_output_relpath": "derived/input_output/data/p00463/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p00463/C++/s417335278.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s417335278", "user_id": "u618330043"}, "prompt_components": {"gold_output": "100\n10\n", "input_to_evaluate": "#include \"stdio.h\"\n#include \"stdlib.h\"\n\nint s[1000];\n\ntypedef struct\n{\n\tint a;\n\tint b;\n\tint w1;\n\tint w2;\n}yoko;\n\nyoko w[100000];\n\nint z[1000];\n\nint ten[1000];\n\nint sortw(const void* a,const void* b)\n{\n\tif(((yoko*)a)[0].a < ((yoko*)b)[0].a)\n\t{\n\t\treturn -1;\n\t}\n\telse if(((yoko*)a)[0].a == ((yoko*)b)[0].a)\n\t{\n\t\treturn 0;\n\t}\n\telse\n\t{\n\t\treturn 1;\n\t}\n}\n\nint ans[1000];\n\nint main()\n{\n\tint nww = 0;\n\twhile(1)\n\t{\n\t\tint n,m,h,k;\n\t\tscanf(\"%d %d %d %d\",&n,&m,&h,&k);\n\t\tif(n == 0 && m == 0 && h == 0 && k == 0)\n\t\t{\n\t\t\tbreak;\n\t\t}\n\t\tfor(int i = 0; i < n; i++)\n\t\t{\n\t\t\tscanf(\"%d\",&(s[i]));\n\t\t}\n\t\tfor(int i = 0; i < m; i++)\n\t\t{\n\t\t\tscanf(\"%d %d\",&(w[i].b),&(w[i].a));\n\t\t}\n\t\tqsort(w,m,sizeof(yoko),sortw);\n\t\tfor(int i = 0; i < n; i++)\n\t\t{\n\t\t\tz[i] = i;\n\t\t}\n\t\tint d;\n\t\tfor(int i = 0; i < m; i++)\n\t\t{\n\t\t\tw[i].w1 = z[w[i].b];\n\t\t\tw[i].w2 = z[w[i].b - 1];\n\t\t\td = z[w[i].b];\n\t\t\tz[w[i].b] = z[w[i].b - 1];\n\t\t\tz[w[i].b - 1] = d;\n\t\t}\n\t\tfor(int i = 0; i < n; i++)\n\t\t{\n\t\t\tten[z[i]] = s[i];\n\t\t}\n\t\tint min;\n\t\tint www = 0;\n\t\tfor(int i = 0; i < k; i++)\n\t\t{\n\t\t\twww = www + ten[i];\n\t\t}\n\t\tmin = www;\n\t\tfor(int i = 0; i < m; i++)\n\t\t{\n\t\t\td = ten[w[i].w1];\n\t\t\tten[w[i].w1] = ten[w[i].w2];\n\t\t\tten[w[i].w2] = d;\n\t\t\twww = 0;\n\t\t\tfor(int i = 0; i < k; i++)\n\t\t\t{\n\t\t\t\twww = www + ten[i];\n\t\t\t}\n\t\t\tif(www < min)\n\t\t\t{\n\t\t\t\tmin = www;\n\t\t\t}\n\t\t\td = ten[w[i].w1];\n\t\t\tten[w[i].w1] = ten[w[i].w2];\n\t\t\tten[w[i].w2] = d;\n\t\t}\n\t\tans[nww] = min;\n\t\tnww++;\n\t}\n\tfor(int i = 0; i < nww; i++)\n\t{\n\t\tprintf(\"%d\\n\",ans[i]);\n\t}\n\treturn 0;\n}", "problem_context": "あみだくじ\n\n問題\n\nあなたは J 君と一緒にあみだくじを使って遊んでいる.あみだくじは n 本の縦棒と\nm 本の横棒からなる.縦棒には左から順に 1 から n の番号がついており,縦棒 i の下端には正整数 si が書かれている.\n\n図 3-1 あみだくじの例(n = 4, m = 5, s1 = 20, s2 = 80, s3 = 100, s4 = 50)\n\n縦棒 i の一番上から順に道をたどっていき到達した下端に書かれている整数が, 縦\n棒 i を選んだ場合の得点である.例えば,図 3-1 では,縦棒 1 を選ぶと得点は 80 点\nであり,縦棒 2 を選ぶと得点は 100 点である.\n\n図 3-2 道のたどり方の例\n\nJ 君は縦棒 1 から縦棒 k までの連続した k 本を選ぶことにした.それら k 本の縦棒を選んだときの点数の合計が J 君の得点となる.ただし,あなたはあみだくじ内の\n横棒を一本選び,その横棒をあみだくじから削除することができる. (削除しなくてもよい.) もし,あなたが横棒を一本削除した場合は,削除後のあみだくじにおいて,\n縦棒 1 から縦棒 k までの連続した k 本の縦棒を選んだときの点数の合計が J 君の得点となる.\n\n入力としてあみだくじの形と J 君の選ぶ縦棒の本数 k が与えられたとき,J 君の得\n点の最小値を求めるプログラムを作成せよ.\n\n入力\n\n入力は複数のデータセットからなる．各データセットは以下の形式で与えられる．\n\n1 行目には 4 つの整数 n, m, h, k が空白区切りで書かれている. n (2 ≤ n ≤ 1000) は縦棒の本数を, m (1 ≤ m ≤ 100000) は横棒の本数を, h (2 ≤ h ≤ 1000) は縦棒の長さを,k (1 ≤ k ≤ n) は J 君が選ぶ縦棒の本数を表す.\n\n続く n 行には縦棒の下端に書かれている点数が書かれている. i + 1 行目 (1 ≤ i ≤ n)には正整数 si が書かれている. また, s1 + s2 + ... + sn ≤ 2000000000 = 2 × 109 を満たす.\n\n続く m 行には横棒の位置が書かれている.横棒には 1 から m までの番号がついている.i + n + 1 行目 (1 ≤ i ≤ m) には, 横棒 i の位置を表す 2 つの整数 ai, bi (1 ≤ ai ≤ n - 1, 1 ≤ bi ≤ h - 1) が空白区切りで書かれており,横棒 i が縦棒 ai と縦棒 ai + 1 を結び, 横棒 i の上端からの距離が bi であることを表す. ただし,どの 2 つの横棒も端点を共有することはない.\n\n採点用データのうち,配点の 20 % 分は横棒を削除しない場合に J 君の得点が最少となる.また,配点の 30 % 分は n ≤ 20, m ≤ 30, h ≤ 10 を満たし,配点の 60 % 分は m �� 1000 を満たす.\n\n入力の終わりは 4つのゼロを含む行で示される. データセットの数は 10 を超えない．\n\n出力\n\nデータセットごとに, J 君の得点の最小値を1 行に出力する.\n\n入出力例\n\n入力例\n\n4 5 7 2\n20\n80\n100\n50\n1 1\n2 6\n2 3\n1 5\n3 1\n2 2 5 1\n10\n20\n1 1\n1 3\n0 0 0 0\n\n出力例\n\n100\n10\n\n1つ目の例 は図 3-1 に対応し,あなたが横棒 4 (縦棒 1 と縦棒 2 を上端から距離 5 の場所で結ぶ横棒)を削除したとき,J 君の得点は最小になる.例 2 では,あなたが横棒を削除しない場合に J 君の得点が最小になる. (図3-3 を見よ.)\n\n図 3-3\n\n上記問題文と自動審判に使われるデータは、情報オリンピック日本委員会が作成し公開している問題文と採点用テストデータです。", "sample_input": "4 5 7 2\n20\n80\n100\n50\n1 1\n2 6\n2 3\n1 5\n3 1\n2 2 5 1\n10\n20\n1 1\n1 3\n0 0 0 0\n"}, "reference_outputs": ["100\n10\n"], "source_document_id": "p00463", "source_text": "あみだくじ\n\n問題\n\nあなたは J 君と一緒にあみだくじを使って遊んでいる.あみだくじは n 本の縦棒と\nm 本の横棒からなる.縦棒には左から順に 1 から n の番号がついており,縦棒 i の下端には正整数 si が書かれている.\n\n図 3-1 あみだくじの例(n = 4, m = 5, s1 = 20, s2 = 80, s3 = 100, s4 = 50)\n\n縦棒 i の一番上から順に道をたどっていき到達した下端に書かれている整数が, 縦\n棒 i を選んだ場合の得点である.例えば,図 3-1 では,縦棒 1 を選ぶと得点は 80 点\nであり,縦棒 2 を選ぶと得点は 100 点である.\n\n図 3-2 道のたどり方の例\n\nJ 君は縦棒 1 から縦棒 k までの連続した k 本を選ぶことにした.それら k 本の縦棒を選んだときの点数の合計が J 君の得点となる.ただし,あなたはあみだくじ内の\n横棒を一本選び,その横棒をあみだくじから削除することができる. (削除しなくてもよい.) もし,あなたが横棒を一本削除した場合は,削除後のあみだくじにおいて,\n縦棒 1 から縦棒 k までの連続した k 本の縦棒を選んだときの点数の合計が J 君の得点となる.\n\n入力としてあみだくじの形と J 君の選ぶ縦棒の本数 k が与えられたとき,J 君の得\n点の最小値を求めるプログラムを作成せよ.\n\n入力\n\n入力は複数のデータセットからなる．各データセットは以下の形式で与えられる．\n\n1 行目には 4 つの整数 n, m, h, k が空白区切りで書かれている. n (2 ≤ n ≤ 1000) は縦棒の本数を, m (1 ≤ m ≤ 100000) は横棒の本数を, h (2 ≤ h ≤ 1000) は縦棒の長さを,k (1 ≤ k ≤ n) は J 君が選ぶ縦棒の本数を表す.\n\n続く n 行には縦棒の下端に書かれている点数が書かれている. i + 1 行目 (1 ≤ i ≤ n)には正整数 si が書かれている. また, s1 + s2 + ... + sn ≤ 2000000000 = 2 × 109 を満たす.\n\n続く m 行には横棒の位置が書かれている.横棒には 1 から m までの番号がついている.i + n + 1 行目 (1 ≤ i ≤ m) には, 横棒 i の位置を表す 2 つの整数 ai, bi (1 ≤ ai ≤ n - 1, 1 ≤ bi ≤ h - 1) が空白区切りで書かれており,横棒 i が縦棒 ai と縦棒 ai + 1 を結び, 横棒 i の上端からの距離が bi であることを表す. ただし,どの 2 つの横棒も端点を共有することはない.\n\n採点用データのうち,配点の 20 % 分は横棒を削除しない場合に J 君の得点が最少となる.また,配点の 30 % 分は n ≤ 20, m ≤ 30, h ≤ 10 を満たし,配点の 60 % 分は m ≤ 1000 を満たす.\n\n入力の終わりは 4つのゼロを含む行で示される. データセットの数は 10 を超えない．\n\n出力\n\nデータセットごとに, J 君の得点の最小値を1 行に出力する.\n\n入出力例\n\n入力例\n\n4 5 7 2\n20\n80\n100\n50\n1 1\n2 6\n2 3\n1 5\n3 1\n2 2 5 1\n10\n20\n1 1\n1 3\n0 0 0 0\n\n出力例\n\n100\n10\n\n1つ目の例 は図 3-1 に対応し,あなたが横棒 4 (縦棒 1 と縦棒 2 を上端から距離 5 の場所で結ぶ横棒)を削除したとき,J 君の得点は最小になる.例 2 では,あなたが横棒を削除しない場合に J 君の得点が最小になる. (図3-3 を見よ.)\n\n図 3-3\n\n上記問題文と自動審判に使われるデータは、情報オリンピック日本委員会が作成し公開している問題文と採点用テストデータです。", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1468, "cpu_time_ms": 60, "memory_kb": 4124}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s045361293", "group_id": "codeNet:p00473", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define M INT_MAX\nint dp[10002][5001][2];\nint main(void){\n\tint n,nn,ti[10001],i,j,k,t,mi;\n\tcin>>n;\n\tnn=n/2;\n\tfor(i=1;i<n;i++) cin>>ti[i];\n\tti[n]=0;\n\tfor(i=0;i<=n;i++){\n\t\tfor(j=0;j<=nn;j++) dp[i][j][0]=M,dp[i][j][1]=M;\n\t}\n\tdp[1][1][0]=ti[1];\n\tfor(i=1;i<n;i++){\n\t\tfor(j=1;j<=nn;j++){\n\t\t\tif(dp[i][j][0]!=M){\n\t\t\t\tdp[i+1][j][1]=min(dp[i+1][j][1],dp[i][j][0]);\n\t\t\t\tt=dp[i][j][0]-ti[i]+ti[i+1];\n\t\t\t\tdp[i+1][j+1][0]=min(dp[i+1][j+1][0],t);\n\t\t\t}\n\t\t\tif(dp[i][j][1]!=M){\n\t\t\t\tdp[i+1][j][1]=min(dp[i+1][j][1],dp[i][j][1]);\n\t\t\t\tt=dp[i][j][1]+ti[i+1]+ti[i];\n\t\t\t\tdp[i+1][j+1][0]=min(dp[i+1][j+1][0],t);\n\t\t\t}\n\t\t}\n\t}\n/*      for(i=1;i<=n;i++){\n\t\tfor(j=1;j<=nn;j++) cout<<dp[i][j][0]<<':'<<dp[i][j][1]<<' ';\n\t\tcout<<endl;\n\t}*/\n\tcout<<min(dp[n][nn][0],dp[n][nn][1])<<endl;\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1516434244, "filename_ext": "cpp", "original_language": "C++", "problem_description_relpath": "problem_descriptions/p00473.html", "problem_id": "p00473", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p00473/input.txt", "sample_output_relpath": "derived/input_output/data/p00473/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p00473/C++/s045361293.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Memory Limit Exceeded", "submission_id": "s045361293", "user_id": "u850274609"}, "prompt_components": {"gold_output": "7\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define M INT_MAX\nint dp[10002][5001][2];\nint main(void){\n\tint n,nn,ti[10001],i,j,k,t,mi;\n\tcin>>n;\n\tnn=n/2;\n\tfor(i=1;i<n;i++) cin>>ti[i];\n\tti[n]=0;\n\tfor(i=0;i<=n;i++){\n\t\tfor(j=0;j<=nn;j++) dp[i][j][0]=M,dp[i][j][1]=M;\n\t}\n\tdp[1][1][0]=ti[1];\n\tfor(i=1;i<n;i++){\n\t\tfor(j=1;j<=nn;j++){\n\t\t\tif(dp[i][j][0]!=M){\n\t\t\t\tdp[i+1][j][1]=min(dp[i+1][j][1],dp[i][j][0]);\n\t\t\t\tt=dp[i][j][0]-ti[i]+ti[i+1];\n\t\t\t\tdp[i+1][j+1][0]=min(dp[i+1][j+1][0],t);\n\t\t\t}\n\t\t\tif(dp[i][j][1]!=M){\n\t\t\t\tdp[i+1][j][1]=min(dp[i+1][j][1],dp[i][j][1]);\n\t\t\t\tt=dp[i][j][1]+ti[i+1]+ti[i];\n\t\t\t\tdp[i+1][j+1][0]=min(dp[i+1][j+1][0],t);\n\t\t\t}\n\t\t}\n\t}\n/*      for(i=1;i<=n;i++){\n\t\tfor(j=1;j<=nn;j++) cout<<dp[i][j][0]<<':'<<dp[i][j][1]<<' ';\n\t\tcout<<endl;\n\t}*/\n\tcout<<min(dp[n][nn][0],dp[n][nn][1])<<endl;\n\treturn 0;\n}\n", "problem_context": "お菓子の分割\n　\n\n問題\n\n長さ N ミリメートルの棒状のお菓子が 1 本ある(ここで N は偶数). 2 人の JOI\n関係者が,このお菓子を複数本に切断して,合計 N/2 ミリメートルずつに分けること\nにした.\n\n理由は不明であるが,このお菓子は場所によって切断のしやすさが異なっている.\n2 人は,お菓子を左から 1 ミリメートルごとに調べ,各場所で切断に何秒かかるか\nを割り出した.2 人がお菓子を分けるための切断にかかる秒数の最小値を求めるプ\nログラムを作成せよ.\n\n入力\n\n入力の 1 行目には,棒の長さ N(2 ≤ N ≤ 10000 ,ただし N は偶数) が書かれてい\nる.入力の i + 1 行目 (1 ≤ i ≤ N − 1) には,左端から i ミリメートル目の場所の切\n断にかかる秒数を表す整数 ti (1 ≤ ti ≤ 10000) が書かれている.切断可能な場所が\nN − 1 箇所であることに注意せよ.\n\n採点用データのうち,配点の 5% 分については,高々 2 カ所を切断することで最\n小値を実現でき,10% 分については,高々 3 カ所を切断することで最小値を実現で\nきる.配点の 20% 分については,N ≤ 20 である.\n\n出力\n\n出力は2 人がお菓子を分るための切断にかかる秒数の最小値を含む 1 行からなる.\n\n入出力例\n\n入力例 1\n\n6\n1\n8\n12\n6\n2\n\n出力例 1\n\n7\n\nこの場合,左端から 1 ミリメートルと 4 ミリメートルの場所で切断するとかかる\n秒数が最小となる.かかる秒数は 1 秒と 6 秒で,合計 7 秒である.\n\n上記問題文と自動審判に使われるデータは、情報オリンピック日本委員会が作成し公開している問題文と採点用テストデータです。", "sample_input": "6\n1\n8\n12\n6\n2\n"}, "reference_outputs": ["7\n"], "source_document_id": "p00473", "source_text": "お菓子の分割\n　\n\n問題\n\n長さ N ミリメートルの棒状のお菓子が 1 本ある(ここで N は偶数). 2 人の JOI\n関係者が,このお菓子を複数本に切断して,合計 N/2 ミリメートルずつに分けること\nにした.\n\n理由は不明であるが,このお菓子は場所によって切断のしやすさが異なっている.\n2 人は,お菓子を左から 1 ミリメートルごとに調べ,各場所で切断に何秒かかるか\nを割り出した.2 人がお菓子を分けるための切断にかかる秒数の最小値を求めるプ\nログラムを作成せよ.\n\n入力\n\n入力の 1 行目には,棒の長さ N(2 ≤ N ≤ 10000 ,ただし N は偶数) が書かれてい\nる.入力の i + 1 行目 (1 ≤ i ≤ N − 1) には,左端から i ミリメートル目の場所の切\n断にかかる秒数を表す整数 ti (1 ≤ ti ≤ 10000) が書かれている.切断可能な場所が\nN − 1 箇所であることに注意せよ.\n\n採点用データのうち,配点の 5% 分については,高々 2 カ所を切断することで最\n小値を実現でき,10% 分については,高々 3 カ所を切断することで最小値を実現で\nきる.配点の 20% 分については,N ≤ 20 である.\n\n出力\n\n出力は2 人がお菓子を分るための切断にかかる秒数の最小値を含む 1 行からなる.\n\n入出力例\n\n入力例 1\n\n6\n1\n8\n12\n6\n2\n\n出力例 1\n\n7\n\nこの場合,左端から 1 ミリメートルと 4 ミリメートルの場所で切断するとかかる\n秒数が最小となる.かかる秒数は 1 秒と 6 秒で,合計 7 秒である.\n\n上記問題文と自動審判に使われるデータは、情報オリンピック日本委員会が作成し公開している問題文と採点用テストデータです。", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 832, "cpu_time_ms": 210, "memory_kb": 393768}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s796352613", "group_id": "codeNet:p00478", "input_text": "a,C;main(b){for(;~scanf(\"%s\",a?&b:&a);)strstr(strcat(strdup(&b),&b),&a)&&C++;C=!printf(\"%d\\n\",C);}", "language": "C++", "metadata": {"date": 1297632556, "filename_ext": "cpp", "original_language": "C++", "problem_description_relpath": "problem_descriptions/p00478.html", "problem_id": "p00478", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p00478/input.txt", "sample_output_relpath": "derived/input_output/data/p00478/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p00478/C++/s796352613.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Compile Error", "submission_id": "s796352613", "user_id": "u907421301"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "a,C;main(b){for(;~scanf(\"%s\",a?&b:&a);)strstr(strcat(strdup(&b),&b),&a)&&C++;C=!printf(\"%d\\n\",C);}", "problem_context": "指輪 (Ring)\n\n問題\n\nあなたは N 個の指輪を持っている．どの指輪にも，アルファベットの大文字 10 文字からなる文字列が刻印されている．指輪には文字列の最初と最後がつながった形で文字が刻印されている．指輪に刻印された文字列を逆順に読む心配はない．\n\n探したい文字列が与えられたとき，その文字列を含む指輪が何個あるかを求めるプログラムを作成せよ．\n\n入力\n\n入力は 2+N 行からなる．\n\n1 行目には，1 文字以上 10 文字以下のアルファベットの大文字からなる探したい文字列が書かれている．\n\n2 行目には，指輪の個数 N ( 1 ≦ N ≦ 100 )が書かれている．\n\n2+i 行目(1 ≤ i ≤ N )には， i 個目の指輪に刻印されている 10 文字からなる文字列が書かれている．\n\n出力\n\n探したい文字列を含む指輪の個数を表す整数を 1 行で出力せよ．\n\n入出力例\n\n入力例 1\n\nABCD\n3\nABCDXXXXXX\nYYYYABCDXX\nDCBAZZZZZZ\n\n出力例 1\n\n2\n\n入力例 2\n\nXYZ\n1\nZAAAAAAAXY\n\n出力例 2\n\n1\n\n入力例 2 の指輪には「XYZ」という文字列が 1 つ含まれている．これは、指輪の文字列の最初と最後がつながっているためである．\n\n入力例 3\n\nPQR\n3\nPQRAAAAPQR\nBBPQRBBBBB\nCCCCCCCCCC\n\n出力例 3\n\n2\n\n入力例 3 の 1 個目の指輪には「PQR」という文字列が 2 つ含まれており， 2 個目の指輪には「PQR」という文字列が 1 個含まれており， 3 個目の指輪には「PQR」という文字列が含まれていない．そのため「PQR」という文字列が含まれている指輪の数は 2 個となる．\n\n問題文と自動審判に使われるデータは、情報オリンピック日本委員会が作成し公開している問題文と採点用テストデータです。", "sample_input": "ABCD\n3\nABCDXXXXXX\nYYYYABCDXX\nDCBAZZZZZZ\n"}, "reference_outputs": ["2\n"], "source_document_id": "p00478", "source_text": "指輪 (Ring)\n\n問題\n\nあなたは N 個の指輪を持っている．ど���指輪にも，アルファベットの大文字 10 文字からなる文字列が刻印されている．指輪には文字列の最初と最後がつながった形で文字が刻印されている．指輪に刻印された文字列を逆順に読む心配はない．\n\n探したい文字列が与えられたとき，その文字列を含む指輪が何個あるかを求めるプログラムを作成せよ．\n\n入力\n\n入力は 2+N 行からなる．\n\n1 行目には，1 文字以上 10 文字以下のアルファベットの大文字からなる探したい文字列が書かれている．\n\n2 行目には，指輪の個数 N ( 1 ≦ N ≦ 100 )が書かれている．\n\n2+i 行目(1 ≤ i ≤ N )には， i 個目の指輪に刻印されている 10 文字からなる文字列が書かれている．\n\n出力\n\n探したい文字列を含む指輪の個数を表す整数を 1 行で出力せよ．\n\n入出力例\n\n入力例 1\n\nABCD\n3\nABCDXXXXXX\nYYYYABCDXX\nDCBAZZZZZZ\n\n出力例 1\n\n2\n\n入力例 2\n\nXYZ\n1\nZAAAAAAAXY\n\n出力例 2\n\n1\n\n入力例 2 の指輪には「XYZ」という文字列が 1 つ含まれている．これは、指輪の文字列の最初と最後がつながっているためである．\n\n入力例 3\n\nPQR\n3\nPQRAAAAPQR\nBBPQRBBBBB\nCCCCCCCCCC\n\n出力例 3\n\n2\n\n入力例 3 の 1 個目の指輪には「PQR」という文字列が 2 つ含まれており， 2 個目の指輪には「PQR」という文字列が 1 個含まれており， 3 個目の指輪には「PQR」という文字列が含まれていない．そのため「PQR」という文字列が含まれている指輪の数は 2 個となる．\n\n問題文と自動審判に使われるデータは、情報オリンピック日本委員会が作成し公開している問題文と採点用テストデータです。", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 98, "cpu_time_ms": 3150, "memory_kb": 30000}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s778376310", "group_id": "codeNet:p00509", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n\ninline string toString(int a){\n  stringstream ss;\n  ss << a;\n  return ss.str();\n}\n\ninline int toInt(string s){\n  stringstream ss(s);\n  int res;\n  ss >> res;\n  return res;\n}\n\ninline bool is_prime(int a){\n  if(a<=1)return false;\n  for(int i=2;i*i<=a;i++){\n    if(a%i==0)return false;\n  }\n  return true;\n}\n\nint rec(int d, int n, string s, string c){\n  if(n>4)return -1;\n  if(d==n){\n    string pal = s + c;\n    reverse(s.begin(),s.end());\n    pal += s;\n    int p = toInt(pal);\n    return is_prime(p)?p:-1;\n  }\n\n  int res = -1;\n  for(int i=0;i<10;i++){\n    if(d==0 && (i%2==0 || i%5==0))continue;\n    res = max( res, rec(d+1, n, s + toString(i), c) );\n  }\n  return res;\n}\n\nint main(){\n  int n,c;\n  cin >> n >> c;\n  string center = (c<0)?\"\":toString(c);\n  int res = rec(0,n,\"\",center);\n\n  if(res<0){\n    for(int i=0;i<n;i++)cout << \"9\";\n    cout << center;\n    for(int i=0;i<n;i++)cout << \"9\";\n    cout << endl;\n  }else{\n    cout << res << endl;\n  }\n}", "language": "C++", "metadata": {"date": 1416541559, "filename_ext": "cpp", "original_language": "C++", "problem_description_relpath": "problem_descriptions/p00509.html", "problem_id": "p00509", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p00509/input.txt", "sample_output_relpath": "derived/input_output/data/p00509/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p00509/C++/s778376310.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s778376310", "user_id": "u914140574"}, "prompt_components": {"gold_output": "101\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n\ninline string toString(int a){\n  stringstream ss;\n  ss << a;\n  return ss.str();\n}\n\ninline int toInt(string s){\n  stringstream ss(s);\n  int res;\n  ss >> res;\n  return res;\n}\n\ninline bool is_prime(int a){\n  if(a<=1)return false;\n  for(int i=2;i*i<=a;i++){\n    if(a%i==0)return false;\n  }\n  return true;\n}\n\nint rec(int d, int n, string s, string c){\n  if(n>4)return -1;\n  if(d==n){\n    string pal = s + c;\n    reverse(s.begin(),s.end());\n    pal += s;\n    int p = toInt(pal);\n    return is_prime(p)?p:-1;\n  }\n\n  int res = -1;\n  for(int i=0;i<10;i++){\n    if(d==0 && (i%2==0 || i%5==0))continue;\n    res = max( res, rec(d+1, n, s + toString(i), c) );\n  }\n  return res;\n}\n\nint main(){\n  int n,c;\n  cin >> n >> c;\n  string center = (c<0)?\"\":toString(c);\n  int res = rec(0,n,\"\",center);\n\n  if(res<0){\n    for(int i=0;i<n;i++)cout << \"9\";\n    cout << center;\n    for(int i=0;i<n;i++)cout << \"9\";\n    cout << endl;\n  }else{\n    cout << res << endl;\n  }\n}", "problem_context": "問題５\n\n　Ｊ中学校の運動会で次のようなクラス対抗の競技を行なうことになった．\n各クラスから生徒代表の男女 n ペア\n\n     　　 (男子生徒 b1， 女子生徒 g1)， (男子生徒 b2， 女子生徒 g2)， … ， (男子生徒 bn， 女子生徒 gn)\n\nを選び，\n0 から 9 までの数字が書かれた旗を自由に選んでもらい\n（それぞれの旗は十分な個数ある），\n横一列に並んでもらう．\nただし，\nペアになっている男子生徒と女子生徒は同じ番号の旗を一人１つずつ\n選ばなければならず，\n並び順は\n\n     　　 b1 b2 … bn c gn … g2 g1\n\nのように，\n男子生徒達 n 人の並び順\nb1 b2 … bn とは逆の順番\ngn … g2 g1 で女子生徒達は\n並ばなければならない．\n中央の c には，\nクラス担任の先生があらかじめ審判長によって指定された\n番号の付いた旗を持って立つ場合と，\n立たないことを審判長に指定される場合とがある．\n\n　こうして並んだ生徒達（と先生）が持った旗の番号\nを 2n 桁（または 2n+1 桁）の整数と考えたとき，\nそれが素数である方が勝ちである．\nただし，\n両クラスとも素数だった場合あるいは両クラスとも素数でなかった場合には，\n数が大きい方が勝ちである． また，\n\n　　\n\n      0 b2 … bn c gn … g2 0\n　あるいは　\n0 b2 … bn gn … g2 0\n\nのように先頭に 0 が来るものは，\n普通使われる数の表し方ではないので禁止されている．\n\n　Ｊ中学校の生徒であるあなたは，\n自分のクラスが勝つためにはどのように並ぶのがよいかを\n考えなければならない．\n\n　入力ファイルの１行目に正整数 n と\n１桁の整数 c（先生が持つ旗の番号）が\n１つの半角空白文字で区切られて書かれている．\nc<0 のときは，\n先生が中央に立たないことを表わす．\n\n与えられる入力は 1≦n≦10 である．\n\n　負けない並び方の順番\n\n　　\n\n     b1 b2 … bn c gn … g2 g1\n　または　\nb1 b2 … bn gn … g2 g1\n\nを出力せよ．\n\n出力ファイルにおいては，\n出力の最後にも改行コードを入れること．\n\n入出力例\n\n入力例１\n\n1 0\n\n出力例１\n\n101\n\n入力例２\n\n1 5\n\n出力例２\n\n757\n\n入力例３\n\n3 7\n\n出力例３\n\n9957599\n\n入力例４\n\n1 -1\n\n出力例４\n\n11\n\n問題文と自動審判に使われるデータは、情報オリンピック日本委員会が作成し公開している問題文と採点用テストデータです。", "sample_input": "1 0\n"}, "reference_outputs": ["101\n"], "source_document_id": "p00509", "source_text": "問題５\n\n　Ｊ中学校の運動会で次のようなクラス対抗の競技を行なうことになった．\n各クラスから生徒代表の男女 n ペア\n\n     　　 (男子生徒 b1， 女子生徒 g1)， (男子生徒 b2， 女子生徒 g2)， … ， (男子生徒 bn， 女子生徒 gn)\n\nを選び，\n0 から 9 までの数字が書かれた旗を自由に選んでもらい\n（それぞれの旗は十分な個数ある），\n横一列に並んでもらう．\nただし，\nペアになっている男子生徒と女子生徒は同じ番号の旗を一人１つずつ\n選ばなければならず，\n並び順は\n\n     　　 b1 b2 … bn c gn … g2 g1\n\nのように，\n男子生徒達 n 人の並び順\nb1 b2 … bn とは逆の順番\ngn … g2 g1 で女子生徒達は\n並ばなければならない．\n中央の c には，\nクラス担任の先生があらかじめ審判長によって指定された\n番号の付いた旗を持って立つ場合と，\n立たないことを審判長に指定される場合とがある．\n\n　こうして並んだ生徒達（と先生）が持った旗の番号\nを 2n 桁（または 2n+1 桁）の整数と考えたとき，\nそれが素数である方が勝ちである．\nただし，\n両クラスとも素数だった場合あるいは両クラスとも素数でなかった場合には，\n数が大きい方が勝ちである． また，\n\n　　\n\n      0 b2 … bn c gn … g2 0\n　あるいは　\n0 b2 … bn gn … g2 0\n\nのように先頭に 0 が来るものは，\n普通使われる数の表し方ではないので禁止されている．\n\n　Ｊ中学校の生徒であるあなたは，\n自分のクラスが勝つためにはどのように並ぶのがよいかを\n考えなければならない．\n\n　入力ファイルの１行目に正整数 n と\n１桁の整数 c（先生が持つ旗の番号）が\n１つの半角空白文字で区切られて書かれている．\nc<0 のときは，\n先生が中央に立たないことを��わす．\n\n与えられる入力は 1≦n≦10 である．\n\n　負けない並び方の順番\n\n　　\n\n     b1 b2 … bn c gn … g2 g1\n　または　\nb1 b2 … bn gn … g2 g1\n\nを出力せよ．\n\n出力ファイルにおいては，\n出力の最後にも改行コードを入れること．\n\n入出力例\n\n入力例１\n\n1 0\n\n出力例１\n\n101\n\n入力例２\n\n1 5\n\n出力例２\n\n757\n\n入力例３\n\n3 7\n\n出力例３\n\n9957599\n\n入力例４\n\n1 -1\n\n出力例４\n\n11\n\n問題文と自動審判に使われるデータは、情報オリンピック日本委員会が作成し公開している問題文と採点用テストデータです。", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 991, "cpu_time_ms": 60, "memory_kb": 1232}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s297424838", "group_id": "codeNet:p00618", "input_text": "#include <iostream>\n#include <cstdio>\n#include <vector>\n#include <algorithm>\n#include <complex>\n#include <queue>\n#include <map>\n#include <set>\n#include <cstring>\n#include <cstdlib>\n#include <string>\n#include <cmath>\nusing namespace std;\n\n#define REP(i,n) for(int i=0;i<(int)n;++i)\n#define FOR(i,c) for(__typeof((c).begin())i=(c).begin();i!=(c).end();++i)\n#define ALL(c) (c).begin(), (c).end()\nconst int INF = 1<<29;\n\nint main() {\n  int n, U;\n  while(cin>>n>>U, n||U) {\n    int bitmask[n];\n    int c[n];\n    memset(bitmask,0,sizeof(bitmask));\n    REP(i,n) {\n      int k;\n      cin >> c[i] >> k;\n      REP(j,k) {\n        int r;\n        cin >> r;\n        bitmask[i] |= 1<<r;\n      }\n    }\n    if (U==0) {                 // ツつ「ツづゥツつゥツ不ツ鳴セ\n      cout << 0 << endl;\n      continue;      \n    }\n    bool ok = 0;\n    int res = 0;\n    for (int k=1; k<=n; ++k) {\n      int S = (1<<k)-1;\n      while(S<1<<n) {\n        int sum = 0;\n        bool dame = 0;\n        REP(i,k) {\n          if (S>>i&1) {\n            if (S&bitmask[i] != bitmask[i]) {\n              dame = 1;\n              break;\n            }\n            sum += c[i];\n          }\n        }\n        if (!dame && sum >= U) {\n          ok = 1;\n          res = k;\n          break;\n        }\n        int x = S&-S, y=S+x;\n        S = ((S & ~y) / x >> 1) | y;\n      }\n      if (ok) break;\n    }\n    cout << res << endl;\n  }\n}", "language": "C++", "metadata": {"date": 1312254351, "filename_ext": "cpp", "original_language": "C++", "problem_description_relpath": "problem_descriptions/p00618.html", "problem_id": "p00618", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p00618/input.txt", "sample_output_relpath": "derived/input_output/data/p00618/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p00618/C++/s297424838.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s297424838", "user_id": "u505648358"}, "prompt_components": {"gold_output": "2\n3\n", "input_to_evaluate": "#include <iostream>\n#include <cstdio>\n#include <vector>\n#include <algorithm>\n#include <complex>\n#include <queue>\n#include <map>\n#include <set>\n#include <cstring>\n#include <cstdlib>\n#include <string>\n#include <cmath>\nusing namespace std;\n\n#define REP(i,n) for(int i=0;i<(int)n;++i)\n#define FOR(i,c) for(__typeof((c).begin())i=(c).begin();i!=(c).end();++i)\n#define ALL(c) (c).begin(), (c).end()\nconst int INF = 1<<29;\n\nint main() {\n  int n, U;\n  while(cin>>n>>U, n||U) {\n    int bitmask[n];\n    int c[n];\n    memset(bitmask,0,sizeof(bitmask));\n    REP(i,n) {\n      int k;\n      cin >> c[i] >> k;\n      REP(j,k) {\n        int r;\n        cin >> r;\n        bitmask[i] |= 1<<r;\n      }\n    }\n    if (U==0) {                 // ツつ「ツづゥツつゥツ不ツ鳴セ\n      cout << 0 << endl;\n      continue;      \n    }\n    bool ok = 0;\n    int res = 0;\n    for (int k=1; k<=n; ++k) {\n      int S = (1<<k)-1;\n      while(S<1<<n) {\n        int sum = 0;\n        bool dame = 0;\n        REP(i,k) {\n          if (S>>i&1) {\n            if (S&bitmask[i] != bitmask[i]) {\n              dame = 1;\n              break;\n            }\n            sum += c[i];\n          }\n        }\n        if (!dame && sum >= U) {\n          ok = 1;\n          res = k;\n          break;\n        }\n        int x = S&-S, y=S+x;\n        S = ((S & ~y) / x >> 1) | y;\n      }\n      if (ok) break;\n    }\n    cout << res << endl;\n  }\n}", "problem_context": "Problem D: Course Planning for Lazy Students\n\n会津大学では2009年度より、授業履修に関する新しい制度を開始した。新制度では必修科目を撤廃���、それぞれの進路を考慮して科目を自由に選択できるようになった。\n\nしかし、どの科目も無条件で履修できるわけではなく、特定の科目を履修するためには、先修条件を満たしている必要がある。下図に履修計画表の一部の例を示す：\n\n図の長方形が１つの科目を表し科目名と単位数を含んでいる。図の矢印が先修条件を表す。矢印の意味は、矢印の終点で指されている科目を履修するためには、その矢印の始点を示す科目を修得している必要がある。例えば、Linear Algebra II (線形代数２)を履修するためには、Linear Algebra I (線形代数１)を修得している必要がある。また、Applied Algebra (応用代数)を履修するためには、Linear Algebra I と Discrete Systems (離散系論)の両方を修得している必要がある。\n\nさて、履修登録計画において卒業に要する最低限の合計単位数 U を満たす履修科目の組み合わせは、怠慢な学生にとって興味深いものである。\n\nあなたの仕事は、与えられた履修計画表と U を読み込み、最低限の履修科目数を報告するプログラムを作成することである。これは計画であるため、履修登録した科目は必ず単位を修得できるものと仮定する。\n\nInput\n\n入力は複数のデータセットからなる。各データセットは以下の形式で与えられる：\n\nn U\n\nc0 k0 r01 r02 ... r0k0\n\nc1 k1 r11 r12 ... r1k1\n\n.\n\n.\n\ncn-1 kn-1 r(n-1)1 r(n-1)2 ... r(n-1)kn-1\n\nn (1 ≤ n ≤ 20) は履修計画表が含む科目の数を示す整数である。科目には 0 から n-1 までの番号が割り当てられているものとし、以下 i 番目の科目を科目 i と呼ぶことにする。\n\nU (1 ≤ U ≤ 100) は必要な合計単位数を表す整数である。\n\nci (1 ≤ ci ≤ 10)は科目 i の単位数を示す。次の ki (0 ≤ ki ≤ 5) は科目 i の先修科目の数を示す。それに続く ri1 ri2 ... riki は科目 i の先修科目の科目番号を示す。\n\nある科目から先修条件を表す矢印を１つ以上たどり、再びその科目に戻るような入力は与えられない。また、U を満たす科目の組み合わせが必ず存在すると仮定してよい。\n\nn と U がともに 0 のとき入力の終わりを示す。データセットの数は 100 を超えない。\n\nOutput\n\n各データセットについて、最低限必要な科目数を１行に出力せよ。\n\nSample Input\n\n4 4\n1 0\n3 2 0 2\n2 0\n2 0\n3 6\n1 0\n3 2 0 2\n2 0\n0 0\n\nOutput for the Sample Input\n\n2\n3", "sample_input": "4 4\n1 0\n3 2 0 2\n2 0\n2 0\n3 6\n1 0\n3 2 0 2\n2 0\n0 0\n"}, "reference_outputs": ["2\n3\n"], "source_document_id": "p00618", "source_text": "Problem D: Course Planning for Lazy Students\n\n会津大学では2009年度より、授業履修に関する新しい制度を開始した。新制度では必修科目を撤廃し、それぞれの進路を考慮して科目を自由に選択できるようになった。\n\nしかし、どの科目も無条件で履修できるわけではなく、特定の科目を履修するためには、先修条件を満たしている必要がある。下図に履修計画表の一部の例を示す：\n\n図の長方形が１つの科目を表し科目名と単位数を含んでいる。図の矢印が先修条件を表す。矢印の意味は、矢印の終点で指されている科目を履修するためには、その矢印の始点を示す科目を修得している必要がある。例えば、Linear Algebra II (線形代数２)を履修するためには、Linear Algebra I (線形代数１)を修得している必要がある。また、Applied Algebra (応用代数)を履修するためには、Linear Algebra I と Discrete Systems (離散系論)の両方を修得している必要がある。\n\nさて、履修登録計画において卒業に要する最低限の合計単位数 U を満たす履修科目の組み合わせは、怠慢な学生にとって興味深いものである。\n\nあなたの仕事は、与えられた履修計画表と U を読み込み、最低限の履修科目数を報告するプログラムを作成することである。これは計画であるため、履修登録した科目は必ず単位を修得できるものと仮定する。\n\nInput\n\n入力は複数のデータセットからなる。各データセットは以下の形式で与えられる：\n\nn U\n\nc0 k0 r01 r02 ... r0k0\n\nc1 k1 r11 r12 ... r1k1\n\n.\n\n.\n\ncn-1 kn-1 r(n-1)1 r(n-1)2 ... r(n-1)kn-1\n\nn (1 ≤ n ≤ 20) は履修計画表が含む科目の数を示す整数である。科目には 0 から n-1 までの番号が割り当てられているものとし、以下 i 番目の科目を科目 i と呼ぶことにする。\n\nU (1 ≤ U ≤ 100) は必要な合計単位数を表す整数である。\n\nci (1 ≤ ci ≤ 10)は科目 i の単位数��示す。次の ki (0 ≤ ki ≤ 5) は科目 i の先修科目の数を示す。それに続く ri1 ri2 ... riki は科目 i の先修科目の科目番号を示す。\n\nある科目から先修条件を表す矢印を１つ以上たどり、再びその科目に戻るような入力は与えられない。また、U を満たす科目の組み合わせが必ず存在すると仮定してよい。\n\nn と U がともに 0 のとき入力の終わりを示す。データセットの数は 100 を超えない。\n\nOutput\n\n各データセットについて、最低限必要な科目数を１行に出力せよ。\n\nSample Input\n\n4 4\n1 0\n3 2 0 2\n2 0\n2 0\n3 6\n1 0\n3 2 0 2\n2 0\n0 0\n\nOutput for the Sample Input\n\n2\n3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1395, "cpu_time_ms": 1700, "memory_kb": 864}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s213436257", "group_id": "codeNet:p00653", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef vector<int>vi;\ntypedef vector<vi>vvi;\n\nconst int B=80;\nint H,W,Q;\nvi *fld,*bucket;\n\nbool solve(){\n    scanf(\"%d%d%d\",&H,&W,&Q);\n    if(H==0&&W==0&&Q==0)return false;\n    fld=new vi[H];\n    bucket=new vi[H/B+1];\n    fill_n(fld,H,vi(W));\n    fill_n(bucket,H/B+1,vi(W/B+1,INT_MAX));\n    vi latte(H/B+1,INT_MAX);\n    vi malta(W/B+1,INT_MAX);\n    for(int i=0;i<H;++i){\n        for(int j=0;j<W;++j){\n            int a;\n            scanf(\"%d\",&a);\n            fld[i][j]=a;\n            bucket[i/B][j/B]=min(bucket[i/B][j/B],a);\n            latte[i/B]=min(latte[i/B],a);\n            malta[j/B]=min(malta[j/B],a);\n        }\n    }\n\n\n    while(Q--){\n        int x1,y1,x2,y2;\n        scanf(\"%d%d%d%d\",&y1,&x1,&y2,&x2);\n        ++y2;++x2;\n\n        int mi=INT_MAX;\n        if(mi<latte[y1/B])y1=(y1/B+1)*B;\n        while(y1<y2&&y1%B!=0){\n            for(int j=x1;j<x2;++j){\n                if(mi<bucket[y1/B][j/B]){\n                    j=(j/B+1)*B-1;\n                    continue;\n                }\n                mi=min(mi,fld[y1][j]);\n            }\n            ++y1;\n        }\n        //if(mi<latte[y2/B]&&y2%B!=0)y2=(y2/B-1)*B;\n        while(y1<y2&&y2%B!=0){\n            --y2;\n            for(int j=x1;j<x2;++j){\n                if(mi<bucket[y2/B][j/B]){\n                    j=(j/B+1)*B-1;\n                    continue;\n                }\n                mi=min(mi,fld[y2][j]);\n            }\n        }\n        if(mi<malta[x1/B])x1=(x1/B+1)*B;\n        while(x1<x2&&x1%B!=0){\n            for(int i=y1;i<y2;++i){\n                if(mi<bucket[i/B][x1/B]){\n                    i=(i/B+1)*B-1;\n                    continue;\n                }\n                mi=min(mi,fld[i][x1]);\n            }\n            ++x1;\n        }\n        //if(mi<malta[x2/B]&&x2%B!=0)x2=(x2/B-1)*B;\n        while(x1<x2&&x2%B!=0){\n            --x2;\n            for(int i=y1;i<y2;++i){\n                if(mi<bucket[i/B][x2/B]){\n                    i=(i/B+1)*B-1;\n                    continue;\n                }\n                mi=min(mi,fld[i][x2]);\n            }\n        }\n        int bx1=x1/B,bx2=x2/B;\n\n        while(y1<y2){\n            int by1=y1/B;\n            if(latte[by1]<mi){\n                for(int j=bx1;j<bx2;++j)\n                    mi=min(mi,bucket[by1][j]);\n            }\n            y1+=B;\n        }\n\n        printf(\"%d\\n\",mi);\n    }\n    return true;\n}\nint main(){\n    while(solve());\n}", "language": "C++", "metadata": {"date": 1429722359, "filename_ext": "cpp", "original_language": "C++", "problem_description_relpath": "problem_descriptions/p00653.html", "problem_id": "p00653", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p00653/input.txt", "sample_output_relpath": "derived/input_output/data/p00653/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p00653/C++/s213436257.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s213436257", "user_id": "u113716229"}, "prompt_components": {"gold_output": "1\n1\n4\n2\n1\n1\n6\n5\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef vector<int>vi;\ntypedef vector<vi>vvi;\n\nconst int B=80;\nint H,W,Q;\nvi *fld,*bucket;\n\nbool solve(){\n    scanf(\"%d%d%d\",&H,&W,&Q);\n    if(H==0&&W==0&&Q==0)return false;\n    fld=new vi[H];\n    bucket=new vi[H/B+1];\n    fill_n(fld,H,vi(W));\n    fill_n(bucket,H/B+1,vi(W/B+1,INT_MAX));\n    vi latte(H/B+1,INT_MAX);\n    vi malta(W/B+1,INT_MAX);\n    for(int i=0;i<H;++i){\n        for(int j=0;j<W;++j){\n            int a;\n            scanf(\"%d\",&a);\n            fld[i][j]=a;\n            bucket[i/B][j/B]=min(bucket[i/B][j/B],a);\n            latte[i/B]=min(latte[i/B],a);\n            malta[j/B]=min(malta[j/B],a);\n        }\n    }\n\n\n    while(Q--){\n        int x1,y1,x2,y2;\n        scanf(\"%d%d%d%d\",&y1,&x1,&y2,&x2);\n        ++y2;++x2;\n\n        int mi=INT_MAX;\n        if(mi<latte[y1/B])y1=(y1/B+1)*B;\n        while(y1<y2&&y1%B!=0){\n            for(int j=x1;j<x2;++j){\n                if(mi<bucket[y1/B][j/B]){\n                    j=(j/B+1)*B-1;\n                    continue;\n                }\n                mi=min(mi,fld[y1][j]);\n            }\n            ++y1;\n        }\n        //if(mi<latte[y2/B]&&y2%B!=0)y2=(y2/B-1)*B;\n        while(y1<y2&&y2%B!=0){\n            --y2;\n            for(int j=x1;j<x2;++j){\n                if(mi<bucket[y2/B][j/B]){\n                    j=(j/B+1)*B-1;\n                    continue;\n                }\n                mi=min(mi,fld[y2][j]);\n            }\n        }\n        if(mi<malta[x1/B])x1=(x1/B+1)*B;\n        while(x1<x2&&x1%B!=0){\n            for(int i=y1;i<y2;++i){\n                if(mi<bucket[i/B][x1/B]){\n                    i=(i/B+1)*B-1;\n                    continue;\n                }\n                mi=min(mi,fld[i][x1]);\n            }\n            ++x1;\n        }\n        //if(mi<malta[x2/B]&&x2%B!=0)x2=(x2/B-1)*B;\n        while(x1<x2&&x2%B!=0){\n            --x2;\n            for(int i=y1;i<y2;++i){\n                if(mi<bucket[i/B][x2/B]){\n                    i=(i/B+1)*B-1;\n                    continue;\n                }\n                mi=min(mi,fld[i][x2]);\n            }\n        }\n        int bx1=x1/B,bx2=x2/B;\n\n        while(y1<y2){\n            int by1=y1/B;\n            if(latte[by1]<mi){\n                for(int j=bx1;j<bx2;++j)\n                    mi=min(mi,bucket[by1][j]);\n            }\n            y1+=B;\n        }\n\n        printf(\"%d\\n\",mi);\n    }\n    return true;\n}\nint main(){\n    while(solve());\n}", "problem_context": "Problem G: School of Killifish\n\nJon is the leader of killifish.\nJon have a problem in these days.\nJon has a plan to built new town in a pond.\nOf course new towns should have a school for children. But there are some natural enemies in a pond.\nJon thinks that the place of a school should be the safest place in a pond for children.\n\nJon has asked by some construction companies to make construction plans and Jon has q construction plans now.\nThe plan is selected by voting. But for each plan, the safest place for the school should be decided before voting.\n\nA pond is expressed by a 2D grid whose size is r*c.\nThe grid has r rows and c columns. The coordinate of the top-left cell is (0,0). The coordinate of the bottom-right cell is expressed as (r-1,c-1).\nEach cell has an integer which implies a dangerousness.\nThe lower value implies safer than the higher value.\nq plans are given by four integer r1 ,c1 ,r2 and c2 which represent the subgrid.\nThe top-left corner is (r1,c1) and the bottom-right corner is (r2,c2).\n\nYou have the r*c grid and q plans. Your task is to find the safest point for each plan.\nYou should find the lowest value in the subgrid.\n\nInput\n\nInput consists of multiple datasets.\n\nEach dataset is given in the following format.\n\nr c q\ngrid0,0 grid0,1 ... grid0,c-1\n...\ngridr-1,0 ... gridr-1,c-1\nr1 c1 r2 c2\n...\nr1 c1 r2 c2\n\nThe first line consists of 3 integers, r ,c , and q .\nNext r lines have c integers.\ngridi,j means a dangerousness of the grid.\nAnd you can assume 0 ≤ gridi,j ≤ 231-1.\nAfter that, q queries, r1, c1, r2 and c2, are given.\n\nThe dataset satisfies following constraints.\n\nr*c ≤ 106\n\nq ≤ 104\n\nFor each query, you can assume that r1≤ r2 and c1 ≤ c2 .\n\nIf r * c ≤ 250000, q ≤ 100 is assured.\nIf r * c > 250000, Input consists of only that case.\n\nOutput\n\nFor each query you should print the lowest value in the subgrid in a line.\n\nSample input\n\n3 3 4\n1 2 3\n4 2 2\n2 1 1\n0 0 2 2\n0 0 1 1\n1 0 1 0\n0 1 1 2\n1 10 4\n1 2 3 4 5 6 7 8 9 10\n0 0 0 9\n0 0 0 4\n0 5 0 9\n0 4 0 5\n0 0 0\n\nSample output\n\n1\n1\n4\n2\n1\n1\n6\n5", "sample_input": "3 3 4\n1 2 3\n4 2 2\n2 1 1\n0 0 2 2\n0 0 1 1\n1 0 1 0\n0 1 1 2\n1 10 4\n1 2 3 4 5 6 7 8 9 10\n0 0 0 9\n0 0 0 4\n0 5 0 9\n0 4 0 5\n0 0 0\n"}, "reference_outputs": ["1\n1\n4\n2\n1\n1\n6\n5\n"], "source_document_id": "p00653", "source_text": "Problem G: School of Killifish\n\nJon is the leader of killifish.\nJon have a problem in these days.\nJon has a plan to built new town in a pond.\nOf course new towns should have a school for children. But there are some natural enemies in a pond.\nJon thinks that the place of a school should be the safest place in a pond for children.\n\nJon has asked by some construction companies to make construction plans and Jon has q construction plans now.\nThe plan is selected by voting. But for each plan, the safest place for the school should be decided before voting.\n\nA pond is expressed by a 2D grid whose size is r*c.\nThe grid has r rows and c columns. The coordinate of the top-left cell is (0,0). The coordinate of the bottom-right cell is expressed as (r-1,c-1).\nEach cell has an integer which implies a dangerousness.\nThe lower value implies safer than the higher value.\nq plans are given by four integer r1 ,c1 ,r2 and c2 which represent the subgrid.\nThe top-left corner is (r1,c1) and the bottom-right corner is (r2,c2).\n\nYou have the r*c grid and q plans. Your task is to find the safest point for each plan.\nYou should find the lowest value in the subgrid.\n\nInput\n\nInput consists of multiple datasets.\n\nEach dataset is given in the following format.\n\nr c q\ngrid0,0 grid0,1 ... grid0,c-1\n...\ngridr-1,0 ... gridr-1,c-1\nr1 c1 r2 c2\n...\nr1 c1 r2 c2\n\nThe first line consists of 3 integers, r ,c , and q .\nNext r lines have c integers.\ngridi,j means a dangerousness of the grid.\nAnd you can assume 0 ≤ gridi,j ≤ 231-1.\nAfter that, q queries, r1, c1, r2 and c2, are given.\n\nThe dataset satisfies following constraints.\n\nr*c ≤ 106\n\nq ≤ 104\n\nFor each query, you can assume that r1≤ r2 and c1 ≤ c2 .\n\nIf r * c ≤ 250000, q ≤ 100 is assured.\nIf r * c > 250000, Input consists of only that case.\n\nOutput\n\nFor each query you should print the lowest value in the subgrid in a line.\n\nSample input\n\n3 3 4\n1 2 3\n4 2 2\n2 1 1\n0 0 2 2\n0 0 1 1\n1 0 1 0\n0 1 1 2\n1 10 4\n1 2 3 4 5 6 7 8 9 10\n0 0 0 9\n0 0 0 4\n0 5 0 9\n0 4 0 5\n0 0 0\n\nSample output\n\n1\n1\n4\n2\n1\n1\n6\n5", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2409, "cpu_time_ms": 19370, "memory_kb": 56632}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s744124738", "group_id": "codeNet:p00660", "input_text": "#include <iostream>\n#include <string>\n#include <algorithm>\n#include <cstdlib>\n#include <cassert>\nusing namespace std;\nint dicea[6],diceb[6];\nstring str[21];\nint mk_num(string *);\n\nvoid lr_hanten(string a[]){\n  for(int i=0;i<7;i++)\n    for(int j=0;j<7/2;j++) swap(a[i][j],a[i][6-j]);\n}\n\nvoid ud_hanten(string a[]){\n  for(int i=0;i<7;i++) \n    for(int j=0;j<7/2;j++) swap(a[j][i],a[6-j][i]);\n}\n\nvoid rol_90(string a[]){\n  string b[7];\n  for(int i=0;i<7;i++)\n    for(int j=0;j<7;j++) {\n      b[i] += a[j][6-i];\n      if(b[i][j] == '-') b[i][j] = '|';\n      else if(b[i][j] =='|') b[i][j] = '-';\n    }\n  for(int i=0;i<7;i++) a[i] = b[i];\n}\n\nvoid choice(string num[],int x,int y){\n  for(int i=0;i<7;i++){\n    num[i]=\"\";\n    for(int j=0;j<7;j++) num[i]+=str[y+i][x+j];\n  }\n}\n\nvoid mk_dice(){\n  string num[2][7];\n  //ue\n  choice(num[0],7,0),choice(num[1],36,0);\n  lr_hanten(num[0]),lr_hanten(num[1]);\n  dicea[0] = mk_num(num[0]),diceb[0]=mk_num(num[1]);\n  \n  //hidari\n  choice(num[0],0,7),choice(num[1],29,7);\n  lr_hanten(num[0]),lr_hanten(num[1]);\n  rol_90(num[0]),rol_90(num[1]);\n  dicea[1] = mk_num(num[0]),diceb[1] = mk_num(num[1]);\n\n  //mid_hidari\n  choice(num[0],7,7),choice(num[1],36,7);\n  lr_hanten(num[0]),lr_hanten(num[1]);\n  dicea[2] = mk_num(num[0]),diceb[2] = mk_num(num[1]);\n\n  //mid_migi\n  choice(num[0],14,7),choice(num[1],43,7);\n  lr_hanten(num[0]),lr_hanten(num[1]);\n  for(int i=0;i<3;i++)rol_90(num[0]),rol_90(num[1]);\n  dicea[3] = mk_num(num[0]),diceb[3] = mk_num(num[1]);\n\n  //migi\n  choice(num[0],21,7),choice(num[1],50,7);\n  lr_hanten(num[0]),lr_hanten(num[1]);\n  dicea[4] = mk_num(num[0]),diceb[4] = mk_num(num[1]);\n\n\n  //sita\n  choice(num[0],7,14),choice(num[1],36,14);\n  ud_hanten(num[0]),ud_hanten(num[1]);\n  lr_hanten(num[0]),lr_hanten(num[1]);\n  dicea[5] = mk_num(num[0]),diceb[5] = mk_num(num[1]);\n}\n\nint main(){\n  srand((unsigned)time(NULL));\n  while(1) {\n    for(int i=0;i<21;i++){\n      cin >> str[i];\n      if(str[i]==\"0\")break;\n    }\n    if(str[0]==\"0\")break;\n    mk_dice();\n    int a=0,b=0;\n    for(int i=0;i<6;i++) assert(dicea[i]!=-1 && diceb[i]!=-1);\n\n    int arr[6]={};\n    for(int i=0;i<100000;i++){\n      arr[rand()%6]++;\n      if(dicea[rand()%6] > diceb[rand()%6]) a++;\n      else if(dicea[rand()%6]<diceb[rand()%6])b++;\n    }\n    // for(int i=0;i<6;i++) cout <<arr[i]<<\" \";cout<<endl;\n    if(a>b-500) cout<<\"HIGH\"<<endl;\n    else cout <<\"LOW\"<<endl;\n  }\n\n}\n\nint mk_num(string a[]){\n  if(a[1]==\"#.....#\" &&\n     a[2]==\"#...|.#\") return 1;\n\n  if(a[1]==\"#..-..#\" && \n     a[2]==\"#...|.#\" &&   \n     a[3]==\"#..-..#\" &&\n     a[4]==\"#.|...#\" &&\n     a[5]==\"#..-..#\") return 2;\n\n  if(a[1]==\"#..-..#\" && \n     a[2]==\"#...|.#\" &&   \n     a[3]==\"#..-..#\" &&\n     a[4]==\"#...|.#\" &&\n     a[5]==\"#..-..#\") return 3;\n\n  if(a[1]==\"#.....#\" &&\n     a[5]==\"#.....#\") return 4;\n\n  if(a[1]==\"#..-..#\" && \n     a[2]==\"#.|...#\" &&\n     a[3]==\"#..-..#\" &&\n     a[4]==\"#...|.#\" &&\n     a[5]==\"#..-..#\") return 5;\n\n  if(a[1]==\"#..-..#\" && \n     a[2]==\"#.|...#\" &&\n     a[3]==\"#..-..#\" &&\n     a[4]==\"#.|.|.#\" &&\n     a[5]==\"#..-..#\") return 6;\n\n  if(a[3]==\"#.....#\" &&\n     a[5]==\"#.....#\") return 7;\n\n  if(a[1]==\"#..-..#\" && \n     a[2]==\"#.|.|.#\" &&\n     a[3]==\"#..-..#\" &&\n     a[4]==\"#.|.|.#\" &&\n     a[5]==\"#..-..#\") return 8;\n\n  if(a[1]==\"#..-..#\" && \n     a[2]==\"#.|.|.#\" &&\n     a[3]==\"#..-..#\" &&\n     a[4]==\"#...|.#\" &&\n     a[5]==\"#..-..#\") return 9;\n  return -1;\n}", "language": "C++", "metadata": {"date": 1452326549, "filename_ext": "cpp", "original_language": "C++", "problem_description_relpath": "problem_descriptions/p00660.html", "problem_id": "p00660", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p00660/input.txt", "sample_output_relpath": "derived/input_output/data/p00660/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p00660/C++/s744124738.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s744124738", "user_id": "u952951927"}, "prompt_components": {"gold_output": "LOW\nHIGH\nHIGH\nLOW\n", "input_to_evaluate": "#include <iostream>\n#include <string>\n#include <algorithm>\n#include <cstdlib>\n#include <cassert>\nusing namespace std;\nint dicea[6],diceb[6];\nstring str[21];\nint mk_num(string *);\n\nvoid lr_hanten(string a[]){\n  for(int i=0;i<7;i++)\n    for(int j=0;j<7/2;j++) swap(a[i][j],a[i][6-j]);\n}\n\nvoid ud_hanten(string a[]){\n  for(int i=0;i<7;i++) \n    for(int j=0;j<7/2;j++) swap(a[j][i],a[6-j][i]);\n}\n\nvoid rol_90(string a[]){\n  string b[7];\n  for(int i=0;i<7;i++)\n    for(int j=0;j<7;j++) {\n      b[i] += a[j][6-i];\n      if(b[i][j] == '-') b[i][j] = '|';\n      else if(b[i][j] =='|') b[i][j] = '-';\n    }\n  for(int i=0;i<7;i++) a[i] = b[i];\n}\n\nvoid choice(string num[],int x,int y){\n  for(int i=0;i<7;i++){\n    num[i]=\"\";\n    for(int j=0;j<7;j++) num[i]+=str[y+i][x+j];\n  }\n}\n\nvoid mk_dice(){\n  string num[2][7];\n  //ue\n  choice(num[0],7,0),choice(num[1],36,0);\n  lr_hanten(num[0]),lr_hanten(num[1]);\n  dicea[0] = mk_num(num[0]),diceb[0]=mk_num(num[1]);\n  \n  //hidari\n  choice(num[0],0,7),choice(num[1],29,7);\n  lr_hanten(num[0]),lr_hanten(num[1]);\n  rol_90(num[0]),rol_90(num[1]);\n  dicea[1] = mk_num(num[0]),diceb[1] = mk_num(num[1]);\n\n  //mid_hidari\n  choice(num[0],7,7),choice(num[1],36,7);\n  lr_hanten(num[0]),lr_hanten(num[1]);\n  dicea[2] = mk_num(num[0]),diceb[2] = mk_num(num[1]);\n\n  //mid_migi\n  choice(num[0],14,7),choice(num[1],43,7);\n  lr_hanten(num[0]),lr_hanten(num[1]);\n  for(int i=0;i<3;i++)rol_90(num[0]),rol_90(num[1]);\n  dicea[3] = mk_num(num[0]),diceb[3] = mk_num(num[1]);\n\n  //migi\n  choice(num[0],21,7),choice(num[1],50,7);\n  lr_hanten(num[0]),lr_hanten(num[1]);\n  dicea[4] = mk_num(num[0]),diceb[4] = mk_num(num[1]);\n\n\n  //sita\n  choice(num[0],7,14),choice(num[1],36,14);\n  ud_hanten(num[0]),ud_hanten(num[1]);\n  lr_hanten(num[0]),lr_hanten(num[1]);\n  dicea[5] = mk_num(num[0]),diceb[5] = mk_num(num[1]);\n}\n\nint main(){\n  srand((unsigned)time(NULL));\n  while(1) {\n    for(int i=0;i<21;i++){\n      cin >> str[i];\n      if(str[i]==\"0\")break;\n    }\n    if(str[0]==\"0\")break;\n    mk_dice();\n    int a=0,b=0;\n    for(int i=0;i<6;i++) assert(dicea[i]!=-1 && diceb[i]!=-1);\n\n    int arr[6]={};\n    for(int i=0;i<100000;i++){\n      arr[rand()%6]++;\n      if(dicea[rand()%6] > diceb[rand()%6]) a++;\n      else if(dicea[rand()%6]<diceb[rand()%6])b++;\n    }\n    // for(int i=0;i<6;i++) cout <<arr[i]<<\" \";cout<<endl;\n    if(a>b-500) cout<<\"HIGH\"<<endl;\n    else cout <<\"LOW\"<<endl;\n  }\n\n}\n\nint mk_num(string a[]){\n  if(a[1]==\"#.....#\" &&\n     a[2]==\"#...|.#\") return 1;\n\n  if(a[1]==\"#..-..#\" && \n     a[2]==\"#...|.#\" &&   \n     a[3]==\"#..-..#\" &&\n     a[4]==\"#.|...#\" &&\n     a[5]==\"#..-..#\") return 2;\n\n  if(a[1]==\"#..-..#\" && \n     a[2]==\"#...|.#\" &&   \n     a[3]==\"#..-..#\" &&\n     a[4]==\"#...|.#\" &&\n     a[5]==\"#..-..#\") return 3;\n\n  if(a[1]==\"#.....#\" &&\n     a[5]==\"#.....#\") return 4;\n\n  if(a[1]==\"#..-..#\" && \n     a[2]==\"#.|...#\" &&\n     a[3]==\"#..-..#\" &&\n     a[4]==\"#...|.#\" &&\n     a[5]==\"#..-..#\") return 5;\n\n  if(a[1]==\"#..-..#\" && \n     a[2]==\"#.|...#\" &&\n     a[3]==\"#..-..#\" &&\n     a[4]==\"#.|.|.#\" &&\n     a[5]==\"#..-..#\") return 6;\n\n  if(a[3]==\"#.....#\" &&\n     a[5]==\"#.....#\") return 7;\n\n  if(a[1]==\"#..-..#\" && \n     a[2]==\"#.|.|.#\" &&\n     a[3]==\"#..-..#\" &&\n     a[4]==\"#.|.|.#\" &&\n     a[5]==\"#..-..#\") return 8;\n\n  if(a[1]==\"#..-..#\" && \n     a[2]==\"#.|.|.#\" &&\n     a[3]==\"#..-..#\" &&\n     a[4]==\"#...|.#\" &&\n     a[5]==\"#..-..#\") return 9;\n  return -1;\n}", "problem_context": "Problem B: High & Low Cube\n\n僕は近所の小学生たちと一緒に夏祭りに来ていた。有り体に言えば保護者役だが、出店の焼きそばやたこ焼きなんかが焼ける匂い、時折聞こえる打ち上げ花火の音などは、この歳になっても心が踊るものがある。が、好奇心旺盛な子供たちがはぐれないように、今日はしっかり見守っていないと。\n\n子供たちはとある出店に興味を持ったようだった。覗き込んでみると、そこでは出店のおじさんとサイコロを使ったゲームをして、勝てば景品が貰えることになっていた。そのゲームは、 High & Low と呼ばれる単純なものだ。参加者とおじさんは1個ずつサイコロを振るが、その前に参加者は、自分の出目がおじさんの出目より大きいか小さいかを予想する。予想が当たれば勝利であり、同じ目が出た場合はどちらもサイコロを振り直す。\n\nこのゲームの少し厄介なところは、参加者のサイコロとおじさんのサイコロが違うものであるかもしれない、という点だ。参加者はあらかじめ両者のサイコロの展開図を見ることができるので、それをヒントに予想することになる。\n\nつまり、簡単な確率の計算だ。とはいえ確率は高校数学の範囲で、小学生にはちょっと荷が重いかもしれない。子供たちの中で一番利発そうな子でさえ、三つ編みにした髪を揺らしながら考え込んでいる。もうすぐ僕に助けを求めてくることだろう。さて、たまにはオトナらしいところを見せてあげようではないか。\n\nInput\n\n入力は複数のケースからなる。\n\n各ケースでは、サイコロの展開図が21×57のグリッドで与えられる。\n\n最初の21×28（(0,0)が左上,(20,27)が右下）のグリッドが参加者のサイコロを表す。\n\n最後の21×28（(0,29)が左上,(20,56)が右下）がおじさんのサイコロを表す。\n\n参加者のサイコロの各面は(0,7)、(7,0)、(7,7)、(7,14)、(7,21)、(14,7)を左上とする7×7のサブグリッドで与えられている。\n\n展開図に書かれている数字は、それぞれ元の数字を\n\n左右反転\n\n左右反転、そのあとで反時計回りに90度回転\n\n左右反転\n\n左右反転、そのあとで反時計回りに270度回転\n\n左右反転\n\n上下反転、そのあとで左右反転\n\nさせたものである。\n\nおじさんのサイコロの各面は(0,36)、(7,29)、(7,36)、(7,43)、(7,50)、(14,36)を左上とする７×７のサブグリッドで与えられている。\n\nおじさんのサイコロの展開図に書かれている数字は参加者のサイコロと同じ規則で描かれている。\n\nサイコロの各面には1から9までの中のどれかが書かれている。\n数字は以下のような7x7のグリッドで与えられる。\n#######\n#.....#\n#...|.#\n#.....#\n#...|.#\n#..-..#\n#######\n\n#######\n#..-..#\n#...|.#\n#..-..#\n#.|...#\n#..-..#\n#######\n\n#######\n#..-..#\n#...|.#\n#..-..#\n#...|.#\n#..-..#\n#######\n\n#######\n#.....#\n#.|.|.#\n#..-..#\n#...|.#\n#.....#\n#######\n\n#######\n#..-..#\n#.|...#\n#..-..#\n#...|.#\n#..-..#\n#######\n\n#######\n#..-..#\n#.|...#\n#..-..#\n#.|.|.#\n#..-..#\n#######\n\n#######\n#..-..#\n#...|.#\n#.....#\n#...|.#\n#.....#\n#######\n\n#######\n#..-..#\n#.|.|.#\n#..-..#\n#.|.|.#\n#..-..#\n#######\n\n#######\n#..-..#\n#.|.|.#\n#..-..#\n#...|.#\n#..-..#\n#######\n\nただし上記の数字を90度、または270度回転させた時、\"|\"と\"-\"は入れ替わっている。\n\n入力の終わりは1つの0からなる行によって与えられる\n\n入力として与えられるサイコロは必ず正しい物である。\nまた決着がつかないようなサイコロは与えられない。\n\nOutput\n\n\"HIGH\"になる場合と\"LOW\"になる場合で確率が高いほうを1行に出力せよ。\n両者の確率が同じ場合は\"HIGH\"を出力せよ。\n\nSample input\n\n.......#######......................#######..............\n.......#.....#......................#..-..#..............\n.......#.|...#......................#.|.|.#..............\n.......#.....#......................#..-..#..............\n.......#.|...#......................#.|...#..............\n.......#..-..#......................#..-..#..............\n.......#######......................#######..............\n############################.############################\n#.....##..-..##.....##..-..#.#.....##..-..##.....##..-..#\n#.-.-.##...|.##.-.-.##.|.|.#.#.....##.|.|.##.-.-.##.|.|.#\n#|.|.|##..-..##|.|.|##..-..#.#....|##..-..##|.|.|##..-..#\n#...-.##.|...##...-.##.|.|.#.#.-.-.##.|...##...-.##.|...#\n#.....##..-..##.....##..-..#.#.....##..-..##.....##..-..#\n############################.############################\n.......#######......................#######..............\n.......#..-..#......................#..-..#..............\n.......#.|...#......................#.|...#..............\n.......#..-..#......................#..-..#..............\n.......#.|.|.#......................#...|.#..............\n.......#..-..#......................#..-..#..............\n.......#######......................#######..............\n.......#######......................#######..............\n.......#..-..#......................#..-..#..............\n.......#.|...#......................#...|.#..............\n.......#..-..#......................#..-..#..............\n.......#...|.#......................#.|.|.#..............\n.......#..-..#......................#..-..#..............\n.......#######......................#######..............\n############################.############################\n#.....##..-..##.....##..-..#.#.....##..-..##.....##..-..#\n#.-.-.##...|.##.-.-.##.|.|.#.#...-.##...|.##.-...##.|.|.#\n#|.|.|##..-..##|.|.|##..-..#.#|.|.|##..-..##|.|.|##..-..#\n#.-.-.##.|...##...-.##.|...#.#.-...##.|.|.##.-.-.##.|...#\n#.....##..-..##.....##..-..#.#.....##..-..##.....##..-..#\n############################.############################\n.......#######......................#######..............\n.......#..-..#......................#..-..#..............\n.......#...|.#......................#.|...#..............\n.......#..-..#......................#..-..#..............\n.......#.|...#......................#...|.#..............\n.......#..-..#......................#..-..#..............\n.......#######......................#######..............\n.......#######......................#######..............\n.......#..-..#......................#..-..#..............\n.......#.|...#......................#.|.|.#..............\n.......#..-..#......................#..-..#..............\n.......#...|.#......................#.|...#..............\n.......#..-..#......................#..-..#..............\n.......#######......................#######..............\n############################.############################\n#.....##..-..##.....##..-..#.#.....##..-..##.....##.....#\n#.-.-.##.|.|.##.-.-.##...|.#.#.....##.|.|.##...-.##.|...#\n#|.|.|##..-..##|....##..-..#.#....|##..-..##|.|.|##.....#\n#.-.-.##.|.|.##.....##.|.|.#.#.-.-.##.|.|.##.-...##.|...#\n#.....##..-..##.....##..-..#.#.....##..-..##.....##..-..#\n############################.############################\n.......#######......................#######..............\n.......#..-..#......................#..-..#..............\n.......#.|.|.#......................#.|...#..............\n.......#..-..#......................#..-..#..............\n.......#...|.#......................#...|.#..............\n.......#..-..#......................#..-..#..............\n.......#######......................#######..............\n.......#######......................#######..............\n.......#..-..#......................#..-..#..............\n.......#.|...#......................#.|.|.#..............\n.......#..-..#......................#..-..#..............\n.......#...|.#......................#.|...#..............\n.......#..-..#......................#..-..#..............\n.......#######......................#######..............\n############################.############################\n#.....##..-..##.....##..-..#.#.....##..-..##.....##..-..#\n#.-.-.##...|.##.-.-.##.|.|.#.#.-...##.|.|.##.-...##.|.|.#\n#|.|.|##..-..##|.|.|##..-..#.#|.|.|##..-..##|.|.|##..-..#\n#...-.##.|...##.-.-.##.|.|.#.#.-.-.##.|...##.-.-.##.|.|.#\n#.....##..-..##.....##..-..#.#.....##..-..##.....##..-..#\n############################.############################\n.......#######......................#######..............\n.......#..-..#......................#..-..#..............\n.......#...|.#......................#.|.|.#..............\n.......#..-..#......................#..-..#..............\n.......#.|...#......................#...|.#..............\n.......#..-..#......................#..-..#..............\n.......#######......................#######..............\n0\n\nSample output\n\nLOW\nHIGH\nHIGH\nLOW\n\nThe University of Aizu Programming Contest 2011 Summer\n\n原案、問題文: Takashi Tayama", "sample_input": ".......#######......................#######..............\n.......#.....#......................#..-..#..............\n.......#.|...#......................#.|.|.#..............\n.......#.....#......................#..-..#..............\n.......#.|...#......................#.|...#..............\n.......#..-..#......................#..-..#..............\n.......#######......................#######..............\n############################.############################\n#.....##..-..##.....##..-..#.#.....##..-..##.....##..-..#\n#.-.-.##...|.##.-.-.##.|.|.#.#.....##.|.|.##.-.-.##.|.|.#\n#|.|.|##..-..##|.|.|##..-..#.#....|##..-..##|.|.|##..-..#\n#...-.##.|...##...-.##.|.|.#.#.-.-.##.|...##...-.##.|...#\n#.....##..-..##.....##..-..#.#.....##..-..##.....##..-..#\n############################.############################\n.......#######......................#######..............\n.......#..-..#......................#..-..#..............\n.......#.|...#......................#.|...#..............\n.......#..-..#......................#..-..#..............\n.......#.|.|.#......................#...|.#..............\n.......#..-..#......................#..-..#..............\n.......#######......................#######..............\n.......#######......................#######..............\n.......#..-..#......................#..-..#..............\n.......#.|...#......................#...|.#..............\n.......#..-..#......................#..-..#..............\n.......#...|.#......................#.|.|.#..............\n.......#..-..#......................#..-..#..............\n.......#######......................#######..............\n############################.############################\n#.....##..-..##.....##..-..#.#.....##..-..##.....##..-..#\n#.-.-.##...|.##.-.-.##.|.|.#.#...-.##...|.##.-...##.|.|.#\n#|.|.|##..-..##|.|.|##..-..#.#|.|.|##..-..##|.|.|##..-..#\n#.-.-.##.|...##...-.##.|...#.#.-...##.|.|.##.-.-.##.|...#\n#.....##..-..##.....##..-..#.#.....##..-..##.....##..-..#\n############################.############################\n.......#######......................#######..............\n.......#..-..#......................#..-..#..............\n.......#...|.#......................#.|...#..............\n.......#..-..#......................#..-..#..............\n.......#.|...#......................#...|.#..............\n.......#..-..#......................#..-..#..............\n.......#######......................#######..............\n.......#######......................#######..............\n.......#..-..#......................#..-..#..............\n.......#.|...#......................#.|.|.#..............\n.......#..-..#......................#..-..#..............\n.......#...|.#......................#.|...#..............\n.......#..-..#......................#..-..#..............\n.......#######......................#######..............\n############################.############################\n#.....##..-..##.....##..-..#.#.....##..-..##.....##.....#\n#.-.-.##.|.|.##.-.-.##...|.#.#.....##.|.|.##...-.##.|...#\n#|.|.|##..-..##|....##..-..#.#....|##..-..##|.|.|##.....#\n#.-.-.##.|.|.##.....##.|.|.#.#.-.-.##.|.|.##.-...##.|...#\n#.....##..-..##.....##..-..#.#.....##..-..##.....##..-..#\n############################.############################\n.......#######......................#######..............\n.......#..-..#......................#..-..#..............\n.......#.|.|.#......................#.|...#..............\n.......#..-..#......................#..-..#..............\n.......#...|.#......................#...|.#..............\n.......#..-..#......................#..-..#..............\n.......#######......................#######..............\n.......#######......................#######..............\n.......#..-..#......................#..-..#..............\n.......#.|...#......................#.|.|.#..............\n.......#..-..#......................#..-..#..............\n.......#...|.#......................#.|...#..............\n.......#..-..#......................#..-..#..............\n.......#######......................#######..............\n############################.############################\n#.....##..-..##.....##..-..#.#.....##..-..##.....##..-..#\n#.-.-.##...|.##.-.-.##.|.|.#.#.-...##.|.|.##.-...##.|.|.#\n#|.|.|##..-..##|.|.|##..-..#.#|.|.|##..-..##|.|.|##..-..#\n#...-.##.|...##.-.-.##.|.|.#.#.-.-.##.|...##.-.-.##.|.|.#\n#.....##..-..##.....##..-..#.#.....##..-..##.....##..-..#\n############################.############################\n.......#######......................#######..............\n.......#..-..#......................#..-..#..............\n.......#...|.#......................#.|.|.#..............\n.......#..-..#......................#..-..#..............\n.......#.|...#......................#...|.#..............\n.......#..-..#......................#..-..#..............\n.......#######......................#######..............\n0\n"}, "reference_outputs": ["LOW\nHIGH\nHIGH\nLOW\n"], "source_document_id": "p00660", "source_text": "Problem B: High & Low Cube\n\n僕は近所の小学生たちと一緒に夏祭りに来ていた。有り体に言えば保護者役だが、出店の焼きそばやたこ焼きなんかが焼ける匂い、時折聞こえる打ち上げ花火の音などは、この歳になっても心が踊るものがある。が、好奇心旺盛な子供たちがはぐれないように、今日はしっかり見守っていないと。\n\n子供たちはとある出店に興味を持ったようだった。覗き込んでみると、そこでは出店のおじさんとサイコロを使ったゲームをして、勝てば景品が貰えることになっていた。そのゲームは、 High & Low と呼ばれる単純なものだ。参加者とおじさんは1個ずつサイコロを振るが、その前に参加者は、自分の出目がおじさんの出目より大きいか小さいかを予想する。予想が当たれば勝利であり、同じ目が出た場合はどちらもサイコロを振り直す。\n\nこのゲームの少し厄介なところは、参加者のサイコロとおじさんのサイコロが違うものであるかもしれない、という点だ。参加者はあらかじめ両者のサイコロの展開図を見ることができるので、それをヒントに予想することになる。\n\nつまり、簡単な確率の計算だ。とはいえ確率は高校数学の範囲で、小学生にはちょっと荷が重いかもしれない。子供たちの中で一番利発そうな子でさえ、三つ編みにした髪を揺らしながら考え込んでいる。もうすぐ僕に助けを求めてくることだろう。さて、たまにはオトナらしいところを見せてあげようではないか。\n\nInput\n\n入力は複数のケースからなる。\n\n各ケースでは、サイコロの展開図が21×57のグリッドで与えられる。\n\n最初の21×28（(0,0)が左上,(20,27)が右下）のグリッドが参加者のサイコロを表す。\n\n最後の21×28（(0,29)が左上,(20,56)が右下）がおじさんのサイコロを表す。\n\n参加者のサイコロの各面は(0,7)、(7,0)、(7,7)、(7,14)、(7,21)、(14,7)を左上とする7×7のサブグリッドで与えられている。\n\n展開図に書かれている数字は、それぞれ元の数字を\n\n左右反転\n\n左右反転、そのあとで反時計回りに90度回転\n\n左右反転\n\n左右反転、そのあとで反時計回りに270度回転\n\n左右反転\n\n上下反転、そのあとで左右反転\n\nさせたものである。\n\nおじさんのサイコロの各面は(0,36)、(7,29)、(7,36)、(7,43)、(7,50)、(14,36)を左上とする７×７のサブグリッドで与えられている。\n\nおじさんのサイコロの展開図に書かれている数字は参加者のサイコロと同じ規則で描かれている。\n\nサイコロの各面には1から9までの中のどれかが書かれている。\n数字は以下のような7x7のグリッドで与えられる。\n#######\n#.....#\n#...|.#\n#.....#\n#...|.#\n#..-..#\n#######\n\n#######\n#..-..#\n#...|.#\n#..-..#\n#.|...#\n#..-..#\n#######\n\n#######\n#..-..#\n#...|.#\n#..-..#\n#...|.#\n#..-..#\n#######\n\n#######\n#.....#\n#.|.|.#\n#..-..#\n#...|.#\n#.....#\n#######\n\n#######\n#..-..#\n#.|...#\n#..-..#\n#...|.#\n#..-..#\n#######\n\n#######\n#..-..#\n#.|...#\n#..-..#\n#.|.|.#\n#..-..#\n#######\n\n#######\n#..-..#\n#...|.#\n#.....#\n#...|.#\n#.....#\n#######\n\n#######\n#..-..#\n#.|.|.#\n#..-..#\n#.|.|.#\n#..-..#\n#######\n\n#######\n#..-..#\n#.|.|.#\n#..-..#\n#...|.#\n#..-..#\n#######\n\nただし上記の数字を90度、または270度回転させた時、\"|\"と\"-\"は入れ替わっている。\n\n入力の終わりは1つの0からなる行によって与えられる\n\n入力として与えられるサイコロは必ず正しい物である。\nまた決着がつかないようなサイコロは与えられない。\n\nOutput\n\n\"HIGH\"になる場合と\"LOW\"になる場合で確率が高いほうを1行に出力せよ。\n両者の確率が同じ場合は\"HIGH\"を出力せよ。\n\nSample input\n\n.......#######......................#######..............\n.......#.....#......................#..-..#..............\n.......#.|...#......................#.|.|.#..............\n.......#.....#......................#..-..#..............\n.......#.|...#......................#.|...#..............\n.......#..-..#......................#..-..#..............\n.......#######......................#######..............\n############################.############################\n#.....##..-..##.....##..-..#.#.....##..-..##.....##..-..#\n#.-.-.##...|.##.-.-.##.|.|.#.#.....##.|.|.##.-.-.##.|.|.#\n#|.|.|##..-..##|.|.|##..-..#.#....|##..-..##|.|.|##..-..#\n#...-.##.|...##...-.##.|.|.#.#.-.-.##.|...##...-.##.|...#\n#.....##..-..##.....##..-..#.#.....##..-..##.....##..-..#\n############################.############################\n.......#######......................#######..............\n.......#..-..#......................#..-..#..............\n.......#.|...#......................#.|...#..............\n.......#..-..#......................#..-..#..............\n.......#.|.|.#......................#...|.#..............\n.......#..-..#......................#..-..#..............\n.......#######......................#######..............\n.......#######......................#######..............\n.......#..-..#......................#..-..#..............\n.......#.|...#......................#...|.#..............\n.......#..-..#......................#..-..#..............\n.......#...|.#......................#.|.|.#..............\n.......#..-..#......................#..-..#..............\n.......#######......................#######..............\n############################.############################\n#.....##..-..##.....##..-..#.#.....##..-..##.....##..-..#\n#.-.-.##...|.##.-.-.##.|.|.#.#...-.##...|.##.-...##.|.|.#\n#|.|.|##..-..##|.|.|##..-..#.#|.|.|##..-..##|.|.|##..-..#\n#.-.-.##.|...##...-.##.|...#.#.-...##.|.|.##.-.-.##.|...#\n#.....##..-..##.....##..-..#.#.....##..-..##.....##..-..#\n############################.############################\n.......#######......................#######..............\n.......#..-..#......................#..-..#..............\n.......#...|.#......................#.|...#..............\n.......#..-..#......................#..-..#..............\n.......#.|...#......................#...|.#..............\n.......#..-..#......................#..-..#..............\n.......#######......................#######..............\n.......#######......................#######..............\n.......#..-..#......................#..-..#..............\n.......#.|...#......................#.|.|.#..............\n.......#..-..#......................#..-..#..............\n.......#...|.#......................#.|...#..............\n.......#..-..#......................#..-..#..............\n.......#######......................#######..............\n############################.############################\n#.....##..-..##.....##..-..#.#.....##..-..##.....##.....#\n#.-.-.##.|.|.##.-.-.##...|.#.#.....##.|.|.##...-.##.|...#\n#|.|.|##..-..##|....##..-..#.#....|##..-..##|.|.|##.....#\n#.-.-.##.|.|.##.....##.|.|.#.#.-.-.##.|.|.##.-...##.|...#\n#.....##..-..##.....##..-..#.#.....##..-..##.....##..-..#\n############################.############################\n.......#######......................#######..............\n.......#..-..#......................#..-..#..............\n.......#.|.|.#......................#.|...#..............\n.......#..-..#......................#..-..#..............\n.......#...|.#......................#...|.#..............\n.......#..-..#......................#..-..#..............\n.......#######......................#######..............\n.......#######......................#######..............\n.......#..-..#......................#..-..#..............\n.......#.|...#......................#.|.|.#..............\n.......#..-..#......................#..-..#..............\n.......#...|.#......................#.|...#..............\n.......#..-..#......................#..-..#..............\n.......#######......................#######..............\n############################.############################\n#.....##..-..##.....##..-..#.#.....##..-..##.....##..-..#\n#.-.-.##...|.##.-.-.##.|.|.#.#.-...##.|.|.##.-...##.|.|.#\n#|.|.|##..-..##|.|.|##..-..#.#|.|.|##..-..##|.|.|##..-..#\n#...-.##.|...##.-.-.##.|.|.#.#.-.-.##.|...##.-.-.##.|.|.#\n#.....##..-..##.....##..-..#.#.....##..-..##.....##..-..#\n############################.############################\n.......#######......................#######..............\n.......#..-..#......................#..-..#..............\n.......#...|.#......................#.|.|.#..............\n.......#..-..#......................#..-..#..............\n.......#.|...#......................#...|.#..............\n.......#..-..#......................#..-..#..............\n.......#######......................#######..............\n0\n\nSample output\n\nLOW\nHIGH\nHIGH\nLOW\n\nThe University of Aizu Programming Contest 2011 Summer\n\n原案、問題文: Takashi Tayama", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 3389, "cpu_time_ms": 430, "memory_kb": 1196}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s097037505", "group_id": "codeNet:p00712", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define rep(i,x,y) for(int i=(x);i<(y);++i)\n#define debug(x) #x << \"=\" << (x)\n\n#ifdef DEBUG\n#define _GLIBCXX_DEBUG\n#define dump(x) std::cerr << debug(x) << \" (L:\" << __LINE__ << \")\" << std::endl\n#else\n#define dump(x)\n#endif\n\ntypedef long long int ll;\ntypedef pair<int,int> pii;\n//template<typename T> using vec=std::vector<T>;\n\nconst int inf=1<<30;\nconst long long int infll=1LL<<58;\nconst double eps=1e-9;\nconst int dx[]={1,0,-1,0},dy[]={0,1,0,-1};\n\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec){\n\tos << \"[\";\n\tfor (const auto &v : vec) {\n\t\tos << v << \",\";\n\t}\n\tos << \"]\";\n\treturn os;\n}\n\nint p,q,a,n;\n\nint dfs(int denom,int numer,int prev,int product,int num){\n    {\n        int tmp1=denom*prev,tmp2=numer*prev+denom*num;\n        if((double)tmp2/tmp1+eps<(double)p/q) return 0;\n    }\n    if((double)numer/denom-eps>(double)p/q) return 0;\n\n    int res=0;\n    if((double)p/q-eps<=(double)numer/denom  and (double)numer/denom<=(double)p/q+eps) ++res;\n    if(num==0) return res;\n\n    int x=prev;\n    while(true){\n        if(product*x>a) break;\n        res+=dfs(denom*x,numer*x+denom,x,product*x,num-1);\n        ++x;\n    }\n    return res;\n}\n\nvoid solve(){\n    while(cin >> p >> q >> a >> n){\n        if(p==0 and q==0 and a==0 and n==0) break;\n        cout << dfs(1,0,1,1,n) << endl;\n    }\n}\n\nint main(){\n\tstd::ios::sync_with_stdio(false);\n\tstd::cin.tie(0);\n\tsolve();\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1448088137, "filename_ext": "cpp", "original_language": "C++11", "problem_description_relpath": "problem_descriptions/p00712.html", "problem_id": "p00712", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p00712/input.txt", "sample_output_relpath": "derived/input_output/data/p00712/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p00712/C++/s097037505.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s097037505", "user_id": "u313705878"}, "prompt_components": {"gold_output": "4\n7\n6\n2\n42\n1\n0\n9\n3\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define rep(i,x,y) for(int i=(x);i<(y);++i)\n#define debug(x) #x << \"=\" << (x)\n\n#ifdef DEBUG\n#define _GLIBCXX_DEBUG\n#define dump(x) std::cerr << debug(x) << \" (L:\" << __LINE__ << \")\" << std::endl\n#else\n#define dump(x)\n#endif\n\ntypedef long long int ll;\ntypedef pair<int,int> pii;\n//template<typename T> using vec=std::vector<T>;\n\nconst int inf=1<<30;\nconst long long int infll=1LL<<58;\nconst double eps=1e-9;\nconst int dx[]={1,0,-1,0},dy[]={0,1,0,-1};\n\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T> &vec){\n\tos << \"[\";\n\tfor (const auto &v : vec) {\n\t\tos << v << \",\";\n\t}\n\tos << \"]\";\n\treturn os;\n}\n\nint p,q,a,n;\n\nint dfs(int denom,int numer,int prev,int product,int num){\n    {\n        int tmp1=denom*prev,tmp2=numer*prev+denom*num;\n        if((double)tmp2/tmp1+eps<(double)p/q) return 0;\n    }\n    if((double)numer/denom-eps>(double)p/q) return 0;\n\n    int res=0;\n    if((double)p/q-eps<=(double)numer/denom  and (double)numer/denom<=(double)p/q+eps) ++res;\n    if(num==0) return res;\n\n    int x=prev;\n    while(true){\n        if(product*x>a) break;\n        res+=dfs(denom*x,numer*x+denom,x,product*x,num-1);\n        ++x;\n    }\n    return res;\n}\n\nvoid solve(){\n    while(cin >> p >> q >> a >> n){\n        if(p==0 and q==0 and a==0 and n==0) break;\n        cout << dfs(1,0,1,1,n) << endl;\n    }\n}\n\nint main(){\n\tstd::ios::sync_with_stdio(false);\n\tstd::cin.tie(0);\n\tsolve();\n\treturn 0;\n}", "problem_context": "Problem C: Unit Fraction Partition\n\nA fraction whose numerator is 1\nand whose denominator is a positive integer\nis called a unit fraction.\nA representation of a positive rational number\np/q\nas the sum of finitely many unit fractions is called a partition of\np/q\ninto unit fractions.\nFor example,\n1/2 + 1/6\nis a partition of\n2/3\ninto unit fractions.\nThe difference in the order of addition is disregarded.\nFor example, we do not distinguish\n1/6 + 1/2\nfrom\n1/2 + 1/6.\n\nFor given four positive integers\np,\nq,\na, and\nn,\ncount the number\nof partitions of\np/q\ninto unit fractions satisfying the following two conditions.\n\nThe partition is the sum of at most\nn\nmany unit fractions.\n\nThe product of the denominators of the unit fractions in the\npartition is less than or equal to\na.\n\nFor example, if\n(p,q,a,n) = (2,3,120,3),\nyou should report 4 since\n\nenumerates all of the valid partitions.\n\nInput\n\nThe input is a sequence of at most 1000 data sets followed by a terminator.\n\nA data set is a line containing four positive integers\np,\nq,\na, and\nn\nsatisfying\np,q <= 800,\na <= 12000\nand\nn <= 7.\nThe integers are separated by a space.\n\nThe terminator is composed of just one line\nwhich contains four zeros separated by a space.\nIt is not a part of the input data but a mark for the end of the input.\n\nOutput\n\nThe output should be composed of lines\neach of which contains a single integer.\nNo other characters should appear in the output.\n\nThe output integer corresponding to a data set\np,\nq,\na,\nn\nshould be the number of all partitions of\np/q\ninto at most\nn\nmany unit fractions such that the product of the denominators of the\nunit fractions is less than or equal to\na.\n\nSample Input\n\n2 3 120 3\n2 3 300 3\n2 3 299 3\n2 3 12 3\n2 3 12000 7\n54 795 12000 7\n2 3 300 1\n2 1 200 5\n2 4 54 2\n0 0 0 0\n\nOutput for the Sample Input\n\n4\n7\n6\n2\n42\n1\n0\n9\n3", "sample_input": "2 3 120 3\n2 3 300 3\n2 3 299 3\n2 3 12 3\n2 3 12000 7\n54 795 12000 7\n2 3 300 1\n2 1 200 5\n2 4 54 2\n0 0 0 0\n"}, "reference_outputs": ["4\n7\n6\n2\n42\n1\n0\n9\n3\n"], "source_document_id": "p00712", "source_text": "Problem C: Unit Fraction Partition\n\nA fraction whose numerator is 1\nand whose denominator is a positive integer\nis called a unit fraction.\nA representation of a positive rational number\np/q\nas the sum of finitely many unit fractions is called a partition of\np/q\ninto unit fractions.\nFor example,\n1/2 + 1/6\nis a partition of\n2/3\ninto unit fractions.\nThe difference in the order of addition is disregarded.\nFor example, we do not distinguish\n1/6 + 1/2\nfrom\n1/2 + 1/6.\n\nFor given four positive integers\np,\nq,\na, and\nn,\ncount the number\nof partitions of\np/q\ninto unit fractions satisfying the following two conditions.\n\nThe partition is the sum of at most\nn\nmany unit fractions.\n\nThe product of the denominators of the unit fractions in the\npartition is less than or equal to\na.\n\nFor example, if\n(p,q,a,n) = (2,3,120,3),\nyou should report 4 since\n\nenumerates all of the valid partitions.\n\nInput\n\nThe input is a sequence of at most 1000 data sets followed by a terminator.\n\nA data set is a line containing four positive integers\np,\nq,\na, and\nn\nsatisfying\np,q <= 800,\na <= 12000\nand\nn <= 7.\nThe integers are separated by a space.\n\nThe terminator is composed of just one line\nwhich contains four zeros separated by a space.\nIt is not a part of the input data but a mark for the end of the input.\n\nOutput\n\nThe output should be composed of lines\neach of which contains a single integer.\nNo other characters should appear in the output.\n\nThe output integer corresponding to a data set\np,\nq,\na,\nn\nshould be the number of all partitions of\np/q\ninto at most\nn\nmany unit fractions such that the product of the denominators of the\nunit fractions is less than or equal to\na.\n\nSample Input\n\n2 3 120 3\n2 3 300 3\n2 3 299 3\n2 3 12 3\n2 3 12000 7\n54 795 12000 7\n2 3 300 1\n2 1 200 5\n2 4 54 2\n0 0 0 0\n\nOutput for the Sample Input\n\n4\n7\n6\n2\n42\n1\n0\n9\n3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1451, "cpu_time_ms": 140, "memory_kb": 3084}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s936896487", "group_id": "codeNet:p00712", "input_text": "#include<iostream>\nusing namespace std;\nconst double eps=1e-9;\ndouble p,q,a;\nint n;\nint ans=0;\nvoid dfs(double pq,int s,int depth,int seki){\n  if(pq>=-eps&&pq<=eps){\n    ans++;\n    return;\n  }\n  for(int i=s;i<=a/2;i++){\n    if(seki*i>a)\n      break;\n    if((pq-(1.0/i))>=-eps&&depth+1<=n){\n      dfs((pq-(1.0/i)),i,depth+1,seki*i);\n    }\n  }\n}\nint main(){\n  while(cin>>p>>q>>a>>n,p+q+a+n){\n    ans=0;\n    for(int i=1;i<=a/2;i++){\n      if((p/q)-(1.0/i)>=-eps)\n\tdfs((p/q)-(1.0/i),i,1,i);\n    }\n    cout<<ans<<endl;\n  }\n  return 0;\n}", "language": "C++", "metadata": {"date": 1509437236, "filename_ext": "cpp", "original_language": "C++", "problem_description_relpath": "problem_descriptions/p00712.html", "problem_id": "p00712", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p00712/input.txt", "sample_output_relpath": "derived/input_output/data/p00712/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p00712/C++/s936896487.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s936896487", "user_id": "u017545322"}, "prompt_components": {"gold_output": "4\n7\n6\n2\n42\n1\n0\n9\n3\n", "input_to_evaluate": "#include<iostream>\nusing namespace std;\nconst double eps=1e-9;\ndouble p,q,a;\nint n;\nint ans=0;\nvoid dfs(double pq,int s,int depth,int seki){\n  if(pq>=-eps&&pq<=eps){\n    ans++;\n    return;\n  }\n  for(int i=s;i<=a/2;i++){\n    if(seki*i>a)\n      break;\n    if((pq-(1.0/i))>=-eps&&depth+1<=n){\n      dfs((pq-(1.0/i)),i,depth+1,seki*i);\n    }\n  }\n}\nint main(){\n  while(cin>>p>>q>>a>>n,p+q+a+n){\n    ans=0;\n    for(int i=1;i<=a/2;i++){\n      if((p/q)-(1.0/i)>=-eps)\n\tdfs((p/q)-(1.0/i),i,1,i);\n    }\n    cout<<ans<<endl;\n  }\n  return 0;\n}", "problem_context": "Problem C: Unit Fraction Partition\n\nA fraction whose numerator is 1\nand whose denominator is a positive integer\nis called a unit fraction.\nA representation of a positive rational number\np/q\nas the sum of finitely many unit fractions is called a partition of\np/q\ninto unit fractions.\nFor example,\n1/2 + 1/6\nis a partition of\n2/3\ninto unit fractions.\nThe difference in the order of addition is disregarded.\nFor example, we do not distinguish\n1/6 + 1/2\nfrom\n1/2 + 1/6.\n\nFor given four positive integers\np,\nq,\na, and\nn,\ncount the number\nof partitions of\np/q\ninto unit fractions satisfying the following two conditions.\n\nThe partition is the sum of at most\nn\nmany unit fractions.\n\nThe product of the denominators of the unit fractions in the\npartition is less than or equal to\na.\n\nFor example, if\n(p,q,a,n) = (2,3,120,3),\nyou should report 4 since\n\nenumerates all of the valid partitions.\n\nInput\n\nThe input is a sequence of at most 1000 data sets followed by a terminator.\n\nA data set is a line containing four positive integers\np,\nq,\na, and\nn\nsatisfying\np,q <= 800,\na <= 12000\nand\nn <= 7.\nThe integers are separated by a space.\n\nThe terminator is composed of just one line\nwhich contains four zeros separated by a space.\nIt is not a part of the input data but a mark for the end of the input.\n\nOutput\n\nThe output should be composed of lines\neach of which contains a single integer.\nNo other characters should appear in the output.\n\nThe output integer corresponding to a data set\np,\nq,\na,\nn\nshould be the number of all partitions of\np/q\ninto at most\nn\nmany unit fractions such that the product of the denominators of the\nunit fractions is less than or equal to\na.\n\nSample Input\n\n2 3 120 3\n2 3 300 3\n2 3 299 3\n2 3 12 3\n2 3 12000 7\n54 795 12000 7\n2 3 300 1\n2 1 200 5\n2 4 54 2\n0 0 0 0\n\nOutput for the Sample Input\n\n4\n7\n6\n2\n42\n1\n0\n9\n3", "sample_input": "2 3 120 3\n2 3 300 3\n2 3 299 3\n2 3 12 3\n2 3 12000 7\n54 795 12000 7\n2 3 300 1\n2 1 200 5\n2 4 54 2\n0 0 0 0\n"}, "reference_outputs": ["4\n7\n6\n2\n42\n1\n0\n9\n3\n"], "source_document_id": "p00712", "source_text": "Problem C: Unit Fraction Partition\n\nA fraction whose numerator is 1\nand whose denominator is a positive integer\nis called a unit fraction.\nA representation of a positive rational number\np/q\nas the sum of finitely many unit fractions is called a partition of\np/q\ninto unit fractions.\nFor example,\n1/2 + 1/6\nis a partition of\n2/3\ninto unit fractions.\nThe difference in the order of addition is disregarded.\nFor example, we do not distinguish\n1/6 + 1/2\nfrom\n1/2 + 1/6.\n\nFor given four positive integers\np,\nq,\na, and\nn,\ncount the number\nof partitions of\np/q\ninto unit fractions satisfying the following two conditions.\n\nThe partition is the sum of at most\nn\nmany unit fractions.\n\nThe product of the denominators of the unit fractions in the\npartition is less than or equal to\na.\n\nFor example, if\n(p,q,a,n) = (2,3,120,3),\nyou should report 4 since\n\nenumerates all of the valid partitions.\n\nInput\n\nThe input is a sequence of at most 1000 data sets followed by a terminator.\n\nA data set is a line containing four positive integers\np,\nq,\na, and\nn\nsatisfying\np,q <= 800,\na <= 12000\nand\nn <= 7.\nThe integers are separated by a space.\n\nThe terminator is composed of just one line\nwhich contains four zeros separated by a space.\nIt is not a part of the input data but a mark for the end of the input.\n\nOutput\n\nThe output should be composed of lines\neach of which contains a single integer.\nNo other characters should appear in the output.\n\nThe output integer corresponding to a data set\np,\nq,\na,\nn\nshould be the number of all partitions of\np/q\ninto at most\nn\nmany unit fractions such that the product of the denominators of the\nunit fractions is less than or equal to\na.\n\nSample Input\n\n2 3 120 3\n2 3 300 3\n2 3 299 3\n2 3 12 3\n2 3 12000 7\n54 795 12000 7\n2 3 300 1\n2 1 200 5\n2 4 54 2\n0 0 0 0\n\nOutput for the Sample Input\n\n4\n7\n6\n2\n42\n1\n0\n9\n3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 531, "cpu_time_ms": 190, "memory_kb": 3184}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s986413849", "group_id": "codeNet:p00731", "input_text": "#include <iostream>\n#include <queue>\n#include <unordered_set>\n\nstruct Action {\n\tsize_t x;\n\tsize_t y;\n\tsize_t cost;\n\tbool left_foot_on;\n};\n\nbool operator>(Action lhs, Action rhs) {\n\treturn lhs.cost > rhs.cost;\n}\n\nbool operator==(Action lhs, Action rhs) {\n\treturn lhs.x == rhs.x && lhs.y == rhs.y && lhs.left_foot_on == rhs.left_foot_on;\n}\n\nnamespace std {\n\ttemplate <>\n\tstruct hash<Action> {\n\t\tusing result_type = size_t;\n\n\t\tresult_type operator()(const Action& act) const {\n\t\t\treturn act.x * 31 + act.y * 12 + act.left_foot_on * 7;\n\t\t}\n\t};\n}\n\nclass Climber {\nprivate:\n\tusing candidates_t = std::priority_queue<Action, std::vector<Action>, std::greater<Action>>;\n\n\tsize_t _width;\n\tsize_t _height;\n\tstd::string* _cliff;\n\tcandidates_t _candidates;\n\tstd::unordered_set<Action> _traversed;\n\n\tchar get(size_t x, size_t y);\n\tvoid try_put_candidate(const Action& now, size_t x, size_t y);\n\tvoid put_candidate(size_t x, size_t y, size_t cost, bool left_foot_on);\npublic:\n\tClimber(size_t width, size_t height);\n\tvoid load();\n\tint climb();\n};\n\nClimber::Climber(size_t width, size_t height) : _width(width), _height(height) { }\n\nvoid Climber::load() {\n\t_cliff = new std::string[_height];\n\tfor (size_t y = 0; y < _height; ++y) {\n\t\tstd::string line;\n\t\tfor (size_t x = 0; x < _width; ++x) {\n\t\t\tchar a;\n\t\t\tstd::cin >> a;\n\t\t\tline += a;\n\t\t}\n\t\t_cliff[y] = line;\n\t}\n}\n\nint Climber::climb() {\n\t// ??????????????????S????????????????¶????????¶???????????????????????????????\n\tfor (size_t y = 0; y < _height; ++y) {\n\t\tfor (size_t x = 0; x < _width; ++x) {\n\t\t\tif (get(x, y) == 'S') {\n\t\t\t\tput_candidate(x, y, 0, false);\n\t\t\t\tput_candidate(x, y, 0, true);\n\t\t\t}\n\t\t}\n\t}\n\t// ???????°???????????????????????????????????????????????????????????????????\n\twhile (!_candidates.empty()) {\n\t\tconst Action now = _candidates.top();\n\t\tif (get(now.x, now.y) == 'T') {\n\t\t\treturn now.cost;\n\t\t}\n\t\t_candidates.pop();\n#ifdef _DEBUG\n\t\t//std::cerr << \"(\" << now.x << \",\" << now.y << \")->\" << now.cost << \" [\" << now.left_foot_on << \"]\\n\";\n#endif\n\t\tif (now.left_foot_on) {\n\t\t\ttry_put_candidate(now, now.x + 1, now.y - 2);\n\t\t\ttry_put_candidate(now, now.x + 1, now.y - 1);\n\t\t\ttry_put_candidate(now, now.x + 1, now.y);\n\t\t\ttry_put_candidate(now, now.x + 1, now.y + 1);\n\t\t\ttry_put_candidate(now, now.x + 1, now.y + 2);\n\t\t\ttry_put_candidate(now, now.x + 2, now.y - 1);\n\t\t\ttry_put_candidate(now, now.x + 2, now.y);\n\t\t\ttry_put_candidate(now, now.x + 2, now.y + 1);\n\t\t\ttry_put_candidate(now, now.x + 3, now.y);\n\t\t} else {\n\t\t\ttry_put_candidate(now, now.x - 1, now.y - 2);\n\t\t\ttry_put_candidate(now, now.x - 1, now.y - 1);\n\t\t\ttry_put_candidate(now, now.x - 1, now.y);\n\t\t\ttry_put_candidate(now, now.x - 1, now.y + 1);\n\t\t\ttry_put_candidate(now, now.x - 1, now.y + 2);\n\t\t\ttry_put_candidate(now, now.x - 2, now.y - 1);\n\t\t\ttry_put_candidate(now, now.x - 2, now.y);\n\t\t\ttry_put_candidate(now, now.x - 2, now.y + 1);\n\t\t\ttry_put_candidate(now, now.x - 3, now.y);\n\t\t}\n\t}\n\t// ????????????????????£???\n\treturn -1;\n}\n\nvoid Climber::try_put_candidate(const Action& now, size_t x, size_t y) {\n\tchar type = get(x, y);\n\tif (type == 'S' || type == 'X' || type == '\\0') {\n\t\treturn; // type==S??????????????????????????????????????????????§????????????????????????????????????????????????????\n\t}\n\tint additionalCost;\n\tif (type == 'T') {\n\t\tadditionalCost = 0; // ????????§??????????????????\n\t} else {\n\t\tadditionalCost = type - '0';\n\t}\n\tput_candidate(x, y, now.cost + additionalCost, !now.left_foot_on);\n}\n\nchar Climber::get(size_t x, size_t y) {\n\tif (x >= _width || y >= _height) {\n\t\treturn '\\0'; // invalid range\n\t}\n\treturn _cliff[y][x];\n}\n\nvoid Climber::put_candidate(size_t x, size_t y, size_t cost, bool left_foot_on) {\n\tAction a{x, y, cost, left_foot_on};\n\tauto alreadyTraversed = _traversed.find(a);\n\tif (alreadyTraversed == _traversed.end() || alreadyTraversed->cost > cost) {\n\t\t_traversed.emplace(a);\n\t\t_candidates.emplace(std::move(a));\n\t}\n}\n\nint main() {\n\tsize_t width, height;\n\twhile (true) {\n\t\tstd::cin >> width >> height;\n\t\tif (width == 0 || height == 0) {\n\t\t\tbreak;\n\t\t}\n\t\tClimber climber(width, height);\n\t\tclimber.load();\n\t\tstd::cout << climber.climb() << std::endl;\n\t}\n}", "language": "C++", "metadata": {"date": 1465817622, "filename_ext": "cpp", "original_language": "C++11", "problem_description_relpath": "problem_descriptions/p00731.html", "problem_id": "p00731", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p00731/input.txt", "sample_output_relpath": "derived/input_output/data/p00731/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p00731/C++/s986413849.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s986413849", "user_id": "u319242829"}, "prompt_components": {"gold_output": "12\n5\n-1\n22\n12\n", "input_to_evaluate": "#include <iostream>\n#include <queue>\n#include <unordered_set>\n\nstruct Action {\n\tsize_t x;\n\tsize_t y;\n\tsize_t cost;\n\tbool left_foot_on;\n};\n\nbool operator>(Action lhs, Action rhs) {\n\treturn lhs.cost > rhs.cost;\n}\n\nbool operator==(Action lhs, Action rhs) {\n\treturn lhs.x == rhs.x && lhs.y == rhs.y && lhs.left_foot_on == rhs.left_foot_on;\n}\n\nnamespace std {\n\ttemplate <>\n\tstruct hash<Action> {\n\t\tusing result_type = size_t;\n\n\t\tresult_type operator()(const Action& act) const {\n\t\t\treturn act.x * 31 + act.y * 12 + act.left_foot_on * 7;\n\t\t}\n\t};\n}\n\nclass Climber {\nprivate:\n\tusing candidates_t = std::priority_queue<Action, std::vector<Action>, std::greater<Action>>;\n\n\tsize_t _width;\n\tsize_t _height;\n\tstd::string* _cliff;\n\tcandidates_t _candidates;\n\tstd::unordered_set<Action> _traversed;\n\n\tchar get(size_t x, size_t y);\n\tvoid try_put_candidate(const Action& now, size_t x, size_t y);\n\tvoid put_candidate(size_t x, size_t y, size_t cost, bool left_foot_on);\npublic:\n\tClimber(size_t width, size_t height);\n\tvoid load();\n\tint climb();\n};\n\nClimber::Climber(size_t width, size_t height) : _width(width), _height(height) { }\n\nvoid Climber::load() {\n\t_cliff = new std::string[_height];\n\tfor (size_t y = 0; y < _height; ++y) {\n\t\tstd::string line;\n\t\tfor (size_t x = 0; x < _width; ++x) {\n\t\t\tchar a;\n\t\t\tstd::cin >> a;\n\t\t\tline += a;\n\t\t}\n\t\t_cliff[y] = line;\n\t}\n}\n\nint Climber::climb() {\n\t// ??????????????????S????????????????¶????????¶???????????????????????????????\n\tfor (size_t y = 0; y < _height; ++y) {\n\t\tfor (size_t x = 0; x < _width; ++x) {\n\t\t\tif (get(x, y) == 'S') {\n\t\t\t\tput_candidate(x, y, 0, false);\n\t\t\t\tput_candidate(x, y, 0, true);\n\t\t\t}\n\t\t}\n\t}\n\t// ???????°???????????????????????????????????????????????????????????????????\n\twhile (!_candidates.empty()) {\n\t\tconst Action now = _candidates.top();\n\t\tif (get(now.x, now.y) == 'T') {\n\t\t\treturn now.cost;\n\t\t}\n\t\t_candidates.pop();\n#ifdef _DEBUG\n\t\t//std::cerr << \"(\" << now.x << \",\" << now.y << \")->\" << now.cost << \" [\" << now.left_foot_on << \"]\\n\";\n#endif\n\t\tif (now.left_foot_on) {\n\t\t\ttry_put_candidate(now, now.x + 1, now.y - 2);\n\t\t\ttry_put_candidate(now, now.x + 1, now.y - 1);\n\t\t\ttry_put_candidate(now, now.x + 1, now.y);\n\t\t\ttry_put_candidate(now, now.x + 1, now.y + 1);\n\t\t\ttry_put_candidate(now, now.x + 1, now.y + 2);\n\t\t\ttry_put_candidate(now, now.x + 2, now.y - 1);\n\t\t\ttry_put_candidate(now, now.x + 2, now.y);\n\t\t\ttry_put_candidate(now, now.x + 2, now.y + 1);\n\t\t\ttry_put_candidate(now, now.x + 3, now.y);\n\t\t} else {\n\t\t\ttry_put_candidate(now, now.x - 1, now.y - 2);\n\t\t\ttry_put_candidate(now, now.x - 1, now.y - 1);\n\t\t\ttry_put_candidate(now, now.x - 1, now.y);\n\t\t\ttry_put_candidate(now, now.x - 1, now.y + 1);\n\t\t\ttry_put_candidate(now, now.x - 1, now.y + 2);\n\t\t\ttry_put_candidate(now, now.x - 2, now.y - 1);\n\t\t\ttry_put_candidate(now, now.x - 2, now.y);\n\t\t\ttry_put_candidate(now, now.x - 2, now.y + 1);\n\t\t\ttry_put_candidate(now, now.x - 3, now.y);\n\t\t}\n\t}\n\t// ????????????????????£???\n\treturn -1;\n}\n\nvoid Climber::try_put_candidate(const Action& now, size_t x, size_t y) {\n\tchar type = get(x, y);\n\tif (type == 'S' || type == 'X' || type == '\\0') {\n\t\treturn; // type==S??????????????????????????????????????????????§????????????????????????????????????????????????????\n\t}\n\tint additionalCost;\n\tif (type == 'T') {\n\t\tadditionalCost = 0; // ????????§??????????????????\n\t} else {\n\t\tadditionalCost = type - '0';\n\t}\n\tput_candidate(x, y, now.cost + additionalCost, !now.left_foot_on);\n}\n\nchar Climber::get(size_t x, size_t y) {\n\tif (x >= _width || y >= _height) {\n\t\treturn '\\0'; // invalid range\n\t}\n\treturn _cliff[y][x];\n}\n\nvoid Climber::put_candidate(size_t x, size_t y, size_t cost, bool left_foot_on) {\n\tAction a{x, y, cost, left_foot_on};\n\tauto alreadyTraversed = _traversed.find(a);\n\tif (alreadyTraversed == _traversed.end() || alreadyTraversed->cost > cost) {\n\t\t_traversed.emplace(a);\n\t\t_candidates.emplace(std::move(a));\n\t}\n}\n\nint main() {\n\tsize_t width, height;\n\twhile (true) {\n\t\tstd::cin >> width >> height;\n\t\tif (width == 0 || height == 0) {\n\t\t\tbreak;\n\t\t}\n\t\tClimber climber(width, height);\n\t\tclimber.load();\n\t\tstd::cout << climber.climb() << std::endl;\n\t}\n}", "problem_context": "Problem D: Cliff Climbing\n\nAt 17:00, special agent Jack starts to escape from the enemy camp.\nThere is a cliff in between the camp and the nearest safety zone.\nJack has to climb the almost vertical cliff\nby stepping his feet on the blocks that cover the cliff.\nThe cliff has slippery blocks where Jack has to\nspend time to take each step.\nHe also has to bypass some blocks that are too loose to support his weight.\nYour mission is to write a program that calculates the minimum time to complete climbing.\n\nFigure D-1 shows an example of cliff data that you will\nreceive.\nThe cliff is covered with square blocks.\nJack starts cliff climbing from the ground under the cliff,\nby stepping his left or right foot on one of the blocks marked with\n'S' at the bottom row.\nThe numbers on the blocks are the \"slippery levels\". It takes\nt time units for him to safely put his foot on a\nblock marked with t, where 1 ≤ t ≤ 9.\nHe cannot put his feet on blocks marked with 'X'.\nHe completes the climbing when he puts\neither of his feet on one of the blocks marked with 'T' at the top row.\n\nFigure D-1: Example of Cliff Data\n\nJack's movement must meet the following constraints.\nAfter putting his left (or right) foot on a block, he can only move\nhis right (or left, respectively) foot.\nHis left foot position (lx, ly) and his right foot position\n(rx, ry) should satisfy\nlx < rx\nand | lx - rx | + | ly - ry | ≤ 3\n.\nThis implies that, given a position of his left foot in Figure D-2 (a), he has to\nplace his right foot on one of the nine blocks marked with blue color.\nSimilarly, given a position of his right foot in Figure D-2 (b),\nhe has to place his\nleft foot on one of the nine blocks marked with blue color.\n\nFigure D-2: Possible Placements of Feet\n\nInput\n\nThe input is a sequence of datasets.\nThe end of the input is indicated by a line containing two zeros separated by a space.\nEach dataset is formatted as follows:\n\nw h\n\ns(1,1) ... s(1,w)\n\ns(2,1) ... s(2,w)\n\n...\n\ns(h,1) ... s(h,w)\n\nThe integers w and h are the width and the height of\nthe matrix data of the cliff. You may assume 2 ≤ w ≤ 30 and 5 ≤ h ≤ 60.\nEach of the following h lines consists of w characters\ndelimited by a space.\nThe character s(y, x) represents the state of the block at\nposition\n(x, y) as follows:\n\n'S': Jack can start cliff climbing from this block.\n\n'T': Jack finishes climbing when he reaches this block.\n\n'X': Jack cannot put his feet on this block.\n\n'1' - '9' (= t): Jack has to spend t time units\nto put either of his feet on this block.\n\nYou can assume that it takes no time to put a foot on a block marked with 'S' or 'T'.\n\nOutput\n\nFor each dataset, print a line only having a decimal integer indicating\nthe minimum time required for the cliff climbing,\nwhen Jack can complete it.\nOtherwise, print a line only having \"-1\" for the dataset.\nEach line should not have any characters other than these numbers.\n\nSample Input\n\n6 6\n4 4 X X T T\n4 7 8 2 X 7\n3 X X X 1 8\n1 2 X X X 6\n1 1 2 4 4 7\nS S 2 3 X X\n2 10\nT 1\n1 X\n1 X\n1 X\n1 1\n1 X\n1 X\n1 1\n1 X\nS S\n2 10\nT X\n1 X\n1 X\n1 X\n1 1\n1 X\n1 X\n1 1\n1 X\nS S\n10 10\nT T T T T T T T T T\nX 2 X X X X X 3 4 X\n9 8 9 X X X 2 9 X 9\n7 7 X 7 3 X X 8 9 X\n8 9 9 9 6 3 X 5 X 5\n8 9 9 9 6 X X 5 X 5\n8 6 5 4 6 8 X 5 X 5\n8 9 3 9 6 8 X 5 X 5\n8 3 9 9 6 X X X 5 X\nS S S S S S S S S S\n10 7\n2 3 2 3 2 3 2 3 T T\n1 2 3 2 3 2 3 2 3 2\n3 2 3 2 3 2 3 2 3 4\n3 2 3 2 3 2 3 2 3 5\n3 2 3 1 3 2 3 2 3 5\n2 2 3 2 4 2 3 2 3 5\nS S 2 3 2 1 2 3 2 3\n0 0\n\nOutput for the Sample Input\n\n12\n5\n-1\n22\n12", "sample_input": "6 6\n4 4 X X T T\n4 7 8 2 X 7\n3 X X X 1 8\n1 2 X X X 6\n1 1 2 4 4 7\nS S 2 3 X X\n2 10\nT 1\n1 X\n1 X\n1 X\n1 1\n1 X\n1 X\n1 1\n1 X\nS S\n2 10\nT X\n1 X\n1 X\n1 X\n1 1\n1 X\n1 X\n1 1\n1 X\nS S\n10 10\nT T T T T T T T T T\nX 2 X X X X X 3 4 X\n9 8 9 X X X 2 9 X 9\n7 7 X 7 3 X X 8 9 X\n8 9 9 9 6 3 X 5 X 5\n8 9 9 9 6 X X 5 X 5\n8 6 5 4 6 8 X 5 X 5\n8 9 3 9 6 8 X 5 X 5\n8 3 9 9 6 X X X 5 X\nS S S S S S S S S S\n10 7\n2 3 2 3 2 3 2 3 T T\n1 2 3 2 3 2 3 2 3 2\n3 2 3 2 3 2 3 2 3 4\n3 2 3 2 3 2 3 2 3 5\n3 2 3 1 3 2 3 2 3 5\n2 2 3 2 4 2 3 2 3 5\nS S 2 3 2 1 2 3 2 3\n0 0\n"}, "reference_outputs": ["12\n5\n-1\n22\n12\n"], "source_document_id": "p00731", "source_text": "Problem D: Cliff Climbing\n\nAt 17:00, special agent Jack starts to escape from the enemy camp.\nThere is a cliff in between the camp and the nearest safety zone.\nJack has to climb the almost vertical cliff\nby stepping his feet on the blocks that cover the cliff.\nThe cliff has slippery blocks where Jack has to\nspend time to take each step.\nHe also has to bypass some blocks that are too loose to support his weight.\nYour mission is to write a program that calculates the minimum time to complete climbing.\n\nFigure D-1 shows an example of cliff data that you will\nreceive.\nThe cliff is covered with square blocks.\nJack starts cliff climbing from the ground under the cliff,\nby stepping his left or right foot on one of the blocks marked with\n'S' at the bottom row.\nThe numbers on the blocks are the \"slippery levels\". It takes\nt time units for him to safely put his foot on a\nblock marked with t, where 1 ≤ t ≤ 9.\nHe cannot put his feet on blocks marked with 'X'.\nHe completes the climbing when he puts\neither of his feet on one of the blocks marked with 'T' at the top row.\n\nFigure D-1: Example of Cliff Data\n\nJack's movement must meet the following constraints.\nAfter putting his left (or right) foot on a block, he can only move\nhis right (or left, respectively) foot.\nHis left foot position (lx, ly) and his right foot position\n(rx, ry) should satisfy\nlx < rx\nand | lx - rx | + | ly - ry | ≤ 3\n.\nThis implies that, given a position of his left foot in Figure D-2 (a), he has to\nplace his right foot on one of the nine blocks marked with blue color.\nSimilarly, given a position of his right foot in Figure D-2 (b),\nhe has to place his\nleft foot on one of the nine blocks marked with blue color.\n\nFigure D-2: Possible Placements of Feet\n\nInput\n\nThe input is a sequence of datasets.\nThe end of the input is indicated by a line containing two zeros separated by a space.\nEach dataset is formatted as follows:\n\nw h\n\ns(1,1) ... s(1,w)\n\ns(2,1) ... s(2,w)\n\n...\n\ns(h,1) ... s(h,w)\n\nThe integers w and h are the width and the height of\nthe matrix data of the cliff. You may assume 2 ≤ w ≤ 30 and 5 ≤ h ≤ 60.\nEach of the following h lines consists of w characters\ndelimited by a space.\nThe character s(y, x) represents the state of the block at\nposition\n(x, y) as follows:\n\n'S': Jack can start cliff climbing from this block.\n\n'T': Jack finishes climbing when he reaches this block.\n\n'X': Jack cannot put his feet on this block.\n\n'1' - '9' (= t): Jack has to spend t time units\nto put either of his feet on this block.\n\nYou can assume that it takes no time to put a foot on a block marked with 'S' or 'T'.\n\nOutput\n\nFor each dataset, print a line only having a decimal integer indicating\nthe minimum time required for the cliff climbing,\nwhen Jack can complete it.\nOtherwise, print a line only having \"-1\" for the dataset.\nEach line should not have any characters other than these numbers.\n\nSample Input\n\n6 6\n4 4 X X T T\n4 7 8 2 X 7\n3 X X X 1 8\n1 2 X X X 6\n1 1 2 4 4 7\nS S 2 3 X X\n2 10\nT 1\n1 X\n1 X\n1 X\n1 1\n1 X\n1 X\n1 1\n1 X\nS S\n2 10\nT X\n1 X\n1 X\n1 X\n1 1\n1 X\n1 X\n1 1\n1 X\nS S\n10 10\nT T T T T T T T T T\nX 2 X X X X X 3 4 X\n9 8 9 X X X 2 9 X 9\n7 7 X 7 3 X X 8 9 X\n8 9 9 9 6 3 X 5 X 5\n8 9 9 9 6 X X 5 X 5\n8 6 5 4 6 8 X 5 X 5\n8 9 3 9 6 8 X 5 X 5\n8 3 9 9 6 X X X 5 X\nS S S S S S S S S S\n10 7\n2 3 2 3 2 3 2 3 T T\n1 2 3 2 3 2 3 2 3 2\n3 2 3 2 3 2 3 2 3 4\n3 2 3 2 3 2 3 2 3 5\n3 2 3 1 3 2 3 2 3 5\n2 2 3 2 4 2 3 2 3 5\nS S 2 3 2 1 2 3 2 3\n0 0\n\nOutput for the Sample Input\n\n12\n5\n-1\n22\n12", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 4109, "cpu_time_ms": 40, "memory_kb": 3600}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s474866800", "group_id": "codeNet:p00744", "input_text": "#define _CRT_SECURE_NO_WARNINGS\n// #define _GLIBCXX_DEBUG\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n// #define int ll\ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\ntypedef pair<int,int> pii;\n#define all(c) begin(c), end(c)\n#define range(i,a,b) for(ll i=a; i<ll(b); i++)\n#define rep(i,b) range(i,0,b)\n#define rangei(i,a,b) for(ll a=a;i<=ll(b);i++)\n#define repi(i,b) rangei(i,1,b)\n#define pb push_back\n#define eb emplace_back\n#define mp make_pair\n#define mt make_tuple\ntemplate<class T> ostream & operator << (ostream &os, vector<T> const &);\ntemplate<int n, class...T>\ntypename enable_if<(n>=sizeof...(T))>::type\n_ot(ostream &, tuple<T...> const &){}\ntemplate<int n, class...T>\ntypename enable_if<(n< sizeof...(T))>::type\n_ot(ostream &os, tuple<T...> const &t){\n    os << (n==0?\"\":\" \") << get<n>(t); _ot<n+1>(os, t);\n}\ntemplate<class...T>\nostream & operator << (ostream &os, tuple<T...> const &t){\n    _ot<0>(os, t); return os;\n}\ntemplate<class T, class U>\nostream & operator<<(ostream &os, pair<T,U> const &p){\n    return os << \"(\" << p.first << \", \" << p.second << \") \";\n}\ntemplate<class T>\nostream & operator<<(ostream &os, vector<T> const &v){\n    rep(i,v.size()) os << v[i] << (i+1==(int)v.size()?\"\":\" \"); return os;\n}\n#ifdef DEBUG\n#define dump(...) (cerr << #__VA_ARGS__ << \" = \" << mt(__VA_ARGS__) \\\n                   << \" [\" << __LINE__ << \"]\" << endl)\n#else\n#define dump(...)\n#endif\nvoid fastios(){\n    ios_base::sync_with_stdio(0);\n    cin.tie(0);\n#define endl '\\n'\n}\ntemplate<class T>\nsize_t uniq(vector<T> &v){\n    sort(v.begin(), v.end());\n    v.erase(unique(v.begin(), v.end()), v.end());\n    return v.size();\n}\ntemplate<class T>\nsize_t uniq(T *l, size_t n){\n    sort(l,l+n);\n    return unique(l,l+n) - l;\n}\n#define mems(arr,val) memset(arr,val,sizeof(arr));\nint const mod = 1000000007;\nint const inf = numeric_limits<int>::max()/8;\n\ntypedef int Capacity;\nstruct Edge {\n    int src, dst;\n    Capacity cap;\n    Edge(int src_, int dst_, Capacity cap_) :\n        src(src_), dst(dst_), cap(cap_) { }\n};\ntypedef vector<Edge> Edges;\ntypedef vector<Edges> Graph;\n\nstruct Dinic {\n    int n, s, t;\n    vector<int> level, iter;\n    vector<vector<Capacity>> cap, flow;\n    vector<vector<int>> g;\n    Capacity inf;\n    Dinic(int n)\n        : n(n), cap(n, vector<Capacity>(n)), flow(n, vector<Capacity>(n)),\n          g(n, vector<int>()), inf(numeric_limits<Capacity>::max()/8){}\n    Dinic(const Graph &graph){\n        *this = Dinic(graph.size());\n        rep(i,n) for(auto &e : graph[i]) addEdge(e.src, e.dst, e.cap);\n    }\n    void addEdge(int u, int v, Capacity c){\n        cap[u][v] += c; cap[v][u] += c; flow[v][u] += c;\n        g[u].push_back(v); g[v].push_back(u);\n    }\n    inline Capacity residue(int u, int v){ return cap[u][v] - flow[u][v]; }\n    Capacity solve(int s, int t){\n        this->t = t, this->s = s;\n        Capacity res = 0, aug = 1;\n        while(aug > 0){\n            levelize();\n            iter.assign(n, 0);\n            aug = augment(s, inf);\n            res += aug;\n        }\n        return res;\n    }\n    void levelize(){\n        level.assign(n, inf); level[s] = 0;\n        queue<int> q; q.emplace(s);\n        while(q.size()){\n            int v = q.front(); q.pop();\n            for(const int &d : g[v]){\n                if(level[d] <= level[v] + 1 || residue(v,d) == 0) continue;\n                level[d] = level[v] + 1; q.emplace(d);\n            }\n        }\n    }\n    Capacity augment(int v, Capacity lim){\n        Capacity res = 0;\n        if(v == t) return lim;\n        for(int &i = iter[v]; i < (int)g[v].size(); i++){\n            const int &d = g[v][i];\n            if(residue(v,d) == 0 || level[v] + 1 != level[d]) continue;\n            Capacity aug = augment(d, min(lim, residue(v,d)));\n            if(aug > 0){\n                flow[v][d] += aug; flow[d][v] -= aug;\n                res += aug; lim -= aug;\n                if(lim == 0) return res;\n            }\n        }\n        return res;\n    }\n};\n\nint main(){\n    fastios();\n    int n,m;\n    while(cin >> n >> m && n|m){\n        vector<int> a(n), b(m);\n        rep(i,n) cin >> a[i];\n        rep(i,m) cin >> b[i];\n        Dinic d(n+m+2);\n        int s = n+m, t = n+m+1;\n        rep(i,m) d.addEdge(i+n,t,1);\n        rep(i,n){\n            d.addEdge(s,i,1);\n            rep(j,m) if(__gcd(a[i],b[j]) != 1) d.addEdge(i,n+j,1);\n        }\n        rep(i,n)rep(j,m){\n            if(d.flow[i][j+n]) dump(i,j, d.flow[i][j+m]);\n        }\n        cout << d.solve(s,t) << endl;\n    }\n}\n\n// int main(){\n//     int N,M;\n//     cin >> N >> M;\n//     Graph g(N);\n//     rep(i,M){\n//         int a,b,c;\n//         cin >> a >> b >> c;\n//         g[a].emplace_back(a,b,c);\n//     }\n//     Dinic dinic(g);\n//     cout << dinic.solve(0,N-1) << endl;\n// }", "language": "C++", "metadata": {"date": 1444922255, "filename_ext": "cpp", "original_language": "C++11", "problem_description_relpath": "problem_descriptions/p00744.html", "problem_id": "p00744", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p00744/input.txt", "sample_output_relpath": "derived/input_output/data/p00744/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p00744/C++/s474866800.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s474866800", "user_id": "u553881259"}, "prompt_components": {"gold_output": "3\n1\n0\n4\n9\n18\n85\n", "input_to_evaluate": "#define _CRT_SECURE_NO_WARNINGS\n// #define _GLIBCXX_DEBUG\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n// #define int ll\ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\ntypedef pair<int,int> pii;\n#define all(c) begin(c), end(c)\n#define range(i,a,b) for(ll i=a; i<ll(b); i++)\n#define rep(i,b) range(i,0,b)\n#define rangei(i,a,b) for(ll a=a;i<=ll(b);i++)\n#define repi(i,b) rangei(i,1,b)\n#define pb push_back\n#define eb emplace_back\n#define mp make_pair\n#define mt make_tuple\ntemplate<class T> ostream & operator << (ostream &os, vector<T> const &);\ntemplate<int n, class...T>\ntypename enable_if<(n>=sizeof...(T))>::type\n_ot(ostream &, tuple<T...> const &){}\ntemplate<int n, class...T>\ntypename enable_if<(n< sizeof...(T))>::type\n_ot(ostream &os, tuple<T...> const &t){\n    os << (n==0?\"\":\" \") << get<n>(t); _ot<n+1>(os, t);\n}\ntemplate<class...T>\nostream & operator << (ostream &os, tuple<T...> const &t){\n    _ot<0>(os, t); return os;\n}\ntemplate<class T, class U>\nostream & operator<<(ostream &os, pair<T,U> const &p){\n    return os << \"(\" << p.first << \", \" << p.second << \") \";\n}\ntemplate<class T>\nostream & operator<<(ostream &os, vector<T> const &v){\n    rep(i,v.size()) os << v[i] << (i+1==(int)v.size()?\"\":\" \"); return os;\n}\n#ifdef DEBUG\n#define dump(...) (cerr << #__VA_ARGS__ << \" = \" << mt(__VA_ARGS__) \\\n                   << \" [\" << __LINE__ << \"]\" << endl)\n#else\n#define dump(...)\n#endif\nvoid fastios(){\n    ios_base::sync_with_stdio(0);\n    cin.tie(0);\n#define endl '\\n'\n}\ntemplate<class T>\nsize_t uniq(vector<T> &v){\n    sort(v.begin(), v.end());\n    v.erase(unique(v.begin(), v.end()), v.end());\n    return v.size();\n}\ntemplate<class T>\nsize_t uniq(T *l, size_t n){\n    sort(l,l+n);\n    return unique(l,l+n) - l;\n}\n#define mems(arr,val) memset(arr,val,sizeof(arr));\nint const mod = 1000000007;\nint const inf = numeric_limits<int>::max()/8;\n\ntypedef int Capacity;\nstruct Edge {\n    int src, dst;\n    Capacity cap;\n    Edge(int src_, int dst_, Capacity cap_) :\n        src(src_), dst(dst_), cap(cap_) { }\n};\ntypedef vector<Edge> Edges;\ntypedef vector<Edges> Graph;\n\nstruct Dinic {\n    int n, s, t;\n    vector<int> level, iter;\n    vector<vector<Capacity>> cap, flow;\n    vector<vector<int>> g;\n    Capacity inf;\n    Dinic(int n)\n        : n(n), cap(n, vector<Capacity>(n)), flow(n, vector<Capacity>(n)),\n          g(n, vector<int>()), inf(numeric_limits<Capacity>::max()/8){}\n    Dinic(const Graph &graph){\n        *this = Dinic(graph.size());\n        rep(i,n) for(auto &e : graph[i]) addEdge(e.src, e.dst, e.cap);\n    }\n    void addEdge(int u, int v, Capacity c){\n        cap[u][v] += c; cap[v][u] += c; flow[v][u] += c;\n        g[u].push_back(v); g[v].push_back(u);\n    }\n    inline Capacity residue(int u, int v){ return cap[u][v] - flow[u][v]; }\n    Capacity solve(int s, int t){\n        this->t = t, this->s = s;\n        Capacity res = 0, aug = 1;\n        while(aug > 0){\n            levelize();\n            iter.assign(n, 0);\n            aug = augment(s, inf);\n            res += aug;\n        }\n        return res;\n    }\n    void levelize(){\n        level.assign(n, inf); level[s] = 0;\n        queue<int> q; q.emplace(s);\n        while(q.size()){\n            int v = q.front(); q.pop();\n            for(const int &d : g[v]){\n                if(level[d] <= level[v] + 1 || residue(v,d) == 0) continue;\n                level[d] = level[v] + 1; q.emplace(d);\n            }\n        }\n    }\n    Capacity augment(int v, Capacity lim){\n        Capacity res = 0;\n        if(v == t) return lim;\n        for(int &i = iter[v]; i < (int)g[v].size(); i++){\n            const int &d = g[v][i];\n            if(residue(v,d) == 0 || level[v] + 1 != level[d]) continue;\n            Capacity aug = augment(d, min(lim, residue(v,d)));\n            if(aug > 0){\n                flow[v][d] += aug; flow[d][v] -= aug;\n                res += aug; lim -= aug;\n                if(lim == 0) return res;\n            }\n        }\n        return res;\n    }\n};\n\nint main(){\n    fastios();\n    int n,m;\n    while(cin >> n >> m && n|m){\n        vector<int> a(n), b(m);\n        rep(i,n) cin >> a[i];\n        rep(i,m) cin >> b[i];\n        Dinic d(n+m+2);\n        int s = n+m, t = n+m+1;\n        rep(i,m) d.addEdge(i+n,t,1);\n        rep(i,n){\n            d.addEdge(s,i,1);\n            rep(j,m) if(__gcd(a[i],b[j]) != 1) d.addEdge(i,n+j,1);\n        }\n        rep(i,n)rep(j,m){\n            if(d.flow[i][j+n]) dump(i,j, d.flow[i][j+m]);\n        }\n        cout << d.solve(s,t) << endl;\n    }\n}\n\n// int main(){\n//     int N,M;\n//     cin >> N >> M;\n//     Graph g(N);\n//     rep(i,M){\n//         int a,b,c;\n//         cin >> a >> b >> c;\n//         g[a].emplace_back(a,b,c);\n//     }\n//     Dinic dinic(g);\n//     cout << dinic.solve(0,N-1) << endl;\n// }", "problem_context": "Problem E: Cards\n\nThere are many blue cards and red cards on the table.\nFor each card, an integer number greater than 1 is printed on its face.\nThe same number may be printed on several cards.\n\nA blue card and a red card can be paired when both of the numbers\nprinted on them have a common divisor greater than 1.\nThere may be more than one red card that can be paired with one blue card.\nAlso, there may be more than one blue card that can be paired with one red card.\nWhen a blue card and a red card are chosen and paired,\nthese two cards are removed from the whole cards on the table.\n\nFigure E-1: Four blue cards and three red cards\n\nFor example, in Figure E-1,\nthere are four blue cards and three red cards.\nNumbers 2, 6, 6 and 15 are printed on the faces of the four blue cards,\nand 2, 3 and 35 are printed on those of the three red cards.\nHere, you can make pairs of blue cards and red cards as follows.\nFirst,\nthe blue card with number 2 on it and the red card with 2 are paired and removed.\nSecond,\none of the two blue cards with 6 and the red card with 3 are paired and removed.\nFinally,\nthe blue card with 15 and the red card with 35 are paired and removed.\nThus the number of removed pairs is three.\n\nNote that the total number of the pairs depends on\nthe way of choosing cards to be paired.\nThe blue card with 15 and the red card with 3 might be paired\nand removed at the beginning.\nIn this case, there are only one more pair that can be removed\nand the total number of the removed pairs is two.\n\nYour job is to find the largest number of pairs that can be removed from the given set of cards on the table.\n\nInput\n\nThe input is a sequence of datasets.\nThe number of the datasets is less than or equal to 100.\nEach dataset is formatted as follows.\n\nm n\n\nb1 ... bk\n... bm\n\nr1 ... rk\n... rn\n\nThe integers m and n are the number of blue cards\nand that of red cards, respectively.\nYou may assume 1 ≤ m ≤ 500 and 1≤ n ≤ 500.\n\nbk (1 ≤ k ≤ m) and\nrk (1 ≤ k ≤ n) are\nnumbers printed on the blue cards and the red cards respectively,\nthat are integers greater than or equal to 2 and less than\n10000000 (=107).\nThe input integers are separated by a space or a newline.\nEach of bm and rn is\nfollowed by a newline.\nThere are no other characters in the dataset.\n\nThe end of the input is indicated by a line containing two zeros\nseparated by a space.\n\nOutput\n\nFor each dataset, output a line containing an integer that indicates\nthe maximum of the number of the pairs.\n\nSample Input\n\n4 3\n2 6 6 15\n2 3 5\n2 3\n4 9\n8 16 32\n4 2\n4 9 11 13\n5 7\n5 5\n2 3 5 1001 1001\n7 11 13 30 30\n10 10\n2 3 5 7 9 11 13 15 17 29\n4 6 10 14 18 22 26 30 34 38\n20 20\n195 144 903 63 137 513 44 626 75 473\n876 421 568 519 755 840 374 368 570 872\n363 650 155 265 64 26 426 391 15 421\n373 984 564 54 823 477 565 866 879 638\n100 100\n195 144 903 63 137 513 44 626 75 473\n876 421 568 519 755 840 374 368 570 872\n363 650 155 265 64 26 426 391 15 421\n373 984 564 54 823 477 565 866 879 638\n117 755 835 683 52 369 302 424 513 870\n75 874 299 228 140 361 30 342 750 819\n761 123 804 325 952 405 578 517 49 457\n932 941 988 767 624 41 912 702 241 426\n351 92 300 648 318 216 785 347 556 535\n166 318 434 746 419 386 928 996 680 975\n231 390 916 220 933 319 37 846 797 54\n272 924 145 348 350 239 563 135 362 119\n446 305 213 879 51 631 43 755 405 499\n509 412 887 203 408 821 298 443 445 96\n274 715 796 417 839 147 654 402 280 17\n298 725 98 287 382 923 694 201 679 99\n699 188 288 364 389 694 185 464 138 406\n558 188 897 354 603 737 277 35 139 556\n826 213 59 922 499 217 846 193 416 525\n69 115 489 355 256 654 49 439 118 961\n0 0\n\nOutput for the Sample Input\n\n3\n1\n0\n4\n9\n18\n85", "sample_input": "4 3\n2 6 6 15\n2 3 5\n2 3\n4 9\n8 16 32\n4 2\n4 9 11 13\n5 7\n5 5\n2 3 5 1001 1001\n7 11 13 30 30\n10 10\n2 3 5 7 9 11 13 15 17 29\n4 6 10 14 18 22 26 30 34 38\n20 20\n195 144 903 63 137 513 44 626 75 473\n876 421 568 519 755 840 374 368 570 872\n363 650 155 265 64 26 426 391 15 421\n373 984 564 54 823 477 565 866 879 638\n100 100\n195 144 903 63 137 513 44 626 75 473\n876 421 568 519 755 840 374 368 570 872\n363 650 155 265 64 26 426 391 15 421\n373 984 564 54 823 477 565 866 879 638\n117 755 835 683 52 369 302 424 513 870\n75 874 299 228 140 361 30 342 750 819\n761 123 804 325 952 405 578 517 49 457\n932 941 988 767 624 41 912 702 241 426\n351 92 300 648 318 216 785 347 556 535\n166 318 434 746 419 386 928 996 680 975\n231 390 916 220 933 319 37 846 797 54\n272 924 145 348 350 239 563 135 362 119\n446 305 213 879 51 631 43 755 405 499\n509 412 887 203 408 821 298 443 445 96\n274 715 796 417 839 147 654 402 280 17\n298 725 98 287 382 923 694 201 679 99\n699 188 288 364 389 694 185 464 138 406\n558 188 897 354 603 737 277 35 139 556\n826 213 59 922 499 217 846 193 416 525\n69 115 489 355 256 654 49 439 118 961\n0 0\n"}, "reference_outputs": ["3\n1\n0\n4\n9\n18\n85\n"], "source_document_id": "p00744", "source_text": "Problem E: Cards\n\nThere are many blue cards and red cards on the table.\nFor each card, an integer number greater than 1 is printed on its face.\nThe same number may be printed on several cards.\n\nA blue card and a red card can be paired when both of the numbers\nprinted on them have a common divisor greater than 1.\nThere may be more than one red card that can be paired with one blue card.\nAlso, there may be more than one blue card that can be paired with one red card.\nWhen a blue card and a red card are chosen and paired,\nthese two cards are removed from the whole cards on the table.\n\nFigure E-1: Four blue cards and three red cards\n\nFor example, in Figure E-1,\nthere are four blue cards and three red cards.\nNumbers 2, 6, 6 and 15 are printed on the faces of the four blue cards,\nand 2, 3 and 35 are printed on those of the three red cards.\nHere, you can make pairs of blue cards and red cards as follows.\nFirst,\nthe blue card with number 2 on it and the red card with 2 are paired and removed.\nSecond,\none of the two blue cards with 6 and the red card with 3 are paired and removed.\nFinally,\nthe blue card with 15 and the red card with 35 are paired and removed.\nThus the number of removed pairs is three.\n\nNote that the total number of the pairs depends on\nthe way of choosing cards to be paired.\nThe blue card with 15 and the red card with 3 might be paired\nand removed at the beginning.\nIn this case, there are only one more pair that can be removed\nand the total number of the removed pairs is two.\n\nYour job is to find the largest number of pairs that can be removed from the given set of cards on the table.\n\nInput\n\nThe input is a sequence of datasets.\nThe number of the datasets is less than or equal to 100.\nEach dataset is formatted as follows.\n\nm n\n\nb1 ... bk\n... bm\n\nr1 ... rk\n... rn\n\nThe integers m and n are the number of blue cards\nand that of red cards, respectively.\nYou may assume 1 ≤ m ≤ 500 and 1≤ n ≤ 500.\n\nbk (1 ≤ k ≤ m) and\nrk (1 ≤ k ≤ n) are\nnumbers printed on the blue cards and the red cards respectively,\nthat are integers greater than or equal to 2 and less than\n10000000 (=107).\nThe input integers are separated by a space or a newline.\nEach of bm and rn is\nfollowed by a newline.\nThere are no other characters in the dataset.\n\nThe end of the input is indicated by a line containing two zeros\nseparated by a space.\n\nOutput\n\nFor each dataset, output a line containing an integer that indicates\nthe maximum of the number of the pairs.\n\nSample Input\n\n4 3\n2 6 6 15\n2 3 5\n2 3\n4 9\n8 16 32\n4 2\n4 9 11 13\n5 7\n5 5\n2 3 5 1001 1001\n7 11 13 30 30\n10 10\n2 3 5 7 9 11 13 15 17 29\n4 6 10 14 18 22 26 30 34 38\n20 20\n195 144 903 63 137 513 44 626 75 473\n876 421 568 519 755 840 374 368 570 872\n363 650 155 265 64 26 426 391 15 421\n373 984 564 54 823 477 565 866 879 638\n100 100\n195 144 903 63 137 513 44 626 75 473\n876 421 568 519 755 840 374 368 570 872\n363 650 155 265 64 26 426 391 15 421\n373 984 564 54 823 477 565 866 879 638\n117 755 835 683 52 369 302 424 513 870\n75 874 299 228 140 361 30 342 750 819\n761 123 804 325 952 405 578 517 49 457\n932 941 988 767 624 41 912 702 241 426\n351 92 300 648 318 216 785 347 556 535\n166 318 434 746 419 386 928 996 680 975\n231 390 916 220 933 319 37 846 797 54\n272 924 145 348 350 239 563 135 362 119\n446 305 213 879 51 631 43 755 405 499\n509 412 887 203 408 821 298 443 445 96\n274 715 796 417 839 147 654 402 280 17\n298 725 98 287 382 923 694 201 679 99\n699 188 288 364 389 694 185 464 138 406\n558 188 897 354 603 737 277 35 139 556\n826 213 59 922 499 217 846 193 416 525\n69 115 489 355 256 654 49 439 118 961\n0 0\n\nOutput for the Sample Input\n\n3\n1\n0\n4\n9\n18\n85", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 4750, "cpu_time_ms": 690, "memory_kb": 10612}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s292311924", "group_id": "codeNet:p00832", "input_text": "#include <cstdio>\n#include <cstring>\n#include <algorithm>\n#include <queue>\n#include <vector>\n\nusing namespace std;\n\nstruct dice{\n\tint val[6];\n\tvoid roti(){\n\t\tint t=val[5];\n\t\tval[5]=val[1];\n\t\tval[1]=val[4];\n\t\tval[4]=val[0];\n\t\tval[0]=t;\n\t}\n\tvoid rotj(){\n\t\tint t=val[3];\n\t\tval[3]=val[1];\n\t\tval[1]=val[2];\n\t\tval[2]=val[0];\n\t\tval[0]=t;\n\t}\n\tvoid rotk(){\n\t\tint t=val[3];\n\t\tval[3]=val[4];\n\t\tval[4]=val[2];\n\t\tval[2]=val[5];\n\t\tval[5]=t;\n\t}\n};\n\nint f[3][3],t[3][3];\ndice cube[3][3][3];\nint n;\nbool res[55];\n\nvoid rec(int cur){\n\tif(cur==27){\n\t\tint sum=0;\n\t\tfor(int i=0;i<3;i++){\n\t\t\tfor(int k=0;k<3;k++){\n\t\t\t\tsum+=cube[i][2][k].val[4];\n\t\t\t}\n\t\t}\n\t\tres[0]=false;\n\t\tres[sum]=true;\n\t\treturn;\n\t}\n\tint k=cur/9;\n\tint i=(cur/3)%3;\n\tint j=cur%3;\n\tdice d=(dice){2,5,6,1,3,4};\n\tfor(int r=0;r<24;r++){\n\t\td.rotk();\n\t\tif(r%4==0){\n\t\t\tif(r<16)d.rotj();\n\t\t\telse if(r==16)d.roti();\n\t\t\telse{\n\t\t\t\tfor(int l=0;l<2;l++){\n\t\t\t\t\td.roti();\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif(k==0 && t[i][j] && t[i][j]!=d.val[0])continue;\n\t\tif(i==2 && f[k][j] && f[k][j]!=d.val[2])continue;\n\t\tif(i && cube[i-1][j][k].val[2]+d.val[3]!=7)continue;\n\t\tif(j && cube[i][j-1][k].val[4]+d.val[5]!=7)continue;\n\t\tif(k && cube[i][j][k-1].val[1]+d.val[0]!=7)continue;\n\t\tcube[i][j][k]=d;\n\t\trec(cur+1);\n\t}\n}\n\nvoid solve(){\n\tmemset(res,false,sizeof(res));\n\tres[0]=true;\n\trec(0);\n\tif(res[0])printf(\"0\\n\");\n\telse{\n\t\tbool c=false;\n\t\tfor(int i=1;i<=54;i++){\n\t\t\tif(res[i]){\n\t\t\t\tif(c)printf(\" \");\n\t\t\t\tc=true;\n\t\t\t\tprintf(\"%d\",i);\n\t\t\t}\n\t\t}\n\t\tprintf(\"\\n\");\n\t}\n}\n\nint main(void){\n\tscanf(\"%d\",&n);\n\tfor(int i=0;i<n;i++){\n\t\tfor(int j=0;j<3;j++){\n\t\t\tfor(int k=0;k<3;k++){\n\t\t\t\tscanf(\"%d\",&t[j][k]);\n\t\t\t}\n\t\t}\n\t\tfor(int j=0;j<3;j++){\n\t\t\tfor(int k=0;k<3;k++){\n\t\t\t\tscanf(\"%d\",&f[j][k]);\n\t\t\t}\n\t\t}\n\t\tsolve();\n\t}\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1462351956, "filename_ext": "cpp", "original_language": "C++", "problem_description_relpath": "problem_descriptions/p00832.html", "problem_id": "p00832", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p00832/input.txt", "sample_output_relpath": "derived/input_output/data/p00832/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p00832/C++/s292311924.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s292311924", "user_id": "u117454239"}, "prompt_components": {"gold_output": "27\n24\n32 33 36\n0\n", "input_to_evaluate": "#include <cstdio>\n#include <cstring>\n#include <algorithm>\n#include <queue>\n#include <vector>\n\nusing namespace std;\n\nstruct dice{\n\tint val[6];\n\tvoid roti(){\n\t\tint t=val[5];\n\t\tval[5]=val[1];\n\t\tval[1]=val[4];\n\t\tval[4]=val[0];\n\t\tval[0]=t;\n\t}\n\tvoid rotj(){\n\t\tint t=val[3];\n\t\tval[3]=val[1];\n\t\tval[1]=val[2];\n\t\tval[2]=val[0];\n\t\tval[0]=t;\n\t}\n\tvoid rotk(){\n\t\tint t=val[3];\n\t\tval[3]=val[4];\n\t\tval[4]=val[2];\n\t\tval[2]=val[5];\n\t\tval[5]=t;\n\t}\n};\n\nint f[3][3],t[3][3];\ndice cube[3][3][3];\nint n;\nbool res[55];\n\nvoid rec(int cur){\n\tif(cur==27){\n\t\tint sum=0;\n\t\tfor(int i=0;i<3;i++){\n\t\t\tfor(int k=0;k<3;k++){\n\t\t\t\tsum+=cube[i][2][k].val[4];\n\t\t\t}\n\t\t}\n\t\tres[0]=false;\n\t\tres[sum]=true;\n\t\treturn;\n\t}\n\tint k=cur/9;\n\tint i=(cur/3)%3;\n\tint j=cur%3;\n\tdice d=(dice){2,5,6,1,3,4};\n\tfor(int r=0;r<24;r++){\n\t\td.rotk();\n\t\tif(r%4==0){\n\t\t\tif(r<16)d.rotj();\n\t\t\telse if(r==16)d.roti();\n\t\t\telse{\n\t\t\t\tfor(int l=0;l<2;l++){\n\t\t\t\t\td.roti();\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif(k==0 && t[i][j] && t[i][j]!=d.val[0])continue;\n\t\tif(i==2 && f[k][j] && f[k][j]!=d.val[2])continue;\n\t\tif(i && cube[i-1][j][k].val[2]+d.val[3]!=7)continue;\n\t\tif(j && cube[i][j-1][k].val[4]+d.val[5]!=7)continue;\n\t\tif(k && cube[i][j][k-1].val[1]+d.val[0]!=7)continue;\n\t\tcube[i][j][k]=d;\n\t\trec(cur+1);\n\t}\n}\n\nvoid solve(){\n\tmemset(res,false,sizeof(res));\n\tres[0]=true;\n\trec(0);\n\tif(res[0])printf(\"0\\n\");\n\telse{\n\t\tbool c=false;\n\t\tfor(int i=1;i<=54;i++){\n\t\t\tif(res[i]){\n\t\t\t\tif(c)printf(\" \");\n\t\t\t\tc=true;\n\t\t\t\tprintf(\"%d\",i);\n\t\t\t}\n\t\t}\n\t\tprintf(\"\\n\");\n\t}\n}\n\nint main(void){\n\tscanf(\"%d\",&n);\n\tfor(int i=0;i<n;i++){\n\t\tfor(int j=0;j<3;j++){\n\t\t\tfor(int k=0;k<3;k++){\n\t\t\t\tscanf(\"%d\",&t[j][k]);\n\t\t\t}\n\t\t}\n\t\tfor(int j=0;j<3;j++){\n\t\t\tfor(int k=0;k<3;k++){\n\t\t\t\tscanf(\"%d\",&f[j][k]);\n\t\t\t}\n\t\t}\n\t\tsolve();\n\t}\n\treturn 0;\n}", "problem_context": "Problem F: Dice Puzzle\n\nLet’s try a dice puzzle. The rules of this puzzle are as follows.\n\nDice with six faces as shown in Figure 1 are used in the puzzle.\n\nFigure 1: Faces of a die\n\nWith twenty seven such dice, a 3 × 3 × 3 cube is built as shown in Figure 2.\n\nFigure 2: 3 × 3 × 3 cube\n\nWhen building up a cube made of dice, the sum of the numbers marked on the faces of adjacent dice that are placed against each other must be seven (See Figure 3). For example, if one face of the pair is marked “2”, then the other face must be “5”.\n\nFigure 3: A pair of faces placed against each other\n\nThe top and the front views of the cube are partially given, i.e. the numbers on faces of\nsome of the dice on the top and on the front are given.\n\nFigure 4: Top and front views of the cube\n\nThe goal of the puzzle is to find all the plausible dice arrangements that are consistent\nwith the given top and front view information.\n\nYour job is to write a program that solves this puzzle.\n\nInput\n\nThe input consists of multiple datasets in the following format.\n\nN\nDataset1\nDataset2\n...\nDatasetN\n\nN is the number of the datasets.\n\nThe format of each dataset is as follows.\n\nT11 T12 T13\nT21 T22 T23\nT31 T32 T33\nF11 F12 F13\nF21 F22 F23\nF31 F32 F33\n\nTij and Fij (1 ≤ i ≤ 3, 1 ≤ j ≤ 3) are the faces of dice appearing on the top and front views,\nas shown in Figure 2, or a zero. A zero means that the face at the corresponding position is\nunknown.\n\nOutput\n\nFor each plausible arrangement of dice, compute the sum of the numbers marked on the nine\nfaces appearing on the right side of the cube, that is, with the notation given in Figure 2,\n\n∑3i=1∑3j=1Rij.\n\nFor each dataset, you should output the right view sums for all the plausible arrangements, in\nascending order and without duplicates. Numbers should be separated by a single space.\n\nWhen there are no plausible arrangements for a dataset, output a zero.\n\nFor example, suppose that the top and the front views are given as follows.\n\nFigure 5: Example\n\nThere are four plausible right views as shown in Figure 6. The right view sums are 33, 36, 32,\nand 33, respectively. After rearranging them into ascending order and eliminating duplicates,\nthe answer should be “32 33 36”.\n\nFigure 6: Plausible right views\n\nThe output should be one line for each dataset. The output may have spaces at ends of lines.\n\nSample Input\n\n4\n1 1 1\n1 1 1\n1 1 1\n2 2 2\n2 2 2\n2 2 2\n4 3 3\n5 2 2\n4 3 3\n6 1 1\n6 1 1\n6 1 0\n1 0 0\n0 2 0\n0 0 0\n5 1 2\n5 1 2\n0 0 0\n2 0 0\n0 3 0\n0 0 0\n0 0 0\n0 0 0\n3 0 1\n\nOutput for the Sample Input\n\n27\n24\n32 33 36\n0", "sample_input": "4\n1 1 1\n1 1 1\n1 1 1\n2 2 2\n2 2 2\n2 2 2\n4 3 3\n5 2 2\n4 3 3\n6 1 1\n6 1 1\n6 1 0\n1 0 0\n0 2 0\n0 0 0\n5 1 2\n5 1 2\n0 0 0\n2 0 0\n0 3 0\n0 0 0\n0 0 0\n0 0 0\n3 0 1\n"}, "reference_outputs": ["27\n24\n32 33 36\n0\n"], "source_document_id": "p00832", "source_text": "Problem F: Dice Puzzle\n\nLet’s try a dice puzzle. The rules of this puzzle are as follows.\n\nDice with six faces as shown in Figure 1 are used in the puzzle.\n\nFigure 1: Faces of a die\n\nWith twenty seven such dice, a 3 × 3 × 3 cube is built as shown in Figure 2.\n\nFigure 2: 3 × 3 × 3 cube\n\nWhen building up a cube made of dice, the sum of the numbers marked on the faces of adjacent dice that are placed against each other must be seven (See Figure 3). For example, if one face of the pair is marked “2”, then the other face must be “5”.\n\nFigure 3: A pair of faces placed against each other\n\nThe top and the front views of the cube are partially given, i.e. the numbers on faces of\nsome of the dice on the top and on the front are given.\n\nFigure 4: Top and front views of the cube\n\nThe goal of the puzzle is to find all the plausible dice arrangements that are consistent\nwith the given top and front view information.\n\nYour job is to write a program that solves this puzzle.\n\nInput\n\nThe input consists of multiple datasets in the following format.\n\nN\nDataset1\nDataset2\n...\nDatasetN\n\nN is the number of the datasets.\n\nThe format of each dataset is as follows.\n\nT11 T12 T13\nT21 T22 T23\nT31 T32 T33\nF11 F12 F13\nF21 F22 F23\nF31 F32 F33\n\nTij and Fij (1 ≤ i ≤ 3, 1 ≤ j ≤ 3) are the faces of dice appearing on the top and front views,\nas shown in Figure 2, or a zero. A zero means that the face at the corresponding position is\nunknown.\n\nOutput\n\nFor each plausible arrangement of dice, compute the sum of the numbers marked on the nine\nfaces appearing on the right side of the cube, that is, with the notation given in Figure 2,\n\n∑3i=1∑3j=1Rij.\n\nFor each dataset, you should output the right view sums for all the plausible arrangements, in\nascending order and without duplicates. Numbers should be separated by a single space.\n\nWhen there are no plausible arrangements for a dataset, output a zero.\n\nFor example, suppose that the top and the front views are given as follows.\n\nFigure 5: Example\n\nThere are four plausible right views as shown in Figure 6. The right view sums are 33, 36, 32,\nand 33, respectively. After rearranging them into ascending order and eliminating duplicates,\nthe answer should be “32 33 36”.\n\nFigure 6: Plausible right views\n\nThe output should be one line for each dataset. The output may have spaces at ends of lines.\n\nSample Input\n\n4\n1 1 1\n1 1 1\n1 1 1\n2 2 2\n2 2 2\n2 2 2\n4 3 3\n5 2 2\n4 3 3\n6 1 1\n6 1 1\n6 1 0\n1 0 0\n0 2 0\n0 0 0\n5 1 2\n5 1 2\n0 0 0\n2 0 0\n0 3 0\n0 0 0\n0 0 0\n0 0 0\n3 0 1\n\nOutput for the Sample Input\n\n27\n24\n32 33 36\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1718, "cpu_time_ms": 20, "memory_kb": 1044}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s209613939", "group_id": "codeNet:p00949", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n  int sum=0;\n  string s,t;\n  cin>>s>>t;\nswap(s,t);\n  vector<string>v[4001];\n  for(int i=0;i<s.size();i++)\n    for(int j=1;j+i<=s.size();j++){\n      string p=s.substr(i,j);\n      sort(p.begin(),p.end());\n      if(find(v[j].begin(),v[j].end(),p)==v[j].end())\n       v[j].push_back(p);\n    }\n\n  for(int i=0;i<4001;i++)\n    sort(v[i].begin(),v[i].end());\n \n  for(int i=0;i<t.size();i++)\n    for(int j=1;j+i<=t.size();j++){\n      string p=t.substr(i,j);\n      sort(p.begin(),p.end());\n      int l=0,r=v[p.size()].size();\n      while(l<r){\n        int mid=(l+r)/2;\n        string vv=v[p.size()][mid];\n        if(vv==p){\n          sum=max(sum,(int)p.size());\n          break;\n        }\n        else if(vv>p)r=mid;\n        else l=mid+1;\n      }\n \n    }\n  cout<<sum<<endl;\n}", "language": "C++", "metadata": {"date": 1497845869, "filename_ext": "cpp", "original_language": "C++", "problem_description_relpath": "problem_descriptions/p00949.html", "problem_id": "p00949", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p00949/input.txt", "sample_output_relpath": "derived/input_output/data/p00949/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p00949/C++/s209613939.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Memory Limit Exceeded", "submission_id": "s209613939", "user_id": "u962041986"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n  int sum=0;\n  string s,t;\n  cin>>s>>t;\nswap(s,t);\n  vector<string>v[4001];\n  for(int i=0;i<s.size();i++)\n    for(int j=1;j+i<=s.size();j++){\n      string p=s.substr(i,j);\n      sort(p.begin(),p.end());\n      if(find(v[j].begin(),v[j].end(),p)==v[j].end())\n       v[j].push_back(p);\n    }\n\n  for(int i=0;i<4001;i++)\n    sort(v[i].begin(),v[i].end());\n \n  for(int i=0;i<t.size();i++)\n    for(int j=1;j+i<=t.size();j++){\n      string p=t.substr(i,j);\n      sort(p.begin(),p.end());\n      int l=0,r=v[p.size()].size();\n      while(l<r){\n        int mid=(l+r)/2;\n        string vv=v[p.size()][mid];\n        if(vv==p){\n          sum=max(sum,(int)p.size());\n          break;\n        }\n        else if(vv>p)r=mid;\n        else l=mid+1;\n      }\n \n    }\n  cout<<sum<<endl;\n}", "problem_context": "MathJax.Hub.Config({ tex2jax: { inlineMath: [[\"$\",\"$\"], [\"\\\\(\",\"\\\\)\"]], processEscapes: true }});\n\nProblem D\nHidden Anagrams\n\nAn anagram is a word or a phrase that is formed by rearranging the letters of another. For instance, by rearranging the letters of \"William Shakespeare,\" we can have its anagrams \"I am a weakish speller,\" \"I'll make a wise phrase,\" and so on. Note that when $A$ is an anagram of $B$, $B$ is an anagram of $A$.\n\nIn the above examples, differences in letter cases are ignored, and word spaces and punctuation symbols are freely inserted and/or removed. These rules are common but not applied here; only exact matching of the letters is considered.\n\nFor two strings $s_1$ and $s_2$ of letters, if a substring $s'_1$ of $s_1$ is an anagram of a substring $s'_2$ of $s_2$, we call $s'_1$ a hidden anagram of the two strings, $s_1$ and $s_2$. Of course, $s'_2$ is also a hidden anagram of them.\n\nYour task is to write a program that, for given two strings, computes the length of the longest hidden anagrams of them.\n\nSuppose, for instance, that \"anagram\" and \"grandmother\" are given. Their substrings \"nagr\" and \"gran\" are hidden anagrams since by moving letters you can have one from the other. They are the longest since any substrings of \"grandmother\" of lengths five or more must contain \"d\" or \"o\" that \"anagram\" does not. In this case, therefore, the length of the longest hidden anagrams is four. Note that a substring must be a sequence of letters occurring consecutively in the original string and so \"nagrm\" and \"granm\" are not hidden anagrams.\n\nInput\n\nThe input consists of a single test case in two lines.\n\n$s_1$\n\n$s_2$\n\n$s_1$ and $s_2$ are strings consisting of lowercase letters (a through z) and their lengths are between 1 and 4000, inclusive.\n\nOutput\n\nOutput the length of the longest hidden anagrams of $s_1$ and $s_2$. If there are no hidden anagrams, print a zero.\n\nSample Input 1\n\nanagram\ngrandmother\n\nSample Output 1\n\n4\n\nSample Input 2\n\nwilliamshakespeare\niamaweakishspeller\n\nSample Output 2\n\n18\n\nSample Input 3\n\naaaaaaaabbbbbbbb\nxxxxxabababxxxxxabab\n\nSample Output 3\n\n6\n\nSample Input 4\n\nabababacdcdcd\nefefefghghghghgh\n\nSample Output 4\n\n0", "sample_input": "anagram\ngrandmother\n"}, "reference_outputs": ["4\n"], "source_document_id": "p00949", "source_text": "MathJax.Hub.Config({ tex2jax: { inlineMath: [[\"$\",\"$\"], [\"\\\\(\",\"\\\\)\"]], processEscapes: true }});\n\nProblem D\nHidden Anagrams\n\nAn anagram is a word or a phrase that is formed by rearranging the letters of another. For instance, by rearranging the letters of \"William Shakespeare,\" we can have its anagrams \"I am a weakish speller,\" \"I'll make a wise phrase,\" and so on. Note that when $A$ is an anagram of $B$, $B$ is an anagram of $A$.\n\nIn the above examples, differences in letter cases are ignored, and word spaces and punctuation symbols are freely inserted and/or removed. These rules are common but not applied here; only exact matching of the letters is considered.\n\nFor two strings $s_1$ and $s_2$ of letters, if a substring $s'_1$ of $s_1$ is an anagram of a substring $s'_2$ of $s_2$, we call $s'_1$ a hidden anagram of the two strings, $s_1$ and $s_2$. Of course, $s'_2$ is also a hidden anagram of them.\n\nYour task is to write a program that, for given two strings, computes the length of the longest hidden anagrams of them.\n\nSuppose, for instance, that \"anagram\" and \"grandmother\" are given. Their substrings \"nagr\" and \"gran\" are hidden anagrams since by moving letters you can have one from the other. They are the longest since any substrings of \"grandmother\" of lengths five or more must contain \"d\" or \"o\" that \"anagram\" does not. In this case, therefore, the length of the longest hidden anagrams is four. Note that a substring must be a sequence of letters occurring consecutively in the original string and so \"nagrm\" and \"granm\" are not hidden anagrams.\n\nInput\n\nThe input consists of a single test case in two lines.\n\n$s_1$\n\n$s_2$\n\n$s_1$ and $s_2$ are strings consisting of lowercase letters (a through z) and their lengths are between 1 and 4000, inclusive.\n\nOutput\n\nOutput the length of the longest hidden anagrams of $s_1$ and $s_2$. If there are no hidden anagrams, print a zero.\n\nSample Input 1\n\nanagram\ngrandmother\n\nSample Output 1\n\n4\n\nSample Input 2\n\nwilliamshakespeare\niamaweakishspeller\n\nSample Output 2\n\n18\n\nSample Input 3\n\naaaaaaaabbbbbbbb\nxxxxxabababxxxxxabab\n\nSample Output 3\n\n6\n\nSample Input 4\n\nabababacdcdcd\nefefefghghghghgh\n\nSample Output 4\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 822, "cpu_time_ms": 20000, "memory_kb": 875092}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s281589778", "group_id": "codeNet:p01127", "input_text": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nbool issquare(vector<string> m, vector<char> &c, int k){\n\tif(k >= c.size()){\n\t\treturn true;\n\t}\n\tint n = (int)c.size();\n\tint h = (int)m.size();\n\tint w = (int)m[0].size();\n\tint r = 0, l = w, u = h, d = 0;\n\tfor(int i = 0; i < h; i++){\n\t\tfor(int j = 0; j < w; j++){\n\t\t\tif(m[i][j] == c[k]){\n\t\t\t\tr = max(r, j);\n\t\t\t\tl = min(l, j);\n\t\t\t\tu = min(u, i);\n\t\t\t\td = max(d, i);\n\t\t\t}\n\t\t}\n\t}\n\t//printf(\"(%d, %d), (%d, %d)\\n\",r,l,u,d);\n\tbool flag = true;\n\tfor(int i = u; i <= d; i++){\n\t\tfor(int j = l; j <= r; j++){\n\t\t\tif(m[i][j] != '?' && m[i][j] != c[k]){\n\t\t\t\tflag = false;\n\t\t\t\ti = j = (int)1e9;\n\t\t\t}\n\t\t}\n\t}\n\tif(!flag)return false;\n\tfor(int i = u; i <= d; i++){\n\t\tfor(int j = l; j <= r; j++){\n\t\t\tif(m[i][j] == c[k]){\n\t\t\t\tm[i][j] = '?';\n\t\t\t}\n\t\t}\n\t}\n\treturn issquare(m, c, k+1);\n}\n\n\n\n\nint main(){\n\tint nn; cin >> nn;\n\tfor(int z = 0; z < nn; z++){\n\t\tint h,w; cin >> h >> w;\n\t\tvector<string> m(h);\n\t\tvector<char> c;\n\t\tfor(int i = 0; i < h; i++){\n\t\t\tcin >> m[i];\n\t\t}\n\t\tfor(int i = 0; i < h; i++){\n\t\t\tfor(int j = 0; j < w; j++){\n\t\t\t\tif(m[i][j] == '.')continue;\n\t\t\t\tbool flag1 = true;\n\t\t\t\tfor(int k = 0; k < c.size(); k++){\n\t\t\t\t\tif(m[i][j] == c[k]){\n\t\t\t\t\t\tflag1 = false;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(flag1)c.push_back(m[i][j]);\n\t\t\t}\n\t\t}\n\t\tsort(c.begin(), c.end());/*\n\t\tfor(int i = 0; i < c.size(); i++){\n\t\t\tcout << c[i] << \" \";\n\t\t}\n\t\tcout << endl;*/\n\t\tbool flag = false;\n\t\tdo{\n\t\t\tif(issquare(m, c, 0)){\n\t\t\t\tflag = true;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}while(next_permutation(c.begin(), c.end()));\n\t\tif(flag){\n\t\t\tcout << \"SAFE\" << endl;\n\t\t}\n\t\telse{\n\t\t\tcout << \"SUSPICIOUS\" << endl;\n\t\t}\n\t}\n\treturn 0;\n}\n\n\n\n", "language": "C++", "metadata": {"date": 1526294408, "filename_ext": "cpp", "original_language": "C++", "problem_description_relpath": "problem_descriptions/p01127.html", "problem_id": "p01127", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p01127/input.txt", "sample_output_relpath": "derived/input_output/data/p01127/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p01127/C++/s281589778.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s281589778", "user_id": "u339187218"}, "prompt_components": {"gold_output": "SAFE\nSAFE\nSAFE\nSUSPICIOUS\nSUSPICIOUS\nSUSPICIOUS\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nbool issquare(vector<string> m, vector<char> &c, int k){\n\tif(k >= c.size()){\n\t\treturn true;\n\t}\n\tint n = (int)c.size();\n\tint h = (int)m.size();\n\tint w = (int)m[0].size();\n\tint r = 0, l = w, u = h, d = 0;\n\tfor(int i = 0; i < h; i++){\n\t\tfor(int j = 0; j < w; j++){\n\t\t\tif(m[i][j] == c[k]){\n\t\t\t\tr = max(r, j);\n\t\t\t\tl = min(l, j);\n\t\t\t\tu = min(u, i);\n\t\t\t\td = max(d, i);\n\t\t\t}\n\t\t}\n\t}\n\t//printf(\"(%d, %d), (%d, %d)\\n\",r,l,u,d);\n\tbool flag = true;\n\tfor(int i = u; i <= d; i++){\n\t\tfor(int j = l; j <= r; j++){\n\t\t\tif(m[i][j] != '?' && m[i][j] != c[k]){\n\t\t\t\tflag = false;\n\t\t\t\ti = j = (int)1e9;\n\t\t\t}\n\t\t}\n\t}\n\tif(!flag)return false;\n\tfor(int i = u; i <= d; i++){\n\t\tfor(int j = l; j <= r; j++){\n\t\t\tif(m[i][j] == c[k]){\n\t\t\t\tm[i][j] = '?';\n\t\t\t}\n\t\t}\n\t}\n\treturn issquare(m, c, k+1);\n}\n\n\n\n\nint main(){\n\tint nn; cin >> nn;\n\tfor(int z = 0; z < nn; z++){\n\t\tint h,w; cin >> h >> w;\n\t\tvector<string> m(h);\n\t\tvector<char> c;\n\t\tfor(int i = 0; i < h; i++){\n\t\t\tcin >> m[i];\n\t\t}\n\t\tfor(int i = 0; i < h; i++){\n\t\t\tfor(int j = 0; j < w; j++){\n\t\t\t\tif(m[i][j] == '.')continue;\n\t\t\t\tbool flag1 = true;\n\t\t\t\tfor(int k = 0; k < c.size(); k++){\n\t\t\t\t\tif(m[i][j] == c[k]){\n\t\t\t\t\t\tflag1 = false;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(flag1)c.push_back(m[i][j]);\n\t\t\t}\n\t\t}\n\t\tsort(c.begin(), c.end());/*\n\t\tfor(int i = 0; i < c.size(); i++){\n\t\t\tcout << c[i] << \" \";\n\t\t}\n\t\tcout << endl;*/\n\t\tbool flag = false;\n\t\tdo{\n\t\t\tif(issquare(m, c, 0)){\n\t\t\t\tflag = true;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}while(next_permutation(c.begin(), c.end()));\n\t\tif(flag){\n\t\t\tcout << \"SAFE\" << endl;\n\t\t}\n\t\telse{\n\t\t\tcout << \"SUSPICIOUS\" << endl;\n\t\t}\n\t}\n\treturn 0;\n}\n\n\n\n", "problem_context": "X-Ray Screening System\n\nこれは 20XX 年の話である．再生発電網による安定したエネルギー供給，および液化合成燃料の発明によって航空旅客数は鰻登りに増加した．しかし，航空機によるテロリズムの脅威は依然として存在するため，高速でかつ高い信頼性をもつ自動手荷物検査システムの重要性が高まっている．検査官が全部の荷物を調べることは実際問題として困難であることから，自動検査において疑わしいと判断された手荷物だけを検査官で改めて調べるという仕組みを整えたいわけである．\n\n航空機業界からの要請を受け，国際客室保護会社（International Cabin Protection Company）では，新たな自動検査システムを開発するため，最近の旅客の手荷物について調査した．調査の結果，最近の旅客の手荷物には次のような傾向があることが判明した．\n\n手荷物は 1 辺だけが短い直方体のような形状をしている．\n\n一般の乗客が手荷物に詰めて航空機に持ち込む品物としてはノートパソコン，音楽プレイヤー，携帯ゲーム機，トランプなどがあり，これらはいずれも長方形である．\n\n個々の品物は，その長方形の辺が手荷物の辺と平行になるように詰めこまれる．\n\n一方，テロリズムに用いられるような武器は，長方形とは非常に異なる形状をもつ．\n\n上記の調査結果をふまえて，以下のような手荷物検査のためのモデルを考案した．それぞれの手荷物は X 線に対して透明である直方体の容器だとみなす．その中には X 線に対して不透明である複数の品物が入っている．ここで，直方体の 3 辺を x 軸，y 軸，z 軸とする座標系を考え，x 軸と平行な方向に X 線を照射して，y-z 平面に投影された画像を撮影する．撮影された画像は適当な大きさの格子に分割され，画像解析によって，それぞれの格子領域に映っている品物の材質が推定される．この会社には非常に高度の解析技術があり，材質の詳細な違いすらも解析することが可能であることから，品物の材質は互いに異なると考えることができる．なお，複数の品物が x 軸方向に関して重なっているときは，それぞれの格子領域について最も手前にある，すなわち x 座標が最小である品物の材質が得られる．また，2 つ以上の品物の x 座標が等しいことはないと仮定する．\n\nあなたの仕事は，画像解析の結果が与えられたときに，長方形ではない（武器であるかもしれない）品物が入っていることが断言できるか，あるいはその手荷物には長方形の品物以外のものは入っていないと推測されるかを判定するプログラムを作成することである．\n\nInput\n\n入力の先頭行には単一の正の整数が含まれ，これはデータセットの個数を表す．それぞれのデータセットは次の形式で与えられる．\n\nH W\n\n解析結果その1\n\n解析結果その2\n\n...\n\n解析結果そのH\n\nH は画像の縦の大きさ，W は横の大きさを表す整数である (1 <= h , w <= 50)．解析結果の各行は W 文字で構成されており，i 番目の文字は，行の左から i 番目にある格子領域における解析結果を表す．物質が検出された格子領域については，その材質が英大文字（A〜Z）によって表される．このとき，同じ材質であれば同じ文字が，また異なる材質であれば異なる文字が用いられる．物質が検出されなかった格子領域についてはドット（.）で表される．\n\nすべてのデータセットについて，材質の種類は 7 種類を超えないことが保証されている．\n\nOutput\n\nそれぞれのデータセットに対して，長方形以外の品物が確実に入っているときは「SUSPICIOUS」を，そうでないときは「SAFE」をそれぞれ 1 行に出力しなさい．\n\nSample Input\n\n6\n1 1\n.\n3 3\n...\n.W.\n...\n10 10\n..........\n.DDDDCCC..\n.DDDDCCC..\n.DDDDCCC..\nADDDDCCC..\nAAA..CCC..\nAAABBBBC..\nAAABBBB...\n..BBBBB...\n..........\n10 10\n..........\n.DDDDDD...\n.DDDDCCC..\n.DDDDCCC..\nADDDDCCC..\nAAA..CCC..\nAAABBBBC..\nAAABBBB...\n..BBBBB...\n..........\n10 10\nR..E..C.T.\nR.EEE.C.T.\n.EEEEE....\nEEEEEEE...\n.EEEEEEE..\n..EEEEEEE.\n...EEEEEEE\n....EEEEE.\n.....EEE..\n......E...\n16 50\n..................................................\n.........AAAAAAAAAAAAAAAA.........................\n....PPP...AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA.....\n....PPP...AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA.....\n....PPP...AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA....\n....PPP..............AAAAA.AAAAAAAAAAAAAAAA.......\n....PPP................A....AAA.AAAAAAAAAA........\n....PPP...........IIIIIAAIIAIII.AAAAAAAAAA........\n..CCCCCCCCCCCCC...IIIIIIAAAAAAAAAAAAAAAAAA........\n..CCCCCCCCCCCCC...IIIIIIIIIIIII...AAAAAAAAAA......\n....PPP............................AAAAAAAAAA.....\nMMMMPPPMMMMMMMMMMMMMMM.............AAAAAAAAAAA....\nMMMMPPPMMMMMMMMMMMMMMM..............AAAAAAAAAAA...\nMMMMMMMMMMMMMMMMMMMMMM...............AAAAAAAAAA...\nMMMMMMMMMMMMMMMMMMMMMM...............AAAAAAAAAA...\nMMMMMMMMMMMMMMMMMMMMMM............................\n\nOutput for the Sample Input\n\nSAFE\nSAFE\nSAFE\nSUSPICIOUS\nSUSPICIOUS\nSUSPICIOUS", "sample_input": "6\n1 1\n.\n3 3\n...\n.W.\n...\n10 10\n..........\n.DDDDCCC..\n.DDDDCCC..\n.DDDDCCC..\nADDDDCCC..\nAAA..CCC..\nAAABBBBC..\nAAABBBB...\n..BBBBB...\n..........\n10 10\n..........\n.DDDDDD...\n.DDDDCCC..\n.DDDDCCC..\nADDDDCCC..\nAAA..CCC..\nAAABBBBC..\nAAABBBB...\n..BBBBB...\n..........\n10 10\nR..E..C.T.\nR.EEE.C.T.\n.EEEEE....\nEEEEEEE...\n.EEEEEEE..\n..EEEEEEE.\n...EEEEEEE\n....EEEEE.\n.....EEE..\n......E...\n16 50\n..................................................\n.........AAAAAAAAAAAAAAAA.........................\n....PPP...AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA.....\n....PPP...AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA.....\n....PPP...AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA....\n....PPP..............AAAAA.AAAAAAAAAAAAAAAA.......\n....PPP................A....AAA.AAAAAAAAAA........\n....PPP...........IIIIIAAIIAIII.AAAAAAAAAA........\n..CCCCCCCCCCCCC...IIIIIIAAAAAAAAAAAAAAAAAA........\n..CCCCCCCCCCCCC...IIIIIIIIIIIII...AAAAAAAAAA......\n....PPP............................AAAAAAAAAA.....\nMMMMPPPMMMMMMMMMMMMMMM.............AAAAAAAAAAA....\nMMMMPPPMMMMMMMMMMMMMMM..............AAAAAAAAAAA...\nMMMMMMMMMMMMMMMMMMMMMM...............AAAAAAAAAA...\nMMMMMMMMMMMMMMMMMMMMMM...............AAAAAAAAAA...\nMMMMMMMMMMMMMMMMMMMMMM............................\n"}, "reference_outputs": ["SAFE\nSAFE\nSAFE\nSUSPICIOUS\nSUSPICIOUS\nSUSPICIOUS\n"], "source_document_id": "p01127", "source_text": "X-Ray Screening System\n\nこれは 20XX 年の話である．再生発電網による安定したエネルギー供給，および液化合成燃料の発明によって航空旅客数は鰻登りに増加した．しかし，航空機によるテロリズムの脅威は依然として存在するため，高速でかつ高い信頼性をもつ自動手荷物検査システムの重要性が高まっている．検査官が全部の荷物を調べることは実際問題として困難であることから，自動検査において疑わしいと判断された手荷物だけを検査官で改めて調べるという仕組みを整えたいわけである．\n\n航空機業界からの要請を受け，国際客室保護会社（International Cabin Protection Company）では，新たな自動検査システムを開発するため，最近の旅客の手荷物について調査した．調査の結果，最近の旅客の手荷物には次のような傾向があることが判明した．\n\n手荷物は 1 辺だけが短い直方体のような形状をしている．\n\n一般の乗客が手荷物に詰めて航空機に持ち込む品物としてはノートパソコン，音楽プレイヤー，携帯ゲーム機，トランプなどがあり，これらはいずれも長方形である．\n\n個々の品物は，その長方形の辺が手荷物の辺と平行になるように詰めこまれる．\n\n一方，テロリズムに用いられるような武器は，長方形とは非常に異なる形状をもつ．\n\n上記の調査結果をふまえて，以下のような手荷物検査のためのモデルを考案した．それぞれの手荷物は X 線に対して透明である直方体の容器だとみなす．その中には X 線に対して不透明である複数の品物が入っている．ここで，直方体の 3 辺を x 軸，y 軸，z 軸とする座標系を考え，x 軸と平行な方向に X 線を照射して，y-z 平面に投影された画像を撮影する．撮影された画像は適当な大きさの格子に分割され，画像解析によって，それぞれの格子領域に映っている品物の材質が推定される．この会社には非常に高度の解析技術があり，材質の詳細な違いすらも解析することが可能であることから，品物の材質は互いに異なると考えることができる．なお，複数の品物が x 軸方向に関して重なっているときは，それぞれの格子領域について最も手前にある，すなわち x 座標が最小である品物の材質が得られる．また，2 つ以上の品物の x 座標が等しいことはないと仮定する．\n\nあなたの仕事は，画像解析の結果が与えられたときに，長方形ではない（武器であるかもしれない）品物が入っていることが断言できるか，あるいはその手荷物には長方形の品物以外のものは入っていないと推測されるかを判定するプログラムを作成することである．\n\nInput\n\n入力の先頭行には単一の正の整数が含まれ，これはデータセットの個数を表す．それぞれのデータセットは次の形式で与えられる．\n\nH W\n\n解析結果その1\n\n解析結果その2\n\n...\n\n解析結果そのH\n\nH は画像の縦の大きさ，W は横の大きさを表す整数である (1 <= h , w <= 50)．解析結果の各行は W 文字で構成されており，i 番目の文字は，行の左から i 番目にある格子領域における解析結果を表す．物質が検出された格子領域については，その材質が英大文字（A〜Z）によって表される．このとき，同じ材質であれば同じ文字が，また異なる材質であれば異なる文字が用いられる．物質が検出されなかった格子領域についてはドット（.）で表される．\n\nすべてのデータセットについて，材質の種類は 7 種類を超えないことが保証されている．\n\nOutput\n\nそれぞれのデータセットに対して，長方形以外の品物が確実に入っているときは「SUSPICIOUS」を，そうでないときは「SAFE」をそれぞれ 1 行に出力しなさい．\n\nSample Input\n\n6\n1 1\n.\n3 3\n...\n.W.\n...\n10 10\n..........\n.DDDDCCC..\n.DDDDCCC..\n.DDDDCCC..\nADDDDCCC..\nAAA..CCC..\nAAABBBBC..\nAAABBBB...\n..BBBBB...\n..........\n10 10\n..........\n.DDDDDD...\n.DDDDCCC..\n.DDDDCCC..\nADDDDCCC..\nAAA..CCC..\nAAABBBBC..\nAAABBBB...\n..BBBBB...\n..........\n10 10\nR..E..C.T.\nR.EEE.C.T.\n.EEEEE....\nEEEEEEE...\n.EEEEEEE..\n..EEEEEEE.\n...EEEEEEE\n....EEEEE.\n.....EEE..\n......E...\n16 50\n..................................................\n.........AAAAAAAAAAAAAAAA.........................\n....PPP...AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA.....\n....PPP...AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA.....\n....PPP...AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA....\n....PPP..............AAAAA.AAAAAAAAAAAAAAAA.......\n....PPP................A....AAA.AAAAAAAAAA........\n....PPP...........IIIIIAAIIAIII.AAAAAAAAAA........\n..CCCCCCCCCCCCC...IIIIIIAAAAAAAAAAAAAAAAAA........\n..CCCCCCCCCCCCC...IIIIIIIIIIIII...AAAAAAAAAA......\n....PPP............................AAAAAAAAAA.....\nMMMMPPPMMMMMMMMMMMMMMM.............AAAAAAAAAAA....\nMMMMPPPMMMMMMMMMMMMMMM..............AAAAAAAAAAA...\nMMMMMMMMMMMMMMMMMMMMMM...............AAAAAAAAAA...\nMMMMMMMMMMMMMMMMMMMMMM...............AAAAAAAAAA...\nMMMMMMMMMMMMMMMMMMMMMM............................\n\nOutput for the Sample Input\n\nSAFE\nSAFE\nSAFE\nSUSPICIOUS\nSUSPICIOUS\nSUSPICIOUS", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1619, "cpu_time_ms": 2790, "memory_kb": 3316}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s664408984", "group_id": "codeNet:p01274", "input_text": "#include<cstdio>\n#include<cstring>\n#include<algorithm>\n#define maxn 100009\nusing namespace std;\n\nint dp1[10009];\nint dp2[10006];\nchar s[25];\n\nint num[105];\n\nint main()\n{\n    int n,m,x,y;\n    while(scanf(\"%d\",&n)&&n!=0)\n    {\n        int ma=-1;\n        for(int i=0; i<n; i++)\n            scanf(\"%d\",&num[i]);\n        sort(num,num+n);\n        memset(dp1,0,sizeof dp1);\n        memset(dp2,0,sizeof dp2);\n        scanf(\"%d\",&m);\n        for(int i=0; i<m; i++)\n        {\n            scanf(\"%s\",s);\n            scanf(\"%d\",&x);\n            scanf(\"%s\",s);\n            scanf(\"%d\",&y);\n//        printf(\"%d %d\\n\",x,y);\n            if(s[0]=='S')\n            {\n                for(int j=x; j<=10000; j++)\n                    dp1[j]=max(dp1[j],dp1[j-x]+y);//single\n            }\n            else\n            {\n                for(int j=x; j<=10000; j++)\n                    dp2[j]=max(dp2[j],dp2[j-x]+y);//all\n            }\n        }\n        long long ans=(long long)1<<62,sum;\n        for(int i=0; i<ans; i++)\n        {\n//            sum=lower_bound(dp2,dp2+10000,num[i])-dp2;\n            sum=i;\n//        printf(\"%d\\n\",tmp);\n            for(int j=0; j<n; j++)\n            {\n                sum+=lower_bound(dp1,dp1+10000,num[j]-dp2[i])-dp1;\n            }\n            ans=min(ans,sum);\n        }\n        printf(\"%lld\\n\",ans);\n    }\n    return 0;\n}", "language": "C++", "metadata": {"date": 1401099441, "filename_ext": "cpp", "original_language": "C++", "problem_description_relpath": "problem_descriptions/p01274.html", "problem_id": "p01274", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p01274/input.txt", "sample_output_relpath": "derived/input_output/data/p01274/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p01274/C++/s664408984.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s664408984", "user_id": "u130398666"}, "prompt_components": {"gold_output": "232\n", "input_to_evaluate": "#include<cstdio>\n#include<cstring>\n#include<algorithm>\n#define maxn 100009\nusing namespace std;\n\nint dp1[10009];\nint dp2[10006];\nchar s[25];\n\nint num[105];\n\nint main()\n{\n    int n,m,x,y;\n    while(scanf(\"%d\",&n)&&n!=0)\n    {\n        int ma=-1;\n        for(int i=0; i<n; i++)\n            scanf(\"%d\",&num[i]);\n        sort(num,num+n);\n        memset(dp1,0,sizeof dp1);\n        memset(dp2,0,sizeof dp2);\n        scanf(\"%d\",&m);\n        for(int i=0; i<m; i++)\n        {\n            scanf(\"%s\",s);\n            scanf(\"%d\",&x);\n            scanf(\"%s\",s);\n            scanf(\"%d\",&y);\n//        printf(\"%d %d\\n\",x,y);\n            if(s[0]=='S')\n            {\n                for(int j=x; j<=10000; j++)\n                    dp1[j]=max(dp1[j],dp1[j-x]+y);//single\n            }\n            else\n            {\n                for(int j=x; j<=10000; j++)\n                    dp2[j]=max(dp2[j],dp2[j-x]+y);//all\n            }\n        }\n        long long ans=(long long)1<<62,sum;\n        for(int i=0; i<ans; i++)\n        {\n//            sum=lower_bound(dp2,dp2+10000,num[i])-dp2;\n            sum=i;\n//        printf(\"%d\\n\",tmp);\n            for(int j=0; j<n; j++)\n            {\n                sum+=lower_bound(dp1,dp1+10000,num[j]-dp2[i])-dp1;\n            }\n            ans=min(ans,sum);\n        }\n        printf(\"%lld\\n\",ans);\n    }\n    return 0;\n}", "problem_context": "Problem B: Magic Slayer\n\nYou are in a fantasy monster-ridden world. You are a slayer fighting against the monsters with magic\nspells.\n\nThe monsters have hit points for each, which represent their vitality. You can decrease their hit points\nby your magic spells: each spell gives certain points of damage, by which monsters lose their hit points,\nto either one monster or all monsters in front of you (depending on the spell). Monsters are defeated\nwhen their hit points decrease to less than or equal to zero. On the other hand, each spell may consume\na certain amount of your magic power. Since your magic power is limited, you want to defeat monsters\nusing the power as little as possible.\n\nWrite a program for this purpose.\n\nInput\n\nThe input consists of multiple datasets. Each dataset has the following format:\n\nN\n\nHP1\n\nHP2\n\n...\n\nHPN\n\nM\n\nName1 MP1 Target1 Damage1\n\nName2 MP2 Target2 Damage2\n\n...\n\nNameM MPM TargetM DamageM\n\nN is the number of monsters in front of you (1 ≤ N ≤ 100); HPi is the hit points of the i-th monster\n(1 ≤ HPi ≤ 100000); M is the number of available magic spells (1 ≤ M ≤ 100); Namej is the name\nof the j-th spell, consisting of up to 16 uppercase and lowercase letters; MPj is the amount of magic\npower consumed by the j-th spell (0 ≤ MPj ≤ 99); Targetj is either \"Single\" or \"All\", where these\nindicate the j-th magic gives damage just to a single monster or to all monsters respectively; Damagej is\nthe amount of damage (per monster in case of \"All\") made by the j-th magic (0 ≤ Damagej ≤ 999999).\n\nAll the numbers in the input are integers. There is at least one spell that gives non-zero damage to\nmonsters.\n\nThe last dataset is followed by a line containing one zero. This line is not a part of any dataset and should not be processed.\n\nOutput\n\nFor each dataset, Print in a line the minimum amount of magic power consumed to defeat all the monsters in the input.\n\nSample Input\n\n3\n8000 15000 30000\n3\nFlare 45 Single 8000\nMeteor 62 All 6000\nUltimate 80 All 9999\n0\n\nOutput for the Sample Input\n\n232", "sample_input": "3\n8000 15000 30000\n3\nFlare 45 Single 8000\nMeteor 62 All 6000\nUltimate 80 All 9999\n0\n"}, "reference_outputs": ["232\n"], "source_document_id": "p01274", "source_text": "Problem B: Magic Slayer\n\nYou are in a fantasy monster-ridden world. You are a slayer fighting against the monsters with magic\nspells.\n\nThe monsters have hit points for each, which represent their vitality. You can decrease their hit points\nby your magic spells: each spell gives certain points of damage, by which monsters lose their hit points,\nto either one monster or all monsters in front of you (depending on the spell). Monsters are defeated\nwhen their hit points decrease to less than or equal to zero. On the other hand, each spell may consume\na certain amount of your magic power. Since your magic power is limited, you want to defeat monsters\nusing the power as little as possible.\n\nWrite a program for this purpose.\n\nInput\n\nThe input consists of multiple datasets. Each dataset has the following format:\n\nN\n\nHP1\n\nHP2\n\n...\n\nHPN\n\nM\n\nName1 MP1 Target1 Damage1\n\nName2 MP2 Target2 Damage2\n\n...\n\nNameM MPM TargetM DamageM\n\nN is the number of monsters in front of you (1 ≤ N ≤ 100); HPi is the hit points of the i-th monster\n(1 ≤ HPi ≤ 100000); M is the number of available magic spells (1 ≤ M ≤ 100); Namej is the name\nof the j-th spell, consisting of up to 16 uppercase and lowercase letters; MPj is the amount of magic\npower consumed by the j-th spell (0 ≤ MPj ≤ 99); Targetj is either \"Single\" or \"All\", where these\nindicate the j-th magic gives damage just to a single monster or to all monsters respectively; Damagej is\nthe amount of damage (per monster in case of \"All\") made by the j-th magic (0 ≤ Damagej ≤ 999999).\n\nAll the numbers in the input are integers. There is at least one spell that gives non-zero damage to\nmonsters.\n\nThe last dataset is followed by a line containing one zero. This line is not a part of any dataset and should not be processed.\n\nOutput\n\nFor each dataset, Print in a line the minimum amount of magic power consumed to defeat all the monsters in the input.\n\nSample Input\n\n3\n8000 15000 30000\n3\nFlare 45 Single 8000\nMeteor 62 All 6000\nUltimate 80 All 9999\n0\n\nOutput for the Sample Input\n\n232", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1335, "cpu_time_ms": 40, "memory_kb": 1128}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s961836625", "group_id": "codeNet:p01296", "input_text": "#include <iostream>\nusing namespace std;\n#define MAX 1000\n#define F_MAX 2000\n\nint n;\nint field[MAX][MAX];\n\nstruct futon{\n\tint x[2], y[2];\n};\n\nfuton F[F_MAX];\n\nint dx[] = {-1,0,1,0}, dy[] = {0,1,0,-1};\n\nbool dfs( int pos ){\n\tif( pos == n ) return true;\n\tbool rep = false;\n\tfor( int i = 0; i < 2; i++ ){\n\t\tint legx, legy, headx, heady;\n\t\tlegx = F[pos].x[i];\n\t\tlegy = F[pos].y[i];\n\t\theadx = F[pos].x[1-i];\n\t\theady = F[pos].y[1-i];\n\t\t//cout << \"----\" << pos << \"------\" << endl;\n\t\t//cout << legx << \" \" << legy << \" \" << headx << \" \" << heady << endl;\n\t\tbool ok = true;\n\t\tfor( int j = 0; j < 4; j++ ){\n\t\t\tif( (0 <= legx+dx[j] && legx+dx[j] < MAX) && (0 <= legy+dy[j] && legy+dy[j] < MAX) ){\n\t\t\t\tif( field[legx+dx[j]][legy+dy[j]] == 1 ) ok = false;\n\t\t\t}\n\t\t\tif( (0 <= headx+dx[j] && headx+dx[j] < MAX) && (0 <= heady+dy[j] && heady+dy[j] < MAX) ){\n\t\t\t\tif( field[headx+dx[j]][heady+dy[j]] == 2 ) ok = false;\n\t\t\t}\n\t\t}\n\t\tif( !ok ) continue;\n\t\tfield[headx][heady] = 1;\n\t\tfield[legx][legy] = 2;\n\t\tif( dfs(pos+1) ) rep = true;\n\t\tfield[headx][heady] = 0;\n\t\tfield[legx][legy] = 0;\n\t}\n\treturn rep;\n}\n\nint main(){\n\twhile( cin >> n, n ){\n\t\tfor( int i = 0; i < n; i++ ){\n\t\t\tint x, y;\n\t\t\tchar d;\n\t\t\tcin >> x >> y >> d;\n\t\t\tF[i].x[0] = x;\n\t\t\tF[i].y[0] = y;\n\t\t\tF[i].x[1] = (d == 'x') ? x+1 : x;\n\t\t\tF[i].y[1] = (d == 'x') ? y : y+1;\n\t\t}\n\t\tfor( int j = 0; j < MAX; j++ ){\n\t\t\tfor( int k = 0; k < MAX; k++ ){\n\t\t\t\tfield[j][k] = 0;\n\t\t\t}\n\t\t}\n\t\t/*for( int i = 0; i < n; i++ ){\n\t\t\tfor( int j = 0; j < 2; j++ ){\n\t\t\t\tcout << F[i].x[j] << \" \" << F[i].y[j] << \" \";\n\t\t\t}\n\t\t\tcout << endl;\n\t\t}*/\n\t\tif( dfs(0) ) cout << \"Yes\" << endl;\n\t\telse cout << \"No\" << endl;\n\t}\n}", "language": "C++", "metadata": {"date": 1395062779, "filename_ext": "cpp", "original_language": "C++", "problem_description_relpath": "problem_descriptions/p01296.html", "problem_id": "p01296", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p01296/input.txt", "sample_output_relpath": "derived/input_output/data/p01296/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p01296/C++/s961836625.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s961836625", "user_id": "u879745691"}, "prompt_components": {"gold_output": "Yes\nNo\nYes\n", "input_to_evaluate": "#include <iostream>\nusing namespace std;\n#define MAX 1000\n#define F_MAX 2000\n\nint n;\nint field[MAX][MAX];\n\nstruct futon{\n\tint x[2], y[2];\n};\n\nfuton F[F_MAX];\n\nint dx[] = {-1,0,1,0}, dy[] = {0,1,0,-1};\n\nbool dfs( int pos ){\n\tif( pos == n ) return true;\n\tbool rep = false;\n\tfor( int i = 0; i < 2; i++ ){\n\t\tint legx, legy, headx, heady;\n\t\tlegx = F[pos].x[i];\n\t\tlegy = F[pos].y[i];\n\t\theadx = F[pos].x[1-i];\n\t\theady = F[pos].y[1-i];\n\t\t//cout << \"----\" << pos << \"------\" << endl;\n\t\t//cout << legx << \" \" << legy << \" \" << headx << \" \" << heady << endl;\n\t\tbool ok = true;\n\t\tfor( int j = 0; j < 4; j++ ){\n\t\t\tif( (0 <= legx+dx[j] && legx+dx[j] < MAX) && (0 <= legy+dy[j] && legy+dy[j] < MAX) ){\n\t\t\t\tif( field[legx+dx[j]][legy+dy[j]] == 1 ) ok = false;\n\t\t\t}\n\t\t\tif( (0 <= headx+dx[j] && headx+dx[j] < MAX) && (0 <= heady+dy[j] && heady+dy[j] < MAX) ){\n\t\t\t\tif( field[headx+dx[j]][heady+dy[j]] == 2 ) ok = false;\n\t\t\t}\n\t\t}\n\t\tif( !ok ) continue;\n\t\tfield[headx][heady] = 1;\n\t\tfield[legx][legy] = 2;\n\t\tif( dfs(pos+1) ) rep = true;\n\t\tfield[headx][heady] = 0;\n\t\tfield[legx][legy] = 0;\n\t}\n\treturn rep;\n}\n\nint main(){\n\twhile( cin >> n, n ){\n\t\tfor( int i = 0; i < n; i++ ){\n\t\t\tint x, y;\n\t\t\tchar d;\n\t\t\tcin >> x >> y >> d;\n\t\t\tF[i].x[0] = x;\n\t\t\tF[i].y[0] = y;\n\t\t\tF[i].x[1] = (d == 'x') ? x+1 : x;\n\t\t\tF[i].y[1] = (d == 'x') ? y : y+1;\n\t\t}\n\t\tfor( int j = 0; j < MAX; j++ ){\n\t\t\tfor( int k = 0; k < MAX; k++ ){\n\t\t\t\tfield[j][k] = 0;\n\t\t\t}\n\t\t}\n\t\t/*for( int i = 0; i < n; i++ ){\n\t\t\tfor( int j = 0; j < 2; j++ ){\n\t\t\t\tcout << F[i].x[j] << \" \" << F[i].y[j] << \" \";\n\t\t\t}\n\t\t\tcout << endl;\n\t\t}*/\n\t\tif( dfs(0) ) cout << \"Yes\" << endl;\n\t\telse cout << \"No\" << endl;\n\t}\n}", "problem_context": "Problem D: Futon\n\nThe sales department of Japanese Ancient Giant Corp. is visiting a hot spring resort for their\nrecreational trip. For deepening their friendships, they are staying in one large room of a\nJapanese-style hotel called a ryokan.\n\nIn the ryokan, people sleep in Japanese-style beds called futons. They all have put their futons\non the floor just as they like. Now they are ready for sleeping but they have one concern: they\ndon’t like to go into their futons with their legs toward heads — this is regarded as a bad custom\nin Japanese tradition. However, it is not obvious whether they can follow a good custom. You\nare requested to write a program answering their question, as a talented programmer.\n\nHere let's model the situation. The room is considered to be a grid on an xy-plane. As usual,\nx-axis points toward right and y-axis points toward up. Each futon occupies two adjacent cells.\nPeople put their pillows on either of the two cells. Their heads come to the pillows; their foots\ncome to the other cells. If the cell of some person's foot becomes adjacent to the cell of another\nperson's head, regardless their directions, then it is considered as a bad case. Otherwise people\nare all right.\n\nInput\n\nThe input is a sequence of datasets. Each dataset is given in the following format:\n\nn\n\nx1 y1 dir1\n\n...\n\nxn yn dirn\n\nn is the number of futons (1 ≤ n ≤ 20,000); (xi, yi) denotes the coordinates of the left-bottom\ncorner of the i-th futon; diri is either 'x' or 'y' and denotes the direction of the i-th futon,\nwhere 'x' means the futon is put horizontally and 'y' means vertically. All coordinate values are\nnon-negative integers not greater than 109 .\n\nIt is guaranteed that no two futons in the input overlap each other.\n\nThe input is terminated by a line with a single zero. This is not part of any dataset and thus\nshould not be processed.\n\nOutput\n\nFor each dataset, print \"Yes\" in a line if it is possible to avoid a bad case, or \"No\" otherwise.\n\nSample Input\n\n4\n0 0 x\n2 0 x\n0 1 x\n2 1 x\n4\n1 0 x\n0 1 x\n2 1 x\n1 2 x\n4\n0 0 x\n2 0 y\n0 1 y\n1 2 x\n0\n\nOutput for the Sample Input\n\nYes\nNo\nYes", "sample_input": "4\n0 0 x\n2 0 x\n0 1 x\n2 1 x\n4\n1 0 x\n0 1 x\n2 1 x\n1 2 x\n4\n0 0 x\n2 0 y\n0 1 y\n1 2 x\n0\n"}, "reference_outputs": ["Yes\nNo\nYes\n"], "source_document_id": "p01296", "source_text": "Problem D: Futon\n\nThe sales department of Japanese Ancient Giant Corp. is visiting a hot spring resort for their\nrecreational trip. For deepening their friendships, they are staying in one large room of a\nJapanese-style hotel called a ryokan.\n\nIn the ryokan, people sleep in Japanese-style beds called futons. They all have put their futons\non the floor just as they like. Now they are ready for sleeping but they have one concern: they\ndon’t like to go into their futons with their legs toward heads — this is regarded as a bad custom\nin Japanese tradition. However, it is not obvious whether they can follow a good custom. You\nare requested to write a program answering their question, as a talented programmer.\n\nHere let's model the situation. The room is considered to be a grid on an xy-plane. As usual,\nx-axis points toward right and y-axis points toward up. Each futon occupies two adjacent cells.\nPeople put their pillows on either of the two cells. Their heads come to the pillows; their foots\ncome to the other cells. If the cell of some person's foot becomes adjacent to the cell of another\nperson's head, regardless their directions, then it is considered as a bad case. Otherwise people\nare all right.\n\nInput\n\nThe input is a sequence of datasets. Each dataset is given in the following format:\n\nn\n\nx1 y1 dir1\n\n...\n\nxn yn dirn\n\nn is the number of futons (1 ≤ n ≤ 20,000); (xi, yi) denotes the coordinates of the left-bottom\ncorner of the i-th futon; diri is either 'x' or 'y' and denotes the direction of the i-th futon,\nwhere 'x' means the futon is put horizontally and 'y' means vertically. All coordinate values are\nnon-negative integers not greater than 109 .\n\nIt is guaranteed that no two futons in the input overlap each other.\n\nThe input is terminated by a line with a single zero. This is not part of any dataset and thus\nshould not be processed.\n\nOutput\n\nFor each dataset, print \"Yes\" in a line if it is possible to avoid a bad case, or \"No\" otherwise.\n\nSample Input\n\n4\n0 0 x\n2 0 x\n0 1 x\n2 1 x\n4\n1 0 x\n0 1 x\n2 1 x\n1 2 x\n4\n0 0 x\n2 0 y\n0 1 y\n1 2 x\n0\n\nOutput for the Sample Input\n\nYes\nNo\nYes", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1629, "cpu_time_ms": 10, "memory_kb": 5048}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s126332106", "group_id": "codeNet:p01316", "input_text": "#include <iostream>\n#include <climits>\n#include <algorithm>\nusing namespace std;\n\n#define p(x) (x)*(x)\n\nint round(int x)\n{\n  if(x > 255) return 255;\n  else if(x < 0) return 0;\n  else return x;\n}\n\nint main()\n{\n  while(1){\n    int N, M;\n    cin >> N >> M;\n    if(N == 0 && M == 0) break;\n    int C[M], x[N];\n    for(int i = 0; i < M; i++)\n      cin >> C[i];\n    for(int i = 0; i < N; i++)\n      cin >> x[i];\n    int a[256];\n    fill(a,a+256,INT_MAX);\n    for(int i = 0; i < M; i++){\n      int n = round(128+C[i]);\n      a[n] = p(n-x[0]);\n    }\n    int b[256];\n    for(int t = 1; t < N; t++){\n      fill(b,b+256,INT_MAX);\n      for(int i = 0; i < 256; i++){\n        if(a[i] == INT_MAX) continue;\n        for(int j = 0; j < M; j++){\n          int n = round(i+C[j]);\n          b[n] = min(b[n],a[i]+p(n-x[t]));\n        }\n      }\n      copy(b,b+256,a);\n    }\n    cout << *min_element(a,a+256) << endl;\n  }\n}", "language": "C++", "metadata": {"date": 1471767417, "filename_ext": "cpp", "original_language": "C++", "problem_description_relpath": "problem_descriptions/p01316.html", "problem_id": "p01316", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p01316/input.txt", "sample_output_relpath": "derived/input_output/data/p01316/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p01316/C++/s126332106.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s126332106", "user_id": "u981364540"}, "prompt_components": {"gold_output": "2\n8\n0\n325125\n65026\n", "input_to_evaluate": "#include <iostream>\n#include <climits>\n#include <algorithm>\nusing namespace std;\n\n#define p(x) (x)*(x)\n\nint round(int x)\n{\n  if(x > 255) return 255;\n  else if(x < 0) return 0;\n  else return x;\n}\n\nint main()\n{\n  while(1){\n    int N, M;\n    cin >> N >> M;\n    if(N == 0 && M == 0) break;\n    int C[M], x[N];\n    for(int i = 0; i < M; i++)\n      cin >> C[i];\n    for(int i = 0; i < N; i++)\n      cin >> x[i];\n    int a[256];\n    fill(a,a+256,INT_MAX);\n    for(int i = 0; i < M; i++){\n      int n = round(128+C[i]);\n      a[n] = p(n-x[0]);\n    }\n    int b[256];\n    for(int t = 1; t < N; t++){\n      fill(b,b+256,INT_MAX);\n      for(int i = 0; i < 256; i++){\n        if(a[i] == INT_MAX) continue;\n        for(int j = 0; j < M; j++){\n          int n = round(i+C[j]);\n          b[n] = min(b[n],a[i]+p(n-x[t]));\n        }\n      }\n      copy(b,b+256,a);\n    }\n    cout << *min_element(a,a+256) << endl;\n  }\n}", "problem_context": "Problem C: Differential Pulse Code Modulation\n\n差分パルス符号変調は主に音声信号を圧縮する際に用いられる圧縮手法の一つである．\n\n音声信号は計算機上では整数列(インパルス列)として扱われる．整数列は入力信号を一定時間間隔で標本化(サンプリング)し，振幅を記録したものである．一般にこの整数列は前後の値が近いという傾向がある．これを利用し，前後の値の差分を符号化し，圧縮率を向上させるのが差分パルス符号変調である．\n\n本問題では差分の値をあらかじめ定められた値の集合から選ぶことを考える．この値の集合をコードブックと呼ぶことにする．復号化後の音声信号\nyn は以下の式で定められる．\n\nyn = yn\n- 1 + C[kn]\n\nここで kn はプログラムによって出力される出力系列， C[j]\nはコードブックの j 番目の値である．ただし yn\nは加算によって0未満の値となった場合は0に，255より大きい値となった場合は255にそれぞれ丸められる．また， y0\nの値は128とする．\n\nあなたの仕事は，入力信号とコードブックが与えられたときに，元の入力信号と復号化後の出力信号との差の二乗和が最小となるように出力系列を選んで，そのときの差の二乗和を出力するプログラムを書くことである．\n\n例えば，コードブックとして {4, 2, 1, 0, -1, -2, -4} という値のセットを使って\n131, 137 という列を圧縮する場合，\ny0 = 128,\ny1 = 128 + 4 = 132,\ny2 = 132 + 4 = 136 という列に圧縮すると\n二乗和が (131 - 132)^2 + (137 - 136)^2 = 2 と最小になる．\n\nまた，同じくコードブックとして {4, 2, 1, 0, -1, -2, -4} という値のセットを使って\n131, 123 という列を圧縮する場合，\ny0 = 128,\ny1 = 128 + 1 = 129,\ny2 = 129 - 4 = 125 と，先程の例とは違って\n131 により近づく +2 を採用しない方が\n(131 - 129) ^ 2 + (123 - 125) ^ 2 = 8\nというより小さな二乗和が得られる．\n\n上記 2つの例は sample input の最初の 2例である．\n\nInput\n\n入力は複数のデータセットから構成される．各データセットの形式は次に示すとおりである．\n\nN M\n\nC1\n\nC2\n\n...\n\nCM\n\nx1\n\nx2\n\n...\n\nxN\n\n最初の行は，入力データセットの大きさを規定する． N は圧縮する入力信号の長さ(サンプル数)である． M\nはコードブックに含まれる値の個数である． N 及び M は1 ≤ N ≤ 20000，1\n≤ M ≤ 16を満たす．\n\nこれに続く M 行は，コードブックの記述である． Ci はコードブックに含まれる\ni 番目の値を表す． Ci は-255 ≤ Ci\n≤ 255を満たす．\n\nこれに続く N 行は，入力信号の記述である． xi は入力信号を表す整数列の i\n番目の値である． xi は0 ≤ xi ≤ 255を満たす．\n\nデータセットの中の入力項目は，すべて整数である．入力の終りは，空白文字1個で区切られた2個のゼロのみからなる行で表される．\n\nOutput\n\n入力の各データセットに対して， 元の入力信号と復号化後の出力信号との差の二乗和の最小値を一行で出力せよ．\n\nSample Input\n\n2 7\n4\n2\n1\n0\n-1\n-2\n-4\n131\n137\n2 7\n4\n2\n1\n0\n-1\n-2\n-4\n131\n123\n10 7\n-4\n-2\n-1\n0\n1\n2\n4\n132\n134\n135\n134\n132\n128\n124\n122\n121\n122\n5 1\n255\n0\n0\n0\n0\n0\n4 1\n0\n255\n0\n255\n0\n0 0\n\nOutput for the Sample Input\n\n2\n8\n0\n325125\n65026", "sample_input": "2 7\n4\n2\n1\n0\n-1\n-2\n-4\n131\n137\n2 7\n4\n2\n1\n0\n-1\n-2\n-4\n131\n123\n10 7\n-4\n-2\n-1\n0\n1\n2\n4\n132\n134\n135\n134\n132\n128\n124\n122\n121\n122\n5 1\n255\n0\n0\n0\n0\n0\n4 1\n0\n255\n0\n255\n0\n0 0\n"}, "reference_outputs": ["2\n8\n0\n325125\n65026\n"], "source_document_id": "p01316", "source_text": "Problem C: Differential Pulse Code Modulation\n\n差分パルス符号変調は主に音声信号を圧縮する際に用いられる圧縮手法の一つである．\n\n音声信号は計算機上では整数列(インパルス列)として扱われる．整数列は入力信号を一定時間間隔で標本化(サンプリング)し，振幅を記録したものである．一般にこの整数列は前後の値が近いという傾向がある．これを利用し，前後の値の差分を符号化し，圧縮率を向上させるのが差分パルス符号変調である．\n\n本問題では差分の値をあらかじめ定められた値の集合から選ぶことを考える．この値の集合をコードブックと呼ぶことにする．復号化後の音声信号\nyn は以下の式で定められる．\n\nyn = yn\n- 1 + C[kn]\n\nここで kn はプログラムによって出力される出力系列， C[j]\nはコードブックの j 番目の値である．ただし yn\nは加算によって0未満の値となった場合は0に，255より大きい値となった場合は255にそれぞれ丸められる．また， y0\nの値は128とする．\n\nあなたの仕事は，入力信号とコードブックが与えられたときに，元の入力信号と復号化後の出力信号との差の二乗和が最小となるように出力系列を選んで，そのときの差の二乗和を出力するプログラムを書くことである．\n\n例えば，コードブックとして {4, 2, 1, 0, -1, -2, -4} という値のセットを使って\n131, 137 という列を圧縮する場合，\ny0 = 128,\ny1 = 128 + 4 = 132,\ny2 = 132 + 4 = 136 という列に圧縮すると\n二乗和が (131 - 132)^2 + (137 - 136)^2 = 2 と最小になる．\n\nまた，同じくコードブックとして {4, 2, 1, 0, -1, -2, -4} という値のセットを使って\n131, 123 という列を圧縮する場合，\ny0 = 128,\ny1 = 128 + 1 = 129,\ny2 = 129 - 4 = 125 と，先程の例とは違って\n131 により近づく +2 を採用しない方が\n(131 - 129) ^ 2 + (123 - 125) ^ 2 = 8\nというより小さな二乗和が得られる．\n\n上記 2つの例は sample input の最初の 2例である．\n\nInput\n\n入力は複数のデータセットから構成される．各データセットの形式は次に示すとおりである．\n\nN M\n\nC1\n\nC2\n\n...\n\nCM\n\nx1\n\nx2\n\n...\n\nxN\n\n最初の行は，入力データセットの大きさを規定する． N は圧縮する入力信号の長さ(サンプル数)である． M\nはコードブックに含まれる値の個数である． N 及び M は1 ≤ N ≤ 20000，1\n≤ M ≤ 16を満たす．\n\nこれに続く M 行は，コードブックの記述である． Ci はコードブックに含まれる\ni 番目の値を表す． Ci は-255 ≤ Ci\n≤ 255を満たす．\n\nこれに続く N 行は，入力信号の記述である． xi は入力信号を表す整数列の i\n番目の値である． xi は0 ≤ xi ≤ 255を満たす．\n\nデータセットの中の入力項目は，すべて整数である．入力の終りは，空白文字1個で区切られた2個のゼロのみからなる行で表される．\n\nOutput\n\n入力の各データセットに対して， 元の入力信号と復号化後の出力信号との差の二乗和の最小値を一行で出力せよ．\n\nSample Input\n\n2 7\n4\n2\n1\n0\n-1\n-2\n-4\n131\n137\n2 7\n4\n2\n1\n0\n-1\n-2\n-4\n131\n123\n10 7\n-4\n-2\n-1\n0\n1\n2\n4\n132\n134\n135\n134\n132\n128\n124\n122\n121\n122\n5 1\n255\n0\n0\n0\n0\n0\n4 1\n0\n255\n0\n255\n0\n0 0\n\nOutput for the Sample Input\n\n2\n8\n0\n325125\n65026", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 900, "cpu_time_ms": 680, "memory_kb": 1236}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s574487919", "group_id": "codeNet:p01414", "input_text": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <queue>\n#include <algorithm>\n#include <cstdlib>\n#include <map>\nusing namespace std;\n\nint N;\n\nvector<int> mem;\nvector<int> mas;\n\nvector<int> item[25];\n\n\nint w[16];\nint h[16];\n\nchar memo[2][1<<25];\nchar dfs(int init){\n\n\tchar *a = memo[0] , *b = memo[1];\n\t\n\tfor(int j = 0 ; j < (1<<25) ; j++)\n\t\ta[j] = 32;\n\t\n\ta[init] = 0;\n\t\n\tfor(int i = 0 ; i < 5 * 5 ; i++){\n\t\tfor(int j = 0 ; j < (1<<25) ; j++) b[j] = a[j];\n\t\tfor(int j = 0 ; j < (1<<25) ; j++){\n\t\t\tif( a[j] == 32 ) continue;\n\t\t\tfor(int k = 0 ; k < item[i].size() ; k++)\n\t\t\t\tb[j^item[i][k]] = min(b[j^item[i][k]],(char)(a[j]+1));\n\t\t}\n\t\tswap(a,b);\n\t}\n\t\n}\t\n\nint main(){\n\t\n\tfor(int w = 1 ; w <= 5 ; w++){\n\t\tfor(int h = 1 ; h <= 5 ; h++){\n\t\t\tfor(int i = 0 ; i <= 5 - h ; i++){\n\t\t\t\tfor(int j = 0 ; j <= 5 - w ; j++){\n\t\t\t\t\tint mask = 0;\n\t\t\t\t\tfor(int k = 0 ; k < h ; k++)\n\t\t\t\t\t\tfor(int l = 0 ; l < w ; l++)\n\t\t\t\t\t\t\tmask |= (1<<((i+k)*5+j+l));\n\t\t\t\t\t//cout << init << \" \" << mask << endl;\n\t\t\t\t\titem[i*5+j].push_back(mask);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tdfs(0);\n\twhile(cin >> N && N){\n\t\tint init = 0;\n\t\tfor(int i = 0 ; i < N ; i++){\n\t\t\tfor(int j = 0 ; j < N ; j++){\n\t\t\t\tint c = 0;\n\t\t\t\tcin >> c;\n\t\t\t\tinit |= (c<<(i*5+j));\n\t\t\t}\n\t\t}\n\t\tint x = memo[0][init];\n\t\tfor(int i = 0 ; i < x ; i++) cout << \"myon\";\n\t\tcout << endl;\n\t}\n}", "language": "C++", "metadata": {"date": 1352044997, "filename_ext": "cpp", "original_language": "C++", "problem_description_relpath": "problem_descriptions/p01414.html", "problem_id": "p01414", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p01414/input.txt", "sample_output_relpath": "derived/input_output/data/p01414/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p01414/C++/s574487919.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Memory Limit Exceeded", "submission_id": "s574487919", "user_id": "u458173932"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <iostream>\n#include <algorithm>\n#include <map>\n#include <queue>\n#include <algorithm>\n#include <cstdlib>\n#include <map>\nusing namespace std;\n\nint N;\n\nvector<int> mem;\nvector<int> mas;\n\nvector<int> item[25];\n\n\nint w[16];\nint h[16];\n\nchar memo[2][1<<25];\nchar dfs(int init){\n\n\tchar *a = memo[0] , *b = memo[1];\n\t\n\tfor(int j = 0 ; j < (1<<25) ; j++)\n\t\ta[j] = 32;\n\t\n\ta[init] = 0;\n\t\n\tfor(int i = 0 ; i < 5 * 5 ; i++){\n\t\tfor(int j = 0 ; j < (1<<25) ; j++) b[j] = a[j];\n\t\tfor(int j = 0 ; j < (1<<25) ; j++){\n\t\t\tif( a[j] == 32 ) continue;\n\t\t\tfor(int k = 0 ; k < item[i].size() ; k++)\n\t\t\t\tb[j^item[i][k]] = min(b[j^item[i][k]],(char)(a[j]+1));\n\t\t}\n\t\tswap(a,b);\n\t}\n\t\n}\t\n\nint main(){\n\t\n\tfor(int w = 1 ; w <= 5 ; w++){\n\t\tfor(int h = 1 ; h <= 5 ; h++){\n\t\t\tfor(int i = 0 ; i <= 5 - h ; i++){\n\t\t\t\tfor(int j = 0 ; j <= 5 - w ; j++){\n\t\t\t\t\tint mask = 0;\n\t\t\t\t\tfor(int k = 0 ; k < h ; k++)\n\t\t\t\t\t\tfor(int l = 0 ; l < w ; l++)\n\t\t\t\t\t\t\tmask |= (1<<((i+k)*5+j+l));\n\t\t\t\t\t//cout << init << \" \" << mask << endl;\n\t\t\t\t\titem[i*5+j].push_back(mask);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tdfs(0);\n\twhile(cin >> N && N){\n\t\tint init = 0;\n\t\tfor(int i = 0 ; i < N ; i++){\n\t\t\tfor(int j = 0 ; j < N ; j++){\n\t\t\t\tint c = 0;\n\t\t\t\tcin >> c;\n\t\t\t\tinit |= (c<<(i*5+j));\n\t\t\t}\n\t\t}\n\t\tint x = memo[0][init];\n\t\tfor(int i = 0 ; i < x ; i++) cout << \"myon\";\n\t\tcout << endl;\n\t}\n}", "problem_context": "H: Rectangular Stamps\n\nICPC で良い成績を収めるには修行が欠かせない．うさぎは ICPC で勝ちたいので，今日も修行をすることにした．\n\n今日の修行は，絵を描くことによって，創造力を高めようというものである．四角いスタンプを用いて，上手く模様を描こう．\n\n大小さまざまなスタンプを使い，4 × 4 のマス目の紙に指定された赤・緑・青の通りの絵を完成させたい．スタンプは長方形であり，マス目にぴったり合わせて使う．スタンプの縦と横を入れ替えることはできない．\n\n紙は最初色が塗られていない状態にある．紙にスタンプを押すと，押された部分がスタンプの色に変わり，下に隠れた色は全く見えなくなる．スタンプの色は付けるインクにより決定されるので，どのスタンプでも，好きな色を選ぶことが可能である．スタンプは紙から一部がはみ出た状態で押すことも可能であり，はみ出た部分は無視される．\n\n1 つのスタンプを複数回使うことは可能である．同じスタンプを別の色に対して使ってもよい．スタンプを押すのはやや神経を使う作業なので，出来るだけスタンプを押す回数を少なくしたい．\n\nInput\n\nN\nH1 W1\n...\nHN WN\nC1,1C1,2C1,3C1,4\nC2,1C2,2C2,3C2,4\nC3,1C3,2C3,3C3,4\nC4,1C4,2C4,3C4,4\n\nN はスタンプの個数，Hi, Wi (1 ≤ i ≤ N) はそれぞれ，i 番目のスタンプの縦の長さ，横の長さを表す整数である．Ci, j (1 ≤ i ≤ 4，1 ≤ j ≤ 4) は���上から i 行目，左から j 列目のマスについて指定された絵の色を表す文字である．赤は R ，緑は G ，青は B で表される．\n\n1 ≤ N ≤ 16，1 ≤ Hi ≤ 4，1 ≤ Wi ≤ 4 を満たす．(Hi, Wi) として同一の組は複数回現れない．\n\nOutput\n\n絵を完成させるためにスタンプを押さなければならない最小の回数を 1 行に出力せよ．\n\nSample Input 1\n\n2\n4 4\n1 1\nRRRR\nRRGR\nRBRR\nRRRR\n\nSample Output 1\n\n3\n\nSample Input 2\n\n1\n2 3\nRRGG\nBRGG\nBRRR\nBRRR\n\nSample Output 2\n\n5", "sample_input": "2\n4 4\n1 1\nRRRR\nRRGR\nRBRR\nRRRR\n"}, "reference_outputs": ["3\n"], "source_document_id": "p01414", "source_text": "H: Rectangular Stamps\n\nICPC で良い成績を収めるには修行が欠かせない．うさぎは ICPC で勝ちたいので，今日も修行をすることにした．\n\n今日の修行は，絵を描くことによって，創造力を高めようというものである．四角いスタンプを用いて，上手く模様を描こう．\n\n大小さまざまなスタンプを使い，4 × 4 のマス目の紙に指定された赤・緑・青の通りの絵を完成させたい．スタンプは長方形であり，マス目にぴったり合わせて使う．スタンプの縦と横を入れ替えることはできない．\n\n紙は最初色が塗られていない状態にある．紙にスタンプを押すと，押された部分がスタンプの色に変わり，下に隠れた色は全く見えなくなる．スタンプの色は付けるインクにより決定されるので，どのスタンプでも，好きな色を選ぶことが可能である．スタンプは紙から一部がはみ出た状態で押すことも可能であり，はみ出た部分は無視される．\n\n1 つのスタンプを複数回使うことは可能である．同じスタンプを別の色に対して使ってもよい．スタンプを押すのはやや神経を使う作業なので，出来るだけスタンプを押す回数を少なくしたい．\n\nInput\n\nN\nH1 W1\n...\nHN WN\nC1,1C1,2C1,3C1,4\nC2,1C2,2C2,3C2,4\nC3,1C3,2C3,3C3,4\nC4,1C4,2C4,3C4,4\n\nN はスタンプの個数，Hi, Wi (1 ≤ i ≤ N) はそれぞれ，i 番目のスタンプの縦の長さ，横の長さを表す整数である．Ci, j (1 ≤ i ≤ 4，1 ≤ j ≤ 4) は，上から i 行目，左から j 列目のマスについて指定された絵の色を表す文字である．赤は R ，緑は G ，青は B で表される．\n\n1 ≤ N ≤ 16，1 ≤ Hi ≤ 4，1 ≤ Wi ≤ 4 を満たす．(Hi, Wi) として同一の組は複数回現れない．\n\nOutput\n\n絵を完成させるためにスタンプを押さなければならない最小の回数を 1 行に出力せよ．\n\nSample Input 1\n\n2\n4 4\n1 1\nRRRR\nRRGR\nRBRR\nRRRR\n\nSample Output 1\n\n3\n\nSample Input 2\n\n1\n2 3\nRRGG\nBRGG\nBRRR\nBRRR\n\nSample Output 2\n\n5", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1313, "cpu_time_ms": 10000, "memory_kb": 66744}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s235437227", "group_id": "codeNet:p01481", "input_text": "#include <iostream>\n#include <string>\n#define N1 (1000+1)\nusing namespace std;\nint find(int);\nvoid unite(int,int);\nbool same(int,int);\nint tree[N1*N1];\nstring str[N1];\nint main(){\n  int W,H,N,x,y,findy,findx;\n  int dx[4]={0,1,0,-1};\n  int dy[4]={-1,0,1,0};\n  cin >> W >> H;\n  for(int i=0;i<H;i++) cin >> str[i];\n  for(int i=0;i<H;i++){\n    for(int j=0;j<W;j++){\n      tree[i*W+j]=i*W+j;      \n    }\n  }\n  for(int i=0;i<H;i++){\n    for(int j=0;j<W;j++){\n      if(str[i][j]=='t') findy=i,findx=j;\n      if(str[i][j]!='#'){\n\tfor(int k=0;k<4;k++)\n\t  if(0<=i+dy[k]&&i+dy[k]<H&&0<=j+dx[k]&&j+dx[k]<W)\n\t    if(str[i+dy[k]][j+dx[k]]!='#')\n\t      unite(i*W+j,(i+dy[k])*W+(j+dx[k]));\n      }\n    }\n  }\n  cin >> N;\n  int flag=0;\n  if(same(0,findy*W+findx)){\n    flag=1;\n    cout << 0 << endl;\n  }\n  int cnt=0;\n  while(N--&&flag==0){\n    cnt++;\n    cin >> x >> y;\n    str[y][x]='.';\n    for(int i=0;i<4;i++)\n      if(0<=y+dy[i]&&y+dy[i]<H&&0<=x+dx[i]&&x+dx[i]<W&&str[y+dy[i]][x+dx[i]]!='#')\n\tunite(y*W+x,(y+dy[i])*W+(x+dx[i]));\n    if(same(0,findy*W+findx)){\n      flag=1;\n      cout << cnt << endl;\n      break;\n    }\n  }\n  if(flag==0) cout << -1 << endl;\n  return 0;\n}\nint st[N1*N1];\nint find(int x){\n  int cnt=0;\n  while(x!=tree[x]){\n    x=tree[x];\n    st[cnt]=x;\n    cnt++;\n  }\n  while(cnt>0){\n    cnt--;\n    tree[st[cnt]]=x;\n  }\n  return x;\n}\nvoid unite(int x,int y){\n  x=find(x),y=find(y);\n  if(x==y) return ;\n  if(x<y) swap(x,y);\n  tree[x]=y;\n}\nbool same(int x,int y){\n  if(find(x)==find(y)) return true;\n  return false;\n}", "language": "C++", "metadata": {"date": 1445433923, "filename_ext": "cpp", "original_language": "C++", "problem_description_relpath": "problem_descriptions/p01481.html", "problem_id": "p01481", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p01481/input.txt", "sample_output_relpath": "derived/input_output/data/p01481/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p01481/C++/s235437227.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s235437227", "user_id": "u084540620"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <iostream>\n#include <string>\n#define N1 (1000+1)\nusing namespace std;\nint find(int);\nvoid unite(int,int);\nbool same(int,int);\nint tree[N1*N1];\nstring str[N1];\nint main(){\n  int W,H,N,x,y,findy,findx;\n  int dx[4]={0,1,0,-1};\n  int dy[4]={-1,0,1,0};\n  cin >> W >> H;\n  for(int i=0;i<H;i++) cin >> str[i];\n  for(int i=0;i<H;i++){\n    for(int j=0;j<W;j++){\n      tree[i*W+j]=i*W+j;      \n    }\n  }\n  for(int i=0;i<H;i++){\n    for(int j=0;j<W;j++){\n      if(str[i][j]=='t') findy=i,findx=j;\n      if(str[i][j]!='#'){\n\tfor(int k=0;k<4;k++)\n\t  if(0<=i+dy[k]&&i+dy[k]<H&&0<=j+dx[k]&&j+dx[k]<W)\n\t    if(str[i+dy[k]][j+dx[k]]!='#')\n\t      unite(i*W+j,(i+dy[k])*W+(j+dx[k]));\n      }\n    }\n  }\n  cin >> N;\n  int flag=0;\n  if(same(0,findy*W+findx)){\n    flag=1;\n    cout << 0 << endl;\n  }\n  int cnt=0;\n  while(N--&&flag==0){\n    cnt++;\n    cin >> x >> y;\n    str[y][x]='.';\n    for(int i=0;i<4;i++)\n      if(0<=y+dy[i]&&y+dy[i]<H&&0<=x+dx[i]&&x+dx[i]<W&&str[y+dy[i]][x+dx[i]]!='#')\n\tunite(y*W+x,(y+dy[i])*W+(x+dx[i]));\n    if(same(0,findy*W+findx)){\n      flag=1;\n      cout << cnt << endl;\n      break;\n    }\n  }\n  if(flag==0) cout << -1 << endl;\n  return 0;\n}\nint st[N1*N1];\nint find(int x){\n  int cnt=0;\n  while(x!=tree[x]){\n    x=tree[x];\n    st[cnt]=x;\n    cnt++;\n  }\n  while(cnt>0){\n    cnt--;\n    tree[st[cnt]]=x;\n  }\n  return x;\n}\nvoid unite(int x,int y){\n  x=find(x),y=find(y);\n  if(x==y) return ;\n  if(x<y) swap(x,y);\n  tree[x]=y;\n}\nbool same(int x,int y){\n  if(find(x)==find(y)) return true;\n  return false;\n}", "problem_context": "Lucky Dip\n\nTime Limit: 8 sec / Memory Limit: 64 MB\n\nC: 福袋\n\n福袋，それは年始を祝う商習慣の一つである．\n人気の福袋には多くの人が開店前から行列を作り，ターゲットの福袋へダッシュする．\nこの風物詩に魅了されたあなたは，今年もお目当ての福袋を狙い，計画を立てていた．\n\nしかし，お客を呼び寄せる側の某百貨店の店長は頭を悩ませていた．\nどうやらフロアの準備が開店に間に合いそうにない．\n\nそこで店長はある一つのアイディアを思いついた．\nそれは開店後，店内を徐々に開放すればなんとか営業できるのではないかというものである．\n\nあなたは刻一刻と変化する店内の情報を元に，お目当ての福袋がどの時間帯から入手できるのかを調べたい．\n\nInput\n\n入力は単一のデータセットで与えられ，EOFで終了する．\n\n店内の様子は各行が W 文字からなる H 行の文字列で表される．\n\n1 行目\n\nW H\n2 < W, H <= 1000\n\n続く H 行\n\n店内の様子\n\n.: 床\n\n#: 壁\n\nt: 目的の福袋\n\n目的の福袋は店内に必ず1つだけ存在する．\n\nH + 2 行目\n\n営業時間 N (0 <= N <= 1000)\n\n続く N 行\n\nx1 y1\nx2 x2\n...\nxi yi\n...\nxn yn\n\n(xi, yi)は，i 時間目に開放される壁の座標を表す．(0 <= xi < W, 0 <= yi < H)\n\nxi が列，yi が行である．\n\n開放される壁の座標の位置が \"#\" なら \".\" に置き換え，\".\" なら何もしない．\n\n目的の福袋が開放されることはない．\n\n(0, 0) が壁になることはない．\n\nまたあるマスからの移動は，上下左右の4方向のマスへのみが可能であり，壁の上へ移動することはできないものとする．\n\nOutput\n\n左上(0, 0) から t の座標へ辿りつけるようになる時間 s (-1 <= s <= N)を1行で出力せよ．\n\n壁を開放せずに辿りつける場合，0 を出力せよ．\n\n営業時間が終了しても到達できなければ -1 を出力すること．\n\nSample Input 1\n\n10 10\n.....#....\n.....#....\n.....#....\n######....\n..........\n####......\n....###...\nt..#..####\n...##.....\n....#...##\n3\n0 3\n0 5\n4 6\n\nSample Output 1\n\n2\n\nSample Input 2\n\n10 10\n.....#....\n.....#....\n.....#....\n##########\n##########\n##########\n##########\nt..#..####\n...##.....\n....#...##\n3\n0 3\n0 5\n4 6\n\nSample Output 2\n\n-1", "sample_input": "10 10\n.....#....\n.....#....\n.....#....\n######....\n..........\n####......\n....###...\nt..#..####\n...##.....\n....#...##\n3\n0 3\n0 5\n4 6\n"}, "reference_outputs": ["2\n"], "source_document_id": "p01481", "source_text": "Lucky Dip\n\nTime Limit: 8 sec / Memory Limit: 64 MB\n\nC: 福袋\n\n福袋，それは年始を祝う商習慣の一つである．\n人気の福袋には多くの人が開店前から行列を作り，ターゲットの福袋へダッシュする．\nこの風物詩に魅了されたあなたは，今年もお目当ての福袋を狙い，計画を立てていた．\n\nしかし，お客を呼び寄せる側の某百貨店の店長は頭を悩ませていた．\nどうやらフロアの準備が開店に間に合いそうにない．\n\nそこで店長はある一つのアイディアを思いついた．\nそれは開店後，店内を徐々に開放すればなんとか営業できるのではないかというものである．\n\nあなたは刻一刻と変化する店内の情報を元に，お目当ての福袋がどの時間帯から入手できるのかを調べたい．\n\nInput\n\n入力は単一のデータセットで与えられ，EOFで終了する．\n\n店内の様子は各行が W 文字からなる H 行の文字列で表される．\n\n1 行目\n\nW H\n2 < W, H <= 1000\n\n続く H 行\n\n店内の様子\n\n.: 床\n\n#: 壁\n\nt: 目的の福袋\n\n目的の福袋は店内に必ず1つだけ存在する．\n\nH + 2 行目\n\n営業時間 N (0 <= N <= 1000)\n\n続く N 行\n\nx1 y1\nx2 x2\n...\nxi yi\n...\nxn yn\n\n(xi, yi)は，i 時間目に開放される壁の座標を表す．(0 <= xi < W, 0 <= yi < H)\n\nxi が列，yi が行である．\n\n開放される壁の座標の位置が \"#\" なら \".\" に置き換え，\".\" なら何もしない．\n\n目的の福袋が開放されることはない．\n\n(0, 0) が壁になることはない．\n\nまたあるマスからの移動は，上下左右の4方向のマスへのみが可能であり，壁の上へ移動することはできないものとする．\n\nOutput\n\n左上(0, 0) から t の座標へ辿りつけるようになる時間 s (-1 <= s <= N)を1行で出力せよ．\n\n壁を開放せずに辿りつける場合，0 を出力せよ．\n\n営業時間が終了しても到達できなければ -1 を出力すること．\n\nSample Input 1\n\n10 10\n.....#....\n.....#....\n.....#....\n######....\n..........\n####......\n....###...\nt..#..####\n...##.....\n....#...##\n3\n0 3\n0 5\n4 6\n\nSample Output 1\n\n2\n\nSample Input 2\n\n10 10\n.....#....\n.....#....\n.....#....\n##########\n##########\n##########\n##########\nt..#..####\n...##.....\n....#...##\n3\n0 3\n0 5\n4 6\n\nSample Output 2\n\n-1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1517, "cpu_time_ms": 60, "memory_kb": 8036}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s193785416", "group_id": "codeNet:p01564", "input_text": "#define NDEBUG\n \n#include <iostream>\n#include <cstring>\n#include <algorithm>\n#include <vector>\n#include <map>\n#include <queue>\n#include <set>\n#include <tuple>\n#include <cassert>\n#include <unistd.h>\n#include <cstdio>\n#include <cstdlib>\n#include <stack>\n#include <random>\nusing namespace std;\n\ninline int fastmax(int a, int b) {\n    assert(sizeof(int) == 4);\n    return a - ((a-b) & (a-b)>>31);\n}\ninline void fastswap(int &a, int &b) {\n    assert(&a == &b);\n    a ^= b;\n    b ^= a;\n    a ^= b;\n}\ntypedef long long ll;\nstruct LCNode {\n    typedef LCNode* NP;\n    typedef int D;\n    static const int INF = 1LL<<25;\n    static LCNode last_d;\n    static NP last;\n    NP p, l, r;\n    int sz;\n    int v, sm, lz;\n    int lsm, rsm, ma, mv;\n    bool rev, lzf;\n    LCNode(D v) :p(NULL), l(last), r(last), sz(1),\n        v(v), sm(v), rev(false),\n        lsm(max(v, 0)), rsm(max(v, 0)), ma(max(v, 0)), mv(v) {}\n    LCNode() : l(NULL), r(NULL), sz(0), v(-INF), mv(-INF) {}\n    inline int pos() {\n        if (p) {\n            if (p->l == this) return -1;\n            if (p->r == this) return 1;\n        }\n        return 0;\n    }\n    inline void rot() {\n        NP qq = p->p;\n        int pps = p->pos();\n        if (p->l == this) {\n            p->l = r; r->p = p;\n            r = p; p->p = this;\n        } else {\n            p->r = l; l->p = p;\n            l = p; p->p = this;\n        }\n        p->update(); update();\n        p = qq;\n        if (!pps) return;\n        if (pps == -1) {\n            qq->l = this;\n        } else {\n            qq->r = this;\n        }\n        qq->update();\n    }\n    void splay() {\n        assert(this != last);\n        int ps;\n        while ((ps = pos())) {\n            int pps = p->pos();\n            if (!pps) {\n                rot();\n            } else if (ps == pps) {\n                p->rot(); rot();\n            } else {\n                rot(); rot();\n            }\n        }\n    }\n    void expose() {\n        assert(this != last);\n        supush();\n        NP u = this;\n        do {\n            u->splay();\n        } while ((u = u->p));\n        u = last;\n        u->p = this;\n        do {\n            u->p->r = u;\n            u->p->update();\n            u = u->p;\n        } while (u->p);\n        splay();\n    }\n    void push() {\n        int lsz = l->sz, rsz = r->sz;\n        if (rev) {\n            if (lsz) {\n                l->revdata();\n            }\n            if (rsz) {\n                r->revdata();\n            }\n            rev = false;\n        }\n        if (lzf) {\n            if (lsz) {\n                l->lzdata(lz);\n            }\n            if (rsz) {\n                r->lzdata(lz);\n            }\n            lzf = false;\n        }\n    }\n    const static int SS = 200001;\n    static NP st[SS];\n    static int stc;\n    void supush() {\n        NP u = this;\n        while (u) {\n            st[stc++] = u;\n            u = u->p;\n        }\n        while (stc) {\n            st[--stc]->push();\n        }\n    }\n    inline void revdata() {\n        swap(l, r);\n        fastswap(lsm, rsm);\n        rev ^= true;\n    }\n    inline void lzdata(D d) {\n        v = mv = d;\n        sm = sz*d;\n        lsm = rsm = ma = fastmax(0, sm);\n        lz = d;\n        lzf = true;\n    }\n    NP update() {\n        assert(this != last);\n        sz = 1+l->sz+r->sz;\n        sm = v+l->sm+r->sm;\n        lsm = fastmax(l->lsm, l->sm+v+r->lsm);\n        rsm = fastmax(r->rsm, r->sm+v+l->rsm);\n        ma = l->rsm+v+r->lsm;\n        ma = fastmax(ma, l->ma);\n        ma = fastmax(ma, r->ma);\n        mv = v;\n        mv = fastmax(mv, l->mv);\n        mv = fastmax(mv, r->mv);\n        return this;\n    }\n \n    void evert() {\n        expose();\n        revdata();\n    }\n};\nLCNode LCNode::last_d = LCNode();\nLCNode::NP LCNode::last = &last_d;\nLCNode::NP LCNode::st[LCNode::SS];\nint LCNode::stc = 0;\n \ninline int getint() {\n    char c;\n    int res = 0;\n    bool neg = false;\n    while (true) {\n        c = getchar_unlocked();\n        if (c == '-') {\n            neg = true;\n            break;\n        }\n        if ('0' <= c && c <= '9') {\n            res = c-'0';\n            break;\n        }\n    }\n    while (c = getchar_unlocked(), '0' <= c && c <= '9') {\n        res *= 10;\n        res += c-'0';\n    }\n    if (neg) res *= -1;\n    return res;\n}\n \ninline void putint(int d) {\n    static char buf[10];\n    int c = 0;\n    bool neg = false;\n    if (d < 0) {\n        putchar_unlocked('-');\n        d *= -1;\n    }\n    if (!d) {\n        putchar_unlocked('0');\n        return;\n    }\n    while (d) {\n        buf[c++] = d%10;\n        d = d/10;\n    }\n    while (c--) {\n        putchar_unlocked(buf[c]+'0');\n    }\n}\n \nconst int MN = 200001;\nLCNode tr[MN];\nint main() {\n    int n = getint(), q = getint();\n    for (int i = 0; i < n; i++) {\n        int w = getint();\n        tr[i] = LCNode(w);\n    }\n    for (int i = 0; i < n-1; i++) {\n        int s = getint(), e = getint(); s--; e--;\n        tr[s].evert();\n        tr[e].expose();\n        tr[s].p = tr+e;\n    }\n    for (int i = 0; i < q; i++) {\n        int t = getint(), a = getint(), b = getint(), c = getint();\n        a--; b--;\n        if (t <= 1) {\n            tr[a].evert();\n            tr[b].expose();\n            tr[b].lzdata(c);\n        } else {\n            tr[a].evert();\n            tr[b].expose();\n            int d;\n            if (tr[b].mv < 0) d = tr[b].mv;\n            else d = tr[b].ma;\n            putint(d);\n            putchar_unlocked('\\n');\n        }\n    }\n}", "language": "C++", "metadata": {"date": 1419697006, "filename_ext": "cpp", "original_language": "C++11", "problem_description_relpath": "problem_descriptions/p01564.html", "problem_id": "p01564", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p01564/input.txt", "sample_output_relpath": "derived/input_output/data/p01564/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p01564/C++/s193785416.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s193785416", "user_id": "u849555829"}, "prompt_components": {"gold_output": "6\n3\n-4\n", "input_to_evaluate": "#define NDEBUG\n \n#include <iostream>\n#include <cstring>\n#include <algorithm>\n#include <vector>\n#include <map>\n#include <queue>\n#include <set>\n#include <tuple>\n#include <cassert>\n#include <unistd.h>\n#include <cstdio>\n#include <cstdlib>\n#include <stack>\n#include <random>\nusing namespace std;\n\ninline int fastmax(int a, int b) {\n    assert(sizeof(int) == 4);\n    return a - ((a-b) & (a-b)>>31);\n}\ninline void fastswap(int &a, int &b) {\n    assert(&a == &b);\n    a ^= b;\n    b ^= a;\n    a ^= b;\n}\ntypedef long long ll;\nstruct LCNode {\n    typedef LCNode* NP;\n    typedef int D;\n    static const int INF = 1LL<<25;\n    static LCNode last_d;\n    static NP last;\n    NP p, l, r;\n    int sz;\n    int v, sm, lz;\n    int lsm, rsm, ma, mv;\n    bool rev, lzf;\n    LCNode(D v) :p(NULL), l(last), r(last), sz(1),\n        v(v), sm(v), rev(false),\n        lsm(max(v, 0)), rsm(max(v, 0)), ma(max(v, 0)), mv(v) {}\n    LCNode() : l(NULL), r(NULL), sz(0), v(-INF), mv(-INF) {}\n    inline int pos() {\n        if (p) {\n            if (p->l == this) return -1;\n            if (p->r == this) return 1;\n        }\n        return 0;\n    }\n    inline void rot() {\n        NP qq = p->p;\n        int pps = p->pos();\n        if (p->l == this) {\n            p->l = r; r->p = p;\n            r = p; p->p = this;\n        } else {\n            p->r = l; l->p = p;\n            l = p; p->p = this;\n        }\n        p->update(); update();\n        p = qq;\n        if (!pps) return;\n        if (pps == -1) {\n            qq->l = this;\n        } else {\n            qq->r = this;\n        }\n        qq->update();\n    }\n    void splay() {\n        assert(this != last);\n        int ps;\n        while ((ps = pos())) {\n            int pps = p->pos();\n            if (!pps) {\n                rot();\n            } else if (ps == pps) {\n                p->rot(); rot();\n            } else {\n                rot(); rot();\n            }\n        }\n    }\n    void expose() {\n        assert(this != last);\n        supush();\n        NP u = this;\n        do {\n            u->splay();\n        } while ((u = u->p));\n        u = last;\n        u->p = this;\n        do {\n            u->p->r = u;\n            u->p->update();\n            u = u->p;\n        } while (u->p);\n        splay();\n    }\n    void push() {\n        int lsz = l->sz, rsz = r->sz;\n        if (rev) {\n            if (lsz) {\n                l->revdata();\n            }\n            if (rsz) {\n                r->revdata();\n            }\n            rev = false;\n        }\n        if (lzf) {\n            if (lsz) {\n                l->lzdata(lz);\n            }\n            if (rsz) {\n                r->lzdata(lz);\n            }\n            lzf = false;\n        }\n    }\n    const static int SS = 200001;\n    static NP st[SS];\n    static int stc;\n    void supush() {\n        NP u = this;\n        while (u) {\n            st[stc++] = u;\n            u = u->p;\n        }\n        while (stc) {\n            st[--stc]->push();\n        }\n    }\n    inline void revdata() {\n        swap(l, r);\n        fastswap(lsm, rsm);\n        rev ^= true;\n    }\n    inline void lzdata(D d) {\n        v = mv = d;\n        sm = sz*d;\n        lsm = rsm = ma = fastmax(0, sm);\n        lz = d;\n        lzf = true;\n    }\n    NP update() {\n        assert(this != last);\n        sz = 1+l->sz+r->sz;\n        sm = v+l->sm+r->sm;\n        lsm = fastmax(l->lsm, l->sm+v+r->lsm);\n        rsm = fastmax(r->rsm, r->sm+v+l->rsm);\n        ma = l->rsm+v+r->lsm;\n        ma = fastmax(ma, l->ma);\n        ma = fastmax(ma, r->ma);\n        mv = v;\n        mv = fastmax(mv, l->mv);\n        mv = fastmax(mv, r->mv);\n        return this;\n    }\n \n    void evert() {\n        expose();\n        revdata();\n    }\n};\nLCNode LCNode::last_d = LCNode();\nLCNode::NP LCNode::last = &last_d;\nLCNode::NP LCNode::st[LCNode::SS];\nint LCNode::stc = 0;\n \ninline int getint() {\n    char c;\n    int res = 0;\n    bool neg = false;\n    while (true) {\n        c = getchar_unlocked();\n        if (c == '-') {\n            neg = true;\n            break;\n        }\n        if ('0' <= c && c <= '9') {\n            res = c-'0';\n            break;\n        }\n    }\n    while (c = getchar_unlocked(), '0' <= c && c <= '9') {\n        res *= 10;\n        res += c-'0';\n    }\n    if (neg) res *= -1;\n    return res;\n}\n \ninline void putint(int d) {\n    static char buf[10];\n    int c = 0;\n    bool neg = false;\n    if (d < 0) {\n        putchar_unlocked('-');\n        d *= -1;\n    }\n    if (!d) {\n        putchar_unlocked('0');\n        return;\n    }\n    while (d) {\n        buf[c++] = d%10;\n        d = d/10;\n    }\n    while (c--) {\n        putchar_unlocked(buf[c]+'0');\n    }\n}\n \nconst int MN = 200001;\nLCNode tr[MN];\nint main() {\n    int n = getint(), q = getint();\n    for (int i = 0; i < n; i++) {\n        int w = getint();\n        tr[i] = LCNode(w);\n    }\n    for (int i = 0; i < n-1; i++) {\n        int s = getint(), e = getint(); s--; e--;\n        tr[s].evert();\n        tr[e].expose();\n        tr[s].p = tr+e;\n    }\n    for (int i = 0; i < q; i++) {\n        int t = getint(), a = getint(), b = getint(), c = getint();\n        a--; b--;\n        if (t <= 1) {\n            tr[a].evert();\n            tr[b].expose();\n            tr[b].lzdata(c);\n        } else {\n            tr[a].evert();\n            tr[b].expose();\n            int d;\n            if (tr[b].mv < 0) d = tr[b].mv;\n            else d = tr[b].ma;\n            putint(d);\n            putchar_unlocked('\\n');\n        }\n    }\n}", "problem_context": "Do use segment tree\n\nGiven a tree with n (1 ≤ n ≤ 200,000) nodes and a list of q (1 ≤ q ≤ 100,000) queries,\nprocess the queries in order and output a value for each output query.\nThe given tree is connected and each node on the tree has a weight wi (-10,000 ≤ wi ≤ 10,000).\n\nEach query consists of a number ti (ti = 1, 2), which indicates the type of the query , and three numbers ai, bi and ci (1 ≤ ai, bi ≤ n, -10,000 ≤ ci ≤ 10,000).\nDepending on the query type, process one of the followings:\n\n(ti = 1: modification query)\nChange the weights of all nodes on the shortest path between ai and bi (both inclusive) to ci.\n\n(ti = 2: output query)\nFirst, create a list of weights on the shortest path between ai and bi (both inclusive) in order. After that, output the maximum sum of a non-empty continuous subsequence of the weights on the list. ci is ignored for output queries.\n\nInput\n\nThe first line contains two integers n and q.\nOn the second line, there are n integers which indicate w1, w2, ... , wn.\n\nEach of the following n - 1 lines consists of two integers si and ei (1 ≤ si, ei ≤ n),\nwhich means that there is an edge between si and ei.\n\nFinally the following q lines give the list of queries, each of which contains four integers in the format described above.\nQueries must be processed one by one from top to bottom.\n\nOutput\n\nFor each output query, output the maximum sum in one line.\n\nSample Input 1\n\n3 4\n1 2 3\n1 2\n2 3\n2 1 3 0\n1 2 2 -4\n2 1 3 0\n2 2 2 0\n\nOutput for the Sample Input 1\n\n6\n3\n-4\n\nSample Input 2\n\n7 5\n-8 5 5 5 5 5 5\n1 2\n2 3\n1 4\n4 5\n1 6\n6 7\n2 3 7 0\n2 5 2 0\n2 4 3 0\n1 1 1 -1\n2 3 7 0\n\nOutput for the Sample Input 2\n\n12\n10\n10\n19\n\nSample Input 3\n\n21 30\n10 0 -10 -8 5 -5 -4 -3 1 -2 8 -1 -7 2 7 6 -9 -6 3 4 9\n10 3\n3 2\n3 12\n12 4\n4 13\n4 9\n10 21\n21 1\n1 11\n11 14\n1 15\n10 6\n6 17\n6 16\n6 5\n5 18\n5 19\n10 7\n10 8\n8 20\n1 1 21 -10\n1 3 19 10\n2 1 13 0\n1 4 18 8\n1 5 17 -5\n2 16 7 0\n1 6 16 5\n1 7 15 4\n2 4 20 0\n1 8 14 3\n1 9 13 -1\n2 9 18 0\n1 10 12 2\n1 11 11 -8\n2 21 15 0\n1 12 10 1\n1 13 9 7\n2 6 14 0\n1 14 8 -2\n1 15 7 -7\n2 10 2 0\n1 16 6 -6\n1 17 5 9\n2 12 17 0\n1 18 4 6\n1 19 3 -3\n2 11 8 0\n1 20 2 -4\n1 21 1 -9\n2 5 19 0\n\nOutput for the Sample Input 3\n\n20\n9\n29\n27\n10\n12\n1\n18\n-2\n-3", "sample_input": "3 4\n1 2 3\n1 2\n2 3\n2 1 3 0\n1 2 2 -4\n2 1 3 0\n2 2 2 0\n"}, "reference_outputs": ["6\n3\n-4\n"], "source_document_id": "p01564", "source_text": "Do use segment tree\n\nGiven a tree with n (1 ≤ n ≤ 200,000) nodes and a list of q (1 ≤ q ≤ 100,000) queries,\nprocess the queries in order and output a value for each output query.\nThe given tree is connected and each node on the tree has a weight wi (-10,000 ≤ wi ≤ 10,000).\n\nEach query consists of a number ti (ti = 1, 2), which indicates the type of the query , and three numbers ai, bi and ci (1 ≤ ai, bi ≤ n, -10,000 ≤ ci ≤ 10,000).\nDepending on the query type, process one of the followings:\n\n(ti = 1: modification query)\nChange the weights of all nodes on the shortest path between ai and bi (both inclusive) to ci.\n\n(ti = 2: output query)\nFirst, create a list of weights on the shortest path between ai and bi (both inclusive) in order. After that, output the maximum sum of a non-empty continuous subsequence of the weights on the list. ci is ignored for output queries.\n\nInput\n\nThe first line contains two integers n and q.\nOn the second line, there are n integers which indicate w1, w2, ... , wn.\n\nEach of the following n - 1 lines consists of two integers si and ei (1 ≤ si, ei ≤ n),\nwhich means that there is an edge between si and ei.\n\nFinally the following q lines give the list of queries, each of which contains four integers in the format described above.\nQueries must be processed one by one from top to bottom.\n\nOutput\n\nFor each output query, output the maximum sum in one line.\n\nSample Input 1\n\n3 4\n1 2 3\n1 2\n2 3\n2 1 3 0\n1 2 2 -4\n2 1 3 0\n2 2 2 0\n\nOutput for the Sample Input 1\n\n6\n3\n-4\n\nSample Input 2\n\n7 5\n-8 5 5 5 5 5 5\n1 2\n2 3\n1 4\n4 5\n1 6\n6 7\n2 3 7 0\n2 5 2 0\n2 4 3 0\n1 1 1 -1\n2 3 7 0\n\nOutput for the Sample Input 2\n\n12\n10\n10\n19\n\nSample Input 3\n\n21 30\n10 0 -10 -8 5 -5 -4 -3 1 -2 8 -1 -7 2 7 6 -9 -6 3 4 9\n10 3\n3 2\n3 12\n12 4\n4 13\n4 9\n10 21\n21 1\n1 11\n11 14\n1 15\n10 6\n6 17\n6 16\n6 5\n5 18\n5 19\n10 7\n10 8\n8 20\n1 1 21 -10\n1 3 19 10\n2 1 13 0\n1 4 18 8\n1 5 17 -5\n2 16 7 0\n1 6 16 5\n1 7 15 4\n2 4 20 0\n1 8 14 3\n1 9 13 -1\n2 9 18 0\n1 10 12 2\n1 11 11 -8\n2 21 15 0\n1 12 10 1\n1 13 9 7\n2 6 14 0\n1 14 8 -2\n1 15 7 -7\n2 10 2 0\n1 16 6 -6\n1 17 5 9\n2 12 17 0\n1 18 4 6\n1 19 3 -3\n2 11 8 0\n1 20 2 -4\n1 21 1 -9\n2 5 19 0\n\nOutput for the Sample Input 3\n\n20\n9\n29\n27\n10\n12\n1\n18\n-2\n-3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 5404, "cpu_time_ms": 250, "memory_kb": 13576}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s624499239", "group_id": "codeNet:p01577", "input_text": "#include<bits/stdc++.h>\n\n#define REP(i,s,n) for(int i=s;i<n;i++)\n#define rep(i,n) REP(i,0,n)\n#define EPS (1e-6)\n#define equals(a,b) (fabs((a)-(b)) < EPS)\n#define COUNTER_CLOCKWISE 1\n#define CLOCKWISE -1 \n#define ONLINE_BACK 2\n#define ONLINE_FRONT -2\n#define ON_SEGMENT 0\n\nusing namespace std;\n\nclass Point{\npublic:\n  double x,y;\n\n  Point(double x = 0,double y = 0): x(x),y(y){}\n\n  Point operator + (Point p){return Point(x+p.x,y+p.y);}\n  Point operator - (Point p){return Point(x-p.x,y-p.y);}\n  Point operator * (double a){return Point(a*x,a*y);}\n  Point operator / (double a){return Point(x/a,y/a);}\n  Point operator * (Point a){ return Point(x * a.x - y * a.y, x * a.y + y * a.x); }\n\n  bool operator < (const Point& p) const{ return !equals(x,p.x)?x<p.x:(!equals(y,p.y)&&y<p.y); }\n\n  bool operator == (const Point& p)const{ return fabs(x-p.x) < EPS && fabs(y-p.y) < EPS; }\n\n};\n\nstruct Segment{\n  Point p1,p2;\n  Segment(Point p1 = Point(),Point p2 = Point()):p1(p1),p2(p2){}\n  bool operator <  (const Segment& s) const { return ( p2 == s.p2 ) ? p1 < s.p1 : p2 < s.p2; }\n  bool operator == (const Segment& s) const { return ( s.p1 == p1 && s.p2 == p2 ) || ( s.p1 == p2 && s.p2 == p1 ); }\n\n};\n\ntypedef Point Vector;\ntypedef Segment Line;\ntypedef vector<Point> Polygon;\n\nostream& operator << (ostream& os,const Point& a){ os << \"(\" << a.x << \",\" << a.y << \")\"; }\n\nostream& operator << (ostream& os,const Segment& a){ os << \"( \" << a.p1 << \" , \" << a.p2 << \" )\"; }\n\ndouble dot(Point a,Point b){ return a.x*b.x + a.y*b.y; }\n\ndouble cross(Point a,Point b){ return a.x*b.y - a.y*b.x; }\n\ndouble norm(Point a){ return a.x*a.x+a.y*a.y; }\n\ndouble abs(Point a){ return sqrt(norm(a)); }\n\n//rad ????§???????????????¢?????§?????????????????¨\nPoint rotate(Point a,double rad){ return Point(cos(rad)*a.x - sin(rad)*a.y,sin(rad)*a.x + cos(rad)*a.y); }\n\n// ??????????????¢????????????\ndouble toRad(double agl){ return agl*M_PI/180.0; }\n\n// a => prev, b => cur, c=> next\n// prev ?????? cur ????????£??? next ????????????????§????????±???????\ndouble getArg(Point a,Point b,Point c){\n  double arg1 = atan2(b.y-a.y,b.x-a.x);\n  double arg2 = atan2(c.y-b.y,c.x-b.x);\n  double arg = fabs( arg1 - arg2 );\n  while( arg > M_PI ) arg -= 2.0 * M_PI;\n  return fabs(arg);\n}\n\nint ccw(Point p0,Point p1,Point p2){\n  Point a = p1-p0;\n  Point b = p2-p0;\n  if(cross(a,b) > EPS)return COUNTER_CLOCKWISE;\n  if(cross(a,b) < -EPS)return CLOCKWISE;\n  if(dot(a,b) < -EPS)return ONLINE_BACK;\n  if(norm(a) < norm(b))return ONLINE_FRONT;\n  return ON_SEGMENT;\n}\n\nPolygon andrewScan(Polygon s) {\n  Polygon u,l;\n  if(s.size() < 3)return s;\n\n  sort(s.begin(),s.end());\n\n  u.push_back(s[0]);\n  u.push_back(s[1]);\n  l.push_back(s[s.size()-1]);\n  l.push_back(s[s.size()-2]);\n\n  for(int i=2;i<s.size();i++) {\n      for(int n=u.size();n >= 2 && ccw(u[n-2],u[n-1],s[i]) != CLOCKWISE; n--)\n        u.pop_back();\n      u.push_back(s[i]);\n    }\n\n  for(int i=s.size()-3; i>=0 ; i--) {\n      for(int n=l.size(); n >= 2 && ccw(l[n-2],l[n-1],s[i]) != CLOCKWISE; n--)\n        l.pop_back();\n      l.push_back(s[i]);\n    }\n\n  reverse(l.begin(),l.end());\n\n  for(int i = u.size()-2; i >= 1; i--) l.push_back(u[i]);\n\n  return l;\n}\n\ninline double heron(Point A,Point B,Point C){\n  double a = abs(B-C);\n  double b = abs(A-C);\n  double c = abs(A-B);\n  double s = ( a + b + c ) / 2;\n  return sqrt( s * ( s - a ) * ( s - b ) * ( s - c ) );\n}\n\n// -----------------------------------------------------------\n\nconst int MAX_V = 1510;\nint V,nV;\nvector<Point> ps,nps;\n\nbool LT(double a,double b) { return !equals(a,b) && a < b; }\nbool LTE(double a,double b) { return equals(a,b) || a < b; }\n\ndouble ternarySearch(int a,int b){\n  int L = 1, R = ( a < b ) ? ( ( b - a - 1 + nV ) % nV ) : ( ( a - 1 - b + nV) % nV );\n  int sp = a;\n  int prev = -1;\n  rep(_,120){\n    if( LT(heron(nps[((L+R*2)/3+sp)%nV],nps[a],nps[b]),heron(nps[((L*2+R)/3+sp)%nV],nps[a],nps[b])) ) {\n      R = ( L + R * 2 ) / 3;\n    } else {\n      L = ( L * 2 + R ) / 3;\n    }\n    if( prev == ((int)((L+R)*0.5+sp))%nV ) break;\n    prev = (int)((L+R)*0.5+sp)%nV;\n  }\n  return heron(nps[(int)(((L+R)*0.5)+sp)%nV],nps[a],nps[b]);\n}\n\nvoid compute(){\n  nps = andrewScan(ps);\n  nV = nps.size();  \n  double maxi = 0;\n  if( nV == 3 ) {\n    rep(i,V) {\n      if( nps[0] == ps[i] || nps[1] == ps[i] || nps[2] == ps[i] ) continue;\n      double area1 = heron(nps[0],nps[1],ps[i]);\n      double area2 = heron(nps[1],nps[2],ps[i]);\n      double area3 = heron(nps[2],nps[0],ps[i]);\n      double area4 = heron(nps[0],nps[1],nps[2]);\n      maxi = max(maxi,area4-min(area1,min(area2,area3)));\n    }\n  } else {\n    rep(i,nV) REP(j,i+1,nV) maxi = max(maxi,ternarySearch(i,j)+ternarySearch(j,i));\n  }\n  printf(\"%.1f\\n\",maxi);\n}\n\nint main(){\n  scanf(\"%d\",&V);\n  ps.resize(V);\n  rep(i,V) scanf(\"%lf %lf\",&ps[i].x,&ps[i].y);\n  compute();\n  return 0;\n}", "language": "C++", "metadata": {"date": 1436646102, "filename_ext": "cpp", "original_language": "C++", "problem_description_relpath": "problem_descriptions/p01577.html", "problem_id": "p01577", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p01577/input.txt", "sample_output_relpath": "derived/input_output/data/p01577/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p01577/C++/s624499239.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s624499239", "user_id": "u116766943"}, "prompt_components": {"gold_output": "7.5\n", "input_to_evaluate": "#include<bits/stdc++.h>\n\n#define REP(i,s,n) for(int i=s;i<n;i++)\n#define rep(i,n) REP(i,0,n)\n#define EPS (1e-6)\n#define equals(a,b) (fabs((a)-(b)) < EPS)\n#define COUNTER_CLOCKWISE 1\n#define CLOCKWISE -1 \n#define ONLINE_BACK 2\n#define ONLINE_FRONT -2\n#define ON_SEGMENT 0\n\nusing namespace std;\n\nclass Point{\npublic:\n  double x,y;\n\n  Point(double x = 0,double y = 0): x(x),y(y){}\n\n  Point operator + (Point p){return Point(x+p.x,y+p.y);}\n  Point operator - (Point p){return Point(x-p.x,y-p.y);}\n  Point operator * (double a){return Point(a*x,a*y);}\n  Point operator / (double a){return Point(x/a,y/a);}\n  Point operator * (Point a){ return Point(x * a.x - y * a.y, x * a.y + y * a.x); }\n\n  bool operator < (const Point& p) const{ return !equals(x,p.x)?x<p.x:(!equals(y,p.y)&&y<p.y); }\n\n  bool operator == (const Point& p)const{ return fabs(x-p.x) < EPS && fabs(y-p.y) < EPS; }\n\n};\n\nstruct Segment{\n  Point p1,p2;\n  Segment(Point p1 = Point(),Point p2 = Point()):p1(p1),p2(p2){}\n  bool operator <  (const Segment& s) const { return ( p2 == s.p2 ) ? p1 < s.p1 : p2 < s.p2; }\n  bool operator == (const Segment& s) const { return ( s.p1 == p1 && s.p2 == p2 ) || ( s.p1 == p2 && s.p2 == p1 ); }\n\n};\n\ntypedef Point Vector;\ntypedef Segment Line;\ntypedef vector<Point> Polygon;\n\nostream& operator << (ostream& os,const Point& a){ os << \"(\" << a.x << \",\" << a.y << \")\"; }\n\nostream& operator << (ostream& os,const Segment& a){ os << \"( \" << a.p1 << \" , \" << a.p2 << \" )\"; }\n\ndouble dot(Point a,Point b){ return a.x*b.x + a.y*b.y; }\n\ndouble cross(Point a,Point b){ return a.x*b.y - a.y*b.x; }\n\ndouble norm(Point a){ return a.x*a.x+a.y*a.y; }\n\ndouble abs(Point a){ return sqrt(norm(a)); }\n\n//rad ????§???????????????¢?????§?????????????????¨\nPoint rotate(Point a,double rad){ return Point(cos(rad)*a.x - sin(rad)*a.y,sin(rad)*a.x + cos(rad)*a.y); }\n\n// ??????????????¢????????????\ndouble toRad(double agl){ return agl*M_PI/180.0; }\n\n// a => prev, b => cur, c=> next\n// prev ?????? cur ????????£??? next ????????????????§????????±???????\ndouble getArg(Point a,Point b,Point c){\n  double arg1 = atan2(b.y-a.y,b.x-a.x);\n  double arg2 = atan2(c.y-b.y,c.x-b.x);\n  double arg = fabs( arg1 - arg2 );\n  while( arg > M_PI ) arg -= 2.0 * M_PI;\n  return fabs(arg);\n}\n\nint ccw(Point p0,Point p1,Point p2){\n  Point a = p1-p0;\n  Point b = p2-p0;\n  if(cross(a,b) > EPS)return COUNTER_CLOCKWISE;\n  if(cross(a,b) < -EPS)return CLOCKWISE;\n  if(dot(a,b) < -EPS)return ONLINE_BACK;\n  if(norm(a) < norm(b))return ONLINE_FRONT;\n  return ON_SEGMENT;\n}\n\nPolygon andrewScan(Polygon s) {\n  Polygon u,l;\n  if(s.size() < 3)return s;\n\n  sort(s.begin(),s.end());\n\n  u.push_back(s[0]);\n  u.push_back(s[1]);\n  l.push_back(s[s.size()-1]);\n  l.push_back(s[s.size()-2]);\n\n  for(int i=2;i<s.size();i++) {\n      for(int n=u.size();n >= 2 && ccw(u[n-2],u[n-1],s[i]) != CLOCKWISE; n--)\n        u.pop_back();\n      u.push_back(s[i]);\n    }\n\n  for(int i=s.size()-3; i>=0 ; i--) {\n      for(int n=l.size(); n >= 2 && ccw(l[n-2],l[n-1],s[i]) != CLOCKWISE; n--)\n        l.pop_back();\n      l.push_back(s[i]);\n    }\n\n  reverse(l.begin(),l.end());\n\n  for(int i = u.size()-2; i >= 1; i--) l.push_back(u[i]);\n\n  return l;\n}\n\ninline double heron(Point A,Point B,Point C){\n  double a = abs(B-C);\n  double b = abs(A-C);\n  double c = abs(A-B);\n  double s = ( a + b + c ) / 2;\n  return sqrt( s * ( s - a ) * ( s - b ) * ( s - c ) );\n}\n\n// -----------------------------------------------------------\n\nconst int MAX_V = 1510;\nint V,nV;\nvector<Point> ps,nps;\n\nbool LT(double a,double b) { return !equals(a,b) && a < b; }\nbool LTE(double a,double b) { return equals(a,b) || a < b; }\n\ndouble ternarySearch(int a,int b){\n  int L = 1, R = ( a < b ) ? ( ( b - a - 1 + nV ) % nV ) : ( ( a - 1 - b + nV) % nV );\n  int sp = a;\n  int prev = -1;\n  rep(_,120){\n    if( LT(heron(nps[((L+R*2)/3+sp)%nV],nps[a],nps[b]),heron(nps[((L*2+R)/3+sp)%nV],nps[a],nps[b])) ) {\n      R = ( L + R * 2 ) / 3;\n    } else {\n      L = ( L * 2 + R ) / 3;\n    }\n    if( prev == ((int)((L+R)*0.5+sp))%nV ) break;\n    prev = (int)((L+R)*0.5+sp)%nV;\n  }\n  return heron(nps[(int)(((L+R)*0.5)+sp)%nV],nps[a],nps[b]);\n}\n\nvoid compute(){\n  nps = andrewScan(ps);\n  nV = nps.size();  \n  double maxi = 0;\n  if( nV == 3 ) {\n    rep(i,V) {\n      if( nps[0] == ps[i] || nps[1] == ps[i] || nps[2] == ps[i] ) continue;\n      double area1 = heron(nps[0],nps[1],ps[i]);\n      double area2 = heron(nps[1],nps[2],ps[i]);\n      double area3 = heron(nps[2],nps[0],ps[i]);\n      double area4 = heron(nps[0],nps[1],nps[2]);\n      maxi = max(maxi,area4-min(area1,min(area2,area3)));\n    }\n  } else {\n    rep(i,nV) REP(j,i+1,nV) maxi = max(maxi,ternarySearch(i,j)+ternarySearch(j,i));\n  }\n  printf(\"%.1f\\n\",maxi);\n}\n\nint main(){\n  scanf(\"%d\",&V);\n  ps.resize(V);\n  rep(i,V) scanf(\"%lf %lf\",&ps[i].x,&ps[i].y);\n  compute();\n  return 0;\n}", "problem_context": "Problem H: Magic Walls\n\nYou are a magician and have a large farm to grow magical fruits.\n\nOne day, you saw a horde of monsters, approaching your farm. They would ruin your magical farm once they reached your farm. Unfortunately, you are not strong enough to fight against those monsters. To protect your farm against them, you decided to build magic walls around your land.\n\nYou have four magic orbs to build the walls, namely, the orbs of Aquamarine (A), Bloodstone (B), Citrine (C) and Diamond (D). When you place them correctly and then cast a spell, there will be magic walls between the orbs A and B, between B and C, between C and D, and between D and A. The walls are built on the line segments connecting two orbs, and form a quadrangle as a whole. As the monsters cannot cross the magic walls, the inside of the magic walls is protected.\n\nNonetheless, you can protect only a part of your land, since there are a couple of restrictions on building the magic walls. There are N hills in your farm, where the orbs can receive rich power of magic. Each orb should be set on the top of one of the hills. Also, to avoid interference between the orbs, you may not place two or more orbs at the same hill.\n\nNow, you want to maximize the area protected by the magic walls. Please figure it out.\n\nInput\n\nThe input begins with an integer N (4 ≤ N ≤ 1500), the number of the hills. Then N line follow. Each of them has two integers x (0 ≤ x ≤ 50000) and y (0 ≤ y ≤ 50000), the x- and y-coordinates of the location of a hill.\n\nIt is guaranteed that no two hills have the same location and that no three hills lie on a single line.\n\nOutput\n\nOutput the maximum area you can protect. The output value should be printed with one digit after the decimal point, and should be exact.\n\nSample Input 1\n\n5\n2 0\n0 1\n1 3\n4 2\n3 4\n\nOutput for the Sample Input 1\n\n7.5\n\nSample Input 2\n\n4\n0 0\n0 3\n1 1\n3 0\n\nOutput for the Sample Input 2\n\n3.0", "sample_input": "5\n2 0\n0 1\n1 3\n4 2\n3 4\n"}, "reference_outputs": ["7.5\n"], "source_document_id": "p01577", "source_text": "Problem H: Magic Walls\n\nYou are a magician and have a large farm to grow magical fruits.\n\nOne day, you saw a horde of monsters, approaching your farm. They would ruin your magical farm once they reached your farm. Unfortunately, you are not strong enough to fight against those monsters. To protect your farm against them, you decided to build magic walls around your land.\n\nYou have four magic orbs to build the walls, namely, the orbs of Aquamarine (A), Bloodstone (B), Citrine (C) and Diamond (D). When you place them correctly and then cast a spell, there will be magic walls between the orbs A and B, between B and C, between C and D, and between D and A. The walls are built on the line segments connecting two orbs, and form a quadrangle as a whole. As the monsters cannot cross the magic walls, the inside of the magic walls is protected.\n\nNonetheless, you can protect only a part of your land, since there are a couple of restrictions on building the magic walls. There are N hills in your farm, where the orbs can receive rich power of magic. Each orb should be set on the top of one of the hills. Also, to avoid interference between the orbs, you may not place two or more orbs at the same hill.\n\nNow, you want to maximize the area protected by the magic walls. Please figure it out.\n\nInput\n\nThe input begins with an integer N (4 ≤ N ≤ 1500), the number of the hills. Then N line follow. Each of them has two integers x (0 ≤ x ≤ 50000) and y (0 ≤ y ≤ 50000), the x- and y-coordinates of the location of a hill.\n\nIt is guaranteed that no two hills have the same location and that no three hills lie on a single line.\n\nOutput\n\nOutput the maximum area you can protect. The output value should be printed with one digit after the decimal point, and should be exact.\n\nSample Input 1\n\n5\n2 0\n0 1\n1 3\n4 2\n3 4\n\nOutput for the Sample Input 1\n\n7.5\n\nSample Input 2\n\n4\n0 0\n0 3\n1 1\n3 0\n\nOutput for the Sample Input 2\n\n3.0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 4818, "cpu_time_ms": 2030, "memory_kb": 1380}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s936803215", "group_id": "codeNet:p01659", "input_text": "#include <iostream>\n#include <sstream>\n#include <cstdio>\n#include <cstdlib>\n#include <cmath>\n#include <ctime>\n#include <cstring>\n#include <string>\n#include <vector>\n#include <stack>\n#include <queue>\n#include <deque>\n#include <map>\n#include <set>\n#include <bitset>\n#include <numeric>\n#include <utility>\n#include <iomanip>\n#include <algorithm>\n#include <functional>\nusing namespace std;\n\ntypedef long long ll;\ntypedef vector<int> vint;\ntypedef vector<ll> vll;\ntypedef pair<int,int> pint;\n\n#define DE 1\n#define FI first\n#define SE second\n#define PB push_back\n#define MP make_pair\n#define ALL(s) (s).begin(),(s).end()\n#define REP(i,n) for (int i = 0; i < (int)(n); ++i)\n#define EACH(i,s) for (typeof((s).begin()) i = (s).begin(); i != (s).end(); ++i)\n#define COUT(x) cout<<#x<<\" = \"<<(x)<<\" (L\"<<__LINE__<<\")\"<<endl\n\ntemplate<class T1, class T2> ostream& operator<<(ostream &s, pair<T1,T2> P){return s<<'<'<<P.first<<\", \"<<P.second<<'>';}\ntemplate<class T> ostream& operator<<(ostream &s, vector<T> P) {s<<\"{ \";for(int i=0;i<P.size();++i){if(i>0)s<<\", \";s<<P[i];}return s<<\" }\"<<endl;}\ntemplate<class T1, class T2> ostream& operator<<(ostream &s, map<T1,T2> P) {s<<\"{ \";for(typeof(P.begin()) it=P.begin();it!=P.end();++it){if(it!=P.begin())s<<\", \";s<<'<'<<it->first<<\"->\"<<it->second<<'>';}return s<<\" }\"<<endl;}\n\n\n\nint main() {\n    //freopen( \"/Users/macuser/Documents/Programming/Contest/input.in\", \"r\", stdin );\n    \n    int N;\n    cin >> N;\n    stack<int> st;\n    int res = 0;\n    \n    st.push(0);\n    for (int i = 0; i < N; ++i) {\n        int a; cin >> a;\n        if (a > st.top()) st.push(a);\n        else if (a == st.top()) {}\n        else {\n            while (st.top() > a) {\n                st.pop();\n                ++res;\n            }\n            if (a > st.top()) st.push(a);\n        }\n    }\n    cout << res + st.size() - 1 << endl;\n    \n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1395205798, "filename_ext": "cpp", "original_language": "C++", "problem_description_relpath": "problem_descriptions/p01659.html", "problem_id": "p01659", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p01659/input.txt", "sample_output_relpath": "derived/input_output/data/p01659/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p01659/C++/s936803215.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s936803215", "user_id": "u328393566"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <iostream>\n#include <sstream>\n#include <cstdio>\n#include <cstdlib>\n#include <cmath>\n#include <ctime>\n#include <cstring>\n#include <string>\n#include <vector>\n#include <stack>\n#include <queue>\n#include <deque>\n#include <map>\n#include <set>\n#include <bitset>\n#include <numeric>\n#include <utility>\n#include <iomanip>\n#include <algorithm>\n#include <functional>\nusing namespace std;\n\ntypedef long long ll;\ntypedef vector<int> vint;\ntypedef vector<ll> vll;\ntypedef pair<int,int> pint;\n\n#define DE 1\n#define FI first\n#define SE second\n#define PB push_back\n#define MP make_pair\n#define ALL(s) (s).begin(),(s).end()\n#define REP(i,n) for (int i = 0; i < (int)(n); ++i)\n#define EACH(i,s) for (typeof((s).begin()) i = (s).begin(); i != (s).end(); ++i)\n#define COUT(x) cout<<#x<<\" = \"<<(x)<<\" (L\"<<__LINE__<<\")\"<<endl\n\ntemplate<class T1, class T2> ostream& operator<<(ostream &s, pair<T1,T2> P){return s<<'<'<<P.first<<\", \"<<P.second<<'>';}\ntemplate<class T> ostream& operator<<(ostream &s, vector<T> P) {s<<\"{ \";for(int i=0;i<P.size();++i){if(i>0)s<<\", \";s<<P[i];}return s<<\" }\"<<endl;}\ntemplate<class T1, class T2> ostream& operator<<(ostream &s, map<T1,T2> P) {s<<\"{ \";for(typeof(P.begin()) it=P.begin();it!=P.end();++it){if(it!=P.begin())s<<\", \";s<<'<'<<it->first<<\"->\"<<it->second<<'>';}return s<<\" }\"<<endl;}\n\n\n\nint main() {\n    //freopen( \"/Users/macuser/Documents/Programming/Contest/input.in\", \"r\", stdin );\n    \n    int N;\n    cin >> N;\n    stack<int> st;\n    int res = 0;\n    \n    st.push(0);\n    for (int i = 0; i < N; ++i) {\n        int a; cin >> a;\n        if (a > st.top()) st.push(a);\n        else if (a == st.top()) {}\n        else {\n            while (st.top() > a) {\n                st.pop();\n                ++res;\n            }\n            if (a > st.top()) st.push(a);\n        }\n    }\n    cout << res + st.size() - 1 << endl;\n    \n    return 0;\n}\n", "problem_context": "D - カーペット\n\n総合研究7号館の引越しに伴い，研究室にカーペットを敷くことになった．\nこの問題では研究室を上から見たときの床を，二次元平面上の多角形とみなす．\n床の形状を表す要素数Nの数列\\{a_i\\}が与えられる．\nR_iを，左下の座標が(i,0)で右上の座標が(i+1,a_i)である各辺がx軸またはy軸に平行な長方形の境界及び内部領域とする．\nこのとき，床を表す多角形はR_1 ∪ R_2 ∪ R_3 ∪ … ∪ R_Nによって表される．\n\nカーペットは長方形であればどんな大きさのものを何枚でも用意することができる．\n以下の条件を満たすようにカーペットを配置し，研究室の床を全て覆いつくしたい．\n\nカーペットは研究室からはみ出してはいけない．\n\nカーペットはいくらでも重ねて敷くことが可能である．このとき，カーペットの厚さは無視する．\n\nカーペットを切り離して利用することはできない．\n\nカーペットは各辺がx軸またはy軸に平行になるように配置しなければならない．\n\n研究室の床を覆い尽くすために必要なカーペットの最小数を求めよ．\n\n図D-1. 入力例1の床\n\n図D-2. 入力例2の床\n\n入力形式\n\n入力は以下の形式で与えられる．\n\nN\na_1 … a_N\n\n出力形式\n\n研究室の床を覆い尽くすために必要なカーペットの最小数を１行に出力せよ．\n\n制約\n\n1 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq a_i \\leq 10^9\n\n入力値はすべて整数である．\n\n入出力例\n\n入力例1\n\n3\n1 2 1\n\n出力例1\n\n2\n\n入力例2\n\n10\n1 2 2 1 3 4 3 1 2 2\n\n出力例2\n\n5", "sample_input": "3\n1 2 1\n"}, "reference_outputs": ["2\n"], "source_document_id": "p01659", "source_text": "D - カーペット\n\n総合研究7号館の引越しに伴い，研究室にカーペットを敷くことになった．\nこの問題では研究室を上から見たときの床を，二次元平面上の多角形とみなす．\n床の形状を表す要素数Nの数列\\{a_i\\}が与えられる．\nR_iを，左下の座標が(i,0)で右上の座標が(i+1,a_i)である各辺がx軸またはy軸に平行な長方形の境界及び内部領域とする．\nこのとき，床を表す多角形はR_1 ∪ R_2 ∪ R_3 ∪ … ∪ R_Nによって表される．\n\nカーペットは長方形であればどんな大きさのものを何枚でも用意することができる．\n以下の条件を満たすようにカーペットを配置し，研究室の床を全て覆いつくしたい．\n\nカーペットは研究室からはみ出してはいけない．\n\nカーペットはいくらでも重ねて敷くことが可能である．このとき，カーペットの厚さは無視する．\n\nカーペットを切り離して利用することはできない．\n\nカーペットは各辺がx軸またはy軸に平行になるように配置しなければならない．\n\n研究室の床を覆い尽くすために必要なカーペットの最小数を求めよ．\n\n図D-1. 入力例1の床\n\n図D-2. 入力例2の床\n\n入力形式\n\n入力は以下の形式で与えられる．\n\nN\na_1 … a_N\n\n出力形式\n\n研究室の床を覆い尽くすために必要なカーペットの最小数を１行に出力せよ．\n\n制約\n\n1 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq a_i \\leq 10^9\n\n入力値はすべて整数である．\n\n入出力例\n\n入力例1\n\n3\n1 2 1\n\n出力例1\n\n2\n\n入力例2\n\n10\n1 2 2 1 3 4 3 1 2 2\n\n出力例2\n\n5", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1863, "cpu_time_ms": 80, "memory_kb": 1800}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s138196106", "group_id": "codeNet:p01812", "input_text": "#include<bits/stdc++.h>\n#define INF (1e9)\n#define N 105\n#define M 16\nusing namespace std;\ntypedef pair<int,int> P;\nint n,m,k,d[M],G[N][N],dp[(1<<M)];\nmap<int,int> to;\n\nint bfs(){\n  queue<P> q;\n  fill(dp,dp+(1<<M),INF);\n  dp[0]=0;\n  q.push(P(0,0));\n  while(!q.empty()){\n    P t=q.front(); q.pop();\n    int cost=t.first,node=t.second;\n    if(node==(1<<m)-1)return cost;\n    if(dp[node]<cost)continue;\n    for(int i=0;i<k;i++){\n      int next=(1<<m)-1;\n      for(int j=0;j<m;j++)\n\tif(!(node&(1<<j))&&to.count(G[d[j]][i]))\n\t  next=next&~(1<<to[G[d[j]][i]]);\n      if(dp[next]>cost+1){\n\tdp[next]=cost+1;\n\tq.push(P(dp[next],next));\n      }\n    }\n  }\n}\n\nint main(){\n  cin>>n>>m>>k;\n  for(int i=0;i<m;i++){\n    cin>>d[i]; d[i]--;\n    to[d[i]]=i;\n  }\n  for(int i=0;i<n;i++)\n    for(int j=0;j<k;j++){\n      cin>>G[i][j];\n      G[i][j]--;\n    }\n  cout<<bfs()<<endl;\n  return 0;\n}", "language": "C++", "metadata": {"date": 1488280261, "filename_ext": "cpp", "original_language": "C++", "problem_description_relpath": "problem_descriptions/p01812.html", "problem_id": "p01812", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p01812/input.txt", "sample_output_relpath": "derived/input_output/data/p01812/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p01812/C++/s138196106.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s138196106", "user_id": "u084540620"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include<bits/stdc++.h>\n#define INF (1e9)\n#define N 105\n#define M 16\nusing namespace std;\ntypedef pair<int,int> P;\nint n,m,k,d[M],G[N][N],dp[(1<<M)];\nmap<int,int> to;\n\nint bfs(){\n  queue<P> q;\n  fill(dp,dp+(1<<M),INF);\n  dp[0]=0;\n  q.push(P(0,0));\n  while(!q.empty()){\n    P t=q.front(); q.pop();\n    int cost=t.first,node=t.second;\n    if(node==(1<<m)-1)return cost;\n    if(dp[node]<cost)continue;\n    for(int i=0;i<k;i++){\n      int next=(1<<m)-1;\n      for(int j=0;j<m;j++)\n\tif(!(node&(1<<j))&&to.count(G[d[j]][i]))\n\t  next=next&~(1<<to[G[d[j]][i]]);\n      if(dp[next]>cost+1){\n\tdp[next]=cost+1;\n\tq.push(P(dp[next],next));\n      }\n    }\n  }\n}\n\nint main(){\n  cin>>n>>m>>k;\n  for(int i=0;i<m;i++){\n    cin>>d[i]; d[i]--;\n    to[d[i]]=i;\n  }\n  for(int i=0;i<n;i++)\n    for(int j=0;j<k;j++){\n      cin>>G[i][j];\n      G[i][j]--;\n    }\n  cout<<bfs()<<endl;\n  return 0;\n}", "problem_context": "真っ暗な部屋\n\n目を覚ますと、A君は真っ暗な部屋の中にいた。\nどうやらA君は N 個の部屋から構成されたダンジョンに迷い込んでしまったようだ。\nあなたはA君がどの部屋に迷い込んだのかを知ることはできなかったが、幸いにもダンジョンのマップを手に入れることができた。\nA君の進むべき道を示し明るい部屋に導こう。\n\nN 個の部屋のうち M 個の部屋が真っ暗な部屋であり、それぞれ D_1, D_2, ..., D_M 番目の部屋が真っ暗な部屋であることが分かっている。\nまた、全ての部屋からちょうど K 本の一方通行の道が順に並んでおり、i 番目の部屋から出る道はそれぞれ\nv_{i,1}, v_{i,2}, ..., v_{i,K} 番目の部屋に繋がっている。\nあなたは、A君に対し今いる部屋から a_1, a_2, ..., a_l 番目の道を順に進ませることができる。\nただし、A君は明るい部屋に到達したらそれ以降の指示は無視する。\nあなたは、指示の前後においてA君が今いる部屋の情報を知ることはできないため、A君がどの部屋にいたとしても明るい部屋に辿り着けるような指示列を伝えなければならない。\n\nそのような指示のうち、最も短いものの長さを答えよ。\n\nConstraints\n\n2 ≤ N ≤ 100\n\n1 ≤ M ≤ min(16, N − 1)\n\n1 ≤ K ≤ N\n\n1 ≤ D_i ≤ N\n\nD_i は全て異なる\n\n1 ≤ v_{i, j} ≤ N\n\n全ての暗い部屋は少なくとも1つの明るい部屋に到達可能である\n\nInput Format\n\n入力は以下の形式で標準入力から与えられる。\n\nN M K\nD_1 D_2 ... D_M\nv_{1,1} v_{1,2} ... v_{1,K}\nv_{2,1} v_{2,2} ... v_{2,K}\n...\nv_{N,1} v_{N,2} ... v_{N,K}\n\nOutput Format\n\n答えを一行に出力せよ。\n\nSample Input 1\n\n4 2 2\n1 2\n2 4\n3 1\n4 2\n1 3\n\nSample Output 1\n\n2\n\n1, 1 という指示を出すと\n\nA君の初期位置が部屋1である場合、2つ目の移動で部屋3に到達する\n\nA君の初期位置が部屋2である場合、1つ目の移動で部屋3に到達する\n\nSample Input 2\n\n3 2 2\n1 2\n2 3\n1 2\n2 1\n\nSample Output 2\n\n3\n\n2, 1, 2 という指示を出すと\n\nA君の初期位置が部屋1である場合、1つ目の移動で部屋3に到達する\n\nA君の初期位置が部屋2である場合、3つ目の移動で部屋3に到達する\n\nSample Input 3\n\n6 3 3\n1 2 3\n4 1 1\n2 5 2\n3 3 6\n4 4 4\n5 5 5\n6 6 6\n\nSample Output 3\n\n3\n\n非連結であるケースや、自己辺、多重辺があるケースに気をつけよう", "sample_input": "4 2 2\n1 2\n2 4\n3 1\n4 2\n1 3\n"}, "reference_outputs": ["2\n"], "source_document_id": "p01812", "source_text": "真っ暗な部屋\n\n目を覚ますと、A君は真っ暗な部屋の中にいた。\nどうやらA君は N 個の部屋から構成されたダンジョンに迷い込んでしまったようだ。\nあなたはA君がどの部屋に迷い込んだのかを知ることはできなかったが、幸いにもダンジョンのマップを手に入れることができた。\nA君の進むべき道を示し明るい部屋に導こう。\n\nN 個の部屋のうち M 個の部屋が真っ暗な部屋であり、それぞれ D_1, D_2, ..., D_M 番目の部屋が真っ暗な部屋であることが分かっている。\nまた、全ての部屋からちょうど K 本の一方通行の道が順に並んでおり、i 番目の部屋から出る道はそれぞれ\nv_{i,1}, v_{i,2}, ..., v_{i,K} 番目の部屋に繋がっている。\nあなたは、A君に対し今いる部屋から a_1, a_2, ..., a_l 番目の道を順に進ませ���ことができる。\nただし、A君は明るい部屋に到達したらそれ以降の指示は無視する。\nあなたは、指示の前後においてA君が今いる部屋の情報を知ることはできないため、A君がどの部屋にいたとしても明るい部屋に辿り着けるような指示列を伝えなければならない。\n\nそのような指示のうち、最も短いものの長さを答えよ。\n\nConstraints\n\n2 ≤ N ≤ 100\n\n1 ≤ M ≤ min(16, N − 1)\n\n1 ≤ K ≤ N\n\n1 ≤ D_i ≤ N\n\nD_i は全て異なる\n\n1 ≤ v_{i, j} ≤ N\n\n全ての暗い部屋は少なくとも1つの明るい部屋に到達可能である\n\nInput Format\n\n入力は以下の形式で標準入力から与えられる。\n\nN M K\nD_1 D_2 ... D_M\nv_{1,1} v_{1,2} ... v_{1,K}\nv_{2,1} v_{2,2} ... v_{2,K}\n...\nv_{N,1} v_{N,2} ... v_{N,K}\n\nOutput Format\n\n答えを一行に出力せよ。\n\nSample Input 1\n\n4 2 2\n1 2\n2 4\n3 1\n4 2\n1 3\n\nSample Output 1\n\n2\n\n1, 1 という指示を出すと\n\nA君の初期位置が部屋1である場合、2つ目の移動で部屋3に到達する\n\nA君の初期位置が部屋2である場合、1つ目の移動で部屋3に到達する\n\nSample Input 2\n\n3 2 2\n1 2\n2 3\n1 2\n2 1\n\nSample Output 2\n\n3\n\n2, 1, 2 という指示を出すと\n\nA君の初期位置が部屋1である場合、1つ目の移動で部屋3に到達する\n\nA君の初期位置が部屋2である場合、3つ目の移動で部屋3に到達する\n\nSample Input 3\n\n6 3 3\n1 2 3\n4 1 1\n2 5 2\n3 3 6\n4 4 4\n5 5 5\n6 6 6\n\nSample Output 3\n\n3\n\n非連結であるケースや、自己辺、多重辺があるケースに気をつけよう", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 868, "cpu_time_ms": 830, "memory_kb": 3576}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s973909896", "group_id": "codeNet:p01940", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nstring t,p;\nchar c;\nint i,j,k,l,x;\nmain(){\n  for(cin>>t>>p;i<t.size();++i){\n    if(t[i]==c&&t[i]!=p[j]){\n      c='0';\n      break;\n    }\n    if(t[i]==p[j])++j,c=t[i];\n  }\n  x=c-'0'?1:0;\n  c='0';\n  for(reverse(t.begin(),t.end()),reverse(p.begin(),p.end());k<t.size();++k){\n    if(t[k]==c&&t[k]!=p[l]){\n      c='0';\n      break;\n    }\n    if(t[k]==p[l])++l,c=t[k];\n  }\n  x&=c-'0'?1:0;\n  cout<<(x&&j==p.size()?\"yes\\n\":\"no\\n\");\n}", "language": "C++", "metadata": {"date": 1506755478, "filename_ext": "cpp", "original_language": "C++", "problem_description_relpath": "problem_descriptions/p01940.html", "problem_id": "p01940", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p01940/input.txt", "sample_output_relpath": "derived/input_output/data/p01940/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p01940/C++/s973909896.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s973909896", "user_id": "u301727652"}, "prompt_components": {"gold_output": "yes\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nstring t,p;\nchar c;\nint i,j,k,l,x;\nmain(){\n  for(cin>>t>>p;i<t.size();++i){\n    if(t[i]==c&&t[i]!=p[j]){\n      c='0';\n      break;\n    }\n    if(t[i]==p[j])++j,c=t[i];\n  }\n  x=c-'0'?1:0;\n  c='0';\n  for(reverse(t.begin(),t.end()),reverse(p.begin(),p.end());k<t.size();++k){\n    if(t[k]==c&&t[k]!=p[l]){\n      c='0';\n      break;\n    }\n    if(t[k]==p[l])++l,c=t[k];\n  }\n  x&=c-'0'?1:0;\n  cout<<(x&&j==p.size()?\"yes\\n\":\"no\\n\");\n}", "problem_context": "C： たったひとつの部分列 - Unique Subsequence -\n\n問題\n\nある日えびちゃんは、机の上に長さ n のテキスト文字列 T と長さ m のパターン文字列 P (m \\leq n) が置かれていることに気づきました。えびちゃんは、文字列に現れる「たったひとつの部分列」が大好きであるため、 P が T のたったひとつの部分列であるかどうかをすぐに調査し始めました。\n\nP が T のたったひとつの部分列であるという性質は以下のように表されます。ここで、文字列 X の i 文字目を X_i と書きます。\n\n長さ m の数列 S = (s_1, ..., s_m) (ただし、 s_1 < s_2 < ... < s_m) で、各 i (i = 1, ..., m) について T_{s_i} = P_i である数列 S が一意に定まる。\n\n調査を始めてから数時間、えびちゃんは文字列をぐっと睨んでいましたが、文字列が長すぎるために疲れてしまったようです。それを見かねたあなたは、えびちゃんを手伝ってあげることにしました。���びちゃんのために、 P が T のたったひとつの部分列であるならば “yes” を、そうでないならば “no” を出力するプログラムを作成してください。\n\n入力形式\n\nT\nP\n\n1 行目には、テキスト文字列 T が与えられる。\n2 行目には、パターン文字列 P が与えられる。\n\n制約\n\n1 \\leq |P| \\leq |T| \\leq 5 \\times 10^5\n\nT および P は英字小文字 ‘a’-’z’ で構成される。\n\n出力形式\n\nP が T のたったひとつの部分列であるならば “yes” を、そうでないならば “no” を1行に出力してください。\n\n入力例1\n\naizucamp\nazu\n\n出力例1\n\nyes\n\n入力例2\n\nabracadabra\nrada\n\n出力例2\n\nno\n\n入力例3\n\nhokkaido\ndekai\n\n出力例3\n\nno", "sample_input": "aizucamp\nazu\n"}, "reference_outputs": ["yes\n"], "source_document_id": "p01940", "source_text": "C： たったひとつの部分列 - Unique Subsequence -\n\n問題\n\nある日えびちゃんは、机の上に長さ n のテキスト文字列 T と長さ m のパターン文字列 P (m \\leq n) が置かれていることに気づきました。えびちゃんは、文字列に現れる「たったひとつの部分列」が大好きであるため、 P が T のたったひとつの部分列であるかどうかをすぐに調査し始めました。\n\nP が T のたったひとつの部分列であるという性質は以下のように表されます。ここで、文字列 X の i 文字目を X_i と書きます。\n\n長さ m の数列 S = (s_1, ..., s_m) (ただし、 s_1 < s_2 < ... < s_m) で、各 i (i = 1, ..., m) について T_{s_i} = P_i である数列 S が一意に定まる。\n\n調査を始めてから数時間、えびちゃんは文字列をぐっと睨んでいましたが、文字列が長すぎるために疲れてしまったようです。それを見かねたあなたは、えびちゃんを手伝ってあげることにしました。えびちゃんのために、 P が T のたったひとつの部分列であるならば “yes” を、そうでないならば “no” を出力するプログラムを作成してください。\n\n入力形式\n\nT\nP\n\n1 行目には、テキスト文字列 T が与えられる。\n2 行目には、パターン文字列 P が与えられる。\n\n制約\n\n1 \\leq |P| \\leq |T| \\leq 5 \\times 10^5\n\nT および P は英字小文字 ‘a’-’z’ で構成される。\n\n出力形式\n\nP が T のたったひとつの部分列であるならば “yes” を、そうでないならば “no” を1行に出力してください。\n\n入力例1\n\naizucamp\nazu\n\n出力例1\n\nyes\n\n入力例2\n\nabracadabra\nrada\n\n出力例2\n\nno\n\n入力例3\n\nhokkaido\ndekai\n\n出力例3\n\nno", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 470, "cpu_time_ms": 30, "memory_kb": 4252}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s410999974", "group_id": "codeNet:p01998", "input_text": "#include<bits/stdc++.h>\n#define X first\n#define Y second\n#define pb push_back\n#define eb pb\n#define rep(X,Y) for(int X=0;X<(Y);++X)\n#define reps(X,O,Y) for(int X=O;X<(Y);++X)\n#define all(X) (X).begin(),(X).end()\n\nusing namespace std;\nusing ll=long long;\n\nconst int N=11234567;\nint prime[N];\n\nint main(){\n\tfill(prime,prime+N,1);\n\tprime[0]=prime[1]=0;\n\trep(i,N)if(prime[i])for(int j=i+i;j<N;j+=i) prime[j]=0;\n\t// rep(i,10) cout<<prime[i];cout<<endl;\n\tint n;\n\tcin>>n;\n\tif(n<=2){ cout<<0<<endl; return 0;}\n\tint re=0;\n\treps(i,3,n+1)if(prime[i] && prime[i+2]) ++re;\n\tcout<<re*2<<endl;\n}\n\n", "language": "C++", "metadata": {"date": 1537336216, "filename_ext": "cpp", "original_language": "C++14", "problem_description_relpath": "problem_descriptions/p01998.html", "problem_id": "p01998", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p01998/input.txt", "sample_output_relpath": "derived/input_output/data/p01998/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p01998/C++/s410999974.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s410999974", "user_id": "u775414834"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include<bits/stdc++.h>\n#define X first\n#define Y second\n#define pb push_back\n#define eb pb\n#define rep(X,Y) for(int X=0;X<(Y);++X)\n#define reps(X,O,Y) for(int X=O;X<(Y);++X)\n#define all(X) (X).begin(),(X).end()\n\nusing namespace std;\nusing ll=long long;\n\nconst int N=11234567;\nint prime[N];\n\nint main(){\n\tfill(prime,prime+N,1);\n\tprime[0]=prime[1]=0;\n\trep(i,N)if(prime[i])for(int j=i+i;j<N;j+=i) prime[j]=0;\n\t// rep(i,10) cout<<prime[i];cout<<endl;\n\tint n;\n\tcin>>n;\n\tif(n<=2){ cout<<0<<endl; return 0;}\n\tint re=0;\n\treps(i,3,n+1)if(prime[i] && prime[i+2]) ++re;\n\tcout<<re*2<<endl;\n}\n\n", "problem_context": "C: 素数\n\n問題\n\nある日、素数が大好きなそすうさ君は $p + q$ が素数となるペア $(p, q)$ で遊んでいた。\nそすうさ君は突然、このペアのうち、 $p$ と $q$ がともに $N$ 以下の素数であるペアがいくつあるか気になりだした。\nそすうさ君に代わって個数を求めよ。\n\n制約\n\n入力値は全て整数である。\n\n$1 \\leq N \\leq 10^7$\n\n入力形式\n\n入力は以下の形式で与えられる。\n\n$N$\n\n出力\n\nペアの個数を出力せよ。また、末尾に改行も出力せよ。\n\nサンプル\n\nサンプル入力 1\n\n3\n\nサンプル出力 1\n\n2\n\nペアは $(2, 3), (3, 2)$ の二つである。\n\nサンプル入力 2\n\n20\n\nサンプル出力 2\n\n8", "sample_input": "3\n"}, "reference_outputs": ["2\n"], "source_document_id": "p01998", "source_text": "C: 素数\n\n問題\n\nある日、素数が大好きなそすうさ君は $p + q$ が素数となるペア $(p, q)$ で遊んでいた。\nそすうさ君は突然、このペアのうち、 $p$ と $q$ がともに $N$ 以下の素数であるペアがいくつあるか気になりだした。\nそすうさ君に代わって個数を求めよ。\n\n制約\n\n入力値は全て整数である。\n\n$1 \\leq N \\leq 10^7$\n\n入力形式\n\n入力は以下の形式で与えられる。\n\n$N$\n\n出力\n\nペアの個数を出力せよ。また、末尾に改行も出力せよ。\n\nサンプル\n\nサンプル入力 1\n\n3\n\nサンプル出力 1\n\n2\n\nペアは $(2, 3), (3, 2)$ の二つである。\n\nサンプル入力 2\n\n20\n\nサンプル出力 2\n\n8", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 582, "cpu_time_ms": 290, "memory_kb": 46984}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s497274715", "group_id": "codeNet:p02258", "input_text": "#include<iostream>\n#include<algorithm>\nusing namespace std;\n \nint main(){\n  long long int mi = 100000000000,ma = -100000000000,a,n;\n  cin >> n;\n  for(int i=0;i<n;i++){\n    cin >> a;\n    ma = max(ma,a-mi);\n    mi = min(mi,a);\n  }\n  cout<<ma<<endl;\n}", "language": "C++", "metadata": {"date": 1502758904, "filename_ext": "cpp", "original_language": "C++", "problem_description_relpath": "problem_descriptions/p02258.html", "problem_id": "p02258", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02258/input.txt", "sample_output_relpath": "derived/input_output/data/p02258/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02258/C++/s497274715.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s497274715", "user_id": "u974072558"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include<iostream>\n#include<algorithm>\nusing namespace std;\n \nint main(){\n  long long int mi = 100000000000,ma = -100000000000,a,n;\n  cin >> n;\n  for(int i=0;i<n;i++){\n    cin >> a;\n    ma = max(ma,a-mi);\n    mi = min(mi,a);\n  }\n  cout<<ma<<endl;\n}", "problem_context": "MathJax.Hub.Config({ tex2jax: { inlineMath: [[\"$\",\"$\"], [\"\\\\(\",\"\\\\)\"]], processEscapes: true }});\n\nMaximum Profit\n\nYou can obtain profits from foreign exchange margin transactions. For example, if you buy 1000 dollar at a rate of 100 yen per dollar, and sell them at a rate of 108 yen per dollar, you can obtain (108 - 100) × 1000 = 8000 yen.\n\nWrite a program which reads values of a currency $R_t$ at a certain time $t$ ($t = 0, 1, 2, ... n-1$), and reports the maximum value of $R_j - R_i$ where $j > i$ .\n\nInput\n\nThe first line contains an integer $n$. In the following $n$ lines, $R_t$ ($t = 0, 1, 2, ... n-1$) are given in order.\n\nOutput\n\nPrint the maximum value in a line.\n\nConstraints\n\n$2 \\leq n \\leq 200,000$\n\n$1 \\leq R_t \\leq 10^9$\n\nSample Input 1\n\n6\n5\n3\n1\n3\n4\n3\n\nSample Output 1\n\n3\n\nSample Input 2\n\n3\n4\n3\n2\n\nSample Output 2\n\n-1", "sample_input": "6\n5\n3\n1\n3\n4\n3\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02258", "source_text": "MathJax.Hub.Config({ tex2jax: { inlineMath: [[\"$\",\"$\"], [\"\\\\(\",\"\\\\)\"]], processEscapes: true }});\n\nMaximum Profit\n\nYou can obtain profits from foreign exchange margin transactions. For example, if you buy 1000 dollar at a rate of 100 yen per dollar, and sell them at a rate of 108 yen per dollar, you can obtain (108 - 100) × 1000 = 8000 yen.\n\nWrite a program which reads values of a currency $R_t$ at a certain time $t$ ($t = 0, 1, 2, ... n-1$), and reports the maximum value of $R_j - R_i$ where $j > i$ .\n\nInput\n\nThe first line contains an integer $n$. In the following $n$ lines, $R_t$ ($t = 0, 1, 2, ... n-1$) are given in order.\n\nOutput\n\nPrint the maximum value in a line.\n\nConstraints\n\n$2 \\leq n \\leq 200,000$\n\n$1 \\leq R_t \\leq 10^9$\n\nSample Input 1\n\n6\n5\n3\n1\n3\n4\n3\n\nSample Output 1\n\n3\n\nSample Input 2\n\n3\n4\n3\n2\n\nSample Output 2\n\n-1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 248, "cpu_time_ms": 50, "memory_kb": 3120}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s070595940", "group_id": "codeNet:p02274", "input_text": "#include <iostream>\n#include<stdio.h>\nusing namespace std;\n#define MAX 200000\n#define mm  10000000000\ntypedef long long ll;\nint L[MAX],R[MAX];\nll merge(int A[],int n,int left,int mid,int right)\n{\n\n    int i,j,k;\n    ll cnt=0;\n    int n1=mid-left;\n    int n2=right-mid;\n    for(i=0; i<n1; i++)L[i]=A[left+i];\n    for(i=0; i<n2; i++)R[i]=A[mid+i];\n    L[n1]=R[n2]=mm;\n    i=0;\n    j=0;\n    for(k=left; k<right; k++)\n    {\n        if(L[i]<=R[j])\n        {\n            A[k]=L[i++];\n        }\n        else\n        {\n            A[k]=R[j++];\n            cnt+=n1-i;//=mid+j-k-i;\n        }\n    }\n    return cnt;\n\n}\nll mergeSort(int A[],int n,int left, int right)\n{\n    int mid;\n    ll v1,v2,v3;\n    if(left+1<right)\n    {\n        mid=(left+right)/2;\n        v1=mergeSort(A,n,left,mid);\n        v2=mergeSort(A,n,mid,right);\n        v3=merge(A,n,left,mid,right);\n        return v1+v2+v3;\n    }\n    return 0;\n}\nint main()\n{\n    int A[MAX],n;\n    scanf(\"%d\",&n);\n    for(int i=0; i<n; i++)\n    {\n        scanf(\"%d\",&A[i]);\n    }\n    ll ans=mergeSort(A,n,0,n);\n    cout<<ans<<endl;\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1584461404, "filename_ext": "cpp", "original_language": "C++", "problem_description_relpath": "problem_descriptions/p02274.html", "problem_id": "p02274", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02274/input.txt", "sample_output_relpath": "derived/input_output/data/p02274/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02274/C++/s070595940.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s070595940", "user_id": "u633917844"}, "prompt_components": {"gold_output": "6\n", "input_to_evaluate": "#include <iostream>\n#include<stdio.h>\nusing namespace std;\n#define MAX 200000\n#define mm  10000000000\ntypedef long long ll;\nint L[MAX],R[MAX];\nll merge(int A[],int n,int left,int mid,int right)\n{\n\n    int i,j,k;\n    ll cnt=0;\n    int n1=mid-left;\n    int n2=right-mid;\n    for(i=0; i<n1; i++)L[i]=A[left+i];\n    for(i=0; i<n2; i++)R[i]=A[mid+i];\n    L[n1]=R[n2]=mm;\n    i=0;\n    j=0;\n    for(k=left; k<right; k++)\n    {\n        if(L[i]<=R[j])\n        {\n            A[k]=L[i++];\n        }\n        else\n        {\n            A[k]=R[j++];\n            cnt+=n1-i;//=mid+j-k-i;\n        }\n    }\n    return cnt;\n\n}\nll mergeSort(int A[],int n,int left, int right)\n{\n    int mid;\n    ll v1,v2,v3;\n    if(left+1<right)\n    {\n        mid=(left+right)/2;\n        v1=mergeSort(A,n,left,mid);\n        v2=mergeSort(A,n,mid,right);\n        v3=merge(A,n,left,mid,right);\n        return v1+v2+v3;\n    }\n    return 0;\n}\nint main()\n{\n    int A[MAX],n;\n    scanf(\"%d\",&n);\n    for(int i=0; i<n; i++)\n    {\n        scanf(\"%d\",&A[i]);\n    }\n    ll ans=mergeSort(A,n,0,n);\n    cout<<ans<<endl;\n    return 0;\n}\n", "problem_context": "MathJax.Hub.Config({ tex2jax: { inlineMath: [[\"$\",\"$\"], [\"\\\\(\",\"\\\\)\"]], processEscapes: true }});\n\nThe Number of Inversions\n\nFor a given sequence $A = \\{a_0, a_1, ... a_{n-1}\\}$, the number of pairs $(i, j)$ where $a_i > a_j$ and $i < j$, is called the number of inversions. The number of inversions is equal to the number of swaps of Bubble Sort defined in the following program:\n\nbubbleSort(A)\ncnt = 0 // the number of inversions\nfor i = 0 to A.length-1\nfor j = A.length-1 downto i+1\nif A[j] < A[j-1]\nswap(A[j], A[j-1])\ncnt++\n\nreturn cnt\n\nFor the given sequence $A$, print the number of inversions of $A$. Note that you should not use the above program, which brings Time Limit Exceeded.\n\nInput\n\nIn the first line, an integer $n$, the number of elements in $A$, is given. In the second line, the elements $a_i$ ($i = 0, 1, .. n-1$) are given separated by space characters.\n\noutput\n\nPrint the number of inversions in a line.\n\nConstraints\n\n$ 1 \\leq n \\leq 200,000$\n\n$ 0 \\leq a_i \\leq 10^9$\n\n$a_i$ are all different\n\nSample Input 1\n\n5\n3 5 2 1 4\n\nSample Output 1\n\n6\n\nSample Input 2\n\n3\n3 1 2\n\nSample Output 2\n\n2", "sample_input": "5\n3 5 2 1 4\n"}, "reference_outputs": ["6\n"], "source_document_id": "p02274", "source_text": "MathJax.Hub.Config({ tex2jax: { inlineMath: [[\"$\",\"$\"], [\"\\\\(\",\"\\\\)\"]], processEscapes: true }});\n\nThe Number of Inversions\n\nFor a given sequence $A = \\{a_0, a_1, ... a_{n-1}\\}$, the number of pairs $(i, j)$ where $a_i > a_j$ and $i < j$, is called the number of inversions. The number of inversions is equal to the number of swaps of Bubble Sort defined in the following program:\n\nbubbleSort(A)\ncnt = 0 // the number of inversions\nfor i = 0 to A.length-1\nfor j = A.length-1 downto i+1\nif A[j] < A[j-1]\nswap(A[j], A[j-1])\ncnt++\n\nreturn cnt\n\nFor the given sequence $A$, print the number of inversions of $A$. Note that you should not use the above program, which brings Time Limit Exceeded.\n\nInput\n\nIn the first line, an integer $n$, the number of elements in $A$, is given. In the second line, the elements $a_i$ ($i = 0, 1, .. n-1$) are given separated by space characters.\n\noutput\n\nPrint the number of inversions in a line.\n\nConstraints\n\n$ 1 \\leq n \\leq 200,000$\n\n$ 0 \\leq a_i \\leq 10^9$\n\n$a_i$ are all different\n\nSample Input 1\n\n5\n3 5 2 1 4\n\nSample Output 1\n\n6\n\nSample Input 2\n\n3\n3 1 2\n\nSample Output 2\n\n2", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1085, "cpu_time_ms": 20, "memory_kb": 4716}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s507742532", "group_id": "codeNet:p02283", "input_text": "#include <cstdio>\n#include <cstdlib>\n#pragma warning(disable : 4996)\nstruct Node {\n\tint key;\n\tNode *p, *l, *r;\n};\nNode *root, *NIL;\nvoid insert(int key_) {\n\tNode *x = root, *y = NIL, *z;\n\tz = (Node*)malloc(sizeof(Node));\n\tz->key = key_, z->l = NIL, z->r = NIL;\n\twhile (x != NIL) {\n\t\ty = x;\n\t\tx = (z->key < x->key) ? x->l : x->r;\n\t}\n\tz->p = y;\n\tif (y == NIL) root = z;\n\telse if (z->key < y->key) y->l = z;\n\telse y->r = z;\n}\nvoid walk1(Node *x) { if (x == NIL) return; walk1(x->l); printf(\" %d\", x->key); walk1(x->r); }\nvoid walk2(Node *x) { if (x == NIL) return; printf(\" %d\", x->key); walk2(x->l); walk2(x->r); }\nint n, v; char c[8];\nint main() {\n\tscanf(\"%d\", &n);\n\tfor (int i = 0; i < n; i++) {\n\t\tscanf(\"%s\", &c);\n\t\tif (c[0] == 'i') scanf(\"%d\", &v), insert(v);\n\t\telse walk1(root), printf(\"\\n\"), walk2(root), printf(\"\\n\");\n\t}\n}", "language": "C++", "metadata": {"date": 1463480465, "filename_ext": "cpp", "original_language": "C++11", "problem_description_relpath": "problem_descriptions/p02283.html", "problem_id": "p02283", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02283/input.txt", "sample_output_relpath": "derived/input_output/data/p02283/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02283/C++/s507742532.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s507742532", "user_id": "u823513038"}, "prompt_components": {"gold_output": " 1 12 17 20 25 30 88\n 30 12 1 20 17 25 88\n", "input_to_evaluate": "#include <cstdio>\n#include <cstdlib>\n#pragma warning(disable : 4996)\nstruct Node {\n\tint key;\n\tNode *p, *l, *r;\n};\nNode *root, *NIL;\nvoid insert(int key_) {\n\tNode *x = root, *y = NIL, *z;\n\tz = (Node*)malloc(sizeof(Node));\n\tz->key = key_, z->l = NIL, z->r = NIL;\n\twhile (x != NIL) {\n\t\ty = x;\n\t\tx = (z->key < x->key) ? x->l : x->r;\n\t}\n\tz->p = y;\n\tif (y == NIL) root = z;\n\telse if (z->key < y->key) y->l = z;\n\telse y->r = z;\n}\nvoid walk1(Node *x) { if (x == NIL) return; walk1(x->l); printf(\" %d\", x->key); walk1(x->r); }\nvoid walk2(Node *x) { if (x == NIL) return; printf(\" %d\", x->key); walk2(x->l); walk2(x->r); }\nint n, v; char c[8];\nint main() {\n\tscanf(\"%d\", &n);\n\tfor (int i = 0; i < n; i++) {\n\t\tscanf(\"%s\", &c);\n\t\tif (c[0] == 'i') scanf(\"%d\", &v), insert(v);\n\t\telse walk1(root), printf(\"\\n\"), walk2(root), printf(\"\\n\");\n\t}\n}", "problem_context": "MathJax.Hub.Config({ tex2jax: { inlineMath: [[\"$\",\"$\"], [\"\\\\(\",\"\\\\)\"]], processEscapes: true }});\n\nBinary Search Tree I\n\nSearch trees are data structures that support dynamic set operations including insert, search, delete and so on. Thus a search tree can be used both as a dictionary and as a priority queue.\n\nBinary search tree is one of fundamental search trees. The keys in a binary search tree are always stored in such a way as to satisfy the following binary search tree property:\n\nLet $x$ be a node in a binary search tree. If $y$ is a node in the left subtree of $x$, then $y.key \\leq x.key$. If $y$ is a node in the right subtree of $x$, then $x.key \\leq y.key$.\n\nThe following figure shows an example of the binary search tree.\n\nFor example, keys of nodes which belong to the left sub-tree of the node containing 80 are less than or equal to 80, and keys of nodes which belong to the right sub-tree are more than or equal to 80. The binary search tree property allows us to print out all the keys in the tree in sorted order by an inorder tree walk.\n\nA binary search tree should be implemented in such a way that the binary search tree property continues to hold after modifications by insertions and deletions. A binary search tree can be represented by a linked data structure in which each node is an object. In addition to a key field and satellite data, each node contains fields left, right, and p that point to the nodes corresponding to its left child, its right child, and its parent, respectively.\n\nTo insert a new value $v$ into a binary search tree $T$, we can use the procedure insert as shown in the following pseudo code. The insert procedure is passed a node $z$ for which $z.key = v$, $z.left = NIL$, and $z.right = NIL$. The procedure modifies $T$ and some of the fields of $z$ in such a way that $z$ is inserted into an appropriate position in the tree.\n\n1 insert(T, z)\n2 y = NIL // parent of x\n3 x = 'the root of T'\n4 while x ≠ NIL\n5 y = x // set the parent\n6 if z.key < x.key\n7 x = x.left // move to the left child\n8 else\n9 x = x.right // move to the right child\n10 z.p = y\n11\n12 if y == NIL // T is empty\n13 'the root of T' = z\n14 else if z.key < y.key\n15 y.left = z // z is the left child of y\n16 else\n17 y.right = z // z is the right child of y\n\nWrite a program which performs the following operations to a binary search tree $T$.\n\ninsert $k$: Insert a node containing $k$ as key into $T$.\n\nprint: Print the keys of the binary search tree by inorder tree walk and preorder tree walk respectively.\n\nYou should use the above pseudo code to implement the insert operation. $T$ is empty at the initial state.\n\nInput\n\nIn the first line, the number of operations $m$ is given. In the following $m$ lines, operations represented by insert $k$ or print are given.\n\nOutput\n\nFor each print operation, print a list of keys obtained by inorder tree walk and preorder tree walk in a line respectively. Put a space character before each key.\n\nConstraints\n\nThe number of operations $\\leq 500,000$\n\nThe number of print operations $\\leq 10$.\n\n$-2,000,000,000 \\leq key \\leq 2,000,000,000$\n\nThe height of the binary tree does not exceed 100 if you employ the above pseudo code.\n\nThe keys in the binary search tree are all different.\n\nSample Input 1\n\n8\ninsert 30\ninsert 88\ninsert 12\ninsert 1\ninsert 20\ninsert 17\ninsert 25\nprint\n\nSample Output 1\n\n1 12 17 20 25 30 88\n30 12 1 20 17 25 88\n\nReference\n\nIntroduction to Algorithms, Thomas H. Cormen, Charles E. Leiserson, Ronald L. Rivest, and Clifford Stein. The MIT Press.", "sample_input": "8\ninsert 30\ninsert 88\ninsert 12\ninsert 1\ninsert 20\ninsert 17\ninsert 25\nprint\n"}, "reference_outputs": [" 1 12 17 20 25 30 88\n 30 12 1 20 17 25 88\n"], "source_document_id": "p02283", "source_text": "MathJax.Hub.Config({ tex2jax: { inlineMath: [[\"$\",\"$\"], [\"\\\\(\",\"\\\\)\"]], processEscapes: true }});\n\nBinary Search Tree I\n\nSearch trees are data structures that support dynamic set operations including insert, search, delete and so on. Thus a search tree can be used both as a dictionary and as a priority queue.\n\nBinary search tree is one of fundamental search trees. The keys in a binary search tree are always stored in such a way as to satisfy the following binary search tree property:\n\nLet $x$ be a node in a binary search tree. If $y$ is a node in the left subtree of $x$, then $y.key \\leq x.key$. If $y$ is a node in the right subtree of $x$, then $x.key \\leq y.key$.\n\nThe following figure shows an example of the binary search tree.\n\nFor example, keys of nodes which belong to the left sub-tree of the node containing 80 are less than or equal to 80, and keys of nodes which belong to the right sub-tree are more than or equal to 80. The binary search tree property allows us to print out all the keys in the tree in sorted order by an inorder tree walk.\n\nA binary search tree should be implemented in such a way that the binary search tree property continues to hold after modifications by insertions and deletions. A binary search tree can be represented by a linked data structure in which each node is an object. In addition to a key field and satellite data, each node contains fields left, right, and p that point to the nodes corresponding to its left child, its right child, and its parent, respectively.\n\nTo insert a new value $v$ into a binary search tree $T$, we can use the procedure insert as shown in the following pseudo code. The insert procedure is passed a node $z$ for which $z.key = v$, $z.left = NIL$, and $z.right = NIL$. The procedure modifies $T$ and some of the fields of $z$ in such a way that $z$ is inserted into an appropriate position in the tree.\n\n1 insert(T, z)\n2 y = NIL // parent of x\n3 x = 'the root of T'\n4 while x ≠ NIL\n5 y = x // set the parent\n6 if z.key < x.key\n7 x = x.left // move to the left child\n8 else\n9 x = x.right // move to the right child\n10 z.p = y\n11\n12 if y == NIL // T is empty\n13 'the root of T' = z\n14 else if z.key < y.key\n15 y.left = z // z is the left child of y\n16 else\n17 y.right = z // z is the right child of y\n\nWrite a program which performs the following operations to a binary search tree $T$.\n\ninsert $k$: Insert a node containing $k$ as key into $T$.\n\nprint: Print the keys of the binary search tree by inorder tree walk and preorder tree walk respectively.\n\nYou should use the above pseudo code to implement the insert operation. $T$ is empty at the initial state.\n\nInput\n\nIn the first line, the number of operations $m$ is given. In the following $m$ lines, operations represented by insert $k$ or print are given.\n\nOutput\n\nFor each print operation, print a list of keys obtained by inorder tree walk and preorder tree walk in a line respectively. Put a space character before each key.\n\nConstraints\n\nThe number of operations $\\leq 500,000$\n\nThe number of print operations $\\leq 10$.\n\n$-2,000,000,000 \\leq key \\leq 2,000,000,000$\n\nThe height of the binary tree does not exceed 100 if you employ the above pseudo code.\n\nThe keys in the binary search tree are all different.\n\nSample Input 1\n\n8\ninsert 30\ninsert 88\ninsert 12\ninsert 1\ninsert 20\ninsert 17\ninsert 25\nprint\n\nSample Output 1\n\n1 12 17 20 25 30 88\n30 12 1 20 17 25 88\n\nReference\n\nIntroduction to Algorithms, Thomas H. Cormen, Charles E. Leiserson, Ronald L. Rivest, and Clifford Stein. The MIT Press.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 827, "cpu_time_ms": 330, "memory_kb": 26024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s219344991", "group_id": "codeNet:p02283", "input_text": "#include <iostream>\n#include <algorithm> // next_permutation\n#include <iomanip>\n#include <cmath>\n#include <vector>\n#include <sstream>\n#include <string>\n#include <cstdio>\n#include <stack>\n#include <queue>\n#include <list>\n#include <numeric> //accumulate\n//#include <unordered_map> //???????????\\??¢??°\n#include <fstream> //ifstream, ofstream\n\n//#define NDEBUG //NDEBUG???#include <cassert>???????????????????????????????????´???assert?????????????????????????????????NDEBUG?????????????????????????????????????????????\n#include <cassert> //assert\n\n\nusing namespace std;\n\n//???????????°??????TEST????????????????????¬???????????????????????????????????¢????????????\n#define TEST //*******************************************************************************************************************************************\n//?????????????????¨??§?????\\????????????????????????????????°?????????????¨???????????????????dout???????????????????????§???????????¬??????????????????????????????????????????\n//??????????????????????????????????????????????????????????§?CPU???????£??????????????????§???TLE?????????????????????????????????????????§????????¨???                           ????????????????????????cerr????????£????????????????????????????????????\n#ifdef TEST\n#define dout cout\n#else\nstringstream dummy; //???????????°??????dout?????????????????????????????????\n#define dout dummy.str(\"\"); dummy.clear(stringstream::goodbit); dummy //dummy?????????????????????????????????????????¨?????¢?????¢???????????????\n//???????????¨??????????????????goodbit?????????????????????????????¨???????????´????????????????????????????????¨?????°?????????????????§???????????????????????????????????? http://d.hatena.ne.jp/linden/20060427/p1\n#endif\n\n//?¨??????????????????????????????????????????????????????´??????OUTPUT2TEXTFILE????????????????????¬???????????????????????????????????¢????????????\n//#define OUTPUT2TEXTFILE //*******************************************************************************************************************************************\n#ifdef OUTPUT2TEXTFILE\n#define dout outputfile //??¨????????????TLE????????§?????????dout?????¨??¨??????????????¢????????????????????????????????????????????§????¨????????????´??????????????£??????????????????????¨?????????????????????????????????????????????§?????????????????????\n//TEST??????????????????????????¨???outputfile??????????????????????????????\n#define OUTPUTFILENAME \"output.txt\"\nofstream outputfile(OUTPUTFILENAME);\n#define OutputFilePath \"/Users/Nag/Documents/Prgm/Test/DerivedData/Test/Build/Products/Debug/output.txt\"\n#endif\n\n#define disp(A) dout << #A << \" = \" << (A) << endl\n#define disP(A) dout << setw(3) << (A) << \" \" // << setw(3) ??????????????\\????????????\n#define rep(i,a,n) for(int (i)=(a); (i)<(n); (i)++)\n\n#define dispAll(A,n) dout << #A << \" = \"; rep(j, 0, (n)) {disP(A[j]);} dout << endl\n\ntypedef pair<int,int> pii;\ntypedef vector<int> vi;\ntypedef unsigned long long ll;\n\nconst int INF = 1e9-1;\n\n\n\nclass Node {\npublic:\n    Node(int value) {\n        v = value;\n        p = NULL;\n        l = NULL;\n        r = NULL;\n    }\n    \n    \n    int v;\n    Node* p;\n    Node* l;\n    Node* r;\n};\n\n\n\nclass BinaryTree {\npublic:\n    BinaryTree() {\n        root = NULL;\n    }\n    \n    \n    Node* root;\n    \n    \n    void insert(int value) {\n        Node* x = new Node(value); //????????????????????????\n        \n        \n        Node* ptr = root; //tree??°?????¨???????????????\n        Node* ptr_parent = NULL;\n        while( ptr!=NULL ) { //NULL????????????????????§?????????????????¨???ptr_parent????????????????????????\n            ptr_parent = ptr;\n            if( x->v < ptr->v ) ptr = ptr->l;\n            else ptr = ptr->r;\n        }\n        \n        \n        if(ptr_parent==NULL) { //tree???????????£?????????????????¨????????????????????????\n            root = x;\n            return;\n        }\n        else if( x->v < ptr_parent->v) {\n            ptr_parent->l = x;\n        }\n        else {\n            ptr_parent->r = x;\n        }\n    }\n    \n    \n    static void printInorder(Node* x) {\n        if(x==NULL) return;\n        \n        printInorder(x->l);\n        cout << \" \" << x->v;\n        printInorder(x->r);\n    }\n    \n    \n    static void printPreorder(Node* x) {\n        if(x==NULL) return;\n        \n        cout << \" \" << x->v;\n        printPreorder(x->l);\n        printPreorder(x->r);\n    }\n    \n    \n};\n\n\nint main(){\n    BinaryTree tree;\n    \n    int numOfQuery; cin >> numOfQuery;\n    string command;\n    int value;\n    rep(i,0,numOfQuery) {\n        cin >> command;\n        if(command[0]=='i') {\n            cin >> value;\n            tree.insert(value);\n        } else {\n            BinaryTree::printInorder(tree.root);\n            cout << endl;\n            BinaryTree::printPreorder(tree.root);\n            cout << endl;\n        }\n    }\n    \n#ifdef OUTPUT2TEXTFILE\n    outputfile.close();\n    cout << \"\\\"\" << OutputFilePath << \"\\\"\" << endl;\n#endif\n    \n    return 0;\n}", "language": "C++", "metadata": {"date": 1506403008, "filename_ext": "cpp", "original_language": "C++", "problem_description_relpath": "problem_descriptions/p02283.html", "problem_id": "p02283", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02283/input.txt", "sample_output_relpath": "derived/input_output/data/p02283/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02283/C++/s219344991.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s219344991", "user_id": "u713060520"}, "prompt_components": {"gold_output": " 1 12 17 20 25 30 88\n 30 12 1 20 17 25 88\n", "input_to_evaluate": "#include <iostream>\n#include <algorithm> // next_permutation\n#include <iomanip>\n#include <cmath>\n#include <vector>\n#include <sstream>\n#include <string>\n#include <cstdio>\n#include <stack>\n#include <queue>\n#include <list>\n#include <numeric> //accumulate\n//#include <unordered_map> //???????????\\??¢??°\n#include <fstream> //ifstream, ofstream\n\n//#define NDEBUG //NDEBUG???#include <cassert>???????????????????????????????????´???assert?????????????????????????????????NDEBUG?????????????????????????????????????????????\n#include <cassert> //assert\n\n\nusing namespace std;\n\n//???????????°??????TEST????????????????????¬???????????????????????????????????¢????????????\n#define TEST //*******************************************************************************************************************************************\n//?????????????????¨??§?????\\????????????????????????????????°?????????????¨???????????????????dout???????????????????????§???????????¬??????????????????????????????????????????\n//??????????????????????????????????????????????????????????§?CPU???????£??????????????????§???TLE?????????????????????????????????????????§????????¨???                           ????????????????????????cerr????????£????????????????????????????????????\n#ifdef TEST\n#define dout cout\n#else\nstringstream dummy; //???????????°??????dout?????????????????????????????????\n#define dout dummy.str(\"\"); dummy.clear(stringstream::goodbit); dummy //dummy?????????????????????????????????????????¨?????¢?????¢???????????????\n//???????????¨??????????????????goodbit?????????????????????????????¨???????????´????????????????????????????????¨?????°?????????????????§???????????????????????????????????? http://d.hatena.ne.jp/linden/20060427/p1\n#endif\n\n//?¨??????????????????????????????????????????????????????´??????OUTPUT2TEXTFILE????????????????????¬???????????????????????????????????¢????????????\n//#define OUTPUT2TEXTFILE //*******************************************************************************************************************************************\n#ifdef OUTPUT2TEXTFILE\n#define dout outputfile //??¨????????????TLE????????§?????????dout?????¨??¨??????????????¢????????????????????????????????????????????§????¨????????????´??????????????£??????????????????????¨?????????????????????????????????????????????§?????????????????????\n//TEST??????????????????????????¨???outputfile??????????????????????????????\n#define OUTPUTFILENAME \"output.txt\"\nofstream outputfile(OUTPUTFILENAME);\n#define OutputFilePath \"/Users/Nag/Documents/Prgm/Test/DerivedData/Test/Build/Products/Debug/output.txt\"\n#endif\n\n#define disp(A) dout << #A << \" = \" << (A) << endl\n#define disP(A) dout << setw(3) << (A) << \" \" // << setw(3) ??????????????\\????????????\n#define rep(i,a,n) for(int (i)=(a); (i)<(n); (i)++)\n\n#define dispAll(A,n) dout << #A << \" = \"; rep(j, 0, (n)) {disP(A[j]);} dout << endl\n\ntypedef pair<int,int> pii;\ntypedef vector<int> vi;\ntypedef unsigned long long ll;\n\nconst int INF = 1e9-1;\n\n\n\nclass Node {\npublic:\n    Node(int value) {\n        v = value;\n        p = NULL;\n        l = NULL;\n        r = NULL;\n    }\n    \n    \n    int v;\n    Node* p;\n    Node* l;\n    Node* r;\n};\n\n\n\nclass BinaryTree {\npublic:\n    BinaryTree() {\n        root = NULL;\n    }\n    \n    \n    Node* root;\n    \n    \n    void insert(int value) {\n        Node* x = new Node(value); //????????????????????????\n        \n        \n        Node* ptr = root; //tree??°?????¨???????????????\n        Node* ptr_parent = NULL;\n        while( ptr!=NULL ) { //NULL????????????????????§?????????????????¨???ptr_parent????????????????????????\n            ptr_parent = ptr;\n            if( x->v < ptr->v ) ptr = ptr->l;\n            else ptr = ptr->r;\n        }\n        \n        \n        if(ptr_parent==NULL) { //tree???????????£?????????????????¨????????????????????????\n            root = x;\n            return;\n        }\n        else if( x->v < ptr_parent->v) {\n            ptr_parent->l = x;\n        }\n        else {\n            ptr_parent->r = x;\n        }\n    }\n    \n    \n    static void printInorder(Node* x) {\n        if(x==NULL) return;\n        \n        printInorder(x->l);\n        cout << \" \" << x->v;\n        printInorder(x->r);\n    }\n    \n    \n    static void printPreorder(Node* x) {\n        if(x==NULL) return;\n        \n        cout << \" \" << x->v;\n        printPreorder(x->l);\n        printPreorder(x->r);\n    }\n    \n    \n};\n\n\nint main(){\n    BinaryTree tree;\n    \n    int numOfQuery; cin >> numOfQuery;\n    string command;\n    int value;\n    rep(i,0,numOfQuery) {\n        cin >> command;\n        if(command[0]=='i') {\n            cin >> value;\n            tree.insert(value);\n        } else {\n            BinaryTree::printInorder(tree.root);\n            cout << endl;\n            BinaryTree::printPreorder(tree.root);\n            cout << endl;\n        }\n    }\n    \n#ifdef OUTPUT2TEXTFILE\n    outputfile.close();\n    cout << \"\\\"\" << OutputFilePath << \"\\\"\" << endl;\n#endif\n    \n    return 0;\n}", "problem_context": "MathJax.Hub.Config({ tex2jax: { inlineMath: [[\"$\",\"$\"], [\"\\\\(\",\"\\\\)\"]], processEscapes: true }});\n\nBinary Search Tree I\n\nSearch trees are data structures that support dynamic set operations including insert, search, delete and so on. Thus a search tree can be used both as a dictionary and as a priority queue.\n\nBinary search tree is one of fundamental search trees. The keys in a binary search tree are always stored in such a way as to satisfy the following binary search tree property:\n\nLet $x$ be a node in a binary search tree. If $y$ is a node in the left subtree of $x$, then $y.key \\leq x.key$. If $y$ is a node in the right subtree of $x$, then $x.key \\leq y.key$.\n\nThe following figure shows an example of the binary search tree.\n\nFor example, keys of nodes which belong to the left sub-tree of the node containing 80 are less than or equal to 80, and keys of nodes which belong to the right sub-tree are more than or equal to 80. The binary search tree property allows us to print out all the keys in the tree in sorted order by an inorder tree walk.\n\nA binary search tree should be implemented in such a way that the binary search tree property continues to hold after modifications by insertions and deletions. A binary search tree can be represented by a linked data structure in which each node is an object. In addition to a key field and satellite data, each node contains fields left, right, and p that point to the nodes corresponding to its left child, its right child, and its parent, respectively.\n\nTo insert a new value $v$ into a binary search tree $T$, we can use the procedure insert as shown in the following pseudo code. The insert procedure is passed a node $z$ for which $z.key = v$, $z.left = NIL$, and $z.right = NIL$. The procedure modifies $T$ and some of the fields of $z$ in such a way that $z$ is inserted into an appropriate position in the tree.\n\n1 insert(T, z)\n2 y = NIL // parent of x\n3 x = 'the root of T'\n4 while x ≠ NIL\n5 y = x // set the parent\n6 if z.key < x.key\n7 x = x.left // move to the left child\n8 else\n9 x = x.right // move to the right child\n10 z.p = y\n11\n12 if y == NIL // T is empty\n13 'the root of T' = z\n14 else if z.key < y.key\n15 y.left = z // z is the left child of y\n16 else\n17 y.right = z // z is the right child of y\n\nWrite a program which performs the following operations to a binary search tree $T$.\n\ninsert $k$: Insert a node containing $k$ as key into $T$.\n\nprint: Print the keys of the binary search tree by inorder tree walk and preorder tree walk respectively.\n\nYou should use the above pseudo code to implement the insert operation. $T$ is empty at the initial state.\n\nInput\n\nIn the first line, the number of operations $m$ is given. In the following $m$ lines, operations represented by insert $k$ or print are given.\n\nOutput\n\nFor each print operation, print a list of keys obtained by inorder tree walk and preorder tree walk in a line respectively. Put a space character before each key.\n\nConstraints\n\nThe number of operations $\\leq 500,000$\n\nThe number of print operations $\\leq 10$.\n\n$-2,000,000,000 \\leq key \\leq 2,000,000,000$\n\nThe height of the binary tree does not exceed 100 if you employ the above pseudo code.\n\nThe keys in the binary search tree are all different.\n\nSample Input 1\n\n8\ninsert 30\ninsert 88\ninsert 12\ninsert 1\ninsert 20\ninsert 17\ninsert 25\nprint\n\nSample Output 1\n\n1 12 17 20 25 30 88\n30 12 1 20 17 25 88\n\nReference\n\nIntroduction to Algorithms, Thomas H. Cormen, Charles E. Leiserson, Ronald L. Rivest, and Clifford Stein. The MIT Press.", "sample_input": "8\ninsert 30\ninsert 88\ninsert 12\ninsert 1\ninsert 20\ninsert 17\ninsert 25\nprint\n"}, "reference_outputs": [" 1 12 17 20 25 30 88\n 30 12 1 20 17 25 88\n"], "source_document_id": "p02283", "source_text": "MathJax.Hub.Config({ tex2jax: { inlineMath: [[\"$\",\"$\"], [\"\\\\(\",\"\\\\)\"]], processEscapes: true }});\n\nBinary Search Tree I\n\nSearch trees are data structures that support dynamic set operations including insert, search, delete and so on. Thus a search tree can be used both as a dictionary and as a priority queue.\n\nBinary search tree is one of fundamental search trees. The keys in a binary search tree are always stored in such a way as to satisfy the following binary search tree property:\n\nLet $x$ be a node in a binary search tree. If $y$ is a node in the left subtree of $x$, then $y.key \\leq x.key$. If $y$ is a node in the right subtree of $x$, then $x.key \\leq y.key$.\n\nThe following figure shows an example of the binary search tree.\n\nFor example, keys of nodes which belong to the left sub-tree of the node containing 80 are less than or equal to 80, and keys of nodes which belong to the right sub-tree are more than or equal to 80. The binary search tree property allows us to print out all the keys in the tree in sorted order by an inorder tree walk.\n\nA binary search tree should be implemented in such a way that the binary search tree property continues to hold after modifications by insertions and deletions. A binary search tree can be represented by a linked data structure in which each node is an object. In addition to a key field and satellite data, each node contains fields left, right, and p that point to the nodes corresponding to its left child, its right child, and its parent, respectively.\n\nTo insert a new value $v$ into a binary search tree $T$, we can use the procedure insert as shown in the following pseudo code. The insert procedure is passed a node $z$ for which $z.key = v$, $z.left = NIL$, and $z.right = NIL$. The procedure modifies $T$ and some of the fields of $z$ in such a way that $z$ is inserted into an appropriate position in the tree.\n\n1 insert(T, z)\n2 y = NIL // parent of x\n3 x = 'the root of T'\n4 while x ≠ NIL\n5 y = x // set the parent\n6 if z.key < x.key\n7 x = x.left // move to the left child\n8 else\n9 x = x.right // move to the right child\n10 z.p = y\n11\n12 if y == NIL // T is empty\n13 'the root of T' = z\n14 else if z.key < y.key\n15 y.left = z // z is the left child of y\n16 else\n17 y.right = z // z is the right child of y\n\nWrite a program which performs the following operations to a binary search tree $T$.\n\ninsert $k$: Insert a node containing $k$ as key into $T$.\n\nprint: Print the keys of the binary search tree by inorder tree walk and preorder tree walk respectively.\n\nYou should use the above pseudo code to implement the insert operation. $T$ is empty at the initial state.\n\nInput\n\nIn the first line, the number of operations $m$ is given. In the following $m$ lines, operations represented by insert $k$ or print are given.\n\nOutput\n\nFor each print operation, print a list of keys obtained by inorder tree walk and preorder tree walk in a line respectively. Put a space character before each key.\n\nConstraints\n\nThe number of operations $\\leq 500,000$\n\nThe number of print operations $\\leq 10$.\n\n$-2,000,000,000 \\leq key \\leq 2,000,000,000$\n\nThe height of the binary tree does not exceed 100 if you employ the above pseudo code.\n\nThe keys in the binary search tree are all different.\n\nSample Input 1\n\n8\ninsert 30\ninsert 88\ninsert 12\ninsert 1\ninsert 20\ninsert 17\ninsert 25\nprint\n\nSample Output 1\n\n1 12 17 20 25 30 88\n30 12 1 20 17 25 88\n\nReference\n\nIntroduction to Algorithms, Thomas H. Cormen, Charles E. Leiserson, Ronald L. Rivest, and Clifford Stein. The MIT Press.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 5003, "cpu_time_ms": 510, "memory_kb": 26636}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s371486432", "group_id": "codeNet:p02289", "input_text": "#include<iostream>\n#include<cstdio>\n#define MAX 2000000+5\nusing namespace std;\nint heap[MAX];\nint num;\nvoid maxheapify(int i){\n\tint largest;\n\tint left=i*2;int right=i*2+1;\n\tif(left<=num&&heap[left]>heap[i]){\n\t\tlargest=left;\n\t}else{\n\t\tlargest=i;\n\t}\n\tif(right<=num&&heap[largest]<heap[right]){\n\t\tlargest=right;\n\t}\n\tif(largest!=i){\n\t\tswap(heap[largest],heap[i]);\n\t\tmaxheapify(largest);\n\t}\n\treturn;\n}\nvoid insert(int i){\nnum++;\nheap[num]=i;\nint t=num;\nwhile(t>1&&heap[t/2]<heap[t]){\n\tswap(heap[t],heap[t/2]);\n\tt=t/2;\n}\nreturn;\n}\nvoid extract(){\n\tcout<<heap[1]<<endl;\n\theap[1]=heap[num];num--;\n\tmaxheapify(1);\n\treturn;\n}\nint main(){\n\tchar s[10];\n\tnum=0;\n\twhile(scanf(\"%s\",&s)){\n\t\tif(s[0]=='i') {\n\t\t\tint i;scanf(\"%d\",&i);insert(i);\n\t\t}else if(s[0]=='e'&&s[1]=='x'){\n\t\t\textract();\n\t\t}else break;\n\t\t\t\n\t\t}\n\t}\n\n", "language": "C++", "metadata": {"date": 1585471621, "filename_ext": "cpp", "original_language": "C++", "problem_description_relpath": "problem_descriptions/p02289.html", "problem_id": "p02289", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02289/input.txt", "sample_output_relpath": "derived/input_output/data/p02289/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02289/C++/s371486432.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s371486432", "user_id": "u682174609"}, "prompt_components": {"gold_output": "8\n10\n11\n2\n", "input_to_evaluate": "#include<iostream>\n#include<cstdio>\n#define MAX 2000000+5\nusing namespace std;\nint heap[MAX];\nint num;\nvoid maxheapify(int i){\n\tint largest;\n\tint left=i*2;int right=i*2+1;\n\tif(left<=num&&heap[left]>heap[i]){\n\t\tlargest=left;\n\t}else{\n\t\tlargest=i;\n\t}\n\tif(right<=num&&heap[largest]<heap[right]){\n\t\tlargest=right;\n\t}\n\tif(largest!=i){\n\t\tswap(heap[largest],heap[i]);\n\t\tmaxheapify(largest);\n\t}\n\treturn;\n}\nvoid insert(int i){\nnum++;\nheap[num]=i;\nint t=num;\nwhile(t>1&&heap[t/2]<heap[t]){\n\tswap(heap[t],heap[t/2]);\n\tt=t/2;\n}\nreturn;\n}\nvoid extract(){\n\tcout<<heap[1]<<endl;\n\theap[1]=heap[num];num--;\n\tmaxheapify(1);\n\treturn;\n}\nint main(){\n\tchar s[10];\n\tnum=0;\n\twhile(scanf(\"%s\",&s)){\n\t\tif(s[0]=='i') {\n\t\t\tint i;scanf(\"%d\",&i);insert(i);\n\t\t}else if(s[0]=='e'&&s[1]=='x'){\n\t\t\textract();\n\t\t}else break;\n\t\t\t\n\t\t}\n\t}\n\n", "problem_context": "MathJax.Hub.Config({ tex2jax: { inlineMath: [[\"$\",\"$\"], [\"\\\\(\",\"\\\\)\"]], processEscapes: true }});\n\nPriority Queue\n\nA priority queue is a data structure which maintains a set $S$ of elements, each of with an associated value (key), and supports the following operations:\n\n$insert(S, k)$: insert an element $k$ into the set $S$\n\n$extractMax(S)$: remove and return the element of $S$ with the largest key\n\nWrite a program which performs the $insert(S, k)$ and $extractMax(S)$ operations to a priority queue $S$.\nThe priority queue manages a set of integers, which are also keys for the priority.\n\nInput\n\nMultiple operations to the priority queue $S$ are given. Each operation is given by \"insert $k$\", \"extract\" or \"end\" in a line. Here, $k$ represents an integer element to be inserted to the priority queue.\n\nThe input ends with \"end\" operation.\n\nOutput\n\nFor each \"extract\" operation, print the element extracted from the priority queue $S$ in a line.\n\nConstraints\n\nThe number of operations $\\leq 2,000,000$\n\n$0 \\leq k \\leq 2,000,000,000$\n\nSample Input 1\n\ninsert 8\ninsert 2\nextract\ninsert 10\nextract\ninsert 11\nextract\nextract\nend\n\nSample Output 1\n\n8\n10\n11\n2", "sample_input": "insert 8\ninsert 2\nextract\ninsert 10\nextract\ninsert 11\nextract\nextract\nend\n"}, "reference_outputs": ["8\n10\n11\n2\n"], "source_document_id": "p02289", "source_text": "MathJax.Hub.Config({ tex2jax: { inlineMath: [[\"$\",\"$\"], [\"\\\\(\",\"\\\\)\"]], processEscapes: true }});\n\nPriority Queue\n\nA priority queue is a data structure which maintains a set $S$ of elements, each of with an associated value (key), and supports the following operations:\n\n$insert(S, k)$: insert an element $k$ into the set $S$\n\n$extractMax(S)$: remove and return the element of $S$ with the largest key\n\nWrite a program which performs the $insert(S, k)$ and $extractMax(S)$ operations to a priority queue $S$.\nThe priority queue manages a set of integers, which are also keys for the priority.\n\nInput\n\nMultiple operations to the priority queue $S$ are given. Each operation is given by \"insert $k$\", \"extract\" or \"end\" in a line. Here, $k$ represents an integer element to be inserted to the priority queue.\n\nThe input ends with \"end\" operation.\n\nOutput\n\nFor each \"extract\" operation, print the element extracted from the priority queue $S$ in a line.\n\nConstraints\n\nThe number of operations $\\leq 2,000,000$\n\n$0 \\leq k \\leq 2,000,000,000$\n\nSample Input 1\n\ninsert 8\ninsert 2\nextract\ninsert 10\nextract\ninsert 11\nextract\nextract\nend\n\nSample Output 1\n\n8\n10\n11\n2", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 801, "cpu_time_ms": 750, "memory_kb": 6956}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s002643060", "group_id": "codeNet:p02289", "input_text": "#include <iostream>\n#include <queue>\n#include <string>\nusing namespace std;\nint main()\n{\n\tpriority_queue<int> Q;\n\tstring S;\n\twhile(true)\n\t{\n\t\tcin >> S;\n\t\tif (S == \"end\")\n\t\t{\n\t\t\treturn 0;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tif (S == \"insert\")\n\t\t\t{\n\t\t\t\tint a;\n\t\t\t\tcin >> a;\n\t\t\t\tQ.push(a);\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tcout << Q.top() << endl;\n\t\t\t\tQ.pop();\n\t\t\t}\n\t\t}\n\t}\n}\n", "language": "C++", "metadata": {"date": 1559874161, "filename_ext": "cpp", "original_language": "C++", "problem_description_relpath": "problem_descriptions/p02289.html", "problem_id": "p02289", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02289/input.txt", "sample_output_relpath": "derived/input_output/data/p02289/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02289/C++/s002643060.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s002643060", "user_id": "u202003995"}, "prompt_components": {"gold_output": "8\n10\n11\n2\n", "input_to_evaluate": "#include <iostream>\n#include <queue>\n#include <string>\nusing namespace std;\nint main()\n{\n\tpriority_queue<int> Q;\n\tstring S;\n\twhile(true)\n\t{\n\t\tcin >> S;\n\t\tif (S == \"end\")\n\t\t{\n\t\t\treturn 0;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tif (S == \"insert\")\n\t\t\t{\n\t\t\t\tint a;\n\t\t\t\tcin >> a;\n\t\t\t\tQ.push(a);\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tcout << Q.top() << endl;\n\t\t\t\tQ.pop();\n\t\t\t}\n\t\t}\n\t}\n}\n", "problem_context": "MathJax.Hub.Config({ tex2jax: { inlineMath: [[\"$\",\"$\"], [\"\\\\(\",\"\\\\)\"]], processEscapes: true }});\n\nPriority Queue\n\nA priority queue is a data structure which maintains a set $S$ of elements, each of with an associated value (key), and supports the following operations:\n\n$insert(S, k)$: insert an element $k$ into the set $S$\n\n$extractMax(S)$: remove and return the element of $S$ with the largest key\n\nWrite a program which performs the $insert(S, k)$ and $extractMax(S)$ operations to a priority queue $S$.\nThe priority queue manages a set of integers, which are also keys for the priority.\n\nInput\n\nMultiple operations to the priority queue $S$ are given. Each operation is given by \"insert $k$\", \"extract\" or \"end\" in a line. Here, $k$ represents an integer element to be inserted to the priority queue.\n\nThe input ends with \"end\" operation.\n\nOutput\n\nFor each \"extract\" operation, print the element extracted from the priority queue $S$ in a line.\n\nConstraints\n\nThe number of operations $\\leq 2,000,000$\n\n$0 \\leq k \\leq 2,000,000,000$\n\nSample Input 1\n\ninsert 8\ninsert 2\nextract\ninsert 10\nextract\ninsert 11\nextract\nextract\nend\n\nSample Output 1\n\n8\n10\n11\n2", "sample_input": "insert 8\ninsert 2\nextract\ninsert 10\nextract\ninsert 11\nextract\nextract\nend\n"}, "reference_outputs": ["8\n10\n11\n2\n"], "source_document_id": "p02289", "source_text": "MathJax.Hub.Config({ tex2jax: { inlineMath: [[\"$\",\"$\"], [\"\\\\(\",\"\\\\)\"]], processEscapes: true }});\n\nPriority Queue\n\nA priority queue is a data structure which maintains a set $S$ of elements, each of with an associated value (key), and supports the following operations:\n\n$insert(S, k)$: insert an element $k$ into the set $S$\n\n$extractMax(S)$: remove and return the element of $S$ with the largest key\n\nWrite a program which performs the $insert(S, k)$ and $extractMax(S)$ operations to a priority queue $S$.\nThe priority queue manages a set of integers, which are also keys for the priority.\n\nInput\n\nMultiple operations to the priority queue $S$ are given. Each operation is given by \"insert $k$\", \"extract\" or \"end\" in a line. Here, $k$ represents an integer element to be inserted to the priority queue.\n\nThe input ends with \"end\" operation.\n\nOutput\n\nFor each \"extract\" operation, print the element extracted from the priority queue $S$ in a line.\n\nConstraints\n\nThe number of operations $\\leq 2,000,000$\n\n$0 \\leq k \\leq 2,000,000,000$\n\nSample Input 1\n\ninsert 8\ninsert 2\nextract\ninsert 10\nextract\ninsert 11\nextract\nextract\nend\n\nSample Output 1\n\n8\n10\n11\n2", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 343, "cpu_time_ms": 1290, "memory_kb": 7044}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s352316240", "group_id": "codeNet:p02328", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n#define FOR(i,a,b) for(int i=(a);i<(b);++i)\n#define rep(i,n)   FOR(i,0,n)\n#define pb push_back\n#define mp make_pair\ntypedef long long ll;\ntypedef pair<int,int> pint;\n\nstruct rect{int ht;int pos;};\nint tb[100001];\nint area_rect(int size,int buf[]){\n    stack<rect> st;\n    int mx=0;\n    buf[size]=0;\n    rep(i,size+1){\n        rect r;\n        r.ht=buf[i];\n        r.pos=i;\n        if(st.empty()) st.push(r);\n        else{\n            if(st.top().ht<r.ht) st.push(r);\n            else if (st.top().ht>r.ht){\n                int ti=i;\n                while(!st.empty()&&st.top().ht>=r.ht){\n                    rect pre=st.top();st.pop();\n                    int area=pre.ht*(i-pre.pos);\n                    mx=max(mx,area);\n                    ti=pre.pos;\n                }\n                r.pos = ti;\n                st.push(r);\n            }\n        }\n    }\n    return mx;\n}\nint main(){\n    int n;\n    cin>>n;\n    rep(i,n) cin>>tb[i];\n    int mx=area_rect(n,tb);\n    cout<<mx<<endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1512828209, "filename_ext": "cpp", "original_language": "C++", "problem_description_relpath": "problem_descriptions/p02328.html", "problem_id": "p02328", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02328/input.txt", "sample_output_relpath": "derived/input_output/data/p02328/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02328/C++/s352316240.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s352316240", "user_id": "u268155858"}, "prompt_components": {"gold_output": "12\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n#define FOR(i,a,b) for(int i=(a);i<(b);++i)\n#define rep(i,n)   FOR(i,0,n)\n#define pb push_back\n#define mp make_pair\ntypedef long long ll;\ntypedef pair<int,int> pint;\n\nstruct rect{int ht;int pos;};\nint tb[100001];\nint area_rect(int size,int buf[]){\n    stack<rect> st;\n    int mx=0;\n    buf[size]=0;\n    rep(i,size+1){\n        rect r;\n        r.ht=buf[i];\n        r.pos=i;\n        if(st.empty()) st.push(r);\n        else{\n            if(st.top().ht<r.ht) st.push(r);\n            else if (st.top().ht>r.ht){\n                int ti=i;\n                while(!st.empty()&&st.top().ht>=r.ht){\n                    rect pre=st.top();st.pop();\n                    int area=pre.ht*(i-pre.pos);\n                    mx=max(mx,area);\n                    ti=pre.pos;\n                }\n                r.pos = ti;\n                st.push(r);\n            }\n        }\n    }\n    return mx;\n}\nint main(){\n    int n;\n    cin>>n;\n    rep(i,n) cin>>tb[i];\n    int mx=area_rect(n,tb);\n    cout<<mx<<endl;\n    return 0;\n}", "problem_context": "MathJax.Hub.Config({ tex2jax: { inlineMath: [[\"$\",\"$\"], [\"\\\\(\",\"\\\\)\"]], processEscapes: true }});\n\nLargest Rectangle in a Histogram\n\nA histogram is made of a number of contiguous bars, which have same width.\n\nFor a given histogram with $N$ bars which have a width of 1 and a height of $h_i$ = $h_1, h_2, ... , h_N$ respectively, find the area of the largest rectangular area.\n\nConstraints\n\n$1 \\leq N \\leq 10^5$\n\n$0 \\leq h_i \\leq 10^9$\n\nInput\n\nThe input is given in the following format.\n\n$N$\n\n$h_1$ $h_2$ ... $h_N$\n\nOutput\n\nPrint the area of the largest rectangle.\n\nSample Input 1\n\n8\n2 1 3 5 3 4 2 1\n\nSample Output 1\n\n12\n\nSample Input 2\n\n3\n2 0 1\n\nSample Output 2\n\n2", "sample_input": "8\n2 1 3 5 3 4 2 1\n"}, "reference_outputs": ["12\n"], "source_document_id": "p02328", "source_text": "MathJax.Hub.Config({ tex2jax: { inlineMath: [[\"$\",\"$\"], [\"\\\\(\",\"\\\\)\"]], processEscapes: true }});\n\nLargest Rectangle in a Histogram\n\nA histogram is made of a number of contiguous bars, which have same width.\n\nFor a given histogram with $N$ bars which have a width of 1 and a height of $h_i$ = $h_1, h_2, ... , h_N$ respectively, find the area of the largest rectangular area.\n\nConstraints\n\n$1 \\leq N \\leq 10^5$\n\n$0 \\leq h_i \\leq 10^9$\n\nInput\n\nThe input is given in the following format.\n\n$N$\n\n$h_1$ $h_2$ ... $h_N$\n\nOutput\n\nPrint the area of the largest rectangle.\n\nSample Input 1\n\n8\n2 1 3 5 3 4 2 1\n\nSample Output 1\n\n12\n\nSample Input 2\n\n3\n2 0 1\n\nSample Output 2\n\n2", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1043, "cpu_time_ms": 20, "memory_kb": 4136}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s860541717", "group_id": "codeNet:p02351", "input_text": "#include <iostream>\n#include <vector>\n#include <string>\n#include <stack>\n#include <map>\n#include <algorithm>\n#include <iomanip>\n#include <cmath>\n#include <queue>\n#include <climits>\nusing namespace std;\n\n\n#define MOD 1000000007\nusing ll = long long;\n\nbool operator<(const pair<int, int>& a, const pair<int, int>& b) {\n\tif (a.first == b.first) {\n\t\treturn a.second < b.second;\n\t}\n\treturn a.first < b.first;\n}\n\nconst int INF = (1LL << 31) - 1;\nconst int sqrtN = 512;\n\nstruct SqrtDecomposition {\n\tint N, K;\n\tvector<ll> data; //内部の値, どのタイミングで変更したか\n\tvector<ll> bucketSum;\n\tvector<ll> bucketAdd;\n\tSqrtDecomposition(int n) : N(n) {\n\t\tK = (N + sqrtN - 1) / sqrtN;\n\t\tdata.assign(K*sqrtN, 0);\n\t\tbucketSum.assign(K, 0);\n\t\tbucketAdd.assign(K, 0);\n\t}\n\n\t// [s, t)\n\tvoid add(ll s, ll t, ll x) {\n\t\tfor (int k = 0; k < K; ++k) {\n\t\t\tll l = k * sqrtN, r = (k + 1) *sqrtN;\n\t\t\tif (r <= s || t <= l) continue;\n\t\t\tif (s <= l && r <= t) {\n\t\t\t\tbucketAdd[k] += x;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tfor (int i = max(s, l); i < min(t, r); ++i) {\n\t\t\t\t\tdata[i] += x;\n\t\t\t\t\tbucketSum[k] += x;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\t//[x, y)\n\tll getSum(ll s, ll t) {\n\t\tll sum = 0;\n\t\tfor (int k = 0; k < K; ++k) {\n\t\t\tll l = k * sqrtN, r = (k + 1)*sqrtN;\n\t\t\tif (r <= s || t <= l) continue;\n\t\t\tif (s <= l && r <= t) {\n\t\t\t\tsum += bucketSum[k] + bucketAdd[k] * sqrtN;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tfor (int i = max(s, l); i < min(t, r); ++i) {\n\t\t\t\t\tsum += data[i] + bucketAdd[k];\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\treturn sum;\n\t}\n};\nint main() {\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\t\n\tll n, q; cin >> n >> q;\n\tSqrtDecomposition sd(n);\n\n\tfor (int i = 0; i < q; ++i) {\n\t\tll com; cin >> com;\n\t\tif (com == 0) {\n\t\t\tll s, t, x; cin >> s >> t >> x;\n\t\t\tsd.add(s, t+1, x);\n\t\t}\n\t\telse {\n\t\t\tll x, y; cin >> x>> y;\n\t\t\tcout << sd.getSum(x, y+1) << endl;\n\t\t}\n\t}\n\tint a; cin >> a;\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1554317979, "filename_ext": "cpp", "original_language": "C++11", "problem_description_relpath": "problem_descriptions/p02351.html", "problem_id": "p02351", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02351/input.txt", "sample_output_relpath": "derived/input_output/data/p02351/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02351/C++/s860541717.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s860541717", "user_id": "u578258337"}, "prompt_components": {"gold_output": "4\n8\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\n#include <string>\n#include <stack>\n#include <map>\n#include <algorithm>\n#include <iomanip>\n#include <cmath>\n#include <queue>\n#include <climits>\nusing namespace std;\n\n\n#define MOD 1000000007\nusing ll = long long;\n\nbool operator<(const pair<int, int>& a, const pair<int, int>& b) {\n\tif (a.first == b.first) {\n\t\treturn a.second < b.second;\n\t}\n\treturn a.first < b.first;\n}\n\nconst int INF = (1LL << 31) - 1;\nconst int sqrtN = 512;\n\nstruct SqrtDecomposition {\n\tint N, K;\n\tvector<ll> data; //内部の値, どのタイミングで変更したか\n\tvector<ll> bucketSum;\n\tvector<ll> bucketAdd;\n\tSqrtDecomposition(int n) : N(n) {\n\t\tK = (N + sqrtN - 1) / sqrtN;\n\t\tdata.assign(K*sqrtN, 0);\n\t\tbucketSum.assign(K, 0);\n\t\tbucketAdd.assign(K, 0);\n\t}\n\n\t// [s, t)\n\tvoid add(ll s, ll t, ll x) {\n\t\tfor (int k = 0; k < K; ++k) {\n\t\t\tll l = k * sqrtN, r = (k + 1) *sqrtN;\n\t\t\tif (r <= s || t <= l) continue;\n\t\t\tif (s <= l && r <= t) {\n\t\t\t\tbucketAdd[k] += x;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tfor (int i = max(s, l); i < min(t, r); ++i) {\n\t\t\t\t\tdata[i] += x;\n\t\t\t\t\tbucketSum[k] += x;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\t//[x, y)\n\tll getSum(ll s, ll t) {\n\t\tll sum = 0;\n\t\tfor (int k = 0; k < K; ++k) {\n\t\t\tll l = k * sqrtN, r = (k + 1)*sqrtN;\n\t\t\tif (r <= s || t <= l) continue;\n\t\t\tif (s <= l && r <= t) {\n\t\t\t\tsum += bucketSum[k] + bucketAdd[k] * sqrtN;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tfor (int i = max(s, l); i < min(t, r); ++i) {\n\t\t\t\t\tsum += data[i] + bucketAdd[k];\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\treturn sum;\n\t}\n};\nint main() {\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\t\n\tll n, q; cin >> n >> q;\n\tSqrtDecomposition sd(n);\n\n\tfor (int i = 0; i < q; ++i) {\n\t\tll com; cin >> com;\n\t\tif (com == 0) {\n\t\t\tll s, t, x; cin >> s >> t >> x;\n\t\t\tsd.add(s, t+1, x);\n\t\t}\n\t\telse {\n\t\t\tll x, y; cin >> x>> y;\n\t\t\tcout << sd.getSum(x, y+1) << endl;\n\t\t}\n\t}\n\tint a; cin >> a;\n\treturn 0;\n}\n", "problem_context": "RSQ and RAQ\n\nWrite a program which manipulates a sequence A = {a1, a2, . . . , an} with the following operations:\n\nadd(s, t, x): add x to as, as+1, ..., at.\n\ngetSum(s, t): report the sum of as, as+1, ..., at.\n\nNote that the initial values of ai (i = 1, 2, . . . , n) are 0.\n\nInput\n\nn q\nquery1\nquery2\n:\nqueryq\n\nIn the first line, n (the number of elements in A) and q (the number of queries) are given. Then, ith query queryi is given in the following format:\n\n0 s t x\n\nor\n\n1 s t\n\nThe first digit represents the type of the query. '0' denotes add(s, t, x) and '1' denotes getSum(s, t).\n\nOutput\n\nFor each getSum operation, print the sum;\n\nConstraints\n\n1 ≤ n ≤ 100000\n\n1 ≤ q ≤ 100000\n\n1 ≤ s ≤ t ≤ n\n\n0 ≤ x < 1000\n\nSample Input 1\n\n3 5\n0 1 2 1\n0 2 3 2\n0 3 3 3\n1 1 2\n1 2 3\n\nSample Output 1\n\n4\n8\n\nSample Input 2\n\n4 3\n1 1 4\n0 1 4 1\n1 1 4\n\nSample Output 2\n\n0\n4", "sample_input": "3 5\n0 1 2 1\n0 2 3 2\n0 3 3 3\n1 1 2\n1 2 3\n"}, "reference_outputs": ["4\n8\n"], "source_document_id": "p02351", "source_text": "RSQ and RAQ\n\nWrite a program which manipulates a sequence A = {a1, a2, . . . , an} with the following operations:\n\nadd(s, t, x): add x to as, as+1, ..., at.\n\ngetSum(s, t): report the sum of as, as+1, ..., at.\n\nNote that the initial values of ai (i = 1, 2, . . . , n) are 0.\n\nInput\n\nn q\nquery1\nquery2\n:\nqueryq\n\nIn the first line, n (the number of elements in A) and q (the number of queries) are given. Then, ith query queryi is given in the following format:\n\n0 s t x\n\nor\n\n1 s t\n\nThe first digit represents the type of the query. '0' denotes add(s, t, x) and '1' denotes getSum(s, t).\n\nOutput\n\nFor each getSum operation, print the sum;\n\nConstraints\n\n1 ≤ n ≤ 100000\n\n1 ≤ q ≤ 100000\n\n1 ≤ s ≤ t ≤ n\n\n0 ≤ x < 1000\n\nSample Input 1\n\n3 5\n0 1 2 1\n0 2 3 2\n0 3 3 3\n1 1 2\n1 2 3\n\nSample Output 1\n\n4\n8\n\nSample Input 2\n\n4 3\n1 1 4\n0 1 4 1\n1 1 4\n\nSample Output 2\n\n0\n4", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1817, "cpu_time_ms": 150, "memory_kb": 3608}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s806969933", "group_id": "codeNet:p02353", "input_text": "// clang-format off\n#include <bits/stdc++.h>\nusing namespace std;\n#define int long long\n#define main signed main()\n#define loop(i, a, n) for (int i = (a); i < (n); i++)\n#define rep(i, n) loop(i, 0, n)\n#define all(v) (v).begin(), (v).end()\n#define rall(v) (v).rbegin(), (v).rend()\n#define prec(n) fixed << setprecision(n)\nconstexpr int INF = sizeof(int) == sizeof(long long) ? 1000000000000000000LL : 1000000000;\nconstexpr int MOD = 1000000007;\nconstexpr double PI = 3.14159265358979;\ntemplate<typename A, typename B> bool cmin(A &a, const B &b) { return a > b ? (a = b, true) : false; }\ntemplate<typename A, typename B> bool cmax(A &a, const B &b) { return a < b ? (a = b, true) : false; }\nbool odd(const int &n) { return n & 1; }\nbool even(const int &n) { return ~n & 1; }\ntemplate<typename T = int> T in() { T x; cin >> x; return x; }\ntemplate<typename T = int> T in(T &&x) { T z(forward<T>(x)); cin >> z; return z; }\ntemplate<typename T> istream &operator>>(istream &is, vector<T> &v) { for (T &x : v) is >> x; return is; }\ntemplate<typename A, typename B> istream &operator>>(istream &is, pair<A, B> &p) { return is >> p.first >> p.second; }\ntemplate<typename T> ostream &operator<<(ostream &os, const vector<vector<T>> &v) { int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? \"\" : \"\\n\"); return os; }\ntemplate<typename T> ostream &operator<<(ostream &os, const vector<T> &v) { int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? \"\" : \" \"); return os; }\ntemplate<typename A, typename B> ostream &operator<<(ostream &os, const pair<A, B> &p) { return os << p.first << ' ' << p.second; }\ntemplate<typename Head, typename Value> auto vectors(const Head &head, const Value &v) { return vector<Value>(head, v); }\ntemplate<typename Head, typename... Tail> auto vectors(Head x, Tail... tail) { auto inner = vectors(tail...); return vector<decltype(inner)>(x, inner); }\n// clang-format on\n\ntemplate<typename LSTTrait> class LazySegTree {\n  using FoldMonoid = typename LSTTrait::FoldMonoid;\n  using ActionMonoid = typename LSTTrait::ActionMonoid;\n  using T = typename FoldMonoid::value_type;\n  using Q = typename ActionMonoid::value_type;\n\n  LSTTrait lstTrait; // apply :: (T, Q) -> T, pow :: (Q, int) -> Q\n  FoldMonoid foldM;\n  ActionMonoid actionM;\n  int size = 1;\n  vector<T> tree; // 1-indexed\n  vector<Q> lazy; // 1-indexed\n\n  void push(int i) {\n    stack<pair<int, int>> s;\n    for (int d = 1; i /= 2; d *= 2) s.emplace(i, d);\n    for (int x, d; s.size(); s.pop()) {\n      tie(x, d) = s.top();\n      update(x * 2, lazy[x], d);\n      update(x * 2 + 1, lazy[x], d);\n      lazy[x] = actionM.id();\n    }\n  }\n\n  void update(const int &i, const Q &x, const int &d) {\n    tree[i] = lstTrait.apply(tree[i], lstTrait.pow(x, d));\n    if (i < size) lazy[i] = actionM(lazy[i], x);\n  }\n\n  void build(int i) {\n    for (int d = 2; i /= 2; d *= 2) tree[i] = lstTrait.apply(foldM(tree[i * 2], tree[i * 2 + 1]), lstTrait.pow(lazy[i], d));\n  }\n\npublic:\n  LazySegTree(const int &n = 0) {\n    while (size < n) size *= 2;\n    tree.assign(size * 2, foldM.id());\n    lazy.assign(size, actionM.id());\n  }\n\n  LazySegTree(const int &n, const T &x) {\n    while (size < n) size *= 2;\n    tree.assign(size * 2, x);\n    lazy.assign(size, actionM.id());\n    for (int i = size - 1; i >= 1; i--) tree[i] = foldM(tree[i * 2], tree[i * 2 + 1]);\n  }\n\n  template<typename InputIterator> LazySegTree(InputIterator first, InputIterator last) {\n    int n = distance(first, last);\n    while (size < n) size *= 2;\n    tree.resize(size * 2, foldM.id());\n    lazy.assign(size, actionM.id());\n    copy(first, last, tree.begin() + size);\n    for (int i = size - 1; i >= 1; i--) tree[i] = foldM(tree[i * 2], tree[i * 2 + 1]);\n  }\n\n  void act(int l, int r, const Q &x) { // [l, r) += x\n    int l0 = l += size, r0 = r += size;\n    push(l0), push(r0 - 1);\n    for (int d = 1; l < r; l /= 2, r /= 2, d *= 2) {\n      if (l & 1) update(l++, x, d);\n      if (r & 1) update(--r, x, d);\n    }\n    build(l0);\n    build(r0 - 1);\n  }\n\n  T fold(int l, int r) { // [l, r)\n    T accl = foldM.id(), accr = foldM.id();\n    for (push(l += size), push((r += size) - 1); l < r; l /= 2, r /= 2) {\n      if (l & 1) accl = foldM(accl, tree[l++]);\n      if (r & 1) accr = foldM(tree[--r], accr);\n    }\n    return foldM(accl, accr);\n  }\n};\n\ntemplate<typename T> struct sumMonoid {\n  using value_type = T;\n  value_type id() { return 0; }\n  value_type operator()(const value_type &a, const value_type &b) { return a + b; }\n};\n\ntemplate<typename T> struct updateMonoid {\n  using value_type = pair<bool, T>;\n  value_type id() { return {false, T()}; }\n  value_type operator()(const value_type &a, const value_type &b) { return b.first ? b : a; }\n};\n\ntemplate<typename T> struct RSQ_RUQ_Trait {\n  using FoldMonoid = sumMonoid<T>;\n  using ActionMonoid = updateMonoid<T>;\n  typename FoldMonoid::value_type apply(typename FoldMonoid::value_type t, typename ActionMonoid::value_type q) { return q.first ? q.second : t; }\n  typename ActionMonoid::value_type pow(typename ActionMonoid::value_type q, const int &d) { return {q.first, q.second * d}; }\n};\n\nmain {\n  int n, q;\n  cin >> n >> q;\n  LazySegTree<RSQ_RUQ_Trait<int>> lst(n, 0);\n  while (q--) {\n    if (in()) {\n      int s, t;\n      cin >> s >> t;\n      cout << lst.fold(s, t + 1) << endl;\n    } else {\n      int s, t, x;\n      cin >> s >> t >> x;\n      lst.act(s, t + 1, {true, x});\n    }\n  }\n}\n\n", "language": "C++", "metadata": {"date": 1527795299, "filename_ext": "cpp", "original_language": "C++14", "problem_description_relpath": "problem_descriptions/p02353.html", "problem_id": "p02353", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02353/input.txt", "sample_output_relpath": "derived/input_output/data/p02353/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02353/C++/s806969933.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s806969933", "user_id": "u449960815"}, "prompt_components": {"gold_output": "-5\n1\n6\n8\n", "input_to_evaluate": "// clang-format off\n#include <bits/stdc++.h>\nusing namespace std;\n#define int long long\n#define main signed main()\n#define loop(i, a, n) for (int i = (a); i < (n); i++)\n#define rep(i, n) loop(i, 0, n)\n#define all(v) (v).begin(), (v).end()\n#define rall(v) (v).rbegin(), (v).rend()\n#define prec(n) fixed << setprecision(n)\nconstexpr int INF = sizeof(int) == sizeof(long long) ? 1000000000000000000LL : 1000000000;\nconstexpr int MOD = 1000000007;\nconstexpr double PI = 3.14159265358979;\ntemplate<typename A, typename B> bool cmin(A &a, const B &b) { return a > b ? (a = b, true) : false; }\ntemplate<typename A, typename B> bool cmax(A &a, const B &b) { return a < b ? (a = b, true) : false; }\nbool odd(const int &n) { return n & 1; }\nbool even(const int &n) { return ~n & 1; }\ntemplate<typename T = int> T in() { T x; cin >> x; return x; }\ntemplate<typename T = int> T in(T &&x) { T z(forward<T>(x)); cin >> z; return z; }\ntemplate<typename T> istream &operator>>(istream &is, vector<T> &v) { for (T &x : v) is >> x; return is; }\ntemplate<typename A, typename B> istream &operator>>(istream &is, pair<A, B> &p) { return is >> p.first >> p.second; }\ntemplate<typename T> ostream &operator<<(ostream &os, const vector<vector<T>> &v) { int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? \"\" : \"\\n\"); return os; }\ntemplate<typename T> ostream &operator<<(ostream &os, const vector<T> &v) { int n = v.size(); rep(i, n) os << v[i] << (i == n - 1 ? \"\" : \" \"); return os; }\ntemplate<typename A, typename B> ostream &operator<<(ostream &os, const pair<A, B> &p) { return os << p.first << ' ' << p.second; }\ntemplate<typename Head, typename Value> auto vectors(const Head &head, const Value &v) { return vector<Value>(head, v); }\ntemplate<typename Head, typename... Tail> auto vectors(Head x, Tail... tail) { auto inner = vectors(tail...); return vector<decltype(inner)>(x, inner); }\n// clang-format on\n\ntemplate<typename LSTTrait> class LazySegTree {\n  using FoldMonoid = typename LSTTrait::FoldMonoid;\n  using ActionMonoid = typename LSTTrait::ActionMonoid;\n  using T = typename FoldMonoid::value_type;\n  using Q = typename ActionMonoid::value_type;\n\n  LSTTrait lstTrait; // apply :: (T, Q) -> T, pow :: (Q, int) -> Q\n  FoldMonoid foldM;\n  ActionMonoid actionM;\n  int size = 1;\n  vector<T> tree; // 1-indexed\n  vector<Q> lazy; // 1-indexed\n\n  void push(int i) {\n    stack<pair<int, int>> s;\n    for (int d = 1; i /= 2; d *= 2) s.emplace(i, d);\n    for (int x, d; s.size(); s.pop()) {\n      tie(x, d) = s.top();\n      update(x * 2, lazy[x], d);\n      update(x * 2 + 1, lazy[x], d);\n      lazy[x] = actionM.id();\n    }\n  }\n\n  void update(const int &i, const Q &x, const int &d) {\n    tree[i] = lstTrait.apply(tree[i], lstTrait.pow(x, d));\n    if (i < size) lazy[i] = actionM(lazy[i], x);\n  }\n\n  void build(int i) {\n    for (int d = 2; i /= 2; d *= 2) tree[i] = lstTrait.apply(foldM(tree[i * 2], tree[i * 2 + 1]), lstTrait.pow(lazy[i], d));\n  }\n\npublic:\n  LazySegTree(const int &n = 0) {\n    while (size < n) size *= 2;\n    tree.assign(size * 2, foldM.id());\n    lazy.assign(size, actionM.id());\n  }\n\n  LazySegTree(const int &n, const T &x) {\n    while (size < n) size *= 2;\n    tree.assign(size * 2, x);\n    lazy.assign(size, actionM.id());\n    for (int i = size - 1; i >= 1; i--) tree[i] = foldM(tree[i * 2], tree[i * 2 + 1]);\n  }\n\n  template<typename InputIterator> LazySegTree(InputIterator first, InputIterator last) {\n    int n = distance(first, last);\n    while (size < n) size *= 2;\n    tree.resize(size * 2, foldM.id());\n    lazy.assign(size, actionM.id());\n    copy(first, last, tree.begin() + size);\n    for (int i = size - 1; i >= 1; i--) tree[i] = foldM(tree[i * 2], tree[i * 2 + 1]);\n  }\n\n  void act(int l, int r, const Q &x) { // [l, r) += x\n    int l0 = l += size, r0 = r += size;\n    push(l0), push(r0 - 1);\n    for (int d = 1; l < r; l /= 2, r /= 2, d *= 2) {\n      if (l & 1) update(l++, x, d);\n      if (r & 1) update(--r, x, d);\n    }\n    build(l0);\n    build(r0 - 1);\n  }\n\n  T fold(int l, int r) { // [l, r)\n    T accl = foldM.id(), accr = foldM.id();\n    for (push(l += size), push((r += size) - 1); l < r; l /= 2, r /= 2) {\n      if (l & 1) accl = foldM(accl, tree[l++]);\n      if (r & 1) accr = foldM(tree[--r], accr);\n    }\n    return foldM(accl, accr);\n  }\n};\n\ntemplate<typename T> struct sumMonoid {\n  using value_type = T;\n  value_type id() { return 0; }\n  value_type operator()(const value_type &a, const value_type &b) { return a + b; }\n};\n\ntemplate<typename T> struct updateMonoid {\n  using value_type = pair<bool, T>;\n  value_type id() { return {false, T()}; }\n  value_type operator()(const value_type &a, const value_type &b) { return b.first ? b : a; }\n};\n\ntemplate<typename T> struct RSQ_RUQ_Trait {\n  using FoldMonoid = sumMonoid<T>;\n  using ActionMonoid = updateMonoid<T>;\n  typename FoldMonoid::value_type apply(typename FoldMonoid::value_type t, typename ActionMonoid::value_type q) { return q.first ? q.second : t; }\n  typename ActionMonoid::value_type pow(typename ActionMonoid::value_type q, const int &d) { return {q.first, q.second * d}; }\n};\n\nmain {\n  int n, q;\n  cin >> n >> q;\n  LazySegTree<RSQ_RUQ_Trait<int>> lst(n, 0);\n  while (q--) {\n    if (in()) {\n      int s, t;\n      cin >> s >> t;\n      cout << lst.fold(s, t + 1) << endl;\n    } else {\n      int s, t, x;\n      cin >> s >> t >> x;\n      lst.act(s, t + 1, {true, x});\n    }\n  }\n}\n\n", "problem_context": "RSQ and RUQ\n\nWrite a program which manipulates a sequence $A$ = {$a_0, a_1, ..., a_{n-1}$} with the following operations:\n\n$update(s, t, x)$: change $a_s, a_{s+1}, ..., a_t$ to $x$.\n\n$getSum(s, t)$: print the sum of $a_s, a_{s+1}, ..., a_t$.\n\nNote that the initial values of $a_i ( i = 0, 1, ..., n-1 )$ are 0.\n\nInput\n\n$n$ $q$\n$query_1$\n$query_2$\n:\n$query_q$\n\nIn the first line, $n$ (the number of elements in $A$) and $q$ (the number of queries) are given. Then, $i$-th query $query_i$ is given in the following format:\n\n0 $s$ $t$ $x$\n\nor\n\n1 $s$ $t$\n\nThe first digit represents the type of the query. '0' denotes $update(s, t, x)$\nand '1' denotes $find(s, t)$.\n\nOutput\n\nFor each $getSum$ query, print the sum in a line.\n\nConstraints\n\n$1 ≤ n ≤ 100000$\n\n$1 ≤ q ≤ 100000$\n\n$0 ≤ s ≤ t < n$\n\n$-1000 ≤ x ≤ 1000$\n\nSample Input 1\n\n6 7\n0 1 3 1\n0 2 4 -2\n1 0 5\n1 0 1\n0 3 5 3\n1 3 4\n1 0 5\n\nSample Output 1\n\n-5\n1\n6\n8", "sample_input": "6 7\n0 1 3 1\n0 2 4 -2\n1 0 5\n1 0 1\n0 3 5 3\n1 3 4\n1 0 5\n"}, "reference_outputs": ["-5\n1\n6\n8\n"], "source_document_id": "p02353", "source_text": "RSQ and RUQ\n\nWrite a program which manipulates a sequence $A$ = {$a_0, a_1, ..., a_{n-1}$} with the following operations:\n\n$update(s, t, x)$: change $a_s, a_{s+1}, ..., a_t$ to $x$.\n\n$getSum(s, t)$: print the sum of $a_s, a_{s+1}, ..., a_t$.\n\nNote that the initial values of $a_i ( i = 0, 1, ..., n-1 )$ are 0.\n\nInput\n\n$n$ $q$\n$query_1$\n$query_2$\n:\n$query_q$\n\nIn the first line, $n$ (the number of elements in $A$) and $q$ (the number of queries) are given. Then, $i$-th query $query_i$ is given in the following format:\n\n0 $s$ $t$ $x$\n\nor\n\n1 $s$ $t$\n\nThe first digit represents the type of the query. '0' denotes $update(s, t, x)$\nand '1' denotes $find(s, t)$.\n\nOutput\n\nFor each $getSum$ query, print the sum in a line.\n\nConstraints\n\n$1 ≤ n ≤ 100000$\n\n$1 ≤ q ≤ 100000$\n\n$0 ≤ s ≤ t < n$\n\n$-1000 ≤ x ≤ 1000$\n\nSample Input 1\n\n6 7\n0 1 3 1\n0 2 4 -2\n1 0 5\n1 0 1\n0 3 5 3\n1 3 4\n1 0 5\n\nSample Output 1\n\n-5\n1\n6\n8", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 5378, "cpu_time_ms": 200, "memory_kb": 7008}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s619289085", "group_id": "codeNet:p02364", "input_text": "#include<cstdio>\n#include<algorithm>\n#include<iostream>\n#include<string>\n\nusing namespace std;\n\n\nstruct edge {int u,v,cost;};\nedge cookies[100000000];\n\nint V,E;\nint par[1000000],rank[10000000];\n\nvoid init(int n){\n  for(int i=0;i<n;i++){\n    par[i]=i;\n    rank[i]=0;\n  }\n}\n\nint find(int x){\n  if(par[x]==x){\n    return x;\n  } else {\n    return par[x]=find(par[x]);\n  }\n}\n\nvoid unite(int x,int y){\n  x=find(x);\n  y=find(y);\n  if(x==y) return;\n\n  if(rank[x]<rank[y]){\n    par[x]=y;\n  } else {\n    par[y]=x;\n    if(rank[x]==rank[y]) rank[x]++;\n  }\n}\n\nbool same(int x,int y){\n  return find(x)==find(y);\n}\n\nbool comp(const edge& e1,const edge& e2){\n  return e1.cost<e2.cost;\n}\n\nint kruskal(){\n  sort(cookies,cookies+E,comp);\n  init(V);\n  int res=0;\n\n  for(int i=0;i<E;i++){\n    edge e=cookies[i];\n    if(!same(e.u,e.v)){\n      unite(e.u,e.v);\n      res+=e.cost;\n    }\n  }\n  return res;\n\n}\n\n\nint main(){\n  scanf(\"%d%d\",&V,&E);\n  for(int i=0;i<E;i++){\n    scanf(\"%d%d%d\",&cookies[i].u,&cookies[i].v,&cookies[i].cost);\n  }\n\n\n  printf(\"%d\\n\",kruskal());\n\n  return 0;\n\n}", "language": "C++", "metadata": {"date": 1456929083, "filename_ext": "cpp", "original_language": "C++", "problem_description_relpath": "problem_descriptions/p02364.html", "problem_id": "p02364", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02364/input.txt", "sample_output_relpath": "derived/input_output/data/p02364/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02364/C++/s619289085.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s619289085", "user_id": "u844104454"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include<cstdio>\n#include<algorithm>\n#include<iostream>\n#include<string>\n\nusing namespace std;\n\n\nstruct edge {int u,v,cost;};\nedge cookies[100000000];\n\nint V,E;\nint par[1000000],rank[10000000];\n\nvoid init(int n){\n  for(int i=0;i<n;i++){\n    par[i]=i;\n    rank[i]=0;\n  }\n}\n\nint find(int x){\n  if(par[x]==x){\n    return x;\n  } else {\n    return par[x]=find(par[x]);\n  }\n}\n\nvoid unite(int x,int y){\n  x=find(x);\n  y=find(y);\n  if(x==y) return;\n\n  if(rank[x]<rank[y]){\n    par[x]=y;\n  } else {\n    par[y]=x;\n    if(rank[x]==rank[y]) rank[x]++;\n  }\n}\n\nbool same(int x,int y){\n  return find(x)==find(y);\n}\n\nbool comp(const edge& e1,const edge& e2){\n  return e1.cost<e2.cost;\n}\n\nint kruskal(){\n  sort(cookies,cookies+E,comp);\n  init(V);\n  int res=0;\n\n  for(int i=0;i<E;i++){\n    edge e=cookies[i];\n    if(!same(e.u,e.v)){\n      unite(e.u,e.v);\n      res+=e.cost;\n    }\n  }\n  return res;\n\n}\n\n\nint main(){\n  scanf(\"%d%d\",&V,&E);\n  for(int i=0;i<E;i++){\n    scanf(\"%d%d%d\",&cookies[i].u,&cookies[i].v,&cookies[i].cost);\n  }\n\n\n  printf(\"%d\\n\",kruskal());\n\n  return 0;\n\n}", "problem_context": "Minimum Spanning Tree\n\nFind the sum of weights of edges of the Minimum Spanning Tree for a given weighted undirected graph G = (V, E).\n\nInput\n\n|V| |E|\ns0 t0 w0\ns1 t1 w1\n:\ns|E|-1 t|E|-1 w|E|-1\n\n, where |V| is the number of vertices and |E| is the number of edges in the graph. The graph vertices are named with the numbers 0, 1,..., |V|-1 respectively.\n\nsi and ti represent source and target verticess of i-th edge (undirected) and wi represents the weight of the i-th edge.\n\nOutput\n\nPrint the sum of the weights of the Minimum Spanning Tree.\n\nConstraints\n\n1 ≤ |V| ≤ 10,000\n\n0 ≤ |E| ≤ 100,000\n\n0 ≤ wi ≤ 10,000\n\nThe graph is connected\n\nThere are no parallel edges\n\nThere are no self-loops\n\nSample Input 1\n\n4 6\n0 1 2\n1 2 1\n2 3 1\n3 0 1\n0 2 3\n1 3 5\n\nSample Output 1\n\n3\n\nSample Input 2\n\n6 9\n0 1 1\n0 2 3\n1 2 1\n1 3 7\n2 4 1\n1 4 3\n3 4 1\n3 5 1\n4 5 6\n\nSample Output 2\n\n5", "sample_input": "4 6\n0 1 2\n1 2 1\n2 3 1\n3 0 1\n0 2 3\n1 3 5\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02364", "source_text": "Minimum Spanning Tree\n\nFind the sum of weights of edges of the Minimum Spanning Tree for a given weighted undirected graph G = (V, E).\n\nInput\n\n|V| |E|\ns0 t0 w0\ns1 t1 w1\n:\ns|E|-1 t|E|-1 w|E|-1\n\n, where |V| is the number of vertices and |E| is the number of edges in the graph. The graph vertices are named with the numbers 0, 1,..., |V|-1 respectively.\n\nsi and ti represent source and target verticess of i-th edge (undirected) and wi represents the weight of the i-th edge.\n\nOutput\n\nPrint the sum of the weights of the Minimum Spanning Tree.\n\nConstraints\n\n1 ≤ |V| ≤ 10,000\n\n0 ≤ |E| ≤ 100,000\n\n0 ≤ wi ≤ 10,000\n\nThe graph is connected\n\nThere are no parallel edges\n\nThere are no self-loops\n\nSample Input 1\n\n4 6\n0 1 2\n1 2 1\n2 3 1\n3 0 1\n0 2 3\n1 3 5\n\nSample Output 1\n\n3\n\nSample Input 2\n\n6 9\n0 1 1\n0 2 3\n1 2 1\n1 3 7\n2 4 1\n1 4 3\n3 4 1\n3 5 1\n4 5 6\n\nSample Output 2\n\n5", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1059, "cpu_time_ms": 40, "memory_kb": 7392}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s066271753", "group_id": "codeNet:p02371", "input_text": "#include <iostream>\n#include <vector>\n#include <queue>\n#include <algorithm>\n#include <functional>\n\nusing namespace std;\ntypedef pair<int, int> P;\nstatic const int INF = 1e9;\nstatic const int SIZE = 100001;\n\nstruct edge\n{\n\tint to, cost;\n};\n\nvector<edge> G[SIZE];\nint d[SIZE];\nint n;\n\nvoid bfs(int v)\n{\n\tfor (int i = 0; i < n; ++i)\n\t{\n\t\td[i] = INF;\n\t}\n\td[v] = 0;\n\tpriority_queue < P, vector<P>, greater<P> > pque;\n\tpque.push(P(0, v));\n\twhile (!pque.empty())\n\t{\n\t\tP p = pque.top();\n\t\tpque.pop();\n\t\tint vertex = p.second;\n\t\tfor (int i = 0; i < G[vertex].size(); ++i)\n\t\t{\n\t\t\tedge e = G[vertex][i];\n\t\t\tif (d[e.to] > d[vertex] + e.cost)\n\t\t\t{\n\t\t\t\td[e.to] = d[vertex] + e.cost;\n\t\t\t\tpque.push(P(d[e.to], e.to));\n\t\t\t}\n\t\t}\n\t}\n}\n\nvoid solve()\n{\n\tcin >> n;\n\tfor (int i = 0; i < n - 1; ++i)\n\t{\n\t\tint s, t, w;\n\t\tcin >> s >> t >> w;\n\t\tedge e1, e2;\n\t\te1.to = t;\n\t\te2.to = s;\n\t\te1.cost = e2.cost = w;\n\t\tG[s].push_back(e1);\n\t\tG[t].push_back(e2);\n\t}\n\tbfs(0);\n\tint maxDist = 0;\n\tint maxv = 0;\n\tfor (int i = 1; i < n; ++i)\n\t{\n\t\tif (maxDist < d[i])\n\t\t{\n\t\t\tmaxDist = d[i];\n\t\t\tmaxv = i;\n\t\t}\n\t}\n\tbfs(maxv);\n\tmaxDist = 0;\n\tfor (int i = 0; i < n; ++i)\n\t{\n\t\tif (maxDist < d[i])\n\t\t{\n\t\t\tmaxDist = d[i];\n\t\t}\n\t}\n\tcout << maxDist << endl;\n}\n\nint main()\n{\n\tsolve();\n\treturn(0);\n}", "language": "C++", "metadata": {"date": 1462114414, "filename_ext": "cpp", "original_language": "C++", "problem_description_relpath": "problem_descriptions/p02371.html", "problem_id": "p02371", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02371/input.txt", "sample_output_relpath": "derived/input_output/data/p02371/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02371/C++/s066271753.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s066271753", "user_id": "u285015144"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\n#include <queue>\n#include <algorithm>\n#include <functional>\n\nusing namespace std;\ntypedef pair<int, int> P;\nstatic const int INF = 1e9;\nstatic const int SIZE = 100001;\n\nstruct edge\n{\n\tint to, cost;\n};\n\nvector<edge> G[SIZE];\nint d[SIZE];\nint n;\n\nvoid bfs(int v)\n{\n\tfor (int i = 0; i < n; ++i)\n\t{\n\t\td[i] = INF;\n\t}\n\td[v] = 0;\n\tpriority_queue < P, vector<P>, greater<P> > pque;\n\tpque.push(P(0, v));\n\twhile (!pque.empty())\n\t{\n\t\tP p = pque.top();\n\t\tpque.pop();\n\t\tint vertex = p.second;\n\t\tfor (int i = 0; i < G[vertex].size(); ++i)\n\t\t{\n\t\t\tedge e = G[vertex][i];\n\t\t\tif (d[e.to] > d[vertex] + e.cost)\n\t\t\t{\n\t\t\t\td[e.to] = d[vertex] + e.cost;\n\t\t\t\tpque.push(P(d[e.to], e.to));\n\t\t\t}\n\t\t}\n\t}\n}\n\nvoid solve()\n{\n\tcin >> n;\n\tfor (int i = 0; i < n - 1; ++i)\n\t{\n\t\tint s, t, w;\n\t\tcin >> s >> t >> w;\n\t\tedge e1, e2;\n\t\te1.to = t;\n\t\te2.to = s;\n\t\te1.cost = e2.cost = w;\n\t\tG[s].push_back(e1);\n\t\tG[t].push_back(e2);\n\t}\n\tbfs(0);\n\tint maxDist = 0;\n\tint maxv = 0;\n\tfor (int i = 1; i < n; ++i)\n\t{\n\t\tif (maxDist < d[i])\n\t\t{\n\t\t\tmaxDist = d[i];\n\t\t\tmaxv = i;\n\t\t}\n\t}\n\tbfs(maxv);\n\tmaxDist = 0;\n\tfor (int i = 0; i < n; ++i)\n\t{\n\t\tif (maxDist < d[i])\n\t\t{\n\t\t\tmaxDist = d[i];\n\t\t}\n\t}\n\tcout << maxDist << endl;\n}\n\nint main()\n{\n\tsolve();\n\treturn(0);\n}", "problem_context": "Diameter of a Tree\n\nGiven a tree T with non-negative weight, find the diameter of the tree.\n\nThe diameter of a tree is the maximum distance between two nodes in a tree.\n\nInput\n\nn\ns1 t1 w1\ns2 t2 w2\n:\nsn-1 tn-1 wn-1\n\nThe first line consists of an integer n which represents the number of nodes in the tree. Every node has a unique ID from 0 to n-1 respectively.\n\nIn the following n-1 lines, edges of the tree are given.\n\nsi and ti represent end-points of the i-th edge (undirected) and wi represents the weight (distance) of the i-th edge.\n\nOutput\n\nPrint the diameter of the tree in a line.\n\nConstraints\n\n1 ≤ n ≤ 100,000\n\n0 ≤ wi ≤ 1,000\n\nSample Input 1\n\n4\n0 1 2\n1 2 1\n1 3 3\n\nSample Output 1\n\n5\n\nSample Input 2\n\n4\n0 1 1\n1 2 2\n2 3 4\n\nSample Output 2\n\n7", "sample_input": "4\n0 1 2\n1 2 1\n1 3 3\n"}, "reference_outputs": ["5\n"], "source_document_id": "p02371", "source_text": "Diameter of a Tree\n\nGiven a tree T with non-negative weight, find the diameter of the tree.\n\nThe diameter of a tree is the maximum distance between two nodes in a tree.\n\nInput\n\nn\ns1 t1 w1\ns2 t2 w2\n:\nsn-1 tn-1 wn-1\n\nThe first line consists of an integer n which represents the number of nodes in the tree. Every node has a unique ID from 0 to n-1 respectively.\n\nIn the following n-1 lines, edges of the tree are given.\n\nsi and ti represent end-points of the i-th edge (undirected) and wi represents the weight (distance) of the i-th edge.\n\nOutput\n\nPrint the diameter of the tree in a line.\n\nConstraints\n\n1 ≤ n ≤ 100,000\n\n0 ≤ wi ≤ 1,000\n\nSample Input 1\n\n4\n0 1 2\n1 2 1\n1 3 3\n\nSample Output 1\n\n5\n\nSample Input 2\n\n4\n0 1 1\n1 2 2\n2 3 4\n\nSample Output 2\n\n7", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1243, "cpu_time_ms": 110, "memory_kb": 7984}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s455919721", "group_id": "codeNet:p02396", "input_text": "#include<iostream>\nusing namespace std;\nint main(){\n\tint x = 0;\n\tcin >> x;\n\tfor (int i = 0; i >= 0;i++){\n\t\tif (x != 0){\n\t\t\tcout << \"Case\" << \" \" << i << \"; \" <<x<< endl;\n\t\t}\n\t}\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1494840532, "filename_ext": "cpp", "original_language": "C++", "problem_description_relpath": "problem_descriptions/p02396.html", "problem_id": "p02396", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02396/input.txt", "sample_output_relpath": "derived/input_output/data/p02396/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02396/C++/s455919721.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s455919721", "user_id": "u499289652"}, "prompt_components": {"gold_output": "Case 1: 3\nCase 2: 5\nCase 3: 11\nCase 4: 7\nCase 5: 8\nCase 6: 19\n", "input_to_evaluate": "#include<iostream>\nusing namespace std;\nint main(){\n\tint x = 0;\n\tcin >> x;\n\tfor (int i = 0; i >= 0;i++){\n\t\tif (x != 0){\n\t\t\tcout << \"Case\" << \" \" << i << \"; \" <<x<< endl;\n\t\t}\n\t}\n\treturn 0;\n}", "problem_context": "Print Test Cases\n\nIn the online judge system, a judge file may include multiple datasets to check whether the submitted program outputs a correct answer for each test case. This task is to practice solving a problem with multiple datasets.\n\nWrite a program which reads an integer x and print it as is. Note that multiple datasets are given for this problem.\n\nInput\n\nThe input consists of multiple datasets. Each dataset consists of an integer x in a line.\n\nThe input ends with an integer 0. You program should not process (print) for this terminal symbol.\n\nOutput\n\nFor each dataset, print x in the following format:\n\nCase i: x\n\nwhere i is the case number which starts with 1. Put a single space between \"Case\" and i. Also, put a single space between ':' and x.\n\nConstraints\n\n1 ≤ x ≤ 10000\n\nThe number of datasets ≤ 10000\n\nSample Input\n\n3\n5\n11\n7\n8\n19\n0\n\nSample Output\n\nCase 1: 3\nCase 2: 5\nCase 3: 11\nCase 4: 7\nCase 5: 8\nCase 6: 19", "sample_input": "3\n5\n11\n7\n8\n19\n0\n"}, "reference_outputs": ["Case 1: 3\nCase 2: 5\nCase 3: 11\nCase 4: 7\nCase 5: 8\nCase 6: 19\n"], "source_document_id": "p02396", "source_text": "Print Test Cases\n\nIn the online judge system, a judge file may include multiple datasets to check whether the submitted program outputs a correct answer for each test case. This task is to practice solving a problem with multiple datasets.\n\nWrite a program which reads an integer x and print it as is. Note that multiple datasets are given for this problem.\n\nInput\n\nThe input consists of multiple datasets. Each dataset consists of an integer x in a line.\n\nThe input ends with an integer 0. You program should not process (print) for this terminal symbol.\n\nOutput\n\nFor each dataset, print x in the following format:\n\nCase i: x\n\nwhere i is the case number which starts with 1. Put a single space between \"Case\" and i. Also, put a single space between ':' and x.\n\nConstraints\n\n1 ≤ x ≤ 10000\n\nThe number of datasets ≤ 10000\n\nSample Input\n\n3\n5\n11\n7\n8\n19\n0\n\nSample Output\n\nCase 1: 3\nCase 2: 5\nCase 3: 11\nCase 4: 7\nCase 5: 8\nCase 6: 19", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 189, "cpu_time_ms": 20000, "memory_kb": 2876}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s484991794", "group_id": "codeNet:p02414", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n    int n,m,l;\n    cin>>n>>m>>l;\n    \n    int a[100][100];\n    for(int i=0;i<n;i++)\n        for(int j=0;j<m;j++) cin>>a[i][j];\n    \n    int b[100][100];\n    for(int i=0;i<m;i++)\n        for(int j=0;j<l;l++) cin>>b[i][j];\n    \n    long long c[100][100] = {};\n    for(int i=0;i<n;i++)\n        for(int j=0;j<l;j++)\n            for(int k=0;k<m;k++) c[i][j] += a[i][k] * b[k][j];\n    \n    for(int i=0;i<n;i++){\n        for(int j=0;j<l;j++){\n            if(j) cout<<\" \";\n            cout<<c[i][j];\n        }\n        cout<<endl;\n    }\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1523872882, "filename_ext": "cpp", "original_language": "C++", "problem_description_relpath": "problem_descriptions/p02414.html", "problem_id": "p02414", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02414/input.txt", "sample_output_relpath": "derived/input_output/data/p02414/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02414/C++/s484991794.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s484991794", "user_id": "u117673497"}, "prompt_components": {"gold_output": "1 8 5\n0 9 6\n4 23 14\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n    int n,m,l;\n    cin>>n>>m>>l;\n    \n    int a[100][100];\n    for(int i=0;i<n;i++)\n        for(int j=0;j<m;j++) cin>>a[i][j];\n    \n    int b[100][100];\n    for(int i=0;i<m;i++)\n        for(int j=0;j<l;l++) cin>>b[i][j];\n    \n    long long c[100][100] = {};\n    for(int i=0;i<n;i++)\n        for(int j=0;j<l;j++)\n            for(int k=0;k<m;k++) c[i][j] += a[i][k] * b[k][j];\n    \n    for(int i=0;i<n;i++){\n        for(int j=0;j<l;j++){\n            if(j) cout<<\" \";\n            cout<<c[i][j];\n        }\n        cout<<endl;\n    }\n    return 0;\n}\n", "problem_context": "MathJax.Hub.Config({ tex2jax: { inlineMath: [[\"$\",\"$\"], [\"\\\\(\",\"\\\\)\"]], processEscapes: true }});\n\nMatrix Multiplication\n\nWrite a program which reads a $n \\times m$ matrix $A$ and a $m \\times l$ matrix $B$, and prints their product, a $n \\times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:\n\n\\[\nc_{ij} = \\sum_{k=1}^m a_{ik}b_{kj}\n\\]\n\nwhere $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.\n\nInput\n\nIn the first line, three integers $n$, $m$ and $l$ are given separated by space characters\n\nIn the following lines, the $n \\times m$ matrix $A$ and the $m \\times l$ matrix $B$ are given.\n\nOutput\n\nPrint elements of the $n \\times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.\n\nConstraints\n\n$1 \\leq n, m, l \\leq 100$\n\n$0 \\leq a_{ij}, b_{ij} \\leq 10000$\n\nSample Input\n\n3 2 3\n1 2\n0 3\n4 5\n1 2 1\n0 3 2\n\nSample Output\n\n1 8 5\n0 9 6\n4 23 14\n\nNote\n\n      解説", "sample_input": "3 2 3\n1 2\n0 3\n4 5\n1 2 1\n0 3 2\n"}, "reference_outputs": ["1 8 5\n0 9 6\n4 23 14\n"], "source_document_id": "p02414", "source_text": "MathJax.Hub.Config({ tex2jax: { inlineMath: [[\"$\",\"$\"], [\"\\\\(\",\"\\\\)\"]], processEscapes: true }});\n\nMatrix Multiplication\n\nWrite a program which reads a $n \\times m$ matrix $A$ and a $m \\times l$ matrix $B$, and prints their product, a $n \\times l$ matrix $C$. An element of matrix $C$ is obtained by the following formula:\n\n\\[\nc_{ij} = \\sum_{k=1}^m a_{ik}b_{kj}\n\\]\n\nwhere $a_{ij}$, $b_{ij}$ and $c_{ij}$ are elements of $A$, $B$ and $C$ respectively.\n\nInput\n\nIn the first line, three integers $n$, $m$ and $l$ are given separated by space characters\n\nIn the following lines, the $n \\times m$ matrix $A$ and the $m \\times l$ matrix $B$ are given.\n\nOutput\n\nPrint elements of the $n \\times l$ matrix $C$ ($c_{ij}$). Print a single space character between adjacent elements.\n\nConstraints\n\n$1 \\leq n, m, l \\leq 100$\n\n$0 \\leq a_{ij}, b_{ij} \\leq 10000$\n\nSample Input\n\n3 2 3\n1 2\n0 3\n4 5\n1 2 1\n0 3 2\n\nSample Output\n\n1 8 5\n0 9 6\n4 23 14\n\nNote\n\n      解説", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 601, "cpu_time_ms": 1990, "memory_kb": 2868}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s097422377", "group_id": "codeNet:p02456", "input_text": "#include \"bits/stdc++.h\"\n\n#define REP(i,num) for(int i=0;i<(num);++i)\n#define ALL(c) c.begin(),c.end()\n#define PRINTALL(c) for(auto& x:c){cout<<x<<' ';}cout<<endl;\n#define PAIRCOMP(c,comp) [](const pair<ll,ll>& lhs,const pair<ll,ll>& rhs){return lhs.c comp rhs.c;}\n\nusing namespace std;\nusing ll = long long;\n\nconstexpr ll atcoder_mod = 1e9+7;\n\ntemplate<typename T=int>\nT in(){T x; cin >> x; return (x);}\ntemplate<typename T=int,typename C=vector<T>>\nC vecin(int N){C x(N);REP(i,N){x[i]=in<T>();}return move(x);}\n\nvoid vout(){cout << endl;}\ntemplate<typename Head,typename... Tail>\nvoid vout(Head&& h,Tail&&... t){cout << ' ' << h;vout(forward<Tail>(t)...);}\nvoid out(){cout << endl;}\ntemplate<typename Head,typename... Tail>\nvoid out(Head&& h,Tail&&... t){cout << h;vout(forward<Tail>(t)...);}\n\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\t\n\tint Q=in();\n\tset<int> S;\n\tREP(i,Q){\n\t\tint q=in();\n\t\tif(q==1){\n\t\t\tout(S.find(in())==S.end()?0:1);\n\t\t}\n\t\telse if(q==2){\n\t\t\tS.erase(in());\n\t\t}\n\t\telse{\n\t\t\tS.insert(in());\n\t\t\tout(S.size());\n\t\t}\n\t}\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1571062785, "filename_ext": "cpp", "original_language": "C++14", "problem_description_relpath": "problem_descriptions/p02456.html", "problem_id": "p02456", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02456/input.txt", "sample_output_relpath": "derived/input_output/data/p02456/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02456/C++/s097422377.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s097422377", "user_id": "u442275619"}, "prompt_components": {"gold_output": "1\n2\n3\n1\n0\n1\n3\n", "input_to_evaluate": "#include \"bits/stdc++.h\"\n\n#define REP(i,num) for(int i=0;i<(num);++i)\n#define ALL(c) c.begin(),c.end()\n#define PRINTALL(c) for(auto& x:c){cout<<x<<' ';}cout<<endl;\n#define PAIRCOMP(c,comp) [](const pair<ll,ll>& lhs,const pair<ll,ll>& rhs){return lhs.c comp rhs.c;}\n\nusing namespace std;\nusing ll = long long;\n\nconstexpr ll atcoder_mod = 1e9+7;\n\ntemplate<typename T=int>\nT in(){T x; cin >> x; return (x);}\ntemplate<typename T=int,typename C=vector<T>>\nC vecin(int N){C x(N);REP(i,N){x[i]=in<T>();}return move(x);}\n\nvoid vout(){cout << endl;}\ntemplate<typename Head,typename... Tail>\nvoid vout(Head&& h,Tail&&... t){cout << ' ' << h;vout(forward<Tail>(t)...);}\nvoid out(){cout << endl;}\ntemplate<typename Head,typename... Tail>\nvoid out(Head&& h,Tail&&... t){cout << h;vout(forward<Tail>(t)...);}\n\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\t\n\tint Q=in();\n\tset<int> S;\n\tREP(i,Q){\n\t\tint q=in();\n\t\tif(q==1){\n\t\t\tout(S.find(in())==S.end()?0:1);\n\t\t}\n\t\telse if(q==2){\n\t\t\tS.erase(in());\n\t\t}\n\t\telse{\n\t\t\tS.insert(in());\n\t\t\tout(S.size());\n\t\t}\n\t}\n\treturn 0;\n}\n", "problem_context": "Set: Delete\n\nFor a set $S$ of integers, perform a sequence of the following operations. Note that each value in $S$ must be unique.\n\ninsert($x$): Insert $x$ to $S$ and report the number of elements in $S$ after the operation.\n\nfind($x$): Report the number of $x$ in $S$ (0 or 1).\n\ndelete($x$): Delete $x$ from $S$.\n\nInput\n\nThe input is given in the following format.\n\n$q$\n$query_1$\n$query_2$\n:\n$query_q$\n\nEach query $query_i$ is given by\n\n0 $x$\n\nor\n\n1 $x$\n\nor\n\n2 $x$\n\nwhere the first digits 0, 1 and 2 represent insert, find and delete operations respectively.\n\nOutput\n\nFor each insert operation, print the number of elements in $S$.\n\nFor each find operation, print the number of specified elements in $S$.\n\nConstraints\n\n$1 \\leq q \\leq 200,000$\n\n$0 \\leq x \\leq 1,000,000,000$\n\nSample Input 1\n\n8\n0 1\n0 2\n0 3\n2 2\n1 1\n1 2\n1 3\n0 2\n\nSample Output 1\n\n1\n2\n3\n1\n0\n1\n3", "sample_input": "8\n0 1\n0 2\n0 3\n2 2\n1 1\n1 2\n1 3\n0 2\n"}, "reference_outputs": ["1\n2\n3\n1\n0\n1\n3\n"], "source_document_id": "p02456", "source_text": "Set: Delete\n\nFor a set $S$ of integers, perform a sequence of the following operations. Note that each value in $S$ must be unique.\n\ninsert($x$): Insert $x$ to $S$ and report the number of elements in $S$ after the operation.\n\nfind($x$): Report the number of $x$ in $S$ (0 or 1).\n\ndelete($x$): Delete $x$ from $S$.\n\nInput\n\nThe input is given in the following format.\n\n$q$\n$query_1$\n$query_2$\n:\n$query_q$\n\nEach query $query_i$ is given by\n\n0 $x$\n\nor\n\n1 $x$\n\nor\n\n2 $x$\n\nwhere the first digits 0, 1 and 2 represent insert, find and delete operations respectively.\n\nOutput\n\nFor each insert operation, print the number of elements in $S$.\n\nFor each find operation, print the number of specified elements in $S$.\n\nConstraints\n\n$1 \\leq q \\leq 200,000$\n\n$0 \\leq x \\leq 1,000,000,000$\n\nSample Input 1\n\n8\n0 1\n0 2\n0 3\n2 2\n1 1\n1 2\n1 3\n0 2\n\nSample Output 1\n\n1\n2\n3\n1\n0\n1\n3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1059, "cpu_time_ms": 220, "memory_kb": 12376}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s570591895", "group_id": "codeNet:p02536", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n\nstruct UnionFind{\n\tvector<int> par;\n\n\tUnionFind(int N){\n\t\tpar.resize(N,-1);\n\t}\n\n\tint root(int x){\n\t\tif(par[x] < 0) return x;\n\t\treturn par[x] = root(par[x]);\n\t}\n\n\tvoid unite(int x, int y){\n\t\tint rx = root(x);\n\t\tint ry = root(y);\n\t\tif(rx == ry) return;\n\t\tif(par[rx] < par[ry]){\n\t\t\tpar[rx] += par[ry];\n\t\t\tpar[ry] = rx;\n\t\t} else {\n\t\t\tpar[ry] += par[rx];\n\t\t\tpar[rx] = ry;\n\t\t}\n\t\t\n\t}\n\n\tbool same(int x, int y){\n\t\treturn par[x] == par[y];\n\t}\n\n};\n\nint main(){\n\tint N,M; cin >> N >> M;\n\tUnionFind uf(N);\n\tfor(int i=0; i<M; i++){\n\t\tint a,b; cin >> a >> b;\n\t\ta--; b--;\n\t\tuf.unite(a,b);\n\t}\n\tset<int> s;\n\tfor(int i=0; i<N; i++){\n\t\ts.insert(uf.root(i));\n\t}\n\tcout << s.size()-1 << endl;\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1601169610, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02536.html", "problem_id": "p02536", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02536/input.txt", "sample_output_relpath": "derived/input_output/data/p02536/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02536/C++/s570591895.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s570591895", "user_id": "u107464079"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n\nstruct UnionFind{\n\tvector<int> par;\n\n\tUnionFind(int N){\n\t\tpar.resize(N,-1);\n\t}\n\n\tint root(int x){\n\t\tif(par[x] < 0) return x;\n\t\treturn par[x] = root(par[x]);\n\t}\n\n\tvoid unite(int x, int y){\n\t\tint rx = root(x);\n\t\tint ry = root(y);\n\t\tif(rx == ry) return;\n\t\tif(par[rx] < par[ry]){\n\t\t\tpar[rx] += par[ry];\n\t\t\tpar[ry] = rx;\n\t\t} else {\n\t\t\tpar[ry] += par[rx];\n\t\t\tpar[rx] = ry;\n\t\t}\n\t\t\n\t}\n\n\tbool same(int x, int y){\n\t\treturn par[x] == par[y];\n\t}\n\n};\n\nint main(){\n\tint N,M; cin >> N >> M;\n\tUnionFind uf(N);\n\tfor(int i=0; i<M; i++){\n\t\tint a,b; cin >> a >> b;\n\t\ta--; b--;\n\t\tuf.unite(a,b);\n\t}\n\tset<int> s;\n\tfor(int i=0; i<N; i++){\n\t\ts.insert(uf.root(i));\n\t}\n\tcout << s.size()-1 << endl;\n\treturn 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N cities numbered 1 through N, and M bidirectional roads numbered 1 through M.\nRoad i connects City A_i and City B_i.\n\nSnuke can perform the following operation zero or more times:\n\nChoose two distinct cities that are not directly connected by a road, and build a new road between the two cities.\n\nAfter he finishes the operations, it must be possible to travel from any city to any other cities by following roads (possibly multiple times).\n\nWhat is the minimum number of roads he must build to achieve the goal?\n\nConstraints\n\n2 \\leq N \\leq 100,000\n\n1 \\leq M \\leq 100,000\n\n1 \\leq A_i < B_i \\leq N\n\nNo two roads connect the same pair of cities.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 B_1\n:\nA_M B_M\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n3 1\n1 2\n\nSample Output 1\n\n1\n\nInitially, there are three cities, and there is a road between City 1 and City 2.\n\nSnuke can achieve the goal by building one new road, for example, between City 1 and City 3.\nAfter that,\n\nWe can travel between 1 and 2 directly.\n\nWe can travel between 1 and 3 directly.\n\nWe can travel between 2 and 3 by following both roads (2 - 1 - 3).", "sample_input": "3 1\n1 2\n"}, "reference_outputs": ["1\n"], "source_document_id": "p02536", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N cities numbered 1 through N, and M bidirectional roads numbered 1 through M.\nRoad i connects City A_i and City B_i.\n\nSnuke can perform the following operation zero or more times:\n\nChoose two distinct cities that are not directly connected by a road, and build a new road between the two cities.\n\nAfter he finishes the operations, it must be possible to travel from any city to any other cities by following roads (possibly multiple times).\n\nWhat is the minimum number of roads he must build to achieve the goal?\n\nConstraints\n\n2 \\leq N \\leq 100,000\n\n1 \\leq M \\leq 100,000\n\n1 \\leq A_i < B_i \\leq N\n\nNo two roads connect the same pair of cities.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 B_1\n:\nA_M B_M\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n3 1\n1 2\n\nSample Output 1\n\n1\n\nInitially, there are three cities, and there is a road between City 1 and City 2.\n\nSnuke can achieve the goal by building one new road, for example, between City 1 and City 3.\nAfter that,\n\nWe can travel between 1 and 2 directly.\n\nWe can travel between 1 and 3 directly.\n\nWe can travel between 2 and 3 by following both roads (2 - 1 - 3).", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 753, "cpu_time_ms": 58, "memory_kb": 7660}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s939345146", "group_id": "codeNet:p02540", "input_text": "/*\nこれを入れて実行\ng++ code.cpp\n./a.out\n */\n \n#include <iostream>\n#include <cstdio>\n#include <stdio.h>\n#include <vector>\n#include <string>\n#include <cstring>\n#include <queue>\n#include <deque>\n#include <stack>\n#include <algorithm>\n#include <utility>\n#include <set>\n#include <map>\n#include <unordered_map>\n#include <unordered_set>\n#include <cmath>\n#include <math.h>\n#include <tuple>\n#include <iomanip>\n#include <bitset>\n#include <functional>\n#include <cassert>\n#include <random>\n\n#define all(x) (x).begin(),(x).end()\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n \nusing namespace std;\ntypedef long long ll;\ntypedef long double ld;\n \nint dy4[4] = {-1, 0, +1, 0};\nint dx4[4] = {0, +1, 0, -1};\nint dy8[8] = {-1, -1, 0, 1, 1, 1, 0, -1};\nint dx8[8] = {0, 1, 1, 1, 0, -1, -1, -1};\n \nconst long long INF = 1LL << 60;\nconst ll MOD = 1e9 + 7;\n \nbool greaterSecond(const pair<int, int>& f, const pair<int, int>& s){\n    return f.second > s.second;\n}\n \nll gcd(ll a, ll b){\n\tif (b == 0)return a;\n\treturn gcd(b, a % b);\n}\n \nll lcm(ll a, ll b){\n    return a / gcd(a, b) * b;\n}\n\nll conbinationMemo[100][100];\n\nvoid cmemoInit(){\n    rep(i, 100){\n        rep(j, 100){\n            conbinationMemo[i][j] = -1;\n        }\n    }\n}\n \nll nCr(ll n, ll r){\n    if(conbinationMemo[n][r] != -1) return conbinationMemo[n][r];\n    if(r == 0 || r == n){\n        return 1;\n    } else if(r == 1){\n        return n;\n    }\n    return conbinationMemo[n][r] = (nCr(n - 1, r) + nCr(n - 1, r - 1));\n}\n \nll nPr(ll n, ll r){\n    r = n - r;\n    ll ret = 1;\n    for (ll i = n; i >= r + 1; i--) ret *= i;\n    return ret;\n}\n//-----------------------ここから-----------\nstruct UnionFind{\n    vector<ll> parent;\n    vector<ll> s;\n \n    UnionFind(ll n){\n        parent.resize(n);\n        s.resize(n, 1);\n        for(int i = 0; i < n; i++) parent[i] = i;\n    }\n \n    ll root(ll node){\n        if(parent[node] == node){\n            return node;\n        } else {\n            return parent[node] = root(parent[node]);\n        }\n    }\n \n    void unite(ll x, ll y){\n        ll rootx = root(x);\n        ll rooty = root(y);\n        if(rootx == rooty) return;\n        if(s[rootx] < s[rooty]) swap(rootx, rooty);\n        s[rootx] += s[rooty];\n        parent[rooty] = rootx;\n    }\n \n    bool isSame(ll x, ll y){\n        return root(x) == root(y);\n    }\n \n    ll size(ll x){\n        return s[root(x)];\n    }\n};\nint main(void){\n    ll n;\n    cin >> n;\n    vector<pair<pair<ll,ll>,ll>> vecx, vecy;\n    rep(i, n){\n        ll x, y;\n        cin >> x >> y;\n        vecx.push_back({{x, y}, i});\n    }\n\n    sort(all(vecx));\n\n    UnionFind uf(n);\n    vector<pair<ll,ll>> mi(200200, {INF, INF});\n    set<pair<ll,ll>> rt;\n    for(ll i = 0; i < n; i++){\n        for(auto &j : rt){\n            if(j.first < vecx[i].first.second){\n                uf.unite(vecx[i].second, j.second);\n            } else {\n                break;\n            }\n        }\n        ll root = uf.root(vecx[i].second);\n        if(mi[root].first > vecx[i].first.second){\n            rt.erase({mi[root].first, root});\n            mi[root] = {vecx[i].first.second, vecx[i].second};\n            rt.insert({mi[root].first, root});\n        }\n    }\n\n    rep(i, n){\n        cout << uf.size(i) << endl;\n    }\n\n    \n}\n\n", "language": "C++", "metadata": {"date": 1600693822, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02540.html", "problem_id": "p02540", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02540/input.txt", "sample_output_relpath": "derived/input_output/data/p02540/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02540/C++/s939345146.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s939345146", "user_id": "u845000384"}, "prompt_components": {"gold_output": "1\n1\n2\n2\n", "input_to_evaluate": "/*\nこれを入れて実行\ng++ code.cpp\n./a.out\n */\n \n#include <iostream>\n#include <cstdio>\n#include <stdio.h>\n#include <vector>\n#include <string>\n#include <cstring>\n#include <queue>\n#include <deque>\n#include <stack>\n#include <algorithm>\n#include <utility>\n#include <set>\n#include <map>\n#include <unordered_map>\n#include <unordered_set>\n#include <cmath>\n#include <math.h>\n#include <tuple>\n#include <iomanip>\n#include <bitset>\n#include <functional>\n#include <cassert>\n#include <random>\n\n#define all(x) (x).begin(),(x).end()\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n \nusing namespace std;\ntypedef long long ll;\ntypedef long double ld;\n \nint dy4[4] = {-1, 0, +1, 0};\nint dx4[4] = {0, +1, 0, -1};\nint dy8[8] = {-1, -1, 0, 1, 1, 1, 0, -1};\nint dx8[8] = {0, 1, 1, 1, 0, -1, -1, -1};\n \nconst long long INF = 1LL << 60;\nconst ll MOD = 1e9 + 7;\n \nbool greaterSecond(const pair<int, int>& f, const pair<int, int>& s){\n    return f.second > s.second;\n}\n \nll gcd(ll a, ll b){\n\tif (b == 0)return a;\n\treturn gcd(b, a % b);\n}\n \nll lcm(ll a, ll b){\n    return a / gcd(a, b) * b;\n}\n\nll conbinationMemo[100][100];\n\nvoid cmemoInit(){\n    rep(i, 100){\n        rep(j, 100){\n            conbinationMemo[i][j] = -1;\n        }\n    }\n}\n \nll nCr(ll n, ll r){\n    if(conbinationMemo[n][r] != -1) return conbinationMemo[n][r];\n    if(r == 0 || r == n){\n        return 1;\n    } else if(r == 1){\n        return n;\n    }\n    return conbinationMemo[n][r] = (nCr(n - 1, r) + nCr(n - 1, r - 1));\n}\n \nll nPr(ll n, ll r){\n    r = n - r;\n    ll ret = 1;\n    for (ll i = n; i >= r + 1; i--) ret *= i;\n    return ret;\n}\n//-----------------------ここから-----------\nstruct UnionFind{\n    vector<ll> parent;\n    vector<ll> s;\n \n    UnionFind(ll n){\n        parent.resize(n);\n        s.resize(n, 1);\n        for(int i = 0; i < n; i++) parent[i] = i;\n    }\n \n    ll root(ll node){\n        if(parent[node] == node){\n            return node;\n        } else {\n            return parent[node] = root(parent[node]);\n        }\n    }\n \n    void unite(ll x, ll y){\n        ll rootx = root(x);\n        ll rooty = root(y);\n        if(rootx == rooty) return;\n        if(s[rootx] < s[rooty]) swap(rootx, rooty);\n        s[rootx] += s[rooty];\n        parent[rooty] = rootx;\n    }\n \n    bool isSame(ll x, ll y){\n        return root(x) == root(y);\n    }\n \n    ll size(ll x){\n        return s[root(x)];\n    }\n};\nint main(void){\n    ll n;\n    cin >> n;\n    vector<pair<pair<ll,ll>,ll>> vecx, vecy;\n    rep(i, n){\n        ll x, y;\n        cin >> x >> y;\n        vecx.push_back({{x, y}, i});\n    }\n\n    sort(all(vecx));\n\n    UnionFind uf(n);\n    vector<pair<ll,ll>> mi(200200, {INF, INF});\n    set<pair<ll,ll>> rt;\n    for(ll i = 0; i < n; i++){\n        for(auto &j : rt){\n            if(j.first < vecx[i].first.second){\n                uf.unite(vecx[i].second, j.second);\n            } else {\n                break;\n            }\n        }\n        ll root = uf.root(vecx[i].second);\n        if(mi[root].first > vecx[i].first.second){\n            rt.erase({mi[root].first, root});\n            mi[root] = {vecx[i].first.second, vecx[i].second};\n            rt.insert({mi[root].first, root});\n        }\n    }\n\n    rep(i, n){\n        cout << uf.size(i) << endl;\n    }\n\n    \n}\n\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N cities on a 2D plane. The coordinate of the i-th city is (x_i, y_i). Here (x_1, x_2, \\dots, x_N) and (y_1, y_2, \\dots, y_N) are both permuations of (1, 2, \\dots, N).\n\nFor each k = 1,2,\\dots,N, find the answer to the following question:\n\nRng is in City k.\nRng can perform the following move arbitrarily many times:\n\nmove to another city that has a smaller x-coordinate and a smaller y-coordinate, or a larger x-coordinate and a larger y-coordinate, than the city he is currently in.\n\nHow many cities (including City k) are reachable from City k?\n\nConstraints\n\n1 \\leq N \\leq 200,000\n\n(x_1, x_2, \\dots, x_N) is a permutation of (1, 2, \\dots, N).\n\n(y_1, y_2, \\dots, y_N) is a permutation of (1, 2, \\dots, N).\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nx_1 y_1\nx_2 y_2\n:\nx_N y_N\n\nOutput\n\nPrint N lines. In i-th line print the answer to the question when k = i.\n\nSample Input 1\n\n4\n1 4\n2 3\n3 1\n4 2\n\nSample Output 1\n\n1\n1\n2\n2\n\nRng can reach City 4 from City 3, or conversely City 3 from City 4.\n\nSample Input 2\n\n7\n6 4\n4 3\n3 5\n7 1\n2 7\n5 2\n1 6\n\nSample Output 2\n\n3\n3\n1\n1\n2\n3\n2", "sample_input": "4\n1 4\n2 3\n3 1\n4 2\n"}, "reference_outputs": ["1\n1\n2\n2\n"], "source_document_id": "p02540", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N cities on a 2D plane. The coordinate of the i-th city is (x_i, y_i). Here (x_1, x_2, \\dots, x_N) and (y_1, y_2, \\dots, y_N) are both permuations of (1, 2, \\dots, N).\n\nFor each k = 1,2,\\dots,N, find the answer to the following question:\n\nRng is in City k.\nRng can perform the following move arbitrarily many times:\n\nmove to another city that has a smaller x-coordinate and a smaller y-coordinate, or a larger x-coordinate and a larger y-coordinate, than the city he is currently in.\n\nHow many cities (including City k) are reachable from City k?\n\nConstraints\n\n1 \\leq N \\leq 200,000\n\n(x_1, x_2, \\dots, x_N) is a permutation of (1, 2, \\dots, N).\n\n(y_1, y_2, \\dots, y_N) is a permutation of (1, 2, \\dots, N).\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nx_1 y_1\nx_2 y_2\n:\nx_N y_N\n\nOutput\n\nPrint N lines. In i-th line print the answer to the question when k = i.\n\nSample Input 1\n\n4\n1 4\n2 3\n3 1\n4 2\n\nSample Output 1\n\n1\n1\n2\n2\n\nRng can reach City 4 from City 3, or conversely City 3 from City 4.\n\nSample Input 2\n\n7\n6 4\n4 3\n3 5\n7 1\n2 7\n5 2\n1 6\n\nSample Output 2\n\n3\n3\n1\n1\n2\n3\n2", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 3229, "cpu_time_ms": 393, "memory_kb": 19096}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s980028051", "group_id": "codeNet:p02546", "input_text": "#pragma GCC optimize(2)\n#include<iostream> \n#include<cstdio> \n#include<cstring> \n#include<algorithm> \n#include<map> \n#define File(x) freopen(x\".in\",\"r\",stdin),freopen(x\".out\",\"w\",stdout);\n#define re register\n#define ri re int\n#define gtch() (p1==p2&&(p2=(p1=buf)+fread(buf,1,1<<21,stdin),p1==p2)?EOF:*p1++)\n#define For(i,a,b) for(ri i=a;i<=b;++i) \n#define iFor(i,a,b) for(ri i=a;i>=b;--i) \nusing namespace std;\ntypedef long long ll;\nchar buf[1<<21],*p1=buf,*p2=buf;\ninline ll fr()\n{\n\tre char ch=getchar();re ll res=0;int bl=0;\n\twhile(!isdigit(ch)) bl=(ch=='-'),ch=getchar();\n\twhile(isdigit(ch)) res=(res<<1)+(res<<3)+ch-'0',ch=getchar();\n\treturn bl?-res:res;\n}\nconst int MAXN=100;\nconst int INF=9e8+5;\nstring s; \nsigned main()\n{\n//\tFile(\"temp\")\n\tcin>>s;\n\tcout<<s;\n\tif(s[s.size()-1]=='s')cout<<\"es\";\n\telse cout<<\"s\";\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1600542255, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02546.html", "problem_id": "p02546", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02546/input.txt", "sample_output_relpath": "derived/input_output/data/p02546/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02546/C++/s980028051.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s980028051", "user_id": "u678679558"}, "prompt_components": {"gold_output": "apples\n", "input_to_evaluate": "#pragma GCC optimize(2)\n#include<iostream> \n#include<cstdio> \n#include<cstring> \n#include<algorithm> \n#include<map> \n#define File(x) freopen(x\".in\",\"r\",stdin),freopen(x\".out\",\"w\",stdout);\n#define re register\n#define ri re int\n#define gtch() (p1==p2&&(p2=(p1=buf)+fread(buf,1,1<<21,stdin),p1==p2)?EOF:*p1++)\n#define For(i,a,b) for(ri i=a;i<=b;++i) \n#define iFor(i,a,b) for(ri i=a;i>=b;--i) \nusing namespace std;\ntypedef long long ll;\nchar buf[1<<21],*p1=buf,*p2=buf;\ninline ll fr()\n{\n\tre char ch=getchar();re ll res=0;int bl=0;\n\twhile(!isdigit(ch)) bl=(ch=='-'),ch=getchar();\n\twhile(isdigit(ch)) res=(res<<1)+(res<<3)+ch-'0',ch=getchar();\n\treturn bl?-res:res;\n}\nconst int MAXN=100;\nconst int INF=9e8+5;\nstring s; \nsigned main()\n{\n//\tFile(\"temp\")\n\tcin>>s;\n\tcout<<s;\n\tif(s[s.size()-1]=='s')cout<<\"es\";\n\telse cout<<\"s\";\n\treturn 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nIn the Kingdom of AtCoder, people use a language called Taknese, which uses lowercase English letters.\n\nIn Taknese, the plural form of a noun is spelled based on the following rules:\n\nIf a noun's singular form does not end with s, append s to the end of the singular form.\n\nIf a noun's singular form ends with s, append es to the end of the singular form.\n\nYou are given the singular form S of a Taknese noun. Output its plural form.\n\nConstraints\n\nS is a string of length 1 between 1000, inclusive.\n\nS contains only lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the plural form of the given Taknese word.\n\nSample Input 1\n\napple\n\nSample Output 1\n\napples\n\napple ends with e, so its plural form is apples.\n\nSample Input 2\n\nbus\n\nSample Output 2\n\nbuses\n\nbus ends with s, so its plural form is buses.\n\nSample Input 3\n\nbox\n\nSample Output 3\n\nboxs", "sample_input": "apple\n"}, "reference_outputs": ["apples\n"], "source_document_id": "p02546", "source_text": "Score : 100 points\n\nProblem Statement\n\nIn the Kingdom of AtCoder, people use a language called Taknese, which uses lowercase English letters.\n\nIn Taknese, the plural form of a noun is spelled based on the following rules:\n\nIf a noun's singular form does not end with s, append s to the end of the singular form.\n\nIf a noun's singular form ends with s, append es to the end of the singular form.\n\nYou are given the singular form S of a Taknese noun. Output its plural form.\n\nConstraints\n\nS is a string of length 1 between 1000, inclusive.\n\nS contains only lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the plural form of the given Taknese word.\n\nSample Input 1\n\napple\n\nSample Output 1\n\napples\n\napple ends with e, so its plural form is apples.\n\nSample Input 2\n\nbus\n\nSample Output 2\n\nbuses\n\nbus ends with s, so its plural form is buses.\n\nSample Input 3\n\nbox\n\nSample Output 3\n\nboxs", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 828, "cpu_time_ms": 9, "memory_kb": 3676}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s894285008", "group_id": "codeNet:p02547", "input_text": "/*input\n6\n1 1\n2 2\n3 3\n4 4\n5 5\n6 6\n*/\n\n#include <bits/stdc++.h>\n#define rep(i, n) for (int i = 0; i < (n); ++i)\nusing namespace std;\nusing ll = long long;\nusing P = pair<int, int>;\n\nint main() {\n  int n;\n  cin >> n;\n  int cnt = 0;\n  rep(i, n) {\n    int a, b;\n    cin >> a >> b;\n    if (a == b) {\n      cnt++;\n      if (cnt == 3) {\n        cout << \"Yes\" << endl;\n        return 0;\n      }\n    }\n    else cnt = 0;\n  }\n  cout << \"No\" << endl;\n}", "language": "C++", "metadata": {"date": 1600542346, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02547.html", "problem_id": "p02547", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02547/input.txt", "sample_output_relpath": "derived/input_output/data/p02547/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02547/C++/s894285008.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s894285008", "user_id": "u965602776"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "/*input\n6\n1 1\n2 2\n3 3\n4 4\n5 5\n6 6\n*/\n\n#include <bits/stdc++.h>\n#define rep(i, n) for (int i = 0; i < (n); ++i)\nusing namespace std;\nusing ll = long long;\nusing P = pair<int, int>;\n\nint main() {\n  int n;\n  cin >> n;\n  int cnt = 0;\n  rep(i, n) {\n    int a, b;\n    cin >> a >> b;\n    if (a == b) {\n      cnt++;\n      if (cnt == 3) {\n        cout << \"Yes\" << endl;\n        return 0;\n      }\n    }\n    else cnt = 0;\n  }\n  cout << \"No\" << endl;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nTak performed the following action N times: rolling two dice.\nThe result of the i-th roll is D_{i,1} and D_{i,2}.\n\nCheck if doublets occurred at least three times in a row.\nSpecifically, check if there exists at lease one i such that D_{i,1}=D_{i,2}, D_{i+1,1}=D_{i+1,2} and D_{i+2,1}=D_{i+2,2} hold.\n\nConstraints\n\n3 \\leq N \\leq 100\n\n1\\leq D_{i,j} \\leq 6\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nD_{1,1} D_{1,2}\n\\vdots\nD_{N,1} D_{N,2}\n\nOutput\n\nPrint Yes if doublets occurred at least three times in a row. Print No otherwise.\n\nSample Input 1\n\n5\n1 2\n6 6\n4 4\n3 3\n3 2\n\nSample Output 1\n\nYes\n\nFrom the second roll to the fourth roll, three doublets occurred in a row.\n\nSample Input 2\n\n5\n1 1\n2 2\n3 4\n5 5\n6 6\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n6\n1 1\n2 2\n3 3\n4 4\n5 5\n6 6\n\nSample Output 3\n\nYes", "sample_input": "5\n1 2\n6 6\n4 4\n3 3\n3 2\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p02547", "source_text": "Score : 200 points\n\nProblem Statement\n\nTak performed the following action N times: rolling two dice.\nThe result of the i-th roll is D_{i,1} and D_{i,2}.\n\nCheck if doublets occurred at least three times in a row.\nSpecifically, check if there exists at lease one i such that D_{i,1}=D_{i,2}, D_{i+1,1}=D_{i+1,2} and D_{i+2,1}=D_{i+2,2} hold.\n\nConstraints\n\n3 \\leq N \\leq 100\n\n1\\leq D_{i,j} \\leq 6\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nD_{1,1} D_{1,2}\n\\vdots\nD_{N,1} D_{N,2}\n\nOutput\n\nPrint Yes if doublets occurred at least three times in a row. Print No otherwise.\n\nSample Input 1\n\n5\n1 2\n6 6\n4 4\n3 3\n3 2\n\nSample Output 1\n\nYes\n\nFrom the second roll to the fourth roll, three doublets occurred in a row.\n\nSample Input 2\n\n5\n1 1\n2 2\n3 4\n5 5\n6 6\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n6\n1 1\n2 2\n3 3\n4 4\n5 5\n6 6\n\nSample Output 3\n\nYes", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 440, "cpu_time_ms": 6, "memory_kb": 3628}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s941211544", "group_id": "codeNet:p02547", "input_text": "// #pragma GCC optimize(\"Ofast\")\n// #pragma GCC target(\"avx,avx2,fma\")\n// #pragma GCC optimization (\"unroll-loops\")\n\n#include<bits/stdc++.h>\n#include <ext/pb_ds/assoc_container.hpp>\n#include <ext/pb_ds/tree_policy.hpp>\nusing namespace __gnu_pbds;\nusing namespace std;\n\n#define fo(i,n)             for(int i=0;i<n;i++)\n#define nl                  \"\\n\"\n#define ff                  first\n#define ss                  second\n#define int                 long long\n#define pb                  push_back\n#define mp                  make_pair\n#define vec(x)              vector<x>\n#define matrix(x)           vector<vector<x>>\n#define sz(x)               (int)x.size()\n#define mem(a,b)            memset(a, b, sizeof a)\n#define vii                 vector<pair<int,int>>\n#define pii                 pair<int,int>\n#define vi                  vector<int>\n#define mii                 map<int,int>\n#define uii                 unordered_map<int,int,custom_hash>\n#define pqb                 priority_queue<int>\n#define pqs                 priority_queue<int,vi,greater<int> >\n#define gcd(a,b)            __gcd(a,b)\n#define lcm(a,b)            (a*(b/gcd(a,b)))\n#define setbits(x)          __builtin_popcountll(x)\n#define zrobits(x)          __builtin_ctzll(x)\n#define mod                 1000000007\n#define MOD                 998244353\n#define inf                 1e18\n#define ps(x,y)             fixed<<setprecision(y)<<x\n#define mk(arr,n,type)      type *arr=new type[n];\n#define w(x)                int x; cin>>x; while(x--)\n#define all(v)              v.begin(),v.end()\n#define rep(i,begin,end)    for (__typeof(end) i = (begin) - ((begin) > (end)); i != (end) - ((begin) > (end)); i += 1 - 2 * ((begin) > (end)))\n#define len(s)              s.length()\n\n#define watch(x)            cout << #x << \" = \" << x << endl\n\n#define deb(...) cerr << \"[\" << #__VA_ARGS__ << \"] : [\", DBG(__VA_ARGS__)\nvoid DBG() { cerr << \"]\\n\";}\ntemplate<typename T, typename ...Args> void DBG(T first, Args... args)\n{cerr << first; if(sizeof...(args))cerr<<\", \"; DBG(args...); }\n\nmt19937                     rng(chrono::steady_clock::now().time_since_epoch().count());\n\ntypedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> pbds; //for storing unique elements\ntypedef tree<int , null_type , less_equal<int> , rb_tree_tag , tree_order_statistics_node_update> ordered_set; //for repeating elements\n \nint power(int a,int b,int m=mod)\n{int ans=1;while(b>0){if(b&1)ans=(ans*a)%m;a=(a*a)%m;b>>=1;}\nreturn ans;}\n\nvoid babuBhaiya()\n{\n\n    ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);\n}\n\nstruct custom_hash {\n    static uint64_t splitmix64(uint64_t x) {\n        x += 0x9e3779b97f4a7c15;\n        x = (x ^ (x >> 30)) * 0xbf58476d1ce4e5b9;\n        x = (x ^ (x >> 27)) * 0x94d049bb133111eb;\n        return x ^ (x >> 31);\n    }\n\n    size_t operator()(uint64_t x) const {\n        static const uint64_t FIXED_RANDOM = chrono::steady_clock::now().time_since_epoch().count();\n        return splitmix64(x + FIXED_RANDOM);\n    }\n};\n\nconst int N = 1e5+1;\nconst double pi = acos(-1);\n\n/*/-----------------------Modular Arithmetic---------------/*/\ninline int add(int x,int y){\n    x+=y;\n    if (x>=mod) return x-mod;\n    return x;\n}\ninline int sub(int x,int y){\n    x-=y;\n    if (x<0) return x+mod;\n    return x;\n}\ninline int mul(int x,int y){\n    return (x*1ll*y)%mod;\n}\n/*/-----------------------------Code begins----------------------------------/*/\n\nvoid solve(){\n\n    int n; cin>>n;\n    vi v;\n    fo(i,n){\n        int a,b; cin>>a>>b;\n        if(a == b) v.pb(i);\n    }\n    if(sz(v)<3){\n        cout<<\"No\\n\";\n    }\n    else{\n        bool flag = false;\n        for(int i = 2;i<sz(v);i++){\n            if(v[i]==v[i-1]+1 and v[i-1]==v[i-2]+1){\n                flag = true;\n                break;\n            }\n        }   \n        if(flag) cout<<\"Yes\";\n        else cout<<\"No\";\n    }\n\n}\n\n \nint32_t main()\n{\n    babuBhaiya();\n\n    int t;\n\n    t = 1;\n   // cin>>t;\n\n    while(t--){\n        solve();\n    }\n    \n    return 0;\n}", "language": "C++", "metadata": {"date": 1600542271, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02547.html", "problem_id": "p02547", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02547/input.txt", "sample_output_relpath": "derived/input_output/data/p02547/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02547/C++/s941211544.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s941211544", "user_id": "u774649089"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "// #pragma GCC optimize(\"Ofast\")\n// #pragma GCC target(\"avx,avx2,fma\")\n// #pragma GCC optimization (\"unroll-loops\")\n\n#include<bits/stdc++.h>\n#include <ext/pb_ds/assoc_container.hpp>\n#include <ext/pb_ds/tree_policy.hpp>\nusing namespace __gnu_pbds;\nusing namespace std;\n\n#define fo(i,n)             for(int i=0;i<n;i++)\n#define nl                  \"\\n\"\n#define ff                  first\n#define ss                  second\n#define int                 long long\n#define pb                  push_back\n#define mp                  make_pair\n#define vec(x)              vector<x>\n#define matrix(x)           vector<vector<x>>\n#define sz(x)               (int)x.size()\n#define mem(a,b)            memset(a, b, sizeof a)\n#define vii                 vector<pair<int,int>>\n#define pii                 pair<int,int>\n#define vi                  vector<int>\n#define mii                 map<int,int>\n#define uii                 unordered_map<int,int,custom_hash>\n#define pqb                 priority_queue<int>\n#define pqs                 priority_queue<int,vi,greater<int> >\n#define gcd(a,b)            __gcd(a,b)\n#define lcm(a,b)            (a*(b/gcd(a,b)))\n#define setbits(x)          __builtin_popcountll(x)\n#define zrobits(x)          __builtin_ctzll(x)\n#define mod                 1000000007\n#define MOD                 998244353\n#define inf                 1e18\n#define ps(x,y)             fixed<<setprecision(y)<<x\n#define mk(arr,n,type)      type *arr=new type[n];\n#define w(x)                int x; cin>>x; while(x--)\n#define all(v)              v.begin(),v.end()\n#define rep(i,begin,end)    for (__typeof(end) i = (begin) - ((begin) > (end)); i != (end) - ((begin) > (end)); i += 1 - 2 * ((begin) > (end)))\n#define len(s)              s.length()\n\n#define watch(x)            cout << #x << \" = \" << x << endl\n\n#define deb(...) cerr << \"[\" << #__VA_ARGS__ << \"] : [\", DBG(__VA_ARGS__)\nvoid DBG() { cerr << \"]\\n\";}\ntemplate<typename T, typename ...Args> void DBG(T first, Args... args)\n{cerr << first; if(sizeof...(args))cerr<<\", \"; DBG(args...); }\n\nmt19937                     rng(chrono::steady_clock::now().time_since_epoch().count());\n\ntypedef tree<int, null_type, less<int>, rb_tree_tag, tree_order_statistics_node_update> pbds; //for storing unique elements\ntypedef tree<int , null_type , less_equal<int> , rb_tree_tag , tree_order_statistics_node_update> ordered_set; //for repeating elements\n \nint power(int a,int b,int m=mod)\n{int ans=1;while(b>0){if(b&1)ans=(ans*a)%m;a=(a*a)%m;b>>=1;}\nreturn ans;}\n\nvoid babuBhaiya()\n{\n\n    ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);\n}\n\nstruct custom_hash {\n    static uint64_t splitmix64(uint64_t x) {\n        x += 0x9e3779b97f4a7c15;\n        x = (x ^ (x >> 30)) * 0xbf58476d1ce4e5b9;\n        x = (x ^ (x >> 27)) * 0x94d049bb133111eb;\n        return x ^ (x >> 31);\n    }\n\n    size_t operator()(uint64_t x) const {\n        static const uint64_t FIXED_RANDOM = chrono::steady_clock::now().time_since_epoch().count();\n        return splitmix64(x + FIXED_RANDOM);\n    }\n};\n\nconst int N = 1e5+1;\nconst double pi = acos(-1);\n\n/*/-----------------------Modular Arithmetic---------------/*/\ninline int add(int x,int y){\n    x+=y;\n    if (x>=mod) return x-mod;\n    return x;\n}\ninline int sub(int x,int y){\n    x-=y;\n    if (x<0) return x+mod;\n    return x;\n}\ninline int mul(int x,int y){\n    return (x*1ll*y)%mod;\n}\n/*/-----------------------------Code begins----------------------------------/*/\n\nvoid solve(){\n\n    int n; cin>>n;\n    vi v;\n    fo(i,n){\n        int a,b; cin>>a>>b;\n        if(a == b) v.pb(i);\n    }\n    if(sz(v)<3){\n        cout<<\"No\\n\";\n    }\n    else{\n        bool flag = false;\n        for(int i = 2;i<sz(v);i++){\n            if(v[i]==v[i-1]+1 and v[i-1]==v[i-2]+1){\n                flag = true;\n                break;\n            }\n        }   \n        if(flag) cout<<\"Yes\";\n        else cout<<\"No\";\n    }\n\n}\n\n \nint32_t main()\n{\n    babuBhaiya();\n\n    int t;\n\n    t = 1;\n   // cin>>t;\n\n    while(t--){\n        solve();\n    }\n    \n    return 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nTak performed the following action N times: rolling two dice.\nThe result of the i-th roll is D_{i,1} and D_{i,2}.\n\nCheck if doublets occurred at least three times in a row.\nSpecifically, check if there exists at lease one i such that D_{i,1}=D_{i,2}, D_{i+1,1}=D_{i+1,2} and D_{i+2,1}=D_{i+2,2} hold.\n\nConstraints\n\n3 \\leq N \\leq 100\n\n1\\leq D_{i,j} \\leq 6\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nD_{1,1} D_{1,2}\n\\vdots\nD_{N,1} D_{N,2}\n\nOutput\n\nPrint Yes if doublets occurred at least three times in a row. Print No otherwise.\n\nSample Input 1\n\n5\n1 2\n6 6\n4 4\n3 3\n3 2\n\nSample Output 1\n\nYes\n\nFrom the second roll to the fourth roll, three doublets occurred in a row.\n\nSample Input 2\n\n5\n1 1\n2 2\n3 4\n5 5\n6 6\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n6\n1 1\n2 2\n3 3\n4 4\n5 5\n6 6\n\nSample Output 3\n\nYes", "sample_input": "5\n1 2\n6 6\n4 4\n3 3\n3 2\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p02547", "source_text": "Score : 200 points\n\nProblem Statement\n\nTak performed the following action N times: rolling two dice.\nThe result of the i-th roll is D_{i,1} and D_{i,2}.\n\nCheck if doublets occurred at least three times in a row.\nSpecifically, check if there exists at lease one i such that D_{i,1}=D_{i,2}, D_{i+1,1}=D_{i+1,2} and D_{i+2,1}=D_{i+2,2} hold.\n\nConstraints\n\n3 \\leq N \\leq 100\n\n1\\leq D_{i,j} \\leq 6\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nD_{1,1} D_{1,2}\n\\vdots\nD_{N,1} D_{N,2}\n\nOutput\n\nPrint Yes if doublets occurred at least three times in a row. Print No otherwise.\n\nSample Input 1\n\n5\n1 2\n6 6\n4 4\n3 3\n3 2\n\nSample Output 1\n\nYes\n\nFrom the second roll to the fourth roll, three doublets occurred in a row.\n\nSample Input 2\n\n5\n1 1\n2 2\n3 4\n5 5\n6 6\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n6\n1 1\n2 2\n3 3\n4 4\n5 5\n6 6\n\nSample Output 3\n\nYes", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 4007, "cpu_time_ms": 8, "memory_kb": 3656}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s274538368", "group_id": "codeNet:p02548", "input_text": "#include <iostream>\n\nusing namespace std;\nint counting(int x) {\n    int ans = 0;\n    for (int i=1; i * i <= x; i++) {\n        if (x % i == 0) {\n            if (i * i == x) ans++;\n            else ans += 2;\n        }\n    }\n    return ans;\n}\nint main() {\n    int N;\n    cin >> N;\n    int ans = 0;\n    for (int nc = 1; nc <= N-1; nc++) {\n        ans += counting(nc);\n    }\n    cout << ans << endl;\n    return 0;\n}\n\n", "language": "C++", "metadata": {"date": 1600542633, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02548.html", "problem_id": "p02548", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02548/input.txt", "sample_output_relpath": "derived/input_output/data/p02548/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02548/C++/s274538368.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s274538368", "user_id": "u721980697"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <iostream>\n\nusing namespace std;\nint counting(int x) {\n    int ans = 0;\n    for (int i=1; i * i <= x; i++) {\n        if (x % i == 0) {\n            if (i * i == x) ans++;\n            else ans += 2;\n        }\n    }\n    return ans;\n}\nint main() {\n    int N;\n    cin >> N;\n    int ans = 0;\n    for (int nc = 1; nc <= N-1; nc++) {\n        ans += counting(nc);\n    }\n    cout << ans << endl;\n    return 0;\n}\n\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nGiven is a positive integer N.\nHow many tuples (A,B,C) of positive integers satisfy A \\times B + C = N?\n\nConstraints\n\n2 \\leq N \\leq 10^6\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n3\n\nSample Output 1\n\n3\n\nThere are 3 tuples of integers that satisfy A \\times B + C = 3: (A, B, C) = (1, 1, 2), (1, 2, 1), (2, 1, 1).\n\nSample Input 2\n\n100\n\nSample Output 2\n\n473\n\nSample Input 3\n\n1000000\n\nSample Output 3\n\n13969985", "sample_input": "3\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02548", "source_text": "Score : 300 points\n\nProblem Statement\n\nGiven is a positive integer N.\nHow many tuples (A,B,C) of positive integers satisfy A \\times B + C = N?\n\nConstraints\n\n2 \\leq N \\leq 10^6\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n3\n\nSample Output 1\n\n3\n\nThere are 3 tuples of integers that satisfy A \\times B + C = 3: (A, B, C) = (1, 1, 2), (1, 2, 1), (2, 1, 1).\n\nSample Input 2\n\n100\n\nSample Output 2\n\n473\n\nSample Input 3\n\n1000000\n\nSample Output 3\n\n13969985", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 412, "cpu_time_ms": 1865, "memory_kb": 3652}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s807528182", "group_id": "codeNet:p02549", "input_text": "#include<bits/stdc++.h>\ntypedef long long int lli;\n\n#define em emplace_back\n#define rep(i,j,n) for(lli i=j;i<n;i++)\n#define repf(i,a,j,n) for(lli i=j,a=0;i<n;i++,a++)\n#define repg(i,j,n) for(int i=j;i>n;--i)\nusing namespace std;\nlli m = 998244353;\n\nvoid solve(){\n\n    lli n,k;\n    cin>>n>>k;\n\n    vector<lli> v;\n\n    vector<lli> arrfront(n+1,0);\n\n    unordered_map<lli,lli> s;\n    \n    rep(i,0,k){\n        lli a,b;\n        cin>>a>>b;\n        if(a==b){\n            v.em(a);\n            continue;\n        }\n        rep(j,a,b+1){\n            v.em(j);\n        }\n    }\n\n    vector<lli> arrback(n+1,0);\n    sort(v.begin(), v.end());\n    lli ans = 0;\n    rep(i,1,n){\n\n        if(arrfront[i]==0){\n            if(i!=1){\n                continue;\n            }else{\n                arrfront[i] = 1;\n            }\n        }\n\n        rep(j,0,v.size()){\n            if(i+v[j]>n){\n                break;\n            }\n            arrfront[i+v[j]] = arrfront[i+v[j]]%m;\n            arrfront[i+v[j]] = (arrfront[i+v[j]]%m + arrfront[i]%m)%m;\n            arrfront[i+v[j]] = arrfront[i+v[j]]%m; \n            \n        }\n    }\n\n    cout<<(arrfront[n]%m);\n\n}\n \n \nint main(){\n    ios_base::sync_with_stdio(false);\n    cin.tie(NULL);\n    solve();\n \n    return 0;\n}", "language": "C++", "metadata": {"date": 1600719186, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02549.html", "problem_id": "p02549", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02549/input.txt", "sample_output_relpath": "derived/input_output/data/p02549/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02549/C++/s807528182.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s807528182", "user_id": "u666281192"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include<bits/stdc++.h>\ntypedef long long int lli;\n\n#define em emplace_back\n#define rep(i,j,n) for(lli i=j;i<n;i++)\n#define repf(i,a,j,n) for(lli i=j,a=0;i<n;i++,a++)\n#define repg(i,j,n) for(int i=j;i>n;--i)\nusing namespace std;\nlli m = 998244353;\n\nvoid solve(){\n\n    lli n,k;\n    cin>>n>>k;\n\n    vector<lli> v;\n\n    vector<lli> arrfront(n+1,0);\n\n    unordered_map<lli,lli> s;\n    \n    rep(i,0,k){\n        lli a,b;\n        cin>>a>>b;\n        if(a==b){\n            v.em(a);\n            continue;\n        }\n        rep(j,a,b+1){\n            v.em(j);\n        }\n    }\n\n    vector<lli> arrback(n+1,0);\n    sort(v.begin(), v.end());\n    lli ans = 0;\n    rep(i,1,n){\n\n        if(arrfront[i]==0){\n            if(i!=1){\n                continue;\n            }else{\n                arrfront[i] = 1;\n            }\n        }\n\n        rep(j,0,v.size()){\n            if(i+v[j]>n){\n                break;\n            }\n            arrfront[i+v[j]] = arrfront[i+v[j]]%m;\n            arrfront[i+v[j]] = (arrfront[i+v[j]]%m + arrfront[i]%m)%m;\n            arrfront[i+v[j]] = arrfront[i+v[j]]%m; \n            \n        }\n    }\n\n    cout<<(arrfront[n]%m);\n\n}\n \n \nint main(){\n    ios_base::sync_with_stdio(false);\n    cin.tie(NULL);\n    solve();\n \n    return 0;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nThere are N cells arranged in a row, numbered 1, 2, \\ldots, N from left to right.\n\nTak lives in these cells and is currently on Cell 1. He is trying to reach Cell N by using the procedure described below.\n\nYou are given an integer K that is less than or equal to 10, and K non-intersecting segments [L_1, R_1], [L_2, R_2], \\ldots, [L_K, R_K].\nLet S be the union of these K segments.\nHere, the segment [l, r] denotes the set consisting of all integers i that satisfy l \\leq i \\leq r.\n\n\bWhen you are on Cell i, pick an integer d from S and move to Cell i + d. You cannot move out of the cells.\n\nTo help Tak, find the number of ways to go to Cell N, modulo 998244353.\n\nConstraints\n\n2 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq K \\leq \\min(N, 10)\n\n1 \\leq L_i \\leq R_i \\leq N\n\n[L_i, R_i] and [L_j, R_j] do not intersect (i \\neq j)\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nL_1 R_1\nL_2 R_2\n:\nL_K R_K\n\nOutput\n\nPrint the number of ways for Tak to go from Cell 1 to Cell N, modulo 998244353.\n\nSample Input 1\n\n5 2\n1 1\n3 4\n\nSample Output 1\n\n4\n\nThe set S is the union of the segment [1, 1] and the segment [3, 4], therefore S = \\{ 1, 3, 4 \\} holds.\n\nThere are 4 possible ways to get to Cell 5:\n\n1 \\to 2 \\to 3 \\to 4 \\to 5,\n\n1 \\to 2 \\to 5,\n\n1 \\to 4 \\to 5 and\n\n1 \\to 5.\n\nSample Input 2\n\n5 2\n3 3\n5 5\n\nSample Output 2\n\n0\n\nBecause S = \\{ 3, 5 \\} holds, you cannot reach to Cell 5.\nPrint 0.\n\nSample Input 3\n\n5 1\n1 2\n\nSample Output 3\n\n5\n\nSample Input 4\n\n60 3\n5 8\n1 3\n10 15\n\nSample Output 4\n\n221823067\n\nNote that you have to print the answer modulo 998244353.", "sample_input": "5 2\n1 1\n3 4\n"}, "reference_outputs": ["4\n"], "source_document_id": "p02549", "source_text": "Score : 400 points\n\nProblem Statement\n\nThere are N cells arranged in a row, numbered 1, 2, \\ldots, N from left to right.\n\nTak lives in these cells and is currently on Cell 1. He is trying to reach Cell N by using the procedure described below.\n\nYou are given an integer K that is less than or equal to 10, and K non-intersecting segments [L_1, R_1], [L_2, R_2], \\ldots, [L_K, R_K].\nLet S be the union of these K segments.\nHere, the segment [l, r] denotes the set consisting of all integers i that satisfy l \\leq i \\leq r.\n\n\bWhen you are on Cell i, pick an integer d from S and move to Cell i + d. You cannot move out of the cells.\n\nTo help Tak, find the number of ways to go to Cell N, modulo 998244353.\n\nConstraints\n\n2 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq K \\leq \\min(N, 10)\n\n1 \\leq L_i \\leq R_i \\leq N\n\n[L_i, R_i] and [L_j, R_j] do not intersect (i \\neq j)\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nL_1 R_1\nL_2 R_2\n:\nL_K R_K\n\nOutput\n\nPrint the number of ways for Tak to go from Cell 1 to Cell N, modulo 998244353.\n\nSample Input 1\n\n5 2\n1 1\n3 4\n\nSample Output 1\n\n4\n\nThe set S is the union of the segment [1, 1] and the segment [3, 4], therefore S = \\{ 1, 3, 4 \\} holds.\n\nThere are 4 possible ways to get to Cell 5:\n\n1 \\to 2 \\to 3 \\to 4 \\to 5,\n\n1 \\to 2 \\to 5,\n\n1 \\to 4 \\to 5 and\n\n1 \\to 5.\n\nSample Input 2\n\n5 2\n3 3\n5 5\n\nSample Output 2\n\n0\n\nBecause S = \\{ 3, 5 \\} holds, you cannot reach to Cell 5.\nPrint 0.\n\nSample Input 3\n\n5 1\n1 2\n\nSample Output 3\n\n5\n\nSample Input 4\n\n60 3\n5 8\n1 3\n10 15\n\nSample Output 4\n\n221823067\n\nNote that you have to print the answer modulo 998244353.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1241, "cpu_time_ms": 2205, "memory_kb": 8048}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s783213358", "group_id": "codeNet:p02549", "input_text": "#include<iostream>\n#include<vector>\nusing LL = long long;\nusing namespace std;\nint mod = 998244353;\nint main() {\n\tLL N, K;\n\tcin >> N >> K;\n\tvector<LL> Li(K), Ri(K);\n\tvector<bool> S_has(N + 1, false);\n\tfor (int i = 0; i < K; i++) {\n\t\tcin >> Li[i] >> Ri[i];\n\t\tfor (int j = Li[i]; j <= Ri[i]; j++) {\n\t\t\tS_has[j] = true;\n\t\t}\n\t}\n\tvector<LL> Dp(N + 1, 0);\n\tDp[1] = 1;\n\n\tfor (int i = 2; i <= N; i++) {\n\t\tDp[i] += Dp[i - 1];\n\t\tfor (int k = 0; k < K; k++) {\n\t\t\tif (i - Li[k] > 0) {\n\t\t\t\tDp[i] += Dp[i - Li[k]];\n\t\t\t}\n\t\t\tif (i - Ri[k] - 1 > 0) {\n\t\t\t\tDp[i] -= Dp[i - Ri[k] - 1];\n\t\t\t}\n\t\t}\n\t\twhile (Dp[i] < 0) {\n\t\t\tDp[i] += mod;\n\t\t}\n\t\tDp[i] = Dp[i] % mod;\n\n\t}\n\tLL ans = Dp[N] - Dp[N - 1];\n\twhile (ans < 0) {\n\t\tans += mod;\n\t}\n\tcout << ans << endl;\n\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1600596600, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02549.html", "problem_id": "p02549", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02549/input.txt", "sample_output_relpath": "derived/input_output/data/p02549/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02549/C++/s783213358.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s783213358", "user_id": "u608654778"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include<iostream>\n#include<vector>\nusing LL = long long;\nusing namespace std;\nint mod = 998244353;\nint main() {\n\tLL N, K;\n\tcin >> N >> K;\n\tvector<LL> Li(K), Ri(K);\n\tvector<bool> S_has(N + 1, false);\n\tfor (int i = 0; i < K; i++) {\n\t\tcin >> Li[i] >> Ri[i];\n\t\tfor (int j = Li[i]; j <= Ri[i]; j++) {\n\t\t\tS_has[j] = true;\n\t\t}\n\t}\n\tvector<LL> Dp(N + 1, 0);\n\tDp[1] = 1;\n\n\tfor (int i = 2; i <= N; i++) {\n\t\tDp[i] += Dp[i - 1];\n\t\tfor (int k = 0; k < K; k++) {\n\t\t\tif (i - Li[k] > 0) {\n\t\t\t\tDp[i] += Dp[i - Li[k]];\n\t\t\t}\n\t\t\tif (i - Ri[k] - 1 > 0) {\n\t\t\t\tDp[i] -= Dp[i - Ri[k] - 1];\n\t\t\t}\n\t\t}\n\t\twhile (Dp[i] < 0) {\n\t\t\tDp[i] += mod;\n\t\t}\n\t\tDp[i] = Dp[i] % mod;\n\n\t}\n\tLL ans = Dp[N] - Dp[N - 1];\n\twhile (ans < 0) {\n\t\tans += mod;\n\t}\n\tcout << ans << endl;\n\n\treturn 0;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nThere are N cells arranged in a row, numbered 1, 2, \\ldots, N from left to right.\n\nTak lives in these cells and is currently on Cell 1. He is trying to reach Cell N by using the procedure described below.\n\nYou are given an integer K that is less than or equal to 10, and K non-intersecting segments [L_1, R_1], [L_2, R_2], \\ldots, [L_K, R_K].\nLet S be the union of these K segments.\nHere, the segment [l, r] denotes the set consisting of all integers i that satisfy l \\leq i \\leq r.\n\n\bWhen you are on Cell i, pick an integer d from S and move to Cell i + d. You cannot move out of the cells.\n\nTo help Tak, find the number of ways to go to Cell N, modulo 998244353.\n\nConstraints\n\n2 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq K \\leq \\min(N, 10)\n\n1 \\leq L_i \\leq R_i \\leq N\n\n[L_i, R_i] and [L_j, R_j] do not intersect (i \\neq j)\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nL_1 R_1\nL_2 R_2\n:\nL_K R_K\n\nOutput\n\nPrint the number of ways for Tak to go from Cell 1 to Cell N, modulo 998244353.\n\nSample Input 1\n\n5 2\n1 1\n3 4\n\nSample Output 1\n\n4\n\nThe set S is the union of the segment [1, 1] and the segment [3, 4], therefore S = \\{ 1, 3, 4 \\} holds.\n\nThere are 4 possible ways to get to Cell 5:\n\n1 \\to 2 \\to 3 \\to 4 \\to 5,\n\n1 \\to 2 \\to 5,\n\n1 \\to 4 \\to 5 and\n\n1 \\to 5.\n\nSample Input 2\n\n5 2\n3 3\n5 5\n\nSample Output 2\n\n0\n\nBecause S = \\{ 3, 5 \\} holds, you cannot reach to Cell 5.\nPrint 0.\n\nSample Input 3\n\n5 1\n1 2\n\nSample Output 3\n\n5\n\nSample Input 4\n\n60 3\n5 8\n1 3\n10 15\n\nSample Output 4\n\n221823067\n\nNote that you have to print the answer modulo 998244353.", "sample_input": "5 2\n1 1\n3 4\n"}, "reference_outputs": ["4\n"], "source_document_id": "p02549", "source_text": "Score : 400 points\n\nProblem Statement\n\nThere are N cells arranged in a row, numbered 1, 2, \\ldots, N from left to right.\n\nTak lives in these cells and is currently on Cell 1. He is trying to reach Cell N by using the procedure described below.\n\nYou are given an integer K that is less than or equal to 10, and K non-intersecting segments [L_1, R_1], [L_2, R_2], \\ldots, [L_K, R_K].\nLet S be the union of these K segments.\nHere, the segment [l, r] denotes the set consisting of all integers i that satisfy l \\leq i \\leq r.\n\n\bWhen you are on Cell i, pick an integer d from S and move to Cell i + d. You cannot move out of the cells.\n\nTo help Tak, find the number of ways to go to Cell N, modulo 998244353.\n\nConstraints\n\n2 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq K \\leq \\min(N, 10)\n\n1 \\leq L_i \\leq R_i \\leq N\n\n[L_i, R_i] and [L_j, R_j] do not intersect (i \\neq j)\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nL_1 R_1\nL_2 R_2\n:\nL_K R_K\n\nOutput\n\nPrint the number of ways for Tak to go from Cell 1 to Cell N, modulo 998244353.\n\nSample Input 1\n\n5 2\n1 1\n3 4\n\nSample Output 1\n\n4\n\nThe set S is the union of the segment [1, 1] and the segment [3, 4], therefore S = \\{ 1, 3, 4 \\} holds.\n\nThere are 4 possible ways to get to Cell 5:\n\n1 \\to 2 \\to 3 \\to 4 \\to 5,\n\n1 \\to 2 \\to 5,\n\n1 \\to 4 \\to 5 and\n\n1 \\to 5.\n\nSample Input 2\n\n5 2\n3 3\n5 5\n\nSample Output 2\n\n0\n\nBecause S = \\{ 3, 5 \\} holds, you cannot reach to Cell 5.\nPrint 0.\n\nSample Input 3\n\n5 1\n1 2\n\nSample Output 3\n\n5\n\nSample Input 4\n\n60 3\n5 8\n1 3\n10 15\n\nSample Output 4\n\n221823067\n\nNote that you have to print the answer modulo 998244353.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 745, "cpu_time_ms": 18, "memory_kb": 4840}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s466928081", "group_id": "codeNet:p02550", "input_text": "#include <bits/stdc++.h>\n#include <set>\nusing namespace std;\nusing pii = pair<int,int>;\nusing pll = pair<long long, long long>;\nconst long long INF = 1<<29;\n\nconst int MOD = 1000000007;\nlong long ruizyou(long long m,long long n){\n  if(m == 0)return 0;\n  if(m == 1)return 1;\n  long long ans = 1;\n  long long tmp = m;\n  for(int i=0;i<=30;i++){\n    if(n & (1<<i)){\n      ans *= tmp;\n      ans %= MOD;\n    }\n    tmp *= tmp;\n    tmp %= MOD;\n  }\n  return ans;\n}\nlong long kaizyou(long long x){\n  if(x == 0)return 1;\n  return x * kaizyou(x-1) % MOD;\n}\nlong long comb(long long x,long long y){\n  long long bunsi = kaizyou(x);\n  long long bunbo = kaizyou(x-y) * kaizyou(y) % MOD;\n  return bunsi * ruizyou(bunbo,MOD-2) % MOD;\n}\nstruct unionfind{\n  vector<int> par;\n  vector<vector<int>> children;\n  vector<int> hukasa;\n  vector<int> kazu;\n  unionfind(int n){\n    par = vector<int>(n);\n    hukasa = vector<int>(n,0);\n    kazu = vector<int>(n,1);\n    for(int i=0;i<n;i++){\n      par.at(i) = i;\n    }\n  }\n  int root(int x){\n    if(par.at(x) == x)return x;\n    return root(par.at(x));\n  }\n  void unite(int x,int y){\n    int rx = root(x);\n    int ry = root(y);\n    if(rx == ry)return;\n    if(hukasa.at(rx) >= hukasa.at(ry)){\n      par.at(ry) = rx;\n      hukasa.at(rx) = max(hukasa.at(ry) + 1,hukasa.at(rx));\n      kazu.at(rx) += kazu.at(ry);\n    }\n    else{\n      par.at(rx) = ry;\n      kazu.at(ry) += kazu.at(rx);\n    }\n  }\n  void newkazu(){\n    int n = kazu.size();\n    for(int i=0;i<n;i++){\n      kazu.at(i) = kazu.at(root(i));\n    }\n  }\n  bool same(int x,int y){\n    return root(x) == root(y);\n  }\n};\nint ctoi(char a){\n  return a - '0';\n}\nlong long gcd(long long a,long long b){\n  long long c = max(a,b);\n  long long d = min(a,b);\n  if(d % c == 0)return c;\n  return gcd(c,d%c);\n}\nlong long lcm(long long a,long long b){\n  return a * b / gcd(a,b);\n}\nvoid hukasa(vector<vector<int>> s,vector<vector<int>> table,int &ans,pii frm,int n,int m){\n  int x,y;\n  tie(x,y) = frm;\n  set<pii> se;\n  if(x-1 >= 0)se.insert(pii(x-1,y));\n  if(x+1 < n)se.insert(pii(x+1,y));\n  if(y-1 >= 0)se.insert(pii(x,y-1));\n  if(y+1 < m)se.insert(pii(x,y+1));\n  for(auto t:se){\n    int tx,ty;\n    tie(tx,ty) = t;\n    if(s.at(tx).at(ty) && table.at(tx).at(ty) == -1){\n      table.at(tx).at(ty) = table.at(x).at(y) + 1;\n      ans = max(ans,table.at(tx).at(ty));\n      hukasa(s,table,ans,t,n,m);\n      table.at(tx).at(ty) = -1;\n    }\n  }\n}\nvoid daiku(int frm,vector<vector<pii>> g,vector<int> &cost,int n){\n  priority_queue<pii,vector<pii>,greater<pii>> q;\n  q.push(pii(cost.at(frm),frm));\n  vector<bool> kakutei(n,false);\n  while(!q.empty()){\n    pii now = q.top();\n    q.pop();\n    int n1,n2;\n    tie(n1,n2) = now;\n    if(kakutei.at(n2))continue;\n    kakutei.at(n2) = true;\n    for(auto t:g.at(n2)){\n      int tx,ty;\n      tie(tx,ty) = t;\n      if(cost.at(tx) > n1 + ty){\n        cost.at(tx) = n1 + ty;\n        q.push(pii(cost.at(tx),tx));\n      }\n    }\n  }\n}\n\nint main(){\n  long long n,x,m;\n  cin >> n >> x >> m;\n  long long a = 0;\n  long long b = 0;\n  int unko = n;\n  int flag = 0;\n  unordered_set<long long> se;\n  while(unko){\n    if(se.count(x)){\n      flag = 1;\n      break;\n    }\n    se.insert(x);\n    unko--;\n    b += x;\n    a++;\n    x *= x;\n    x %= m;\n    if(x == 0 || x == 1)break;\n  }\n  if(x == 0)cout << b << endl;\n  else if(x == 1){\n    //cout << 'n' << endl;\n    cout << b + n - a << endl;\n  }\n  else if(flag == 1){\n    long long ans = 0;\n    ans += b * (n/a);\n    n %= a;\n    for(int i=0;i<n;i++){\n      ans += x;\n      x *= x;\n      x %= m;\n    }\n    cout << ans << endl;\n  }\n  else cout << b <<endl;\n}", "language": "C++", "metadata": {"date": 1600547758, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02550.html", "problem_id": "p02550", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02550/input.txt", "sample_output_relpath": "derived/input_output/data/p02550/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02550/C++/s466928081.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s466928081", "user_id": "u953499988"}, "prompt_components": {"gold_output": "1369\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#include <set>\nusing namespace std;\nusing pii = pair<int,int>;\nusing pll = pair<long long, long long>;\nconst long long INF = 1<<29;\n\nconst int MOD = 1000000007;\nlong long ruizyou(long long m,long long n){\n  if(m == 0)return 0;\n  if(m == 1)return 1;\n  long long ans = 1;\n  long long tmp = m;\n  for(int i=0;i<=30;i++){\n    if(n & (1<<i)){\n      ans *= tmp;\n      ans %= MOD;\n    }\n    tmp *= tmp;\n    tmp %= MOD;\n  }\n  return ans;\n}\nlong long kaizyou(long long x){\n  if(x == 0)return 1;\n  return x * kaizyou(x-1) % MOD;\n}\nlong long comb(long long x,long long y){\n  long long bunsi = kaizyou(x);\n  long long bunbo = kaizyou(x-y) * kaizyou(y) % MOD;\n  return bunsi * ruizyou(bunbo,MOD-2) % MOD;\n}\nstruct unionfind{\n  vector<int> par;\n  vector<vector<int>> children;\n  vector<int> hukasa;\n  vector<int> kazu;\n  unionfind(int n){\n    par = vector<int>(n);\n    hukasa = vector<int>(n,0);\n    kazu = vector<int>(n,1);\n    for(int i=0;i<n;i++){\n      par.at(i) = i;\n    }\n  }\n  int root(int x){\n    if(par.at(x) == x)return x;\n    return root(par.at(x));\n  }\n  void unite(int x,int y){\n    int rx = root(x);\n    int ry = root(y);\n    if(rx == ry)return;\n    if(hukasa.at(rx) >= hukasa.at(ry)){\n      par.at(ry) = rx;\n      hukasa.at(rx) = max(hukasa.at(ry) + 1,hukasa.at(rx));\n      kazu.at(rx) += kazu.at(ry);\n    }\n    else{\n      par.at(rx) = ry;\n      kazu.at(ry) += kazu.at(rx);\n    }\n  }\n  void newkazu(){\n    int n = kazu.size();\n    for(int i=0;i<n;i++){\n      kazu.at(i) = kazu.at(root(i));\n    }\n  }\n  bool same(int x,int y){\n    return root(x) == root(y);\n  }\n};\nint ctoi(char a){\n  return a - '0';\n}\nlong long gcd(long long a,long long b){\n  long long c = max(a,b);\n  long long d = min(a,b);\n  if(d % c == 0)return c;\n  return gcd(c,d%c);\n}\nlong long lcm(long long a,long long b){\n  return a * b / gcd(a,b);\n}\nvoid hukasa(vector<vector<int>> s,vector<vector<int>> table,int &ans,pii frm,int n,int m){\n  int x,y;\n  tie(x,y) = frm;\n  set<pii> se;\n  if(x-1 >= 0)se.insert(pii(x-1,y));\n  if(x+1 < n)se.insert(pii(x+1,y));\n  if(y-1 >= 0)se.insert(pii(x,y-1));\n  if(y+1 < m)se.insert(pii(x,y+1));\n  for(auto t:se){\n    int tx,ty;\n    tie(tx,ty) = t;\n    if(s.at(tx).at(ty) && table.at(tx).at(ty) == -1){\n      table.at(tx).at(ty) = table.at(x).at(y) + 1;\n      ans = max(ans,table.at(tx).at(ty));\n      hukasa(s,table,ans,t,n,m);\n      table.at(tx).at(ty) = -1;\n    }\n  }\n}\nvoid daiku(int frm,vector<vector<pii>> g,vector<int> &cost,int n){\n  priority_queue<pii,vector<pii>,greater<pii>> q;\n  q.push(pii(cost.at(frm),frm));\n  vector<bool> kakutei(n,false);\n  while(!q.empty()){\n    pii now = q.top();\n    q.pop();\n    int n1,n2;\n    tie(n1,n2) = now;\n    if(kakutei.at(n2))continue;\n    kakutei.at(n2) = true;\n    for(auto t:g.at(n2)){\n      int tx,ty;\n      tie(tx,ty) = t;\n      if(cost.at(tx) > n1 + ty){\n        cost.at(tx) = n1 + ty;\n        q.push(pii(cost.at(tx),tx));\n      }\n    }\n  }\n}\n\nint main(){\n  long long n,x,m;\n  cin >> n >> x >> m;\n  long long a = 0;\n  long long b = 0;\n  int unko = n;\n  int flag = 0;\n  unordered_set<long long> se;\n  while(unko){\n    if(se.count(x)){\n      flag = 1;\n      break;\n    }\n    se.insert(x);\n    unko--;\n    b += x;\n    a++;\n    x *= x;\n    x %= m;\n    if(x == 0 || x == 1)break;\n  }\n  if(x == 0)cout << b << endl;\n  else if(x == 1){\n    //cout << 'n' << endl;\n    cout << b + n - a << endl;\n  }\n  else if(flag == 1){\n    long long ans = 0;\n    ans += b * (n/a);\n    n %= a;\n    for(int i=0;i<n;i++){\n      ans += x;\n      x *= x;\n      x %= m;\n    }\n    cout << ans << endl;\n  }\n  else cout << b <<endl;\n}", "problem_context": "Score : 500 points\n\nProblem Statement\n\nLet us denote by f(x, m) the remainder of the Euclidean division of x by m.\n\nLet A be the sequence that is defined by the initial value A_1=X and the recurrence relation A_{n+1} = f(A_n^2, M).\nFind \\displaystyle{\\sum_{i=1}^N A_i}.\n\nConstraints\n\n1 \\leq N \\leq 10^{10}\n\n0 \\leq X < M \\leq 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN X M\n\nOutput\n\nPrint \\displaystyle{\\sum_{i=1}^N A_i}.\n\nSample Input 1\n\n6 2 1001\n\nSample Output 1\n\n1369\n\nThe sequence A begins 2,4,16,256,471,620,\\ldots Therefore, the answer is 2+4+16+256+471+620=1369.\n\nSample Input 2\n\n1000 2 16\n\nSample Output 2\n\n6\n\nThe sequence A begins 2,4,0,0,\\ldots Therefore, the answer is 6.\n\nSample Input 3\n\n10000000000 10 99959\n\nSample Output 3\n\n492443256176507", "sample_input": "6 2 1001\n"}, "reference_outputs": ["1369\n"], "source_document_id": "p02550", "source_text": "Score : 500 points\n\nProblem Statement\n\nLet us denote by f(x, m) the remainder of the Euclidean division of x by m.\n\nLet A be the sequence that is defined by the initial value A_1=X and the recurrence relation A_{n+1} = f(A_n^2, M).\nFind \\displaystyle{\\sum_{i=1}^N A_i}.\n\nConstraints\n\n1 \\leq N \\leq 10^{10}\n\n0 \\leq X < M \\leq 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN X M\n\nOutput\n\nPrint \\displaystyle{\\sum_{i=1}^N A_i}.\n\nSample Input 1\n\n6 2 1001\n\nSample Output 1\n\n1369\n\nThe sequence A begins 2,4,16,256,471,620,\\ldots Therefore, the answer is 2+4+16+256+471+620=1369.\n\nSample Input 2\n\n1000 2 16\n\nSample Output 2\n\n6\n\nThe sequence A begins 2,4,0,0,\\ldots Therefore, the answer is 6.\n\nSample Input 3\n\n10000000000 10 99959\n\nSample Output 3\n\n492443256176507", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 3576, "cpu_time_ms": 18, "memory_kb": 5236}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s333691271", "group_id": "codeNet:p02552", "input_text": "//header{{{\n#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\n#include <ext/pb_ds/assoc_container.hpp>\n#include <ext/pb_ds/tree_policy.hpp>\n#include <ext/pb_ds/tag_and_trait.hpp>\n#include <ext/pb_ds/trie_policy.hpp>\n \nusing namespace __gnu_pbds;\nusing namespace std;\n \n#define rep(i,n) for(int i=0;i<(n);++i)\n#define reps(i,n) for(int i=1;i<=(n);++i)\n#define all(x) begin(x),end(x)\n#define Fixed fixed << setprecision(12)\n#define int int_fast64_t\nusing pii = pair<int,int>;\nconstexpr int INF  = 0x3f3f3f3f;\nconstexpr long long LINF = 0x3f3f3f3f3f3f3f3fLL;\nconstexpr int mod1 = 1e9+7;\nconstexpr int mod2 = 998244353;\n \ntemplate <class Func>\nclass FixPoint : Func {\npublic:\n    explicit constexpr FixPoint(Func&& f) noexcept : Func(forward<Func>(f)) {}\n \n    template <class... Args>\n    constexpr decltype(auto) operator()(Args&&... args) const {\n        return Func::operator()(*this, std::forward<Args>(args)...);\n    }\n};\n \ntemplate <class Func>\nstatic inline constexpr decltype(auto) makeFixPoint(Func&& f) noexcept {\n    return FixPoint<Func>{forward<Func>(f)};\n}\n \ntemplate <class A, class B> inline bool chmax(A &a, const B &b) { return b > a && (a = b, true); }\ntemplate <class A, class B> inline bool chmin(A &a, const B &b) { return b < a && (a = b, true); }\n \ntemplate <class T> using min_heap = priority_queue<T,vector<T>,greater<T> >;\ntemplate <class T> using max_heap = priority_queue<T>;\ntemplate <class A, class B> using umap = unordered_map<A,B>;\ntemplate <class T> using Set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;\ntemplate <class K, class V> using Umap = gp_hash_table<K, V>;\nusing Trie = trie<string, null_type, trie_string_access_traits<>, pat_trie_tag, trie_prefix_search_node_update>;\n \ninline int square(int a){ return a * a;}\ninline int updiv(int a,int b){ return (a + b - 1) / b; }\n \nconstexpr int dx[] = {1,0,-1,0,1,1,-1,-1};\nconstexpr int dy[] = {0,-1,0,1,1,-1,-1,1};\n//}}}\n\nsigned main(){\n    cin.tie(nullptr);\n    ios_base::sync_with_stdio(false);\n    cout.setf(ios_base::fixed);\n    cout.precision(10);\n\n    int x;\n    cin >> x;\n\n    if(x == 0){\n        cout << 1 << '\\n';\n    }else{\n        cout << 0 << '\\n';\n    }\n\n    return 0;\n}", "language": "C++", "metadata": {"date": 1600029740, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02552.html", "problem_id": "p02552", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02552/input.txt", "sample_output_relpath": "derived/input_output/data/p02552/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02552/C++/s333691271.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s333691271", "user_id": "u803754262"}, "prompt_components": {"gold_output": "0\n", "input_to_evaluate": "//header{{{\n#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\n#include <ext/pb_ds/assoc_container.hpp>\n#include <ext/pb_ds/tree_policy.hpp>\n#include <ext/pb_ds/tag_and_trait.hpp>\n#include <ext/pb_ds/trie_policy.hpp>\n \nusing namespace __gnu_pbds;\nusing namespace std;\n \n#define rep(i,n) for(int i=0;i<(n);++i)\n#define reps(i,n) for(int i=1;i<=(n);++i)\n#define all(x) begin(x),end(x)\n#define Fixed fixed << setprecision(12)\n#define int int_fast64_t\nusing pii = pair<int,int>;\nconstexpr int INF  = 0x3f3f3f3f;\nconstexpr long long LINF = 0x3f3f3f3f3f3f3f3fLL;\nconstexpr int mod1 = 1e9+7;\nconstexpr int mod2 = 998244353;\n \ntemplate <class Func>\nclass FixPoint : Func {\npublic:\n    explicit constexpr FixPoint(Func&& f) noexcept : Func(forward<Func>(f)) {}\n \n    template <class... Args>\n    constexpr decltype(auto) operator()(Args&&... args) const {\n        return Func::operator()(*this, std::forward<Args>(args)...);\n    }\n};\n \ntemplate <class Func>\nstatic inline constexpr decltype(auto) makeFixPoint(Func&& f) noexcept {\n    return FixPoint<Func>{forward<Func>(f)};\n}\n \ntemplate <class A, class B> inline bool chmax(A &a, const B &b) { return b > a && (a = b, true); }\ntemplate <class A, class B> inline bool chmin(A &a, const B &b) { return b < a && (a = b, true); }\n \ntemplate <class T> using min_heap = priority_queue<T,vector<T>,greater<T> >;\ntemplate <class T> using max_heap = priority_queue<T>;\ntemplate <class A, class B> using umap = unordered_map<A,B>;\ntemplate <class T> using Set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;\ntemplate <class K, class V> using Umap = gp_hash_table<K, V>;\nusing Trie = trie<string, null_type, trie_string_access_traits<>, pat_trie_tag, trie_prefix_search_node_update>;\n \ninline int square(int a){ return a * a;}\ninline int updiv(int a,int b){ return (a + b - 1) / b; }\n \nconstexpr int dx[] = {1,0,-1,0,1,1,-1,-1};\nconstexpr int dy[] = {0,-1,0,1,1,-1,-1,1};\n//}}}\n\nsigned main(){\n    cin.tie(nullptr);\n    ios_base::sync_with_stdio(false);\n    cout.setf(ios_base::fixed);\n    cout.precision(10);\n\n    int x;\n    cin >> x;\n\n    if(x == 0){\n        cout << 1 << '\\n';\n    }else{\n        cout << 0 << '\\n';\n    }\n\n    return 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nGiven is an integer x that is greater than or equal to 0, and less than or equal to 1.\nOutput 1 if x is equal to 0, or 0 if x is equal to 1.\n\nConstraints\n\n0 \\leq x \\leq 1\n\nx is an integer\n\nInput\n\nInput is given from Standard Input in the following format:\n\nx\n\nOutput\n\nPrint 1 if x is equal to 0, or 0 if x is equal to 1.\n\nSample Input 1\n\n1\n\nSample Output 1\n\n0\n\nSample Input 2\n\n0\n\nSample Output 2\n\n1", "sample_input": "1\n"}, "reference_outputs": ["0\n"], "source_document_id": "p02552", "source_text": "Score : 100 points\n\nProblem Statement\n\nGiven is an integer x that is greater than or equal to 0, and less than or equal to 1.\nOutput 1 if x is equal to 0, or 0 if x is equal to 1.\n\nConstraints\n\n0 \\leq x \\leq 1\n\nx is an integer\n\nInput\n\nInput is given from Standard Input in the following format:\n\nx\n\nOutput\n\nPrint 1 if x is equal to 0, or 0 if x is equal to 1.\n\nSample Input 1\n\n1\n\nSample Output 1\n\n0\n\nSample Input 2\n\n0\n\nSample Output 2\n\n1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2207, "cpu_time_ms": 9, "memory_kb": 3612}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s078749581", "group_id": "codeNet:p02552", "input_text": "#include<iostream>\n#include<vector>\n#include<cmath>\n#include<stdio.h>\n#include<string>\nusing namespace std;\n\nint main() {\n\tint x;\n\tcin >> x;\n\tif (x == 0) {\n\t\tcout << 1 << endl;\n\t}\n\telse cout << 0 << endl;\n\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1600023718, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02552.html", "problem_id": "p02552", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02552/input.txt", "sample_output_relpath": "derived/input_output/data/p02552/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02552/C++/s078749581.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s078749581", "user_id": "u813600655"}, "prompt_components": {"gold_output": "0\n", "input_to_evaluate": "#include<iostream>\n#include<vector>\n#include<cmath>\n#include<stdio.h>\n#include<string>\nusing namespace std;\n\nint main() {\n\tint x;\n\tcin >> x;\n\tif (x == 0) {\n\t\tcout << 1 << endl;\n\t}\n\telse cout << 0 << endl;\n\n\treturn 0;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nGiven is an integer x that is greater than or equal to 0, and less than or equal to 1.\nOutput 1 if x is equal to 0, or 0 if x is equal to 1.\n\nConstraints\n\n0 \\leq x \\leq 1\n\nx is an integer\n\nInput\n\nInput is given from Standard Input in the following format:\n\nx\n\nOutput\n\nPrint 1 if x is equal to 0, or 0 if x is equal to 1.\n\nSample Input 1\n\n1\n\nSample Output 1\n\n0\n\nSample Input 2\n\n0\n\nSample Output 2\n\n1", "sample_input": "1\n"}, "reference_outputs": ["0\n"], "source_document_id": "p02552", "source_text": "Score : 100 points\n\nProblem Statement\n\nGiven is an integer x that is greater than or equal to 0, and less than or equal to 1.\nOutput 1 if x is equal to 0, or 0 if x is equal to 1.\n\nConstraints\n\n0 \\leq x \\leq 1\n\nx is an integer\n\nInput\n\nInput is given from Standard Input in the following format:\n\nx\n\nOutput\n\nPrint 1 if x is equal to 0, or 0 if x is equal to 1.\n\nSample Input 1\n\n1\n\nSample Output 1\n\n0\n\nSample Input 2\n\n0\n\nSample Output 2\n\n1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 219, "cpu_time_ms": 8, "memory_kb": 3632}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s612137662", "group_id": "codeNet:p02552", "input_text": "#define _GLIBCXX_DEBUG\n#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n  int x;\n  cin >> x;\n  if (x==0) cout << 1 << endl;\n  else cout << 0 << endl;\n}", "language": "C++", "metadata": {"date": 1600023703, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02552.html", "problem_id": "p02552", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02552/input.txt", "sample_output_relpath": "derived/input_output/data/p02552/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02552/C++/s612137662.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s612137662", "user_id": "u042329722"}, "prompt_components": {"gold_output": "0\n", "input_to_evaluate": "#define _GLIBCXX_DEBUG\n#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n  int x;\n  cin >> x;\n  if (x==0) cout << 1 << endl;\n  else cout << 0 << endl;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nGiven is an integer x that is greater than or equal to 0, and less than or equal to 1.\nOutput 1 if x is equal to 0, or 0 if x is equal to 1.\n\nConstraints\n\n0 \\leq x \\leq 1\n\nx is an integer\n\nInput\n\nInput is given from Standard Input in the following format:\n\nx\n\nOutput\n\nPrint 1 if x is equal to 0, or 0 if x is equal to 1.\n\nSample Input 1\n\n1\n\nSample Output 1\n\n0\n\nSample Input 2\n\n0\n\nSample Output 2\n\n1", "sample_input": "1\n"}, "reference_outputs": ["0\n"], "source_document_id": "p02552", "source_text": "Score : 100 points\n\nProblem Statement\n\nGiven is an integer x that is greater than or equal to 0, and less than or equal to 1.\nOutput 1 if x is equal to 0, or 0 if x is equal to 1.\n\nConstraints\n\n0 \\leq x \\leq 1\n\nx is an integer\n\nInput\n\nInput is given from Standard Input in the following format:\n\nx\n\nOutput\n\nPrint 1 if x is equal to 0, or 0 if x is equal to 1.\n\nSample Input 1\n\n1\n\nSample Output 1\n\n0\n\nSample Input 2\n\n0\n\nSample Output 2\n\n1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 162, "cpu_time_ms": 7, "memory_kb": 3628}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s326896175", "group_id": "codeNet:p02553", "input_text": "#include <bits/stdc++.h>\n#define _GLIBCXX_DEBUG\n#define rep(i, n) for (int i = 0; i < (n); i++)\nusing ll = long long;\nusing namespace std;\n\nint main()\n{\n   ll a, b, c, d;\n   cin >> a >> b >> c >> d;\n\n   cout <<  max(max((b*c),(b*d)),max((a*d),(a*c)))<< endl;\n\n}\n\n\n", "language": "C++", "metadata": {"date": 1600646195, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02553.html", "problem_id": "p02553", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02553/input.txt", "sample_output_relpath": "derived/input_output/data/p02553/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02553/C++/s326896175.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s326896175", "user_id": "u483065848"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define _GLIBCXX_DEBUG\n#define rep(i, n) for (int i = 0; i < (n); i++)\nusing ll = long long;\nusing namespace std;\n\nint main()\n{\n   ll a, b, c, d;\n   cin >> a >> b >> c >> d;\n\n   cout <<  max(max((b*c),(b*d)),max((a*d),(a*c)))<< endl;\n\n}\n\n\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nGiven are integers a,b,c and d.\nIf x and y are integers and a \\leq x \\leq b and c\\leq y \\leq d hold, what is the maximum possible value of x \\times y?\n\nConstraints\n\n-10^9 \\leq a \\leq b \\leq 10^9\n\n-10^9 \\leq c \\leq d \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\na b c d\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n1 2 1 1\n\nSample Output 1\n\n2\n\nIf x = 1 and y = 1 then x \\times y = 1.\nIf x = 2 and y = 1 then x \\times y = 2.\nTherefore, the answer is 2.\n\nSample Input 2\n\n3 5 -4 -2\n\nSample Output 2\n\n-6\n\nThe answer can be negative.\n\nSample Input 3\n\n-1000000000 0 -1000000000 0\n\nSample Output 3\n\n1000000000000000000", "sample_input": "1 2 1 1\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02553", "source_text": "Score : 200 points\n\nProblem Statement\n\nGiven are integers a,b,c and d.\nIf x and y are integers and a \\leq x \\leq b and c\\leq y \\leq d hold, what is the maximum possible value of x \\times y?\n\nConstraints\n\n-10^9 \\leq a \\leq b \\leq 10^9\n\n-10^9 \\leq c \\leq d \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\na b c d\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n1 2 1 1\n\nSample Output 1\n\n2\n\nIf x = 1 and y = 1 then x \\times y = 1.\nIf x = 2 and y = 1 then x \\times y = 2.\nTherefore, the answer is 2.\n\nSample Input 2\n\n3 5 -4 -2\n\nSample Output 2\n\n-6\n\nThe answer can be negative.\n\nSample Input 3\n\n-1000000000 0 -1000000000 0\n\nSample Output 3\n\n1000000000000000000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 264, "cpu_time_ms": 5, "memory_kb": 3624}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s587209275", "group_id": "codeNet:p02553", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n int64_t a, b, c, d;\n cin >> a >> b >> c >> d;\n \n if (a >= 0 && c >= 0) cout << b * d << endl;\n else if (b <= 0 && d <= 0) cout << a * c << endl;\n else if (a >= 0 && d <= 0) cout << a * d << endl;\n else if (b <= 0 && c >= 0) cout << b * c << endl;\n else if (a * b <= 0 && c * d <= 0) cout << max(a * c, b * d) << endl;\n else cout << b * d << endl;\n\n\n  \n}\n", "language": "C++", "metadata": {"date": 1600025888, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02553.html", "problem_id": "p02553", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02553/input.txt", "sample_output_relpath": "derived/input_output/data/p02553/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02553/C++/s587209275.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s587209275", "user_id": "u614060232"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n int64_t a, b, c, d;\n cin >> a >> b >> c >> d;\n \n if (a >= 0 && c >= 0) cout << b * d << endl;\n else if (b <= 0 && d <= 0) cout << a * c << endl;\n else if (a >= 0 && d <= 0) cout << a * d << endl;\n else if (b <= 0 && c >= 0) cout << b * c << endl;\n else if (a * b <= 0 && c * d <= 0) cout << max(a * c, b * d) << endl;\n else cout << b * d << endl;\n\n\n  \n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nGiven are integers a,b,c and d.\nIf x and y are integers and a \\leq x \\leq b and c\\leq y \\leq d hold, what is the maximum possible value of x \\times y?\n\nConstraints\n\n-10^9 \\leq a \\leq b \\leq 10^9\n\n-10^9 \\leq c \\leq d \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\na b c d\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n1 2 1 1\n\nSample Output 1\n\n2\n\nIf x = 1 and y = 1 then x \\times y = 1.\nIf x = 2 and y = 1 then x \\times y = 2.\nTherefore, the answer is 2.\n\nSample Input 2\n\n3 5 -4 -2\n\nSample Output 2\n\n-6\n\nThe answer can be negative.\n\nSample Input 3\n\n-1000000000 0 -1000000000 0\n\nSample Output 3\n\n1000000000000000000", "sample_input": "1 2 1 1\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02553", "source_text": "Score : 200 points\n\nProblem Statement\n\nGiven are integers a,b,c and d.\nIf x and y are integers and a \\leq x \\leq b and c\\leq y \\leq d hold, what is the maximum possible value of x \\times y?\n\nConstraints\n\n-10^9 \\leq a \\leq b \\leq 10^9\n\n-10^9 \\leq c \\leq d \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\na b c d\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n1 2 1 1\n\nSample Output 1\n\n2\n\nIf x = 1 and y = 1 then x \\times y = 1.\nIf x = 2 and y = 1 then x \\times y = 2.\nTherefore, the answer is 2.\n\nSample Input 2\n\n3 5 -4 -2\n\nSample Output 2\n\n-6\n\nThe answer can be negative.\n\nSample Input 3\n\n-1000000000 0 -1000000000 0\n\nSample Output 3\n\n1000000000000000000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 415, "cpu_time_ms": 7, "memory_kb": 3672}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s376179033", "group_id": "codeNet:p02553", "input_text": "#include <iostream>\n#include <vector>\n#include <limits.h>\n#include <cmath>\nusing namespace std;\nint main(void){\n    // Your code here!\n    long x1,x2,y1,y2;\n    cin>>x1>>x2>>y1>>y2;\n    long answer=-1*pow(10,18);\n    vector<vector<long>> vec={{x1,x2},{y1,y2}};\n    for(int i=0;i<2;i++){\n        for(int j=0;j<2;j++){\n            if(vec[0][i]*vec[1][j]>answer){\n                answer=vec[0][i]*vec[1][j];\n            }\n        }\n    }\n    cout<<answer;\n}", "language": "C++", "metadata": {"date": 1600025075, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02553.html", "problem_id": "p02553", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02553/input.txt", "sample_output_relpath": "derived/input_output/data/p02553/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02553/C++/s376179033.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s376179033", "user_id": "u279746470"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\n#include <limits.h>\n#include <cmath>\nusing namespace std;\nint main(void){\n    // Your code here!\n    long x1,x2,y1,y2;\n    cin>>x1>>x2>>y1>>y2;\n    long answer=-1*pow(10,18);\n    vector<vector<long>> vec={{x1,x2},{y1,y2}};\n    for(int i=0;i<2;i++){\n        for(int j=0;j<2;j++){\n            if(vec[0][i]*vec[1][j]>answer){\n                answer=vec[0][i]*vec[1][j];\n            }\n        }\n    }\n    cout<<answer;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nGiven are integers a,b,c and d.\nIf x and y are integers and a \\leq x \\leq b and c\\leq y \\leq d hold, what is the maximum possible value of x \\times y?\n\nConstraints\n\n-10^9 \\leq a \\leq b \\leq 10^9\n\n-10^9 \\leq c \\leq d \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\na b c d\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n1 2 1 1\n\nSample Output 1\n\n2\n\nIf x = 1 and y = 1 then x \\times y = 1.\nIf x = 2 and y = 1 then x \\times y = 2.\nTherefore, the answer is 2.\n\nSample Input 2\n\n3 5 -4 -2\n\nSample Output 2\n\n-6\n\nThe answer can be negative.\n\nSample Input 3\n\n-1000000000 0 -1000000000 0\n\nSample Output 3\n\n1000000000000000000", "sample_input": "1 2 1 1\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02553", "source_text": "Score : 200 points\n\nProblem Statement\n\nGiven are integers a,b,c and d.\nIf x and y are integers and a \\leq x \\leq b and c\\leq y \\leq d hold, what is the maximum possible value of x \\times y?\n\nConstraints\n\n-10^9 \\leq a \\leq b \\leq 10^9\n\n-10^9 \\leq c \\leq d \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\na b c d\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n1 2 1 1\n\nSample Output 1\n\n2\n\nIf x = 1 and y = 1 then x \\times y = 1.\nIf x = 2 and y = 1 then x \\times y = 2.\nTherefore, the answer is 2.\n\nSample Input 2\n\n3 5 -4 -2\n\nSample Output 2\n\n-6\n\nThe answer can be negative.\n\nSample Input 3\n\n-1000000000 0 -1000000000 0\n\nSample Output 3\n\n1000000000000000000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 454, "cpu_time_ms": 6, "memory_kb": 3628}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s574474952", "group_id": "codeNet:p02554", "input_text": "#include <bits/stdc++.h>\n//#include <chrono>\n//#pragma GCC optimize(\"Ofast\")\nusing namespace std;\n#define reps(i,s,n) for(int i = s; i < n; i++)\n#define rep(i,n) reps(i,0,n)\n#define Rreps(i,n,e) for(int i = n - 1; i >= e; --i)\n#define Rrep(i,n) Rreps(i,n,0)\n#define ALL(a) a.begin(), a.end()\n#define fi first\n#define se second\ntypedef long long ll;\ntypedef vector<ll> vec;\ntypedef vector<vec> mat;\n\nll N,M,H,W,Q,K,A,B;\nstring S;\ntypedef pair<ll, ll> P;\nconst ll INF = (1LL<<60);\n\ntemplate <unsigned long long mod > class modint{\npublic:\n    ll x;\n    constexpr modint(){x = 0;}\n    constexpr modint(ll _x) : x((_x < 0 ? ((_x += (LLONG_MAX / mod) * mod) < 0 ? _x + (LLONG_MAX / mod) * mod : _x) : _x)%mod){}\n    constexpr modint operator-(){\n        return x == 0 ? 0 : mod - x;\n    }\n    constexpr modint& operator+=(const modint& a){\n        if((x += a.x) >= mod) x -= mod;\n        return *this;\n    }\n    constexpr modint operator+(const modint& a) const{\n        return modint(*this) += a;\n    }\n    constexpr modint& operator-=(const modint& a){\n        if((x -= a.x) < 0) x += mod;\n        return *this;\n    }\n    constexpr modint operator-(const modint& a) const{\n        return modint(*this) -= a;\n    }\n    constexpr modint& operator*=(const modint& a){\n        (x *= a.x)%=mod;\n        return *this;\n    }\n    constexpr modint operator*(const modint& a) const{\n        return modint(*this) *= a;\n    }\n    constexpr modint pow(unsigned long long pw) const{\n        modint res(1), comp(*this);\n        while(pw){\n            if(pw&1) res *= comp;\n            comp *= comp;\n            pw >>= 1;\n        }\n        return res;\n    }\n    //以下、modが素数のときのみ\n    constexpr modint inv() const{\n        return modint(*this).pow(mod - 2);\n    }\n    constexpr modint& operator/=(const modint &a){\n        (x *= a.inv().x)%=mod;\n        return *this;\n    }\n    constexpr modint operator/(const modint &a) const{\n        return modint(*this) /= a;\n    }\n};\n#define mod2 1000000007\nusing mint = modint<mod2>;\n\nostream& operator<<(ostream& os, const mint& a){\n    os << a.x;\n    return os;\n}\nusing vm = vector<mint>;\nint main() {\n    cin>>N;\n    mint res(10);\n    res = res.pow(N);\n    res -= mint(9).pow(N) * 2;\n    res += mint(8).pow(N);\n    cout<<res<<endl;\n}", "language": "C++", "metadata": {"date": 1600023865, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02554.html", "problem_id": "p02554", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02554/input.txt", "sample_output_relpath": "derived/input_output/data/p02554/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02554/C++/s574474952.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s574474952", "user_id": "u016531517"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\n//#include <chrono>\n//#pragma GCC optimize(\"Ofast\")\nusing namespace std;\n#define reps(i,s,n) for(int i = s; i < n; i++)\n#define rep(i,n) reps(i,0,n)\n#define Rreps(i,n,e) for(int i = n - 1; i >= e; --i)\n#define Rrep(i,n) Rreps(i,n,0)\n#define ALL(a) a.begin(), a.end()\n#define fi first\n#define se second\ntypedef long long ll;\ntypedef vector<ll> vec;\ntypedef vector<vec> mat;\n\nll N,M,H,W,Q,K,A,B;\nstring S;\ntypedef pair<ll, ll> P;\nconst ll INF = (1LL<<60);\n\ntemplate <unsigned long long mod > class modint{\npublic:\n    ll x;\n    constexpr modint(){x = 0;}\n    constexpr modint(ll _x) : x((_x < 0 ? ((_x += (LLONG_MAX / mod) * mod) < 0 ? _x + (LLONG_MAX / mod) * mod : _x) : _x)%mod){}\n    constexpr modint operator-(){\n        return x == 0 ? 0 : mod - x;\n    }\n    constexpr modint& operator+=(const modint& a){\n        if((x += a.x) >= mod) x -= mod;\n        return *this;\n    }\n    constexpr modint operator+(const modint& a) const{\n        return modint(*this) += a;\n    }\n    constexpr modint& operator-=(const modint& a){\n        if((x -= a.x) < 0) x += mod;\n        return *this;\n    }\n    constexpr modint operator-(const modint& a) const{\n        return modint(*this) -= a;\n    }\n    constexpr modint& operator*=(const modint& a){\n        (x *= a.x)%=mod;\n        return *this;\n    }\n    constexpr modint operator*(const modint& a) const{\n        return modint(*this) *= a;\n    }\n    constexpr modint pow(unsigned long long pw) const{\n        modint res(1), comp(*this);\n        while(pw){\n            if(pw&1) res *= comp;\n            comp *= comp;\n            pw >>= 1;\n        }\n        return res;\n    }\n    //以下、modが素数のときのみ\n    constexpr modint inv() const{\n        return modint(*this).pow(mod - 2);\n    }\n    constexpr modint& operator/=(const modint &a){\n        (x *= a.inv().x)%=mod;\n        return *this;\n    }\n    constexpr modint operator/(const modint &a) const{\n        return modint(*this) /= a;\n    }\n};\n#define mod2 1000000007\nusing mint = modint<mod2>;\n\nostream& operator<<(ostream& os, const mint& a){\n    os << a.x;\n    return os;\n}\nusing vm = vector<mint>;\nint main() {\n    cin>>N;\n    mint res(10);\n    res = res.pow(N);\n    res -= mint(9).pow(N) * 2;\n    res += mint(8).pow(N);\n    cout<<res<<endl;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nHow many integer sequences A_1,A_2,\\ldots,A_N of length N satisfy all of the following conditions?\n\n0 \\leq A_i \\leq 9\n\nThere exists some i such that A_i=0 holds.\n\nThere exists some i such that A_i=9 holds.\n\nThe answer can be very large, so output it modulo 10^9 + 7.\n\nConstraints\n\n1 \\leq N \\leq 10^6\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the answer modulo 10^9 + 7.\n\nSample Input 1\n\n2\n\nSample Output 1\n\n2\n\nTwo sequences \\{0,9\\} and \\{9,0\\} satisfy all conditions.\n\nSample Input 2\n\n1\n\nSample Output 2\n\n0\n\nSample Input 3\n\n869121\n\nSample Output 3\n\n2511445", "sample_input": "2\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02554", "source_text": "Score : 300 points\n\nProblem Statement\n\nHow many integer sequences A_1,A_2,\\ldots,A_N of length N satisfy all of the following conditions?\n\n0 \\leq A_i \\leq 9\n\nThere exists some i such that A_i=0 holds.\n\nThere exists some i such that A_i=9 holds.\n\nThe answer can be very large, so output it modulo 10^9 + 7.\n\nConstraints\n\n1 \\leq N \\leq 10^6\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the answer modulo 10^9 + 7.\n\nSample Input 1\n\n2\n\nSample Output 1\n\n2\n\nTwo sequences \\{0,9\\} and \\{9,0\\} satisfy all conditions.\n\nSample Input 2\n\n1\n\nSample Output 2\n\n0\n\nSample Input 3\n\n869121\n\nSample Output 3\n\n2511445", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2277, "cpu_time_ms": 6, "memory_kb": 3632}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s567099485", "group_id": "codeNet:p02555", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  int s;\n  cin>>s;\n  vector<long long> dp(s+1,0);\n  long long max = pow(10,9)+7;\n  \n  dp[0] = 1;\n  for(int i=3;i<=s;i++){\n    dp[i] = (dp[i-1]+dp[i-3])%max;\n  }\n  cout<<dp[s]<<endl;\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1600178594, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02555.html", "problem_id": "p02555", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02555/input.txt", "sample_output_relpath": "derived/input_output/data/p02555/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02555/C++/s567099485.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s567099485", "user_id": "u323051878"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  int s;\n  cin>>s;\n  vector<long long> dp(s+1,0);\n  long long max = pow(10,9)+7;\n  \n  dp[0] = 1;\n  for(int i=3;i<=s;i++){\n    dp[i] = (dp[i-1]+dp[i-3])%max;\n  }\n  cout<<dp[s]<<endl;\n  return 0;\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nGiven is an integer S.\nFind how many sequences there are whose terms are all integers greater than or equal to 3, and whose sum is equal to S.\nThe answer can be very large, so output it modulo 10^9 + 7.\n\nConstraints\n\n1 \\leq S \\leq 2000\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n7\n\nSample Output 1\n\n3\n\n3 sequences satisfy the condition: \\{3,4\\}, \\{4,3\\} and \\{7\\}.\n\nSample Input 2\n\n2\n\nSample Output 2\n\n0\n\nThere are no sequences that satisfy the condition.\n\nSample Input 3\n\n1729\n\nSample Output 3\n\n294867501", "sample_input": "7\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02555", "source_text": "Score : 400 points\n\nProblem Statement\n\nGiven is an integer S.\nFind how many sequences there are whose terms are all integers greater than or equal to 3, and whose sum is equal to S.\nThe answer can be very large, so output it modulo 10^9 + 7.\n\nConstraints\n\n1 \\leq S \\leq 2000\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n7\n\nSample Output 1\n\n3\n\n3 sequences satisfy the condition: \\{3,4\\}, \\{4,3\\} and \\{7\\}.\n\nSample Input 2\n\n2\n\nSample Output 2\n\n0\n\nThere are no sequences that satisfy the condition.\n\nSample Input 3\n\n1729\n\nSample Output 3\n\n294867501", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 255, "cpu_time_ms": 5, "memory_kb": 3592}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s428364969", "group_id": "codeNet:p02556", "input_text": "#pragma optimization_level 3\n#include <bits/stdc++.h>\n#define  f               first\n#define  s               second\n#define  sym(s)          s = \"#\" + s + \"#\";\n#define  all(x)          (x).begin(), (x).end()\n#define  alll(x,n)       x+1, x+n+1\n#define  newl            cout<<\"\\n\";\n#define  foo(i,a,n)      for(ll i = (a); i <= n; i++)\n#define  deb1(a)         cout<<a<<\"\\n\";\n#define  deb2(a,b)       cout<<a<<\" \"<<b<<\"\\n\";\n#define  deb3(a,b,c)     cout<<a<<\" \"<<b<<\" \"<<c<<\"\\n\";\n#define  deb4(a,b,c,d)   cout<<a<<\" \"<<b<<\" \"<<c<<\" \"<<d<<\"\\n\";\n#define  debp(a)         cout<<a.f<<\" \"<<a.s<<\"\\n\";\n#define  debv(a)         for(auto it: a)cout<<it<<\" \";newl;\n#define  debm(a)         for(auto it: a)cout<<\"{\"<<it.f<<\",\"<<it.s<<\"}, \";newl;\n#define  deb1d(a,n)      foo(i,1,n)cout<<a[i]<<\" \";newl;\n#define  deb2d(a,n,m)    foo(i,1,n){foo(j,1,m){cout<<a[i][j]<<\" \";}newl;}\n\nusing namespace std;\nusing ll              =  long long;\nusing ld              =  long double;\nconst ll   MOD        =  1e+9 + 7;\nconst ll   INF        =  LLONG_MAX;\nconst int  N          =  (int)2e+5 + 8;\n\nll n, x[N], y[N];\n\nvoid MAIN(int tc){\n    cin >> n;\\\n    ll mnx, mxx, mny, mxy;\n    mnx = mny = INF;\n    mxx = mxy = -INF;\n    for(int i = 1; i <= n; i++){\n        cin >> x[i] >> y[i];\n        mnx = min(mnx, x[i]);\n        mxx = max(mxx, x[i]);\n        mny = min(mny, y[i]);\n        mxy = max(mxy, y[i]);\n    }\n\n    set<pair<ll,ll>> points;\n    ll tmn, tmx;\n\n    tmn = INF; tmx = -INF;\n    for(int i = 1; i <= n; i++){\n        if(x[i] == mnx){\n            tmn = min(tmn, y[i]);\n            tmx = max(tmx, y[i]);\n        }\n    }\n    points.insert({mnx,tmn});\n    points.insert({mnx,tmx});\n\n    tmn = INF; tmx = -INF;\n    for(int i = 1; i <= n; i++){\n        if(x[i] == mxx){\n            tmn = min(tmn, y[i]);\n            tmx = max(tmx, y[i]);\n        }\n    }\n    points.insert({mxx,tmn});\n    points.insert({mxx,tmx});\n\n\n    tmn = INF; tmx = -INF;\n    for(int i = 1; i <= n; i++){\n        if(y[i] == mny){\n            tmn = min(tmn, x[i]);\n            tmx = max(tmx, x[i]);\n        }\n    }\n    points.insert({tmn, mny});\n    points.insert({tmx, mny});\n\n    tmn = INF; tmx = -INF;\n    for(int i = 1; i <= n; i++){\n        if(y[i] == mxy){\n            tmn = min(tmn, x[i]);\n            tmx = max(tmx, x[i]);\n        }\n    }\n    points.insert({tmn, mxy});\n    points.insert({tmx, mxy});\n\n    ll res = 0;\n    for(auto [x1,y1]: points){\n        for(auto [x2, y2]: points){\n            res = max(res, abs(x1 - x2) + abs(y1 - y2));\n        }\n    }\n\n    deb1(res);\n\n\n}\n\nint main(){\n    ios:: sync_with_stdio(false); \n    cin.tie(nullptr); cout.tie(nullptr);\n    cout<<fixed; cout<<setprecision(10);\n\n    int test_cases = 1;\n    //cin>>test_cases;\n    for(int i = 1; i <= test_cases; i++){\n        MAIN(i);\n    }\n}", "language": "C++", "metadata": {"date": 1600026600, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02556.html", "problem_id": "p02556", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02556/input.txt", "sample_output_relpath": "derived/input_output/data/p02556/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02556/C++/s428364969.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s428364969", "user_id": "u622748505"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#pragma optimization_level 3\n#include <bits/stdc++.h>\n#define  f               first\n#define  s               second\n#define  sym(s)          s = \"#\" + s + \"#\";\n#define  all(x)          (x).begin(), (x).end()\n#define  alll(x,n)       x+1, x+n+1\n#define  newl            cout<<\"\\n\";\n#define  foo(i,a,n)      for(ll i = (a); i <= n; i++)\n#define  deb1(a)         cout<<a<<\"\\n\";\n#define  deb2(a,b)       cout<<a<<\" \"<<b<<\"\\n\";\n#define  deb3(a,b,c)     cout<<a<<\" \"<<b<<\" \"<<c<<\"\\n\";\n#define  deb4(a,b,c,d)   cout<<a<<\" \"<<b<<\" \"<<c<<\" \"<<d<<\"\\n\";\n#define  debp(a)         cout<<a.f<<\" \"<<a.s<<\"\\n\";\n#define  debv(a)         for(auto it: a)cout<<it<<\" \";newl;\n#define  debm(a)         for(auto it: a)cout<<\"{\"<<it.f<<\",\"<<it.s<<\"}, \";newl;\n#define  deb1d(a,n)      foo(i,1,n)cout<<a[i]<<\" \";newl;\n#define  deb2d(a,n,m)    foo(i,1,n){foo(j,1,m){cout<<a[i][j]<<\" \";}newl;}\n\nusing namespace std;\nusing ll              =  long long;\nusing ld              =  long double;\nconst ll   MOD        =  1e+9 + 7;\nconst ll   INF        =  LLONG_MAX;\nconst int  N          =  (int)2e+5 + 8;\n\nll n, x[N], y[N];\n\nvoid MAIN(int tc){\n    cin >> n;\\\n    ll mnx, mxx, mny, mxy;\n    mnx = mny = INF;\n    mxx = mxy = -INF;\n    for(int i = 1; i <= n; i++){\n        cin >> x[i] >> y[i];\n        mnx = min(mnx, x[i]);\n        mxx = max(mxx, x[i]);\n        mny = min(mny, y[i]);\n        mxy = max(mxy, y[i]);\n    }\n\n    set<pair<ll,ll>> points;\n    ll tmn, tmx;\n\n    tmn = INF; tmx = -INF;\n    for(int i = 1; i <= n; i++){\n        if(x[i] == mnx){\n            tmn = min(tmn, y[i]);\n            tmx = max(tmx, y[i]);\n        }\n    }\n    points.insert({mnx,tmn});\n    points.insert({mnx,tmx});\n\n    tmn = INF; tmx = -INF;\n    for(int i = 1; i <= n; i++){\n        if(x[i] == mxx){\n            tmn = min(tmn, y[i]);\n            tmx = max(tmx, y[i]);\n        }\n    }\n    points.insert({mxx,tmn});\n    points.insert({mxx,tmx});\n\n\n    tmn = INF; tmx = -INF;\n    for(int i = 1; i <= n; i++){\n        if(y[i] == mny){\n            tmn = min(tmn, x[i]);\n            tmx = max(tmx, x[i]);\n        }\n    }\n    points.insert({tmn, mny});\n    points.insert({tmx, mny});\n\n    tmn = INF; tmx = -INF;\n    for(int i = 1; i <= n; i++){\n        if(y[i] == mxy){\n            tmn = min(tmn, x[i]);\n            tmx = max(tmx, x[i]);\n        }\n    }\n    points.insert({tmn, mxy});\n    points.insert({tmx, mxy});\n\n    ll res = 0;\n    for(auto [x1,y1]: points){\n        for(auto [x2, y2]: points){\n            res = max(res, abs(x1 - x2) + abs(y1 - y2));\n        }\n    }\n\n    deb1(res);\n\n\n}\n\nint main(){\n    ios:: sync_with_stdio(false); \n    cin.tie(nullptr); cout.tie(nullptr);\n    cout<<fixed; cout<<setprecision(10);\n\n    int test_cases = 1;\n    //cin>>test_cases;\n    for(int i = 1; i <= test_cases; i++){\n        MAIN(i);\n    }\n}", "problem_context": "Score : 500 points\n\nProblem Statement\n\nThere are N points on the 2D plane, i-th of which is located on (x_i, y_i).\nThere can be multiple points that share the same coordinate.\nWhat is the maximum possible Manhattan distance between two distinct points?\n\nHere, the Manhattan distance between two points (x_i, y_i) and (x_j, y_j) is defined by |x_i-x_j| + |y_i-y_j|.\n\nConstraints\n\n2 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq x_i,y_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nx_1 y_1\nx_2 y_2\n:\nx_N y_N\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n3\n1 1\n2 4\n3 2\n\nSample Output 1\n\n4\n\nThe Manhattan distance between the first point and the second point is |1-2|+|1-4|=4, which is maximum possible.\n\nSample Input 2\n\n2\n1 1\n1 1\n\nSample Output 2\n\n0", "sample_input": "3\n1 1\n2 4\n3 2\n"}, "reference_outputs": ["4\n"], "source_document_id": "p02556", "source_text": "Score : 500 points\n\nProblem Statement\n\nThere are N points on the 2D plane, i-th of which is located on (x_i, y_i).\nThere can be multiple points that share the same coordinate.\nWhat is the maximum possible Manhattan distance between two distinct points?\n\nHere, the Manhattan distance between two points (x_i, y_i) and (x_j, y_j) is defined by |x_i-x_j| + |y_i-y_j|.\n\nConstraints\n\n2 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq x_i,y_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nx_1 y_1\nx_2 y_2\n:\nx_N y_N\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n3\n1 1\n2 4\n3 2\n\nSample Output 1\n\n4\n\nThe Manhattan distance between the first point and the second point is |1-2|+|1-4|=4, which is maximum possible.\n\nSample Input 2\n\n2\n1 1\n1 1\n\nSample Output 2\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2779, "cpu_time_ms": 49, "memory_kb": 6772}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s959314295", "group_id": "codeNet:p02557", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint n,i,j;\nint a[200000];\nint b[200000];\n\nint main(){\n\tcin >> n;\n\tfor(i = 0; i < n; i++){ cin >> a[i]; }\n\tfor(i = 0; i < n; i++){ cin >> b[i]; }\n\ti = 0; j = n-1;\n\twhile(i <= j){\n\t\tif(a[i] == b[i]){\n\t\t\t//cout << a[i] << \" \" << b[i] << endl;\n\t\t\tswap(a[i],a[j]);\n\t\t\t//cout << a[j] << \" \" << a[i] << endl;\n\t\t\tif(a[i] == b[i]) { cout << \"No\" << endl; return 0;}\n\t\t}\n\t\ti++; j--;\n\t}\n\tcout << \"Yes\" << endl;\n\tfor(i = 0; i < n; i++){cout << a[i] << \" \";}\n\tcout << endl;\n}\n", "language": "C++", "metadata": {"date": 1600028351, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02557.html", "problem_id": "p02557", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02557/input.txt", "sample_output_relpath": "derived/input_output/data/p02557/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02557/C++/s959314295.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s959314295", "user_id": "u301041462"}, "prompt_components": {"gold_output": "Yes\n2 2 3 1 1 1\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint n,i,j;\nint a[200000];\nint b[200000];\n\nint main(){\n\tcin >> n;\n\tfor(i = 0; i < n; i++){ cin >> a[i]; }\n\tfor(i = 0; i < n; i++){ cin >> b[i]; }\n\ti = 0; j = n-1;\n\twhile(i <= j){\n\t\tif(a[i] == b[i]){\n\t\t\t//cout << a[i] << \" \" << b[i] << endl;\n\t\t\tswap(a[i],a[j]);\n\t\t\t//cout << a[j] << \" \" << a[i] << endl;\n\t\t\tif(a[i] == b[i]) { cout << \"No\" << endl; return 0;}\n\t\t}\n\t\ti++; j--;\n\t}\n\tcout << \"Yes\" << endl;\n\tfor(i = 0; i < n; i++){cout << a[i] << \" \";}\n\tcout << endl;\n}\n", "problem_context": "Score : 600 points\n\nProblem Statement\n\nGiven are two sequences A and B, both of length N.\nA and B are each sorted in the ascending order.\nCheck if it is possible to reorder the terms of B so that for each i (1 \\leq i \\leq N) A_i \\neq B_i holds, and if it is possible, output any of the reorderings that achieve it.\n\nConstraints\n\n1\\leq N \\leq 2 \\times 10^5\n\n1\\leq A_i,B_i \\leq N\n\nA and B are each sorted in the ascending order.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 \\cdots A_N\nB_1 B_2 \\cdots B_N\n\nOutput\n\nIf there exist no reorderings that satisfy the condition, print No.\n\nIf there exists a reordering that satisfies the condition, print Yes on the first line.\nAfter that, print a reordering of B on the second line, separating terms with a whitespace.\n\nIf there are multiple reorderings that satisfy the condition, you can print any of them.\n\nSample Input 1\n\n6\n1 1 1 2 2 3\n1 1 1 2 2 3\n\nSample Output 1\n\nYes\n2 2 3 1 1 1\n\nSample Input 2\n\n3\n1 1 2\n1 1 3\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n4\n1 1 2 3\n1 2 3 3\n\nSample Output 3\n\nYes\n3 3 1 2", "sample_input": "6\n1 1 1 2 2 3\n1 1 1 2 2 3\n"}, "reference_outputs": ["Yes\n2 2 3 1 1 1\n"], "source_document_id": "p02557", "source_text": "Score : 600 points\n\nProblem Statement\n\nGiven are two sequences A and B, both of length N.\nA and B are each sorted in the ascending order.\nCheck if it is possible to reorder the terms of B so that for each i (1 \\leq i \\leq N) A_i \\neq B_i holds, and if it is possible, output any of the reorderings that achieve it.\n\nConstraints\n\n1\\leq N \\leq 2 \\times 10^5\n\n1\\leq A_i,B_i \\leq N\n\nA and B are each sorted in the ascending order.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 \\cdots A_N\nB_1 B_2 \\cdots B_N\n\nOutput\n\nIf there exist no reorderings that satisfy the condition, print No.\n\nIf there exists a reordering that satisfies the condition, print Yes on the first line.\nAfter that, print a reordering of B on the second line, separating terms with a whitespace.\n\nIf there are multiple reorderings that satisfy the condition, you can print any of them.\n\nSample Input 1\n\n6\n1 1 1 2 2 3\n1 1 1 2 2 3\n\nSample Output 1\n\nYes\n2 2 3 1 1 1\n\nSample Input 2\n\n3\n1 1 2\n1 1 3\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n4\n1 1 2 3\n1 2 3 3\n\nSample Output 3\n\nYes\n3 3 1 2", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 510, "cpu_time_ms": 108, "memory_kb": 5184}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s568793342", "group_id": "codeNet:p02562", "input_text": "#include <bits/stdc++.h>\n#include <atcoder/all>\nusing namespace std;\nusing namespace atcoder;\n\nusing ll=long long;\n#define rng(i,l,r) for(int i=int(l);i<int(r);i++)\n#define rep(i,r) rng(i,0,r)\n#define rrng(i,l,r) for(int i=int(r)-1;i>=int(l);i--)\n#define rrep(i,r) rrng(i,0,r)\n#define pb push_back\n#define eb emplace_back\n#define mp make_pair\n#define mt make_tuple\n#define F first\n#define S second\n#define bg begin()\n#define ed end()\n#define all(x) x.bg,x.ed\n#define si(x) int(x.size())\n#define inf INT_MAX/2-100\n#define infl LLONG_MAX/3\n#ifdef LOCAL\n#define dmp(x) cerr<<__LINE__<<' '<<#x<<' '<<x<<endl\n#else\n#define dmp(x) void(0)\n#endif\n\ntemplate<class t,class u>bool chmax(t&a,u b){if(a<b)a=b;return a<b;}\ntemplate<class t,class u>bool chmin(t&a,u b){if(b<a)a=b;return b<a;}\n\ntemplate<class t>using vc=vector<t>;\ntemplate<class t>using vvc=vector<vector<t>>;\n\nusing pi=pair<int,int>;\nusing pl=pair<ll,ll>;\nusing vi=vc<int>;\nusing vl=vc<ll>;\n\n\nll readl(void){\n\tll x;\n\tcin>>x;\n\treturn x;\n}\nint readi(void){\n\tint x;\n\tcin>>x;\n\treturn x;\n}\n\nstring readstr(){\n\tstring s;\n\tcin>>s;\n\treturn s;\n}\nvi readvi(int n,int off=0){\n\tvi v(n);\n\trep(i,n)v[i]=readi(),v[i]+=off;\n\treturn v;\n}\n\nvl readvl(int n,int off=0){\n\tvl v(n);\n\trep(i,n)v[i]=readl(),v[i]+=off;\n\treturn v;\n}\n\ntemplate<class t>\nvoid print(t x,int suc=1){\n\tcout<<x;\n\tif(suc==1)cout<<\"\\n\";\n\tif(suc==2)cout<<\" \";\n}\n\ntemplate<class t>\nvoid print(const vc<t>&v,int suc=1){\n\trep(i,si(v))print(v[i],i==int(si(v))-1?1:suc);\n}\n\ntemplate<class t>\nbool inc(t a,t b,t c){\n\treturn !(c<b||b<a);\n}\n\ntemplate<class t>\nvoid compress(vc<t>&v){\n\tsort(all(v));\n\tv.erase(unique(all(v)),v.ed);\n}\n\ntemplate<class t>\nint lwb(const vc<t>&v,const t&a){\n\treturn lower_bound(all(v),a)-v.bg;\n}\n\ntemplate<class t>\nstruct Compress{\n\tvc<t>v;\n\tCompress()=default;\n\tCompress(const vc<t>&x){\n\t\tadd(x);\n\t}\n\tCompress(const initializer_list<vc<t> >&x){\n\t\tfor(auto &p:x)add(p);\n\t}\n\tvoid add(const t&x){\n\t\tv.eb(x);\n\t}\n\tvoid add(const vc<t>&x){\n\t\tcopy(all(x),back_inserter(v));\n\t}\n\tvoid build(){\n\t\tcompress(v);\n\t}\n\tint get(const t&x)const{\n\t\treturn lwb(v,x);\n\t}\n\tvc<t>get(const vc<t>&x)const{\n\t\tvc<t>res(x);\n\t\tfor(auto &p:res)p=get(p);\n\t\treturn res;\n\t}\n\tconst t &operator[](int x)const{\n\t\treturn v[x];\n\t}\n\tint size(){\n\t\treturn v.size();\n\t}\n};\nvoid Yes(bool ex=true){\n\tcout<<\"Yes\\n\";\n\tif(ex)exit(0);\n}\nvoid YES(bool ex=true){\n\tcout<<\"YES\\n\";\n\tif(ex)exit(0);\n}\nvoid No(bool ex=true){\n\tcout<<\"No\\n\";\n\tif(ex)exit(0);\n}\nvoid NO(bool ex=true){\n\tcout<<\"NO\\n\";\n\tif(ex)exit(0);\n}\nvoid orYes(bool x,bool ex=true){\n\tif(x)Yes(ex);\n\telse No(ex);\n}\nvoid orYES(bool x,bool ex=true){\n\tif(x)YES(ex);\n\telse NO(ex);\n}\nvoid Possible(bool ex=true){\n\tcout<<\"Possible\\n\";\n\tif(ex)exit(0);\n}\nvoid POSSIBLE(bool ex=true){\n\tcout<<\"POSSIBLE\\n\";\n\tif(ex)exit(0);\n}\nvoid Impossible(bool ex=true){\n\tcout<<\"Impossible\\n\";\n\tif(ex)exit(0);\n}\nvoid IMPOSSIBLE(bool ex=true){\n\tcout<<\"IMPOSSIBLE\\n\";\n\tif(ex)exit(0);\n}\nvoid orPossible(bool x,bool ex=true){\n\tif(x)Possible(ex);\n\telse Impossible(ex);\n}\nvoid orPOSSIBLE(bool x,bool ex=true){\n\tif(x)POSSIBLE(ex);\n\telse IMPOSSIBLE(ex);\n}\n\n\n\nll n,k,a[55][55];\nint main(void){\n\tcin.tie(0);\n\tios::sync_with_stdio(0);\n\tcin>>n>>k;\n\trep(i,n)rep(j,n)cin>>a[i][j];\n\tmcf_graph<ll,ll> g(n*2+2);\n\trep(i,n){\n\t\trep(j,n){\n\t\t\tg.add_edge(i,n+j,1,1e9-a[i][j]);\n\t\t}\n\t}\n\trep(i,n){\n\t\tg.add_edge(n*2,i,k,0);\n\t\tg.add_edge(n+i,n*2+1,k,0);\n\t}\n\tvc<pl>p=g.slope(n*2,n*2+1);\n\tfor(auto &i:p){\n\t\tswap(i.F,i.S);\n\t\ti.F=i.S*1e9-i.F;\n\t}\n\tsort(all(p));\n\tprint(p.back().F);\n\tmcf_graph<ll,ll> ans(n*2+2);\n\trep(i,n){\n\t\trep(j,n){\n\t\t\tans.add_edge(i,n+j,1,1e9-a[i][j]);\n\t\t}\n\t}\n\trep(i,n){\n\t\tans.add_edge(n*2,i,k,0);\n\t\tans.add_edge(n+i,n*2+1,k,0);\n\t}\n\tans.flow(n*2,n*2+1,p.back().S);\n\trep(i,n){\n\t\trep(j,n){\n\t\t\tif(ans.get_edge(i*n+j).flow==1)cout<<'X';\n\t\t\telse cout<<'.';\n\t\t}\n\t\tcout<<endl;\n\t}\n}\n", "language": "C++", "metadata": {"date": 1599684588, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1 with AC Library v1.1)", "problem_description_relpath": "problem_descriptions/p02562.html", "problem_id": "p02562", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02562/input.txt", "sample_output_relpath": "derived/input_output/data/p02562/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02562/C++/s568793342.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s568793342", "user_id": "u743900647"}, "prompt_components": {"gold_output": "19\nX..\n..X\n.X.\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#include <atcoder/all>\nusing namespace std;\nusing namespace atcoder;\n\nusing ll=long long;\n#define rng(i,l,r) for(int i=int(l);i<int(r);i++)\n#define rep(i,r) rng(i,0,r)\n#define rrng(i,l,r) for(int i=int(r)-1;i>=int(l);i--)\n#define rrep(i,r) rrng(i,0,r)\n#define pb push_back\n#define eb emplace_back\n#define mp make_pair\n#define mt make_tuple\n#define F first\n#define S second\n#define bg begin()\n#define ed end()\n#define all(x) x.bg,x.ed\n#define si(x) int(x.size())\n#define inf INT_MAX/2-100\n#define infl LLONG_MAX/3\n#ifdef LOCAL\n#define dmp(x) cerr<<__LINE__<<' '<<#x<<' '<<x<<endl\n#else\n#define dmp(x) void(0)\n#endif\n\ntemplate<class t,class u>bool chmax(t&a,u b){if(a<b)a=b;return a<b;}\ntemplate<class t,class u>bool chmin(t&a,u b){if(b<a)a=b;return b<a;}\n\ntemplate<class t>using vc=vector<t>;\ntemplate<class t>using vvc=vector<vector<t>>;\n\nusing pi=pair<int,int>;\nusing pl=pair<ll,ll>;\nusing vi=vc<int>;\nusing vl=vc<ll>;\n\n\nll readl(void){\n\tll x;\n\tcin>>x;\n\treturn x;\n}\nint readi(void){\n\tint x;\n\tcin>>x;\n\treturn x;\n}\n\nstring readstr(){\n\tstring s;\n\tcin>>s;\n\treturn s;\n}\nvi readvi(int n,int off=0){\n\tvi v(n);\n\trep(i,n)v[i]=readi(),v[i]+=off;\n\treturn v;\n}\n\nvl readvl(int n,int off=0){\n\tvl v(n);\n\trep(i,n)v[i]=readl(),v[i]+=off;\n\treturn v;\n}\n\ntemplate<class t>\nvoid print(t x,int suc=1){\n\tcout<<x;\n\tif(suc==1)cout<<\"\\n\";\n\tif(suc==2)cout<<\" \";\n}\n\ntemplate<class t>\nvoid print(const vc<t>&v,int suc=1){\n\trep(i,si(v))print(v[i],i==int(si(v))-1?1:suc);\n}\n\ntemplate<class t>\nbool inc(t a,t b,t c){\n\treturn !(c<b||b<a);\n}\n\ntemplate<class t>\nvoid compress(vc<t>&v){\n\tsort(all(v));\n\tv.erase(unique(all(v)),v.ed);\n}\n\ntemplate<class t>\nint lwb(const vc<t>&v,const t&a){\n\treturn lower_bound(all(v),a)-v.bg;\n}\n\ntemplate<class t>\nstruct Compress{\n\tvc<t>v;\n\tCompress()=default;\n\tCompress(const vc<t>&x){\n\t\tadd(x);\n\t}\n\tCompress(const initializer_list<vc<t> >&x){\n\t\tfor(auto &p:x)add(p);\n\t}\n\tvoid add(const t&x){\n\t\tv.eb(x);\n\t}\n\tvoid add(const vc<t>&x){\n\t\tcopy(all(x),back_inserter(v));\n\t}\n\tvoid build(){\n\t\tcompress(v);\n\t}\n\tint get(const t&x)const{\n\t\treturn lwb(v,x);\n\t}\n\tvc<t>get(const vc<t>&x)const{\n\t\tvc<t>res(x);\n\t\tfor(auto &p:res)p=get(p);\n\t\treturn res;\n\t}\n\tconst t &operator[](int x)const{\n\t\treturn v[x];\n\t}\n\tint size(){\n\t\treturn v.size();\n\t}\n};\nvoid Yes(bool ex=true){\n\tcout<<\"Yes\\n\";\n\tif(ex)exit(0);\n}\nvoid YES(bool ex=true){\n\tcout<<\"YES\\n\";\n\tif(ex)exit(0);\n}\nvoid No(bool ex=true){\n\tcout<<\"No\\n\";\n\tif(ex)exit(0);\n}\nvoid NO(bool ex=true){\n\tcout<<\"NO\\n\";\n\tif(ex)exit(0);\n}\nvoid orYes(bool x,bool ex=true){\n\tif(x)Yes(ex);\n\telse No(ex);\n}\nvoid orYES(bool x,bool ex=true){\n\tif(x)YES(ex);\n\telse NO(ex);\n}\nvoid Possible(bool ex=true){\n\tcout<<\"Possible\\n\";\n\tif(ex)exit(0);\n}\nvoid POSSIBLE(bool ex=true){\n\tcout<<\"POSSIBLE\\n\";\n\tif(ex)exit(0);\n}\nvoid Impossible(bool ex=true){\n\tcout<<\"Impossible\\n\";\n\tif(ex)exit(0);\n}\nvoid IMPOSSIBLE(bool ex=true){\n\tcout<<\"IMPOSSIBLE\\n\";\n\tif(ex)exit(0);\n}\nvoid orPossible(bool x,bool ex=true){\n\tif(x)Possible(ex);\n\telse Impossible(ex);\n}\nvoid orPOSSIBLE(bool x,bool ex=true){\n\tif(x)POSSIBLE(ex);\n\telse IMPOSSIBLE(ex);\n}\n\n\n\nll n,k,a[55][55];\nint main(void){\n\tcin.tie(0);\n\tios::sync_with_stdio(0);\n\tcin>>n>>k;\n\trep(i,n)rep(j,n)cin>>a[i][j];\n\tmcf_graph<ll,ll> g(n*2+2);\n\trep(i,n){\n\t\trep(j,n){\n\t\t\tg.add_edge(i,n+j,1,1e9-a[i][j]);\n\t\t}\n\t}\n\trep(i,n){\n\t\tg.add_edge(n*2,i,k,0);\n\t\tg.add_edge(n+i,n*2+1,k,0);\n\t}\n\tvc<pl>p=g.slope(n*2,n*2+1);\n\tfor(auto &i:p){\n\t\tswap(i.F,i.S);\n\t\ti.F=i.S*1e9-i.F;\n\t}\n\tsort(all(p));\n\tprint(p.back().F);\n\tmcf_graph<ll,ll> ans(n*2+2);\n\trep(i,n){\n\t\trep(j,n){\n\t\t\tans.add_edge(i,n+j,1,1e9-a[i][j]);\n\t\t}\n\t}\n\trep(i,n){\n\t\tans.add_edge(n*2,i,k,0);\n\t\tans.add_edge(n+i,n*2+1,k,0);\n\t}\n\tans.flow(n*2,n*2+1,p.back().S);\n\trep(i,n){\n\t\trep(j,n){\n\t\t\tif(ans.get_edge(i*n+j).flow==1)cout<<'X';\n\t\t\telse cout<<'.';\n\t\t}\n\t\tcout<<endl;\n\t}\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nYou are given a grid of N rows and M columns. The square at the i-th row and j-th column will be denoted as (i,j).\nA nonnegative integer A_{i,j} is written for each square (i,j).\n\nYou choose some of the squares so that each row and column contains at most K chosen squares.\nUnder this constraint, calculate the maximum value of the sum of the integers written on the chosen squares.\nAdditionally, calculate a way to choose squares that acheives the maximum.\n\nConstraints\n\n1 \\leq N \\leq 50\n\n1 \\leq K \\leq N\n\n0 \\leq A_{i,j} \\leq 10^9\n\nAll values in Input are integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nA_{1,1} A_{1,2} \\cdots A_{1,N}\nA_{2,1} A_{2,2} \\cdots A_{2,N}\n\\vdots\nA_{N,1} A_{N,2} \\cdots A_{N,N}\n\nOutput\n\nOn the first line, print the maximum value of the sum of the integers written on the chosen squares.\n\nOn the next N lines, print a way that achieves the maximum.\n\nPrecisely, output the strings t_1,t_2,\\cdots,t_N, that satisfies t_{i,j}=X if you choose (i,j) and t_{i,j}=. otherwise.\n\nYou may print any way to choose squares that maximizes the sum.\n\nSample Input 1\n\n3 1\n5 3 2\n1 4 8\n7 6 9\n\nSample Output 1\n\n19\nX..\n..X\n.X.\n\nSample Input 2\n\n3 2\n10 10 1\n10 10 1\n1 1 10\n\nSample Output 2\n\n50\nXX.\nXX.\n..X", "sample_input": "3 1\n5 3 2\n1 4 8\n7 6 9\n"}, "reference_outputs": ["19\nX..\n..X\n.X.\n"], "source_document_id": "p02562", "source_text": "Score : 100 points\n\nProblem Statement\n\nYou are given a grid of N rows and M columns. The square at the i-th row and j-th column will be denoted as (i,j).\nA nonnegative integer A_{i,j} is written for each square (i,j).\n\nYou choose some of the squares so that each row and column contains at most K chosen squares.\nUnder this constraint, calculate the maximum value of the sum of the integers written on the chosen squares.\nAdditionally, calculate a way to choose squares that acheives the maximum.\n\nConstraints\n\n1 \\leq N \\leq 50\n\n1 \\leq K \\leq N\n\n0 \\leq A_{i,j} \\leq 10^9\n\nAll values in Input are integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nA_{1,1} A_{1,2} \\cdots A_{1,N}\nA_{2,1} A_{2,2} \\cdots A_{2,N}\n\\vdots\nA_{N,1} A_{N,2} \\cdots A_{N,N}\n\nOutput\n\nOn the first line, print the maximum value of the sum of the integers written on the chosen squares.\n\nOn the next N lines, print a way that achieves the maximum.\n\nPrecisely, output the strings t_1,t_2,\\cdots,t_N, that satisfies t_{i,j}=X if you choose (i,j) and t_{i,j}=. otherwise.\n\nYou may print any way to choose squares that maximizes the sum.\n\nSample Input 1\n\n3 1\n5 3 2\n1 4 8\n7 6 9\n\nSample Output 1\n\n19\nX..\n..X\n.X.\n\nSample Input 2\n\n3 2\n10 10 1\n10 10 1\n1 1 10\n\nSample Output 2\n\n50\nXX.\nXX.\n..X", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 3767, "cpu_time_ms": 84, "memory_kb": 4160}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s125326346", "group_id": "codeNet:p02570", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n    long long d,t,s;\n    cin >> d >> t >> s;\n    if(d/s <= t){\n        cout << \"Yes\" << endl;\n    }else{\n        cout << \"No\" << endl;\n    }\n    return 0;\n}", "language": "C++", "metadata": {"date": 1598732572, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02570.html", "problem_id": "p02570", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02570/input.txt", "sample_output_relpath": "derived/input_output/data/p02570/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02570/C++/s125326346.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s125326346", "user_id": "u497715246"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n    long long d,t,s;\n    cin >> d >> t >> s;\n    if(d/s <= t){\n        cout << \"Yes\" << endl;\n    }else{\n        cout << \"No\" << endl;\n    }\n    return 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nTakahashi is meeting up with Aoki.\n\nThey have planned to meet at a place that is D meters away from Takahashi's house in T minutes from now.\n\nTakahashi will leave his house now and go straight to the place at a speed of S meters per minute.\n\nWill he arrive in time?\n\nConstraints\n\n1 \\leq D \\leq 10000\n\n1 \\leq T \\leq 10000\n\n1 \\leq S \\leq 10000\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nD T S\n\nOutput\n\nIf Takahashi will reach the place in time, print Yes; otherwise, print No.\n\nSample Input 1\n\n1000 15 80\n\nSample Output 1\n\nYes\n\nIt takes 12.5 minutes to go 1000 meters to the place at a speed of 80 meters per minute. They have planned to meet in 15 minutes so he will arrive in time.\n\nSample Input 2\n\n2000 20 100\n\nSample Output 2\n\nYes\n\nIt takes 20 minutes to go 2000 meters to the place at a speed of 100 meters per minute. They have planned to meet in 20 minutes so he will arrive just on time.\n\nSample Input 3\n\n10000 1 1\n\nSample Output 3\n\nNo\n\nHe will be late.", "sample_input": "1000 15 80\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p02570", "source_text": "Score : 100 points\n\nProblem Statement\n\nTakahashi is meeting up with Aoki.\n\nThey have planned to meet at a place that is D meters away from Takahashi's house in T minutes from now.\n\nTakahashi will leave his house now and go straight to the place at a speed of S meters per minute.\n\nWill he arrive in time?\n\nConstraints\n\n1 \\leq D \\leq 10000\n\n1 \\leq T \\leq 10000\n\n1 \\leq S \\leq 10000\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nD T S\n\nOutput\n\nIf Takahashi will reach the place in time, print Yes; otherwise, print No.\n\nSample Input 1\n\n1000 15 80\n\nSample Output 1\n\nYes\n\nIt takes 12.5 minutes to go 1000 meters to the place at a speed of 80 meters per minute. They have planned to meet in 15 minutes so he will arrive in time.\n\nSample Input 2\n\n2000 20 100\n\nSample Output 2\n\nYes\n\nIt takes 20 minutes to go 2000 meters to the place at a speed of 100 meters per minute. They have planned to meet in 20 minutes so he will arrive just on time.\n\nSample Input 3\n\n10000 1 1\n\nSample Output 3\n\nNo\n\nHe will be late.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 215, "cpu_time_ms": 7, "memory_kb": 3552}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s116165382", "group_id": "codeNet:p02570", "input_text": "#include <iostream>\n#include <string>\n\nusing namespace std;\n\nint main(){\n  int d,t,s;\n  cin >> d >> t >> s ;\n  if(d > t * s) cout  << 'Yes';\n  else cout << 'No';\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1598728452, "filename_ext": "cpp", "original_language": "C++ (Clang 10.0.0)", "problem_description_relpath": "problem_descriptions/p02570.html", "problem_id": "p02570", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02570/input.txt", "sample_output_relpath": "derived/input_output/data/p02570/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02570/C++/s116165382.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s116165382", "user_id": "u260228177"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <iostream>\n#include <string>\n\nusing namespace std;\n\nint main(){\n  int d,t,s;\n  cin >> d >> t >> s ;\n  if(d > t * s) cout  << 'Yes';\n  else cout << 'No';\n  return 0;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nTakahashi is meeting up with Aoki.\n\nThey have planned to meet at a place that is D meters away from Takahashi's house in T minutes from now.\n\nTakahashi will leave his house now and go straight to the place at a speed of S meters per minute.\n\nWill he arrive in time?\n\nConstraints\n\n1 \\leq D \\leq 10000\n\n1 \\leq T \\leq 10000\n\n1 \\leq S \\leq 10000\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nD T S\n\nOutput\n\nIf Takahashi will reach the place in time, print Yes; otherwise, print No.\n\nSample Input 1\n\n1000 15 80\n\nSample Output 1\n\nYes\n\nIt takes 12.5 minutes to go 1000 meters to the place at a speed of 80 meters per minute. They have planned to meet in 15 minutes so he will arrive in time.\n\nSample Input 2\n\n2000 20 100\n\nSample Output 2\n\nYes\n\nIt takes 20 minutes to go 2000 meters to the place at a speed of 100 meters per minute. They have planned to meet in 20 minutes so he will arrive just on time.\n\nSample Input 3\n\n10000 1 1\n\nSample Output 3\n\nNo\n\nHe will be late.", "sample_input": "1000 15 80\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p02570", "source_text": "Score : 100 points\n\nProblem Statement\n\nTakahashi is meeting up with Aoki.\n\nThey have planned to meet at a place that is D meters away from Takahashi's house in T minutes from now.\n\nTakahashi will leave his house now and go straight to the place at a speed of S meters per minute.\n\nWill he arrive in time?\n\nConstraints\n\n1 \\leq D \\leq 10000\n\n1 \\leq T \\leq 10000\n\n1 \\leq S \\leq 10000\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nD T S\n\nOutput\n\nIf Takahashi will reach the place in time, print Yes; otherwise, print No.\n\nSample Input 1\n\n1000 15 80\n\nSample Output 1\n\nYes\n\nIt takes 12.5 minutes to go 1000 meters to the place at a speed of 80 meters per minute. They have planned to meet in 15 minutes so he will arrive in time.\n\nSample Input 2\n\n2000 20 100\n\nSample Output 2\n\nYes\n\nIt takes 20 minutes to go 2000 meters to the place at a speed of 100 meters per minute. They have planned to meet in 20 minutes so he will arrive just on time.\n\nSample Input 3\n\n10000 1 1\n\nSample Output 3\n\nNo\n\nHe will be late.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 176, "cpu_time_ms": 9, "memory_kb": 3192}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s681491388", "group_id": "codeNet:p02571", "input_text": "#include<bits/stdc++.h>\n#define Vsort(a) sort(a.begin(), a.end())\n#define rep(i,n) for(long long int i = 0; i < (n); i++)\n#define ll long long\n#define P pair<int, int>\nusing namespace std;\n\nint main() {\n  string s, t;\n  cin >> s >> t;\n  int count = s.size() - t.size();\n  vector<long long int> wa(count);\n  int size = t.size();\n  rep(i, count){\n    rep(j, size){\n      char S, T;\n      S = s.at(i + j); T = t.at(j);\n      if(S != T) wa[i]++;\n    }\n  }\n  Vsort(wa);\n  cout << wa[0] << endl;\n}\n", "language": "C++", "metadata": {"date": 1598734761, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02571.html", "problem_id": "p02571", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02571/input.txt", "sample_output_relpath": "derived/input_output/data/p02571/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02571/C++/s681491388.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s681491388", "user_id": "u424661377"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include<bits/stdc++.h>\n#define Vsort(a) sort(a.begin(), a.end())\n#define rep(i,n) for(long long int i = 0; i < (n); i++)\n#define ll long long\n#define P pair<int, int>\nusing namespace std;\n\nint main() {\n  string s, t;\n  cin >> s >> t;\n  int count = s.size() - t.size();\n  vector<long long int> wa(count);\n  int size = t.size();\n  rep(i, count){\n    rep(j, size){\n      char S, T;\n      S = s.at(i + j); T = t.at(j);\n      if(S != T) wa[i]++;\n    }\n  }\n  Vsort(wa);\n  cout << wa[0] << endl;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nGiven are two strings S and T.\n\nLet us change some of the characters in S so that T will be a substring of S.\n\nAt least how many characters do we need to change?\n\nHere, a substring is a consecutive subsequence. For example, xxx is a substring of yxxxy, but not a substring of xxyxx.\n\nConstraints\n\nThe lengths of S and T are each at least 1 and at most 1000.\n\nThe length of T is at most that of S.\n\nS and T consist of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\nT\n\nOutput\n\nPrint the minimum number of characters in S that need to be changed.\n\nSample Input 1\n\ncabacc\nabc\n\nSample Output 1\n\n1\n\nFor example, changing the fourth character a in S to c will match the second through fourth characters in S to T.\n\nSince S itself does not have T as its substring, this number of changes - one - is the minimum needed.\n\nSample Input 2\n\ncodeforces\natcoder\n\nSample Output 2\n\n6", "sample_input": "cabacc\nabc\n"}, "reference_outputs": ["1\n"], "source_document_id": "p02571", "source_text": "Score : 200 points\n\nProblem Statement\n\nGiven are two strings S and T.\n\nLet us change some of the characters in S so that T will be a substring of S.\n\nAt least how many characters do we need to change?\n\nHere, a substring is a consecutive subsequence. For example, xxx is a substring of yxxxy, but not a substring of xxyxx.\n\nConstraints\n\nThe lengths of S and T are each at least 1 and at most 1000.\n\nThe length of T is at most that of S.\n\nS and T consist of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\nT\n\nOutput\n\nPrint the minimum number of characters in S that need to be changed.\n\nSample Input 1\n\ncabacc\nabc\n\nSample Output 1\n\n1\n\nFor example, changing the fourth character a in S to c will match the second through fourth characters in S to T.\n\nSince S itself does not have T as its substring, this number of changes - one - is the minimum needed.\n\nSample Input 2\n\ncodeforces\natcoder\n\nSample Output 2\n\n6", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 492, "cpu_time_ms": 103, "memory_kb": 3604}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s088790489", "group_id": "codeNet:p02571", "input_text": "#include<bits/stdc++.h>\n#define ll long long int\nusing namespace std;\nint main()\n{\n    string str,ptr;\n    cin>>str>>ptr;\n    int mx=0;\n    for(int i=0; i<ptr.size(); i++)\n    {\n        int x=i;\n        int cnt=0;\n        for(int j=i; j<str.size(); j++)\n        {\n            if(str[j]==ptr[x])\n            {\n                cnt++;\n            }\n            else\n            {\n\n                mx=max(cnt,mx);\n                cnt=0;\n            }\n            x++;\n        }\n        mx=max(cnt,mx);\n    }\n    cout<<ptr.size()-mx<<endl;\n\n\n}\n", "language": "C++", "metadata": {"date": 1598728715, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02571.html", "problem_id": "p02571", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02571/input.txt", "sample_output_relpath": "derived/input_output/data/p02571/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02571/C++/s088790489.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s088790489", "user_id": "u940113787"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include<bits/stdc++.h>\n#define ll long long int\nusing namespace std;\nint main()\n{\n    string str,ptr;\n    cin>>str>>ptr;\n    int mx=0;\n    for(int i=0; i<ptr.size(); i++)\n    {\n        int x=i;\n        int cnt=0;\n        for(int j=i; j<str.size(); j++)\n        {\n            if(str[j]==ptr[x])\n            {\n                cnt++;\n            }\n            else\n            {\n\n                mx=max(cnt,mx);\n                cnt=0;\n            }\n            x++;\n        }\n        mx=max(cnt,mx);\n    }\n    cout<<ptr.size()-mx<<endl;\n\n\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nGiven are two strings S and T.\n\nLet us change some of the characters in S so that T will be a substring of S.\n\nAt least how many characters do we need to change?\n\nHere, a substring is a consecutive subsequence. For example, xxx is a substring of yxxxy, but not a substring of xxyxx.\n\nConstraints\n\nThe lengths of S and T are each at least 1 and at most 1000.\n\nThe length of T is at most that of S.\n\nS and T consist of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\nT\n\nOutput\n\nPrint the minimum number of characters in S that need to be changed.\n\nSample Input 1\n\ncabacc\nabc\n\nSample Output 1\n\n1\n\nFor example, changing the fourth character a in S to c will match the second through fourth characters in S to T.\n\nSince S itself does not have T as its substring, this number of changes - one - is the minimum needed.\n\nSample Input 2\n\ncodeforces\natcoder\n\nSample Output 2\n\n6", "sample_input": "cabacc\nabc\n"}, "reference_outputs": ["1\n"], "source_document_id": "p02571", "source_text": "Score : 200 points\n\nProblem Statement\n\nGiven are two strings S and T.\n\nLet us change some of the characters in S so that T will be a substring of S.\n\nAt least how many characters do we need to change?\n\nHere, a substring is a consecutive subsequence. For example, xxx is a substring of yxxxy, but not a substring of xxyxx.\n\nConstraints\n\nThe lengths of S and T are each at least 1 and at most 1000.\n\nThe length of T is at most that of S.\n\nS and T consist of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\nT\n\nOutput\n\nPrint the minimum number of characters in S that need to be changed.\n\nSample Input 1\n\ncabacc\nabc\n\nSample Output 1\n\n1\n\nFor example, changing the fourth character a in S to c will match the second through fourth characters in S to T.\n\nSince S itself does not have T as its substring, this number of changes - one - is the minimum needed.\n\nSample Input 2\n\ncodeforces\natcoder\n\nSample Output 2\n\n6", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 539, "cpu_time_ms": 23, "memory_kb": 3596}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s980446156", "group_id": "codeNet:p02573", "input_text": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define x first\n#define y second\n#define PQ priority_queue\n#define pb push_back\n#define fu(i,a,j) for(int i=a;i<j;i++)\n#define fd(i,a,j) for(int i=a;i>=j;i--)\n#define SYNC ios::sync_with_stdio(0),cin.tie(NULL),cout.tie(NULL)\n#define MOD 1000000007 \n#define MOD2 1000000021\n#define MAXN 2000000\n#define INF 1e9\nusing namespace std;\n\ntypedef long long ll;\ntypedef long double ld;\ntypedef double db;\ntypedef pair<int, int> pii;\ntypedef pair<ll, ll> pll;\ntypedef vector<int> vi;\ntypedef vector<ll> vll;\ntypedef vector<pii> vpii;\ntypedef vector<pll> vpll;\ntypedef vector<string> vs;\n\n//ll gcd(ll a, ll b) { return b ? gcd(b, a % b) : a; }\n\nll m_pow(ll a, ll b, ll M = MOD) { ll res = 1; for (; b; b >>= 1, a = (a * a) % M)if (b & 1)res = (res * a) % M; return res; }\nll gcd(ll a, ll b) { if (a < b) swap(a, b); for (; b; a %= b, swap(a, b)); return a; }\nll lcm(ll a, ll b) { return a * b / gcd(a, b); };\ndb dis(pii a, pii b) { return sqrt((a.x - b.x) * (a.x - b.x) + (a.y - b.y) * (a.y - b.y)); }\nint dr[] = { 0, 1, 0, -1, 1,1,-1,-1 };\nint dc[] = { 1, 0, -1, 0, 1,-1,1,-1 };\n\nint n, m, k, t;\n\nstring ansok[2] = { \"NO\",\"YES\" };\n\npii a[200005];\nint par[200005];\nint sz[200005];\nint Find(int u) {\n\tif (par[u] < 0) { return u; }\n\treturn par[u] = Find(par[u]);\n}\nbool Union(int u, int v) {\n\tu = Find(u);\n\tv = Find(v);\n\tif (u == v)\n\t\treturn 0;\n\tpar[v] = u;\n\tsz[u] += sz[v];\n\treturn 1;\n}\nint main()\n{\n\tSYNC;\n\tmemset(par, -1, sizeof par);\n\tcin >> n >> m;\n\tfor (int i = 1; i <= n; i++)\n\t\tsz[i] = 1;\n\tfor (int i = 0; i < m; i++) {\n\t\tint u, v;\n\t\tcin >> u >> v;\n\t\tUnion(u,v);\n\t}\n\tint mx = 0;\n\tfor (int i = 1; i <= n; i++) {\n\t\tmx = max(mx, sz[Find(i)]);\n\t}\n\tcout << mx << '\\n';\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1598728795, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02573.html", "problem_id": "p02573", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02573/input.txt", "sample_output_relpath": "derived/input_output/data/p02573/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02573/C++/s980446156.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s980446156", "user_id": "u203081684"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define all(v) v.begin(), v.end()\n#define x first\n#define y second\n#define PQ priority_queue\n#define pb push_back\n#define fu(i,a,j) for(int i=a;i<j;i++)\n#define fd(i,a,j) for(int i=a;i>=j;i--)\n#define SYNC ios::sync_with_stdio(0),cin.tie(NULL),cout.tie(NULL)\n#define MOD 1000000007 \n#define MOD2 1000000021\n#define MAXN 2000000\n#define INF 1e9\nusing namespace std;\n\ntypedef long long ll;\ntypedef long double ld;\ntypedef double db;\ntypedef pair<int, int> pii;\ntypedef pair<ll, ll> pll;\ntypedef vector<int> vi;\ntypedef vector<ll> vll;\ntypedef vector<pii> vpii;\ntypedef vector<pll> vpll;\ntypedef vector<string> vs;\n\n//ll gcd(ll a, ll b) { return b ? gcd(b, a % b) : a; }\n\nll m_pow(ll a, ll b, ll M = MOD) { ll res = 1; for (; b; b >>= 1, a = (a * a) % M)if (b & 1)res = (res * a) % M; return res; }\nll gcd(ll a, ll b) { if (a < b) swap(a, b); for (; b; a %= b, swap(a, b)); return a; }\nll lcm(ll a, ll b) { return a * b / gcd(a, b); };\ndb dis(pii a, pii b) { return sqrt((a.x - b.x) * (a.x - b.x) + (a.y - b.y) * (a.y - b.y)); }\nint dr[] = { 0, 1, 0, -1, 1,1,-1,-1 };\nint dc[] = { 1, 0, -1, 0, 1,-1,1,-1 };\n\nint n, m, k, t;\n\nstring ansok[2] = { \"NO\",\"YES\" };\n\npii a[200005];\nint par[200005];\nint sz[200005];\nint Find(int u) {\n\tif (par[u] < 0) { return u; }\n\treturn par[u] = Find(par[u]);\n}\nbool Union(int u, int v) {\n\tu = Find(u);\n\tv = Find(v);\n\tif (u == v)\n\t\treturn 0;\n\tpar[v] = u;\n\tsz[u] += sz[v];\n\treturn 1;\n}\nint main()\n{\n\tSYNC;\n\tmemset(par, -1, sizeof par);\n\tcin >> n >> m;\n\tfor (int i = 1; i <= n; i++)\n\t\tsz[i] = 1;\n\tfor (int i = 0; i < m; i++) {\n\t\tint u, v;\n\t\tcin >> u >> v;\n\t\tUnion(u,v);\n\t}\n\tint mx = 0;\n\tfor (int i = 1; i <= n; i++) {\n\t\tmx = max(mx, sz[Find(i)]);\n\t}\n\tcout << mx << '\\n';\n\treturn 0;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nThere are N persons called Person 1 through Person N.\n\nYou are given M facts that \"Person A_i and Person B_i are friends.\" The same fact may be given multiple times.\n\nIf X and Y are friends, and Y and Z are friends, then X and Z are also friends. There is no friendship that cannot be derived from the M given facts.\n\nTakahashi the evil wants to divide the N persons into some number of groups so that every person has no friend in his/her group.\n\nAt least how many groups does he need to make?\n\nConstraints\n\n2 \\leq N \\leq 2\\times 10^5\n\n0 \\leq M \\leq 2\\times 10^5\n\n1\\leq A_i,B_i\\leq N\n\nA_i \\neq B_i\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 B_1\n\\vdots\nA_M B_M\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n5 3\n1 2\n3 4\n5 1\n\nSample Output 1\n\n3\n\nDividing them into three groups such as \\{1,3\\}, \\{2,4\\}, and \\{5\\} achieves the goal.\n\nSample Input 2\n\n4 10\n1 2\n2 1\n1 2\n2 1\n1 2\n1 3\n1 4\n2 3\n2 4\n3 4\n\nSample Output 2\n\n4\n\nSample Input 3\n\n10 4\n3 1\n4 1\n5 9\n2 6\n\nSample Output 3\n\n3", "sample_input": "5 3\n1 2\n3 4\n5 1\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02573", "source_text": "Score : 400 points\n\nProblem Statement\n\nThere are N persons called Person 1 through Person N.\n\nYou are given M facts that \"Person A_i and Person B_i are friends.\" The same fact may be given multiple times.\n\nIf X and Y are friends, and Y and Z are friends, then X and Z are also friends. There is no friendship that cannot be derived from the M given facts.\n\nTakahashi the evil wants to divide the N persons into some number of groups so that every person has no friend in his/her group.\n\nAt least how many groups does he need to make?\n\nConstraints\n\n2 \\leq N \\leq 2\\times 10^5\n\n0 \\leq M \\leq 2\\times 10^5\n\n1\\leq A_i,B_i\\leq N\n\nA_i \\neq B_i\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 B_1\n\\vdots\nA_M B_M\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n5 3\n1 2\n3 4\n5 1\n\nSample Output 1\n\n3\n\nDividing them into three groups such as \\{1,3\\}, \\{2,4\\}, and \\{5\\} achieves the goal.\n\nSample Input 2\n\n4 10\n1 2\n2 1\n1 2\n2 1\n1 2\n1 3\n1 4\n2 3\n2 4\n3 4\n\nSample Output 2\n\n4\n\nSample Input 3\n\n10 4\n3 1\n4 1\n5 9\n2 6\n\nSample Output 3\n\n3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1731, "cpu_time_ms": 54, "memory_kb": 5732}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s030600402", "group_id": "codeNet:p02575", "input_text": "#include<bits/stdc++.h>\n\n#define si(a) scanf(\"%d\",&a)\n#define sl(a) scanf(\"%lld\",&a)\n#define sd(a) scanf(\"%lf\",&a)\n#define sc(a) scahf(\"%c\",&a);\n#define ss(a) scanf(\"%s\",a)\n#define pi(a) printf(\"%d\\n\",a)\n#define pl(a) printf(\"%lld\\n\",a)\n#define pc(a) putchar(a)\n#define ms(a) memset(a,0,sizeof(a))\n#define repi(i, a, b) for(register int i=a;i<=b;++i)\n#define repd(i, a, b) for(register int i=a;i>=b;--i)\n#define reps(s) for(register int i=head[s];i;i=Next[i])\n#define ll long long\n#define ull unsigned long long\n#define vi vector<int>\n#define pii pair<int,int>\n#define mii unordered_map<int,int>\n#define msi unordered_map<string,int>\n#define lowbit(x) ((x)&(-(x)))\n#define ce(i, r) i==r?'\\n':' '\n#define pb push_back\n#define fi first\n#define se second\n#define all(x) x.begin(),x.end()\n#define INF 0x3f3f3f3f\n#define pr(x) cout<<#x<<\": \"<<x<<endl\nusing namespace std;\n\ninline int qr() {\n    int f = 0, fu = 1;\n    char c = getchar();\n    while (c < '0' || c > '9') {\n        if (c == '-')fu = -1;\n        c = getchar();\n    }\n    while (c >= '0' && c <= '9') {\n        f = (f << 3) + (f << 1) + c - 48;\n        c = getchar();\n    }\n    return f * fu;\n}\n\n\nconst int N = 4e5 + 10;\n\nstruct Seg_Tree {\n    struct T {\n        int l, r, ans, add;\n    } t[N * 4];\n\n    void build(int p, int l, int r) {\n        t[p].l = l, t[p].r = r, t[p].ans=INF, t[p].add = 0;\n        if (l == r)return;\n        int mid = (l + r) >> 1;\n        build(p << 1, l, mid);\n        build(p << 1 | 1, mid + 1, r);\n    }\n\n    void spread(int p) {\n        if (t[p].add) {\n            t[p << 1].ans = t[p].l - t[p].add;\n            t[p << 1].add = t[p].add;\n            t[p << 1 | 1].ans = ((t[p].l + t[p].r) >> 1) + 1 - t[p].add;\n            t[p << 1 | 1].add = t[p].add;\n            t[p].add = 0;\n        }\n    }\n\n    void change(int p, int l, int r, int c) {\n        //if (t[p].r < l || t[p].l > r)return;\n        if (l <= t[p].l && t[p].r <= r) {\n            t[p].ans = l - c, t[p].add = c;\n            return;\n        }\n        spread(p);\n        int mid = (t[p].l + t[p].r) >> 1;\n        if (l <= mid)change(p << 1, l, r, c);\n        if (r > mid)change(p << 1 | 1, l, r, c);\n        t[p].ans = min(t[p << 1].ans, t[p << 1 | 1].ans);\n    }\n\n    int ask(int p, int x) {\n        if (t[p].l == t[p].r)return x - t[p].ans;\n        spread(p);\n        int mid = (t[p].l + t[p].r) >> 1;\n        return x <= mid ? ask(p >> 1, x) : ask(p << 1 | 1, x);\n    }\n} tr;\n\nint n, m, now = 1;\n\nint main() {\n    n = qr(), m = qr();\n    tr.build(1, 1, m);\n    repi(i, 1, n) {\n        int l = qr(), r = qr();\n        if (now >= l && now <= r)tr.change(1, now, r, -INF), now = r + 1;\n        else if (now < l)tr.change(1, l, r, tr.ask(1, l - 1));\n        if (now > m) {\n            repi(j, i, n)puts(\"-1\");\n            return 0;\n        }\n        pi(i + tr.t[1].ans);\n    }\n    return 0;\n}", "language": "C++", "metadata": {"date": 1598739313, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02575.html", "problem_id": "p02575", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02575/input.txt", "sample_output_relpath": "derived/input_output/data/p02575/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02575/C++/s030600402.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s030600402", "user_id": "u593074754"}, "prompt_components": {"gold_output": "1\n3\n6\n-1\n", "input_to_evaluate": "#include<bits/stdc++.h>\n\n#define si(a) scanf(\"%d\",&a)\n#define sl(a) scanf(\"%lld\",&a)\n#define sd(a) scanf(\"%lf\",&a)\n#define sc(a) scahf(\"%c\",&a);\n#define ss(a) scanf(\"%s\",a)\n#define pi(a) printf(\"%d\\n\",a)\n#define pl(a) printf(\"%lld\\n\",a)\n#define pc(a) putchar(a)\n#define ms(a) memset(a,0,sizeof(a))\n#define repi(i, a, b) for(register int i=a;i<=b;++i)\n#define repd(i, a, b) for(register int i=a;i>=b;--i)\n#define reps(s) for(register int i=head[s];i;i=Next[i])\n#define ll long long\n#define ull unsigned long long\n#define vi vector<int>\n#define pii pair<int,int>\n#define mii unordered_map<int,int>\n#define msi unordered_map<string,int>\n#define lowbit(x) ((x)&(-(x)))\n#define ce(i, r) i==r?'\\n':' '\n#define pb push_back\n#define fi first\n#define se second\n#define all(x) x.begin(),x.end()\n#define INF 0x3f3f3f3f\n#define pr(x) cout<<#x<<\": \"<<x<<endl\nusing namespace std;\n\ninline int qr() {\n    int f = 0, fu = 1;\n    char c = getchar();\n    while (c < '0' || c > '9') {\n        if (c == '-')fu = -1;\n        c = getchar();\n    }\n    while (c >= '0' && c <= '9') {\n        f = (f << 3) + (f << 1) + c - 48;\n        c = getchar();\n    }\n    return f * fu;\n}\n\n\nconst int N = 4e5 + 10;\n\nstruct Seg_Tree {\n    struct T {\n        int l, r, ans, add;\n    } t[N * 4];\n\n    void build(int p, int l, int r) {\n        t[p].l = l, t[p].r = r, t[p].ans=INF, t[p].add = 0;\n        if (l == r)return;\n        int mid = (l + r) >> 1;\n        build(p << 1, l, mid);\n        build(p << 1 | 1, mid + 1, r);\n    }\n\n    void spread(int p) {\n        if (t[p].add) {\n            t[p << 1].ans = t[p].l - t[p].add;\n            t[p << 1].add = t[p].add;\n            t[p << 1 | 1].ans = ((t[p].l + t[p].r) >> 1) + 1 - t[p].add;\n            t[p << 1 | 1].add = t[p].add;\n            t[p].add = 0;\n        }\n    }\n\n    void change(int p, int l, int r, int c) {\n        //if (t[p].r < l || t[p].l > r)return;\n        if (l <= t[p].l && t[p].r <= r) {\n            t[p].ans = l - c, t[p].add = c;\n            return;\n        }\n        spread(p);\n        int mid = (t[p].l + t[p].r) >> 1;\n        if (l <= mid)change(p << 1, l, r, c);\n        if (r > mid)change(p << 1 | 1, l, r, c);\n        t[p].ans = min(t[p << 1].ans, t[p << 1 | 1].ans);\n    }\n\n    int ask(int p, int x) {\n        if (t[p].l == t[p].r)return x - t[p].ans;\n        spread(p);\n        int mid = (t[p].l + t[p].r) >> 1;\n        return x <= mid ? ask(p >> 1, x) : ask(p << 1 | 1, x);\n    }\n} tr;\n\nint n, m, now = 1;\n\nint main() {\n    n = qr(), m = qr();\n    tr.build(1, 1, m);\n    repi(i, 1, n) {\n        int l = qr(), r = qr();\n        if (now >= l && now <= r)tr.change(1, now, r, -INF), now = r + 1;\n        else if (now < l)tr.change(1, l, r, tr.ask(1, l - 1));\n        if (now > m) {\n            repi(j, i, n)puts(\"-1\");\n            return 0;\n        }\n        pi(i + tr.t[1].ans);\n    }\n    return 0;\n}", "problem_context": "Score : 600 points\n\nProblem Statement\n\nThere is a grid of squares with H+1 horizontal rows and W vertical columns.\n\nYou will start at one of the squares in the top row and repeat moving one square right or down. However, for each integer i from 1 through H, you cannot move down from the A_i-th, (A_i + 1)-th, \\ldots, B_i-th squares from the left in the i-th row from the top.\n\nFor each integer k from 1 through H, find the minimum number of moves needed to reach one of the squares in the (k+1)-th row from the top. (The starting square can be chosen individually for each case.) If, starting from any square in the top row, none of the squares in the (k+1)-th row can be reached, print -1 instead.\n\nConstraints\n\n1 \\leq H,W \\leq 2\\times 10^5\n\n1 \\leq A_i \\leq B_i \\leq W\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W\nA_1 B_1\nA_2 B_2\n:\nA_H B_H\n\nOutput\n\nPrint H lines. The i-th line should contain the answer for the case k=i.\n\nSample Input 1\n\n4 4\n2 4\n1 1\n2 3\n2 4\n\nSample Output 1\n\n1\n3\n6\n-1\n\nLet (i,j) denote the square at the i-th row from the top and j-th column from the left.\n\nFor k=1, we need one move such as (1,1) → (2,1).\n\nFor k=2, we need three moves such as (1,1) → (2,1) → (2,2) → (3,2).\n\nFor k=3, we need six moves such as (1,1) → (2,1) → (2,2) → (3,2) → (3,3) → (3,4) → (4,4).\n\nFor k=4, it is impossible to reach any square in the fifth row from the top.", "sample_input": "4 4\n2 4\n1 1\n2 3\n2 4\n"}, "reference_outputs": ["1\n3\n6\n-1\n"], "source_document_id": "p02575", "source_text": "Score : 600 points\n\nProblem Statement\n\nThere is a grid of squares with H+1 horizontal rows and W vertical columns.\n\nYou will start at one of the squares in the top row and repeat moving one square right or down. However, for each integer i from 1 through H, you cannot move down from the A_i-th, (A_i + 1)-th, \\ldots, B_i-th squares from the left in the i-th row from the top.\n\nFor each integer k from 1 through H, find the minimum number of moves needed to reach one of the squares in the (k+1)-th row from the top. (The starting square can be chosen individually for each case.) If, starting from any square in the top row, none of the squares in the (k+1)-th row can be reached, print -1 instead.\n\nConstraints\n\n1 \\leq H,W \\leq 2\\times 10^5\n\n1 \\leq A_i \\leq B_i \\leq W\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W\nA_1 B_1\nA_2 B_2\n:\nA_H B_H\n\nOutput\n\nPrint H lines. The i-th line should contain the answer for the case k=i.\n\nSample Input 1\n\n4 4\n2 4\n1 1\n2 3\n2 4\n\nSample Output 1\n\n1\n3\n6\n-1\n\nLet (i,j) denote the square at the i-th row from the top and j-th column from the left.\n\nFor k=1, we need one move such as (1,1) → (2,1).\n\nFor k=2, we need three moves such as (1,1) → (2,1) → (2,2) → (3,2).\n\nFor k=3, we need six moves such as (1,1) → (2,1) → (2,2) → (3,2) → (3,3) → (3,4) → (4,4).\n\nFor k=4, it is impossible to reach any square in the fifth row from the top.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2839, "cpu_time_ms": 2206, "memory_kb": 11804}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s391437372", "group_id": "codeNet:p02576", "input_text": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\n#define out(x) cout << x << '\\n'\n#define lli long long int\n#define uli unsigned long long int\n#define rep(i, m, n) for (lli i = m; i < (n); i++)\n#define repe(i, m, n) for (lli i = m; i <= (n); i++)\n#define ALL(x) (x).begin(), (x).end()\n#define SIZE(x) ((lli)(x).size())\n#define MAX(x) *max_element(ALL(x))\n#define MIN(x) *min_element(ALL(x))\n#define _GLIBCXX_DEBUG\nconst lli INF = 2147483647;\nconst lli MINF = -2147483648;\nconst lli LINF = 9223372036854775807;\nconst lli MOD = 1000000007; //10^9+7\nconst double PI = acos(-1);\n#define SORT(n) sort(n.begin(), n.end())\n#define SORTR(n) sort(n.begin(), n.end(), greater<int>())\n#define REV(n) reverse(n.begin(), n.end())\n#define pb push_back\n#define eb emplace_back\n#define mp make_pair\nusing vi = vector<int>;\nusing vvi = vector<vi>;\nusing vvvi = vector<vvi>;\nusing vlli = vector<lli>;\nusing vvli = vector<vlli>;\nusing vs = vector<string>;\nusing vvs = vector<vs>;\nusing vb = vector<bool>;\nusing vvb = vector<vb>;\nusing ll = long long;\n//---------------------------------------------------------------------------------------------------\n// vector入力\ntemplate <typename T>\nistream &operator>>(istream &is, vector<T> &vec)\n{\n  for (T &x : vec)\n    is >> x;\n  return is;\n}\n// vector出力\ntemplate <typename T>\nostream &operator<<(ostream &os, vector<T> &vec)\n{\n  // os << '{';\n  for (int i = 0; i < vec.size(); i++)\n  {\n    os << vec[i] << (i + 1 == vec.size() ? \"\" : \"\");\n  }\n  // os << '}';\n  return os;\n}\n// aよりもbが大きいならばaをbで更新する(更新されたならばtrueを返す)\ntemplate <typename T>\nbool chmax(T &a, const T &b)\n{\n  if (a < b)\n  {\n    a = b; // aをbで更新\n    return true;\n  }\n  return false;\n}\n// aよりもbが小さいならばaをbで更新する(更新されたならばtrueを返す)\ntemplate <typename T>\nbool chmin(T &a, const T &b)\n{\n  if (a > b)\n  {\n    a = b; // aをbで更新\n    return true;\n  }\n  return false;\n}\n//---------------------------------------------------------------------------------------------------\n//---------------------------------------------------------------------------------------------------\nvoid solve()\n{\n  lli a = 0, b = 0, c = 0, h = 0, n = 0, x, t, w = 0, ans = 0, count = 0;\n  vector<pair<lli, lli>> pr;\n  map<lli, lli> ma;\n  set<lli> st;\n\n  ios::sync_with_stdio(false);\n  cin.tie(nullptr);\n  cin >> n >> x >> t;\n  while (n > count)\n  {\n    count += x;\n    ans += t;\n  }\n  out(ans);\n  // if ()\n  // {\n  //   out(\"Yes\");\n  // }\n  // else\n  // {\n  //   out(\"No\");\n  // }\n}\n\n//---------------------------------------------------------------------------------------------------\nsigned main()\n{\n  solve();\n}", "language": "C++", "metadata": {"date": 1598124249, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02576.html", "problem_id": "p02576", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02576/input.txt", "sample_output_relpath": "derived/input_output/data/p02576/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02576/C++/s391437372.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s391437372", "user_id": "u363892646"}, "prompt_components": {"gold_output": "12\n", "input_to_evaluate": "#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\n#define out(x) cout << x << '\\n'\n#define lli long long int\n#define uli unsigned long long int\n#define rep(i, m, n) for (lli i = m; i < (n); i++)\n#define repe(i, m, n) for (lli i = m; i <= (n); i++)\n#define ALL(x) (x).begin(), (x).end()\n#define SIZE(x) ((lli)(x).size())\n#define MAX(x) *max_element(ALL(x))\n#define MIN(x) *min_element(ALL(x))\n#define _GLIBCXX_DEBUG\nconst lli INF = 2147483647;\nconst lli MINF = -2147483648;\nconst lli LINF = 9223372036854775807;\nconst lli MOD = 1000000007; //10^9+7\nconst double PI = acos(-1);\n#define SORT(n) sort(n.begin(), n.end())\n#define SORTR(n) sort(n.begin(), n.end(), greater<int>())\n#define REV(n) reverse(n.begin(), n.end())\n#define pb push_back\n#define eb emplace_back\n#define mp make_pair\nusing vi = vector<int>;\nusing vvi = vector<vi>;\nusing vvvi = vector<vvi>;\nusing vlli = vector<lli>;\nusing vvli = vector<vlli>;\nusing vs = vector<string>;\nusing vvs = vector<vs>;\nusing vb = vector<bool>;\nusing vvb = vector<vb>;\nusing ll = long long;\n//---------------------------------------------------------------------------------------------------\n// vector入力\ntemplate <typename T>\nistream &operator>>(istream &is, vector<T> &vec)\n{\n  for (T &x : vec)\n    is >> x;\n  return is;\n}\n// vector出力\ntemplate <typename T>\nostream &operator<<(ostream &os, vector<T> &vec)\n{\n  // os << '{';\n  for (int i = 0; i < vec.size(); i++)\n  {\n    os << vec[i] << (i + 1 == vec.size() ? \"\" : \"\");\n  }\n  // os << '}';\n  return os;\n}\n// aよりもbが大きいならばaをbで更新する(更新されたならばtrueを返す)\ntemplate <typename T>\nbool chmax(T &a, const T &b)\n{\n  if (a < b)\n  {\n    a = b; // aをbで更新\n    return true;\n  }\n  return false;\n}\n// aよりもbが小さいならばaをbで更新する(更新されたならばtrueを返す)\ntemplate <typename T>\nbool chmin(T &a, const T &b)\n{\n  if (a > b)\n  {\n    a = b; // aをbで更新\n    return true;\n  }\n  return false;\n}\n//---------------------------------------------------------------------------------------------------\n//---------------------------------------------------------------------------------------------------\nvoid solve()\n{\n  lli a = 0, b = 0, c = 0, h = 0, n = 0, x, t, w = 0, ans = 0, count = 0;\n  vector<pair<lli, lli>> pr;\n  map<lli, lli> ma;\n  set<lli> st;\n\n  ios::sync_with_stdio(false);\n  cin.tie(nullptr);\n  cin >> n >> x >> t;\n  while (n > count)\n  {\n    count += x;\n    ans += t;\n  }\n  out(ans);\n  // if ()\n  // {\n  //   out(\"Yes\");\n  // }\n  // else\n  // {\n  //   out(\"No\");\n  // }\n}\n\n//---------------------------------------------------------------------------------------------------\nsigned main()\n{\n  solve();\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nTakahashi loves takoyaki - a ball-shaped snack.\n\nWith a takoyaki machine, he can make at most X pieces of takoyaki at a time, taking T minutes regardless of the number of pieces to make.\n\nHow long does it take to make N takoyaki?\n\nConstraints\n\n1 \\leq N,X,T \\leq 1000\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN X T\n\nOutput\n\nPrint an integer representing the minimum number of minutes needed to make N pieces of takoyaki.\n\nSample Input 1\n\n20 12 6\n\nSample Output 1\n\n12\n\nHe can make 12 pieces of takoyaki in the first 6 minutes and 8 more in the next 6 minutes, so he can make 20 in a total of 12 minutes.\n\nNote that being able to make 12 in 6 minutes does not mean he can make 2 in 1 minute.\n\nSample Input 2\n\n1000 1 1000\n\nSample Output 2\n\n1000000\n\nIt seems to take a long time to make this kind of takoyaki.", "sample_input": "20 12 6\n"}, "reference_outputs": ["12\n"], "source_document_id": "p02576", "source_text": "Score : 100 points\n\nProblem Statement\n\nTakahashi loves takoyaki - a ball-shaped snack.\n\nWith a takoyaki machine, he can make at most X pieces of takoyaki at a time, taking T minutes regardless of the number of pieces to make.\n\nHow long does it take to make N takoyaki?\n\nConstraints\n\n1 \\leq N,X,T \\leq 1000\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN X T\n\nOutput\n\nPrint an integer representing the minimum number of minutes needed to make N pieces of takoyaki.\n\nSample Input 1\n\n20 12 6\n\nSample Output 1\n\n12\n\nHe can make 12 pieces of takoyaki in the first 6 minutes and 8 more in the next 6 minutes, so he can make 20 in a total of 12 minutes.\n\nNote that being able to make 12 in 6 minutes does not mean he can make 2 in 1 minute.\n\nSample Input 2\n\n1000 1 1000\n\nSample Output 2\n\n1000000\n\nIt seems to take a long time to make this kind of takoyaki.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2719, "cpu_time_ms": 7, "memory_kb": 3644}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s737260029", "group_id": "codeNet:p02576", "input_text": "#include <bits/stdc++.h>\n#define ll long long\n#define the_flash ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0)\n \nusing namespace std;\n \nint main()\n{\n    the_flash;\n    int n, x, t, sum = 0;\n    cin >> n >> x >> t;\n    \n    if (x > 1)\n    {\n        while (x * t <= n)\n            x += x;\n    }\n    else \n    {\n        cout << n * t << \"\\n\";\n        return 0;\n    }\n\n    cout << x << \"\\n\"; \n    return 0;\n}", "language": "C++", "metadata": {"date": 1598124070, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02576.html", "problem_id": "p02576", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02576/input.txt", "sample_output_relpath": "derived/input_output/data/p02576/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02576/C++/s737260029.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s737260029", "user_id": "u489075504"}, "prompt_components": {"gold_output": "12\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define ll long long\n#define the_flash ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0)\n \nusing namespace std;\n \nint main()\n{\n    the_flash;\n    int n, x, t, sum = 0;\n    cin >> n >> x >> t;\n    \n    if (x > 1)\n    {\n        while (x * t <= n)\n            x += x;\n    }\n    else \n    {\n        cout << n * t << \"\\n\";\n        return 0;\n    }\n\n    cout << x << \"\\n\"; \n    return 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nTakahashi loves takoyaki - a ball-shaped snack.\n\nWith a takoyaki machine, he can make at most X pieces of takoyaki at a time, taking T minutes regardless of the number of pieces to make.\n\nHow long does it take to make N takoyaki?\n\nConstraints\n\n1 \\leq N,X,T \\leq 1000\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN X T\n\nOutput\n\nPrint an integer representing the minimum number of minutes needed to make N pieces of takoyaki.\n\nSample Input 1\n\n20 12 6\n\nSample Output 1\n\n12\n\nHe can make 12 pieces of takoyaki in the first 6 minutes and 8 more in the next 6 minutes, so he can make 20 in a total of 12 minutes.\n\nNote that being able to make 12 in 6 minutes does not mean he can make 2 in 1 minute.\n\nSample Input 2\n\n1000 1 1000\n\nSample Output 2\n\n1000000\n\nIt seems to take a long time to make this kind of takoyaki.", "sample_input": "20 12 6\n"}, "reference_outputs": ["12\n"], "source_document_id": "p02576", "source_text": "Score : 100 points\n\nProblem Statement\n\nTakahashi loves takoyaki - a ball-shaped snack.\n\nWith a takoyaki machine, he can make at most X pieces of takoyaki at a time, taking T minutes regardless of the number of pieces to make.\n\nHow long does it take to make N takoyaki?\n\nConstraints\n\n1 \\leq N,X,T \\leq 1000\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN X T\n\nOutput\n\nPrint an integer representing the minimum number of minutes needed to make N pieces of takoyaki.\n\nSample Input 1\n\n20 12 6\n\nSample Output 1\n\n12\n\nHe can make 12 pieces of takoyaki in the first 6 minutes and 8 more in the next 6 minutes, so he can make 20 in a total of 12 minutes.\n\nNote that being able to make 12 in 6 minutes does not mean he can make 2 in 1 minute.\n\nSample Input 2\n\n1000 1 1000\n\nSample Output 2\n\n1000000\n\nIt seems to take a long time to make this kind of takoyaki.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 415, "cpu_time_ms": 9, "memory_kb": 3572}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s360486332", "group_id": "codeNet:p02576", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n \nint main() {\n    int N; cin >> N;\n    int X; cin >> X;\n    int T; cin >> T;\n    int ans = 0;\n    int tako = 0;\n\n    while(true){\n        ans += T;\n        tako += X;\n        if(tako >= N){\n            break;\n        }\n    }\n    cout << ans << endl;\n}", "language": "C++", "metadata": {"date": 1598123067, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02576.html", "problem_id": "p02576", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02576/input.txt", "sample_output_relpath": "derived/input_output/data/p02576/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02576/C++/s360486332.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s360486332", "user_id": "u757672175"}, "prompt_components": {"gold_output": "12\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n \nint main() {\n    int N; cin >> N;\n    int X; cin >> X;\n    int T; cin >> T;\n    int ans = 0;\n    int tako = 0;\n\n    while(true){\n        ans += T;\n        tako += X;\n        if(tako >= N){\n            break;\n        }\n    }\n    cout << ans << endl;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nTakahashi loves takoyaki - a ball-shaped snack.\n\nWith a takoyaki machine, he can make at most X pieces of takoyaki at a time, taking T minutes regardless of the number of pieces to make.\n\nHow long does it take to make N takoyaki?\n\nConstraints\n\n1 \\leq N,X,T \\leq 1000\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN X T\n\nOutput\n\nPrint an integer representing the minimum number of minutes needed to make N pieces of takoyaki.\n\nSample Input 1\n\n20 12 6\n\nSample Output 1\n\n12\n\nHe can make 12 pieces of takoyaki in the first 6 minutes and 8 more in the next 6 minutes, so he can make 20 in a total of 12 minutes.\n\nNote that being able to make 12 in 6 minutes does not mean he can make 2 in 1 minute.\n\nSample Input 2\n\n1000 1 1000\n\nSample Output 2\n\n1000000\n\nIt seems to take a long time to make this kind of takoyaki.", "sample_input": "20 12 6\n"}, "reference_outputs": ["12\n"], "source_document_id": "p02576", "source_text": "Score : 100 points\n\nProblem Statement\n\nTakahashi loves takoyaki - a ball-shaped snack.\n\nWith a takoyaki machine, he can make at most X pieces of takoyaki at a time, taking T minutes regardless of the number of pieces to make.\n\nHow long does it take to make N takoyaki?\n\nConstraints\n\n1 \\leq N,X,T \\leq 1000\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN X T\n\nOutput\n\nPrint an integer representing the minimum number of minutes needed to make N pieces of takoyaki.\n\nSample Input 1\n\n20 12 6\n\nSample Output 1\n\n12\n\nHe can make 12 pieces of takoyaki in the first 6 minutes and 8 more in the next 6 minutes, so he can make 20 in a total of 12 minutes.\n\nNote that being able to make 12 in 6 minutes does not mean he can make 2 in 1 minute.\n\nSample Input 2\n\n1000 1 1000\n\nSample Output 2\n\n1000000\n\nIt seems to take a long time to make this kind of takoyaki.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 298, "cpu_time_ms": 3, "memory_kb": 3616}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s486166135", "group_id": "codeNet:p02578", "input_text": "#include<stdio.h>\nint main()\n{\n   long long int n,s=0,a,b,i,m;\n    scanf(\"%lld\",&n);\n    scanf(\"%lld\",&a);\n    m=a;\n    for(i=1;i<n;i++)\n    {\n        scanf(\"%lld\",&b);\n        if(b>m)m=b;\n         else if(b<m)\n           s=m-b+s;\n    }\n    printf(\"%lld\\n\",s);\n}\n", "language": "C++", "metadata": {"date": 1598128772, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02578.html", "problem_id": "p02578", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02578/input.txt", "sample_output_relpath": "derived/input_output/data/p02578/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02578/C++/s486166135.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s486166135", "user_id": "u975689564"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include<stdio.h>\nint main()\n{\n   long long int n,s=0,a,b,i,m;\n    scanf(\"%lld\",&n);\n    scanf(\"%lld\",&a);\n    m=a;\n    for(i=1;i<n;i++)\n    {\n        scanf(\"%lld\",&b);\n        if(b>m)m=b;\n         else if(b<m)\n           s=m-b+s;\n    }\n    printf(\"%lld\\n\",s);\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nN persons are standing in a row. The height of the i-th person from the front is A_i.\n\nWe want to have each person stand on a stool of some heights - at least zero - so that the following condition is satisfied for every person:\n\nCondition: Nobody in front of the person is taller than the person. Here, the height of a person includes the stool.\n\nFind the minimum total height of the stools needed to meet this goal.\n\nConstraints\n\n1 \\leq N \\leq 2\\times 10^5\n\n1 \\leq A_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 \\ldots A_N\n\nOutput\n\nPrint the minimum total height of the stools needed to meet the goal.\n\nSample Input 1\n\n5\n2 1 5 4 3\n\nSample Output 1\n\n4\n\nIf the persons stand on stools of heights 0, 1, 0, 1, and 2, respectively, their heights will be 2, 2, 5, 5, and 5, satisfying the condition.\n\nWe cannot meet the goal with a smaller total height of the stools.\n\nSample Input 2\n\n5\n3 3 3 3 3\n\nSample Output 2\n\n0\n\nGiving a stool of height 0 to everyone will work.", "sample_input": "5\n2 1 5 4 3\n"}, "reference_outputs": ["4\n"], "source_document_id": "p02578", "source_text": "Score : 300 points\n\nProblem Statement\n\nN persons are standing in a row. The height of the i-th person from the front is A_i.\n\nWe want to have each person stand on a stool of some heights - at least zero - so that the following condition is satisfied for every person:\n\nCondition: Nobody in front of the person is taller than the person. Here, the height of a person includes the stool.\n\nFind the minimum total height of the stools needed to meet this goal.\n\nConstraints\n\n1 \\leq N \\leq 2\\times 10^5\n\n1 \\leq A_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 \\ldots A_N\n\nOutput\n\nPrint the minimum total height of the stools needed to meet the goal.\n\nSample Input 1\n\n5\n2 1 5 4 3\n\nSample Output 1\n\n4\n\nIf the persons stand on stools of heights 0, 1, 0, 1, and 2, respectively, their heights will be 2, 2, 5, 5, and 5, satisfying the condition.\n\nWe cannot meet the goal with a smaller total height of the stools.\n\nSample Input 2\n\n5\n3 3 3 3 3\n\nSample Output 2\n\n0\n\nGiving a stool of height 0 to everyone will work.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 263, "cpu_time_ms": 39, "memory_kb": 1704}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s731106383", "group_id": "codeNet:p02579", "input_text": "#include <bits/stdc++.h>\n\n#define fastio ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);\n#define endl \"\\n\"\n\nusing namespace std;\nusing ll = long long;\nusing P = pair<int, int>;\n\nconst ll MOD = 1000000007LL; // = 10^9 + 7\nconst double PI = 3.14159265358979;\n\nint h, w;\nint seen[1010][1010];\n\nvector<string> mp;\nint dx[4] = {0, -1, 0, 1};\nint dy[4] = {-1, 0, 1, 0};\n\nvoid bfs(queue<P> que, int lv)\n{\n  if (que.empty()) return;\n  queue<P> tmp;\n  tmp.push(que.front());\n\n  // 歩き\n  while(!que.empty())\n  {\n    P tp = que.front();\n    que.pop();\n    for(int i = 0; i < 4; ++i)\n    {\n      int ny = tp.first  + dy[i];\n      int nx = tp.second + dx[i];\n\n      if (ny < 0 || h <= ny) continue;\n      if (nx < 0 || w <= nx) continue;\n\n      if (seen[ny][nx] == 0 && mp[ny][nx] == '.')\n      {\n        seen[ny][nx] = lv;\n        que.push(P(ny, nx));\n        tmp.push(P(ny, nx));\n      }\n    }\n  }\n\n  // ワープ\n  queue<P> next_que;\n  while(!tmp.empty())\n  {\n    P tp = tmp.front();\n    tmp.pop();\n    for(int y = -2; y <= 2; ++y)\n    {\n      int ny = tp.first + y;\n      if (ny < 0 || h <= ny) continue;\n\n      for(int x = -2; x <= 2; ++x)\n      {\n        int nx = tp.second + x;\n        if (nx < 0 || w <= nx) continue;\n\n        if (seen[ny][nx] == 0 && mp[ny][nx] == '.')\n        {\n          seen[ny][nx] = lv + 1;\n          next_que.push(P(ny, nx));\n        }\n      }\n    }\n  }\n  bfs(next_que, lv + 1);\n}\n\nvoid solve()\n{\n  int cy, cx;\n  int dy, dx;\n\n  cin >> h >> w;\n  cin >> cy >> cx;\n  cin >> dy >> dx;\n\n  mp.resize(h);\n  cx--; cy--;\n  dx--; dy--;\n  for(int i = 0; i < h; ++i)\n  {\n    cin >> mp[i];\n  }\n\n  queue<P> que;\n  que.push(P(cy, cx));\n  seen[cy][cx] = 1;\n\n  bfs(que, 1);\n  /*\n  for(int ih = 0; ih < h; ++ih)\n  {\n    for(int iw = 0; iw < w; ++iw)\n    {\n      cout << seen[ih][iw];\n    }\n    cout << endl;\n  }\n  //*/\n  cout << seen[dy][dx] - 1;\n\n}\n\nint main()\n{\n  fastio;\n  solve();\n\n  return 0;\n}", "language": "C++", "metadata": {"date": 1598613920, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02579.html", "problem_id": "p02579", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02579/input.txt", "sample_output_relpath": "derived/input_output/data/p02579/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02579/C++/s731106383.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s731106383", "user_id": "u866535689"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\n#define fastio ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);\n#define endl \"\\n\"\n\nusing namespace std;\nusing ll = long long;\nusing P = pair<int, int>;\n\nconst ll MOD = 1000000007LL; // = 10^9 + 7\nconst double PI = 3.14159265358979;\n\nint h, w;\nint seen[1010][1010];\n\nvector<string> mp;\nint dx[4] = {0, -1, 0, 1};\nint dy[4] = {-1, 0, 1, 0};\n\nvoid bfs(queue<P> que, int lv)\n{\n  if (que.empty()) return;\n  queue<P> tmp;\n  tmp.push(que.front());\n\n  // 歩き\n  while(!que.empty())\n  {\n    P tp = que.front();\n    que.pop();\n    for(int i = 0; i < 4; ++i)\n    {\n      int ny = tp.first  + dy[i];\n      int nx = tp.second + dx[i];\n\n      if (ny < 0 || h <= ny) continue;\n      if (nx < 0 || w <= nx) continue;\n\n      if (seen[ny][nx] == 0 && mp[ny][nx] == '.')\n      {\n        seen[ny][nx] = lv;\n        que.push(P(ny, nx));\n        tmp.push(P(ny, nx));\n      }\n    }\n  }\n\n  // ワープ\n  queue<P> next_que;\n  while(!tmp.empty())\n  {\n    P tp = tmp.front();\n    tmp.pop();\n    for(int y = -2; y <= 2; ++y)\n    {\n      int ny = tp.first + y;\n      if (ny < 0 || h <= ny) continue;\n\n      for(int x = -2; x <= 2; ++x)\n      {\n        int nx = tp.second + x;\n        if (nx < 0 || w <= nx) continue;\n\n        if (seen[ny][nx] == 0 && mp[ny][nx] == '.')\n        {\n          seen[ny][nx] = lv + 1;\n          next_que.push(P(ny, nx));\n        }\n      }\n    }\n  }\n  bfs(next_que, lv + 1);\n}\n\nvoid solve()\n{\n  int cy, cx;\n  int dy, dx;\n\n  cin >> h >> w;\n  cin >> cy >> cx;\n  cin >> dy >> dx;\n\n  mp.resize(h);\n  cx--; cy--;\n  dx--; dy--;\n  for(int i = 0; i < h; ++i)\n  {\n    cin >> mp[i];\n  }\n\n  queue<P> que;\n  que.push(P(cy, cx));\n  seen[cy][cx] = 1;\n\n  bfs(que, 1);\n  /*\n  for(int ih = 0; ih < h; ++ih)\n  {\n    for(int iw = 0; iw < w; ++iw)\n    {\n      cout << seen[ih][iw];\n    }\n    cout << endl;\n  }\n  //*/\n  cout << seen[dy][dx] - 1;\n\n}\n\nint main()\n{\n  fastio;\n  solve();\n\n  return 0;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nA maze is composed of a grid of H \\times W squares - H vertical, W horizontal.\n\nThe square at the i-th row from the top and the j-th column from the left - (i,j) - is a wall if S_{ij} is # and a road if S_{ij} is ..\n\nThere is a magician in (C_h,C_w). He can do the following two kinds of moves:\n\nMove A: Walk to a road square that is vertically or horizontally adjacent to the square he is currently in.\n\nMove B: Use magic to warp himself to a road square in the 5\\times 5 area centered at the square he is currently in.\n\nIn either case, he cannot go out of the maze.\n\nAt least how many times does he need to use the magic to reach (D_h, D_w)?\n\nConstraints\n\n1 \\leq H,W \\leq 10^3\n\n1 \\leq C_h,D_h \\leq H\n\n1 \\leq C_w,D_w \\leq W\n\nS_{ij} is # or ..\n\nS_{C_h C_w} and S_{D_h D_w} are ..\n\n(C_h,C_w) \\neq (D_h,D_w)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W\nC_h C_w\nD_h D_w\nS_{11}\\ldots S_{1W}\n\\vdots\nS_{H1}\\ldots S_{HW}\n\nOutput\n\nPrint the minimum number of times the magician needs to use the magic. If he cannot reach (D_h,D_w), print -1 instead.\n\nSample Input 1\n\n4 4\n1 1\n4 4\n..#.\n..#.\n.#..\n.#..\n\nSample Output 1\n\n1\n\nFor example, by walking to (2,2) and then using the magic to travel to (4,4), just one use of magic is enough.\n\nNote that he cannot walk diagonally.\n\nSample Input 2\n\n4 4\n1 4\n4 1\n.##.\n####\n####\n.##.\n\nSample Output 2\n\n-1\n\nHe cannot move from there.\n\nSample Input 3\n\n4 4\n2 2\n3 3\n....\n....\n....\n....\n\nSample Output 3\n\n0\n\nNo use of magic is needed.\n\nSample Input 4\n\n4 5\n1 2\n2 5\n#.###\n####.\n#..##\n#..##\n\nSample Output 4\n\n2", "sample_input": "4 4\n1 1\n4 4\n..#.\n..#.\n.#..\n.#..\n"}, "reference_outputs": ["1\n"], "source_document_id": "p02579", "source_text": "Score : 400 points\n\nProblem Statement\n\nA maze is composed of a grid of H \\times W squares - H vertical, W horizontal.\n\nThe square at the i-th row from the top and the j-th column from the left - (i,j) - is a wall if S_{ij} is # and a road if S_{ij} is ..\n\nThere is a magician in (C_h,C_w). He can do the following two kinds of moves:\n\nMove A: Walk to a road square that is vertically or horizontally adjacent to the square he is currently in.\n\nMove B: Use magic to warp himself to a road square in the 5\\times 5 area centered at the square he is currently in.\n\nIn either case, he cannot go out of the maze.\n\nAt least how many times does he need to use the magic to reach (D_h, D_w)?\n\nConstraints\n\n1 \\leq H,W \\leq 10^3\n\n1 \\leq C_h,D_h \\leq H\n\n1 \\leq C_w,D_w \\leq W\n\nS_{ij} is # or ..\n\nS_{C_h C_w} and S_{D_h D_w} are ..\n\n(C_h,C_w) \\neq (D_h,D_w)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W\nC_h C_w\nD_h D_w\nS_{11}\\ldots S_{1W}\n\\vdots\nS_{H1}\\ldots S_{HW}\n\nOutput\n\nPrint the minimum number of times the magician needs to use the magic. If he cannot reach (D_h,D_w), print -1 instead.\n\nSample Input 1\n\n4 4\n1 1\n4 4\n..#.\n..#.\n.#..\n.#..\n\nSample Output 1\n\n1\n\nFor example, by walking to (2,2) and then using the magic to travel to (4,4), just one use of magic is enough.\n\nNote that he cannot walk diagonally.\n\nSample Input 2\n\n4 4\n1 4\n4 1\n.##.\n####\n####\n.##.\n\nSample Output 2\n\n-1\n\nHe cannot move from there.\n\nSample Input 3\n\n4 4\n2 2\n3 3\n....\n....\n....\n....\n\nSample Output 3\n\n0\n\nNo use of magic is needed.\n\nSample Input 4\n\n4 5\n1 2\n2 5\n#.###\n####.\n#..##\n#..##\n\nSample Output 4\n\n2", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1918, "cpu_time_ms": 95, "memory_kb": 10380}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s314041453", "group_id": "codeNet:p02579", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\n\n#define F first\n#define S second\n#define pb push_back\n#define mp make_pair\n\nll gcd(ll a, ll b){\n\tif (a == 0) return b;\n\treturn gcd(b%a, a);\n}\n\nll lcm(ll a, ll b){\n\treturn (a/gcd(a, b))*b;\n}\n\nll ans = 1e10;\nll n,m,xi,yi , xf,yf;\nll a[1004][1004];\n\nbool check(ll x, ll y)\n{\n\treturn (x >= 0 && y >= 0 && x < n && y < m);\n}\n\nll b[] = {0 , 0 , 1, -1};\nll d[] = {-1 , 1 , 0 , 0};\n\n\nvoid solve(ll cx ,ll cy ,ll fx ,ll fy ,ll cnt)\n{\n\tif(cx == fx && cy == fy)\n\t{\n\t\tans = min(ans,cnt);\n\t}\n\n\ta[cx][cy] = 1;\n\n\tfor(ll i=0;i<4;i++)\n\t{\n\t\tll nx = cx + b[i];\n\t\tll ny = cy + d[i];\n\n\t\tif(check(nx,ny))\n\t\t{\n\t\t\tif(a[nx][ny] == 0)\n\t\t\t\tsolve(nx,ny,fx,fy,cnt);\n\t\t}\n\t}\n\n\n\tfor(ll i=-2;i<3;i++)\n\t{\n\t\tfor(ll j=-2;j<3;j++)\n\t\t{\n\t\t\tll nx = cx + i;\n\t\t\tll ny = cy + j;\n\t\t\tif(check(nx,ny))\n\t\t\t{\n\t\t\t\tif(a[nx][ny] == 0)\n\t\t\t\t{\n\t\t\t\t\tsolve(nx,ny,fx,fy,cnt+1);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n}\n\nint main()\n{\n\tios_base::sync_with_stdio(false);\n\tcin.tie(NULL);\n\tcout.tie(NULL);\n\n\n\tcin >> n >> m >> xi >> yi >> xf >> yf;\n\tll i,j;\n\n\n\tfor(i=0;i<n;i++)\n\t{\n\t\tfor(j=0;j<m;j++)\n\t\t{\n\t\t\tchar c;\n\t\t\tcin >> c;\n\n\t\t\tif(c == '.')\n\t\t\t\ta[i][j] = 0;\n\t\t\telse\n\t\t\t\ta[i][j] = 2;\n\t\t}\n\t}\n\n\tsolve(xi-1, yi - 1 , xf-1 , yf-1 ,0);\n\n\n\tif(ans == 1e10)\n\t\tcout << -1 << endl;\n\telse\n\t\tcout << ans << endl;\n}", "language": "C++", "metadata": {"date": 1598131332, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02579.html", "problem_id": "p02579", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02579/input.txt", "sample_output_relpath": "derived/input_output/data/p02579/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02579/C++/s314041453.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s314041453", "user_id": "u705313695"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\n\n#define F first\n#define S second\n#define pb push_back\n#define mp make_pair\n\nll gcd(ll a, ll b){\n\tif (a == 0) return b;\n\treturn gcd(b%a, a);\n}\n\nll lcm(ll a, ll b){\n\treturn (a/gcd(a, b))*b;\n}\n\nll ans = 1e10;\nll n,m,xi,yi , xf,yf;\nll a[1004][1004];\n\nbool check(ll x, ll y)\n{\n\treturn (x >= 0 && y >= 0 && x < n && y < m);\n}\n\nll b[] = {0 , 0 , 1, -1};\nll d[] = {-1 , 1 , 0 , 0};\n\n\nvoid solve(ll cx ,ll cy ,ll fx ,ll fy ,ll cnt)\n{\n\tif(cx == fx && cy == fy)\n\t{\n\t\tans = min(ans,cnt);\n\t}\n\n\ta[cx][cy] = 1;\n\n\tfor(ll i=0;i<4;i++)\n\t{\n\t\tll nx = cx + b[i];\n\t\tll ny = cy + d[i];\n\n\t\tif(check(nx,ny))\n\t\t{\n\t\t\tif(a[nx][ny] == 0)\n\t\t\t\tsolve(nx,ny,fx,fy,cnt);\n\t\t}\n\t}\n\n\n\tfor(ll i=-2;i<3;i++)\n\t{\n\t\tfor(ll j=-2;j<3;j++)\n\t\t{\n\t\t\tll nx = cx + i;\n\t\t\tll ny = cy + j;\n\t\t\tif(check(nx,ny))\n\t\t\t{\n\t\t\t\tif(a[nx][ny] == 0)\n\t\t\t\t{\n\t\t\t\t\tsolve(nx,ny,fx,fy,cnt+1);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n}\n\nint main()\n{\n\tios_base::sync_with_stdio(false);\n\tcin.tie(NULL);\n\tcout.tie(NULL);\n\n\n\tcin >> n >> m >> xi >> yi >> xf >> yf;\n\tll i,j;\n\n\n\tfor(i=0;i<n;i++)\n\t{\n\t\tfor(j=0;j<m;j++)\n\t\t{\n\t\t\tchar c;\n\t\t\tcin >> c;\n\n\t\t\tif(c == '.')\n\t\t\t\ta[i][j] = 0;\n\t\t\telse\n\t\t\t\ta[i][j] = 2;\n\t\t}\n\t}\n\n\tsolve(xi-1, yi - 1 , xf-1 , yf-1 ,0);\n\n\n\tif(ans == 1e10)\n\t\tcout << -1 << endl;\n\telse\n\t\tcout << ans << endl;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nA maze is composed of a grid of H \\times W squares - H vertical, W horizontal.\n\nThe square at the i-th row from the top and the j-th column from the left - (i,j) - is a wall if S_{ij} is # and a road if S_{ij} is ..\n\nThere is a magician in (C_h,C_w). He can do the following two kinds of moves:\n\nMove A: Walk to a road square that is vertically or horizontally adjacent to the square he is currently in.\n\nMove B: Use magic to warp himself to a road square in the 5\\times 5 area centered at the square he is currently in.\n\nIn either case, he cannot go out of the maze.\n\nAt least how many times does he need to use the magic to reach (D_h, D_w)?\n\nConstraints\n\n1 \\leq H,W \\leq 10^3\n\n1 \\leq C_h,D_h \\leq H\n\n1 \\leq C_w,D_w \\leq W\n\nS_{ij} is # or ..\n\nS_{C_h C_w} and S_{D_h D_w} are ..\n\n(C_h,C_w) \\neq (D_h,D_w)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W\nC_h C_w\nD_h D_w\nS_{11}\\ldots S_{1W}\n\\vdots\nS_{H1}\\ldots S_{HW}\n\nOutput\n\nPrint the minimum number of times the magician needs to use the magic. If he cannot reach (D_h,D_w), print -1 instead.\n\nSample Input 1\n\n4 4\n1 1\n4 4\n..#.\n..#.\n.#..\n.#..\n\nSample Output 1\n\n1\n\nFor example, by walking to (2,2) and then using the magic to travel to (4,4), just one use of magic is enough.\n\nNote that he cannot walk diagonally.\n\nSample Input 2\n\n4 4\n1 4\n4 1\n.##.\n####\n####\n.##.\n\nSample Output 2\n\n-1\n\nHe cannot move from there.\n\nSample Input 3\n\n4 4\n2 2\n3 3\n....\n....\n....\n....\n\nSample Output 3\n\n0\n\nNo use of magic is needed.\n\nSample Input 4\n\n4 5\n1 2\n2 5\n#.###\n####.\n#..##\n#..##\n\nSample Output 4\n\n2", "sample_input": "4 4\n1 1\n4 4\n..#.\n..#.\n.#..\n.#..\n"}, "reference_outputs": ["1\n"], "source_document_id": "p02579", "source_text": "Score : 400 points\n\nProblem Statement\n\nA maze is composed of a grid of H \\times W squares - H vertical, W horizontal.\n\nThe square at the i-th row from the top and the j-th column from the left - (i,j) - is a wall if S_{ij} is # and a road if S_{ij} is ..\n\nThere is a magician in (C_h,C_w). He can do the following two kinds of moves:\n\nMove A: Walk to a road square that is vertically or horizontally adjacent to the square he is currently in.\n\nMove B: Use magic to warp himself to a road square in the 5\\times 5 area centered at the square he is currently in.\n\nIn either case, he cannot go out of the maze.\n\nAt least how many times does he need to use the magic to reach (D_h, D_w)?\n\nConstraints\n\n1 \\leq H,W \\leq 10^3\n\n1 \\leq C_h,D_h \\leq H\n\n1 \\leq C_w,D_w \\leq W\n\nS_{ij} is # or ..\n\nS_{C_h C_w} and S_{D_h D_w} are ..\n\n(C_h,C_w) \\neq (D_h,D_w)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W\nC_h C_w\nD_h D_w\nS_{11}\\ldots S_{1W}\n\\vdots\nS_{H1}\\ldots S_{HW}\n\nOutput\n\nPrint the minimum number of times the magician needs to use the magic. If he cannot reach (D_h,D_w), print -1 instead.\n\nSample Input 1\n\n4 4\n1 1\n4 4\n..#.\n..#.\n.#..\n.#..\n\nSample Output 1\n\n1\n\nFor example, by walking to (2,2) and then using the magic to travel to (4,4), just one use of magic is enough.\n\nNote that he cannot walk diagonally.\n\nSample Input 2\n\n4 4\n1 4\n4 1\n.##.\n####\n####\n.##.\n\nSample Output 2\n\n-1\n\nHe cannot move from there.\n\nSample Input 3\n\n4 4\n2 2\n3 3\n....\n....\n....\n....\n\nSample Output 3\n\n0\n\nNo use of magic is needed.\n\nSample Input 4\n\n4 5\n1 2\n2 5\n#.###\n####.\n#..##\n#..##\n\nSample Output 4\n\n2", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1293, "cpu_time_ms": 91, "memory_kb": 50644}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s772403893", "group_id": "codeNet:p02584", "input_text": "// https://atcoder.jp/contests/abc175/tasks/abc175_c\n#include <iostream>\n#include <vector>\n#include <deque>\n#include <tuple>\n#include <algorithm>\n#include <iterator> // std::back_inserter\n\nusing namespace std;\n\nint main()\n{\n    long long x, k, d;\n    cin >> x >> k >> d;\n    long long mod = x % d;\n    long long div = x / d;\n    if (d * k < x)\n    {\n        cout << x - d * k << endl;\n        exit(0);\n    }\n    long long a = (x / d) * d;\n    if ((k - div) % 2 == 0)\n    {\n        cout << x - a << endl;\n    }\n    else\n    {\n        cout << d - (x - a) << endl;\n    }\n}\n", "language": "C++", "metadata": {"date": 1598472700, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02584.html", "problem_id": "p02584", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02584/input.txt", "sample_output_relpath": "derived/input_output/data/p02584/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02584/C++/s772403893.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s772403893", "user_id": "u904912386"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "// https://atcoder.jp/contests/abc175/tasks/abc175_c\n#include <iostream>\n#include <vector>\n#include <deque>\n#include <tuple>\n#include <algorithm>\n#include <iterator> // std::back_inserter\n\nusing namespace std;\n\nint main()\n{\n    long long x, k, d;\n    cin >> x >> k >> d;\n    long long mod = x % d;\n    long long div = x / d;\n    if (d * k < x)\n    {\n        cout << x - d * k << endl;\n        exit(0);\n    }\n    long long a = (x / d) * d;\n    if ((k - div) % 2 == 0)\n    {\n        cout << x - a << endl;\n    }\n    else\n    {\n        cout << d - (x - a) << endl;\n    }\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nTakahashi, who lives on the number line, is now at coordinate X. He will make exactly K moves of distance D in the positive or negative direction.\n\nMore specifically, in one move, he can go from coordinate x to x + D or x - D.\n\nHe wants to make K moves so that the absolute value of the coordinate of the destination will be the smallest possible.\n\nFind the minimum possible absolute value of the coordinate of the destination.\n\nConstraints\n\n-10^{15} \\leq X \\leq 10^{15}\n\n1 \\leq K \\leq 10^{15}\n\n1 \\leq D \\leq 10^{15}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX K D\n\nOutput\n\nPrint the minimum possible absolute value of the coordinate of the destination.\n\nSample Input 1\n\n6 2 4\n\nSample Output 1\n\n2\n\nTakahashi is now at coordinate 6. It is optimal to make the following moves:\n\nMove from coordinate 6 to (6 - 4 =) 2.\n\nMove from coordinate 2 to (2 - 4 =) -2.\n\nHere, the absolute value of the coordinate of the destination is 2, and we cannot make it smaller.\n\nSample Input 2\n\n7 4 3\n\nSample Output 2\n\n1\n\nTakahashi is now at coordinate 7. It is optimal to make, for example, the following moves:\n\nMove from coordinate 7 to 4.\n\nMove from coordinate 4 to 7.\n\nMove from coordinate 7 to 4.\n\nMove from coordinate 4 to 1.\n\nHere, the absolute value of the coordinate of the destination is 1, and we cannot make it smaller.\n\nSample Input 3\n\n10 1 2\n\nSample Output 3\n\n8\n\nSample Input 4\n\n1000000000000000 1000000000000000 1000000000000000\n\nSample Output 4\n\n1000000000000000\n\nThe answer can be enormous.", "sample_input": "6 2 4\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02584", "source_text": "Score : 300 points\n\nProblem Statement\n\nTakahashi, who lives on the number line, is now at coordinate X. He will make exactly K moves of distance D in the positive or negative direction.\n\nMore specifically, in one move, he can go from coordinate x to x + D or x - D.\n\nHe wants to make K moves so that the absolute value of the coordinate of the destination will be the smallest possible.\n\nFind the minimum possible absolute value of the coordinate of the destination.\n\nConstraints\n\n-10^{15} \\leq X \\leq 10^{15}\n\n1 \\leq K \\leq 10^{15}\n\n1 \\leq D \\leq 10^{15}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX K D\n\nOutput\n\nPrint the minimum possible absolute value of the coordinate of the destination.\n\nSample Input 1\n\n6 2 4\n\nSample Output 1\n\n2\n\nTakahashi is now at coordinate 6. It is optimal to make the following moves:\n\nMove from coordinate 6 to (6 - 4 =) 2.\n\nMove from coordinate 2 to (2 - 4 =) -2.\n\nHere, the absolute value of the coordinate of the destination is 2, and we cannot make it smaller.\n\nSample Input 2\n\n7 4 3\n\nSample Output 2\n\n1\n\nTakahashi is now at coordinate 7. It is optimal to make, for example, the following moves:\n\nMove from coordinate 7 to 4.\n\nMove from coordinate 4 to 7.\n\nMove from coordinate 7 to 4.\n\nMove from coordinate 4 to 1.\n\nHere, the absolute value of the coordinate of the destination is 1, and we cannot make it smaller.\n\nSample Input 3\n\n10 1 2\n\nSample Output 3\n\n8\n\nSample Input 4\n\n1000000000000000 1000000000000000 1000000000000000\n\nSample Output 4\n\n1000000000000000\n\nThe answer can be enormous.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 570, "cpu_time_ms": 9, "memory_kb": 3624}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s515783394", "group_id": "codeNet:p02584", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  long long x,k,d;\n  cin >> x >> k >> d;\n  //xは現在の座標\n  //kは移動回数\n  //dは一回の移動距離\n  \n  while(abs(x)>abs(d)){\n      if(x>=0){\n        x-=d;\n        k--;\n      }\n      else{\n        x+=d;\n        k--;\n      }\n    if(k==0) break;\n  }\n  if(k%2==0){\n    cout << abs(x) << endl;\n    return 0;}\n  else{\n    if(x>=0)x-=d;\n    else x+=d;\n  }\n    cout << abs(x) << endl;\n    return 0;\n  }", "language": "C++", "metadata": {"date": 1597836197, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02584.html", "problem_id": "p02584", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02584/input.txt", "sample_output_relpath": "derived/input_output/data/p02584/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02584/C++/s515783394.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s515783394", "user_id": "u461563687"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  long long x,k,d;\n  cin >> x >> k >> d;\n  //xは現在の座標\n  //kは移動回数\n  //dは一回の移動距離\n  \n  while(abs(x)>abs(d)){\n      if(x>=0){\n        x-=d;\n        k--;\n      }\n      else{\n        x+=d;\n        k--;\n      }\n    if(k==0) break;\n  }\n  if(k%2==0){\n    cout << abs(x) << endl;\n    return 0;}\n  else{\n    if(x>=0)x-=d;\n    else x+=d;\n  }\n    cout << abs(x) << endl;\n    return 0;\n  }", "problem_context": "Score : 300 points\n\nProblem Statement\n\nTakahashi, who lives on the number line, is now at coordinate X. He will make exactly K moves of distance D in the positive or negative direction.\n\nMore specifically, in one move, he can go from coordinate x to x + D or x - D.\n\nHe wants to make K moves so that the absolute value of the coordinate of the destination will be the smallest possible.\n\nFind the minimum possible absolute value of the coordinate of the destination.\n\nConstraints\n\n-10^{15} \\leq X \\leq 10^{15}\n\n1 \\leq K \\leq 10^{15}\n\n1 \\leq D \\leq 10^{15}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX K D\n\nOutput\n\nPrint the minimum possible absolute value of the coordinate of the destination.\n\nSample Input 1\n\n6 2 4\n\nSample Output 1\n\n2\n\nTakahashi is now at coordinate 6. It is optimal to make the following moves:\n\nMove from coordinate 6 to (6 - 4 =) 2.\n\nMove from coordinate 2 to (2 - 4 =) -2.\n\nHere, the absolute value of the coordinate of the destination is 2, and we cannot make it smaller.\n\nSample Input 2\n\n7 4 3\n\nSample Output 2\n\n1\n\nTakahashi is now at coordinate 7. It is optimal to make, for example, the following moves:\n\nMove from coordinate 7 to 4.\n\nMove from coordinate 4 to 7.\n\nMove from coordinate 7 to 4.\n\nMove from coordinate 4 to 1.\n\nHere, the absolute value of the coordinate of the destination is 1, and we cannot make it smaller.\n\nSample Input 3\n\n10 1 2\n\nSample Output 3\n\n8\n\nSample Input 4\n\n1000000000000000 1000000000000000 1000000000000000\n\nSample Output 4\n\n1000000000000000\n\nThe answer can be enormous.", "sample_input": "6 2 4\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02584", "source_text": "Score : 300 points\n\nProblem Statement\n\nTakahashi, who lives on the number line, is now at coordinate X. He will make exactly K moves of distance D in the positive or negative direction.\n\nMore specifically, in one move, he can go from coordinate x to x + D or x - D.\n\nHe wants to make K moves so that the absolute value of the coordinate of the destination will be the smallest possible.\n\nFind the minimum possible absolute value of the coordinate of the destination.\n\nConstraints\n\n-10^{15} \\leq X \\leq 10^{15}\n\n1 \\leq K \\leq 10^{15}\n\n1 \\leq D \\leq 10^{15}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX K D\n\nOutput\n\nPrint the minimum possible absolute value of the coordinate of the destination.\n\nSample Input 1\n\n6 2 4\n\nSample Output 1\n\n2\n\nTakahashi is now at coordinate 6. It is optimal to make the following moves:\n\nMove from coordinate 6 to (6 - 4 =) 2.\n\nMove from coordinate 2 to (2 - 4 =) -2.\n\nHere, the absolute value of the coordinate of the destination is 2, and we cannot make it smaller.\n\nSample Input 2\n\n7 4 3\n\nSample Output 2\n\n1\n\nTakahashi is now at coordinate 7. It is optimal to make, for example, the following moves:\n\nMove from coordinate 7 to 4.\n\nMove from coordinate 4 to 7.\n\nMove from coordinate 7 to 4.\n\nMove from coordinate 4 to 1.\n\nHere, the absolute value of the coordinate of the destination is 1, and we cannot make it smaller.\n\nSample Input 3\n\n10 1 2\n\nSample Output 3\n\n8\n\nSample Input 4\n\n1000000000000000 1000000000000000 1000000000000000\n\nSample Output 4\n\n1000000000000000\n\nThe answer can be enormous.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 470, "cpu_time_ms": 2205, "memory_kb": 3564}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s979826880", "group_id": "codeNet:p02584", "input_text": "/****************************************\n\n\t\t\tLostMartian\n\n****************************************/\n#pragma GCC target(\"avx,avx2,fma\") \n#pragma GCC optimize(\"Ofast\")  \n#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <fstream>\n#include <queue>\n#include <deque>\n#include <bitset>\n#include <iterator>\n#include <list>\n#include <stack>\n#include <map>\n#include <unordered_map>\n#include <unordered_set>\n#include <set>\n#include <functional>\n#include <utility>\n#include <climits>\n#include <numeric>\n#include <cmath>\n#include <cstdio>\n#include <cstring>\n#include <iomanip>\n#include <cassert>\nusing namespace std;\ntypedef long long ll;\n\ntemplate <typename Arg1>\nvoid pn(Arg1&& arg1) {\n\tcout << arg1 << \"\\n\";\n}\ntemplate <typename Arg1, typename... Args>\nvoid pn(Arg1&& arg1, Args&&... args) { \n\tcout << arg1 << \" \"; \n\tpn(args...); \n}\ntemplate <typename Arg1>\nvoid ps(Arg1&& arg1) { \n\tcout << arg1 << \" \";\n}\ntemplate <typename Arg1, typename... Args>\nvoid ps(Arg1&& arg1, Args&&... args) { \n\tcout << arg1 << \" \"; \n\tps(args...); \n}\ntemplate <typename Arg1>\nvoid read(Arg1&& arg1) {\n\tcin >> arg1; \n}\ntemplate <typename Arg1, typename... Args>\nvoid read(Arg1&& arg1, Args&&... args) { \n\tcin >> arg1; \n\tread(args...); \n}\n\n#define rep(i,m,n) for(ll i=m; i<n; i++)\n#define repr(i,m,n) for(ll i=m; i>=n; i--)\n#define vll vector<ll >\n#define vvl vector<vector<ll > >\n#define pi pair<ll, ll >\n#define vpi vector<pi >\n#define umap unordered_map<ll, ll >\n#define pb push_back\n#define mk make_pair\n#define sz size()\n#define fi first\n#define se second\n#define all(x) x.begin(), x.end()\n#define test ll t; cin>>t; while(t--)\n#define ini(a, x) memset(a, x, sizeof(a))\n#define d(x) cout<<\"Value of \"#x\" = \"<<x<<\"\\n\";\n#define debug(...) fprintf(stderr, __VA_ARGS__), fflush(stderr)\n#define iAmSpeed ios_base::sync_with_stdio(false); cin.tie(NULL);\nvoid LOCAL();\nint main()\n{\n\tclock_t z = clock();\n\t//LOCAL();\n\tiAmSpeed\n\tll x, k, d;\n\tcin>>x>>k>>d;\n\tll m=abs(x)/d;\n\tif(m>=k) {\n\t\tif(x<0) {\n\t\t\tpn(-x-d*k);\n\t\t\treturn 0;\n\t\t}\n\t\telse {\n\t\t\tpn(x-d*k);\n\t\t\treturn 0;\n\t\t}\n\t}\n\tif(x<0) {\n\t\tx+=m*d;\n\t\tk-=m;\n\t\tif(!(k&1)) {\n\t\t\tpn(min(-x,x+d));\n\t\t}\n\t\telse {\n\t\t\tpn(min(abs(d-x), abs(-x-d)));\n\t\t}\n\t} \n\telse {\n\t\tx-=m*d;\n\t\tk-=m;\n\t\tif(!(k&1)) {\n\t\t\tpn(min(x, d-x));\n\t\t}\n\t\telse {\n\t\t\tpn(min(abs(d+x), abs(x-d)));\n\t\t}\n\n\t}\n\n\n\n\n\n\n\n\n\n\n\n\n\n\tdebug(\"Total Time: %.7f\\n\", (double)(clock() - z) / CLOCKS_PER_SEC);\n\treturn 0;\n}\nvoid LOCAL() {\n\t#ifndef ONLINE_JUDGE\n\tfreopen(\"input.txt\", \"r\", stdin);\n\tfreopen(\"output.txt\", \"w\", stdout);\n\t#endif\n}\n", "language": "C++", "metadata": {"date": 1597521680, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02584.html", "problem_id": "p02584", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02584/input.txt", "sample_output_relpath": "derived/input_output/data/p02584/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02584/C++/s979826880.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s979826880", "user_id": "u764177390"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "/****************************************\n\n\t\t\tLostMartian\n\n****************************************/\n#pragma GCC target(\"avx,avx2,fma\") \n#pragma GCC optimize(\"Ofast\")  \n#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <fstream>\n#include <queue>\n#include <deque>\n#include <bitset>\n#include <iterator>\n#include <list>\n#include <stack>\n#include <map>\n#include <unordered_map>\n#include <unordered_set>\n#include <set>\n#include <functional>\n#include <utility>\n#include <climits>\n#include <numeric>\n#include <cmath>\n#include <cstdio>\n#include <cstring>\n#include <iomanip>\n#include <cassert>\nusing namespace std;\ntypedef long long ll;\n\ntemplate <typename Arg1>\nvoid pn(Arg1&& arg1) {\n\tcout << arg1 << \"\\n\";\n}\ntemplate <typename Arg1, typename... Args>\nvoid pn(Arg1&& arg1, Args&&... args) { \n\tcout << arg1 << \" \"; \n\tpn(args...); \n}\ntemplate <typename Arg1>\nvoid ps(Arg1&& arg1) { \n\tcout << arg1 << \" \";\n}\ntemplate <typename Arg1, typename... Args>\nvoid ps(Arg1&& arg1, Args&&... args) { \n\tcout << arg1 << \" \"; \n\tps(args...); \n}\ntemplate <typename Arg1>\nvoid read(Arg1&& arg1) {\n\tcin >> arg1; \n}\ntemplate <typename Arg1, typename... Args>\nvoid read(Arg1&& arg1, Args&&... args) { \n\tcin >> arg1; \n\tread(args...); \n}\n\n#define rep(i,m,n) for(ll i=m; i<n; i++)\n#define repr(i,m,n) for(ll i=m; i>=n; i--)\n#define vll vector<ll >\n#define vvl vector<vector<ll > >\n#define pi pair<ll, ll >\n#define vpi vector<pi >\n#define umap unordered_map<ll, ll >\n#define pb push_back\n#define mk make_pair\n#define sz size()\n#define fi first\n#define se second\n#define all(x) x.begin(), x.end()\n#define test ll t; cin>>t; while(t--)\n#define ini(a, x) memset(a, x, sizeof(a))\n#define d(x) cout<<\"Value of \"#x\" = \"<<x<<\"\\n\";\n#define debug(...) fprintf(stderr, __VA_ARGS__), fflush(stderr)\n#define iAmSpeed ios_base::sync_with_stdio(false); cin.tie(NULL);\nvoid LOCAL();\nint main()\n{\n\tclock_t z = clock();\n\t//LOCAL();\n\tiAmSpeed\n\tll x, k, d;\n\tcin>>x>>k>>d;\n\tll m=abs(x)/d;\n\tif(m>=k) {\n\t\tif(x<0) {\n\t\t\tpn(-x-d*k);\n\t\t\treturn 0;\n\t\t}\n\t\telse {\n\t\t\tpn(x-d*k);\n\t\t\treturn 0;\n\t\t}\n\t}\n\tif(x<0) {\n\t\tx+=m*d;\n\t\tk-=m;\n\t\tif(!(k&1)) {\n\t\t\tpn(min(-x,x+d));\n\t\t}\n\t\telse {\n\t\t\tpn(min(abs(d-x), abs(-x-d)));\n\t\t}\n\t} \n\telse {\n\t\tx-=m*d;\n\t\tk-=m;\n\t\tif(!(k&1)) {\n\t\t\tpn(min(x, d-x));\n\t\t}\n\t\telse {\n\t\t\tpn(min(abs(d+x), abs(x-d)));\n\t\t}\n\n\t}\n\n\n\n\n\n\n\n\n\n\n\n\n\n\tdebug(\"Total Time: %.7f\\n\", (double)(clock() - z) / CLOCKS_PER_SEC);\n\treturn 0;\n}\nvoid LOCAL() {\n\t#ifndef ONLINE_JUDGE\n\tfreopen(\"input.txt\", \"r\", stdin);\n\tfreopen(\"output.txt\", \"w\", stdout);\n\t#endif\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nTakahashi, who lives on the number line, is now at coordinate X. He will make exactly K moves of distance D in the positive or negative direction.\n\nMore specifically, in one move, he can go from coordinate x to x + D or x - D.\n\nHe wants to make K moves so that the absolute value of the coordinate of the destination will be the smallest possible.\n\nFind the minimum possible absolute value of the coordinate of the destination.\n\nConstraints\n\n-10^{15} \\leq X \\leq 10^{15}\n\n1 \\leq K \\leq 10^{15}\n\n1 \\leq D \\leq 10^{15}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX K D\n\nOutput\n\nPrint the minimum possible absolute value of the coordinate of the destination.\n\nSample Input 1\n\n6 2 4\n\nSample Output 1\n\n2\n\nTakahashi is now at coordinate 6. It is optimal to make the following moves:\n\nMove from coordinate 6 to (6 - 4 =) 2.\n\nMove from coordinate 2 to (2 - 4 =) -2.\n\nHere, the absolute value of the coordinate of the destination is 2, and we cannot make it smaller.\n\nSample Input 2\n\n7 4 3\n\nSample Output 2\n\n1\n\nTakahashi is now at coordinate 7. It is optimal to make, for example, the following moves:\n\nMove from coordinate 7 to 4.\n\nMove from coordinate 4 to 7.\n\nMove from coordinate 7 to 4.\n\nMove from coordinate 4 to 1.\n\nHere, the absolute value of the coordinate of the destination is 1, and we cannot make it smaller.\n\nSample Input 3\n\n10 1 2\n\nSample Output 3\n\n8\n\nSample Input 4\n\n1000000000000000 1000000000000000 1000000000000000\n\nSample Output 4\n\n1000000000000000\n\nThe answer can be enormous.", "sample_input": "6 2 4\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02584", "source_text": "Score : 300 points\n\nProblem Statement\n\nTakahashi, who lives on the number line, is now at coordinate X. He will make exactly K moves of distance D in the positive or negative direction.\n\nMore specifically, in one move, he can go from coordinate x to x + D or x - D.\n\nHe wants to make K moves so that the absolute value of the coordinate of the destination will be the smallest possible.\n\nFind the minimum possible absolute value of the coordinate of the destination.\n\nConstraints\n\n-10^{15} \\leq X \\leq 10^{15}\n\n1 \\leq K \\leq 10^{15}\n\n1 \\leq D \\leq 10^{15}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX K D\n\nOutput\n\nPrint the minimum possible absolute value of the coordinate of the destination.\n\nSample Input 1\n\n6 2 4\n\nSample Output 1\n\n2\n\nTakahashi is now at coordinate 6. It is optimal to make the following moves:\n\nMove from coordinate 6 to (6 - 4 =) 2.\n\nMove from coordinate 2 to (2 - 4 =) -2.\n\nHere, the absolute value of the coordinate of the destination is 2, and we cannot make it smaller.\n\nSample Input 2\n\n7 4 3\n\nSample Output 2\n\n1\n\nTakahashi is now at coordinate 7. It is optimal to make, for example, the following moves:\n\nMove from coordinate 7 to 4.\n\nMove from coordinate 4 to 7.\n\nMove from coordinate 7 to 4.\n\nMove from coordinate 4 to 1.\n\nHere, the absolute value of the coordinate of the destination is 1, and we cannot make it smaller.\n\nSample Input 3\n\n10 1 2\n\nSample Output 3\n\n8\n\nSample Input 4\n\n1000000000000000 1000000000000000 1000000000000000\n\nSample Output 4\n\n1000000000000000\n\nThe answer can be enormous.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2518, "cpu_time_ms": 9, "memory_kb": 3796}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s872371763", "group_id": "codeNet:p02584", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n#define rep(i,n) for(int i=0;i<(n);i++)\n#define PI acos(-1)\ntypedef  long long ll;\nll gcd(ll x,ll y){\n   if(y==0) return x;\n   else return gcd(y,x%y);\n}\nll lcm(ll x,ll y){\n   return x/gcd(x,y)*y;\n}\n\nint main(){\n   ll x,k,d;\n   cin>>x>>k>>d;\n   ll ans=10000000000000000;\n      ll a=-x/(2*d)+k/2;\n\n   for(ll i=a-10000;i<a+10000;i++){\n      if(i<0){\n         continue;\n      }\n      ll y=x+(2*i-k)*d;\n      ll z=abs(y);\n      if((y-x)/d!=(2*i-k)){\n         continue;\n      }\n      ans=min(ans,z);\n   }  \n   \n   cout<<ans<<endl;\n   return 0;\n}\n", "language": "C++", "metadata": {"date": 1597521549, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02584.html", "problem_id": "p02584", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02584/input.txt", "sample_output_relpath": "derived/input_output/data/p02584/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02584/C++/s872371763.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s872371763", "user_id": "u738164318"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n#define rep(i,n) for(int i=0;i<(n);i++)\n#define PI acos(-1)\ntypedef  long long ll;\nll gcd(ll x,ll y){\n   if(y==0) return x;\n   else return gcd(y,x%y);\n}\nll lcm(ll x,ll y){\n   return x/gcd(x,y)*y;\n}\n\nint main(){\n   ll x,k,d;\n   cin>>x>>k>>d;\n   ll ans=10000000000000000;\n      ll a=-x/(2*d)+k/2;\n\n   for(ll i=a-10000;i<a+10000;i++){\n      if(i<0){\n         continue;\n      }\n      ll y=x+(2*i-k)*d;\n      ll z=abs(y);\n      if((y-x)/d!=(2*i-k)){\n         continue;\n      }\n      ans=min(ans,z);\n   }  \n   \n   cout<<ans<<endl;\n   return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nTakahashi, who lives on the number line, is now at coordinate X. He will make exactly K moves of distance D in the positive or negative direction.\n\nMore specifically, in one move, he can go from coordinate x to x + D or x - D.\n\nHe wants to make K moves so that the absolute value of the coordinate of the destination will be the smallest possible.\n\nFind the minimum possible absolute value of the coordinate of the destination.\n\nConstraints\n\n-10^{15} \\leq X \\leq 10^{15}\n\n1 \\leq K \\leq 10^{15}\n\n1 \\leq D \\leq 10^{15}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX K D\n\nOutput\n\nPrint the minimum possible absolute value of the coordinate of the destination.\n\nSample Input 1\n\n6 2 4\n\nSample Output 1\n\n2\n\nTakahashi is now at coordinate 6. It is optimal to make the following moves:\n\nMove from coordinate 6 to (6 - 4 =) 2.\n\nMove from coordinate 2 to (2 - 4 =) -2.\n\nHere, the absolute value of the coordinate of the destination is 2, and we cannot make it smaller.\n\nSample Input 2\n\n7 4 3\n\nSample Output 2\n\n1\n\nTakahashi is now at coordinate 7. It is optimal to make, for example, the following moves:\n\nMove from coordinate 7 to 4.\n\nMove from coordinate 4 to 7.\n\nMove from coordinate 7 to 4.\n\nMove from coordinate 4 to 1.\n\nHere, the absolute value of the coordinate of the destination is 1, and we cannot make it smaller.\n\nSample Input 3\n\n10 1 2\n\nSample Output 3\n\n8\n\nSample Input 4\n\n1000000000000000 1000000000000000 1000000000000000\n\nSample Output 4\n\n1000000000000000\n\nThe answer can be enormous.", "sample_input": "6 2 4\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02584", "source_text": "Score : 300 points\n\nProblem Statement\n\nTakahashi, who lives on the number line, is now at coordinate X. He will make exactly K moves of distance D in the positive or negative direction.\n\nMore specifically, in one move, he can go from coordinate x to x + D or x - D.\n\nHe wants to make K moves so that the absolute value of the coordinate of the destination will be the smallest possible.\n\nFind the minimum possible absolute value of the coordinate of the destination.\n\nConstraints\n\n-10^{15} \\leq X \\leq 10^{15}\n\n1 \\leq K \\leq 10^{15}\n\n1 \\leq D \\leq 10^{15}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX K D\n\nOutput\n\nPrint the minimum possible absolute value of the coordinate of the destination.\n\nSample Input 1\n\n6 2 4\n\nSample Output 1\n\n2\n\nTakahashi is now at coordinate 6. It is optimal to make the following moves:\n\nMove from coordinate 6 to (6 - 4 =) 2.\n\nMove from coordinate 2 to (2 - 4 =) -2.\n\nHere, the absolute value of the coordinate of the destination is 2, and we cannot make it smaller.\n\nSample Input 2\n\n7 4 3\n\nSample Output 2\n\n1\n\nTakahashi is now at coordinate 7. It is optimal to make, for example, the following moves:\n\nMove from coordinate 7 to 4.\n\nMove from coordinate 4 to 7.\n\nMove from coordinate 7 to 4.\n\nMove from coordinate 4 to 1.\n\nHere, the absolute value of the coordinate of the destination is 1, and we cannot make it smaller.\n\nSample Input 3\n\n10 1 2\n\nSample Output 3\n\n8\n\nSample Input 4\n\n1000000000000000 1000000000000000 1000000000000000\n\nSample Output 4\n\n1000000000000000\n\nThe answer can be enormous.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 585, "cpu_time_ms": 7, "memory_kb": 3620}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s231732408", "group_id": "codeNet:p02584", "input_text": "#include <iostream>\n#include <string>\n#include <vector>\n#include <cmath>\n\n#define rep(i, n) for (int i = 0; i < (n); ++i)\n\nusing std::cin;\nusing std::cout;\nusing std::endl;\nusing std::string;\nusing std::vector;\n\nint main()\n{\n  long long X, K, D;\n  cin >> X >> K >> D;\n\n  if (X >= K * D)\n  {\n    cout << X - K * D << endl;\n  }\n  else\n  {\n    int div = X / D;\n    K -= div;\n    X -= div * D;\n    if (K % 2 == 0)\n    {\n      cout << X << endl;\n    }\n    else\n    {\n      cout << std::abs(X - D) << endl;\n    }\n  }\n\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1597519359, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02584.html", "problem_id": "p02584", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02584/input.txt", "sample_output_relpath": "derived/input_output/data/p02584/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02584/C++/s231732408.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s231732408", "user_id": "u320027541"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <iostream>\n#include <string>\n#include <vector>\n#include <cmath>\n\n#define rep(i, n) for (int i = 0; i < (n); ++i)\n\nusing std::cin;\nusing std::cout;\nusing std::endl;\nusing std::string;\nusing std::vector;\n\nint main()\n{\n  long long X, K, D;\n  cin >> X >> K >> D;\n\n  if (X >= K * D)\n  {\n    cout << X - K * D << endl;\n  }\n  else\n  {\n    int div = X / D;\n    K -= div;\n    X -= div * D;\n    if (K % 2 == 0)\n    {\n      cout << X << endl;\n    }\n    else\n    {\n      cout << std::abs(X - D) << endl;\n    }\n  }\n\n  return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nTakahashi, who lives on the number line, is now at coordinate X. He will make exactly K moves of distance D in the positive or negative direction.\n\nMore specifically, in one move, he can go from coordinate x to x + D or x - D.\n\nHe wants to make K moves so that the absolute value of the coordinate of the destination will be the smallest possible.\n\nFind the minimum possible absolute value of the coordinate of the destination.\n\nConstraints\n\n-10^{15} \\leq X \\leq 10^{15}\n\n1 \\leq K \\leq 10^{15}\n\n1 \\leq D \\leq 10^{15}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX K D\n\nOutput\n\nPrint the minimum possible absolute value of the coordinate of the destination.\n\nSample Input 1\n\n6 2 4\n\nSample Output 1\n\n2\n\nTakahashi is now at coordinate 6. It is optimal to make the following moves:\n\nMove from coordinate 6 to (6 - 4 =) 2.\n\nMove from coordinate 2 to (2 - 4 =) -2.\n\nHere, the absolute value of the coordinate of the destination is 2, and we cannot make it smaller.\n\nSample Input 2\n\n7 4 3\n\nSample Output 2\n\n1\n\nTakahashi is now at coordinate 7. It is optimal to make, for example, the following moves:\n\nMove from coordinate 7 to 4.\n\nMove from coordinate 4 to 7.\n\nMove from coordinate 7 to 4.\n\nMove from coordinate 4 to 1.\n\nHere, the absolute value of the coordinate of the destination is 1, and we cannot make it smaller.\n\nSample Input 3\n\n10 1 2\n\nSample Output 3\n\n8\n\nSample Input 4\n\n1000000000000000 1000000000000000 1000000000000000\n\nSample Output 4\n\n1000000000000000\n\nThe answer can be enormous.", "sample_input": "6 2 4\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02584", "source_text": "Score : 300 points\n\nProblem Statement\n\nTakahashi, who lives on the number line, is now at coordinate X. He will make exactly K moves of distance D in the positive or negative direction.\n\nMore specifically, in one move, he can go from coordinate x to x + D or x - D.\n\nHe wants to make K moves so that the absolute value of the coordinate of the destination will be the smallest possible.\n\nFind the minimum possible absolute value of the coordinate of the destination.\n\nConstraints\n\n-10^{15} \\leq X \\leq 10^{15}\n\n1 \\leq K \\leq 10^{15}\n\n1 \\leq D \\leq 10^{15}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX K D\n\nOutput\n\nPrint the minimum possible absolute value of the coordinate of the destination.\n\nSample Input 1\n\n6 2 4\n\nSample Output 1\n\n2\n\nTakahashi is now at coordinate 6. It is optimal to make the following moves:\n\nMove from coordinate 6 to (6 - 4 =) 2.\n\nMove from coordinate 2 to (2 - 4 =) -2.\n\nHere, the absolute value of the coordinate of the destination is 2, and we cannot make it smaller.\n\nSample Input 2\n\n7 4 3\n\nSample Output 2\n\n1\n\nTakahashi is now at coordinate 7. It is optimal to make, for example, the following moves:\n\nMove from coordinate 7 to 4.\n\nMove from coordinate 4 to 7.\n\nMove from coordinate 7 to 4.\n\nMove from coordinate 4 to 1.\n\nHere, the absolute value of the coordinate of the destination is 1, and we cannot make it smaller.\n\nSample Input 3\n\n10 1 2\n\nSample Output 3\n\n8\n\nSample Input 4\n\n1000000000000000 1000000000000000 1000000000000000\n\nSample Output 4\n\n1000000000000000\n\nThe answer can be enormous.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 526, "cpu_time_ms": 6, "memory_kb": 3636}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s272725638", "group_id": "codeNet:p02585", "input_text": "\n#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define INF 1e9\n#define PI 3.14159265359\n#define MOD 1000000007\n#define ALL(v) v.begin(),v.end()\n#define ALLR(v) v.rbegin(),v.rend()\n#define F first\n#define S second\ntypedef long long ll;\nconst int dx[4] = {1,0,-1,0};\nconst int dy[4] = {0,1,0,-1};\n//isPrime\n//modpow modinv\n//getDigit\ntemplate<class T> inline bool chmin(T& a, T b) {\n  if (a > b) {\n    a = b;\n    return true;\n  }\n  return false;\n}\ntemplate<class T> inline bool chmax(T& a, T b) {\n  if (a < b) {\n    a = b;\n    return true;\n  }\n  return false;\n}\nint main() {\n  cout << fixed << setprecision(10);\n  int n,k;\n  cin >> n >> k;\n  vector<ll> p(n),c(n);\n  rep(i,n) cin >> p[i];\n  rep(i,n) p[i]--;\n  rep(i,n) cin >> c[i];\n  vector<vector<int>> a;\n  map<int,int> mp;\n  rep(i,n){\n    if(mp[i]!=0)continue;\n    mp[i]++;\n    int q = i;\n    vector<int> b;\n    rep(j,n){\n      b.push_back(c[q]);\n      q=p[q];\n      if(mp[q]!=0){\n        break;\n      }\n      mp[q]++;\n    }\n    a.push_back(b);\n  }\n  ll t = -1e18;\n  for(auto b:a){\n    int m = b.size();\n    vector<ll> d(2*m+1);\n    rep(i,m){\n      d[i+1]=d[i]+b[i];\n    }\n    rep(i,m){\n      d[i+m+1]=d[i+m]+b[i];\n    }\n    ll res = 0;\n    if((d[m]-d[0])>=0){\n      if(k%m==0&&k>=m){\n        res+=(k/m-1)*(d[m]-d[0]);\n      }else{\n        res += (k/m)*(d[m]-d[0]);\n      }\n    }else{\n      res = 0;\n    }\n\n\n    int k1;\n    if(k%m==0&&k>=m){\n      k1=m;\n    }else{\n      k1=k%m;\n    }\n    ll ans = -1e18;\n    for(int add=1; add<=k1; add++){\n      for(int i=0; i+add<2*m+1; i++){\n        ans = max(ans,d[i+add]-d[i]);\n      }\n    }\n    t = max(t,ans+res);\n  }\n  cout << t << endl;\n\n}\n", "language": "C++", "metadata": {"date": 1597546704, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02585.html", "problem_id": "p02585", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02585/input.txt", "sample_output_relpath": "derived/input_output/data/p02585/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02585/C++/s272725638.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s272725638", "user_id": "u474760662"}, "prompt_components": {"gold_output": "8\n", "input_to_evaluate": "\n#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define INF 1e9\n#define PI 3.14159265359\n#define MOD 1000000007\n#define ALL(v) v.begin(),v.end()\n#define ALLR(v) v.rbegin(),v.rend()\n#define F first\n#define S second\ntypedef long long ll;\nconst int dx[4] = {1,0,-1,0};\nconst int dy[4] = {0,1,0,-1};\n//isPrime\n//modpow modinv\n//getDigit\ntemplate<class T> inline bool chmin(T& a, T b) {\n  if (a > b) {\n    a = b;\n    return true;\n  }\n  return false;\n}\ntemplate<class T> inline bool chmax(T& a, T b) {\n  if (a < b) {\n    a = b;\n    return true;\n  }\n  return false;\n}\nint main() {\n  cout << fixed << setprecision(10);\n  int n,k;\n  cin >> n >> k;\n  vector<ll> p(n),c(n);\n  rep(i,n) cin >> p[i];\n  rep(i,n) p[i]--;\n  rep(i,n) cin >> c[i];\n  vector<vector<int>> a;\n  map<int,int> mp;\n  rep(i,n){\n    if(mp[i]!=0)continue;\n    mp[i]++;\n    int q = i;\n    vector<int> b;\n    rep(j,n){\n      b.push_back(c[q]);\n      q=p[q];\n      if(mp[q]!=0){\n        break;\n      }\n      mp[q]++;\n    }\n    a.push_back(b);\n  }\n  ll t = -1e18;\n  for(auto b:a){\n    int m = b.size();\n    vector<ll> d(2*m+1);\n    rep(i,m){\n      d[i+1]=d[i]+b[i];\n    }\n    rep(i,m){\n      d[i+m+1]=d[i+m]+b[i];\n    }\n    ll res = 0;\n    if((d[m]-d[0])>=0){\n      if(k%m==0&&k>=m){\n        res+=(k/m-1)*(d[m]-d[0]);\n      }else{\n        res += (k/m)*(d[m]-d[0]);\n      }\n    }else{\n      res = 0;\n    }\n\n\n    int k1;\n    if(k%m==0&&k>=m){\n      k1=m;\n    }else{\n      k1=k%m;\n    }\n    ll ans = -1e18;\n    for(int add=1; add<=k1; add++){\n      for(int i=0; i+add<2*m+1; i++){\n        ans = max(ans,d[i+add]-d[i]);\n      }\n    }\n    t = max(t,ans+res);\n  }\n  cout << t << endl;\n\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nTakahashi will play a game using a piece on an array of squares numbered 1, 2, \\cdots, N. Square i has an integer C_i written on it. Also, he is given a permutation of 1, 2, \\cdots, N: P_1, P_2, \\cdots, P_N.\n\nNow, he will choose one square and place the piece on that square. Then, he will make the following move some number of times between 1 and K (inclusive):\n\nIn one move, if the piece is now on Square i (1 \\leq i \\leq N), move it to Square P_i. Here, his score increases by C_{P_i}.\n\nHelp him by finding the maximum possible score at the end of the game. (The score is 0 at the beginning of the game.)\n\nConstraints\n\n2 \\leq N \\leq 5000\n\n1 \\leq K \\leq 10^9\n\n1 \\leq P_i \\leq N\n\nP_i \\neq i\n\nP_1, P_2, \\cdots, P_N are all different.\n\n-10^9 \\leq C_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nP_1 P_2 \\cdots P_N\nC_1 C_2 \\cdots C_N\n\nOutput\n\nPrint the maximum possible score at the end of the game.\n\nSample Input 1\n\n5 2\n2 4 5 1 3\n3 4 -10 -8 8\n\nSample Output 1\n\n8\n\nWhen we start at some square of our choice and make at most two moves, we have the following options:\n\nIf we start at Square 1, making one move sends the piece to Square 2, after which the score is 4. Making another move sends the piece to Square 4, after which the score is 4 + (-8) = -4.\n\nIf we start at Square 2, making one move sends the piece to Square 4, after which the score is -8. Making another move sends the piece to Square 1, after which the score is -8 + 3 = -5.\n\nIf we start at Square 3, making one move sends the piece to Square 5, after which the score is 8. Making another move sends the piece to Square 3, after which the score is 8 + (-10) = -2.\n\nIf we start at Square 4, making one move sends the piece to Square 1, after which the score is 3. Making another move sends the piece to Square 2, after which the score is 3 + 4 = 7.\n\nIf we start at Square 5, making one move sends the piece to Square 3, after which the score is -10. Making another move sends the piece to Square 5, after which the score is -10 + 8 = -2.\n\nThe maximum score achieved is 8.\n\nSample Input 2\n\n2 3\n2 1\n10 -7\n\nSample Output 2\n\n13\n\nSample Input 3\n\n3 3\n3 1 2\n-1000 -2000 -3000\n\nSample Output 3\n\n-1000\n\nWe have to make at least one move.\n\nSample Input 4\n\n10 58\n9 1 6 7 8 4 3 2 10 5\n695279662 988782657 -119067776 382975538 -151885171 -177220596 -169777795 37619092 389386780 980092719\n\nSample Output 4\n\n29507023469\n\nThe absolute value of the answer may be enormous.", "sample_input": "5 2\n2 4 5 1 3\n3 4 -10 -8 8\n"}, "reference_outputs": ["8\n"], "source_document_id": "p02585", "source_text": "Score : 400 points\n\nProblem Statement\n\nTakahashi will play a game using a piece on an array of squares numbered 1, 2, \\cdots, N. Square i has an integer C_i written on it. Also, he is given a permutation of 1, 2, \\cdots, N: P_1, P_2, \\cdots, P_N.\n\nNow, he will choose one square and place the piece on that square. Then, he will make the following move some number of times between 1 and K (inclusive):\n\nIn one move, if the piece is now on Square i (1 \\leq i \\leq N), move it to Square P_i. Here, his score increases by C_{P_i}.\n\nHelp him by finding the maximum possible score at the end of the game. (The score is 0 at the beginning of the game.)\n\nConstraints\n\n2 \\leq N \\leq 5000\n\n1 \\leq K \\leq 10^9\n\n1 \\leq P_i \\leq N\n\nP_i \\neq i\n\nP_1, P_2, \\cdots, P_N are all different.\n\n-10^9 \\leq C_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nP_1 P_2 \\cdots P_N\nC_1 C_2 \\cdots C_N\n\nOutput\n\nPrint the maximum possible score at the end of the game.\n\nSample Input 1\n\n5 2\n2 4 5 1 3\n3 4 -10 -8 8\n\nSample Output 1\n\n8\n\nWhen we start at some square of our choice and make at most two moves, we have the following options:\n\nIf we start at Square 1, making one move sends the piece to Square 2, after which the score is 4. Making another move sends the piece to Square 4, after which the score is 4 + (-8) = -4.\n\nIf we start at Square 2, making one move sends the piece to Square 4, after which the score is -8. Making another move sends the piece to Square 1, after which the score is -8 + 3 = -5.\n\nIf we start at Square 3, making one move sends the piece to Square 5, after which the score is 8. Making another move sends the piece to Square 3, after which the score is 8 + (-10) = -2.\n\nIf we start at Square 4, making one move sends the piece to Square 1, after which the score is 3. Making another move sends the piece to Square 2, after which the score is 3 + 4 = 7.\n\nIf we start at Square 5, making one move sends the piece to Square 3, after which the score is -10. Making another move sends the piece to Square 5, after which the score is -10 + 8 = -2.\n\nThe maximum score achieved is 8.\n\nSample Input 2\n\n2 3\n2 1\n10 -7\n\nSample Output 2\n\n13\n\nSample Input 3\n\n3 3\n3 1 2\n-1000 -2000 -3000\n\nSample Output 3\n\n-1000\n\nWe have to make at least one move.\n\nSample Input 4\n\n10 58\n9 1 6 7 8 4 3 2 10 5\n695279662 988782657 -119067776 382975538 -151885171 -177220596 -169777795 37619092 389386780 980092719\n\nSample Output 4\n\n29507023469\n\nThe absolute value of the answer may be enormous.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1686, "cpu_time_ms": 48, "memory_kb": 4032}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s590837510", "group_id": "codeNet:p02586", "input_text": "#include <bits/stdc++.h>\n#define int long long\nusing namespace std;\n\nconst int Sz = 3e3 + 3;\nusing ii = pair<int,int>;\n\nint n, m, k;\nint x, y, z;\nint val = 0;\nint f[Sz][Sz][4];\nint a[Sz][Sz];\nint dp(int row, int col, int cnt){\n    if(row > n || col > m) return 0;\n    int &res = f[row][col][cnt];\n    if(res != -1) return res;\n    res = dp(row + 1, col, 0);\n    if(cnt < 3) res += a[row][col];\n    if(cnt < 3){\n    if(a[row][col] != 0)\n        res = max(res, dp(row, col + 1, cnt + 1) + a[row][col]);\n        res = max(res, dp(row, col + 1, cnt));\n    }\n    //cout << row << \" \" << col << \" \" << res << '\\n';\n    return res;\n}\nvoid trace(int row, int col, int cnt){\n    if(row > n || col > m) return ;\n    if(f[row][col][cnt] == f[row + 1][col][0]) return trace(row + 1, col, 0);\n    if(f[row][col][cnt] == f[row][col + 1][cnt]) return trace(row, col + 1, cnt);\n    cout << row << \" \" << col << '\\n';\n    return trace(row, col + 1, cnt + 1);\n}\nint32_t main()\n{\n    //freopen(\"inp.txt\" , \"r\", stdin);\n    //freopen(\"out.txt\", \"w\", stdout);\n    memset(f, -1, sizeof f);\n    ios::sync_with_stdio(0);\n    cin.tie(0);\n    cout.tie(0);\n    cin >> n >> m >> k;\n    while(k--){\n        cin >> x >> y >> z;\n        a[x][y] = z;\n    }\n    cout << dp(1, 1, 0);\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1598390347, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02586.html", "problem_id": "p02586", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02586/input.txt", "sample_output_relpath": "derived/input_output/data/p02586/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02586/C++/s590837510.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s590837510", "user_id": "u179794617"}, "prompt_components": {"gold_output": "8\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define int long long\nusing namespace std;\n\nconst int Sz = 3e3 + 3;\nusing ii = pair<int,int>;\n\nint n, m, k;\nint x, y, z;\nint val = 0;\nint f[Sz][Sz][4];\nint a[Sz][Sz];\nint dp(int row, int col, int cnt){\n    if(row > n || col > m) return 0;\n    int &res = f[row][col][cnt];\n    if(res != -1) return res;\n    res = dp(row + 1, col, 0);\n    if(cnt < 3) res += a[row][col];\n    if(cnt < 3){\n    if(a[row][col] != 0)\n        res = max(res, dp(row, col + 1, cnt + 1) + a[row][col]);\n        res = max(res, dp(row, col + 1, cnt));\n    }\n    //cout << row << \" \" << col << \" \" << res << '\\n';\n    return res;\n}\nvoid trace(int row, int col, int cnt){\n    if(row > n || col > m) return ;\n    if(f[row][col][cnt] == f[row + 1][col][0]) return trace(row + 1, col, 0);\n    if(f[row][col][cnt] == f[row][col + 1][cnt]) return trace(row, col + 1, cnt);\n    cout << row << \" \" << col << '\\n';\n    return trace(row, col + 1, cnt + 1);\n}\nint32_t main()\n{\n    //freopen(\"inp.txt\" , \"r\", stdin);\n    //freopen(\"out.txt\", \"w\", stdout);\n    memset(f, -1, sizeof f);\n    ios::sync_with_stdio(0);\n    cin.tie(0);\n    cout.tie(0);\n    cin >> n >> m >> k;\n    while(k--){\n        cin >> x >> y >> z;\n        a[x][y] = z;\n    }\n    cout << dp(1, 1, 0);\n    return 0;\n}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nThere are K items placed on a grid of squares with R rows and C columns. Let (i, j) denote the square at the i-th row (1 \\leq i \\leq R) and the j-th column (1 \\leq j \\leq C). The i-th item is at (r_i, c_i) and has the value v_i.\n\nTakahashi will begin at (1, 1), the start, and get to (R, C), the goal. When he is at (i, j), he can move to (i + 1, j) or (i, j + 1) (but cannot move to a non-existent square).\n\nHe can pick up items on the squares he visits, including the start and the goal, but at most three for each row. It is allowed to ignore the item on a square he visits.\n\nFind the maximum possible sum of the values of items he picks up.\n\nConstraints\n\n1 \\leq R, C \\leq 3000\n\n1 \\leq K \\leq \\min(2 \\times 10^5, R \\times C)\n\n1 \\leq r_i \\leq R\n\n1 \\leq c_i \\leq C\n\n(r_i, c_i) \\neq (r_j, c_j) (i \\neq j)\n\n1 \\leq v_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nR C K\nr_1 c_1 v_1\nr_2 c_2 v_2\n:\nr_K c_K v_K\n\nOutput\n\nPrint the maximum possible sum of the values of items Takahashi picks up.\n\nSample Input 1\n\n2 2 3\n1 1 3\n2 1 4\n1 2 5\n\nSample Output 1\n\n8\n\nHe has two ways to get to the goal:\n\nVisit (1, 1), (1, 2), and (2, 2), in this order. In this case, the total value of the items he can pick up is 3 + 5 = 8.\n\nVisit (1, 1), (2, 1), and (2, 2), in this order. In this case, the total value of the items he can pick up is 3 + 4 = 7.\n\nThus, the maximum possible sum of the values of items he picks up is 8.\n\nSample Input 2\n\n2 5 5\n1 1 3\n2 4 20\n1 2 1\n1 3 4\n1 4 2\n\nSample Output 2\n\n29\n\nWe have four items in the 1-st row. The optimal choices are as follows:\n\nVisit (1, 1) (1, 2), (1, 3), (1, 4), (2, 4), and (2, 5), in this order, and pick up all items except the one on (1, 2). Then, the total value of the items he picks up will be 3 + 4 + 2 + 20 = 29.\n\nSample Input 3\n\n4 5 10\n2 5 12\n1 5 12\n2 3 15\n1 2 20\n1 1 28\n2 4 26\n3 2 27\n4 5 21\n3 5 10\n1 3 10\n\nSample Output 3\n\n142", "sample_input": "2 2 3\n1 1 3\n2 1 4\n1 2 5\n"}, "reference_outputs": ["8\n"], "source_document_id": "p02586", "source_text": "Score : 500 points\n\nProblem Statement\n\nThere are K items placed on a grid of squares with R rows and C columns. Let (i, j) denote the square at the i-th row (1 \\leq i \\leq R) and the j-th column (1 \\leq j \\leq C). The i-th item is at (r_i, c_i) and has the value v_i.\n\nTakahashi will begin at (1, 1), the start, and get to (R, C), the goal. When he is at (i, j), he can move to (i + 1, j) or (i, j + 1) (but cannot move to a non-existent square).\n\nHe can pick up items on the squares he visits, including the start and the goal, but at most three for each row. It is allowed to ignore the item on a square he visits.\n\nFind the maximum possible sum of the values of items he picks up.\n\nConstraints\n\n1 \\leq R, C \\leq 3000\n\n1 \\leq K \\leq \\min(2 \\times 10^5, R \\times C)\n\n1 \\leq r_i \\leq R\n\n1 \\leq c_i \\leq C\n\n(r_i, c_i) \\neq (r_j, c_j) (i \\neq j)\n\n1 \\leq v_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nR C K\nr_1 c_1 v_1\nr_2 c_2 v_2\n:\nr_K c_K v_K\n\nOutput\n\nPrint the maximum possible sum of the values of items Takahashi picks up.\n\nSample Input 1\n\n2 2 3\n1 1 3\n2 1 4\n1 2 5\n\nSample Output 1\n\n8\n\nHe has two ways to get to the goal:\n\nVisit (1, 1), (1, 2), and (2, 2), in this order. In this case, the total value of the items he can pick up is 3 + 5 = 8.\n\nVisit (1, 1), (2, 1), and (2, 2), in this order. In this case, the total value of the items he can pick up is 3 + 4 = 7.\n\nThus, the maximum possible sum of the values of items he picks up is 8.\n\nSample Input 2\n\n2 5 5\n1 1 3\n2 4 20\n1 2 1\n1 3 4\n1 4 2\n\nSample Output 2\n\n29\n\nWe have four items in the 1-st row. The optimal choices are as follows:\n\nVisit (1, 1) (1, 2), (1, 3), (1, 4), (2, 4), and (2, 5), in this order, and pick up all items except the one on (1, 2). Then, the total value of the items he picks up will be 3 + 4 + 2 + 20 = 29.\n\nSample Input 3\n\n4 5 10\n2 5 12\n1 5 12\n2 3 15\n1 2 20\n1 1 28\n2 4 26\n3 2 27\n4 5 21\n3 5 10\n1 3 10\n\nSample Output 3\n\n142", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1266, "cpu_time_ms": 562, "memory_kb": 356228}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s428022761", "group_id": "codeNet:p02587", "input_text": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint n;\nstring s[54];\nlong long c[54];\nlong long dist[54][2][24];\npriority_queue<pair<long long, pair<int, pair<int, int>>>> pq;\nvector<long long> ans;\n\nvoid solve(){\n    cin>>n;\n    memset(dist, -1, sizeof(dist));\n    for(int i = 0; i < n; i++){\n        cin>>s[i]>>c[i];\n        dist[i][0][s[i].length()] = c[i];\n        pq.push({-c[i], {i, {0, s[i].length()}}});\n    }\n    while(!pq.empty()){\n        pair<long long, pair<int, pair<int, int>>> now = pq.top();\n        pq.pop();\n        long long cost = -now.first;\n        int idx = now.second.first;\n        int dir = now.second.second.first;\n        int rem = now.second.second.second;\n        if(cost > dist[idx][dir][rem])  continue;\n        if(dir == 0){\n            for(int nextIdx = 0; nextIdx < n; nextIdx++){\n                const int L = s[idx].length();\n                const int R = s[nextIdx].length();\n                bool can = true;\n                int lRem = rem, rRem = R;\n                while(lRem && rRem){\n                    if(s[idx][L-lRem] != s[nextIdx][rRem-1])  can = false;\n                    lRem--;\n                    rRem--;\n                }\n                if(!can)    continue;\n                long long nextCost = cost + c[nextIdx];\n                if(lRem + rRem <= 1){\n                    ans.push_back(nextCost);\n                    continue;\n                }\n                if(lRem && (dist[idx][0][lRem] > nextCost || dist[idx][0][lRem] == -1)){\n                    dist[idx][0][lRem] = nextCost;\n                    pq.push({-nextCost, {idx, {0, lRem}}});\n                }\n                if(rRem && (dist[nextIdx][1][rRem] > nextCost || dist[nextIdx][1][rRem] == -1)){\n                    dist[nextIdx][1][rRem] = nextCost;\n                    pq.push({-nextCost, {nextIdx, {1, rRem}}});\n                }\n            }\n        }\n        else {\n            for(int nextIdx = 0; nextIdx < n; nextIdx++){\n                const int L = s[nextIdx].length();\n                const int R = s[idx].length();\n                bool can = true;\n                int lRem = L, rRem = rem;\n                while(lRem && rRem){\n                    if(s[nextIdx][L-lRem] != s[idx][rRem-1])  can = false;\n                    lRem--;\n                    rRem--;\n                }\n                if(!can)    continue;\n                long long nextCost = cost + c[nextIdx];\n                if(lRem + rRem <= 1){\n                    ans.push_back(nextCost);\n                    continue;\n                }\n                if(lRem && (dist[nextIdx][0][lRem] > nextCost || dist[nextIdx][0][lRem] == -1)){\n                    dist[nextIdx][0][lRem] = nextCost;\n                    pq.push({-nextCost, {nextIdx, {0, lRem}}});\n                }\n                if(rRem && (dist[idx][1][rRem] > nextCost || dist[idx][1][rRem] == -1)){\n                    dist[idx][1][rRem] = nextCost;\n                    pq.push({-nextCost, {idx, {1, rRem}}});\n                }\n            }\n        }\n    }\n    if(ans.size() == 0) cout<<-1<<endl;\n    else\n    {\n        cout<<*min_element(ans.begin(), ans.end());\n    }\n    \n}\n\nint main(){\n    ios::sync_with_stdio(false);\n    cin.tie(0);\n    cout.tie(0);\n    int TC;\n    //cin>>TC;\n    TC=1;\n    while(TC--){\n        solve();\n    }\n}", "language": "C++", "metadata": {"date": 1597544766, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02587.html", "problem_id": "p02587", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02587/input.txt", "sample_output_relpath": "derived/input_output/data/p02587/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02587/C++/s428022761.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s428022761", "user_id": "u541786453"}, "prompt_components": {"gold_output": "7\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint n;\nstring s[54];\nlong long c[54];\nlong long dist[54][2][24];\npriority_queue<pair<long long, pair<int, pair<int, int>>>> pq;\nvector<long long> ans;\n\nvoid solve(){\n    cin>>n;\n    memset(dist, -1, sizeof(dist));\n    for(int i = 0; i < n; i++){\n        cin>>s[i]>>c[i];\n        dist[i][0][s[i].length()] = c[i];\n        pq.push({-c[i], {i, {0, s[i].length()}}});\n    }\n    while(!pq.empty()){\n        pair<long long, pair<int, pair<int, int>>> now = pq.top();\n        pq.pop();\n        long long cost = -now.first;\n        int idx = now.second.first;\n        int dir = now.second.second.first;\n        int rem = now.second.second.second;\n        if(cost > dist[idx][dir][rem])  continue;\n        if(dir == 0){\n            for(int nextIdx = 0; nextIdx < n; nextIdx++){\n                const int L = s[idx].length();\n                const int R = s[nextIdx].length();\n                bool can = true;\n                int lRem = rem, rRem = R;\n                while(lRem && rRem){\n                    if(s[idx][L-lRem] != s[nextIdx][rRem-1])  can = false;\n                    lRem--;\n                    rRem--;\n                }\n                if(!can)    continue;\n                long long nextCost = cost + c[nextIdx];\n                if(lRem + rRem <= 1){\n                    ans.push_back(nextCost);\n                    continue;\n                }\n                if(lRem && (dist[idx][0][lRem] > nextCost || dist[idx][0][lRem] == -1)){\n                    dist[idx][0][lRem] = nextCost;\n                    pq.push({-nextCost, {idx, {0, lRem}}});\n                }\n                if(rRem && (dist[nextIdx][1][rRem] > nextCost || dist[nextIdx][1][rRem] == -1)){\n                    dist[nextIdx][1][rRem] = nextCost;\n                    pq.push({-nextCost, {nextIdx, {1, rRem}}});\n                }\n            }\n        }\n        else {\n            for(int nextIdx = 0; nextIdx < n; nextIdx++){\n                const int L = s[nextIdx].length();\n                const int R = s[idx].length();\n                bool can = true;\n                int lRem = L, rRem = rem;\n                while(lRem && rRem){\n                    if(s[nextIdx][L-lRem] != s[idx][rRem-1])  can = false;\n                    lRem--;\n                    rRem--;\n                }\n                if(!can)    continue;\n                long long nextCost = cost + c[nextIdx];\n                if(lRem + rRem <= 1){\n                    ans.push_back(nextCost);\n                    continue;\n                }\n                if(lRem && (dist[nextIdx][0][lRem] > nextCost || dist[nextIdx][0][lRem] == -1)){\n                    dist[nextIdx][0][lRem] = nextCost;\n                    pq.push({-nextCost, {nextIdx, {0, lRem}}});\n                }\n                if(rRem && (dist[idx][1][rRem] > nextCost || dist[idx][1][rRem] == -1)){\n                    dist[idx][1][rRem] = nextCost;\n                    pq.push({-nextCost, {idx, {1, rRem}}});\n                }\n            }\n        }\n    }\n    if(ans.size() == 0) cout<<-1<<endl;\n    else\n    {\n        cout<<*min_element(ans.begin(), ans.end());\n    }\n    \n}\n\nint main(){\n    ios::sync_with_stdio(false);\n    cin.tie(0);\n    cout.tie(0);\n    int TC;\n    //cin>>TC;\n    TC=1;\n    while(TC--){\n        solve();\n    }\n}", "problem_context": "Score : 600 points\n\nProblem Statement\n\nWe have N strings of lowercase English letters: S_1, S_2, \\cdots, S_N.\n\nTakahashi wants to make a string that is a palindrome by choosing one or more of these strings - the same string can be chosen more than once - and concatenating them in some order of his choice.\n\nThe cost of using the string S_i once is C_i, and the cost of using it multiple times is C_i multiplied by that number of times.\n\nFind the minimum total cost needed to choose strings so that Takahashi can make a palindrome.\n\nIf there is no choice of strings in which he can make a palindrome, print -1.\n\nConstraints\n\n1 \\leq N \\leq 50\n\n1 \\leq |S_i| \\leq 20\n\nS_i consists of lowercase English letters.\n\n1 \\leq C_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS_1 C_1\nS_2 C_2\n:\nS_N C_N\n\nOutput\n\nPrint the minimum total cost needed to choose strings so that Takahashi can make a palindrome, or -1 if there is no such choice.\n\nSample Input 1\n\n3\nba 3\nabc 4\ncbaa 5\n\nSample Output 1\n\n7\n\nWe have ba, abc, and cbaa.\n\nFor example, we can use ba once and abc once for a cost of 7, then concatenate them in the order abc, ba to make a palindrome.\nAlso, we can use abc once and cbaa once for a cost of 9, then concatenate them in the order cbaa, abc to make a palindrome.\n\nWe cannot make a palindrome for a cost less than 7, so we should print 7.\n\nSample Input 2\n\n2\nabcab 5\ncba 3\n\nSample Output 2\n\n11\n\nWe can choose abcab once and cba twice, then concatenate them in the order abcab, cba, cba to make a palindrome for a cost of 11.\n\nSample Input 3\n\n4\nab 5\ncba 3\na 12\nab 10\n\nSample Output 3\n\n8\n\nWe can choose a once, which is already a palindrome, but it is cheaper to concatenate ab and cba.\n\nSample Input 4\n\n2\nabc 1\nab 2\n\nSample Output 4\n\n-1\n\nWe cannot make a palindrome, so we should print -1.", "sample_input": "3\nba 3\nabc 4\ncbaa 5\n"}, "reference_outputs": ["7\n"], "source_document_id": "p02587", "source_text": "Score : 600 points\n\nProblem Statement\n\nWe have N strings of lowercase English letters: S_1, S_2, \\cdots, S_N.\n\nTakahashi wants to make a string that is a palindrome by choosing one or more of these strings - the same string can be chosen more than once - and concatenating them in some order of his choice.\n\nThe cost of using the string S_i once is C_i, and the cost of using it multiple times is C_i multiplied by that number of times.\n\nFind the minimum total cost needed to choose strings so that Takahashi can make a palindrome.\n\nIf there is no choice of strings in which he can make a palindrome, print -1.\n\nConstraints\n\n1 \\leq N \\leq 50\n\n1 \\leq |S_i| \\leq 20\n\nS_i consists of lowercase English letters.\n\n1 \\leq C_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS_1 C_1\nS_2 C_2\n:\nS_N C_N\n\nOutput\n\nPrint the minimum total cost needed to choose strings so that Takahashi can make a palindrome, or -1 if there is no such choice.\n\nSample Input 1\n\n3\nba 3\nabc 4\ncbaa 5\n\nSample Output 1\n\n7\n\nWe have ba, abc, and cbaa.\n\nFor example, we can use ba once and abc once for a cost of 7, then concatenate them in the order abc, ba to make a palindrome.\nAlso, we can use abc once and cbaa once for a cost of 9, then concatenate them in the order cbaa, abc to make a palindrome.\n\nWe cannot make a palindrome for a cost less than 7, so we should print 7.\n\nSample Input 2\n\n2\nabcab 5\ncba 3\n\nSample Output 2\n\n11\n\nWe can choose abcab once and cba twice, then concatenate them in the order abcab, cba, cba to make a palindrome for a cost of 11.\n\nSample Input 3\n\n4\nab 5\ncba 3\na 12\nab 10\n\nSample Output 3\n\n8\n\nWe can choose a once, which is already a palindrome, but it is cheaper to concatenate ab and cba.\n\nSample Input 4\n\n2\nabc 1\nab 2\n\nSample Output 4\n\n-1\n\nWe cannot make a palindrome, so we should print -1.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 3293, "cpu_time_ms": 6, "memory_kb": 3696}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s869263256", "group_id": "codeNet:p02588", "input_text": "#include \"bits/stdc++.h\"\n \nusing namespace std;\ntypedef long long ll;\ntypedef vector<ll> vll;\n#define int ll\ntypedef pair<int,int> pii;\n#define fi first\n#define se second\n#define Sort(a) sort(a.begin(),a.end())\n#define rep(i,n) for(int i = 0;i < (n) ; i++) \n#define REP(i,n) for(int i = 0;i < (n) ; i++) \n#define MP(a,b) make_pair(a,b)\n#define pb(a) push_back(a)\n#define INF LLONG_MAX/4\n#define INTINF INT_MAX/2\n#define all(x) (x).begin(),(x).end()\n#define debug(x) cerr<<#x<<\": \"<<x<<endl\n#define debug_vec(v) cerr<<#v<<\":\";rep(i,v.size())cerr<<\" \"<<v[i];cerr<<endl\ntemplate<class T> inline bool chmax(T &a, T b){if(a < b){a = b;return true;}return false;}\ntemplate<class T> inline bool chmin(T &a, T b){if(a > b){a = b;return true;}return false;}\n/*----------------------------------------------------------------*/\n// const int MOD = 998244353;\n// const int MOD = 1000000007;\nvector<pii> p;\n/*----------------------------------------------------------------*/\nsigned main(){\n\t\n\tint n;\n\tcin >> n;\n\tint cnt[300][300] = {};\n\trep(i,n){\n\t\tstring a;\n\t\tcin >> a;\n\t\t// cerr << a << endl;\n\t\tint m = a.size();\n\t\tint z = 0;\n\t\tint f = 0;\n\t\tint x2 = 0;\n\t\tint x5 = 0;\n\n\t\trep(j,m){\n\t\t\tif(a[m-1-j] == '.'){\n\t\t\t\tf = 1;\n\t\t\t\ta.erase(m-1-j,1);\n\t\t\t\tbreak;\n\t\t\t}else{\n\t\t\t\tz++;\n\t\t\t}\n\t\t}\n\t\tif(f==0)z = 0;\n\t\t\n\t\tx2 = -z;\n\t\tx5 = -z;\n\t\tcerr << a << endl;\n\t\tint A = stoll(a);\n\t\twhile(A%2 == 0){\n\t\t\tA /= 2;\n\t\t\tx2++;\n\t\t}\n\t\twhile(A%5 == 0){\n\t\t\tA /= 5;\n\t\t\tx5++;\n\t\t}\n\t\tp.push_back(MP(x2,x5));\n\t\t// cerr << x2 <<\" \" << x5 << endl;\n\t\tcnt[x2+150][x5+150]++;\n\t}\n\n\tint s[310][310] = {};\n\trep(i,301)rep(j,301)s[i+1][j+1] = s[i+1][j] + s[i][j+1] - s[i][j] + cnt[i][j];\n\n\tint ans = 0;\n\trep(i,n){\n\t\tint x2 = p[i].first;\n\t\tint x5 = p[i].second;\n\t\t// cerr << x2 << \" \" << x5 << endl;\n\t\tint y2 = 150-x2;\n\t\tint y5 = 150-x5;\n\t\tint pl = s[300][300]-s[y2][300]-s[300][y5]+s[y2][y5];\n\t\tif(x2>=0&&x5>=0)pl--;\n\t\tans += pl;\n\t\t// cerr << x2 <<\" \" << x5 << \" : \" << pl << endl;\n\t}\n\tcout << ans/2 << endl;\n\t\n\n\n\t\n\n\n\treturn 0;\n}\n/*----------------------------------------------------------------*/\n\n// g++ -std=gnu++17 code1.cpp\n// sudo pip3 install --upgrade online-judge-tools\n// rm -r -f test;oj dl https://abc174.contest.atcoder.jp/tasks/abc174_b\n// rm -r -f test;oj d https://atcoder.jp/contests/agc047/tasks/agc047_a", "language": "C++", "metadata": {"date": 1597024604, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02588.html", "problem_id": "p02588", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02588/input.txt", "sample_output_relpath": "derived/input_output/data/p02588/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02588/C++/s869263256.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s869263256", "user_id": "u548768105"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include \"bits/stdc++.h\"\n \nusing namespace std;\ntypedef long long ll;\ntypedef vector<ll> vll;\n#define int ll\ntypedef pair<int,int> pii;\n#define fi first\n#define se second\n#define Sort(a) sort(a.begin(),a.end())\n#define rep(i,n) for(int i = 0;i < (n) ; i++) \n#define REP(i,n) for(int i = 0;i < (n) ; i++) \n#define MP(a,b) make_pair(a,b)\n#define pb(a) push_back(a)\n#define INF LLONG_MAX/4\n#define INTINF INT_MAX/2\n#define all(x) (x).begin(),(x).end()\n#define debug(x) cerr<<#x<<\": \"<<x<<endl\n#define debug_vec(v) cerr<<#v<<\":\";rep(i,v.size())cerr<<\" \"<<v[i];cerr<<endl\ntemplate<class T> inline bool chmax(T &a, T b){if(a < b){a = b;return true;}return false;}\ntemplate<class T> inline bool chmin(T &a, T b){if(a > b){a = b;return true;}return false;}\n/*----------------------------------------------------------------*/\n// const int MOD = 998244353;\n// const int MOD = 1000000007;\nvector<pii> p;\n/*----------------------------------------------------------------*/\nsigned main(){\n\t\n\tint n;\n\tcin >> n;\n\tint cnt[300][300] = {};\n\trep(i,n){\n\t\tstring a;\n\t\tcin >> a;\n\t\t// cerr << a << endl;\n\t\tint m = a.size();\n\t\tint z = 0;\n\t\tint f = 0;\n\t\tint x2 = 0;\n\t\tint x5 = 0;\n\n\t\trep(j,m){\n\t\t\tif(a[m-1-j] == '.'){\n\t\t\t\tf = 1;\n\t\t\t\ta.erase(m-1-j,1);\n\t\t\t\tbreak;\n\t\t\t}else{\n\t\t\t\tz++;\n\t\t\t}\n\t\t}\n\t\tif(f==0)z = 0;\n\t\t\n\t\tx2 = -z;\n\t\tx5 = -z;\n\t\tcerr << a << endl;\n\t\tint A = stoll(a);\n\t\twhile(A%2 == 0){\n\t\t\tA /= 2;\n\t\t\tx2++;\n\t\t}\n\t\twhile(A%5 == 0){\n\t\t\tA /= 5;\n\t\t\tx5++;\n\t\t}\n\t\tp.push_back(MP(x2,x5));\n\t\t// cerr << x2 <<\" \" << x5 << endl;\n\t\tcnt[x2+150][x5+150]++;\n\t}\n\n\tint s[310][310] = {};\n\trep(i,301)rep(j,301)s[i+1][j+1] = s[i+1][j] + s[i][j+1] - s[i][j] + cnt[i][j];\n\n\tint ans = 0;\n\trep(i,n){\n\t\tint x2 = p[i].first;\n\t\tint x5 = p[i].second;\n\t\t// cerr << x2 << \" \" << x5 << endl;\n\t\tint y2 = 150-x2;\n\t\tint y5 = 150-x5;\n\t\tint pl = s[300][300]-s[y2][300]-s[300][y5]+s[y2][y5];\n\t\tif(x2>=0&&x5>=0)pl--;\n\t\tans += pl;\n\t\t// cerr << x2 <<\" \" << x5 << \" : \" << pl << endl;\n\t}\n\tcout << ans/2 << endl;\n\t\n\n\n\t\n\n\n\treturn 0;\n}\n/*----------------------------------------------------------------*/\n\n// g++ -std=gnu++17 code1.cpp\n// sudo pip3 install --upgrade online-judge-tools\n// rm -r -f test;oj dl https://abc174.contest.atcoder.jp/tasks/abc174_b\n// rm -r -f test;oj d https://atcoder.jp/contests/agc047/tasks/agc047_a", "problem_context": "Score : 300 points\n\nProblem Statement\n\nYou are given N real values A_1, A_2, \\ldots, A_N.\nCompute the number of pairs of indices (i, j)\nsuch that i < j and the product A_i \\cdot A_j is integer.\n\nConstraints\n\n2 \\leq N \\leq 200\\,000\n\n0 < A_i < 10^4\n\nA_i is given with at most 9 digits after the decimal.\n\nInput\n\nInput is given from Standard Input in the following format.\n\nN\nA_1\nA_2\n\\vdots\nA_N\n\nOutput\n\nPrint the number of pairs with integer product A_i \\cdot A_j (and i < j).\n\nSample Input 1\n\n5\n7.5\n2.4\n17.000000001\n17\n16.000000000\n\nSample Output 1\n\n3\n\nThere are 3 pairs with integer product:\n\n7.5 \\cdot 2.4 = 18\n\n7.5 \\cdot 16 = 120\n\n17 \\cdot 16 = 272\n\nSample Input 2\n\n11\n0.9\n1\n1\n1.25\n2.30000\n5\n70\n0.000000001\n9999.999999999\n0.999999999\n1.000000001\n\nSample Output 2\n\n8", "sample_input": "5\n7.5\n2.4\n17.000000001\n17\n16.000000000\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02588", "source_text": "Score : 300 points\n\nProblem Statement\n\nYou are given N real values A_1, A_2, \\ldots, A_N.\nCompute the number of pairs of indices (i, j)\nsuch that i < j and the product A_i \\cdot A_j is integer.\n\nConstraints\n\n2 \\leq N \\leq 200\\,000\n\n0 < A_i < 10^4\n\nA_i is given with at most 9 digits after the decimal.\n\nInput\n\nInput is given from Standard Input in the following format.\n\nN\nA_1\nA_2\n\\vdots\nA_N\n\nOutput\n\nPrint the number of pairs with integer product A_i \\cdot A_j (and i < j).\n\nSample Input 1\n\n5\n7.5\n2.4\n17.000000001\n17\n16.000000000\n\nSample Output 1\n\n3\n\nThere are 3 pairs with integer product:\n\n7.5 \\cdot 2.4 = 18\n\n7.5 \\cdot 16 = 120\n\n17 \\cdot 16 = 272\n\nSample Input 2\n\n11\n0.9\n1\n1\n1.25\n2.30000\n5\n70\n0.000000001\n9999.999999999\n0.999999999\n1.000000001\n\nSample Output 2\n\n8", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2265, "cpu_time_ms": 618, "memory_kb": 8184}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s696102540", "group_id": "codeNet:p02594", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef long double lld;\nll MOD = (1e9)+7;\nconst int dr[] = {+1, -1, +0, +0, +1, -1, +1, -1};\nconst int dc[] = {+0, +0, +1, -1, +1, -1, -1, +1};\nconst int kx[] = {+1, +2, -1, -2, +1, +2, -1, -2};\nconst int ky[] = {+2, +1, +2, +1, -2, -1, -2, -1};\n//#pragma GCC target (\"avx2\")\n//#pragma GCC optimization (\"O3\")\n//#pragma GCC optimization (\"unroll-loops\")\ninline void fastIO(){\n  ios_base::sync_with_stdio(0);cin.tie(0);\n}\ntemplate<typename T> ostream& operator<<(ostream &os, const vector<T> &v) { os << '{'; string sep; for (const auto &x : v) os << sep << x, sep = \", \"; return os << '}'; }\ntemplate<typename T, size_t size> ostream& operator<<(ostream &os, const array<T, size> &arr) { os << '{'; string sep; for (const auto &x : arr) os << sep << x, sep = \", \"; return os << '}'; }\ntemplate<typename A, typename B> ostream& operator<<(ostream &os, const pair<A, B> &p) { return os << '(' << p.first << \", \" << p.second << ')'; }\n\nvoid debug_out() { cerr << endl; }\ntemplate<typename Head, typename... Tail> void debug_out(Head H, Tail... T) { cerr << ' ' << H; debug_out(T...); }\n\n#ifdef LOCAL\n#define debug(...) cerr << \"(\" << #__VA_ARGS__ << \"):\", debug_out(__VA_ARGS__)\n#else\n#define debug(...) 47\n#endif\nconst ll MAXN=5050;\n\nint main(){\n  fastIO();\n  int x;\n  cin>>x;\n  if(x>=30){\n    cout<<\"Yes\"<<endl;\n  }else{\n    cout<<\"No\"<<endl;\n  }\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1599480136, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02594.html", "problem_id": "p02594", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02594/input.txt", "sample_output_relpath": "derived/input_output/data/p02594/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02594/C++/s696102540.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s696102540", "user_id": "u240010800"}, "prompt_components": {"gold_output": "No\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long int ll;\ntypedef long double lld;\nll MOD = (1e9)+7;\nconst int dr[] = {+1, -1, +0, +0, +1, -1, +1, -1};\nconst int dc[] = {+0, +0, +1, -1, +1, -1, -1, +1};\nconst int kx[] = {+1, +2, -1, -2, +1, +2, -1, -2};\nconst int ky[] = {+2, +1, +2, +1, -2, -1, -2, -1};\n//#pragma GCC target (\"avx2\")\n//#pragma GCC optimization (\"O3\")\n//#pragma GCC optimization (\"unroll-loops\")\ninline void fastIO(){\n  ios_base::sync_with_stdio(0);cin.tie(0);\n}\ntemplate<typename T> ostream& operator<<(ostream &os, const vector<T> &v) { os << '{'; string sep; for (const auto &x : v) os << sep << x, sep = \", \"; return os << '}'; }\ntemplate<typename T, size_t size> ostream& operator<<(ostream &os, const array<T, size> &arr) { os << '{'; string sep; for (const auto &x : arr) os << sep << x, sep = \", \"; return os << '}'; }\ntemplate<typename A, typename B> ostream& operator<<(ostream &os, const pair<A, B> &p) { return os << '(' << p.first << \", \" << p.second << ')'; }\n\nvoid debug_out() { cerr << endl; }\ntemplate<typename Head, typename... Tail> void debug_out(Head H, Tail... T) { cerr << ' ' << H; debug_out(T...); }\n\n#ifdef LOCAL\n#define debug(...) cerr << \"(\" << #__VA_ARGS__ << \"):\", debug_out(__VA_ARGS__)\n#else\n#define debug(...) 47\n#endif\nconst ll MAXN=5050;\n\nint main(){\n  fastIO();\n  int x;\n  cin>>x;\n  if(x>=30){\n    cout<<\"Yes\"<<endl;\n  }else{\n    cout<<\"No\"<<endl;\n  }\n  return 0;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nYou will turn on the air conditioner if, and only if, the temperature of the room is 30 degrees Celsius or above.\n\nThe current temperature of the room is X degrees Celsius. Will you turn on the air conditioner?\n\nConstraints\n\n-40 \\leq X \\leq 40\n\nX is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint Yes if you will turn on the air conditioner; print No otherwise.\n\nSample Input 1\n\n25\n\nSample Output 1\n\nNo\n\nSample Input 2\n\n30\n\nSample Output 2\n\nYes", "sample_input": "25\n"}, "reference_outputs": ["No\n"], "source_document_id": "p02594", "source_text": "Score : 100 points\n\nProblem Statement\n\nYou will turn on the air conditioner if, and only if, the temperature of the room is 30 degrees Celsius or above.\n\nThe current temperature of the room is X degrees Celsius. Will you turn on the air conditioner?\n\nConstraints\n\n-40 \\leq X \\leq 40\n\nX is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint Yes if you will turn on the air conditioner; print No otherwise.\n\nSample Input 1\n\n25\n\nSample Output 1\n\nNo\n\nSample Input 2\n\n30\n\nSample Output 2\n\nYes", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1432, "cpu_time_ms": 6, "memory_kb": 3616}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s715818352", "group_id": "codeNet:p02594", "input_text": "#include <iostream>\nusing namespace std;\n\nint main()\n{\n\tint X;\n\tcin >> X;\n\tif (X < 30) {\n\t\tcout << \"Yes\" << endl;\n\t}\n\telse cout << \"No\" << endl;\n\n}\n", "language": "C++", "metadata": {"date": 1597953543, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02594.html", "problem_id": "p02594", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02594/input.txt", "sample_output_relpath": "derived/input_output/data/p02594/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02594/C++/s715818352.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s715818352", "user_id": "u046198295"}, "prompt_components": {"gold_output": "No\n", "input_to_evaluate": "#include <iostream>\nusing namespace std;\n\nint main()\n{\n\tint X;\n\tcin >> X;\n\tif (X < 30) {\n\t\tcout << \"Yes\" << endl;\n\t}\n\telse cout << \"No\" << endl;\n\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nYou will turn on the air conditioner if, and only if, the temperature of the room is 30 degrees Celsius or above.\n\nThe current temperature of the room is X degrees Celsius. Will you turn on the air conditioner?\n\nConstraints\n\n-40 \\leq X \\leq 40\n\nX is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint Yes if you will turn on the air conditioner; print No otherwise.\n\nSample Input 1\n\n25\n\nSample Output 1\n\nNo\n\nSample Input 2\n\n30\n\nSample Output 2\n\nYes", "sample_input": "25\n"}, "reference_outputs": ["No\n"], "source_document_id": "p02594", "source_text": "Score : 100 points\n\nProblem Statement\n\nYou will turn on the air conditioner if, and only if, the temperature of the room is 30 degrees Celsius or above.\n\nThe current temperature of the room is X degrees Celsius. Will you turn on the air conditioner?\n\nConstraints\n\n-40 \\leq X \\leq 40\n\nX is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint Yes if you will turn on the air conditioner; print No otherwise.\n\nSample Input 1\n\n25\n\nSample Output 1\n\nNo\n\nSample Input 2\n\n30\n\nSample Output 2\n\nYes", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 148, "cpu_time_ms": 6, "memory_kb": 3620}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s382061014", "group_id": "codeNet:p02594", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n#define IOS ios::sync_with_stdio(false); cin.tie(0); cout.tie(0);\n#define int long long\n#define pb push_back\n#define ff first\n#define ss second\n\nbool isvalid(int x,int y,int n,int m)\n{\n    return (x>=0 && x<n && y>=0 && y<m);\n}\n\nint cx[]={0,0,1,1,1,-1,-1,-1};\nint cy[]={1,-1,1,0,-1,1,0,-1};\n\nint32_t main()\n{\n    IOS;\n\tint t;\n\tcin>>t;\n\twhile(t--)\n\t{\n\t    int n;\n\t    cin>>n;\n\t    if(n>=30)\n\t    cout<<\"YES\"<<endl;\n\t    else\n\t    cout<<\"NO\"<<endl;\n\t\n\t\n\t\n\t}\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1596416490, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02594.html", "problem_id": "p02594", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02594/input.txt", "sample_output_relpath": "derived/input_output/data/p02594/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02594/C++/s382061014.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s382061014", "user_id": "u149439372"}, "prompt_components": {"gold_output": "No\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n#define IOS ios::sync_with_stdio(false); cin.tie(0); cout.tie(0);\n#define int long long\n#define pb push_back\n#define ff first\n#define ss second\n\nbool isvalid(int x,int y,int n,int m)\n{\n    return (x>=0 && x<n && y>=0 && y<m);\n}\n\nint cx[]={0,0,1,1,1,-1,-1,-1};\nint cy[]={1,-1,1,0,-1,1,0,-1};\n\nint32_t main()\n{\n    IOS;\n\tint t;\n\tcin>>t;\n\twhile(t--)\n\t{\n\t    int n;\n\t    cin>>n;\n\t    if(n>=30)\n\t    cout<<\"YES\"<<endl;\n\t    else\n\t    cout<<\"NO\"<<endl;\n\t\n\t\n\t\n\t}\n\treturn 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nYou will turn on the air conditioner if, and only if, the temperature of the room is 30 degrees Celsius or above.\n\nThe current temperature of the room is X degrees Celsius. Will you turn on the air conditioner?\n\nConstraints\n\n-40 \\leq X \\leq 40\n\nX is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint Yes if you will turn on the air conditioner; print No otherwise.\n\nSample Input 1\n\n25\n\nSample Output 1\n\nNo\n\nSample Input 2\n\n30\n\nSample Output 2\n\nYes", "sample_input": "25\n"}, "reference_outputs": ["No\n"], "source_document_id": "p02594", "source_text": "Score : 100 points\n\nProblem Statement\n\nYou will turn on the air conditioner if, and only if, the temperature of the room is 30 degrees Celsius or above.\n\nThe current temperature of the room is X degrees Celsius. Will you turn on the air conditioner?\n\nConstraints\n\n-40 \\leq X \\leq 40\n\nX is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint Yes if you will turn on the air conditioner; print No otherwise.\n\nSample Input 1\n\n25\n\nSample Output 1\n\nNo\n\nSample Input 2\n\n30\n\nSample Output 2\n\nYes", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 513, "cpu_time_ms": 2218, "memory_kb": 7592}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s318813841", "group_id": "codeNet:p02595", "input_text": "#include<iostream>\nusing namespace std;\nconst int BUF = 200005;\n\n\nint N, D;\nint pt[BUF][2];\n\nvoid read() {\n    cin >> N >> D;\n    for (int i = 0; i < N; ++i) {\n        cin >> pt[i][0] >> pt[i][1];\n    }\n}\n\n\nvoid work() {\n    int cnt = 0;\n    for (int i = 0; i < N; ++i) {\n        cnt += 1LL * pt[i][0] * pt[i][0] + 1LL * pt[i][1] * pt[i][1] <= 1LL * D * D;\n    }\n    cout << cnt << endl;\n}\n\n\nint main() {\n    read();\n    work();\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1596517630, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02595.html", "problem_id": "p02595", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02595/input.txt", "sample_output_relpath": "derived/input_output/data/p02595/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02595/C++/s318813841.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s318813841", "user_id": "u052873655"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include<iostream>\nusing namespace std;\nconst int BUF = 200005;\n\n\nint N, D;\nint pt[BUF][2];\n\nvoid read() {\n    cin >> N >> D;\n    for (int i = 0; i < N; ++i) {\n        cin >> pt[i][0] >> pt[i][1];\n    }\n}\n\n\nvoid work() {\n    int cnt = 0;\n    for (int i = 0; i < N; ++i) {\n        cnt += 1LL * pt[i][0] * pt[i][0] + 1LL * pt[i][1] * pt[i][1] <= 1LL * D * D;\n    }\n    cout << cnt << endl;\n}\n\n\nint main() {\n    read();\n    work();\n    return 0;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nWe have N points in the two-dimensional plane. The coordinates of the i-th point are (X_i,Y_i).\n\nAmong them, we are looking for the points such that the distance from the origin is at most D. How many such points are there?\n\nWe remind you that the distance between the origin and the point (p, q) can be represented as \\sqrt{p^2+q^2}.\n\nConstraints\n\n1 \\leq N \\leq 2\\times 10^5\n\n0 \\leq D \\leq 2\\times 10^5\n\n|X_i|,|Y_i| \\leq 2\\times 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN D\nX_1 Y_1\n\\vdots\nX_N Y_N\n\nOutput\n\nPrint an integer representing the number of points such that the distance from the origin is at most D.\n\nSample Input 1\n\n4 5\n0 5\n-2 4\n3 4\n4 -4\n\nSample Output 1\n\n3\n\nThe distance between the origin and each of the given points is as follows:\n\n\\sqrt{0^2+5^2}=5\n\n\\sqrt{(-2)^2+4^2}=4.472\\ldots\n\n\\sqrt{3^2+4^2}=5\n\n\\sqrt{4^2+(-4)^2}=5.656\\ldots\n\nThus, we have three points such that the distance from the origin is at most 5.\n\nSample Input 2\n\n12 3\n1 1\n1 1\n1 1\n1 1\n1 2\n1 3\n2 1\n2 2\n2 3\n3 1\n3 2\n3 3\n\nSample Output 2\n\n7\n\nMultiple points may exist at the same coordinates.\n\nSample Input 3\n\n20 100000\n14309 -32939\n-56855 100340\n151364 25430\n103789 -113141\n147404 -136977\n-37006 -30929\n188810 -49557\n13419 70401\n-88280 165170\n-196399 137941\n-176527 -61904\n46659 115261\n-153551 114185\n98784 -6820\n94111 -86268\n-30401 61477\n-55056 7872\n5901 -163796\n138819 -185986\n-69848 -96669\n\nSample Output 3\n\n6", "sample_input": "4 5\n0 5\n-2 4\n3 4\n4 -4\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02595", "source_text": "Score : 200 points\n\nProblem Statement\n\nWe have N points in the two-dimensional plane. The coordinates of the i-th point are (X_i,Y_i).\n\nAmong them, we are looking for the points such that the distance from the origin is at most D. How many such points are there?\n\nWe remind you that the distance between the origin and the point (p, q) can be represented as \\sqrt{p^2+q^2}.\n\nConstraints\n\n1 \\leq N \\leq 2\\times 10^5\n\n0 \\leq D \\leq 2\\times 10^5\n\n|X_i|,|Y_i| \\leq 2\\times 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN D\nX_1 Y_1\n\\vdots\nX_N Y_N\n\nOutput\n\nPrint an integer representing the number of points such that the distance from the origin is at most D.\n\nSample Input 1\n\n4 5\n0 5\n-2 4\n3 4\n4 -4\n\nSample Output 1\n\n3\n\nThe distance between the origin and each of the given points is as follows:\n\n\\sqrt{0^2+5^2}=5\n\n\\sqrt{(-2)^2+4^2}=4.472\\ldots\n\n\\sqrt{3^2+4^2}=5\n\n\\sqrt{4^2+(-4)^2}=5.656\\ldots\n\nThus, we have three points such that the distance from the origin is at most 5.\n\nSample Input 2\n\n12 3\n1 1\n1 1\n1 1\n1 1\n1 2\n1 3\n2 1\n2 2\n2 3\n3 1\n3 2\n3 3\n\nSample Output 2\n\n7\n\nMultiple points may exist at the same coordinates.\n\nSample Input 3\n\n20 100000\n14309 -32939\n-56855 100340\n151364 25430\n103789 -113141\n147404 -136977\n-37006 -30929\n188810 -49557\n13419 70401\n-88280 165170\n-196399 137941\n-176527 -61904\n46659 115261\n-153551 114185\n98784 -6820\n94111 -86268\n-30401 61477\n-55056 7872\n5901 -163796\n138819 -185986\n-69848 -96669\n\nSample Output 3\n\n6", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 445, "cpu_time_ms": 101, "memory_kb": 5160}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s948771299", "group_id": "codeNet:p02595", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n//#pragma gcc optimize(\"O3\")\n//#pragma gcc optimize(\"unroll-loops\")\n#ifdef EVAH\n    #define _WIN32_WINNT 0x0500\n    #include<windows.h>\n#endif\n#define openFile(n) ShellExecute(nullptr,\"open\",n,nullptr,nullptr,SW_SHOWNORMAL);\n#define closeP(n) system((string(\"taskkill /im \")+n+\" /f\").c_str());\n#define closeConsole PostMessage(GetConsoleWindow(), WM_CLOSE, 0, 0);\n#define opf \"output.txt\"\n#define ipf \"input.txt\"\n#define mem(n,x) memset(n,x,sizeof(n));\n#define sf scanf\n#define pf printf\n#define ff first\n#define ss second\n#define pb push_back\n#define PII pair<int,int>\n#define For(x,n) for(int i=x; i<n; i++)\n#define stv v+2*(mid-tl+1)\n#define LL long long int\n#define PI acos(-1.0)\n#define N 100000000\n\n\nint main() {\n    ios_base::sync_with_stdio(false);\n    cin.tie(nullptr); cout.tie(nullptr);\n    #ifdef EVAH\n        //freopen(ipf,\"r\",stdin);\n        //openFile(ipf);\n        //closeConsole;\n        //freopen(opf,\"w\",stdout);\n    #endif\n\n    LL n,d,x,y,cnt=0;\n    cin >> n >> d;\n    while(n-- > 0) {\n        cin >> x >> y;\n        if(sqrt(x*x+y*y)<=d) cnt++;\n    }\n    cout << cnt << \"\\n\";\n\n    #ifdef EVAH\n        //openFile(opf);\n        //Sleep(3000);\n        //closeP(\"notepad.exe\");\n        //closeConsole;\n    #endif\n}\n", "language": "C++", "metadata": {"date": 1596416732, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02595.html", "problem_id": "p02595", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02595/input.txt", "sample_output_relpath": "derived/input_output/data/p02595/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02595/C++/s948771299.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s948771299", "user_id": "u709944434"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n//#pragma gcc optimize(\"O3\")\n//#pragma gcc optimize(\"unroll-loops\")\n#ifdef EVAH\n    #define _WIN32_WINNT 0x0500\n    #include<windows.h>\n#endif\n#define openFile(n) ShellExecute(nullptr,\"open\",n,nullptr,nullptr,SW_SHOWNORMAL);\n#define closeP(n) system((string(\"taskkill /im \")+n+\" /f\").c_str());\n#define closeConsole PostMessage(GetConsoleWindow(), WM_CLOSE, 0, 0);\n#define opf \"output.txt\"\n#define ipf \"input.txt\"\n#define mem(n,x) memset(n,x,sizeof(n));\n#define sf scanf\n#define pf printf\n#define ff first\n#define ss second\n#define pb push_back\n#define PII pair<int,int>\n#define For(x,n) for(int i=x; i<n; i++)\n#define stv v+2*(mid-tl+1)\n#define LL long long int\n#define PI acos(-1.0)\n#define N 100000000\n\n\nint main() {\n    ios_base::sync_with_stdio(false);\n    cin.tie(nullptr); cout.tie(nullptr);\n    #ifdef EVAH\n        //freopen(ipf,\"r\",stdin);\n        //openFile(ipf);\n        //closeConsole;\n        //freopen(opf,\"w\",stdout);\n    #endif\n\n    LL n,d,x,y,cnt=0;\n    cin >> n >> d;\n    while(n-- > 0) {\n        cin >> x >> y;\n        if(sqrt(x*x+y*y)<=d) cnt++;\n    }\n    cout << cnt << \"\\n\";\n\n    #ifdef EVAH\n        //openFile(opf);\n        //Sleep(3000);\n        //closeP(\"notepad.exe\");\n        //closeConsole;\n    #endif\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nWe have N points in the two-dimensional plane. The coordinates of the i-th point are (X_i,Y_i).\n\nAmong them, we are looking for the points such that the distance from the origin is at most D. How many such points are there?\n\nWe remind you that the distance between the origin and the point (p, q) can be represented as \\sqrt{p^2+q^2}.\n\nConstraints\n\n1 \\leq N \\leq 2\\times 10^5\n\n0 \\leq D \\leq 2\\times 10^5\n\n|X_i|,|Y_i| \\leq 2\\times 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN D\nX_1 Y_1\n\\vdots\nX_N Y_N\n\nOutput\n\nPrint an integer representing the number of points such that the distance from the origin is at most D.\n\nSample Input 1\n\n4 5\n0 5\n-2 4\n3 4\n4 -4\n\nSample Output 1\n\n3\n\nThe distance between the origin and each of the given points is as follows:\n\n\\sqrt{0^2+5^2}=5\n\n\\sqrt{(-2)^2+4^2}=4.472\\ldots\n\n\\sqrt{3^2+4^2}=5\n\n\\sqrt{4^2+(-4)^2}=5.656\\ldots\n\nThus, we have three points such that the distance from the origin is at most 5.\n\nSample Input 2\n\n12 3\n1 1\n1 1\n1 1\n1 1\n1 2\n1 3\n2 1\n2 2\n2 3\n3 1\n3 2\n3 3\n\nSample Output 2\n\n7\n\nMultiple points may exist at the same coordinates.\n\nSample Input 3\n\n20 100000\n14309 -32939\n-56855 100340\n151364 25430\n103789 -113141\n147404 -136977\n-37006 -30929\n188810 -49557\n13419 70401\n-88280 165170\n-196399 137941\n-176527 -61904\n46659 115261\n-153551 114185\n98784 -6820\n94111 -86268\n-30401 61477\n-55056 7872\n5901 -163796\n138819 -185986\n-69848 -96669\n\nSample Output 3\n\n6", "sample_input": "4 5\n0 5\n-2 4\n3 4\n4 -4\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02595", "source_text": "Score : 200 points\n\nProblem Statement\n\nWe have N points in the two-dimensional plane. The coordinates of the i-th point are (X_i,Y_i).\n\nAmong them, we are looking for the points such that the distance from the origin is at most D. How many such points are there?\n\nWe remind you that the distance between the origin and the point (p, q) can be represented as \\sqrt{p^2+q^2}.\n\nConstraints\n\n1 \\leq N \\leq 2\\times 10^5\n\n0 \\leq D \\leq 2\\times 10^5\n\n|X_i|,|Y_i| \\leq 2\\times 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN D\nX_1 Y_1\n\\vdots\nX_N Y_N\n\nOutput\n\nPrint an integer representing the number of points such that the distance from the origin is at most D.\n\nSample Input 1\n\n4 5\n0 5\n-2 4\n3 4\n4 -4\n\nSample Output 1\n\n3\n\nThe distance between the origin and each of the given points is as follows:\n\n\\sqrt{0^2+5^2}=5\n\n\\sqrt{(-2)^2+4^2}=4.472\\ldots\n\n\\sqrt{3^2+4^2}=5\n\n\\sqrt{4^2+(-4)^2}=5.656\\ldots\n\nThus, we have three points such that the distance from the origin is at most 5.\n\nSample Input 2\n\n12 3\n1 1\n1 1\n1 1\n1 1\n1 2\n1 3\n2 1\n2 2\n2 3\n3 1\n3 2\n3 3\n\nSample Output 2\n\n7\n\nMultiple points may exist at the same coordinates.\n\nSample Input 3\n\n20 100000\n14309 -32939\n-56855 100340\n151364 25430\n103789 -113141\n147404 -136977\n-37006 -30929\n188810 -49557\n13419 70401\n-88280 165170\n-196399 137941\n-176527 -61904\n46659 115261\n-153551 114185\n98784 -6820\n94111 -86268\n-30401 61477\n-55056 7872\n5901 -163796\n138819 -185986\n-69848 -96669\n\nSample Output 3\n\n6", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1276, "cpu_time_ms": 51, "memory_kb": 3664}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s440725386", "group_id": "codeNet:p02596", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n    int k;\n    cin >> k;\n    \n    if (k%2==0 || k%5==0 || k%17==0 || k%19==0 || k%23==0 || k%29==0 || k%31==0) {\n        cout << -1 << endl;\n        return 0;\n    }\n    else {\n        long long s = 7, o = 10, ans = 1;\n        while (1) {\n            if (s%k == 0) {\n                cout << ans << endl;\n                break;\n            }\n            s += o*7;\n            o *= 10;\n            ans++;\n        }\n    }\n}", "language": "C++", "metadata": {"date": 1600392029, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02596.html", "problem_id": "p02596", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02596/input.txt", "sample_output_relpath": "derived/input_output/data/p02596/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02596/C++/s440725386.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s440725386", "user_id": "u528258842"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n    int k;\n    cin >> k;\n    \n    if (k%2==0 || k%5==0 || k%17==0 || k%19==0 || k%23==0 || k%29==0 || k%31==0) {\n        cout << -1 << endl;\n        return 0;\n    }\n    else {\n        long long s = 7, o = 10, ans = 1;\n        while (1) {\n            if (s%k == 0) {\n                cout << ans << endl;\n                break;\n            }\n            s += o*7;\n            o *= 10;\n            ans++;\n        }\n    }\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nTakahashi loves the number 7 and multiples of K.\n\nWhere is the first occurrence of a multiple of K in the sequence 7,77,777,\\ldots? (Also see Output and Sample Input/Output below.)\n\nIf the sequence contains no multiples of K, print -1 instead.\n\nConstraints\n\n1 \\leq K \\leq 10^6\n\nK is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nK\n\nOutput\n\nPrint an integer representing the position of the first occurrence of a multiple of K. (For example, if the first occurrence is the fourth element of the sequence, print 4.)\n\nSample Input 1\n\n101\n\nSample Output 1\n\n4\n\nNone of 7, 77, and 777 is a multiple of 101, but 7777 is.\n\nSample Input 2\n\n2\n\nSample Output 2\n\n-1\n\nAll elements in the sequence are odd numbers; there are no multiples of 2.\n\nSample Input 3\n\n999983\n\nSample Output 3\n\n999982", "sample_input": "101\n"}, "reference_outputs": ["4\n"], "source_document_id": "p02596", "source_text": "Score : 300 points\n\nProblem Statement\n\nTakahashi loves the number 7 and multiples of K.\n\nWhere is the first occurrence of a multiple of K in the sequence 7,77,777,\\ldots? (Also see Output and Sample Input/Output below.)\n\nIf the sequence contains no multiples of K, print -1 instead.\n\nConstraints\n\n1 \\leq K \\leq 10^6\n\nK is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nK\n\nOutput\n\nPrint an integer representing the position of the first occurrence of a multiple of K. (For example, if the first occurrence is the fourth element of the sequence, print 4.)\n\nSample Input 1\n\n101\n\nSample Output 1\n\n4\n\nNone of 7, 77, and 777 is a multiple of 101, but 7777 is.\n\nSample Input 2\n\n2\n\nSample Output 2\n\n-1\n\nAll elements in the sequence are odd numbers; there are no multiples of 2.\n\nSample Input 3\n\n999983\n\nSample Output 3\n\n999982", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 479, "cpu_time_ms": 2205, "memory_kb": 3608}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s726797086", "group_id": "codeNet:p02600", "input_text": "#include<iostream>\n#include<vector>\n#include<string>\n#include<algorithm>\n#include<queue>\n#include<deque>\n#include<cmath>\n#include<map>\n#include<unordered_map>\n#include<set>\n#include<cstring>\n#include<iomanip> //cout << fixed << setprecision(15) << x << endl;\n\nusing namespace std;\ntypedef long long ll;\nconst ll INF = 1e9 + 8;\nconst ll MOD = 1e9 + 7;\nconst ll LLINF = 1e18;\n#define Pint pair<int, int>\n#define rng(i,a,b) for(int i=int(a);i<int(b);i++)\n#define rnr(i,a,b) for(int i=int(a);i>=int(b);i--)\n#define rep(i,b) rng(i,0,b)\n#define pb push_back\n#define mp make_pair\n#define all(x) (x).begin(),(x).end()\n/* -- template -- */\n\nint main() {\n    int x; cin >> x;\n    for(int i = 0; i < 8; ++i) {\n        if(x < 600 + 200 * i) {\n            cout << 8 - i << endl;\n            return 0;\n        }\n    }\n}\n", "language": "C++", "metadata": {"date": 1595980378, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02600.html", "problem_id": "p02600", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02600/input.txt", "sample_output_relpath": "derived/input_output/data/p02600/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02600/C++/s726797086.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s726797086", "user_id": "u275488634"}, "prompt_components": {"gold_output": "7\n", "input_to_evaluate": "#include<iostream>\n#include<vector>\n#include<string>\n#include<algorithm>\n#include<queue>\n#include<deque>\n#include<cmath>\n#include<map>\n#include<unordered_map>\n#include<set>\n#include<cstring>\n#include<iomanip> //cout << fixed << setprecision(15) << x << endl;\n\nusing namespace std;\ntypedef long long ll;\nconst ll INF = 1e9 + 8;\nconst ll MOD = 1e9 + 7;\nconst ll LLINF = 1e18;\n#define Pint pair<int, int>\n#define rng(i,a,b) for(int i=int(a);i<int(b);i++)\n#define rnr(i,a,b) for(int i=int(a);i>=int(b);i--)\n#define rep(i,b) rng(i,0,b)\n#define pb push_back\n#define mp make_pair\n#define all(x) (x).begin(),(x).end()\n/* -- template -- */\n\nint main() {\n    int x; cin >> x;\n    for(int i = 0; i < 8; ++i) {\n        if(x < 600 + 200 * i) {\n            cout << 8 - i << endl;\n            return 0;\n        }\n    }\n}\n", "problem_context": "Score: 100 points\n\nProblem Statement\n\nM-kun is a competitor in AtCoder, whose highest rating is X.\n\nIn this site, a competitor is given a kyu (class) according to his/her highest rating. For ratings from 400 through 1999, the following kyus are given:\n\nFrom 400 through 599: 8-kyu\n\nFrom 600 through 799: 7-kyu\n\nFrom 800 through 999: 6-kyu\n\nFrom 1000 through 1199: 5-kyu\n\nFrom 1200 through 1399: 4-kyu\n\nFrom 1400 through 1599: 3-kyu\n\nFrom 1600 through 1799: 2-kyu\n\nFrom 1800 through 1999: 1-kyu\n\nWhat kyu does M-kun have?\n\nConstraints\n\n400 \\leq X \\leq 1999\n\nX is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint the kyu M-kun has, as an integer.\nFor example, if he has 8-kyu, print 8.\n\nSample Input 1\n\n725\n\nSample Output 1\n\n7\n\nM-kun's highest rating is 725, which corresponds to 7-kyu.\n\nThus, 7 is the correct output.\n\nSample Input 2\n\n1600\n\nSample Output 2\n\n2\n\nM-kun's highest rating is 1600, which corresponds to 2-kyu.\n\nThus, 2 is the correct output.", "sample_input": "725\n"}, "reference_outputs": ["7\n"], "source_document_id": "p02600", "source_text": "Score: 100 points\n\nProblem Statement\n\nM-kun is a competitor in AtCoder, whose highest rating is X.\n\nIn this site, a competitor is given a kyu (class) according to his/her highest rating. For ratings from 400 through 1999, the following kyus are given:\n\nFrom 400 through 599: 8-kyu\n\nFrom 600 through 799: 7-kyu\n\nFrom 800 through 999: 6-kyu\n\nFrom 1000 through 1199: 5-kyu\n\nFrom 1200 through 1399: 4-kyu\n\nFrom 1400 through 1599: 3-kyu\n\nFrom 1600 through 1799: 2-kyu\n\nFrom 1800 through 1999: 1-kyu\n\nWhat kyu does M-kun have?\n\nConstraints\n\n400 \\leq X \\leq 1999\n\nX is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint the kyu M-kun has, as an integer.\nFor example, if he has 8-kyu, print 8.\n\nSample Input 1\n\n725\n\nSample Output 1\n\n7\n\nM-kun's highest rating is 725, which corresponds to 7-kyu.\n\nThus, 7 is the correct output.\n\nSample Input 2\n\n1600\n\nSample Output 2\n\n2\n\nM-kun's highest rating is 1600, which corresponds to 2-kyu.\n\nThus, 2 is the correct output.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 806, "cpu_time_ms": 8, "memory_kb": 3592}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s983068999", "group_id": "codeNet:p02604", "input_text": "#include<cstdio>\n#include<vector>\n#include<queue>\n#include<map>\n#include<set>\n#include<unordered_map>\n#include<stack>\n#include<string>\n#include<algorithm>\n#include<functional>\n#include<cstring>\n#include<complex>\n#include<bitset>\n#include<iostream>\n#include<cassert>\nusing namespace std;\n\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef pair<ll, ll> P;\ntypedef pair<ll, P> Q;\ntypedef complex<double> C;\n#define cx real()\n#define cy imag()\nconst ll INF = 1LL << 60;\nconst double DINF = 1e30;\nconst ll mod = 1000000007;\nconst ll dx[4] = {1, 0, -1, 0};\nconst ll dy[4] = {0, -1, 0, 1};\nconst C I = C(0, 1);\nconst double EPS = 1e-10;\nconst ll NCK_MAX = 510000;\n\nll gcd(ll a, ll b) {\n  if (b == 0) return a;\n  return gcd(b, a % b);\n}\n\nll extgcd(ll a, ll b, ll& x, ll& y) {\n  if (b == 0) {\n    x = 1, y = 0; return a;\n  }\n  ll q = a/b, g = extgcd(b, a - q*b, x, y);\n  ll z = x - q * y;\n  x = y;\n  y = z;\n  return g;\n}\n\nll invmod (ll a, ll m) { // a^-1 mod m\n  ll x, y;\n  extgcd(a, m, x, y);\n  x %= m;\n  if (x < 0) x += m;\n  return x;\n}\n\nll *fac, *finv, *inv;\n\nvoid nCk_init(ll mod) {\n  fac = new ll[NCK_MAX];\n  finv = new ll[NCK_MAX];\n  inv = new ll[NCK_MAX];\n  fac[0] = fac[1] = 1;\n  finv[0] = finv[1] = 1;\n  inv[1] = 1;\n  for (ll i = 2; i < NCK_MAX; i++) {\n    fac[i] = fac[i-1] * i % mod;\n    inv[i] = mod - inv[mod%i] * (mod / i) % mod;\n    finv[i] = finv[i-1] * inv[i] % mod;\n  }\n}\n\nll nCk(ll n, ll k, ll mod) {\n  if (fac == NULL) nCk_init(mod);\n  if (n < k) return 0;\n  if (n < 0 || k < 0) return 0;\n  return fac[n] * (finv[k] * finv[n-k] % mod) % mod;\n}\n\ntemplate <typename T>\nclass Zip {\n  vector<T> d;\n  bool flag;\n  void init() {\n    sort(d.begin(), d.end());\n    d.erase(unique(d.begin(), d.end()), d.end());\n    flag = false;\n  }\npublic:\n  Zip() {\n    flag = false;\n  }\n  void add(T x) {\n    d.push_back(x);\n    flag = true;\n  }\n  ll getNum(T x) {\n    if (flag) init();\n    return lower_bound(d.begin(), d.end(), x) - d.begin();\n  }\n  ll size() {\n    if (flag) init();\n    return (ll)d.size();\n  }\n};\n\nclass UnionFind {\n  vector<ll> par, rank; // par > 0: number, par < 0: -par\npublic:\n  UnionFind(ll n) : par(n, 1), rank(n, 0) {}\n  ll getSize(ll x) {\n    return par[find(x)];\n  }\n  ll find(ll x) {\n    if (par[x] > 0) return x;\n    return -(par[x] = -find(-par[x]));\n  }\n  void merge(ll x, ll y) {\n    x = find(x);\n    y = find(y);\n    if (x == y) return;\n    if (rank[x] < rank[y]) {\n      par[y] += par[x];\n      par[x] = -y;\n    } else {\n      par[x] += par[y];\n      par[y] = -x;\n      if (rank[x] == rank[y]) rank[x]++;\n    }\n  }\n  bool isSame(ll x, ll y) {\n    return find(x) == find(y);\n  }\n};\n\n\ntemplate <typename T>\nclass SegmentTree {\n  ll n;\n  vector<T> node;\n  function<T(T, T)> fun, fun2;\n  bool customChange;\n  T outValue, initValue;\npublic:\n  void init(ll num, function<T(T, T)> resultFunction, T init, T out, function<T(T, T)> changeFunction = NULL) {\n    // changeFunction: (input, beforevalue) => newvalue\n    fun = resultFunction;\n    fun2 = changeFunction;\n    customChange = changeFunction != NULL;\n    n = 1;\n    while (n < num) n *= 2;\n    node.resize(2 * n - 1);\n    fill(node.begin(), node.end(), init);\n    outValue = out;\n    initValue = init;\n  }\n  void valueChange(ll num, T value) {\n    num += n-1;\n    if (customChange) node[num] = fun2(value, node[num]);\n    else node[num] = value;\n    while (num > 0) num = (num - 1) / 2, node[num] = fun(node[num * 2 + 1], node[num * 2 + 2]);\n  }\n  T rangeQuery(ll a, ll b, ll l = 0, ll r = -1, ll k = 0) { // [a, b)\n    if (r == -1) r = n;\n    if (a <= l && r <= b) return node[k];\n    if (b <= l || r <= a) return outValue;\n    ll mid = (l + r) / 2;\n    return fun(rangeQuery(a, b, l, mid, 2*k+1), rangeQuery(a, b, mid, r, 2*k+2));\n  }\n};\n\ntemplate <typename T>\nclass Graph {\n  struct edge { ll to; T cost; };\n  struct edge_data { ll from, to; T cost; };\n\n  ll v;\n  vector<vector<edge>> e, re;\n  vector<edge_data> ed;\n  vector<bool> used;\n  vector<ll> vs, cmp;\n  bool isDirected, isMinasEdge;\npublic:\n  Graph(ll _v, bool _isDirected = true, ll range_add = 0) {\n    // range_add 0:no / 1:in / 2:out / 3:in+ut\n    //_v++;\n    v = _v, isDirected = _isDirected; isMinasEdge = false;\n    e.resize(v), re.resize(v);\n  }\n  void add_edge(ll s, ll t, T cost = 1) {\n    e[s].push_back((edge){t, cost});\n    if (!isDirected) e[t].push_back((edge){s, cost});\n    else re[t].push_back((edge){s, cost});\n    ed.push_back((edge_data){s, t, cost});\n    if (cost < 0) isMinasEdge = true;\n  }\n  vector<T> dijkstra(ll s) {\n    vector<T> d(v, INF);\n    d[s] = 0;\n    auto edge_cmp = [](const edge& a, const edge& b) { return a.cost > b.cost; };\n    priority_queue<edge, vector<edge>, decltype(edge_cmp)> pq(edge_cmp);\n    pq.push((edge){s, 0});\n    while (!pq.empty()) {\n      edge temp = pq.top(); pq.pop();\n      if (d[temp.to] < temp.cost) continue;\n      for (const edge& next : e[temp.to]) {\n        T cost = temp.cost + next.cost;\n        if (d[next.to] > cost) {\n          d[next.to] = cost;\n          pq.push((edge){next.to, cost});\n        }\n      }\n    }\n    return d;\n  }\n  vector<T> bellmanford(ll s) {\n    vector<T> d(v, INF);\n    d[s] = 0;\n    for (ll i = 0; i < v; i++) {\n      for (const edge_data& temp : ed) {\n        if (d[temp.from] != INF && d[temp.to] > d[temp.from] + temp.cost) d[temp.to] = d[temp.from] + temp.cost;\n        if (!isDirected && d[temp.to] != INF && d[temp.from] > d[temp.to] + temp.cost) d[temp.from] = d[temp.to] + temp.cost;\n      }\n    }\n    for (ll i = 0; i < v; i++) {\n      for (const edge_data& temp : ed) {\n        if (d[temp.from] != INF && d[temp.to] > d[temp.from] + temp.cost) d[temp.to] = -INF;\n        if (!isDirected && d[temp.to] != INF && d[temp.from] > d[temp.to] + temp.cost) d[temp.from] = -INF;\n      }\n    }\n    return d;\n  }\n  vector<T> shortest_path(ll s) {\n    if (isMinasEdge) return bellmanford(s);\n    else return dijkstra(s);\n  }\n  T kruskal() {\n    // if (isDirected)\n    UnionFind uf(v);\n    auto edge_data_cmp = [](const edge_data& a, const edge_data& b) { return a.cost < b.cost; };\n    sort(ed.begin(), ed.end(), edge_data_cmp);\n    T ans = 0;\n    for (const edge_data& temp : ed) {\n      if (uf.isSame(temp.from, temp.to)) continue;\n      uf.merge(temp.from, temp.to);\n      ans += temp.cost;\n    }\n    return ans;\n  }\n  void scc_dfs(ll s) {\n    used[s] = true;\n    for (const edge& i : e[s]) if (!used[i.to]) scc_dfs(i.to);\n    vs.push_back(s);\n  }\n  void scc_rdfs(ll s, ll k) {\n    used[s] = true;\n    cmp[s] = k;\n    for (const edge& i : re[s]) if (!used[i.to]) scc_rdfs(i.to, k);\n  }\n  vector<ll> scc() {\n    used.resize(v);\n    fill(used.begin(), used.end(), false);\n    cmp.resize(v);\n    vs.clear();\n    for (ll i = 0; i < v; i++) if (!used[i]) scc_dfs(i);\n    used.resize(v);\n    fill(used.begin(), used.end(), false);\n    ll k = 0;\n    for (ll i = vs.size() - 1; i >= 0; i--) if (!used[vs[i]]) scc_rdfs(vs[i], k++);\n    return cmp;\n  }\n};\n\nclass RollingHash {\n  int base;\n  vector<__int128> hash;\n  vector<__int128> pw;\n  const __int128 hashmod = (1ull << 61) - 1;\npublic:\n  RollingHash(string s, int base = 10007) : base(base), hash(s.length()+1, 0), pw(s.length()+1, 1) {\n    for (int i = 0; i < (int)s.length(); i++) {\n      hash[i+1] = (hash[i] * base + s[i]) % hashmod;\n      pw[i+1] = pw[i] * base % hashmod;\n    }\n  }\n  ll get(ll a, ll b) { // [a, b)\n    __int128 tmp = hashmod + hash[b] - hash[a] * pw[b-a] % hashmod;\n    if (tmp >= hashmod) tmp -= hashmod;\n    return (ll)tmp;\n  }\n};\n\nll n, x[15], y[15], p[15], ans[16], dir[15];\n\nvoid check() {\n  vector<ll> vx, vy;\n  vx.push_back(0);\n  vy.push_back(0);\n  ll counter = 0;\n  for (ll i = 0; i < n; i++) {\n    if (dir[i] == 1) vx.push_back(x[i]), counter++;\n    if (dir[i] == 2) vy.push_back(y[i]), counter++;\n  }\n  ll tmp = 0;\n  for (ll i = 0; i < n; i++) {\n    ll mn = INF;\n    for (ll j : vx) mn = min(mn, abs(x[i] - j));\n    for (ll j : vy) mn = min(mn, abs(y[i] - j));\n    tmp += mn * p[i];\n  }\n  ans[counter] = min(ans[counter], tmp);\n}\n\nint main() {\n  scanf(\"%lld\", &n);\n  for (ll i = 0; i < n; i++) scanf(\"%lld%lld%lld\", &x[i], &y[i], &p[i]);\n  for (ll i = 0; i <= n; i++) ans[i] = INF;\n  check();\n  for (ll i = 0; i < 10000000; i++) {\n    ll tmp = rand() % n;\n    dir[tmp]++;\n    if (dir[tmp] == 3) dir[tmp] = 0;\n    check();\n  }\n  for (ll i = 1; i <= n; i++) ans[i] = min(ans[i], ans[i-1]);\n  for (ll i = 0; i <= n; i++) printf(\"%lld\\n\", ans[i]);\n}\n", "language": "C++", "metadata": {"date": 1595731181, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02604.html", "problem_id": "p02604", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02604/input.txt", "sample_output_relpath": "derived/input_output/data/p02604/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02604/C++/s983068999.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s983068999", "user_id": "u820262277"}, "prompt_components": {"gold_output": "2900\n900\n0\n0\n", "input_to_evaluate": "#include<cstdio>\n#include<vector>\n#include<queue>\n#include<map>\n#include<set>\n#include<unordered_map>\n#include<stack>\n#include<string>\n#include<algorithm>\n#include<functional>\n#include<cstring>\n#include<complex>\n#include<bitset>\n#include<iostream>\n#include<cassert>\nusing namespace std;\n\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef pair<ll, ll> P;\ntypedef pair<ll, P> Q;\ntypedef complex<double> C;\n#define cx real()\n#define cy imag()\nconst ll INF = 1LL << 60;\nconst double DINF = 1e30;\nconst ll mod = 1000000007;\nconst ll dx[4] = {1, 0, -1, 0};\nconst ll dy[4] = {0, -1, 0, 1};\nconst C I = C(0, 1);\nconst double EPS = 1e-10;\nconst ll NCK_MAX = 510000;\n\nll gcd(ll a, ll b) {\n  if (b == 0) return a;\n  return gcd(b, a % b);\n}\n\nll extgcd(ll a, ll b, ll& x, ll& y) {\n  if (b == 0) {\n    x = 1, y = 0; return a;\n  }\n  ll q = a/b, g = extgcd(b, a - q*b, x, y);\n  ll z = x - q * y;\n  x = y;\n  y = z;\n  return g;\n}\n\nll invmod (ll a, ll m) { // a^-1 mod m\n  ll x, y;\n  extgcd(a, m, x, y);\n  x %= m;\n  if (x < 0) x += m;\n  return x;\n}\n\nll *fac, *finv, *inv;\n\nvoid nCk_init(ll mod) {\n  fac = new ll[NCK_MAX];\n  finv = new ll[NCK_MAX];\n  inv = new ll[NCK_MAX];\n  fac[0] = fac[1] = 1;\n  finv[0] = finv[1] = 1;\n  inv[1] = 1;\n  for (ll i = 2; i < NCK_MAX; i++) {\n    fac[i] = fac[i-1] * i % mod;\n    inv[i] = mod - inv[mod%i] * (mod / i) % mod;\n    finv[i] = finv[i-1] * inv[i] % mod;\n  }\n}\n\nll nCk(ll n, ll k, ll mod) {\n  if (fac == NULL) nCk_init(mod);\n  if (n < k) return 0;\n  if (n < 0 || k < 0) return 0;\n  return fac[n] * (finv[k] * finv[n-k] % mod) % mod;\n}\n\ntemplate <typename T>\nclass Zip {\n  vector<T> d;\n  bool flag;\n  void init() {\n    sort(d.begin(), d.end());\n    d.erase(unique(d.begin(), d.end()), d.end());\n    flag = false;\n  }\npublic:\n  Zip() {\n    flag = false;\n  }\n  void add(T x) {\n    d.push_back(x);\n    flag = true;\n  }\n  ll getNum(T x) {\n    if (flag) init();\n    return lower_bound(d.begin(), d.end(), x) - d.begin();\n  }\n  ll size() {\n    if (flag) init();\n    return (ll)d.size();\n  }\n};\n\nclass UnionFind {\n  vector<ll> par, rank; // par > 0: number, par < 0: -par\npublic:\n  UnionFind(ll n) : par(n, 1), rank(n, 0) {}\n  ll getSize(ll x) {\n    return par[find(x)];\n  }\n  ll find(ll x) {\n    if (par[x] > 0) return x;\n    return -(par[x] = -find(-par[x]));\n  }\n  void merge(ll x, ll y) {\n    x = find(x);\n    y = find(y);\n    if (x == y) return;\n    if (rank[x] < rank[y]) {\n      par[y] += par[x];\n      par[x] = -y;\n    } else {\n      par[x] += par[y];\n      par[y] = -x;\n      if (rank[x] == rank[y]) rank[x]++;\n    }\n  }\n  bool isSame(ll x, ll y) {\n    return find(x) == find(y);\n  }\n};\n\n\ntemplate <typename T>\nclass SegmentTree {\n  ll n;\n  vector<T> node;\n  function<T(T, T)> fun, fun2;\n  bool customChange;\n  T outValue, initValue;\npublic:\n  void init(ll num, function<T(T, T)> resultFunction, T init, T out, function<T(T, T)> changeFunction = NULL) {\n    // changeFunction: (input, beforevalue) => newvalue\n    fun = resultFunction;\n    fun2 = changeFunction;\n    customChange = changeFunction != NULL;\n    n = 1;\n    while (n < num) n *= 2;\n    node.resize(2 * n - 1);\n    fill(node.begin(), node.end(), init);\n    outValue = out;\n    initValue = init;\n  }\n  void valueChange(ll num, T value) {\n    num += n-1;\n    if (customChange) node[num] = fun2(value, node[num]);\n    else node[num] = value;\n    while (num > 0) num = (num - 1) / 2, node[num] = fun(node[num * 2 + 1], node[num * 2 + 2]);\n  }\n  T rangeQuery(ll a, ll b, ll l = 0, ll r = -1, ll k = 0) { // [a, b)\n    if (r == -1) r = n;\n    if (a <= l && r <= b) return node[k];\n    if (b <= l || r <= a) return outValue;\n    ll mid = (l + r) / 2;\n    return fun(rangeQuery(a, b, l, mid, 2*k+1), rangeQuery(a, b, mid, r, 2*k+2));\n  }\n};\n\ntemplate <typename T>\nclass Graph {\n  struct edge { ll to; T cost; };\n  struct edge_data { ll from, to; T cost; };\n\n  ll v;\n  vector<vector<edge>> e, re;\n  vector<edge_data> ed;\n  vector<bool> used;\n  vector<ll> vs, cmp;\n  bool isDirected, isMinasEdge;\npublic:\n  Graph(ll _v, bool _isDirected = true, ll range_add = 0) {\n    // range_add 0:no / 1:in / 2:out / 3:in+ut\n    //_v++;\n    v = _v, isDirected = _isDirected; isMinasEdge = false;\n    e.resize(v), re.resize(v);\n  }\n  void add_edge(ll s, ll t, T cost = 1) {\n    e[s].push_back((edge){t, cost});\n    if (!isDirected) e[t].push_back((edge){s, cost});\n    else re[t].push_back((edge){s, cost});\n    ed.push_back((edge_data){s, t, cost});\n    if (cost < 0) isMinasEdge = true;\n  }\n  vector<T> dijkstra(ll s) {\n    vector<T> d(v, INF);\n    d[s] = 0;\n    auto edge_cmp = [](const edge& a, const edge& b) { return a.cost > b.cost; };\n    priority_queue<edge, vector<edge>, decltype(edge_cmp)> pq(edge_cmp);\n    pq.push((edge){s, 0});\n    while (!pq.empty()) {\n      edge temp = pq.top(); pq.pop();\n      if (d[temp.to] < temp.cost) continue;\n      for (const edge& next : e[temp.to]) {\n        T cost = temp.cost + next.cost;\n        if (d[next.to] > cost) {\n          d[next.to] = cost;\n          pq.push((edge){next.to, cost});\n        }\n      }\n    }\n    return d;\n  }\n  vector<T> bellmanford(ll s) {\n    vector<T> d(v, INF);\n    d[s] = 0;\n    for (ll i = 0; i < v; i++) {\n      for (const edge_data& temp : ed) {\n        if (d[temp.from] != INF && d[temp.to] > d[temp.from] + temp.cost) d[temp.to] = d[temp.from] + temp.cost;\n        if (!isDirected && d[temp.to] != INF && d[temp.from] > d[temp.to] + temp.cost) d[temp.from] = d[temp.to] + temp.cost;\n      }\n    }\n    for (ll i = 0; i < v; i++) {\n      for (const edge_data& temp : ed) {\n        if (d[temp.from] != INF && d[temp.to] > d[temp.from] + temp.cost) d[temp.to] = -INF;\n        if (!isDirected && d[temp.to] != INF && d[temp.from] > d[temp.to] + temp.cost) d[temp.from] = -INF;\n      }\n    }\n    return d;\n  }\n  vector<T> shortest_path(ll s) {\n    if (isMinasEdge) return bellmanford(s);\n    else return dijkstra(s);\n  }\n  T kruskal() {\n    // if (isDirected)\n    UnionFind uf(v);\n    auto edge_data_cmp = [](const edge_data& a, const edge_data& b) { return a.cost < b.cost; };\n    sort(ed.begin(), ed.end(), edge_data_cmp);\n    T ans = 0;\n    for (const edge_data& temp : ed) {\n      if (uf.isSame(temp.from, temp.to)) continue;\n      uf.merge(temp.from, temp.to);\n      ans += temp.cost;\n    }\n    return ans;\n  }\n  void scc_dfs(ll s) {\n    used[s] = true;\n    for (const edge& i : e[s]) if (!used[i.to]) scc_dfs(i.to);\n    vs.push_back(s);\n  }\n  void scc_rdfs(ll s, ll k) {\n    used[s] = true;\n    cmp[s] = k;\n    for (const edge& i : re[s]) if (!used[i.to]) scc_rdfs(i.to, k);\n  }\n  vector<ll> scc() {\n    used.resize(v);\n    fill(used.begin(), used.end(), false);\n    cmp.resize(v);\n    vs.clear();\n    for (ll i = 0; i < v; i++) if (!used[i]) scc_dfs(i);\n    used.resize(v);\n    fill(used.begin(), used.end(), false);\n    ll k = 0;\n    for (ll i = vs.size() - 1; i >= 0; i--) if (!used[vs[i]]) scc_rdfs(vs[i], k++);\n    return cmp;\n  }\n};\n\nclass RollingHash {\n  int base;\n  vector<__int128> hash;\n  vector<__int128> pw;\n  const __int128 hashmod = (1ull << 61) - 1;\npublic:\n  RollingHash(string s, int base = 10007) : base(base), hash(s.length()+1, 0), pw(s.length()+1, 1) {\n    for (int i = 0; i < (int)s.length(); i++) {\n      hash[i+1] = (hash[i] * base + s[i]) % hashmod;\n      pw[i+1] = pw[i] * base % hashmod;\n    }\n  }\n  ll get(ll a, ll b) { // [a, b)\n    __int128 tmp = hashmod + hash[b] - hash[a] * pw[b-a] % hashmod;\n    if (tmp >= hashmod) tmp -= hashmod;\n    return (ll)tmp;\n  }\n};\n\nll n, x[15], y[15], p[15], ans[16], dir[15];\n\nvoid check() {\n  vector<ll> vx, vy;\n  vx.push_back(0);\n  vy.push_back(0);\n  ll counter = 0;\n  for (ll i = 0; i < n; i++) {\n    if (dir[i] == 1) vx.push_back(x[i]), counter++;\n    if (dir[i] == 2) vy.push_back(y[i]), counter++;\n  }\n  ll tmp = 0;\n  for (ll i = 0; i < n; i++) {\n    ll mn = INF;\n    for (ll j : vx) mn = min(mn, abs(x[i] - j));\n    for (ll j : vy) mn = min(mn, abs(y[i] - j));\n    tmp += mn * p[i];\n  }\n  ans[counter] = min(ans[counter], tmp);\n}\n\nint main() {\n  scanf(\"%lld\", &n);\n  for (ll i = 0; i < n; i++) scanf(\"%lld%lld%lld\", &x[i], &y[i], &p[i]);\n  for (ll i = 0; i <= n; i++) ans[i] = INF;\n  check();\n  for (ll i = 0; i < 10000000; i++) {\n    ll tmp = rand() % n;\n    dir[tmp]++;\n    if (dir[tmp] == 3) dir[tmp] = 0;\n    check();\n  }\n  for (ll i = 1; i <= n; i++) ans[i] = min(ans[i], ans[i-1]);\n  for (ll i = 0; i <= n; i++) printf(\"%lld\\n\", ans[i]);\n}\n", "problem_context": "Score: 500 points\n\nProblem Statement\n\nNew AtCoder City has an infinite grid of streets, as follows:\n\nAt the center of the city stands a clock tower. Let (0, 0) be the coordinates of this point.\n\nA straight street, which we will call East-West Main Street, runs east-west and passes the clock tower. It corresponds to the x-axis in the two-dimensional coordinate plane.\n\nThere are also other infinitely many streets parallel to East-West Main Street, with a distance of 1 between them. They correspond to the lines \\ldots, y = -2, y = -1, y = 1, y = 2, \\ldots in the two-dimensional coordinate plane.\n\nA straight street, which we will call North-South Main Street, runs north-south and passes the clock tower. It corresponds to the y-axis in the two-dimensional coordinate plane.\n\nThere are also other infinitely many streets parallel to North-South Main Street, with a distance of 1 between them. They correspond to the lines \\ldots, x = -2, x = -1, x = 1, x = 2, \\ldots in the two-dimensional coordinate plane.\n\nThere are N residential areas in New AtCoder City. The i-th area is located at the intersection with the coordinates (X_i, Y_i) and has a population of P_i. Each citizen in the city lives in one of these areas.\n\nThe city currently has only two railroads, stretching infinitely, one along East-West Main Street and the other along North-South Main Street.\n\nM-kun, the mayor, thinks that they are not enough for the commuters, so he decides to choose K streets and build a railroad stretching infinitely along each of those streets.\n\nLet the walking distance of each citizen be the distance from his/her residential area to the nearest railroad.\n\nM-kun wants to build railroads so that the sum of the walking distances of all citizens, S, is minimized.\n\nFor each K = 0, 1, 2, \\dots, N, what is the minimum possible value of S after building railroads?\n\nConstraints\n\n1 \\leq N \\leq 15\n\n-10 \\ 000 \\leq X_i \\leq 10 \\ 000\n\n-10 \\ 000 \\leq Y_i \\leq 10 \\ 000\n\n1 \\leq P_i \\leq 1 \\ 000 \\ 000\n\nThe locations of the N residential areas, (X_i, Y_i), are all distinct.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nX_1 Y_1 P_1\nX_2 Y_2 P_2\n: : :\nX_N Y_N P_N\n\nOutput\n\nPrint the answer in N+1 lines.\n\nThe i-th line (i = 1, \\ldots, N+1) should contain the minimum possible value of S after building railroads for the case K = i-1.\n\nSample Input 1\n\n3\n1 2 300\n3 3 600\n1 4 800\n\nSample Output 1\n\n2900\n900\n0\n0\n\nWhen K = 0, the residents of Area 1, 2, and 3 have to walk the distances of 1, 3, and 1, respectively, to reach a railroad.\n\nThus, the sum of the walking distances of all citizens, S, is 1 \\times 300 + 3 \\times 600 + 1 \\times 800 = 2900.\n\nWhen K = 1, if we build a railroad along the street corresponding to the line y = 4 in the coordinate plane, the walking distances of the citizens of Area 1, 2, and 3 become 1, 1, and 0, respectively.\n\nThen, S = 1 \\times 300 + 1 \\times 600 + 0 \\times 800 = 900.\n\nWe have many other options for where we build the railroad, but none of them makes S less than 900.\n\nWhen K = 2, if we build a railroad along the street corresponding to the lines x = 1 and x = 3 in the coordinate plane, all citizens can reach a railroad with the walking distance of 0, so S = 0. We can also have S = 0 when K = 3.\n\nThe figure below shows the optimal way to build railroads for the cases K = 0, 1, 2.\n\nThe street painted blue represents the roads along which we build railroads.\n\nSample Input 2\n\n5\n3 5 400\n5 3 700\n5 5 1000\n5 7 700\n7 5 400\n\nSample Output 2\n\n13800\n1600\n0\n0\n0\n0\n\nThe figure below shows the optimal way to build railroads for the cases K = 1, 2.\n\nSample Input 3\n\n6\n2 5 1000\n5 2 1100\n5 5 1700\n-2 -5 900\n-5 -2 600\n-5 -5 2200\n\nSample Output 3\n\n26700\n13900\n3200\n1200\n0\n0\n0\n\nThe figure below shows the optimal way to build railroads for the case K = 3.\n\nSample Input 4\n\n8\n2 2 286017\n3 1 262355\n2 -2 213815\n1 -3 224435\n-2 -2 136860\n-3 -1 239338\n-2 2 217647\n-1 3 141903\n\nSample Output 4\n\n2576709\n1569381\n868031\n605676\n366338\n141903\n0\n0\n0\n\nThe figure below shows the optimal way to build railroads for the case K = 4.", "sample_input": "3\n1 2 300\n3 3 600\n1 4 800\n"}, "reference_outputs": ["2900\n900\n0\n0\n"], "source_document_id": "p02604", "source_text": "Score: 500 points\n\nProblem Statement\n\nNew AtCoder City has an infinite grid of streets, as follows:\n\nAt the center of the city stands a clock tower. Let (0, 0) be the coordinates of this point.\n\nA straight street, which we will call East-West Main Street, runs east-west and passes the clock tower. It corresponds to the x-axis in the two-dimensional coordinate plane.\n\nThere are also other infinitely many streets parallel to East-West Main Street, with a distance of 1 between them. They correspond to the lines \\ldots, y = -2, y = -1, y = 1, y = 2, \\ldots in the two-dimensional coordinate plane.\n\nA straight street, which we will call North-South Main Street, runs north-south and passes the clock tower. It corresponds to the y-axis in the two-dimensional coordinate plane.\n\nThere are also other infinitely many streets parallel to North-South Main Street, with a distance of 1 between them. They correspond to the lines \\ldots, x = -2, x = -1, x = 1, x = 2, \\ldots in the two-dimensional coordinate plane.\n\nThere are N residential areas in New AtCoder City. The i-th area is located at the intersection with the coordinates (X_i, Y_i) and has a population of P_i. Each citizen in the city lives in one of these areas.\n\nThe city currently has only two railroads, stretching infinitely, one along East-West Main Street and the other along North-South Main Street.\n\nM-kun, the mayor, thinks that they are not enough for the commuters, so he decides to choose K streets and build a railroad stretching infinitely along each of those streets.\n\nLet the walking distance of each citizen be the distance from his/her residential area to the nearest railroad.\n\nM-kun wants to build railroads so that the sum of the walking distances of all citizens, S, is minimized.\n\nFor each K = 0, 1, 2, \\dots, N, what is the minimum possible value of S after building railroads?\n\nConstraints\n\n1 \\leq N \\leq 15\n\n-10 \\ 000 \\leq X_i \\leq 10 \\ 000\n\n-10 \\ 000 \\leq Y_i \\leq 10 \\ 000\n\n1 \\leq P_i \\leq 1 \\ 000 \\ 000\n\nThe locations of the N residential areas, (X_i, Y_i), are all distinct.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nX_1 Y_1 P_1\nX_2 Y_2 P_2\n: : :\nX_N Y_N P_N\n\nOutput\n\nPrint the answer in N+1 lines.\n\nThe i-th line (i = 1, \\ldots, N+1) should contain the minimum possible value of S after building railroads for the case K = i-1.\n\nSample Input 1\n\n3\n1 2 300\n3 3 600\n1 4 800\n\nSample Output 1\n\n2900\n900\n0\n0\n\nWhen K = 0, the residents of Area 1, 2, and 3 have to walk the distances of 1, 3, and 1, respectively, to reach a railroad.\n\nThus, the sum of the walking distances of all citizens, S, is 1 \\times 300 + 3 \\times 600 + 1 \\times 800 = 2900.\n\nWhen K = 1, if we build a railroad along the street corresponding to the line y = 4 in the coordinate plane, the walking distances of the citizens of Area 1, 2, and 3 become 1, 1, and 0, respectively.\n\nThen, S = 1 \\times 300 + 1 \\times 600 + 0 \\times 800 = 900.\n\nWe have many other options for where we build the railroad, but none of them makes S less than 900.\n\nWhen K = 2, if we build a railroad along the street corresponding to the lines x = 1 and x = 3 in the coordinate plane, all citizens can reach a railroad with the walking distance of 0, so S = 0. We can also have S = 0 when K = 3.\n\nThe figure below shows the optimal way to build railroads for the cases K = 0, 1, 2.\n\nThe street painted blue represents the roads along which we build railroads.\n\nSample Input 2\n\n5\n3 5 400\n5 3 700\n5 5 1000\n5 7 700\n7 5 400\n\nSample Output 2\n\n13800\n1600\n0\n0\n0\n0\n\nThe figure below shows the optimal way to build railroads for the cases K = 1, 2.\n\nSample Input 3\n\n6\n2 5 1000\n5 2 1100\n5 5 1700\n-2 -5 900\n-5 -2 600\n-5 -5 2200\n\nSample Output 3\n\n26700\n13900\n3200\n1200\n0\n0\n0\n\nThe figure below shows the optimal way to build railroads for the case K = 3.\n\nSample Input 4\n\n8\n2 2 286017\n3 1 262355\n2 -2 213815\n1 -3 224435\n-2 -2 136860\n-3 -1 239338\n-2 2 217647\n-1 3 141903\n\nSample Output 4\n\n2576709\n1569381\n868031\n605676\n366338\n141903\n0\n0\n0\n\nThe figure below shows the optimal way to build railroads for the case K = 4.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 8369, "cpu_time_ms": 3308, "memory_kb": 3772}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s425131249", "group_id": "codeNet:p02605", "input_text": "#include <algorithm>\n#include <iostream>\n#include <iomanip>\n#include <numeric>\n#include <cassert>\n#include <vector>\n#include <cmath>\n#include <queue>\n#include <set>\n#include <map>\n#define syosu(x) fixed<<setprecision(x)\nusing namespace std;\ntypedef long long ll;\ntypedef unsigned int uint;\ntypedef unsigned long long ull;\ntypedef pair<int,int> P;\ntypedef pair<double,double> pdd;\ntypedef pair<ll,ll> pll;\ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\ntypedef vector<double> vd;\ntypedef vector<vd> vvd;\ntypedef vector<ll> vl;\ntypedef vector<vl> vvl;\ntypedef vector<string> vs;\ntypedef vector<P> vp;\ntypedef vector<vp> vvp;\ntypedef vector<pll> vpll;\ntypedef pair<int,P> pip;\ntypedef vector<pip> vip;\nconst int inf=1<<28;\nconst ll INF=1ll<<60;\nconst double pi=acos(-1);\nconst double eps=1e-8;\nconst ll mod=998244353;\nconst int dx[4]={-1,0,1,0},dy[4]={0,-1,0,1};\n\nconst int M=500001;\nint n;\nvi x,y,a;\nmap<char,int> mp={\n\t{'U',0},\n\t{'R',1},\n\t{'D',2},\n\t{'L',3},\n};\n\nint main(){\n\tcin>>n;\n\tint res=inf;\n\tx=y=a=vi(n);\n\tfor(int i=0;i<n;i++){\n\t\tchar c;\n\t\tcin>>x[i]>>y[i]>>c;\n\t\ta[i]=mp[c];\n\t}\n\tvvp b(M);\n\tfor(int i=0;i<n;i++) if(a[i]%2==0) b[x[i]].push_back({y[i],a[i]});\n\tfor(int i=0;i<M;i++) if(!b[i].empty()){\n\t\tsort(b[i].begin(),b[i].end());\n\t\tint tmp=-inf;\n\t\tfor(auto p:b[i]){\n\t\t\tif(p.second==0) tmp=p.first;\n\t\t\telse res=min(res,p.first-tmp);\n\t\t}\n\t}\n\tb=vvp(M);\n\tfor(int i=0;i<n;i++) if(a[i]%2==1) b[y[i]].push_back({x[i],a[i]});\n\tfor(int i=0;i<M;i++) if(!b[i].empty()){\n\t\tsort(b[i].begin(),b[i].end());\n\t\tint tmp=-inf;\n\t\tfor(auto p:b[i]){\n\t\t\tif(p.second==1) tmp=p.first;\n\t\t\telse res=min(res,p.first-tmp);\n\t\t}\n\t}\n\tb=vvp(M);\n\tfor(int i=0;i<n;i++) b[x[i]+y[i]].push_back({x[i],a[i]});\n\tfor(int i=0;i<M;i++) if(!b[i].empty()){\n\t\tsort(b[i].begin(),b[i].end());\n\t\tint tmp=-inf;\n\t\tfor(auto p:b[i]){\n\t\t\tif(p.second==1) tmp=p.first;\n\t\t\tif(p.second==0) res=min(res,(p.first-tmp)*2);\n\t\t}\n\t\ttmp=-inf;\n\t\tfor(auto p:b[i]){\n\t\t\tif(p.second==2) tmp=p.first;\n\t\t\tif(p.second==3) res=min(res,(p.first-tmp)*2);\n\t\t}\n\t}\n\tb=vvp(M);\n\tfor(int i=0;i<n;i++) b[x[i]-y[i]+M].push_back({x[i],a[i]});\n\tfor(int i=0;i<M;i++) if(!b[i].empty()){\n\t\tsort(b[i].begin(),b[i].end());\n\t\tint tmp=-inf;\n\t\tfor(auto p:b[i]){\n\t\t\tif(p.second==0) tmp=p.first;\n\t\t\tif(p.second==3) res=min(res,(p.first-tmp)*2);\n\t\t}\n\t\ttmp=-inf;\n\t\tfor(auto p:b[i]){\n\t\t\tif(p.second==1) tmp=p.first;\n\t\t\tif(p.second==2) res=min(res,(p.first-tmp)*2);\n\t\t}\n\t}\n\tif(res==inf) cout<<\"SAFE\"<<endl;\n\telse cout<<res*5<<endl;\n}", "language": "C++", "metadata": {"date": 1601200099, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02605.html", "problem_id": "p02605", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02605/input.txt", "sample_output_relpath": "derived/input_output/data/p02605/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02605/C++/s425131249.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s425131249", "user_id": "u434747175"}, "prompt_components": {"gold_output": "230\n", "input_to_evaluate": "#include <algorithm>\n#include <iostream>\n#include <iomanip>\n#include <numeric>\n#include <cassert>\n#include <vector>\n#include <cmath>\n#include <queue>\n#include <set>\n#include <map>\n#define syosu(x) fixed<<setprecision(x)\nusing namespace std;\ntypedef long long ll;\ntypedef unsigned int uint;\ntypedef unsigned long long ull;\ntypedef pair<int,int> P;\ntypedef pair<double,double> pdd;\ntypedef pair<ll,ll> pll;\ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\ntypedef vector<double> vd;\ntypedef vector<vd> vvd;\ntypedef vector<ll> vl;\ntypedef vector<vl> vvl;\ntypedef vector<string> vs;\ntypedef vector<P> vp;\ntypedef vector<vp> vvp;\ntypedef vector<pll> vpll;\ntypedef pair<int,P> pip;\ntypedef vector<pip> vip;\nconst int inf=1<<28;\nconst ll INF=1ll<<60;\nconst double pi=acos(-1);\nconst double eps=1e-8;\nconst ll mod=998244353;\nconst int dx[4]={-1,0,1,0},dy[4]={0,-1,0,1};\n\nconst int M=500001;\nint n;\nvi x,y,a;\nmap<char,int> mp={\n\t{'U',0},\n\t{'R',1},\n\t{'D',2},\n\t{'L',3},\n};\n\nint main(){\n\tcin>>n;\n\tint res=inf;\n\tx=y=a=vi(n);\n\tfor(int i=0;i<n;i++){\n\t\tchar c;\n\t\tcin>>x[i]>>y[i]>>c;\n\t\ta[i]=mp[c];\n\t}\n\tvvp b(M);\n\tfor(int i=0;i<n;i++) if(a[i]%2==0) b[x[i]].push_back({y[i],a[i]});\n\tfor(int i=0;i<M;i++) if(!b[i].empty()){\n\t\tsort(b[i].begin(),b[i].end());\n\t\tint tmp=-inf;\n\t\tfor(auto p:b[i]){\n\t\t\tif(p.second==0) tmp=p.first;\n\t\t\telse res=min(res,p.first-tmp);\n\t\t}\n\t}\n\tb=vvp(M);\n\tfor(int i=0;i<n;i++) if(a[i]%2==1) b[y[i]].push_back({x[i],a[i]});\n\tfor(int i=0;i<M;i++) if(!b[i].empty()){\n\t\tsort(b[i].begin(),b[i].end());\n\t\tint tmp=-inf;\n\t\tfor(auto p:b[i]){\n\t\t\tif(p.second==1) tmp=p.first;\n\t\t\telse res=min(res,p.first-tmp);\n\t\t}\n\t}\n\tb=vvp(M);\n\tfor(int i=0;i<n;i++) b[x[i]+y[i]].push_back({x[i],a[i]});\n\tfor(int i=0;i<M;i++) if(!b[i].empty()){\n\t\tsort(b[i].begin(),b[i].end());\n\t\tint tmp=-inf;\n\t\tfor(auto p:b[i]){\n\t\t\tif(p.second==1) tmp=p.first;\n\t\t\tif(p.second==0) res=min(res,(p.first-tmp)*2);\n\t\t}\n\t\ttmp=-inf;\n\t\tfor(auto p:b[i]){\n\t\t\tif(p.second==2) tmp=p.first;\n\t\t\tif(p.second==3) res=min(res,(p.first-tmp)*2);\n\t\t}\n\t}\n\tb=vvp(M);\n\tfor(int i=0;i<n;i++) b[x[i]-y[i]+M].push_back({x[i],a[i]});\n\tfor(int i=0;i<M;i++) if(!b[i].empty()){\n\t\tsort(b[i].begin(),b[i].end());\n\t\tint tmp=-inf;\n\t\tfor(auto p:b[i]){\n\t\t\tif(p.second==0) tmp=p.first;\n\t\t\tif(p.second==3) res=min(res,(p.first-tmp)*2);\n\t\t}\n\t\ttmp=-inf;\n\t\tfor(auto p:b[i]){\n\t\t\tif(p.second==1) tmp=p.first;\n\t\t\tif(p.second==2) res=min(res,(p.first-tmp)*2);\n\t\t}\n\t}\n\tif(res==inf) cout<<\"SAFE\"<<endl;\n\telse cout<<res*5<<endl;\n}", "problem_context": "Score: 600 points\n\nProblem Statement\n\nM-kun is a brilliant air traffic controller.\n\nOn the display of his radar, there are N airplanes numbered 1, 2, ..., N, all flying at the same altitude.\n\nEach of the airplanes flies at a constant speed of 0.1 per second in a constant direction. The current coordinates of the airplane numbered i are (X_i, Y_i), and the direction of the airplane is as follows:\n\nif U_i is U, it flies in the positive y direction;\n\nif U_i is R, it flies in the positive x direction;\n\nif U_i is D, it flies in the negative y direction;\n\nif U_i is L, it flies in the negative x direction.\n\nTo help M-kun in his work, determine whether there is a pair of airplanes that will collide with each other if they keep flying as they are now.\n\nIf there is such a pair, find the number of seconds after which the first collision will happen.\n\nWe assume that the airplanes are negligibly small so that two airplanes only collide when they reach the same coordinates simultaneously.\n\nConstraints\n\n1 \\leq N \\leq 200000\n\n0 \\leq X_i, Y_i \\leq 200000\n\nU_i is U, R, D, or L.\n\nThe current positions of the N airplanes, (X_i, Y_i), are all distinct.\n\nN, X_i, and Y_i are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nX_1 Y_1 U_1\nX_2 Y_2 U_2\nX_3 Y_3 U_3\n:\nX_N Y_N U_N\n\nOutput\n\nIf there is a pair of airplanes that will collide with each other if they keep flying as they are now, print an integer representing the number of seconds after which the first collision will happen.\n\nIf there is no such pair, print SAFE.\n\nSample Input 1\n\n2\n11 1 U\n11 47 D\n\nSample Output 1\n\n230\n\nIf the airplanes keep flying as they are now, two airplanes numbered 1 and 2 will reach the coordinates (11, 24) simultaneously and collide.\n\nSample Input 2\n\n4\n20 30 U\n30 20 R\n20 10 D\n10 20 L\n\nSample Output 2\n\nSAFE\n\nNo pair of airplanes will collide.\n\nSample Input 3\n\n8\n168 224 U\n130 175 R\n111 198 D\n121 188 L\n201 116 U\n112 121 R\n145 239 D\n185 107 L\n\nSample Output 3\n\n100", "sample_input": "2\n11 1 U\n11 47 D\n"}, "reference_outputs": ["230\n"], "source_document_id": "p02605", "source_text": "Score: 600 points\n\nProblem Statement\n\nM-kun is a brilliant air traffic controller.\n\nOn the display of his radar, there are N airplanes numbered 1, 2, ..., N, all flying at the same altitude.\n\nEach of the airplanes flies at a constant speed of 0.1 per second in a constant direction. The current coordinates of the airplane numbered i are (X_i, Y_i), and the direction of the airplane is as follows:\n\nif U_i is U, it flies in the positive y direction;\n\nif U_i is R, it flies in the positive x direction;\n\nif U_i is D, it flies in the negative y direction;\n\nif U_i is L, it flies in the negative x direction.\n\nTo help M-kun in his work, determine whether there is a pair of airplanes that will collide with each other if they keep flying as they are now.\n\nIf there is such a pair, find the number of seconds after which the first collision will happen.\n\nWe assume that the airplanes are negligibly small so that two airplanes only collide when they reach the same coordinates simultaneously.\n\nConstraints\n\n1 \\leq N \\leq 200000\n\n0 \\leq X_i, Y_i \\leq 200000\n\nU_i is U, R, D, or L.\n\nThe current positions of the N airplanes, (X_i, Y_i), are all distinct.\n\nN, X_i, and Y_i are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nX_1 Y_1 U_1\nX_2 Y_2 U_2\nX_3 Y_3 U_3\n:\nX_N Y_N U_N\n\nOutput\n\nIf there is a pair of airplanes that will collide with each other if they keep flying as they are now, print an integer representing the number of seconds after which the first collision will happen.\n\nIf there is no such pair, print SAFE.\n\nSample Input 1\n\n2\n11 1 U\n11 47 D\n\nSample Output 1\n\n230\n\nIf the airplanes keep flying as they are now, two airplanes numbered 1 and 2 will reach the coordinates (11, 24) simultaneously and collide.\n\nSample Input 2\n\n4\n20 30 U\n30 20 R\n20 10 D\n10 20 L\n\nSample Output 2\n\nSAFE\n\nNo pair of airplanes will collide.\n\nSample Input 3\n\n8\n168 224 U\n130 175 R\n111 198 D\n121 188 L\n201 116 U\n112 121 R\n145 239 D\n185 107 L\n\nSample Output 3\n\n100", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2439, "cpu_time_ms": 278, "memory_kb": 35436}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s486612593", "group_id": "codeNet:p02606", "input_text": "#include <iostream>\nusing namespace std;\nint main(){\n  int l,r,d,result=0;\n  cin >> l >> r >> d;\n  for(;l<=r;l++){\n    if(l%d==0) result++;\n  }\n  cout << result << endl;\n  return 0;\n}", "language": "C++", "metadata": {"date": 1594526620, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02606.html", "problem_id": "p02606", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02606/input.txt", "sample_output_relpath": "derived/input_output/data/p02606/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02606/C++/s486612593.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s486612593", "user_id": "u091870478"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <iostream>\nusing namespace std;\nint main(){\n  int l,r,d,result=0;\n  cin >> l >> r >> d;\n  for(;l<=r;l++){\n    if(l%d==0) result++;\n  }\n  cout << result << endl;\n  return 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nHow many multiples of d are there among the integers between L and R (inclusive)?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq L \\leq R \\leq 100\n\n1 \\leq d \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nL R d\n\nOutput\n\nPrint the number of multiples of d among the integers between L and R (inclusive).\n\nSample Input 1\n\n5 10 2\n\nSample Output 1\n\n3\n\nAmong the integers between 5 and 10, there are three multiples of 2: 6, 8, and 10.\n\nSample Input 2\n\n6 20 7\n\nSample Output 2\n\n2\n\nAmong the integers between 6 and 20, there are two multiples of 7: 7 and 14.\n\nSample Input 3\n\n1 100 1\n\nSample Output 3\n\n100", "sample_input": "5 10 2\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02606", "source_text": "Score : 100 points\n\nProblem Statement\n\nHow many multiples of d are there among the integers between L and R (inclusive)?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq L \\leq R \\leq 100\n\n1 \\leq d \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nL R d\n\nOutput\n\nPrint the number of multiples of d among the integers between L and R (inclusive).\n\nSample Input 1\n\n5 10 2\n\nSample Output 1\n\n3\n\nAmong the integers between 5 and 10, there are three multiples of 2: 6, 8, and 10.\n\nSample Input 2\n\n6 20 7\n\nSample Output 2\n\n2\n\nAmong the integers between 6 and 20, there are two multiples of 7: 7 and 14.\n\nSample Input 3\n\n1 100 1\n\nSample Output 3\n\n100", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 183, "cpu_time_ms": 7, "memory_kb": 3624}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s891867279", "group_id": "codeNet:p02606", "input_text": "#include <bits/stdc++.h>\n\n#ifdef NON_SUBMIT\n#define TEST(n) (n)\n#define tout cerr\n#else\n#define TEST(n) ((void)0)\n#define tout cin\n#endif\n\nusing namespace std;\n\nint main()\n{\n\tios::sync_with_stdio(false);\n\tcin.tie(NULL); cout.tie(NULL);\n\tTEST(freopen(\"input.txt\",\"r\",stdin));\n\tTEST(freopen(\"output.txt\",\"w\",stdout));\n\tTEST(freopen(\"debug.txt\",\"w\",stderr));\n\tint L, R, D;\n\tcin>>L>>R>>D;\n\tcout<<R/D-(L-1)/D<<'\\n';\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1594515668, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02606.html", "problem_id": "p02606", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02606/input.txt", "sample_output_relpath": "derived/input_output/data/p02606/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02606/C++/s891867279.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s891867279", "user_id": "u548859367"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\n#ifdef NON_SUBMIT\n#define TEST(n) (n)\n#define tout cerr\n#else\n#define TEST(n) ((void)0)\n#define tout cin\n#endif\n\nusing namespace std;\n\nint main()\n{\n\tios::sync_with_stdio(false);\n\tcin.tie(NULL); cout.tie(NULL);\n\tTEST(freopen(\"input.txt\",\"r\",stdin));\n\tTEST(freopen(\"output.txt\",\"w\",stdout));\n\tTEST(freopen(\"debug.txt\",\"w\",stderr));\n\tint L, R, D;\n\tcin>>L>>R>>D;\n\tcout<<R/D-(L-1)/D<<'\\n';\n\treturn 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nHow many multiples of d are there among the integers between L and R (inclusive)?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq L \\leq R \\leq 100\n\n1 \\leq d \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nL R d\n\nOutput\n\nPrint the number of multiples of d among the integers between L and R (inclusive).\n\nSample Input 1\n\n5 10 2\n\nSample Output 1\n\n3\n\nAmong the integers between 5 and 10, there are three multiples of 2: 6, 8, and 10.\n\nSample Input 2\n\n6 20 7\n\nSample Output 2\n\n2\n\nAmong the integers between 6 and 20, there are two multiples of 7: 7 and 14.\n\nSample Input 3\n\n1 100 1\n\nSample Output 3\n\n100", "sample_input": "5 10 2\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02606", "source_text": "Score : 100 points\n\nProblem Statement\n\nHow many multiples of d are there among the integers between L and R (inclusive)?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq L \\leq R \\leq 100\n\n1 \\leq d \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nL R d\n\nOutput\n\nPrint the number of multiples of d among the integers between L and R (inclusive).\n\nSample Input 1\n\n5 10 2\n\nSample Output 1\n\n3\n\nAmong the integers between 5 and 10, there are three multiples of 2: 6, 8, and 10.\n\nSample Input 2\n\n6 20 7\n\nSample Output 2\n\n2\n\nAmong the integers between 6 and 20, there are two multiples of 7: 7 and 14.\n\nSample Input 3\n\n1 100 1\n\nSample Output 3\n\n100", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 423, "cpu_time_ms": 8, "memory_kb": 3608}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s606703743", "group_id": "codeNet:p02607", "input_text": "#include<bits/stdc++.h>\n#define ll long long\n#define ld long double\n#define ull unsigned long long\n#define mp make_pair\n#define pb(x) push_back(x)\n#define vi vector<int>\n#define vs vector<string>\n#define vll vector<long long>\n#define vc vector<char>\n#define vs vector<string>\n#define pii pair<int, int>\n#define pll pair<long long, long long>\n#define pil pair<int, long long>\n#define pli pair<long long, int>\n#define pcc pair<char, char>\n#define pdd pair<double, double>\n#define mll map<long long ,long long>\n#define gcd __gcd\nusing namespace std;\nint main()\n{\n\tll n;\n\tll a[100];\n\tll ct=0;\n\tcin>>n;\n\tfor(ll i=0;i<n;i++)\n\t{\n\t\tcin>>a[i];\n\t}\n\tfor(ll i=0; i<n;i++)\n\t{\n\t\tif((i+1)%2!=0 && (a[i]%2!=0))\n\t\t\tct++;\n\t}\n\tcout<<ct<<\"\\n\";\n}", "language": "C++", "metadata": {"date": 1594516170, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02607.html", "problem_id": "p02607", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02607/input.txt", "sample_output_relpath": "derived/input_output/data/p02607/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02607/C++/s606703743.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s606703743", "user_id": "u856436548"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include<bits/stdc++.h>\n#define ll long long\n#define ld long double\n#define ull unsigned long long\n#define mp make_pair\n#define pb(x) push_back(x)\n#define vi vector<int>\n#define vs vector<string>\n#define vll vector<long long>\n#define vc vector<char>\n#define vs vector<string>\n#define pii pair<int, int>\n#define pll pair<long long, long long>\n#define pil pair<int, long long>\n#define pli pair<long long, int>\n#define pcc pair<char, char>\n#define pdd pair<double, double>\n#define mll map<long long ,long long>\n#define gcd __gcd\nusing namespace std;\nint main()\n{\n\tll n;\n\tll a[100];\n\tll ct=0;\n\tcin>>n;\n\tfor(ll i=0;i<n;i++)\n\t{\n\t\tcin>>a[i];\n\t}\n\tfor(ll i=0; i<n;i++)\n\t{\n\t\tif((i+1)%2!=0 && (a[i]%2!=0))\n\t\t\tct++;\n\t}\n\tcout<<ct<<\"\\n\";\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nWe have N squares assigned the numbers 1,2,3,\\ldots,N. Each square has an integer written on it, and the integer written on Square i is a_i.\n\nHow many squares i satisfy both of the following conditions?\n\nThe assigned number, i, is odd.\n\nThe written integer is odd.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N, a_i \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 \\cdots a_N\n\nOutput\n\nPrint the number of squares that satisfy both of the conditions.\n\nSample Input 1\n\n5\n1 3 4 5 7\n\nSample Output 1\n\n2\n\nTwo squares, Square 1 and 5, satisfy both of the conditions.\n\nFor Square 2 and 4, the assigned numbers are not odd.\n\nFor Square 3, the written integer is not odd.\n\nSample Input 2\n\n15\n13 76 46 15 50 98 93 77 31 43 84 90 6 24 14\n\nSample Output 2\n\n3", "sample_input": "5\n1 3 4 5 7\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02607", "source_text": "Score : 200 points\n\nProblem Statement\n\nWe have N squares assigned the numbers 1,2,3,\\ldots,N. Each square has an integer written on it, and the integer written on Square i is a_i.\n\nHow many squares i satisfy both of the following conditions?\n\nThe assigned number, i, is odd.\n\nThe written integer is odd.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N, a_i \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 \\cdots a_N\n\nOutput\n\nPrint the number of squares that satisfy both of the conditions.\n\nSample Input 1\n\n5\n1 3 4 5 7\n\nSample Output 1\n\n2\n\nTwo squares, Square 1 and 5, satisfy both of the conditions.\n\nFor Square 2 and 4, the assigned numbers are not odd.\n\nFor Square 3, the written integer is not odd.\n\nSample Input 2\n\n15\n13 76 46 15 50 98 93 77 31 43 84 90 6 24 14\n\nSample Output 2\n\n3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 725, "cpu_time_ms": 6, "memory_kb": 3628}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s717178011", "group_id": "codeNet:p02607", "input_text": "#include <iostream>\nusing namespace std;\nint main()\n{\n    int cnt = 0, val, n;\n    cin >> n;\n    for (int i = 1; i <= n; i++)\n    {\n        cin >> val;\n        if ((i % 2) == 1 && (val % 2) == 1)\n            cnt++;\n    }\n    cout << cnt << endl;\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1594516139, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02607.html", "problem_id": "p02607", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02607/input.txt", "sample_output_relpath": "derived/input_output/data/p02607/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02607/C++/s717178011.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s717178011", "user_id": "u124676202"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <iostream>\nusing namespace std;\nint main()\n{\n    int cnt = 0, val, n;\n    cin >> n;\n    for (int i = 1; i <= n; i++)\n    {\n        cin >> val;\n        if ((i % 2) == 1 && (val % 2) == 1)\n            cnt++;\n    }\n    cout << cnt << endl;\n    return 0;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nWe have N squares assigned the numbers 1,2,3,\\ldots,N. Each square has an integer written on it, and the integer written on Square i is a_i.\n\nHow many squares i satisfy both of the following conditions?\n\nThe assigned number, i, is odd.\n\nThe written integer is odd.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N, a_i \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 \\cdots a_N\n\nOutput\n\nPrint the number of squares that satisfy both of the conditions.\n\nSample Input 1\n\n5\n1 3 4 5 7\n\nSample Output 1\n\n2\n\nTwo squares, Square 1 and 5, satisfy both of the conditions.\n\nFor Square 2 and 4, the assigned numbers are not odd.\n\nFor Square 3, the written integer is not odd.\n\nSample Input 2\n\n15\n13 76 46 15 50 98 93 77 31 43 84 90 6 24 14\n\nSample Output 2\n\n3", "sample_input": "5\n1 3 4 5 7\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02607", "source_text": "Score : 200 points\n\nProblem Statement\n\nWe have N squares assigned the numbers 1,2,3,\\ldots,N. Each square has an integer written on it, and the integer written on Square i is a_i.\n\nHow many squares i satisfy both of the following conditions?\n\nThe assigned number, i, is odd.\n\nThe written integer is odd.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N, a_i \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 \\cdots a_N\n\nOutput\n\nPrint the number of squares that satisfy both of the conditions.\n\nSample Input 1\n\n5\n1 3 4 5 7\n\nSample Output 1\n\n2\n\nTwo squares, Square 1 and 5, satisfy both of the conditions.\n\nFor Square 2 and 4, the assigned numbers are not odd.\n\nFor Square 3, the written integer is not odd.\n\nSample Input 2\n\n15\n13 76 46 15 50 98 93 77 31 43 84 90 6 24 14\n\nSample Output 2\n\n3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 262, "cpu_time_ms": 7, "memory_kb": 3588}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s500254213", "group_id": "codeNet:p02607", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n    int N;\n    cin >> N;\n    int ans = 0;\n    for (int i = 1; i <= N; i++) {\n        int A;\n        cin >> A;\n        if (i % 2 == 1 && A % 2 == 1) ans++;\n    }\n    cout << ans << endl;\n}", "language": "C++", "metadata": {"date": 1594515804, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02607.html", "problem_id": "p02607", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02607/input.txt", "sample_output_relpath": "derived/input_output/data/p02607/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02607/C++/s500254213.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s500254213", "user_id": "u658901072"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n    int N;\n    cin >> N;\n    int ans = 0;\n    for (int i = 1; i <= N; i++) {\n        int A;\n        cin >> A;\n        if (i % 2 == 1 && A % 2 == 1) ans++;\n    }\n    cout << ans << endl;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nWe have N squares assigned the numbers 1,2,3,\\ldots,N. Each square has an integer written on it, and the integer written on Square i is a_i.\n\nHow many squares i satisfy both of the following conditions?\n\nThe assigned number, i, is odd.\n\nThe written integer is odd.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N, a_i \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 \\cdots a_N\n\nOutput\n\nPrint the number of squares that satisfy both of the conditions.\n\nSample Input 1\n\n5\n1 3 4 5 7\n\nSample Output 1\n\n2\n\nTwo squares, Square 1 and 5, satisfy both of the conditions.\n\nFor Square 2 and 4, the assigned numbers are not odd.\n\nFor Square 3, the written integer is not odd.\n\nSample Input 2\n\n15\n13 76 46 15 50 98 93 77 31 43 84 90 6 24 14\n\nSample Output 2\n\n3", "sample_input": "5\n1 3 4 5 7\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02607", "source_text": "Score : 200 points\n\nProblem Statement\n\nWe have N squares assigned the numbers 1,2,3,\\ldots,N. Each square has an integer written on it, and the integer written on Square i is a_i.\n\nHow many squares i satisfy both of the following conditions?\n\nThe assigned number, i, is odd.\n\nThe written integer is odd.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N, a_i \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 \\cdots a_N\n\nOutput\n\nPrint the number of squares that satisfy both of the conditions.\n\nSample Input 1\n\n5\n1 3 4 5 7\n\nSample Output 1\n\n2\n\nTwo squares, Square 1 and 5, satisfy both of the conditions.\n\nFor Square 2 and 4, the assigned numbers are not odd.\n\nFor Square 3, the written integer is not odd.\n\nSample Input 2\n\n15\n13 76 46 15 50 98 93 77 31 43 84 90 6 24 14\n\nSample Output 2\n\n3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 247, "cpu_time_ms": 7, "memory_kb": 3592}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s337381529", "group_id": "codeNet:p02608", "input_text": "#include <iostream>\n\nusing namespace std;\n\nint main()\n{\n    int n;\n    cin>>n;\n    int arr[10001] = {0};\n    int m =  min(n,99);\n    for(int i = 1 ; i <= m ; i++)\n    {\n        for(int j = 1 ; j <= m ;j++)\n        {\n            for(int z = 1 ; z <= m ;z++)\n            {\n                if(i*i+j*j+z*z+i*j+i*z+j*z <= 10000)\n                    arr[i*i+j*j+z*z+i*j+i*z+j*z]++;\n            }\n        }\n    }\n    for(int  i = 1 ; i <= n ; i++)\n    {\n        cout<<arr[i]<<endl;\n    }\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1597990092, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02608.html", "problem_id": "p02608", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02608/input.txt", "sample_output_relpath": "derived/input_output/data/p02608/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02608/C++/s337381529.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s337381529", "user_id": "u353919145"}, "prompt_components": {"gold_output": "0\n0\n0\n0\n0\n1\n0\n0\n0\n0\n3\n0\n0\n0\n0\n0\n3\n3\n0\n0\n", "input_to_evaluate": "#include <iostream>\n\nusing namespace std;\n\nint main()\n{\n    int n;\n    cin>>n;\n    int arr[10001] = {0};\n    int m =  min(n,99);\n    for(int i = 1 ; i <= m ; i++)\n    {\n        for(int j = 1 ; j <= m ;j++)\n        {\n            for(int z = 1 ; z <= m ;z++)\n            {\n                if(i*i+j*j+z*z+i*j+i*z+j*z <= 10000)\n                    arr[i*i+j*j+z*z+i*j+i*z+j*z]++;\n            }\n        }\n    }\n    for(int  i = 1 ; i <= n ; i++)\n    {\n        cout<<arr[i]<<endl;\n    }\n    return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nLet f(n) be the number of triples of integers (x,y,z) that satisfy both of the following conditions:\n\n1 \\leq x,y,z\n\nx^2 + y^2 + z^2 + xy + yz + zx = n\n\nGiven an integer N, find each of f(1),f(2),f(3),\\ldots,f(N).\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^4\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint N lines. The i-th line should contain the value f(i).\n\nSample Input 1\n\n20\n\nSample Output 1\n\n0\n0\n0\n0\n0\n1\n0\n0\n0\n0\n3\n0\n0\n0\n0\n0\n3\n3\n0\n0\n\nFor n=6, only (1,1,1) satisfies both of the conditions. Thus, f(6) = 1.\n\nFor n=11, three triples, (1,1,2), (1,2,1), and (2,1,1), satisfy both of the conditions. Thus, f(6) = 3.\n\nFor n=17, three triples, (1,2,2), (2,1,2), and (2,2,1), satisfy both of the conditions. Thus, f(17) = 3.\n\nFor n=18, three triples, (1,1,3), (1,3,1), and (3,1,1), satisfy both of the conditions. Thus, f(18) = 3.", "sample_input": "20\n"}, "reference_outputs": ["0\n0\n0\n0\n0\n1\n0\n0\n0\n0\n3\n0\n0\n0\n0\n0\n3\n3\n0\n0\n"], "source_document_id": "p02608", "source_text": "Score : 300 points\n\nProblem Statement\n\nLet f(n) be the number of triples of integers (x,y,z) that satisfy both of the following conditions:\n\n1 \\leq x,y,z\n\nx^2 + y^2 + z^2 + xy + yz + zx = n\n\nGiven an integer N, find each of f(1),f(2),f(3),\\ldots,f(N).\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^4\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint N lines. The i-th line should contain the value f(i).\n\nSample Input 1\n\n20\n\nSample Output 1\n\n0\n0\n0\n0\n0\n1\n0\n0\n0\n0\n3\n0\n0\n0\n0\n0\n3\n3\n0\n0\n\nFor n=6, only (1,1,1) satisfies both of the conditions. Thus, f(6) = 1.\n\nFor n=11, three triples, (1,1,2), (1,2,1), and (2,1,1), satisfy both of the conditions. Thus, f(6) = 3.\n\nFor n=17, three triples, (1,2,2), (2,1,2), and (2,2,1), satisfy both of the conditions. Thus, f(17) = 3.\n\nFor n=18, three triples, (1,1,3), (1,3,1), and (3,1,1), satisfy both of the conditions. Thus, f(18) = 3.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 497, "cpu_time_ms": 23, "memory_kb": 3592}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s807119466", "group_id": "codeNet:p02608", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n\nint func(int A){\n  int count=0;\n  for(int i=1;i<55;i++){\n    for(int j=1;j<55;j++){\n      for(int k=1;k<55;k++){\n        int B=i*i+j*j+k*k+i*j+j*k+k*i;\n        if(A==B){\n          count++;\n        }\n      }\n    }\n  }\n  return count;\n}\n    \nint main(){\n  int N;\n  cin >> N;\n  for(int i=0;i<N;i++){\n    cout << func(i+1) << endl;\n  }\n}\n  ", "language": "C++", "metadata": {"date": 1594518989, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02608.html", "problem_id": "p02608", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02608/input.txt", "sample_output_relpath": "derived/input_output/data/p02608/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02608/C++/s807119466.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s807119466", "user_id": "u280966279"}, "prompt_components": {"gold_output": "0\n0\n0\n0\n0\n1\n0\n0\n0\n0\n3\n0\n0\n0\n0\n0\n3\n3\n0\n0\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n\nint func(int A){\n  int count=0;\n  for(int i=1;i<55;i++){\n    for(int j=1;j<55;j++){\n      for(int k=1;k<55;k++){\n        int B=i*i+j*j+k*k+i*j+j*k+k*i;\n        if(A==B){\n          count++;\n        }\n      }\n    }\n  }\n  return count;\n}\n    \nint main(){\n  int N;\n  cin >> N;\n  for(int i=0;i<N;i++){\n    cout << func(i+1) << endl;\n  }\n}\n  ", "problem_context": "Score : 300 points\n\nProblem Statement\n\nLet f(n) be the number of triples of integers (x,y,z) that satisfy both of the following conditions:\n\n1 \\leq x,y,z\n\nx^2 + y^2 + z^2 + xy + yz + zx = n\n\nGiven an integer N, find each of f(1),f(2),f(3),\\ldots,f(N).\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^4\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint N lines. The i-th line should contain the value f(i).\n\nSample Input 1\n\n20\n\nSample Output 1\n\n0\n0\n0\n0\n0\n1\n0\n0\n0\n0\n3\n0\n0\n0\n0\n0\n3\n3\n0\n0\n\nFor n=6, only (1,1,1) satisfies both of the conditions. Thus, f(6) = 1.\n\nFor n=11, three triples, (1,1,2), (1,2,1), and (2,1,1), satisfy both of the conditions. Thus, f(6) = 3.\n\nFor n=17, three triples, (1,2,2), (2,1,2), and (2,2,1), satisfy both of the conditions. Thus, f(17) = 3.\n\nFor n=18, three triples, (1,1,3), (1,3,1), and (3,1,1), satisfy both of the conditions. Thus, f(18) = 3.", "sample_input": "20\n"}, "reference_outputs": ["0\n0\n0\n0\n0\n1\n0\n0\n0\n0\n3\n0\n0\n0\n0\n0\n3\n3\n0\n0\n"], "source_document_id": "p02608", "source_text": "Score : 300 points\n\nProblem Statement\n\nLet f(n) be the number of triples of integers (x,y,z) that satisfy both of the following conditions:\n\n1 \\leq x,y,z\n\nx^2 + y^2 + z^2 + xy + yz + zx = n\n\nGiven an integer N, find each of f(1),f(2),f(3),\\ldots,f(N).\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^4\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint N lines. The i-th line should contain the value f(i).\n\nSample Input 1\n\n20\n\nSample Output 1\n\n0\n0\n0\n0\n0\n1\n0\n0\n0\n0\n3\n0\n0\n0\n0\n0\n3\n3\n0\n0\n\nFor n=6, only (1,1,1) satisfies both of the conditions. Thus, f(6) = 1.\n\nFor n=11, three triples, (1,1,2), (1,2,1), and (2,1,1), satisfy both of the conditions. Thus, f(6) = 3.\n\nFor n=17, three triples, (1,2,2), (2,1,2), and (2,2,1), satisfy both of the conditions. Thus, f(17) = 3.\n\nFor n=18, three triples, (1,1,3), (1,3,1), and (3,1,1), satisfy both of the conditions. Thus, f(18) = 3.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 382, "cpu_time_ms": 1899, "memory_kb": 3544}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s414817745", "group_id": "codeNet:p02608", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n    long long int n,m,i,j,k,l,p,b,t;\n    cin>>n;\n    t=0;\n    for(i=1; i<=n; i++)\n    {\n        p = sqrt(i/2);\n        t=0;\n        for(j=1; j<=p; j++)\n        {\n            for(k=1; k<=p; k++)\n            {\n                for(l=1; l<=p; l++)\n                {\n                    b = j*j+k*k+l*l+j*k+k*l+j*l;\n                    if(b==i)\n                    {\n                        t++;\n                        break;\n                    }\n                }\n            }\n        }\n        cout<<t<<endl;\n    }\n}\n", "language": "C++", "metadata": {"date": 1594518483, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02608.html", "problem_id": "p02608", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02608/input.txt", "sample_output_relpath": "derived/input_output/data/p02608/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02608/C++/s414817745.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s414817745", "user_id": "u085746830"}, "prompt_components": {"gold_output": "0\n0\n0\n0\n0\n1\n0\n0\n0\n0\n3\n0\n0\n0\n0\n0\n3\n3\n0\n0\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n    long long int n,m,i,j,k,l,p,b,t;\n    cin>>n;\n    t=0;\n    for(i=1; i<=n; i++)\n    {\n        p = sqrt(i/2);\n        t=0;\n        for(j=1; j<=p; j++)\n        {\n            for(k=1; k<=p; k++)\n            {\n                for(l=1; l<=p; l++)\n                {\n                    b = j*j+k*k+l*l+j*k+k*l+j*l;\n                    if(b==i)\n                    {\n                        t++;\n                        break;\n                    }\n                }\n            }\n        }\n        cout<<t<<endl;\n    }\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nLet f(n) be the number of triples of integers (x,y,z) that satisfy both of the following conditions:\n\n1 \\leq x,y,z\n\nx^2 + y^2 + z^2 + xy + yz + zx = n\n\nGiven an integer N, find each of f(1),f(2),f(3),\\ldots,f(N).\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^4\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint N lines. The i-th line should contain the value f(i).\n\nSample Input 1\n\n20\n\nSample Output 1\n\n0\n0\n0\n0\n0\n1\n0\n0\n0\n0\n3\n0\n0\n0\n0\n0\n3\n3\n0\n0\n\nFor n=6, only (1,1,1) satisfies both of the conditions. Thus, f(6) = 1.\n\nFor n=11, three triples, (1,1,2), (1,2,1), and (2,1,1), satisfy both of the conditions. Thus, f(6) = 3.\n\nFor n=17, three triples, (1,2,2), (2,1,2), and (2,2,1), satisfy both of the conditions. Thus, f(17) = 3.\n\nFor n=18, three triples, (1,1,3), (1,3,1), and (3,1,1), satisfy both of the conditions. Thus, f(18) = 3.", "sample_input": "20\n"}, "reference_outputs": ["0\n0\n0\n0\n0\n1\n0\n0\n0\n0\n3\n0\n0\n0\n0\n0\n3\n3\n0\n0\n"], "source_document_id": "p02608", "source_text": "Score : 300 points\n\nProblem Statement\n\nLet f(n) be the number of triples of integers (x,y,z) that satisfy both of the following conditions:\n\n1 \\leq x,y,z\n\nx^2 + y^2 + z^2 + xy + yz + zx = n\n\nGiven an integer N, find each of f(1),f(2),f(3),\\ldots,f(N).\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^4\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint N lines. The i-th line should contain the value f(i).\n\nSample Input 1\n\n20\n\nSample Output 1\n\n0\n0\n0\n0\n0\n1\n0\n0\n0\n0\n3\n0\n0\n0\n0\n0\n3\n3\n0\n0\n\nFor n=6, only (1,1,1) satisfies both of the conditions. Thus, f(6) = 1.\n\nFor n=11, three triples, (1,1,2), (1,2,1), and (2,1,1), satisfy both of the conditions. Thus, f(6) = 3.\n\nFor n=17, three triples, (1,2,2), (2,1,2), and (2,2,1), satisfy both of the conditions. Thus, f(17) = 3.\n\nFor n=18, three triples, (1,1,3), (1,3,1), and (3,1,1), satisfy both of the conditions. Thus, f(18) = 3.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 575, "cpu_time_ms": 1373, "memory_kb": 3500}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s554866027", "group_id": "codeNet:p02608", "input_text": "#pragma region Headers\n#ifndef _GLIBCXX_NO_ASSERT\n#include <cassert>\n#endif\n#include <cctype>\n#include <cerrno>\n#include <cfloat>\n#include <ciso646>\n#include <climits>\n#include <clocale>\n#include <cmath>\n#include <csetjmp>\n#include <csignal>\n#include <cstdarg>\n#include <cstddef>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <ctime>\n#include <cwchar>\n#include <cwctype>\n\n// C++\n#include <algorithm>\n#include <bitset>\n#include <complex>\n#include <deque>\n#include <exception>\n#include <fstream>\n#include <functional>\n#include <iomanip>\n#include <ios>\n#include <iosfwd>\n#include <iostream>\n#include <istream>\n#include <iterator>\n#include <limits>\n#include <list>\n#include <locale>\n#include <map>\n#include <memory>\n#include <new>\n#include <numeric>\n#include <ostream>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <stack>\n#include <stdexcept>\n#include <streambuf>\n#include <string>\n#include <typeinfo>\n#include <utility>\n#include <valarray>\n#include <vector>\n\n#if __cplusplus >= 201103L\n#include <array>\n#include <atomic>\n#include <chrono>\n#include <codecvt>\n#include <condition_variable>\n#include <forward_list>\n#include <future>\n#include <initializer_list>\n#include <mutex>\n#include <random>\n#include <ratio>\n#include <regex>\n#include <scoped_allocator>\n#include <system_error>\n#include <thread>\n#include <tuple>\n#include <typeindex>\n#include <type_traits>\n#include <unordered_map>\n#include <unordered_set>\n#endif\n#pragma endregion\n\nusing namespace std;\n#pragma region Macros\n#define CHOOSE(a) CHOOSE2 a\n#define CHOOSE2(a0, a1, a2, a3, a4, x, ...) x\n#define debug_1(x1) cout << #x1 << \": \" << x1 << endl\n#define debug_2(x1, x2) cout << #x1 << \": \" << x1 << \", \" #x2 << \": \" << x2 << endl\n#define debug_3(x1, x2, x3) cout << #x1 << \": \" << x1 << \", \" #x2 << \": \" << x2 << \", \" #x3 << \": \" << x3 << endl\n#define debug_4(x1, x2, x3, x4) cout << #x1 << \": \" << x1 << \", \" #x2 << \": \" << x2 << \", \" #x3 << \": \" << x3 << \", \" #x4 << \": \" << x4 << endl\n#define debug_5(x1, x2, x3, x4, x5) cout << #x1 << \": \" << x1 << \", \" #x2 << \": \" << x2 << \", \" #x3 << \": \" << x3 << \", \" #x4 << \": \" << x4 << \", \" #x5 << \": \" << x5 << endl\n#ifdef _DEBUG\n#define debug(...)                                                      \\\n  CHOOSE((__VA_ARGS__, debug_5, debug_4, debug_3, debug_2, debug_1, ~)) \\\n  (__VA_ARGS__)\n#else\n#define debug(...)\n#endif\n#pragma region end\n\n#pragma region Libraries\ntemplate <typename T>\nstring to_string(T o)\n{\n  stringstream s;\n  s << o;\n  return s.str();\n}\n\ntemplate <typename T>\nstring to_string(vector<T> v)\n{\n  stringstream s;\n  s << \"[\";\n  for (auto i = 0; i < v.size(); i++)\n  {\n    s << to_string(v.at(i));\n    if (i != v.size() - 1)\n    {\n      s << \", \";\n    }\n  }\n  s << \"]\";\n  return s.str();\n}\n\ntemplate <typename T>\nostream &operator<<(ostream &o, const vector<T> &obj)\n{\n  o << to_string(obj);\n  return o;\n}\n\ntemplate <typename T>\nstring to_string(vector<vector<T>> m)\n{\n  stringstream s;\n  s << \"[\" << endl;\n  for (auto i = 0; i < m.size(); i++)\n  {\n    auto v = m[i];\n    s << \"  \"\n      << \"#\" << i << \":\"\n      << \" \" << to_string(v);\n    s << \", \" << endl;\n  }\n  s << \"]\";\n  return s.str();\n}\n\ntemplate <typename T>\nostream &operator<<(ostream &o, const vector<vector<T>> &obj)\n{\n  o << to_string(obj);\n  return o;\n}\n\ntemplate <typename K, typename V>\nstring to_string(pair<K, V> p)\n{\n  stringstream s;\n  s << \"pair(\" << to_string(p.first) << \", \" << to_string(p.second) << \")\";\n  return s.str();\n}\n\ntemplate <typename K, typename V>\nostream &operator<<(ostream &o, const pair<K, V> &obj)\n{\n  o << to_string(obj);\n  return o;\n}\n\ntemplate <typename K, typename V>\nstring to_string(map<K, V> m)\n{\n  stringstream s;\n  s << \"{\" << endl;\n  for (const auto &p : m)\n  {\n    s << \"  \" << to_string(p.first) << \": \" << to_string(p.second) << \",\" << endl;\n  }\n  s << \"}\";\n  return s.str();\n}\n\ntemplate <typename K, typename V>\nostream &operator<<(ostream &o, const map<K, V> &obj)\n{\n  o << to_string(obj);\n  return o;\n}\n\ntemplate <typename T>\nstring to_string(set<T> ss)\n{\n  stringstream s;\n  s << \"set\"\n    << \"{\";\n  for (auto itr = ss.begin(); itr != ss.end(); itr++)\n  {\n    s << to_string(*itr);\n    if (next(itr, 1) != ss.end())\n    {\n      s << \", \";\n    }\n  }\n  s << \"}\";\n  return s.str();\n}\n\ntemplate <typename T>\nostream &operator<<(ostream &o, const set<T> &obj)\n{\n  o << to_string(obj);\n  return o;\n}\n\ntemplate <typename T>\nstring to_string(queue<T> q)\n{\n  auto temp = queue<T>{};\n  stringstream s;\n  s << \"queue{\";\n  while (!q.empty())\n  {\n    auto top = q.front();\n    s << to_string(top) << \", \";\n    q.pop();\n    temp.push(top);\n  }\n  s << \"}\";\n\n  while (!temp.empty())\n  {\n    auto top = temp.front();\n    temp.pop();\n    q.push(top);\n  }\n\n  return s.str();\n}\n\ntemplate <typename T>\nostream &operator<<(ostream &o, const queue<T> &obj)\n{\n  o << to_string(obj);\n  return o;\n}\n#pragma endregion\n\ntypedef long long ll;\n\nint main()\n{\n  cin.tie(0);\n  ios::sync_with_stdio(false);\n  std::cout << std::setprecision(20);\n\n  ll n;\n  cin >> n;\n  map<ll, ll> cnt;\n\n  for (int x = 1; x <= 100; x++)\n  {\n    for (int y = 1; y <= 100; y++)\n    {\n      for (int z = 1; z <= 100; z++)\n      {\n        ll val = x * x + y * y + z * z + x * y + y * z + z * x;\n        if (val >= 1 && val <= 10000)\n        {\n          cnt[val]++;\n        }\n      }\n    }\n  }\n\n  for (auto i = 1; i <= n; i++)\n  {\n    cout << cnt[i] << endl;\n  }\n\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1594517436, "filename_ext": "cpp", "original_language": "C++ (Clang 10.0.0)", "problem_description_relpath": "problem_descriptions/p02608.html", "problem_id": "p02608", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02608/input.txt", "sample_output_relpath": "derived/input_output/data/p02608/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02608/C++/s554866027.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s554866027", "user_id": "u734834944"}, "prompt_components": {"gold_output": "0\n0\n0\n0\n0\n1\n0\n0\n0\n0\n3\n0\n0\n0\n0\n0\n3\n3\n0\n0\n", "input_to_evaluate": "#pragma region Headers\n#ifndef _GLIBCXX_NO_ASSERT\n#include <cassert>\n#endif\n#include <cctype>\n#include <cerrno>\n#include <cfloat>\n#include <ciso646>\n#include <climits>\n#include <clocale>\n#include <cmath>\n#include <csetjmp>\n#include <csignal>\n#include <cstdarg>\n#include <cstddef>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <ctime>\n#include <cwchar>\n#include <cwctype>\n\n// C++\n#include <algorithm>\n#include <bitset>\n#include <complex>\n#include <deque>\n#include <exception>\n#include <fstream>\n#include <functional>\n#include <iomanip>\n#include <ios>\n#include <iosfwd>\n#include <iostream>\n#include <istream>\n#include <iterator>\n#include <limits>\n#include <list>\n#include <locale>\n#include <map>\n#include <memory>\n#include <new>\n#include <numeric>\n#include <ostream>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <stack>\n#include <stdexcept>\n#include <streambuf>\n#include <string>\n#include <typeinfo>\n#include <utility>\n#include <valarray>\n#include <vector>\n\n#if __cplusplus >= 201103L\n#include <array>\n#include <atomic>\n#include <chrono>\n#include <codecvt>\n#include <condition_variable>\n#include <forward_list>\n#include <future>\n#include <initializer_list>\n#include <mutex>\n#include <random>\n#include <ratio>\n#include <regex>\n#include <scoped_allocator>\n#include <system_error>\n#include <thread>\n#include <tuple>\n#include <typeindex>\n#include <type_traits>\n#include <unordered_map>\n#include <unordered_set>\n#endif\n#pragma endregion\n\nusing namespace std;\n#pragma region Macros\n#define CHOOSE(a) CHOOSE2 a\n#define CHOOSE2(a0, a1, a2, a3, a4, x, ...) x\n#define debug_1(x1) cout << #x1 << \": \" << x1 << endl\n#define debug_2(x1, x2) cout << #x1 << \": \" << x1 << \", \" #x2 << \": \" << x2 << endl\n#define debug_3(x1, x2, x3) cout << #x1 << \": \" << x1 << \", \" #x2 << \": \" << x2 << \", \" #x3 << \": \" << x3 << endl\n#define debug_4(x1, x2, x3, x4) cout << #x1 << \": \" << x1 << \", \" #x2 << \": \" << x2 << \", \" #x3 << \": \" << x3 << \", \" #x4 << \": \" << x4 << endl\n#define debug_5(x1, x2, x3, x4, x5) cout << #x1 << \": \" << x1 << \", \" #x2 << \": \" << x2 << \", \" #x3 << \": \" << x3 << \", \" #x4 << \": \" << x4 << \", \" #x5 << \": \" << x5 << endl\n#ifdef _DEBUG\n#define debug(...)                                                      \\\n  CHOOSE((__VA_ARGS__, debug_5, debug_4, debug_3, debug_2, debug_1, ~)) \\\n  (__VA_ARGS__)\n#else\n#define debug(...)\n#endif\n#pragma region end\n\n#pragma region Libraries\ntemplate <typename T>\nstring to_string(T o)\n{\n  stringstream s;\n  s << o;\n  return s.str();\n}\n\ntemplate <typename T>\nstring to_string(vector<T> v)\n{\n  stringstream s;\n  s << \"[\";\n  for (auto i = 0; i < v.size(); i++)\n  {\n    s << to_string(v.at(i));\n    if (i != v.size() - 1)\n    {\n      s << \", \";\n    }\n  }\n  s << \"]\";\n  return s.str();\n}\n\ntemplate <typename T>\nostream &operator<<(ostream &o, const vector<T> &obj)\n{\n  o << to_string(obj);\n  return o;\n}\n\ntemplate <typename T>\nstring to_string(vector<vector<T>> m)\n{\n  stringstream s;\n  s << \"[\" << endl;\n  for (auto i = 0; i < m.size(); i++)\n  {\n    auto v = m[i];\n    s << \"  \"\n      << \"#\" << i << \":\"\n      << \" \" << to_string(v);\n    s << \", \" << endl;\n  }\n  s << \"]\";\n  return s.str();\n}\n\ntemplate <typename T>\nostream &operator<<(ostream &o, const vector<vector<T>> &obj)\n{\n  o << to_string(obj);\n  return o;\n}\n\ntemplate <typename K, typename V>\nstring to_string(pair<K, V> p)\n{\n  stringstream s;\n  s << \"pair(\" << to_string(p.first) << \", \" << to_string(p.second) << \")\";\n  return s.str();\n}\n\ntemplate <typename K, typename V>\nostream &operator<<(ostream &o, const pair<K, V> &obj)\n{\n  o << to_string(obj);\n  return o;\n}\n\ntemplate <typename K, typename V>\nstring to_string(map<K, V> m)\n{\n  stringstream s;\n  s << \"{\" << endl;\n  for (const auto &p : m)\n  {\n    s << \"  \" << to_string(p.first) << \": \" << to_string(p.second) << \",\" << endl;\n  }\n  s << \"}\";\n  return s.str();\n}\n\ntemplate <typename K, typename V>\nostream &operator<<(ostream &o, const map<K, V> &obj)\n{\n  o << to_string(obj);\n  return o;\n}\n\ntemplate <typename T>\nstring to_string(set<T> ss)\n{\n  stringstream s;\n  s << \"set\"\n    << \"{\";\n  for (auto itr = ss.begin(); itr != ss.end(); itr++)\n  {\n    s << to_string(*itr);\n    if (next(itr, 1) != ss.end())\n    {\n      s << \", \";\n    }\n  }\n  s << \"}\";\n  return s.str();\n}\n\ntemplate <typename T>\nostream &operator<<(ostream &o, const set<T> &obj)\n{\n  o << to_string(obj);\n  return o;\n}\n\ntemplate <typename T>\nstring to_string(queue<T> q)\n{\n  auto temp = queue<T>{};\n  stringstream s;\n  s << \"queue{\";\n  while (!q.empty())\n  {\n    auto top = q.front();\n    s << to_string(top) << \", \";\n    q.pop();\n    temp.push(top);\n  }\n  s << \"}\";\n\n  while (!temp.empty())\n  {\n    auto top = temp.front();\n    temp.pop();\n    q.push(top);\n  }\n\n  return s.str();\n}\n\ntemplate <typename T>\nostream &operator<<(ostream &o, const queue<T> &obj)\n{\n  o << to_string(obj);\n  return o;\n}\n#pragma endregion\n\ntypedef long long ll;\n\nint main()\n{\n  cin.tie(0);\n  ios::sync_with_stdio(false);\n  std::cout << std::setprecision(20);\n\n  ll n;\n  cin >> n;\n  map<ll, ll> cnt;\n\n  for (int x = 1; x <= 100; x++)\n  {\n    for (int y = 1; y <= 100; y++)\n    {\n      for (int z = 1; z <= 100; z++)\n      {\n        ll val = x * x + y * y + z * z + x * y + y * z + z * x;\n        if (val >= 1 && val <= 10000)\n        {\n          cnt[val]++;\n        }\n      }\n    }\n  }\n\n  for (auto i = 1; i <= n; i++)\n  {\n    cout << cnt[i] << endl;\n  }\n\n  return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nLet f(n) be the number of triples of integers (x,y,z) that satisfy both of the following conditions:\n\n1 \\leq x,y,z\n\nx^2 + y^2 + z^2 + xy + yz + zx = n\n\nGiven an integer N, find each of f(1),f(2),f(3),\\ldots,f(N).\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^4\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint N lines. The i-th line should contain the value f(i).\n\nSample Input 1\n\n20\n\nSample Output 1\n\n0\n0\n0\n0\n0\n1\n0\n0\n0\n0\n3\n0\n0\n0\n0\n0\n3\n3\n0\n0\n\nFor n=6, only (1,1,1) satisfies both of the conditions. Thus, f(6) = 1.\n\nFor n=11, three triples, (1,1,2), (1,2,1), and (2,1,1), satisfy both of the conditions. Thus, f(6) = 3.\n\nFor n=17, three triples, (1,2,2), (2,1,2), and (2,2,1), satisfy both of the conditions. Thus, f(17) = 3.\n\nFor n=18, three triples, (1,1,3), (1,3,1), and (3,1,1), satisfy both of the conditions. Thus, f(18) = 3.", "sample_input": "20\n"}, "reference_outputs": ["0\n0\n0\n0\n0\n1\n0\n0\n0\n0\n3\n0\n0\n0\n0\n0\n3\n3\n0\n0\n"], "source_document_id": "p02608", "source_text": "Score : 300 points\n\nProblem Statement\n\nLet f(n) be the number of triples of integers (x,y,z) that satisfy both of the following conditions:\n\n1 \\leq x,y,z\n\nx^2 + y^2 + z^2 + xy + yz + zx = n\n\nGiven an integer N, find each of f(1),f(2),f(3),\\ldots,f(N).\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^4\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint N lines. The i-th line should contain the value f(i).\n\nSample Input 1\n\n20\n\nSample Output 1\n\n0\n0\n0\n0\n0\n1\n0\n0\n0\n0\n3\n0\n0\n0\n0\n0\n3\n3\n0\n0\n\nFor n=6, only (1,1,1) satisfies both of the conditions. Thus, f(6) = 1.\n\nFor n=11, three triples, (1,1,2), (1,2,1), and (2,1,1), satisfy both of the conditions. Thus, f(6) = 3.\n\nFor n=17, three triples, (1,2,2), (2,1,2), and (2,2,1), satisfy both of the conditions. Thus, f(17) = 3.\n\nFor n=18, three triples, (1,1,3), (1,3,1), and (3,1,1), satisfy both of the conditions. Thus, f(18) = 3.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 5391, "cpu_time_ms": 58, "memory_kb": 3764}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s115318534", "group_id": "codeNet:p02609", "input_text": "#include \"bits/stdc++.h\"\n\n#define MOD 1000000007\n#define rep(i, n) for(ll i=0; i < (n); i++)\n#define rrep(i, n) for(ll i=(n)-1; i >=0; i--)\n#define ALL(v) v.begin(),v.end()\n#define rALL(v) v.rbegin(),v.rend()\n#define FOR(i, j, k) for(ll i=j;i<k;i++)\n#define debug_print(var) cerr << #var << \"=\" << var <<endl;\n#define DUMP(i, v)for(ll i=0;i<v.size();i++)cerr<<v[i]<<\" \"\n\nusing namespace std;\ntypedef long long int ll;\ntypedef vector<ll> llvec;\ntypedef vector<double> dvec;\ntypedef pair<ll, ll> P;\ntypedef long double ld;\nstruct edge{ll x, c;};\n\nll mod(ll a, ll mod){\n  ll res = a%mod;\n  while(res<0){\n    res=res + mod;\n  }\n  return res;\n}\n\nll modpow(ll a, ll n, ll mod){\n  ll res=1;\n  while(n>0){\n    if(n&1) res=res*a%mod;\n    a=a*a%mod;\n    n>>=1;\n  }\n  return res;\n}\n\nll modinv(ll a, ll mod){\n  return modpow(a, mod-2, mod);\n}\n\nll gcd(ll a, ll b){\n  ll r = a%b;\n  if(r==0) return b;\n  else return gcd(b, a%b);\n}\n\nbool is_prime(ll n){\n  ll i = 2;\n  if(n==1)return false;\n  if(n==2)return true;\n  bool res = true;\n  while(i*i <n){\n    if(n%i==0){\n      res = false;\n    }\n    i = i+1;\n  }\n\n  //if(i==1)res = false;\n  if(n%i==0)res=false;\n  return res;\n}\n\nstruct UnionFind{\n  ll N;\n  llvec p;\n  llvec cnt;\n  UnionFind(ll n){\n    N = n;\n    p=llvec(N);\n    cnt=llvec(N, 0);\n    rep(i, N){\n      p[i] = i;\n      cnt[i] = 1;\n    }\n  }\n\n  void con(ll a, ll b){\n    P at = root(a);\n    P bt = root(b);\n    if(at.second!=bt.second){\n      if(at.first>bt.first){\n        swap(at, bt);\n        swap(a, b);\n      }\n      p[at.second] = bt.second;\n      cnt[bt.second]+=cnt[at.second];\n      p[a]=bt.second;\n    }\n  }\n\n  P root(ll a){\n    ll atmp = a;\n    ll c=0;\n    while(atmp!=p[atmp]){\n      atmp = p[atmp];\n      c++;\n    }\n    p[a] = atmp;\n    return {c, atmp};\n  }\n\n  bool is_con(ll a, ll b){\n    P at=root(a);\n    P bt=root(b);\n    return at.second == bt.second;\n  }\n  \n};\n\nstruct dijkstra{\n  ll N;\n  llvec d;\n  vector<vector<edge>> e;\n  dijkstra(ll n){\n    N = n;\n    //d = llvec(N, 1e18);\n    e = vector<vector<edge>>(N);\n  }\n\n  void add_edge(ll from, ll to, ll cost){\n    e[from].push_back({to, cost});\n  }\n\n  void run(ll start){\n    priority_queue<P, vector<P>, greater<P>> que;\n    que.push({0, start});\n    d = llvec(N, 1e18);\n    d[start]=0;\n    while(!que.empty()){\n      P q = que.top();que.pop();\n      ll dc = q.first;\n      ll x = q.second;\n      if(dc>d[x]){\n        continue;\n      }else{\n        for(auto ip: e[x]){\n          if(d[ip.x]<=d[x]+ip.c){\n            continue;\n          }else{\n            d[ip.x]= d[x]+ip.c;\n            que.push({d[ip.x], ip.x});\n          }\n        }\n      }\n    }\n  }  \n};\n\nll dp[5000000];\nll func2(ll n, ll s){\n  if(n==0)return s;\n  ll cnt = 0;\n  rep(i, 20){\n    if(n>>i&1)cnt++;\n  }\n  ll ans = 0;\n  rep(i, 20){\n    if(n>>i&1){\n      ans = mod(ans + modpow(2, i, cnt), cnt);\n    }\n  }\n  return func2(ans, s+1);\n}\n\n\n/**************************************\n** A main function starts from here  **\n***************************************/\nint main(){\n  ll N;\n  cin >> N;\n  string X;\n  cin >> X;\n  ll cnt=0;\n  rep(i, N){\n    if(X[i]=='1')cnt++;\n  }\n  ll cnt_m1=0;\n  ll cnt_p1=0;\n  rep(i, N){\n    if(X[i]=='1'){\n      if(cnt>0)cnt_m1 = mod(cnt_m1+modpow(2, N-i-1, cnt-1), cnt-1);\n      cnt_p1 = mod(cnt_p1+modpow(2, N-i-1, cnt+1), cnt+1);\n    }\n  }\n  /*\n  rep(i, N+1){\n    dp[i] = func2(i, 0);\n  }\n  */\n  rep(i, N){\n    if(X[i]=='0'){\n      ll tmp = mod(cnt_p1+modpow(2, N-i-1, cnt+1), cnt+1);\n      cout << func2(tmp, 1)<<endl;\n    }else{\n      ll tmp = mod(cnt_m1-modpow(2, N-i-1, cnt-1), cnt-1);\n      tmp = mod(tmp, cnt-1);\n      cout << func2(tmp, 1)<<endl;\n    }\n  }\n  \n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1594521514, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02609.html", "problem_id": "p02609", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02609/input.txt", "sample_output_relpath": "derived/input_output/data/p02609/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02609/C++/s115318534.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s115318534", "user_id": "u225053756"}, "prompt_components": {"gold_output": "2\n1\n1\n", "input_to_evaluate": "#include \"bits/stdc++.h\"\n\n#define MOD 1000000007\n#define rep(i, n) for(ll i=0; i < (n); i++)\n#define rrep(i, n) for(ll i=(n)-1; i >=0; i--)\n#define ALL(v) v.begin(),v.end()\n#define rALL(v) v.rbegin(),v.rend()\n#define FOR(i, j, k) for(ll i=j;i<k;i++)\n#define debug_print(var) cerr << #var << \"=\" << var <<endl;\n#define DUMP(i, v)for(ll i=0;i<v.size();i++)cerr<<v[i]<<\" \"\n\nusing namespace std;\ntypedef long long int ll;\ntypedef vector<ll> llvec;\ntypedef vector<double> dvec;\ntypedef pair<ll, ll> P;\ntypedef long double ld;\nstruct edge{ll x, c;};\n\nll mod(ll a, ll mod){\n  ll res = a%mod;\n  while(res<0){\n    res=res + mod;\n  }\n  return res;\n}\n\nll modpow(ll a, ll n, ll mod){\n  ll res=1;\n  while(n>0){\n    if(n&1) res=res*a%mod;\n    a=a*a%mod;\n    n>>=1;\n  }\n  return res;\n}\n\nll modinv(ll a, ll mod){\n  return modpow(a, mod-2, mod);\n}\n\nll gcd(ll a, ll b){\n  ll r = a%b;\n  if(r==0) return b;\n  else return gcd(b, a%b);\n}\n\nbool is_prime(ll n){\n  ll i = 2;\n  if(n==1)return false;\n  if(n==2)return true;\n  bool res = true;\n  while(i*i <n){\n    if(n%i==0){\n      res = false;\n    }\n    i = i+1;\n  }\n\n  //if(i==1)res = false;\n  if(n%i==0)res=false;\n  return res;\n}\n\nstruct UnionFind{\n  ll N;\n  llvec p;\n  llvec cnt;\n  UnionFind(ll n){\n    N = n;\n    p=llvec(N);\n    cnt=llvec(N, 0);\n    rep(i, N){\n      p[i] = i;\n      cnt[i] = 1;\n    }\n  }\n\n  void con(ll a, ll b){\n    P at = root(a);\n    P bt = root(b);\n    if(at.second!=bt.second){\n      if(at.first>bt.first){\n        swap(at, bt);\n        swap(a, b);\n      }\n      p[at.second] = bt.second;\n      cnt[bt.second]+=cnt[at.second];\n      p[a]=bt.second;\n    }\n  }\n\n  P root(ll a){\n    ll atmp = a;\n    ll c=0;\n    while(atmp!=p[atmp]){\n      atmp = p[atmp];\n      c++;\n    }\n    p[a] = atmp;\n    return {c, atmp};\n  }\n\n  bool is_con(ll a, ll b){\n    P at=root(a);\n    P bt=root(b);\n    return at.second == bt.second;\n  }\n  \n};\n\nstruct dijkstra{\n  ll N;\n  llvec d;\n  vector<vector<edge>> e;\n  dijkstra(ll n){\n    N = n;\n    //d = llvec(N, 1e18);\n    e = vector<vector<edge>>(N);\n  }\n\n  void add_edge(ll from, ll to, ll cost){\n    e[from].push_back({to, cost});\n  }\n\n  void run(ll start){\n    priority_queue<P, vector<P>, greater<P>> que;\n    que.push({0, start});\n    d = llvec(N, 1e18);\n    d[start]=0;\n    while(!que.empty()){\n      P q = que.top();que.pop();\n      ll dc = q.first;\n      ll x = q.second;\n      if(dc>d[x]){\n        continue;\n      }else{\n        for(auto ip: e[x]){\n          if(d[ip.x]<=d[x]+ip.c){\n            continue;\n          }else{\n            d[ip.x]= d[x]+ip.c;\n            que.push({d[ip.x], ip.x});\n          }\n        }\n      }\n    }\n  }  \n};\n\nll dp[5000000];\nll func2(ll n, ll s){\n  if(n==0)return s;\n  ll cnt = 0;\n  rep(i, 20){\n    if(n>>i&1)cnt++;\n  }\n  ll ans = 0;\n  rep(i, 20){\n    if(n>>i&1){\n      ans = mod(ans + modpow(2, i, cnt), cnt);\n    }\n  }\n  return func2(ans, s+1);\n}\n\n\n/**************************************\n** A main function starts from here  **\n***************************************/\nint main(){\n  ll N;\n  cin >> N;\n  string X;\n  cin >> X;\n  ll cnt=0;\n  rep(i, N){\n    if(X[i]=='1')cnt++;\n  }\n  ll cnt_m1=0;\n  ll cnt_p1=0;\n  rep(i, N){\n    if(X[i]=='1'){\n      if(cnt>0)cnt_m1 = mod(cnt_m1+modpow(2, N-i-1, cnt-1), cnt-1);\n      cnt_p1 = mod(cnt_p1+modpow(2, N-i-1, cnt+1), cnt+1);\n    }\n  }\n  /*\n  rep(i, N+1){\n    dp[i] = func2(i, 0);\n  }\n  */\n  rep(i, N){\n    if(X[i]=='0'){\n      ll tmp = mod(cnt_p1+modpow(2, N-i-1, cnt+1), cnt+1);\n      cout << func2(tmp, 1)<<endl;\n    }else{\n      ll tmp = mod(cnt_m1-modpow(2, N-i-1, cnt-1), cnt-1);\n      tmp = mod(tmp, cnt-1);\n      cout << func2(tmp, 1)<<endl;\n    }\n  }\n  \n  return 0;\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nLet \\mathrm{popcount}(n) be the number of 1s in the binary representation of n.\nFor example, \\mathrm{popcount}(3) = 2, \\mathrm{popcount}(7) = 3, and \\mathrm{popcount}(0) = 0.\n\nLet f(n) be the number of times the following operation will be done when we repeat it until n becomes 0: \"replace n with the remainder when n is divided by \\mathrm{popcount}(n).\" (It can be proved that, under the constraints of this problem, n always becomes 0 after a finite number of operations.)\n\nFor example, when n=7, it becomes 0 after two operations, as follows:\n\n\\mathrm{popcount}(7)=3, so we divide 7 by 3 and replace it with the remainder, 1.\n\n\\mathrm{popcount}(1)=1, so we divide 1 by 1 and replace it with the remainder, 0.\n\nYou are given an integer X with N digits in binary.\nFor each integer i such that 1 \\leq i \\leq N, let X_i be what X becomes when the i-th bit from the top is inverted.\nFind f(X_1), f(X_2), \\ldots, f(X_N).\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\nX is an integer with N digits in binary, possibly with leading zeros.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nX\n\nOutput\n\nPrint N lines. The i-th line should contain the value f(X_i).\n\nSample Input 1\n\n3\n011\n\nSample Output 1\n\n2\n1\n1\n\nX_1 = 7, which will change as follows: 7 \\rightarrow 1 \\rightarrow 0. Thus, f(7) = 2.\n\nX_2 = 1, which will change as follows: 1 \\rightarrow 0. Thus, f(1) = 1.\n\nX_3 = 2, which will change as follows: 2 \\rightarrow 0. Thus, f(2) = 1.\n\nSample Input 2\n\n23\n00110111001011011001110\n\nSample Output 2\n\n2\n1\n2\n2\n1\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n1\n3", "sample_input": "3\n011\n"}, "reference_outputs": ["2\n1\n1\n"], "source_document_id": "p02609", "source_text": "Score : 400 points\n\nProblem Statement\n\nLet \\mathrm{popcount}(n) be the number of 1s in the binary representation of n.\nFor example, \\mathrm{popcount}(3) = 2, \\mathrm{popcount}(7) = 3, and \\mathrm{popcount}(0) = 0.\n\nLet f(n) be the number of times the following operation will be done when we repeat it until n becomes 0: \"replace n with the remainder when n is divided by \\mathrm{popcount}(n).\" (It can be proved that, under the constraints of this problem, n always becomes 0 after a finite number of operations.)\n\nFor example, when n=7, it becomes 0 after two operations, as follows:\n\n\\mathrm{popcount}(7)=3, so we divide 7 by 3 and replace it with the remainder, 1.\n\n\\mathrm{popcount}(1)=1, so we divide 1 by 1 and replace it with the remainder, 0.\n\nYou are given an integer X with N digits in binary.\nFor each integer i such that 1 \\leq i \\leq N, let X_i be what X becomes when the i-th bit from the top is inverted.\nFind f(X_1), f(X_2), \\ldots, f(X_N).\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\nX is an integer with N digits in binary, possibly with leading zeros.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nX\n\nOutput\n\nPrint N lines. The i-th line should contain the value f(X_i).\n\nSample Input 1\n\n3\n011\n\nSample Output 1\n\n2\n1\n1\n\nX_1 = 7, which will change as follows: 7 \\rightarrow 1 \\rightarrow 0. Thus, f(7) = 2.\n\nX_2 = 1, which will change as follows: 1 \\rightarrow 0. Thus, f(1) = 1.\n\nX_3 = 2, which will change as follows: 2 \\rightarrow 0. Thus, f(2) = 1.\n\nSample Input 2\n\n23\n00110111001011011001110\n\nSample Output 2\n\n2\n1\n2\n2\n1\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n2\n1\n3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 3632, "cpu_time_ms": 552, "memory_kb": 3692}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s913567047", "group_id": "codeNet:p02610", "input_text": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <map>\n#include <queue>\n#include <cstdio>\n#include <ctime>\n#include <assert.h>\n#include <chrono>\n#include <random>\n#include <numeric>\n#include <set>\nusing namespace std;\ntypedef long long int ll;\nusing ull = unsigned long long;\n\nll solve(vector<pair<int,int>> v){\n    int n=v.size();\n    for(int i=0;i<n;i++){\n        v[i].first=min(v[i].first,n);\n    }\n    vector<vector<int>> s(n+1);\n    for(int i=0;i<n;i++){\n        s[v[i].first].push_back(v[i].second);\n    }\n    ll res=0;\n    priority_queue<ll> q;\n    for(int i=n;i>=1;i--){\n        for(int x:s[i]){q.push(x);}\n        if(q.size()){\n            res+=q.top();\n            q.pop();\n        }\n    }\n    return res;\n}\n\nint main(){\n    cin.tie(nullptr);\n    ios::sync_with_stdio(false);\n    int q; cin >> q;\n    while(q--){\n        int n; cin >> n;\n        vector<pair<int,int>> pl,pr;\n        ll res=0;\n        for(int i=0;i<n;i++){\n            int k,l,r; cin >> k >> l >> r;\n            int m=min(l,r);\n            res+=m;\n            l-=m,r-=m;\n            if(l>0)pl.push_back({k,l});\n            else pr.push_back({n-k,r});\n        }\n        res+=solve(pl);\n        res+=solve(pr);\n        printf(\"%lld\\n\",res );\n    }\n}", "language": "C++", "metadata": {"date": 1594755900, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02610.html", "problem_id": "p02610", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02610/input.txt", "sample_output_relpath": "derived/input_output/data/p02610/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02610/C++/s913567047.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s913567047", "user_id": "u928536113"}, "prompt_components": {"gold_output": "25\n221\n1354\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <map>\n#include <queue>\n#include <cstdio>\n#include <ctime>\n#include <assert.h>\n#include <chrono>\n#include <random>\n#include <numeric>\n#include <set>\nusing namespace std;\ntypedef long long int ll;\nusing ull = unsigned long long;\n\nll solve(vector<pair<int,int>> v){\n    int n=v.size();\n    for(int i=0;i<n;i++){\n        v[i].first=min(v[i].first,n);\n    }\n    vector<vector<int>> s(n+1);\n    for(int i=0;i<n;i++){\n        s[v[i].first].push_back(v[i].second);\n    }\n    ll res=0;\n    priority_queue<ll> q;\n    for(int i=n;i>=1;i--){\n        for(int x:s[i]){q.push(x);}\n        if(q.size()){\n            res+=q.top();\n            q.pop();\n        }\n    }\n    return res;\n}\n\nint main(){\n    cin.tie(nullptr);\n    ios::sync_with_stdio(false);\n    int q; cin >> q;\n    while(q--){\n        int n; cin >> n;\n        vector<pair<int,int>> pl,pr;\n        ll res=0;\n        for(int i=0;i<n;i++){\n            int k,l,r; cin >> k >> l >> r;\n            int m=min(l,r);\n            res+=m;\n            l-=m,r-=m;\n            if(l>0)pl.push_back({k,l});\n            else pr.push_back({n-k,r});\n        }\n        res+=solve(pl);\n        res+=solve(pr);\n        printf(\"%lld\\n\",res );\n    }\n}", "problem_context": "Score : 500 points\n\nProblem Statement\n\nWe have N camels numbered 1,2,\\ldots,N.\nSnuke has decided to make them line up in a row.\n\nThe happiness of Camel i will be L_i if it is among the K_i frontmost camels, and R_i otherwise.\n\nSnuke wants to maximize the total happiness of the camels. Find the maximum possible total happiness of the camel.\n\nSolve this problem for each of the T test cases given.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq T \\leq 10^5\n\n1 \\leq N \\leq 2 \\times 10^{5}\n\n1 \\leq K_i \\leq N\n\n1 \\leq L_i, R_i \\leq 10^9\n\nThe sum of values of N in each input file is at most 2 \\times 10^5.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nT\n\\mathrm{case}_1\n\\vdots\n\\mathrm{case}_T\n\nEach case is given in the following format:\n\nN\nK_1 L_1 R_1\n\\vdots\nK_N L_N R_N\n\nOutput\n\nPrint T lines. The i-th line should contain the answer to the i-th test case.\n\nSample Input 1\n\n3\n2\n1 5 10\n2 15 5\n3\n2 93 78\n1 71 59\n3 57 96\n19\n19 23 16\n5 90 13\n12 85 70\n19 67 78\n12 16 60\n18 48 28\n5 4 24\n12 97 97\n4 57 87\n19 91 74\n18 100 76\n7 86 46\n9 100 57\n3 76 73\n6 84 93\n1 6 84\n11 75 94\n19 15 3\n12 11 34\n\nSample Output 1\n\n25\n221\n1354\n\nIn the first test case, it is optimal to line up the camels in the order 2, 1.\n\nCamel 1 is not the frontmost camel, so its happiness will be 10.\n\nCamel 2 is among the two frontmost camels, so its happiness will be 15.\n\nIn the second test case, it is optimal to line up the camels in the order 2, 1, 3.\n\nCamel 1 is among the two frontmost camels, so its happiness will be 93.\n\nCamel 2 is the frontmost camel, so its happiness will be 71.\n\nCamel 3 is among the three frontmost camels, so its happiness will be 57.", "sample_input": "3\n2\n1 5 10\n2 15 5\n3\n2 93 78\n1 71 59\n3 57 96\n19\n19 23 16\n5 90 13\n12 85 70\n19 67 78\n12 16 60\n18 48 28\n5 4 24\n12 97 97\n4 57 87\n19 91 74\n18 100 76\n7 86 46\n9 100 57\n3 76 73\n6 84 93\n1 6 84\n11 75 94\n19 15 3\n12 11 34\n"}, "reference_outputs": ["25\n221\n1354\n"], "source_document_id": "p02610", "source_text": "Score : 500 points\n\nProblem Statement\n\nWe have N camels numbered 1,2,\\ldots,N.\nSnuke has decided to make them line up in a row.\n\nThe happiness of Camel i will be L_i if it is among the K_i frontmost camels, and R_i otherwise.\n\nSnuke wants to maximize the total happiness of the camels. Find the maximum possible total happiness of the camel.\n\nSolve this problem for each of the T test cases given.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq T \\leq 10^5\n\n1 \\leq N \\leq 2 \\times 10^{5}\n\n1 \\leq K_i \\leq N\n\n1 \\leq L_i, R_i \\leq 10^9\n\nThe sum of values of N in each input file is at most 2 \\times 10^5.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nT\n\\mathrm{case}_1\n\\vdots\n\\mathrm{case}_T\n\nEach case is given in the following format:\n\nN\nK_1 L_1 R_1\n\\vdots\nK_N L_N R_N\n\nOutput\n\nPrint T lines. The i-th line should contain the answer to the i-th test case.\n\nSample Input 1\n\n3\n2\n1 5 10\n2 15 5\n3\n2 93 78\n1 71 59\n3 57 96\n19\n19 23 16\n5 90 13\n12 85 70\n19 67 78\n12 16 60\n18 48 28\n5 4 24\n12 97 97\n4 57 87\n19 91 74\n18 100 76\n7 86 46\n9 100 57\n3 76 73\n6 84 93\n1 6 84\n11 75 94\n19 15 3\n12 11 34\n\nSample Output 1\n\n25\n221\n1354\n\nIn the first test case, it is optimal to line up the camels in the order 2, 1.\n\nCamel 1 is not the frontmost camel, so its happiness will be 10.\n\nCamel 2 is among the two frontmost camels, so its happiness will be 15.\n\nIn the second test case, it is optimal to line up the camels in the order 2, 1, 3.\n\nCamel 1 is among the two frontmost camels, so its happiness will be 93.\n\nCamel 2 is the frontmost camel, so its happiness will be 71.\n\nCamel 3 is among the three frontmost camels, so its happiness will be 57.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1242, "cpu_time_ms": 84, "memory_kb": 11108}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s277819194", "group_id": "codeNet:p02610", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n#define m_p make_pair\n#define all(x) (x).begin(),(x).end()\n#define sz(x) ((int)(x).size())\n#define fi first\n#define se second\ntypedef long long ll;\nmt19937 rnd(chrono::steady_clock::now().time_since_epoch().count());\nmt19937 rnf(2106);\nconst int N = 200005;\nstruct ban\n{\n    int k, l, r;\n};\nbool operator<(const ban& a, const ban& b)\n{\n    return abs(a.l - a.r) < abs(b.l - b.r);\n}\n\nint n;\nban a[N];\n\nvoid ubd(int tl, int tr, int x, int y, int pos, vector<int>& s, vector<int>& p)\n{\n    if (tl == tr)\n    {\n        s[pos] += y;\n        p[pos] = min(p[pos], 0);\n        return;\n    }\n    int m = (tl + tr) / 2;\n    if (x <= m)\n        ubd(tl, m, x, y, pos * 2, s, p);\n    else\n        ubd(m + 1, tr, x, y, pos * 2 + 1, s, p);\n    s[pos] = s[pos * 2] + s[pos * 2 + 1];\n    p[pos] = min(p[pos * 2], s[pos * 2] + p[pos * 2 + 1]);\n}\n\nvoid solv()\n{\n    scanf(\"%d\", &n);\n    for (int i = 1; i <= n; ++i)\n        scanf(\"%d%d%d\", &a[i].k, &a[i].l, &a[i].r);\n    sort(a + 1, a + n + 1);\n    reverse(a + 1, a + n + 1);\n\n    vector<int> sl, pl, sr, pr;\n    sl.assign(n * 4 + 5, 0);\n    pl.assign(n * 4 + 5, 0);\n    sr.assign(n * 4 + 5, 0);\n    pr.assign(n * 4 + 5, 0);\n\n    for (int i = 1; i <= n; ++i)\n    {\n        ubd(1, n, i, 1, 1, sl, pl);\n        ubd(1, n, i, 1, 1, sr, pr);\n    }\n\n    ll ans = 0;\n    for (int i = 1; i <= n; ++i)\n    {\n        if (a[i].l > a[i].r)\n        {\n            ubd(1, n, a[i].k, -1, 1, sl, pl);\n            if (pl[1] < 0)\n            {\n                ubd(1, n, a[i].k, 1, 1, sl, pl);\n                ans += a[i].r;\n            }\n            else\n                ans += a[i].l;\n        }\n        else\n        {\n            if (n - a[i].k == 0)\n            {\n                ans += a[i].l;\n                continue;\n            }\n            ubd(1, n, n - a[i].k, -1, 1, sr, pr);\n            if (pr[1] < 0)\n            {\n                ubd(1, n, n - a[i].k, 1, 1, sr, pr);\n                ans += a[i].l;\n            }\n            else\n                ans += a[i].r;\n        }\n        //ubd(1, n, n, -2, 1, sl, pl);\n        //ubd(1, n, 1, -2, 1, sr, pr);\n    }\n    printf(\"%lld\\n\", ans);\n}\n\nint main()\n{\n    #ifdef SOMETHING\n    freopen(\"input.txt\", \"r\", stdin);\n    //freopen(\"output.txt\", \"w\", stdout);\n    #endif // SOMETHING\n    int tt;\n    scanf(\"%d\", &tt);\n    while (tt--)\n        solv();\n    return 0;\n}\n\n//while ((double)clock() / CLOCKS_PER_SEC <= 0.9){}\n", "language": "C++", "metadata": {"date": 1594520004, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02610.html", "problem_id": "p02610", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02610/input.txt", "sample_output_relpath": "derived/input_output/data/p02610/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02610/C++/s277819194.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s277819194", "user_id": "u742977643"}, "prompt_components": {"gold_output": "25\n221\n1354\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n#define m_p make_pair\n#define all(x) (x).begin(),(x).end()\n#define sz(x) ((int)(x).size())\n#define fi first\n#define se second\ntypedef long long ll;\nmt19937 rnd(chrono::steady_clock::now().time_since_epoch().count());\nmt19937 rnf(2106);\nconst int N = 200005;\nstruct ban\n{\n    int k, l, r;\n};\nbool operator<(const ban& a, const ban& b)\n{\n    return abs(a.l - a.r) < abs(b.l - b.r);\n}\n\nint n;\nban a[N];\n\nvoid ubd(int tl, int tr, int x, int y, int pos, vector<int>& s, vector<int>& p)\n{\n    if (tl == tr)\n    {\n        s[pos] += y;\n        p[pos] = min(p[pos], 0);\n        return;\n    }\n    int m = (tl + tr) / 2;\n    if (x <= m)\n        ubd(tl, m, x, y, pos * 2, s, p);\n    else\n        ubd(m + 1, tr, x, y, pos * 2 + 1, s, p);\n    s[pos] = s[pos * 2] + s[pos * 2 + 1];\n    p[pos] = min(p[pos * 2], s[pos * 2] + p[pos * 2 + 1]);\n}\n\nvoid solv()\n{\n    scanf(\"%d\", &n);\n    for (int i = 1; i <= n; ++i)\n        scanf(\"%d%d%d\", &a[i].k, &a[i].l, &a[i].r);\n    sort(a + 1, a + n + 1);\n    reverse(a + 1, a + n + 1);\n\n    vector<int> sl, pl, sr, pr;\n    sl.assign(n * 4 + 5, 0);\n    pl.assign(n * 4 + 5, 0);\n    sr.assign(n * 4 + 5, 0);\n    pr.assign(n * 4 + 5, 0);\n\n    for (int i = 1; i <= n; ++i)\n    {\n        ubd(1, n, i, 1, 1, sl, pl);\n        ubd(1, n, i, 1, 1, sr, pr);\n    }\n\n    ll ans = 0;\n    for (int i = 1; i <= n; ++i)\n    {\n        if (a[i].l > a[i].r)\n        {\n            ubd(1, n, a[i].k, -1, 1, sl, pl);\n            if (pl[1] < 0)\n            {\n                ubd(1, n, a[i].k, 1, 1, sl, pl);\n                ans += a[i].r;\n            }\n            else\n                ans += a[i].l;\n        }\n        else\n        {\n            if (n - a[i].k == 0)\n            {\n                ans += a[i].l;\n                continue;\n            }\n            ubd(1, n, n - a[i].k, -1, 1, sr, pr);\n            if (pr[1] < 0)\n            {\n                ubd(1, n, n - a[i].k, 1, 1, sr, pr);\n                ans += a[i].l;\n            }\n            else\n                ans += a[i].r;\n        }\n        //ubd(1, n, n, -2, 1, sl, pl);\n        //ubd(1, n, 1, -2, 1, sr, pr);\n    }\n    printf(\"%lld\\n\", ans);\n}\n\nint main()\n{\n    #ifdef SOMETHING\n    freopen(\"input.txt\", \"r\", stdin);\n    //freopen(\"output.txt\", \"w\", stdout);\n    #endif // SOMETHING\n    int tt;\n    scanf(\"%d\", &tt);\n    while (tt--)\n        solv();\n    return 0;\n}\n\n//while ((double)clock() / CLOCKS_PER_SEC <= 0.9){}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nWe have N camels numbered 1,2,\\ldots,N.\nSnuke has decided to make them line up in a row.\n\nThe happiness of Camel i will be L_i if it is among the K_i frontmost camels, and R_i otherwise.\n\nSnuke wants to maximize the total happiness of the camels. Find the maximum possible total happiness of the camel.\n\nSolve this problem for each of the T test cases given.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq T \\leq 10^5\n\n1 \\leq N \\leq 2 \\times 10^{5}\n\n1 \\leq K_i \\leq N\n\n1 \\leq L_i, R_i \\leq 10^9\n\nThe sum of values of N in each input file is at most 2 \\times 10^5.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nT\n\\mathrm{case}_1\n\\vdots\n\\mathrm{case}_T\n\nEach case is given in the following format:\n\nN\nK_1 L_1 R_1\n\\vdots\nK_N L_N R_N\n\nOutput\n\nPrint T lines. The i-th line should contain the answer to the i-th test case.\n\nSample Input 1\n\n3\n2\n1 5 10\n2 15 5\n3\n2 93 78\n1 71 59\n3 57 96\n19\n19 23 16\n5 90 13\n12 85 70\n19 67 78\n12 16 60\n18 48 28\n5 4 24\n12 97 97\n4 57 87\n19 91 74\n18 100 76\n7 86 46\n9 100 57\n3 76 73\n6 84 93\n1 6 84\n11 75 94\n19 15 3\n12 11 34\n\nSample Output 1\n\n25\n221\n1354\n\nIn the first test case, it is optimal to line up the camels in the order 2, 1.\n\nCamel 1 is not the frontmost camel, so its happiness will be 10.\n\nCamel 2 is among the two frontmost camels, so its happiness will be 15.\n\nIn the second test case, it is optimal to line up the camels in the order 2, 1, 3.\n\nCamel 1 is among the two frontmost camels, so its happiness will be 93.\n\nCamel 2 is the frontmost camel, so its happiness will be 71.\n\nCamel 3 is among the three frontmost camels, so its happiness will be 57.", "sample_input": "3\n2\n1 5 10\n2 15 5\n3\n2 93 78\n1 71 59\n3 57 96\n19\n19 23 16\n5 90 13\n12 85 70\n19 67 78\n12 16 60\n18 48 28\n5 4 24\n12 97 97\n4 57 87\n19 91 74\n18 100 76\n7 86 46\n9 100 57\n3 76 73\n6 84 93\n1 6 84\n11 75 94\n19 15 3\n12 11 34\n"}, "reference_outputs": ["25\n221\n1354\n"], "source_document_id": "p02610", "source_text": "Score : 500 points\n\nProblem Statement\n\nWe have N camels numbered 1,2,\\ldots,N.\nSnuke has decided to make them line up in a row.\n\nThe happiness of Camel i will be L_i if it is among the K_i frontmost camels, and R_i otherwise.\n\nSnuke wants to maximize the total happiness of the camels. Find the maximum possible total happiness of the camel.\n\nSolve this problem for each of the T test cases given.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq T \\leq 10^5\n\n1 \\leq N \\leq 2 \\times 10^{5}\n\n1 \\leq K_i \\leq N\n\n1 \\leq L_i, R_i \\leq 10^9\n\nThe sum of values of N in each input file is at most 2 \\times 10^5.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nT\n\\mathrm{case}_1\n\\vdots\n\\mathrm{case}_T\n\nEach case is given in the following format:\n\nN\nK_1 L_1 R_1\n\\vdots\nK_N L_N R_N\n\nOutput\n\nPrint T lines. The i-th line should contain the answer to the i-th test case.\n\nSample Input 1\n\n3\n2\n1 5 10\n2 15 5\n3\n2 93 78\n1 71 59\n3 57 96\n19\n19 23 16\n5 90 13\n12 85 70\n19 67 78\n12 16 60\n18 48 28\n5 4 24\n12 97 97\n4 57 87\n19 91 74\n18 100 76\n7 86 46\n9 100 57\n3 76 73\n6 84 93\n1 6 84\n11 75 94\n19 15 3\n12 11 34\n\nSample Output 1\n\n25\n221\n1354\n\nIn the first test case, it is optimal to line up the camels in the order 2, 1.\n\nCamel 1 is not the frontmost camel, so its happiness will be 10.\n\nCamel 2 is among the two frontmost camels, so its happiness will be 15.\n\nIn the second test case, it is optimal to line up the camels in the order 2, 1, 3.\n\nCamel 1 is among the two frontmost camels, so its happiness will be 93.\n\nCamel 2 is the frontmost camel, so its happiness will be 71.\n\nCamel 3 is among the three frontmost camels, so its happiness will be 57.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2431, "cpu_time_ms": 185, "memory_kb": 18004}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s538790818", "group_id": "codeNet:p02613", "input_text": "#include <bits/stdc++.h>\n#define rep(i,n) for (int i=0; i< int (n); i++)\nusing namespace std;\ntypedef long long ll;\n\nint main(){\n\nint n;\ncin >> n;\nvector<string> s(100010);\nint a=0, w=0, t=0, r=0;\nrep(i,n) {\n    cin >> s[i];\n    if(s[i]==\"AC\") a++;\n    if(s[i]==\"WA\") w++;\n    if(s[i]==\"TLE\") t++;\n    if(s[i]==\"RE\") r++;\n}\ncout << \"AC x \" << a << endl;\ncout << \"WA x \" << w << endl;\ncout << \"TLE x \" << t << endl;\ncout << \"RE x \" << r << endl;\n\n}", "language": "C++", "metadata": {"date": 1593997690, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02613.html", "problem_id": "p02613", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02613/input.txt", "sample_output_relpath": "derived/input_output/data/p02613/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02613/C++/s538790818.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s538790818", "user_id": "u778605027"}, "prompt_components": {"gold_output": "AC x 3\nWA x 1\nTLE x 2\nRE x 0\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define rep(i,n) for (int i=0; i< int (n); i++)\nusing namespace std;\ntypedef long long ll;\n\nint main(){\n\nint n;\ncin >> n;\nvector<string> s(100010);\nint a=0, w=0, t=0, r=0;\nrep(i,n) {\n    cin >> s[i];\n    if(s[i]==\"AC\") a++;\n    if(s[i]==\"WA\") w++;\n    if(s[i]==\"TLE\") t++;\n    if(s[i]==\"RE\") r++;\n}\ncout << \"AC x \" << a << endl;\ncout << \"WA x \" << w << endl;\ncout << \"TLE x \" << t << endl;\ncout << \"RE x \" << r << endl;\n\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nTakahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.\n\nThe problem has N test cases.\n\nFor each test case i (1\\leq i \\leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is AC, WA, TLE, and RE, respectively.\n\nSee the Output section for the output format.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\nS_i is AC, WA, TLE, or RE.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS_1\n\\vdots\nS_N\n\nOutput\n\nLet C_0, C_1, C_2, and C_3 be the numbers of test cases for which the verdict is AC, WA, TLE, and RE, respectively. Print the following:\n\nAC x C_0\nWA x C_1\nTLE x C_2\nRE x C_3\n\nSample Input 1\n\n6\nAC\nTLE\nAC\nAC\nWA\nTLE\n\nSample Output 1\n\nAC x 3\nWA x 1\nTLE x 2\nRE x 0\n\nWe have 3, 1, 2, and 0 test case(s) for which the verdict is AC, WA, TLE, and RE, respectively.\n\nSample Input 2\n\n10\nAC\nAC\nAC\nAC\nAC\nAC\nAC\nAC\nAC\nAC\n\nSample Output 2\n\nAC x 10\nWA x 0\nTLE x 0\nRE x 0", "sample_input": "6\nAC\nTLE\nAC\nAC\nWA\nTLE\n"}, "reference_outputs": ["AC x 3\nWA x 1\nTLE x 2\nRE x 0\n"], "source_document_id": "p02613", "source_text": "Score : 200 points\n\nProblem Statement\n\nTakahashi is participating in a programming contest called AXC002, and he has just submitted his code to Problem A.\n\nThe problem has N test cases.\n\nFor each test case i (1\\leq i \\leq N), you are given a string S_i representing the verdict for that test case. Find the numbers of test cases for which the verdict is AC, WA, TLE, and RE, respectively.\n\nSee the Output section for the output format.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\nS_i is AC, WA, TLE, or RE.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS_1\n\\vdots\nS_N\n\nOutput\n\nLet C_0, C_1, C_2, and C_3 be the numbers of test cases for which the verdict is AC, WA, TLE, and RE, respectively. Print the following:\n\nAC x C_0\nWA x C_1\nTLE x C_2\nRE x C_3\n\nSample Input 1\n\n6\nAC\nTLE\nAC\nAC\nWA\nTLE\n\nSample Output 1\n\nAC x 3\nWA x 1\nTLE x 2\nRE x 0\n\nWe have 3, 1, 2, and 0 test case(s) for which the verdict is AC, WA, TLE, and RE, respectively.\n\nSample Input 2\n\n10\nAC\nAC\nAC\nAC\nAC\nAC\nAC\nAC\nAC\nAC\n\nSample Output 2\n\nAC x 10\nWA x 0\nTLE x 0\nRE x 0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 447, "cpu_time_ms": 33, "memory_kb": 6424}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s963844331", "group_id": "codeNet:p02614", "input_text": "#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <numeric>\n\nusing namespace std;\ntypedef long long ll;\nint H,W,K;\n\nint main(){\n  cin >> H >> W >> K;\n  vector<vector<int> > c(H,vector<int>(W));\n  int all =0;\n  for(int i=0;i<H;i++){\n    for(int j=0;j<W;j++){\n      char a;\n      cin >> a;\n      if(a=='#') {\n\tall++;\n\tc[i][j]=1;\n      }\n      else c[i][j]=0;\n    }\n  }\n  int ans =0;\n  for(int bith = 0;bith<(1<<H);++bith){\n    for(int bitw = 0;bitw<(1<<W);++bitw){\n      int black=0;\n      for(int i=0;i<H;i++){\n\tfor(int j=0;j<W;j++){\n\t  if((bith & (1<<i)) && (bitw & (1<<j))){\n\t    black+=c[i][j];\n\t  }\n\t}\n      }\n      if(black==K) ans++;\n    }\n  }\n  cout << ans << endl;\n}\n", "language": "C++", "metadata": {"date": 1600531464, "filename_ext": "cpp", "original_language": "C++ (Clang 10.0.0)", "problem_description_relpath": "problem_descriptions/p02614.html", "problem_id": "p02614", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02614/input.txt", "sample_output_relpath": "derived/input_output/data/p02614/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02614/C++/s963844331.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s963844331", "user_id": "u345981182"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <numeric>\n\nusing namespace std;\ntypedef long long ll;\nint H,W,K;\n\nint main(){\n  cin >> H >> W >> K;\n  vector<vector<int> > c(H,vector<int>(W));\n  int all =0;\n  for(int i=0;i<H;i++){\n    for(int j=0;j<W;j++){\n      char a;\n      cin >> a;\n      if(a=='#') {\n\tall++;\n\tc[i][j]=1;\n      }\n      else c[i][j]=0;\n    }\n  }\n  int ans =0;\n  for(int bith = 0;bith<(1<<H);++bith){\n    for(int bitw = 0;bitw<(1<<W);++bitw){\n      int black=0;\n      for(int i=0;i<H;i++){\n\tfor(int j=0;j<W;j++){\n\t  if((bith & (1<<i)) && (bitw & (1<<j))){\n\t    black+=c[i][j];\n\t  }\n\t}\n      }\n      if(black==K) ans++;\n    }\n  }\n  cout << ans << endl;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nWe have a grid of H rows and W columns of squares. The color of the square at the i-th row from the top and the j-th column from the left (1 \\leq i \\leq H, 1 \\leq j \\leq W) is given to you as a character c_{i,j}: the square is white if c_{i,j} is ., and black if c_{i,j} is #.\n\nConsider doing the following operation:\n\nChoose some number of rows (possibly zero), and some number of columns (possibly zero). Then, paint red all squares in the chosen rows and all squares in the chosen columns.\n\nYou are given a positive integer K. How many choices of rows and columns result in exactly K black squares remaining after the operation? Here, we consider two choices different when there is a row or column chosen in only one of those choices.\n\nConstraints\n\n1 \\leq H, W \\leq 6\n\n1 \\leq K \\leq HW\n\nc_{i,j} is . or #.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W K\nc_{1,1}c_{1,2}...c_{1,W}\nc_{2,1}c_{2,2}...c_{2,W}\n:\nc_{H,1}c_{H,2}...c_{H,W}\n\nOutput\n\nPrint an integer representing the number of choices of rows and columns satisfying the condition.\n\nSample Input 1\n\n2 3 2\n..#\n###\n\nSample Output 1\n\n5\n\nFive choices below satisfy the condition.\n\nThe 1-st row and 1-st column\n\nThe 1-st row and 2-nd column\n\nThe 1-st row and 3-rd column\n\nThe 1-st and 2-nd column\n\nThe 3-rd column\n\nSample Input 2\n\n2 3 4\n..#\n###\n\nSample Output 2\n\n1\n\nOne choice, which is choosing nothing, satisfies the condition.\n\nSample Input 3\n\n2 2 3\n##\n##\n\nSample Output 3\n\n0\n\nSample Input 4\n\n6 6 8\n..##..\n.#..#.\n#....#\n######\n#....#\n#....#\n\nSample Output 4\n\n208", "sample_input": "2 3 2\n..#\n###\n"}, "reference_outputs": ["5\n"], "source_document_id": "p02614", "source_text": "Score : 300 points\n\nProblem Statement\n\nWe have a grid of H rows and W columns of squares. The color of the square at the i-th row from the top and the j-th column from the left (1 \\leq i \\leq H, 1 \\leq j \\leq W) is given to you as a character c_{i,j}: the square is white if c_{i,j} is ., and black if c_{i,j} is #.\n\nConsider doing the following operation:\n\nChoose some number of rows (possibly zero), and some number of columns (possibly zero). Then, paint red all squares in the chosen rows and all squares in the chosen columns.\n\nYou are given a positive integer K. How many choices of rows and columns result in exactly K black squares remaining after the operation? Here, we consider two choices different when there is a row or column chosen in only one of those choices.\n\nConstraints\n\n1 \\leq H, W \\leq 6\n\n1 \\leq K \\leq HW\n\nc_{i,j} is . or #.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W K\nc_{1,1}c_{1,2}...c_{1,W}\nc_{2,1}c_{2,2}...c_{2,W}\n:\nc_{H,1}c_{H,2}...c_{H,W}\n\nOutput\n\nPrint an integer representing the number of choices of rows and columns satisfying the condition.\n\nSample Input 1\n\n2 3 2\n..#\n###\n\nSample Output 1\n\n5\n\nFive choices below satisfy the condition.\n\nThe 1-st row and 1-st column\n\nThe 1-st row and 2-nd column\n\nThe 1-st row and 3-rd column\n\nThe 1-st and 2-nd column\n\nThe 3-rd column\n\nSample Input 2\n\n2 3 4\n..#\n###\n\nSample Output 2\n\n1\n\nOne choice, which is choosing nothing, satisfies the condition.\n\nSample Input 3\n\n2 2 3\n##\n##\n\nSample Output 3\n\n0\n\nSample Input 4\n\n6 6 8\n..##..\n.#..#.\n#....#\n######\n#....#\n#....#\n\nSample Output 4\n\n208", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 710, "cpu_time_ms": 6, "memory_kb": 3200}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s923763823", "group_id": "codeNet:p02614", "input_text": "#include <bits/stdc++.h>\n#include <limits>\n#include <math.h>\n#include <cmath>\n#include <cctype>\n#include <cstdio>\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing pll = pair<ll, ll> ;\nusing vs = vector<string>;\nusing vb = vector<bool>;\nusing vll = vector<long long>;\nusing vvll = vector<vector<long long >>;\n#define PI  3.1415926535\n#define rep(i, k, n) for(ll i = k; i < n; i++)\n\nint main(){\n  ll h, w, k;\n  cin >> h >> w >> k;\n  \n  vector<vector<char>> block(h,vector<char>(w));\n  \n  rep(i, 0, h){\n    rep(j, 0, w){\n      cin >> block[i][j];\n    }\n  }\n  \n  ll ans = 0;\n  for(ll bit = 0; bit < (1<<(h+w)); bit ++){\n    \n    vector<vector<char>> painted(h,vector<char>(w));\n    rep(i, 0, h){\n      rep(j, 0, w){\n        painted[i][j] = block[i][j];\n      }\n    }\n    \n    rep(i, 0, h+w){\n      if(bit & (1 << i)){\n        if(i < h){\n          rep(j, 0, w){painted[i][j] = 'R';}\n        }\n        else{\n          rep(j, 0, h){painted[j][i-h] = 'R';}\n        }\n      }\n    }\n\t\n    ll cnt = 0;\n    rep(i, 0, h){\n      rep(j, 0, w){\n        if(painted[i][j] == '#'){cnt++;}\n      }\n    }\n    \n    if(cnt == k){ans++;}\n  }\n  \n  cout << ans << endl;\n    \n}\n\n\n\n\n", "language": "C++", "metadata": {"date": 1595960473, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02614.html", "problem_id": "p02614", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02614/input.txt", "sample_output_relpath": "derived/input_output/data/p02614/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02614/C++/s923763823.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s923763823", "user_id": "u108843155"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#include <limits>\n#include <math.h>\n#include <cmath>\n#include <cctype>\n#include <cstdio>\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing pll = pair<ll, ll> ;\nusing vs = vector<string>;\nusing vb = vector<bool>;\nusing vll = vector<long long>;\nusing vvll = vector<vector<long long >>;\n#define PI  3.1415926535\n#define rep(i, k, n) for(ll i = k; i < n; i++)\n\nint main(){\n  ll h, w, k;\n  cin >> h >> w >> k;\n  \n  vector<vector<char>> block(h,vector<char>(w));\n  \n  rep(i, 0, h){\n    rep(j, 0, w){\n      cin >> block[i][j];\n    }\n  }\n  \n  ll ans = 0;\n  for(ll bit = 0; bit < (1<<(h+w)); bit ++){\n    \n    vector<vector<char>> painted(h,vector<char>(w));\n    rep(i, 0, h){\n      rep(j, 0, w){\n        painted[i][j] = block[i][j];\n      }\n    }\n    \n    rep(i, 0, h+w){\n      if(bit & (1 << i)){\n        if(i < h){\n          rep(j, 0, w){painted[i][j] = 'R';}\n        }\n        else{\n          rep(j, 0, h){painted[j][i-h] = 'R';}\n        }\n      }\n    }\n\t\n    ll cnt = 0;\n    rep(i, 0, h){\n      rep(j, 0, w){\n        if(painted[i][j] == '#'){cnt++;}\n      }\n    }\n    \n    if(cnt == k){ans++;}\n  }\n  \n  cout << ans << endl;\n    \n}\n\n\n\n\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nWe have a grid of H rows and W columns of squares. The color of the square at the i-th row from the top and the j-th column from the left (1 \\leq i \\leq H, 1 \\leq j \\leq W) is given to you as a character c_{i,j}: the square is white if c_{i,j} is ., and black if c_{i,j} is #.\n\nConsider doing the following operation:\n\nChoose some number of rows (possibly zero), and some number of columns (possibly zero). Then, paint red all squares in the chosen rows and all squares in the chosen columns.\n\nYou are given a positive integer K. How many choices of rows and columns result in exactly K black squares remaining after the operation? Here, we consider two choices different when there is a row or column chosen in only one of those choices.\n\nConstraints\n\n1 \\leq H, W \\leq 6\n\n1 \\leq K \\leq HW\n\nc_{i,j} is . or #.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W K\nc_{1,1}c_{1,2}...c_{1,W}\nc_{2,1}c_{2,2}...c_{2,W}\n:\nc_{H,1}c_{H,2}...c_{H,W}\n\nOutput\n\nPrint an integer representing the number of choices of rows and columns satisfying the condition.\n\nSample Input 1\n\n2 3 2\n..#\n###\n\nSample Output 1\n\n5\n\nFive choices below satisfy the condition.\n\nThe 1-st row and 1-st column\n\nThe 1-st row and 2-nd column\n\nThe 1-st row and 3-rd column\n\nThe 1-st and 2-nd column\n\nThe 3-rd column\n\nSample Input 2\n\n2 3 4\n..#\n###\n\nSample Output 2\n\n1\n\nOne choice, which is choosing nothing, satisfies the condition.\n\nSample Input 3\n\n2 2 3\n##\n##\n\nSample Output 3\n\n0\n\nSample Input 4\n\n6 6 8\n..##..\n.#..#.\n#....#\n######\n#....#\n#....#\n\nSample Output 4\n\n208", "sample_input": "2 3 2\n..#\n###\n"}, "reference_outputs": ["5\n"], "source_document_id": "p02614", "source_text": "Score : 300 points\n\nProblem Statement\n\nWe have a grid of H rows and W columns of squares. The color of the square at the i-th row from the top and the j-th column from the left (1 \\leq i \\leq H, 1 \\leq j \\leq W) is given to you as a character c_{i,j}: the square is white if c_{i,j} is ., and black if c_{i,j} is #.\n\nConsider doing the following operation:\n\nChoose some number of rows (possibly zero), and some number of columns (possibly zero). Then, paint red all squares in the chosen rows and all squares in the chosen columns.\n\nYou are given a positive integer K. How many choices of rows and columns result in exactly K black squares remaining after the operation? Here, we consider two choices different when there is a row or column chosen in only one of those choices.\n\nConstraints\n\n1 \\leq H, W \\leq 6\n\n1 \\leq K \\leq HW\n\nc_{i,j} is . or #.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W K\nc_{1,1}c_{1,2}...c_{1,W}\nc_{2,1}c_{2,2}...c_{2,W}\n:\nc_{H,1}c_{H,2}...c_{H,W}\n\nOutput\n\nPrint an integer representing the number of choices of rows and columns satisfying the condition.\n\nSample Input 1\n\n2 3 2\n..#\n###\n\nSample Output 1\n\n5\n\nFive choices below satisfy the condition.\n\nThe 1-st row and 1-st column\n\nThe 1-st row and 2-nd column\n\nThe 1-st row and 3-rd column\n\nThe 1-st and 2-nd column\n\nThe 3-rd column\n\nSample Input 2\n\n2 3 4\n..#\n###\n\nSample Output 2\n\n1\n\nOne choice, which is choosing nothing, satisfies the condition.\n\nSample Input 3\n\n2 2 3\n##\n##\n\nSample Output 3\n\n0\n\nSample Input 4\n\n6 6 8\n..##..\n.#..#.\n#....#\n######\n#....#\n#....#\n\nSample Output 4\n\n208", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1187, "cpu_time_ms": 8, "memory_kb": 3640}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s073989855", "group_id": "codeNet:p02614", "input_text": "#include<bits/stdc++.h>\n// #define int long long\n#define rep(i, n) for(int i = 0; i < (int)n; i++)\n#define repa(i, s, n) for(int i = s; i < (int)n; i++)\nusing namespace std;\nusing ll = long long;\ntypedef vector<int> vi;\n\nsigned main() {\n    int h, w, k;\n    cin >> h >> w >> k;\n    vector<string> s(h);\n    int ans = 0;\n    rep(i, h) cin >> s[i];\n\n    rep(is, 1<<h)rep(js, 1<<w){\n        int cnt = 0;\n        rep(i, h)rep(j, w){\n            if(is>>i & 1) continue;\n            if(js>>i & 1) continue;\n            if(s[i][j] == '#') cnt++;\n        }\n        if(cnt == k) ans++;\n    }\n\n    cout << ans << endl;\n}", "language": "C++", "metadata": {"date": 1594080398, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02614.html", "problem_id": "p02614", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02614/input.txt", "sample_output_relpath": "derived/input_output/data/p02614/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02614/C++/s073989855.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s073989855", "user_id": "u510749912"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include<bits/stdc++.h>\n// #define int long long\n#define rep(i, n) for(int i = 0; i < (int)n; i++)\n#define repa(i, s, n) for(int i = s; i < (int)n; i++)\nusing namespace std;\nusing ll = long long;\ntypedef vector<int> vi;\n\nsigned main() {\n    int h, w, k;\n    cin >> h >> w >> k;\n    vector<string> s(h);\n    int ans = 0;\n    rep(i, h) cin >> s[i];\n\n    rep(is, 1<<h)rep(js, 1<<w){\n        int cnt = 0;\n        rep(i, h)rep(j, w){\n            if(is>>i & 1) continue;\n            if(js>>i & 1) continue;\n            if(s[i][j] == '#') cnt++;\n        }\n        if(cnt == k) ans++;\n    }\n\n    cout << ans << endl;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nWe have a grid of H rows and W columns of squares. The color of the square at the i-th row from the top and the j-th column from the left (1 \\leq i \\leq H, 1 \\leq j \\leq W) is given to you as a character c_{i,j}: the square is white if c_{i,j} is ., and black if c_{i,j} is #.\n\nConsider doing the following operation:\n\nChoose some number of rows (possibly zero), and some number of columns (possibly zero). Then, paint red all squares in the chosen rows and all squares in the chosen columns.\n\nYou are given a positive integer K. How many choices of rows and columns result in exactly K black squares remaining after the operation? Here, we consider two choices different when there is a row or column chosen in only one of those choices.\n\nConstraints\n\n1 \\leq H, W \\leq 6\n\n1 \\leq K \\leq HW\n\nc_{i,j} is . or #.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W K\nc_{1,1}c_{1,2}...c_{1,W}\nc_{2,1}c_{2,2}...c_{2,W}\n:\nc_{H,1}c_{H,2}...c_{H,W}\n\nOutput\n\nPrint an integer representing the number of choices of rows and columns satisfying the condition.\n\nSample Input 1\n\n2 3 2\n..#\n###\n\nSample Output 1\n\n5\n\nFive choices below satisfy the condition.\n\nThe 1-st row and 1-st column\n\nThe 1-st row and 2-nd column\n\nThe 1-st row and 3-rd column\n\nThe 1-st and 2-nd column\n\nThe 3-rd column\n\nSample Input 2\n\n2 3 4\n..#\n###\n\nSample Output 2\n\n1\n\nOne choice, which is choosing nothing, satisfies the condition.\n\nSample Input 3\n\n2 2 3\n##\n##\n\nSample Output 3\n\n0\n\nSample Input 4\n\n6 6 8\n..##..\n.#..#.\n#....#\n######\n#....#\n#....#\n\nSample Output 4\n\n208", "sample_input": "2 3 2\n..#\n###\n"}, "reference_outputs": ["5\n"], "source_document_id": "p02614", "source_text": "Score : 300 points\n\nProblem Statement\n\nWe have a grid of H rows and W columns of squares. The color of the square at the i-th row from the top and the j-th column from the left (1 \\leq i \\leq H, 1 \\leq j \\leq W) is given to you as a character c_{i,j}: the square is white if c_{i,j} is ., and black if c_{i,j} is #.\n\nConsider doing the following operation:\n\nChoose some number of rows (possibly zero), and some number of columns (possibly zero). Then, paint red all squares in the chosen rows and all squares in the chosen columns.\n\nYou are given a positive integer K. How many choices of rows and columns result in exactly K black squares remaining after the operation? Here, we consider two choices different when there is a row or column chosen in only one of those choices.\n\nConstraints\n\n1 \\leq H, W \\leq 6\n\n1 \\leq K \\leq HW\n\nc_{i,j} is . or #.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W K\nc_{1,1}c_{1,2}...c_{1,W}\nc_{2,1}c_{2,2}...c_{2,W}\n:\nc_{H,1}c_{H,2}...c_{H,W}\n\nOutput\n\nPrint an integer representing the number of choices of rows and columns satisfying the condition.\n\nSample Input 1\n\n2 3 2\n..#\n###\n\nSample Output 1\n\n5\n\nFive choices below satisfy the condition.\n\nThe 1-st row and 1-st column\n\nThe 1-st row and 2-nd column\n\nThe 1-st row and 3-rd column\n\nThe 1-st and 2-nd column\n\nThe 3-rd column\n\nSample Input 2\n\n2 3 4\n..#\n###\n\nSample Output 2\n\n1\n\nOne choice, which is choosing nothing, satisfies the condition.\n\nSample Input 3\n\n2 2 3\n##\n##\n\nSample Output 3\n\n0\n\nSample Input 4\n\n6 6 8\n..##..\n.#..#.\n#....#\n######\n#....#\n#....#\n\nSample Output 4\n\n208", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 610, "cpu_time_ms": 7, "memory_kb": 3552}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s807447364", "group_id": "codeNet:p02614", "input_text": "#include <iostream>\n#include <stdio.h>\n#include <stdlib.h>\n#include <cmath>\n#include <fstream>\n#include <vector>\n#include <string>\n#include <algorithm>\n#include <cmath>\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\nconst double PI=3.1415926535897932;\nusing namespace std;\ntypedef long long ll;\n\nint main(void){\n    ll h,w,q;\n    cin>>h>>w>>q;\n    int a[h][w];\n    rep(i,h){\n        rep(j,w){\n            char c;\n            cin>>c;\n            if(c=='.')a[i][j]=1;\n            else a[i][j]=0;\n        }\n    }\n    int ans=0;\n    for(int bit=0;bit<(1<<h);bit++){\n        vector <int>ex;\n        for(int i=0;i<h;i++){\n            if(bit&1<<i){\n                ex.push_back(i);\n            }\n        }\n        for(int c=0;c<(1<<w);c++){\n            vector <int> ew;\n            for(int j=0;j<w;j++){\n                if(c&1<<j){\n                    ew.push_back(j);\n                }\n            }\n            int s=0;\n            rep(k,h){\n                int fa=1;\n                for(auto x:ex){\n                    if(k==x)fa=0;\n                }\n                if(fa==0)continue;\n                rep(l,w){\n                    int f=1;\n                    for(auto y:ew){\n                        if(l==y)f=0;\n                    }\n                    if(f){\n                        if(a[k][l]==0)s++;\n                    }\n                }\n            }\n            if(q==s)ans++;\n        }\n    }\n    cout<<ans<<endl;\n}", "language": "C++", "metadata": {"date": 1594000128, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02614.html", "problem_id": "p02614", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02614/input.txt", "sample_output_relpath": "derived/input_output/data/p02614/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02614/C++/s807447364.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s807447364", "user_id": "u783299609"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include <iostream>\n#include <stdio.h>\n#include <stdlib.h>\n#include <cmath>\n#include <fstream>\n#include <vector>\n#include <string>\n#include <algorithm>\n#include <cmath>\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\nconst double PI=3.1415926535897932;\nusing namespace std;\ntypedef long long ll;\n\nint main(void){\n    ll h,w,q;\n    cin>>h>>w>>q;\n    int a[h][w];\n    rep(i,h){\n        rep(j,w){\n            char c;\n            cin>>c;\n            if(c=='.')a[i][j]=1;\n            else a[i][j]=0;\n        }\n    }\n    int ans=0;\n    for(int bit=0;bit<(1<<h);bit++){\n        vector <int>ex;\n        for(int i=0;i<h;i++){\n            if(bit&1<<i){\n                ex.push_back(i);\n            }\n        }\n        for(int c=0;c<(1<<w);c++){\n            vector <int> ew;\n            for(int j=0;j<w;j++){\n                if(c&1<<j){\n                    ew.push_back(j);\n                }\n            }\n            int s=0;\n            rep(k,h){\n                int fa=1;\n                for(auto x:ex){\n                    if(k==x)fa=0;\n                }\n                if(fa==0)continue;\n                rep(l,w){\n                    int f=1;\n                    for(auto y:ew){\n                        if(l==y)f=0;\n                    }\n                    if(f){\n                        if(a[k][l]==0)s++;\n                    }\n                }\n            }\n            if(q==s)ans++;\n        }\n    }\n    cout<<ans<<endl;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nWe have a grid of H rows and W columns of squares. The color of the square at the i-th row from the top and the j-th column from the left (1 \\leq i \\leq H, 1 \\leq j \\leq W) is given to you as a character c_{i,j}: the square is white if c_{i,j} is ., and black if c_{i,j} is #.\n\nConsider doing the following operation:\n\nChoose some number of rows (possibly zero), and some number of columns (possibly zero). Then, paint red all squares in the chosen rows and all squares in the chosen columns.\n\nYou are given a positive integer K. How many choices of rows and columns result in exactly K black squares remaining after the operation? Here, we consider two choices different when there is a row or column chosen in only one of those choices.\n\nConstraints\n\n1 \\leq H, W \\leq 6\n\n1 \\leq K \\leq HW\n\nc_{i,j} is . or #.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W K\nc_{1,1}c_{1,2}...c_{1,W}\nc_{2,1}c_{2,2}...c_{2,W}\n:\nc_{H,1}c_{H,2}...c_{H,W}\n\nOutput\n\nPrint an integer representing the number of choices of rows and columns satisfying the condition.\n\nSample Input 1\n\n2 3 2\n..#\n###\n\nSample Output 1\n\n5\n\nFive choices below satisfy the condition.\n\nThe 1-st row and 1-st column\n\nThe 1-st row and 2-nd column\n\nThe 1-st row and 3-rd column\n\nThe 1-st and 2-nd column\n\nThe 3-rd column\n\nSample Input 2\n\n2 3 4\n..#\n###\n\nSample Output 2\n\n1\n\nOne choice, which is choosing nothing, satisfies the condition.\n\nSample Input 3\n\n2 2 3\n##\n##\n\nSample Output 3\n\n0\n\nSample Input 4\n\n6 6 8\n..##..\n.#..#.\n#....#\n######\n#....#\n#....#\n\nSample Output 4\n\n208", "sample_input": "2 3 2\n..#\n###\n"}, "reference_outputs": ["5\n"], "source_document_id": "p02614", "source_text": "Score : 300 points\n\nProblem Statement\n\nWe have a grid of H rows and W columns of squares. The color of the square at the i-th row from the top and the j-th column from the left (1 \\leq i \\leq H, 1 \\leq j \\leq W) is given to you as a character c_{i,j}: the square is white if c_{i,j} is ., and black if c_{i,j} is #.\n\nConsider doing the following operation:\n\nChoose some number of rows (possibly zero), and some number of columns (possibly zero). Then, paint red all squares in the chosen rows and all squares in the chosen columns.\n\nYou are given a positive integer K. How many choices of rows and columns result in exactly K black squares remaining after the operation? Here, we consider two choices different when there is a row or column chosen in only one of those choices.\n\nConstraints\n\n1 \\leq H, W \\leq 6\n\n1 \\leq K \\leq HW\n\nc_{i,j} is . or #.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W K\nc_{1,1}c_{1,2}...c_{1,W}\nc_{2,1}c_{2,2}...c_{2,W}\n:\nc_{H,1}c_{H,2}...c_{H,W}\n\nOutput\n\nPrint an integer representing the number of choices of rows and columns satisfying the condition.\n\nSample Input 1\n\n2 3 2\n..#\n###\n\nSample Output 1\n\n5\n\nFive choices below satisfy the condition.\n\nThe 1-st row and 1-st column\n\nThe 1-st row and 2-nd column\n\nThe 1-st row and 3-rd column\n\nThe 1-st and 2-nd column\n\nThe 3-rd column\n\nSample Input 2\n\n2 3 4\n..#\n###\n\nSample Output 2\n\n1\n\nOne choice, which is choosing nothing, satisfies the condition.\n\nSample Input 3\n\n2 2 3\n##\n##\n\nSample Output 3\n\n0\n\nSample Input 4\n\n6 6 8\n..##..\n.#..#.\n#....#\n######\n#....#\n#....#\n\nSample Output 4\n\n208", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1419, "cpu_time_ms": 8, "memory_kb": 3632}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s632810778", "group_id": "codeNet:p02615", "input_text": "#include<bits/stdc++.h>\n#define pb push_back\n#define mp make_pair\n#define forn(i,a,b) for(int i =a;i<b;i++)\n#define fi first\n#define se second\n#define fast ios_base::sync_with_stdio(false);\nusing namespace std;\n\n//for debugging \n/*\ng++ -D_GLIBCXX_ASSERTIONS -DDEBUG -ggdb3 -std=c++14 \n*/\nint recur_depth = 0;\n#ifdef DEBUG\n#define dbg(x) {++recur_depth; auto x_=x; --recur_depth; cerr<<string(recur_depth, '\\t')<<\"\\e[91m\"<<__func__<<\":\"<<__LINE__<<\"\\t\"<<#x<<\" = \"<<x_<<\"\\e[39m\"<<endl;}\n#else\n#define dbg(x)\n#endif\ntemplate<typename Ostream, typename Cont>\ntypename enable_if<is_same<Ostream,ostream>::value, Ostream&>::type operator<<(Ostream& os,  const Cont& v){\n\tos<<\"[\";\n\tfor(auto& x:v){os<<x<<\", \";}\n\treturn os<<\"]\";\n}\ntemplate<typename Ostream, typename ...Ts>\nOstream& operator<<(Ostream& os,  const pair<Ts...>& p){\n\treturn os<<\"{\"<<p.first<<\", \"<<p.second<<\"}\";\n}\n// debugging ends here\n\ntypedef long long int ll;\ntypedef vector<int> vi;\ntypedef pair<int,int> pii;\ntypedef pair<ll,ll> pll;\n\n\nvoid solve(){\n\tint n;\n\tcin >> n;\n\tll a[n];\n\tforn(i,0,n) cin >> a[i];\n\tsort(a,a+n);\n\treverse(a,a+n);\n\tlong long int ans = 0;\n\tans+=a[0];\n\tfor(int i=0;i<((n-1)/2 - 1);i++){\n\t\tans+=(2*a[i+1]);\n\t\t// cout << ans << endl;\n\t}\n\tif(n%2){\n\t\tans+=a[(n-1)/2];\n\t}\n\telse{\n\t\tans+=2*a[(n-1)/2];\n\t}\n\tcout << ans << endl;\n}\n\nint main(){\n\tfast;\n\t#ifndef ONLINE_JUDGE\n\t\tfreopen(\"input.txt\",\"r\",stdin);\n\t\tfreopen(\"output.txt\",\"w\",stdout);\n\t#endif\n\n\t// int t;cin >> t;while(t--)\n\t\tsolve();\n}\n", "language": "C++", "metadata": {"date": 1593999954, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02615.html", "problem_id": "p02615", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02615/input.txt", "sample_output_relpath": "derived/input_output/data/p02615/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02615/C++/s632810778.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s632810778", "user_id": "u768225950"}, "prompt_components": {"gold_output": "7\n", "input_to_evaluate": "#include<bits/stdc++.h>\n#define pb push_back\n#define mp make_pair\n#define forn(i,a,b) for(int i =a;i<b;i++)\n#define fi first\n#define se second\n#define fast ios_base::sync_with_stdio(false);\nusing namespace std;\n\n//for debugging \n/*\ng++ -D_GLIBCXX_ASSERTIONS -DDEBUG -ggdb3 -std=c++14 \n*/\nint recur_depth = 0;\n#ifdef DEBUG\n#define dbg(x) {++recur_depth; auto x_=x; --recur_depth; cerr<<string(recur_depth, '\\t')<<\"\\e[91m\"<<__func__<<\":\"<<__LINE__<<\"\\t\"<<#x<<\" = \"<<x_<<\"\\e[39m\"<<endl;}\n#else\n#define dbg(x)\n#endif\ntemplate<typename Ostream, typename Cont>\ntypename enable_if<is_same<Ostream,ostream>::value, Ostream&>::type operator<<(Ostream& os,  const Cont& v){\n\tos<<\"[\";\n\tfor(auto& x:v){os<<x<<\", \";}\n\treturn os<<\"]\";\n}\ntemplate<typename Ostream, typename ...Ts>\nOstream& operator<<(Ostream& os,  const pair<Ts...>& p){\n\treturn os<<\"{\"<<p.first<<\", \"<<p.second<<\"}\";\n}\n// debugging ends here\n\ntypedef long long int ll;\ntypedef vector<int> vi;\ntypedef pair<int,int> pii;\ntypedef pair<ll,ll> pll;\n\n\nvoid solve(){\n\tint n;\n\tcin >> n;\n\tll a[n];\n\tforn(i,0,n) cin >> a[i];\n\tsort(a,a+n);\n\treverse(a,a+n);\n\tlong long int ans = 0;\n\tans+=a[0];\n\tfor(int i=0;i<((n-1)/2 - 1);i++){\n\t\tans+=(2*a[i+1]);\n\t\t// cout << ans << endl;\n\t}\n\tif(n%2){\n\t\tans+=a[(n-1)/2];\n\t}\n\telse{\n\t\tans+=2*a[(n-1)/2];\n\t}\n\tcout << ans << endl;\n}\n\nint main(){\n\tfast;\n\t#ifndef ONLINE_JUDGE\n\t\tfreopen(\"input.txt\",\"r\",stdin);\n\t\tfreopen(\"output.txt\",\"w\",stdout);\n\t#endif\n\n\t// int t;cin >> t;while(t--)\n\t\tsolve();\n}\n", "problem_context": "Score: 400 points\n\nProblem Statement\n\nQuickly after finishing the tutorial of the online game ATChat, you have decided to visit a particular place with N-1 players who happen to be there. These N players, including you, are numbered 1 through N, and the friendliness of Player i is A_i.\n\nThe N players will arrive at the place one by one in some order. To make sure nobody gets lost, you have set the following rule: players who have already arrived there should form a circle, and a player who has just arrived there should cut into the circle somewhere.\n\nWhen each player, except the first one to arrive, arrives at the place, the player gets comfort equal to the smaller of the friendliness of the clockwise adjacent player and that of the counter-clockwise adjacent player. The first player to arrive there gets the comfort of 0.\n\nWhat is the maximum total comfort the N players can get by optimally choosing the order of arrivals and the positions in the circle to cut into?\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq A_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 \\dots A_N\n\nOutput\n\nPrint the maximum total comfort the N players can get.\n\nSample Input 1\n\n4\n2 2 1 3\n\nSample Output 1\n\n7\n\nBy arriving at the place in the order Player 4, 2, 1, 3, and cutting into the circle as shown in the figure, they can get the total comfort of 7.\n\nThey cannot get the total comfort greater than 7, so the answer is 7.\n\nSample Input 2\n\n7\n1 1 1 1 1 1 1\n\nSample Output 2\n\n6", "sample_input": "4\n2 2 1 3\n"}, "reference_outputs": ["7\n"], "source_document_id": "p02615", "source_text": "Score: 400 points\n\nProblem Statement\n\nQuickly after finishing the tutorial of the online game ATChat, you have decided to visit a particular place with N-1 players who happen to be there. These N players, including you, are numbered 1 through N, and the friendliness of Player i is A_i.\n\nThe N players will arrive at the place one by one in some order. To make sure nobody gets lost, you have set the following rule: players who have already arrived there should form a circle, and a player who has just arrived there should cut into the circle somewhere.\n\nWhen each player, except the first one to arrive, arrives at the place, the player gets comfort equal to the smaller of the friendliness of the clockwise adjacent player and that of the counter-clockwise adjacent player. The first player to arrive there gets the comfort of 0.\n\nWhat is the maximum total comfort the N players can get by optimally choosing the order of arrivals and the positions in the circle to cut into?\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq A_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 \\dots A_N\n\nOutput\n\nPrint the maximum total comfort the N players can get.\n\nSample Input 1\n\n4\n2 2 1 3\n\nSample Output 1\n\n7\n\nBy arriving at the place in the order Player 4, 2, 1, 3, and cutting into the circle as shown in the figure, they can get the total comfort of 7.\n\nThey cannot get the total comfort greater than 7, so the answer is 7.\n\nSample Input 2\n\n7\n1 1 1 1 1 1 1\n\nSample Output 2\n\n6", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1470, "cpu_time_ms": 51, "memory_kb": 5208}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s379690414", "group_id": "codeNet:p02616", "input_text": "#define _USE_MATH_DEFINES\n#include <bits/stdc++.h>\nusing namespace std;\n\n//template\n#define rep(i,a,b) for(int i=(int)(a);i<(int)(b);i++)\n#define ALL(v) (v).begin(),(v).end()\ntypedef long long int ll;\nconst int inf = 0x3fffffff; const ll INF = 0x1fffffffffffffff; const double eps=1e-12;\ntemplate<typename T>inline bool chmax(T& a,T b){if(a<b){a=b;return 1;}return 0;}\ntemplate<typename T>inline bool chmin(T& a,T b){if(a>b){a=b;return 1;}return 0;}\n//end\n\ntemplate<unsigned mod=1000000007>struct fp {\n   int v; static unsigned get_mod(){return mod;}\n   int inv() const{\n      int tmp,a=v,b=mod,x=1,y=0;\n      while(b)tmp=a/b,a-=tmp*b,swap(a,b),x-=tmp*y,swap(x,y);\n      if(x<0){x+=mod;} return x;\n   }\n   fp():v(0){}\n   fp(ll x):v(x>=0?x%mod:mod+(x%mod)){}\n   fp operator-()const{return fp(-v);}\n   fp pow(ll t){fp res=1,b=*this; while(t){if(t&1)res*=b;b*=b;t>>=1;} return res;}\n   fp& operator+=(const fp& x){if((v+=x.v)>=(int)mod)v-=mod; return *this;}\n   fp& operator-=(const fp& x){if((v+=mod-x.v)>=(int)mod)v-=mod; return *this;}\n   fp& operator*=(const fp& x){v=ll(v)*x.v%mod; return *this;}\n   fp& operator/=(const fp& x){v=ll(v)*x.inv()%mod; return *this;}\n   fp operator+(const fp& x)const{return fp(*this)+=x;}\n   fp operator-(const fp& x)const{return fp(*this)-=x;}\n   fp operator*(const fp& x)const{return fp(*this)*=x;}\n   fp operator/(const fp& x)const{return fp(*this)/=x;}\n   bool operator==(const fp& x)const{return v==x.v;}\n   bool operator!=(const fp& x)const{return v!=x.v;}\n}; using Fp=fp<>;\n\nint main(){\n   int n,k; cin>>n>>k;\n   vector<int> a(n);\n   rep(i,0,n)cin>>a[i];\n   sort(ALL(a));\n   if(a.back()<0 and k%2==1){\n      Fp res=1;\n      rep(i,n-k,n)res*=a[i];\n      cout<<res.v<<endl; return 0;\n   }\n   vector<int> pos,neg;\n   rep(i,0,n){\n      if(a[i]>=0)pos.push_back(a[i]);\n      else neg.push_back(-a[i]);\n   }\n   sort(ALL(pos),greater<int>());\n   sort(ALL(neg),greater<int>());\n   Fp res=1;\n   int pi=0,ni=0;\n   while(k){\n      if(k==1){\n         res*=pos[pi]; k--;\n         continue;\n      }\n      if(neg.size()-ni<=1){\n         res*=1LL*pos[pi]*pos[pi+1];\n         pi+=2; k-=2;\n      }\n      else if(pos.size()-pi==0){\n         res*=1LL*neg[ni]*neg[ni+1];\n         ni+=2; k-=2;\n      }\n      else{\n         ll P=1LL*pos[pi]*pos[pi+1];\n         ll Q=1LL*neg[ni]*neg[ni+1];\n         if(P<Q){\n            res*=Q; ni+=2; k-=2;\n         }\n         else{\n            res*=P; pi+=2; k-=2;\n         }\n      }\n   }\n   cout<<res.v<<endl;\n   return 0;\n}", "language": "C++", "metadata": {"date": 1599290496, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02616.html", "problem_id": "p02616", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02616/input.txt", "sample_output_relpath": "derived/input_output/data/p02616/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02616/C++/s379690414.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s379690414", "user_id": "u407614884"}, "prompt_components": {"gold_output": "12\n", "input_to_evaluate": "#define _USE_MATH_DEFINES\n#include <bits/stdc++.h>\nusing namespace std;\n\n//template\n#define rep(i,a,b) for(int i=(int)(a);i<(int)(b);i++)\n#define ALL(v) (v).begin(),(v).end()\ntypedef long long int ll;\nconst int inf = 0x3fffffff; const ll INF = 0x1fffffffffffffff; const double eps=1e-12;\ntemplate<typename T>inline bool chmax(T& a,T b){if(a<b){a=b;return 1;}return 0;}\ntemplate<typename T>inline bool chmin(T& a,T b){if(a>b){a=b;return 1;}return 0;}\n//end\n\ntemplate<unsigned mod=1000000007>struct fp {\n   int v; static unsigned get_mod(){return mod;}\n   int inv() const{\n      int tmp,a=v,b=mod,x=1,y=0;\n      while(b)tmp=a/b,a-=tmp*b,swap(a,b),x-=tmp*y,swap(x,y);\n      if(x<0){x+=mod;} return x;\n   }\n   fp():v(0){}\n   fp(ll x):v(x>=0?x%mod:mod+(x%mod)){}\n   fp operator-()const{return fp(-v);}\n   fp pow(ll t){fp res=1,b=*this; while(t){if(t&1)res*=b;b*=b;t>>=1;} return res;}\n   fp& operator+=(const fp& x){if((v+=x.v)>=(int)mod)v-=mod; return *this;}\n   fp& operator-=(const fp& x){if((v+=mod-x.v)>=(int)mod)v-=mod; return *this;}\n   fp& operator*=(const fp& x){v=ll(v)*x.v%mod; return *this;}\n   fp& operator/=(const fp& x){v=ll(v)*x.inv()%mod; return *this;}\n   fp operator+(const fp& x)const{return fp(*this)+=x;}\n   fp operator-(const fp& x)const{return fp(*this)-=x;}\n   fp operator*(const fp& x)const{return fp(*this)*=x;}\n   fp operator/(const fp& x)const{return fp(*this)/=x;}\n   bool operator==(const fp& x)const{return v==x.v;}\n   bool operator!=(const fp& x)const{return v!=x.v;}\n}; using Fp=fp<>;\n\nint main(){\n   int n,k; cin>>n>>k;\n   vector<int> a(n);\n   rep(i,0,n)cin>>a[i];\n   sort(ALL(a));\n   if(a.back()<0 and k%2==1){\n      Fp res=1;\n      rep(i,n-k,n)res*=a[i];\n      cout<<res.v<<endl; return 0;\n   }\n   vector<int> pos,neg;\n   rep(i,0,n){\n      if(a[i]>=0)pos.push_back(a[i]);\n      else neg.push_back(-a[i]);\n   }\n   sort(ALL(pos),greater<int>());\n   sort(ALL(neg),greater<int>());\n   Fp res=1;\n   int pi=0,ni=0;\n   while(k){\n      if(k==1){\n         res*=pos[pi]; k--;\n         continue;\n      }\n      if(neg.size()-ni<=1){\n         res*=1LL*pos[pi]*pos[pi+1];\n         pi+=2; k-=2;\n      }\n      else if(pos.size()-pi==0){\n         res*=1LL*neg[ni]*neg[ni+1];\n         ni+=2; k-=2;\n      }\n      else{\n         ll P=1LL*pos[pi]*pos[pi+1];\n         ll Q=1LL*neg[ni]*neg[ni+1];\n         if(P<Q){\n            res*=Q; ni+=2; k-=2;\n         }\n         else{\n            res*=P; pi+=2; k-=2;\n         }\n      }\n   }\n   cout<<res.v<<endl;\n   return 0;\n}", "problem_context": "Score : 500 points\n\nProblem Statement\n\nGiven are N integers A_1,\\ldots,A_N.\n\nWe will choose exactly K of these elements. Find the maximum possible product of the chosen elements.\n\nThen, print the maximum product modulo (10^9+7), using an integer between 0 and 10^9+6 (inclusive).\n\nConstraints\n\n1 \\leq K \\leq N \\leq 2\\times 10^5\n\n|A_i| \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nA_1 \\ldots A_N\n\nOutput\n\nPrint the maximum product modulo (10^9+7), using an integer between 0 and 10^9+6 (inclusive).\n\nSample Input 1\n\n4 2\n1 2 -3 -4\n\nSample Output 1\n\n12\n\nThe possible products of the two chosen elements are 2, -3, -4, -6, -8, and 12, so the maximum product is 12.\n\nSample Input 2\n\n4 3\n-1 -2 -3 -4\n\nSample Output 2\n\n1000000001\n\nThe possible products of the three chosen elements are -24, -12, -8, and -6, so the maximum product is -6.\n\nWe print this value modulo (10^9+7), that is, 1000000001.\n\nSample Input 3\n\n2 1\n-1 1000000000\n\nSample Output 3\n\n1000000000\n\nThe possible products of the one chosen element are -1 and 1000000000, so the maximum product is 1000000000.\n\nSample Input 4\n\n10 10\n1000000000 100000000 10000000 1000000 100000 10000 1000 100 10 1\n\nSample Output 4\n\n999983200\n\nBe sure to print the product modulo (10^9+7).", "sample_input": "4 2\n1 2 -3 -4\n"}, "reference_outputs": ["12\n"], "source_document_id": "p02616", "source_text": "Score : 500 points\n\nProblem Statement\n\nGiven are N integers A_1,\\ldots,A_N.\n\nWe will choose exactly K of these elements. Find the maximum possible product of the chosen elements.\n\nThen, print the maximum product modulo (10^9+7), using an integer between 0 and 10^9+6 (inclusive).\n\nConstraints\n\n1 \\leq K \\leq N \\leq 2\\times 10^5\n\n|A_i| \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nA_1 \\ldots A_N\n\nOutput\n\nPrint the maximum product modulo (10^9+7), using an integer between 0 and 10^9+6 (inclusive).\n\nSample Input 1\n\n4 2\n1 2 -3 -4\n\nSample Output 1\n\n12\n\nThe possible products of the two chosen elements are 2, -3, -4, -6, -8, and 12, so the maximum product is 12.\n\nSample Input 2\n\n4 3\n-1 -2 -3 -4\n\nSample Output 2\n\n1000000001\n\nThe possible products of the three chosen elements are -24, -12, -8, and -6, so the maximum product is -6.\n\nWe print this value modulo (10^9+7), that is, 1000000001.\n\nSample Input 3\n\n2 1\n-1 1000000000\n\nSample Output 3\n\n1000000000\n\nThe possible products of the one chosen element are -1 and 1000000000, so the maximum product is 1000000000.\n\nSample Input 4\n\n10 10\n1000000000 100000000 10000000 1000000 100000 10000 1000 100 10 1\n\nSample Output 4\n\n999983200\n\nBe sure to print the product modulo (10^9+7).", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2476, "cpu_time_ms": 90, "memory_kb": 5112}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s069864174", "group_id": "codeNet:p02616", "input_text": "#include<iostream>\n#include<math.h>\n#include<algorithm>\n#include<stdint.h>\n#include<vector>\n#include<deque>\n#include<stack>\n#include<functional>\n#include<string>\n#include<cstring>\n#include<time.h>\n#include<array>\n#include<iomanip>\n#include<list>\n#include<set>\n#include<unordered_map>\n#include<unordered_set>\n#include<random>\n#include<bitset>\n#include <queue>\n#include <map>\n\n\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing uint = unsigned int;\nusing ldouble = long double;\n\n\n//BDD,ZDD,kdtree, bdtree,bicalc, bolonoy, doloney, tree, chinesemod,segmenttree,daikusutora, saidairyuu, 2bugurahu, heirokenshutu, topologicalsort, kyourenketuseibun\n\n#define REP(i,a,b) for(int i = a; i < b; ++i)\n#define PRI(s) cout << s << endl\n#define PRIY PRI(\"Yes\")\n#define PRIN PRI(\"No\")\n\nll N, K;\nvector<ll> a;\nvector<ll> ap;\nvector<ll> am;\nll MOD = 1000000007;\n\nll mod(ll x) { return (x%MOD + MOD) % MOD; }\nint main() {\n\tcin >> N >> K;\n\ta.resize(N);\n\tREP(i,0, N) {\n\t\tcin >> a[i];\n\t\tif (a[i] >= 0)ap.push_back(a[i]);\n\t\telse am.push_back(a[i]);\n\t}\n\n\tbool minus = false;\n\tint ccc = 0;\n\twhile (ccc + 2 <= K && ccc + 2 <= am.size()) ccc += 2;\n\tif (ccc + ap.size() < K) minus = true;\n\tif (minus) {\n\t\tsort(a.begin(), a.end(), [](ll x, ll y) {return abs(x) < abs(y); });\n\t\tll ret = 1;\n\t\tREP(i, 0, K) ret = mod(ret * a[i]);\n\t\tPRI(ret);\n\t\treturn 0;\n\t}\n\tsort(ap.begin(), ap.end(), greater<ll>());\n\tsort(am.begin(), am.end(), less<ll>());\n\tvector<ll> pick(K);\n\tREP(i, 0, K) pick[i] = i < a.size() ? ap[i] : 0;\n\tsort(pick.begin(), pick.end(), less<ll>());\n\tfor (int i = 0; i + 1 < K && i + 1 < am.size(); i += 2) {\n\t\tif (pick[i] * pick[i + 1] < am[i] * am[i + 1]) {\n\t\t\tpick[i] = am[i];\n\t\t\tpick[i + 1] = am[i + 1];\n\t\t}\n\t\telse break;\n\t}\n\tll ret = 1;\n\tREP(i, 0, K) ret = mod(ret * pick[i]);\n\tPRI(ret);\n\treturn 0;\n}\n\n\n", "language": "C++", "metadata": {"date": 1598548810, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02616.html", "problem_id": "p02616", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02616/input.txt", "sample_output_relpath": "derived/input_output/data/p02616/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02616/C++/s069864174.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s069864174", "user_id": "u539145601"}, "prompt_components": {"gold_output": "12\n", "input_to_evaluate": "#include<iostream>\n#include<math.h>\n#include<algorithm>\n#include<stdint.h>\n#include<vector>\n#include<deque>\n#include<stack>\n#include<functional>\n#include<string>\n#include<cstring>\n#include<time.h>\n#include<array>\n#include<iomanip>\n#include<list>\n#include<set>\n#include<unordered_map>\n#include<unordered_set>\n#include<random>\n#include<bitset>\n#include <queue>\n#include <map>\n\n\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing uint = unsigned int;\nusing ldouble = long double;\n\n\n//BDD,ZDD,kdtree, bdtree,bicalc, bolonoy, doloney, tree, chinesemod,segmenttree,daikusutora, saidairyuu, 2bugurahu, heirokenshutu, topologicalsort, kyourenketuseibun\n\n#define REP(i,a,b) for(int i = a; i < b; ++i)\n#define PRI(s) cout << s << endl\n#define PRIY PRI(\"Yes\")\n#define PRIN PRI(\"No\")\n\nll N, K;\nvector<ll> a;\nvector<ll> ap;\nvector<ll> am;\nll MOD = 1000000007;\n\nll mod(ll x) { return (x%MOD + MOD) % MOD; }\nint main() {\n\tcin >> N >> K;\n\ta.resize(N);\n\tREP(i,0, N) {\n\t\tcin >> a[i];\n\t\tif (a[i] >= 0)ap.push_back(a[i]);\n\t\telse am.push_back(a[i]);\n\t}\n\n\tbool minus = false;\n\tint ccc = 0;\n\twhile (ccc + 2 <= K && ccc + 2 <= am.size()) ccc += 2;\n\tif (ccc + ap.size() < K) minus = true;\n\tif (minus) {\n\t\tsort(a.begin(), a.end(), [](ll x, ll y) {return abs(x) < abs(y); });\n\t\tll ret = 1;\n\t\tREP(i, 0, K) ret = mod(ret * a[i]);\n\t\tPRI(ret);\n\t\treturn 0;\n\t}\n\tsort(ap.begin(), ap.end(), greater<ll>());\n\tsort(am.begin(), am.end(), less<ll>());\n\tvector<ll> pick(K);\n\tREP(i, 0, K) pick[i] = i < a.size() ? ap[i] : 0;\n\tsort(pick.begin(), pick.end(), less<ll>());\n\tfor (int i = 0; i + 1 < K && i + 1 < am.size(); i += 2) {\n\t\tif (pick[i] * pick[i + 1] < am[i] * am[i + 1]) {\n\t\t\tpick[i] = am[i];\n\t\t\tpick[i + 1] = am[i + 1];\n\t\t}\n\t\telse break;\n\t}\n\tll ret = 1;\n\tREP(i, 0, K) ret = mod(ret * pick[i]);\n\tPRI(ret);\n\treturn 0;\n}\n\n\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nGiven are N integers A_1,\\ldots,A_N.\n\nWe will choose exactly K of these elements. Find the maximum possible product of the chosen elements.\n\nThen, print the maximum product modulo (10^9+7), using an integer between 0 and 10^9+6 (inclusive).\n\nConstraints\n\n1 \\leq K \\leq N \\leq 2\\times 10^5\n\n|A_i| \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nA_1 \\ldots A_N\n\nOutput\n\nPrint the maximum product modulo (10^9+7), using an integer between 0 and 10^9+6 (inclusive).\n\nSample Input 1\n\n4 2\n1 2 -3 -4\n\nSample Output 1\n\n12\n\nThe possible products of the two chosen elements are 2, -3, -4, -6, -8, and 12, so the maximum product is 12.\n\nSample Input 2\n\n4 3\n-1 -2 -3 -4\n\nSample Output 2\n\n1000000001\n\nThe possible products of the three chosen elements are -24, -12, -8, and -6, so the maximum product is -6.\n\nWe print this value modulo (10^9+7), that is, 1000000001.\n\nSample Input 3\n\n2 1\n-1 1000000000\n\nSample Output 3\n\n1000000000\n\nThe possible products of the one chosen element are -1 and 1000000000, so the maximum product is 1000000000.\n\nSample Input 4\n\n10 10\n1000000000 100000000 10000000 1000000 100000 10000 1000 100 10 1\n\nSample Output 4\n\n999983200\n\nBe sure to print the product modulo (10^9+7).", "sample_input": "4 2\n1 2 -3 -4\n"}, "reference_outputs": ["12\n"], "source_document_id": "p02616", "source_text": "Score : 500 points\n\nProblem Statement\n\nGiven are N integers A_1,\\ldots,A_N.\n\nWe will choose exactly K of these elements. Find the maximum possible product of the chosen elements.\n\nThen, print the maximum product modulo (10^9+7), using an integer between 0 and 10^9+6 (inclusive).\n\nConstraints\n\n1 \\leq K \\leq N \\leq 2\\times 10^5\n\n|A_i| \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nA_1 \\ldots A_N\n\nOutput\n\nPrint the maximum product modulo (10^9+7), using an integer between 0 and 10^9+6 (inclusive).\n\nSample Input 1\n\n4 2\n1 2 -3 -4\n\nSample Output 1\n\n12\n\nThe possible products of the two chosen elements are 2, -3, -4, -6, -8, and 12, so the maximum product is 12.\n\nSample Input 2\n\n4 3\n-1 -2 -3 -4\n\nSample Output 2\n\n1000000001\n\nThe possible products of the three chosen elements are -24, -12, -8, and -6, so the maximum product is -6.\n\nWe print this value modulo (10^9+7), that is, 1000000001.\n\nSample Input 3\n\n2 1\n-1 1000000000\n\nSample Output 3\n\n1000000000\n\nThe possible products of the one chosen element are -1 and 1000000000, so the maximum product is 1000000000.\n\nSample Input 4\n\n10 10\n1000000000 100000000 10000000 1000000 100000 10000 1000 100 10 1\n\nSample Output 4\n\n999983200\n\nBe sure to print the product modulo (10^9+7).", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1817, "cpu_time_ms": 174, "memory_kb": 8240}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s544015197", "group_id": "codeNet:p02616", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nint a[100005];\nint zheng[100005];\nint ffu[100005];\nconst long long mod=1e9+7;\nbool cmp(int a,int b){\n    return abs(a)>abs(b);\n}\n\nint n,k;\nint main()\n{\n    scanf(\"%d%d\",&n,&k);\n    int s1=0,s2=0,kk=k;\n    for(int i=0;i<n;i++)\n\t{\n        scanf(\"%d\",&a[i]);\n        if(a[i]>0){\n           zheng[s1]=a[i];s1++;\n\t\t   }\n        if(a[i]<0){\n           ffu[s2]=a[i];s2++;\n\t\t   }\n    }\n    sort(zheng,zheng+s1,cmp);\n    sort(ffu,ffu+s2,cmp);\n    long long ans=1;\n    int ss1=0,ss2=0;\n    while(true)\n\t{\n        if(k==0)\n           break;\n        if(abs(zheng[ss1])>abs(ffu[ss2]))\n\t\t{\n            ans=(ans*zheng[ss1])%mod;\n            ss1++;\n            k--;\n        }\n        else\n\t\t{\n            ans=(ans*ffu[ss2])%mod;\n            ss2++;\n            k--;\n        }\n    }\n    if(ans>0){\n    printf(\"%lld\\n\",ans%mod);\n    return 0;\n    }\n     if(ans>0){\n    printf(\"%lld\\n\",ans%mod);\n    return 0;\n    }\n    if(ans<0&&s1>0)\n\t{\n        long long ans1=1;\n        if(ss1<s1)\n        ans1=(ans/ffu[ss2-1])*zheng[ss1]%mod;\n        if(ss2<s2)\n        ans=(ans/zheng[ss1-1])*ffu[ss2]%mod;\n        printf(\"%lld\",max(ans1,ans)%mod);\n        return 0;\n    }\n    if(ans<0&&s1==0)\n\t{\n        sort(ffu,ffu+s2);\n        long long ans2=1;\n        for(int i=s2-1;i>=0;i--)\n            ans2=(ffu[i]*ans2%mod);\n        printf(\"%lld\",ans2%mod);\n    }\n    return 0;\n}\n\n ", "language": "C++", "metadata": {"date": 1594993018, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02616.html", "problem_id": "p02616", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02616/input.txt", "sample_output_relpath": "derived/input_output/data/p02616/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02616/C++/s544015197.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s544015197", "user_id": "u018679195"}, "prompt_components": {"gold_output": "12\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nint a[100005];\nint zheng[100005];\nint ffu[100005];\nconst long long mod=1e9+7;\nbool cmp(int a,int b){\n    return abs(a)>abs(b);\n}\n\nint n,k;\nint main()\n{\n    scanf(\"%d%d\",&n,&k);\n    int s1=0,s2=0,kk=k;\n    for(int i=0;i<n;i++)\n\t{\n        scanf(\"%d\",&a[i]);\n        if(a[i]>0){\n           zheng[s1]=a[i];s1++;\n\t\t   }\n        if(a[i]<0){\n           ffu[s2]=a[i];s2++;\n\t\t   }\n    }\n    sort(zheng,zheng+s1,cmp);\n    sort(ffu,ffu+s2,cmp);\n    long long ans=1;\n    int ss1=0,ss2=0;\n    while(true)\n\t{\n        if(k==0)\n           break;\n        if(abs(zheng[ss1])>abs(ffu[ss2]))\n\t\t{\n            ans=(ans*zheng[ss1])%mod;\n            ss1++;\n            k--;\n        }\n        else\n\t\t{\n            ans=(ans*ffu[ss2])%mod;\n            ss2++;\n            k--;\n        }\n    }\n    if(ans>0){\n    printf(\"%lld\\n\",ans%mod);\n    return 0;\n    }\n     if(ans>0){\n    printf(\"%lld\\n\",ans%mod);\n    return 0;\n    }\n    if(ans<0&&s1>0)\n\t{\n        long long ans1=1;\n        if(ss1<s1)\n        ans1=(ans/ffu[ss2-1])*zheng[ss1]%mod;\n        if(ss2<s2)\n        ans=(ans/zheng[ss1-1])*ffu[ss2]%mod;\n        printf(\"%lld\",max(ans1,ans)%mod);\n        return 0;\n    }\n    if(ans<0&&s1==0)\n\t{\n        sort(ffu,ffu+s2);\n        long long ans2=1;\n        for(int i=s2-1;i>=0;i--)\n            ans2=(ffu[i]*ans2%mod);\n        printf(\"%lld\",ans2%mod);\n    }\n    return 0;\n}\n\n ", "problem_context": "Score : 500 points\n\nProblem Statement\n\nGiven are N integers A_1,\\ldots,A_N.\n\nWe will choose exactly K of these elements. Find the maximum possible product of the chosen elements.\n\nThen, print the maximum product modulo (10^9+7), using an integer between 0 and 10^9+6 (inclusive).\n\nConstraints\n\n1 \\leq K \\leq N \\leq 2\\times 10^5\n\n|A_i| \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nA_1 \\ldots A_N\n\nOutput\n\nPrint the maximum product modulo (10^9+7), using an integer between 0 and 10^9+6 (inclusive).\n\nSample Input 1\n\n4 2\n1 2 -3 -4\n\nSample Output 1\n\n12\n\nThe possible products of the two chosen elements are 2, -3, -4, -6, -8, and 12, so the maximum product is 12.\n\nSample Input 2\n\n4 3\n-1 -2 -3 -4\n\nSample Output 2\n\n1000000001\n\nThe possible products of the three chosen elements are -24, -12, -8, and -6, so the maximum product is -6.\n\nWe print this value modulo (10^9+7), that is, 1000000001.\n\nSample Input 3\n\n2 1\n-1 1000000000\n\nSample Output 3\n\n1000000000\n\nThe possible products of the one chosen element are -1 and 1000000000, so the maximum product is 1000000000.\n\nSample Input 4\n\n10 10\n1000000000 100000000 10000000 1000000 100000 10000 1000 100 10 1\n\nSample Output 4\n\n999983200\n\nBe sure to print the product modulo (10^9+7).", "sample_input": "4 2\n1 2 -3 -4\n"}, "reference_outputs": ["12\n"], "source_document_id": "p02616", "source_text": "Score : 500 points\n\nProblem Statement\n\nGiven are N integers A_1,\\ldots,A_N.\n\nWe will choose exactly K of these elements. Find the maximum possible product of the chosen elements.\n\nThen, print the maximum product modulo (10^9+7), using an integer between 0 and 10^9+6 (inclusive).\n\nConstraints\n\n1 \\leq K \\leq N \\leq 2\\times 10^5\n\n|A_i| \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nA_1 \\ldots A_N\n\nOutput\n\nPrint the maximum product modulo (10^9+7), using an integer between 0 and 10^9+6 (inclusive).\n\nSample Input 1\n\n4 2\n1 2 -3 -4\n\nSample Output 1\n\n12\n\nThe possible products of the two chosen elements are 2, -3, -4, -6, -8, and 12, so the maximum product is 12.\n\nSample Input 2\n\n4 3\n-1 -2 -3 -4\n\nSample Output 2\n\n1000000001\n\nThe possible products of the three chosen elements are -24, -12, -8, and -6, so the maximum product is -6.\n\nWe print this value modulo (10^9+7), that is, 1000000001.\n\nSample Input 3\n\n2 1\n-1 1000000000\n\nSample Output 3\n\n1000000000\n\nThe possible products of the one chosen element are -1 and 1000000000, so the maximum product is 1000000000.\n\nSample Input 4\n\n10 10\n1000000000 100000000 10000000 1000000 100000 10000 1000 100 10 1\n\nSample Output 4\n\n999983200\n\nBe sure to print the product modulo (10^9+7).", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1387, "cpu_time_ms": 120, "memory_kb": 4544}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s900963243", "group_id": "codeNet:p02616", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nusing LL = long long;\nusing LD = long double;\nusing PII = pair<int, int>;\nusing PLI = pair<long long, int>;\nusing PLL = pair<long long, long long>;\nusing TI = tuple<int, int, int>;\nmt19937 mrand(random_device{}());\nint rnd(int x) { return mrand() % x; }\ntemplate<class A, class B> ostream& operator <<(ostream& out, const pair<A, B> &p) {\n    return out << \"(\" << p.first << \", \" << p.second << \")\";\n}\ntemplate <typename T, size_t N>\nostream& operator <<(ostream& out, const array<T, N>& a) {\n    out << \"[\"; bool first = true;\n    for (auto& v : a) { out << (first ? \"\" : \", \"); out << v; first = 0;} out << \"]\";\n    return out;\n}\ntemplate <typename T>\nostream& operator <<(ostream& out, const vector<T>& a) {\n    out << \"[\"; bool first = true;\n    for (auto& v : a) { out << (first ? \"\" : \", \"); out << v; first = 0;} out << \"]\";\n    return out;\n}\ntemplate <typename T>\nostream& operator <<(ostream& out, const deque<T>& a) {\n    out << \"[\"; bool first = true;\n    for (auto& v : a) { out << (first ? \"\" : \", \"); out << v; first = 0;} out << \"]\";\n    return out;\n}\ntemplate <typename T, class Cmp>\nostream& operator <<(ostream& out, const set<T, Cmp>& a) {\n    out << \"{\"; bool first = true;\n    for (auto& v : a) { out << (first ? \"\" : \", \"); out << v; first = 0;} out << \"}\";\n    return out;\n}\ntemplate <typename T>\nostream& operator <<(ostream& out, const unordered_set<T>& a) {\n    out << \"{\"; bool first = true;\n    for (auto& v : a) { out << (first ? \"\" : \", \"); out << v; first = 0;} out << \"}\";\n    return out;\n}\ntemplate <typename U, typename T, class Cmp>\nostream& operator <<(ostream& out, const map<U, T, Cmp>& a) {\n    out << \"{\"; bool first = true;\n    for (auto& p : a) { out << (first ? \"\" : \", \"); out << p.first << \":\" << p.second; first = 0;} out << \"}\";\n    return out;\n}\ntemplate<class T> inline void YES(T condition) { \n    if(condition) cout << \"YES\" << '\\n';\n    else cout << \"NO\" << '\\n';\n}\ntemplate<class T> inline void Yes(T condition) {\n    if(condition) cout << \"Yes\" << '\\n';\n    else cout << \"No\" << '\\n';\n}\ntemplate<class T> T gcd(T a, T b) {\n    while (b) {\n        T tmp = b;\n        b = a % b;\n        a = tmp;\n    }\n    return a;\n}\ntemplate<class T> T lcm(T a, T b){\n    return a / gcd(a, b) * b;\n}\n\n#define trace(...) __f(#__VA_ARGS__, __VA_ARGS__)\ntemplate <typename Arg1>\nvoid __f(const char* name, Arg1&& arg1){\n    cerr << name << \": \" << arg1 << endl;\n}\ntemplate <typename Arg1, typename... Args>\nvoid __f(const char* names, Arg1&& arg1, Args&&... args){\n    const char* comma = strchr(names + 1, ',');\n    cerr.write(names, comma - names) << \": \" << arg1 << \" |\";\n    __f(comma + 1, args...);\n}\n\nlong long qpow(long long a, long long b, int MOD) {\n    if (b == 0) return 1;\n    long long res = 1;\n    while (b) {\n        if (b & 1) res = (res * a) % MOD;\n        a = (a * a) % MOD;\n        b >>= 1;\n    }\n    return res;\n}\n\nconst int MOD = 1e9 + 7;\nconst int maxn = 2e6;\nint fac[maxn + 5];\nint invfac[maxn + 5];\nvoid init() {\n    fac[0] = 1;\n    for (int i = 1; i <= maxn; i++) fac[i] = 1LL * fac[i - 1] * i % MOD;\n    invfac[maxn] = (int)(qpow(fac[maxn], MOD - 2, MOD));\n    for (int i = maxn - 1; i >= 0; i--) invfac[i] = 1LL * invfac[i + 1] * (i + 1) % MOD;\n}\nint C(int n, int k) {\n    assert(0 <= k && n >= k);\n    int tmp = (int)(1LL * invfac[k] * invfac[n - k] % MOD);\n    return (int)(1LL * fac[n] * tmp % MOD);\n}\n\nint main() {\n    cin.tie(nullptr);\n    ios::sync_with_stdio(false);\n\n    int n, k;\n    cin >> n >> k;\n    vector<LL> a(n), pos, zero, neg;\n    for (int i = 0; i < n; i++) {\n        cin >> a[i];\n        if (a[i] > 0) {\n            pos.push_back(a[i]);\n        } else if (a[i] == 0) {\n            zero.push_back(a[i]);\n        } else {\n            neg.push_back(a[i]);\n        }\n    }\n    sort(pos.begin(), pos.end());\n    sort(neg.begin(), neg.end());\n    reverse(neg.begin(), neg.end());\n    int pcnt = pos.size(), zcnt = zero.size(), ncnt = neg.size();\n    LL ALL = 1;\n    for (auto& v: a) ALL = (ALL * v) % MOD;\n    ALL = (ALL + MOD) % MOD;\n    if (k == 1) {\n        LL ans = *max_element(a.begin(), a.end()) % MOD;\n        cout << (ans + MOD) % MOD << '\\n';\n        return 0;\n    }\n    if (k == pcnt + zcnt + ncnt) {\n        cout << ALL << '\\n';\n        return 0;\n    }\n    if (k > pcnt + ncnt) {\n        cout << 0 << '\\n';\n        return 0;\n    } else if (pcnt == 0) {\n        if (k & 1) {\n            if (zcnt) { cout << 0 << '\\n'; return 0; }\n            LL now = 1;\n            for (int i = 0; i < k; i++) now = (now * neg[i]) % MOD;\n            cout << (now + MOD) % MOD << '\\n';\n            return 0;\n        } else {\n            if (k > ncnt) { cout << 0 << '\\n'; return 0; }\n            LL now = 1;\n            for (int i = ncnt - 1; i; i--) now = (now * neg[i]) % MOD;\n            cout << (now + MOD) % MOD << '\\n';\n            return 0;\n        }\n    } else {\n        LL now = 1;\n        int i = pos.size() - 1, j = neg.size() - 1;\n        for (; k; ) {\n            if (k == 1) {\n                if (i >= 0) now = now * pos[i--] % MOD;\n                else if (j >= 1) {\n                    now = now * qpow(a[0], MOD - 2, MOD) % MOD;\n                    now = now * abs(neg[j--]) % MOD;\n                    now = now * abs(neg[j--]) % MOD;\n                } else {\n                    now = now * a[j] % MOD;\n                }\n                k--;\n            } else {\n                LL P = 0, N = 0;\n                if (i >= 1) P = pos[i] * pos[i - 1];\n                else if (i == 0) P = pos[i];\n                if (j >= 1) N = neg[j] * neg[j - 1];\n                else if (j == 0) N = neg[j];\n                if (P > N) {\n                    now = now * (P % MOD) % MOD;\n                    k -= 1 + (i > 0);\n                    i -= 1 + (i > 0);\n                } else {\n                    now = now * (N % MOD) % MOD;\n                    k -= 1 + (j > 0);\n                    j -= 1 + (j > 0);\n                }\n            }\n        }\n\n        cout << (now + MOD) % MOD << '\\n';\n    }\n\n\n\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1594307358, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02616.html", "problem_id": "p02616", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02616/input.txt", "sample_output_relpath": "derived/input_output/data/p02616/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02616/C++/s900963243.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s900963243", "user_id": "u283661333"}, "prompt_components": {"gold_output": "12\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nusing LL = long long;\nusing LD = long double;\nusing PII = pair<int, int>;\nusing PLI = pair<long long, int>;\nusing PLL = pair<long long, long long>;\nusing TI = tuple<int, int, int>;\nmt19937 mrand(random_device{}());\nint rnd(int x) { return mrand() % x; }\ntemplate<class A, class B> ostream& operator <<(ostream& out, const pair<A, B> &p) {\n    return out << \"(\" << p.first << \", \" << p.second << \")\";\n}\ntemplate <typename T, size_t N>\nostream& operator <<(ostream& out, const array<T, N>& a) {\n    out << \"[\"; bool first = true;\n    for (auto& v : a) { out << (first ? \"\" : \", \"); out << v; first = 0;} out << \"]\";\n    return out;\n}\ntemplate <typename T>\nostream& operator <<(ostream& out, const vector<T>& a) {\n    out << \"[\"; bool first = true;\n    for (auto& v : a) { out << (first ? \"\" : \", \"); out << v; first = 0;} out << \"]\";\n    return out;\n}\ntemplate <typename T>\nostream& operator <<(ostream& out, const deque<T>& a) {\n    out << \"[\"; bool first = true;\n    for (auto& v : a) { out << (first ? \"\" : \", \"); out << v; first = 0;} out << \"]\";\n    return out;\n}\ntemplate <typename T, class Cmp>\nostream& operator <<(ostream& out, const set<T, Cmp>& a) {\n    out << \"{\"; bool first = true;\n    for (auto& v : a) { out << (first ? \"\" : \", \"); out << v; first = 0;} out << \"}\";\n    return out;\n}\ntemplate <typename T>\nostream& operator <<(ostream& out, const unordered_set<T>& a) {\n    out << \"{\"; bool first = true;\n    for (auto& v : a) { out << (first ? \"\" : \", \"); out << v; first = 0;} out << \"}\";\n    return out;\n}\ntemplate <typename U, typename T, class Cmp>\nostream& operator <<(ostream& out, const map<U, T, Cmp>& a) {\n    out << \"{\"; bool first = true;\n    for (auto& p : a) { out << (first ? \"\" : \", \"); out << p.first << \":\" << p.second; first = 0;} out << \"}\";\n    return out;\n}\ntemplate<class T> inline void YES(T condition) { \n    if(condition) cout << \"YES\" << '\\n';\n    else cout << \"NO\" << '\\n';\n}\ntemplate<class T> inline void Yes(T condition) {\n    if(condition) cout << \"Yes\" << '\\n';\n    else cout << \"No\" << '\\n';\n}\ntemplate<class T> T gcd(T a, T b) {\n    while (b) {\n        T tmp = b;\n        b = a % b;\n        a = tmp;\n    }\n    return a;\n}\ntemplate<class T> T lcm(T a, T b){\n    return a / gcd(a, b) * b;\n}\n\n#define trace(...) __f(#__VA_ARGS__, __VA_ARGS__)\ntemplate <typename Arg1>\nvoid __f(const char* name, Arg1&& arg1){\n    cerr << name << \": \" << arg1 << endl;\n}\ntemplate <typename Arg1, typename... Args>\nvoid __f(const char* names, Arg1&& arg1, Args&&... args){\n    const char* comma = strchr(names + 1, ',');\n    cerr.write(names, comma - names) << \": \" << arg1 << \" |\";\n    __f(comma + 1, args...);\n}\n\nlong long qpow(long long a, long long b, int MOD) {\n    if (b == 0) return 1;\n    long long res = 1;\n    while (b) {\n        if (b & 1) res = (res * a) % MOD;\n        a = (a * a) % MOD;\n        b >>= 1;\n    }\n    return res;\n}\n\nconst int MOD = 1e9 + 7;\nconst int maxn = 2e6;\nint fac[maxn + 5];\nint invfac[maxn + 5];\nvoid init() {\n    fac[0] = 1;\n    for (int i = 1; i <= maxn; i++) fac[i] = 1LL * fac[i - 1] * i % MOD;\n    invfac[maxn] = (int)(qpow(fac[maxn], MOD - 2, MOD));\n    for (int i = maxn - 1; i >= 0; i--) invfac[i] = 1LL * invfac[i + 1] * (i + 1) % MOD;\n}\nint C(int n, int k) {\n    assert(0 <= k && n >= k);\n    int tmp = (int)(1LL * invfac[k] * invfac[n - k] % MOD);\n    return (int)(1LL * fac[n] * tmp % MOD);\n}\n\nint main() {\n    cin.tie(nullptr);\n    ios::sync_with_stdio(false);\n\n    int n, k;\n    cin >> n >> k;\n    vector<LL> a(n), pos, zero, neg;\n    for (int i = 0; i < n; i++) {\n        cin >> a[i];\n        if (a[i] > 0) {\n            pos.push_back(a[i]);\n        } else if (a[i] == 0) {\n            zero.push_back(a[i]);\n        } else {\n            neg.push_back(a[i]);\n        }\n    }\n    sort(pos.begin(), pos.end());\n    sort(neg.begin(), neg.end());\n    reverse(neg.begin(), neg.end());\n    int pcnt = pos.size(), zcnt = zero.size(), ncnt = neg.size();\n    LL ALL = 1;\n    for (auto& v: a) ALL = (ALL * v) % MOD;\n    ALL = (ALL + MOD) % MOD;\n    if (k == 1) {\n        LL ans = *max_element(a.begin(), a.end()) % MOD;\n        cout << (ans + MOD) % MOD << '\\n';\n        return 0;\n    }\n    if (k == pcnt + zcnt + ncnt) {\n        cout << ALL << '\\n';\n        return 0;\n    }\n    if (k > pcnt + ncnt) {\n        cout << 0 << '\\n';\n        return 0;\n    } else if (pcnt == 0) {\n        if (k & 1) {\n            if (zcnt) { cout << 0 << '\\n'; return 0; }\n            LL now = 1;\n            for (int i = 0; i < k; i++) now = (now * neg[i]) % MOD;\n            cout << (now + MOD) % MOD << '\\n';\n            return 0;\n        } else {\n            if (k > ncnt) { cout << 0 << '\\n'; return 0; }\n            LL now = 1;\n            for (int i = ncnt - 1; i; i--) now = (now * neg[i]) % MOD;\n            cout << (now + MOD) % MOD << '\\n';\n            return 0;\n        }\n    } else {\n        LL now = 1;\n        int i = pos.size() - 1, j = neg.size() - 1;\n        for (; k; ) {\n            if (k == 1) {\n                if (i >= 0) now = now * pos[i--] % MOD;\n                else if (j >= 1) {\n                    now = now * qpow(a[0], MOD - 2, MOD) % MOD;\n                    now = now * abs(neg[j--]) % MOD;\n                    now = now * abs(neg[j--]) % MOD;\n                } else {\n                    now = now * a[j] % MOD;\n                }\n                k--;\n            } else {\n                LL P = 0, N = 0;\n                if (i >= 1) P = pos[i] * pos[i - 1];\n                else if (i == 0) P = pos[i];\n                if (j >= 1) N = neg[j] * neg[j - 1];\n                else if (j == 0) N = neg[j];\n                if (P > N) {\n                    now = now * (P % MOD) % MOD;\n                    k -= 1 + (i > 0);\n                    i -= 1 + (i > 0);\n                } else {\n                    now = now * (N % MOD) % MOD;\n                    k -= 1 + (j > 0);\n                    j -= 1 + (j > 0);\n                }\n            }\n        }\n\n        cout << (now + MOD) % MOD << '\\n';\n    }\n\n\n\n    return 0;\n}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nGiven are N integers A_1,\\ldots,A_N.\n\nWe will choose exactly K of these elements. Find the maximum possible product of the chosen elements.\n\nThen, print the maximum product modulo (10^9+7), using an integer between 0 and 10^9+6 (inclusive).\n\nConstraints\n\n1 \\leq K \\leq N \\leq 2\\times 10^5\n\n|A_i| \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nA_1 \\ldots A_N\n\nOutput\n\nPrint the maximum product modulo (10^9+7), using an integer between 0 and 10^9+6 (inclusive).\n\nSample Input 1\n\n4 2\n1 2 -3 -4\n\nSample Output 1\n\n12\n\nThe possible products of the two chosen elements are 2, -3, -4, -6, -8, and 12, so the maximum product is 12.\n\nSample Input 2\n\n4 3\n-1 -2 -3 -4\n\nSample Output 2\n\n1000000001\n\nThe possible products of the three chosen elements are -24, -12, -8, and -6, so the maximum product is -6.\n\nWe print this value modulo (10^9+7), that is, 1000000001.\n\nSample Input 3\n\n2 1\n-1 1000000000\n\nSample Output 3\n\n1000000000\n\nThe possible products of the one chosen element are -1 and 1000000000, so the maximum product is 1000000000.\n\nSample Input 4\n\n10 10\n1000000000 100000000 10000000 1000000 100000 10000 1000 100 10 1\n\nSample Output 4\n\n999983200\n\nBe sure to print the product modulo (10^9+7).", "sample_input": "4 2\n1 2 -3 -4\n"}, "reference_outputs": ["12\n"], "source_document_id": "p02616", "source_text": "Score : 500 points\n\nProblem Statement\n\nGiven are N integers A_1,\\ldots,A_N.\n\nWe will choose exactly K of these elements. Find the maximum possible product of the chosen elements.\n\nThen, print the maximum product modulo (10^9+7), using an integer between 0 and 10^9+6 (inclusive).\n\nConstraints\n\n1 \\leq K \\leq N \\leq 2\\times 10^5\n\n|A_i| \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nA_1 \\ldots A_N\n\nOutput\n\nPrint the maximum product modulo (10^9+7), using an integer between 0 and 10^9+6 (inclusive).\n\nSample Input 1\n\n4 2\n1 2 -3 -4\n\nSample Output 1\n\n12\n\nThe possible products of the two chosen elements are 2, -3, -4, -6, -8, and 12, so the maximum product is 12.\n\nSample Input 2\n\n4 3\n-1 -2 -3 -4\n\nSample Output 2\n\n1000000001\n\nThe possible products of the three chosen elements are -24, -12, -8, and -6, so the maximum product is -6.\n\nWe print this value modulo (10^9+7), that is, 1000000001.\n\nSample Input 3\n\n2 1\n-1 1000000000\n\nSample Output 3\n\n1000000000\n\nThe possible products of the one chosen element are -1 and 1000000000, so the maximum product is 1000000000.\n\nSample Input 4\n\n10 10\n1000000000 100000000 10000000 1000000 100000 10000 1000 100 10 1\n\nSample Output 4\n\n999983200\n\nBe sure to print the product modulo (10^9+7).", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 6040, "cpu_time_ms": 48, "memory_kb": 6920}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s772204069", "group_id": "codeNet:p02617", "input_text": "/*\n* welcome to my code!\n* ------------------------------------------\n* author : lynmisakura(twitter : @andoreiji11)\n*/\n\n#include<bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n\n#define REP(i,n) for(int i = 0;i < n;i++)\n#define all(x) x.begin(),x.end()\n#define dup(x,y) (x + y - 1)/y\n#define sz(v) (int)v.size()\n#define mp make_pair\n#define pb push_back\n#define eb emplace_back\n#define fi first\n#define se second\n\ntemplate<class T> bool chmin(T& a,T b){if(a>b){a=b;return 1;}else return false;}\ntemplate<class T> bool chmax(T& a,T b){if(a<b){a=b;return 1;}else return false;}\n\nint main(void){\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n\n    int N;\n    cin >> N;\n\n    ll ans = 0;\n    for(ll i = 0;i <= N - 1;i++){\n        ans += (i + 1) * (N - i);\n    }\n\n    REP(i,N - 1){\n\n       int u,v;cin >> u >> v;\n       if(u > v)swap(u,v);\n\n       ans -= u * (N + 1 - v);\n\n    }\n\n    cout << ans << '\\n';\n\n}\n", "language": "C++", "metadata": {"date": 1594058134, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02617.html", "problem_id": "p02617", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02617/input.txt", "sample_output_relpath": "derived/input_output/data/p02617/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02617/C++/s772204069.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s772204069", "user_id": "u426397594"}, "prompt_components": {"gold_output": "7\n", "input_to_evaluate": "/*\n* welcome to my code!\n* ------------------------------------------\n* author : lynmisakura(twitter : @andoreiji11)\n*/\n\n#include<bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\n\n#define REP(i,n) for(int i = 0;i < n;i++)\n#define all(x) x.begin(),x.end()\n#define dup(x,y) (x + y - 1)/y\n#define sz(v) (int)v.size()\n#define mp make_pair\n#define pb push_back\n#define eb emplace_back\n#define fi first\n#define se second\n\ntemplate<class T> bool chmin(T& a,T b){if(a>b){a=b;return 1;}else return false;}\ntemplate<class T> bool chmax(T& a,T b){if(a<b){a=b;return 1;}else return false;}\n\nint main(void){\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n\n    int N;\n    cin >> N;\n\n    ll ans = 0;\n    for(ll i = 0;i <= N - 1;i++){\n        ans += (i + 1) * (N - i);\n    }\n\n    REP(i,N - 1){\n\n       int u,v;cin >> u >> v;\n       if(u > v)swap(u,v);\n\n       ans -= u * (N + 1 - v);\n\n    }\n\n    cout << ans << '\\n';\n\n}\n", "problem_context": "Score : 600 points\n\nProblem Statement\n\nWe have a tree with N vertices and N-1 edges, respectively numbered 1, 2,\\cdots, N and 1, 2, \\cdots, N-1. Edge i connects Vertex u_i and v_i.\n\nFor integers L, R (1 \\leq L \\leq R \\leq N), let us define a function f(L, R) as follows:\n\nLet S be the set of the vertices numbered L through R. f(L, R) represents the number of connected components in the subgraph formed only from the vertex set S and the edges whose endpoints both belong to S.\n\nCompute \\sum_{L=1}^{N} \\sum_{R=L}^{N} f(L, R).\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq u_i, v_i \\leq N\n\nThe given graph is a tree.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nu_1 v_1\nu_2 v_2\n:\nu_{N-1} v_{N-1}\n\nOutput\n\nPrint \\sum_{L=1}^{N} \\sum_{R=L}^{N} f(L, R).\n\nSample Input 1\n\n3\n1 3\n2 3\n\nSample Output 1\n\n7\n\nWe have six possible pairs (L, R) as follows:\n\nFor L = 1, R = 1, S = \\{1\\} and we have 1 connected component.\n\nFor L = 1, R = 2, S = \\{1, 2\\} and we have 2 connected components.\n\nFor L = 1, R = 3, S = \\{1, 2, 3\\} and we have 1 connected component, since S contains both endpoints of each of the edges 1, 2.\n\nFor L = 2, R = 2, S = \\{2\\} and we have 1 connected component.\n\nFor L = 2, R = 3, S = \\{2, 3\\} and we have 1 connected component, since S contains both endpoints of Edge 2.\n\nFor L = 3, R = 3, S = \\{3\\} and we have 1 connected component.\n\nThe sum of these is 7.\n\nSample Input 2\n\n2\n1 2\n\nSample Output 2\n\n3\n\nSample Input 3\n\n10\n5 3\n5 7\n8 9\n1 9\n9 10\n8 4\n7 4\n6 10\n7 2\n\nSample Output 3\n\n113", "sample_input": "3\n1 3\n2 3\n"}, "reference_outputs": ["7\n"], "source_document_id": "p02617", "source_text": "Score : 600 points\n\nProblem Statement\n\nWe have a tree with N vertices and N-1 edges, respectively numbered 1, 2,\\cdots, N and 1, 2, \\cdots, N-1. Edge i connects Vertex u_i and v_i.\n\nFor integers L, R (1 \\leq L \\leq R \\leq N), let us define a function f(L, R) as follows:\n\nLet S be the set of the vertices numbered L through R. f(L, R) represents the number of connected components in the subgraph formed only from the vertex set S and the edges whose endpoints both belong to S.\n\nCompute \\sum_{L=1}^{N} \\sum_{R=L}^{N} f(L, R).\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq u_i, v_i \\leq N\n\nThe given graph is a tree.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nu_1 v_1\nu_2 v_2\n:\nu_{N-1} v_{N-1}\n\nOutput\n\nPrint \\sum_{L=1}^{N} \\sum_{R=L}^{N} f(L, R).\n\nSample Input 1\n\n3\n1 3\n2 3\n\nSample Output 1\n\n7\n\nWe have six possible pairs (L, R) as follows:\n\nFor L = 1, R = 1, S = \\{1\\} and we have 1 connected component.\n\nFor L = 1, R = 2, S = \\{1, 2\\} and we have 2 connected components.\n\nFor L = 1, R = 3, S = \\{1, 2, 3\\} and we have 1 connected component, since S contains both endpoints of each of the edges 1, 2.\n\nFor L = 2, R = 2, S = \\{2\\} and we have 1 connected component.\n\nFor L = 2, R = 3, S = \\{2, 3\\} and we have 1 connected component, since S contains both endpoints of Edge 2.\n\nFor L = 3, R = 3, S = \\{3\\} and we have 1 connected component.\n\nThe sum of these is 7.\n\nSample Input 2\n\n2\n1 2\n\nSample Output 2\n\n3\n\nSample Input 3\n\n10\n5 3\n5 7\n8 9\n1 9\n9 10\n8 4\n7 4\n6 10\n7 2\n\nSample Output 3\n\n113", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 916, "cpu_time_ms": 43, "memory_kb": 3544}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s226277304", "group_id": "codeNet:p02621", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n    int n;\n    cin>>n;\n    cout<<n+n*n+n*n*n<<endl;\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1593306167, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02621.html", "problem_id": "p02621", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02621/input.txt", "sample_output_relpath": "derived/input_output/data/p02621/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02621/C++/s226277304.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s226277304", "user_id": "u534673300"}, "prompt_components": {"gold_output": "14\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n    int n;\n    cin>>n;\n    cout<<n+n*n+n*n*n<<endl;\n    return 0;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nGiven an integer a as input, print the value a + a^2 + a^3.\n\nConstraints\n\n1 \\leq a \\leq 10\n\na is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\na\n\nOutput\n\nPrint the value a + a^2 + a^3 as an integer.\n\nSample Input 1\n\n2\n\nSample Output 1\n\n14\n\nWhen a = 2, we have a + a^2 + a^3 = 2 + 2^2 + 2^3 = 2 + 4 + 8 = 14.\n\nPrint the answer as an input. Outputs such as 14.0 will be judged as incorrect.\n\nSample Input 2\n\n10\n\nSample Output 2\n\n1110", "sample_input": "2\n"}, "reference_outputs": ["14\n"], "source_document_id": "p02621", "source_text": "Score : 100 points\n\nProblem Statement\n\nGiven an integer a as input, print the value a + a^2 + a^3.\n\nConstraints\n\n1 \\leq a \\leq 10\n\na is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\na\n\nOutput\n\nPrint the value a + a^2 + a^3 as an integer.\n\nSample Input 1\n\n2\n\nSample Output 1\n\n14\n\nWhen a = 2, we have a + a^2 + a^3 = 2 + 2^2 + 2^3 = 2 + 4 + 8 = 14.\n\nPrint the answer as an input. Outputs such as 14.0 will be judged as incorrect.\n\nSample Input 2\n\n10\n\nSample Output 2\n\n1110", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 126, "cpu_time_ms": 7, "memory_kb": 3592}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s684851336", "group_id": "codeNet:p02621", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nint main() {\n  int a;\n  cin >> a;\n  int ans = a;\n  ans += a * a;\n  ans += a * a * a;\n  cout << ans << endl;\n  return 0;\n}", "language": "C++", "metadata": {"date": 1593306050, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02621.html", "problem_id": "p02621", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02621/input.txt", "sample_output_relpath": "derived/input_output/data/p02621/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02621/C++/s684851336.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s684851336", "user_id": "u902387200"}, "prompt_components": {"gold_output": "14\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nint main() {\n  int a;\n  cin >> a;\n  int ans = a;\n  ans += a * a;\n  ans += a * a * a;\n  cout << ans << endl;\n  return 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nGiven an integer a as input, print the value a + a^2 + a^3.\n\nConstraints\n\n1 \\leq a \\leq 10\n\na is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\na\n\nOutput\n\nPrint the value a + a^2 + a^3 as an integer.\n\nSample Input 1\n\n2\n\nSample Output 1\n\n14\n\nWhen a = 2, we have a + a^2 + a^3 = 2 + 2^2 + 2^3 = 2 + 4 + 8 = 14.\n\nPrint the answer as an input. Outputs such as 14.0 will be judged as incorrect.\n\nSample Input 2\n\n10\n\nSample Output 2\n\n1110", "sample_input": "2\n"}, "reference_outputs": ["14\n"], "source_document_id": "p02621", "source_text": "Score : 100 points\n\nProblem Statement\n\nGiven an integer a as input, print the value a + a^2 + a^3.\n\nConstraints\n\n1 \\leq a \\leq 10\n\na is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\na\n\nOutput\n\nPrint the value a + a^2 + a^3 as an integer.\n\nSample Input 1\n\n2\n\nSample Output 1\n\n14\n\nWhen a = 2, we have a + a^2 + a^3 = 2 + 2^2 + 2^3 = 2 + 4 + 8 = 14.\n\nPrint the answer as an input. Outputs such as 14.0 will be judged as incorrect.\n\nSample Input 2\n\n10\n\nSample Output 2\n\n1110", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 190, "cpu_time_ms": 7, "memory_kb": 3632}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s336426749", "group_id": "codeNet:p02622", "input_text": "#include<bits/stdc++.h>\n\n#define all(n) n.begin(),n.end()\n#define ll long long\n\n#define pb push_back\n#define eb emplace_back\n#define endl \"\\n\"\n#define pll pair<ll,ll>\n\n#define ff first\n#define ss second\n\nusing namespace std;\nconst ll maxn=1e6+2;\nconst ll maxx=1e16;\nconst ll mod=998244353;\nconst ll mod1=998244353;\n\nvector<ll>  ans[maxn];\npll a[maxn];\nint main()\n{\n    ios_base::sync_with_stdio(false);\n    cin.tie(0);\n    cout.tie(0);\n    if (fopen(\"TEAMS.INP\",\"r\"))\n    {\n        freopen(\"TEAMS.INP\", \"r\", stdin);\n        freopen(\"TEAMS.OUT\", \"w\", stdout);\n    }\n   string s;\n    string t;\n     cin>>s>>t;\n      ll ans=0;\n      for (int i=0;i<s.length();i++)\n      {\n          if (s[i]!=t[i]) ans++;\n      }\n      cout <<ans;\n\n\n\n}\n", "language": "C++", "metadata": {"date": 1593306158, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02622.html", "problem_id": "p02622", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02622/input.txt", "sample_output_relpath": "derived/input_output/data/p02622/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02622/C++/s336426749.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s336426749", "user_id": "u401520167"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include<bits/stdc++.h>\n\n#define all(n) n.begin(),n.end()\n#define ll long long\n\n#define pb push_back\n#define eb emplace_back\n#define endl \"\\n\"\n#define pll pair<ll,ll>\n\n#define ff first\n#define ss second\n\nusing namespace std;\nconst ll maxn=1e6+2;\nconst ll maxx=1e16;\nconst ll mod=998244353;\nconst ll mod1=998244353;\n\nvector<ll>  ans[maxn];\npll a[maxn];\nint main()\n{\n    ios_base::sync_with_stdio(false);\n    cin.tie(0);\n    cout.tie(0);\n    if (fopen(\"TEAMS.INP\",\"r\"))\n    {\n        freopen(\"TEAMS.INP\", \"r\", stdin);\n        freopen(\"TEAMS.OUT\", \"w\", stdout);\n    }\n   string s;\n    string t;\n     cin>>s>>t;\n      ll ans=0;\n      for (int i=0;i<s.length();i++)\n      {\n          if (s[i]!=t[i]) ans++;\n      }\n      cout <<ans;\n\n\n\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nGiven are strings S and T. Consider changing S to T by repeating the operation below. Find the minimum number of operations required to do so.\n\nOperation: Choose one character of S and replace it with a different character.\n\nConstraints\n\nS and T have lengths between 1 and 2\\times 10^5 (inclusive).\n\nS and T consists of lowercase English letters.\n\nS and T have equal lengths.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\nT\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\ncupofcoffee\ncupofhottea\n\nSample Output 1\n\n4\n\nWe can achieve the objective in four operations, such as the following:\n\nFirst, replace the sixth character c with h.\n\nSecond, replace the eighth character f with t.\n\nThird, replace the ninth character f with t.\n\nFourth, replace the eleventh character e with a.\n\nSample Input 2\n\nabcde\nbcdea\n\nSample Output 2\n\n5\n\nSample Input 3\n\napple\napple\n\nSample Output 3\n\n0\n\nNo operations may be needed to achieve the objective.", "sample_input": "cupofcoffee\ncupofhottea\n"}, "reference_outputs": ["4\n"], "source_document_id": "p02622", "source_text": "Score : 200 points\n\nProblem Statement\n\nGiven are strings S and T. Consider changing S to T by repeating the operation below. Find the minimum number of operations required to do so.\n\nOperation: Choose one character of S and replace it with a different character.\n\nConstraints\n\nS and T have lengths between 1 and 2\\times 10^5 (inclusive).\n\nS and T consists of lowercase English letters.\n\nS and T have equal lengths.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\nT\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\ncupofcoffee\ncupofhottea\n\nSample Output 1\n\n4\n\nWe can achieve the objective in four operations, such as the following:\n\nFirst, replace the sixth character c with h.\n\nSecond, replace the eighth character f with t.\n\nThird, replace the ninth character f with t.\n\nFourth, replace the eleventh character e with a.\n\nSample Input 2\n\nabcde\nbcdea\n\nSample Output 2\n\n5\n\nSample Input 3\n\napple\napple\n\nSample Output 3\n\n0\n\nNo operations may be needed to achieve the objective.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 733, "cpu_time_ms": 33, "memory_kb": 27224}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s910287338", "group_id": "codeNet:p02627", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n  char c;\n  cin>>c;\n  int d=(int)c;\n  if(d>=65 && d<=90)\n  {\n    cout << 'A'<<'\\n';\n  }\n  if(d>=97 && d<=122)\n  {\n    cout << 'a'<<'\\n';\n  }\n}\n", "language": "C++", "metadata": {"date": 1592788664, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02627.html", "problem_id": "p02627", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02627/input.txt", "sample_output_relpath": "derived/input_output/data/p02627/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02627/C++/s910287338.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s910287338", "user_id": "u552937692"}, "prompt_components": {"gold_output": "A\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n  char c;\n  cin>>c;\n  int d=(int)c;\n  if(d>=65 && d<=90)\n  {\n    cout << 'A'<<'\\n';\n  }\n  if(d>=97 && d<=122)\n  {\n    cout << 'a'<<'\\n';\n  }\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nAn uppercase or lowercase English letter \\alpha will be given as input.\nIf \\alpha is uppercase, print A; if it is lowercase, print a.\n\nConstraints\n\n\\alpha is an uppercase (A - Z) or lowercase (a - z) English letter.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nα\n\nOutput\n\nIf \\alpha is uppercase, print A; if it is lowercase, print a.\n\nSample Input 1\n\nB\n\nSample Output 1\n\nA\n\nB is uppercase, so we should print A.\n\nSample Input 2\n\na\n\nSample Output 2\n\na\n\na is lowercase, so we should print a.", "sample_input": "B\n"}, "reference_outputs": ["A\n"], "source_document_id": "p02627", "source_text": "Score : 100 points\n\nProblem Statement\n\nAn uppercase or lowercase English letter \\alpha will be given as input.\nIf \\alpha is uppercase, print A; if it is lowercase, print a.\n\nConstraints\n\n\\alpha is an uppercase (A - Z) or lowercase (a - z) English letter.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nα\n\nOutput\n\nIf \\alpha is uppercase, print A; if it is lowercase, print a.\n\nSample Input 1\n\nB\n\nSample Output 1\n\nA\n\nB is uppercase, so we should print A.\n\nSample Input 2\n\na\n\nSample Output 2\n\na\n\na is lowercase, so we should print a.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 201, "cpu_time_ms": 8, "memory_kb": 3616}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s897910011", "group_id": "codeNet:p02627", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n#define ll long long\n\nint main() {\n    char c;\n    cin >> c;\n    if (c >= 'A' && c <= 'Z') cout << 'A' << endl;\n    else cout << 'a' << endl;\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1592787656, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02627.html", "problem_id": "p02627", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02627/input.txt", "sample_output_relpath": "derived/input_output/data/p02627/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02627/C++/s897910011.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s897910011", "user_id": "u548834738"}, "prompt_components": {"gold_output": "A\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n#define ll long long\n\nint main() {\n    char c;\n    cin >> c;\n    if (c >= 'A' && c <= 'Z') cout << 'A' << endl;\n    else cout << 'a' << endl;\n    return 0;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nAn uppercase or lowercase English letter \\alpha will be given as input.\nIf \\alpha is uppercase, print A; if it is lowercase, print a.\n\nConstraints\n\n\\alpha is an uppercase (A - Z) or lowercase (a - z) English letter.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nα\n\nOutput\n\nIf \\alpha is uppercase, print A; if it is lowercase, print a.\n\nSample Input 1\n\nB\n\nSample Output 1\n\nA\n\nB is uppercase, so we should print A.\n\nSample Input 2\n\na\n\nSample Output 2\n\na\n\na is lowercase, so we should print a.", "sample_input": "B\n"}, "reference_outputs": ["A\n"], "source_document_id": "p02627", "source_text": "Score : 100 points\n\nProblem Statement\n\nAn uppercase or lowercase English letter \\alpha will be given as input.\nIf \\alpha is uppercase, print A; if it is lowercase, print a.\n\nConstraints\n\n\\alpha is an uppercase (A - Z) or lowercase (a - z) English letter.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nα\n\nOutput\n\nIf \\alpha is uppercase, print A; if it is lowercase, print a.\n\nSample Input 1\n\nB\n\nSample Output 1\n\nA\n\nB is uppercase, so we should print A.\n\nSample Input 2\n\na\n\nSample Output 2\n\na\n\na is lowercase, so we should print a.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 204, "cpu_time_ms": 7, "memory_kb": 3632}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s591150165", "group_id": "codeNet:p02628", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main () {\n    int n, k;\n    while (scanf(\"%d %d\", &n, &k) == 2) {\n        vector<int> p(n, 0);\n        for (int i = 0; i < n; i++) scanf(\"%d\", &p[i]);\n        sort(p.begin(), p.end());\n        long long s = 0;\n        for (int i = 0; i < n && i < k; i++) s += p[i];\n        printf(\"%lld\\n\", s);\n    }\n}\n\n", "language": "C++", "metadata": {"date": 1592787839, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02628.html", "problem_id": "p02628", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02628/input.txt", "sample_output_relpath": "derived/input_output/data/p02628/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02628/C++/s591150165.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s591150165", "user_id": "u143746002"}, "prompt_components": {"gold_output": "210\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main () {\n    int n, k;\n    while (scanf(\"%d %d\", &n, &k) == 2) {\n        vector<int> p(n, 0);\n        for (int i = 0; i < n; i++) scanf(\"%d\", &p[i]);\n        sort(p.begin(), p.end());\n        long long s = 0;\n        for (int i = 0; i < n && i < k; i++) s += p[i];\n        printf(\"%lld\\n\", s);\n    }\n}\n\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nA shop sells N kinds of fruits, Fruit 1, \\ldots, N, at prices of p_1, \\ldots, p_N yen per item, respectively. (Yen is the currency of Japan.)\n\nHere, we will choose K kinds of fruits and buy one of each chosen kind. Find the minimum possible total price of those fruits.\n\nConstraints\n\n1 \\leq K \\leq N \\leq 1000\n\n1 \\leq p_i \\leq 1000\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\np_1 p_2 \\ldots p_N\n\nOutput\n\nPrint an integer representing the minimum possible total price of fruits.\n\nSample Input 1\n\n5 3\n50 100 80 120 80\n\nSample Output 1\n\n210\n\nThis shop sells Fruit 1, 2, 3, 4, and 5 for 50 yen, 100 yen, 80 yen, 120 yen, and 80 yen, respectively.\n\nThe minimum total price for three kinds of fruits is 50 + 80 + 80 = 210 yen when choosing Fruit 1, 3, and 5.\n\nSample Input 2\n\n1 1\n1000\n\nSample Output 2\n\n1000", "sample_input": "5 3\n50 100 80 120 80\n"}, "reference_outputs": ["210\n"], "source_document_id": "p02628", "source_text": "Score : 200 points\n\nProblem Statement\n\nA shop sells N kinds of fruits, Fruit 1, \\ldots, N, at prices of p_1, \\ldots, p_N yen per item, respectively. (Yen is the currency of Japan.)\n\nHere, we will choose K kinds of fruits and buy one of each chosen kind. Find the minimum possible total price of those fruits.\n\nConstraints\n\n1 \\leq K \\leq N \\leq 1000\n\n1 \\leq p_i \\leq 1000\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\np_1 p_2 \\ldots p_N\n\nOutput\n\nPrint an integer representing the minimum possible total price of fruits.\n\nSample Input 1\n\n5 3\n50 100 80 120 80\n\nSample Output 1\n\n210\n\nThis shop sells Fruit 1, 2, 3, 4, and 5 for 50 yen, 100 yen, 80 yen, 120 yen, and 80 yen, respectively.\n\nThe minimum total price for three kinds of fruits is 50 + 80 + 80 = 210 yen when choosing Fruit 1, 3, and 5.\n\nSample Input 2\n\n1 1\n1000\n\nSample Output 2\n\n1000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 355, "cpu_time_ms": 6, "memory_kb": 3792}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s029963050", "group_id": "codeNet:p02629", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing pii = pair<int, int>;\n\n#define pb push_back\n#define mp make_pair\n#define eb emplace_back\n#define all(x) (x).begin(),(x).end()\n#define x first\n#define y second\n\nconst int MOD = 1e9 + 7;\n\nvoid setIO() {\n\tios_base::sync_with_stdio(0);\n\tcin.tie(0);\n}\n\n//ctrl q is comment\n//ctrl b is run\n//ctrl s is compile\n//shift r is search & replace\n//shift d is delete a line\n\nbool comp(pii a, pii b){\n    return a.x == b.x ? a.y < b.y : a.x < b.x;\n}\nint main(){\n    setIO();\n    ll n; cin >> n;\n    int p26 = 0;\n    ll mult = 26;\n    int temp = n;\n    while(temp > mult){\n        temp -= mult;\n        mult *= 26;\n        ++p26;\n    }\n    mult = 1;\n    for(int i = 0; i < p26; ++i){\n        mult *= 26;\n    }\n    string ans = \"\";\n    for(int i = p26; i >= 0; --i){\n        if(n % mult == 0 && mult != 1){\n            ans += (char)(n / mult - 2 + 'a');\n            n %= mult;\n            n += mult;\n        }\n        else{\n            ans += (char)(n / mult - 1 + 'a');\n            n %= mult;\n        }\n        mult /= 26;\n    }\n    cout << ans << \"\\n\";\n}\n\n", "language": "C++", "metadata": {"date": 1592788760, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02629.html", "problem_id": "p02629", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02629/input.txt", "sample_output_relpath": "derived/input_output/data/p02629/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02629/C++/s029963050.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s029963050", "user_id": "u816600238"}, "prompt_components": {"gold_output": "b\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nusing pii = pair<int, int>;\n\n#define pb push_back\n#define mp make_pair\n#define eb emplace_back\n#define all(x) (x).begin(),(x).end()\n#define x first\n#define y second\n\nconst int MOD = 1e9 + 7;\n\nvoid setIO() {\n\tios_base::sync_with_stdio(0);\n\tcin.tie(0);\n}\n\n//ctrl q is comment\n//ctrl b is run\n//ctrl s is compile\n//shift r is search & replace\n//shift d is delete a line\n\nbool comp(pii a, pii b){\n    return a.x == b.x ? a.y < b.y : a.x < b.x;\n}\nint main(){\n    setIO();\n    ll n; cin >> n;\n    int p26 = 0;\n    ll mult = 26;\n    int temp = n;\n    while(temp > mult){\n        temp -= mult;\n        mult *= 26;\n        ++p26;\n    }\n    mult = 1;\n    for(int i = 0; i < p26; ++i){\n        mult *= 26;\n    }\n    string ans = \"\";\n    for(int i = p26; i >= 0; --i){\n        if(n % mult == 0 && mult != 1){\n            ans += (char)(n / mult - 2 + 'a');\n            n %= mult;\n            n += mult;\n        }\n        else{\n            ans += (char)(n / mult - 1 + 'a');\n            n %= mult;\n        }\n        mult /= 26;\n    }\n    cout << ans << \"\\n\";\n}\n\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\n1000000000000001 dogs suddenly appeared under the roof of Roger's house, all of which he decided to keep. The dogs had been numbered 1 through 1000000000000001, but he gave them new names, as follows:\n\nthe dogs numbered 1,2,\\cdots,26 were respectively given the names a, b, ..., z;\n\nthe dogs numbered 27,28,29,\\cdots,701,702 were respectively given the names aa, ab, ac, ..., zy, zz;\n\nthe dogs numbered 703,704,705,\\cdots,18277,18278 were respectively given the names aaa, aab, aac, ..., zzy, zzz;\n\nthe dogs numbered 18279,18280,18281,\\cdots,475253,475254 were respectively given the names aaaa, aaab, aaac, ..., zzzy, zzzz;\n\nthe dogs numbered 475255,475256,\\cdots were respectively given the names aaaaa, aaaab, ...;\n\nand so on.\n\nTo sum it up, the dogs numbered 1, 2, \\cdots were respectively given the following names:\n\na, b, ..., z, aa, ab, ..., az, ba, bb, ..., bz, ..., za, zb, ..., zz, aaa, aab, ..., aaz, aba, abb, ..., abz, ..., zzz, aaaa, ...\n\nNow, Roger asks you:\n\n\"What is the name for the dog numbered N?\"\n\nConstraints\n\nN is an integer.\n\n1 \\leq N \\leq 1000000000000001\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the answer to Roger's question as a string consisting of lowercase English letters.\n\nSample Input 1\n\n2\n\nSample Output 1\n\nb\n\nSample Input 2\n\n27\n\nSample Output 2\n\naa\n\nSample Input 3\n\n123456789\n\nSample Output 3\n\njjddja", "sample_input": "2\n"}, "reference_outputs": ["b\n"], "source_document_id": "p02629", "source_text": "Score : 300 points\n\nProblem Statement\n\n1000000000000001 dogs suddenly appeared under the roof of Roger's house, all of which he decided to keep. The dogs had been numbered 1 through 1000000000000001, but he gave them new names, as follows:\n\nthe dogs numbered 1,2,\\cdots,26 were respectively given the names a, b, ..., z;\n\nthe dogs numbered 27,28,29,\\cdots,701,702 were respectively given the names aa, ab, ac, ..., zy, zz;\n\nthe dogs numbered 703,704,705,\\cdots,18277,18278 were respectively given the names aaa, aab, aac, ..., zzy, zzz;\n\nthe dogs numbered 18279,18280,18281,\\cdots,475253,475254 were respectively given the names aaaa, aaab, aaac, ..., zzzy, zzzz;\n\nthe dogs numbered 475255,475256,\\cdots were respectively given the names aaaaa, aaaab, ...;\n\nand so on.\n\nTo sum it up, the dogs numbered 1, 2, \\cdots were respectively given the following names:\n\na, b, ..., z, aa, ab, ..., az, ba, bb, ..., bz, ..., za, zb, ..., zz, aaa, aab, ..., aaz, aba, abb, ..., abz, ..., zzz, aaaa, ...\n\nNow, Roger asks you:\n\n\"What is the name for the dog numbered N?\"\n\nConstraints\n\nN is an integer.\n\n1 \\leq N \\leq 1000000000000001\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the answer to Roger's question as a string consisting of lowercase English letters.\n\nSample Input 1\n\n2\n\nSample Output 1\n\nb\n\nSample Input 2\n\n27\n\nSample Output 2\n\naa\n\nSample Input 3\n\n123456789\n\nSample Output 3\n\njjddja", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1117, "cpu_time_ms": 6, "memory_kb": 3636}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s086966410", "group_id": "codeNet:p02633", "input_text": "#include <stdio.h>\n\nint main()\n{\n  \n  int x;\n  scanf(\"%d\",&x);\n  int result=360/x;\n  if(x*result==360)\n    \tprintf(\"%d\",result);\n \telse\n      \tprintf(\"%d\",result+1);\n}", "language": "C++", "metadata": {"date": 1592975877, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02633.html", "problem_id": "p02633", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02633/input.txt", "sample_output_relpath": "derived/input_output/data/p02633/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02633/C++/s086966410.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s086966410", "user_id": "u885060644"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <stdio.h>\n\nint main()\n{\n  \n  int x;\n  scanf(\"%d\",&x);\n  int result=360/x;\n  if(x*result==360)\n    \tprintf(\"%d\",result);\n \telse\n      \tprintf(\"%d\",result+1);\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nTakahashi is standing on a two-dimensional plane, facing north. Find the minimum positive integer K such that Takahashi will be at the starting position again after he does the following action K times:\n\nGo one meter in the direction he is facing. Then, turn X degrees counter-clockwise.\n\nConstraints\n\n1 \\leq X \\leq 179\n\nX is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint the number of times Takahashi will do the action before he is at the starting position again.\n\nSample Input 1\n\n90\n\nSample Output 1\n\n4\n\nTakahashi's path is a square.\n\nSample Input 2\n\n1\n\nSample Output 2\n\n360", "sample_input": "90\n"}, "reference_outputs": ["4\n"], "source_document_id": "p02633", "source_text": "Score : 200 points\n\nProblem Statement\n\nTakahashi is standing on a two-dimensional plane, facing north. Find the minimum positive integer K such that Takahashi will be at the starting position again after he does the following action K times:\n\nGo one meter in the direction he is facing. Then, turn X degrees counter-clockwise.\n\nConstraints\n\n1 \\leq X \\leq 179\n\nX is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint the number of times Takahashi will do the action before he is at the starting position again.\n\nSample Input 1\n\n90\n\nSample Output 1\n\n4\n\nTakahashi's path is a square.\n\nSample Input 2\n\n1\n\nSample Output 2\n\n360", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 167, "cpu_time_ms": 6, "memory_kb": 1656}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s053625603", "group_id": "codeNet:p02633", "input_text": "#include<bits/stdc++.h>\n#include<vector>\n#include<cmath>\n#include<math.h>\n#include<cstdlib>\n#include<assert.h>\n#include<string>\n#include<sstream>\n#include<algorithm>\n#include<ctime>\n#include<iostream>\n#define ll long long \n#define ld long double\n#define pb push_back\n#define rep(i,n) for(i=0;i<n;i++)\n#define rep1(j,n) for (j=0;j<=n;j++)\n#define PI 3.14159265358979323846\n#define mod 1000000007\n#define fastio ios_base::sync_with_stdio(false); cin.tie(NULL);cout.tie(NULL) \nusing namespace std;\n/*void input(vector<ld>& v,ld n)\n{\n\tld i,io;\n\trep(i,n)\n\t{\n\t\tcin>>io;\n\t\tv.pb(io);\n\t}\n}*/\nint main()\n{\n\tfastio;\n\tint n;\n\tcin>>n;\n\tcout<<(360)/n<<endl;\t\n}", "language": "C++", "metadata": {"date": 1592701394, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02633.html", "problem_id": "p02633", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02633/input.txt", "sample_output_relpath": "derived/input_output/data/p02633/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02633/C++/s053625603.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s053625603", "user_id": "u992895833"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include<bits/stdc++.h>\n#include<vector>\n#include<cmath>\n#include<math.h>\n#include<cstdlib>\n#include<assert.h>\n#include<string>\n#include<sstream>\n#include<algorithm>\n#include<ctime>\n#include<iostream>\n#define ll long long \n#define ld long double\n#define pb push_back\n#define rep(i,n) for(i=0;i<n;i++)\n#define rep1(j,n) for (j=0;j<=n;j++)\n#define PI 3.14159265358979323846\n#define mod 1000000007\n#define fastio ios_base::sync_with_stdio(false); cin.tie(NULL);cout.tie(NULL) \nusing namespace std;\n/*void input(vector<ld>& v,ld n)\n{\n\tld i,io;\n\trep(i,n)\n\t{\n\t\tcin>>io;\n\t\tv.pb(io);\n\t}\n}*/\nint main()\n{\n\tfastio;\n\tint n;\n\tcin>>n;\n\tcout<<(360)/n<<endl;\t\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nTakahashi is standing on a two-dimensional plane, facing north. Find the minimum positive integer K such that Takahashi will be at the starting position again after he does the following action K times:\n\nGo one meter in the direction he is facing. Then, turn X degrees counter-clockwise.\n\nConstraints\n\n1 \\leq X \\leq 179\n\nX is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint the number of times Takahashi will do the action before he is at the starting position again.\n\nSample Input 1\n\n90\n\nSample Output 1\n\n4\n\nTakahashi's path is a square.\n\nSample Input 2\n\n1\n\nSample Output 2\n\n360", "sample_input": "90\n"}, "reference_outputs": ["4\n"], "source_document_id": "p02633", "source_text": "Score : 200 points\n\nProblem Statement\n\nTakahashi is standing on a two-dimensional plane, facing north. Find the minimum positive integer K such that Takahashi will be at the starting position again after he does the following action K times:\n\nGo one meter in the direction he is facing. Then, turn X degrees counter-clockwise.\n\nConstraints\n\n1 \\leq X \\leq 179\n\nX is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint the number of times Takahashi will do the action before he is at the starting position again.\n\nSample Input 1\n\n90\n\nSample Output 1\n\n4\n\nTakahashi's path is a square.\n\nSample Input 2\n\n1\n\nSample Output 2\n\n360", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 646, "cpu_time_ms": 8, "memory_kb": 3648}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s490504407", "group_id": "codeNet:p02639", "input_text": "#include <bits/stdc++.h>\n#define rep(i, n) for (int i = 0; i < (n); ++i)\nusing namespace std;\nusing ll = long long;\nusing P = pair<int, int>;\nconst int INF = INT32_MAX;\nconst ll INFL = INT64_MAX;\nconst int mod = 1e9 + 7;\n\ntemplate <typename T>\nvoid print_vec(vector<T> v) {\n  for (T i : v) cout << i << \" \";\n  cout << endl;\n}\n\nint main() {\n  int ans = 0;\n  rep(i, 5) {\n    int x;\n    cin >> x;\n    if (x == 0) ans = i + 1;\n  }\n  cout << ans << endl;\n  return 0;\n}", "language": "C++", "metadata": {"date": 1592182922, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02639.html", "problem_id": "p02639", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02639/input.txt", "sample_output_relpath": "derived/input_output/data/p02639/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02639/C++/s490504407.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s490504407", "user_id": "u894496005"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define rep(i, n) for (int i = 0; i < (n); ++i)\nusing namespace std;\nusing ll = long long;\nusing P = pair<int, int>;\nconst int INF = INT32_MAX;\nconst ll INFL = INT64_MAX;\nconst int mod = 1e9 + 7;\n\ntemplate <typename T>\nvoid print_vec(vector<T> v) {\n  for (T i : v) cout << i << \" \";\n  cout << endl;\n}\n\nint main() {\n  int ans = 0;\n  rep(i, 5) {\n    int x;\n    cin >> x;\n    if (x == 0) ans = i + 1;\n  }\n  cout << ans << endl;\n  return 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nWe have five variables x_1, x_2, x_3, x_4, and x_5.\n\nThe variable x_i was initially assigned a value of i.\n\nSnuke chose one of these variables and assigned it 0.\n\nYou are given the values of the five variables after this assignment.\n\nFind out which variable Snuke assigned 0.\n\nConstraints\n\nThe values of x_1, x_2, x_3, x_4, and x_5 given as input are a possible outcome of the assignment by Snuke.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nx_1 x_2 x_3 x_4 x_5\n\nOutput\n\nIf the variable Snuke assigned 0 was x_i, print the integer i.\n\nSample Input 1\n\n0 2 3 4 5\n\nSample Output 1\n\n1\n\nIn this case, Snuke assigned 0 to x_1, so we should print 1.\n\nSample Input 2\n\n1 2 0 4 5\n\nSample Output 2\n\n3", "sample_input": "0 2 3 4 5\n"}, "reference_outputs": ["1\n"], "source_document_id": "p02639", "source_text": "Score : 100 points\n\nProblem Statement\n\nWe have five variables x_1, x_2, x_3, x_4, and x_5.\n\nThe variable x_i was initially assigned a value of i.\n\nSnuke chose one of these variables and assigned it 0.\n\nYou are given the values of the five variables after this assignment.\n\nFind out which variable Snuke assigned 0.\n\nConstraints\n\nThe values of x_1, x_2, x_3, x_4, and x_5 given as input are a possible outcome of the assignment by Snuke.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nx_1 x_2 x_3 x_4 x_5\n\nOutput\n\nIf the variable Snuke assigned 0 was x_i, print the integer i.\n\nSample Input 1\n\n0 2 3 4 5\n\nSample Output 1\n\n1\n\nIn this case, Snuke assigned 0 to x_1, so we should print 1.\n\nSample Input 2\n\n1 2 0 4 5\n\nSample Output 2\n\n3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 463, "cpu_time_ms": 2, "memory_kb": 3584}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s139291902", "group_id": "codeNet:p02640", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){int m,n;if(m<=n&&n<=2*m&&n%2==0)cout<<\"Yes\"<<endl;else{cout<<\"No\"<<endl;}}", "language": "C++", "metadata": {"date": 1592183219, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02640.html", "problem_id": "p02640", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02640/input.txt", "sample_output_relpath": "derived/input_output/data/p02640/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02640/C++/s139291902.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s139291902", "user_id": "u934015186"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){int m,n;if(m<=n&&n<=2*m&&n%2==0)cout<<\"Yes\"<<endl;else{cout<<\"No\"<<endl;}}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nThere are some animals in a garden. Each of them is a crane with two legs or a turtle with four legs.\n\nTakahashi says: \"there are X animals in total in the garden, and they have Y legs in total.\" Determine whether there is a combination of numbers of cranes and turtles in which this statement is correct.\n\nConstraints\n\n1 \\leq X \\leq 100\n\n1 \\leq Y \\leq 100\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX Y\n\nOutput\n\nIf there is a combination of numbers of cranes and turtles in which the statement is correct, print Yes; otherwise, print No.\n\nSample Input 1\n\n3 8\n\nSample Output 1\n\nYes\n\nThe statement \"there are 3 animals in total in the garden, and they have 8 legs in total\" is correct if there are two cranes and one turtle. Thus, there is a combination of numbers of cranes and turtles in which the statement is correct.\n\nSample Input 2\n\n2 100\n\nSample Output 2\n\nNo\n\nThere is no combination of numbers of cranes and turtles in which this statement is correct.\n\nSample Input 3\n\n1 2\n\nSample Output 3\n\nYes\n\nWe also consider the case in which there are only cranes or only turtles.", "sample_input": "3 8\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p02640", "source_text": "Score : 200 points\n\nProblem Statement\n\nThere are some animals in a garden. Each of them is a crane with two legs or a turtle with four legs.\n\nTakahashi says: \"there are X animals in total in the garden, and they have Y legs in total.\" Determine whether there is a combination of numbers of cranes and turtles in which this statement is correct.\n\nConstraints\n\n1 \\leq X \\leq 100\n\n1 \\leq Y \\leq 100\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX Y\n\nOutput\n\nIf there is a combination of numbers of cranes and turtles in which the statement is correct, print Yes; otherwise, print No.\n\nSample Input 1\n\n3 8\n\nSample Output 1\n\nYes\n\nThe statement \"there are 3 animals in total in the garden, and they have 8 legs in total\" is correct if there are two cranes and one turtle. Thus, there is a combination of numbers of cranes and turtles in which the statement is correct.\n\nSample Input 2\n\n2 100\n\nSample Output 2\n\nNo\n\nThere is no combination of numbers of cranes and turtles in which this statement is correct.\n\nSample Input 3\n\n1 2\n\nSample Output 3\n\nYes\n\nWe also consider the case in which there are only cranes or only turtles.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 130, "cpu_time_ms": 3, "memory_kb": 3676}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s155329689", "group_id": "codeNet:p02641", "input_text": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nint main() {\n\nint x,n, r{101};\nvector<int>v{};\ncin>>x>>n;\nif(!n)\n  cout << x;\nelse\n{\n\n  int c;\n  for(int i = 0; i < n; i++)\n  {\n    cin >> c;\n    v.push_back(abs(c));\n  }\n\n  sort(v.begin(), v.end());\n  auto it = find(v.begin(),v.end(), x);\n  \n  if (it == v.end()){\n    cout << x;\n    exit(0);\n  }\n    \n \n  \n  int z = 1;\n  while(true)\n  {\n    if(*(it-z) != x-z)\n    {\n      z = x-z;\n      break;\n    }\n    else if (*(it+z) != x+z)\n    {\n      z = x+z;\n      break;\n    }\n    z++;\n    \n  }\n  cout << z;\n  \n\n\n\n}\nreturn 0;\n}", "language": "C++", "metadata": {"date": 1601042084, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02641.html", "problem_id": "p02641", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02641/input.txt", "sample_output_relpath": "derived/input_output/data/p02641/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02641/C++/s155329689.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s155329689", "user_id": "u629482802"}, "prompt_components": {"gold_output": "8\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nint main() {\n\nint x,n, r{101};\nvector<int>v{};\ncin>>x>>n;\nif(!n)\n  cout << x;\nelse\n{\n\n  int c;\n  for(int i = 0; i < n; i++)\n  {\n    cin >> c;\n    v.push_back(abs(c));\n  }\n\n  sort(v.begin(), v.end());\n  auto it = find(v.begin(),v.end(), x);\n  \n  if (it == v.end()){\n    cout << x;\n    exit(0);\n  }\n    \n \n  \n  int z = 1;\n  while(true)\n  {\n    if(*(it-z) != x-z)\n    {\n      z = x-z;\n      break;\n    }\n    else if (*(it+z) != x+z)\n    {\n      z = x+z;\n      break;\n    }\n    z++;\n    \n  }\n  cout << z;\n  \n\n\n\n}\nreturn 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nGiven are an integer X and an integer sequence of length N: p_1, \\ldots, p_N.\n\nAmong the integers not contained in the sequence p_1, \\ldots, p_N (not necessarily positive), find the integer nearest to X, that is, find the integer whose absolute difference with X is the minimum. If there are multiple such integers, report the smallest such integer.\n\nConstraints\n\n1 \\leq X \\leq 100\n\n0 \\leq N \\leq 100\n\n1 \\leq p_i \\leq 100\n\np_1, \\ldots, p_N are all distinct.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX N\np_1 ... p_N\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n6 5\n4 7 10 6 5\n\nSample Output 1\n\n8\n\nAmong the integers not contained in the sequence 4, 7, 10, 6, 5, the one nearest to 6 is 8.\n\nSample Input 2\n\n10 5\n4 7 10 6 5\n\nSample Output 2\n\n9\n\nAmong the integers not contained in the sequence 4, 7, 10, 6, 5, the ones nearest to 10 are 9 and 11. We should print the smaller one, 9.\n\nSample Input 3\n\n100 0\n\nSample Output 3\n\n100\n\nWhen N = 0, the second line in the input will be empty. Also, as seen here, X itself can be the answer.", "sample_input": "6 5\n4 7 10 6 5\n"}, "reference_outputs": ["8\n"], "source_document_id": "p02641", "source_text": "Score : 300 points\n\nProblem Statement\n\nGiven are an integer X and an integer sequence of length N: p_1, \\ldots, p_N.\n\nAmong the integers not contained in the sequence p_1, \\ldots, p_N (not necessarily positive), find the integer nearest to X, that is, find the integer whose absolute difference with X is the minimum. If there are multiple such integers, report the smallest such integer.\n\nConstraints\n\n1 \\leq X \\leq 100\n\n0 \\leq N \\leq 100\n\n1 \\leq p_i \\leq 100\n\np_1, \\ldots, p_N are all distinct.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX N\np_1 ... p_N\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n6 5\n4 7 10 6 5\n\nSample Output 1\n\n8\n\nAmong the integers not contained in the sequence 4, 7, 10, 6, 5, the one nearest to 6 is 8.\n\nSample Input 2\n\n10 5\n4 7 10 6 5\n\nSample Output 2\n\n9\n\nAmong the integers not contained in the sequence 4, 7, 10, 6, 5, the ones nearest to 10 are 9 and 11. We should print the smaller one, 9.\n\nSample Input 3\n\n100 0\n\nSample Output 3\n\n100\n\nWhen N = 0, the second line in the input will be empty. Also, as seen here, X itself can be the answer.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 601, "cpu_time_ms": 8, "memory_kb": 3548}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s977135282", "group_id": "codeNet:p02641", "input_text": "#include <algorithm>\n#include <bitset>\n#include <complex>\n#include <deque>\n#include <exception>\n#include <fstream>\n#include <functional>\n#include <iomanip>\n#include <ios>\n#include <iosfwd>\n#include <iostream>\n#include <istream>\n#include <iterator>\n#include <limits>\n#include <list>\n#include <locale>\n#include <map>\n#include <memory>\n#include <new>\n#include <numeric>\n#include <ostream>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <stack>\n#include <stdexcept>\n#include <streambuf>\n#include <string>\n#include <typeinfo>\n#include <utility>\n#include <valarray>\n#include <vector>\n\nusing namespace std;\n#define int long long\n#define ld long double\n#define all(x) x.begin(),x.end()\n#define max3(a,b,c) max(a,max(b,c))\n#define min3(a,b,c) min(a,min(b,c))\n#define vi vector<int>\n#define vstr vector<string>\n#define vbool vector<bool>\n#define vvi vector<vector<int> >\n#define mii map<int,int>\n#define pb push_back\n#define pii pair<int,int>\n#define vpair vector<pii > \n#define mkp make_pair\n#define scan(a,n) for(int i =0 ; i<n ; i++) cin>>a[i]\n#define print(a,n) for(int i = 0 ; i < n ; i++) {cout<<a[i]<<' ';}cout<<'\\n'\n#define mem(a,v) memset(a,v,sizeof(a))\n#define loop(i,a,b) for (int i = a; i < b; i++)\n#define loope(i,a,b) for (int i = a; i <= b; i++)\n#define FastIO ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL)\n#define PRECISION std::cout.unsetf ( std::ios::fixed );std::cout.precision(9)\n#define PI 3.14159265\n#define S second\n#define F first\n#define CHECK cout<<\"CHEDEDWB\"<<endl\nint mod = 1e9+7;\nint inf = 1e18;\nint m_inf = INT_MIN;\n\nvoid solve()\n{\n\tint x,n;\n\tcin>>x>>n;\n\tif(n==0)\n\t\tcout<<x<<endl;\n\telse\n\t{\n\t\tint p=0,q=0;\n\t\tvector<bool> ans(101,false);\n\t\tvi arr(n);\n\t\tloop(i,0,n)\n\t\t{\n\t\t\tcin>>arr[i];\n\t\t\tans[arr[i]] = true;\n\t\t}\n\t\tsort(all(arr));\n\t\tloop(i,x,101)\n\t\t{\n\t\t\tif(ans[i]==false)\n\t\t\t\t{\n\t\t\t\t\tp = i;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t}\n\t\tfor(int i = x;i>0;i--)\n\t\t{\n\t\t\tif(ans[i]==false)\n\t\t\t\t{\n\t\t\t\t\tq = i;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t}\n\t\tif(abs(x-p)<abs(x-q))\n\t\t\tcout<<p<<endl;\n\t\telse\n\t\t\tcout<<q<<endl;\n\t}\n}\n\nint32_t main()\n{\n\tFastIO; PRECISION;\n\tint t = 1;\n\t//cin>>t;\n\twhile(t--)\n\t\tsolve();\n\treturn 0;\n} ", "language": "C++", "metadata": {"date": 1592189120, "filename_ext": "cpp", "original_language": "C++ (Clang 10.0.0)", "problem_description_relpath": "problem_descriptions/p02641.html", "problem_id": "p02641", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02641/input.txt", "sample_output_relpath": "derived/input_output/data/p02641/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02641/C++/s977135282.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s977135282", "user_id": "u860952176"}, "prompt_components": {"gold_output": "8\n", "input_to_evaluate": "#include <algorithm>\n#include <bitset>\n#include <complex>\n#include <deque>\n#include <exception>\n#include <fstream>\n#include <functional>\n#include <iomanip>\n#include <ios>\n#include <iosfwd>\n#include <iostream>\n#include <istream>\n#include <iterator>\n#include <limits>\n#include <list>\n#include <locale>\n#include <map>\n#include <memory>\n#include <new>\n#include <numeric>\n#include <ostream>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <stack>\n#include <stdexcept>\n#include <streambuf>\n#include <string>\n#include <typeinfo>\n#include <utility>\n#include <valarray>\n#include <vector>\n\nusing namespace std;\n#define int long long\n#define ld long double\n#define all(x) x.begin(),x.end()\n#define max3(a,b,c) max(a,max(b,c))\n#define min3(a,b,c) min(a,min(b,c))\n#define vi vector<int>\n#define vstr vector<string>\n#define vbool vector<bool>\n#define vvi vector<vector<int> >\n#define mii map<int,int>\n#define pb push_back\n#define pii pair<int,int>\n#define vpair vector<pii > \n#define mkp make_pair\n#define scan(a,n) for(int i =0 ; i<n ; i++) cin>>a[i]\n#define print(a,n) for(int i = 0 ; i < n ; i++) {cout<<a[i]<<' ';}cout<<'\\n'\n#define mem(a,v) memset(a,v,sizeof(a))\n#define loop(i,a,b) for (int i = a; i < b; i++)\n#define loope(i,a,b) for (int i = a; i <= b; i++)\n#define FastIO ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL)\n#define PRECISION std::cout.unsetf ( std::ios::fixed );std::cout.precision(9)\n#define PI 3.14159265\n#define S second\n#define F first\n#define CHECK cout<<\"CHEDEDWB\"<<endl\nint mod = 1e9+7;\nint inf = 1e18;\nint m_inf = INT_MIN;\n\nvoid solve()\n{\n\tint x,n;\n\tcin>>x>>n;\n\tif(n==0)\n\t\tcout<<x<<endl;\n\telse\n\t{\n\t\tint p=0,q=0;\n\t\tvector<bool> ans(101,false);\n\t\tvi arr(n);\n\t\tloop(i,0,n)\n\t\t{\n\t\t\tcin>>arr[i];\n\t\t\tans[arr[i]] = true;\n\t\t}\n\t\tsort(all(arr));\n\t\tloop(i,x,101)\n\t\t{\n\t\t\tif(ans[i]==false)\n\t\t\t\t{\n\t\t\t\t\tp = i;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t}\n\t\tfor(int i = x;i>0;i--)\n\t\t{\n\t\t\tif(ans[i]==false)\n\t\t\t\t{\n\t\t\t\t\tq = i;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t}\n\t\tif(abs(x-p)<abs(x-q))\n\t\t\tcout<<p<<endl;\n\t\telse\n\t\t\tcout<<q<<endl;\n\t}\n}\n\nint32_t main()\n{\n\tFastIO; PRECISION;\n\tint t = 1;\n\t//cin>>t;\n\twhile(t--)\n\t\tsolve();\n\treturn 0;\n} ", "problem_context": "Score : 300 points\n\nProblem Statement\n\nGiven are an integer X and an integer sequence of length N: p_1, \\ldots, p_N.\n\nAmong the integers not contained in the sequence p_1, \\ldots, p_N (not necessarily positive), find the integer nearest to X, that is, find the integer whose absolute difference with X is the minimum. If there are multiple such integers, report the smallest such integer.\n\nConstraints\n\n1 \\leq X \\leq 100\n\n0 \\leq N \\leq 100\n\n1 \\leq p_i \\leq 100\n\np_1, \\ldots, p_N are all distinct.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX N\np_1 ... p_N\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n6 5\n4 7 10 6 5\n\nSample Output 1\n\n8\n\nAmong the integers not contained in the sequence 4, 7, 10, 6, 5, the one nearest to 6 is 8.\n\nSample Input 2\n\n10 5\n4 7 10 6 5\n\nSample Output 2\n\n9\n\nAmong the integers not contained in the sequence 4, 7, 10, 6, 5, the ones nearest to 10 are 9 and 11. We should print the smaller one, 9.\n\nSample Input 3\n\n100 0\n\nSample Output 3\n\n100\n\nWhen N = 0, the second line in the input will be empty. Also, as seen here, X itself can be the answer.", "sample_input": "6 5\n4 7 10 6 5\n"}, "reference_outputs": ["8\n"], "source_document_id": "p02641", "source_text": "Score : 300 points\n\nProblem Statement\n\nGiven are an integer X and an integer sequence of length N: p_1, \\ldots, p_N.\n\nAmong the integers not contained in the sequence p_1, \\ldots, p_N (not necessarily positive), find the integer nearest to X, that is, find the integer whose absolute difference with X is the minimum. If there are multiple such integers, report the smallest such integer.\n\nConstraints\n\n1 \\leq X \\leq 100\n\n0 \\leq N \\leq 100\n\n1 \\leq p_i \\leq 100\n\np_1, \\ldots, p_N are all distinct.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX N\np_1 ... p_N\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n6 5\n4 7 10 6 5\n\nSample Output 1\n\n8\n\nAmong the integers not contained in the sequence 4, 7, 10, 6, 5, the one nearest to 6 is 8.\n\nSample Input 2\n\n10 5\n4 7 10 6 5\n\nSample Output 2\n\n9\n\nAmong the integers not contained in the sequence 4, 7, 10, 6, 5, the ones nearest to 10 are 9 and 11. We should print the smaller one, 9.\n\nSample Input 3\n\n100 0\n\nSample Output 3\n\n100\n\nWhen N = 0, the second line in the input will be empty. Also, as seen here, X itself can be the answer.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2117, "cpu_time_ms": 4, "memory_kb": 3196}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s351696386", "group_id": "codeNet:p02641", "input_text": "// clang-format off\n#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing P = pair<ll, ll>;\nusing G = vector<vector<ll>>;\n#define G(i, j) i, vector<ll>(j)\n#define Gv(i, j, k) i, vector<ll>(j, k)\n#define rep(i,n) for(ll i=0, i##_len=(n); i<i##_len; ++i)\n#define rep1(i,n) for(ll i=1, i##_len=(n); i<=i##_len; ++i)\n#define rrep(i,n) for(ll i=n-1; i>=0; --i)\n#define rrep1(i,n) for(ll i=n; i>0; --i)\n#define all(x) (x).begin(),(x).end()\n#define SORT(x) sort(all(x))\n#define SORT_DESC(x) sort((x).rbegin(),(x).rend())\n#define pb push_back\n#define mp make_pair\n#define coutl cout<<fixed<<setprecision(10)\n#define ANS(ans) cout<<ans<<endl\n#define END(ans) ANS(ans); return\nconst ll LINF = (1LL << 62) - 1;\nconst int INF = (1 << 30) - 1;\ntemplate<class T>inline bool chmax(T &a, const T &b){if (a<b){a=b;return 1;}return 0;}\ntemplate<class T>inline bool chmin(T &a, const T &b){if (b<a){a=b;return 1;}return 0;}\n// clang-format on\n\nvoid solve(long long X, long long N, std::vector<long long> p) {\n  ll a, s = INF;\n  rep(i, 102) {\n    if (find(all(p), i) != p.end())\n      continue;\n    ll d = abs(X - i);\n    if (d < s) {\n      a = i;\n      s = d;\n    }\n  }\n  ANS(a);\n}\n\n// clang-format off\nint main() {\n  long long X;\n  scanf(\"%lld\",&X);\n  long long N;\n  scanf(\"%lld\",&N);\n  std::vector<long long> p(N);\n  for(int i = 0 ; i < N ; i++){\n    scanf(\"%lld\",&p[i]);\n  }\n  solve(X, N, std::move(p));\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1592185337, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02641.html", "problem_id": "p02641", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02641/input.txt", "sample_output_relpath": "derived/input_output/data/p02641/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02641/C++/s351696386.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s351696386", "user_id": "u891692185"}, "prompt_components": {"gold_output": "8\n", "input_to_evaluate": "// clang-format off\n#pragma GCC optimize(\"Ofast\")\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing P = pair<ll, ll>;\nusing G = vector<vector<ll>>;\n#define G(i, j) i, vector<ll>(j)\n#define Gv(i, j, k) i, vector<ll>(j, k)\n#define rep(i,n) for(ll i=0, i##_len=(n); i<i##_len; ++i)\n#define rep1(i,n) for(ll i=1, i##_len=(n); i<=i##_len; ++i)\n#define rrep(i,n) for(ll i=n-1; i>=0; --i)\n#define rrep1(i,n) for(ll i=n; i>0; --i)\n#define all(x) (x).begin(),(x).end()\n#define SORT(x) sort(all(x))\n#define SORT_DESC(x) sort((x).rbegin(),(x).rend())\n#define pb push_back\n#define mp make_pair\n#define coutl cout<<fixed<<setprecision(10)\n#define ANS(ans) cout<<ans<<endl\n#define END(ans) ANS(ans); return\nconst ll LINF = (1LL << 62) - 1;\nconst int INF = (1 << 30) - 1;\ntemplate<class T>inline bool chmax(T &a, const T &b){if (a<b){a=b;return 1;}return 0;}\ntemplate<class T>inline bool chmin(T &a, const T &b){if (b<a){a=b;return 1;}return 0;}\n// clang-format on\n\nvoid solve(long long X, long long N, std::vector<long long> p) {\n  ll a, s = INF;\n  rep(i, 102) {\n    if (find(all(p), i) != p.end())\n      continue;\n    ll d = abs(X - i);\n    if (d < s) {\n      a = i;\n      s = d;\n    }\n  }\n  ANS(a);\n}\n\n// clang-format off\nint main() {\n  long long X;\n  scanf(\"%lld\",&X);\n  long long N;\n  scanf(\"%lld\",&N);\n  std::vector<long long> p(N);\n  for(int i = 0 ; i < N ; i++){\n    scanf(\"%lld\",&p[i]);\n  }\n  solve(X, N, std::move(p));\n  return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nGiven are an integer X and an integer sequence of length N: p_1, \\ldots, p_N.\n\nAmong the integers not contained in the sequence p_1, \\ldots, p_N (not necessarily positive), find the integer nearest to X, that is, find the integer whose absolute difference with X is the minimum. If there are multiple such integers, report the smallest such integer.\n\nConstraints\n\n1 \\leq X \\leq 100\n\n0 \\leq N \\leq 100\n\n1 \\leq p_i \\leq 100\n\np_1, \\ldots, p_N are all distinct.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX N\np_1 ... p_N\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n6 5\n4 7 10 6 5\n\nSample Output 1\n\n8\n\nAmong the integers not contained in the sequence 4, 7, 10, 6, 5, the one nearest to 6 is 8.\n\nSample Input 2\n\n10 5\n4 7 10 6 5\n\nSample Output 2\n\n9\n\nAmong the integers not contained in the sequence 4, 7, 10, 6, 5, the ones nearest to 10 are 9 and 11. We should print the smaller one, 9.\n\nSample Input 3\n\n100 0\n\nSample Output 3\n\n100\n\nWhen N = 0, the second line in the input will be empty. Also, as seen here, X itself can be the answer.", "sample_input": "6 5\n4 7 10 6 5\n"}, "reference_outputs": ["8\n"], "source_document_id": "p02641", "source_text": "Score : 300 points\n\nProblem Statement\n\nGiven are an integer X and an integer sequence of length N: p_1, \\ldots, p_N.\n\nAmong the integers not contained in the sequence p_1, \\ldots, p_N (not necessarily positive), find the integer nearest to X, that is, find the integer whose absolute difference with X is the minimum. If there are multiple such integers, report the smallest such integer.\n\nConstraints\n\n1 \\leq X \\leq 100\n\n0 \\leq N \\leq 100\n\n1 \\leq p_i \\leq 100\n\np_1, \\ldots, p_N are all distinct.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX N\np_1 ... p_N\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n6 5\n4 7 10 6 5\n\nSample Output 1\n\n8\n\nAmong the integers not contained in the sequence 4, 7, 10, 6, 5, the one nearest to 6 is 8.\n\nSample Input 2\n\n10 5\n4 7 10 6 5\n\nSample Output 2\n\n9\n\nAmong the integers not contained in the sequence 4, 7, 10, 6, 5, the ones nearest to 10 are 9 and 11. We should print the smaller one, 9.\n\nSample Input 3\n\n100 0\n\nSample Output 3\n\n100\n\nWhen N = 0, the second line in the input will be empty. Also, as seen here, X itself can be the answer.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1452, "cpu_time_ms": 7, "memory_kb": 3692}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s642314164", "group_id": "codeNet:p02644", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define FOR(i,a,b) for (int i = (a); i < (b); ++i)\n#define F0R(i,a) FOR(i,0,a)\n#define ROF(i,a,b) for (int i = (b)-1; i >= (a); --i)\n#define R0F(i,a) ROF(i,0,a)\n\nusing ll = long long;\nusing ld = long double;\nll INF = LLONG_MAX;\n\nusing vi = vector<int>;\nusing vll = vector<ll>;\nusing pii = pair<int, int>;\n\nnamespace output {\n\tvoid pr(int x) { cout << x; }\n\tvoid pr(long x) { cout << x; }\n\tvoid pr(ll x) { cout << x; }\n\tvoid pr(unsigned x) { cout << x; }\n\tvoid pr(unsigned long x) { cout << x; }\n\tvoid pr(unsigned long long x) { cout << x; }\n\tvoid pr(float x) { cout << x; }\n\tvoid pr(double x) { cout << x; }\n\tvoid pr(ld x) { cout << x; }\n\tvoid pr(char x) { cout << x; }\n\tvoid pr(const char* x) { cout << x; }\n\tvoid pr(const string& x) { cout << x; }\n\tvoid pr(bool x) { pr(x ? \"true\" : \"false\"); }\n\ttemplate<class T> void pr(const complex<T>& x) { cout << x; }\n\t\n\ttemplate<class T1, class T2> void pr(const pair<T1,T2>& x);\n\ttemplate<class T> void pr(const T& x);\n\t\n\ttemplate<class T, class... Ts> void pr(const T& t, const Ts&... ts) { \n\t\tpr(t); pr(ts...); \n\t}\n\ttemplate<class T1, class T2> void pr(const pair<T1,T2>& x) { \n\t\tpr(\"{\",x.f,\", \",x.s,\"}\"); \n\t}\n\ttemplate<class T> void pr(const T& x) { \n\t\tpr(\"{\"); // const iterator needed for vector<bool>\n\t\tbool fst = 1; for (const auto& a: x) pr(!fst?\", \":\"\",a), fst = 0; \n\t\tpr(\"}\");\n\t}\n\t\n\tvoid print() { pr(\"\\n\"); } // print w/ spaces\n\ttemplate<class T, class... Ts> void print(const T& t, const Ts&... ts) { \n\t\tpr(t); if (sizeof...(ts)) pr(\" \"); print(ts...); \n\t}\n}\n\nusing namespace output;\n\nusing state = tuple<int, int, int, int>;\n\nvi DX = {-1, 1, 0, 0};\nvi DY = {0, 0, -1, 1};\n\nint main() {\n\t// ios::sync_with_stdio(0), cin.tie(0), cout.tie(0);\n\t\n\tint H, W, K; cin >> H >> W >> K;\n\tint X1, Y1, X2, Y2; cin >> X1 >> Y1 >> X2 >> Y2; --X1; --Y1; --X2; --Y2;\n\tswap(X1, Y1);\n\tswap(X2, Y2);\n\n\tvector<vector<bool>> grid (H, vector<bool> (W));\n\tF0R(i, H) {\n\t\tF0R(j, W) {\n\t\t\tchar c; cin >> c;\n\t\t\tgrid[i][j] = c == '@';\n\t\t}\n\t}\n\n\tvector<vector<vector<vector<int>>>> dist (H, vector<vector<vector<int>>> (W, vector<vector<int>> (4, vector<int> (K + 1, 1e7))));\n\t\n\tdeque<state> q;\n\tF0R(i, 4) {\n\t\tq.push_front(make_tuple(X1, Y1, i, K));\n\t\tdist[Y1][X1][i][K] = 1;\n\t}\n\t\n\twhile (!q.empty()) {\n\t\tstate v = q.front();\n\t\tq.pop_front();\n\n\n\t\tint x = get<0>(v);\n\t\tint y = get<1>(v);\n\t\tint d = get<2>(v);\n\t\tint r = get<3>(v);\n\t\t\t\t\n\t\tint dis = dist[y][x][d][r];\n\n\t\t// print(\"SEARCHING\", x, y, d, r);\n\n\t\tF0R(i, 4) {\n\t\t\tif (dis + 1 < dist[y][x][i][K]) {\n\t\t\t\tdist[y][x][i][K] = dis + 1;\n\t\t\t\tq.push_back(make_tuple(x, y, i, K));\n\t\t\t}\n\t\t}\n\n\t\tif (r > 0) {\n\t\t\tint nx = x + DX[d];\n\t\t\tint ny = y + DY[d];\n\t\t\tif (0 <= nx && nx < W && 0 <= ny && ny < H && !grid[ny][nx]) {\n\t\t\t\tif (dis < dist[ny][nx][d][r-1]) {\n\t\t\t\t\tdist[ny][nx][d][r-1] = dis;\n\t\t\t\t\tq.push_front(make_tuple(nx, ny, d, r - 1));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tint ans = 1e7;\n\tF0R(i, 4) F0R(k, K+1) ans = min(ans, dist[Y2][X2][i][k]);\n\tprint((ans < 1e7) ? ans : -1); \n}", "language": "C++", "metadata": {"date": 1592272430, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02644.html", "problem_id": "p02644", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02644/input.txt", "sample_output_relpath": "derived/input_output/data/p02644/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02644/C++/s642314164.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s642314164", "user_id": "u148425972"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define FOR(i,a,b) for (int i = (a); i < (b); ++i)\n#define F0R(i,a) FOR(i,0,a)\n#define ROF(i,a,b) for (int i = (b)-1; i >= (a); --i)\n#define R0F(i,a) ROF(i,0,a)\n\nusing ll = long long;\nusing ld = long double;\nll INF = LLONG_MAX;\n\nusing vi = vector<int>;\nusing vll = vector<ll>;\nusing pii = pair<int, int>;\n\nnamespace output {\n\tvoid pr(int x) { cout << x; }\n\tvoid pr(long x) { cout << x; }\n\tvoid pr(ll x) { cout << x; }\n\tvoid pr(unsigned x) { cout << x; }\n\tvoid pr(unsigned long x) { cout << x; }\n\tvoid pr(unsigned long long x) { cout << x; }\n\tvoid pr(float x) { cout << x; }\n\tvoid pr(double x) { cout << x; }\n\tvoid pr(ld x) { cout << x; }\n\tvoid pr(char x) { cout << x; }\n\tvoid pr(const char* x) { cout << x; }\n\tvoid pr(const string& x) { cout << x; }\n\tvoid pr(bool x) { pr(x ? \"true\" : \"false\"); }\n\ttemplate<class T> void pr(const complex<T>& x) { cout << x; }\n\t\n\ttemplate<class T1, class T2> void pr(const pair<T1,T2>& x);\n\ttemplate<class T> void pr(const T& x);\n\t\n\ttemplate<class T, class... Ts> void pr(const T& t, const Ts&... ts) { \n\t\tpr(t); pr(ts...); \n\t}\n\ttemplate<class T1, class T2> void pr(const pair<T1,T2>& x) { \n\t\tpr(\"{\",x.f,\", \",x.s,\"}\"); \n\t}\n\ttemplate<class T> void pr(const T& x) { \n\t\tpr(\"{\"); // const iterator needed for vector<bool>\n\t\tbool fst = 1; for (const auto& a: x) pr(!fst?\", \":\"\",a), fst = 0; \n\t\tpr(\"}\");\n\t}\n\t\n\tvoid print() { pr(\"\\n\"); } // print w/ spaces\n\ttemplate<class T, class... Ts> void print(const T& t, const Ts&... ts) { \n\t\tpr(t); if (sizeof...(ts)) pr(\" \"); print(ts...); \n\t}\n}\n\nusing namespace output;\n\nusing state = tuple<int, int, int, int>;\n\nvi DX = {-1, 1, 0, 0};\nvi DY = {0, 0, -1, 1};\n\nint main() {\n\t// ios::sync_with_stdio(0), cin.tie(0), cout.tie(0);\n\t\n\tint H, W, K; cin >> H >> W >> K;\n\tint X1, Y1, X2, Y2; cin >> X1 >> Y1 >> X2 >> Y2; --X1; --Y1; --X2; --Y2;\n\tswap(X1, Y1);\n\tswap(X2, Y2);\n\n\tvector<vector<bool>> grid (H, vector<bool> (W));\n\tF0R(i, H) {\n\t\tF0R(j, W) {\n\t\t\tchar c; cin >> c;\n\t\t\tgrid[i][j] = c == '@';\n\t\t}\n\t}\n\n\tvector<vector<vector<vector<int>>>> dist (H, vector<vector<vector<int>>> (W, vector<vector<int>> (4, vector<int> (K + 1, 1e7))));\n\t\n\tdeque<state> q;\n\tF0R(i, 4) {\n\t\tq.push_front(make_tuple(X1, Y1, i, K));\n\t\tdist[Y1][X1][i][K] = 1;\n\t}\n\t\n\twhile (!q.empty()) {\n\t\tstate v = q.front();\n\t\tq.pop_front();\n\n\n\t\tint x = get<0>(v);\n\t\tint y = get<1>(v);\n\t\tint d = get<2>(v);\n\t\tint r = get<3>(v);\n\t\t\t\t\n\t\tint dis = dist[y][x][d][r];\n\n\t\t// print(\"SEARCHING\", x, y, d, r);\n\n\t\tF0R(i, 4) {\n\t\t\tif (dis + 1 < dist[y][x][i][K]) {\n\t\t\t\tdist[y][x][i][K] = dis + 1;\n\t\t\t\tq.push_back(make_tuple(x, y, i, K));\n\t\t\t}\n\t\t}\n\n\t\tif (r > 0) {\n\t\t\tint nx = x + DX[d];\n\t\t\tint ny = y + DY[d];\n\t\t\tif (0 <= nx && nx < W && 0 <= ny && ny < H && !grid[ny][nx]) {\n\t\t\t\tif (dis < dist[ny][nx][d][r-1]) {\n\t\t\t\t\tdist[ny][nx][d][r-1] = dis;\n\t\t\t\t\tq.push_front(make_tuple(nx, ny, d, r - 1));\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tint ans = 1e7;\n\tF0R(i, 4) F0R(k, K+1) ans = min(ans, dist[Y2][X2][i][k]);\n\tprint((ans < 1e7) ? ans : -1); \n}", "problem_context": "Score : 600 points\n\nProblem Statement\n\nSnuke, a water strider, lives in a rectangular pond that can be seen as a grid with H east-west rows and W north-south columns. Let (i,j) be the square at the i-th row from the north and j-th column from the west.\n\nSome of the squares have a lotus leaf on it and cannot be entered.\nThe square (i,j) has a lotus leaf on it if c_{ij} is @, and it does not if c_{ij} is ..\n\nIn one stroke, Snuke can move between 1 and K squares (inclusive) toward one of the four directions: north, east, south, and west.\nThe move may not pass through a square with a lotus leaf. Moving to such a square or out of the pond is also forbidden.\n\nFind the minimum number of strokes Snuke takes to travel from the square (x_1,y_1) to (x_2,y_2).\nIf the travel from (x_1,y_1) to (x_2,y_2) is impossible, point out that fact.\n\nConstraints\n\n1 \\leq H,W,K \\leq 10^6\n\nH \\times W \\leq 10^6\n\n1 \\leq x_1,x_2 \\leq H\n\n1 \\leq y_1,y_2 \\leq W\n\nx_1 \\neq x_2 or y_1 \\neq y_2.\n\nc_{i,j} is . or @.\n\nc_{x_1,y_1} = .\n\nc_{x_2,y_2} = .\n\nAll numbers in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W K\nx_1 y_1 x_2 y_2\nc_{1,1}c_{1,2} .. c_{1,W}\nc_{2,1}c_{2,2} .. c_{2,W}\n:\nc_{H,1}c_{H,2} .. c_{H,W}\n\nOutput\n\nPrint the minimum number of strokes Snuke takes to travel from the square (x_1,y_1) to (x_2,y_2), or print -1 if the travel is impossible.\n\nSample Input 1\n\n3 5 2\n3 2 3 4\n.....\n.@..@\n..@..\n\nSample Output 1\n\n5\n\nInitially, Snuke is at the square (3,2).\nHe can reach the square (3, 4) by making five strokes as follows:\n\nFrom (3, 2), go west one square to (3, 1).\n\nFrom (3, 1), go north two squares to (1, 1).\n\nFrom (1, 1), go east two squares to (1, 3).\n\nFrom (1, 3), go east one square to (1, 4).\n\nFrom (1, 4), go south two squares to (3, 4).\n\nSample Input 2\n\n1 6 4\n1 1 1 6\n......\n\nSample Output 2\n\n2\n\nSample Input 3\n\n3 3 1\n2 1 2 3\n.@.\n.@.\n.@.\n\nSample Output 3\n\n-1", "sample_input": "3 5 2\n3 2 3 4\n.....\n.@..@\n..@..\n"}, "reference_outputs": ["5\n"], "source_document_id": "p02644", "source_text": "Score : 600 points\n\nProblem Statement\n\nSnuke, a water strider, lives in a rectangular pond that can be seen as a grid with H east-west rows and W north-south columns. Let (i,j) be the square at the i-th row from the north and j-th column from the west.\n\nSome of the squares have a lotus leaf on it and cannot be entered.\nThe square (i,j) has a lotus leaf on it if c_{ij} is @, and it does not if c_{ij} is ..\n\nIn one stroke, Snuke can move between 1 and K squares (inclusive) toward one of the four directions: north, east, south, and west.\nThe move may not pass through a square with a lotus leaf. Moving to such a square or out of the pond is also forbidden.\n\nFind the minimum number of strokes Snuke takes to travel from the square (x_1,y_1) to (x_2,y_2).\nIf the travel from (x_1,y_1) to (x_2,y_2) is impossible, point out that fact.\n\nConstraints\n\n1 \\leq H,W,K \\leq 10^6\n\nH \\times W \\leq 10^6\n\n1 \\leq x_1,x_2 \\leq H\n\n1 \\leq y_1,y_2 \\leq W\n\nx_1 \\neq x_2 or y_1 \\neq y_2.\n\nc_{i,j} is . or @.\n\nc_{x_1,y_1} = .\n\nc_{x_2,y_2} = .\n\nAll numbers in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W K\nx_1 y_1 x_2 y_2\nc_{1,1}c_{1,2} .. c_{1,W}\nc_{2,1}c_{2,2} .. c_{2,W}\n:\nc_{H,1}c_{H,2} .. c_{H,W}\n\nOutput\n\nPrint the minimum number of strokes Snuke takes to travel from the square (x_1,y_1) to (x_2,y_2), or print -1 if the travel is impossible.\n\nSample Input 1\n\n3 5 2\n3 2 3 4\n.....\n.@..@\n..@..\n\nSample Output 1\n\n5\n\nInitially, Snuke is at the square (3,2).\nHe can reach the square (3, 4) by making five strokes as follows:\n\nFrom (3, 2), go west one square to (3, 1).\n\nFrom (3, 1), go north two squares to (1, 1).\n\nFrom (1, 1), go east two squares to (1, 3).\n\nFrom (1, 3), go east one square to (1, 4).\n\nFrom (1, 4), go south two squares to (3, 4).\n\nSample Input 2\n\n1 6 4\n1 1 1 6\n......\n\nSample Output 2\n\n2\n\nSample Input 3\n\n3 3 1\n2 1 2 3\n.@.\n.@.\n.@.\n\nSample Output 3\n\n-1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2984, "cpu_time_ms": 3335, "memory_kb": 3557680}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s334577794", "group_id": "codeNet:p02646", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nint main() {\n  int a,v;\n  cin >> a >> v;\n  int b,w;\n  cin >> b >> w;\n  int t;\n  cin >> t;\n  bool fg = false;\n  for (int i = 1; i <= t; i++) {\n    if (a > b) {\n      a = a - v;\n      b = b - w;\n      if (a == b) {\n        fg = true;\n      }\n    }\n    if (a < b) {\n      a = a + v;\n      b = b + w;\n      if (a == b) {\n        fg = true;\n      }\n    }\n  }\n  if (fg) {\n    cout << \"YES\" << endl;\n  } else {\n    cout << \"NO\" << endl;\n  }\n  return 0;\n}", "language": "C++", "metadata": {"date": 1592103135, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02646.html", "problem_id": "p02646", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02646/input.txt", "sample_output_relpath": "derived/input_output/data/p02646/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02646/C++/s334577794.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s334577794", "user_id": "u583232278"}, "prompt_components": {"gold_output": "YES\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nint main() {\n  int a,v;\n  cin >> a >> v;\n  int b,w;\n  cin >> b >> w;\n  int t;\n  cin >> t;\n  bool fg = false;\n  for (int i = 1; i <= t; i++) {\n    if (a > b) {\n      a = a - v;\n      b = b - w;\n      if (a == b) {\n        fg = true;\n      }\n    }\n    if (a < b) {\n      a = a + v;\n      b = b + w;\n      if (a == b) {\n        fg = true;\n      }\n    }\n  }\n  if (fg) {\n    cout << \"YES\" << endl;\n  } else {\n    cout << \"NO\" << endl;\n  }\n  return 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nTwo children are playing tag on a number line. (In the game of tag, the child called \"it\" tries to catch the other child.) The child who is \"it\" is now at coordinate A, and he can travel the distance of V per second.\nThe other child is now at coordinate B, and she can travel the distance of W per second.\n\nHe can catch her when his coordinate is the same as hers.\nDetermine whether he can catch her within T seconds (including exactly T seconds later).\nWe assume that both children move optimally.\n\nConstraints\n\n-10^9 \\leq A,B \\leq 10^9\n\n1 \\leq V,W \\leq 10^9\n\n1 \\leq T \\leq 10^9\n\nA \\neq B\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA V\nB W\nT\n\nOutput\n\nIf \"it\" can catch the other child, print YES; otherwise, print NO.\n\nSample Input 1\n\n1 2\n3 1\n3\n\nSample Output 1\n\nYES\n\nSample Input 2\n\n1 2\n3 2\n3\n\nSample Output 2\n\nNO\n\nSample Input 3\n\n1 2\n3 3\n3\n\nSample Output 3\n\nNO", "sample_input": "1 2\n3 1\n3\n"}, "reference_outputs": ["YES\n"], "source_document_id": "p02646", "source_text": "Score : 200 points\n\nProblem Statement\n\nTwo children are playing tag on a number line. (In the game of tag, the child called \"it\" tries to catch the other child.) The child who is \"it\" is now at coordinate A, and he can travel the distance of V per second.\nThe other child is now at coordinate B, and she can travel the distance of W per second.\n\nHe can catch her when his coordinate is the same as hers.\nDetermine whether he can catch her within T seconds (including exactly T seconds later).\nWe assume that both children move optimally.\n\nConstraints\n\n-10^9 \\leq A,B \\leq 10^9\n\n1 \\leq V,W \\leq 10^9\n\n1 \\leq T \\leq 10^9\n\nA \\neq B\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA V\nB W\nT\n\nOutput\n\nIf \"it\" can catch the other child, print YES; otherwise, print NO.\n\nSample Input 1\n\n1 2\n3 1\n3\n\nSample Output 1\n\nYES\n\nSample Input 2\n\n1 2\n3 2\n3\n\nSample Output 2\n\nNO\n\nSample Input 3\n\n1 2\n3 3\n3\n\nSample Output 3\n\nNO", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 492, "cpu_time_ms": 968, "memory_kb": 3628}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s919710448", "group_id": "codeNet:p02647", "input_text": "#include <iostream>\n#include <string>\n#include <vector>\n#include <stdio.h>\n#include <algorithm>\n#define _USE_MATH_DEFINES\n#include <cmath>\n#include <numeric>\n#include <iomanip>\n#include <deque>\n#include <tuple>\n#include <queue>\n#include <stack>\n#include <map>\n#include <set>\n#include <unordered_map>\n#include <sstream>\n#include <stdexcept>\n#include <boost/multiprecision/cpp_int.hpp>\n#include <boost/multiprecision/cpp_dec_float.hpp>\n\n#define rep(i, x) for (int i = 0; i < (int)(x); i++)\n#define FOR(i, a, done) for (int i = (a); i < (done); ++i)\n#define all(a) (a).begin(), (a).end()\n#define x first\n#define y second\n#define debug(a) cout << (a) << endl\nnamespace mp = boost::multiprecision;\nusing cpp_int = mp::cpp_int;\nusing ll = long long;\nusing namespace std;\ntemplate <class T>\nbool chmax(T &a, const T &b)\n{\n\tif (a < b)\n\t{\n\t\ta = b;\n\t\treturn 1;\n\t}\n\treturn 0;\n}\ntemplate <class T>\nbool chmin(T &a, const T &b)\n{\n\tif (a > b)\n\t{\n\t\ta = b;\n\t\treturn 1;\n\t}\n\treturn 0;\n}\n\nll M = 1000000007;\n\nvoid solve()\n{\n\tint n,k;\n\tcin>>n>>k;\n\tvector<int>a(n);\n\tvector<vector<int>>imos(k+2,vector<int>(n+2,0));\n\trep(i,n){\n\t\tcin>>a[i];\n\t\tint mi=max(i-a[i],0);\n\t\tint ma=min(n-1,i+a[i]);\n\t\timos[0][mi]++;\n\t\timos[0][ma+1]--;\n\t\t\n\t}\n\tif((ll)n*k>=(ll)1e6 or n<=k){\n\t\trep(i,n){\n\t\t\tcout<<n;\n\t\t\tif(i!=n-1){\n\t\t\t\tcout<<\" \";\n\t\t\t}else{\n\t\t\t\tcout<<endl;\n\t\t\t}\n\t\t}\n\t\treturn ;\n\t}\n\tint cur=0;\n\trep(j,min(k,50)){\n\t\tcur=0;\n\t\tbool fin=true;\n\t\trep(i,n){\n\t\t\tcur+=imos[j][i];\n\t\t\ta[i]=cur;\n\t\t\tint mi=max(i-a[i],0);\n\t\t\tint ma=min(n-1,i+a[i]);\n\t\t\timos[j+1][mi]++;\n\t\t\timos[j+1][ma+1]--;\n\t\t\tif(a[i]!=n){\n\t\t\t\tfin=false;\n\t\t\t}\n\t\t}\n\t\tif(fin){\n\t\t\t//cout<<j<<endl;\n\t\t\trep(i,n){\n\t\t\t\tcout<<n;\n\t\t\t\tif(i!=n-1){\n\t\t\t\t\tcout<<\" \";\n\t\t\t\t}else{\n\t\t\t\t\tcout<<endl;\n\t\t\t\t}\n\t\t\t}\n\t\t\treturn ;\n\t\t}\n\t}\n\trep(i,n){\n\t\tcout<<a[i];\n\t\tif(i!=n-1){\n\t\t\tcout<<\" \";\n\t\t}else{\n\t\t\tcout<<endl;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tios::sync_with_stdio(false);\n\tcin.tie(nullptr);\n\tsolve();\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1592100078, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02647.html", "problem_id": "p02647", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02647/input.txt", "sample_output_relpath": "derived/input_output/data/p02647/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02647/C++/s919710448.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s919710448", "user_id": "u775013393"}, "prompt_components": {"gold_output": "1 2 2 1 2\n", "input_to_evaluate": "#include <iostream>\n#include <string>\n#include <vector>\n#include <stdio.h>\n#include <algorithm>\n#define _USE_MATH_DEFINES\n#include <cmath>\n#include <numeric>\n#include <iomanip>\n#include <deque>\n#include <tuple>\n#include <queue>\n#include <stack>\n#include <map>\n#include <set>\n#include <unordered_map>\n#include <sstream>\n#include <stdexcept>\n#include <boost/multiprecision/cpp_int.hpp>\n#include <boost/multiprecision/cpp_dec_float.hpp>\n\n#define rep(i, x) for (int i = 0; i < (int)(x); i++)\n#define FOR(i, a, done) for (int i = (a); i < (done); ++i)\n#define all(a) (a).begin(), (a).end()\n#define x first\n#define y second\n#define debug(a) cout << (a) << endl\nnamespace mp = boost::multiprecision;\nusing cpp_int = mp::cpp_int;\nusing ll = long long;\nusing namespace std;\ntemplate <class T>\nbool chmax(T &a, const T &b)\n{\n\tif (a < b)\n\t{\n\t\ta = b;\n\t\treturn 1;\n\t}\n\treturn 0;\n}\ntemplate <class T>\nbool chmin(T &a, const T &b)\n{\n\tif (a > b)\n\t{\n\t\ta = b;\n\t\treturn 1;\n\t}\n\treturn 0;\n}\n\nll M = 1000000007;\n\nvoid solve()\n{\n\tint n,k;\n\tcin>>n>>k;\n\tvector<int>a(n);\n\tvector<vector<int>>imos(k+2,vector<int>(n+2,0));\n\trep(i,n){\n\t\tcin>>a[i];\n\t\tint mi=max(i-a[i],0);\n\t\tint ma=min(n-1,i+a[i]);\n\t\timos[0][mi]++;\n\t\timos[0][ma+1]--;\n\t\t\n\t}\n\tif((ll)n*k>=(ll)1e6 or n<=k){\n\t\trep(i,n){\n\t\t\tcout<<n;\n\t\t\tif(i!=n-1){\n\t\t\t\tcout<<\" \";\n\t\t\t}else{\n\t\t\t\tcout<<endl;\n\t\t\t}\n\t\t}\n\t\treturn ;\n\t}\n\tint cur=0;\n\trep(j,min(k,50)){\n\t\tcur=0;\n\t\tbool fin=true;\n\t\trep(i,n){\n\t\t\tcur+=imos[j][i];\n\t\t\ta[i]=cur;\n\t\t\tint mi=max(i-a[i],0);\n\t\t\tint ma=min(n-1,i+a[i]);\n\t\t\timos[j+1][mi]++;\n\t\t\timos[j+1][ma+1]--;\n\t\t\tif(a[i]!=n){\n\t\t\t\tfin=false;\n\t\t\t}\n\t\t}\n\t\tif(fin){\n\t\t\t//cout<<j<<endl;\n\t\t\trep(i,n){\n\t\t\t\tcout<<n;\n\t\t\t\tif(i!=n-1){\n\t\t\t\t\tcout<<\" \";\n\t\t\t\t}else{\n\t\t\t\t\tcout<<endl;\n\t\t\t\t}\n\t\t\t}\n\t\t\treturn ;\n\t\t}\n\t}\n\trep(i,n){\n\t\tcout<<a[i];\n\t\tif(i!=n-1){\n\t\t\tcout<<\" \";\n\t\t}else{\n\t\t\tcout<<endl;\n\t\t}\n\t}\n}\n\nint main()\n{\n\tios::sync_with_stdio(false);\n\tcin.tie(nullptr);\n\tsolve();\n\treturn 0;\n}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nWe have N bulbs arranged on a number line, numbered 1 to N from left to right.\nBulb i is at coordinate i.\n\nEach bulb has a non-negative integer parameter called intensity.\nWhen there is a bulb of intensity d at coordinate x, the bulb illuminates the segment from coordinate x-d-0.5 to x+d+0.5.\nInitially, the intensity of Bulb i is A_i. We will now do the following operation K times in a row:\n\nFor each integer i between 1 and N (inclusive), let B_i be the number of bulbs illuminating coordinate i. Then, change the intensity of each bulb i to B_i.\n\nFind the intensity of each bulb after the K operations.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq K \\leq 2 \\times 10^5\n\n0 \\leq A_i \\leq N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nA_1 A_2 \\ldots A_N\n\nOutput\n\nPrint the intensity A{'}_i of each bulb i after the K operations to Standard Output in the following format:\n\nA{'}_1 A{'}_2 \\ldots A{'}_N\n\nSample Input 1\n\n5 1\n1 0 0 1 0\n\nSample Output 1\n\n1 2 2 1 2\n\nInitially, only Bulb 1 illuminates coordinate 1, so the intensity of Bulb 1 becomes 1 after the operation.\nSimilarly, the bulbs initially illuminating coordinate 2 are Bulb 1 and 2, so the intensity of Bulb 2 becomes 2.\n\nSample Input 2\n\n5 2\n1 0 0 1 0\n\nSample Output 2\n\n3 3 4 4 3", "sample_input": "5 1\n1 0 0 1 0\n"}, "reference_outputs": ["1 2 2 1 2\n"], "source_document_id": "p02647", "source_text": "Score : 500 points\n\nProblem Statement\n\nWe have N bulbs arranged on a number line, numbered 1 to N from left to right.\nBulb i is at coordinate i.\n\nEach bulb has a non-negative integer parameter called intensity.\nWhen there is a bulb of intensity d at coordinate x, the bulb illuminates the segment from coordinate x-d-0.5 to x+d+0.5.\nInitially, the intensity of Bulb i is A_i. We will now do the following operation K times in a row:\n\nFor each integer i between 1 and N (inclusive), let B_i be the number of bulbs illuminating coordinate i. Then, change the intensity of each bulb i to B_i.\n\nFind the intensity of each bulb after the K operations.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq K \\leq 2 \\times 10^5\n\n0 \\leq A_i \\leq N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nA_1 A_2 \\ldots A_N\n\nOutput\n\nPrint the intensity A{'}_i of each bulb i after the K operations to Standard Output in the following format:\n\nA{'}_1 A{'}_2 \\ldots A{'}_N\n\nSample Input 1\n\n5 1\n1 0 0 1 0\n\nSample Output 1\n\n1 2 2 1 2\n\nInitially, only Bulb 1 illuminates coordinate 1, so the intensity of Bulb 1 becomes 1 after the operation.\nSimilarly, the bulbs initially illuminating coordinate 2 are Bulb 1 and 2, so the intensity of Bulb 2 becomes 2.\n\nSample Input 2\n\n5 2\n1 0 0 1 0\n\nSample Output 2\n\n3 3 4 4 3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1900, "cpu_time_ms": 2207, "memory_kb": 3532348}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s359053831", "group_id": "codeNet:p02647", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n\nint main() {\n    ll N, K; cin >> N >> K;\n    vector<ll> A(N); for (int i = 0; i < N; i++) cin >> A[i];\n\n    while (K--) {\n        vector<ll> inout(N+1, 0);\n        for (int i = 0; i < N; i++) {\n            inout[max((ll)0, i - A[i])]++;\n            inout[min(N, i+A[i]+1)]--;\n        }\n        A[0] = inout[0];\n        for (int i = 1; i < N; i++) {\n            A[i] = A[i-1] + inout[i];\n        }\n        bool f = true;\n        for (int i = 0; i < N; i++) {\n            f = f && (A[i] == N);\n        }\n        if (f) break;\n    }\n    for (int i = 0; i < N; i++) {\n        cout << A[i] << ' ';\n    }\n    cout << endl;\n}", "language": "C++", "metadata": {"date": 1592098837, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02647.html", "problem_id": "p02647", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02647/input.txt", "sample_output_relpath": "derived/input_output/data/p02647/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02647/C++/s359053831.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s359053831", "user_id": "u858575800"}, "prompt_components": {"gold_output": "1 2 2 1 2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n\nint main() {\n    ll N, K; cin >> N >> K;\n    vector<ll> A(N); for (int i = 0; i < N; i++) cin >> A[i];\n\n    while (K--) {\n        vector<ll> inout(N+1, 0);\n        for (int i = 0; i < N; i++) {\n            inout[max((ll)0, i - A[i])]++;\n            inout[min(N, i+A[i]+1)]--;\n        }\n        A[0] = inout[0];\n        for (int i = 1; i < N; i++) {\n            A[i] = A[i-1] + inout[i];\n        }\n        bool f = true;\n        for (int i = 0; i < N; i++) {\n            f = f && (A[i] == N);\n        }\n        if (f) break;\n    }\n    for (int i = 0; i < N; i++) {\n        cout << A[i] << ' ';\n    }\n    cout << endl;\n}", "problem_context": "Score : 500 points\n\nProblem Statement\n\nWe have N bulbs arranged on a number line, numbered 1 to N from left to right.\nBulb i is at coordinate i.\n\nEach bulb has a non-negative integer parameter called intensity.\nWhen there is a bulb of intensity d at coordinate x, the bulb illuminates the segment from coordinate x-d-0.5 to x+d+0.5.\nInitially, the intensity of Bulb i is A_i. We will now do the following operation K times in a row:\n\nFor each integer i between 1 and N (inclusive), let B_i be the number of bulbs illuminating coordinate i. Then, change the intensity of each bulb i to B_i.\n\nFind the intensity of each bulb after the K operations.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq K \\leq 2 \\times 10^5\n\n0 \\leq A_i \\leq N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nA_1 A_2 \\ldots A_N\n\nOutput\n\nPrint the intensity A{'}_i of each bulb i after the K operations to Standard Output in the following format:\n\nA{'}_1 A{'}_2 \\ldots A{'}_N\n\nSample Input 1\n\n5 1\n1 0 0 1 0\n\nSample Output 1\n\n1 2 2 1 2\n\nInitially, only Bulb 1 illuminates coordinate 1, so the intensity of Bulb 1 becomes 1 after the operation.\nSimilarly, the bulbs initially illuminating coordinate 2 are Bulb 1 and 2, so the intensity of Bulb 2 becomes 2.\n\nSample Input 2\n\n5 2\n1 0 0 1 0\n\nSample Output 2\n\n3 3 4 4 3", "sample_input": "5 1\n1 0 0 1 0\n"}, "reference_outputs": ["1 2 2 1 2\n"], "source_document_id": "p02647", "source_text": "Score : 500 points\n\nProblem Statement\n\nWe have N bulbs arranged on a number line, numbered 1 to N from left to right.\nBulb i is at coordinate i.\n\nEach bulb has a non-negative integer parameter called intensity.\nWhen there is a bulb of intensity d at coordinate x, the bulb illuminates the segment from coordinate x-d-0.5 to x+d+0.5.\nInitially, the intensity of Bulb i is A_i. We will now do the following operation K times in a row:\n\nFor each integer i between 1 and N (inclusive), let B_i be the number of bulbs illuminating coordinate i. Then, change the intensity of each bulb i to B_i.\n\nFind the intensity of each bulb after the K operations.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq K \\leq 2 \\times 10^5\n\n0 \\leq A_i \\leq N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nA_1 A_2 \\ldots A_N\n\nOutput\n\nPrint the intensity A{'}_i of each bulb i after the K operations to Standard Output in the following format:\n\nA{'}_1 A{'}_2 \\ldots A{'}_N\n\nSample Input 1\n\n5 1\n1 0 0 1 0\n\nSample Output 1\n\n1 2 2 1 2\n\nInitially, only Bulb 1 illuminates coordinate 1, so the intensity of Bulb 1 becomes 1 after the operation.\nSimilarly, the bulbs initially illuminating coordinate 2 are Bulb 1 and 2, so the intensity of Bulb 2 becomes 2.\n\nSample Input 2\n\n5 2\n1 0 0 1 0\n\nSample Output 2\n\n3 3 4 4 3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 687, "cpu_time_ms": 81, "memory_kb": 6376}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s937100166", "group_id": "codeNet:p02648", "input_text": "#include <bits/stdc++.h>\ntypedef long long LL;\n#define FOR(i,a,b) for(int i=(a);i<(b);++i)\n#define REP(i,n) FOR(i,0,n)\n\nusing namespace std;\n\nint main(void)\n{\n  int n;\n  cin >> n;\n  vector<LL> value(1<<18), weight(1<<18);\n  FOR(i,1,n+1) cin >> value[i] >> weight[i];\n  vector<vector<pair<LL, LL>>> hanzen(1<<11); // weight, value\n  hanzen[0].emplace_back(0,0);\n  FOR(bits,1,1<<11) {\n    for(pair<LL,LL> p:hanzen[bits/2]) {\n      pair<LL,LL> added = make_pair(p.first+weight[bits], p.second+value[bits]);\n      hanzen[bits].push_back(p);\n      hanzen[bits].push_back(added);\n    }\n    vector<pair<LL,LL>> tmp(hanzen[bits].begin(),hanzen[bits].end());\n    sort(tmp.begin(),tmp.end());\n    hanzen[bits].clear();\n    hanzen[bits].emplace_back(0,0);\n    for(pair<LL,LL> p:tmp) {\n      if(hanzen[bits].back().second < p.second) hanzen[bits].push_back(p);\n    }\n  }\n  int q;\n  cin >> q;\n  while(q--) {\n    LL v, l;\n    cin >> v >> l;\n    vector<pair<LL,LL>> comb;\n    comb.emplace_back(0,0);\n    while(v>=(1<<11)) {\n      vector<pair<LL,LL>> tmp(comb.begin(), comb.end());\n      for(pair<LL,LL> p:tmp) {\n        pair<LL,LL> added = make_pair(p.first+weight[v], p.second+value[v]);\n        comb.push_back(added);\n      }\n      v/=2;\n    }\n    LL answer = 0;\n    for(pair<LL,LL> p: comb) {\n      LL cw,cv;\n      tie(cw,cv) = p;\n      if(cw>l) continue;\n      auto ite = lower_bound(hanzen[v].begin(),hanzen[v].end(), make_pair(l-cw+1,0ll));\n      --ite;\n      answer=max(answer, cv+ite->second);\n    }\n    cout << answer << endl;\n  }\n\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1592114167, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02648.html", "problem_id": "p02648", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02648/input.txt", "sample_output_relpath": "derived/input_output/data/p02648/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02648/C++/s937100166.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s937100166", "user_id": "u633757735"}, "prompt_components": {"gold_output": "0\n3\n3\n", "input_to_evaluate": "#include <bits/stdc++.h>\ntypedef long long LL;\n#define FOR(i,a,b) for(int i=(a);i<(b);++i)\n#define REP(i,n) FOR(i,0,n)\n\nusing namespace std;\n\nint main(void)\n{\n  int n;\n  cin >> n;\n  vector<LL> value(1<<18), weight(1<<18);\n  FOR(i,1,n+1) cin >> value[i] >> weight[i];\n  vector<vector<pair<LL, LL>>> hanzen(1<<11); // weight, value\n  hanzen[0].emplace_back(0,0);\n  FOR(bits,1,1<<11) {\n    for(pair<LL,LL> p:hanzen[bits/2]) {\n      pair<LL,LL> added = make_pair(p.first+weight[bits], p.second+value[bits]);\n      hanzen[bits].push_back(p);\n      hanzen[bits].push_back(added);\n    }\n    vector<pair<LL,LL>> tmp(hanzen[bits].begin(),hanzen[bits].end());\n    sort(tmp.begin(),tmp.end());\n    hanzen[bits].clear();\n    hanzen[bits].emplace_back(0,0);\n    for(pair<LL,LL> p:tmp) {\n      if(hanzen[bits].back().second < p.second) hanzen[bits].push_back(p);\n    }\n  }\n  int q;\n  cin >> q;\n  while(q--) {\n    LL v, l;\n    cin >> v >> l;\n    vector<pair<LL,LL>> comb;\n    comb.emplace_back(0,0);\n    while(v>=(1<<11)) {\n      vector<pair<LL,LL>> tmp(comb.begin(), comb.end());\n      for(pair<LL,LL> p:tmp) {\n        pair<LL,LL> added = make_pair(p.first+weight[v], p.second+value[v]);\n        comb.push_back(added);\n      }\n      v/=2;\n    }\n    LL answer = 0;\n    for(pair<LL,LL> p: comb) {\n      LL cw,cv;\n      tie(cw,cv) = p;\n      if(cw>l) continue;\n      auto ite = lower_bound(hanzen[v].begin(),hanzen[v].end(), make_pair(l-cw+1,0ll));\n      --ite;\n      answer=max(answer, cv+ite->second);\n    }\n    cout << answer << endl;\n  }\n\n  return 0;\n}\n", "problem_context": "Score : 700 points\n\nProblem Statement\n\nWe have a rooted binary tree with N vertices, where the vertices are numbered 1 to N.\nVertex 1 is the root, and the parent of Vertex i (i \\geq 2) is Vertex \\left[ \\frac{i}{2} \\right].\n\nEach vertex has one item in it. The item in Vertex i has a value of V_i and a weight of W_i.\nNow, process the following query Q times:\n\nGiven are a vertex v of the tree and a positive integer L.\nLet us choose some (possibly none) of the items in v and the ancestors of v so that their total weight is at most L.\nFind the maximum possible total value of the chosen items.\n\nHere, Vertex u is said to be an ancestor of Vertex v when u is an indirect parent of v, that is, there exists a sequence of vertices w_1,w_2,\\ldots,w_k (k\\geq 2) where w_1=v, w_k=u, and w_{i+1} is the parent of w_i for each i.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N < 2^{18}\n\n1 \\leq Q \\leq 10^5\n\n1 \\leq V_i \\leq 10^5\n\n1 \\leq W_i \\leq 10^5\n\nFor the values v and L given in each query, 1 \\leq v \\leq N and 1 \\leq L \\leq 10^5.\n\nInput\n\nLet v_i and L_i be the values v and L given in the i-th query.\nThen, Input is given from Standard Input in the following format:\n\nN\nV_1 W_1\n:\nV_N W_N\nQ\nv_1 L_1\n:\nv_Q L_Q\n\nOutput\n\nFor each integer i from 1 through Q,\nthe i-th line should contain the response to the i-th query.\n\nSample Input 1\n\n3\n1 2\n2 3\n3 4\n3\n1 1\n2 5\n3 5\n\nSample Output 1\n\n0\n3\n3\n\nIn the first query, we are given only one choice: the item with (V, W)=(1,2). Since L = 1, we cannot actually choose it, so our response should be 0.\n\nIn the second query, we are given two choices: the items with (V, W)=(1,2) and (V, W)=(2,3). Since L = 5, we can choose both of them, so our response should be 3.\n\nSample Input 2\n\n15\n123 119\n129 120\n132 112\n126 109\n118 103\n115 109\n102 100\n130 120\n105 105\n132 115\n104 102\n107 107\n127 116\n121 104\n121 115\n8\n8 234\n9 244\n10 226\n11 227\n12 240\n13 237\n14 206\n15 227\n\nSample Output 2\n\n256\n255\n250\n247\n255\n259\n223\n253", "sample_input": "3\n1 2\n2 3\n3 4\n3\n1 1\n2 5\n3 5\n"}, "reference_outputs": ["0\n3\n3\n"], "source_document_id": "p02648", "source_text": "Score : 700 points\n\nProblem Statement\n\nWe have a rooted binary tree with N vertices, where the vertices are numbered 1 to N.\nVertex 1 is the root, and the parent of Vertex i (i \\geq 2) is Vertex \\left[ \\frac{i}{2} \\right].\n\nEach vertex has one item in it. The item in Vertex i has a value of V_i and a weight of W_i.\nNow, process the following query Q times:\n\nGiven are a vertex v of the tree and a positive integer L.\nLet us choose some (possibly none) of the items in v and the ancestors of v so that their total weight is at most L.\nFind the maximum possible total value of the chosen items.\n\nHere, Vertex u is said to be an ancestor of Vertex v when u is an indirect parent of v, that is, there exists a sequence of vertices w_1,w_2,\\ldots,w_k (k\\geq 2) where w_1=v, w_k=u, and w_{i+1} is the parent of w_i for each i.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N < 2^{18}\n\n1 \\leq Q \\leq 10^5\n\n1 \\leq V_i \\leq 10^5\n\n1 \\leq W_i \\leq 10^5\n\nFor the values v and L given in each query, 1 \\leq v \\leq N and 1 \\leq L \\leq 10^5.\n\nInput\n\nLet v_i and L_i be the values v and L given in the i-th query.\nThen, Input is given from Standard Input in the following format:\n\nN\nV_1 W_1\n:\nV_N W_N\nQ\nv_1 L_1\n:\nv_Q L_Q\n\nOutput\n\nFor each integer i from 1 through Q,\nthe i-th line should contain the response to the i-th query.\n\nSample Input 1\n\n3\n1 2\n2 3\n3 4\n3\n1 1\n2 5\n3 5\n\nSample Output 1\n\n0\n3\n3\n\nIn the first query, we are given only one choice: the item with (V, W)=(1,2). Since L = 1, we cannot actually choose it, so our response should be 0.\n\nIn the second query, we are given two choices: the items with (V, W)=(1,2) and (V, W)=(2,3). Since L = 5, we can choose both of them, so our response should be 3.\n\nSample Input 2\n\n15\n123 119\n129 120\n132 112\n126 109\n118 103\n115 109\n102 100\n130 120\n105 105\n132 115\n104 102\n107 107\n127 116\n121 104\n121 115\n8\n8 234\n9 244\n10 226\n11 227\n12 240\n13 237\n14 206\n15 227\n\nSample Output 2\n\n256\n255\n250\n247\n255\n259\n223\n253", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1540, "cpu_time_ms": 1266, "memory_kb": 51104}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s714032417", "group_id": "codeNet:p02648", "input_text": "#include<bits/stdc++.h>\n\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll,ll> pa;\n\n#define fst first\n#define snd second\n#define pb push_back\n\nconst int maxn=500005,maxm=512;\nconst double pi=acos(-1.0);\n//const ll mod=1000000007;\nconst ll mod=998244353;\nconst double eps=1e-8;\n\nint dig(int xx)\n{\n    for(int i=0;;i++)\n    {\n        if(xx>>i&1) return i;\n    }\n}\n\n\nstruct dat\n{\n    int sta;\n    ll v,w;\n    dat(ll v=0,ll w=0):sta(sta),v(v),w(w){}\n};\n\nint n,q;\nint v[maxn]={0},w[maxn]={0};\n\nll ve[maxm][maxm][2]={0};\n\nvector<pa> ans1[maxm];\n\nvector<pa> tmp;\n\nll cl2(int vv,int ww)\n{\n    int lb=0,ub=ans1[vv].size();\n    while(ub-lb>1)\n    {\n        int mid=(ub+lb)/2;\n        if(ans1[vv][mid].fst<=ww) lb=mid;\n        else ub=mid;\n    }\n    return ans1[vv][lb].snd;\n}\n\n\nvoid solve(int vv,int L)\n{\n    int i,j;\n    if(vv<512)\n    {\n        for(j=0;;j++) {if((vv<<j)>=maxm/2&&(vv<<j)<maxm) break;}\n        ll ans=0;\n        for(i=1;i<(1<<(j+1));i++)\n        {\n            if(ve[vv<<j][i][1]<=L) ans=max(ans,ve[vv<<j][i][0]);\n        }\n        printf(\"%lld\\n\",ans);return;\n    }\n    tmp.clear();tmp.pb(pa(0,0));if(w[vv]<=L) tmp.pb(pa(w[vv],v[vv]));\n    while(1)\n    {\n        vv/=2;\n        if(vv>=maxm/2&&vv<maxm) break;\n        int nn=tmp.size();\n        for(i=0;i<nn;i++)\n        {\n            if(tmp[i].fst+w[vv]<=L) {tmp.pb(pa(tmp[i].fst+w[vv],tmp[i].snd+v[vv]));}\n        }\n    }\n    ll ans=0;\n    for(i=0;i<tmp.size();i++)\n    {\n        ll www=tmp[i].fst,vvv=tmp[i].snd;\n        ans=max(ans,cl2(vv,L-www)+vvv);\n    }\n    printf(\"%lld\\n\",ans);\n}\n\nbool cmp(pa a,pa b)\n{\n    if(a.fst!=b.fst) return a.fst<b.fst;\n    return a.snd<b.snd;\n}\n\nint tp[maxn];\n\nint main()\n{\n\tint i,j;\n\tscanf(\"%d\",&n);\n\tfor(i=1;i<=n;i++)\n    {\n        scanf(\"%d %d\",v+i,w+i);\n    }\n    n=max(n,maxm-1);\n    for(i=maxm/2;i<maxm;i++)\n    {\n        for(j=1;j<maxm;j++)\n        {\n            int jj=j&(-j);jj=j-jj;\n            ve[i][j][0]=ve[i][jj][0]+v[i>>(8-dig(j))];\n            ve[i][j][1]=ve[i][jj][1]+w[i>>(8-dig(j))];\n        }\n    }\n    for(i=maxm/2;i<maxm;i++)\n    {\n        for(j=0;j<maxm;j++) ans1[i].pb(pa(ve[i][j][1],ve[i][j][0]));\n        sort(ans1[i].begin(),ans1[i].end(),cmp);\n    }\n\n    scanf(\"%d\",&q);\n    for(i=0;i<q;i++)\n    {\n        int vv,L;\n        scanf(\"%d %d\",&vv,&L);\n        solve(vv,L);\n    }\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1592102845, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02648.html", "problem_id": "p02648", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02648/input.txt", "sample_output_relpath": "derived/input_output/data/p02648/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02648/C++/s714032417.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s714032417", "user_id": "u721530356"}, "prompt_components": {"gold_output": "0\n3\n3\n", "input_to_evaluate": "#include<bits/stdc++.h>\n\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll,ll> pa;\n\n#define fst first\n#define snd second\n#define pb push_back\n\nconst int maxn=500005,maxm=512;\nconst double pi=acos(-1.0);\n//const ll mod=1000000007;\nconst ll mod=998244353;\nconst double eps=1e-8;\n\nint dig(int xx)\n{\n    for(int i=0;;i++)\n    {\n        if(xx>>i&1) return i;\n    }\n}\n\n\nstruct dat\n{\n    int sta;\n    ll v,w;\n    dat(ll v=0,ll w=0):sta(sta),v(v),w(w){}\n};\n\nint n,q;\nint v[maxn]={0},w[maxn]={0};\n\nll ve[maxm][maxm][2]={0};\n\nvector<pa> ans1[maxm];\n\nvector<pa> tmp;\n\nll cl2(int vv,int ww)\n{\n    int lb=0,ub=ans1[vv].size();\n    while(ub-lb>1)\n    {\n        int mid=(ub+lb)/2;\n        if(ans1[vv][mid].fst<=ww) lb=mid;\n        else ub=mid;\n    }\n    return ans1[vv][lb].snd;\n}\n\n\nvoid solve(int vv,int L)\n{\n    int i,j;\n    if(vv<512)\n    {\n        for(j=0;;j++) {if((vv<<j)>=maxm/2&&(vv<<j)<maxm) break;}\n        ll ans=0;\n        for(i=1;i<(1<<(j+1));i++)\n        {\n            if(ve[vv<<j][i][1]<=L) ans=max(ans,ve[vv<<j][i][0]);\n        }\n        printf(\"%lld\\n\",ans);return;\n    }\n    tmp.clear();tmp.pb(pa(0,0));if(w[vv]<=L) tmp.pb(pa(w[vv],v[vv]));\n    while(1)\n    {\n        vv/=2;\n        if(vv>=maxm/2&&vv<maxm) break;\n        int nn=tmp.size();\n        for(i=0;i<nn;i++)\n        {\n            if(tmp[i].fst+w[vv]<=L) {tmp.pb(pa(tmp[i].fst+w[vv],tmp[i].snd+v[vv]));}\n        }\n    }\n    ll ans=0;\n    for(i=0;i<tmp.size();i++)\n    {\n        ll www=tmp[i].fst,vvv=tmp[i].snd;\n        ans=max(ans,cl2(vv,L-www)+vvv);\n    }\n    printf(\"%lld\\n\",ans);\n}\n\nbool cmp(pa a,pa b)\n{\n    if(a.fst!=b.fst) return a.fst<b.fst;\n    return a.snd<b.snd;\n}\n\nint tp[maxn];\n\nint main()\n{\n\tint i,j;\n\tscanf(\"%d\",&n);\n\tfor(i=1;i<=n;i++)\n    {\n        scanf(\"%d %d\",v+i,w+i);\n    }\n    n=max(n,maxm-1);\n    for(i=maxm/2;i<maxm;i++)\n    {\n        for(j=1;j<maxm;j++)\n        {\n            int jj=j&(-j);jj=j-jj;\n            ve[i][j][0]=ve[i][jj][0]+v[i>>(8-dig(j))];\n            ve[i][j][1]=ve[i][jj][1]+w[i>>(8-dig(j))];\n        }\n    }\n    for(i=maxm/2;i<maxm;i++)\n    {\n        for(j=0;j<maxm;j++) ans1[i].pb(pa(ve[i][j][1],ve[i][j][0]));\n        sort(ans1[i].begin(),ans1[i].end(),cmp);\n    }\n\n    scanf(\"%d\",&q);\n    for(i=0;i<q;i++)\n    {\n        int vv,L;\n        scanf(\"%d %d\",&vv,&L);\n        solve(vv,L);\n    }\n    return 0;\n}\n", "problem_context": "Score : 700 points\n\nProblem Statement\n\nWe have a rooted binary tree with N vertices, where the vertices are numbered 1 to N.\nVertex 1 is the root, and the parent of Vertex i (i \\geq 2) is Vertex \\left[ \\frac{i}{2} \\right].\n\nEach vertex has one item in it. The item in Vertex i has a value of V_i and a weight of W_i.\nNow, process the following query Q times:\n\nGiven are a vertex v of the tree and a positive integer L.\nLet us choose some (possibly none) of the items in v and the ancestors of v so that their total weight is at most L.\nFind the maximum possible total value of the chosen items.\n\nHere, Vertex u is said to be an ancestor of Vertex v when u is an indirect parent of v, that is, there exists a sequence of vertices w_1,w_2,\\ldots,w_k (k\\geq 2) where w_1=v, w_k=u, and w_{i+1} is the parent of w_i for each i.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N < 2^{18}\n\n1 \\leq Q \\leq 10^5\n\n1 \\leq V_i \\leq 10^5\n\n1 \\leq W_i \\leq 10^5\n\nFor the values v and L given in each query, 1 \\leq v \\leq N and 1 \\leq L \\leq 10^5.\n\nInput\n\nLet v_i and L_i be the values v and L given in the i-th query.\nThen, Input is given from Standard Input in the following format:\n\nN\nV_1 W_1\n:\nV_N W_N\nQ\nv_1 L_1\n:\nv_Q L_Q\n\nOutput\n\nFor each integer i from 1 through Q,\nthe i-th line should contain the response to the i-th query.\n\nSample Input 1\n\n3\n1 2\n2 3\n3 4\n3\n1 1\n2 5\n3 5\n\nSample Output 1\n\n0\n3\n3\n\nIn the first query, we are given only one choice: the item with (V, W)=(1,2). Since L = 1, we cannot actually choose it, so our response should be 0.\n\nIn the second query, we are given two choices: the items with (V, W)=(1,2) and (V, W)=(2,3). Since L = 5, we can choose both of them, so our response should be 3.\n\nSample Input 2\n\n15\n123 119\n129 120\n132 112\n126 109\n118 103\n115 109\n102 100\n130 120\n105 105\n132 115\n104 102\n107 107\n127 116\n121 104\n121 115\n8\n8 234\n9 244\n10 226\n11 227\n12 240\n13 237\n14 206\n15 227\n\nSample Output 2\n\n256\n255\n250\n247\n255\n259\n223\n253", "sample_input": "3\n1 2\n2 3\n3 4\n3\n1 1\n2 5\n3 5\n"}, "reference_outputs": ["0\n3\n3\n"], "source_document_id": "p02648", "source_text": "Score : 700 points\n\nProblem Statement\n\nWe have a rooted binary tree with N vertices, where the vertices are numbered 1 to N.\nVertex 1 is the root, and the parent of Vertex i (i \\geq 2) is Vertex \\left[ \\frac{i}{2} \\right].\n\nEach vertex has one item in it. The item in Vertex i has a value of V_i and a weight of W_i.\nNow, process the following query Q times:\n\nGiven are a vertex v of the tree and a positive integer L.\nLet us choose some (possibly none) of the items in v and the ancestors of v so that their total weight is at most L.\nFind the maximum possible total value of the chosen items.\n\nHere, Vertex u is said to be an ancestor of Vertex v when u is an indirect parent of v, that is, there exists a sequence of vertices w_1,w_2,\\ldots,w_k (k\\geq 2) where w_1=v, w_k=u, and w_{i+1} is the parent of w_i for each i.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N < 2^{18}\n\n1 \\leq Q \\leq 10^5\n\n1 \\leq V_i \\leq 10^5\n\n1 \\leq W_i \\leq 10^5\n\nFor the values v and L given in each query, 1 \\leq v \\leq N and 1 \\leq L \\leq 10^5.\n\nInput\n\nLet v_i and L_i be the values v and L given in the i-th query.\nThen, Input is given from Standard Input in the following format:\n\nN\nV_1 W_1\n:\nV_N W_N\nQ\nv_1 L_1\n:\nv_Q L_Q\n\nOutput\n\nFor each integer i from 1 through Q,\nthe i-th line should contain the response to the i-th query.\n\nSample Input 1\n\n3\n1 2\n2 3\n3 4\n3\n1 1\n2 5\n3 5\n\nSample Output 1\n\n0\n3\n3\n\nIn the first query, we are given only one choice: the item with (V, W)=(1,2). Since L = 1, we cannot actually choose it, so our response should be 0.\n\nIn the second query, we are given two choices: the items with (V, W)=(1,2) and (V, W)=(2,3). Since L = 5, we can choose both of them, so our response should be 3.\n\nSample Input 2\n\n15\n123 119\n129 120\n132 112\n126 109\n118 103\n115 109\n102 100\n130 120\n105 105\n132 115\n104 102\n107 107\n127 116\n121 104\n121 115\n8\n8 234\n9 244\n10 226\n11 227\n12 240\n13 237\n14 206\n15 227\n\nSample Output 2\n\n256\n255\n250\n247\n255\n259\n223\n253", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2319, "cpu_time_ms": 1624, "memory_kb": 9776}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s765020763", "group_id": "codeNet:p02652", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nint main() {\nll Z=0;\nstring s;\ncin>>s;\nll rui=0;\nll a=0;\nll f=0;\nll s1=s.size();\nll b[s1+1];\nll c[s1+1];\nfor (ll i=0;i<s1;i++){\nif(s.at(i)=='1'){\na++;}\nelse{\na--;}\nb[i]=a;\nc[i]=a;\nZ=max(Z,a);}\nfor (ll i=s1-2;i>=0;i--){\nb[i]=max(b[i],b[i+1]);}\nfor (ll i=0;i<s1;i++){\nif(s.at(i)=='1'){\nrui++;}\nelse if(s.at(i)=='0'){\nrui--;}\nelse{\nif(rui-c[i-1]+b[i]+2<=Z){\nrui++;}\nelse{\nrui--;}}\nf=min(f,rui);}\nll Z1=Z+1;\nll f1=0;\nrui=0;\nfor (ll i=0;i<s1;i++){\nif(s.at(i)=='1'){\nrui++;}\nelse if(s.at(i)=='0'){\nrui--;}\nelse{\nif(rui+b[i]-c[i-1]+2<=Z1){\nrui++;}\nelse{\nrui--;}}\nf1=min(f1,rui);}\nll ans=min(Z-f,Z1-f1);\nif(s.at(0)=='?'){\nans=1;}\ncout<<ans<<endl;}\n", "language": "C++", "metadata": {"date": 1591596352, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02652.html", "problem_id": "p02652", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02652/input.txt", "sample_output_relpath": "derived/input_output/data/p02652/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02652/C++/s765020763.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s765020763", "user_id": "u722640678"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nint main() {\nll Z=0;\nstring s;\ncin>>s;\nll rui=0;\nll a=0;\nll f=0;\nll s1=s.size();\nll b[s1+1];\nll c[s1+1];\nfor (ll i=0;i<s1;i++){\nif(s.at(i)=='1'){\na++;}\nelse{\na--;}\nb[i]=a;\nc[i]=a;\nZ=max(Z,a);}\nfor (ll i=s1-2;i>=0;i--){\nb[i]=max(b[i],b[i+1]);}\nfor (ll i=0;i<s1;i++){\nif(s.at(i)=='1'){\nrui++;}\nelse if(s.at(i)=='0'){\nrui--;}\nelse{\nif(rui-c[i-1]+b[i]+2<=Z){\nrui++;}\nelse{\nrui--;}}\nf=min(f,rui);}\nll Z1=Z+1;\nll f1=0;\nrui=0;\nfor (ll i=0;i<s1;i++){\nif(s.at(i)=='1'){\nrui++;}\nelse if(s.at(i)=='0'){\nrui--;}\nelse{\nif(rui+b[i]-c[i-1]+2<=Z1){\nrui++;}\nelse{\nrui--;}}\nf1=min(f1,rui);}\nll ans=min(Z-f,Z1-f1);\nif(s.at(0)=='?'){\nans=1;}\ncout<<ans<<endl;}\n", "problem_context": "Score : 800 points\n\nProblem Statement\n\nGiven is a string S, where each character is 0, 1, or ?.\n\nConsider making a string S' by replacing each occurrence of ? with 0 or 1 (we can choose the character for each ? independently).\nLet us define the unbalancedness of S' as follows:\n\n(The unbalancedness of S') = \\max \\{ The absolute difference between the number of occurrences of 0 and 1 between the l-th and r-th character of S (inclusive) :\\ 1 \\leq l \\leq r \\leq |S|\\}\n\nFind the minimum possible unbalancedness of S'.\n\nConstraints\n\n1 \\leq |S| \\leq 10^6\n\nEach character of S is 0, 1, or ?.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the minimum possible unbalancedness of S'.\n\nSample Input 1\n\n0??\n\nSample Output 1\n\n1\n\nWe can make S'= 010 and achieve the minimum possible unbalancedness of 1.\n\nSample Input 2\n\n0??0\n\nSample Output 2\n\n2\n\nSample Input 3\n\n??00????0??0????0?0??00??1???11?1?1???1?11?111???1\n\nSample Output 3\n\n4", "sample_input": "0??\n"}, "reference_outputs": ["1\n"], "source_document_id": "p02652", "source_text": "Score : 800 points\n\nProblem Statement\n\nGiven is a string S, where each character is 0, 1, or ?.\n\nConsider making a string S' by replacing each occurrence of ? with 0 or 1 (we can choose the character for each ? independently).\nLet us define the unbalancedness of S' as follows:\n\n(The unbalancedness of S') = \\max \\{ The absolute difference between the number of occurrences of 0 and 1 between the l-th and r-th character of S (inclusive) :\\ 1 \\leq l \\leq r \\leq |S|\\}\n\nFind the minimum possible unbalancedness of S'.\n\nConstraints\n\n1 \\leq |S| \\leq 10^6\n\nEach character of S is 0, 1, or ?.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the minimum possible unbalancedness of S'.\n\nSample Input 1\n\n0??\n\nSample Output 1\n\n1\n\nWe can make S'= 010 and achieve the minimum possible unbalancedness of 1.\n\nSample Input 2\n\n0??0\n\nSample Output 2\n\n2\n\nSample Input 3\n\n??00????0??0????0?0??00??1???11?1?1???1?11?111???1\n\nSample Output 3\n\n4", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 708, "cpu_time_ms": 52, "memory_kb": 20080}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s413711993", "group_id": "codeNet:p02653", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nconst int maxn = 5010, P = 1000000007;\nint n, A, B, ans, pw[maxn], f[maxn][maxn][2], pre[maxn][maxn][2], h[maxn];\n\nint main() {\n    scanf(\"%d %d %d\", &n, &A, &B);\n    if (A < B) swap(A, B);\n    pw[0] = pw[1] = 1;\n    for (int i = 2; i <= n; i++) {\n        pw[i] = (pw[i - 1] + pw[i - 1]) % P;\n    }\n    f[0][0][0] = f[0][0][1] = 1, h[0] = 1;\n    pre[0][0][0] = pre[0][0][1] = 1;\n    for (int i = 1; i <= n; i++) {\n        for (int j = 1; j <= i; j++) {\n            (f[i][j][0] += pre[i - 1][i - j][1]) %= P;\n            (f[i][j][1] += pre[i - B][i - j][0]) %= P;\n        }\n        for (int j = max(0, i - B + 1); j < i; j++) {\n            (f[i][0][1] += h[j]) %= P;\n        }\n        for (int j = A; j <= i; j++) {\n            int s = 1LL * (f[i][j][0] + f[i][j][1]) * pw[n - i] % P;\n            (ans += s) %= P, f[i][j][0] = f[i][j][1] = 0;\n        }\n        for (int j = 0; j <= i; j++) {\n            (h[i] += f[i][j][0]) %= P;\n            pre[i][i - j][0] = (pre[i - 1][i - j][0] + f[i][j][0]) % P;\n            pre[i][i - j][1] = (pre[i - 1][i - j][1] + f[i][j][1]) % P;\n        }\n    }\n    printf(\"%d\\n\", (ans + P) % P);\n    return 0;\n}", "language": "C++", "metadata": {"date": 1591857700, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02653.html", "problem_id": "p02653", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02653/input.txt", "sample_output_relpath": "derived/input_output/data/p02653/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02653/C++/s413711993.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s413711993", "user_id": "u813182415"}, "prompt_components": {"gold_output": "11\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nconst int maxn = 5010, P = 1000000007;\nint n, A, B, ans, pw[maxn], f[maxn][maxn][2], pre[maxn][maxn][2], h[maxn];\n\nint main() {\n    scanf(\"%d %d %d\", &n, &A, &B);\n    if (A < B) swap(A, B);\n    pw[0] = pw[1] = 1;\n    for (int i = 2; i <= n; i++) {\n        pw[i] = (pw[i - 1] + pw[i - 1]) % P;\n    }\n    f[0][0][0] = f[0][0][1] = 1, h[0] = 1;\n    pre[0][0][0] = pre[0][0][1] = 1;\n    for (int i = 1; i <= n; i++) {\n        for (int j = 1; j <= i; j++) {\n            (f[i][j][0] += pre[i - 1][i - j][1]) %= P;\n            (f[i][j][1] += pre[i - B][i - j][0]) %= P;\n        }\n        for (int j = max(0, i - B + 1); j < i; j++) {\n            (f[i][0][1] += h[j]) %= P;\n        }\n        for (int j = A; j <= i; j++) {\n            int s = 1LL * (f[i][j][0] + f[i][j][1]) * pw[n - i] % P;\n            (ans += s) %= P, f[i][j][0] = f[i][j][1] = 0;\n        }\n        for (int j = 0; j <= i; j++) {\n            (h[i] += f[i][j][0]) %= P;\n            pre[i][i - j][0] = (pre[i - 1][i - j][0] + f[i][j][0]) % P;\n            pre[i][i - j][1] = (pre[i - 1][i - j][1] + f[i][j][1]) % P;\n        }\n    }\n    printf(\"%d\\n\", (ans + P) % P);\n    return 0;\n}", "problem_context": "Score : 800 points\n\nProblem Statement\n\nSnuke has a string x of length N.\nInitially, every character in x is 0.\n\nSnuke can do the following two operations any number of times in any order:\n\nChoose A consecutive characters in x and replace each of them with 0.\n\nChoose B consecutive characters in x and replace each of them with 1.\n\nFind the number of different strings that x can be after Snuke finishes doing operations.\nThis count can be enormous, so compute it modulo (10^9+7).\n\nConstraints\n\n1 \\leq N \\leq 5000\n\n1 \\leq A,B \\leq N\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN A B\n\nOutput\n\nPrint the number of different strings that x can be after Snuke finishes doing operations, modulo (10^9+7).\n\nSample Input 1\n\n4 2 3\n\nSample Output 1\n\n11\n\nFor example, x can be 0011 or 1111 in the end, but cannot be 0110.\n\nSample Input 2\n\n10 7 2\n\nSample Output 2\n\n533\n\nSample Input 3\n\n1000 100 10\n\nSample Output 3\n\n828178524", "sample_input": "4 2 3\n"}, "reference_outputs": ["11\n"], "source_document_id": "p02653", "source_text": "Score : 800 points\n\nProblem Statement\n\nSnuke has a string x of length N.\nInitially, every character in x is 0.\n\nSnuke can do the following two operations any number of times in any order:\n\nChoose A consecutive characters in x and replace each of them with 0.\n\nChoose B consecutive characters in x and replace each of them with 1.\n\nFind the number of different strings that x can be after Snuke finishes doing operations.\nThis count can be enormous, so compute it modulo (10^9+7).\n\nConstraints\n\n1 \\leq N \\leq 5000\n\n1 \\leq A,B \\leq N\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN A B\n\nOutput\n\nPrint the number of different strings that x can be after Snuke finishes doing operations, modulo (10^9+7).\n\nSample Input 1\n\n4 2 3\n\nSample Output 1\n\n11\n\nFor example, x can be 0011 or 1111 in the end, but cannot be 0110.\n\nSample Input 2\n\n10 7 2\n\nSample Output 2\n\n533\n\nSample Input 3\n\n1000 100 10\n\nSample Output 3\n\n828178524", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1187, "cpu_time_ms": 266, "memory_kb": 237152}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s526850861", "group_id": "codeNet:p02657", "input_text": "#include<iostream>\n#include<algorithm>\n#include<cstring>\nusing namespace std;\n\nint n,m;\nint main()\n{\n    cin>>n>>m;\n    cout<<n*m<<endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1590973294, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02657.html", "problem_id": "p02657", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02657/input.txt", "sample_output_relpath": "derived/input_output/data/p02657/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02657/C++/s526850861.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s526850861", "user_id": "u728513189"}, "prompt_components": {"gold_output": "10\n", "input_to_evaluate": "#include<iostream>\n#include<algorithm>\n#include<cstring>\nusing namespace std;\n\nint n,m;\nint main()\n{\n    cin>>n>>m;\n    cout<<n*m<<endl;\n    return 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nCompute A \\times B.\n\nConstraints\n\n1 \\leq A \\leq 100\n\n1 \\leq B \\leq 100\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nPrint the value A \\times B as an integer.\n\nSample Input 1\n\n2 5\n\nSample Output 1\n\n10\n\nWe have 2 \\times 5 = 10.\n\nSample Input 2\n\n100 100\n\nSample Output 2\n\n10000", "sample_input": "2 5\n"}, "reference_outputs": ["10\n"], "source_document_id": "p02657", "source_text": "Score : 100 points\n\nProblem Statement\n\nCompute A \\times B.\n\nConstraints\n\n1 \\leq A \\leq 100\n\n1 \\leq B \\leq 100\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nPrint the value A \\times B as an integer.\n\nSample Input 1\n\n2 5\n\nSample Output 1\n\n10\n\nWe have 2 \\times 5 = 10.\n\nSample Input 2\n\n100 100\n\nSample Output 2\n\n10000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 152, "cpu_time_ms": 2, "memory_kb": 3636}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s679332258", "group_id": "codeNet:p02657", "input_text": "#include <iostream>\n#include <sstream>\n#include <iomanip>\n#include <vector>\n#include <deque>\n#include <list>\n#include <set>\n#include <map>\n#include <stack>\n#include <queue>\n#include <bitset>\n#include <string>\n#include <numeric>\n#include <algorithm>\n#include <functional>\n#include <iterator>\n#include <cstdio>\n#include <cstring>\n#include <cmath>\n#include <cstdlib>\n#include <cctype>\n#include <complex>\n#include <ctime>\n#define ll long long\nusing namespace std;\n\nint main(){\n\tint a,b;\n\twhile(scanf(\"%d%d\",&a,&b)==2)\n    {\n        printf(\"%d\\n\",a*b);\n    }\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1590973277, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02657.html", "problem_id": "p02657", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02657/input.txt", "sample_output_relpath": "derived/input_output/data/p02657/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02657/C++/s679332258.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s679332258", "user_id": "u987474395"}, "prompt_components": {"gold_output": "10\n", "input_to_evaluate": "#include <iostream>\n#include <sstream>\n#include <iomanip>\n#include <vector>\n#include <deque>\n#include <list>\n#include <set>\n#include <map>\n#include <stack>\n#include <queue>\n#include <bitset>\n#include <string>\n#include <numeric>\n#include <algorithm>\n#include <functional>\n#include <iterator>\n#include <cstdio>\n#include <cstring>\n#include <cmath>\n#include <cstdlib>\n#include <cctype>\n#include <complex>\n#include <ctime>\n#define ll long long\nusing namespace std;\n\nint main(){\n\tint a,b;\n\twhile(scanf(\"%d%d\",&a,&b)==2)\n    {\n        printf(\"%d\\n\",a*b);\n    }\n\treturn 0;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nCompute A \\times B.\n\nConstraints\n\n1 \\leq A \\leq 100\n\n1 \\leq B \\leq 100\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nPrint the value A \\times B as an integer.\n\nSample Input 1\n\n2 5\n\nSample Output 1\n\n10\n\nWe have 2 \\times 5 = 10.\n\nSample Input 2\n\n100 100\n\nSample Output 2\n\n10000", "sample_input": "2 5\n"}, "reference_outputs": ["10\n"], "source_document_id": "p02657", "source_text": "Score : 100 points\n\nProblem Statement\n\nCompute A \\times B.\n\nConstraints\n\n1 \\leq A \\leq 100\n\n1 \\leq B \\leq 100\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nPrint the value A \\times B as an integer.\n\nSample Input 1\n\n2 5\n\nSample Output 1\n\n10\n\nWe have 2 \\times 5 = 10.\n\nSample Input 2\n\n100 100\n\nSample Output 2\n\n10000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 567, "cpu_time_ms": 5, "memory_kb": 3816}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s152557954", "group_id": "codeNet:p02657", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef long double ld;\ntypedef pair<int, int> P;\nconst int maxn = 500050;\nconst int inf = 0x3f3f3f3f;\nconst int mod = 998244353;\nconst ll linf = 7e18;\nll power(ll x, ll y)\n{\n    ll ans = 1;\n    while (y)\n    {\n        if (y & 1)\n            ans = ans * x % mod;\n        x = x * x % mod;\n        y >>= 1;\n    }\n    return ans;\n}\n\nll gcd(ll x, ll y)\n{\n    if (x % y == 0)\n        return y;\n    return gcd(y, x % y);\n}\n\nint main()\n{\n    ios::sync_with_stdio(0);\n    cin.tie(0);\n    int n, m;\n    cin >> n >> m;\n    cout << n * m << \"\\n\";\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1590973265, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02657.html", "problem_id": "p02657", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02657/input.txt", "sample_output_relpath": "derived/input_output/data/p02657/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02657/C++/s152557954.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s152557954", "user_id": "u526466255"}, "prompt_components": {"gold_output": "10\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef long double ld;\ntypedef pair<int, int> P;\nconst int maxn = 500050;\nconst int inf = 0x3f3f3f3f;\nconst int mod = 998244353;\nconst ll linf = 7e18;\nll power(ll x, ll y)\n{\n    ll ans = 1;\n    while (y)\n    {\n        if (y & 1)\n            ans = ans * x % mod;\n        x = x * x % mod;\n        y >>= 1;\n    }\n    return ans;\n}\n\nll gcd(ll x, ll y)\n{\n    if (x % y == 0)\n        return y;\n    return gcd(y, x % y);\n}\n\nint main()\n{\n    ios::sync_with_stdio(0);\n    cin.tie(0);\n    int n, m;\n    cin >> n >> m;\n    cout << n * m << \"\\n\";\n    return 0;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nCompute A \\times B.\n\nConstraints\n\n1 \\leq A \\leq 100\n\n1 \\leq B \\leq 100\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nPrint the value A \\times B as an integer.\n\nSample Input 1\n\n2 5\n\nSample Output 1\n\n10\n\nWe have 2 \\times 5 = 10.\n\nSample Input 2\n\n100 100\n\nSample Output 2\n\n10000", "sample_input": "2 5\n"}, "reference_outputs": ["10\n"], "source_document_id": "p02657", "source_text": "Score : 100 points\n\nProblem Statement\n\nCompute A \\times B.\n\nConstraints\n\n1 \\leq A \\leq 100\n\n1 \\leq B \\leq 100\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nPrint the value A \\times B as an integer.\n\nSample Input 1\n\n2 5\n\nSample Output 1\n\n10\n\nWe have 2 \\times 5 = 10.\n\nSample Input 2\n\n100 100\n\nSample Output 2\n\n10000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 620, "cpu_time_ms": 4, "memory_kb": 3636}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s156539410", "group_id": "codeNet:p02661", "input_text": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint main() {\n    int n;\n    cin >> n;\n\n    int A[n], B[n];\n    for(int i=0; i<n; i++) cin >> A[i] >> B[i];\n\n    sort(A, A+n);\n    sort(B, B+n);\n\n    int left, right;\n    if(n%2 == 0) {\n        left = A[n/2-1] + A[n/2];\n        right = B[n/2-1] + B[n/2];\n    } else {\n        left = A[n/2];\n        right = B[n/2];\n    }\n\n    cout << right - left +1 << endl;\n\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1591051772, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02661.html", "problem_id": "p02661", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02661/input.txt", "sample_output_relpath": "derived/input_output/data/p02661/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02661/C++/s156539410.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s156539410", "user_id": "u878967567"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint main() {\n    int n;\n    cin >> n;\n\n    int A[n], B[n];\n    for(int i=0; i<n; i++) cin >> A[i] >> B[i];\n\n    sort(A, A+n);\n    sort(B, B+n);\n\n    int left, right;\n    if(n%2 == 0) {\n        left = A[n/2-1] + A[n/2];\n        right = B[n/2-1] + B[n/2];\n    } else {\n        left = A[n/2];\n        right = B[n/2];\n    }\n\n    cout << right - left +1 << endl;\n\n    return 0;\n}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nThere are N integers X_1, X_2, \\cdots, X_N, and we know that A_i \\leq X_i \\leq B_i.\nFind the number of different values that the median of X_1, X_2, \\cdots, X_N can take.\n\nNotes\n\nThe median of X_1, X_2, \\cdots, X_N is defined as follows. Let x_1, x_2, \\cdots, x_N be the result of sorting X_1, X_2, \\cdots, X_N in ascending order.\n\nIf N is odd, the median is x_{(N+1)/2};\n\nif N is even, the median is (x_{N/2} + x_{N/2+1}) / 2.\n\nConstraints\n\n2 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq A_i \\leq B_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 B_1\nA_2 B_2\n:\nA_N B_N\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n2\n1 2\n2 3\n\nSample Output 1\n\n3\n\nIf X_1 = 1 and X_2 = 2, the median is \\frac{3}{2};\n\nif X_1 = 1 and X_2 = 3, the median is 2;\n\nif X_1 = 2 and X_2 = 2, the median is 2;\n\nif X_1 = 2 and X_2 = 3, the median is \\frac{5}{2}.\n\nThus, the median can take three values: \\frac{3}{2}, 2, and \\frac{5}{2}.\n\nSample Input 2\n\n3\n100 100\n10 10000\n1 1000000000\n\nSample Output 2\n\n9991", "sample_input": "2\n1 2\n2 3\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02661", "source_text": "Score : 500 points\n\nProblem Statement\n\nThere are N integers X_1, X_2, \\cdots, X_N, and we know that A_i \\leq X_i \\leq B_i.\nFind the number of different values that the median of X_1, X_2, \\cdots, X_N can take.\n\nNotes\n\nThe median of X_1, X_2, \\cdots, X_N is defined as follows. Let x_1, x_2, \\cdots, x_N be the result of sorting X_1, X_2, \\cdots, X_N in ascending order.\n\nIf N is odd, the median is x_{(N+1)/2};\n\nif N is even, the median is (x_{N/2} + x_{N/2+1}) / 2.\n\nConstraints\n\n2 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq A_i \\leq B_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 B_1\nA_2 B_2\n:\nA_N B_N\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n2\n1 2\n2 3\n\nSample Output 1\n\n3\n\nIf X_1 = 1 and X_2 = 2, the median is \\frac{3}{2};\n\nif X_1 = 1 and X_2 = 3, the median is 2;\n\nif X_1 = 2 and X_2 = 2, the median is 2;\n\nif X_1 = 2 and X_2 = 3, the median is \\frac{5}{2}.\n\nThus, the median can take three values: \\frac{3}{2}, 2, and \\frac{5}{2}.\n\nSample Input 2\n\n3\n100 100\n10 10000\n1 1000000000\n\nSample Output 2\n\n9991", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 423, "cpu_time_ms": 144, "memory_kb": 5056}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s700440446", "group_id": "codeNet:p02661", "input_text": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nint main() {\n\tint N;\n\tcin >> N;\n\tvector< pair<int, int>> AB(N);\n\tfor (int i = 0; i < N; i++) cin >> AB[i].first >> AB[i].second;\n\n\tif (N % 2 == 0) {\n\t\tsort(AB.begin(), AB.end());\n\t\tdouble Amin = AB[N / 2 - 1].first;\n\t\tdouble Amax = min(AB[N / 2 - 1].second, AB[N / 2].second);\n\t\tsort(AB.begin(), AB.end(), [](auto& a, auto& b) {return a.second > b.second; });\n\t\tdouble Bmin = max(AB[N / 2].first, AB[N / 2 - 1].first);\n\t\tdouble Bmax = AB[N / 2 - 1].second;\n\t\tcout << ((Amax + Bmax) / 2 - (Amin + Bmin) / 2) * 2 + 1 << endl;\n\t}\n\telse {\n\t\tsort(AB.begin(), AB.end());\n\t\tdouble Amin = AB[(N - 1) / 2].first;\n\t\tdouble Amax = min(AB[(N - 1) / 2].second, AB[(N + 1) / 2].second);\n\t\tsort(AB.begin(), AB.end(), [](auto& a, auto& b) {return a.second > b.second; });\n\t\tdouble Bmin = max(AB[(N - 1) / 2].first, AB[(N + 1) / 2].first);\n\t\tdouble Bmax = AB[(N - 1) / 2].second;\n\t\tif (Amax < Bmin) cout << (Amax - Amin) + 1 + (Bmax - Bmin) + 1;\n\t\telse cout << Bmax - Amin + 1;\n\t}\n\n}\n", "language": "C++", "metadata": {"date": 1590978196, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02661.html", "problem_id": "p02661", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02661/input.txt", "sample_output_relpath": "derived/input_output/data/p02661/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02661/C++/s700440446.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s700440446", "user_id": "u868132236"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nint main() {\n\tint N;\n\tcin >> N;\n\tvector< pair<int, int>> AB(N);\n\tfor (int i = 0; i < N; i++) cin >> AB[i].first >> AB[i].second;\n\n\tif (N % 2 == 0) {\n\t\tsort(AB.begin(), AB.end());\n\t\tdouble Amin = AB[N / 2 - 1].first;\n\t\tdouble Amax = min(AB[N / 2 - 1].second, AB[N / 2].second);\n\t\tsort(AB.begin(), AB.end(), [](auto& a, auto& b) {return a.second > b.second; });\n\t\tdouble Bmin = max(AB[N / 2].first, AB[N / 2 - 1].first);\n\t\tdouble Bmax = AB[N / 2 - 1].second;\n\t\tcout << ((Amax + Bmax) / 2 - (Amin + Bmin) / 2) * 2 + 1 << endl;\n\t}\n\telse {\n\t\tsort(AB.begin(), AB.end());\n\t\tdouble Amin = AB[(N - 1) / 2].first;\n\t\tdouble Amax = min(AB[(N - 1) / 2].second, AB[(N + 1) / 2].second);\n\t\tsort(AB.begin(), AB.end(), [](auto& a, auto& b) {return a.second > b.second; });\n\t\tdouble Bmin = max(AB[(N - 1) / 2].first, AB[(N + 1) / 2].first);\n\t\tdouble Bmax = AB[(N - 1) / 2].second;\n\t\tif (Amax < Bmin) cout << (Amax - Amin) + 1 + (Bmax - Bmin) + 1;\n\t\telse cout << Bmax - Amin + 1;\n\t}\n\n}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nThere are N integers X_1, X_2, \\cdots, X_N, and we know that A_i \\leq X_i \\leq B_i.\nFind the number of different values that the median of X_1, X_2, \\cdots, X_N can take.\n\nNotes\n\nThe median of X_1, X_2, \\cdots, X_N is defined as follows. Let x_1, x_2, \\cdots, x_N be the result of sorting X_1, X_2, \\cdots, X_N in ascending order.\n\nIf N is odd, the median is x_{(N+1)/2};\n\nif N is even, the median is (x_{N/2} + x_{N/2+1}) / 2.\n\nConstraints\n\n2 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq A_i \\leq B_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 B_1\nA_2 B_2\n:\nA_N B_N\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n2\n1 2\n2 3\n\nSample Output 1\n\n3\n\nIf X_1 = 1 and X_2 = 2, the median is \\frac{3}{2};\n\nif X_1 = 1 and X_2 = 3, the median is 2;\n\nif X_1 = 2 and X_2 = 2, the median is 2;\n\nif X_1 = 2 and X_2 = 3, the median is \\frac{5}{2}.\n\nThus, the median can take three values: \\frac{3}{2}, 2, and \\frac{5}{2}.\n\nSample Input 2\n\n3\n100 100\n10 10000\n1 1000000000\n\nSample Output 2\n\n9991", "sample_input": "2\n1 2\n2 3\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02661", "source_text": "Score : 500 points\n\nProblem Statement\n\nThere are N integers X_1, X_2, \\cdots, X_N, and we know that A_i \\leq X_i \\leq B_i.\nFind the number of different values that the median of X_1, X_2, \\cdots, X_N can take.\n\nNotes\n\nThe median of X_1, X_2, \\cdots, X_N is defined as follows. Let x_1, x_2, \\cdots, x_N be the result of sorting X_1, X_2, \\cdots, X_N in ascending order.\n\nIf N is odd, the median is x_{(N+1)/2};\n\nif N is even, the median is (x_{N/2} + x_{N/2+1}) / 2.\n\nConstraints\n\n2 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq A_i \\leq B_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 B_1\nA_2 B_2\n:\nA_N B_N\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n2\n1 2\n2 3\n\nSample Output 1\n\n3\n\nIf X_1 = 1 and X_2 = 2, the median is \\frac{3}{2};\n\nif X_1 = 1 and X_2 = 3, the median is 2;\n\nif X_1 = 2 and X_2 = 2, the median is 2;\n\nif X_1 = 2 and X_2 = 3, the median is \\frac{5}{2}.\n\nThus, the median can take three values: \\frac{3}{2}, 2, and \\frac{5}{2}.\n\nSample Input 2\n\n3\n100 100\n10 10000\n1 1000000000\n\nSample Output 2\n\n9991", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1048, "cpu_time_ms": 143, "memory_kb": 4844}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s702672358", "group_id": "codeNet:p02663", "input_text": " #include<bits/stdc++.h>\n//#include <ext/pb_ds/assoc_container.hpp>\n//#include <ext/pb_ds/tree_policy.hpp>\n#define ll long long\n#define pb push_back\n#define mod 1000000007\n#define ff first\n#define ss second\n#define pi 3.1415926535\n#define endl '\\n'\nusing namespace std;\nstruct custom {\n    static uint64_t splitmix64(uint64_t x)\n    {\n        x += 0x9e3779b97f4a7c15;\n        x = (x ^ (x >> 30)) * 0xbf58476d1ce4e5b9;\n        x = (x ^ (x >> 27)) * 0x94d049bb133111eb;\n        return x ^ (x >> 31);\n    }\n    size_t operator()(uint64_t x) const {\n        static const uint64_t FIXED_RANDOM = chrono::steady_clock::now().time_since_epoch().count();\n        return splitmix64(x + FIXED_RANDOM);\n    }\n};\n//using namespace __gnu_pbds;\n//typedef tree<ll,null_type,less_equal<int>,rb_tree_tag,tree_order_statistics_node_update> indexed_set;\nconst ll inf=1e19;\n/*ll power(ll x,ll y)\n{\n    ll res=1;\n    while(y>0)\n    {\n        if(y%2==1)\n            res=(res*x)%mod;\n        x=(x*x)%mod;\n        y=(y>>1);\n    }\n    return res;\n}*/\nint main()\n{\n    ios_base::sync_with_stdio(false);\n    cin.tie(0);\n    cout.tie(0);\n    ll a,b,c,d,x,y,r,k;\n    cin>>a>>b>>c>>d>>k;\n    x=a*60+b;\n    y=c*60+d;\n    x=abs(x-y);\n    cout<<max(0LL,x-k)<<endl;\n}\n", "language": "C++", "metadata": {"date": 1590888023, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02663.html", "problem_id": "p02663", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02663/input.txt", "sample_output_relpath": "derived/input_output/data/p02663/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02663/C++/s702672358.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s702672358", "user_id": "u621153914"}, "prompt_components": {"gold_output": "270\n", "input_to_evaluate": " #include<bits/stdc++.h>\n//#include <ext/pb_ds/assoc_container.hpp>\n//#include <ext/pb_ds/tree_policy.hpp>\n#define ll long long\n#define pb push_back\n#define mod 1000000007\n#define ff first\n#define ss second\n#define pi 3.1415926535\n#define endl '\\n'\nusing namespace std;\nstruct custom {\n    static uint64_t splitmix64(uint64_t x)\n    {\n        x += 0x9e3779b97f4a7c15;\n        x = (x ^ (x >> 30)) * 0xbf58476d1ce4e5b9;\n        x = (x ^ (x >> 27)) * 0x94d049bb133111eb;\n        return x ^ (x >> 31);\n    }\n    size_t operator()(uint64_t x) const {\n        static const uint64_t FIXED_RANDOM = chrono::steady_clock::now().time_since_epoch().count();\n        return splitmix64(x + FIXED_RANDOM);\n    }\n};\n//using namespace __gnu_pbds;\n//typedef tree<ll,null_type,less_equal<int>,rb_tree_tag,tree_order_statistics_node_update> indexed_set;\nconst ll inf=1e19;\n/*ll power(ll x,ll y)\n{\n    ll res=1;\n    while(y>0)\n    {\n        if(y%2==1)\n            res=(res*x)%mod;\n        x=(x*x)%mod;\n        y=(y>>1);\n    }\n    return res;\n}*/\nint main()\n{\n    ios_base::sync_with_stdio(false);\n    cin.tie(0);\n    cout.tie(0);\n    ll a,b,c,d,x,y,r,k;\n    cin>>a>>b>>c>>d>>k;\n    x=a*60+b;\n    y=c*60+d;\n    x=abs(x-y);\n    cout<<max(0LL,x-k)<<endl;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nIn this problem, we use the 24-hour clock.\n\nTakahashi gets up exactly at the time H_1 : M_1 and goes to bed exactly at the time H_2 : M_2. (See Sample Inputs below for clarity.)\nHe has decided to study for K consecutive minutes while he is up.\nWhat is the length of the period in which he can start studying?\n\nConstraints\n\n0 \\le H_1, H_2 \\le 23\n\n0 \\le M_1, M_2 \\le 59\n\nThe time H_1 : M_1 comes before the time H_2 : M_2.\n\nK \\ge 1\n\nTakahashi is up for at least K minutes.\n\nAll values in input are integers (without leading zeros).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH_1 M_1 H_2 M_2 K\n\nOutput\n\nPrint the length of the period in which he can start studying, as an integer.\n\nSample Input 1\n\n10 0 15 0 30\n\nSample Output 1\n\n270\n\nTakahashi gets up at exactly ten in the morning and goes to bed at exactly three in the afternoon.\nIt takes 30 minutes to do the study, so he can start it in the period between ten o'clock and half-past two. The length of this period is 270 minutes, so we should print 270.\n\nSample Input 2\n\n10 0 12 0 120\n\nSample Output 2\n\n0\n\nTakahashi gets up at exactly ten in the morning and goes to bed at exactly noon. It takes 120 minutes to do the study, so he has to start it at exactly ten o'clock. Thus, we should print 0.", "sample_input": "10 0 15 0 30\n"}, "reference_outputs": ["270\n"], "source_document_id": "p02663", "source_text": "Score : 100 points\n\nProblem Statement\n\nIn this problem, we use the 24-hour clock.\n\nTakahashi gets up exactly at the time H_1 : M_1 and goes to bed exactly at the time H_2 : M_2. (See Sample Inputs below for clarity.)\nHe has decided to study for K consecutive minutes while he is up.\nWhat is the length of the period in which he can start studying?\n\nConstraints\n\n0 \\le H_1, H_2 \\le 23\n\n0 \\le M_1, M_2 \\le 59\n\nThe time H_1 : M_1 comes before the time H_2 : M_2.\n\nK \\ge 1\n\nTakahashi is up for at least K minutes.\n\nAll values in input are integers (without leading zeros).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH_1 M_1 H_2 M_2 K\n\nOutput\n\nPrint the length of the period in which he can start studying, as an integer.\n\nSample Input 1\n\n10 0 15 0 30\n\nSample Output 1\n\n270\n\nTakahashi gets up at exactly ten in the morning and goes to bed at exactly three in the afternoon.\nIt takes 30 minutes to do the study, so he can start it in the period between ten o'clock and half-past two. The length of this period is 270 minutes, so we should print 270.\n\nSample Input 2\n\n10 0 12 0 120\n\nSample Output 2\n\n0\n\nTakahashi gets up at exactly ten in the morning and goes to bed at exactly noon. It takes 120 minutes to do the study, so he has to start it at exactly ten o'clock. Thus, we should print 0.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1234, "cpu_time_ms": 2, "memory_kb": 3652}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s048515025", "group_id": "codeNet:p02663", "input_text": "#include <bits/stdc++.h>\n \n#define int         long long\n#define uint        unsigned int\n#define ld          long double\n#define showoff     ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);\n#define pb          push_back\n#define pii         pair<int,int>\n#define FOR(i,a,b)  for(int i=a;i<b;++i)\n#define RFOR(i,a,b) for(int i=a;i>b;--i)\n#define f           first\n#define se          second\n#define maxn        200005\n#define all(v)      v.begin(),v.end()\n#define sz(x)       (int)x.size()\n#define mod         998244353\n#define pqueue      priority_queue<pii>\n#define pdqueue     priority_queue< int,vector<int> ,greater< int >>\n \nusing namespace std;\n \n \nmt19937 rng(chrono::steady_clock::now().time_since_epoch().count());\n  \nint power(int a,int n)\n{\n    a %= mod;\n    if(n == 1)return a;\n    if(n == 0)return 1;\n    if(n%2)return (a*(power((a*a)%mod,n/2)%mod))%mod;\n    return power((a*a)%mod,n/2)%mod;\n}\n \nconst int inf = (int) 1e18;\n \nint inverse(int x){\n    return power(x,mod-2)%mod;//little fermat....\n}  \n\nvoid solve(){\n    int h1,m1,h2,m2,k;\n    cin >> h1 >> m1 >> h2 >> m2 >> k;\n    int tot = 0;\n    if(h2 > h1)tot = m2+(h2-h1-1)*60+60-m1;\n    else tot = m2-m1;\n    cout << max(0LL,tot-k) << \"\\n\";\n}       \n\n \nsigned main()   \n{\n    showoff;\n    int T = 1;\n    //cin >> T;\n    FOR(t,1,T+1){\n        solve();\n        cout << \"\\n\";\n    }\n    return 0;\n}\n//*->for large size of matrix take int not long long if possible......\n//*->always take maximum as inf for safer side ...", "language": "C++", "metadata": {"date": 1590887555, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02663.html", "problem_id": "p02663", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02663/input.txt", "sample_output_relpath": "derived/input_output/data/p02663/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02663/C++/s048515025.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s048515025", "user_id": "u578751202"}, "prompt_components": {"gold_output": "270\n", "input_to_evaluate": "#include <bits/stdc++.h>\n \n#define int         long long\n#define uint        unsigned int\n#define ld          long double\n#define showoff     ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);\n#define pb          push_back\n#define pii         pair<int,int>\n#define FOR(i,a,b)  for(int i=a;i<b;++i)\n#define RFOR(i,a,b) for(int i=a;i>b;--i)\n#define f           first\n#define se          second\n#define maxn        200005\n#define all(v)      v.begin(),v.end()\n#define sz(x)       (int)x.size()\n#define mod         998244353\n#define pqueue      priority_queue<pii>\n#define pdqueue     priority_queue< int,vector<int> ,greater< int >>\n \nusing namespace std;\n \n \nmt19937 rng(chrono::steady_clock::now().time_since_epoch().count());\n  \nint power(int a,int n)\n{\n    a %= mod;\n    if(n == 1)return a;\n    if(n == 0)return 1;\n    if(n%2)return (a*(power((a*a)%mod,n/2)%mod))%mod;\n    return power((a*a)%mod,n/2)%mod;\n}\n \nconst int inf = (int) 1e18;\n \nint inverse(int x){\n    return power(x,mod-2)%mod;//little fermat....\n}  \n\nvoid solve(){\n    int h1,m1,h2,m2,k;\n    cin >> h1 >> m1 >> h2 >> m2 >> k;\n    int tot = 0;\n    if(h2 > h1)tot = m2+(h2-h1-1)*60+60-m1;\n    else tot = m2-m1;\n    cout << max(0LL,tot-k) << \"\\n\";\n}       \n\n \nsigned main()   \n{\n    showoff;\n    int T = 1;\n    //cin >> T;\n    FOR(t,1,T+1){\n        solve();\n        cout << \"\\n\";\n    }\n    return 0;\n}\n//*->for large size of matrix take int not long long if possible......\n//*->always take maximum as inf for safer side ...", "problem_context": "Score : 100 points\n\nProblem Statement\n\nIn this problem, we use the 24-hour clock.\n\nTakahashi gets up exactly at the time H_1 : M_1 and goes to bed exactly at the time H_2 : M_2. (See Sample Inputs below for clarity.)\nHe has decided to study for K consecutive minutes while he is up.\nWhat is the length of the period in which he can start studying?\n\nConstraints\n\n0 \\le H_1, H_2 \\le 23\n\n0 \\le M_1, M_2 \\le 59\n\nThe time H_1 : M_1 comes before the time H_2 : M_2.\n\nK \\ge 1\n\nTakahashi is up for at least K minutes.\n\nAll values in input are integers (without leading zeros).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH_1 M_1 H_2 M_2 K\n\nOutput\n\nPrint the length of the period in which he can start studying, as an integer.\n\nSample Input 1\n\n10 0 15 0 30\n\nSample Output 1\n\n270\n\nTakahashi gets up at exactly ten in the morning and goes to bed at exactly three in the afternoon.\nIt takes 30 minutes to do the study, so he can start it in the period between ten o'clock and half-past two. The length of this period is 270 minutes, so we should print 270.\n\nSample Input 2\n\n10 0 12 0 120\n\nSample Output 2\n\n0\n\nTakahashi gets up at exactly ten in the morning and goes to bed at exactly noon. It takes 120 minutes to do the study, so he has to start it at exactly ten o'clock. Thus, we should print 0.", "sample_input": "10 0 15 0 30\n"}, "reference_outputs": ["270\n"], "source_document_id": "p02663", "source_text": "Score : 100 points\n\nProblem Statement\n\nIn this problem, we use the 24-hour clock.\n\nTakahashi gets up exactly at the time H_1 : M_1 and goes to bed exactly at the time H_2 : M_2. (See Sample Inputs below for clarity.)\nHe has decided to study for K consecutive minutes while he is up.\nWhat is the length of the period in which he can start studying?\n\nConstraints\n\n0 \\le H_1, H_2 \\le 23\n\n0 \\le M_1, M_2 \\le 59\n\nThe time H_1 : M_1 comes before the time H_2 : M_2.\n\nK \\ge 1\n\nTakahashi is up for at least K minutes.\n\nAll values in input are integers (without leading zeros).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH_1 M_1 H_2 M_2 K\n\nOutput\n\nPrint the length of the period in which he can start studying, as an integer.\n\nSample Input 1\n\n10 0 15 0 30\n\nSample Output 1\n\n270\n\nTakahashi gets up at exactly ten in the morning and goes to bed at exactly three in the afternoon.\nIt takes 30 minutes to do the study, so he can start it in the period between ten o'clock and half-past two. The length of this period is 270 minutes, so we should print 270.\n\nSample Input 2\n\n10 0 12 0 120\n\nSample Output 2\n\n0\n\nTakahashi gets up at exactly ten in the morning and goes to bed at exactly noon. It takes 120 minutes to do the study, so he has to start it at exactly ten o'clock. Thus, we should print 0.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1486, "cpu_time_ms": 2, "memory_kb": 3636}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s859744047", "group_id": "codeNet:p02664", "input_text": "#include <bits/stdc++.h>\n#include <string>\nusing namespace std;\n\nint main() {\n  string t;\n  cin >> t;\n  int i;\n  for(i=0;i<(int)t.size();i++){\n    if(t.at(i)=='?'){\n      t.at(i)='D';\n    }\n  }\n  cout << t << endl;\n}", "language": "C++", "metadata": {"date": 1590892682, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02664.html", "problem_id": "p02664", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02664/input.txt", "sample_output_relpath": "derived/input_output/data/p02664/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02664/C++/s859744047.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s859744047", "user_id": "u714851895"}, "prompt_components": {"gold_output": "PDPDPDP\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#include <string>\nusing namespace std;\n\nint main() {\n  string t;\n  cin >> t;\n  int i;\n  for(i=0;i<(int)t.size();i++){\n    if(t.at(i)=='?'){\n      t.at(i)='D';\n    }\n  }\n  cout << t << endl;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nFor a string S consisting of the uppercase English letters P and D, let the doctoral and postdoctoral quotient of S be the total number of occurrences of D and PD in S as contiguous substrings. For example, if S = PPDDP, it contains two occurrences of D and one occurrence of PD as contiguous substrings, so the doctoral and postdoctoral quotient of S is 3.\n\nWe have a string T consisting of P, D, and ?.\n\nAmong the strings that can be obtained by replacing each ? in T with P or D, find one with the maximum possible doctoral and postdoctoral quotient.\n\nConstraints\n\n1 \\leq |T| \\leq 2 \\times 10^5\n\nT consists of P, D, and ?.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nT\n\nOutput\n\nPrint one string with the maximum possible doctoral and postdoctoral quotient among the strings that can be obtained by replacing each ? in T with P or D.\nIf there are multiple such strings, you may print any of them.\n\nSample Input 1\n\nPD?D??P\n\nSample Output 1\n\nPDPDPDP\n\nThis string contains three occurrences of D and three occurrences of PD as contiguous substrings, so its doctoral and postdoctoral quotient is 6, which is the maximum doctoral and postdoctoral quotient of a string obtained by replacing each ? in T with P or D.\n\nSample Input 2\n\nP?P?\n\nSample Output 2\n\nPDPD", "sample_input": "PD?D??P\n"}, "reference_outputs": ["PDPDPDP\n"], "source_document_id": "p02664", "source_text": "Score : 200 points\n\nProblem Statement\n\nFor a string S consisting of the uppercase English letters P and D, let the doctoral and postdoctoral quotient of S be the total number of occurrences of D and PD in S as contiguous substrings. For example, if S = PPDDP, it contains two occurrences of D and one occurrence of PD as contiguous substrings, so the doctoral and postdoctoral quotient of S is 3.\n\nWe have a string T consisting of P, D, and ?.\n\nAmong the strings that can be obtained by replacing each ? in T with P or D, find one with the maximum possible doctoral and postdoctoral quotient.\n\nConstraints\n\n1 \\leq |T| \\leq 2 \\times 10^5\n\nT consists of P, D, and ?.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nT\n\nOutput\n\nPrint one string with the maximum possible doctoral and postdoctoral quotient among the strings that can be obtained by replacing each ? in T with P or D.\nIf there are multiple such strings, you may print any of them.\n\nSample Input 1\n\nPD?D??P\n\nSample Output 1\n\nPDPDPDP\n\nThis string contains three occurrences of D and three occurrences of PD as contiguous substrings, so its doctoral and postdoctoral quotient is 6, which is the maximum doctoral and postdoctoral quotient of a string obtained by replacing each ? in T with P or D.\n\nSample Input 2\n\nP?P?\n\nSample Output 2\n\nPDPD", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 216, "cpu_time_ms": 14, "memory_kb": 3676}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s936829179", "group_id": "codeNet:p02664", "input_text": "#include <bits/stdc++.h>\n#include <iostream>\nusing namespace std;\n\nint main()\n{\n\tstring s;\n    cin >> s;\n    int l =s.length();\n   for(int i=0;i<l;i++)\n   {\n       if(s[i]=='?')\n       {\n           if(i==l-1 && i-1>=0 && s[i-1]=='P')\n           {\n\t\t\t\ts[i]='D';\n           }\n           else if(i-1>=0 && s[i-1]=='P' && i+1<l && s[i+1]!='D')\n           {\n               s[i]='D';\n           }\n           else\n          \t s[i]='P';\n       }\n   }\n    cout << s << endl;\n    \n    \n    \n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1590889250, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02664.html", "problem_id": "p02664", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02664/input.txt", "sample_output_relpath": "derived/input_output/data/p02664/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02664/C++/s936829179.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s936829179", "user_id": "u447706255"}, "prompt_components": {"gold_output": "PDPDPDP\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#include <iostream>\nusing namespace std;\n\nint main()\n{\n\tstring s;\n    cin >> s;\n    int l =s.length();\n   for(int i=0;i<l;i++)\n   {\n       if(s[i]=='?')\n       {\n           if(i==l-1 && i-1>=0 && s[i-1]=='P')\n           {\n\t\t\t\ts[i]='D';\n           }\n           else if(i-1>=0 && s[i-1]=='P' && i+1<l && s[i+1]!='D')\n           {\n               s[i]='D';\n           }\n           else\n          \t s[i]='P';\n       }\n   }\n    cout << s << endl;\n    \n    \n    \n\treturn 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nFor a string S consisting of the uppercase English letters P and D, let the doctoral and postdoctoral quotient of S be the total number of occurrences of D and PD in S as contiguous substrings. For example, if S = PPDDP, it contains two occurrences of D and one occurrence of PD as contiguous substrings, so the doctoral and postdoctoral quotient of S is 3.\n\nWe have a string T consisting of P, D, and ?.\n\nAmong the strings that can be obtained by replacing each ? in T with P or D, find one with the maximum possible doctoral and postdoctoral quotient.\n\nConstraints\n\n1 \\leq |T| \\leq 2 \\times 10^5\n\nT consists of P, D, and ?.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nT\n\nOutput\n\nPrint one string with the maximum possible doctoral and postdoctoral quotient among the strings that can be obtained by replacing each ? in T with P or D.\nIf there are multiple such strings, you may print any of them.\n\nSample Input 1\n\nPD?D??P\n\nSample Output 1\n\nPDPDPDP\n\nThis string contains three occurrences of D and three occurrences of PD as contiguous substrings, so its doctoral and postdoctoral quotient is 6, which is the maximum doctoral and postdoctoral quotient of a string obtained by replacing each ? in T with P or D.\n\nSample Input 2\n\nP?P?\n\nSample Output 2\n\nPDPD", "sample_input": "PD?D??P\n"}, "reference_outputs": ["PDPDPDP\n"], "source_document_id": "p02664", "source_text": "Score : 200 points\n\nProblem Statement\n\nFor a string S consisting of the uppercase English letters P and D, let the doctoral and postdoctoral quotient of S be the total number of occurrences of D and PD in S as contiguous substrings. For example, if S = PPDDP, it contains two occurrences of D and one occurrence of PD as contiguous substrings, so the doctoral and postdoctoral quotient of S is 3.\n\nWe have a string T consisting of P, D, and ?.\n\nAmong the strings that can be obtained by replacing each ? in T with P or D, find one with the maximum possible doctoral and postdoctoral quotient.\n\nConstraints\n\n1 \\leq |T| \\leq 2 \\times 10^5\n\nT consists of P, D, and ?.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nT\n\nOutput\n\nPrint one string with the maximum possible doctoral and postdoctoral quotient among the strings that can be obtained by replacing each ? in T with P or D.\nIf there are multiple such strings, you may print any of them.\n\nSample Input 1\n\nPD?D??P\n\nSample Output 1\n\nPDPDPDP\n\nThis string contains three occurrences of D and three occurrences of PD as contiguous substrings, so its doctoral and postdoctoral quotient is 6, which is the maximum doctoral and postdoctoral quotient of a string obtained by replacing each ? in T with P or D.\n\nSample Input 2\n\nP?P?\n\nSample Output 2\n\nPDPD", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 493, "cpu_time_ms": 13, "memory_kb": 3724}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s000458005", "group_id": "codeNet:p02664", "input_text": "#include <bits/stdc++.h>\n#include <iostream>\n#include <math.h>\nusing namespace std;\n\nint main() {\n    string T;\n    cin >> T;\n    int len = T.size();\n    string n = \"\";\n    for (int i=0; i < len; i++) {\n        if (T[i] == '?') {\n            if (i == (len -1)) {\n                n += \"D\";\n            } else if (i > 0 && T[i-1] == 'P') {\n                n += \"D\";\n            } else if (i < (len - 1) && T[i+1] == 'P') {\n                n += \"D\";\n            }\n            else {\n                n += \"P\";\n            }\n        } else {\n            n += T[i];\n        }\n    }\n\n    cout << n << endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1590887729, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02664.html", "problem_id": "p02664", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02664/input.txt", "sample_output_relpath": "derived/input_output/data/p02664/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02664/C++/s000458005.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s000458005", "user_id": "u651314218"}, "prompt_components": {"gold_output": "PDPDPDP\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#include <iostream>\n#include <math.h>\nusing namespace std;\n\nint main() {\n    string T;\n    cin >> T;\n    int len = T.size();\n    string n = \"\";\n    for (int i=0; i < len; i++) {\n        if (T[i] == '?') {\n            if (i == (len -1)) {\n                n += \"D\";\n            } else if (i > 0 && T[i-1] == 'P') {\n                n += \"D\";\n            } else if (i < (len - 1) && T[i+1] == 'P') {\n                n += \"D\";\n            }\n            else {\n                n += \"P\";\n            }\n        } else {\n            n += T[i];\n        }\n    }\n\n    cout << n << endl;\n    return 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nFor a string S consisting of the uppercase English letters P and D, let the doctoral and postdoctoral quotient of S be the total number of occurrences of D and PD in S as contiguous substrings. For example, if S = PPDDP, it contains two occurrences of D and one occurrence of PD as contiguous substrings, so the doctoral and postdoctoral quotient of S is 3.\n\nWe have a string T consisting of P, D, and ?.\n\nAmong the strings that can be obtained by replacing each ? in T with P or D, find one with the maximum possible doctoral and postdoctoral quotient.\n\nConstraints\n\n1 \\leq |T| \\leq 2 \\times 10^5\n\nT consists of P, D, and ?.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nT\n\nOutput\n\nPrint one string with the maximum possible doctoral and postdoctoral quotient among the strings that can be obtained by replacing each ? in T with P or D.\nIf there are multiple such strings, you may print any of them.\n\nSample Input 1\n\nPD?D??P\n\nSample Output 1\n\nPDPDPDP\n\nThis string contains three occurrences of D and three occurrences of PD as contiguous substrings, so its doctoral and postdoctoral quotient is 6, which is the maximum doctoral and postdoctoral quotient of a string obtained by replacing each ? in T with P or D.\n\nSample Input 2\n\nP?P?\n\nSample Output 2\n\nPDPD", "sample_input": "PD?D??P\n"}, "reference_outputs": ["PDPDPDP\n"], "source_document_id": "p02664", "source_text": "Score : 200 points\n\nProblem Statement\n\nFor a string S consisting of the uppercase English letters P and D, let the doctoral and postdoctoral quotient of S be the total number of occurrences of D and PD in S as contiguous substrings. For example, if S = PPDDP, it contains two occurrences of D and one occurrence of PD as contiguous substrings, so the doctoral and postdoctoral quotient of S is 3.\n\nWe have a string T consisting of P, D, and ?.\n\nAmong the strings that can be obtained by replacing each ? in T with P or D, find one with the maximum possible doctoral and postdoctoral quotient.\n\nConstraints\n\n1 \\leq |T| \\leq 2 \\times 10^5\n\nT consists of P, D, and ?.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nT\n\nOutput\n\nPrint one string with the maximum possible doctoral and postdoctoral quotient among the strings that can be obtained by replacing each ? in T with P or D.\nIf there are multiple such strings, you may print any of them.\n\nSample Input 1\n\nPD?D??P\n\nSample Output 1\n\nPDPDPDP\n\nThis string contains three occurrences of D and three occurrences of PD as contiguous substrings, so its doctoral and postdoctoral quotient is 6, which is the maximum doctoral and postdoctoral quotient of a string obtained by replacing each ? in T with P or D.\n\nSample Input 2\n\nP?P?\n\nSample Output 2\n\nPDPD", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 615, "cpu_time_ms": 14, "memory_kb": 3924}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s200875344", "group_id": "codeNet:p02664", "input_text": "#include<bits/stdc++.h>\ntypedef long long ll;\ntypedef long double ld;\nusing namespace std;\n\nusing Pii = pair<int, int>;\nusing Pll = pair<ll, ll>;\n\n#define REP(i, l, n) for(int i=(l), i##_len=(n); i<i##_len; ++i)\n#define ALL(x) (x).begin(),(x).end()\n#define pb push_back\n\nll gcd(ll a,ll b){return b ? gcd(b,a%b) : a;}\nll lcm(ll a,ll b){return a/gcd(a,b)*b;}\n\nchar alpha[26] = {'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z'};\n\nint dx[4] = {-1, 1, 0, 0};\nint dy[4] = {0, 0, 1, -1};\n\nint main(){\n    string t; cin >> t;\n    REP(i, 0, t.size()){\n        if(t[i] == '?'){\n            cout << \"D\";\n        }else{\n            cout << t[i];\n        }\n    }\n    cout << endl;\n}", "language": "C++", "metadata": {"date": 1590887089, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02664.html", "problem_id": "p02664", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02664/input.txt", "sample_output_relpath": "derived/input_output/data/p02664/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02664/C++/s200875344.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s200875344", "user_id": "u639426108"}, "prompt_components": {"gold_output": "PDPDPDP\n", "input_to_evaluate": "#include<bits/stdc++.h>\ntypedef long long ll;\ntypedef long double ld;\nusing namespace std;\n\nusing Pii = pair<int, int>;\nusing Pll = pair<ll, ll>;\n\n#define REP(i, l, n) for(int i=(l), i##_len=(n); i<i##_len; ++i)\n#define ALL(x) (x).begin(),(x).end()\n#define pb push_back\n\nll gcd(ll a,ll b){return b ? gcd(b,a%b) : a;}\nll lcm(ll a,ll b){return a/gcd(a,b)*b;}\n\nchar alpha[26] = {'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z'};\n\nint dx[4] = {-1, 1, 0, 0};\nint dy[4] = {0, 0, 1, -1};\n\nint main(){\n    string t; cin >> t;\n    REP(i, 0, t.size()){\n        if(t[i] == '?'){\n            cout << \"D\";\n        }else{\n            cout << t[i];\n        }\n    }\n    cout << endl;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nFor a string S consisting of the uppercase English letters P and D, let the doctoral and postdoctoral quotient of S be the total number of occurrences of D and PD in S as contiguous substrings. For example, if S = PPDDP, it contains two occurrences of D and one occurrence of PD as contiguous substrings, so the doctoral and postdoctoral quotient of S is 3.\n\nWe have a string T consisting of P, D, and ?.\n\nAmong the strings that can be obtained by replacing each ? in T with P or D, find one with the maximum possible doctoral and postdoctoral quotient.\n\nConstraints\n\n1 \\leq |T| \\leq 2 \\times 10^5\n\nT consists of P, D, and ?.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nT\n\nOutput\n\nPrint one string with the maximum possible doctoral and postdoctoral quotient among the strings that can be obtained by replacing each ? in T with P or D.\nIf there are multiple such strings, you may print any of them.\n\nSample Input 1\n\nPD?D??P\n\nSample Output 1\n\nPDPDPDP\n\nThis string contains three occurrences of D and three occurrences of PD as contiguous substrings, so its doctoral and postdoctoral quotient is 6, which is the maximum doctoral and postdoctoral quotient of a string obtained by replacing each ? in T with P or D.\n\nSample Input 2\n\nP?P?\n\nSample Output 2\n\nPDPD", "sample_input": "PD?D??P\n"}, "reference_outputs": ["PDPDPDP\n"], "source_document_id": "p02664", "source_text": "Score : 200 points\n\nProblem Statement\n\nFor a string S consisting of the uppercase English letters P and D, let the doctoral and postdoctoral quotient of S be the total number of occurrences of D and PD in S as contiguous substrings. For example, if S = PPDDP, it contains two occurrences of D and one occurrence of PD as contiguous substrings, so the doctoral and postdoctoral quotient of S is 3.\n\nWe have a string T consisting of P, D, and ?.\n\nAmong the strings that can be obtained by replacing each ? in T with P or D, find one with the maximum possible doctoral and postdoctoral quotient.\n\nConstraints\n\n1 \\leq |T| \\leq 2 \\times 10^5\n\nT consists of P, D, and ?.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nT\n\nOutput\n\nPrint one string with the maximum possible doctoral and postdoctoral quotient among the strings that can be obtained by replacing each ? in T with P or D.\nIf there are multiple such strings, you may print any of them.\n\nSample Input 1\n\nPD?D??P\n\nSample Output 1\n\nPDPDPDP\n\nThis string contains three occurrences of D and three occurrences of PD as contiguous substrings, so its doctoral and postdoctoral quotient is 6, which is the maximum doctoral and postdoctoral quotient of a string obtained by replacing each ? in T with P or D.\n\nSample Input 2\n\nP?P?\n\nSample Output 2\n\nPDPD", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 750, "cpu_time_ms": 19, "memory_kb": 3724}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s333941648", "group_id": "codeNet:p02665", "input_text": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#include <vector>\n#include <map>\n#include <set>\n#include <queue>\n#include <math.h>\n#include <iostream>\n#include <stdio.h>\n\ntypedef long long ll;\ntypedef vector<ll> vll;\ntypedef pair<ll,ll> pairll;\n\n#define sll(x) scanf(\"%lld\",&x);\n#define READ freopen(\"in.txt\",\"r\",stdin)\n#define WRITE freopen(\"out.txt\",\"w\",stdout)\n\n#define ff first\n#define ss second\n\ninline ll readInt()\n{\n    ll in; scanf(\"%lld\",&in); return in;\n}\n\ninline ll ADD(ll a, ll b, ll mod)\n{\n    return (a + b + mod + mod)%mod;\n}\n\ninline ll SUBS(ll a, ll b, ll mod)\n{\n    return (a-b+mod + mod) %mod;\n}\n\ninline ll MUL(ll a, ll b, ll mod)\n{\n    return (a*b + mod)%mod;\n}\n\nll bigMod(ll base, ll power, ll mod)\n{\n    if(!power) return 1;\n    if(!base) return 0;\n\n    ll temp = bigMod(base, power/2, mod);\n\n    if(power%2 == 0)\n    {\n        return (temp*temp)%mod;\n    }\n    else return (((temp*temp)%mod)*base)%mod;\n}\n\ninline ll modInverse(ll a, ll modp)\n{\n    return bigMod(a, modp -2, modp);\n}\n\ninline ll modInverseExtended(ll a, ll m) \n{ \n    ll m0 = m; \n    ll y = 0, x = 1; \n  \n    if (m == 1) \n      return 0; \n  \n    while (a > 1) \n    { \n        // q is quotient \n        ll q = a / m; \n        ll t = m; \n  \n        // m is remainder now, process same as \n        // Euclid's algo \n        m = a % m, a = t; \n        t = y; \n  \n        // Update y and x \n        y = x - q * y; \n        x = t; \n    } \n  \n    // Make x positive \n    if (x < 0) \n       x += m0; \n  \n    return x; \n} \n  \n\nvoid autoinput()\n{\n    #ifndef ONLINE_JUDGE\n    READ; \n    //WRITE;\n\n    #endif\n}\n\nint main()\n{\n    autoinput();\n\n    ll N;\n\n    sll(N);\n\n    vector<ll> leaves(N+1), freedom(N+1);\n\n    freedom[0] = 1;\n\n    for(ll i = 0; i <= N; i++)\n    {\n        sll(leaves[i]);\n    }\n\n    for(ll i = 0; i <= N; i++)\n    {\n        if(!i)\n        {   \n            freedom[i] -= leaves[i];\n        }\n        else\n        {\n            if(freedom[i-1] < INT64_MAX/10) freedom[i] = 2*freedom[i-1] - leaves[i];\n            else freedom[i] = freedom[i-1];\n        }\n\n        if(freedom[i] < 0)\n        {\n            puts(\"-1\"); return 0;\n        }\n\n    }\n\n    vll tree(N+1);\n\n\n    tree[N] = leaves[N];\n\n    ll sum = tree[N];\n    \n    for(ll i = N-1; i >= 0; i--)\n    {\n        tree[i] = min(freedom[i],tree[i+1]);\n        tree[i] += leaves[i];\n\n        sum += tree[i];\n\n    }\n\n    printf(\"%lld\\n\",sum);\n\n}\n\n", "language": "C++", "metadata": {"date": 1590897296, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02665.html", "problem_id": "p02665", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02665/input.txt", "sample_output_relpath": "derived/input_output/data/p02665/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02665/C++/s333941648.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s333941648", "user_id": "u075588643"}, "prompt_components": {"gold_output": "7\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#include <vector>\n#include <map>\n#include <set>\n#include <queue>\n#include <math.h>\n#include <iostream>\n#include <stdio.h>\n\ntypedef long long ll;\ntypedef vector<ll> vll;\ntypedef pair<ll,ll> pairll;\n\n#define sll(x) scanf(\"%lld\",&x);\n#define READ freopen(\"in.txt\",\"r\",stdin)\n#define WRITE freopen(\"out.txt\",\"w\",stdout)\n\n#define ff first\n#define ss second\n\ninline ll readInt()\n{\n    ll in; scanf(\"%lld\",&in); return in;\n}\n\ninline ll ADD(ll a, ll b, ll mod)\n{\n    return (a + b + mod + mod)%mod;\n}\n\ninline ll SUBS(ll a, ll b, ll mod)\n{\n    return (a-b+mod + mod) %mod;\n}\n\ninline ll MUL(ll a, ll b, ll mod)\n{\n    return (a*b + mod)%mod;\n}\n\nll bigMod(ll base, ll power, ll mod)\n{\n    if(!power) return 1;\n    if(!base) return 0;\n\n    ll temp = bigMod(base, power/2, mod);\n\n    if(power%2 == 0)\n    {\n        return (temp*temp)%mod;\n    }\n    else return (((temp*temp)%mod)*base)%mod;\n}\n\ninline ll modInverse(ll a, ll modp)\n{\n    return bigMod(a, modp -2, modp);\n}\n\ninline ll modInverseExtended(ll a, ll m) \n{ \n    ll m0 = m; \n    ll y = 0, x = 1; \n  \n    if (m == 1) \n      return 0; \n  \n    while (a > 1) \n    { \n        // q is quotient \n        ll q = a / m; \n        ll t = m; \n  \n        // m is remainder now, process same as \n        // Euclid's algo \n        m = a % m, a = t; \n        t = y; \n  \n        // Update y and x \n        y = x - q * y; \n        x = t; \n    } \n  \n    // Make x positive \n    if (x < 0) \n       x += m0; \n  \n    return x; \n} \n  \n\nvoid autoinput()\n{\n    #ifndef ONLINE_JUDGE\n    READ; \n    //WRITE;\n\n    #endif\n}\n\nint main()\n{\n    autoinput();\n\n    ll N;\n\n    sll(N);\n\n    vector<ll> leaves(N+1), freedom(N+1);\n\n    freedom[0] = 1;\n\n    for(ll i = 0; i <= N; i++)\n    {\n        sll(leaves[i]);\n    }\n\n    for(ll i = 0; i <= N; i++)\n    {\n        if(!i)\n        {   \n            freedom[i] -= leaves[i];\n        }\n        else\n        {\n            if(freedom[i-1] < INT64_MAX/10) freedom[i] = 2*freedom[i-1] - leaves[i];\n            else freedom[i] = freedom[i-1];\n        }\n\n        if(freedom[i] < 0)\n        {\n            puts(\"-1\"); return 0;\n        }\n\n    }\n\n    vll tree(N+1);\n\n\n    tree[N] = leaves[N];\n\n    ll sum = tree[N];\n    \n    for(ll i = N-1; i >= 0; i--)\n    {\n        tree[i] = min(freedom[i],tree[i+1]);\n        tree[i] += leaves[i];\n\n        sum += tree[i];\n\n    }\n\n    printf(\"%lld\\n\",sum);\n\n}\n\n", "problem_context": "Score : 600 points\n\nProblem Statement\n\nGiven is an integer sequence of length N+1: A_0, A_1, A_2, \\ldots, A_N. Is there a binary tree of depth N such that, for each d = 0, 1, \\ldots, N, there are exactly A_d leaves at depth d? If such a tree exists, print the maximum possible number of vertices in such a tree; otherwise, print -1.\n\nNotes\n\nA binary tree is a rooted tree such that each vertex has at most two direct children.\n\nA leaf in a binary tree is a vertex with zero children.\n\nThe depth of a vertex v in a binary tree is the distance from the tree's root to v. (The root has the depth of 0.)\n\nThe depth of a binary tree is the maximum depth of a vertex in the tree.\n\nConstraints\n\n0 \\leq N \\leq 10^5\n\n0 \\leq A_i \\leq 10^{8} (0 \\leq i \\leq N)\n\nA_N \\geq 1\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_0 A_1 A_2 \\cdots A_N\n\nOutput\n\nPrint the answer as an integer.\n\nSample Input 1\n\n3\n0 1 1 2\n\nSample Output 1\n\n7\n\nBelow is the tree with the maximum possible number of vertices. It has seven vertices, so we should print 7.\n\nSample Input 2\n\n4\n0 0 1 0 2\n\nSample Output 2\n\n10\n\nSample Input 3\n\n2\n0 3 1\n\nSample Output 3\n\n-1\n\nSample Input 4\n\n1\n1 1\n\nSample Output 4\n\n-1\n\nSample Input 5\n\n10\n0 0 1 1 2 3 5 8 13 21 34\n\nSample Output 5\n\n264", "sample_input": "3\n0 1 1 2\n"}, "reference_outputs": ["7\n"], "source_document_id": "p02665", "source_text": "Score : 600 points\n\nProblem Statement\n\nGiven is an integer sequence of length N+1: A_0, A_1, A_2, \\ldots, A_N. Is there a binary tree of depth N such that, for each d = 0, 1, \\ldots, N, there are exactly A_d leaves at depth d? If such a tree exists, print the maximum possible number of vertices in such a tree; otherwise, print -1.\n\nNotes\n\nA binary tree is a rooted tree such that each vertex has at most two direct children.\n\nA leaf in a binary tree is a vertex with zero children.\n\nThe depth of a vertex v in a binary tree is the distance from the tree's root to v. (The root has the depth of 0.)\n\nThe depth of a binary tree is the maximum depth of a vertex in the tree.\n\nConstraints\n\n0 \\leq N \\leq 10^5\n\n0 \\leq A_i \\leq 10^{8} (0 \\leq i \\leq N)\n\nA_N \\geq 1\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_0 A_1 A_2 \\cdots A_N\n\nOutput\n\nPrint the answer as an integer.\n\nSample Input 1\n\n3\n0 1 1 2\n\nSample Output 1\n\n7\n\nBelow is the tree with the maximum possible number of vertices. It has seven vertices, so we should print 7.\n\nSample Input 2\n\n4\n0 0 1 0 2\n\nSample Output 2\n\n10\n\nSample Input 3\n\n2\n0 3 1\n\nSample Output 3\n\n-1\n\nSample Input 4\n\n1\n1 1\n\nSample Output 4\n\n-1\n\nSample Input 5\n\n10\n0 0 1 1 2 3 5 8 13 21 34\n\nSample Output 5\n\n264", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2390, "cpu_time_ms": 24, "memory_kb": 5604}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s433788519", "group_id": "codeNet:p02670", "input_text": "#pragma GCC optimize (\"O3\")\n#pragma GCC target (\"avx2\")\n//#include<bits/stdc++.h>\n#include<cstdio>\n#include<cstring>\n#include<algorithm>\n\nusing namespace std;\ntypedef long long ll;\n#define rep(i, n) for(int i = 0; i < (n); i++)\n#define rep1(i, n) for(int i = 1; i <= (n); i++)\n#define co(x) cout << (x) << \"\\n\"\n#define cosp(x) cout << (x) << \" \"\n#define ce(x) cerr << (x) << \"\\n\"\n#define cesp(x) cerr << (x) << \" \"\n#define pb push_back\n#define mp make_pair\n#define chmin(x, y) x = min(x, y)\n#define chmax(x, y) x = max(x, y)\n#define Would\n#define you\n#define please\n\nconst int CM = 1 << 17, CL = 12;\nchar cn[CM + CL], * ci = cn + CM + CL, * owa = cn + CM, ct;\nconst ll ma0 = 1157442765409226768;\nconst ll ma1 = 1085102592571150095;\nconst ll ma2 = 71777214294589695;\nconst ll ma3 = 281470681808895;\nconst ll ma4 = 4294967295;\ninline int getint() {\n\tif (ci - owa > 0) {\n\t\tmemcpy(cn, owa, CL);\n\t\tci -= CM;\n\t\tfread(cn + CL, 1, CM, stdin);\n\t}\n\tll tmp = *(ll*)ci;\n\tint dig = 68 - __builtin_ctzll((tmp & ma0) ^ ma0);\n\ttmp = tmp << dig & ma1;\n\ttmp = tmp * 10 + (tmp >> 8) & ma2;\n\ttmp = tmp * 100 + (tmp >> 16) & ma3;\n\ttmp = tmp * 10000 + (tmp >> 32) & ma4;\n\tci += 72 - dig >> 3;\n\treturn tmp;\n}\n\nunsigned char D[252004];\nbool E[252004];\nint Q[252004];\nint main() {\n\t//cin.tie(0);\n\t//ios::sync_with_stdio(false);\n\n\n\tint N = getint();\n\tint n = N + 2;\n\trep1(i, N) {\n\t\tint ij = n * i + 1;\n\t\tunsigned char kari = min(i - 1, N - i);\n\t\tunsigned char kari2 = 3;\n\n\t\trep(j, kari) {\n\t\t\tD[ij++] = kari2++;\n\t\t}\n\t\trep(j, N - kari - kari) {\n\t\t\tD[ij++] = kari + 3;\n\t\t}\n\t\trep(j, kari) {\n\t\t\tD[ij++] = --kari2;\n\t\t}\n\t}\n\n\tint kotae = 0;\n\trep(k, N * N) {\n\t\tint ij = getint();\n\t\tij += (ij - 1) / N * 2 + N + 2;\n\n\t\tkotae += D[ij];\n\t\tE[ij] = 1;\n\n\t\tint p = 0, q = 0;\n\t\tQ[p++] = ij;\n\n\t\twhile (p > q) {\n\t\t\tint ij = Q[q++];\n\t\t\tint d =\tD[ij] - E[ij] + 1;\n\n\t\t\tif (D[ij - n] > d) {\n\t\t\t\tD[ij - n] = d;\n\t\t\t\tQ[p++] = ij - n;\n\t\t\t}\n\t\t\tif (D[ij + n] > d) {\n\t\t\t\tD[ij + n] = d;\n\t\t\t\tQ[p++] = ij + n;\n\t\t\t}\n\t\t\tif (D[ij - 1] > d) {\n\t\t\t\tD[ij - 1] = d;\n\t\t\t\tQ[p++] = ij - 1;\n\t\t\t}\n\t\t\tif (D[ij + 1] > d) {\n\t\t\t\tD[ij + 1] = d;\n\t\t\t\tQ[p++] = ij + 1;\n\t\t\t}\n\t\t}\n\t}\n\n\tprintf(\"%d\\n\", kotae - 3 * N * N);\n\n\n\n\tWould you please return 0;\n}", "language": "C++", "metadata": {"date": 1590957593, "filename_ext": "cpp", "original_language": "C++ (Clang 10.0.0)", "problem_description_relpath": "problem_descriptions/p02670.html", "problem_id": "p02670", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02670/input.txt", "sample_output_relpath": "derived/input_output/data/p02670/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02670/C++/s433788519.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s433788519", "user_id": "u096883693"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#pragma GCC optimize (\"O3\")\n#pragma GCC target (\"avx2\")\n//#include<bits/stdc++.h>\n#include<cstdio>\n#include<cstring>\n#include<algorithm>\n\nusing namespace std;\ntypedef long long ll;\n#define rep(i, n) for(int i = 0; i < (n); i++)\n#define rep1(i, n) for(int i = 1; i <= (n); i++)\n#define co(x) cout << (x) << \"\\n\"\n#define cosp(x) cout << (x) << \" \"\n#define ce(x) cerr << (x) << \"\\n\"\n#define cesp(x) cerr << (x) << \" \"\n#define pb push_back\n#define mp make_pair\n#define chmin(x, y) x = min(x, y)\n#define chmax(x, y) x = max(x, y)\n#define Would\n#define you\n#define please\n\nconst int CM = 1 << 17, CL = 12;\nchar cn[CM + CL], * ci = cn + CM + CL, * owa = cn + CM, ct;\nconst ll ma0 = 1157442765409226768;\nconst ll ma1 = 1085102592571150095;\nconst ll ma2 = 71777214294589695;\nconst ll ma3 = 281470681808895;\nconst ll ma4 = 4294967295;\ninline int getint() {\n\tif (ci - owa > 0) {\n\t\tmemcpy(cn, owa, CL);\n\t\tci -= CM;\n\t\tfread(cn + CL, 1, CM, stdin);\n\t}\n\tll tmp = *(ll*)ci;\n\tint dig = 68 - __builtin_ctzll((tmp & ma0) ^ ma0);\n\ttmp = tmp << dig & ma1;\n\ttmp = tmp * 10 + (tmp >> 8) & ma2;\n\ttmp = tmp * 100 + (tmp >> 16) & ma3;\n\ttmp = tmp * 10000 + (tmp >> 32) & ma4;\n\tci += 72 - dig >> 3;\n\treturn tmp;\n}\n\nunsigned char D[252004];\nbool E[252004];\nint Q[252004];\nint main() {\n\t//cin.tie(0);\n\t//ios::sync_with_stdio(false);\n\n\n\tint N = getint();\n\tint n = N + 2;\n\trep1(i, N) {\n\t\tint ij = n * i + 1;\n\t\tunsigned char kari = min(i - 1, N - i);\n\t\tunsigned char kari2 = 3;\n\n\t\trep(j, kari) {\n\t\t\tD[ij++] = kari2++;\n\t\t}\n\t\trep(j, N - kari - kari) {\n\t\t\tD[ij++] = kari + 3;\n\t\t}\n\t\trep(j, kari) {\n\t\t\tD[ij++] = --kari2;\n\t\t}\n\t}\n\n\tint kotae = 0;\n\trep(k, N * N) {\n\t\tint ij = getint();\n\t\tij += (ij - 1) / N * 2 + N + 2;\n\n\t\tkotae += D[ij];\n\t\tE[ij] = 1;\n\n\t\tint p = 0, q = 0;\n\t\tQ[p++] = ij;\n\n\t\twhile (p > q) {\n\t\t\tint ij = Q[q++];\n\t\t\tint d =\tD[ij] - E[ij] + 1;\n\n\t\t\tif (D[ij - n] > d) {\n\t\t\t\tD[ij - n] = d;\n\t\t\t\tQ[p++] = ij - n;\n\t\t\t}\n\t\t\tif (D[ij + n] > d) {\n\t\t\t\tD[ij + n] = d;\n\t\t\t\tQ[p++] = ij + n;\n\t\t\t}\n\t\t\tif (D[ij - 1] > d) {\n\t\t\t\tD[ij - 1] = d;\n\t\t\t\tQ[p++] = ij - 1;\n\t\t\t}\n\t\t\tif (D[ij + 1] > d) {\n\t\t\t\tD[ij + 1] = d;\n\t\t\t\tQ[p++] = ij + 1;\n\t\t\t}\n\t\t}\n\t}\n\n\tprintf(\"%d\\n\", kotae - 3 * N * N);\n\n\n\n\tWould you please return 0;\n}", "problem_context": "Score : 700 points\n\nProblem Statement\n\nTonight, in your favourite cinema they are giving the movie Joker and all seats are occupied. In the cinema there are N rows with N seats each, forming an N\\times N square. We denote with 1, 2,\\dots, N the viewers in the first row (from left to right); with N+1, \\dots, 2N the viewers in the second row (from left to right); and so on until the last row, whose viewers are denoted by N^2-N+1,\\dots, N^2.\n\nAt the end of the movie, the viewers go out of the cinema in a certain order: the i-th viewer leaving her seat is the one denoted by the number P_i. The viewer P_{i+1} waits until viewer P_i has left the cinema before leaving her seat.\nTo exit from the cinema, a viewer must move from seat to seat until she exits the square of seats (any side of the square is a valid exit). A viewer can move from a seat to one of its 4 adjacent seats (same row or same column).\nWhile leaving the cinema, it might be that a certain viewer x goes through a seat currently occupied by viewer y; in that case viewer y will hate viewer x forever. Each viewer chooses the way that minimizes the number of viewers that will hate her forever.\n\nCompute the number of pairs of viewers (x, y) such that y will hate x forever.\n\nConstraints\n\n2 \\le N \\le 500\n\nThe sequence P_1, P_2, \\dots, P_{N^2} is a permutation of \\{1, 2, \\dots, N^2\\}.\n\nInput\n\nThe input is given from Standard Input in the format\n\nN\nP_1 P_2 \\cdots P_{N^2}\n\nOutput\n\nIf ans is the number of pairs of viewers described in the statement, you should print on Standard Output\n\nans\n\nSample Input 1\n\n3\n1 3 7 9 5 4 8 6 2\n\nSample Output 1\n\n1\n\nBefore the end of the movie, the viewers are arranged in the cinema as follows:\n\n1 2 3\n4 5 6\n7 8 9\n\nThe first four viewers leaving the cinema (1, 3, 7, 9) can leave the cinema without going through any seat, so they will not be hated by anybody.\n\nThen, viewer 5 must go through one of the seats where viewers 2, 4, 6, 8 are currently seated while leaving the cinema; hence he will be hated by at least one of those viewers.\n\nFinally the remaining viewers can leave the cinema (in the order 4, 8, 6, 2) without going through any occupied seat (actually, they can leave the cinema without going through any seat at all).\n\nSample Input 2\n\n4\n6 7 1 4 13 16 10 9 5 11 12 14 15 2 3 8\n\nSample Output 2\n\n3\n\nSample Input 3\n\n6\n11 21 35 22 7 36 27 34 8 20 15 13 16 1 24 3 2 17 26 9 18 32 31 23 19 14 4 25 10 29 28 33 12 6 5 30\n\nSample Output 3\n\n11", "sample_input": "3\n1 3 7 9 5 4 8 6 2\n"}, "reference_outputs": ["1\n"], "source_document_id": "p02670", "source_text": "Score : 700 points\n\nProblem Statement\n\nTonight, in your favourite cinema they are giving the movie Joker and all seats are occupied. In the cinema there are N rows with N seats each, forming an N\\times N square. We denote with 1, 2,\\dots, N the viewers in the first row (from left to right); with N+1, \\dots, 2N the viewers in the second row (from left to right); and so on until the last row, whose viewers are denoted by N^2-N+1,\\dots, N^2.\n\nAt the end of the movie, the viewers go out of the cinema in a certain order: the i-th viewer leaving her seat is the one denoted by the number P_i. The viewer P_{i+1} waits until viewer P_i has left the cinema before leaving her seat.\nTo exit from the cinema, a viewer must move from seat to seat until she exits the square of seats (any side of the square is a valid exit). A viewer can move from a seat to one of its 4 adjacent seats (same row or same column).\nWhile leaving the cinema, it might be that a certain viewer x goes through a seat currently occupied by viewer y; in that case viewer y will hate viewer x forever. Each viewer chooses the way that minimizes the number of viewers that will hate her forever.\n\nCompute the number of pairs of viewers (x, y) such that y will hate x forever.\n\nConstraints\n\n2 \\le N \\le 500\n\nThe sequence P_1, P_2, \\dots, P_{N^2} is a permutation of \\{1, 2, \\dots, N^2\\}.\n\nInput\n\nThe input is given from Standard Input in the format\n\nN\nP_1 P_2 \\cdots P_{N^2}\n\nOutput\n\nIf ans is the number of pairs of viewers described in the statement, you should print on Standard Output\n\nans\n\nSample Input 1\n\n3\n1 3 7 9 5 4 8 6 2\n\nSample Output 1\n\n1\n\nBefore the end of the movie, the viewers are arranged in the cinema as follows:\n\n1 2 3\n4 5 6\n7 8 9\n\nThe first four viewers leaving the cinema (1, 3, 7, 9) can leave the cinema without going through any seat, so they will not be hated by anybody.\n\nThen, viewer 5 must go through one of the seats where viewers 2, 4, 6, 8 are currently seated while leaving the cinema; hence he will be hated by at least one of those viewers.\n\nFinally the remaining viewers can leave the cinema (in the order 4, 8, 6, 2) without going through any occupied seat (actually, they can leave the cinema without going through any seat at all).\n\nSample Input 2\n\n4\n6 7 1 4 13 16 10 9 5 11 12 14 15 2 3 8\n\nSample Output 2\n\n3\n\nSample Input 3\n\n6\n11 21 35 22 7 36 27 34 8 20 15 13 16 1 24 3 2 17 26 9 18 32 31 23 19 14 4 25 10 29 28 33 12 6 5 30\n\nSample Output 3\n\n11", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2169, "cpu_time_ms": 167, "memory_kb": 4512}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s462404729", "group_id": "codeNet:p02670", "input_text": "#include <bits/stdc++.h>\n\n#define ll long long\n\nusing namespace std;\n\nconst int MAXN = 250010;\nconst int MAXM = 10010;\nconst int MAXINT = 2147483647;\nconst int INF = 0x3f3f3f3f;\nconst int mod = 1e9 + 7;\n\nint n, m, k;\nint ans, tot, cnt;\n\nint a[MAXM][MAXM];\nint vis[MAXM][MAXM];\n\nstring s;\n\ninline int read() {\n\tint s = 0, f = 1;\n\tchar ch = getchar();\n\twhile ('0' > ch || ch > '9') {if (ch == '-') f = -1; ch = getchar();}\n\twhile ('0' <= ch && ch <= '9') {s = (s << 3) + (s << 1) + ch - 48; ch = getchar();}\n\treturn s * f;\n}\n\nint d[] = {-1, 1, n, -n};\nint dx[] = {0, 1, 0, -1};\nint dy[] = {1, 0, -1, 0};\n\nvoid Bfs(int s) {\n\tqueue<int> qx, qy;\n\tqueue<int> q1;\n\tqx.push((s - 1) / n + 1);\n\tqy.push((s - 1) % n + 1);\n//\tprintf(\"%d %d\\n\", qx.front(), qy.front());\n\tq1.push(0);\n\tmemset(vis, 0, sizeof(vis));\n//\tvis[z] = 0;\n\tint res = INF;\n\twhile (qx.size()) {\n\t\tint x = qx.front(), y = qy.front(), t = q1.front();\n\t\tqx.pop(); qy.pop();\n\t\tq1.pop();\n\t\tvis[x][y] = 1;\n//\t\tif (x % n == 1 || x <= n || x > n * n - n || x % n == 0)\n\t\tif (x == 1 || x == n || y == 1 || y == n) {\n\t\t\tres = min(res, t);\n//\t\t\tprintf(\"finish: %d\\n\", t);\n\t\t\tcontinue;\n\t\t}\n\t\tfor (int i = 0; i < 4; i++) {\n\t\t\tint xx = x + dx[i];\n\t\t\tint yy = y + dy[i];\n\t\t\tif (1 <= xx && xx <= n && 1 <= yy && yy <= n && !vis[xx][yy]) {\n\t\t\t\tqx.push(xx);\n\t\t\t\tqy.push(yy);\n\t\t\t\tq1.push(t + a[xx][yy]);\n\t\t\t}\n//\t\t\tif (x / n * n < x + d[i] && x + d[i] <= x / n * n + n && !vis[x + d[i]]) {\n//\t\t\t\tq.push(x + d[i]);\n//\t\t\t\tq1.push(t + e[x][i]);\n//\t\t\t}\n\t\t}\n//\t\tfor (int i = 2; i < 4; i++) {\n//\t\t\tif (0 < x + d[i] && x + d[i] <= n * n && !vis[x + d[i]]) {\n//\t\t\t\tq.push(x + d[i]);\n//\t\t\t\tq1.push(t + e[x][i]);\n//\t\t\t}\n//\t\t}\n\t}\n\tans += res;\n\treturn;\n}\n\nint p[MAXN];\n\nint main(){\n\tint T;\n\tscanf(\"%d\", &n);\n\tfor (int i = 1; i <= n * n; i++) {\n\t\tscanf(\"%d\", &p[i]);\n\t}\n//\tfor (int i = 1; i <= n * n; i++) {\n//\t\tint c = i;\n//\t\te[c][1] = e[c][2] = e[c][3] = e[c][0] = 1;\n//\t}\n\tfor (int i = 1; i <= n; i++) {\n\t\tfor (int j = 1; j <= n; j++) {\n\t\t\ta[i][j] = 1;\n\t\t}\n\t}\n\t\t\n\tfor (int i = 1; i <= n * n; i++) {\n\t\tBfs(p[i]);\n\t\ta[(p[i] - 1) / n + 1][(p[i] - 1) % n + 1] = 0;\n//\t\tint c = n * (p[i] - 1) + p[i];\n////\t\te[c][1] = e[c][2] = e[c][3] = e[c][4] = 0;\n//\t\tif (c > n) e[c - n][2] = 0;\n//\t\tif (c < n * n - n + 1) e[c + n][3] = 0;\n//\t\te[c - 1][0] = e[c + 1][1] = 0;\n//\t\tprint();\n\t}\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n\n", "language": "C++", "metadata": {"date": 1590288013, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02670.html", "problem_id": "p02670", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02670/input.txt", "sample_output_relpath": "derived/input_output/data/p02670/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02670/C++/s462404729.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s462404729", "user_id": "u965377001"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\n#define ll long long\n\nusing namespace std;\n\nconst int MAXN = 250010;\nconst int MAXM = 10010;\nconst int MAXINT = 2147483647;\nconst int INF = 0x3f3f3f3f;\nconst int mod = 1e9 + 7;\n\nint n, m, k;\nint ans, tot, cnt;\n\nint a[MAXM][MAXM];\nint vis[MAXM][MAXM];\n\nstring s;\n\ninline int read() {\n\tint s = 0, f = 1;\n\tchar ch = getchar();\n\twhile ('0' > ch || ch > '9') {if (ch == '-') f = -1; ch = getchar();}\n\twhile ('0' <= ch && ch <= '9') {s = (s << 3) + (s << 1) + ch - 48; ch = getchar();}\n\treturn s * f;\n}\n\nint d[] = {-1, 1, n, -n};\nint dx[] = {0, 1, 0, -1};\nint dy[] = {1, 0, -1, 0};\n\nvoid Bfs(int s) {\n\tqueue<int> qx, qy;\n\tqueue<int> q1;\n\tqx.push((s - 1) / n + 1);\n\tqy.push((s - 1) % n + 1);\n//\tprintf(\"%d %d\\n\", qx.front(), qy.front());\n\tq1.push(0);\n\tmemset(vis, 0, sizeof(vis));\n//\tvis[z] = 0;\n\tint res = INF;\n\twhile (qx.size()) {\n\t\tint x = qx.front(), y = qy.front(), t = q1.front();\n\t\tqx.pop(); qy.pop();\n\t\tq1.pop();\n\t\tvis[x][y] = 1;\n//\t\tif (x % n == 1 || x <= n || x > n * n - n || x % n == 0)\n\t\tif (x == 1 || x == n || y == 1 || y == n) {\n\t\t\tres = min(res, t);\n//\t\t\tprintf(\"finish: %d\\n\", t);\n\t\t\tcontinue;\n\t\t}\n\t\tfor (int i = 0; i < 4; i++) {\n\t\t\tint xx = x + dx[i];\n\t\t\tint yy = y + dy[i];\n\t\t\tif (1 <= xx && xx <= n && 1 <= yy && yy <= n && !vis[xx][yy]) {\n\t\t\t\tqx.push(xx);\n\t\t\t\tqy.push(yy);\n\t\t\t\tq1.push(t + a[xx][yy]);\n\t\t\t}\n//\t\t\tif (x / n * n < x + d[i] && x + d[i] <= x / n * n + n && !vis[x + d[i]]) {\n//\t\t\t\tq.push(x + d[i]);\n//\t\t\t\tq1.push(t + e[x][i]);\n//\t\t\t}\n\t\t}\n//\t\tfor (int i = 2; i < 4; i++) {\n//\t\t\tif (0 < x + d[i] && x + d[i] <= n * n && !vis[x + d[i]]) {\n//\t\t\t\tq.push(x + d[i]);\n//\t\t\t\tq1.push(t + e[x][i]);\n//\t\t\t}\n//\t\t}\n\t}\n\tans += res;\n\treturn;\n}\n\nint p[MAXN];\n\nint main(){\n\tint T;\n\tscanf(\"%d\", &n);\n\tfor (int i = 1; i <= n * n; i++) {\n\t\tscanf(\"%d\", &p[i]);\n\t}\n//\tfor (int i = 1; i <= n * n; i++) {\n//\t\tint c = i;\n//\t\te[c][1] = e[c][2] = e[c][3] = e[c][0] = 1;\n//\t}\n\tfor (int i = 1; i <= n; i++) {\n\t\tfor (int j = 1; j <= n; j++) {\n\t\t\ta[i][j] = 1;\n\t\t}\n\t}\n\t\t\n\tfor (int i = 1; i <= n * n; i++) {\n\t\tBfs(p[i]);\n\t\ta[(p[i] - 1) / n + 1][(p[i] - 1) % n + 1] = 0;\n//\t\tint c = n * (p[i] - 1) + p[i];\n////\t\te[c][1] = e[c][2] = e[c][3] = e[c][4] = 0;\n//\t\tif (c > n) e[c - n][2] = 0;\n//\t\tif (c < n * n - n + 1) e[c + n][3] = 0;\n//\t\te[c - 1][0] = e[c + 1][1] = 0;\n//\t\tprint();\n\t}\n\tprintf(\"%d\\n\", ans);\n\treturn 0;\n}\n\n", "problem_context": "Score : 700 points\n\nProblem Statement\n\nTonight, in your favourite cinema they are giving the movie Joker and all seats are occupied. In the cinema there are N rows with N seats each, forming an N\\times N square. We denote with 1, 2,\\dots, N the viewers in the first row (from left to right); with N+1, \\dots, 2N the viewers in the second row (from left to right); and so on until the last row, whose viewers are denoted by N^2-N+1,\\dots, N^2.\n\nAt the end of the movie, the viewers go out of the cinema in a certain order: the i-th viewer leaving her seat is the one denoted by the number P_i. The viewer P_{i+1} waits until viewer P_i has left the cinema before leaving her seat.\nTo exit from the cinema, a viewer must move from seat to seat until she exits the square of seats (any side of the square is a valid exit). A viewer can move from a seat to one of its 4 adjacent seats (same row or same column).\nWhile leaving the cinema, it might be that a certain viewer x goes through a seat currently occupied by viewer y; in that case viewer y will hate viewer x forever. Each viewer chooses the way that minimizes the number of viewers that will hate her forever.\n\nCompute the number of pairs of viewers (x, y) such that y will hate x forever.\n\nConstraints\n\n2 \\le N \\le 500\n\nThe sequence P_1, P_2, \\dots, P_{N^2} is a permutation of \\{1, 2, \\dots, N^2\\}.\n\nInput\n\nThe input is given from Standard Input in the format\n\nN\nP_1 P_2 \\cdots P_{N^2}\n\nOutput\n\nIf ans is the number of pairs of viewers described in the statement, you should print on Standard Output\n\nans\n\nSample Input 1\n\n3\n1 3 7 9 5 4 8 6 2\n\nSample Output 1\n\n1\n\nBefore the end of the movie, the viewers are arranged in the cinema as follows:\n\n1 2 3\n4 5 6\n7 8 9\n\nThe first four viewers leaving the cinema (1, 3, 7, 9) can leave the cinema without going through any seat, so they will not be hated by anybody.\n\nThen, viewer 5 must go through one of the seats where viewers 2, 4, 6, 8 are currently seated while leaving the cinema; hence he will be hated by at least one of those viewers.\n\nFinally the remaining viewers can leave the cinema (in the order 4, 8, 6, 2) without going through any occupied seat (actually, they can leave the cinema without going through any seat at all).\n\nSample Input 2\n\n4\n6 7 1 4 13 16 10 9 5 11 12 14 15 2 3 8\n\nSample Output 2\n\n3\n\nSample Input 3\n\n6\n11 21 35 22 7 36 27 34 8 20 15 13 16 1 24 3 2 17 26 9 18 32 31 23 19 14 4 25 10 29 28 33 12 6 5 30\n\nSample Output 3\n\n11", "sample_input": "3\n1 3 7 9 5 4 8 6 2\n"}, "reference_outputs": ["1\n"], "source_document_id": "p02670", "source_text": "Score : 700 points\n\nProblem Statement\n\nTonight, in your favourite cinema they are giving the movie Joker and all seats are occupied. In the cinema there are N rows with N seats each, forming an N\\times N square. We denote with 1, 2,\\dots, N the viewers in the first row (from left to right); with N+1, \\dots, 2N the viewers in the second row (from left to right); and so on until the last row, whose viewers are denoted by N^2-N+1,\\dots, N^2.\n\nAt the end of the movie, the viewers go out of the cinema in a certain order: the i-th viewer leaving her seat is the one denoted by the number P_i. The viewer P_{i+1} waits until viewer P_i has left the cinema before leaving her seat.\nTo exit from the cinema, a viewer must move from seat to seat until she exits the square of seats (any side of the square is a valid exit). A viewer can move from a seat to one of its 4 adjacent seats (same row or same column).\nWhile leaving the cinema, it might be that a certain viewer x goes through a seat currently occupied by viewer y; in that case viewer y will hate viewer x forever. Each viewer chooses the way that minimizes the number of viewers that will hate her forever.\n\nCompute the number of pairs of viewers (x, y) such that y will hate x forever.\n\nConstraints\n\n2 \\le N \\le 500\n\nThe sequence P_1, P_2, \\dots, P_{N^2} is a permutation of \\{1, 2, \\dots, N^2\\}.\n\nInput\n\nThe input is given from Standard Input in the format\n\nN\nP_1 P_2 \\cdots P_{N^2}\n\nOutput\n\nIf ans is the number of pairs of viewers described in the statement, you should print on Standard Output\n\nans\n\nSample Input 1\n\n3\n1 3 7 9 5 4 8 6 2\n\nSample Output 1\n\n1\n\nBefore the end of the movie, the viewers are arranged in the cinema as follows:\n\n1 2 3\n4 5 6\n7 8 9\n\nThe first four viewers leaving the cinema (1, 3, 7, 9) can leave the cinema without going through any seat, so they will not be hated by anybody.\n\nThen, viewer 5 must go through one of the seats where viewers 2, 4, 6, 8 are currently seated while leaving the cinema; hence he will be hated by at least one of those viewers.\n\nFinally the remaining viewers can leave the cinema (in the order 4, 8, 6, 2) without going through any occupied seat (actually, they can leave the cinema without going through any seat at all).\n\nSample Input 2\n\n4\n6 7 1 4 13 16 10 9 5 11 12 14 15 2 3 8\n\nSample Output 2\n\n3\n\nSample Input 3\n\n6\n11 21 35 22 7 36 27 34 8 20 15 13 16 1 24 3 2 17 26 9 18 32 31 23 19 14 4 25 10 29 28 33 12 6 5 30\n\nSample Output 3\n\n11", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2335, "cpu_time_ms": 2244, "memory_kb": 1189656}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s569649283", "group_id": "codeNet:p02675", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair< ll, ll > Pi;\n#define rep(i,n) for(int i=0;i<(n);i++)\n#define rep2(i,n) for(int i=1;i<=(n);i++)\n#define rep3(i,i0,n) for(int i=i0;i<(n);i++)\n#define pb push_back\n#define mod 1000000007\nconst ll INF = 1LL << 60;\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }\nll gcd(ll a, ll b) {return b?gcd(b,a%b):a;}\nll lcm(ll a, ll b) {return a/gcd(a,b)*b;}\n#define all(x) x.begin(), x.end()\n#define mp make_pair\nbool compare(Pi a, Pi b) {\n    if(a.first != b.first){\n        return a.first < b.first;\n        \n    }else{\n        return a.second < b.second;\n    }\n}\n\n\nbool In_map(ll y,ll x,ll h,ll w){\n    if(y<0 || x<0 || y>=h || x>=w){\n        return 0;\n    }else{\n        return 1;\n    }\n}\nconst vector<ll> dx{1,0,-1,0};\nconst vector<ll> dy{0,1,0,-1};\n\n\nint main() {\n    ll N;\n    cin >>N;\n    ll x = N%10;\n    if(x==3){\n        cout<<\"bon\"<<endl;\n    }else if(x==0 || x==1 || x==6 || x==8){\n        cout<<\"pon\"<<endl;\n    }else{\n        cout<<\"hon\"<<endl;\n    }\n\n\n\n    return 0;\n    \n\n}", "language": "C++", "metadata": {"date": 1597164830, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02675.html", "problem_id": "p02675", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02675/input.txt", "sample_output_relpath": "derived/input_output/data/p02675/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02675/C++/s569649283.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s569649283", "user_id": "u222188267"}, "prompt_components": {"gold_output": "pon\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair< ll, ll > Pi;\n#define rep(i,n) for(int i=0;i<(n);i++)\n#define rep2(i,n) for(int i=1;i<=(n);i++)\n#define rep3(i,i0,n) for(int i=i0;i<(n);i++)\n#define pb push_back\n#define mod 1000000007\nconst ll INF = 1LL << 60;\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }\nll gcd(ll a, ll b) {return b?gcd(b,a%b):a;}\nll lcm(ll a, ll b) {return a/gcd(a,b)*b;}\n#define all(x) x.begin(), x.end()\n#define mp make_pair\nbool compare(Pi a, Pi b) {\n    if(a.first != b.first){\n        return a.first < b.first;\n        \n    }else{\n        return a.second < b.second;\n    }\n}\n\n\nbool In_map(ll y,ll x,ll h,ll w){\n    if(y<0 || x<0 || y>=h || x>=w){\n        return 0;\n    }else{\n        return 1;\n    }\n}\nconst vector<ll> dx{1,0,-1,0};\nconst vector<ll> dy{0,1,0,-1};\n\n\nint main() {\n    ll N;\n    cin >>N;\n    ll x = N%10;\n    if(x==3){\n        cout<<\"bon\"<<endl;\n    }else if(x==0 || x==1 || x==6 || x==8){\n        cout<<\"pon\"<<endl;\n    }else{\n        cout<<\"hon\"<<endl;\n    }\n\n\n\n    return 0;\n    \n\n}", "problem_context": "Score: 100 points\n\nProblem Statement\n\nThe cat Snuke wants to play a popular Japanese game called ÅtCoder, so Iroha has decided to teach him Japanese.\n\nWhen counting pencils in Japanese, the counter word \"本\" follows the number. The pronunciation of this word varies depending on the number. Specifically, the pronunciation of \"本\" in the phrase \"N 本\" for a positive integer N not exceeding 999 is as follows:\n\nhon when the digit in the one's place of N is 2, 4, 5, 7, or 9;\n\npon when the digit in the one's place of N is 0, 1, 6 or 8;\n\nbon when the digit in the one's place of N is 3.\n\nGiven N, print the pronunciation of \"本\" in the phrase \"N 本\".\n\nConstraints\n\nN is a positive integer not exceeding 999.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n16\n\nSample Output 1\n\npon\n\nThe digit in the one's place of 16 is 6, so the \"本\" in \"16 本\" is pronounced pon.\n\nSample Input 2\n\n2\n\nSample Output 2\n\nhon\n\nSample Input 3\n\n183\n\nSample Output 3\n\nbon", "sample_input": "16\n"}, "reference_outputs": ["pon\n"], "source_document_id": "p02675", "source_text": "Score: 100 points\n\nProblem Statement\n\nThe cat Snuke wants to play a popular Japanese game called ÅtCoder, so Iroha has decided to teach him Japanese.\n\nWhen counting pencils in Japanese, the counter word \"本\" follows the number. The pronunciation of this word varies depending on the number. Specifically, the pronunciation of \"本\" in the phrase \"N 本\" for a positive integer N not exceeding 999 is as follows:\n\nhon when the digit in the one's place of N is 2, 4, 5, 7, or 9;\n\npon when the digit in the one's place of N is 0, 1, 6 or 8;\n\nbon when the digit in the one's place of N is 3.\n\nGiven N, print the pronunciation of \"本\" in the phrase \"N 本\".\n\nConstraints\n\nN is a positive integer not exceeding 999.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n16\n\nSample Output 1\n\npon\n\nThe digit in the one's place of 16 is 6, so the \"本\" in \"16 本\" is pronounced pon.\n\nSample Input 2\n\n2\n\nSample Output 2\n\nhon\n\nSample Input 3\n\n183\n\nSample Output 3\n\nbon", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1185, "cpu_time_ms": 6, "memory_kb": 3624}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s444334303", "group_id": "codeNet:p02676", "input_text": "/*\nURL_HERE\n*/\n/*\n\n*/\n#ifdef _WIN32\n\t#pragma warning(disable:4996)\n#endif\n#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#include <algorithm>\n\n#define ten5p1 100001\n#define ten6p1 1000001\n#define ten8p1 100000001\n#define ten9p1 1000000001\n#define ll long long\n#define rep(var,n) for(int var=0;var<n;++var)\n#define repi(n) rep(i,n)\n#define repj(n) rep(j,n)\n#define repi1(n) for(int i=1;i<n;++i)\n#define _min(a,b) a<b?a:b\n#define _max(a,b) a>b?a:b\n#define zeroi(data,n) memset(data,0,sizeof(int)*n);\n#define zeroll(data,n) memset(data,0,sizeof(long long)*n);\n#define one(data,n) {for(int _ONEI=0;_ONEI<n;++_ONEI) data[_ONEI]=1;}\n#define readc(var) fscanf(_fin,\"%c\",var)\n#define readi(var) fscanf(_fin,\"%d\",var)\n#define readll(var) fscanf(_fin,\"%lld\",var)\n#define repreadi(data,n) rep(_repreadi, n) readi(&data[_repreadi])\n#define writec(var) fprintf(_fout,\"%c\",var)\n#define writecsp(var) fprintf(_fout,\"%c \",var)\n#define writecln(var) fprintf(_fout,\"%c\\n\",var)\n#define writei(var) fprintf(_fout,\"%d\",var)\n#define writeisp(var) fprintf(_fout,\"%d \",var)\n#define writellsp(var) fprintf(_fout,\"%lld \",var)\n#define writeiln(var) fprintf(_fout,\"%d\\n\",var)\n#define writellln(var) fprintf(_fout,\"%lld\\n\",var)\n#define writefln(var) fprintf(_fout,\"%f\\n\",var)\n#define writes(str) fprintf(_fout,\"%s\",str)\n#define writesp() fprintf(_fout,\" \")\n#define writeln() fprintf(_fout,\"\\n\")\n#define iseven(x) ((x&1)==0 ? 1:0)\n#define RUN_LOCAL(testfilename) {_fin = fopen(testfilename, \"r\"); if(_fin==NULL) _fin=stdin;}\n#define swap(type,a, b) {type t=a;a=b;b=t;}\n#define swapxor(a,b) {a^=b;b^=a;a^=b;}\n#define sort(data,n) std::sort(data,data+n)\n#define mod(a,b) b==0 ? 0 : a==0 ? 0 :(a>0 ? a%b : b + a % b)\nll gcd(ll a, ll b) { if (b == 0) return a; return gcd(b, a % b); }\n\nFILE* _fin = stdin;\nFILE* _fout = stdout;\nvoid reversei(int* data, int n) { int k = n >> 1; repi(k) { int tmp = data[i]; data[i] = data[n - i - 1]; data[n - i - 1] = tmp; } }\nint bsearch(int val, int* data, int n) { if (data[0] > val) return -1; if (data[n - 1] < val) return n; int l = 0; int r = n - 1; for (; l < r;) { int mid = (l + r + 1) >> 1; if (data[mid] <= val) l = mid; else r = mid - 1; }if (data[r] != val) ++r; return r; }\nint reads(char* str, int maxsize) \n{ \n\tfor (;;)\n\t{ \n\t\tif(fgets(str, maxsize, _fin)==NULL) break; \n\t\tif (str[0] != '\\n' && str[0] != '\\r') break;\n\t} \n\tint slen = strlen(str); \n\tif (slen == 0) return 0;\n\tif (str[slen - 1] == '\\n' || str[slen - 1] == '\\r') str[--slen] = 0;\n\treturn slen; \n}\n\n#define _Vec(type, name) \\\nstruct name { type* data; int size; int n; };\\\nvoid init(name* t, int size) { t->data = (type*)malloc(sizeof(type) * size); t->size = size; t->n = 0; }\\\nvoid resize(name* t) { int ns = t->size * 1.2f; t->data = (type*)realloc(t->data, sizeof(type) * ns); t->size = ns; }\\\nvoid add(name* t, type val) { if (t->n >= t->size) resize(t); int k = t->n; t->data[k] = val; t->n = k + 1; }\\\nvoid free(name* t) { free(t->data);}\n_Vec(int, Veci)\n_Vec(long long, Vecll)\n_Vec(char*, Vecs)\n\n#define _ispal(type, name) int name(type* a, type* b, int n){repi(n){if (a[i] != b[n - i - 1]){return 0;}}return 1;}\n_ispal(int, ispali)\n_ispal(char, ispalc)\n\n\n#define _Pair(type, name) struct name{type x, y;}; \\\nint cmp_##name(const void* _a, const void* _b){name* a = (name*)_a;name* b = (name*)_b;if (a->x == b->x){if (a->y < b->y) return -1;else return 1;}if (a->x < b->x) return -1;else return 1;}\\\nvoid sort_##name(name* d, int n){qsort(d, n, sizeof(name), cmp_##name);}\n\t_Pair(int, Pairi)\n\n\tint cmp_Str(const void* _a, const void* _b) { char* a = *((char**)_a); char* b = *((char**)_b); return strcmp(a, b); }\nvoid sort_Str(char** str, int n) { qsort(str, n, sizeof(char*), cmp_Str); }\n\nint main()\n{\n\tRUN_LOCAL(\"dataabc168B.txt\");\n\n\tint k; readi(&k);\n\tchar s[102];\n\tint len = reads(s, 102);\n\n\trepi(k) writec(s[i]);\n\tif(k<=len) writes(\"...\\n\");\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1590035006, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02676.html", "problem_id": "p02676", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02676/input.txt", "sample_output_relpath": "derived/input_output/data/p02676/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02676/C++/s444334303.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s444334303", "user_id": "u950002813"}, "prompt_components": {"gold_output": "nikoand...\n", "input_to_evaluate": "/*\nURL_HERE\n*/\n/*\n\n*/\n#ifdef _WIN32\n\t#pragma warning(disable:4996)\n#endif\n#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#include <algorithm>\n\n#define ten5p1 100001\n#define ten6p1 1000001\n#define ten8p1 100000001\n#define ten9p1 1000000001\n#define ll long long\n#define rep(var,n) for(int var=0;var<n;++var)\n#define repi(n) rep(i,n)\n#define repj(n) rep(j,n)\n#define repi1(n) for(int i=1;i<n;++i)\n#define _min(a,b) a<b?a:b\n#define _max(a,b) a>b?a:b\n#define zeroi(data,n) memset(data,0,sizeof(int)*n);\n#define zeroll(data,n) memset(data,0,sizeof(long long)*n);\n#define one(data,n) {for(int _ONEI=0;_ONEI<n;++_ONEI) data[_ONEI]=1;}\n#define readc(var) fscanf(_fin,\"%c\",var)\n#define readi(var) fscanf(_fin,\"%d\",var)\n#define readll(var) fscanf(_fin,\"%lld\",var)\n#define repreadi(data,n) rep(_repreadi, n) readi(&data[_repreadi])\n#define writec(var) fprintf(_fout,\"%c\",var)\n#define writecsp(var) fprintf(_fout,\"%c \",var)\n#define writecln(var) fprintf(_fout,\"%c\\n\",var)\n#define writei(var) fprintf(_fout,\"%d\",var)\n#define writeisp(var) fprintf(_fout,\"%d \",var)\n#define writellsp(var) fprintf(_fout,\"%lld \",var)\n#define writeiln(var) fprintf(_fout,\"%d\\n\",var)\n#define writellln(var) fprintf(_fout,\"%lld\\n\",var)\n#define writefln(var) fprintf(_fout,\"%f\\n\",var)\n#define writes(str) fprintf(_fout,\"%s\",str)\n#define writesp() fprintf(_fout,\" \")\n#define writeln() fprintf(_fout,\"\\n\")\n#define iseven(x) ((x&1)==0 ? 1:0)\n#define RUN_LOCAL(testfilename) {_fin = fopen(testfilename, \"r\"); if(_fin==NULL) _fin=stdin;}\n#define swap(type,a, b) {type t=a;a=b;b=t;}\n#define swapxor(a,b) {a^=b;b^=a;a^=b;}\n#define sort(data,n) std::sort(data,data+n)\n#define mod(a,b) b==0 ? 0 : a==0 ? 0 :(a>0 ? a%b : b + a % b)\nll gcd(ll a, ll b) { if (b == 0) return a; return gcd(b, a % b); }\n\nFILE* _fin = stdin;\nFILE* _fout = stdout;\nvoid reversei(int* data, int n) { int k = n >> 1; repi(k) { int tmp = data[i]; data[i] = data[n - i - 1]; data[n - i - 1] = tmp; } }\nint bsearch(int val, int* data, int n) { if (data[0] > val) return -1; if (data[n - 1] < val) return n; int l = 0; int r = n - 1; for (; l < r;) { int mid = (l + r + 1) >> 1; if (data[mid] <= val) l = mid; else r = mid - 1; }if (data[r] != val) ++r; return r; }\nint reads(char* str, int maxsize) \n{ \n\tfor (;;)\n\t{ \n\t\tif(fgets(str, maxsize, _fin)==NULL) break; \n\t\tif (str[0] != '\\n' && str[0] != '\\r') break;\n\t} \n\tint slen = strlen(str); \n\tif (slen == 0) return 0;\n\tif (str[slen - 1] == '\\n' || str[slen - 1] == '\\r') str[--slen] = 0;\n\treturn slen; \n}\n\n#define _Vec(type, name) \\\nstruct name { type* data; int size; int n; };\\\nvoid init(name* t, int size) { t->data = (type*)malloc(sizeof(type) * size); t->size = size; t->n = 0; }\\\nvoid resize(name* t) { int ns = t->size * 1.2f; t->data = (type*)realloc(t->data, sizeof(type) * ns); t->size = ns; }\\\nvoid add(name* t, type val) { if (t->n >= t->size) resize(t); int k = t->n; t->data[k] = val; t->n = k + 1; }\\\nvoid free(name* t) { free(t->data);}\n_Vec(int, Veci)\n_Vec(long long, Vecll)\n_Vec(char*, Vecs)\n\n#define _ispal(type, name) int name(type* a, type* b, int n){repi(n){if (a[i] != b[n - i - 1]){return 0;}}return 1;}\n_ispal(int, ispali)\n_ispal(char, ispalc)\n\n\n#define _Pair(type, name) struct name{type x, y;}; \\\nint cmp_##name(const void* _a, const void* _b){name* a = (name*)_a;name* b = (name*)_b;if (a->x == b->x){if (a->y < b->y) return -1;else return 1;}if (a->x < b->x) return -1;else return 1;}\\\nvoid sort_##name(name* d, int n){qsort(d, n, sizeof(name), cmp_##name);}\n\t_Pair(int, Pairi)\n\n\tint cmp_Str(const void* _a, const void* _b) { char* a = *((char**)_a); char* b = *((char**)_b); return strcmp(a, b); }\nvoid sort_Str(char** str, int n) { qsort(str, n, sizeof(char*), cmp_Str); }\n\nint main()\n{\n\tRUN_LOCAL(\"dataabc168B.txt\");\n\n\tint k; readi(&k);\n\tchar s[102];\n\tint len = reads(s, 102);\n\n\trepi(k) writec(s[i]);\n\tif(k<=len) writes(\"...\\n\");\n\treturn 0;\n}", "problem_context": "Score: 200 points\n\nProblem Statement\n\nWe have a string S consisting of lowercase English letters.\n\nIf the length of S is at most K, print S without change.\n\nIf the length of S exceeds K, extract the first K characters in S, append ... to the end of them, and print the result.\n\nConstraints\n\nK is an integer between 1 and 100 (inclusive).\n\nS is a string consisting of lowercase English letters.\n\nThe length of S is between 1 and 100 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nK\nS\n\nOutput\n\nPrint a string as stated in Problem Statement.\n\nSample Input 1\n\n7\nnikoandsolstice\n\nSample Output 1\n\nnikoand...\n\nnikoandsolstice has a length of 15, which exceeds K=7.\n\nWe should extract the first 7 characters in this string, append ... to the end of them, and print the result nikoand....\n\nSample Input 2\n\n40\nferelibenterhominesidquodvoluntcredunt\n\nSample Output 2\n\nferelibenterhominesidquodvoluntcredunt\n\nThe famous quote from Gaius Julius Caesar.", "sample_input": "7\nnikoandsolstice\n"}, "reference_outputs": ["nikoand...\n"], "source_document_id": "p02676", "source_text": "Score: 200 points\n\nProblem Statement\n\nWe have a string S consisting of lowercase English letters.\n\nIf the length of S is at most K, print S without change.\n\nIf the length of S exceeds K, extract the first K characters in S, append ... to the end of them, and print the result.\n\nConstraints\n\nK is an integer between 1 and 100 (inclusive).\n\nS is a string consisting of lowercase English letters.\n\nThe length of S is between 1 and 100 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nK\nS\n\nOutput\n\nPrint a string as stated in Problem Statement.\n\nSample Input 1\n\n7\nnikoandsolstice\n\nSample Output 1\n\nnikoand...\n\nnikoandsolstice has a length of 15, which exceeds K=7.\n\nWe should extract the first 7 characters in this string, append ... to the end of them, and print the result nikoand....\n\nSample Input 2\n\n40\nferelibenterhominesidquodvoluntcredunt\n\nSample Output 2\n\nferelibenterhominesidquodvoluntcredunt\n\nThe famous quote from Gaius Julius Caesar.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 3858, "cpu_time_ms": 8, "memory_kb": 1712}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s131727196", "group_id": "codeNet:p02676", "input_text": "#pragma GCC optimize(\"O3\")\n#include <bits/stdc++.h>\nusing namespace std;\n#define boost ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0)\n#define rando mt19937 rng(chrono::steady_clock::now().time_since_epoch().count())\n#define fi first\n#define se second\n#define debug(x) cerr << \" - \" << #x << \": \" << x << endl;\n#define debugs(x, y) cerr << \" - \" << #x << \": \" << x << \" \" << #y << \": \" << y << endl;\n#define debugii(x) cerr << \" - \" << #x << \": \" << x.fi<<\",\"<<x.se << endl;\n#define sep() cerr << \"--------------------\" << endl;\n#define all(x) (x).begin(),(x).end()\n#define sz(x) (ll)x.size()\n#define ld long double\n#define ll long long\n//#define int ll\n#define ii pair<int,int>\n#define v vector<int>\n#define vii vector<ii>\n#define vv vector<vector<int> >\n#define mp make_pair\n#define INF 1000000000\n#define pb push_back\n#define EPS 1e-9\nconst int MOD = 1000000007; // 998244353\nint32_t main(){\n\tboost;\n\t//freopen(\".in\",\"r\",stdin);\n\tint k;\n\tstring s;\n\tcin>>k>>s;\n\tif(sz(s)<=k)cout<<s<<\"\\n\";\n\telse{\n\t\tcout<<s.substr(0,k)<<\"...\\n\";\n\t}\n\treturn 0;\n}\n\n//do smth instead of nothing and stay organized\n//long long\n//array bounds\n//special cases\n//binary search", "language": "C++", "metadata": {"date": 1589763825, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02676.html", "problem_id": "p02676", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02676/input.txt", "sample_output_relpath": "derived/input_output/data/p02676/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02676/C++/s131727196.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s131727196", "user_id": "u036734295"}, "prompt_components": {"gold_output": "nikoand...\n", "input_to_evaluate": "#pragma GCC optimize(\"O3\")\n#include <bits/stdc++.h>\nusing namespace std;\n#define boost ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0)\n#define rando mt19937 rng(chrono::steady_clock::now().time_since_epoch().count())\n#define fi first\n#define se second\n#define debug(x) cerr << \" - \" << #x << \": \" << x << endl;\n#define debugs(x, y) cerr << \" - \" << #x << \": \" << x << \" \" << #y << \": \" << y << endl;\n#define debugii(x) cerr << \" - \" << #x << \": \" << x.fi<<\",\"<<x.se << endl;\n#define sep() cerr << \"--------------------\" << endl;\n#define all(x) (x).begin(),(x).end()\n#define sz(x) (ll)x.size()\n#define ld long double\n#define ll long long\n//#define int ll\n#define ii pair<int,int>\n#define v vector<int>\n#define vii vector<ii>\n#define vv vector<vector<int> >\n#define mp make_pair\n#define INF 1000000000\n#define pb push_back\n#define EPS 1e-9\nconst int MOD = 1000000007; // 998244353\nint32_t main(){\n\tboost;\n\t//freopen(\".in\",\"r\",stdin);\n\tint k;\n\tstring s;\n\tcin>>k>>s;\n\tif(sz(s)<=k)cout<<s<<\"\\n\";\n\telse{\n\t\tcout<<s.substr(0,k)<<\"...\\n\";\n\t}\n\treturn 0;\n}\n\n//do smth instead of nothing and stay organized\n//long long\n//array bounds\n//special cases\n//binary search", "problem_context": "Score: 200 points\n\nProblem Statement\n\nWe have a string S consisting of lowercase English letters.\n\nIf the length of S is at most K, print S without change.\n\nIf the length of S exceeds K, extract the first K characters in S, append ... to the end of them, and print the result.\n\nConstraints\n\nK is an integer between 1 and 100 (inclusive).\n\nS is a string consisting of lowercase English letters.\n\nThe length of S is between 1 and 100 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nK\nS\n\nOutput\n\nPrint a string as stated in Problem Statement.\n\nSample Input 1\n\n7\nnikoandsolstice\n\nSample Output 1\n\nnikoand...\n\nnikoandsolstice has a length of 15, which exceeds K=7.\n\nWe should extract the first 7 characters in this string, append ... to the end of them, and print the result nikoand....\n\nSample Input 2\n\n40\nferelibenterhominesidquodvoluntcredunt\n\nSample Output 2\n\nferelibenterhominesidquodvoluntcredunt\n\nThe famous quote from Gaius Julius Caesar.", "sample_input": "7\nnikoandsolstice\n"}, "reference_outputs": ["nikoand...\n"], "source_document_id": "p02676", "source_text": "Score: 200 points\n\nProblem Statement\n\nWe have a string S consisting of lowercase English letters.\n\nIf the length of S is at most K, print S without change.\n\nIf the length of S exceeds K, extract the first K characters in S, append ... to the end of them, and print the result.\n\nConstraints\n\nK is an integer between 1 and 100 (inclusive).\n\nS is a string consisting of lowercase English letters.\n\nThe length of S is between 1 and 100 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nK\nS\n\nOutput\n\nPrint a string as stated in Problem Statement.\n\nSample Input 1\n\n7\nnikoandsolstice\n\nSample Output 1\n\nnikoand...\n\nnikoandsolstice has a length of 15, which exceeds K=7.\n\nWe should extract the first 7 characters in this string, append ... to the end of them, and print the result nikoand....\n\nSample Input 2\n\n40\nferelibenterhominesidquodvoluntcredunt\n\nSample Output 2\n\nferelibenterhominesidquodvoluntcredunt\n\nThe famous quote from Gaius Julius Caesar.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1163, "cpu_time_ms": 3, "memory_kb": 3652}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s271914015", "group_id": "codeNet:p02677", "input_text": "#include <bits/stdc++.h>\n#define IOS ios_base::sync_with_stdio(0); cin.tie(0);\nusing namespace std;\ntypedef long long ll;\n\n#define mp make_pair\n#define fi first\n#define se second\n#define pb push_back\n#define PI pair<int,int>\n\nconst double pi = acos(-1.0);\nconst int inf = 0x3f3f3f3f;\nconst ll INF = 0x3f3f3f3f3f3f3f3fll;\nconst ll mod = (ll)(1e9 + 7);\nconst int N = 1000010;\n\nint A, B, H, M;\n\nint main() {    \n    while (cin >> A >> B >> H >> M) {\n        double e1 = -(1.0 * (H * 60 + M) / 360 * pi - pi / 2);\n        double e2 = -(1.0 * M / 30 * pi - pi / 2);\n        double a = A * cos(e1), b = A * sin(e1);\n        double c = B * cos(e2), d = B * sin(e2);\n        double dis = sqrt((a - c) * (a - c) + (b - d) * (b - d));\n        cout << setprecision(14) << dis << endl;\n    }\n    return 0;\n}\n    \n", "language": "C++", "metadata": {"date": 1590186873, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02677.html", "problem_id": "p02677", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02677/input.txt", "sample_output_relpath": "derived/input_output/data/p02677/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02677/C++/s271914015.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s271914015", "user_id": "u753288484"}, "prompt_components": {"gold_output": "5.00000000000000000000\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define IOS ios_base::sync_with_stdio(0); cin.tie(0);\nusing namespace std;\ntypedef long long ll;\n\n#define mp make_pair\n#define fi first\n#define se second\n#define pb push_back\n#define PI pair<int,int>\n\nconst double pi = acos(-1.0);\nconst int inf = 0x3f3f3f3f;\nconst ll INF = 0x3f3f3f3f3f3f3f3fll;\nconst ll mod = (ll)(1e9 + 7);\nconst int N = 1000010;\n\nint A, B, H, M;\n\nint main() {    \n    while (cin >> A >> B >> H >> M) {\n        double e1 = -(1.0 * (H * 60 + M) / 360 * pi - pi / 2);\n        double e2 = -(1.0 * M / 30 * pi - pi / 2);\n        double a = A * cos(e1), b = A * sin(e1);\n        double c = B * cos(e2), d = B * sin(e2);\n        double dis = sqrt((a - c) * (a - c) + (b - d) * (b - d));\n        cout << setprecision(14) << dis << endl;\n    }\n    return 0;\n}\n    \n", "problem_context": "Score: 300 points\n\nProblem Statement\n\nConsider an analog clock whose hour and minute hands are A and B centimeters long, respectively.\n\nAn endpoint of the hour hand and an endpoint of the minute hand are fixed at the same point, around which each hand rotates clockwise at constant angular velocity. It takes the hour and minute hands 12 hours and 1 hour to make one full rotation, respectively.\n\nAt 0 o'clock, the two hands overlap each other. H hours and M minutes later, what is the distance in centimeters between the unfixed endpoints of the hands?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq A, B \\leq 1000\n\n0 \\leq H \\leq 11\n\n0 \\leq M \\leq 59\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B H M\n\nOutput\n\nPrint the answer without units. Your output will be accepted when its absolute or relative error from the correct value is at most 10^{-9}.\n\nSample Input 1\n\n3 4 9 0\n\nSample Output 1\n\n5.00000000000000000000\n\nThe two hands will be in the positions shown in the figure below, so the answer is 5 centimeters.\n\nSample Input 2\n\n3 4 10 40\n\nSample Output 2\n\n4.56425719433005567605\n\nThe two hands will be in the positions shown in the figure below. Note that each hand always rotates at constant angular velocity.", "sample_input": "3 4 9 0\n"}, "reference_outputs": ["5.00000000000000000000\n"], "source_document_id": "p02677", "source_text": "Score: 300 points\n\nProblem Statement\n\nConsider an analog clock whose hour and minute hands are A and B centimeters long, respectively.\n\nAn endpoint of the hour hand and an endpoint of the minute hand are fixed at the same point, around which each hand rotates clockwise at constant angular velocity. It takes the hour and minute hands 12 hours and 1 hour to make one full rotation, respectively.\n\nAt 0 o'clock, the two hands overlap each other. H hours and M minutes later, what is the distance in centimeters between the unfixed endpoints of the hands?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq A, B \\leq 1000\n\n0 \\leq H \\leq 11\n\n0 \\leq M \\leq 59\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B H M\n\nOutput\n\nPrint the answer without units. Your output will be accepted when its absolute or relative error from the correct value is at most 10^{-9}.\n\nSample Input 1\n\n3 4 9 0\n\nSample Output 1\n\n5.00000000000000000000\n\nThe two hands will be in the positions shown in the figure below, so the answer is 5 centimeters.\n\nSample Input 2\n\n3 4 10 40\n\nSample Output 2\n\n4.56425719433005567605\n\nThe two hands will be in the positions shown in the figure below. Note that each hand always rotates at constant angular velocity.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 801, "cpu_time_ms": 2, "memory_kb": 4156}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s786133660", "group_id": "codeNet:p02677", "input_text": "#include<iostream>\n#include<cstdio>\n#include<cmath>\nusing namespace std;\nint h, m, hl, ml;\ndouble angle, radian, ans;\nint main()\n{\n\tscanf(\"%d%d%d%d\", &hl, &ml, &h, &m);\n\tangle = fabs(0.5 *( h * 60 + m) - 6 * m * 0.1 * 10);\n\t//cout<<angle<<endl;\n\tif(angle > 180) angle -= 180;\n\tif(angle == 0) \n\t{\n\t\tprintf(\"%d\", abs(hl - ml));\n\t\treturn 0;\n\t}\n\tradian = angle * 3.14159265358979323846 / 180 * 1e-9 *1e9;\n\t//cout<<radian<<endl;\n\tans = hl * hl + ml *ml - 2 * hl * ml * cos(angle * M_PI/180);\n\tprintf(\"%.20f\", sqrt(hl * hl + ml *ml - 2 * hl * ml * cos(angle * M_PI/180)));\n\treturn 0;\n} ", "language": "C++", "metadata": {"date": 1589853837, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02677.html", "problem_id": "p02677", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02677/input.txt", "sample_output_relpath": "derived/input_output/data/p02677/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02677/C++/s786133660.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s786133660", "user_id": "u336448256"}, "prompt_components": {"gold_output": "5.00000000000000000000\n", "input_to_evaluate": "#include<iostream>\n#include<cstdio>\n#include<cmath>\nusing namespace std;\nint h, m, hl, ml;\ndouble angle, radian, ans;\nint main()\n{\n\tscanf(\"%d%d%d%d\", &hl, &ml, &h, &m);\n\tangle = fabs(0.5 *( h * 60 + m) - 6 * m * 0.1 * 10);\n\t//cout<<angle<<endl;\n\tif(angle > 180) angle -= 180;\n\tif(angle == 0) \n\t{\n\t\tprintf(\"%d\", abs(hl - ml));\n\t\treturn 0;\n\t}\n\tradian = angle * 3.14159265358979323846 / 180 * 1e-9 *1e9;\n\t//cout<<radian<<endl;\n\tans = hl * hl + ml *ml - 2 * hl * ml * cos(angle * M_PI/180);\n\tprintf(\"%.20f\", sqrt(hl * hl + ml *ml - 2 * hl * ml * cos(angle * M_PI/180)));\n\treturn 0;\n} ", "problem_context": "Score: 300 points\n\nProblem Statement\n\nConsider an analog clock whose hour and minute hands are A and B centimeters long, respectively.\n\nAn endpoint of the hour hand and an endpoint of the minute hand are fixed at the same point, around which each hand rotates clockwise at constant angular velocity. It takes the hour and minute hands 12 hours and 1 hour to make one full rotation, respectively.\n\nAt 0 o'clock, the two hands overlap each other. H hours and M minutes later, what is the distance in centimeters between the unfixed endpoints of the hands?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq A, B \\leq 1000\n\n0 \\leq H \\leq 11\n\n0 \\leq M \\leq 59\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B H M\n\nOutput\n\nPrint the answer without units. Your output will be accepted when its absolute or relative error from the correct value is at most 10^{-9}.\n\nSample Input 1\n\n3 4 9 0\n\nSample Output 1\n\n5.00000000000000000000\n\nThe two hands will be in the positions shown in the figure below, so the answer is 5 centimeters.\n\nSample Input 2\n\n3 4 10 40\n\nSample Output 2\n\n4.56425719433005567605\n\nThe two hands will be in the positions shown in the figure below. Note that each hand always rotates at constant angular velocity.", "sample_input": "3 4 9 0\n"}, "reference_outputs": ["5.00000000000000000000\n"], "source_document_id": "p02677", "source_text": "Score: 300 points\n\nProblem Statement\n\nConsider an analog clock whose hour and minute hands are A and B centimeters long, respectively.\n\nAn endpoint of the hour hand and an endpoint of the minute hand are fixed at the same point, around which each hand rotates clockwise at constant angular velocity. It takes the hour and minute hands 12 hours and 1 hour to make one full rotation, respectively.\n\nAt 0 o'clock, the two hands overlap each other. H hours and M minutes later, what is the distance in centimeters between the unfixed endpoints of the hands?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq A, B \\leq 1000\n\n0 \\leq H \\leq 11\n\n0 \\leq M \\leq 59\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B H M\n\nOutput\n\nPrint the answer without units. Your output will be accepted when its absolute or relative error from the correct value is at most 10^{-9}.\n\nSample Input 1\n\n3 4 9 0\n\nSample Output 1\n\n5.00000000000000000000\n\nThe two hands will be in the positions shown in the figure below, so the answer is 5 centimeters.\n\nSample Input 2\n\n3 4 10 40\n\nSample Output 2\n\n4.56425719433005567605\n\nThe two hands will be in the positions shown in the figure below. Note that each hand always rotates at constant angular velocity.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 580, "cpu_time_ms": 3, "memory_kb": 4204}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s860412183", "group_id": "codeNet:p02677", "input_text": "#include <bits/stdc++.h>\n#define REP(i, n) for (ll i = 1; i <= n; i++)\n#define rep(i, n) for (ll i = 0; i < n; i++)\n#define ll long long\nusing namespace std;\n\nint main()\n{\n    int A,B,H,M;\n    float PI = 3.14159265358979323846f;\n    float ans = 0;\n    cin >> A >> B >> H >> M;\n    float a,b,c;\n    a = (60.0f*H + M) * 6.0f;\n    b = (60.0f*H + M) * 0.5f;\n    c = min(abs(b - a),abs(360.0f - b + a));\n    ans = sqrtl(A*A+B*B-2.0f*A*B*cos(PI * c / 180.0f));\n    cout << fixed << setprecision(15) << ans << endl;\n    \n}\n", "language": "C++", "metadata": {"date": 1589769097, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02677.html", "problem_id": "p02677", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02677/input.txt", "sample_output_relpath": "derived/input_output/data/p02677/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02677/C++/s860412183.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s860412183", "user_id": "u442790386"}, "prompt_components": {"gold_output": "5.00000000000000000000\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define REP(i, n) for (ll i = 1; i <= n; i++)\n#define rep(i, n) for (ll i = 0; i < n; i++)\n#define ll long long\nusing namespace std;\n\nint main()\n{\n    int A,B,H,M;\n    float PI = 3.14159265358979323846f;\n    float ans = 0;\n    cin >> A >> B >> H >> M;\n    float a,b,c;\n    a = (60.0f*H + M) * 6.0f;\n    b = (60.0f*H + M) * 0.5f;\n    c = min(abs(b - a),abs(360.0f - b + a));\n    ans = sqrtl(A*A+B*B-2.0f*A*B*cos(PI * c / 180.0f));\n    cout << fixed << setprecision(15) << ans << endl;\n    \n}\n", "problem_context": "Score: 300 points\n\nProblem Statement\n\nConsider an analog clock whose hour and minute hands are A and B centimeters long, respectively.\n\nAn endpoint of the hour hand and an endpoint of the minute hand are fixed at the same point, around which each hand rotates clockwise at constant angular velocity. It takes the hour and minute hands 12 hours and 1 hour to make one full rotation, respectively.\n\nAt 0 o'clock, the two hands overlap each other. H hours and M minutes later, what is the distance in centimeters between the unfixed endpoints of the hands?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq A, B \\leq 1000\n\n0 \\leq H \\leq 11\n\n0 \\leq M \\leq 59\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B H M\n\nOutput\n\nPrint the answer without units. Your output will be accepted when its absolute or relative error from the correct value is at most 10^{-9}.\n\nSample Input 1\n\n3 4 9 0\n\nSample Output 1\n\n5.00000000000000000000\n\nThe two hands will be in the positions shown in the figure below, so the answer is 5 centimeters.\n\nSample Input 2\n\n3 4 10 40\n\nSample Output 2\n\n4.56425719433005567605\n\nThe two hands will be in the positions shown in the figure below. Note that each hand always rotates at constant angular velocity.", "sample_input": "3 4 9 0\n"}, "reference_outputs": ["5.00000000000000000000\n"], "source_document_id": "p02677", "source_text": "Score: 300 points\n\nProblem Statement\n\nConsider an analog clock whose hour and minute hands are A and B centimeters long, respectively.\n\nAn endpoint of the hour hand and an endpoint of the minute hand are fixed at the same point, around which each hand rotates clockwise at constant angular velocity. It takes the hour and minute hands 12 hours and 1 hour to make one full rotation, respectively.\n\nAt 0 o'clock, the two hands overlap each other. H hours and M minutes later, what is the distance in centimeters between the unfixed endpoints of the hands?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq A, B \\leq 1000\n\n0 \\leq H \\leq 11\n\n0 \\leq M \\leq 59\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B H M\n\nOutput\n\nPrint the answer without units. Your output will be accepted when its absolute or relative error from the correct value is at most 10^{-9}.\n\nSample Input 1\n\n3 4 9 0\n\nSample Output 1\n\n5.00000000000000000000\n\nThe two hands will be in the positions shown in the figure below, so the answer is 5 centimeters.\n\nSample Input 2\n\n3 4 10 40\n\nSample Output 2\n\n4.56425719433005567605\n\nThe two hands will be in the positions shown in the figure below. Note that each hand always rotates at constant angular velocity.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 516, "cpu_time_ms": 13, "memory_kb": 4028}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s791003160", "group_id": "codeNet:p02677", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define REP(i, n) for(int64_t i = 0; i < n; i++)\n#define REPR(i, n) for(int64_t i = n; i >= 0; i--)\n#define FOR(i, m, n) for(int64_t i = m; i < n; i++)\n#define FORR(i, m, n) for(int64_t i = m; i >= n; i--)\n#define ALL(v) v.begin(), v.end()\ntypedef long long ll;\ntemplate<typename A, size_t N, typename T>\nvoid Fill(A (&array)[N], const T &val){\n    fill( (T*)array, (T*)(array+N), val );\n}\ntemplate<class T>\ninline bool chmax(T &a, T b) {if(a < b) {a = b;return true;}return false;}\ntemplate<class T>\ninline bool chmin(T &a, T b) {if(a > b) {a = b;return true;}return false;}\nconst ll INF= 1ll << 60;\nconst ll MOD = 1000000007;\ndouble EPS = 1e-10;\n//----------------------------------------------------------\n\ndouble a,b,h,m;\nint main(){\n    cin >> a >> b >> h >> m;\n    double ans = 0;\n    double mk = M_PI/1800.0;\n    double hk = M_PI/21600.0;\n    double mr = ((mk*(h*3600+m*60)-h*2*M_PI)>=0?mk*(h*3600+m*60)-h*2*M_PI:mk*(h*3600+m*60));\n    double hr = hk*(h*3600+m*60);\n    double dr = ((mr-hr)>=0?mr-hr:hr-mr);\n    if(dr>M_PI)\n    {\n        double t1 = ((2*M_PI-hr)-mr>=0?(2*M_PI-hr)-mr:mr-(2*M_PI-hr));\n        double t2 = ((2*M_PI-mr)-hr>=0?(2*M_PI-mr)-hr:hr-(2*M_PI-mr));\n        dr=(t1>M_PI?t2:t1);\n    }\n    ans = sqrt(a*a+b*b-2*a*b*cos(dr));\n    cout << fixed << setprecision(11) << ans << endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1589766215, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02677.html", "problem_id": "p02677", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02677/input.txt", "sample_output_relpath": "derived/input_output/data/p02677/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02677/C++/s791003160.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s791003160", "user_id": "u567406270"}, "prompt_components": {"gold_output": "5.00000000000000000000\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define REP(i, n) for(int64_t i = 0; i < n; i++)\n#define REPR(i, n) for(int64_t i = n; i >= 0; i--)\n#define FOR(i, m, n) for(int64_t i = m; i < n; i++)\n#define FORR(i, m, n) for(int64_t i = m; i >= n; i--)\n#define ALL(v) v.begin(), v.end()\ntypedef long long ll;\ntemplate<typename A, size_t N, typename T>\nvoid Fill(A (&array)[N], const T &val){\n    fill( (T*)array, (T*)(array+N), val );\n}\ntemplate<class T>\ninline bool chmax(T &a, T b) {if(a < b) {a = b;return true;}return false;}\ntemplate<class T>\ninline bool chmin(T &a, T b) {if(a > b) {a = b;return true;}return false;}\nconst ll INF= 1ll << 60;\nconst ll MOD = 1000000007;\ndouble EPS = 1e-10;\n//----------------------------------------------------------\n\ndouble a,b,h,m;\nint main(){\n    cin >> a >> b >> h >> m;\n    double ans = 0;\n    double mk = M_PI/1800.0;\n    double hk = M_PI/21600.0;\n    double mr = ((mk*(h*3600+m*60)-h*2*M_PI)>=0?mk*(h*3600+m*60)-h*2*M_PI:mk*(h*3600+m*60));\n    double hr = hk*(h*3600+m*60);\n    double dr = ((mr-hr)>=0?mr-hr:hr-mr);\n    if(dr>M_PI)\n    {\n        double t1 = ((2*M_PI-hr)-mr>=0?(2*M_PI-hr)-mr:mr-(2*M_PI-hr));\n        double t2 = ((2*M_PI-mr)-hr>=0?(2*M_PI-mr)-hr:hr-(2*M_PI-mr));\n        dr=(t1>M_PI?t2:t1);\n    }\n    ans = sqrt(a*a+b*b-2*a*b*cos(dr));\n    cout << fixed << setprecision(11) << ans << endl;\n    return 0;\n}", "problem_context": "Score: 300 points\n\nProblem Statement\n\nConsider an analog clock whose hour and minute hands are A and B centimeters long, respectively.\n\nAn endpoint of the hour hand and an endpoint of the minute hand are fixed at the same point, around which each hand rotates clockwise at constant angular velocity. It takes the hour and minute hands 12 hours and 1 hour to make one full rotation, respectively.\n\nAt 0 o'clock, the two hands overlap each other. H hours and M minutes later, what is the distance in centimeters between the unfixed endpoints of the hands?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq A, B \\leq 1000\n\n0 \\leq H \\leq 11\n\n0 \\leq M \\leq 59\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B H M\n\nOutput\n\nPrint the answer without units. Your output will be accepted when its absolute or relative error from the correct value is at most 10^{-9}.\n\nSample Input 1\n\n3 4 9 0\n\nSample Output 1\n\n5.00000000000000000000\n\nThe two hands will be in the positions shown in the figure below, so the answer is 5 centimeters.\n\nSample Input 2\n\n3 4 10 40\n\nSample Output 2\n\n4.56425719433005567605\n\nThe two hands will be in the positions shown in the figure below. Note that each hand always rotates at constant angular velocity.", "sample_input": "3 4 9 0\n"}, "reference_outputs": ["5.00000000000000000000\n"], "source_document_id": "p02677", "source_text": "Score: 300 points\n\nProblem Statement\n\nConsider an analog clock whose hour and minute hands are A and B centimeters long, respectively.\n\nAn endpoint of the hour hand and an endpoint of the minute hand are fixed at the same point, around which each hand rotates clockwise at constant angular velocity. It takes the hour and minute hands 12 hours and 1 hour to make one full rotation, respectively.\n\nAt 0 o'clock, the two hands overlap each other. H hours and M minutes later, what is the distance in centimeters between the unfixed endpoints of the hands?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq A, B \\leq 1000\n\n0 \\leq H \\leq 11\n\n0 \\leq M \\leq 59\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B H M\n\nOutput\n\nPrint the answer without units. Your output will be accepted when its absolute or relative error from the correct value is at most 10^{-9}.\n\nSample Input 1\n\n3 4 9 0\n\nSample Output 1\n\n5.00000000000000000000\n\nThe two hands will be in the positions shown in the figure below, so the answer is 5 centimeters.\n\nSample Input 2\n\n3 4 10 40\n\nSample Output 2\n\n4.56425719433005567605\n\nThe two hands will be in the positions shown in the figure below. Note that each hand always rotates at constant angular velocity.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1368, "cpu_time_ms": 8, "memory_kb": 4188}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s269417471", "group_id": "codeNet:p02678", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\ndouble PI = acos(-1.0);\n#define all(v) v.begin(),v.end()\n\nint main(){\n    ios::sync_with_stdio(0);\n    cin.tie(0);\n\n    int n,m;\n    cin >> n >> m;\n\n    vector<int> adj[n+1];\n\n    for(int i= 0 ; i < m ; ++i ){\n        int a,b;\n        cin >> a >> b;\n        adj[a].push_back(b);\n        adj[b].push_back(a);\n    }\n\n    for( int i = 1 ; i < n + 1 ; ++i ){\n        for( int x : adj[i] ) cout << x <<\" \";\n        cout << endl;\n    }\n    vector<int> ans( n - 1 , -1 );\n    bool ok = true;\n    unordered_set<int> S;\n\n    for( int i = 2 ; i <= n ; ++i ){\n        sort(all(adj[i]));\n        bool ga = binary_search(all(adj[i]), 1);\n        if(ga){\n            ans[i-2] = 1;\n            S.insert(i);\n        }\n    }\n\n    for( int x : S ){\n        for( int y : adj[x] ){\n            if( ans[y-2] == -1 ) {\n                ans[y-2] = x;\n            }\n        }\n    }\n\n    for( int i = 0 ; i < ans.size() ; ++i ){\n        if( ans[i] == -1 ){\n            ok = 0;\n            break;\n        }\n    }\n    if( ok ){\n        cout << \"Yes\\n\";\n        for( int x : ans ) cout << x <<'\\n';\n    } else cout << \"No\\n\";\n\n    \n    return 0;\n}", "language": "C++", "metadata": {"date": 1589775640, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02678.html", "problem_id": "p02678", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02678/input.txt", "sample_output_relpath": "derived/input_output/data/p02678/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02678/C++/s269417471.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s269417471", "user_id": "u655630568"}, "prompt_components": {"gold_output": "Yes\n1\n2\n2\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\ndouble PI = acos(-1.0);\n#define all(v) v.begin(),v.end()\n\nint main(){\n    ios::sync_with_stdio(0);\n    cin.tie(0);\n\n    int n,m;\n    cin >> n >> m;\n\n    vector<int> adj[n+1];\n\n    for(int i= 0 ; i < m ; ++i ){\n        int a,b;\n        cin >> a >> b;\n        adj[a].push_back(b);\n        adj[b].push_back(a);\n    }\n\n    for( int i = 1 ; i < n + 1 ; ++i ){\n        for( int x : adj[i] ) cout << x <<\" \";\n        cout << endl;\n    }\n    vector<int> ans( n - 1 , -1 );\n    bool ok = true;\n    unordered_set<int> S;\n\n    for( int i = 2 ; i <= n ; ++i ){\n        sort(all(adj[i]));\n        bool ga = binary_search(all(adj[i]), 1);\n        if(ga){\n            ans[i-2] = 1;\n            S.insert(i);\n        }\n    }\n\n    for( int x : S ){\n        for( int y : adj[x] ){\n            if( ans[y-2] == -1 ) {\n                ans[y-2] = x;\n            }\n        }\n    }\n\n    for( int i = 0 ; i < ans.size() ; ++i ){\n        if( ans[i] == -1 ){\n            ok = 0;\n            break;\n        }\n    }\n    if( ok ){\n        cout << \"Yes\\n\";\n        for( int x : ans ) cout << x <<'\\n';\n    } else cout << \"No\\n\";\n\n    \n    return 0;\n}", "problem_context": "Score: 400 points\n\nProblem Statement\n\nThere is a cave.\n\nThe cave has N rooms and M passages. The rooms are numbered 1 to N, and the passages are numbered 1 to M. Passage i connects Room A_i and Room B_i bidirectionally. One can travel between any two rooms by traversing passages. Room 1 is a special room with an entrance from the outside.\n\nIt is dark in the cave, so we have decided to place a signpost in each room except Room 1. The signpost in each room will point to one of the rooms directly connected to that room with a passage.\n\nSince it is dangerous in the cave, our objective is to satisfy the condition below for each room except Room 1.\n\nIf you start in that room and repeatedly move to the room indicated by the signpost in the room you are in, you will reach Room 1 after traversing the minimum number of passages possible.\n\nDetermine whether there is a way to place signposts satisfying our objective, and print one such way if it exists.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 2 \\times 10^5\n\n1 \\leq A_i, B_i \\leq N\\ (1 \\leq i \\leq M)\n\nA_i \\neq B_i\\ (1 \\leq i \\leq M)\n\nOne can travel between any two rooms by traversing passages.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 B_1\n:\nA_M B_M\n\nOutput\n\nIf there is no way to place signposts satisfying the objective, print No.\n\nOtherwise, print N lines. The first line should contain Yes, and the i-th line (2 \\leq i \\leq N) should contain the integer representing the room indicated by the signpost in Room i.\n\nSample Input 1\n\n4 4\n1 2\n2 3\n3 4\n4 2\n\nSample Output 1\n\nYes\n1\n2\n2\n\nIf we place the signposts as described in the sample output, the following happens:\n\nStarting in Room 2, you will reach Room 1 after traversing one passage: (2) \\to 1. This is the minimum number of passages possible.\n\nStarting in Room 3, you will reach Room 1 after traversing two passages: (3) \\to 2 \\to 1. This is the minimum number of passages possible.\n\nStarting in Room 4, you will reach Room 1 after traversing two passages: (4) \\to 2 \\to 1. This is the minimum number of passages possible.\n\nThus, the objective is satisfied.\n\nSample Input 2\n\n6 9\n3 4\n6 1\n2 4\n5 3\n4 6\n1 5\n6 2\n4 5\n5 6\n\nSample Output 2\n\nYes\n6\n5\n5\n1\n1\n\nIf there are multiple solutions, any of them will be accepted.", "sample_input": "4 4\n1 2\n2 3\n3 4\n4 2\n"}, "reference_outputs": ["Yes\n1\n2\n2\n"], "source_document_id": "p02678", "source_text": "Score: 400 points\n\nProblem Statement\n\nThere is a cave.\n\nThe cave has N rooms and M passages. The rooms are numbered 1 to N, and the passages are numbered 1 to M. Passage i connects Room A_i and Room B_i bidirectionally. One can travel between any two rooms by traversing passages. Room 1 is a special room with an entrance from the outside.\n\nIt is dark in the cave, so we have decided to place a signpost in each room except Room 1. The signpost in each room will point to one of the rooms directly connected to that room with a passage.\n\nSince it is dangerous in the cave, our objective is to satisfy the condition below for each room except Room 1.\n\nIf you start in that room and repeatedly move to the room indicated by the signpost in the room you are in, you will reach Room 1 after traversing the minimum number of passages possible.\n\nDetermine whether there is a way to place signposts satisfying our objective, and print one such way if it exists.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 2 \\times 10^5\n\n1 \\leq A_i, B_i \\leq N\\ (1 \\leq i \\leq M)\n\nA_i \\neq B_i\\ (1 \\leq i \\leq M)\n\nOne can travel between any two rooms by traversing passages.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 B_1\n:\nA_M B_M\n\nOutput\n\nIf there is no way to place signposts satisfying the objective, print No.\n\nOtherwise, print N lines. The first line should contain Yes, and the i-th line (2 \\leq i \\leq N) should contain the integer representing the room indicated by the signpost in Room i.\n\nSample Input 1\n\n4 4\n1 2\n2 3\n3 4\n4 2\n\nSample Output 1\n\nYes\n1\n2\n2\n\nIf we place the signposts as described in the sample output, the following happens:\n\nStarting in Room 2, you will reach Room 1 after traversing one passage: (2) \\to 1. This is the minimum number of passages possible.\n\nStarting in Room 3, you will reach Room 1 after traversing two passages: (3) \\to 2 \\to 1. This is the minimum number of passages possible.\n\nStarting in Room 4, you will reach Room 1 after traversing two passages: (4) \\to 2 \\to 1. This is the minimum number of passages possible.\n\nThus, the objective is satisfied.\n\nSample Input 2\n\n6 9\n3 4\n6 1\n2 4\n5 3\n4 6\n1 5\n6 2\n4 5\n5 6\n\nSample Output 2\n\nYes\n6\n5\n5\n1\n1\n\nIf there are multiple solutions, any of them will be accepted.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1163, "cpu_time_ms": 240, "memory_kb": 13776}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s409697927", "group_id": "codeNet:p02679", "input_text": "#include<bits/stdc++.h>\n#define _ ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);\n#define endl '\\n'\n#define INF 0x3f3f3f3f\n#define MAX (1<<20)\n#define MOD 1000000007\n#define i64 long long\n#define all(x) (x).begin() , (x).end()\n#define sz(x) (int)(x).size()\n#define ii pair<i64, i64>\n#define fs first\n#define sc second\n#define eb emplace_back\n#define vi vector<i64>\n#define vvi vector<vi>\n#define vii vector<ii>\n#define vvii vector<vii>\n#define lsb(x) ((x) & (-x))\n#define gcd(x,y) __gcd((x),(y))\n\nusing namespace std;\n\nmap<ii, i64> f;\nvii dir;\nvi pot2;\ni64 n, xz, yz, zz, a, b, ans, fator;\n\nint main(){_\n    cin >> n;\n    \n    pot2.eb(1);\n    for (int i=n; i--;){\n        pot2.eb((2*pot2.back())%MOD);\n    }\n\n    dir = vii(n);\n    for (auto &[x, y] : dir){\n        cin >> x >> y;\n\n        if (!x) {\n            if (!y){\n                ++zz;\n                continue;\n            }else{\n                ++xz;\n            }\n        }else if (!y){\n            ++yz;\n        }\n        \n        if (x<0){\n            x = -x; y = -y;\n        }\n\n        i64 mdc = abs(gcd(x, y));\n        x /= mdc; y/=mdc;\n        \n        ++f[{x,y}];\n    }\n    \n    ans = 1LL;\n    \n    fator = (pot2[xz] + pot2[yz] - 1LL + MOD)%MOD;\n    ans = (ans * fator) % MOD;\n\n    for (auto [p, c] : f){\n        i64 x = p.fs, y=p.sc;\n\n        // cout << x << \" \" << y << \" >> \" << c << endl;\n\n        if (!x || !y || !c) continue;\n\n        a = (y > 0 ? y : -y);\n        b = (y > 0 ? -x : x);\n\n        fator = (pot2[c] + pot2[f[{a,b}]] - 1LL + MOD) % MOD;\n        ans = (ans * fator) % MOD;\n\n        f[{a,b}] *= !(f[{a,b}]);\n    }\n\n\n    cout << (ans-1LL+zz)%MOD << endl;\n\n    return 0;\n}", "language": "C++", "metadata": {"date": 1593776165, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02679.html", "problem_id": "p02679", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02679/input.txt", "sample_output_relpath": "derived/input_output/data/p02679/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02679/C++/s409697927.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s409697927", "user_id": "u781725464"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include<bits/stdc++.h>\n#define _ ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);\n#define endl '\\n'\n#define INF 0x3f3f3f3f\n#define MAX (1<<20)\n#define MOD 1000000007\n#define i64 long long\n#define all(x) (x).begin() , (x).end()\n#define sz(x) (int)(x).size()\n#define ii pair<i64, i64>\n#define fs first\n#define sc second\n#define eb emplace_back\n#define vi vector<i64>\n#define vvi vector<vi>\n#define vii vector<ii>\n#define vvii vector<vii>\n#define lsb(x) ((x) & (-x))\n#define gcd(x,y) __gcd((x),(y))\n\nusing namespace std;\n\nmap<ii, i64> f;\nvii dir;\nvi pot2;\ni64 n, xz, yz, zz, a, b, ans, fator;\n\nint main(){_\n    cin >> n;\n    \n    pot2.eb(1);\n    for (int i=n; i--;){\n        pot2.eb((2*pot2.back())%MOD);\n    }\n\n    dir = vii(n);\n    for (auto &[x, y] : dir){\n        cin >> x >> y;\n\n        if (!x) {\n            if (!y){\n                ++zz;\n                continue;\n            }else{\n                ++xz;\n            }\n        }else if (!y){\n            ++yz;\n        }\n        \n        if (x<0){\n            x = -x; y = -y;\n        }\n\n        i64 mdc = abs(gcd(x, y));\n        x /= mdc; y/=mdc;\n        \n        ++f[{x,y}];\n    }\n    \n    ans = 1LL;\n    \n    fator = (pot2[xz] + pot2[yz] - 1LL + MOD)%MOD;\n    ans = (ans * fator) % MOD;\n\n    for (auto [p, c] : f){\n        i64 x = p.fs, y=p.sc;\n\n        // cout << x << \" \" << y << \" >> \" << c << endl;\n\n        if (!x || !y || !c) continue;\n\n        a = (y > 0 ? y : -y);\n        b = (y > 0 ? -x : x);\n\n        fator = (pot2[c] + pot2[f[{a,b}]] - 1LL + MOD) % MOD;\n        ans = (ans * fator) % MOD;\n\n        f[{a,b}] *= !(f[{a,b}]);\n    }\n\n\n    cout << (ans-1LL+zz)%MOD << endl;\n\n    return 0;\n}", "problem_context": "Score: 500 points\n\nProblem Statement\n\nWe have caught N sardines. The deliciousness and fragrantness of the i-th sardine is A_i and B_i, respectively.\n\nWe will choose one or more of these sardines and put them into a cooler. However, two sardines on bad terms cannot be chosen at the same time.\n\nThe i-th and j-th sardines (i \\neq j) are on bad terms if and only if A_i \\cdot A_j + B_i \\cdot B_j = 0.\n\nIn how many ways can we choose the set of sardines to put into the cooler? Since the count can be enormous, print it modulo 1000000007.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 2 \\times 10^5\n\n-10^{18} \\leq A_i, B_i \\leq 10^{18}\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 B_1\n:\nA_N B_N\n\nOutput\n\nPrint the count modulo 1000000007.\n\nSample Input 1\n\n3\n1 2\n-1 1\n2 -1\n\nSample Output 1\n\n5\n\nThere are five ways to choose the set of sardines, as follows:\n\nThe 1-st\n\nThe 1-st and 2-nd\n\nThe 2-nd\n\nThe 2-nd and 3-rd\n\nThe 3-rd\n\nSample Input 2\n\n10\n3 2\n3 2\n-1 1\n2 -1\n-3 -9\n-8 12\n7 7\n8 1\n8 2\n8 4\n\nSample Output 2\n\n479", "sample_input": "3\n1 2\n-1 1\n2 -1\n"}, "reference_outputs": ["5\n"], "source_document_id": "p02679", "source_text": "Score: 500 points\n\nProblem Statement\n\nWe have caught N sardines. The deliciousness and fragrantness of the i-th sardine is A_i and B_i, respectively.\n\nWe will choose one or more of these sardines and put them into a cooler. However, two sardines on bad terms cannot be chosen at the same time.\n\nThe i-th and j-th sardines (i \\neq j) are on bad terms if and only if A_i \\cdot A_j + B_i \\cdot B_j = 0.\n\nIn how many ways can we choose the set of sardines to put into the cooler? Since the count can be enormous, print it modulo 1000000007.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 2 \\times 10^5\n\n-10^{18} \\leq A_i, B_i \\leq 10^{18}\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 B_1\n:\nA_N B_N\n\nOutput\n\nPrint the count modulo 1000000007.\n\nSample Input 1\n\n3\n1 2\n-1 1\n2 -1\n\nSample Output 1\n\n5\n\nThere are five ways to choose the set of sardines, as follows:\n\nThe 1-st\n\nThe 1-st and 2-nd\n\nThe 2-nd\n\nThe 2-nd and 3-rd\n\nThe 3-rd\n\nSample Input 2\n\n10\n3 2\n3 2\n-1 1\n2 -1\n-3 -9\n-8 12\n7 7\n8 1\n8 2\n8 4\n\nSample Output 2\n\n479", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1659, "cpu_time_ms": 470, "memory_kb": 32948}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s558168219", "group_id": "codeNet:p02679", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair<ll,ll> P;\n\n#define p_ary(ary,a,b) do { cout << \"[\"; for (int count = (a);count < (b);++count) cout << ary[count] << ((b)-1 == count ? \"\" : \", \"); cout << \"]\\n\"; } while(0)\n#define p_map(map,it) do {cout << \"{\";for (auto (it) = map.begin();;++(it)) {if ((it) == map.end()) {cout << \"}\\n\";break;}else cout << \"\" << (it)->first << \"=>\" << (it)->second << \", \";}}while(0)\n\ntemplate<typename T1,typename T2>ostream& operator<<(ostream& os,const pair<T1,T2>& a) {os << \"(\" << a.first << \", \" << a.second << \")\";return os;}\n\nconst char newl = '\\n';\n\nconst ll mod = 1000000007;\n//const ll mod = 998244353;\n\nconst int MAX_N = 200010;\nll fact[MAX_N],fact_inv[MAX_N],inv[MAX_N];\n\nll pow_mod(ll a,ll b) {\n    ll ret;\n    if (b < 0) ret = pow_mod(a,mod+b-1);\n    else if (b == 0) ret = 1;\n    else if (b == 1) ret = a;\n    else {\n        ll c = pow_mod(a,b/2);\n        if (b%2) ret = (c*c)%mod*a%mod;\n        else ret = c*c%mod;\n    }\n    return ret;\n}\n\nvoid init(int x) {\n    fact[0] = 1;fact[1] = 1;\n    for (int i = 2;i <= x;++i) fact[i] = fact[i-1]*i%mod;\n    fact_inv[x] = pow_mod(fact[x],-1);\n    for (int i = x;i > 0;--i) fact_inv[i-1] = fact_inv[i]*i%mod;\n    for (int i = 1;i <= x;++i) inv[i] = fact_inv[i]*fact[i-1]%mod;\n}\n\nll combi(ll a, ll b) {\n    return fact[a]*fact_inv[b]%mod*fact_inv[a-b]%mod;\n}\n\nint main() {\n    int n,m = 0;\n    cin >> n;\n    init(n);\n    map<P,int> mp;\n    set<P> st;\n    for (int i = 0;i < n;++i) {\n        ll a,b;\n        scanf(\"%lld%lld\",&a,&b);\n        if (a == 0 && b == 0) {\n            n--;\n            m++;\n            continue;\n        }\n        ll g = gcd(abs(a),abs(b));\n        a /= g;\n        b /= g;\n        if (a < 0 || (a == 0 && b < 0)) {\n            a *= -1;\n            b *= -1;\n        }\n        mp[make_pair(a,b)]++;\n    }\n    ll ans = pow_mod(2,n)-1,s = 1;\n    for (auto p : mp) {\n        P q = make_pair(p.first.second,-p.first.first);\n        if (q.first < 0 || (q.first == 0 && q.second < 0)) {\n            q.first *= -1;\n            q.second *= -1;\n        }\n        if (mp.find(q) == mp.end() || st.find(p.first) != st.end()) continue;\n        n -= p.second+mp[q];\n        (ans -= (pow_mod(2,p.second)-1)*(pow_mod(2,mp[q])-1)%mod*(pow_mod(2,n)*s%mod)%mod) %= mod;\n        st.insert(p.first);\n        st.insert(q);\n        (s *= (pow_mod(2,p.second+mp[q])-(pow_mod(2,p.second)-1)*(pow_mod(2,mp[q])-1)%mod)%mod) %= mod;\n    }\n    cout << (ans+m+mod)%mod << endl;\n}", "language": "C++", "metadata": {"date": 1589767290, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02679.html", "problem_id": "p02679", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02679/input.txt", "sample_output_relpath": "derived/input_output/data/p02679/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02679/C++/s558168219.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s558168219", "user_id": "u506255180"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair<ll,ll> P;\n\n#define p_ary(ary,a,b) do { cout << \"[\"; for (int count = (a);count < (b);++count) cout << ary[count] << ((b)-1 == count ? \"\" : \", \"); cout << \"]\\n\"; } while(0)\n#define p_map(map,it) do {cout << \"{\";for (auto (it) = map.begin();;++(it)) {if ((it) == map.end()) {cout << \"}\\n\";break;}else cout << \"\" << (it)->first << \"=>\" << (it)->second << \", \";}}while(0)\n\ntemplate<typename T1,typename T2>ostream& operator<<(ostream& os,const pair<T1,T2>& a) {os << \"(\" << a.first << \", \" << a.second << \")\";return os;}\n\nconst char newl = '\\n';\n\nconst ll mod = 1000000007;\n//const ll mod = 998244353;\n\nconst int MAX_N = 200010;\nll fact[MAX_N],fact_inv[MAX_N],inv[MAX_N];\n\nll pow_mod(ll a,ll b) {\n    ll ret;\n    if (b < 0) ret = pow_mod(a,mod+b-1);\n    else if (b == 0) ret = 1;\n    else if (b == 1) ret = a;\n    else {\n        ll c = pow_mod(a,b/2);\n        if (b%2) ret = (c*c)%mod*a%mod;\n        else ret = c*c%mod;\n    }\n    return ret;\n}\n\nvoid init(int x) {\n    fact[0] = 1;fact[1] = 1;\n    for (int i = 2;i <= x;++i) fact[i] = fact[i-1]*i%mod;\n    fact_inv[x] = pow_mod(fact[x],-1);\n    for (int i = x;i > 0;--i) fact_inv[i-1] = fact_inv[i]*i%mod;\n    for (int i = 1;i <= x;++i) inv[i] = fact_inv[i]*fact[i-1]%mod;\n}\n\nll combi(ll a, ll b) {\n    return fact[a]*fact_inv[b]%mod*fact_inv[a-b]%mod;\n}\n\nint main() {\n    int n,m = 0;\n    cin >> n;\n    init(n);\n    map<P,int> mp;\n    set<P> st;\n    for (int i = 0;i < n;++i) {\n        ll a,b;\n        scanf(\"%lld%lld\",&a,&b);\n        if (a == 0 && b == 0) {\n            n--;\n            m++;\n            continue;\n        }\n        ll g = gcd(abs(a),abs(b));\n        a /= g;\n        b /= g;\n        if (a < 0 || (a == 0 && b < 0)) {\n            a *= -1;\n            b *= -1;\n        }\n        mp[make_pair(a,b)]++;\n    }\n    ll ans = pow_mod(2,n)-1,s = 1;\n    for (auto p : mp) {\n        P q = make_pair(p.first.second,-p.first.first);\n        if (q.first < 0 || (q.first == 0 && q.second < 0)) {\n            q.first *= -1;\n            q.second *= -1;\n        }\n        if (mp.find(q) == mp.end() || st.find(p.first) != st.end()) continue;\n        n -= p.second+mp[q];\n        (ans -= (pow_mod(2,p.second)-1)*(pow_mod(2,mp[q])-1)%mod*(pow_mod(2,n)*s%mod)%mod) %= mod;\n        st.insert(p.first);\n        st.insert(q);\n        (s *= (pow_mod(2,p.second+mp[q])-(pow_mod(2,p.second)-1)*(pow_mod(2,mp[q])-1)%mod)%mod) %= mod;\n    }\n    cout << (ans+m+mod)%mod << endl;\n}", "problem_context": "Score: 500 points\n\nProblem Statement\n\nWe have caught N sardines. The deliciousness and fragrantness of the i-th sardine is A_i and B_i, respectively.\n\nWe will choose one or more of these sardines and put them into a cooler. However, two sardines on bad terms cannot be chosen at the same time.\n\nThe i-th and j-th sardines (i \\neq j) are on bad terms if and only if A_i \\cdot A_j + B_i \\cdot B_j = 0.\n\nIn how many ways can we choose the set of sardines to put into the cooler? Since the count can be enormous, print it modulo 1000000007.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 2 \\times 10^5\n\n-10^{18} \\leq A_i, B_i \\leq 10^{18}\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 B_1\n:\nA_N B_N\n\nOutput\n\nPrint the count modulo 1000000007.\n\nSample Input 1\n\n3\n1 2\n-1 1\n2 -1\n\nSample Output 1\n\n5\n\nThere are five ways to choose the set of sardines, as follows:\n\nThe 1-st\n\nThe 1-st and 2-nd\n\nThe 2-nd\n\nThe 2-nd and 3-rd\n\nThe 3-rd\n\nSample Input 2\n\n10\n3 2\n3 2\n-1 1\n2 -1\n-3 -9\n-8 12\n7 7\n8 1\n8 2\n8 4\n\nSample Output 2\n\n479", "sample_input": "3\n1 2\n-1 1\n2 -1\n"}, "reference_outputs": ["5\n"], "source_document_id": "p02679", "source_text": "Score: 500 points\n\nProblem Statement\n\nWe have caught N sardines. The deliciousness and fragrantness of the i-th sardine is A_i and B_i, respectively.\n\nWe will choose one or more of these sardines and put them into a cooler. However, two sardines on bad terms cannot be chosen at the same time.\n\nThe i-th and j-th sardines (i \\neq j) are on bad terms if and only if A_i \\cdot A_j + B_i \\cdot B_j = 0.\n\nIn how many ways can we choose the set of sardines to put into the cooler? Since the count can be enormous, print it modulo 1000000007.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 2 \\times 10^5\n\n-10^{18} \\leq A_i, B_i \\leq 10^{18}\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 B_1\n:\nA_N B_N\n\nOutput\n\nPrint the count modulo 1000000007.\n\nSample Input 1\n\n3\n1 2\n-1 1\n2 -1\n\nSample Output 1\n\n5\n\nThere are five ways to choose the set of sardines, as follows:\n\nThe 1-st\n\nThe 1-st and 2-nd\n\nThe 2-nd\n\nThe 2-nd and 3-rd\n\nThe 3-rd\n\nSample Input 2\n\n10\n3 2\n3 2\n-1 1\n2 -1\n-3 -9\n-8 12\n7 7\n8 1\n8 2\n8 4\n\nSample Output 2\n\n479", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2494, "cpu_time_ms": 312, "memory_kb": 20888}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s136178695", "group_id": "codeNet:p02681", "input_text": "#include <bits/stdc++.h>\n#define ALL(a)  (a).begin(),(a).end()\n#define sz(x) int(x.size())\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int, int> P;\ntypedef pair<long long, long long> Pll;\ntypedef vector<int> vi;\ntypedef vector<vector<int>> vvi;\ntypedef vector<long long> vll;\ntypedef vector<vector<long long>> vvll;\ntemplate <typename T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate <typename T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }\nconst long long INF = 1LL << 60;\nconst int INT_INF = 1 << 30;\n#define MOD 1000000007LL\n#define PI 3.141592653589793\n#define endl \"\\n\"\n\nint main(){\n  ios::sync_with_stdio(false);\n  cin.tie(nullptr);\n  string S, T;\n  cin >> S >> T;\n  bool flag = false;\n  for(int i = 0; i < 26; i++){\n    string str = S + (char)(i + 'a');\n    if(str == T) flag = true;\n  }\n  if(flag) cout << \"Yes\" << endl;\n  else cout << \"No\" << endl;\n}", "language": "C++", "metadata": {"date": 1589158939, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02681.html", "problem_id": "p02681", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02681/input.txt", "sample_output_relpath": "derived/input_output/data/p02681/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02681/C++/s136178695.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s136178695", "user_id": "u455266724"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define ALL(a)  (a).begin(),(a).end()\n#define sz(x) int(x.size())\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int, int> P;\ntypedef pair<long long, long long> Pll;\ntypedef vector<int> vi;\ntypedef vector<vector<int>> vvi;\ntypedef vector<long long> vll;\ntypedef vector<vector<long long>> vvll;\ntemplate <typename T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate <typename T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }\nconst long long INF = 1LL << 60;\nconst int INT_INF = 1 << 30;\n#define MOD 1000000007LL\n#define PI 3.141592653589793\n#define endl \"\\n\"\n\nint main(){\n  ios::sync_with_stdio(false);\n  cin.tie(nullptr);\n  string S, T;\n  cin >> S >> T;\n  bool flag = false;\n  for(int i = 0; i < 26; i++){\n    string str = S + (char)(i + 'a');\n    if(str == T) flag = true;\n  }\n  if(flag) cout << \"Yes\" << endl;\n  else cout << \"No\" << endl;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nTakahashi wants to be a member of some web service.\n\nHe tried to register himself with the ID S, which turned out to be already used by another user.\n\nThus, he decides to register using a string obtained by appending one character at the end of S as his ID.\n\nHe is now trying to register with the ID T. Determine whether this string satisfies the property above.\n\nConstraints\n\nS and T are strings consisting of lowercase English letters.\n\n1 \\leq |S| \\leq 10\n\n|T| = |S| + 1\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\nT\n\nOutput\n\nIf T satisfies the property in Problem Statement, print Yes; otherwise, print No.\n\nSample Input 1\n\nchokudai\nchokudaiz\n\nSample Output 1\n\nYes\n\nchokudaiz can be obtained by appending z at the end of chokudai.\n\nSample Input 2\n\nsnuke\nsnekee\n\nSample Output 2\n\nNo\n\nsnekee cannot be obtained by appending one character at the end of snuke.\n\nSample Input 3\n\na\naa\n\nSample Output 3\n\nYes", "sample_input": "chokudai\nchokudaiz\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p02681", "source_text": "Score : 100 points\n\nProblem Statement\n\nTakahashi wants to be a member of some web service.\n\nHe tried to register himself with the ID S, which turned out to be already used by another user.\n\nThus, he decides to register using a string obtained by appending one character at the end of S as his ID.\n\nHe is now trying to register with the ID T. Determine whether this string satisfies the property above.\n\nConstraints\n\nS and T are strings consisting of lowercase English letters.\n\n1 \\leq |S| \\leq 10\n\n|T| = |S| + 1\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\nT\n\nOutput\n\nIf T satisfies the property in Problem Statement, print Yes; otherwise, print No.\n\nSample Input 1\n\nchokudai\nchokudaiz\n\nSample Output 1\n\nYes\n\nchokudaiz can be obtained by appending z at the end of chokudai.\n\nSample Input 2\n\nsnuke\nsnekee\n\nSample Output 2\n\nNo\n\nsnekee cannot be obtained by appending one character at the end of snuke.\n\nSample Input 3\n\na\naa\n\nSample Output 3\n\nYes", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 940, "cpu_time_ms": 9, "memory_kb": 3652}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s231737286", "group_id": "codeNet:p02682", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n\tlong long a,b,c,k;\n\tscanf(\"%lld %lld %lld %lld\",&a,&b,&c,&k);\n\tlong long ans = min(a,k);\n\tk-=a;\n\tk = k-b;\n\tif(k){\n\t\tans -= k;\n\t}\n\tprintf(\"%lld\\n\", ans);\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1600514167, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02682.html", "problem_id": "p02682", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02682/input.txt", "sample_output_relpath": "derived/input_output/data/p02682/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02682/C++/s231737286.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s231737286", "user_id": "u653041893"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n\tlong long a,b,c,k;\n\tscanf(\"%lld %lld %lld %lld\",&a,&b,&c,&k);\n\tlong long ans = min(a,k);\n\tk-=a;\n\tk = k-b;\n\tif(k){\n\t\tans -= k;\n\t}\n\tprintf(\"%lld\\n\", ans);\n\treturn 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nWe have A cards, each of which has an integer 1 written on it. Similarly, we also have B cards with 0s and C cards with -1s.\n\nWe will pick up K among these cards. What is the maximum possible sum of the numbers written on the cards chosen?\n\nConstraints\n\nAll values in input are integers.\n\n0 \\leq A, B, C\n\n1 \\leq K \\leq A + B + C \\leq 2 \\times 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B C K\n\nOutput\n\nPrint the maximum possible sum of the numbers written on the cards chosen.\n\nSample Input 1\n\n2 1 1 3\n\nSample Output 1\n\n2\n\nConsider picking up two cards with 1s and one card with a 0.\nIn this case, the sum of the numbers written on the cards is 2, which is the maximum possible value.\n\nSample Input 2\n\n1 2 3 4\n\nSample Output 2\n\n0\n\nSample Input 3\n\n2000000000 0 0 2000000000\n\nSample Output 3\n\n2000000000", "sample_input": "2 1 1 3\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02682", "source_text": "Score : 200 points\n\nProblem Statement\n\nWe have A cards, each of which has an integer 1 written on it. Similarly, we also have B cards with 0s and C cards with -1s.\n\nWe will pick up K among these cards. What is the maximum possible sum of the numbers written on the cards chosen?\n\nConstraints\n\nAll values in input are integers.\n\n0 \\leq A, B, C\n\n1 \\leq K \\leq A + B + C \\leq 2 \\times 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B C K\n\nOutput\n\nPrint the maximum possible sum of the numbers written on the cards chosen.\n\nSample Input 1\n\n2 1 1 3\n\nSample Output 1\n\n2\n\nConsider picking up two cards with 1s and one card with a 0.\nIn this case, the sum of the numbers written on the cards is 2, which is the maximum possible value.\n\nSample Input 2\n\n1 2 3 4\n\nSample Output 2\n\n0\n\nSample Input 3\n\n2000000000 0 0 2000000000\n\nSample Output 3\n\n2000000000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 223, "cpu_time_ms": 9, "memory_kb": 3732}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s282371064", "group_id": "codeNet:p02682", "input_text": "#include <bits/stdc++.h>\n#define rep(i,n) for(int i = 0;i < (n); ++i)\nusing namespace std;\nusing ll = long long;\nusing P = pair<int,int>;\nint main() {\n  ll a,b,c;\n  ll k;\n  cin >> a >> b >> c >> k;\n  ll ans;\n  if(k - a - b > 0){\n    ans = a - (k - a - b);\n  }else if(k < a){\n    ans = k;\n  }else if(k - a - b < 0){\n    ans = a;\n  }\n  cout << ans << endl;\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1589160764, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02682.html", "problem_id": "p02682", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02682/input.txt", "sample_output_relpath": "derived/input_output/data/p02682/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02682/C++/s282371064.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s282371064", "user_id": "u951586418"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define rep(i,n) for(int i = 0;i < (n); ++i)\nusing namespace std;\nusing ll = long long;\nusing P = pair<int,int>;\nint main() {\n  ll a,b,c;\n  ll k;\n  cin >> a >> b >> c >> k;\n  ll ans;\n  if(k - a - b > 0){\n    ans = a - (k - a - b);\n  }else if(k < a){\n    ans = k;\n  }else if(k - a - b < 0){\n    ans = a;\n  }\n  cout << ans << endl;\n  return 0;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nWe have A cards, each of which has an integer 1 written on it. Similarly, we also have B cards with 0s and C cards with -1s.\n\nWe will pick up K among these cards. What is the maximum possible sum of the numbers written on the cards chosen?\n\nConstraints\n\nAll values in input are integers.\n\n0 \\leq A, B, C\n\n1 \\leq K \\leq A + B + C \\leq 2 \\times 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B C K\n\nOutput\n\nPrint the maximum possible sum of the numbers written on the cards chosen.\n\nSample Input 1\n\n2 1 1 3\n\nSample Output 1\n\n2\n\nConsider picking up two cards with 1s and one card with a 0.\nIn this case, the sum of the numbers written on the cards is 2, which is the maximum possible value.\n\nSample Input 2\n\n1 2 3 4\n\nSample Output 2\n\n0\n\nSample Input 3\n\n2000000000 0 0 2000000000\n\nSample Output 3\n\n2000000000", "sample_input": "2 1 1 3\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02682", "source_text": "Score : 200 points\n\nProblem Statement\n\nWe have A cards, each of which has an integer 1 written on it. Similarly, we also have B cards with 0s and C cards with -1s.\n\nWe will pick up K among these cards. What is the maximum possible sum of the numbers written on the cards chosen?\n\nConstraints\n\nAll values in input are integers.\n\n0 \\leq A, B, C\n\n1 \\leq K \\leq A + B + C \\leq 2 \\times 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B C K\n\nOutput\n\nPrint the maximum possible sum of the numbers written on the cards chosen.\n\nSample Input 1\n\n2 1 1 3\n\nSample Output 1\n\n2\n\nConsider picking up two cards with 1s and one card with a 0.\nIn this case, the sum of the numbers written on the cards is 2, which is the maximum possible value.\n\nSample Input 2\n\n1 2 3 4\n\nSample Output 2\n\n0\n\nSample Input 3\n\n2000000000 0 0 2000000000\n\nSample Output 3\n\n2000000000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 369, "cpu_time_ms": 3, "memory_kb": 3628}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s207004647", "group_id": "codeNet:p02682", "input_text": "#include <iostream>\n#include <vector>\n#include <queue>\n#include <algorithm>\n#include <cmath>\n#include <bitset>\n#include <iomanip>\n#include <stack>\n#include <list>\n#include <map>\n#include <unordered_map>\n#include <chrono>\n#include <numeric>\nusing namespace std;\nusing ll = long long;\nconst ll INF = (ll)1e18+1;\nconst ll DIV = 1000000007;\n//#define TEST\nint main()\n{\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n#ifdef TEST\n    chrono::system_clock::time_point start, end;\n    start = chrono::system_clock::now();\n#endif\n    long A,B,C,K;\n    cin >> A >> B >> C >> K;\n    if(K <= A) cout << K << endl;\n    else if(K > A && K <= A+B) cout << A << endl;\n    else cout << A - (K - (A + B)) << endl;\n#ifdef TEST\n    end = chrono::system_clock::now();\n    cerr << static_cast<double>(chrono::duration_cast<chrono::microseconds>(end - start).count() / 1000.0) << \"[ms]\" << endl;\n#endif\n    return 0;\n}", "language": "C++", "metadata": {"date": 1589159168, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02682.html", "problem_id": "p02682", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02682/input.txt", "sample_output_relpath": "derived/input_output/data/p02682/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02682/C++/s207004647.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s207004647", "user_id": "u645961531"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\n#include <queue>\n#include <algorithm>\n#include <cmath>\n#include <bitset>\n#include <iomanip>\n#include <stack>\n#include <list>\n#include <map>\n#include <unordered_map>\n#include <chrono>\n#include <numeric>\nusing namespace std;\nusing ll = long long;\nconst ll INF = (ll)1e18+1;\nconst ll DIV = 1000000007;\n//#define TEST\nint main()\n{\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n#ifdef TEST\n    chrono::system_clock::time_point start, end;\n    start = chrono::system_clock::now();\n#endif\n    long A,B,C,K;\n    cin >> A >> B >> C >> K;\n    if(K <= A) cout << K << endl;\n    else if(K > A && K <= A+B) cout << A << endl;\n    else cout << A - (K - (A + B)) << endl;\n#ifdef TEST\n    end = chrono::system_clock::now();\n    cerr << static_cast<double>(chrono::duration_cast<chrono::microseconds>(end - start).count() / 1000.0) << \"[ms]\" << endl;\n#endif\n    return 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nWe have A cards, each of which has an integer 1 written on it. Similarly, we also have B cards with 0s and C cards with -1s.\n\nWe will pick up K among these cards. What is the maximum possible sum of the numbers written on the cards chosen?\n\nConstraints\n\nAll values in input are integers.\n\n0 \\leq A, B, C\n\n1 \\leq K \\leq A + B + C \\leq 2 \\times 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B C K\n\nOutput\n\nPrint the maximum possible sum of the numbers written on the cards chosen.\n\nSample Input 1\n\n2 1 1 3\n\nSample Output 1\n\n2\n\nConsider picking up two cards with 1s and one card with a 0.\nIn this case, the sum of the numbers written on the cards is 2, which is the maximum possible value.\n\nSample Input 2\n\n1 2 3 4\n\nSample Output 2\n\n0\n\nSample Input 3\n\n2000000000 0 0 2000000000\n\nSample Output 3\n\n2000000000", "sample_input": "2 1 1 3\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02682", "source_text": "Score : 200 points\n\nProblem Statement\n\nWe have A cards, each of which has an integer 1 written on it. Similarly, we also have B cards with 0s and C cards with -1s.\n\nWe will pick up K among these cards. What is the maximum possible sum of the numbers written on the cards chosen?\n\nConstraints\n\nAll values in input are integers.\n\n0 \\leq A, B, C\n\n1 \\leq K \\leq A + B + C \\leq 2 \\times 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B C K\n\nOutput\n\nPrint the maximum possible sum of the numbers written on the cards chosen.\n\nSample Input 1\n\n2 1 1 3\n\nSample Output 1\n\n2\n\nConsider picking up two cards with 1s and one card with a 0.\nIn this case, the sum of the numbers written on the cards is 2, which is the maximum possible value.\n\nSample Input 2\n\n1 2 3 4\n\nSample Output 2\n\n0\n\nSample Input 3\n\n2000000000 0 0 2000000000\n\nSample Output 3\n\n2000000000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 897, "cpu_time_ms": 6, "memory_kb": 3604}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s621002870", "group_id": "codeNet:p02683", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nint mi=INT_MAX;\nbool xx=false;\nvoid recursrion(int index ,int currSum,int K,vector < pair< int , vector<int> > > &arr,vector<int> Books,int N,int M)\n{\n    if(index>=N){return ;}\n    recursrion(index+1,currSum,K,arr,Books,N,M);\n    int cost=arr[index].first;\n    currSum+=cost;\n    vector<int> x=arr[index].second;\n    for(int i=0;i<M;i++)\n    {\n        Books[i]+=x[i];\n    }\n    int FLAG=0;\n    for(int i=0;i<M;i++)\n    {\n        if(Books[i]<K)\n        {\n            FLAG=1;\n            break;\n        }\n    }\n    if(FLAG==0)\n    {\n        xx=true;\n        mi=min(mi,currSum);\n    }\n    recursrion(index+1,currSum,K,arr,Books,N,M);\n    return ;\n}\nint main()\n{\n    // freopen(\"input.txt\",\"r\",stdin);freopen(\"output.txt\",\"w\",stdout);\n    int N,M,K;\n    cin>>N>>M>>K;\n    vector < pair < int , vector<int> > > arr;\n    for(int i=0;i<N;i++)\n    {\n        int x;\n        cin>>x;\n        vector<int> S(M);\n        for(auto &it:S)\n        {\n            cin>>it;\n        }\n        arr.push_back(make_pair(x,S));\n    }\n    vector<int> Books(M,0);\n    recursrion(0,0,K,arr,Books,N,M);\n    if(xx==true)\n    {\n        cout<<mi;\n    }\n    else\n    {\n        cout<<-1;\n    }\n    \n}", "language": "C++", "metadata": {"date": 1589161291, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02683.html", "problem_id": "p02683", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02683/input.txt", "sample_output_relpath": "derived/input_output/data/p02683/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02683/C++/s621002870.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s621002870", "user_id": "u880337594"}, "prompt_components": {"gold_output": "120\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nint mi=INT_MAX;\nbool xx=false;\nvoid recursrion(int index ,int currSum,int K,vector < pair< int , vector<int> > > &arr,vector<int> Books,int N,int M)\n{\n    if(index>=N){return ;}\n    recursrion(index+1,currSum,K,arr,Books,N,M);\n    int cost=arr[index].first;\n    currSum+=cost;\n    vector<int> x=arr[index].second;\n    for(int i=0;i<M;i++)\n    {\n        Books[i]+=x[i];\n    }\n    int FLAG=0;\n    for(int i=0;i<M;i++)\n    {\n        if(Books[i]<K)\n        {\n            FLAG=1;\n            break;\n        }\n    }\n    if(FLAG==0)\n    {\n        xx=true;\n        mi=min(mi,currSum);\n    }\n    recursrion(index+1,currSum,K,arr,Books,N,M);\n    return ;\n}\nint main()\n{\n    // freopen(\"input.txt\",\"r\",stdin);freopen(\"output.txt\",\"w\",stdout);\n    int N,M,K;\n    cin>>N>>M>>K;\n    vector < pair < int , vector<int> > > arr;\n    for(int i=0;i<N;i++)\n    {\n        int x;\n        cin>>x;\n        vector<int> S(M);\n        for(auto &it:S)\n        {\n            cin>>it;\n        }\n        arr.push_back(make_pair(x,S));\n    }\n    vector<int> Books(M,0);\n    recursrion(0,0,K,arr,Books,N,M);\n    if(xx==true)\n    {\n        cout<<mi;\n    }\n    else\n    {\n        cout<<-1;\n    }\n    \n}", "problem_context": "Score : 300 points\n\nProblem\n\nTakahashi, who is a novice in competitive programming, wants to learn M algorithms.\nInitially, his understanding level of each of the M algorithms is 0.\n\nTakahashi is visiting a bookstore, where he finds N books on algorithms.\nThe i-th book (1\\leq i\\leq N) is sold for C_i yen (the currency of Japan). If he buys and reads it, his understanding level of the j-th algorithm will increase by A_{i,j} for each j (1\\leq j\\leq M).\nThere is no other way to increase the understanding levels of the algorithms.\n\nTakahashi's objective is to make his understanding levels of all the M algorithms X or higher. Determine whether this objective is achievable. If it is achievable, find the minimum amount of money needed to achieve it.\n\nConstraints\n\nAll values in input are integers.\n\n1\\leq N, M\\leq 12\n\n1\\leq X\\leq 10^5\n\n1\\leq C_i \\leq 10^5\n\n0\\leq A_{i, j} \\leq 10^5\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M X\nC_1 A_{1,1} A_{1,2} \\cdots A_{1,M}\nC_2 A_{2,1} A_{2,2} \\cdots A_{2,M}\n\\vdots\nC_N A_{N,1} A_{N,2} \\cdots A_{N,M}\n\nOutput\n\nIf the objective is not achievable, print -1; otherwise, print the minimum amount of money needed to achieve it.\n\nSample Input 1\n\n3 3 10\n60 2 2 4\n70 8 7 9\n50 2 3 9\n\nSample Output 1\n\n120\n\nBuying the second and third books makes his understanding levels of all the algorithms 10 or higher, at the minimum cost possible.\n\nSample Input 2\n\n3 3 10\n100 3 1 4\n100 1 5 9\n100 2 6 5\n\nSample Output 2\n\n-1\n\nBuying all the books is still not enough to make his understanding levels of all the algorithms 10 or higher.\n\nSample Input 3\n\n8 5 22\n100 3 7 5 3 1\n164 4 5 2 7 8\n334 7 2 7 2 9\n234 4 7 2 8 2\n541 5 4 3 3 6\n235 4 8 6 9 7\n394 3 6 1 6 2\n872 8 4 3 7 2\n\nSample Output 3\n\n1067", "sample_input": "3 3 10\n60 2 2 4\n70 8 7 9\n50 2 3 9\n"}, "reference_outputs": ["120\n"], "source_document_id": "p02683", "source_text": "Score : 300 points\n\nProblem\n\nTakahashi, who is a novice in competitive programming, wants to learn M algorithms.\nInitially, his understanding level of each of the M algorithms is 0.\n\nTakahashi is visiting a bookstore, where he finds N books on algorithms.\nThe i-th book (1\\leq i\\leq N) is sold for C_i yen (the currency of Japan). If he buys and reads it, his understanding level of the j-th algorithm will increase by A_{i,j} for each j (1\\leq j\\leq M).\nThere is no other way to increase the understanding levels of the algorithms.\n\nTakahashi's objective is to make his understanding levels of all the M algorithms X or higher. Determine whether this objective is achievable. If it is achievable, find the minimum amount of money needed to achieve it.\n\nConstraints\n\nAll values in input are integers.\n\n1\\leq N, M\\leq 12\n\n1\\leq X\\leq 10^5\n\n1\\leq C_i \\leq 10^5\n\n0\\leq A_{i, j} \\leq 10^5\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M X\nC_1 A_{1,1} A_{1,2} \\cdots A_{1,M}\nC_2 A_{2,1} A_{2,2} \\cdots A_{2,M}\n\\vdots\nC_N A_{N,1} A_{N,2} \\cdots A_{N,M}\n\nOutput\n\nIf the objective is not achievable, print -1; otherwise, print the minimum amount of money needed to achieve it.\n\nSample Input 1\n\n3 3 10\n60 2 2 4\n70 8 7 9\n50 2 3 9\n\nSample Output 1\n\n120\n\nBuying the second and third books makes his understanding levels of all the algorithms 10 or higher, at the minimum cost possible.\n\nSample Input 2\n\n3 3 10\n100 3 1 4\n100 1 5 9\n100 2 6 5\n\nSample Output 2\n\n-1\n\nBuying all the books is still not enough to make his understanding levels of all the algorithms 10 or higher.\n\nSample Input 3\n\n8 5 22\n100 3 7 5 3 1\n164 4 5 2 7 8\n334 7 2 7 2 9\n234 4 7 2 8 2\n541 5 4 3 3 6\n235 4 8 6 9 7\n394 3 6 1 6 2\n872 8 4 3 7 2\n\nSample Output 3\n\n1067", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1212, "cpu_time_ms": 4, "memory_kb": 3544}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s143941947", "group_id": "codeNet:p02683", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n\n#define fast_io ios_base::sync_with_stdio(false); cin.tie(nullptr)\n#define rep(i, x, y) for(decltype(y) i = (x) - ((x) > (y)); i != (y) - ((x) > (y)); i += 1 - 2 * ((x) > (y)))\n#define trav(i,a) for(auto& (i) : (a))\n#define all(a) (a).begin(),(a).end()\n#define sz(a) int((a).size())\n#define clr(a,x) memset((a),(x),sizeof(a)) // array (0,-1)\n#define dbg(x) cerr << \"STDERR => \" << __LINE__ << \": \" << #x << \" = \" << (x) << \"  :(\\n\";\n#define pb push_back\n#define mp make_pair\nmt19937 rng(chrono::steady_clock::now().time_since_epoch().count());\ninline void cpuTime() { cerr << \"cpu time : \" << double(clock())/CLOCKS_PER_SEC << \"\\n\"; return; }\nusing ll = long long;\nusing ull = unsigned long long;\nusing F = float;\nusing D = double;\nusing vi = vector<int>;\nusing pii = pair<int,int>;\n\n\n\nvoid solve(){\n\n    int n, m, x;\n    cin >> n >> m >> x;\n\n    vector<vi> c(n, vi(m+1, 0));\n    rep(i,0,n){\n        rep(j,0,m+1){\n            cin >> c[i][j];\n        }\n    }\n\n\n    vector<bool> a(n,0), b(n,0);\n    ll cost = 0, ans = LLONG_MAX;\n    vi sum(m, 0);\n\n    rep(i,0,n){\n        a[n-1-i] = 1;\n        b = a;\n\n        do{\n            rep(j,0,m) sum[j] = 0;\n            cost = 0;\n            rep(j,0,n){\n                if(b[j]){\n                    cost += c[j][0];\n                    rep(k,0,m){\n                        sum[k] += c[j][k+1];\n                    }\n                }\n            }\n\n            rep(k,0,m){\n                if(sum[k] < x) break;\n                if(k==(m-1)) ans = min(ans, cost);\n            }\n        }while(next_permutation(all(b)));\n    }\n\n    if(ans==LLONG_MAX) cout << \"-1\\n\";\n    else cout << ans << \"\\n\";\n\n    return;\n}\n\n/*\n read the question carefully ( what're the exact constraints? )\n look out for SPECIAL CASES (n=1?) and OVERFLOW (ll vs int?) ARRAY OUT OF BOUNDS\n Check datatypes\n*/\nint main(){\n\n    fast_io;\n    int t=1;\n    // cin >> t;\n\n    while(t--){\n        solve();\n    }\n\n    cpuTime();\nreturn 0;\n}\n", "language": "C++", "metadata": {"date": 1589160833, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02683.html", "problem_id": "p02683", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02683/input.txt", "sample_output_relpath": "derived/input_output/data/p02683/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02683/C++/s143941947.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s143941947", "user_id": "u153767929"}, "prompt_components": {"gold_output": "120\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n\n#define fast_io ios_base::sync_with_stdio(false); cin.tie(nullptr)\n#define rep(i, x, y) for(decltype(y) i = (x) - ((x) > (y)); i != (y) - ((x) > (y)); i += 1 - 2 * ((x) > (y)))\n#define trav(i,a) for(auto& (i) : (a))\n#define all(a) (a).begin(),(a).end()\n#define sz(a) int((a).size())\n#define clr(a,x) memset((a),(x),sizeof(a)) // array (0,-1)\n#define dbg(x) cerr << \"STDERR => \" << __LINE__ << \": \" << #x << \" = \" << (x) << \"  :(\\n\";\n#define pb push_back\n#define mp make_pair\nmt19937 rng(chrono::steady_clock::now().time_since_epoch().count());\ninline void cpuTime() { cerr << \"cpu time : \" << double(clock())/CLOCKS_PER_SEC << \"\\n\"; return; }\nusing ll = long long;\nusing ull = unsigned long long;\nusing F = float;\nusing D = double;\nusing vi = vector<int>;\nusing pii = pair<int,int>;\n\n\n\nvoid solve(){\n\n    int n, m, x;\n    cin >> n >> m >> x;\n\n    vector<vi> c(n, vi(m+1, 0));\n    rep(i,0,n){\n        rep(j,0,m+1){\n            cin >> c[i][j];\n        }\n    }\n\n\n    vector<bool> a(n,0), b(n,0);\n    ll cost = 0, ans = LLONG_MAX;\n    vi sum(m, 0);\n\n    rep(i,0,n){\n        a[n-1-i] = 1;\n        b = a;\n\n        do{\n            rep(j,0,m) sum[j] = 0;\n            cost = 0;\n            rep(j,0,n){\n                if(b[j]){\n                    cost += c[j][0];\n                    rep(k,0,m){\n                        sum[k] += c[j][k+1];\n                    }\n                }\n            }\n\n            rep(k,0,m){\n                if(sum[k] < x) break;\n                if(k==(m-1)) ans = min(ans, cost);\n            }\n        }while(next_permutation(all(b)));\n    }\n\n    if(ans==LLONG_MAX) cout << \"-1\\n\";\n    else cout << ans << \"\\n\";\n\n    return;\n}\n\n/*\n read the question carefully ( what're the exact constraints? )\n look out for SPECIAL CASES (n=1?) and OVERFLOW (ll vs int?) ARRAY OUT OF BOUNDS\n Check datatypes\n*/\nint main(){\n\n    fast_io;\n    int t=1;\n    // cin >> t;\n\n    while(t--){\n        solve();\n    }\n\n    cpuTime();\nreturn 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem\n\nTakahashi, who is a novice in competitive programming, wants to learn M algorithms.\nInitially, his understanding level of each of the M algorithms is 0.\n\nTakahashi is visiting a bookstore, where he finds N books on algorithms.\nThe i-th book (1\\leq i\\leq N) is sold for C_i yen (the currency of Japan). If he buys and reads it, his understanding level of the j-th algorithm will increase by A_{i,j} for each j (1\\leq j\\leq M).\nThere is no other way to increase the understanding levels of the algorithms.\n\nTakahashi's objective is to make his understanding levels of all the M algorithms X or higher. Determine whether this objective is achievable. If it is achievable, find the minimum amount of money needed to achieve it.\n\nConstraints\n\nAll values in input are integers.\n\n1\\leq N, M\\leq 12\n\n1\\leq X\\leq 10^5\n\n1\\leq C_i \\leq 10^5\n\n0\\leq A_{i, j} \\leq 10^5\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M X\nC_1 A_{1,1} A_{1,2} \\cdots A_{1,M}\nC_2 A_{2,1} A_{2,2} \\cdots A_{2,M}\n\\vdots\nC_N A_{N,1} A_{N,2} \\cdots A_{N,M}\n\nOutput\n\nIf the objective is not achievable, print -1; otherwise, print the minimum amount of money needed to achieve it.\n\nSample Input 1\n\n3 3 10\n60 2 2 4\n70 8 7 9\n50 2 3 9\n\nSample Output 1\n\n120\n\nBuying the second and third books makes his understanding levels of all the algorithms 10 or higher, at the minimum cost possible.\n\nSample Input 2\n\n3 3 10\n100 3 1 4\n100 1 5 9\n100 2 6 5\n\nSample Output 2\n\n-1\n\nBuying all the books is still not enough to make his understanding levels of all the algorithms 10 or higher.\n\nSample Input 3\n\n8 5 22\n100 3 7 5 3 1\n164 4 5 2 7 8\n334 7 2 7 2 9\n234 4 7 2 8 2\n541 5 4 3 3 6\n235 4 8 6 9 7\n394 3 6 1 6 2\n872 8 4 3 7 2\n\nSample Output 3\n\n1067", "sample_input": "3 3 10\n60 2 2 4\n70 8 7 9\n50 2 3 9\n"}, "reference_outputs": ["120\n"], "source_document_id": "p02683", "source_text": "Score : 300 points\n\nProblem\n\nTakahashi, who is a novice in competitive programming, wants to learn M algorithms.\nInitially, his understanding level of each of the M algorithms is 0.\n\nTakahashi is visiting a bookstore, where he finds N books on algorithms.\nThe i-th book (1\\leq i\\leq N) is sold for C_i yen (the currency of Japan). If he buys and reads it, his understanding level of the j-th algorithm will increase by A_{i,j} for each j (1\\leq j\\leq M).\nThere is no other way to increase the understanding levels of the algorithms.\n\nTakahashi's objective is to make his understanding levels of all the M algorithms X or higher. Determine whether this objective is achievable. If it is achievable, find the minimum amount of money needed to achieve it.\n\nConstraints\n\nAll values in input are integers.\n\n1\\leq N, M\\leq 12\n\n1\\leq X\\leq 10^5\n\n1\\leq C_i \\leq 10^5\n\n0\\leq A_{i, j} \\leq 10^5\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M X\nC_1 A_{1,1} A_{1,2} \\cdots A_{1,M}\nC_2 A_{2,1} A_{2,2} \\cdots A_{2,M}\n\\vdots\nC_N A_{N,1} A_{N,2} \\cdots A_{N,M}\n\nOutput\n\nIf the objective is not achievable, print -1; otherwise, print the minimum amount of money needed to achieve it.\n\nSample Input 1\n\n3 3 10\n60 2 2 4\n70 8 7 9\n50 2 3 9\n\nSample Output 1\n\n120\n\nBuying the second and third books makes his understanding levels of all the algorithms 10 or higher, at the minimum cost possible.\n\nSample Input 2\n\n3 3 10\n100 3 1 4\n100 1 5 9\n100 2 6 5\n\nSample Output 2\n\n-1\n\nBuying all the books is still not enough to make his understanding levels of all the algorithms 10 or higher.\n\nSample Input 3\n\n8 5 22\n100 3 7 5 3 1\n164 4 5 2 7 8\n334 7 2 7 2 9\n234 4 7 2 8 2\n541 5 4 3 3 6\n235 4 8 6 9 7\n394 3 6 1 6 2\n872 8 4 3 7 2\n\nSample Output 3\n\n1067", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1987, "cpu_time_ms": 3, "memory_kb": 3852}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s669777914", "group_id": "codeNet:p02683", "input_text": "#include <bits/stdc++.h>\n\n/*==========type============*/\ntypedef long long ll;\ntypedef std::pair<int,int> pii;\ntypedef std::pair<ll,ll> pll;\ntypedef std::pair<std::string,ll> psl;\n\n/*==========constant============*/\n#define INF INT_MAX\n#define INF_L LONG_MAX\n#define INF_LL LLONG_MAX\n#define MOD 1000000007\n\n/*==========function============*/\n#define REP(ii,jj,nn) for (ll ii=jj;ii<(nn);ii++)\n#define RREP(ii,nn,jj) for (ll ii = nn; jj<ii;ii--)\n#define each(i,...) for (auto&& i:__VA_ARGS__)\n#define ALL(vec) (vec).begin(),(vec).end()\n#define sum(...) accumulate(ALL(__VA_ARGS__),0LL)\n#define dsum(...) accumulate(ALL(__VA_ARGS__),0.0)\n#define vec(type,name,...) vector<type> name(__VA_ARGS__)\ntemplate<class T> inline auto max(const T& a){ return *max_element(ALL(a)); }\ntemplate<class T> inline auto min(const T& a){ return *min_element(ALL(a)); }\ninline ll gcd(ll a,ll b){if(b == 0) return a;return  gcd(b,a%b);}\ninline ll lcm(ll a,ll b){ll g = gcd(a,b);return a / g * b;}\n\nusing namespace std;\n\nll n,m,x;\nvector<ll> c(12);\nvector<ll> a[12];\n\nbool eval(vector<ll> aa){\n    REP(i,0,aa.size()){\n        if(aa[i] < x)return false;\n    }\n    return true;\n}\n\nll dfs(ll index, ll cost,vector<ll>& aa){\n    if(eval(aa))return cost;\n    if(index >= n)return INF;\n\n    ll ret = INF;\n    \n    vector<ll> aaa = aa;\n    REP(i,0,aaa.size())aaa[i] += a[index][i];\n    ret = min(ret,dfs(index+1,cost+c[index],aaa));\n\n    ret = min(ret,dfs(index+1,cost,aa));\n\n    return ret;\n}\n\nint main(void){\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n\n    cin >> n >> m >> x;\n    REP(i,0,n){\n        cin >> c[i];\n        REP(j,0,m){\n            ll aa;\n            cin >> aa;\n            a[i].push_back(aa);\n        }\n    }\n    \n    vector<ll> aaa(m,0);\n    ll ans = dfs(0,0,aaa);\n    if(ans == INF)ans = -1;\n    \n    cout << ans << endl;\n\n    return 0;\n}    ", "language": "C++", "metadata": {"date": 1589160340, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02683.html", "problem_id": "p02683", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02683/input.txt", "sample_output_relpath": "derived/input_output/data/p02683/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02683/C++/s669777914.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s669777914", "user_id": "u855087874"}, "prompt_components": {"gold_output": "120\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\n/*==========type============*/\ntypedef long long ll;\ntypedef std::pair<int,int> pii;\ntypedef std::pair<ll,ll> pll;\ntypedef std::pair<std::string,ll> psl;\n\n/*==========constant============*/\n#define INF INT_MAX\n#define INF_L LONG_MAX\n#define INF_LL LLONG_MAX\n#define MOD 1000000007\n\n/*==========function============*/\n#define REP(ii,jj,nn) for (ll ii=jj;ii<(nn);ii++)\n#define RREP(ii,nn,jj) for (ll ii = nn; jj<ii;ii--)\n#define each(i,...) for (auto&& i:__VA_ARGS__)\n#define ALL(vec) (vec).begin(),(vec).end()\n#define sum(...) accumulate(ALL(__VA_ARGS__),0LL)\n#define dsum(...) accumulate(ALL(__VA_ARGS__),0.0)\n#define vec(type,name,...) vector<type> name(__VA_ARGS__)\ntemplate<class T> inline auto max(const T& a){ return *max_element(ALL(a)); }\ntemplate<class T> inline auto min(const T& a){ return *min_element(ALL(a)); }\ninline ll gcd(ll a,ll b){if(b == 0) return a;return  gcd(b,a%b);}\ninline ll lcm(ll a,ll b){ll g = gcd(a,b);return a / g * b;}\n\nusing namespace std;\n\nll n,m,x;\nvector<ll> c(12);\nvector<ll> a[12];\n\nbool eval(vector<ll> aa){\n    REP(i,0,aa.size()){\n        if(aa[i] < x)return false;\n    }\n    return true;\n}\n\nll dfs(ll index, ll cost,vector<ll>& aa){\n    if(eval(aa))return cost;\n    if(index >= n)return INF;\n\n    ll ret = INF;\n    \n    vector<ll> aaa = aa;\n    REP(i,0,aaa.size())aaa[i] += a[index][i];\n    ret = min(ret,dfs(index+1,cost+c[index],aaa));\n\n    ret = min(ret,dfs(index+1,cost,aa));\n\n    return ret;\n}\n\nint main(void){\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n\n    cin >> n >> m >> x;\n    REP(i,0,n){\n        cin >> c[i];\n        REP(j,0,m){\n            ll aa;\n            cin >> aa;\n            a[i].push_back(aa);\n        }\n    }\n    \n    vector<ll> aaa(m,0);\n    ll ans = dfs(0,0,aaa);\n    if(ans == INF)ans = -1;\n    \n    cout << ans << endl;\n\n    return 0;\n}    ", "problem_context": "Score : 300 points\n\nProblem\n\nTakahashi, who is a novice in competitive programming, wants to learn M algorithms.\nInitially, his understanding level of each of the M algorithms is 0.\n\nTakahashi is visiting a bookstore, where he finds N books on algorithms.\nThe i-th book (1\\leq i\\leq N) is sold for C_i yen (the currency of Japan). If he buys and reads it, his understanding level of the j-th algorithm will increase by A_{i,j} for each j (1\\leq j\\leq M).\nThere is no other way to increase the understanding levels of the algorithms.\n\nTakahashi's objective is to make his understanding levels of all the M algorithms X or higher. Determine whether this objective is achievable. If it is achievable, find the minimum amount of money needed to achieve it.\n\nConstraints\n\nAll values in input are integers.\n\n1\\leq N, M\\leq 12\n\n1\\leq X\\leq 10^5\n\n1\\leq C_i \\leq 10^5\n\n0\\leq A_{i, j} \\leq 10^5\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M X\nC_1 A_{1,1} A_{1,2} \\cdots A_{1,M}\nC_2 A_{2,1} A_{2,2} \\cdots A_{2,M}\n\\vdots\nC_N A_{N,1} A_{N,2} \\cdots A_{N,M}\n\nOutput\n\nIf the objective is not achievable, print -1; otherwise, print the minimum amount of money needed to achieve it.\n\nSample Input 1\n\n3 3 10\n60 2 2 4\n70 8 7 9\n50 2 3 9\n\nSample Output 1\n\n120\n\nBuying the second and third books makes his understanding levels of all the algorithms 10 or higher, at the minimum cost possible.\n\nSample Input 2\n\n3 3 10\n100 3 1 4\n100 1 5 9\n100 2 6 5\n\nSample Output 2\n\n-1\n\nBuying all the books is still not enough to make his understanding levels of all the algorithms 10 or higher.\n\nSample Input 3\n\n8 5 22\n100 3 7 5 3 1\n164 4 5 2 7 8\n334 7 2 7 2 9\n234 4 7 2 8 2\n541 5 4 3 3 6\n235 4 8 6 9 7\n394 3 6 1 6 2\n872 8 4 3 7 2\n\nSample Output 3\n\n1067", "sample_input": "3 3 10\n60 2 2 4\n70 8 7 9\n50 2 3 9\n"}, "reference_outputs": ["120\n"], "source_document_id": "p02683", "source_text": "Score : 300 points\n\nProblem\n\nTakahashi, who is a novice in competitive programming, wants to learn M algorithms.\nInitially, his understanding level of each of the M algorithms is 0.\n\nTakahashi is visiting a bookstore, where he finds N books on algorithms.\nThe i-th book (1\\leq i\\leq N) is sold for C_i yen (the currency of Japan). If he buys and reads it, his understanding level of the j-th algorithm will increase by A_{i,j} for each j (1\\leq j\\leq M).\nThere is no other way to increase the understanding levels of the algorithms.\n\nTakahashi's objective is to make his understanding levels of all the M algorithms X or higher. Determine whether this objective is achievable. If it is achievable, find the minimum amount of money needed to achieve it.\n\nConstraints\n\nAll values in input are integers.\n\n1\\leq N, M\\leq 12\n\n1\\leq X\\leq 10^5\n\n1\\leq C_i \\leq 10^5\n\n0\\leq A_{i, j} \\leq 10^5\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M X\nC_1 A_{1,1} A_{1,2} \\cdots A_{1,M}\nC_2 A_{2,1} A_{2,2} \\cdots A_{2,M}\n\\vdots\nC_N A_{N,1} A_{N,2} \\cdots A_{N,M}\n\nOutput\n\nIf the objective is not achievable, print -1; otherwise, print the minimum amount of money needed to achieve it.\n\nSample Input 1\n\n3 3 10\n60 2 2 4\n70 8 7 9\n50 2 3 9\n\nSample Output 1\n\n120\n\nBuying the second and third books makes his understanding levels of all the algorithms 10 or higher, at the minimum cost possible.\n\nSample Input 2\n\n3 3 10\n100 3 1 4\n100 1 5 9\n100 2 6 5\n\nSample Output 2\n\n-1\n\nBuying all the books is still not enough to make his understanding levels of all the algorithms 10 or higher.\n\nSample Input 3\n\n8 5 22\n100 3 7 5 3 1\n164 4 5 2 7 8\n334 7 2 7 2 9\n234 4 7 2 8 2\n541 5 4 3 3 6\n235 4 8 6 9 7\n394 3 6 1 6 2\n872 8 4 3 7 2\n\nSample Output 3\n\n1067", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1838, "cpu_time_ms": 5, "memory_kb": 3664}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s913111433", "group_id": "codeNet:p02687", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n  string S;\n  cin >> S;\n  \n  if(S == \"ABC\") cout << \"ARC\" << endl;\n  else cout << \"ABC\" << endl;\n  \n  return 0;\n}", "language": "C++", "metadata": {"date": 1588554455, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02687.html", "problem_id": "p02687", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02687/input.txt", "sample_output_relpath": "derived/input_output/data/p02687/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02687/C++/s913111433.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s913111433", "user_id": "u750541753"}, "prompt_components": {"gold_output": "ARC\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n  string S;\n  cin >> S;\n  \n  if(S == \"ABC\") cout << \"ARC\" << endl;\n  else cout << \"ABC\" << endl;\n  \n  return 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nAtCoder Inc. holds a contest every Saturday.\n\nThere are two types of contests called ABC and ARC, and just one of them is held at a time.\n\nThe company holds these two types of contests alternately: an ARC follows an ABC and vice versa.\n\nGiven a string S representing the type of the contest held last week, print the string representing the type of the contest held this week.\n\nConstraints\n\nS is ABC or ARC.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the string representing the type of the contest held this week.\n\nSample Input 1\n\nABC\n\nSample Output 1\n\nARC\n\nThey held an ABC last week, so they will hold an ARC this week.", "sample_input": "ABC\n"}, "reference_outputs": ["ARC\n"], "source_document_id": "p02687", "source_text": "Score : 100 points\n\nProblem Statement\n\nAtCoder Inc. holds a contest every Saturday.\n\nThere are two types of contests called ABC and ARC, and just one of them is held at a time.\n\nThe company holds these two types of contests alternately: an ARC follows an ABC and vice versa.\n\nGiven a string S representing the type of the contest held last week, print the string representing the type of the contest held this week.\n\nConstraints\n\nS is ABC or ARC.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the string representing the type of the contest held this week.\n\nSample Input 1\n\nABC\n\nSample Output 1\n\nARC\n\nThey held an ABC last week, so they will hold an ARC this week.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 170, "cpu_time_ms": 2, "memory_kb": 3624}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s545682789", "group_id": "codeNet:p02688", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n    int a,b,c;\n    cin>>a>>b;\n    vector<int>m(a+1,0);\n    m[0]=1;\n    for(int i=0; i<b; i++)\n    {\n        cin>>c;\n        vector<int>n(c);\n        for(int j=0; j<c; j++)\n        {\n            cin>>n[i];\n            m[n[i]]++;\n        }\n    }\n    int p=0;\n    for(int k=0; k<a+1; k++)\n    {\n        if(m[k]==0)\n            p++;\n    }\n    cout<<p<<endl;\n}\n", "language": "C++", "metadata": {"date": 1592286826, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02688.html", "problem_id": "p02688", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02688/input.txt", "sample_output_relpath": "derived/input_output/data/p02688/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02688/C++/s545682789.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s545682789", "user_id": "u210555114"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n    int a,b,c;\n    cin>>a>>b;\n    vector<int>m(a+1,0);\n    m[0]=1;\n    for(int i=0; i<b; i++)\n    {\n        cin>>c;\n        vector<int>n(c);\n        for(int j=0; j<c; j++)\n        {\n            cin>>n[i];\n            m[n[i]]++;\n        }\n    }\n    int p=0;\n    for(int k=0; k<a+1; k++)\n    {\n        if(m[k]==0)\n            p++;\n    }\n    cout<<p<<endl;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nN Snukes called Snuke 1, Snuke 2, ..., Snuke N live in a town.\n\nThere are K kinds of snacks sold in this town, called Snack 1, Snack 2, ..., Snack K. The following d_i Snukes have Snack i: Snuke A_{i, 1}, A_{i, 2}, \\cdots, A_{i, {d_i}}.\n\nTakahashi will walk around this town and make mischief on the Snukes who have no snacks. How many Snukes will fall victim to Takahashi's mischief?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 100\n\n1 \\leq K \\leq 100\n\n1 \\leq d_i \\leq N\n\n1 \\leq A_{i, 1} < \\cdots < A_{i, d_i} \\leq N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nd_1\nA_{1, 1} \\cdots A_{1, d_1}\n\\vdots\nd_K\nA_{K, 1} \\cdots A_{K, d_K}\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n3 2\n2\n1 3\n1\n3\n\nSample Output 1\n\n1\n\nSnuke 1 has Snack 1.\n\nSnuke 2 has no snacks.\n\nSnuke 3 has Snack 1 and 2.\n\nThus, there will be one victim: Snuke 2.\n\nSample Input 2\n\n3 3\n1\n3\n1\n3\n1\n3\n\nSample Output 2\n\n2", "sample_input": "3 2\n2\n1 3\n1\n3\n"}, "reference_outputs": ["1\n"], "source_document_id": "p02688", "source_text": "Score : 200 points\n\nProblem Statement\n\nN Snukes called Snuke 1, Snuke 2, ..., Snuke N live in a town.\n\nThere are K kinds of snacks sold in this town, called Snack 1, Snack 2, ..., Snack K. The following d_i Snukes have Snack i: Snuke A_{i, 1}, A_{i, 2}, \\cdots, A_{i, {d_i}}.\n\nTakahashi will walk around this town and make mischief on the Snukes who have no snacks. How many Snukes will fall victim to Takahashi's mischief?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 100\n\n1 \\leq K \\leq 100\n\n1 \\leq d_i \\leq N\n\n1 \\leq A_{i, 1} < \\cdots < A_{i, d_i} \\leq N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nd_1\nA_{1, 1} \\cdots A_{1, d_1}\n\\vdots\nd_K\nA_{K, 1} \\cdots A_{K, d_K}\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n3 2\n2\n1 3\n1\n3\n\nSample Output 1\n\n1\n\nSnuke 1 has Snack 1.\n\nSnuke 2 has no snacks.\n\nSnuke 3 has Snack 1 and 2.\n\nThus, there will be one victim: Snuke 2.\n\nSample Input 2\n\n3 3\n1\n3\n1\n3\n1\n3\n\nSample Output 2\n\n2", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 414, "cpu_time_ms": 111, "memory_kb": 3628}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s151986949", "group_id": "codeNet:p02688", "input_text": "#define dbg(...) \"amit_dwivedi\"\n#define db(...)  \"Too OP\"\n#include \"bits/stdc++.h\"        \nusing namespace std;using ll=long long;\nll n,m,L,R;\nconst int mod = 1e9+7;\n\nvoid sol(){\n    int n,k;\n    cin>>n>>k;\n    bool snuke[n+1] = {0};\n    for(int i = 0,temp; i <k;i++){\n        cin>>temp;\n        for(int j=0,l; j<temp; j++) {\n            cin>>l;\n            snuke[l] = true;\n        }\n    }\n    int ans = 0;\n    for(int i=1; i<=n; i++) {\n        ans += (!snuke[i]);\n    }\n    cout << ans << endl;\n\n}\nint main(){\n    ios_base::sync_with_stdio(false);cin.tie(nullptr);\n    // int t;cin>>t;while(t--)\n    sol();\n}\n ", "language": "C++", "metadata": {"date": 1588595350, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02688.html", "problem_id": "p02688", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02688/input.txt", "sample_output_relpath": "derived/input_output/data/p02688/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02688/C++/s151986949.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s151986949", "user_id": "u256710795"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#define dbg(...) \"amit_dwivedi\"\n#define db(...)  \"Too OP\"\n#include \"bits/stdc++.h\"        \nusing namespace std;using ll=long long;\nll n,m,L,R;\nconst int mod = 1e9+7;\n\nvoid sol(){\n    int n,k;\n    cin>>n>>k;\n    bool snuke[n+1] = {0};\n    for(int i = 0,temp; i <k;i++){\n        cin>>temp;\n        for(int j=0,l; j<temp; j++) {\n            cin>>l;\n            snuke[l] = true;\n        }\n    }\n    int ans = 0;\n    for(int i=1; i<=n; i++) {\n        ans += (!snuke[i]);\n    }\n    cout << ans << endl;\n\n}\nint main(){\n    ios_base::sync_with_stdio(false);cin.tie(nullptr);\n    // int t;cin>>t;while(t--)\n    sol();\n}\n ", "problem_context": "Score : 200 points\n\nProblem Statement\n\nN Snukes called Snuke 1, Snuke 2, ..., Snuke N live in a town.\n\nThere are K kinds of snacks sold in this town, called Snack 1, Snack 2, ..., Snack K. The following d_i Snukes have Snack i: Snuke A_{i, 1}, A_{i, 2}, \\cdots, A_{i, {d_i}}.\n\nTakahashi will walk around this town and make mischief on the Snukes who have no snacks. How many Snukes will fall victim to Takahashi's mischief?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 100\n\n1 \\leq K \\leq 100\n\n1 \\leq d_i \\leq N\n\n1 \\leq A_{i, 1} < \\cdots < A_{i, d_i} \\leq N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nd_1\nA_{1, 1} \\cdots A_{1, d_1}\n\\vdots\nd_K\nA_{K, 1} \\cdots A_{K, d_K}\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n3 2\n2\n1 3\n1\n3\n\nSample Output 1\n\n1\n\nSnuke 1 has Snack 1.\n\nSnuke 2 has no snacks.\n\nSnuke 3 has Snack 1 and 2.\n\nThus, there will be one victim: Snuke 2.\n\nSample Input 2\n\n3 3\n1\n3\n1\n3\n1\n3\n\nSample Output 2\n\n2", "sample_input": "3 2\n2\n1 3\n1\n3\n"}, "reference_outputs": ["1\n"], "source_document_id": "p02688", "source_text": "Score : 200 points\n\nProblem Statement\n\nN Snukes called Snuke 1, Snuke 2, ..., Snuke N live in a town.\n\nThere are K kinds of snacks sold in this town, called Snack 1, Snack 2, ..., Snack K. The following d_i Snukes have Snack i: Snuke A_{i, 1}, A_{i, 2}, \\cdots, A_{i, {d_i}}.\n\nTakahashi will walk around this town and make mischief on the Snukes who have no snacks. How many Snukes will fall victim to Takahashi's mischief?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 100\n\n1 \\leq K \\leq 100\n\n1 \\leq d_i \\leq N\n\n1 \\leq A_{i, 1} < \\cdots < A_{i, d_i} \\leq N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nd_1\nA_{1, 1} \\cdots A_{1, d_1}\n\\vdots\nd_K\nA_{K, 1} \\cdots A_{K, d_K}\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n3 2\n2\n1 3\n1\n3\n\nSample Output 1\n\n1\n\nSnuke 1 has Snack 1.\n\nSnuke 2 has no snacks.\n\nSnuke 3 has Snack 1 and 2.\n\nThus, there will be one victim: Snuke 2.\n\nSample Input 2\n\n3 3\n1\n3\n1\n3\n1\n3\n\nSample Output 2\n\n2", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 612, "cpu_time_ms": 3, "memory_kb": 3620}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s590089134", "group_id": "codeNet:p02688", "input_text": "#include<iostream>\n#include<vector>\nusing namespace std;\nint main() {\n\tint n, k, d,numofnusuke,count=0;\n\tcin >> n >> k;\n\tvector<bool> nusuke(n,false);\n\tfor (int i = 0; i < k; i++) {\n\t\tcin >> d;\n\t\tfor (int j = 0; j < d; j++) {\n\t\t\tcin >> numofnusuke;\n\t\t\tnusuke[numofnusuke-1] = true;\n\t\t}\n\t}\n\tfor (int i = 0; i < n; i++) {\n\t\tif (nusuke[i] == false)\n\t\t\tcount++;\n\t}\n\tcout << count;\n}", "language": "C++", "metadata": {"date": 1588557998, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02688.html", "problem_id": "p02688", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02688/input.txt", "sample_output_relpath": "derived/input_output/data/p02688/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02688/C++/s590089134.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s590089134", "user_id": "u417503954"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include<iostream>\n#include<vector>\nusing namespace std;\nint main() {\n\tint n, k, d,numofnusuke,count=0;\n\tcin >> n >> k;\n\tvector<bool> nusuke(n,false);\n\tfor (int i = 0; i < k; i++) {\n\t\tcin >> d;\n\t\tfor (int j = 0; j < d; j++) {\n\t\t\tcin >> numofnusuke;\n\t\t\tnusuke[numofnusuke-1] = true;\n\t\t}\n\t}\n\tfor (int i = 0; i < n; i++) {\n\t\tif (nusuke[i] == false)\n\t\t\tcount++;\n\t}\n\tcout << count;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nN Snukes called Snuke 1, Snuke 2, ..., Snuke N live in a town.\n\nThere are K kinds of snacks sold in this town, called Snack 1, Snack 2, ..., Snack K. The following d_i Snukes have Snack i: Snuke A_{i, 1}, A_{i, 2}, \\cdots, A_{i, {d_i}}.\n\nTakahashi will walk around this town and make mischief on the Snukes who have no snacks. How many Snukes will fall victim to Takahashi's mischief?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 100\n\n1 \\leq K \\leq 100\n\n1 \\leq d_i \\leq N\n\n1 \\leq A_{i, 1} < \\cdots < A_{i, d_i} \\leq N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nd_1\nA_{1, 1} \\cdots A_{1, d_1}\n\\vdots\nd_K\nA_{K, 1} \\cdots A_{K, d_K}\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n3 2\n2\n1 3\n1\n3\n\nSample Output 1\n\n1\n\nSnuke 1 has Snack 1.\n\nSnuke 2 has no snacks.\n\nSnuke 3 has Snack 1 and 2.\n\nThus, there will be one victim: Snuke 2.\n\nSample Input 2\n\n3 3\n1\n3\n1\n3\n1\n3\n\nSample Output 2\n\n2", "sample_input": "3 2\n2\n1 3\n1\n3\n"}, "reference_outputs": ["1\n"], "source_document_id": "p02688", "source_text": "Score : 200 points\n\nProblem Statement\n\nN Snukes called Snuke 1, Snuke 2, ..., Snuke N live in a town.\n\nThere are K kinds of snacks sold in this town, called Snack 1, Snack 2, ..., Snack K. The following d_i Snukes have Snack i: Snuke A_{i, 1}, A_{i, 2}, \\cdots, A_{i, {d_i}}.\n\nTakahashi will walk around this town and make mischief on the Snukes who have no snacks. How many Snukes will fall victim to Takahashi's mischief?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 100\n\n1 \\leq K \\leq 100\n\n1 \\leq d_i \\leq N\n\n1 \\leq A_{i, 1} < \\cdots < A_{i, d_i} \\leq N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nd_1\nA_{1, 1} \\cdots A_{1, d_1}\n\\vdots\nd_K\nA_{K, 1} \\cdots A_{K, d_K}\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n3 2\n2\n1 3\n1\n3\n\nSample Output 1\n\n1\n\nSnuke 1 has Snack 1.\n\nSnuke 2 has no snacks.\n\nSnuke 3 has Snack 1 and 2.\n\nThus, there will be one victim: Snuke 2.\n\nSample Input 2\n\n3 3\n1\n3\n1\n3\n1\n3\n\nSample Output 2\n\n2", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 378, "cpu_time_ms": 4, "memory_kb": 3584}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s229179027", "group_id": "codeNet:p02689", "input_text": "#include <iostream>\n#include <vector>\n#include <map>\n#include <string>\n#include <algorithm>\nusing namespace std;\n\n\nint main(){\n    int N,M;\n    cin >> N >> M;\n\n    vector<int> H(N,0);\n    for(int i=0;i<N;i++) cin >> H[i];\n\n    int A,B;\n    vector<int> bad(N,0);\n    for(int i=0;i<M;i++){\n        cin >> A >> B;\n        if(H[A-1]<=H[B-1]){\n            bad[A-1] = 1; // 悪である\n        }\n        if(H[A-1]>=H[B-1]){\n            bad[B-1] = 1; // 悪である\n        }\n    }\n\n    int count=0;\n    for(int i=0;i<N;i++){\n        if(bad[i]==0){\n            count++;\n        }\n    }\n\n    cout << count << endl;\n\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1588555181, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02689.html", "problem_id": "p02689", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02689/input.txt", "sample_output_relpath": "derived/input_output/data/p02689/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02689/C++/s229179027.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s229179027", "user_id": "u658096542"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\n#include <map>\n#include <string>\n#include <algorithm>\nusing namespace std;\n\n\nint main(){\n    int N,M;\n    cin >> N >> M;\n\n    vector<int> H(N,0);\n    for(int i=0;i<N;i++) cin >> H[i];\n\n    int A,B;\n    vector<int> bad(N,0);\n    for(int i=0;i<M;i++){\n        cin >> A >> B;\n        if(H[A-1]<=H[B-1]){\n            bad[A-1] = 1; // 悪である\n        }\n        if(H[A-1]>=H[B-1]){\n            bad[B-1] = 1; // 悪である\n        }\n    }\n\n    int count=0;\n    for(int i=0;i<N;i++){\n        if(bad[i]==0){\n            count++;\n        }\n    }\n\n    cout << count << endl;\n\n    return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N observatories in AtCoder Hill, called Obs. 1, Obs. 2, ..., Obs. N. The elevation of Obs. i is H_i.\nThere are also M roads, each connecting two different observatories. Road j connects Obs. A_j and Obs. B_j.\n\nObs. i is said to be good when its elevation is higher than those of all observatories that can be reached from Obs. i using just one road.\nNote that Obs. i is also good when no observatory can be reached from Obs. i using just one road.\n\nHow many good observatories are there?\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq H_i \\leq 10^9\n\n1 \\leq A_i,B_i \\leq N\n\nA_i \\neq B_i\n\nMultiple roads may connect the same pair of observatories.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nH_1 H_2 ... H_N\nA_1 B_1\nA_2 B_2\n:\nA_M B_M\n\nOutput\n\nPrint the number of good observatories.\n\nSample Input 1\n\n4 3\n1 2 3 4\n1 3\n2 3\n2 4\n\nSample Output 1\n\n2\n\nFrom Obs. 1, you can reach Obs. 3 using just one road. The elevation of Obs. 1 is not higher than that of Obs. 3, so Obs. 1 is not good.\n\nFrom Obs. 2, you can reach Obs. 3 and 4 using just one road. The elevation of Obs. 2 is not higher than that of Obs. 3, so Obs. 2 is not good.\n\nFrom Obs. 3, you can reach Obs. 1 and 2 using just one road. The elevation of Obs. 3 is higher than those of Obs. 1 and 2, so Obs. 3 is good.\n\nFrom Obs. 4, you can reach Obs. 2 using just one road. The elevation of Obs. 4 is higher than that of Obs. 2, so Obs. 4 is good.\n\nThus, the good observatories are Obs. 3 and 4, so there are two good observatories.\n\nSample Input 2\n\n6 5\n8 6 9 1 2 1\n1 3\n4 2\n4 3\n4 6\n4 6\n\nSample Output 2\n\n3", "sample_input": "4 3\n1 2 3 4\n1 3\n2 3\n2 4\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02689", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N observatories in AtCoder Hill, called Obs. 1, Obs. 2, ..., Obs. N. The elevation of Obs. i is H_i.\nThere are also M roads, each connecting two different observatories. Road j connects Obs. A_j and Obs. B_j.\n\nObs. i is said to be good when its elevation is higher than those of all observatories that can be reached from Obs. i using just one road.\nNote that Obs. i is also good when no observatory can be reached from Obs. i using just one road.\n\nHow many good observatories are there?\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq H_i \\leq 10^9\n\n1 \\leq A_i,B_i \\leq N\n\nA_i \\neq B_i\n\nMultiple roads may connect the same pair of observatories.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nH_1 H_2 ... H_N\nA_1 B_1\nA_2 B_2\n:\nA_M B_M\n\nOutput\n\nPrint the number of good observatories.\n\nSample Input 1\n\n4 3\n1 2 3 4\n1 3\n2 3\n2 4\n\nSample Output 1\n\n2\n\nFrom Obs. 1, you can reach Obs. 3 using just one road. The elevation of Obs. 1 is not higher than that of Obs. 3, so Obs. 1 is not good.\n\nFrom Obs. 2, you can reach Obs. 3 and 4 using just one road. The elevation of Obs. 2 is not higher than that of Obs. 3, so Obs. 2 is not good.\n\nFrom Obs. 3, you can reach Obs. 1 and 2 using just one road. The elevation of Obs. 3 is higher than those of Obs. 1 and 2, so Obs. 3 is good.\n\nFrom Obs. 4, you can reach Obs. 2 using just one road. The elevation of Obs. 4 is higher than that of Obs. 2, so Obs. 4 is good.\n\nThus, the good observatories are Obs. 3 and 4, so there are two good observatories.\n\nSample Input 2\n\n6 5\n8 6 9 1 2 1\n1 3\n4 2\n4 3\n4 6\n4 6\n\nSample Output 2\n\n3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 626, "cpu_time_ms": 78, "memory_kb": 4048}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s225706917", "group_id": "codeNet:p02689", "input_text": "/**\n * Dont raise your voice, improve your argument.\n * --Desmond Tutu\n */\n\n#include <bits/stdc++.h>\nusing namespace std;\n\nvector<string> vec_splitter(string s) {\n    for(char& c: s) c = c == ','?  ' ': c;\n    stringstream ss; ss << s;\n    vector<string> res;\n    for(string z; ss >> z; res.push_back(z));\n    return res;\n}\n\nvoid debug_out(vector<string> __attribute__ ((unused)) args, __attribute__ ((unused)) int idx) { cerr << endl; }\ntemplate <typename Head, typename... Tail>\nvoid debug_out(vector<string> args, int idx, Head H, Tail... T) {\n    if(idx > 0) cerr << \", \";\n    stringstream ss; ss << H;\n    cerr << args[idx] << \" = \" << ss.str();\n    debug_out(args, idx + 1, T...);\n}\n\n#ifdef XOX\n#define debug(...) debug_out(vec_splitter(#__VA_ARGS__), 0, __VA_ARGS__)\n#else\n#define debug(...) 42\n#endif\n\nconst double PI = acos(-1);\ntypedef long long ll;\n#define int ll\n#define fori(n) for(int i=0; i<int(n); i++)\n\n#define cins(s) string s; cin>>s;\n#define cini(i) int i; cin>>i;\n#define cind(d) double d; cin>>d;\n#define cinai(a, n) vi a(n); fori(n) { cin>>a[i]; }\n#define cinas(s, n) vs s(n); fori(n) { cin>>s[i]; }\n#define cinad(a, n) vd a(n); fori(n) { cin>>a[i]; }\n\ntypedef pair<int, int> pii;\ntypedef pair<double, double> pdd;\ntypedef vector<double> vd;\ntypedef vector<bool> vb;\ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\ntypedef vector<vvi> vvvi;\ntypedef vector<string> vs;\n\nvoid solve() {\n    cini(n);\n    cini(m);\n    cinai(h,n);\n    vvi adj(n);\n    for(int i=0; i<m; i++) {\n        cini(a);\n        cini(b);\n        a--;\n        b--;\n        adj[a].push_back(b);\n        adj[b].push_back(a);\n    }\n\n    vb ans(n, true);\n\n    for(int i=0; i<n; i++) {\n        for(int j : adj[i])\n            if(h[i]<=h[j])\n                ans[i]=false;\n    }\n\n    int cnt=0;\n    for(int i=0; i<n; i++)\n        if(ans[i])\n            cnt++;\n    cout<<cnt<<endl;\n    \n}\n\nsigned main() {\n    cin.tie(nullptr);\n    std::ios::sync_with_stdio(false);\n    solve();\n}\n\n", "language": "C++", "metadata": {"date": 1588554562, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02689.html", "problem_id": "p02689", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02689/input.txt", "sample_output_relpath": "derived/input_output/data/p02689/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02689/C++/s225706917.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s225706917", "user_id": "u014617387"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "/**\n * Dont raise your voice, improve your argument.\n * --Desmond Tutu\n */\n\n#include <bits/stdc++.h>\nusing namespace std;\n\nvector<string> vec_splitter(string s) {\n    for(char& c: s) c = c == ','?  ' ': c;\n    stringstream ss; ss << s;\n    vector<string> res;\n    for(string z; ss >> z; res.push_back(z));\n    return res;\n}\n\nvoid debug_out(vector<string> __attribute__ ((unused)) args, __attribute__ ((unused)) int idx) { cerr << endl; }\ntemplate <typename Head, typename... Tail>\nvoid debug_out(vector<string> args, int idx, Head H, Tail... T) {\n    if(idx > 0) cerr << \", \";\n    stringstream ss; ss << H;\n    cerr << args[idx] << \" = \" << ss.str();\n    debug_out(args, idx + 1, T...);\n}\n\n#ifdef XOX\n#define debug(...) debug_out(vec_splitter(#__VA_ARGS__), 0, __VA_ARGS__)\n#else\n#define debug(...) 42\n#endif\n\nconst double PI = acos(-1);\ntypedef long long ll;\n#define int ll\n#define fori(n) for(int i=0; i<int(n); i++)\n\n#define cins(s) string s; cin>>s;\n#define cini(i) int i; cin>>i;\n#define cind(d) double d; cin>>d;\n#define cinai(a, n) vi a(n); fori(n) { cin>>a[i]; }\n#define cinas(s, n) vs s(n); fori(n) { cin>>s[i]; }\n#define cinad(a, n) vd a(n); fori(n) { cin>>a[i]; }\n\ntypedef pair<int, int> pii;\ntypedef pair<double, double> pdd;\ntypedef vector<double> vd;\ntypedef vector<bool> vb;\ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\ntypedef vector<vvi> vvvi;\ntypedef vector<string> vs;\n\nvoid solve() {\n    cini(n);\n    cini(m);\n    cinai(h,n);\n    vvi adj(n);\n    for(int i=0; i<m; i++) {\n        cini(a);\n        cini(b);\n        a--;\n        b--;\n        adj[a].push_back(b);\n        adj[b].push_back(a);\n    }\n\n    vb ans(n, true);\n\n    for(int i=0; i<n; i++) {\n        for(int j : adj[i])\n            if(h[i]<=h[j])\n                ans[i]=false;\n    }\n\n    int cnt=0;\n    for(int i=0; i<n; i++)\n        if(ans[i])\n            cnt++;\n    cout<<cnt<<endl;\n    \n}\n\nsigned main() {\n    cin.tie(nullptr);\n    std::ios::sync_with_stdio(false);\n    solve();\n}\n\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N observatories in AtCoder Hill, called Obs. 1, Obs. 2, ..., Obs. N. The elevation of Obs. i is H_i.\nThere are also M roads, each connecting two different observatories. Road j connects Obs. A_j and Obs. B_j.\n\nObs. i is said to be good when its elevation is higher than those of all observatories that can be reached from Obs. i using just one road.\nNote that Obs. i is also good when no observatory can be reached from Obs. i using just one road.\n\nHow many good observatories are there?\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq H_i \\leq 10^9\n\n1 \\leq A_i,B_i \\leq N\n\nA_i \\neq B_i\n\nMultiple roads may connect the same pair of observatories.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nH_1 H_2 ... H_N\nA_1 B_1\nA_2 B_2\n:\nA_M B_M\n\nOutput\n\nPrint the number of good observatories.\n\nSample Input 1\n\n4 3\n1 2 3 4\n1 3\n2 3\n2 4\n\nSample Output 1\n\n2\n\nFrom Obs. 1, you can reach Obs. 3 using just one road. The elevation of Obs. 1 is not higher than that of Obs. 3, so Obs. 1 is not good.\n\nFrom Obs. 2, you can reach Obs. 3 and 4 using just one road. The elevation of Obs. 2 is not higher than that of Obs. 3, so Obs. 2 is not good.\n\nFrom Obs. 3, you can reach Obs. 1 and 2 using just one road. The elevation of Obs. 3 is higher than those of Obs. 1 and 2, so Obs. 3 is good.\n\nFrom Obs. 4, you can reach Obs. 2 using just one road. The elevation of Obs. 4 is higher than that of Obs. 2, so Obs. 4 is good.\n\nThus, the good observatories are Obs. 3 and 4, so there are two good observatories.\n\nSample Input 2\n\n6 5\n8 6 9 1 2 1\n1 3\n4 2\n4 3\n4 6\n4 6\n\nSample Output 2\n\n3", "sample_input": "4 3\n1 2 3 4\n1 3\n2 3\n2 4\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02689", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N observatories in AtCoder Hill, called Obs. 1, Obs. 2, ..., Obs. N. The elevation of Obs. i is H_i.\nThere are also M roads, each connecting two different observatories. Road j connects Obs. A_j and Obs. B_j.\n\nObs. i is said to be good when its elevation is higher than those of all observatories that can be reached from Obs. i using just one road.\nNote that Obs. i is also good when no observatory can be reached from Obs. i using just one road.\n\nHow many good observatories are there?\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq H_i \\leq 10^9\n\n1 \\leq A_i,B_i \\leq N\n\nA_i \\neq B_i\n\nMultiple roads may connect the same pair of observatories.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nH_1 H_2 ... H_N\nA_1 B_1\nA_2 B_2\n:\nA_M B_M\n\nOutput\n\nPrint the number of good observatories.\n\nSample Input 1\n\n4 3\n1 2 3 4\n1 3\n2 3\n2 4\n\nSample Output 1\n\n2\n\nFrom Obs. 1, you can reach Obs. 3 using just one road. The elevation of Obs. 1 is not higher than that of Obs. 3, so Obs. 1 is not good.\n\nFrom Obs. 2, you can reach Obs. 3 and 4 using just one road. The elevation of Obs. 2 is not higher than that of Obs. 3, so Obs. 2 is not good.\n\nFrom Obs. 3, you can reach Obs. 1 and 2 using just one road. The elevation of Obs. 3 is higher than those of Obs. 1 and 2, so Obs. 3 is good.\n\nFrom Obs. 4, you can reach Obs. 2 using just one road. The elevation of Obs. 4 is higher than that of Obs. 2, so Obs. 4 is good.\n\nThus, the good observatories are Obs. 3 and 4, so there are two good observatories.\n\nSample Input 2\n\n6 5\n8 6 9 1 2 1\n1 3\n4 2\n4 3\n4 6\n4 6\n\nSample Output 2\n\n3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1963, "cpu_time_ms": 51, "memory_kb": 9788}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s811742174", "group_id": "codeNet:p02690", "input_text": "// myfirstatcoder.cpp : アプリケーションのエントリ ポイントを定義します。\n\n#include \"bits/stdc++.h\"\n#define rep(i,cc,n) for(int i=cc;i<(n);++i)\n#define drep(i,cc,n) for(int i=cc;i>(n);--i)\n#define llrep(i,cc,n) for(long long i=cc;i<(n);++i)\nusing namespace std;\nusing ll = long long;\n\nint main()\n{\n\tint x;\n\tcin >> x;\n\tllrep(i, -200, 200)\n\t\tllrep(j, -200, 200)\n\t\tif (i*i*i*i*i - j * j*j*j*j == x) {\n\t\t\tcout << i << \" \" << j << endl;\n\t\t\treturn 0;\n\t\t}\n\t//cout << a << b << endl;\n}\n\n/*\nライブラリ\n・string\n・vector<int>\n::::vector<vector<int>> A(N,vector<int>(M));\n::::A[i][j] = i;\n・map<string,int>\n\n関数\n・rep(i,n) … ループ(i=0;i<N;++i)\n・rep_b(i,n) … ループ(i=1;i<=N;++i)\n・gcd(int, int) … 最大公約数 int\n・find_string(str, str) … 文字列検索 bool\n*/", "language": "C++", "metadata": {"date": 1588566120, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02690.html", "problem_id": "p02690", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02690/input.txt", "sample_output_relpath": "derived/input_output/data/p02690/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02690/C++/s811742174.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s811742174", "user_id": "u415727168"}, "prompt_components": {"gold_output": "2 -1\n", "input_to_evaluate": "// myfirstatcoder.cpp : アプリケーションのエントリ ポイントを定義します。\n\n#include \"bits/stdc++.h\"\n#define rep(i,cc,n) for(int i=cc;i<(n);++i)\n#define drep(i,cc,n) for(int i=cc;i>(n);--i)\n#define llrep(i,cc,n) for(long long i=cc;i<(n);++i)\nusing namespace std;\nusing ll = long long;\n\nint main()\n{\n\tint x;\n\tcin >> x;\n\tllrep(i, -200, 200)\n\t\tllrep(j, -200, 200)\n\t\tif (i*i*i*i*i - j * j*j*j*j == x) {\n\t\t\tcout << i << \" \" << j << endl;\n\t\t\treturn 0;\n\t\t}\n\t//cout << a << b << endl;\n}\n\n/*\nライブラリ\n・string\n・vector<int>\n::::vector<vector<int>> A(N,vector<int>(M));\n::::A[i][j] = i;\n・map<string,int>\n\n関数\n・rep(i,n) … ループ(i=0;i<N;++i)\n・rep_b(i,n) … ループ(i=1;i<=N;++i)\n・gcd(int, int) … 最大公約数 int\n・find_string(str, str) … 文字列検索 bool\n*/", "problem_context": "Score : 400 points\n\nProblem Statement\n\nGive a pair of integers (A, B) such that A^5-B^5 = X.\nIt is guaranteed that there exists such a pair for the given integer X.\n\nConstraints\n\n1 \\leq X \\leq 10^9\n\nX is an integer.\n\nThere exists a pair of integers (A, B) satisfying the condition in Problem Statement.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint A and B, with space in between.\nIf there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.\n\nA B\n\nSample Input 1\n\n33\n\nSample Output 1\n\n2 -1\n\nFor A=2 and B=-1, A^5-B^5 = 33.\n\nSample Input 2\n\n1\n\nSample Output 2\n\n0 -1", "sample_input": "33\n"}, "reference_outputs": ["2 -1\n"], "source_document_id": "p02690", "source_text": "Score : 400 points\n\nProblem Statement\n\nGive a pair of integers (A, B) such that A^5-B^5 = X.\nIt is guaranteed that there exists such a pair for the given integer X.\n\nConstraints\n\n1 \\leq X \\leq 10^9\n\nX is an integer.\n\nThere exists a pair of integers (A, B) satisfying the condition in Problem Statement.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint A and B, with space in between.\nIf there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.\n\nA B\n\nSample Input 1\n\n33\n\nSample Output 1\n\n2 -1\n\nFor A=2 and B=-1, A^5-B^5 = 33.\n\nSample Input 2\n\n1\n\nSample Output 2\n\n0 -1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 810, "cpu_time_ms": 2, "memory_kb": 3620}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s853331829", "group_id": "codeNet:p02690", "input_text": "#include <stdio.h>\n#include <vector> \n#include <algorithm>\n#include <functional>\n#include <iostream>\n#include <iomanip>\n#include <limits>\n#include <cmath>\nusing namespace std;\n\nint main(){\n    signed long X;\n    cin>>X;\n    signed long A,B;\n    vector<signed long> ALL;\n    for(int i=0;i<10;i++){\n        long tmp=pow(i,5);\n        ALL.push_back(tmp);\n        cout<<tmp<<endl;\n    }\n    bool ok=false;\n    for(int i=-9;i<10;i++){\n        signed long tmp;\n        if(i<0){\n            tmp=X-ALL[abs(i)];\n        }else{\n            tmp=X+ALL[i];\n\n        }\n        if(tmp<0){\n            for(int j=0;j<ALL.size();j++){\n            if(ALL[j]==abs(tmp)){\n                A=-j;\n                B=i;\n                ok=true;\n                break;\n            }\n        }\n        }else{\n            for(int j=0;j<ALL.size();j++){\n                if(ALL[j]==tmp){\n                    A=j;\n                    B=i;\n                    ok=true;\n                    break;\n                }\n            }\n        }\n\n        if(ok)break;\n    }\n    cout<<A<<\" \"<<B;\n\n\n\n\n\n}\n\n", "language": "C++", "metadata": {"date": 1588557801, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02690.html", "problem_id": "p02690", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02690/input.txt", "sample_output_relpath": "derived/input_output/data/p02690/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02690/C++/s853331829.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s853331829", "user_id": "u227763649"}, "prompt_components": {"gold_output": "2 -1\n", "input_to_evaluate": "#include <stdio.h>\n#include <vector> \n#include <algorithm>\n#include <functional>\n#include <iostream>\n#include <iomanip>\n#include <limits>\n#include <cmath>\nusing namespace std;\n\nint main(){\n    signed long X;\n    cin>>X;\n    signed long A,B;\n    vector<signed long> ALL;\n    for(int i=0;i<10;i++){\n        long tmp=pow(i,5);\n        ALL.push_back(tmp);\n        cout<<tmp<<endl;\n    }\n    bool ok=false;\n    for(int i=-9;i<10;i++){\n        signed long tmp;\n        if(i<0){\n            tmp=X-ALL[abs(i)];\n        }else{\n            tmp=X+ALL[i];\n\n        }\n        if(tmp<0){\n            for(int j=0;j<ALL.size();j++){\n            if(ALL[j]==abs(tmp)){\n                A=-j;\n                B=i;\n                ok=true;\n                break;\n            }\n        }\n        }else{\n            for(int j=0;j<ALL.size();j++){\n                if(ALL[j]==tmp){\n                    A=j;\n                    B=i;\n                    ok=true;\n                    break;\n                }\n            }\n        }\n\n        if(ok)break;\n    }\n    cout<<A<<\" \"<<B;\n\n\n\n\n\n}\n\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nGive a pair of integers (A, B) such that A^5-B^5 = X.\nIt is guaranteed that there exists such a pair for the given integer X.\n\nConstraints\n\n1 \\leq X \\leq 10^9\n\nX is an integer.\n\nThere exists a pair of integers (A, B) satisfying the condition in Problem Statement.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint A and B, with space in between.\nIf there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.\n\nA B\n\nSample Input 1\n\n33\n\nSample Output 1\n\n2 -1\n\nFor A=2 and B=-1, A^5-B^5 = 33.\n\nSample Input 2\n\n1\n\nSample Output 2\n\n0 -1", "sample_input": "33\n"}, "reference_outputs": ["2 -1\n"], "source_document_id": "p02690", "source_text": "Score : 400 points\n\nProblem Statement\n\nGive a pair of integers (A, B) such that A^5-B^5 = X.\nIt is guaranteed that there exists such a pair for the given integer X.\n\nConstraints\n\n1 \\leq X \\leq 10^9\n\nX is an integer.\n\nThere exists a pair of integers (A, B) satisfying the condition in Problem Statement.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint A and B, with space in between.\nIf there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.\n\nA B\n\nSample Input 1\n\n33\n\nSample Output 1\n\n2 -1\n\nFor A=2 and B=-1, A^5-B^5 = 33.\n\nSample Input 2\n\n1\n\nSample Output 2\n\n0 -1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1062, "cpu_time_ms": 3, "memory_kb": 4108}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s161110874", "group_id": "codeNet:p02690", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing grid = vector<vector<char>>;\n\nint dx[] = { 0, 1, -1, 0, 1, -1, 1, -1 };  // i<4:4way i<8:8way\nint dy[] = { 1, 0, 0, -1, 1, -1, -1, 1 };\n\nconstexpr ll MOD = 1000000007;\n//constexpr ll MOD = 998244353;\n\nconstexpr ll INF = 1050000000;\nconstexpr ll LONGINF = 1050000000000000000;\nstruct all_init {\n    all_init() {\n        cout.tie(nullptr);\n        cin.tie(nullptr);\n        ios::sync_with_stdio(false);\n        cout << fixed << setprecision(11);\n    };\n} ALL_INIT;\nstruct edge {\n    int from, to;\n    ll cost;\n    ll capa;\n \n    edge(int s, int d) : from(s), to(d) {cost = 0;capa = 0;}\n    edge(int s, int d, ll w) : from(s), to(d), cost(w) { capa = 0; }\n    edge(int s, int d, ll x, ll y) : from(s), to(d), cost(x), capa(y) {}\n \n    bool operator<(const edge& x) const {\n        if(cost<x.cost){\n            return true;\n        }\n        return false;\n    }\n};\nusing graph = vector<vector<edge>>;\nvoid add_edge(vector<vector<edge>>& g, int a, int b, ll cost, ll cap) {\n    g[a].emplace_back(a, b, cost, cap);\n    g[b].emplace_back(b, a, cost, cap);\n}\n \n#define CIN(vector_array_etc, n)         \\\n  for (int loop = 0; loop < n; loop++) { \\\n    cin >> vector_array_etc[loop];       \\\n  }\n#define COUT(vector_array_etc, n)                                   \\\n  for (int LOOP = 0; LOOP < n; LOOP++) {                            \\\n    cout << vector_array_etc[LOOP] << (LOOP == n - 1 ? '\\n' : ' '); \\\n  }\n#define VC(Type_name) vector<Type_name>\n#define SORT(vector_etc) sort(vector_etc.begin(), vector_etc.end())\n#define ALL(vec_etc) vec_etc.begin(), vec_etc.end()\n#define VCVC(Type_name) vector<vector<Type_name>>  \n#define WARSHALL vector<vector<ll>> g(n, vector<ll>(n, LONGINF))\n#define endl '\\n'\n\n \ntemplate <class T>\nbool chmax(T& a, const T& b) {\n    if (a < b) {\n        a = b;\n        return true;\n    }\n    return false;\n}\ntemplate <class T>\nbool chmin(T& a, const T& b) {\n    if (b < a) {\n        a = b;\n        return true;\n    }\n    return false;\n}\ntemplate <typename T>\nistream& operator>>(istream& is, vector<T>& Vec) {\n    for (T& x : Vec) {\n        is >> x;\n    }\n    return is;\n}\ntemplate <typename V, typename H>\nvoid resize(vector<V>& vec, const H head) {\n    vec.resize(head);\n}\ntemplate <typename V, typename H, typename... T>\nvoid resize(vector<V>& vec, const H& head, const T... tail) {\n    vec.resize(head);\n    for (auto& v : vec) {\n        resize(v, tail...);\n    }\n}\ntemplate <ll mod>\nstruct ModInt {\n    long long val;\n    constexpr ModInt(long long v = 0) noexcept : val(v% mod) {\n        if (val < 0) val += mod;\n    }\n    constexpr int getmod() { return mod; }\n    constexpr ModInt operator-() const noexcept { return val ? mod - val : 0; }\n    constexpr ModInt operator+(const ModInt& r) const noexcept {\n        return ModInt(*this) += r;\n    }\n    constexpr ModInt operator-(const ModInt& r) const noexcept {\n        return ModInt(*this) -= r;\n    }\n    constexpr ModInt operator*(const ModInt& r) const noexcept {\n        return ModInt(*this) *= r;\n    }\n    constexpr ModInt operator/(const ModInt& r) const noexcept {\n        return ModInt(*this) /= r;\n    }\n    constexpr ModInt& operator+=(const ModInt& r) noexcept {\n        val += r.val;\n        if (val >= mod) val -= mod;\n        return *this;\n    }\n    constexpr ModInt& operator-=(const ModInt& r) noexcept {\n        val -= r.val;\n        if (val < 0) val += mod;\n        return *this;\n    }\n    constexpr ModInt& operator*=(const ModInt& r) noexcept {\n        val = val * r.val % mod;\n        return *this;\n    }\n    constexpr ModInt& operator/=(const ModInt& r) noexcept {\n        long long a = r.val, b = mod, u = 1, v = 0;\n        while (b) {\n            long long t = a / b;\n            a -= t * b;\n            swap(a, b);\n            u -= t * v;\n            swap(u, v);\n        }\n        val = val * u % mod;\n        if (val < 0) val += mod;\n        return *this;\n    }\n    constexpr bool operator==(const ModInt& r) const noexcept {\n        return this->val == r.val;\n    }\n    constexpr bool operator!=(const ModInt& r) const noexcept {\n        return this->val != r.val;\n    }\n    friend ostream& operator<<(ostream& os, const ModInt<mod>& x) noexcept {\n        return os << x.val;\n    }\n    friend istream& operator>>(istream& is, ModInt<mod>& x) noexcept {\n        return is >> x.val;\n    }\n    friend constexpr ModInt<mod> modpow(const ModInt<mod>& a,\n        long long n) noexcept {\n        if (n == 0) return 1;\n        auto t = modpow(a, n / 2);\n        t = t * t;\n        if (n & 1) t = t * a;\n        return t;\n    }\n};\ntemplate <class T>\nstruct nCk {\n    vector<T> fact_, inv_, finv_;\n    constexpr nCk() {}\n    constexpr nCk(int n) noexcept : fact_(n, 1), inv_(n, 1), finv_(n, 1) {\n        init(n);\n    }\n    constexpr void init(int n) noexcept {\n        fact_.assign(n, 1), inv_.assign(n, 1), finv_.assign(n, 1);\n        ll MOD = 1000000007;\n        for (ll i = 2; i < n; i++) {\n            fact_[i] = fact_[i - 1] * i;\n            inv_[i] = -inv_[MOD % i] * (MOD / i);\n            finv_[i] = finv_[i - 1] * inv_[i];\n        }\n    }\n    constexpr T com(ll n, ll k) const noexcept {\n        if (n < k || n < 0 || k < 0) return 0;\n        return fact_[n] * finv_[k] * finv_[n - k];\n    }\n    constexpr T fact(int n) const noexcept {\n        if (n < 0) return 0;\n        return fact_[n];\n    }\n    constexpr T inv(int n) const noexcept {\n        if (n < 0) return 0;\n        return inv_[n];\n    }\n    constexpr T finv(int n) const noexcept {\n        if (n < 0) return 0;\n        return finv_[n];\n    }\n};\n\nll PowMod(ll n, ll k, ll mod) {\n    ll r = 1;\n \n    for (; k > 0; k >>= 1) {\n        if (k & 1) {\n            r = (r * n) % mod;\n        }\n        n = (n * n) % mod;\n    }\n    return r;\n}\nll Gcd(ll a, ll b) {\n    return b != 0 ? Gcd(b, a % b) : a;\n}\nll Lcm(ll a, ll b) {\n    return a / Gcd(a, b) * b;\n}\nvector<string> Split(string s, string t) {\n    vector<string> v;\n    int p = s.find(t);\n    while (p != s.npos) {\n        v.emplace_back(s.substr(0, p));\n        s = s.substr(p + (int)t.size());\n        p = s.find(t);\n    }\n    v.emplace_back(s);\n    return v;\n}\nvector<int> Lis(const vector<int>& a) {\n    #define Index_of(as, x) distance(as.begin(), upper_bound(as.begin(), as.end(),x))\n//#define Index_of(as, x) \\\n  distance(as.begin(), upper_bound(as.begin(), as.end(), x))\n    const int n = a.size();\n    vector<int> A(n, INF);\n    vector<int> id(n);\n    for (int i = 0; i < n; ++i) {\n        id[i] = Index_of(A, a[i]);\n        A[id[i]] = a[i];\n    }\n    int m = *max_element(id.begin(), id.end());\n    vector<int> b(m + 1);\n    for (int i = n - 1; i >= 0; --i)\n        if (id[i] == m) b[m--] = a[i];\n    return b;\n}\nstring LcsAlphabeticalMinOrder(string a, string b) {\n    if (a.size() < b.size()) {\n        swap(a, b);\n    }\n \n    int n = a.size(), m = b.size();\n \n    vector<string> dp(m + 1);\n \n    for (int i = 0; i < n; i++) {\n        vector<string> to(m + 1);\n        for (int j = 0; j < m; j++) {\n            if (a[i] == b[j]) {\n                to[j + 1] = dp[j] + a[i];\n            }\n            else {\n                if (to[j].size() > dp[j + 1].size()) {\n                    to[j + 1] = to[j];\n                }\n                else if (to[j].size() < dp[j + 1].size()) {\n                    to[j + 1] = dp[j + 1];\n                }\n                else if (to[j] < dp[j + 1]) {\n                    to[j + 1] = to[j];\n                }\n                else {\n                    to[j + 1] = dp[j + 1];\n                }\n            }\n        }\n        dp.swap(to);\n    }\n    return dp[m];\n}\nstring Lcs(const string& s, const string& t) {\n    int n = s.size();\n    int m = t.size();\n    int dp[n+1][m+1];\n    for (int i = 1; i <= n; i++) {\n        for (int j = 1; j <= m; j++) {\n            if (s[i - 1] == t[j - 1]) {\n                dp[i][j] = dp[i - 1][j - 1] + 1;\n            }\n            else {\n                dp[i][j] = max(dp[i - 1][j], dp[i][j - 1]);\n            }\n        }\n    }\n    string ans = \"\";\n    int i = s.size(), j = t.size();\n    while (i > 0 && j > 0) {\n        if (s[i - 1] == t[j - 1]) {\n            ans += s[i - 1];\n            i--;\n            j--;\n        }\n        else if (dp[i - 1][j] >= dp[i][j - 1])\n            i--;\n        else\n            j--;\n    }\n    reverse(ans.begin(), ans.end());\n    return ans;\n}\nvector<int> LcsInteger(const vector<int> &a, const vector<int> &b) {\n#define index_of(as, x) \\\n  distance(as.begin(), lower_bound(as.begin(), as.end(), x))\n    struct node {\n        int value;\n        node* next;\n        node(int value, node* next) : value(value), next(next) {}\n    };\n    const int n = a.size(), m = b.size();\n    map<int, vector<int>> M;\n    for (int j = m - 1; j >= 0; --j) M[b[j]].push_back(j);\n    vector<int> xs(n + 1, INF);\n    xs[0] = -INF;\n    vector<node*> link(n + 1);\n    for (int i = 0; i < n; ++i) {\n        if (M.count(a[i])) {\n            vector<int> ys = M[a[i]];\n            for (int j = 0; j < (int)ys.size(); ++j) {\n                int k = index_of(xs, ys[j]);\n                xs[k] = ys[j];\n                link[k] = new node(b[ys[j]], link[k - 1]);\n            }\n        }\n    }\n    vector<int> c;\n    int l = index_of(xs, INF - 1) - 1;\n    for (node* p = link[l]; p; p = p->next) c.push_back(p->value);\n    reverse(c.begin(), c.end());\n    return c;\n}\nbool IsPrime(ll n) {\n    if (n < 2) return false;\n    for (ll i = 2; i * i <= n; i++)\n        if (!(n % i)) return false;\n    return true;\n}\nvector<ll> Eratosthenes(int n) {\n    vector<ll> res;\n    vector<bool> Prime(n + 1, true);\n    Prime[0] = Prime[1] = false;\n    for (int i = 2; i * i <= n; i++) {\n        if (Prime[i]) {\n            for (int j = 2; i * j <= n; j++) {\n                Prime[i * j] = false;\n            }\n        }\n    }\n    for (int i = 2; i <= n; i++) {\n        if (Prime[i]) {\n            res.emplace_back(i);\n        }\n    }\n    return res;\n}\nll maxSubArraySum(vector<ll> a,int left,int right) {\n    //[left,right)\n    int size=a.size(); \n    ll max_so_far = -LONGINF, max_ending_here = 0; \n  \n    for (int i = left; i < right; i++) { \n        max_ending_here = max_ending_here + a[i]; \n        if (max_so_far < max_ending_here) {\n            max_so_far = max_ending_here; \n        }\n  \n        if (max_ending_here < 0) {\n            max_ending_here = 0; \n        }\n    } \n    return max_so_far; \n}\nll MergeCount(vector<int>& a) {\n    ll count = 0;\n    int n = a.size();\n    if (n > 1) {\n        vector<int> b(a.begin(), a.begin() + n / 2);\n        vector<int> c(a.begin() + n / 2, a.end());\n        count += MergeCount(b);\n        count += MergeCount(c);\n        for (int i = 0, j = 0, k = 0; i < n; ++i)\n            if (k == (int)c.size())\n                a[i] = b[j++];\n            else if (j == (int)b.size())\n                a[i] = c[k++];\n            else if (b[j] <= c[k])\n                a[i] = b[j++];\n            else {\n                a[i] = c[k++];\n                count += n / 2 - j;\n            }\n    }\n    return count;\n}\nbool WarshallFloyd(vector<vector<ll>>& c) {\n    int V = c.size();\n    for (int i = 0; i < V; i++) {\n        c[i][i] = 0;\n    }\n \n    for (int i = 0; i < V; i++) {\n        for (int j = 0; j < V; j++) {\n            for (int k = 0; k < V; k++) {\n                if (c[j][k] > c[j][i] + c[i][k]) {\n                    if(c[j][i] != LONGINF && c[i][k] != LONGINF){\n                        c[j][k] = c[j][i] + c[i][k];\n                    }\n                }\n            }\n        }\n    }\n \n    for (int i = 0; i < V; i++) {\n        if (c[i][i] < 0) {\n            return false;\n        }\n    }\n \n    return true;\n}\nvector<ll> Dijkstra(int i, vector<vector<edge>> graph) {\n    int n = graph.size();\n    vector<ll> d(n, LONGINF);\n    d[i] = 0;\n    priority_queue<pair<ll, int>, vector<pair<ll, int>>, greater<pair<ll, int>>>\n        q;\n    q.push(make_pair(0, i));\n    while (!q.empty()) {\n        pair<ll, int> p = q.top();\n        q.pop();\n        int v = p.second;\n        if (d[v] < p.first) {\n            continue;\n        }\n        for (auto x : graph[v]) {\n            if (d[x.to] > d[v] + x.cost) {\n                d[x.to] = d[v] + x.cost;\n                q.push(make_pair(d[x.to], x.to));\n            }\n        }\n    }\n    return d;\n}\nvector<vector<ll>> gridDijkstra(const int &start_h,const int &start_w,const vector<vector<ll>> &a){\n    const int h=a.size();\n    const int w=a[0].size();\n    vector<vector<ll>> dp(h,vector<ll>(w,LONGINF));\n\n    struct status{\n        int x,y;\n        ll cost;\n        status(int x_,int y_):status(x_,y_,1LL){};\n        status(int x_,int y_,ll cost_):x(x_),y(y_),cost(cost_){};\n    };\n    class Compare {\n    public:\n\t    bool operator()(const status&from, const status&to) {\n\t\t    return from.cost>to.cost;\n\t    }\n    };\n\n    priority_queue<status,vector<status>,Compare> q;\n    status tmp_start(start_h,start_w,0LL);\n    q.push(tmp_start);\n\n    //from,to cost\n    auto costFunction=[](const ll a,const ll b){return max(b-a,0LL);};\n    //auto costFinction=[](const ll a,const ll b){return a+b};\n\n    #define COST costFunction(a[x][y],a[nx][ny])\n\n    while(q.size()){\n        status tmp1(q.top());\n        int x=tmp1.x;\n        int y=tmp1.y;\n        ll sum=tmp1.cost;\n        q.pop();\n        if(chmin(dp[x][y],sum)){\n            for(int i=0;i<4;i++){\n                int nx=x+dx[i];\n                int ny=y+dy[i];\n                if(nx<0||nx>=h||ny<0||ny>=w){\n                    continue;\n                }\n                if(dp[nx][ny]!=LONGINF&&dp[nx][ny]<=sum+COST){\n                    continue;\n                }\n                status tmp2(nx,ny,sum+COST);\n                q.push(tmp2);\n            }\n        }\n    }\n\n    return dp;\n}\nbool BellmanFord(int start, int V, int E, vector<edge> Edge, vector<ll>& d) {\n    resize(d, V);\n    fill(d.begin(), d.end(), LONGINF);\n    d[start] = 0;\n    vector<bool> t(V, false);\n    for (int i = 0; i < V - 1; i++) {\n        for (int j = 0; j < E; j++) {\n            edge e = Edge[j];\n            if (d[e.from] == LONGINF) {\n                continue;\n            }\n            if (d[e.to] > d[e.from] + e.cost) {\n                d[e.to] = d[e.from] + e.cost;\n            }\n        }\n    }\n    for (int i = 0; i < V; i++) {\n        for (int j = 0; j < E; j++) {\n            edge e = Edge[j];\n            if (d[e.from] == LONGINF) {\n                continue;\n            }\n            if (d[e.to] > d[e.from] + e.cost) {\n                d[e.to] = d[e.from] + e.cost;\n                t[e.to] = true;\n                /*\n                if (i == V - 1) {\n                        return false;\n                }\n                */\n            }\n            if (t[e.from]) {\n                t[e.to] = true;\n            }\n        }\n    }\n \n    if (t[V - 1]) {\n        return false;\n    }\n \n    return true;\n}\nbool TopologicalSort(const vector<vector<edge>>& g, vector<int>& ans) {\n    int n = g.size(), k = 0;\n    vector<int> ord(n), in(n);\n    for (auto& es : g) {\n        for (auto& e : es) {\n            in[e.to]++;\n        }\n    }\n    queue<int> q;\n    for (int i = 0; i < n; ++i) {\n        if (in[i] == 0) q.push(i);\n    }\n    while (!q.empty()) {\n        int v = q.front();\n        q.pop();\n        ord[k++] = v;\n        for (auto& e : g[v]) {\n            if (--in[e.to] == 0) q.push(e.to);\n        }\n    }\n    ans = ord;\n    if (*max_element(in.begin(), in.end()) == 0) {\n        return true;\n    }\n    return false;\n}\nvector<int> ArticulationNode(const vector<vector<edge>>& g) {\n    int n = g.size(), idx;\n    vector<int> low(n), ord(n), art;\n    function<void(int)> DFS = [&](int v) {\n        low[v] = ord[v] = ++idx;\n        for (auto& e : g[v]) {\n            int w = e.to;\n            if (ord[w] == 0) {\n                DFS(w);\n                low[v] = min(low[v], low[w]);\n                if ((ord[v] == 1 && ord[w] != 2) || (ord[v] != 1 && low[w] >= ord[v])) {\n                    art.push_back(v);\n                }\n            }\n            else {\n                low[v] = min(low[v], ord[w]);\n            }\n        }\n    };\n    for (int u = 0; u < n; u++) {\n        if (ord[u] == 0) {\n            idx = 0;\n            DFS(u);\n        }\n    }\n \n    sort(art.begin(), art.end());\n    art.erase(unique(art.begin(), art.end()),\n        art.end());\n \n    return art;\n}\nedge TreeDiameter(const vector<vector<edge>>& g) {\n    int start = 0;\n    static const auto bfs = [](const vector<vector<edge>>& g, int s,\n        queue<int>& q, vector<ll>& dist) {\n            while (!q.empty()) {\n                q.pop();\n            }\n            q.push(s);\n            int n = g.size();\n            dist.assign(n, LONGINF);\n            dist[s] = 0;\n            while (q.size()) {\n                int u = q.front();\n                q.pop();\n                for (auto& e : g[u]) {\n                    int v = e.to;\n                    if (dist[v] == LONGINF) {\n                        dist[v] = dist[u] + e.cost;\n                        q.push(v);\n                    }\n                }\n            }\n            return dist;\n    };\n    vector<ll> dist;\n    queue<int> q;\n    bfs(g, start, q, dist);\n    int n = g.size(), u = -1, v = -1;\n    for (int i = 0; i < n; i++)\n        if (dist[i] != LONGINF && (u == -1 || dist[i] > dist[u])) u = i;\n    bfs(g, u, q, dist);\n    for (int i = 0; i < n; i++)\n        if (dist[i] != LONGINF && (v == -1 || dist[i] > dist[v])) v = i;\n    ll d = dist[v];\n    if (u > v) swap(u, v);\n    return edge(u, v, d);\n}\nclass UnionFind {\nprivate:\n    std::vector<int> parent;\n    std::vector<int> height;\n    std::vector<int> m_size;\n    int forest_num;\n \npublic:\n    UnionFind(int size_) : parent(size_), height(size_, 0), m_size(size_, 1) {\n        forest_num = size_;\n        for (int i = 0; i < size_; ++i) parent[i] = i;\n    }\n    void init(int size_) {\n        parent.resize(size_);\n        height.resize(size_, 0);\n        m_size.resize(size_, 1);\n        forest_num = size_;\n        for (int i = 0; i < size_; ++i) parent[i] = i;\n    }\n    int find(int x) {\n        if (parent[x] == x) return x;\n        return parent[x] = find(parent[x]);\n    }\n    bool unite(int x, int y) {\n        x = find(x);\n        y = find(y);\n        if (x == y) return false;\n        int t = size(x) + size(y);\n        m_size[x] = m_size[y] = t;\n        if (height[x] < height[y])\n            parent[x] = y;\n        else\n            parent[y] = x;\n        if (height[x] == height[y]) ++height[x];\n        forest_num--;\n        return true;\n    }\n    bool same(int x, int y) { return find(x) == find(y); }\n    int size(int x) {\n        if (parent[x] == x) return m_size[x];\n        return size(parent[x] = find(parent[x]));\n    }\n    int forest() { return forest_num; }\n    vector<int> get_parent(){\n        return parent;\n    }\n};\nclass Dinic {\nprivate:\n    int n, s, t;\n    vector<int> level, prog, que;\n    vector<vector<ll>> cap, flow;\n    vector<vector<int>> g;\n    ll inf;\n \npublic:\n    Dinic(const vector<vector<edge>>& graph)\n        : n(graph.size()),\n        cap(n, vector<ll>(n)),\n        flow(n, vector<ll>(n)),\n        g(n, vector<int>()),\n        inf(LONGINF) {\n        for (int i = 0; i < n; i++) {\n            for (auto& e : graph[i]) {\n                int u = e.from, v = e.to;\n                ll c = e.capa;\n                cap[u][v] += c;\n                cap[v][u] += c;\n                flow[v][u] += c;\n                g[u].push_back(v);\n                g[v].push_back(u);\n            }\n        }\n    }\n    inline ll residue(int u, int v) { return cap[u][v] - flow[u][v]; }\n    ll solve(int s_, int t_) {\n        this->t = t_, this->s = s_;\n        que.resize(n + 1);\n        ll res = 0;\n        while (levelize()) {\n            prog.assign(n, 0);\n            res += augment(s, inf);\n        }\n        return res;\n    }\n    bool levelize() {\n        int l = 0, r = 0;\n        level.assign(n, -1);\n        level[s] = 0;\n        que[r++] = s;\n        while (l != r) {\n            int v = que[l++];\n            if (v == t) break;\n            for (const int& d : g[v])\n                if (level[d] == -1 && residue(v, d) != 0) {\n                    level[d] = level[v] + 1;\n                    que[r++] = d;\n                }\n        }\n        return level[t] != -1;\n    }\n    ll augment(int v, ll lim) {\n        ll res = 0;\n        if (v == t) return lim;\n        for (int& i = prog[v]; i < (int)g[v].size(); i++) {\n            const int& d = g[v][i];\n            if (residue(v, d) == 0 || level[v] >= level[d]) continue;\n            const ll aug = augment(d, min(lim, residue(v, d)));\n            flow[v][d] += aug;\n            flow[d][v] -= aug;\n            res += aug;\n            lim -= aug;\n            if (lim == 0) break;\n        }\n        return res;\n    }\n};\nclass MinimumCostFlow {\nprivate:\n    using Flow = ll;\n    using Cost = ll;\n    struct Edge {\n        int d;\n        Flow c, f;\n        Cost w;\n        int r, is_r;\n        Edge(int d_, Flow c_, Flow f_, Cost w_, int r_, bool is_r_)\n            : d(d_), c(c_), f(f_), w(w_), r(r_), is_r(is_r_) {}\n    };\n    int n;\n    vector<vector<Edge>> g;\n \npublic:\n    MinimumCostFlow(int n_) : n(n_), g(vector<vector<Edge>>(n_)) {}\n \n    void add_edge(int src, int dst, Cost cost,Flow cap) {\n        int rsrc = g[dst].size();\n        int rdst = g[src].size();\n        g[src].emplace_back(dst, cap, 0, cost, rsrc, false);\n        g[dst].emplace_back(src, cap, cap, -cost, rdst, true);\n    }\n \n    Cost solve(int s, int t, Flow f) {\n        Cost res = 0;\n \n        vector<Cost> h(n + 10), dist(n);\n        vector<int> prevv(n + 10), preve(n + 10);\n \n        using pcv = pair<Cost, int>;\n        priority_queue<pcv, vector<pcv>, greater<pcv>> q;\n        fill(h.begin(), h.end(), 0);\n        while (f > 0) {\n            fill(dist.begin(), dist.end(), LONGINF);\n            dist[s] = 0;\n            q.emplace(0, s);\n            while (q.size()) {\n                Cost cd;\n                int v;\n                tie(cd, v) = q.top();\n                q.pop();\n                if (dist[v] < cd) continue;\n                for (int i = 0; i < (int)(g[v].size()); ++i) {\n                    Edge& e = g[v][i];\n                    if (residue(e) == 0) continue;\n                    if (dist[e.d] + h[e.d] > cd + h[v] + e.w) {\n                        dist[e.d] = dist[v] + e.w + h[v] - h[e.d];\n                        prevv[e.d] = v;\n                        preve[e.d] = i;\n                        q.emplace(dist[e.d], e.d);\n                    }\n                }\n            }\n \n            if (dist[t] == LONGINF) return -1;\n \n            for (int i = 0; i < n; ++i) h[i] += dist[i];\n            Flow d = f;\n            for (int v = t; v != s; v = prevv[v]) {\n                chmin(d, residue(g[prevv[v]][preve[v]]));\n            }\n            f -= d;\n            res += d * h[t];\n            for (int v = t; v != s; v = prevv[v]) {\n                Edge& e = g[prevv[v]][preve[v]];\n                e.f += d;\n                g[v][e.r].f -= d;\n            }\n        }\n        return res;\n    }\n \n    Flow residue(const Edge& e) { return e.c - e.f; }\n \n    void show() {\n        for (int i = 0; i < n; ++i) {\n            for (int j = 0; j < (int)(g[i].size()); ++j) {\n                Edge& e = g[i][j];\n                if (e.is_r) continue;\n                cout << i << \"->\" << e.d << \"(flow:\" << e.f << \")\" << endl;\n            }\n        }\n    }\n};\nclass BipartiteMatching {\nprivate:\n    int V;\n    vector<int> match;\n    vector<bool> used;\n    vector<vector<int>> g;\n    vector<pair<int, int>> match_pair;\n \n    bool dfs(int v) {\n        used[v] = true;\n        for (int i = 0; i < (int)g[v].size(); i++) {\n            int u = g[v][i];\n            int w = match[u];\n            if (w < 0 || !used[w] && dfs(w)) {\n                match[v] = u;\n                match[u] = v;\n                match_pair.emplace_back(make_pair(u, v));\n                return true;\n            }\n        }\n        return false;\n    }\n \npublic:\n    BipartiteMatching(int n) {\n        V = n;\n        resize(match, n);\n        resize(used, n);\n        resize(g, n);\n    }\n \n    void add_edge(int u, int v) {\n        g[u].emplace_back(v);\n        g[v].emplace_back(u);\n    }\n \n    int MatchingSolve() {\n        int res = 0;\n        fill(match.begin(), match.end(), -1);\n \n        for (int v = 0; v < V; v++) {\n            if (match[v] < 0) {\n                fill(used.begin(), used.end(), false);\n                if (dfs(v)) {\n                    res++;\n                }\n            }\n        }\n        return res;\n    }\n \n    vector<pair<int, int>> get_pair() {\n        for (auto x : match_pair) {\n            cout << x.first << \"  \" << x.second << endl;\n        }\n        return match_pair;\n    }\n};\nclass Lca {\nprivate:\n    int n;\n    int log2_n;\n    vector<vector<int>> parent;\n    vector<int> depth;\n    \n    void dfs(const vector<vector<edge>>& g, int v, int p, int d) {\n        parent[0][v] = p;\n        depth[v] = d;\n        for (auto& e : g[v]) {\n            if (e.to != p) {\n                dfs(g, e.to, v, d + 1);\n            }\n        }\n    }\n \npublic:\n    Lca(const vector<vector<edge>>& g, int root) {\n        n = g.size();\n        log2_n = (int)log2(n) + 1;\n        resize(parent, log2_n, n);\n        resize(depth, n);\n \n        dfs(g, root, -1, 0);\n \n        for (int k = 0; k + 1 < log2_n; k++) {\n            for (int v = 0; v < (int)g.size(); v++) {\n                if (parent[k][v] < 0) {\n                    parent[k + 1][v] = -1;\n                }\n                else {\n                    parent[k + 1][v] = parent[k][parent[k][v]];\n                }\n            }\n        }\n    }\n \n    int get_lca(int u, int v) {\n        if (depth[u] > depth[v]) {\n            swap(u, v);\n        }\n \n        for (int k = 0; k < log2_n; k++) {\n            if ((depth[v] - depth[u]) >> k & 1) {\n                v = parent[k][v];\n            }\n        }\n        if (u == v) {\n            return u;\n        }\n \n        for (int k = log2_n - 1; k >= 0; k--) {\n            if (parent[k][u] != parent[k][v]) {\n                u = parent[k][u];\n                v = parent[k][v];\n            }\n        }\n        return parent[0][u];\n    }\n \n    int get_depth(int v) { return depth[v]; }\n};\nclass DAG {\nprivate:\n    int n;\n    vector<vector<edge>> g;\n    vector<int> visited;\n    vector<int> dp;\n    vector<int> topological;\n \n    int dfs(int s) {\n        if ((int)g[s].size() == 0) {\n            return 1;\n        }\n        if (dp[s] > 0) {\n            return dp[s];\n        }\n \n        int mx = 1;\n        for (auto j : g[s]) {\n            if (visited[j.to] == 0) {\n                visited[j.to] = 1;\n                int l = 0;\n                l = dfs(j.to);\n                chmax(mx, l);\n            }\n            else {\n                chmax(mx, dp[j.to]);\n            }\n        }\n        return dp[s] = mx + 1;\n    }\n \npublic:\n    DAG(const vector<vector<edge>>& f) {\n        g = f;\n        n = f.size();\n        resize(visited, n + 1);\n        fill(visited.begin(), visited.end(), 0);\n        resize(dp, n + 1);\n        fill(dp.begin(), dp.end(), -1);\n        resize(topological, n);\n    }\n    DAG(int x) {\n        n = x;\n        resize(g, n);\n        resize(visited, n + 1);\n        fill(visited.begin(), visited.end(), 0);\n        resize(dp, n + 1);\n        fill(dp.begin(), dp.end(), -1);\n    }\n \n    void add_edge(int a, int b) { g[a].emplace_back(a, b); }\n    void add_edge(int a, int b, ll c) { g[a].emplace_back(a, b, c); }\n    void add_edge(int a, int b, ll c, ll d) { g[a].emplace_back(a, b, c, d); }\n \n    int longest_path() {\n        int mx = -1;\n        int res=0;\n        for (int i = 0; i < n; i++) {\n            int h = 0;\n            if (visited[i] == 0) {\n                h = dfs(i);\n                if(mx<h){\n                    mx=h;\n                    res=i;\n                }\n            }\n        }\n        return res;\n    }\n \n    bool TopologicalSort() {\n        int k = g.size();\n        vector<int> ord(n), in(n);\n        for (int i=0;i<n;i++) {\n            for (auto& e : g[i]) {\n                in[e.to]++;\n            }\n        }\n        priority_queue<int> q;\n        for (int i = 0; i < n; ++i) {\n            if (in[i] == 0) q.push(i);\n        }\n        while (!q.empty()) {\n            int v = q.top();\n            q.pop();\n            ord[v] = k;\n            k--;\n            for (auto& e : g[v]) {\n                in[e.to]-=1;\n                if (in[e.to] == 0) {\n                    q.push(e.to);\n                }\n            }\n        }\n        topological = ord;\n        if (*max_element(in.begin(), in.end()) == 0) {\n            return true;\n        }\n        return false;\n    }\n \n    vector<int> getTopologicalArray(){\n        return topological;\n    }\n};\n\n//↑ここまでGitHubに突っ込んだ\n\n\n\n\nclass RangeMinimumUpdateQuerySegmentTree {\nprivate:\n    int n;\n    ll inf = (1LL << 31) - 1;  // 2^31-1\n    vector<ll> dat, lazy;\n \n    void eval(int len, int k) {\n        if (lazy[k] == inf) return;\n        if (k * 2 + 1 < n * 2 - 1) {\n            lazy[2 * k + 1] = lazy[k];\n            lazy[2 * k + 2] = lazy[k];\n        }\n        dat[k] = lazy[k];\n        lazy[k] = inf;\n    }\n \npublic:\n    RangeMinimumUpdateQuerySegmentTree() {}\n    RangeMinimumUpdateQuerySegmentTree(int n_) {\n        n = 1;\n        while (n < n_) n *= 2;\n        dat.assign(n * 2, inf);\n        lazy.assign(n * 2, inf);\n    }\n \n    // [a,b)\n    ll update(int a, int b, ll x, int k, int l, int r) {\n        eval(r - l, k);\n        if (b <= l || r <= a) return dat[k];\n        if (a <= l && r <= b) {\n            lazy[k] = x;\n            return lazy[k];\n        }\n        return dat[k] = min(update(a, b, x, 2 * k + 1, l, (l + r) / 2),\n            update(a, b, x, 2 * k + 2, (l + r) / 2, r));\n    }\n    ll update(int a, int b, ll x) { return update(a, b, x, 0, 0, n); }\n \n    // [a, b)\n    ll query(int a, int b, int k, int l, int r) {\n        eval(r - l, k);\n        if (b <= l || r <= a) return inf;\n        if (a <= l && r <= b) return dat[k];\n        ll vl = query(a, b, 2 * k + 1, l, (l + r) / 2);\n        ll vr = query(a, b, 2 * k + 2, (l + r) / 2, r);\n        return min(vl, vr);\n    }\n    ll query(int a, int b) { return query(a, b, 0, 0, n); }\n};\nclass RangeSumQuerySegmentTree {\nprivate:\n    struct Node {\n        Node* left, * right;\n        ll v;\n \n        Node() : left(nullptr), right(nullptr), v(0) {}\n    };\n    Node* root;\n    ll n, n0;\n    ll query(ll a, ll b, Node* n, ll l, ll r) {\n        if (a <= l && r <= b) {\n            return n->v;\n        }\n        if (r <= a || b <= l) {\n            return 0;\n        }\n \n        ll lv = n->left ? query(a, b, n->left, l, (l + r) >> 1) : 0;\n        ll rv = n->right ? query(a, b, n->right, (l + r) >> 1, r) : 0;\n        return (lv + rv) % MOD;\n    }\n \npublic:\n    RangeSumQuerySegmentTree(ll n) : n(n) {\n        n0 = 1;\n        while (n0 < n) n0 <<= 1;\n        root = new Node();\n    }\n    ~RangeSumQuerySegmentTree() {\n        delete root;\n        root = nullptr;\n    }\n \n    void update(ll k, ll x) {\n        Node* n = root;\n        ll l = 0, r = n0;\n        n->v = (n->v + x) % MOD;\n        while (r - l > 1) {\n            ll m = (l + r) >> 1;\n            if (k < m) {\n                if (!n->left) n->left = new Node();\n                n = n->left;\n \n                r = m;\n            }\n            else {\n                if (!n->right) n->right = new Node();\n                n = n->right;\n \n                l = m;\n            }\n            n->v = (n->v + x) % MOD;\n        }\n    }\n \n    ll query(ll a, ll b) { return query(a, b, root, 0, n0); }\n \n    ll lquery(ll b) { return query(0, b, root, 0, n0); }\n \n    ll rquery(ll a) { return query(a, n0, root, 0, n0); }\n};\nclass KDimensionalTree {\npublic:\n    struct Node {\n        int location;\n        int p, l, r;\n        Node() {}\n    };\n    struct Point {\n        int id, x, y;\n        Point() {}\n        Point(int i, int a, int b) {\n            id = i;\n            x = a;\n            y = b;\n        }\n        bool operator<(const Point& p) const { return id < p.id; }\n        void print() { cout << id << endl; }\n    };\n    static const ll NIL = -1;\n    static bool lessX(const Point& p1, const Point& p2) { return p1.x < p2.x; }\n    static bool lessY(const Point& p1, const Point& p2) { return p1.y < p2.y; }\n \n    int N;\n    vector<Point> P;\n    vector<Node> T;\n    int np;\n \n    KDimensionalTree() {}\n    KDimensionalTree(int N) { init(N); }\n \n    void init(int n) {\n        N = n;\n        P.clear();\n        T.clear();\n        resize(P, N);\n        resize(T, N);\n        np = 0;\n    }\n \n    int makeKDTree(int l, int r, int depth) {\n        if (l >= r) {\n            return NIL;\n        }\n        int mid = (l + r) / 2;\n        int t = np++;\n        if (depth & 1) {\n            sort(P.begin() + l, P.begin() + r, lessY);\n        }\n        else {\n            sort(P.begin() + l, P.begin() + r, lessX);\n        }\n        T[t].location = mid;\n        T[t].l = makeKDTree(l, mid, depth + 1);\n        T[t].r = makeKDTree(mid + 1, r, depth + 1);\n        return t;\n    }\n    void find(int v, int sx, int tx, int sy, int ty, int depth,\n        vector<Point>& ans) {\n        int x = P[T[v].location].x;\n        int y = P[T[v].location].y;\n        if (sx <= x && x <= tx && sy <= y && y <= ty) {\n            ans.push_back(P[T[v].location]);\n        }\n        if (depth % 2 == 0) {\n            if (T[v].l != NIL) {\n                if (sx <= x) find(T[v].l, sx, tx, sy, ty, depth + 1, ans);\n            }\n            if (T[v].r != NIL) {\n                if (x <= tx) find(T[v].r, sx, tx, sy, ty, depth + 1, ans);\n            }\n        }\n        else {\n            if (T[v].l != NIL) {\n                if (sy <= y) find(T[v].l, sx, tx, sy, ty, depth + 1, ans);\n            }\n            if (T[v].r != NIL) {\n                if (y <= ty) find(T[v].r, sx, tx, sy, ty, depth + 1, ans);\n            }\n        }\n    }\n    void add_point(int i, int x, int y) {\n        P[i].id = i;\n        P[i].x = x;\n        P[i].y = y;\n        T[i].l = T[i].r = T[i].p = NIL;\n    }\n};\nclass RangeAddQuerySegmentTree {\nprivate:\n    int n;\n    vector<ll> data;\n \npublic:\n    RangeAddQuerySegmentTree() {}\n    RangeAddQuerySegmentTree(int N) {\n        n = N;\n        resize(data, n + 1);\n        fill(data.begin(), data.end(), 0);\n    }\n \n    void add(int i, ll x) {\n        while (i) {\n            data[i] += x;\n            i -= (i & -i);\n        }\n    }\n    void add(int i, int j, ll x) {\n        add(j, x);\n        add(i - 1, -x);\n    }\n \n    ll get(int i) {\n        ll res = 0;\n        while (i <= n) {\n            res += data[i];\n            i += (i & -i);\n        }\n        return res;\n    }\n};\nclass RangeSumAddQuerySegmentTree {\nprivate:\n    vector<ll> bit0, bit1;\n    int n;\n \n    ll sum(const vector<ll>& b, int i) {\n        ll s = 0;\n        while (i > 0) {\n            s += b[i];\n            i -= (i & -i);\n        }\n        return s;\n    }\n \n    void add(vector<ll>& b, int i, ll v) {\n        while (i <= n) {\n            b[i] += v;\n            i += (i & -i);\n        }\n    }\n \npublic:\n    RangeSumAddQuerySegmentTree() {}\n    RangeSumAddQuerySegmentTree(int N) {\n        n = N;\n        resize(bit0, n + 1);\n        resize(bit1, n + 1);\n        fill(bit0.begin(), bit0.end(), 0);\n        fill(bit1.begin(), bit1.end(), 0);\n    }\n \n    void update(int l, int r, ll x) {\n        add(bit0, l, -x * (l - 1));\n        add(bit1, l, x);\n        add(bit0, r + 1, x * r);\n        add(bit1, r + 1, -x);\n    }\n \n    ll query(int l, int r) {\n        ll res = 0;\n        res += sum(bit0, r) + sum(bit1, r) * r;\n        res -= sum(bit0, l - 1) + sum(bit1, l - 1) * (l - 1);\n        return res;\n    }\n};\n\n\nlong double cross(const complex<long double> &a, const complex<long double> &b) { return a.real() * b.imag() - a.imag() * b.real(); }\nlong double dot(const complex<long double> &a, const complex<long double> &b) { return a.real() * b.real() + a.imag() * b.imag(); }\n\npair<long double,complex<long double>> smallest_enclosing_disc(vector<complex<long double>> ps){\n    const long double pi = 3.1415926535897932384626;\n    static const long double eps = 1e-10;\n    static const long double inf = 1e12;\n\n    using circle = pair<complex<long double>, long double>;\n\n    auto c3 = [](const complex<long double> &a, const complex<long double> &b, const complex<long double> &c){\n        long double A = norm(b - c);\n        long double B = norm(c - a);\n        long double C = norm(a - b);\n        long double S = abs(cross(b - a, c - a));\n        complex<long double> p = (A*(B+C-A)*a + B*(C+A-B)*b + C*(A+B-C)*c) / (4*S*S);\n        long double r = abs(p - a);\n        return make_pair(r, p);\n    };\n\n    auto c2 = [](const complex<long double> &a, const complex<long double> &b){\n        complex<long double> c = (a + b) / (long double)2;\n        long double r = abs(a - c);\n        return make_pair(r, c);\n    };\n\n    auto in_circle = [](const complex<long double> &a, const pair<long double, complex<long double>> &c){\n        return norm(a - c.second) <= c.first*c.first + eps;\n    };\n\n    int n = ps.size();\n    random_shuffle(ps.begin(), ps.end());\n    pair<long double, complex<long double>> c = c2(ps[0], ps[1]);\n    for(int i = 2; i < n; ++i){\n        if(!in_circle(ps[i], c)){\n            c = c2(ps[0], ps[i]);\n            for(int j = 1; j < i; ++j){\n                if(!in_circle(ps[j], c)){\n                    c = c2(ps[j], ps[i]);\n                    for(int k = 0; k < j; ++k){\n                        if(!in_circle(ps[k], c)){\n                            c = c3(ps[i], ps[j], ps[k]);\n                        }\n                    }\n                }\n            }\n        }\n    }\n    return c;\n}\n\npair<ll, vector<edge>> Prim_minimumSpanningTree(const vector<vector<edge>> &g, int r,int K) {\n  int n = g.size();\n  vector<edge> T;\n  ll total = 0;\n\n  vector<bool> visited(n);\n  priority_queue<edge> Q;\n  Q.push( edge(-1, r, 0,0));\n  ll ans=0;\n  int k=0;\n  while (!Q.empty()) {\n    edge e = Q.top(); Q.pop();\n    if (visited[e.to]) continue;\n    T.push_back(e);\n    total += e.cost;\n    ans=max(ans,-e.cost);\n    k++;\n    if(k==K){\n        break;\n    }\n    visited[e.to] = true;\n    for(auto f:g[e.to]) if (!visited[f.to]) Q.push(f);\n  }\n  return pair<ll, vector<edge>>(ans, T);\n}\n\n\n\nclass NodeTwoColoring{\n    private:\n        vector<vector<edge>> G;\n        vector<int> visited;\n        vector<int> white;\n        vector<int> black;\n        \n        void dfs(const vector<vector<edge>> &G,int v=0, ll d=0) { \n            if(d & 1){white.push_back(v+1);}\n            else{black.push_back(v+1);}\n            visited[v]=1+(d&1);\n \n\t        for (auto nv : G[v]) {\n\t\t        if (visited[nv.to]==-1){}\n                else{\n                    continue;\n                }\n\t\t        dfs(G,nv.to,d+nv.cost);\n\t        }\n        }\n        \n    public:\n    NodeTwoColoring(){};\n    NodeTwoColoring(const vector<vector<edge>> &g):G(g){\n        int n=G.size();\n        visited.resize(n,-1);\n        dfs(G);\n    };\n \n    vector<int> get_white(){\n        return white;\n    }\n    vector<int> get_black(){\n        return black;\n    }\n\n    vector<int> get_color(){\n        return visited;\n    }\n \n};\n\n/*\nconst int MAX = 510000;\nlong long fac[MAX], finv[MAX], inv[MAX];\n\nvoid COMinit() {\n    fac[0] = fac[1] = 1;\n    finv[0] = finv[1] = 1;\n    inv[1] = 1;\n    for (int i = 2; i < MAX; i++){\n        fac[i] = fac[i - 1] * i % MOD;\n        inv[i] = MOD - inv[MOD%i] * (MOD / i) % MOD;\n        finv[i] = finv[i - 1] * inv[i] % MOD;\n    }\n}\n\nlong long COM(int n, int k){\n    if (n < k) return 0;\n    if (n < 0 || k < 0) return 0;\n    return fac[n] * (finv[k] * finv[n - k] % MOD) % MOD;\n}\n*/\n\n\nint main() {\n    ll x;cin>>x;\n\n    for(ll i=-5000;i<=5000;i++){\n        for(ll j=-5000;j<=5000;j++){\n            if(i*i*i*i*i-(j*j*j*j*j)==x){\n                cout<<i<<\" \"<<j<<endl;\n                return 0;\n            }\n        }\n    }\n\n    ;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1588555071, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02690.html", "problem_id": "p02690", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02690/input.txt", "sample_output_relpath": "derived/input_output/data/p02690/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02690/C++/s161110874.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s161110874", "user_id": "u385617244"}, "prompt_components": {"gold_output": "2 -1\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing grid = vector<vector<char>>;\n\nint dx[] = { 0, 1, -1, 0, 1, -1, 1, -1 };  // i<4:4way i<8:8way\nint dy[] = { 1, 0, 0, -1, 1, -1, -1, 1 };\n\nconstexpr ll MOD = 1000000007;\n//constexpr ll MOD = 998244353;\n\nconstexpr ll INF = 1050000000;\nconstexpr ll LONGINF = 1050000000000000000;\nstruct all_init {\n    all_init() {\n        cout.tie(nullptr);\n        cin.tie(nullptr);\n        ios::sync_with_stdio(false);\n        cout << fixed << setprecision(11);\n    };\n} ALL_INIT;\nstruct edge {\n    int from, to;\n    ll cost;\n    ll capa;\n \n    edge(int s, int d) : from(s), to(d) {cost = 0;capa = 0;}\n    edge(int s, int d, ll w) : from(s), to(d), cost(w) { capa = 0; }\n    edge(int s, int d, ll x, ll y) : from(s), to(d), cost(x), capa(y) {}\n \n    bool operator<(const edge& x) const {\n        if(cost<x.cost){\n            return true;\n        }\n        return false;\n    }\n};\nusing graph = vector<vector<edge>>;\nvoid add_edge(vector<vector<edge>>& g, int a, int b, ll cost, ll cap) {\n    g[a].emplace_back(a, b, cost, cap);\n    g[b].emplace_back(b, a, cost, cap);\n}\n \n#define CIN(vector_array_etc, n)         \\\n  for (int loop = 0; loop < n; loop++) { \\\n    cin >> vector_array_etc[loop];       \\\n  }\n#define COUT(vector_array_etc, n)                                   \\\n  for (int LOOP = 0; LOOP < n; LOOP++) {                            \\\n    cout << vector_array_etc[LOOP] << (LOOP == n - 1 ? '\\n' : ' '); \\\n  }\n#define VC(Type_name) vector<Type_name>\n#define SORT(vector_etc) sort(vector_etc.begin(), vector_etc.end())\n#define ALL(vec_etc) vec_etc.begin(), vec_etc.end()\n#define VCVC(Type_name) vector<vector<Type_name>>  \n#define WARSHALL vector<vector<ll>> g(n, vector<ll>(n, LONGINF))\n#define endl '\\n'\n\n \ntemplate <class T>\nbool chmax(T& a, const T& b) {\n    if (a < b) {\n        a = b;\n        return true;\n    }\n    return false;\n}\ntemplate <class T>\nbool chmin(T& a, const T& b) {\n    if (b < a) {\n        a = b;\n        return true;\n    }\n    return false;\n}\ntemplate <typename T>\nistream& operator>>(istream& is, vector<T>& Vec) {\n    for (T& x : Vec) {\n        is >> x;\n    }\n    return is;\n}\ntemplate <typename V, typename H>\nvoid resize(vector<V>& vec, const H head) {\n    vec.resize(head);\n}\ntemplate <typename V, typename H, typename... T>\nvoid resize(vector<V>& vec, const H& head, const T... tail) {\n    vec.resize(head);\n    for (auto& v : vec) {\n        resize(v, tail...);\n    }\n}\ntemplate <ll mod>\nstruct ModInt {\n    long long val;\n    constexpr ModInt(long long v = 0) noexcept : val(v% mod) {\n        if (val < 0) val += mod;\n    }\n    constexpr int getmod() { return mod; }\n    constexpr ModInt operator-() const noexcept { return val ? mod - val : 0; }\n    constexpr ModInt operator+(const ModInt& r) const noexcept {\n        return ModInt(*this) += r;\n    }\n    constexpr ModInt operator-(const ModInt& r) const noexcept {\n        return ModInt(*this) -= r;\n    }\n    constexpr ModInt operator*(const ModInt& r) const noexcept {\n        return ModInt(*this) *= r;\n    }\n    constexpr ModInt operator/(const ModInt& r) const noexcept {\n        return ModInt(*this) /= r;\n    }\n    constexpr ModInt& operator+=(const ModInt& r) noexcept {\n        val += r.val;\n        if (val >= mod) val -= mod;\n        return *this;\n    }\n    constexpr ModInt& operator-=(const ModInt& r) noexcept {\n        val -= r.val;\n        if (val < 0) val += mod;\n        return *this;\n    }\n    constexpr ModInt& operator*=(const ModInt& r) noexcept {\n        val = val * r.val % mod;\n        return *this;\n    }\n    constexpr ModInt& operator/=(const ModInt& r) noexcept {\n        long long a = r.val, b = mod, u = 1, v = 0;\n        while (b) {\n            long long t = a / b;\n            a -= t * b;\n            swap(a, b);\n            u -= t * v;\n            swap(u, v);\n        }\n        val = val * u % mod;\n        if (val < 0) val += mod;\n        return *this;\n    }\n    constexpr bool operator==(const ModInt& r) const noexcept {\n        return this->val == r.val;\n    }\n    constexpr bool operator!=(const ModInt& r) const noexcept {\n        return this->val != r.val;\n    }\n    friend ostream& operator<<(ostream& os, const ModInt<mod>& x) noexcept {\n        return os << x.val;\n    }\n    friend istream& operator>>(istream& is, ModInt<mod>& x) noexcept {\n        return is >> x.val;\n    }\n    friend constexpr ModInt<mod> modpow(const ModInt<mod>& a,\n        long long n) noexcept {\n        if (n == 0) return 1;\n        auto t = modpow(a, n / 2);\n        t = t * t;\n        if (n & 1) t = t * a;\n        return t;\n    }\n};\ntemplate <class T>\nstruct nCk {\n    vector<T> fact_, inv_, finv_;\n    constexpr nCk() {}\n    constexpr nCk(int n) noexcept : fact_(n, 1), inv_(n, 1), finv_(n, 1) {\n        init(n);\n    }\n    constexpr void init(int n) noexcept {\n        fact_.assign(n, 1), inv_.assign(n, 1), finv_.assign(n, 1);\n        ll MOD = 1000000007;\n        for (ll i = 2; i < n; i++) {\n            fact_[i] = fact_[i - 1] * i;\n            inv_[i] = -inv_[MOD % i] * (MOD / i);\n            finv_[i] = finv_[i - 1] * inv_[i];\n        }\n    }\n    constexpr T com(ll n, ll k) const noexcept {\n        if (n < k || n < 0 || k < 0) return 0;\n        return fact_[n] * finv_[k] * finv_[n - k];\n    }\n    constexpr T fact(int n) const noexcept {\n        if (n < 0) return 0;\n        return fact_[n];\n    }\n    constexpr T inv(int n) const noexcept {\n        if (n < 0) return 0;\n        return inv_[n];\n    }\n    constexpr T finv(int n) const noexcept {\n        if (n < 0) return 0;\n        return finv_[n];\n    }\n};\n\nll PowMod(ll n, ll k, ll mod) {\n    ll r = 1;\n \n    for (; k > 0; k >>= 1) {\n        if (k & 1) {\n            r = (r * n) % mod;\n        }\n        n = (n * n) % mod;\n    }\n    return r;\n}\nll Gcd(ll a, ll b) {\n    return b != 0 ? Gcd(b, a % b) : a;\n}\nll Lcm(ll a, ll b) {\n    return a / Gcd(a, b) * b;\n}\nvector<string> Split(string s, string t) {\n    vector<string> v;\n    int p = s.find(t);\n    while (p != s.npos) {\n        v.emplace_back(s.substr(0, p));\n        s = s.substr(p + (int)t.size());\n        p = s.find(t);\n    }\n    v.emplace_back(s);\n    return v;\n}\nvector<int> Lis(const vector<int>& a) {\n    #define Index_of(as, x) distance(as.begin(), upper_bound(as.begin(), as.end(),x))\n//#define Index_of(as, x) \\\n  distance(as.begin(), upper_bound(as.begin(), as.end(), x))\n    const int n = a.size();\n    vector<int> A(n, INF);\n    vector<int> id(n);\n    for (int i = 0; i < n; ++i) {\n        id[i] = Index_of(A, a[i]);\n        A[id[i]] = a[i];\n    }\n    int m = *max_element(id.begin(), id.end());\n    vector<int> b(m + 1);\n    for (int i = n - 1; i >= 0; --i)\n        if (id[i] == m) b[m--] = a[i];\n    return b;\n}\nstring LcsAlphabeticalMinOrder(string a, string b) {\n    if (a.size() < b.size()) {\n        swap(a, b);\n    }\n \n    int n = a.size(), m = b.size();\n \n    vector<string> dp(m + 1);\n \n    for (int i = 0; i < n; i++) {\n        vector<string> to(m + 1);\n        for (int j = 0; j < m; j++) {\n            if (a[i] == b[j]) {\n                to[j + 1] = dp[j] + a[i];\n            }\n            else {\n                if (to[j].size() > dp[j + 1].size()) {\n                    to[j + 1] = to[j];\n                }\n                else if (to[j].size() < dp[j + 1].size()) {\n                    to[j + 1] = dp[j + 1];\n                }\n                else if (to[j] < dp[j + 1]) {\n                    to[j + 1] = to[j];\n                }\n                else {\n                    to[j + 1] = dp[j + 1];\n                }\n            }\n        }\n        dp.swap(to);\n    }\n    return dp[m];\n}\nstring Lcs(const string& s, const string& t) {\n    int n = s.size();\n    int m = t.size();\n    int dp[n+1][m+1];\n    for (int i = 1; i <= n; i++) {\n        for (int j = 1; j <= m; j++) {\n            if (s[i - 1] == t[j - 1]) {\n                dp[i][j] = dp[i - 1][j - 1] + 1;\n            }\n            else {\n                dp[i][j] = max(dp[i - 1][j], dp[i][j - 1]);\n            }\n        }\n    }\n    string ans = \"\";\n    int i = s.size(), j = t.size();\n    while (i > 0 && j > 0) {\n        if (s[i - 1] == t[j - 1]) {\n            ans += s[i - 1];\n            i--;\n            j--;\n        }\n        else if (dp[i - 1][j] >= dp[i][j - 1])\n            i--;\n        else\n            j--;\n    }\n    reverse(ans.begin(), ans.end());\n    return ans;\n}\nvector<int> LcsInteger(const vector<int> &a, const vector<int> &b) {\n#define index_of(as, x) \\\n  distance(as.begin(), lower_bound(as.begin(), as.end(), x))\n    struct node {\n        int value;\n        node* next;\n        node(int value, node* next) : value(value), next(next) {}\n    };\n    const int n = a.size(), m = b.size();\n    map<int, vector<int>> M;\n    for (int j = m - 1; j >= 0; --j) M[b[j]].push_back(j);\n    vector<int> xs(n + 1, INF);\n    xs[0] = -INF;\n    vector<node*> link(n + 1);\n    for (int i = 0; i < n; ++i) {\n        if (M.count(a[i])) {\n            vector<int> ys = M[a[i]];\n            for (int j = 0; j < (int)ys.size(); ++j) {\n                int k = index_of(xs, ys[j]);\n                xs[k] = ys[j];\n                link[k] = new node(b[ys[j]], link[k - 1]);\n            }\n        }\n    }\n    vector<int> c;\n    int l = index_of(xs, INF - 1) - 1;\n    for (node* p = link[l]; p; p = p->next) c.push_back(p->value);\n    reverse(c.begin(), c.end());\n    return c;\n}\nbool IsPrime(ll n) {\n    if (n < 2) return false;\n    for (ll i = 2; i * i <= n; i++)\n        if (!(n % i)) return false;\n    return true;\n}\nvector<ll> Eratosthenes(int n) {\n    vector<ll> res;\n    vector<bool> Prime(n + 1, true);\n    Prime[0] = Prime[1] = false;\n    for (int i = 2; i * i <= n; i++) {\n        if (Prime[i]) {\n            for (int j = 2; i * j <= n; j++) {\n                Prime[i * j] = false;\n            }\n        }\n    }\n    for (int i = 2; i <= n; i++) {\n        if (Prime[i]) {\n            res.emplace_back(i);\n        }\n    }\n    return res;\n}\nll maxSubArraySum(vector<ll> a,int left,int right) {\n    //[left,right)\n    int size=a.size(); \n    ll max_so_far = -LONGINF, max_ending_here = 0; \n  \n    for (int i = left; i < right; i++) { \n        max_ending_here = max_ending_here + a[i]; \n        if (max_so_far < max_ending_here) {\n            max_so_far = max_ending_here; \n        }\n  \n        if (max_ending_here < 0) {\n            max_ending_here = 0; \n        }\n    } \n    return max_so_far; \n}\nll MergeCount(vector<int>& a) {\n    ll count = 0;\n    int n = a.size();\n    if (n > 1) {\n        vector<int> b(a.begin(), a.begin() + n / 2);\n        vector<int> c(a.begin() + n / 2, a.end());\n        count += MergeCount(b);\n        count += MergeCount(c);\n        for (int i = 0, j = 0, k = 0; i < n; ++i)\n            if (k == (int)c.size())\n                a[i] = b[j++];\n            else if (j == (int)b.size())\n                a[i] = c[k++];\n            else if (b[j] <= c[k])\n                a[i] = b[j++];\n            else {\n                a[i] = c[k++];\n                count += n / 2 - j;\n            }\n    }\n    return count;\n}\nbool WarshallFloyd(vector<vector<ll>>& c) {\n    int V = c.size();\n    for (int i = 0; i < V; i++) {\n        c[i][i] = 0;\n    }\n \n    for (int i = 0; i < V; i++) {\n        for (int j = 0; j < V; j++) {\n            for (int k = 0; k < V; k++) {\n                if (c[j][k] > c[j][i] + c[i][k]) {\n                    if(c[j][i] != LONGINF && c[i][k] != LONGINF){\n                        c[j][k] = c[j][i] + c[i][k];\n                    }\n                }\n            }\n        }\n    }\n \n    for (int i = 0; i < V; i++) {\n        if (c[i][i] < 0) {\n            return false;\n        }\n    }\n \n    return true;\n}\nvector<ll> Dijkstra(int i, vector<vector<edge>> graph) {\n    int n = graph.size();\n    vector<ll> d(n, LONGINF);\n    d[i] = 0;\n    priority_queue<pair<ll, int>, vector<pair<ll, int>>, greater<pair<ll, int>>>\n        q;\n    q.push(make_pair(0, i));\n    while (!q.empty()) {\n        pair<ll, int> p = q.top();\n        q.pop();\n        int v = p.second;\n        if (d[v] < p.first) {\n            continue;\n        }\n        for (auto x : graph[v]) {\n            if (d[x.to] > d[v] + x.cost) {\n                d[x.to] = d[v] + x.cost;\n                q.push(make_pair(d[x.to], x.to));\n            }\n        }\n    }\n    return d;\n}\nvector<vector<ll>> gridDijkstra(const int &start_h,const int &start_w,const vector<vector<ll>> &a){\n    const int h=a.size();\n    const int w=a[0].size();\n    vector<vector<ll>> dp(h,vector<ll>(w,LONGINF));\n\n    struct status{\n        int x,y;\n        ll cost;\n        status(int x_,int y_):status(x_,y_,1LL){};\n        status(int x_,int y_,ll cost_):x(x_),y(y_),cost(cost_){};\n    };\n    class Compare {\n    public:\n\t    bool operator()(const status&from, const status&to) {\n\t\t    return from.cost>to.cost;\n\t    }\n    };\n\n    priority_queue<status,vector<status>,Compare> q;\n    status tmp_start(start_h,start_w,0LL);\n    q.push(tmp_start);\n\n    //from,to cost\n    auto costFunction=[](const ll a,const ll b){return max(b-a,0LL);};\n    //auto costFinction=[](const ll a,const ll b){return a+b};\n\n    #define COST costFunction(a[x][y],a[nx][ny])\n\n    while(q.size()){\n        status tmp1(q.top());\n        int x=tmp1.x;\n        int y=tmp1.y;\n        ll sum=tmp1.cost;\n        q.pop();\n        if(chmin(dp[x][y],sum)){\n            for(int i=0;i<4;i++){\n                int nx=x+dx[i];\n                int ny=y+dy[i];\n                if(nx<0||nx>=h||ny<0||ny>=w){\n                    continue;\n                }\n                if(dp[nx][ny]!=LONGINF&&dp[nx][ny]<=sum+COST){\n                    continue;\n                }\n                status tmp2(nx,ny,sum+COST);\n                q.push(tmp2);\n            }\n        }\n    }\n\n    return dp;\n}\nbool BellmanFord(int start, int V, int E, vector<edge> Edge, vector<ll>& d) {\n    resize(d, V);\n    fill(d.begin(), d.end(), LONGINF);\n    d[start] = 0;\n    vector<bool> t(V, false);\n    for (int i = 0; i < V - 1; i++) {\n        for (int j = 0; j < E; j++) {\n            edge e = Edge[j];\n            if (d[e.from] == LONGINF) {\n                continue;\n            }\n            if (d[e.to] > d[e.from] + e.cost) {\n                d[e.to] = d[e.from] + e.cost;\n            }\n        }\n    }\n    for (int i = 0; i < V; i++) {\n        for (int j = 0; j < E; j++) {\n            edge e = Edge[j];\n            if (d[e.from] == LONGINF) {\n                continue;\n            }\n            if (d[e.to] > d[e.from] + e.cost) {\n                d[e.to] = d[e.from] + e.cost;\n                t[e.to] = true;\n                /*\n                if (i == V - 1) {\n                        return false;\n                }\n                */\n            }\n            if (t[e.from]) {\n                t[e.to] = true;\n            }\n        }\n    }\n \n    if (t[V - 1]) {\n        return false;\n    }\n \n    return true;\n}\nbool TopologicalSort(const vector<vector<edge>>& g, vector<int>& ans) {\n    int n = g.size(), k = 0;\n    vector<int> ord(n), in(n);\n    for (auto& es : g) {\n        for (auto& e : es) {\n            in[e.to]++;\n        }\n    }\n    queue<int> q;\n    for (int i = 0; i < n; ++i) {\n        if (in[i] == 0) q.push(i);\n    }\n    while (!q.empty()) {\n        int v = q.front();\n        q.pop();\n        ord[k++] = v;\n        for (auto& e : g[v]) {\n            if (--in[e.to] == 0) q.push(e.to);\n        }\n    }\n    ans = ord;\n    if (*max_element(in.begin(), in.end()) == 0) {\n        return true;\n    }\n    return false;\n}\nvector<int> ArticulationNode(const vector<vector<edge>>& g) {\n    int n = g.size(), idx;\n    vector<int> low(n), ord(n), art;\n    function<void(int)> DFS = [&](int v) {\n        low[v] = ord[v] = ++idx;\n        for (auto& e : g[v]) {\n            int w = e.to;\n            if (ord[w] == 0) {\n                DFS(w);\n                low[v] = min(low[v], low[w]);\n                if ((ord[v] == 1 && ord[w] != 2) || (ord[v] != 1 && low[w] >= ord[v])) {\n                    art.push_back(v);\n                }\n            }\n            else {\n                low[v] = min(low[v], ord[w]);\n            }\n        }\n    };\n    for (int u = 0; u < n; u++) {\n        if (ord[u] == 0) {\n            idx = 0;\n            DFS(u);\n        }\n    }\n \n    sort(art.begin(), art.end());\n    art.erase(unique(art.begin(), art.end()),\n        art.end());\n \n    return art;\n}\nedge TreeDiameter(const vector<vector<edge>>& g) {\n    int start = 0;\n    static const auto bfs = [](const vector<vector<edge>>& g, int s,\n        queue<int>& q, vector<ll>& dist) {\n            while (!q.empty()) {\n                q.pop();\n            }\n            q.push(s);\n            int n = g.size();\n            dist.assign(n, LONGINF);\n            dist[s] = 0;\n            while (q.size()) {\n                int u = q.front();\n                q.pop();\n                for (auto& e : g[u]) {\n                    int v = e.to;\n                    if (dist[v] == LONGINF) {\n                        dist[v] = dist[u] + e.cost;\n                        q.push(v);\n                    }\n                }\n            }\n            return dist;\n    };\n    vector<ll> dist;\n    queue<int> q;\n    bfs(g, start, q, dist);\n    int n = g.size(), u = -1, v = -1;\n    for (int i = 0; i < n; i++)\n        if (dist[i] != LONGINF && (u == -1 || dist[i] > dist[u])) u = i;\n    bfs(g, u, q, dist);\n    for (int i = 0; i < n; i++)\n        if (dist[i] != LONGINF && (v == -1 || dist[i] > dist[v])) v = i;\n    ll d = dist[v];\n    if (u > v) swap(u, v);\n    return edge(u, v, d);\n}\nclass UnionFind {\nprivate:\n    std::vector<int> parent;\n    std::vector<int> height;\n    std::vector<int> m_size;\n    int forest_num;\n \npublic:\n    UnionFind(int size_) : parent(size_), height(size_, 0), m_size(size_, 1) {\n        forest_num = size_;\n        for (int i = 0; i < size_; ++i) parent[i] = i;\n    }\n    void init(int size_) {\n        parent.resize(size_);\n        height.resize(size_, 0);\n        m_size.resize(size_, 1);\n        forest_num = size_;\n        for (int i = 0; i < size_; ++i) parent[i] = i;\n    }\n    int find(int x) {\n        if (parent[x] == x) return x;\n        return parent[x] = find(parent[x]);\n    }\n    bool unite(int x, int y) {\n        x = find(x);\n        y = find(y);\n        if (x == y) return false;\n        int t = size(x) + size(y);\n        m_size[x] = m_size[y] = t;\n        if (height[x] < height[y])\n            parent[x] = y;\n        else\n            parent[y] = x;\n        if (height[x] == height[y]) ++height[x];\n        forest_num--;\n        return true;\n    }\n    bool same(int x, int y) { return find(x) == find(y); }\n    int size(int x) {\n        if (parent[x] == x) return m_size[x];\n        return size(parent[x] = find(parent[x]));\n    }\n    int forest() { return forest_num; }\n    vector<int> get_parent(){\n        return parent;\n    }\n};\nclass Dinic {\nprivate:\n    int n, s, t;\n    vector<int> level, prog, que;\n    vector<vector<ll>> cap, flow;\n    vector<vector<int>> g;\n    ll inf;\n \npublic:\n    Dinic(const vector<vector<edge>>& graph)\n        : n(graph.size()),\n        cap(n, vector<ll>(n)),\n        flow(n, vector<ll>(n)),\n        g(n, vector<int>()),\n        inf(LONGINF) {\n        for (int i = 0; i < n; i++) {\n            for (auto& e : graph[i]) {\n                int u = e.from, v = e.to;\n                ll c = e.capa;\n                cap[u][v] += c;\n                cap[v][u] += c;\n                flow[v][u] += c;\n                g[u].push_back(v);\n                g[v].push_back(u);\n            }\n        }\n    }\n    inline ll residue(int u, int v) { return cap[u][v] - flow[u][v]; }\n    ll solve(int s_, int t_) {\n        this->t = t_, this->s = s_;\n        que.resize(n + 1);\n        ll res = 0;\n        while (levelize()) {\n            prog.assign(n, 0);\n            res += augment(s, inf);\n        }\n        return res;\n    }\n    bool levelize() {\n        int l = 0, r = 0;\n        level.assign(n, -1);\n        level[s] = 0;\n        que[r++] = s;\n        while (l != r) {\n            int v = que[l++];\n            if (v == t) break;\n            for (const int& d : g[v])\n                if (level[d] == -1 && residue(v, d) != 0) {\n                    level[d] = level[v] + 1;\n                    que[r++] = d;\n                }\n        }\n        return level[t] != -1;\n    }\n    ll augment(int v, ll lim) {\n        ll res = 0;\n        if (v == t) return lim;\n        for (int& i = prog[v]; i < (int)g[v].size(); i++) {\n            const int& d = g[v][i];\n            if (residue(v, d) == 0 || level[v] >= level[d]) continue;\n            const ll aug = augment(d, min(lim, residue(v, d)));\n            flow[v][d] += aug;\n            flow[d][v] -= aug;\n            res += aug;\n            lim -= aug;\n            if (lim == 0) break;\n        }\n        return res;\n    }\n};\nclass MinimumCostFlow {\nprivate:\n    using Flow = ll;\n    using Cost = ll;\n    struct Edge {\n        int d;\n        Flow c, f;\n        Cost w;\n        int r, is_r;\n        Edge(int d_, Flow c_, Flow f_, Cost w_, int r_, bool is_r_)\n            : d(d_), c(c_), f(f_), w(w_), r(r_), is_r(is_r_) {}\n    };\n    int n;\n    vector<vector<Edge>> g;\n \npublic:\n    MinimumCostFlow(int n_) : n(n_), g(vector<vector<Edge>>(n_)) {}\n \n    void add_edge(int src, int dst, Cost cost,Flow cap) {\n        int rsrc = g[dst].size();\n        int rdst = g[src].size();\n        g[src].emplace_back(dst, cap, 0, cost, rsrc, false);\n        g[dst].emplace_back(src, cap, cap, -cost, rdst, true);\n    }\n \n    Cost solve(int s, int t, Flow f) {\n        Cost res = 0;\n \n        vector<Cost> h(n + 10), dist(n);\n        vector<int> prevv(n + 10), preve(n + 10);\n \n        using pcv = pair<Cost, int>;\n        priority_queue<pcv, vector<pcv>, greater<pcv>> q;\n        fill(h.begin(), h.end(), 0);\n        while (f > 0) {\n            fill(dist.begin(), dist.end(), LONGINF);\n            dist[s] = 0;\n            q.emplace(0, s);\n            while (q.size()) {\n                Cost cd;\n                int v;\n                tie(cd, v) = q.top();\n                q.pop();\n                if (dist[v] < cd) continue;\n                for (int i = 0; i < (int)(g[v].size()); ++i) {\n                    Edge& e = g[v][i];\n                    if (residue(e) == 0) continue;\n                    if (dist[e.d] + h[e.d] > cd + h[v] + e.w) {\n                        dist[e.d] = dist[v] + e.w + h[v] - h[e.d];\n                        prevv[e.d] = v;\n                        preve[e.d] = i;\n                        q.emplace(dist[e.d], e.d);\n                    }\n                }\n            }\n \n            if (dist[t] == LONGINF) return -1;\n \n            for (int i = 0; i < n; ++i) h[i] += dist[i];\n            Flow d = f;\n            for (int v = t; v != s; v = prevv[v]) {\n                chmin(d, residue(g[prevv[v]][preve[v]]));\n            }\n            f -= d;\n            res += d * h[t];\n            for (int v = t; v != s; v = prevv[v]) {\n                Edge& e = g[prevv[v]][preve[v]];\n                e.f += d;\n                g[v][e.r].f -= d;\n            }\n        }\n        return res;\n    }\n \n    Flow residue(const Edge& e) { return e.c - e.f; }\n \n    void show() {\n        for (int i = 0; i < n; ++i) {\n            for (int j = 0; j < (int)(g[i].size()); ++j) {\n                Edge& e = g[i][j];\n                if (e.is_r) continue;\n                cout << i << \"->\" << e.d << \"(flow:\" << e.f << \")\" << endl;\n            }\n        }\n    }\n};\nclass BipartiteMatching {\nprivate:\n    int V;\n    vector<int> match;\n    vector<bool> used;\n    vector<vector<int>> g;\n    vector<pair<int, int>> match_pair;\n \n    bool dfs(int v) {\n        used[v] = true;\n        for (int i = 0; i < (int)g[v].size(); i++) {\n            int u = g[v][i];\n            int w = match[u];\n            if (w < 0 || !used[w] && dfs(w)) {\n                match[v] = u;\n                match[u] = v;\n                match_pair.emplace_back(make_pair(u, v));\n                return true;\n            }\n        }\n        return false;\n    }\n \npublic:\n    BipartiteMatching(int n) {\n        V = n;\n        resize(match, n);\n        resize(used, n);\n        resize(g, n);\n    }\n \n    void add_edge(int u, int v) {\n        g[u].emplace_back(v);\n        g[v].emplace_back(u);\n    }\n \n    int MatchingSolve() {\n        int res = 0;\n        fill(match.begin(), match.end(), -1);\n \n        for (int v = 0; v < V; v++) {\n            if (match[v] < 0) {\n                fill(used.begin(), used.end(), false);\n                if (dfs(v)) {\n                    res++;\n                }\n            }\n        }\n        return res;\n    }\n \n    vector<pair<int, int>> get_pair() {\n        for (auto x : match_pair) {\n            cout << x.first << \"  \" << x.second << endl;\n        }\n        return match_pair;\n    }\n};\nclass Lca {\nprivate:\n    int n;\n    int log2_n;\n    vector<vector<int>> parent;\n    vector<int> depth;\n    \n    void dfs(const vector<vector<edge>>& g, int v, int p, int d) {\n        parent[0][v] = p;\n        depth[v] = d;\n        for (auto& e : g[v]) {\n            if (e.to != p) {\n                dfs(g, e.to, v, d + 1);\n            }\n        }\n    }\n \npublic:\n    Lca(const vector<vector<edge>>& g, int root) {\n        n = g.size();\n        log2_n = (int)log2(n) + 1;\n        resize(parent, log2_n, n);\n        resize(depth, n);\n \n        dfs(g, root, -1, 0);\n \n        for (int k = 0; k + 1 < log2_n; k++) {\n            for (int v = 0; v < (int)g.size(); v++) {\n                if (parent[k][v] < 0) {\n                    parent[k + 1][v] = -1;\n                }\n                else {\n                    parent[k + 1][v] = parent[k][parent[k][v]];\n                }\n            }\n        }\n    }\n \n    int get_lca(int u, int v) {\n        if (depth[u] > depth[v]) {\n            swap(u, v);\n        }\n \n        for (int k = 0; k < log2_n; k++) {\n            if ((depth[v] - depth[u]) >> k & 1) {\n                v = parent[k][v];\n            }\n        }\n        if (u == v) {\n            return u;\n        }\n \n        for (int k = log2_n - 1; k >= 0; k--) {\n            if (parent[k][u] != parent[k][v]) {\n                u = parent[k][u];\n                v = parent[k][v];\n            }\n        }\n        return parent[0][u];\n    }\n \n    int get_depth(int v) { return depth[v]; }\n};\nclass DAG {\nprivate:\n    int n;\n    vector<vector<edge>> g;\n    vector<int> visited;\n    vector<int> dp;\n    vector<int> topological;\n \n    int dfs(int s) {\n        if ((int)g[s].size() == 0) {\n            return 1;\n        }\n        if (dp[s] > 0) {\n            return dp[s];\n        }\n \n        int mx = 1;\n        for (auto j : g[s]) {\n            if (visited[j.to] == 0) {\n                visited[j.to] = 1;\n                int l = 0;\n                l = dfs(j.to);\n                chmax(mx, l);\n            }\n            else {\n                chmax(mx, dp[j.to]);\n            }\n        }\n        return dp[s] = mx + 1;\n    }\n \npublic:\n    DAG(const vector<vector<edge>>& f) {\n        g = f;\n        n = f.size();\n        resize(visited, n + 1);\n        fill(visited.begin(), visited.end(), 0);\n        resize(dp, n + 1);\n        fill(dp.begin(), dp.end(), -1);\n        resize(topological, n);\n    }\n    DAG(int x) {\n        n = x;\n        resize(g, n);\n        resize(visited, n + 1);\n        fill(visited.begin(), visited.end(), 0);\n        resize(dp, n + 1);\n        fill(dp.begin(), dp.end(), -1);\n    }\n \n    void add_edge(int a, int b) { g[a].emplace_back(a, b); }\n    void add_edge(int a, int b, ll c) { g[a].emplace_back(a, b, c); }\n    void add_edge(int a, int b, ll c, ll d) { g[a].emplace_back(a, b, c, d); }\n \n    int longest_path() {\n        int mx = -1;\n        int res=0;\n        for (int i = 0; i < n; i++) {\n            int h = 0;\n            if (visited[i] == 0) {\n                h = dfs(i);\n                if(mx<h){\n                    mx=h;\n                    res=i;\n                }\n            }\n        }\n        return res;\n    }\n \n    bool TopologicalSort() {\n        int k = g.size();\n        vector<int> ord(n), in(n);\n        for (int i=0;i<n;i++) {\n            for (auto& e : g[i]) {\n                in[e.to]++;\n            }\n        }\n        priority_queue<int> q;\n        for (int i = 0; i < n; ++i) {\n            if (in[i] == 0) q.push(i);\n        }\n        while (!q.empty()) {\n            int v = q.top();\n            q.pop();\n            ord[v] = k;\n            k--;\n            for (auto& e : g[v]) {\n                in[e.to]-=1;\n                if (in[e.to] == 0) {\n                    q.push(e.to);\n                }\n            }\n        }\n        topological = ord;\n        if (*max_element(in.begin(), in.end()) == 0) {\n            return true;\n        }\n        return false;\n    }\n \n    vector<int> getTopologicalArray(){\n        return topological;\n    }\n};\n\n//↑ここまでGitHubに突っ込んだ\n\n\n\n\nclass RangeMinimumUpdateQuerySegmentTree {\nprivate:\n    int n;\n    ll inf = (1LL << 31) - 1;  // 2^31-1\n    vector<ll> dat, lazy;\n \n    void eval(int len, int k) {\n        if (lazy[k] == inf) return;\n        if (k * 2 + 1 < n * 2 - 1) {\n            lazy[2 * k + 1] = lazy[k];\n            lazy[2 * k + 2] = lazy[k];\n        }\n        dat[k] = lazy[k];\n        lazy[k] = inf;\n    }\n \npublic:\n    RangeMinimumUpdateQuerySegmentTree() {}\n    RangeMinimumUpdateQuerySegmentTree(int n_) {\n        n = 1;\n        while (n < n_) n *= 2;\n        dat.assign(n * 2, inf);\n        lazy.assign(n * 2, inf);\n    }\n \n    // [a,b)\n    ll update(int a, int b, ll x, int k, int l, int r) {\n        eval(r - l, k);\n        if (b <= l || r <= a) return dat[k];\n        if (a <= l && r <= b) {\n            lazy[k] = x;\n            return lazy[k];\n        }\n        return dat[k] = min(update(a, b, x, 2 * k + 1, l, (l + r) / 2),\n            update(a, b, x, 2 * k + 2, (l + r) / 2, r));\n    }\n    ll update(int a, int b, ll x) { return update(a, b, x, 0, 0, n); }\n \n    // [a, b)\n    ll query(int a, int b, int k, int l, int r) {\n        eval(r - l, k);\n        if (b <= l || r <= a) return inf;\n        if (a <= l && r <= b) return dat[k];\n        ll vl = query(a, b, 2 * k + 1, l, (l + r) / 2);\n        ll vr = query(a, b, 2 * k + 2, (l + r) / 2, r);\n        return min(vl, vr);\n    }\n    ll query(int a, int b) { return query(a, b, 0, 0, n); }\n};\nclass RangeSumQuerySegmentTree {\nprivate:\n    struct Node {\n        Node* left, * right;\n        ll v;\n \n        Node() : left(nullptr), right(nullptr), v(0) {}\n    };\n    Node* root;\n    ll n, n0;\n    ll query(ll a, ll b, Node* n, ll l, ll r) {\n        if (a <= l && r <= b) {\n            return n->v;\n        }\n        if (r <= a || b <= l) {\n            return 0;\n        }\n \n        ll lv = n->left ? query(a, b, n->left, l, (l + r) >> 1) : 0;\n        ll rv = n->right ? query(a, b, n->right, (l + r) >> 1, r) : 0;\n        return (lv + rv) % MOD;\n    }\n \npublic:\n    RangeSumQuerySegmentTree(ll n) : n(n) {\n        n0 = 1;\n        while (n0 < n) n0 <<= 1;\n        root = new Node();\n    }\n    ~RangeSumQuerySegmentTree() {\n        delete root;\n        root = nullptr;\n    }\n \n    void update(ll k, ll x) {\n        Node* n = root;\n        ll l = 0, r = n0;\n        n->v = (n->v + x) % MOD;\n        while (r - l > 1) {\n            ll m = (l + r) >> 1;\n            if (k < m) {\n                if (!n->left) n->left = new Node();\n                n = n->left;\n \n                r = m;\n            }\n            else {\n                if (!n->right) n->right = new Node();\n                n = n->right;\n \n                l = m;\n            }\n            n->v = (n->v + x) % MOD;\n        }\n    }\n \n    ll query(ll a, ll b) { return query(a, b, root, 0, n0); }\n \n    ll lquery(ll b) { return query(0, b, root, 0, n0); }\n \n    ll rquery(ll a) { return query(a, n0, root, 0, n0); }\n};\nclass KDimensionalTree {\npublic:\n    struct Node {\n        int location;\n        int p, l, r;\n        Node() {}\n    };\n    struct Point {\n        int id, x, y;\n        Point() {}\n        Point(int i, int a, int b) {\n            id = i;\n            x = a;\n            y = b;\n        }\n        bool operator<(const Point& p) const { return id < p.id; }\n        void print() { cout << id << endl; }\n    };\n    static const ll NIL = -1;\n    static bool lessX(const Point& p1, const Point& p2) { return p1.x < p2.x; }\n    static bool lessY(const Point& p1, const Point& p2) { return p1.y < p2.y; }\n \n    int N;\n    vector<Point> P;\n    vector<Node> T;\n    int np;\n \n    KDimensionalTree() {}\n    KDimensionalTree(int N) { init(N); }\n \n    void init(int n) {\n        N = n;\n        P.clear();\n        T.clear();\n        resize(P, N);\n        resize(T, N);\n        np = 0;\n    }\n \n    int makeKDTree(int l, int r, int depth) {\n        if (l >= r) {\n            return NIL;\n        }\n        int mid = (l + r) / 2;\n        int t = np++;\n        if (depth & 1) {\n            sort(P.begin() + l, P.begin() + r, lessY);\n        }\n        else {\n            sort(P.begin() + l, P.begin() + r, lessX);\n        }\n        T[t].location = mid;\n        T[t].l = makeKDTree(l, mid, depth + 1);\n        T[t].r = makeKDTree(mid + 1, r, depth + 1);\n        return t;\n    }\n    void find(int v, int sx, int tx, int sy, int ty, int depth,\n        vector<Point>& ans) {\n        int x = P[T[v].location].x;\n        int y = P[T[v].location].y;\n        if (sx <= x && x <= tx && sy <= y && y <= ty) {\n            ans.push_back(P[T[v].location]);\n        }\n        if (depth % 2 == 0) {\n            if (T[v].l != NIL) {\n                if (sx <= x) find(T[v].l, sx, tx, sy, ty, depth + 1, ans);\n            }\n            if (T[v].r != NIL) {\n                if (x <= tx) find(T[v].r, sx, tx, sy, ty, depth + 1, ans);\n            }\n        }\n        else {\n            if (T[v].l != NIL) {\n                if (sy <= y) find(T[v].l, sx, tx, sy, ty, depth + 1, ans);\n            }\n            if (T[v].r != NIL) {\n                if (y <= ty) find(T[v].r, sx, tx, sy, ty, depth + 1, ans);\n            }\n        }\n    }\n    void add_point(int i, int x, int y) {\n        P[i].id = i;\n        P[i].x = x;\n        P[i].y = y;\n        T[i].l = T[i].r = T[i].p = NIL;\n    }\n};\nclass RangeAddQuerySegmentTree {\nprivate:\n    int n;\n    vector<ll> data;\n \npublic:\n    RangeAddQuerySegmentTree() {}\n    RangeAddQuerySegmentTree(int N) {\n        n = N;\n        resize(data, n + 1);\n        fill(data.begin(), data.end(), 0);\n    }\n \n    void add(int i, ll x) {\n        while (i) {\n            data[i] += x;\n            i -= (i & -i);\n        }\n    }\n    void add(int i, int j, ll x) {\n        add(j, x);\n        add(i - 1, -x);\n    }\n \n    ll get(int i) {\n        ll res = 0;\n        while (i <= n) {\n            res += data[i];\n            i += (i & -i);\n        }\n        return res;\n    }\n};\nclass RangeSumAddQuerySegmentTree {\nprivate:\n    vector<ll> bit0, bit1;\n    int n;\n \n    ll sum(const vector<ll>& b, int i) {\n        ll s = 0;\n        while (i > 0) {\n            s += b[i];\n            i -= (i & -i);\n        }\n        return s;\n    }\n \n    void add(vector<ll>& b, int i, ll v) {\n        while (i <= n) {\n            b[i] += v;\n            i += (i & -i);\n        }\n    }\n \npublic:\n    RangeSumAddQuerySegmentTree() {}\n    RangeSumAddQuerySegmentTree(int N) {\n        n = N;\n        resize(bit0, n + 1);\n        resize(bit1, n + 1);\n        fill(bit0.begin(), bit0.end(), 0);\n        fill(bit1.begin(), bit1.end(), 0);\n    }\n \n    void update(int l, int r, ll x) {\n        add(bit0, l, -x * (l - 1));\n        add(bit1, l, x);\n        add(bit0, r + 1, x * r);\n        add(bit1, r + 1, -x);\n    }\n \n    ll query(int l, int r) {\n        ll res = 0;\n        res += sum(bit0, r) + sum(bit1, r) * r;\n        res -= sum(bit0, l - 1) + sum(bit1, l - 1) * (l - 1);\n        return res;\n    }\n};\n\n\nlong double cross(const complex<long double> &a, const complex<long double> &b) { return a.real() * b.imag() - a.imag() * b.real(); }\nlong double dot(const complex<long double> &a, const complex<long double> &b) { return a.real() * b.real() + a.imag() * b.imag(); }\n\npair<long double,complex<long double>> smallest_enclosing_disc(vector<complex<long double>> ps){\n    const long double pi = 3.1415926535897932384626;\n    static const long double eps = 1e-10;\n    static const long double inf = 1e12;\n\n    using circle = pair<complex<long double>, long double>;\n\n    auto c3 = [](const complex<long double> &a, const complex<long double> &b, const complex<long double> &c){\n        long double A = norm(b - c);\n        long double B = norm(c - a);\n        long double C = norm(a - b);\n        long double S = abs(cross(b - a, c - a));\n        complex<long double> p = (A*(B+C-A)*a + B*(C+A-B)*b + C*(A+B-C)*c) / (4*S*S);\n        long double r = abs(p - a);\n        return make_pair(r, p);\n    };\n\n    auto c2 = [](const complex<long double> &a, const complex<long double> &b){\n        complex<long double> c = (a + b) / (long double)2;\n        long double r = abs(a - c);\n        return make_pair(r, c);\n    };\n\n    auto in_circle = [](const complex<long double> &a, const pair<long double, complex<long double>> &c){\n        return norm(a - c.second) <= c.first*c.first + eps;\n    };\n\n    int n = ps.size();\n    random_shuffle(ps.begin(), ps.end());\n    pair<long double, complex<long double>> c = c2(ps[0], ps[1]);\n    for(int i = 2; i < n; ++i){\n        if(!in_circle(ps[i], c)){\n            c = c2(ps[0], ps[i]);\n            for(int j = 1; j < i; ++j){\n                if(!in_circle(ps[j], c)){\n                    c = c2(ps[j], ps[i]);\n                    for(int k = 0; k < j; ++k){\n                        if(!in_circle(ps[k], c)){\n                            c = c3(ps[i], ps[j], ps[k]);\n                        }\n                    }\n                }\n            }\n        }\n    }\n    return c;\n}\n\npair<ll, vector<edge>> Prim_minimumSpanningTree(const vector<vector<edge>> &g, int r,int K) {\n  int n = g.size();\n  vector<edge> T;\n  ll total = 0;\n\n  vector<bool> visited(n);\n  priority_queue<edge> Q;\n  Q.push( edge(-1, r, 0,0));\n  ll ans=0;\n  int k=0;\n  while (!Q.empty()) {\n    edge e = Q.top(); Q.pop();\n    if (visited[e.to]) continue;\n    T.push_back(e);\n    total += e.cost;\n    ans=max(ans,-e.cost);\n    k++;\n    if(k==K){\n        break;\n    }\n    visited[e.to] = true;\n    for(auto f:g[e.to]) if (!visited[f.to]) Q.push(f);\n  }\n  return pair<ll, vector<edge>>(ans, T);\n}\n\n\n\nclass NodeTwoColoring{\n    private:\n        vector<vector<edge>> G;\n        vector<int> visited;\n        vector<int> white;\n        vector<int> black;\n        \n        void dfs(const vector<vector<edge>> &G,int v=0, ll d=0) { \n            if(d & 1){white.push_back(v+1);}\n            else{black.push_back(v+1);}\n            visited[v]=1+(d&1);\n \n\t        for (auto nv : G[v]) {\n\t\t        if (visited[nv.to]==-1){}\n                else{\n                    continue;\n                }\n\t\t        dfs(G,nv.to,d+nv.cost);\n\t        }\n        }\n        \n    public:\n    NodeTwoColoring(){};\n    NodeTwoColoring(const vector<vector<edge>> &g):G(g){\n        int n=G.size();\n        visited.resize(n,-1);\n        dfs(G);\n    };\n \n    vector<int> get_white(){\n        return white;\n    }\n    vector<int> get_black(){\n        return black;\n    }\n\n    vector<int> get_color(){\n        return visited;\n    }\n \n};\n\n/*\nconst int MAX = 510000;\nlong long fac[MAX], finv[MAX], inv[MAX];\n\nvoid COMinit() {\n    fac[0] = fac[1] = 1;\n    finv[0] = finv[1] = 1;\n    inv[1] = 1;\n    for (int i = 2; i < MAX; i++){\n        fac[i] = fac[i - 1] * i % MOD;\n        inv[i] = MOD - inv[MOD%i] * (MOD / i) % MOD;\n        finv[i] = finv[i - 1] * inv[i] % MOD;\n    }\n}\n\nlong long COM(int n, int k){\n    if (n < k) return 0;\n    if (n < 0 || k < 0) return 0;\n    return fac[n] * (finv[k] * finv[n - k] % MOD) % MOD;\n}\n*/\n\n\nint main() {\n    ll x;cin>>x;\n\n    for(ll i=-5000;i<=5000;i++){\n        for(ll j=-5000;j<=5000;j++){\n            if(i*i*i*i*i-(j*j*j*j*j)==x){\n                cout<<i<<\" \"<<j<<endl;\n                return 0;\n            }\n        }\n    }\n\n    ;\n    return 0;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nGive a pair of integers (A, B) such that A^5-B^5 = X.\nIt is guaranteed that there exists such a pair for the given integer X.\n\nConstraints\n\n1 \\leq X \\leq 10^9\n\nX is an integer.\n\nThere exists a pair of integers (A, B) satisfying the condition in Problem Statement.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint A and B, with space in between.\nIf there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.\n\nA B\n\nSample Input 1\n\n33\n\nSample Output 1\n\n2 -1\n\nFor A=2 and B=-1, A^5-B^5 = 33.\n\nSample Input 2\n\n1\n\nSample Output 2\n\n0 -1", "sample_input": "33\n"}, "reference_outputs": ["2 -1\n"], "source_document_id": "p02690", "source_text": "Score : 400 points\n\nProblem Statement\n\nGive a pair of integers (A, B) such that A^5-B^5 = X.\nIt is guaranteed that there exists such a pair for the given integer X.\n\nConstraints\n\n1 \\leq X \\leq 10^9\n\nX is an integer.\n\nThere exists a pair of integers (A, B) satisfying the condition in Problem Statement.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint A and B, with space in between.\nIf there are multiple pairs of integers (A, B) satisfying the condition, you may print any of them.\n\nA B\n\nSample Input 1\n\n33\n\nSample Output 1\n\n2 -1\n\nFor A=2 and B=-1, A^5-B^5 = 33.\n\nSample Input 2\n\n1\n\nSample Output 2\n\n0 -1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 39778, "cpu_time_ms": 54, "memory_kb": 3708}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s253950378", "group_id": "codeNet:p02691", "input_text": "#include <bits/stdc++.h>\n#define REP(i,n) for (int i = 0; i < (n); i++)\n#define RREP(i, s, n) for (int i = s; i < (n); i++)\n#define ALL(a) a.begin(), a.end()\n#define RALL(a) a.rbegin(), a.rend()\ntemplate<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }\nusing namespace std;\nusing ll = long long;\ntypedef pair<int, int> pint;\ntypedef pair<ll, ll> pll;\nconst ll MOD = 1000000007;\nconst ll INF = MOD * MOD;\nconst int inf = (1<<29);\n\nint main() {\n\n    int n;\n    cin >> n;\n    vector<int> a(n);\n    REP(i, n) cin >> a[i];\n    \n    int res = 0;\n\n    for(int i = 0; i < n; i++) {\n        for(int j = i+1; j < n; j++) {\n            if (abs(i-j) == a[i] + a[j]) res++;\n        }\n    }\n\n    cout << res << endl;\n    \n    return 0;\n}", "language": "C++", "metadata": {"date": 1596121141, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02691.html", "problem_id": "p02691", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02691/input.txt", "sample_output_relpath": "derived/input_output/data/p02691/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02691/C++/s253950378.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s253950378", "user_id": "u538125576"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define REP(i,n) for (int i = 0; i < (n); i++)\n#define RREP(i, s, n) for (int i = s; i < (n); i++)\n#define ALL(a) a.begin(), a.end()\n#define RALL(a) a.rbegin(), a.rend()\ntemplate<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }\nusing namespace std;\nusing ll = long long;\ntypedef pair<int, int> pint;\ntypedef pair<ll, ll> pll;\nconst ll MOD = 1000000007;\nconst ll INF = MOD * MOD;\nconst int inf = (1<<29);\n\nint main() {\n\n    int n;\n    cin >> n;\n    vector<int> a(n);\n    REP(i, n) cin >> a[i];\n    \n    int res = 0;\n\n    for(int i = 0; i < n; i++) {\n        for(int j = i+1; j < n; j++) {\n            if (abs(i-j) == a[i] + a[j]) res++;\n        }\n    }\n\n    cout << res << endl;\n    \n    return 0;\n}", "problem_context": "Score: 500 points\n\nProblem Statement\n\nYou are the top spy of AtCoder Kingdom. To prevent the stolen secret from being handed to AlDebaran Kingdom, you have sneaked into the party where the transaction happens.\n\nThere are N attendees in the party, and they are given attendee numbers from 1 through N. The height of Attendee i is A_i.\n\nAccording to an examination beforehand, you know that a pair of attendees satisfying the condition below will make the transaction.\n\nThe absolute difference of their attendee numbers is equal to the sum of their heights.\n\nThere are \\frac{N(N-1)}{2} ways to choose two from the N attendees and make a pair. Among them, how many satisfy the condition above?\n\nP.S.: We cannot let you know the secret.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq A_i \\leq 10^9\\ (1 \\leq i \\leq N)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 \\dots A_N\n\nOutput\n\nPrint the number of pairs satisfying the condition.\n\nSample Input 1\n\n6\n2 3 3 1 3 1\n\nSample Output 1\n\n3\n\nA_1 + A_4 = 3, so the pair of Attendee 1 and 4 satisfy the condition.\n\nA_2 + A_6 = 4, so the pair of Attendee 2 and 6 satisfy the condition.\n\nA_4 + A_6 = 2, so the pair of Attendee 4 and 6 satisfy the condition.\n\nNo other pair satisfies the condition, so you should print 3.\n\nSample Input 2\n\n6\n5 2 4 2 8 8\n\nSample Output 2\n\n0\n\nNo pair satisfies the condition, so you should print 0.\n\nSample Input 3\n\n32\n3 1 4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5\n\nSample Output 3\n\n22", "sample_input": "6\n2 3 3 1 3 1\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02691", "source_text": "Score: 500 points\n\nProblem Statement\n\nYou are the top spy of AtCoder Kingdom. To prevent the stolen secret from being handed to AlDebaran Kingdom, you have sneaked into the party where the transaction happens.\n\nThere are N attendees in the party, and they are given attendee numbers from 1 through N. The height of Attendee i is A_i.\n\nAccording to an examination beforehand, you know that a pair of attendees satisfying the condition below will make the transaction.\n\nThe absolute difference of their attendee numbers is equal to the sum of their heights.\n\nThere are \\frac{N(N-1)}{2} ways to choose two from the N attendees and make a pair. Among them, how many satisfy the condition above?\n\nP.S.: We cannot let you know the secret.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq A_i \\leq 10^9\\ (1 \\leq i \\leq N)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 \\dots A_N\n\nOutput\n\nPrint the number of pairs satisfying the condition.\n\nSample Input 1\n\n6\n2 3 3 1 3 1\n\nSample Output 1\n\n3\n\nA_1 + A_4 = 3, so the pair of Attendee 1 and 4 satisfy the condition.\n\nA_2 + A_6 = 4, so the pair of Attendee 2 and 6 satisfy the condition.\n\nA_4 + A_6 = 2, so the pair of Attendee 4 and 6 satisfy the condition.\n\nNo other pair satisfies the condition, so you should print 3.\n\nSample Input 2\n\n6\n5 2 4 2 8 8\n\nSample Output 2\n\n0\n\nNo pair satisfies the condition, so you should print 0.\n\nSample Input 3\n\n32\n3 1 4 1 5 9 2 6 5 3 5 8 9 7 9 3 2 3 8 4 6 2 6 4 3 3 8 3 2 7 9 5\n\nSample Output 3\n\n22", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 851, "cpu_time_ms": 2205, "memory_kb": 4188}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s450250619", "group_id": "codeNet:p02692", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n  int n; cin >> n;\n  vector<int> v(3);\n  vector<char> ans(n);\n  int ind=0;\n  cin >> v[0] >> v[1] >> v[2];\n  int t=v[0]+v[1]+v[2];\n  bool ok=1;\n  while (n--) {\n    string s; cin >> s;\n    if (!ok) continue;\n    if (!v[s[0]-'A'] && !v[s[1]-'A']) {\n      ok=0;\n      continue;\n    }\n    if (!v[s[0]-'A']) v[s[0]-'A']++, v[s[1]-'A']--, ans[ind++]=s[0];\n    else if (!v[s[1]-'A']) v[s[1]-'A']++, v[s[0]-'A']--, ans[ind++]=s[1];\n    else {\n      if (t == 2) {\n        string c=\"#\";\n        if (n--) {\n          cin >> c;\n        }\n        if (c != \"#\") {\n          if (s[0] == c[0] || s[0] == c[1])\n            v[s[0]-'A']++, v[s[1]-'A']--, ans[ind++]=s[0];\n          else\n            v[s[1]-'A']++, v[s[0]-'A']--, ans[ind++]=s[1];\n        }\n        else \n          v[s[0]-'A']++, v[s[1]-'A']--, ans[ind++]=s[0];\n      }\n      else {\n        if (v[s[1]-'A'] == t-1)\n          v[s[0]-'A']++, v[s[1]-'A']--, ans[ind++]=s[0];\n        else\n          v[s[1]-'A']++, v[s[0]-'A']--, ans[ind++]=s[1];\n      }\n    }\n  }\n  if (n == 0 || !ok) cout << \"No\";\n  else {\n    cout << \"Yes\\n\";\n    for (char c : ans)\n      cout << c << \"\\n\";\n  }\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1591533695, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02692.html", "problem_id": "p02692", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02692/input.txt", "sample_output_relpath": "derived/input_output/data/p02692/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02692/C++/s450250619.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s450250619", "user_id": "u376415869"}, "prompt_components": {"gold_output": "Yes\nA\nC\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n  int n; cin >> n;\n  vector<int> v(3);\n  vector<char> ans(n);\n  int ind=0;\n  cin >> v[0] >> v[1] >> v[2];\n  int t=v[0]+v[1]+v[2];\n  bool ok=1;\n  while (n--) {\n    string s; cin >> s;\n    if (!ok) continue;\n    if (!v[s[0]-'A'] && !v[s[1]-'A']) {\n      ok=0;\n      continue;\n    }\n    if (!v[s[0]-'A']) v[s[0]-'A']++, v[s[1]-'A']--, ans[ind++]=s[0];\n    else if (!v[s[1]-'A']) v[s[1]-'A']++, v[s[0]-'A']--, ans[ind++]=s[1];\n    else {\n      if (t == 2) {\n        string c=\"#\";\n        if (n--) {\n          cin >> c;\n        }\n        if (c != \"#\") {\n          if (s[0] == c[0] || s[0] == c[1])\n            v[s[0]-'A']++, v[s[1]-'A']--, ans[ind++]=s[0];\n          else\n            v[s[1]-'A']++, v[s[0]-'A']--, ans[ind++]=s[1];\n        }\n        else \n          v[s[0]-'A']++, v[s[1]-'A']--, ans[ind++]=s[0];\n      }\n      else {\n        if (v[s[1]-'A'] == t-1)\n          v[s[0]-'A']++, v[s[1]-'A']--, ans[ind++]=s[0];\n        else\n          v[s[1]-'A']++, v[s[0]-'A']--, ans[ind++]=s[1];\n      }\n    }\n  }\n  if (n == 0 || !ok) cout << \"No\";\n  else {\n    cout << \"Yes\\n\";\n    for (char c : ans)\n      cout << c << \"\\n\";\n  }\n  return 0;\n}\n", "problem_context": "Score : 600 points\n\nProblem Statement\n\nThere is a game that involves three variables, denoted A, B, and C.\n\nAs the game progresses, there will be N events where you are asked to make a choice.\nEach of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.\n\nAfter each choice, none of A, B, and C should be negative.\n\nDetermine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n0 \\leq A,B,C \\leq 10^9\n\nN, A, B, C are integers.\n\ns_i is AB, AC, or BC.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN A B C\ns_1\ns_2\n:\ns_N\n\nOutput\n\nIf it is possible to make N choices under the condition, print Yes; otherwise, print No.\n\nAlso, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.\n\nSample Input 1\n\n2 1 3 0\nAB\nAC\n\nSample Output 1\n\nYes\nA\nC\n\nYou can successfully make two choices, as follows:\n\nIn the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.\n\nIn the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.\n\nSample Input 2\n\n3 1 0 0\nAB\nBC\nAB\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n1 0 9 0\nAC\n\nSample Output 3\n\nNo\n\nSample Input 4\n\n8 6 9 1\nAC\nBC\nAB\nBC\nAC\nBC\nAB\nAB\n\nSample Output 4\n\nYes\nC\nB\nB\nC\nC\nB\nA\nA", "sample_input": "2 1 3 0\nAB\nAC\n"}, "reference_outputs": ["Yes\nA\nC\n"], "source_document_id": "p02692", "source_text": "Score : 600 points\n\nProblem Statement\n\nThere is a game that involves three variables, denoted A, B, and C.\n\nAs the game progresses, there will be N events where you are asked to make a choice.\nEach of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.\n\nAfter each choice, none of A, B, and C should be negative.\n\nDetermine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n0 \\leq A,B,C \\leq 10^9\n\nN, A, B, C are integers.\n\ns_i is AB, AC, or BC.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN A B C\ns_1\ns_2\n:\ns_N\n\nOutput\n\nIf it is possible to make N choices under the condition, print Yes; otherwise, print No.\n\nAlso, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.\n\nSample Input 1\n\n2 1 3 0\nAB\nAC\n\nSample Output 1\n\nYes\nA\nC\n\nYou can successfully make two choices, as follows:\n\nIn the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.\n\nIn the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.\n\nSample Input 2\n\n3 1 0 0\nAB\nBC\nAB\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n1 0 9 0\nAC\n\nSample Output 3\n\nNo\n\nSample Input 4\n\n8 6 9 1\nAC\nBC\nAB\nBC\nAC\nBC\nAB\nAB\n\nSample Output 4\n\nYes\nC\nB\nB\nC\nC\nB\nA\nA", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1196, "cpu_time_ms": 26, "memory_kb": 3708}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s447744827", "group_id": "codeNet:p02692", "input_text": "#include <iomanip>\n#include <cstdio>\n#include <cstdlib>\n#include <cmath>\n#include <climits>\n#include <cassert>\n#include <iostream>\n#include <string>\n#include <stack>\n#include <queue>\n#include <vector>\n#include <map>\n#include <set>\n#include <algorithm>\n#include <numeric>\n#include <sstream>\n#include <bitset>\n#define repr(i,a,b) for(int i=a;i<b;i++)\n#define rep(i,n) for(int i=0;i<n;i++)\n#define invrepr(i,a,b) for(int i=b-1;i>=a;i--)\n#define invrep(i,n) invrepr(i,0,n)\n \nusing namespace std;\ntypedef long long ll;\nconst ll MOD=1e9+7;\n \nint main() {\n    std::ios::sync_with_stdio(0); cin.tie(0);\n \n    ll i,j,h;\n    ll Q,M,K,P,A,B,C,N,X;\n \n    long double x;\n \n    string S;\n \n    ll ans=0;\n    ll count=0;\n    ll flag=0;\n    ll temp=0;\n    vector<char> kotae;\n    vector<string> ss;\n    ll a,b;\n    cin >>N>>A>>B>>C;\n\nrep(i,N){\n  cin>>S;\n  ss.push_back(S);\n}\n//cout<<\"aa\"<<endl;\nmap <char,ll> mm;\nmm['B']=B;\nmm['A']=A;\nmm['C']=C;\n//cout<<0;\nif(A+B+C==0){\n  cout<<\"No\"<<endl;\n  return 0;\n}else if(A+B+C==1){\n  rep(i,N){\n  \tif(mm[ss[i][0]]==0 && mm[ss[i][1]]==0){\n      cout << \"No\"<<endl;\n      return 0;\n    }else if (mm[ss[i][0]]==0){\n      mm[ss[i][0]]++;\n      mm[ss[i][1]]--;\n      kotae.push_back(ss[i][0]);\n    }else{\n      mm[ss[i][0]]--;\n      mm[ss[i][1]]++;\n      kotae.push_back(ss[i][1]);\n    }\n  }\n}else{\n    //cout<<\"ee\"<<endl;\n    //cout<<ss[i][0<<ss[i][1]<<endl;\n    \n\tif(mm[ss[0][0]]==0 && mm[ss[0][1]]==0){\n        cout<<\"No\"<<endl;\n        return 0;\n    }else{\n        \n        rep(i,N){\n            \n            if(mm[ss[i][0]]==0){\n                mm[ss[i][0]]++;\n                mm[ss[i][1]]--;\n                kotae.push_back(ss[i][0]);\n            }else if(mm[ss[i][1]]==0){\n                mm[ss[i][1]]++;\n                mm[ss[i][0]]--;\n                kotae.push_back(ss[i][1]);\n            }else if(i!=N-1 && (mm[ss[i][0]]==1 || mm[ss[i][1]]==1)){\n                if(ss[i+1][0]==ss[i][0] || ss[i+1][1]==ss[i][0] ){\n                    mm[ss[i][1]]--;\n                    mm[ss[i][0]]++;\n                    kotae.push_back(ss[i][0]);\n                    \n\n                }else{\n                    mm[ss[i][1]]++;\n                    mm[ss[i][0]]--;\n                    kotae.push_back(ss[i][1]);\n                }\n            \n            }else{\n                mm[ss[i][0]]--;\n                mm[ss[i][1]]++;\n                kotae.push_back(ss[i][1]);\n            }\n        }\n\n\n    }\n}\n \n\ncout<<\"Yes\"<<endl;\nrep(i,N){\n    cout<<kotae[i]<<endl;\n}\n \n    return 0;\n}", "language": "C++", "metadata": {"date": 1588550319, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02692.html", "problem_id": "p02692", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02692/input.txt", "sample_output_relpath": "derived/input_output/data/p02692/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02692/C++/s447744827.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s447744827", "user_id": "u924153316"}, "prompt_components": {"gold_output": "Yes\nA\nC\n", "input_to_evaluate": "#include <iomanip>\n#include <cstdio>\n#include <cstdlib>\n#include <cmath>\n#include <climits>\n#include <cassert>\n#include <iostream>\n#include <string>\n#include <stack>\n#include <queue>\n#include <vector>\n#include <map>\n#include <set>\n#include <algorithm>\n#include <numeric>\n#include <sstream>\n#include <bitset>\n#define repr(i,a,b) for(int i=a;i<b;i++)\n#define rep(i,n) for(int i=0;i<n;i++)\n#define invrepr(i,a,b) for(int i=b-1;i>=a;i--)\n#define invrep(i,n) invrepr(i,0,n)\n \nusing namespace std;\ntypedef long long ll;\nconst ll MOD=1e9+7;\n \nint main() {\n    std::ios::sync_with_stdio(0); cin.tie(0);\n \n    ll i,j,h;\n    ll Q,M,K,P,A,B,C,N,X;\n \n    long double x;\n \n    string S;\n \n    ll ans=0;\n    ll count=0;\n    ll flag=0;\n    ll temp=0;\n    vector<char> kotae;\n    vector<string> ss;\n    ll a,b;\n    cin >>N>>A>>B>>C;\n\nrep(i,N){\n  cin>>S;\n  ss.push_back(S);\n}\n//cout<<\"aa\"<<endl;\nmap <char,ll> mm;\nmm['B']=B;\nmm['A']=A;\nmm['C']=C;\n//cout<<0;\nif(A+B+C==0){\n  cout<<\"No\"<<endl;\n  return 0;\n}else if(A+B+C==1){\n  rep(i,N){\n  \tif(mm[ss[i][0]]==0 && mm[ss[i][1]]==0){\n      cout << \"No\"<<endl;\n      return 0;\n    }else if (mm[ss[i][0]]==0){\n      mm[ss[i][0]]++;\n      mm[ss[i][1]]--;\n      kotae.push_back(ss[i][0]);\n    }else{\n      mm[ss[i][0]]--;\n      mm[ss[i][1]]++;\n      kotae.push_back(ss[i][1]);\n    }\n  }\n}else{\n    //cout<<\"ee\"<<endl;\n    //cout<<ss[i][0<<ss[i][1]<<endl;\n    \n\tif(mm[ss[0][0]]==0 && mm[ss[0][1]]==0){\n        cout<<\"No\"<<endl;\n        return 0;\n    }else{\n        \n        rep(i,N){\n            \n            if(mm[ss[i][0]]==0){\n                mm[ss[i][0]]++;\n                mm[ss[i][1]]--;\n                kotae.push_back(ss[i][0]);\n            }else if(mm[ss[i][1]]==0){\n                mm[ss[i][1]]++;\n                mm[ss[i][0]]--;\n                kotae.push_back(ss[i][1]);\n            }else if(i!=N-1 && (mm[ss[i][0]]==1 || mm[ss[i][1]]==1)){\n                if(ss[i+1][0]==ss[i][0] || ss[i+1][1]==ss[i][0] ){\n                    mm[ss[i][1]]--;\n                    mm[ss[i][0]]++;\n                    kotae.push_back(ss[i][0]);\n                    \n\n                }else{\n                    mm[ss[i][1]]++;\n                    mm[ss[i][0]]--;\n                    kotae.push_back(ss[i][1]);\n                }\n            \n            }else{\n                mm[ss[i][0]]--;\n                mm[ss[i][1]]++;\n                kotae.push_back(ss[i][1]);\n            }\n        }\n\n\n    }\n}\n \n\ncout<<\"Yes\"<<endl;\nrep(i,N){\n    cout<<kotae[i]<<endl;\n}\n \n    return 0;\n}", "problem_context": "Score : 600 points\n\nProblem Statement\n\nThere is a game that involves three variables, denoted A, B, and C.\n\nAs the game progresses, there will be N events where you are asked to make a choice.\nEach of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.\n\nAfter each choice, none of A, B, and C should be negative.\n\nDetermine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n0 \\leq A,B,C \\leq 10^9\n\nN, A, B, C are integers.\n\ns_i is AB, AC, or BC.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN A B C\ns_1\ns_2\n:\ns_N\n\nOutput\n\nIf it is possible to make N choices under the condition, print Yes; otherwise, print No.\n\nAlso, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.\n\nSample Input 1\n\n2 1 3 0\nAB\nAC\n\nSample Output 1\n\nYes\nA\nC\n\nYou can successfully make two choices, as follows:\n\nIn the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.\n\nIn the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.\n\nSample Input 2\n\n3 1 0 0\nAB\nBC\nAB\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n1 0 9 0\nAC\n\nSample Output 3\n\nNo\n\nSample Input 4\n\n8 6 9 1\nAC\nBC\nAB\nBC\nAC\nBC\nAB\nAB\n\nSample Output 4\n\nYes\nC\nB\nB\nC\nC\nB\nA\nA", "sample_input": "2 1 3 0\nAB\nAC\n"}, "reference_outputs": ["Yes\nA\nC\n"], "source_document_id": "p02692", "source_text": "Score : 600 points\n\nProblem Statement\n\nThere is a game that involves three variables, denoted A, B, and C.\n\nAs the game progresses, there will be N events where you are asked to make a choice.\nEach of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.\n\nAfter each choice, none of A, B, and C should be negative.\n\nDetermine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n0 \\leq A,B,C \\leq 10^9\n\nN, A, B, C are integers.\n\ns_i is AB, AC, or BC.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN A B C\ns_1\ns_2\n:\ns_N\n\nOutput\n\nIf it is possible to make N choices under the condition, print Yes; otherwise, print No.\n\nAlso, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.\n\nSample Input 1\n\n2 1 3 0\nAB\nAC\n\nSample Output 1\n\nYes\nA\nC\n\nYou can successfully make two choices, as follows:\n\nIn the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.\n\nIn the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.\n\nSample Input 2\n\n3 1 0 0\nAB\nBC\nAB\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n1 0 9 0\nAC\n\nSample Output 3\n\nNo\n\nSample Input 4\n\n8 6 9 1\nAC\nBC\nAB\nBC\nAC\nBC\nAB\nAB\n\nSample Output 4\n\nYes\nC\nB\nB\nC\nC\nB\nA\nA", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2494, "cpu_time_ms": 150, "memory_kb": 7452}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s475108541", "group_id": "codeNet:p02692", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n#define rep(i,n) for (int i = 0; i < (n); ++i)\n#define INF (1LL<<50)\n#define MOD 1000000007\n\nint main(){\n    int N,A,B,C,D;\n    cin >> N >> A >> B >> C;\n    vector<string> S(N);\n    rep(i,N){\n        cin >> S[i];\n    }\n    bool flg = true;\n    rep(i,N){\n        if(S[i]==\"AB\"){\n            if(A<B){\n                A++;\n                B--;\n            }else{\n                A--;B++;\n            }\n        }else if(S[i]==\"AC\"){\n            if(A<C){\n                A++;C--;\n            }else{\n                A--;C++;\n            }\n        }else{\n            if(B<C){\n                B++;C--;\n            }else{\n                B--;C++;\n            }\n        }\n        if(A*B*C<0) {\n            flg=false;\n            break;\n        }\n    }\n    if(flg){\n        cout << \"Yes\" << endl;\n        rep(i,N){\n        if(S[i]==\"AB\"){\n            if(A<B){\n                cout << \"A\" << endl;\n            }else{\n                cout << \"B\" << endl;\n            }\n        }else if(S[i]==\"AC\"){\n            if(A<C){\n                cout << \"A\" << endl;\n            }else{\n                cout << \"C\" << endl;\n            }\n        }else{\n            if(B<C){\n                cout << \"B\" << endl;\n            }else{\n                cout << \"C\" << endl;\n            }\n        }}\n    }else{\n        cout << \"No\" << endl;\n    }\n    return 0;\n}", "language": "C++", "metadata": {"date": 1588538288, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02692.html", "problem_id": "p02692", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02692/input.txt", "sample_output_relpath": "derived/input_output/data/p02692/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02692/C++/s475108541.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s475108541", "user_id": "u870092796"}, "prompt_components": {"gold_output": "Yes\nA\nC\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n#define rep(i,n) for (int i = 0; i < (n); ++i)\n#define INF (1LL<<50)\n#define MOD 1000000007\n\nint main(){\n    int N,A,B,C,D;\n    cin >> N >> A >> B >> C;\n    vector<string> S(N);\n    rep(i,N){\n        cin >> S[i];\n    }\n    bool flg = true;\n    rep(i,N){\n        if(S[i]==\"AB\"){\n            if(A<B){\n                A++;\n                B--;\n            }else{\n                A--;B++;\n            }\n        }else if(S[i]==\"AC\"){\n            if(A<C){\n                A++;C--;\n            }else{\n                A--;C++;\n            }\n        }else{\n            if(B<C){\n                B++;C--;\n            }else{\n                B--;C++;\n            }\n        }\n        if(A*B*C<0) {\n            flg=false;\n            break;\n        }\n    }\n    if(flg){\n        cout << \"Yes\" << endl;\n        rep(i,N){\n        if(S[i]==\"AB\"){\n            if(A<B){\n                cout << \"A\" << endl;\n            }else{\n                cout << \"B\" << endl;\n            }\n        }else if(S[i]==\"AC\"){\n            if(A<C){\n                cout << \"A\" << endl;\n            }else{\n                cout << \"C\" << endl;\n            }\n        }else{\n            if(B<C){\n                cout << \"B\" << endl;\n            }else{\n                cout << \"C\" << endl;\n            }\n        }}\n    }else{\n        cout << \"No\" << endl;\n    }\n    return 0;\n}", "problem_context": "Score : 600 points\n\nProblem Statement\n\nThere is a game that involves three variables, denoted A, B, and C.\n\nAs the game progresses, there will be N events where you are asked to make a choice.\nEach of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.\n\nAfter each choice, none of A, B, and C should be negative.\n\nDetermine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n0 \\leq A,B,C \\leq 10^9\n\nN, A, B, C are integers.\n\ns_i is AB, AC, or BC.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN A B C\ns_1\ns_2\n:\ns_N\n\nOutput\n\nIf it is possible to make N choices under the condition, print Yes; otherwise, print No.\n\nAlso, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.\n\nSample Input 1\n\n2 1 3 0\nAB\nAC\n\nSample Output 1\n\nYes\nA\nC\n\nYou can successfully make two choices, as follows:\n\nIn the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.\n\nIn the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.\n\nSample Input 2\n\n3 1 0 0\nAB\nBC\nAB\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n1 0 9 0\nAC\n\nSample Output 3\n\nNo\n\nSample Input 4\n\n8 6 9 1\nAC\nBC\nAB\nBC\nAC\nBC\nAB\nAB\n\nSample Output 4\n\nYes\nC\nB\nB\nC\nC\nB\nA\nA", "sample_input": "2 1 3 0\nAB\nAC\n"}, "reference_outputs": ["Yes\nA\nC\n"], "source_document_id": "p02692", "source_text": "Score : 600 points\n\nProblem Statement\n\nThere is a game that involves three variables, denoted A, B, and C.\n\nAs the game progresses, there will be N events where you are asked to make a choice.\nEach of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.\n\nAfter each choice, none of A, B, and C should be negative.\n\nDetermine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n0 \\leq A,B,C \\leq 10^9\n\nN, A, B, C are integers.\n\ns_i is AB, AC, or BC.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN A B C\ns_1\ns_2\n:\ns_N\n\nOutput\n\nIf it is possible to make N choices under the condition, print Yes; otherwise, print No.\n\nAlso, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.\n\nSample Input 1\n\n2 1 3 0\nAB\nAC\n\nSample Output 1\n\nYes\nA\nC\n\nYou can successfully make two choices, as follows:\n\nIn the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.\n\nIn the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.\n\nSample Input 2\n\n3 1 0 0\nAB\nBC\nAB\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n1 0 9 0\nAC\n\nSample Output 3\n\nNo\n\nSample Input 4\n\n8 6 9 1\nAC\nBC\nAB\nBC\nAC\nBC\nAB\nAB\n\nSample Output 4\n\nYes\nC\nB\nB\nC\nC\nB\nA\nA", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1398, "cpu_time_ms": 158, "memory_kb": 6428}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s930037947", "group_id": "codeNet:p02692", "input_text": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nconst int N = 1e5 + 10;\n\nint n, d[3];\nint a[3][N], step[N];\n\nint finddif(int x, int y) {\n    for (int i = 0; i < 3; i++)\n        if (a[i][x] && i != y)\n            return i;\n}\n\nvoid solve(int p0, int p1, int p2) {\n    int t[3];\n    t[0] = d[0]; t[1] = d[1]; t[2] = d[2];\n    for (int i = 0; i < n; i++) {\n        if (a[p0][i]) {\n            t[p0]++; t[finddif(i, p0)]--;\n            step[i] = p0;\n        } else {\n            t[p1]++; t[finddif(i, p1)]--;\n            step[i] = p1;\n        }\n        if (t[0] < 0) return;\n        if (t[1] < 0) return;\n        if (t[2] < 0) return;\n    }\n    puts(\"Yes\");\n    for (int i = 0; i < n; i++)\n        cout << (char)(step[i] + 'A') << endl;\n    exit(0);\n}\n\nvoid Try1() {\n    int t[3];\n    t[0] = d[0]; t[1] = d[1]; t[2] = d[2];\n    for (int i = 0; i < n; i++) {\n        int x = rand() % 2 + 1;\n        if (t[a[!x][i]] == 0) x ^= 1;\n        t[a[x][i]]++; t[a[!x][i]]--;\n        step[i] = x;\n        if (t[0] < 0) return;\n        if (t[1] < 0) return;\n        if (t[2] < 0) return;\n    }\n    puts(\"Yes\");\n    for (int i = 0; i < n; i++)\n        cout << (char)(step[i] + 'A') << endl;\n    exit(0);\n}\n\nvoid Try2() {\n    int t[3];\n    t[0] = d[0]; t[1] = d[1]; t[2] = d[2];\n    for (int i = 0; i < n; i++) {\n        int x = 0;\n        if (t[a[x][i]] < t[a[!x][i]]) x ^= 1;\n        t[a[x][i]]++; t[a[!x][i]]--;\n        step[i] = x;\n        if (t[0] < 0) return;\n        if (t[1] < 0) return;\n        if (t[2] < 0) return;\n    }\n    puts(\"Yes\");\n    for (int i = 0; i < n; i++)\n        cout << (char)(step[i] + 'A') << endl;\n    exit(0);\n}\n\nint main() {\n    if (fopen(\"A.inp\", \"r\"))\n    freopen(\"A.inp\", \"r\", stdin),\n    freopen(\"A.out\", \"w\", stdout);\n    cin >> n >> d[0] >> d[1] >> d[2];\n    for (int i = 0; i < n; i++) {\n        string str; cin >> str;\n        a[str[0] - 'A'][i] = a[str[1] - 'A'][i] = 1;\n    }\n    solve(0, 1, 2);\n    solve(0, 2, 1);\n    solve(1, 0, 2);\n    solve(1, 2, 0);\n    solve(2, 0, 1);\n    solve(2, 1, 0);\n//    for (int i = 0; i < 200; i++)\n//        Try1();\n//    Try2();\n    puts(\"No\");\n}\n", "language": "C++", "metadata": {"date": 1588536600, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02692.html", "problem_id": "p02692", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02692/input.txt", "sample_output_relpath": "derived/input_output/data/p02692/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02692/C++/s930037947.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s930037947", "user_id": "u401341828"}, "prompt_components": {"gold_output": "Yes\nA\nC\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nconst int N = 1e5 + 10;\n\nint n, d[3];\nint a[3][N], step[N];\n\nint finddif(int x, int y) {\n    for (int i = 0; i < 3; i++)\n        if (a[i][x] && i != y)\n            return i;\n}\n\nvoid solve(int p0, int p1, int p2) {\n    int t[3];\n    t[0] = d[0]; t[1] = d[1]; t[2] = d[2];\n    for (int i = 0; i < n; i++) {\n        if (a[p0][i]) {\n            t[p0]++; t[finddif(i, p0)]--;\n            step[i] = p0;\n        } else {\n            t[p1]++; t[finddif(i, p1)]--;\n            step[i] = p1;\n        }\n        if (t[0] < 0) return;\n        if (t[1] < 0) return;\n        if (t[2] < 0) return;\n    }\n    puts(\"Yes\");\n    for (int i = 0; i < n; i++)\n        cout << (char)(step[i] + 'A') << endl;\n    exit(0);\n}\n\nvoid Try1() {\n    int t[3];\n    t[0] = d[0]; t[1] = d[1]; t[2] = d[2];\n    for (int i = 0; i < n; i++) {\n        int x = rand() % 2 + 1;\n        if (t[a[!x][i]] == 0) x ^= 1;\n        t[a[x][i]]++; t[a[!x][i]]--;\n        step[i] = x;\n        if (t[0] < 0) return;\n        if (t[1] < 0) return;\n        if (t[2] < 0) return;\n    }\n    puts(\"Yes\");\n    for (int i = 0; i < n; i++)\n        cout << (char)(step[i] + 'A') << endl;\n    exit(0);\n}\n\nvoid Try2() {\n    int t[3];\n    t[0] = d[0]; t[1] = d[1]; t[2] = d[2];\n    for (int i = 0; i < n; i++) {\n        int x = 0;\n        if (t[a[x][i]] < t[a[!x][i]]) x ^= 1;\n        t[a[x][i]]++; t[a[!x][i]]--;\n        step[i] = x;\n        if (t[0] < 0) return;\n        if (t[1] < 0) return;\n        if (t[2] < 0) return;\n    }\n    puts(\"Yes\");\n    for (int i = 0; i < n; i++)\n        cout << (char)(step[i] + 'A') << endl;\n    exit(0);\n}\n\nint main() {\n    if (fopen(\"A.inp\", \"r\"))\n    freopen(\"A.inp\", \"r\", stdin),\n    freopen(\"A.out\", \"w\", stdout);\n    cin >> n >> d[0] >> d[1] >> d[2];\n    for (int i = 0; i < n; i++) {\n        string str; cin >> str;\n        a[str[0] - 'A'][i] = a[str[1] - 'A'][i] = 1;\n    }\n    solve(0, 1, 2);\n    solve(0, 2, 1);\n    solve(1, 0, 2);\n    solve(1, 2, 0);\n    solve(2, 0, 1);\n    solve(2, 1, 0);\n//    for (int i = 0; i < 200; i++)\n//        Try1();\n//    Try2();\n    puts(\"No\");\n}\n", "problem_context": "Score : 600 points\n\nProblem Statement\n\nThere is a game that involves three variables, denoted A, B, and C.\n\nAs the game progresses, there will be N events where you are asked to make a choice.\nEach of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.\n\nAfter each choice, none of A, B, and C should be negative.\n\nDetermine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n0 \\leq A,B,C \\leq 10^9\n\nN, A, B, C are integers.\n\ns_i is AB, AC, or BC.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN A B C\ns_1\ns_2\n:\ns_N\n\nOutput\n\nIf it is possible to make N choices under the condition, print Yes; otherwise, print No.\n\nAlso, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.\n\nSample Input 1\n\n2 1 3 0\nAB\nAC\n\nSample Output 1\n\nYes\nA\nC\n\nYou can successfully make two choices, as follows:\n\nIn the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.\n\nIn the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.\n\nSample Input 2\n\n3 1 0 0\nAB\nBC\nAB\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n1 0 9 0\nAC\n\nSample Output 3\n\nNo\n\nSample Input 4\n\n8 6 9 1\nAC\nBC\nAB\nBC\nAC\nBC\nAB\nAB\n\nSample Output 4\n\nYes\nC\nB\nB\nC\nC\nB\nA\nA", "sample_input": "2 1 3 0\nAB\nAC\n"}, "reference_outputs": ["Yes\nA\nC\n"], "source_document_id": "p02692", "source_text": "Score : 600 points\n\nProblem Statement\n\nThere is a game that involves three variables, denoted A, B, and C.\n\nAs the game progresses, there will be N events where you are asked to make a choice.\nEach of these choices is represented by a string s_i. If s_i is AB, you must add 1 to A or B then subtract 1 from the other; if s_i is AC, you must add 1 to A or C then subtract 1 from the other; if s_i is BC, you must add 1 to B or C then subtract 1 from the other.\n\nAfter each choice, none of A, B, and C should be negative.\n\nDetermine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n0 \\leq A,B,C \\leq 10^9\n\nN, A, B, C are integers.\n\ns_i is AB, AC, or BC.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN A B C\ns_1\ns_2\n:\ns_N\n\nOutput\n\nIf it is possible to make N choices under the condition, print Yes; otherwise, print No.\n\nAlso, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (A, B, or C) to which you add 1 in the i-th choice.\n\nSample Input 1\n\n2 1 3 0\nAB\nAC\n\nSample Output 1\n\nYes\nA\nC\n\nYou can successfully make two choices, as follows:\n\nIn the first choice, add 1 to A and subtract 1 from B. A becomes 2, and B becomes 2.\n\nIn the second choice, add 1 to C and subtract 1 from A. C becomes 1, and A becomes 1.\n\nSample Input 2\n\n3 1 0 0\nAB\nBC\nAB\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n1 0 9 0\nAC\n\nSample Output 3\n\nNo\n\nSample Input 4\n\n8 6 9 1\nAC\nBC\nAB\nBC\nAC\nBC\nAB\nAB\n\nSample Output 4\n\nYes\nC\nB\nB\nC\nC\nB\nA\nA", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2105, "cpu_time_ms": 155, "memory_kb": 5140}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s050594044", "group_id": "codeNet:p02693", "input_text": "#include <iostream>\nusing namespace std;\n\nint main() {\n    int K, A, B;\n    bool flag;\n    cin >> K >> A >> B;\n\n\n    flag = false;\n    for (int i=1; i<=1000; i++) {\n        if (A<=i*K and i*K<=B) {\n            flag = true;\n            break;\n        }\n    }\n\n    if (flag) {\n        cout << \"OK\" << endl;\n    } else {\n        cout << \"NG\" << endl;\n    }\n    return 0;\n}", "language": "C++", "metadata": {"date": 1588470186, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02693.html", "problem_id": "p02693", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02693/input.txt", "sample_output_relpath": "derived/input_output/data/p02693/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02693/C++/s050594044.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s050594044", "user_id": "u963164554"}, "prompt_components": {"gold_output": "OK\n", "input_to_evaluate": "#include <iostream>\nusing namespace std;\n\nint main() {\n    int K, A, B;\n    bool flag;\n    cin >> K >> A >> B;\n\n\n    flag = false;\n    for (int i=1; i<=1000; i++) {\n        if (A<=i*K and i*K<=B) {\n            flag = true;\n            break;\n        }\n    }\n\n    if (flag) {\n        cout << \"OK\" << endl;\n    } else {\n        cout << \"NG\" << endl;\n    }\n    return 0;\n}", "problem_context": "Score: 100 points\n\nProblem Statement\n\nTakahashi the Jumbo will practice golf.\n\nHis objective is to get a carry distance that is a multiple of K, while he can only make a carry distance of between A and B (inclusive).\n\nIf he can achieve the objective, print OK; if he cannot, print NG.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq A \\leq B \\leq 1000\n\n1 \\leq K \\leq 1000\n\nInput\n\nInput is given from Standard Input in the following format:\n\nK\nA B\n\nOutput\n\nIf he can achieve the objective, print OK; if he cannot, print NG.\n\nSample Input 1\n\n7\n500 600\n\nSample Output 1\n\nOK\n\nAmong the multiples of 7, for example, 567 lies between 500 and 600.\n\nSample Input 2\n\n4\n5 7\n\nSample Output 2\n\nNG\n\nNo multiple of 4 lies between 5 and 7.\n\nSample Input 3\n\n1\n11 11\n\nSample Output 3\n\nOK", "sample_input": "7\n500 600\n"}, "reference_outputs": ["OK\n"], "source_document_id": "p02693", "source_text": "Score: 100 points\n\nProblem Statement\n\nTakahashi the Jumbo will practice golf.\n\nHis objective is to get a carry distance that is a multiple of K, while he can only make a carry distance of between A and B (inclusive).\n\nIf he can achieve the objective, print OK; if he cannot, print NG.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq A \\leq B \\leq 1000\n\n1 \\leq K \\leq 1000\n\nInput\n\nInput is given from Standard Input in the following format:\n\nK\nA B\n\nOutput\n\nIf he can achieve the objective, print OK; if he cannot, print NG.\n\nSample Input 1\n\n7\n500 600\n\nSample Output 1\n\nOK\n\nAmong the multiples of 7, for example, 567 lies between 500 and 600.\n\nSample Input 2\n\n4\n5 7\n\nSample Output 2\n\nNG\n\nNo multiple of 4 lies between 5 and 7.\n\nSample Input 3\n\n1\n11 11\n\nSample Output 3\n\nOK", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 369, "cpu_time_ms": 2, "memory_kb": 3624}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s712271223", "group_id": "codeNet:p02694", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n#define rep(i,n) for (int i = 0; i < (n); ++i)\n#define dup(x,y) (((x)+(y)-1)/(y))\n#define ALL(x) (x).begin(), (x).end()\ntypedef long long ll;\ntypedef pair<int, int> pii;\nconst double EPS = 1e-10;\nconst int INF = 1e9;\nconst ll LINF = 1e15;\nconst int MOD = 1000000007;\nconst double PI = acos(-1);\nint dx[4] = {0,1,0,-1};\nint dy[4] = {1,0,-1,0};\n\nint main() {\n\tll x;\n\tcin >> x;\n\tll cur = 100;\n\tint ans = 0;\n\tif (x == 100) {\n\t\tcout << 0 << endl;\n\t\treturn 0;\n\t}\n\twhile (cur < x / 1.01) {\n\t\tans++;\n\t\tcur *= 1.01;\n\t}\n\tcout << ans + 1 << endl;\n}", "language": "C++", "metadata": {"date": 1599979294, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02694.html", "problem_id": "p02694", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02694/input.txt", "sample_output_relpath": "derived/input_output/data/p02694/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02694/C++/s712271223.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s712271223", "user_id": "u280175105"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n#define rep(i,n) for (int i = 0; i < (n); ++i)\n#define dup(x,y) (((x)+(y)-1)/(y))\n#define ALL(x) (x).begin(), (x).end()\ntypedef long long ll;\ntypedef pair<int, int> pii;\nconst double EPS = 1e-10;\nconst int INF = 1e9;\nconst ll LINF = 1e15;\nconst int MOD = 1000000007;\nconst double PI = acos(-1);\nint dx[4] = {0,1,0,-1};\nint dy[4] = {1,0,-1,0};\n\nint main() {\n\tll x;\n\tcin >> x;\n\tll cur = 100;\n\tint ans = 0;\n\tif (x == 100) {\n\t\tcout << 0 << endl;\n\t\treturn 0;\n\t}\n\twhile (cur < x / 1.01) {\n\t\tans++;\n\t\tcur *= 1.01;\n\t}\n\tcout << ans + 1 << endl;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nTakahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.\n\nThe bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)\n\nAssuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?\n\nConstraints\n\n101 \\le X \\le 10^{18}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint the number of years it takes for Takahashi's balance to reach X yen or above for the first time.\n\nSample Input 1\n\n103\n\nSample Output 1\n\n3\n\nThe balance after one year is 101 yen.\n\nThe balance after two years is 102 yen.\n\nThe balance after three years is 103 yen.\n\nThus, it takes three years for the balance to reach 103 yen or above.\n\nSample Input 2\n\n1000000000000000000\n\nSample Output 2\n\n3760\n\nSample Input 3\n\n1333333333\n\nSample Output 3\n\n1706", "sample_input": "103\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02694", "source_text": "Score : 200 points\n\nProblem Statement\n\nTakahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.\n\nThe bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)\n\nAssuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?\n\nConstraints\n\n101 \\le X \\le 10^{18}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint the number of years it takes for Takahashi's balance to reach X yen or above for the first time.\n\nSample Input 1\n\n103\n\nSample Output 1\n\n3\n\nThe balance after one year is 101 yen.\n\nThe balance after two years is 102 yen.\n\nThe balance after three years is 103 yen.\n\nThus, it takes three years for the balance to reach 103 yen or above.\n\nSample Input 2\n\n1000000000000000000\n\nSample Output 2\n\n3760\n\nSample Input 3\n\n1333333333\n\nSample Output 3\n\n1706", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 582, "cpu_time_ms": 8, "memory_kb": 3644}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s020058443", "group_id": "codeNet:p02694", "input_text": "#define ll long long\n#include \"bits/stdc++.h\"\nusing namespace std;\nvector<pair<ll ,ll >>vc;\nconst int N = 2e5 + 2;\nll arr[N];\nint main() {\nll n;\ncin>>n;\nll res=100;\nll cnt=0;\nwhile(res <= n)\n{\n    res+=(.01 * res );\n    cnt++;\n    if(res==n)break;\n\n}\ncout<<cnt;\n}", "language": "C++", "metadata": {"date": 1588491359, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02694.html", "problem_id": "p02694", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02694/input.txt", "sample_output_relpath": "derived/input_output/data/p02694/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02694/C++/s020058443.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s020058443", "user_id": "u839830822"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#define ll long long\n#include \"bits/stdc++.h\"\nusing namespace std;\nvector<pair<ll ,ll >>vc;\nconst int N = 2e5 + 2;\nll arr[N];\nint main() {\nll n;\ncin>>n;\nll res=100;\nll cnt=0;\nwhile(res <= n)\n{\n    res+=(.01 * res );\n    cnt++;\n    if(res==n)break;\n\n}\ncout<<cnt;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nTakahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.\n\nThe bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)\n\nAssuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?\n\nConstraints\n\n101 \\le X \\le 10^{18}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint the number of years it takes for Takahashi's balance to reach X yen or above for the first time.\n\nSample Input 1\n\n103\n\nSample Output 1\n\n3\n\nThe balance after one year is 101 yen.\n\nThe balance after two years is 102 yen.\n\nThe balance after three years is 103 yen.\n\nThus, it takes three years for the balance to reach 103 yen or above.\n\nSample Input 2\n\n1000000000000000000\n\nSample Output 2\n\n3760\n\nSample Input 3\n\n1333333333\n\nSample Output 3\n\n1706", "sample_input": "103\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02694", "source_text": "Score : 200 points\n\nProblem Statement\n\nTakahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.\n\nThe bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)\n\nAssuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?\n\nConstraints\n\n101 \\le X \\le 10^{18}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint the number of years it takes for Takahashi's balance to reach X yen or above for the first time.\n\nSample Input 1\n\n103\n\nSample Output 1\n\n3\n\nThe balance after one year is 101 yen.\n\nThe balance after two years is 102 yen.\n\nThe balance after three years is 103 yen.\n\nThus, it takes three years for the balance to reach 103 yen or above.\n\nSample Input 2\n\n1000000000000000000\n\nSample Output 2\n\n3760\n\nSample Input 3\n\n1333333333\n\nSample Output 3\n\n1706", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 263, "cpu_time_ms": 3, "memory_kb": 3588}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s510674419", "group_id": "codeNet:p02694", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> pii;\ntypedef pair<ll,ll> pll;\ntypedef pair<ll,int> pli;\ntypedef vector<int> vi;\ntypedef vector<ll> vl;\ntypedef vector<pii> vpii;\ntypedef vector<pll> vpll;\n#define F first\n#define S second\ntypedef vector<pli> vpli;\n#define MOD 1000000007\n#define mp make_pair\n#define pb push_back\n#define all(v) v.begin(),v.end() \n#define tests int t; cin>>t; while(t--)\n#define take(a,b,c) for(b=0;b<c;b++) cin>>a[b];\n#define INF 1e18\n// https://codeforces.com/problemset/page/3?tags=1500-1800\nmap <int,stack<int> > m;\nint main()\n{\t\n  ll x;\n  cin>>x;\n  ll y=100;\n  ll j=1;\n  while(1){\n    y+=y/100;\n    if(y>=x){\n      cout<<j;\n      break;\n    }\n    else j++;\n  }\n}\n", "language": "C++", "metadata": {"date": 1588468634, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02694.html", "problem_id": "p02694", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02694/input.txt", "sample_output_relpath": "derived/input_output/data/p02694/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02694/C++/s510674419.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s510674419", "user_id": "u867414600"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> pii;\ntypedef pair<ll,ll> pll;\ntypedef pair<ll,int> pli;\ntypedef vector<int> vi;\ntypedef vector<ll> vl;\ntypedef vector<pii> vpii;\ntypedef vector<pll> vpll;\n#define F first\n#define S second\ntypedef vector<pli> vpli;\n#define MOD 1000000007\n#define mp make_pair\n#define pb push_back\n#define all(v) v.begin(),v.end() \n#define tests int t; cin>>t; while(t--)\n#define take(a,b,c) for(b=0;b<c;b++) cin>>a[b];\n#define INF 1e18\n// https://codeforces.com/problemset/page/3?tags=1500-1800\nmap <int,stack<int> > m;\nint main()\n{\t\n  ll x;\n  cin>>x;\n  ll y=100;\n  ll j=1;\n  while(1){\n    y+=y/100;\n    if(y>=x){\n      cout<<j;\n      break;\n    }\n    else j++;\n  }\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nTakahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.\n\nThe bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)\n\nAssuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?\n\nConstraints\n\n101 \\le X \\le 10^{18}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint the number of years it takes for Takahashi's balance to reach X yen or above for the first time.\n\nSample Input 1\n\n103\n\nSample Output 1\n\n3\n\nThe balance after one year is 101 yen.\n\nThe balance after two years is 102 yen.\n\nThe balance after three years is 103 yen.\n\nThus, it takes three years for the balance to reach 103 yen or above.\n\nSample Input 2\n\n1000000000000000000\n\nSample Output 2\n\n3760\n\nSample Input 3\n\n1333333333\n\nSample Output 3\n\n1706", "sample_input": "103\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02694", "source_text": "Score : 200 points\n\nProblem Statement\n\nTakahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.\n\nThe bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)\n\nAssuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?\n\nConstraints\n\n101 \\le X \\le 10^{18}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint the number of years it takes for Takahashi's balance to reach X yen or above for the first time.\n\nSample Input 1\n\n103\n\nSample Output 1\n\n3\n\nThe balance after one year is 101 yen.\n\nThe balance after two years is 102 yen.\n\nThe balance after three years is 103 yen.\n\nThus, it takes three years for the balance to reach 103 yen or above.\n\nSample Input 2\n\n1000000000000000000\n\nSample Output 2\n\n3760\n\nSample Input 3\n\n1333333333\n\nSample Output 3\n\n1706", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 739, "cpu_time_ms": 6, "memory_kb": 3624}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s034586657", "group_id": "codeNet:p02694", "input_text": "#include <bits/stdc++.h>\n#define INF 1e9\nusing namespace std;\n\n#define REPR(i,n) for(int i=(n); i >= 0; --i)\n#define FOR(i, m, n) for(int i = (m); i < (n); ++i)\n#define REP(i, n) for(int i=0, i##_len=(n); i<i##_len; ++i)\n#define ALL(a)  (a).begin(),(a).end()\n#define endl \"\\n\"\n\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return true; } return false; }\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return true; } return false; }\ntypedef long long ll;\n\nvoid solve() {\n    ll X;\n    cin >> X;\n    int nen = 0;\n    ll now = 100;\n    while (now < X) {\n        nen++;\n        now*=1.01;\n    }\n    cout << nen << endl;\n}\n\nint main() {\n    solve();\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1588468624, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02694.html", "problem_id": "p02694", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02694/input.txt", "sample_output_relpath": "derived/input_output/data/p02694/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02694/C++/s034586657.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s034586657", "user_id": "u492030100"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define INF 1e9\nusing namespace std;\n\n#define REPR(i,n) for(int i=(n); i >= 0; --i)\n#define FOR(i, m, n) for(int i = (m); i < (n); ++i)\n#define REP(i, n) for(int i=0, i##_len=(n); i<i##_len; ++i)\n#define ALL(a)  (a).begin(),(a).end()\n#define endl \"\\n\"\n\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return true; } return false; }\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return true; } return false; }\ntypedef long long ll;\n\nvoid solve() {\n    ll X;\n    cin >> X;\n    int nen = 0;\n    ll now = 100;\n    while (now < X) {\n        nen++;\n        now*=1.01;\n    }\n    cout << nen << endl;\n}\n\nint main() {\n    solve();\n    return 0;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nTakahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.\n\nThe bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)\n\nAssuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?\n\nConstraints\n\n101 \\le X \\le 10^{18}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint the number of years it takes for Takahashi's balance to reach X yen or above for the first time.\n\nSample Input 1\n\n103\n\nSample Output 1\n\n3\n\nThe balance after one year is 101 yen.\n\nThe balance after two years is 102 yen.\n\nThe balance after three years is 103 yen.\n\nThus, it takes three years for the balance to reach 103 yen or above.\n\nSample Input 2\n\n1000000000000000000\n\nSample Output 2\n\n3760\n\nSample Input 3\n\n1333333333\n\nSample Output 3\n\n1706", "sample_input": "103\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02694", "source_text": "Score : 200 points\n\nProblem Statement\n\nTakahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.\n\nThe bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)\n\nAssuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?\n\nConstraints\n\n101 \\le X \\le 10^{18}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint the number of years it takes for Takahashi's balance to reach X yen or above for the first time.\n\nSample Input 1\n\n103\n\nSample Output 1\n\n3\n\nThe balance after one year is 101 yen.\n\nThe balance after two years is 102 yen.\n\nThe balance after three years is 103 yen.\n\nThus, it takes three years for the balance to reach 103 yen or above.\n\nSample Input 2\n\n1000000000000000000\n\nSample Output 2\n\n3760\n\nSample Input 3\n\n1333333333\n\nSample Output 3\n\n1706", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 697, "cpu_time_ms": 2, "memory_kb": 3632}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s599239787", "group_id": "codeNet:p02695", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n#define FOR(var, begin, end) for (int var = (begin); var <= (end); var++)\n#define RFOR(var, begin, end) for (int var = (begin); var >= (end); var--)\n#define REP(var, length) FOR(var, 0, length - 1)\n#define RREP(var, length) RFOR(var, length - 1, 0)\n#define EACH(value, var) for (auto value : var)\n#define SORT(var) sort(var.begin(), var.end())\n#define REVERSE(var) reverse(var.begin(), var.end())\n#define RSORT(var) \\\n  SORT(var);       \\\n  REVERSE(var)\n#define OPTIMIZE_STDIO         \\\n  ios::sync_with_stdio(false); \\\n  cin.tie(0);                  \\\n  cout.precision(10);          \\\n  cout << fixed\n#define endl '\\n'\n\nconst int INF = 1e9;\nconst ll MOD = 1e9 + 7;\nconst ll LINF = 1e18;\nstruct mint {\n  ll x;\n  mint() : x(0) {\n  }\n  mint(ll x) : x((x % MOD + MOD) % MOD) {\n  }\n  mint& operator+=(const mint& r) {\n    if ((x += r.x) >= MOD) {\n      x -= MOD;\n    }\n    return *this;\n  }\n  mint& operator-=(const mint& r) {\n    if ((x -= r.x) < 0) {\n      x += MOD;\n    }\n    return *this;\n  }\n  mint& operator*=(const mint& r) {\n    if ((x *= r.x) > MOD) {\n      x %= MOD;\n    }\n    return *this;\n  }\n  mint& operator++() {\n    if ((++x) >= MOD) {\n      x -= MOD;\n    }\n    return *this;\n  }\n  mint operator++(int) {\n    mint ret = x;\n    if ((++x) >= MOD) {\n      x -= MOD;\n    }\n    return ret;\n  }\n  mint& operator--() {\n    if ((--x) < 0) {\n      x += MOD;\n    }\n    return *this;\n  }\n  mint operator--(int) {\n    mint ret = x;\n    if ((--x) < 0) {\n      x += MOD;\n    }\n    return ret;\n  }\n  mint operator+(const mint& r) {\n    mint ret;\n    return ret = x + r.x;\n  }\n  mint operator-(const mint& r) {\n    mint ret;\n    return ret = x - r.x;\n  }\n  mint operator*(const mint& r) {\n    mint ret;\n    return ret = x * r.x;\n  }\n  mint operator-() {\n    return mint() - *this;\n  }\n  bool operator<(const mint& a) {\n    return x < a.x;\n  }\n  bool operator>(const mint& a) {\n    return x > a.x;\n  }\n  bool operator<=(const mint& a) {\n    return x <= a.x;\n  }\n  bool operator>=(const mint& a) {\n    return x >= a.x;\n  }\n  bool operator==(const mint& a) {\n    return x == a.x;\n  }\n  bool operator!=(const mint& a) {\n    return x != a.x;\n  }\n};\nostream& operator<<(ostream& os, const mint& r) {\n  os << r.x;\n  return os;\n}\nostream& operator>>(ostream& os, const mint& r) {\n  os >> r.x;\n  return os;\n}\n\nint n, m, q;\nvector<int> a, b, c, d;\nint ans;\n\nvoid dfs(vector<int> buf) {\n  if (buf.size() == n + 1) {\n    int now = 0;\n    REP(i, q) {\n      if ((buf[b[i]] - buf[a[i]]) == c[i]) now += d[i];\n    }\n    ans = max(ans, now);\n    return;\n  }\n\n  buf.push_back(buf.back());\n  while (buf.back() <= m) {\n    dfs(buf);\n    buf.back()++;\n  }\n}\n\nvoid solve(istream& cin, ostream& cout) {\n  cin >> n >> m >> q;\n  a = b = c = d = vector<int>(q);\n  REP(i, q) {\n    cin >> a[i] >> b[i] >> c[i] >> d[i];\n  }\n  dfs(vector<int>(1, 1));\n  cout << ans << endl;\n}\n\n#ifndef TEST\nint main() {\n  OPTIMIZE_STDIO;\n  solve(cin, cout);\n  return 0;\n}\n#endif\n", "language": "C++", "metadata": {"date": 1588483056, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02695.html", "problem_id": "p02695", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02695/input.txt", "sample_output_relpath": "derived/input_output/data/p02695/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02695/C++/s599239787.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s599239787", "user_id": "u068177169"}, "prompt_components": {"gold_output": "110\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n#define FOR(var, begin, end) for (int var = (begin); var <= (end); var++)\n#define RFOR(var, begin, end) for (int var = (begin); var >= (end); var--)\n#define REP(var, length) FOR(var, 0, length - 1)\n#define RREP(var, length) RFOR(var, length - 1, 0)\n#define EACH(value, var) for (auto value : var)\n#define SORT(var) sort(var.begin(), var.end())\n#define REVERSE(var) reverse(var.begin(), var.end())\n#define RSORT(var) \\\n  SORT(var);       \\\n  REVERSE(var)\n#define OPTIMIZE_STDIO         \\\n  ios::sync_with_stdio(false); \\\n  cin.tie(0);                  \\\n  cout.precision(10);          \\\n  cout << fixed\n#define endl '\\n'\n\nconst int INF = 1e9;\nconst ll MOD = 1e9 + 7;\nconst ll LINF = 1e18;\nstruct mint {\n  ll x;\n  mint() : x(0) {\n  }\n  mint(ll x) : x((x % MOD + MOD) % MOD) {\n  }\n  mint& operator+=(const mint& r) {\n    if ((x += r.x) >= MOD) {\n      x -= MOD;\n    }\n    return *this;\n  }\n  mint& operator-=(const mint& r) {\n    if ((x -= r.x) < 0) {\n      x += MOD;\n    }\n    return *this;\n  }\n  mint& operator*=(const mint& r) {\n    if ((x *= r.x) > MOD) {\n      x %= MOD;\n    }\n    return *this;\n  }\n  mint& operator++() {\n    if ((++x) >= MOD) {\n      x -= MOD;\n    }\n    return *this;\n  }\n  mint operator++(int) {\n    mint ret = x;\n    if ((++x) >= MOD) {\n      x -= MOD;\n    }\n    return ret;\n  }\n  mint& operator--() {\n    if ((--x) < 0) {\n      x += MOD;\n    }\n    return *this;\n  }\n  mint operator--(int) {\n    mint ret = x;\n    if ((--x) < 0) {\n      x += MOD;\n    }\n    return ret;\n  }\n  mint operator+(const mint& r) {\n    mint ret;\n    return ret = x + r.x;\n  }\n  mint operator-(const mint& r) {\n    mint ret;\n    return ret = x - r.x;\n  }\n  mint operator*(const mint& r) {\n    mint ret;\n    return ret = x * r.x;\n  }\n  mint operator-() {\n    return mint() - *this;\n  }\n  bool operator<(const mint& a) {\n    return x < a.x;\n  }\n  bool operator>(const mint& a) {\n    return x > a.x;\n  }\n  bool operator<=(const mint& a) {\n    return x <= a.x;\n  }\n  bool operator>=(const mint& a) {\n    return x >= a.x;\n  }\n  bool operator==(const mint& a) {\n    return x == a.x;\n  }\n  bool operator!=(const mint& a) {\n    return x != a.x;\n  }\n};\nostream& operator<<(ostream& os, const mint& r) {\n  os << r.x;\n  return os;\n}\nostream& operator>>(ostream& os, const mint& r) {\n  os >> r.x;\n  return os;\n}\n\nint n, m, q;\nvector<int> a, b, c, d;\nint ans;\n\nvoid dfs(vector<int> buf) {\n  if (buf.size() == n + 1) {\n    int now = 0;\n    REP(i, q) {\n      if ((buf[b[i]] - buf[a[i]]) == c[i]) now += d[i];\n    }\n    ans = max(ans, now);\n    return;\n  }\n\n  buf.push_back(buf.back());\n  while (buf.back() <= m) {\n    dfs(buf);\n    buf.back()++;\n  }\n}\n\nvoid solve(istream& cin, ostream& cout) {\n  cin >> n >> m >> q;\n  a = b = c = d = vector<int>(q);\n  REP(i, q) {\n    cin >> a[i] >> b[i] >> c[i] >> d[i];\n  }\n  dfs(vector<int>(1, 1));\n  cout << ans << endl;\n}\n\n#ifndef TEST\nint main() {\n  OPTIMIZE_STDIO;\n  solve(cin, cout);\n  return 0;\n}\n#endif\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nGiven are positive integers N, M, Q, and Q quadruples of integers ( a_i , b_i , c_i , d_i ).\n\nConsider a sequence A satisfying the following conditions:\n\nA is a sequence of N positive integers.\n\n1 \\leq A_1 \\leq A_2 \\le \\cdots \\leq A_N \\leq M.\n\nLet us define a score of this sequence as follows:\n\nThe score is the sum of d_i over all indices i such that A_{b_i} - A_{a_i} = c_i. (If there is no such i, the score is 0.)\n\nFind the maximum possible score of A.\n\nConstraints\n\nAll values in input are integers.\n\n2 ≤ N ≤ 10\n\n1 \\leq M \\leq 10\n\n1 \\leq Q \\leq 50\n\n1 \\leq a_i < b_i \\leq N ( i = 1, 2, ..., Q )\n\n0 \\leq c_i \\leq M - 1 ( i = 1, 2, ..., Q )\n\n(a_i, b_i, c_i) \\neq (a_j, b_j, c_j) (where i \\neq j)\n\n1 \\leq d_i \\leq 10^5 ( i = 1, 2, ..., Q )\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M Q\na_1 b_1 c_1 d_1\n:\na_Q b_Q c_Q d_Q\n\nOutput\n\nPrint the maximum possible score of A.\n\nSample Input 1\n\n3 4 3\n1 3 3 100\n1 2 2 10\n2 3 2 10\n\nSample Output 1\n\n110\n\nWhen A = \\{1, 3, 4\\}, its score is 110. Under these conditions, no sequence has a score greater than 110, so the answer is 110.\n\nSample Input 2\n\n4 6 10\n2 4 1 86568\n1 4 0 90629\n2 3 0 90310\n3 4 1 29211\n3 4 3 78537\n3 4 2 8580\n1 2 1 96263\n1 4 2 2156\n1 2 0 94325\n1 4 3 94328\n\nSample Output 2\n\n357500\n\nSample Input 3\n\n10 10 1\n1 10 9 1\n\nSample Output 3\n\n1", "sample_input": "3 4 3\n1 3 3 100\n1 2 2 10\n2 3 2 10\n"}, "reference_outputs": ["110\n"], "source_document_id": "p02695", "source_text": "Score : 300 points\n\nProblem Statement\n\nGiven are positive integers N, M, Q, and Q quadruples of integers ( a_i , b_i , c_i , d_i ).\n\nConsider a sequence A satisfying the following conditions:\n\nA is a sequence of N positive integers.\n\n1 \\leq A_1 \\leq A_2 \\le \\cdots \\leq A_N \\leq M.\n\nLet us define a score of this sequence as follows:\n\nThe score is the sum of d_i over all indices i such that A_{b_i} - A_{a_i} = c_i. (If there is no such i, the score is 0.)\n\nFind the maximum possible score of A.\n\nConstraints\n\nAll values in input are integers.\n\n2 ≤ N ≤ 10\n\n1 \\leq M \\leq 10\n\n1 \\leq Q \\leq 50\n\n1 \\leq a_i < b_i \\leq N ( i = 1, 2, ..., Q )\n\n0 \\leq c_i \\leq M - 1 ( i = 1, 2, ..., Q )\n\n(a_i, b_i, c_i) \\neq (a_j, b_j, c_j) (where i \\neq j)\n\n1 \\leq d_i \\leq 10^5 ( i = 1, 2, ..., Q )\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M Q\na_1 b_1 c_1 d_1\n:\na_Q b_Q c_Q d_Q\n\nOutput\n\nPrint the maximum possible score of A.\n\nSample Input 1\n\n3 4 3\n1 3 3 100\n1 2 2 10\n2 3 2 10\n\nSample Output 1\n\n110\n\nWhen A = \\{1, 3, 4\\}, its score is 110. Under these conditions, no sequence has a score greater than 110, so the answer is 110.\n\nSample Input 2\n\n4 6 10\n2 4 1 86568\n1 4 0 90629\n2 3 0 90310\n3 4 1 29211\n3 4 3 78537\n3 4 2 8580\n1 2 1 96263\n1 4 2 2156\n1 2 0 94325\n1 4 3 94328\n\nSample Output 2\n\n357500\n\nSample Input 3\n\n10 10 1\n1 10 9 1\n\nSample Output 3\n\n1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2996, "cpu_time_ms": 26, "memory_kb": 3668}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s658761323", "group_id": "codeNet:p02696", "input_text": "#include <bits/stdc++.h>\n#define rep(i,n) for(int i = 0; i < n; i++)\n#define vi vector<int>\n#define vvi vector<vi>\n#define pii pair<int, int>\n#define mod 1000000007\nusing ll = long long;\nusing namespace std;\nint main(){\n  ll a,b,n;\n  cin >> a >> b >> n;\n  ll ans = 0;\n  for(ll x = n; x >= 0; x--){\n    ll val = ll(a * x / b) - a * ll(x / b);\n    ans = ans < val ? val : ans;\n    if(ans > val + 10) break;\n  }\n  cout << ans << endl;\n}", "language": "C++", "metadata": {"date": 1588473449, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02696.html", "problem_id": "p02696", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02696/input.txt", "sample_output_relpath": "derived/input_output/data/p02696/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02696/C++/s658761323.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s658761323", "user_id": "u396266329"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define rep(i,n) for(int i = 0; i < n; i++)\n#define vi vector<int>\n#define vvi vector<vi>\n#define pii pair<int, int>\n#define mod 1000000007\nusing ll = long long;\nusing namespace std;\nint main(){\n  ll a,b,n;\n  cin >> a >> b >> n;\n  ll ans = 0;\n  for(ll x = n; x >= 0; x--){\n    ll val = ll(a * x / b) - a * ll(x / b);\n    ans = ans < val ? val : ans;\n    if(ans > val + 10) break;\n  }\n  cout << ans << endl;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nGiven are integers A, B, and N.\n\nFind the maximum possible value of floor(Ax/B) - A × floor(x/B) for a non-negative integer x not greater than N.\n\nHere floor(t) denotes the greatest integer not greater than the real number t.\n\nConstraints\n\n1 ≤ A ≤ 10^{6}\n\n1 ≤ B ≤ 10^{12}\n\n1 ≤ N ≤ 10^{12}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B N\n\nOutput\n\nPrint the maximum possible value of floor(Ax/B) - A × floor(x/B) for a non-negative integer x not greater than N, as an integer.\n\nSample Input 1\n\n5 7 4\n\nSample Output 1\n\n2\n\nWhen x=3, floor(Ax/B)-A×floor(x/B) = floor(15/7) - 5×floor(3/7) = 2. This is the maximum value possible.\n\nSample Input 2\n\n11 10 9\n\nSample Output 2\n\n9", "sample_input": "5 7 4\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02696", "source_text": "Score : 400 points\n\nProblem Statement\n\nGiven are integers A, B, and N.\n\nFind the maximum possible value of floor(Ax/B) - A × floor(x/B) for a non-negative integer x not greater than N.\n\nHere floor(t) denotes the greatest integer not greater than the real number t.\n\nConstraints\n\n1 ≤ A ≤ 10^{6}\n\n1 ≤ B ≤ 10^{12}\n\n1 ≤ N ≤ 10^{12}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B N\n\nOutput\n\nPrint the maximum possible value of floor(Ax/B) - A × floor(x/B) for a non-negative integer x not greater than N, as an integer.\n\nSample Input 1\n\n5 7 4\n\nSample Output 1\n\n2\n\nWhen x=3, floor(Ax/B)-A×floor(x/B) = floor(15/7) - 5×floor(3/7) = 2. This is the maximum value possible.\n\nSample Input 2\n\n11 10 9\n\nSample Output 2\n\n9", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 433, "cpu_time_ms": 2205, "memory_kb": 3652}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s486257017", "group_id": "codeNet:p02697", "input_text": "//g++ -std=gnu++14 a.cpp\n#include <algorithm>\n#include <bitset>\n#include <complex>\n#include <deque>\n#include <iostream>\n#include <istream>\n#include <iterator>\n#include <map>\n#include <queue>\n#include <set>\n#include <stack>\n#include <string>\n#include <vector>\n#include <tuple>\n#include <iomanip>\n#include <random>\n#include <math.h>\n\nusing namespace std;\n\n#define ll long long\n#define rep(i, n) for(ll i = 0; i < (n); i++)\nll MOD = 1e9 + 7;\nint INF = 1 << 30;\nll INFL = 1LL << 60;\n\nint main() {\n  ll N,M;\n  cin >> N >> M;\n  ll a,b;\n  a=3;\n  b=5;\n    if(M>=1)cout << 1 << \" \" << 2 << endl;\n    if(M>=2)cout << 3 << \" \" << 5 << endl;\n  if(M>=3){\n    for(int i =3;i <= M;i++){\n      a++;\n      b=a+i;\n      cout << a << \" \" << b << endl;\n    }\n  }\n\n\n\n\n}\n", "language": "C++", "metadata": {"date": 1588743013, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02697.html", "problem_id": "p02697", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02697/input.txt", "sample_output_relpath": "derived/input_output/data/p02697/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02697/C++/s486257017.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s486257017", "user_id": "u388134182"}, "prompt_components": {"gold_output": "2 3\n", "input_to_evaluate": "//g++ -std=gnu++14 a.cpp\n#include <algorithm>\n#include <bitset>\n#include <complex>\n#include <deque>\n#include <iostream>\n#include <istream>\n#include <iterator>\n#include <map>\n#include <queue>\n#include <set>\n#include <stack>\n#include <string>\n#include <vector>\n#include <tuple>\n#include <iomanip>\n#include <random>\n#include <math.h>\n\nusing namespace std;\n\n#define ll long long\n#define rep(i, n) for(ll i = 0; i < (n); i++)\nll MOD = 1e9 + 7;\nint INF = 1 << 30;\nll INFL = 1LL << 60;\n\nint main() {\n  ll N,M;\n  cin >> N >> M;\n  ll a,b;\n  a=3;\n  b=5;\n    if(M>=1)cout << 1 << \" \" << 2 << endl;\n    if(M>=2)cout << 3 << \" \" << 5 << endl;\n  if(M>=3){\n    for(int i =3;i <= M;i++){\n      a++;\n      b=a+i;\n      cout << a << \" \" << b << endl;\n    }\n  }\n\n\n\n\n}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nYou are going to hold a competition of one-to-one game called AtCoder Janken. (Janken is the Japanese name for Rock-paper-scissors.)\nN players will participate in this competition, and they are given distinct integers from 1 through N.\nThe arena has M playing fields for two players. You need to assign each playing field two distinct integers between 1 and N (inclusive).\nYou cannot assign the same integer to multiple playing fields.\nThe competition consists of N rounds, each of which proceeds as follows:\n\nFor each player, if there is a playing field that is assigned the player's integer, the player goes to that field and fight the other player who comes there.\n\nThen, each player adds 1 to its integer. If it becomes N+1, change it to 1.\n\nYou want to ensure that no player fights the same opponent more than once during the N rounds.\nPrint an assignment of integers to the playing fields satisfying this condition.\nIt can be proved that such an assignment always exists under the constraints given.\n\nConstraints\n\n1 \\leq M\n\nM \\times 2 +1 \\leq N \\leq 200000\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\n\nOutput\n\nPrint M lines in the format below.\nThe i-th line should contain the two integers a_i and b_i assigned to the i-th playing field.\n\na_1 b_1\na_2 b_2\n:\na_M b_M\n\nSample Input 1\n\n4 1\n\nSample Output 1\n\n2 3\n\nLet us call the four players A, B, C, and D, and assume that they are initially given the integers 1, 2, 3, and 4, respectively.\n\nThe 1-st round is fought by B and C, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 2, 3, 4, and 1, respectively.\n\nThe 2-nd round is fought by A and B, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 3, 4, 1, and 2, respectively.\n\nThe 3-rd round is fought by D and A, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 4, 1, 2, and 3, respectively.\n\nThe 4-th round is fought by C and D, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 1, 2, 3, and 4, respectively.\n\nNo player fights the same opponent more than once during the four rounds, so this solution will be accepted.\n\nSample Input 2\n\n7 3\n\nSample Output 2\n\n1 6\n2 5\n3 4", "sample_input": "4 1\n"}, "reference_outputs": ["2 3\n"], "source_document_id": "p02697", "source_text": "Score : 500 points\n\nProblem Statement\n\nYou are going to hold a competition of one-to-one game called AtCoder Janken. (Janken is the Japanese name for Rock-paper-scissors.)\nN players will participate in this competition, and they are given distinct integers from 1 through N.\nThe arena has M playing fields for two players. You need to assign each playing field two distinct integers between 1 and N (inclusive).\nYou cannot assign the same integer to multiple playing fields.\nThe competition consists of N rounds, each of which proceeds as follows:\n\nFor each player, if there is a playing field that is assigned the player's integer, the player goes to that field and fight the other player who comes there.\n\nThen, each player adds 1 to its integer. If it becomes N+1, change it to 1.\n\nYou want to ensure that no player fights the same opponent more than once during the N rounds.\nPrint an assignment of integers to the playing fields satisfying this condition.\nIt can be proved that such an assignment always exists under the constraints given.\n\nConstraints\n\n1 \\leq M\n\nM \\times 2 +1 \\leq N \\leq 200000\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\n\nOutput\n\nPrint M lines in the format below.\nThe i-th line should contain the two integers a_i and b_i assigned to the i-th playing field.\n\na_1 b_1\na_2 b_2\n:\na_M b_M\n\nSample Input 1\n\n4 1\n\nSample Output 1\n\n2 3\n\nLet us call the four players A, B, C, and D, and assume that they are initially given the integers 1, 2, 3, and 4, respectively.\n\nThe 1-st round is fought by B and C, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 2, 3, 4, and 1, respectively.\n\nThe 2-nd round is fought by A and B, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 3, 4, 1, and 2, respectively.\n\nThe 3-rd round is fought by D and A, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 4, 1, 2, and 3, respectively.\n\nThe 4-th round is fought by C and D, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 1, 2, 3, and 4, respectively.\n\nNo player fights the same opponent more than once during the four rounds, so this solution will be accepted.\n\nSample Input 2\n\n7 3\n\nSample Output 2\n\n1 6\n2 5\n3 4", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 749, "cpu_time_ms": 131, "memory_kb": 3644}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s017604377", "group_id": "codeNet:p02697", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define rep2(i, s, n) for (int i = (s); i < (int)(n); i++)\ntypedef long long ll;\n#define ALL(v) v.begin(), v.end()\n#define vmax(v) *max_element(ALL(v))\n#define vmin(v) *min_element(ALL(v))\n#define chmax(x, a) x = max(x, a)\n#define chmin(x, a) x = min(x, a)\n\nint main() {\n    int N, M; cin >> N >> M;\n    if (M % 2 == 1) {\n        int tmp = 1;\n        int mx = M;\n        while(tmp != mx) {\n            cout << tmp << \" \" << mx << endl;\n            tmp++;\n            mx--;\n        }\n        tmp = M+1;\n        mx = 2*M+1;\n        while(tmp < mx) {\n            cout << tmp << \" \" << mx << endl;\n            tmp++;\n            mx--;\n        }\n    }\n    else {\n        int tmp = 1;\n        int mx = M+1;\n        while(tmp != M-tmp+2) {\n            cout << tmp << \" \" << mx << endl;\n            tmp++;\n            mx--;\n        }\n        tmp = M+2;\n        mx = 2*M+1;\n        while(tmp < mx) {\n            cout << tmp << \" \" << mx << endl;\n            tmp++;\n            mx--;\n        }\n    }\n}\n", "language": "C++", "metadata": {"date": 1588527503, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02697.html", "problem_id": "p02697", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02697/input.txt", "sample_output_relpath": "derived/input_output/data/p02697/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02697/C++/s017604377.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s017604377", "user_id": "u552357043"}, "prompt_components": {"gold_output": "2 3\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define rep2(i, s, n) for (int i = (s); i < (int)(n); i++)\ntypedef long long ll;\n#define ALL(v) v.begin(), v.end()\n#define vmax(v) *max_element(ALL(v))\n#define vmin(v) *min_element(ALL(v))\n#define chmax(x, a) x = max(x, a)\n#define chmin(x, a) x = min(x, a)\n\nint main() {\n    int N, M; cin >> N >> M;\n    if (M % 2 == 1) {\n        int tmp = 1;\n        int mx = M;\n        while(tmp != mx) {\n            cout << tmp << \" \" << mx << endl;\n            tmp++;\n            mx--;\n        }\n        tmp = M+1;\n        mx = 2*M+1;\n        while(tmp < mx) {\n            cout << tmp << \" \" << mx << endl;\n            tmp++;\n            mx--;\n        }\n    }\n    else {\n        int tmp = 1;\n        int mx = M+1;\n        while(tmp != M-tmp+2) {\n            cout << tmp << \" \" << mx << endl;\n            tmp++;\n            mx--;\n        }\n        tmp = M+2;\n        mx = 2*M+1;\n        while(tmp < mx) {\n            cout << tmp << \" \" << mx << endl;\n            tmp++;\n            mx--;\n        }\n    }\n}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nYou are going to hold a competition of one-to-one game called AtCoder Janken. (Janken is the Japanese name for Rock-paper-scissors.)\nN players will participate in this competition, and they are given distinct integers from 1 through N.\nThe arena has M playing fields for two players. You need to assign each playing field two distinct integers between 1 and N (inclusive).\nYou cannot assign the same integer to multiple playing fields.\nThe competition consists of N rounds, each of which proceeds as follows:\n\nFor each player, if there is a playing field that is assigned the player's integer, the player goes to that field and fight the other player who comes there.\n\nThen, each player adds 1 to its integer. If it becomes N+1, change it to 1.\n\nYou want to ensure that no player fights the same opponent more than once during the N rounds.\nPrint an assignment of integers to the playing fields satisfying this condition.\nIt can be proved that such an assignment always exists under the constraints given.\n\nConstraints\n\n1 \\leq M\n\nM \\times 2 +1 \\leq N \\leq 200000\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\n\nOutput\n\nPrint M lines in the format below.\nThe i-th line should contain the two integers a_i and b_i assigned to the i-th playing field.\n\na_1 b_1\na_2 b_2\n:\na_M b_M\n\nSample Input 1\n\n4 1\n\nSample Output 1\n\n2 3\n\nLet us call the four players A, B, C, and D, and assume that they are initially given the integers 1, 2, 3, and 4, respectively.\n\nThe 1-st round is fought by B and C, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 2, 3, 4, and 1, respectively.\n\nThe 2-nd round is fought by A and B, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 3, 4, 1, and 2, respectively.\n\nThe 3-rd round is fought by D and A, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 4, 1, 2, and 3, respectively.\n\nThe 4-th round is fought by C and D, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 1, 2, 3, and 4, respectively.\n\nNo player fights the same opponent more than once during the four rounds, so this solution will be accepted.\n\nSample Input 2\n\n7 3\n\nSample Output 2\n\n1 6\n2 5\n3 4", "sample_input": "4 1\n"}, "reference_outputs": ["2 3\n"], "source_document_id": "p02697", "source_text": "Score : 500 points\n\nProblem Statement\n\nYou are going to hold a competition of one-to-one game called AtCoder Janken. (Janken is the Japanese name for Rock-paper-scissors.)\nN players will participate in this competition, and they are given distinct integers from 1 through N.\nThe arena has M playing fields for two players. You need to assign each playing field two distinct integers between 1 and N (inclusive).\nYou cannot assign the same integer to multiple playing fields.\nThe competition consists of N rounds, each of which proceeds as follows:\n\nFor each player, if there is a playing field that is assigned the player's integer, the player goes to that field and fight the other player who comes there.\n\nThen, each player adds 1 to its integer. If it becomes N+1, change it to 1.\n\nYou want to ensure that no player fights the same opponent more than once during the N rounds.\nPrint an assignment of integers to the playing fields satisfying this condition.\nIt can be proved that such an assignment always exists under the constraints given.\n\nConstraints\n\n1 \\leq M\n\nM \\times 2 +1 \\leq N \\leq 200000\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\n\nOutput\n\nPrint M lines in the format below.\nThe i-th line should contain the two integers a_i and b_i assigned to the i-th playing field.\n\na_1 b_1\na_2 b_2\n:\na_M b_M\n\nSample Input 1\n\n4 1\n\nSample Output 1\n\n2 3\n\nLet us call the four players A, B, C, and D, and assume that they are initially given the integers 1, 2, 3, and 4, respectively.\n\nThe 1-st round is fought by B and C, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 2, 3, 4, and 1, respectively.\n\nThe 2-nd round is fought by A and B, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 3, 4, 1, and 2, respectively.\n\nThe 3-rd round is fought by D and A, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 4, 1, 2, and 3, respectively.\n\nThe 4-th round is fought by C and D, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 1, 2, 3, and 4, respectively.\n\nNo player fights the same opponent more than once during the four rounds, so this solution will be accepted.\n\nSample Input 2\n\n7 3\n\nSample Output 2\n\n1 6\n2 5\n3 4", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1091, "cpu_time_ms": 132, "memory_kb": 3548}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s552000481", "group_id": "codeNet:p02697", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n    int N, M;\n    cin >> N >> M;\n    int LL, LR, RL, RR;\n    LL = 1;\n    LR = N / 2;\n    RL = LR + 1;\n    RR = N;\n    if(N % 2 == 0) LR--;\n    int count = 0;\n    while(true){\n        cout << RL << \" \" << RR << endl;\n        count++;\n        if(count == M) break;\n        RL++;\n        RR--;\n        cout << LL << \" \" << LR << endl;\n        count++;\n        if(count == M) break;\n        LL++;\n        LR++;\n    }\n}", "language": "C++", "metadata": {"date": 1588473431, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02697.html", "problem_id": "p02697", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02697/input.txt", "sample_output_relpath": "derived/input_output/data/p02697/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02697/C++/s552000481.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s552000481", "user_id": "u811542492"}, "prompt_components": {"gold_output": "2 3\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n    int N, M;\n    cin >> N >> M;\n    int LL, LR, RL, RR;\n    LL = 1;\n    LR = N / 2;\n    RL = LR + 1;\n    RR = N;\n    if(N % 2 == 0) LR--;\n    int count = 0;\n    while(true){\n        cout << RL << \" \" << RR << endl;\n        count++;\n        if(count == M) break;\n        RL++;\n        RR--;\n        cout << LL << \" \" << LR << endl;\n        count++;\n        if(count == M) break;\n        LL++;\n        LR++;\n    }\n}", "problem_context": "Score : 500 points\n\nProblem Statement\n\nYou are going to hold a competition of one-to-one game called AtCoder Janken. (Janken is the Japanese name for Rock-paper-scissors.)\nN players will participate in this competition, and they are given distinct integers from 1 through N.\nThe arena has M playing fields for two players. You need to assign each playing field two distinct integers between 1 and N (inclusive).\nYou cannot assign the same integer to multiple playing fields.\nThe competition consists of N rounds, each of which proceeds as follows:\n\nFor each player, if there is a playing field that is assigned the player's integer, the player goes to that field and fight the other player who comes there.\n\nThen, each player adds 1 to its integer. If it becomes N+1, change it to 1.\n\nYou want to ensure that no player fights the same opponent more than once during the N rounds.\nPrint an assignment of integers to the playing fields satisfying this condition.\nIt can be proved that such an assignment always exists under the constraints given.\n\nConstraints\n\n1 \\leq M\n\nM \\times 2 +1 \\leq N \\leq 200000\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\n\nOutput\n\nPrint M lines in the format below.\nThe i-th line should contain the two integers a_i and b_i assigned to the i-th playing field.\n\na_1 b_1\na_2 b_2\n:\na_M b_M\n\nSample Input 1\n\n4 1\n\nSample Output 1\n\n2 3\n\nLet us call the four players A, B, C, and D, and assume that they are initially given the integers 1, 2, 3, and 4, respectively.\n\nThe 1-st round is fought by B and C, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 2, 3, 4, and 1, respectively.\n\nThe 2-nd round is fought by A and B, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 3, 4, 1, and 2, respectively.\n\nThe 3-rd round is fought by D and A, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 4, 1, 2, and 3, respectively.\n\nThe 4-th round is fought by C and D, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 1, 2, 3, and 4, respectively.\n\nNo player fights the same opponent more than once during the four rounds, so this solution will be accepted.\n\nSample Input 2\n\n7 3\n\nSample Output 2\n\n1 6\n2 5\n3 4", "sample_input": "4 1\n"}, "reference_outputs": ["2 3\n"], "source_document_id": "p02697", "source_text": "Score : 500 points\n\nProblem Statement\n\nYou are going to hold a competition of one-to-one game called AtCoder Janken. (Janken is the Japanese name for Rock-paper-scissors.)\nN players will participate in this competition, and they are given distinct integers from 1 through N.\nThe arena has M playing fields for two players. You need to assign each playing field two distinct integers between 1 and N (inclusive).\nYou cannot assign the same integer to multiple playing fields.\nThe competition consists of N rounds, each of which proceeds as follows:\n\nFor each player, if there is a playing field that is assigned the player's integer, the player goes to that field and fight the other player who comes there.\n\nThen, each player adds 1 to its integer. If it becomes N+1, change it to 1.\n\nYou want to ensure that no player fights the same opponent more than once during the N rounds.\nPrint an assignment of integers to the playing fields satisfying this condition.\nIt can be proved that such an assignment always exists under the constraints given.\n\nConstraints\n\n1 \\leq M\n\nM \\times 2 +1 \\leq N \\leq 200000\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\n\nOutput\n\nPrint M lines in the format below.\nThe i-th line should contain the two integers a_i and b_i assigned to the i-th playing field.\n\na_1 b_1\na_2 b_2\n:\na_M b_M\n\nSample Input 1\n\n4 1\n\nSample Output 1\n\n2 3\n\nLet us call the four players A, B, C, and D, and assume that they are initially given the integers 1, 2, 3, and 4, respectively.\n\nThe 1-st round is fought by B and C, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 2, 3, 4, and 1, respectively.\n\nThe 2-nd round is fought by A and B, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 3, 4, 1, and 2, respectively.\n\nThe 3-rd round is fought by D and A, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 4, 1, 2, and 3, respectively.\n\nThe 4-th round is fought by C and D, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 1, 2, 3, and 4, respectively.\n\nNo player fights the same opponent more than once during the four rounds, so this solution will be accepted.\n\nSample Input 2\n\n7 3\n\nSample Output 2\n\n1 6\n2 5\n3 4", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 472, "cpu_time_ms": 134, "memory_kb": 3604}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s096759321", "group_id": "codeNet:p02697", "input_text": "#include <bits/stdc++.h> //Andrei Alexandru a.k.a Sho10\n#define ll long long int\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"Ofast\")\n#define all(a) (a).begin(), (a).end()\n#define sz size\n#define f first\n#define s second\n#define pb push_back\n#define er erase\n#define in insert\n#define mp make_pair\n#define pi pair\n#define rc(s) return cout<<s,0\n#define endl '\\n'\n#define mod 1000000007\n#define PI 3.14159265359\n#define CODE_START  ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0);\nusing namespace std;\nll n,m,q,ans=0,a[55],b[55],c[55],d[55];\nvector<ll>v;\nint32_t main(){\nCODE_START;\ncin>>n>>m;\nif(n%2==1){\n    n--;\nll l=1,r=n;\nfor(ll i=0;i<m;i++)\n{\n    cout<<l<<' '<<r<<endl;\n    l++;\n    r--;\n}\n}else {\nll l=1,r=n;\nfor(ll i=0;i<m;i++)\n{\n    cout<<l<<' '<<r;\n    l++;\n    r=r-2;\n}\n}\n}\n", "language": "C++", "metadata": {"date": 1588472679, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02697.html", "problem_id": "p02697", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02697/input.txt", "sample_output_relpath": "derived/input_output/data/p02697/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02697/C++/s096759321.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s096759321", "user_id": "u794807449"}, "prompt_components": {"gold_output": "2 3\n", "input_to_evaluate": "#include <bits/stdc++.h> //Andrei Alexandru a.k.a Sho10\n#define ll long long int\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"Ofast\")\n#define all(a) (a).begin(), (a).end()\n#define sz size\n#define f first\n#define s second\n#define pb push_back\n#define er erase\n#define in insert\n#define mp make_pair\n#define pi pair\n#define rc(s) return cout<<s,0\n#define endl '\\n'\n#define mod 1000000007\n#define PI 3.14159265359\n#define CODE_START  ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0);\nusing namespace std;\nll n,m,q,ans=0,a[55],b[55],c[55],d[55];\nvector<ll>v;\nint32_t main(){\nCODE_START;\ncin>>n>>m;\nif(n%2==1){\n    n--;\nll l=1,r=n;\nfor(ll i=0;i<m;i++)\n{\n    cout<<l<<' '<<r<<endl;\n    l++;\n    r--;\n}\n}else {\nll l=1,r=n;\nfor(ll i=0;i<m;i++)\n{\n    cout<<l<<' '<<r;\n    l++;\n    r=r-2;\n}\n}\n}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nYou are going to hold a competition of one-to-one game called AtCoder Janken. (Janken is the Japanese name for Rock-paper-scissors.)\nN players will participate in this competition, and they are given distinct integers from 1 through N.\nThe arena has M playing fields for two players. You need to assign each playing field two distinct integers between 1 and N (inclusive).\nYou cannot assign the same integer to multiple playing fields.\nThe competition consists of N rounds, each of which proceeds as follows:\n\nFor each player, if there is a playing field that is assigned the player's integer, the player goes to that field and fight the other player who comes there.\n\nThen, each player adds 1 to its integer. If it becomes N+1, change it to 1.\n\nYou want to ensure that no player fights the same opponent more than once during the N rounds.\nPrint an assignment of integers to the playing fields satisfying this condition.\nIt can be proved that such an assignment always exists under the constraints given.\n\nConstraints\n\n1 \\leq M\n\nM \\times 2 +1 \\leq N \\leq 200000\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\n\nOutput\n\nPrint M lines in the format below.\nThe i-th line should contain the two integers a_i and b_i assigned to the i-th playing field.\n\na_1 b_1\na_2 b_2\n:\na_M b_M\n\nSample Input 1\n\n4 1\n\nSample Output 1\n\n2 3\n\nLet us call the four players A, B, C, and D, and assume that they are initially given the integers 1, 2, 3, and 4, respectively.\n\nThe 1-st round is fought by B and C, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 2, 3, 4, and 1, respectively.\n\nThe 2-nd round is fought by A and B, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 3, 4, 1, and 2, respectively.\n\nThe 3-rd round is fought by D and A, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 4, 1, 2, and 3, respectively.\n\nThe 4-th round is fought by C and D, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 1, 2, 3, and 4, respectively.\n\nNo player fights the same opponent more than once during the four rounds, so this solution will be accepted.\n\nSample Input 2\n\n7 3\n\nSample Output 2\n\n1 6\n2 5\n3 4", "sample_input": "4 1\n"}, "reference_outputs": ["2 3\n"], "source_document_id": "p02697", "source_text": "Score : 500 points\n\nProblem Statement\n\nYou are going to hold a competition of one-to-one game called AtCoder Janken. (Janken is the Japanese name for Rock-paper-scissors.)\nN players will participate in this competition, and they are given distinct integers from 1 through N.\nThe arena has M playing fields for two players. You need to assign each playing field two distinct integers between 1 and N (inclusive).\nYou cannot assign the same integer to multiple playing fields.\nThe competition consists of N rounds, each of which proceeds as follows:\n\nFor each player, if there is a playing field that is assigned the player's integer, the player goes to that field and fight the other player who comes there.\n\nThen, each player adds 1 to its integer. If it becomes N+1, change it to 1.\n\nYou want to ensure that no player fights the same opponent more than once during the N rounds.\nPrint an assignment of integers to the playing fields satisfying this condition.\nIt can be proved that such an assignment always exists under the constraints given.\n\nConstraints\n\n1 \\leq M\n\nM \\times 2 +1 \\leq N \\leq 200000\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\n\nOutput\n\nPrint M lines in the format below.\nThe i-th line should contain the two integers a_i and b_i assigned to the i-th playing field.\n\na_1 b_1\na_2 b_2\n:\na_M b_M\n\nSample Input 1\n\n4 1\n\nSample Output 1\n\n2 3\n\nLet us call the four players A, B, C, and D, and assume that they are initially given the integers 1, 2, 3, and 4, respectively.\n\nThe 1-st round is fought by B and C, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 2, 3, 4, and 1, respectively.\n\nThe 2-nd round is fought by A and B, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 3, 4, 1, and 2, respectively.\n\nThe 3-rd round is fought by D and A, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 4, 1, 2, and 3, respectively.\n\nThe 4-th round is fought by C and D, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 1, 2, 3, and 4, respectively.\n\nNo player fights the same opponent more than once during the four rounds, so this solution will be accepted.\n\nSample Input 2\n\n7 3\n\nSample Output 2\n\n1 6\n2 5\n3 4", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 796, "cpu_time_ms": 17, "memory_kb": 3692}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s302902696", "group_id": "codeNet:p02697", "input_text": "#include<bits/stdc++.h>\n#define ll long long\n#define ALL(v) (v).begin(),(v).end()\n#define REP(i,p,n) for(int i=p;i<(int)(n);++i)\n#define rep(i,n) REP(i,0,n)\n#define dump(a) (cerr << #a << \"=\" << (a) << endl)\n#define DUMP(list) cout << \"{ \"; for(auto nth : list){ cout << nth << \" \"; } cout << \"}\" << endl;\ntemplate<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return true; } return false; }\ntemplate<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return true; } return false; }\n\nusing namespace std;\ntypedef pair<ll, ll> pint;\n\nconst int MOD = 1000000007;\nvoid yesno(bool b) {\n    if (b) {\n        cout << \"Yes\" << endl;\n    }     else {\n        cout << \"No\" << endl;\n    }\n}\n\nint main() {\n    int N, M;\n    cin >> N >> M;\n    ll l = 1;\n    ll r = N;\n//    rep(i, M) {\n//            cout << l << \" \" << r << endl;\n//            l++;\n//            r--;\n//    }\n    if (N % 2 == 0) {\n        rep(i, M) {\n            if (i != M- 1) {\n                cout << l << \" \" << r << endl;\n                l++;\n                r--;\n            } else {\n                r--;\n                cout << l << \" \" << r << endl;\n            }\n        }\n    } else {\n        rep(i, M) {\n            cout << l << \" \" << r << endl;\n            l++;\n            r--;\n        }\n    }\n}\n", "language": "C++", "metadata": {"date": 1588471980, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02697.html", "problem_id": "p02697", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02697/input.txt", "sample_output_relpath": "derived/input_output/data/p02697/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02697/C++/s302902696.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s302902696", "user_id": "u545305086"}, "prompt_components": {"gold_output": "2 3\n", "input_to_evaluate": "#include<bits/stdc++.h>\n#define ll long long\n#define ALL(v) (v).begin(),(v).end()\n#define REP(i,p,n) for(int i=p;i<(int)(n);++i)\n#define rep(i,n) REP(i,0,n)\n#define dump(a) (cerr << #a << \"=\" << (a) << endl)\n#define DUMP(list) cout << \"{ \"; for(auto nth : list){ cout << nth << \" \"; } cout << \"}\" << endl;\ntemplate<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return true; } return false; }\ntemplate<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return true; } return false; }\n\nusing namespace std;\ntypedef pair<ll, ll> pint;\n\nconst int MOD = 1000000007;\nvoid yesno(bool b) {\n    if (b) {\n        cout << \"Yes\" << endl;\n    }     else {\n        cout << \"No\" << endl;\n    }\n}\n\nint main() {\n    int N, M;\n    cin >> N >> M;\n    ll l = 1;\n    ll r = N;\n//    rep(i, M) {\n//            cout << l << \" \" << r << endl;\n//            l++;\n//            r--;\n//    }\n    if (N % 2 == 0) {\n        rep(i, M) {\n            if (i != M- 1) {\n                cout << l << \" \" << r << endl;\n                l++;\n                r--;\n            } else {\n                r--;\n                cout << l << \" \" << r << endl;\n            }\n        }\n    } else {\n        rep(i, M) {\n            cout << l << \" \" << r << endl;\n            l++;\n            r--;\n        }\n    }\n}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nYou are going to hold a competition of one-to-one game called AtCoder Janken. (Janken is the Japanese name for Rock-paper-scissors.)\nN players will participate in this competition, and they are given distinct integers from 1 through N.\nThe arena has M playing fields for two players. You need to assign each playing field two distinct integers between 1 and N (inclusive).\nYou cannot assign the same integer to multiple playing fields.\nThe competition consists of N rounds, each of which proceeds as follows:\n\nFor each player, if there is a playing field that is assigned the player's integer, the player goes to that field and fight the other player who comes there.\n\nThen, each player adds 1 to its integer. If it becomes N+1, change it to 1.\n\nYou want to ensure that no player fights the same opponent more than once during the N rounds.\nPrint an assignment of integers to the playing fields satisfying this condition.\nIt can be proved that such an assignment always exists under the constraints given.\n\nConstraints\n\n1 \\leq M\n\nM \\times 2 +1 \\leq N \\leq 200000\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\n\nOutput\n\nPrint M lines in the format below.\nThe i-th line should contain the two integers a_i and b_i assigned to the i-th playing field.\n\na_1 b_1\na_2 b_2\n:\na_M b_M\n\nSample Input 1\n\n4 1\n\nSample Output 1\n\n2 3\n\nLet us call the four players A, B, C, and D, and assume that they are initially given the integers 1, 2, 3, and 4, respectively.\n\nThe 1-st round is fought by B and C, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 2, 3, 4, and 1, respectively.\n\nThe 2-nd round is fought by A and B, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 3, 4, 1, and 2, respectively.\n\nThe 3-rd round is fought by D and A, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 4, 1, 2, and 3, respectively.\n\nThe 4-th round is fought by C and D, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 1, 2, 3, and 4, respectively.\n\nNo player fights the same opponent more than once during the four rounds, so this solution will be accepted.\n\nSample Input 2\n\n7 3\n\nSample Output 2\n\n1 6\n2 5\n3 4", "sample_input": "4 1\n"}, "reference_outputs": ["2 3\n"], "source_document_id": "p02697", "source_text": "Score : 500 points\n\nProblem Statement\n\nYou are going to hold a competition of one-to-one game called AtCoder Janken. (Janken is the Japanese name for Rock-paper-scissors.)\nN players will participate in this competition, and they are given distinct integers from 1 through N.\nThe arena has M playing fields for two players. You need to assign each playing field two distinct integers between 1 and N (inclusive).\nYou cannot assign the same integer to multiple playing fields.\nThe competition consists of N rounds, each of which proceeds as follows:\n\nFor each player, if there is a playing field that is assigned the player's integer, the player goes to that field and fight the other player who comes there.\n\nThen, each player adds 1 to its integer. If it becomes N+1, change it to 1.\n\nYou want to ensure that no player fights the same opponent more than once during the N rounds.\nPrint an assignment of integers to the playing fields satisfying this condition.\nIt can be proved that such an assignment always exists under the constraints given.\n\nConstraints\n\n1 \\leq M\n\nM \\times 2 +1 \\leq N \\leq 200000\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\n\nOutput\n\nPrint M lines in the format below.\nThe i-th line should contain the two integers a_i and b_i assigned to the i-th playing field.\n\na_1 b_1\na_2 b_2\n:\na_M b_M\n\nSample Input 1\n\n4 1\n\nSample Output 1\n\n2 3\n\nLet us call the four players A, B, C, and D, and assume that they are initially given the integers 1, 2, 3, and 4, respectively.\n\nThe 1-st round is fought by B and C, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 2, 3, 4, and 1, respectively.\n\nThe 2-nd round is fought by A and B, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 3, 4, 1, and 2, respectively.\n\nThe 3-rd round is fought by D and A, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 4, 1, 2, and 3, respectively.\n\nThe 4-th round is fought by C and D, who has the integers 2 and 3, respectively. After this round, A, B, C, and D have the integers 1, 2, 3, and 4, respectively.\n\nNo player fights the same opponent more than once during the four rounds, so this solution will be accepted.\n\nSample Input 2\n\n7 3\n\nSample Output 2\n\n1 6\n2 5\n3 4", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1289, "cpu_time_ms": 135, "memory_kb": 3640}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s762349234", "group_id": "codeNet:p02698", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n#include <ext/pb_ds/assoc_container.hpp>\n#include <ext/pb_ds/tree_policy.hpp>\nusing namespace __gnu_pbds;\n#define M1 \t\t\t\t\t1000000007\n#define M2 \t\t\t\t\t998244353\n#define ll \t\t\t\t\tint\n#define pll \t\t\t\tpair<ll,ll>\n#define mll \t\t\t\tmap<ll,ll>\n#define F \t\t\t\t\tfirst\n#define S \t\t\t\t\tsecond\n#define PB \t\t\t\t\tpush_back\n#define mp \t\t\t\t\tmake_pair\n#define lb \t\t\t\t\tlower_bound\n#define ub \t\t\t\t\tupper_bound\n#define V(a) \t\t\t\tvector<a>\n#define endl \t\t\t\t'\\n'\n#define test(t) \t\t\twhile(t--)\n#define PI \t\t\t\t\tacos(-1.0)\n#define rep(i,a,b) \t\t\tfor(ll i=a;i<b;i++)\n#define repp(i,b,a) \t\tfor(ll i=b-1;i>=a;i--)\n#define clr(ar, val)\t\tmemset(ar, val, sizeof(ar))\n#define setbits(x) \t\t\t__builtin_popcountll(x)\n#define zrobits(x) \t\t\t__builtin_ctzll(x)\n#define ps(y) \t\t\t\tfixed << setprecision(y)\n#define all(x) \t\t\t\tbegin(x),end(x)\n#define allr(x) \t\t\trbegin(x),rend(x)\nconst int inf= \t\t\t\t0x3f3f3f3f;\n// const ll INF= \t\t\t\t0x3f3f3f3f3f3f3f3f;\nconst int dx[4]= \t\t\t{ 0, -1, 0, 1 };\nconst int dy[4]= \t\t\t{ -1, 0, 1, 0 };\n\nunsigned  int  randInt (){ \n    static  unsigned  int  tx  =  123456789 ,  ty = 362436069 ,  tz = 521288629 ,  tw = 88675123 ; \n    unsigned  int  tt  =  ( tx ^ ( tx << 11 )); \n    tx  =  ty ;  ty  =  tz ;  tz  =  tw ; \n    return  (  tw = ( tw^ ( tw >> 19 )) ^ ( tt ^ ( tt >> 8 ))  ); \n}\n\nmt19937 rng(chrono::steady_clock::now().time_since_epoch().count());\ntemplate<typename T>\n#define o_set(T) tree<T, null_type,less<T>, rb_tree_tag,tree_order_statistics_node_update>\n//member functions :\n//1. order_of_key(k) : number of elements strictly lesser than k\n//2. find_by_order(k) : k-th element in the set\n\nll floor_div(ll a, ll b) {\n\treturn a / b - (((a ^ b) < 0) and a % b);\n}\nll ceil_div(ll a, ll b){\n    return a / b + (((a ^ b) >= 0) and a % b);\n}\n\nvector<int> suffix_array_cyclic(string s){\n    int n = s.size(), N = n + 256;\n    vector<int> sa(n), ra(n);\n    for(int i = 0; i < n; i++) sa[i] = i, ra[i] = s[i];\n    for(int k = 0; k < n; k ? k *= 2 : k++)\n    {\n        vector<int> nsa(sa), nra(n), cnt(N);\n        for(int i = 0; i < n; i++) nsa[i] = (nsa[i] - k + n) % n;\n        for(int i = 0; i < n; i++) cnt[ra[i]]++;\n        for(int i = 1; i < N; i++) cnt[i] += cnt[i - 1];\n        for(int i = n - 1; i >= 0; i--) sa[--cnt[ra[nsa[i]]]] = nsa[i];\n \n        int r = 0;\n        for(int i = 1; i < n; i++)\n        {\n            if(ra[sa[i]] != ra[sa[i - 1]]) r++;\n            else if(ra[(sa[i] + k) % n] != ra[(sa[i - 1] + k) % n]) r++;\n            nra[sa[i]] = r;\n        }\n        ra = nra;\n    }\n    return sa;\n}\n \nvector<int> kasai(string s, vector<int> sa)\n{\n    int n = s.size(), k = 0;\n    vector<int> ra(n), lcp(n);\n    for(int i = 0; i < n; i++) ra[sa[i]] = i;\n    for(int i = 0; i < n; i++)\n    {\n        if(k) k--;\n        if(ra[i] == n - 1) {k = 0; continue;}\n        int j = sa[ra[i] + 1];\n        while(k < n && s[(i + k) % n] == s[(j + k) % n]) k++;\n        lcp[ra[i]] = k;\n        if(ra[(sa[ra[i]] + 1) % n] > ra[(sa[ra[j]] + 1) % n]) k = 0;\n    }\n    return lcp;\n}\n\ninline void INP()\n{\n\t#ifndef ONLINE_JUDGE\n\t    freopen(\"input.txt\",\"r\",stdin);   \n\t    freopen(\"output.txt\",\"w\",stdout);\n\t#endif \n}\nV(ll) adj[200005];\nll n,k;\nll val[200005];\nll dp[200005];\no_set(int) v;\n\nll mytree[800005];\n\n\nvoid build(ll ind, ll l, ll r){\n    if (l == r){\n        mytree[ind] = 0;\n        return;\n    }\n    ll mid = (l+r)/2;\n    build(2*ind,l,mid);\n    build(2*ind+1,mid+1,r);\n    mytree[ind] = max(mytree[2*ind],mytree[2*ind+1]);\n}\n\nvoid update(ll ind, ll l, ll r, ll t, ll val){\n    if (t < l || t > r){\n        return;\n    }\n    if (l == r){\n        mytree[ind] = val;\n        return;\n    }\n    ll mid = (l+r)/2;\n    update(2*ind,l,mid,t,val);\n    update(2*ind+1,mid+1,r,t,val);\n    mytree[ind] = max(mytree[2*ind],mytree[2*ind+1]);\n\n}\n\nll query(ll ind, ll l, ll r, ll qs, ll qe){\n    if (qe < l || qs > r){\n        return -1;\n    }\n    if (l >= qs && r <= qe){\n        return mytree[ind];\n    }\n    ll mid = (l+r)/2;\n    return max(query(2*ind,l,mid,qs,qe),query(2*ind+1,mid+1,r,qs,qe));\n}\nmap<ll,bool> visited;\nvoid dfs(ll node, ll depth){\n    visited[node] = 1;\n    ll qps = v.order_of_key(val[node]);\n    v.insert(val[node]);\n    ll qry = query(1,0,n-1,0,max(qps-1,0))+1;\n    dp[node] =qry;\n    update(1,0,n-1,depth,dp[node]);\n    dp[node] = query(1,0,n-1,0,n-1);\n    \n    for(ll child:adj[node]){\n        if (!visited[child]){\n            dfs(child,depth+1);\n        }\n    }\n    v.erase(val[node]);\n    update(1,0,n-1,depth,0);\n}\n\nvoid solve()\n{\n\t\n\tcin >> n;\n    rep(i,1,n+1) cin >> val[i];\n    rep(i,0,n-1){\n        ll x,y;\n        cin >> x >> y;\n        adj[x].PB(y);\n        adj[y].PB(x);\n    }\n    rep(i,0,200005) dp[i] = 1;\n    build(1,0,n-1);\n    dfs(1,0);\n\trep(i,1,n+1) cout << dp[i] << endl;\n}\n\nint32_t main(){\n    ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);\n    int t=1;\n    // cin>>t;\n    test(t){\n        solve();\n    }\n    return 0;\n}", "language": "C++", "metadata": {"date": 1588538937, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02698.html", "problem_id": "p02698", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02698/input.txt", "sample_output_relpath": "derived/input_output/data/p02698/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02698/C++/s762349234.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s762349234", "user_id": "u050982791"}, "prompt_components": {"gold_output": "1\n2\n3\n3\n4\n4\n5\n2\n2\n3\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n#include <ext/pb_ds/assoc_container.hpp>\n#include <ext/pb_ds/tree_policy.hpp>\nusing namespace __gnu_pbds;\n#define M1 \t\t\t\t\t1000000007\n#define M2 \t\t\t\t\t998244353\n#define ll \t\t\t\t\tint\n#define pll \t\t\t\tpair<ll,ll>\n#define mll \t\t\t\tmap<ll,ll>\n#define F \t\t\t\t\tfirst\n#define S \t\t\t\t\tsecond\n#define PB \t\t\t\t\tpush_back\n#define mp \t\t\t\t\tmake_pair\n#define lb \t\t\t\t\tlower_bound\n#define ub \t\t\t\t\tupper_bound\n#define V(a) \t\t\t\tvector<a>\n#define endl \t\t\t\t'\\n'\n#define test(t) \t\t\twhile(t--)\n#define PI \t\t\t\t\tacos(-1.0)\n#define rep(i,a,b) \t\t\tfor(ll i=a;i<b;i++)\n#define repp(i,b,a) \t\tfor(ll i=b-1;i>=a;i--)\n#define clr(ar, val)\t\tmemset(ar, val, sizeof(ar))\n#define setbits(x) \t\t\t__builtin_popcountll(x)\n#define zrobits(x) \t\t\t__builtin_ctzll(x)\n#define ps(y) \t\t\t\tfixed << setprecision(y)\n#define all(x) \t\t\t\tbegin(x),end(x)\n#define allr(x) \t\t\trbegin(x),rend(x)\nconst int inf= \t\t\t\t0x3f3f3f3f;\n// const ll INF= \t\t\t\t0x3f3f3f3f3f3f3f3f;\nconst int dx[4]= \t\t\t{ 0, -1, 0, 1 };\nconst int dy[4]= \t\t\t{ -1, 0, 1, 0 };\n\nunsigned  int  randInt (){ \n    static  unsigned  int  tx  =  123456789 ,  ty = 362436069 ,  tz = 521288629 ,  tw = 88675123 ; \n    unsigned  int  tt  =  ( tx ^ ( tx << 11 )); \n    tx  =  ty ;  ty  =  tz ;  tz  =  tw ; \n    return  (  tw = ( tw^ ( tw >> 19 )) ^ ( tt ^ ( tt >> 8 ))  ); \n}\n\nmt19937 rng(chrono::steady_clock::now().time_since_epoch().count());\ntemplate<typename T>\n#define o_set(T) tree<T, null_type,less<T>, rb_tree_tag,tree_order_statistics_node_update>\n//member functions :\n//1. order_of_key(k) : number of elements strictly lesser than k\n//2. find_by_order(k) : k-th element in the set\n\nll floor_div(ll a, ll b) {\n\treturn a / b - (((a ^ b) < 0) and a % b);\n}\nll ceil_div(ll a, ll b){\n    return a / b + (((a ^ b) >= 0) and a % b);\n}\n\nvector<int> suffix_array_cyclic(string s){\n    int n = s.size(), N = n + 256;\n    vector<int> sa(n), ra(n);\n    for(int i = 0; i < n; i++) sa[i] = i, ra[i] = s[i];\n    for(int k = 0; k < n; k ? k *= 2 : k++)\n    {\n        vector<int> nsa(sa), nra(n), cnt(N);\n        for(int i = 0; i < n; i++) nsa[i] = (nsa[i] - k + n) % n;\n        for(int i = 0; i < n; i++) cnt[ra[i]]++;\n        for(int i = 1; i < N; i++) cnt[i] += cnt[i - 1];\n        for(int i = n - 1; i >= 0; i--) sa[--cnt[ra[nsa[i]]]] = nsa[i];\n \n        int r = 0;\n        for(int i = 1; i < n; i++)\n        {\n            if(ra[sa[i]] != ra[sa[i - 1]]) r++;\n            else if(ra[(sa[i] + k) % n] != ra[(sa[i - 1] + k) % n]) r++;\n            nra[sa[i]] = r;\n        }\n        ra = nra;\n    }\n    return sa;\n}\n \nvector<int> kasai(string s, vector<int> sa)\n{\n    int n = s.size(), k = 0;\n    vector<int> ra(n), lcp(n);\n    for(int i = 0; i < n; i++) ra[sa[i]] = i;\n    for(int i = 0; i < n; i++)\n    {\n        if(k) k--;\n        if(ra[i] == n - 1) {k = 0; continue;}\n        int j = sa[ra[i] + 1];\n        while(k < n && s[(i + k) % n] == s[(j + k) % n]) k++;\n        lcp[ra[i]] = k;\n        if(ra[(sa[ra[i]] + 1) % n] > ra[(sa[ra[j]] + 1) % n]) k = 0;\n    }\n    return lcp;\n}\n\ninline void INP()\n{\n\t#ifndef ONLINE_JUDGE\n\t    freopen(\"input.txt\",\"r\",stdin);   \n\t    freopen(\"output.txt\",\"w\",stdout);\n\t#endif \n}\nV(ll) adj[200005];\nll n,k;\nll val[200005];\nll dp[200005];\no_set(int) v;\n\nll mytree[800005];\n\n\nvoid build(ll ind, ll l, ll r){\n    if (l == r){\n        mytree[ind] = 0;\n        return;\n    }\n    ll mid = (l+r)/2;\n    build(2*ind,l,mid);\n    build(2*ind+1,mid+1,r);\n    mytree[ind] = max(mytree[2*ind],mytree[2*ind+1]);\n}\n\nvoid update(ll ind, ll l, ll r, ll t, ll val){\n    if (t < l || t > r){\n        return;\n    }\n    if (l == r){\n        mytree[ind] = val;\n        return;\n    }\n    ll mid = (l+r)/2;\n    update(2*ind,l,mid,t,val);\n    update(2*ind+1,mid+1,r,t,val);\n    mytree[ind] = max(mytree[2*ind],mytree[2*ind+1]);\n\n}\n\nll query(ll ind, ll l, ll r, ll qs, ll qe){\n    if (qe < l || qs > r){\n        return -1;\n    }\n    if (l >= qs && r <= qe){\n        return mytree[ind];\n    }\n    ll mid = (l+r)/2;\n    return max(query(2*ind,l,mid,qs,qe),query(2*ind+1,mid+1,r,qs,qe));\n}\nmap<ll,bool> visited;\nvoid dfs(ll node, ll depth){\n    visited[node] = 1;\n    ll qps = v.order_of_key(val[node]);\n    v.insert(val[node]);\n    ll qry = query(1,0,n-1,0,max(qps-1,0))+1;\n    dp[node] =qry;\n    update(1,0,n-1,depth,dp[node]);\n    dp[node] = query(1,0,n-1,0,n-1);\n    \n    for(ll child:adj[node]){\n        if (!visited[child]){\n            dfs(child,depth+1);\n        }\n    }\n    v.erase(val[node]);\n    update(1,0,n-1,depth,0);\n}\n\nvoid solve()\n{\n\t\n\tcin >> n;\n    rep(i,1,n+1) cin >> val[i];\n    rep(i,0,n-1){\n        ll x,y;\n        cin >> x >> y;\n        adj[x].PB(y);\n        adj[y].PB(x);\n    }\n    rep(i,0,200005) dp[i] = 1;\n    build(1,0,n-1);\n    dfs(1,0);\n\trep(i,1,n+1) cout << dp[i] << endl;\n}\n\nint32_t main(){\n    ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);\n    int t=1;\n    // cin>>t;\n    test(t){\n        solve();\n    }\n    return 0;\n}", "problem_context": "Score : 600 points\n\nProblem Statement\n\nWe have a tree with N vertices, whose i-th edge connects Vertex u_i and Vertex v_i.\nVertex i has an integer a_i written on it.\nFor every integer k from 1 through N, solve the following problem:\n\nWe will make a sequence by lining up the integers written on the vertices along the shortest path from Vertex 1 to Vertex k, in the order they appear. Find the length of the longest increasing subsequence of this sequence.\n\nHere, the longest increasing subsequence of a sequence A of length L is the subsequence A_{i_1} , A_{i_2} , ... , A_{i_M} with the greatest possible value of M such that 1 \\leq i_1 < i_2 < ... < i_M \\leq L and A_{i_1} < A_{i_2} < ... < A_{i_M}.\n\nConstraints\n\n2 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq a_i \\leq 10^9\n\n1 \\leq u_i , v_i \\leq N\n\nu_i \\neq v_i\n\nThe given graph is a tree.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_N\nu_1 v_1\nu_2 v_2\n:\nu_{N-1} v_{N-1}\n\nOutput\n\nPrint N lines. The k-th line, print the length of the longest increasing subsequence of the sequence obtained from the shortest path from Vertex 1 to Vertex k.\n\nSample Input 1\n\n10\n1 2 5 3 4 6 7 3 2 4\n1 2\n2 3\n3 4\n4 5\n3 6\n6 7\n1 8\n8 9\n9 10\n\nSample Output 1\n\n1\n2\n3\n3\n4\n4\n5\n2\n2\n3\n\nFor example, the sequence A obtained from the shortest path from Vertex 1 to Vertex 5 is 1,2,5,3,4. Its longest increasing subsequence is A_1, A_2, A_4, A_5, with the length of 4.", "sample_input": "10\n1 2 5 3 4 6 7 3 2 4\n1 2\n2 3\n3 4\n4 5\n3 6\n6 7\n1 8\n8 9\n9 10\n"}, "reference_outputs": ["1\n2\n3\n3\n4\n4\n5\n2\n2\n3\n"], "source_document_id": "p02698", "source_text": "Score : 600 points\n\nProblem Statement\n\nWe have a tree with N vertices, whose i-th edge connects Vertex u_i and Vertex v_i.\nVertex i has an integer a_i written on it.\nFor every integer k from 1 through N, solve the following problem:\n\nWe will make a sequence by lining up the integers written on the vertices along the shortest path from Vertex 1 to Vertex k, in the order they appear. Find the length of the longest increasing subsequence of this sequence.\n\nHere, the longest increasing subsequence of a sequence A of length L is the subsequence A_{i_1} , A_{i_2} , ... , A_{i_M} with the greatest possible value of M such that 1 \\leq i_1 < i_2 < ... < i_M \\leq L and A_{i_1} < A_{i_2} < ... < A_{i_M}.\n\nConstraints\n\n2 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq a_i \\leq 10^9\n\n1 \\leq u_i , v_i \\leq N\n\nu_i \\neq v_i\n\nThe given graph is a tree.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_N\nu_1 v_1\nu_2 v_2\n:\nu_{N-1} v_{N-1}\n\nOutput\n\nPrint N lines. The k-th line, print the length of the longest increasing subsequence of the sequence obtained from the shortest path from Vertex 1 to Vertex k.\n\nSample Input 1\n\n10\n1 2 5 3 4 6 7 3 2 4\n1 2\n2 3\n3 4\n4 5\n3 6\n6 7\n1 8\n8 9\n9 10\n\nSample Output 1\n\n1\n2\n3\n3\n4\n4\n5\n2\n2\n3\n\nFor example, the sequence A obtained from the shortest path from Vertex 1 to Vertex 5 is 1,2,5,3,4. Its longest increasing subsequence is A_1, A_2, A_4, A_5, with the length of 4.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 4893, "cpu_time_ms": 501, "memory_kb": 47632}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s256636496", "group_id": "codeNet:p02699", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define int           long long\n#define S             second\n#define F             first\n#define pb            push_back\n#define all(c)        (c).begin(),(c).end()\n#define rall(c)       (c).rbegin(),(c).rend() \n#define lb            lower_bound\n#define si(c)         (int)((c).size())\n#define lcm(a, b)      (a * (b / __gcd(a,b)))  \n#define inf           (long long )(1e18+1)\n#define endl          '\\n'\n#define mp            make_pair\n#define time(s)       (double(clock()-s)/double(CLOCKS_PER_SEC))\n#define debug(args...)    _F(#args, args)\n#define vi            std::vector<int>\n#define pii           pair<int, int> \n#define vpi           vector<pii>\n\nclock_t start;\nmt19937_64 rng(chrono::system_clock::now().time_since_epoch().count());\n\ntemplate<typename T> void _F(const char *name, T arg1){\n    cerr << name << \" = \" << arg1 << endl;\n}\ntemplate<typename T, typename... Args> void _F(const char *names, T arg1, Args... args){\n    const char *name = strchr(names, ',');\n    cerr.write(names, name-names) << \" = \" << arg1 << endl;\n    _F(name+2, args...);\n}\ntemplate<typename T1, typename T2> istream& operator>>(istream& in, pair<T1, T2> &q){\n    in >> q.F >> q.S; return in;\n}\ntemplate<typename T1, typename T2> ostream& operator<<(ostream& out, pair<T1, T2> &q){\n    out << q.F << \" \" << q.S; return out;\n}\ntemplate< typename T1, typename T2> pair<T1, T2> operator+(pair<T1, T2> p1, pair<T1, T2> p2){\n    return {p1.F+p2.F, p1.S+p2.S};\n}\ntemplate< typename T1, typename T2> pair<T1, T2> operator-(pair<T1, T2> p1, pair<T1, T2> p2){\n    return {p1.F-p2.F, p1.S-p2.S};\n}\n\nvoid solve(){\n    int s, w;\n    cin >> s >> w;\n    if(w >= s){\n        cout << \"unsafe\" << endl;\n    }else{\n        cout << \"safe\" << endl;\n    }\n}\n\nsigned main(){\n\n    ios_base::sync_with_stdio(0); \n    cin.tie(0); cout.tie(0);   \n\n    int t = 1;\n    start = clock(); \n\n    cout << fixed << setprecision(12);\n\n    #ifndef ONLINE_JUDGE\n    freopen(\"input.txt\", \"r\", stdin); \n    freopen(\"output.txt\", \"w\", stdout);\n    freopen(\"error.txt\", \"w\", stderr);\n    #endif\n\n    //cin >> t;\n\n    for(int i = 1; i <= t; ++i){\n        //cout << \"Case #\" << i << \": \"; \n        solve();\n       // cout << endl;\n    }\n    //cerr << time(start);\n    return 0;\n}", "language": "C++", "metadata": {"date": 1588016550, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02699.html", "problem_id": "p02699", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02699/input.txt", "sample_output_relpath": "derived/input_output/data/p02699/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02699/C++/s256636496.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s256636496", "user_id": "u613865539"}, "prompt_components": {"gold_output": "unsafe\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define int           long long\n#define S             second\n#define F             first\n#define pb            push_back\n#define all(c)        (c).begin(),(c).end()\n#define rall(c)       (c).rbegin(),(c).rend() \n#define lb            lower_bound\n#define si(c)         (int)((c).size())\n#define lcm(a, b)      (a * (b / __gcd(a,b)))  \n#define inf           (long long )(1e18+1)\n#define endl          '\\n'\n#define mp            make_pair\n#define time(s)       (double(clock()-s)/double(CLOCKS_PER_SEC))\n#define debug(args...)    _F(#args, args)\n#define vi            std::vector<int>\n#define pii           pair<int, int> \n#define vpi           vector<pii>\n\nclock_t start;\nmt19937_64 rng(chrono::system_clock::now().time_since_epoch().count());\n\ntemplate<typename T> void _F(const char *name, T arg1){\n    cerr << name << \" = \" << arg1 << endl;\n}\ntemplate<typename T, typename... Args> void _F(const char *names, T arg1, Args... args){\n    const char *name = strchr(names, ',');\n    cerr.write(names, name-names) << \" = \" << arg1 << endl;\n    _F(name+2, args...);\n}\ntemplate<typename T1, typename T2> istream& operator>>(istream& in, pair<T1, T2> &q){\n    in >> q.F >> q.S; return in;\n}\ntemplate<typename T1, typename T2> ostream& operator<<(ostream& out, pair<T1, T2> &q){\n    out << q.F << \" \" << q.S; return out;\n}\ntemplate< typename T1, typename T2> pair<T1, T2> operator+(pair<T1, T2> p1, pair<T1, T2> p2){\n    return {p1.F+p2.F, p1.S+p2.S};\n}\ntemplate< typename T1, typename T2> pair<T1, T2> operator-(pair<T1, T2> p1, pair<T1, T2> p2){\n    return {p1.F-p2.F, p1.S-p2.S};\n}\n\nvoid solve(){\n    int s, w;\n    cin >> s >> w;\n    if(w >= s){\n        cout << \"unsafe\" << endl;\n    }else{\n        cout << \"safe\" << endl;\n    }\n}\n\nsigned main(){\n\n    ios_base::sync_with_stdio(0); \n    cin.tie(0); cout.tie(0);   \n\n    int t = 1;\n    start = clock(); \n\n    cout << fixed << setprecision(12);\n\n    #ifndef ONLINE_JUDGE\n    freopen(\"input.txt\", \"r\", stdin); \n    freopen(\"output.txt\", \"w\", stdout);\n    freopen(\"error.txt\", \"w\", stderr);\n    #endif\n\n    //cin >> t;\n\n    for(int i = 1; i <= t; ++i){\n        //cout << \"Case #\" << i << \": \"; \n        solve();\n       // cout << endl;\n    }\n    //cerr << time(start);\n    return 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nThere are S sheep and W wolves.\n\nIf the number of wolves is greater than or equal to that of sheep, the wolves will attack the sheep.\n\nIf the wolves will attack the sheep, print unsafe; otherwise, print safe.\n\nConstraints\n\n1 \\leq S \\leq 100\n\n1 \\leq W \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS W\n\nOutput\n\nIf the wolves will attack the sheep, print unsafe; otherwise, print safe.\n\nSample Input 1\n\n4 5\n\nSample Output 1\n\nunsafe\n\nThere are four sheep and five wolves. The number of wolves is not less than that of sheep, so they will attack them.\n\nSample Input 2\n\n100 2\n\nSample Output 2\n\nsafe\n\nMany a sheep drive away two wolves.\n\nSample Input 3\n\n10 10\n\nSample Output 3\n\nunsafe", "sample_input": "4 5\n"}, "reference_outputs": ["unsafe\n"], "source_document_id": "p02699", "source_text": "Score : 100 points\n\nProblem Statement\n\nThere are S sheep and W wolves.\n\nIf the number of wolves is greater than or equal to that of sheep, the wolves will attack the sheep.\n\nIf the wolves will attack the sheep, print unsafe; otherwise, print safe.\n\nConstraints\n\n1 \\leq S \\leq 100\n\n1 \\leq W \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS W\n\nOutput\n\nIf the wolves will attack the sheep, print unsafe; otherwise, print safe.\n\nSample Input 1\n\n4 5\n\nSample Output 1\n\nunsafe\n\nThere are four sheep and five wolves. The number of wolves is not less than that of sheep, so they will attack them.\n\nSample Input 2\n\n100 2\n\nSample Output 2\n\nsafe\n\nMany a sheep drive away two wolves.\n\nSample Input 3\n\n10 10\n\nSample Output 3\n\nunsafe", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2272, "cpu_time_ms": 5, "memory_kb": 3640}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s857500067", "group_id": "codeNet:p02701", "input_text": "#include <iostream>\n#include <algorithm>\n#include <vector>\n#include <bits/stdc++.h>\nusing namespace std;\n\nbool isKaibun(string s);\n\nint main()\n{\n   int num;\n   cin >> num;\n   //景品の種類が、すでに持っている景品の種類と一致しているかみて、一致していなければインクリメントする\n\n   string temp;\n   int ans = 0;\n\n   vector<string> list(num+1, \"111\");\n\n   //くじ引き1つ1つについて確認\n   for ( int i = 1; i <= num; i++)\n   {\n       cin >> temp;\n\n       for(int k = 1; k <= num; k++)\n       {\n           if(list[k] == \"111\")\n           {\n               list[k] = temp;\n               ans++;\n               break;\n           }\n\n           if(list[k] == temp)\n           {\n               //重複している\n               break;\n           }\n       }\n   }\n\n   cout << ans << endl;\n   \n}", "language": "C++", "metadata": {"date": 1589080638, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02701.html", "problem_id": "p02701", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02701/input.txt", "sample_output_relpath": "derived/input_output/data/p02701/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02701/C++/s857500067.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s857500067", "user_id": "u969223279"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <iostream>\n#include <algorithm>\n#include <vector>\n#include <bits/stdc++.h>\nusing namespace std;\n\nbool isKaibun(string s);\n\nint main()\n{\n   int num;\n   cin >> num;\n   //景品の種類が、すでに持っている景品の種類と一致しているかみて、一致していなければインクリメントする\n\n   string temp;\n   int ans = 0;\n\n   vector<string> list(num+1, \"111\");\n\n   //くじ引き1つ1つについて確認\n   for ( int i = 1; i <= num; i++)\n   {\n       cin >> temp;\n\n       for(int k = 1; k <= num; k++)\n       {\n           if(list[k] == \"111\")\n           {\n               list[k] = temp;\n               ans++;\n               break;\n           }\n\n           if(list[k] == temp)\n           {\n               //重複している\n               break;\n           }\n       }\n   }\n\n   cout << ans << endl;\n   \n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nYou drew lottery N times. In the i-th draw, you got an item of the kind represented by a string S_i.\n\nHow many kinds of items did you get?\n\nConstraints\n\n1 \\leq N \\leq 2\\times 10^5\n\nS_i consists of lowercase English letters and has a length between 1 and 10 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS_1\n:\nS_N\n\nOutput\n\nPrint the number of kinds of items you got.\n\nSample Input 1\n\n3\napple\norange\napple\n\nSample Output 1\n\n2\n\nYou got two kinds of items: apple and orange.\n\nSample Input 2\n\n5\ngrape\ngrape\ngrape\ngrape\ngrape\n\nSample Output 2\n\n1\n\nSample Input 3\n\n4\naaaa\na\naaa\naa\n\nSample Output 3\n\n4", "sample_input": "3\napple\norange\napple\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02701", "source_text": "Score : 300 points\n\nProblem Statement\n\nYou drew lottery N times. In the i-th draw, you got an item of the kind represented by a string S_i.\n\nHow many kinds of items did you get?\n\nConstraints\n\n1 \\leq N \\leq 2\\times 10^5\n\nS_i consists of lowercase English letters and has a length between 1 and 10 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS_1\n:\nS_N\n\nOutput\n\nPrint the number of kinds of items you got.\n\nSample Input 1\n\n3\napple\norange\napple\n\nSample Output 1\n\n2\n\nYou got two kinds of items: apple and orange.\n\nSample Input 2\n\n5\ngrape\ngrape\ngrape\ngrape\ngrape\n\nSample Output 2\n\n1\n\nSample Input 3\n\n4\naaaa\na\naaa\naa\n\nSample Output 3\n\n4", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 842, "cpu_time_ms": 2206, "memory_kb": 9632}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s150071938", "group_id": "codeNet:p02701", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(void)\n{\n\tint N;\n\tcin >> N;\n\n\tvector<string> S(N);\n\tfor (int i = 0; i < N; i++) {\n\t\tcin >> S.at(i);\n\t}\n\n\tint cnt = 0;\n\tfor (int i = 0; i < N; i++) {\n\t\tint flag = 0;\n\t\tfor (int j = 0; j < i; j++) {\n\t\t\tif (i != j && S.at(i).at(0) == S.at(j).at(0)) {\n\t\t\t\tif (S.at(i) == S.at(j)){\n\t\t\t\t\tflag++;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif (flag == 0 || i == 0) cnt++;\n\t\tflag = 0;\n\t}\n\n\tcout << cnt << endl;\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1587952322, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02701.html", "problem_id": "p02701", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02701/input.txt", "sample_output_relpath": "derived/input_output/data/p02701/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02701/C++/s150071938.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s150071938", "user_id": "u175174084"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(void)\n{\n\tint N;\n\tcin >> N;\n\n\tvector<string> S(N);\n\tfor (int i = 0; i < N; i++) {\n\t\tcin >> S.at(i);\n\t}\n\n\tint cnt = 0;\n\tfor (int i = 0; i < N; i++) {\n\t\tint flag = 0;\n\t\tfor (int j = 0; j < i; j++) {\n\t\t\tif (i != j && S.at(i).at(0) == S.at(j).at(0)) {\n\t\t\t\tif (S.at(i) == S.at(j)){\n\t\t\t\t\tflag++;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif (flag == 0 || i == 0) cnt++;\n\t\tflag = 0;\n\t}\n\n\tcout << cnt << endl;\n\treturn 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nYou drew lottery N times. In the i-th draw, you got an item of the kind represented by a string S_i.\n\nHow many kinds of items did you get?\n\nConstraints\n\n1 \\leq N \\leq 2\\times 10^5\n\nS_i consists of lowercase English letters and has a length between 1 and 10 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS_1\n:\nS_N\n\nOutput\n\nPrint the number of kinds of items you got.\n\nSample Input 1\n\n3\napple\norange\napple\n\nSample Output 1\n\n2\n\nYou got two kinds of items: apple and orange.\n\nSample Input 2\n\n5\ngrape\ngrape\ngrape\ngrape\ngrape\n\nSample Output 2\n\n1\n\nSample Input 3\n\n4\naaaa\na\naaa\naa\n\nSample Output 3\n\n4", "sample_input": "3\napple\norange\napple\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02701", "source_text": "Score : 300 points\n\nProblem Statement\n\nYou drew lottery N times. In the i-th draw, you got an item of the kind represented by a string S_i.\n\nHow many kinds of items did you get?\n\nConstraints\n\n1 \\leq N \\leq 2\\times 10^5\n\nS_i consists of lowercase English letters and has a length between 1 and 10 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS_1\n:\nS_N\n\nOutput\n\nPrint the number of kinds of items you got.\n\nSample Input 1\n\n3\napple\norange\napple\n\nSample Output 1\n\n2\n\nYou got two kinds of items: apple and orange.\n\nSample Input 2\n\n5\ngrape\ngrape\ngrape\ngrape\ngrape\n\nSample Output 2\n\n1\n\nSample Input 3\n\n4\naaaa\na\naaa\naa\n\nSample Output 3\n\n4", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 457, "cpu_time_ms": 2206, "memory_kb": 9600}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s723169438", "group_id": "codeNet:p02701", "input_text": "#pragma region\n#define _USE_MATH_DEFINES\n#include <iostream>\n#include <string>\n#include <algorithm>\n#include <cmath>\n#include <cstdlib>\n#include <vector>\n#include <map>\n#include <queue>\n#include <stack>\n#include <set>\n#include <list>\n#include <iomanip>\n#include <cstdint>\n#include <cstdlib>\n\nusing namespace std;\ntypedef long long ll;\n//#define rep(i, s, e) for (int(i) = (s); (i) < (e); ++(i))\n#define rep(i, e) for (int(i) = 0; (i) < (e); ++(i))\n#define rrep(i, s) for (int(i) = (s) - 1; (i) >= 0; --(i))\n#define all(x) x.begin(),x.end()\n#pragma endregion\n\n\nint main()\n{\n\tint n; cin >> n;\n\tset<string> s;\n\trep(i, n)\n\t{\n\t\tstring t; cin >> t;\n\t\ts.insert(t);\n\t}\n\tcout << s.size() << endl;\n}\n", "language": "C++", "metadata": {"date": 1587949463, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02701.html", "problem_id": "p02701", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02701/input.txt", "sample_output_relpath": "derived/input_output/data/p02701/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02701/C++/s723169438.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s723169438", "user_id": "u521389909"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#pragma region\n#define _USE_MATH_DEFINES\n#include <iostream>\n#include <string>\n#include <algorithm>\n#include <cmath>\n#include <cstdlib>\n#include <vector>\n#include <map>\n#include <queue>\n#include <stack>\n#include <set>\n#include <list>\n#include <iomanip>\n#include <cstdint>\n#include <cstdlib>\n\nusing namespace std;\ntypedef long long ll;\n//#define rep(i, s, e) for (int(i) = (s); (i) < (e); ++(i))\n#define rep(i, e) for (int(i) = 0; (i) < (e); ++(i))\n#define rrep(i, s) for (int(i) = (s) - 1; (i) >= 0; --(i))\n#define all(x) x.begin(),x.end()\n#pragma endregion\n\n\nint main()\n{\n\tint n; cin >> n;\n\tset<string> s;\n\trep(i, n)\n\t{\n\t\tstring t; cin >> t;\n\t\ts.insert(t);\n\t}\n\tcout << s.size() << endl;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nYou drew lottery N times. In the i-th draw, you got an item of the kind represented by a string S_i.\n\nHow many kinds of items did you get?\n\nConstraints\n\n1 \\leq N \\leq 2\\times 10^5\n\nS_i consists of lowercase English letters and has a length between 1 and 10 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS_1\n:\nS_N\n\nOutput\n\nPrint the number of kinds of items you got.\n\nSample Input 1\n\n3\napple\norange\napple\n\nSample Output 1\n\n2\n\nYou got two kinds of items: apple and orange.\n\nSample Input 2\n\n5\ngrape\ngrape\ngrape\ngrape\ngrape\n\nSample Output 2\n\n1\n\nSample Input 3\n\n4\naaaa\na\naaa\naa\n\nSample Output 3\n\n4", "sample_input": "3\napple\norange\napple\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02701", "source_text": "Score : 300 points\n\nProblem Statement\n\nYou drew lottery N times. In the i-th draw, you got an item of the kind represented by a string S_i.\n\nHow many kinds of items did you get?\n\nConstraints\n\n1 \\leq N \\leq 2\\times 10^5\n\nS_i consists of lowercase English letters and has a length between 1 and 10 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS_1\n:\nS_N\n\nOutput\n\nPrint the number of kinds of items you got.\n\nSample Input 1\n\n3\napple\norange\napple\n\nSample Output 1\n\n2\n\nYou got two kinds of items: apple and orange.\n\nSample Input 2\n\n5\ngrape\ngrape\ngrape\ngrape\ngrape\n\nSample Output 2\n\n1\n\nSample Input 3\n\n4\naaaa\na\naaa\naa\n\nSample Output 3\n\n4", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 690, "cpu_time_ms": 208, "memory_kb": 19220}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s235844901", "group_id": "codeNet:p02706", "input_text": "#include<iostream>\nusing namespace std;\nint main(){\n  int n,m,a[10005],sum = 0;\n  cin>>n>>m;\n  for(int i=0;i<m;i++){\n    cin>>a[i];\n    sum += a[i];\n  }\n  if(n>=sum){\n    cout<<n-sum<<'\\n';\n  }\n  else if(n<sum){\n    cout<<-1<<'\\n';\n  }\n  return 0;\n}", "language": "C++", "metadata": {"date": 1587345410, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02706.html", "problem_id": "p02706", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02706/input.txt", "sample_output_relpath": "derived/input_output/data/p02706/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02706/C++/s235844901.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s235844901", "user_id": "u364428932"}, "prompt_components": {"gold_output": "30\n", "input_to_evaluate": "#include<iostream>\nusing namespace std;\nint main(){\n  int n,m,a[10005],sum = 0;\n  cin>>n>>m;\n  for(int i=0;i<m;i++){\n    cin>>a[i];\n    sum += a[i];\n  }\n  if(n>=sum){\n    cout<<n-sum<<'\\n';\n  }\n  else if(n<sum){\n    cout<<-1<<'\\n';\n  }\n  return 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nTakahashi has N days of summer vacation.\n\nHis teacher gave him M summer assignments. It will take A_i days for him to do the i-th assignment.\n\nHe cannot do multiple assignments on the same day, or hang out on a day he does an assignment.\n\nWhat is the maximum number of days Takahashi can hang out during the vacation if he finishes all the assignments during this vacation?\n\nIf Takahashi cannot finish all the assignments during the vacation, print -1 instead.\n\nConstraints\n\n1 \\leq N \\leq 10^6\n\n1 \\leq M \\leq 10^4\n\n1 \\leq A_i \\leq 10^4\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 ... A_M\n\nOutput\n\nPrint the maximum number of days Takahashi can hang out during the vacation, or -1.\n\nSample Input 1\n\n41 2\n5 6\n\nSample Output 1\n\n30\n\nFor example, he can do the first assignment on the first 5 days, hang out on the next 30 days, and do the second assignment on the last 6 days of the vacation. In this way, he can safely spend 30 days hanging out.\n\nSample Input 2\n\n10 2\n5 6\n\nSample Output 2\n\n-1\n\nHe cannot finish his assignments.\n\nSample Input 3\n\n11 2\n5 6\n\nSample Output 3\n\n0\n\nHe can finish his assignments, but he will have no time to hang out.\n\nSample Input 4\n\n314 15\n9 26 5 35 8 9 79 3 23 8 46 2 6 43 3\n\nSample Output 4\n\n9", "sample_input": "41 2\n5 6\n"}, "reference_outputs": ["30\n"], "source_document_id": "p02706", "source_text": "Score : 200 points\n\nProblem Statement\n\nTakahashi has N days of summer vacation.\n\nHis teacher gave him M summer assignments. It will take A_i days for him to do the i-th assignment.\n\nHe cannot do multiple assignments on the same day, or hang out on a day he does an assignment.\n\nWhat is the maximum number of days Takahashi can hang out during the vacation if he finishes all the assignments during this vacation?\n\nIf Takahashi cannot finish all the assignments during the vacation, print -1 instead.\n\nConstraints\n\n1 \\leq N \\leq 10^6\n\n1 \\leq M \\leq 10^4\n\n1 \\leq A_i \\leq 10^4\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 ... A_M\n\nOutput\n\nPrint the maximum number of days Takahashi can hang out during the vacation, or -1.\n\nSample Input 1\n\n41 2\n5 6\n\nSample Output 1\n\n30\n\nFor example, he can do the first assignment on the first 5 days, hang out on the next 30 days, and do the second assignment on the last 6 days of the vacation. In this way, he can safely spend 30 days hanging out.\n\nSample Input 2\n\n10 2\n5 6\n\nSample Output 2\n\n-1\n\nHe cannot finish his assignments.\n\nSample Input 3\n\n11 2\n5 6\n\nSample Output 3\n\n0\n\nHe can finish his assignments, but he will have no time to hang out.\n\nSample Input 4\n\n314 15\n9 26 5 35 8 9 79 3 23 8 46 2 6 43 3\n\nSample Output 4\n\n9", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 249, "cpu_time_ms": 6, "memory_kb": 3664}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s498546782", "group_id": "codeNet:p02706", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nconst double PI = 3.141592653589793238463;\nint main()\n{\n    long long int n, sum = 0;\n    int m;\n    cin >> n >> m;\n    int a[m];\n    for (int i = 0; i < m; i++)\n    {\n        cin >> a[i];\n        sum += a[i];\n    }\n    if (sum <= n)\n    {\n        cout << n - sum;\n    }\n    else\n    {\n        cout << \"-1\";\n    }\n\n    return 0;\n}", "language": "C++", "metadata": {"date": 1587345186, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02706.html", "problem_id": "p02706", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02706/input.txt", "sample_output_relpath": "derived/input_output/data/p02706/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02706/C++/s498546782.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s498546782", "user_id": "u968850687"}, "prompt_components": {"gold_output": "30\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nconst double PI = 3.141592653589793238463;\nint main()\n{\n    long long int n, sum = 0;\n    int m;\n    cin >> n >> m;\n    int a[m];\n    for (int i = 0; i < m; i++)\n    {\n        cin >> a[i];\n        sum += a[i];\n    }\n    if (sum <= n)\n    {\n        cout << n - sum;\n    }\n    else\n    {\n        cout << \"-1\";\n    }\n\n    return 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nTakahashi has N days of summer vacation.\n\nHis teacher gave him M summer assignments. It will take A_i days for him to do the i-th assignment.\n\nHe cannot do multiple assignments on the same day, or hang out on a day he does an assignment.\n\nWhat is the maximum number of days Takahashi can hang out during the vacation if he finishes all the assignments during this vacation?\n\nIf Takahashi cannot finish all the assignments during the vacation, print -1 instead.\n\nConstraints\n\n1 \\leq N \\leq 10^6\n\n1 \\leq M \\leq 10^4\n\n1 \\leq A_i \\leq 10^4\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 ... A_M\n\nOutput\n\nPrint the maximum number of days Takahashi can hang out during the vacation, or -1.\n\nSample Input 1\n\n41 2\n5 6\n\nSample Output 1\n\n30\n\nFor example, he can do the first assignment on the first 5 days, hang out on the next 30 days, and do the second assignment on the last 6 days of the vacation. In this way, he can safely spend 30 days hanging out.\n\nSample Input 2\n\n10 2\n5 6\n\nSample Output 2\n\n-1\n\nHe cannot finish his assignments.\n\nSample Input 3\n\n11 2\n5 6\n\nSample Output 3\n\n0\n\nHe can finish his assignments, but he will have no time to hang out.\n\nSample Input 4\n\n314 15\n9 26 5 35 8 9 79 3 23 8 46 2 6 43 3\n\nSample Output 4\n\n9", "sample_input": "41 2\n5 6\n"}, "reference_outputs": ["30\n"], "source_document_id": "p02706", "source_text": "Score : 200 points\n\nProblem Statement\n\nTakahashi has N days of summer vacation.\n\nHis teacher gave him M summer assignments. It will take A_i days for him to do the i-th assignment.\n\nHe cannot do multiple assignments on the same day, or hang out on a day he does an assignment.\n\nWhat is the maximum number of days Takahashi can hang out during the vacation if he finishes all the assignments during this vacation?\n\nIf Takahashi cannot finish all the assignments during the vacation, print -1 instead.\n\nConstraints\n\n1 \\leq N \\leq 10^6\n\n1 \\leq M \\leq 10^4\n\n1 \\leq A_i \\leq 10^4\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 ... A_M\n\nOutput\n\nPrint the maximum number of days Takahashi can hang out during the vacation, or -1.\n\nSample Input 1\n\n41 2\n5 6\n\nSample Output 1\n\n30\n\nFor example, he can do the first assignment on the first 5 days, hang out on the next 30 days, and do the second assignment on the last 6 days of the vacation. In this way, he can safely spend 30 days hanging out.\n\nSample Input 2\n\n10 2\n5 6\n\nSample Output 2\n\n-1\n\nHe cannot finish his assignments.\n\nSample Input 3\n\n11 2\n5 6\n\nSample Output 3\n\n0\n\nHe can finish his assignments, but he will have no time to hang out.\n\nSample Input 4\n\n314 15\n9 26 5 35 8 9 79 3 23 8 46 2 6 43 3\n\nSample Output 4\n\n9", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 376, "cpu_time_ms": 6, "memory_kb": 3656}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s053514636", "group_id": "codeNet:p02706", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n    int n, m;\n    cin >> n >> m;\n    int sum = 0, a;\n    for(int i = 0; i < m; i++){\n        cin >> a;\n        sum += a;\n    }\n\n    if(n - sum >= 0) cout << n - sum << endl;\n    else cout << -1 << endl;\n\n}", "language": "C++", "metadata": {"date": 1587344777, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02706.html", "problem_id": "p02706", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02706/input.txt", "sample_output_relpath": "derived/input_output/data/p02706/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02706/C++/s053514636.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s053514636", "user_id": "u147762850"}, "prompt_components": {"gold_output": "30\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n    int n, m;\n    cin >> n >> m;\n    int sum = 0, a;\n    for(int i = 0; i < m; i++){\n        cin >> a;\n        sum += a;\n    }\n\n    if(n - sum >= 0) cout << n - sum << endl;\n    else cout << -1 << endl;\n\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nTakahashi has N days of summer vacation.\n\nHis teacher gave him M summer assignments. It will take A_i days for him to do the i-th assignment.\n\nHe cannot do multiple assignments on the same day, or hang out on a day he does an assignment.\n\nWhat is the maximum number of days Takahashi can hang out during the vacation if he finishes all the assignments during this vacation?\n\nIf Takahashi cannot finish all the assignments during the vacation, print -1 instead.\n\nConstraints\n\n1 \\leq N \\leq 10^6\n\n1 \\leq M \\leq 10^4\n\n1 \\leq A_i \\leq 10^4\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 ... A_M\n\nOutput\n\nPrint the maximum number of days Takahashi can hang out during the vacation, or -1.\n\nSample Input 1\n\n41 2\n5 6\n\nSample Output 1\n\n30\n\nFor example, he can do the first assignment on the first 5 days, hang out on the next 30 days, and do the second assignment on the last 6 days of the vacation. In this way, he can safely spend 30 days hanging out.\n\nSample Input 2\n\n10 2\n5 6\n\nSample Output 2\n\n-1\n\nHe cannot finish his assignments.\n\nSample Input 3\n\n11 2\n5 6\n\nSample Output 3\n\n0\n\nHe can finish his assignments, but he will have no time to hang out.\n\nSample Input 4\n\n314 15\n9 26 5 35 8 9 79 3 23 8 46 2 6 43 3\n\nSample Output 4\n\n9", "sample_input": "41 2\n5 6\n"}, "reference_outputs": ["30\n"], "source_document_id": "p02706", "source_text": "Score : 200 points\n\nProblem Statement\n\nTakahashi has N days of summer vacation.\n\nHis teacher gave him M summer assignments. It will take A_i days for him to do the i-th assignment.\n\nHe cannot do multiple assignments on the same day, or hang out on a day he does an assignment.\n\nWhat is the maximum number of days Takahashi can hang out during the vacation if he finishes all the assignments during this vacation?\n\nIf Takahashi cannot finish all the assignments during the vacation, print -1 instead.\n\nConstraints\n\n1 \\leq N \\leq 10^6\n\n1 \\leq M \\leq 10^4\n\n1 \\leq A_i \\leq 10^4\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 ... A_M\n\nOutput\n\nPrint the maximum number of days Takahashi can hang out during the vacation, or -1.\n\nSample Input 1\n\n41 2\n5 6\n\nSample Output 1\n\n30\n\nFor example, he can do the first assignment on the first 5 days, hang out on the next 30 days, and do the second assignment on the last 6 days of the vacation. In this way, he can safely spend 30 days hanging out.\n\nSample Input 2\n\n10 2\n5 6\n\nSample Output 2\n\n-1\n\nHe cannot finish his assignments.\n\nSample Input 3\n\n11 2\n5 6\n\nSample Output 3\n\n0\n\nHe can finish his assignments, but he will have no time to hang out.\n\nSample Input 4\n\n314 15\n9 26 5 35 8 9 79 3 23 8 46 2 6 43 3\n\nSample Output 4\n\n9", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 265, "cpu_time_ms": 7, "memory_kb": 3624}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s249554225", "group_id": "codeNet:p02707", "input_text": "#include <bits/stdc++.h>\ntypedef long long ll;\nusing namespace std;\n\nconst int INF = 1e9;\nconst int MOD = 1e9+7;\nconst ll LINF = 1e18;\n\n#define FOR(i,a,b) for(int i=(a);i<(b);++i)\n#define REP(i,n) for(int i=0;i<(n);++i)\n#define REPR(i,n) for(int i=n;i>=0;i--)\n#define ALL(v) (v.begin(),v.end())\n#define COUT(x) cout<<(x)<<'\\n'\n\nint main(){\n    int n;\n    cin >> n;\n    int a[200010];\n    int t;\n    REP(i,n-1){\n        cin >> t;\n        a[t]++;\n    }\n    for(int i=1;i<n+1;i++){\n        COUT(a[i]);\n    }\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1587345441, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02707.html", "problem_id": "p02707", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02707/input.txt", "sample_output_relpath": "derived/input_output/data/p02707/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02707/C++/s249554225.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s249554225", "user_id": "u459105164"}, "prompt_components": {"gold_output": "2\n2\n0\n0\n0\n", "input_to_evaluate": "#include <bits/stdc++.h>\ntypedef long long ll;\nusing namespace std;\n\nconst int INF = 1e9;\nconst int MOD = 1e9+7;\nconst ll LINF = 1e18;\n\n#define FOR(i,a,b) for(int i=(a);i<(b);++i)\n#define REP(i,n) for(int i=0;i<(n);++i)\n#define REPR(i,n) for(int i=n;i>=0;i--)\n#define ALL(v) (v.begin(),v.end())\n#define COUT(x) cout<<(x)<<'\\n'\n\nint main(){\n    int n;\n    cin >> n;\n    int a[200010];\n    int t;\n    REP(i,n-1){\n        cin >> t;\n        a[t]++;\n    }\n    for(int i=1;i<n+1;i++){\n        COUT(a[i]);\n    }\n    return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nA company has N members, who are assigned ID numbers 1, ..., N.\n\nEvery member, except the member numbered 1, has exactly one immediate boss with a smaller ID number.\n\nWhen a person X is the immediate boss of a person Y, the person Y is said to be an immediate subordinate of the person X.\n\nYou are given the information that the immediate boss of the member numbered i is the member numbered A_i. For each member, find how many immediate subordinates it has.\n\nConstraints\n\n2 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq A_i < i\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_2 ... A_N\n\nOutput\n\nFor each of the members numbered 1, 2, ..., N, print the number of immediate subordinates it has, in its own line.\n\nSample Input 1\n\n5\n1 1 2 2\n\nSample Output 1\n\n2\n2\n0\n0\n0\n\nThe member numbered 1 has two immediate subordinates: the members numbered 2 and 3.\n\nThe member numbered 2 has two immediate subordinates: the members numbered 4 and 5.\n\nThe members numbered 3, 4, and 5 do not have immediate subordinates.\n\nSample Input 2\n\n10\n1 1 1 1 1 1 1 1 1\n\nSample Output 2\n\n9\n0\n0\n0\n0\n0\n0\n0\n0\n0\n\nSample Input 3\n\n7\n1 2 3 4 5 6\n\nSample Output 3\n\n1\n1\n1\n1\n1\n1\n0", "sample_input": "5\n1 1 2 2\n"}, "reference_outputs": ["2\n2\n0\n0\n0\n"], "source_document_id": "p02707", "source_text": "Score : 300 points\n\nProblem Statement\n\nA company has N members, who are assigned ID numbers 1, ..., N.\n\nEvery member, except the member numbered 1, has exactly one immediate boss with a smaller ID number.\n\nWhen a person X is the immediate boss of a person Y, the person Y is said to be an immediate subordinate of the person X.\n\nYou are given the information that the immediate boss of the member numbered i is the member numbered A_i. For each member, find how many immediate subordinates it has.\n\nConstraints\n\n2 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq A_i < i\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_2 ... A_N\n\nOutput\n\nFor each of the members numbered 1, 2, ..., N, print the number of immediate subordinates it has, in its own line.\n\nSample Input 1\n\n5\n1 1 2 2\n\nSample Output 1\n\n2\n2\n0\n0\n0\n\nThe member numbered 1 has two immediate subordinates: the members numbered 2 and 3.\n\nThe member numbered 2 has two immediate subordinates: the members numbered 4 and 5.\n\nThe members numbered 3, 4, and 5 do not have immediate subordinates.\n\nSample Input 2\n\n10\n1 1 1 1 1 1 1 1 1\n\nSample Output 2\n\n9\n0\n0\n0\n0\n0\n0\n0\n0\n0\n\nSample Input 3\n\n7\n1 2 3 4 5 6\n\nSample Output 3\n\n1\n1\n1\n1\n1\n1\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 521, "cpu_time_ms": 62, "memory_kb": 4404}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s030448810", "group_id": "codeNet:p02707", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef long double ld;\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }\nconst ll INF=1LL<<60;\nconst int inf=1<<30;\nconst int mod=1e9+7;\nint main(){\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n    int n;cin >> n;\n    vector<int> c(n);\n    for(int i=0;i<n-1;i++){\n        int a;cin >> a;\n        a--;\n        c[a]++;\n    }\n    for(int i=0;i<n;i++){\n        cout << c[i] << endl;\n    }\n}", "language": "C++", "metadata": {"date": 1587344623, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02707.html", "problem_id": "p02707", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02707/input.txt", "sample_output_relpath": "derived/input_output/data/p02707/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02707/C++/s030448810.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s030448810", "user_id": "u244626757"}, "prompt_components": {"gold_output": "2\n2\n0\n0\n0\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef long double ld;\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }\nconst ll INF=1LL<<60;\nconst int inf=1<<30;\nconst int mod=1e9+7;\nint main(){\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n    int n;cin >> n;\n    vector<int> c(n);\n    for(int i=0;i<n-1;i++){\n        int a;cin >> a;\n        a--;\n        c[a]++;\n    }\n    for(int i=0;i<n;i++){\n        cout << c[i] << endl;\n    }\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nA company has N members, who are assigned ID numbers 1, ..., N.\n\nEvery member, except the member numbered 1, has exactly one immediate boss with a smaller ID number.\n\nWhen a person X is the immediate boss of a person Y, the person Y is said to be an immediate subordinate of the person X.\n\nYou are given the information that the immediate boss of the member numbered i is the member numbered A_i. For each member, find how many immediate subordinates it has.\n\nConstraints\n\n2 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq A_i < i\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_2 ... A_N\n\nOutput\n\nFor each of the members numbered 1, 2, ..., N, print the number of immediate subordinates it has, in its own line.\n\nSample Input 1\n\n5\n1 1 2 2\n\nSample Output 1\n\n2\n2\n0\n0\n0\n\nThe member numbered 1 has two immediate subordinates: the members numbered 2 and 3.\n\nThe member numbered 2 has two immediate subordinates: the members numbered 4 and 5.\n\nThe members numbered 3, 4, and 5 do not have immediate subordinates.\n\nSample Input 2\n\n10\n1 1 1 1 1 1 1 1 1\n\nSample Output 2\n\n9\n0\n0\n0\n0\n0\n0\n0\n0\n0\n\nSample Input 3\n\n7\n1 2 3 4 5 6\n\nSample Output 3\n\n1\n1\n1\n1\n1\n1\n0", "sample_input": "5\n1 1 2 2\n"}, "reference_outputs": ["2\n2\n0\n0\n0\n"], "source_document_id": "p02707", "source_text": "Score : 300 points\n\nProblem Statement\n\nA company has N members, who are assigned ID numbers 1, ..., N.\n\nEvery member, except the member numbered 1, has exactly one immediate boss with a smaller ID number.\n\nWhen a person X is the immediate boss of a person Y, the person Y is said to be an immediate subordinate of the person X.\n\nYou are given the information that the immediate boss of the member numbered i is the member numbered A_i. For each member, find how many immediate subordinates it has.\n\nConstraints\n\n2 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq A_i < i\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_2 ... A_N\n\nOutput\n\nFor each of the members numbered 1, 2, ..., N, print the number of immediate subordinates it has, in its own line.\n\nSample Input 1\n\n5\n1 1 2 2\n\nSample Output 1\n\n2\n2\n0\n0\n0\n\nThe member numbered 1 has two immediate subordinates: the members numbered 2 and 3.\n\nThe member numbered 2 has two immediate subordinates: the members numbered 4 and 5.\n\nThe members numbered 3, 4, and 5 do not have immediate subordinates.\n\nSample Input 2\n\n10\n1 1 1 1 1 1 1 1 1\n\nSample Output 2\n\n9\n0\n0\n0\n0\n0\n0\n0\n0\n0\n\nSample Input 3\n\n7\n1 2 3 4 5 6\n\nSample Output 3\n\n1\n1\n1\n1\n1\n1\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 584, "cpu_time_ms": 282, "memory_kb": 3992}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s097126888", "group_id": "codeNet:p02708", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n\nconst ll maxs = 1e5+5;\nconst ll lmaxs = 20;\nll mod = 1e9+7;\nll oo = 1e15;\n\n#define IOS ios_base::sync_with_stdio(false); cin.tie(nullptr); cout.tie(nullptr);\n#define pb push_back\n#define mp make_pair\n#define ff first\n#define ss second\n#define I insert\n#define endl '\\n'\n\nvoid pre(){\n\n}\n\nll get(ll x){\n    return x*(x-1)/2;\n}\n\nvoid solve(){ \n   ll n , k;\n   cin >> n >> k;\n   ll ans=0;\n   \n   for(ll i=k;i<=n+1;i++){\n       ll MIN = get(i);\n       ll MAX = n*i - get(i);\n       ans += MAX - MIN + 1; \n       ans %= mod;\n   }\n\n   cout << ans << endl;\n}\n\nint main(){\n    // #ifndef ONLINE_JUDGE\n    // freopen(\"input00.txt\",\"r\",stdin);\n    // #endif\n    IOS;\n    pre();\n    ll T = 1;   \n    //cin>>T;\n    while(T--){  \n        solve();\n    }\n    return 0;\n}", "language": "C++", "metadata": {"date": 1588498661, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02708.html", "problem_id": "p02708", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02708/input.txt", "sample_output_relpath": "derived/input_output/data/p02708/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02708/C++/s097126888.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s097126888", "user_id": "u299658942"}, "prompt_components": {"gold_output": "10\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n\nconst ll maxs = 1e5+5;\nconst ll lmaxs = 20;\nll mod = 1e9+7;\nll oo = 1e15;\n\n#define IOS ios_base::sync_with_stdio(false); cin.tie(nullptr); cout.tie(nullptr);\n#define pb push_back\n#define mp make_pair\n#define ff first\n#define ss second\n#define I insert\n#define endl '\\n'\n\nvoid pre(){\n\n}\n\nll get(ll x){\n    return x*(x-1)/2;\n}\n\nvoid solve(){ \n   ll n , k;\n   cin >> n >> k;\n   ll ans=0;\n   \n   for(ll i=k;i<=n+1;i++){\n       ll MIN = get(i);\n       ll MAX = n*i - get(i);\n       ans += MAX - MIN + 1; \n       ans %= mod;\n   }\n\n   cout << ans << endl;\n}\n\nint main(){\n    // #ifndef ONLINE_JUDGE\n    // freopen(\"input00.txt\",\"r\",stdin);\n    // #endif\n    IOS;\n    pre();\n    ll T = 1;   \n    //cin>>T;\n    while(T--){  \n        solve();\n    }\n    return 0;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nWe have N+1 integers: 10^{100}, 10^{100}+1, ..., 10^{100}+N.\n\nWe will choose K or more of these integers. Find the number of possible values of the sum of the chosen numbers, modulo (10^9+7).\n\nConstraints\n\n1 \\leq N \\leq 2\\times 10^5\n\n1 \\leq K \\leq N+1\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the number of possible values of the sum, modulo (10^9+7).\n\nSample Input 1\n\n3 2\n\nSample Output 1\n\n10\n\nThe sum can take 10 values, as follows:\n\n(10^{100})+(10^{100}+1)=2\\times 10^{100}+1\n\n(10^{100})+(10^{100}+2)=2\\times 10^{100}+2\n\n(10^{100})+(10^{100}+3)=(10^{100}+1)+(10^{100}+2)=2\\times 10^{100}+3\n\n(10^{100}+1)+(10^{100}+3)=2\\times 10^{100}+4\n\n(10^{100}+2)+(10^{100}+3)=2\\times 10^{100}+5\n\n(10^{100})+(10^{100}+1)+(10^{100}+2)=3\\times 10^{100}+3\n\n(10^{100})+(10^{100}+1)+(10^{100}+3)=3\\times 10^{100}+4\n\n(10^{100})+(10^{100}+2)+(10^{100}+3)=3\\times 10^{100}+5\n\n(10^{100}+1)+(10^{100}+2)+(10^{100}+3)=3\\times 10^{100}+6\n\n(10^{100})+(10^{100}+1)+(10^{100}+2)+(10^{100}+3)=4\\times 10^{100}+6\n\nSample Input 2\n\n200000 200001\n\nSample Output 2\n\n1\n\nWe must choose all of the integers, so the sum can take just 1 value.\n\nSample Input 3\n\n141421 35623\n\nSample Output 3\n\n220280457", "sample_input": "3 2\n"}, "reference_outputs": ["10\n"], "source_document_id": "p02708", "source_text": "Score : 400 points\n\nProblem Statement\n\nWe have N+1 integers: 10^{100}, 10^{100}+1, ..., 10^{100}+N.\n\nWe will choose K or more of these integers. Find the number of possible values of the sum of the chosen numbers, modulo (10^9+7).\n\nConstraints\n\n1 \\leq N \\leq 2\\times 10^5\n\n1 \\leq K \\leq N+1\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the number of possible values of the sum, modulo (10^9+7).\n\nSample Input 1\n\n3 2\n\nSample Output 1\n\n10\n\nThe sum can take 10 values, as follows:\n\n(10^{100})+(10^{100}+1)=2\\times 10^{100}+1\n\n(10^{100})+(10^{100}+2)=2\\times 10^{100}+2\n\n(10^{100})+(10^{100}+3)=(10^{100}+1)+(10^{100}+2)=2\\times 10^{100}+3\n\n(10^{100}+1)+(10^{100}+3)=2\\times 10^{100}+4\n\n(10^{100}+2)+(10^{100}+3)=2\\times 10^{100}+5\n\n(10^{100})+(10^{100}+1)+(10^{100}+2)=3\\times 10^{100}+3\n\n(10^{100})+(10^{100}+1)+(10^{100}+3)=3\\times 10^{100}+4\n\n(10^{100})+(10^{100}+2)+(10^{100}+3)=3\\times 10^{100}+5\n\n(10^{100}+1)+(10^{100}+2)+(10^{100}+3)=3\\times 10^{100}+6\n\n(10^{100})+(10^{100}+1)+(10^{100}+2)+(10^{100}+3)=4\\times 10^{100}+6\n\nSample Input 2\n\n200000 200001\n\nSample Output 2\n\n1\n\nWe must choose all of the integers, so the sum can take just 1 value.\n\nSample Input 3\n\n141421 35623\n\nSample Output 3\n\n220280457", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 822, "cpu_time_ms": 6, "memory_kb": 3616}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s353593963", "group_id": "codeNet:p02708", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n#define forr(i,a,n)\tfor(long long int i=a; i<n; i++)\n#define loop(i,a,n)\tfor(long long int i=a; i>=n; i--)\nconst long long int m=1e9+7;\nint main() \n{\t\n\tios_base :: sync_with_stdio(false),cin.tie(NULL),cout.tie(0);\t\n\n\tlong long int a,b,ct=0;\n\tcin>>a>>b;\n\tforr(i,b,a+2)\n\t{\n\t\tlong long int x=(i*(i-1)/2);\n\t\tlong long int y=(a*(a+1)/2)-((a-i)*(a-i+1)/2);\n\t\tct+=(y-x+1);\n\t\tct%=m;\n\t}\n\tcout<<ct;\n\t\n\treturn 0;\t\n}", "language": "C++", "metadata": {"date": 1587368300, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02708.html", "problem_id": "p02708", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02708/input.txt", "sample_output_relpath": "derived/input_output/data/p02708/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02708/C++/s353593963.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s353593963", "user_id": "u625431756"}, "prompt_components": {"gold_output": "10\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n#define forr(i,a,n)\tfor(long long int i=a; i<n; i++)\n#define loop(i,a,n)\tfor(long long int i=a; i>=n; i--)\nconst long long int m=1e9+7;\nint main() \n{\t\n\tios_base :: sync_with_stdio(false),cin.tie(NULL),cout.tie(0);\t\n\n\tlong long int a,b,ct=0;\n\tcin>>a>>b;\n\tforr(i,b,a+2)\n\t{\n\t\tlong long int x=(i*(i-1)/2);\n\t\tlong long int y=(a*(a+1)/2)-((a-i)*(a-i+1)/2);\n\t\tct+=(y-x+1);\n\t\tct%=m;\n\t}\n\tcout<<ct;\n\t\n\treturn 0;\t\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nWe have N+1 integers: 10^{100}, 10^{100}+1, ..., 10^{100}+N.\n\nWe will choose K or more of these integers. Find the number of possible values of the sum of the chosen numbers, modulo (10^9+7).\n\nConstraints\n\n1 \\leq N \\leq 2\\times 10^5\n\n1 \\leq K \\leq N+1\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the number of possible values of the sum, modulo (10^9+7).\n\nSample Input 1\n\n3 2\n\nSample Output 1\n\n10\n\nThe sum can take 10 values, as follows:\n\n(10^{100})+(10^{100}+1)=2\\times 10^{100}+1\n\n(10^{100})+(10^{100}+2)=2\\times 10^{100}+2\n\n(10^{100})+(10^{100}+3)=(10^{100}+1)+(10^{100}+2)=2\\times 10^{100}+3\n\n(10^{100}+1)+(10^{100}+3)=2\\times 10^{100}+4\n\n(10^{100}+2)+(10^{100}+3)=2\\times 10^{100}+5\n\n(10^{100})+(10^{100}+1)+(10^{100}+2)=3\\times 10^{100}+3\n\n(10^{100})+(10^{100}+1)+(10^{100}+3)=3\\times 10^{100}+4\n\n(10^{100})+(10^{100}+2)+(10^{100}+3)=3\\times 10^{100}+5\n\n(10^{100}+1)+(10^{100}+2)+(10^{100}+3)=3\\times 10^{100}+6\n\n(10^{100})+(10^{100}+1)+(10^{100}+2)+(10^{100}+3)=4\\times 10^{100}+6\n\nSample Input 2\n\n200000 200001\n\nSample Output 2\n\n1\n\nWe must choose all of the integers, so the sum can take just 1 value.\n\nSample Input 3\n\n141421 35623\n\nSample Output 3\n\n220280457", "sample_input": "3 2\n"}, "reference_outputs": ["10\n"], "source_document_id": "p02708", "source_text": "Score : 400 points\n\nProblem Statement\n\nWe have N+1 integers: 10^{100}, 10^{100}+1, ..., 10^{100}+N.\n\nWe will choose K or more of these integers. Find the number of possible values of the sum of the chosen numbers, modulo (10^9+7).\n\nConstraints\n\n1 \\leq N \\leq 2\\times 10^5\n\n1 \\leq K \\leq N+1\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the number of possible values of the sum, modulo (10^9+7).\n\nSample Input 1\n\n3 2\n\nSample Output 1\n\n10\n\nThe sum can take 10 values, as follows:\n\n(10^{100})+(10^{100}+1)=2\\times 10^{100}+1\n\n(10^{100})+(10^{100}+2)=2\\times 10^{100}+2\n\n(10^{100})+(10^{100}+3)=(10^{100}+1)+(10^{100}+2)=2\\times 10^{100}+3\n\n(10^{100}+1)+(10^{100}+3)=2\\times 10^{100}+4\n\n(10^{100}+2)+(10^{100}+3)=2\\times 10^{100}+5\n\n(10^{100})+(10^{100}+1)+(10^{100}+2)=3\\times 10^{100}+3\n\n(10^{100})+(10^{100}+1)+(10^{100}+3)=3\\times 10^{100}+4\n\n(10^{100})+(10^{100}+2)+(10^{100}+3)=3\\times 10^{100}+5\n\n(10^{100}+1)+(10^{100}+2)+(10^{100}+3)=3\\times 10^{100}+6\n\n(10^{100})+(10^{100}+1)+(10^{100}+2)+(10^{100}+3)=4\\times 10^{100}+6\n\nSample Input 2\n\n200000 200001\n\nSample Output 2\n\n1\n\nWe must choose all of the integers, so the sum can take just 1 value.\n\nSample Input 3\n\n141421 35623\n\nSample Output 3\n\n220280457", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 449, "cpu_time_ms": 3, "memory_kb": 3640}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s252227588", "group_id": "codeNet:p02709", "input_text": "#include <iostream>\n#include <sstream>\n#include <iomanip>\n#include <algorithm>\n#include <functional>\n#include <iterator>\n#include <numeric>\n#include <cstdint>\n#include <cmath>\n#include <bitset>\n#include <string>\n#include <list>\n#include <vector>\n#include <stack>\n#include <queue>\n#include <set>\n#include <map>\n\n#define N_TIMES(i, n)     for ( uint64_t i = 0;     i <  n; ++i )\n#define N_TIMES_REV(i, n) for (  int64_t i = n - 1; i >= 0; --i )\n\nusing namespace std;\n\nstruct VectorItem\n{\n  int64_t key, val;\n  VectorItem(int64_t key = 0, int64_t val = 0) : key(key), val(val) {}\n  bool operator>(const VectorItem &item) const {\n    return val > item.val;\n  }\n};\n\nint main()\n{\n  int64_t N;\n  cin >> N;\n\n  vector<VectorItem> A(N);\n  N_TIMES(n, N) {\n    int64_t a;\n    cin >> a;\n\n    A[n] = VectorItem(n, a);\n  }\n  sort(A.begin(), A.end(), greater<VectorItem>());\n\n  vector<vector<int64_t>> dp(N + 1, vector<int64_t>(N + 1, 0));\n  for (int64_t n = 0; n < N; ++n) {\n    for (int64_t x = 0; x <= n; ++x) {\n      int64_t y = n - x;\n      dp[x + 1][y] = max(dp[x + 1][y], dp[x][y] + A[n].val * (((N - 1) - x) - A[n].key));\n      dp[x][y + 1] = max(dp[x][y + 1], dp[x][y] + A[n].val * (A[n].key - y));\n    }\n  }\n\n  int64_t ans = 0;\n  for (int64_t x = 0; x <= N; ++x) {\n    int64_t y = N - x;\n    ans = max(ans, dp[x][y]);\n  }\n  cout << ans << endl;\n\n  return 0;\n}", "language": "C++", "metadata": {"date": 1587367286, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02709.html", "problem_id": "p02709", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02709/input.txt", "sample_output_relpath": "derived/input_output/data/p02709/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02709/C++/s252227588.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s252227588", "user_id": "u198355306"}, "prompt_components": {"gold_output": "20\n", "input_to_evaluate": "#include <iostream>\n#include <sstream>\n#include <iomanip>\n#include <algorithm>\n#include <functional>\n#include <iterator>\n#include <numeric>\n#include <cstdint>\n#include <cmath>\n#include <bitset>\n#include <string>\n#include <list>\n#include <vector>\n#include <stack>\n#include <queue>\n#include <set>\n#include <map>\n\n#define N_TIMES(i, n)     for ( uint64_t i = 0;     i <  n; ++i )\n#define N_TIMES_REV(i, n) for (  int64_t i = n - 1; i >= 0; --i )\n\nusing namespace std;\n\nstruct VectorItem\n{\n  int64_t key, val;\n  VectorItem(int64_t key = 0, int64_t val = 0) : key(key), val(val) {}\n  bool operator>(const VectorItem &item) const {\n    return val > item.val;\n  }\n};\n\nint main()\n{\n  int64_t N;\n  cin >> N;\n\n  vector<VectorItem> A(N);\n  N_TIMES(n, N) {\n    int64_t a;\n    cin >> a;\n\n    A[n] = VectorItem(n, a);\n  }\n  sort(A.begin(), A.end(), greater<VectorItem>());\n\n  vector<vector<int64_t>> dp(N + 1, vector<int64_t>(N + 1, 0));\n  for (int64_t n = 0; n < N; ++n) {\n    for (int64_t x = 0; x <= n; ++x) {\n      int64_t y = n - x;\n      dp[x + 1][y] = max(dp[x + 1][y], dp[x][y] + A[n].val * (((N - 1) - x) - A[n].key));\n      dp[x][y + 1] = max(dp[x][y + 1], dp[x][y] + A[n].val * (A[n].key - y));\n    }\n  }\n\n  int64_t ans = 0;\n  for (int64_t x = 0; x <= N; ++x) {\n    int64_t y = N - x;\n    ans = max(ans, dp[x][y]);\n  }\n  cout << ans << endl;\n\n  return 0;\n}", "problem_context": "Score : 500 points\n\nProblem Statement\n\nThere are N children standing in a line from left to right. The activeness of the i-th child from the left is A_i.\n\nYou can rearrange these children just one time in any order you like.\n\nWhen a child who originally occupies the x-th position from the left in the line moves to the y-th position from the left, that child earns A_x \\times |x-y| happiness points.\n\nFind the maximum total happiness points the children can earn.\n\nConstraints\n\n2 \\leq N \\leq 2000\n\n1 \\leq A_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the maximum total happiness points the children can earn.\n\nSample Input 1\n\n4\n1 3 4 2\n\nSample Output 1\n\n20\n\nIf we move the 1-st child from the left to the 3-rd position from the left, the 2-nd child to the 4-th position, the 3-rd child to the 1-st position, and the 4-th child to the 2-nd position, the children earns 1 \\times |1-3|+3 \\times |2-4|+4 \\times |3-1|+2 \\times |4-2|=20 happiness points in total.\n\nSample Input 2\n\n6\n5 5 6 1 1 1\n\nSample Output 2\n\n58\n\nSample Input 3\n\n6\n8 6 9 1 2 1\n\nSample Output 3\n\n85", "sample_input": "4\n1 3 4 2\n"}, "reference_outputs": ["20\n"], "source_document_id": "p02709", "source_text": "Score : 500 points\n\nProblem Statement\n\nThere are N children standing in a line from left to right. The activeness of the i-th child from the left is A_i.\n\nYou can rearrange these children just one time in any order you like.\n\nWhen a child who originally occupies the x-th position from the left in the line moves to the y-th position from the left, that child earns A_x \\times |x-y| happiness points.\n\nFind the maximum total happiness points the children can earn.\n\nConstraints\n\n2 \\leq N \\leq 2000\n\n1 \\leq A_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the maximum total happiness points the children can earn.\n\nSample Input 1\n\n4\n1 3 4 2\n\nSample Output 1\n\n20\n\nIf we move the 1-st child from the left to the 3-rd position from the left, the 2-nd child to the 4-th position, the 3-rd child to the 1-st position, and the 4-th child to the 2-nd position, the children earns 1 \\times |1-3|+3 \\times |2-4|+4 \\times |3-1|+2 \\times |4-2|=20 happiness points in total.\n\nSample Input 2\n\n6\n5 5 6 1 1 1\n\nSample Output 2\n\n58\n\nSample Input 3\n\n6\n8 6 9 1 2 1\n\nSample Output 3\n\n85", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1353, "cpu_time_ms": 41, "memory_kb": 34684}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s714366959", "group_id": "codeNet:p02712", "input_text": "#include <iostream>\n#include <vector>\n#include <string>\n#include <algorithm>\n#include <cmath>\n#include <stack>\n#include <queue>\n#include <set>\n#include <map>\n#include <iomanip>\nusing namespace std;\ntypedef long long ll;\ntypedef vector<int> VI;\ntypedef vector<ll> VL;\ntypedef vector<string> VS;\ntypedef vector< vector<int> > VVI;\ntypedef vector< vector<ll> > VVL;\ntypedef pair<int,int> PII;\ntypedef pair<ll,ll> PLL;\n#define rep(i,n) for(int i=0;i<(n);i++)\n#define all(a) (a).begin(),(a).end()\n#define pf push_front\n#define pb push_back\n#define mp make_pair\n#define mt make_tuple\n#define ub upper_bound\n#define lb lower_bound\n \nint main(){\n  int N;\n  cin>>N;\n  VI X(N);\n  rep(i,N) if((i+1)%3 and (i+1)%5) X[i]=i+1;\n  ll ans=0;\n  rep(i,N) ans+=X[i];\n  cout<<ans<<endl;\n}\n\n", "language": "C++", "metadata": {"date": 1586741852, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02712.html", "problem_id": "p02712", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02712/input.txt", "sample_output_relpath": "derived/input_output/data/p02712/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02712/C++/s714366959.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s714366959", "user_id": "u154756110"}, "prompt_components": {"gold_output": "60\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\n#include <string>\n#include <algorithm>\n#include <cmath>\n#include <stack>\n#include <queue>\n#include <set>\n#include <map>\n#include <iomanip>\nusing namespace std;\ntypedef long long ll;\ntypedef vector<int> VI;\ntypedef vector<ll> VL;\ntypedef vector<string> VS;\ntypedef vector< vector<int> > VVI;\ntypedef vector< vector<ll> > VVL;\ntypedef pair<int,int> PII;\ntypedef pair<ll,ll> PLL;\n#define rep(i,n) for(int i=0;i<(n);i++)\n#define all(a) (a).begin(),(a).end()\n#define pf push_front\n#define pb push_back\n#define mp make_pair\n#define mt make_tuple\n#define ub upper_bound\n#define lb lower_bound\n \nint main(){\n  int N;\n  cin>>N;\n  VI X(N);\n  rep(i,N) if((i+1)%3 and (i+1)%5) X[i]=i+1;\n  ll ans=0;\n  rep(i,N) ans+=X[i];\n  cout<<ans<<endl;\n}\n\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nLet us define the FizzBuzz sequence a_1,a_2,... as follows:\n\nIf both 3 and 5 divides i, a_i=\\mbox{FizzBuzz}.\n\nIf the above does not hold but 3 divides i, a_i=\\mbox{Fizz}.\n\nIf none of the above holds but 5 divides i, a_i=\\mbox{Buzz}.\n\nIf none of the above holds, a_i=i.\n\nFind the sum of all numbers among the first N terms of the FizzBuzz sequence.\n\nConstraints\n\n1 \\leq N \\leq 10^6\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the sum of all numbers among the first N terms of the FizzBuzz sequence.\n\nSample Input 1\n\n15\n\nSample Output 1\n\n60\n\nThe first 15 terms of the FizzBuzz sequence are:\n\n1,2,\\mbox{Fizz},4,\\mbox{Buzz},\\mbox{Fizz},7,8,\\mbox{Fizz},\\mbox{Buzz},11,\\mbox{Fizz},13,14,\\mbox{FizzBuzz}\n\nAmong them, numbers are 1,2,4,7,8,11,13,14, and the sum of them is 60.\n\nSample Input 2\n\n1000000\n\nSample Output 2\n\n266666333332\n\nWatch out for overflow.", "sample_input": "15\n"}, "reference_outputs": ["60\n"], "source_document_id": "p02712", "source_text": "Score : 200 points\n\nProblem Statement\n\nLet us define the FizzBuzz sequence a_1,a_2,... as follows:\n\nIf both 3 and 5 divides i, a_i=\\mbox{FizzBuzz}.\n\nIf the above does not hold but 3 divides i, a_i=\\mbox{Fizz}.\n\nIf none of the above holds but 5 divides i, a_i=\\mbox{Buzz}.\n\nIf none of the above holds, a_i=i.\n\nFind the sum of all numbers among the first N terms of the FizzBuzz sequence.\n\nConstraints\n\n1 \\leq N \\leq 10^6\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the sum of all numbers among the first N terms of the FizzBuzz sequence.\n\nSample Input 1\n\n15\n\nSample Output 1\n\n60\n\nThe first 15 terms of the FizzBuzz sequence are:\n\n1,2,\\mbox{Fizz},4,\\mbox{Buzz},\\mbox{Fizz},7,8,\\mbox{Fizz},\\mbox{Buzz},11,\\mbox{Fizz},13,14,\\mbox{FizzBuzz}\n\nAmong them, numbers are 1,2,4,7,8,11,13,14, and the sum of them is 60.\n\nSample Input 2\n\n1000000\n\nSample Output 2\n\n266666333332\n\nWatch out for overflow.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 769, "cpu_time_ms": 10, "memory_kb": 7088}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s925785118", "group_id": "codeNet:p02712", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nusing lint = long long int;\nint main()\n{\n    lint num;\n    lint sum = 0;\n    cin >> num;\n    for (lint i = 1; i < num;i++)\n    {\n        if (i%3 != 0 && i%5 !=0)\n            sum = sum + i;\n    }\n    cout << sum << endl;\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1586740915, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02712.html", "problem_id": "p02712", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02712/input.txt", "sample_output_relpath": "derived/input_output/data/p02712/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02712/C++/s925785118.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s925785118", "user_id": "u085606120"}, "prompt_components": {"gold_output": "60\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nusing lint = long long int;\nint main()\n{\n    lint num;\n    lint sum = 0;\n    cin >> num;\n    for (lint i = 1; i < num;i++)\n    {\n        if (i%3 != 0 && i%5 !=0)\n            sum = sum + i;\n    }\n    cout << sum << endl;\n    return 0;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nLet us define the FizzBuzz sequence a_1,a_2,... as follows:\n\nIf both 3 and 5 divides i, a_i=\\mbox{FizzBuzz}.\n\nIf the above does not hold but 3 divides i, a_i=\\mbox{Fizz}.\n\nIf none of the above holds but 5 divides i, a_i=\\mbox{Buzz}.\n\nIf none of the above holds, a_i=i.\n\nFind the sum of all numbers among the first N terms of the FizzBuzz sequence.\n\nConstraints\n\n1 \\leq N \\leq 10^6\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the sum of all numbers among the first N terms of the FizzBuzz sequence.\n\nSample Input 1\n\n15\n\nSample Output 1\n\n60\n\nThe first 15 terms of the FizzBuzz sequence are:\n\n1,2,\\mbox{Fizz},4,\\mbox{Buzz},\\mbox{Fizz},7,8,\\mbox{Fizz},\\mbox{Buzz},11,\\mbox{Fizz},13,14,\\mbox{FizzBuzz}\n\nAmong them, numbers are 1,2,4,7,8,11,13,14, and the sum of them is 60.\n\nSample Input 2\n\n1000000\n\nSample Output 2\n\n266666333332\n\nWatch out for overflow.", "sample_input": "15\n"}, "reference_outputs": ["60\n"], "source_document_id": "p02712", "source_text": "Score : 200 points\n\nProblem Statement\n\nLet us define the FizzBuzz sequence a_1,a_2,... as follows:\n\nIf both 3 and 5 divides i, a_i=\\mbox{FizzBuzz}.\n\nIf the above does not hold but 3 divides i, a_i=\\mbox{Fizz}.\n\nIf none of the above holds but 5 divides i, a_i=\\mbox{Buzz}.\n\nIf none of the above holds, a_i=i.\n\nFind the sum of all numbers among the first N terms of the FizzBuzz sequence.\n\nConstraints\n\n1 \\leq N \\leq 10^6\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the sum of all numbers among the first N terms of the FizzBuzz sequence.\n\nSample Input 1\n\n15\n\nSample Output 1\n\n60\n\nThe first 15 terms of the FizzBuzz sequence are:\n\n1,2,\\mbox{Fizz},4,\\mbox{Buzz},\\mbox{Fizz},7,8,\\mbox{Fizz},\\mbox{Buzz},11,\\mbox{Fizz},13,14,\\mbox{FizzBuzz}\n\nAmong them, numbers are 1,2,4,7,8,11,13,14, and the sum of them is 60.\n\nSample Input 2\n\n1000000\n\nSample Output 2\n\n266666333332\n\nWatch out for overflow.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 282, "cpu_time_ms": 11, "memory_kb": 3636}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s997911118", "group_id": "codeNet:p02712", "input_text": "#include <bits/stdc++.h>\n#include <map> // pair\nusing namespace std;\n\ntypedef long long ll;\n#define vec vector<int>\n#define vecll vector<ll>\n#define vpair vector<pair<int, int>>\n#define vpairll vector<pair<ll, ll>>\n#define fi first\n#define se second\n#define pb push_back\n#define mp make_pair\n#define rep(i,n)   for(int i=(int)0; i<(int)n; i++)\n#define llrep(i,n)   for(ll i=(ll)0; i<(ll)n; i++)\n#define REP(i,m,n) for(int i=(int)m; i<(int)n; i++)\n#define all(var)     (var).begin(), (var).end()\n#define prt(var)     cout << var << endl\n#define prt_dbl(i,var) cout<<fixed<<setprecision(i)<<var<<endl;\ntemplate <typename Val>\nVal gcd(Val a, Val b) {\n//use ll or int for gcd\n    if (b==0) return a;\n    else return gcd(b, a%b);\n}\ntemplate <typename Val>\nVal vec_max(vector<Val> v){\n  return *max_element(v.begin(),v.end());\n}\ntemplate <typename Val>\nVal vec_min(vector<Val> v){\n  return *min_element(v.begin(),v.end());\n}\n\n\n//---------------------------------------------------------------\n\nint main(){\n  ll N;\n  cin>>N;\n  ll count = 1;\n  ll c = 0;\n  while(1){\n    if(count%3==0||count%5==0){\n      c+=0;\n\n    }else {\n      c+=count;\n    }\n    if(count==N){\n      break;\n    }\n      count++;\n  }\n\n\n  cout<<c<<endl;\n\n\n\n\n\n\n\n\n\n\n\n\n}\n", "language": "C++", "metadata": {"date": 1586740182, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02712.html", "problem_id": "p02712", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02712/input.txt", "sample_output_relpath": "derived/input_output/data/p02712/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02712/C++/s997911118.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s997911118", "user_id": "u906250335"}, "prompt_components": {"gold_output": "60\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#include <map> // pair\nusing namespace std;\n\ntypedef long long ll;\n#define vec vector<int>\n#define vecll vector<ll>\n#define vpair vector<pair<int, int>>\n#define vpairll vector<pair<ll, ll>>\n#define fi first\n#define se second\n#define pb push_back\n#define mp make_pair\n#define rep(i,n)   for(int i=(int)0; i<(int)n; i++)\n#define llrep(i,n)   for(ll i=(ll)0; i<(ll)n; i++)\n#define REP(i,m,n) for(int i=(int)m; i<(int)n; i++)\n#define all(var)     (var).begin(), (var).end()\n#define prt(var)     cout << var << endl\n#define prt_dbl(i,var) cout<<fixed<<setprecision(i)<<var<<endl;\ntemplate <typename Val>\nVal gcd(Val a, Val b) {\n//use ll or int for gcd\n    if (b==0) return a;\n    else return gcd(b, a%b);\n}\ntemplate <typename Val>\nVal vec_max(vector<Val> v){\n  return *max_element(v.begin(),v.end());\n}\ntemplate <typename Val>\nVal vec_min(vector<Val> v){\n  return *min_element(v.begin(),v.end());\n}\n\n\n//---------------------------------------------------------------\n\nint main(){\n  ll N;\n  cin>>N;\n  ll count = 1;\n  ll c = 0;\n  while(1){\n    if(count%3==0||count%5==0){\n      c+=0;\n\n    }else {\n      c+=count;\n    }\n    if(count==N){\n      break;\n    }\n      count++;\n  }\n\n\n  cout<<c<<endl;\n\n\n\n\n\n\n\n\n\n\n\n\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nLet us define the FizzBuzz sequence a_1,a_2,... as follows:\n\nIf both 3 and 5 divides i, a_i=\\mbox{FizzBuzz}.\n\nIf the above does not hold but 3 divides i, a_i=\\mbox{Fizz}.\n\nIf none of the above holds but 5 divides i, a_i=\\mbox{Buzz}.\n\nIf none of the above holds, a_i=i.\n\nFind the sum of all numbers among the first N terms of the FizzBuzz sequence.\n\nConstraints\n\n1 \\leq N \\leq 10^6\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the sum of all numbers among the first N terms of the FizzBuzz sequence.\n\nSample Input 1\n\n15\n\nSample Output 1\n\n60\n\nThe first 15 terms of the FizzBuzz sequence are:\n\n1,2,\\mbox{Fizz},4,\\mbox{Buzz},\\mbox{Fizz},7,8,\\mbox{Fizz},\\mbox{Buzz},11,\\mbox{Fizz},13,14,\\mbox{FizzBuzz}\n\nAmong them, numbers are 1,2,4,7,8,11,13,14, and the sum of them is 60.\n\nSample Input 2\n\n1000000\n\nSample Output 2\n\n266666333332\n\nWatch out for overflow.", "sample_input": "15\n"}, "reference_outputs": ["60\n"], "source_document_id": "p02712", "source_text": "Score : 200 points\n\nProblem Statement\n\nLet us define the FizzBuzz sequence a_1,a_2,... as follows:\n\nIf both 3 and 5 divides i, a_i=\\mbox{FizzBuzz}.\n\nIf the above does not hold but 3 divides i, a_i=\\mbox{Fizz}.\n\nIf none of the above holds but 5 divides i, a_i=\\mbox{Buzz}.\n\nIf none of the above holds, a_i=i.\n\nFind the sum of all numbers among the first N terms of the FizzBuzz sequence.\n\nConstraints\n\n1 \\leq N \\leq 10^6\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the sum of all numbers among the first N terms of the FizzBuzz sequence.\n\nSample Input 1\n\n15\n\nSample Output 1\n\n60\n\nThe first 15 terms of the FizzBuzz sequence are:\n\n1,2,\\mbox{Fizz},4,\\mbox{Buzz},\\mbox{Fizz},7,8,\\mbox{Fizz},\\mbox{Buzz},11,\\mbox{Fizz},13,14,\\mbox{FizzBuzz}\n\nAmong them, numbers are 1,2,4,7,8,11,13,14, and the sum of them is 60.\n\nSample Input 2\n\n1000000\n\nSample Output 2\n\n266666333332\n\nWatch out for overflow.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1226, "cpu_time_ms": 8, "memory_kb": 3620}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s451870999", "group_id": "codeNet:p02715", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nusing lint = long long int;\nconst lint MOD = 1e9+7;\n\nlint modpow(lint m, lint n){\n  if(n == 0) return 1;\n  else if(n % 2 == 0) return modpow(m * m % MOD, n/2);\n  else{\n    return modpow(m, n - 1) * m % MOD;\n  }\n}\n\nsigned main(){\n\tlint N, K; cin >> N >> K;\n\tlint ans = 0;\n\tvector<lint> data(K + 1, 0);\n\tfor(lint i = K; i > 0; i--){\n\t\tlint num = modpow(K/i, N);\n\t\tfor(lint j = 2 * i; j <= K; j += i){\n\t\t\tnum = num - data[j] + MOD;\n\t\t\tnum %= MOD;\n\t\t}\n\t\tdata[i] = num;\n\t\tans += num * i;\n\t\tans %= MOD;\n\t}\n\tcout << ans << endl;\n}\n", "language": "C++", "metadata": {"date": 1587870959, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02715.html", "problem_id": "p02715", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02715/input.txt", "sample_output_relpath": "derived/input_output/data/p02715/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02715/C++/s451870999.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s451870999", "user_id": "u265359795"}, "prompt_components": {"gold_output": "9\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nusing lint = long long int;\nconst lint MOD = 1e9+7;\n\nlint modpow(lint m, lint n){\n  if(n == 0) return 1;\n  else if(n % 2 == 0) return modpow(m * m % MOD, n/2);\n  else{\n    return modpow(m, n - 1) * m % MOD;\n  }\n}\n\nsigned main(){\n\tlint N, K; cin >> N >> K;\n\tlint ans = 0;\n\tvector<lint> data(K + 1, 0);\n\tfor(lint i = K; i > 0; i--){\n\t\tlint num = modpow(K/i, N);\n\t\tfor(lint j = 2 * i; j <= K; j += i){\n\t\t\tnum = num - data[j] + MOD;\n\t\t\tnum %= MOD;\n\t\t}\n\t\tdata[i] = num;\n\t\tans += num * i;\n\t\tans %= MOD;\n\t}\n\tcout << ans << endl;\n}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nConsider sequences \\{A_1,...,A_N\\} of length N consisting of integers between 1 and K (inclusive).\n\nThere are K^N such sequences. Find the sum of \\gcd(A_1, ..., A_N) over all of them.\n\nSince this sum can be enormous, print the value modulo (10^9+7).\n\nHere \\gcd(A_1, ..., A_N) denotes the greatest common divisor of A_1, ..., A_N.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n1 \\leq K \\leq 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the sum of \\gcd(A_1, ..., A_N) over all K^N sequences, modulo (10^9+7).\n\nSample Input 1\n\n3 2\n\nSample Output 1\n\n9\n\n\\gcd(1,1,1)+\\gcd(1,1,2)+\\gcd(1,2,1)+\\gcd(1,2,2)\n+\\gcd(2,1,1)+\\gcd(2,1,2)+\\gcd(2,2,1)+\\gcd(2,2,2)\n=1+1+1+1+1+1+1+2=9\n\nThus, the answer is 9.\n\nSample Input 2\n\n3 200\n\nSample Output 2\n\n10813692\n\nSample Input 3\n\n100000 100000\n\nSample Output 3\n\n742202979\n\nBe sure to print the sum modulo (10^9+7).", "sample_input": "3 2\n"}, "reference_outputs": ["9\n"], "source_document_id": "p02715", "source_text": "Score : 500 points\n\nProblem Statement\n\nConsider sequences \\{A_1,...,A_N\\} of length N consisting of integers between 1 and K (inclusive).\n\nThere are K^N such sequences. Find the sum of \\gcd(A_1, ..., A_N) over all of them.\n\nSince this sum can be enormous, print the value modulo (10^9+7).\n\nHere \\gcd(A_1, ..., A_N) denotes the greatest common divisor of A_1, ..., A_N.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n1 \\leq K \\leq 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the sum of \\gcd(A_1, ..., A_N) over all K^N sequences, modulo (10^9+7).\n\nSample Input 1\n\n3 2\n\nSample Output 1\n\n9\n\n\\gcd(1,1,1)+\\gcd(1,1,2)+\\gcd(1,2,1)+\\gcd(1,2,2)\n+\\gcd(2,1,1)+\\gcd(2,1,2)+\\gcd(2,2,1)+\\gcd(2,2,2)\n=1+1+1+1+1+1+1+2=9\n\nThus, the answer is 9.\n\nSample Input 2\n\n3 200\n\nSample Output 2\n\n10813692\n\nSample Input 3\n\n100000 100000\n\nSample Output 3\n\n742202979\n\nBe sure to print the sum modulo (10^9+7).", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 570, "cpu_time_ms": 20, "memory_kb": 4052}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s276744931", "group_id": "codeNet:p02715", "input_text": "#include <bits/stdc++.h>\n#include <math.h>\n#include <unordered_map>\n#include <unordered_set>\n#include <tuple>\n \n#define io ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);\n#define PB push_back\n#define MP make_pair\n#define REP(i,a,b) for (ll i = a; i < b; i++)\n#define enl \"\\n\"\n#define INF std::numeric_limits<ll>::max()\n#define F first\n#define S second\n \nusing namespace std;\n \ntypedef long long int ll;\ntypedef unsigned long long int ull;\ntypedef long double ldb;\ntypedef vector<long long> vll;\ntypedef pair<long long,long long> pll;\n \nll greatestSubarraySum(ll array[], ll n);\nll binarySearch(vll arr, ll l, ll r, ll x);\nll modpower(ll x, ll y, ll p);\nll power(ll x, ll y);\nll gcd(ll a, ll b);\nll lcm(ll a, ll b);\nll search(ll arr[], ll n, ll k);\nstring findSum(string str1, string str2);\nll extendedGcd(ll a, ll b, ll & x, ll & y); \nbool find_any_solution(ll a, ll b, ll c, ll &x0, ll &y0, ll &g);\nll countSetBits(ll n); \nvoid primeFactors(ll n, map<ll,ll>& arr2, ll k, ll& flaggy);\nvoid matrixMultiply(ll a[3][3], ll b[3][3]);\nvoid matrixPower(ll F[7][7], ll n);\nll sumSquareRootDecomposition(ll arr[], vll helper, ll n, ll l, ll r);\nvll squareRootDecompositionSumArray(ll arr[], ll n);\nll minSquareRootDecomposition(ll arr[], vll helper, ll n, ll l, ll r);\nll maxSquareRootDecomposition(ll arr[], vll helper, ll n, ll l, ll r);\nvll squareRootDecompositionMinArray(ll arr[], ll n);\nvll squareRootDecompositionMaxArray(ll arr[], ll n);\nvoid updateSquareRootDecompositionMinArray(ll arr[], vll &helper, ll n, ll i, ll x);\nvoid updateSquareRootDecompositionMaxArray(ll arr[], vll &helper, ll n, ll i, ll x);\nvoid updateSquareRootDecompositionSumArray(ll arr[], vll &helper, ll n, ll i, ll x);\nvoid dfs(ll i, set<ll> arr[], ll visited[]);\nvoid uni(ll x, ll y, ll par[], ll size[]);\nll find(ll x, ll par[], ll size[]);\nll modulo( ll value, ll m);\nclass FenwickTree;\nvoid pairsort(ll a[], ll b[], ll n);\nll max(ll a, ll b);\nll min(ll a, ll b);\nll modInverse(ll a, ll m);\nll modsum(ll a, ll b, ll m);\nll modmul(ll a, ll b, ll m);\nstring reverseOfString(string s);\nll nCrMod(ll n, ll r, ll mod);\nvll kmpArray(string s);\n \n \n#define MAXI 998244353\n \n \nll fact[1000000];\n\nll floorSqrt(ll x)  \n{     \n    // Base cases \n    if (x == 0 || x == 1)  \n       return x; \n  \n    // Do Binary Search for floor(sqrt(x)) \n    ll start = 1, end = x, ans;    \n    while (start <= end)  \n    {         \n        ll mid = (start + end) / 2; \n  \n        // If x is a perfect square \n        if (mid*mid == x) \n            return mid; \n  \n        // Since we need floor, we update answer when mid*mid is  \n        // smaller than x, and move closer to sqrt(x) \n        if (mid*mid < x)  \n        { \n            start = mid + 1; \n            ans = mid; \n        }  \n        else // If mid*mid is greater than x \n            end = mid-1;         \n    } \n    return ans; \n} \n\nint main(){\n \n    io\n \n    ll q=1;\n    // cin>>q;\n    REP(currentIndex,0,q){\n\n        ll n,k;\n        cin>>n>>k;\n\n        ll current[k+1];\n        REP(i,0,k+1)current[i]=0;\n\n\n        ll ans=0;\n\n        REP(i,1,k+1){\n\n            ll temp=0;\n\n            if(i==1){\n\n                current[i]=1;\n\n            } else {\n\n\n                for(ll j=1; j<=floorSqrt(i); j++){\n\n                    if(i%j==0){\n\n                        \n\n                        temp+=current[j];\n                        if(j!=i/j)temp+=current[i/j];\n                    }\n\n\n                }\n\n\n\n                current[i]=i-temp;\n\n\n\n            }\n\n\n            ans=modsum(ans, modmul(i-temp, modpower(k/i, n, 1000000007), 1000000007), 1000000007);\n\n        }\n\n        cout<<ans<<endl;\n\n\n\n    }\n\n\n\n\n \n \n \n \n \n}\n \n \nvll kmpArray(string s){\n \n    vll arr(s.length(), 0);\n \n    REP(i,1,s.length()){\n \n        ll len=arr[i-1];\n        while(len>0 && s[len]!=s[i])len=arr[len-1];\n        if(s[len]==s[i])len++;\n        arr[i]=len;\n \n \n \n    }\n \n    return arr;\n \n \n \n}\n \n \n \nll nCrMod(ll n, ll r, ll mod){\n \n    return (fact[n]* modInverse(fact[r], mod) % mod * modInverse(fact[n-r], mod) % mod) % mod; \n \n}\n \nvoid SieveOfEratosthenes(ll n, bool isPrime[]) \n{ \n \n    isPrime[0] = isPrime[1] = false; \n    for (ll i = 2; i <= n; i++) \n        isPrime[i] = true; \n  \n    for (ll p = 2; p * p <= n; p++) { \n \n \n        if (isPrime[p] == true) { \n \n            for (ll i = p * 2; i <= n; i += p) \n                isPrime[i] = false; \n        } \n    } \n} \n \nstring reverseOfString(string s){\n \n    string t;\n    REP(i,0,s.length()){\n \n        t+=s[s.length()-i-1];\n \n    }\n \n    return t;\n \n}\n \nclass FenwickTree{\n \nprivate:\n    ll n;\n \n    ll h(ll i){return (i|(i+1));}\n    ll g(ll i){return (i&(i+1));}\n \n \n \npublic:\n \n    ll *sumtree;\n    ll *mainArray;\n \n    FenwickTree(ll n){\n \n        this->n=n;\n        mainArray = (ll*)malloc(n*sizeof(ll));\n        sumtree = (ll*)calloc(n, sizeof(ll));\n \n    }\n \n \n \n    void addElementAtIndex(ll i, ll x){\n        mainArray[i]=x;\n        update(i,x);\n    }\n \n    void update(ll i, ll delta){\n \n        for(ll j=i; j<n; j=h(j)){\n            sumtree[j]+=delta;\n \n        }\n \n    }\n \n    ll sum(ll i, ll j){\n \n        ll sum1=0, sum2=0;\n        ll i1=i,j1=j;\n        while(j>=0){\n            sum1+=sumtree[j];\n            j=g(j)-1;\n        }\n        while(i>=0){\n            sum2+=sumtree[i];\n            i=g(i)-1;\n        }\n        return sum1-sum2+mainArray[i1];\n \n    }\n \n \n};\n \nll modsum(ll a, ll b, ll m){\n \n    return ((a%m)+(b%m))%m;\n \n}\n \nll modmul(ll a, ll b, ll m){\n \n    return ((a%m)*(b%m))%m;\n \n \n}\n \nll modInverse(ll a, ll m) \n{ \n \n    return modpower(a, m-2, m); \n \n} \n \nll max(ll a, ll b){\n \n    if(a>b)return a;\n    else return b;\n}\n \nll min(ll a, ll b){\n \n    if(a<b)return a;\n    return b;\n \n}\n \n \nvoid pairsort(ll a[], ll b[], ll n) \n{ \n    pair<ll, ll> pairt[n]; \n  \n \n    for (ll i = 0; i < n; i++)  \n    { \n        pairt[i].first = a[i]; \n        pairt[i].second = b[i]; \n    } \n  \n    sort(pairt, pairt + n); \n      \n    for (ll i = 0; i < n; i++)  \n    { \n        a[i] = pairt[i].first; \n        b[i] = pairt[i].second; \n    } \n}\n \nll extendedGcd(ll a, ll b, ll & x, ll & y) {\n    if (a == 0) {\n        x = 0;\n        y = 1;\n        return b;\n    }\n    ll x1, y1;\n    ll d = extendedGcd(b % a, a, x1, y1);\n    x = y1 - (b / a) * x1;\n    y = x1;\n    return d;\n}\n \nbool find_any_solution(ll a, ll b, ll c, ll &x0, ll &y0, ll &g) {\n    g = extendedGcd(abs(a), abs(b), x0, y0);\n    if (c % g) {\n        return false;\n    }\n \n    x0 *= c / g;\n    y0 *= c / g;\n    if (a < 0) x0 = -x0;\n    if (b < 0) y0 = -y0;\n    return true;\n}\n \n \nstring findSum(string str1, string str2) \n{ \n \n    if (str1.length() > str2.length()) {\n        string s = str1;\n        str1=str2;\n        str2=s;\n    }\n  \n \n    string str = \"\"; \n  \n \n    int n1 = str1.length(), n2 = str2.length(); \n  \n \n    reverse(str1.begin(), str1.end()); \n    reverse(str2.begin(), str2.end()); \n  \n    int carry = 0; \n    for (int i=0; i<n1; i++) \n    { \n \n        int sum = ((str1[i]-'0')+(str2[i]-'0')+carry); \n        str.push_back(sum%10 + '0'); \n  \n        carry = sum/10; \n    } \n  \n    // Add remaining digits of larger number \n    for (int i=n1; i<n2; i++) \n    { \n        int sum = ((str2[i]-'0')+carry); \n        str.push_back(sum%10 + '0'); \n        carry = sum/10; \n    } \n  \n    // Add remaining carry \n    if (carry) \n        str.push_back(carry+'0'); \n  \n    // reverse resultant string \n    reverse(str.begin(), str.end()); \n  \n    return str; \n} \n \n \n \nll binarySearch(vll arr, ll l, ll r, ll x) \n{ \n    if (r >= l) { \n        ll mid = l + (r - l) / 2; \n  \n        // If the element is present at the middle \n        // itself \n        if (arr[mid] == x) \n            return mid; \n  \n        // If element is smaller than mid, then \n        // it can only be present in left subarray \n        if (arr[mid] > x) \n            return binarySearch(arr, l, mid - 1, x); \n  \n        // Else the element can only be present \n        // in right subarray \n        return binarySearch(arr, mid + 1, r, x); \n    } \n  \n    // We reach here when element is not \n    // present in array \n    return -1; \n} \n \nll greatestSubarraySum(ll array[], ll n){\n \n    ll best = 0, sum = 0;\n    for (ll k = 0; k < n; k++) {\n        sum = max(array[k],sum+array[k]);\n        best = max(best,sum);\n    }\n \n    return best;\n}\n \nll modpower(ll x, ll y, ll p) \n{ \n    ll res = 1;      // Initialize result \n  \n    x = x % p;  // Update x if it is more than or  \n                // equal to p \n  \n    while (y > 0) \n    { \n        // If y is odd, multiply x with result \n        if (y & 1) \n            res = (res*x) % p; \n  \n        // y must be even now \n        y = y>>1; // y = y/2 \n        x = (x*x) % p;   \n    } \n    return res; \n} \n \n \nll gcd(ll a, ll b)\n{\n    if (a == 0)\n        return b;\n    \n    return gcd(b%a, a);\n}\n \nll lcm(ll a, ll b)  \n{  \n    return (a*b)/gcd(a, b);  \n} \n \n \nll power(ll x, ll y) \n{ \n    ll temp; \n    if( y == 0) \n        return 1; \n    temp = power(x, y/2); \n    if (y%2 == 0) \n        return temp*temp; \n    else\n        return x*temp*temp; \n}\n \nll modulo( ll value, ll m) {\n    ll mod = value % m;\n    if (value < 0) {\n        mod += m;\n    }\n    return mod;\n}\n \nll find(ll x, ll par[], ll size[]){\n \n    if(x==par[x])return x;\n    else return par[x]=find(par[x],par, size);\n \n}\n \nvoid uni(ll x, ll y, ll par[], ll size[]){\n \n    x=find(x,par,size);\n    y=find(y,par,size);\n \n    if(size[x]>size[y])swap(x,y);\n \n    par[x]=y;\n    size[y]+=size[x];\n \n \n}\n \nvoid dfs(ll i, set<ll> arr[], ll visited[]){\n \n    if(visited[i])return;\n \n    cout<<(char)('a'+i);\n \n    visited[i]=1;\n \n    for(auto u:arr[i])dfs(u, arr, visited);\n \n \n}\n \n \nll countSetBits(ll n) \n{ \n    ll count = 0; \n    while (n) { \n        count += n & 1; \n        n >>= 1; \n    } \n    return count; \n} \n \n \nll flag2;\n \n \nvoid primeFactors(ll n, map<ll,ll>& arr2, ll k, ll& flaggy)  \n{  \n    ll count=0;\n \n    ll flag=0;\n \n    while (n % 2 == 0)  \n    {  \n        n = n/2;\n        count++;  \n    }  \n  \n    if(count%k != 0){\n \n        flag=1;\n \n        arr2[2]=count%k;\n \n    }\n    count=0;\n \n    for (int i = 3; i <= sqrt(n); i = i + 2)  \n    {  \n        while (n % i == 0)  \n        {  \n            n = n/i;\n            count++;  \n        }  \n \n \n        if(count%k!=0){\n \n            flag=1;\n            arr2[i]=count%k;\n \n        }\n \n        count=0;\n    }  \n  \n    if (n > 2)  \n        {\n            if(1%k!=0){\n \n                flag=1;\n                arr2[n]=1%k;\n \n            }\n        }\n \n        if(flag==0){flag2++;flaggy=1;}\n \n}  \n \nvoid matrixMultiply(ll* a[], ll *b[], ll n) \n{ \n \n    ll mul[n][n]; \n    for (ll i = 0; i < n; i++) \n    { \n        for (ll j = 0; j < n; j++) \n        { \n            mul[i][j] = 0; \n            for (ll k = 0; k < n; k++) \n                mul[i][j] += a[i][k]*b[k][j]; \n        } \n    } \n  \n    for (int i=0; i<n; i++) \n        for (int j=0; j<n; j++) \n            a[i][j] = mul[i][j];\n}\n \nvoid matrixPower(ll **F, ll n, ll k) \n{ \n \n    if(n==1)return;\n \n    ll **M = (ll **)malloc(k*sizeof(ll *));\n \n \n    REP(i,0,k){\n        M[i]=(ll *)malloc(k*sizeof(ll));\n        REP(j,0,k){\n            M[i][j]=F[i][j];\n        }\n    }\n \n  \n    matrixPower(F, n/2, k); \n  \n    matrixMultiply(F, F, k); \n  \n    if (n%2 != 0) \n        matrixMultiply(F, M,k); \n  \n}\n \nvll squareRootDecompositionMinArray(ll arr[], ll n){\n \n    ll k=(ll)ceil(sqrt(n));\n    vll helper(k,INF);\n \n    REP(i,0,n)helper[i/k]=min(helper[i/k],arr[i]);\n \n    return helper;\n \n \n}\nvll squareRootDecompositionMaxArray(ll arr[], ll n){\n \n    ll k=(ll)ceil(sqrt(n));\n    vll helper(k,-INF);\n \n    REP(i,0,n)helper[i/k]=max(helper[i/k],arr[i]);\n \n    return helper;\n \n \n}\n \nll minSquareRootDecomposition(ll arr[], vll helper, ll n, ll l, ll r){\n \n    ll k=(ll)ceil(sqrt(n));\n \n    ll a=l/k;\n    ll b=r/k;\n \n    ll min1=INF;\n \n    if(a==b){\n \n        REP(i,l,r+1)min1=min(min1,arr[i]);\n \n        return min1;\n    }\n \n    REP(i,l,(a+1)*k)min1=min(min1,arr[i]);\n    REP(i,a+1,b)min1=min(min1,helper[i]);\n    REP(i,b*k,r+1)min1=min(min1,arr[i]);\n \n    return min1;\n \n \n}\nll maxSquareRootDecomposition(ll arr[], vll helper, ll n, ll l, ll r){\n \n    ll k=(ll)ceil(sqrt(n));\n \n    ll a=l/k;\n    ll b=r/k;\n \n    ll min1=-INF;\n \n    if(a==b){\n \n        REP(i,l,r+1)min1=max(min1,arr[i]);\n \n        return min1;\n    }\n \n    REP(i,l,(a+1)*k)min1=max(min1,arr[i]);\n    REP(i,a+1,b)min1=max(min1,helper[i]);\n    REP(i,b*k,r+1)min1=max(min1,arr[i]);\n \n    return min1;\n \n \n}\n \nvll squareRootDecompositionSumArray(ll arr[], ll n){\n \n    ll k=(ll)ceil(sqrt(n));\n \n    //preprocessed array\n \n    vll helper(k,0);\n \n    //preprocessing\n \n    REP(i,0,n)helper[i/k]+=arr[i];\n \n    return helper;\n \n \n}\n \nvoid updateSquareRootDecompositionSumArray(ll arr[], vll &helper, ll n, ll i, ll x){\n \n    ll k=(ll)ceil(sqrt(n));\n    ll delta=x-arr[i];\n    arr[i]=x;\n    helper[i/k]+=delta;\n \n}\n \nvoid updateSquareRootDecompositionMinArray(ll arr[], vll &helper, ll n, ll i, ll x){\n \n    ll k=(ll)ceil(sqrt(n));\n    if(helper[i/k]==arr[i]){\n \n        if(x<arr[i])helper[i/k]=arr[i];\n        else{\n \n            ll min1=INF;\n            REP(j,i/k*k,(i/k+1)*k)min1=min(min1,arr[j]);\n            helper[i/k]=min1;\n \n        }\n \n    } else{\n \n        helper[i/k]=min(helper[i/k],x);\n    }\n \n \n    arr[i]=x;\n \n \n}\nvoid updateSquareRootDecompositionMaxArray(ll arr[], vll &helper, ll n, ll i, ll x){\n \n    ll k=(ll)ceil(sqrt(n));\n    if(helper[i/k]==arr[i]){\n \n        if(x<arr[i])helper[i/k]=arr[i];\n        else{\n \n            ll min1=-INF;\n            REP(j,i/k*k,(i/k+1)*k)min1=max(min1,arr[j]);\n            helper[i/k]=min1;\n \n        }\n \n    } else{\n \n        helper[i/k]=max(helper[i/k],x);\n    }\n \n \n    arr[i]=x;\n \n \n}\n \nll sumSquareRootDecomposition(ll arr[], vll helper, ll n, ll l, ll r){\n \n    ll k=(ll)ceil(sqrt(n));\n \n    ll a=l/k;\n    ll b=r/k;\n \n    ll sum=0;\n \n    if(a==b){\n \n        REP(i,l,r+1)sum+=arr[i];\n \n        return sum;\n \n    }\n \n    REP(i,l,(a+1)*k){sum+=arr[i];}\n    REP(i,b*k,r+1)sum+=arr[i];\n    REP(i,a+1,b)sum+=helper[i];\n \n    return sum;\n \n}\t", "language": "C++", "metadata": {"date": 1586744832, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02715.html", "problem_id": "p02715", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02715/input.txt", "sample_output_relpath": "derived/input_output/data/p02715/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02715/C++/s276744931.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s276744931", "user_id": "u330464428"}, "prompt_components": {"gold_output": "9\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#include <math.h>\n#include <unordered_map>\n#include <unordered_set>\n#include <tuple>\n \n#define io ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);\n#define PB push_back\n#define MP make_pair\n#define REP(i,a,b) for (ll i = a; i < b; i++)\n#define enl \"\\n\"\n#define INF std::numeric_limits<ll>::max()\n#define F first\n#define S second\n \nusing namespace std;\n \ntypedef long long int ll;\ntypedef unsigned long long int ull;\ntypedef long double ldb;\ntypedef vector<long long> vll;\ntypedef pair<long long,long long> pll;\n \nll greatestSubarraySum(ll array[], ll n);\nll binarySearch(vll arr, ll l, ll r, ll x);\nll modpower(ll x, ll y, ll p);\nll power(ll x, ll y);\nll gcd(ll a, ll b);\nll lcm(ll a, ll b);\nll search(ll arr[], ll n, ll k);\nstring findSum(string str1, string str2);\nll extendedGcd(ll a, ll b, ll & x, ll & y); \nbool find_any_solution(ll a, ll b, ll c, ll &x0, ll &y0, ll &g);\nll countSetBits(ll n); \nvoid primeFactors(ll n, map<ll,ll>& arr2, ll k, ll& flaggy);\nvoid matrixMultiply(ll a[3][3], ll b[3][3]);\nvoid matrixPower(ll F[7][7], ll n);\nll sumSquareRootDecomposition(ll arr[], vll helper, ll n, ll l, ll r);\nvll squareRootDecompositionSumArray(ll arr[], ll n);\nll minSquareRootDecomposition(ll arr[], vll helper, ll n, ll l, ll r);\nll maxSquareRootDecomposition(ll arr[], vll helper, ll n, ll l, ll r);\nvll squareRootDecompositionMinArray(ll arr[], ll n);\nvll squareRootDecompositionMaxArray(ll arr[], ll n);\nvoid updateSquareRootDecompositionMinArray(ll arr[], vll &helper, ll n, ll i, ll x);\nvoid updateSquareRootDecompositionMaxArray(ll arr[], vll &helper, ll n, ll i, ll x);\nvoid updateSquareRootDecompositionSumArray(ll arr[], vll &helper, ll n, ll i, ll x);\nvoid dfs(ll i, set<ll> arr[], ll visited[]);\nvoid uni(ll x, ll y, ll par[], ll size[]);\nll find(ll x, ll par[], ll size[]);\nll modulo( ll value, ll m);\nclass FenwickTree;\nvoid pairsort(ll a[], ll b[], ll n);\nll max(ll a, ll b);\nll min(ll a, ll b);\nll modInverse(ll a, ll m);\nll modsum(ll a, ll b, ll m);\nll modmul(ll a, ll b, ll m);\nstring reverseOfString(string s);\nll nCrMod(ll n, ll r, ll mod);\nvll kmpArray(string s);\n \n \n#define MAXI 998244353\n \n \nll fact[1000000];\n\nll floorSqrt(ll x)  \n{     \n    // Base cases \n    if (x == 0 || x == 1)  \n       return x; \n  \n    // Do Binary Search for floor(sqrt(x)) \n    ll start = 1, end = x, ans;    \n    while (start <= end)  \n    {         \n        ll mid = (start + end) / 2; \n  \n        // If x is a perfect square \n        if (mid*mid == x) \n            return mid; \n  \n        // Since we need floor, we update answer when mid*mid is  \n        // smaller than x, and move closer to sqrt(x) \n        if (mid*mid < x)  \n        { \n            start = mid + 1; \n            ans = mid; \n        }  \n        else // If mid*mid is greater than x \n            end = mid-1;         \n    } \n    return ans; \n} \n\nint main(){\n \n    io\n \n    ll q=1;\n    // cin>>q;\n    REP(currentIndex,0,q){\n\n        ll n,k;\n        cin>>n>>k;\n\n        ll current[k+1];\n        REP(i,0,k+1)current[i]=0;\n\n\n        ll ans=0;\n\n        REP(i,1,k+1){\n\n            ll temp=0;\n\n            if(i==1){\n\n                current[i]=1;\n\n            } else {\n\n\n                for(ll j=1; j<=floorSqrt(i); j++){\n\n                    if(i%j==0){\n\n                        \n\n                        temp+=current[j];\n                        if(j!=i/j)temp+=current[i/j];\n                    }\n\n\n                }\n\n\n\n                current[i]=i-temp;\n\n\n\n            }\n\n\n            ans=modsum(ans, modmul(i-temp, modpower(k/i, n, 1000000007), 1000000007), 1000000007);\n\n        }\n\n        cout<<ans<<endl;\n\n\n\n    }\n\n\n\n\n \n \n \n \n \n}\n \n \nvll kmpArray(string s){\n \n    vll arr(s.length(), 0);\n \n    REP(i,1,s.length()){\n \n        ll len=arr[i-1];\n        while(len>0 && s[len]!=s[i])len=arr[len-1];\n        if(s[len]==s[i])len++;\n        arr[i]=len;\n \n \n \n    }\n \n    return arr;\n \n \n \n}\n \n \n \nll nCrMod(ll n, ll r, ll mod){\n \n    return (fact[n]* modInverse(fact[r], mod) % mod * modInverse(fact[n-r], mod) % mod) % mod; \n \n}\n \nvoid SieveOfEratosthenes(ll n, bool isPrime[]) \n{ \n \n    isPrime[0] = isPrime[1] = false; \n    for (ll i = 2; i <= n; i++) \n        isPrime[i] = true; \n  \n    for (ll p = 2; p * p <= n; p++) { \n \n \n        if (isPrime[p] == true) { \n \n            for (ll i = p * 2; i <= n; i += p) \n                isPrime[i] = false; \n        } \n    } \n} \n \nstring reverseOfString(string s){\n \n    string t;\n    REP(i,0,s.length()){\n \n        t+=s[s.length()-i-1];\n \n    }\n \n    return t;\n \n}\n \nclass FenwickTree{\n \nprivate:\n    ll n;\n \n    ll h(ll i){return (i|(i+1));}\n    ll g(ll i){return (i&(i+1));}\n \n \n \npublic:\n \n    ll *sumtree;\n    ll *mainArray;\n \n    FenwickTree(ll n){\n \n        this->n=n;\n        mainArray = (ll*)malloc(n*sizeof(ll));\n        sumtree = (ll*)calloc(n, sizeof(ll));\n \n    }\n \n \n \n    void addElementAtIndex(ll i, ll x){\n        mainArray[i]=x;\n        update(i,x);\n    }\n \n    void update(ll i, ll delta){\n \n        for(ll j=i; j<n; j=h(j)){\n            sumtree[j]+=delta;\n \n        }\n \n    }\n \n    ll sum(ll i, ll j){\n \n        ll sum1=0, sum2=0;\n        ll i1=i,j1=j;\n        while(j>=0){\n            sum1+=sumtree[j];\n            j=g(j)-1;\n        }\n        while(i>=0){\n            sum2+=sumtree[i];\n            i=g(i)-1;\n        }\n        return sum1-sum2+mainArray[i1];\n \n    }\n \n \n};\n \nll modsum(ll a, ll b, ll m){\n \n    return ((a%m)+(b%m))%m;\n \n}\n \nll modmul(ll a, ll b, ll m){\n \n    return ((a%m)*(b%m))%m;\n \n \n}\n \nll modInverse(ll a, ll m) \n{ \n \n    return modpower(a, m-2, m); \n \n} \n \nll max(ll a, ll b){\n \n    if(a>b)return a;\n    else return b;\n}\n \nll min(ll a, ll b){\n \n    if(a<b)return a;\n    return b;\n \n}\n \n \nvoid pairsort(ll a[], ll b[], ll n) \n{ \n    pair<ll, ll> pairt[n]; \n  \n \n    for (ll i = 0; i < n; i++)  \n    { \n        pairt[i].first = a[i]; \n        pairt[i].second = b[i]; \n    } \n  \n    sort(pairt, pairt + n); \n      \n    for (ll i = 0; i < n; i++)  \n    { \n        a[i] = pairt[i].first; \n        b[i] = pairt[i].second; \n    } \n}\n \nll extendedGcd(ll a, ll b, ll & x, ll & y) {\n    if (a == 0) {\n        x = 0;\n        y = 1;\n        return b;\n    }\n    ll x1, y1;\n    ll d = extendedGcd(b % a, a, x1, y1);\n    x = y1 - (b / a) * x1;\n    y = x1;\n    return d;\n}\n \nbool find_any_solution(ll a, ll b, ll c, ll &x0, ll &y0, ll &g) {\n    g = extendedGcd(abs(a), abs(b), x0, y0);\n    if (c % g) {\n        return false;\n    }\n \n    x0 *= c / g;\n    y0 *= c / g;\n    if (a < 0) x0 = -x0;\n    if (b < 0) y0 = -y0;\n    return true;\n}\n \n \nstring findSum(string str1, string str2) \n{ \n \n    if (str1.length() > str2.length()) {\n        string s = str1;\n        str1=str2;\n        str2=s;\n    }\n  \n \n    string str = \"\"; \n  \n \n    int n1 = str1.length(), n2 = str2.length(); \n  \n \n    reverse(str1.begin(), str1.end()); \n    reverse(str2.begin(), str2.end()); \n  \n    int carry = 0; \n    for (int i=0; i<n1; i++) \n    { \n \n        int sum = ((str1[i]-'0')+(str2[i]-'0')+carry); \n        str.push_back(sum%10 + '0'); \n  \n        carry = sum/10; \n    } \n  \n    // Add remaining digits of larger number \n    for (int i=n1; i<n2; i++) \n    { \n        int sum = ((str2[i]-'0')+carry); \n        str.push_back(sum%10 + '0'); \n        carry = sum/10; \n    } \n  \n    // Add remaining carry \n    if (carry) \n        str.push_back(carry+'0'); \n  \n    // reverse resultant string \n    reverse(str.begin(), str.end()); \n  \n    return str; \n} \n \n \n \nll binarySearch(vll arr, ll l, ll r, ll x) \n{ \n    if (r >= l) { \n        ll mid = l + (r - l) / 2; \n  \n        // If the element is present at the middle \n        // itself \n        if (arr[mid] == x) \n            return mid; \n  \n        // If element is smaller than mid, then \n        // it can only be present in left subarray \n        if (arr[mid] > x) \n            return binarySearch(arr, l, mid - 1, x); \n  \n        // Else the element can only be present \n        // in right subarray \n        return binarySearch(arr, mid + 1, r, x); \n    } \n  \n    // We reach here when element is not \n    // present in array \n    return -1; \n} \n \nll greatestSubarraySum(ll array[], ll n){\n \n    ll best = 0, sum = 0;\n    for (ll k = 0; k < n; k++) {\n        sum = max(array[k],sum+array[k]);\n        best = max(best,sum);\n    }\n \n    return best;\n}\n \nll modpower(ll x, ll y, ll p) \n{ \n    ll res = 1;      // Initialize result \n  \n    x = x % p;  // Update x if it is more than or  \n                // equal to p \n  \n    while (y > 0) \n    { \n        // If y is odd, multiply x with result \n        if (y & 1) \n            res = (res*x) % p; \n  \n        // y must be even now \n        y = y>>1; // y = y/2 \n        x = (x*x) % p;   \n    } \n    return res; \n} \n \n \nll gcd(ll a, ll b)\n{\n    if (a == 0)\n        return b;\n    \n    return gcd(b%a, a);\n}\n \nll lcm(ll a, ll b)  \n{  \n    return (a*b)/gcd(a, b);  \n} \n \n \nll power(ll x, ll y) \n{ \n    ll temp; \n    if( y == 0) \n        return 1; \n    temp = power(x, y/2); \n    if (y%2 == 0) \n        return temp*temp; \n    else\n        return x*temp*temp; \n}\n \nll modulo( ll value, ll m) {\n    ll mod = value % m;\n    if (value < 0) {\n        mod += m;\n    }\n    return mod;\n}\n \nll find(ll x, ll par[], ll size[]){\n \n    if(x==par[x])return x;\n    else return par[x]=find(par[x],par, size);\n \n}\n \nvoid uni(ll x, ll y, ll par[], ll size[]){\n \n    x=find(x,par,size);\n    y=find(y,par,size);\n \n    if(size[x]>size[y])swap(x,y);\n \n    par[x]=y;\n    size[y]+=size[x];\n \n \n}\n \nvoid dfs(ll i, set<ll> arr[], ll visited[]){\n \n    if(visited[i])return;\n \n    cout<<(char)('a'+i);\n \n    visited[i]=1;\n \n    for(auto u:arr[i])dfs(u, arr, visited);\n \n \n}\n \n \nll countSetBits(ll n) \n{ \n    ll count = 0; \n    while (n) { \n        count += n & 1; \n        n >>= 1; \n    } \n    return count; \n} \n \n \nll flag2;\n \n \nvoid primeFactors(ll n, map<ll,ll>& arr2, ll k, ll& flaggy)  \n{  \n    ll count=0;\n \n    ll flag=0;\n \n    while (n % 2 == 0)  \n    {  \n        n = n/2;\n        count++;  \n    }  \n  \n    if(count%k != 0){\n \n        flag=1;\n \n        arr2[2]=count%k;\n \n    }\n    count=0;\n \n    for (int i = 3; i <= sqrt(n); i = i + 2)  \n    {  \n        while (n % i == 0)  \n        {  \n            n = n/i;\n            count++;  \n        }  \n \n \n        if(count%k!=0){\n \n            flag=1;\n            arr2[i]=count%k;\n \n        }\n \n        count=0;\n    }  \n  \n    if (n > 2)  \n        {\n            if(1%k!=0){\n \n                flag=1;\n                arr2[n]=1%k;\n \n            }\n        }\n \n        if(flag==0){flag2++;flaggy=1;}\n \n}  \n \nvoid matrixMultiply(ll* a[], ll *b[], ll n) \n{ \n \n    ll mul[n][n]; \n    for (ll i = 0; i < n; i++) \n    { \n        for (ll j = 0; j < n; j++) \n        { \n            mul[i][j] = 0; \n            for (ll k = 0; k < n; k++) \n                mul[i][j] += a[i][k]*b[k][j]; \n        } \n    } \n  \n    for (int i=0; i<n; i++) \n        for (int j=0; j<n; j++) \n            a[i][j] = mul[i][j];\n}\n \nvoid matrixPower(ll **F, ll n, ll k) \n{ \n \n    if(n==1)return;\n \n    ll **M = (ll **)malloc(k*sizeof(ll *));\n \n \n    REP(i,0,k){\n        M[i]=(ll *)malloc(k*sizeof(ll));\n        REP(j,0,k){\n            M[i][j]=F[i][j];\n        }\n    }\n \n  \n    matrixPower(F, n/2, k); \n  \n    matrixMultiply(F, F, k); \n  \n    if (n%2 != 0) \n        matrixMultiply(F, M,k); \n  \n}\n \nvll squareRootDecompositionMinArray(ll arr[], ll n){\n \n    ll k=(ll)ceil(sqrt(n));\n    vll helper(k,INF);\n \n    REP(i,0,n)helper[i/k]=min(helper[i/k],arr[i]);\n \n    return helper;\n \n \n}\nvll squareRootDecompositionMaxArray(ll arr[], ll n){\n \n    ll k=(ll)ceil(sqrt(n));\n    vll helper(k,-INF);\n \n    REP(i,0,n)helper[i/k]=max(helper[i/k],arr[i]);\n \n    return helper;\n \n \n}\n \nll minSquareRootDecomposition(ll arr[], vll helper, ll n, ll l, ll r){\n \n    ll k=(ll)ceil(sqrt(n));\n \n    ll a=l/k;\n    ll b=r/k;\n \n    ll min1=INF;\n \n    if(a==b){\n \n        REP(i,l,r+1)min1=min(min1,arr[i]);\n \n        return min1;\n    }\n \n    REP(i,l,(a+1)*k)min1=min(min1,arr[i]);\n    REP(i,a+1,b)min1=min(min1,helper[i]);\n    REP(i,b*k,r+1)min1=min(min1,arr[i]);\n \n    return min1;\n \n \n}\nll maxSquareRootDecomposition(ll arr[], vll helper, ll n, ll l, ll r){\n \n    ll k=(ll)ceil(sqrt(n));\n \n    ll a=l/k;\n    ll b=r/k;\n \n    ll min1=-INF;\n \n    if(a==b){\n \n        REP(i,l,r+1)min1=max(min1,arr[i]);\n \n        return min1;\n    }\n \n    REP(i,l,(a+1)*k)min1=max(min1,arr[i]);\n    REP(i,a+1,b)min1=max(min1,helper[i]);\n    REP(i,b*k,r+1)min1=max(min1,arr[i]);\n \n    return min1;\n \n \n}\n \nvll squareRootDecompositionSumArray(ll arr[], ll n){\n \n    ll k=(ll)ceil(sqrt(n));\n \n    //preprocessed array\n \n    vll helper(k,0);\n \n    //preprocessing\n \n    REP(i,0,n)helper[i/k]+=arr[i];\n \n    return helper;\n \n \n}\n \nvoid updateSquareRootDecompositionSumArray(ll arr[], vll &helper, ll n, ll i, ll x){\n \n    ll k=(ll)ceil(sqrt(n));\n    ll delta=x-arr[i];\n    arr[i]=x;\n    helper[i/k]+=delta;\n \n}\n \nvoid updateSquareRootDecompositionMinArray(ll arr[], vll &helper, ll n, ll i, ll x){\n \n    ll k=(ll)ceil(sqrt(n));\n    if(helper[i/k]==arr[i]){\n \n        if(x<arr[i])helper[i/k]=arr[i];\n        else{\n \n            ll min1=INF;\n            REP(j,i/k*k,(i/k+1)*k)min1=min(min1,arr[j]);\n            helper[i/k]=min1;\n \n        }\n \n    } else{\n \n        helper[i/k]=min(helper[i/k],x);\n    }\n \n \n    arr[i]=x;\n \n \n}\nvoid updateSquareRootDecompositionMaxArray(ll arr[], vll &helper, ll n, ll i, ll x){\n \n    ll k=(ll)ceil(sqrt(n));\n    if(helper[i/k]==arr[i]){\n \n        if(x<arr[i])helper[i/k]=arr[i];\n        else{\n \n            ll min1=-INF;\n            REP(j,i/k*k,(i/k+1)*k)min1=max(min1,arr[j]);\n            helper[i/k]=min1;\n \n        }\n \n    } else{\n \n        helper[i/k]=max(helper[i/k],x);\n    }\n \n \n    arr[i]=x;\n \n \n}\n \nll sumSquareRootDecomposition(ll arr[], vll helper, ll n, ll l, ll r){\n \n    ll k=(ll)ceil(sqrt(n));\n \n    ll a=l/k;\n    ll b=r/k;\n \n    ll sum=0;\n \n    if(a==b){\n \n        REP(i,l,r+1)sum+=arr[i];\n \n        return sum;\n \n    }\n \n    REP(i,l,(a+1)*k){sum+=arr[i];}\n    REP(i,b*k,r+1)sum+=arr[i];\n    REP(i,a+1,b)sum+=helper[i];\n \n    return sum;\n \n}\t", "problem_context": "Score : 500 points\n\nProblem Statement\n\nConsider sequences \\{A_1,...,A_N\\} of length N consisting of integers between 1 and K (inclusive).\n\nThere are K^N such sequences. Find the sum of \\gcd(A_1, ..., A_N) over all of them.\n\nSince this sum can be enormous, print the value modulo (10^9+7).\n\nHere \\gcd(A_1, ..., A_N) denotes the greatest common divisor of A_1, ..., A_N.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n1 \\leq K \\leq 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the sum of \\gcd(A_1, ..., A_N) over all K^N sequences, modulo (10^9+7).\n\nSample Input 1\n\n3 2\n\nSample Output 1\n\n9\n\n\\gcd(1,1,1)+\\gcd(1,1,2)+\\gcd(1,2,1)+\\gcd(1,2,2)\n+\\gcd(2,1,1)+\\gcd(2,1,2)+\\gcd(2,2,1)+\\gcd(2,2,2)\n=1+1+1+1+1+1+1+2=9\n\nThus, the answer is 9.\n\nSample Input 2\n\n3 200\n\nSample Output 2\n\n10813692\n\nSample Input 3\n\n100000 100000\n\nSample Output 3\n\n742202979\n\nBe sure to print the sum modulo (10^9+7).", "sample_input": "3 2\n"}, "reference_outputs": ["9\n"], "source_document_id": "p02715", "source_text": "Score : 500 points\n\nProblem Statement\n\nConsider sequences \\{A_1,...,A_N\\} of length N consisting of integers between 1 and K (inclusive).\n\nThere are K^N such sequences. Find the sum of \\gcd(A_1, ..., A_N) over all of them.\n\nSince this sum can be enormous, print the value modulo (10^9+7).\n\nHere \\gcd(A_1, ..., A_N) denotes the greatest common divisor of A_1, ..., A_N.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n1 \\leq K \\leq 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the sum of \\gcd(A_1, ..., A_N) over all K^N sequences, modulo (10^9+7).\n\nSample Input 1\n\n3 2\n\nSample Output 1\n\n9\n\n\\gcd(1,1,1)+\\gcd(1,1,2)+\\gcd(1,2,1)+\\gcd(1,2,2)\n+\\gcd(2,1,1)+\\gcd(2,1,2)+\\gcd(2,2,1)+\\gcd(2,2,2)\n=1+1+1+1+1+1+1+2=9\n\nThus, the answer is 9.\n\nSample Input 2\n\n3 200\n\nSample Output 2\n\n10813692\n\nSample Input 3\n\n100000 100000\n\nSample Output 3\n\n742202979\n\nBe sure to print the sum modulo (10^9+7).", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 13966, "cpu_time_ms": 499, "memory_kb": 4460}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s495120797", "group_id": "codeNet:p02715", "input_text": "#include <bits/stdc++.h>\n#include <variant>\n#include <boost/range/algorithm.hpp>\n#include <boost/range/numeric.hpp>\n#include <boost/range/irange.hpp>\n#include <boost/range/adaptor/indexed.hpp>\n#define FOR(i,k,n)  for(int i = (k);i < (n);++i)\n#define REP(i,n)    FOR(i,0,n)\n#define ALL(x) begin(x),end(x)\n\nusing namespace std;\nusing namespace boost::adaptors;\nusing namespace std::string_literals;\nusing ll = int64_t;\nusing vecint = vector<int>;\nusing vecll = vector<ll>;\nusing boost::irange;\nconstexpr ll MOD = 1000000007;\n\nll pmod(ll base, ll index) {\n  if (index == 0) return 1;\n  if (index%2 == 1) return pmod(base, index-1) * base % MOD;\n  ll h = pmod(base, index/2);\n  return h * h % MOD;\n}\n\nint main() {\n  ios::sync_with_stdio(false);\n  cin.tie(nullptr);\n  ll n,k;\n  cin>>n>>k;\n  vecll v(k+1);\n  FOR(i,1,k+1) {\n    v[i] = pmod(k/i, n);\n  }\n  for (int i = k; i > 0; --i) {\n    for (int j = 2*i; j <= k; j += i) {\n      v[i] += MOD - v[j];\n      v[i] %= MOD;\n    }\n  }\n  ll ans = 0;\n  FOR(i,1,k+1) {\n    ans += i * v[i] % MOD;\n    ans %= MOD;\n  }\n  cout<<ans<<endl;\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1586740733, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02715.html", "problem_id": "p02715", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02715/input.txt", "sample_output_relpath": "derived/input_output/data/p02715/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02715/C++/s495120797.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s495120797", "user_id": "u508192873"}, "prompt_components": {"gold_output": "9\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#include <variant>\n#include <boost/range/algorithm.hpp>\n#include <boost/range/numeric.hpp>\n#include <boost/range/irange.hpp>\n#include <boost/range/adaptor/indexed.hpp>\n#define FOR(i,k,n)  for(int i = (k);i < (n);++i)\n#define REP(i,n)    FOR(i,0,n)\n#define ALL(x) begin(x),end(x)\n\nusing namespace std;\nusing namespace boost::adaptors;\nusing namespace std::string_literals;\nusing ll = int64_t;\nusing vecint = vector<int>;\nusing vecll = vector<ll>;\nusing boost::irange;\nconstexpr ll MOD = 1000000007;\n\nll pmod(ll base, ll index) {\n  if (index == 0) return 1;\n  if (index%2 == 1) return pmod(base, index-1) * base % MOD;\n  ll h = pmod(base, index/2);\n  return h * h % MOD;\n}\n\nint main() {\n  ios::sync_with_stdio(false);\n  cin.tie(nullptr);\n  ll n,k;\n  cin>>n>>k;\n  vecll v(k+1);\n  FOR(i,1,k+1) {\n    v[i] = pmod(k/i, n);\n  }\n  for (int i = k; i > 0; --i) {\n    for (int j = 2*i; j <= k; j += i) {\n      v[i] += MOD - v[j];\n      v[i] %= MOD;\n    }\n  }\n  ll ans = 0;\n  FOR(i,1,k+1) {\n    ans += i * v[i] % MOD;\n    ans %= MOD;\n  }\n  cout<<ans<<endl;\n  return 0;\n}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nConsider sequences \\{A_1,...,A_N\\} of length N consisting of integers between 1 and K (inclusive).\n\nThere are K^N such sequences. Find the sum of \\gcd(A_1, ..., A_N) over all of them.\n\nSince this sum can be enormous, print the value modulo (10^9+7).\n\nHere \\gcd(A_1, ..., A_N) denotes the greatest common divisor of A_1, ..., A_N.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n1 \\leq K \\leq 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the sum of \\gcd(A_1, ..., A_N) over all K^N sequences, modulo (10^9+7).\n\nSample Input 1\n\n3 2\n\nSample Output 1\n\n9\n\n\\gcd(1,1,1)+\\gcd(1,1,2)+\\gcd(1,2,1)+\\gcd(1,2,2)\n+\\gcd(2,1,1)+\\gcd(2,1,2)+\\gcd(2,2,1)+\\gcd(2,2,2)\n=1+1+1+1+1+1+1+2=9\n\nThus, the answer is 9.\n\nSample Input 2\n\n3 200\n\nSample Output 2\n\n10813692\n\nSample Input 3\n\n100000 100000\n\nSample Output 3\n\n742202979\n\nBe sure to print the sum modulo (10^9+7).", "sample_input": "3 2\n"}, "reference_outputs": ["9\n"], "source_document_id": "p02715", "source_text": "Score : 500 points\n\nProblem Statement\n\nConsider sequences \\{A_1,...,A_N\\} of length N consisting of integers between 1 and K (inclusive).\n\nThere are K^N such sequences. Find the sum of \\gcd(A_1, ..., A_N) over all of them.\n\nSince this sum can be enormous, print the value modulo (10^9+7).\n\nHere \\gcd(A_1, ..., A_N) denotes the greatest common divisor of A_1, ..., A_N.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n1 \\leq K \\leq 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the sum of \\gcd(A_1, ..., A_N) over all K^N sequences, modulo (10^9+7).\n\nSample Input 1\n\n3 2\n\nSample Output 1\n\n9\n\n\\gcd(1,1,1)+\\gcd(1,1,2)+\\gcd(1,2,1)+\\gcd(1,2,2)\n+\\gcd(2,1,1)+\\gcd(2,1,2)+\\gcd(2,2,1)+\\gcd(2,2,2)\n=1+1+1+1+1+1+1+2=9\n\nThus, the answer is 9.\n\nSample Input 2\n\n3 200\n\nSample Output 2\n\n10813692\n\nSample Input 3\n\n100000 100000\n\nSample Output 3\n\n742202979\n\nBe sure to print the sum modulo (10^9+7).", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1084, "cpu_time_ms": 24, "memory_kb": 3992}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s992141407", "group_id": "codeNet:p02719", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef long double ld;\nconst int mod=1000000007;\nconst double PI = 3.14159265359;\n#define mxe(v) *max_element(v.begin(),v.end())\n#define mne(v) *min_element(v.begin(),v.end())\n#define INF 1000000000000\n#define pb push_back\n#define pf push_front\n#define ppb pop_back\n#define ppf pop_front\n#define mp make_pair\n#define lb lower_bound\n#define ub upper_bound\n#define FOR(i,n) for(int i=0;i<(n);i++)\n#define FORA(i,a,b) for(int i=(a);i<=(b);i++)\n#define FORD(i,a,b) for(int i=(a);i>=(b);i--)\n#define FAST ios_base::sync_with_stdio(false);cin.tie(NULL);\n#define count_1(n)  __builtin_popcountll(n)\n#define parity(n)   __builtin_parityll(n)   //Even parity 0 as output\nvoid show    (int a[], int arraysize) { for (int i = 0; i < arraysize; ++i)  {cout << a[i] << \" \";}\tcout<<endl;}\nint gcd(int a, int b) { if (b == 0) return a; return gcd(b, a % b);}\nvoid sieve(int n)\n{\n    bool prime[n+1];\n    memset(prime, true, sizeof(prime));\n\n    for (int p=2; p*p<=n; p++)\n    {\n        if (prime[p] == true)\n        {\n            for (int i=p*p; i<=n; i += p)\n                prime[i] = false;\n        }\n    }\n    for (int p=2; p<=n; p++)\n       if (prime[p])\n          cout << p << \" \";\n}\nint main()\n{FAST\nint n,k;\ncin>>n>>k;\nif(k>=n)\n{\n\tcout<<min(n,abs(n-k));\n}\nelse\n{\n\tcout<<n%k<<endl;\n}\nreturn  0;\n}\n\n\n\n\n", "language": "C++", "metadata": {"date": 1592770786, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02719.html", "problem_id": "p02719", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02719/input.txt", "sample_output_relpath": "derived/input_output/data/p02719/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02719/C++/s992141407.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s992141407", "user_id": "u076444486"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef long double ld;\nconst int mod=1000000007;\nconst double PI = 3.14159265359;\n#define mxe(v) *max_element(v.begin(),v.end())\n#define mne(v) *min_element(v.begin(),v.end())\n#define INF 1000000000000\n#define pb push_back\n#define pf push_front\n#define ppb pop_back\n#define ppf pop_front\n#define mp make_pair\n#define lb lower_bound\n#define ub upper_bound\n#define FOR(i,n) for(int i=0;i<(n);i++)\n#define FORA(i,a,b) for(int i=(a);i<=(b);i++)\n#define FORD(i,a,b) for(int i=(a);i>=(b);i--)\n#define FAST ios_base::sync_with_stdio(false);cin.tie(NULL);\n#define count_1(n)  __builtin_popcountll(n)\n#define parity(n)   __builtin_parityll(n)   //Even parity 0 as output\nvoid show    (int a[], int arraysize) { for (int i = 0; i < arraysize; ++i)  {cout << a[i] << \" \";}\tcout<<endl;}\nint gcd(int a, int b) { if (b == 0) return a; return gcd(b, a % b);}\nvoid sieve(int n)\n{\n    bool prime[n+1];\n    memset(prime, true, sizeof(prime));\n\n    for (int p=2; p*p<=n; p++)\n    {\n        if (prime[p] == true)\n        {\n            for (int i=p*p; i<=n; i += p)\n                prime[i] = false;\n        }\n    }\n    for (int p=2; p<=n; p++)\n       if (prime[p])\n          cout << p << \" \";\n}\nint main()\n{FAST\nint n,k;\ncin>>n>>k;\nif(k>=n)\n{\n\tcout<<min(n,abs(n-k));\n}\nelse\n{\n\tcout<<n%k<<endl;\n}\nreturn  0;\n}\n\n\n\n\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nGiven any integer x, Aoki can do the operation below.\n\nOperation: Replace x with the absolute difference of x and K.\n\nYou are given the initial value of an integer N. Find the minimum possible value taken by N after Aoki does the operation zero or more times.\n\nConstraints\n\n0 ≤ N ≤ 10^{18}\n\n1 ≤ K ≤ 10^{18}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the minimum possible value taken by N after Aoki does the operation zero or more times.\n\nSample Input 1\n\n7 4\n\nSample Output 1\n\n1\n\nInitially, N=7.\n\nAfter one operation, N becomes |7-4| = 3.\n\nAfter two operations, N becomes |3-4| = 1, which is the minimum value taken by N.\n\nSample Input 2\n\n2 6\n\nSample Output 2\n\n2\n\nN=2 after zero operations is the minimum.\n\nSample Input 3\n\n1000000000000000000 1\n\nSample Output 3\n\n0", "sample_input": "7 4\n"}, "reference_outputs": ["1\n"], "source_document_id": "p02719", "source_text": "Score : 300 points\n\nProblem Statement\n\nGiven any integer x, Aoki can do the operation below.\n\nOperation: Replace x with the absolute difference of x and K.\n\nYou are given the initial value of an integer N. Find the minimum possible value taken by N after Aoki does the operation zero or more times.\n\nConstraints\n\n0 ≤ N ≤ 10^{18}\n\n1 ≤ K ≤ 10^{18}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the minimum possible value taken by N after Aoki does the operation zero or more times.\n\nSample Input 1\n\n7 4\n\nSample Output 1\n\n1\n\nInitially, N=7.\n\nAfter one operation, N becomes |7-4| = 3.\n\nAfter two operations, N becomes |3-4| = 1, which is the minimum value taken by N.\n\nSample Input 2\n\n2 6\n\nSample Output 2\n\n2\n\nN=2 after zero operations is the minimum.\n\nSample Input 3\n\n1000000000000000000 1\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1361, "cpu_time_ms": 6, "memory_kb": 3628}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s491490420", "group_id": "codeNet:p02719", "input_text": "                   /**Bismillahir Rahmanir Rahim.**/\n/*\n         Md.Fagun Molla\n         18ICTCSE006\n         BSMRSTU(SHIICT)\n*/\n#include <bits/stdc++.h>\nusing namespace std;\n\n\n#define  gcd(a,b)         __gcd(a,b)\n#define  lcm(a,b)         (a*b)/gcd(a,b)\n#define  ll               long long\n#define  vi               std::vector<int>\n#define  pb               push_back\n#define  MAX              100007\n#define  End              return 0;\n#define  pi               acos(-1)\n\nmap<string,int>v;\nint main () {\n    ios_base::sync_with_stdio(false); cin.tie(0);cout.tie(0);\n    ll n,k;\n    cin>>n>>k;\n    ll x=n%k;\n    ll y=abs((n/k+1)*(k)-n);\n    //cout<<x<<\" \"<<y<<endl;\n    cout<<min(x,y)<<endl;\n    End\n}\n/* pray for me\nDo before die\n*/\n", "language": "C++", "metadata": {"date": 1586317867, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02719.html", "problem_id": "p02719", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02719/input.txt", "sample_output_relpath": "derived/input_output/data/p02719/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02719/C++/s491490420.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s491490420", "user_id": "u199299168"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "                   /**Bismillahir Rahmanir Rahim.**/\n/*\n         Md.Fagun Molla\n         18ICTCSE006\n         BSMRSTU(SHIICT)\n*/\n#include <bits/stdc++.h>\nusing namespace std;\n\n\n#define  gcd(a,b)         __gcd(a,b)\n#define  lcm(a,b)         (a*b)/gcd(a,b)\n#define  ll               long long\n#define  vi               std::vector<int>\n#define  pb               push_back\n#define  MAX              100007\n#define  End              return 0;\n#define  pi               acos(-1)\n\nmap<string,int>v;\nint main () {\n    ios_base::sync_with_stdio(false); cin.tie(0);cout.tie(0);\n    ll n,k;\n    cin>>n>>k;\n    ll x=n%k;\n    ll y=abs((n/k+1)*(k)-n);\n    //cout<<x<<\" \"<<y<<endl;\n    cout<<min(x,y)<<endl;\n    End\n}\n/* pray for me\nDo before die\n*/\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nGiven any integer x, Aoki can do the operation below.\n\nOperation: Replace x with the absolute difference of x and K.\n\nYou are given the initial value of an integer N. Find the minimum possible value taken by N after Aoki does the operation zero or more times.\n\nConstraints\n\n0 ≤ N ≤ 10^{18}\n\n1 ≤ K ≤ 10^{18}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the minimum possible value taken by N after Aoki does the operation zero or more times.\n\nSample Input 1\n\n7 4\n\nSample Output 1\n\n1\n\nInitially, N=7.\n\nAfter one operation, N becomes |7-4| = 3.\n\nAfter two operations, N becomes |3-4| = 1, which is the minimum value taken by N.\n\nSample Input 2\n\n2 6\n\nSample Output 2\n\n2\n\nN=2 after zero operations is the minimum.\n\nSample Input 3\n\n1000000000000000000 1\n\nSample Output 3\n\n0", "sample_input": "7 4\n"}, "reference_outputs": ["1\n"], "source_document_id": "p02719", "source_text": "Score : 300 points\n\nProblem Statement\n\nGiven any integer x, Aoki can do the operation below.\n\nOperation: Replace x with the absolute difference of x and K.\n\nYou are given the initial value of an integer N. Find the minimum possible value taken by N after Aoki does the operation zero or more times.\n\nConstraints\n\n0 ≤ N ≤ 10^{18}\n\n1 ≤ K ≤ 10^{18}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the minimum possible value taken by N after Aoki does the operation zero or more times.\n\nSample Input 1\n\n7 4\n\nSample Output 1\n\n1\n\nInitially, N=7.\n\nAfter one operation, N becomes |7-4| = 3.\n\nAfter two operations, N becomes |3-4| = 1, which is the minimum value taken by N.\n\nSample Input 2\n\n2 6\n\nSample Output 2\n\n2\n\nN=2 after zero operations is the minimum.\n\nSample Input 3\n\n1000000000000000000 1\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 736, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s663885604", "group_id": "codeNet:p02719", "input_text": "#include <bits/stdc++.h>\n#define rep(i,n) for (int i = 0; i < (n); ++i)\n#define MIN(a,b) ((a) <= (b) ? (a) : (b))\n#define ALL(v) (v).begin(), (v).end()\n#define SORT(v) sort( ALL(v) )\n\nusing namespace std;\nusing ll = long long;\nusing P = pair<int,int>;\nusing ull  = unsigned long long;\n\n\n\nint main()\n{\n\n\n   ll N,K; cin >> N >> K;\n\n   N%=K;\n   cout << min(N, K-N)<<endl;\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1586055895, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02719.html", "problem_id": "p02719", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02719/input.txt", "sample_output_relpath": "derived/input_output/data/p02719/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02719/C++/s663885604.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s663885604", "user_id": "u227426199"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define rep(i,n) for (int i = 0; i < (n); ++i)\n#define MIN(a,b) ((a) <= (b) ? (a) : (b))\n#define ALL(v) (v).begin(), (v).end()\n#define SORT(v) sort( ALL(v) )\n\nusing namespace std;\nusing ll = long long;\nusing P = pair<int,int>;\nusing ull  = unsigned long long;\n\n\n\nint main()\n{\n\n\n   ll N,K; cin >> N >> K;\n\n   N%=K;\n   cout << min(N, K-N)<<endl;\n    return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nGiven any integer x, Aoki can do the operation below.\n\nOperation: Replace x with the absolute difference of x and K.\n\nYou are given the initial value of an integer N. Find the minimum possible value taken by N after Aoki does the operation zero or more times.\n\nConstraints\n\n0 ≤ N ≤ 10^{18}\n\n1 ≤ K ≤ 10^{18}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the minimum possible value taken by N after Aoki does the operation zero or more times.\n\nSample Input 1\n\n7 4\n\nSample Output 1\n\n1\n\nInitially, N=7.\n\nAfter one operation, N becomes |7-4| = 3.\n\nAfter two operations, N becomes |3-4| = 1, which is the minimum value taken by N.\n\nSample Input 2\n\n2 6\n\nSample Output 2\n\n2\n\nN=2 after zero operations is the minimum.\n\nSample Input 3\n\n1000000000000000000 1\n\nSample Output 3\n\n0", "sample_input": "7 4\n"}, "reference_outputs": ["1\n"], "source_document_id": "p02719", "source_text": "Score : 300 points\n\nProblem Statement\n\nGiven any integer x, Aoki can do the operation below.\n\nOperation: Replace x with the absolute difference of x and K.\n\nYou are given the initial value of an integer N. Find the minimum possible value taken by N after Aoki does the operation zero or more times.\n\nConstraints\n\n0 ≤ N ≤ 10^{18}\n\n1 ≤ K ≤ 10^{18}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the minimum possible value taken by N after Aoki does the operation zero or more times.\n\nSample Input 1\n\n7 4\n\nSample Output 1\n\n1\n\nInitially, N=7.\n\nAfter one operation, N becomes |7-4| = 3.\n\nAfter two operations, N becomes |3-4| = 1, which is the minimum value taken by N.\n\nSample Input 2\n\n2 6\n\nSample Output 2\n\n2\n\nN=2 after zero operations is the minimum.\n\nSample Input 3\n\n1000000000000000000 1\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 385, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s166514746", "group_id": "codeNet:p02719", "input_text": "#include <bits/stdc++.h>\n#define rep(i, n) for (int i = 0; i < (n); ++i)\nusing namespace std;\nusing ll = long long;\nusing P = pair<int, int>;\n\nint main()\n{\n  ll N, K;\n  cin >> N >> K;\n  if (N >= K) {\n    N = N % K;\n  }\n  N = min(N, abs(N-K));\n  cout << N << endl;\n}", "language": "C++", "metadata": {"date": 1586049844, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02719.html", "problem_id": "p02719", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02719/input.txt", "sample_output_relpath": "derived/input_output/data/p02719/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02719/C++/s166514746.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s166514746", "user_id": "u027641915"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define rep(i, n) for (int i = 0; i < (n); ++i)\nusing namespace std;\nusing ll = long long;\nusing P = pair<int, int>;\n\nint main()\n{\n  ll N, K;\n  cin >> N >> K;\n  if (N >= K) {\n    N = N % K;\n  }\n  N = min(N, abs(N-K));\n  cout << N << endl;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nGiven any integer x, Aoki can do the operation below.\n\nOperation: Replace x with the absolute difference of x and K.\n\nYou are given the initial value of an integer N. Find the minimum possible value taken by N after Aoki does the operation zero or more times.\n\nConstraints\n\n0 ≤ N ≤ 10^{18}\n\n1 ≤ K ≤ 10^{18}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the minimum possible value taken by N after Aoki does the operation zero or more times.\n\nSample Input 1\n\n7 4\n\nSample Output 1\n\n1\n\nInitially, N=7.\n\nAfter one operation, N becomes |7-4| = 3.\n\nAfter two operations, N becomes |3-4| = 1, which is the minimum value taken by N.\n\nSample Input 2\n\n2 6\n\nSample Output 2\n\n2\n\nN=2 after zero operations is the minimum.\n\nSample Input 3\n\n1000000000000000000 1\n\nSample Output 3\n\n0", "sample_input": "7 4\n"}, "reference_outputs": ["1\n"], "source_document_id": "p02719", "source_text": "Score : 300 points\n\nProblem Statement\n\nGiven any integer x, Aoki can do the operation below.\n\nOperation: Replace x with the absolute difference of x and K.\n\nYou are given the initial value of an integer N. Find the minimum possible value taken by N after Aoki does the operation zero or more times.\n\nConstraints\n\n0 ≤ N ≤ 10^{18}\n\n1 ≤ K ≤ 10^{18}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the minimum possible value taken by N after Aoki does the operation zero or more times.\n\nSample Input 1\n\n7 4\n\nSample Output 1\n\n1\n\nInitially, N=7.\n\nAfter one operation, N becomes |7-4| = 3.\n\nAfter two operations, N becomes |3-4| = 1, which is the minimum value taken by N.\n\nSample Input 2\n\n2 6\n\nSample Output 2\n\n2\n\nN=2 after zero operations is the minimum.\n\nSample Input 3\n\n1000000000000000000 1\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 265, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s795416980", "group_id": "codeNet:p02719", "input_text": "// SeeAlso: \n\n#include <bits/stdc++.h>\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef vector<int> vi;\ntypedef vector<ll> vl;\ntypedef pair<int,int> pii;\ntypedef pair<ll,ll> pll;\n\n#define MAX 100000\n#define NIL -1\n#define MOD 1000000007\n\ntypedef int _loop_int;\n#define rep(i,n) for(int i = 0; i < n; i++)\n#define FOR(i,a,b) for(_loop_int i=(_loop_int)(a);i<(_loop_int)(b);++i)\n#define FORR(i,a,b) for(_loop_int i=(_loop_int)(b)-1;i>=(_loop_int)(a);--i)\n\n#define debug(x) cout<<#x<<\": \"<<x<<endl\n#define debig_vec(v) cout<<#v<<\":\";rep(i,v.size())cout<<\" \"<<v[i];cout<<endl\n#define ALL(a) (a).begin(),(a).end()\n\n// 最大公約数\ninline constexpr ll gcd(ll a,ll b){if(!a||!b)return 0;while(b){ll c=b;b=a%b;a=c;}return a;}\n// 最小公倍数\ninline constexpr ll lcm(ll a,ll b){if(!a||!b)return 0;return a*b/gcd(a,b);}\n\n#define print2D(h, w, arr) rep(i, h) { rep(j, w) cout << arr[i][j] << \" \"; cout << endl; }\ntemplate<class T> void print(const T& x){cout << setprecision(12) << x << endl;}\ntemplate<class T, class... A> void print(const T& first, const A&... rest) { cout << first << \" \"; print(rest...); }\n\nint main() {\n    ll n,k;\n    cin>>n>>k;\n    ll t = n%k;\n    print(min(abs(t-k), t));\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1586048976, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02719.html", "problem_id": "p02719", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02719/input.txt", "sample_output_relpath": "derived/input_output/data/p02719/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02719/C++/s795416980.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s795416980", "user_id": "u185518252"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "// SeeAlso: \n\n#include <bits/stdc++.h>\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef vector<int> vi;\ntypedef vector<ll> vl;\ntypedef pair<int,int> pii;\ntypedef pair<ll,ll> pll;\n\n#define MAX 100000\n#define NIL -1\n#define MOD 1000000007\n\ntypedef int _loop_int;\n#define rep(i,n) for(int i = 0; i < n; i++)\n#define FOR(i,a,b) for(_loop_int i=(_loop_int)(a);i<(_loop_int)(b);++i)\n#define FORR(i,a,b) for(_loop_int i=(_loop_int)(b)-1;i>=(_loop_int)(a);--i)\n\n#define debug(x) cout<<#x<<\": \"<<x<<endl\n#define debig_vec(v) cout<<#v<<\":\";rep(i,v.size())cout<<\" \"<<v[i];cout<<endl\n#define ALL(a) (a).begin(),(a).end()\n\n// 最大公約数\ninline constexpr ll gcd(ll a,ll b){if(!a||!b)return 0;while(b){ll c=b;b=a%b;a=c;}return a;}\n// 最小公倍数\ninline constexpr ll lcm(ll a,ll b){if(!a||!b)return 0;return a*b/gcd(a,b);}\n\n#define print2D(h, w, arr) rep(i, h) { rep(j, w) cout << arr[i][j] << \" \"; cout << endl; }\ntemplate<class T> void print(const T& x){cout << setprecision(12) << x << endl;}\ntemplate<class T, class... A> void print(const T& first, const A&... rest) { cout << first << \" \"; print(rest...); }\n\nint main() {\n    ll n,k;\n    cin>>n>>k;\n    ll t = n%k;\n    print(min(abs(t-k), t));\n    return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nGiven any integer x, Aoki can do the operation below.\n\nOperation: Replace x with the absolute difference of x and K.\n\nYou are given the initial value of an integer N. Find the minimum possible value taken by N after Aoki does the operation zero or more times.\n\nConstraints\n\n0 ≤ N ≤ 10^{18}\n\n1 ≤ K ≤ 10^{18}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the minimum possible value taken by N after Aoki does the operation zero or more times.\n\nSample Input 1\n\n7 4\n\nSample Output 1\n\n1\n\nInitially, N=7.\n\nAfter one operation, N becomes |7-4| = 3.\n\nAfter two operations, N becomes |3-4| = 1, which is the minimum value taken by N.\n\nSample Input 2\n\n2 6\n\nSample Output 2\n\n2\n\nN=2 after zero operations is the minimum.\n\nSample Input 3\n\n1000000000000000000 1\n\nSample Output 3\n\n0", "sample_input": "7 4\n"}, "reference_outputs": ["1\n"], "source_document_id": "p02719", "source_text": "Score : 300 points\n\nProblem Statement\n\nGiven any integer x, Aoki can do the operation below.\n\nOperation: Replace x with the absolute difference of x and K.\n\nYou are given the initial value of an integer N. Find the minimum possible value taken by N after Aoki does the operation zero or more times.\n\nConstraints\n\n0 ≤ N ≤ 10^{18}\n\n1 ≤ K ≤ 10^{18}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the minimum possible value taken by N after Aoki does the operation zero or more times.\n\nSample Input 1\n\n7 4\n\nSample Output 1\n\n1\n\nInitially, N=7.\n\nAfter one operation, N becomes |7-4| = 3.\n\nAfter two operations, N becomes |3-4| = 1, which is the minimum value taken by N.\n\nSample Input 2\n\n2 6\n\nSample Output 2\n\n2\n\nN=2 after zero operations is the minimum.\n\nSample Input 3\n\n1000000000000000000 1\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1212, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s707094579", "group_id": "codeNet:p02720", "input_text": "#include<bits/stdc++.h>\n#define pb push_back\n#define mp make_pair\n#define fst first\n#define snd second\nusing namespace std;\n\ntypedef long long ll;\ntypedef double db;\ntypedef long double ldb;\n\ntemplate<class T> inline void checkmin(T &a,const T &b){if(b<a) a=b;}\ntemplate<class T> inline void checkmax(T &a,const T &b){if(b>a) a=b;}\n\nconst int inf=1e9+10;\nconst int maxn=15;\nconst int mod=2e5;\n\nint dp[maxn][maxn],k,tot[maxn];\n\nint add(int &a,int b){\n\ta=(a+b)%mod;\n}\n\nint main(){\n\tcin>>k;\n\tfor(int t=0;t<10;t++) dp[1][t]=1;\n\tfor(int i=1;i<=10;i++){\n\t\tfor(int t=0;t<10;t++){\n\t\t\tif(t-1>=0) add(dp[i+1][t-1],dp[i][t]);\n\t\t\tif(t+1<=9) add(dp[i+1][t+1],dp[i][t]); \n\t\t\tadd(dp[i+1][t],dp[i][t]);\n\t\t}\n\t\tfor(int t=1;t<10;t++){\n\t\t\tadd(tot[i],dp[i][t]);\n\t\t}\n\t\tadd(tot[i],tot[i-1]);\n\t}\n\tint len=1,sum=0;\n\tfor(;;){\n\t\tfor(int t=1;t<10;t++){\n\t\t\tsum+=dp[len][t];\n\t\t}\n\t\tif(sum>=k) break;\n\t\tlen++;\n\t}\n//\tcout<<len<<endl;\n\tint mini=0,maxi=9;\n\tdp[len][0]=tot[len-1];\n\tstring ans=\"\";\n\tfor(int i=len;i>=1;i--){\n\t\tfor(int t=mini;t<=maxi;t++){\n\t\t\tif(dp[i][t]>=k){\n\t\t\t\tmini=max(0,t-1);\n\t\t\t\tmaxi=min(9,t+1);\n\t\t\t\tans+=char('0'+t);\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\telse{\n\t\t\t\tk-=dp[i][t];\n\t\t\t//\tcout<<i<<\" \"<<t<<\" \"<<mini<<\" \"<<maxi<<\" \"<<dp[i][t]<<\" \"<<k<<endl;\n\t\t\t}\n\t\t}\n\t}\n\tcout<<ans;\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1586921226, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02720.html", "problem_id": "p02720", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02720/input.txt", "sample_output_relpath": "derived/input_output/data/p02720/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02720/C++/s707094579.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s707094579", "user_id": "u739318530"}, "prompt_components": {"gold_output": "23\n", "input_to_evaluate": "#include<bits/stdc++.h>\n#define pb push_back\n#define mp make_pair\n#define fst first\n#define snd second\nusing namespace std;\n\ntypedef long long ll;\ntypedef double db;\ntypedef long double ldb;\n\ntemplate<class T> inline void checkmin(T &a,const T &b){if(b<a) a=b;}\ntemplate<class T> inline void checkmax(T &a,const T &b){if(b>a) a=b;}\n\nconst int inf=1e9+10;\nconst int maxn=15;\nconst int mod=2e5;\n\nint dp[maxn][maxn],k,tot[maxn];\n\nint add(int &a,int b){\n\ta=(a+b)%mod;\n}\n\nint main(){\n\tcin>>k;\n\tfor(int t=0;t<10;t++) dp[1][t]=1;\n\tfor(int i=1;i<=10;i++){\n\t\tfor(int t=0;t<10;t++){\n\t\t\tif(t-1>=0) add(dp[i+1][t-1],dp[i][t]);\n\t\t\tif(t+1<=9) add(dp[i+1][t+1],dp[i][t]); \n\t\t\tadd(dp[i+1][t],dp[i][t]);\n\t\t}\n\t\tfor(int t=1;t<10;t++){\n\t\t\tadd(tot[i],dp[i][t]);\n\t\t}\n\t\tadd(tot[i],tot[i-1]);\n\t}\n\tint len=1,sum=0;\n\tfor(;;){\n\t\tfor(int t=1;t<10;t++){\n\t\t\tsum+=dp[len][t];\n\t\t}\n\t\tif(sum>=k) break;\n\t\tlen++;\n\t}\n//\tcout<<len<<endl;\n\tint mini=0,maxi=9;\n\tdp[len][0]=tot[len-1];\n\tstring ans=\"\";\n\tfor(int i=len;i>=1;i--){\n\t\tfor(int t=mini;t<=maxi;t++){\n\t\t\tif(dp[i][t]>=k){\n\t\t\t\tmini=max(0,t-1);\n\t\t\t\tmaxi=min(9,t+1);\n\t\t\t\tans+=char('0'+t);\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\telse{\n\t\t\t\tk-=dp[i][t];\n\t\t\t//\tcout<<i<<\" \"<<t<<\" \"<<mini<<\" \"<<maxi<<\" \"<<dp[i][t]<<\" \"<<k<<endl;\n\t\t\t}\n\t\t}\n\t}\n\tcout<<ans;\n\treturn 0;\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nA positive integer X is said to be a lunlun number if and only if the following condition is satisfied:\n\nIn the base ten representation of X (without leading zeros), for every pair of two adjacent digits, the absolute difference of those digits is at most 1.\n\nFor example, 1234, 1, and 334 are lunlun numbers, while none of 31415, 119, or 13579 is.\n\nYou are given a positive integer K. Find the K-th smallest lunlun number.\n\nConstraints\n\n1 \\leq K \\leq 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nK\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n15\n\nSample Output 1\n\n23\n\nWe will list the 15 smallest lunlun numbers in ascending order:\n\n1,\n2,\n3,\n4,\n5,\n6,\n7,\n8,\n9,\n10,\n11,\n12,\n21,\n22,\n23.\n\nThus, the answer is 23.\n\nSample Input 2\n\n1\n\nSample Output 2\n\n1\n\nSample Input 3\n\n13\n\nSample Output 3\n\n21\n\nSample Input 4\n\n100000\n\nSample Output 4\n\n3234566667\n\nNote that the answer may not fit into the 32-bit signed integer type.", "sample_input": "15\n"}, "reference_outputs": ["23\n"], "source_document_id": "p02720", "source_text": "Score : 400 points\n\nProblem Statement\n\nA positive integer X is said to be a lunlun number if and only if the following condition is satisfied:\n\nIn the base ten representation of X (without leading zeros), for every pair of two adjacent digits, the absolute difference of those digits is at most 1.\n\nFor example, 1234, 1, and 334 are lunlun numbers, while none of 31415, 119, or 13579 is.\n\nYou are given a positive integer K. Find the K-th smallest lunlun number.\n\nConstraints\n\n1 \\leq K \\leq 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nK\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n15\n\nSample Output 1\n\n23\n\nWe will list the 15 smallest lunlun numbers in ascending order:\n\n1,\n2,\n3,\n4,\n5,\n6,\n7,\n8,\n9,\n10,\n11,\n12,\n21,\n22,\n23.\n\nThus, the answer is 23.\n\nSample Input 2\n\n1\n\nSample Output 2\n\n1\n\nSample Input 3\n\n13\n\nSample Output 3\n\n21\n\nSample Input 4\n\n100000\n\nSample Output 4\n\n3234566667\n\nNote that the answer may not fit into the 32-bit signed integer type.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1255, "cpu_time_ms": 3, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s286623593", "group_id": "codeNet:p02721", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntemplate<typename T1,typename T2> bool chmin(T1 &a,T2 b){if(a<=b)return 0; a=b; return 1;}\ntemplate<typename T1,typename T2> bool chmax(T1 &a,T2 b){if(a>=b)return 0; a=b; return 1;}\n\n\n\n\nsigned main(){\n    ios::sync_with_stdio(false);\n    cin.tie(0);\n    cout << fixed << setprecision(20);\n\n    int n,k,c;\n    cin>>n>>k>>c;\n    string s;\n    cin>>s;\n    if(c==0){\n        int cnt = 0;\n        for(int i=0;i<n;i++){\n            if(s[i]='o')cnt++;\n        }\n        if(cnt == k){\n            for(int i=0;i<n;i++){\n                if(s[i]=='o'){\n                    cout << i +1 << endl;\n                }\n\n            }\n        }\n        return 0;\n    }\n    vector<int> ans;\n    int a[n+1]={};\n    int r = 0;\n    for(int i=0;i<n;i++){\n        if(i) chmax(a[i],a[i-1]);\n        if(s[i] == 'o' && i >= r){\n            chmax(a[min(n,i+c+1)],a[i]+1);\n            r = i+c+1;\n        }\n    }\n    //for(int i=0;i<=n;i++) cout << a[i];\n    //cout << endl;\n    chmax(a[n],a[n-1]);\n    if(a[n] == k){\n        int r = n-1;\n        for(int p=k-1;p>=0;p--){\n            int cnt = 0;\n            int v = -1;\n            for(int i=r;i>=0;i--){\n                if(a[i] != p){\n                    r = i;\n                    break;\n                }\n                if(s[i] == 'o'){\n                    cnt++;\n                    v = i+1;\n                }\n            }\n            //cerr << p << \" \" << cnt << endl;\n            if(cnt == 1){\n                ans.push_back(v);\n                r = min(r,v-c-2);\n            }\n        }\n    }\n    if(ans.size())sort(ans.begin(),ans.end());\n    for(auto i:ans){\n        cout << i << \"\\n\";\n    }\n\n}", "language": "C++", "metadata": {"date": 1586054364, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02721.html", "problem_id": "p02721", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02721/input.txt", "sample_output_relpath": "derived/input_output/data/p02721/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02721/C++/s286623593.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s286623593", "user_id": "u676029460"}, "prompt_components": {"gold_output": "6\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntemplate<typename T1,typename T2> bool chmin(T1 &a,T2 b){if(a<=b)return 0; a=b; return 1;}\ntemplate<typename T1,typename T2> bool chmax(T1 &a,T2 b){if(a>=b)return 0; a=b; return 1;}\n\n\n\n\nsigned main(){\n    ios::sync_with_stdio(false);\n    cin.tie(0);\n    cout << fixed << setprecision(20);\n\n    int n,k,c;\n    cin>>n>>k>>c;\n    string s;\n    cin>>s;\n    if(c==0){\n        int cnt = 0;\n        for(int i=0;i<n;i++){\n            if(s[i]='o')cnt++;\n        }\n        if(cnt == k){\n            for(int i=0;i<n;i++){\n                if(s[i]=='o'){\n                    cout << i +1 << endl;\n                }\n\n            }\n        }\n        return 0;\n    }\n    vector<int> ans;\n    int a[n+1]={};\n    int r = 0;\n    for(int i=0;i<n;i++){\n        if(i) chmax(a[i],a[i-1]);\n        if(s[i] == 'o' && i >= r){\n            chmax(a[min(n,i+c+1)],a[i]+1);\n            r = i+c+1;\n        }\n    }\n    //for(int i=0;i<=n;i++) cout << a[i];\n    //cout << endl;\n    chmax(a[n],a[n-1]);\n    if(a[n] == k){\n        int r = n-1;\n        for(int p=k-1;p>=0;p--){\n            int cnt = 0;\n            int v = -1;\n            for(int i=r;i>=0;i--){\n                if(a[i] != p){\n                    r = i;\n                    break;\n                }\n                if(s[i] == 'o'){\n                    cnt++;\n                    v = i+1;\n                }\n            }\n            //cerr << p << \" \" << cnt << endl;\n            if(cnt == 1){\n                ans.push_back(v);\n                r = min(r,v-c-2);\n            }\n        }\n    }\n    if(ans.size())sort(ans.begin(),ans.end());\n    for(auto i:ans){\n        cout << i << \"\\n\";\n    }\n\n}", "problem_context": "Score : 500 points\n\nProblem Statement\n\nTakahashi has decided to work on K days of his choice from the N days starting with tomorrow.\n\nYou are given an integer C and a string S. Takahashi will choose his workdays as follows:\n\nAfter working for a day, he will refrain from working on the subsequent C days.\n\nIf the i-th character of S is x, he will not work on Day i, where Day 1 is tomorrow, Day 2 is the day after tomorrow, and so on.\n\nFind all days on which Takahashi is bound to work.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq K \\leq N\n\n0 \\leq C \\leq N\n\nThe length of S is N.\n\nEach character of S is o or x.\n\nTakahashi can choose his workdays so that the conditions in Problem Statement are satisfied.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K C\nS\n\nOutput\n\nPrint all days on which Takahashi is bound to work in ascending order, one per line.\n\nSample Input 1\n\n11 3 2\nooxxxoxxxoo\n\nSample Output 1\n\n6\n\nTakahashi is going to work on 3 days out of the 11 days. After working for a day, he will refrain from working on the subsequent 2 days.\n\nThere are four possible choices for his workdays: Day 1,6,10, Day 1,6,11, Day 2,6,10, and Day 2,6,11.\n\nThus, he is bound to work on Day 6.\n\nSample Input 2\n\n5 2 3\nooxoo\n\nSample Output 2\n\n1\n5\n\nThere is only one possible choice for his workdays: Day 1,5.\n\nSample Input 3\n\n5 1 0\nooooo\n\nSample Output 3\n\nThere may be no days on which he is bound to work.\n\nSample Input 4\n\n16 4 3\nooxxoxoxxxoxoxxo\n\nSample Output 4\n\n11\n16", "sample_input": "11 3 2\nooxxxoxxxoo\n"}, "reference_outputs": ["6\n"], "source_document_id": "p02721", "source_text": "Score : 500 points\n\nProblem Statement\n\nTakahashi has decided to work on K days of his choice from the N days starting with tomorrow.\n\nYou are given an integer C and a string S. Takahashi will choose his workdays as follows:\n\nAfter working for a day, he will refrain from working on the subsequent C days.\n\nIf the i-th character of S is x, he will not work on Day i, where Day 1 is tomorrow, Day 2 is the day after tomorrow, and so on.\n\nFind all days on which Takahashi is bound to work.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq K \\leq N\n\n0 \\leq C \\leq N\n\nThe length of S is N.\n\nEach character of S is o or x.\n\nTakahashi can choose his workdays so that the conditions in Problem Statement are satisfied.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K C\nS\n\nOutput\n\nPrint all days on which Takahashi is bound to work in ascending order, one per line.\n\nSample Input 1\n\n11 3 2\nooxxxoxxxoo\n\nSample Output 1\n\n6\n\nTakahashi is going to work on 3 days out of the 11 days. After working for a day, he will refrain from working on the subsequent 2 days.\n\nThere are four possible choices for his workdays: Day 1,6,10, Day 1,6,11, Day 2,6,10, and Day 2,6,11.\n\nThus, he is bound to work on Day 6.\n\nSample Input 2\n\n5 2 3\nooxoo\n\nSample Output 2\n\n1\n5\n\nThere is only one possible choice for his workdays: Day 1,5.\n\nSample Input 3\n\n5 1 0\nooooo\n\nSample Output 3\n\nThere may be no days on which he is bound to work.\n\nSample Input 4\n\n16 4 3\nooxxoxoxxxoxoxxo\n\nSample Output 4\n\n11\n16", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1691, "cpu_time_ms": 299, "memory_kb": 1812}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s965379663", "group_id": "codeNet:p02721", "input_text": "#include <bits/stdc++.h> \nusing namespace std; \n#pragma GCC target (\"avx2\")\n#pragma GCC optimization (\"O3\")\n#pragma GCC optimization (\"unroll-loops\")\n#define flash ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0)\n#define debug(x) cerr << \" - \" << #x << \": \" << x << endl;\n#define debugs(x, y) cerr << \" - \" << #x << \": \" << x << \" \" << #y << \": \" << y << endl;\n#define all(x) (x).begin(),(x).end()\n#define sz(x) (ll)x.size()\n#define ll long long\n#define INF 1000000000\n#define MOD 1000000007\n#define pb push_back\n#define ve vector<ll>\n#define dos pair<ll,ll>\n#define vedos vector<dos>\n#define rand mt19937 rng(chrono::steady_clock::now().time_since_epoch().count())\n#define EPS 0.000001\nstruct greateri\n{\n    template<class T>\n    bool operator()(T const &a, T const &b) const { return a > b; }\n};\nvoid setIO(string s) {\n    ios_base::sync_with_stdio(0); cin.tie(0); \n    freopen((s+\".in\").c_str(),\"r\",stdin);\n    freopen((s+\".out\").c_str(),\"w\",stdout);\n}\nint dp[300001],dp1[300001];\nstring kal;\nint c,n,k;\nset<int>pos;\nset<int>posi;\nint solve(int index)\n{\n    int ans=1;\n    auto u = pos.lower_bound(index+c+1);\n    if(dp[index]!=-1)return dp[index];\n    if(u!=pos.end())\n    {\n       ans=max(ans,1+solve((*u))); \n    }\n    return dp[index]=ans;\n}\nint solve1(int index)\n{\n    int ans=1;\n    auto u = posi.lower_bound(-index+c+1);\n    if(dp1[index]!=-1)return dp1[index];\n    if(u!=pos.end() && (*u)<=0)\n    {\n       ans=max(ans,1+solve1(-(*u))); \n    }\n    return dp1[index]=ans;\n}\nint main()\n{\n  //flash;\n  cin>>n>>k>>c;\n  cin>>kal;\n  ve kaki;\n  memset(dp,-1,sizeof dp);\n  memset(dp1,-1,sizeof dp1);\n  for (int i = 0; i < kal.size(); ++i)\n  {\n      if(kal[i]=='o'){pos.insert(i);posi.insert(-i);kaki.pb(i);}\n  }\n  for(auto it:pos){solve(it);solve1(it);}\n  int last=0;\n  ve ans;\n  for (int i = 0; i < kaki.size(); ++i)\n  {\n    int v=0;\n    int s=0;\n    if((i+1)>=kaki.size())s=0;\n    else s = dp[kaki[i+1]];\n    if((i-1)<0)v=0;\n    else v = dp1[kaki[i-1]];\n    if((v+s)<k)ans.pb(kaki[i]);\n  }\n  for(auto it:ans)cout<<it+1<<'\\n';\n  return 0;\n}\n//code the AC sol !\n// BS/queue/map", "language": "C++", "metadata": {"date": 1586054177, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02721.html", "problem_id": "p02721", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02721/input.txt", "sample_output_relpath": "derived/input_output/data/p02721/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02721/C++/s965379663.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s965379663", "user_id": "u753916957"}, "prompt_components": {"gold_output": "6\n", "input_to_evaluate": "#include <bits/stdc++.h> \nusing namespace std; \n#pragma GCC target (\"avx2\")\n#pragma GCC optimization (\"O3\")\n#pragma GCC optimization (\"unroll-loops\")\n#define flash ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0)\n#define debug(x) cerr << \" - \" << #x << \": \" << x << endl;\n#define debugs(x, y) cerr << \" - \" << #x << \": \" << x << \" \" << #y << \": \" << y << endl;\n#define all(x) (x).begin(),(x).end()\n#define sz(x) (ll)x.size()\n#define ll long long\n#define INF 1000000000\n#define MOD 1000000007\n#define pb push_back\n#define ve vector<ll>\n#define dos pair<ll,ll>\n#define vedos vector<dos>\n#define rand mt19937 rng(chrono::steady_clock::now().time_since_epoch().count())\n#define EPS 0.000001\nstruct greateri\n{\n    template<class T>\n    bool operator()(T const &a, T const &b) const { return a > b; }\n};\nvoid setIO(string s) {\n    ios_base::sync_with_stdio(0); cin.tie(0); \n    freopen((s+\".in\").c_str(),\"r\",stdin);\n    freopen((s+\".out\").c_str(),\"w\",stdout);\n}\nint dp[300001],dp1[300001];\nstring kal;\nint c,n,k;\nset<int>pos;\nset<int>posi;\nint solve(int index)\n{\n    int ans=1;\n    auto u = pos.lower_bound(index+c+1);\n    if(dp[index]!=-1)return dp[index];\n    if(u!=pos.end())\n    {\n       ans=max(ans,1+solve((*u))); \n    }\n    return dp[index]=ans;\n}\nint solve1(int index)\n{\n    int ans=1;\n    auto u = posi.lower_bound(-index+c+1);\n    if(dp1[index]!=-1)return dp1[index];\n    if(u!=pos.end() && (*u)<=0)\n    {\n       ans=max(ans,1+solve1(-(*u))); \n    }\n    return dp1[index]=ans;\n}\nint main()\n{\n  //flash;\n  cin>>n>>k>>c;\n  cin>>kal;\n  ve kaki;\n  memset(dp,-1,sizeof dp);\n  memset(dp1,-1,sizeof dp1);\n  for (int i = 0; i < kal.size(); ++i)\n  {\n      if(kal[i]=='o'){pos.insert(i);posi.insert(-i);kaki.pb(i);}\n  }\n  for(auto it:pos){solve(it);solve1(it);}\n  int last=0;\n  ve ans;\n  for (int i = 0; i < kaki.size(); ++i)\n  {\n    int v=0;\n    int s=0;\n    if((i+1)>=kaki.size())s=0;\n    else s = dp[kaki[i+1]];\n    if((i-1)<0)v=0;\n    else v = dp1[kaki[i-1]];\n    if((v+s)<k)ans.pb(kaki[i]);\n  }\n  for(auto it:ans)cout<<it+1<<'\\n';\n  return 0;\n}\n//code the AC sol !\n// BS/queue/map", "problem_context": "Score : 500 points\n\nProblem Statement\n\nTakahashi has decided to work on K days of his choice from the N days starting with tomorrow.\n\nYou are given an integer C and a string S. Takahashi will choose his workdays as follows:\n\nAfter working for a day, he will refrain from working on the subsequent C days.\n\nIf the i-th character of S is x, he will not work on Day i, where Day 1 is tomorrow, Day 2 is the day after tomorrow, and so on.\n\nFind all days on which Takahashi is bound to work.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq K \\leq N\n\n0 \\leq C \\leq N\n\nThe length of S is N.\n\nEach character of S is o or x.\n\nTakahashi can choose his workdays so that the conditions in Problem Statement are satisfied.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K C\nS\n\nOutput\n\nPrint all days on which Takahashi is bound to work in ascending order, one per line.\n\nSample Input 1\n\n11 3 2\nooxxxoxxxoo\n\nSample Output 1\n\n6\n\nTakahashi is going to work on 3 days out of the 11 days. After working for a day, he will refrain from working on the subsequent 2 days.\n\nThere are four possible choices for his workdays: Day 1,6,10, Day 1,6,11, Day 2,6,10, and Day 2,6,11.\n\nThus, he is bound to work on Day 6.\n\nSample Input 2\n\n5 2 3\nooxoo\n\nSample Output 2\n\n1\n5\n\nThere is only one possible choice for his workdays: Day 1,5.\n\nSample Input 3\n\n5 1 0\nooooo\n\nSample Output 3\n\nThere may be no days on which he is bound to work.\n\nSample Input 4\n\n16 4 3\nooxxoxoxxxoxoxxo\n\nSample Output 4\n\n11\n16", "sample_input": "11 3 2\nooxxxoxxxoo\n"}, "reference_outputs": ["6\n"], "source_document_id": "p02721", "source_text": "Score : 500 points\n\nProblem Statement\n\nTakahashi has decided to work on K days of his choice from the N days starting with tomorrow.\n\nYou are given an integer C and a string S. Takahashi will choose his workdays as follows:\n\nAfter working for a day, he will refrain from working on the subsequent C days.\n\nIf the i-th character of S is x, he will not work on Day i, where Day 1 is tomorrow, Day 2 is the day after tomorrow, and so on.\n\nFind all days on which Takahashi is bound to work.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq K \\leq N\n\n0 \\leq C \\leq N\n\nThe length of S is N.\n\nEach character of S is o or x.\n\nTakahashi can choose his workdays so that the conditions in Problem Statement are satisfied.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K C\nS\n\nOutput\n\nPrint all days on which Takahashi is bound to work in ascending order, one per line.\n\nSample Input 1\n\n11 3 2\nooxxxoxxxoo\n\nSample Output 1\n\n6\n\nTakahashi is going to work on 3 days out of the 11 days. After working for a day, he will refrain from working on the subsequent 2 days.\n\nThere are four possible choices for his workdays: Day 1,6,10, Day 1,6,11, Day 2,6,10, and Day 2,6,11.\n\nThus, he is bound to work on Day 6.\n\nSample Input 2\n\n5 2 3\nooxoo\n\nSample Output 2\n\n1\n5\n\nThere is only one possible choice for his workdays: Day 1,5.\n\nSample Input 3\n\n5 1 0\nooooo\n\nSample Output 3\n\nThere may be no days on which he is bound to work.\n\nSample Input 4\n\n16 4 3\nooxxoxoxxxoxoxxo\n\nSample Output 4\n\n11\n16", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2088, "cpu_time_ms": 271, "memory_kb": 29300}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s939788986", "group_id": "codeNet:p02722", "input_text": "#include<bits/stdc++.h>\n#define ll long long int\n#define ld long double\n#define inf LLONG_MAX>>2\n#define MAX 1000000\n#define mod 1000000007\n#define pb push_back\n#define f(i,a,n,x) for ((i)=(a);(i)<(n);(i)+=(x))\n#define fd(i,a,n,x) for ((i)=(a);(i)>=(n);(i)-=(x))\n#define fi first\n#define se second\n#define mk make_pair\n#define pi pair\n#define vt vector\n#define ms multiset\n#define is insert\nusing namespace std;\nvoid read(vt<ll> &a,ll n){ll i,temp;f(i,0,n,1){cin>>temp;a.pb(temp);}}\nll fa[MAX];\nll power(ll p,ll q){\n    ll res=1;\n    p%=mod;\n    while(q){\n        if (q&1)\n            res=(res*p)%mod;\n        q>>=1;\n        p=(p*p)%mod;\n    }\n    return res;\n}\nll fact(ll n){\n    if (n<=1)\n        return fa[n]=1;\n    if (fa[n])\n        return fa[n];\n    return fa[n]=(n*fact(n-1))%mod;\n}\nll ncr(ll n,ll r){\n    if (!r)\n        return 1;\n    return (((fact(n)*power(fact(n-r),mod-2))%mod)*power(fact(r),mod-2))%mod;\n}\nvoid solve(){\n    ll n,i,n1,count=0;\n    vt<ll> a;\n    cin>>n;\n    if (n==2){\n        cout<<1<<endl;\n        return;\n    }\n    n1=n;\n    for (i=2;i*i<=(n-1);i++)\n        if (!((n-1)%i))\n            if ((n-1)/i==i)\n                count++;\n            else\n                count+=2;\n    count++;\n    for (i=2;i*i<=n;i++)\n        if (!(n%i))\n            if (n/i==i)\n                a.pb(i);\n            else{\n                a.pb(i);\n                a.pb(n/i);\n            }\n    a.pb(n);\n    f(i,0,a.size(),1){\n        n1=n;\n        while(!(n1%a[i]))\n            n1/=a[i];\n        if (n1%a[i]==1)\n            count++;\n    }\n    cout<<count<<endl;\n}\nint main(){\n    ios_base::sync_with_stdio(false);\n    cin.tie(NULL);\n    cout.tie(NULL);\n    ll t=1;\n    //cin>>t;\n    while(t--)\n        solve();\n    return 0;\n}", "language": "C++", "metadata": {"date": 1595917262, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02722.html", "problem_id": "p02722", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02722/input.txt", "sample_output_relpath": "derived/input_output/data/p02722/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02722/C++/s939788986.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s939788986", "user_id": "u020278929"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include<bits/stdc++.h>\n#define ll long long int\n#define ld long double\n#define inf LLONG_MAX>>2\n#define MAX 1000000\n#define mod 1000000007\n#define pb push_back\n#define f(i,a,n,x) for ((i)=(a);(i)<(n);(i)+=(x))\n#define fd(i,a,n,x) for ((i)=(a);(i)>=(n);(i)-=(x))\n#define fi first\n#define se second\n#define mk make_pair\n#define pi pair\n#define vt vector\n#define ms multiset\n#define is insert\nusing namespace std;\nvoid read(vt<ll> &a,ll n){ll i,temp;f(i,0,n,1){cin>>temp;a.pb(temp);}}\nll fa[MAX];\nll power(ll p,ll q){\n    ll res=1;\n    p%=mod;\n    while(q){\n        if (q&1)\n            res=(res*p)%mod;\n        q>>=1;\n        p=(p*p)%mod;\n    }\n    return res;\n}\nll fact(ll n){\n    if (n<=1)\n        return fa[n]=1;\n    if (fa[n])\n        return fa[n];\n    return fa[n]=(n*fact(n-1))%mod;\n}\nll ncr(ll n,ll r){\n    if (!r)\n        return 1;\n    return (((fact(n)*power(fact(n-r),mod-2))%mod)*power(fact(r),mod-2))%mod;\n}\nvoid solve(){\n    ll n,i,n1,count=0;\n    vt<ll> a;\n    cin>>n;\n    if (n==2){\n        cout<<1<<endl;\n        return;\n    }\n    n1=n;\n    for (i=2;i*i<=(n-1);i++)\n        if (!((n-1)%i))\n            if ((n-1)/i==i)\n                count++;\n            else\n                count+=2;\n    count++;\n    for (i=2;i*i<=n;i++)\n        if (!(n%i))\n            if (n/i==i)\n                a.pb(i);\n            else{\n                a.pb(i);\n                a.pb(n/i);\n            }\n    a.pb(n);\n    f(i,0,a.size(),1){\n        n1=n;\n        while(!(n1%a[i]))\n            n1/=a[i];\n        if (n1%a[i]==1)\n            count++;\n    }\n    cout<<count<<endl;\n}\nint main(){\n    ios_base::sync_with_stdio(false);\n    cin.tie(NULL);\n    cout.tie(NULL);\n    ll t=1;\n    //cin>>t;\n    while(t--)\n        solve();\n    return 0;\n}", "problem_context": "Score : 600 points\n\nProblem Statement\n\nGiven is a positive integer N.\n\nWe will choose an integer K between 2 and N (inclusive), then we will repeat the operation below until N becomes less than K.\n\nOperation: if K divides N, replace N with N/K; otherwise, replace N with N-K.\n\nIn how many choices of K will N become 1 in the end?\n\nConstraints\n\n2 \\leq N \\leq 10^{12}\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the number of choices of K in which N becomes 1 in the end.\n\nSample Input 1\n\n6\n\nSample Output 1\n\n3\n\nThere are three choices of K in which N becomes 1 in the end: 2, 5, and 6.\n\nIn each of these choices, N will change as follows:\n\nWhen K=2: 6 \\to 3 \\to 1\n\nWhen K=5: 6 \\to 1\n\nWhen K=6: 6 \\to 1\n\nSample Input 2\n\n3141\n\nSample Output 2\n\n13\n\nSample Input 3\n\n314159265358\n\nSample Output 3\n\n9", "sample_input": "6\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02722", "source_text": "Score : 600 points\n\nProblem Statement\n\nGiven is a positive integer N.\n\nWe will choose an integer K between 2 and N (inclusive), then we will repeat the operation below until N becomes less than K.\n\nOperation: if K divides N, replace N with N/K; otherwise, replace N with N-K.\n\nIn how many choices of K will N become 1 in the end?\n\nConstraints\n\n2 \\leq N \\leq 10^{12}\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the number of choices of K in which N becomes 1 in the end.\n\nSample Input 1\n\n6\n\nSample Output 1\n\n3\n\nThere are three choices of K in which N becomes 1 in the end: 2, 5, and 6.\n\nIn each of these choices, N will change as follows:\n\nWhen K=2: 6 \\to 3 \\to 1\n\nWhen K=5: 6 \\to 1\n\nWhen K=6: 6 \\to 1\n\nSample Input 2\n\n3141\n\nSample Output 2\n\n13\n\nSample Input 3\n\n314159265358\n\nSample Output 3\n\n9", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1728, "cpu_time_ms": 32, "memory_kb": 3648}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s553483874", "group_id": "codeNet:p02722", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nusing ull=unsigned long long;\n#define mod 1000000007\n#define mod2 998244353 \n#define PI 3.14159265\n#define ll long long\n#define ld long double\n#define pi pair<ll,ll>\n#define pb push_back\n#define vi vector<ll>\n#define sz size()\n#define setbits(x)  __builtin_popcount(x)\n#define fi first\n#define se second\n#define lz length()\n#define all(x) (x).begin(),(x).end()\n#define scf(x) scanf(\"%lld\",&x)\n#define rep(i,n) for(ll i=0;i<n;i++)\nconst int INF = (int)1e9;\nconst ll IINF=1LL<<62;\nconst int maxn=10000005;\n\n//int divr[maxn];\n/**/\n/*void divisor()\n{for(int i=2;i<sqrt(maxn);i++)\n     {\n          if(!divr[i])\n          {\n               for(int j=i*i;j<maxn;j+=i)if(!divr[j])divr[j]=i;     \n          }\n     }\n     for(int i=1;i<maxn;i++)if(!divr[i])divr[i]=i;\n}*/\n \n/*const int N=1000005;\nll n;\nstruct line {\n    long long m, c;\n    long long eval(long long x) { return m * x + c; }\n    long double intersectX(line l) { return (long double) (c - l.c) / (l.m - m); }\n};\nvector<pair<pi,ll>> rect;\ndeque<line> dq;\n*/\n/*int find(int a){\n     if(a==par[a])return a;\n     return par[a]=find(par[a]);\n}\nvoid unite(int a,int b){\n     a=find(a),b=find(b);\n     if(a==b)return ;\n     par[b]=a;\n}\nll modexpo(ll a,ll b)\n{\n     ll ans=1LL;\n     while(b>0)\n     {\n          if(b&1)ans=(ans*a)%mod;\n          a=(a*a)%mod;\n          b>>=1;\n     }\n     return ans;\n}\n*/\nint main(){\n    ll n;\n    cin>>n;\n    int res=0;\n    ll m=n-1;\n    for(ll i=1LL;i<=sqrt(n);i++){\n              if(n%i==0){\n                   ll t=n,d=i;\n                   if(i>1LL){\n                   while(t%d==0)t/=d;\n                   if(t%d==1)res++;\n                   } \n                   d=n/i;\n                   t=n;\n                   if(1LL*i*i!=n){\n                        while(t%d==0)t/=d;\n                        if(t%d==1)res++;\n                   }\n                   \n                   \n              }\n\n    }\n    for(int i=1LL;i<=sqrt(m);i++){\n         if((m)%i==0){\n              if(i>1LL)res++;\n              if(1LL*i*i!=m)res++;\n         }\n    }\n    cout<<res;\n}\n \n \n \n \n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n", "language": "C++", "metadata": {"date": 1593753956, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02722.html", "problem_id": "p02722", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02722/input.txt", "sample_output_relpath": "derived/input_output/data/p02722/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02722/C++/s553483874.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s553483874", "user_id": "u856095980"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nusing ull=unsigned long long;\n#define mod 1000000007\n#define mod2 998244353 \n#define PI 3.14159265\n#define ll long long\n#define ld long double\n#define pi pair<ll,ll>\n#define pb push_back\n#define vi vector<ll>\n#define sz size()\n#define setbits(x)  __builtin_popcount(x)\n#define fi first\n#define se second\n#define lz length()\n#define all(x) (x).begin(),(x).end()\n#define scf(x) scanf(\"%lld\",&x)\n#define rep(i,n) for(ll i=0;i<n;i++)\nconst int INF = (int)1e9;\nconst ll IINF=1LL<<62;\nconst int maxn=10000005;\n\n//int divr[maxn];\n/**/\n/*void divisor()\n{for(int i=2;i<sqrt(maxn);i++)\n     {\n          if(!divr[i])\n          {\n               for(int j=i*i;j<maxn;j+=i)if(!divr[j])divr[j]=i;     \n          }\n     }\n     for(int i=1;i<maxn;i++)if(!divr[i])divr[i]=i;\n}*/\n \n/*const int N=1000005;\nll n;\nstruct line {\n    long long m, c;\n    long long eval(long long x) { return m * x + c; }\n    long double intersectX(line l) { return (long double) (c - l.c) / (l.m - m); }\n};\nvector<pair<pi,ll>> rect;\ndeque<line> dq;\n*/\n/*int find(int a){\n     if(a==par[a])return a;\n     return par[a]=find(par[a]);\n}\nvoid unite(int a,int b){\n     a=find(a),b=find(b);\n     if(a==b)return ;\n     par[b]=a;\n}\nll modexpo(ll a,ll b)\n{\n     ll ans=1LL;\n     while(b>0)\n     {\n          if(b&1)ans=(ans*a)%mod;\n          a=(a*a)%mod;\n          b>>=1;\n     }\n     return ans;\n}\n*/\nint main(){\n    ll n;\n    cin>>n;\n    int res=0;\n    ll m=n-1;\n    for(ll i=1LL;i<=sqrt(n);i++){\n              if(n%i==0){\n                   ll t=n,d=i;\n                   if(i>1LL){\n                   while(t%d==0)t/=d;\n                   if(t%d==1)res++;\n                   } \n                   d=n/i;\n                   t=n;\n                   if(1LL*i*i!=n){\n                        while(t%d==0)t/=d;\n                        if(t%d==1)res++;\n                   }\n                   \n                   \n              }\n\n    }\n    for(int i=1LL;i<=sqrt(m);i++){\n         if((m)%i==0){\n              if(i>1LL)res++;\n              if(1LL*i*i!=m)res++;\n         }\n    }\n    cout<<res;\n}\n \n \n \n \n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n", "problem_context": "Score : 600 points\n\nProblem Statement\n\nGiven is a positive integer N.\n\nWe will choose an integer K between 2 and N (inclusive), then we will repeat the operation below until N becomes less than K.\n\nOperation: if K divides N, replace N with N/K; otherwise, replace N with N-K.\n\nIn how many choices of K will N become 1 in the end?\n\nConstraints\n\n2 \\leq N \\leq 10^{12}\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the number of choices of K in which N becomes 1 in the end.\n\nSample Input 1\n\n6\n\nSample Output 1\n\n3\n\nThere are three choices of K in which N becomes 1 in the end: 2, 5, and 6.\n\nIn each of these choices, N will change as follows:\n\nWhen K=2: 6 \\to 3 \\to 1\n\nWhen K=5: 6 \\to 1\n\nWhen K=6: 6 \\to 1\n\nSample Input 2\n\n3141\n\nSample Output 2\n\n13\n\nSample Input 3\n\n314159265358\n\nSample Output 3\n\n9", "sample_input": "6\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02722", "source_text": "Score : 600 points\n\nProblem Statement\n\nGiven is a positive integer N.\n\nWe will choose an integer K between 2 and N (inclusive), then we will repeat the operation below until N becomes less than K.\n\nOperation: if K divides N, replace N with N/K; otherwise, replace N with N-K.\n\nIn how many choices of K will N become 1 in the end?\n\nConstraints\n\n2 \\leq N \\leq 10^{12}\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the number of choices of K in which N becomes 1 in the end.\n\nSample Input 1\n\n6\n\nSample Output 1\n\n3\n\nThere are three choices of K in which N becomes 1 in the end: 2, 5, and 6.\n\nIn each of these choices, N will change as follows:\n\nWhen K=2: 6 \\to 3 \\to 1\n\nWhen K=5: 6 \\to 1\n\nWhen K=6: 6 \\to 1\n\nSample Input 2\n\n3141\n\nSample Output 2\n\n13\n\nSample Input 3\n\n314159265358\n\nSample Output 3\n\n9", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2116, "cpu_time_ms": 33, "memory_kb": 3676}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s404197230", "group_id": "codeNet:p02723", "input_text": "#include <bits/stdc++.h>\n \n#define IOS ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);\n#define endl \"\\n\"\n#define rep(i, n) for(int i = 0; i < (int)(n); i++)\n#define rrep(i, n) for(int i = ((int)(n)-1); i >= 0; i--)\n#define all(x) (x).begin(),(x).end()\n \nusing namespace std;\nusing ll = long long;\n \ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }\n\nstruct edge { int to; int cost; };\n \ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\ntypedef pair<int,int> P;\n \nconst int INF = 1e9;\nconst int MOD = 1e9+7;\nconst double EPS = 1.0e-10;\nconst double PI = acos(-1.0);\n \nconst int mx4[] = {0,1,0,-1};\nconst int my4[] = {1,0,-1,0};\nconst int mx8[] = {0,1,1,1,0,-1,-1,-1};\nconst int my8[] = {1,1,0,-1,-1,-1,0,1};\n\nint main() {\n\tstring s;\n\tcin >> s;\n\tcout << (s[2] == s[3] && s[4] == s[5] ? \"Yes\" : \"No\") << endl;\t\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1585538649, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02723.html", "problem_id": "p02723", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02723/input.txt", "sample_output_relpath": "derived/input_output/data/p02723/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02723/C++/s404197230.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s404197230", "user_id": "u216772548"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <bits/stdc++.h>\n \n#define IOS ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);\n#define endl \"\\n\"\n#define rep(i, n) for(int i = 0; i < (int)(n); i++)\n#define rrep(i, n) for(int i = ((int)(n)-1); i >= 0; i--)\n#define all(x) (x).begin(),(x).end()\n \nusing namespace std;\nusing ll = long long;\n \ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }\n\nstruct edge { int to; int cost; };\n \ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\ntypedef pair<int,int> P;\n \nconst int INF = 1e9;\nconst int MOD = 1e9+7;\nconst double EPS = 1.0e-10;\nconst double PI = acos(-1.0);\n \nconst int mx4[] = {0,1,0,-1};\nconst int my4[] = {1,0,-1,0};\nconst int mx8[] = {0,1,1,1,0,-1,-1,-1};\nconst int my8[] = {1,1,0,-1,-1,-1,0,1};\n\nint main() {\n\tstring s;\n\tcin >> s;\n\tcout << (s[2] == s[3] && s[4] == s[5] ? \"Yes\" : \"No\") << endl;\t\n\treturn 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nA string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.\n\nGiven a string S, determine whether it is coffee-like.\n\nConstraints\n\nS is a string of length 6 consisting of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nIf S is coffee-like, print Yes; otherwise, print No.\n\nSample Input 1\n\nsippuu\n\nSample Output 1\n\nYes\n\nIn sippuu, the 3-rd and 4-th characters are equal, and the 5-th and 6-th characters are also equal.\n\nSample Input 2\n\niphone\n\nSample Output 2\n\nNo\n\nSample Input 3\n\ncoffee\n\nSample Output 3\n\nYes", "sample_input": "sippuu\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p02723", "source_text": "Score : 100 points\n\nProblem Statement\n\nA string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.\n\nGiven a string S, determine whether it is coffee-like.\n\nConstraints\n\nS is a string of length 6 consisting of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nIf S is coffee-like, print Yes; otherwise, print No.\n\nSample Input 1\n\nsippuu\n\nSample Output 1\n\nYes\n\nIn sippuu, the 3-rd and 4-th characters are equal, and the 5-th and 6-th characters are also equal.\n\nSample Input 2\n\niphone\n\nSample Output 2\n\nNo\n\nSample Input 3\n\ncoffee\n\nSample Output 3\n\nYes", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 947, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s510517192", "group_id": "codeNet:p02723", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long\nint main()\n{\n    string s ;\n    cin>>s;\n    if(s[2]==s[3]&&s[4]==s[5])\n        cout<<\"Yes\"<<\"\\n\";\n    else\n        cout<<\"No\"<<\"\\n\";\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1585443744, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02723.html", "problem_id": "p02723", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02723/input.txt", "sample_output_relpath": "derived/input_output/data/p02723/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02723/C++/s510517192.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s510517192", "user_id": "u615662336"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long\nint main()\n{\n    string s ;\n    cin>>s;\n    if(s[2]==s[3]&&s[4]==s[5])\n        cout<<\"Yes\"<<\"\\n\";\n    else\n        cout<<\"No\"<<\"\\n\";\n    return 0;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nA string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.\n\nGiven a string S, determine whether it is coffee-like.\n\nConstraints\n\nS is a string of length 6 consisting of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nIf S is coffee-like, print Yes; otherwise, print No.\n\nSample Input 1\n\nsippuu\n\nSample Output 1\n\nYes\n\nIn sippuu, the 3-rd and 4-th characters are equal, and the 5-th and 6-th characters are also equal.\n\nSample Input 2\n\niphone\n\nSample Output 2\n\nNo\n\nSample Input 3\n\ncoffee\n\nSample Output 3\n\nYes", "sample_input": "sippuu\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p02723", "source_text": "Score : 100 points\n\nProblem Statement\n\nA string of length 6 consisting of lowercase English letters is said to be coffee-like if and only if its 3-rd and 4-th characters are equal and its 5-th and 6-th characters are also equal.\n\nGiven a string S, determine whether it is coffee-like.\n\nConstraints\n\nS is a string of length 6 consisting of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nIf S is coffee-like, print Yes; otherwise, print No.\n\nSample Input 1\n\nsippuu\n\nSample Output 1\n\nYes\n\nIn sippuu, the 3-rd and 4-th characters are equal, and the 5-th and 6-th characters are also equal.\n\nSample Input 2\n\niphone\n\nSample Output 2\n\nNo\n\nSample Input 3\n\ncoffee\n\nSample Output 3\n\nYes", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 215, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s243028638", "group_id": "codeNet:p02724", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n\tios_base::sync_with_stdio(false);\n    long int x;cin>>x;\n  \tlong long int ans=(x/500)*1000;\n  \tx%=500;\n  \tans+=5*(x/5);\n  \tcout<<ans<<\"\\n\";\n  return 0;\n}", "language": "C++", "metadata": {"date": 1585466103, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02724.html", "problem_id": "p02724", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02724/input.txt", "sample_output_relpath": "derived/input_output/data/p02724/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02724/C++/s243028638.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s243028638", "user_id": "u511724424"}, "prompt_components": {"gold_output": "2020\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n\tios_base::sync_with_stdio(false);\n    long int x;cin>>x;\n  \tlong long int ans=(x/500)*1000;\n  \tx%=500;\n  \tans+=5*(x/5);\n  \tcout<<ans<<\"\\n\";\n  return 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nTakahashi loves gold coins. He gains 1000 happiness points for each 500-yen coin he has and gains 5 happiness points for each 5-yen coin he has. (Yen is the currency of Japan.)\n\nTakahashi has X yen. If he exchanges his money so that he will gain the most happiness points, how many happiness points will he earn?\n\n(We assume that there are six kinds of coins available: 500-yen, 100-yen, 50-yen, 10-yen, 5-yen, and 1-yen coins.)\n\nConstraints\n\n0 \\leq X \\leq 10^9\n\nX is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint the maximum number of happiness points that can be earned.\n\nSample Input 1\n\n1024\n\nSample Output 1\n\n2020\n\nBy exchanging his money so that he gets two 500-yen coins and four 5-yen coins, he gains 2020 happiness points, which is the maximum number of happiness points that can be earned.\n\nSample Input 2\n\n0\n\nSample Output 2\n\n0\n\nHe is penniless - or yenless.\n\nSample Input 3\n\n1000000000\n\nSample Output 3\n\n2000000000\n\nHe is a billionaire - in yen.", "sample_input": "1024\n"}, "reference_outputs": ["2020\n"], "source_document_id": "p02724", "source_text": "Score : 200 points\n\nProblem Statement\n\nTakahashi loves gold coins. He gains 1000 happiness points for each 500-yen coin he has and gains 5 happiness points for each 5-yen coin he has. (Yen is the currency of Japan.)\n\nTakahashi has X yen. If he exchanges his money so that he will gain the most happiness points, how many happiness points will he earn?\n\n(We assume that there are six kinds of coins available: 500-yen, 100-yen, 50-yen, 10-yen, 5-yen, and 1-yen coins.)\n\nConstraints\n\n0 \\leq X \\leq 10^9\n\nX is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint the maximum number of happiness points that can be earned.\n\nSample Input 1\n\n1024\n\nSample Output 1\n\n2020\n\nBy exchanging his money so that he gets two 500-yen coins and four 5-yen coins, he gains 2020 happiness points, which is the maximum number of happiness points that can be earned.\n\nSample Input 2\n\n0\n\nSample Output 2\n\n0\n\nHe is penniless - or yenless.\n\nSample Input 3\n\n1000000000\n\nSample Output 3\n\n2000000000\n\nHe is a billionaire - in yen.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 211, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s027627168", "group_id": "codeNet:p02724", "input_text": "//#pragma GCC optimize(\"O3\")\n//#pragma GCC target(\"avx\")\n\n#include <algorithm>\n#include <cmath>\n#include <functional>\n#include <iomanip>\n#include <iostream>\n#include <iterator>\n#include <list>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <random>\n#include <set>\n#include <sstream>\n#include <string>\n#include <type_traits>\n#include <unordered_map>\n#include <unordered_set>\n#include <utility>\n#include <vector>\n\nusing namespace std;\n\n// Types\nusing ll = long long int;\nusing ld = long double;\nusing str = string;\ntemplate <class T> using u_set = unordered_set<T>;\ntemplate <class K, class V> using u_map = unordered_map<K, V>;\ntemplate <class V> using graph = u_map<V, u_set<V>>;\n\nnamespace io {\n// Input\nusing IS = istream;\nIS &in(IS &);\nIS &in(IS &i) { return i; }\ntemplate <class T, class... Ts> IS &in(IS &i, T &a, Ts &... as) {\n  return in(i >> a, as...);\n}\ntemplate <class V> IS &operator>>(IS &i, vector<V> &a) {\n  for_each(a.begin(), a.end(), [&i](auto &e) { i >> e; });\n  return i;\n}\ntemplate <class F, class S> IS &operator>>(IS &i, pair<F, S> &p) {\n  return in(i, p.first, p.second);\n}\ntemplate <class... Ts, size_t... I>\nIS &tuple_in(IS &i, tuple<Ts...> &t, index_sequence<I...>) {\n  return in(i, get<I>(t)...);\n}\ntemplate <class... Ts> IS &operator>>(IS &i, tuple<Ts...> &t) {\n  return tuple_in(i, t, make_index_sequence<sizeof...(Ts)>());\n}\n// Output\nusing OS = ostream;\nOS &out(OS &o) { return o << endl; }\ntemplate <class T> OS &out(OS &o, T const &a) { return o << a << endl; }\ntemplate <class T, class... Ts> OS &out(OS &o, T const &a, Ts const &... as) {\n  return out(o << a << \" \", as...);\n}\ntemplate <class F, class S> OS &operator<<(OS &o, pair<F, S> const &p) {\n  return o << p.first << \":\" << p.second;\n}\ntemplate <class... Ts> OS &args_out(OS &o, Ts const &... ts);\nOS &args_out(OS &o) { return o; }\ntemplate <class T> OS &args_out(OS &o, T const &t) { return o << t; }\ntemplate <class T0, class T1, class... Ts>\nOS &args_out(OS &o, T0 const &t0, T1 const &t1, Ts const &... ts) {\n  return args_out(o << t0 << \",\", t1, ts...);\n}\ntemplate <class... Ts, size_t... I>\nOS &tuple_out(OS &o, tuple<Ts...> const &t, index_sequence<I...>) {\n  return args_out(o, get<I>(t)...);\n}\ntemplate <class... Ts> OS &operator<<(OS &o, tuple<Ts...> const &t) {\n  return tuple_out(o << \"(\", t, make_index_sequence<sizeof...(Ts)>()) << \")\";\n}\ntemplate <class T> struct Joiner {\n  str const pre;\n  str const post;\n  str const delim;\n  vector<T> const container;\n  Joiner(vector<T> v, str const &delim, str const &pre, str const &post)\n      : pre(pre), post(post), delim(delim), container(v) {}\n};\ntemplate <class T> OS &operator<<(OS &o, Joiner<T> const &joiner) {\n  auto itr = joiner.container.begin();\n  auto end = joiner.container.end();\n  o << joiner.pre;\n  if (itr != end)\n    o << *(itr++);\n  while (itr != end)\n    o << joiner.delim << *(itr++);\n  return o << joiner.post;\n}\ntemplate <class Itr, class T = typename iterator_traits<Itr>::value_type>\nJoiner<T> join(Itr b, Itr e, str const &delim = \"\"s, str const &pre = \"\"s,\n               str const &post = \"\"s) {\n  return Joiner<T>(vector<T>(b, e), delim, pre, post);\n}\ntemplate <\n    class C,\n    class T = typename iterator_traits<typename C::iterator>::value_type,\n    typename enable_if<!is_same<C, str>::value, nullptr_t>::type = nullptr>\nOS &operator<<(OS &o, C const &a) {\n  return o << join(a.begin(), a.end(), \",\", \"[\", \"]\");\n}\n} // namespace io\nauto input = [](auto &... a) { io::in(cin, a...); };\nauto print = [](auto const &... a) { io::out(cout, a...); };\n#ifdef JUMPAKU_DEBUG\nauto dump = [](auto const &... a) { io::out(cerr, a...); };\n#else\nauto dump = [](auto const &...) {};\n#endif\nusing io::join;\n\n// Hash\nnamespace hashcode {\ntemplate <class... Ts> uint64_t hash_args(uint64_t h, Ts const &... ts);\nuint64_t hash_args(uint64_t h) { return h; }\ntemplate <class T, class... Ts>\nuint64_t hash_args(uint64_t h, T const &t, Ts const &... ts) {\n  constexpr hash<T> hasher;\n  return hash_args(((h << 19) - h) ^ hasher(t), ts...);\n}\ntemplate <class... Ts, size_t... I>\nuint64_t hash_tuple(tuple<Ts...> const &t, index_sequence<I...>) {\n  return hash_args(17, get<I>(t)...);\n}\n} // namespace hashcode\nnamespace std {\ntemplate <class... Ts> struct hash<tuple<Ts...>> {\n  size_t operator()(tuple<Ts...> const &t) const {\n    uint64_t h = hashcode::hash_tuple(t, index_sequence_for<Ts...>());\n    return h ^ (h >> 32);\n  }\n};\n} // namespace std\n\n// Range\nnamespace ranges {\ntemplate <class T, class Itr> struct iterator_base {\n  using difference_type = ll;\n  using value_type = T;\n  using pointer = T *;\n  using reference = T &;\n  using iterator_category = random_access_iterator_tag;\n  ll i;\n  iterator_base(ll const &i = 0) : i(i) {}\n  bool operator==(Itr const &itr) const { return i == itr.i; }\n  bool operator!=(Itr const &itr) const { return i != itr.i; }\n  ll operator-(Itr const &itr) const { return i - itr.i; }\n  Itr operator++(int) { return with(i++); }\n  Itr operator--(int) { return with(i--); }\n  Itr operator+(ll const &n) const { return with(i + n); }\n  Itr operator-(ll const &n) const { return with(i - n); }\n  Itr &operator+=(ll const &n) {\n    i += n;\n    return self();\n  }\n  Itr &operator-=(ll const &n) { return self() += (-n); }\n  Itr &operator++() { return self() += 1; }\n  Itr &operator--() { return self() -= 1; }\n\nprotected:\n  virtual Itr with(ll i) const = 0;\n  virtual Itr &self() = 0;\n};\ntemplate <class T> struct seq_base {\n  ll const b;\n  ll const e;\n  seq_base(ll b, ll e) : b(b), e(e) {}\n  ll size() const { return e - b; }\n  bool empty() const { return size() == 0; }\n};\ntemplate <class T> struct seq : seq_base<T> {\n  struct iterator : iterator_base<T, iterator> {\n    seq<T> const &s;\n    iterator(seq<T> const &s, ll const &i)\n        : iterator_base<T, iterator>(i), s(s) {}\n    iterator with(ll i) const override { return iterator(s, i); }\n    iterator &self() override { return *this; }\n    T operator*() const { return s[this->i]; }\n    iterator &operator=(iterator const &itr) {\n      this->i = itr.i;\n      return *this;\n    }\n  };\n  function<T(ll)> const f;\n  seq(ll b, ll e, function<T(ll)> const &f) : seq_base<T>(b, e), f(f) {}\n  iterator begin() const { return iterator(*this, 0); }\n  iterator end() const { return iterator(*this, this->size()); }\n  T operator[](ll i) const { return f(i + this->b); }\n};\nstruct range : seq_base<ll> {\n  struct iterator : iterator_base<ll, iterator> {\n    iterator(ll const &i) : iterator_base<ll, iterator>(i) {}\n    iterator with(ll i) const override { return iterator(i); }\n    iterator &self() override { return *this; }\n    ll operator*() const { return i; }\n  };\n  range(ll n) : range(0LL, n) {}\n  range(ll b, ll e) : seq_base<ll>(b, e) {}\n  iterator begin() const { return iterator(b); }\n  iterator end() const { return iterator(e); }\n  ll operator[](ll i) const { return i + b; }\n};\n} // namespace ranges\nusing range = ranges::range;\nrange::iterator end(ll i) { return range::iterator(i); }\nrange::iterator begin(ll i) { return range::iterator(i); }\ntemplate <class F> auto seq(ll b, ll e, F const &f) {\n  using T = decltype(f(declval<ll>()));\n  return ranges::seq<T>(b, e, f);\n}\ntemplate <class F> auto seq(ll n, F const &f) { return seq(0, n, f); }\ntemplate <class T = ll> vector<T> vec(size_t n, T const &init = T()) {\n  return vector<T>(n, init);\n}\n\nll gcd(ll p, ll q) { return (q == 0) ? p : gcd(q, p % q); }\nll lcm(ll p, ll q) { return p / gcd(q, p) * q; }\nbool odd(ll n) { return n & 1; }\nbool even(ll n) { return !odd(n); }\n\nconstexpr ll MOD = 1e9 + 7;\n\nvoid solve();\nint main() {\n  ll t = 1;\n  /** input(t); /**/\n  for ([[maybe_unused]] auto &&i : range(t)) {\n    solve();\n  }\n}\n\nvoid solve() {\n  ll X;\n  input(X);\n  ll a = X / 500;\n  ll b = (X % 500) / 5;\n  print(1000 * a + 5 * b);\n}\n", "language": "C++", "metadata": {"date": 1585443866, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02724.html", "problem_id": "p02724", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02724/input.txt", "sample_output_relpath": "derived/input_output/data/p02724/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02724/C++/s027627168.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s027627168", "user_id": "u465699806"}, "prompt_components": {"gold_output": "2020\n", "input_to_evaluate": "//#pragma GCC optimize(\"O3\")\n//#pragma GCC target(\"avx\")\n\n#include <algorithm>\n#include <cmath>\n#include <functional>\n#include <iomanip>\n#include <iostream>\n#include <iterator>\n#include <list>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <random>\n#include <set>\n#include <sstream>\n#include <string>\n#include <type_traits>\n#include <unordered_map>\n#include <unordered_set>\n#include <utility>\n#include <vector>\n\nusing namespace std;\n\n// Types\nusing ll = long long int;\nusing ld = long double;\nusing str = string;\ntemplate <class T> using u_set = unordered_set<T>;\ntemplate <class K, class V> using u_map = unordered_map<K, V>;\ntemplate <class V> using graph = u_map<V, u_set<V>>;\n\nnamespace io {\n// Input\nusing IS = istream;\nIS &in(IS &);\nIS &in(IS &i) { return i; }\ntemplate <class T, class... Ts> IS &in(IS &i, T &a, Ts &... as) {\n  return in(i >> a, as...);\n}\ntemplate <class V> IS &operator>>(IS &i, vector<V> &a) {\n  for_each(a.begin(), a.end(), [&i](auto &e) { i >> e; });\n  return i;\n}\ntemplate <class F, class S> IS &operator>>(IS &i, pair<F, S> &p) {\n  return in(i, p.first, p.second);\n}\ntemplate <class... Ts, size_t... I>\nIS &tuple_in(IS &i, tuple<Ts...> &t, index_sequence<I...>) {\n  return in(i, get<I>(t)...);\n}\ntemplate <class... Ts> IS &operator>>(IS &i, tuple<Ts...> &t) {\n  return tuple_in(i, t, make_index_sequence<sizeof...(Ts)>());\n}\n// Output\nusing OS = ostream;\nOS &out(OS &o) { return o << endl; }\ntemplate <class T> OS &out(OS &o, T const &a) { return o << a << endl; }\ntemplate <class T, class... Ts> OS &out(OS &o, T const &a, Ts const &... as) {\n  return out(o << a << \" \", as...);\n}\ntemplate <class F, class S> OS &operator<<(OS &o, pair<F, S> const &p) {\n  return o << p.first << \":\" << p.second;\n}\ntemplate <class... Ts> OS &args_out(OS &o, Ts const &... ts);\nOS &args_out(OS &o) { return o; }\ntemplate <class T> OS &args_out(OS &o, T const &t) { return o << t; }\ntemplate <class T0, class T1, class... Ts>\nOS &args_out(OS &o, T0 const &t0, T1 const &t1, Ts const &... ts) {\n  return args_out(o << t0 << \",\", t1, ts...);\n}\ntemplate <class... Ts, size_t... I>\nOS &tuple_out(OS &o, tuple<Ts...> const &t, index_sequence<I...>) {\n  return args_out(o, get<I>(t)...);\n}\ntemplate <class... Ts> OS &operator<<(OS &o, tuple<Ts...> const &t) {\n  return tuple_out(o << \"(\", t, make_index_sequence<sizeof...(Ts)>()) << \")\";\n}\ntemplate <class T> struct Joiner {\n  str const pre;\n  str const post;\n  str const delim;\n  vector<T> const container;\n  Joiner(vector<T> v, str const &delim, str const &pre, str const &post)\n      : pre(pre), post(post), delim(delim), container(v) {}\n};\ntemplate <class T> OS &operator<<(OS &o, Joiner<T> const &joiner) {\n  auto itr = joiner.container.begin();\n  auto end = joiner.container.end();\n  o << joiner.pre;\n  if (itr != end)\n    o << *(itr++);\n  while (itr != end)\n    o << joiner.delim << *(itr++);\n  return o << joiner.post;\n}\ntemplate <class Itr, class T = typename iterator_traits<Itr>::value_type>\nJoiner<T> join(Itr b, Itr e, str const &delim = \"\"s, str const &pre = \"\"s,\n               str const &post = \"\"s) {\n  return Joiner<T>(vector<T>(b, e), delim, pre, post);\n}\ntemplate <\n    class C,\n    class T = typename iterator_traits<typename C::iterator>::value_type,\n    typename enable_if<!is_same<C, str>::value, nullptr_t>::type = nullptr>\nOS &operator<<(OS &o, C const &a) {\n  return o << join(a.begin(), a.end(), \",\", \"[\", \"]\");\n}\n} // namespace io\nauto input = [](auto &... a) { io::in(cin, a...); };\nauto print = [](auto const &... a) { io::out(cout, a...); };\n#ifdef JUMPAKU_DEBUG\nauto dump = [](auto const &... a) { io::out(cerr, a...); };\n#else\nauto dump = [](auto const &...) {};\n#endif\nusing io::join;\n\n// Hash\nnamespace hashcode {\ntemplate <class... Ts> uint64_t hash_args(uint64_t h, Ts const &... ts);\nuint64_t hash_args(uint64_t h) { return h; }\ntemplate <class T, class... Ts>\nuint64_t hash_args(uint64_t h, T const &t, Ts const &... ts) {\n  constexpr hash<T> hasher;\n  return hash_args(((h << 19) - h) ^ hasher(t), ts...);\n}\ntemplate <class... Ts, size_t... I>\nuint64_t hash_tuple(tuple<Ts...> const &t, index_sequence<I...>) {\n  return hash_args(17, get<I>(t)...);\n}\n} // namespace hashcode\nnamespace std {\ntemplate <class... Ts> struct hash<tuple<Ts...>> {\n  size_t operator()(tuple<Ts...> const &t) const {\n    uint64_t h = hashcode::hash_tuple(t, index_sequence_for<Ts...>());\n    return h ^ (h >> 32);\n  }\n};\n} // namespace std\n\n// Range\nnamespace ranges {\ntemplate <class T, class Itr> struct iterator_base {\n  using difference_type = ll;\n  using value_type = T;\n  using pointer = T *;\n  using reference = T &;\n  using iterator_category = random_access_iterator_tag;\n  ll i;\n  iterator_base(ll const &i = 0) : i(i) {}\n  bool operator==(Itr const &itr) const { return i == itr.i; }\n  bool operator!=(Itr const &itr) const { return i != itr.i; }\n  ll operator-(Itr const &itr) const { return i - itr.i; }\n  Itr operator++(int) { return with(i++); }\n  Itr operator--(int) { return with(i--); }\n  Itr operator+(ll const &n) const { return with(i + n); }\n  Itr operator-(ll const &n) const { return with(i - n); }\n  Itr &operator+=(ll const &n) {\n    i += n;\n    return self();\n  }\n  Itr &operator-=(ll const &n) { return self() += (-n); }\n  Itr &operator++() { return self() += 1; }\n  Itr &operator--() { return self() -= 1; }\n\nprotected:\n  virtual Itr with(ll i) const = 0;\n  virtual Itr &self() = 0;\n};\ntemplate <class T> struct seq_base {\n  ll const b;\n  ll const e;\n  seq_base(ll b, ll e) : b(b), e(e) {}\n  ll size() const { return e - b; }\n  bool empty() const { return size() == 0; }\n};\ntemplate <class T> struct seq : seq_base<T> {\n  struct iterator : iterator_base<T, iterator> {\n    seq<T> const &s;\n    iterator(seq<T> const &s, ll const &i)\n        : iterator_base<T, iterator>(i), s(s) {}\n    iterator with(ll i) const override { return iterator(s, i); }\n    iterator &self() override { return *this; }\n    T operator*() const { return s[this->i]; }\n    iterator &operator=(iterator const &itr) {\n      this->i = itr.i;\n      return *this;\n    }\n  };\n  function<T(ll)> const f;\n  seq(ll b, ll e, function<T(ll)> const &f) : seq_base<T>(b, e), f(f) {}\n  iterator begin() const { return iterator(*this, 0); }\n  iterator end() const { return iterator(*this, this->size()); }\n  T operator[](ll i) const { return f(i + this->b); }\n};\nstruct range : seq_base<ll> {\n  struct iterator : iterator_base<ll, iterator> {\n    iterator(ll const &i) : iterator_base<ll, iterator>(i) {}\n    iterator with(ll i) const override { return iterator(i); }\n    iterator &self() override { return *this; }\n    ll operator*() const { return i; }\n  };\n  range(ll n) : range(0LL, n) {}\n  range(ll b, ll e) : seq_base<ll>(b, e) {}\n  iterator begin() const { return iterator(b); }\n  iterator end() const { return iterator(e); }\n  ll operator[](ll i) const { return i + b; }\n};\n} // namespace ranges\nusing range = ranges::range;\nrange::iterator end(ll i) { return range::iterator(i); }\nrange::iterator begin(ll i) { return range::iterator(i); }\ntemplate <class F> auto seq(ll b, ll e, F const &f) {\n  using T = decltype(f(declval<ll>()));\n  return ranges::seq<T>(b, e, f);\n}\ntemplate <class F> auto seq(ll n, F const &f) { return seq(0, n, f); }\ntemplate <class T = ll> vector<T> vec(size_t n, T const &init = T()) {\n  return vector<T>(n, init);\n}\n\nll gcd(ll p, ll q) { return (q == 0) ? p : gcd(q, p % q); }\nll lcm(ll p, ll q) { return p / gcd(q, p) * q; }\nbool odd(ll n) { return n & 1; }\nbool even(ll n) { return !odd(n); }\n\nconstexpr ll MOD = 1e9 + 7;\n\nvoid solve();\nint main() {\n  ll t = 1;\n  /** input(t); /**/\n  for ([[maybe_unused]] auto &&i : range(t)) {\n    solve();\n  }\n}\n\nvoid solve() {\n  ll X;\n  input(X);\n  ll a = X / 500;\n  ll b = (X % 500) / 5;\n  print(1000 * a + 5 * b);\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nTakahashi loves gold coins. He gains 1000 happiness points for each 500-yen coin he has and gains 5 happiness points for each 5-yen coin he has. (Yen is the currency of Japan.)\n\nTakahashi has X yen. If he exchanges his money so that he will gain the most happiness points, how many happiness points will he earn?\n\n(We assume that there are six kinds of coins available: 500-yen, 100-yen, 50-yen, 10-yen, 5-yen, and 1-yen coins.)\n\nConstraints\n\n0 \\leq X \\leq 10^9\n\nX is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint the maximum number of happiness points that can be earned.\n\nSample Input 1\n\n1024\n\nSample Output 1\n\n2020\n\nBy exchanging his money so that he gets two 500-yen coins and four 5-yen coins, he gains 2020 happiness points, which is the maximum number of happiness points that can be earned.\n\nSample Input 2\n\n0\n\nSample Output 2\n\n0\n\nHe is penniless - or yenless.\n\nSample Input 3\n\n1000000000\n\nSample Output 3\n\n2000000000\n\nHe is a billionaire - in yen.", "sample_input": "1024\n"}, "reference_outputs": ["2020\n"], "source_document_id": "p02724", "source_text": "Score : 200 points\n\nProblem Statement\n\nTakahashi loves gold coins. He gains 1000 happiness points for each 500-yen coin he has and gains 5 happiness points for each 5-yen coin he has. (Yen is the currency of Japan.)\n\nTakahashi has X yen. If he exchanges his money so that he will gain the most happiness points, how many happiness points will he earn?\n\n(We assume that there are six kinds of coins available: 500-yen, 100-yen, 50-yen, 10-yen, 5-yen, and 1-yen coins.)\n\nConstraints\n\n0 \\leq X \\leq 10^9\n\nX is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint the maximum number of happiness points that can be earned.\n\nSample Input 1\n\n1024\n\nSample Output 1\n\n2020\n\nBy exchanging his money so that he gets two 500-yen coins and four 5-yen coins, he gains 2020 happiness points, which is the maximum number of happiness points that can be earned.\n\nSample Input 2\n\n0\n\nSample Output 2\n\n0\n\nHe is penniless - or yenless.\n\nSample Input 3\n\n1000000000\n\nSample Output 3\n\n2000000000\n\nHe is a billionaire - in yen.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 7767, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s547485135", "group_id": "codeNet:p02725", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n  int k,n;\n  cin>>k>>n;\n  vector<int> a(n);\n  for(int i=0; i<n; i++){\n    cin>>a.at(i);\n  }\n  int ans;\n  if((a.at(n-1)-a.at(1))>=20-a.at(n-1)+a.at(1)){\n    ans=a.at(1)+20-a.at(n-1);\n  }\n  else ans=a.at(n-1)-a.at(0);\n  \n  cout<<ans<<endl;\n}\n", "language": "C++", "metadata": {"date": 1597853495, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02725.html", "problem_id": "p02725", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02725/input.txt", "sample_output_relpath": "derived/input_output/data/p02725/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02725/C++/s547485135.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s547485135", "user_id": "u668010224"}, "prompt_components": {"gold_output": "10\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n  int k,n;\n  cin>>k>>n;\n  vector<int> a(n);\n  for(int i=0; i<n; i++){\n    cin>>a.at(i);\n  }\n  int ans;\n  if((a.at(n-1)-a.at(1))>=20-a.at(n-1)+a.at(1)){\n    ans=a.at(1)+20-a.at(n-1);\n  }\n  else ans=a.at(n-1)-a.at(0);\n  \n  cout<<ans<<endl;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere is a circular pond with a perimeter of K meters, and N houses around them.\n\nThe i-th house is built at a distance of A_i meters from the northmost point of the pond, measured clockwise around the pond.\n\nWhen traveling between these houses, you can only go around the pond.\n\nFind the minimum distance that needs to be traveled when you start at one of the houses and visit all the N houses.\n\nConstraints\n\n2 \\leq K \\leq 10^6\n\n2 \\leq N \\leq 2 \\times 10^5\n\n0 \\leq A_1 < ... < A_N < K\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nK N\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the minimum distance that needs to be traveled when you start at one of the houses and visit all the N houses.\n\nSample Input 1\n\n20 3\n5 10 15\n\nSample Output 1\n\n10\n\nIf you start at the 1-st house and go to the 2-nd and 3-rd houses in this order, the total distance traveled will be 10.\n\nSample Input 2\n\n20 3\n0 5 15\n\nSample Output 2\n\n10\n\nIf you start at the 2-nd house and go to the 1-st and 3-rd houses in this order, the total distance traveled will be 10.", "sample_input": "20 3\n5 10 15\n"}, "reference_outputs": ["10\n"], "source_document_id": "p02725", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere is a circular pond with a perimeter of K meters, and N houses around them.\n\nThe i-th house is built at a distance of A_i meters from the northmost point of the pond, measured clockwise around the pond.\n\nWhen traveling between these houses, you can only go around the pond.\n\nFind the minimum distance that needs to be traveled when you start at one of the houses and visit all the N houses.\n\nConstraints\n\n2 \\leq K \\leq 10^6\n\n2 \\leq N \\leq 2 \\times 10^5\n\n0 \\leq A_1 < ... < A_N < K\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nK N\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the minimum distance that needs to be traveled when you start at one of the houses and visit all the N houses.\n\nSample Input 1\n\n20 3\n5 10 15\n\nSample Output 1\n\n10\n\nIf you start at the 1-st house and go to the 2-nd and 3-rd houses in this order, the total distance traveled will be 10.\n\nSample Input 2\n\n20 3\n0 5 15\n\nSample Output 2\n\n10\n\nIf you start at the 2-nd house and go to the 1-st and 3-rd houses in this order, the total distance traveled will be 10.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 297, "cpu_time_ms": 62, "memory_kb": 4052}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s551296712", "group_id": "codeNet:p02726", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nconst int N=2005;\nint n,x,y;\nint cnt[N];\nint main() {\n\tint i,j;\n\tcin>>n>>x>>y;\n\tfor (i=1;i<n;i++)\n\t\tfor (j=i+1;j<=n;j++) {\n\t\t\tif (i<x&&j<x) cnt[j-i]++;\n\t\t\telse if (i>y&&j>y) cnt[j-i]++;\n\t\t\telse if (i<x&&j>y) cnt[j-y+x-i+1]++;\n\t\t\telse if (i<x&&j>=x) cnt[min(j-i,y-j+1+x-i)]++;\n\t\t\telse if (i<=y&&j>y) cnt[min(j-i,i-x+1+j-y)]++;\n\t\t\telse cnt[min(j-i,i-x+y-j+1)]++;\n//\t\t\tcout<<i<<' '<<j<<' '<<cnt[1]<<endl; \n\t\t}\n\tfor (i=1;i<=n-1;i++) cout<<cnt[i]<<endl;\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1588554544, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02726.html", "problem_id": "p02726", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02726/input.txt", "sample_output_relpath": "derived/input_output/data/p02726/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02726/C++/s551296712.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s551296712", "user_id": "u018679195"}, "prompt_components": {"gold_output": "5\n4\n1\n0\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nconst int N=2005;\nint n,x,y;\nint cnt[N];\nint main() {\n\tint i,j;\n\tcin>>n>>x>>y;\n\tfor (i=1;i<n;i++)\n\t\tfor (j=i+1;j<=n;j++) {\n\t\t\tif (i<x&&j<x) cnt[j-i]++;\n\t\t\telse if (i>y&&j>y) cnt[j-i]++;\n\t\t\telse if (i<x&&j>y) cnt[j-y+x-i+1]++;\n\t\t\telse if (i<x&&j>=x) cnt[min(j-i,y-j+1+x-i)]++;\n\t\t\telse if (i<=y&&j>y) cnt[min(j-i,i-x+1+j-y)]++;\n\t\t\telse cnt[min(j-i,i-x+y-j+1)]++;\n//\t\t\tcout<<i<<' '<<j<<' '<<cnt[1]<<endl; \n\t\t}\n\tfor (i=1;i<=n-1;i++) cout<<cnt[i]<<endl;\n\treturn 0;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nWe have an undirected graph G with N vertices numbered 1 to N and N edges as follows:\n\nFor each i=1,2,...,N-1, there is an edge between Vertex i and Vertex i+1.\n\nThere is an edge between Vertex X and Vertex Y.\n\nFor each k=1,2,...,N-1, solve the problem below:\n\nFind the number of pairs of integers (i,j) (1 \\leq i < j \\leq N) such that the shortest distance between Vertex i and Vertex j in G is k.\n\nConstraints\n\n3 \\leq N \\leq 2 \\times 10^3\n\n1 \\leq X,Y \\leq N\n\nX+1 < Y\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN X Y\n\nOutput\n\nFor each k=1, 2, ..., N-1 in this order, print a line containing the answer to the problem.\n\nSample Input 1\n\n5 2 4\n\nSample Output 1\n\n5\n4\n1\n0\n\nThe graph in this input is as follows:\n\nThere are five pairs (i,j) (1 \\leq i < j \\leq N) such that the shortest distance between Vertex i and Vertex j is 1: (1,2)\\,,(2,3)\\,,(2,4)\\,,(3,4)\\,,(4,5).\n\nThere are four pairs (i,j) (1 \\leq i < j \\leq N) such that the shortest distance between Vertex i and Vertex j is 2: (1,3)\\,,(1,4)\\,,(2,5)\\,,(3,5).\n\nThere is one pair (i,j) (1 \\leq i < j \\leq N) such that the shortest distance between Vertex i and Vertex j is 3: (1,5).\n\nThere are no pairs (i,j) (1 \\leq i < j \\leq N) such that the shortest distance between Vertex i and Vertex j is 4.\n\nSample Input 2\n\n3 1 3\n\nSample Output 2\n\n3\n0\n\nThe graph in this input is as follows:\n\nSample Input 3\n\n7 3 7\n\nSample Output 3\n\n7\n8\n4\n2\n0\n0\n\nSample Input 4\n\n10 4 8\n\nSample Output 4\n\n10\n12\n10\n8\n4\n1\n0\n0\n0", "sample_input": "5 2 4\n"}, "reference_outputs": ["5\n4\n1\n0\n"], "source_document_id": "p02726", "source_text": "Score : 400 points\n\nProblem Statement\n\nWe have an undirected graph G with N vertices numbered 1 to N and N edges as follows:\n\nFor each i=1,2,...,N-1, there is an edge between Vertex i and Vertex i+1.\n\nThere is an edge between Vertex X and Vertex Y.\n\nFor each k=1,2,...,N-1, solve the problem below:\n\nFind the number of pairs of integers (i,j) (1 \\leq i < j \\leq N) such that the shortest distance between Vertex i and Vertex j in G is k.\n\nConstraints\n\n3 \\leq N \\leq 2 \\times 10^3\n\n1 \\leq X,Y \\leq N\n\nX+1 < Y\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN X Y\n\nOutput\n\nFor each k=1, 2, ..., N-1 in this order, print a line containing the answer to the problem.\n\nSample Input 1\n\n5 2 4\n\nSample Output 1\n\n5\n4\n1\n0\n\nThe graph in this input is as follows:\n\nThere are five pairs (i,j) (1 \\leq i < j \\leq N) such that the shortest distance between Vertex i and Vertex j is 1: (1,2)\\,,(2,3)\\,,(2,4)\\,,(3,4)\\,,(4,5).\n\nThere are four pairs (i,j) (1 \\leq i < j \\leq N) such that the shortest distance between Vertex i and Vertex j is 2: (1,3)\\,,(1,4)\\,,(2,5)\\,,(3,5).\n\nThere is one pair (i,j) (1 \\leq i < j \\leq N) such that the shortest distance between Vertex i and Vertex j is 3: (1,5).\n\nThere are no pairs (i,j) (1 \\leq i < j \\leq N) such that the shortest distance between Vertex i and Vertex j is 4.\n\nSample Input 2\n\n3 1 3\n\nSample Output 2\n\n3\n0\n\nThe graph in this input is as follows:\n\nSample Input 3\n\n7 3 7\n\nSample Output 3\n\n7\n8\n4\n2\n0\n0\n\nSample Input 4\n\n10 4 8\n\nSample Output 4\n\n10\n12\n10\n8\n4\n1\n0\n0\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 507, "cpu_time_ms": 8, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s947435528", "group_id": "codeNet:p02726", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nconst ll MOD = 1e9 + 7;\nconst int inf = 1e9;\nconst ll INF = 1e18;\nconst double pi = 3.14159265358979323846;\n#define rep(i,n) for(ll i=0;i<n;i++)\n\nint main(){\n\tint n;cin>>n;\n\tint x,y;cin>>x>>y;\n\tx--;y--;\n\tint ans[n+1]={};\n\tfor(int i=0;i<n-1;i++){\n\t\tfor(int j=i+1;j<n;j++){\n\t\t\tint sum=abs(x-i)+abs(y-j)+1;\n\t\t\tans[min(sum,j-i)]++;\n\t\t\t//cout<<i+1<<\" \"<<j+1<<\" : \"<<min(sum,j-i)<<\"\\n\";\n\t\t}\n\t}\n\n\tfor(int i=1;i<n;i++) cout<<ans[i]<<\"\\n\";\n}", "language": "C++", "metadata": {"date": 1588183207, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02726.html", "problem_id": "p02726", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02726/input.txt", "sample_output_relpath": "derived/input_output/data/p02726/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02726/C++/s947435528.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s947435528", "user_id": "u877494916"}, "prompt_components": {"gold_output": "5\n4\n1\n0\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nconst ll MOD = 1e9 + 7;\nconst int inf = 1e9;\nconst ll INF = 1e18;\nconst double pi = 3.14159265358979323846;\n#define rep(i,n) for(ll i=0;i<n;i++)\n\nint main(){\n\tint n;cin>>n;\n\tint x,y;cin>>x>>y;\n\tx--;y--;\n\tint ans[n+1]={};\n\tfor(int i=0;i<n-1;i++){\n\t\tfor(int j=i+1;j<n;j++){\n\t\t\tint sum=abs(x-i)+abs(y-j)+1;\n\t\t\tans[min(sum,j-i)]++;\n\t\t\t//cout<<i+1<<\" \"<<j+1<<\" : \"<<min(sum,j-i)<<\"\\n\";\n\t\t}\n\t}\n\n\tfor(int i=1;i<n;i++) cout<<ans[i]<<\"\\n\";\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nWe have an undirected graph G with N vertices numbered 1 to N and N edges as follows:\n\nFor each i=1,2,...,N-1, there is an edge between Vertex i and Vertex i+1.\n\nThere is an edge between Vertex X and Vertex Y.\n\nFor each k=1,2,...,N-1, solve the problem below:\n\nFind the number of pairs of integers (i,j) (1 \\leq i < j \\leq N) such that the shortest distance between Vertex i and Vertex j in G is k.\n\nConstraints\n\n3 \\leq N \\leq 2 \\times 10^3\n\n1 \\leq X,Y \\leq N\n\nX+1 < Y\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN X Y\n\nOutput\n\nFor each k=1, 2, ..., N-1 in this order, print a line containing the answer to the problem.\n\nSample Input 1\n\n5 2 4\n\nSample Output 1\n\n5\n4\n1\n0\n\nThe graph in this input is as follows:\n\nThere are five pairs (i,j) (1 \\leq i < j \\leq N) such that the shortest distance between Vertex i and Vertex j is 1: (1,2)\\,,(2,3)\\,,(2,4)\\,,(3,4)\\,,(4,5).\n\nThere are four pairs (i,j) (1 \\leq i < j \\leq N) such that the shortest distance between Vertex i and Vertex j is 2: (1,3)\\,,(1,4)\\,,(2,5)\\,,(3,5).\n\nThere is one pair (i,j) (1 \\leq i < j \\leq N) such that the shortest distance between Vertex i and Vertex j is 3: (1,5).\n\nThere are no pairs (i,j) (1 \\leq i < j \\leq N) such that the shortest distance between Vertex i and Vertex j is 4.\n\nSample Input 2\n\n3 1 3\n\nSample Output 2\n\n3\n0\n\nThe graph in this input is as follows:\n\nSample Input 3\n\n7 3 7\n\nSample Output 3\n\n7\n8\n4\n2\n0\n0\n\nSample Input 4\n\n10 4 8\n\nSample Output 4\n\n10\n12\n10\n8\n4\n1\n0\n0\n0", "sample_input": "5 2 4\n"}, "reference_outputs": ["5\n4\n1\n0\n"], "source_document_id": "p02726", "source_text": "Score : 400 points\n\nProblem Statement\n\nWe have an undirected graph G with N vertices numbered 1 to N and N edges as follows:\n\nFor each i=1,2,...,N-1, there is an edge between Vertex i and Vertex i+1.\n\nThere is an edge between Vertex X and Vertex Y.\n\nFor each k=1,2,...,N-1, solve the problem below:\n\nFind the number of pairs of integers (i,j) (1 \\leq i < j \\leq N) such that the shortest distance between Vertex i and Vertex j in G is k.\n\nConstraints\n\n3 \\leq N \\leq 2 \\times 10^3\n\n1 \\leq X,Y \\leq N\n\nX+1 < Y\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN X Y\n\nOutput\n\nFor each k=1, 2, ..., N-1 in this order, print a line containing the answer to the problem.\n\nSample Input 1\n\n5 2 4\n\nSample Output 1\n\n5\n4\n1\n0\n\nThe graph in this input is as follows:\n\nThere are five pairs (i,j) (1 \\leq i < j \\leq N) such that the shortest distance between Vertex i and Vertex j is 1: (1,2)\\,,(2,3)\\,,(2,4)\\,,(3,4)\\,,(4,5).\n\nThere are four pairs (i,j) (1 \\leq i < j \\leq N) such that the shortest distance between Vertex i and Vertex j is 2: (1,3)\\,,(1,4)\\,,(2,5)\\,,(3,5).\n\nThere is one pair (i,j) (1 \\leq i < j \\leq N) such that the shortest distance between Vertex i and Vertex j is 3: (1,5).\n\nThere are no pairs (i,j) (1 \\leq i < j \\leq N) such that the shortest distance between Vertex i and Vertex j is 4.\n\nSample Input 2\n\n3 1 3\n\nSample Output 2\n\n3\n0\n\nThe graph in this input is as follows:\n\nSample Input 3\n\n7 3 7\n\nSample Output 3\n\n7\n8\n4\n2\n0\n0\n\nSample Input 4\n\n10 4 8\n\nSample Output 4\n\n10\n12\n10\n8\n4\n1\n0\n0\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 500, "cpu_time_ms": 5, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s321407937", "group_id": "codeNet:p02729", "input_text": "#include <iostream>\n#include <vector>\n#include <string>\n#include <set>\n#include <list>\n#include <deque>\n#include <cstdio>\n#include <cstring>\n#include <queue>\n#include <stack>\n#include <algorithm>\n#include <cmath>\n#define ll long long\n#define INF 0x3f3f3f3f\n#define SIS std::ios::sync_with_stdio(false)\nusing namespace std;\nll fast_pow(ll a,ll b,ll mod)\n{\n    ll c=1;\n    while(b>=2)\n    {\n        if(b%2==0)\n            a*=a,b/=2;\n        else\n            c*=a,a*=a,b--,b/=2;\n        a%=mod,c%=mod;\n    }\n    return (a*c)%mod;\n}\nll cal(ll n,ll m);\nint main()\n{\n    int n,m;\n    while(cin>>n>>m)\n    {\n        ll ans=0;\n        if(n>1)\n            ans+=cal(n,2);\n        if(m>1)\n            ans+=cal(m,2);\n        cout<<ans<<endl;\n    }\n    return 0;\n}\n\nll cal(ll n,ll m)\n{\n    return n*(n-1)/2;\n}\n", "language": "C++", "metadata": {"date": 1584927653, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02729.html", "problem_id": "p02729", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02729/input.txt", "sample_output_relpath": "derived/input_output/data/p02729/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02729/C++/s321407937.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s321407937", "user_id": "u313799429"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\n#include <string>\n#include <set>\n#include <list>\n#include <deque>\n#include <cstdio>\n#include <cstring>\n#include <queue>\n#include <stack>\n#include <algorithm>\n#include <cmath>\n#define ll long long\n#define INF 0x3f3f3f3f\n#define SIS std::ios::sync_with_stdio(false)\nusing namespace std;\nll fast_pow(ll a,ll b,ll mod)\n{\n    ll c=1;\n    while(b>=2)\n    {\n        if(b%2==0)\n            a*=a,b/=2;\n        else\n            c*=a,a*=a,b--,b/=2;\n        a%=mod,c%=mod;\n    }\n    return (a*c)%mod;\n}\nll cal(ll n,ll m);\nint main()\n{\n    int n,m;\n    while(cin>>n>>m)\n    {\n        ll ans=0;\n        if(n>1)\n            ans+=cal(n,2);\n        if(m>1)\n            ans+=cal(m,2);\n        cout<<ans<<endl;\n    }\n    return 0;\n}\n\nll cal(ll n,ll m)\n{\n    return n*(n-1)/2;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nWe have N+M balls, each of which has an integer written on it.\n\nIt is known that:\n\nThe numbers written on N of the balls are even.\n\nThe numbers written on M of the balls are odd.\n\nFind the number of ways to choose two of the N+M balls (disregarding order) so that the sum of the numbers written on them is even.\n\nIt can be shown that this count does not depend on the actual values written on the balls.\n\nConstraints\n\n0 \\leq N,M \\leq 100\n\n2 \\leq N+M\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n2 1\n\nSample Output 1\n\n1\n\nFor example, let us assume that the numbers written on the three balls are 1,2,4.\n\nIf we choose the two balls with 1 and 2, the sum is odd;\n\nIf we choose the two balls with 1 and 4, the sum is odd;\n\nIf we choose the two balls with 2 and 4, the sum is even.\n\nThus, the answer is 1.\n\nSample Input 2\n\n4 3\n\nSample Output 2\n\n9\n\nSample Input 3\n\n1 1\n\nSample Output 3\n\n0\n\nSample Input 4\n\n13 3\n\nSample Output 4\n\n81\n\nSample Input 5\n\n0 3\n\nSample Output 5\n\n3", "sample_input": "2 1\n"}, "reference_outputs": ["1\n"], "source_document_id": "p02729", "source_text": "Score : 100 points\n\nProblem Statement\n\nWe have N+M balls, each of which has an integer written on it.\n\nIt is known that:\n\nThe numbers written on N of the balls are even.\n\nThe numbers written on M of the balls are odd.\n\nFind the number of ways to choose two of the N+M balls (disregarding order) so that the sum of the numbers written on them is even.\n\nIt can be shown that this count does not depend on the actual values written on the balls.\n\nConstraints\n\n0 \\leq N,M \\leq 100\n\n2 \\leq N+M\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n2 1\n\nSample Output 1\n\n1\n\nFor example, let us assume that the numbers written on the three balls are 1,2,4.\n\nIf we choose the two balls with 1 and 2, the sum is odd;\n\nIf we choose the two balls with 1 and 4, the sum is odd;\n\nIf we choose the two balls with 2 and 4, the sum is even.\n\nThus, the answer is 1.\n\nSample Input 2\n\n4 3\n\nSample Output 2\n\n9\n\nSample Input 3\n\n1 1\n\nSample Output 3\n\n0\n\nSample Input 4\n\n13 3\n\nSample Output 4\n\n81\n\nSample Input 5\n\n0 3\n\nSample Output 5\n\n3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 797, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s866172986", "group_id": "codeNet:p02730", "input_text": "#include <bits/stdc++.h>\n#define rep(i,n) for (int i=0;i<(n);i++)\n#define adrep(i,s,n) for (int i=(s);i<(n);i++)\nusing namespace std;\ntypedef long long ll;\n\nint check(string t){\n\n  int n=t.length();\n  rep(i,n){\n    //cout<<t[i]<<\" \"<<t[n-(i+1)]<<endl;\n    if(t[i]!=t[n-(i+1)]){\n      return 0;\n    }\n  }\n  return 1;\n}\n\nint main(){\n\n string s;\n  \n  cin>>s;\n  \n  int N=s.length();\n  \n  if(check(s)==0){cout<<\"No\"<<endl;return 0;}\n  string s1=s.substr(0,(N-1)/2);\n  //cout<<s1<<endl;\n  if(check(s1)==0){cout<<\"No\"<<endl;return 0;}\n  string s2=s.substr((N+3)/2-1,(N-1)/2);\n  //cout<<s2<<endl;\n  if(check(s2)==0){cout<<\"No\"<<endl;return 0;}\n  \n  cout<<\"Yes\"<<endl;\n}\n", "language": "C++", "metadata": {"date": 1584926408, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02730.html", "problem_id": "p02730", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02730/input.txt", "sample_output_relpath": "derived/input_output/data/p02730/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02730/C++/s866172986.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s866172986", "user_id": "u978535698"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define rep(i,n) for (int i=0;i<(n);i++)\n#define adrep(i,s,n) for (int i=(s);i<(n);i++)\nusing namespace std;\ntypedef long long ll;\n\nint check(string t){\n\n  int n=t.length();\n  rep(i,n){\n    //cout<<t[i]<<\" \"<<t[n-(i+1)]<<endl;\n    if(t[i]!=t[n-(i+1)]){\n      return 0;\n    }\n  }\n  return 1;\n}\n\nint main(){\n\n string s;\n  \n  cin>>s;\n  \n  int N=s.length();\n  \n  if(check(s)==0){cout<<\"No\"<<endl;return 0;}\n  string s1=s.substr(0,(N-1)/2);\n  //cout<<s1<<endl;\n  if(check(s1)==0){cout<<\"No\"<<endl;return 0;}\n  string s2=s.substr((N+3)/2-1,(N-1)/2);\n  //cout<<s2<<endl;\n  if(check(s2)==0){cout<<\"No\"<<endl;return 0;}\n  \n  cout<<\"Yes\"<<endl;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nA string S of an odd length is said to be a strong palindrome if and only if all of the following conditions are satisfied:\n\nS is a palindrome.\n\nLet N be the length of S. The string formed by the 1-st through ((N-1)/2)-th characters of S is a palindrome.\n\nThe string consisting of the (N+3)/2-st through N-th characters of S is a palindrome.\n\nDetermine whether S is a strong palindrome.\n\nConstraints\n\nS consists of lowercase English letters.\n\nThe length of S is an odd number between 3 and 99 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nIf S is a strong palindrome, print Yes;\notherwise, print No.\n\nSample Input 1\n\nakasaka\n\nSample Output 1\n\nYes\n\nS is akasaka.\n\nThe string formed by the 1-st through the 3-rd characters is aka.\n\nThe string formed by the 5-th through the 7-th characters is aka.\nAll of these are palindromes, so S is a strong palindrome.\n\nSample Input 2\n\nlevel\n\nSample Output 2\n\nNo\n\nSample Input 3\n\natcoder\n\nSample Output 3\n\nNo", "sample_input": "akasaka\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p02730", "source_text": "Score : 200 points\n\nProblem Statement\n\nA string S of an odd length is said to be a strong palindrome if and only if all of the following conditions are satisfied:\n\nS is a palindrome.\n\nLet N be the length of S. The string formed by the 1-st through ((N-1)/2)-th characters of S is a palindrome.\n\nThe string consisting of the (N+3)/2-st through N-th characters of S is a palindrome.\n\nDetermine whether S is a strong palindrome.\n\nConstraints\n\nS consists of lowercase English letters.\n\nThe length of S is an odd number between 3 and 99 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nIf S is a strong palindrome, print Yes;\notherwise, print No.\n\nSample Input 1\n\nakasaka\n\nSample Output 1\n\nYes\n\nS is akasaka.\n\nThe string formed by the 1-st through the 3-rd characters is aka.\n\nThe string formed by the 5-th through the 7-th characters is aka.\nAll of these are palindromes, so S is a strong palindrome.\n\nSample Input 2\n\nlevel\n\nSample Output 2\n\nNo\n\nSample Input 3\n\natcoder\n\nSample Output 3\n\nNo", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 662, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s026990361", "group_id": "codeNet:p02730", "input_text": "#include <iostream>\nusing namespace std;\n#define int long long\nsigned main() {\n\tstring s;\n\tcin>>s;\n\tint n=s.size();\n\tint i=0;\n\tint j=s.size()-1;\n\twhile(i<j)\n\t{\n\t    if(s[i]!=s[j])\n\t    break;\n\t    i++;\n\t    j--;\n\t}\n\tif(i!=j)\n\t{\n\t    cout<<\"No\"<<endl;\n\t    return 0;\n\t}\n\tj=(n-1)/2-1;\n\ti=0;\n\twhile(i<j)\n\t{\n\t    if(s[i]!=s[j])\n\t    {\n\t        cout<<\"No\";\n\t        return 0;\n\t    }\n\t    i++;\n\t    j--;\n\t}\n\tcout<<\"Yes\";\n}\n", "language": "C++", "metadata": {"date": 1584925918, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02730.html", "problem_id": "p02730", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02730/input.txt", "sample_output_relpath": "derived/input_output/data/p02730/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02730/C++/s026990361.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s026990361", "user_id": "u124510775"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <iostream>\nusing namespace std;\n#define int long long\nsigned main() {\n\tstring s;\n\tcin>>s;\n\tint n=s.size();\n\tint i=0;\n\tint j=s.size()-1;\n\twhile(i<j)\n\t{\n\t    if(s[i]!=s[j])\n\t    break;\n\t    i++;\n\t    j--;\n\t}\n\tif(i!=j)\n\t{\n\t    cout<<\"No\"<<endl;\n\t    return 0;\n\t}\n\tj=(n-1)/2-1;\n\ti=0;\n\twhile(i<j)\n\t{\n\t    if(s[i]!=s[j])\n\t    {\n\t        cout<<\"No\";\n\t        return 0;\n\t    }\n\t    i++;\n\t    j--;\n\t}\n\tcout<<\"Yes\";\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nA string S of an odd length is said to be a strong palindrome if and only if all of the following conditions are satisfied:\n\nS is a palindrome.\n\nLet N be the length of S. The string formed by the 1-st through ((N-1)/2)-th characters of S is a palindrome.\n\nThe string consisting of the (N+3)/2-st through N-th characters of S is a palindrome.\n\nDetermine whether S is a strong palindrome.\n\nConstraints\n\nS consists of lowercase English letters.\n\nThe length of S is an odd number between 3 and 99 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nIf S is a strong palindrome, print Yes;\notherwise, print No.\n\nSample Input 1\n\nakasaka\n\nSample Output 1\n\nYes\n\nS is akasaka.\n\nThe string formed by the 1-st through the 3-rd characters is aka.\n\nThe string formed by the 5-th through the 7-th characters is aka.\nAll of these are palindromes, so S is a strong palindrome.\n\nSample Input 2\n\nlevel\n\nSample Output 2\n\nNo\n\nSample Input 3\n\natcoder\n\nSample Output 3\n\nNo", "sample_input": "akasaka\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p02730", "source_text": "Score : 200 points\n\nProblem Statement\n\nA string S of an odd length is said to be a strong palindrome if and only if all of the following conditions are satisfied:\n\nS is a palindrome.\n\nLet N be the length of S. The string formed by the 1-st through ((N-1)/2)-th characters of S is a palindrome.\n\nThe string consisting of the (N+3)/2-st through N-th characters of S is a palindrome.\n\nDetermine whether S is a strong palindrome.\n\nConstraints\n\nS consists of lowercase English letters.\n\nThe length of S is an odd number between 3 and 99 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nIf S is a strong palindrome, print Yes;\notherwise, print No.\n\nSample Input 1\n\nakasaka\n\nSample Output 1\n\nYes\n\nS is akasaka.\n\nThe string formed by the 1-st through the 3-rd characters is aka.\n\nThe string formed by the 5-th through the 7-th characters is aka.\nAll of these are palindromes, so S is a strong palindrome.\n\nSample Input 2\n\nlevel\n\nSample Output 2\n\nNo\n\nSample Input 3\n\natcoder\n\nSample Output 3\n\nNo", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 417, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s174515385", "group_id": "codeNet:p02730", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nusing P = pair<ll,ll>;\nconst ll mod = 1e9+7;\n#define ALL(x) (x).begin(),(x).end()\n#define pow(x,y) modpow(x,y)\n#define REP(i,n) for(ll (i)=0;(i)<(n);(i)++)\n\ntemplate <class T = int>T in(){\n    T x;\n    cin >> x;\n    return (x);\n}\n\nsigned main(){\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n    cout<<fixed<<setprecision(10);\n    string S = in<string>();\n    bool ok = 1;\n    int N = S.size();\n    REP(i,N/2)if(S[i] != S[N-1-i])ok = 0;\n    REP(i,(N/2)/2)if(S[i] != S[N/2-1-i])ok = 0;\n    REP(i,(N/2)/2)if(S[N-1-i] != S[N/2+1-i])ok = 0;\n    cout << (ok ? \"Yes\" : \"No\") << \"\\n\";\n}", "language": "C++", "metadata": {"date": 1584925816, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02730.html", "problem_id": "p02730", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02730/input.txt", "sample_output_relpath": "derived/input_output/data/p02730/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02730/C++/s174515385.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s174515385", "user_id": "u017078415"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nusing P = pair<ll,ll>;\nconst ll mod = 1e9+7;\n#define ALL(x) (x).begin(),(x).end()\n#define pow(x,y) modpow(x,y)\n#define REP(i,n) for(ll (i)=0;(i)<(n);(i)++)\n\ntemplate <class T = int>T in(){\n    T x;\n    cin >> x;\n    return (x);\n}\n\nsigned main(){\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n    cout<<fixed<<setprecision(10);\n    string S = in<string>();\n    bool ok = 1;\n    int N = S.size();\n    REP(i,N/2)if(S[i] != S[N-1-i])ok = 0;\n    REP(i,(N/2)/2)if(S[i] != S[N/2-1-i])ok = 0;\n    REP(i,(N/2)/2)if(S[N-1-i] != S[N/2+1-i])ok = 0;\n    cout << (ok ? \"Yes\" : \"No\") << \"\\n\";\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nA string S of an odd length is said to be a strong palindrome if and only if all of the following conditions are satisfied:\n\nS is a palindrome.\n\nLet N be the length of S. The string formed by the 1-st through ((N-1)/2)-th characters of S is a palindrome.\n\nThe string consisting of the (N+3)/2-st through N-th characters of S is a palindrome.\n\nDetermine whether S is a strong palindrome.\n\nConstraints\n\nS consists of lowercase English letters.\n\nThe length of S is an odd number between 3 and 99 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nIf S is a strong palindrome, print Yes;\notherwise, print No.\n\nSample Input 1\n\nakasaka\n\nSample Output 1\n\nYes\n\nS is akasaka.\n\nThe string formed by the 1-st through the 3-rd characters is aka.\n\nThe string formed by the 5-th through the 7-th characters is aka.\nAll of these are palindromes, so S is a strong palindrome.\n\nSample Input 2\n\nlevel\n\nSample Output 2\n\nNo\n\nSample Input 3\n\natcoder\n\nSample Output 3\n\nNo", "sample_input": "akasaka\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p02730", "source_text": "Score : 200 points\n\nProblem Statement\n\nA string S of an odd length is said to be a strong palindrome if and only if all of the following conditions are satisfied:\n\nS is a palindrome.\n\nLet N be the length of S. The string formed by the 1-st through ((N-1)/2)-th characters of S is a palindrome.\n\nThe string consisting of the (N+3)/2-st through N-th characters of S is a palindrome.\n\nDetermine whether S is a strong palindrome.\n\nConstraints\n\nS consists of lowercase English letters.\n\nThe length of S is an odd number between 3 and 99 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nIf S is a strong palindrome, print Yes;\notherwise, print No.\n\nSample Input 1\n\nakasaka\n\nSample Output 1\n\nYes\n\nS is akasaka.\n\nThe string formed by the 1-st through the 3-rd characters is aka.\n\nThe string formed by the 5-th through the 7-th characters is aka.\nAll of these are palindromes, so S is a strong palindrome.\n\nSample Input 2\n\nlevel\n\nSample Output 2\n\nNo\n\nSample Input 3\n\natcoder\n\nSample Output 3\n\nNo", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 650, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s202038551", "group_id": "codeNet:p02731", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n \nint main(){\n  int L;\n  cin >> L;\n  \n  double count=L*L*L/27;\n  cout << fixed << setprecision(15) << count << endl;\n}", "language": "C++", "metadata": {"date": 1584932354, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02731.html", "problem_id": "p02731", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02731/input.txt", "sample_output_relpath": "derived/input_output/data/p02731/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02731/C++/s202038551.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s202038551", "user_id": "u982720765"}, "prompt_components": {"gold_output": "1.000000000000\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n \nint main(){\n  int L;\n  cin >> L;\n  \n  double count=L*L*L/27;\n  cout << fixed << setprecision(15) << count << endl;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nGiven is a positive integer L.\nFind the maximum possible volume of a rectangular cuboid whose sum of the dimensions (not necessarily integers) is L.\n\nConstraints\n\n1 ≤ L ≤ 1000\n\nL is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nL\n\nOutput\n\nPrint the maximum possible volume of a rectangular cuboid whose sum of the dimensions (not necessarily integers) is L.\nYour output is considered correct if its absolute or relative error from our answer is at most 10^{-6}.\n\nSample Input 1\n\n3\n\nSample Output 1\n\n1.000000000000\n\nFor example, a rectangular cuboid whose dimensions are 0.8, 1, and 1.2 has a volume of 0.96.\n\nOn the other hand, if the dimensions are 1, 1, and 1, the volume of the rectangular cuboid is 1, which is greater.\n\nSample Input 2\n\n999\n\nSample Output 2\n\n36926037.000000000000", "sample_input": "3\n"}, "reference_outputs": ["1.000000000000\n"], "source_document_id": "p02731", "source_text": "Score : 300 points\n\nProblem Statement\n\nGiven is a positive integer L.\nFind the maximum possible volume of a rectangular cuboid whose sum of the dimensions (not necessarily integers) is L.\n\nConstraints\n\n1 ≤ L ≤ 1000\n\nL is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nL\n\nOutput\n\nPrint the maximum possible volume of a rectangular cuboid whose sum of the dimensions (not necessarily integers) is L.\nYour output is considered correct if its absolute or relative error from our answer is at most 10^{-6}.\n\nSample Input 1\n\n3\n\nSample Output 1\n\n1.000000000000\n\nFor example, a rectangular cuboid whose dimensions are 0.8, 1, and 1.2 has a volume of 0.96.\n\nOn the other hand, if the dimensions are 1, 1, and 1, the volume of the rectangular cuboid is 1, which is greater.\n\nSample Input 2\n\n999\n\nSample Output 2\n\n36926037.000000000000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 164, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s691784520", "group_id": "codeNet:p02731", "input_text": "#include<bits/stdc++.h> \nusing namespace std;\n\nint main()\n{\n    int l;\n    cin>>l;\n    float f=l/3.0;\n    cout<<fixed << setprecision(6) <<f*f*f;\n\n    return 0;\n}", "language": "C++", "metadata": {"date": 1584927271, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02731.html", "problem_id": "p02731", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02731/input.txt", "sample_output_relpath": "derived/input_output/data/p02731/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02731/C++/s691784520.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s691784520", "user_id": "u737925023"}, "prompt_components": {"gold_output": "1.000000000000\n", "input_to_evaluate": "#include<bits/stdc++.h> \nusing namespace std;\n\nint main()\n{\n    int l;\n    cin>>l;\n    float f=l/3.0;\n    cout<<fixed << setprecision(6) <<f*f*f;\n\n    return 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nGiven is a positive integer L.\nFind the maximum possible volume of a rectangular cuboid whose sum of the dimensions (not necessarily integers) is L.\n\nConstraints\n\n1 ≤ L ≤ 1000\n\nL is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nL\n\nOutput\n\nPrint the maximum possible volume of a rectangular cuboid whose sum of the dimensions (not necessarily integers) is L.\nYour output is considered correct if its absolute or relative error from our answer is at most 10^{-6}.\n\nSample Input 1\n\n3\n\nSample Output 1\n\n1.000000000000\n\nFor example, a rectangular cuboid whose dimensions are 0.8, 1, and 1.2 has a volume of 0.96.\n\nOn the other hand, if the dimensions are 1, 1, and 1, the volume of the rectangular cuboid is 1, which is greater.\n\nSample Input 2\n\n999\n\nSample Output 2\n\n36926037.000000000000", "sample_input": "3\n"}, "reference_outputs": ["1.000000000000\n"], "source_document_id": "p02731", "source_text": "Score : 300 points\n\nProblem Statement\n\nGiven is a positive integer L.\nFind the maximum possible volume of a rectangular cuboid whose sum of the dimensions (not necessarily integers) is L.\n\nConstraints\n\n1 ≤ L ≤ 1000\n\nL is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nL\n\nOutput\n\nPrint the maximum possible volume of a rectangular cuboid whose sum of the dimensions (not necessarily integers) is L.\nYour output is considered correct if its absolute or relative error from our answer is at most 10^{-6}.\n\nSample Input 1\n\n3\n\nSample Output 1\n\n1.000000000000\n\nFor example, a rectangular cuboid whose dimensions are 0.8, 1, and 1.2 has a volume of 0.96.\n\nOn the other hand, if the dimensions are 1, 1, and 1, the volume of the rectangular cuboid is 1, which is greater.\n\nSample Input 2\n\n999\n\nSample Output 2\n\n36926037.000000000000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 162, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s125952458", "group_id": "codeNet:p02731", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n \n#define F(i,a,b) for(long long  i =a; i<b; i++)\n#define rF(i,a,b) for(long long i=a-1; i>=b;i--)\n#define endl \"\\n\"\n#define min1(x,y,z) min(x, min(y,z))\n#define max1(x,y,z) max(x, max(y,z))\n#define input_vector(v,n,type) vector<type> v;for(int i=0;i<n;i++){type x;cin>>x;v.push_back(x);}\n#define IOS ios_base::sync_with_stdio(false);  cin.tie(NULL);  cout.tie(NULL);\n#define int long long\n#define inf (1LL<<61)\ntypedef pair<int,int> ii;\ntypedef vector<pair<int,int>> vii;\ntypedef vector<int> vi;\n \n \n \nint32_t main()\n{\n        IOS;\n\n        int L;\n        cin>>L;\n\n        if (L == 1) {\n                double ans = (double)1/(double)27;\n                cout<<fixed<<setprecision(10)<<ans<<endl;\n                return 0;\n        }\n        if (L == 2) {\n                double ans = (double)8/(double)27;\n                cout<<fixed<<setprecision(10)<<ans<<endl;\n                return 0;\n        }\n        if (true) {\n                double x = (double)L/(double)3;\n                double ans = x*x*x;\n                cout<<fixed<<setprecision(10)<<ans<<endl;\n        } else if (L%3 == 1) {\n                double ans = (L/3*(L+1)/3*L/3);\n                cout<<fixed<<setprecision(10)<<ans<<endl;\n        } else {\n                double ans = (L/3*(L+1)/3*(L+1)/3);\n                cout<<fixed<<setprecision(10)<<ans<<endl;\n        }\n        \n\n\n\n\n\n        \n \n \n \n            \n \n \n \n      \n \n \n        \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n        return 0;\n}", "language": "C++", "metadata": {"date": 1584926744, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02731.html", "problem_id": "p02731", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02731/input.txt", "sample_output_relpath": "derived/input_output/data/p02731/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02731/C++/s125952458.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s125952458", "user_id": "u470329674"}, "prompt_components": {"gold_output": "1.000000000000\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n \n#define F(i,a,b) for(long long  i =a; i<b; i++)\n#define rF(i,a,b) for(long long i=a-1; i>=b;i--)\n#define endl \"\\n\"\n#define min1(x,y,z) min(x, min(y,z))\n#define max1(x,y,z) max(x, max(y,z))\n#define input_vector(v,n,type) vector<type> v;for(int i=0;i<n;i++){type x;cin>>x;v.push_back(x);}\n#define IOS ios_base::sync_with_stdio(false);  cin.tie(NULL);  cout.tie(NULL);\n#define int long long\n#define inf (1LL<<61)\ntypedef pair<int,int> ii;\ntypedef vector<pair<int,int>> vii;\ntypedef vector<int> vi;\n \n \n \nint32_t main()\n{\n        IOS;\n\n        int L;\n        cin>>L;\n\n        if (L == 1) {\n                double ans = (double)1/(double)27;\n                cout<<fixed<<setprecision(10)<<ans<<endl;\n                return 0;\n        }\n        if (L == 2) {\n                double ans = (double)8/(double)27;\n                cout<<fixed<<setprecision(10)<<ans<<endl;\n                return 0;\n        }\n        if (true) {\n                double x = (double)L/(double)3;\n                double ans = x*x*x;\n                cout<<fixed<<setprecision(10)<<ans<<endl;\n        } else if (L%3 == 1) {\n                double ans = (L/3*(L+1)/3*L/3);\n                cout<<fixed<<setprecision(10)<<ans<<endl;\n        } else {\n                double ans = (L/3*(L+1)/3*(L+1)/3);\n                cout<<fixed<<setprecision(10)<<ans<<endl;\n        }\n        \n\n\n\n\n\n        \n \n \n \n            \n \n \n \n      \n \n \n        \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n \n        return 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nGiven is a positive integer L.\nFind the maximum possible volume of a rectangular cuboid whose sum of the dimensions (not necessarily integers) is L.\n\nConstraints\n\n1 ≤ L ≤ 1000\n\nL is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nL\n\nOutput\n\nPrint the maximum possible volume of a rectangular cuboid whose sum of the dimensions (not necessarily integers) is L.\nYour output is considered correct if its absolute or relative error from our answer is at most 10^{-6}.\n\nSample Input 1\n\n3\n\nSample Output 1\n\n1.000000000000\n\nFor example, a rectangular cuboid whose dimensions are 0.8, 1, and 1.2 has a volume of 0.96.\n\nOn the other hand, if the dimensions are 1, 1, and 1, the volume of the rectangular cuboid is 1, which is greater.\n\nSample Input 2\n\n999\n\nSample Output 2\n\n36926037.000000000000", "sample_input": "3\n"}, "reference_outputs": ["1.000000000000\n"], "source_document_id": "p02731", "source_text": "Score : 300 points\n\nProblem Statement\n\nGiven is a positive integer L.\nFind the maximum possible volume of a rectangular cuboid whose sum of the dimensions (not necessarily integers) is L.\n\nConstraints\n\n1 ≤ L ≤ 1000\n\nL is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nL\n\nOutput\n\nPrint the maximum possible volume of a rectangular cuboid whose sum of the dimensions (not necessarily integers) is L.\nYour output is considered correct if its absolute or relative error from our answer is at most 10^{-6}.\n\nSample Input 1\n\n3\n\nSample Output 1\n\n1.000000000000\n\nFor example, a rectangular cuboid whose dimensions are 0.8, 1, and 1.2 has a volume of 0.96.\n\nOn the other hand, if the dimensions are 1, 1, and 1, the volume of the rectangular cuboid is 1, which is greater.\n\nSample Input 2\n\n999\n\nSample Output 2\n\n36926037.000000000000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1517, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s940229322", "group_id": "codeNet:p02732", "input_text": "#include \"./bits/stdc++.h\"\n\nusing namespace std;\n\nint main() {\n    int N;\n    vector<int> A;\n\n    cin >> N;\n    for (int i = 0; i < N; i++) {\n        int tmp;\n        cin >> tmp;\n        A.emplace_back(tmp);\n    }\n    \n    int count_box[int(2e5) + 1];\n    vector<int> memo;\n    \n    for (int i = 0; i < N; i++) {\n        if (count_box[A[i]] == 0) memo.emplace_back(A[i]);\n        count_box[A[i]]++;\n    }\n\n    long long total = 0;\n    for (auto& v : memo) total += count_box[v] * (count_box[v] - 1) / 2;\n\n    for (int i = 0; i < N; i++) {\n        long long result = total - count_box[A[i]] + 1;\n        cout << result << endl;\n    }\n}", "language": "C++", "metadata": {"date": 1585917708, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02732.html", "problem_id": "p02732", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02732/input.txt", "sample_output_relpath": "derived/input_output/data/p02732/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02732/C++/s940229322.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s940229322", "user_id": "u436976004"}, "prompt_components": {"gold_output": "2\n2\n3\n2\n3\n", "input_to_evaluate": "#include \"./bits/stdc++.h\"\n\nusing namespace std;\n\nint main() {\n    int N;\n    vector<int> A;\n\n    cin >> N;\n    for (int i = 0; i < N; i++) {\n        int tmp;\n        cin >> tmp;\n        A.emplace_back(tmp);\n    }\n    \n    int count_box[int(2e5) + 1];\n    vector<int> memo;\n    \n    for (int i = 0; i < N; i++) {\n        if (count_box[A[i]] == 0) memo.emplace_back(A[i]);\n        count_box[A[i]]++;\n    }\n\n    long long total = 0;\n    for (auto& v : memo) total += count_box[v] * (count_box[v] - 1) / 2;\n\n    for (int i = 0; i < N; i++) {\n        long long result = total - count_box[A[i]] + 1;\n        cout << result << endl;\n    }\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nWe have N balls. The i-th ball has an integer A_i written on it.\n\nFor each k=1, 2, ..., N, solve the following problem and print the answer.\n\nFind the number of ways to choose two distinct balls (disregarding order) from the N-1 balls other than the k-th ball so that the integers written on them are equal.\n\nConstraints\n\n3 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq A_i \\leq N\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nFor each k=1,2,...,N, print a line containing the answer.\n\nSample Input 1\n\n5\n1 1 2 1 2\n\nSample Output 1\n\n2\n2\n3\n2\n3\n\nConsider the case k=1 for example. The numbers written on the remaining balls are 1,2,1,2.\n\nFrom these balls, there are two ways to choose two distinct balls so that the integers written on them are equal.\n\nThus, the answer for k=1 is 2.\n\nSample Input 2\n\n4\n1 2 3 4\n\nSample Output 2\n\n0\n0\n0\n0\n\nNo two balls have equal numbers written on them.\n\nSample Input 3\n\n5\n3 3 3 3 3\n\nSample Output 3\n\n6\n6\n6\n6\n6\n\nAny two balls have equal numbers written on them.\n\nSample Input 4\n\n8\n1 2 1 4 2 1 4 1\n\nSample Output 4\n\n5\n7\n5\n7\n7\n5\n7\n5", "sample_input": "5\n1 1 2 1 2\n"}, "reference_outputs": ["2\n2\n3\n2\n3\n"], "source_document_id": "p02732", "source_text": "Score : 400 points\n\nProblem Statement\n\nWe have N balls. The i-th ball has an integer A_i written on it.\n\nFor each k=1, 2, ..., N, solve the following problem and print the answer.\n\nFind the number of ways to choose two distinct balls (disregarding order) from the N-1 balls other than the k-th ball so that the integers written on them are equal.\n\nConstraints\n\n3 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq A_i \\leq N\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nFor each k=1,2,...,N, print a line containing the answer.\n\nSample Input 1\n\n5\n1 1 2 1 2\n\nSample Output 1\n\n2\n2\n3\n2\n3\n\nConsider the case k=1 for example. The numbers written on the remaining balls are 1,2,1,2.\n\nFrom these balls, there are two ways to choose two distinct balls so that the integers written on them are equal.\n\nThus, the answer for k=1 is 2.\n\nSample Input 2\n\n4\n1 2 3 4\n\nSample Output 2\n\n0\n0\n0\n0\n\nNo two balls have equal numbers written on them.\n\nSample Input 3\n\n5\n3 3 3 3 3\n\nSample Output 3\n\n6\n6\n6\n6\n6\n\nAny two balls have equal numbers written on them.\n\nSample Input 4\n\n8\n1 2 1 4 2 1 4 1\n\nSample Output 4\n\n5\n7\n5\n7\n7\n5\n7\n5", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 634, "cpu_time_ms": 372, "memory_kb": 4212}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s134120512", "group_id": "codeNet:p02733", "input_text": "/*\n    アリナ・グレイはかわいい\n*/\n\n#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing P = pair<int,int>;\n#define itn int\n#define endl \"\\n\"\n\nint main(void){\n    int h,w,k;\n    cin >> h >> w >> k;\n    string s[1004];\n    int mn = 1LL<<30;\n    \n    for(int i = 0;i < h;i++)cin >> s[i];\n    \n    for(int i = 0;i < (1 << (h-1));i++){\n        int sum = 0,a[100] = {};\n        for(int j = 0;j < h;j++){\n            a[j] = sum;\n            if(i & (1 << j))sum++;\n        }\n        sum++;\n        int num = __builtin_popcount(i),b[100] = {};\n        \n        //for(int p = 0;p < h;p++)b[p] = 0;\n        for(int p = 0;p < w;p++){\n            for(int q = 0;q < h;q++){\n                b[a[q]] += (s[q][p]-'0');\n            }\n            for(int q = 0;q < sum;q++){\n                if(b[q] > k){\n                    num++;\n                    for(int l = 0;l < sum;l++)b[l] = 0;\n                    for(int l = 0;l < h;l++)b[a[l]] += (s[l][p]-'0');\n                    break;\n                }\n            }\n            for(int l = 0;l < num;l++)if(b[l] > k)num = 1LL<<30;\n        }\n        mn = min(mn,num);\n    }\n    cout << mn << endl;\n}\n", "language": "C++", "metadata": {"date": 1584954801, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02733.html", "problem_id": "p02733", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02733/input.txt", "sample_output_relpath": "derived/input_output/data/p02733/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02733/C++/s134120512.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s134120512", "user_id": "u512624048"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "/*\n    アリナ・グレイはかわいい\n*/\n\n#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing P = pair<int,int>;\n#define itn int\n#define endl \"\\n\"\n\nint main(void){\n    int h,w,k;\n    cin >> h >> w >> k;\n    string s[1004];\n    int mn = 1LL<<30;\n    \n    for(int i = 0;i < h;i++)cin >> s[i];\n    \n    for(int i = 0;i < (1 << (h-1));i++){\n        int sum = 0,a[100] = {};\n        for(int j = 0;j < h;j++){\n            a[j] = sum;\n            if(i & (1 << j))sum++;\n        }\n        sum++;\n        int num = __builtin_popcount(i),b[100] = {};\n        \n        //for(int p = 0;p < h;p++)b[p] = 0;\n        for(int p = 0;p < w;p++){\n            for(int q = 0;q < h;q++){\n                b[a[q]] += (s[q][p]-'0');\n            }\n            for(int q = 0;q < sum;q++){\n                if(b[q] > k){\n                    num++;\n                    for(int l = 0;l < sum;l++)b[l] = 0;\n                    for(int l = 0;l < h;l++)b[a[l]] += (s[l][p]-'0');\n                    break;\n                }\n            }\n            for(int l = 0;l < num;l++)if(b[l] > k)num = 1LL<<30;\n        }\n        mn = min(mn,num);\n    }\n    cout << mn << endl;\n}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nWe have a chocolate bar partitioned into H horizontal rows and W vertical columns of squares.\n\nThe square (i, j) at the i-th row from the top and the j-th column from the left is dark if S_{i,j} is 0, and white if S_{i,j} is 1.\n\nWe will cut the bar some number of times to divide it into some number of blocks. In each cut, we cut the whole bar by a line running along some boundaries of squares from end to end of the bar.\n\nHow many times do we need to cut the bar so that every block after the cuts has K or less white squares?\n\nConstraints\n\n1 \\leq H \\leq 10\n\n1 \\leq W \\leq 1000\n\n1 \\leq K \\leq H \\times W\n\nS_{i,j} is 0 or 1.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W K\nS_{1,1}S_{1,2}...S_{1,W}\n:\nS_{H,1}S_{H,2}...S_{H,W}\n\nOutput\n\nPrint the number of minimum times the bar needs to be cut so that every block after the cuts has K or less white squares.\n\nSample Input 1\n\n3 5 4\n11100\n10001\n00111\n\nSample Output 1\n\n2\n\nFor example, cutting between the 1-st and 2-nd rows and between the 3-rd and 4-th columns - as shown in the figure to the left - works.\n\nNote that we cannot cut the bar in the ways shown in the two figures to the right.\n\nSample Input 2\n\n3 5 8\n11100\n10001\n00111\n\nSample Output 2\n\n0\n\nNo cut is needed.\n\nSample Input 3\n\n4 10 4\n1110010010\n1000101110\n0011101001\n1101000111\n\nSample Output 3\n\n3", "sample_input": "3 5 4\n11100\n10001\n00111\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02733", "source_text": "Score : 500 points\n\nProblem Statement\n\nWe have a chocolate bar partitioned into H horizontal rows and W vertical columns of squares.\n\nThe square (i, j) at the i-th row from the top and the j-th column from the left is dark if S_{i,j} is 0, and white if S_{i,j} is 1.\n\nWe will cut the bar some number of times to divide it into some number of blocks. In each cut, we cut the whole bar by a line running along some boundaries of squares from end to end of the bar.\n\nHow many times do we need to cut the bar so that every block after the cuts has K or less white squares?\n\nConstraints\n\n1 \\leq H \\leq 10\n\n1 \\leq W \\leq 1000\n\n1 \\leq K \\leq H \\times W\n\nS_{i,j} is 0 or 1.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W K\nS_{1,1}S_{1,2}...S_{1,W}\n:\nS_{H,1}S_{H,2}...S_{H,W}\n\nOutput\n\nPrint the number of minimum times the bar needs to be cut so that every block after the cuts has K or less white squares.\n\nSample Input 1\n\n3 5 4\n11100\n10001\n00111\n\nSample Output 1\n\n2\n\nFor example, cutting between the 1-st and 2-nd rows and between the 3-rd and 4-th columns - as shown in the figure to the left - works.\n\nNote that we cannot cut the bar in the ways shown in the two figures to the right.\n\nSample Input 2\n\n3 5 8\n11100\n10001\n00111\n\nSample Output 2\n\n0\n\nNo cut is needed.\n\nSample Input 3\n\n4 10 4\n1110010010\n1000101110\n0011101001\n1101000111\n\nSample Output 3\n\n3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1164, "cpu_time_ms": 103, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s203990510", "group_id": "codeNet:p02733", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n#define FOR(i, a, b) for(int i=(a);i<(b);++i)\n#define rep(i, n) FOR(i, 0, n)\n#define whole(x) (x).begin(),(x).end()\n#define UNIQUE(v) v.erase(unique(v.begin(), v.end()), v.end())\nusing ll = long long;\nusing P = pair<int, int>;\nconst int mod = 1000000007;\nconst int INF = 1001001001;\nint sum[11][1005];\n\nint main(){\n    int h, w, k;\n    cin >> h >> w >> k;\n    vector<string> s(h);\n    rep(i, h) {\n        cin >> s[i];\n    }\n    rep(i, h) rep(j, w) {\n        sum[i][j+1] = sum[i][j] + (s[i][j]-'0');\n    }\n    \n    \n    int ans = INF;\n    rep(i, 1<<(h-1)) {\n        int res = __builtin_popcount(i);\n        int st = 0;\n        int temp = 0;\n        rep(j, w) rep(l, h) {\n            temp += (sum[l][j+1] - sum[l][st]);\n            if (i>>l&1 || l==h-1) {\n                if (temp>k) {\n                    st = j;\n                    res++;\n                    l = 0;\n                }\n                temp = 0;\n               \n            }\n        }\n        \n        ans = min(ans, res);\n    }\n    \n    \n    \n    cout << ans << endl;\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1584937948, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02733.html", "problem_id": "p02733", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02733/input.txt", "sample_output_relpath": "derived/input_output/data/p02733/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02733/C++/s203990510.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s203990510", "user_id": "u488493347"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n#define FOR(i, a, b) for(int i=(a);i<(b);++i)\n#define rep(i, n) FOR(i, 0, n)\n#define whole(x) (x).begin(),(x).end()\n#define UNIQUE(v) v.erase(unique(v.begin(), v.end()), v.end())\nusing ll = long long;\nusing P = pair<int, int>;\nconst int mod = 1000000007;\nconst int INF = 1001001001;\nint sum[11][1005];\n\nint main(){\n    int h, w, k;\n    cin >> h >> w >> k;\n    vector<string> s(h);\n    rep(i, h) {\n        cin >> s[i];\n    }\n    rep(i, h) rep(j, w) {\n        sum[i][j+1] = sum[i][j] + (s[i][j]-'0');\n    }\n    \n    \n    int ans = INF;\n    rep(i, 1<<(h-1)) {\n        int res = __builtin_popcount(i);\n        int st = 0;\n        int temp = 0;\n        rep(j, w) rep(l, h) {\n            temp += (sum[l][j+1] - sum[l][st]);\n            if (i>>l&1 || l==h-1) {\n                if (temp>k) {\n                    st = j;\n                    res++;\n                    l = 0;\n                }\n                temp = 0;\n               \n            }\n        }\n        \n        ans = min(ans, res);\n    }\n    \n    \n    \n    cout << ans << endl;\n    return 0;\n}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nWe have a chocolate bar partitioned into H horizontal rows and W vertical columns of squares.\n\nThe square (i, j) at the i-th row from the top and the j-th column from the left is dark if S_{i,j} is 0, and white if S_{i,j} is 1.\n\nWe will cut the bar some number of times to divide it into some number of blocks. In each cut, we cut the whole bar by a line running along some boundaries of squares from end to end of the bar.\n\nHow many times do we need to cut the bar so that every block after the cuts has K or less white squares?\n\nConstraints\n\n1 \\leq H \\leq 10\n\n1 \\leq W \\leq 1000\n\n1 \\leq K \\leq H \\times W\n\nS_{i,j} is 0 or 1.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W K\nS_{1,1}S_{1,2}...S_{1,W}\n:\nS_{H,1}S_{H,2}...S_{H,W}\n\nOutput\n\nPrint the number of minimum times the bar needs to be cut so that every block after the cuts has K or less white squares.\n\nSample Input 1\n\n3 5 4\n11100\n10001\n00111\n\nSample Output 1\n\n2\n\nFor example, cutting between the 1-st and 2-nd rows and between the 3-rd and 4-th columns - as shown in the figure to the left - works.\n\nNote that we cannot cut the bar in the ways shown in the two figures to the right.\n\nSample Input 2\n\n3 5 8\n11100\n10001\n00111\n\nSample Output 2\n\n0\n\nNo cut is needed.\n\nSample Input 3\n\n4 10 4\n1110010010\n1000101110\n0011101001\n1101000111\n\nSample Output 3\n\n3", "sample_input": "3 5 4\n11100\n10001\n00111\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02733", "source_text": "Score : 500 points\n\nProblem Statement\n\nWe have a chocolate bar partitioned into H horizontal rows and W vertical columns of squares.\n\nThe square (i, j) at the i-th row from the top and the j-th column from the left is dark if S_{i,j} is 0, and white if S_{i,j} is 1.\n\nWe will cut the bar some number of times to divide it into some number of blocks. In each cut, we cut the whole bar by a line running along some boundaries of squares from end to end of the bar.\n\nHow many times do we need to cut the bar so that every block after the cuts has K or less white squares?\n\nConstraints\n\n1 \\leq H \\leq 10\n\n1 \\leq W \\leq 1000\n\n1 \\leq K \\leq H \\times W\n\nS_{i,j} is 0 or 1.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W K\nS_{1,1}S_{1,2}...S_{1,W}\n:\nS_{H,1}S_{H,2}...S_{H,W}\n\nOutput\n\nPrint the number of minimum times the bar needs to be cut so that every block after the cuts has K or less white squares.\n\nSample Input 1\n\n3 5 4\n11100\n10001\n00111\n\nSample Output 1\n\n2\n\nFor example, cutting between the 1-st and 2-nd rows and between the 3-rd and 4-th columns - as shown in the figure to the left - works.\n\nNote that we cannot cut the bar in the ways shown in the two figures to the right.\n\nSample Input 2\n\n3 5 8\n11100\n10001\n00111\n\nSample Output 2\n\n0\n\nNo cut is needed.\n\nSample Input 3\n\n4 10 4\n1110010010\n1000101110\n0011101001\n1101000111\n\nSample Output 3\n\n3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1096, "cpu_time_ms": 2103, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s336135148", "group_id": "codeNet:p02735", "input_text": "#include<iostream>\n#include<cstring>\n#include<algorithm>\nusing namespace std;\nint main(){\n\tint h,w;\n\tcin>>h>>w;\n\tchar ptr[150][150];\n\tint dp[150][150];\n\tfor(int i=1;i<=h;i++){\n\t\tfor(int j=1;j<=w;j++){\n\t\t\tcin>>ptr[i][j];\n\t\t} \n\t}\n\tmemset(dp,0x3f,sizeof(dp));\n\tdp[1][1]=(ptr[1][1]=='#');\n\tfor(int i=1;i<=h;i++){\n\t\tfor(int j=1;j<=w;j++){\n\t\t\tif(ptr[i][j+1]=='.'){//下一步，代表不要变 \n\t\t\t\tdp[i][j+1]=min(dp[i][j+1],dp[i][j]); \n\t\t\t}else{//下一步代表要变 \n\t\t\t\tdp[i][j+1]=min(dp[i][j+1],dp[i][j]+(ptr[i][j]=='.')); \n\t\t\t}\n\t\t\tif(ptr[i+1][j]=='.'){//下一步代表不要变 \n\t\t\t\tdp[i+1][j]=min(dp[i+1][j],dp[i][j]);\n\t\t\t}else{//下一步代表要变 \n\t\t\t\tdp[i+1][j]=min(dp[i+1][j],dp[i][j]+(ptr[i][j]=='.'));\n\t\t\t}\n\t\t}\n\t}\n\tcout<<dp[h][w]<<endl;\n\treturn 0;\n} ", "language": "C++", "metadata": {"date": 1584912514, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02735.html", "problem_id": "p02735", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02735/input.txt", "sample_output_relpath": "derived/input_output/data/p02735/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02735/C++/s336135148.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s336135148", "user_id": "u501033825"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include<iostream>\n#include<cstring>\n#include<algorithm>\nusing namespace std;\nint main(){\n\tint h,w;\n\tcin>>h>>w;\n\tchar ptr[150][150];\n\tint dp[150][150];\n\tfor(int i=1;i<=h;i++){\n\t\tfor(int j=1;j<=w;j++){\n\t\t\tcin>>ptr[i][j];\n\t\t} \n\t}\n\tmemset(dp,0x3f,sizeof(dp));\n\tdp[1][1]=(ptr[1][1]=='#');\n\tfor(int i=1;i<=h;i++){\n\t\tfor(int j=1;j<=w;j++){\n\t\t\tif(ptr[i][j+1]=='.'){//下一步，代表不要变 \n\t\t\t\tdp[i][j+1]=min(dp[i][j+1],dp[i][j]); \n\t\t\t}else{//下一步代表要变 \n\t\t\t\tdp[i][j+1]=min(dp[i][j+1],dp[i][j]+(ptr[i][j]=='.')); \n\t\t\t}\n\t\t\tif(ptr[i+1][j]=='.'){//下一步代表不要变 \n\t\t\t\tdp[i+1][j]=min(dp[i+1][j],dp[i][j]);\n\t\t\t}else{//下一步代表要变 \n\t\t\t\tdp[i+1][j]=min(dp[i+1][j],dp[i][j]+(ptr[i][j]=='.'));\n\t\t\t}\n\t\t}\n\t}\n\tcout<<dp[h][w]<<endl;\n\treturn 0;\n} ", "problem_context": "Score : 400 points\n\nProblem Statement\n\nConsider a grid with H rows and W columns of squares. Let (r, c) denote the square at the r-th row from the top and the c-th column from the left.\nEach square is painted black or white.\n\nThe grid is said to be good if and only if the following condition is satisfied:\n\nFrom (1, 1), we can reach (H, W) by moving one square right or down repeatedly, while always being on a white square.\n\nNote that (1, 1) and (H, W) must be white if the grid is good.\n\nYour task is to make the grid good by repeating the operation below. Find the minimum number of operations needed to complete the task. It can be proved that you can always complete the task in a finite number of operations.\n\nChoose four integers r_0, c_0, r_1, c_1(1 \\leq r_0 \\leq r_1 \\leq H, 1 \\leq c_0 \\leq c_1 \\leq W). For each pair r, c (r_0 \\leq r \\leq r_1, c_0 \\leq c \\leq c_1), invert the color of (r, c) - that is, from white to black and vice versa.\n\nConstraints\n\n2 \\leq H, W \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W\ns_{11} s_{12} \\cdots s_{1W}\ns_{21} s_{22} \\cdots s_{2W}\n\\vdots\ns_{H1} s_{H2} \\cdots s_{HW}\n\nHere s_{rc} represents the color of (r, c) - # stands for black, and . stands for white.\n\nOutput\n\nPrint the minimum number of operations needed.\n\nSample Input 1\n\n3 3\n.##\n.#.\n##.\n\nSample Output 1\n\n1\n\nDo the operation with (r_0, c_0, r_1, c_1) = (2, 2, 2, 2) to change just the color of (2, 2), and we are done.\n\nSample Input 2\n\n2 2\n#.\n.#\n\nSample Output 2\n\n2\n\nSample Input 3\n\n4 4\n..##\n#...\n###.\n###.\n\nSample Output 3\n\n0\n\nNo operation may be needed.\n\nSample Input 4\n\n5 5\n.#.#.\n#.#.#\n.#.#.\n#.#.#\n.#.#.\n\nSample Output 4\n\n4", "sample_input": "3 3\n.##\n.#.\n##.\n"}, "reference_outputs": ["1\n"], "source_document_id": "p02735", "source_text": "Score : 400 points\n\nProblem Statement\n\nConsider a grid with H rows and W columns of squares. Let (r, c) denote the square at the r-th row from the top and the c-th column from the left.\nEach square is painted black or white.\n\nThe grid is said to be good if and only if the following condition is satisfied:\n\nFrom (1, 1), we can reach (H, W) by moving one square right or down repeatedly, while always being on a white square.\n\nNote that (1, 1) and (H, W) must be white if the grid is good.\n\nYour task is to make the grid good by repeating the operation below. Find the minimum number of operations needed to complete the task. It can be proved that you can always complete the task in a finite number of operations.\n\nChoose four integers r_0, c_0, r_1, c_1(1 \\leq r_0 \\leq r_1 \\leq H, 1 \\leq c_0 \\leq c_1 \\leq W). For each pair r, c (r_0 \\leq r \\leq r_1, c_0 \\leq c \\leq c_1), invert the color of (r, c) - that is, from white to black and vice versa.\n\nConstraints\n\n2 \\leq H, W \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W\ns_{11} s_{12} \\cdots s_{1W}\ns_{21} s_{22} \\cdots s_{2W}\n\\vdots\ns_{H1} s_{H2} \\cdots s_{HW}\n\nHere s_{rc} represents the color of (r, c) - # stands for black, and . stands for white.\n\nOutput\n\nPrint the minimum number of operations needed.\n\nSample Input 1\n\n3 3\n.##\n.#.\n##.\n\nSample Output 1\n\n1\n\nDo the operation with (r_0, c_0, r_1, c_1) = (2, 2, 2, 2) to change just the color of (2, 2), and we are done.\n\nSample Input 2\n\n2 2\n#.\n.#\n\nSample Output 2\n\n2\n\nSample Input 3\n\n4 4\n..##\n#...\n###.\n###.\n\nSample Output 3\n\n0\n\nNo operation may be needed.\n\nSample Input 4\n\n5 5\n.#.#.\n#.#.#\n.#.#.\n#.#.#\n.#.#.\n\nSample Output 4\n\n4", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 762, "cpu_time_ms": 2, "memory_kb": 384}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s223220013", "group_id": "codeNet:p02735", "input_text": "#include <bits/stdc++.h>\n#include <unistd.h>\n#include <sys/time.h>\n#include <stdlib.h>\n \nusing namespace std;\n \ntypedef long long ll;\ntypedef pair<ll,ll> P;\ntypedef pair<P, ll> T;\n \nlong long int INF = 1e18;\nconst ll fact_table = 800008;\ndouble Pi = 3.1415926535897932384626;\n\npriority_queue <ll> pql;\npriority_queue <P> pqp;\npriority_queue <P> bag;\n//big priority queue\npriority_queue <ll,vector<ll>,greater<ll> > pqls;\npriority_queue <P,vector<P>,greater<P> > pqps;\n//small priority queue\n//top pop\n \nll dx[8]={1,0,-1,0,1,1,-1,-1};\nll dy[8]={0,1,0,-1,1,-1,-1,1};\nchar dir[] = \"DRUL\";\n//↓,→,↑,←\n \n \n#define p(x) cout<<x<<\"\\n\";\n#define el cout<<endl;\n#define pe(x) cout<<(x)<<\" \";\n#define ps(x) cout<<fixed<<setprecision(25)<<x<<endl;\n#define pu(x) cout<<(x);\n#define pb push_back\n// #define lb lower_bound\n#define ub upper_bound\n#define CLEAR(a) a = decltype(a)(); \n#define pc(x) cout << x << \",\";\n \n \nll mod = 998244353;\n// ll mod = 1000000007;\n  \nll mypow(ll number1,ll number2, ll mod){\n \n    if(number2 == 0){\n        return 1;\n    }else{\n        ll number3 = mypow(number1,number2 / 2, mod);\n        number3 *= number3;\n        number3 %= mod;\n        if(number2%2==1){\n            number3 *= number1;\n            number3 %= mod;\n        }\n        return number3;\n    }\n}\nll rui(ll number1,ll number2){\n \n    if(number2 == 0){\n        return 1;\n    }else{\n        ll number3 = rui(number1,number2 / 2);\n        number3 *= number3;\n        number3 %= mod;\n        if(number2%2==1){\n            number3 *= number1;\n            number3 %= mod;\n        }\n        return number3;\n    }\n}\nll gcd(ll number1,ll number2){\n \n    if(number1 > number2){\n        swap(number1,number2);\n    }\n    if(number1 == 0 || number1 == number2){\n        return number2;\n    }else{\n        return gcd(number2 % number1,number1);\n    }\n}\nvoid YES(bool condition){\n \n    if(condition){\n        p(\"YES\");\n    }else{\n        p(\"NO\");\n    }\n    return;\n}\nvoid Yes(bool condition){\n \n    if(condition){\n        p(\"Yes\");\n    }else{\n        p(\"No\");\n    }\n    return;\n}\n \n/*\nll fact[fact_table + 5],rfact[fact_table + 5];\n \n \nvoid c3_init(){\n    fact[0] = rfact[0] = 1;\n    for(ll i=1; i<=fact_table; i++){\n        fact[i] = (fact[i-1]*i) % mod;\n    }\n    rfact[fact_table] = rui(fact[fact_table],mod - 2);\n    for(ll i=fact_table; i>=1; i--){\n       rfact[i-1] = rfact[i] * i;\n       rfact[i-1] %= mod;\n    }\n    return;}\nll c3(ll n,ll r){\n    return (((fact[n] * rfact[r]) % mod ) * rfact[n-r]) % mod;}\n*/\nbool multicase = false;\n\nll n,m,num,sum,a,b,c,d,e,h,q,p;\nll w, ans;\nll k;\nchar s[105][105];\nvector<P> G[500005];\nll cost[100005];\n\nvoid solve(){\n    cin >> h >> w;\n    for(ll i=0;i<h;i++){\n        cin >> s[i];\n    }\n    for(ll i=0;i<h;i++){\n        for(ll j=0;j<w;j++){\n            ll x = i, y = j;\n            for(ll k=0;k<2;k++){\n                ll nx = i + dx[k], ny = j + dy[k];\n                if(nx < 0 || ny < 0 || nx >= h || ny >= w)continue;\n                ll fromid = i * w + j;\n                ll toid = nx * w + ny;\n                if(s[x][y] == s[nx][ny]){\n                    G[fromid].pb(P(toid, 0));\n                }else{\n                    G[fromid].pb(P(toid, 1));\n                }\n            }\n        }\n    }\n    ll c1 = 0, c2 = 0;\n    if(s[0][0] == '#')c1++;\n    if(s[h-1][w-1] == '#')c2++;\n    G[h*w].pb(P(0, c1));\n    G[h*w-1].pb(P(h*w+1, c2));\n    for(ll i=0;i<h*w+10;i++){\n        cost[i] = INF;\n    }\n    cost[h*w] = 0;\n    pqps.push(P(0, h*w));\n    while(!pqps.empty()){\n        P p = pqps.top();\n        pqps.pop();\n        ll v = p.second;\n        ll nowcost = p.first;\n        if(nowcost > cost[v])continue;\n        for(ll i=0;i<G[v].size();i++){\n            ll nv = G[v][i].first;\n            ll newcost = cost[v] + G[v][i].second;\n            if(cost[nv] > newcost){\n                cost[nv] = newcost;\n                pqps.push(P(newcost, nv));\n            }\n\n        }\n    }\n    ll ans = cost[h*w+1];\n    p(ans / 2);\n    return;\n}\n\nint main(){\n    // init();\n    ios::sync_with_stdio(false);\n    cin.tie(nullptr);\n    ll q;\n    if(multicase){\n        cin >> q;\n    }else{\n        q = 1;\n    }\n    while(q--){\n        solve();\n    }\n    return 0;\n\n}\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n", "language": "C++", "metadata": {"date": 1584840602, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02735.html", "problem_id": "p02735", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02735/input.txt", "sample_output_relpath": "derived/input_output/data/p02735/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02735/C++/s223220013.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s223220013", "user_id": "u399527088"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#include <unistd.h>\n#include <sys/time.h>\n#include <stdlib.h>\n \nusing namespace std;\n \ntypedef long long ll;\ntypedef pair<ll,ll> P;\ntypedef pair<P, ll> T;\n \nlong long int INF = 1e18;\nconst ll fact_table = 800008;\ndouble Pi = 3.1415926535897932384626;\n\npriority_queue <ll> pql;\npriority_queue <P> pqp;\npriority_queue <P> bag;\n//big priority queue\npriority_queue <ll,vector<ll>,greater<ll> > pqls;\npriority_queue <P,vector<P>,greater<P> > pqps;\n//small priority queue\n//top pop\n \nll dx[8]={1,0,-1,0,1,1,-1,-1};\nll dy[8]={0,1,0,-1,1,-1,-1,1};\nchar dir[] = \"DRUL\";\n//↓,→,↑,←\n \n \n#define p(x) cout<<x<<\"\\n\";\n#define el cout<<endl;\n#define pe(x) cout<<(x)<<\" \";\n#define ps(x) cout<<fixed<<setprecision(25)<<x<<endl;\n#define pu(x) cout<<(x);\n#define pb push_back\n// #define lb lower_bound\n#define ub upper_bound\n#define CLEAR(a) a = decltype(a)(); \n#define pc(x) cout << x << \",\";\n \n \nll mod = 998244353;\n// ll mod = 1000000007;\n  \nll mypow(ll number1,ll number2, ll mod){\n \n    if(number2 == 0){\n        return 1;\n    }else{\n        ll number3 = mypow(number1,number2 / 2, mod);\n        number3 *= number3;\n        number3 %= mod;\n        if(number2%2==1){\n            number3 *= number1;\n            number3 %= mod;\n        }\n        return number3;\n    }\n}\nll rui(ll number1,ll number2){\n \n    if(number2 == 0){\n        return 1;\n    }else{\n        ll number3 = rui(number1,number2 / 2);\n        number3 *= number3;\n        number3 %= mod;\n        if(number2%2==1){\n            number3 *= number1;\n            number3 %= mod;\n        }\n        return number3;\n    }\n}\nll gcd(ll number1,ll number2){\n \n    if(number1 > number2){\n        swap(number1,number2);\n    }\n    if(number1 == 0 || number1 == number2){\n        return number2;\n    }else{\n        return gcd(number2 % number1,number1);\n    }\n}\nvoid YES(bool condition){\n \n    if(condition){\n        p(\"YES\");\n    }else{\n        p(\"NO\");\n    }\n    return;\n}\nvoid Yes(bool condition){\n \n    if(condition){\n        p(\"Yes\");\n    }else{\n        p(\"No\");\n    }\n    return;\n}\n \n/*\nll fact[fact_table + 5],rfact[fact_table + 5];\n \n \nvoid c3_init(){\n    fact[0] = rfact[0] = 1;\n    for(ll i=1; i<=fact_table; i++){\n        fact[i] = (fact[i-1]*i) % mod;\n    }\n    rfact[fact_table] = rui(fact[fact_table],mod - 2);\n    for(ll i=fact_table; i>=1; i--){\n       rfact[i-1] = rfact[i] * i;\n       rfact[i-1] %= mod;\n    }\n    return;}\nll c3(ll n,ll r){\n    return (((fact[n] * rfact[r]) % mod ) * rfact[n-r]) % mod;}\n*/\nbool multicase = false;\n\nll n,m,num,sum,a,b,c,d,e,h,q,p;\nll w, ans;\nll k;\nchar s[105][105];\nvector<P> G[500005];\nll cost[100005];\n\nvoid solve(){\n    cin >> h >> w;\n    for(ll i=0;i<h;i++){\n        cin >> s[i];\n    }\n    for(ll i=0;i<h;i++){\n        for(ll j=0;j<w;j++){\n            ll x = i, y = j;\n            for(ll k=0;k<2;k++){\n                ll nx = i + dx[k], ny = j + dy[k];\n                if(nx < 0 || ny < 0 || nx >= h || ny >= w)continue;\n                ll fromid = i * w + j;\n                ll toid = nx * w + ny;\n                if(s[x][y] == s[nx][ny]){\n                    G[fromid].pb(P(toid, 0));\n                }else{\n                    G[fromid].pb(P(toid, 1));\n                }\n            }\n        }\n    }\n    ll c1 = 0, c2 = 0;\n    if(s[0][0] == '#')c1++;\n    if(s[h-1][w-1] == '#')c2++;\n    G[h*w].pb(P(0, c1));\n    G[h*w-1].pb(P(h*w+1, c2));\n    for(ll i=0;i<h*w+10;i++){\n        cost[i] = INF;\n    }\n    cost[h*w] = 0;\n    pqps.push(P(0, h*w));\n    while(!pqps.empty()){\n        P p = pqps.top();\n        pqps.pop();\n        ll v = p.second;\n        ll nowcost = p.first;\n        if(nowcost > cost[v])continue;\n        for(ll i=0;i<G[v].size();i++){\n            ll nv = G[v][i].first;\n            ll newcost = cost[v] + G[v][i].second;\n            if(cost[nv] > newcost){\n                cost[nv] = newcost;\n                pqps.push(P(newcost, nv));\n            }\n\n        }\n    }\n    ll ans = cost[h*w+1];\n    p(ans / 2);\n    return;\n}\n\nint main(){\n    // init();\n    ios::sync_with_stdio(false);\n    cin.tie(nullptr);\n    ll q;\n    if(multicase){\n        cin >> q;\n    }else{\n        q = 1;\n    }\n    while(q--){\n        solve();\n    }\n    return 0;\n\n}\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nConsider a grid with H rows and W columns of squares. Let (r, c) denote the square at the r-th row from the top and the c-th column from the left.\nEach square is painted black or white.\n\nThe grid is said to be good if and only if the following condition is satisfied:\n\nFrom (1, 1), we can reach (H, W) by moving one square right or down repeatedly, while always being on a white square.\n\nNote that (1, 1) and (H, W) must be white if the grid is good.\n\nYour task is to make the grid good by repeating the operation below. Find the minimum number of operations needed to complete the task. It can be proved that you can always complete the task in a finite number of operations.\n\nChoose four integers r_0, c_0, r_1, c_1(1 \\leq r_0 \\leq r_1 \\leq H, 1 \\leq c_0 \\leq c_1 \\leq W). For each pair r, c (r_0 \\leq r \\leq r_1, c_0 \\leq c \\leq c_1), invert the color of (r, c) - that is, from white to black and vice versa.\n\nConstraints\n\n2 \\leq H, W \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W\ns_{11} s_{12} \\cdots s_{1W}\ns_{21} s_{22} \\cdots s_{2W}\n\\vdots\ns_{H1} s_{H2} \\cdots s_{HW}\n\nHere s_{rc} represents the color of (r, c) - # stands for black, and . stands for white.\n\nOutput\n\nPrint the minimum number of operations needed.\n\nSample Input 1\n\n3 3\n.##\n.#.\n##.\n\nSample Output 1\n\n1\n\nDo the operation with (r_0, c_0, r_1, c_1) = (2, 2, 2, 2) to change just the color of (2, 2), and we are done.\n\nSample Input 2\n\n2 2\n#.\n.#\n\nSample Output 2\n\n2\n\nSample Input 3\n\n4 4\n..##\n#...\n###.\n###.\n\nSample Output 3\n\n0\n\nNo operation may be needed.\n\nSample Input 4\n\n5 5\n.#.#.\n#.#.#\n.#.#.\n#.#.#\n.#.#.\n\nSample Output 4\n\n4", "sample_input": "3 3\n.##\n.#.\n##.\n"}, "reference_outputs": ["1\n"], "source_document_id": "p02735", "source_text": "Score : 400 points\n\nProblem Statement\n\nConsider a grid with H rows and W columns of squares. Let (r, c) denote the square at the r-th row from the top and the c-th column from the left.\nEach square is painted black or white.\n\nThe grid is said to be good if and only if the following condition is satisfied:\n\nFrom (1, 1), we can reach (H, W) by moving one square right or down repeatedly, while always being on a white square.\n\nNote that (1, 1) and (H, W) must be white if the grid is good.\n\nYour task is to make the grid good by repeating the operation below. Find the minimum number of operations needed to complete the task. It can be proved that you can always complete the task in a finite number of operations.\n\nChoose four integers r_0, c_0, r_1, c_1(1 \\leq r_0 \\leq r_1 \\leq H, 1 \\leq c_0 \\leq c_1 \\leq W). For each pair r, c (r_0 \\leq r \\leq r_1, c_0 \\leq c \\leq c_1), invert the color of (r, c) - that is, from white to black and vice versa.\n\nConstraints\n\n2 \\leq H, W \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W\ns_{11} s_{12} \\cdots s_{1W}\ns_{21} s_{22} \\cdots s_{2W}\n\\vdots\ns_{H1} s_{H2} \\cdots s_{HW}\n\nHere s_{rc} represents the color of (r, c) - # stands for black, and . stands for white.\n\nOutput\n\nPrint the minimum number of operations needed.\n\nSample Input 1\n\n3 3\n.##\n.#.\n##.\n\nSample Output 1\n\n1\n\nDo the operation with (r_0, c_0, r_1, c_1) = (2, 2, 2, 2) to change just the color of (2, 2), and we are done.\n\nSample Input 2\n\n2 2\n#.\n.#\n\nSample Output 2\n\n2\n\nSample Input 3\n\n4 4\n..##\n#...\n###.\n###.\n\nSample Output 3\n\n0\n\nNo operation may be needed.\n\nSample Input 4\n\n5 5\n.#.#.\n#.#.#\n.#.#.\n#.#.#\n.#.#.\n\nSample Output 4\n\n4", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 4196, "cpu_time_ms": 7, "memory_kb": 12544}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s631694037", "group_id": "codeNet:p02736", "input_text": "#include<bits/stdc++.h>\n#define Tp template<typename Ty>\n#define Ts template<typename Ty,typename... Ar>\n#define Reg register\n#define RI Reg int\n#define Con const\n#define CI Con int&\n#define I inline\n#define W while\n#define N 1000000\nusing namespace std;\nint n,a[N+5];char s[N+5];\nint main()\n{\n\tRI i;for(scanf(\"%d%s\",&n,s),--n,i=0;i^n;++i) a[i]=abs(s[i]-s[i+1]);\n\tRI f=1;for(i=0;i^n;++i) if(a[i]==1) {f=0;break;}\n\tfor(i=0;i^n;++i) a[i]==2&&(a[i]=f);\n\tRI ans=0;for(i=0;i^n;++i) (((n-1)^i)==(n-1)-i)&&(ans^=a[i]);\n\treturn printf(\"%d\",ans*(f+1)),0;\n}", "language": "C++", "metadata": {"date": 1589767076, "filename_ext": "cpp", "original_language": "C++ (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02736.html", "problem_id": "p02736", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02736/input.txt", "sample_output_relpath": "derived/input_output/data/p02736/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02736/C++/s631694037.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s631694037", "user_id": "u752711517"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include<bits/stdc++.h>\n#define Tp template<typename Ty>\n#define Ts template<typename Ty,typename... Ar>\n#define Reg register\n#define RI Reg int\n#define Con const\n#define CI Con int&\n#define I inline\n#define W while\n#define N 1000000\nusing namespace std;\nint n,a[N+5];char s[N+5];\nint main()\n{\n\tRI i;for(scanf(\"%d%s\",&n,s),--n,i=0;i^n;++i) a[i]=abs(s[i]-s[i+1]);\n\tRI f=1;for(i=0;i^n;++i) if(a[i]==1) {f=0;break;}\n\tfor(i=0;i^n;++i) a[i]==2&&(a[i]=f);\n\tRI ans=0;for(i=0;i^n;++i) (((n-1)^i)==(n-1)-i)&&(ans^=a[i]);\n\treturn printf(\"%d\",ans*(f+1)),0;\n}", "problem_context": "Score : 700 points\n\nProblem Statement\n\nGiven is a sequence of N digits a_1a_2\\ldots a_N, where each element is 1, 2, or 3.\nLet x_{i,j} defined as follows:\n\nx_{1,j} := a_j \\quad (1 \\leq j \\leq N)\n\nx_{i,j} := | x_{i-1,j} - x_{i-1,j+1} | \\quad (2 \\leq i \\leq N and 1 \\leq j \\leq N+1-i)\n\nFind x_{N,1}.\n\nConstraints\n\n2 \\leq N \\leq 10^6\n\na_i = 1,2,3 (1 \\leq i \\leq N)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1a_2\\ldotsa_N\n\nOutput\n\nPrint x_{N,1}.\n\nSample Input 1\n\n4\n1231\n\nSample Output 1\n\n1\n\nx_{1,1},x_{1,2},x_{1,3},x_{1,4} are respectively 1,2,3,1.\n\nx_{2,1},x_{2,2},x_{2,3} are respectively |1-2| = 1,|2-3| = 1,|3-1| = 2.\n\nx_{3,1},x_{3,2} are respectively |1-1| = 0,|1-2| = 1.\n\nFinally, x_{4,1} = |0-1| = 1, so the answer is 1.\n\nSample Input 2\n\n10\n2311312312\n\nSample Output 2\n\n0", "sample_input": "4\n1231\n"}, "reference_outputs": ["1\n"], "source_document_id": "p02736", "source_text": "Score : 700 points\n\nProblem Statement\n\nGiven is a sequence of N digits a_1a_2\\ldots a_N, where each element is 1, 2, or 3.\nLet x_{i,j} defined as follows:\n\nx_{1,j} := a_j \\quad (1 \\leq j \\leq N)\n\nx_{i,j} := | x_{i-1,j} - x_{i-1,j+1} | \\quad (2 \\leq i \\leq N and 1 \\leq j \\leq N+1-i)\n\nFind x_{N,1}.\n\nConstraints\n\n2 \\leq N \\leq 10^6\n\na_i = 1,2,3 (1 \\leq i \\leq N)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1a_2\\ldotsa_N\n\nOutput\n\nPrint x_{N,1}.\n\nSample Input 1\n\n4\n1231\n\nSample Output 1\n\n1\n\nx_{1,1},x_{1,2},x_{1,3},x_{1,4} are respectively 1,2,3,1.\n\nx_{2,1},x_{2,2},x_{2,3} are respectively |1-2| = 1,|2-3| = 1,|3-1| = 2.\n\nx_{3,1},x_{3,2} are respectively |1-1| = 0,|1-2| = 1.\n\nFinally, x_{4,1} = |0-1| = 1, so the answer is 1.\n\nSample Input 2\n\n10\n2311312312\n\nSample Output 2\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 547, "cpu_time_ms": 12, "memory_kb": 5120}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s765853104", "group_id": "codeNet:p02742", "input_text": "#include <iostream>\nusing namespace std;\n\nint main() {\n\tlong long h,w;cin >>h>>w;\n\tlong long out =1;\n\tif(h>1 && w>1){\n\t\tout= (h/2 + h%2)*(w/2 + w%2) + (h/2)*(w/2);\n\t}\n\tcout << out << endl;\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1587833967, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02742.html", "problem_id": "p02742", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02742/input.txt", "sample_output_relpath": "derived/input_output/data/p02742/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02742/C++/s765853104.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s765853104", "user_id": "u960687982"}, "prompt_components": {"gold_output": "10\n", "input_to_evaluate": "#include <iostream>\nusing namespace std;\n\nint main() {\n\tlong long h,w;cin >>h>>w;\n\tlong long out =1;\n\tif(h>1 && w>1){\n\t\tout= (h/2 + h%2)*(w/2 + w%2) + (h/2)*(w/2);\n\t}\n\tcout << out << endl;\n\treturn 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nWe have a board with H horizontal rows and W vertical columns of squares.\nThere is a bishop at the top-left square on this board.\nHow many squares can this bishop reach by zero or more movements?\n\nHere the bishop can only move diagonally.\nMore formally, the bishop can move from the square at the r_1-th row (from the top) and the c_1-th column (from the left) to the square at the r_2-th row and the c_2-th column if and only if exactly one of the following holds:\n\nr_1 + c_1 = r_2 + c_2\n\nr_1 - c_1 = r_2 - c_2\n\nFor example, in the following figure, the bishop can move to any of the red squares in one move:\n\nConstraints\n\n1 \\leq H, W \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH \\ W\n\nOutput\n\nPrint the number of squares the bishop can reach.\n\nSample Input 1\n\n4 5\n\nSample Output 1\n\n10\n\nThe bishop can reach the cyan squares in the following figure:\n\nSample Input 2\n\n7 3\n\nSample Output 2\n\n11\n\nThe bishop can reach the cyan squares in the following figure:\n\nSample Input 3\n\n1000000000 1000000000\n\nSample Output 3\n\n500000000000000000", "sample_input": "4 5\n"}, "reference_outputs": ["10\n"], "source_document_id": "p02742", "source_text": "Score : 200 points\n\nProblem Statement\n\nWe have a board with H horizontal rows and W vertical columns of squares.\nThere is a bishop at the top-left square on this board.\nHow many squares can this bishop reach by zero or more movements?\n\nHere the bishop can only move diagonally.\nMore formally, the bishop can move from the square at the r_1-th row (from the top) and the c_1-th column (from the left) to the square at the r_2-th row and the c_2-th column if and only if exactly one of the following holds:\n\nr_1 + c_1 = r_2 + c_2\n\nr_1 - c_1 = r_2 - c_2\n\nFor example, in the following figure, the bishop can move to any of the red squares in one move:\n\nConstraints\n\n1 \\leq H, W \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH \\ W\n\nOutput\n\nPrint the number of squares the bishop can reach.\n\nSample Input 1\n\n4 5\n\nSample Output 1\n\n10\n\nThe bishop can reach the cyan squares in the following figure:\n\nSample Input 2\n\n7 3\n\nSample Output 2\n\n11\n\nThe bishop can reach the cyan squares in the following figure:\n\nSample Input 3\n\n1000000000 1000000000\n\nSample Output 3\n\n500000000000000000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 201, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s785850610", "group_id": "codeNet:p02742", "input_text": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n\nint main() {\n  long long H, W;\n  cin >> H >> W;\n  double ans = ((H+1)/2)*((W+1)/2)+(H/2)*(W/2);\n  cout << long(ans) << endl;\n}\n", "language": "C++", "metadata": {"date": 1584237141, "filename_ext": "cpp", "original_language": "C++14 (Clang 3.8.0)", "problem_description_relpath": "problem_descriptions/p02742.html", "problem_id": "p02742", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02742/input.txt", "sample_output_relpath": "derived/input_output/data/p02742/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02742/C++/s785850610.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s785850610", "user_id": "u748503010"}, "prompt_components": {"gold_output": "10\n", "input_to_evaluate": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n\nint main() {\n  long long H, W;\n  cin >> H >> W;\n  double ans = ((H+1)/2)*((W+1)/2)+(H/2)*(W/2);\n  cout << long(ans) << endl;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nWe have a board with H horizontal rows and W vertical columns of squares.\nThere is a bishop at the top-left square on this board.\nHow many squares can this bishop reach by zero or more movements?\n\nHere the bishop can only move diagonally.\nMore formally, the bishop can move from the square at the r_1-th row (from the top) and the c_1-th column (from the left) to the square at the r_2-th row and the c_2-th column if and only if exactly one of the following holds:\n\nr_1 + c_1 = r_2 + c_2\n\nr_1 - c_1 = r_2 - c_2\n\nFor example, in the following figure, the bishop can move to any of the red squares in one move:\n\nConstraints\n\n1 \\leq H, W \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH \\ W\n\nOutput\n\nPrint the number of squares the bishop can reach.\n\nSample Input 1\n\n4 5\n\nSample Output 1\n\n10\n\nThe bishop can reach the cyan squares in the following figure:\n\nSample Input 2\n\n7 3\n\nSample Output 2\n\n11\n\nThe bishop can reach the cyan squares in the following figure:\n\nSample Input 3\n\n1000000000 1000000000\n\nSample Output 3\n\n500000000000000000", "sample_input": "4 5\n"}, "reference_outputs": ["10\n"], "source_document_id": "p02742", "source_text": "Score : 200 points\n\nProblem Statement\n\nWe have a board with H horizontal rows and W vertical columns of squares.\nThere is a bishop at the top-left square on this board.\nHow many squares can this bishop reach by zero or more movements?\n\nHere the bishop can only move diagonally.\nMore formally, the bishop can move from the square at the r_1-th row (from the top) and the c_1-th column (from the left) to the square at the r_2-th row and the c_2-th column if and only if exactly one of the following holds:\n\nr_1 + c_1 = r_2 + c_2\n\nr_1 - c_1 = r_2 - c_2\n\nFor example, in the following figure, the bishop can move to any of the red squares in one move:\n\nConstraints\n\n1 \\leq H, W \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH \\ W\n\nOutput\n\nPrint the number of squares the bishop can reach.\n\nSample Input 1\n\n4 5\n\nSample Output 1\n\n10\n\nThe bishop can reach the cyan squares in the following figure:\n\nSample Input 2\n\n7 3\n\nSample Output 2\n\n11\n\nThe bishop can reach the cyan squares in the following figure:\n\nSample Input 3\n\n1000000000 1000000000\n\nSample Output 3\n\n500000000000000000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 190, "cpu_time_ms": 11, "memory_kb": 888}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s088392844", "group_id": "codeNet:p02742", "input_text": "#include <bits/stdc++.h>\n//上記が使用不可な環境において\n/*\n#include <iostream> // cout, endl, cin\n#include <string> // string, to_string, stoi\n#include <iomanip>  //setprecsion\n#include <vector> // vector\n#include <algorithm> // min, max, swap, sort, reverse, lower_bound, upper_bound\n#include <utility> // pair, make_pair\n#include <cmath>  //sin, cos, tan\n#include <tuple> // tuple, make_tuple\n#include <cstdint> // int64_t, int*_t\n#include <cstdio> // printf\n#include <map> // map\n#include <queue> // queue, priority_queue\n#include <set> // set\n#include <stack> // stack\n#include <deque> // deque\n#include <unordered_map> // unordered_map\n#include <unordered_set> // unordered_set\n#include <bitset> // bitset\n#include <cctype> // isupper, islower, isdigit, toupper, tolower\n#include <cstdlib>\n#include <cstring>\n#include <numeric>\n#include <complex>\n#include <bitset>\n#include <utility>\n#include <functional>\n*/\nusing namespace std;\n\ntypedef long long int ll;\ntypedef long long int lli;\ntypedef unsigned long long int ull;\ntypedef long double ld;\ntypedef string str;\ntypedef vector<char> vc;\ntypedef vector<bool> vb;\ntypedef vector<ld> vd;\ntypedef vector<str> vs;\ntypedef vector<ll> vll;\ntypedef vector<pair<ll, ll>> vpll;\ntypedef vector<vector<ll>> vvll;\ntypedef vector<vector<char>> vvc;\ntypedef vector<vector<str>> vvs;\nconst ld PI = acos(-1.0);\nconst ll MAX = 9000000000000000000;\nconst ll MIN = -9000000000000000000;\nconst ld DMAX = 4500;\nconst ld DMIN = -4500;\n\n//謎\nconst int INF = INT_MAX;\nconst ll LLINF = 1LL << 60;\nconst ll MOD = 1000000007;\nconst ld EPS = 1e-9;\nll dx[8] = {1, 0, -1, 0, 1, -1, -1, 1};\nll dy[8] = {0, 1, 0, -1, 1, 1, -1, -1};\n\n//0~nの範囲操作\n#define rep(i, n) for (ll i = 0; i < (n); ++i)\n//1~nの範囲操作\n#define rrep(i, n) for (ll i = 1; i <= (n); ++i)\n#define irep(it, stl) for (auto it = stl.begin(); it != stl.end(); it++)\n#define drep(i, n) for (ll i = (n)-1; i >= 0; --i)\n//出力後改行を\n#define fin(ans) cout << (ans) << endl;\n//出力後空白を\n#define blank(ans) cout << (ans) << \" \";\n#define mp(p, q) make_pair(p, q)\n#define pb(n) push_back(n)\n//配列全操作\n#define all(a) a.begin(), a.end()\n\n//配列の合計\ntemplate <typename T>\nT Sum(vector<T> n, ll a = 0, ll b = 0)\n{\n  if (b == 0)\n  {\n    return (accumulate(n.begin() + a, n.end(), 0));\n  }\n  else\n  {\n    return (accumulate(n.begin() + a, n.begin() + b, 0));\n  }\n}\ntemplate <>\nld Sum(vector<ld> n, ll a, ll b)\n{\n  if (b == 0)\n  {\n    return (accumulate(n.begin() + a, n.end(), 0));\n  }\n  else\n  {\n    return (accumulate(n.begin() + a, n.begin() + b, 0));\n  }\n}\n//配列を昇順\ntemplate <typename T>\nvoid Sort(T &n, ll a = 0, ll b = 0)\n{\n  if (b == 0)\n  {\n    return (sort(n.begin() + a, n.end()));\n  }\n  else\n  {\n    return (sort(n.begin() + a, n.begin() + b));\n  }\n}\n//配列を降順\ntemplate <typename T>\nvoid Reve(T &n, ll a = 0, ll b = 0)\n{\n  if (b == 0)\n  {\n    return (reverse(n.begin() + a, n.end()));\n  }\n  else\n  {\n    return (reverse(n.begin() + a, n.begin() + b));\n  }\n}\n//配列nをmにコピー\ntemplate <typename T, typename U>\nvoid Copy(T &n, U &m, ll a = 0, ll b = 0)\n{\n  copy(all(n), m.begin());\n}\n//小数点型に\ntemplate <typename T>\nld Cast(T n)\n{\n  return static_cast<ld>(n);\n}\n//配列入力\ntemplate <typename T>\nvoid V(T &n)\n{\n  for (ll i = 0; i < n.size(); i++)\n  {\n    cin >> n[i];\n  }\n}\n//２列配列入力\ntemplate <typename T, typename U>\nvoid V2(T &n, U &m)\n{\n  for (ll i = 0; i < n.size(); i++)\n  {\n    cin >> n[i] >> m[i];\n  }\n}\n//３列配列入力\ntemplate <typename T, typename U, typename W>\nvoid V3(T &n, U &m, W &p)\n{\n  for (ll i = 0; i < n.size(); i++)\n  {\n    cin >> n[i] >> m[i] >> p[i];\n  }\n}\n//yes, noと表示\nvoid yn(bool a)\n{\n  if (a)\n    cout << \"yes\" << endl;\n  else\n    cout << \"no\" << endl;\n}\n//Yes, Noと表示\nvoid Yn(bool a)\n{\n  if (a)\n    cout << \"Yes\" << endl;\n  else\n    cout << \"No\" << endl;\n}\n//YES, NOと表示\nvoid YN(bool a)\n{\n  if (a)\n    cout << \"YES\" << endl;\n  else\n    cout << \"NO\" << endl;\n}\n//yes, noと表示後終了\nvoid fyn(bool a)\n{\n  if (a)\n    cout << \"yes\" << endl;\n  else\n    cout << \"no\" << endl;\n  exit(0);\n}\n//Yes, Noと表示後終了\nvoid fYn(bool a)\n{\n  if (a)\n    cout << \"Yes\" << endl;\n  else\n    cout << \"No\" << endl;\n  exit(0);\n}\n//YES, NOと表示後終了\nvoid fYN(bool a)\n{\n  if (a)\n    cout << \"YES\" << endl;\n  else\n    cout << \"NO\" << endl;\n  exit(0);\n}\n//AC, WAと表示\nvoid AC(bool a)\n{\n  if (a)\n    cout << \"AC\" << endl;\n  else\n    cout << \"WA\" << endl;\n}\n//AC, WAと表示後終了\nvoid fAC(bool a)\n{\n  if (a)\n    cout << \"AC\" << endl;\n  else\n    cout << \"WA\" << endl;\n  exit(0);\n}\n//noneと表示後終了\nvoid fnone(void)\n{\n  cout << \"None\" << endl;\n  exit(0);\n}\n//Odd(奇数), Even(偶数)と表示後終了\nvoid fOdd(bool a)\n{\n  if (a)\n    cout << \"Odd\" << endl;\n  else\n    cout << \"Even\" << endl;\n  exit(0);\n}\n//Possible, Impossibleと表示後終了\nvoid Possible(bool a)\n{\n  if (a)\n    cout << \"Possible\" << endl;\n  else\n    cout << \"Impossible\" << endl;\n  exit(0);\n}\n//POSSIBLE, IMPOSSIBLEと表示後終了\nvoid POSSIBLE(bool a)\n{\n  if (a)\n    cout << \"POSSIBLE\" << endl;\n  else\n    cout << \"IMPOSSIBLE\" << endl;\n  exit(0);\n}\n//四角　表示文字 a 縦幅 h 横幅 w\nvoid square(char a, ll h, ll w)\n{\n  for (ll i = 0; i < h; i++)\n  {\n    for (ll j = 0; j < w; j++)\n    {\n      cout << a;\n    }\n    cout << endl;\n  }\n}\n//四角枠　外周 a 中身 b 縦幅 h 横幅 w\nvoid yoke(char a, char b, ll h, ll w)\n{\n  for (ll i = 0; i < h; i++)\n  {\n    for (ll j = 0; j < w; j++)\n    {\n      if (i == 0 || i == h - 1)\n        cout << a;\n      else if (j == 0 || j == w - 1)\n        cout << a;\n      else\n        cout << b;\n    }\n    cout << endl;\n  }\n}\n//四捨五入\nll C45(ll n)\n{\n  return (n + 1) / 2;\n}\n//文字列からcを探す\nll stcount(str s, char c)\n{\n  return count(s.cbegin(), s.cend(), c);\n}\n//素数\nbool IsPrime(ll num)\n{\n  if (num < 2)\n    return false;\n  else if (num == 2)\n    return true;\n  else if (num % 2 == 0)\n    return false;\n  ld sqrtNum = sqrt(num);\n  for (ll i = 3; i <= sqrtNum; i += 2)\n  {\n    if (num % i == 0)\n      return false;\n  }\n  return true;\n}\n//桁数\nll GetDigit(ll num)\n{\n  return log10(num) + 1;\n}\n//各桁の和\nll KSum(ll n)\n{\n  ll sum = 0;\n  if (n < 0)\n    return 0;\n  while (n > 0)\n  {\n    sum += n % 10;\n    n /= 10;\n  }\n  return sum;\n}\n//数値反転\nbool KReve(ll n)\n{\n  int reverse = 0;\n  int remaind;\n  int tmp = n;\n  while (tmp != 0)\n  {\n    remaind = tmp % 10;\n    reverse = reverse * 10 + remaind;\n    tmp /= 10;\n  }\n  if (reverse == n)\n    return true;\n  else\n    return false;\n}\n//約数全列挙\nvector<ll> enum_div(ll n)\n{\n  vector<ll> ret;\n  for (ll i = 1; i * i <= n; ++i)\n  {\n    if (n % i == 0)\n    {\n      ret.push_back(i);\n      if (i != 1 && i * i != n)\n      {\n        ret.push_back(n / i);\n      }\n    }\n  }\n  return ret;\n}\n//最大公約数\nll gcd(ll a, ll b)\n{\n  return b ? gcd(b, a % b) : a;\n}\n//複数個の最大公約数\nll ngcd(vector<ll> a)\n{\n  ll res;\n  res = a[0];\n  for (ll i = 1; i < a.size() && res != 1; i++)\n  {\n    res = gcd(a[i], res);\n  }\n  return res;\n}\n//最小公倍数\nll lcm(ll a, ll b)\n{\n  return a * b / gcd(a, b);\n}\n//複数個の最小公倍数\nll nlcm(vector<ll> numbers)\n{\n  ll res;\n  res = numbers[0];\n  for (ll i = 1; i < numbers.size(); i++)\n  {\n    res = lcm(res, numbers[i]);\n  }\n  return res;\n}\n//累乗\nll Pow(ll x, ll n)\n{\n  ll res = 1;\n  rep(i, n) res = res * x;\n  return res;\n}\n//累乗(xのn乗%mod)\nll mod_pow(ll x, ll n, ll mod = MAX)\n{\n  ll res = 1;\n  while (n > 0)\n  {\n    if (n & 1)\n      res = res * x % mod;\n    x = x * x % mod;\n    n >>= 1;\n  }\n  return res;\n}\n//階乗\nll factorial(ll n)\n{\n  if (n > 0)\n    return n * factorial(n - 1);\n  else\n    return 1;\n}\n//順列 nPr\nll perm(ll a, ll b)\n{\n  return (factorial(a) / factorial(a - b));\n}\n//組み合わせ　nCr\nll comb(ll a, ll b)\n{\n  return (factorial(a) / (factorial(a - b) * factorial(b)));\n}\n//n ~ mの和\nll sigma(ll n, ll m)\n{\n  return ((n + m) * (m - n + 1) * 0.5);\n}\n//期待値\nld hope(ld a)\n{\n  return (sigma(1, a) / a);\n}\n//謎\ntemplate <class T>\ninline bool chmax(T &a, T b)\n{\n  if (a < b)\n  {\n    a = b;\n    return 1;\n  }\n  return 0;\n}\ntemplate <class T>\ninline bool chmin(T &a, T b)\n{\n  if (a > b)\n  {\n    a = b;\n    return 1;\n  }\n  return 0;\n}\n/*\n//幅優先探索\n// 各座標に格納したい情報を構造体にする\n// 今回はX座標,Y座標,深さ(距離)を記述している\nstruct Corr\n{\n  ll x;\n  ll y;\n  ll depth;\n};\nqueue<Corr> q;\nll bfs(vector<vector<ll>> grid)\n{\n  // 既に探索の場所を1，探索していなかったら0を格納する配列\n  vector<vector<ll>> ispassed(grid.size(), vector<ll>(grid[0].size(), false));\n  // このような記述をしておくと，この後のfor文が綺麗にかける\n  ll dx[8] = {1, 0, -1, 0};\n  ll dy[8] = {0, 1, 0, -1};\n  while (!q.empty())\n  {\n    Corr now = q.front();\n    q.pop();\n    //今いる座標は(x,y)=(now.x, now.y)で，深さ(距離)はnow.depthである  ここで，今いる座標がゴール(探索対象)なのか判定する\n    for (ll i = 0; i < 4; i++)\n    {\n      ll nextx = now.x + dx[i];\n      ll nexty = now.y + dy[i];\n\n      // 次に探索する場所のX座標がはみ出した時\n      if (nextx >= grid[0].size())\n        continue;\n      if (nextx < 0)\n        continue;\n\n      // 次に探索する場所のY座標がはみ���した時\n      if (nexty >= grid.size())\n        continue;\n      if (nexty < 0)\n        continue;\n\n      // 次に探索する場所が既に探索済みの場合\n      if (ispassed[nexty][nextx])\n        continue;\n\n      ispassed[nexty][nextx] = true;\n      Corr next = {nextx, nexty, now.depth + 1};\n      q.push(next);\n    }\n  }\n}\n*/\n//謎\n//セグメント木\nclass Monoid\n{\npublic:\n  // 単位元\n  ll unit;\n\n  Monoid()\n  {\n    // 単位元\n    unit = 0;\n  }\n\n  // 演算関数\n  ll calc(ll a, ll b)\n  {\n    return a + b;\n  }\n};\n\nclass SegmentTree\n{\npublic:\n  // セグメント木の葉の要素数\n  ll n;\n\n  // セグメント木\n  vector<ll> tree;\n\n  // モノイド\n  Monoid mono;\n\n  SegmentTree(vector<ll> &v)\n  {\n    n = 1 << (ll)ceil(log2(v.size()));\n    tree = vector<ll>(n << 1);\n    for (ll i = 0; i < v.size(); i++)\n    {\n      update(i, v[i]);\n    }\n    for (ll i = v.size(); i < n; i++)\n    {\n      update(i, mono.unit);\n    }\n  }\n\n  // k番目の値(0-indexed)をxに変更\n  void update(ll k, ll x)\n  {\n    k += n;\n    tree[k] = x;\n    for (k = k >> 1; k > 0; k >>= 1)\n    {\n      tree[k] = mono.calc(tree[k << 1 | 0], tree[k << 1 | 1]);\n    }\n  }\n\n  // [l, r)の最小値(0-indexed)を求める．\n  ll query(ll l, ll r)\n  {\n    ll res = mono.unit;\n    l += n;\n    r += n;\n    while (l < r)\n    {\n      if (l & 1)\n      {\n        res = mono.calc(res, tree[l++]);\n      }\n      if (r & 1)\n      {\n        res = mono.calc(res, tree[--r]);\n      }\n      l >>= 1;\n      r >>= 1;\n    }\n    return res;\n  }\n  ll operator[](ll k)\n  {\n    // st[i]で添字iの要素の値を返す\n    if (k - n >= 0 || k < 0)\n    {\n      return -INF;\n    }\n    return tree[tree.size() - n + k];\n  }\n\n  void show()\n  {\n    int ret = 2;\n    for (ll i = 1; i < 2 * n; i++)\n    {\n      cout << tree[i] << \" \";\n      if (i == ret - 1)\n      {\n        cout << endl;\n        ret <<= 1;\n      }\n    }\n    cout << endl;\n  }\n};\n//点と線の最短距離\nstruct Point\n{\n  ld x;\n  ld y;\n};\n\nstruct LineSegment\n{\n  Point start;\n  Point end;\n};\n\n/**\n   @brief 線分と点の距離を計算する。\n   @param line 線分\n   @param point 点\n   @return ユークリッド距離\n */\nld calc_dist(const LineSegment &line, const Point &point)\n{\n  ld x0 = point.x, y0 = point.y;\n  ld x1 = line.start.x, y1 = line.start.y;\n  ld x2 = line.end.x, y2 = line.end.y;\n\n  ld a = x2 - x1;\n  ld b = y2 - y1;\n  ld a2 = a * a;\n  ld b2 = b * b;\n  ld r2 = a2 + b2;\n  ld tt = -(a * (x1 - x0) + b * (y1 - y0));\n\n  if (tt < 0)\n    return sqrt((x1 - x0) * (x1 - x0) + (y1 - y0) * (y1 - y0));\n  else if (tt > r2)\n    return sqrt((x2 - x0) * (x2 - x0) + (y2 - y0) * (y2 - y0));\n\n  ld f1 = a * (y1 - y0) - b * (x1 - x0);\n  return sqrt((f1 * f1) / r2);\n}\n//文字を数字に\nll Moji(char a)\n{\n  return (a - 48);\n}\n\n//大文字->小文字(+32)\n\nvoid Main()\n{\n  ll h, w; cin >> h >> w;\n  if(h * w % 2 == 1) fin(h * w / 2 + 1)\n  else fin(h * w / 2)\n}\n\nint main()\n{\n  ios::sync_with_stdio(false);\n  cin.tie(0);\n  cout << fixed << setprecision(20);\n  Main();\n  return 0;\n}\n/*\n//test時\ng++ test.cpp -o a;./a\n*/\n", "language": "C++", "metadata": {"date": 1584234883, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02742.html", "problem_id": "p02742", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02742/input.txt", "sample_output_relpath": "derived/input_output/data/p02742/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02742/C++/s088392844.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s088392844", "user_id": "u743889070"}, "prompt_components": {"gold_output": "10\n", "input_to_evaluate": "#include <bits/stdc++.h>\n//上記が使用不可な環境において\n/*\n#include <iostream> // cout, endl, cin\n#include <string> // string, to_string, stoi\n#include <iomanip>  //setprecsion\n#include <vector> // vector\n#include <algorithm> // min, max, swap, sort, reverse, lower_bound, upper_bound\n#include <utility> // pair, make_pair\n#include <cmath>  //sin, cos, tan\n#include <tuple> // tuple, make_tuple\n#include <cstdint> // int64_t, int*_t\n#include <cstdio> // printf\n#include <map> // map\n#include <queue> // queue, priority_queue\n#include <set> // set\n#include <stack> // stack\n#include <deque> // deque\n#include <unordered_map> // unordered_map\n#include <unordered_set> // unordered_set\n#include <bitset> // bitset\n#include <cctype> // isupper, islower, isdigit, toupper, tolower\n#include <cstdlib>\n#include <cstring>\n#include <numeric>\n#include <complex>\n#include <bitset>\n#include <utility>\n#include <functional>\n*/\nusing namespace std;\n\ntypedef long long int ll;\ntypedef long long int lli;\ntypedef unsigned long long int ull;\ntypedef long double ld;\ntypedef string str;\ntypedef vector<char> vc;\ntypedef vector<bool> vb;\ntypedef vector<ld> vd;\ntypedef vector<str> vs;\ntypedef vector<ll> vll;\ntypedef vector<pair<ll, ll>> vpll;\ntypedef vector<vector<ll>> vvll;\ntypedef vector<vector<char>> vvc;\ntypedef vector<vector<str>> vvs;\nconst ld PI = acos(-1.0);\nconst ll MAX = 9000000000000000000;\nconst ll MIN = -9000000000000000000;\nconst ld DMAX = 4500;\nconst ld DMIN = -4500;\n\n//謎\nconst int INF = INT_MAX;\nconst ll LLINF = 1LL << 60;\nconst ll MOD = 1000000007;\nconst ld EPS = 1e-9;\nll dx[8] = {1, 0, -1, 0, 1, -1, -1, 1};\nll dy[8] = {0, 1, 0, -1, 1, 1, -1, -1};\n\n//0~nの範囲操作\n#define rep(i, n) for (ll i = 0; i < (n); ++i)\n//1~nの範囲操作\n#define rrep(i, n) for (ll i = 1; i <= (n); ++i)\n#define irep(it, stl) for (auto it = stl.begin(); it != stl.end(); it++)\n#define drep(i, n) for (ll i = (n)-1; i >= 0; --i)\n//出力後改行を\n#define fin(ans) cout << (ans) << endl;\n//出力後空白を\n#define blank(ans) cout << (ans) << \" \";\n#define mp(p, q) make_pair(p, q)\n#define pb(n) push_back(n)\n//配列全操作\n#define all(a) a.begin(), a.end()\n\n//配列の合計\ntemplate <typename T>\nT Sum(vector<T> n, ll a = 0, ll b = 0)\n{\n  if (b == 0)\n  {\n    return (accumulate(n.begin() + a, n.end(), 0));\n  }\n  else\n  {\n    return (accumulate(n.begin() + a, n.begin() + b, 0));\n  }\n}\ntemplate <>\nld Sum(vector<ld> n, ll a, ll b)\n{\n  if (b == 0)\n  {\n    return (accumulate(n.begin() + a, n.end(), 0));\n  }\n  else\n  {\n    return (accumulate(n.begin() + a, n.begin() + b, 0));\n  }\n}\n//配列を昇順\ntemplate <typename T>\nvoid Sort(T &n, ll a = 0, ll b = 0)\n{\n  if (b == 0)\n  {\n    return (sort(n.begin() + a, n.end()));\n  }\n  else\n  {\n    return (sort(n.begin() + a, n.begin() + b));\n  }\n}\n//配列を降順\ntemplate <typename T>\nvoid Reve(T &n, ll a = 0, ll b = 0)\n{\n  if (b == 0)\n  {\n    return (reverse(n.begin() + a, n.end()));\n  }\n  else\n  {\n    return (reverse(n.begin() + a, n.begin() + b));\n  }\n}\n//配列nをmにコピー\ntemplate <typename T, typename U>\nvoid Copy(T &n, U &m, ll a = 0, ll b = 0)\n{\n  copy(all(n), m.begin());\n}\n//小数点型に\ntemplate <typename T>\nld Cast(T n)\n{\n  return static_cast<ld>(n);\n}\n//配列入力\ntemplate <typename T>\nvoid V(T &n)\n{\n  for (ll i = 0; i < n.size(); i++)\n  {\n    cin >> n[i];\n  }\n}\n//２列配列入力\ntemplate <typename T, typename U>\nvoid V2(T &n, U &m)\n{\n  for (ll i = 0; i < n.size(); i++)\n  {\n    cin >> n[i] >> m[i];\n  }\n}\n//３列配列入力\ntemplate <typename T, typename U, typename W>\nvoid V3(T &n, U &m, W &p)\n{\n  for (ll i = 0; i < n.size(); i++)\n  {\n    cin >> n[i] >> m[i] >> p[i];\n  }\n}\n//yes, noと表示\nvoid yn(bool a)\n{\n  if (a)\n    cout << \"yes\" << endl;\n  else\n    cout << \"no\" << endl;\n}\n//Yes, Noと表示\nvoid Yn(bool a)\n{\n  if (a)\n    cout << \"Yes\" << endl;\n  else\n    cout << \"No\" << endl;\n}\n//YES, NOと表示\nvoid YN(bool a)\n{\n  if (a)\n    cout << \"YES\" << endl;\n  else\n    cout << \"NO\" << endl;\n}\n//yes, noと表示後終了\nvoid fyn(bool a)\n{\n  if (a)\n    cout << \"yes\" << endl;\n  else\n    cout << \"no\" << endl;\n  exit(0);\n}\n//Yes, Noと表示後終了\nvoid fYn(bool a)\n{\n  if (a)\n    cout << \"Yes\" << endl;\n  else\n    cout << \"No\" << endl;\n  exit(0);\n}\n//YES, NOと表示後終了\nvoid fYN(bool a)\n{\n  if (a)\n    cout << \"YES\" << endl;\n  else\n    cout << \"NO\" << endl;\n  exit(0);\n}\n//AC, WAと表示\nvoid AC(bool a)\n{\n  if (a)\n    cout << \"AC\" << endl;\n  else\n    cout << \"WA\" << endl;\n}\n//AC, WAと表示後終了\nvoid fAC(bool a)\n{\n  if (a)\n    cout << \"AC\" << endl;\n  else\n    cout << \"WA\" << endl;\n  exit(0);\n}\n//noneと表示後終了\nvoid fnone(void)\n{\n  cout << \"None\" << endl;\n  exit(0);\n}\n//Odd(奇数), Even(偶数)と表示後終了\nvoid fOdd(bool a)\n{\n  if (a)\n    cout << \"Odd\" << endl;\n  else\n    cout << \"Even\" << endl;\n  exit(0);\n}\n//Possible, Impossibleと表示後終了\nvoid Possible(bool a)\n{\n  if (a)\n    cout << \"Possible\" << endl;\n  else\n    cout << \"Impossible\" << endl;\n  exit(0);\n}\n//POSSIBLE, IMPOSSIBLEと表示後終了\nvoid POSSIBLE(bool a)\n{\n  if (a)\n    cout << \"POSSIBLE\" << endl;\n  else\n    cout << \"IMPOSSIBLE\" << endl;\n  exit(0);\n}\n//四角　表示文字 a 縦幅 h 横幅 w\nvoid square(char a, ll h, ll w)\n{\n  for (ll i = 0; i < h; i++)\n  {\n    for (ll j = 0; j < w; j++)\n    {\n      cout << a;\n    }\n    cout << endl;\n  }\n}\n//四角枠　外周 a 中身 b 縦幅 h 横幅 w\nvoid yoke(char a, char b, ll h, ll w)\n{\n  for (ll i = 0; i < h; i++)\n  {\n    for (ll j = 0; j < w; j++)\n    {\n      if (i == 0 || i == h - 1)\n        cout << a;\n      else if (j == 0 || j == w - 1)\n        cout << a;\n      else\n        cout << b;\n    }\n    cout << endl;\n  }\n}\n//四捨五入\nll C45(ll n)\n{\n  return (n + 1) / 2;\n}\n//文字列からcを探す\nll stcount(str s, char c)\n{\n  return count(s.cbegin(), s.cend(), c);\n}\n//素数\nbool IsPrime(ll num)\n{\n  if (num < 2)\n    return false;\n  else if (num == 2)\n    return true;\n  else if (num % 2 == 0)\n    return false;\n  ld sqrtNum = sqrt(num);\n  for (ll i = 3; i <= sqrtNum; i += 2)\n  {\n    if (num % i == 0)\n      return false;\n  }\n  return true;\n}\n//桁数\nll GetDigit(ll num)\n{\n  return log10(num) + 1;\n}\n//各桁の和\nll KSum(ll n)\n{\n  ll sum = 0;\n  if (n < 0)\n    return 0;\n  while (n > 0)\n  {\n    sum += n % 10;\n    n /= 10;\n  }\n  return sum;\n}\n//数値反転\nbool KReve(ll n)\n{\n  int reverse = 0;\n  int remaind;\n  int tmp = n;\n  while (tmp != 0)\n  {\n    remaind = tmp % 10;\n    reverse = reverse * 10 + remaind;\n    tmp /= 10;\n  }\n  if (reverse == n)\n    return true;\n  else\n    return false;\n}\n//約数全列挙\nvector<ll> enum_div(ll n)\n{\n  vector<ll> ret;\n  for (ll i = 1; i * i <= n; ++i)\n  {\n    if (n % i == 0)\n    {\n      ret.push_back(i);\n      if (i != 1 && i * i != n)\n      {\n        ret.push_back(n / i);\n      }\n    }\n  }\n  return ret;\n}\n//最大公約数\nll gcd(ll a, ll b)\n{\n  return b ? gcd(b, a % b) : a;\n}\n//複数個の最大公約数\nll ngcd(vector<ll> a)\n{\n  ll res;\n  res = a[0];\n  for (ll i = 1; i < a.size() && res != 1; i++)\n  {\n    res = gcd(a[i], res);\n  }\n  return res;\n}\n//最小公倍数\nll lcm(ll a, ll b)\n{\n  return a * b / gcd(a, b);\n}\n//複数個の最小公倍数\nll nlcm(vector<ll> numbers)\n{\n  ll res;\n  res = numbers[0];\n  for (ll i = 1; i < numbers.size(); i++)\n  {\n    res = lcm(res, numbers[i]);\n  }\n  return res;\n}\n//累乗\nll Pow(ll x, ll n)\n{\n  ll res = 1;\n  rep(i, n) res = res * x;\n  return res;\n}\n//累乗(xのn乗%mod)\nll mod_pow(ll x, ll n, ll mod = MAX)\n{\n  ll res = 1;\n  while (n > 0)\n  {\n    if (n & 1)\n      res = res * x % mod;\n    x = x * x % mod;\n    n >>= 1;\n  }\n  return res;\n}\n//階乗\nll factorial(ll n)\n{\n  if (n > 0)\n    return n * factorial(n - 1);\n  else\n    return 1;\n}\n//順列 nPr\nll perm(ll a, ll b)\n{\n  return (factorial(a) / factorial(a - b));\n}\n//組み合わせ　nCr\nll comb(ll a, ll b)\n{\n  return (factorial(a) / (factorial(a - b) * factorial(b)));\n}\n//n ~ mの和\nll sigma(ll n, ll m)\n{\n  return ((n + m) * (m - n + 1) * 0.5);\n}\n//期待値\nld hope(ld a)\n{\n  return (sigma(1, a) / a);\n}\n//謎\ntemplate <class T>\ninline bool chmax(T &a, T b)\n{\n  if (a < b)\n  {\n    a = b;\n    return 1;\n  }\n  return 0;\n}\ntemplate <class T>\ninline bool chmin(T &a, T b)\n{\n  if (a > b)\n  {\n    a = b;\n    return 1;\n  }\n  return 0;\n}\n/*\n//幅優先探索\n// 各座標に格納したい情報を構造体にする\n// 今回はX座標,Y座標,深さ(距離)を記述している\nstruct Corr\n{\n  ll x;\n  ll y;\n  ll depth;\n};\nqueue<Corr> q;\nll bfs(vector<vector<ll>> grid)\n{\n  // 既に探索の場所を1，探索していなかったら0を格納する配列\n  vector<vector<ll>> ispassed(grid.size(), vector<ll>(grid[0].size(), false));\n  // このような記述をしておくと，この後のfor文が綺麗にかける\n  ll dx[8] = {1, 0, -1, 0};\n  ll dy[8] = {0, 1, 0, -1};\n  while (!q.empty())\n  {\n    Corr now = q.front();\n    q.pop();\n    //今いる座標は(x,y)=(now.x, now.y)で，深さ(距離)はnow.depthである  ここで，今いる座標がゴール(探索対象)なのか判定する\n    for (ll i = 0; i < 4; i++)\n    {\n      ll nextx = now.x + dx[i];\n      ll nexty = now.y + dy[i];\n\n      // 次に探索する場所のX座標がはみ出した時\n      if (nextx >= grid[0].size())\n        continue;\n      if (nextx < 0)\n        continue;\n\n      // 次に探索する場所のY座標がはみ出した時\n      if (nexty >= grid.size())\n        continue;\n      if (nexty < 0)\n        continue;\n\n      // 次に探索する場所が既に探索済みの場合\n      if (ispassed[nexty][nextx])\n        continue;\n\n      ispassed[nexty][nextx] = true;\n      Corr next = {nextx, nexty, now.depth + 1};\n      q.push(next);\n    }\n  }\n}\n*/\n//謎\n//セグメント木\nclass Monoid\n{\npublic:\n  // 単位元\n  ll unit;\n\n  Monoid()\n  {\n    // 単位元\n    unit = 0;\n  }\n\n  // 演算関数\n  ll calc(ll a, ll b)\n  {\n    return a + b;\n  }\n};\n\nclass SegmentTree\n{\npublic:\n  // セグメント木の葉の要素数\n  ll n;\n\n  // セグメント木\n  vector<ll> tree;\n\n  // モノイド\n  Monoid mono;\n\n  SegmentTree(vector<ll> &v)\n  {\n    n = 1 << (ll)ceil(log2(v.size()));\n    tree = vector<ll>(n << 1);\n    for (ll i = 0; i < v.size(); i++)\n    {\n      update(i, v[i]);\n    }\n    for (ll i = v.size(); i < n; i++)\n    {\n      update(i, mono.unit);\n    }\n  }\n\n  // k番目の値(0-indexed)をxに変更\n  void update(ll k, ll x)\n  {\n    k += n;\n    tree[k] = x;\n    for (k = k >> 1; k > 0; k >>= 1)\n    {\n      tree[k] = mono.calc(tree[k << 1 | 0], tree[k << 1 | 1]);\n    }\n  }\n\n  // [l, r)の最小値(0-indexed)を求める．\n  ll query(ll l, ll r)\n  {\n    ll res = mono.unit;\n    l += n;\n    r += n;\n    while (l < r)\n    {\n      if (l & 1)\n      {\n        res = mono.calc(res, tree[l++]);\n      }\n      if (r & 1)\n      {\n        res = mono.calc(res, tree[--r]);\n      }\n      l >>= 1;\n      r >>= 1;\n    }\n    return res;\n  }\n  ll operator[](ll k)\n  {\n    // st[i]で添字iの要素の値を返す\n    if (k - n >= 0 || k < 0)\n    {\n      return -INF;\n    }\n    return tree[tree.size() - n + k];\n  }\n\n  void show()\n  {\n    int ret = 2;\n    for (ll i = 1; i < 2 * n; i++)\n    {\n      cout << tree[i] << \" \";\n      if (i == ret - 1)\n      {\n        cout << endl;\n        ret <<= 1;\n      }\n    }\n    cout << endl;\n  }\n};\n//点と線の最短距離\nstruct Point\n{\n  ld x;\n  ld y;\n};\n\nstruct LineSegment\n{\n  Point start;\n  Point end;\n};\n\n/**\n   @brief 線分と点の距離を計算する。\n   @param line 線分\n   @param point 点\n   @return ユークリッド距離\n */\nld calc_dist(const LineSegment &line, const Point &point)\n{\n  ld x0 = point.x, y0 = point.y;\n  ld x1 = line.start.x, y1 = line.start.y;\n  ld x2 = line.end.x, y2 = line.end.y;\n\n  ld a = x2 - x1;\n  ld b = y2 - y1;\n  ld a2 = a * a;\n  ld b2 = b * b;\n  ld r2 = a2 + b2;\n  ld tt = -(a * (x1 - x0) + b * (y1 - y0));\n\n  if (tt < 0)\n    return sqrt((x1 - x0) * (x1 - x0) + (y1 - y0) * (y1 - y0));\n  else if (tt > r2)\n    return sqrt((x2 - x0) * (x2 - x0) + (y2 - y0) * (y2 - y0));\n\n  ld f1 = a * (y1 - y0) - b * (x1 - x0);\n  return sqrt((f1 * f1) / r2);\n}\n//文字を数字に\nll Moji(char a)\n{\n  return (a - 48);\n}\n\n//大文字->小文字(+32)\n\nvoid Main()\n{\n  ll h, w; cin >> h >> w;\n  if(h * w % 2 == 1) fin(h * w / 2 + 1)\n  else fin(h * w / 2)\n}\n\nint main()\n{\n  ios::sync_with_stdio(false);\n  cin.tie(0);\n  cout << fixed << setprecision(20);\n  Main();\n  return 0;\n}\n/*\n//test時\ng++ test.cpp -o a;./a\n*/\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nWe have a board with H horizontal rows and W vertical columns of squares.\nThere is a bishop at the top-left square on this board.\nHow many squares can this bishop reach by zero or more movements?\n\nHere the bishop can only move diagonally.\nMore formally, the bishop can move from the square at the r_1-th row (from the top) and the c_1-th column (from the left) to the square at the r_2-th row and the c_2-th column if and only if exactly one of the following holds:\n\nr_1 + c_1 = r_2 + c_2\n\nr_1 - c_1 = r_2 - c_2\n\nFor example, in the following figure, the bishop can move to any of the red squares in one move:\n\nConstraints\n\n1 \\leq H, W \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH \\ W\n\nOutput\n\nPrint the number of squares the bishop can reach.\n\nSample Input 1\n\n4 5\n\nSample Output 1\n\n10\n\nThe bishop can reach the cyan squares in the following figure:\n\nSample Input 2\n\n7 3\n\nSample Output 2\n\n11\n\nThe bishop can reach the cyan squares in the following figure:\n\nSample Input 3\n\n1000000000 1000000000\n\nSample Output 3\n\n500000000000000000", "sample_input": "4 5\n"}, "reference_outputs": ["10\n"], "source_document_id": "p02742", "source_text": "Score : 200 points\n\nProblem Statement\n\nWe have a board with H horizontal rows and W vertical columns of squares.\nThere is a bishop at the top-left square on this board.\nHow many squares can this bishop reach by zero or more movements?\n\nHere the bishop can only move diagonally.\nMore formally, the bishop can move from the square at the r_1-th row (from the top) and the c_1-th column (from the left) to the square at the r_2-th row and the c_2-th column if and only if exactly one of the following holds:\n\nr_1 + c_1 = r_2 + c_2\n\nr_1 - c_1 = r_2 - c_2\n\nFor example, in the following figure, the bishop can move to any of the red squares in one move:\n\nConstraints\n\n1 \\leq H, W \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH \\ W\n\nOutput\n\nPrint the number of squares the bishop can reach.\n\nSample Input 1\n\n4 5\n\nSample Output 1\n\n10\n\nThe bishop can reach the cyan squares in the following figure:\n\nSample Input 2\n\n7 3\n\nSample Output 2\n\n11\n\nThe bishop can reach the cyan squares in the following figure:\n\nSample Input 3\n\n1000000000 1000000000\n\nSample Output 3\n\n500000000000000000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 12426, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s030562312", "group_id": "codeNet:p02742", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nusing lint = long;\nusing ll = long long;\n#define rep(i,n) for(lint (i) = 0;(i) < (lint)(n);(i)++)\n#define repInRange(i,start,end) for(lint (i) = (start);(i) < (end);++(i))\nusing lpair = pair<lint,lint>;\nusing Vecint = vector<lint>;\nusing Llist = list<lint>;\n\nll pow(ll k,ll l) {\n\tll ret = 1;\n\trep(i,l) {\n\t\tret *= k;\n\t}\n\treturn ret;\n}\n\ntemplate <typename T>\nT sum(vector<T> vec) {\n\tll ret = 0;\n\trep(i,vec.size()) {\n\t\tret += vec.at(i);\n\t}\n\treturn ret;\n}\n\nvoid Main() {\n\tll h,w;\n\tcin >> h >> w;\n\tcout << h*w/2 + (h*w)%2 << '\\n';\n}\n\nsigned main() {\n\tcin.tie(nullptr);\n\tios::sync_with_stdio(false);\n\tMain();\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1584234413, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02742.html", "problem_id": "p02742", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02742/input.txt", "sample_output_relpath": "derived/input_output/data/p02742/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02742/C++/s030562312.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s030562312", "user_id": "u538351278"}, "prompt_components": {"gold_output": "10\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nusing lint = long;\nusing ll = long long;\n#define rep(i,n) for(lint (i) = 0;(i) < (lint)(n);(i)++)\n#define repInRange(i,start,end) for(lint (i) = (start);(i) < (end);++(i))\nusing lpair = pair<lint,lint>;\nusing Vecint = vector<lint>;\nusing Llist = list<lint>;\n\nll pow(ll k,ll l) {\n\tll ret = 1;\n\trep(i,l) {\n\t\tret *= k;\n\t}\n\treturn ret;\n}\n\ntemplate <typename T>\nT sum(vector<T> vec) {\n\tll ret = 0;\n\trep(i,vec.size()) {\n\t\tret += vec.at(i);\n\t}\n\treturn ret;\n}\n\nvoid Main() {\n\tll h,w;\n\tcin >> h >> w;\n\tcout << h*w/2 + (h*w)%2 << '\\n';\n}\n\nsigned main() {\n\tcin.tie(nullptr);\n\tios::sync_with_stdio(false);\n\tMain();\n\treturn 0;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nWe have a board with H horizontal rows and W vertical columns of squares.\nThere is a bishop at the top-left square on this board.\nHow many squares can this bishop reach by zero or more movements?\n\nHere the bishop can only move diagonally.\nMore formally, the bishop can move from the square at the r_1-th row (from the top) and the c_1-th column (from the left) to the square at the r_2-th row and the c_2-th column if and only if exactly one of the following holds:\n\nr_1 + c_1 = r_2 + c_2\n\nr_1 - c_1 = r_2 - c_2\n\nFor example, in the following figure, the bishop can move to any of the red squares in one move:\n\nConstraints\n\n1 \\leq H, W \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH \\ W\n\nOutput\n\nPrint the number of squares the bishop can reach.\n\nSample Input 1\n\n4 5\n\nSample Output 1\n\n10\n\nThe bishop can reach the cyan squares in the following figure:\n\nSample Input 2\n\n7 3\n\nSample Output 2\n\n11\n\nThe bishop can reach the cyan squares in the following figure:\n\nSample Input 3\n\n1000000000 1000000000\n\nSample Output 3\n\n500000000000000000", "sample_input": "4 5\n"}, "reference_outputs": ["10\n"], "source_document_id": "p02742", "source_text": "Score : 200 points\n\nProblem Statement\n\nWe have a board with H horizontal rows and W vertical columns of squares.\nThere is a bishop at the top-left square on this board.\nHow many squares can this bishop reach by zero or more movements?\n\nHere the bishop can only move diagonally.\nMore formally, the bishop can move from the square at the r_1-th row (from the top) and the c_1-th column (from the left) to the square at the r_2-th row and the c_2-th column if and only if exactly one of the following holds:\n\nr_1 + c_1 = r_2 + c_2\n\nr_1 - c_1 = r_2 - c_2\n\nFor example, in the following figure, the bishop can move to any of the red squares in one move:\n\nConstraints\n\n1 \\leq H, W \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH \\ W\n\nOutput\n\nPrint the number of squares the bishop can reach.\n\nSample Input 1\n\n4 5\n\nSample Output 1\n\n10\n\nThe bishop can reach the cyan squares in the following figure:\n\nSample Input 2\n\n7 3\n\nSample Output 2\n\n11\n\nThe bishop can reach the cyan squares in the following figure:\n\nSample Input 3\n\n1000000000 1000000000\n\nSample Output 3\n\n500000000000000000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 662, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s976246339", "group_id": "codeNet:p02742", "input_text": "#include<cstdio>\n\nlong long n, m;\n\nint main() {\n  scanf(\"%lld %lld\", &n, &m);\n  if (n == 1 || m == 1) {\n    printf(\"1\\n\");\n  } else {\n    printf(\"%lld\\n\", (n*m+1)/2);\n  }\n}\n", "language": "C++", "metadata": {"date": 1584234373, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02742.html", "problem_id": "p02742", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02742/input.txt", "sample_output_relpath": "derived/input_output/data/p02742/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02742/C++/s976246339.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s976246339", "user_id": "u475056780"}, "prompt_components": {"gold_output": "10\n", "input_to_evaluate": "#include<cstdio>\n\nlong long n, m;\n\nint main() {\n  scanf(\"%lld %lld\", &n, &m);\n  if (n == 1 || m == 1) {\n    printf(\"1\\n\");\n  } else {\n    printf(\"%lld\\n\", (n*m+1)/2);\n  }\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nWe have a board with H horizontal rows and W vertical columns of squares.\nThere is a bishop at the top-left square on this board.\nHow many squares can this bishop reach by zero or more movements?\n\nHere the bishop can only move diagonally.\nMore formally, the bishop can move from the square at the r_1-th row (from the top) and the c_1-th column (from the left) to the square at the r_2-th row and the c_2-th column if and only if exactly one of the following holds:\n\nr_1 + c_1 = r_2 + c_2\n\nr_1 - c_1 = r_2 - c_2\n\nFor example, in the following figure, the bishop can move to any of the red squares in one move:\n\nConstraints\n\n1 \\leq H, W \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH \\ W\n\nOutput\n\nPrint the number of squares the bishop can reach.\n\nSample Input 1\n\n4 5\n\nSample Output 1\n\n10\n\nThe bishop can reach the cyan squares in the following figure:\n\nSample Input 2\n\n7 3\n\nSample Output 2\n\n11\n\nThe bishop can reach the cyan squares in the following figure:\n\nSample Input 3\n\n1000000000 1000000000\n\nSample Output 3\n\n500000000000000000", "sample_input": "4 5\n"}, "reference_outputs": ["10\n"], "source_document_id": "p02742", "source_text": "Score : 200 points\n\nProblem Statement\n\nWe have a board with H horizontal rows and W vertical columns of squares.\nThere is a bishop at the top-left square on this board.\nHow many squares can this bishop reach by zero or more movements?\n\nHere the bishop can only move diagonally.\nMore formally, the bishop can move from the square at the r_1-th row (from the top) and the c_1-th column (from the left) to the square at the r_2-th row and the c_2-th column if and only if exactly one of the following holds:\n\nr_1 + c_1 = r_2 + c_2\n\nr_1 - c_1 = r_2 - c_2\n\nFor example, in the following figure, the bishop can move to any of the red squares in one move:\n\nConstraints\n\n1 \\leq H, W \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH \\ W\n\nOutput\n\nPrint the number of squares the bishop can reach.\n\nSample Input 1\n\n4 5\n\nSample Output 1\n\n10\n\nThe bishop can reach the cyan squares in the following figure:\n\nSample Input 2\n\n7 3\n\nSample Output 2\n\n11\n\nThe bishop can reach the cyan squares in the following figure:\n\nSample Input 3\n\n1000000000 1000000000\n\nSample Output 3\n\n500000000000000000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 173, "cpu_time_ms": 1, "memory_kb": 128}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s951302901", "group_id": "codeNet:p02745", "input_text": "#include <cstring>\n#include <cstdio>\n#include <algorithm>\n#include <cmath>\n#include <cstdlib>\n#include <vector>\n#include <iostream>\n#include <queue>\n#include <stack>\n#define lson rt<<1\n#define rson rt<<1|1\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int, int>  P;\ntypedef pair<int, P>  PP;\nconst int maxn=43+10;\nchar a[maxn],b[maxn],c[maxn];\nbool xab[maxn],xba[maxn],xbc[maxn],xac[maxn],xcb[maxn];\nint main()\n{\n    cin>>a>>b>>c;\n    int lena=strlen(a),lenb=strlen(b),lenc=strlen(c);\n    int len=max(max(strlen(a),strlen(b)),strlen(c));\n    for(int i=-len;i<=len;i++)\n    {\n        int flag=0;\n        for(int j=0;j<lena;j++)\n        {\n            if(0<=j+i&&j+i<lenb)\n            {\n                if(a[j]!='?'&&a[j]!=b[i+j]&&b[i+j]!='?')\n                {\n                    flag=1;\n                    break;\n                }\n            }\n        }\n        if(flag==0){\n            xab[i+len]=1;\n        }\n    }\n    \n    for(int i=-len;i<=len;i++)\n    {\n        int flag=0;\n        for(int j=0;j<lenb;j++)\n        {\n            if(0<=j+i&&j+i<lenc)\n            {\n                if(b[j]!='?'&&b[j]!=c[i+j]&&c[i+j]!='?')\n                {\n                    flag=1;\n                    break;\n                }\n            }\n        }\n        if(flag==0){\n            xbc[i+len]=1;\n        }\n    }\n    \n    for(int i=-len;i<=len;i++)\n    {\n        int flag=0;\n        for(int j=0;j<lena;j++)\n        {\n            if(0<=j+i&&j+i<lenc)\n            {\n                if(a[j]!='?'&&a[j]!=c[i+j]&&c[i+j]!='?')\n                {\n                    flag=1;\n                    break;\n                }\n            }\n        }\n        if(flag==0)\n            xac[i+len]=1;\n    }\n    \n    int ans=1e9;\n    for(int i=-len*2;i<=len*2;i++)\n        for(int j=-len*2;j<=len*2;j++)\n        {\n            int l=0,r=lena;\n            l=min(min(-i,-j),l);\n            r=max(r,max(-i+lenb,-j+lenc));\n            if(-len<=i&&i<=len&&xab[i+len]==0)\n                continue;\n            int p=j-i;\n            if(-len<=p&&p<=len&&xbc[p+len]==0)\n                continue;\n            \n            if(-len<=j&&j<=len&&xac[j+len]==0)\n                continue;\n            \n            ans=min(r-l,ans);\n            if(ans==4)\n                cout<<i<<\" \"<<j<<endl;\n        }\n    cout<<ans;\n}\n\n\n", "language": "C++", "metadata": {"date": 1584255561, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02745.html", "problem_id": "p02745", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02745/input.txt", "sample_output_relpath": "derived/input_output/data/p02745/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02745/C++/s951302901.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s951302901", "user_id": "u746857715"}, "prompt_components": {"gold_output": "7\n", "input_to_evaluate": "#include <cstring>\n#include <cstdio>\n#include <algorithm>\n#include <cmath>\n#include <cstdlib>\n#include <vector>\n#include <iostream>\n#include <queue>\n#include <stack>\n#define lson rt<<1\n#define rson rt<<1|1\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int, int>  P;\ntypedef pair<int, P>  PP;\nconst int maxn=43+10;\nchar a[maxn],b[maxn],c[maxn];\nbool xab[maxn],xba[maxn],xbc[maxn],xac[maxn],xcb[maxn];\nint main()\n{\n    cin>>a>>b>>c;\n    int lena=strlen(a),lenb=strlen(b),lenc=strlen(c);\n    int len=max(max(strlen(a),strlen(b)),strlen(c));\n    for(int i=-len;i<=len;i++)\n    {\n        int flag=0;\n        for(int j=0;j<lena;j++)\n        {\n            if(0<=j+i&&j+i<lenb)\n            {\n                if(a[j]!='?'&&a[j]!=b[i+j]&&b[i+j]!='?')\n                {\n                    flag=1;\n                    break;\n                }\n            }\n        }\n        if(flag==0){\n            xab[i+len]=1;\n        }\n    }\n    \n    for(int i=-len;i<=len;i++)\n    {\n        int flag=0;\n        for(int j=0;j<lenb;j++)\n        {\n            if(0<=j+i&&j+i<lenc)\n            {\n                if(b[j]!='?'&&b[j]!=c[i+j]&&c[i+j]!='?')\n                {\n                    flag=1;\n                    break;\n                }\n            }\n        }\n        if(flag==0){\n            xbc[i+len]=1;\n        }\n    }\n    \n    for(int i=-len;i<=len;i++)\n    {\n        int flag=0;\n        for(int j=0;j<lena;j++)\n        {\n            if(0<=j+i&&j+i<lenc)\n            {\n                if(a[j]!='?'&&a[j]!=c[i+j]&&c[i+j]!='?')\n                {\n                    flag=1;\n                    break;\n                }\n            }\n        }\n        if(flag==0)\n            xac[i+len]=1;\n    }\n    \n    int ans=1e9;\n    for(int i=-len*2;i<=len*2;i++)\n        for(int j=-len*2;j<=len*2;j++)\n        {\n            int l=0,r=lena;\n            l=min(min(-i,-j),l);\n            r=max(r,max(-i+lenb,-j+lenc));\n            if(-len<=i&&i<=len&&xab[i+len]==0)\n                continue;\n            int p=j-i;\n            if(-len<=p&&p<=len&&xbc[p+len]==0)\n                continue;\n            \n            if(-len<=j&&j<=len&&xac[j+len]==0)\n                continue;\n            \n            ans=min(r-l,ans);\n            if(ans==4)\n                cout<<i<<\" \"<<j<<endl;\n        }\n    cout<<ans;\n}\n\n\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nSnuke has a string s.\nFrom this string, Anuke, Bnuke, and Cnuke obtained strings a, b, and c, respectively, as follows:\n\nChoose a non-empty (contiguous) substring of s (possibly s itself). Then, replace some characters (possibly all or none) in it with ?s.\n\nFor example, if s is mississippi, we can choose the substring ssissip and replace its 1-st and 3-rd characters with ? to obtain ?s?ssip.\n\nYou are given the strings a, b, and c.\nFind the minimum possible length of s.\n\nConstraints\n\n1 \\leq |a|, |b|, |c| \\leq 2000\n\na, b, and c consists of lowercase English letters and ?s.\n\nInput\n\nInput is given from Standard Input in the following format:\n\na\nb\nc\n\nOutput\n\nPrint the minimum possible length of s.\n\nSample Input 1\n\na?c\nder\ncod\n\nSample Output 1\n\n7\n\nFor example, s could be atcoder.\n\nSample Input 2\n\natcoder\natcoder\n???????\n\nSample Output 2\n\n7\n\na, b, and c may not be distinct.", "sample_input": "a?c\nder\ncod\n"}, "reference_outputs": ["7\n"], "source_document_id": "p02745", "source_text": "Score : 500 points\n\nProblem Statement\n\nSnuke has a string s.\nFrom this string, Anuke, Bnuke, and Cnuke obtained strings a, b, and c, respectively, as follows:\n\nChoose a non-empty (contiguous) substring of s (possibly s itself). Then, replace some characters (possibly all or none) in it with ?s.\n\nFor example, if s is mississippi, we can choose the substring ssissip and replace its 1-st and 3-rd characters with ? to obtain ?s?ssip.\n\nYou are given the strings a, b, and c.\nFind the minimum possible length of s.\n\nConstraints\n\n1 \\leq |a|, |b|, |c| \\leq 2000\n\na, b, and c consists of lowercase English letters and ?s.\n\nInput\n\nInput is given from Standard Input in the following format:\n\na\nb\nc\n\nOutput\n\nPrint the minimum possible length of s.\n\nSample Input 1\n\na?c\nder\ncod\n\nSample Output 1\n\n7\n\nFor example, s could be atcoder.\n\nSample Input 2\n\natcoder\natcoder\n???????\n\nSample Output 2\n\n7\n\na, b, and c may not be distinct.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2289, "cpu_time_ms": 106, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s404444614", "group_id": "codeNet:p02749", "input_text": "#include<iostream>\n#include<vector>\nusing namespace std;\ntypedef long long li;\n#define rep(i,n) for(int i=0;i<(n);i++)\n#define df 0\ntemplate<class T> void print(const T& t){ cout << t << \"\\n\"; }\ntemplate<class T, class... Ts> void print(const T& t, const Ts&... ts) { cout << t; if (sizeof...(ts)) cout << \" \"; print(ts...); }\n// Container コンテナ型, map以外\ntemplate< template<class ...> class Ctn,class T>\nstd::ostream& operator<<(std::ostream& os,const Ctn<T>& v){\n  auto itr=v.begin();\n  while(itr!=v.end()){\n    if(itr!=v.begin())cout << \" \";\n    cout << *(itr++);\n  }\n  return os;\n}\n\nvoid dfs(vector<vector<int>>& adj,vector<vector<int>>& col,\n         int p=-1,int a=0){\n  int n=adj.size();\n  static vector<int> seen(n,0);\n  static int c=0;\n  seen[a]=1;\n  col[c].push_back(a);\n  c^=1;\n  for(int x:adj[a]){\n    if(x==p) continue;\n    dfs(adj,col,a,x);\n  }\n  c^=1;\n}\n\nvoid balance(vector<int>& p,vector<vector<int>> col){\n  int n=p.size();\n  int a=0,b=1;\n  if(col[0].size()<col[1].size()){ a=1;b=0; }\n\n  rep(i,n){\n    if(i%3==0){\n      p[*col[a].rbegin()]=i+1;\n      col[a].pop_back();\n    }else if(i%3==1){\n      p[*col[b].rbegin()]=i+1;\n      col[b].pop_back();\n    }else{\n      int c=(col[0].size()<=col[1].size());\n      p[*col[c].rbegin()]=i+1;\n      col[c].pop_back();\n    }\n  }\n}\n\nvoid umbalance(vector<int>& p,vector<vector<int>> col){\n  int n=p.size();\n  int a=0,b=1;\n  if(col[0].size()<col[1].size()){ a=1;b=0; }\n  int c=3;\n  while(c<=n){\n    p[*col[b].rbegin()]=c;\n    col[b].pop_back();\n    c+=3;\n    if(col[b].size()==0) b=a;\n  }\n  c=1;\n  for(int x: col[a]){\n    p[x]=c;\n    c+=c%3;\n  }\n}\n\nint main(){\n  int n; cin >>n;\n  vector<vector<int>> adj(n);\n  rep(i,n-1){\n    int a,b; cin >>a >>b; a--; b--;\n    adj[a].push_back(b);\n    adj[b].push_back(a);\n  }\n  vector<vector<int>> col(2);\n  dfs(adj,col);\n  \n  vector<int> p(n);\n  int a=0,b=1;\n  if(col[0].size()<col[1].size()){ a=1;b=0; }\n  if(col[a].size()<col[b].size()*2){\n    balance(p,col);\n  }else{\n    umbalance(p,col);\n  }\n  print(p);\n}\n", "language": "C++", "metadata": {"date": 1589413329, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02749.html", "problem_id": "p02749", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02749/input.txt", "sample_output_relpath": "derived/input_output/data/p02749/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02749/C++/s404444614.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s404444614", "user_id": "u014847113"}, "prompt_components": {"gold_output": "1 2 5 4 3\n", "input_to_evaluate": "#include<iostream>\n#include<vector>\nusing namespace std;\ntypedef long long li;\n#define rep(i,n) for(int i=0;i<(n);i++)\n#define df 0\ntemplate<class T> void print(const T& t){ cout << t << \"\\n\"; }\ntemplate<class T, class... Ts> void print(const T& t, const Ts&... ts) { cout << t; if (sizeof...(ts)) cout << \" \"; print(ts...); }\n// Container コンテナ型, map以外\ntemplate< template<class ...> class Ctn,class T>\nstd::ostream& operator<<(std::ostream& os,const Ctn<T>& v){\n  auto itr=v.begin();\n  while(itr!=v.end()){\n    if(itr!=v.begin())cout << \" \";\n    cout << *(itr++);\n  }\n  return os;\n}\n\nvoid dfs(vector<vector<int>>& adj,vector<vector<int>>& col,\n         int p=-1,int a=0){\n  int n=adj.size();\n  static vector<int> seen(n,0);\n  static int c=0;\n  seen[a]=1;\n  col[c].push_back(a);\n  c^=1;\n  for(int x:adj[a]){\n    if(x==p) continue;\n    dfs(adj,col,a,x);\n  }\n  c^=1;\n}\n\nvoid balance(vector<int>& p,vector<vector<int>> col){\n  int n=p.size();\n  int a=0,b=1;\n  if(col[0].size()<col[1].size()){ a=1;b=0; }\n\n  rep(i,n){\n    if(i%3==0){\n      p[*col[a].rbegin()]=i+1;\n      col[a].pop_back();\n    }else if(i%3==1){\n      p[*col[b].rbegin()]=i+1;\n      col[b].pop_back();\n    }else{\n      int c=(col[0].size()<=col[1].size());\n      p[*col[c].rbegin()]=i+1;\n      col[c].pop_back();\n    }\n  }\n}\n\nvoid umbalance(vector<int>& p,vector<vector<int>> col){\n  int n=p.size();\n  int a=0,b=1;\n  if(col[0].size()<col[1].size()){ a=1;b=0; }\n  int c=3;\n  while(c<=n){\n    p[*col[b].rbegin()]=c;\n    col[b].pop_back();\n    c+=3;\n    if(col[b].size()==0) b=a;\n  }\n  c=1;\n  for(int x: col[a]){\n    p[x]=c;\n    c+=c%3;\n  }\n}\n\nint main(){\n  int n; cin >>n;\n  vector<vector<int>> adj(n);\n  rep(i,n-1){\n    int a,b; cin >>a >>b; a--; b--;\n    adj[a].push_back(b);\n    adj[b].push_back(a);\n  }\n  vector<vector<int>> col(2);\n  dfs(adj,col);\n  \n  vector<int> p(n);\n  int a=0,b=1;\n  if(col[0].size()<col[1].size()){ a=1;b=0; }\n  if(col[a].size()<col[b].size()*2){\n    balance(p,col);\n  }else{\n    umbalance(p,col);\n  }\n  print(p);\n}\n", "problem_context": "Score : 600 points\n\nProblem Statement\n\nWe have a tree with N vertices. The vertices are numbered 1 to N, and the i-th edge connects Vertex a_i and Vertex b_i.\n\nTakahashi loves the number 3. He is seeking a permutation p_1, p_2, \\ldots , p_N of integers from 1 to N satisfying the following condition:\n\nFor every pair of vertices (i, j), if the distance between Vertex i and Vertex j is 3, the sum or product of p_i and p_j is a multiple of 3.\n\nHere the distance between Vertex i and Vertex j is the number of edges contained in the shortest path from Vertex i to Vertex j.\n\nHelp Takahashi by finding a permutation that satisfies the condition.\n\nConstraints\n\n2\\leq N\\leq 2\\times 10^5\n\n1\\leq a_i, b_i \\leq N\n\nThe given graph is a tree.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 b_1\na_2 b_2\n\\vdots\na_{N-1} b_{N-1}\n\nOutput\n\nIf no permutation satisfies the condition, print -1.\n\nOtherwise, print a permutation satisfying the condition, with space in between.\nIf there are multiple solutions, you can print any of them.\n\nSample Input 1\n\n5\n1 2\n1 3\n3 4\n3 5\n\nSample Output 1\n\n1 2 5 4 3\n\nThe distance between two vertices is 3 for the two pairs (2, 4) and (2, 5).\n\np_2 + p_4 = 6\n\np_2\\times p_5 = 6\n\nThus, this permutation satisfies the condition.", "sample_input": "5\n1 2\n1 3\n3 4\n3 5\n"}, "reference_outputs": ["1 2 5 4 3\n"], "source_document_id": "p02749", "source_text": "Score : 600 points\n\nProblem Statement\n\nWe have a tree with N vertices. The vertices are numbered 1 to N, and the i-th edge connects Vertex a_i and Vertex b_i.\n\nTakahashi loves the number 3. He is seeking a permutation p_1, p_2, \\ldots , p_N of integers from 1 to N satisfying the following condition:\n\nFor every pair of vertices (i, j), if the distance between Vertex i and Vertex j is 3, the sum or product of p_i and p_j is a multiple of 3.\n\nHere the distance between Vertex i and Vertex j is the number of edges contained in the shortest path from Vertex i to Vertex j.\n\nHelp Takahashi by finding a permutation that satisfies the condition.\n\nConstraints\n\n2\\leq N\\leq 2\\times 10^5\n\n1\\leq a_i, b_i \\leq N\n\nThe given graph is a tree.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 b_1\na_2 b_2\n\\vdots\na_{N-1} b_{N-1}\n\nOutput\n\nIf no permutation satisfies the condition, print -1.\n\nOtherwise, print a permutation satisfying the condition, with space in between.\nIf there are multiple solutions, you can print any of them.\n\nSample Input 1\n\n5\n1 2\n1 3\n3 4\n3 5\n\nSample Output 1\n\n1 2 5 4 3\n\nThe distance between two vertices is 3 for the two pairs (2, 4) and (2, 5).\n\np_2 + p_4 = 6\n\np_2\\times p_5 = 6\n\nThus, this permutation satisfies the condition.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2016, "cpu_time_ms": 186, "memory_kb": 21148}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s446252656", "group_id": "codeNet:p02749", "input_text": "#include <bits/stdc++.h>\n#define _overload3(_1, _2, _3, name, ...) name\n#define _rep(i, n) repi(i, 0, n)\n#define repi(i, a, b) for (ll i = (ll)(a); i < (ll)(b); ++i)\n#define rep(...) _overload3(__VA_ARGS__, repi, _rep, )(__VA_ARGS__)\n#define ll long long\n#define lld long double\n#define ALL(x) x.begin(), x.end()\nusing namespace std;\nconst ll INF = 1ll << 60;\nmap<int, vector<int>> g;\nmap<int, int> color;\nint red = 0;\nint blue = 0;\n\nvoid dfs(int cur, int par, int col)\n{\n    color[cur] = col;\n    if (col == 0)\n        red++;\n    else\n        blue++;\n    for (auto x : g[cur])\n    {\n        if (x != par)\n        {\n            dfs(x, cur, (col + 1) % 2);\n        }\n    }\n}\n\nint main()\n{\n    int n;\n    cin >> n;\n    rep(i, n - 1)\n    {\n        int a, b;\n        cin >> a >> b;\n        g[a].push_back(b);\n        g[b].push_back(a);\n    }\n    dfs(1, 0, 0);\n    deque<int> q[3];\n    rep(i, 1, n + 1) q[i % 3].push_back(i);\n    map<int, int> ans;\n    //0:red 1:blue\n    if (red <= n / 3)\n    {\n        rep(i, 1, n + 1)\n        {\n            if (color[i] == 0)\n            {\n                ans[i] = q[0].front();\n                q[0].pop_front();\n            }\n            else\n            {\n                for (int j = 2; j >= 0; j--)\n                {\n                    if (!q[j].empty())\n                    {\n                        ans[i] = q[j].front();\n                        q[i].pop_front();\n                    }\n                }\n            }\n        }\n    }\n    else if (blue <= n / 3)\n    {\n        rep(i, 1, n + 1)\n        {\n            if (color[i] == 1)\n            {\n                ans[i] = q[0].front();\n                q[0].pop_front();\n            }\n            else\n            {\n                for (int j = 2; j >= 0; j--)\n                {\n                    if (!q[j].empty())\n                    {\n                        ans[i] = q[j].front();\n                        q[i].pop_front();\n                    }\n                }\n            }\n        }\n    }\n    else\n    {\n        rep(i, 1, n + 1)\n        {\n            if (color[i] == 0)\n            {\n                if (!q[1].empty())\n                {\n                    ans[i] = q[1].front();\n                    q[1].pop_front();\n                }\n                else\n                {\n                    ans[i] = q[0].front();\n                    q[0].pop_front();\n                }\n            }\n            else\n            {\n                if (!q[2].empty())\n                {\n                    ans[i] = q[2].front();\n                    q[2].pop_front();\n                }\n                else\n                {\n                    ans[i] = q[0].front();\n                    q[0].pop_front();\n                }\n            }\n        }\n    }\n    rep(i, 1, n + 1)\n    {\n        cout << ans[i] << \" \";\n    }\n    cout << endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1583801287, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02749.html", "problem_id": "p02749", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02749/input.txt", "sample_output_relpath": "derived/input_output/data/p02749/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02749/C++/s446252656.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s446252656", "user_id": "u174404613"}, "prompt_components": {"gold_output": "1 2 5 4 3\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define _overload3(_1, _2, _3, name, ...) name\n#define _rep(i, n) repi(i, 0, n)\n#define repi(i, a, b) for (ll i = (ll)(a); i < (ll)(b); ++i)\n#define rep(...) _overload3(__VA_ARGS__, repi, _rep, )(__VA_ARGS__)\n#define ll long long\n#define lld long double\n#define ALL(x) x.begin(), x.end()\nusing namespace std;\nconst ll INF = 1ll << 60;\nmap<int, vector<int>> g;\nmap<int, int> color;\nint red = 0;\nint blue = 0;\n\nvoid dfs(int cur, int par, int col)\n{\n    color[cur] = col;\n    if (col == 0)\n        red++;\n    else\n        blue++;\n    for (auto x : g[cur])\n    {\n        if (x != par)\n        {\n            dfs(x, cur, (col + 1) % 2);\n        }\n    }\n}\n\nint main()\n{\n    int n;\n    cin >> n;\n    rep(i, n - 1)\n    {\n        int a, b;\n        cin >> a >> b;\n        g[a].push_back(b);\n        g[b].push_back(a);\n    }\n    dfs(1, 0, 0);\n    deque<int> q[3];\n    rep(i, 1, n + 1) q[i % 3].push_back(i);\n    map<int, int> ans;\n    //0:red 1:blue\n    if (red <= n / 3)\n    {\n        rep(i, 1, n + 1)\n        {\n            if (color[i] == 0)\n            {\n                ans[i] = q[0].front();\n                q[0].pop_front();\n            }\n            else\n            {\n                for (int j = 2; j >= 0; j--)\n                {\n                    if (!q[j].empty())\n                    {\n                        ans[i] = q[j].front();\n                        q[i].pop_front();\n                    }\n                }\n            }\n        }\n    }\n    else if (blue <= n / 3)\n    {\n        rep(i, 1, n + 1)\n        {\n            if (color[i] == 1)\n            {\n                ans[i] = q[0].front();\n                q[0].pop_front();\n            }\n            else\n            {\n                for (int j = 2; j >= 0; j--)\n                {\n                    if (!q[j].empty())\n                    {\n                        ans[i] = q[j].front();\n                        q[i].pop_front();\n                    }\n                }\n            }\n        }\n    }\n    else\n    {\n        rep(i, 1, n + 1)\n        {\n            if (color[i] == 0)\n            {\n                if (!q[1].empty())\n                {\n                    ans[i] = q[1].front();\n                    q[1].pop_front();\n                }\n                else\n                {\n                    ans[i] = q[0].front();\n                    q[0].pop_front();\n                }\n            }\n            else\n            {\n                if (!q[2].empty())\n                {\n                    ans[i] = q[2].front();\n                    q[2].pop_front();\n                }\n                else\n                {\n                    ans[i] = q[0].front();\n                    q[0].pop_front();\n                }\n            }\n        }\n    }\n    rep(i, 1, n + 1)\n    {\n        cout << ans[i] << \" \";\n    }\n    cout << endl;\n    return 0;\n}", "problem_context": "Score : 600 points\n\nProblem Statement\n\nWe have a tree with N vertices. The vertices are numbered 1 to N, and the i-th edge connects Vertex a_i and Vertex b_i.\n\nTakahashi loves the number 3. He is seeking a permutation p_1, p_2, \\ldots , p_N of integers from 1 to N satisfying the following condition:\n\nFor every pair of vertices (i, j), if the distance between Vertex i and Vertex j is 3, the sum or product of p_i and p_j is a multiple of 3.\n\nHere the distance between Vertex i and Vertex j is the number of edges contained in the shortest path from Vertex i to Vertex j.\n\nHelp Takahashi by finding a permutation that satisfies the condition.\n\nConstraints\n\n2\\leq N\\leq 2\\times 10^5\n\n1\\leq a_i, b_i \\leq N\n\nThe given graph is a tree.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 b_1\na_2 b_2\n\\vdots\na_{N-1} b_{N-1}\n\nOutput\n\nIf no permutation satisfies the condition, print -1.\n\nOtherwise, print a permutation satisfying the condition, with space in between.\nIf there are multiple solutions, you can print any of them.\n\nSample Input 1\n\n5\n1 2\n1 3\n3 4\n3 5\n\nSample Output 1\n\n1 2 5 4 3\n\nThe distance between two vertices is 3 for the two pairs (2, 4) and (2, 5).\n\np_2 + p_4 = 6\n\np_2\\times p_5 = 6\n\nThus, this permutation satisfies the condition.", "sample_input": "5\n1 2\n1 3\n3 4\n3 5\n"}, "reference_outputs": ["1 2 5 4 3\n"], "source_document_id": "p02749", "source_text": "Score : 600 points\n\nProblem Statement\n\nWe have a tree with N vertices. The vertices are numbered 1 to N, and the i-th edge connects Vertex a_i and Vertex b_i.\n\nTakahashi loves the number 3. He is seeking a permutation p_1, p_2, \\ldots , p_N of integers from 1 to N satisfying the following condition:\n\nFor every pair of vertices (i, j), if the distance between Vertex i and Vertex j is 3, the sum or product of p_i and p_j is a multiple of 3.\n\nHere the distance between Vertex i and Vertex j is the number of edges contained in the shortest path from Vertex i to Vertex j.\n\nHelp Takahashi by finding a permutation that satisfies the condition.\n\nConstraints\n\n2\\leq N\\leq 2\\times 10^5\n\n1\\leq a_i, b_i \\leq N\n\nThe given graph is a tree.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 b_1\na_2 b_2\n\\vdots\na_{N-1} b_{N-1}\n\nOutput\n\nIf no permutation satisfies the condition, print -1.\n\nOtherwise, print a permutation satisfying the condition, with space in between.\nIf there are multiple solutions, you can print any of them.\n\nSample Input 1\n\n5\n1 2\n1 3\n3 4\n3 5\n\nSample Output 1\n\n1 2 5 4 3\n\nThe distance between two vertices is 3 for the two pairs (2, 4) and (2, 5).\n\np_2 + p_4 = 6\n\np_2\\times p_5 = 6\n\nThus, this permutation satisfies the condition.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2834, "cpu_time_ms": 638, "memory_kb": 46592}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s321899550", "group_id": "codeNet:p02749", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n#define FOR(i, a, b) for(int i=(a);i<(b);++i)\n#define rep(i, n) FOR(i, 0, n)\n#define whole(x) (x).begin(),(x).end()\n#define UNIQUE(v) v.erase(unique(v.begin(), v.end()), v.end())\nusing ll = long long;\nusing P = pair<int, int>;\nconst int mod = 1000000007;\n\nvector<int> to[200005];\n//int root[200005];\nint depth[200005];\n\nvoid dfs(int v, int p=-1) {\n    if (p==-1) depth[v] = 0;\n    else {\n        depth[v] = depth[p]+1;\n    }\n    for(int e: to[v]) {\n        if(e==p) continue;\n        dfs(e, v);\n    }\n    \n}\n\nint main(){\n    int n;\n    cin >> n;\n    vector<int> p(n);\n    rep(i, n-1) {\n        int a, b;\n        cin >> a >> b;\n        a--; b--;\n        if (a>b) swap(a, b);\n        to[a].push_back(b);\n        to[b].push_back(a);\n    }\n    dfs(0, -1);\n    int odd = 0;\n    int even = 0;\n    rep(i, n) {\n        if (depth[i]%2) odd++;\n        else even++;\n    }\n    int mod3[3];\n    rep(i, 3) {\n        if (n%3==0) {\n            mod3[0] = n/3;\n            mod3[1] = n/3;\n            mod3[2] = n/3;\n        }\n        else if (n%3==1) {\n            mod3[0] = n/3;\n            mod3[1] = n/3+1;\n            mod3[2] = n/3+1;\n        }\n        else {\n            mod3[0] = n/3;\n            mod3[1] = n/3+1;\n            mod3[2] = n/3+1;\n        }\n    }\n    if (max(odd, even)>(mod3[0]+mod3[1])) {\n        cout << \"-1\" << endl;\n        return 0;\n    }\n    \n    vector<int> ans(n);\n    queue<int> res[3];\n    rep(i, n) {\n        int v = (i+1)%3;\n        res[v].push(i+1);\n    }\n    if (even>odd) {\n        rep(i, n) {\n            depth[i]++;\n        }\n    }\n    rep(i, n) {\n        if(depth[i]%2) {\n            if (!res[1].empty()) {\n                ans[i] = res[1].front();\n                res[1].pop();\n            }\n            else {\n                ans[i] = res[0].front();\n                res[0].pop();\n            }\n        }\n        else {\n            if (!res[2].empty()) {\n                ans[i] = res[2].front();\n                res[2].pop();\n            }\n            else {\n                ans[i] = res[0].front();\n                res[0].pop();\n            }\n        }\n        cout << ans[i] << \" \";\n    }\n    cout << endl;\n    \n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1583721553, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02749.html", "problem_id": "p02749", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02749/input.txt", "sample_output_relpath": "derived/input_output/data/p02749/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02749/C++/s321899550.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s321899550", "user_id": "u488493347"}, "prompt_components": {"gold_output": "1 2 5 4 3\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n#define FOR(i, a, b) for(int i=(a);i<(b);++i)\n#define rep(i, n) FOR(i, 0, n)\n#define whole(x) (x).begin(),(x).end()\n#define UNIQUE(v) v.erase(unique(v.begin(), v.end()), v.end())\nusing ll = long long;\nusing P = pair<int, int>;\nconst int mod = 1000000007;\n\nvector<int> to[200005];\n//int root[200005];\nint depth[200005];\n\nvoid dfs(int v, int p=-1) {\n    if (p==-1) depth[v] = 0;\n    else {\n        depth[v] = depth[p]+1;\n    }\n    for(int e: to[v]) {\n        if(e==p) continue;\n        dfs(e, v);\n    }\n    \n}\n\nint main(){\n    int n;\n    cin >> n;\n    vector<int> p(n);\n    rep(i, n-1) {\n        int a, b;\n        cin >> a >> b;\n        a--; b--;\n        if (a>b) swap(a, b);\n        to[a].push_back(b);\n        to[b].push_back(a);\n    }\n    dfs(0, -1);\n    int odd = 0;\n    int even = 0;\n    rep(i, n) {\n        if (depth[i]%2) odd++;\n        else even++;\n    }\n    int mod3[3];\n    rep(i, 3) {\n        if (n%3==0) {\n            mod3[0] = n/3;\n            mod3[1] = n/3;\n            mod3[2] = n/3;\n        }\n        else if (n%3==1) {\n            mod3[0] = n/3;\n            mod3[1] = n/3+1;\n            mod3[2] = n/3+1;\n        }\n        else {\n            mod3[0] = n/3;\n            mod3[1] = n/3+1;\n            mod3[2] = n/3+1;\n        }\n    }\n    if (max(odd, even)>(mod3[0]+mod3[1])) {\n        cout << \"-1\" << endl;\n        return 0;\n    }\n    \n    vector<int> ans(n);\n    queue<int> res[3];\n    rep(i, n) {\n        int v = (i+1)%3;\n        res[v].push(i+1);\n    }\n    if (even>odd) {\n        rep(i, n) {\n            depth[i]++;\n        }\n    }\n    rep(i, n) {\n        if(depth[i]%2) {\n            if (!res[1].empty()) {\n                ans[i] = res[1].front();\n                res[1].pop();\n            }\n            else {\n                ans[i] = res[0].front();\n                res[0].pop();\n            }\n        }\n        else {\n            if (!res[2].empty()) {\n                ans[i] = res[2].front();\n                res[2].pop();\n            }\n            else {\n                ans[i] = res[0].front();\n                res[0].pop();\n            }\n        }\n        cout << ans[i] << \" \";\n    }\n    cout << endl;\n    \n    return 0;\n}\n", "problem_context": "Score : 600 points\n\nProblem Statement\n\nWe have a tree with N vertices. The vertices are numbered 1 to N, and the i-th edge connects Vertex a_i and Vertex b_i.\n\nTakahashi loves the number 3. He is seeking a permutation p_1, p_2, \\ldots , p_N of integers from 1 to N satisfying the following condition:\n\nFor every pair of vertices (i, j), if the distance between Vertex i and Vertex j is 3, the sum or product of p_i and p_j is a multiple of 3.\n\nHere the distance between Vertex i and Vertex j is the number of edges contained in the shortest path from Vertex i to Vertex j.\n\nHelp Takahashi by finding a permutation that satisfies the condition.\n\nConstraints\n\n2\\leq N\\leq 2\\times 10^5\n\n1\\leq a_i, b_i \\leq N\n\nThe given graph is a tree.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 b_1\na_2 b_2\n\\vdots\na_{N-1} b_{N-1}\n\nOutput\n\nIf no permutation satisfies the condition, print -1.\n\nOtherwise, print a permutation satisfying the condition, with space in between.\nIf there are multiple solutions, you can print any of them.\n\nSample Input 1\n\n5\n1 2\n1 3\n3 4\n3 5\n\nSample Output 1\n\n1 2 5 4 3\n\nThe distance between two vertices is 3 for the two pairs (2, 4) and (2, 5).\n\np_2 + p_4 = 6\n\np_2\\times p_5 = 6\n\nThus, this permutation satisfies the condition.", "sample_input": "5\n1 2\n1 3\n3 4\n3 5\n"}, "reference_outputs": ["1 2 5 4 3\n"], "source_document_id": "p02749", "source_text": "Score : 600 points\n\nProblem Statement\n\nWe have a tree with N vertices. The vertices are numbered 1 to N, and the i-th edge connects Vertex a_i and Vertex b_i.\n\nTakahashi loves the number 3. He is seeking a permutation p_1, p_2, \\ldots , p_N of integers from 1 to N satisfying the following condition:\n\nFor every pair of vertices (i, j), if the distance between Vertex i and Vertex j is 3, the sum or product of p_i and p_j is a multiple of 3.\n\nHere the distance between Vertex i and Vertex j is the number of edges contained in the shortest path from Vertex i to Vertex j.\n\nHelp Takahashi by finding a permutation that satisfies the condition.\n\nConstraints\n\n2\\leq N\\leq 2\\times 10^5\n\n1\\leq a_i, b_i \\leq N\n\nThe given graph is a tree.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 b_1\na_2 b_2\n\\vdots\na_{N-1} b_{N-1}\n\nOutput\n\nIf no permutation satisfies the condition, print -1.\n\nOtherwise, print a permutation satisfying the condition, with space in between.\nIf there are multiple solutions, you can print any of them.\n\nSample Input 1\n\n5\n1 2\n1 3\n3 4\n3 5\n\nSample Output 1\n\n1 2 5 4 3\n\nThe distance between two vertices is 3 for the two pairs (2, 4) and (2, 5).\n\np_2 + p_4 = 6\n\np_2\\times p_5 = 6\n\nThus, this permutation satisfies the condition.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2194, "cpu_time_ms": 222, "memory_kb": 20224}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s235372052", "group_id": "codeNet:p02750", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\ntemplate<typename T>\nvoid out(T x) { cout << x << endl; exit(0); }\n#define watch(x) cout << (#x) << \" is \" << (x) << endl\n\n\n\n\n\nusing ll = long long;\n\nconst ll mod = 1e9+7;\nconst int maxn = 1e3 + 5;\nconst ll inf = 1e18;\n\n\nstruct store {\n    ll a, b;\n    void read() {\n\tcin>>a>>b;\n    }\n    bool operator<(const store&o ) const {\n\t//return b/a < o.b/o.a;\n\treturn (1+b)*o.a < (1+o.b)*a;\n    }\n};\n\nint n;\nll T;\n\n\nvoid relax(ll &x, ll y) {\n    x = min(x, y);\n}\n\n\nint main() {\n    ios_base::sync_with_stdio(false); cin.tie(0);  cout.tie(0);\n\n    cin>>n>>T;\n    vector<store> v;\n    vector<ll> B;\n    for (int i=0; i<n; i++) {\n\tstore s;\n\ts.read();\n\tif (s.a==0) {\n\t    B.push_back(s.b);\n\t} else {\n\t    v.push_back(s);\n\t}\n    }\n\n\n    sort(v.begin(), v.end());\n\n    const int N = 50; // > 1e9\n    // a(aT+b+1)+b -> a^i -> exponential time increase\n\n    vector<ll> dp(N+1, inf);\n    dp[0] = 0;\n\n    for (int i=0; i<(int)v.size(); i++) {\n\tfor (int j=N; j>=0; j--) {\n\t    if (dp[j] < T) {\n\t\trelax(dp[j+1], dp[j] + 1 + ((dp[j]+1)*v[i].a + v[i].b));\n\t    }\n\t}\n    }\n\n\n\n    sort(B.begin(), B.end());\n    vector<ll> cost;\n    cost.push_back(0);\n    for (int i=1; i<(int)B.size(); i++) {\n\tB[i] += B[i-1];\n    }\n    for (int i=0; i<(int)B.size(); i++) {\n\tcost.push_back((i+1) + B[i]);\n    }\n\n\n    int hi = 0;\n    for (int i=0; i<=N; i++) {\n\tif (dp[i] <= T) {\n\t    ll leftover = T-dp[i];\n\t    auto iter = std::prev(upper_bound(cost.begin(), cost.end(), leftover));\n\t    int take = i + (iter-cost.begin());\n\t    //watch(iter-cost.begin());\n\t    hi = max(hi, take);\n\t}\n    }\n\n    cout<<hi<<endl;    \n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1598702948, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02750.html", "problem_id": "p02750", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02750/input.txt", "sample_output_relpath": "derived/input_output/data/p02750/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02750/C++/s235372052.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s235372052", "user_id": "u774417629"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\ntemplate<typename T>\nvoid out(T x) { cout << x << endl; exit(0); }\n#define watch(x) cout << (#x) << \" is \" << (x) << endl\n\n\n\n\n\nusing ll = long long;\n\nconst ll mod = 1e9+7;\nconst int maxn = 1e3 + 5;\nconst ll inf = 1e18;\n\n\nstruct store {\n    ll a, b;\n    void read() {\n\tcin>>a>>b;\n    }\n    bool operator<(const store&o ) const {\n\t//return b/a < o.b/o.a;\n\treturn (1+b)*o.a < (1+o.b)*a;\n    }\n};\n\nint n;\nll T;\n\n\nvoid relax(ll &x, ll y) {\n    x = min(x, y);\n}\n\n\nint main() {\n    ios_base::sync_with_stdio(false); cin.tie(0);  cout.tie(0);\n\n    cin>>n>>T;\n    vector<store> v;\n    vector<ll> B;\n    for (int i=0; i<n; i++) {\n\tstore s;\n\ts.read();\n\tif (s.a==0) {\n\t    B.push_back(s.b);\n\t} else {\n\t    v.push_back(s);\n\t}\n    }\n\n\n    sort(v.begin(), v.end());\n\n    const int N = 50; // > 1e9\n    // a(aT+b+1)+b -> a^i -> exponential time increase\n\n    vector<ll> dp(N+1, inf);\n    dp[0] = 0;\n\n    for (int i=0; i<(int)v.size(); i++) {\n\tfor (int j=N; j>=0; j--) {\n\t    if (dp[j] < T) {\n\t\trelax(dp[j+1], dp[j] + 1 + ((dp[j]+1)*v[i].a + v[i].b));\n\t    }\n\t}\n    }\n\n\n\n    sort(B.begin(), B.end());\n    vector<ll> cost;\n    cost.push_back(0);\n    for (int i=1; i<(int)B.size(); i++) {\n\tB[i] += B[i-1];\n    }\n    for (int i=0; i<(int)B.size(); i++) {\n\tcost.push_back((i+1) + B[i]);\n    }\n\n\n    int hi = 0;\n    for (int i=0; i<=N; i++) {\n\tif (dp[i] <= T) {\n\t    ll leftover = T-dp[i];\n\t    auto iter = std::prev(upper_bound(cost.begin(), cost.end(), leftover));\n\t    int take = i + (iter-cost.begin());\n\t    //watch(iter-cost.begin());\n\t    hi = max(hi, take);\n\t}\n    }\n\n    cout<<hi<<endl;    \n    return 0;\n}\n", "problem_context": "Score : 800 points\n\nProblem Statement\n\nThere are N stores called Store 1, Store 2, \\cdots, Store N. Takahashi, who is at his house at time 0, is planning to visit some of these stores.\n\nIt takes Takahashi one unit of time to travel from his house to one of the stores, or between any two stores.\n\nIf Takahashi reaches Store i at time t, he can do shopping there after standing in a queue for a_i \\times t + b_i units of time. (We assume that it takes no time other than waiting.)\n\nAll the stores close at time T + 0.5. If Takahashi is standing in a queue for some store then, he cannot do shopping there.\n\nTakahashi does not do shopping more than once in the same store.\n\nFind the maximum number of times he can do shopping before time T + 0.5.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 2 \\times 10^5\n\n0 \\leq a_i \\leq 10^9\n\n0 \\leq b_i \\leq 10^9\n\n0 \\leq T \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN T\na_1 b_1\na_2 b_2\n\\vdots\na_N b_N\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n3 7\n2 0\n3 2\n0 3\n\nSample Output 1\n\n2\n\nHere is one possible way to visit stores:\n\nFrom time 0 to time 1: in 1 unit of time, he travels from his house to Store 1.\n\nFrom time 1 to time 3: for 2 units of time, he stands in a queue for Store 1 to do shopping.\n\nFrom time 3 to time 4: in 1 unit of time, he travels from Store 1 to Store 3.\n\nFrom time 4 to time 7: for 3 units of time, he stands in a queue for Store 3 to do shopping.\n\nIn this way, he can do shopping twice before time 7.5.\n\nSample Input 2\n\n1 3\n0 3\n\nSample Output 2\n\n0\n\nSample Input 3\n\n5 21600\n2 14\n3 22\n1 3\n1 10\n1 9\n\nSample Output 3\n\n5\n\nSample Input 4\n\n7 57\n0 25\n3 10\n2 4\n5 15\n3 22\n2 14\n1 15\n\nSample Output 4\n\n3", "sample_input": "3 7\n2 0\n3 2\n0 3\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02750", "source_text": "Score : 800 points\n\nProblem Statement\n\nThere are N stores called Store 1, Store 2, \\cdots, Store N. Takahashi, who is at his house at time 0, is planning to visit some of these stores.\n\nIt takes Takahashi one unit of time to travel from his house to one of the stores, or between any two stores.\n\nIf Takahashi reaches Store i at time t, he can do shopping there after standing in a queue for a_i \\times t + b_i units of time. (We assume that it takes no time other than waiting.)\n\nAll the stores close at time T + 0.5. If Takahashi is standing in a queue for some store then, he cannot do shopping there.\n\nTakahashi does not do shopping more than once in the same store.\n\nFind the maximum number of times he can do shopping before time T + 0.5.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 2 \\times 10^5\n\n0 \\leq a_i \\leq 10^9\n\n0 \\leq b_i \\leq 10^9\n\n0 \\leq T \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN T\na_1 b_1\na_2 b_2\n\\vdots\na_N b_N\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n3 7\n2 0\n3 2\n0 3\n\nSample Output 1\n\n2\n\nHere is one possible way to visit stores:\n\nFrom time 0 to time 1: in 1 unit of time, he travels from his house to Store 1.\n\nFrom time 1 to time 3: for 2 units of time, he stands in a queue for Store 1 to do shopping.\n\nFrom time 3 to time 4: in 1 unit of time, he travels from Store 1 to Store 3.\n\nFrom time 4 to time 7: for 3 units of time, he stands in a queue for Store 3 to do shopping.\n\nIn this way, he can do shopping twice before time 7.5.\n\nSample Input 2\n\n1 3\n0 3\n\nSample Output 2\n\n0\n\nSample Input 3\n\n5 21600\n2 14\n3 22\n1 3\n1 10\n1 9\n\nSample Output 3\n\n5\n\nSample Input 4\n\n7 57\n0 25\n3 10\n2 4\n5 15\n3 22\n2 14\n1 15\n\nSample Output 4\n\n3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1641, "cpu_time_ms": 63, "memory_kb": 7928}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s224271966", "group_id": "codeNet:p02751", "input_text": "#include <bits/stdc++.h>\n#define rep(i, n) for (int i = 0; i < (n); ++i)\n#define sz(x) int(x.size())\nusing namespace std;\n\ntypedef long long ll;\n// const int INF = 1e8;\nconst ll INF = 1LL << 60;\ntypedef pair<int, int> P;\n\nll N, M;\n\nint main() {\n    cin >> N >> M;\n    ll n = pow(2, N) - 1;\n    ll m = pow(2, M) - 1;\n\n    if (n == 1) {\n        rep(i, m) {\n            cout << 1;\n        }\n        cout << endl;\n        return 0;\n    } else if (m == 1) {\n        rep(i, n) {\n            cout << 1 << endl;\n        }\n        return 0;\n    }\n\n    rep(i, n) {\n        rep(j, m) {\n            if (i == 0 && j == 0) cout << 0;\n            else cout << 1;\n        }\n        cout << endl;\n    }\n}", "language": "C++", "metadata": {"date": 1583722027, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02751.html", "problem_id": "p02751", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02751/input.txt", "sample_output_relpath": "derived/input_output/data/p02751/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02751/C++/s224271966.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s224271966", "user_id": "u455366471"}, "prompt_components": {"gold_output": "111\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define rep(i, n) for (int i = 0; i < (n); ++i)\n#define sz(x) int(x.size())\nusing namespace std;\n\ntypedef long long ll;\n// const int INF = 1e8;\nconst ll INF = 1LL << 60;\ntypedef pair<int, int> P;\n\nll N, M;\n\nint main() {\n    cin >> N >> M;\n    ll n = pow(2, N) - 1;\n    ll m = pow(2, M) - 1;\n\n    if (n == 1) {\n        rep(i, m) {\n            cout << 1;\n        }\n        cout << endl;\n        return 0;\n    } else if (m == 1) {\n        rep(i, n) {\n            cout << 1 << endl;\n        }\n        return 0;\n    }\n\n    rep(i, n) {\n        rep(j, m) {\n            if (i == 0 && j == 0) cout << 0;\n            else cout << 1;\n        }\n        cout << endl;\n    }\n}", "problem_context": "Score : 900 points\n\nProblem Statement\n\nWe have a grid with (2^N - 1) rows and (2^M-1) columns.\nYou are asked to write 0 or 1 in each of these squares.\nLet a_{i,j} be the number written in the square at the i-th row from the top and the j-th column from the left.\n\nFor a quadruple of integers (i_1, i_2, j_1, j_2) such that 1\\leq i_1 \\leq i_2\\leq 2^N-1, 1\\leq j_1 \\leq j_2\\leq 2^M-1, let\nS(i_1, i_2, j_1, j_2) = \\displaystyle \\sum_{r=i_1}^{i_2}\\sum_{c=j_1}^{j_2}a_{r,c}.\nThen, let the oddness of the grid be the number of quadruples (i_1, i_2, j_1, j_2) such that S(i_1, i_2, j_1, j_2) is odd.\n\nFind a way to fill in the grid that maximizes its oddness.\n\nConstraints\n\nN and M are integers between 1 and 10 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\n\nOutput\n\nPrint numbers to write in the grid so that its oddness is maximized, in the following format:\n\na_{1,1}a_{1,2}\\cdots a_{1,2^M-1}\na_{2,1}a_{2,2}\\cdots a_{2,2^M-1}\n\\vdots\na_{2^N-1,1}a_{2^N-1,2}\\cdots a_{2^N-1,2^M-1}\n\nIf there are multiple solutions, you can print any of them.\n\nSample Input 1\n\n1 2\n\nSample Output 1\n\n111\n\nFor this grid, S(1, 1, 1, 1), S(1, 1, 2, 2), S(1, 1, 3, 3), and S(1, 1, 1, 3) are odd, so it has the oddness of 4.\n\nWe cannot make the oddness 5 or higher, so this is one of the ways that maximize the oddness.", "sample_input": "1 2\n"}, "reference_outputs": ["111\n"], "source_document_id": "p02751", "source_text": "Score : 900 points\n\nProblem Statement\n\nWe have a grid with (2^N - 1) rows and (2^M-1) columns.\nYou are asked to write 0 or 1 in each of these squares.\nLet a_{i,j} be the number written in the square at the i-th row from the top and the j-th column from the left.\n\nFor a quadruple of integers (i_1, i_2, j_1, j_2) such that 1\\leq i_1 \\leq i_2\\leq 2^N-1, 1\\leq j_1 \\leq j_2\\leq 2^M-1, let\nS(i_1, i_2, j_1, j_2) = \\displaystyle \\sum_{r=i_1}^{i_2}\\sum_{c=j_1}^{j_2}a_{r,c}.\nThen, let the oddness of the grid be the number of quadruples (i_1, i_2, j_1, j_2) such that S(i_1, i_2, j_1, j_2) is odd.\n\nFind a way to fill in the grid that maximizes its oddness.\n\nConstraints\n\nN and M are integers between 1 and 10 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\n\nOutput\n\nPrint numbers to write in the grid so that its oddness is maximized, in the following format:\n\na_{1,1}a_{1,2}\\cdots a_{1,2^M-1}\na_{2,1}a_{2,2}\\cdots a_{2,2^M-1}\n\\vdots\na_{2^N-1,1}a_{2^N-1,2}\\cdots a_{2^N-1,2^M-1}\n\nIf there are multiple solutions, you can print any of them.\n\nSample Input 1\n\n1 2\n\nSample Output 1\n\n111\n\nFor this grid, S(1, 1, 1, 1), S(1, 1, 2, 2), S(1, 1, 3, 3), and S(1, 1, 1, 3) are odd, so it has the oddness of 4.\n\nWe cannot make the oddness 5 or higher, so this is one of the ways that maximize the oddness.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 687, "cpu_time_ms": 52, "memory_kb": 1280}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s009978965", "group_id": "codeNet:p02753", "input_text": "#include <bits/stdc++.h>\n#define pi 3.14159\nusing namespace std;\n\nint main()\n {\n \tstring s;\n \tcin>>s;\n \tif(s[0]==s[1]&&s[1]==s[2])\n \t\tcout<<\"No\"<<endl;\n \telse\n \t\tcout<<\"Yes\"<<endl;\n \treturn 0;\n}\n \t\n \t\t\t\t\t", "language": "C++", "metadata": {"date": 1593975614, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02753.html", "problem_id": "p02753", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02753/input.txt", "sample_output_relpath": "derived/input_output/data/p02753/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02753/C++/s009978965.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s009978965", "user_id": "u246218976"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define pi 3.14159\nusing namespace std;\n\nint main()\n {\n \tstring s;\n \tcin>>s;\n \tif(s[0]==s[1]&&s[1]==s[2])\n \t\tcout<<\"No\"<<endl;\n \telse\n \t\tcout<<\"Yes\"<<endl;\n \treturn 0;\n}\n \t\n \t\t\t\t\t", "problem_context": "Score : 100 points\n\nProblem Statement\n\nIn AtCoder City, there are three stations numbered 1, 2, and 3.\n\nEach of these stations is operated by one of the two railway companies, A and B. A string S of length 3 represents which company operates each station. If S_i is A, Company A operates Station i; if S_i is B, Company B operates Station i.\n\nTo improve the transportation condition, for each pair of a station operated by Company A and one operated by Company B, there will be a bus service connecting them.\n\nDetermine if there is a pair of stations that will be connected by a bus service.\n\nConstraints\n\nEach character of S is A or B.\n\n|S| = 3\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nIf there is a pair of stations that will be connected by a bus service, print Yes; otherwise, print No.\n\nSample Input 1\n\nABA\n\nSample Output 1\n\nYes\n\nCompany A operates Station 1 and 3, while Company B operates Station 2.\n\nThere will be a bus service between Station 1 and 2, and between Station 2 and 3, so print Yes.\n\nSample Input 2\n\nBBA\n\nSample Output 2\n\nYes\n\nCompany B operates Station 1 and 2, while Company A operates Station 3.\n\nThere will be a bus service between Station 1 and 3, and between Station 2 and 3, so print Yes.\n\nSample Input 3\n\nBBB\n\nSample Output 3\n\nNo\n\nCompany B operates all the stations. Thus, there will be no bus service, so print No.", "sample_input": "ABA\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p02753", "source_text": "Score : 100 points\n\nProblem Statement\n\nIn AtCoder City, there are three stations numbered 1, 2, and 3.\n\nEach of these stations is operated by one of the two railway companies, A and B. A string S of length 3 represents which company operates each station. If S_i is A, Company A operates Station i; if S_i is B, Company B operates Station i.\n\nTo improve the transportation condition, for each pair of a station operated by Company A and one operated by Company B, there will be a bus service connecting them.\n\nDetermine if there is a pair of stations that will be connected by a bus service.\n\nConstraints\n\nEach character of S is A or B.\n\n|S| = 3\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nIf there is a pair of stations that will be connected by a bus service, print Yes; otherwise, print No.\n\nSample Input 1\n\nABA\n\nSample Output 1\n\nYes\n\nCompany A operates Station 1 and 3, while Company B operates Station 2.\n\nThere will be a bus service between Station 1 and 2, and between Station 2 and 3, so print Yes.\n\nSample Input 2\n\nBBA\n\nSample Output 2\n\nYes\n\nCompany B operates Station 1 and 2, while Company A operates Station 3.\n\nThere will be a bus service between Station 1 and 3, and between Station 2 and 3, so print Yes.\n\nSample Input 3\n\nBBB\n\nSample Output 3\n\nNo\n\nCompany B operates all the stations. Thus, there will be no bus service, so print No.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 204, "cpu_time_ms": 7, "memory_kb": 3548}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s020571343", "group_id": "codeNet:p02754", "input_text": "#include <bits/stdc++.h>\n#define rep(i, n) for(int i = 0; i < n; i++)\n \nusing namespace std;\n \nint main() {\n  int N, A, B, ans;\n  cin >> N >> A >> B;\n  int x = N / (A + B);\n  if(N % (A + B) == 0){\n    ans = A * x;\n  }\n  else{ \n    ans = A * x + min(A, N - ((A + B) * x));\n  }\n  cout << ans << endl;\n  \n}", "language": "C++", "metadata": {"date": 1583641097, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02754.html", "problem_id": "p02754", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02754/input.txt", "sample_output_relpath": "derived/input_output/data/p02754/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02754/C++/s020571343.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s020571343", "user_id": "u684002488"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define rep(i, n) for(int i = 0; i < n; i++)\n \nusing namespace std;\n \nint main() {\n  int N, A, B, ans;\n  cin >> N >> A >> B;\n  int x = N / (A + B);\n  if(N % (A + B) == 0){\n    ans = A * x;\n  }\n  else{ \n    ans = A * x + min(A, N - ((A + B) * x));\n  }\n  cout << ans << endl;\n  \n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nTakahashi has many red balls and blue balls. Now, he will place them in a row.\n\nInitially, there is no ball placed.\n\nTakahashi, who is very patient, will do the following operation 10^{100} times:\n\nPlace A blue balls at the end of the row of balls already placed. Then, place B red balls at the end of the row.\n\nHow many blue balls will be there among the first N balls in the row of balls made this way?\n\nConstraints\n\n1 \\leq N \\leq 10^{18}\n\nA, B \\geq 0\n\n0 < A + B \\leq 10^{18}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN A B\n\nOutput\n\nPrint the number of blue balls that will be there among the first N balls in the row of balls.\n\nSample Input 1\n\n8 3 4\n\nSample Output 1\n\n4\n\nLet b denote a blue ball, and r denote a red ball. The first eight balls in the row will be bbbrrrrb, among which there are four blue balls.\n\nSample Input 2\n\n8 0 4\n\nSample Output 2\n\n0\n\nHe placed only red balls from the beginning.\n\nSample Input 3\n\n6 2 4\n\nSample Output 3\n\n2\n\nAmong bbrrrr, there are two blue balls.", "sample_input": "8 3 4\n"}, "reference_outputs": ["4\n"], "source_document_id": "p02754", "source_text": "Score : 200 points\n\nProblem Statement\n\nTakahashi has many red balls and blue balls. Now, he will place them in a row.\n\nInitially, there is no ball placed.\n\nTakahashi, who is very patient, will do the following operation 10^{100} times:\n\nPlace A blue balls at the end of the row of balls already placed. Then, place B red balls at the end of the row.\n\nHow many blue balls will be there among the first N balls in the row of balls made this way?\n\nConstraints\n\n1 \\leq N \\leq 10^{18}\n\nA, B \\geq 0\n\n0 < A + B \\leq 10^{18}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN A B\n\nOutput\n\nPrint the number of blue balls that will be there among the first N balls in the row of balls.\n\nSample Input 1\n\n8 3 4\n\nSample Output 1\n\n4\n\nLet b denote a blue ball, and r denote a red ball. The first eight balls in the row will be bbbrrrrb, among which there are four blue balls.\n\nSample Input 2\n\n8 0 4\n\nSample Output 2\n\n0\n\nHe placed only red balls from the beginning.\n\nSample Input 3\n\n6 2 4\n\nSample Output 3\n\n2\n\nAmong bbrrrr, there are two blue balls.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 303, "cpu_time_ms": 98, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s872451548", "group_id": "codeNet:p02754", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n   int n, a ,b, c=0, cntball=0;\n   string s=\"\";\n   cin>>n>>a>>b;\n   for(int i=0 ; i<n ; i++){\n       if(cntball==n)break;\n    for(int j=0 ; j<a ; j++){s+='b';cntball++; if(cntball==n)break;}\n    if(cntball==n)break;\n    for(int k=0 ; k<b ; k++){s+='r';cntball++; if(cntball==n)break;}\n    if(cntball==n)break;\n   }\n   for(int i=0 ; i<s.size() ; i++)\n   if(s[i]=='b')c++;\n   \n   cout<<c<<\" \"<<s;;\n}", "language": "C++", "metadata": {"date": 1583640074, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02754.html", "problem_id": "p02754", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02754/input.txt", "sample_output_relpath": "derived/input_output/data/p02754/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02754/C++/s872451548.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s872451548", "user_id": "u846716020"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n   int n, a ,b, c=0, cntball=0;\n   string s=\"\";\n   cin>>n>>a>>b;\n   for(int i=0 ; i<n ; i++){\n       if(cntball==n)break;\n    for(int j=0 ; j<a ; j++){s+='b';cntball++; if(cntball==n)break;}\n    if(cntball==n)break;\n    for(int k=0 ; k<b ; k++){s+='r';cntball++; if(cntball==n)break;}\n    if(cntball==n)break;\n   }\n   for(int i=0 ; i<s.size() ; i++)\n   if(s[i]=='b')c++;\n   \n   cout<<c<<\" \"<<s;;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nTakahashi has many red balls and blue balls. Now, he will place them in a row.\n\nInitially, there is no ball placed.\n\nTakahashi, who is very patient, will do the following operation 10^{100} times:\n\nPlace A blue balls at the end of the row of balls already placed. Then, place B red balls at the end of the row.\n\nHow many blue balls will be there among the first N balls in the row of balls made this way?\n\nConstraints\n\n1 \\leq N \\leq 10^{18}\n\nA, B \\geq 0\n\n0 < A + B \\leq 10^{18}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN A B\n\nOutput\n\nPrint the number of blue balls that will be there among the first N balls in the row of balls.\n\nSample Input 1\n\n8 3 4\n\nSample Output 1\n\n4\n\nLet b denote a blue ball, and r denote a red ball. The first eight balls in the row will be bbbrrrrb, among which there are four blue balls.\n\nSample Input 2\n\n8 0 4\n\nSample Output 2\n\n0\n\nHe placed only red balls from the beginning.\n\nSample Input 3\n\n6 2 4\n\nSample Output 3\n\n2\n\nAmong bbrrrr, there are two blue balls.", "sample_input": "8 3 4\n"}, "reference_outputs": ["4\n"], "source_document_id": "p02754", "source_text": "Score : 200 points\n\nProblem Statement\n\nTakahashi has many red balls and blue balls. Now, he will place them in a row.\n\nInitially, there is no ball placed.\n\nTakahashi, who is very patient, will do the following operation 10^{100} times:\n\nPlace A blue balls at the end of the row of balls already placed. Then, place B red balls at the end of the row.\n\nHow many blue balls will be there among the first N balls in the row of balls made this way?\n\nConstraints\n\n1 \\leq N \\leq 10^{18}\n\nA, B \\geq 0\n\n0 < A + B \\leq 10^{18}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN A B\n\nOutput\n\nPrint the number of blue balls that will be there among the first N balls in the row of balls.\n\nSample Input 1\n\n8 3 4\n\nSample Output 1\n\n4\n\nLet b denote a blue ball, and r denote a red ball. The first eight balls in the row will be bbbrrrrb, among which there are four blue balls.\n\nSample Input 2\n\n8 0 4\n\nSample Output 2\n\n0\n\nHe placed only red balls from the beginning.\n\nSample Input 3\n\n6 2 4\n\nSample Output 3\n\n2\n\nAmong bbrrrr, there are two blue balls.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 455, "cpu_time_ms": 2108, "memory_kb": 1050884}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s998864007", "group_id": "codeNet:p02754", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n  long long n,a,b,ans=0;\n  cin>>n>>a>>b;\n  ans+=(n%(a+b))*a;\n  n-=(n%(a+b))*a;\n  if(n>=a) ans+=a;\n  else ans+=n;\n  cout<<ans<<endl;\n  return 0;\n}", "language": "C++", "metadata": {"date": 1583636478, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02754.html", "problem_id": "p02754", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02754/input.txt", "sample_output_relpath": "derived/input_output/data/p02754/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02754/C++/s998864007.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s998864007", "user_id": "u814514683"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n  long long n,a,b,ans=0;\n  cin>>n>>a>>b;\n  ans+=(n%(a+b))*a;\n  n-=(n%(a+b))*a;\n  if(n>=a) ans+=a;\n  else ans+=n;\n  cout<<ans<<endl;\n  return 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nTakahashi has many red balls and blue balls. Now, he will place them in a row.\n\nInitially, there is no ball placed.\n\nTakahashi, who is very patient, will do the following operation 10^{100} times:\n\nPlace A blue balls at the end of the row of balls already placed. Then, place B red balls at the end of the row.\n\nHow many blue balls will be there among the first N balls in the row of balls made this way?\n\nConstraints\n\n1 \\leq N \\leq 10^{18}\n\nA, B \\geq 0\n\n0 < A + B \\leq 10^{18}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN A B\n\nOutput\n\nPrint the number of blue balls that will be there among the first N balls in the row of balls.\n\nSample Input 1\n\n8 3 4\n\nSample Output 1\n\n4\n\nLet b denote a blue ball, and r denote a red ball. The first eight balls in the row will be bbbrrrrb, among which there are four blue balls.\n\nSample Input 2\n\n8 0 4\n\nSample Output 2\n\n0\n\nHe placed only red balls from the beginning.\n\nSample Input 3\n\n6 2 4\n\nSample Output 3\n\n2\n\nAmong bbrrrr, there are two blue balls.", "sample_input": "8 3 4\n"}, "reference_outputs": ["4\n"], "source_document_id": "p02754", "source_text": "Score : 200 points\n\nProblem Statement\n\nTakahashi has many red balls and blue balls. Now, he will place them in a row.\n\nInitially, there is no ball placed.\n\nTakahashi, who is very patient, will do the following operation 10^{100} times:\n\nPlace A blue balls at the end of the row of balls already placed. Then, place B red balls at the end of the row.\n\nHow many blue balls will be there among the first N balls in the row of balls made this way?\n\nConstraints\n\n1 \\leq N \\leq 10^{18}\n\nA, B \\geq 0\n\n0 < A + B \\leq 10^{18}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN A B\n\nOutput\n\nPrint the number of blue balls that will be there among the first N balls in the row of balls.\n\nSample Input 1\n\n8 3 4\n\nSample Output 1\n\n4\n\nLet b denote a blue ball, and r denote a red ball. The first eight balls in the row will be bbbrrrrb, among which there are four blue balls.\n\nSample Input 2\n\n8 0 4\n\nSample Output 2\n\n0\n\nHe placed only red balls from the beginning.\n\nSample Input 3\n\n6 2 4\n\nSample Output 3\n\n2\n\nAmong bbrrrr, there are two blue balls.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 202, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s203601883", "group_id": "codeNet:p02754", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long ;\nint main()\n{\n    ll N, A, B;\n    cin >> N >> A >> B;\n\n    if(A == 0 && B == 0) \n    {\n        cout << 0 << endl;\n        return 0;\n    }\n    if(A == 0) \n    {\n        cout << 0 << endl;\n        return 0;\n    }\n\n    ll quotient = N /(A+B);\n    ll rem = N % (A+B);\n\n\n    ll result = A*quotient ;\n    if(rem <= A)\n    {\n        result += rem;\n    }\n    else\n    {\n        result += rem;\n    }\n    \n    cout << result << endl;\n\n\n    return 0;\n}", "language": "C++", "metadata": {"date": 1583633812, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02754.html", "problem_id": "p02754", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02754/input.txt", "sample_output_relpath": "derived/input_output/data/p02754/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02754/C++/s203601883.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s203601883", "user_id": "u090445726"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long ;\nint main()\n{\n    ll N, A, B;\n    cin >> N >> A >> B;\n\n    if(A == 0 && B == 0) \n    {\n        cout << 0 << endl;\n        return 0;\n    }\n    if(A == 0) \n    {\n        cout << 0 << endl;\n        return 0;\n    }\n\n    ll quotient = N /(A+B);\n    ll rem = N % (A+B);\n\n\n    ll result = A*quotient ;\n    if(rem <= A)\n    {\n        result += rem;\n    }\n    else\n    {\n        result += rem;\n    }\n    \n    cout << result << endl;\n\n\n    return 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nTakahashi has many red balls and blue balls. Now, he will place them in a row.\n\nInitially, there is no ball placed.\n\nTakahashi, who is very patient, will do the following operation 10^{100} times:\n\nPlace A blue balls at the end of the row of balls already placed. Then, place B red balls at the end of the row.\n\nHow many blue balls will be there among the first N balls in the row of balls made this way?\n\nConstraints\n\n1 \\leq N \\leq 10^{18}\n\nA, B \\geq 0\n\n0 < A + B \\leq 10^{18}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN A B\n\nOutput\n\nPrint the number of blue balls that will be there among the first N balls in the row of balls.\n\nSample Input 1\n\n8 3 4\n\nSample Output 1\n\n4\n\nLet b denote a blue ball, and r denote a red ball. The first eight balls in the row will be bbbrrrrb, among which there are four blue balls.\n\nSample Input 2\n\n8 0 4\n\nSample Output 2\n\n0\n\nHe placed only red balls from the beginning.\n\nSample Input 3\n\n6 2 4\n\nSample Output 3\n\n2\n\nAmong bbrrrr, there are two blue balls.", "sample_input": "8 3 4\n"}, "reference_outputs": ["4\n"], "source_document_id": "p02754", "source_text": "Score : 200 points\n\nProblem Statement\n\nTakahashi has many red balls and blue balls. Now, he will place them in a row.\n\nInitially, there is no ball placed.\n\nTakahashi, who is very patient, will do the following operation 10^{100} times:\n\nPlace A blue balls at the end of the row of balls already placed. Then, place B red balls at the end of the row.\n\nHow many blue balls will be there among the first N balls in the row of balls made this way?\n\nConstraints\n\n1 \\leq N \\leq 10^{18}\n\nA, B \\geq 0\n\n0 < A + B \\leq 10^{18}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN A B\n\nOutput\n\nPrint the number of blue balls that will be there among the first N balls in the row of balls.\n\nSample Input 1\n\n8 3 4\n\nSample Output 1\n\n4\n\nLet b denote a blue ball, and r denote a red ball. The first eight balls in the row will be bbbrrrrb, among which there are four blue balls.\n\nSample Input 2\n\n8 0 4\n\nSample Output 2\n\n0\n\nHe placed only red balls from the beginning.\n\nSample Input 3\n\n6 2 4\n\nSample Output 3\n\n2\n\nAmong bbrrrr, there are two blue balls.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 510, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s023138029", "group_id": "codeNet:p02755", "input_text": "#include <iostream>\n\nusing namespace std;\n\nint SolveTaxIncrease(int A, int B) {\n  for (int p = 10 * B; p <= 10 * B + 9; ++p) {\n    const int tax = 8 * p / 100;\n    if (tax == A) return p;\n  }\n  return -1;\n}\n\nint main() {\n  int A, B;\n  cin >> A >> B;\n  cout << SolveTaxIncrease(A, B) << endl;\n\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1583643829, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02755.html", "problem_id": "p02755", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02755/input.txt", "sample_output_relpath": "derived/input_output/data/p02755/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02755/C++/s023138029.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s023138029", "user_id": "u090097090"}, "prompt_components": {"gold_output": "25\n", "input_to_evaluate": "#include <iostream>\n\nusing namespace std;\n\nint SolveTaxIncrease(int A, int B) {\n  for (int p = 10 * B; p <= 10 * B + 9; ++p) {\n    const int tax = 8 * p / 100;\n    if (tax == A) return p;\n  }\n  return -1;\n}\n\nint main() {\n  int A, B;\n  cin >> A >> B;\n  cout << SolveTaxIncrease(A, B) << endl;\n\n  return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nFind the price of a product before tax such that, when the consumption tax rate is 8 percent and 10 percent, the amount of consumption tax levied on it is A yen and B yen, respectively. (Yen is the currency of Japan.)\n\nHere, the price before tax must be a positive integer, and the amount of consumption tax is rounded down to the nearest integer.\n\nIf multiple prices satisfy the condition, print the lowest such price; if no price satisfies the condition, print -1.\n\nConstraints\n\n1 \\leq A \\leq B \\leq 100\n\nA and B are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nIf there is a price that satisfies the condition, print an integer representing the lowest such price; otherwise, print -1.\n\nSample Input 1\n\n2 2\n\nSample Output 1\n\n25\n\nIf the price of a product before tax is 25 yen, the amount of consumption tax levied on it is:\n\nWhen the consumption tax rate is 8 percent: \\lfloor 25 \\times 0.08 \\rfloor = \\lfloor 2 \\rfloor = 2 yen.\n\nWhen the consumption tax rate is 10 percent: \\lfloor 25 \\times 0.1 \\rfloor = \\lfloor 2.5 \\rfloor = 2 yen.\n\nThus, the price of 25 yen satisfies the condition. There are other possible prices, such as 26 yen, but print the minimum such price, 25.\n\nSample Input 2\n\n8 10\n\nSample Output 2\n\n100\n\nIf the price of a product before tax is 100 yen, the amount of consumption tax levied on it is:\n\nWhen the consumption tax rate is 8 percent: \\lfloor 100 \\times 0.08 \\rfloor = 8 yen.\n\nWhen the consumption tax rate is 10 percent: \\lfloor 100 \\times 0.1 \\rfloor = 10 yen.\n\nSample Input 3\n\n19 99\n\nSample Output 3\n\n-1\n\nThere is no price before tax satisfying this condition, so print -1.", "sample_input": "2 2\n"}, "reference_outputs": ["25\n"], "source_document_id": "p02755", "source_text": "Score : 300 points\n\nProblem Statement\n\nFind the price of a product before tax such that, when the consumption tax rate is 8 percent and 10 percent, the amount of consumption tax levied on it is A yen and B yen, respectively. (Yen is the currency of Japan.)\n\nHere, the price before tax must be a positive integer, and the amount of consumption tax is rounded down to the nearest integer.\n\nIf multiple prices satisfy the condition, print the lowest such price; if no price satisfies the condition, print -1.\n\nConstraints\n\n1 \\leq A \\leq B \\leq 100\n\nA and B are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nIf there is a price that satisfies the condition, print an integer representing the lowest such price; otherwise, print -1.\n\nSample Input 1\n\n2 2\n\nSample Output 1\n\n25\n\nIf the price of a product before tax is 25 yen, the amount of consumption tax levied on it is:\n\nWhen the consumption tax rate is 8 percent: \\lfloor 25 \\times 0.08 \\rfloor = \\lfloor 2 \\rfloor = 2 yen.\n\nWhen the consumption tax rate is 10 percent: \\lfloor 25 \\times 0.1 \\rfloor = \\lfloor 2.5 \\rfloor = 2 yen.\n\nThus, the price of 25 yen satisfies the condition. There are other possible prices, such as 26 yen, but print the minimum such price, 25.\n\nSample Input 2\n\n8 10\n\nSample Output 2\n\n100\n\nIf the price of a product before tax is 100 yen, the amount of consumption tax levied on it is:\n\nWhen the consumption tax rate is 8 percent: \\lfloor 100 \\times 0.08 \\rfloor = 8 yen.\n\nWhen the consumption tax rate is 10 percent: \\lfloor 100 \\times 0.1 \\rfloor = 10 yen.\n\nSample Input 3\n\n19 99\n\nSample Output 3\n\n-1\n\nThere is no price before tax satisfying this condition, so print -1.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 307, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s240389328", "group_id": "codeNet:p02755", "input_text": "#include<iostream>\n#include<cmath>\nusing namespace std;\n\nint main()\n{\n    int n, k;\n    cin >> n >> k;\n\n    int x = ceil((100*n)/8);\n\n    if(ceil((x/10)) == k)\n        cout << x << endl;\n    else\n        cout << \"-1\" << endl;\n\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1583637209, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02755.html", "problem_id": "p02755", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02755/input.txt", "sample_output_relpath": "derived/input_output/data/p02755/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02755/C++/s240389328.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s240389328", "user_id": "u044179865"}, "prompt_components": {"gold_output": "25\n", "input_to_evaluate": "#include<iostream>\n#include<cmath>\nusing namespace std;\n\nint main()\n{\n    int n, k;\n    cin >> n >> k;\n\n    int x = ceil((100*n)/8);\n\n    if(ceil((x/10)) == k)\n        cout << x << endl;\n    else\n        cout << \"-1\" << endl;\n\n    return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nFind the price of a product before tax such that, when the consumption tax rate is 8 percent and 10 percent, the amount of consumption tax levied on it is A yen and B yen, respectively. (Yen is the currency of Japan.)\n\nHere, the price before tax must be a positive integer, and the amount of consumption tax is rounded down to the nearest integer.\n\nIf multiple prices satisfy the condition, print the lowest such price; if no price satisfies the condition, print -1.\n\nConstraints\n\n1 \\leq A \\leq B \\leq 100\n\nA and B are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nIf there is a price that satisfies the condition, print an integer representing the lowest such price; otherwise, print -1.\n\nSample Input 1\n\n2 2\n\nSample Output 1\n\n25\n\nIf the price of a product before tax is 25 yen, the amount of consumption tax levied on it is:\n\nWhen the consumption tax rate is 8 percent: \\lfloor 25 \\times 0.08 \\rfloor = \\lfloor 2 \\rfloor = 2 yen.\n\nWhen the consumption tax rate is 10 percent: \\lfloor 25 \\times 0.1 \\rfloor = \\lfloor 2.5 \\rfloor = 2 yen.\n\nThus, the price of 25 yen satisfies the condition. There are other possible prices, such as 26 yen, but print the minimum such price, 25.\n\nSample Input 2\n\n8 10\n\nSample Output 2\n\n100\n\nIf the price of a product before tax is 100 yen, the amount of consumption tax levied on it is:\n\nWhen the consumption tax rate is 8 percent: \\lfloor 100 \\times 0.08 \\rfloor = 8 yen.\n\nWhen the consumption tax rate is 10 percent: \\lfloor 100 \\times 0.1 \\rfloor = 10 yen.\n\nSample Input 3\n\n19 99\n\nSample Output 3\n\n-1\n\nThere is no price before tax satisfying this condition, so print -1.", "sample_input": "2 2\n"}, "reference_outputs": ["25\n"], "source_document_id": "p02755", "source_text": "Score : 300 points\n\nProblem Statement\n\nFind the price of a product before tax such that, when the consumption tax rate is 8 percent and 10 percent, the amount of consumption tax levied on it is A yen and B yen, respectively. (Yen is the currency of Japan.)\n\nHere, the price before tax must be a positive integer, and the amount of consumption tax is rounded down to the nearest integer.\n\nIf multiple prices satisfy the condition, print the lowest such price; if no price satisfies the condition, print -1.\n\nConstraints\n\n1 \\leq A \\leq B \\leq 100\n\nA and B are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nIf there is a price that satisfies the condition, print an integer representing the lowest such price; otherwise, print -1.\n\nSample Input 1\n\n2 2\n\nSample Output 1\n\n25\n\nIf the price of a product before tax is 25 yen, the amount of consumption tax levied on it is:\n\nWhen the consumption tax rate is 8 percent: \\lfloor 25 \\times 0.08 \\rfloor = \\lfloor 2 \\rfloor = 2 yen.\n\nWhen the consumption tax rate is 10 percent: \\lfloor 25 \\times 0.1 \\rfloor = \\lfloor 2.5 \\rfloor = 2 yen.\n\nThus, the price of 25 yen satisfies the condition. There are other possible prices, such as 26 yen, but print the minimum such price, 25.\n\nSample Input 2\n\n8 10\n\nSample Output 2\n\n100\n\nIf the price of a product before tax is 100 yen, the amount of consumption tax levied on it is:\n\nWhen the consumption tax rate is 8 percent: \\lfloor 100 \\times 0.08 \\rfloor = 8 yen.\n\nWhen the consumption tax rate is 10 percent: \\lfloor 100 \\times 0.1 \\rfloor = 10 yen.\n\nSample Input 3\n\n19 99\n\nSample Output 3\n\n-1\n\nThere is no price before tax satisfying this condition, so print -1.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 243, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s806221926", "group_id": "codeNet:p02756", "input_text": "#include <bits/stdc++.h>\n#define be(v) (v).begin(),(v).end()\n#define pb(q) push_back(q)\ntypedef long long ll;\nusing namespace std;\nconst ll mod=1000000007, INF=mod*mod*3LL;\n#define doublecout(a) cout<<fixed<<setprecision(10)<<a<<endl;\n\nint main() {\n    cin.tie(0);\n    cout.tie(0);\n    ios::sync_with_stdio(false);\n    deque<int> dq;\n    string s;\n    bool maki = 0;\n    int q,t,a;\n    char b;\n    cin >> s >> q;\n    int n = s.length();\n    for(int i=0;i<n;i++){\n    \tdq.push_back(s[i] - 'a');\n    }\n    while(q--){\n    \tcin >> t;\n    \tif(t == 1) maki ^= 1;\n    \telse {\n    \t\tcin >> a >> b;\n    \t\tif((a == 1) ^ maki){\n    \t\t\tdq.push_front((b - 'a'));\n    \t\t}else{\n    \t\t\tdq.push_back((b - 'a'));\n    \t\t}\n    \t}\n    }\n    if(maki){\n    \twhile(!dq.empty()){\n    \t\tcout << char('a' + dq.back());\n    \t\tdq.pop_back();\n    \t}\n    }else{\n    \twhile(!dq.empty()){\n    \t\tcout << char('a' + dq.front());\n    \t\tdq.pop_front();\n    \t}\n    }\n    cout << endl;\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1590801133, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02756.html", "problem_id": "p02756", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02756/input.txt", "sample_output_relpath": "derived/input_output/data/p02756/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02756/C++/s806221926.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s806221926", "user_id": "u192903163"}, "prompt_components": {"gold_output": "cpa\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define be(v) (v).begin(),(v).end()\n#define pb(q) push_back(q)\ntypedef long long ll;\nusing namespace std;\nconst ll mod=1000000007, INF=mod*mod*3LL;\n#define doublecout(a) cout<<fixed<<setprecision(10)<<a<<endl;\n\nint main() {\n    cin.tie(0);\n    cout.tie(0);\n    ios::sync_with_stdio(false);\n    deque<int> dq;\n    string s;\n    bool maki = 0;\n    int q,t,a;\n    char b;\n    cin >> s >> q;\n    int n = s.length();\n    for(int i=0;i<n;i++){\n    \tdq.push_back(s[i] - 'a');\n    }\n    while(q--){\n    \tcin >> t;\n    \tif(t == 1) maki ^= 1;\n    \telse {\n    \t\tcin >> a >> b;\n    \t\tif((a == 1) ^ maki){\n    \t\t\tdq.push_front((b - 'a'));\n    \t\t}else{\n    \t\t\tdq.push_back((b - 'a'));\n    \t\t}\n    \t}\n    }\n    if(maki){\n    \twhile(!dq.empty()){\n    \t\tcout << char('a' + dq.back());\n    \t\tdq.pop_back();\n    \t}\n    }else{\n    \twhile(!dq.empty()){\n    \t\tcout << char('a' + dq.front());\n    \t\tdq.pop_front();\n    \t}\n    }\n    cout << endl;\n    return 0;\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nTakahashi has a string S consisting of lowercase English letters.\n\nStarting with this string, he will produce a new one in the procedure given as follows.\n\nThe procedure consists of Q operations. In Operation i (1 \\leq i \\leq Q), an integer T_i is provided, which means the following:\n\nIf T_i = 1: reverse the string S.\n\nIf T_i = 2: An integer F_i and a lowercase English letter C_i are additionally provided.\n\nIf F_i = 1 : Add C_i to the beginning of the string S.\n\nIf F_i = 2 : Add C_i to the end of the string S.\n\nHelp Takahashi by finding the final string that results from the procedure.\n\nConstraints\n\n1 \\leq |S| \\leq 10^5\n\nS consists of lowercase English letters.\n\n1 \\leq Q \\leq 2 \\times 10^5\n\nT_i = 1 or 2.\n\nF_i = 1 or 2, if provided.\n\nC_i is a lowercase English letter, if provided.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\nQ\nQuery_1\n:\nQuery_Q\n\nIn the 3-rd through the (Q+2)-th lines, Query_i is one of the following:\n\n1\n\nwhich means T_i = 1, and:\n\n2 F_i C_i\n\nwhich means T_i = 2.\n\nOutput\n\nPrint the resulting string.\n\nSample Input 1\n\na\n4\n2 1 p\n1\n2 2 c\n1\n\nSample Output 1\n\ncpa\n\nThere will be Q = 4 operations. Initially, S is a.\n\nOperation 1: Add p at the beginning of S. S becomes pa.\n\nOperation 2: Reverse S. S becomes ap.\n\nOperation 3: Add c at the end of S. S becomes apc.\n\nOperation 4: Reverse S. S becomes cpa.\n\nThus, the resulting string is cpa.\n\nSample Input 2\n\na\n6\n2 2 a\n2 1 b\n1\n2 2 c\n1\n1\n\nSample Output 2\n\naabc\n\nThere will be Q = 6 operations. Initially, S is a.\n\nOperation 1: S becomes aa.\n\nOperation 2: S becomes baa.\n\nOperation 3: S becomes aab.\n\nOperation 4: S becomes aabc.\n\nOperation 5: S becomes cbaa.\n\nOperation 6: S becomes aabc.\n\nThus, the resulting string is aabc.\n\nSample Input 3\n\ny\n1\n2 1 x\n\nSample Output 3\n\nxy", "sample_input": "a\n4\n2 1 p\n1\n2 2 c\n1\n"}, "reference_outputs": ["cpa\n"], "source_document_id": "p02756", "source_text": "Score : 400 points\n\nProblem Statement\n\nTakahashi has a string S consisting of lowercase English letters.\n\nStarting with this string, he will produce a new one in the procedure given as follows.\n\nThe procedure consists of Q operations. In Operation i (1 \\leq i \\leq Q), an integer T_i is provided, which means the following:\n\nIf T_i = 1: reverse the string S.\n\nIf T_i = 2: An integer F_i and a lowercase English letter C_i are additionally provided.\n\nIf F_i = 1 : Add C_i to the beginning of the string S.\n\nIf F_i = 2 : Add C_i to the end of the string S.\n\nHelp Takahashi by finding the final string that results from the procedure.\n\nConstraints\n\n1 \\leq |S| \\leq 10^5\n\nS consists of lowercase English letters.\n\n1 \\leq Q \\leq 2 \\times 10^5\n\nT_i = 1 or 2.\n\nF_i = 1 or 2, if provided.\n\nC_i is a lowercase English letter, if provided.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\nQ\nQuery_1\n:\nQuery_Q\n\nIn the 3-rd through the (Q+2)-th lines, Query_i is one of the following:\n\n1\n\nwhich means T_i = 1, and:\n\n2 F_i C_i\n\nwhich means T_i = 2.\n\nOutput\n\nPrint the resulting string.\n\nSample Input 1\n\na\n4\n2 1 p\n1\n2 2 c\n1\n\nSample Output 1\n\ncpa\n\nThere will be Q = 4 operations. Initially, S is a.\n\nOperation 1: Add p at the beginning of S. S becomes pa.\n\nOperation 2: Reverse S. S becomes ap.\n\nOperation 3: Add c at the end of S. S becomes apc.\n\nOperation 4: Reverse S. S becomes cpa.\n\nThus, the resulting string is cpa.\n\nSample Input 2\n\na\n6\n2 2 a\n2 1 b\n1\n2 2 c\n1\n1\n\nSample Output 2\n\naabc\n\nThere will be Q = 6 operations. Initially, S is a.\n\nOperation 1: S becomes aa.\n\nOperation 2: S becomes baa.\n\nOperation 3: S becomes aab.\n\nOperation 4: S becomes aabc.\n\nOperation 5: S becomes cbaa.\n\nOperation 6: S becomes aabc.\n\nThus, the resulting string is aabc.\n\nSample Input 3\n\ny\n1\n2 1 x\n\nSample Output 3\n\nxy", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 964, "cpu_time_ms": 34, "memory_kb": 1872}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s486002171", "group_id": "codeNet:p02756", "input_text": "#include <bits/stdc++.h>\n#define range(i, l, r) for(long long int (i) = (l); (i) < (r); (i)++)\n#define reversed_range(i, l, r) for (long long int (i) = (r) - 1; (i) >= l; (i)--)\nusing namespace std;\ntemplate <typename T>\nusing vec = vector<T>;\nusing lint = long long;\nusing ulint = unsigned long long;\nusing pint = pair<int, int>;\nusing plint = pair<lint, lint>;\n\ntemplate <typename S, typename T>\nostream& operator <<(ostream& os, pair<S, T> p) {\n    os << \"(\";\n    os << p.first << \", \" << p.second;\n    return os << \")\";\n}\n\ntemplate <typename T>\nostream& operator <<(ostream& os, vec<T> v) {\n    os << \"[\";\n    if (v.size() == 0) return os << \"]\";\n    for (int i = 0; i < v.size() - 1; i++) {\n        os << v.at(i) << \", \";\n    }\n    return os << v.at(v.size() - 1) << \"]\";\n}\n\ntemplate <typename T>\nostream& operator <<(ostream& os, set<T>& s) {\n    os << \"{\";\n    if (s.begin() == s.end()) return os << \"}\";\n    auto it_first_item = s.begin();\n    os << *it_first_item;\n    for (auto it = ++it_first_item; it != s.end(); it++) {\n        os << \", \" << *it;\n    }\n    return os << \"}\";\n}\n\ntemplate <typename T>\nostream& operator <<(ostream& os, unordered_set<T>& s) {\n    os << \"{\";\n    if (s.begin() == s.end()) return os << \"}\";\n    auto it_first_item = s.begin();\n    os << *it_first_item;\n    for (auto it = ++it_first_item; it != s.end(); it++) {\n        os << \", \" << *it;\n    }\n    return os << \"}\";\n}\n\ntemplate <typename K, typename V>\nostream& operator <<(ostream& os, map<K, V> m) {\n    os << \"{\";\n    if (m.begin() == m.end()) return os << \"}\";\n    auto it_first_item = m.begin();\n    os << it_first_item->first << \": \" << it_first_item->second;\n    for (auto it = ++it_first_item; it != m.end(); it++) {\n        os << \", \" << it->first << \": \" << it->second;\n    }\n    return os << \"}\";\n}\n\ntemplate <typename K, typename V>\nostream& operator <<(ostream& os, unordered_map<K, V> m) {\n    os << \"{\";\n    if (m.begin() == m.end()) return os << \"}\";\n    auto it_first_item = m.begin();\n    os << it_first_item->first << \": \" << it_first_item->second;\n    for (auto it = ++it_first_item; it != m.end(); it++) {\n        os << \", \" << it->first << \": \" << it->second;\n    }\n    return os << \"}\";\n}\n\nlint pow(lint num, lint e, lint MOD) {\n    lint res = 1;\n    lint cur_num = num;\n    while (e) {\n        if (e & 1) {\n            res *= cur_num;\n            res %= MOD;\n        }\n        cur_num *= cur_num;\n        cur_num %= MOD;\n        e >>= 1;\n    }\n    return res;\n}\n\nint main() {\n    cin.tie(0); cout.tie(0);\n    ios::sync_with_stdio(false);\n    cout << fixed << setprecision(10);\n    string S; cin >> S;\n    deque<char> cur_S;\n    range(i, 0, S.size()) cur_S.emplace_back(S.at(i));\n    lint Q; cin >> Q;\n    range(_, 0, Q) {\n        lint q_type; cin >> q_type;\n        if (q_type == 1) {\n            char front, back;\n            front = cur_S.front(); \n            back = cur_S.back();\n            cur_S.at(0) = back;\n            cur_S.at(cur_S.size() - 1) = front;\n        }\n        else {\n            lint f; cin >> f;\n            char c; cin >> c;\n            if (f == 1) cur_S.emplace_front(c);\n            else cur_S.emplace_back(c);\n        }\n    }\n    for (const char& c : cur_S) cout << c;\n    cout << '\\n';\n}", "language": "C++", "metadata": {"date": 1585097742, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02756.html", "problem_id": "p02756", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02756/input.txt", "sample_output_relpath": "derived/input_output/data/p02756/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02756/C++/s486002171.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s486002171", "user_id": "u069838609"}, "prompt_components": {"gold_output": "cpa\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define range(i, l, r) for(long long int (i) = (l); (i) < (r); (i)++)\n#define reversed_range(i, l, r) for (long long int (i) = (r) - 1; (i) >= l; (i)--)\nusing namespace std;\ntemplate <typename T>\nusing vec = vector<T>;\nusing lint = long long;\nusing ulint = unsigned long long;\nusing pint = pair<int, int>;\nusing plint = pair<lint, lint>;\n\ntemplate <typename S, typename T>\nostream& operator <<(ostream& os, pair<S, T> p) {\n    os << \"(\";\n    os << p.first << \", \" << p.second;\n    return os << \")\";\n}\n\ntemplate <typename T>\nostream& operator <<(ostream& os, vec<T> v) {\n    os << \"[\";\n    if (v.size() == 0) return os << \"]\";\n    for (int i = 0; i < v.size() - 1; i++) {\n        os << v.at(i) << \", \";\n    }\n    return os << v.at(v.size() - 1) << \"]\";\n}\n\ntemplate <typename T>\nostream& operator <<(ostream& os, set<T>& s) {\n    os << \"{\";\n    if (s.begin() == s.end()) return os << \"}\";\n    auto it_first_item = s.begin();\n    os << *it_first_item;\n    for (auto it = ++it_first_item; it != s.end(); it++) {\n        os << \", \" << *it;\n    }\n    return os << \"}\";\n}\n\ntemplate <typename T>\nostream& operator <<(ostream& os, unordered_set<T>& s) {\n    os << \"{\";\n    if (s.begin() == s.end()) return os << \"}\";\n    auto it_first_item = s.begin();\n    os << *it_first_item;\n    for (auto it = ++it_first_item; it != s.end(); it++) {\n        os << \", \" << *it;\n    }\n    return os << \"}\";\n}\n\ntemplate <typename K, typename V>\nostream& operator <<(ostream& os, map<K, V> m) {\n    os << \"{\";\n    if (m.begin() == m.end()) return os << \"}\";\n    auto it_first_item = m.begin();\n    os << it_first_item->first << \": \" << it_first_item->second;\n    for (auto it = ++it_first_item; it != m.end(); it++) {\n        os << \", \" << it->first << \": \" << it->second;\n    }\n    return os << \"}\";\n}\n\ntemplate <typename K, typename V>\nostream& operator <<(ostream& os, unordered_map<K, V> m) {\n    os << \"{\";\n    if (m.begin() == m.end()) return os << \"}\";\n    auto it_first_item = m.begin();\n    os << it_first_item->first << \": \" << it_first_item->second;\n    for (auto it = ++it_first_item; it != m.end(); it++) {\n        os << \", \" << it->first << \": \" << it->second;\n    }\n    return os << \"}\";\n}\n\nlint pow(lint num, lint e, lint MOD) {\n    lint res = 1;\n    lint cur_num = num;\n    while (e) {\n        if (e & 1) {\n            res *= cur_num;\n            res %= MOD;\n        }\n        cur_num *= cur_num;\n        cur_num %= MOD;\n        e >>= 1;\n    }\n    return res;\n}\n\nint main() {\n    cin.tie(0); cout.tie(0);\n    ios::sync_with_stdio(false);\n    cout << fixed << setprecision(10);\n    string S; cin >> S;\n    deque<char> cur_S;\n    range(i, 0, S.size()) cur_S.emplace_back(S.at(i));\n    lint Q; cin >> Q;\n    range(_, 0, Q) {\n        lint q_type; cin >> q_type;\n        if (q_type == 1) {\n            char front, back;\n            front = cur_S.front(); \n            back = cur_S.back();\n            cur_S.at(0) = back;\n            cur_S.at(cur_S.size() - 1) = front;\n        }\n        else {\n            lint f; cin >> f;\n            char c; cin >> c;\n            if (f == 1) cur_S.emplace_front(c);\n            else cur_S.emplace_back(c);\n        }\n    }\n    for (const char& c : cur_S) cout << c;\n    cout << '\\n';\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nTakahashi has a string S consisting of lowercase English letters.\n\nStarting with this string, he will produce a new one in the procedure given as follows.\n\nThe procedure consists of Q operations. In Operation i (1 \\leq i \\leq Q), an integer T_i is provided, which means the following:\n\nIf T_i = 1: reverse the string S.\n\nIf T_i = 2: An integer F_i and a lowercase English letter C_i are additionally provided.\n\nIf F_i = 1 : Add C_i to the beginning of the string S.\n\nIf F_i = 2 : Add C_i to the end of the string S.\n\nHelp Takahashi by finding the final string that results from the procedure.\n\nConstraints\n\n1 \\leq |S| \\leq 10^5\n\nS consists of lowercase English letters.\n\n1 \\leq Q \\leq 2 \\times 10^5\n\nT_i = 1 or 2.\n\nF_i = 1 or 2, if provided.\n\nC_i is a lowercase English letter, if provided.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\nQ\nQuery_1\n:\nQuery_Q\n\nIn the 3-rd through the (Q+2)-th lines, Query_i is one of the following:\n\n1\n\nwhich means T_i = 1, and:\n\n2 F_i C_i\n\nwhich means T_i = 2.\n\nOutput\n\nPrint the resulting string.\n\nSample Input 1\n\na\n4\n2 1 p\n1\n2 2 c\n1\n\nSample Output 1\n\ncpa\n\nThere will be Q = 4 operations. Initially, S is a.\n\nOperation 1: Add p at the beginning of S. S becomes pa.\n\nOperation 2: Reverse S. S becomes ap.\n\nOperation 3: Add c at the end of S. S becomes apc.\n\nOperation 4: Reverse S. S becomes cpa.\n\nThus, the resulting string is cpa.\n\nSample Input 2\n\na\n6\n2 2 a\n2 1 b\n1\n2 2 c\n1\n1\n\nSample Output 2\n\naabc\n\nThere will be Q = 6 operations. Initially, S is a.\n\nOperation 1: S becomes aa.\n\nOperation 2: S becomes baa.\n\nOperation 3: S becomes aab.\n\nOperation 4: S becomes aabc.\n\nOperation 5: S becomes cbaa.\n\nOperation 6: S becomes aabc.\n\nThus, the resulting string is aabc.\n\nSample Input 3\n\ny\n1\n2 1 x\n\nSample Output 3\n\nxy", "sample_input": "a\n4\n2 1 p\n1\n2 2 c\n1\n"}, "reference_outputs": ["cpa\n"], "source_document_id": "p02756", "source_text": "Score : 400 points\n\nProblem Statement\n\nTakahashi has a string S consisting of lowercase English letters.\n\nStarting with this string, he will produce a new one in the procedure given as follows.\n\nThe procedure consists of Q operations. In Operation i (1 \\leq i \\leq Q), an integer T_i is provided, which means the following:\n\nIf T_i = 1: reverse the string S.\n\nIf T_i = 2: An integer F_i and a lowercase English letter C_i are additionally provided.\n\nIf F_i = 1 : Add C_i to the beginning of the string S.\n\nIf F_i = 2 : Add C_i to the end of the string S.\n\nHelp Takahashi by finding the final string that results from the procedure.\n\nConstraints\n\n1 \\leq |S| \\leq 10^5\n\nS consists of lowercase English letters.\n\n1 \\leq Q \\leq 2 \\times 10^5\n\nT_i = 1 or 2.\n\nF_i = 1 or 2, if provided.\n\nC_i is a lowercase English letter, if provided.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\nQ\nQuery_1\n:\nQuery_Q\n\nIn the 3-rd through the (Q+2)-th lines, Query_i is one of the following:\n\n1\n\nwhich means T_i = 1, and:\n\n2 F_i C_i\n\nwhich means T_i = 2.\n\nOutput\n\nPrint the resulting string.\n\nSample Input 1\n\na\n4\n2 1 p\n1\n2 2 c\n1\n\nSample Output 1\n\ncpa\n\nThere will be Q = 4 operations. Initially, S is a.\n\nOperation 1: Add p at the beginning of S. S becomes pa.\n\nOperation 2: Reverse S. S becomes ap.\n\nOperation 3: Add c at the end of S. S becomes apc.\n\nOperation 4: Reverse S. S becomes cpa.\n\nThus, the resulting string is cpa.\n\nSample Input 2\n\na\n6\n2 2 a\n2 1 b\n1\n2 2 c\n1\n1\n\nSample Output 2\n\naabc\n\nThere will be Q = 6 operations. Initially, S is a.\n\nOperation 1: S becomes aa.\n\nOperation 2: S becomes baa.\n\nOperation 3: S becomes aab.\n\nOperation 4: S becomes aabc.\n\nOperation 5: S becomes cbaa.\n\nOperation 6: S becomes aabc.\n\nThus, the resulting string is aabc.\n\nSample Input 3\n\ny\n1\n2 1 x\n\nSample Output 3\n\nxy", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 3232, "cpu_time_ms": 32, "memory_kb": 976}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s705971115", "group_id": "codeNet:p02756", "input_text": "#include <iostream>\n#include <deque>\n#include <string>\n\nvoid solve() {\n  std::string str;\n  std::deque<char> d;\n  int q;\n  bool reverse = false;\n  std::cin >> str >> q;\n  for (int i = 0; i < str.size(); i++) d.push_back(str[i]);\n  \n  for (int i = 0; i < q; i++) {\n    int t;\n    if (t == 1) reverse = (!reverse);\n    else {\n      int f;\n      char c;\n      std::cin >> f >> c;\n      if (f == 1 && !reverse || f == 2 && reverse) d.push_front(c);\n      else d.push_back(c);\n    }\n  }\n  if (reverse)\n    for (std::deque<char>::reverse_iterator i = d.rbegin(); i != d.rend(); i++)\n      std::cout << *i;\n  else\n    for (std::deque<char>::iterator i = d.begin(); i != d.end(); ++i)\n      std::cout << *i;\n}\nint main() {\n  solve();\n  return 0;\n}", "language": "C++", "metadata": {"date": 1583849478, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02756.html", "problem_id": "p02756", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02756/input.txt", "sample_output_relpath": "derived/input_output/data/p02756/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02756/C++/s705971115.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s705971115", "user_id": "u420345622"}, "prompt_components": {"gold_output": "cpa\n", "input_to_evaluate": "#include <iostream>\n#include <deque>\n#include <string>\n\nvoid solve() {\n  std::string str;\n  std::deque<char> d;\n  int q;\n  bool reverse = false;\n  std::cin >> str >> q;\n  for (int i = 0; i < str.size(); i++) d.push_back(str[i]);\n  \n  for (int i = 0; i < q; i++) {\n    int t;\n    if (t == 1) reverse = (!reverse);\n    else {\n      int f;\n      char c;\n      std::cin >> f >> c;\n      if (f == 1 && !reverse || f == 2 && reverse) d.push_front(c);\n      else d.push_back(c);\n    }\n  }\n  if (reverse)\n    for (std::deque<char>::reverse_iterator i = d.rbegin(); i != d.rend(); i++)\n      std::cout << *i;\n  else\n    for (std::deque<char>::iterator i = d.begin(); i != d.end(); ++i)\n      std::cout << *i;\n}\nint main() {\n  solve();\n  return 0;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nTakahashi has a string S consisting of lowercase English letters.\n\nStarting with this string, he will produce a new one in the procedure given as follows.\n\nThe procedure consists of Q operations. In Operation i (1 \\leq i \\leq Q), an integer T_i is provided, which means the following:\n\nIf T_i = 1: reverse the string S.\n\nIf T_i = 2: An integer F_i and a lowercase English letter C_i are additionally provided.\n\nIf F_i = 1 : Add C_i to the beginning of the string S.\n\nIf F_i = 2 : Add C_i to the end of the string S.\n\nHelp Takahashi by finding the final string that results from the procedure.\n\nConstraints\n\n1 \\leq |S| \\leq 10^5\n\nS consists of lowercase English letters.\n\n1 \\leq Q \\leq 2 \\times 10^5\n\nT_i = 1 or 2.\n\nF_i = 1 or 2, if provided.\n\nC_i is a lowercase English letter, if provided.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\nQ\nQuery_1\n:\nQuery_Q\n\nIn the 3-rd through the (Q+2)-th lines, Query_i is one of the following:\n\n1\n\nwhich means T_i = 1, and:\n\n2 F_i C_i\n\nwhich means T_i = 2.\n\nOutput\n\nPrint the resulting string.\n\nSample Input 1\n\na\n4\n2 1 p\n1\n2 2 c\n1\n\nSample Output 1\n\ncpa\n\nThere will be Q = 4 operations. Initially, S is a.\n\nOperation 1: Add p at the beginning of S. S becomes pa.\n\nOperation 2: Reverse S. S becomes ap.\n\nOperation 3: Add c at the end of S. S becomes apc.\n\nOperation 4: Reverse S. S becomes cpa.\n\nThus, the resulting string is cpa.\n\nSample Input 2\n\na\n6\n2 2 a\n2 1 b\n1\n2 2 c\n1\n1\n\nSample Output 2\n\naabc\n\nThere will be Q = 6 operations. Initially, S is a.\n\nOperation 1: S becomes aa.\n\nOperation 2: S becomes baa.\n\nOperation 3: S becomes aab.\n\nOperation 4: S becomes aabc.\n\nOperation 5: S becomes cbaa.\n\nOperation 6: S becomes aabc.\n\nThus, the resulting string is aabc.\n\nSample Input 3\n\ny\n1\n2 1 x\n\nSample Output 3\n\nxy", "sample_input": "a\n4\n2 1 p\n1\n2 2 c\n1\n"}, "reference_outputs": ["cpa\n"], "source_document_id": "p02756", "source_text": "Score : 400 points\n\nProblem Statement\n\nTakahashi has a string S consisting of lowercase English letters.\n\nStarting with this string, he will produce a new one in the procedure given as follows.\n\nThe procedure consists of Q operations. In Operation i (1 \\leq i \\leq Q), an integer T_i is provided, which means the following:\n\nIf T_i = 1: reverse the string S.\n\nIf T_i = 2: An integer F_i and a lowercase English letter C_i are additionally provided.\n\nIf F_i = 1 : Add C_i to the beginning of the string S.\n\nIf F_i = 2 : Add C_i to the end of the string S.\n\nHelp Takahashi by finding the final string that results from the procedure.\n\nConstraints\n\n1 \\leq |S| \\leq 10^5\n\nS consists of lowercase English letters.\n\n1 \\leq Q \\leq 2 \\times 10^5\n\nT_i = 1 or 2.\n\nF_i = 1 or 2, if provided.\n\nC_i is a lowercase English letter, if provided.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\nQ\nQuery_1\n:\nQuery_Q\n\nIn the 3-rd through the (Q+2)-th lines, Query_i is one of the following:\n\n1\n\nwhich means T_i = 1, and:\n\n2 F_i C_i\n\nwhich means T_i = 2.\n\nOutput\n\nPrint the resulting string.\n\nSample Input 1\n\na\n4\n2 1 p\n1\n2 2 c\n1\n\nSample Output 1\n\ncpa\n\nThere will be Q = 4 operations. Initially, S is a.\n\nOperation 1: Add p at the beginning of S. S becomes pa.\n\nOperation 2: Reverse S. S becomes ap.\n\nOperation 3: Add c at the end of S. S becomes apc.\n\nOperation 4: Reverse S. S becomes cpa.\n\nThus, the resulting string is cpa.\n\nSample Input 2\n\na\n6\n2 2 a\n2 1 b\n1\n2 2 c\n1\n1\n\nSample Output 2\n\naabc\n\nThere will be Q = 6 operations. Initially, S is a.\n\nOperation 1: S becomes aa.\n\nOperation 2: S becomes baa.\n\nOperation 3: S becomes aab.\n\nOperation 4: S becomes aabc.\n\nOperation 5: S becomes cbaa.\n\nOperation 6: S becomes aabc.\n\nThus, the resulting string is aabc.\n\nSample Input 3\n\ny\n1\n2 1 x\n\nSample Output 3\n\nxy", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 739, "cpu_time_ms": 17, "memory_kb": 896}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s507966726", "group_id": "codeNet:p02756", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n\ntypedef long long ll;\ntypedef long double ld;\ntypedef vector<int> vi;\ntypedef vector<double> vd;\ntypedef vector<ll> vl;\ntypedef vector<vi> vvi;\ntypedef vector<vl> vvl;\ntypedef pair<int,int> pii;\ntypedef pair<double, double> pdd;\ntypedef pair<ll, ll> pll;\ntypedef vector<pii> vii;\ntypedef vector<pll> vll;\ntypedef vector<pdd> vdd;\n\n#define rep(i, n) for(int i = 0; i < (int)(n); i++)\n#define mem(a,b) memset(a, b, sizeof(a) )\n#define all(x) (x).begin(),(x).end()\n#define INF 1000000000000\n#define MOD 1000000007\n#define PB push_back\n#define MP make_pair\n#define F first\n#define S second\n\ninline void normal(ll &a) { a %= MOD; (a < 0) && (a += MOD); }\ninline ll modMul(ll a, ll b) { a %= MOD, b %= MOD; normal(a), normal(b); return (a*b)%MOD; }\ninline ll modAdd(ll a, ll b) { a %= MOD, b %= MOD; normal(a), normal(b); return (a+b)%MOD; }\ninline ll modSub(ll a, ll b) { a %= MOD, b %= MOD; normal(a), normal(b); a -= b; normal(a); return a; }\ninline ll modPow(ll b, ll p) { ll r = 1; while(p) { if(p&1) r = modMul(r, b); b = modMul(b, b); p >>= 1; } return r; }\ninline ll modInverse(ll a) { return modPow(a, MOD-2); }\ninline ll modDiv(ll a, ll b) { return modMul(a, modInverse(b)); }\n\nll gcd(ll a,ll b){return b?gcd(b,a%b):a;}\nll lcm(ll a,ll b){return a*b/gcd(a,b);}\n\nint ctoi(char c) {\n\tif (c >= '0' && c <= '9') {\n\t\treturn c - '0';\n\t}\n\treturn 0;\n}\n\nint main(){\n    string s;int q;cin>>s>>q;\n    int t[q],f[q];\n    char c[q];\n    deque<char> d;\n    rep(i,s.size()){\n        d.push_back(s[i]);\n    }\n    rep(i,q){\n        cin>>t[i];\n        if(t[i]==2){\n            cin>>f[i]>>c[i];\n        }\n    }\n    bool a=true;\n    rep(i,q){\n        if(t[i]==1){\n            if(a)a=false;\n            else a=true;\n        }\n        else{\n            if(f[i]==1){\n                if(a){\n                    d.push_front(c[i]);\n                }\n                else{\n                    d.push_back(c[i]);\n                }\n            }\n            if(f[i]==2){\n                if(!a){\n                    d.push_front(c[i]);\n                }\n                else{\n                    d.push_back(c[i]);\n                }\n            }\n        }\n    }\n    if(!a) reverse(all(d));\n    rep(i,d.size())cout<<d[i];\n}\n", "language": "C++", "metadata": {"date": 1583644113, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02756.html", "problem_id": "p02756", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02756/input.txt", "sample_output_relpath": "derived/input_output/data/p02756/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02756/C++/s507966726.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s507966726", "user_id": "u789323170"}, "prompt_components": {"gold_output": "cpa\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n\ntypedef long long ll;\ntypedef long double ld;\ntypedef vector<int> vi;\ntypedef vector<double> vd;\ntypedef vector<ll> vl;\ntypedef vector<vi> vvi;\ntypedef vector<vl> vvl;\ntypedef pair<int,int> pii;\ntypedef pair<double, double> pdd;\ntypedef pair<ll, ll> pll;\ntypedef vector<pii> vii;\ntypedef vector<pll> vll;\ntypedef vector<pdd> vdd;\n\n#define rep(i, n) for(int i = 0; i < (int)(n); i++)\n#define mem(a,b) memset(a, b, sizeof(a) )\n#define all(x) (x).begin(),(x).end()\n#define INF 1000000000000\n#define MOD 1000000007\n#define PB push_back\n#define MP make_pair\n#define F first\n#define S second\n\ninline void normal(ll &a) { a %= MOD; (a < 0) && (a += MOD); }\ninline ll modMul(ll a, ll b) { a %= MOD, b %= MOD; normal(a), normal(b); return (a*b)%MOD; }\ninline ll modAdd(ll a, ll b) { a %= MOD, b %= MOD; normal(a), normal(b); return (a+b)%MOD; }\ninline ll modSub(ll a, ll b) { a %= MOD, b %= MOD; normal(a), normal(b); a -= b; normal(a); return a; }\ninline ll modPow(ll b, ll p) { ll r = 1; while(p) { if(p&1) r = modMul(r, b); b = modMul(b, b); p >>= 1; } return r; }\ninline ll modInverse(ll a) { return modPow(a, MOD-2); }\ninline ll modDiv(ll a, ll b) { return modMul(a, modInverse(b)); }\n\nll gcd(ll a,ll b){return b?gcd(b,a%b):a;}\nll lcm(ll a,ll b){return a*b/gcd(a,b);}\n\nint ctoi(char c) {\n\tif (c >= '0' && c <= '9') {\n\t\treturn c - '0';\n\t}\n\treturn 0;\n}\n\nint main(){\n    string s;int q;cin>>s>>q;\n    int t[q],f[q];\n    char c[q];\n    deque<char> d;\n    rep(i,s.size()){\n        d.push_back(s[i]);\n    }\n    rep(i,q){\n        cin>>t[i];\n        if(t[i]==2){\n            cin>>f[i]>>c[i];\n        }\n    }\n    bool a=true;\n    rep(i,q){\n        if(t[i]==1){\n            if(a)a=false;\n            else a=true;\n        }\n        else{\n            if(f[i]==1){\n                if(a){\n                    d.push_front(c[i]);\n                }\n                else{\n                    d.push_back(c[i]);\n                }\n            }\n            if(f[i]==2){\n                if(!a){\n                    d.push_front(c[i]);\n                }\n                else{\n                    d.push_back(c[i]);\n                }\n            }\n        }\n    }\n    if(!a) reverse(all(d));\n    rep(i,d.size())cout<<d[i];\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nTakahashi has a string S consisting of lowercase English letters.\n\nStarting with this string, he will produce a new one in the procedure given as follows.\n\nThe procedure consists of Q operations. In Operation i (1 \\leq i \\leq Q), an integer T_i is provided, which means the following:\n\nIf T_i = 1: reverse the string S.\n\nIf T_i = 2: An integer F_i and a lowercase English letter C_i are additionally provided.\n\nIf F_i = 1 : Add C_i to the beginning of the string S.\n\nIf F_i = 2 : Add C_i to the end of the string S.\n\nHelp Takahashi by finding the final string that results from the procedure.\n\nConstraints\n\n1 \\leq |S| \\leq 10^5\n\nS consists of lowercase English letters.\n\n1 \\leq Q \\leq 2 \\times 10^5\n\nT_i = 1 or 2.\n\nF_i = 1 or 2, if provided.\n\nC_i is a lowercase English letter, if provided.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\nQ\nQuery_1\n:\nQuery_Q\n\nIn the 3-rd through the (Q+2)-th lines, Query_i is one of the following:\n\n1\n\nwhich means T_i = 1, and:\n\n2 F_i C_i\n\nwhich means T_i = 2.\n\nOutput\n\nPrint the resulting string.\n\nSample Input 1\n\na\n4\n2 1 p\n1\n2 2 c\n1\n\nSample Output 1\n\ncpa\n\nThere will be Q = 4 operations. Initially, S is a.\n\nOperation 1: Add p at the beginning of S. S becomes pa.\n\nOperation 2: Reverse S. S becomes ap.\n\nOperation 3: Add c at the end of S. S becomes apc.\n\nOperation 4: Reverse S. S becomes cpa.\n\nThus, the resulting string is cpa.\n\nSample Input 2\n\na\n6\n2 2 a\n2 1 b\n1\n2 2 c\n1\n1\n\nSample Output 2\n\naabc\n\nThere will be Q = 6 operations. Initially, S is a.\n\nOperation 1: S becomes aa.\n\nOperation 2: S becomes baa.\n\nOperation 3: S becomes aab.\n\nOperation 4: S becomes aabc.\n\nOperation 5: S becomes cbaa.\n\nOperation 6: S becomes aabc.\n\nThus, the resulting string is aabc.\n\nSample Input 3\n\ny\n1\n2 1 x\n\nSample Output 3\n\nxy", "sample_input": "a\n4\n2 1 p\n1\n2 2 c\n1\n"}, "reference_outputs": ["cpa\n"], "source_document_id": "p02756", "source_text": "Score : 400 points\n\nProblem Statement\n\nTakahashi has a string S consisting of lowercase English letters.\n\nStarting with this string, he will produce a new one in the procedure given as follows.\n\nThe procedure consists of Q operations. In Operation i (1 \\leq i \\leq Q), an integer T_i is provided, which means the following:\n\nIf T_i = 1: reverse the string S.\n\nIf T_i = 2: An integer F_i and a lowercase English letter C_i are additionally provided.\n\nIf F_i = 1 : Add C_i to the beginning of the string S.\n\nIf F_i = 2 : Add C_i to the end of the string S.\n\nHelp Takahashi by finding the final string that results from the procedure.\n\nConstraints\n\n1 \\leq |S| \\leq 10^5\n\nS consists of lowercase English letters.\n\n1 \\leq Q \\leq 2 \\times 10^5\n\nT_i = 1 or 2.\n\nF_i = 1 or 2, if provided.\n\nC_i is a lowercase English letter, if provided.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\nQ\nQuery_1\n:\nQuery_Q\n\nIn the 3-rd through the (Q+2)-th lines, Query_i is one of the following:\n\n1\n\nwhich means T_i = 1, and:\n\n2 F_i C_i\n\nwhich means T_i = 2.\n\nOutput\n\nPrint the resulting string.\n\nSample Input 1\n\na\n4\n2 1 p\n1\n2 2 c\n1\n\nSample Output 1\n\ncpa\n\nThere will be Q = 4 operations. Initially, S is a.\n\nOperation 1: Add p at the beginning of S. S becomes pa.\n\nOperation 2: Reverse S. S becomes ap.\n\nOperation 3: Add c at the end of S. S becomes apc.\n\nOperation 4: Reverse S. S becomes cpa.\n\nThus, the resulting string is cpa.\n\nSample Input 2\n\na\n6\n2 2 a\n2 1 b\n1\n2 2 c\n1\n1\n\nSample Output 2\n\naabc\n\nThere will be Q = 6 operations. Initially, S is a.\n\nOperation 1: S becomes aa.\n\nOperation 2: S becomes baa.\n\nOperation 3: S becomes aab.\n\nOperation 4: S becomes aabc.\n\nOperation 5: S becomes cbaa.\n\nOperation 6: S becomes aabc.\n\nThus, the resulting string is aabc.\n\nSample Input 3\n\ny\n1\n2 1 x\n\nSample Output 3\n\nxy", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2245, "cpu_time_ms": 91, "memory_kb": 2688}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s624116932", "group_id": "codeNet:p02756", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nstring c,st;\nchar zsd;\nint len;\nint q,l,f;\nint main() {\n\tcin>>c>>q;len=c.size();\n\twhile(q--)\n\t{\n\t\tcin>>l;\n\t\tif(l==1) \n\t\t{\n\t\t\tfor(int i=0;i<len;i++)\n\t\t\tst[i]=c[len-i-1];\n\t\t\tfor(int i=0;i<len;i++)\n\t\t\tc[i]=st[i];\n\t\t}\n\t\tif(l==2)\n\t\t{\n\t\t\tscanf(\"%d %c\",&f,&zsd);\n\t\t\tif(f==1) c=zsd+c,len++;\n\t\t\tif(f==2) c=c+zsd,len++;\n\t\t}\n\t}\n\tcout<<c;\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1583635424, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02756.html", "problem_id": "p02756", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02756/input.txt", "sample_output_relpath": "derived/input_output/data/p02756/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02756/C++/s624116932.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s624116932", "user_id": "u231578174"}, "prompt_components": {"gold_output": "cpa\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nstring c,st;\nchar zsd;\nint len;\nint q,l,f;\nint main() {\n\tcin>>c>>q;len=c.size();\n\twhile(q--)\n\t{\n\t\tcin>>l;\n\t\tif(l==1) \n\t\t{\n\t\t\tfor(int i=0;i<len;i++)\n\t\t\tst[i]=c[len-i-1];\n\t\t\tfor(int i=0;i<len;i++)\n\t\t\tc[i]=st[i];\n\t\t}\n\t\tif(l==2)\n\t\t{\n\t\t\tscanf(\"%d %c\",&f,&zsd);\n\t\t\tif(f==1) c=zsd+c,len++;\n\t\t\tif(f==2) c=c+zsd,len++;\n\t\t}\n\t}\n\tcout<<c;\n\treturn 0;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nTakahashi has a string S consisting of lowercase English letters.\n\nStarting with this string, he will produce a new one in the procedure given as follows.\n\nThe procedure consists of Q operations. In Operation i (1 \\leq i \\leq Q), an integer T_i is provided, which means the following:\n\nIf T_i = 1: reverse the string S.\n\nIf T_i = 2: An integer F_i and a lowercase English letter C_i are additionally provided.\n\nIf F_i = 1 : Add C_i to the beginning of the string S.\n\nIf F_i = 2 : Add C_i to the end of the string S.\n\nHelp Takahashi by finding the final string that results from the procedure.\n\nConstraints\n\n1 \\leq |S| \\leq 10^5\n\nS consists of lowercase English letters.\n\n1 \\leq Q \\leq 2 \\times 10^5\n\nT_i = 1 or 2.\n\nF_i = 1 or 2, if provided.\n\nC_i is a lowercase English letter, if provided.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\nQ\nQuery_1\n:\nQuery_Q\n\nIn the 3-rd through the (Q+2)-th lines, Query_i is one of the following:\n\n1\n\nwhich means T_i = 1, and:\n\n2 F_i C_i\n\nwhich means T_i = 2.\n\nOutput\n\nPrint the resulting string.\n\nSample Input 1\n\na\n4\n2 1 p\n1\n2 2 c\n1\n\nSample Output 1\n\ncpa\n\nThere will be Q = 4 operations. Initially, S is a.\n\nOperation 1: Add p at the beginning of S. S becomes pa.\n\nOperation 2: Reverse S. S becomes ap.\n\nOperation 3: Add c at the end of S. S becomes apc.\n\nOperation 4: Reverse S. S becomes cpa.\n\nThus, the resulting string is cpa.\n\nSample Input 2\n\na\n6\n2 2 a\n2 1 b\n1\n2 2 c\n1\n1\n\nSample Output 2\n\naabc\n\nThere will be Q = 6 operations. Initially, S is a.\n\nOperation 1: S becomes aa.\n\nOperation 2: S becomes baa.\n\nOperation 3: S becomes aab.\n\nOperation 4: S becomes aabc.\n\nOperation 5: S becomes cbaa.\n\nOperation 6: S becomes aabc.\n\nThus, the resulting string is aabc.\n\nSample Input 3\n\ny\n1\n2 1 x\n\nSample Output 3\n\nxy", "sample_input": "a\n4\n2 1 p\n1\n2 2 c\n1\n"}, "reference_outputs": ["cpa\n"], "source_document_id": "p02756", "source_text": "Score : 400 points\n\nProblem Statement\n\nTakahashi has a string S consisting of lowercase English letters.\n\nStarting with this string, he will produce a new one in the procedure given as follows.\n\nThe procedure consists of Q operations. In Operation i (1 \\leq i \\leq Q), an integer T_i is provided, which means the following:\n\nIf T_i = 1: reverse the string S.\n\nIf T_i = 2: An integer F_i and a lowercase English letter C_i are additionally provided.\n\nIf F_i = 1 : Add C_i to the beginning of the string S.\n\nIf F_i = 2 : Add C_i to the end of the string S.\n\nHelp Takahashi by finding the final string that results from the procedure.\n\nConstraints\n\n1 \\leq |S| \\leq 10^5\n\nS consists of lowercase English letters.\n\n1 \\leq Q \\leq 2 \\times 10^5\n\nT_i = 1 or 2.\n\nF_i = 1 or 2, if provided.\n\nC_i is a lowercase English letter, if provided.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\nQ\nQuery_1\n:\nQuery_Q\n\nIn the 3-rd through the (Q+2)-th lines, Query_i is one of the following:\n\n1\n\nwhich means T_i = 1, and:\n\n2 F_i C_i\n\nwhich means T_i = 2.\n\nOutput\n\nPrint the resulting string.\n\nSample Input 1\n\na\n4\n2 1 p\n1\n2 2 c\n1\n\nSample Output 1\n\ncpa\n\nThere will be Q = 4 operations. Initially, S is a.\n\nOperation 1: Add p at the beginning of S. S becomes pa.\n\nOperation 2: Reverse S. S becomes ap.\n\nOperation 3: Add c at the end of S. S becomes apc.\n\nOperation 4: Reverse S. S becomes cpa.\n\nThus, the resulting string is cpa.\n\nSample Input 2\n\na\n6\n2 2 a\n2 1 b\n1\n2 2 c\n1\n1\n\nSample Output 2\n\naabc\n\nThere will be Q = 6 operations. Initially, S is a.\n\nOperation 1: S becomes aa.\n\nOperation 2: S becomes baa.\n\nOperation 3: S becomes aab.\n\nOperation 4: S becomes aabc.\n\nOperation 5: S becomes cbaa.\n\nOperation 6: S becomes aabc.\n\nThus, the resulting string is aabc.\n\nSample Input 3\n\ny\n1\n2 1 x\n\nSample Output 3\n\nxy", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 384, "cpu_time_ms": 2103, "memory_kb": 1496}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s485490885", "group_id": "codeNet:p02756", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define INF -99999999\ntypedef pair<int, int> P;\nint main(void)\n{\n  string S;\n  cin >> S;\n  ll Q;\n  cin >> Q;\n\n  bool swap = false;\n\n  for (ll i = 0; i < Q; i++)\n  {\n    ll T;\n    cin >> T;\n\n    if (T == 1)\n    {\n      swap = !swap;\n      continue;\n    }\n    else\n    {\n      ll F;\n      cin >> F;\n      string C;\n      cin >> C;\n      if (!swap)\n      {\n        if (F == 1)\n        {\n          S = C+S;\n        }\n        else\n        {\n          S += C;\n        }\n      }\n      else{\n        if(F==1){\n          S+=C;\n        }\n        else{\n          S = C+S;\n        }\n      }\n    }\n  }\n\n  if (swap)\n  {\n    reverse(S.begin(), S.end());\n  }\n  \n  cout<<S<<endl;\n\n  return 0;\n}", "language": "C++", "metadata": {"date": 1583634095, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02756.html", "problem_id": "p02756", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02756/input.txt", "sample_output_relpath": "derived/input_output/data/p02756/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02756/C++/s485490885.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s485490885", "user_id": "u991462056"}, "prompt_components": {"gold_output": "cpa\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define INF -99999999\ntypedef pair<int, int> P;\nint main(void)\n{\n  string S;\n  cin >> S;\n  ll Q;\n  cin >> Q;\n\n  bool swap = false;\n\n  for (ll i = 0; i < Q; i++)\n  {\n    ll T;\n    cin >> T;\n\n    if (T == 1)\n    {\n      swap = !swap;\n      continue;\n    }\n    else\n    {\n      ll F;\n      cin >> F;\n      string C;\n      cin >> C;\n      if (!swap)\n      {\n        if (F == 1)\n        {\n          S = C+S;\n        }\n        else\n        {\n          S += C;\n        }\n      }\n      else{\n        if(F==1){\n          S+=C;\n        }\n        else{\n          S = C+S;\n        }\n      }\n    }\n  }\n\n  if (swap)\n  {\n    reverse(S.begin(), S.end());\n  }\n  \n  cout<<S<<endl;\n\n  return 0;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nTakahashi has a string S consisting of lowercase English letters.\n\nStarting with this string, he will produce a new one in the procedure given as follows.\n\nThe procedure consists of Q operations. In Operation i (1 \\leq i \\leq Q), an integer T_i is provided, which means the following:\n\nIf T_i = 1: reverse the string S.\n\nIf T_i = 2: An integer F_i and a lowercase English letter C_i are additionally provided.\n\nIf F_i = 1 : Add C_i to the beginning of the string S.\n\nIf F_i = 2 : Add C_i to the end of the string S.\n\nHelp Takahashi by finding the final string that results from the procedure.\n\nConstraints\n\n1 \\leq |S| \\leq 10^5\n\nS consists of lowercase English letters.\n\n1 \\leq Q \\leq 2 \\times 10^5\n\nT_i = 1 or 2.\n\nF_i = 1 or 2, if provided.\n\nC_i is a lowercase English letter, if provided.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\nQ\nQuery_1\n:\nQuery_Q\n\nIn the 3-rd through the (Q+2)-th lines, Query_i is one of the following:\n\n1\n\nwhich means T_i = 1, and:\n\n2 F_i C_i\n\nwhich means T_i = 2.\n\nOutput\n\nPrint the resulting string.\n\nSample Input 1\n\na\n4\n2 1 p\n1\n2 2 c\n1\n\nSample Output 1\n\ncpa\n\nThere will be Q = 4 operations. Initially, S is a.\n\nOperation 1: Add p at the beginning of S. S becomes pa.\n\nOperation 2: Reverse S. S becomes ap.\n\nOperation 3: Add c at the end of S. S becomes apc.\n\nOperation 4: Reverse S. S becomes cpa.\n\nThus, the resulting string is cpa.\n\nSample Input 2\n\na\n6\n2 2 a\n2 1 b\n1\n2 2 c\n1\n1\n\nSample Output 2\n\naabc\n\nThere will be Q = 6 operations. Initially, S is a.\n\nOperation 1: S becomes aa.\n\nOperation 2: S becomes baa.\n\nOperation 3: S becomes aab.\n\nOperation 4: S becomes aabc.\n\nOperation 5: S becomes cbaa.\n\nOperation 6: S becomes aabc.\n\nThus, the resulting string is aabc.\n\nSample Input 3\n\ny\n1\n2 1 x\n\nSample Output 3\n\nxy", "sample_input": "a\n4\n2 1 p\n1\n2 2 c\n1\n"}, "reference_outputs": ["cpa\n"], "source_document_id": "p02756", "source_text": "Score : 400 points\n\nProblem Statement\n\nTakahashi has a string S consisting of lowercase English letters.\n\nStarting with this string, he will produce a new one in the procedure given as follows.\n\nThe procedure consists of Q operations. In Operation i (1 \\leq i \\leq Q), an integer T_i is provided, which means the following:\n\nIf T_i = 1: reverse the string S.\n\nIf T_i = 2: An integer F_i and a lowercase English letter C_i are additionally provided.\n\nIf F_i = 1 : Add C_i to the beginning of the string S.\n\nIf F_i = 2 : Add C_i to the end of the string S.\n\nHelp Takahashi by finding the final string that results from the procedure.\n\nConstraints\n\n1 \\leq |S| \\leq 10^5\n\nS consists of lowercase English letters.\n\n1 \\leq Q \\leq 2 \\times 10^5\n\nT_i = 1 or 2.\n\nF_i = 1 or 2, if provided.\n\nC_i is a lowercase English letter, if provided.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\nQ\nQuery_1\n:\nQuery_Q\n\nIn the 3-rd through the (Q+2)-th lines, Query_i is one of the following:\n\n1\n\nwhich means T_i = 1, and:\n\n2 F_i C_i\n\nwhich means T_i = 2.\n\nOutput\n\nPrint the resulting string.\n\nSample Input 1\n\na\n4\n2 1 p\n1\n2 2 c\n1\n\nSample Output 1\n\ncpa\n\nThere will be Q = 4 operations. Initially, S is a.\n\nOperation 1: Add p at the beginning of S. S becomes pa.\n\nOperation 2: Reverse S. S becomes ap.\n\nOperation 3: Add c at the end of S. S becomes apc.\n\nOperation 4: Reverse S. S becomes cpa.\n\nThus, the resulting string is cpa.\n\nSample Input 2\n\na\n6\n2 2 a\n2 1 b\n1\n2 2 c\n1\n1\n\nSample Output 2\n\naabc\n\nThere will be Q = 6 operations. Initially, S is a.\n\nOperation 1: S becomes aa.\n\nOperation 2: S becomes baa.\n\nOperation 3: S becomes aab.\n\nOperation 4: S becomes aabc.\n\nOperation 5: S becomes cbaa.\n\nOperation 6: S becomes aabc.\n\nThus, the resulting string is aabc.\n\nSample Input 3\n\ny\n1\n2 1 x\n\nSample Output 3\n\nxy", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 744, "cpu_time_ms": 2103, "memory_kb": 1608}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s869739262", "group_id": "codeNet:p02760", "input_text": "#include <bits/stdc++.h>\n#define debug(x) cerr << #x << \": \" << x << endl;\n\nusing namespace std;\nusing ll = long long;\nusing ii = pair<int, int>;\nusing vi = vector<int>;\n\nconst int MAX { 1000010 };\nconst ll MOD { 1000000007 };\nconst double PI = acos(-1.0);\n\nint main(){\n\tios::sync_with_stdio(false);\n    map<int, ii> c;\n    for(int i=0; i<3; ++i)\n        for(int j=0; j<3; ++j){\n            int aux;\n            cin >> aux;\n            c[aux] = make_pair(i, j);\n        }\n\n    int N;\n    int I[3] = {}, J[3] = {};\n    cin >> N;\n    while(N--){\n        int aux;\n        cin >> aux;\n        if (c.find(aux) != c.end()){\n            debug(aux);\n            ii v = c[aux];\n            debug(v.first);\n            debug(v.second);\n            I[v.first]++;\n            J[v.second]++;\n        }\n    }\n\n    int aux_dig = 0;\n    for(int i=0; i<3; ++i){\n        debug(I[i]);\n        debug(J[i]);\n        if(I[i] && J[i]) aux_dig++;\n\n        if(I[i] == 3 || J[i] == 3){\n            cout << \"Yes\\n\";\n            return 0;\n        }\n    }\n\n    aux_dig == 3? cout << \"Yes\\n\" : cout << \"No\\n\";\n\n    return 0;\n}", "language": "C++", "metadata": {"date": 1598689162, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02760.html", "problem_id": "p02760", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02760/input.txt", "sample_output_relpath": "derived/input_output/data/p02760/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02760/C++/s869739262.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s869739262", "user_id": "u863370423"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define debug(x) cerr << #x << \": \" << x << endl;\n\nusing namespace std;\nusing ll = long long;\nusing ii = pair<int, int>;\nusing vi = vector<int>;\n\nconst int MAX { 1000010 };\nconst ll MOD { 1000000007 };\nconst double PI = acos(-1.0);\n\nint main(){\n\tios::sync_with_stdio(false);\n    map<int, ii> c;\n    for(int i=0; i<3; ++i)\n        for(int j=0; j<3; ++j){\n            int aux;\n            cin >> aux;\n            c[aux] = make_pair(i, j);\n        }\n\n    int N;\n    int I[3] = {}, J[3] = {};\n    cin >> N;\n    while(N--){\n        int aux;\n        cin >> aux;\n        if (c.find(aux) != c.end()){\n            debug(aux);\n            ii v = c[aux];\n            debug(v.first);\n            debug(v.second);\n            I[v.first]++;\n            J[v.second]++;\n        }\n    }\n\n    int aux_dig = 0;\n    for(int i=0; i<3; ++i){\n        debug(I[i]);\n        debug(J[i]);\n        if(I[i] && J[i]) aux_dig++;\n\n        if(I[i] == 3 || J[i] == 3){\n            cout << \"Yes\\n\";\n            return 0;\n        }\n    }\n\n    aux_dig == 3? cout << \"Yes\\n\" : cout << \"No\\n\";\n\n    return 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nWe have a bingo card with a 3\\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.\n\nThe MC will choose N numbers, b_1, b_2, \\cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.\n\nDetermine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq A_{i, j} \\leq 100\n\nA_{i_1, j_1} \\neq A_{i_2, j_2} ((i_1, j_1) \\neq (i_2, j_2))\n\n1 \\leq N \\leq 10\n\n1 \\leq b_i \\leq 100\n\nb_i \\neq b_j (i \\neq j)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA_{1, 1} A_{1, 2} A_{1, 3}\nA_{2, 1} A_{2, 2} A_{2, 3}\nA_{3, 1} A_{3, 2} A_{3, 3}\nN\nb_1\n\\vdots\nb_N\n\nOutput\n\nIf we will have a bingo, print Yes; otherwise, print No.\n\nSample Input 1\n\n84 97 66\n79 89 11\n61 59 7\n7\n89\n7\n87\n79\n24\n84\n30\n\nSample Output 1\n\nYes\n\nWe will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.\n\nSample Input 2\n\n41 7 46\n26 89 2\n78 92 8\n5\n6\n45\n16\n57\n17\n\nSample Output 2\n\nNo\n\nWe will mark nothing.\n\nSample Input 3\n\n60 88 34\n92 41 43\n65 73 48\n10\n60\n43\n88\n11\n48\n73\n65\n41\n92\n34\n\nSample Output 3\n\nYes\n\nWe will mark all the squares.", "sample_input": "84 97 66\n79 89 11\n61 59 7\n7\n89\n7\n87\n79\n24\n84\n30\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p02760", "source_text": "Score : 200 points\n\nProblem Statement\n\nWe have a bingo card with a 3\\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.\n\nThe MC will choose N numbers, b_1, b_2, \\cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.\n\nDetermine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq A_{i, j} \\leq 100\n\nA_{i_1, j_1} \\neq A_{i_2, j_2} ((i_1, j_1) \\neq (i_2, j_2))\n\n1 \\leq N \\leq 10\n\n1 \\leq b_i \\leq 100\n\nb_i \\neq b_j (i \\neq j)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA_{1, 1} A_{1, 2} A_{1, 3}\nA_{2, 1} A_{2, 2} A_{2, 3}\nA_{3, 1} A_{3, 2} A_{3, 3}\nN\nb_1\n\\vdots\nb_N\n\nOutput\n\nIf we will have a bingo, print Yes; otherwise, print No.\n\nSample Input 1\n\n84 97 66\n79 89 11\n61 59 7\n7\n89\n7\n87\n79\n24\n84\n30\n\nSample Output 1\n\nYes\n\nWe will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.\n\nSample Input 2\n\n41 7 46\n26 89 2\n78 92 8\n5\n6\n45\n16\n57\n17\n\nSample Output 2\n\nNo\n\nWe will mark nothing.\n\nSample Input 3\n\n60 88 34\n92 41 43\n65 73 48\n10\n60\n43\n88\n11\n48\n73\n65\n41\n92\n34\n\nSample Output 3\n\nYes\n\nWe will mark all the squares.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1096, "cpu_time_ms": 8, "memory_kb": 3596}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s137209205", "group_id": "codeNet:p02760", "input_text": "#include <bits/stdc++.h>\n#include <type_traits>\nusing namespace std;\n\n#define COUT(x) cout << #x << \" = \" << (x) << \" (L\" << __LINE__ << \")\" << endl\ntemplate<class T1, class T2> ostream& operator << (ostream &s, pair<T1,T2> P)\n{ return s << '<' << P.first << \", \" << P.second << '>'; }\ntemplate<class T> ostream& operator << (ostream &s, vector<T> P)\n{ for (int i = 0; i < P.size(); ++i) { if (i > 0) { s << \" \"; } s << P[i]; } return s; }\ntemplate<class T> ostream& operator << (ostream &s, vector<vector<T> > P)\n{ for (int i = 0; i < P.size(); ++i) { s << endl << P[i]; } return s << endl; }\ntemplate<class T> ostream& operator << (ostream &s, set<T> P)\n{ for(auto it : P) { s << \"<\" << it << \"> \"; } return s << endl; }\ntemplate<class T1, class T2> ostream& operator << (ostream &s, map<T1,T2> P)\n{ for(auto it : P) { s << \"<\" << it.first << \"->\" << it.second << \"> \"; } return s << endl; }\n\n#define rep(i, n) for (int i = 0; i < (n); ++i)\n#define rrep(i, n) for (int i = 1; i <= (n); ++i)\n#define drep(i, n) for (int i = (n)-1; i >= 0; --i)\n#define ddrep(i, n) for (int i = n; i > 0; --i)\n#define srep(i, s, t) for (int i = s; i < t; ++i)\n#define ssrep(i, s, t) for (int i = s; i <= t; ++i)\n\ntemplate<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }\n\nusing ll = long long;\nusing pi = pair<int, int>;\nusing vi = vector<int>;\nusing vvi = vector<vi>;\nusing vl = vector<ll>;\nusing vvl = vector<vl>;\nusing ld = long double;\nusing str = string;\n\n#define rng(a) a.begin(), a.end()\n#define rrng(a) a.rbegin(), a.rend()\n#define pb push_back\n#define eb emplace_back\n#define fi first\n#define se second\n\nlong int M = 1e+9+7;\nint inf = 1e+9;\n\nint main(void){\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n    cout << std::setprecision(10);\n\n    int ans=0;\n    vvi a(3,vi(3));\n    vvi flag(3,vi(3));\n    rep(i,3){\n        rep(j,3){\n            cin >> a[i][j];\n        }\n    }\n    int n;\n    cin >> n;\n    vi b(n);\n    rep(i,n){\n        cin >> b[i];\n        rep(j,3){\n            rep(k,3){\n                if(b[i] == a[j][k]) flag[j][k] = 1;\n            }\n        }\n    }\n\n    rep(i,3){\n        if(flag[i][0] && flag[i][1] && flag[i][2]) ans++;\n        if(flag[0][i] && flag[1][i] && flag[2][i]) ans++;\n    }\n    if(flag[0][0] && flag[1][1] && flag[2][2]) ans++;\n    if(flag[0][2] && flag[1][1] && flag[2][0]) ans++;\n\n    /*\n    rep(i,3){\n        rep(j,3){\n            cout << flag[i][j] << \" \";\n        }\n        cout << endl;\n    }\n    */\n\n    if(ans) cout << \"Yes\" << endl;\n    else cout << \"No\" << endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1590021083, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02760.html", "problem_id": "p02760", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02760/input.txt", "sample_output_relpath": "derived/input_output/data/p02760/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02760/C++/s137209205.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s137209205", "user_id": "u636706582"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#include <type_traits>\nusing namespace std;\n\n#define COUT(x) cout << #x << \" = \" << (x) << \" (L\" << __LINE__ << \")\" << endl\ntemplate<class T1, class T2> ostream& operator << (ostream &s, pair<T1,T2> P)\n{ return s << '<' << P.first << \", \" << P.second << '>'; }\ntemplate<class T> ostream& operator << (ostream &s, vector<T> P)\n{ for (int i = 0; i < P.size(); ++i) { if (i > 0) { s << \" \"; } s << P[i]; } return s; }\ntemplate<class T> ostream& operator << (ostream &s, vector<vector<T> > P)\n{ for (int i = 0; i < P.size(); ++i) { s << endl << P[i]; } return s << endl; }\ntemplate<class T> ostream& operator << (ostream &s, set<T> P)\n{ for(auto it : P) { s << \"<\" << it << \"> \"; } return s << endl; }\ntemplate<class T1, class T2> ostream& operator << (ostream &s, map<T1,T2> P)\n{ for(auto it : P) { s << \"<\" << it.first << \"->\" << it.second << \"> \"; } return s << endl; }\n\n#define rep(i, n) for (int i = 0; i < (n); ++i)\n#define rrep(i, n) for (int i = 1; i <= (n); ++i)\n#define drep(i, n) for (int i = (n)-1; i >= 0; --i)\n#define ddrep(i, n) for (int i = n; i > 0; --i)\n#define srep(i, s, t) for (int i = s; i < t; ++i)\n#define ssrep(i, s, t) for (int i = s; i <= t; ++i)\n\ntemplate<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }\n\nusing ll = long long;\nusing pi = pair<int, int>;\nusing vi = vector<int>;\nusing vvi = vector<vi>;\nusing vl = vector<ll>;\nusing vvl = vector<vl>;\nusing ld = long double;\nusing str = string;\n\n#define rng(a) a.begin(), a.end()\n#define rrng(a) a.rbegin(), a.rend()\n#define pb push_back\n#define eb emplace_back\n#define fi first\n#define se second\n\nlong int M = 1e+9+7;\nint inf = 1e+9;\n\nint main(void){\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n    cout << std::setprecision(10);\n\n    int ans=0;\n    vvi a(3,vi(3));\n    vvi flag(3,vi(3));\n    rep(i,3){\n        rep(j,3){\n            cin >> a[i][j];\n        }\n    }\n    int n;\n    cin >> n;\n    vi b(n);\n    rep(i,n){\n        cin >> b[i];\n        rep(j,3){\n            rep(k,3){\n                if(b[i] == a[j][k]) flag[j][k] = 1;\n            }\n        }\n    }\n\n    rep(i,3){\n        if(flag[i][0] && flag[i][1] && flag[i][2]) ans++;\n        if(flag[0][i] && flag[1][i] && flag[2][i]) ans++;\n    }\n    if(flag[0][0] && flag[1][1] && flag[2][2]) ans++;\n    if(flag[0][2] && flag[1][1] && flag[2][0]) ans++;\n\n    /*\n    rep(i,3){\n        rep(j,3){\n            cout << flag[i][j] << \" \";\n        }\n        cout << endl;\n    }\n    */\n\n    if(ans) cout << \"Yes\" << endl;\n    else cout << \"No\" << endl;\n    return 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nWe have a bingo card with a 3\\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.\n\nThe MC will choose N numbers, b_1, b_2, \\cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.\n\nDetermine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq A_{i, j} \\leq 100\n\nA_{i_1, j_1} \\neq A_{i_2, j_2} ((i_1, j_1) \\neq (i_2, j_2))\n\n1 \\leq N \\leq 10\n\n1 \\leq b_i \\leq 100\n\nb_i \\neq b_j (i \\neq j)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA_{1, 1} A_{1, 2} A_{1, 3}\nA_{2, 1} A_{2, 2} A_{2, 3}\nA_{3, 1} A_{3, 2} A_{3, 3}\nN\nb_1\n\\vdots\nb_N\n\nOutput\n\nIf we will have a bingo, print Yes; otherwise, print No.\n\nSample Input 1\n\n84 97 66\n79 89 11\n61 59 7\n7\n89\n7\n87\n79\n24\n84\n30\n\nSample Output 1\n\nYes\n\nWe will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.\n\nSample Input 2\n\n41 7 46\n26 89 2\n78 92 8\n5\n6\n45\n16\n57\n17\n\nSample Output 2\n\nNo\n\nWe will mark nothing.\n\nSample Input 3\n\n60 88 34\n92 41 43\n65 73 48\n10\n60\n43\n88\n11\n48\n73\n65\n41\n92\n34\n\nSample Output 3\n\nYes\n\nWe will mark all the squares.", "sample_input": "84 97 66\n79 89 11\n61 59 7\n7\n89\n7\n87\n79\n24\n84\n30\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p02760", "source_text": "Score : 200 points\n\nProblem Statement\n\nWe have a bingo card with a 3\\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.\n\nThe MC will choose N numbers, b_1, b_2, \\cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.\n\nDetermine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq A_{i, j} \\leq 100\n\nA_{i_1, j_1} \\neq A_{i_2, j_2} ((i_1, j_1) \\neq (i_2, j_2))\n\n1 \\leq N \\leq 10\n\n1 \\leq b_i \\leq 100\n\nb_i \\neq b_j (i \\neq j)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA_{1, 1} A_{1, 2} A_{1, 3}\nA_{2, 1} A_{2, 2} A_{2, 3}\nA_{3, 1} A_{3, 2} A_{3, 3}\nN\nb_1\n\\vdots\nb_N\n\nOutput\n\nIf we will have a bingo, print Yes; otherwise, print No.\n\nSample Input 1\n\n84 97 66\n79 89 11\n61 59 7\n7\n89\n7\n87\n79\n24\n84\n30\n\nSample Output 1\n\nYes\n\nWe will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.\n\nSample Input 2\n\n41 7 46\n26 89 2\n78 92 8\n5\n6\n45\n16\n57\n17\n\nSample Output 2\n\nNo\n\nWe will mark nothing.\n\nSample Input 3\n\n60 88 34\n92 41 43\n65 73 48\n10\n60\n43\n88\n11\n48\n73\n65\n41\n92\n34\n\nSample Output 3\n\nYes\n\nWe will mark all the squares.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2643, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s056228792", "group_id": "codeNet:p02760", "input_text": "#include <iostream>\n#include<vector>\n#include<algorithm>\n#include<string>\nusing namespace std;\n#define rep(N) for(int i=0;i<N;i++)\n#define rep2(N1,N2) for(int i=0;i<N1;i++)for(int j=0;j<N2;j++)\n#define rep3(N1,N2,N3)for(int i=0;i<N1;i++)for(int j=0;j<N2;j++)for(int k=0;k<N3;k++)\n#define For(i,N) for(int i=0;i<N;i++)\nvoid yn(bool b) {\n\tif (b)printf(\"yes\\n\");\n\telse printf(\"no\\n\");\n}\n\nvoid Yn(bool b) {\n\tif (b)printf(\"Yes\\n\");\n\telse printf(\"No\\n\");\n}\n\nvoid YN(bool b) {\n\tif (b)printf(\"YES\\n\");\n\telse printf(\"NO\\n\");\n}\n\nint main(){\n\tvector<vector<int>>A(3);\n\trep(3)A[i].resize(3);\n\trep2(3, 3)\n\t\tcin >> A[i][j];\n\tint N;\n\tcin >> N;\n\tvector<int>b(N);\n\trep(N)cin >> b[i];\n\tFor(i, N) {\n\t\tFor(j, 3) {\n\t\t\tFor(k, 3) {\n\t\t\t\tif (b[i] == A[j][k])\n\t\t\t\t\tA[j][k] = 0;\n\t\t\t}\n\t\t}\n\t}\n\tint flag = 0;\n\tint flag2 = 1;\n\tvector<int>vflag(8, 1);\n\trep(3) {\n\t\tif (A[0][i] != 0)\n\t\t\tvflag[0] = 0;\n\t\tif (A[1][i] != 0)\n\t\t\tvflag[1] = 0;\n\t\tif (A[2][i] != 0)\n\t\t\tvflag[2] = 0;\n\t\tif (A[i][0] != 0)\n\t\t\tvflag[3] = 0;\n\t\tif (A[i][1] != 0)\n\t\t\tvflag[4] = 0;\n\t\tif (A[i][2] != 0)\n\t\t\tvflag[5] = 0;\n\t\tif (A[i][i] != 0)\n\t\t\tvflag[6] = 0;\n\t\tif (A[2 - i][i] != 0)\n\t\t\tvflag[7] = 0;\n\t}\n\trep(8) {\n\t\tif (vflag[i] == 1)\n\t\t\tflag = 1;\n\t}\n\tYn(flag);\n\n}", "language": "C++", "metadata": {"date": 1587921247, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02760.html", "problem_id": "p02760", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02760/input.txt", "sample_output_relpath": "derived/input_output/data/p02760/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02760/C++/s056228792.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s056228792", "user_id": "u868344991"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <iostream>\n#include<vector>\n#include<algorithm>\n#include<string>\nusing namespace std;\n#define rep(N) for(int i=0;i<N;i++)\n#define rep2(N1,N2) for(int i=0;i<N1;i++)for(int j=0;j<N2;j++)\n#define rep3(N1,N2,N3)for(int i=0;i<N1;i++)for(int j=0;j<N2;j++)for(int k=0;k<N3;k++)\n#define For(i,N) for(int i=0;i<N;i++)\nvoid yn(bool b) {\n\tif (b)printf(\"yes\\n\");\n\telse printf(\"no\\n\");\n}\n\nvoid Yn(bool b) {\n\tif (b)printf(\"Yes\\n\");\n\telse printf(\"No\\n\");\n}\n\nvoid YN(bool b) {\n\tif (b)printf(\"YES\\n\");\n\telse printf(\"NO\\n\");\n}\n\nint main(){\n\tvector<vector<int>>A(3);\n\trep(3)A[i].resize(3);\n\trep2(3, 3)\n\t\tcin >> A[i][j];\n\tint N;\n\tcin >> N;\n\tvector<int>b(N);\n\trep(N)cin >> b[i];\n\tFor(i, N) {\n\t\tFor(j, 3) {\n\t\t\tFor(k, 3) {\n\t\t\t\tif (b[i] == A[j][k])\n\t\t\t\t\tA[j][k] = 0;\n\t\t\t}\n\t\t}\n\t}\n\tint flag = 0;\n\tint flag2 = 1;\n\tvector<int>vflag(8, 1);\n\trep(3) {\n\t\tif (A[0][i] != 0)\n\t\t\tvflag[0] = 0;\n\t\tif (A[1][i] != 0)\n\t\t\tvflag[1] = 0;\n\t\tif (A[2][i] != 0)\n\t\t\tvflag[2] = 0;\n\t\tif (A[i][0] != 0)\n\t\t\tvflag[3] = 0;\n\t\tif (A[i][1] != 0)\n\t\t\tvflag[4] = 0;\n\t\tif (A[i][2] != 0)\n\t\t\tvflag[5] = 0;\n\t\tif (A[i][i] != 0)\n\t\t\tvflag[6] = 0;\n\t\tif (A[2 - i][i] != 0)\n\t\t\tvflag[7] = 0;\n\t}\n\trep(8) {\n\t\tif (vflag[i] == 1)\n\t\t\tflag = 1;\n\t}\n\tYn(flag);\n\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nWe have a bingo card with a 3\\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.\n\nThe MC will choose N numbers, b_1, b_2, \\cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.\n\nDetermine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq A_{i, j} \\leq 100\n\nA_{i_1, j_1} \\neq A_{i_2, j_2} ((i_1, j_1) \\neq (i_2, j_2))\n\n1 \\leq N \\leq 10\n\n1 \\leq b_i \\leq 100\n\nb_i \\neq b_j (i \\neq j)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA_{1, 1} A_{1, 2} A_{1, 3}\nA_{2, 1} A_{2, 2} A_{2, 3}\nA_{3, 1} A_{3, 2} A_{3, 3}\nN\nb_1\n\\vdots\nb_N\n\nOutput\n\nIf we will have a bingo, print Yes; otherwise, print No.\n\nSample Input 1\n\n84 97 66\n79 89 11\n61 59 7\n7\n89\n7\n87\n79\n24\n84\n30\n\nSample Output 1\n\nYes\n\nWe will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.\n\nSample Input 2\n\n41 7 46\n26 89 2\n78 92 8\n5\n6\n45\n16\n57\n17\n\nSample Output 2\n\nNo\n\nWe will mark nothing.\n\nSample Input 3\n\n60 88 34\n92 41 43\n65 73 48\n10\n60\n43\n88\n11\n48\n73\n65\n41\n92\n34\n\nSample Output 3\n\nYes\n\nWe will mark all the squares.", "sample_input": "84 97 66\n79 89 11\n61 59 7\n7\n89\n7\n87\n79\n24\n84\n30\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p02760", "source_text": "Score : 200 points\n\nProblem Statement\n\nWe have a bingo card with a 3\\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.\n\nThe MC will choose N numbers, b_1, b_2, \\cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.\n\nDetermine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq A_{i, j} \\leq 100\n\nA_{i_1, j_1} \\neq A_{i_2, j_2} ((i_1, j_1) \\neq (i_2, j_2))\n\n1 \\leq N \\leq 10\n\n1 \\leq b_i \\leq 100\n\nb_i \\neq b_j (i \\neq j)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA_{1, 1} A_{1, 2} A_{1, 3}\nA_{2, 1} A_{2, 2} A_{2, 3}\nA_{3, 1} A_{3, 2} A_{3, 3}\nN\nb_1\n\\vdots\nb_N\n\nOutput\n\nIf we will have a bingo, print Yes; otherwise, print No.\n\nSample Input 1\n\n84 97 66\n79 89 11\n61 59 7\n7\n89\n7\n87\n79\n24\n84\n30\n\nSample Output 1\n\nYes\n\nWe will mark A_{1, 1}, A_{2, 1}, A_{2, 2}, A_{3, 3}, and complete the diagonal from the top-left to the bottom-right.\n\nSample Input 2\n\n41 7 46\n26 89 2\n78 92 8\n5\n6\n45\n16\n57\n17\n\nSample Output 2\n\nNo\n\nWe will mark nothing.\n\nSample Input 3\n\n60 88 34\n92 41 43\n65 73 48\n10\n60\n43\n88\n11\n48\n73\n65\n41\n92\n34\n\nSample Output 3\n\nYes\n\nWe will mark all the squares.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1193, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s519440209", "group_id": "codeNet:p02762", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nvector<int>vect[100001];\nvector<int>block[100001];\nset<int>r;\n\nvoid dfs(bool visited[],int src)\n{\n       r.insert(src);\n      visited[src]=true;\n\n       for(int i=0;i<vect[src].size();i++)\n       {\n           if(visited[vect[src][i]]==false)\n                dfs(visited,vect[src][i]);\n       }\n }\nint main()\n{\n    int n,m,k;\n     cin>>n>>m>>k;\n\n       for(int i=1;i<=m;i++)\n       {\n        int u,v;\n         cin>>u>>v;\n\n           vect[u].push_back(v);\n           vect[v].push_back(u);\n       }\n       for(int i=1;i<=k;i++)\n        {\n           int u,v;\n            cin>>u>>v;\n\n            block[u].push_back(v);\n            block[v].push_back(u);\n        }\n\n        bool visited[n+1]={false};\n\n        int arr[n+1];\n\n    for(int i=1;i<=n;i++)\n    {\n       if(visited[i]==false)\n       {\n          r.clear();\n         dfs(visited,i);\n\n          for(auto itr = r.begin();itr!=r.end();itr++)\n          {\n            int x = (*itr);\n\n             arr[x] = r.size()-vect[x].size()-1;\n\n               for(int j=0;j<block[x].size();j++)\n                 if(r.find(block[x][j])!=r.end()) arr[x]--;\n           }\n       }\n    }\n      for(int i=1;i<=n;i++)\n        cout<<arr[i]<<\" \";\n}\n", "language": "C++", "metadata": {"date": 1583222197, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02762.html", "problem_id": "p02762", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02762/input.txt", "sample_output_relpath": "derived/input_output/data/p02762/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02762/C++/s519440209.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s519440209", "user_id": "u549517003"}, "prompt_components": {"gold_output": "0 1 0 1\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nvector<int>vect[100001];\nvector<int>block[100001];\nset<int>r;\n\nvoid dfs(bool visited[],int src)\n{\n       r.insert(src);\n      visited[src]=true;\n\n       for(int i=0;i<vect[src].size();i++)\n       {\n           if(visited[vect[src][i]]==false)\n                dfs(visited,vect[src][i]);\n       }\n }\nint main()\n{\n    int n,m,k;\n     cin>>n>>m>>k;\n\n       for(int i=1;i<=m;i++)\n       {\n        int u,v;\n         cin>>u>>v;\n\n           vect[u].push_back(v);\n           vect[v].push_back(u);\n       }\n       for(int i=1;i<=k;i++)\n        {\n           int u,v;\n            cin>>u>>v;\n\n            block[u].push_back(v);\n            block[v].push_back(u);\n        }\n\n        bool visited[n+1]={false};\n\n        int arr[n+1];\n\n    for(int i=1;i<=n;i++)\n    {\n       if(visited[i]==false)\n       {\n          r.clear();\n         dfs(visited,i);\n\n          for(auto itr = r.begin();itr!=r.end();itr++)\n          {\n            int x = (*itr);\n\n             arr[x] = r.size()-vect[x].size()-1;\n\n               for(int j=0;j<block[x].size();j++)\n                 if(r.find(block[x][j])!=r.end()) arr[x]--;\n           }\n       }\n    }\n      for(int i=1;i<=n;i++)\n        cout<<arr[i]<<\" \";\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nAn SNS has N users - User 1, User 2, \\cdots, User N.\n\nBetween these N users, there are some relationships - M friendships and K blockships.\n\nFor each i = 1, 2, \\cdots, M, there is a bidirectional friendship between User A_i and User B_i.\n\nFor each i = 1, 2, \\cdots, K, there is a bidirectional blockship between User C_i and User D_i.\n\nWe define User a to be a friend candidate for User b when all of the following four conditions are satisfied:\n\na \\neq b.\n\nThere is not a friendship between User a and User b.\n\nThere is not a blockship between User a and User b.\n\nThere exists a sequence c_0, c_1, c_2, \\cdots, c_L consisting of integers between 1 and N (inclusive) such that c_0 = a, c_L = b, and there is a friendship between User c_i and c_{i+1} for each i = 0, 1, \\cdots, L - 1.\n\nFor each user i = 1, 2, ... N, how many friend candidates does it have?\n\nConstraints\n\nAll values in input are integers.\n\n2 ≤ N ≤ 10^5\n\n0 \\leq M \\leq 10^5\n\n0 \\leq K \\leq 10^5\n\n1 \\leq A_i, B_i \\leq N\n\nA_i \\neq B_i\n\n1 \\leq C_i, D_i \\leq N\n\nC_i \\neq D_i\n\n(A_i, B_i) \\neq (A_j, B_j) (i \\neq j)\n\n(A_i, B_i) \\neq (B_j, A_j)\n\n(C_i, D_i) \\neq (C_j, D_j) (i \\neq j)\n\n(C_i, D_i) \\neq (D_j, C_j)\n\n(A_i, B_i) \\neq (C_j, D_j)\n\n(A_i, B_i) \\neq (D_j, C_j)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M K\nA_1 B_1\n\\vdots\nA_M B_M\nC_1 D_1\n\\vdots\nC_K D_K\n\nOutput\n\nPrint the answers in order, with space in between.\n\nSample Input 1\n\n4 4 1\n2 1\n1 3\n3 2\n3 4\n4 1\n\nSample Output 1\n\n0 1 0 1\n\nThere is a friendship between User 2 and 3, and between 3 and 4. Also, there is no friendship or blockship between User 2 and 4. Thus, User 4 is a friend candidate for User 2.\n\nHowever, neither User 1 or 3 is a friend candidate for User 2, so User 2 has one friend candidate.\n\nSample Input 2\n\n5 10 0\n1 2\n1 3\n1 4\n1 5\n3 2\n2 4\n2 5\n4 3\n5 3\n4 5\n\nSample Output 2\n\n0 0 0 0 0\n\nEveryone is a friend of everyone else and has no friend candidate.\n\nSample Input 3\n\n10 9 3\n10 1\n6 7\n8 2\n2 5\n8 4\n7 3\n10 9\n6 4\n5 8\n2 6\n7 5\n3 1\n\nSample Output 3\n\n1 3 5 4 3 3 3 3 1 0", "sample_input": "4 4 1\n2 1\n1 3\n3 2\n3 4\n4 1\n"}, "reference_outputs": ["0 1 0 1\n"], "source_document_id": "p02762", "source_text": "Score : 400 points\n\nProblem Statement\n\nAn SNS has N users - User 1, User 2, \\cdots, User N.\n\nBetween these N users, there are some relationships - M friendships and K blockships.\n\nFor each i = 1, 2, \\cdots, M, there is a bidirectional friendship between User A_i and User B_i.\n\nFor each i = 1, 2, \\cdots, K, there is a bidirectional blockship between User C_i and User D_i.\n\nWe define User a to be a friend candidate for User b when all of the following four conditions are satisfied:\n\na \\neq b.\n\nThere is not a friendship between User a and User b.\n\nThere is not a blockship between User a and User b.\n\nThere exists a sequence c_0, c_1, c_2, \\cdots, c_L consisting of integers between 1 and N (inclusive) such that c_0 = a, c_L = b, and there is a friendship between User c_i and c_{i+1} for each i = 0, 1, \\cdots, L - 1.\n\nFor each user i = 1, 2, ... N, how many friend candidates does it have?\n\nConstraints\n\nAll values in input are integers.\n\n2 ≤ N ≤ 10^5\n\n0 \\leq M \\leq 10^5\n\n0 \\leq K \\leq 10^5\n\n1 \\leq A_i, B_i \\leq N\n\nA_i \\neq B_i\n\n1 \\leq C_i, D_i \\leq N\n\nC_i \\neq D_i\n\n(A_i, B_i) \\neq (A_j, B_j) (i \\neq j)\n\n(A_i, B_i) \\neq (B_j, A_j)\n\n(C_i, D_i) \\neq (C_j, D_j) (i \\neq j)\n\n(C_i, D_i) \\neq (D_j, C_j)\n\n(A_i, B_i) \\neq (C_j, D_j)\n\n(A_i, B_i) \\neq (D_j, C_j)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M K\nA_1 B_1\n\\vdots\nA_M B_M\nC_1 D_1\n\\vdots\nC_K D_K\n\nOutput\n\nPrint the answers in order, with space in between.\n\nSample Input 1\n\n4 4 1\n2 1\n1 3\n3 2\n3 4\n4 1\n\nSample Output 1\n\n0 1 0 1\n\nThere is a friendship between User 2 and 3, and between 3 and 4. Also, there is no friendship or blockship between User 2 and 4. Thus, User 4 is a friend candidate for User 2.\n\nHowever, neither User 1 or 3 is a friend candidate for User 2, so User 2 has one friend candidate.\n\nSample Input 2\n\n5 10 0\n1 2\n1 3\n1 4\n1 5\n3 2\n2 4\n2 5\n4 3\n5 3\n4 5\n\nSample Output 2\n\n0 0 0 0 0\n\nEveryone is a friend of everyone else and has no friend candidate.\n\nSample Input 3\n\n10 9 3\n10 1\n6 7\n8 2\n2 5\n8 4\n7 3\n10 9\n6 4\n5 8\n2 6\n7 5\n3 1\n\nSample Output 3\n\n1 3 5 4 3 3 3 3 1 0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1222, "cpu_time_ms": 283, "memory_kb": 17016}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s319140982", "group_id": "codeNet:p02763", "input_text": "#include<bits/stdc++.h>\n\nusing namespace std;\n\ntypedef long long int ll;\n\nconst ll mod = 1e9 + 7;\nconst ll MAXN = 5e5 + 5;\n\nvector < vector < ll > > t(4 * MAXN, vector < ll > (26, 0));\nll n;\nstring s;\n\nvoid build(ll v, ll tl, ll tr){\n  if(tl == tr){\n    t[v][s[tl] - 'a']++;\n  }else{\n    ll tm = (tr - tl) / 2 + tl;\n    build(2 * v, tl, tm);\n    build(2 * v + 1, tm + 1, tr);\n    for(int i = 0; i < 26; i++) t[v][i] = t[2 * v][i] + t[2 * v + 1][i];\n  }\n}\n\nvoid update(ll v, ll tl, ll tr, ll pos, char ch){\n  if(tl == tr){\n    t[v][s[tl] - 'a']--;\n    t[v][ch - 'a']++;\n  }else{\n    ll tm = (tr - tl) / 2 + tl;\n    if(pos <= tm) update(2 * v, tl, tm, pos, ch);\n    else update(2 * v + 1, tm + 1, tr, pos, ch);\n    for(int i = 0; i < 26; i++) t[v][i] = t[2 * v][i] + t[2 * v + 1][i];\n  }\n}\n\nvector < ll > query(ll v, ll tl, ll tr, ll l, ll r){\n  if(l > r){\n    vector < ll > tmp(26, 0);\n    return tmp;\n  }\n  if(tl == l && tr == r){\n    return t[v];\n  }else{\n    ll tm = (tr - tl) / 2 + tl;\n    vector < ll > a = query(2 * v, tl, tm, l, min(r, tm));\n    vector < ll > b = query(2 * v + 1, tm + 1, tr, max(l, tm + 1), r);\n    for(int i = 0; i < 26; i++) a[i] += b[i];\n    return a;\n  }\n}\n\nint main(){\n  ios_base::sync_with_stdio(false);\n  cin.tie(0);cout.tie(0);\n\n  cin >> n;\n  cin >> s;\n\n  build(1, 0, n - 1);\n\n  ll q;\n  cin >> q;\n  while(q--){\n    int a;\n    cin >> a;\n    if(a == 1){\n      ll pos;\n      cin >> pos;\n      char ch;\n      cin >> ch;\n      update(1, 0, n - 1, pos - 1, ch);\n      s[pos - 1] = ch;\n    }else{\n      ll l, r;\n      cin >> l >> r;\n      vector < ll > ans = query(1, 0, n - 1, l - 1, r - 1);\n      ll cnt = 0;\n      for(int i = 0; i < 26; i++){\n        if(ans[i]) cnt++;\n      }\n      cout << cnt << '\\n';\n    }\n  }\n}\n", "language": "C++", "metadata": {"date": 1587809961, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02763.html", "problem_id": "p02763", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02763/input.txt", "sample_output_relpath": "derived/input_output/data/p02763/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02763/C++/s319140982.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s319140982", "user_id": "u929156598"}, "prompt_components": {"gold_output": "3\n1\n5\n", "input_to_evaluate": "#include<bits/stdc++.h>\n\nusing namespace std;\n\ntypedef long long int ll;\n\nconst ll mod = 1e9 + 7;\nconst ll MAXN = 5e5 + 5;\n\nvector < vector < ll > > t(4 * MAXN, vector < ll > (26, 0));\nll n;\nstring s;\n\nvoid build(ll v, ll tl, ll tr){\n  if(tl == tr){\n    t[v][s[tl] - 'a']++;\n  }else{\n    ll tm = (tr - tl) / 2 + tl;\n    build(2 * v, tl, tm);\n    build(2 * v + 1, tm + 1, tr);\n    for(int i = 0; i < 26; i++) t[v][i] = t[2 * v][i] + t[2 * v + 1][i];\n  }\n}\n\nvoid update(ll v, ll tl, ll tr, ll pos, char ch){\n  if(tl == tr){\n    t[v][s[tl] - 'a']--;\n    t[v][ch - 'a']++;\n  }else{\n    ll tm = (tr - tl) / 2 + tl;\n    if(pos <= tm) update(2 * v, tl, tm, pos, ch);\n    else update(2 * v + 1, tm + 1, tr, pos, ch);\n    for(int i = 0; i < 26; i++) t[v][i] = t[2 * v][i] + t[2 * v + 1][i];\n  }\n}\n\nvector < ll > query(ll v, ll tl, ll tr, ll l, ll r){\n  if(l > r){\n    vector < ll > tmp(26, 0);\n    return tmp;\n  }\n  if(tl == l && tr == r){\n    return t[v];\n  }else{\n    ll tm = (tr - tl) / 2 + tl;\n    vector < ll > a = query(2 * v, tl, tm, l, min(r, tm));\n    vector < ll > b = query(2 * v + 1, tm + 1, tr, max(l, tm + 1), r);\n    for(int i = 0; i < 26; i++) a[i] += b[i];\n    return a;\n  }\n}\n\nint main(){\n  ios_base::sync_with_stdio(false);\n  cin.tie(0);cout.tie(0);\n\n  cin >> n;\n  cin >> s;\n\n  build(1, 0, n - 1);\n\n  ll q;\n  cin >> q;\n  while(q--){\n    int a;\n    cin >> a;\n    if(a == 1){\n      ll pos;\n      cin >> pos;\n      char ch;\n      cin >> ch;\n      update(1, 0, n - 1, pos - 1, ch);\n      s[pos - 1] = ch;\n    }else{\n      ll l, r;\n      cin >> l >> r;\n      vector < ll > ans = query(1, 0, n - 1, l - 1, r - 1);\n      ll cnt = 0;\n      for(int i = 0; i < 26; i++){\n        if(ans[i]) cnt++;\n      }\n      cout << cnt << '\\n';\n    }\n  }\n}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nYou are given a string S of length N consisting of lowercase English letters.\n\nProcess Q queries of the following two types:\n\nType 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)\n\nType 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).\n\nConstraints\n\nN, Q, i_q, l_q, and r_q are integers.\n\nS is a string consisting of lowercase English letters.\n\nc_q is a lowercase English letter.\n\n1 \\leq N \\leq 500000\n\n1 \\leq Q \\leq 20000\n\n|S| = N\n\n1 \\leq i_q \\leq N\n\n1 \\leq l_q \\leq r_q \\leq N\n\nThere is at least one query of type 2 in each testcase.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS\nQ\nQuery_1\n\\vdots\nQuery_Q\n\nHere, Query_i in the 4-th through (Q+3)-th lines is one of the following:\n\n1 i_q c_q\n\n2 l_q r_q\n\nOutput\n\nFor each query of type 2, print a line containing the answer.\n\nSample Input 1\n\n7\nabcdbbd\n6\n2 3 6\n1 5 z\n2 1 1\n1 4 a\n1 7 d\n2 1 7\n\nSample Output 1\n\n3\n1\n5\n\nIn the first query, cdbb contains three kinds of letters: b , c , and d, so we print 3.\n\nIn the second query, S is modified to abcdzbd.\n\nIn the third query, a contains one kind of letter: a, so we print 1.\n\nIn the fourth query, S is modified to abcazbd.\n\nIn the fifth query, S does not change and is still abcazbd.\n\nIn the sixth query, abcazbd contains five kinds of letters: a, b, c, d, and z, so we print 5.", "sample_input": "7\nabcdbbd\n6\n2 3 6\n1 5 z\n2 1 1\n1 4 a\n1 7 d\n2 1 7\n"}, "reference_outputs": ["3\n1\n5\n"], "source_document_id": "p02763", "source_text": "Score : 500 points\n\nProblem Statement\n\nYou are given a string S of length N consisting of lowercase English letters.\n\nProcess Q queries of the following two types:\n\nType 1: change the i_q-th character of S to c_q. (Do nothing if the i_q-th character is already c_q.)\n\nType 2: answer the number of different characters occurring in the substring of S between the l_q-th and r_q-th characters (inclusive).\n\nConstraints\n\nN, Q, i_q, l_q, and r_q are integers.\n\nS is a string consisting of lowercase English letters.\n\nc_q is a lowercase English letter.\n\n1 \\leq N \\leq 500000\n\n1 \\leq Q \\leq 20000\n\n|S| = N\n\n1 \\leq i_q \\leq N\n\n1 \\leq l_q \\leq r_q \\leq N\n\nThere is at least one query of type 2 in each testcase.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS\nQ\nQuery_1\n\\vdots\nQuery_Q\n\nHere, Query_i in the 4-th through (Q+3)-th lines is one of the following:\n\n1 i_q c_q\n\n2 l_q r_q\n\nOutput\n\nFor each query of type 2, print a line containing the answer.\n\nSample Input 1\n\n7\nabcdbbd\n6\n2 3 6\n1 5 z\n2 1 1\n1 4 a\n1 7 d\n2 1 7\n\nSample Output 1\n\n3\n1\n5\n\nIn the first query, cdbb contains three kinds of letters: b , c , and d, so we print 3.\n\nIn the second query, S is modified to abcdzbd.\n\nIn the third query, a contains one kind of letter: a, so we print 1.\n\nIn the fourth query, S is modified to abcazbd.\n\nIn the fifth query, S does not change and is still abcazbd.\n\nIn the sixth query, abcazbd contains five kinds of letters: a, b, c, d, and z, so we print 5.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1744, "cpu_time_ms": 426, "memory_kb": 485524}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s863947419", "group_id": "codeNet:p02764", "input_text": "#include <cmath>\n#include <random>\n#include <iostream>\n#include <iomanip>\n#include <algorithm>\n\nusing namespace std;\n\nconst int maxn = 65;\nconst double pi = acos(-1.0);\n\ndouble x[maxn], y[maxn], c[maxn];\nint n, k;\n\ndouble t[maxn];\n\ninline double sqr(double x){\n    return x * x;\n}\n\ninline double dist(double x1,double y1,double x2, double y2){\n    return sqrt(sqr(x1 - x2) + sqr(y1 - y2));\n}\n\ndouble calc_time(double c_x,double c_y){\n    for (int i = 1;i <= n;i++){\n        t[i] = dist(c_x,c_y,x[i],y[i]) * c[i];\n    }\n    nth_element(t+1,t + k, t+n+1);\n    return t[k];\n}\n\nint main(int argc, const char * argv[]) {\n    cin >> n >> k;\n    for (int i = 1;i <= n;i++){\n        cin >> x[i] >> y[i] >> c[i];\n    }\n    random_device rd;\n    mt19937 gen(rd());\n    uniform_real_distribution<> dis2(-1000, 1000);\n    double init_x = dis2(gen);\n    double init_y = dis2(gen);\n\n    double radius = 1500;\n    double ans = calc_time(init_x,init_y);\n    \n\n    //hyperparemeters\n    double alpha = 0.97;\n    int rounds = 750;\n    int randoms = 900;\n    \n  \n\n    while (rounds--){\n        double best_x = 0;\n        double best_y = 0;\n        double cur_best = 1e15;\n        uniform_real_distribution<> dis(-radius, radius);\n        for (int i = 1;i <= randoms;i++){\n            double nx = init_x + dis(gen);\n            double ny = init_y + dis(gen);\n            double score = calc_time(nx, ny);\n            if (score < cur_best){\n                cur_best = score;\n                best_x = nx;\n                best_y = ny;\n            }\n        }\n        if (cur_best < ans){\n            init_x = best_x;\n            init_y = best_y;\n            ans = min(ans, cur_best);\n        }\n\n        radius *= alpha;\n    }\n    cout << fixed << setprecision(8);\n    cout << ans << endl;\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1584508160, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02764.html", "problem_id": "p02764", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02764/input.txt", "sample_output_relpath": "derived/input_output/data/p02764/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02764/C++/s863947419.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s863947419", "user_id": "u222846612"}, "prompt_components": {"gold_output": "2.4\n", "input_to_evaluate": "#include <cmath>\n#include <random>\n#include <iostream>\n#include <iomanip>\n#include <algorithm>\n\nusing namespace std;\n\nconst int maxn = 65;\nconst double pi = acos(-1.0);\n\ndouble x[maxn], y[maxn], c[maxn];\nint n, k;\n\ndouble t[maxn];\n\ninline double sqr(double x){\n    return x * x;\n}\n\ninline double dist(double x1,double y1,double x2, double y2){\n    return sqrt(sqr(x1 - x2) + sqr(y1 - y2));\n}\n\ndouble calc_time(double c_x,double c_y){\n    for (int i = 1;i <= n;i++){\n        t[i] = dist(c_x,c_y,x[i],y[i]) * c[i];\n    }\n    nth_element(t+1,t + k, t+n+1);\n    return t[k];\n}\n\nint main(int argc, const char * argv[]) {\n    cin >> n >> k;\n    for (int i = 1;i <= n;i++){\n        cin >> x[i] >> y[i] >> c[i];\n    }\n    random_device rd;\n    mt19937 gen(rd());\n    uniform_real_distribution<> dis2(-1000, 1000);\n    double init_x = dis2(gen);\n    double init_y = dis2(gen);\n\n    double radius = 1500;\n    double ans = calc_time(init_x,init_y);\n    \n\n    //hyperparemeters\n    double alpha = 0.97;\n    int rounds = 750;\n    int randoms = 900;\n    \n  \n\n    while (rounds--){\n        double best_x = 0;\n        double best_y = 0;\n        double cur_best = 1e15;\n        uniform_real_distribution<> dis(-radius, radius);\n        for (int i = 1;i <= randoms;i++){\n            double nx = init_x + dis(gen);\n            double ny = init_y + dis(gen);\n            double score = calc_time(nx, ny);\n            if (score < cur_best){\n                cur_best = score;\n                best_x = nx;\n                best_y = ny;\n            }\n        }\n        if (cur_best < ans){\n            init_x = best_x;\n            init_y = best_y;\n            ans = min(ans, cur_best);\n        }\n\n        radius *= alpha;\n    }\n    cout << fixed << setprecision(8);\n    cout << ans << endl;\n    return 0;\n}\n", "problem_context": "Score : 600 points\n\nProblem Statement\n\nTakahashi wants to grill N pieces of meat on a grilling net, which can be seen as a two-dimensional plane. The coordinates of the i-th piece of meat are \\left(x_i, y_i\\right), and its hardness is c_i.\n\nTakahashi can use one heat source to grill the meat. If he puts the heat source at coordinates \\left(X, Y\\right), where X and Y are real numbers, the i-th piece of meat will be ready to eat in c_i \\times \\sqrt{\\left(X - x_i\\right)^2 + \\left(Y-y_i\\right)^2} seconds.\n\nTakahashi wants to eat K pieces of meat. Find the time required to have K or more pieces of meat ready if he put the heat source to minimize this time.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 60\n\n1 \\leq K \\leq N\n\n-1000 \\leq x_i , y_i \\leq 1000\n\n\\left(x_i, y_i\\right) \\neq \\left(x_j, y_j\\right) \\left(i \\neq j \\right)\n\n1 \\leq c_i \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nx_1 y_1 c_1\n\\vdots\nx_N y_N c_N\n\nOutput\n\nPrint the answer.\n\nIt will be considered correct if its absolute or relative error from our answer is at most 10^{-6}.\n\nSample Input 1\n\n4 3\n-1 0 3\n0 0 3\n1 0 2\n1 1 40\n\nSample Output 1\n\n2.4\n\nIf we put the heat source at \\left(-0.2, 0\\right), the 1-st, 2-nd, and 3-rd pieces of meat will be ready to eat within 2.4 seconds. This is the optimal place to put the heat source.\n\nSample Input 2\n\n10 5\n-879 981 26\n890 -406 81\n512 859 97\n362 -955 25\n128 553 17\n-885 763 2\n449 310 57\n-656 -204 11\n-270 76 40\n184 170 16\n\nSample Output 2\n\n7411.2252", "sample_input": "4 3\n-1 0 3\n0 0 3\n1 0 2\n1 1 40\n"}, "reference_outputs": ["2.4\n"], "source_document_id": "p02764", "source_text": "Score : 600 points\n\nProblem Statement\n\nTakahashi wants to grill N pieces of meat on a grilling net, which can be seen as a two-dimensional plane. The coordinates of the i-th piece of meat are \\left(x_i, y_i\\right), and its hardness is c_i.\n\nTakahashi can use one heat source to grill the meat. If he puts the heat source at coordinates \\left(X, Y\\right), where X and Y are real numbers, the i-th piece of meat will be ready to eat in c_i \\times \\sqrt{\\left(X - x_i\\right)^2 + \\left(Y-y_i\\right)^2} seconds.\n\nTakahashi wants to eat K pieces of meat. Find the time required to have K or more pieces of meat ready if he put the heat source to minimize this time.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 60\n\n1 \\leq K \\leq N\n\n-1000 \\leq x_i , y_i \\leq 1000\n\n\\left(x_i, y_i\\right) \\neq \\left(x_j, y_j\\right) \\left(i \\neq j \\right)\n\n1 \\leq c_i \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nx_1 y_1 c_1\n\\vdots\nx_N y_N c_N\n\nOutput\n\nPrint the answer.\n\nIt will be considered correct if its absolute or relative error from our answer is at most 10^{-6}.\n\nSample Input 1\n\n4 3\n-1 0 3\n0 0 3\n1 0 2\n1 1 40\n\nSample Output 1\n\n2.4\n\nIf we put the heat source at \\left(-0.2, 0\\right), the 1-st, 2-nd, and 3-rd pieces of meat will be ready to eat within 2.4 seconds. This is the optimal place to put the heat source.\n\nSample Input 2\n\n10 5\n-879 981 26\n890 -406 81\n512 859 97\n362 -955 25\n128 553 17\n-885 763 2\n449 310 57\n-656 -204 11\n-270 76 40\n184 170 16\n\nSample Output 2\n\n7411.2252", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1782, "cpu_time_ms": 384, "memory_kb": 384}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s699843919", "group_id": "codeNet:p02765", "input_text": "#define _GLIBCXX_DEBUG\n#include <bits/stdc++.h>\n#define REP(i, n) for (int i = 0; i < (n); ++i)\n#define REPS(I, a, b) for (int i = (a); i < (b); ++i)\nusing namespace std;\nusing ll = long long;\n\nint main() {\n \n  int n,r; \n  cin >> n >> r;\n\n  if(n < 10){\n    r += 100 * (10-n);\n  }\n  \n  cout << r << endl;\n}", "language": "C++", "metadata": {"date": 1599764170, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02765.html", "problem_id": "p02765", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02765/input.txt", "sample_output_relpath": "derived/input_output/data/p02765/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02765/C++/s699843919.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s699843919", "user_id": "u514896542"}, "prompt_components": {"gold_output": "3719\n", "input_to_evaluate": "#define _GLIBCXX_DEBUG\n#include <bits/stdc++.h>\n#define REP(i, n) for (int i = 0; i < (n); ++i)\n#define REPS(I, a, b) for (int i = (a); i < (b); ++i)\nusing namespace std;\nusing ll = long long;\n\nint main() {\n \n  int n,r; \n  cin >> n >> r;\n\n  if(n < 10){\n    r += 100 * (10-n);\n  }\n  \n  cout << r << endl;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nTakahashi is a member of a programming competition site, ButCoder.\n\nEach member of ButCoder is assigned two values: Inner Rating and Displayed Rating.\n\nThe Displayed Rating of a member is equal to their Inner Rating if the member has participated in 10 or more contests. Otherwise, the Displayed Rating will be their Inner Rating minus 100 \\times (10 - K) when the member has participated in K contests.\n\nTakahashi has participated in N contests, and his Displayed Rating is R. Find his Inner Rating.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 100\n\n0 \\leq R \\leq 4111\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN R\n\nOutput\n\nPrint his Inner Rating.\n\nSample Input 1\n\n2 2919\n\nSample Output 1\n\n3719\n\nTakahashi has participated in 2 contests, which is less than 10, so his Displayed Rating is his Inner Rating minus 100 \\times (10 - 2) = 800.\n\nThus, Takahashi's Inner Rating is 2919 + 800 = 3719.\n\nSample Input 2\n\n22 3051\n\nSample Output 2\n\n3051", "sample_input": "2 2919\n"}, "reference_outputs": ["3719\n"], "source_document_id": "p02765", "source_text": "Score : 100 points\n\nProblem Statement\n\nTakahashi is a member of a programming competition site, ButCoder.\n\nEach member of ButCoder is assigned two values: Inner Rating and Displayed Rating.\n\nThe Displayed Rating of a member is equal to their Inner Rating if the member has participated in 10 or more contests. Otherwise, the Displayed Rating will be their Inner Rating minus 100 \\times (10 - K) when the member has participated in K contests.\n\nTakahashi has participated in N contests, and his Displayed Rating is R. Find his Inner Rating.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 100\n\n0 \\leq R \\leq 4111\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN R\n\nOutput\n\nPrint his Inner Rating.\n\nSample Input 1\n\n2 2919\n\nSample Output 1\n\n3719\n\nTakahashi has participated in 2 contests, which is less than 10, so his Displayed Rating is his Inner Rating minus 100 \\times (10 - 2) = 800.\n\nThus, Takahashi's Inner Rating is 2919 + 800 = 3719.\n\nSample Input 2\n\n22 3051\n\nSample Output 2\n\n3051", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 305, "cpu_time_ms": 6, "memory_kb": 3572}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s067800794", "group_id": "codeNet:p02765", "input_text": "#include <iostream>\nusing namespace std;\n \nint main(){\n int n,r;\n  cin >> n >> r;\n  if(n < 10){\n   \tr+=100*(10-n);\n  }\n  cout << r << endl;\n}", "language": "C++", "metadata": {"date": 1582424059, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02765.html", "problem_id": "p02765", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02765/input.txt", "sample_output_relpath": "derived/input_output/data/p02765/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02765/C++/s067800794.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s067800794", "user_id": "u262549958"}, "prompt_components": {"gold_output": "3719\n", "input_to_evaluate": "#include <iostream>\nusing namespace std;\n \nint main(){\n int n,r;\n  cin >> n >> r;\n  if(n < 10){\n   \tr+=100*(10-n);\n  }\n  cout << r << endl;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nTakahashi is a member of a programming competition site, ButCoder.\n\nEach member of ButCoder is assigned two values: Inner Rating and Displayed Rating.\n\nThe Displayed Rating of a member is equal to their Inner Rating if the member has participated in 10 or more contests. Otherwise, the Displayed Rating will be their Inner Rating minus 100 \\times (10 - K) when the member has participated in K contests.\n\nTakahashi has participated in N contests, and his Displayed Rating is R. Find his Inner Rating.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 100\n\n0 \\leq R \\leq 4111\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN R\n\nOutput\n\nPrint his Inner Rating.\n\nSample Input 1\n\n2 2919\n\nSample Output 1\n\n3719\n\nTakahashi has participated in 2 contests, which is less than 10, so his Displayed Rating is his Inner Rating minus 100 \\times (10 - 2) = 800.\n\nThus, Takahashi's Inner Rating is 2919 + 800 = 3719.\n\nSample Input 2\n\n22 3051\n\nSample Output 2\n\n3051", "sample_input": "2 2919\n"}, "reference_outputs": ["3719\n"], "source_document_id": "p02765", "source_text": "Score : 100 points\n\nProblem Statement\n\nTakahashi is a member of a programming competition site, ButCoder.\n\nEach member of ButCoder is assigned two values: Inner Rating and Displayed Rating.\n\nThe Displayed Rating of a member is equal to their Inner Rating if the member has participated in 10 or more contests. Otherwise, the Displayed Rating will be their Inner Rating minus 100 \\times (10 - K) when the member has participated in K contests.\n\nTakahashi has participated in N contests, and his Displayed Rating is R. Find his Inner Rating.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 100\n\n0 \\leq R \\leq 4111\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN R\n\nOutput\n\nPrint his Inner Rating.\n\nSample Input 1\n\n2 2919\n\nSample Output 1\n\n3719\n\nTakahashi has participated in 2 contests, which is less than 10, so his Displayed Rating is his Inner Rating minus 100 \\times (10 - 2) = 800.\n\nThus, Takahashi's Inner Rating is 2919 + 800 = 3719.\n\nSample Input 2\n\n22 3051\n\nSample Output 2\n\n3051", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 141, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s019222752", "group_id": "codeNet:p02765", "input_text": "#include <iostream>\n#include <algorithm>\n#include <cmath>\n#include <string>\n#include <cstdlib>\n#include <vector>\n#include <iomanip>\n#include <utility>\nusing namespace std;\n#define ll long long\n\nint main(void){\n    ll n, r;\n    cin >> n >> r;\n    if(n >= 10)\n        cout << r << endl;\n    else if(n < 10)\n        cout << r + 100*(10-n) << endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1582423341, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02765.html", "problem_id": "p02765", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02765/input.txt", "sample_output_relpath": "derived/input_output/data/p02765/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02765/C++/s019222752.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s019222752", "user_id": "u157195505"}, "prompt_components": {"gold_output": "3719\n", "input_to_evaluate": "#include <iostream>\n#include <algorithm>\n#include <cmath>\n#include <string>\n#include <cstdlib>\n#include <vector>\n#include <iomanip>\n#include <utility>\nusing namespace std;\n#define ll long long\n\nint main(void){\n    ll n, r;\n    cin >> n >> r;\n    if(n >= 10)\n        cout << r << endl;\n    else if(n < 10)\n        cout << r + 100*(10-n) << endl;\n    return 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nTakahashi is a member of a programming competition site, ButCoder.\n\nEach member of ButCoder is assigned two values: Inner Rating and Displayed Rating.\n\nThe Displayed Rating of a member is equal to their Inner Rating if the member has participated in 10 or more contests. Otherwise, the Displayed Rating will be their Inner Rating minus 100 \\times (10 - K) when the member has participated in K contests.\n\nTakahashi has participated in N contests, and his Displayed Rating is R. Find his Inner Rating.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 100\n\n0 \\leq R \\leq 4111\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN R\n\nOutput\n\nPrint his Inner Rating.\n\nSample Input 1\n\n2 2919\n\nSample Output 1\n\n3719\n\nTakahashi has participated in 2 contests, which is less than 10, so his Displayed Rating is his Inner Rating minus 100 \\times (10 - 2) = 800.\n\nThus, Takahashi's Inner Rating is 2919 + 800 = 3719.\n\nSample Input 2\n\n22 3051\n\nSample Output 2\n\n3051", "sample_input": "2 2919\n"}, "reference_outputs": ["3719\n"], "source_document_id": "p02765", "source_text": "Score : 100 points\n\nProblem Statement\n\nTakahashi is a member of a programming competition site, ButCoder.\n\nEach member of ButCoder is assigned two values: Inner Rating and Displayed Rating.\n\nThe Displayed Rating of a member is equal to their Inner Rating if the member has participated in 10 or more contests. Otherwise, the Displayed Rating will be their Inner Rating minus 100 \\times (10 - K) when the member has participated in K contests.\n\nTakahashi has participated in N contests, and his Displayed Rating is R. Find his Inner Rating.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 100\n\n0 \\leq R \\leq 4111\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN R\n\nOutput\n\nPrint his Inner Rating.\n\nSample Input 1\n\n2 2919\n\nSample Output 1\n\n3719\n\nTakahashi has participated in 2 contests, which is less than 10, so his Displayed Rating is his Inner Rating minus 100 \\times (10 - 2) = 800.\n\nThus, Takahashi's Inner Rating is 2919 + 800 = 3719.\n\nSample Input 2\n\n22 3051\n\nSample Output 2\n\n3051", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 360, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s986142485", "group_id": "codeNet:p02766", "input_text": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <ctime>\n#include <cmath>\n#include <string>\n#include <stdlib.h>\n#include <fstream>\n#include <set>\n#include <map>\n#include <stack>\n#include <deque>\n#include <iterator>\nusing namespace std;\n\n\nint main(){\n    long long n, k, c = 0;\n    cin >> n >> k;\n    while(n){\n      n /= k;\n      c++;\n    }\n    cout << c;\n}", "language": "C++", "metadata": {"date": 1582714530, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02766.html", "problem_id": "p02766", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02766/input.txt", "sample_output_relpath": "derived/input_output/data/p02766/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02766/C++/s986142485.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s986142485", "user_id": "u595984176"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <ctime>\n#include <cmath>\n#include <string>\n#include <stdlib.h>\n#include <fstream>\n#include <set>\n#include <map>\n#include <stack>\n#include <deque>\n#include <iterator>\nusing namespace std;\n\n\nint main(){\n    long long n, k, c = 0;\n    cin >> n >> k;\n    while(n){\n      n /= k;\n      c++;\n    }\n    cout << c;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nGiven is an integer N. Find the number of digits that N has in base K.\n\nNotes\n\nFor information on base-K representation, see Positional notation - Wikipedia.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^9\n\n2 \\leq K \\leq 10\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the number of digits that N has in base K.\n\nSample Input 1\n\n11 2\n\nSample Output 1\n\n4\n\nIn binary, 11 is represented as 1011.\n\nSample Input 2\n\n1010101 10\n\nSample Output 2\n\n7\n\nSample Input 3\n\n314159265 3\n\nSample Output 3\n\n18", "sample_input": "11 2\n"}, "reference_outputs": ["4\n"], "source_document_id": "p02766", "source_text": "Score : 200 points\n\nProblem Statement\n\nGiven is an integer N. Find the number of digits that N has in base K.\n\nNotes\n\nFor information on base-K representation, see Positional notation - Wikipedia.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^9\n\n2 \\leq K \\leq 10\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the number of digits that N has in base K.\n\nSample Input 1\n\n11 2\n\nSample Output 1\n\n4\n\nIn binary, 11 is represented as 1011.\n\nSample Input 2\n\n1010101 10\n\nSample Output 2\n\n7\n\nSample Input 3\n\n314159265 3\n\nSample Output 3\n\n18", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 376, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s901617987", "group_id": "codeNet:p02766", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\ntypedef long long ll;\ntypedef int64_t i6;\n\n#define rep(i, n) for (ll i = 0; i < n; ++i)\n#define Sort(x) sort(x.begin(), x.end())\n#define Sort_rev(x) sort(x.begin(), x.end(), greater<int>())\n#define ALL(v) (v).begin(), (v).end()\n\n// π M_PI\n// deg = rad*180/M_PI\n\nint main() {\n    ll n, k;\n    cin >> n >> k;\n    ll ans = 0;\n    while ( n > pow(k, ans) ) {\n        // cout << ans << \" \" << pow(k, ans) << endl;\n        ans++;\n    }\n    cout << ans << endl;\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1582433031, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02766.html", "problem_id": "p02766", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02766/input.txt", "sample_output_relpath": "derived/input_output/data/p02766/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02766/C++/s901617987.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s901617987", "user_id": "u745852541"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\ntypedef long long ll;\ntypedef int64_t i6;\n\n#define rep(i, n) for (ll i = 0; i < n; ++i)\n#define Sort(x) sort(x.begin(), x.end())\n#define Sort_rev(x) sort(x.begin(), x.end(), greater<int>())\n#define ALL(v) (v).begin(), (v).end()\n\n// π M_PI\n// deg = rad*180/M_PI\n\nint main() {\n    ll n, k;\n    cin >> n >> k;\n    ll ans = 0;\n    while ( n > pow(k, ans) ) {\n        // cout << ans << \" \" << pow(k, ans) << endl;\n        ans++;\n    }\n    cout << ans << endl;\n    return 0;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nGiven is an integer N. Find the number of digits that N has in base K.\n\nNotes\n\nFor information on base-K representation, see Positional notation - Wikipedia.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^9\n\n2 \\leq K \\leq 10\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the number of digits that N has in base K.\n\nSample Input 1\n\n11 2\n\nSample Output 1\n\n4\n\nIn binary, 11 is represented as 1011.\n\nSample Input 2\n\n1010101 10\n\nSample Output 2\n\n7\n\nSample Input 3\n\n314159265 3\n\nSample Output 3\n\n18", "sample_input": "11 2\n"}, "reference_outputs": ["4\n"], "source_document_id": "p02766", "source_text": "Score : 200 points\n\nProblem Statement\n\nGiven is an integer N. Find the number of digits that N has in base K.\n\nNotes\n\nFor information on base-K representation, see Positional notation - Wikipedia.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^9\n\n2 \\leq K \\leq 10\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the number of digits that N has in base K.\n\nSample Input 1\n\n11 2\n\nSample Output 1\n\n4\n\nIn binary, 11 is represented as 1011.\n\nSample Input 2\n\n1010101 10\n\nSample Output 2\n\n7\n\nSample Input 3\n\n314159265 3\n\nSample Output 3\n\n18", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 519, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s022668069", "group_id": "codeNet:p02766", "input_text": "//#include <bits/stdc++.h>\n#include <iostream>\n#include <vector>\n#include <string>\n#include <math.h>\nusing namespace std;\ntypedef long long ll;\nconst double EPS = 1e-9;\ntypedef vector<int> vint;\ntypedef pair<int, int> pint;\n#define inf 1e+9\n#define rep(i, n) REP(i, 0, n)\n#define all(v) v.begin(), v.end()\n#define msg(a) cout << #a << \" \" << a << endl;\n#define REP(i, x, n) for(int i = x; i < n; i++)\n#define pri(a) cout << a << endl;\n\nint main(){\n  cin.tie(nullptr);\n\tios::sync_with_stdio(false);\n\n  ll n,k,ans=0;\n  cin >> n >> k;\n\n  if(n>=1){\n    ans++;\n  }\n\n  int i=1,h=k;\n  while(n>=h){\n    ans++;\n    i++;\n    h = pow(k,i);\n  }\n\n\n  pri(ans);\n\n}", "language": "C++", "metadata": {"date": 1582424080, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02766.html", "problem_id": "p02766", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02766/input.txt", "sample_output_relpath": "derived/input_output/data/p02766/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02766/C++/s022668069.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s022668069", "user_id": "u220892578"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "//#include <bits/stdc++.h>\n#include <iostream>\n#include <vector>\n#include <string>\n#include <math.h>\nusing namespace std;\ntypedef long long ll;\nconst double EPS = 1e-9;\ntypedef vector<int> vint;\ntypedef pair<int, int> pint;\n#define inf 1e+9\n#define rep(i, n) REP(i, 0, n)\n#define all(v) v.begin(), v.end()\n#define msg(a) cout << #a << \" \" << a << endl;\n#define REP(i, x, n) for(int i = x; i < n; i++)\n#define pri(a) cout << a << endl;\n\nint main(){\n  cin.tie(nullptr);\n\tios::sync_with_stdio(false);\n\n  ll n,k,ans=0;\n  cin >> n >> k;\n\n  if(n>=1){\n    ans++;\n  }\n\n  int i=1,h=k;\n  while(n>=h){\n    ans++;\n    i++;\n    h = pow(k,i);\n  }\n\n\n  pri(ans);\n\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nGiven is an integer N. Find the number of digits that N has in base K.\n\nNotes\n\nFor information on base-K representation, see Positional notation - Wikipedia.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^9\n\n2 \\leq K \\leq 10\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the number of digits that N has in base K.\n\nSample Input 1\n\n11 2\n\nSample Output 1\n\n4\n\nIn binary, 11 is represented as 1011.\n\nSample Input 2\n\n1010101 10\n\nSample Output 2\n\n7\n\nSample Input 3\n\n314159265 3\n\nSample Output 3\n\n18", "sample_input": "11 2\n"}, "reference_outputs": ["4\n"], "source_document_id": "p02766", "source_text": "Score : 200 points\n\nProblem Statement\n\nGiven is an integer N. Find the number of digits that N has in base K.\n\nNotes\n\nFor information on base-K representation, see Positional notation - Wikipedia.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^9\n\n2 \\leq K \\leq 10\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the number of digits that N has in base K.\n\nSample Input 1\n\n11 2\n\nSample Output 1\n\n4\n\nIn binary, 11 is represented as 1011.\n\nSample Input 2\n\n1010101 10\n\nSample Output 2\n\n7\n\nSample Input 3\n\n314159265 3\n\nSample Output 3\n\n18", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 649, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s983532682", "group_id": "codeNet:p02767", "input_text": "#include<bits/stdc++.h>\n#define ing long long \n#define rap(i,n) for(int i=0;i<n;i++)\nusing namespace std;\nsigned main(){\n  int n,a[100000],cum=0,sum=0;\n  cin>>n;\n  for(int i=0;i<n;i++){\n    cin>>a[i];\n    cum+=a[i];\n  }\n  cum = cum / n+1;\n  for(int i=0;i<n;i++){\n    sum+=pow(abs(cum-a[i]),2);\n  }\n\n  cout<<sum<<\"\\n\";\n\n  return(0);\n}\n", "language": "C++", "metadata": {"date": 1582425084, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02767.html", "problem_id": "p02767", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02767/input.txt", "sample_output_relpath": "derived/input_output/data/p02767/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02767/C++/s983532682.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s983532682", "user_id": "u652908807"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include<bits/stdc++.h>\n#define ing long long \n#define rap(i,n) for(int i=0;i<n;i++)\nusing namespace std;\nsigned main(){\n  int n,a[100000],cum=0,sum=0;\n  cin>>n;\n  for(int i=0;i<n;i++){\n    cin>>a[i];\n    cum+=a[i];\n  }\n  cum = cum / n+1;\n  for(int i=0;i<n;i++){\n    sum+=pow(abs(cum-a[i]),2);\n  }\n\n  cout<<sum<<\"\\n\";\n\n  return(0);\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N people living on a number line.\n\nThe i-th person lives at coordinate X_i.\n\nYou are going to hold a meeting that all N people have to attend.\n\nThe meeting can be held at any integer coordinate. If you choose to hold the meeting at coordinate P, the i-th person will spend (X_i - P)^2 points of stamina to attend the meeting.\n\nFind the minimum total points of stamina the N people have to spend.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 100\n\n1 \\leq X_i \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nX_1 X_2 ... X_N\n\nOutput\n\nPrint the minimum total stamina the N people have to spend.\n\nSample Input 1\n\n2\n1 4\n\nSample Output 1\n\n5\n\nAssume the meeting is held at coordinate 2. In this case, the first person will spend (1 - 2)^2 points of stamina, and the second person will spend (4 - 2)^2 = 4 points of stamina, for a total of 5 points of stamina. This is the minimum total stamina that the 2 people have to spend.\n\nNote that you can hold the meeting only at an integer coordinate.\n\nSample Input 2\n\n7\n14 14 2 13 56 2 37\n\nSample Output 2\n\n2354", "sample_input": "2\n1 4\n"}, "reference_outputs": ["5\n"], "source_document_id": "p02767", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N people living on a number line.\n\nThe i-th person lives at coordinate X_i.\n\nYou are going to hold a meeting that all N people have to attend.\n\nThe meeting can be held at any integer coordinate. If you choose to hold the meeting at coordinate P, the i-th person will spend (X_i - P)^2 points of stamina to attend the meeting.\n\nFind the minimum total points of stamina the N people have to spend.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 100\n\n1 \\leq X_i \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nX_1 X_2 ... X_N\n\nOutput\n\nPrint the minimum total stamina the N people have to spend.\n\nSample Input 1\n\n2\n1 4\n\nSample Output 1\n\n5\n\nAssume the meeting is held at coordinate 2. In this case, the first person will spend (1 - 2)^2 points of stamina, and the second person will spend (4 - 2)^2 = 4 points of stamina, for a total of 5 points of stamina. This is the minimum total stamina that the 2 people have to spend.\n\nNote that you can hold the meeting only at an integer coordinate.\n\nSample Input 2\n\n7\n14 14 2 13 56 2 37\n\nSample Output 2\n\n2354", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 334, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s613636366", "group_id": "codeNet:p02767", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n#define IO ios::sync_with_stdio(false), cin.tie(0), cout.tie(0)\ntypedef long long ll;\nconst int maxn = 105;\nint a[maxn];\n\nint main()\n{\n    IO;\n    int n;\n    cin >> n;\n    for (int i = 1; i <= n; ++i)\n        cin >> a[i];\n    ll minn = 0x3f3f3f3f;\n    for (int pos = 1; pos <= 100; ++pos)\n    {\n        ll t = 0;\n        for (int i = 1; i <= n; ++i)\n            t += (pos - a[i]) * (pos - a[i]);\n        minn = min(minn, t);\n    }\n    cout << minn << endl;\n}", "language": "C++", "metadata": {"date": 1582424005, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02767.html", "problem_id": "p02767", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02767/input.txt", "sample_output_relpath": "derived/input_output/data/p02767/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02767/C++/s613636366.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s613636366", "user_id": "u035226457"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n#define IO ios::sync_with_stdio(false), cin.tie(0), cout.tie(0)\ntypedef long long ll;\nconst int maxn = 105;\nint a[maxn];\n\nint main()\n{\n    IO;\n    int n;\n    cin >> n;\n    for (int i = 1; i <= n; ++i)\n        cin >> a[i];\n    ll minn = 0x3f3f3f3f;\n    for (int pos = 1; pos <= 100; ++pos)\n    {\n        ll t = 0;\n        for (int i = 1; i <= n; ++i)\n            t += (pos - a[i]) * (pos - a[i]);\n        minn = min(minn, t);\n    }\n    cout << minn << endl;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N people living on a number line.\n\nThe i-th person lives at coordinate X_i.\n\nYou are going to hold a meeting that all N people have to attend.\n\nThe meeting can be held at any integer coordinate. If you choose to hold the meeting at coordinate P, the i-th person will spend (X_i - P)^2 points of stamina to attend the meeting.\n\nFind the minimum total points of stamina the N people have to spend.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 100\n\n1 \\leq X_i \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nX_1 X_2 ... X_N\n\nOutput\n\nPrint the minimum total stamina the N people have to spend.\n\nSample Input 1\n\n2\n1 4\n\nSample Output 1\n\n5\n\nAssume the meeting is held at coordinate 2. In this case, the first person will spend (1 - 2)^2 points of stamina, and the second person will spend (4 - 2)^2 = 4 points of stamina, for a total of 5 points of stamina. This is the minimum total stamina that the 2 people have to spend.\n\nNote that you can hold the meeting only at an integer coordinate.\n\nSample Input 2\n\n7\n14 14 2 13 56 2 37\n\nSample Output 2\n\n2354", "sample_input": "2\n1 4\n"}, "reference_outputs": ["5\n"], "source_document_id": "p02767", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N people living on a number line.\n\nThe i-th person lives at coordinate X_i.\n\nYou are going to hold a meeting that all N people have to attend.\n\nThe meeting can be held at any integer coordinate. If you choose to hold the meeting at coordinate P, the i-th person will spend (X_i - P)^2 points of stamina to attend the meeting.\n\nFind the minimum total points of stamina the N people have to spend.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 100\n\n1 \\leq X_i \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nX_1 X_2 ... X_N\n\nOutput\n\nPrint the minimum total stamina the N people have to spend.\n\nSample Input 1\n\n2\n1 4\n\nSample Output 1\n\n5\n\nAssume the meeting is held at coordinate 2. In this case, the first person will spend (1 - 2)^2 points of stamina, and the second person will spend (4 - 2)^2 = 4 points of stamina, for a total of 5 points of stamina. This is the minimum total stamina that the 2 people have to spend.\n\nNote that you can hold the meeting only at an integer coordinate.\n\nSample Input 2\n\n7\n14 14 2 13 56 2 37\n\nSample Output 2\n\n2354", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 504, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s907191769", "group_id": "codeNet:p02767", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\n#if DEBUG && !ONLINE_JUDGE\n  #include \"header.h\"\n#else\n  #define debug(args...)\n#endif\n\ntypedef vector<int> vi;\ntypedef pair<int,int> ii;\ntypedef long long lli;\ntypedef long double ld;\n\n#define pb push_back\n#define all(x) x.begin(),x.end()\n#define SZ(x) (int)(x).size()\n#define fi first\n#define se second\n#define lb lower_bound\n#define ub upper_bound\n#define rep(i,a,b) for(auto i=(a);i<b;i++)\n\n#define INF (int)1e9\n#define EPS 1e-9\n#define MOD 1000000007\nvoid preprocess(void) {\n  return;\n}\nint main() {\n  ios_base::sync_with_stdio(false);\n  cin.tie(NULL);\n  cout.precision(20);\n  preprocess();\n  int n; cin>>n;\n  vi x(n);\n  rep(i,0,n) cin>>x[i];\n  lli ans = 0;\n  rep(i,0,n) ans += x[i];\n  ans /= n;\n  lli fans = MOD * 1LL * MOD;\n  rep(k,ans-2,ans+2) {\n    lli sum = 0;\n    rep(i,0,n) sum += (x[i]-k)*1LL*(x[i]-k);\n    fans = min(fans, sum);\n  }\n  cout<<fans<<endl;\n}\n\n", "language": "C++", "metadata": {"date": 1582423531, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02767.html", "problem_id": "p02767", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02767/input.txt", "sample_output_relpath": "derived/input_output/data/p02767/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02767/C++/s907191769.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s907191769", "user_id": "u447708702"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\n#if DEBUG && !ONLINE_JUDGE\n  #include \"header.h\"\n#else\n  #define debug(args...)\n#endif\n\ntypedef vector<int> vi;\ntypedef pair<int,int> ii;\ntypedef long long lli;\ntypedef long double ld;\n\n#define pb push_back\n#define all(x) x.begin(),x.end()\n#define SZ(x) (int)(x).size()\n#define fi first\n#define se second\n#define lb lower_bound\n#define ub upper_bound\n#define rep(i,a,b) for(auto i=(a);i<b;i++)\n\n#define INF (int)1e9\n#define EPS 1e-9\n#define MOD 1000000007\nvoid preprocess(void) {\n  return;\n}\nint main() {\n  ios_base::sync_with_stdio(false);\n  cin.tie(NULL);\n  cout.precision(20);\n  preprocess();\n  int n; cin>>n;\n  vi x(n);\n  rep(i,0,n) cin>>x[i];\n  lli ans = 0;\n  rep(i,0,n) ans += x[i];\n  ans /= n;\n  lli fans = MOD * 1LL * MOD;\n  rep(k,ans-2,ans+2) {\n    lli sum = 0;\n    rep(i,0,n) sum += (x[i]-k)*1LL*(x[i]-k);\n    fans = min(fans, sum);\n  }\n  cout<<fans<<endl;\n}\n\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N people living on a number line.\n\nThe i-th person lives at coordinate X_i.\n\nYou are going to hold a meeting that all N people have to attend.\n\nThe meeting can be held at any integer coordinate. If you choose to hold the meeting at coordinate P, the i-th person will spend (X_i - P)^2 points of stamina to attend the meeting.\n\nFind the minimum total points of stamina the N people have to spend.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 100\n\n1 \\leq X_i \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nX_1 X_2 ... X_N\n\nOutput\n\nPrint the minimum total stamina the N people have to spend.\n\nSample Input 1\n\n2\n1 4\n\nSample Output 1\n\n5\n\nAssume the meeting is held at coordinate 2. In this case, the first person will spend (1 - 2)^2 points of stamina, and the second person will spend (4 - 2)^2 = 4 points of stamina, for a total of 5 points of stamina. This is the minimum total stamina that the 2 people have to spend.\n\nNote that you can hold the meeting only at an integer coordinate.\n\nSample Input 2\n\n7\n14 14 2 13 56 2 37\n\nSample Output 2\n\n2354", "sample_input": "2\n1 4\n"}, "reference_outputs": ["5\n"], "source_document_id": "p02767", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N people living on a number line.\n\nThe i-th person lives at coordinate X_i.\n\nYou are going to hold a meeting that all N people have to attend.\n\nThe meeting can be held at any integer coordinate. If you choose to hold the meeting at coordinate P, the i-th person will spend (X_i - P)^2 points of stamina to attend the meeting.\n\nFind the minimum total points of stamina the N people have to spend.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 100\n\n1 \\leq X_i \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nX_1 X_2 ... X_N\n\nOutput\n\nPrint the minimum total stamina the N people have to spend.\n\nSample Input 1\n\n2\n1 4\n\nSample Output 1\n\n5\n\nAssume the meeting is held at coordinate 2. In this case, the first person will spend (1 - 2)^2 points of stamina, and the second person will spend (4 - 2)^2 = 4 points of stamina, for a total of 5 points of stamina. This is the minimum total stamina that the 2 people have to spend.\n\nNote that you can hold the meeting only at an integer coordinate.\n\nSample Input 2\n\n7\n14 14 2 13 56 2 37\n\nSample Output 2\n\n2354", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 917, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s312312066", "group_id": "codeNet:p02768", "input_text": "#include <iostream>\n#include <cstdio>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <functional>\n#include <iomanip>\n#include <stdlib.h>\n#include <string.h>\n#include <cstring>\n#include <cmath>\n#include <map>\n#include <queue>\n#include <deque>\n#include <stack>\n#include <set>\n#include <stdio.h>\n#include <tuple>\n#include <bitset>\n#include <cfloat>\n#include <fstream>\n#include <limits.h>\n#include <list>\n#include <math.h>\n#include <random>\n#include <unordered_map>\n#include <unordered_set>\n#include <bitset>\n#include <numeric>\n#include <utility>\n#include <sstream>\n#include <cassert>\ntemplate<class T> inline bool chmin(T& a, T b) {\n\tif (a > b) {\n\t\ta = b;\n\t\treturn true;\n\t}\n\treturn false;\n}\ntemplate<class T> inline bool chmax(T& a, T b) {\n\tif (a < b) {\n\t\ta = b;\n\t\treturn true;\n\t}\n\treturn false;\n}\nusing namespace std;\n#define int long long\n#define ll long long\n#define rep(i, n) for (ll i = 0; i < (n); i++)\n#define P pair<ll, ll>\n#define sz(x) (ll)x.size()\n#define ALL(x) (x).begin(),(x).end()\n#define ALLR(x) (x).rbegin(),(x).rend()\n#define VE vector<ll>\n#define COUT(x) cout<<(x)<<endl\n#define MA map<ll,ll>\n#define SE set<ll>\n#define PQ priority_queue<ll>\n#define PQR priority_queue<ll,VE,greater<ll>>\n#define YES(n) cout << ((n) ? \"YES\" : \"NO\"  ) << endl\n#define Yes(n) cout << ((n) ? \"Yes\" : \"No\"  ) << endl\n#define EPS (1e-14)\n#define pb push_back\nlong long MOD = 1000000007;\n//const long long MOD = 998244353;\nconst long long INF = 1LL << 60;\nconst double PI = acos(-1.0);\nusing Graph = vector<VE>;\nstruct mint {\n\tll x; // typedef long long ll;\n\tmint(ll x = 0) :x((x%MOD + MOD) % MOD) {}\n\tmint operator-() const { return mint(-x); }\n\tmint& operator+=(const mint a) {\n\t\tif ((x += a.x) >= MOD) x -= MOD;\n\t\treturn *this;\n\t}\n\tmint& operator-=(const mint a) {\n\t\tif ((x += MOD - a.x) >= MOD) x -= MOD;\n\t\treturn *this;\n\t}\n\tmint& operator*=(const mint a) {\n\t\t(x *= a.x) %= MOD;\n\t\treturn *this;\n\t}\n\tmint operator+(const mint a) const {\n\t\tmint res(*this);\n\t\treturn res += a;\n\t}\n\tmint operator-(const mint a) const {\n\t\tmint res(*this);\n\t\treturn res -= a;\n\t}\n\tmint operator*(const mint a) const {\n\t\tmint res(*this);\n\t\treturn res *= a;\n\t}\n\tmint pow(ll t) const {\n\t\tif (!t) return 1;\n\t\tmint a = pow(t >> 1);\n\t\ta *= a;\n\t\tif (t & 1) a *= *this;\n\t\treturn a;\n\t}\n\n\t// for prime MOD\n\tmint inv() const {\n\t\treturn pow(MOD - 2);\n\t}\n\tmint& operator/=(const mint a) {\n\t\treturn (*this) *= a.inv();\n\t}\n\tmint operator/(const mint a) const {\n\t\tmint res(*this);\n\t\treturn res /= a;\n\t}\n\tfriend ostream& operator<<(ostream& os, const mint& m) {\n\t\tos << m.x;\n\t\treturn os;\n\t}\n};\nstruct combination {\n\tvector<mint> fact, ifact;\n\tcombination(int n) :fact(n + 1), ifact(n + 1) {\n\t\t//assert(n < MOD);\n\t\tfact[0] = 1;\n\t\tfor (int i = 1; i <= n; ++i) fact[i] = fact[i - 1] * i;\n\t\tifact[n] = fact[n].inv();\n\t\tfor (int i = n; i >= 1; --i) ifact[i - 1] = ifact[i] * i;\n\t}\n\tmint operator()(int n, int k) {\n\t\tif (k < 0 || k > n) return 0;\n\t\treturn fact[n] * ifact[k] * ifact[n - k];\n\t}\n}com(200010);\nstruct Sieve {\n\tint n;\n\tvector<int> f, primes;\n\t\n\tSieve(int n = 1) :n(n), f(n + 1) {\n\t\tf[0] = f[1] = -1;\n\t\tfor (ll i = 2; i <= n; ++i) {\n\t\t\tif (f[i]) continue;\n\t\t\tprimes.push_back(i);\n\t\t\tf[i] = i;\n\t\t\tfor (ll j = i * i; j <= n; j += i) {\n\t\t\t\tif (!f[j]) f[j] = i;\n\t\t\t}\n\t\t}\n\t}\n\t\n\tbool isPrime(int x) { return f[x] == x; }\n\t\n\tvector<int> factorList(int x) {\n\t\tvector<int> res;\n\t\twhile (x != 1) {\n\t\t\tres.push_back(f[x]);\n\t\t\tx /= f[x];\n\t\t}\n\t\treturn res;\n\t}\n\t\n\tvector<P> factor(int x) {\n\t\tvector<int> fl = factorList(x);\n\t\tif (fl.size() == 0) return {};\n\t\tvector<P> res(1, P(fl[0], 0));\n\t\tfor (int p : fl) {\n\t\t\tif (res.back().first == p) {\n\t\t\t\tres.back().second++;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tres.emplace_back(p, 1);\n\t\t\t}\n\t\t}\n\t\treturn res;\n\t}\n};\nclass UnionFind {\npublic:\n\tvector <ll> par; \n\tvector <ll> siz; \n\n\t// Constructor\n\tUnionFind(ll sz_) : par(sz_), siz(sz_, 1) {\n\t\tfor (ll i = 0; i < sz_; ++i) par[i] = i; \n\t}\n\tvoid init(ll sz_) {\n\t\tpar.resize(sz_);\n\t\tsiz.resize(sz_, 1);\n\t\tfor (ll i = 0; i < sz_; ++i) par[i] = i; \n\t}\n\n\t// Member Function\n\t// Find\n\tll root(ll x) { \n\t\twhile (par[x] != x) {\n\t\t\tx = par[x] = par[par[x]]; \n\t\t}\n\t\treturn x;\n\t}\n\n\t// Union(Unite, Merge)\n\tbool merge(ll x, ll y) {\n\t\tx = root(x);\n\t\ty = root(y);\n\t\tif (x == y) return false;\n\t\t\n\t\tif (siz[x] < siz[y]) swap(x, y);\n\t\tsiz[x] += siz[y];\n\t\tpar[y] = x;\n\t\treturn true;\n\t}\n\n\tbool issame(ll x, ll y) {\n\t\treturn root(x) == root(y);\n\t}\n\n\tll size(ll x) {\n\t\treturn siz[root(x)];\n\t}\n};\ntemplate<class t> t gcd(t a, t b) { return b != 0 ? gcd(b, a % b) : a; }\nll lcm(ll a, ll b) {\n\tll g = gcd(a, b);\n\treturn a * b / g;\n}\nbool prime(ll n) {\n\tfor (ll i = 2; i <= sqrt(n); i++) {\n\t\tif (n%i == 0)return false;\n\t}\n\treturn n != 1;\n}\nmap<ll, ll> prime_factor(ll n) {\n\tmap<ll, ll> ret;\n\tfor (ll i = 2; i * i <= n; i++) {\n\t\twhile (n % i == 0) {\n\t\t\tret[i]++;\n\t\t\tn /= i;\n\t\t}\n\t}\n\tif (n != 1) ret[n] = 1;\n\treturn ret;\n}\nll modinv(ll a, ll m) {\n\tll b = m, u = 1, v = 0;\n\twhile (b) {\n\t\tll t = a / b;\n\t\ta -= t * b; swap(a, b);\n\t\tu -= t * v; swap(u, v);\n\t}\n\tu %= m;\n\tif (u < 0) u += m;\n\treturn u;\n}\nvector<pair<char, int>> RunLength(string s) {\n\tif (s.size() == 0)return {};\n\tvector<pair<char, int>>res(1, pair<char, int>(s[0], 0));\n\tfor (char p : s) {\n\t\tif (res.back().first == p) {\n\t\t\tres.back().second++;\n\t\t}\n\t\telse {\n\t\t\tres.emplace_back(p, 1);\n\t\t}\n\t}\n\treturn res;\n}\n// Digit Count\nint GetDigit(int num) {\n\treturn log10(num) + 1;\n}\n// bit calculation[how many \"1\"] (= __builtin_popcount())\nint bit_count(int n) {\n\tint cnt = 0;\n\twhile (n > 0) {\n\t\tif (n % 2 == 1)cnt++;\n\t\tn /= 2;\n\t}\n\treturn cnt;\n}\nmint POW(mint n, int p) {\n\tif (p == 0)return 1;\n\tif (p % 2 == 0) {\n\t\tmint t = POW(n, p / 2);\n\t\treturn t * t;\n\t}\n\treturn n * POW(n, p - 1);\n}\n\n\nconst int dx[4] = { 1,0,-1,0 };\nconst int dy[4] = { 0,1,0,-1 };\n\nstruct edge { ll to, cost; };\ntypedef long double ld;\n\nsigned main() {\n\tios_base::sync_with_stdio(0);\n\tcin.tie(0);\n\tcout.tie(0);\n\t//cout << fixed << setprecision(15);\n\tint n, a, b; cin >> n >> a >> b;\n\tmint ans = POW(2,n);\n\tans -= 1;\n\tmint tmp = 1;\n\trep(i, a) {\n\t\ttmp *= n - i;\n\t\ttmp /= i + 1;\n\t}\n\tans -= tmp;\n\ttmp = 1;\n\trep(i, b) {\n\t\ttmp *= n - i; tmp /= i + 1;\n\t}\n\tans -= tmp;\n\tcout << ans << endl;\n\treturn 0;\n\n}", "language": "C++", "metadata": {"date": 1584889698, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02768.html", "problem_id": "p02768", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02768/input.txt", "sample_output_relpath": "derived/input_output/data/p02768/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02768/C++/s312312066.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s312312066", "user_id": "u809967037"}, "prompt_components": {"gold_output": "7\n", "input_to_evaluate": "#include <iostream>\n#include <cstdio>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <functional>\n#include <iomanip>\n#include <stdlib.h>\n#include <string.h>\n#include <cstring>\n#include <cmath>\n#include <map>\n#include <queue>\n#include <deque>\n#include <stack>\n#include <set>\n#include <stdio.h>\n#include <tuple>\n#include <bitset>\n#include <cfloat>\n#include <fstream>\n#include <limits.h>\n#include <list>\n#include <math.h>\n#include <random>\n#include <unordered_map>\n#include <unordered_set>\n#include <bitset>\n#include <numeric>\n#include <utility>\n#include <sstream>\n#include <cassert>\ntemplate<class T> inline bool chmin(T& a, T b) {\n\tif (a > b) {\n\t\ta = b;\n\t\treturn true;\n\t}\n\treturn false;\n}\ntemplate<class T> inline bool chmax(T& a, T b) {\n\tif (a < b) {\n\t\ta = b;\n\t\treturn true;\n\t}\n\treturn false;\n}\nusing namespace std;\n#define int long long\n#define ll long long\n#define rep(i, n) for (ll i = 0; i < (n); i++)\n#define P pair<ll, ll>\n#define sz(x) (ll)x.size()\n#define ALL(x) (x).begin(),(x).end()\n#define ALLR(x) (x).rbegin(),(x).rend()\n#define VE vector<ll>\n#define COUT(x) cout<<(x)<<endl\n#define MA map<ll,ll>\n#define SE set<ll>\n#define PQ priority_queue<ll>\n#define PQR priority_queue<ll,VE,greater<ll>>\n#define YES(n) cout << ((n) ? \"YES\" : \"NO\"  ) << endl\n#define Yes(n) cout << ((n) ? \"Yes\" : \"No\"  ) << endl\n#define EPS (1e-14)\n#define pb push_back\nlong long MOD = 1000000007;\n//const long long MOD = 998244353;\nconst long long INF = 1LL << 60;\nconst double PI = acos(-1.0);\nusing Graph = vector<VE>;\nstruct mint {\n\tll x; // typedef long long ll;\n\tmint(ll x = 0) :x((x%MOD + MOD) % MOD) {}\n\tmint operator-() const { return mint(-x); }\n\tmint& operator+=(const mint a) {\n\t\tif ((x += a.x) >= MOD) x -= MOD;\n\t\treturn *this;\n\t}\n\tmint& operator-=(const mint a) {\n\t\tif ((x += MOD - a.x) >= MOD) x -= MOD;\n\t\treturn *this;\n\t}\n\tmint& operator*=(const mint a) {\n\t\t(x *= a.x) %= MOD;\n\t\treturn *this;\n\t}\n\tmint operator+(const mint a) const {\n\t\tmint res(*this);\n\t\treturn res += a;\n\t}\n\tmint operator-(const mint a) const {\n\t\tmint res(*this);\n\t\treturn res -= a;\n\t}\n\tmint operator*(const mint a) const {\n\t\tmint res(*this);\n\t\treturn res *= a;\n\t}\n\tmint pow(ll t) const {\n\t\tif (!t) return 1;\n\t\tmint a = pow(t >> 1);\n\t\ta *= a;\n\t\tif (t & 1) a *= *this;\n\t\treturn a;\n\t}\n\n\t// for prime MOD\n\tmint inv() const {\n\t\treturn pow(MOD - 2);\n\t}\n\tmint& operator/=(const mint a) {\n\t\treturn (*this) *= a.inv();\n\t}\n\tmint operator/(const mint a) const {\n\t\tmint res(*this);\n\t\treturn res /= a;\n\t}\n\tfriend ostream& operator<<(ostream& os, const mint& m) {\n\t\tos << m.x;\n\t\treturn os;\n\t}\n};\nstruct combination {\n\tvector<mint> fact, ifact;\n\tcombination(int n) :fact(n + 1), ifact(n + 1) {\n\t\t//assert(n < MOD);\n\t\tfact[0] = 1;\n\t\tfor (int i = 1; i <= n; ++i) fact[i] = fact[i - 1] * i;\n\t\tifact[n] = fact[n].inv();\n\t\tfor (int i = n; i >= 1; --i) ifact[i - 1] = ifact[i] * i;\n\t}\n\tmint operator()(int n, int k) {\n\t\tif (k < 0 || k > n) return 0;\n\t\treturn fact[n] * ifact[k] * ifact[n - k];\n\t}\n}com(200010);\nstruct Sieve {\n\tint n;\n\tvector<int> f, primes;\n\t\n\tSieve(int n = 1) :n(n), f(n + 1) {\n\t\tf[0] = f[1] = -1;\n\t\tfor (ll i = 2; i <= n; ++i) {\n\t\t\tif (f[i]) continue;\n\t\t\tprimes.push_back(i);\n\t\t\tf[i] = i;\n\t\t\tfor (ll j = i * i; j <= n; j += i) {\n\t\t\t\tif (!f[j]) f[j] = i;\n\t\t\t}\n\t\t}\n\t}\n\t\n\tbool isPrime(int x) { return f[x] == x; }\n\t\n\tvector<int> factorList(int x) {\n\t\tvector<int> res;\n\t\twhile (x != 1) {\n\t\t\tres.push_back(f[x]);\n\t\t\tx /= f[x];\n\t\t}\n\t\treturn res;\n\t}\n\t\n\tvector<P> factor(int x) {\n\t\tvector<int> fl = factorList(x);\n\t\tif (fl.size() == 0) return {};\n\t\tvector<P> res(1, P(fl[0], 0));\n\t\tfor (int p : fl) {\n\t\t\tif (res.back().first == p) {\n\t\t\t\tres.back().second++;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tres.emplace_back(p, 1);\n\t\t\t}\n\t\t}\n\t\treturn res;\n\t}\n};\nclass UnionFind {\npublic:\n\tvector <ll> par; \n\tvector <ll> siz; \n\n\t// Constructor\n\tUnionFind(ll sz_) : par(sz_), siz(sz_, 1) {\n\t\tfor (ll i = 0; i < sz_; ++i) par[i] = i; \n\t}\n\tvoid init(ll sz_) {\n\t\tpar.resize(sz_);\n\t\tsiz.resize(sz_, 1);\n\t\tfor (ll i = 0; i < sz_; ++i) par[i] = i; \n\t}\n\n\t// Member Function\n\t// Find\n\tll root(ll x) { \n\t\twhile (par[x] != x) {\n\t\t\tx = par[x] = par[par[x]]; \n\t\t}\n\t\treturn x;\n\t}\n\n\t// Union(Unite, Merge)\n\tbool merge(ll x, ll y) {\n\t\tx = root(x);\n\t\ty = root(y);\n\t\tif (x == y) return false;\n\t\t\n\t\tif (siz[x] < siz[y]) swap(x, y);\n\t\tsiz[x] += siz[y];\n\t\tpar[y] = x;\n\t\treturn true;\n\t}\n\n\tbool issame(ll x, ll y) {\n\t\treturn root(x) == root(y);\n\t}\n\n\tll size(ll x) {\n\t\treturn siz[root(x)];\n\t}\n};\ntemplate<class t> t gcd(t a, t b) { return b != 0 ? gcd(b, a % b) : a; }\nll lcm(ll a, ll b) {\n\tll g = gcd(a, b);\n\treturn a * b / g;\n}\nbool prime(ll n) {\n\tfor (ll i = 2; i <= sqrt(n); i++) {\n\t\tif (n%i == 0)return false;\n\t}\n\treturn n != 1;\n}\nmap<ll, ll> prime_factor(ll n) {\n\tmap<ll, ll> ret;\n\tfor (ll i = 2; i * i <= n; i++) {\n\t\twhile (n % i == 0) {\n\t\t\tret[i]++;\n\t\t\tn /= i;\n\t\t}\n\t}\n\tif (n != 1) ret[n] = 1;\n\treturn ret;\n}\nll modinv(ll a, ll m) {\n\tll b = m, u = 1, v = 0;\n\twhile (b) {\n\t\tll t = a / b;\n\t\ta -= t * b; swap(a, b);\n\t\tu -= t * v; swap(u, v);\n\t}\n\tu %= m;\n\tif (u < 0) u += m;\n\treturn u;\n}\nvector<pair<char, int>> RunLength(string s) {\n\tif (s.size() == 0)return {};\n\tvector<pair<char, int>>res(1, pair<char, int>(s[0], 0));\n\tfor (char p : s) {\n\t\tif (res.back().first == p) {\n\t\t\tres.back().second++;\n\t\t}\n\t\telse {\n\t\t\tres.emplace_back(p, 1);\n\t\t}\n\t}\n\treturn res;\n}\n// Digit Count\nint GetDigit(int num) {\n\treturn log10(num) + 1;\n}\n// bit calculation[how many \"1\"] (= __builtin_popcount())\nint bit_count(int n) {\n\tint cnt = 0;\n\twhile (n > 0) {\n\t\tif (n % 2 == 1)cnt++;\n\t\tn /= 2;\n\t}\n\treturn cnt;\n}\nmint POW(mint n, int p) {\n\tif (p == 0)return 1;\n\tif (p % 2 == 0) {\n\t\tmint t = POW(n, p / 2);\n\t\treturn t * t;\n\t}\n\treturn n * POW(n, p - 1);\n}\n\n\nconst int dx[4] = { 1,0,-1,0 };\nconst int dy[4] = { 0,1,0,-1 };\n\nstruct edge { ll to, cost; };\ntypedef long double ld;\n\nsigned main() {\n\tios_base::sync_with_stdio(0);\n\tcin.tie(0);\n\tcout.tie(0);\n\t//cout << fixed << setprecision(15);\n\tint n, a, b; cin >> n >> a >> b;\n\tmint ans = POW(2,n);\n\tans -= 1;\n\tmint tmp = 1;\n\trep(i, a) {\n\t\ttmp *= n - i;\n\t\ttmp /= i + 1;\n\t}\n\tans -= tmp;\n\ttmp = 1;\n\trep(i, b) {\n\t\ttmp *= n - i; tmp /= i + 1;\n\t}\n\tans -= tmp;\n\tcout << ans << endl;\n\treturn 0;\n\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nAkari has n kinds of flowers, one of each kind.\n\nShe is going to choose one or more of these flowers to make a bouquet.\n\nHowever, she hates two numbers a and b, so the number of flowers in the bouquet cannot be a or b.\n\nHow many different bouquets are there that Akari can make?\n\nFind the count modulo (10^9 + 7).\n\nHere, two bouquets are considered different when there is a flower that is used in one of the bouquets but not in the other bouquet.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq n \\leq 10^9\n\n1 \\leq a < b \\leq \\textrm{min}(n, 2 \\times 10^5)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn a b\n\nOutput\n\nPrint the number of bouquets that Akari can make, modulo (10^9 + 7). (If there are no such bouquets, print 0.)\n\nSample Input 1\n\n4 1 3\n\nSample Output 1\n\n7\n\nIn this case, Akari can choose 2 or 4 flowers to make the bouquet.\n\nThere are 6 ways to choose 2 out of the 4 flowers, and 1 way to choose 4, so there are a total of 7 different bouquets that Akari can make.\n\nSample Input 2\n\n1000000000 141421 173205\n\nSample Output 2\n\n34076506\n\nPrint the count modulo (10^9 + 7).", "sample_input": "4 1 3\n"}, "reference_outputs": ["7\n"], "source_document_id": "p02768", "source_text": "Score : 400 points\n\nProblem Statement\n\nAkari has n kinds of flowers, one of each kind.\n\nShe is going to choose one or more of these flowers to make a bouquet.\n\nHowever, she hates two numbers a and b, so the number of flowers in the bouquet cannot be a or b.\n\nHow many different bouquets are there that Akari can make?\n\nFind the count modulo (10^9 + 7).\n\nHere, two bouquets are considered different when there is a flower that is used in one of the bouquets but not in the other bouquet.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq n \\leq 10^9\n\n1 \\leq a < b \\leq \\textrm{min}(n, 2 \\times 10^5)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn a b\n\nOutput\n\nPrint the number of bouquets that Akari can make, modulo (10^9 + 7). (If there are no such bouquets, print 0.)\n\nSample Input 1\n\n4 1 3\n\nSample Output 1\n\n7\n\nIn this case, Akari can choose 2 or 4 flowers to make the bouquet.\n\nThere are 6 ways to choose 2 out of the 4 flowers, and 1 way to choose 4, so there are a total of 7 different bouquets that Akari can make.\n\nSample Input 2\n\n1000000000 141421 173205\n\nSample Output 2\n\n34076506\n\nPrint the count modulo (10^9 + 7).", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 6133, "cpu_time_ms": 332, "memory_kb": 3328}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s100130684", "group_id": "codeNet:p02768", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint kaizyou(int x,int y);\nint main(){\n    int N=0;\n    int a=0;\n    int b=0;\n    int result=0;\n    cin >> N >> a >> b;\n   for(int i=1;i<=N;i++){\n       if((i==a)||(i==b)){\n           continue;\n       }else{\n           result+=kaizyou(N,i)/kaizyou(i,i);\n       }\n   }\n   cout << result << endl;\n}\nint kaizyou(int x,int y){\n    int point=x;\n    int result=1;\n    for(int i=1;i<point+1;i++){\n        result*=x;\n        x--;\n        if (i==y){\n            break;\n        }\n    }\n    return result;\n}\n\n", "language": "C++", "metadata": {"date": 1582954021, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02768.html", "problem_id": "p02768", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02768/input.txt", "sample_output_relpath": "derived/input_output/data/p02768/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02768/C++/s100130684.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s100130684", "user_id": "u529973556"}, "prompt_components": {"gold_output": "7\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint kaizyou(int x,int y);\nint main(){\n    int N=0;\n    int a=0;\n    int b=0;\n    int result=0;\n    cin >> N >> a >> b;\n   for(int i=1;i<=N;i++){\n       if((i==a)||(i==b)){\n           continue;\n       }else{\n           result+=kaizyou(N,i)/kaizyou(i,i);\n       }\n   }\n   cout << result << endl;\n}\nint kaizyou(int x,int y){\n    int point=x;\n    int result=1;\n    for(int i=1;i<point+1;i++){\n        result*=x;\n        x--;\n        if (i==y){\n            break;\n        }\n    }\n    return result;\n}\n\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nAkari has n kinds of flowers, one of each kind.\n\nShe is going to choose one or more of these flowers to make a bouquet.\n\nHowever, she hates two numbers a and b, so the number of flowers in the bouquet cannot be a or b.\n\nHow many different bouquets are there that Akari can make?\n\nFind the count modulo (10^9 + 7).\n\nHere, two bouquets are considered different when there is a flower that is used in one of the bouquets but not in the other bouquet.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq n \\leq 10^9\n\n1 \\leq a < b \\leq \\textrm{min}(n, 2 \\times 10^5)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn a b\n\nOutput\n\nPrint the number of bouquets that Akari can make, modulo (10^9 + 7). (If there are no such bouquets, print 0.)\n\nSample Input 1\n\n4 1 3\n\nSample Output 1\n\n7\n\nIn this case, Akari can choose 2 or 4 flowers to make the bouquet.\n\nThere are 6 ways to choose 2 out of the 4 flowers, and 1 way to choose 4, so there are a total of 7 different bouquets that Akari can make.\n\nSample Input 2\n\n1000000000 141421 173205\n\nSample Output 2\n\n34076506\n\nPrint the count modulo (10^9 + 7).", "sample_input": "4 1 3\n"}, "reference_outputs": ["7\n"], "source_document_id": "p02768", "source_text": "Score : 400 points\n\nProblem Statement\n\nAkari has n kinds of flowers, one of each kind.\n\nShe is going to choose one or more of these flowers to make a bouquet.\n\nHowever, she hates two numbers a and b, so the number of flowers in the bouquet cannot be a or b.\n\nHow many different bouquets are there that Akari can make?\n\nFind the count modulo (10^9 + 7).\n\nHere, two bouquets are considered different when there is a flower that is used in one of the bouquets but not in the other bouquet.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq n \\leq 10^9\n\n1 \\leq a < b \\leq \\textrm{min}(n, 2 \\times 10^5)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn a b\n\nOutput\n\nPrint the number of bouquets that Akari can make, modulo (10^9 + 7). (If there are no such bouquets, print 0.)\n\nSample Input 1\n\n4 1 3\n\nSample Output 1\n\n7\n\nIn this case, Akari can choose 2 or 4 flowers to make the bouquet.\n\nThere are 6 ways to choose 2 out of the 4 flowers, and 1 way to choose 4, so there are a total of 7 different bouquets that Akari can make.\n\nSample Input 2\n\n1000000000 141421 173205\n\nSample Output 2\n\n34076506\n\nPrint the count modulo (10^9 + 7).", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 544, "cpu_time_ms": 99, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s054791758", "group_id": "codeNet:p02768", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i,n) for(int i=0;i<n;i++)\n#define mfill(x,y) memset(x,y,sizeof(x))\n#define all(v) v.begin(), v.end()\n#define in(x,y,h,w) if(0<=x&&x<h&&0<=y&&y<w)\n#define y0 y12345\n#define y1 y54321\n\n#ifdef LOCAL\n#define debug(...) fprintf(stderr,__VA_ARGS__)\n#else\n#define debug(...) 42\n#endif\n\nusing ul = unsigned long;\nusing ll = long long;\nusing P = pair<int, int>;\nusing vint = vector<int>;using vvint = vector<vector<int>>;\nusing vll = vector<ll>;using vvll = vector<vector<ll>>;\ntemplate<class T>bool chmax(T &a, const T &b){if(a<b){a=b;return 1;}return 0;}\ntemplate<class T>bool chmin(T &a, const T &b){if(a>b){a=b;return 1;}return 0;}\ntemplate <class T>void initvv(vector<vector<T> > &v, int a, int b, const T &t = T()){\n    v.assign(a, vector<T>(b, t));\n}\ntemplate <class T>T gcd(T &a, T &b){if(a<b){swap(a,b);} T r = a%b; while(r!=0){a=b;b=r;r=a%b;} return b;}\n\nvint dx = {-1, 0, 1, 0}, dy = {0, -1, 0, 1};\nvint dx8 = {-1, -1, -1, 0, 1, 1, 1, 0}, dy8 = {-1, 0, 1, 1, 1, 0, -1, -1};\nll mod = 1000000007;\nll pow2(ll x, ll p){\n    if(p == 0){return 1;}\n    ll ret = pow2(x, p/2);\n    return ((ret*ret%mod)*(p%2==1?x:1))%mod;\n}\n\nint main() {\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n    debug(\"debug test\\n\");\n    ll n, a, b;cin>>n>>a>>b;\n    ll base = pow2(2, n) - 1;\n    \n    ll par = 1;\n    ll chil = 1;\n    for(int i = n;i>n-min(a, n-a);i--){\n        //if(i<=n+1-i)break;\n        par = par*i%mod;\n        chil = chil*(n+1-i)%mod;\n    }\n    ll minusa = par*pow2(chil, mod-2) % mod;\n    par = 1;\n    chil = 1;\n    for(int i = n;i>n-min(b, n-b);i--){\n        //if(i<=n+1-i)break;\n        par = par*i%mod;\n        chil = chil*(n+1-i)%mod;\n    }\n    ll minusb = par*pow2(chil, mod-2) % mod;\n    debug(\"nf %d\\n\", base);\n    cout << (base - minusa - minusb + mod) % mod << endl;\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1582463219, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02768.html", "problem_id": "p02768", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02768/input.txt", "sample_output_relpath": "derived/input_output/data/p02768/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02768/C++/s054791758.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s054791758", "user_id": "u398437835"}, "prompt_components": {"gold_output": "7\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i,n) for(int i=0;i<n;i++)\n#define mfill(x,y) memset(x,y,sizeof(x))\n#define all(v) v.begin(), v.end()\n#define in(x,y,h,w) if(0<=x&&x<h&&0<=y&&y<w)\n#define y0 y12345\n#define y1 y54321\n\n#ifdef LOCAL\n#define debug(...) fprintf(stderr,__VA_ARGS__)\n#else\n#define debug(...) 42\n#endif\n\nusing ul = unsigned long;\nusing ll = long long;\nusing P = pair<int, int>;\nusing vint = vector<int>;using vvint = vector<vector<int>>;\nusing vll = vector<ll>;using vvll = vector<vector<ll>>;\ntemplate<class T>bool chmax(T &a, const T &b){if(a<b){a=b;return 1;}return 0;}\ntemplate<class T>bool chmin(T &a, const T &b){if(a>b){a=b;return 1;}return 0;}\ntemplate <class T>void initvv(vector<vector<T> > &v, int a, int b, const T &t = T()){\n    v.assign(a, vector<T>(b, t));\n}\ntemplate <class T>T gcd(T &a, T &b){if(a<b){swap(a,b);} T r = a%b; while(r!=0){a=b;b=r;r=a%b;} return b;}\n\nvint dx = {-1, 0, 1, 0}, dy = {0, -1, 0, 1};\nvint dx8 = {-1, -1, -1, 0, 1, 1, 1, 0}, dy8 = {-1, 0, 1, 1, 1, 0, -1, -1};\nll mod = 1000000007;\nll pow2(ll x, ll p){\n    if(p == 0){return 1;}\n    ll ret = pow2(x, p/2);\n    return ((ret*ret%mod)*(p%2==1?x:1))%mod;\n}\n\nint main() {\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n    debug(\"debug test\\n\");\n    ll n, a, b;cin>>n>>a>>b;\n    ll base = pow2(2, n) - 1;\n    \n    ll par = 1;\n    ll chil = 1;\n    for(int i = n;i>n-min(a, n-a);i--){\n        //if(i<=n+1-i)break;\n        par = par*i%mod;\n        chil = chil*(n+1-i)%mod;\n    }\n    ll minusa = par*pow2(chil, mod-2) % mod;\n    par = 1;\n    chil = 1;\n    for(int i = n;i>n-min(b, n-b);i--){\n        //if(i<=n+1-i)break;\n        par = par*i%mod;\n        chil = chil*(n+1-i)%mod;\n    }\n    ll minusb = par*pow2(chil, mod-2) % mod;\n    debug(\"nf %d\\n\", base);\n    cout << (base - minusa - minusb + mod) % mod << endl;\n    return 0;\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nAkari has n kinds of flowers, one of each kind.\n\nShe is going to choose one or more of these flowers to make a bouquet.\n\nHowever, she hates two numbers a and b, so the number of flowers in the bouquet cannot be a or b.\n\nHow many different bouquets are there that Akari can make?\n\nFind the count modulo (10^9 + 7).\n\nHere, two bouquets are considered different when there is a flower that is used in one of the bouquets but not in the other bouquet.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq n \\leq 10^9\n\n1 \\leq a < b \\leq \\textrm{min}(n, 2 \\times 10^5)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn a b\n\nOutput\n\nPrint the number of bouquets that Akari can make, modulo (10^9 + 7). (If there are no such bouquets, print 0.)\n\nSample Input 1\n\n4 1 3\n\nSample Output 1\n\n7\n\nIn this case, Akari can choose 2 or 4 flowers to make the bouquet.\n\nThere are 6 ways to choose 2 out of the 4 flowers, and 1 way to choose 4, so there are a total of 7 different bouquets that Akari can make.\n\nSample Input 2\n\n1000000000 141421 173205\n\nSample Output 2\n\n34076506\n\nPrint the count modulo (10^9 + 7).", "sample_input": "4 1 3\n"}, "reference_outputs": ["7\n"], "source_document_id": "p02768", "source_text": "Score : 400 points\n\nProblem Statement\n\nAkari has n kinds of flowers, one of each kind.\n\nShe is going to choose one or more of these flowers to make a bouquet.\n\nHowever, she hates two numbers a and b, so the number of flowers in the bouquet cannot be a or b.\n\nHow many different bouquets are there that Akari can make?\n\nFind the count modulo (10^9 + 7).\n\nHere, two bouquets are considered different when there is a flower that is used in one of the bouquets but not in the other bouquet.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq n \\leq 10^9\n\n1 \\leq a < b \\leq \\textrm{min}(n, 2 \\times 10^5)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn a b\n\nOutput\n\nPrint the number of bouquets that Akari can make, modulo (10^9 + 7). (If there are no such bouquets, print 0.)\n\nSample Input 1\n\n4 1 3\n\nSample Output 1\n\n7\n\nIn this case, Akari can choose 2 or 4 flowers to make the bouquet.\n\nThere are 6 ways to choose 2 out of the 4 flowers, and 1 way to choose 4, so there are a total of 7 different bouquets that Akari can make.\n\nSample Input 2\n\n1000000000 141421 173205\n\nSample Output 2\n\n34076506\n\nPrint the count modulo (10^9 + 7).", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1848, "cpu_time_ms": 9, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s804868368", "group_id": "codeNet:p02769", "input_text": "// warm heart, wagging tail,and a smile just for you!\n//                                                                     ██���████████\n//                                                                   ███╬╬╬╬╬╬╬╬╬╬███\n//                                                                ███╬╬╬╬╬████╬╬╬╬╬╬███\n//                                            ███████████       ██╬╬╬╬╬████╬╬████╬╬╬╬╬██\n//                                      █████████╬╬╬╬╬████████████╬╬╬╬╬██╬╬╬╬╬╬███╬╬╬╬╬██\n//                               ████████╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬█████████╬╬╬╬╬╬██╬╬╬╬╬╬╬██\n//                             ████╬██╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬█████████╬╬╬╬╬╬╬╬╬╬╬██\n//                           ███╬╬╬█╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬██╬╬███╬╬╬╬╬╬╬█████\n//                         ███╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬██╬╬╬████████╬╬╬╬╬██\n//                       ███╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬███╬╬╬╬╬╬╬╬╬███\n//                     ███╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬█████╬╬╬╬╬╬╬██\n//                 ████╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬████╬╬╬╬╬████\n//     █████████████╬╬╬╬╬╬╬╬██╬╬╬╬╬████╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬█████╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬███╬╬╬╬██████\n//   ████╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬██╬╬██████╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬██████╬╬╬╬╬╬╬███████████╬╬╬╬╬╬╬╬██╬╬╬██╬╬╬██\n// ███╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬██╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬██╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬████╬╬╬╬╬╬╬╬╬╬╬█╬╬╬╬╬╬╬██╬╬╬╬╬╬╬╬██\n// ██╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬██╬╬╬╬▓▓▓▓▓▓╬╬╬████╬╬████╬╬╬╬╬╬╬▓▓▓▓▓▓▓▓██╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬██╬╬╬╬╬╬╬███\n// ██╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬██████▓▓▓▓▓▓▓╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬▓▓▓▓▓▓▓██╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬██╬╬╬╬█████\n// ███╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬███╬╬╬╬╬██╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬█████╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬████████\n//   ███╬╬╬╬╬╬╬╬╬╬╬╬╬█████╬╬╬╬╬╬╬╬██╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬███╬╬██╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬██\n//       ██████████████  ████╬╬╬╬╬╬███████████████████████████╬╬╬╬╬██╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬████\n//                         ███████                           █████  ███████████████████  \n//\n#include \"bits/stdc++.h\"\nusing namespace std;\n#define INF (1LL<<60)\n#define fs first\n#define sc second\n#define int long long\n#define FOR(i,a,b) for(int i=(a);i<(b);++i)\n#define RFOR(i,a,b) for(int i = (b-1);i>=(a);--i)\n#define REP(i,n)  FOR(i,0,(n))\n#define RREP(i,n) RFOR(i,0,(n))\n#define ITR(itr,mp) for(auto itr = (mp).begin(); itr != (mp).end(); ++itr)\n#define RITR(itr,mp) for(auto itr = (mp).rbegin(); itr != (mp).rend(); ++itr)\n#define range(i,a,b) ((a)<=(i) && (i)<(b))\n#define debug(x)  cout << #x << \" = \" << (x) << endl\n#define SP << \" \" << \ntemplate<typename T1,typename T2> inline void chmin(T1 &a,T2 b){if(a>b) a=b;}\ntemplate<typename T1,typename T2> inline void chmax(T1 &a,T2 b){if(a<b) a=b;}\n#define MSB(x) (63-__builtin_clzll(x))\n#define pcnt(x) (__builtin_popcountll(x))\n#define parity(i,j) (i&(1LL<<j))\ntypedef pair<int,int> P;\ntypedef tuple<int,int,int> T;\n\nvector<int> MODS = { 1000000007, 998244353 }; // 実行時に決まる\ntemplate<int IND = 0> struct Fp {\n    long long val;\n    \n    int MOD = MODS[IND];\n    constexpr Fp(long long v = 0) noexcept : val(v % MODS[IND]) {\n        if (val < 0) val += MOD;\n    }\n    constexpr int getmod() { return MOD; }\n    constexpr Fp operator - () const noexcept {\n        return val ? MOD - val : 0;\n    }\n    constexpr Fp operator + (const Fp& r) const noexcept { return Fp(*this) += r; }\n    constexpr Fp operator - (const Fp& r) const noexcept { return Fp(*this) -= r; }\n    constexpr Fp operator * (const Fp& r) const noexcept { return Fp(*this) *= r; }\n    constexpr Fp operator / (const Fp& r) const noexcept { return Fp(*this) /= r; }\n    constexpr Fp& operator += (const Fp& r) noexcept {\n        val += r.val;\n        if (val >= MOD) val -= MOD;\n        return *this;\n    }\n    constexpr Fp& operator -= (const Fp& r) noexcept {\n        val -= r.val;\n        if (val < 0) val += MOD;\n        return *this;\n    }\n    constexpr Fp& operator *= (const Fp& r) noexcept {\n        val = val * r.val % MOD;\n        return *this;\n    }\n    constexpr Fp& operator /= (const Fp& r) noexcept {\n        long long a = r.val, b = MOD, u = 1, v = 0;\n        while (b) {\n            long long t = a / b;\n            a -= t * b; swap(a, b);\n            u -= t * v; swap(u, v);\n        }\n        val = val * u % MOD;\n        if (val < 0) val += MOD;\n        return *this;\n    }\n    constexpr bool operator == (const Fp& r) const noexcept {\n        return this->val == r.val;\n    }\n    constexpr bool operator != (const Fp& r) const noexcept {\n        return this->val != r.val;\n    }\n    friend constexpr ostream& operator << (ostream &os, const Fp<IND>& x) noexcept {\n        return os << x.val;\n    }\n    friend constexpr istream& operator >> (istream &is, Fp<IND>& x) noexcept {\n        return is >> x.val;\n    }\n    friend constexpr Fp<IND> modpow(const Fp<IND> &a, long long n) noexcept {\n        if (n == 0) return 1;\n        auto t = modpow(a, n / 2);\n        t = t * t;\n        if (n & 1) t = t * a;\n        return t;\n    }\n};\nusing mint = Fp<0>; // MODを変える場合は値を変更\ntypedef vector<mint> vec;\ntypedef vector<vector<mint>> mat;\n\nsigned main(){\n  ios::sync_with_stdio(false);\n  cin.tie(0);\n\n  int n,k;\n  cin >> n >> k;\n\n  vec fact(n+10,1),inv(n+10,1);\n  REP(i,n+5) fact[i+1] = fact[i]*(i+1), inv[i+1] /= fact[i+1];\n\n  chmin(k,n-1);\n  mint ans = 0;\n  REP(i,k+1){\n    mint c = fact[n]*inv[i]*inv[n-i];\n    ans += c*fact[n-1]*inv[i]*inv[n-1-i];\n    // debug(ans);\n  }\n\n  cout << ans << endl;\n\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1582407101, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02769.html", "problem_id": "p02769", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02769/input.txt", "sample_output_relpath": "derived/input_output/data/p02769/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02769/C++/s804868368.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s804868368", "user_id": "u239493918"}, "prompt_components": {"gold_output": "10\n", "input_to_evaluate": "// warm heart, wagging tail,and a smile just for you!\n//                                                                     ███████████\n//                                                                   ███╬╬╬╬╬╬╬╬╬╬███\n//                                                                ███╬╬╬╬╬████╬╬╬╬╬╬███\n//                                            ███████████       ██╬╬╬╬╬████╬╬████╬╬╬╬╬██\n//                                      █████████╬╬╬╬╬████████████╬╬╬╬╬██╬╬╬╬╬╬███╬╬╬╬╬██\n//                               ████████╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬█████████╬╬╬╬╬╬██╬╬╬╬╬╬╬██\n//                             ████╬██╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬█████████╬╬╬╬╬╬╬╬╬╬╬██\n//                           ���██╬╬╬█╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬██╬╬███╬╬╬╬╬╬╬█████\n//                         ███╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬██╬╬╬████████╬╬╬╬╬██\n//                       ███╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬███╬╬╬╬╬╬╬╬╬███\n//                     ███╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬█████╬╬╬╬╬╬╬██\n//                 ████╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬████╬╬╬╬╬████\n//     █████████████╬╬╬╬╬╬╬╬██╬╬╬╬╬████╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬█████╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬███╬╬╬╬██████\n//   ████╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬██╬╬██████╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬██████╬╬╬╬╬╬╬███████████╬╬╬╬╬╬╬╬██╬╬╬██╬╬╬██\n// ███╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬██╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬██╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬████╬╬╬╬╬╬╬╬╬╬╬█╬╬╬╬╬╬╬██╬╬╬╬╬╬╬╬██\n// ██╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬██╬╬╬╬▓▓▓▓▓▓╬╬╬████╬╬████╬╬╬╬╬╬╬▓▓▓▓▓▓▓▓██╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬██╬╬╬╬╬╬╬███\n// ██╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬██████▓▓▓▓▓▓▓╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬▓▓▓▓▓▓▓██╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬██╬╬╬╬█████\n// ███╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬███╬╬╬╬╬██╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬█████╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬████████\n//   ███╬╬╬╬╬╬╬╬╬╬╬╬╬█████╬╬╬╬╬╬╬╬██╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬███╬╬██╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬██\n//       ██████████████  ████╬╬╬╬╬╬███████████████████████████╬╬╬╬╬██╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬╬████\n//                         ███████                           █████  ███████████████████  \n//\n#include \"bits/stdc++.h\"\nusing namespace std;\n#define INF (1LL<<60)\n#define fs first\n#define sc second\n#define int long long\n#define FOR(i,a,b) for(int i=(a);i<(b);++i)\n#define RFOR(i,a,b) for(int i = (b-1);i>=(a);--i)\n#define REP(i,n)  FOR(i,0,(n))\n#define RREP(i,n) RFOR(i,0,(n))\n#define ITR(itr,mp) for(auto itr = (mp).begin(); itr != (mp).end(); ++itr)\n#define RITR(itr,mp) for(auto itr = (mp).rbegin(); itr != (mp).rend(); ++itr)\n#define range(i,a,b) ((a)<=(i) && (i)<(b))\n#define debug(x)  cout << #x << \" = \" << (x) << endl\n#define SP << \" \" << \ntemplate<typename T1,typename T2> inline void chmin(T1 &a,T2 b){if(a>b) a=b;}\ntemplate<typename T1,typename T2> inline void chmax(T1 &a,T2 b){if(a<b) a=b;}\n#define MSB(x) (63-__builtin_clzll(x))\n#define pcnt(x) (__builtin_popcountll(x))\n#define parity(i,j) (i&(1LL<<j))\ntypedef pair<int,int> P;\ntypedef tuple<int,int,int> T;\n\nvector<int> MODS = { 1000000007, 998244353 }; // 実行時に決まる\ntemplate<int IND = 0> struct Fp {\n    long long val;\n    \n    int MOD = MODS[IND];\n    constexpr Fp(long long v = 0) noexcept : val(v % MODS[IND]) {\n        if (val < 0) val += MOD;\n    }\n    constexpr int getmod() { return MOD; }\n    constexpr Fp operator - () const noexcept {\n        return val ? MOD - val : 0;\n    }\n    constexpr Fp operator + (const Fp& r) const noexcept { return Fp(*this) += r; }\n    constexpr Fp operator - (const Fp& r) const noexcept { return Fp(*this) -= r; }\n    constexpr Fp operator * (const Fp& r) const noexcept { return Fp(*this) *= r; }\n    constexpr Fp operator / (const Fp& r) const noexcept { return Fp(*this) /= r; }\n    constexpr Fp& operator += (const Fp& r) noexcept {\n        val += r.val;\n        if (val >= MOD) val -= MOD;\n        return *this;\n    }\n    constexpr Fp& operator -= (const Fp& r) noexcept {\n        val -= r.val;\n        if (val < 0) val += MOD;\n        return *this;\n    }\n    constexpr Fp& operator *= (const Fp& r) noexcept {\n        val = val * r.val % MOD;\n        return *this;\n    }\n    constexpr Fp& operator /= (const Fp& r) noexcept {\n        long long a = r.val, b = MOD, u = 1, v = 0;\n        while (b) {\n            long long t = a / b;\n            a -= t * b; swap(a, b);\n            u -= t * v; swap(u, v);\n        }\n        val = val * u % MOD;\n        if (val < 0) val += MOD;\n        return *this;\n    }\n    constexpr bool operator == (const Fp& r) const noexcept {\n        return this->val == r.val;\n    }\n    constexpr bool operator != (const Fp& r) const noexcept {\n        return this->val != r.val;\n    }\n    friend constexpr ostream& operator << (ostream &os, const Fp<IND>& x) noexcept {\n        return os << x.val;\n    }\n    friend constexpr istream& operator >> (istream &is, Fp<IND>& x) noexcept {\n        return is >> x.val;\n    }\n    friend constexpr Fp<IND> modpow(const Fp<IND> &a, long long n) noexcept {\n        if (n == 0) return 1;\n        auto t = modpow(a, n / 2);\n        t = t * t;\n        if (n & 1) t = t * a;\n        return t;\n    }\n};\nusing mint = Fp<0>; // MODを変える場合は値を変更\ntypedef vector<mint> vec;\ntypedef vector<vector<mint>> mat;\n\nsigned main(){\n  ios::sync_with_stdio(false);\n  cin.tie(0);\n\n  int n,k;\n  cin >> n >> k;\n\n  vec fact(n+10,1),inv(n+10,1);\n  REP(i,n+5) fact[i+1] = fact[i]*(i+1), inv[i+1] /= fact[i+1];\n\n  chmin(k,n-1);\n  mint ans = 0;\n  REP(i,k+1){\n    mint c = fact[n]*inv[i]*inv[n-i];\n    ans += c*fact[n-1]*inv[i]*inv[n-1-i];\n    // debug(ans);\n  }\n\n  cout << ans << endl;\n\n  return 0;\n}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nThere is a building with n rooms, numbered 1 to n.\n\nWe can move from any room to any other room in the building.\n\nLet us call the following event a move: a person in some room i goes to another room j~ (i \\neq j).\n\nInitially, there was one person in each room in the building.\n\nAfter that, we know that there were exactly k moves happened up to now.\n\nWe are interested in the number of people in each of the n rooms now. How many combinations of numbers of people in the n rooms are possible?\n\nFind the count modulo (10^9 + 7).\n\nConstraints\n\nAll values in input are integers.\n\n3 \\leq n \\leq 2 \\times 10^5\n\n2 \\leq k \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn k\n\nOutput\n\nPrint the number of possible combinations of numbers of people in the n rooms now, modulo (10^9 + 7).\n\nSample Input 1\n\n3 2\n\nSample Output 1\n\n10\n\nLet c_1, c_2, and c_3 be the number of people in Room 1, 2, and 3 now, respectively. There are 10 possible combination of (c_1, c_2, c_3):\n\n(0, 0, 3)\n\n(0, 1, 2)\n\n(0, 2, 1)\n\n(0, 3, 0)\n\n(1, 0, 2)\n\n(1, 1, 1)\n\n(1, 2, 0)\n\n(2, 0, 1)\n\n(2, 1, 0)\n\n(3, 0, 0)\n\nFor example, (c_1, c_2, c_3) will be (0, 1, 2) if the person in Room 1 goes to Room 2 and then one of the persons in Room 2 goes to Room 3.\n\nSample Input 2\n\n200000 1000000000\n\nSample Output 2\n\n607923868\n\nPrint the count modulo (10^9 + 7).\n\nSample Input 3\n\n15 6\n\nSample Output 3\n\n22583772", "sample_input": "3 2\n"}, "reference_outputs": ["10\n"], "source_document_id": "p02769", "source_text": "Score : 500 points\n\nProblem Statement\n\nThere is a building with n rooms, numbered 1 to n.\n\nWe can move from any room to any other room in the building.\n\nLet us call the following event a move: a person in some room i goes to another room j~ (i \\neq j).\n\nInitially, there was one person in each room in the building.\n\nAfter that, we know that there were exactly k moves happened up to now.\n\nWe are interested in the number of people in each of the n rooms now. How many combinations of numbers of people in the n rooms are possible?\n\nFind the count modulo (10^9 + 7).\n\nConstraints\n\nAll values in input are integers.\n\n3 \\leq n \\leq 2 \\times 10^5\n\n2 \\leq k \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn k\n\nOutput\n\nPrint the number of possible combinations of numbers of people in the n rooms now, modulo (10^9 + 7).\n\nSample Input 1\n\n3 2\n\nSample Output 1\n\n10\n\nLet c_1, c_2, and c_3 be the number of people in Room 1, 2, and 3 now, respectively. There are 10 possible combination of (c_1, c_2, c_3):\n\n(0, 0, 3)\n\n(0, 1, 2)\n\n(0, 2, 1)\n\n(0, 3, 0)\n\n(1, 0, 2)\n\n(1, 1, 1)\n\n(1, 2, 0)\n\n(2, 0, 1)\n\n(2, 1, 0)\n\n(3, 0, 0)\n\nFor example, (c_1, c_2, c_3) will be (0, 1, 2) if the person in Room 1 goes to Room 2 and then one of the persons in Room 2 goes to Room 3.\n\nSample Input 2\n\n200000 1000000000\n\nSample Output 2\n\n607923868\n\nPrint the count modulo (10^9 + 7).\n\nSample Input 3\n\n15 6\n\nSample Output 3\n\n22583772", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 8294, "cpu_time_ms": 84, "memory_kb": 6528}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s172040789", "group_id": "codeNet:p02769", "input_text": "#include <iostream>\n#include <string>\n#include <queue>\n#include <stack>\n#include <algorithm>\n#include <list>\n#include <vector>\n#include <complex>\n#include <utility>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <cmath>\n#include <climits>\n#include <bitset>\n#include <ctime>\n#include <map>\n#include <unordered_map>\n#include <set>\n#include <unordered_set>\n#include <cassert>\n#include <cstddef>\n#include <iomanip>\n#include <numeric>\n#include <tuple>\n#include <sstream>\n#include <fstream>\n#include <functional>\n\nusing namespace std;\n#define REP(i, n) for (int (i) = 0; (i) < (n); (i)++)\n#define FOR(i, a, b) for (int (i) = (a); (i) < (b); (i)++)\n#define RREP(i, a) for(int (i) = (a) - 1; (i) >= 0; (i)--)\n#define FORR(i, a, b) for(int (i) = (a) - 1; (i) >= (b); (i)--)\n#define DEBUG(C) cerr << #C << \" = \" << C << endl;\nusing LL = long long;\nusing VI = vector<int>;\nusing VVI = vector<VI>;\nusing VL = vector<LL>;\nusing VVL = vector<VL>;\nusing VD = vector<double>;\nusing VVD = vector<VD>;\nusing PII = pair<int, int>;\nusing PDD = pair<double, double>;\nusing PLL = pair<LL, LL>;\nusing VPII = vector<PII>;\ntemplate<typename T> using VT = vector<T>;\n#define ALL(a) begin((a)), end((a))\n#define RALL(a) rbegin((a)), rend((a))\n#define SORT(a) sort(ALL((a)))\n#define RSORT(a) sort(RALL((a)))\n#define REVERSE(a) reverse(ALL((a)))\n#define MP make_pair\n#define FORE(a, b) for (auto &&a : (b))\n#define EB emplace_back\n#define GREATER(T) T, VT<T> greater<T>\ntemplate<typename T> inline bool chmax(T &a, T b){if (a < b){a = b;return true;}return false;}\ntemplate<typename T> inline bool chmin(T &a, T b){if (a > b){a = b;return true;}return false;}\n\nconst int INF = 1e9;\nconst int MOD = INF + 7;\nconst LL LLINF = 1e18;\n\n// 剰余計算,MOD計算,順列・組み合わせ,Permutation・Combination\n\ntemplate<int mod>\nclass mod_calc {\nprivate:\n    const int defnum = -1;\npublic:\n    mod_calc() { }\n    const inline int add(int a, const int b) const {\n        a += b;\n        while (a < 0) a += mod;\n        while (a >= mod) a -= mod;\n        return a;\n    }\n    const inline int mul(const int a, const int b) const {\n        return (long long)a * b % mod;\n    }\n    const inline void add_ref(int &a, const int b) const {\n        a = this->add(a, b);\n    }\n    const inline void mul_ref(int &a, const int b) const {\n        a = this->mul(a, b);\n    }\n    const inline void add_ref(long long &a, const int b) const {\n        a = this->add(a, b);\n    }\n    const inline void mul_ref(long long &a, const int b) const {\n        a = this->mul(a, b);\n    }\n    const inline int pow(int a, int p) const {\n        int res = 1;\n        while (p > 0) {\n            if (p & 1) res = this->mul(res, a);\n            a = this->mul(a, a);\n            p >>= 1;\n        }\n        return res;\n    }\n    const inline int inverse(int a) const {\n        return this->pow(a, mod - 2);\n    }\n};\n\nconst int MAX = 5e5 + 10;\nmod_calc<MOD> mc;\nint memo_fact[MAX], memo_inv_fact[MAX];\n\ninline int fact(int n) {\n    if (memo_fact[n] != -1) return memo_fact[n];\n    return memo_fact[n] = (n == 0 ? 1 : mc.mul(n, fact(n - 1)));\n}\n\ninline int inv_fact(int n) {\n    if (memo_inv_fact[n] != -1) return memo_inv_fact[n];\n    return memo_inv_fact[n] = mc.inverse(fact(n));\n}\n\ninline long long perm(int n, int r) {\n    return mc.mul(fact(n), inv_fact(n - r));\n}\n\ninline long long comb(int n, int r) {\n    return mc.mul(mc.mul(fact(n), inv_fact(r)), inv_fact(n - r));\n}\n\n// M個の物をN人で分ける\ninline long long comb_with_repetition(int M, int N) {\n    return comb(M + N - 1, N - 1);\n}\n\n//最初に呼んで♪ O(MAX)\ninline void init() {\n    memset(memo_fact, -1, sizeof(memo_fact));\n    memset(memo_inv_fact, -1, sizeof(memo_inv_fact));\n    for (int i = 0; i < MAX; i++) {\n        fact(i);\n        inv_fact(i);\n    }\n}\n\nint main(void) {\n    init();\n    int N, K;\n    cin >> N >> K;\n    if (N <= K + 1) {\n        cout << comb_with_repetition(N, N) << endl;\n        return 0;\n    }\n\n    // 0 個の部屋が K 個以下\n    LL ans = comb_with_repetition(N, N);\n    FOR(zero_cnt, K + 1, N) {\n        LL tmp = comb(N - 1, N - zero_cnt - 1);\n        const auto tmp2 = mc.mul(fact(N), mc.mul(inv_fact(N - zero_cnt), inv_fact(zero_cnt)));\n        tmp = mc.mul(tmp, tmp2);\n        ans = mc.add(ans, -tmp);\n    }\n\n    cout << ans << endl;\n}\n", "language": "C++", "metadata": {"date": 1582404574, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02769.html", "problem_id": "p02769", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02769/input.txt", "sample_output_relpath": "derived/input_output/data/p02769/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02769/C++/s172040789.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s172040789", "user_id": "u443010331"}, "prompt_components": {"gold_output": "10\n", "input_to_evaluate": "#include <iostream>\n#include <string>\n#include <queue>\n#include <stack>\n#include <algorithm>\n#include <list>\n#include <vector>\n#include <complex>\n#include <utility>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <cmath>\n#include <climits>\n#include <bitset>\n#include <ctime>\n#include <map>\n#include <unordered_map>\n#include <set>\n#include <unordered_set>\n#include <cassert>\n#include <cstddef>\n#include <iomanip>\n#include <numeric>\n#include <tuple>\n#include <sstream>\n#include <fstream>\n#include <functional>\n\nusing namespace std;\n#define REP(i, n) for (int (i) = 0; (i) < (n); (i)++)\n#define FOR(i, a, b) for (int (i) = (a); (i) < (b); (i)++)\n#define RREP(i, a) for(int (i) = (a) - 1; (i) >= 0; (i)--)\n#define FORR(i, a, b) for(int (i) = (a) - 1; (i) >= (b); (i)--)\n#define DEBUG(C) cerr << #C << \" = \" << C << endl;\nusing LL = long long;\nusing VI = vector<int>;\nusing VVI = vector<VI>;\nusing VL = vector<LL>;\nusing VVL = vector<VL>;\nusing VD = vector<double>;\nusing VVD = vector<VD>;\nusing PII = pair<int, int>;\nusing PDD = pair<double, double>;\nusing PLL = pair<LL, LL>;\nusing VPII = vector<PII>;\ntemplate<typename T> using VT = vector<T>;\n#define ALL(a) begin((a)), end((a))\n#define RALL(a) rbegin((a)), rend((a))\n#define SORT(a) sort(ALL((a)))\n#define RSORT(a) sort(RALL((a)))\n#define REVERSE(a) reverse(ALL((a)))\n#define MP make_pair\n#define FORE(a, b) for (auto &&a : (b))\n#define EB emplace_back\n#define GREATER(T) T, VT<T> greater<T>\ntemplate<typename T> inline bool chmax(T &a, T b){if (a < b){a = b;return true;}return false;}\ntemplate<typename T> inline bool chmin(T &a, T b){if (a > b){a = b;return true;}return false;}\n\nconst int INF = 1e9;\nconst int MOD = INF + 7;\nconst LL LLINF = 1e18;\n\n// 剰余計算,MOD計算,順列・組み合わせ,Permutation・Combination\n\ntemplate<int mod>\nclass mod_calc {\nprivate:\n    const int defnum = -1;\npublic:\n    mod_calc() { }\n    const inline int add(int a, const int b) const {\n        a += b;\n        while (a < 0) a += mod;\n        while (a >= mod) a -= mod;\n        return a;\n    }\n    const inline int mul(const int a, const int b) const {\n        return (long long)a * b % mod;\n    }\n    const inline void add_ref(int &a, const int b) const {\n        a = this->add(a, b);\n    }\n    const inline void mul_ref(int &a, const int b) const {\n        a = this->mul(a, b);\n    }\n    const inline void add_ref(long long &a, const int b) const {\n        a = this->add(a, b);\n    }\n    const inline void mul_ref(long long &a, const int b) const {\n        a = this->mul(a, b);\n    }\n    const inline int pow(int a, int p) const {\n        int res = 1;\n        while (p > 0) {\n            if (p & 1) res = this->mul(res, a);\n            a = this->mul(a, a);\n            p >>= 1;\n        }\n        return res;\n    }\n    const inline int inverse(int a) const {\n        return this->pow(a, mod - 2);\n    }\n};\n\nconst int MAX = 5e5 + 10;\nmod_calc<MOD> mc;\nint memo_fact[MAX], memo_inv_fact[MAX];\n\ninline int fact(int n) {\n    if (memo_fact[n] != -1) return memo_fact[n];\n    return memo_fact[n] = (n == 0 ? 1 : mc.mul(n, fact(n - 1)));\n}\n\ninline int inv_fact(int n) {\n    if (memo_inv_fact[n] != -1) return memo_inv_fact[n];\n    return memo_inv_fact[n] = mc.inverse(fact(n));\n}\n\ninline long long perm(int n, int r) {\n    return mc.mul(fact(n), inv_fact(n - r));\n}\n\ninline long long comb(int n, int r) {\n    return mc.mul(mc.mul(fact(n), inv_fact(r)), inv_fact(n - r));\n}\n\n// M個の物をN人で分ける\ninline long long comb_with_repetition(int M, int N) {\n    return comb(M + N - 1, N - 1);\n}\n\n//最初に呼んで♪ O(MAX)\ninline void init() {\n    memset(memo_fact, -1, sizeof(memo_fact));\n    memset(memo_inv_fact, -1, sizeof(memo_inv_fact));\n    for (int i = 0; i < MAX; i++) {\n        fact(i);\n        inv_fact(i);\n    }\n}\n\nint main(void) {\n    init();\n    int N, K;\n    cin >> N >> K;\n    if (N <= K + 1) {\n        cout << comb_with_repetition(N, N) << endl;\n        return 0;\n    }\n\n    // 0 個の部屋が K 個以下\n    LL ans = comb_with_repetition(N, N);\n    FOR(zero_cnt, K + 1, N) {\n        LL tmp = comb(N - 1, N - zero_cnt - 1);\n        const auto tmp2 = mc.mul(fact(N), mc.mul(inv_fact(N - zero_cnt), inv_fact(zero_cnt)));\n        tmp = mc.mul(tmp, tmp2);\n        ans = mc.add(ans, -tmp);\n    }\n\n    cout << ans << endl;\n}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nThere is a building with n rooms, numbered 1 to n.\n\nWe can move from any room to any other room in the building.\n\nLet us call the following event a move: a person in some room i goes to another room j~ (i \\neq j).\n\nInitially, there was one person in each room in the building.\n\nAfter that, we know that there were exactly k moves happened up to now.\n\nWe are interested in the number of people in each of the n rooms now. How many combinations of numbers of people in the n rooms are possible?\n\nFind the count modulo (10^9 + 7).\n\nConstraints\n\nAll values in input are integers.\n\n3 \\leq n \\leq 2 \\times 10^5\n\n2 \\leq k \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn k\n\nOutput\n\nPrint the number of possible combinations of numbers of people in the n rooms now, modulo (10^9 + 7).\n\nSample Input 1\n\n3 2\n\nSample Output 1\n\n10\n\nLet c_1, c_2, and c_3 be the number of people in Room 1, 2, and 3 now, respectively. There are 10 possible combination of (c_1, c_2, c_3):\n\n(0, 0, 3)\n\n(0, 1, 2)\n\n(0, 2, 1)\n\n(0, 3, 0)\n\n(1, 0, 2)\n\n(1, 1, 1)\n\n(1, 2, 0)\n\n(2, 0, 1)\n\n(2, 1, 0)\n\n(3, 0, 0)\n\nFor example, (c_1, c_2, c_3) will be (0, 1, 2) if the person in Room 1 goes to Room 2 and then one of the persons in Room 2 goes to Room 3.\n\nSample Input 2\n\n200000 1000000000\n\nSample Output 2\n\n607923868\n\nPrint the count modulo (10^9 + 7).\n\nSample Input 3\n\n15 6\n\nSample Output 3\n\n22583772", "sample_input": "3 2\n"}, "reference_outputs": ["10\n"], "source_document_id": "p02769", "source_text": "Score : 500 points\n\nProblem Statement\n\nThere is a building with n rooms, numbered 1 to n.\n\nWe can move from any room to any other room in the building.\n\nLet us call the following event a move: a person in some room i goes to another room j~ (i \\neq j).\n\nInitially, there was one person in each room in the building.\n\nAfter that, we know that there were exactly k moves happened up to now.\n\nWe are interested in the number of people in each of the n rooms now. How many combinations of numbers of people in the n rooms are possible?\n\nFind the count modulo (10^9 + 7).\n\nConstraints\n\nAll values in input are integers.\n\n3 \\leq n \\leq 2 \\times 10^5\n\n2 \\leq k \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn k\n\nOutput\n\nPrint the number of possible combinations of numbers of people in the n rooms now, modulo (10^9 + 7).\n\nSample Input 1\n\n3 2\n\nSample Output 1\n\n10\n\nLet c_1, c_2, and c_3 be the number of people in Room 1, 2, and 3 now, respectively. There are 10 possible combination of (c_1, c_2, c_3):\n\n(0, 0, 3)\n\n(0, 1, 2)\n\n(0, 2, 1)\n\n(0, 3, 0)\n\n(1, 0, 2)\n\n(1, 1, 1)\n\n(1, 2, 0)\n\n(2, 0, 1)\n\n(2, 1, 0)\n\n(3, 0, 0)\n\nFor example, (c_1, c_2, c_3) will be (0, 1, 2) if the person in Room 1 goes to Room 2 and then one of the persons in Room 2 goes to Room 3.\n\nSample Input 2\n\n200000 1000000000\n\nSample Output 2\n\n607923868\n\nPrint the count modulo (10^9 + 7).\n\nSample Input 3\n\n15 6\n\nSample Output 3\n\n22583772", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 4302, "cpu_time_ms": 87, "memory_kb": 4096}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s853599650", "group_id": "codeNet:p02770", "input_text": "#pragma GCC optimize(\"Ofast\")\n//#pragma GCC optimize(\"unroll-loops\")\n//#pragma GCC push_options\n//#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n#include<bits/stdc++.h>\n#include <xmmintrin.h>\n#include <immintrin.h>\nusing namespace::std;\n__attribute__((constructor))void init(){cin.tie(0);ios::sync_with_stdio(false);cout<<fixed<<setprecision(15);}\n#include<ext/pb_ds/assoc_container.hpp>\n#include<ext/pb_ds/tree_policy.hpp>\n#include <ext/pb_ds/priority_queue.hpp>\n#include<ext/pb_ds/tag_and_trait.hpp>\n// #include <boost/multiprecision/cpp_dec_float.hpp>\n// #include <boost/multiprecision/cpp_int.hpp>\n// namespace mp = boost::multiprecision;\n// typedef mp::number<mp::cpp_dec_float<0>> cdouble;\n// typedef mp::cpp_int cint;\ntemplate<typename T>using pbds=__gnu_pbds::tree<T,__gnu_pbds::null_type,less<T>,__gnu_pbds::rb_tree_tag,__gnu_pbds::tree_order_statistics_node_update>;\ntemplate<typename T>using pbds_map=__gnu_pbds::tree<T,T,less<T>,__gnu_pbds::rb_tree_tag,__gnu_pbds::tree_order_statistics_node_update>;\ntemplate<typename T,typename E>using hash_map=__gnu_pbds::gp_hash_table<T,E>;\ntemplate<typename T>using pqueue =__gnu_pbds::priority_queue<T, greater<T>,__gnu_pbds::rc_binomial_heap_tag>;\ntypedef long long lint;\n#define INF (1LL<<60)\n#define IINF (1<<30)\n#define EPS (1e-10)\n#define MOD 1000000007LL\n//#define MOD 998244353LL\ntypedef vector<lint> vec;\ntypedef vector<vector<lint>> mat;\ntypedef vector<vector<vector<lint>>> mat3;\ntypedef vector<string> svec;\ntypedef vector<vector<string>> smat;\ntemplate<typename T>inline void numout(T t){bool f=0;for(auto i:t){cout<<(f?\" \":\"\")<<i<INF/2?i:\"INF\";f=1;}cout<<endl;}\ntemplate<typename T>inline void numout2(T t){for(auto i:t)numout(i);}\ntemplate<typename T>inline void output(T t){bool f=0;for(auto i:t){cout<<(f?\" \":\"\")<<i;f=1;}cout<<endl;}\ntemplate<typename T>inline void output2(T t){for(auto i:t)output(i);}\ntemplate<typename T>inline void _output(T t){bool f=0;for(lint i=0;i<t.size();i++){cout<<f?\"\":\" \"<<t[i];f=1;}cout<<endl;}\ntemplate<typename T>inline void _output2(T t){for(lint i=0;i<t.size();i++)output(t[i]);}\n#define rep(i,n) for(lint i=0;i<lint(n);++i)\n#define repi(i,a,b) for(lint i=lint(a);i<(lint)(b);++i)\n#define rrep(i,n) for(lint i=lint(n)-1;i>=0;--i)\n#define rrepi(i,a,b) for(lint i=lint(b)-1;i>=lint(a);--i)\n#define irep(i) for(lint i=0;;++i)\n#define all(n) begin(n),end(n)\n#define dist(a,b,c,d) sqrt(pow(a-c,2)+pow(b-d,2))\ninline lint gcd(lint A,lint B){return B?gcd(B,A%B):A;}\ninline lint lcm(lint A,lint B){return A/gcd(A,B)*B;}\n// inline cint cgcd(cint A,cint B){return B?cgcd(B,A%B):A;}\n// inline cint clcm(cint A,cint B){return A/cgcd(A,B)*B;}\ninline bool chmin(auto& s,const auto& t){bool res=s>t;s=min(s,t);return res;}\ninline bool chmax(auto& s,const auto& t){bool res=s<t;s=max(s,t);return res;}\nconst vector<lint> dx={1,0,-1,0,1,1,-1,-1};\nconst vector<lint> dy={0,1,0,-1,1,-1,1,-1};\n#define SUM(v) accumulate(all(v),0LL)\n//auto call=[&](auto f,auto... args){return f(f,args...);};\n\nint main(){\n    lint k,q;\n    cin>>k>>q;\n    vec b(k);\n    rep(i,k)cin>>b[i];\n    rep(i,q){\n        lint n,x,m;\n        cin>>n>>x>>m;\n        vec c(k);\n        rep(j,k)c[j]=(b[j]-1)%m+1;\n        __int128_t cnt=__int128_t(SUM(c))*((n-1)/k)+x%m;\n        rep(j,(n-1)%k)cnt+=c[j];\n        cout<<(lint)(n-1-(cnt/m))<<endl;\n    }\n}\n", "language": "C++", "metadata": {"date": 1582409205, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02770.html", "problem_id": "p02770", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02770/input.txt", "sample_output_relpath": "derived/input_output/data/p02770/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02770/C++/s853599650.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s853599650", "user_id": "u168579419"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#pragma GCC optimize(\"Ofast\")\n//#pragma GCC optimize(\"unroll-loops\")\n//#pragma GCC push_options\n//#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n#include<bits/stdc++.h>\n#include <xmmintrin.h>\n#include <immintrin.h>\nusing namespace::std;\n__attribute__((constructor))void init(){cin.tie(0);ios::sync_with_stdio(false);cout<<fixed<<setprecision(15);}\n#include<ext/pb_ds/assoc_container.hpp>\n#include<ext/pb_ds/tree_policy.hpp>\n#include <ext/pb_ds/priority_queue.hpp>\n#include<ext/pb_ds/tag_and_trait.hpp>\n// #include <boost/multiprecision/cpp_dec_float.hpp>\n// #include <boost/multiprecision/cpp_int.hpp>\n// namespace mp = boost::multiprecision;\n// typedef mp::number<mp::cpp_dec_float<0>> cdouble;\n// typedef mp::cpp_int cint;\ntemplate<typename T>using pbds=__gnu_pbds::tree<T,__gnu_pbds::null_type,less<T>,__gnu_pbds::rb_tree_tag,__gnu_pbds::tree_order_statistics_node_update>;\ntemplate<typename T>using pbds_map=__gnu_pbds::tree<T,T,less<T>,__gnu_pbds::rb_tree_tag,__gnu_pbds::tree_order_statistics_node_update>;\ntemplate<typename T,typename E>using hash_map=__gnu_pbds::gp_hash_table<T,E>;\ntemplate<typename T>using pqueue =__gnu_pbds::priority_queue<T, greater<T>,__gnu_pbds::rc_binomial_heap_tag>;\ntypedef long long lint;\n#define INF (1LL<<60)\n#define IINF (1<<30)\n#define EPS (1e-10)\n#define MOD 1000000007LL\n//#define MOD 998244353LL\ntypedef vector<lint> vec;\ntypedef vector<vector<lint>> mat;\ntypedef vector<vector<vector<lint>>> mat3;\ntypedef vector<string> svec;\ntypedef vector<vector<string>> smat;\ntemplate<typename T>inline void numout(T t){bool f=0;for(auto i:t){cout<<(f?\" \":\"\")<<i<INF/2?i:\"INF\";f=1;}cout<<endl;}\ntemplate<typename T>inline void numout2(T t){for(auto i:t)numout(i);}\ntemplate<typename T>inline void output(T t){bool f=0;for(auto i:t){cout<<(f?\" \":\"\")<<i;f=1;}cout<<endl;}\ntemplate<typename T>inline void output2(T t){for(auto i:t)output(i);}\ntemplate<typename T>inline void _output(T t){bool f=0;for(lint i=0;i<t.size();i++){cout<<f?\"\":\" \"<<t[i];f=1;}cout<<endl;}\ntemplate<typename T>inline void _output2(T t){for(lint i=0;i<t.size();i++)output(t[i]);}\n#define rep(i,n) for(lint i=0;i<lint(n);++i)\n#define repi(i,a,b) for(lint i=lint(a);i<(lint)(b);++i)\n#define rrep(i,n) for(lint i=lint(n)-1;i>=0;--i)\n#define rrepi(i,a,b) for(lint i=lint(b)-1;i>=lint(a);--i)\n#define irep(i) for(lint i=0;;++i)\n#define all(n) begin(n),end(n)\n#define dist(a,b,c,d) sqrt(pow(a-c,2)+pow(b-d,2))\ninline lint gcd(lint A,lint B){return B?gcd(B,A%B):A;}\ninline lint lcm(lint A,lint B){return A/gcd(A,B)*B;}\n// inline cint cgcd(cint A,cint B){return B?cgcd(B,A%B):A;}\n// inline cint clcm(cint A,cint B){return A/cgcd(A,B)*B;}\ninline bool chmin(auto& s,const auto& t){bool res=s>t;s=min(s,t);return res;}\ninline bool chmax(auto& s,const auto& t){bool res=s<t;s=max(s,t);return res;}\nconst vector<lint> dx={1,0,-1,0,1,1,-1,-1};\nconst vector<lint> dy={0,1,0,-1,1,-1,1,-1};\n#define SUM(v) accumulate(all(v),0LL)\n//auto call=[&](auto f,auto... args){return f(f,args...);};\n\nint main(){\n    lint k,q;\n    cin>>k>>q;\n    vec b(k);\n    rep(i,k)cin>>b[i];\n    rep(i,q){\n        lint n,x,m;\n        cin>>n>>x>>m;\n        vec c(k);\n        rep(j,k)c[j]=(b[j]-1)%m+1;\n        __int128_t cnt=__int128_t(SUM(c))*((n-1)/k)+x%m;\n        rep(j,(n-1)%k)cnt+=c[j];\n        cout<<(lint)(n-1-(cnt/m))<<endl;\n    }\n}\n", "problem_context": "Score : 600 points\n\nProblem Statement\n\nWe have a sequence of k numbers: d_0,d_1,...,d_{k - 1}.\n\nProcess the following q queries in order:\n\nThe i-th query contains three integers n_i, x_i, and m_i.\nLet a_0,a_1,...,a_{n_i - 1} be the following sequence of n_i numbers: \\begin{eqnarray} a_j = \\begin{cases} x_i & ( j = 0 ) \\\\ a_{j - 1} + d_{(j - 1)~\\textrm{mod}~k} & ( 0 < j \\leq n_i - 1 ) \\end{cases}\\end{eqnarray}\nPrint the number of j~(0 \\leq j < n_i - 1) such that (a_j~\\textrm{mod}~m_i) < (a_{j + 1}~\\textrm{mod}~m_i).\n\nHere (y~\\textrm{mod}~z) denotes the remainder of y divided by z, for two integers y and z~(z > 0).\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq k, q \\leq 5000\n\n0 \\leq d_i \\leq 10^9\n\n2 \\leq n_i \\leq 10^9\n\n0 \\leq x_i \\leq 10^9\n\n2 \\leq m_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nk q\nd_0 d_1 ... d_{k - 1}\nn_1 x_1 m_1\nn_2 x_2 m_2\n:\nn_q x_q m_q\n\nOutput\n\nPrint q lines.\n\nThe i-th line should contain the response to the i-th query.\n\nSample Input 1\n\n3 1\n3 1 4\n5 3 2\n\nSample Output 1\n\n1\n\nFor the first query, the sequence {a_j} will be 3,6,7,11,14.\n\n(a_0~\\textrm{mod}~2) > (a_1~\\textrm{mod}~2)\n\n(a_1~\\textrm{mod}~2) < (a_2~\\textrm{mod}~2)\n\n(a_2~\\textrm{mod}~2) = (a_3~\\textrm{mod}~2)\n\n(a_3~\\textrm{mod}~2) > (a_4~\\textrm{mod}~2)\n\nThus, the response to this query should be 1.\n\nSample Input 2\n\n7 3\n27 18 28 18 28 46 1000000000\n1000000000 1 7\n1000000000 2 10\n1000000000 3 12\n\nSample Output 2\n\n224489796\n214285714\n559523809", "sample_input": "3 1\n3 1 4\n5 3 2\n"}, "reference_outputs": ["1\n"], "source_document_id": "p02770", "source_text": "Score : 600 points\n\nProblem Statement\n\nWe have a sequence of k numbers: d_0,d_1,...,d_{k - 1}.\n\nProcess the following q queries in order:\n\nThe i-th query contains three integers n_i, x_i, and m_i.\nLet a_0,a_1,...,a_{n_i - 1} be the following sequence of n_i numbers: \\begin{eqnarray} a_j = \\begin{cases} x_i & ( j = 0 ) \\\\ a_{j - 1} + d_{(j - 1)~\\textrm{mod}~k} & ( 0 < j \\leq n_i - 1 ) \\end{cases}\\end{eqnarray}\nPrint the number of j~(0 \\leq j < n_i - 1) such that (a_j~\\textrm{mod}~m_i) < (a_{j + 1}~\\textrm{mod}~m_i).\n\nHere (y~\\textrm{mod}~z) denotes the remainder of y divided by z, for two integers y and z~(z > 0).\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq k, q \\leq 5000\n\n0 \\leq d_i \\leq 10^9\n\n2 \\leq n_i \\leq 10^9\n\n0 \\leq x_i \\leq 10^9\n\n2 \\leq m_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nk q\nd_0 d_1 ... d_{k - 1}\nn_1 x_1 m_1\nn_2 x_2 m_2\n:\nn_q x_q m_q\n\nOutput\n\nPrint q lines.\n\nThe i-th line should contain the response to the i-th query.\n\nSample Input 1\n\n3 1\n3 1 4\n5 3 2\n\nSample Output 1\n\n1\n\nFor the first query, the sequence {a_j} will be 3,6,7,11,14.\n\n(a_0~\\textrm{mod}~2) > (a_1~\\textrm{mod}~2)\n\n(a_1~\\textrm{mod}~2) < (a_2~\\textrm{mod}~2)\n\n(a_2~\\textrm{mod}~2) = (a_3~\\textrm{mod}~2)\n\n(a_3~\\textrm{mod}~2) > (a_4~\\textrm{mod}~2)\n\nThus, the response to this query should be 1.\n\nSample Input 2\n\n7 3\n27 18 28 18 28 46 1000000000\n1000000000 1 7\n1000000000 2 10\n1000000000 3 12\n\nSample Output 2\n\n224489796\n214285714\n559523809", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 3333, "cpu_time_ms": 309, "memory_kb": 384}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s018802356", "group_id": "codeNet:p02771", "input_text": "#include <bits/stdc++.h>\n#define rep(i,n) for (int i = 0; i < (n); ++i)\n#define repit(it, li) for(auto it=li.begin(); it!=li.end(); it++)\nusing namespace std;\nusing ll = long long;\nusing P = pair<int,int>;\n\nint main(){\n   int a, b, c;\n   cin>>a>>b>>c;\n\n   bool y=false;\n   if(a==b && a!=c) y=true;\n   if(a==c && a!=b) y=true;\n   if(b==c && b!=a) y=true;\n\n   if(y) cout<<\"Yes\"<<endl;\n   else cout<<\"No\"<<endl;\n   return 0;\n}\n", "language": "C++", "metadata": {"date": 1598054524, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02771.html", "problem_id": "p02771", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02771/input.txt", "sample_output_relpath": "derived/input_output/data/p02771/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02771/C++/s018802356.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s018802356", "user_id": "u347579043"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define rep(i,n) for (int i = 0; i < (n); ++i)\n#define repit(it, li) for(auto it=li.begin(); it!=li.end(); it++)\nusing namespace std;\nusing ll = long long;\nusing P = pair<int,int>;\n\nint main(){\n   int a, b, c;\n   cin>>a>>b>>c;\n\n   bool y=false;\n   if(a==b && a!=c) y=true;\n   if(a==c && a!=b) y=true;\n   if(b==c && b!=a) y=true;\n\n   if(y) cout<<\"Yes\"<<endl;\n   else cout<<\"No\"<<endl;\n   return 0;\n}\n", "problem_context": "Score: 100 points\n\nProblem Statement\n\nA triple of numbers is said to be poor when two of those numbers are equal but the other number is different from those two numbers.\n\nYou will be given three integers A, B, and C. If this triple is poor, print Yes; otherwise, print No.\n\nConstraints\n\nA, B, and C are all integers between 1 and 9 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B C\n\nOutput\n\nIf the given triple is poor, print Yes; otherwise, print No.\n\nSample Input 1\n\n5 7 5\n\nSample Output 1\n\nYes\n\nA and C are equal, but B is different from those two numbers, so this triple is poor.\n\nSample Input 2\n\n4 4 4\n\nSample Output 2\n\nNo\n\nA, B, and C are all equal, so this triple is not poor.\n\nSample Input 3\n\n4 9 6\n\nSample Output 3\n\nNo\n\nSample Input 4\n\n3 3 4\n\nSample Output 4\n\nYes", "sample_input": "5 7 5\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p02771", "source_text": "Score: 100 points\n\nProblem Statement\n\nA triple of numbers is said to be poor when two of those numbers are equal but the other number is different from those two numbers.\n\nYou will be given three integers A, B, and C. If this triple is poor, print Yes; otherwise, print No.\n\nConstraints\n\nA, B, and C are all integers between 1 and 9 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B C\n\nOutput\n\nIf the given triple is poor, print Yes; otherwise, print No.\n\nSample Input 1\n\n5 7 5\n\nSample Output 1\n\nYes\n\nA and C are equal, but B is different from those two numbers, so this triple is poor.\n\nSample Input 2\n\n4 4 4\n\nSample Output 2\n\nNo\n\nA, B, and C are all equal, so this triple is not poor.\n\nSample Input 3\n\n4 9 6\n\nSample Output 3\n\nNo\n\nSample Input 4\n\n3 3 4\n\nSample Output 4\n\nYes", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 424, "cpu_time_ms": 7, "memory_kb": 3624}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s741200309", "group_id": "codeNet:p02773", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n)  for(long long i=0;i<(long long)(n);i++)\n#define REP(i,k,n) for(long long i=k;i<(long long)(n);i++)\n#define all(a) a.begin(),a.end()\n#define pb push_back\n#define eb emplace_back\n#define lb(v,k) (lower_bound(all(v),k)-v.begin())\n#define ub(v,k) (upper_bound(all(v),k)-v.begin())\n#define fi first\n#define se second\n#define pi M_PI\ntypedef long long ll;\ntypedef pair<ll,ll> P;\ntypedef tuple<ll,ll,ll> PP;\ntypedef multiset<ll> S;\ntypedef priority_queue<ll> PQ;\ntypedef priority_queue<P,vector<P>,greater<P>> SPQ;\nusing vi=vector<ll>;\nusing vvi=vector<vi>;\nusing vvvi=vector<vvi>;\nconst ll inf=1001001001001001;\nconst int INF=1001001001;\nconst int mod=1000000007;\ntemplate<class T> bool chmin(T&a,T b){if(a>b){a=b;return true;}return false;}\ntemplate<class T> bool chmax(T&a,T b){if(a<b){a=b;return true;}return false;}\ntemplate<class T> void out(T a){cout<<a<<endl;}\ntemplate<class T> void outp(T a){cout<<'('<<a.fi<<','<<a.se<<')'<<endl;}\ntemplate<class T> void outvp(T v){rep(i,v.size())outp(v[i]);}\ntemplate<class T> void outv(T v){rep(i,v.size()){if(i)cout<<' ';cout<<v[i];}cout<<endl;}\ntemplate<class T> void outvv(T v){rep(i,v.size()){rep(j,v[i].size()){if(j)cout<<' ';cout<<v[i][j];}cout<<endl;}}\nll gcd(ll a,ll b){\n    if(b==0)return a;\n    return gcd(b,a%b);\n}\nll modpow(ll a,ll b){\n    a%=mod;\n    if(b==0)return 1;\n    if(b&1)return a*modpow(a,b-1)%mod;\n    ll k=modpow(a,b/2);\n    return k*k%mod;\n}\nint main(){\n    ll n;cin>>n;\n    vector<string> v(n),ans;\n    rep(i,n)cin>>v[i];\n    sort(all(v));\n    ll from=-1,to=-1;\n    ll m=0;\n    while(to<n-1){\n        from=to+1;\n        while(v[from]==v[to+1]){\n            to++;\n            if(to>=n-1)break;\n        }\n        chmax(m,to-from);\n    }\n    from=-1;\n    to=-1;\n    while(to<n-1){\n        from=to+1;\n        while(v[from]==v[to+1]){\n            to++;\n            if(to>=n-1)break;\n        }\n        if(to-from==m)ans.pb(v[to]);\n    }\n    sort(all(ans));\n    for(auto x:ans)out(x);\n}", "language": "C++", "metadata": {"date": 1582552163, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02773.html", "problem_id": "p02773", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02773/input.txt", "sample_output_relpath": "derived/input_output/data/p02773/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02773/C++/s741200309.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s741200309", "user_id": "u422633119"}, "prompt_components": {"gold_output": "beet\nvet\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n)  for(long long i=0;i<(long long)(n);i++)\n#define REP(i,k,n) for(long long i=k;i<(long long)(n);i++)\n#define all(a) a.begin(),a.end()\n#define pb push_back\n#define eb emplace_back\n#define lb(v,k) (lower_bound(all(v),k)-v.begin())\n#define ub(v,k) (upper_bound(all(v),k)-v.begin())\n#define fi first\n#define se second\n#define pi M_PI\ntypedef long long ll;\ntypedef pair<ll,ll> P;\ntypedef tuple<ll,ll,ll> PP;\ntypedef multiset<ll> S;\ntypedef priority_queue<ll> PQ;\ntypedef priority_queue<P,vector<P>,greater<P>> SPQ;\nusing vi=vector<ll>;\nusing vvi=vector<vi>;\nusing vvvi=vector<vvi>;\nconst ll inf=1001001001001001;\nconst int INF=1001001001;\nconst int mod=1000000007;\ntemplate<class T> bool chmin(T&a,T b){if(a>b){a=b;return true;}return false;}\ntemplate<class T> bool chmax(T&a,T b){if(a<b){a=b;return true;}return false;}\ntemplate<class T> void out(T a){cout<<a<<endl;}\ntemplate<class T> void outp(T a){cout<<'('<<a.fi<<','<<a.se<<')'<<endl;}\ntemplate<class T> void outvp(T v){rep(i,v.size())outp(v[i]);}\ntemplate<class T> void outv(T v){rep(i,v.size()){if(i)cout<<' ';cout<<v[i];}cout<<endl;}\ntemplate<class T> void outvv(T v){rep(i,v.size()){rep(j,v[i].size()){if(j)cout<<' ';cout<<v[i][j];}cout<<endl;}}\nll gcd(ll a,ll b){\n    if(b==0)return a;\n    return gcd(b,a%b);\n}\nll modpow(ll a,ll b){\n    a%=mod;\n    if(b==0)return 1;\n    if(b&1)return a*modpow(a,b-1)%mod;\n    ll k=modpow(a,b/2);\n    return k*k%mod;\n}\nint main(){\n    ll n;cin>>n;\n    vector<string> v(n),ans;\n    rep(i,n)cin>>v[i];\n    sort(all(v));\n    ll from=-1,to=-1;\n    ll m=0;\n    while(to<n-1){\n        from=to+1;\n        while(v[from]==v[to+1]){\n            to++;\n            if(to>=n-1)break;\n        }\n        chmax(m,to-from);\n    }\n    from=-1;\n    to=-1;\n    while(to<n-1){\n        from=to+1;\n        while(v[from]==v[to+1]){\n            to++;\n            if(to>=n-1)break;\n        }\n        if(to-from==m)ans.pb(v[to]);\n    }\n    sort(all(ans));\n    for(auto x:ans)out(x);\n}", "problem_context": "Score: 300 points\n\nProblem Statement\n\nWe have N voting papers. The i-th vote (1 \\leq i \\leq N) has the string S_i written on it.\n\nPrint all strings that are written on the most number of votes, in lexicographical order.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\nS_i (1 \\leq i \\leq N) are strings consisting of lowercase English letters.\n\nThe length of S_i (1 \\leq i \\leq N) is between 1 and 10 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS_1\n:\nS_N\n\nOutput\n\nPrint all strings in question in lexicographical order.\n\nSample Input 1\n\n7\nbeat\nvet\nbeet\nbed\nvet\nbet\nbeet\n\nSample Output 1\n\nbeet\nvet\n\nbeet and vet are written on two sheets each, while beat, bed, and bet are written on one vote each. Thus, we should print the strings beet and vet.\n\nSample Input 2\n\n8\nbuffalo\nbuffalo\nbuffalo\nbuffalo\nbuffalo\nbuffalo\nbuffalo\nbuffalo\n\nSample Output 2\n\nbuffalo\n\nSample Input 3\n\n7\nbass\nbass\nkick\nkick\nbass\nkick\nkick\n\nSample Output 3\n\nkick\n\nSample Input 4\n\n4\nushi\ntapu\nnichia\nkun\n\nSample Output 4\n\nkun\nnichia\ntapu\nushi", "sample_input": "7\nbeat\nvet\nbeet\nbed\nvet\nbet\nbeet\n"}, "reference_outputs": ["beet\nvet\n"], "source_document_id": "p02773", "source_text": "Score: 300 points\n\nProblem Statement\n\nWe have N voting papers. The i-th vote (1 \\leq i \\leq N) has the string S_i written on it.\n\nPrint all strings that are written on the most number of votes, in lexicographical order.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\nS_i (1 \\leq i \\leq N) are strings consisting of lowercase English letters.\n\nThe length of S_i (1 \\leq i \\leq N) is between 1 and 10 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS_1\n:\nS_N\n\nOutput\n\nPrint all strings in question in lexicographical order.\n\nSample Input 1\n\n7\nbeat\nvet\nbeet\nbed\nvet\nbet\nbeet\n\nSample Output 1\n\nbeet\nvet\n\nbeet and vet are written on two sheets each, while beat, bed, and bet are written on one vote each. Thus, we should print the strings beet and vet.\n\nSample Input 2\n\n8\nbuffalo\nbuffalo\nbuffalo\nbuffalo\nbuffalo\nbuffalo\nbuffalo\nbuffalo\n\nSample Output 2\n\nbuffalo\n\nSample Input 3\n\n7\nbass\nbass\nkick\nkick\nbass\nkick\nkick\n\nSample Output 3\n\nkick\n\nSample Input 4\n\n4\nushi\ntapu\nnichia\nkun\n\nSample Output 4\n\nkun\nnichia\ntapu\nushi", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2009, "cpu_time_ms": 641, "memory_kb": 15988}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s196351034", "group_id": "codeNet:p02773", "input_text": "#include <iostream>\n#include <vector>\n#include <string>\n#include <algorithm>\nusing namespace std;\n\nconst int P = 1e6, N = 2e5+9;\nstring s[N], ans[200009];\nint hd[P+9], nxt[N], cnt[N], n, c = 0;\n\nint main(){\n    cin >> n;\n    string st;\n    for(int i = 1; i <= n; i++){\n        cin >> st;\n        int num = 0;\n        bool cr = 0;\n        for(int j = 0, power = 1; j < st.size(); j++, power = (power*130)%P){\n            num = (num + st.at(j)*power)%P;\n        }\n        for(int j = hd[num]; j; j = nxt[j]){\n            if(s[j] == st){\n                cr = 1, cnt[j]++;\n                break;\n            }\n        }\n        if(!cr){\n            nxt[++c]=hd[num], hd[num]=c, cnt[c]++, s[c] = st;\n        }\n    }\n    int max = 0, a = 0;\n    for(int i = 0; i < P; i++){\n        for(int j = hd[i]; j; j = nxt[j]){\n            if(cnt[j] > max){\n                fill(ans, ans+a+1, 0);\n                ans[a=0] = s[j];\n                max = cnt[j];\n            }\n            else if(cnt[j] == max) ans[++a] = s[j];\n        }\n    }\n    sort(ans, ans+a+1);\n    for(int i = 0; i <= a; i++) cout << ans[i] << endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1582029414, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02773.html", "problem_id": "p02773", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02773/input.txt", "sample_output_relpath": "derived/input_output/data/p02773/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02773/C++/s196351034.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s196351034", "user_id": "u508187310"}, "prompt_components": {"gold_output": "beet\nvet\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\n#include <string>\n#include <algorithm>\nusing namespace std;\n\nconst int P = 1e6, N = 2e5+9;\nstring s[N], ans[200009];\nint hd[P+9], nxt[N], cnt[N], n, c = 0;\n\nint main(){\n    cin >> n;\n    string st;\n    for(int i = 1; i <= n; i++){\n        cin >> st;\n        int num = 0;\n        bool cr = 0;\n        for(int j = 0, power = 1; j < st.size(); j++, power = (power*130)%P){\n            num = (num + st.at(j)*power)%P;\n        }\n        for(int j = hd[num]; j; j = nxt[j]){\n            if(s[j] == st){\n                cr = 1, cnt[j]++;\n                break;\n            }\n        }\n        if(!cr){\n            nxt[++c]=hd[num], hd[num]=c, cnt[c]++, s[c] = st;\n        }\n    }\n    int max = 0, a = 0;\n    for(int i = 0; i < P; i++){\n        for(int j = hd[i]; j; j = nxt[j]){\n            if(cnt[j] > max){\n                fill(ans, ans+a+1, 0);\n                ans[a=0] = s[j];\n                max = cnt[j];\n            }\n            else if(cnt[j] == max) ans[++a] = s[j];\n        }\n    }\n    sort(ans, ans+a+1);\n    for(int i = 0; i <= a; i++) cout << ans[i] << endl;\n    return 0;\n}", "problem_context": "Score: 300 points\n\nProblem Statement\n\nWe have N voting papers. The i-th vote (1 \\leq i \\leq N) has the string S_i written on it.\n\nPrint all strings that are written on the most number of votes, in lexicographical order.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\nS_i (1 \\leq i \\leq N) are strings consisting of lowercase English letters.\n\nThe length of S_i (1 \\leq i \\leq N) is between 1 and 10 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS_1\n:\nS_N\n\nOutput\n\nPrint all strings in question in lexicographical order.\n\nSample Input 1\n\n7\nbeat\nvet\nbeet\nbed\nvet\nbet\nbeet\n\nSample Output 1\n\nbeet\nvet\n\nbeet and vet are written on two sheets each, while beat, bed, and bet are written on one vote each. Thus, we should print the strings beet and vet.\n\nSample Input 2\n\n8\nbuffalo\nbuffalo\nbuffalo\nbuffalo\nbuffalo\nbuffalo\nbuffalo\nbuffalo\n\nSample Output 2\n\nbuffalo\n\nSample Input 3\n\n7\nbass\nbass\nkick\nkick\nbass\nkick\nkick\n\nSample Output 3\n\nkick\n\nSample Input 4\n\n4\nushi\ntapu\nnichia\nkun\n\nSample Output 4\n\nkun\nnichia\ntapu\nushi", "sample_input": "7\nbeat\nvet\nbeet\nbed\nvet\nbet\nbeet\n"}, "reference_outputs": ["beet\nvet\n"], "source_document_id": "p02773", "source_text": "Score: 300 points\n\nProblem Statement\n\nWe have N voting papers. The i-th vote (1 \\leq i \\leq N) has the string S_i written on it.\n\nPrint all strings that are written on the most number of votes, in lexicographical order.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\nS_i (1 \\leq i \\leq N) are strings consisting of lowercase English letters.\n\nThe length of S_i (1 \\leq i \\leq N) is between 1 and 10 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS_1\n:\nS_N\n\nOutput\n\nPrint all strings in question in lexicographical order.\n\nSample Input 1\n\n7\nbeat\nvet\nbeet\nbed\nvet\nbet\nbeet\n\nSample Output 1\n\nbeet\nvet\n\nbeet and vet are written on two sheets each, while beat, bed, and bet are written on one vote each. Thus, we should print the strings beet and vet.\n\nSample Input 2\n\n8\nbuffalo\nbuffalo\nbuffalo\nbuffalo\nbuffalo\nbuffalo\nbuffalo\nbuffalo\n\nSample Output 2\n\nbuffalo\n\nSample Input 3\n\n7\nbass\nbass\nkick\nkick\nbass\nkick\nkick\n\nSample Output 3\n\nkick\n\nSample Input 4\n\n4\nushi\ntapu\nnichia\nkun\n\nSample Output 4\n\nkun\nnichia\ntapu\nushi", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1119, "cpu_time_ms": 2103, "memory_kb": 19968}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s020201941", "group_id": "codeNet:p02777", "input_text": "#include<iostream>\n#include<string>\n#include<vector>\n#include<algorithm>\n#include<cmath>\n\n#define big ((long long)(1e9)+7)\n\nusing namespace std;\n\ntypedef unsigned long long ull;\ntypedef long long ll;\n\nint main()\n{\n  string s,t;\n  cin >> s >> t;\n  int a,b;\n  cin >> a >> b;\n  string u;\n  cin >> u;\n  if(s == u)\n    a--;\n  if(t == u)\n    b--;\n  cout << a << \" \" << b << endl;\n}\n", "language": "C++", "metadata": {"date": 1581278946, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02777.html", "problem_id": "p02777", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02777/input.txt", "sample_output_relpath": "derived/input_output/data/p02777/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02777/C++/s020201941.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s020201941", "user_id": "u115819033"}, "prompt_components": {"gold_output": "2 4\n", "input_to_evaluate": "#include<iostream>\n#include<string>\n#include<vector>\n#include<algorithm>\n#include<cmath>\n\n#define big ((long long)(1e9)+7)\n\nusing namespace std;\n\ntypedef unsigned long long ull;\ntypedef long long ll;\n\nint main()\n{\n  string s,t;\n  cin >> s >> t;\n  int a,b;\n  cin >> a >> b;\n  string u;\n  cin >> u;\n  if(s == u)\n    a--;\n  if(t == u)\n    b--;\n  cout << a << \" \" << b << endl;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nWe have A balls with the string S written on each of them and B balls with the string T written on each of them.\n\nFrom these balls, Takahashi chooses one with the string U written on it and throws it away.\n\nFind the number of balls with the string S and balls with the string T that we have now.\n\nConstraints\n\nS, T, and U are strings consisting of lowercase English letters.\n\nThe lengths of S and T are each between 1 and 10 (inclusive).\n\nS \\not= T\n\nS=U or T=U.\n\n1 \\leq A,B \\leq 10\n\nA and B are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS T\nA B\nU\n\nOutput\n\nPrint the answer, with space in between.\n\nSample Input 1\n\nred blue\n3 4\nred\n\nSample Output 1\n\n2 4\n\nTakahashi chose a ball with red written on it and threw it away.\nNow we have two balls with the string S and four balls with the string T.\n\nSample Input 2\n\nred blue\n5 5\nblue\n\nSample Output 2\n\n5 4\n\nTakahashi chose a ball with blue written on it and threw it away.\nNow we have five balls with the string S and four balls with the string T.", "sample_input": "red blue\n3 4\nred\n"}, "reference_outputs": ["2 4\n"], "source_document_id": "p02777", "source_text": "Score : 100 points\n\nProblem Statement\n\nWe have A balls with the string S written on each of them and B balls with the string T written on each of them.\n\nFrom these balls, Takahashi chooses one with the string U written on it and throws it away.\n\nFind the number of balls with the string S and balls with the string T that we have now.\n\nConstraints\n\nS, T, and U are strings consisting of lowercase English letters.\n\nThe lengths of S and T are each between 1 and 10 (inclusive).\n\nS \\not= T\n\nS=U or T=U.\n\n1 \\leq A,B \\leq 10\n\nA and B are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS T\nA B\nU\n\nOutput\n\nPrint the answer, with space in between.\n\nSample Input 1\n\nred blue\n3 4\nred\n\nSample Output 1\n\n2 4\n\nTakahashi chose a ball with red written on it and threw it away.\nNow we have two balls with the string S and four balls with the string T.\n\nSample Input 2\n\nred blue\n5 5\nblue\n\nSample Output 2\n\n5 4\n\nTakahashi chose a ball with blue written on it and threw it away.\nNow we have five balls with the string S and four balls with the string T.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 376, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s878210568", "group_id": "codeNet:p02779", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  int N, c=0;\n  string ans = \"YES\";\n  cin >> N;\n  vector<string> A(N);\n  for (int i; i < N; i++){\n    cin >> A.at(i);\n  }\n  set<string> B;\n  while (c < N){\n    if (B.count(A.at(c)) == 1){\n      ans = \"NO\";\n      break;\n    }\n    B.insert(A.at(c));\n    c++;\n  }\n  cout << ans << endl;\n}", "language": "C++", "metadata": {"date": 1595524490, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02779.html", "problem_id": "p02779", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02779/input.txt", "sample_output_relpath": "derived/input_output/data/p02779/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02779/C++/s878210568.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s878210568", "user_id": "u627600101"}, "prompt_components": {"gold_output": "YES\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  int N, c=0;\n  string ans = \"YES\";\n  cin >> N;\n  vector<string> A(N);\n  for (int i; i < N; i++){\n    cin >> A.at(i);\n  }\n  set<string> B;\n  while (c < N){\n    if (B.count(A.at(c)) == 1){\n      ans = \"NO\";\n      break;\n    }\n    B.insert(A.at(c));\n    c++;\n  }\n  cout << ans << endl;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nGiven is a sequence of integers A_1, A_2, ..., A_N.\nIf its elements are pairwise distinct, print YES; otherwise, print NO.\n\nConstraints\n\n2 ≤ N ≤ 200000\n\n1 ≤ A_i ≤ 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 ... A_N\n\nOutput\n\nIf the elements of the sequence are pairwise distinct, print YES; otherwise, print NO.\n\nSample Input 1\n\n5\n2 6 1 4 5\n\nSample Output 1\n\nYES\n\nThe elements are pairwise distinct.\n\nSample Input 2\n\n6\n4 1 3 1 6 2\n\nSample Output 2\n\nNO\n\nThe second and fourth elements are identical.\n\nSample Input 3\n\n2\n10000000 10000000\n\nSample Output 3\n\nNO", "sample_input": "5\n2 6 1 4 5\n"}, "reference_outputs": ["YES\n"], "source_document_id": "p02779", "source_text": "Score : 300 points\n\nProblem Statement\n\nGiven is a sequence of integers A_1, A_2, ..., A_N.\nIf its elements are pairwise distinct, print YES; otherwise, print NO.\n\nConstraints\n\n2 ≤ N ≤ 200000\n\n1 ≤ A_i ≤ 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 ... A_N\n\nOutput\n\nIf the elements of the sequence are pairwise distinct, print YES; otherwise, print NO.\n\nSample Input 1\n\n5\n2 6 1 4 5\n\nSample Output 1\n\nYES\n\nThe elements are pairwise distinct.\n\nSample Input 2\n\n6\n4 1 3 1 6 2\n\nSample Output 2\n\nNO\n\nThe second and fourth elements are identical.\n\nSample Input 3\n\n2\n10000000 10000000\n\nSample Output 3\n\nNO", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 344, "cpu_time_ms": 214, "memory_kb": 25120}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s273224293", "group_id": "codeNet:p02779", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nint b=1,a;\nint main(){\n  cin>>a;\n  vector<int> c(a);\n  for(int i=0;i<a;i++)cin>>c[i];\n  for(int i=0;i<a;i++){\n    for(int j=1;j<a-i;j++){\n      if(c[i]==c[i+j])b=0;\n    }\n  }\n  if(b)cout<<\"Yes\"<<endl;\n  else cout<<\"No\"<<endl;\n}", "language": "C++", "metadata": {"date": 1581937673, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02779.html", "problem_id": "p02779", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02779/input.txt", "sample_output_relpath": "derived/input_output/data/p02779/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02779/C++/s273224293.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s273224293", "user_id": "u401379763"}, "prompt_components": {"gold_output": "YES\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nint b=1,a;\nint main(){\n  cin>>a;\n  vector<int> c(a);\n  for(int i=0;i<a;i++)cin>>c[i];\n  for(int i=0;i<a;i++){\n    for(int j=1;j<a-i;j++){\n      if(c[i]==c[i+j])b=0;\n    }\n  }\n  if(b)cout<<\"Yes\"<<endl;\n  else cout<<\"No\"<<endl;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nGiven is a sequence of integers A_1, A_2, ..., A_N.\nIf its elements are pairwise distinct, print YES; otherwise, print NO.\n\nConstraints\n\n2 ≤ N ≤ 200000\n\n1 ≤ A_i ≤ 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 ... A_N\n\nOutput\n\nIf the elements of the sequence are pairwise distinct, print YES; otherwise, print NO.\n\nSample Input 1\n\n5\n2 6 1 4 5\n\nSample Output 1\n\nYES\n\nThe elements are pairwise distinct.\n\nSample Input 2\n\n6\n4 1 3 1 6 2\n\nSample Output 2\n\nNO\n\nThe second and fourth elements are identical.\n\nSample Input 3\n\n2\n10000000 10000000\n\nSample Output 3\n\nNO", "sample_input": "5\n2 6 1 4 5\n"}, "reference_outputs": ["YES\n"], "source_document_id": "p02779", "source_text": "Score : 300 points\n\nProblem Statement\n\nGiven is a sequence of integers A_1, A_2, ..., A_N.\nIf its elements are pairwise distinct, print YES; otherwise, print NO.\n\nConstraints\n\n2 ≤ N ≤ 200000\n\n1 ≤ A_i ≤ 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 ... A_N\n\nOutput\n\nIf the elements of the sequence are pairwise distinct, print YES; otherwise, print NO.\n\nSample Input 1\n\n5\n2 6 1 4 5\n\nSample Output 1\n\nYES\n\nThe elements are pairwise distinct.\n\nSample Input 2\n\n6\n4 1 3 1 6 2\n\nSample Output 2\n\nNO\n\nThe second and fourth elements are identical.\n\nSample Input 3\n\n2\n10000000 10000000\n\nSample Output 3\n\nNO", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 272, "cpu_time_ms": 2103, "memory_kb": 1024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s535726320", "group_id": "codeNet:p02779", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n#define lowbit(x) ((x)&(-x))\ntypedef long long LL;\n\nmap<int, int> store;\n\nvoid run_case() {\n    int N, t;\n    cin >> N;\n    for(int i = 0; i < N; ++i) {\n        cin >> t;\n        if(store.count(t)) {\n            cout << \"NO\";\n            return;\n        }\n        store[t]++;\n    }\n    cout << \"YES\";\n}\n\nint main() {\n    ios::sync_with_stdio(false), cin.tie(0);\n    run_case();\n    cout.flush();\n    return 0;\n}", "language": "C++", "metadata": {"date": 1581278831, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02779.html", "problem_id": "p02779", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02779/input.txt", "sample_output_relpath": "derived/input_output/data/p02779/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02779/C++/s535726320.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s535726320", "user_id": "u545866784"}, "prompt_components": {"gold_output": "YES\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n#define lowbit(x) ((x)&(-x))\ntypedef long long LL;\n\nmap<int, int> store;\n\nvoid run_case() {\n    int N, t;\n    cin >> N;\n    for(int i = 0; i < N; ++i) {\n        cin >> t;\n        if(store.count(t)) {\n            cout << \"NO\";\n            return;\n        }\n        store[t]++;\n    }\n    cout << \"YES\";\n}\n\nint main() {\n    ios::sync_with_stdio(false), cin.tie(0);\n    run_case();\n    cout.flush();\n    return 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nGiven is a sequence of integers A_1, A_2, ..., A_N.\nIf its elements are pairwise distinct, print YES; otherwise, print NO.\n\nConstraints\n\n2 ≤ N ≤ 200000\n\n1 ≤ A_i ≤ 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 ... A_N\n\nOutput\n\nIf the elements of the sequence are pairwise distinct, print YES; otherwise, print NO.\n\nSample Input 1\n\n5\n2 6 1 4 5\n\nSample Output 1\n\nYES\n\nThe elements are pairwise distinct.\n\nSample Input 2\n\n6\n4 1 3 1 6 2\n\nSample Output 2\n\nNO\n\nThe second and fourth elements are identical.\n\nSample Input 3\n\n2\n10000000 10000000\n\nSample Output 3\n\nNO", "sample_input": "5\n2 6 1 4 5\n"}, "reference_outputs": ["YES\n"], "source_document_id": "p02779", "source_text": "Score : 300 points\n\nProblem Statement\n\nGiven is a sequence of integers A_1, A_2, ..., A_N.\nIf its elements are pairwise distinct, print YES; otherwise, print NO.\n\nConstraints\n\n2 ≤ N ≤ 200000\n\n1 ≤ A_i ≤ 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 ... A_N\n\nOutput\n\nIf the elements of the sequence are pairwise distinct, print YES; otherwise, print NO.\n\nSample Input 1\n\n5\n2 6 1 4 5\n\nSample Output 1\n\nYES\n\nThe elements are pairwise distinct.\n\nSample Input 2\n\n6\n4 1 3 1 6 2\n\nSample Output 2\n\nNO\n\nThe second and fourth elements are identical.\n\nSample Input 3\n\n2\n10000000 10000000\n\nSample Output 3\n\nNO", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 456, "cpu_time_ms": 124, "memory_kb": 9600}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s795867565", "group_id": "codeNet:p02780", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n   int n,k;\n   cin>>n>>k;\n\n  vector<int>p(n);\n\n  for(int i=0;i<n;i++)\n  {\n      cin>>p[i];\n  }\n\n  sort(p.begin(),p.end());\n  reverse(p.begin(),p.end());\n\n  int ans =0;\n  \n  for(int i=0;i<k;i++)\n  {\n     int me = p[i];\n     int po =0;\n    for(int j=1;j<=me;j++)\n    {\n       po += j;\n    }\n   \n    ans += po/me;\n  }\n\n  cout<<setprecision(10)<<ans<<endl;\n  \n  return 0;\n\n}\n", "language": "C++", "metadata": {"date": 1590346225, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02780.html", "problem_id": "p02780", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02780/input.txt", "sample_output_relpath": "derived/input_output/data/p02780/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02780/C++/s795867565.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s795867565", "user_id": "u814773738"}, "prompt_components": {"gold_output": "7.000000000000\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n   int n,k;\n   cin>>n>>k;\n\n  vector<int>p(n);\n\n  for(int i=0;i<n;i++)\n  {\n      cin>>p[i];\n  }\n\n  sort(p.begin(),p.end());\n  reverse(p.begin(),p.end());\n\n  int ans =0;\n  \n  for(int i=0;i<k;i++)\n  {\n     int me = p[i];\n     int po =0;\n    for(int j=1;j<=me;j++)\n    {\n       po += j;\n    }\n   \n    ans += po/me;\n  }\n\n  cout<<setprecision(10)<<ans<<endl;\n  \n  return 0;\n\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nWe have N dice arranged in a line from left to right. The i-th die from the left shows p_i numbers from 1 to p_i with equal probability when thrown.\n\nWe will choose K adjacent dice, throw each of them independently, and compute the sum of the numbers shown. Find the maximum possible value of the expected value of this sum.\n\nConstraints\n\n1 ≤ K ≤ N ≤ 200000\n\n1 ≤ p_i ≤ 1000\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\np_1 ... p_N\n\nOutput\n\nPrint the maximum possible value of the expected value of the sum of the numbers shown.\n\nYour output will be considered correct when its absolute or relative error from our answer is at most 10^{-6}.\n\nSample Input 1\n\n5 3\n1 2 2 4 5\n\nSample Output 1\n\n7.000000000000\n\nWhen we throw the third, fourth, and fifth dice from the left, the expected value of the sum of the numbers shown is 7. This is the maximum value we can achieve.\n\nSample Input 2\n\n4 1\n6 6 6 6\n\nSample Output 2\n\n3.500000000000\n\nRegardless of which die we choose, the expected value of the number shown is 3.5.\n\nSample Input 3\n\n10 4\n17 13 13 12 15 20 10 13 17 11\n\nSample Output 3\n\n32.000000000000", "sample_input": "5 3\n1 2 2 4 5\n"}, "reference_outputs": ["7.000000000000\n"], "source_document_id": "p02780", "source_text": "Score : 400 points\n\nProblem Statement\n\nWe have N dice arranged in a line from left to right. The i-th die from the left shows p_i numbers from 1 to p_i with equal probability when thrown.\n\nWe will choose K adjacent dice, throw each of them independently, and compute the sum of the numbers shown. Find the maximum possible value of the expected value of this sum.\n\nConstraints\n\n1 ≤ K ≤ N ≤ 200000\n\n1 ≤ p_i ≤ 1000\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\np_1 ... p_N\n\nOutput\n\nPrint the maximum possible value of the expected value of the sum of the numbers shown.\n\nYour output will be considered correct when its absolute or relative error from our answer is at most 10^{-6}.\n\nSample Input 1\n\n5 3\n1 2 2 4 5\n\nSample Output 1\n\n7.000000000000\n\nWhen we throw the third, fourth, and fifth dice from the left, the expected value of the sum of the numbers shown is 7. This is the maximum value we can achieve.\n\nSample Input 2\n\n4 1\n6 6 6 6\n\nSample Output 2\n\n3.500000000000\n\nRegardless of which die we choose, the expected value of the number shown is 3.5.\n\nSample Input 3\n\n10 4\n17 13 13 12 15 20 10 13 17 11\n\nSample Output 3\n\n32.000000000000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 431, "cpu_time_ms": 164, "memory_kb": 1024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s239339487", "group_id": "codeNet:p02780", "input_text": "//\n//AtCoder Beginner Contest 154\n//D - Dice in Line\n//\n\n#include <iostream>\n#include <algorithm>\n#include <vector>\n#include <iomanip>\n#include <cmath>\n#include <ctime>\n#include <queue>\n#include <map>\n#include <functional>\n\nusing namespace std;\n\n#define REP(i,n) for(ll i=0;i<(ll)(n);i++)\n#define REPD(i,n) for(ll i=n-1;i>=0;i--)\n#define FOR(i,a,b) for(ll i=a;i<=(ll)(b);i++)\n#define FORD(i,a,b) for(ll i=a;i>=(ll)(b);i--)\n#define ALL(x) (x).begin(),(x).end()\n#define RALL(x) (x).rbegin(),(x).rend()\n\nusing ll = long long;\nusing ld = long double;\n\nconst double PI = 3.14159265358979323846;\n\nll gcd(ll x, ll y) { return (x % y)? gcd(y, x % y): y; }    //最大公約数\nll lcm(ll x, ll y) { return x / gcd(x, y) * y; }            //最小公倍数\n\nint main()\n{\n    int n, k;\n\n    cin >> n >> k;\n\n    int p[n];\n    \n    REP(i, n) cin >> p[i];\n\n    vector<ld> sumList;\n\n    ld sum = 0;\n    REP(i, n){\n        sum += (1.0+(ld)p[i])/2.0;\n        sumList.push_back(sum);\n    }\n\n    ld ans = 0;\n    if (n == k) ans = sum;\n    else{\n        REP(i, n-k){\n            ans = max(ans, sumList[i+k] - sumList[i]);\n        }\n    }\n    \n    cout << fixed;\n    cout << setprecision(12) << ans << endl;\n\n    return 0;\n}\n\n", "language": "C++", "metadata": {"date": 1589469146, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02780.html", "problem_id": "p02780", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02780/input.txt", "sample_output_relpath": "derived/input_output/data/p02780/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02780/C++/s239339487.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s239339487", "user_id": "u506417357"}, "prompt_components": {"gold_output": "7.000000000000\n", "input_to_evaluate": "//\n//AtCoder Beginner Contest 154\n//D - Dice in Line\n//\n\n#include <iostream>\n#include <algorithm>\n#include <vector>\n#include <iomanip>\n#include <cmath>\n#include <ctime>\n#include <queue>\n#include <map>\n#include <functional>\n\nusing namespace std;\n\n#define REP(i,n) for(ll i=0;i<(ll)(n);i++)\n#define REPD(i,n) for(ll i=n-1;i>=0;i--)\n#define FOR(i,a,b) for(ll i=a;i<=(ll)(b);i++)\n#define FORD(i,a,b) for(ll i=a;i>=(ll)(b);i--)\n#define ALL(x) (x).begin(),(x).end()\n#define RALL(x) (x).rbegin(),(x).rend()\n\nusing ll = long long;\nusing ld = long double;\n\nconst double PI = 3.14159265358979323846;\n\nll gcd(ll x, ll y) { return (x % y)? gcd(y, x % y): y; }    //最大公約数\nll lcm(ll x, ll y) { return x / gcd(x, y) * y; }            //最小公倍数\n\nint main()\n{\n    int n, k;\n\n    cin >> n >> k;\n\n    int p[n];\n    \n    REP(i, n) cin >> p[i];\n\n    vector<ld> sumList;\n\n    ld sum = 0;\n    REP(i, n){\n        sum += (1.0+(ld)p[i])/2.0;\n        sumList.push_back(sum);\n    }\n\n    ld ans = 0;\n    if (n == k) ans = sum;\n    else{\n        REP(i, n-k){\n            ans = max(ans, sumList[i+k] - sumList[i]);\n        }\n    }\n    \n    cout << fixed;\n    cout << setprecision(12) << ans << endl;\n\n    return 0;\n}\n\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nWe have N dice arranged in a line from left to right. The i-th die from the left shows p_i numbers from 1 to p_i with equal probability when thrown.\n\nWe will choose K adjacent dice, throw each of them independently, and compute the sum of the numbers shown. Find the maximum possible value of the expected value of this sum.\n\nConstraints\n\n1 ≤ K ≤ N ≤ 200000\n\n1 ≤ p_i ≤ 1000\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\np_1 ... p_N\n\nOutput\n\nPrint the maximum possible value of the expected value of the sum of the numbers shown.\n\nYour output will be considered correct when its absolute or relative error from our answer is at most 10^{-6}.\n\nSample Input 1\n\n5 3\n1 2 2 4 5\n\nSample Output 1\n\n7.000000000000\n\nWhen we throw the third, fourth, and fifth dice from the left, the expected value of the sum of the numbers shown is 7. This is the maximum value we can achieve.\n\nSample Input 2\n\n4 1\n6 6 6 6\n\nSample Output 2\n\n3.500000000000\n\nRegardless of which die we choose, the expected value of the number shown is 3.5.\n\nSample Input 3\n\n10 4\n17 13 13 12 15 20 10 13 17 11\n\nSample Output 3\n\n32.000000000000", "sample_input": "5 3\n1 2 2 4 5\n"}, "reference_outputs": ["7.000000000000\n"], "source_document_id": "p02780", "source_text": "Score : 400 points\n\nProblem Statement\n\nWe have N dice arranged in a line from left to right. The i-th die from the left shows p_i numbers from 1 to p_i with equal probability when thrown.\n\nWe will choose K adjacent dice, throw each of them independently, and compute the sum of the numbers shown. Find the maximum possible value of the expected value of this sum.\n\nConstraints\n\n1 ≤ K ≤ N ≤ 200000\n\n1 ≤ p_i ≤ 1000\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\np_1 ... p_N\n\nOutput\n\nPrint the maximum possible value of the expected value of the sum of the numbers shown.\n\nYour output will be considered correct when its absolute or relative error from our answer is at most 10^{-6}.\n\nSample Input 1\n\n5 3\n1 2 2 4 5\n\nSample Output 1\n\n7.000000000000\n\nWhen we throw the third, fourth, and fifth dice from the left, the expected value of the sum of the numbers shown is 7. This is the maximum value we can achieve.\n\nSample Input 2\n\n4 1\n6 6 6 6\n\nSample Output 2\n\n3.500000000000\n\nRegardless of which die we choose, the expected value of the number shown is 3.5.\n\nSample Input 3\n\n10 4\n17 13 13 12 15 20 10 13 17 11\n\nSample Output 3\n\n32.000000000000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1205, "cpu_time_ms": 53, "memory_kb": 7280}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s072262132", "group_id": "codeNet:p02780", "input_text": "#include <algorithm>\n#include <iomanip>\n#include <iostream>\n\nusing namespace std;\n\nint main()\n{\n  int n, k; cin >> n >> k;\n  int p[200000]; for (int i = 0; i < n; ++i) cin >> p[i];\n  \n  int sum = 0;\n  for (int i = 0; i < k; ++i) sum += p[i];\n  int mx = sum;\n  for (int i = k; i < n; ++i) {\n    sum += p[i] - p[i-k]; mx = max(mx, sum);\n  }\n  \n  double ans = (mx+k)/2.0;\n  cout << fixed << setprecision(12) << ans << endl;\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1585271410, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02780.html", "problem_id": "p02780", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02780/input.txt", "sample_output_relpath": "derived/input_output/data/p02780/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02780/C++/s072262132.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s072262132", "user_id": "u896847891"}, "prompt_components": {"gold_output": "7.000000000000\n", "input_to_evaluate": "#include <algorithm>\n#include <iomanip>\n#include <iostream>\n\nusing namespace std;\n\nint main()\n{\n  int n, k; cin >> n >> k;\n  int p[200000]; for (int i = 0; i < n; ++i) cin >> p[i];\n  \n  int sum = 0;\n  for (int i = 0; i < k; ++i) sum += p[i];\n  int mx = sum;\n  for (int i = k; i < n; ++i) {\n    sum += p[i] - p[i-k]; mx = max(mx, sum);\n  }\n  \n  double ans = (mx+k)/2.0;\n  cout << fixed << setprecision(12) << ans << endl;\n  return 0;\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nWe have N dice arranged in a line from left to right. The i-th die from the left shows p_i numbers from 1 to p_i with equal probability when thrown.\n\nWe will choose K adjacent dice, throw each of them independently, and compute the sum of the numbers shown. Find the maximum possible value of the expected value of this sum.\n\nConstraints\n\n1 ≤ K ≤ N ≤ 200000\n\n1 ≤ p_i ≤ 1000\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\np_1 ... p_N\n\nOutput\n\nPrint the maximum possible value of the expected value of the sum of the numbers shown.\n\nYour output will be considered correct when its absolute or relative error from our answer is at most 10^{-6}.\n\nSample Input 1\n\n5 3\n1 2 2 4 5\n\nSample Output 1\n\n7.000000000000\n\nWhen we throw the third, fourth, and fifth dice from the left, the expected value of the sum of the numbers shown is 7. This is the maximum value we can achieve.\n\nSample Input 2\n\n4 1\n6 6 6 6\n\nSample Output 2\n\n3.500000000000\n\nRegardless of which die we choose, the expected value of the number shown is 3.5.\n\nSample Input 3\n\n10 4\n17 13 13 12 15 20 10 13 17 11\n\nSample Output 3\n\n32.000000000000", "sample_input": "5 3\n1 2 2 4 5\n"}, "reference_outputs": ["7.000000000000\n"], "source_document_id": "p02780", "source_text": "Score : 400 points\n\nProblem Statement\n\nWe have N dice arranged in a line from left to right. The i-th die from the left shows p_i numbers from 1 to p_i with equal probability when thrown.\n\nWe will choose K adjacent dice, throw each of them independently, and compute the sum of the numbers shown. Find the maximum possible value of the expected value of this sum.\n\nConstraints\n\n1 ≤ K ≤ N ≤ 200000\n\n1 ≤ p_i ≤ 1000\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\np_1 ... p_N\n\nOutput\n\nPrint the maximum possible value of the expected value of the sum of the numbers shown.\n\nYour output will be considered correct when its absolute or relative error from our answer is at most 10^{-6}.\n\nSample Input 1\n\n5 3\n1 2 2 4 5\n\nSample Output 1\n\n7.000000000000\n\nWhen we throw the third, fourth, and fifth dice from the left, the expected value of the sum of the numbers shown is 7. This is the maximum value we can achieve.\n\nSample Input 2\n\n4 1\n6 6 6 6\n\nSample Output 2\n\n3.500000000000\n\nRegardless of which die we choose, the expected value of the number shown is 3.5.\n\nSample Input 3\n\n10 4\n17 13 13 12 15 20 10 13 17 11\n\nSample Output 3\n\n32.000000000000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 435, "cpu_time_ms": 63, "memory_kb": 1024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s510389062", "group_id": "codeNet:p02783", "input_text": "#include <iostream>\nusing namespace std;\n\nint main() {\n\tint a,b;\n\tcin >> a >> b;\n\tif(a%b==0)cout << a/b << '\\n';\n\telse cout << a/b+1 << '\\n';\n}", "language": "C++", "metadata": {"date": 1580080310, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02783.html", "problem_id": "p02783", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02783/input.txt", "sample_output_relpath": "derived/input_output/data/p02783/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02783/C++/s510389062.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s510389062", "user_id": "u184704421"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <iostream>\nusing namespace std;\n\nint main() {\n\tint a,b;\n\tcin >> a >> b;\n\tif(a%b==0)cout << a/b << '\\n';\n\telse cout << a/b+1 << '\\n';\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nServal is fighting with a monster.\n\nThe health of the monster is H.\n\nIn one attack, Serval can decrease the monster's health by A.\nThere is no other way to decrease the monster's health.\n\nServal wins when the monster's health becomes 0 or below.\n\nFind the number of attacks Serval needs to make before winning.\n\nConstraints\n\n1 \\leq H \\leq 10^4\n\n1 \\leq A \\leq 10^4\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH A\n\nOutput\n\nPrint the number of attacks Serval needs to make before winning.\n\nSample Input 1\n\n10 4\n\nSample Output 1\n\n3\n\nAfter one attack, the monster's health will be 6.\n\nAfter two attacks, the monster's health will be 2.\n\nAfter three attacks, the monster's health will be -2.\n\nThus, Serval needs to make three attacks to win.\n\nSample Input 2\n\n1 10000\n\nSample Output 2\n\n1\n\nSample Input 3\n\n10000 1\n\nSample Output 3\n\n10000", "sample_input": "10 4\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02783", "source_text": "Score : 100 points\n\nProblem Statement\n\nServal is fighting with a monster.\n\nThe health of the monster is H.\n\nIn one attack, Serval can decrease the monster's health by A.\nThere is no other way to decrease the monster's health.\n\nServal wins when the monster's health becomes 0 or below.\n\nFind the number of attacks Serval needs to make before winning.\n\nConstraints\n\n1 \\leq H \\leq 10^4\n\n1 \\leq A \\leq 10^4\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH A\n\nOutput\n\nPrint the number of attacks Serval needs to make before winning.\n\nSample Input 1\n\n10 4\n\nSample Output 1\n\n3\n\nAfter one attack, the monster's health will be 6.\n\nAfter two attacks, the monster's health will be 2.\n\nAfter three attacks, the monster's health will be -2.\n\nThus, Serval needs to make three attacks to win.\n\nSample Input 2\n\n1 10000\n\nSample Output 2\n\n1\n\nSample Input 3\n\n10000 1\n\nSample Output 3\n\n10000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 143, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s060290378", "group_id": "codeNet:p02784", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n    int h,n;\n  cin>>h>>n;\n  int c,sum=0;\n  for(int i=0;i<n;i++)\n  {\n    cin>>c;\n    sum +=c;\n  }\n  if(sum>=h)\n     cout<<\"Yes\"<<endl;\n  else\n     cout<<\"No\"<<endl;\n  return 0;\n}", "language": "C++", "metadata": {"date": 1580168769, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02784.html", "problem_id": "p02784", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02784/input.txt", "sample_output_relpath": "derived/input_output/data/p02784/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02784/C++/s060290378.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s060290378", "user_id": "u393332137"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n    int h,n;\n  cin>>h>>n;\n  int c,sum=0;\n  for(int i=0;i<n;i++)\n  {\n    cin>>c;\n    sum +=c;\n  }\n  if(sum>=h)\n     cout<<\"Yes\"<<endl;\n  else\n     cout<<\"No\"<<endl;\n  return 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nRaccoon is fighting with a monster.\n\nThe health of the monster is H.\n\nRaccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i.\nThere is no other way to decrease the monster's health.\n\nRaccoon wins when the monster's health becomes 0 or below.\n\nIf Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.\n\nConstraints\n\n1 \\leq H \\leq 10^9\n\n1 \\leq N \\leq 10^5\n\n1 \\leq A_i \\leq 10^4\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH N\nA_1 A_2 ... A_N\n\nOutput\n\nIf Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.\n\nSample Input 1\n\n10 3\n4 5 6\n\nSample Output 1\n\nYes\n\nThe monster's health will become 0 or below after, for example, using the second and third moves.\n\nSample Input 2\n\n20 3\n4 5 6\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n210 5\n31 41 59 26 53\n\nSample Output 3\n\nYes\n\nSample Input 4\n\n211 5\n31 41 59 26 53\n\nSample Output 4\n\nNo", "sample_input": "10 3\n4 5 6\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p02784", "source_text": "Score : 200 points\n\nProblem Statement\n\nRaccoon is fighting with a monster.\n\nThe health of the monster is H.\n\nRaccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i.\nThere is no other way to decrease the monster's health.\n\nRaccoon wins when the monster's health becomes 0 or below.\n\nIf Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.\n\nConstraints\n\n1 \\leq H \\leq 10^9\n\n1 \\leq N \\leq 10^5\n\n1 \\leq A_i \\leq 10^4\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH N\nA_1 A_2 ... A_N\n\nOutput\n\nIf Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.\n\nSample Input 1\n\n10 3\n4 5 6\n\nSample Output 1\n\nYes\n\nThe monster's health will become 0 or below after, for example, using the second and third moves.\n\nSample Input 2\n\n20 3\n4 5 6\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n210 5\n31 41 59 26 53\n\nSample Output 3\n\nYes\n\nSample Input 4\n\n211 5\n31 41 59 26 53\n\nSample Output 4\n\nNo", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 235, "cpu_time_ms": 36, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s290922763", "group_id": "codeNet:p02784", "input_text": "#include <bits/stdc++.h>\n#define rep(i, x, N) for (long long i = x; i < (N); i++)\nusing namespace std;\nint main()\n{\n\tint N,H;\n\tcin>>H>>N;\n\tvector<int>A(N);\n\tint sum=0;\n\trep(i,0,N){\n\t\tcin>>A[i];\n\t\tsum+=A[i];\n\t}\n\tif(H<=sum){\n\t\tcout<<\"Yes\"<<endl;\n\t}\n\telse{\n\t\tcout<<\"No\"<<endl;\n\t}\n\n\n}\n\n", "language": "C++", "metadata": {"date": 1580070467, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02784.html", "problem_id": "p02784", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02784/input.txt", "sample_output_relpath": "derived/input_output/data/p02784/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02784/C++/s290922763.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s290922763", "user_id": "u466393447"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define rep(i, x, N) for (long long i = x; i < (N); i++)\nusing namespace std;\nint main()\n{\n\tint N,H;\n\tcin>>H>>N;\n\tvector<int>A(N);\n\tint sum=0;\n\trep(i,0,N){\n\t\tcin>>A[i];\n\t\tsum+=A[i];\n\t}\n\tif(H<=sum){\n\t\tcout<<\"Yes\"<<endl;\n\t}\n\telse{\n\t\tcout<<\"No\"<<endl;\n\t}\n\n\n}\n\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nRaccoon is fighting with a monster.\n\nThe health of the monster is H.\n\nRaccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i.\nThere is no other way to decrease the monster's health.\n\nRaccoon wins when the monster's health becomes 0 or below.\n\nIf Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.\n\nConstraints\n\n1 \\leq H \\leq 10^9\n\n1 \\leq N \\leq 10^5\n\n1 \\leq A_i \\leq 10^4\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH N\nA_1 A_2 ... A_N\n\nOutput\n\nIf Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.\n\nSample Input 1\n\n10 3\n4 5 6\n\nSample Output 1\n\nYes\n\nThe monster's health will become 0 or below after, for example, using the second and third moves.\n\nSample Input 2\n\n20 3\n4 5 6\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n210 5\n31 41 59 26 53\n\nSample Output 3\n\nYes\n\nSample Input 4\n\n211 5\n31 41 59 26 53\n\nSample Output 4\n\nNo", "sample_input": "10 3\n4 5 6\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p02784", "source_text": "Score : 200 points\n\nProblem Statement\n\nRaccoon is fighting with a monster.\n\nThe health of the monster is H.\n\nRaccoon can use N kinds of special moves. Using the i-th move decreases the monster's health by A_i.\nThere is no other way to decrease the monster's health.\n\nRaccoon wins when the monster's health becomes 0 or below.\n\nIf Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.\n\nConstraints\n\n1 \\leq H \\leq 10^9\n\n1 \\leq N \\leq 10^5\n\n1 \\leq A_i \\leq 10^4\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH N\nA_1 A_2 ... A_N\n\nOutput\n\nIf Raccoon can win without using the same move twice or more, print Yes; otherwise, print No.\n\nSample Input 1\n\n10 3\n4 5 6\n\nSample Output 1\n\nYes\n\nThe monster's health will become 0 or below after, for example, using the second and third moves.\n\nSample Input 2\n\n20 3\n4 5 6\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n210 5\n31 41 59 26 53\n\nSample Output 3\n\nYes\n\nSample Input 4\n\n211 5\n31 41 59 26 53\n\nSample Output 4\n\nNo", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 282, "cpu_time_ms": 29, "memory_kb": 640}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s186581521", "group_id": "codeNet:p02785", "input_text": "#include<bits/stdc++.h>                          \nusing namespace std;\nbool cmp(int x,int y)\n{\n\treturn x>y;\n}\nlong long n,k,a[200005],ans,h;\nint main(){\n    cin>>n>>k;\n    for(int i=1;i<=n;i++)\n        cin>>a[i],ans+=a[i];\n    sort(a+1,a+1+n,cmp);\n    h=min(k,n);\n    for(int i=1;i<=h;i++) ans-=a[i];\n    cout<<ans;\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1585130739, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02785.html", "problem_id": "p02785", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02785/input.txt", "sample_output_relpath": "derived/input_output/data/p02785/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02785/C++/s186581521.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s186581521", "user_id": "u469639111"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include<bits/stdc++.h>                          \nusing namespace std;\nbool cmp(int x,int y)\n{\n\treturn x>y;\n}\nlong long n,k,a[200005],ans,h;\nint main(){\n    cin>>n>>k;\n    for(int i=1;i<=n;i++)\n        cin>>a[i],ans+=a[i];\n    sort(a+1,a+1+n,cmp);\n    h=min(k,n);\n    for(int i=1;i<=h;i++) ans-=a[i];\n    cout<<ans;\n\treturn 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nFennec is fighting with N monsters.\n\nThe health of the i-th monster is H_i.\n\nFennec can do the following two actions:\n\nAttack: Fennec chooses one monster. That monster's health will decrease by 1.\n\nSpecial Move: Fennec chooses one monster. That monster's health will become 0.\n\nThere is no way other than Attack and Special Move to decrease the monsters' health.\n\nFennec wins when all the monsters' healths become 0 or below.\n\nFind the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\n0 \\leq K \\leq 2 \\times 10^5\n\n1 \\leq H_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nH_1 ... H_N\n\nOutput\n\nPrint the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning.\n\nSample Input 1\n\n3 1\n4 1 5\n\nSample Output 1\n\n5\n\nBy using Special Move on the third monster, and doing Attack four times on the first monster and once on the second monster, Fennec can win with five Attacks.\n\nSample Input 2\n\n8 9\n7 9 3 2 3 8 4 6\n\nSample Output 2\n\n0\n\nShe can use Special Move on all the monsters.\n\nSample Input 3\n\n3 0\n1000000000 1000000000 1000000000\n\nSample Output 3\n\n3000000000\n\nWatch out for overflow.", "sample_input": "3 1\n4 1 5\n"}, "reference_outputs": ["5\n"], "source_document_id": "p02785", "source_text": "Score : 300 points\n\nProblem Statement\n\nFennec is fighting with N monsters.\n\nThe health of the i-th monster is H_i.\n\nFennec can do the following two actions:\n\nAttack: Fennec chooses one monster. That monster's health will decrease by 1.\n\nSpecial Move: Fennec chooses one monster. That monster's health will become 0.\n\nThere is no way other than Attack and Special Move to decrease the monsters' health.\n\nFennec wins when all the monsters' healths become 0 or below.\n\nFind the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\n0 \\leq K \\leq 2 \\times 10^5\n\n1 \\leq H_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nH_1 ... H_N\n\nOutput\n\nPrint the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning.\n\nSample Input 1\n\n3 1\n4 1 5\n\nSample Output 1\n\n5\n\nBy using Special Move on the third monster, and doing Attack four times on the first monster and once on the second monster, Fennec can win with five Attacks.\n\nSample Input 2\n\n8 9\n7 9 3 2 3 8 4 6\n\nSample Output 2\n\n0\n\nShe can use Special Move on all the monsters.\n\nSample Input 3\n\n3 0\n1000000000 1000000000 1000000000\n\nSample Output 3\n\n3000000000\n\nWatch out for overflow.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 328, "cpu_time_ms": 96, "memory_kb": 1792}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s894621031", "group_id": "codeNet:p02785", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\n#define REP(i,n) for (ll i = 0; i < (n); ++i)\n\n\nvoid solve(long long N, long long K, std::vector<long long> H){\n    sort(H.begin(), H.end());\n    ll ans = 0;\n    for(ll i = 0; i < N - K; ++i){\n        ans += H.at(i);\n    }\n    cout << ans << endl;\n}\n\n// Generated by 1.1.6 https://github.com/kyuridenamida/atcoder-tools\nint main(){\n    long long N;\n    scanf(\"%lld\",&N);\n    long long K;\n    scanf(\"%lld\",&K);\n    std::vector<long long> H(N);\n    for(int i = 0 ; i < N ; i++){\n        scanf(\"%lld\",&H[i]);\n    }\n    solve(N, K, std::move(H));\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1584949718, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02785.html", "problem_id": "p02785", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02785/input.txt", "sample_output_relpath": "derived/input_output/data/p02785/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02785/C++/s894621031.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s894621031", "user_id": "u455757400"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\n#define REP(i,n) for (ll i = 0; i < (n); ++i)\n\n\nvoid solve(long long N, long long K, std::vector<long long> H){\n    sort(H.begin(), H.end());\n    ll ans = 0;\n    for(ll i = 0; i < N - K; ++i){\n        ans += H.at(i);\n    }\n    cout << ans << endl;\n}\n\n// Generated by 1.1.6 https://github.com/kyuridenamida/atcoder-tools\nint main(){\n    long long N;\n    scanf(\"%lld\",&N);\n    long long K;\n    scanf(\"%lld\",&K);\n    std::vector<long long> H(N);\n    for(int i = 0 ; i < N ; i++){\n        scanf(\"%lld\",&H[i]);\n    }\n    solve(N, K, std::move(H));\n    return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nFennec is fighting with N monsters.\n\nThe health of the i-th monster is H_i.\n\nFennec can do the following two actions:\n\nAttack: Fennec chooses one monster. That monster's health will decrease by 1.\n\nSpecial Move: Fennec chooses one monster. That monster's health will become 0.\n\nThere is no way other than Attack and Special Move to decrease the monsters' health.\n\nFennec wins when all the monsters' healths become 0 or below.\n\nFind the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\n0 \\leq K \\leq 2 \\times 10^5\n\n1 \\leq H_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nH_1 ... H_N\n\nOutput\n\nPrint the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning.\n\nSample Input 1\n\n3 1\n4 1 5\n\nSample Output 1\n\n5\n\nBy using Special Move on the third monster, and doing Attack four times on the first monster and once on the second monster, Fennec can win with five Attacks.\n\nSample Input 2\n\n8 9\n7 9 3 2 3 8 4 6\n\nSample Output 2\n\n0\n\nShe can use Special Move on all the monsters.\n\nSample Input 3\n\n3 0\n1000000000 1000000000 1000000000\n\nSample Output 3\n\n3000000000\n\nWatch out for overflow.", "sample_input": "3 1\n4 1 5\n"}, "reference_outputs": ["5\n"], "source_document_id": "p02785", "source_text": "Score : 300 points\n\nProblem Statement\n\nFennec is fighting with N monsters.\n\nThe health of the i-th monster is H_i.\n\nFennec can do the following two actions:\n\nAttack: Fennec chooses one monster. That monster's health will decrease by 1.\n\nSpecial Move: Fennec chooses one monster. That monster's health will become 0.\n\nThere is no way other than Attack and Special Move to decrease the monsters' health.\n\nFennec wins when all the monsters' healths become 0 or below.\n\nFind the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning when she can use Special Move at most K times.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\n0 \\leq K \\leq 2 \\times 10^5\n\n1 \\leq H_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nH_1 ... H_N\n\nOutput\n\nPrint the minimum number of times Fennec needs to do Attack (not counting Special Move) before winning.\n\nSample Input 1\n\n3 1\n4 1 5\n\nSample Output 1\n\n5\n\nBy using Special Move on the third monster, and doing Attack four times on the first monster and once on the second monster, Fennec can win with five Attacks.\n\nSample Input 2\n\n8 9\n7 9 3 2 3 8 4 6\n\nSample Output 2\n\n0\n\nShe can use Special Move on all the monsters.\n\nSample Input 3\n\n3 0\n1000000000 1000000000 1000000000\n\nSample Output 3\n\n3000000000\n\nWatch out for overflow.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 659, "cpu_time_ms": 38, "memory_kb": 1792}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s249435138", "group_id": "codeNet:p02786", "input_text": "#include <iostream>\n#include <string>\n#include <set>\n#include <algorithm>\nusing namespace std;\n\nint main() {\n\n    unsigned long h;\n    cin >> h;\n\n    long ans = 0;\n    long num = 1;\n    while ( h > 0 ) {\n        ans += num;\n        num *= 2;\n        h /= 2;\n    }\n    \n    cout << ans << endl;\n}", "language": "C++", "metadata": {"date": 1580071516, "filename_ext": "cpp", "original_language": "C++14 (Clang 3.8.0)", "problem_description_relpath": "problem_descriptions/p02786.html", "problem_id": "p02786", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02786/input.txt", "sample_output_relpath": "derived/input_output/data/p02786/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02786/C++/s249435138.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s249435138", "user_id": "u519759783"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <iostream>\n#include <string>\n#include <set>\n#include <algorithm>\nusing namespace std;\n\nint main() {\n\n    unsigned long h;\n    cin >> h;\n\n    long ans = 0;\n    long num = 1;\n    while ( h > 0 ) {\n        ans += num;\n        num *= 2;\n        h /= 2;\n    }\n    \n    cout << ans << endl;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nCaracal is fighting with a monster.\n\nThe health of the monster is H.\n\nCaracal can attack by choosing one monster. When a monster is attacked, depending on that monster's health, the following happens:\n\nIf the monster's health is 1, it drops to 0.\n\nIf the monster's health, X, is greater than 1, that monster disappears. Then, two new monsters appear, each with the health of \\lfloor X/2 \\rfloor.\n\n(\\lfloor r \\rfloor denotes the greatest integer not exceeding r.)\n\nCaracal wins when the healths of all existing monsters become 0 or below.\n\nFind the minimum number of attacks Caracal needs to make before winning.\n\nConstraints\n\n1 \\leq H \\leq 10^{12}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH\n\nOutput\n\nFind the minimum number of attacks Caracal needs to make before winning.\n\nSample Input 1\n\n2\n\nSample Output 1\n\n3\n\nWhen Caracal attacks the initial monster, it disappears, and two monsters appear, each with the health of 1.\n\nThen, Caracal can attack each of these new monsters once and win with a total of three attacks.\n\nSample Input 2\n\n4\n\nSample Output 2\n\n7\n\nSample Input 3\n\n1000000000000\n\nSample Output 3\n\n1099511627775", "sample_input": "2\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02786", "source_text": "Score : 400 points\n\nProblem Statement\n\nCaracal is fighting with a monster.\n\nThe health of the monster is H.\n\nCaracal can attack by choosing one monster. When a monster is attacked, depending on that monster's health, the following happens:\n\nIf the monster's health is 1, it drops to 0.\n\nIf the monster's health, X, is greater than 1, that monster disappears. Then, two new monsters appear, each with the health of \\lfloor X/2 \\rfloor.\n\n(\\lfloor r \\rfloor denotes the greatest integer not exceeding r.)\n\nCaracal wins when the healths of all existing monsters become 0 or below.\n\nFind the minimum number of attacks Caracal needs to make before winning.\n\nConstraints\n\n1 \\leq H \\leq 10^{12}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH\n\nOutput\n\nFind the minimum number of attacks Caracal needs to make before winning.\n\nSample Input 1\n\n2\n\nSample Output 1\n\n3\n\nWhen Caracal attacks the initial monster, it disappears, and two monsters appear, each with the health of 1.\n\nThen, Caracal can attack each of these new monsters once and win with a total of three attacks.\n\nSample Input 2\n\n4\n\nSample Output 2\n\n7\n\nSample Input 3\n\n1000000000000\n\nSample Output 3\n\n1099511627775", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 295, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s689579608", "group_id": "codeNet:p02788", "input_text": "//MADE BY Y_is_sunshine;\n//#include <bits/stdc++.h>\n//#include <memory.h>\n#include <algorithm>\n#include <iostream>\n#include <cstdlib>\n#include <cstring>\n#include <sstream>\n#include <cstdio>\n#include <vector>\n#include <string>\n#include <cmath>\n#include <queue>\n#include <stack>\n#include <map>\n#include <set>\n\n#define INF 0x3f3f3f3f\n#define MAXN 200005\n\ntypedef long long ll;\n\nconst ll mod = 1e9 + 7;\nconst double PI = acos(-1);\n\nusing namespace std;\n\nint N, M, K;\n\nstruct node {\n\tll at;\n\tll cost;\n\tbool operator < (const node a) const {\n\t\treturn this->at < a.at;\n\t}\n}p[MAXN];\n\nint main(void)\n{\n#ifdef Sunshine\n\tfreopen(\"data.txt\", \"r\", stdin);\n#endif\n\n\tios_base::sync_with_stdio(false);\n\tcin.tie(NULL);\n\n\tll N, M, K;\n\tcin >> N >> M >> K;\n\tM *= 2;\n\tfor (int i = 1; i <= N; i++)\n\t\tcin >> p[i].at >> p[i].cost;\n\n\tsort(p + 1, p + 1 + N);\n\tll ans = 0;\n\n\tfor (int i = 1; i <= N; i++) {\n\t\tif (p[i].cost <= 0)\n\t\t\tcontinue;\n\t\tint j = i + 1;\n\t\tll res = p[i].cost / K + (p[i].cost % K == 0ll ? 0 : 1);\n\t\tans += res;\n\t\tfor (; j <= N; j++) {\n\t\t\tif (p[j].at > p[i].at + M)\n\t\t\t\tbreak;\n\t\t\telse\n\t\t\t\tp[j].cost -= res;\n\t\t}\n\t}\n\n\tcout << ans << '\\n';\n\t\n\n\n\n#ifdef Sunshine\n\tfreopen(\"CON\", \"r\", stdin);\n\tsystem(\"pause\");\n#endif\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1580072751, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02788.html", "problem_id": "p02788", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02788/input.txt", "sample_output_relpath": "derived/input_output/data/p02788/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02788/C++/s689579608.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s689579608", "user_id": "u717365311"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "//MADE BY Y_is_sunshine;\n//#include <bits/stdc++.h>\n//#include <memory.h>\n#include <algorithm>\n#include <iostream>\n#include <cstdlib>\n#include <cstring>\n#include <sstream>\n#include <cstdio>\n#include <vector>\n#include <string>\n#include <cmath>\n#include <queue>\n#include <stack>\n#include <map>\n#include <set>\n\n#define INF 0x3f3f3f3f\n#define MAXN 200005\n\ntypedef long long ll;\n\nconst ll mod = 1e9 + 7;\nconst double PI = acos(-1);\n\nusing namespace std;\n\nint N, M, K;\n\nstruct node {\n\tll at;\n\tll cost;\n\tbool operator < (const node a) const {\n\t\treturn this->at < a.at;\n\t}\n}p[MAXN];\n\nint main(void)\n{\n#ifdef Sunshine\n\tfreopen(\"data.txt\", \"r\", stdin);\n#endif\n\n\tios_base::sync_with_stdio(false);\n\tcin.tie(NULL);\n\n\tll N, M, K;\n\tcin >> N >> M >> K;\n\tM *= 2;\n\tfor (int i = 1; i <= N; i++)\n\t\tcin >> p[i].at >> p[i].cost;\n\n\tsort(p + 1, p + 1 + N);\n\tll ans = 0;\n\n\tfor (int i = 1; i <= N; i++) {\n\t\tif (p[i].cost <= 0)\n\t\t\tcontinue;\n\t\tint j = i + 1;\n\t\tll res = p[i].cost / K + (p[i].cost % K == 0ll ? 0 : 1);\n\t\tans += res;\n\t\tfor (; j <= N; j++) {\n\t\t\tif (p[j].at > p[i].at + M)\n\t\t\t\tbreak;\n\t\t\telse\n\t\t\t\tp[j].cost -= res;\n\t\t}\n\t}\n\n\tcout << ans << '\\n';\n\t\n\n\n\n#ifdef Sunshine\n\tfreopen(\"CON\", \"r\", stdin);\n\tsystem(\"pause\");\n#endif\n\treturn 0;\n}", "problem_context": "Score : 600 points\n\nProblem Statement\n\nSilver Fox is fighting with N monsters.\n\nThe monsters are standing in a row, and we can assume them to be standing on a number line. The i-th monster, standing at the coordinate X_i, has the health of H_i.\n\nSilver Fox can use bombs to attack the monsters.\nUsing a bomb at the coordinate x decreases the healths of all monsters between the coordinates x-D and x+D (inclusive) by A.\nThere is no way other than bombs to decrease the monster's health.\n\nSilver Fox wins when all the monsters' healths become 0 or below.\n\nFind the minimum number of bombs needed to win.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\n0 \\leq D \\leq 10^9\n\n1 \\leq A \\leq 10^9\n\n0 \\leq X_i \\leq 10^9\n\n1 \\leq H_i \\leq 10^9\n\nX_i are distinct.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN D A\nX_1 H_1\n:\nX_N H_N\n\nOutput\n\nPrint the minimum number of bombs needed to win.\n\nSample Input 1\n\n3 3 2\n1 2\n5 4\n9 2\n\nSample Output 1\n\n2\n\nFirst, let us use a bomb at the coordinate 4 to decrease the first and second monsters' health by 2.\n\nThen, use a bomb at the coordinate 6 to decrease the second and third monsters' health by 2.\n\nNow, all the monsters' healths are 0.\nWe cannot make all the monsters' health drop to 0 or below with just one bomb.\n\nSample Input 2\n\n9 4 1\n1 5\n2 4\n3 3\n4 2\n5 1\n6 2\n7 3\n8 4\n9 5\n\nSample Output 2\n\n5\n\nWe should use five bombs at the coordinate 5.\n\nSample Input 3\n\n3 0 1\n300000000 1000000000\n100000000 1000000000\n200000000 1000000000\n\nSample Output 3\n\n3000000000\n\nWatch out for overflow.", "sample_input": "3 3 2\n1 2\n5 4\n9 2\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02788", "source_text": "Score : 600 points\n\nProblem Statement\n\nSilver Fox is fighting with N monsters.\n\nThe monsters are standing in a row, and we can assume them to be standing on a number line. The i-th monster, standing at the coordinate X_i, has the health of H_i.\n\nSilver Fox can use bombs to attack the monsters.\nUsing a bomb at the coordinate x decreases the healths of all monsters between the coordinates x-D and x+D (inclusive) by A.\nThere is no way other than bombs to decrease the monster's health.\n\nSilver Fox wins when all the monsters' healths become 0 or below.\n\nFind the minimum number of bombs needed to win.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\n0 \\leq D \\leq 10^9\n\n1 \\leq A \\leq 10^9\n\n0 \\leq X_i \\leq 10^9\n\n1 \\leq H_i \\leq 10^9\n\nX_i are distinct.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN D A\nX_1 H_1\n:\nX_N H_N\n\nOutput\n\nPrint the minimum number of bombs needed to win.\n\nSample Input 1\n\n3 3 2\n1 2\n5 4\n9 2\n\nSample Output 1\n\n2\n\nFirst, let us use a bomb at the coordinate 4 to decrease the first and second monsters' health by 2.\n\nThen, use a bomb at the coordinate 6 to decrease the second and third monsters' health by 2.\n\nNow, all the monsters' healths are 0.\nWe cannot make all the monsters' health drop to 0 or below with just one bomb.\n\nSample Input 2\n\n9 4 1\n1 5\n2 4\n3 3\n4 2\n5 1\n6 2\n7 3\n8 4\n9 5\n\nSample Output 2\n\n5\n\nWe should use five bombs at the coordinate 5.\n\nSample Input 3\n\n3 0 1\n300000000 1000000000\n100000000 1000000000\n200000000 1000000000\n\nSample Output 3\n\n3000000000\n\nWatch out for overflow.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1216, "cpu_time_ms": 2103, "memory_kb": 3328}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s644570189", "group_id": "codeNet:p02790", "input_text": "#pragma GCC optimize(\"Ofast,unroll-loops,no-stack-protector,fast-math\")\n#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n \n#include<bits/stdc++.h>\n#include<iostream>\n#include<cstdio>\n#include<algorithm>\n#include<cstring>\n#include<string>\n \nusing namespace std;\n \nconst int MAX_N = int(1e6) + 10;\nconst long long int MOD=1e9+7;\nconst long long int INF=1e18;\n \n \ntypedef long long int ll;\ntypedef unsigned long long int llu;\n \n \n \nstruct fenwick{\n  int lim;\n  long long int *tree;\n  fenwick(int _lim){\n      lim=_lim;\n      tree=new long long int[lim];\n  }\n  void init(){\n    for(int i=0;i<lim;i++){\n      tree[i]=0;\n    }\n  }\n  void update(int x,long long int v){\n    while(x<lim){\n      tree[x]+=v;\n      x+=x&(-x);\n    }\n  }\n  long long int query(int x){\n    long long int ans=0;\n    while(x>0){\n      ans+=tree[x];\n      x-=x&(-x);\n    }\n    return ans;\n  }\n  int _query(int k){\n    int low=1;\n    int high=500000;\n    int ans=0;int x=k;\n    while(low<=high){\n      int mid=low+(high-low)/2;\n      if(query(mid)>=x){\n        ans=mid;\n        high=mid-1;\n      }else{\n        low=mid+1;\n      }\n    }\n    return ans;\n  }\n};/*\nstruct z_function{\n  string &txt;\n  int *z;\n  z_function(string &_txt):txt(_txt){\n    z=new int[1+txt.length()];\n  }\n  void cal(){\n    z[0]=0;\n    int l=0;\n    int r=0;\n    for(int i=1;i<txt.length();i++){\n    //  cout<<l<<\" \"<<r<<endl;\n      if(i>r){\n        l=i;\n        r=i;\n        while(r<txt.length() && txt[r]==txt[r-l]){\n          r++;\n        }\n      //  cout<<r<<\" \";\n        z[i]=r-l;\n        r=r-1;\n      }else{\n              if(z[i-l]<r-i+1)\n                z[i]=z[i-l];\n              else{\n                l=i;\n                while(r<txt.length() && txt[r]==txt[r-l]){\n                  r++;\n                }\n                z[i]=r-l;\n                r=r-1;\n              }\n      }\n    }\n  }\n};\nstruct palindromic_tree{\n  map<char,struct palindromic_tree*>m;\n  int length;\n  int end_indx;\n  struct palindromic_tree* suffix;\n  palindromic_tree(int _length,int _end_indx){\n    length=_length;\n    end_indx=_end_indx;\n  }\n};\nclass palindromic_string{\npublic:\n  string &s;\n  struct palindromic_tree* real_root;\n  struct palindromic_tree* imaginary_root;\n  struct palindromic_tree* curr;\n  long long int *prefix;\n  palindromic_string(string &_s):s(_s){\n       real_root=new palindromic_tree(0,-1);\n       imaginary_root=new palindromic_tree(-1,-1);\n       curr=real_root;\n       real_root->suffix=imaginary_root;prefix=new long long int[1+s.length()];\n       imaginary_root->suffix=imaginary_root;\n  }\n  void add(char ch){\n    int indx=s.size();\n    struct palindromic_tree* temp=curr;\n    s+=ch;\n    while(indx-temp->length-1<0 || s[indx-temp->length-1]!=s[indx])\n      temp=temp->suffix;\n    if((temp->m).find(ch)!=(temp->m).end()){\n      curr=(temp->m)[ch];\n      return;\n    }else{\n      curr=new palindromic_tree((temp->length)+2,indx);\n    }\n \n    (temp->m)[ch]=curr;\n \n    if(curr->length==1){\n      curr->suffix=real_root;\n      return;\n    }else{\n      temp=temp->suffix;\n      while(indx-temp->length-1<0 || s[indx-temp->length-1]!=s[indx])\n        temp=temp->suffix;\n      curr->suffix=(temp->m)[ch];\n    }\n  }\n \n  void cal(){\n    prefix[0]=0;\n    long long int p=29LL;\n    for(int i=0;i<s.length();i++){\n      prefix[i+1]=(prefix[i]+(p*s[i]))%MOD;\n      p=(p*p)%MOD;\n    }\n  }\n};\nstruct prime_numbers{\n  int *seive;\n  int len;\n  prime_numbers(int _len){\n    len=_len;\n    seive=new int[len+1];\n  }\n  void init(){\n    seive[0]=1;\n    seive[1]=1;\n  }\n  void cal(){\n    for(int i=2;i*i<=len;i++){\n      for(int j=i*i;j<=len;j+=i){\n        seive[j]=1;\n      }\n    }\n  }\n};\n*/\nll mul(ll a,ll b){\n  if(a>=MOD)a=a%MOD;\n  while(a<0)a+=MOD;\n  if(b>=MOD)b=b%MOD;\n  while(b<0)b+=MOD;\n  ll c=a*b;\n  if(c>=MOD)c=c%MOD;\n  while(c<0)c+=MOD;\n  return c;\n}\nll add(ll a,ll b){\n  if(a>=MOD)a=a%MOD;\n  while(a<0)a+=MOD;\n  if(b>=MOD)b=b%MOD;\n  while(b<0)b+=MOD;\n  ll ans=(a+b);\n  if(ans>=MOD)ans=ans%MOD;\n  while(ans<0)ans+=MOD;\n  return ans;\n}\nll power(ll a,ll b,ll c){\n  ll ans=1;\n  while(b){\n    if(b&1){\n      ans=mul(ans,a);\n    }\n    a=mul(a,a);\n    b=b/2;\n  }\n  return ans;\n}\ntemplate<class T1, class T2>\nistream &operator>>(istream &in, pair<T1, T2> &P){\n  in >> P.first >> P.second;\n  return in;\n}\n \ntemplate<class T1, class T2>\nostream &operator<<(ostream &out, const pair<T1, T2> &P){\n  out << \"(\" << P.first << \", \" << P.second << \")\";\n  return out;\n}\ntemplate<class T>\nistream &operator>>(istream &in, vector<T> &arr){\n  for(auto &x: arr) in >> x;\n  return in;\n}\ntemplate<class T>\nostream &operator<<(ostream &out, const vector<T> &arr){\n  for(auto &x: arr) out << x << ' '; cout << \"\\n\";\n  return out;\n}\ntemplate<class T>\nistream &operator>>(istream &in, deque<T> &arr){\n  for(auto &x: arr) in >> x;\n  return in;\n}\ntemplate<class T>\nostream &operator<<(ostream &out, const deque<T> &arr){\n  for(auto &x: arr) out << x << ' '; cout << \"\\n\";\n  return out;\n}\nmt19937 rnd(time(0));\nstruct sparse{\n  int table[200005][25];\n  int n;\n  sparse(int len1):n(len1){\n  }\n  void init(int *a){\n \n    for(int i=1;i<=n;i++){\n      table[i][0]=a[i];\n    }\n \n   // cout<<table[1][0]<<endl;\n \n    for(int j=1;j<25;j++){\n      for(int i=1;i<=n;i++){\n        if(i+(1<<j)-1<=n){\n          table[i][j]=__gcd(table[i][j-1],table[i+(1<<(j-1))][j-1]);\n        }\n      }\n    }\n  }\n  int find(int *a,int start,int end){\n    int dis=end-start+1;\n    int g=0;\n    for(int j=25;j>=0;j--){\n      if(dis&(1<<j)){\n     //     cout<<dis<<\" \"<<table[start][j]<<\" \"<<j<<endl;\n          g=__gcd(g,table[start][j]);\n          start=start+(1<<j);\n      }\n    }\n    return g;\n  }\n};\ninline ll gcd(ll a,ll b){\n  while(b)a%=b,swap(a,b);\n  return a;\n}\n// vector<pair<int,int> >v[1000005];\n// ll t[1000005];ll h[1000005]; ;;;;;;multiset<pair<ll,pair<int,pair<ll,ll> > > >s;ll A,B;bool vis[1000005];ll dis[1000005];int parent[1000005];vector<int>ans;\n// ll c[1000005];\n \nstruct SOS{\n  ll *dp;\n  int limit;\n  vector<int>&arr;\n \n  SOS(int _limit,vector<int>&v):arr(v){\n \n    limit=_limit;\n    dp=new ll[(1<<limit)+10];\n  }\n \n  void init(){\n    for(int i=0;i<(1<<limit);i++){\n      dp[i]=0;\n    }\n    for(int i=0;i<arr.size();i++){\n       dp[arr[i]]++;\n    }\n  }\n \n  void build1(){\n    for(int i=0;i<limit;i++){\n      for(int j=0;j<(1<<limit);j++){\n        if(j&(1<<i)){\n          dp[j]=add(dp[j],dp[j^(1<<i)]);\n      }\n    }\n  }\n }\n  void build2(){\n    for(int i=0;i<limit;i++){\n      for(int j=(1<<limit)-1;j>=0;j--){\n        if(j&(1<<i)){\n          dp[j^(1<<i)]=add(dp[j^(1<<i)],dp[j]);\n        }\n      }\n    }\n  }\n// }\n \n};\n \n// string s;\nint find(int arr[],int x)\n{\n    while(x!=arr[x])\n    {\n        x=arr[x];\n    }\n \n    return x;\n}\n \nvoid connect(int x,int arr[],int size[],int comp[],int y)\n{\n    int rootA=find(arr,x);\n    int rootB=find(arr,y);\n    if(rootA==rootB)return;\n \n    if(size[rootA]<size[rootB])\n    {\n        arr[rootA]=rootB;\n        size[rootB]+=size[rootA];\n        comp[rootB]=min(comp[rootA],comp[rootB]);\n    }else{\n        arr[rootB]=rootA;\n        size[rootA]+=size[rootB];\n        comp[rootA]=min(comp[rootA],comp[rootB]);\n    }\n \n \n}\nstruct lazylam{\n  ll *tree;\n  int n;\n  lazylam(int size):n(size){\n    tree=new ll[4*n+1];\n \n  }\n  void init(){\n    for(int i=0;i<=4*n;i++){\n     tree[i]=0;\n    }\n  }\n  void update(int x,ll v){\n    upd(1,1,n,x,v);\n  }\n  void upd(int nd,int st,int en,int x,ll v){\n    if(st==en){\n      tree[nd]+=v;\n      return;\n    }\n    int mid=(st+en)/2;\n    if(x<=mid){\n      upd(2*nd,st,mid,x,v);\n    }else{\n      upd(2*nd+1,mid+1,en,x,v);\n    }\n \n    tree[nd]=tree[2*nd]+tree[2*nd+1];\n  }\n};\nstruct graph{\n  vector<int> *v;\n  int n;\n  long long int *values;\n  int *start;\n  int *end;\n  graph(int size):n(size){\n    v=new vector<int>[n+1];\n    values=new ll[n+1];\n    for(int i=1;i<n;i++){\n      int x,y;\n      cin>>x>>y;\n      v[x].push_back(y);\n      v[y].push_back(x);\n    }\n    for(int i=1;i<=n;i++){\n      cin>>values[i];\n    }\n  }\n  void dfs(){\n    int gtime=0;\n    start=new int[n+1];\n    end=new int[n+1];\n    dfs_start_end(1,0,gtime);\n  }\n  void dfs_start_end(int i,int p,int &gtime){\n       gtime++;\n       start[i]=gtime;\n       for(auto it:v[i]){\n        if(it!=p){\n          dfs_start_end(it,i,gtime);\n        }\n       }\n       end[i]=gtime;\n  }\n};\n\n\nint main()\n{\n   ios_base::sync_with_stdio(false);\n   cin.tie(NULL);\n   cout.tie(NULL);\n \n\n  \n  int n,m;\n  cin>>n>>m;\n  \n  string str1=\"\";\n  string str2=\"\";\n\n  for(int i=1;i<=m;i++){\n      str1+=to_string(n);\n     // cout<<str1<<endl;\n  }\n\n  for(int i=1;i<=n;i++){\n      str2+=to_string(m);\n  }\n\n  if(str1.compare(str2)<0)cout<<str1<<endl;\n  else cout<<str2<<endl;\n  \n  \n \n  \n \n}\n", "language": "C++", "metadata": {"date": 1579463775, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02790.html", "problem_id": "p02790", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02790/input.txt", "sample_output_relpath": "derived/input_output/data/p02790/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02790/C++/s644570189.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s644570189", "user_id": "u899316634"}, "prompt_components": {"gold_output": "3333\n", "input_to_evaluate": "#pragma GCC optimize(\"Ofast,unroll-loops,no-stack-protector,fast-math\")\n#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n \n#include<bits/stdc++.h>\n#include<iostream>\n#include<cstdio>\n#include<algorithm>\n#include<cstring>\n#include<string>\n \nusing namespace std;\n \nconst int MAX_N = int(1e6) + 10;\nconst long long int MOD=1e9+7;\nconst long long int INF=1e18;\n \n \ntypedef long long int ll;\ntypedef unsigned long long int llu;\n \n \n \nstruct fenwick{\n  int lim;\n  long long int *tree;\n  fenwick(int _lim){\n      lim=_lim;\n      tree=new long long int[lim];\n  }\n  void init(){\n    for(int i=0;i<lim;i++){\n      tree[i]=0;\n    }\n  }\n  void update(int x,long long int v){\n    while(x<lim){\n      tree[x]+=v;\n      x+=x&(-x);\n    }\n  }\n  long long int query(int x){\n    long long int ans=0;\n    while(x>0){\n      ans+=tree[x];\n      x-=x&(-x);\n    }\n    return ans;\n  }\n  int _query(int k){\n    int low=1;\n    int high=500000;\n    int ans=0;int x=k;\n    while(low<=high){\n      int mid=low+(high-low)/2;\n      if(query(mid)>=x){\n        ans=mid;\n        high=mid-1;\n      }else{\n        low=mid+1;\n      }\n    }\n    return ans;\n  }\n};/*\nstruct z_function{\n  string &txt;\n  int *z;\n  z_function(string &_txt):txt(_txt){\n    z=new int[1+txt.length()];\n  }\n  void cal(){\n    z[0]=0;\n    int l=0;\n    int r=0;\n    for(int i=1;i<txt.length();i++){\n    //  cout<<l<<\" \"<<r<<endl;\n      if(i>r){\n        l=i;\n        r=i;\n        while(r<txt.length() && txt[r]==txt[r-l]){\n          r++;\n        }\n      //  cout<<r<<\" \";\n        z[i]=r-l;\n        r=r-1;\n      }else{\n              if(z[i-l]<r-i+1)\n                z[i]=z[i-l];\n              else{\n                l=i;\n                while(r<txt.length() && txt[r]==txt[r-l]){\n                  r++;\n                }\n                z[i]=r-l;\n                r=r-1;\n              }\n      }\n    }\n  }\n};\nstruct palindromic_tree{\n  map<char,struct palindromic_tree*>m;\n  int length;\n  int end_indx;\n  struct palindromic_tree* suffix;\n  palindromic_tree(int _length,int _end_indx){\n    length=_length;\n    end_indx=_end_indx;\n  }\n};\nclass palindromic_string{\npublic:\n  string &s;\n  struct palindromic_tree* real_root;\n  struct palindromic_tree* imaginary_root;\n  struct palindromic_tree* curr;\n  long long int *prefix;\n  palindromic_string(string &_s):s(_s){\n       real_root=new palindromic_tree(0,-1);\n       imaginary_root=new palindromic_tree(-1,-1);\n       curr=real_root;\n       real_root->suffix=imaginary_root;prefix=new long long int[1+s.length()];\n       imaginary_root->suffix=imaginary_root;\n  }\n  void add(char ch){\n    int indx=s.size();\n    struct palindromic_tree* temp=curr;\n    s+=ch;\n    while(indx-temp->length-1<0 || s[indx-temp->length-1]!=s[indx])\n      temp=temp->suffix;\n    if((temp->m).find(ch)!=(temp->m).end()){\n      curr=(temp->m)[ch];\n      return;\n    }else{\n      curr=new palindromic_tree((temp->length)+2,indx);\n    }\n \n    (temp->m)[ch]=curr;\n \n    if(curr->length==1){\n      curr->suffix=real_root;\n      return;\n    }else{\n      temp=temp->suffix;\n      while(indx-temp->length-1<0 || s[indx-temp->length-1]!=s[indx])\n        temp=temp->suffix;\n      curr->suffix=(temp->m)[ch];\n    }\n  }\n \n  void cal(){\n    prefix[0]=0;\n    long long int p=29LL;\n    for(int i=0;i<s.length();i++){\n      prefix[i+1]=(prefix[i]+(p*s[i]))%MOD;\n      p=(p*p)%MOD;\n    }\n  }\n};\nstruct prime_numbers{\n  int *seive;\n  int len;\n  prime_numbers(int _len){\n    len=_len;\n    seive=new int[len+1];\n  }\n  void init(){\n    seive[0]=1;\n    seive[1]=1;\n  }\n  void cal(){\n    for(int i=2;i*i<=len;i++){\n      for(int j=i*i;j<=len;j+=i){\n        seive[j]=1;\n      }\n    }\n  }\n};\n*/\nll mul(ll a,ll b){\n  if(a>=MOD)a=a%MOD;\n  while(a<0)a+=MOD;\n  if(b>=MOD)b=b%MOD;\n  while(b<0)b+=MOD;\n  ll c=a*b;\n  if(c>=MOD)c=c%MOD;\n  while(c<0)c+=MOD;\n  return c;\n}\nll add(ll a,ll b){\n  if(a>=MOD)a=a%MOD;\n  while(a<0)a+=MOD;\n  if(b>=MOD)b=b%MOD;\n  while(b<0)b+=MOD;\n  ll ans=(a+b);\n  if(ans>=MOD)ans=ans%MOD;\n  while(ans<0)ans+=MOD;\n  return ans;\n}\nll power(ll a,ll b,ll c){\n  ll ans=1;\n  while(b){\n    if(b&1){\n      ans=mul(ans,a);\n    }\n    a=mul(a,a);\n    b=b/2;\n  }\n  return ans;\n}\ntemplate<class T1, class T2>\nistream &operator>>(istream &in, pair<T1, T2> &P){\n  in >> P.first >> P.second;\n  return in;\n}\n \ntemplate<class T1, class T2>\nostream &operator<<(ostream &out, const pair<T1, T2> &P){\n  out << \"(\" << P.first << \", \" << P.second << \")\";\n  return out;\n}\ntemplate<class T>\nistream &operator>>(istream &in, vector<T> &arr){\n  for(auto &x: arr) in >> x;\n  return in;\n}\ntemplate<class T>\nostream &operator<<(ostream &out, const vector<T> &arr){\n  for(auto &x: arr) out << x << ' '; cout << \"\\n\";\n  return out;\n}\ntemplate<class T>\nistream &operator>>(istream &in, deque<T> &arr){\n  for(auto &x: arr) in >> x;\n  return in;\n}\ntemplate<class T>\nostream &operator<<(ostream &out, const deque<T> &arr){\n  for(auto &x: arr) out << x << ' '; cout << \"\\n\";\n  return out;\n}\nmt19937 rnd(time(0));\nstruct sparse{\n  int table[200005][25];\n  int n;\n  sparse(int len1):n(len1){\n  }\n  void init(int *a){\n \n    for(int i=1;i<=n;i++){\n      table[i][0]=a[i];\n    }\n \n   // cout<<table[1][0]<<endl;\n \n    for(int j=1;j<25;j++){\n      for(int i=1;i<=n;i++){\n        if(i+(1<<j)-1<=n){\n          table[i][j]=__gcd(table[i][j-1],table[i+(1<<(j-1))][j-1]);\n        }\n      }\n    }\n  }\n  int find(int *a,int start,int end){\n    int dis=end-start+1;\n    int g=0;\n    for(int j=25;j>=0;j--){\n      if(dis&(1<<j)){\n     //     cout<<dis<<\" \"<<table[start][j]<<\" \"<<j<<endl;\n          g=__gcd(g,table[start][j]);\n          start=start+(1<<j);\n      }\n    }\n    return g;\n  }\n};\ninline ll gcd(ll a,ll b){\n  while(b)a%=b,swap(a,b);\n  return a;\n}\n// vector<pair<int,int> >v[1000005];\n// ll t[1000005];ll h[1000005]; ;;;;;;multiset<pair<ll,pair<int,pair<ll,ll> > > >s;ll A,B;bool vis[1000005];ll dis[1000005];int parent[1000005];vector<int>ans;\n// ll c[1000005];\n \nstruct SOS{\n  ll *dp;\n  int limit;\n  vector<int>&arr;\n \n  SOS(int _limit,vector<int>&v):arr(v){\n \n    limit=_limit;\n    dp=new ll[(1<<limit)+10];\n  }\n \n  void init(){\n    for(int i=0;i<(1<<limit);i++){\n      dp[i]=0;\n    }\n    for(int i=0;i<arr.size();i++){\n       dp[arr[i]]++;\n    }\n  }\n \n  void build1(){\n    for(int i=0;i<limit;i++){\n      for(int j=0;j<(1<<limit);j++){\n        if(j&(1<<i)){\n          dp[j]=add(dp[j],dp[j^(1<<i)]);\n      }\n    }\n  }\n }\n  void build2(){\n    for(int i=0;i<limit;i++){\n      for(int j=(1<<limit)-1;j>=0;j--){\n        if(j&(1<<i)){\n          dp[j^(1<<i)]=add(dp[j^(1<<i)],dp[j]);\n        }\n      }\n    }\n  }\n// }\n \n};\n \n// string s;\nint find(int arr[],int x)\n{\n    while(x!=arr[x])\n    {\n        x=arr[x];\n    }\n \n    return x;\n}\n \nvoid connect(int x,int arr[],int size[],int comp[],int y)\n{\n    int rootA=find(arr,x);\n    int rootB=find(arr,y);\n    if(rootA==rootB)return;\n \n    if(size[rootA]<size[rootB])\n    {\n        arr[rootA]=rootB;\n        size[rootB]+=size[rootA];\n        comp[rootB]=min(comp[rootA],comp[rootB]);\n    }else{\n        arr[rootB]=rootA;\n        size[rootA]+=size[rootB];\n        comp[rootA]=min(comp[rootA],comp[rootB]);\n    }\n \n \n}\nstruct lazylam{\n  ll *tree;\n  int n;\n  lazylam(int size):n(size){\n    tree=new ll[4*n+1];\n \n  }\n  void init(){\n    for(int i=0;i<=4*n;i++){\n     tree[i]=0;\n    }\n  }\n  void update(int x,ll v){\n    upd(1,1,n,x,v);\n  }\n  void upd(int nd,int st,int en,int x,ll v){\n    if(st==en){\n      tree[nd]+=v;\n      return;\n    }\n    int mid=(st+en)/2;\n    if(x<=mid){\n      upd(2*nd,st,mid,x,v);\n    }else{\n      upd(2*nd+1,mid+1,en,x,v);\n    }\n \n    tree[nd]=tree[2*nd]+tree[2*nd+1];\n  }\n};\nstruct graph{\n  vector<int> *v;\n  int n;\n  long long int *values;\n  int *start;\n  int *end;\n  graph(int size):n(size){\n    v=new vector<int>[n+1];\n    values=new ll[n+1];\n    for(int i=1;i<n;i++){\n      int x,y;\n      cin>>x>>y;\n      v[x].push_back(y);\n      v[y].push_back(x);\n    }\n    for(int i=1;i<=n;i++){\n      cin>>values[i];\n    }\n  }\n  void dfs(){\n    int gtime=0;\n    start=new int[n+1];\n    end=new int[n+1];\n    dfs_start_end(1,0,gtime);\n  }\n  void dfs_start_end(int i,int p,int &gtime){\n       gtime++;\n       start[i]=gtime;\n       for(auto it:v[i]){\n        if(it!=p){\n          dfs_start_end(it,i,gtime);\n        }\n       }\n       end[i]=gtime;\n  }\n};\n\n\nint main()\n{\n   ios_base::sync_with_stdio(false);\n   cin.tie(NULL);\n   cout.tie(NULL);\n \n\n  \n  int n,m;\n  cin>>n>>m;\n  \n  string str1=\"\";\n  string str2=\"\";\n\n  for(int i=1;i<=m;i++){\n      str1+=to_string(n);\n     // cout<<str1<<endl;\n  }\n\n  for(int i=1;i<=n;i++){\n      str2+=to_string(m);\n  }\n\n  if(str1.compare(str2)<0)cout<<str1<<endl;\n  else cout<<str2<<endl;\n  \n  \n \n  \n \n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nGiven are 1-digit positive integers a and b. Consider these two strings: the concatenation of b copies of the digit a, and the concatenation of a copies of the digit b. Which of these is lexicographically smaller?\n\nConstraints\n\n1 \\leq a \\leq 9\n\n1 \\leq b \\leq 9\n\na and b are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\na b\n\nOutput\n\nPrint the lexicographically smaller of the two strings. (If the two strings are equal, print one of them.)\n\nSample Input 1\n\n4 3\n\nSample Output 1\n\n3333\n\nWe have two strings 444 and 3333. Between them, 3333 is the lexicographically smaller.\n\nSample Input 2\n\n7 7\n\nSample Output 2\n\n7777777", "sample_input": "4 3\n"}, "reference_outputs": ["3333\n"], "source_document_id": "p02790", "source_text": "Score : 200 points\n\nProblem Statement\n\nGiven are 1-digit positive integers a and b. Consider these two strings: the concatenation of b copies of the digit a, and the concatenation of a copies of the digit b. Which of these is lexicographically smaller?\n\nConstraints\n\n1 \\leq a \\leq 9\n\n1 \\leq b \\leq 9\n\na and b are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\na b\n\nOutput\n\nPrint the lexicographically smaller of the two strings. (If the two strings are equal, print one of them.)\n\nSample Input 1\n\n4 3\n\nSample Output 1\n\n3333\n\nWe have two strings 444 and 3333. Between them, 3333 is the lexicographically smaller.\n\nSample Input 2\n\n7 7\n\nSample Output 2\n\n7777777", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 8620, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s486234912", "group_id": "codeNet:p02791", "input_text": "#include<iostream>\n#include <string.h>\n#include<stdio.h>\n#include <math.h>\nusing namespace std;\n\nint main() {\n\tint n, P[200000], ans = 0, a1, a2 = 1;\n\tcin >> n;\n\tfor (int i = 0; i < n; i++) {\n\t\tcin >> P[i];\n\t}\n\ta2 = P[0];\n\n\tfor (int i = 0; i < n; i++) {\n\t\tif (P[i] <= a2) {\n\t\t\ta2 = P[i];\n\t\t\tans++;\n\t\t}\n\t\n\t}\n\n\tcout << ans << endl;\n\n\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1579467983, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02791.html", "problem_id": "p02791", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02791/input.txt", "sample_output_relpath": "derived/input_output/data/p02791/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02791/C++/s486234912.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s486234912", "user_id": "u459447880"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include<iostream>\n#include <string.h>\n#include<stdio.h>\n#include <math.h>\nusing namespace std;\n\nint main() {\n\tint n, P[200000], ans = 0, a1, a2 = 1;\n\tcin >> n;\n\tfor (int i = 0; i < n; i++) {\n\t\tcin >> P[i];\n\t}\n\ta2 = P[0];\n\n\tfor (int i = 0; i < n; i++) {\n\t\tif (P[i] <= a2) {\n\t\t\ta2 = P[i];\n\t\t\tans++;\n\t\t}\n\t\n\t}\n\n\tcout << ans << endl;\n\n\n\treturn 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nGiven is a permutation P_1, \\ldots, P_N of 1, \\ldots, N.\nFind the number of integers i (1 \\leq i \\leq N) that satisfy the following condition:\n\nFor any integer j (1 \\leq j \\leq i), P_i \\leq P_j.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\nP_1, \\ldots, P_N is a permutation of 1, \\ldots, N.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nP_1 ... P_N\n\nOutput\n\nPrint the number of integers i that satisfy the condition.\n\nSample Input 1\n\n5\n4 2 5 1 3\n\nSample Output 1\n\n3\n\ni=1, 2, and 4 satisfy the condition, but i=3 does not - for example, P_i > P_j holds for j = 1.\n\nSimilarly, i=5 does not satisfy the condition, either. Thus, there are three integers that satisfy the condition.\n\nSample Input 2\n\n4\n4 3 2 1\n\nSample Output 2\n\n4\n\nAll integers i (1 \\leq i \\leq N) satisfy the condition.\n\nSample Input 3\n\n6\n1 2 3 4 5 6\n\nSample Output 3\n\n1\n\nOnly i=1 satisfies the condition.\n\nSample Input 4\n\n8\n5 7 4 2 6 8 1 3\n\nSample Output 4\n\n4\n\nSample Input 5\n\n1\n1\n\nSample Output 5\n\n1", "sample_input": "5\n4 2 5 1 3\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02791", "source_text": "Score : 300 points\n\nProblem Statement\n\nGiven is a permutation P_1, \\ldots, P_N of 1, \\ldots, N.\nFind the number of integers i (1 \\leq i \\leq N) that satisfy the following condition:\n\nFor any integer j (1 \\leq j \\leq i), P_i \\leq P_j.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\nP_1, \\ldots, P_N is a permutation of 1, \\ldots, N.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nP_1 ... P_N\n\nOutput\n\nPrint the number of integers i that satisfy the condition.\n\nSample Input 1\n\n5\n4 2 5 1 3\n\nSample Output 1\n\n3\n\ni=1, 2, and 4 satisfy the condition, but i=3 does not - for example, P_i > P_j holds for j = 1.\n\nSimilarly, i=5 does not satisfy the condition, either. Thus, there are three integers that satisfy the condition.\n\nSample Input 2\n\n4\n4 3 2 1\n\nSample Output 2\n\n4\n\nAll integers i (1 \\leq i \\leq N) satisfy the condition.\n\nSample Input 3\n\n6\n1 2 3 4 5 6\n\nSample Output 3\n\n1\n\nOnly i=1 satisfies the condition.\n\nSample Input 4\n\n8\n5 7 4 2 6 8 1 3\n\nSample Output 4\n\n4\n\nSample Input 5\n\n1\n1\n\nSample Output 5\n\n1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 344, "cpu_time_ms": 79, "memory_kb": 1024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s492600302", "group_id": "codeNet:p02791", "input_text": "#include<stdio.h>\nint a[1000000];\nint main()\n{\n\tint n,min,mint=0,i;\n\tscanf(\"%d\",&n);\n\tfor(i=0;i<n;i++)\n\tscanf(\"%d\",&a[i]);\n\tfor(i=0;i<n;i++)\n\t{\n\t\tif(i==0)\n\t\t{\n\t\t\tmin=a[i];\n\t\t\tmint++;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tif(a[i]<=min)\n\t\t\t{\n\t\t\t\tmin=a[i];\n\t\t\t\tmint++;\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%d\",mint);\n}", "language": "C++", "metadata": {"date": 1579465034, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02791.html", "problem_id": "p02791", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02791/input.txt", "sample_output_relpath": "derived/input_output/data/p02791/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02791/C++/s492600302.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s492600302", "user_id": "u481490614"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include<stdio.h>\nint a[1000000];\nint main()\n{\n\tint n,min,mint=0,i;\n\tscanf(\"%d\",&n);\n\tfor(i=0;i<n;i++)\n\tscanf(\"%d\",&a[i]);\n\tfor(i=0;i<n;i++)\n\t{\n\t\tif(i==0)\n\t\t{\n\t\t\tmin=a[i];\n\t\t\tmint++;\n\t\t}\n\t\telse\n\t\t{\n\t\t\tif(a[i]<=min)\n\t\t\t{\n\t\t\t\tmin=a[i];\n\t\t\t\tmint++;\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%d\",mint);\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nGiven is a permutation P_1, \\ldots, P_N of 1, \\ldots, N.\nFind the number of integers i (1 \\leq i \\leq N) that satisfy the following condition:\n\nFor any integer j (1 \\leq j \\leq i), P_i \\leq P_j.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\nP_1, \\ldots, P_N is a permutation of 1, \\ldots, N.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nP_1 ... P_N\n\nOutput\n\nPrint the number of integers i that satisfy the condition.\n\nSample Input 1\n\n5\n4 2 5 1 3\n\nSample Output 1\n\n3\n\ni=1, 2, and 4 satisfy the condition, but i=3 does not - for example, P_i > P_j holds for j = 1.\n\nSimilarly, i=5 does not satisfy the condition, either. Thus, there are three integers that satisfy the condition.\n\nSample Input 2\n\n4\n4 3 2 1\n\nSample Output 2\n\n4\n\nAll integers i (1 \\leq i \\leq N) satisfy the condition.\n\nSample Input 3\n\n6\n1 2 3 4 5 6\n\nSample Output 3\n\n1\n\nOnly i=1 satisfies the condition.\n\nSample Input 4\n\n8\n5 7 4 2 6 8 1 3\n\nSample Output 4\n\n4\n\nSample Input 5\n\n1\n1\n\nSample Output 5\n\n1", "sample_input": "5\n4 2 5 1 3\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02791", "source_text": "Score : 300 points\n\nProblem Statement\n\nGiven is a permutation P_1, \\ldots, P_N of 1, \\ldots, N.\nFind the number of integers i (1 \\leq i \\leq N) that satisfy the following condition:\n\nFor any integer j (1 \\leq j \\leq i), P_i \\leq P_j.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\nP_1, \\ldots, P_N is a permutation of 1, \\ldots, N.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nP_1 ... P_N\n\nOutput\n\nPrint the number of integers i that satisfy the condition.\n\nSample Input 1\n\n5\n4 2 5 1 3\n\nSample Output 1\n\n3\n\ni=1, 2, and 4 satisfy the condition, but i=3 does not - for example, P_i > P_j holds for j = 1.\n\nSimilarly, i=5 does not satisfy the condition, either. Thus, there are three integers that satisfy the condition.\n\nSample Input 2\n\n4\n4 3 2 1\n\nSample Output 2\n\n4\n\nAll integers i (1 \\leq i \\leq N) satisfy the condition.\n\nSample Input 3\n\n6\n1 2 3 4 5 6\n\nSample Output 3\n\n1\n\nOnly i=1 satisfies the condition.\n\nSample Input 4\n\n8\n5 7 4 2 6 8 1 3\n\nSample Output 4\n\n4\n\nSample Input 5\n\n1\n1\n\nSample Output 5\n\n1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 279, "cpu_time_ms": 20, "memory_kb": 896}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s510453583", "group_id": "codeNet:p02791", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n \ntypedef long long ll;\ntypedef double D;\ntypedef vector<int> VI;\ntypedef vector<ll> VL;\ntypedef pair<int,int> PII;\ntypedef pair<ll,ll> PLL;\ntypedef long double ld;\n\n#define rd(x) scanf(\"%d\",&x)\n#define rd2(x,y) scanf(\"%d %d\",&x,&y)\n#define rd3(x,y,z) scanf(\"%d %d %d\",&x,&y,&z)\n#define rl(x) scanf(\"%lld\",&x)\n#define rl2(x,y) scanf(\"%lld %lld\",&x,&y)\n#define rl3(x,y,z) scanf(\"%lld %lld %lld\",&x,&y,&z)\n#define wd(x) printf(\"%d\" ,x)\n#define wd2(x,y) printf(\"%d %d\",x,y)\n#define wl(x) printf(\"%lld\",x)\n#define wl2(x,y) printf(\"%lld %lld\",x,y)\n#define PC(x) putchar(x)\n#define GC() getchar()\n#define NL printf(\"\\n\")\n#define SP printf(\" \")\n \n#define SZ(a) (int)a.size()\n#define ALL(a) a.begin(), a.end()\n#define ITER(it,a) for (__typeof(a.begin()) it = a.begin(); it != a.end(); it++)\n#define FILL(a,value) memset(a, value, sizeof(a))\n\n#define F first\n#define S second\n#define MP make_pair\n#define PB push_back\n\n#define SPEED ios::sync_with_stdio(false); cin.tie(0); cout.tie(0)\n#define fastio ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0);\n#define fast_cin() ios_base::sync_with_stdio(false); cin.tie(NULL)\n#define fr(i,s,e) for(int i=s;i<e;i++)\n#define frl(i,s,e) for(ll i=s;i<e;i++)\n#define frr(i,s,e) for(int i=s-1;i>=e;i--)\n#define frv(i,a) for(int i = 0;i<(int)a.size();i++)\n#define frvr(i,a) for(int i = a.size()-1;i>=0;i--)\n#define tr(i,a) for(typeof(a.begin()) i = a.begin(); i != a.end();i++)\n\n#define inf 10000000000000\n#define mod 1000000007\n#define maxn 100009\n#define maxr 100009\n\nvoid solve()\n{\n\tll n;\n\trl(n);\n\tVL arr(n),tmp;\n\tfr(i,0,n)\n\t\trl(arr[i]);\n\tll ct=0,mx=inf;\n\n\tfr(i,0,n)\n\t{\n\t\tmx=min(mx,arr[i]);\n\t\tif(mx==arr[i])\n\t\t\tct++;\n\t}\n\twl(ct);\n\tNL;\n\treturn;\n}\nint main(){\n\t//sstd::ios::sync_with_stdio(false); cin.tie(NULL);\n\tsolve();\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1579464351, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02791.html", "problem_id": "p02791", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02791/input.txt", "sample_output_relpath": "derived/input_output/data/p02791/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02791/C++/s510453583.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s510453583", "user_id": "u431615124"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n \ntypedef long long ll;\ntypedef double D;\ntypedef vector<int> VI;\ntypedef vector<ll> VL;\ntypedef pair<int,int> PII;\ntypedef pair<ll,ll> PLL;\ntypedef long double ld;\n\n#define rd(x) scanf(\"%d\",&x)\n#define rd2(x,y) scanf(\"%d %d\",&x,&y)\n#define rd3(x,y,z) scanf(\"%d %d %d\",&x,&y,&z)\n#define rl(x) scanf(\"%lld\",&x)\n#define rl2(x,y) scanf(\"%lld %lld\",&x,&y)\n#define rl3(x,y,z) scanf(\"%lld %lld %lld\",&x,&y,&z)\n#define wd(x) printf(\"%d\" ,x)\n#define wd2(x,y) printf(\"%d %d\",x,y)\n#define wl(x) printf(\"%lld\",x)\n#define wl2(x,y) printf(\"%lld %lld\",x,y)\n#define PC(x) putchar(x)\n#define GC() getchar()\n#define NL printf(\"\\n\")\n#define SP printf(\" \")\n \n#define SZ(a) (int)a.size()\n#define ALL(a) a.begin(), a.end()\n#define ITER(it,a) for (__typeof(a.begin()) it = a.begin(); it != a.end(); it++)\n#define FILL(a,value) memset(a, value, sizeof(a))\n\n#define F first\n#define S second\n#define MP make_pair\n#define PB push_back\n\n#define SPEED ios::sync_with_stdio(false); cin.tie(0); cout.tie(0)\n#define fastio ios_base::sync_with_stdio(false);cin.tie(0);cout.tie(0);\n#define fast_cin() ios_base::sync_with_stdio(false); cin.tie(NULL)\n#define fr(i,s,e) for(int i=s;i<e;i++)\n#define frl(i,s,e) for(ll i=s;i<e;i++)\n#define frr(i,s,e) for(int i=s-1;i>=e;i--)\n#define frv(i,a) for(int i = 0;i<(int)a.size();i++)\n#define frvr(i,a) for(int i = a.size()-1;i>=0;i--)\n#define tr(i,a) for(typeof(a.begin()) i = a.begin(); i != a.end();i++)\n\n#define inf 10000000000000\n#define mod 1000000007\n#define maxn 100009\n#define maxr 100009\n\nvoid solve()\n{\n\tll n;\n\trl(n);\n\tVL arr(n),tmp;\n\tfr(i,0,n)\n\t\trl(arr[i]);\n\tll ct=0,mx=inf;\n\n\tfr(i,0,n)\n\t{\n\t\tmx=min(mx,arr[i]);\n\t\tif(mx==arr[i])\n\t\t\tct++;\n\t}\n\twl(ct);\n\tNL;\n\treturn;\n}\nint main(){\n\t//sstd::ios::sync_with_stdio(false); cin.tie(NULL);\n\tsolve();\n\treturn 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nGiven is a permutation P_1, \\ldots, P_N of 1, \\ldots, N.\nFind the number of integers i (1 \\leq i \\leq N) that satisfy the following condition:\n\nFor any integer j (1 \\leq j \\leq i), P_i \\leq P_j.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\nP_1, \\ldots, P_N is a permutation of 1, \\ldots, N.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nP_1 ... P_N\n\nOutput\n\nPrint the number of integers i that satisfy the condition.\n\nSample Input 1\n\n5\n4 2 5 1 3\n\nSample Output 1\n\n3\n\ni=1, 2, and 4 satisfy the condition, but i=3 does not - for example, P_i > P_j holds for j = 1.\n\nSimilarly, i=5 does not satisfy the condition, either. Thus, there are three integers that satisfy the condition.\n\nSample Input 2\n\n4\n4 3 2 1\n\nSample Output 2\n\n4\n\nAll integers i (1 \\leq i \\leq N) satisfy the condition.\n\nSample Input 3\n\n6\n1 2 3 4 5 6\n\nSample Output 3\n\n1\n\nOnly i=1 satisfies the condition.\n\nSample Input 4\n\n8\n5 7 4 2 6 8 1 3\n\nSample Output 4\n\n4\n\nSample Input 5\n\n1\n1\n\nSample Output 5\n\n1", "sample_input": "5\n4 2 5 1 3\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02791", "source_text": "Score : 300 points\n\nProblem Statement\n\nGiven is a permutation P_1, \\ldots, P_N of 1, \\ldots, N.\nFind the number of integers i (1 \\leq i \\leq N) that satisfy the following condition:\n\nFor any integer j (1 \\leq j \\leq i), P_i \\leq P_j.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\nP_1, \\ldots, P_N is a permutation of 1, \\ldots, N.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nP_1 ... P_N\n\nOutput\n\nPrint the number of integers i that satisfy the condition.\n\nSample Input 1\n\n5\n4 2 5 1 3\n\nSample Output 1\n\n3\n\ni=1, 2, and 4 satisfy the condition, but i=3 does not - for example, P_i > P_j holds for j = 1.\n\nSimilarly, i=5 does not satisfy the condition, either. Thus, there are three integers that satisfy the condition.\n\nSample Input 2\n\n4\n4 3 2 1\n\nSample Output 2\n\n4\n\nAll integers i (1 \\leq i \\leq N) satisfy the condition.\n\nSample Input 3\n\n6\n1 2 3 4 5 6\n\nSample Output 3\n\n1\n\nOnly i=1 satisfies the condition.\n\nSample Input 4\n\n8\n5 7 4 2 6 8 1 3\n\nSample Output 4\n\n4\n\nSample Input 5\n\n1\n1\n\nSample Output 5\n\n1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1814, "cpu_time_ms": 21, "memory_kb": 1792}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s207396951", "group_id": "codeNet:p02792", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nint N;\ntypedef long long ll;\ntypedef pair<int,int> P;\n\nP f(int x){\n    int a = x%10;\n    int b = 0;\n    while(x){\n        b=x;\n        x /= 10;\n    }\n    return P(a,b);\n}\n\n\nint main(){\n    cin >> N;\n    map<P,int> freq;\n    for(int i = 1;i<=N;i++){\n        P p = f(i);\n        freq[p]++;\n    }\n    ll ans = 0;\n    for(int i = 1;i<=N;i++){\n        P p = f(i);\n        P q(p.second, p.first);\n        ans += freq[q];\n    }\n    cout << ans << endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1587418060, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02792.html", "problem_id": "p02792", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02792/input.txt", "sample_output_relpath": "derived/input_output/data/p02792/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02792/C++/s207396951.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s207396951", "user_id": "u529722835"}, "prompt_components": {"gold_output": "17\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nint N;\ntypedef long long ll;\ntypedef pair<int,int> P;\n\nP f(int x){\n    int a = x%10;\n    int b = 0;\n    while(x){\n        b=x;\n        x /= 10;\n    }\n    return P(a,b);\n}\n\n\nint main(){\n    cin >> N;\n    map<P,int> freq;\n    for(int i = 1;i<=N;i++){\n        P p = f(i);\n        freq[p]++;\n    }\n    ll ans = 0;\n    for(int i = 1;i<=N;i++){\n        P p = f(i);\n        P q(p.second, p.first);\n        ans += freq[q];\n    }\n    cout << ans << endl;\n    return 0;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nGiven is a positive integer N.\n\nFind the number of pairs (A, B) of positive integers not greater than N that satisfy the following condition:\n\nWhen A and B are written in base ten without leading zeros, the last digit of A is equal to the first digit of B, and the first digit of A is equal to the last digit of B.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n25\n\nSample Output 1\n\n17\n\nThe following 17 pairs satisfy the condition: (1,1), (1,11), (2,2), (2,22), (3,3), (4,4), (5,5), (6,6), (7,7), (8,8), (9,9), (11,1), (11,11), (12,21), (21,12), (22,2), and (22,22).\n\nSample Input 2\n\n1\n\nSample Output 2\n\n1\n\nSample Input 3\n\n100\n\nSample Output 3\n\n108\n\nSample Input 4\n\n2020\n\nSample Output 4\n\n40812\n\nSample Input 5\n\n200000\n\nSample Output 5\n\n400000008", "sample_input": "25\n"}, "reference_outputs": ["17\n"], "source_document_id": "p02792", "source_text": "Score : 400 points\n\nProblem Statement\n\nGiven is a positive integer N.\n\nFind the number of pairs (A, B) of positive integers not greater than N that satisfy the following condition:\n\nWhen A and B are written in base ten without leading zeros, the last digit of A is equal to the first digit of B, and the first digit of A is equal to the last digit of B.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n25\n\nSample Output 1\n\n17\n\nThe following 17 pairs satisfy the condition: (1,1), (1,11), (2,2), (2,22), (3,3), (4,4), (5,5), (6,6), (7,7), (8,8), (9,9), (11,1), (11,11), (12,21), (21,12), (22,2), and (22,22).\n\nSample Input 2\n\n1\n\nSample Output 2\n\n1\n\nSample Input 3\n\n100\n\nSample Output 3\n\n108\n\nSample Input 4\n\n2020\n\nSample Output 4\n\n40812\n\nSample Input 5\n\n200000\n\nSample Output 5\n\n400000008", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 507, "cpu_time_ms": 9, "memory_kb": 384}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s039401996", "group_id": "codeNet:p02792", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for(int i = 0; i < (int)(n); i++)\n\nint c[10][10];\n\nint main(){\n    int n;\n    cin >> n;\n\n    rep(i,10)rep(j,10) c[i][j] = 0;\n\n    int first, last;\n    for(int i = 1; i <= n; i++){\n        int j = i;\n        last = j % 10;\n        while(j > 10){\n            j /= 10;\n        }\n        first = j;\n        c[first][last]++;\n    }\n\n    long long ans = 0;\n    for(int i = 0; i <= 9; i++){\n        for(int j = 0; j <= 9; j++){\n            ans += c[i][j] * c[j][i];\n        }\n    }\n\n    cout << ans << endl;\n\n    return 0;\n}", "language": "C++", "metadata": {"date": 1585088974, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02792.html", "problem_id": "p02792", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02792/input.txt", "sample_output_relpath": "derived/input_output/data/p02792/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02792/C++/s039401996.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s039401996", "user_id": "u621582427"}, "prompt_components": {"gold_output": "17\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for(int i = 0; i < (int)(n); i++)\n\nint c[10][10];\n\nint main(){\n    int n;\n    cin >> n;\n\n    rep(i,10)rep(j,10) c[i][j] = 0;\n\n    int first, last;\n    for(int i = 1; i <= n; i++){\n        int j = i;\n        last = j % 10;\n        while(j > 10){\n            j /= 10;\n        }\n        first = j;\n        c[first][last]++;\n    }\n\n    long long ans = 0;\n    for(int i = 0; i <= 9; i++){\n        for(int j = 0; j <= 9; j++){\n            ans += c[i][j] * c[j][i];\n        }\n    }\n\n    cout << ans << endl;\n\n    return 0;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nGiven is a positive integer N.\n\nFind the number of pairs (A, B) of positive integers not greater than N that satisfy the following condition:\n\nWhen A and B are written in base ten without leading zeros, the last digit of A is equal to the first digit of B, and the first digit of A is equal to the last digit of B.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n25\n\nSample Output 1\n\n17\n\nThe following 17 pairs satisfy the condition: (1,1), (1,11), (2,2), (2,22), (3,3), (4,4), (5,5), (6,6), (7,7), (8,8), (9,9), (11,1), (11,11), (12,21), (21,12), (22,2), and (22,22).\n\nSample Input 2\n\n1\n\nSample Output 2\n\n1\n\nSample Input 3\n\n100\n\nSample Output 3\n\n108\n\nSample Input 4\n\n2020\n\nSample Output 4\n\n40812\n\nSample Input 5\n\n200000\n\nSample Output 5\n\n400000008", "sample_input": "25\n"}, "reference_outputs": ["17\n"], "source_document_id": "p02792", "source_text": "Score : 400 points\n\nProblem Statement\n\nGiven is a positive integer N.\n\nFind the number of pairs (A, B) of positive integers not greater than N that satisfy the following condition:\n\nWhen A and B are written in base ten without leading zeros, the last digit of A is equal to the first digit of B, and the first digit of A is equal to the last digit of B.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n25\n\nSample Output 1\n\n17\n\nThe following 17 pairs satisfy the condition: (1,1), (1,11), (2,2), (2,22), (3,3), (4,4), (5,5), (6,6), (7,7), (8,8), (9,9), (11,1), (11,11), (12,21), (21,12), (22,2), and (22,22).\n\nSample Input 2\n\n1\n\nSample Output 2\n\n1\n\nSample Input 3\n\n100\n\nSample Output 3\n\n108\n\nSample Input 4\n\n2020\n\nSample Output 4\n\n40812\n\nSample Input 5\n\n200000\n\nSample Output 5\n\n400000008", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 580, "cpu_time_ms": 5, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s414012048", "group_id": "codeNet:p02792", "input_text": "#include <iostream>\n#include <vector>\nusing namespace std;\n\nint maxnum(int n){\n  while(n > 9){\n    n /= 10;\n  }\n  return n;\n}\n\nint minnum(int n){\n  return n % 10;\n}\n\nint main(void){\n  int N;\n  cin >> N;\n  \n  vector<vector<int>>num(10,vector<int>(10,0));\n  for(int i=0;i<=N;i++){\n    num[maxnum(i)][minnum(i)]++;\n  }\n  \n  long long ans = 0;\n  for(int i=1;i<10;i++){\n    for(int j=1;j<10;j++){\n      ans += num[i][j] * num[j][i];\n    }\n  }\n  \n  cout << ans << endl;\n  \n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1582759246, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02792.html", "problem_id": "p02792", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02792/input.txt", "sample_output_relpath": "derived/input_output/data/p02792/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02792/C++/s414012048.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s414012048", "user_id": "u407416173"}, "prompt_components": {"gold_output": "17\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\nusing namespace std;\n\nint maxnum(int n){\n  while(n > 9){\n    n /= 10;\n  }\n  return n;\n}\n\nint minnum(int n){\n  return n % 10;\n}\n\nint main(void){\n  int N;\n  cin >> N;\n  \n  vector<vector<int>>num(10,vector<int>(10,0));\n  for(int i=0;i<=N;i++){\n    num[maxnum(i)][minnum(i)]++;\n  }\n  \n  long long ans = 0;\n  for(int i=1;i<10;i++){\n    for(int j=1;j<10;j++){\n      ans += num[i][j] * num[j][i];\n    }\n  }\n  \n  cout << ans << endl;\n  \n  return 0;\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nGiven is a positive integer N.\n\nFind the number of pairs (A, B) of positive integers not greater than N that satisfy the following condition:\n\nWhen A and B are written in base ten without leading zeros, the last digit of A is equal to the first digit of B, and the first digit of A is equal to the last digit of B.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n25\n\nSample Output 1\n\n17\n\nThe following 17 pairs satisfy the condition: (1,1), (1,11), (2,2), (2,22), (3,3), (4,4), (5,5), (6,6), (7,7), (8,8), (9,9), (11,1), (11,11), (12,21), (21,12), (22,2), and (22,22).\n\nSample Input 2\n\n1\n\nSample Output 2\n\n1\n\nSample Input 3\n\n100\n\nSample Output 3\n\n108\n\nSample Input 4\n\n2020\n\nSample Output 4\n\n40812\n\nSample Input 5\n\n200000\n\nSample Output 5\n\n400000008", "sample_input": "25\n"}, "reference_outputs": ["17\n"], "source_document_id": "p02792", "source_text": "Score : 400 points\n\nProblem Statement\n\nGiven is a positive integer N.\n\nFind the number of pairs (A, B) of positive integers not greater than N that satisfy the following condition:\n\nWhen A and B are written in base ten without leading zeros, the last digit of A is equal to the first digit of B, and the first digit of A is equal to the last digit of B.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n25\n\nSample Output 1\n\n17\n\nThe following 17 pairs satisfy the condition: (1,1), (1,11), (2,2), (2,22), (3,3), (4,4), (5,5), (6,6), (7,7), (8,8), (9,9), (11,1), (11,11), (12,21), (21,12), (22,2), and (22,22).\n\nSample Input 2\n\n1\n\nSample Output 2\n\n1\n\nSample Input 3\n\n100\n\nSample Output 3\n\n108\n\nSample Input 4\n\n2020\n\nSample Output 4\n\n40812\n\nSample Input 5\n\n200000\n\nSample Output 5\n\n400000008", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 481, "cpu_time_ms": 5, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s544939004", "group_id": "codeNet:p02793", "input_text": "#include <iostream>\n#include <cstring>\n#include <map>\n#include <iomanip>\n#include <algorithm>\n#include <cmath>\n#include <set>\n#include <vector>\n#include <queue>\n#include <list>\n#include <numeric>\n#include <stdio.h>\n#include <string>\n#include <cstdlib>\n#include <math.h>\n#include <stack>\n#include <climits>\n#include <bitset>\n#include <utility>\n#define rep(i,n) for (int i = 0; i < (n); ++i)\n\nusing namespace std;\nusing P = pair<int,int>;\ntypedef long long ll;\ntemplate<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }\n\n//最大公約数\nll gcd(ll x, ll y) {\n    ll tmp = 0;\n    if (x < y){\n        tmp=x;\n        x=y;\n        y=tmp;\n    }\n    while (y > 0) {\n        ll r = x % y;\n        x = y;\n        y = r;\n        }\n    return x;\n}\n\n//最大公倍数\nll lcm(ll x,ll y){\n    return x/gcd(x,y)*y;\n}\n\nconst int MAX = 1e6+1;\nconst ll MOD = 1e9+7;\n\nlong long fac[MAX], finv[MAX], inv[MAX];\n\n// テーブルを作る前処理\nvoid COMinit() {\n    fac[0] = fac[1] = 1;\n    finv[0] = finv[1] = 1;\n    inv[1] = 1;\n    for (int i = 2; i < MAX; i++){\n        fac[i] = fac[i - 1] * i % MOD;\n        inv[i] = MOD - inv[MOD%i] * (MOD / i) % MOD;\n        finv[i] = finv[i - 1] * inv[i] % MOD;\n    }\n}\n\nstruct mint {\n  ll x; // typedef long long ll;\n    mint(ll x=0):x((x%MOD+MOD)%MOD){}\n    mint operator-() const { return mint(-x);}\n    mint& operator+=(const mint a) {\n    if ((x += a.x) >= MOD) x -= MOD;\n    return *this;\n    }\n    mint& operator-=(const mint a) {\n    if ((x += MOD-a.x) >= MOD) x -= MOD;\n    return *this;\n    }\n    mint& operator*=(const mint a) {\n        (x *= a.x) %= MOD;\n        return *this;\n    }\n    mint operator+(const mint a) const {\n        mint res(*this);\n        return res+=a;\n    }\n    mint operator-(const mint a) const {\n        mint res(*this);\n        return res-=a;\n    }\n    mint operator*(const mint a) const {\n        mint res(*this);\n        return res*=a;\n    }\n    mint pow(ll t) const {\n        if (!t) return 1;\n        mint a = pow(t>>1);\n        a *= a;\n        if (t&1) a *= *this;\n        return a;\n    }\n\n    // for prime MOD\n    mint inv() const {\n        return pow(MOD-2);\n    }\n    mint& operator/=(const mint a) {\n        return (*this) *= a.inv();\n    }\n    mint operator/(const mint a) const {\n        mint res(*this);\n        return res/=a;\n    }\n};\n\n// 二項係数計算\nlong long COM(int n, int k){\n    if (n < k) return 0;\n    if (n < 0 || k < 0) return 0;\n    return fac[n] * (finv[k] * finv[n - k] % MOD) % MOD;\n}\n\n\n//階乗\nll kaijo(ll k){\n    ll sum = 1;\n    for (ll i = 1; i <= k; ++i)\n    {\n        sum *= i;\n        sum%=1000000000+7;\n    }\n    return sum;\n}\n\nlong long modpow(long long a, long long n, long long MOD) {\n    long long res = 1;\n    while (n > 0) {\n        if (n & 1) res = res * a % MOD;\n        a = a * a % MOD;\n        n >>= 1;\n    }\n    return res;\n}\n\n//sieve(MAX);でベクトルIsPrimeに「MAXまでの数値の素数の真偽」を格納する。\nstruct Sieve {\n    int n;\n    vector<int> f, primes;\n    Sieve(int n=1):n(n), f(n+1) {\n        f[0] = f[1] = -1;\n        for (ll i = 2; i <= n; ++i) {\n        if (f[i]) continue;\n        primes.push_back(i);\n        f[i] = i;\n        for (ll j = i*i; j <= n; j += i) {\n            if (!f[j]) f[j] = i;\n        }\n        }\n    }\n    bool isPrime(int x) { return f[x] == x;}\n    vector<int> factorList(int x) {\n        vector<int> res;\n        while (x != 1) {\n        res.push_back(f[x]);\n        x /= f[x];\n        }\n        return res;\n    }\n    vector<P> factor(int x) {\n        vector<int> fl = factorList(x);\n        if (fl.size() == 0) return {};\n        vector<P> res(1, P(fl[0], 0));\n        for (int p : fl) {\n        if (res.back().first == p) {\n            res.back().second++;\n        } else {\n            res.emplace_back(p, 1);\n        }\n        }\n        return res;\n    }\n};\nstruct UnionFind {\n    vector<int> par;\n    UnionFind(int n) : par(n, -1) { }\n    int root(int x) {\n        if (par[x] < 0) return x;\n        else return par[x] = root(par[x]);\n    }\n    bool issame(int x, int y) {\n        return root(x) == root(y);\n    }\n    bool merge(int x, int y) {\n        x = root(x); y = root(y);\n        if (x == y) return false;\n        if (par[x] > par[y]) swap(x, y); // merge technique\n        par[x] += par[y];\n        par[y] = x;\n        return true;\n    }\n    int size(int x) {\n        return -par[root(x)];\n    }\n};\n\nll count(int n, int a){\n    ll bunshi = 1;\n    for(int i = 0; i < a; i++){\n        bunshi*=(n-i);\n        bunshi%=MOD;\n    }\n    ll bunbo = 1;\n    for(int i = 1; i < a+1; i++){\n        bunbo*=i;\n        bunbo%=MOD;\n    }\n    bunbo = modpow(bunbo,MOD-2,MOD);\n    // cout<<(bunshi*bunbo)%MOD<<endl;\n    return (bunshi*bunbo)%MOD;\n}\n\n// 約数列挙。約数をvector<ll>で返す。計算量はsqrt(n)。\nvector<ll> divisor(ll n) {\n    vector<ll> ret;\n    for(ll i = 1; i * i <= n; i++) {\n        if(n % i == 0) {\n        ret.push_back(i);\n        if(i * i != n) ret.push_back(n / i);\n        }\n    }\n    sort(begin(ret), end(ret));\n    return (ret);\n}\n\n\n\n// ここから開始\nconst ll INF = 1e18;\n\nint main(){\n    Sieve sieve(1e6);\n    int N;\n    cin>>N;\n    int a[N];\n    map<int,int> mp;\n    for(int i = 0; i < N; i++){\n        cin>>a[i];\n    }\n    rep(i,N){\n        auto f = sieve.factor(a[i]);\n        for(auto p: f){\n            mp[p.first] = max(mp[p.first],p.second);\n        }\n    }\n    // for(int j = 2; j <= 100000; j++) if(v[j]>0)cout<<j<<\" \"<<v[j]<<endl;\n    mint lcm = 0;\n    for(auto p: mp){\n        rep(i, p.second){\n            lcm*=p.first;\n        }\n    }\n    mint ans;\n    rep(i,N){\n        mint s = lcm/a[i];\n        ans+=s;\n    }\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1588492430, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02793.html", "problem_id": "p02793", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02793/input.txt", "sample_output_relpath": "derived/input_output/data/p02793/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02793/C++/s544939004.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s544939004", "user_id": "u622585907"}, "prompt_components": {"gold_output": "13\n", "input_to_evaluate": "#include <iostream>\n#include <cstring>\n#include <map>\n#include <iomanip>\n#include <algorithm>\n#include <cmath>\n#include <set>\n#include <vector>\n#include <queue>\n#include <list>\n#include <numeric>\n#include <stdio.h>\n#include <string>\n#include <cstdlib>\n#include <math.h>\n#include <stack>\n#include <climits>\n#include <bitset>\n#include <utility>\n#define rep(i,n) for (int i = 0; i < (n); ++i)\n\nusing namespace std;\nusing P = pair<int,int>;\ntypedef long long ll;\ntemplate<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }\n\n//最大公約数\nll gcd(ll x, ll y) {\n    ll tmp = 0;\n    if (x < y){\n        tmp=x;\n        x=y;\n        y=tmp;\n    }\n    while (y > 0) {\n        ll r = x % y;\n        x = y;\n        y = r;\n        }\n    return x;\n}\n\n//最大公倍数\nll lcm(ll x,ll y){\n    return x/gcd(x,y)*y;\n}\n\nconst int MAX = 1e6+1;\nconst ll MOD = 1e9+7;\n\nlong long fac[MAX], finv[MAX], inv[MAX];\n\n// テーブルを作る前処理\nvoid COMinit() {\n    fac[0] = fac[1] = 1;\n    finv[0] = finv[1] = 1;\n    inv[1] = 1;\n    for (int i = 2; i < MAX; i++){\n        fac[i] = fac[i - 1] * i % MOD;\n        inv[i] = MOD - inv[MOD%i] * (MOD / i) % MOD;\n        finv[i] = finv[i - 1] * inv[i] % MOD;\n    }\n}\n\nstruct mint {\n  ll x; // typedef long long ll;\n    mint(ll x=0):x((x%MOD+MOD)%MOD){}\n    mint operator-() const { return mint(-x);}\n    mint& operator+=(const mint a) {\n    if ((x += a.x) >= MOD) x -= MOD;\n    return *this;\n    }\n    mint& operator-=(const mint a) {\n    if ((x += MOD-a.x) >= MOD) x -= MOD;\n    return *this;\n    }\n    mint& operator*=(const mint a) {\n        (x *= a.x) %= MOD;\n        return *this;\n    }\n    mint operator+(const mint a) const {\n        mint res(*this);\n        return res+=a;\n    }\n    mint operator-(const mint a) const {\n        mint res(*this);\n        return res-=a;\n    }\n    mint operator*(const mint a) const {\n        mint res(*this);\n        return res*=a;\n    }\n    mint pow(ll t) const {\n        if (!t) return 1;\n        mint a = pow(t>>1);\n        a *= a;\n        if (t&1) a *= *this;\n        return a;\n    }\n\n    // for prime MOD\n    mint inv() const {\n        return pow(MOD-2);\n    }\n    mint& operator/=(const mint a) {\n        return (*this) *= a.inv();\n    }\n    mint operator/(const mint a) const {\n        mint res(*this);\n        return res/=a;\n    }\n};\n\n// 二項係数計算\nlong long COM(int n, int k){\n    if (n < k) return 0;\n    if (n < 0 || k < 0) return 0;\n    return fac[n] * (finv[k] * finv[n - k] % MOD) % MOD;\n}\n\n\n//階乗\nll kaijo(ll k){\n    ll sum = 1;\n    for (ll i = 1; i <= k; ++i)\n    {\n        sum *= i;\n        sum%=1000000000+7;\n    }\n    return sum;\n}\n\nlong long modpow(long long a, long long n, long long MOD) {\n    long long res = 1;\n    while (n > 0) {\n        if (n & 1) res = res * a % MOD;\n        a = a * a % MOD;\n        n >>= 1;\n    }\n    return res;\n}\n\n//sieve(MAX);でベクトルIsPrimeに「MAXまでの数値の素数の真偽」を格納する。\nstruct Sieve {\n    int n;\n    vector<int> f, primes;\n    Sieve(int n=1):n(n), f(n+1) {\n        f[0] = f[1] = -1;\n        for (ll i = 2; i <= n; ++i) {\n        if (f[i]) continue;\n        primes.push_back(i);\n        f[i] = i;\n        for (ll j = i*i; j <= n; j += i) {\n            if (!f[j]) f[j] = i;\n        }\n        }\n    }\n    bool isPrime(int x) { return f[x] == x;}\n    vector<int> factorList(int x) {\n        vector<int> res;\n        while (x != 1) {\n        res.push_back(f[x]);\n        x /= f[x];\n        }\n        return res;\n    }\n    vector<P> factor(int x) {\n        vector<int> fl = factorList(x);\n        if (fl.size() == 0) return {};\n        vector<P> res(1, P(fl[0], 0));\n        for (int p : fl) {\n        if (res.back().first == p) {\n            res.back().second++;\n        } else {\n            res.emplace_back(p, 1);\n        }\n        }\n        return res;\n    }\n};\nstruct UnionFind {\n    vector<int> par;\n    UnionFind(int n) : par(n, -1) { }\n    int root(int x) {\n        if (par[x] < 0) return x;\n        else return par[x] = root(par[x]);\n    }\n    bool issame(int x, int y) {\n        return root(x) == root(y);\n    }\n    bool merge(int x, int y) {\n        x = root(x); y = root(y);\n        if (x == y) return false;\n        if (par[x] > par[y]) swap(x, y); // merge technique\n        par[x] += par[y];\n        par[y] = x;\n        return true;\n    }\n    int size(int x) {\n        return -par[root(x)];\n    }\n};\n\nll count(int n, int a){\n    ll bunshi = 1;\n    for(int i = 0; i < a; i++){\n        bunshi*=(n-i);\n        bunshi%=MOD;\n    }\n    ll bunbo = 1;\n    for(int i = 1; i < a+1; i++){\n        bunbo*=i;\n        bunbo%=MOD;\n    }\n    bunbo = modpow(bunbo,MOD-2,MOD);\n    // cout<<(bunshi*bunbo)%MOD<<endl;\n    return (bunshi*bunbo)%MOD;\n}\n\n// 約数列挙。約数をvector<ll>で返す。計算量はsqrt(n)。\nvector<ll> divisor(ll n) {\n    vector<ll> ret;\n    for(ll i = 1; i * i <= n; i++) {\n        if(n % i == 0) {\n        ret.push_back(i);\n        if(i * i != n) ret.push_back(n / i);\n        }\n    }\n    sort(begin(ret), end(ret));\n    return (ret);\n}\n\n\n\n// ここから開始\nconst ll INF = 1e18;\n\nint main(){\n    Sieve sieve(1e6);\n    int N;\n    cin>>N;\n    int a[N];\n    map<int,int> mp;\n    for(int i = 0; i < N; i++){\n        cin>>a[i];\n    }\n    rep(i,N){\n        auto f = sieve.factor(a[i]);\n        for(auto p: f){\n            mp[p.first] = max(mp[p.first],p.second);\n        }\n    }\n    // for(int j = 2; j <= 100000; j++) if(v[j]>0)cout<<j<<\" \"<<v[j]<<endl;\n    mint lcm = 0;\n    for(auto p: mp){\n        rep(i, p.second){\n            lcm*=p.first;\n        }\n    }\n    mint ans;\n    rep(i,N){\n        mint s = lcm/a[i];\n        ans+=s;\n    }\n    return 0;\n}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nGiven are N positive integers A_1,...,A_N.\n\nConsider positive integers B_1, ..., B_N that satisfy the following condition.\n\nCondition: For any i, j such that 1 \\leq i < j \\leq N, A_i B_i = A_j B_j holds.\n\nFind the minimum possible value of B_1 + ... + B_N for such B_1,...,B_N.\n\nSince the answer can be enormous, print the sum modulo (10^9 +7).\n\nConstraints\n\n1 \\leq N \\leq 10^4\n\n1 \\leq A_i \\leq 10^6\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 ... A_N\n\nOutput\n\nPrint the minimum possible value of B_1 + ... + B_N for B_1,...,B_N that satisfy the condition, modulo (10^9 +7).\n\nSample Input 1\n\n3\n2 3 4\n\nSample Output 1\n\n13\n\nLet B_1=6, B_2=4, and B_3=3, and the condition will be satisfied.\n\nSample Input 2\n\n5\n12 12 12 12 12\n\nSample Output 2\n\n5\n\nWe can let all B_i be 1.\n\nSample Input 3\n\n3\n1000000 999999 999998\n\nSample Output 3\n\n996989508\n\nPrint the sum modulo (10^9+7).", "sample_input": "3\n2 3 4\n"}, "reference_outputs": ["13\n"], "source_document_id": "p02793", "source_text": "Score : 500 points\n\nProblem Statement\n\nGiven are N positive integers A_1,...,A_N.\n\nConsider positive integers B_1, ..., B_N that satisfy the following condition.\n\nCondition: For any i, j such that 1 \\leq i < j \\leq N, A_i B_i = A_j B_j holds.\n\nFind the minimum possible value of B_1 + ... + B_N for such B_1,...,B_N.\n\nSince the answer can be enormous, print the sum modulo (10^9 +7).\n\nConstraints\n\n1 \\leq N \\leq 10^4\n\n1 \\leq A_i \\leq 10^6\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 ... A_N\n\nOutput\n\nPrint the minimum possible value of B_1 + ... + B_N for B_1,...,B_N that satisfy the condition, modulo (10^9 +7).\n\nSample Input 1\n\n3\n2 3 4\n\nSample Output 1\n\n13\n\nLet B_1=6, B_2=4, and B_3=3, and the condition will be satisfied.\n\nSample Input 2\n\n5\n12 12 12 12 12\n\nSample Output 2\n\n5\n\nWe can let all B_i be 1.\n\nSample Input 3\n\n3\n1000000 999999 999998\n\nSample Output 3\n\n996989508\n\nPrint the sum modulo (10^9+7).", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 5769, "cpu_time_ms": 18, "memory_kb": 4984}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s159247731", "group_id": "codeNet:p02795", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n  int H, W, N;\n  cin >> H >> W >> N;\n  int ans = 0;\n  if (N%max(H, W)==0) ans = N/max(H, W);\n  else ans = N/max(H, W)+1;\n  cout << ans << endl;\n}", "language": "C++", "metadata": {"date": 1579377951, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02795.html", "problem_id": "p02795", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02795/input.txt", "sample_output_relpath": "derived/input_output/data/p02795/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02795/C++/s159247731.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s159247731", "user_id": "u852770206"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n  int H, W, N;\n  cin >> H >> W >> N;\n  int ans = 0;\n  if (N%max(H, W)==0) ans = N/max(H, W);\n  else ans = N/max(H, W)+1;\n  cout << ans << endl;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nWe have a grid with H rows and W columns, where all the squares are initially white.\n\nYou will perform some number of painting operations on the grid.\nIn one operation, you can do one of the following two actions:\n\nChoose one row, then paint all the squares in that row black.\n\nChoose one column, then paint all the squares in that column black.\n\nAt least how many operations do you need in order to have N or more black squares in the grid?\nIt is guaranteed that, under the conditions in Constraints, having N or more black squares is always possible by performing some number of operations.\n\nConstraints\n\n1 \\leq H \\leq 100\n\n1 \\leq W \\leq 100\n\n1 \\leq N \\leq H \\times W\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH\nW\nN\n\nOutput\n\nPrint the minimum number of operations needed.\n\nSample Input 1\n\n3\n7\n10\n\nSample Output 1\n\n2\n\nYou can have 14 black squares in the grid by performing the \"row\" operation twice, on different rows.\n\nSample Input 2\n\n14\n12\n112\n\nSample Output 2\n\n8\n\nSample Input 3\n\n2\n100\n200\n\nSample Output 3\n\n2", "sample_input": "3\n7\n10\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02795", "source_text": "Score : 100 points\n\nProblem Statement\n\nWe have a grid with H rows and W columns, where all the squares are initially white.\n\nYou will perform some number of painting operations on the grid.\nIn one operation, you can do one of the following two actions:\n\nChoose one row, then paint all the squares in that row black.\n\nChoose one column, then paint all the squares in that column black.\n\nAt least how many operations do you need in order to have N or more black squares in the grid?\nIt is guaranteed that, under the conditions in Constraints, having N or more black squares is always possible by performing some number of operations.\n\nConstraints\n\n1 \\leq H \\leq 100\n\n1 \\leq W \\leq 100\n\n1 \\leq N \\leq H \\times W\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH\nW\nN\n\nOutput\n\nPrint the minimum number of operations needed.\n\nSample Input 1\n\n3\n7\n10\n\nSample Output 1\n\n2\n\nYou can have 14 black squares in the grid by performing the \"row\" operation twice, on different rows.\n\nSample Input 2\n\n14\n12\n112\n\nSample Output 2\n\n8\n\nSample Input 3\n\n2\n100\n200\n\nSample Output 3\n\n2", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 205, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s743099729", "group_id": "codeNet:p02801", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\nchar C;\ncin>>C;\n     if(C=='a')\ncout<<\"b\"<<endl;\nelse if(C=='b')\ncout<<\"c\"<<endl;\nelse if(C=='c')\ncout<<\"d\"<<endl;\nelse  if(C=='d')\ncout<<\"e\"<<endl;\nelse  if(C=='e')\ncout<<\"f\"<<endl;\nelse  if(C=='f')\ncout<<\"g\"<<endl;\nelse  if(C=='g')\ncout<<\"h\"<<endl;\nelse  if(C=='h')\ncout<<\"i\"<<endl;\nelse  if(C=='i')\ncout<<\"j\"<<endl;\nelse  if(C=='j')\ncout<<\"k\"<<endl;\nelse  if(C=='k')\ncout<<\"l\"<<endl;\nelse  if(C=='l')\ncout<<\"m\"<<endl;\nelse  if(C=='m')\ncout<<\"n\"<<endl;\nelse  if(C=='n')\ncout<<\"o\"<<endl;\nelse  if(C=='o')\ncout<<\"p\"<<endl;\nelse  if(C=='p')\ncout<<\"q\"<<endl;\nelse  if(C=='q')\ncout<<\"r\"<<endl;\nelse  if(C=='r')\ncout<<\"s\"<<endl;\nelse if(C=='s')\ncout<<\"t\"<<endl;\nelse if(C=='t')\ncout<<\"u\"<<endl;\nelse if(C=='u')\ncout<<\"v\"<<endl;\nelse  if(C=='v')\ncout<<\"w\"<<endl;\nelse if(C=='w')\ncout<<\"x\"<<endl;\nelse if(C=='x')\ncout<<\"y\"<<endl;\nelse if(C=='y')\ncout<<\"z\"<<endl;\n}", "language": "C++", "metadata": {"date": 1587647830, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02801.html", "problem_id": "p02801", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02801/input.txt", "sample_output_relpath": "derived/input_output/data/p02801/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02801/C++/s743099729.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s743099729", "user_id": "u983563612"}, "prompt_components": {"gold_output": "b\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\nchar C;\ncin>>C;\n     if(C=='a')\ncout<<\"b\"<<endl;\nelse if(C=='b')\ncout<<\"c\"<<endl;\nelse if(C=='c')\ncout<<\"d\"<<endl;\nelse  if(C=='d')\ncout<<\"e\"<<endl;\nelse  if(C=='e')\ncout<<\"f\"<<endl;\nelse  if(C=='f')\ncout<<\"g\"<<endl;\nelse  if(C=='g')\ncout<<\"h\"<<endl;\nelse  if(C=='h')\ncout<<\"i\"<<endl;\nelse  if(C=='i')\ncout<<\"j\"<<endl;\nelse  if(C=='j')\ncout<<\"k\"<<endl;\nelse  if(C=='k')\ncout<<\"l\"<<endl;\nelse  if(C=='l')\ncout<<\"m\"<<endl;\nelse  if(C=='m')\ncout<<\"n\"<<endl;\nelse  if(C=='n')\ncout<<\"o\"<<endl;\nelse  if(C=='o')\ncout<<\"p\"<<endl;\nelse  if(C=='p')\ncout<<\"q\"<<endl;\nelse  if(C=='q')\ncout<<\"r\"<<endl;\nelse  if(C=='r')\ncout<<\"s\"<<endl;\nelse if(C=='s')\ncout<<\"t\"<<endl;\nelse if(C=='t')\ncout<<\"u\"<<endl;\nelse if(C=='u')\ncout<<\"v\"<<endl;\nelse  if(C=='v')\ncout<<\"w\"<<endl;\nelse if(C=='w')\ncout<<\"x\"<<endl;\nelse if(C=='x')\ncout<<\"y\"<<endl;\nelse if(C=='y')\ncout<<\"z\"<<endl;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nGiven is a lowercase English letter C that is not z. Print the letter that follows C in alphabetical order.\n\nConstraints\n\nC is a lowercase English letter that is not z.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nC\n\nOutput\n\nPrint the letter that follows C in alphabetical order.\n\nSample Input 1\n\na\n\nSample Output 1\n\nb\n\na is followed by b.\n\nSample Input 2\n\ny\n\nSample Output 2\n\nz\n\ny is followed by z.", "sample_input": "a\n"}, "reference_outputs": ["b\n"], "source_document_id": "p02801", "source_text": "Score : 100 points\n\nProblem Statement\n\nGiven is a lowercase English letter C that is not z. Print the letter that follows C in alphabetical order.\n\nConstraints\n\nC is a lowercase English letter that is not z.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nC\n\nOutput\n\nPrint the letter that follows C in alphabetical order.\n\nSample Input 1\n\na\n\nSample Output 1\n\nb\n\na is followed by b.\n\nSample Input 2\n\ny\n\nSample Output 2\n\nz\n\ny is followed by z.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 918, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s969550745", "group_id": "codeNet:p02802", "input_text": "#include <bits/stdc++.h>\n\n#ifdef __LOCAL\n    #define DBG(X) cout << #X << \" = \" << (X) << endl;\n    #define SAY(X) cout << (X) << endl;\n#else\n    #define DBG(X)\n    #define SAY(X)\n#endif\n\nusing namespace std;\nusing ll = long long int;\ninline void fast_io() { ios_base::sync_with_stdio(false); cin.tie(nullptr); cout.tie(nullptr); };\n\n\nint main()\n{\n\n    ll N,M;\n    ll __correct, __wrong;\n    __correct = __wrong = 0;\n    cin >> N >> M;\n    vector<bool> AC(N+10,false);\n\n    for(int i=0;i<M;i++){\n        int p;\n        string S;\n        cin >> p >> S;\n        if(AC[p]) continue;\n        else{\n            if(S==\"AC\"){\n                AC[p] = true;\n                __correct++;\n            }\n            else if(S==\"WA\"){\n                __wrong++;\n            }\n        }\n\n    }\n\n    cout << __correct << \" \" << __wrong << endl;\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1578886124, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02802.html", "problem_id": "p02802", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02802/input.txt", "sample_output_relpath": "derived/input_output/data/p02802/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02802/C++/s969550745.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s969550745", "user_id": "u858670323"}, "prompt_components": {"gold_output": "2 2\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\n#ifdef __LOCAL\n    #define DBG(X) cout << #X << \" = \" << (X) << endl;\n    #define SAY(X) cout << (X) << endl;\n#else\n    #define DBG(X)\n    #define SAY(X)\n#endif\n\nusing namespace std;\nusing ll = long long int;\ninline void fast_io() { ios_base::sync_with_stdio(false); cin.tie(nullptr); cout.tie(nullptr); };\n\n\nint main()\n{\n\n    ll N,M;\n    ll __correct, __wrong;\n    __correct = __wrong = 0;\n    cin >> N >> M;\n    vector<bool> AC(N+10,false);\n\n    for(int i=0;i<M;i++){\n        int p;\n        string S;\n        cin >> p >> S;\n        if(AC[p]) continue;\n        else{\n            if(S==\"AC\"){\n                AC[p] = true;\n                __correct++;\n            }\n            else if(S==\"WA\"){\n                __wrong++;\n            }\n        }\n\n    }\n\n    cout << __correct << \" \" << __wrong << endl;\n    return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nTakahashi participated in a contest on AtCoder.\n\nThe contest had N problems.\n\nTakahashi made M submissions during the contest.\n\nThe i-th submission was made for the p_i-th problem and received the verdict S_i (AC or WA).\n\nThe number of Takahashi's correct answers is the number of problems on which he received an AC once or more.\n\nThe number of Takahashi's penalties is the sum of the following count for the problems on which he received an AC once or more: the number of WAs received before receiving an AC for the first time on that problem.\n\nFind the numbers of Takahashi's correct answers and penalties.\n\nConstraints\n\nN, M, and p_i are integers.\n\n1 \\leq N \\leq 10^5\n\n0 \\leq M \\leq 10^5\n\n1 \\leq p_i \\leq N\n\nS_i is AC or WA.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\np_1 S_1\n:\np_M S_M\n\nOutput\n\nPrint the number of Takahashi's correct answers and the number of Takahashi's penalties.\n\nSample Input 1\n\n2 5\n1 WA\n1 AC\n2 WA\n2 AC\n2 WA\n\nSample Output 1\n\n2 2\n\nIn his second submission, he received an AC on the first problem for the first time. Before this, he received one WA on this problem.\n\nIn his fourth submission, he received an AC on the second problem for the first time. Before this, he received one WA on this problem.\n\nThus, he has two correct answers and two penalties.\n\nSample Input 2\n\n100000 3\n7777 AC\n7777 AC\n7777 AC\n\nSample Output 2\n\n1 0\n\nNote that it is pointless to get an AC more than once on the same problem.\n\nSample Input 3\n\n6 0\n\nSample Output 3\n\n0 0", "sample_input": "2 5\n1 WA\n1 AC\n2 WA\n2 AC\n2 WA\n"}, "reference_outputs": ["2 2\n"], "source_document_id": "p02802", "source_text": "Score : 300 points\n\nProblem Statement\n\nTakahashi participated in a contest on AtCoder.\n\nThe contest had N problems.\n\nTakahashi made M submissions during the contest.\n\nThe i-th submission was made for the p_i-th problem and received the verdict S_i (AC or WA).\n\nThe number of Takahashi's correct answers is the number of problems on which he received an AC once or more.\n\nThe number of Takahashi's penalties is the sum of the following count for the problems on which he received an AC once or more: the number of WAs received before receiving an AC for the first time on that problem.\n\nFind the numbers of Takahashi's correct answers and penalties.\n\nConstraints\n\nN, M, and p_i are integers.\n\n1 \\leq N \\leq 10^5\n\n0 \\leq M \\leq 10^5\n\n1 \\leq p_i \\leq N\n\nS_i is AC or WA.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\np_1 S_1\n:\np_M S_M\n\nOutput\n\nPrint the number of Takahashi's correct answers and the number of Takahashi's penalties.\n\nSample Input 1\n\n2 5\n1 WA\n1 AC\n2 WA\n2 AC\n2 WA\n\nSample Output 1\n\n2 2\n\nIn his second submission, he received an AC on the first problem for the first time. Before this, he received one WA on this problem.\n\nIn his fourth submission, he received an AC on the second problem for the first time. Before this, he received one WA on this problem.\n\nThus, he has two correct answers and two penalties.\n\nSample Input 2\n\n100000 3\n7777 AC\n7777 AC\n7777 AC\n\nSample Output 2\n\n1 0\n\nNote that it is pointless to get an AC more than once on the same problem.\n\nSample Input 3\n\n6 0\n\nSample Output 3\n\n0 0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 846, "cpu_time_ms": 66, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s539538321", "group_id": "codeNet:p02802", "input_text": "#include<iostream>\nusing namespace std;\n#include<string>\nint main()\n{int n,m, a[10],i,cnt=0,cnt1=0;\n string s[10];\n cin>>n>>m;\n for(i=0;i<m;i++)\n   cin>>a[i]>>s[i];\n for(i=0;i<m;i++)\n {if(s[i]==\"AC\")\n {++cnt;continue;}\n  else if(s[i]==\"WA\")\n  {++cnt1;}}\n cout<<cnt<<cnt1;\n return 0;}\n \n ", "language": "C++", "metadata": {"date": 1578885525, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02802.html", "problem_id": "p02802", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02802/input.txt", "sample_output_relpath": "derived/input_output/data/p02802/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02802/C++/s539538321.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s539538321", "user_id": "u394741016"}, "prompt_components": {"gold_output": "2 2\n", "input_to_evaluate": "#include<iostream>\nusing namespace std;\n#include<string>\nint main()\n{int n,m, a[10],i,cnt=0,cnt1=0;\n string s[10];\n cin>>n>>m;\n for(i=0;i<m;i++)\n   cin>>a[i]>>s[i];\n for(i=0;i<m;i++)\n {if(s[i]==\"AC\")\n {++cnt;continue;}\n  else if(s[i]==\"WA\")\n  {++cnt1;}}\n cout<<cnt<<cnt1;\n return 0;}\n \n ", "problem_context": "Score : 300 points\n\nProblem Statement\n\nTakahashi participated in a contest on AtCoder.\n\nThe contest had N problems.\n\nTakahashi made M submissions during the contest.\n\nThe i-th submission was made for the p_i-th problem and received the verdict S_i (AC or WA).\n\nThe number of Takahashi's correct answers is the number of problems on which he received an AC once or more.\n\nThe number of Takahashi's penalties is the sum of the following count for the problems on which he received an AC once or more: the number of WAs received before receiving an AC for the first time on that problem.\n\nFind the numbers of Takahashi's correct answers and penalties.\n\nConstraints\n\nN, M, and p_i are integers.\n\n1 \\leq N \\leq 10^5\n\n0 \\leq M \\leq 10^5\n\n1 \\leq p_i \\leq N\n\nS_i is AC or WA.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\np_1 S_1\n:\np_M S_M\n\nOutput\n\nPrint the number of Takahashi's correct answers and the number of Takahashi's penalties.\n\nSample Input 1\n\n2 5\n1 WA\n1 AC\n2 WA\n2 AC\n2 WA\n\nSample Output 1\n\n2 2\n\nIn his second submission, he received an AC on the first problem for the first time. Before this, he received one WA on this problem.\n\nIn his fourth submission, he received an AC on the second problem for the first time. Before this, he received one WA on this problem.\n\nThus, he has two correct answers and two penalties.\n\nSample Input 2\n\n100000 3\n7777 AC\n7777 AC\n7777 AC\n\nSample Output 2\n\n1 0\n\nNote that it is pointless to get an AC more than once on the same problem.\n\nSample Input 3\n\n6 0\n\nSample Output 3\n\n0 0", "sample_input": "2 5\n1 WA\n1 AC\n2 WA\n2 AC\n2 WA\n"}, "reference_outputs": ["2 2\n"], "source_document_id": "p02802", "source_text": "Score : 300 points\n\nProblem Statement\n\nTakahashi participated in a contest on AtCoder.\n\nThe contest had N problems.\n\nTakahashi made M submissions during the contest.\n\nThe i-th submission was made for the p_i-th problem and received the verdict S_i (AC or WA).\n\nThe number of Takahashi's correct answers is the number of problems on which he received an AC once or more.\n\nThe number of Takahashi's penalties is the sum of the following count for the problems on which he received an AC once or more: the number of WAs received before receiving an AC for the first time on that problem.\n\nFind the numbers of Takahashi's correct answers and penalties.\n\nConstraints\n\nN, M, and p_i are integers.\n\n1 \\leq N \\leq 10^5\n\n0 \\leq M \\leq 10^5\n\n1 \\leq p_i \\leq N\n\nS_i is AC or WA.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\np_1 S_1\n:\np_M S_M\n\nOutput\n\nPrint the number of Takahashi's correct answers and the number of Takahashi's penalties.\n\nSample Input 1\n\n2 5\n1 WA\n1 AC\n2 WA\n2 AC\n2 WA\n\nSample Output 1\n\n2 2\n\nIn his second submission, he received an AC on the first problem for the first time. Before this, he received one WA on this problem.\n\nIn his fourth submission, he received an AC on the second problem for the first time. Before this, he received one WA on this problem.\n\nThus, he has two correct answers and two penalties.\n\nSample Input 2\n\n100000 3\n7777 AC\n7777 AC\n7777 AC\n\nSample Output 2\n\n1 0\n\nNote that it is pointless to get an AC more than once on the same problem.\n\nSample Input 3\n\n6 0\n\nSample Output 3\n\n0 0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 287, "cpu_time_ms": 97, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s284041490", "group_id": "codeNet:p02804", "input_text": "#define _USE_MATH_DEFINES\n#include<iostream>\n#include<string>\n#include<vector>\n#include<algorithm>\n#include<stdio.h>\n#include<cmath>\n#include<stack>\n#include<set>\n#include<map>\n#include<stdio.h>\n#include<functional>\n#include<queue>\n\nusing ll = long long;\n\nusing namespace std;\n\nll mod = 1000000007;\n\nll n_pow(ll a, ll n) {\n\tif (n == 0)return 1;\n\tll t = n_pow(a, n / 2);\n\tt *= t;\n\tt %= mod;\n\tif (n % 2 == 1)t *= a;\n\treturn t % mod;\n}\n\nconst int INF = 1001001001;\n\n\nint main() {\n\tll n, k;\n\tcin >> n >> k;\n\tvector<ll>a(n);\n\tfor (int i = 0; i < n; i++) {\n\t\tcin >> a[i];\n\t}\n\tsort(a.begin(), a.end());\n\tvector<ll>f(n + 1), f_inv(n + 1);\n\tf[0] = 1;\n\tf_inv[0] = n_pow(f[0], mod - 2);\n\tfor (int i = 1; i < n + 1; i++) {\n\t\tf[i] = (i*f[i - 1]) % mod;\n\t\tf_inv[i] = n_pow(f[i], mod - 2);\n\t}\n\tll s_max = 0;\n\tfor (int i = k - 1; i < n; i++) {\n\t\tll tmp = (((f[i] * f_inv[i - k + 1]) % mod)*f_inv[k - 1]) % mod;\n\t\ts_max += (tmp * a[i]) % mod;\n\t\ts_max %= mod;\n\t}\n\tll s_min = 0;\n\tfor (int i = 0; i < n - k + 1; i++) {\n\t\tll tmp = (((f[n - i - 1] * f_inv[n - i - k]) % mod)*f_inv[k - 1]) % mod;\n\t\ts_min += (tmp * a[i]) % mod;\n\t\ts_min %= mod;\n\t}\n\tll ans = (s_max - s_min) % mod;\n\tif (ans < 0)ans += mod;\n\tcout << ans << endl;\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1587844426, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02804.html", "problem_id": "p02804", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02804/input.txt", "sample_output_relpath": "derived/input_output/data/p02804/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02804/C++/s284041490.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s284041490", "user_id": "u670815700"}, "prompt_components": {"gold_output": "11\n", "input_to_evaluate": "#define _USE_MATH_DEFINES\n#include<iostream>\n#include<string>\n#include<vector>\n#include<algorithm>\n#include<stdio.h>\n#include<cmath>\n#include<stack>\n#include<set>\n#include<map>\n#include<stdio.h>\n#include<functional>\n#include<queue>\n\nusing ll = long long;\n\nusing namespace std;\n\nll mod = 1000000007;\n\nll n_pow(ll a, ll n) {\n\tif (n == 0)return 1;\n\tll t = n_pow(a, n / 2);\n\tt *= t;\n\tt %= mod;\n\tif (n % 2 == 1)t *= a;\n\treturn t % mod;\n}\n\nconst int INF = 1001001001;\n\n\nint main() {\n\tll n, k;\n\tcin >> n >> k;\n\tvector<ll>a(n);\n\tfor (int i = 0; i < n; i++) {\n\t\tcin >> a[i];\n\t}\n\tsort(a.begin(), a.end());\n\tvector<ll>f(n + 1), f_inv(n + 1);\n\tf[0] = 1;\n\tf_inv[0] = n_pow(f[0], mod - 2);\n\tfor (int i = 1; i < n + 1; i++) {\n\t\tf[i] = (i*f[i - 1]) % mod;\n\t\tf_inv[i] = n_pow(f[i], mod - 2);\n\t}\n\tll s_max = 0;\n\tfor (int i = k - 1; i < n; i++) {\n\t\tll tmp = (((f[i] * f_inv[i - k + 1]) % mod)*f_inv[k - 1]) % mod;\n\t\ts_max += (tmp * a[i]) % mod;\n\t\ts_max %= mod;\n\t}\n\tll s_min = 0;\n\tfor (int i = 0; i < n - k + 1; i++) {\n\t\tll tmp = (((f[n - i - 1] * f_inv[n - i - k]) % mod)*f_inv[k - 1]) % mod;\n\t\ts_min += (tmp * a[i]) % mod;\n\t\ts_min %= mod;\n\t}\n\tll ans = (s_max - s_min) % mod;\n\tif (ans < 0)ans += mod;\n\tcout << ans << endl;\n\treturn 0;\n}", "problem_context": "Score : 500 points\n\nProblem Statement\n\nFor a finite set of integers X, let f(X)=\\max X - \\min X.\n\nGiven are N integers A_1,...,A_N.\n\nWe will choose K of them and let S be the set of the integers chosen. If we distinguish elements with different indices even when their values are the same, there are {}_N C_K ways to make this choice. Find the sum of f(S) over all those ways.\n\nSince the answer can be enormous, print it \\bmod (10^9+7).\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq K \\leq N\n\n|A_i| \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nA_1 ... A_N\n\nOutput\n\nPrint the answer \\bmod (10^9+7).\n\nSample Input 1\n\n4 2\n1 1 3 4\n\nSample Output 1\n\n11\n\nThere are six ways to choose S: \\{1,1\\},\\{1,3\\},\\{1,4\\},\\{1,3\\},\\{1,4\\}, \\{3,4\\} (we distinguish the two 1s). The value of f(S) for these choices are 0,2,3,2,3,1, respectively, for the total of 11.\n\nSample Input 2\n\n6 3\n10 10 10 -10 -10 -10\n\nSample Output 2\n\n360\n\nThere are 20 ways to choose S. In 18 of them, f(S)=20, and in 2 of them, f(S)=0.\n\nSample Input 3\n\n3 1\n1 1 1\n\nSample Output 3\n\n0\n\nSample Input 4\n\n10 6\n1000000000 1000000000 1000000000 1000000000 1000000000 0 0 0 0 0\n\nSample Output 4\n\n999998537\n\nPrint the sum \\bmod (10^9+7).", "sample_input": "4 2\n1 1 3 4\n"}, "reference_outputs": ["11\n"], "source_document_id": "p02804", "source_text": "Score : 500 points\n\nProblem Statement\n\nFor a finite set of integers X, let f(X)=\\max X - \\min X.\n\nGiven are N integers A_1,...,A_N.\n\nWe will choose K of them and let S be the set of the integers chosen. If we distinguish elements with different indices even when their values are the same, there are {}_N C_K ways to make this choice. Find the sum of f(S) over all those ways.\n\nSince the answer can be enormous, print it \\bmod (10^9+7).\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq K \\leq N\n\n|A_i| \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nA_1 ... A_N\n\nOutput\n\nPrint the answer \\bmod (10^9+7).\n\nSample Input 1\n\n4 2\n1 1 3 4\n\nSample Output 1\n\n11\n\nThere are six ways to choose S: \\{1,1\\},\\{1,3\\},\\{1,4\\},\\{1,3\\},\\{1,4\\}, \\{3,4\\} (we distinguish the two 1s). The value of f(S) for these choices are 0,2,3,2,3,1, respectively, for the total of 11.\n\nSample Input 2\n\n6 3\n10 10 10 -10 -10 -10\n\nSample Output 2\n\n360\n\nThere are 20 ways to choose S. In 18 of them, f(S)=20, and in 2 of them, f(S)=0.\n\nSample Input 3\n\n3 1\n1 1 1\n\nSample Output 3\n\n0\n\nSample Input 4\n\n10 6\n1000000000 1000000000 1000000000 1000000000 1000000000 0 0 0 0 0\n\nSample Output 4\n\n999998537\n\nPrint the sum \\bmod (10^9+7).", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1216, "cpu_time_ms": 149, "memory_kb": 2560}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s779637861", "group_id": "codeNet:p02804", "input_text": "#include<iostream>\n#include<vector>\n#include<string>\n#include<algorithm>\n#include<utility>\n#include<cmath>\n#include<climits>\n#include<queue>\n#include<stack>\n#include<numeric>\n#include<set>\n#include<iomanip>\n#include<map>\n#include<type_traits>\n#include<tuple>\n#include<deque>\n#include<cassert>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll,int> p;\n#define rep(i,N) for(ll (i)=0;(i)<(N);(i)++)\nconst int mod = 1000000007;\nconst int INF = 1001001001;\n\nstruct mint {\n  ll x; // typedef long long ll;\n  mint(ll x=0):x((x%mod+mod)%mod){}\n  mint operator-() const { return mint(-x);}\n  mint& operator+=(const mint a) {\n    if ((x += a.x) >= mod) x -= mod;\n    return *this;\n  }\n  mint& operator-=(const mint a) {\n    if ((x += mod-a.x) >= mod) x -= mod;\n    return *this;\n  }\n  mint& operator*=(const mint a) { (x *= a.x) %= mod; return *this;}\n  mint operator+(const mint a) const { return mint(*this) += a;}\n  mint operator-(const mint a) const { return mint(*this) -= a;}\n  mint operator*(const mint a) const { return mint(*this) *= a;}\n  mint pow(ll t) const {\n    if (!t) return 1;\n    mint a = pow(t>>1);\n    a *= a;\n    if (t&1) a *= *this;\n    return a;\n  }\n\n  // for prime mod\n  mint inv() const { return pow(mod-2);}\n  mint& operator/=(const mint a) { return *this *= a.inv();}\n  mint operator/(const mint a) const { return mint(*this) /= a;}\n};\nistream& operator>>(istream& is, const mint& a) { return is >> a.x;}\nostream& operator<<(ostream& os, const mint& a) { return os << a.x;}\n\nstruct combination {\n  vector<mint> fact, ifact;\n  combination(int n):fact(n+1),ifact(n+1) {\n    assert(n < mod);\n    fact[0] = 1;\n    for (int i = 1; i <= n; ++i) fact[i] = fact[i-1]*i;\n    ifact[n] = fact[n].inv();\n    for (int i = n; i >= 1; --i) ifact[i-1] = ifact[i]*i;\n  }\n  mint operator()(int n, int k) {\n    if (k < 0 || k > n) return 0;\n    return fact[n]*ifact[k]*ifact[n-k];\n  }\n};\n\nint main() {\n  int n, k;\n  cin >> n >> k;\n  vector<int> a(n);\n  rep(i, n) cin >> a[i];\n  sort(a.begin(), a.end());\n  combination comb(n);\n  mint ans = 0;\n  rep(ii, 2) {\n    mint s = 0;\n    rep(i, n) {\n      s +=  comb(i, k - 1) * a[i];\n    }\n    reverse(a.begin(), a.end());\n    if(ii == 0) ans += s;\n    else ans -= s;\n  }\n  cout << ans << endl;\n}\n", "language": "C++", "metadata": {"date": 1586328828, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02804.html", "problem_id": "p02804", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02804/input.txt", "sample_output_relpath": "derived/input_output/data/p02804/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02804/C++/s779637861.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s779637861", "user_id": "u239409893"}, "prompt_components": {"gold_output": "11\n", "input_to_evaluate": "#include<iostream>\n#include<vector>\n#include<string>\n#include<algorithm>\n#include<utility>\n#include<cmath>\n#include<climits>\n#include<queue>\n#include<stack>\n#include<numeric>\n#include<set>\n#include<iomanip>\n#include<map>\n#include<type_traits>\n#include<tuple>\n#include<deque>\n#include<cassert>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll,int> p;\n#define rep(i,N) for(ll (i)=0;(i)<(N);(i)++)\nconst int mod = 1000000007;\nconst int INF = 1001001001;\n\nstruct mint {\n  ll x; // typedef long long ll;\n  mint(ll x=0):x((x%mod+mod)%mod){}\n  mint operator-() const { return mint(-x);}\n  mint& operator+=(const mint a) {\n    if ((x += a.x) >= mod) x -= mod;\n    return *this;\n  }\n  mint& operator-=(const mint a) {\n    if ((x += mod-a.x) >= mod) x -= mod;\n    return *this;\n  }\n  mint& operator*=(const mint a) { (x *= a.x) %= mod; return *this;}\n  mint operator+(const mint a) const { return mint(*this) += a;}\n  mint operator-(const mint a) const { return mint(*this) -= a;}\n  mint operator*(const mint a) const { return mint(*this) *= a;}\n  mint pow(ll t) const {\n    if (!t) return 1;\n    mint a = pow(t>>1);\n    a *= a;\n    if (t&1) a *= *this;\n    return a;\n  }\n\n  // for prime mod\n  mint inv() const { return pow(mod-2);}\n  mint& operator/=(const mint a) { return *this *= a.inv();}\n  mint operator/(const mint a) const { return mint(*this) /= a;}\n};\nistream& operator>>(istream& is, const mint& a) { return is >> a.x;}\nostream& operator<<(ostream& os, const mint& a) { return os << a.x;}\n\nstruct combination {\n  vector<mint> fact, ifact;\n  combination(int n):fact(n+1),ifact(n+1) {\n    assert(n < mod);\n    fact[0] = 1;\n    for (int i = 1; i <= n; ++i) fact[i] = fact[i-1]*i;\n    ifact[n] = fact[n].inv();\n    for (int i = n; i >= 1; --i) ifact[i-1] = ifact[i]*i;\n  }\n  mint operator()(int n, int k) {\n    if (k < 0 || k > n) return 0;\n    return fact[n]*ifact[k]*ifact[n-k];\n  }\n};\n\nint main() {\n  int n, k;\n  cin >> n >> k;\n  vector<int> a(n);\n  rep(i, n) cin >> a[i];\n  sort(a.begin(), a.end());\n  combination comb(n);\n  mint ans = 0;\n  rep(ii, 2) {\n    mint s = 0;\n    rep(i, n) {\n      s +=  comb(i, k - 1) * a[i];\n    }\n    reverse(a.begin(), a.end());\n    if(ii == 0) ans += s;\n    else ans -= s;\n  }\n  cout << ans << endl;\n}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nFor a finite set of integers X, let f(X)=\\max X - \\min X.\n\nGiven are N integers A_1,...,A_N.\n\nWe will choose K of them and let S be the set of the integers chosen. If we distinguish elements with different indices even when their values are the same, there are {}_N C_K ways to make this choice. Find the sum of f(S) over all those ways.\n\nSince the answer can be enormous, print it \\bmod (10^9+7).\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq K \\leq N\n\n|A_i| \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nA_1 ... A_N\n\nOutput\n\nPrint the answer \\bmod (10^9+7).\n\nSample Input 1\n\n4 2\n1 1 3 4\n\nSample Output 1\n\n11\n\nThere are six ways to choose S: \\{1,1\\},\\{1,3\\},\\{1,4\\},\\{1,3\\},\\{1,4\\}, \\{3,4\\} (we distinguish the two 1s). The value of f(S) for these choices are 0,2,3,2,3,1, respectively, for the total of 11.\n\nSample Input 2\n\n6 3\n10 10 10 -10 -10 -10\n\nSample Output 2\n\n360\n\nThere are 20 ways to choose S. In 18 of them, f(S)=20, and in 2 of them, f(S)=0.\n\nSample Input 3\n\n3 1\n1 1 1\n\nSample Output 3\n\n0\n\nSample Input 4\n\n10 6\n1000000000 1000000000 1000000000 1000000000 1000000000 0 0 0 0 0\n\nSample Output 4\n\n999998537\n\nPrint the sum \\bmod (10^9+7).", "sample_input": "4 2\n1 1 3 4\n"}, "reference_outputs": ["11\n"], "source_document_id": "p02804", "source_text": "Score : 500 points\n\nProblem Statement\n\nFor a finite set of integers X, let f(X)=\\max X - \\min X.\n\nGiven are N integers A_1,...,A_N.\n\nWe will choose K of them and let S be the set of the integers chosen. If we distinguish elements with different indices even when their values are the same, there are {}_N C_K ways to make this choice. Find the sum of f(S) over all those ways.\n\nSince the answer can be enormous, print it \\bmod (10^9+7).\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq K \\leq N\n\n|A_i| \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nA_1 ... A_N\n\nOutput\n\nPrint the answer \\bmod (10^9+7).\n\nSample Input 1\n\n4 2\n1 1 3 4\n\nSample Output 1\n\n11\n\nThere are six ways to choose S: \\{1,1\\},\\{1,3\\},\\{1,4\\},\\{1,3\\},\\{1,4\\}, \\{3,4\\} (we distinguish the two 1s). The value of f(S) for these choices are 0,2,3,2,3,1, respectively, for the total of 11.\n\nSample Input 2\n\n6 3\n10 10 10 -10 -10 -10\n\nSample Output 2\n\n360\n\nThere are 20 ways to choose S. In 18 of them, f(S)=20, and in 2 of them, f(S)=0.\n\nSample Input 3\n\n3 1\n1 1 1\n\nSample Output 3\n\n0\n\nSample Input 4\n\n10 6\n1000000000 1000000000 1000000000 1000000000 1000000000 0 0 0 0 0\n\nSample Output 4\n\n999998537\n\nPrint the sum \\bmod (10^9+7).", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2245, "cpu_time_ms": 51, "memory_kb": 2176}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s851021925", "group_id": "codeNet:p02805", "input_text": "#include <iostream>\n#include <string>\n#include <utility>\n#include <queue>\n#include <cstdio>\n#include <cmath>\n#include <algorithm>\n#define llint long long\n#define inf 1e18\n#define eps 1e-9\n#define mod 1000000007\n\nusing namespace std;\ntypedef pair<llint, llint> P;\n\nstruct vec2d{\n\tdouble x, y;\n\tvec2d(){}\n\tvec2d(double x, double y){\n\t\tthis->x = x, this->y = y;\n\t}\n\tdouble add(double a, double b){\n\t\tif(fabs(a+b) < eps * (fabs(a) + fabs(b))) return 0.0;\n\t\treturn a+b;\n\t}\n\tvec2d operator+(vec2d ope){\n\t\treturn vec2d(add(x, ope.x), add(y, ope.y));\n\t}\n\tvec2d operator-(vec2d ope){\n\t\treturn vec2d(add(x, -ope.x), add(y, -ope.y));\n\t}\n\tvec2d operator*(double t){\n\t\treturn vec2d(x*t, y*t);\n\t}\n\tvec2d operator/(double t){\n\t\treturn vec2d(x/t, y/t);\n\t}\n\tdouble dot(vec2d ope){\n\t\treturn add(x*ope.x, y*ope.y);\n\t}\n\tdouble cross(vec2d ope){\n\t\treturn add(x*ope.y, -y*ope.x);\n\t}\n\tdouble norm(){\n\t\tdouble d2 = dot(*this);\n\t\tif(d2 > 0) return sqrt(d2);\n\t\treturn 0.0;\n\t}\n};\n\ndouble distPP(vec2d p, vec2d q){\n\treturn (p-q).norm();\n}\n\ndouble distSP(vec2d p, vec2d q, vec2d x)\n{\n\tif((x-p).dot(q-p) <= 0) return distPP(p, x);\n\tif((x-q).dot(p-q) <= 0) return distPP(q, x);\n\treturn fabs( (x-p).cross(q-p) / distPP(p, q) );\n}\n\nbool isOnS(vec2d p, vec2d q, vec2d x)\n{\n\treturn (p-x).cross(q-x) == 0 && (p-x).dot(q-x) <= 0;\n}\n\nbool isCross(vec2d p, vec2d q, vec2d r, vec2d s)\n{\n\tif((q-p).cross(s-r) == 0){\n\t\treturn isOnS(p, q, r) || isOnS(p, q, s) || isOnS(r, s, p) || isOnS(r, s, q);\t\n\t}\n\tdouble t = (r-p).cross(s-r) / (q-p).cross(s-r);\n\tvec2d x = p + (q-p)*t;\n\treturn isOnS(p, q, x) && isOnS(r, s, x);\n}\n\nbool getCross(vec2d p, vec2d q, vec2d r, vec2d s, vec2d &ret)\n{\n\tif((q-p).cross(s-r) == 0){\n\t\treturn false;\n\t}\n\tdouble t = (r-p).cross(s-r) / (q-p).cross(s-r);\n\tret = p + (q-p)*t;\n\treturn true;\n}\n\nllint n;\nvec2d p[55];\n\nbool get(vec2d o, vec2d a, vec2d b, vec2d &ret)\n{\n\tvec2d A = (o + a) * 0.5, B = (o + b) * 0.5;\n\tvec2d nA = vec2d(A.y, -A.x), nB = vec2d(B.y, -B.x);\n\tnA = nA / nA.norm(), nB = nB / nB.norm();\n\t//cout << o.x << \" \" << o.y << \" \" << a.x << \" \"  << a.y << \" \" << b.x << \" \" << b.y << endl;\n\treturn getCross(A, A+nA, B, B+nB, ret);\n}\n\nbool check(double r)\n{\n\tfor(int i = 1; i <= n; i++){\n\t\tfor(int j = i+1; j <= n; j++){\n\t\t\tvec2d c = (p[i] + p[j]) * 0.5;\n\t\t\tbool flag = true;\n\t\t\tfor(int l = 1; l <= n; l++){\n\t\t\t\tif(distPP(c, p[l]) > r + eps){\n\t\t\t\t\tflag = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(flag) return true;\n\t\t}\n\t}\n\tfor(int i = 1; i <= n; i++){\n\t\tfor(int j = i+1; j <= n; j++){\n\t\t\tfor(int k = j+1; k <= n; k++){\n\t\t\t\tvec2d c;\n\t\t\t\tif(!get(p[i], p[j], p[k], c)) continue;\n\t\t\t\t//cout << c.x << \" \" << c.y << endl;\n\t\t\t\tbool flag = true;\n\t\t\t\tfor(int l = 1; l <= n; l++){\n\t\t\t\t\tif(distPP(c, p[l]) > r + eps){\n\t\t\t\t\t\tflag = false;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(flag) return true;\n\t\t\t}\n\t\t}\n\t}\n\treturn false;\n}\n\nint main(void)\n{\n\tios::sync_with_stdio(0);\n\tcin.tie(0);\n\t\n\tcin >> n;\n\tfor(int i = 1; i <= n; i++) cin >> p[i].x >> p[i].y;\n\t\n\tif(n == 2){\n\t\tprintf(\"%.11f\\n\", distPP(p[1], p[2])*0.5);\n\t\treturn 0;\n\t}\n\t\n\tdouble ans = inf;\n\t\n\tfor(int i = 1; i <= n; i++){\n\t\tfor(int j = i+1; j <= n; j++){\n\t\t\tvec2d c = (p[i] + p[j]) * 0.5;\n\t\t\tdouble r = distPP(c, p[i]);\n\t\t\tbool flag = true;\n\t\t\tfor(int l = 1; l <= n; l++){\n\t\t\t\tif(distPP(c, p[l]) > r + eps){\n\t\t\t\t\tflag = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(flag) ans = min(ans, r);\n\t\t}\n\t}\n\tfor(int i = 1; i <= n; i++){\n\t\tfor(int j = i+1; j <= n; j++){\n\t\t\tfor(int k = j+1; k <= n; k++){\n\t\t\t\tvec2d c;\n\t\t\t\tdouble r = distPP(c, p[i]);\n\t\t\t\tif(!get(p[i], p[j], p[k], c)) continue;\n\t\t\t\t//cout << c.x << \" \" << c.y << endl;\n\t\t\t\tbool flag = true;\n\t\t\t\tfor(int l = 1; l <= n; l++){\n\t\t\t\t\tif(distPP(c, p[l]) > r + eps){\n\t\t\t\t\t\tflag = false;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(flag) ans = min(ans, r);\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%.11f\\n\", ans);\n\t\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1578883962, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02805.html", "problem_id": "p02805", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02805/input.txt", "sample_output_relpath": "derived/input_output/data/p02805/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02805/C++/s851021925.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s851021925", "user_id": "u319282133"}, "prompt_components": {"gold_output": "0.500000000000000000\n", "input_to_evaluate": "#include <iostream>\n#include <string>\n#include <utility>\n#include <queue>\n#include <cstdio>\n#include <cmath>\n#include <algorithm>\n#define llint long long\n#define inf 1e18\n#define eps 1e-9\n#define mod 1000000007\n\nusing namespace std;\ntypedef pair<llint, llint> P;\n\nstruct vec2d{\n\tdouble x, y;\n\tvec2d(){}\n\tvec2d(double x, double y){\n\t\tthis->x = x, this->y = y;\n\t}\n\tdouble add(double a, double b){\n\t\tif(fabs(a+b) < eps * (fabs(a) + fabs(b))) return 0.0;\n\t\treturn a+b;\n\t}\n\tvec2d operator+(vec2d ope){\n\t\treturn vec2d(add(x, ope.x), add(y, ope.y));\n\t}\n\tvec2d operator-(vec2d ope){\n\t\treturn vec2d(add(x, -ope.x), add(y, -ope.y));\n\t}\n\tvec2d operator*(double t){\n\t\treturn vec2d(x*t, y*t);\n\t}\n\tvec2d operator/(double t){\n\t\treturn vec2d(x/t, y/t);\n\t}\n\tdouble dot(vec2d ope){\n\t\treturn add(x*ope.x, y*ope.y);\n\t}\n\tdouble cross(vec2d ope){\n\t\treturn add(x*ope.y, -y*ope.x);\n\t}\n\tdouble norm(){\n\t\tdouble d2 = dot(*this);\n\t\tif(d2 > 0) return sqrt(d2);\n\t\treturn 0.0;\n\t}\n};\n\ndouble distPP(vec2d p, vec2d q){\n\treturn (p-q).norm();\n}\n\ndouble distSP(vec2d p, vec2d q, vec2d x)\n{\n\tif((x-p).dot(q-p) <= 0) return distPP(p, x);\n\tif((x-q).dot(p-q) <= 0) return distPP(q, x);\n\treturn fabs( (x-p).cross(q-p) / distPP(p, q) );\n}\n\nbool isOnS(vec2d p, vec2d q, vec2d x)\n{\n\treturn (p-x).cross(q-x) == 0 && (p-x).dot(q-x) <= 0;\n}\n\nbool isCross(vec2d p, vec2d q, vec2d r, vec2d s)\n{\n\tif((q-p).cross(s-r) == 0){\n\t\treturn isOnS(p, q, r) || isOnS(p, q, s) || isOnS(r, s, p) || isOnS(r, s, q);\t\n\t}\n\tdouble t = (r-p).cross(s-r) / (q-p).cross(s-r);\n\tvec2d x = p + (q-p)*t;\n\treturn isOnS(p, q, x) && isOnS(r, s, x);\n}\n\nbool getCross(vec2d p, vec2d q, vec2d r, vec2d s, vec2d &ret)\n{\n\tif((q-p).cross(s-r) == 0){\n\t\treturn false;\n\t}\n\tdouble t = (r-p).cross(s-r) / (q-p).cross(s-r);\n\tret = p + (q-p)*t;\n\treturn true;\n}\n\nllint n;\nvec2d p[55];\n\nbool get(vec2d o, vec2d a, vec2d b, vec2d &ret)\n{\n\tvec2d A = (o + a) * 0.5, B = (o + b) * 0.5;\n\tvec2d nA = vec2d(A.y, -A.x), nB = vec2d(B.y, -B.x);\n\tnA = nA / nA.norm(), nB = nB / nB.norm();\n\t//cout << o.x << \" \" << o.y << \" \" << a.x << \" \"  << a.y << \" \" << b.x << \" \" << b.y << endl;\n\treturn getCross(A, A+nA, B, B+nB, ret);\n}\n\nbool check(double r)\n{\n\tfor(int i = 1; i <= n; i++){\n\t\tfor(int j = i+1; j <= n; j++){\n\t\t\tvec2d c = (p[i] + p[j]) * 0.5;\n\t\t\tbool flag = true;\n\t\t\tfor(int l = 1; l <= n; l++){\n\t\t\t\tif(distPP(c, p[l]) > r + eps){\n\t\t\t\t\tflag = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(flag) return true;\n\t\t}\n\t}\n\tfor(int i = 1; i <= n; i++){\n\t\tfor(int j = i+1; j <= n; j++){\n\t\t\tfor(int k = j+1; k <= n; k++){\n\t\t\t\tvec2d c;\n\t\t\t\tif(!get(p[i], p[j], p[k], c)) continue;\n\t\t\t\t//cout << c.x << \" \" << c.y << endl;\n\t\t\t\tbool flag = true;\n\t\t\t\tfor(int l = 1; l <= n; l++){\n\t\t\t\t\tif(distPP(c, p[l]) > r + eps){\n\t\t\t\t\t\tflag = false;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(flag) return true;\n\t\t\t}\n\t\t}\n\t}\n\treturn false;\n}\n\nint main(void)\n{\n\tios::sync_with_stdio(0);\n\tcin.tie(0);\n\t\n\tcin >> n;\n\tfor(int i = 1; i <= n; i++) cin >> p[i].x >> p[i].y;\n\t\n\tif(n == 2){\n\t\tprintf(\"%.11f\\n\", distPP(p[1], p[2])*0.5);\n\t\treturn 0;\n\t}\n\t\n\tdouble ans = inf;\n\t\n\tfor(int i = 1; i <= n; i++){\n\t\tfor(int j = i+1; j <= n; j++){\n\t\t\tvec2d c = (p[i] + p[j]) * 0.5;\n\t\t\tdouble r = distPP(c, p[i]);\n\t\t\tbool flag = true;\n\t\t\tfor(int l = 1; l <= n; l++){\n\t\t\t\tif(distPP(c, p[l]) > r + eps){\n\t\t\t\t\tflag = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(flag) ans = min(ans, r);\n\t\t}\n\t}\n\tfor(int i = 1; i <= n; i++){\n\t\tfor(int j = i+1; j <= n; j++){\n\t\t\tfor(int k = j+1; k <= n; k++){\n\t\t\t\tvec2d c;\n\t\t\t\tdouble r = distPP(c, p[i]);\n\t\t\t\tif(!get(p[i], p[j], p[k], c)) continue;\n\t\t\t\t//cout << c.x << \" \" << c.y << endl;\n\t\t\t\tbool flag = true;\n\t\t\t\tfor(int l = 1; l <= n; l++){\n\t\t\t\t\tif(distPP(c, p[l]) > r + eps){\n\t\t\t\t\t\tflag = false;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tif(flag) ans = min(ans, r);\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%.11f\\n\", ans);\n\t\n\treturn 0;\n}", "problem_context": "Score : 600 points\n\nProblem Statement\n\nGiven are N points (x_i, y_i) in a two-dimensional plane.\n\nFind the minimum radius of a circle such that all the points are inside or on it.\n\nConstraints\n\n2 \\leq N \\leq 50\n\n0 \\leq x_i \\leq 1000\n\n0 \\leq y_i \\leq 1000\n\nThe given N points are all different.\n\nThe values in input are all integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nx_1 y_1\n:\nx_N y_N\n\nOutput\n\nPrint the minimum radius of a circle such that all the N points are inside or on it.\n\nYour output will be considered correct if the absolute or relative error from our answer is at most 10^{-6}.\n\nSample Input 1\n\n2\n0 0\n1 0\n\nSample Output 1\n\n0.500000000000000000\n\nBoth points are contained in the circle centered at (0.5,0) with a radius of 0.5.\n\nSample Input 2\n\n3\n0 0\n0 1\n1 0\n\nSample Output 2\n\n0.707106781186497524\n\nSample Input 3\n\n10\n10 9\n5 9\n2 0\n0 0\n2 7\n3 3\n2 5\n10 0\n3 7\n1 9\n\nSample Output 3\n\n6.726812023536805158\n\nIf the absolute or relative error from our answer is at most 10^{-6}, the output will be considered correct.", "sample_input": "2\n0 0\n1 0\n"}, "reference_outputs": ["0.500000000000000000\n"], "source_document_id": "p02805", "source_text": "Score : 600 points\n\nProblem Statement\n\nGiven are N points (x_i, y_i) in a two-dimensional plane.\n\nFind the minimum radius of a circle such that all the points are inside or on it.\n\nConstraints\n\n2 \\leq N \\leq 50\n\n0 \\leq x_i \\leq 1000\n\n0 \\leq y_i \\leq 1000\n\nThe given N points are all different.\n\nThe values in input are all integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nx_1 y_1\n:\nx_N y_N\n\nOutput\n\nPrint the minimum radius of a circle such that all the N points are inside or on it.\n\nYour output will be considered correct if the absolute or relative error from our answer is at most 10^{-6}.\n\nSample Input 1\n\n2\n0 0\n1 0\n\nSample Output 1\n\n0.500000000000000000\n\nBoth points are contained in the circle centered at (0.5,0) with a radius of 0.5.\n\nSample Input 2\n\n3\n0 0\n0 1\n1 0\n\nSample Output 2\n\n0.707106781186497524\n\nSample Input 3\n\n10\n10 9\n5 9\n2 0\n0 0\n2 7\n3 3\n2 5\n10 0\n3 7\n1 9\n\nSample Output 3\n\n6.726812023536805158\n\nIf the absolute or relative error from our answer is at most 10^{-6}, the output will be considered correct.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 3760, "cpu_time_ms": 7, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s619908578", "group_id": "codeNet:p02806", "input_text": "#include<bits/stdc++.h>\n#define F first\n#define S second\nusing ll = long long;\nconst ll mod = 1000000007;\nconst ll infi = 1000000000000000;\nconst ll md = 998244353;\nusing namespace std;\nusing vl = vector<ll>;\nusing pll =  pair<ll,ll>;\n\nvoid  solve(){\n    int n,sum;\n    cin>>n;\n    vector<pair<string ,int>> a(n);\n    string s;\n    for(int i=0;i<n;i++){\n        cin>>a[i].F>>a[i].S;\n    }\n    cin>>s;\n    int f=1,i;\n    sum =0;\n    for(i=0;i<n;i++) if(a[i].F==s) break;\n  i++;\n    for(;i<n;i++){\n        sum += a[i].S;\n    }\n    cout<<sum;\n}\n        \nint main() {\n    ios_base::sync_with_stdio(false);\n    cin.tie(NULL);\n   // int n; cin>>n; for(int i=0;i<n;i++)\n        solve();\n    return 0;\n}", "language": "C++", "metadata": {"date": 1578793697, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02806.html", "problem_id": "p02806", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02806/input.txt", "sample_output_relpath": "derived/input_output/data/p02806/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02806/C++/s619908578.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s619908578", "user_id": "u121748552"}, "prompt_components": {"gold_output": "30\n", "input_to_evaluate": "#include<bits/stdc++.h>\n#define F first\n#define S second\nusing ll = long long;\nconst ll mod = 1000000007;\nconst ll infi = 1000000000000000;\nconst ll md = 998244353;\nusing namespace std;\nusing vl = vector<ll>;\nusing pll =  pair<ll,ll>;\n\nvoid  solve(){\n    int n,sum;\n    cin>>n;\n    vector<pair<string ,int>> a(n);\n    string s;\n    for(int i=0;i<n;i++){\n        cin>>a[i].F>>a[i].S;\n    }\n    cin>>s;\n    int f=1,i;\n    sum =0;\n    for(i=0;i<n;i++) if(a[i].F==s) break;\n  i++;\n    for(;i<n;i++){\n        sum += a[i].S;\n    }\n    cout<<sum;\n}\n        \nint main() {\n    ios_base::sync_with_stdio(false);\n    cin.tie(NULL);\n   // int n; cin>>n; for(int i=0;i<n;i++)\n        solve();\n    return 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nNiwango created a playlist of N songs.\nThe title and the duration of the i-th song are s_i and t_i seconds, respectively.\nIt is guaranteed that s_1,\\ldots,s_N are all distinct.\n\nNiwango was doing some work while playing this playlist. (That is, all the songs were played once, in the order they appear in the playlist, without any pause in between.)\nHowever, he fell asleep during his work, and he woke up after all the songs were played.\nAccording to his record, it turned out that he fell asleep at the very end of the song titled X.\n\nFind the duration of time when some song was played while Niwango was asleep.\n\nConstraints\n\n1 \\leq N \\leq 50\n\ns_i and X are strings of length between 1 and 100 (inclusive) consisting of lowercase English letters.\n\ns_1,\\ldots,s_N are distinct.\n\nThere exists an integer i such that s_i = X.\n\n1 \\leq t_i \\leq 1000\n\nt_i is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\ns_1 t_1\n\\vdots\ns_{N} t_N\nX\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n3\ndwango 2\nsixth 5\nprelims 25\ndwango\n\nSample Output 1\n\n30\n\nWhile Niwango was asleep, two songs were played: sixth and prelims.\n\nThe answer is the total duration of these songs, 30.\n\nSample Input 2\n\n1\nabcde 1000\nabcde\n\nSample Output 2\n\n0\n\nNo songs were played while Niwango was asleep.\n\nIn such a case, the total duration of songs is 0.\n\nSample Input 3\n\n15\nypnxn 279\nkgjgwx 464\nqquhuwq 327\nrxing 549\npmuduhznoaqu 832\ndagktgdarveusju 595\nwunfagppcoi 200\ndhavrncwfw 720\njpcmigg 658\nwrczqxycivdqn 639\nmcmkkbnjfeod 992\nhtqvkgkbhtytsz 130\ntwflegsjz 467\ndswxxrxuzzfhkp 989\nszfwtzfpnscgue 958\npmuduhznoaqu\n\nSample Output 3\n\n6348", "sample_input": "3\ndwango 2\nsixth 5\nprelims 25\ndwango\n"}, "reference_outputs": ["30\n"], "source_document_id": "p02806", "source_text": "Score : 200 points\n\nProblem Statement\n\nNiwango created a playlist of N songs.\nThe title and the duration of the i-th song are s_i and t_i seconds, respectively.\nIt is guaranteed that s_1,\\ldots,s_N are all distinct.\n\nNiwango was doing some work while playing this playlist. (That is, all the songs were played once, in the order they appear in the playlist, without any pause in between.)\nHowever, he fell asleep during his work, and he woke up after all the songs were played.\nAccording to his record, it turned out that he fell asleep at the very end of the song titled X.\n\nFind the duration of time when some song was played while Niwango was asleep.\n\nConstraints\n\n1 \\leq N \\leq 50\n\ns_i and X are strings of length between 1 and 100 (inclusive) consisting of lowercase English letters.\n\ns_1,\\ldots,s_N are distinct.\n\nThere exists an integer i such that s_i = X.\n\n1 \\leq t_i \\leq 1000\n\nt_i is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\ns_1 t_1\n\\vdots\ns_{N} t_N\nX\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n3\ndwango 2\nsixth 5\nprelims 25\ndwango\n\nSample Output 1\n\n30\n\nWhile Niwango was asleep, two songs were played: sixth and prelims.\n\nThe answer is the total duration of these songs, 30.\n\nSample Input 2\n\n1\nabcde 1000\nabcde\n\nSample Output 2\n\n0\n\nNo songs were played while Niwango was asleep.\n\nIn such a case, the total duration of songs is 0.\n\nSample Input 3\n\n15\nypnxn 279\nkgjgwx 464\nqquhuwq 327\nrxing 549\npmuduhznoaqu 832\ndagktgdarveusju 595\nwunfagppcoi 200\ndhavrncwfw 720\njpcmigg 658\nwrczqxycivdqn 639\nmcmkkbnjfeod 992\nhtqvkgkbhtytsz 130\ntwflegsjz 467\ndswxxrxuzzfhkp 989\nszfwtzfpnscgue 958\npmuduhznoaqu\n\nSample Output 3\n\n6348", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 695, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s666126444", "group_id": "codeNet:p02811", "input_text": "#include <iostream>\nusing namespace std;\nint main()\n{\n    int p,n;\n    cin>>p>>n;\n    int mul = p*500;\n    if(mul>=n)\n    {\n        cout<<\"Yes\";\n    }\n    else cout<<\"No\";\n\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1590601225, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02811.html", "problem_id": "p02811", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02811/input.txt", "sample_output_relpath": "derived/input_output/data/p02811/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02811/C++/s666126444.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s666126444", "user_id": "u020840327"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <iostream>\nusing namespace std;\nint main()\n{\n    int p,n;\n    cin>>p>>n;\n    int mul = p*500;\n    if(mul>=n)\n    {\n        cout<<\"Yes\";\n    }\n    else cout<<\"No\";\n\n    return 0;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nTakahashi has K 500-yen coins. (Yen is the currency of Japan.)\nIf these coins add up to X yen or more, print Yes; otherwise, print No.\n\nConstraints\n\n1 \\leq K \\leq 100\n\n1 \\leq X \\leq 10^5\n\nInput\n\nInput is given from Standard Input in the following format:\n\nK X\n\nOutput\n\nIf the coins add up to X yen or more, print Yes; otherwise, print No.\n\nSample Input 1\n\n2 900\n\nSample Output 1\n\nYes\n\nTwo 500-yen coins add up to 1000 yen, which is not less than X = 900 yen.\n\nSample Input 2\n\n1 501\n\nSample Output 2\n\nNo\n\nOne 500-yen coin is worth 500 yen, which is less than X = 501 yen.\n\nSample Input 3\n\n4 2000\n\nSample Output 3\n\nYes\n\nFour 500-yen coins add up to 2000 yen, which is not less than X = 2000 yen.", "sample_input": "2 900\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p02811", "source_text": "Score : 100 points\n\nProblem Statement\n\nTakahashi has K 500-yen coins. (Yen is the currency of Japan.)\nIf these coins add up to X yen or more, print Yes; otherwise, print No.\n\nConstraints\n\n1 \\leq K \\leq 100\n\n1 \\leq X \\leq 10^5\n\nInput\n\nInput is given from Standard Input in the following format:\n\nK X\n\nOutput\n\nIf the coins add up to X yen or more, print Yes; otherwise, print No.\n\nSample Input 1\n\n2 900\n\nSample Output 1\n\nYes\n\nTwo 500-yen coins add up to 1000 yen, which is not less than X = 900 yen.\n\nSample Input 2\n\n1 501\n\nSample Output 2\n\nNo\n\nOne 500-yen coin is worth 500 yen, which is less than X = 501 yen.\n\nSample Input 3\n\n4 2000\n\nSample Output 3\n\nYes\n\nFour 500-yen coins add up to 2000 yen, which is not less than X = 2000 yen.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 189, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s749510123", "group_id": "codeNet:p02812", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n \nint main() {\n  int N;\n  int x=0;\n  string S;\n  cin >> N >> S;\n  for(int i=0;i<N-2; i++){\n    if(S.at(i)=='A'&&S.at(i+1)=='B'&&S.at(i+2)=='C'){\n      x++;\n    }\n  }\n  cout << x << endl;\n}", "language": "C++", "metadata": {"date": 1578710518, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02812.html", "problem_id": "p02812", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02812/input.txt", "sample_output_relpath": "derived/input_output/data/p02812/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02812/C++/s749510123.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s749510123", "user_id": "u217508499"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n \nint main() {\n  int N;\n  int x=0;\n  string S;\n  cin >> N >> S;\n  for(int i=0;i<N-2; i++){\n    if(S.at(i)=='A'&&S.at(i+1)=='B'&&S.at(i+2)=='C'){\n      x++;\n    }\n  }\n  cout << x << endl;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nWe have a string S of length N consisting of uppercase English letters.\n\nHow many times does ABC occur in S as contiguous subsequences (see Sample Inputs and Outputs)?\n\nConstraints\n\n3 \\leq N \\leq 50\n\nS consists of uppercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS\n\nOutput\n\nPrint number of occurrences of ABC in S as contiguous subsequences.\n\nSample Input 1\n\n10\nZABCDBABCQ\n\nSample Output 1\n\n2\n\nTwo contiguous subsequences of S are equal to ABC: the 2-nd through 4-th characters, and the 7-th through 9-th characters.\n\nSample Input 2\n\n19\nTHREEONEFOURONEFIVE\n\nSample Output 2\n\n0\n\nNo contiguous subsequences of S are equal to ABC.\n\nSample Input 3\n\n33\nABCCABCBABCCABACBCBBABCBCBCBCABCB\n\nSample Output 3\n\n5", "sample_input": "10\nZABCDBABCQ\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02812", "source_text": "Score : 200 points\n\nProblem Statement\n\nWe have a string S of length N consisting of uppercase English letters.\n\nHow many times does ABC occur in S as contiguous subsequences (see Sample Inputs and Outputs)?\n\nConstraints\n\n3 \\leq N \\leq 50\n\nS consists of uppercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS\n\nOutput\n\nPrint number of occurrences of ABC in S as contiguous subsequences.\n\nSample Input 1\n\n10\nZABCDBABCQ\n\nSample Output 1\n\n2\n\nTwo contiguous subsequences of S are equal to ABC: the 2-nd through 4-th characters, and the 7-th through 9-th characters.\n\nSample Input 2\n\n19\nTHREEONEFOURONEFIVE\n\nSample Output 2\n\n0\n\nNo contiguous subsequences of S are equal to ABC.\n\nSample Input 3\n\n33\nABCCABCBABCCABACBCBBABCBCBCBCABCB\n\nSample Output 3\n\n5", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 234, "cpu_time_ms": 2, "memory_kb": 384}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s730913139", "group_id": "codeNet:p02813", "input_text": "/*                        ______\n _______   /\\     |``\\   |        |  /\n    |     /  \\    |__/   |____    |/\n    |    / _ _\\   |  \\   |        |\\\n    |   /      \\  |   \\  |______  |  \\\n\n            Dept. of CSE\n        Comilla  University\n\n*/\n#include<bits/stdc++.h>\n#define pi 2*acos(0.0)\n#define ll long long\n#define FIO ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);\n#define Node struct node\n#define spc \" \"\n#define  E  2.71828182845904523536\n#define pb push_back\n#define pp pop_back\n#define valid(nx,ny) nx>=0 && nx<n && ny>=0 && ny<m\n#define ee endl\n#define pii pair<int,int>\n#define infinity 10000000000000000\n#define mod 1000000007\nint fx[]={0,0,+1,-1};\nint fy[]={+1,-1,0,0};\n\nusing namespace std;\n///check n=1;\n///check corner case;\nconst int maX=1e5+1;\nvector<ll>Graph[maX],cost[maX];\nll visit[maX];\n\n\nint main()\n{\n   ll n,i,j,cc=0,k;\n   cin>>n;\n   ll p[n],q[n];for(i=0;i<n;i++)cin>>p[i];\n   for(i=0;i<n;i++)cin>>q[i];\n   vector<ll>a;\n   for(i=0;i<n;i++)a.pb(i+1);\n   ll pp=0,qq=0,x=0,y=0;\n   while(1){\n     ll cc=0;\n      for(i=0;i<n;i++){\n        if(p[i]!=a[i]){cc=1;break;}\n      }\n      if(cc==1 && x==0)pp++;\n      else x=1;\n      ll dd=0;\n      for(i=0;i<n;i++){\n        if(q[i]!=a[i]){dd=1;break;}\n      }\n      if(dd==1 && y==0)qq++;\n      else y=1;\n      if(x && y)break;\n      next_permutation(a.begin(),a.end());\n   }\n   cout<<abs(pp-qq)<<endl;\nreturn 0;\n}\n", "language": "C++", "metadata": {"date": 1589586463, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02813.html", "problem_id": "p02813", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02813/input.txt", "sample_output_relpath": "derived/input_output/data/p02813/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02813/C++/s730913139.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s730913139", "user_id": "u164081575"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "/*                        ______\n _______   /\\     |``\\   |        |  /\n    |     /  \\    |__/   |____    |/\n    |    / _ _\\   |  \\   |        |\\\n    |   /      \\  |   \\  |______  |  \\\n\n            Dept. of CSE\n        Comilla  University\n\n*/\n#include<bits/stdc++.h>\n#define pi 2*acos(0.0)\n#define ll long long\n#define FIO ios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);\n#define Node struct node\n#define spc \" \"\n#define  E  2.71828182845904523536\n#define pb push_back\n#define pp pop_back\n#define valid(nx,ny) nx>=0 && nx<n && ny>=0 && ny<m\n#define ee endl\n#define pii pair<int,int>\n#define infinity 10000000000000000\n#define mod 1000000007\nint fx[]={0,0,+1,-1};\nint fy[]={+1,-1,0,0};\n\nusing namespace std;\n///check n=1;\n///check corner case;\nconst int maX=1e5+1;\nvector<ll>Graph[maX],cost[maX];\nll visit[maX];\n\n\nint main()\n{\n   ll n,i,j,cc=0,k;\n   cin>>n;\n   ll p[n],q[n];for(i=0;i<n;i++)cin>>p[i];\n   for(i=0;i<n;i++)cin>>q[i];\n   vector<ll>a;\n   for(i=0;i<n;i++)a.pb(i+1);\n   ll pp=0,qq=0,x=0,y=0;\n   while(1){\n     ll cc=0;\n      for(i=0;i<n;i++){\n        if(p[i]!=a[i]){cc=1;break;}\n      }\n      if(cc==1 && x==0)pp++;\n      else x=1;\n      ll dd=0;\n      for(i=0;i<n;i++){\n        if(q[i]!=a[i]){dd=1;break;}\n      }\n      if(dd==1 && y==0)qq++;\n      else y=1;\n      if(x && y)break;\n      next_permutation(a.begin(),a.end());\n   }\n   cout<<abs(pp-qq)<<endl;\nreturn 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nWe have two permutations P and Q of size N (that is, P and Q are both rearrangements of (1,~2,~...,~N)).\n\nThere are N! possible permutations of size N. Among them, let P and Q be the a-th and b-th lexicographically smallest permutations, respectively. Find |a - b|.\n\nNotes\n\nFor two sequences X and Y, X is said to be lexicographically smaller than Y if and only if there exists an integer k such that X_i = Y_i~(1 \\leq i < k) and X_k < Y_k.\n\nConstraints\n\n2 \\leq N \\leq 8\n\nP and Q are permutations of size N.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nP_1 P_2 ... P_N\nQ_1 Q_2 ... Q_N\n\nOutput\n\nPrint |a - b|.\n\nSample Input 1\n\n3\n1 3 2\n3 1 2\n\nSample Output 1\n\n3\n\nThere are 6 permutations of size 3: (1,~2,~3), (1,~3,~2), (2,~1,~3), (2,~3,~1), (3,~1,~2), and (3,~2,~1). Among them, (1,~3,~2) and (3,~1,~2) come 2-nd and 5-th in lexicographical order, so the answer is |2 - 5| = 3.\n\nSample Input 2\n\n8\n7 3 5 4 2 1 6 8\n3 8 2 5 4 6 7 1\n\nSample Output 2\n\n17517\n\nSample Input 3\n\n3\n1 2 3\n1 2 3\n\nSample Output 3\n\n0", "sample_input": "3\n1 3 2\n3 1 2\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02813", "source_text": "Score : 300 points\n\nProblem Statement\n\nWe have two permutations P and Q of size N (that is, P and Q are both rearrangements of (1,~2,~...,~N)).\n\nThere are N! possible permutations of size N. Among them, let P and Q be the a-th and b-th lexicographically smallest permutations, respectively. Find |a - b|.\n\nNotes\n\nFor two sequences X and Y, X is said to be lexicographically smaller than Y if and only if there exists an integer k such that X_i = Y_i~(1 \\leq i < k) and X_k < Y_k.\n\nConstraints\n\n2 \\leq N \\leq 8\n\nP and Q are permutations of size N.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nP_1 P_2 ... P_N\nQ_1 Q_2 ... Q_N\n\nOutput\n\nPrint |a - b|.\n\nSample Input 1\n\n3\n1 3 2\n3 1 2\n\nSample Output 1\n\n3\n\nThere are 6 permutations of size 3: (1,~2,~3), (1,~3,~2), (2,~1,~3), (2,~3,~1), (3,~1,~2), and (3,~2,~1). Among them, (1,~3,~2) and (3,~1,~2) come 2-nd and 5-th in lexicographical order, so the answer is |2 - 5| = 3.\n\nSample Input 2\n\n8\n7 3 5 4 2 1 6 8\n3 8 2 5 4 6 7 1\n\nSample Output 2\n\n17517\n\nSample Input 3\n\n3\n1 2 3\n1 2 3\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1383, "cpu_time_ms": 3, "memory_kb": 4992}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s112455959", "group_id": "codeNet:p02813", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n    int n,i,j,k;cin>>n;\n    int p[n],q[n];\n    for(i=0;i<n;i++) cin>>p[i];\n    for(i=0;i<n;i++) cin>>q[i];\n    int arr[n]; for(i=0;i<n;i++) arr[i]=i+1;\n    k=1;int a,b;\n    do\n    {\n        int f=1;\n        for(i=0;i<n;i++)\n        {\n            if(arr[i]!=p[i])\n            {\n                f=0;break;\n            }\n        }\n        if(f==1) a=k;\n\n        f=1;\n        for(i=0;i<n;i++)\n        {\n            if(arr[i]!=q[i])\n               {\n                   f=0;break;\n               }\n        }\n        if(f==1) b=k;\n        k++;\n    }while(next_permutation(arr,arr+n));\n\n    cout<<abs(a-b);\n\n\n\n\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1585782052, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02813.html", "problem_id": "p02813", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02813/input.txt", "sample_output_relpath": "derived/input_output/data/p02813/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02813/C++/s112455959.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s112455959", "user_id": "u093792099"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n    int n,i,j,k;cin>>n;\n    int p[n],q[n];\n    for(i=0;i<n;i++) cin>>p[i];\n    for(i=0;i<n;i++) cin>>q[i];\n    int arr[n]; for(i=0;i<n;i++) arr[i]=i+1;\n    k=1;int a,b;\n    do\n    {\n        int f=1;\n        for(i=0;i<n;i++)\n        {\n            if(arr[i]!=p[i])\n            {\n                f=0;break;\n            }\n        }\n        if(f==1) a=k;\n\n        f=1;\n        for(i=0;i<n;i++)\n        {\n            if(arr[i]!=q[i])\n               {\n                   f=0;break;\n               }\n        }\n        if(f==1) b=k;\n        k++;\n    }while(next_permutation(arr,arr+n));\n\n    cout<<abs(a-b);\n\n\n\n\n    return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nWe have two permutations P and Q of size N (that is, P and Q are both rearrangements of (1,~2,~...,~N)).\n\nThere are N! possible permutations of size N. Among them, let P and Q be the a-th and b-th lexicographically smallest permutations, respectively. Find |a - b|.\n\nNotes\n\nFor two sequences X and Y, X is said to be lexicographically smaller than Y if and only if there exists an integer k such that X_i = Y_i~(1 \\leq i < k) and X_k < Y_k.\n\nConstraints\n\n2 \\leq N \\leq 8\n\nP and Q are permutations of size N.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nP_1 P_2 ... P_N\nQ_1 Q_2 ... Q_N\n\nOutput\n\nPrint |a - b|.\n\nSample Input 1\n\n3\n1 3 2\n3 1 2\n\nSample Output 1\n\n3\n\nThere are 6 permutations of size 3: (1,~2,~3), (1,~3,~2), (2,~1,~3), (2,~3,~1), (3,~1,~2), and (3,~2,~1). Among them, (1,~3,~2) and (3,~1,~2) come 2-nd and 5-th in lexicographical order, so the answer is |2 - 5| = 3.\n\nSample Input 2\n\n8\n7 3 5 4 2 1 6 8\n3 8 2 5 4 6 7 1\n\nSample Output 2\n\n17517\n\nSample Input 3\n\n3\n1 2 3\n1 2 3\n\nSample Output 3\n\n0", "sample_input": "3\n1 3 2\n3 1 2\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02813", "source_text": "Score : 300 points\n\nProblem Statement\n\nWe have two permutations P and Q of size N (that is, P and Q are both rearrangements of (1,~2,~...,~N)).\n\nThere are N! possible permutations of size N. Among them, let P and Q be the a-th and b-th lexicographically smallest permutations, respectively. Find |a - b|.\n\nNotes\n\nFor two sequences X and Y, X is said to be lexicographically smaller than Y if and only if there exists an integer k such that X_i = Y_i~(1 \\leq i < k) and X_k < Y_k.\n\nConstraints\n\n2 \\leq N \\leq 8\n\nP and Q are permutations of size N.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nP_1 P_2 ... P_N\nQ_1 Q_2 ... Q_N\n\nOutput\n\nPrint |a - b|.\n\nSample Input 1\n\n3\n1 3 2\n3 1 2\n\nSample Output 1\n\n3\n\nThere are 6 permutations of size 3: (1,~2,~3), (1,~3,~2), (2,~1,~3), (2,~3,~1), (3,~1,~2), and (3,~2,~1). Among them, (1,~3,~2) and (3,~1,~2) come 2-nd and 5-th in lexicographical order, so the answer is |2 - 5| = 3.\n\nSample Input 2\n\n8\n7 3 5 4 2 1 6 8\n3 8 2 5 4 6 7 1\n\nSample Output 2\n\n17517\n\nSample Input 3\n\n3\n1 2 3\n1 2 3\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 679, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s009174475", "group_id": "codeNet:p02813", "input_text": "#define _GLIBCXX_DEBUG\n#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define rep(i,N) for(int i = 0;i < (int)(N);i++)\nint main(){\nint n;\n  cin>>n;\n  vector<int>p(n),q(n);\n  rep(i,n) cin>>p[i]>>q[i];\n  vector<int>a(n);\n  rep(i,n) a[i]=i+1;\n  \n  map<vector<int>,int> mp;\n  do{\n    mp[a]=mp.size();\n  }while(next_permutation(a.begin(),a.end()));\n  int ans=abs(mp[p]-mp[q]);\n              cout<<ans<<endl;\n               }\n  \n", "language": "C++", "metadata": {"date": 1584868907, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02813.html", "problem_id": "p02813", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02813/input.txt", "sample_output_relpath": "derived/input_output/data/p02813/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02813/C++/s009174475.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s009174475", "user_id": "u485925545"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#define _GLIBCXX_DEBUG\n#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define rep(i,N) for(int i = 0;i < (int)(N);i++)\nint main(){\nint n;\n  cin>>n;\n  vector<int>p(n),q(n);\n  rep(i,n) cin>>p[i]>>q[i];\n  vector<int>a(n);\n  rep(i,n) a[i]=i+1;\n  \n  map<vector<int>,int> mp;\n  do{\n    mp[a]=mp.size();\n  }while(next_permutation(a.begin(),a.end()));\n  int ans=abs(mp[p]-mp[q]);\n              cout<<ans<<endl;\n               }\n  \n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nWe have two permutations P and Q of size N (that is, P and Q are both rearrangements of (1,~2,~...,~N)).\n\nThere are N! possible permutations of size N. Among them, let P and Q be the a-th and b-th lexicographically smallest permutations, respectively. Find |a - b|.\n\nNotes\n\nFor two sequences X and Y, X is said to be lexicographically smaller than Y if and only if there exists an integer k such that X_i = Y_i~(1 \\leq i < k) and X_k < Y_k.\n\nConstraints\n\n2 \\leq N \\leq 8\n\nP and Q are permutations of size N.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nP_1 P_2 ... P_N\nQ_1 Q_2 ... Q_N\n\nOutput\n\nPrint |a - b|.\n\nSample Input 1\n\n3\n1 3 2\n3 1 2\n\nSample Output 1\n\n3\n\nThere are 6 permutations of size 3: (1,~2,~3), (1,~3,~2), (2,~1,~3), (2,~3,~1), (3,~1,~2), and (3,~2,~1). Among them, (1,~3,~2) and (3,~1,~2) come 2-nd and 5-th in lexicographical order, so the answer is |2 - 5| = 3.\n\nSample Input 2\n\n8\n7 3 5 4 2 1 6 8\n3 8 2 5 4 6 7 1\n\nSample Output 2\n\n17517\n\nSample Input 3\n\n3\n1 2 3\n1 2 3\n\nSample Output 3\n\n0", "sample_input": "3\n1 3 2\n3 1 2\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02813", "source_text": "Score : 300 points\n\nProblem Statement\n\nWe have two permutations P and Q of size N (that is, P and Q are both rearrangements of (1,~2,~...,~N)).\n\nThere are N! possible permutations of size N. Among them, let P and Q be the a-th and b-th lexicographically smallest permutations, respectively. Find |a - b|.\n\nNotes\n\nFor two sequences X and Y, X is said to be lexicographically smaller than Y if and only if there exists an integer k such that X_i = Y_i~(1 \\leq i < k) and X_k < Y_k.\n\nConstraints\n\n2 \\leq N \\leq 8\n\nP and Q are permutations of size N.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nP_1 P_2 ... P_N\nQ_1 Q_2 ... Q_N\n\nOutput\n\nPrint |a - b|.\n\nSample Input 1\n\n3\n1 3 2\n3 1 2\n\nSample Output 1\n\n3\n\nThere are 6 permutations of size 3: (1,~2,~3), (1,~3,~2), (2,~1,~3), (2,~3,~1), (3,~1,~2), and (3,~2,~1). Among them, (1,~3,~2) and (3,~1,~2) come 2-nd and 5-th in lexicographical order, so the answer is |2 - 5| = 3.\n\nSample Input 2\n\n8\n7 3 5 4 2 1 6 8\n3 8 2 5 4 6 7 1\n\nSample Output 2\n\n17517\n\nSample Input 3\n\n3\n1 2 3\n1 2 3\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 442, "cpu_time_ms": 66, "memory_kb": 6528}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s565306836", "group_id": "codeNet:p02814", "input_text": "#define _USE_MATH_DEFINES\n\n#include <iostream>\n#include <iomanip>\n#include <stdio.h>\n\n#include <sstream>\n#include <algorithm>\n#include <iterator>\n#include <cmath>\n#include <complex>\n\n#include <string>\n#include <cstring>\n#include <vector>\n#include <bitset>\n\n#include <queue>\n#include <set>\n#include <map>\n#include <stack>\n#include <list>\n\n#include <ctime>\n////\n//#include <random>//\n/////////\n\ntypedef long long LL;\ntypedef long double LD;\ntypedef unsigned long long ULL;\n\n////定数\nconst int INF = (int)1e9 + 10;\nconst LL MOD = (LL)1e9 + 7;\nconst LL LINF = (LL)4e18 + 20;\nconst LD PI = acos(-1.0);\nconst double EPS = 1e-9; \n/////////\nusing namespace::std;\n//////////////\nLL gcd(LL a, LL b) {\n\tif (b == 0) {\n\t\treturn a;\n\t}\n\telse {\n\t\treturn gcd(b, a % b);\n\t}\n}\nLL lcm(LL a, LL b) {\n\treturn a / gcd(a, b) * b;\n}\n\nvoid solve() {\n\tLL N, M;\n\tcin >> N >> M;\n\n\tint SF = -1;\n\tvector<LL> A(N);\n\tfor (int i = 0; i < N; ++i) {\n\t\tcin >> A[i];\n\t\tint cnt = 0;\n\t\twhile (A[i] % 2 == 0) {\n\t\t\t++cnt;\n\t\t\tA[i] /= 2;\n\t\t}\n\n\t\tif (SF == -1) {\n\t\t\tSF = cnt;\n\t\t}\n\t\telse if(SF != cnt){\n\t\t\tcout << 0 << endl;\n\t\t\treturn;\n\t\t}\n\t}\n\t\n\t\n\tLL res = A[0];\n\tfor (int i = 1; i < N; ++i) {\n\t\tres = lcm(res, A[i]);\n\t\tif (res > M || res < 0) {\n\t\t\tcout << 0 << endl;//関係ない\n\t\t\treturn;\n\t\t}\n\t}\n\tres <<= (SF-1);\n\tLL ter = (M / res) - (M / (res * 2));\n\tcout << ter << endl;\n}\n\nsigned main(void) {\n\tstd::cin.tie(0);\n\tstd::ios::sync_with_stdio(false);\n\tstd::cout << std::fixed;//小数を10進数表示\n\tcout << setprecision(16);//小数点以下の桁数を指定//coutとcerrで別\t\n\n\tsolve();\n}\n", "language": "C++", "metadata": {"date": 1586402189, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02814.html", "problem_id": "p02814", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02814/input.txt", "sample_output_relpath": "derived/input_output/data/p02814/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02814/C++/s565306836.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s565306836", "user_id": "u870307668"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#define _USE_MATH_DEFINES\n\n#include <iostream>\n#include <iomanip>\n#include <stdio.h>\n\n#include <sstream>\n#include <algorithm>\n#include <iterator>\n#include <cmath>\n#include <complex>\n\n#include <string>\n#include <cstring>\n#include <vector>\n#include <bitset>\n\n#include <queue>\n#include <set>\n#include <map>\n#include <stack>\n#include <list>\n\n#include <ctime>\n////\n//#include <random>//\n/////////\n\ntypedef long long LL;\ntypedef long double LD;\ntypedef unsigned long long ULL;\n\n////定数\nconst int INF = (int)1e9 + 10;\nconst LL MOD = (LL)1e9 + 7;\nconst LL LINF = (LL)4e18 + 20;\nconst LD PI = acos(-1.0);\nconst double EPS = 1e-9; \n/////////\nusing namespace::std;\n//////////////\nLL gcd(LL a, LL b) {\n\tif (b == 0) {\n\t\treturn a;\n\t}\n\telse {\n\t\treturn gcd(b, a % b);\n\t}\n}\nLL lcm(LL a, LL b) {\n\treturn a / gcd(a, b) * b;\n}\n\nvoid solve() {\n\tLL N, M;\n\tcin >> N >> M;\n\n\tint SF = -1;\n\tvector<LL> A(N);\n\tfor (int i = 0; i < N; ++i) {\n\t\tcin >> A[i];\n\t\tint cnt = 0;\n\t\twhile (A[i] % 2 == 0) {\n\t\t\t++cnt;\n\t\t\tA[i] /= 2;\n\t\t}\n\n\t\tif (SF == -1) {\n\t\t\tSF = cnt;\n\t\t}\n\t\telse if(SF != cnt){\n\t\t\tcout << 0 << endl;\n\t\t\treturn;\n\t\t}\n\t}\n\t\n\t\n\tLL res = A[0];\n\tfor (int i = 1; i < N; ++i) {\n\t\tres = lcm(res, A[i]);\n\t\tif (res > M || res < 0) {\n\t\t\tcout << 0 << endl;//関係ない\n\t\t\treturn;\n\t\t}\n\t}\n\tres <<= (SF-1);\n\tLL ter = (M / res) - (M / (res * 2));\n\tcout << ter << endl;\n}\n\nsigned main(void) {\n\tstd::cin.tie(0);\n\tstd::ios::sync_with_stdio(false);\n\tstd::cout << std::fixed;//小数を10進数表示\n\tcout << setprecision(16);//小数点以下の桁数を指定//coutとcerrで別\t\n\n\tsolve();\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nGiven are a sequence A= {a_1,a_2,......a_N} of N positive even numbers, and an integer M.\n\nLet a semi-common multiple of A be a positive integer X that satisfies the following condition for every k (1 \\leq k \\leq N):\n\nThere exists a non-negative integer p such that X= a_k \\times (p+0.5).\n\nFind the number of semi-common multiples of A among the integers between 1 and M (inclusive).\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^9\n\n2 \\leq a_i \\leq 10^9\n\na_i is an even number.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\na_1 a_2 ... a_N\n\nOutput\n\nPrint the number of semi-common multiples of A among the integers between 1 and M (inclusive).\n\nSample Input 1\n\n2 50\n6 10\n\nSample Output 1\n\n2\n\n15 = 6 \\times 2.5\n\n15 = 10 \\times 1.5\n\n45 = 6 \\times 7.5\n\n45 = 10 \\times 4.5\n\nThus, 15 and 45 are semi-common multiples of A. There are no other semi-common multiples of A between 1 and 50, so the answer is 2.\n\nSample Input 2\n\n3 100\n14 22 40\n\nSample Output 2\n\n0\n\nThe answer can be 0.\n\nSample Input 3\n\n5 1000000000\n6 6 2 6 2\n\nSample Output 3\n\n166666667", "sample_input": "2 50\n6 10\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02814", "source_text": "Score : 400 points\n\nProblem Statement\n\nGiven are a sequence A= {a_1,a_2,......a_N} of N positive even numbers, and an integer M.\n\nLet a semi-common multiple of A be a positive integer X that satisfies the following condition for every k (1 \\leq k \\leq N):\n\nThere exists a non-negative integer p such that X= a_k \\times (p+0.5).\n\nFind the number of semi-common multiples of A among the integers between 1 and M (inclusive).\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^9\n\n2 \\leq a_i \\leq 10^9\n\na_i is an even number.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\na_1 a_2 ... a_N\n\nOutput\n\nPrint the number of semi-common multiples of A among the integers between 1 and M (inclusive).\n\nSample Input 1\n\n2 50\n6 10\n\nSample Output 1\n\n2\n\n15 = 6 \\times 2.5\n\n15 = 10 \\times 1.5\n\n45 = 6 \\times 7.5\n\n45 = 10 \\times 4.5\n\nThus, 15 and 45 are semi-common multiples of A. There are no other semi-common multiples of A between 1 and 50, so the answer is 2.\n\nSample Input 2\n\n3 100\n14 22 40\n\nSample Output 2\n\n0\n\nThe answer can be 0.\n\nSample Input 3\n\n5 1000000000\n6 6 2 6 2\n\nSample Output 3\n\n166666667", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1555, "cpu_time_ms": 16, "memory_kb": 1024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s386495902", "group_id": "codeNet:p02814", "input_text": "/*\nこれを入れて実行\ng++ code.cpp\n./a.out\n */\n \n#include <iostream>\n#include <stdio.h>\n#include <vector>\n#include <string>\n#include <queue>\n#include <deque>\n#include <algorithm>\n#include <utility>\n#include <set>\n#include <map>\n#include <cmath>\n#include <math.h>\n#include <tuple>\n#include <iomanip>\n#include <bitset>\n \nusing namespace std;\ntypedef long long ll;\ntypedef long double ld;\n \nint dy4[4] = {-1, 0, +1, 0};\nint dx4[4] = {0, +1, 0, -1};\nint dy8[8] = {-1, -1, 0, 1, 1, 1, 0, -1};\nint dx8[8] = {0, 1, 1, 1, 0, -1, -1, -1};\n \nconst long long INF = 1LL << 60;\nconst ll MOD = 1e9 + 7;\n \nbool greaterSecond(const pair<int, int>& f, const pair<int, int>& s){\n    return f.second > s.second;\n}\n \nll gcd(ll a, ll b){\n\tif (b == 0)return a;\n\treturn gcd(b, a % b);\n}\n \nll lcm(ll a, ll b){\n    return a / gcd(a, b) * b;\n}\n \nll nCr(ll n, ll r){\n    if(r == 0 || r == n){\n        return 1;\n    } else if(r == 1){\n        return n;\n    }\n    return (nCr(n - 1, r) + nCr(n - 1, r - 1));\n}\n \nll nPr(ll n, ll r){\n    r = n - r;\n    ll ret = 1;\n    for (ll i = n; i >= r + 1; i--) ret *= i;\n    return ret;\n}\n \n//-----------------------ここから-----------\n\nint main(void){\n    ll n,m;\n    cin >> n >> m;\n\n    vector<ll> a(n);\n    for(int i = 0; i < n; i++) cin >> a[i];\n\n    bool f = true;\n    ll maxi = 0;\n    ll lcmAll = 1;\n\n    set<ll> div;\n\n\n    for(int i = 0; i < n; i++){\n        maxi = max(maxi, a[i]);\n        lcmAll = lcm(lcmAll, a[i] / 2);\n        if((a[i] / 2) % 2 == 0){\n            ll cnt = 0;\n            ll tmp = a[i];\n            while(true){\n                if(tmp % 2 == 0){\n                    tmp /= 2;\n                    cnt++;\n                } else {\n                    break;\n                }\n            }\n            div.insert(cnt);\n        } else {\n            div.insert(1);\n        }\n    }\n\n    if(div.size() > 1){\n        f = false;\n    }\n\n    if(!f){\n        cout << 0 << endl;\n        return 0;\n    }\n\n    ll ans = 0;\n\n\n    ans = (m / lcmAll) - m / (lcmAll * 2);\n\n\n    cout << ans << endl;\n\n\n}", "language": "C++", "metadata": {"date": 1578718291, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02814.html", "problem_id": "p02814", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02814/input.txt", "sample_output_relpath": "derived/input_output/data/p02814/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02814/C++/s386495902.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s386495902", "user_id": "u845000384"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "/*\nこれを入れて実行\ng++ code.cpp\n./a.out\n */\n \n#include <iostream>\n#include <stdio.h>\n#include <vector>\n#include <string>\n#include <queue>\n#include <deque>\n#include <algorithm>\n#include <utility>\n#include <set>\n#include <map>\n#include <cmath>\n#include <math.h>\n#include <tuple>\n#include <iomanip>\n#include <bitset>\n \nusing namespace std;\ntypedef long long ll;\ntypedef long double ld;\n \nint dy4[4] = {-1, 0, +1, 0};\nint dx4[4] = {0, +1, 0, -1};\nint dy8[8] = {-1, -1, 0, 1, 1, 1, 0, -1};\nint dx8[8] = {0, 1, 1, 1, 0, -1, -1, -1};\n \nconst long long INF = 1LL << 60;\nconst ll MOD = 1e9 + 7;\n \nbool greaterSecond(const pair<int, int>& f, const pair<int, int>& s){\n    return f.second > s.second;\n}\n \nll gcd(ll a, ll b){\n\tif (b == 0)return a;\n\treturn gcd(b, a % b);\n}\n \nll lcm(ll a, ll b){\n    return a / gcd(a, b) * b;\n}\n \nll nCr(ll n, ll r){\n    if(r == 0 || r == n){\n        return 1;\n    } else if(r == 1){\n        return n;\n    }\n    return (nCr(n - 1, r) + nCr(n - 1, r - 1));\n}\n \nll nPr(ll n, ll r){\n    r = n - r;\n    ll ret = 1;\n    for (ll i = n; i >= r + 1; i--) ret *= i;\n    return ret;\n}\n \n//-----------------------ここから-----------\n\nint main(void){\n    ll n,m;\n    cin >> n >> m;\n\n    vector<ll> a(n);\n    for(int i = 0; i < n; i++) cin >> a[i];\n\n    bool f = true;\n    ll maxi = 0;\n    ll lcmAll = 1;\n\n    set<ll> div;\n\n\n    for(int i = 0; i < n; i++){\n        maxi = max(maxi, a[i]);\n        lcmAll = lcm(lcmAll, a[i] / 2);\n        if((a[i] / 2) % 2 == 0){\n            ll cnt = 0;\n            ll tmp = a[i];\n            while(true){\n                if(tmp % 2 == 0){\n                    tmp /= 2;\n                    cnt++;\n                } else {\n                    break;\n                }\n            }\n            div.insert(cnt);\n        } else {\n            div.insert(1);\n        }\n    }\n\n    if(div.size() > 1){\n        f = false;\n    }\n\n    if(!f){\n        cout << 0 << endl;\n        return 0;\n    }\n\n    ll ans = 0;\n\n\n    ans = (m / lcmAll) - m / (lcmAll * 2);\n\n\n    cout << ans << endl;\n\n\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nGiven are a sequence A= {a_1,a_2,......a_N} of N positive even numbers, and an integer M.\n\nLet a semi-common multiple of A be a positive integer X that satisfies the following condition for every k (1 \\leq k \\leq N):\n\nThere exists a non-negative integer p such that X= a_k \\times (p+0.5).\n\nFind the number of semi-common multiples of A among the integers between 1 and M (inclusive).\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^9\n\n2 \\leq a_i \\leq 10^9\n\na_i is an even number.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\na_1 a_2 ... a_N\n\nOutput\n\nPrint the number of semi-common multiples of A among the integers between 1 and M (inclusive).\n\nSample Input 1\n\n2 50\n6 10\n\nSample Output 1\n\n2\n\n15 = 6 \\times 2.5\n\n15 = 10 \\times 1.5\n\n45 = 6 \\times 7.5\n\n45 = 10 \\times 4.5\n\nThus, 15 and 45 are semi-common multiples of A. There are no other semi-common multiples of A between 1 and 50, so the answer is 2.\n\nSample Input 2\n\n3 100\n14 22 40\n\nSample Output 2\n\n0\n\nThe answer can be 0.\n\nSample Input 3\n\n5 1000000000\n6 6 2 6 2\n\nSample Output 3\n\n166666667", "sample_input": "2 50\n6 10\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02814", "source_text": "Score : 400 points\n\nProblem Statement\n\nGiven are a sequence A= {a_1,a_2,......a_N} of N positive even numbers, and an integer M.\n\nLet a semi-common multiple of A be a positive integer X that satisfies the following condition for every k (1 \\leq k \\leq N):\n\nThere exists a non-negative integer p such that X= a_k \\times (p+0.5).\n\nFind the number of semi-common multiples of A among the integers between 1 and M (inclusive).\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^9\n\n2 \\leq a_i \\leq 10^9\n\na_i is an even number.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\na_1 a_2 ... a_N\n\nOutput\n\nPrint the number of semi-common multiples of A among the integers between 1 and M (inclusive).\n\nSample Input 1\n\n2 50\n6 10\n\nSample Output 1\n\n2\n\n15 = 6 \\times 2.5\n\n15 = 10 \\times 1.5\n\n45 = 6 \\times 7.5\n\n45 = 10 \\times 4.5\n\nThus, 15 and 45 are semi-common multiples of A. There are no other semi-common multiples of A between 1 and 50, so the answer is 2.\n\nSample Input 2\n\n3 100\n14 22 40\n\nSample Output 2\n\n0\n\nThe answer can be 0.\n\nSample Input 3\n\n5 1000000000\n6 6 2 6 2\n\nSample Output 3\n\n166666667", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2028, "cpu_time_ms": 58, "memory_kb": 1152}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s447314854", "group_id": "codeNet:p02814", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (int64_t i = 0; i < (int64_t)(n); i++)\n\nint main(){\n    int64_t n, m;\n    cin >> n >> m;\n    vector<int64_t> a(n);\n    rep(i,n) cin >> a[i];\n\n    vector<int64_t> b(n);\n    bool bl = true;\n    int64_t ans = 0;\n    rep(i,n){\n        int64_t ai = a[i];\n        int64_t bi = 0;\n        while(ai%2 != 0){\n            ai /= 2;\n            bi++;\n        }\n        b[i] = bi;\n        if(i > 0 && b[i-1] != b[i]){\n            bl = false;\n            break;\n        }\n    }\n    int64_t lcma = a[n-1];\n    if(bl){\n        rep(i,n-1){\n            int64_t ai = a[i]; \n            lcma = ai/__gcd(ai,lcma)*lcma;\n        }\n        lcma /= 2;\n        ans = (m/lcma+1)/2;\n        if(ans < 0) ans = 0;\n    }\n    cout << ans << endl;\n    //cout << lcma << endl;\n}", "language": "C++", "metadata": {"date": 1578712980, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02814.html", "problem_id": "p02814", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02814/input.txt", "sample_output_relpath": "derived/input_output/data/p02814/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02814/C++/s447314854.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s447314854", "user_id": "u366974105"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (int64_t i = 0; i < (int64_t)(n); i++)\n\nint main(){\n    int64_t n, m;\n    cin >> n >> m;\n    vector<int64_t> a(n);\n    rep(i,n) cin >> a[i];\n\n    vector<int64_t> b(n);\n    bool bl = true;\n    int64_t ans = 0;\n    rep(i,n){\n        int64_t ai = a[i];\n        int64_t bi = 0;\n        while(ai%2 != 0){\n            ai /= 2;\n            bi++;\n        }\n        b[i] = bi;\n        if(i > 0 && b[i-1] != b[i]){\n            bl = false;\n            break;\n        }\n    }\n    int64_t lcma = a[n-1];\n    if(bl){\n        rep(i,n-1){\n            int64_t ai = a[i]; \n            lcma = ai/__gcd(ai,lcma)*lcma;\n        }\n        lcma /= 2;\n        ans = (m/lcma+1)/2;\n        if(ans < 0) ans = 0;\n    }\n    cout << ans << endl;\n    //cout << lcma << endl;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nGiven are a sequence A= {a_1,a_2,......a_N} of N positive even numbers, and an integer M.\n\nLet a semi-common multiple of A be a positive integer X that satisfies the following condition for every k (1 \\leq k \\leq N):\n\nThere exists a non-negative integer p such that X= a_k \\times (p+0.5).\n\nFind the number of semi-common multiples of A among the integers between 1 and M (inclusive).\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^9\n\n2 \\leq a_i \\leq 10^9\n\na_i is an even number.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\na_1 a_2 ... a_N\n\nOutput\n\nPrint the number of semi-common multiples of A among the integers between 1 and M (inclusive).\n\nSample Input 1\n\n2 50\n6 10\n\nSample Output 1\n\n2\n\n15 = 6 \\times 2.5\n\n15 = 10 \\times 1.5\n\n45 = 6 \\times 7.5\n\n45 = 10 \\times 4.5\n\nThus, 15 and 45 are semi-common multiples of A. There are no other semi-common multiples of A between 1 and 50, so the answer is 2.\n\nSample Input 2\n\n3 100\n14 22 40\n\nSample Output 2\n\n0\n\nThe answer can be 0.\n\nSample Input 3\n\n5 1000000000\n6 6 2 6 2\n\nSample Output 3\n\n166666667", "sample_input": "2 50\n6 10\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02814", "source_text": "Score : 400 points\n\nProblem Statement\n\nGiven are a sequence A= {a_1,a_2,......a_N} of N positive even numbers, and an integer M.\n\nLet a semi-common multiple of A be a positive integer X that satisfies the following condition for every k (1 \\leq k \\leq N):\n\nThere exists a non-negative integer p such that X= a_k \\times (p+0.5).\n\nFind the number of semi-common multiples of A among the integers between 1 and M (inclusive).\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^9\n\n2 \\leq a_i \\leq 10^9\n\na_i is an even number.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\na_1 a_2 ... a_N\n\nOutput\n\nPrint the number of semi-common multiples of A among the integers between 1 and M (inclusive).\n\nSample Input 1\n\n2 50\n6 10\n\nSample Output 1\n\n2\n\n15 = 6 \\times 2.5\n\n15 = 10 \\times 1.5\n\n45 = 6 \\times 7.5\n\n45 = 10 \\times 4.5\n\nThus, 15 and 45 are semi-common multiples of A. There are no other semi-common multiples of A between 1 and 50, so the answer is 2.\n\nSample Input 2\n\n3 100\n14 22 40\n\nSample Output 2\n\n0\n\nThe answer can be 0.\n\nSample Input 3\n\n5 1000000000\n6 6 2 6 2\n\nSample Output 3\n\n166666667", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 812, "cpu_time_ms": 60, "memory_kb": 1792}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s188282414", "group_id": "codeNet:p02815", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef signed long long ll;\n\n#undef _P\n#define _P(...) (void)printf(__VA_ARGS__)\n#define FOR(x,to) for(x=0;x<(to);x++)\n#define FORR(x,arr) for(auto& x:arr)\n#define ITR(x,c) for(__typeof(c.begin()) x=c.begin();x!=c.end();x++)\n#define ALL(a) (a.begin()),(a.end())\n#define ZERO(a) memset(a,0,sizeof(a))\n#define MINUS(a) memset(a,0xff,sizeof(a))\n//-------------------------------------------------------\n\nint N;\nll C[202020];\nll mo=1000000007;\n\nvoid solve() {\n\tint i,j,k,l,r,x,y; string s;\n\t\n\tcin>>N;\n\tFOR(i,N) cin>>C[i];\n\tsort(C,C+N);\n\treverse(C,C+N);\n\tll p=1,q=1;\n\tFOR(i,N) q=q*2%mo;\n\tll sum=1;\n\tll ret=0;\n\tFOR(i,N) {\n\t\tq=q*(mo+1)/2%mo;\n\t\t(ret+=(C[i]*sum)%mo*q)%=mo;\n\t\tsum=(sum*2+p)%mo;\n\t\tp=p*2%mo;\n\t}\n\tcout<<ret*p%mo<<endl;\n}\n\n\nint main(int argc,char** argv){\n\tstring s;int i;\n\tif(argc==1) ios::sync_with_stdio(false), cin.tie(0);\n\tFOR(i,argc-1) s+=argv[i+1],s+='\\n'; FOR(i,s.size()) ungetc(s[s.size()-1-i],stdin);\n\tcout.tie(0); solve(); return 0;\n}\n", "language": "C++", "metadata": {"date": 1578727190, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02815.html", "problem_id": "p02815", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02815/input.txt", "sample_output_relpath": "derived/input_output/data/p02815/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02815/C++/s188282414.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s188282414", "user_id": "u452725238"}, "prompt_components": {"gold_output": "999999993\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef signed long long ll;\n\n#undef _P\n#define _P(...) (void)printf(__VA_ARGS__)\n#define FOR(x,to) for(x=0;x<(to);x++)\n#define FORR(x,arr) for(auto& x:arr)\n#define ITR(x,c) for(__typeof(c.begin()) x=c.begin();x!=c.end();x++)\n#define ALL(a) (a.begin()),(a.end())\n#define ZERO(a) memset(a,0,sizeof(a))\n#define MINUS(a) memset(a,0xff,sizeof(a))\n//-------------------------------------------------------\n\nint N;\nll C[202020];\nll mo=1000000007;\n\nvoid solve() {\n\tint i,j,k,l,r,x,y; string s;\n\t\n\tcin>>N;\n\tFOR(i,N) cin>>C[i];\n\tsort(C,C+N);\n\treverse(C,C+N);\n\tll p=1,q=1;\n\tFOR(i,N) q=q*2%mo;\n\tll sum=1;\n\tll ret=0;\n\tFOR(i,N) {\n\t\tq=q*(mo+1)/2%mo;\n\t\t(ret+=(C[i]*sum)%mo*q)%=mo;\n\t\tsum=(sum*2+p)%mo;\n\t\tp=p*2%mo;\n\t}\n\tcout<<ret*p%mo<<endl;\n}\n\n\nint main(int argc,char** argv){\n\tstring s;int i;\n\tif(argc==1) ios::sync_with_stdio(false), cin.tie(0);\n\tFOR(i,argc-1) s+=argv[i+1],s+='\\n'; FOR(i,s.size()) ungetc(s[s.size()-1-i],stdin);\n\tcout.tie(0); solve(); return 0;\n}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nFor two sequences S and T of length N consisting of 0 and 1, let us define f(S, T) as follows:\n\nConsider repeating the following operation on S so that S will be equal to T. f(S, T) is the minimum possible total cost of those operations.\n\nChange S_i (from 0 to 1 or vice versa). The cost of this operation is D \\times C_i, where D is the number of integers j such that S_j \\neq T_j (1 \\leq j \\leq N) just before this change.\n\nThere are 2^N \\times (2^N - 1) pairs (S, T) of different sequences of length N consisting of 0 and 1. Compute the sum of f(S, T) over all of those pairs, modulo (10^9+7).\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq C_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nC_1 C_2 \\cdots C_N\n\nOutput\n\nPrint the sum of f(S, T), modulo (10^9+7).\n\nSample Input 1\n\n1\n1000000000\n\nSample Output 1\n\n999999993\n\nThere are two pairs (S, T) of different sequences of length 2 consisting of 0 and 1, as follows:\n\nS = (0), T = (1): by changing S_1 to 1, we can have S = T at the cost of 1000000000, so f(S, T) = 1000000000.\n\nS = (1), T = (0): by changing S_1 to 0, we can have S = T at the cost of 1000000000, so f(S, T) = 1000000000.\n\nThe sum of these is 2000000000, and we should print it modulo (10^9+7), that is, 999999993.\n\nSample Input 2\n\n2\n5 8\n\nSample Output 2\n\n124\n\nThere are 12 pairs (S, T) of different sequences of length 3 consisting of 0 and 1, which include:\n\nS = (0, 1), T = (1, 0)\n\nIn this case, if we first change S_1 to 1 then change S_2 to 0, the total cost is 5 \\times 2 + 8 = 18. We cannot have S = T at a smaller cost, so f(S, T) = 18.\n\nSample Input 3\n\n5\n52 67 72 25 79\n\nSample Output 3\n\n269312", "sample_input": "1\n1000000000\n"}, "reference_outputs": ["999999993\n"], "source_document_id": "p02815", "source_text": "Score : 500 points\n\nProblem Statement\n\nFor two sequences S and T of length N consisting of 0 and 1, let us define f(S, T) as follows:\n\nConsider repeating the following operation on S so that S will be equal to T. f(S, T) is the minimum possible total cost of those operations.\n\nChange S_i (from 0 to 1 or vice versa). The cost of this operation is D \\times C_i, where D is the number of integers j such that S_j \\neq T_j (1 \\leq j \\leq N) just before this change.\n\nThere are 2^N \\times (2^N - 1) pairs (S, T) of different sequences of length N consisting of 0 and 1. Compute the sum of f(S, T) over all of those pairs, modulo (10^9+7).\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq C_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nC_1 C_2 \\cdots C_N\n\nOutput\n\nPrint the sum of f(S, T), modulo (10^9+7).\n\nSample Input 1\n\n1\n1000000000\n\nSample Output 1\n\n999999993\n\nThere are two pairs (S, T) of different sequences of length 2 consisting of 0 and 1, as follows:\n\nS = (0), T = (1): by changing S_1 to 1, we can have S = T at the cost of 1000000000, so f(S, T) = 1000000000.\n\nS = (1), T = (0): by changing S_1 to 0, we can have S = T at the cost of 1000000000, so f(S, T) = 1000000000.\n\nThe sum of these is 2000000000, and we should print it modulo (10^9+7), that is, 999999993.\n\nSample Input 2\n\n2\n5 8\n\nSample Output 2\n\n124\n\nThere are 12 pairs (S, T) of different sequences of length 3 consisting of 0 and 1, which include:\n\nS = (0, 1), T = (1, 0)\n\nIn this case, if we first change S_1 to 1 then change S_2 to 0, the total cost is 5 \\times 2 + 8 = 18. We cannot have S = T at a smaller cost, so f(S, T) = 18.\n\nSample Input 3\n\n5\n52 67 72 25 79\n\nSample Output 3\n\n269312", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 996, "cpu_time_ms": 47, "memory_kb": 1792}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s817559625", "group_id": "codeNet:p02817", "input_text": "#include <iostream>\n#include <algorithm>\n#include <string>\nusing namespace std;\ntypedef long long ll;\n\n\nint main(void){\n  string s,t;\n  \n  cin >> s >> t;\n  \n  cout << t << s << endl;\n  \n  return 0;\n}", "language": "C++", "metadata": {"date": 1583037298, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02817.html", "problem_id": "p02817", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02817/input.txt", "sample_output_relpath": "derived/input_output/data/p02817/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02817/C++/s817559625.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s817559625", "user_id": "u088895504"}, "prompt_components": {"gold_output": "atcoder\n", "input_to_evaluate": "#include <iostream>\n#include <algorithm>\n#include <string>\nusing namespace std;\ntypedef long long ll;\n\n\nint main(void){\n  string s,t;\n  \n  cin >> s >> t;\n  \n  cout << t << s << endl;\n  \n  return 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nGiven are two strings S and T consisting of lowercase English letters. Concatenate T and S in this order, without space in between, and print the resulting string.\n\nConstraints\n\nS and T are strings consisting of lowercase English letters.\n\nThe lengths of S and T are between 1 and 100 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS T\n\nOutput\n\nPrint the resulting string.\n\nSample Input 1\n\noder atc\n\nSample Output 1\n\natcoder\n\nWhen S = oder and T = atc, concatenating T and S in this order results in atcoder.\n\nSample Input 2\n\nhumu humu\n\nSample Output 2\n\nhumuhumu", "sample_input": "oder atc\n"}, "reference_outputs": ["atcoder\n"], "source_document_id": "p02817", "source_text": "Score : 100 points\n\nProblem Statement\n\nGiven are two strings S and T consisting of lowercase English letters. Concatenate T and S in this order, without space in between, and print the resulting string.\n\nConstraints\n\nS and T are strings consisting of lowercase English letters.\n\nThe lengths of S and T are between 1 and 100 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS T\n\nOutput\n\nPrint the resulting string.\n\nSample Input 1\n\noder atc\n\nSample Output 1\n\natcoder\n\nWhen S = oder and T = atc, concatenating T and S in this order results in atcoder.\n\nSample Input 2\n\nhumu humu\n\nSample Output 2\n\nhumuhumu", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 199, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s115896107", "group_id": "codeNet:p02819", "input_text": "/**\n * Created by hiramekun at 19:56 on 2019-12-29.\n */\n#include <bits/stdc++.h>\n\nusing namespace std;\n\nusing ll = long long;\nusing vl = vector<ll>;\nusing vvl = vector<vl>;\nusing vb = vector<bool>;\nusing P = pair<ll, ll>;\ntemplate<typename T> using pq = priority_queue<T>;\ntemplate<typename T> using minpq = priority_queue<T, vector<T>, greater<T>>;\ntemplate<typename T, typename K> using ump = unordered_map<T, K>;\nconst ll dx[4] = {1, 0, -1, 0}, dy[4] = {0, 1, 0, -1};\nconst ll mod = 1000000007;\nconst ll inf = ll(1e9);\nconst ll e5 = ll(1e5);\nconst ll ll_inf = ll(1e9) * ll(1e9);\n\n#define rep(i, n) for(ll i = 0; i < (ll)(n); i++)\n#define repr(i, n) for(ll i = ll(n - 1); i >= 0; i--)\n#define each(i, mp) for(auto& i:mp)\n#define eb emplace_back\n#define F first\n#define S second\n#define all(obj) (obj).begin(), (obj).end()\n\ntemplate<class T>\nostream &operator<<(ostream &out, const vector<T> &list) {\n    ll n = list.size();\n    rep(i, n) out << list[i] << ' ';\n    return out;\n}\n\ntemplate<class T>\nistream &operator>>(istream &in, vector<T> &list) {\n    ll n = list.size();\n    rep(i, n) in >> list[i];\n    return in;\n}\n\ntemplate<class T>\nostream &operator<<(ostream &out, const vector<vector<T>> &list) {\n    ll n = list.size();\n    rep(i, n) out << list[i] << '\\n';\n    return out;\n}\n\n/* ------------- ANSWER ------------- */\n/* ---------------------------------- */\n// 素因数分解\nmap<ll, ll> prime_factor(ll n) {\n    map<ll, ll> mp;\n    for (ll i = 2; i * i <= n; ++i) {\n        while (n % i == 0) {\n            mp[i]++;\n            n /= i;\n        }\n    }\n    if (n != 1) mp[n]++;\n    return mp;\n}\n\n// 素数判定\nbool is_prime(ll n) {\n    for (int i = 2; i * i <= n; i++) if (n % i == 0) return false;\n    return n != 1;\n}\n\n// 約数列挙\nvector<ll> divisor(ll n) {\n    vector<ll> res;\n    for (ll i = 1; i * i <= n; ++i) {\n        if (n % i == 0) {\n            res.emplace_back(i);\n            if (i != n / i) res.emplace_back(n / i);\n        }\n    }\n    return res;\n}\n\nvoid solve() {\n    ll x;\n    cin >> x;\n    for (ll i = x; i <= 1e5 * 2; ++i) {\n        if (is_prime(i)) {\n            cout << i << '\\n';\n            return;\n        }\n    }\n}\n\nint main() {\n#ifdef MY_DEBUG\n    while (true) {\n#endif\n        solve();\n#ifdef MY_DEBUG\n    }\n#endif\n    return 0;\n}", "language": "C++", "metadata": {"date": 1577676756, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02819.html", "problem_id": "p02819", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02819/input.txt", "sample_output_relpath": "derived/input_output/data/p02819/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02819/C++/s115896107.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s115896107", "user_id": "u136378781"}, "prompt_components": {"gold_output": "23\n", "input_to_evaluate": "/**\n * Created by hiramekun at 19:56 on 2019-12-29.\n */\n#include <bits/stdc++.h>\n\nusing namespace std;\n\nusing ll = long long;\nusing vl = vector<ll>;\nusing vvl = vector<vl>;\nusing vb = vector<bool>;\nusing P = pair<ll, ll>;\ntemplate<typename T> using pq = priority_queue<T>;\ntemplate<typename T> using minpq = priority_queue<T, vector<T>, greater<T>>;\ntemplate<typename T, typename K> using ump = unordered_map<T, K>;\nconst ll dx[4] = {1, 0, -1, 0}, dy[4] = {0, 1, 0, -1};\nconst ll mod = 1000000007;\nconst ll inf = ll(1e9);\nconst ll e5 = ll(1e5);\nconst ll ll_inf = ll(1e9) * ll(1e9);\n\n#define rep(i, n) for(ll i = 0; i < (ll)(n); i++)\n#define repr(i, n) for(ll i = ll(n - 1); i >= 0; i--)\n#define each(i, mp) for(auto& i:mp)\n#define eb emplace_back\n#define F first\n#define S second\n#define all(obj) (obj).begin(), (obj).end()\n\ntemplate<class T>\nostream &operator<<(ostream &out, const vector<T> &list) {\n    ll n = list.size();\n    rep(i, n) out << list[i] << ' ';\n    return out;\n}\n\ntemplate<class T>\nistream &operator>>(istream &in, vector<T> &list) {\n    ll n = list.size();\n    rep(i, n) in >> list[i];\n    return in;\n}\n\ntemplate<class T>\nostream &operator<<(ostream &out, const vector<vector<T>> &list) {\n    ll n = list.size();\n    rep(i, n) out << list[i] << '\\n';\n    return out;\n}\n\n/* ------------- ANSWER ------------- */\n/* ---------------------------------- */\n// 素因数分解\nmap<ll, ll> prime_factor(ll n) {\n    map<ll, ll> mp;\n    for (ll i = 2; i * i <= n; ++i) {\n        while (n % i == 0) {\n            mp[i]++;\n            n /= i;\n        }\n    }\n    if (n != 1) mp[n]++;\n    return mp;\n}\n\n// 素数判定\nbool is_prime(ll n) {\n    for (int i = 2; i * i <= n; i++) if (n % i == 0) return false;\n    return n != 1;\n}\n\n// 約数列挙\nvector<ll> divisor(ll n) {\n    vector<ll> res;\n    for (ll i = 1; i * i <= n; ++i) {\n        if (n % i == 0) {\n            res.emplace_back(i);\n            if (i != n / i) res.emplace_back(n / i);\n        }\n    }\n    return res;\n}\n\nvoid solve() {\n    ll x;\n    cin >> x;\n    for (ll i = x; i <= 1e5 * 2; ++i) {\n        if (is_prime(i)) {\n            cout << i << '\\n';\n            return;\n        }\n    }\n}\n\nint main() {\n#ifdef MY_DEBUG\n    while (true) {\n#endif\n        solve();\n#ifdef MY_DEBUG\n    }\n#endif\n    return 0;\n}", "problem_context": "Score: 300 points\n\nProblem Statement\n\nFind the minimum prime number greater than or equal to X.\n\nNotes\n\nA prime number is an integer greater than 1 that cannot be evenly divided by any positive integer except 1 and itself.\n\nFor example, 2, 3, and 5 are prime numbers, while 4 and 6 are not.\n\nConstraints\n\n2 \\le X \\le 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint the minimum prime number greater than or equal to X.\n\nSample Input 1\n\n20\n\nSample Output 1\n\n23\n\nThe minimum prime number greater than or equal to 20 is 23.\n\nSample Input 2\n\n2\n\nSample Output 2\n\n2\n\nX itself can be a prime number.\n\nSample Input 3\n\n99992\n\nSample Output 3\n\n100003", "sample_input": "20\n"}, "reference_outputs": ["23\n"], "source_document_id": "p02819", "source_text": "Score: 300 points\n\nProblem Statement\n\nFind the minimum prime number greater than or equal to X.\n\nNotes\n\nA prime number is an integer greater than 1 that cannot be evenly divided by any positive integer except 1 and itself.\n\nFor example, 2, 3, and 5 are prime numbers, while 4 and 6 are not.\n\nConstraints\n\n2 \\le X \\le 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint the minimum prime number greater than or equal to X.\n\nSample Input 1\n\n20\n\nSample Output 1\n\n23\n\nThe minimum prime number greater than or equal to 20 is 23.\n\nSample Input 2\n\n2\n\nSample Output 2\n\n2\n\nX itself can be a prime number.\n\nSample Input 3\n\n99992\n\nSample Output 3\n\n100003", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2277, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s955887450", "group_id": "codeNet:p02821", "input_text": "#include<bits/stdc++.h>\n#define ll long long\n#define mp make_pair\n#define F first\n#define S second\n#define db double\n#define pb push_back\n#define rep(i,a,b)  for(ll i=a;i<=b;i++)\nusing namespace std;\n \n ll mod=1e9 +7;\n \nll expo(ll base,ll exponent,ll mod){\n    ll ans=1;\n    while(exponent!=0){\n        if(exponent&1) ans=(1LL*ans*base)%mod;\n        base=(1LL*base*base)%mod;\n        exponent>>=1;\n    }\n    return ans%mod;\n}\n \nvector<bool>  prime(90000002,true);\nvoid Sieve() \n{ \n   \n    for (int p=2; p*p<=90000001; p++) \n    { \n        // If prime[p] is not changed, then it is a prime \n        if (prime[p] == true) \n        { \n            for (int i=p*p; i<=90000001; i += p) \n                prime[i] = false; \n        } \n    } \n}\n\nconst ll M=200006;\nll f[M],inv[M];\n\nvoid compute(){\n    f[0]=1;\n    rep(i,1,M-1){\n        f[i]=(1LL*i*f[i-1])%mod;\n    }\n    inv[M-1]=expo(f[M-1],mod-2,mod);\n    for(ll i=M-2;i>=0;i--){\n        inv[i]=(1LL*(i+1)*inv[i+1])%mod;\n    }\n}\nll C(ll n,ll r){\n    return (1LL*((1LL*f[n]*inv[r])%mod)*inv[n-r])%mod;\n}\n\nll pre[200005]={0};\n\npair<ll,ll> func(ll x,vector<ll>&a,ll n)\n{\n  ll num=0,i;\n  ll res=0;\n  rep(i,0,n-1)\n  {\n    ll it=lower_bound(a.begin(),a.end(),x-a[i])-a.begin();\n    num+=n-it;\n    res+=pre[n-1]-pre[it-1];\n    res+=(n-it)*a[i];\n  }\n  return {res,num};\n\n}\n\nint main()\n{\n    ios_base::sync_with_stdio(false);\n    cin.tie(NULL);\n    // compute();\n    Sieve();\n    ll tests=1;\n    // cin>>tests;\n    while(tests--)\n    {\n      ll i,j,n,m;\n      cin>>n>>m;\n      vector<ll>a(n),b(n),c(n);\n      rep(i,0,n-1) cin>>a[i];\n      sort(a.begin(),a.end());\n      pre[0]=a[0];\n      rep(i,1,n-1) pre[i]=pre[i-1]+a[i];\n\n      ll lo=0,hi=200005;\n      ll ans=-1;\n      while(hi>=lo)\n      {\n        ll mid=(lo+hi)/2;\n        if(func(mid,a,n).second>=m)\n        {\n          lo=mid+1;\n        }\n        else\n        {\n          // ans=mid;\n          hi=mid-1;\n        }\n      }\n      ans=func(lo-1,a,n).first;\n      ans-=(func(lo-1,a,n).second-m)*(lo-1);\n      cout<<ans;\n\n\n\n    }\n    return 0;\n   }", "language": "C++", "metadata": {"date": 1594957345, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02821.html", "problem_id": "p02821", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02821/input.txt", "sample_output_relpath": "derived/input_output/data/p02821/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02821/C++/s955887450.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s955887450", "user_id": "u362345573"}, "prompt_components": {"gold_output": "202\n", "input_to_evaluate": "#include<bits/stdc++.h>\n#define ll long long\n#define mp make_pair\n#define F first\n#define S second\n#define db double\n#define pb push_back\n#define rep(i,a,b)  for(ll i=a;i<=b;i++)\nusing namespace std;\n \n ll mod=1e9 +7;\n \nll expo(ll base,ll exponent,ll mod){\n    ll ans=1;\n    while(exponent!=0){\n        if(exponent&1) ans=(1LL*ans*base)%mod;\n        base=(1LL*base*base)%mod;\n        exponent>>=1;\n    }\n    return ans%mod;\n}\n \nvector<bool>  prime(90000002,true);\nvoid Sieve() \n{ \n   \n    for (int p=2; p*p<=90000001; p++) \n    { \n        // If prime[p] is not changed, then it is a prime \n        if (prime[p] == true) \n        { \n            for (int i=p*p; i<=90000001; i += p) \n                prime[i] = false; \n        } \n    } \n}\n\nconst ll M=200006;\nll f[M],inv[M];\n\nvoid compute(){\n    f[0]=1;\n    rep(i,1,M-1){\n        f[i]=(1LL*i*f[i-1])%mod;\n    }\n    inv[M-1]=expo(f[M-1],mod-2,mod);\n    for(ll i=M-2;i>=0;i--){\n        inv[i]=(1LL*(i+1)*inv[i+1])%mod;\n    }\n}\nll C(ll n,ll r){\n    return (1LL*((1LL*f[n]*inv[r])%mod)*inv[n-r])%mod;\n}\n\nll pre[200005]={0};\n\npair<ll,ll> func(ll x,vector<ll>&a,ll n)\n{\n  ll num=0,i;\n  ll res=0;\n  rep(i,0,n-1)\n  {\n    ll it=lower_bound(a.begin(),a.end(),x-a[i])-a.begin();\n    num+=n-it;\n    res+=pre[n-1]-pre[it-1];\n    res+=(n-it)*a[i];\n  }\n  return {res,num};\n\n}\n\nint main()\n{\n    ios_base::sync_with_stdio(false);\n    cin.tie(NULL);\n    // compute();\n    Sieve();\n    ll tests=1;\n    // cin>>tests;\n    while(tests--)\n    {\n      ll i,j,n,m;\n      cin>>n>>m;\n      vector<ll>a(n),b(n),c(n);\n      rep(i,0,n-1) cin>>a[i];\n      sort(a.begin(),a.end());\n      pre[0]=a[0];\n      rep(i,1,n-1) pre[i]=pre[i-1]+a[i];\n\n      ll lo=0,hi=200005;\n      ll ans=-1;\n      while(hi>=lo)\n      {\n        ll mid=(lo+hi)/2;\n        if(func(mid,a,n).second>=m)\n        {\n          lo=mid+1;\n        }\n        else\n        {\n          // ans=mid;\n          hi=mid-1;\n        }\n      }\n      ans=func(lo-1,a,n).first;\n      ans-=(func(lo-1,a,n).second-m)*(lo-1);\n      cout<<ans;\n\n\n\n    }\n    return 0;\n   }", "problem_context": "Score : 500 points\n\nProblem Statement\n\nTakahashi has come to a party as a special guest.\nThere are N ordinary guests at the party. The i-th ordinary guest has a power of A_i.\n\nTakahashi has decided to perform M handshakes to increase the happiness of the party (let the current happiness be 0).\nA handshake will be performed as follows:\n\nTakahashi chooses one (ordinary) guest x for his left hand and another guest y for his right hand (x and y can be the same).\n\nThen, he shakes the left hand of Guest x and the right hand of Guest y simultaneously to increase the happiness by A_x+A_y.\n\nHowever, Takahashi should not perform the same handshake more than once. Formally, the following condition must hold:\n\nAssume that, in the k-th handshake, Takahashi shakes the left hand of Guest x_k and the right hand of Guest y_k. Then, there is no pair p, q (1 \\leq p < q \\leq M) such that (x_p,y_p)=(x_q,y_q).\n\nWhat is the maximum possible happiness after M handshakes?\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq N^2\n\n1 \\leq A_i \\leq 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the maximum possible happiness after M handshakes.\n\nSample Input 1\n\n5 3\n10 14 19 34 33\n\nSample Output 1\n\n202\n\nLet us say that Takahashi performs the following handshakes:\n\nIn the first handshake, Takahashi shakes the left hand of Guest 4 and the right hand of Guest 4.\n\nIn the second handshake, Takahashi shakes the left hand of Guest 4 and the right hand of Guest 5.\n\nIn the third handshake, Takahashi shakes the left hand of Guest 5 and the right hand of Guest 4.\n\nThen, we will have the happiness of (34+34)+(34+33)+(33+34)=202.\n\nWe cannot achieve the happiness of 203 or greater, so the answer is 202.\n\nSample Input 2\n\n9 14\n1 3 5 110 24 21 34 5 3\n\nSample Output 2\n\n1837\n\nSample Input 3\n\n9 73\n67597 52981 5828 66249 75177 64141 40773 79105 16076\n\nSample Output 3\n\n8128170", "sample_input": "5 3\n10 14 19 34 33\n"}, "reference_outputs": ["202\n"], "source_document_id": "p02821", "source_text": "Score : 500 points\n\nProblem Statement\n\nTakahashi has come to a party as a special guest.\nThere are N ordinary guests at the party. The i-th ordinary guest has a power of A_i.\n\nTakahashi has decided to perform M handshakes to increase the happiness of the party (let the current happiness be 0).\nA handshake will be performed as follows:\n\nTakahashi chooses one (ordinary) guest x for his left hand and another guest y for his right hand (x and y can be the same).\n\nThen, he shakes the left hand of Guest x and the right hand of Guest y simultaneously to increase the happiness by A_x+A_y.\n\nHowever, Takahashi should not perform the same handshake more than once. Formally, the following condition must hold:\n\nAssume that, in the k-th handshake, Takahashi shakes the left hand of Guest x_k and the right hand of Guest y_k. Then, there is no pair p, q (1 \\leq p < q \\leq M) such that (x_p,y_p)=(x_q,y_q).\n\nWhat is the maximum possible happiness after M handshakes?\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq N^2\n\n1 \\leq A_i \\leq 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the maximum possible happiness after M handshakes.\n\nSample Input 1\n\n5 3\n10 14 19 34 33\n\nSample Output 1\n\n202\n\nLet us say that Takahashi performs the following handshakes:\n\nIn the first handshake, Takahashi shakes the left hand of Guest 4 and the right hand of Guest 4.\n\nIn the second handshake, Takahashi shakes the left hand of Guest 4 and the right hand of Guest 5.\n\nIn the third handshake, Takahashi shakes the left hand of Guest 5 and the right hand of Guest 4.\n\nThen, we will have the happiness of (34+34)+(34+33)+(33+34)=202.\n\nWe cannot achieve the happiness of 203 or greater, so the answer is 202.\n\nSample Input 2\n\n9 14\n1 3 5 110 24 21 34 5 3\n\nSample Output 2\n\n1837\n\nSample Input 3\n\n9 73\n67597 52981 5828 66249 75177 64141 40773 79105 16076\n\nSample Output 3\n\n8128170", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2036, "cpu_time_ms": 437, "memory_kb": 17452}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s743032252", "group_id": "codeNet:p02823", "input_text": "#include <bits/stdc++.h>\n#define rep(i, a, n) for (int i = a; i < n; i++)\n#define repr(i, a, n) for (int i = n - 1; i >= a; i--)\nusing namespace std;\nusing ll = long long;\nusing P = pair<int, int>;\ntemplate <typename T> void chmin(T &a, T b) { a = min(a, b); }\ntemplate <typename T> void chmax(T &a, T b) { a = max(a, b); }\n\nint main() {\n  ios::sync_with_stdio(false);\n  cin.tie(0);\n\n  ll n, a, b;\n  cin >> n >> a >> b;\n  if ((b - a) % 2 == 0)\n    cout << (b - a) / 2 << endl;\n  else {\n    if (a - 1 <= n - b)\n      cout << b - 1 << endl;\n    else\n      cout << n - a << endl;\n  }\n}\n", "language": "C++", "metadata": {"date": 1591996074, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02823.html", "problem_id": "p02823", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02823/input.txt", "sample_output_relpath": "derived/input_output/data/p02823/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02823/C++/s743032252.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s743032252", "user_id": "u688789047"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define rep(i, a, n) for (int i = a; i < n; i++)\n#define repr(i, a, n) for (int i = n - 1; i >= a; i--)\nusing namespace std;\nusing ll = long long;\nusing P = pair<int, int>;\ntemplate <typename T> void chmin(T &a, T b) { a = min(a, b); }\ntemplate <typename T> void chmax(T &a, T b) { a = max(a, b); }\n\nint main() {\n  ios::sync_with_stdio(false);\n  cin.tie(0);\n\n  ll n, a, b;\n  cin >> n >> a >> b;\n  if ((b - a) % 2 == 0)\n    cout << (b - a) / 2 << endl;\n  else {\n    if (a - 1 <= n - b)\n      cout << b - 1 << endl;\n    else\n      cout << n - a << endl;\n  }\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\n2N players are running a competitive table tennis training on N tables numbered from 1 to N.\n\nThe training consists of rounds.\nIn each round, the players form N pairs, one pair per table.\nIn each pair, competitors play a match against each other.\nAs a result, one of them wins and the other one loses.\n\nThe winner of the match on table X plays on table X-1 in the next round,\nexcept for the winner of the match on table 1 who stays at table 1.\n\nSimilarly, the loser of the match on table X plays on table X+1 in the next round,\nexcept for the loser of the match on table N who stays at table N.\n\nTwo friends are playing their first round matches on distinct tables A and B.\nLet's assume that the friends are strong enough to win or lose any match at will.\nWhat is the smallest number of rounds after which the friends can get to play a match against each other?\n\nConstraints\n\n2 \\leq N \\leq 10^{18}\n\n1 \\leq A < B \\leq N\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN A B\n\nOutput\n\nPrint the smallest number of rounds after which the friends can get to play a match against each other.\n\nSample Input 1\n\n5 2 4\n\nSample Output 1\n\n1\n\nIf the first friend loses their match and the second friend wins their match, they will both move to table 3 and play each other in the next round.\n\nSample Input 2\n\n5 2 3\n\nSample Output 2\n\n2\n\nIf both friends win two matches in a row, they will both move to table 1.", "sample_input": "5 2 4\n"}, "reference_outputs": ["1\n"], "source_document_id": "p02823", "source_text": "Score : 300 points\n\nProblem Statement\n\n2N players are running a competitive table tennis training on N tables numbered from 1 to N.\n\nThe training consists of rounds.\nIn each round, the players form N pairs, one pair per table.\nIn each pair, competitors play a match against each other.\nAs a result, one of them wins and the other one loses.\n\nThe winner of the match on table X plays on table X-1 in the next round,\nexcept for the winner of the match on table 1 who stays at table 1.\n\nSimilarly, the loser of the match on table X plays on table X+1 in the next round,\nexcept for the loser of the match on table N who stays at table N.\n\nTwo friends are playing their first round matches on distinct tables A and B.\nLet's assume that the friends are strong enough to win or lose any match at will.\nWhat is the smallest number of rounds after which the friends can get to play a match against each other?\n\nConstraints\n\n2 \\leq N \\leq 10^{18}\n\n1 \\leq A < B \\leq N\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN A B\n\nOutput\n\nPrint the smallest number of rounds after which the friends can get to play a match against each other.\n\nSample Input 1\n\n5 2 4\n\nSample Output 1\n\n1\n\nIf the first friend loses their match and the second friend wins their match, they will both move to table 3 and play each other in the next round.\n\nSample Input 2\n\n5 2 3\n\nSample Output 2\n\n2\n\nIf both friends win two matches in a row, they will both move to table 1.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 583, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s381486538", "group_id": "codeNet:p02824", "input_text": "#include <bits/stdc++.h>\n#define int long long\nusing namespace std;\nconst int N=1e5+5;\nint n,m,v,p,cnt;\nint a[N];\nsigned main() \n{\n\tcin>>n>>m>>v>>p;//m个评委,每个评委给v个题目加分，选前p名 \n\tfor (int i=1;i<=n;i++) cin>>a[i];\n\tsort(a+1,a+n+1);\n\tif (v<=p)\n\t{\n\t\tfor (int i=1;i<=n;i++) if (a[i]+m>=a[n-p+1]) cnt++;\n\t\tcout<<cnt<<endl;\n\t} else\n\t{\n\t\tfor (int i=1;i<=n;i++) \n\t\t{\n\t\t\tint j=n-i+1;//正数第j名 \n\t\t\tif (j<=p) \n\t\t\t{\n\t\t\t\tcout<<n-i+1<<endl;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tif (i+p-1>=v && a[i]+m>=a[n-p+1]) //取比自己低的人和最高的人加满 \n\t\t\t{\n//\t\t\t\tcout<<\"CASE2\"<<endl;\n\t\t\t\tcout<<n-i+1<<endl;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tint tmp=v*m-(i+p-1)*m;//还需要给这么多\n\t\t\tint temp=0;\n\t\t\tfor (int k=i+1;a[k]<a[i]+m,k<=n-p+1;k++)\n\t\t\t\ttemp+=a[i]+m-a[k];\n\t\t\tif (temp>=tmp && a[i]+m>=a[n-p+1])\n\t\t\t{\n\t\t\t\tcout<<n-i+1<<endl;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1594571970, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02824.html", "problem_id": "p02824", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02824/input.txt", "sample_output_relpath": "derived/input_output/data/p02824/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02824/C++/s381486538.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s381486538", "user_id": "u863370423"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define int long long\nusing namespace std;\nconst int N=1e5+5;\nint n,m,v,p,cnt;\nint a[N];\nsigned main() \n{\n\tcin>>n>>m>>v>>p;//m个评委,每个评委给v个题目加分，选前p名 \n\tfor (int i=1;i<=n;i++) cin>>a[i];\n\tsort(a+1,a+n+1);\n\tif (v<=p)\n\t{\n\t\tfor (int i=1;i<=n;i++) if (a[i]+m>=a[n-p+1]) cnt++;\n\t\tcout<<cnt<<endl;\n\t} else\n\t{\n\t\tfor (int i=1;i<=n;i++) \n\t\t{\n\t\t\tint j=n-i+1;//正数第j名 \n\t\t\tif (j<=p) \n\t\t\t{\n\t\t\t\tcout<<n-i+1<<endl;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tif (i+p-1>=v && a[i]+m>=a[n-p+1]) //取比自己低的人和最高的人加满 \n\t\t\t{\n//\t\t\t\tcout<<\"CASE2\"<<endl;\n\t\t\t\tcout<<n-i+1<<endl;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\tint tmp=v*m-(i+p-1)*m;//还需要给这么多\n\t\t\tint temp=0;\n\t\t\tfor (int k=i+1;a[k]<a[i]+m,k<=n-p+1;k++)\n\t\t\t\ttemp+=a[i]+m-a[k];\n\t\t\tif (temp>=tmp && a[i]+m>=a[n-p+1])\n\t\t\t{\n\t\t\t\tcout<<n-i+1<<endl;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t}\n\treturn 0;\n}\n", "problem_context": "Score : 700 points\n\nProblem Statement\n\nN problems are proposed for an upcoming contest. Problem i has an initial integer score of A_i points.\n\nM judges are about to vote for problems they like. Each judge will choose exactly V problems, independently from the other judges,\nand increase the score of each chosen problem by 1.\n\nAfter all M judges cast their vote, the problems will be sorted in non-increasing order of score, and the first P problems will be chosen for the problemset.\nProblems with the same score can be ordered arbitrarily, this order is decided by the chief judge.\n\nHow many problems out of the given N have a chance to be chosen for the problemset?\n\nConstraints\n\n2 \\le N \\le 10^5\n\n1 \\le M \\le 10^9\n\n1 \\le V \\le N - 1\n\n1 \\le P \\le N - 1\n\n0 \\le A_i \\le 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M V P\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the number of problems that have a chance to be chosen for the problemset.\n\nSample Input 1\n\n6 1 2 2\n2 1 1 3 0 2\n\nSample Output 1\n\n5\n\nIf the only judge votes for problems 2 and 5, the scores will be 2 2 1 3 1 2.\nThe problemset will consist of problem 4 and one of problems 1, 2, or 6.\n\nIf the only judge votes for problems 3 and 4, the scores will be 2 1 2 4 0 2.\nThe problemset will consist of problem 4 and one of problems 1, 3, or 6.\n\nThus, problems 1, 2, 3, 4, and 6 have a chance to be chosen for the problemset. On the contrary, there is no way for problem 5 to be chosen.\n\nSample Input 2\n\n6 1 5 2\n2 1 1 3 0 2\n\nSample Output 2\n\n3\n\nOnly problems 1, 4, and 6 have a chance to be chosen.\n\nSample Input 3\n\n10 4 8 5\n7 2 3 6 1 6 5 4 6 5\n\nSample Output 3\n\n8", "sample_input": "6 1 2 2\n2 1 1 3 0 2\n"}, "reference_outputs": ["5\n"], "source_document_id": "p02824", "source_text": "Score : 700 points\n\nProblem Statement\n\nN problems are proposed for an upcoming contest. Problem i has an initial integer score of A_i points.\n\nM judges are about to vote for problems they like. Each judge will choose exactly V problems, independently from the other judges,\nand increase the score of each chosen problem by 1.\n\nAfter all M judges cast their vote, the problems will be sorted in non-increasing order of score, and the first P problems will be chosen for the problemset.\nProblems with the same score can be ordered arbitrarily, this order is decided by the chief judge.\n\nHow many problems out of the given N have a chance to be chosen for the problemset?\n\nConstraints\n\n2 \\le N \\le 10^5\n\n1 \\le M \\le 10^9\n\n1 \\le V \\le N - 1\n\n1 \\le P \\le N - 1\n\n0 \\le A_i \\le 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M V P\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the number of problems that have a chance to be chosen for the problemset.\n\nSample Input 1\n\n6 1 2 2\n2 1 1 3 0 2\n\nSample Output 1\n\n5\n\nIf the only judge votes for problems 2 and 5, the scores will be 2 2 1 3 1 2.\nThe problemset will consist of problem 4 and one of problems 1, 2, or 6.\n\nIf the only judge votes for problems 3 and 4, the scores will be 2 1 2 4 0 2.\nThe problemset will consist of problem 4 and one of problems 1, 3, or 6.\n\nThus, problems 1, 2, 3, 4, and 6 have a chance to be chosen for the problemset. On the contrary, there is no way for problem 5 to be chosen.\n\nSample Input 2\n\n6 1 5 2\n2 1 1 3 0 2\n\nSample Output 2\n\n3\n\nOnly problems 1, 4, and 6 have a chance to be chosen.\n\nSample Input 3\n\n10 4 8 5\n7 2 3 6 1 6 5 4 6 5\n\nSample Output 3\n\n8", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 865, "cpu_time_ms": 2205, "memory_kb": 4372}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s920348665", "group_id": "codeNet:p02824", "input_text": "// includes\n#include <bits/stdc++.h>\nusing namespace std;\n\n// macros\n#define pb emplace_back\n#define mk make_pair\n#define FOR(i, a, b) for(int i=(a);i<(b);++i)\n#define rep(i, n) FOR(i, 0, n)\n#define rrep(i, n) for(int i=((int)(n)-1);i>=0;i--)\n#define irep(itr, st) for(auto itr = (st).begin(); itr != (st).end(); ++itr)\n#define irrep(itr, st) for(auto itr = (st).rbegin(); itr != (st).rend(); ++itr)\n#define whole(x) (x).begin(),(x).end()\n#define sz(x) ((int)(x).size())\n#define bit(n) (1LL<<(n))\n#define F first\n#define S second\n// functions\ntemplate <typename T> void unique(T& c){c.erase(std::unique(c.begin(), c.end()), c.end());}\ntemplate <class T>bool chmax(T &a, const T &b){if(a < b){a = b; return 1;} return 0;}\ntemplate <class T>bool chmin(T &a, const T &b){if(a > b){a = b; return 1;} return 0;}\ntemplate <typename T> istream &operator>>(istream &is, vector<T> &vec){for(auto &v: vec)is >> v; return is;}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T>& vec){for(int i = 0; i < vec.size(); i++){ os << vec[i]; if(i + 1 != vec.size())os << \" \";} return os;}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << \" \";} return os;}\ntemplate <typename T> ostream &operator<<(ostream &os, const unordered_set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << \" \";} return os;}\ntemplate <typename T> ostream &operator<<(ostream &os, const multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << \" \";} return os;}\ntemplate <typename T> ostream &operator<<(ostream &os, const unordered_multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << \" \";} return os;}\ntemplate <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p){os << \"(\" << p.first << \", \" << p.second << \")\"; return os;}\ntemplate <typename T1, typename T2> ostream &operator<<(ostream &os, const map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os << \"(\" << itr->first << \", \" << itr->second << \")\"; auto titr = itr; if(++titr != mp.end())os << \" \"; } return os;}\ntemplate <typename T1, typename T2> ostream &operator<<(ostream &os, const unordered_map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os << \"(\" << itr->first << \", \" << itr->second << \")\"; auto titr = itr; if(++titr != mp.end())os << \" \"; } return os;}\n//  types\nusing ll = long long int;\nusing P = pair<int, int>;\n// constants\nconst int inf = 1e9;\nconst ll linf = 1LL << 60;\nconst double EPS = 1e-10;\nconst int mod = 1000000007;\nconst int dx[4] = {-1, 0, 1, 0};\nconst int dy[4] = {0, -1, 0, 1};\n// io\nstruct fast_io{\n  fast_io(){ios_base::sync_with_stdio(false); cin.tie(nullptr); cout << fixed << setprecision(20);}\n} fast_io_;\n\n\nint main(int argc, char const* argv[])\n{\n  ll n, m, v, p; cin >> n >> m >> v >> p;\n  vector<ll> a(n); cin >> a;\n  sort(whole(a));\n  vector<ll> acc = a;\n  for(int i = 1; i < n; i++)acc[i] += acc[i-1];\n  map<ll, int> fir, cnt;\n  rrep(i, n)fir[a[i]] = i;\n  rep(i, n)cnt[a[i]]++;\n  int res = 0;\n  ll sum = 0;\n  //cerr << a << endl;\n  irep(itr, cnt){\n    sum += itr->second;\n    bool ok = false;\n    if(sum >= v){\n      int idx = upper_bound(whole(a), itr->first + m) - a.begin();\n      if(n - idx >= p)ok = false;\n      else ok = true;\n    }\n    else{\n      ll rem = v - sum;\n      int idx = upper_bound(whole(a), itr->first + m) - a.begin();\n      if(n - idx >= p)ok = false;\n      else if(n - idx >= rem)ok = true;\n      else{\n        rem = rem - (p - 1);\n        ll curr = acc[idx-1] - (acc[fir[itr->first] + itr->second - 1]);\n        //cerr << curr << \" \" << rem << endl;\n        if((m + itr->first) * (ll)(idx - 1 - (fir[itr->first] + itr->second - 1)) - curr >= rem * m)ok = true;\n      }\n    }\n    if(ok)res += itr->second;\n    //cerr << itr->first << \" \" << ok << endl;\n  }\n  cout << res << endl;\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1590978138, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02824.html", "problem_id": "p02824", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02824/input.txt", "sample_output_relpath": "derived/input_output/data/p02824/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02824/C++/s920348665.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s920348665", "user_id": "u424110125"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "// includes\n#include <bits/stdc++.h>\nusing namespace std;\n\n// macros\n#define pb emplace_back\n#define mk make_pair\n#define FOR(i, a, b) for(int i=(a);i<(b);++i)\n#define rep(i, n) FOR(i, 0, n)\n#define rrep(i, n) for(int i=((int)(n)-1);i>=0;i--)\n#define irep(itr, st) for(auto itr = (st).begin(); itr != (st).end(); ++itr)\n#define irrep(itr, st) for(auto itr = (st).rbegin(); itr != (st).rend(); ++itr)\n#define whole(x) (x).begin(),(x).end()\n#define sz(x) ((int)(x).size())\n#define bit(n) (1LL<<(n))\n#define F first\n#define S second\n// functions\ntemplate <typename T> void unique(T& c){c.erase(std::unique(c.begin(), c.end()), c.end());}\ntemplate <class T>bool chmax(T &a, const T &b){if(a < b){a = b; return 1;} return 0;}\ntemplate <class T>bool chmin(T &a, const T &b){if(a > b){a = b; return 1;} return 0;}\ntemplate <typename T> istream &operator>>(istream &is, vector<T> &vec){for(auto &v: vec)is >> v; return is;}\ntemplate <typename T> ostream &operator<<(ostream &os, const vector<T>& vec){for(int i = 0; i < vec.size(); i++){ os << vec[i]; if(i + 1 != vec.size())os << \" \";} return os;}\ntemplate <typename T> ostream &operator<<(ostream &os, const set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << \" \";} return os;}\ntemplate <typename T> ostream &operator<<(ostream &os, const unordered_set<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << \" \";} return os;}\ntemplate <typename T> ostream &operator<<(ostream &os, const multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << \" \";} return os;}\ntemplate <typename T> ostream &operator<<(ostream &os, const unordered_multiset<T>& st){for(auto itr = st.begin(); itr != st.end(); ++itr){ os << *itr; auto titr = itr; if(++titr != st.end())os << \" \";} return os;}\ntemplate <typename T1, typename T2> ostream &operator<<(ostream &os, const pair<T1, T2> &p){os << \"(\" << p.first << \", \" << p.second << \")\"; return os;}\ntemplate <typename T1, typename T2> ostream &operator<<(ostream &os, const map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os << \"(\" << itr->first << \", \" << itr->second << \")\"; auto titr = itr; if(++titr != mp.end())os << \" \"; } return os;}\ntemplate <typename T1, typename T2> ostream &operator<<(ostream &os, const unordered_map<T1, T2> &mp){for(auto itr = mp.begin(); itr != mp.end(); ++itr){ os << \"(\" << itr->first << \", \" << itr->second << \")\"; auto titr = itr; if(++titr != mp.end())os << \" \"; } return os;}\n//  types\nusing ll = long long int;\nusing P = pair<int, int>;\n// constants\nconst int inf = 1e9;\nconst ll linf = 1LL << 60;\nconst double EPS = 1e-10;\nconst int mod = 1000000007;\nconst int dx[4] = {-1, 0, 1, 0};\nconst int dy[4] = {0, -1, 0, 1};\n// io\nstruct fast_io{\n  fast_io(){ios_base::sync_with_stdio(false); cin.tie(nullptr); cout << fixed << setprecision(20);}\n} fast_io_;\n\n\nint main(int argc, char const* argv[])\n{\n  ll n, m, v, p; cin >> n >> m >> v >> p;\n  vector<ll> a(n); cin >> a;\n  sort(whole(a));\n  vector<ll> acc = a;\n  for(int i = 1; i < n; i++)acc[i] += acc[i-1];\n  map<ll, int> fir, cnt;\n  rrep(i, n)fir[a[i]] = i;\n  rep(i, n)cnt[a[i]]++;\n  int res = 0;\n  ll sum = 0;\n  //cerr << a << endl;\n  irep(itr, cnt){\n    sum += itr->second;\n    bool ok = false;\n    if(sum >= v){\n      int idx = upper_bound(whole(a), itr->first + m) - a.begin();\n      if(n - idx >= p)ok = false;\n      else ok = true;\n    }\n    else{\n      ll rem = v - sum;\n      int idx = upper_bound(whole(a), itr->first + m) - a.begin();\n      if(n - idx >= p)ok = false;\n      else if(n - idx >= rem)ok = true;\n      else{\n        rem = rem - (p - 1);\n        ll curr = acc[idx-1] - (acc[fir[itr->first] + itr->second - 1]);\n        //cerr << curr << \" \" << rem << endl;\n        if((m + itr->first) * (ll)(idx - 1 - (fir[itr->first] + itr->second - 1)) - curr >= rem * m)ok = true;\n      }\n    }\n    if(ok)res += itr->second;\n    //cerr << itr->first << \" \" << ok << endl;\n  }\n  cout << res << endl;\n  return 0;\n}\n", "problem_context": "Score : 700 points\n\nProblem Statement\n\nN problems are proposed for an upcoming contest. Problem i has an initial integer score of A_i points.\n\nM judges are about to vote for problems they like. Each judge will choose exactly V problems, independently from the other judges,\nand increase the score of each chosen problem by 1.\n\nAfter all M judges cast their vote, the problems will be sorted in non-increasing order of score, and the first P problems will be chosen for the problemset.\nProblems with the same score can be ordered arbitrarily, this order is decided by the chief judge.\n\nHow many problems out of the given N have a chance to be chosen for the problemset?\n\nConstraints\n\n2 \\le N \\le 10^5\n\n1 \\le M \\le 10^9\n\n1 \\le V \\le N - 1\n\n1 \\le P \\le N - 1\n\n0 \\le A_i \\le 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M V P\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the number of problems that have a chance to be chosen for the problemset.\n\nSample Input 1\n\n6 1 2 2\n2 1 1 3 0 2\n\nSample Output 1\n\n5\n\nIf the only judge votes for problems 2 and 5, the scores will be 2 2 1 3 1 2.\nThe problemset will consist of problem 4 and one of problems 1, 2, or 6.\n\nIf the only judge votes for problems 3 and 4, the scores will be 2 1 2 4 0 2.\nThe problemset will consist of problem 4 and one of problems 1, 3, or 6.\n\nThus, problems 1, 2, 3, 4, and 6 have a chance to be chosen for the problemset. On the contrary, there is no way for problem 5 to be chosen.\n\nSample Input 2\n\n6 1 5 2\n2 1 1 3 0 2\n\nSample Output 2\n\n3\n\nOnly problems 1, 4, and 6 have a chance to be chosen.\n\nSample Input 3\n\n10 4 8 5\n7 2 3 6 1 6 5 4 6 5\n\nSample Output 3\n\n8", "sample_input": "6 1 2 2\n2 1 1 3 0 2\n"}, "reference_outputs": ["5\n"], "source_document_id": "p02824", "source_text": "Score : 700 points\n\nProblem Statement\n\nN problems are proposed for an upcoming contest. Problem i has an initial integer score of A_i points.\n\nM judges are about to vote for problems they like. Each judge will choose exactly V problems, independently from the other judges,\nand increase the score of each chosen problem by 1.\n\nAfter all M judges cast their vote, the problems will be sorted in non-increasing order of score, and the first P problems will be chosen for the problemset.\nProblems with the same score can be ordered arbitrarily, this order is decided by the chief judge.\n\nHow many problems out of the given N have a chance to be chosen for the problemset?\n\nConstraints\n\n2 \\le N \\le 10^5\n\n1 \\le M \\le 10^9\n\n1 \\le V \\le N - 1\n\n1 \\le P \\le N - 1\n\n0 \\le A_i \\le 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M V P\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the number of problems that have a chance to be chosen for the problemset.\n\nSample Input 1\n\n6 1 2 2\n2 1 1 3 0 2\n\nSample Output 1\n\n5\n\nIf the only judge votes for problems 2 and 5, the scores will be 2 2 1 3 1 2.\nThe problemset will consist of problem 4 and one of problems 1, 2, or 6.\n\nIf the only judge votes for problems 3 and 4, the scores will be 2 1 2 4 0 2.\nThe problemset will consist of problem 4 and one of problems 1, 3, or 6.\n\nThus, problems 1, 2, 3, 4, and 6 have a chance to be chosen for the problemset. On the contrary, there is no way for problem 5 to be chosen.\n\nSample Input 2\n\n6 1 5 2\n2 1 1 3 0 2\n\nSample Output 2\n\n3\n\nOnly problems 1, 4, and 6 have a chance to be chosen.\n\nSample Input 3\n\n10 4 8 5\n7 2 3 6 1 6 5 4 6 5\n\nSample Output 3\n\n8", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 4105, "cpu_time_ms": 125, "memory_kb": 14336}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s043927989", "group_id": "codeNet:p02824", "input_text": "// Hail god Yato\n \n#include <bits/stdc++.h> \nusing namespace std;\n \n#define add(x) accumulate(x)\n#define sz(x) (int)(x).size()\n#define mp make_pair\n#define pb push_back\n#define ff first\n#define ss second\n#define lb lower_bound\n#define ub upper_bound\n#define all(x) x.begin(), x.end() \n#define rep(i, a, b) for (int i=a; i<(b); i++)\n#define hs ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);\ntypedef long long ll;\ntypedef pair<ll,ll> pll;\ntypedef vector<ll> vll;\ntypedef vector<pll> vpll;\nconst ll mod = 1000000007;\nconst ll INF = 1e18;\nconst ll MAX = 100001;\n//\n//\n\n                        ll n,m,p,v;\n                        int arr[MAX];\n                ll oper(ll ix){\n                        if(ix>=v){\n                                if(arr[ix]+m>=arr[n-p])\n                                        return 1;\n                                return 0;\n                        }\n                        ll idx=ub(arr+1,arr+n+1,arr[ix]+m)-arr;\n                        if(n-idx+1>=p){\n                                // cout<<ix<<'\\n';\n                                return 0;\n                        }\n                        ll x=v-(ix+p-1);\n                        ll oper=x*m;\n                        rep(i,ix+1,idx){\n                                oper-=min(oper,arr[ix]+m-arr[i]);\n                        }\n                        if(oper)\n                                return 0;\n                        return 1;\n                }\n                void solve(){\n                        cin>>n>>m>>v>>p;\n                        // int arr[n+1];\n                        rep(i,0,n)\n                                cin>>arr[i+1];\n                        sort(arr+1,arr+n+1);\n                        ll lo=0,hi=n+1;\n                        while(lo<hi){\n                                ll mid=(lo+hi)>>1;\n                                if(oper(mid))\n                                        hi=mid;\n                                else\n                                        lo=mid+1;\n                        }\n                        cout<<n+1-lo;\n                }\n                int main(){ \n                        hs;\n                        ll t;\n                        t=1;\n                        // cin>>t;\n                        for (int i=1; i<=t; i++){\n                                //printf(\"Case #%d: \", i);\n                                solve();\n                         }\n        return 0; \n}         \n ", "language": "C++", "metadata": {"date": 1577701959, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02824.html", "problem_id": "p02824", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02824/input.txt", "sample_output_relpath": "derived/input_output/data/p02824/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02824/C++/s043927989.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s043927989", "user_id": "u216557283"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "// Hail god Yato\n \n#include <bits/stdc++.h> \nusing namespace std;\n \n#define add(x) accumulate(x)\n#define sz(x) (int)(x).size()\n#define mp make_pair\n#define pb push_back\n#define ff first\n#define ss second\n#define lb lower_bound\n#define ub upper_bound\n#define all(x) x.begin(), x.end() \n#define rep(i, a, b) for (int i=a; i<(b); i++)\n#define hs ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);\ntypedef long long ll;\ntypedef pair<ll,ll> pll;\ntypedef vector<ll> vll;\ntypedef vector<pll> vpll;\nconst ll mod = 1000000007;\nconst ll INF = 1e18;\nconst ll MAX = 100001;\n//\n//\n\n                        ll n,m,p,v;\n                        int arr[MAX];\n                ll oper(ll ix){\n                        if(ix>=v){\n                                if(arr[ix]+m>=arr[n-p])\n                                        return 1;\n                                return 0;\n                        }\n                        ll idx=ub(arr+1,arr+n+1,arr[ix]+m)-arr;\n                        if(n-idx+1>=p){\n                                // cout<<ix<<'\\n';\n                                return 0;\n                        }\n                        ll x=v-(ix+p-1);\n                        ll oper=x*m;\n                        rep(i,ix+1,idx){\n                                oper-=min(oper,arr[ix]+m-arr[i]);\n                        }\n                        if(oper)\n                                return 0;\n                        return 1;\n                }\n                void solve(){\n                        cin>>n>>m>>v>>p;\n                        // int arr[n+1];\n                        rep(i,0,n)\n                                cin>>arr[i+1];\n                        sort(arr+1,arr+n+1);\n                        ll lo=0,hi=n+1;\n                        while(lo<hi){\n                                ll mid=(lo+hi)>>1;\n                                if(oper(mid))\n                                        hi=mid;\n                                else\n                                        lo=mid+1;\n                        }\n                        cout<<n+1-lo;\n                }\n                int main(){ \n                        hs;\n                        ll t;\n                        t=1;\n                        // cin>>t;\n                        for (int i=1; i<=t; i++){\n                                //printf(\"Case #%d: \", i);\n                                solve();\n                         }\n        return 0; \n}         \n ", "problem_context": "Score : 700 points\n\nProblem Statement\n\nN problems are proposed for an upcoming contest. Problem i has an initial integer score of A_i points.\n\nM judges are about to vote for problems they like. Each judge will choose exactly V problems, independently from the other judges,\nand increase the score of each chosen problem by 1.\n\nAfter all M judges cast their vote, the problems will be sorted in non-increasing order of score, and the first P problems will be chosen for the problemset.\nProblems with the same score can be ordered arbitrarily, this order is decided by the chief judge.\n\nHow many problems out of the given N have a chance to be chosen for the problemset?\n\nConstraints\n\n2 \\le N \\le 10^5\n\n1 \\le M \\le 10^9\n\n1 \\le V \\le N - 1\n\n1 \\le P \\le N - 1\n\n0 \\le A_i \\le 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M V P\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the number of problems that have a chance to be chosen for the problemset.\n\nSample Input 1\n\n6 1 2 2\n2 1 1 3 0 2\n\nSample Output 1\n\n5\n\nIf the only judge votes for problems 2 and 5, the scores will be 2 2 1 3 1 2.\nThe problemset will consist of problem 4 and one of problems 1, 2, or 6.\n\nIf the only judge votes for problems 3 and 4, the scores will be 2 1 2 4 0 2.\nThe problemset will consist of problem 4 and one of problems 1, 3, or 6.\n\nThus, problems 1, 2, 3, 4, and 6 have a chance to be chosen for the problemset. On the contrary, there is no way for problem 5 to be chosen.\n\nSample Input 2\n\n6 1 5 2\n2 1 1 3 0 2\n\nSample Output 2\n\n3\n\nOnly problems 1, 4, and 6 have a chance to be chosen.\n\nSample Input 3\n\n10 4 8 5\n7 2 3 6 1 6 5 4 6 5\n\nSample Output 3\n\n8", "sample_input": "6 1 2 2\n2 1 1 3 0 2\n"}, "reference_outputs": ["5\n"], "source_document_id": "p02824", "source_text": "Score : 700 points\n\nProblem Statement\n\nN problems are proposed for an upcoming contest. Problem i has an initial integer score of A_i points.\n\nM judges are about to vote for problems they like. Each judge will choose exactly V problems, independently from the other judges,\nand increase the score of each chosen problem by 1.\n\nAfter all M judges cast their vote, the problems will be sorted in non-increasing order of score, and the first P problems will be chosen for the problemset.\nProblems with the same score can be ordered arbitrarily, this order is decided by the chief judge.\n\nHow many problems out of the given N have a chance to be chosen for the problemset?\n\nConstraints\n\n2 \\le N \\le 10^5\n\n1 \\le M \\le 10^9\n\n1 \\le V \\le N - 1\n\n1 \\le P \\le N - 1\n\n0 \\le A_i \\le 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M V P\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the number of problems that have a chance to be chosen for the problemset.\n\nSample Input 1\n\n6 1 2 2\n2 1 1 3 0 2\n\nSample Output 1\n\n5\n\nIf the only judge votes for problems 2 and 5, the scores will be 2 2 1 3 1 2.\nThe problemset will consist of problem 4 and one of problems 1, 2, or 6.\n\nIf the only judge votes for problems 3 and 4, the scores will be 2 1 2 4 0 2.\nThe problemset will consist of problem 4 and one of problems 1, 3, or 6.\n\nThus, problems 1, 2, 3, 4, and 6 have a chance to be chosen for the problemset. On the contrary, there is no way for problem 5 to be chosen.\n\nSample Input 2\n\n6 1 5 2\n2 1 1 3 0 2\n\nSample Output 2\n\n3\n\nOnly problems 1, 4, and 6 have a chance to be chosen.\n\nSample Input 3\n\n10 4 8 5\n7 2 3 6 1 6 5 4 6 5\n\nSample Output 3\n\n8", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2434, "cpu_time_ms": 19, "memory_kb": 640}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s897786829", "group_id": "codeNet:p02824", "input_text": "#include <iostream>\n#include <cstring>\n#include <stdlib.h>\n#include <vector>\n#include <algorithm>\n#include <cmath>\n#include <stack>\n#include <queue>\n#include <math.h>\n#include <string>\n#include <map>\n#include <cstdlib>\n#include <sstream>\n#include <bitset>\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair<ll,ll> pa;\n\nint main()\n{\n    ll N, M, V, P;\n    cin >> N >> M >> V >> P;\n    vector<ll> A(N);\n    for(int i=0; i<N; i++){\n        cin >> A[i];\n    }\n    sort(A.begin(), A.end());\n    reverse(A.begin(), A.end());\n    ll MIN=A[P-1], ans=0;\n    if(V-P<=0){\n        for(int i=0; i<N; i++){\n            if(MIN<=A[i]+M) ans++;\n        }\n        cout << ans << endl;\n        return 0;\n    }\n\n    ans=P;\n    ll R=N-1;\n    ll tmp=A[R]+M;\n    pa pairs=pa(V-P, M);\n    bool ok=false;\n    for(int i=R-1; i>=P-1; i--){\n        if(i==R)continue;\n        if(tmp<A[i]){\n            ok=false;\n            break;\n        }\n        ll r = tmp-A[i];\n        if(r>=M) pairs.first--;\n        else{\n            if(r>pairs.second){\n                pairs.first--;\n                pairs.second+=M;\n            }\n            pairs.second-=r;\n        }\n    }\n    if(pairs.first<0 || (pairs.first<=0 && pairs.second<=M)) ok=true;\n    if(ok){\n        cout << N;\n        return 0;\n    }\n    ll L=P-1;\n    while(R-L>=2){\n        ll mid=(R+L)/2;\n        tmp = A[mid]+M;\n        pa pairs=pa(V-P, M);\n        bool ok=false;\n        for(int i=N-1; i>=P-1; i--){\n            if(i==mid)continue;\n            if(tmp<A[i]){\n                ok=false;\n                break;\n            }\n            ll r=tmp-A[i];\n            if(r>=M) pairs.first--;\n            else{\n                if(r>pairs.second){\n                    pairs.first--;\n                    pairs.second+=M;\n                }\n                pairs.second-=r;\n            }\n        }\n\n        if(pairs.first<0 || (pairs.second<=M && pairs.first<=0)) ok=true;\n        if(ok) L=mid;\n        else R=mid;\n    }\n    cout << L+1 << endl;\n    \n    return 0;\n}", "language": "C++", "metadata": {"date": 1577589058, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02824.html", "problem_id": "p02824", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02824/input.txt", "sample_output_relpath": "derived/input_output/data/p02824/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02824/C++/s897786829.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s897786829", "user_id": "u227379863"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include <iostream>\n#include <cstring>\n#include <stdlib.h>\n#include <vector>\n#include <algorithm>\n#include <cmath>\n#include <stack>\n#include <queue>\n#include <math.h>\n#include <string>\n#include <map>\n#include <cstdlib>\n#include <sstream>\n#include <bitset>\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair<ll,ll> pa;\n\nint main()\n{\n    ll N, M, V, P;\n    cin >> N >> M >> V >> P;\n    vector<ll> A(N);\n    for(int i=0; i<N; i++){\n        cin >> A[i];\n    }\n    sort(A.begin(), A.end());\n    reverse(A.begin(), A.end());\n    ll MIN=A[P-1], ans=0;\n    if(V-P<=0){\n        for(int i=0; i<N; i++){\n            if(MIN<=A[i]+M) ans++;\n        }\n        cout << ans << endl;\n        return 0;\n    }\n\n    ans=P;\n    ll R=N-1;\n    ll tmp=A[R]+M;\n    pa pairs=pa(V-P, M);\n    bool ok=false;\n    for(int i=R-1; i>=P-1; i--){\n        if(i==R)continue;\n        if(tmp<A[i]){\n            ok=false;\n            break;\n        }\n        ll r = tmp-A[i];\n        if(r>=M) pairs.first--;\n        else{\n            if(r>pairs.second){\n                pairs.first--;\n                pairs.second+=M;\n            }\n            pairs.second-=r;\n        }\n    }\n    if(pairs.first<0 || (pairs.first<=0 && pairs.second<=M)) ok=true;\n    if(ok){\n        cout << N;\n        return 0;\n    }\n    ll L=P-1;\n    while(R-L>=2){\n        ll mid=(R+L)/2;\n        tmp = A[mid]+M;\n        pa pairs=pa(V-P, M);\n        bool ok=false;\n        for(int i=N-1; i>=P-1; i--){\n            if(i==mid)continue;\n            if(tmp<A[i]){\n                ok=false;\n                break;\n            }\n            ll r=tmp-A[i];\n            if(r>=M) pairs.first--;\n            else{\n                if(r>pairs.second){\n                    pairs.first--;\n                    pairs.second+=M;\n                }\n                pairs.second-=r;\n            }\n        }\n\n        if(pairs.first<0 || (pairs.second<=M && pairs.first<=0)) ok=true;\n        if(ok) L=mid;\n        else R=mid;\n    }\n    cout << L+1 << endl;\n    \n    return 0;\n}", "problem_context": "Score : 700 points\n\nProblem Statement\n\nN problems are proposed for an upcoming contest. Problem i has an initial integer score of A_i points.\n\nM judges are about to vote for problems they like. Each judge will choose exactly V problems, independently from the other judges,\nand increase the score of each chosen problem by 1.\n\nAfter all M judges cast their vote, the problems will be sorted in non-increasing order of score, and the first P problems will be chosen for the problemset.\nProblems with the same score can be ordered arbitrarily, this order is decided by the chief judge.\n\nHow many problems out of the given N have a chance to be chosen for the problemset?\n\nConstraints\n\n2 \\le N \\le 10^5\n\n1 \\le M \\le 10^9\n\n1 \\le V \\le N - 1\n\n1 \\le P \\le N - 1\n\n0 \\le A_i \\le 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M V P\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the number of problems that have a chance to be chosen for the problemset.\n\nSample Input 1\n\n6 1 2 2\n2 1 1 3 0 2\n\nSample Output 1\n\n5\n\nIf the only judge votes for problems 2 and 5, the scores will be 2 2 1 3 1 2.\nThe problemset will consist of problem 4 and one of problems 1, 2, or 6.\n\nIf the only judge votes for problems 3 and 4, the scores will be 2 1 2 4 0 2.\nThe problemset will consist of problem 4 and one of problems 1, 3, or 6.\n\nThus, problems 1, 2, 3, 4, and 6 have a chance to be chosen for the problemset. On the contrary, there is no way for problem 5 to be chosen.\n\nSample Input 2\n\n6 1 5 2\n2 1 1 3 0 2\n\nSample Output 2\n\n3\n\nOnly problems 1, 4, and 6 have a chance to be chosen.\n\nSample Input 3\n\n10 4 8 5\n7 2 3 6 1 6 5 4 6 5\n\nSample Output 3\n\n8", "sample_input": "6 1 2 2\n2 1 1 3 0 2\n"}, "reference_outputs": ["5\n"], "source_document_id": "p02824", "source_text": "Score : 700 points\n\nProblem Statement\n\nN problems are proposed for an upcoming contest. Problem i has an initial integer score of A_i points.\n\nM judges are about to vote for problems they like. Each judge will choose exactly V problems, independently from the other judges,\nand increase the score of each chosen problem by 1.\n\nAfter all M judges cast their vote, the problems will be sorted in non-increasing order of score, and the first P problems will be chosen for the problemset.\nProblems with the same score can be ordered arbitrarily, this order is decided by the chief judge.\n\nHow many problems out of the given N have a chance to be chosen for the problemset?\n\nConstraints\n\n2 \\le N \\le 10^5\n\n1 \\le M \\le 10^9\n\n1 \\le V \\le N - 1\n\n1 \\le P \\le N - 1\n\n0 \\le A_i \\le 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M V P\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the number of problems that have a chance to be chosen for the problemset.\n\nSample Input 1\n\n6 1 2 2\n2 1 1 3 0 2\n\nSample Output 1\n\n5\n\nIf the only judge votes for problems 2 and 5, the scores will be 2 2 1 3 1 2.\nThe problemset will consist of problem 4 and one of problems 1, 2, or 6.\n\nIf the only judge votes for problems 3 and 4, the scores will be 2 1 2 4 0 2.\nThe problemset will consist of problem 4 and one of problems 1, 3, or 6.\n\nThus, problems 1, 2, 3, 4, and 6 have a chance to be chosen for the problemset. On the contrary, there is no way for problem 5 to be chosen.\n\nSample Input 2\n\n6 1 5 2\n2 1 1 3 0 2\n\nSample Output 2\n\n3\n\nOnly problems 1, 4, and 6 have a chance to be chosen.\n\nSample Input 3\n\n10 4 8 5\n7 2 3 6 1 6 5 4 6 5\n\nSample Output 3\n\n8", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1992, "cpu_time_ms": 50, "memory_kb": 1024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s726216624", "group_id": "codeNet:p02825", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n#define ALL(obj) (obj).begin(),(obj).end()\n#define SPEED cin.tie(0);ios::sync_with_stdio(false);\n\ntemplate<class T> using PQ = priority_queue<T>;\ntemplate<class T> using PQR = priority_queue<T,vector<T>,greater<T>>;\n\nconstexpr long long MOD = (long long)1e9 + 7;\nconstexpr long long MOD2 = 998244353;\nconstexpr long long HIGHINF = (long long)1e18;\nconstexpr long long LOWINF = (long long)1e15;\nconstexpr long double PI = 3.1415926535897932384626433L;\n\ntemplate <class T> vector<T> multivector(size_t N,T init){return vector<T>(N,init);}\ntemplate <class... T> auto multivector(size_t N,T... t){return vector<decltype(multivector(t...))>(N,multivector(t...));}\ntemplate <class T> void corner(bool flg, T hoge) {if (flg) {cout << hoge << endl; exit(0);}}\ntemplate <class T, class U>ostream &operator<<(ostream &o, const map<T, U>&obj) {o << \"{\"; for (auto &x : obj) o << \" {\" << x.first << \" : \" << x.second << \"}\" << \",\"; o << \" }\"; return o;}\ntemplate <class T>ostream &operator<<(ostream &o, const set<T>&obj) {o << \"{\"; for (auto itr = obj.begin(); itr != obj.end(); ++itr) o << (itr != obj.begin() ? \", \" : \"\") << *itr; o << \"}\"; return o;}\ntemplate <class T>ostream &operator<<(ostream &o, const multiset<T>&obj) {o << \"{\"; for (auto itr = obj.begin(); itr != obj.end(); ++itr) o << (itr != obj.begin() ? \", \" : \"\") << *itr; o << \"}\"; return o;}\ntemplate <class T>ostream &operator<<(ostream &o, const vector<T>&obj) {o << \"{\"; for (int i = 0; i < (int)obj.size(); ++i)o << (i > 0 ? \", \" : \"\") << obj[i]; o << \"}\"; return o;}\ntemplate <class T, class U>ostream &operator<<(ostream &o, const pair<T, U>&obj) {o << \"{\" << obj.first << \", \" << obj.second << \"}\"; return o;}\nvoid print(void) {cout << endl;}\ntemplate <class Head> void print(Head&& head) {cout << head;print();}\ntemplate <class Head, class... Tail> void print(Head&& head, Tail&&... tail) {cout << head << \" \";print(forward<Tail>(tail)...);}\ntemplate <class T> void chmax(T& a, const T b){a=max(a,b);}\ntemplate <class T> void chmin(T& a, const T b){a=min(a,b);}\nstd::vector<std::string> split(const std::string &str, const char delemiter) {std::vector<std::string> res;std::stringstream ss(str);std::string buffer; while( std::getline(ss, buffer, delemiter) ) res.push_back(buffer); return res;}\nvoid YN(bool flg) {cout << (flg ? \"YES\" : \"NO\") << endl;}\nvoid Yn(bool flg) {cout << (flg ? \"Yes\" : \"No\") << endl;}\nvoid yn(bool flg) {cout << (flg ? \"yes\" : \"no\") << endl;}\n\nvector<string> f(const int N,map<int,int>& mv,map<int,vector<string>>& mp){\n\tvector<string> res(N,string(N,'.'));\n\tint idx=0;\n\tfor(auto e:mv){\n\t\tint x=e.first,y=e.second;\n\t\tfor(int n = 0; n < y; ++n){\n\t\t\tfor(int i = 0; i < x; ++i) {\n\t\t\t\tfor(int j = 0; j < x; ++j) {\n\t\t\t\t\tres[idx+i][idx+j]=mp[x][i][j];\n\t\t\t\t}\n\t\t\t}\n\t\t\tidx+=x;\n\t\t}\n\t}\n\treturn res;\n}\n\nint main() {\n\tmap<int,vector<string>> mp;\n\tmp[3]={\n\t\t\"aa.\",\n\t\t\"..a\",\n\t\t\"..a\",\n\t\t};\n\tmp[4]={\n\t\t\"abcc\",\n\t\t\"abdd\",\n\t\t\"ccab\",\n\t\t\"ddab\",\n\t\t};\n\tmp[6]={\n\t\t\"aabbaa\",\n\t\t\"b.a.b.\",\n\t\t\"b.a.b.\",\n\t\t\".a.b.a\",\n\t\t\".a.b.a\",\n\t\t\"bbaabb\"\n\t\t};\n\tmp[7]={\n\t\t\"acc..b.\",\n\t\t\"a..aab.\",\n\t\t\"bb..bcc\",\n\t\t\"..ccb.a\",\n\t\t\"a..aa.a\",\n\t\t\"a....cb\",\n\t\t\".aa..cb\"\n\t\t};\n\tmap<int,int> mv;\n\tint N; cin >> N;\n\tcorner(N==2||N==5,-1);\n\tif(N%3==0){\n\t\tmv[3]=N/3;\n\t}\n\telse{\n\t\tint x,y,z;\n\t\tfor(int i = 0; i*7 <= N; ++i) {\n\t\t\tfor(int j = 0; j*6 + i*7 <= N; ++j) {\n\t\t\t\tint k = N - j*6 - i*7;\n\t\t\t\tif(k<0 || k%4) continue;\n\t\t\t\tk/=4;\n\t\t\t\tx=i,y=j,z=k;\n\t\t\t}\n\t\t}\n\t\tmv[7]=x,mv[6]=y,mv[4]=z;\n\t}\n\tauto ans=f(N,mv,mp);\n\tfor(int i = 0; i < N; ++i) cout << ans[i] << endl;\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1596089092, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02825.html", "problem_id": "p02825", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02825/input.txt", "sample_output_relpath": "derived/input_output/data/p02825/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02825/C++/s726216624.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s726216624", "user_id": "u898651494"}, "prompt_components": {"gold_output": "aabb..\nb..zz.\nba....\n.a..aa\n..a..b\n..a..b\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n#define ALL(obj) (obj).begin(),(obj).end()\n#define SPEED cin.tie(0);ios::sync_with_stdio(false);\n\ntemplate<class T> using PQ = priority_queue<T>;\ntemplate<class T> using PQR = priority_queue<T,vector<T>,greater<T>>;\n\nconstexpr long long MOD = (long long)1e9 + 7;\nconstexpr long long MOD2 = 998244353;\nconstexpr long long HIGHINF = (long long)1e18;\nconstexpr long long LOWINF = (long long)1e15;\nconstexpr long double PI = 3.1415926535897932384626433L;\n\ntemplate <class T> vector<T> multivector(size_t N,T init){return vector<T>(N,init);}\ntemplate <class... T> auto multivector(size_t N,T... t){return vector<decltype(multivector(t...))>(N,multivector(t...));}\ntemplate <class T> void corner(bool flg, T hoge) {if (flg) {cout << hoge << endl; exit(0);}}\ntemplate <class T, class U>ostream &operator<<(ostream &o, const map<T, U>&obj) {o << \"{\"; for (auto &x : obj) o << \" {\" << x.first << \" : \" << x.second << \"}\" << \",\"; o << \" }\"; return o;}\ntemplate <class T>ostream &operator<<(ostream &o, const set<T>&obj) {o << \"{\"; for (auto itr = obj.begin(); itr != obj.end(); ++itr) o << (itr != obj.begin() ? \", \" : \"\") << *itr; o << \"}\"; return o;}\ntemplate <class T>ostream &operator<<(ostream &o, const multiset<T>&obj) {o << \"{\"; for (auto itr = obj.begin(); itr != obj.end(); ++itr) o << (itr != obj.begin() ? \", \" : \"\") << *itr; o << \"}\"; return o;}\ntemplate <class T>ostream &operator<<(ostream &o, const vector<T>&obj) {o << \"{\"; for (int i = 0; i < (int)obj.size(); ++i)o << (i > 0 ? \", \" : \"\") << obj[i]; o << \"}\"; return o;}\ntemplate <class T, class U>ostream &operator<<(ostream &o, const pair<T, U>&obj) {o << \"{\" << obj.first << \", \" << obj.second << \"}\"; return o;}\nvoid print(void) {cout << endl;}\ntemplate <class Head> void print(Head&& head) {cout << head;print();}\ntemplate <class Head, class... Tail> void print(Head&& head, Tail&&... tail) {cout << head << \" \";print(forward<Tail>(tail)...);}\ntemplate <class T> void chmax(T& a, const T b){a=max(a,b);}\ntemplate <class T> void chmin(T& a, const T b){a=min(a,b);}\nstd::vector<std::string> split(const std::string &str, const char delemiter) {std::vector<std::string> res;std::stringstream ss(str);std::string buffer; while( std::getline(ss, buffer, delemiter) ) res.push_back(buffer); return res;}\nvoid YN(bool flg) {cout << (flg ? \"YES\" : \"NO\") << endl;}\nvoid Yn(bool flg) {cout << (flg ? \"Yes\" : \"No\") << endl;}\nvoid yn(bool flg) {cout << (flg ? \"yes\" : \"no\") << endl;}\n\nvector<string> f(const int N,map<int,int>& mv,map<int,vector<string>>& mp){\n\tvector<string> res(N,string(N,'.'));\n\tint idx=0;\n\tfor(auto e:mv){\n\t\tint x=e.first,y=e.second;\n\t\tfor(int n = 0; n < y; ++n){\n\t\t\tfor(int i = 0; i < x; ++i) {\n\t\t\t\tfor(int j = 0; j < x; ++j) {\n\t\t\t\t\tres[idx+i][idx+j]=mp[x][i][j];\n\t\t\t\t}\n\t\t\t}\n\t\t\tidx+=x;\n\t\t}\n\t}\n\treturn res;\n}\n\nint main() {\n\tmap<int,vector<string>> mp;\n\tmp[3]={\n\t\t\"aa.\",\n\t\t\"..a\",\n\t\t\"..a\",\n\t\t};\n\tmp[4]={\n\t\t\"abcc\",\n\t\t\"abdd\",\n\t\t\"ccab\",\n\t\t\"ddab\",\n\t\t};\n\tmp[6]={\n\t\t\"aabbaa\",\n\t\t\"b.a.b.\",\n\t\t\"b.a.b.\",\n\t\t\".a.b.a\",\n\t\t\".a.b.a\",\n\t\t\"bbaabb\"\n\t\t};\n\tmp[7]={\n\t\t\"acc..b.\",\n\t\t\"a..aab.\",\n\t\t\"bb..bcc\",\n\t\t\"..ccb.a\",\n\t\t\"a..aa.a\",\n\t\t\"a....cb\",\n\t\t\".aa..cb\"\n\t\t};\n\tmap<int,int> mv;\n\tint N; cin >> N;\n\tcorner(N==2||N==5,-1);\n\tif(N%3==0){\n\t\tmv[3]=N/3;\n\t}\n\telse{\n\t\tint x,y,z;\n\t\tfor(int i = 0; i*7 <= N; ++i) {\n\t\t\tfor(int j = 0; j*6 + i*7 <= N; ++j) {\n\t\t\t\tint k = N - j*6 - i*7;\n\t\t\t\tif(k<0 || k%4) continue;\n\t\t\t\tk/=4;\n\t\t\t\tx=i,y=j,z=k;\n\t\t\t}\n\t\t}\n\t\tmv[7]=x,mv[6]=y,mv[4]=z;\n\t}\n\tauto ans=f(N,mv,mp);\n\tfor(int i = 0; i < N; ++i) cout << ans[i] << endl;\n    return 0;\n}\n", "problem_context": "Score : 900 points\n\nProblem Statement\n\nLet us consider a grid of squares with N rows and N columns. You want to put some domino pieces on this grid.\nEach domino piece covers two squares that have a common side. Each square can be covered by at most one piece.\n\nFor each row of the grid, let's define its quality as the number of domino pieces that cover at least one square in this row.\nWe define the quality of each column similarly.\n\nFind a way to put at least one domino piece on the grid so that the quality of every row is equal to the quality of every column,\nor determine that such a placement doesn't exist.\n\nConstraints\n\n2 \\le N \\le 1000\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nIf the required domino placement doesn't exist, print a single integer -1.\n\nOtherwise, output your placement as N strings of N characters each.\nIf a square is not covered, the corresponding character must be . (a dot).\nOtherwise, it must contain a lowercase English letter.\nSquares covered by the same domino piece must contain the same letter.\nIf two squares have a common side but belong to different pieces, they must contain different letters.\n\nSample Input 1\n\n6\n\nSample Output 1\n\naabb..\nb..zz.\nba....\n.a..aa\n..a..b\n..a..b\n\nThe quality of every row and every column is 2.\n\nSample Input 2\n\n2\n\nSample Output 2\n\n-1", "sample_input": "6\n"}, "reference_outputs": ["aabb..\nb..zz.\nba....\n.a..aa\n..a..b\n..a..b\n"], "source_document_id": "p02825", "source_text": "Score : 900 points\n\nProblem Statement\n\nLet us consider a grid of squares with N rows and N columns. You want to put some domino pieces on this grid.\nEach domino piece covers two squares that have a common side. Each square can be covered by at most one piece.\n\nFor each row of the grid, let's define its quality as the number of domino pieces that cover at least one square in this row.\nWe define the quality of each column similarly.\n\nFind a way to put at least one domino piece on the grid so that the quality of every row is equal to the quality of every column,\nor determine that such a placement doesn't exist.\n\nConstraints\n\n2 \\le N \\le 1000\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nIf the required domino placement doesn't exist, print a single integer -1.\n\nOtherwise, output your placement as N strings of N characters each.\nIf a square is not covered, the corresponding character must be . (a dot).\nOtherwise, it must contain a lowercase English letter.\nSquares covered by the same domino piece must contain the same letter.\nIf two squares have a common side but belong to different pieces, they must contain different letters.\n\nSample Input 1\n\n6\n\nSample Output 1\n\naabb..\nb..zz.\nba....\n.a..aa\n..a..b\n..a..b\n\nThe quality of every row and every column is 2.\n\nSample Input 2\n\n2\n\nSample Output 2\n\n-1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 3574, "cpu_time_ms": 13, "memory_kb": 4640}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s384872075", "group_id": "codeNet:p02830", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  int N;\n  cin >> N;\n  string S, T;\n  cin >> S >> T;\n  \n  for(int i=0; i<N; i++){\n    cout << S[i] << T[i];\n  }\n  cout << endl;\n  \n  return 0;\n}", "language": "C++", "metadata": {"date": 1577548405, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02830.html", "problem_id": "p02830", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02830/input.txt", "sample_output_relpath": "derived/input_output/data/p02830/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02830/C++/s384872075.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s384872075", "user_id": "u120826790"}, "prompt_components": {"gold_output": "icpc\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  int N;\n  cin >> N;\n  string S, T;\n  cin >> S >> T;\n  \n  for(int i=0; i<N; i++){\n    cout << S[i] << T[i];\n  }\n  cout << endl;\n  \n  return 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nGiven are strings s and t of length N each, both consisting of lowercase English letters.\n\nLet us form a new string by alternating the characters of S and the characters of T, as follows: the first character of S, the first character of T, the second character of S, the second character of T, ..., the N-th character of S, the N-th character of T. Print this new string.\n\nConstraints\n\n1 \\leq N \\leq 100\n\n|S| = |T| = N\n\nS and T are strings consisting of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS T\n\nOutput\n\nPrint the string formed.\n\nSample Input 1\n\n2\nip cc\n\nSample Output 1\n\nicpc\n\nSample Input 2\n\n8\nhmhmnknk uuuuuuuu\n\nSample Output 2\n\nhumuhumunukunuku\n\nSample Input 3\n\n5\naaaaa aaaaa\n\nSample Output 3\n\naaaaaaaaaa", "sample_input": "2\nip cc\n"}, "reference_outputs": ["icpc\n"], "source_document_id": "p02830", "source_text": "Score : 200 points\n\nProblem Statement\n\nGiven are strings s and t of length N each, both consisting of lowercase English letters.\n\nLet us form a new string by alternating the characters of S and the characters of T, as follows: the first character of S, the first character of T, the second character of S, the second character of T, ..., the N-th character of S, the N-th character of T. Print this new string.\n\nConstraints\n\n1 \\leq N \\leq 100\n\n|S| = |T| = N\n\nS and T are strings consisting of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS T\n\nOutput\n\nPrint the string formed.\n\nSample Input 1\n\n2\nip cc\n\nSample Output 1\n\nicpc\n\nSample Input 2\n\n8\nhmhmnknk uuuuuuuu\n\nSample Output 2\n\nhumuhumunukunuku\n\nSample Input 3\n\n5\naaaaa aaaaa\n\nSample Output 3\n\naaaaaaaaaa", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 203, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s422772843", "group_id": "codeNet:p02830", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nchar s1[105],s2[105];\nint main()\n{\n\tint n;\n\tcin>>n;\n\tfor (int i=1;i<=n;i++)  cin>>s1[i];\n\tfor (int i=1;i<=n;i++)  cin>>s2[i];\n\tfor (int i=1;i<=n;i++)  cout<<s1[i]<<s2[i];\n\tcout<<endl;\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1577066645, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02830.html", "problem_id": "p02830", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02830/input.txt", "sample_output_relpath": "derived/input_output/data/p02830/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02830/C++/s422772843.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s422772843", "user_id": "u952557476"}, "prompt_components": {"gold_output": "icpc\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nchar s1[105],s2[105];\nint main()\n{\n\tint n;\n\tcin>>n;\n\tfor (int i=1;i<=n;i++)  cin>>s1[i];\n\tfor (int i=1;i<=n;i++)  cin>>s2[i];\n\tfor (int i=1;i<=n;i++)  cout<<s1[i]<<s2[i];\n\tcout<<endl;\n\treturn 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nGiven are strings s and t of length N each, both consisting of lowercase English letters.\n\nLet us form a new string by alternating the characters of S and the characters of T, as follows: the first character of S, the first character of T, the second character of S, the second character of T, ..., the N-th character of S, the N-th character of T. Print this new string.\n\nConstraints\n\n1 \\leq N \\leq 100\n\n|S| = |T| = N\n\nS and T are strings consisting of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS T\n\nOutput\n\nPrint the string formed.\n\nSample Input 1\n\n2\nip cc\n\nSample Output 1\n\nicpc\n\nSample Input 2\n\n8\nhmhmnknk uuuuuuuu\n\nSample Output 2\n\nhumuhumunukunuku\n\nSample Input 3\n\n5\naaaaa aaaaa\n\nSample Output 3\n\naaaaaaaaaa", "sample_input": "2\nip cc\n"}, "reference_outputs": ["icpc\n"], "source_document_id": "p02830", "source_text": "Score : 200 points\n\nProblem Statement\n\nGiven are strings s and t of length N each, both consisting of lowercase English letters.\n\nLet us form a new string by alternating the characters of S and the characters of T, as follows: the first character of S, the first character of T, the second character of S, the second character of T, ..., the N-th character of S, the N-th character of T. Print this new string.\n\nConstraints\n\n1 \\leq N \\leq 100\n\n|S| = |T| = N\n\nS and T are strings consisting of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS T\n\nOutput\n\nPrint the string formed.\n\nSample Input 1\n\n2\nip cc\n\nSample Output 1\n\nicpc\n\nSample Input 2\n\n8\nhmhmnknk uuuuuuuu\n\nSample Output 2\n\nhumuhumunukunuku\n\nSample Input 3\n\n5\naaaaa aaaaa\n\nSample Output 3\n\naaaaaaaaaa", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 242, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s394907400", "group_id": "codeNet:p02831", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nlong gcd(long a, long b) {\n\n  if (b == 0) {\n    return a;\n  }\n\n  return gcd(b, a % b);\n}\n\nlong lcm(long a, long b) {\n  \n  return a / gcd(a, b) * b;\n\n}\n\nint main() {\n\n  int A, B;\n  cin >> A >> B;\n\n  long long answer = lcm(A, B);\n\n  cout << answer << endl;\n\n  return 0;\n\n}", "language": "C++", "metadata": {"date": 1584141698, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02831.html", "problem_id": "p02831", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02831/input.txt", "sample_output_relpath": "derived/input_output/data/p02831/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02831/C++/s394907400.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s394907400", "user_id": "u046482892"}, "prompt_components": {"gold_output": "6\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nlong gcd(long a, long b) {\n\n  if (b == 0) {\n    return a;\n  }\n\n  return gcd(b, a % b);\n}\n\nlong lcm(long a, long b) {\n  \n  return a / gcd(a, b) * b;\n\n}\n\nint main() {\n\n  int A, B;\n  cin >> A >> B;\n\n  long long answer = lcm(A, B);\n\n  cout << answer << endl;\n\n  return 0;\n\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nTakahashi is organizing a party.\n\nAt the party, each guest will receive one or more snack pieces.\n\nTakahashi predicts that the number of guests at this party will be A or B.\n\nFind the minimum number of pieces that can be evenly distributed to the guests in both of the cases predicted.\n\nWe assume that a piece cannot be divided and distributed to multiple guests.\n\nConstraints\n\n1 \\leq A, B \\leq 10^5\n\nA \\neq B\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nPrint the minimum number of pieces that can be evenly distributed to the guests in both of the cases with A guests and B guests.\n\nSample Input 1\n\n2 3\n\nSample Output 1\n\n6\n\nWhen we have six snack pieces, each guest can take three pieces if we have two guests, and each guest can take two if we have three guests.\n\nSample Input 2\n\n123 456\n\nSample Output 2\n\n18696\n\nSample Input 3\n\n100000 99999\n\nSample Output 3\n\n9999900000", "sample_input": "2 3\n"}, "reference_outputs": ["6\n"], "source_document_id": "p02831", "source_text": "Score : 300 points\n\nProblem Statement\n\nTakahashi is organizing a party.\n\nAt the party, each guest will receive one or more snack pieces.\n\nTakahashi predicts that the number of guests at this party will be A or B.\n\nFind the minimum number of pieces that can be evenly distributed to the guests in both of the cases predicted.\n\nWe assume that a piece cannot be divided and distributed to multiple guests.\n\nConstraints\n\n1 \\leq A, B \\leq 10^5\n\nA \\neq B\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nPrint the minimum number of pieces that can be evenly distributed to the guests in both of the cases with A guests and B guests.\n\nSample Input 1\n\n2 3\n\nSample Output 1\n\n6\n\nWhen we have six snack pieces, each guest can take three pieces if we have two guests, and each guest can take two if we have three guests.\n\nSample Input 2\n\n123 456\n\nSample Output 2\n\n18696\n\nSample Input 3\n\n100000 99999\n\nSample Output 3\n\n9999900000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 317, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s127954471", "group_id": "codeNet:p02831", "input_text": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint main() {\n    ios::sync_with_stdio(0);\n    cin.tie(0);\n    cout.tie(0);\n\n    int a, b;\n    cin >> a >> b;\n\n    int aa = a, bb = b;\n    while (b != 0) {\n        int c = a % b;\n        a = b, b = c;\n    }\n\n    cout << (long long) aa / a * bb;\n\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1578878676, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02831.html", "problem_id": "p02831", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02831/input.txt", "sample_output_relpath": "derived/input_output/data/p02831/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02831/C++/s127954471.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s127954471", "user_id": "u809013442"}, "prompt_components": {"gold_output": "6\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint main() {\n    ios::sync_with_stdio(0);\n    cin.tie(0);\n    cout.tie(0);\n\n    int a, b;\n    cin >> a >> b;\n\n    int aa = a, bb = b;\n    while (b != 0) {\n        int c = a % b;\n        a = b, b = c;\n    }\n\n    cout << (long long) aa / a * bb;\n\n    return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nTakahashi is organizing a party.\n\nAt the party, each guest will receive one or more snack pieces.\n\nTakahashi predicts that the number of guests at this party will be A or B.\n\nFind the minimum number of pieces that can be evenly distributed to the guests in both of the cases predicted.\n\nWe assume that a piece cannot be divided and distributed to multiple guests.\n\nConstraints\n\n1 \\leq A, B \\leq 10^5\n\nA \\neq B\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nPrint the minimum number of pieces that can be evenly distributed to the guests in both of the cases with A guests and B guests.\n\nSample Input 1\n\n2 3\n\nSample Output 1\n\n6\n\nWhen we have six snack pieces, each guest can take three pieces if we have two guests, and each guest can take two if we have three guests.\n\nSample Input 2\n\n123 456\n\nSample Output 2\n\n18696\n\nSample Input 3\n\n100000 99999\n\nSample Output 3\n\n9999900000", "sample_input": "2 3\n"}, "reference_outputs": ["6\n"], "source_document_id": "p02831", "source_text": "Score : 300 points\n\nProblem Statement\n\nTakahashi is organizing a party.\n\nAt the party, each guest will receive one or more snack pieces.\n\nTakahashi predicts that the number of guests at this party will be A or B.\n\nFind the minimum number of pieces that can be evenly distributed to the guests in both of the cases predicted.\n\nWe assume that a piece cannot be divided and distributed to multiple guests.\n\nConstraints\n\n1 \\leq A, B \\leq 10^5\n\nA \\neq B\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nPrint the minimum number of pieces that can be evenly distributed to the guests in both of the cases with A guests and B guests.\n\nSample Input 1\n\n2 3\n\nSample Output 1\n\n6\n\nWhen we have six snack pieces, each guest can take three pieces if we have two guests, and each guest can take two if we have three guests.\n\nSample Input 2\n\n123 456\n\nSample Output 2\n\n18696\n\nSample Input 3\n\n100000 99999\n\nSample Output 3\n\n9999900000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 309, "cpu_time_ms": 2, "memory_kb": 384}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s497890081", "group_id": "codeNet:p02832", "input_text": "#include <bits/stdc++.h>\n#define rep(i,n) for(int i=0; i<n; i++)\n#define PI 3.14159265359\ntypedef long long ll;\nusing namespace std;\n\nint main(){\n    int n; cin >> n;\n    int a[n]; int now=1;\n    rep(i,n) cin >> a[i];\n    rep(i,n) if(a[i]==now) now++;\n    if(now==1) cout << -1 << endl;\n    else cout << n-now+1 << endl;\nreturn 0;\n}\n", "language": "C++", "metadata": {"date": 1577068444, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02832.html", "problem_id": "p02832", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02832/input.txt", "sample_output_relpath": "derived/input_output/data/p02832/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02832/C++/s497890081.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s497890081", "user_id": "u437779154"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define rep(i,n) for(int i=0; i<n; i++)\n#define PI 3.14159265359\ntypedef long long ll;\nusing namespace std;\n\nint main(){\n    int n; cin >> n;\n    int a[n]; int now=1;\n    rep(i,n) cin >> a[i];\n    rep(i,n) if(a[i]==now) now++;\n    if(now==1) cout << -1 << endl;\n    else cout << n-now+1 << endl;\nreturn 0;\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nWe have N bricks arranged in a row from left to right.\n\nThe i-th brick from the left (1 \\leq i \\leq N) has an integer a_i written on it.\n\nAmong them, you can break at most N-1 bricks of your choice.\n\nLet us say there are K bricks remaining. Snuke will be satisfied if, for each integer i (1 \\leq i \\leq K), the i-th of those brick from the left has the integer i written on it.\n\nFind the minimum number of bricks you need to break to satisfy Snuke's desire. If his desire is unsatisfiable, print -1 instead.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 200000\n\n1 \\leq a_i \\leq N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_N\n\nOutput\n\nPrint the minimum number of bricks that need to be broken to satisfy Snuke's desire, or print -1 if his desire is unsatisfiable.\n\nSample Input 1\n\n3\n2 1 2\n\nSample Output 1\n\n1\n\nIf we break the leftmost brick, the remaining bricks have integers 1 and 2 written on them from left to right, in which case Snuke will be satisfied.\n\nSample Input 2\n\n3\n2 2 2\n\nSample Output 2\n\n-1\n\nIn this case, there is no way to break some of the bricks to satisfy Snuke's desire.\n\nSample Input 3\n\n10\n3 1 4 1 5 9 2 6 5 3\n\nSample Output 3\n\n7\n\nSample Input 4\n\n1\n1\n\nSample Output 4\n\n0\n\nThere may be no need to break the bricks at all.", "sample_input": "3\n2 1 2\n"}, "reference_outputs": ["1\n"], "source_document_id": "p02832", "source_text": "Score : 400 points\n\nProblem Statement\n\nWe have N bricks arranged in a row from left to right.\n\nThe i-th brick from the left (1 \\leq i \\leq N) has an integer a_i written on it.\n\nAmong them, you can break at most N-1 bricks of your choice.\n\nLet us say there are K bricks remaining. Snuke will be satisfied if, for each integer i (1 \\leq i \\leq K), the i-th of those brick from the left has the integer i written on it.\n\nFind the minimum number of bricks you need to break to satisfy Snuke's desire. If his desire is unsatisfiable, print -1 instead.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 200000\n\n1 \\leq a_i \\leq N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_N\n\nOutput\n\nPrint the minimum number of bricks that need to be broken to satisfy Snuke's desire, or print -1 if his desire is unsatisfiable.\n\nSample Input 1\n\n3\n2 1 2\n\nSample Output 1\n\n1\n\nIf we break the leftmost brick, the remaining bricks have integers 1 and 2 written on them from left to right, in which case Snuke will be satisfied.\n\nSample Input 2\n\n3\n2 2 2\n\nSample Output 2\n\n-1\n\nIn this case, there is no way to break some of the bricks to satisfy Snuke's desire.\n\nSample Input 3\n\n10\n3 1 4 1 5 9 2 6 5 3\n\nSample Output 3\n\n7\n\nSample Input 4\n\n1\n1\n\nSample Output 4\n\n0\n\nThere may be no need to break the bricks at all.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 333, "cpu_time_ms": 80, "memory_kb": 1024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s487644866", "group_id": "codeNet:p02832", "input_text": "#include <iostream>\n#include <algorithm>\n#include <math.h>\n#include <string>\nusing namespace std;\n\n#define N 200000\n#define M 100\n\nint main(){\n\tint a[N], b,r,x, i,j = 0,n, ans = 0, br = 1;\n\n\tcin >> n;\n\n\tfor (i = 0; i < n; i++) {\n\t\tcin >> a[i];\n\t}\n\n\tfor (i = 0; i < n; i++) {\n\t\tif (a[i] == br) {\n\t\t\tif (br == 1) {\n\t\t\t\tans += i - j;\n\t\t\t\tj = i;\n\t\t\t\tbr++;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tans += i - j - 1;\n\t\t\t\tj = i;\n\t\t\t\tbr++;\n\t\t\t}\n\t\t}\n\t}\n\n\tif (br != 1) {\n\t\tcout << ans << endl;\n\t}\n\telse {\n\t\tcout << -1;\n\t}\n\t\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1577067956, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02832.html", "problem_id": "p02832", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02832/input.txt", "sample_output_relpath": "derived/input_output/data/p02832/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02832/C++/s487644866.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s487644866", "user_id": "u049068827"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <iostream>\n#include <algorithm>\n#include <math.h>\n#include <string>\nusing namespace std;\n\n#define N 200000\n#define M 100\n\nint main(){\n\tint a[N], b,r,x, i,j = 0,n, ans = 0, br = 1;\n\n\tcin >> n;\n\n\tfor (i = 0; i < n; i++) {\n\t\tcin >> a[i];\n\t}\n\n\tfor (i = 0; i < n; i++) {\n\t\tif (a[i] == br) {\n\t\t\tif (br == 1) {\n\t\t\t\tans += i - j;\n\t\t\t\tj = i;\n\t\t\t\tbr++;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tans += i - j - 1;\n\t\t\t\tj = i;\n\t\t\t\tbr++;\n\t\t\t}\n\t\t}\n\t}\n\n\tif (br != 1) {\n\t\tcout << ans << endl;\n\t}\n\telse {\n\t\tcout << -1;\n\t}\n\t\n\treturn 0;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nWe have N bricks arranged in a row from left to right.\n\nThe i-th brick from the left (1 \\leq i \\leq N) has an integer a_i written on it.\n\nAmong them, you can break at most N-1 bricks of your choice.\n\nLet us say there are K bricks remaining. Snuke will be satisfied if, for each integer i (1 \\leq i \\leq K), the i-th of those brick from the left has the integer i written on it.\n\nFind the minimum number of bricks you need to break to satisfy Snuke's desire. If his desire is unsatisfiable, print -1 instead.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 200000\n\n1 \\leq a_i \\leq N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_N\n\nOutput\n\nPrint the minimum number of bricks that need to be broken to satisfy Snuke's desire, or print -1 if his desire is unsatisfiable.\n\nSample Input 1\n\n3\n2 1 2\n\nSample Output 1\n\n1\n\nIf we break the leftmost brick, the remaining bricks have integers 1 and 2 written on them from left to right, in which case Snuke will be satisfied.\n\nSample Input 2\n\n3\n2 2 2\n\nSample Output 2\n\n-1\n\nIn this case, there is no way to break some of the bricks to satisfy Snuke's desire.\n\nSample Input 3\n\n10\n3 1 4 1 5 9 2 6 5 3\n\nSample Output 3\n\n7\n\nSample Input 4\n\n1\n1\n\nSample Output 4\n\n0\n\nThere may be no need to break the bricks at all.", "sample_input": "3\n2 1 2\n"}, "reference_outputs": ["1\n"], "source_document_id": "p02832", "source_text": "Score : 400 points\n\nProblem Statement\n\nWe have N bricks arranged in a row from left to right.\n\nThe i-th brick from the left (1 \\leq i \\leq N) has an integer a_i written on it.\n\nAmong them, you can break at most N-1 bricks of your choice.\n\nLet us say there are K bricks remaining. Snuke will be satisfied if, for each integer i (1 \\leq i \\leq K), the i-th of those brick from the left has the integer i written on it.\n\nFind the minimum number of bricks you need to break to satisfy Snuke's desire. If his desire is unsatisfiable, print -1 instead.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 200000\n\n1 \\leq a_i \\leq N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_N\n\nOutput\n\nPrint the minimum number of bricks that need to be broken to satisfy Snuke's desire, or print -1 if his desire is unsatisfiable.\n\nSample Input 1\n\n3\n2 1 2\n\nSample Output 1\n\n1\n\nIf we break the leftmost brick, the remaining bricks have integers 1 and 2 written on them from left to right, in which case Snuke will be satisfied.\n\nSample Input 2\n\n3\n2 2 2\n\nSample Output 2\n\n-1\n\nIn this case, there is no way to break some of the bricks to satisfy Snuke's desire.\n\nSample Input 3\n\n10\n3 1 4 1 5 9 2 6 5 3\n\nSample Output 3\n\n7\n\nSample Input 4\n\n1\n1\n\nSample Output 4\n\n0\n\nThere may be no need to break the bricks at all.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 504, "cpu_time_ms": 78, "memory_kb": 1024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s285209855", "group_id": "codeNet:p02835", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n#define int long long\n\nsigned main(void){\n    int a,b,c; cin >> a >>  b >> c;\n    if(a+b+c < 22) cout << \"win\" << endl;\n    else cout << \"bust\" << endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1575902953, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02835.html", "problem_id": "p02835", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02835/input.txt", "sample_output_relpath": "derived/input_output/data/p02835/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02835/C++/s285209855.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s285209855", "user_id": "u030848580"}, "prompt_components": {"gold_output": "win\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n#define int long long\n\nsigned main(void){\n    int a,b,c; cin >> a >>  b >> c;\n    if(a+b+c < 22) cout << \"win\" << endl;\n    else cout << \"bust\" << endl;\n    return 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nGiven are three integers A_1, A_2, and A_3.\n\nIf A_1+A_2+A_3 is greater than or equal to 22, print bust; otherwise, print win.\n\nConstraints\n\n1 \\leq A_i \\leq 13 \\ \\ (i=1,2,3)\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA_1 A_2 A_3\n\nOutput\n\nIf A_1+A_2+A_3 is greater than or equal to 22, print bust; otherwise, print win.\n\nSample Input 1\n\n5 7 9\n\nSample Output 1\n\nwin\n\n5+7+9=21, so print win.\n\nSample Input 2\n\n13 7 2\n\nSample Output 2\n\nbust\n\n13+7+2=22, so print bust.", "sample_input": "5 7 9\n"}, "reference_outputs": ["win\n"], "source_document_id": "p02835", "source_text": "Score : 100 points\n\nProblem Statement\n\nGiven are three integers A_1, A_2, and A_3.\n\nIf A_1+A_2+A_3 is greater than or equal to 22, print bust; otherwise, print win.\n\nConstraints\n\n1 \\leq A_i \\leq 13 \\ \\ (i=1,2,3)\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA_1 A_2 A_3\n\nOutput\n\nIf A_1+A_2+A_3 is greater than or equal to 22, print bust; otherwise, print win.\n\nSample Input 1\n\n5 7 9\n\nSample Output 1\n\nwin\n\n5+7+9=21, so print win.\n\nSample Input 2\n\n13 7 2\n\nSample Output 2\n\nbust\n\n13+7+2=22, so print bust.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 213, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s051096303", "group_id": "codeNet:p02835", "input_text": "#include <stdio.h>\nint main(){\n    int a,b,c;\n    scanf(\"%d %d %d\",a,b,c);\n    if(a+b+c<=21){\n        printf(\"win\");\n    }else{\n        printf(\"bust\");\n    }\n    return 0;\n}", "language": "C++", "metadata": {"date": 1575856966, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02835.html", "problem_id": "p02835", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02835/input.txt", "sample_output_relpath": "derived/input_output/data/p02835/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02835/C++/s051096303.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s051096303", "user_id": "u685629265"}, "prompt_components": {"gold_output": "win\n", "input_to_evaluate": "#include <stdio.h>\nint main(){\n    int a,b,c;\n    scanf(\"%d %d %d\",a,b,c);\n    if(a+b+c<=21){\n        printf(\"win\");\n    }else{\n        printf(\"bust\");\n    }\n    return 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nGiven are three integers A_1, A_2, and A_3.\n\nIf A_1+A_2+A_3 is greater than or equal to 22, print bust; otherwise, print win.\n\nConstraints\n\n1 \\leq A_i \\leq 13 \\ \\ (i=1,2,3)\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA_1 A_2 A_3\n\nOutput\n\nIf A_1+A_2+A_3 is greater than or equal to 22, print bust; otherwise, print win.\n\nSample Input 1\n\n5 7 9\n\nSample Output 1\n\nwin\n\n5+7+9=21, so print win.\n\nSample Input 2\n\n13 7 2\n\nSample Output 2\n\nbust\n\n13+7+2=22, so print bust.", "sample_input": "5 7 9\n"}, "reference_outputs": ["win\n"], "source_document_id": "p02835", "source_text": "Score : 100 points\n\nProblem Statement\n\nGiven are three integers A_1, A_2, and A_3.\n\nIf A_1+A_2+A_3 is greater than or equal to 22, print bust; otherwise, print win.\n\nConstraints\n\n1 \\leq A_i \\leq 13 \\ \\ (i=1,2,3)\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA_1 A_2 A_3\n\nOutput\n\nIf A_1+A_2+A_3 is greater than or equal to 22, print bust; otherwise, print win.\n\nSample Input 1\n\n5 7 9\n\nSample Output 1\n\nwin\n\n5+7+9=21, so print win.\n\nSample Input 2\n\n13 7 2\n\nSample Output 2\n\nbust\n\n13+7+2=22, so print bust.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 173, "cpu_time_ms": 141, "memory_kb": 128}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s797566577", "group_id": "codeNet:p02835", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n\n\nint main(){\n\tint a,b,c;\n\tcin>>a>>b>>c;\n\tif(a+b+c>=22)puts(\"bust\");\n\telse puts(\"win\");\n\n}\n", "language": "C++", "metadata": {"date": 1575856954, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02835.html", "problem_id": "p02835", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02835/input.txt", "sample_output_relpath": "derived/input_output/data/p02835/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02835/C++/s797566577.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s797566577", "user_id": "u414275860"}, "prompt_components": {"gold_output": "win\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n\n\nint main(){\n\tint a,b,c;\n\tcin>>a>>b>>c;\n\tif(a+b+c>=22)puts(\"bust\");\n\telse puts(\"win\");\n\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nGiven are three integers A_1, A_2, and A_3.\n\nIf A_1+A_2+A_3 is greater than or equal to 22, print bust; otherwise, print win.\n\nConstraints\n\n1 \\leq A_i \\leq 13 \\ \\ (i=1,2,3)\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA_1 A_2 A_3\n\nOutput\n\nIf A_1+A_2+A_3 is greater than or equal to 22, print bust; otherwise, print win.\n\nSample Input 1\n\n5 7 9\n\nSample Output 1\n\nwin\n\n5+7+9=21, so print win.\n\nSample Input 2\n\n13 7 2\n\nSample Output 2\n\nbust\n\n13+7+2=22, so print bust.", "sample_input": "5 7 9\n"}, "reference_outputs": ["win\n"], "source_document_id": "p02835", "source_text": "Score : 100 points\n\nProblem Statement\n\nGiven are three integers A_1, A_2, and A_3.\n\nIf A_1+A_2+A_3 is greater than or equal to 22, print bust; otherwise, print win.\n\nConstraints\n\n1 \\leq A_i \\leq 13 \\ \\ (i=1,2,3)\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA_1 A_2 A_3\n\nOutput\n\nIf A_1+A_2+A_3 is greater than or equal to 22, print bust; otherwise, print win.\n\nSample Input 1\n\n5 7 9\n\nSample Output 1\n\nwin\n\n5+7+9=21, so print win.\n\nSample Input 2\n\n13 7 2\n\nSample Output 2\n\nbust\n\n13+7+2=22, so print bust.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 136, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s491191006", "group_id": "codeNet:p02835", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for(int i = 0; i < n; i++)\n\nint main(){\n    int A,B,C;\n    cin >> A >> B >> C;\n    if(A+B+C > 21)cout << \"bust\";\n    else cout <<\"win\";\n    return 0;\n}", "language": "C++", "metadata": {"date": 1575856914, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02835.html", "problem_id": "p02835", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02835/input.txt", "sample_output_relpath": "derived/input_output/data/p02835/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02835/C++/s491191006.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s491191006", "user_id": "u923676814"}, "prompt_components": {"gold_output": "win\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for(int i = 0; i < n; i++)\n\nint main(){\n    int A,B,C;\n    cin >> A >> B >> C;\n    if(A+B+C > 21)cout << \"bust\";\n    else cout <<\"win\";\n    return 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nGiven are three integers A_1, A_2, and A_3.\n\nIf A_1+A_2+A_3 is greater than or equal to 22, print bust; otherwise, print win.\n\nConstraints\n\n1 \\leq A_i \\leq 13 \\ \\ (i=1,2,3)\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA_1 A_2 A_3\n\nOutput\n\nIf A_1+A_2+A_3 is greater than or equal to 22, print bust; otherwise, print win.\n\nSample Input 1\n\n5 7 9\n\nSample Output 1\n\nwin\n\n5+7+9=21, so print win.\n\nSample Input 2\n\n13 7 2\n\nSample Output 2\n\nbust\n\n13+7+2=22, so print bust.", "sample_input": "5 7 9\n"}, "reference_outputs": ["win\n"], "source_document_id": "p02835", "source_text": "Score : 100 points\n\nProblem Statement\n\nGiven are three integers A_1, A_2, and A_3.\n\nIf A_1+A_2+A_3 is greater than or equal to 22, print bust; otherwise, print win.\n\nConstraints\n\n1 \\leq A_i \\leq 13 \\ \\ (i=1,2,3)\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA_1 A_2 A_3\n\nOutput\n\nIf A_1+A_2+A_3 is greater than or equal to 22, print bust; otherwise, print win.\n\nSample Input 1\n\n5 7 9\n\nSample Output 1\n\nwin\n\n5+7+9=21, so print win.\n\nSample Input 2\n\n13 7 2\n\nSample Output 2\n\nbust\n\n13+7+2=22, so print bust.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 215, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s522742253", "group_id": "codeNet:p02837", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nvoid solve(int N,vector<vector<int>> &x,vector<vector<int>> &y,vector<vector<int>> &hito,int &ans){\n\tfor(int i=0;i<hito.size();i++){\n\t\tbool pro =true;\n\t\tfor(int k=0;k<N;k++){\n\t\t\tif(hito.at(i).at(k)==1)\n        for(int j=0;j<x.at(k).size();j++)\n          if(hito.at(i).at(x.at(k).at(j)) != y.at(k).at(j) ){pro =false;break;}\n\t\t\tif(!pro)break;\n\t\t}\n\t\tif(pro){\n\t\t\tint cu=0;\n\t\t\tfor(int j=0;j<N;j++)if(hito.at(i).at(j)==1)cu++;\n\t\t\tans=max(ans,cu);\n\t\t}\n\t}\n}\n\nint main(){\n\tint N; cin >> N;\n\tvector<vector<int>> x(N);\n\tvector<vector<int>> y(N);\n\tint a;\n\tint x1,y1;\n\tfor(int i=0;i<N;i++){\n\t\tcin >> a;\n\t\tfor(int j=0;j<a;j++){\n\t\t\tcin >> x1>> y1;\n\t\t\tx.at(i).push_back(x1-1);\n\t\t\ty.at(i).push_back(y1);\n\t\t}\n\t}\n\tint p =(1<<16);\n\tvector <vector<int>> hito(p,vector<int>(16,0));\n\t\n\tfor(int t=0;t<(1<<16);t++){\n\t\tbitset<16> s(t);\n\t\tfor(int i=0;i<N;i++){\n\t\t\tif(s.test(i)){\n\t\t\t\thito.at(t).at(i)=1;\n\t\t\t}\n\t\t}\n\t}\n\t\n\tint ans=0;\n\tsolve(N,x,y,hito,ans);\n\n\tcout<<ans<<endl;\n}\n\n\n\n\n", "language": "C++", "metadata": {"date": 1575866285, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02837.html", "problem_id": "p02837", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02837/input.txt", "sample_output_relpath": "derived/input_output/data/p02837/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02837/C++/s522742253.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s522742253", "user_id": "u819160021"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nvoid solve(int N,vector<vector<int>> &x,vector<vector<int>> &y,vector<vector<int>> &hito,int &ans){\n\tfor(int i=0;i<hito.size();i++){\n\t\tbool pro =true;\n\t\tfor(int k=0;k<N;k++){\n\t\t\tif(hito.at(i).at(k)==1)\n        for(int j=0;j<x.at(k).size();j++)\n          if(hito.at(i).at(x.at(k).at(j)) != y.at(k).at(j) ){pro =false;break;}\n\t\t\tif(!pro)break;\n\t\t}\n\t\tif(pro){\n\t\t\tint cu=0;\n\t\t\tfor(int j=0;j<N;j++)if(hito.at(i).at(j)==1)cu++;\n\t\t\tans=max(ans,cu);\n\t\t}\n\t}\n}\n\nint main(){\n\tint N; cin >> N;\n\tvector<vector<int>> x(N);\n\tvector<vector<int>> y(N);\n\tint a;\n\tint x1,y1;\n\tfor(int i=0;i<N;i++){\n\t\tcin >> a;\n\t\tfor(int j=0;j<a;j++){\n\t\t\tcin >> x1>> y1;\n\t\t\tx.at(i).push_back(x1-1);\n\t\t\ty.at(i).push_back(y1);\n\t\t}\n\t}\n\tint p =(1<<16);\n\tvector <vector<int>> hito(p,vector<int>(16,0));\n\t\n\tfor(int t=0;t<(1<<16);t++){\n\t\tbitset<16> s(t);\n\t\tfor(int i=0;i<N;i++){\n\t\t\tif(s.test(i)){\n\t\t\t\thito.at(t).at(i)=1;\n\t\t\t}\n\t\t}\n\t}\n\t\n\tint ans=0;\n\tsolve(N,x,y,hito,ans);\n\n\tcout<<ans<<endl;\n}\n\n\n\n\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N people numbered 1 to N. Each of them is either an honest person whose testimonies are always correct or an unkind person whose testimonies may be correct or not.\n\nPerson i gives A_i testimonies. The j-th testimony by Person i is represented by two integers x_{ij} and y_{ij}. If y_{ij} = 1, the testimony says Person x_{ij} is honest; if y_{ij} = 0, it says Person x_{ij} is unkind.\n\nHow many honest persons can be among those N people at most?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 15\n\n0 \\leq A_i \\leq N - 1\n\n1 \\leq x_{ij} \\leq N\n\nx_{ij} \\neq i\n\nx_{ij_1} \\neq x_{ij_2} (j_1 \\neq j_2)\n\ny_{ij} = 0, 1\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1\nx_{11} y_{11}\nx_{12} y_{12}\n:\nx_{1A_1} y_{1A_1}\nA_2\nx_{21} y_{21}\nx_{22} y_{22}\n:\nx_{2A_2} y_{2A_2}\n:\nA_N\nx_{N1} y_{N1}\nx_{N2} y_{N2}\n:\nx_{NA_N} y_{NA_N}\n\nOutput\n\nPrint the maximum possible number of honest persons among the N people.\n\nSample Input 1\n\n3\n1\n2 1\n1\n1 1\n1\n2 0\n\nSample Output 1\n\n2\n\nIf Person 1 and Person 2 are honest and Person 3 is unkind, we have two honest persons without inconsistencies, which is the maximum possible number of honest persons.\n\nSample Input 2\n\n3\n2\n2 1\n3 0\n2\n3 1\n1 0\n2\n1 1\n2 0\n\nSample Output 2\n\n0\n\nAssuming that one or more of them are honest immediately leads to a contradiction.\n\nSample Input 3\n\n2\n1\n2 0\n1\n1 0\n\nSample Output 3\n\n1", "sample_input": "3\n1\n2 1\n1\n1 1\n1\n2 0\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02837", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N people numbered 1 to N. Each of them is either an honest person whose testimonies are always correct or an unkind person whose testimonies may be correct or not.\n\nPerson i gives A_i testimonies. The j-th testimony by Person i is represented by two integers x_{ij} and y_{ij}. If y_{ij} = 1, the testimony says Person x_{ij} is honest; if y_{ij} = 0, it says Person x_{ij} is unkind.\n\nHow many honest persons can be among those N people at most?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 15\n\n0 \\leq A_i \\leq N - 1\n\n1 \\leq x_{ij} \\leq N\n\nx_{ij} \\neq i\n\nx_{ij_1} \\neq x_{ij_2} (j_1 \\neq j_2)\n\ny_{ij} = 0, 1\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1\nx_{11} y_{11}\nx_{12} y_{12}\n:\nx_{1A_1} y_{1A_1}\nA_2\nx_{21} y_{21}\nx_{22} y_{22}\n:\nx_{2A_2} y_{2A_2}\n:\nA_N\nx_{N1} y_{N1}\nx_{N2} y_{N2}\n:\nx_{NA_N} y_{NA_N}\n\nOutput\n\nPrint the maximum possible number of honest persons among the N people.\n\nSample Input 1\n\n3\n1\n2 1\n1\n1 1\n1\n2 0\n\nSample Output 1\n\n2\n\nIf Person 1 and Person 2 are honest and Person 3 is unkind, we have two honest persons without inconsistencies, which is the maximum possible number of honest persons.\n\nSample Input 2\n\n3\n2\n2 1\n3 0\n2\n3 1\n1 0\n2\n1 1\n2 0\n\nSample Output 2\n\n0\n\nAssuming that one or more of them are honest immediately leads to a contradiction.\n\nSample Input 3\n\n2\n1\n2 0\n1\n1 0\n\nSample Output 3\n\n1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 999, "cpu_time_ms": 20, "memory_kb": 6912}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s128036937", "group_id": "codeNet:p02838", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nconst long long MOD = 1e9 + 7;\n\n#include <math.h>\n#define PI 3.14159265358979323846264338327950L\n\nlong long gcd(long long a, long long b) {\n    if (a == 0)\n        return b;\n    return gcd(b % a, a);\n}\nlong long lcm(long long a, long long b) {\n    return (a * b) / gcd(a, b);\n}\n\nint main() {\n    int n;\n    cin >> n;\n    vector<long long> a(n);\n    for (int i = 0; i < n; i++) cin >> a[i];\n    vector<int> zerobit(61);\n    vector<int> onebit(61);\n    for (int i = 0; i < n; i++) {\n        for (long long bit = 0; bit <= 60; bit++) {\n            if (a[i] & (1ll << bit)) onebit[bit]++;\n            else zerobit[bit]++;\n        }\n    }\n    long long sum = 0;\n    for (long long bit = 0; bit <= 60; bit++) {\n        sum += (((long long)zerobit[bit] * onebit[bit]) % MOD) * (1ll << bit); sum %= MOD;\n    }\n    cout << sum;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1593249859, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02838.html", "problem_id": "p02838", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02838/input.txt", "sample_output_relpath": "derived/input_output/data/p02838/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02838/C++/s128036937.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s128036937", "user_id": "u221780420"}, "prompt_components": {"gold_output": "6\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nconst long long MOD = 1e9 + 7;\n\n#include <math.h>\n#define PI 3.14159265358979323846264338327950L\n\nlong long gcd(long long a, long long b) {\n    if (a == 0)\n        return b;\n    return gcd(b % a, a);\n}\nlong long lcm(long long a, long long b) {\n    return (a * b) / gcd(a, b);\n}\n\nint main() {\n    int n;\n    cin >> n;\n    vector<long long> a(n);\n    for (int i = 0; i < n; i++) cin >> a[i];\n    vector<int> zerobit(61);\n    vector<int> onebit(61);\n    for (int i = 0; i < n; i++) {\n        for (long long bit = 0; bit <= 60; bit++) {\n            if (a[i] & (1ll << bit)) onebit[bit]++;\n            else zerobit[bit]++;\n        }\n    }\n    long long sum = 0;\n    for (long long bit = 0; bit <= 60; bit++) {\n        sum += (((long long)zerobit[bit] * onebit[bit]) % MOD) * (1ll << bit); sum %= MOD;\n    }\n    cout << sum;\n    return 0;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nWe have N integers. The i-th integer is A_i.\n\nFind \\sum_{i=1}^{N-1}\\sum_{j=i+1}^{N} (A_i \\mbox{ XOR } A_j), modulo (10^9+7).\n\nWhat is \\mbox{ XOR }?\n\nThe XOR of integers A and B, A \\mbox{ XOR } B, is defined as follows:\n\nWhen A \\mbox{ XOR } B is written in base two, the digit in the 2^k's place (k \\geq 0) is 1 if either A or B, but not both, has 1 in the 2^k's place, and 0 otherwise.\n\nFor example, 3 \\mbox{ XOR } 5 = 6. (In base two: 011 \\mbox{ XOR } 101 = 110.)\n\nConstraints\n\n2 \\leq N \\leq 3 \\times 10^5\n\n0 \\leq A_i < 2^{60}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the value \\sum_{i=1}^{N-1}\\sum_{j=i+1}^{N} (A_i \\mbox{ XOR } A_j), modulo (10^9+7).\n\nSample Input 1\n\n3\n1 2 3\n\nSample Output 1\n\n6\n\nWe have (1\\mbox{ XOR } 2)+(1\\mbox{ XOR } 3)+(2\\mbox{ XOR } 3)=3+2+1=6.\n\nSample Input 2\n\n10\n3 1 4 1 5 9 2 6 5 3\n\nSample Output 2\n\n237\n\nSample Input 3\n\n10\n3 14 159 2653 58979 323846 2643383 27950288 419716939 9375105820\n\nSample Output 3\n\n103715602\n\nPrint the sum modulo (10^9+7).", "sample_input": "3\n1 2 3\n"}, "reference_outputs": ["6\n"], "source_document_id": "p02838", "source_text": "Score : 400 points\n\nProblem Statement\n\nWe have N integers. The i-th integer is A_i.\n\nFind \\sum_{i=1}^{N-1}\\sum_{j=i+1}^{N} (A_i \\mbox{ XOR } A_j), modulo (10^9+7).\n\nWhat is \\mbox{ XOR }?\n\nThe XOR of integers A and B, A \\mbox{ XOR } B, is defined as follows:\n\nWhen A \\mbox{ XOR } B is written in base two, the digit in the 2^k's place (k \\geq 0) is 1 if either A or B, but not both, has 1 in the 2^k's place, and 0 otherwise.\n\nFor example, 3 \\mbox{ XOR } 5 = 6. (In base two: 011 \\mbox{ XOR } 101 = 110.)\n\nConstraints\n\n2 \\leq N \\leq 3 \\times 10^5\n\n0 \\leq A_i < 2^{60}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the value \\sum_{i=1}^{N-1}\\sum_{j=i+1}^{N} (A_i \\mbox{ XOR } A_j), modulo (10^9+7).\n\nSample Input 1\n\n3\n1 2 3\n\nSample Output 1\n\n6\n\nWe have (1\\mbox{ XOR } 2)+(1\\mbox{ XOR } 3)+(2\\mbox{ XOR } 3)=3+2+1=6.\n\nSample Input 2\n\n10\n3 1 4 1 5 9 2 6 5 3\n\nSample Output 2\n\n237\n\nSample Input 3\n\n10\n3 14 159 2653 58979 323846 2643383 27950288 419716939 9375105820\n\nSample Output 3\n\n103715602\n\nPrint the sum modulo (10^9+7).", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 880, "cpu_time_ms": 201, "memory_kb": 5624}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s578893699", "group_id": "codeNet:p02839", "input_text": "#include \"bits/stdc++.h\"\n#define in std::cin\n#define out std::cout\n#define rep(i,N) for(LL i=0;i<N;++i)\ntypedef long long int LL;\n\nLL H, W;\nstd::vector<std::vector<LL>>A, B;\nstd::vector<std::vector<std::vector<int>>>memo;\n\nbool dp(LL i, LL j, LL k)\n{\n\tif (i < 0 || j < 0) return false;\n\tif (i == 0 && j == 0) return k == std::abs(A[0][0] - B[0][0]);\n\tif (memo[i][j][k] != -1) return memo[i][j][k];\n\tLL d = std::abs(A[i][j] - B[i][j]);\n\tLL m1 = std::abs(k - d), m2 = k + d;\n\tbool res1 = dp(i - 1, j, m1), res2 = dp(i - 1, j, m2), res3 = dp(i, j - 1, m1), res4 = dp(i, j - 1, m2);\n\treturn memo[i][j][k] = (res1 || res2 || res3 || res4);\n}\n\nint main()\n{\n\tin >> H >> W;\n\tA.resize(H, std::vector<LL>(W));\n\tB.resize(H, std::vector<LL>(W));\n\trep(i, H) rep(j, W) in >> A[i][j];\n\trep(i, H) rep(j, W) in >> B[i][j];\n\n\tmemo.resize(H, std::vector<std::vector<int>>(W, std::vector<int>((H + W - 1) * 80, -1)));\n\trep(k, (H + W - 1) * 80)\n\t{\n\t\tif (dp(H - 1, W - 1, k))\n\t\t{\n\t\t\tout << k << std::endl;\n\t\t\treturn 0;\n\t\t}\n\t}\n}\n", "language": "C++", "metadata": {"date": 1576547931, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02839.html", "problem_id": "p02839", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02839/input.txt", "sample_output_relpath": "derived/input_output/data/p02839/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02839/C++/s578893699.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s578893699", "user_id": "u660613376"}, "prompt_components": {"gold_output": "0\n", "input_to_evaluate": "#include \"bits/stdc++.h\"\n#define in std::cin\n#define out std::cout\n#define rep(i,N) for(LL i=0;i<N;++i)\ntypedef long long int LL;\n\nLL H, W;\nstd::vector<std::vector<LL>>A, B;\nstd::vector<std::vector<std::vector<int>>>memo;\n\nbool dp(LL i, LL j, LL k)\n{\n\tif (i < 0 || j < 0) return false;\n\tif (i == 0 && j == 0) return k == std::abs(A[0][0] - B[0][0]);\n\tif (memo[i][j][k] != -1) return memo[i][j][k];\n\tLL d = std::abs(A[i][j] - B[i][j]);\n\tLL m1 = std::abs(k - d), m2 = k + d;\n\tbool res1 = dp(i - 1, j, m1), res2 = dp(i - 1, j, m2), res3 = dp(i, j - 1, m1), res4 = dp(i, j - 1, m2);\n\treturn memo[i][j][k] = (res1 || res2 || res3 || res4);\n}\n\nint main()\n{\n\tin >> H >> W;\n\tA.resize(H, std::vector<LL>(W));\n\tB.resize(H, std::vector<LL>(W));\n\trep(i, H) rep(j, W) in >> A[i][j];\n\trep(i, H) rep(j, W) in >> B[i][j];\n\n\tmemo.resize(H, std::vector<std::vector<int>>(W, std::vector<int>((H + W - 1) * 80, -1)));\n\trep(k, (H + W - 1) * 80)\n\t{\n\t\tif (dp(H - 1, W - 1, k))\n\t\t{\n\t\t\tout << k << std::endl;\n\t\t\treturn 0;\n\t\t}\n\t}\n}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nWe have a grid with H horizontal rows and W vertical columns. Let (i,j) denote the square at the i-th row from the top and the j-th column from the left.\n\nThe square (i, j) has two numbers A_{ij} and B_{ij} written on it.\n\nFirst, for each square, Takahashi paints one of the written numbers red and the other blue.\n\nThen, he travels from the square (1, 1) to the square (H, W). In one move, he can move from a square (i, j) to the square (i+1, j) or the square (i, j+1). He must not leave the grid.\n\nLet the unbalancedness be the absolute difference of the sum of red numbers and the sum of blue numbers written on the squares along Takahashi's path, including the squares (1, 1) and (H, W).\n\nTakahashi wants to make the unbalancedness as small as possible by appropriately painting the grid and traveling on it.\n\nFind the minimum unbalancedness possible.\n\nConstraints\n\n2 \\leq H \\leq 80\n\n2 \\leq W \\leq 80\n\n0 \\leq A_{ij} \\leq 80\n\n0 \\leq B_{ij} \\leq 80\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W\nA_{11} A_{12} \\ldots A_{1W}\n:\nA_{H1} A_{H2} \\ldots A_{HW}\nB_{11} B_{12} \\ldots B_{1W}\n:\nB_{H1} B_{H2} \\ldots B_{HW}\n\nOutput\n\nPrint the minimum unbalancedness possible.\n\nSample Input 1\n\n2 2\n1 2\n3 4\n3 4\n2 1\n\nSample Output 1\n\n0\n\nBy painting the grid and traveling on it as shown in the figure below, the sum of red numbers and the sum of blue numbers are 3+3+1=7 and 1+2+4=7, respectively, for the unbalancedness of 0.\n\nSample Input 2\n\n2 3\n1 10 80\n80 10 1\n1 2 3\n4 5 6\n\nSample Output 2\n\n2", "sample_input": "2 2\n1 2\n3 4\n3 4\n2 1\n"}, "reference_outputs": ["0\n"], "source_document_id": "p02839", "source_text": "Score : 500 points\n\nProblem Statement\n\nWe have a grid with H horizontal rows and W vertical columns. Let (i,j) denote the square at the i-th row from the top and the j-th column from the left.\n\nThe square (i, j) has two numbers A_{ij} and B_{ij} written on it.\n\nFirst, for each square, Takahashi paints one of the written numbers red and the other blue.\n\nThen, he travels from the square (1, 1) to the square (H, W). In one move, he can move from a square (i, j) to the square (i+1, j) or the square (i, j+1). He must not leave the grid.\n\nLet the unbalancedness be the absolute difference of the sum of red numbers and the sum of blue numbers written on the squares along Takahashi's path, including the squares (1, 1) and (H, W).\n\nTakahashi wants to make the unbalancedness as small as possible by appropriately painting the grid and traveling on it.\n\nFind the minimum unbalancedness possible.\n\nConstraints\n\n2 \\leq H \\leq 80\n\n2 \\leq W \\leq 80\n\n0 \\leq A_{ij} \\leq 80\n\n0 \\leq B_{ij} \\leq 80\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W\nA_{11} A_{12} \\ldots A_{1W}\n:\nA_{H1} A_{H2} \\ldots A_{HW}\nB_{11} B_{12} \\ldots B_{1W}\n:\nB_{H1} B_{H2} \\ldots B_{HW}\n\nOutput\n\nPrint the minimum unbalancedness possible.\n\nSample Input 1\n\n2 2\n1 2\n3 4\n3 4\n2 1\n\nSample Output 1\n\n0\n\nBy painting the grid and traveling on it as shown in the figure below, the sum of red numbers and the sum of blue numbers are 3+3+1=7 and 1+2+4=7, respectively, for the unbalancedness of 0.\n\nSample Input 2\n\n2 3\n1 10 80\n80 10 1\n1 2 3\n4 5 6\n\nSample Output 2\n\n2", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1006, "cpu_time_ms": 2123, "memory_kb": 324736}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s870728357", "group_id": "codeNet:p02841", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\n\nint main() {\n    int n;\n    cin >> n;\n    int ans;\n    ans = n/2;\n    double res;\n    int i = 0;\n    for(i = 0;i < n;i++) {\n       res = i * 1.08;\n       if(int(res) == n) {\n           cout << i << '\\n';\n           return 0;\n       }\n    }\n    cout << \":(\" << '\\n';\n}\n", "language": "C++", "metadata": {"date": 1575253442, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02841.html", "problem_id": "p02841", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02841/input.txt", "sample_output_relpath": "derived/input_output/data/p02841/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02841/C++/s870728357.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s870728357", "user_id": "u017829818"}, "prompt_components": {"gold_output": "0\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\n\nint main() {\n    int n;\n    cin >> n;\n    int ans;\n    ans = n/2;\n    double res;\n    int i = 0;\n    for(i = 0;i < n;i++) {\n       res = i * 1.08;\n       if(int(res) == n) {\n           cout << i << '\\n';\n           return 0;\n       }\n    }\n    cout << \":(\" << '\\n';\n}\n", "problem_context": "Score: 100 points\n\nProblem Statement\n\nIn this problem, a date is written as Y-M-D. For example, 2019-11-30 means November 30, 2019.\n\nIntegers M_1, D_1, M_2, and D_2 will be given as input.\n\nIt is known that the date 2019-M_2-D_2 follows 2019-M_1-D_1.\n\nDetermine whether the date 2019-M_1-D_1 is the last day of a month.\n\nConstraints\n\nBoth 2019-M_1-D_1 and 2019-M_2-D_2 are valid dates in the Gregorian calendar.\n\nThe date 2019-M_2-D_2 follows 2019-M_1-D_1.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nM_1 D_1\nM_2 D_2\n\nOutput\n\nIf the date 2019-M_1-D_1 is the last day of a month, print 1; otherwise, print 0.\n\nSample Input 1\n\n11 16\n11 17\n\nSample Output 1\n\n0\n\nNovember 16 is not the last day of a month.\n\nSample Input 2\n\n11 30\n12 1\n\nSample Output 2\n\n1\n\nNovember 30 is the last day of November.", "sample_input": "11 16\n11 17\n"}, "reference_outputs": ["0\n"], "source_document_id": "p02841", "source_text": "Score: 100 points\n\nProblem Statement\n\nIn this problem, a date is written as Y-M-D. For example, 2019-11-30 means November 30, 2019.\n\nIntegers M_1, D_1, M_2, and D_2 will be given as input.\n\nIt is known that the date 2019-M_2-D_2 follows 2019-M_1-D_1.\n\nDetermine whether the date 2019-M_1-D_1 is the last day of a month.\n\nConstraints\n\nBoth 2019-M_1-D_1 and 2019-M_2-D_2 are valid dates in the Gregorian calendar.\n\nThe date 2019-M_2-D_2 follows 2019-M_1-D_1.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nM_1 D_1\nM_2 D_2\n\nOutput\n\nIf the date 2019-M_1-D_1 is the last day of a month, print 1; otherwise, print 0.\n\nSample Input 1\n\n11 16\n11 17\n\nSample Output 1\n\n0\n\nNovember 16 is not the last day of a month.\n\nSample Input 2\n\n11 30\n12 1\n\nSample Output 2\n\n1\n\nNovember 30 is the last day of November.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 316, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s215908622", "group_id": "codeNet:p02842", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  int N; cin >> N;\n  for(int i=1; i<=N; i++){\n    if(i*108/100==N){\n      cout << i << endl;\n      return 0;\n    }\n  }\n  cout << \":(\" << endl;\n}", "language": "C++", "metadata": {"date": 1588378979, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02842.html", "problem_id": "p02842", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02842/input.txt", "sample_output_relpath": "derived/input_output/data/p02842/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02842/C++/s215908622.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s215908622", "user_id": "u816742421"}, "prompt_components": {"gold_output": "400\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  int N; cin >> N;\n  for(int i=1; i<=N; i++){\n    if(i*108/100==N){\n      cout << i << endl;\n      return 0;\n    }\n  }\n  cout << \":(\" << endl;\n}", "problem_context": "Score: 200 points\n\nProblem Statement\n\nTakahashi bought a piece of apple pie at ABC Confiserie. According to his memory, he paid N yen (the currency of Japan) for it.\n\nThe consumption tax rate for foods in this shop is 8 percent. That is, to buy an apple pie priced at X yen before tax, you have to pay X \\times 1.08 yen (rounded down to the nearest integer).\n\nTakahashi forgot the price of his apple pie before tax, X, and wants to know it again. Write a program that takes N as input and finds X. We assume X is an integer.\n\nIf there are multiple possible values for X, find any one of them. Also, Takahashi's memory of N, the amount he paid, may be incorrect. If no value could be X, report that fact.\n\nConstraints\n\n1 \\leq N \\leq 50000\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nIf there are values that could be X, the price of the apple pie before tax, print any one of them.\n\nIf there are multiple such values, printing any one of them will be accepted.\n\nIf no value could be X, print :(.\n\nSample Input 1\n\n432\n\nSample Output 1\n\n400\n\nIf the apple pie is priced at 400 yen before tax, you have to pay 400 \\times 1.08 = 432 yen to buy one.\n\nOtherwise, the amount you have to pay will not be 432 yen.\n\nSample Input 2\n\n1079\n\nSample Output 2\n\n:(\n\nThere is no possible price before tax for which you have to pay 1079 yen with tax.\n\nSample Input 3\n\n1001\n\nSample Output 3\n\n927\n\nIf the apple pie is priced 927 yen before tax, by rounding down 927 \\times 1.08 = 1001.16, you have to pay 1001 yen.", "sample_input": "432\n"}, "reference_outputs": ["400\n"], "source_document_id": "p02842", "source_text": "Score: 200 points\n\nProblem Statement\n\nTakahashi bought a piece of apple pie at ABC Confiserie. According to his memory, he paid N yen (the currency of Japan) for it.\n\nThe consumption tax rate for foods in this shop is 8 percent. That is, to buy an apple pie priced at X yen before tax, you have to pay X \\times 1.08 yen (rounded down to the nearest integer).\n\nTakahashi forgot the price of his apple pie before tax, X, and wants to know it again. Write a program that takes N as input and finds X. We assume X is an integer.\n\nIf there are multiple possible values for X, find any one of them. Also, Takahashi's memory of N, the amount he paid, may be incorrect. If no value could be X, report that fact.\n\nConstraints\n\n1 \\leq N \\leq 50000\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nIf there are values that could be X, the price of the apple pie before tax, print any one of them.\n\nIf there are multiple such values, printing any one of them will be accepted.\n\nIf no value could be X, print :(.\n\nSample Input 1\n\n432\n\nSample Output 1\n\n400\n\nIf the apple pie is priced at 400 yen before tax, you have to pay 400 \\times 1.08 = 432 yen to buy one.\n\nOtherwise, the amount you have to pay will not be 432 yen.\n\nSample Input 2\n\n1079\n\nSample Output 2\n\n:(\n\nThere is no possible price before tax for which you have to pay 1079 yen with tax.\n\nSample Input 3\n\n1001\n\nSample Output 3\n\n927\n\nIf the apple pie is priced 927 yen before tax, by rounding down 927 \\times 1.08 = 1001.16, you have to pay 1001 yen.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 203, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s079594275", "group_id": "codeNet:p02842", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n    \nint main() {\n    int N;\n    cin>>N;\n    int X=(N+1)*100/108;\n    if (X*108/100==N) cout<<X<<endl;\n    else cout<<\":(\"<<endl;\n}", "language": "C++", "metadata": {"date": 1586668468, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02842.html", "problem_id": "p02842", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02842/input.txt", "sample_output_relpath": "derived/input_output/data/p02842/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02842/C++/s079594275.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s079594275", "user_id": "u045238009"}, "prompt_components": {"gold_output": "400\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n    \nint main() {\n    int N;\n    cin>>N;\n    int X=(N+1)*100/108;\n    if (X*108/100==N) cout<<X<<endl;\n    else cout<<\":(\"<<endl;\n}", "problem_context": "Score: 200 points\n\nProblem Statement\n\nTakahashi bought a piece of apple pie at ABC Confiserie. According to his memory, he paid N yen (the currency of Japan) for it.\n\nThe consumption tax rate for foods in this shop is 8 percent. That is, to buy an apple pie priced at X yen before tax, you have to pay X \\times 1.08 yen (rounded down to the nearest integer).\n\nTakahashi forgot the price of his apple pie before tax, X, and wants to know it again. Write a program that takes N as input and finds X. We assume X is an integer.\n\nIf there are multiple possible values for X, find any one of them. Also, Takahashi's memory of N, the amount he paid, may be incorrect. If no value could be X, report that fact.\n\nConstraints\n\n1 \\leq N \\leq 50000\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nIf there are values that could be X, the price of the apple pie before tax, print any one of them.\n\nIf there are multiple such values, printing any one of them will be accepted.\n\nIf no value could be X, print :(.\n\nSample Input 1\n\n432\n\nSample Output 1\n\n400\n\nIf the apple pie is priced at 400 yen before tax, you have to pay 400 \\times 1.08 = 432 yen to buy one.\n\nOtherwise, the amount you have to pay will not be 432 yen.\n\nSample Input 2\n\n1079\n\nSample Output 2\n\n:(\n\nThere is no possible price before tax for which you have to pay 1079 yen with tax.\n\nSample Input 3\n\n1001\n\nSample Output 3\n\n927\n\nIf the apple pie is priced 927 yen before tax, by rounding down 927 \\times 1.08 = 1001.16, you have to pay 1001 yen.", "sample_input": "432\n"}, "reference_outputs": ["400\n"], "source_document_id": "p02842", "source_text": "Score: 200 points\n\nProblem Statement\n\nTakahashi bought a piece of apple pie at ABC Confiserie. According to his memory, he paid N yen (the currency of Japan) for it.\n\nThe consumption tax rate for foods in this shop is 8 percent. That is, to buy an apple pie priced at X yen before tax, you have to pay X \\times 1.08 yen (rounded down to the nearest integer).\n\nTakahashi forgot the price of his apple pie before tax, X, and wants to know it again. Write a program that takes N as input and finds X. We assume X is an integer.\n\nIf there are multiple possible values for X, find any one of them. Also, Takahashi's memory of N, the amount he paid, may be incorrect. If no value could be X, report that fact.\n\nConstraints\n\n1 \\leq N \\leq 50000\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nIf there are values that could be X, the price of the apple pie before tax, print any one of them.\n\nIf there are multiple such values, printing any one of them will be accepted.\n\nIf no value could be X, print :(.\n\nSample Input 1\n\n432\n\nSample Output 1\n\n400\n\nIf the apple pie is priced at 400 yen before tax, you have to pay 400 \\times 1.08 = 432 yen to buy one.\n\nOtherwise, the amount you have to pay will not be 432 yen.\n\nSample Input 2\n\n1079\n\nSample Output 2\n\n:(\n\nThere is no possible price before tax for which you have to pay 1079 yen with tax.\n\nSample Input 3\n\n1001\n\nSample Output 3\n\n927\n\nIf the apple pie is priced 927 yen before tax, by rounding down 927 \\times 1.08 = 1001.16, you have to pay 1001 yen.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 177, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s418235510", "group_id": "codeNet:p02842", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  int n, a;\n  for(int i = 0; i < n + 1; i++){\n    a = i * 1.08;\n    if(a == n){\n      cout << i << endl;\n      return 0;\n    }\n  }\n  cout << \":(\" << endl;\n}", "language": "C++", "metadata": {"date": 1586337291, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02842.html", "problem_id": "p02842", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02842/input.txt", "sample_output_relpath": "derived/input_output/data/p02842/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02842/C++/s418235510.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s418235510", "user_id": "u917049698"}, "prompt_components": {"gold_output": "400\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  int n, a;\n  for(int i = 0; i < n + 1; i++){\n    a = i * 1.08;\n    if(a == n){\n      cout << i << endl;\n      return 0;\n    }\n  }\n  cout << \":(\" << endl;\n}", "problem_context": "Score: 200 points\n\nProblem Statement\n\nTakahashi bought a piece of apple pie at ABC Confiserie. According to his memory, he paid N yen (the currency of Japan) for it.\n\nThe consumption tax rate for foods in this shop is 8 percent. That is, to buy an apple pie priced at X yen before tax, you have to pay X \\times 1.08 yen (rounded down to the nearest integer).\n\nTakahashi forgot the price of his apple pie before tax, X, and wants to know it again. Write a program that takes N as input and finds X. We assume X is an integer.\n\nIf there are multiple possible values for X, find any one of them. Also, Takahashi's memory of N, the amount he paid, may be incorrect. If no value could be X, report that fact.\n\nConstraints\n\n1 \\leq N \\leq 50000\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nIf there are values that could be X, the price of the apple pie before tax, print any one of them.\n\nIf there are multiple such values, printing any one of them will be accepted.\n\nIf no value could be X, print :(.\n\nSample Input 1\n\n432\n\nSample Output 1\n\n400\n\nIf the apple pie is priced at 400 yen before tax, you have to pay 400 \\times 1.08 = 432 yen to buy one.\n\nOtherwise, the amount you have to pay will not be 432 yen.\n\nSample Input 2\n\n1079\n\nSample Output 2\n\n:(\n\nThere is no possible price before tax for which you have to pay 1079 yen with tax.\n\nSample Input 3\n\n1001\n\nSample Output 3\n\n927\n\nIf the apple pie is priced 927 yen before tax, by rounding down 927 \\times 1.08 = 1001.16, you have to pay 1001 yen.", "sample_input": "432\n"}, "reference_outputs": ["400\n"], "source_document_id": "p02842", "source_text": "Score: 200 points\n\nProblem Statement\n\nTakahashi bought a piece of apple pie at ABC Confiserie. According to his memory, he paid N yen (the currency of Japan) for it.\n\nThe consumption tax rate for foods in this shop is 8 percent. That is, to buy an apple pie priced at X yen before tax, you have to pay X \\times 1.08 yen (rounded down to the nearest integer).\n\nTakahashi forgot the price of his apple pie before tax, X, and wants to know it again. Write a program that takes N as input and finds X. We assume X is an integer.\n\nIf there are multiple possible values for X, find any one of them. Also, Takahashi's memory of N, the amount he paid, may be incorrect. If no value could be X, report that fact.\n\nConstraints\n\n1 \\leq N \\leq 50000\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nIf there are values that could be X, the price of the apple pie before tax, print any one of them.\n\nIf there are multiple such values, printing any one of them will be accepted.\n\nIf no value could be X, print :(.\n\nSample Input 1\n\n432\n\nSample Output 1\n\n400\n\nIf the apple pie is priced at 400 yen before tax, you have to pay 400 \\times 1.08 = 432 yen to buy one.\n\nOtherwise, the amount you have to pay will not be 432 yen.\n\nSample Input 2\n\n1079\n\nSample Output 2\n\n:(\n\nThere is no possible price before tax for which you have to pay 1079 yen with tax.\n\nSample Input 3\n\n1001\n\nSample Output 3\n\n927\n\nIf the apple pie is priced 927 yen before tax, by rounding down 927 \\times 1.08 = 1001.16, you have to pay 1001 yen.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 215, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s870757945", "group_id": "codeNet:p02843", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing P = pair<ll, ll>;\n\nint main() {\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n\n    int X;\n    cin >> X;\n    cout << ((X % 100 <= X / 100 * 5) ? 1 : 0) << endl;\n\n    return 0;\n}", "language": "C++", "metadata": {"date": 1589148076, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02843.html", "problem_id": "p02843", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02843/input.txt", "sample_output_relpath": "derived/input_output/data/p02843/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02843/C++/s870757945.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s870757945", "user_id": "u433685759"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing P = pair<ll, ll>;\n\nint main() {\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n\n    int X;\n    cin >> X;\n    cout << ((X % 100 <= X / 100 * 5) ? 1 : 0) << endl;\n\n    return 0;\n}", "problem_context": "Score: 300 points\n\nProblem Statement\n\nAtCoder Mart sells 1000000 of each of the six items below:\n\nRiceballs, priced at 100 yen (the currency of Japan) each\n\nSandwiches, priced at 101 yen each\n\nCookies, priced at 102 yen each\n\nCakes, priced at 103 yen each\n\nCandies, priced at 104 yen each\n\nComputers, priced at 105 yen each\n\nTakahashi wants to buy some of them that cost exactly X yen in total.\nDetermine whether this is possible.\n\n(Ignore consumption tax.)\n\nConstraints\n\n1 \\leq X \\leq 100000\n\nX is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nIf it is possible to buy some set of items that cost exactly X yen in total, print 1; otherwise, print 0.\n\nSample Input 1\n\n615\n\nSample Output 1\n\n1\n\nFor example, we can buy one of each kind of item, which will cost 100+101+102+103+104+105=615 yen in total.\n\nSample Input 2\n\n217\n\nSample Output 2\n\n0\n\nNo set of items costs 217 yen in total.", "sample_input": "615\n"}, "reference_outputs": ["1\n"], "source_document_id": "p02843", "source_text": "Score: 300 points\n\nProblem Statement\n\nAtCoder Mart sells 1000000 of each of the six items below:\n\nRiceballs, priced at 100 yen (the currency of Japan) each\n\nSandwiches, priced at 101 yen each\n\nCookies, priced at 102 yen each\n\nCakes, priced at 103 yen each\n\nCandies, priced at 104 yen each\n\nComputers, priced at 105 yen each\n\nTakahashi wants to buy some of them that cost exactly X yen in total.\nDetermine whether this is possible.\n\n(Ignore consumption tax.)\n\nConstraints\n\n1 \\leq X \\leq 100000\n\nX is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nIf it is possible to buy some set of items that cost exactly X yen in total, print 1; otherwise, print 0.\n\nSample Input 1\n\n615\n\nSample Output 1\n\n1\n\nFor example, we can buy one of each kind of item, which will cost 100+101+102+103+104+105=615 yen in total.\n\nSample Input 2\n\n217\n\nSample Output 2\n\n0\n\nNo set of items costs 217 yen in total.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 253, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s174479375", "group_id": "codeNet:p02844", "input_text": "#include <iostream>\n#include <iomanip>\n#include<math.h>\n#include<list>\n#include <algorithm>\n#include<set>\n#include<vector>\n#include<math.h>\n#include<map>\n#include<string>\n#include <numeric>\n#include <queue>\n#include <sstream>\n\nusing namespace std;\nusing ll = long long;\nusing vll = vector<long long>;\nusing sll = set<long long>;\n\ntemplate<typename T>\nT gcd(T a, T b) { return b ? gcd(b, a % b) : a; }\ntemplate<typename T>\nT lcm(T a, T b) { return a / gcd(a, b) * b; }\n\ntemplate<typename T>\nmap<T, T> primeFactor(T n) {\n\tmap<T, T> res;\n\tfor (T i = 2; i * i <= n; ++i) {\n\t\twhile (n % i == 0) {\n\t\t\tres[i] ++;\n\t\t\tn /= i;\n\t\t}\n\t}\n\tif (n != 1) res[n] = 1;\n\treturn res;\n}\n\ntemplate<typename T>\nbool IsPrimeNumber(T num)\n{\n\tif (num <= 2) return true;\n\telse if (num % 2 == 0) return false;\n\n\tdouble sqrtNum = sqrt(num);\n\tfor (int i = 3; i <= sqrtNum; i += 2)\n\t{\n\t\tif (num % i == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t}\n\n\treturn true;\n}\n\nlong long modinv(long long a, long long m) {\n\tlong long b = m, u = 1, v = 0;\n\twhile (b) {\n\t\tlong long t = a / b;\n\t\ta -= t * b; swap(a, b);\n\t\tu -= t * v; swap(u, v);\n\t}\n\tu %= m;\n\tif (u < 0) u += m;\n\treturn u;\n}\n\n\n#define in(x) cin >> x\n#define out(x) cout << x\n#define outn(x) cout << x << '\\n'\n#define outs(x) cout << x << ' '\n#define rep(i,s,e) for(ll i=s;i<e;i++)\n#define repeq(i,s,e) for(ll i=s;i<=e;i++)\n\n\nint main() {\n\tll n;\n\tstring s, si, sj, sk;\n\tin(n);\n\tin(s);\n\n\tmap<string, ll> dic1,dic2,dic3,dic;\n\n\n\trep(i, 0, s.size()) {\n\t\tsi = s.substr(i, 1);\n\t\tif (dic3[si] > 2) {\n\t\t\ts.erase(s.begin() + i);\n\t\t\ti--;\n\t\t}\n\t\telse {\n\t\t\tdic3[si]++;\n\t\t}\n\t}\n\n\tn = s.size();\n\trep(i, 0, n - 2) {\n\t\tsi = s.substr(i, 1);\n\t\tif (dic1[si] == 0) {\n\t\t\tdic2.clear();\n\t\t\trep(j, i + 1, n - 1) {\n\t\t\t\tsj = s.substr(j, 1);\n\t\t\t\tif (dic2[sj] == 0) {\n\t\t\t\t\trep(k, j + 1, n) {\n\t\t\t\t\t\tsk = s.substr(k, 1);\n\t\t\t\t\t\tdic[si + sj + sk]++;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tdic2[sj]++;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\telse {\n\t\t\tdic1[si]++;\n\t\t}\n\t}\n\n\toutn(dic.size());\n\treturn 0;\n\n\n}\n", "language": "C++", "metadata": {"date": 1575257284, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02844.html", "problem_id": "p02844", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02844/input.txt", "sample_output_relpath": "derived/input_output/data/p02844/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02844/C++/s174479375.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s174479375", "user_id": "u757628628"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <iostream>\n#include <iomanip>\n#include<math.h>\n#include<list>\n#include <algorithm>\n#include<set>\n#include<vector>\n#include<math.h>\n#include<map>\n#include<string>\n#include <numeric>\n#include <queue>\n#include <sstream>\n\nusing namespace std;\nusing ll = long long;\nusing vll = vector<long long>;\nusing sll = set<long long>;\n\ntemplate<typename T>\nT gcd(T a, T b) { return b ? gcd(b, a % b) : a; }\ntemplate<typename T>\nT lcm(T a, T b) { return a / gcd(a, b) * b; }\n\ntemplate<typename T>\nmap<T, T> primeFactor(T n) {\n\tmap<T, T> res;\n\tfor (T i = 2; i * i <= n; ++i) {\n\t\twhile (n % i == 0) {\n\t\t\tres[i] ++;\n\t\t\tn /= i;\n\t\t}\n\t}\n\tif (n != 1) res[n] = 1;\n\treturn res;\n}\n\ntemplate<typename T>\nbool IsPrimeNumber(T num)\n{\n\tif (num <= 2) return true;\n\telse if (num % 2 == 0) return false;\n\n\tdouble sqrtNum = sqrt(num);\n\tfor (int i = 3; i <= sqrtNum; i += 2)\n\t{\n\t\tif (num % i == 0)\n\t\t{\n\t\t\treturn false;\n\t\t}\n\t}\n\n\treturn true;\n}\n\nlong long modinv(long long a, long long m) {\n\tlong long b = m, u = 1, v = 0;\n\twhile (b) {\n\t\tlong long t = a / b;\n\t\ta -= t * b; swap(a, b);\n\t\tu -= t * v; swap(u, v);\n\t}\n\tu %= m;\n\tif (u < 0) u += m;\n\treturn u;\n}\n\n\n#define in(x) cin >> x\n#define out(x) cout << x\n#define outn(x) cout << x << '\\n'\n#define outs(x) cout << x << ' '\n#define rep(i,s,e) for(ll i=s;i<e;i++)\n#define repeq(i,s,e) for(ll i=s;i<=e;i++)\n\n\nint main() {\n\tll n;\n\tstring s, si, sj, sk;\n\tin(n);\n\tin(s);\n\n\tmap<string, ll> dic1,dic2,dic3,dic;\n\n\n\trep(i, 0, s.size()) {\n\t\tsi = s.substr(i, 1);\n\t\tif (dic3[si] > 2) {\n\t\t\ts.erase(s.begin() + i);\n\t\t\ti--;\n\t\t}\n\t\telse {\n\t\t\tdic3[si]++;\n\t\t}\n\t}\n\n\tn = s.size();\n\trep(i, 0, n - 2) {\n\t\tsi = s.substr(i, 1);\n\t\tif (dic1[si] == 0) {\n\t\t\tdic2.clear();\n\t\t\trep(j, i + 1, n - 1) {\n\t\t\t\tsj = s.substr(j, 1);\n\t\t\t\tif (dic2[sj] == 0) {\n\t\t\t\t\trep(k, j + 1, n) {\n\t\t\t\t\t\tsk = s.substr(k, 1);\n\t\t\t\t\t\tdic[si + sj + sk]++;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\telse {\n\t\t\t\t\tdic2[sj]++;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\telse {\n\t\t\tdic1[si]++;\n\t\t}\n\t}\n\n\toutn(dic.size());\n\treturn 0;\n\n\n}\n", "problem_context": "Score: 400 points\n\nProblem Statement\n\nAtCoder Inc. has decided to lock the door of its office with a 3-digit PIN code.\n\nThe company has an N-digit lucky number, S. Takahashi, the president, will erase N-3 digits from S and concatenate the remaining 3 digits without changing the order to set the PIN code.\n\nHow many different PIN codes can he set this way?\n\nBoth the lucky number and the PIN code may begin with a 0.\n\nConstraints\n\n4 \\leq N \\leq 30000\n\nS is a string of length N consisting of digits.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS\n\nOutput\n\nPrint the number of different PIN codes Takahashi can set.\n\nSample Input 1\n\n4\n0224\n\nSample Output 1\n\n3\n\nTakahashi has the following options:\n\nErase the first digit of S and set 224.\n\nErase the second digit of S and set 024.\n\nErase the third digit of S and set 024.\n\nErase the fourth digit of S and set 022.\n\nThus, he can set three different PIN codes: 022, 024, and 224.\n\nSample Input 2\n\n6\n123123\n\nSample Output 2\n\n17\n\nSample Input 3\n\n19\n3141592653589793238\n\nSample Output 3\n\n329", "sample_input": "4\n0224\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02844", "source_text": "Score: 400 points\n\nProblem Statement\n\nAtCoder Inc. has decided to lock the door of its office with a 3-digit PIN code.\n\nThe company has an N-digit lucky number, S. Takahashi, the president, will erase N-3 digits from S and concatenate the remaining 3 digits without changing the order to set the PIN code.\n\nHow many different PIN codes can he set this way?\n\nBoth the lucky number and the PIN code may begin with a 0.\n\nConstraints\n\n4 \\leq N \\leq 30000\n\nS is a string of length N consisting of digits.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS\n\nOutput\n\nPrint the number of different PIN codes Takahashi can set.\n\nSample Input 1\n\n4\n0224\n\nSample Output 1\n\n3\n\nTakahashi has the following options:\n\nErase the first digit of S and set 224.\n\nErase the second digit of S and set 024.\n\nErase the third digit of S and set 024.\n\nErase the fourth digit of S and set 022.\n\nThus, he can set three different PIN codes: 022, 024, and 224.\n\nSample Input 2\n\n6\n123123\n\nSample Output 2\n\n17\n\nSample Input 3\n\n19\n3141592653589793238\n\nSample Output 3\n\n329", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1940, "cpu_time_ms": 16, "memory_kb": 384}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s837251215", "group_id": "codeNet:p02846", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int, int> P;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define chmin(x, y) x = min(x, y)\n#define chmax(x, y) x = max(x, y)\n#define MOD (int) (1e9+7)\n#define INF (int) 2e9\n#define LLINF (ll) 2e18\n\nint main(){\n    ll t1, t2;\n    ll a1, a2, b1, b2;\n    cin >> t1 >> t2 >> a1 >> a2 >> b1 >> b2;\n\n    ll d1 = a1-b1;\n    ll d2 = a2-b2;\n\n    ll st = d1*t1+d2*t2;\n    printf(\"%lld\\n\", st);\n\n    if(st==0){\n        cout << \"infinity\" << endl;\n        return 0;\n    }\n\n    if(st>0){\n        ll l = 0;\n        ll r = (ll) 1e10+5;\n        ll tmp;\n        while(r-l>1){\n            tmp = (l+r)/2;\n            if(tmp*st+d1*t1>=0){\n                r = tmp;\n            }else{\n                l = tmp;\n            }\n        }\n        tmp = r;\n        printf(\"%lld\\n\", tmp);\n\n        ll ans = tmp*2-1;\n        if(tmp*st+d1*t1==0){\n            ans += 1;\n        }\n        cout << ans << endl;\n    }else{\n        ll l = 0;\n        ll r = (ll) 1e10+5;\n        ll tmp;\n        while(r-l>1){\n            tmp = (l+r)/2;\n            if(tmp*st+d1*t1<=0){\n                r = tmp;\n            }else{\n                l = tmp;\n            }\n        }\n        tmp = r;\n        ll ans = tmp*2-1;\n        if(tmp*st+d1*t1==0){\n            ans += 1;\n        }\n        cout << ans << endl;\n    }\n\n    return 0;\n}", "language": "C++", "metadata": {"date": 1575257817, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02846.html", "problem_id": "p02846", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02846/input.txt", "sample_output_relpath": "derived/input_output/data/p02846/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02846/C++/s837251215.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s837251215", "user_id": "u263654061"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int, int> P;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define chmin(x, y) x = min(x, y)\n#define chmax(x, y) x = max(x, y)\n#define MOD (int) (1e9+7)\n#define INF (int) 2e9\n#define LLINF (ll) 2e18\n\nint main(){\n    ll t1, t2;\n    ll a1, a2, b1, b2;\n    cin >> t1 >> t2 >> a1 >> a2 >> b1 >> b2;\n\n    ll d1 = a1-b1;\n    ll d2 = a2-b2;\n\n    ll st = d1*t1+d2*t2;\n    printf(\"%lld\\n\", st);\n\n    if(st==0){\n        cout << \"infinity\" << endl;\n        return 0;\n    }\n\n    if(st>0){\n        ll l = 0;\n        ll r = (ll) 1e10+5;\n        ll tmp;\n        while(r-l>1){\n            tmp = (l+r)/2;\n            if(tmp*st+d1*t1>=0){\n                r = tmp;\n            }else{\n                l = tmp;\n            }\n        }\n        tmp = r;\n        printf(\"%lld\\n\", tmp);\n\n        ll ans = tmp*2-1;\n        if(tmp*st+d1*t1==0){\n            ans += 1;\n        }\n        cout << ans << endl;\n    }else{\n        ll l = 0;\n        ll r = (ll) 1e10+5;\n        ll tmp;\n        while(r-l>1){\n            tmp = (l+r)/2;\n            if(tmp*st+d1*t1<=0){\n                r = tmp;\n            }else{\n                l = tmp;\n            }\n        }\n        tmp = r;\n        ll ans = tmp*2-1;\n        if(tmp*st+d1*t1==0){\n            ans += 1;\n        }\n        cout << ans << endl;\n    }\n\n    return 0;\n}", "problem_context": "Score: 600 points\n\nProblem Statement\n\nTakahashi and Aoki are training for long-distance races in an infinitely long straight course running from west to east.\n\nThey start simultaneously at the same point and moves as follows towards the east:\n\nTakahashi runs A_1 meters per minute for the first T_1 minutes, then runs at A_2 meters per minute for the subsequent T_2 minutes, and alternates between these two modes forever.\n\nAoki runs B_1 meters per minute for the first T_1 minutes, then runs at B_2 meters per minute for the subsequent T_2 minutes, and alternates between these two modes forever.\n\nHow many times will Takahashi and Aoki meet each other, that is, come to the same point? We do not count the start of the run. If they meet infinitely many times, report that fact.\n\nConstraints\n\n1 \\leq T_i \\leq 100000\n\n1 \\leq A_i \\leq 10^{10}\n\n1 \\leq B_i \\leq 10^{10}\n\nA_1 \\neq B_1\n\nA_2 \\neq B_2\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nT_1 T_2\nA_1 A_2\nB_1 B_2\n\nOutput\n\nPrint the number of times Takahashi and Aoki will meet each other.\n\nIf they meet infinitely many times, print infinity instead.\n\nSample Input 1\n\n1 2\n10 10\n12 4\n\nSample Output 1\n\n1\n\nThey will meet just once, \\frac{4}{3} minutes after they start, at \\frac{40}{3} meters from where they start.\n\nSample Input 2\n\n100 1\n101 101\n102 1\n\nSample Output 2\n\ninfinity\n\nThey will meet 101, 202, 303, 404, 505, 606, ... minutes after they start, that is, they will meet infinitely many times.\n\nSample Input 3\n\n12000 15700\n3390000000 3810000000\n5550000000 2130000000\n\nSample Output 3\n\n113\n\nThe values in input may not fit into a 32-bit integer type.", "sample_input": "1 2\n10 10\n12 4\n"}, "reference_outputs": ["1\n"], "source_document_id": "p02846", "source_text": "Score: 600 points\n\nProblem Statement\n\nTakahashi and Aoki are training for long-distance races in an infinitely long straight course running from west to east.\n\nThey start simultaneously at the same point and moves as follows towards the east:\n\nTakahashi runs A_1 meters per minute for the first T_1 minutes, then runs at A_2 meters per minute for the subsequent T_2 minutes, and alternates between these two modes forever.\n\nAoki runs B_1 meters per minute for the first T_1 minutes, then runs at B_2 meters per minute for the subsequent T_2 minutes, and alternates between these two modes forever.\n\nHow many times will Takahashi and Aoki meet each other, that is, come to the same point? We do not count the start of the run. If they meet infinitely many times, report that fact.\n\nConstraints\n\n1 \\leq T_i \\leq 100000\n\n1 \\leq A_i \\leq 10^{10}\n\n1 \\leq B_i \\leq 10^{10}\n\nA_1 \\neq B_1\n\nA_2 \\neq B_2\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nT_1 T_2\nA_1 A_2\nB_1 B_2\n\nOutput\n\nPrint the number of times Takahashi and Aoki will meet each other.\n\nIf they meet infinitely many times, print infinity instead.\n\nSample Input 1\n\n1 2\n10 10\n12 4\n\nSample Output 1\n\n1\n\nThey will meet just once, \\frac{4}{3} minutes after they start, at \\frac{40}{3} meters from where they start.\n\nSample Input 2\n\n100 1\n101 101\n102 1\n\nSample Output 2\n\ninfinity\n\nThey will meet 101, 202, 303, 404, 505, 606, ... minutes after they start, that is, they will meet infinitely many times.\n\nSample Input 3\n\n12000 15700\n3390000000 3810000000\n5550000000 2130000000\n\nSample Output 3\n\n113\n\nThe values in input may not fit into a 32-bit integer type.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1370, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s972028532", "group_id": "codeNet:p02848", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n \nint main() {\n  int N;\n  cin >> N;\n\n  string input;\n  cin >> input;\n\n  for (int i = 0; i < input.size(); i++)\n  {\n      /* code */\n      cout << (char)((input[i] + N) % (26 + 'A') + 'A');\n    //   cout << (char)(input[i] + N);\n  }\n  cout << endl;\n  \n  return 0;\n}", "language": "C++", "metadata": {"date": 1574648234, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02848.html", "problem_id": "p02848", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02848/input.txt", "sample_output_relpath": "derived/input_output/data/p02848/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02848/C++/s972028532.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s972028532", "user_id": "u585586208"}, "prompt_components": {"gold_output": "CDEZAB\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n \nint main() {\n  int N;\n  cin >> N;\n\n  string input;\n  cin >> input;\n\n  for (int i = 0; i < input.size(); i++)\n  {\n      /* code */\n      cout << (char)((input[i] + N) % (26 + 'A') + 'A');\n    //   cout << (char)(input[i] + N);\n  }\n  cout << endl;\n  \n  return 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nWe have a string S consisting of uppercase English letters. Additionally, an integer N will be given.\n\nShift each character of S by N in alphabetical order (see below), and print the resulting string.\n\nWe assume that A follows Z. For example, shifting A by 2 results in C (A \\to B \\to C), and shifting Y by 3 results in B (Y \\to Z \\to A \\to B).\n\nConstraints\n\n0 \\leq N \\leq 26\n\n1 \\leq |S| \\leq 10^4\n\nS consists of uppercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS\n\nOutput\n\nPrint the string resulting from shifting each character of S by N in alphabetical order.\n\nSample Input 1\n\n2\nABCXYZ\n\nSample Output 1\n\nCDEZAB\n\nNote that A follows Z.\n\nSample Input 2\n\n0\nABCXYZ\n\nSample Output 2\n\nABCXYZ\n\nSample Input 3\n\n13\nABCDEFGHIJKLMNOPQRSTUVWXYZ\n\nSample Output 3\n\nNOPQRSTUVWXYZABCDEFGHIJKLM", "sample_input": "2\nABCXYZ\n"}, "reference_outputs": ["CDEZAB\n"], "source_document_id": "p02848", "source_text": "Score : 200 points\n\nProblem Statement\n\nWe have a string S consisting of uppercase English letters. Additionally, an integer N will be given.\n\nShift each character of S by N in alphabetical order (see below), and print the resulting string.\n\nWe assume that A follows Z. For example, shifting A by 2 results in C (A \\to B \\to C), and shifting Y by 3 results in B (Y \\to Z \\to A \\to B).\n\nConstraints\n\n0 \\leq N \\leq 26\n\n1 \\leq |S| \\leq 10^4\n\nS consists of uppercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS\n\nOutput\n\nPrint the string resulting from shifting each character of S by N in alphabetical order.\n\nSample Input 1\n\n2\nABCXYZ\n\nSample Output 1\n\nCDEZAB\n\nNote that A follows Z.\n\nSample Input 2\n\n0\nABCXYZ\n\nSample Output 2\n\nABCXYZ\n\nSample Input 3\n\n13\nABCDEFGHIJKLMNOPQRSTUVWXYZ\n\nSample Output 3\n\nNOPQRSTUVWXYZABCDEFGHIJKLM", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 310, "cpu_time_ms": 2, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s400043912", "group_id": "codeNet:p02852", "input_text": "/**\n *      author  : 𝒌𝒚𝒐𝒎𝒖𝒌𝒚𝒐𝒎𝒖𝒑𝒖𝒓𝒊𝒏\n *      created : 2019-11-24 22:06:13\n**/\n\n#include <iostream>\n#include <deque>\n#include <map>\n#include <queue>\n#include <set>\n#include <stack>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <cmath>\n#include <complex>\n#include <numeric>\n#include <bitset>\n#include <cassert>\n#include <cctype>\n#include <functional>\n#include <iomanip>\n#include <random>\n#include <utility>\n\nusing namespace std;\n\nusing int64 = long long;\n#define debug(_) cerr << #_ << \": \" << (_) << '\\n'\ntemplate<typename T> inline void chmin(T &a, T b) { if (a > b) a = b; return; }\ntemplate<typename T> inline void chmax(T &a, T b) { if (a < b) a = b; return; }\ntemplate<typename T> ostream& operator<<(ostream& os, const vector<T>& vec) { os << '{'; for (size_t i = 0; i < vec.size(); ++i) { os << vec[i]; if (i != vec.size() - 1) os << ','; } os << '}'; return os; }\ntemplate<typename T, typename U> ostream& operator<<(ostream& os, const pair<T, U>& p) { return os << '{' << p.first << \" \" << p.second << '}'; }\n\nint main() {\n  ios_base::sync_with_stdio(false);\n  cin.tie(nullptr);\n\n  int n, m; cin >> n >> m;\n  string s; cin >> s;\n\n  vector<int> ans;\n\n  reverse(s.begin(), s.end());\n  //debug(s);\n\n  int cur = 0;\n\n  while (cur < n) {\n    int next = -1;\n    int res = (int) s.size() - 1 - cur;\n    //debug(res);\n    \n    for (int i = min(m, res); i >= 1; --i) {\n      if (s[cur + i] == '0') {\n        next = i;\n        break;\n      }\n    }\n    if (next == -1) {\n      cout << -1 << endl;\n      return 0;\n    } else {\n      cur += next;\n      ans.emplace_back(next);\n    }\n  }\n\n  reverse(ans.begin(), ans.end());\n\n  for (int xx : ans) {\n    cout << xx << \" \";\n  }\n\n  return 0;\n}", "language": "C++", "metadata": {"date": 1574651582, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02852.html", "problem_id": "p02852", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02852/input.txt", "sample_output_relpath": "derived/input_output/data/p02852/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02852/C++/s400043912.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s400043912", "user_id": "u095266283"}, "prompt_components": {"gold_output": "1 3 2 3\n", "input_to_evaluate": "/**\n *      author  : 𝒌𝒚𝒐𝒎𝒖𝒌𝒚𝒐𝒎𝒖𝒑𝒖𝒓𝒊𝒏\n *      created : 2019-11-24 22:06:13\n**/\n\n#include <iostream>\n#include <deque>\n#include <map>\n#include <queue>\n#include <set>\n#include <stack>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <cmath>\n#include <complex>\n#include <numeric>\n#include <bitset>\n#include <cassert>\n#include <cctype>\n#include <functional>\n#include <iomanip>\n#include <random>\n#include <utility>\n\nusing namespace std;\n\nusing int64 = long long;\n#define debug(_) cerr << #_ << \": \" << (_) << '\\n'\ntemplate<typename T> inline void chmin(T &a, T b) { if (a > b) a = b; return; }\ntemplate<typename T> inline void chmax(T &a, T b) { if (a < b) a = b; return; }\ntemplate<typename T> ostream& operator<<(ostream& os, const vector<T>& vec) { os << '{'; for (size_t i = 0; i < vec.size(); ++i) { os << vec[i]; if (i != vec.size() - 1) os << ','; } os << '}'; return os; }\ntemplate<typename T, typename U> ostream& operator<<(ostream& os, const pair<T, U>& p) { return os << '{' << p.first << \" \" << p.second << '}'; }\n\nint main() {\n  ios_base::sync_with_stdio(false);\n  cin.tie(nullptr);\n\n  int n, m; cin >> n >> m;\n  string s; cin >> s;\n\n  vector<int> ans;\n\n  reverse(s.begin(), s.end());\n  //debug(s);\n\n  int cur = 0;\n\n  while (cur < n) {\n    int next = -1;\n    int res = (int) s.size() - 1 - cur;\n    //debug(res);\n    \n    for (int i = min(m, res); i >= 1; --i) {\n      if (s[cur + i] == '0') {\n        next = i;\n        break;\n      }\n    }\n    if (next == -1) {\n      cout << -1 << endl;\n      return 0;\n    } else {\n      cur += next;\n      ans.emplace_back(next);\n    }\n  }\n\n  reverse(ans.begin(), ans.end());\n\n  for (int xx : ans) {\n    cout << xx << \" \";\n  }\n\n  return 0;\n}", "problem_context": "Score : 600 points\n\nProblem Statement\n\nTakahashi is playing a board game called Sugoroku.\n\nOn the board, there are N + 1 squares numbered 0 to N. Takahashi starts at Square 0, and he has to stop exactly at Square N to win the game.\n\nThe game uses a roulette with the M numbers from 1 to M. In each turn, Takahashi spins the roulette. If the number x comes up when he is at Square s, he moves to Square s+x. If this makes him go beyond Square N, he loses the game.\n\nAdditionally, some of the squares are Game Over Squares. He also loses the game if he stops at one of those squares. You are given a string S of length N + 1, representing which squares are Game Over Squares. For each i (0 \\leq i \\leq N), Square i is a Game Over Square if S[i] = 1 and not if S[i] = 0.\n\nFind the sequence of numbers coming up in the roulette in which Takahashi can win the game in the fewest number of turns possible. If there are multiple such sequences, find the lexicographically smallest such sequence. If Takahashi cannot win the game, print -1.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n|S| = N + 1\n\nS consists of 0 and 1.\n\nS[0] = 0\n\nS[N] = 0\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nS\n\nOutput\n\nIf Takahashi can win the game, print the lexicographically smallest sequence among the shortest sequences of numbers coming up in the roulette in which Takahashi can win the game, with spaces in between.\n\nIf Takahashi cannot win the game, print -1.\n\nSample Input 1\n\n9 3\n0001000100\n\nSample Output 1\n\n1 3 2 3\n\nIf the numbers 1, 3, 2, 3 come up in this order, Takahashi can reach Square 9 via Square 1, 4, and 6. He cannot reach Square 9 in three or fewer turns, and this is the lexicographically smallest sequence in which he reaches Square 9 in four turns.\n\nSample Input 2\n\n5 4\n011110\n\nSample Output 2\n\n-1\n\nTakahashi cannot reach Square 5.\n\nSample Input 3\n\n6 6\n0101010\n\nSample Output 3\n\n6", "sample_input": "9 3\n0001000100\n"}, "reference_outputs": ["1 3 2 3\n"], "source_document_id": "p02852", "source_text": "Score : 600 points\n\nProblem Statement\n\nTakahashi is playing a board game called Sugoroku.\n\nOn the board, there are N + 1 squares numbered 0 to N. Takahashi starts at Square 0, and he has to stop exactly at Square N to win the game.\n\nThe game uses a roulette with the M numbers from 1 to M. In each turn, Takahashi spins the roulette. If the number x comes up when he is at Square s, he moves to Square s+x. If this makes him go beyond Square N, he loses the game.\n\nAdditionally, some of the squares are Game Over Squares. He also loses the game if he stops at one of those squares. You are given a string S of length N + 1, representing which squares are Game Over Squares. For each i (0 \\leq i \\leq N), Square i is a Game Over Square if S[i] = 1 and not if S[i] = 0.\n\nFind the sequence of numbers coming up in the roulette in which Takahashi can win the game in the fewest number of turns possible. If there are multiple such sequences, find the lexicographically smallest such sequence. If Takahashi cannot win the game, print -1.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n|S| = N + 1\n\nS consists of 0 and 1.\n\nS[0] = 0\n\nS[N] = 0\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nS\n\nOutput\n\nIf Takahashi can win the game, print the lexicographically smallest sequence among the shortest sequences of numbers coming up in the roulette in which Takahashi can win the game, with spaces in between.\n\nIf Takahashi cannot win the game, print -1.\n\nSample Input 1\n\n9 3\n0001000100\n\nSample Output 1\n\n1 3 2 3\n\nIf the numbers 1, 3, 2, 3 come up in this order, Takahashi can reach Square 9 via Square 1, 4, and 6. He cannot reach Square 9 in three or fewer turns, and this is the lexicographically smallest sequence in which he reaches Square 9 in four turns.\n\nSample Input 2\n\n5 4\n011110\n\nSample Output 2\n\n-1\n\nTakahashi cannot reach Square 5.\n\nSample Input 3\n\n6 6\n0101010\n\nSample Output 3\n\n6", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1749, "cpu_time_ms": 9, "memory_kb": 1096}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s841518372", "group_id": "codeNet:p02854", "input_text": "#include <iostream>\n#include <algorithm>\nusing namespace std;\ntypedef long long ll;\n\n\nint main(void){\n  int n,i;\n  ll a[200005],s=0,ls;\n  \n  cin >> n;\n  for (i=0;i<n;i++){\n    cin >> a[i];\n    s+=a[i];\n  }\n  \n  i=1;\n  ls=a[0];\n  while (i<n && ls*2<s){\n    ls+=a[i];\n    i++;\n  }\n  \n  ll v1,v2;\n  v1=ls*2-s;\n  ls-=a[i-1];\n  v2=s-ls*2;\n  \n  cout << min(v1,v2) << endl;\n  \n  return 0;\n}", "language": "C++", "metadata": {"date": 1583788405, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02854.html", "problem_id": "p02854", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02854/input.txt", "sample_output_relpath": "derived/input_output/data/p02854/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02854/C++/s841518372.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s841518372", "user_id": "u088895504"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <iostream>\n#include <algorithm>\nusing namespace std;\ntypedef long long ll;\n\n\nint main(void){\n  int n,i;\n  ll a[200005],s=0,ls;\n  \n  cin >> n;\n  for (i=0;i<n;i++){\n    cin >> a[i];\n    s+=a[i];\n  }\n  \n  i=1;\n  ls=a[0];\n  while (i<n && ls*2<s){\n    ls+=a[i];\n    i++;\n  }\n  \n  ll v1,v2;\n  v1=ls*2-s;\n  ls-=a[i-1];\n  v2=s-ls*2;\n  \n  cout << min(v1,v2) << endl;\n  \n  return 0;\n}", "problem_context": "Score: 200 points\n\nProblem Statement\n\nTakahashi, who works at DISCO, is standing before an iron bar.\nThe bar has N-1 notches, which divide the bar into N sections. The i-th section from the left has a length of A_i millimeters.\n\nTakahashi wanted to choose a notch and cut the bar at that point into two parts with the same length.\nHowever, this may not be possible as is, so he will do the following operations some number of times before he does the cut:\n\nChoose one section and expand it, increasing its length by 1 millimeter. Doing this operation once costs 1 yen (the currency of Japan).\n\nChoose one section of length at least 2 millimeters and shrink it, decreasing its length by 1 millimeter. Doing this operation once costs 1 yen.\n\nFind the minimum amount of money needed before cutting the bar into two parts with the same length.\n\nConstraints\n\n2 \\leq N \\leq 200000\n\n1 \\leq A_i \\leq 2020202020\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 A_3 ... A_N\n\nOutput\n\nPrint an integer representing the minimum amount of money needed before cutting the bar into two parts with the same length.\n\nSample Input 1\n\n3\n2 4 3\n\nSample Output 1\n\n3\n\nThe initial lengths of the sections are [2, 4, 3] (in millimeters). Takahashi can cut the bar equally after doing the following operations for 3 yen:\n\nShrink the second section from the left. The lengths of the sections are now [2, 3, 3].\n\nShrink the first section from the left. The lengths of the sections are now [1, 3, 3].\n\nShrink the second section from the left. The lengths of the sections are now [1, 2, 3], and we can cut the bar at the second notch from the left into two parts of length 3 each.\n\nSample Input 2\n\n12\n100 104 102 105 103 103 101 105 104 102 104 101\n\nSample Output 2\n\n0", "sample_input": "3\n2 4 3\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02854", "source_text": "Score: 200 points\n\nProblem Statement\n\nTakahashi, who works at DISCO, is standing before an iron bar.\nThe bar has N-1 notches, which divide the bar into N sections. The i-th section from the left has a length of A_i millimeters.\n\nTakahashi wanted to choose a notch and cut the bar at that point into two parts with the same length.\nHowever, this may not be possible as is, so he will do the following operations some number of times before he does the cut:\n\nChoose one section and expand it, increasing its length by 1 millimeter. Doing this operation once costs 1 yen (the currency of Japan).\n\nChoose one section of length at least 2 millimeters and shrink it, decreasing its length by 1 millimeter. Doing this operation once costs 1 yen.\n\nFind the minimum amount of money needed before cutting the bar into two parts with the same length.\n\nConstraints\n\n2 \\leq N \\leq 200000\n\n1 \\leq A_i \\leq 2020202020\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 A_3 ... A_N\n\nOutput\n\nPrint an integer representing the minimum amount of money needed before cutting the bar into two parts with the same length.\n\nSample Input 1\n\n3\n2 4 3\n\nSample Output 1\n\n3\n\nThe initial lengths of the sections are [2, 4, 3] (in millimeters). Takahashi can cut the bar equally after doing the following operations for 3 yen:\n\nShrink the second section from the left. The lengths of the sections are now [2, 3, 3].\n\nShrink the first section from the left. The lengths of the sections are now [1, 3, 3].\n\nShrink the second section from the left. The lengths of the sections are now [1, 2, 3], and we can cut the bar at the second notch from the left into two parts of length 3 each.\n\nSample Input 2\n\n12\n100 104 102 105 103 103 101 105 104 102 104 101\n\nSample Output 2\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 383, "cpu_time_ms": 85, "memory_kb": 1792}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s756534396", "group_id": "codeNet:p02855", "input_text": "#include \"bits/stdc++.h\"\n// Begin Header {{{\n#define all(x)          (x).begin(), (x).end()\n#define rep(i, n)       for (i64 i = 0, i##_limit = (n); i < i##_limit; ++i)\n#define reps(i, s, t)   for (i64 i = (s), i##_limit = (t); i <= i##_limit; ++i)\n#define repr(i, s, t)   for (i64 i = (s), i##_limit = (t); i >= i##_limit; --i)\n#define var(Type, ...)  Type __VA_ARGS__; input(__VA_ARGS__)\n#ifndef DBG\n#define trace(...)\n#endif\nusing namespace std;\nusing i64 = int_fast64_t;\nusing pii = pair<i64, i64>;\ntemplate <class T, class U> inline bool chmax(T &a, const U &b) { return b > a && (a = b, true); }\ntemplate <class T, class U> inline bool chmin(T &a, const U &b) { return b < a && (a = b, true); }\ninline i64  sigma(i64 n)            { return (n * (n + 1) >> 1); }\ninline i64  updiv(i64 a, i64 b)     { return (a + b - 1) / b; }\ninline i64  sqr(i64 n)              { return n * n; }\ninline string to_string(char c)     { return string(1, c); }\nconstexpr int INF  = 0x3f3f3f3f;\nconstexpr i64 LINF = 0x3f3f3f3f3f3f3f3fLL;\n\ntemplate <class T>\ninline vector<T> make_v(const T &initValue, size_t sz) {\n    return vector<T>(sz, initValue);\n}\ntemplate <class T, class... Args>\ninline auto make_v(const T &initValue, size_t sz, Args... args) {\n    return vector<decltype(make_v<T>(initValue, args...))>(sz, make_v<T>(initValue, args...));\n}\n\ninline void input() {}\ntemplate <class Head, class... Tail>\ninline void input(Head &head, Tail&... tail) { cin >> head; input(tail...); }\n\ninline void print() { cout << \"\\n\"; }\ntemplate <class Head, class... Tail>\ninline void print(Head &&head, Tail&&... tail) {\n    cout << head;\n    if (sizeof...(tail)) cout << ' ';\n    print(forward<Tail>(tail)...);\n}\n\ntemplate <class T>\ninline ostream& operator<< (ostream &out, const vector<T> &vec) {\n    static constexpr const char *delim[] = { \" \", \"\" };\n    for (const auto &e : vec) out << e << delim[&e == &vec.back()];\n    return out;\n}\n\ntemplate <typename Func>\nstruct FixPoint : Func {\n    inline constexpr FixPoint(Func &&f) noexcept : Func(forward<Func>(f)) {}\n\n    template <typename... Args>\n    inline decltype(auto) operator()(Args &&... args) const {\n        return Func::operator()(*this, forward<Args>(args)...);\n    }\n};\n\ntemplate< typename Func >\ninline decltype(auto) makeFixPoint(Func &&f) {\n    return FixPoint< Func >{forward< Func >(f)};\n}\n// }}} End Header\n\nsigned main()\n{\n    ios::sync_with_stdio(false); cin.tie(nullptr);\n\n    var(int, H, W, K);\n    vector<string> mat(H);\n    auto g = make_v<int>(0, H, W);\n\n    rep(i, H) {\n        input(mat[i]);\n    }\n\n    {\n        int id = 1;\n        rep(i, H) {\n            rep(j, W) {\n                if (mat[i][j] == '#') {\n                    g[i][j] = id++;\n                }\n            }\n        }\n    }\n\n    rep(i, H) {\n        rep(_, W) rep(j, W) {\n            if (g[i][j]) continue;\n            if (j+1 < W && g[i][j+1]) g[i][j] = g[i][j+1];\n            if (j-1 >= 0 && g[i][j-1]) g[i][j] = g[i][j-1];\n        }\n    }\n\n    rep(j, W) {\n        rep(_, H) rep(i, H) {\n            if (g[i][j]) continue;\n            if (i+1 < H && g[i+1][j]) g[i][j] = g[i+1][j];\n            if (i-1 >= 0 && g[i-1][j]) g[i][j] = g[i-1][j];\n        }\n    }\n\n    rep(i, H) {\n        print(g[i]);\n    }\n\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1574565978, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02855.html", "problem_id": "p02855", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02855/input.txt", "sample_output_relpath": "derived/input_output/data/p02855/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02855/C++/s756534396.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s756534396", "user_id": "u897304429"}, "prompt_components": {"gold_output": "1 2 2\n1 3 4\n5 5 4\n", "input_to_evaluate": "#include \"bits/stdc++.h\"\n// Begin Header {{{\n#define all(x)          (x).begin(), (x).end()\n#define rep(i, n)       for (i64 i = 0, i##_limit = (n); i < i##_limit; ++i)\n#define reps(i, s, t)   for (i64 i = (s), i##_limit = (t); i <= i##_limit; ++i)\n#define repr(i, s, t)   for (i64 i = (s), i##_limit = (t); i >= i##_limit; --i)\n#define var(Type, ...)  Type __VA_ARGS__; input(__VA_ARGS__)\n#ifndef DBG\n#define trace(...)\n#endif\nusing namespace std;\nusing i64 = int_fast64_t;\nusing pii = pair<i64, i64>;\ntemplate <class T, class U> inline bool chmax(T &a, const U &b) { return b > a && (a = b, true); }\ntemplate <class T, class U> inline bool chmin(T &a, const U &b) { return b < a && (a = b, true); }\ninline i64  sigma(i64 n)            { return (n * (n + 1) >> 1); }\ninline i64  updiv(i64 a, i64 b)     { return (a + b - 1) / b; }\ninline i64  sqr(i64 n)              { return n * n; }\ninline string to_string(char c)     { return string(1, c); }\nconstexpr int INF  = 0x3f3f3f3f;\nconstexpr i64 LINF = 0x3f3f3f3f3f3f3f3fLL;\n\ntemplate <class T>\ninline vector<T> make_v(const T &initValue, size_t sz) {\n    return vector<T>(sz, initValue);\n}\ntemplate <class T, class... Args>\ninline auto make_v(const T &initValue, size_t sz, Args... args) {\n    return vector<decltype(make_v<T>(initValue, args...))>(sz, make_v<T>(initValue, args...));\n}\n\ninline void input() {}\ntemplate <class Head, class... Tail>\ninline void input(Head &head, Tail&... tail) { cin >> head; input(tail...); }\n\ninline void print() { cout << \"\\n\"; }\ntemplate <class Head, class... Tail>\ninline void print(Head &&head, Tail&&... tail) {\n    cout << head;\n    if (sizeof...(tail)) cout << ' ';\n    print(forward<Tail>(tail)...);\n}\n\ntemplate <class T>\ninline ostream& operator<< (ostream &out, const vector<T> &vec) {\n    static constexpr const char *delim[] = { \" \", \"\" };\n    for (const auto &e : vec) out << e << delim[&e == &vec.back()];\n    return out;\n}\n\ntemplate <typename Func>\nstruct FixPoint : Func {\n    inline constexpr FixPoint(Func &&f) noexcept : Func(forward<Func>(f)) {}\n\n    template <typename... Args>\n    inline decltype(auto) operator()(Args &&... args) const {\n        return Func::operator()(*this, forward<Args>(args)...);\n    }\n};\n\ntemplate< typename Func >\ninline decltype(auto) makeFixPoint(Func &&f) {\n    return FixPoint< Func >{forward< Func >(f)};\n}\n// }}} End Header\n\nsigned main()\n{\n    ios::sync_with_stdio(false); cin.tie(nullptr);\n\n    var(int, H, W, K);\n    vector<string> mat(H);\n    auto g = make_v<int>(0, H, W);\n\n    rep(i, H) {\n        input(mat[i]);\n    }\n\n    {\n        int id = 1;\n        rep(i, H) {\n            rep(j, W) {\n                if (mat[i][j] == '#') {\n                    g[i][j] = id++;\n                }\n            }\n        }\n    }\n\n    rep(i, H) {\n        rep(_, W) rep(j, W) {\n            if (g[i][j]) continue;\n            if (j+1 < W && g[i][j+1]) g[i][j] = g[i][j+1];\n            if (j-1 >= 0 && g[i][j-1]) g[i][j] = g[i][j-1];\n        }\n    }\n\n    rep(j, W) {\n        rep(_, H) rep(i, H) {\n            if (g[i][j]) continue;\n            if (i+1 < H && g[i+1][j]) g[i][j] = g[i+1][j];\n            if (i-1 >= 0 && g[i-1][j]) g[i][j] = g[i-1][j];\n        }\n    }\n\n    rep(i, H) {\n        print(g[i]);\n    }\n\n    return 0;\n}\n", "problem_context": "Score: 400 points\n\nProblem Statement\n\nChokudai made a rectangular cake for contestants in DDCC 2020 Finals.\n\nThe cake has H - 1 horizontal notches and W - 1 vertical notches, which divide the cake into H \\times W equal sections. K of these sections has a strawberry on top of each of them.\n\nThe positions of the strawberries are given to you as H \\times W characters s_{i, j} (1 \\leq i \\leq H, 1 \\leq j \\leq W). If s_{i, j} is #, the section at the i-th row from the top and the j-th column from the left contains a strawberry; if s_{i, j} is ., the section does not contain one. There are exactly K occurrences of #s.\n\nTakahashi wants to cut this cake into K pieces and serve them to the contestants. Each of these pieces must satisfy the following conditions:\n\nHas a rectangular shape.\n\nContains exactly one strawberry.\n\nOne possible way to cut the cake is shown below:\n\nFind one way to cut the cake and satisfy the condition. We can show that this is always possible, regardless of the number and positions of the strawberries.\n\nConstraints\n\n1 \\leq H \\leq 300\n\n1 \\leq W \\leq 300\n\n1 \\leq K \\leq H \\times W\n\ns_{i, j} is # or ..\n\nThere are exactly K occurrences of # in s.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W K\ns_{1, 1} s_{1, 2} \\cdots s_{1, W}\ns_{2, 1} s_{2, 2} \\cdots s_{2, W}\n:\ns_{H, 1} s_{H, 2} \\cdots s_{H, W}\n\nOutput\n\nAssign the numbers 1, 2, 3, \\dots, K to the K pieces obtained after the cut, in any order. Then, let a_{i, j} be the number representing the piece containing the section at the i-th row from the top and the j-th column from the left of the cake. Output should be in the following format:\n\na_{1, 1} \\ a_{1, 2} \\ \\cdots \\ a_{1, W}\na_{2, 1} \\ a_{2, 2} \\ \\cdots \\ a_{2, W}\n:\na_{H, 1} \\ a_{H, 2} \\ \\cdots \\ a_{H, W}\n\nIf multiple solutions exist, any of them will be accepted.\n\nSample Input 1\n\n3 3 5\n#.#\n.#.\n#.#\n\nSample Output 1\n\n1 2 2\n1 3 4\n5 5 4\n\nOne way to cut this cake is shown below:\n\nSample Input 2\n\n3 7 7\n#...#.#\n..#...#\n.#..#..\n\nSample Output 2\n\n1 1 2 2 3 4 4\n6 6 2 2 3 5 5\n6 6 7 7 7 7 7\n\nOne way to cut this cake is shown below:\n\nSample Input 3\n\n13 21 106\n.....................\n.####.####.####.####.\n..#.#..#.#.#....#....\n..#.#..#.#.#....#....\n..#.#..#.#.#....#....\n.####.####.####.####.\n.....................\n.####.####.####.####.\n....#.#..#....#.#..#.\n.####.#..#.####.#..#.\n.#....#..#.#....#..#.\n.####.####.####.####.\n.....................\n\nSample Output 3\n\n12 12 23 34 45 45 60 71 82 93 93 2 13 24 35 35 17 28 39 50 50\n12 12 23 34 45 45 60 71 82 93 93 2 13 24 35 35 17 28 39 50 50\n12 12 56 89 89 89 60 104 82 31 31 46 13 24 35 35 61 61 39 50 50\n12 12 67 67 100 100 60 9 9 42 42 57 13 24 6 72 72 72 72 72 72\n12 12 78 5 5 5 20 20 20 53 68 68 90 24 6 83 83 83 83 83 83\n16 16 27 38 49 49 64 75 86 97 79 79 90 101 6 94 94 105 10 21 21\n16 16 27 38 49 49 64 75 86 97 79 79 90 101 6 94 94 105 10 21 21\n32 32 43 54 65 65 80 11 106 95 22 22 33 44 55 55 70 1 96 85 85\n32 32 43 54 76 76 91 11 106 84 84 4 99 66 66 66 81 1 96 74 74\n14 14 3 98 87 87 102 11 73 73 73 4 99 88 77 77 92 92 63 63 63\n25 25 3 98 87 87 7 29 62 62 62 15 99 88 77 77 103 19 30 52 52\n36 36 47 58 69 69 18 29 40 51 51 26 37 48 59 59 8 19 30 41 41\n36 36 47 58 69 69 18 29 40 51 51 26 37 48 59 59 8 19 30 41 41", "sample_input": "3 3 5\n#.#\n.#.\n#.#\n"}, "reference_outputs": ["1 2 2\n1 3 4\n5 5 4\n"], "source_document_id": "p02855", "source_text": "Score: 400 points\n\nProblem Statement\n\nChokudai made a rectangular cake for contestants in DDCC 2020 Finals.\n\nThe cake has H - 1 horizontal notches and W - 1 vertical notches, which divide the cake into H \\times W equal sections. K of these sections has a strawberry on top of each of them.\n\nThe positions of the strawberries are given to you as H \\times W characters s_{i, j} (1 \\leq i \\leq H, 1 \\leq j \\leq W). If s_{i, j} is #, the section at the i-th row from the top and the j-th column from the left contains a strawberry; if s_{i, j} is ., the section does not contain one. There are exactly K occurrences of #s.\n\nTakahashi wants to cut this cake into K pieces and serve them to the contestants. Each of these pieces must satisfy the following conditions:\n\nHas a rectangular shape.\n\nContains exactly one strawberry.\n\nOne possible way to cut the cake is shown below:\n\nFind one way to cut the cake and satisfy the condition. We can show that this is always possible, regardless of the number and positions of the strawberries.\n\nConstraints\n\n1 \\leq H \\leq 300\n\n1 \\leq W \\leq 300\n\n1 \\leq K \\leq H \\times W\n\ns_{i, j} is # or ..\n\nThere are exactly K occurrences of # in s.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W K\ns_{1, 1} s_{1, 2} \\cdots s_{1, W}\ns_{2, 1} s_{2, 2} \\cdots s_{2, W}\n:\ns_{H, 1} s_{H, 2} \\cdots s_{H, W}\n\nOutput\n\nAssign the numbers 1, 2, 3, \\dots, K to the K pieces obtained after the cut, in any order. Then, let a_{i, j} be the number representing the piece containing the section at the i-th row from the top and the j-th column from the left of the cake. Output should be in the following format:\n\na_{1, 1} \\ a_{1, 2} \\ \\cdots \\ a_{1, W}\na_{2, 1} \\ a_{2, 2} \\ \\cdots \\ a_{2, W}\n:\na_{H, 1} \\ a_{H, 2} \\ \\cdots \\ a_{H, W}\n\nIf multiple solutions exist, any of them will be accepted.\n\nSample Input 1\n\n3 3 5\n#.#\n.#.\n#.#\n\nSample Output 1\n\n1 2 2\n1 3 4\n5 5 4\n\nOne way to cut this cake is shown below:\n\nSample Input 2\n\n3 7 7\n#...#.#\n..#...#\n.#..#..\n\nSample Output 2\n\n1 1 2 2 3 4 4\n6 6 2 2 3 5 5\n6 6 7 7 7 7 7\n\nOne way to cut this cake is shown below:\n\nSample Input 3\n\n13 21 106\n.....................\n.####.####.####.####.\n..#.#..#.#.#....#....\n..#.#..#.#.#....#....\n..#.#..#.#.#....#....\n.####.####.####.####.\n.....................\n.####.####.####.####.\n....#.#..#....#.#..#.\n.####.#..#.####.#..#.\n.#....#..#.#....#..#.\n.####.####.####.####.\n.....................\n\nSample Output 3\n\n12 12 23 34 45 45 60 71 82 93 93 2 13 24 35 35 17 28 39 50 50\n12 12 23 34 45 45 60 71 82 93 93 2 13 24 35 35 17 28 39 50 50\n12 12 56 89 89 89 60 104 82 31 31 46 13 24 35 35 61 61 39 50 50\n12 12 67 67 100 100 60 9 9 42 42 57 13 24 6 72 72 72 72 72 72\n12 12 78 5 5 5 20 20 20 53 68 68 90 24 6 83 83 83 83 83 83\n16 16 27 38 49 49 64 75 86 97 79 79 90 101 6 94 94 105 10 21 21\n16 16 27 38 49 49 64 75 86 97 79 79 90 101 6 94 94 105 10 21 21\n32 32 43 54 65 65 80 11 106 95 22 22 33 44 55 55 70 1 96 85 85\n32 32 43 54 76 76 91 11 106 84 84 4 99 66 66 66 81 1 96 74 74\n14 14 3 98 87 87 102 11 73 73 73 4 99 88 77 77 92 92 63 63 63\n25 25 3 98 87 87 7 29 62 62 62 15 99 88 77 77 103 19 30 52 52\n36 36 47 58 69 69 18 29 40 51 51 26 37 48 59 59 8 19 30 41 41\n36 36 47 58 69 69 18 29 40 51 51 26 37 48 59 59 8 19 30 41 41", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 3250, "cpu_time_ms": 79, "memory_kb": 1280}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s215368493", "group_id": "codeNet:p02855", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define ll long long\n#define p_b push_back\n#define pl pair<ll,ll>\n\nll modo = 1000000007;\nll MOD = modo;\n\nint main()\n{\n\tios_base::sync_with_stdio(false);\n\tcin.tie(NULL);\n\tll t;\n\tt = 1;\n\t//cin >> t;\n\twhile(t--)\n\t{\n\t\tll h,w,k;\n\t\tcin >> h >> w >> k;\n\t\tstring s[h];\n\t\tll i,j;\n\t\tll first = -1;\n\t\tfor(i=0;i<h;i++)\n\t\t{\n\t\t\tcin >> s[i];\n\t\t\tif(first!= -1)\n\t\t\t{\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tfor(j=0;j<w;j++)\n\t\t\t{\n\t\t\t\tif(s[i][j]=='#')\n\t\t\t\t{\n\t\t\t\t\tfirst = i;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tll arr[h][w];\n\t\tll cur = 0;\n\t\t\n\n\t\tfor(i=first;i<h;i++)\n\t\t{\n\t\t\tll count = 0;\n\t\t\tfor(j=0;j<w;j++)\n\t\t\t{\n\t\t\t\tif(s[i][j] == '#')\n\t\t\t\t{\n\t\t\t\t\tcount = 1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(!count)\n\t\t\t{\n\t\t\t\tfor(j=0;j<w;j++)\n\t\t\t\t{\n\t\t\t\t\tarr[i][j] = arr[i-1][j];\n\t\t\t\t}\n\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tll flag = 0;\n\t\t\t\tfor(j=0;j<w;j++)\n\t\t\t\t{\n\t\t\t\t\tif(s[i][j] == '#')\n\t\t\t\t\t{\n\t\t\t\t\t\tcur++;\n\t\t\t\t\t\tflag = 1;\n\n\t\t\t\t\t}\n\t\t\t\t\tif(flag)\n\t\t\t\t\t{\n\t\t\t\t\t\tarr[i][j] = cur;\n\t\t\t\t\t}\n\t\t\t\t\telse\n\t\t\t\t\t\tarr[i][j] = cur+1;\n\n\t\t\t\t\t// << i << \" \" << j << \" \" << arr[i][j] << endl;\n\n\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor(i=first-1;i>=0;i--)\n\t\t{\n\n\t\t\tfor(j=0;j<w;j++)\n\t\t\t{\n\t\t\t\tarr[i][j] = arr[i+1][j] ;\n\n\t\t\t}\n\t\t}\n\t\tfor(i=0;i<h;i++)\n\t\t{\n\t\t\tfor(j=0;j<w;j++)\n\t\t\t{\n\t\t\t\tcout << arr[i][j] << \" \";\n\t\t\t}\n\t\t\tcout << endl;\n\t\t}\n\n\n\n\t}\t\n\t\n\treturn 0;\n\n}", "language": "C++", "metadata": {"date": 1574564020, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02855.html", "problem_id": "p02855", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02855/input.txt", "sample_output_relpath": "derived/input_output/data/p02855/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02855/C++/s215368493.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s215368493", "user_id": "u414949029"}, "prompt_components": {"gold_output": "1 2 2\n1 3 4\n5 5 4\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define ll long long\n#define p_b push_back\n#define pl pair<ll,ll>\n\nll modo = 1000000007;\nll MOD = modo;\n\nint main()\n{\n\tios_base::sync_with_stdio(false);\n\tcin.tie(NULL);\n\tll t;\n\tt = 1;\n\t//cin >> t;\n\twhile(t--)\n\t{\n\t\tll h,w,k;\n\t\tcin >> h >> w >> k;\n\t\tstring s[h];\n\t\tll i,j;\n\t\tll first = -1;\n\t\tfor(i=0;i<h;i++)\n\t\t{\n\t\t\tcin >> s[i];\n\t\t\tif(first!= -1)\n\t\t\t{\n\t\t\t\tcontinue;\n\t\t\t}\n\t\t\tfor(j=0;j<w;j++)\n\t\t\t{\n\t\t\t\tif(s[i][j]=='#')\n\t\t\t\t{\n\t\t\t\t\tfirst = i;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tll arr[h][w];\n\t\tll cur = 0;\n\t\t\n\n\t\tfor(i=first;i<h;i++)\n\t\t{\n\t\t\tll count = 0;\n\t\t\tfor(j=0;j<w;j++)\n\t\t\t{\n\t\t\t\tif(s[i][j] == '#')\n\t\t\t\t{\n\t\t\t\t\tcount = 1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(!count)\n\t\t\t{\n\t\t\t\tfor(j=0;j<w;j++)\n\t\t\t\t{\n\t\t\t\t\tarr[i][j] = arr[i-1][j];\n\t\t\t\t}\n\n\t\t\t}\n\t\t\telse\n\t\t\t{\n\t\t\t\tll flag = 0;\n\t\t\t\tfor(j=0;j<w;j++)\n\t\t\t\t{\n\t\t\t\t\tif(s[i][j] == '#')\n\t\t\t\t\t{\n\t\t\t\t\t\tcur++;\n\t\t\t\t\t\tflag = 1;\n\n\t\t\t\t\t}\n\t\t\t\t\tif(flag)\n\t\t\t\t\t{\n\t\t\t\t\t\tarr[i][j] = cur;\n\t\t\t\t\t}\n\t\t\t\t\telse\n\t\t\t\t\t\tarr[i][j] = cur+1;\n\n\t\t\t\t\t// << i << \" \" << j << \" \" << arr[i][j] << endl;\n\n\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor(i=first-1;i>=0;i--)\n\t\t{\n\n\t\t\tfor(j=0;j<w;j++)\n\t\t\t{\n\t\t\t\tarr[i][j] = arr[i+1][j] ;\n\n\t\t\t}\n\t\t}\n\t\tfor(i=0;i<h;i++)\n\t\t{\n\t\t\tfor(j=0;j<w;j++)\n\t\t\t{\n\t\t\t\tcout << arr[i][j] << \" \";\n\t\t\t}\n\t\t\tcout << endl;\n\t\t}\n\n\n\n\t}\t\n\t\n\treturn 0;\n\n}", "problem_context": "Score: 400 points\n\nProblem Statement\n\nChokudai made a rectangular cake for contestants in DDCC 2020 Finals.\n\nThe cake has H - 1 horizontal notches and W - 1 vertical notches, which divide the cake into H \\times W equal sections. K of these sections has a strawberry on top of each of them.\n\nThe positions of the strawberries are given to you as H \\times W characters s_{i, j} (1 \\leq i \\leq H, 1 \\leq j \\leq W). If s_{i, j} is #, the section at the i-th row from the top and the j-th column from the left contains a strawberry; if s_{i, j} is ., the section does not contain one. There are exactly K occurrences of #s.\n\nTakahashi wants to cut this cake into K pieces and serve them to the contestants. Each of these pieces must satisfy the following conditions:\n\nHas a rectangular shape.\n\nContains exactly one strawberry.\n\nOne possible way to cut the cake is shown below:\n\nFind one way to cut the cake and satisfy the condition. We can show that this is always possible, regardless of the number and positions of the strawberries.\n\nConstraints\n\n1 \\leq H \\leq 300\n\n1 \\leq W \\leq 300\n\n1 \\leq K \\leq H \\times W\n\ns_{i, j} is # or ..\n\nThere are exactly K occurrences of # in s.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W K\ns_{1, 1} s_{1, 2} \\cdots s_{1, W}\ns_{2, 1} s_{2, 2} \\cdots s_{2, W}\n:\ns_{H, 1} s_{H, 2} \\cdots s_{H, W}\n\nOutput\n\nAssign the numbers 1, 2, 3, \\dots, K to the K pieces obtained after the cut, in any order. Then, let a_{i, j} be the number representing the piece containing the section at the i-th row from the top and the j-th column from the left of the cake. Output should be in the following format:\n\na_{1, 1} \\ a_{1, 2} \\ \\cdots \\ a_{1, W}\na_{2, 1} \\ a_{2, 2} \\ \\cdots \\ a_{2, W}\n:\na_{H, 1} \\ a_{H, 2} \\ \\cdots \\ a_{H, W}\n\nIf multiple solutions exist, any of them will be accepted.\n\nSample Input 1\n\n3 3 5\n#.#\n.#.\n#.#\n\nSample Output 1\n\n1 2 2\n1 3 4\n5 5 4\n\nOne way to cut this cake is shown below:\n\nSample Input 2\n\n3 7 7\n#...#.#\n..#...#\n.#..#..\n\nSample Output 2\n\n1 1 2 2 3 4 4\n6 6 2 2 3 5 5\n6 6 7 7 7 7 7\n\nOne way to cut this cake is shown below:\n\nSample Input 3\n\n13 21 106\n.....................\n.####.####.####.####.\n..#.#..#.#.#....#....\n..#.#..#.#.#....#....\n..#.#..#.#.#....#....\n.####.####.####.####.\n.....................\n.####.####.####.####.\n....#.#..#....#.#..#.\n.####.#..#.####.#..#.\n.#....#..#.#....#..#.\n.####.####.####.####.\n.....................\n\nSample Output 3\n\n12 12 23 34 45 45 60 71 82 93 93 2 13 24 35 35 17 28 39 50 50\n12 12 23 34 45 45 60 71 82 93 93 2 13 24 35 35 17 28 39 50 50\n12 12 56 89 89 89 60 104 82 31 31 46 13 24 35 35 61 61 39 50 50\n12 12 67 67 100 100 60 9 9 42 42 57 13 24 6 72 72 72 72 72 72\n12 12 78 5 5 5 20 20 20 53 68 68 90 24 6 83 83 83 83 83 83\n16 16 27 38 49 49 64 75 86 97 79 79 90 101 6 94 94 105 10 21 21\n16 16 27 38 49 49 64 75 86 97 79 79 90 101 6 94 94 105 10 21 21\n32 32 43 54 65 65 80 11 106 95 22 22 33 44 55 55 70 1 96 85 85\n32 32 43 54 76 76 91 11 106 84 84 4 99 66 66 66 81 1 96 74 74\n14 14 3 98 87 87 102 11 73 73 73 4 99 88 77 77 92 92 63 63 63\n25 25 3 98 87 87 7 29 62 62 62 15 99 88 77 77 103 19 30 52 52\n36 36 47 58 69 69 18 29 40 51 51 26 37 48 59 59 8 19 30 41 41\n36 36 47 58 69 69 18 29 40 51 51 26 37 48 59 59 8 19 30 41 41", "sample_input": "3 3 5\n#.#\n.#.\n#.#\n"}, "reference_outputs": ["1 2 2\n1 3 4\n5 5 4\n"], "source_document_id": "p02855", "source_text": "Score: 400 points\n\nProblem Statement\n\nChokudai made a rectangular cake for contestants in DDCC 2020 Finals.\n\nThe cake has H - 1 horizontal notches and W - 1 vertical notches, which divide the cake into H \\times W equal sections. K of these sections has a strawberry on top of each of them.\n\nThe positions of the strawberries are given to you as H \\times W characters s_{i, j} (1 \\leq i \\leq H, 1 \\leq j \\leq W). If s_{i, j} is #, the section at the i-th row from the top and the j-th column from the left contains a strawberry; if s_{i, j} is ., the section does not contain one. There are exactly K occurrences of #s.\n\nTakahashi wants to cut this cake into K pieces and serve them to the contestants. Each of these pieces must satisfy the following conditions:\n\nHas a rectangular shape.\n\nContains exactly one strawberry.\n\nOne possible way to cut the cake is shown below:\n\nFind one way to cut the cake and satisfy the condition. We can show that this is always possible, regardless of the number and positions of the strawberries.\n\nConstraints\n\n1 \\leq H \\leq 300\n\n1 \\leq W \\leq 300\n\n1 \\leq K \\leq H \\times W\n\ns_{i, j} is # or ..\n\nThere are exactly K occurrences of # in s.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W K\ns_{1, 1} s_{1, 2} \\cdots s_{1, W}\ns_{2, 1} s_{2, 2} \\cdots s_{2, W}\n:\ns_{H, 1} s_{H, 2} \\cdots s_{H, W}\n\nOutput\n\nAssign the numbers 1, 2, 3, \\dots, K to the K pieces obtained after the cut, in any order. Then, let a_{i, j} be the number representing the piece containing the section at the i-th row from the top and the j-th column from the left of the cake. Output should be in the following format:\n\na_{1, 1} \\ a_{1, 2} \\ \\cdots \\ a_{1, W}\na_{2, 1} \\ a_{2, 2} \\ \\cdots \\ a_{2, W}\n:\na_{H, 1} \\ a_{H, 2} \\ \\cdots \\ a_{H, W}\n\nIf multiple solutions exist, any of them will be accepted.\n\nSample Input 1\n\n3 3 5\n#.#\n.#.\n#.#\n\nSample Output 1\n\n1 2 2\n1 3 4\n5 5 4\n\nOne way to cut this cake is shown below:\n\nSample Input 2\n\n3 7 7\n#...#.#\n..#...#\n.#..#..\n\nSample Output 2\n\n1 1 2 2 3 4 4\n6 6 2 2 3 5 5\n6 6 7 7 7 7 7\n\nOne way to cut this cake is shown below:\n\nSample Input 3\n\n13 21 106\n.....................\n.####.####.####.####.\n..#.#..#.#.#....#....\n..#.#..#.#.#....#....\n..#.#..#.#.#....#....\n.####.####.####.####.\n.....................\n.####.####.####.####.\n....#.#..#....#.#..#.\n.####.#..#.####.#..#.\n.#....#..#.#....#..#.\n.####.####.####.####.\n.....................\n\nSample Output 3\n\n12 12 23 34 45 45 60 71 82 93 93 2 13 24 35 35 17 28 39 50 50\n12 12 23 34 45 45 60 71 82 93 93 2 13 24 35 35 17 28 39 50 50\n12 12 56 89 89 89 60 104 82 31 31 46 13 24 35 35 61 61 39 50 50\n12 12 67 67 100 100 60 9 9 42 42 57 13 24 6 72 72 72 72 72 72\n12 12 78 5 5 5 20 20 20 53 68 68 90 24 6 83 83 83 83 83 83\n16 16 27 38 49 49 64 75 86 97 79 79 90 101 6 94 94 105 10 21 21\n16 16 27 38 49 49 64 75 86 97 79 79 90 101 6 94 94 105 10 21 21\n32 32 43 54 65 65 80 11 106 95 22 22 33 44 55 55 70 1 96 85 85\n32 32 43 54 76 76 91 11 106 84 84 4 99 66 66 66 81 1 96 74 74\n14 14 3 98 87 87 102 11 73 73 73 4 99 88 77 77 92 92 63 63 63\n25 25 3 98 87 87 7 29 62 62 62 15 99 88 77 77 103 19 30 52 52\n36 36 47 58 69 69 18 29 40 51 51 26 37 48 59 59 8 19 30 41 41\n36 36 47 58 69 69 18 29 40 51 51 26 37 48 59 59 8 19 30 41 41", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1276, "cpu_time_ms": 9, "memory_kb": 1536}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s408415042", "group_id": "codeNet:p02859", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n\tint r; cin >> r;\n\tcout << r*r << endl;\n}", "language": "C++", "metadata": {"date": 1577772853, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02859.html", "problem_id": "p02859", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02859/input.txt", "sample_output_relpath": "derived/input_output/data/p02859/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02859/C++/s408415042.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s408415042", "user_id": "u734333003"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n\tint r; cin >> r;\n\tcout << r*r << endl;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nGiven is an integer r.\n\nHow many times is the area of a circle of radius r larger than the area of a circle of radius 1?\n\nIt can be proved that the answer is always an integer under the constraints given.\n\nConstraints\n\n1 \\leq r \\leq 100\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nr\n\nOutput\n\nPrint the area of a circle of radius r, divided by the area of a circle of radius 1, as an integer.\n\nSample Input 1\n\n2\n\nSample Output 1\n\n4\n\nThe area of a circle of radius 2 is 4 times larger than the area of a circle of radius 1.\n\nNote that output must be an integer - for example, 4.0 will not be accepted.\n\nSample Input 2\n\n100\n\nSample Output 2\n\n10000", "sample_input": "2\n"}, "reference_outputs": ["4\n"], "source_document_id": "p02859", "source_text": "Score : 100 points\n\nProblem Statement\n\nGiven is an integer r.\n\nHow many times is the area of a circle of radius r larger than the area of a circle of radius 1?\n\nIt can be proved that the answer is always an integer under the constraints given.\n\nConstraints\n\n1 \\leq r \\leq 100\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nr\n\nOutput\n\nPrint the area of a circle of radius r, divided by the area of a circle of radius 1, as an integer.\n\nSample Input 1\n\n2\n\nSample Output 1\n\n4\n\nThe area of a circle of radius 2 is 4 times larger than the area of a circle of radius 1.\n\nNote that output must be an integer - for example, 4.0 will not be accepted.\n\nSample Input 2\n\n100\n\nSample Output 2\n\n10000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 99, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s087453305", "group_id": "codeNet:p02859", "input_text": "#include <iostream>\nusing namespace std;\n\nint main() {\n\tint a;\n\tcin >> a;\n\tcout << a * a << '\\n';\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1573956082, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02859.html", "problem_id": "p02859", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02859/input.txt", "sample_output_relpath": "derived/input_output/data/p02859/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02859/C++/s087453305.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s087453305", "user_id": "u690769164"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <iostream>\nusing namespace std;\n\nint main() {\n\tint a;\n\tcin >> a;\n\tcout << a * a << '\\n';\n\treturn 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nGiven is an integer r.\n\nHow many times is the area of a circle of radius r larger than the area of a circle of radius 1?\n\nIt can be proved that the answer is always an integer under the constraints given.\n\nConstraints\n\n1 \\leq r \\leq 100\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nr\n\nOutput\n\nPrint the area of a circle of radius r, divided by the area of a circle of radius 1, as an integer.\n\nSample Input 1\n\n2\n\nSample Output 1\n\n4\n\nThe area of a circle of radius 2 is 4 times larger than the area of a circle of radius 1.\n\nNote that output must be an integer - for example, 4.0 will not be accepted.\n\nSample Input 2\n\n100\n\nSample Output 2\n\n10000", "sample_input": "2\n"}, "reference_outputs": ["4\n"], "source_document_id": "p02859", "source_text": "Score : 100 points\n\nProblem Statement\n\nGiven is an integer r.\n\nHow many times is the area of a circle of radius r larger than the area of a circle of radius 1?\n\nIt can be proved that the answer is always an integer under the constraints given.\n\nConstraints\n\n1 \\leq r \\leq 100\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nr\n\nOutput\n\nPrint the area of a circle of radius r, divided by the area of a circle of radius 1, as an integer.\n\nSample Input 1\n\n2\n\nSample Output 1\n\n4\n\nThe area of a circle of radius 2 is 4 times larger than the area of a circle of radius 1.\n\nNote that output must be an integer - for example, 4.0 will not be accepted.\n\nSample Input 2\n\n100\n\nSample Output 2\n\n10000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 110, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s914544013", "group_id": "codeNet:p02859", "input_text": "#include<iostream>\n#include<bits/stdc++.h>\n#include<string>\nusing namespace std;\nint main()\n{\n  int r ;\n  cin >> r  ;\n  \n  cout << r*r << endl ;\n  return 0 ;\n}", "language": "C++", "metadata": {"date": 1573956067, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02859.html", "problem_id": "p02859", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02859/input.txt", "sample_output_relpath": "derived/input_output/data/p02859/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02859/C++/s914544013.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s914544013", "user_id": "u904995051"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include<iostream>\n#include<bits/stdc++.h>\n#include<string>\nusing namespace std;\nint main()\n{\n  int r ;\n  cin >> r  ;\n  \n  cout << r*r << endl ;\n  return 0 ;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nGiven is an integer r.\n\nHow many times is the area of a circle of radius r larger than the area of a circle of radius 1?\n\nIt can be proved that the answer is always an integer under the constraints given.\n\nConstraints\n\n1 \\leq r \\leq 100\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nr\n\nOutput\n\nPrint the area of a circle of radius r, divided by the area of a circle of radius 1, as an integer.\n\nSample Input 1\n\n2\n\nSample Output 1\n\n4\n\nThe area of a circle of radius 2 is 4 times larger than the area of a circle of radius 1.\n\nNote that output must be an integer - for example, 4.0 will not be accepted.\n\nSample Input 2\n\n100\n\nSample Output 2\n\n10000", "sample_input": "2\n"}, "reference_outputs": ["4\n"], "source_document_id": "p02859", "source_text": "Score : 100 points\n\nProblem Statement\n\nGiven is an integer r.\n\nHow many times is the area of a circle of radius r larger than the area of a circle of radius 1?\n\nIt can be proved that the answer is always an integer under the constraints given.\n\nConstraints\n\n1 \\leq r \\leq 100\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nr\n\nOutput\n\nPrint the area of a circle of radius r, divided by the area of a circle of radius 1, as an integer.\n\nSample Input 1\n\n2\n\nSample Output 1\n\n4\n\nThe area of a circle of radius 2 is 4 times larger than the area of a circle of radius 1.\n\nNote that output must be an integer - for example, 4.0 will not be accepted.\n\nSample Input 2\n\n100\n\nSample Output 2\n\n10000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 159, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s049919791", "group_id": "codeNet:p02860", "input_text": "#include<iostream>\n#include<cstdlib>\n#include<utility>\n#include<tuple>\n#include<string>\n#include<vector>\n#include<numeric>\n#include<algorithm>\n#include<queue>\n#include<deque>\n#include<bitset>\n#include<cmath>\n#include<map>\nusing namespace std;\nusing ll = long long int;\nconst ll mod = 1e9 + 7;\n\nint main() {\n\n\tint n;\n\tstring s;\n\tcin >> n >> s;\n\n\tif (n % 2 != 0) {\n\t\tcout << \"No\" << endl;\n\t\treturn 0;\n\t}\n\n\tint m = n / 2;\n\tfor (int i = 0; i < n / 2; i++) {\n\t\tif (s[i] != s[i + m]) {\n\t\t\tcout << \"No\" << endl;\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\tcout << \"Yes\" << endl;\n\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1582789699, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02860.html", "problem_id": "p02860", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02860/input.txt", "sample_output_relpath": "derived/input_output/data/p02860/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02860/C++/s049919791.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s049919791", "user_id": "u870074807"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include<iostream>\n#include<cstdlib>\n#include<utility>\n#include<tuple>\n#include<string>\n#include<vector>\n#include<numeric>\n#include<algorithm>\n#include<queue>\n#include<deque>\n#include<bitset>\n#include<cmath>\n#include<map>\nusing namespace std;\nusing ll = long long int;\nconst ll mod = 1e9 + 7;\n\nint main() {\n\n\tint n;\n\tstring s;\n\tcin >> n >> s;\n\n\tif (n % 2 != 0) {\n\t\tcout << \"No\" << endl;\n\t\treturn 0;\n\t}\n\n\tint m = n / 2;\n\tfor (int i = 0; i < n / 2; i++) {\n\t\tif (s[i] != s[i + m]) {\n\t\t\tcout << \"No\" << endl;\n\t\t\treturn 0;\n\t\t}\n\t}\n\n\tcout << \"Yes\" << endl;\n\n\treturn 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nGiven are a positive integer N and a string S of length N consisting of lowercase English letters.\n\nDetermine whether the string is a concatenation of two copies of some string.\nThat is, determine whether there is a string T such that S = T + T.\n\nConstraints\n\n1 \\leq N \\leq 100\n\nS consists of lowercase English letters.\n\n|S| = N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS\n\nOutput\n\nIf S is a concatenation of two copies of some string, print Yes; otherwise, print No.\n\nSample Input 1\n\n6\nabcabc\n\nSample Output 1\n\nYes\n\nLet T = abc, and S = T + T.\n\nSample Input 2\n\n6\nabcadc\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n1\nz\n\nSample Output 3\n\nNo", "sample_input": "6\nabcabc\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p02860", "source_text": "Score : 200 points\n\nProblem Statement\n\nGiven are a positive integer N and a string S of length N consisting of lowercase English letters.\n\nDetermine whether the string is a concatenation of two copies of some string.\nThat is, determine whether there is a string T such that S = T + T.\n\nConstraints\n\n1 \\leq N \\leq 100\n\nS consists of lowercase English letters.\n\n|S| = N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS\n\nOutput\n\nIf S is a concatenation of two copies of some string, print Yes; otherwise, print No.\n\nSample Input 1\n\n6\nabcabc\n\nSample Output 1\n\nYes\n\nLet T = abc, and S = T + T.\n\nSample Input 2\n\n6\nabcadc\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n1\nz\n\nSample Output 3\n\nNo", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 563, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s979899179", "group_id": "codeNet:p02860", "input_text": "#include <iostream>\nusing namespace std;\nint main(void){\n  string ans = \"Yes\";\n  int n; cin >> n;\n  string s; cin >> s;\n  if(n % 2 != 0) ans = \"No\";\n  int k = n /2;\n  for(int i = 0; i < k; i++){\n    if(s.at(i) != s.at(i+k)) ans = \"No\";\n  }\n  cout << ans << endl;\n}\n", "language": "C++", "metadata": {"date": 1573956867, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02860.html", "problem_id": "p02860", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02860/input.txt", "sample_output_relpath": "derived/input_output/data/p02860/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02860/C++/s979899179.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s979899179", "user_id": "u327499140"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <iostream>\nusing namespace std;\nint main(void){\n  string ans = \"Yes\";\n  int n; cin >> n;\n  string s; cin >> s;\n  if(n % 2 != 0) ans = \"No\";\n  int k = n /2;\n  for(int i = 0; i < k; i++){\n    if(s.at(i) != s.at(i+k)) ans = \"No\";\n  }\n  cout << ans << endl;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nGiven are a positive integer N and a string S of length N consisting of lowercase English letters.\n\nDetermine whether the string is a concatenation of two copies of some string.\nThat is, determine whether there is a string T such that S = T + T.\n\nConstraints\n\n1 \\leq N \\leq 100\n\nS consists of lowercase English letters.\n\n|S| = N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS\n\nOutput\n\nIf S is a concatenation of two copies of some string, print Yes; otherwise, print No.\n\nSample Input 1\n\n6\nabcabc\n\nSample Output 1\n\nYes\n\nLet T = abc, and S = T + T.\n\nSample Input 2\n\n6\nabcadc\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n1\nz\n\nSample Output 3\n\nNo", "sample_input": "6\nabcabc\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p02860", "source_text": "Score : 200 points\n\nProblem Statement\n\nGiven are a positive integer N and a string S of length N consisting of lowercase English letters.\n\nDetermine whether the string is a concatenation of two copies of some string.\nThat is, determine whether there is a string T such that S = T + T.\n\nConstraints\n\n1 \\leq N \\leq 100\n\nS consists of lowercase English letters.\n\n|S| = N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS\n\nOutput\n\nIf S is a concatenation of two copies of some string, print Yes; otherwise, print No.\n\nSample Input 1\n\n6\nabcabc\n\nSample Output 1\n\nYes\n\nLet T = abc, and S = T + T.\n\nSample Input 2\n\n6\nabcadc\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n1\nz\n\nSample Output 3\n\nNo", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 265, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s430329549", "group_id": "codeNet:p02861", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n \nint facctorialMethod(int k){\n    int sum = 1;\n    for (int i = 1; i <= k; ++i)\n    {\n        sum *= i;\n    }\n    return sum;\n}\n\nint main(){\n  int n;\n  cin >> n;\n  vector<double>x(n);\n  vector<double>y(n);\n  for(int i=0;i<n;i++){\n    cin >> x.at(i) >> y.at(i);\n  }\n  vector<int>in(n);\n  for(int i=0;i<n;i++){\n    in.at(i)=i;\n  }\n  double ans=0;\n  for(int i=0;i<n;i++){\n    for(int j=0;j<n;j++){\n      double x_long=pow(x.at(i)-x.at(j),2.0);\n      double y_long=pow(y.at(i)-y.at(j),2.0);\n      ans+=sqrt(x_long+y_long);\n    }\n  }\n  ans/=facctorialMethod(n);\n  ans*=facctorialMethod(n-1);\n  cout << fixed << setprecision(10);\n  cout << ans << endl;\n}", "language": "C++", "metadata": {"date": 1591515278, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02861.html", "problem_id": "p02861", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02861/input.txt", "sample_output_relpath": "derived/input_output/data/p02861/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02861/C++/s430329549.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s430329549", "user_id": "u191114518"}, "prompt_components": {"gold_output": "2.2761423749\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n \nint facctorialMethod(int k){\n    int sum = 1;\n    for (int i = 1; i <= k; ++i)\n    {\n        sum *= i;\n    }\n    return sum;\n}\n\nint main(){\n  int n;\n  cin >> n;\n  vector<double>x(n);\n  vector<double>y(n);\n  for(int i=0;i<n;i++){\n    cin >> x.at(i) >> y.at(i);\n  }\n  vector<int>in(n);\n  for(int i=0;i<n;i++){\n    in.at(i)=i;\n  }\n  double ans=0;\n  for(int i=0;i<n;i++){\n    for(int j=0;j<n;j++){\n      double x_long=pow(x.at(i)-x.at(j),2.0);\n      double y_long=pow(y.at(i)-y.at(j),2.0);\n      ans+=sqrt(x_long+y_long);\n    }\n  }\n  ans/=facctorialMethod(n);\n  ans*=facctorialMethod(n-1);\n  cout << fixed << setprecision(10);\n  cout << ans << endl;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N towns in a coordinate plane. Town i is located at coordinates (x_i, y_i). The distance between Town i and Town j is \\sqrt{\\left(x_i-x_j\\right)^2+\\left(y_i-y_j\\right)^2}.\n\nThere are N! possible paths to visit all of these towns once. Let the length of a path be the distance covered when we start at the first town in the path, visit the second, third, \\dots, towns, and arrive at the last town (assume that we travel in a straight line from a town to another). Compute the average length of these N! paths.\n\nConstraints\n\n2 \\leq N \\leq 8\n\n-1000 \\leq x_i \\leq 1000\n\n-1000 \\leq y_i \\leq 1000\n\n\\left(x_i, y_i\\right) \\neq \\left(x_j, y_j\\right) (if i \\neq j)\n\n(Added 21:12 JST) All values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nx_1 y_1\n:\nx_N y_N\n\nOutput\n\nPrint the average length of the paths.\nYour output will be judges as correct when the absolute difference from the judge's output is at most 10^{-6}.\n\nSample Input 1\n\n3\n0 0\n1 0\n0 1\n\nSample Output 1\n\n2.2761423749\n\nThere are six paths to visit the towns: 1 → 2 → 3, 1 → 3 → 2, 2 → 1 → 3, 2 → 3 → 1, 3 → 1 → 2, and 3 → 2 → 1.\n\nThe length of the path 1 → 2 → 3 is \\sqrt{\\left(0-1\\right)^2+\\left(0-0\\right)^2} + \\sqrt{\\left(1-0\\right)^2+\\left(0-1\\right)^2} = 1+\\sqrt{2}.\n\nBy calculating the lengths of the other paths in this way, we see that the average length of all routes is:\n\n\\frac{\\left(1+\\sqrt{2}\\right)+\\left(1+\\sqrt{2}\\right)+\\left(2\\right)+\\left(1+\\sqrt{2}\\right)+\\left(2\\right)+\\left(1+\\sqrt{2}\\right)}{6} = 2.276142...\n\nSample Input 2\n\n2\n-879 981\n-866 890\n\nSample Output 2\n\n91.9238815543\n\nThere are two paths to visit the towns: 1 → 2 and 2 → 1. These paths have the same length.\n\nSample Input 3\n\n8\n-406 10\n512 859\n494 362\n-955 -475\n128 553\n-986 -885\n763 77\n449 310\n\nSample Output 3\n\n7641.9817824387", "sample_input": "3\n0 0\n1 0\n0 1\n"}, "reference_outputs": ["2.2761423749\n"], "source_document_id": "p02861", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N towns in a coordinate plane. Town i is located at coordinates (x_i, y_i). The distance between Town i and Town j is \\sqrt{\\left(x_i-x_j\\right)^2+\\left(y_i-y_j\\right)^2}.\n\nThere are N! possible paths to visit all of these towns once. Let the length of a path be the distance covered when we start at the first town in the path, visit the second, third, \\dots, towns, and arrive at the last town (assume that we travel in a straight line from a town to another). Compute the average length of these N! paths.\n\nConstraints\n\n2 \\leq N \\leq 8\n\n-1000 \\leq x_i \\leq 1000\n\n-1000 \\leq y_i \\leq 1000\n\n\\left(x_i, y_i\\right) \\neq \\left(x_j, y_j\\right) (if i \\neq j)\n\n(Added 21:12 JST) All values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nx_1 y_1\n:\nx_N y_N\n\nOutput\n\nPrint the average length of the paths.\nYour output will be judges as correct when the absolute difference from the judge's output is at most 10^{-6}.\n\nSample Input 1\n\n3\n0 0\n1 0\n0 1\n\nSample Output 1\n\n2.2761423749\n\nThere are six paths to visit the towns: 1 → 2 → 3, 1 → 3 → 2, 2 → 1 → 3, 2 → 3 → 1, 3 → 1 → 2, and 3 → 2 → 1.\n\nThe length of the path 1 → 2 → 3 is \\sqrt{\\left(0-1\\right)^2+\\left(0-0\\right)^2} + \\sqrt{\\left(1-0\\right)^2+\\left(0-1\\right)^2} = 1+\\sqrt{2}.\n\nBy calculating the lengths of the other paths in this way, we see that the average length of all routes is:\n\n\\frac{\\left(1+\\sqrt{2}\\right)+\\left(1+\\sqrt{2}\\right)+\\left(2\\right)+\\left(1+\\sqrt{2}\\right)+\\left(2\\right)+\\left(1+\\sqrt{2}\\right)}{6} = 2.276142...\n\nSample Input 2\n\n2\n-879 981\n-866 890\n\nSample Output 2\n\n91.9238815543\n\nThere are two paths to visit the towns: 1 → 2 and 2 → 1. These paths have the same length.\n\nSample Input 3\n\n8\n-406 10\n512 859\n494 362\n-955 -475\n128 553\n-986 -885\n763 77\n449 310\n\nSample Output 3\n\n7641.9817824387", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 695, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s512760593", "group_id": "codeNet:p02862", "input_text": "#include <iostream>\n#define rep(i,n)  for (int i=1;i<=n;i++)\n\nusing namespace std;\nlong int d=1000000000+7;\nint main()\n{\nlong int x,y;\ncin>>x>>y;\nif ((x+y)%3!=0)\ncout <<0;\nelse\n{long int a,b;\na=(2*y-x)/3;\nb=(2*x-y)/3;\nlong int a0=1,a1=1;\nrep(i,a)\na1*=i;\nrep(i,a)\na0*=(a+b-i+1);\ncout <<(a0/a1)%d;\n}\n\n\n\n}", "language": "C++", "metadata": {"date": 1574020258, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02862.html", "problem_id": "p02862", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02862/input.txt", "sample_output_relpath": "derived/input_output/data/p02862/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02862/C++/s512760593.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s512760593", "user_id": "u437083392"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <iostream>\n#define rep(i,n)  for (int i=1;i<=n;i++)\n\nusing namespace std;\nlong int d=1000000000+7;\nint main()\n{\nlong int x,y;\ncin>>x>>y;\nif ((x+y)%3!=0)\ncout <<0;\nelse\n{long int a,b;\na=(2*y-x)/3;\nb=(2*x-y)/3;\nlong int a0=1,a1=1;\nrep(i,a)\na1*=i;\nrep(i,a)\na0*=(a+b-i+1);\ncout <<(a0/a1)%d;\n}\n\n\n\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nThere is a knight - the chess piece - at the origin (0, 0) of a two-dimensional grid.\n\nWhen the knight is at the square (i, j), it can be moved to either (i+1,j+2) or (i+2, j+1).\n\nIn how many ways can the knight reach the square (X, Y)?\n\nFind the number of ways modulo 10^9 + 7.\n\nConstraints\n\n1 \\leq X \\leq 10^6\n\n1 \\leq Y \\leq 10^6\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX Y\n\nOutput\n\nPrint the number of ways for the knight to reach (X, Y) from (0, 0), modulo 10^9 + 7.\n\nSample Input 1\n\n3 3\n\nSample Output 1\n\n2\n\nThere are two ways: (0,0) \\to (1,2) \\to (3,3) and (0,0) \\to (2,1) \\to (3,3).\n\nSample Input 2\n\n2 2\n\nSample Output 2\n\n0\n\nThe knight cannot reach (2,2).\n\nSample Input 3\n\n999999 999999\n\nSample Output 3\n\n151840682\n\nPrint the number of ways modulo 10^9 + 7.", "sample_input": "3 3\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02862", "source_text": "Score : 400 points\n\nProblem Statement\n\nThere is a knight - the chess piece - at the origin (0, 0) of a two-dimensional grid.\n\nWhen the knight is at the square (i, j), it can be moved to either (i+1,j+2) or (i+2, j+1).\n\nIn how many ways can the knight reach the square (X, Y)?\n\nFind the number of ways modulo 10^9 + 7.\n\nConstraints\n\n1 \\leq X \\leq 10^6\n\n1 \\leq Y \\leq 10^6\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX Y\n\nOutput\n\nPrint the number of ways for the knight to reach (X, Y) from (0, 0), modulo 10^9 + 7.\n\nSample Input 1\n\n3 3\n\nSample Output 1\n\n2\n\nThere are two ways: (0,0) \\to (1,2) \\to (3,3) and (0,0) \\to (2,1) \\to (3,3).\n\nSample Input 2\n\n2 2\n\nSample Output 2\n\n0\n\nThe knight cannot reach (2,2).\n\nSample Input 3\n\n999999 999999\n\nSample Output 3\n\n151840682\n\nPrint the number of ways modulo 10^9 + 7.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 302, "cpu_time_ms": 116, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s497358256", "group_id": "codeNet:p02866", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef pair<ll, ll> l_l;\ntypedef pair<int, int> i_i;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define EPS (1e-7)\n#define INF (1e9)\n#define PI (acos(-1))\n\nconst ll mod = 998244353;\n\nll safePow(ll x, ll y){\n    ll result = 1;\n    rep(i, y){\n        result = (result * x) % mod;\n    }\n    return result;\n}\n\nint main() {\n    int n;\n    cin >> n;\n    vector<int> d(n);\n    rep(i, n) cin >> d[i];\n    if(d[0] != 0){\n        cout << 0 << endl;\n        return 0;\n    }\n    sort(d.begin(), d.end());\n    if(d[1] != 1){\n        cout << 0 << endl;\n        return 0;\n    }\n\n    ll cnt = 0, cur_d = 0, prev_cnt = 1;\n    ll ans = 1;\n    rep(i, n){\n        if(d[i] == cur_d){\n            cnt++;\n        } else {\n            if(d[i] != cur_d + 1){\n                ans = 0;\n                break;\n            }\n            ans = (ans * safePow(prev_cnt, cnt)) % mod;\n            prev_cnt = cnt;\n            cnt = 1;\n            cur_d++;\n        }\n        if(i == n - 1){\n            ans = (ans * safePow(prev_cnt, cnt)) % mod;\n        }\n    }\n    cout << ans << endl;\n\n    \n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1592113551, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02866.html", "problem_id": "p02866", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02866/input.txt", "sample_output_relpath": "derived/input_output/data/p02866/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02866/C++/s497358256.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s497358256", "user_id": "u225642513"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef pair<ll, ll> l_l;\ntypedef pair<int, int> i_i;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define EPS (1e-7)\n#define INF (1e9)\n#define PI (acos(-1))\n\nconst ll mod = 998244353;\n\nll safePow(ll x, ll y){\n    ll result = 1;\n    rep(i, y){\n        result = (result * x) % mod;\n    }\n    return result;\n}\n\nint main() {\n    int n;\n    cin >> n;\n    vector<int> d(n);\n    rep(i, n) cin >> d[i];\n    if(d[0] != 0){\n        cout << 0 << endl;\n        return 0;\n    }\n    sort(d.begin(), d.end());\n    if(d[1] != 1){\n        cout << 0 << endl;\n        return 0;\n    }\n\n    ll cnt = 0, cur_d = 0, prev_cnt = 1;\n    ll ans = 1;\n    rep(i, n){\n        if(d[i] == cur_d){\n            cnt++;\n        } else {\n            if(d[i] != cur_d + 1){\n                ans = 0;\n                break;\n            }\n            ans = (ans * safePow(prev_cnt, cnt)) % mod;\n            prev_cnt = cnt;\n            cnt = 1;\n            cur_d++;\n        }\n        if(i == n - 1){\n            ans = (ans * safePow(prev_cnt, cnt)) % mod;\n        }\n    }\n    cout << ans << endl;\n\n    \n    return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nGiven is an integer sequence D_1,...,D_N of N elements. Find the number, modulo 998244353, of trees with N vertices numbered 1 to N that satisfy the following condition:\n\nFor every integer i from 1 to N, the distance between Vertex 1 and Vertex i is D_i.\n\nNotes\n\nA tree of N vertices is a connected undirected graph with N vertices and N-1 edges, and the distance between two vertices are the number of edges in the shortest path between them.\n\nTwo trees are considered different if and only if there are two vertices x and y such that there is an edge between x and y in one of those trees and not in the other.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n0 \\leq D_i \\leq N-1\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nD_1 D_2 ... D_N\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n4\n0 1 1 2\n\nSample Output 1\n\n2\n\nFor example, a tree with edges (1,2), (1,3), and (2,4) satisfies the condition.\n\nSample Input 2\n\n4\n1 1 1 1\n\nSample Output 2\n\n0\n\nSample Input 3\n\n7\n0 3 2 1 2 2 1\n\nSample Output 3\n\n24", "sample_input": "4\n0 1 1 2\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02866", "source_text": "Score : 300 points\n\nProblem Statement\n\nGiven is an integer sequence D_1,...,D_N of N elements. Find the number, modulo 998244353, of trees with N vertices numbered 1 to N that satisfy the following condition:\n\nFor every integer i from 1 to N, the distance between Vertex 1 and Vertex i is D_i.\n\nNotes\n\nA tree of N vertices is a connected undirected graph with N vertices and N-1 edges, and the distance between two vertices are the number of edges in the shortest path between them.\n\nTwo trees are considered different if and only if there are two vertices x and y such that there is an edge between x and y in one of those trees and not in the other.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n0 \\leq D_i \\leq N-1\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nD_1 D_2 ... D_N\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n4\n0 1 1 2\n\nSample Output 1\n\n2\n\nFor example, a tree with edges (1,2), (1,3), and (2,4) satisfies the condition.\n\nSample Input 2\n\n4\n1 1 1 1\n\nSample Output 2\n\n0\n\nSample Input 3\n\n7\n0 3 2 1 2 2 1\n\nSample Output 3\n\n24", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1186, "cpu_time_ms": 35, "memory_kb": 768}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s361451403", "group_id": "codeNet:p02866", "input_text": "#include <iostream>\n#include <cmath>\n\nusing namespace std;\nstatic const int MAX = 100000;\n\nint main(void) {\n  long long int N, i, Ds[MAX], Es[MAX];\n  long long int ans = 1;\n  cin >> N;\n  for (i=0;i<N;i++) {\n    cin >> Ds[i];\n    Es[Ds[i]] ++;\n  }\n\n  if (Ds[0] != 0 && Es[0] != 1) {\n    cout << 0 << endl;\n    return 0;\n  }\n\n  for (i=0;i<N-1;i++) {\n    if (Es[i] == 0) break;\n    ans *= pow(Es[i], Es[i+1]);\n  }\n\n  cout << (ans % 998244353) << endl;\n\n}\n", "language": "C++", "metadata": {"date": 1573353605, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02866.html", "problem_id": "p02866", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02866/input.txt", "sample_output_relpath": "derived/input_output/data/p02866/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02866/C++/s361451403.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s361451403", "user_id": "u015318452"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <iostream>\n#include <cmath>\n\nusing namespace std;\nstatic const int MAX = 100000;\n\nint main(void) {\n  long long int N, i, Ds[MAX], Es[MAX];\n  long long int ans = 1;\n  cin >> N;\n  for (i=0;i<N;i++) {\n    cin >> Ds[i];\n    Es[Ds[i]] ++;\n  }\n\n  if (Ds[0] != 0 && Es[0] != 1) {\n    cout << 0 << endl;\n    return 0;\n  }\n\n  for (i=0;i<N-1;i++) {\n    if (Es[i] == 0) break;\n    ans *= pow(Es[i], Es[i+1]);\n  }\n\n  cout << (ans % 998244353) << endl;\n\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nGiven is an integer sequence D_1,...,D_N of N elements. Find the number, modulo 998244353, of trees with N vertices numbered 1 to N that satisfy the following condition:\n\nFor every integer i from 1 to N, the distance between Vertex 1 and Vertex i is D_i.\n\nNotes\n\nA tree of N vertices is a connected undirected graph with N vertices and N-1 edges, and the distance between two vertices are the number of edges in the shortest path between them.\n\nTwo trees are considered different if and only if there are two vertices x and y such that there is an edge between x and y in one of those trees and not in the other.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n0 \\leq D_i \\leq N-1\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nD_1 D_2 ... D_N\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n4\n0 1 1 2\n\nSample Output 1\n\n2\n\nFor example, a tree with edges (1,2), (1,3), and (2,4) satisfies the condition.\n\nSample Input 2\n\n4\n1 1 1 1\n\nSample Output 2\n\n0\n\nSample Input 3\n\n7\n0 3 2 1 2 2 1\n\nSample Output 3\n\n24", "sample_input": "4\n0 1 1 2\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02866", "source_text": "Score : 300 points\n\nProblem Statement\n\nGiven is an integer sequence D_1,...,D_N of N elements. Find the number, modulo 998244353, of trees with N vertices numbered 1 to N that satisfy the following condition:\n\nFor every integer i from 1 to N, the distance between Vertex 1 and Vertex i is D_i.\n\nNotes\n\nA tree of N vertices is a connected undirected graph with N vertices and N-1 edges, and the distance between two vertices are the number of edges in the shortest path between them.\n\nTwo trees are considered different if and only if there are two vertices x and y such that there is an edge between x and y in one of those trees and not in the other.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n0 \\leq D_i \\leq N-1\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nD_1 D_2 ... D_N\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n4\n0 1 1 2\n\nSample Output 1\n\n2\n\nFor example, a tree with edges (1,2), (1,3), and (2,4) satisfies the condition.\n\nSample Input 2\n\n4\n1 1 1 1\n\nSample Output 2\n\n0\n\nSample Input 3\n\n7\n0 3 2 1 2 2 1\n\nSample Output 3\n\n24", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 452, "cpu_time_ms": 31, "memory_kb": 1920}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s450792859", "group_id": "codeNet:p02866", "input_text": "#include<iostream>\n#include<string>\n#include<iomanip>\n#include<cmath>\n#include<vector>\n#include<algorithm>\n\nusing namespace std;\n\n#define int long long\n#define endl \"\\n\"\n\nconst long long INF = (long long)1e18;\nconst long long MOD = 998244353; \n\nstring yn(bool f){return f?\"Yes\":\"No\";}\nstring YN(bool f){return f?\"YES\":\"NO\";}\n\n\n\nlong long power(long long x, long long n){\n\tlong long ans = 1;\n\tfor(;n;n>>=1,x*=x,ans%=MOD,x%=MOD)\n\t\tif(n&1)ans*=x;\n\treturn ans%MOD;\n}\n\n\n\nsigned main(){\n\tcin.tie(nullptr);\n\tios::sync_with_stdio(false);\n\tcout<<fixed<<setprecision(10);\n\t\n\tint N, zero = 0, maximum = 0;\n\tvector<int> D;\n\tvector<int> con;\n\t\n\tcin>>N;\n\t\n\tD.resize(N);\n\tcon.resize(N);\n\t\n\tfor(int i = 0; i < N; i++){\n\t\tcin>>D[i];\n\t\t// if(!D[i])zero++;\n\t\tcon[D[i]]++;\n\t\tmaximum = max(maximum, D[i]);\n\t}\n\t\n\tif(D[0]){\n\t\tcout<<0<<endl;\n\t} else if(con[0] >= 2){\n\t\tcout<<0<<endl;\n\t} else {\n\t\tint ans = 1;\n\t\t\n\t\tfor(int i = 1; i <= maximum; i++){\n\t\t\tif(con[i] == 0) ans = 0;\n\t\t\t// else ans *= power(i, con[i]);\n\t\t\telse ans *= power(con[i-1], con[i]);\n\t\t\t\n\t\t\tans %= MOD;\n\t\t}\n\t\t\n\t\tcout<<ans<<endl;\n\t}\n\t\n\t\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1573353154, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02866.html", "problem_id": "p02866", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02866/input.txt", "sample_output_relpath": "derived/input_output/data/p02866/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02866/C++/s450792859.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s450792859", "user_id": "u233393801"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include<iostream>\n#include<string>\n#include<iomanip>\n#include<cmath>\n#include<vector>\n#include<algorithm>\n\nusing namespace std;\n\n#define int long long\n#define endl \"\\n\"\n\nconst long long INF = (long long)1e18;\nconst long long MOD = 998244353; \n\nstring yn(bool f){return f?\"Yes\":\"No\";}\nstring YN(bool f){return f?\"YES\":\"NO\";}\n\n\n\nlong long power(long long x, long long n){\n\tlong long ans = 1;\n\tfor(;n;n>>=1,x*=x,ans%=MOD,x%=MOD)\n\t\tif(n&1)ans*=x;\n\treturn ans%MOD;\n}\n\n\n\nsigned main(){\n\tcin.tie(nullptr);\n\tios::sync_with_stdio(false);\n\tcout<<fixed<<setprecision(10);\n\t\n\tint N, zero = 0, maximum = 0;\n\tvector<int> D;\n\tvector<int> con;\n\t\n\tcin>>N;\n\t\n\tD.resize(N);\n\tcon.resize(N);\n\t\n\tfor(int i = 0; i < N; i++){\n\t\tcin>>D[i];\n\t\t// if(!D[i])zero++;\n\t\tcon[D[i]]++;\n\t\tmaximum = max(maximum, D[i]);\n\t}\n\t\n\tif(D[0]){\n\t\tcout<<0<<endl;\n\t} else if(con[0] >= 2){\n\t\tcout<<0<<endl;\n\t} else {\n\t\tint ans = 1;\n\t\t\n\t\tfor(int i = 1; i <= maximum; i++){\n\t\t\tif(con[i] == 0) ans = 0;\n\t\t\t// else ans *= power(i, con[i]);\n\t\t\telse ans *= power(con[i-1], con[i]);\n\t\t\t\n\t\t\tans %= MOD;\n\t\t}\n\t\t\n\t\tcout<<ans<<endl;\n\t}\n\t\n\t\n\treturn 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nGiven is an integer sequence D_1,...,D_N of N elements. Find the number, modulo 998244353, of trees with N vertices numbered 1 to N that satisfy the following condition:\n\nFor every integer i from 1 to N, the distance between Vertex 1 and Vertex i is D_i.\n\nNotes\n\nA tree of N vertices is a connected undirected graph with N vertices and N-1 edges, and the distance between two vertices are the number of edges in the shortest path between them.\n\nTwo trees are considered different if and only if there are two vertices x and y such that there is an edge between x and y in one of those trees and not in the other.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n0 \\leq D_i \\leq N-1\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nD_1 D_2 ... D_N\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n4\n0 1 1 2\n\nSample Output 1\n\n2\n\nFor example, a tree with edges (1,2), (1,3), and (2,4) satisfies the condition.\n\nSample Input 2\n\n4\n1 1 1 1\n\nSample Output 2\n\n0\n\nSample Input 3\n\n7\n0 3 2 1 2 2 1\n\nSample Output 3\n\n24", "sample_input": "4\n0 1 1 2\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02866", "source_text": "Score : 300 points\n\nProblem Statement\n\nGiven is an integer sequence D_1,...,D_N of N elements. Find the number, modulo 998244353, of trees with N vertices numbered 1 to N that satisfy the following condition:\n\nFor every integer i from 1 to N, the distance between Vertex 1 and Vertex i is D_i.\n\nNotes\n\nA tree of N vertices is a connected undirected graph with N vertices and N-1 edges, and the distance between two vertices are the number of edges in the shortest path between them.\n\nTwo trees are considered different if and only if there are two vertices x and y such that there is an edge between x and y in one of those trees and not in the other.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n0 \\leq D_i \\leq N-1\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nD_1 D_2 ... D_N\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n4\n0 1 1 2\n\nSample Output 1\n\n2\n\nFor example, a tree with edges (1,2), (1,3), and (2,4) satisfies the condition.\n\nSample Input 2\n\n4\n1 1 1 1\n\nSample Output 2\n\n0\n\nSample Input 3\n\n7\n0 3 2 1 2 2 1\n\nSample Output 3\n\n24", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1093, "cpu_time_ms": 10, "memory_kb": 1792}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s261353045", "group_id": "codeNet:p02867", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n#define rep(i, n) for (ll i = 0; i < (ll)(n); i++)\n\nint main()\n{\nll n ;\ncin >> n ;\nvector<pair<ll,ll>> a;\nrep(i, n){\n  ll x ;\n  cin >> x ;\n  a.emplace_back(x,i);\n}\nvector<pair<ll,ll>> b;\nrep(i, n){\n  ll x ;\n  cin >> x ;\n  b.emplace_back(x,i);\n}\nsort(a.begin(),a.end());\nsort(b.begin(),b.end());\nrep(i,n){\n  if(a[i].first>b[i].first){\n    cout << \"No\" << endl;\n    return 0;\n  }\n}\n\nset<ll> s;\ns.insert(b[0].second);\nbool ok=0;\nll ind=0;\nrep(i,n){\n  if(i>ind){\n    s.clear();\n    ind=i;\n  }\n  while(ind!=n-1){\n    if(b[ind].second>=a[ind+1].second){\n      ind++;\n      s.insert(b[ind+1].second);\n    }\n    else break;\n  }\n  if(s.find(a[i].second)!=s.end())ok=1;\n}\nif(ok){\n  cout << \"Yes\" << endl;\n}\nelse{\n  cout << \"No\" << endl;\n}\nreturn 0;\n}", "language": "C++", "metadata": {"date": 1573360670, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02867.html", "problem_id": "p02867", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02867/input.txt", "sample_output_relpath": "derived/input_output/data/p02867/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02867/C++/s261353045.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s261353045", "user_id": "u419307948"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n#define rep(i, n) for (ll i = 0; i < (ll)(n); i++)\n\nint main()\n{\nll n ;\ncin >> n ;\nvector<pair<ll,ll>> a;\nrep(i, n){\n  ll x ;\n  cin >> x ;\n  a.emplace_back(x,i);\n}\nvector<pair<ll,ll>> b;\nrep(i, n){\n  ll x ;\n  cin >> x ;\n  b.emplace_back(x,i);\n}\nsort(a.begin(),a.end());\nsort(b.begin(),b.end());\nrep(i,n){\n  if(a[i].first>b[i].first){\n    cout << \"No\" << endl;\n    return 0;\n  }\n}\n\nset<ll> s;\ns.insert(b[0].second);\nbool ok=0;\nll ind=0;\nrep(i,n){\n  if(i>ind){\n    s.clear();\n    ind=i;\n  }\n  while(ind!=n-1){\n    if(b[ind].second>=a[ind+1].second){\n      ind++;\n      s.insert(b[ind+1].second);\n    }\n    else break;\n  }\n  if(s.find(a[i].second)!=s.end())ok=1;\n}\nif(ok){\n  cout << \"Yes\" << endl;\n}\nelse{\n  cout << \"No\" << endl;\n}\nreturn 0;\n}", "problem_context": "Score : 600 points\n\nProblem Statement\n\nGiven are two integer sequences of N elements each: A_1,...,A_N and B_1,...,B_N.\nDetermine if it is possible to do the following operation at most N-2 times (possibly zero) so that, for every integer i from 1 to N, A_i \\leq B_i holds:\n\nChoose two distinct integers x and y between 1 and N (inclusive), and swap the values of A_x and A_y.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n1 \\leq A_i,B_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\nB_1 B_2 ... B_N\n\nOutput\n\nIf the objective is achievable, print Yes; if it is not, print No.\n\nSample Input 1\n\n3\n1 3 2\n1 2 3\n\nSample Output 1\n\nYes\n\nWe should swap the values of A_2 and A_3.\n\nSample Input 2\n\n3\n1 2 3\n2 2 2\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n6\n3 1 2 6 3 4\n2 2 8 3 4 3\n\nSample Output 3\n\nYes", "sample_input": "3\n1 3 2\n1 2 3\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p02867", "source_text": "Score : 600 points\n\nProblem Statement\n\nGiven are two integer sequences of N elements each: A_1,...,A_N and B_1,...,B_N.\nDetermine if it is possible to do the following operation at most N-2 times (possibly zero) so that, for every integer i from 1 to N, A_i \\leq B_i holds:\n\nChoose two distinct integers x and y between 1 and N (inclusive), and swap the values of A_x and A_y.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n1 \\leq A_i,B_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\nB_1 B_2 ... B_N\n\nOutput\n\nIf the objective is achievable, print Yes; if it is not, print No.\n\nSample Input 1\n\n3\n1 3 2\n1 2 3\n\nSample Output 1\n\nYes\n\nWe should swap the values of A_2 and A_3.\n\nSample Input 2\n\n3\n1 2 3\n2 2 2\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n6\n3 1 2 6 3 4\n2 2 8 3 4 3\n\nSample Output 3\n\nYes", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 808, "cpu_time_ms": 142, "memory_kb": 8048}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s990460005", "group_id": "codeNet:p02867", "input_text": "#define _CRT_SECURE_NO_WARNINGS\n#include \"bits/stdc++.h\"\n#if defined(_MSC_VER) || defined(ONLINE_JUDGE)\n#define getchar_unlocked _getchar_nolock\n#define putchar_unlocked _putchar_nolock\n#endif\n#define rep(i, n) for(int i=0; i<(n); ++i)\n#define FOR(i, m, n) for(int i=(m); i<(n); ++i)\n#define sz(x) ((int)(x).size())\n#define all(x) (x).begin(),(x).end()\n#define rall(x) (x).rbegin(),(x).rend()\n#define mp make_pair\n#define pb push_back\n#define eb emplace_back\n\nusing namespace std;\nusing LL = long long;\t\tusing VB = vector<bool>;\nusing VI = vector<int>;\t\tusing VL = vector<LL>;\nusing VS = vector<string>;\tusing VD = vector<double>;\nusing VVI = vector<VI>;\t\tusing VVL = vector<VL>;\nusing PII = pair<int, int>;\tusing PLL = pair<LL, LL>;\nusing VP = vector<PII>;\t\tusing VPL = vector<PLL>;\nconst int inf = (int)1e9;\nconst LL inf_ll = (LL)1e18, MOD = 1000000007;\nconst double PI = acos(-1.0), EPS = 1e-12;\n\ntemplate<class T>void Sort(T& a) { sort(all(a)); }\ntemplate<class T>void RSort(T& a) { sort(rall(a)); }\ntemplate<class T>void Reverse(T& a) { reverse(all(a)); }\ntemplate<class T>void Unique(T& a) { a.erase(unique(all(a)), a.end()); }\ntemplate<class T>T Sorted(T a) { Sort(a); return a; }\ntemplate<class T>T RSorted(T a) { RSort(a); return a; }\ntemplate<class T>T Reversed(T a) { Reverse(a); return a; }\ntemplate<class T>T Uniqued(T a) { Unique(a); return a; }\ntemplate<class T>auto Max(const T& a) { return *max_element(all(a)); }\ntemplate<class T>auto Min(const T& a) { return *min_element(all(a)); }\ntemplate<class T>int MaxPos(const T& a) { return max_element(all(a)) - a.begin(); }\ntemplate<class T>int MinPos(const T& a) { return min_element(all(a)) - a.begin(); }\ntemplate<class T, class U>int Count(const T& a, const  U& v) { return count(all(a), v); }\ntemplate<class T, class U>int Find(const T& a, const U& v) { auto pos = find(all(a), v); return pos == a.end() ? -1 : pos - a.begin(); }\ntemplate<class T, class U>U Sum(const T& a, const U& v) { return accumulate(all(a), v); }\ntemplate<class T, class U>int Lower(const T& a, const U& v) { return lower_bound(all(a), v) - a.begin(); }\ntemplate<class T, class U>int Upper(const T& a, const U& v) { return upper_bound(all(a), v) - a.begin(); }\ntemplate<class T, class P>void RemoveIf(T& a, P f) { a.erase(remove_if(all(a), f), a.end()); }\ntemplate<class T>T Age(T n, T m) { return (n + m - 1) / m; }\ntemplate<class T>T Gcd(T n, T m) { return m ? Gcd(m, n % m) : n; }\ntemplate<class T>T Lcm(T n, T m) { return n / Gcd(n, m) * m; }\ntemplate<class T>T Pow(T a, T n) { T r = 1; while (n > 0) { if (n & 1)r *= a; a *= a; n /= 2; }return r; }\ntemplate<class T>T Powmod(T a, T n, T m = MOD) { T r = 1; while (n > 0) { if (n & 1)r = r * a % m, n--; else a = a * a % m, n /= 2; }return r; }\ntemplate<class T>bool chmax(T& a, const T& b) { if (a < b) { a = b; return true; } return false; }\ntemplate<class T>bool chmin(T& a, const T& b) { if (a > b) { a = b; return true; } return false; }\nstring operator*(string s, int n) { string ret; rep(i, n)ret += s; return ret; }\n\n// --- input --- //\ntemplate<class T>T InputF() { T ret; cin >> ret; return ret; }\ntemplate<> char InputF() {\n\tchar ret = '\\0', c = getchar_unlocked();\n\twhile (c != '\\0' && c != '\\n' && c != '\\t' && c != ' ') { ret = c; c = getchar_unlocked(); }\n\treturn ret;\n}\ntemplate<> string InputF() {\n\tstring ret; char c = getchar_unlocked();\n\twhile (c != '\\0' && c != '\\n' && c != '\\t' && c != ' ') { ret.push_back(c); c = getchar_unlocked(); }\n\treturn ret;\n}\ntemplate<> int InputF() {\n\tint ret = 0; bool neg = false; char c = getchar_unlocked();\n\tif (c == '-') { neg = true; c = getchar_unlocked(); }\n\twhile (isdigit(c)) { ret = ret * 10 + (c - '0'); c = getchar_unlocked(); }\n\treturn neg ? -ret : ret;\n}\ntemplate<> LL InputF() {\n\tLL ret = 0; bool neg = false; char c = getchar_unlocked();\n\tif (c == '-') { neg = true; c = getchar_unlocked(); }\n\twhile (isdigit(c)) { ret = ret * 10LL + (LL(c) - LL('0')); c = getchar_unlocked(); }\n\treturn neg ? -ret : ret;\n}\ntemplate<> double InputF() {\n\tdouble ret = 0, dp = 1; bool neg = false, adp = false; char c = getchar_unlocked();\n\tif (c == '-') { neg = true; c = getchar_unlocked(); }\n\twhile (isdigit(c) || c == '.') {\n\t\tif (c == '.')adp = true;\n\t\telse if (adp)ret += (c - '0') * (dp *= 0.1);\n\t\telse ret = ret * 10.0 + (c - '0');\n\t\tc = getchar_unlocked();\n\t}\n\treturn neg ? -ret : ret;\n}\nstring GetLine() {\n\tstring ret; char c = getchar_unlocked();\n\twhile (c != '\\0' && c != '\\n') { ret.push_back(c); c = getchar_unlocked(); }\n\treturn ret;\n}\nstruct Input {\n\tstruct InputV {\n\t\tint n, m;\n\t\tInputV(int N) :n(N), m(-1) {}\n\t\tInputV(pair<int, int> N) { tie(n, m) = N; }\n\t\ttemplate<class T>operator vector<T>() {\n\t\t\tvector<T> ret(n); rep(i, n)ret[i] = InputF<T>(); return ret;\n\t\t}\n\t\ttemplate<class T>operator vector<vector<T>>() {\n\t\t\tassert(m != -1); vector<vector<T>> ret(n, vector<T>(m));\n\t\t\trep(i, n)rep(j, m)ret[i][j] = InputF<T>();\n\t\t\treturn ret;\n\t\t}\n\t};\n\ttemplate<class T>operator T() { return InputF<T>(); }\n\tInputV operator[](int t) { return InputV(t); }\n\tInputV operator[](pair<int, int> t) { return InputV(t); }\n}in;\n\n// --- output --- //\nstruct BoolStr {\n\tconst char* t, * f; BoolStr(const char* _t, const char* _f) :t(_t), f(_f) {}\n}Yes(\"Yes\", \"No\"), yes(\"yes\", \"no\"), YES(\"YES\", \"NO\"), Int(\"1\", \"0\");\nstruct DivStr {\n\tconst char* d, * l; DivStr(const char* _d, const char* _l) :d(_d), l(_l) {}\n}spc(\" \", \"\\n\"), no_spc(\"\", \"\\n\"), end_line(\"\\n\", \"\\n\"), comma(\",\", \"\\n\"), no_endl(\" \", \"\");\nclass Print {\n\tBoolStr B{ Yes }; DivStr D{ spc };\tvoid p(double v) { printf(\"%.20f\", v); }\n\tvoid p(int v) { printf(\"%d\", v); }\tvoid p(LL v) { printf(\"%lld\", v); }\n\tvoid p(char v) { putchar(v); }\t\tvoid p(bool v) { printf(v ? B.t : B.f); }\n\ttemplate<class T>void p(const T& v) { cout << v; }\n\ttemplate<class T, class U>void p(const pair<T, U>& v) { p(v.first); printf(D.d); p(v.second); }\n\ttemplate<class T>void p(const vector<T>& v) { rep(i, sz(v)) { if (i)printf(D.d); p(v[i]); } }\n\ttemplate<class T>void p(const vector<vector<T>>& v) { rep(i, sz(v)) { if (i)printf(D.l); p(v[i]); } }\n\tvoid p(const BoolStr& v) { B = v; } void p(const DivStr& v) { D = v; }\n\ttemplate<class T>bool isPrint(const T& v) { return !is_same<BoolStr, T>::value && !is_same<DivStr, T>::value; }\npublic:\n\tvoid operator()() { printf(D.l); }\n\ttemplate<class H>void operator()(H&& h) {\n\t\tp(h); if (isPrint(h))printf(D.l); B = Yes; D = spc;\n\t}\n\ttemplate<class H, class...T>void operator()(H&& h, T&& ...t) {\n\t\tp(h); if (isPrint(h))printf(D.d); operator()(forward<T>(t)...);\n\t}\n}out;\n\n// --- step --- //\nclass step {\n\tstruct It {\n\t\tint x, s; It(int _x, int _s) :x(_x), s(_s) { assert(s); }\n\t\tint operator*() { return x; } void operator++() { x += s; }\n\t\tbool operator!=(It& i) { return 0 < s ? x < i.x : x >= i.x; }\n\t}; int x, y, s;\npublic:\n\tstep(int _y, int _s = 1) :x(0 < _s ? 0 : _y), y(0 < _s ? _y : 0), s(_s) {}\n\tstep(int _x, int _y, int _s) :x(_x), y(_y), s(_s) {}\n\tIt begin() { return { x,s }; } It end() { return { y,s }; }\n};\n\n// --- dump --- //\n#if __has_include(\"dump.hpp\")\n#include \"dump.hpp\"\n#else\n#define dump(...) (void(0))\n#endif\n\n\nint main() {\n\tint n = in;\n\tVI a = in[n], b = in[n];\n\n\tVI A = b, B = b; Sort(A); Sort(B);\n\tbool flag = true;\n\trep(i, n) {\n\t\tif (A[i] > B[i])flag = false;\n\t}\n\n\tif (!flag) {\n\t\tout(\"No\");\n\t\treturn 0;\n\t}\n\n\tif (a == b || A != B) {\n\t\tout(\"Yes\");\n\t\treturn 0;\n\t}\n\n\tmap<int, int> m;\n\trep(i, n)m[A[i]] = i;\n\tVP ab(n);\n\trep(i, n) {\n\t\tab[i] = mp(m[a[i]], m[b[i]]);\n\t}\n\tSort(ab);\n\n\tint pos = 0;\n\tint cnt_e = 0;\n\trep(i, n)cnt_e += ab[i].first == ab[i].second;\n\tfor (int cnt = 0; cnt < n - 2;) {\n\t\tif (ab[pos].first != ab[pos].second) {\n\t\t\tcnt++;\n\t\t\tint pos2 = ab[pos].second;\n\t\t\tswap(ab[pos].second, ab[pos2].second);\n\t\t\tif (ab[pos].second == ab[pos].first)cnt_e++;\n\t\t\tif (ab[pos2].second == ab[pos2].first)cnt_e++;\n\t\t\tif (cnt_e == n)break;\n\t\t}\n\t\tpos = (pos + 1) % n;\n\t}\n\n\tbool flag2 = true;\n\trep(i, n) {\n\t\tif (ab[i].first != ab[i].second)flag2 = false;\n\t}\n\tout(flag2);\n\n}", "language": "C++", "metadata": {"date": 1573357543, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02867.html", "problem_id": "p02867", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02867/input.txt", "sample_output_relpath": "derived/input_output/data/p02867/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02867/C++/s990460005.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s990460005", "user_id": "u172873334"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#define _CRT_SECURE_NO_WARNINGS\n#include \"bits/stdc++.h\"\n#if defined(_MSC_VER) || defined(ONLINE_JUDGE)\n#define getchar_unlocked _getchar_nolock\n#define putchar_unlocked _putchar_nolock\n#endif\n#define rep(i, n) for(int i=0; i<(n); ++i)\n#define FOR(i, m, n) for(int i=(m); i<(n); ++i)\n#define sz(x) ((int)(x).size())\n#define all(x) (x).begin(),(x).end()\n#define rall(x) (x).rbegin(),(x).rend()\n#define mp make_pair\n#define pb push_back\n#define eb emplace_back\n\nusing namespace std;\nusing LL = long long;\t\tusing VB = vector<bool>;\nusing VI = vector<int>;\t\tusing VL = vector<LL>;\nusing VS = vector<string>;\tusing VD = vector<double>;\nusing VVI = vector<VI>;\t\tusing VVL = vector<VL>;\nusing PII = pair<int, int>;\tusing PLL = pair<LL, LL>;\nusing VP = vector<PII>;\t\tusing VPL = vector<PLL>;\nconst int inf = (int)1e9;\nconst LL inf_ll = (LL)1e18, MOD = 1000000007;\nconst double PI = acos(-1.0), EPS = 1e-12;\n\ntemplate<class T>void Sort(T& a) { sort(all(a)); }\ntemplate<class T>void RSort(T& a) { sort(rall(a)); }\ntemplate<class T>void Reverse(T& a) { reverse(all(a)); }\ntemplate<class T>void Unique(T& a) { a.erase(unique(all(a)), a.end()); }\ntemplate<class T>T Sorted(T a) { Sort(a); return a; }\ntemplate<class T>T RSorted(T a) { RSort(a); return a; }\ntemplate<class T>T Reversed(T a) { Reverse(a); return a; }\ntemplate<class T>T Uniqued(T a) { Unique(a); return a; }\ntemplate<class T>auto Max(const T& a) { return *max_element(all(a)); }\ntemplate<class T>auto Min(const T& a) { return *min_element(all(a)); }\ntemplate<class T>int MaxPos(const T& a) { return max_element(all(a)) - a.begin(); }\ntemplate<class T>int MinPos(const T& a) { return min_element(all(a)) - a.begin(); }\ntemplate<class T, class U>int Count(const T& a, const  U& v) { return count(all(a), v); }\ntemplate<class T, class U>int Find(const T& a, const U& v) { auto pos = find(all(a), v); return pos == a.end() ? -1 : pos - a.begin(); }\ntemplate<class T, class U>U Sum(const T& a, const U& v) { return accumulate(all(a), v); }\ntemplate<class T, class U>int Lower(const T& a, const U& v) { return lower_bound(all(a), v) - a.begin(); }\ntemplate<class T, class U>int Upper(const T& a, const U& v) { return upper_bound(all(a), v) - a.begin(); }\ntemplate<class T, class P>void RemoveIf(T& a, P f) { a.erase(remove_if(all(a), f), a.end()); }\ntemplate<class T>T Age(T n, T m) { return (n + m - 1) / m; }\ntemplate<class T>T Gcd(T n, T m) { return m ? Gcd(m, n % m) : n; }\ntemplate<class T>T Lcm(T n, T m) { return n / Gcd(n, m) * m; }\ntemplate<class T>T Pow(T a, T n) { T r = 1; while (n > 0) { if (n & 1)r *= a; a *= a; n /= 2; }return r; }\ntemplate<class T>T Powmod(T a, T n, T m = MOD) { T r = 1; while (n > 0) { if (n & 1)r = r * a % m, n--; else a = a * a % m, n /= 2; }return r; }\ntemplate<class T>bool chmax(T& a, const T& b) { if (a < b) { a = b; return true; } return false; }\ntemplate<class T>bool chmin(T& a, const T& b) { if (a > b) { a = b; return true; } return false; }\nstring operator*(string s, int n) { string ret; rep(i, n)ret += s; return ret; }\n\n// --- input --- //\ntemplate<class T>T InputF() { T ret; cin >> ret; return ret; }\ntemplate<> char InputF() {\n\tchar ret = '\\0', c = getchar_unlocked();\n\twhile (c != '\\0' && c != '\\n' && c != '\\t' && c != ' ') { ret = c; c = getchar_unlocked(); }\n\treturn ret;\n}\ntemplate<> string InputF() {\n\tstring ret; char c = getchar_unlocked();\n\twhile (c != '\\0' && c != '\\n' && c != '\\t' && c != ' ') { ret.push_back(c); c = getchar_unlocked(); }\n\treturn ret;\n}\ntemplate<> int InputF() {\n\tint ret = 0; bool neg = false; char c = getchar_unlocked();\n\tif (c == '-') { neg = true; c = getchar_unlocked(); }\n\twhile (isdigit(c)) { ret = ret * 10 + (c - '0'); c = getchar_unlocked(); }\n\treturn neg ? -ret : ret;\n}\ntemplate<> LL InputF() {\n\tLL ret = 0; bool neg = false; char c = getchar_unlocked();\n\tif (c == '-') { neg = true; c = getchar_unlocked(); }\n\twhile (isdigit(c)) { ret = ret * 10LL + (LL(c) - LL('0')); c = getchar_unlocked(); }\n\treturn neg ? -ret : ret;\n}\ntemplate<> double InputF() {\n\tdouble ret = 0, dp = 1; bool neg = false, adp = false; char c = getchar_unlocked();\n\tif (c == '-') { neg = true; c = getchar_unlocked(); }\n\twhile (isdigit(c) || c == '.') {\n\t\tif (c == '.')adp = true;\n\t\telse if (adp)ret += (c - '0') * (dp *= 0.1);\n\t\telse ret = ret * 10.0 + (c - '0');\n\t\tc = getchar_unlocked();\n\t}\n\treturn neg ? -ret : ret;\n}\nstring GetLine() {\n\tstring ret; char c = getchar_unlocked();\n\twhile (c != '\\0' && c != '\\n') { ret.push_back(c); c = getchar_unlocked(); }\n\treturn ret;\n}\nstruct Input {\n\tstruct InputV {\n\t\tint n, m;\n\t\tInputV(int N) :n(N), m(-1) {}\n\t\tInputV(pair<int, int> N) { tie(n, m) = N; }\n\t\ttemplate<class T>operator vector<T>() {\n\t\t\tvector<T> ret(n); rep(i, n)ret[i] = InputF<T>(); return ret;\n\t\t}\n\t\ttemplate<class T>operator vector<vector<T>>() {\n\t\t\tassert(m != -1); vector<vector<T>> ret(n, vector<T>(m));\n\t\t\trep(i, n)rep(j, m)ret[i][j] = InputF<T>();\n\t\t\treturn ret;\n\t\t}\n\t};\n\ttemplate<class T>operator T() { return InputF<T>(); }\n\tInputV operator[](int t) { return InputV(t); }\n\tInputV operator[](pair<int, int> t) { return InputV(t); }\n}in;\n\n// --- output --- //\nstruct BoolStr {\n\tconst char* t, * f; BoolStr(const char* _t, const char* _f) :t(_t), f(_f) {}\n}Yes(\"Yes\", \"No\"), yes(\"yes\", \"no\"), YES(\"YES\", \"NO\"), Int(\"1\", \"0\");\nstruct DivStr {\n\tconst char* d, * l; DivStr(const char* _d, const char* _l) :d(_d), l(_l) {}\n}spc(\" \", \"\\n\"), no_spc(\"\", \"\\n\"), end_line(\"\\n\", \"\\n\"), comma(\",\", \"\\n\"), no_endl(\" \", \"\");\nclass Print {\n\tBoolStr B{ Yes }; DivStr D{ spc };\tvoid p(double v) { printf(\"%.20f\", v); }\n\tvoid p(int v) { printf(\"%d\", v); }\tvoid p(LL v) { printf(\"%lld\", v); }\n\tvoid p(char v) { putchar(v); }\t\tvoid p(bool v) { printf(v ? B.t : B.f); }\n\ttemplate<class T>void p(const T& v) { cout << v; }\n\ttemplate<class T, class U>void p(const pair<T, U>& v) { p(v.first); printf(D.d); p(v.second); }\n\ttemplate<class T>void p(const vector<T>& v) { rep(i, sz(v)) { if (i)printf(D.d); p(v[i]); } }\n\ttemplate<class T>void p(const vector<vector<T>>& v) { rep(i, sz(v)) { if (i)printf(D.l); p(v[i]); } }\n\tvoid p(const BoolStr& v) { B = v; } void p(const DivStr& v) { D = v; }\n\ttemplate<class T>bool isPrint(const T& v) { return !is_same<BoolStr, T>::value && !is_same<DivStr, T>::value; }\npublic:\n\tvoid operator()() { printf(D.l); }\n\ttemplate<class H>void operator()(H&& h) {\n\t\tp(h); if (isPrint(h))printf(D.l); B = Yes; D = spc;\n\t}\n\ttemplate<class H, class...T>void operator()(H&& h, T&& ...t) {\n\t\tp(h); if (isPrint(h))printf(D.d); operator()(forward<T>(t)...);\n\t}\n}out;\n\n// --- step --- //\nclass step {\n\tstruct It {\n\t\tint x, s; It(int _x, int _s) :x(_x), s(_s) { assert(s); }\n\t\tint operator*() { return x; } void operator++() { x += s; }\n\t\tbool operator!=(It& i) { return 0 < s ? x < i.x : x >= i.x; }\n\t}; int x, y, s;\npublic:\n\tstep(int _y, int _s = 1) :x(0 < _s ? 0 : _y), y(0 < _s ? _y : 0), s(_s) {}\n\tstep(int _x, int _y, int _s) :x(_x), y(_y), s(_s) {}\n\tIt begin() { return { x,s }; } It end() { return { y,s }; }\n};\n\n// --- dump --- //\n#if __has_include(\"dump.hpp\")\n#include \"dump.hpp\"\n#else\n#define dump(...) (void(0))\n#endif\n\n\nint main() {\n\tint n = in;\n\tVI a = in[n], b = in[n];\n\n\tVI A = b, B = b; Sort(A); Sort(B);\n\tbool flag = true;\n\trep(i, n) {\n\t\tif (A[i] > B[i])flag = false;\n\t}\n\n\tif (!flag) {\n\t\tout(\"No\");\n\t\treturn 0;\n\t}\n\n\tif (a == b || A != B) {\n\t\tout(\"Yes\");\n\t\treturn 0;\n\t}\n\n\tmap<int, int> m;\n\trep(i, n)m[A[i]] = i;\n\tVP ab(n);\n\trep(i, n) {\n\t\tab[i] = mp(m[a[i]], m[b[i]]);\n\t}\n\tSort(ab);\n\n\tint pos = 0;\n\tint cnt_e = 0;\n\trep(i, n)cnt_e += ab[i].first == ab[i].second;\n\tfor (int cnt = 0; cnt < n - 2;) {\n\t\tif (ab[pos].first != ab[pos].second) {\n\t\t\tcnt++;\n\t\t\tint pos2 = ab[pos].second;\n\t\t\tswap(ab[pos].second, ab[pos2].second);\n\t\t\tif (ab[pos].second == ab[pos].first)cnt_e++;\n\t\t\tif (ab[pos2].second == ab[pos2].first)cnt_e++;\n\t\t\tif (cnt_e == n)break;\n\t\t}\n\t\tpos = (pos + 1) % n;\n\t}\n\n\tbool flag2 = true;\n\trep(i, n) {\n\t\tif (ab[i].first != ab[i].second)flag2 = false;\n\t}\n\tout(flag2);\n\n}", "problem_context": "Score : 600 points\n\nProblem Statement\n\nGiven are two integer sequences of N elements each: A_1,...,A_N and B_1,...,B_N.\nDetermine if it is possible to do the following operation at most N-2 times (possibly zero) so that, for every integer i from 1 to N, A_i \\leq B_i holds:\n\nChoose two distinct integers x and y between 1 and N (inclusive), and swap the values of A_x and A_y.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n1 \\leq A_i,B_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\nB_1 B_2 ... B_N\n\nOutput\n\nIf the objective is achievable, print Yes; if it is not, print No.\n\nSample Input 1\n\n3\n1 3 2\n1 2 3\n\nSample Output 1\n\nYes\n\nWe should swap the values of A_2 and A_3.\n\nSample Input 2\n\n3\n1 2 3\n2 2 2\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n6\n3 1 2 6 3 4\n2 2 8 3 4 3\n\nSample Output 3\n\nYes", "sample_input": "3\n1 3 2\n1 2 3\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p02867", "source_text": "Score : 600 points\n\nProblem Statement\n\nGiven are two integer sequences of N elements each: A_1,...,A_N and B_1,...,B_N.\nDetermine if it is possible to do the following operation at most N-2 times (possibly zero) so that, for every integer i from 1 to N, A_i \\leq B_i holds:\n\nChoose two distinct integers x and y between 1 and N (inclusive), and swap the values of A_x and A_y.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n1 \\leq A_i,B_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\nB_1 B_2 ... B_N\n\nOutput\n\nIf the objective is achievable, print Yes; if it is not, print No.\n\nSample Input 1\n\n3\n1 3 2\n1 2 3\n\nSample Output 1\n\nYes\n\nWe should swap the values of A_2 and A_3.\n\nSample Input 2\n\n3\n1 2 3\n2 2 2\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n6\n3 1 2 6 3 4\n2 2 8 3 4 3\n\nSample Output 3\n\nYes", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 7919, "cpu_time_ms": 136, "memory_kb": 11904}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s865269319", "group_id": "codeNet:p02869", "input_text": "// https://atcoder.jp/contests/nikkei2019-2-qual/tasks/nikkei2019_2_qual_e\n#define CIN_ONLY\n#define DECIMAL_DIGITS 10\n#define STATIC_MOD 1e9 + 7\n\n#ifdef BTK\n/*<head>*/\n#    include \"Template.hpp\"\n/*</head>*/\n#else\n/*<body>*/\n/* #region auto includes */\n/* #region stl */\n/*<stl>*/\n#    include <bits/stdc++.h>\n#    include <sys/types.h>\n#    include <unistd.h>\nusing namespace std;\n/*</stl>*/\n/* #endregion */\n/* #region template/IncludeSTL.hpp*/\n/**\n * @file IncludeSTL.hpp\n * @author btk\n * @brief 標準ライブラリをincludeするだけ\n * @version 0.1\n * @date 2019-07-21\n * @todo 何故か2回includeされる（展開scriptに\n * @copyright Copyright (c) 2019\n *\n */\n\n\n/* #endregion */\n/* #region template/Macro.hpp*/\n/**\n * @file Macro.hpp\n * @author btk\n * @brief マクロとか，LLとか\n * @version 0.1\n * @date 2019-07-13\n *\n * @copyright Copyright (c) 2019\n *\n */\n\n\n//! LL\nusing LL = long long;\n\n/**\n * @def DEBUG\n * @brief デバッグ用のif文 提出時はif(0)で実行されない\n */\n\n/*</head>*/\n#    ifdef BTK\n#        define DEBUG if (1)\n#    else\n#        ifdef CIN_ONLY\n#            define FAST_IO\n#        endif\n#        define DEBUG if (0)\n#    endif\n/**\n * @def ALL(v)\n * @brief\n * ALLマクロ\n */\n#    define ALL(v) (v).begin(), (v).end()\n\n/**\n * @def REC(ret, ...)\n * @brief\n * 再帰ラムダをするためのマクロ\n */\n#    define REC(ret, ...) std::function<ret(__VA_ARGS__)>\n\n/**\n * @def VAR_NAME(var)\n * @brief 変数名を取得する\n */\n#    define VAR_NAME(var) #    var\n\n/**\n * @brief\n * rangeで生まれる使わない変数を消す用（警告消し）\n */\ntemplate <typename T>\ninline T& unused_var(T& v) {\n    return v;\n}\n/* #endregion */\n/* #region template/IO.hpp*/\n/**\n * @file IO.hpp\n * @author btk\n * @brief cin高速化とか，出力の小数桁固定とか\n * @version 0.1\n * @date 2019-07-13\n *\n * @copyright Copyright (c) 2019\n */\n\n\n/**\n * @brief 入出力の設定を行うための構造体\n */\nstruct cww {\n    /**\n     * @brief Construct a new cww::cww object\n     * @details\n     * CIN_ONLYを定義すると，submit時にcinとscanfの同期を切る設定が走る\n     * DECIMAL_DIGITSを定義すると，doubleの出力時指定した桁数分小数部を吐くようになる\n     */\n    cww() {\n#    ifdef FAST_IO\n        ios::sync_with_stdio(false);\n        cin.tie(0);\n#    endif\n#    ifdef DECIMAL_DIGITS\n        cout << fixed;\n        cout << setprecision(DECIMAL_DIGITS);\n#    endif\n    }\n};\n\n//! 入出力設定構造体を実体化\ncww star;\n\n/**\n * @brief\n * vectorに直接cin流すためのやつ\n * @tparam T\n * @param is\n * @param v\n * @return istream&\n */\ntemplate <typename T>\nstd::istream& operator>>(std::istream& is, std::vector<T>& v) {\n    for (auto& it : v) is >> it;\n    return is;\n}\n/* #endregion */\n/* #region template/Loop.hpp*/\n/**\n * @file Loop.hpp\n * @author btk\n * @brief rangeとかループ系のクラス\n * @version 0.1\n * @date 2019-07-13\n *\n * @copyright Copyright (c) 2019\n *\n */\n\n\n/**\n * @brief\n * rangeを逆向きに操作したいとき用\n * @details\n * ループの範囲は[bg,ed)なので注意\n * @see range\n */\nclass reverse_range {\n  private:\n    struct I {\n        int x;\n        int operator*() { return x - 1; }\n        bool operator!=(I& lhs) { return x > lhs.x; }\n        void operator++() { --x; }\n    };\n    I i, n;\n\n  public:\n    /**\n     * @brief Construct a new reverse range object\n     *\n     * @param n\n     */\n    reverse_range(int n) : i({0}), n({n}) {}\n    /**\n     * @brief Construct a new reverse range object\n     *\n     * @param i\n     * @param n\n     */\n    reverse_range(int i, int n) : i({i}), n({n}) {}\n    /**\n     * @brief\n     * begin iterator\n     * @return I&\n     */\n    I& begin() { return n; }\n    /**\n     * @brief\n     * end iterator\n     * @return I&\n     */\n    I& end() { return i; }\n};\n/**\n * @brief\n * python みたいな range-based for を実現\n * @details\n * ループの範囲は[bg,ed)なので注意\n * !つけると逆向きにループが回る (reverse_range)\n * 空間計算量はO(1)\n * 使わない変数ができて警告が出がちなので，unused_varとかを使って警告消しするとよい\n */\nclass range {\n  private:\n    struct I {\n        int x;\n        int operator*() { return x; }\n        bool operator!=(I& lhs) { return x < lhs.x; }\n        void operator++() { ++x; }\n    };\n    I i, n;\n\n  public:\n    /**\n     * @brief Construct a new range object\n     *\n     * @param n\n     */\n    range(int n) : i({0}), n({n}) {}\n    /**\n     * @brief Construct a new range object\n     *\n     * @param i\n     * @param n\n     */\n    range(int i, int n) : i({i}), n({n}) {}\n    /**\n     * @brief\n     * begin iterator\n     * @return I&\n     */\n    I& begin() { return i; }\n    /**\n     * @brief\n     * end iterator\n     * @return I&\n     */\n    I& end() { return n; }\n    /**\n     * @brief\n     * 逆向きに参照するrange(reverse_rangeを取得できるs)\n     * @return reverse_range\n     */\n    reverse_range operator!() { return reverse_range(*i, *n); }\n};\n/* #endregion */\n/* #region template/MinMaxOperation.hpp*/\n/**\n * @file MinMaxOperation.hpp\n * @author btk\n * @brief 最大値とか最小値を求める\n * @version 0.1\n * @date 2019-07-04\n *\n * @copyright Copyright (c) 2019\n *\n */\n\n/**\n * @brief 2項の最小値求める\n *\n * @tparam T\n */\ntemplate <typename T>\nstruct min_op {\n    /**\n     * @brief 本体\n     *\n     * @param l\n     * @param r\n     * @return T\n     */\n    static T exec(const T l, const T r) { return l < r ? l : r; }\n};\n\n/**\n * @brief 2項の最大値求める\n *\n * @tparam T\n */\ntemplate <typename T>\nstruct max_op {\n    /**\n     * @brief 本体\n     *\n     * @param l\n     * @param r\n     * @return T\n     */\n    static T exec(const T l, const T r) { return l > r ? l : r; }\n};\n\n/**\n * @brief テンプレート再帰の末尾\n *\n * @tparam F 二項演算\n * @tparam T\n * @param v\n * @return T\n */\ntemplate <typename F, typename T>\ninline T multi_op(T&& v) {\n    return v;\n}\n\n/**\n * @brief 複数項における演算の結果を返す\n *\n * @tparam F\n * @tparam T\n * @tparam Ts\n * @param head\n * @param tail\n * @return T\n */\ntemplate <typename F, typename T, typename... Ts>\ninline T multi_op(const T head, Ts&&... tail) {\n    return F::exec(head, multi_op<F>(tail...));\n}\n\n/**\n * @brief 複数項の最小値\n * @see multi_op\n * @tparam T\n * @tparam Ts\n * @param head\n * @param tail\n * @return T\n */\ntemplate <typename T, typename... Ts>\ninline T multi_min(T&& head, Ts&&... tail) {\n    return multi_op<min_op<T>>(head, tail...);\n}\n\n/**\n * @brief 複数項の最大値\n * @see multi_op\n * @tparam T\n * @tparam Ts\n * @param head\n * @param tail\n * @return T\n */\ntemplate <typename T, typename... Ts>\ninline T multi_max(T&& head, Ts&&... tail) {\n    return multi_op<max_op<T>>(head, tail...);\n}\n\n/**\n * @brief\n * \b先頭の値をFで参照する関数に基づいて変更できたらする\n * @tparam F\n * @tparam T\n * @tparam Ts\n * @param target\n * @param candidates\n * @return true\n * @return false\n */\ntemplate <typename F, typename T, typename... Ts>\ninline bool ch_op(T& target, Ts&&... candidates) {\n    const T old = target;\n    target      = multi_op<F>(target, candidates...);\n    return old != target;\n}\n\n/**\n * @brief change min\n * @tparam T 型\n * @param target 変更する値\n * @param candidates\n * @return 更新があればtrue\n */\ntemplate <typename T, typename... Ts>\ninline bool chmin(T& target, Ts&&... candidates) {\n    return ch_op<min_op<T>>(target, candidates...);\n}\n\n/**\n * @brief chminのmax版\n * @see chmin\n *  @tparam T 型\n * @param target 変更する値\n * @param candidates\n * @return 更新があればtrue\n */\ntemplate <typename T, typename... Ts>\ninline bool chmax(T& target, Ts&&... candidates) {\n    return ch_op<max_op<T>>(target, candidates...);\n}\n/* #endregion */\n/* #region template/Random.hpp*/\n/**\n * @file Random.hpp\n * @author btk\n * @brief 乱数生成系\n * @version 0.1\n * @date 2019-07-13\n * @copyright Copyright (c) 2019\n */\n\n\n//! 乱数のシード値をプロセスIDとして取得\nconst pid_t pid = getpid();\n\n/**\n * @brief XorShift32の実装\n */\nclass XorShift32 {\n  private:\n    //! XorShiftの現在の値\n    unsigned value;\n\n    /**\n     * @brief XorShift32のアルゴリズムに基づいて value を更新\n     */\n    inline void update() {\n        value = value ^ (value << 13);\n        value = value ^ (value >> 17);\n        value = value ^ (value << 5);\n    }\n\n    /**\n     * @brief 値を更新し，更新前の値を返却\n     * @return unsigned 呼び出し時の value を用いる\n     */\n    inline unsigned get() {\n        unsigned v = value;\n        update();\n        return v;\n    }\n\n  public:\n    /**\n     * @brief [0, 2^bit) の範囲の乱数値を取り出す\n     * @tparam デフォルトは31\n     * @return int\n     */\n    template <int bit = 31>\n    inline int next_int() {\n        return (int)(get() >> (32 - bit));\n    }\n\n    /**\n     * @brief [-2^bit,2^bit)の範囲の乱数値を取り出す\n     * @tparam デフォルトは31\n     * @return int\n     */\n    template <int bit = 31>\n    inline int next_signed() {\n        unsigned v = get();\n        return (int)((v >> (31 - bit)) - (1 << (bit)));\n    }\n\n    /**\n     * @brief next_int呼び出し時の最大値を取得\n     * @tparam 31\n     * @return int\n     */\n    template <int bit = 31>\n    inline int range_max() {\n        return (int)((1u << bit) - 1);\n    };\n\n    /**\n     * @brief Construct a new XorShift32 object\n     * @param seed\n     * @details 初期シードをvalueとするXorShift32のインスタンスを生成\n     */\n    XorShift32(const unsigned seed) {\n        value = seed;\n        update();\n    }\n\n    /**\n     * @brief Construct a new XorShift 32 object\n     * @details 初期シードをプロセスIDとするXorShift32のインスタンスを生成\n     */\n    XorShift32() : XorShift32(pid) {}\n};\n/* #endregion */\n/* #region Template.hpp*/\n/**\n * @file Template.hpp\n * @brief 競技プログラミング用テンプレート\n * @author btk15049\n * @date 2019/05/02\n */\n\n\n/* #endregion */\n/* #endregion */\n/*</body>*/\n#endif\n\nLL N;\nLL K;\nLL a[112345];\nLL b[112345];\nLL c[112345];\n\n\nbool solve() {\n    set<LL> s;\n    for (int i : range(N)) {\n        s.insert(K + N + i);\n    }\n    for (int i : range(N)) {\n        a[i]    = K + i;\n        c[i]    = K + 2 * N + i;\n        auto it = s.upper_bound(c[i] - a[i]);\n        if (it == s.begin()) {\n            return false;\n        }\n        --it;\n        b[i] = *it;\n        s.erase(b[i]);\n    }\n    return true;\n}\n\nint main() {\n    /* write here */\n    if (K == 1) {\n        return -1;\n    }\n    cin >> N >> K;\n    if (solve()) {\n        for (int i : range(N)) {\n            cout << a[i] << \" \" << b[i] << \" \" << c[i] << endl;\n        }\n    }\n    else {\n        cout << -1 << endl;\n    }\n    return 0;\n}", "language": "C++", "metadata": {"date": 1573356055, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02869.html", "problem_id": "p02869", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02869/input.txt", "sample_output_relpath": "derived/input_output/data/p02869/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02869/C++/s865269319.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s865269319", "user_id": "u613658617"}, "prompt_components": {"gold_output": "1 2 3\n", "input_to_evaluate": "// https://atcoder.jp/contests/nikkei2019-2-qual/tasks/nikkei2019_2_qual_e\n#define CIN_ONLY\n#define DECIMAL_DIGITS 10\n#define STATIC_MOD 1e9 + 7\n\n#ifdef BTK\n/*<head>*/\n#    include \"Template.hpp\"\n/*</head>*/\n#else\n/*<body>*/\n/* #region auto includes */\n/* #region stl */\n/*<stl>*/\n#    include <bits/stdc++.h>\n#    include <sys/types.h>\n#    include <unistd.h>\nusing namespace std;\n/*</stl>*/\n/* #endregion */\n/* #region template/IncludeSTL.hpp*/\n/**\n * @file IncludeSTL.hpp\n * @author btk\n * @brief 標準ライブラリをincludeするだけ\n * @version 0.1\n * @date 2019-07-21\n * @todo 何故か2回includeされる（展開scriptに\n * @copyright Copyright (c) 2019\n *\n */\n\n\n/* #endregion */\n/* #region template/Macro.hpp*/\n/**\n * @file Macro.hpp\n * @author btk\n * @brief マクロとか，LLとか\n * @version 0.1\n * @date 2019-07-13\n *\n * @copyright Copyright (c) 2019\n *\n */\n\n\n//! LL\nusing LL = long long;\n\n/**\n * @def DEBUG\n * @brief デバッグ用のif文 提出時はif(0)で実行されない\n */\n\n/*</head>*/\n#    ifdef BTK\n#        define DEBUG if (1)\n#    else\n#        ifdef CIN_ONLY\n#            define FAST_IO\n#        endif\n#        define DEBUG if (0)\n#    endif\n/**\n * @def ALL(v)\n * @brief\n * ALLマクロ\n */\n#    define ALL(v) (v).begin(), (v).end()\n\n/**\n * @def REC(ret, ...)\n * @brief\n * 再帰ラムダをするためのマクロ\n */\n#    define REC(ret, ...) std::function<ret(__VA_ARGS__)>\n\n/**\n * @def VAR_NAME(var)\n * @brief 変数名を取得する\n */\n#    define VAR_NAME(var) #    var\n\n/**\n * @brief\n * rangeで生まれる使わない変数を消す用（警告消し）\n */\ntemplate <typename T>\ninline T& unused_var(T& v) {\n    return v;\n}\n/* #endregion */\n/* #region template/IO.hpp*/\n/**\n * @file IO.hpp\n * @author btk\n * @brief cin高速化とか，出力の小数桁固定とか\n * @version 0.1\n * @date 2019-07-13\n *\n * @copyright Copyright (c) 2019\n */\n\n\n/**\n * @brief 入出力の設定を行うための構造体\n */\nstruct cww {\n    /**\n     * @brief Construct a new cww::cww object\n     * @details\n     * CIN_ONLYを定義すると，submit時にcinとscanfの同期を切る設定が走る\n     * DECIMAL_DIGITSを定義すると，doubleの出力時指定した桁数分小数部を吐くようになる\n     */\n    cww() {\n#    ifdef FAST_IO\n        ios::sync_with_stdio(false);\n        cin.tie(0);\n#    endif\n#    ifdef DECIMAL_DIGITS\n        cout << fixed;\n        cout << setprecision(DECIMAL_DIGITS);\n#    endif\n    }\n};\n\n//! 入出力設定構造体を実体化\ncww star;\n\n/**\n * @brief\n * vectorに直接cin流すためのやつ\n * @tparam T\n * @param is\n * @param v\n * @return istream&\n */\ntemplate <typename T>\nstd::istream& operator>>(std::istream& is, std::vector<T>& v) {\n    for (auto& it : v) is >> it;\n    return is;\n}\n/* #endregion */\n/* #region template/Loop.hpp*/\n/**\n * @file Loop.hpp\n * @author btk\n * @brief rangeとかループ系のクラス\n * @version 0.1\n * @date 2019-07-13\n *\n * @copyright Copyright (c) 2019\n *\n */\n\n\n/**\n * @brief\n * rangeを逆向きに操作したいとき用\n * @details\n * ループの範囲は[bg,ed)なので注意\n * @see range\n */\nclass reverse_range {\n  private:\n    struct I {\n        int x;\n        int operator*() { return x - 1; }\n        bool operator!=(I& lhs) { return x > lhs.x; }\n        void operator++() { --x; }\n    };\n    I i, n;\n\n  public:\n    /**\n     * @brief Construct a new reverse range object\n     *\n     * @param n\n     */\n    reverse_range(int n) : i({0}), n({n}) {}\n    /**\n     * @brief Construct a new reverse range object\n     *\n     * @param i\n     * @param n\n     */\n    reverse_range(int i, int n) : i({i}), n({n}) {}\n    /**\n     * @brief\n     * begin iterator\n     * @return I&\n     */\n    I& begin() { return n; }\n    /**\n     * @brief\n     * end iterator\n     * @return I&\n     */\n    I& end() { return i; }\n};\n/**\n * @brief\n * python みたいな range-based for を実現\n * @details\n * ループの範囲は[bg,ed)なので注意\n * !つけると逆向きにループが回る (reverse_range)\n * 空間計算量はO(1)\n * 使わない変数ができて警告が出がちなので，unused_varとかを使って警告消しするとよい\n */\nclass range {\n  private:\n    struct I {\n        int x;\n        int operator*() { return x; }\n        bool operator!=(I& lhs) { return x < lhs.x; }\n        void operator++() { ++x; }\n    };\n    I i, n;\n\n  public:\n    /**\n     * @brief Construct a new range object\n     *\n     * @param n\n     */\n    range(int n) : i({0}), n({n}) {}\n    /**\n     * @brief Construct a new range object\n     *\n     * @param i\n     * @param n\n     */\n    range(int i, int n) : i({i}), n({n}) {}\n    /**\n     * @brief\n     * begin iterator\n     * @return I&\n     */\n    I& begin() { return i; }\n    /**\n     * @brief\n     * end iterator\n     * @return I&\n     */\n    I& end() { return n; }\n    /**\n     * @brief\n     * 逆向きに参照するrange(reverse_rangeを取得できるs)\n     * @return reverse_range\n     */\n    reverse_range operator!() { return reverse_range(*i, *n); }\n};\n/* #endregion */\n/* #region template/MinMaxOperation.hpp*/\n/**\n * @file MinMaxOperation.hpp\n * @author btk\n * @brief 最大値とか最小値を求める\n * @version 0.1\n * @date 2019-07-04\n *\n * @copyright Copyright (c) 2019\n *\n */\n\n/**\n * @brief 2項の最小値求める\n *\n * @tparam T\n */\ntemplate <typename T>\nstruct min_op {\n    /**\n     * @brief 本体\n     *\n     * @param l\n     * @param r\n     * @return T\n     */\n    static T exec(const T l, const T r) { return l < r ? l : r; }\n};\n\n/**\n * @brief 2項の最大値求める\n *\n * @tparam T\n */\ntemplate <typename T>\nstruct max_op {\n    /**\n     * @brief 本体\n     *\n     * @param l\n     * @param r\n     * @return T\n     */\n    static T exec(const T l, const T r) { return l > r ? l : r; }\n};\n\n/**\n * @brief テンプレート再帰の末尾\n *\n * @tparam F 二項演算\n * @tparam T\n * @param v\n * @return T\n */\ntemplate <typename F, typename T>\ninline T multi_op(T&& v) {\n    return v;\n}\n\n/**\n * @brief 複数項における演算の結果を返す\n *\n * @tparam F\n * @tparam T\n * @tparam Ts\n * @param head\n * @param tail\n * @return T\n */\ntemplate <typename F, typename T, typename... Ts>\ninline T multi_op(const T head, Ts&&... tail) {\n    return F::exec(head, multi_op<F>(tail...));\n}\n\n/**\n * @brief 複数項の最小値\n * @see multi_op\n * @tparam T\n * @tparam Ts\n * @param head\n * @param tail\n * @return T\n */\ntemplate <typename T, typename... Ts>\ninline T multi_min(T&& head, Ts&&... tail) {\n    return multi_op<min_op<T>>(head, tail...);\n}\n\n/**\n * @brief 複数項の最大値\n * @see multi_op\n * @tparam T\n * @tparam Ts\n * @param head\n * @param tail\n * @return T\n */\ntemplate <typename T, typename... Ts>\ninline T multi_max(T&& head, Ts&&... tail) {\n    return multi_op<max_op<T>>(head, tail...);\n}\n\n/**\n * @brief\n * \b先頭の値をFで参照する関数に基づいて変更できたらする\n * @tparam F\n * @tparam T\n * @tparam Ts\n * @param target\n * @param candidates\n * @return true\n * @return false\n */\ntemplate <typename F, typename T, typename... Ts>\ninline bool ch_op(T& target, Ts&&... candidates) {\n    const T old = target;\n    target      = multi_op<F>(target, candidates...);\n    return old != target;\n}\n\n/**\n * @brief change min\n * @tparam T 型\n * @param target 変更する値\n * @param candidates\n * @return 更新があればtrue\n */\ntemplate <typename T, typename... Ts>\ninline bool chmin(T& target, Ts&&... candidates) {\n    return ch_op<min_op<T>>(target, candidates...);\n}\n\n/**\n * @brief chminのmax版\n * @see chmin\n *  @tparam T 型\n * @param target 変更する値\n * @param candidates\n * @return 更新があればtrue\n */\ntemplate <typename T, typename... Ts>\ninline bool chmax(T& target, Ts&&... candidates) {\n    return ch_op<max_op<T>>(target, candidates...);\n}\n/* #endregion */\n/* #region template/Random.hpp*/\n/**\n * @file Random.hpp\n * @author btk\n * @brief 乱数生成系\n * @version 0.1\n * @date 2019-07-13\n * @copyright Copyright (c) 2019\n */\n\n\n//! 乱数のシード値をプロセスIDとして取得\nconst pid_t pid = getpid();\n\n/**\n * @brief XorShift32の実装\n */\nclass XorShift32 {\n  private:\n    //! XorShiftの現在の値\n    unsigned value;\n\n    /**\n     * @brief XorShift32のアルゴリズムに基づいて value を更新\n     */\n    inline void update() {\n        value = value ^ (value << 13);\n        value = value ^ (value >> 17);\n        value = value ^ (value << 5);\n    }\n\n    /**\n     * @brief 値を更新し，更新前の値を返却\n     * @return unsigned 呼び出し時の value を用いる\n     */\n    inline unsigned get() {\n        unsigned v = value;\n        update();\n        return v;\n    }\n\n  public:\n    /**\n     * @brief [0, 2^bit) の範囲の乱数値を取り出す\n     * @tparam デフォルトは31\n     * @return int\n     */\n    template <int bit = 31>\n    inline int next_int() {\n        return (int)(get() >> (32 - bit));\n    }\n\n    /**\n     * @brief [-2^bit,2^bit)の範囲の乱数値を取り出す\n     * @tparam デフォルトは31\n     * @return int\n     */\n    template <int bit = 31>\n    inline int next_signed() {\n        unsigned v = get();\n        return (int)((v >> (31 - bit)) - (1 << (bit)));\n    }\n\n    /**\n     * @brief next_int呼び出し時の最大値を取得\n     * @tparam 31\n     * @return int\n     */\n    template <int bit = 31>\n    inline int range_max() {\n        return (int)((1u << bit) - 1);\n    };\n\n    /**\n     * @brief Construct a new XorShift32 object\n     * @param seed\n     * @details 初期シードをvalueとするXorShift32のインスタンスを生成\n     */\n    XorShift32(const unsigned seed) {\n        value = seed;\n        update();\n    }\n\n    /**\n     * @brief Construct a new XorShift 32 object\n     * @details 初期シードをプロセスIDとするXorShift32のインスタンスを生成\n     */\n    XorShift32() : XorShift32(pid) {}\n};\n/* #endregion */\n/* #region Template.hpp*/\n/**\n * @file Template.hpp\n * @brief 競技プログラミング用テンプレート\n * @author btk15049\n * @date 2019/05/02\n */\n\n\n/* #endregion */\n/* #endregion */\n/*</body>*/\n#endif\n\nLL N;\nLL K;\nLL a[112345];\nLL b[112345];\nLL c[112345];\n\n\nbool solve() {\n    set<LL> s;\n    for (int i : range(N)) {\n        s.insert(K + N + i);\n    }\n    for (int i : range(N)) {\n        a[i]    = K + i;\n        c[i]    = K + 2 * N + i;\n        auto it = s.upper_bound(c[i] - a[i]);\n        if (it == s.begin()) {\n            return false;\n        }\n        --it;\n        b[i] = *it;\n        s.erase(b[i]);\n    }\n    return true;\n}\n\nint main() {\n    /* write here */\n    if (K == 1) {\n        return -1;\n    }\n    cin >> N >> K;\n    if (solve()) {\n        for (int i : range(N)) {\n            cout << a[i] << \" \" << b[i] << \" \" << c[i] << endl;\n        }\n    }\n    else {\n        cout << -1 << endl;\n    }\n    return 0;\n}", "problem_context": "Score : 700 points\n\nProblem Statement\n\nGiven are positive integers N and K.\n\nDetermine if the 3N integers K, K+1, ..., K+3N-1 can be partitioned into N triples (a_1,b_1,c_1), ..., (a_N,b_N,c_N) so that the condition below is satisfied. Any of the integers K, K+1, ..., K+3N-1 must appear in exactly one of those triples.\n\nFor every integer i from 1 to N, a_i + b_i \\leq c_i holds.\n\nIf the answer is yes, construct one such partition.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq K \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nIf it is impossible to partition the integers satisfying the condition, print -1. If it is possible, print N triples in the following format:\n\na_1 b_1 c_1\n:\na_N b_N c_N\n\nSample Input 1\n\n1 1\n\nSample Output 1\n\n1 2 3\n\nSample Input 2\n\n3 3\n\nSample Output 2\n\n-1", "sample_input": "1 1\n"}, "reference_outputs": ["1 2 3\n"], "source_document_id": "p02869", "source_text": "Score : 700 points\n\nProblem Statement\n\nGiven are positive integers N and K.\n\nDetermine if the 3N integers K, K+1, ..., K+3N-1 can be partitioned into N triples (a_1,b_1,c_1), ..., (a_N,b_N,c_N) so that the condition below is satisfied. Any of the integers K, K+1, ..., K+3N-1 must appear in exactly one of those triples.\n\nFor every integer i from 1 to N, a_i + b_i \\leq c_i holds.\n\nIf the answer is yes, construct one such partition.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq K \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nIf it is impossible to partition the integers satisfying the condition, print -1. If it is possible, print N triples in the following format:\n\na_1 b_1 c_1\n:\na_N b_N c_N\n\nSample Input 1\n\n1 1\n\nSample Output 1\n\n1 2 3\n\nSample Input 2\n\n3 3\n\nSample Output 2\n\n-1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 10849, "cpu_time_ms": 29, "memory_kb": 7168}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s776817602", "group_id": "codeNet:p02873", "input_text": "/*\n\n    author : s@if\n\n*/\n\n#include<bits/stdc++.h>\n#include<ext/pb_ds/assoc_container.hpp>\nusing namespace __gnu_pbds;\nusing namespace std;\n\n#define \t\tNIL \t\t\t-1\n#define\t\t \tfi\t \t\t    first\n#define \t\tsec \t\t\tsecond\n#define \t\tMAX \t\t\tINT_MAX\n#define\t\t\tINF \t\t\t99999999\n#define \t\tll \t\t\t    long long\n#define \t\tPI \t\t\t    acos(-1.0)\n#define\t\t\tMOD \t\t\t1000000007\n#define \t\tPLL \t\t\tpair<ll,ll>\n#define \t\tPII\t\t\t    pair<int,int>\n#define \t\tull \t\t\tunsigned long long\n#define \t\tFor(i,a,b) \t\tfor(int i=a;i<=(int)b;i++)\ntypedef tree<int, null_type, less<int>, rb_tree_tag,\n            tree_order_statistics_node_update> new_data_set;\n\n//*find_by_order(k)  gives the kth element;\n//order_of_key(item)   gives the index(number of element strictly less than item) of item;\n\n\ninline int in() {int x; scanf(\"%d\", &x); return x; }\nbool Check(int N , int pos)\t{\treturn (bool) (N & (1<<pos));}\nint Set(int N, int pos) {\treturn N = N | (1<<pos);}\n\nint fx[]={+0,+0,+1,-1,-1,+1,-1,+1};\nint fy[]={-1,+1,+0,+0,+1,+1,-1,-1};\nint hr[]={-2,-2,-1,+1,+2,+2,-1,+1};\nint hc[]={+1,-1,+2,+2,-1,+1,-2,-2};\nint dx[]={+1,-1,+0,+0};\nint dy[]={+0,+0,+1,-1};\n\nconst int MAXN = (int)1e5+9;\n\nint main()\n{\n/*\tfreopen(\"input.txt\",\"r\",stdin);\n    freopen(\"output.txt\",\"w\",stdout);\n    ios_base::sync_with_stdio(false);\n    cin.tie(0);\n    cout.tie(0);  */\n\n    int i,j,k,l,m,n,p,q,x,y,u,v,r,tc,t;\n\n    string s; cin>>s; n = s.size();\n\n    int ara[n+9]; ara[n] = 0;\n\n    for(i=n-1; i>=0; )\n    {\n        int cnt1 = 0, cnt2 = 0; j = i;\n\n        while(j>=0 && s[j]=='>'){\n            j--; cnt1++;\n        }\n\n        while(j>=0 && s[j]=='<'){\n            j--; cnt2++;\n        }\n\n        k = i;\n\n        for(p=k, q=1; q<cnt1; q++, p--)\n            ara[p] = q;\n        ara[p] = max(cnt1, cnt2); p--;\n\n        for(q=1, v = cnt2-1; q<=cnt2; q++, p--)\n        {\n            ara[p] = v; v--;\n        }\n\n        i = j;\n    }\n\n    ll ans = 0;\n    for(i=0; i<=n; i++){\n       // cout<<ara[i]<<\" \";\n        ans+=ara[i];\n    }\n\n   // cout<<endl;\n\n    cout<<ans<<endl;\n\n  //  main();\n\n    return 0;\n}\n\n// read the question correctly (is y a vowel? what are the exact constraints?)\n// look out for SPECIAL CASES (n=1?) and overflow (ll vs int?)\n", "language": "C++", "metadata": {"date": 1572845134, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02873.html", "problem_id": "p02873", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02873/input.txt", "sample_output_relpath": "derived/input_output/data/p02873/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02873/C++/s776817602.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s776817602", "user_id": "u253790619"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "/*\n\n    author : s@if\n\n*/\n\n#include<bits/stdc++.h>\n#include<ext/pb_ds/assoc_container.hpp>\nusing namespace __gnu_pbds;\nusing namespace std;\n\n#define \t\tNIL \t\t\t-1\n#define\t\t \tfi\t \t\t    first\n#define \t\tsec \t\t\tsecond\n#define \t\tMAX \t\t\tINT_MAX\n#define\t\t\tINF \t\t\t99999999\n#define \t\tll \t\t\t    long long\n#define \t\tPI \t\t\t    acos(-1.0)\n#define\t\t\tMOD \t\t\t1000000007\n#define \t\tPLL \t\t\tpair<ll,ll>\n#define \t\tPII\t\t\t    pair<int,int>\n#define \t\tull \t\t\tunsigned long long\n#define \t\tFor(i,a,b) \t\tfor(int i=a;i<=(int)b;i++)\ntypedef tree<int, null_type, less<int>, rb_tree_tag,\n            tree_order_statistics_node_update> new_data_set;\n\n//*find_by_order(k)  gives the kth element;\n//order_of_key(item)   gives the index(number of element strictly less than item) of item;\n\n\ninline int in() {int x; scanf(\"%d\", &x); return x; }\nbool Check(int N , int pos)\t{\treturn (bool) (N & (1<<pos));}\nint Set(int N, int pos) {\treturn N = N | (1<<pos);}\n\nint fx[]={+0,+0,+1,-1,-1,+1,-1,+1};\nint fy[]={-1,+1,+0,+0,+1,+1,-1,-1};\nint hr[]={-2,-2,-1,+1,+2,+2,-1,+1};\nint hc[]={+1,-1,+2,+2,-1,+1,-2,-2};\nint dx[]={+1,-1,+0,+0};\nint dy[]={+0,+0,+1,-1};\n\nconst int MAXN = (int)1e5+9;\n\nint main()\n{\n/*\tfreopen(\"input.txt\",\"r\",stdin);\n    freopen(\"output.txt\",\"w\",stdout);\n    ios_base::sync_with_stdio(false);\n    cin.tie(0);\n    cout.tie(0);  */\n\n    int i,j,k,l,m,n,p,q,x,y,u,v,r,tc,t;\n\n    string s; cin>>s; n = s.size();\n\n    int ara[n+9]; ara[n] = 0;\n\n    for(i=n-1; i>=0; )\n    {\n        int cnt1 = 0, cnt2 = 0; j = i;\n\n        while(j>=0 && s[j]=='>'){\n            j--; cnt1++;\n        }\n\n        while(j>=0 && s[j]=='<'){\n            j--; cnt2++;\n        }\n\n        k = i;\n\n        for(p=k, q=1; q<cnt1; q++, p--)\n            ara[p] = q;\n        ara[p] = max(cnt1, cnt2); p--;\n\n        for(q=1, v = cnt2-1; q<=cnt2; q++, p--)\n        {\n            ara[p] = v; v--;\n        }\n\n        i = j;\n    }\n\n    ll ans = 0;\n    for(i=0; i<=n; i++){\n       // cout<<ara[i]<<\" \";\n        ans+=ara[i];\n    }\n\n   // cout<<endl;\n\n    cout<<ans<<endl;\n\n  //  main();\n\n    return 0;\n}\n\n// read the question correctly (is y a vowel? what are the exact constraints?)\n// look out for SPECIAL CASES (n=1?) and overflow (ll vs int?)\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nGiven is a string S of length N-1.\nEach character in S is < or >.\n\nA sequence of N non-negative integers, a_1,a_2,\\cdots,a_N, is said to be good when the following condition is satisfied for all i (1 \\leq i \\leq N-1):\n\nIf S_i= <: a_i<a_{i+1}\n\nIf S_i= >: a_i>a_{i+1}\n\nFind the minimum possible sum of the elements of a good sequence of N non-negative integers.\n\nConstraints\n\n2 \\leq N \\leq 5 \\times 10^5\n\nS is a string of length N-1 consisting of < and >.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nFind the minimum possible sum of the elements of a good sequence of N non-negative integers.\n\nSample Input 1\n\n<>>\n\nSample Output 1\n\n3\n\na=(0,2,1,0) is a good sequence whose sum is 3.\nThere is no good sequence whose sum is less than 3.\n\nSample Input 2\n\n<>>><<><<<<<>>><\n\nSample Output 2\n\n28", "sample_input": "<>>\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02873", "source_text": "Score : 300 points\n\nProblem Statement\n\nGiven is a string S of length N-1.\nEach character in S is < or >.\n\nA sequence of N non-negative integers, a_1,a_2,\\cdots,a_N, is said to be good when the following condition is satisfied for all i (1 \\leq i \\leq N-1):\n\nIf S_i= <: a_i<a_{i+1}\n\nIf S_i= >: a_i>a_{i+1}\n\nFind the minimum possible sum of the elements of a good sequence of N non-negative integers.\n\nConstraints\n\n2 \\leq N \\leq 5 \\times 10^5\n\nS is a string of length N-1 consisting of < and >.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nFind the minimum possible sum of the elements of a good sequence of N non-negative integers.\n\nSample Input 1\n\n<>>\n\nSample Output 1\n\n3\n\na=(0,2,1,0) is a good sequence whose sum is 3.\nThere is no good sequence whose sum is less than 3.\n\nSample Input 2\n\n<>>><<><<<<<>>><\n\nSample Output 2\n\n28", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2176, "cpu_time_ms": 24, "memory_kb": 2820}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s832693252", "group_id": "codeNet:p02880", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  int N;\n  cin >> N;\n  \n  for (double i = 9.0; i > 0.0; i--){\n    N /= i;\n  }\n  \n  if (N == 1.0){\n    cout << \"Yes\" << endl;\n  }\n  else{\n    cout << \"No\" << endl;\n  }\n}\n", "language": "C++", "metadata": {"date": 1588919837, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02880.html", "problem_id": "p02880", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02880/input.txt", "sample_output_relpath": "derived/input_output/data/p02880/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02880/C++/s832693252.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s832693252", "user_id": "u302636975"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  int N;\n  cin >> N;\n  \n  for (double i = 9.0; i > 0.0; i--){\n    N /= i;\n  }\n  \n  if (N == 1.0){\n    cout << \"Yes\" << endl;\n  }\n  else{\n    cout << \"No\" << endl;\n  }\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nHaving learned the multiplication table, Takahashi can multiply two integers between 1 and 9 (inclusive) together.\n\nGiven an integer N, determine whether N can be represented as the product of two integers between 1 and 9. If it can, print Yes; if it cannot, print No.\n\nConstraints\n\n1 \\leq N \\leq 100\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nIf N can be represented as the product of two integers between 1 and 9 (inclusive), print Yes; if it cannot, print No.\n\nSample Input 1\n\n10\n\nSample Output 1\n\nYes\n\n10 can be represented as, for example, 2 \\times 5.\n\nSample Input 2\n\n50\n\nSample Output 2\n\nNo\n\n50 cannot be represented as the product of two integers between 1 and 9.\n\nSample Input 3\n\n81\n\nSample Output 3\n\nYes", "sample_input": "10\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p02880", "source_text": "Score : 200 points\n\nProblem Statement\n\nHaving learned the multiplication table, Takahashi can multiply two integers between 1 and 9 (inclusive) together.\n\nGiven an integer N, determine whether N can be represented as the product of two integers between 1 and 9. If it can, print Yes; if it cannot, print No.\n\nConstraints\n\n1 \\leq N \\leq 100\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nIf N can be represented as the product of two integers between 1 and 9 (inclusive), print Yes; if it cannot, print No.\n\nSample Input 1\n\n10\n\nSample Output 1\n\nYes\n\n10 can be represented as, for example, 2 \\times 5.\n\nSample Input 2\n\n50\n\nSample Output 2\n\nNo\n\n50 cannot be represented as the product of two integers between 1 and 9.\n\nSample Input 3\n\n81\n\nSample Output 3\n\nYes", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 228, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s148223716", "group_id": "codeNet:p02880", "input_text": "#include<stdio.h>\nint main()\n{\n \tint n;\n  \tscanf(\"%d\",&n);\n  \tint a[100];\n  int p = -1;\n  \tfor(int i = 1 ; i <= 9 ; i++)\n      for(int j = 1 ; j <=9 ; j++)\n          a[++p] = i * j;\n  int count = 0;\n  for(int i = 1 ; i <= p ; i++)\n  {\n   \tif(a[i] == n)\n    {\n      count = 1;\n      break;\n    }\n    \n  }\n  if(count) printf(\"Yes\");\n  else printf(\"No\");\n  return 0;\n}", "language": "C++", "metadata": {"date": 1572248092, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02880.html", "problem_id": "p02880", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02880/input.txt", "sample_output_relpath": "derived/input_output/data/p02880/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02880/C++/s148223716.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s148223716", "user_id": "u665785827"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include<stdio.h>\nint main()\n{\n \tint n;\n  \tscanf(\"%d\",&n);\n  \tint a[100];\n  int p = -1;\n  \tfor(int i = 1 ; i <= 9 ; i++)\n      for(int j = 1 ; j <=9 ; j++)\n          a[++p] = i * j;\n  int count = 0;\n  for(int i = 1 ; i <= p ; i++)\n  {\n   \tif(a[i] == n)\n    {\n      count = 1;\n      break;\n    }\n    \n  }\n  if(count) printf(\"Yes\");\n  else printf(\"No\");\n  return 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nHaving learned the multiplication table, Takahashi can multiply two integers between 1 and 9 (inclusive) together.\n\nGiven an integer N, determine whether N can be represented as the product of two integers between 1 and 9. If it can, print Yes; if it cannot, print No.\n\nConstraints\n\n1 \\leq N \\leq 100\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nIf N can be represented as the product of two integers between 1 and 9 (inclusive), print Yes; if it cannot, print No.\n\nSample Input 1\n\n10\n\nSample Output 1\n\nYes\n\n10 can be represented as, for example, 2 \\times 5.\n\nSample Input 2\n\n50\n\nSample Output 2\n\nNo\n\n50 cannot be represented as the product of two integers between 1 and 9.\n\nSample Input 3\n\n81\n\nSample Output 3\n\nYes", "sample_input": "10\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p02880", "source_text": "Score : 200 points\n\nProblem Statement\n\nHaving learned the multiplication table, Takahashi can multiply two integers between 1 and 9 (inclusive) together.\n\nGiven an integer N, determine whether N can be represented as the product of two integers between 1 and 9. If it can, print Yes; if it cannot, print No.\n\nConstraints\n\n1 \\leq N \\leq 100\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nIf N can be represented as the product of two integers between 1 and 9 (inclusive), print Yes; if it cannot, print No.\n\nSample Input 1\n\n10\n\nSample Output 1\n\nYes\n\n10 can be represented as, for example, 2 \\times 5.\n\nSample Input 2\n\n50\n\nSample Output 2\n\nNo\n\n50 cannot be represented as the product of two integers between 1 and 9.\n\nSample Input 3\n\n81\n\nSample Output 3\n\nYes", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 365, "cpu_time_ms": 1, "memory_kb": 128}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s105932577", "group_id": "codeNet:p02881", "input_text": "#include <iostream>\n#include <vector>\n#include <stdint.h>\n#include <utility>\nusing namespace std;\nint main() {\n\tint64_t A;\n\tcin >> A;\n\n\tvector<pair<int64_t, int64_t>>v;\n\tfor (int64_t i = 1; i*i <= A; i++) {\n\t\tif (A%i==0 ) {\n\t\t\tv.push_back(pair<int64_t, int64_t>(i, A / i));\n\t\t}\n\t}\n\n\tint64_t min=1e12;\n\tint64_t tmp = 0;\n\tfor (int64_t j = 0; j < v.size(); j++) {\n\t\ttmp = v[j].first + v[j].second - 2;\n\t\tif (tmp < min) min = tmp;\n\t}\n\tcout << min << endl;\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1576636717, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02881.html", "problem_id": "p02881", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02881/input.txt", "sample_output_relpath": "derived/input_output/data/p02881/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02881/C++/s105932577.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s105932577", "user_id": "u123550214"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\n#include <stdint.h>\n#include <utility>\nusing namespace std;\nint main() {\n\tint64_t A;\n\tcin >> A;\n\n\tvector<pair<int64_t, int64_t>>v;\n\tfor (int64_t i = 1; i*i <= A; i++) {\n\t\tif (A%i==0 ) {\n\t\t\tv.push_back(pair<int64_t, int64_t>(i, A / i));\n\t\t}\n\t}\n\n\tint64_t min=1e12;\n\tint64_t tmp = 0;\n\tfor (int64_t j = 0; j < v.size(); j++) {\n\t\ttmp = v[j].first + v[j].second - 2;\n\t\tif (tmp < min) min = tmp;\n\t}\n\tcout << min << endl;\n\treturn 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nTakahashi is standing on a multiplication table with infinitely many rows and columns.\n\nThe square (i,j) contains the integer i \\times j. Initially, Takahashi is standing at (1,1).\n\nIn one move, he can move from (i,j) to either (i+1,j) or (i,j+1).\n\nGiven an integer N, find the minimum number of moves needed to reach a square that contains N.\n\nConstraints\n\n2 \\leq N \\leq 10^{12}\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the minimum number of moves needed to reach a square that contains the integer N.\n\nSample Input 1\n\n10\n\nSample Output 1\n\n5\n\n(2,5) can be reached in five moves. We cannot reach a square that contains 10 in less than five moves.\n\nSample Input 2\n\n50\n\nSample Output 2\n\n13\n\n(5, 10) can be reached in 13 moves.\n\nSample Input 3\n\n10000000019\n\nSample Output 3\n\n10000000018\n\nBoth input and output may be enormous.", "sample_input": "10\n"}, "reference_outputs": ["5\n"], "source_document_id": "p02881", "source_text": "Score : 300 points\n\nProblem Statement\n\nTakahashi is standing on a multiplication table with infinitely many rows and columns.\n\nThe square (i,j) contains the integer i \\times j. Initially, Takahashi is standing at (1,1).\n\nIn one move, he can move from (i,j) to either (i+1,j) or (i,j+1).\n\nGiven an integer N, find the minimum number of moves needed to reach a square that contains N.\n\nConstraints\n\n2 \\leq N \\leq 10^{12}\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the minimum number of moves needed to reach a square that contains the integer N.\n\nSample Input 1\n\n10\n\nSample Output 1\n\n5\n\n(2,5) can be reached in five moves. We cannot reach a square that contains 10 in less than five moves.\n\nSample Input 2\n\n50\n\nSample Output 2\n\n13\n\n(5, 10) can be reached in 13 moves.\n\nSample Input 3\n\n10000000019\n\nSample Output 3\n\n10000000018\n\nBoth input and output may be enormous.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 464, "cpu_time_ms": 11, "memory_kb": 384}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s685196864", "group_id": "codeNet:p02881", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  long long int N;\n  cin >> N;\n  \n  long long int ans = N-1;\n  int a;\n  for(int i=2; i < int(sqrt(float(N)))+2 ;i++){\n    if(N%i==0){\n      ans = min( ans , (i+N/i-2) );\n    }\n  }\n  \n  cout << ans << endl;\n\n}", "language": "C++", "metadata": {"date": 1572438146, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02881.html", "problem_id": "p02881", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02881/input.txt", "sample_output_relpath": "derived/input_output/data/p02881/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02881/C++/s685196864.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s685196864", "user_id": "u783911129"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  long long int N;\n  cin >> N;\n  \n  long long int ans = N-1;\n  int a;\n  for(int i=2; i < int(sqrt(float(N)))+2 ;i++){\n    if(N%i==0){\n      ans = min( ans , (i+N/i-2) );\n    }\n  }\n  \n  cout << ans << endl;\n\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nTakahashi is standing on a multiplication table with infinitely many rows and columns.\n\nThe square (i,j) contains the integer i \\times j. Initially, Takahashi is standing at (1,1).\n\nIn one move, he can move from (i,j) to either (i+1,j) or (i,j+1).\n\nGiven an integer N, find the minimum number of moves needed to reach a square that contains N.\n\nConstraints\n\n2 \\leq N \\leq 10^{12}\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the minimum number of moves needed to reach a square that contains the integer N.\n\nSample Input 1\n\n10\n\nSample Output 1\n\n5\n\n(2,5) can be reached in five moves. We cannot reach a square that contains 10 in less than five moves.\n\nSample Input 2\n\n50\n\nSample Output 2\n\n13\n\n(5, 10) can be reached in 13 moves.\n\nSample Input 3\n\n10000000019\n\nSample Output 3\n\n10000000018\n\nBoth input and output may be enormous.", "sample_input": "10\n"}, "reference_outputs": ["5\n"], "source_document_id": "p02881", "source_text": "Score : 300 points\n\nProblem Statement\n\nTakahashi is standing on a multiplication table with infinitely many rows and columns.\n\nThe square (i,j) contains the integer i \\times j. Initially, Takahashi is standing at (1,1).\n\nIn one move, he can move from (i,j) to either (i+1,j) or (i,j+1).\n\nGiven an integer N, find the minimum number of moves needed to reach a square that contains N.\n\nConstraints\n\n2 \\leq N \\leq 10^{12}\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the minimum number of moves needed to reach a square that contains the integer N.\n\nSample Input 1\n\n10\n\nSample Output 1\n\n5\n\n(2,5) can be reached in five moves. We cannot reach a square that contains 10 in less than five moves.\n\nSample Input 2\n\n50\n\nSample Output 2\n\n13\n\n(5, 10) can be reached in 13 moves.\n\nSample Input 3\n\n10000000019\n\nSample Output 3\n\n10000000018\n\nBoth input and output may be enormous.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 267, "cpu_time_ms": 12, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s059226750", "group_id": "codeNet:p02881", "input_text": "#include<cstdio>\n#include<cmath>\n#include<algorithm>\nusing namespace std;\ntypedef long long LL;\nconst int MAXN=int(1e5+5);\nLL n;\nint main()\n{\n    scanf(\"%lld\",&n);\n    for(LL i=sqrt(n)+1;i>=1;i--)\n    if(n%i==0) {\n        printf(\"%lld\",i+(n/i)-2);\n        return 0;\n    }\n}\n", "language": "C++", "metadata": {"date": 1572224753, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02881.html", "problem_id": "p02881", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02881/input.txt", "sample_output_relpath": "derived/input_output/data/p02881/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02881/C++/s059226750.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s059226750", "user_id": "u601167480"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include<cstdio>\n#include<cmath>\n#include<algorithm>\nusing namespace std;\ntypedef long long LL;\nconst int MAXN=int(1e5+5);\nLL n;\nint main()\n{\n    scanf(\"%lld\",&n);\n    for(LL i=sqrt(n)+1;i>=1;i--)\n    if(n%i==0) {\n        printf(\"%lld\",i+(n/i)-2);\n        return 0;\n    }\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nTakahashi is standing on a multiplication table with infinitely many rows and columns.\n\nThe square (i,j) contains the integer i \\times j. Initially, Takahashi is standing at (1,1).\n\nIn one move, he can move from (i,j) to either (i+1,j) or (i,j+1).\n\nGiven an integer N, find the minimum number of moves needed to reach a square that contains N.\n\nConstraints\n\n2 \\leq N \\leq 10^{12}\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the minimum number of moves needed to reach a square that contains the integer N.\n\nSample Input 1\n\n10\n\nSample Output 1\n\n5\n\n(2,5) can be reached in five moves. We cannot reach a square that contains 10 in less than five moves.\n\nSample Input 2\n\n50\n\nSample Output 2\n\n13\n\n(5, 10) can be reached in 13 moves.\n\nSample Input 3\n\n10000000019\n\nSample Output 3\n\n10000000018\n\nBoth input and output may be enormous.", "sample_input": "10\n"}, "reference_outputs": ["5\n"], "source_document_id": "p02881", "source_text": "Score : 300 points\n\nProblem Statement\n\nTakahashi is standing on a multiplication table with infinitely many rows and columns.\n\nThe square (i,j) contains the integer i \\times j. Initially, Takahashi is standing at (1,1).\n\nIn one move, he can move from (i,j) to either (i+1,j) or (i,j+1).\n\nGiven an integer N, find the minimum number of moves needed to reach a square that contains N.\n\nConstraints\n\n2 \\leq N \\leq 10^{12}\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the minimum number of moves needed to reach a square that contains the integer N.\n\nSample Input 1\n\n10\n\nSample Output 1\n\n5\n\n(2,5) can be reached in five moves. We cannot reach a square that contains 10 in less than five moves.\n\nSample Input 2\n\n50\n\nSample Output 2\n\n13\n\n(5, 10) can be reached in 13 moves.\n\nSample Input 3\n\n10000000019\n\nSample Output 3\n\n10000000018\n\nBoth input and output may be enormous.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 274, "cpu_time_ms": 10, "memory_kb": 128}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s283756039", "group_id": "codeNet:p02882", "input_text": "#include <iostream>\n#include <vector>\n#include <string>\n#include <cstring>\n#include <queue>\n#include <set>\n#include <stack>\n#include <map>\n#include <unordered_map>\n#include <cmath>\n#include <utility> // pair make_pair\n#include <algorithm>\n#include <functional>\n#include <iomanip>\n#include <numeric>\n#include <climits> // LLONG_MAX, LLONG_MIN, INT_MIN, INT_MAX\n#include <assert.h>\n\n#define m0(x) memset(x,0,sizeof(x))\n#define m1(x) memset(x,63,sizeof(x))\n#define fill(x,y) memset(x,y,sizeof(x))\n#define rep(i, n) for (int i = 0; i < (n); ++i)\n#define ll long long\n//#define int ll\n#define INF INT_MAX/10\n#define MOD 1000000007\n#define PI 3.14159265359\n\nusing namespace std;\nusing Pi = pair<int, int>;\nusing Graph = vector<vector<int> >;\nusing WeightGraph = vector<vector<Pi> >;\n\nint Input[100100];\n\nint main() {\n  long double N, M, X; cin >> N >> M >> X;\n  if (X ==  (1.0 / 2.0) * pow(N, 2) * M) {\n    cout << 45.0 << endl;\n  } else if ( X > (1.0 / 2.0) * pow(N, 2) * M) {\n    long double ans = atan((pow(N, 2) * M - X) / ((pow(N, 3) * (1.0 / 2.0)))) * 180 / PI;\n    cout << setprecision(12) << ans << endl;\n  } else {\n    long double ans = atan( (N * pow(M, 2))/ (X*2)) * 180 / PI;\n    cout << setprecision(12) << ans << endl;\n  }\n}\n", "language": "C++", "metadata": {"date": 1572226685, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02882.html", "problem_id": "p02882", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02882/input.txt", "sample_output_relpath": "derived/input_output/data/p02882/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02882/C++/s283756039.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s283756039", "user_id": "u703205079"}, "prompt_components": {"gold_output": "45.0000000000\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\n#include <string>\n#include <cstring>\n#include <queue>\n#include <set>\n#include <stack>\n#include <map>\n#include <unordered_map>\n#include <cmath>\n#include <utility> // pair make_pair\n#include <algorithm>\n#include <functional>\n#include <iomanip>\n#include <numeric>\n#include <climits> // LLONG_MAX, LLONG_MIN, INT_MIN, INT_MAX\n#include <assert.h>\n\n#define m0(x) memset(x,0,sizeof(x))\n#define m1(x) memset(x,63,sizeof(x))\n#define fill(x,y) memset(x,y,sizeof(x))\n#define rep(i, n) for (int i = 0; i < (n); ++i)\n#define ll long long\n//#define int ll\n#define INF INT_MAX/10\n#define MOD 1000000007\n#define PI 3.14159265359\n\nusing namespace std;\nusing Pi = pair<int, int>;\nusing Graph = vector<vector<int> >;\nusing WeightGraph = vector<vector<Pi> >;\n\nint Input[100100];\n\nint main() {\n  long double N, M, X; cin >> N >> M >> X;\n  if (X ==  (1.0 / 2.0) * pow(N, 2) * M) {\n    cout << 45.0 << endl;\n  } else if ( X > (1.0 / 2.0) * pow(N, 2) * M) {\n    long double ans = atan((pow(N, 2) * M - X) / ((pow(N, 3) * (1.0 / 2.0)))) * 180 / PI;\n    cout << setprecision(12) << ans << endl;\n  } else {\n    long double ans = atan( (N * pow(M, 2))/ (X*2)) * 180 / PI;\n    cout << setprecision(12) << ans << endl;\n  }\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nTakahashi has a water bottle with the shape of a rectangular prism whose base is a square of side a~\\mathrm{cm} and whose height is b~\\mathrm{cm}. (The thickness of the bottle can be ignored.)\n\nWe will pour x~\\mathrm{cm}^3 of water into the bottle, and gradually tilt the bottle around one of the sides of the base.\n\nWhen will the water be spilled? More formally, find the maximum angle in which we can tilt the bottle without spilling any water.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq a \\leq 100\n\n1 \\leq b \\leq 100\n\n1 \\leq x \\leq a^2b\n\nInput\n\nInput is given from Standard Input in the following format:\n\na b x\n\nOutput\n\nPrint the maximum angle in which we can tilt the bottle without spilling any water, in degrees.\nYour output will be judged as correct when the absolute or relative error from the judge's output is at most 10^{-6}.\n\nSample Input 1\n\n2 2 4\n\nSample Output 1\n\n45.0000000000\n\nThis bottle has a cubic shape, and it is half-full. The water gets spilled when we tilt the bottle more than 45 degrees.\n\nSample Input 2\n\n12 21 10\n\nSample Output 2\n\n89.7834636934\n\nThis bottle is almost empty. When the water gets spilled, the bottle is nearly horizontal.\n\nSample Input 3\n\n3 1 8\n\nSample Output 3\n\n4.2363947991\n\nThis bottle is almost full. When the water gets spilled, the bottle is still nearly vertical.", "sample_input": "2 2 4\n"}, "reference_outputs": ["45.0000000000\n"], "source_document_id": "p02882", "source_text": "Score : 400 points\n\nProblem Statement\n\nTakahashi has a water bottle with the shape of a rectangular prism whose base is a square of side a~\\mathrm{cm} and whose height is b~\\mathrm{cm}. (The thickness of the bottle can be ignored.)\n\nWe will pour x~\\mathrm{cm}^3 of water into the bottle, and gradually tilt the bottle around one of the sides of the base.\n\nWhen will the water be spilled? More formally, find the maximum angle in which we can tilt the bottle without spilling any water.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq a \\leq 100\n\n1 \\leq b \\leq 100\n\n1 \\leq x \\leq a^2b\n\nInput\n\nInput is given from Standard Input in the following format:\n\na b x\n\nOutput\n\nPrint the maximum angle in which we can tilt the bottle without spilling any water, in degrees.\nYour output will be judged as correct when the absolute or relative error from the judge's output is at most 10^{-6}.\n\nSample Input 1\n\n2 2 4\n\nSample Output 1\n\n45.0000000000\n\nThis bottle has a cubic shape, and it is half-full. The water gets spilled when we tilt the bottle more than 45 degrees.\n\nSample Input 2\n\n12 21 10\n\nSample Output 2\n\n89.7834636934\n\nThis bottle is almost empty. When the water gets spilled, the bottle is nearly horizontal.\n\nSample Input 3\n\n3 1 8\n\nSample Output 3\n\n4.2363947991\n\nThis bottle is almost full. When the water gets spilled, the bottle is still nearly vertical.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1233, "cpu_time_ms": 3, "memory_kb": 384}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s287371868", "group_id": "codeNet:p02885", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n    int a, b;\n    cin >> a >> b;\n\n    cout << (a > 2 * b ? a - 2 * b : 0) << endl;\n}", "language": "C++", "metadata": {"date": 1579034600, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02885.html", "problem_id": "p02885", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02885/input.txt", "sample_output_relpath": "derived/input_output/data/p02885/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02885/C++/s287371868.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s287371868", "user_id": "u164352406"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n    int a, b;\n    cin >> a >> b;\n\n    cout << (a > 2 * b ? a - 2 * b : 0) << endl;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nThe window of Takahashi's room has a width of A. There are two curtains hung over the window, each of which has a horizontal length of B. (Vertically, the curtains are long enough to cover the whole window.)\n\nWe will close the window so as to minimize the total horizontal length of the uncovered part of the window.\nFind the total horizontal length of the uncovered parts of the window then.\n\nConstraints\n\n1 \\leq A \\leq 100\n\n1 \\leq B \\leq 100\n\nA and B are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nPrint the total horizontal length of the uncovered parts of the window.\n\nSample Input 1\n\n12 4\n\nSample Output 1\n\n4\n\nWe have a window with a horizontal length of 12, and two curtains, each of length 4, that cover both ends of the window, for example. The uncovered part has a horizontal length of 4.\n\nSample Input 2\n\n20 15\n\nSample Output 2\n\n0\n\nIf the window is completely covered, print 0.\n\nSample Input 3\n\n20 30\n\nSample Output 3\n\n0\n\nEach curtain may be longer than the window.", "sample_input": "12 4\n"}, "reference_outputs": ["4\n"], "source_document_id": "p02885", "source_text": "Score : 100 points\n\nProblem Statement\n\nThe window of Takahashi's room has a width of A. There are two curtains hung over the window, each of which has a horizontal length of B. (Vertically, the curtains are long enough to cover the whole window.)\n\nWe will close the window so as to minimize the total horizontal length of the uncovered part of the window.\nFind the total horizontal length of the uncovered parts of the window then.\n\nConstraints\n\n1 \\leq A \\leq 100\n\n1 \\leq B \\leq 100\n\nA and B are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nPrint the total horizontal length of the uncovered parts of the window.\n\nSample Input 1\n\n12 4\n\nSample Output 1\n\n4\n\nWe have a window with a horizontal length of 12, and two curtains, each of length 4, that cover both ends of the window, for example. The uncovered part has a horizontal length of 4.\n\nSample Input 2\n\n20 15\n\nSample Output 2\n\n0\n\nIf the window is completely covered, print 0.\n\nSample Input 3\n\n20 30\n\nSample Output 3\n\n0\n\nEach curtain may be longer than the window.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 144, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s605819257", "group_id": "codeNet:p02887", "input_text": "#include<iostream>\n#include<string>\n#include<algorithm>\n#include<math.h>\n#include<queue>\n#include<vector>\n#include<map>\n#include<iomanip>\n\n\nusing namespace std;\n#define rep(i,n) for(int i=0;i<(n);i++)\n#define rep(i,n) for(int i=0;i<(n);i++)\n#define printfloat(x) cout << setprecision(7) << (x) << endl;\n\nlong double pi = 3.14159265359;\nint n,cnt=0;\nstring s;\n\nint main(){\n    cin >> n;\n    cin >> s;\n    rep(i,s.size()-1){\n        if(s[i] != s[i+1]){\n            cnt++;\n        }\n    }\n    cout << cnt+1 << endl;\n\n\nreturn 0;\n}", "language": "C++", "metadata": {"date": 1593982086, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02887.html", "problem_id": "p02887", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02887/input.txt", "sample_output_relpath": "derived/input_output/data/p02887/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02887/C++/s605819257.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s605819257", "user_id": "u482454662"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include<iostream>\n#include<string>\n#include<algorithm>\n#include<math.h>\n#include<queue>\n#include<vector>\n#include<map>\n#include<iomanip>\n\n\nusing namespace std;\n#define rep(i,n) for(int i=0;i<(n);i++)\n#define rep(i,n) for(int i=0;i<(n);i++)\n#define printfloat(x) cout << setprecision(7) << (x) << endl;\n\nlong double pi = 3.14159265359;\nint n,cnt=0;\nstring s;\n\nint main(){\n    cin >> n;\n    cin >> s;\n    rep(i,s.size()-1){\n        if(s[i] != s[i+1]){\n            cnt++;\n        }\n    }\n    cout << cnt+1 << endl;\n\n\nreturn 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N slimes lining up from left to right. The colors of these slimes will be given as a string S of length N consisting of lowercase English letters. The i-th slime from the left has the color that corresponds to the i-th character of S.\n\nAdjacent slimes with the same color will fuse into one larger slime without changing the color. If there were a slime adjacent to this group of slimes before fusion, that slime is now adjacent to the new larger slime.\n\nUltimately, how many slimes will be there?\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n|S| = N\n\nS consists of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS\n\nOutput\n\nPrint the final number of slimes.\n\nSample Input 1\n\n10\naabbbbaaca\n\nSample Output 1\n\n5\n\nUltimately, these slimes will fuse into abaca.\n\nSample Input 2\n\n5\naaaaa\n\nSample Output 2\n\n1\n\nAll the slimes will fuse into one.\n\nSample Input 3\n\n20\nxxzaffeeeeddfkkkkllq\n\nSample Output 3\n\n10", "sample_input": "10\naabbbbaaca\n"}, "reference_outputs": ["5\n"], "source_document_id": "p02887", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N slimes lining up from left to right. The colors of these slimes will be given as a string S of length N consisting of lowercase English letters. The i-th slime from the left has the color that corresponds to the i-th character of S.\n\nAdjacent slimes with the same color will fuse into one larger slime without changing the color. If there were a slime adjacent to this group of slimes before fusion, that slime is now adjacent to the new larger slime.\n\nUltimately, how many slimes will be there?\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n|S| = N\n\nS consists of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS\n\nOutput\n\nPrint the final number of slimes.\n\nSample Input 1\n\n10\naabbbbaaca\n\nSample Output 1\n\n5\n\nUltimately, these slimes will fuse into abaca.\n\nSample Input 2\n\n5\naaaaa\n\nSample Output 2\n\n1\n\nAll the slimes will fuse into one.\n\nSample Input 3\n\n20\nxxzaffeeeeddfkkkkllq\n\nSample Output 3\n\n10", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 526, "cpu_time_ms": 10, "memory_kb": 3760}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s608043909", "group_id": "codeNet:p02888", "input_text": "#include <bits/stdc++.h>\n\n#define rep(i, n) for(int i = 0; i<(n); i++)\n\nusing namespace std;\n\nconst int MAX = 310;\nconst long long INF = 1LL << 50;\n\nlong long G[MAX][MAX];\nusing pll = pair<long long, long long>;\n\nint main(void) {\n    int N, M;\n    long long L;\n    cin >> N >> M >> L;\n\n    rep(i, MAX) {\n        rep(j, MAX) G[i][j] = INF;\n        G[i][i] = 0;\n    }\n\n    rep(i, M) {\n        int a, b;\n        long long c;\n        cin >> a >> b >> c;\n        --a;\n        --b;\n        G[a][b] = G[b][a] = c;\n    }\n\n    vector<vector<pll>> dist(N, vector<pll>(N, {INF, INF}));\n    rep(s, N) {\n        dist[s][s] = {0, 0};\n        priority_queue<\n                pair<pll, int>,\n                vector<pair<pll, int>>,\n                greater<pair<pll, int>>> que;\n\n        que.push(make_pair(pll(0, 0), s));\n        while (!que.empty()) {\n            auto p = que.top();\n            que.pop();\n\n            long long v = p.second;\n            long long kaisuu = p.first.first;\n            long long used = p.first.second;\n\n            if (p.first > dist[s][v])continue;\n\n            rep(nv, N) {\n                if (nv == v) continue;\n                if (G[v][nv] > L) continue;\n\n                long long nused = used + G[v][nv];\n                pll np = {0, 0};\n                if (nused > L) {\n                    np = {kaisuu + 1, G[v][nv]};\n                } else {\n                    np = {kaisuu, nused};\n                }\n\n                if (dist[s][nv] > np) {\n                    dist[s][nv] = np;\n                    que.push(make_pair(np, nv));\n                }\n            }\n\n        }\n    }\n\n    int Q;\n    cin >> Q;\n    while (Q--) {\n        int a, b;\n        cin >> a >> b;\n        --a;\n        --b;\n\n        long long res = dist[a][b].first;\n        if (res >= INF) {\n            cout << -1 << endl;\n        } else {\n            cout << res << endl;\n        }\n    }\n}\n", "language": "C++", "metadata": {"date": 1571706423, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02888.html", "problem_id": "p02888", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02888/input.txt", "sample_output_relpath": "derived/input_output/data/p02888/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02888/C++/s608043909.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s608043909", "user_id": "u976045502"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\n#define rep(i, n) for(int i = 0; i<(n); i++)\n\nusing namespace std;\n\nconst int MAX = 310;\nconst long long INF = 1LL << 50;\n\nlong long G[MAX][MAX];\nusing pll = pair<long long, long long>;\n\nint main(void) {\n    int N, M;\n    long long L;\n    cin >> N >> M >> L;\n\n    rep(i, MAX) {\n        rep(j, MAX) G[i][j] = INF;\n        G[i][i] = 0;\n    }\n\n    rep(i, M) {\n        int a, b;\n        long long c;\n        cin >> a >> b >> c;\n        --a;\n        --b;\n        G[a][b] = G[b][a] = c;\n    }\n\n    vector<vector<pll>> dist(N, vector<pll>(N, {INF, INF}));\n    rep(s, N) {\n        dist[s][s] = {0, 0};\n        priority_queue<\n                pair<pll, int>,\n                vector<pair<pll, int>>,\n                greater<pair<pll, int>>> que;\n\n        que.push(make_pair(pll(0, 0), s));\n        while (!que.empty()) {\n            auto p = que.top();\n            que.pop();\n\n            long long v = p.second;\n            long long kaisuu = p.first.first;\n            long long used = p.first.second;\n\n            if (p.first > dist[s][v])continue;\n\n            rep(nv, N) {\n                if (nv == v) continue;\n                if (G[v][nv] > L) continue;\n\n                long long nused = used + G[v][nv];\n                pll np = {0, 0};\n                if (nused > L) {\n                    np = {kaisuu + 1, G[v][nv]};\n                } else {\n                    np = {kaisuu, nused};\n                }\n\n                if (dist[s][nv] > np) {\n                    dist[s][nv] = np;\n                    que.push(make_pair(np, nv));\n                }\n            }\n\n        }\n    }\n\n    int Q;\n    cin >> Q;\n    while (Q--) {\n        int a, b;\n        cin >> a >> b;\n        --a;\n        --b;\n\n        long long res = dist[a][b].first;\n        if (res >= INF) {\n            cout << -1 << endl;\n        } else {\n            cout << res << endl;\n        }\n    }\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nTakahashi has N sticks that are distinguishable from each other. The length of the i-th stick is L_i.\n\nHe is going to form a triangle using three of these sticks. Let a, b, and c be the lengths of the three sticks used. Here, all of the following conditions must be satisfied:\n\na < b + c\n\nb < c + a\n\nc < a + b\n\nHow many different triangles can be formed? Two triangles are considered different when there is a stick used in only one of them.\n\nConstraints\n\nAll values in input are integers.\n\n3 \\leq N \\leq 2 \\times 10^3\n\n1 \\leq L_i \\leq 10^3\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nL_1 L_2 ... L_N\n\nConstraints\n\nPrint the number of different triangles that can be formed.\n\nSample Input 1\n\n4\n3 4 2 1\n\nSample Output 1\n\n1\n\nOnly one triangle can be formed: the triangle formed by the first, second, and third sticks.\n\nSample Input 2\n\n3\n1 1000 1\n\nSample Output 2\n\n0\n\nNo triangles can be formed.\n\nSample Input 3\n\n7\n218 786 704 233 645 728 389\n\nSample Output 3\n\n23", "sample_input": "4\n3 4 2 1\n"}, "reference_outputs": ["1\n"], "source_document_id": "p02888", "source_text": "Score : 400 points\n\nProblem Statement\n\nTakahashi has N sticks that are distinguishable from each other. The length of the i-th stick is L_i.\n\nHe is going to form a triangle using three of these sticks. Let a, b, and c be the lengths of the three sticks used. Here, all of the following conditions must be satisfied:\n\na < b + c\n\nb < c + a\n\nc < a + b\n\nHow many different triangles can be formed? Two triangles are considered different when there is a stick used in only one of them.\n\nConstraints\n\nAll values in input are integers.\n\n3 \\leq N \\leq 2 \\times 10^3\n\n1 \\leq L_i \\leq 10^3\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nL_1 L_2 ... L_N\n\nConstraints\n\nPrint the number of different triangles that can be formed.\n\nSample Input 1\n\n4\n3 4 2 1\n\nSample Output 1\n\n1\n\nOnly one triangle can be formed: the triangle formed by the first, second, and third sticks.\n\nSample Input 2\n\n3\n1 1000 1\n\nSample Output 2\n\n0\n\nNo triangles can be formed.\n\nSample Input 3\n\n7\n218 786 704 233 645 728 389\n\nSample Output 3\n\n23", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1886, "cpu_time_ms": 98, "memory_kb": 1024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s625342470", "group_id": "codeNet:p02889", "input_text": "#include <stdio.h>\n#include <set>\n#include <map>\n#include <unordered_map>\n#include <unordered_set>\n#include <list>\n#include <queue>\n#include <stack>\n#include <cmath>\n#include <ctime>\n#include <cstdio>\n#include <vector>\n#include <string>\n#include <bitset>\n#include <cctype>\n#include <cstdlib>\n#include <cstring>\n#include <utility>\n#include <numeric>\n#include <complex>\n#include <sstream>\n#include <fstream>\n#include <iomanip>\n#include <cassert>\n#include <iostream>\n#include <iterator>\n#include <algorithm>\n#include <functional>\nusing namespace std;\ntypedef long long ll;\nconst double EPS = 1e-9;\ntypedef vector<int> vint;\ntypedef vector<vector<int>> v2int;\ntypedef vector<ll> vll;\ntypedef vector<vector<ll>> v2ll;\ntypedef list<int> liint;\ntypedef pair<int, int> pint;\nconst int INF = int(2e9);\nconst ll LINF = ll(2e9) * ll(2e9);\n#define rep(i, n) REP(i, 0, n)\n#define ALL(v) v.begin(), v.end()\n#define MSG(a) cout << #a << \" \" << a << endl;\n#define REP(i, x, n) for(int i = x; i < n; i++)\ntemplate<class T, class C> void chmax(T& a, C b) { a > b ? : a = b; }\ntemplate<class T, class C> void chmin(T& a, C b) { a < b ? : a = b; }\n\n\n\n#include <algorithm>\n#include <vector>\n#include <functional>\n#include <climits>\n\nclass warshall_floyd\n{\nprivate:\n    int node_num;\n    bool is_negative_graph;\n    std::vector<std::vector<long long>> cost_matrix;//隣接行列を構築\n    std::vector<std::vector<int>> pred;//経路（遷移元）を保持\n\npublic:\n    warshall_floyd(const int node_num, const std::vector<std::vector<long long>> &adj_matrix);\n    long long get_cost(int start, int end) const;\n    std::vector<int> get_min_path(int start, int end) const;\n};\n\nwarshall_floyd::warshall_floyd(const int node_num,\n    const std::vector<std::vector<long long>> &adj_matrix) :\n    cost_matrix(adj_matrix),\n    node_num(node_num),\n    is_negative_graph(false),\n    pred(node_num + 1, std::vector<int>(node_num + 1, INT_MAX))\n{\n    //predの初期化\n    for (int i = 0; i <= node_num; i++) {\n        for (int j = 0; j <= node_num; j++) {\n            if (i == j) pred[i][j] = -1;\n            else if (adj_matrix[i][j] < LLONG_MAX) {\n                pred[i][j] = i;\n            }\n        }\n    }\n    //ワーシャルフロイドの更新式\n    for (int k = 0; k <= node_num; k++) {\n        for (int i = 0; i <= node_num; i++) {\n            for (int j = 0; j <= node_num; j++) {\n                if (cost_matrix[i][k] < LLONG_MAX && cost_matrix[k][j] < LLONG_MAX) {\n                    if (cost_matrix[i][k] + cost_matrix[k][j] < cost_matrix[i][j]) {\n                        cost_matrix[i][j] = cost_matrix[i][k] + cost_matrix[k][j];\n                        //経路復元用\n                        //pred[i][j]にはi→jの最短経路におけるjの1つ前の頂点が入る。\n                        //pred[k][j]にはk→jの最短経路におけるjの1つ前の頂点が入っている。\n                        //この処理を通るということは最短経路がkを使った経路に変わる\n                        //ということでありi→jへの経路の中にk→jの最短経路を含むことになる。\n                        //従って新しいi→jにおけるjの１つ前の頂点は\n                        //k→jにおけるjの１つ前の頂点、すなわちpred[k][j]となる。\n                        pred[i][j] = pred[k][j];\n                    }\n                }\n            }\n        }\n    }\n\n}\n\n\n\n\nlong long warshall_floyd::get_cost(int start, int end) const {\n    return cost_matrix[start][end];\n}\n\nstd::vector<int> warshall_floyd::get_min_path(int start, int end) const {\n    int node = end;\n    std::vector<int> vec;\n    vec.push_back(node);\n    //終点から始点までの経路をたどる\n    while (1) {\n        //負のサイクルを含む頂点or\n        //始点から辿れない頂点or\n        //始点であれば終了\n        if (node == start) break;\n        if (cost_matrix[node][node] < 0 ||\n            pred[start][node] >= INT_MAX ||\n            pred[start][node] == -1) break;\n        node = pred[start][node];\n        vec.push_back(node);\n    }\n    std::reverse(vec.begin(), vec.end());\n    return vec;\n}\n\n\nint main() {\n    ios_base::sync_with_stdio(false);\n    cin.tie(NULL);\n    int N, M;\n    ll L;\n    cin >> N >> M >> L;\n    v2ll adj_matrix(N + 1, vll(N + 1, LLONG_MAX));\n    rep(i, M) {\n        int a, b, c;\n        cin >> a >> b >> c;\n        if (c <= L)\n        {\n            adj_matrix[a][b] = c;\n            adj_matrix[b][a] = c;\n        }\n    }\n    warshall_floyd wf(N, adj_matrix);\n    int Q;\n    cin >> Q;\n    vint s(Q), t(Q);\n    vll ans(Q);\n    rep(i, Q) {\n        cin >> s[i] >> t[i];\n        if (wf.get_cost(s[i], t[i]) >= LLONG_MAX) {\n            cout << -1 << endl;\n            continue;\n        }\n        auto min_path = wf.get_min_path(s[i], t[i]);\n        int ans = 0;\n        \n        int fill_point = min_path[0];\n        \n        REP(j, 1, min_path.size()) {\n            if (wf.get_cost(fill_point, min_path[j]) > ll(L)) {\n                fill_point = min_path[j - 1];\n                ans++;\n            }\n\n        }\n        int add = 0;\n        if (wf.get_cost(s[i], t[i]) % L != 0) add = 1;\n        cout << max(ll(ans), wf.get_cost(s[i], t[i])/L + add - 1) << endl;\n    }\n    \n    return 0;\n}", "language": "C++", "metadata": {"date": 1571540824, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02889.html", "problem_id": "p02889", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02889/input.txt", "sample_output_relpath": "derived/input_output/data/p02889/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02889/C++/s625342470.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s625342470", "user_id": "u391331433"}, "prompt_components": {"gold_output": "0\n1\n", "input_to_evaluate": "#include <stdio.h>\n#include <set>\n#include <map>\n#include <unordered_map>\n#include <unordered_set>\n#include <list>\n#include <queue>\n#include <stack>\n#include <cmath>\n#include <ctime>\n#include <cstdio>\n#include <vector>\n#include <string>\n#include <bitset>\n#include <cctype>\n#include <cstdlib>\n#include <cstring>\n#include <utility>\n#include <numeric>\n#include <complex>\n#include <sstream>\n#include <fstream>\n#include <iomanip>\n#include <cassert>\n#include <iostream>\n#include <iterator>\n#include <algorithm>\n#include <functional>\nusing namespace std;\ntypedef long long ll;\nconst double EPS = 1e-9;\ntypedef vector<int> vint;\ntypedef vector<vector<int>> v2int;\ntypedef vector<ll> vll;\ntypedef vector<vector<ll>> v2ll;\ntypedef list<int> liint;\ntypedef pair<int, int> pint;\nconst int INF = int(2e9);\nconst ll LINF = ll(2e9) * ll(2e9);\n#define rep(i, n) REP(i, 0, n)\n#define ALL(v) v.begin(), v.end()\n#define MSG(a) cout << #a << \" \" << a << endl;\n#define REP(i, x, n) for(int i = x; i < n; i++)\ntemplate<class T, class C> void chmax(T& a, C b) { a > b ? : a = b; }\ntemplate<class T, class C> void chmin(T& a, C b) { a < b ? : a = b; }\n\n\n\n#include <algorithm>\n#include <vector>\n#include <functional>\n#include <climits>\n\nclass warshall_floyd\n{\nprivate:\n    int node_num;\n    bool is_negative_graph;\n    std::vector<std::vector<long long>> cost_matrix;//隣接行列を構築\n    std::vector<std::vector<int>> pred;//経路（遷移元）を保持\n\npublic:\n    warshall_floyd(const int node_num, const std::vector<std::vector<long long>> &adj_matrix);\n    long long get_cost(int start, int end) const;\n    std::vector<int> get_min_path(int start, int end) const;\n};\n\nwarshall_floyd::warshall_floyd(const int node_num,\n    const std::vector<std::vector<long long>> &adj_matrix) :\n    cost_matrix(adj_matrix),\n    node_num(node_num),\n    is_negative_graph(false),\n    pred(node_num + 1, std::vector<int>(node_num + 1, INT_MAX))\n{\n    //predの初期化\n    for (int i = 0; i <= node_num; i++) {\n        for (int j = 0; j <= node_num; j++) {\n            if (i == j) pred[i][j] = -1;\n            else if (adj_matrix[i][j] < LLONG_MAX) {\n                pred[i][j] = i;\n            }\n        }\n    }\n    //ワーシャルフロイドの更新式\n    for (int k = 0; k <= node_num; k++) {\n        for (int i = 0; i <= node_num; i++) {\n            for (int j = 0; j <= node_num; j++) {\n                if (cost_matrix[i][k] < LLONG_MAX && cost_matrix[k][j] < LLONG_MAX) {\n                    if (cost_matrix[i][k] + cost_matrix[k][j] < cost_matrix[i][j]) {\n                        cost_matrix[i][j] = cost_matrix[i][k] + cost_matrix[k][j];\n                        //経路復元用\n                        //pred[i][j]にはi→jの最短経路におけるjの1つ前の頂点が入る。\n                        //pred[k][j]にはk→jの最短経路におけるjの1つ前の頂点が入っている。\n                        //この処理を通るということは最短経路がkを使った経路に変わる\n                        //ということでありi→jへの経路の中にk→jの最短経路を含むことになる。\n                        //従って新しいi→jにおけるjの１つ前の頂点は\n                        //k→jにおけるjの１つ前の頂点、すなわちpred[k][j]となる。\n                        pred[i][j] = pred[k][j];\n                    }\n                }\n            }\n        }\n    }\n\n}\n\n\n\n\nlong long warshall_floyd::get_cost(int start, int end) const {\n    return cost_matrix[start][end];\n}\n\nstd::vector<int> warshall_floyd::get_min_path(int start, int end) const {\n    int node = end;\n    std::vector<int> vec;\n    vec.push_back(node);\n    //終点から始点までの経路をたどる\n    while (1) {\n        //負のサイクルを含む頂点or\n        //始点から辿れない頂点or\n        //始点であれば終了\n        if (node == start) break;\n        if (cost_matrix[node][node] < 0 ||\n            pred[start][node] >= INT_MAX ||\n            pred[start][node] == -1) break;\n        node = pred[start][node];\n        vec.push_back(node);\n    }\n    std::reverse(vec.begin(), vec.end());\n    return vec;\n}\n\n\nint main() {\n    ios_base::sync_with_stdio(false);\n    cin.tie(NULL);\n    int N, M;\n    ll L;\n    cin >> N >> M >> L;\n    v2ll adj_matrix(N + 1, vll(N + 1, LLONG_MAX));\n    rep(i, M) {\n        int a, b, c;\n        cin >> a >> b >> c;\n        if (c <= L)\n        {\n            adj_matrix[a][b] = c;\n            adj_matrix[b][a] = c;\n        }\n    }\n    warshall_floyd wf(N, adj_matrix);\n    int Q;\n    cin >> Q;\n    vint s(Q), t(Q);\n    vll ans(Q);\n    rep(i, Q) {\n        cin >> s[i] >> t[i];\n        if (wf.get_cost(s[i], t[i]) >= LLONG_MAX) {\n            cout << -1 << endl;\n            continue;\n        }\n        auto min_path = wf.get_min_path(s[i], t[i]);\n        int ans = 0;\n        \n        int fill_point = min_path[0];\n        \n        REP(j, 1, min_path.size()) {\n            if (wf.get_cost(fill_point, min_path[j]) > ll(L)) {\n                fill_point = min_path[j - 1];\n                ans++;\n            }\n\n        }\n        int add = 0;\n        if (wf.get_cost(s[i], t[i]) % L != 0) add = 1;\n        cout << max(ll(ans), wf.get_cost(s[i], t[i])/L + add - 1) << endl;\n    }\n    \n    return 0;\n}", "problem_context": "Score : 500 points\n\nProblem Statement\n\nThere are N towns numbered 1 to N and M roads. The i-th road connects Town A_i and Town B_i bidirectionally and has a length of C_i.\n\nTakahashi will travel between these towns by car, passing through these roads. The fuel tank of his car can contain at most L liters of fuel, and one liter of fuel is consumed for each unit distance traveled. When visiting a town while traveling, he can full the tank (or choose not to do so). Travel that results in the tank becoming empty halfway on the road cannot be done.\n\nProcess the following Q queries:\n\nThe tank is now full. Find the minimum number of times he needs to full his tank while traveling from Town s_i to Town t_i. If Town t_i is unreachable, print -1.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 300\n\n0 \\leq M \\leq \\frac{N(N-1)}{2}\n\n1 \\leq L \\leq 10^9\n\n1 \\leq A_i, B_i \\leq N\n\nA_i \\neq B_i\n\n\\left(A_i, B_i\\right) \\neq \\left(A_j, B_j\\right) (if i \\neq j)\n\n\\left(A_i, B_i\\right) \\neq \\left(B_j, A_j\\right) (if i \\neq j)\n\n1 \\leq C_i \\leq 10^9\n\n1 \\leq Q \\leq N\\left(N-1\\right)\n\n1 \\leq s_i, t_i \\leq N\n\ns_i \\neq t_i\n\n\\left(s_i, t_i\\right) \\neq \\left(s_j, t_j\\right) (if i \\neq j)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M L\nA_1 B_1 C_1\n:\nA_M B_M C_M\nQ\ns_1 t_1\n:\ns_Q t_Q\n\nOutput\n\nPrint Q lines.\n\nThe i-th line should contain the minimum number of times the tank needs to be fulled while traveling from Town s_i to Town t_i. If Town t_i is unreachable, the line should contain -1 instead.\n\nSample Input 1\n\n3 2 5\n1 2 3\n2 3 3\n2\n3 2\n1 3\n\nSample Output 1\n\n0\n1\n\nTo travel from Town 3 to Town 2, we can use the second road to reach Town 2 without fueling the tank on the way.\n\nTo travel from Town 1 to Town 3, we can first use the first road to get to Town 2, full the tank, and use the second road to reach Town 3.\n\nSample Input 2\n\n4 0 1\n1\n2 1\n\nSample Output 2\n\n-1\n\nThere may be no road at all.\n\nSample Input 3\n\n5 4 4\n1 2 2\n2 3 2\n3 4 3\n4 5 2\n20\n2 1\n3 1\n4 1\n5 1\n1 2\n3 2\n4 2\n5 2\n1 3\n2 3\n4 3\n5 3\n1 4\n2 4\n3 4\n5 4\n1 5\n2 5\n3 5\n4 5\n\nSample Output 3\n\n0\n0\n1\n2\n0\n0\n1\n2\n0\n0\n0\n1\n1\n1\n0\n0\n2\n2\n1\n0", "sample_input": "3 2 5\n1 2 3\n2 3 3\n2\n3 2\n1 3\n"}, "reference_outputs": ["0\n1\n"], "source_document_id": "p02889", "source_text": "Score : 500 points\n\nProblem Statement\n\nThere are N towns numbered 1 to N and M roads. The i-th road connects Town A_i and Town B_i bidirectionally and has a length of C_i.\n\nTakahashi will travel between these towns by car, passing through these roads. The fuel tank of his car can contain at most L liters of fuel, and one liter of fuel is consumed for each unit distance traveled. When visiting a town while traveling, he can full the tank (or choose not to do so). Travel that results in the tank becoming empty halfway on the road cannot be done.\n\nProcess the following Q queries:\n\nThe tank is now full. Find the minimum number of times he needs to full his tank while traveling from Town s_i to Town t_i. If Town t_i is unreachable, print -1.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 300\n\n0 \\leq M \\leq \\frac{N(N-1)}{2}\n\n1 \\leq L \\leq 10^9\n\n1 \\leq A_i, B_i \\leq N\n\nA_i \\neq B_i\n\n\\left(A_i, B_i\\right) \\neq \\left(A_j, B_j\\right) (if i \\neq j)\n\n\\left(A_i, B_i\\right) \\neq \\left(B_j, A_j\\right) (if i \\neq j)\n\n1 \\leq C_i \\leq 10^9\n\n1 \\leq Q \\leq N\\left(N-1\\right)\n\n1 \\leq s_i, t_i \\leq N\n\ns_i \\neq t_i\n\n\\left(s_i, t_i\\right) \\neq \\left(s_j, t_j\\right) (if i \\neq j)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M L\nA_1 B_1 C_1\n:\nA_M B_M C_M\nQ\ns_1 t_1\n:\ns_Q t_Q\n\nOutput\n\nPrint Q lines.\n\nThe i-th line should contain the minimum number of times the tank needs to be fulled while traveling from Town s_i to Town t_i. If Town t_i is unreachable, the line should contain -1 instead.\n\nSample Input 1\n\n3 2 5\n1 2 3\n2 3 3\n2\n3 2\n1 3\n\nSample Output 1\n\n0\n1\n\nTo travel from Town 3 to Town 2, we can use the second road to reach Town 2 without fueling the tank on the way.\n\nTo travel from Town 1 to Town 3, we can first use the first road to get to Town 2, full the tank, and use the second road to reach Town 3.\n\nSample Input 2\n\n4 0 1\n1\n2 1\n\nSample Output 2\n\n-1\n\nThere may be no road at all.\n\nSample Input 3\n\n5 4 4\n1 2 2\n2 3 2\n3 4 3\n4 5 2\n20\n2 1\n3 1\n4 1\n5 1\n1 2\n3 2\n4 2\n5 2\n1 3\n2 3\n4 3\n5 3\n1 4\n2 4\n3 4\n5 4\n1 5\n2 5\n3 5\n4 5\n\nSample Output 3\n\n0\n0\n1\n2\n0\n0\n1\n2\n0\n0\n0\n1\n1\n1\n0\n0\n2\n2\n1\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 5286, "cpu_time_ms": 292, "memory_kb": 3712}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s719151432", "group_id": "codeNet:p02889", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n  int n, m, l;\n  cin>>n>>m>>l;\n  long long cost[n][n];\n  long long inf = 300 * 1e9;\n  for (int i=0; i<n; i++) {\n    for (int j=0; j<n; j++) {\n      cost[i][j] = inf;\n    }\n    cost[i][i] = 0;\n  }\n  for (int i=0; i<m; i++) {\n    int a, b, c;\n    cin>>a>>b>>c;\n    --a;\n    --b;\n    cost[a][b] = c;\n    cost[b][a] = c;\n  }\n  for (int k=0; k<n; k++) {\n    for (int i=0; i<n; i++) {\n      for (int j=0; j<n; j++) {\n        if (cost[i][k] != inf && cost[k][j] != inf) {\n          cost[i][j] = min(cost[i][k] + cost[k][j], cost[i][j]);\n        }\n      }\n    }\n  }\n  int edge[n][n];\n  for (int i=0; i<n; i++) {\n    for (int j=0; j<n; j++) {\n      if (i == j) {\n        edge[i][j] = 0;\n      } else if (cost[i][j] <= l) {\n        edge[i][j] = 1;\n      } else {\n        edge[i][j] = 0;\n      }\n    }\n  }\n  int num[n][n];\n  for (int i=0; i<n; i++) {\n    for (int j=0; j<n; j++) {\n      if (i == j) {\n        num[i][j] = 0;\n      } else if (edge[i][j] == 1) {\n        num[i][j] = 1;\n      } else {\n        num[i][j] = n;\n      }\n    }\n  }\n  for (int k=0; k<n; k++) {\n    for (int i=0; i<n; i++) {\n      for (int j=0; j<n; j++) {\n        if (num[i][k] != n && num[k][k] != n) {\n          num[i][j] = min(num[i][k] + num[k][j], num[i][j]);\n        }\n      }\n    }\n  }\n  int q;\n  cin>>q;\n  for (int i=0; i<q; i++) {\n    int s, t;\n    cin>>s>>t;\n    --s;\n    --t;\n    if (num[s][t] == n) {\n      cout<<-1<<endl;\n    } else {\n      cout<<num[s][t]-1<<endl;\n    }\n  }\n}", "language": "C++", "metadata": {"date": 1571536624, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02889.html", "problem_id": "p02889", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02889/input.txt", "sample_output_relpath": "derived/input_output/data/p02889/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02889/C++/s719151432.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s719151432", "user_id": "u313766957"}, "prompt_components": {"gold_output": "0\n1\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n  int n, m, l;\n  cin>>n>>m>>l;\n  long long cost[n][n];\n  long long inf = 300 * 1e9;\n  for (int i=0; i<n; i++) {\n    for (int j=0; j<n; j++) {\n      cost[i][j] = inf;\n    }\n    cost[i][i] = 0;\n  }\n  for (int i=0; i<m; i++) {\n    int a, b, c;\n    cin>>a>>b>>c;\n    --a;\n    --b;\n    cost[a][b] = c;\n    cost[b][a] = c;\n  }\n  for (int k=0; k<n; k++) {\n    for (int i=0; i<n; i++) {\n      for (int j=0; j<n; j++) {\n        if (cost[i][k] != inf && cost[k][j] != inf) {\n          cost[i][j] = min(cost[i][k] + cost[k][j], cost[i][j]);\n        }\n      }\n    }\n  }\n  int edge[n][n];\n  for (int i=0; i<n; i++) {\n    for (int j=0; j<n; j++) {\n      if (i == j) {\n        edge[i][j] = 0;\n      } else if (cost[i][j] <= l) {\n        edge[i][j] = 1;\n      } else {\n        edge[i][j] = 0;\n      }\n    }\n  }\n  int num[n][n];\n  for (int i=0; i<n; i++) {\n    for (int j=0; j<n; j++) {\n      if (i == j) {\n        num[i][j] = 0;\n      } else if (edge[i][j] == 1) {\n        num[i][j] = 1;\n      } else {\n        num[i][j] = n;\n      }\n    }\n  }\n  for (int k=0; k<n; k++) {\n    for (int i=0; i<n; i++) {\n      for (int j=0; j<n; j++) {\n        if (num[i][k] != n && num[k][k] != n) {\n          num[i][j] = min(num[i][k] + num[k][j], num[i][j]);\n        }\n      }\n    }\n  }\n  int q;\n  cin>>q;\n  for (int i=0; i<q; i++) {\n    int s, t;\n    cin>>s>>t;\n    --s;\n    --t;\n    if (num[s][t] == n) {\n      cout<<-1<<endl;\n    } else {\n      cout<<num[s][t]-1<<endl;\n    }\n  }\n}", "problem_context": "Score : 500 points\n\nProblem Statement\n\nThere are N towns numbered 1 to N and M roads. The i-th road connects Town A_i and Town B_i bidirectionally and has a length of C_i.\n\nTakahashi will travel between these towns by car, passing through these roads. The fuel tank of his car can contain at most L liters of fuel, and one liter of fuel is consumed for each unit distance traveled. When visiting a town while traveling, he can full the tank (or choose not to do so). Travel that results in the tank becoming empty halfway on the road cannot be done.\n\nProcess the following Q queries:\n\nThe tank is now full. Find the minimum number of times he needs to full his tank while traveling from Town s_i to Town t_i. If Town t_i is unreachable, print -1.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 300\n\n0 \\leq M \\leq \\frac{N(N-1)}{2}\n\n1 \\leq L \\leq 10^9\n\n1 \\leq A_i, B_i \\leq N\n\nA_i \\neq B_i\n\n\\left(A_i, B_i\\right) \\neq \\left(A_j, B_j\\right) (if i \\neq j)\n\n\\left(A_i, B_i\\right) \\neq \\left(B_j, A_j\\right) (if i \\neq j)\n\n1 \\leq C_i \\leq 10^9\n\n1 \\leq Q \\leq N\\left(N-1\\right)\n\n1 \\leq s_i, t_i \\leq N\n\ns_i \\neq t_i\n\n\\left(s_i, t_i\\right) \\neq \\left(s_j, t_j\\right) (if i \\neq j)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M L\nA_1 B_1 C_1\n:\nA_M B_M C_M\nQ\ns_1 t_1\n:\ns_Q t_Q\n\nOutput\n\nPrint Q lines.\n\nThe i-th line should contain the minimum number of times the tank needs to be fulled while traveling from Town s_i to Town t_i. If Town t_i is unreachable, the line should contain -1 instead.\n\nSample Input 1\n\n3 2 5\n1 2 3\n2 3 3\n2\n3 2\n1 3\n\nSample Output 1\n\n0\n1\n\nTo travel from Town 3 to Town 2, we can use the second road to reach Town 2 without fueling the tank on the way.\n\nTo travel from Town 1 to Town 3, we can first use the first road to get to Town 2, full the tank, and use the second road to reach Town 3.\n\nSample Input 2\n\n4 0 1\n1\n2 1\n\nSample Output 2\n\n-1\n\nThere may be no road at all.\n\nSample Input 3\n\n5 4 4\n1 2 2\n2 3 2\n3 4 3\n4 5 2\n20\n2 1\n3 1\n4 1\n5 1\n1 2\n3 2\n4 2\n5 2\n1 3\n2 3\n4 3\n5 3\n1 4\n2 4\n3 4\n5 4\n1 5\n2 5\n3 5\n4 5\n\nSample Output 3\n\n0\n0\n1\n2\n0\n0\n1\n2\n0\n0\n0\n1\n1\n1\n0\n0\n2\n2\n1\n0", "sample_input": "3 2 5\n1 2 3\n2 3 3\n2\n3 2\n1 3\n"}, "reference_outputs": ["0\n1\n"], "source_document_id": "p02889", "source_text": "Score : 500 points\n\nProblem Statement\n\nThere are N towns numbered 1 to N and M roads. The i-th road connects Town A_i and Town B_i bidirectionally and has a length of C_i.\n\nTakahashi will travel between these towns by car, passing through these roads. The fuel tank of his car can contain at most L liters of fuel, and one liter of fuel is consumed for each unit distance traveled. When visiting a town while traveling, he can full the tank (or choose not to do so). Travel that results in the tank becoming empty halfway on the road cannot be done.\n\nProcess the following Q queries:\n\nThe tank is now full. Find the minimum number of times he needs to full his tank while traveling from Town s_i to Town t_i. If Town t_i is unreachable, print -1.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 300\n\n0 \\leq M \\leq \\frac{N(N-1)}{2}\n\n1 \\leq L \\leq 10^9\n\n1 \\leq A_i, B_i \\leq N\n\nA_i \\neq B_i\n\n\\left(A_i, B_i\\right) \\neq \\left(A_j, B_j\\right) (if i \\neq j)\n\n\\left(A_i, B_i\\right) \\neq \\left(B_j, A_j\\right) (if i \\neq j)\n\n1 \\leq C_i \\leq 10^9\n\n1 \\leq Q \\leq N\\left(N-1\\right)\n\n1 \\leq s_i, t_i \\leq N\n\ns_i \\neq t_i\n\n\\left(s_i, t_i\\right) \\neq \\left(s_j, t_j\\right) (if i \\neq j)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M L\nA_1 B_1 C_1\n:\nA_M B_M C_M\nQ\ns_1 t_1\n:\ns_Q t_Q\n\nOutput\n\nPrint Q lines.\n\nThe i-th line should contain the minimum number of times the tank needs to be fulled while traveling from Town s_i to Town t_i. If Town t_i is unreachable, the line should contain -1 instead.\n\nSample Input 1\n\n3 2 5\n1 2 3\n2 3 3\n2\n3 2\n1 3\n\nSample Output 1\n\n0\n1\n\nTo travel from Town 3 to Town 2, we can use the second road to reach Town 2 without fueling the tank on the way.\n\nTo travel from Town 1 to Town 3, we can first use the first road to get to Town 2, full the tank, and use the second road to reach Town 3.\n\nSample Input 2\n\n4 0 1\n1\n2 1\n\nSample Output 2\n\n-1\n\nThere may be no road at all.\n\nSample Input 3\n\n5 4 4\n1 2 2\n2 3 2\n3 4 3\n4 5 2\n20\n2 1\n3 1\n4 1\n5 1\n1 2\n3 2\n4 2\n5 2\n1 3\n2 3\n4 3\n5 3\n1 4\n2 4\n3 4\n5 4\n1 5\n2 5\n3 5\n4 5\n\nSample Output 3\n\n0\n0\n1\n2\n0\n0\n1\n2\n0\n0\n0\n1\n1\n1\n0\n0\n2\n2\n1\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1512, "cpu_time_ms": 309, "memory_kb": 1920}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s564812969", "group_id": "codeNet:p02900", "input_text": "#include <cstdio>\n#include <cctype>\n#define int long long\n#define il inline\n#define rgi register long long\n#define sp putchar(' ')\n#define el putchar('\\n')\nusing namespace std;\nil int ri()\n{\n\tregister int o1=0;\n\tregister bool o2=0;\n\tregister char o3;\n\twhile(!isdigit(o3=getchar()))\n\t\to2|=o3=='-';\n\twhile(isdigit(o3))\n\t\to1=(o1<<1)+(o1<<3)+(o3^48),o3=getchar();\n\treturn o2?-o1:o1;\n}\nil void wi(int o1)\n{\n\tif(o1<0)\n\t\tputchar('-'),o1=-o1;\n\trgi o2=o1/10;\n\tif(o2)\n\t\twi(o2);\n\tputchar((o1-(o2<<1)-(o2<<3))^48);\n}\nint a,b,c;\nil int gcd(int p,int q)\n{\n\tif(q==0)\n\t\treturn p;\n\treturn gcd(q,p%q);\n}\nil int divide(int n)\n{\n\tint ret=0;\n\tfor(rgi i=2;i*i<=n;++i)\n\t\tif(n%i==0)\n\t\t{\n\t\t\t++ret;\n\t\t\twhile(n%i==0)\n\t\t\t\tn/=i;\n\t\t}\n\tif(n>1)\n\t\t++ret;\n\treturn ret+1;\n}\nsigned main()\n{\n\ta=ri(),b=ri();\n\tc=gcd(a,b);\n\tint ans=divide(c);\n\twi(ans);\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1569720005, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02900.html", "problem_id": "p02900", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02900/input.txt", "sample_output_relpath": "derived/input_output/data/p02900/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02900/C++/s564812969.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s564812969", "user_id": "u862024582"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <cstdio>\n#include <cctype>\n#define int long long\n#define il inline\n#define rgi register long long\n#define sp putchar(' ')\n#define el putchar('\\n')\nusing namespace std;\nil int ri()\n{\n\tregister int o1=0;\n\tregister bool o2=0;\n\tregister char o3;\n\twhile(!isdigit(o3=getchar()))\n\t\to2|=o3=='-';\n\twhile(isdigit(o3))\n\t\to1=(o1<<1)+(o1<<3)+(o3^48),o3=getchar();\n\treturn o2?-o1:o1;\n}\nil void wi(int o1)\n{\n\tif(o1<0)\n\t\tputchar('-'),o1=-o1;\n\trgi o2=o1/10;\n\tif(o2)\n\t\twi(o2);\n\tputchar((o1-(o2<<1)-(o2<<3))^48);\n}\nint a,b,c;\nil int gcd(int p,int q)\n{\n\tif(q==0)\n\t\treturn p;\n\treturn gcd(q,p%q);\n}\nil int divide(int n)\n{\n\tint ret=0;\n\tfor(rgi i=2;i*i<=n;++i)\n\t\tif(n%i==0)\n\t\t{\n\t\t\t++ret;\n\t\t\twhile(n%i==0)\n\t\t\t\tn/=i;\n\t\t}\n\tif(n>1)\n\t\t++ret;\n\treturn ret+1;\n}\nsigned main()\n{\n\ta=ri(),b=ri();\n\tc=gcd(a,b);\n\tint ans=divide(c);\n\twi(ans);\n\treturn 0;\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nGiven are positive integers A and B.\n\nLet us choose some number of positive common divisors of A and B.\n\nHere, any two of the chosen divisors must be coprime.\n\nAt most, how many divisors can we choose?\n\nDefinition of common divisor\n\nAn integer d is said to be a common divisor of integers x and y when d divides both x and y.\n\nDefinition of being coprime\n\nIntegers x and y are said to be coprime when x and y have no positive common divisors other than 1.\n\nDefinition of dividing\n\nAn integer x is said to divide another integer y when there exists an integer \\alpha such that y = \\alpha x.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq A, B \\leq 10^{12}\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nPrint the maximum number of divisors that can be chosen to satisfy the condition.\n\nSample Input 1\n\n12 18\n\nSample Output 1\n\n3\n\n12 and 18 have the following positive common divisors: 1, 2, 3, and 6.\n\n1 and 2 are coprime, 2 and 3 are coprime, and 3 and 1 are coprime, so we can choose 1, 2, and 3, which achieve the maximum result.\n\nSample Input 2\n\n420 660\n\nSample Output 2\n\n4\n\nSample Input 3\n\n1 2019\n\nSample Output 3\n\n1\n\n1 and 2019 have no positive common divisors other than 1.", "sample_input": "12 18\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02900", "source_text": "Score : 400 points\n\nProblem Statement\n\nGiven are positive integers A and B.\n\nLet us choose some number of positive common divisors of A and B.\n\nHere, any two of the chosen divisors must be coprime.\n\nAt most, how many divisors can we choose?\n\nDefinition of common divisor\n\nAn integer d is said to be a common divisor of integers x and y when d divides both x and y.\n\nDefinition of being coprime\n\nIntegers x and y are said to be coprime when x and y have no positive common divisors other than 1.\n\nDefinition of dividing\n\nAn integer x is said to divide another integer y when there exists an integer \\alpha such that y = \\alpha x.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq A, B \\leq 10^{12}\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nPrint the maximum number of divisors that can be chosen to satisfy the condition.\n\nSample Input 1\n\n12 18\n\nSample Output 1\n\n3\n\n12 and 18 have the following positive common divisors: 1, 2, 3, and 6.\n\n1 and 2 are coprime, 2 and 3 are coprime, and 3 and 1 are coprime, so we can choose 1, 2, and 3, which achieve the maximum result.\n\nSample Input 2\n\n420 660\n\nSample Output 2\n\n4\n\nSample Input 3\n\n1 2019\n\nSample Output 3\n\n1\n\n1 and 2019 have no positive common divisors other than 1.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 827, "cpu_time_ms": 10, "memory_kb": 128}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s539784353", "group_id": "codeNet:p02903", "input_text": "#include <cstdio>\n#include <iostream>\n#include <iomanip>\n#include <functional>\n#include <algorithm>\n#include <string>\n#include <vector>\n#include <limits>\n#include <numeric>\n#include <queue>\n#include <cmath>\n#include <set>\n#include <map>\n#include <stack>\n\nusing namespace std;\n\n#define INFint (1<<30)\n#define BOUND 27182818284\n#define MAT 2\n\ntypedef long long ll;\ntypedef long long int lli;\ntypedef pair<ll, ll> P;\n\nll MOD = 1000000007;\nconst ll INF = (1ll<<60);\n#define rep(i, n) for(int i = 0; i < (int)(n); i++)\n#define repi(i, a, b) for(int i=int(a);i<int(b);++i)\n\ntemplate<class T>\nbool umax(T &a, const T &b) {\n    if (a < b) {\n        a = b;\n        return true;\n    }\n    return false;\n}\n\ntemplate<class T>\nbool umin(T &a, const T &b) {\n    if (b < a) {\n        a = b;\n        return true;\n    }\n    return false;\n}\n\n// gcd\ntemplate<typename T>\nT gcd(T a, T b) {\n    if (a == 0)\n        return b;\n    return gcd(b % a, a);\n}\n\nint findGCD(int arr[], int n) {\n    int result = arr[0];\n    for (int i = 1; i < n; i++)\n        result = gcd(arr[i], result);\n    return result;\n}\n\ntemplate<typename T>\nT lcm(T m, T n) {\n    // 引数に0がある場合は0を返す\n    if ((0 == m) || (0 == n))\n        return 0;\n    return ((m / gcd(m, n)) * n); // lcm = m * n / gcd(m,n)\n}\n\ntemplate<typename A, size_t N, typename T>\nvoid Fill(A (&array)[N], const T &val) {\n    fill((T *) array, (T *) (array + N), val);\n}\n\n\nint dx[5] = {1, 0, -1, 0};\nint dy[5] = {0, 1, 0, -1};\n\n// v.front() = -BOUND;\n// v.back() = BOUND;\n\n//struct edge{\n//    int cost, to;\n//\n//    edge(int in_cost, int in_to){\n//        cost=in_cost;\n//        to=in_to;\n//    }\n//    bool operator<(const edge &a) const\n//    {\n//        return cost > a.cost;\n//    }\n//};\nint main() {\n    int H,W,A,B; cin >> H >> W >> A >> B;\n    int a[1010][1010];\n    Fill(a,0);\n\n    for(int i=0; i<H; i++){\n        for(int j=0; j<W; j++){\n            if( (i<B && j<A)||(i>=B && j>=A) ){\n                a[i][j]=1;\n            }\n        }\n    }\n\n    for(int i=0; i<H; i++){\n        for(int j=0; j<W; j++){\n            cout << a[i][j];\n        }\n        cout << endl;\n    }\n    return 0;\n}", "language": "C++", "metadata": {"date": 1572585882, "filename_ext": "cpp", "original_language": "C++14 (Clang 3.8.0)", "problem_description_relpath": "problem_descriptions/p02903.html", "problem_id": "p02903", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02903/input.txt", "sample_output_relpath": "derived/input_output/data/p02903/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02903/C++/s539784353.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s539784353", "user_id": "u991664217"}, "prompt_components": {"gold_output": "100\n010\n001\n", "input_to_evaluate": "#include <cstdio>\n#include <iostream>\n#include <iomanip>\n#include <functional>\n#include <algorithm>\n#include <string>\n#include <vector>\n#include <limits>\n#include <numeric>\n#include <queue>\n#include <cmath>\n#include <set>\n#include <map>\n#include <stack>\n\nusing namespace std;\n\n#define INFint (1<<30)\n#define BOUND 27182818284\n#define MAT 2\n\ntypedef long long ll;\ntypedef long long int lli;\ntypedef pair<ll, ll> P;\n\nll MOD = 1000000007;\nconst ll INF = (1ll<<60);\n#define rep(i, n) for(int i = 0; i < (int)(n); i++)\n#define repi(i, a, b) for(int i=int(a);i<int(b);++i)\n\ntemplate<class T>\nbool umax(T &a, const T &b) {\n    if (a < b) {\n        a = b;\n        return true;\n    }\n    return false;\n}\n\ntemplate<class T>\nbool umin(T &a, const T &b) {\n    if (b < a) {\n        a = b;\n        return true;\n    }\n    return false;\n}\n\n// gcd\ntemplate<typename T>\nT gcd(T a, T b) {\n    if (a == 0)\n        return b;\n    return gcd(b % a, a);\n}\n\nint findGCD(int arr[], int n) {\n    int result = arr[0];\n    for (int i = 1; i < n; i++)\n        result = gcd(arr[i], result);\n    return result;\n}\n\ntemplate<typename T>\nT lcm(T m, T n) {\n    // 引数に0がある場合は0を返す\n    if ((0 == m) || (0 == n))\n        return 0;\n    return ((m / gcd(m, n)) * n); // lcm = m * n / gcd(m,n)\n}\n\ntemplate<typename A, size_t N, typename T>\nvoid Fill(A (&array)[N], const T &val) {\n    fill((T *) array, (T *) (array + N), val);\n}\n\n\nint dx[5] = {1, 0, -1, 0};\nint dy[5] = {0, 1, 0, -1};\n\n// v.front() = -BOUND;\n// v.back() = BOUND;\n\n//struct edge{\n//    int cost, to;\n//\n//    edge(int in_cost, int in_to){\n//        cost=in_cost;\n//        to=in_to;\n//    }\n//    bool operator<(const edge &a) const\n//    {\n//        return cost > a.cost;\n//    }\n//};\nint main() {\n    int H,W,A,B; cin >> H >> W >> A >> B;\n    int a[1010][1010];\n    Fill(a,0);\n\n    for(int i=0; i<H; i++){\n        for(int j=0; j<W; j++){\n            if( (i<B && j<A)||(i>=B && j>=A) ){\n                a[i][j]=1;\n            }\n        }\n    }\n\n    for(int i=0; i<H; i++){\n        for(int j=0; j<W; j++){\n            cout << a[i][j];\n        }\n        cout << endl;\n    }\n    return 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nWe have a square grid with H rows and W columns.\nSnuke wants to write 0 or 1 in each of the squares.\nHere, all of the following conditions have to be satisfied:\n\nFor every row, the smaller of the following is A: the number of 0s contained in the row, and the number of 1s contained in the row. (If these two numbers are equal, “the smaller” should be read as “either”.)\n\nFor every column, the smaller of the following is B: the number of 0s contained in the column, and the number of 1s contained in the column.\n\nDetermine if these conditions can be satisfied by writing 0 or 1 in each of the squares. If the answer is yes, show one way to fill the squares so that the conditions are satisfied.\n\nConstraints\n\n1 \\leq H,W \\leq 1000\n\n0 \\leq A\n\n2 \\times A \\leq W\n\n0 \\leq B\n\n2 \\times B \\leq H\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W A B\n\nOutput\n\nIf the conditions cannot be satisfied by writing 0 or 1 in each of the squares, print -1.\n\nIf the conditions can be satisfied, print one way to fill the squares so that the conditions are satisfied, in the following format:\n\ns_{11}s_{12}\\cdots s_{1W}\ns_{21}s_{22}\\cdots s_{2W}\n\\vdots\ns_{H1}s_{H2}\\cdots s_{HW}\n\nHere s_{ij} is the digit written in the square at the i-th row from the top and the j-th column from the left in the grid.\n\nIf multiple solutions exist, printing any of them will be accepted.\n\nSample Input 1\n\n3 3 1 1\n\nSample Output 1\n\n100\n010\n001\n\nEvery row contains two 0s and one 1, so the first condition is satisfied.\nAlso, every column contains two 0s and one 1, so the second condition is satisfied.\n\nSample Input 2\n\n1 5 2 0\n\nSample Output 2\n\n01010", "sample_input": "3 3 1 1\n"}, "reference_outputs": ["100\n010\n001\n"], "source_document_id": "p02903", "source_text": "Score : 300 points\n\nProblem Statement\n\nWe have a square grid with H rows and W columns.\nSnuke wants to write 0 or 1 in each of the squares.\nHere, all of the following conditions have to be satisfied:\n\nFor every row, the smaller of the following is A: the number of 0s contained in the row, and the number of 1s contained in the row. (If these two numbers are equal, “the smaller” should be read as “either”.)\n\nFor every column, the smaller of the following is B: the number of 0s contained in the column, and the number of 1s contained in the column.\n\nDetermine if these conditions can be satisfied by writing 0 or 1 in each of the squares. If the answer is yes, show one way to fill the squares so that the conditions are satisfied.\n\nConstraints\n\n1 \\leq H,W \\leq 1000\n\n0 \\leq A\n\n2 \\times A \\leq W\n\n0 \\leq B\n\n2 \\times B \\leq H\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W A B\n\nOutput\n\nIf the conditions cannot be satisfied by writing 0 or 1 in each of the squares, print -1.\n\nIf the conditions can be satisfied, print one way to fill the squares so that the conditions are satisfied, in the following format:\n\ns_{11}s_{12}\\cdots s_{1W}\ns_{21}s_{22}\\cdots s_{2W}\n\\vdots\ns_{H1}s_{H2}\\cdots s_{HW}\n\nHere s_{ij} is the digit written in the square at the i-th row from the top and the j-th column from the left in the grid.\n\nIf multiple solutions exist, printing any of them will be accepted.\n\nSample Input 1\n\n3 3 1 1\n\nSample Output 1\n\n100\n010\n001\n\nEvery row contains two 0s and one 1, so the first condition is satisfied.\nAlso, every column contains two 0s and one 1, so the second condition is satisfied.\n\nSample Input 2\n\n1 5 2 0\n\nSample Output 2\n\n01010", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2136, "cpu_time_ms": 187, "memory_kb": 5248}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s313351196", "group_id": "codeNet:p02903", "input_text": "#define DEBUG 1\n#include <algorithm>\n#include <cmath>\n#include <cstring>\n#include <deque>\n#include <iomanip>\n#include <iostream>\n#include <map>\n#include <queue>\n#include <set>\n#include <string>\n#include <tuple>\n#include <utility>\n#include <vector>\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing ld = long double;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing pll = pair<ll, ll>;\nusing tll = tuple<ll, ll, ll>;\n#define all(v) (v).begin(), (v).end()\n#define for1(i, n) for (ll i = 0; i < (n); i++)\n#define for2(i, m, n) for (ll i = (m); i < (n); i++)\n#define for3(i, m, n, d) for (ll i = (m); i < (n); i += (d))\n#define rfor2(i, m, n) for (ll i = (m); i > (n); i--)\n#define rfor3(i, m, n, d) for (ll i = (m); i > (n); i += (d))\n#define INF 1111111111111111111LL\n#define MOD 1000000007LL  // 10**9 + 7\n#define print(...) print_1(__VA_ARGS__)\n#define in(...) in_1(__VA_ARGS__)\n#if DEBUG\n#define dump(...) dump_1(#__VA_ARGS__, __VA_ARGS__)\n#else\n#define dump(...)\n#endif\ntemplate <typename Head>\nvoid dump_1(const char* str, Head&& h)\n{\n    cerr << str << \": \" << h << '\\n';\n}\ntemplate <typename Head, typename... Tail>\nvoid dump_1(const char* str, Head&& h, Tail&&... t)\n{\n    while (*str != ',') {\n        cerr << *str++;\n    }\n    cerr << \": \" << h << ' ';\n    dump_1(str + 1, t...);\n}\ntemplate <typename T1, typename T2>\nostream& operator<<(ostream& os, const pair<T1, T2>& v)\n{\n    os << '(' << v.first << \", \" << v.second << ')';\n    return os;\n}\ntemplate <typename T1, typename T2, typename T3>\nostream& operator<<(ostream& os, const tuple<T1, T2, T3>& v)\n{\n    os << '(' << get<0>(v) << \", \" << get<1>(v) << \", \" << get<2>(v) << ')';\n    return os;\n}\ntemplate <typename T>\nostream& operator<<(ostream& os, const vector<T>& v)\n{\n    for (auto it = v.begin(); it != v.end(); it++) {\n        if (it != v.begin()) {\n            os << ' ';\n        }\n        os << *it;\n    }\n    return os;\n}\ntemplate <typename T>\nostream& operator<<(ostream& os, const set<T>& v)\n{\n    for (auto it = v.begin(); it != v.end(); it++) {\n        if (it != v.begin()) {\n            os << ' ';\n        }\n        os << *it;\n    }\n    return os;\n}\ntemplate <typename T>\nostream& operator<<(ostream& os, const multiset<T>& v)\n{\n    for (auto it = v.begin(); it != v.end(); it++) {\n        if (it != v.begin()) {\n            os << ' ';\n        }\n        os << *it;\n    }\n    return os;\n}\ntemplate <typename T1, typename T2>\nostream& operator<<(ostream& os, const map<T1, T2>& v)\n{\n    os << '{';\n    for (auto it = v.begin(); it != v.end(); it++) {\n        if (it != v.begin()) {\n            os << \", \";\n        }\n        os << it->first << ':' << it->second;\n    }\n    os << '}';\n    return os;\n}\nvoid Yes(void) { cout << \"Yes\" << '\\n'; }\nvoid No(void) { cout << \"No\" << '\\n'; }\nvoid YES(void) { cout << \"YES\" << '\\n'; }\nvoid NO(void) { cout << \"NO\" << '\\n'; }\ntemplate <typename T>\nvoid chmax(T& a, const T& b)\n{\n    if (a < b) {\n        a = b;\n    }\n}\ntemplate <typename T>\nvoid chmin(T& a, const T& b)\n{\n    if (a > b) {\n        a = b;\n    }\n}\ntemplate <typename T>\nvoid vin(vector<T>& v, ll len)\n{\n    for1 (i, len) {\n        cin >> v[i];\n    }\n}\ntemplate <typename Head>\nvoid in_1(Head& h)\n{\n    cin >> h;\n}\ntemplate <typename Head, typename... Tail>\nvoid in_1(Head& h, Tail&... t)\n{\n    cin >> h;\n    in_1(t...);\n}\ntemplate <typename Head>\nvoid print_1(Head&& h)\n{\n    cout << h << '\\n';\n}\ntemplate <typename Head, typename... Tail>\nvoid print_1(Head&& h, Tail&&... t)\n{\n    cout << h << ' ';\n    print_1(t...);\n}\n//---------------------------------------------------------\nvoid solve()\n{\n    ll H, W, A, B;\n    in(H, W, A, B);\n    if (A == 0 && B == 0) {\n        for1 (h, H) {\n            for1 (w, W) {\n                cout << \"0\";\n            }\n            cout << \"\\n\";\n        }\n        return;\n    }\n    if (B == 0) {\n        for1 (h, H) {\n            for1 (w, A) {\n                cout << \"1\";\n            }\n            for1 (w, W - A) {\n                cout << \"0\";\n            }\n            cout << \"\\n\";\n        }\n        return;\n    }\n    if (A == 0) {\n        for1 (h, B) {\n            for1 (w, W) {\n                cout << \"1\";\n            }\n            cout << \"\\n\";\n        }\n        for1 (h, H - B) {\n            for1 (w, W) {\n                cout << \"0\";\n            }\n            cout << \"\\n\";\n        }\n        return;\n    }\n    if ((W % A == 0) && (H % B == 0) && (W / A == H / B)) {\n        for1 (h, H) {\n            for1 (w, W) {\n                if (w / A == h / B) {\n                    cout << \"1\";\n                }\n                else {\n                    cout << \"0\";\n                }\n            }\n            cout << \"\\n\";\n        }\n        return;\n    }\n    ll ans[1001][1001];\n    ll total[1001];\n\n    for2 (wd, 1, A + 1) {\n        for1 (h, H) {\n            for1 (w, W) {\n                if ((w + wd * h) % W < A) {\n                    ans[h][w] = 1;\n                }\n                else {\n                    ans[h][w] = 0;\n                }\n            }\n        }\n        for1 (w, W) {\n            total[w] = 0;\n        }\n        for1 (h, H) {\n            for1 (w, W) {\n                total[w] += ans[h][w];\n            }\n        }\n        bool ok = true;\n        for1 (w, W) {\n            if (total[w] != B) {\n                ok = false;\n                break;\n            }\n        }\n        if (ok) {\n            for1 (h, H) {\n                for1 (w, W) {\n                    if (ans[h][w] != 0) {\n                        cout << '1';\n                    } else {\n                        cout << '0';\n                    }\n                }\n                cout << '\\n';\n            }\n            return;\n        }\n    }\n    No();\n}\n\nint main()\n{\n    ios::sync_with_stdio(false);\n    cin.tie(0);\n    cout << fixed << setprecision(16);\n    cerr << fixed << setprecision(16);\n    solve();\n}\n", "language": "C++", "metadata": {"date": 1569117709, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02903.html", "problem_id": "p02903", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02903/input.txt", "sample_output_relpath": "derived/input_output/data/p02903/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02903/C++/s313351196.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s313351196", "user_id": "u426683236"}, "prompt_components": {"gold_output": "100\n010\n001\n", "input_to_evaluate": "#define DEBUG 1\n#include <algorithm>\n#include <cmath>\n#include <cstring>\n#include <deque>\n#include <iomanip>\n#include <iostream>\n#include <map>\n#include <queue>\n#include <set>\n#include <string>\n#include <tuple>\n#include <utility>\n#include <vector>\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing ld = long double;\nusing vll = vector<ll>;\nusing vvll = vector<vll>;\nusing pll = pair<ll, ll>;\nusing tll = tuple<ll, ll, ll>;\n#define all(v) (v).begin(), (v).end()\n#define for1(i, n) for (ll i = 0; i < (n); i++)\n#define for2(i, m, n) for (ll i = (m); i < (n); i++)\n#define for3(i, m, n, d) for (ll i = (m); i < (n); i += (d))\n#define rfor2(i, m, n) for (ll i = (m); i > (n); i--)\n#define rfor3(i, m, n, d) for (ll i = (m); i > (n); i += (d))\n#define INF 1111111111111111111LL\n#define MOD 1000000007LL  // 10**9 + 7\n#define print(...) print_1(__VA_ARGS__)\n#define in(...) in_1(__VA_ARGS__)\n#if DEBUG\n#define dump(...) dump_1(#__VA_ARGS__, __VA_ARGS__)\n#else\n#define dump(...)\n#endif\ntemplate <typename Head>\nvoid dump_1(const char* str, Head&& h)\n{\n    cerr << str << \": \" << h << '\\n';\n}\ntemplate <typename Head, typename... Tail>\nvoid dump_1(const char* str, Head&& h, Tail&&... t)\n{\n    while (*str != ',') {\n        cerr << *str++;\n    }\n    cerr << \": \" << h << ' ';\n    dump_1(str + 1, t...);\n}\ntemplate <typename T1, typename T2>\nostream& operator<<(ostream& os, const pair<T1, T2>& v)\n{\n    os << '(' << v.first << \", \" << v.second << ')';\n    return os;\n}\ntemplate <typename T1, typename T2, typename T3>\nostream& operator<<(ostream& os, const tuple<T1, T2, T3>& v)\n{\n    os << '(' << get<0>(v) << \", \" << get<1>(v) << \", \" << get<2>(v) << ')';\n    return os;\n}\ntemplate <typename T>\nostream& operator<<(ostream& os, const vector<T>& v)\n{\n    for (auto it = v.begin(); it != v.end(); it++) {\n        if (it != v.begin()) {\n            os << ' ';\n        }\n        os << *it;\n    }\n    return os;\n}\ntemplate <typename T>\nostream& operator<<(ostream& os, const set<T>& v)\n{\n    for (auto it = v.begin(); it != v.end(); it++) {\n        if (it != v.begin()) {\n            os << ' ';\n        }\n        os << *it;\n    }\n    return os;\n}\ntemplate <typename T>\nostream& operator<<(ostream& os, const multiset<T>& v)\n{\n    for (auto it = v.begin(); it != v.end(); it++) {\n        if (it != v.begin()) {\n            os << ' ';\n        }\n        os << *it;\n    }\n    return os;\n}\ntemplate <typename T1, typename T2>\nostream& operator<<(ostream& os, const map<T1, T2>& v)\n{\n    os << '{';\n    for (auto it = v.begin(); it != v.end(); it++) {\n        if (it != v.begin()) {\n            os << \", \";\n        }\n        os << it->first << ':' << it->second;\n    }\n    os << '}';\n    return os;\n}\nvoid Yes(void) { cout << \"Yes\" << '\\n'; }\nvoid No(void) { cout << \"No\" << '\\n'; }\nvoid YES(void) { cout << \"YES\" << '\\n'; }\nvoid NO(void) { cout << \"NO\" << '\\n'; }\ntemplate <typename T>\nvoid chmax(T& a, const T& b)\n{\n    if (a < b) {\n        a = b;\n    }\n}\ntemplate <typename T>\nvoid chmin(T& a, const T& b)\n{\n    if (a > b) {\n        a = b;\n    }\n}\ntemplate <typename T>\nvoid vin(vector<T>& v, ll len)\n{\n    for1 (i, len) {\n        cin >> v[i];\n    }\n}\ntemplate <typename Head>\nvoid in_1(Head& h)\n{\n    cin >> h;\n}\ntemplate <typename Head, typename... Tail>\nvoid in_1(Head& h, Tail&... t)\n{\n    cin >> h;\n    in_1(t...);\n}\ntemplate <typename Head>\nvoid print_1(Head&& h)\n{\n    cout << h << '\\n';\n}\ntemplate <typename Head, typename... Tail>\nvoid print_1(Head&& h, Tail&&... t)\n{\n    cout << h << ' ';\n    print_1(t...);\n}\n//---------------------------------------------------------\nvoid solve()\n{\n    ll H, W, A, B;\n    in(H, W, A, B);\n    if (A == 0 && B == 0) {\n        for1 (h, H) {\n            for1 (w, W) {\n                cout << \"0\";\n            }\n            cout << \"\\n\";\n        }\n        return;\n    }\n    if (B == 0) {\n        for1 (h, H) {\n            for1 (w, A) {\n                cout << \"1\";\n            }\n            for1 (w, W - A) {\n                cout << \"0\";\n            }\n            cout << \"\\n\";\n        }\n        return;\n    }\n    if (A == 0) {\n        for1 (h, B) {\n            for1 (w, W) {\n                cout << \"1\";\n            }\n            cout << \"\\n\";\n        }\n        for1 (h, H - B) {\n            for1 (w, W) {\n                cout << \"0\";\n            }\n            cout << \"\\n\";\n        }\n        return;\n    }\n    if ((W % A == 0) && (H % B == 0) && (W / A == H / B)) {\n        for1 (h, H) {\n            for1 (w, W) {\n                if (w / A == h / B) {\n                    cout << \"1\";\n                }\n                else {\n                    cout << \"0\";\n                }\n            }\n            cout << \"\\n\";\n        }\n        return;\n    }\n    ll ans[1001][1001];\n    ll total[1001];\n\n    for2 (wd, 1, A + 1) {\n        for1 (h, H) {\n            for1 (w, W) {\n                if ((w + wd * h) % W < A) {\n                    ans[h][w] = 1;\n                }\n                else {\n                    ans[h][w] = 0;\n                }\n            }\n        }\n        for1 (w, W) {\n            total[w] = 0;\n        }\n        for1 (h, H) {\n            for1 (w, W) {\n                total[w] += ans[h][w];\n            }\n        }\n        bool ok = true;\n        for1 (w, W) {\n            if (total[w] != B) {\n                ok = false;\n                break;\n            }\n        }\n        if (ok) {\n            for1 (h, H) {\n                for1 (w, W) {\n                    if (ans[h][w] != 0) {\n                        cout << '1';\n                    } else {\n                        cout << '0';\n                    }\n                }\n                cout << '\\n';\n            }\n            return;\n        }\n    }\n    No();\n}\n\nint main()\n{\n    ios::sync_with_stdio(false);\n    cin.tie(0);\n    cout << fixed << setprecision(16);\n    cerr << fixed << setprecision(16);\n    solve();\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nWe have a square grid with H rows and W columns.\nSnuke wants to write 0 or 1 in each of the squares.\nHere, all of the following conditions have to be satisfied:\n\nFor every row, the smaller of the following is A: the number of 0s contained in the row, and the number of 1s contained in the row. (If these two numbers are equal, “the smaller” should be read as “either”.)\n\nFor every column, the smaller of the following is B: the number of 0s contained in the column, and the number of 1s contained in the column.\n\nDetermine if these conditions can be satisfied by writing 0 or 1 in each of the squares. If the answer is yes, show one way to fill the squares so that the conditions are satisfied.\n\nConstraints\n\n1 \\leq H,W \\leq 1000\n\n0 \\leq A\n\n2 \\times A \\leq W\n\n0 \\leq B\n\n2 \\times B \\leq H\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W A B\n\nOutput\n\nIf the conditions cannot be satisfied by writing 0 or 1 in each of the squares, print -1.\n\nIf the conditions can be satisfied, print one way to fill the squares so that the conditions are satisfied, in the following format:\n\ns_{11}s_{12}\\cdots s_{1W}\ns_{21}s_{22}\\cdots s_{2W}\n\\vdots\ns_{H1}s_{H2}\\cdots s_{HW}\n\nHere s_{ij} is the digit written in the square at the i-th row from the top and the j-th column from the left in the grid.\n\nIf multiple solutions exist, printing any of them will be accepted.\n\nSample Input 1\n\n3 3 1 1\n\nSample Output 1\n\n100\n010\n001\n\nEvery row contains two 0s and one 1, so the first condition is satisfied.\nAlso, every column contains two 0s and one 1, so the second condition is satisfied.\n\nSample Input 2\n\n1 5 2 0\n\nSample Output 2\n\n01010", "sample_input": "3 3 1 1\n"}, "reference_outputs": ["100\n010\n001\n"], "source_document_id": "p02903", "source_text": "Score : 300 points\n\nProblem Statement\n\nWe have a square grid with H rows and W columns.\nSnuke wants to write 0 or 1 in each of the squares.\nHere, all of the following conditions have to be satisfied:\n\nFor every row, the smaller of the following is A: the number of 0s contained in the row, and the number of 1s contained in the row. (If these two numbers are equal, “the smaller” should be read as “either”.)\n\nFor every column, the smaller of the following is B: the number of 0s contained in the column, and the number of 1s contained in the column.\n\nDetermine if these conditions can be satisfied by writing 0 or 1 in each of the squares. If the answer is yes, show one way to fill the squares so that the conditions are satisfied.\n\nConstraints\n\n1 \\leq H,W \\leq 1000\n\n0 \\leq A\n\n2 \\times A \\leq W\n\n0 \\leq B\n\n2 \\times B \\leq H\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W A B\n\nOutput\n\nIf the conditions cannot be satisfied by writing 0 or 1 in each of the squares, print -1.\n\nIf the conditions can be satisfied, print one way to fill the squares so that the conditions are satisfied, in the following format:\n\ns_{11}s_{12}\\cdots s_{1W}\ns_{21}s_{22}\\cdots s_{2W}\n\\vdots\ns_{H1}s_{H2}\\cdots s_{HW}\n\nHere s_{ij} is the digit written in the square at the i-th row from the top and the j-th column from the left in the grid.\n\nIf multiple solutions exist, printing any of them will be accepted.\n\nSample Input 1\n\n3 3 1 1\n\nSample Output 1\n\n100\n010\n001\n\nEvery row contains two 0s and one 1, so the first condition is satisfied.\nAlso, every column contains two 0s and one 1, so the second condition is satisfied.\n\nSample Input 2\n\n1 5 2 0\n\nSample Output 2\n\n01010", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 5856, "cpu_time_ms": 2103, "memory_kb": 8064}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s778889273", "group_id": "codeNet:p02904", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nconst int INF = 1e9;\n\nstruct segtree {\n\t\n\tvector <int> tree;\n\tint size;\n\t\n\tvoid init (int n) {\n\t\tsize = 1;\n\t\twhile (size < n) {\n\t\t\tsize <<= 1;\n\t\t}\n\t\ttree.assign(size<<1, INF);\n\t}\n\t\n\tint son (int v, int num) {\n\t\treturn (v<<1)+(num-1);\n\t}\n\t\n\tvoid set (int v, int lv, int rv, int i, int x) {\n\t\tif (lv == rv) {\n\t\t\ttree[v] = x;\n\t\t\treturn;\n\t\t}\n\t\tint mid = (lv+rv)>>1;\n\t\tif (mid >= i) {\n\t\t\tset (son(v, 1), lv, mid, i, x);\n\t\t} else {\n\t\t\tset (son(v, 2), mid+1, rv, i, x);\n\t\t}\n\t\ttree[v] = min(tree[son(v, 1)], tree[son(v, 2)]);\n\t}\n\t\n\tvoid set (int i, int x) {\n\t\tif (!x) x = INF;\n\t\tset (1, 1, size, i, x);\n\t}\n\t\n\tint inv (int v, int lv, int rv, int l, int r) {\n\t\tif (lv > r || rv < l) {\n\t\t\treturn INF;\n\t\t}\n\t\tif (lv >= l && rv <= r) {\n\t\t\treturn tree[v];\n\t\t}\n\t\tint mid = (lv+rv)>>1;\n\t\tint left = inv(son(v, 1), lv, mid, l, min(r, mid));\n\t\tint right = inv(son(v, 2), mid+1, rv, max(mid+1, l), r);\n\t\treturn min(right, left);\n\t}\n\t\n\tint inv (int l, int r) {\n\t\treturn inv (1, 1, size, l, r);\n\t}\n\t\n};\n\nint main()\n{\n\tios_base::sync_with_stdio(0);\n\tcin.tie(0); cout.tie(0);\n\tint n, k, ans = 0;\n\tsegtree t;\n\tcin >> n >> k;\n\tt.init(n);\n\tvector <int> a(n+1);\n\tfor (int i=1; i<=n; i++) {\n\t\tcin >> a[i];\n\t\ta[i] ++;\n\t}\n\tint tec = 1;\n\tfor (int i=2; i<=n; i++) {\n\t\tif (a[i] > a[i-1]) {\n\t\t\ttec ++;\n\t\t} else {\n\t\t\tif (tec >= k) break;\n\t\t\ttec = 1;\n\t\t}\n\t}\n\tif (tec >= k) {\n\t\tans ++;\n\t}\n\ttec = 0; // will use for the leftmost inversion with current element\n\tset <pair <int, int>> s;\n\tfor (int i=1; i<=n; i++) {\n\t\tif (i > k) {\n\t\t\tt.set(a[i-k], INF);\n\t\t}\n\t\tbool check = 0;\n\t\ttec = t.inv(a[i], n);\n\t\tif (tec < INF) {\n\t\t\ts.insert({tec, i});\n\t\t\tcheck = 1;\n\t\t}\n\t\twhile (!s.empty()) {\n\t\t\tpair <int, int> m = *s.begin();\n\t\t\tif (m.first <= i-k) {\n\t\t\t\ts.erase(m);\n\t\t\t\tcheck = 1;\n\t\t\t} else break;\n\t\t}\n\t\tif (check && i >= k) {\n\t\t\tans ++;\n\t\t}\n\t\tt.set(a[i], i);\n\t}\n\tcout << ans;\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1588987933, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02904.html", "problem_id": "p02904", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02904/input.txt", "sample_output_relpath": "derived/input_output/data/p02904/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02904/C++/s778889273.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s778889273", "user_id": "u627941097"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing ll = long long;\nconst int INF = 1e9;\n\nstruct segtree {\n\t\n\tvector <int> tree;\n\tint size;\n\t\n\tvoid init (int n) {\n\t\tsize = 1;\n\t\twhile (size < n) {\n\t\t\tsize <<= 1;\n\t\t}\n\t\ttree.assign(size<<1, INF);\n\t}\n\t\n\tint son (int v, int num) {\n\t\treturn (v<<1)+(num-1);\n\t}\n\t\n\tvoid set (int v, int lv, int rv, int i, int x) {\n\t\tif (lv == rv) {\n\t\t\ttree[v] = x;\n\t\t\treturn;\n\t\t}\n\t\tint mid = (lv+rv)>>1;\n\t\tif (mid >= i) {\n\t\t\tset (son(v, 1), lv, mid, i, x);\n\t\t} else {\n\t\t\tset (son(v, 2), mid+1, rv, i, x);\n\t\t}\n\t\ttree[v] = min(tree[son(v, 1)], tree[son(v, 2)]);\n\t}\n\t\n\tvoid set (int i, int x) {\n\t\tif (!x) x = INF;\n\t\tset (1, 1, size, i, x);\n\t}\n\t\n\tint inv (int v, int lv, int rv, int l, int r) {\n\t\tif (lv > r || rv < l) {\n\t\t\treturn INF;\n\t\t}\n\t\tif (lv >= l && rv <= r) {\n\t\t\treturn tree[v];\n\t\t}\n\t\tint mid = (lv+rv)>>1;\n\t\tint left = inv(son(v, 1), lv, mid, l, min(r, mid));\n\t\tint right = inv(son(v, 2), mid+1, rv, max(mid+1, l), r);\n\t\treturn min(right, left);\n\t}\n\t\n\tint inv (int l, int r) {\n\t\treturn inv (1, 1, size, l, r);\n\t}\n\t\n};\n\nint main()\n{\n\tios_base::sync_with_stdio(0);\n\tcin.tie(0); cout.tie(0);\n\tint n, k, ans = 0;\n\tsegtree t;\n\tcin >> n >> k;\n\tt.init(n);\n\tvector <int> a(n+1);\n\tfor (int i=1; i<=n; i++) {\n\t\tcin >> a[i];\n\t\ta[i] ++;\n\t}\n\tint tec = 1;\n\tfor (int i=2; i<=n; i++) {\n\t\tif (a[i] > a[i-1]) {\n\t\t\ttec ++;\n\t\t} else {\n\t\t\tif (tec >= k) break;\n\t\t\ttec = 1;\n\t\t}\n\t}\n\tif (tec >= k) {\n\t\tans ++;\n\t}\n\ttec = 0; // will use for the leftmost inversion with current element\n\tset <pair <int, int>> s;\n\tfor (int i=1; i<=n; i++) {\n\t\tif (i > k) {\n\t\t\tt.set(a[i-k], INF);\n\t\t}\n\t\tbool check = 0;\n\t\ttec = t.inv(a[i], n);\n\t\tif (tec < INF) {\n\t\t\ts.insert({tec, i});\n\t\t\tcheck = 1;\n\t\t}\n\t\twhile (!s.empty()) {\n\t\t\tpair <int, int> m = *s.begin();\n\t\t\tif (m.first <= i-k) {\n\t\t\t\ts.erase(m);\n\t\t\t\tcheck = 1;\n\t\t\t} else break;\n\t\t}\n\t\tif (check && i >= k) {\n\t\t\tans ++;\n\t\t}\n\t\tt.set(a[i], i);\n\t}\n\tcout << ans;\n\treturn 0;\n}\n", "problem_context": "Score : 700 points\n\nProblem Statement\n\nSnuke has a permutation (P_0,P_1,\\cdots,P_{N-1}) of (0,1,\\cdots,N-1).\n\nNow, he will perform the following operation exactly once:\n\nChoose K consecutive elements in P and sort them in ascending order.\n\nFind the number of permutations that can be produced as P after the operation.\n\nConstraints\n\n2 \\leq N \\leq 200000\n\n2 \\leq K \\leq N\n\n0 \\leq P_i \\leq N-1\n\nP_0,P_1,\\cdots,P_{N-1} are all different.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nP_0 P_1 \\cdots P_{N-1}\n\nOutput\n\nPrint the number of permutations that can be produced as P after the operation.\n\nSample Input 1\n\n5 3\n0 2 1 4 3\n\nSample Output 1\n\n2\n\nTwo permutations can be produced as P after the operation: (0,1,2,4,3) and (0,2,1,3,4).\n\nSample Input 2\n\n4 4\n0 1 2 3\n\nSample Output 2\n\n1\n\nSample Input 3\n\n10 4\n2 0 1 3 7 5 4 6 8 9\n\nSample Output 3\n\n6", "sample_input": "5 3\n0 2 1 4 3\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02904", "source_text": "Score : 700 points\n\nProblem Statement\n\nSnuke has a permutation (P_0,P_1,\\cdots,P_{N-1}) of (0,1,\\cdots,N-1).\n\nNow, he will perform the following operation exactly once:\n\nChoose K consecutive elements in P and sort them in ascending order.\n\nFind the number of permutations that can be produced as P after the operation.\n\nConstraints\n\n2 \\leq N \\leq 200000\n\n2 \\leq K \\leq N\n\n0 \\leq P_i \\leq N-1\n\nP_0,P_1,\\cdots,P_{N-1} are all different.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nP_0 P_1 \\cdots P_{N-1}\n\nOutput\n\nPrint the number of permutations that can be produced as P after the operation.\n\nSample Input 1\n\n5 3\n0 2 1 4 3\n\nSample Output 1\n\n2\n\nTwo permutations can be produced as P after the operation: (0,1,2,4,3) and (0,2,1,3,4).\n\nSample Input 2\n\n4 4\n0 1 2 3\n\nSample Output 2\n\n1\n\nSample Input 3\n\n10 4\n2 0 1 3 7 5 4 6 8 9\n\nSample Output 3\n\n6", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1911, "cpu_time_ms": 138, "memory_kb": 12416}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s571823302", "group_id": "codeNet:p02910", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nint main()\n{\n\n\nstring s;\ncin>>s;\nif(s[0] || s[2]||s[4] == 'R'||'U' ||'D')\n{\n    cout<<\"YES\"<<endl;\n}\nelse if (s[1]||s[3]||s[5]== 'L'||'U'||'D')\n{\n    cout<<\"YES\"<<endl;\n}\nelse\n    cout<<\"NO\"<<endl;\n}\n\n", "language": "C++", "metadata": {"date": 1568596397, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02910.html", "problem_id": "p02910", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02910/input.txt", "sample_output_relpath": "derived/input_output/data/p02910/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02910/C++/s571823302.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s571823302", "user_id": "u222613738"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nint main()\n{\n\n\nstring s;\ncin>>s;\nif(s[0] || s[2]||s[4] == 'R'||'U' ||'D')\n{\n    cout<<\"YES\"<<endl;\n}\nelse if (s[1]||s[3]||s[5]== 'L'||'U'||'D')\n{\n    cout<<\"YES\"<<endl;\n}\nelse\n    cout<<\"NO\"<<endl;\n}\n\n", "problem_context": "Score: 200 points\n\nProblem Statement\n\nTakahashi will do a tap dance. The dance is described by a string S where each character is L, R, U, or D. These characters indicate the positions on which Takahashi should step. He will follow these instructions one by one in order, starting with the first character.\n\nS is said to be easily playable if and only if it satisfies both of the following conditions:\n\nEvery character in an odd position (1-st, 3-rd, 5-th, \\ldots) is R, U, or D.\n\nEvery character in an even position (2-nd, 4-th, 6-th, \\ldots) is L, U, or D.\n\nYour task is to print Yes if S is easily playable, and No otherwise.\n\nConstraints\n\nS is a string of length between 1 and 100 (inclusive).\n\nEach character of S is L, R, U, or D.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint Yes if S is easily playable, and No otherwise.\n\nSample Input 1\n\nRUDLUDR\n\nSample Output 1\n\nYes\n\nEvery character in an odd position (1-st, 3-rd, 5-th, 7-th) is R, U, or D.\n\nEvery character in an even position (2-nd, 4-th, 6-th) is L, U, or D.\n\nThus, S is easily playable.\n\nSample Input 2\n\nDULL\n\nSample Output 2\n\nNo\n\nThe 3-rd character is not R, U, nor D, so S is not easily playable.\n\nSample Input 3\n\nUUUUUUUUUUUUUUU\n\nSample Output 3\n\nYes\n\nSample Input 4\n\nULURU\n\nSample Output 4\n\nNo\n\nSample Input 5\n\nRDULULDURURLRDULRLR\n\nSample Output 5\n\nYes", "sample_input": "RUDLUDR\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p02910", "source_text": "Score: 200 points\n\nProblem Statement\n\nTakahashi will do a tap dance. The dance is described by a string S where each character is L, R, U, or D. These characters indicate the positions on which Takahashi should step. He will follow these instructions one by one in order, starting with the first character.\n\nS is said to be easily playable if and only if it satisfies both of the following conditions:\n\nEvery character in an odd position (1-st, 3-rd, 5-th, \\ldots) is R, U, or D.\n\nEvery character in an even position (2-nd, 4-th, 6-th, \\ldots) is L, U, or D.\n\nYour task is to print Yes if S is easily playable, and No otherwise.\n\nConstraints\n\nS is a string of length between 1 and 100 (inclusive).\n\nEach character of S is L, R, U, or D.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint Yes if S is easily playable, and No otherwise.\n\nSample Input 1\n\nRUDLUDR\n\nSample Output 1\n\nYes\n\nEvery character in an odd position (1-st, 3-rd, 5-th, 7-th) is R, U, or D.\n\nEvery character in an even position (2-nd, 4-th, 6-th) is L, U, or D.\n\nThus, S is easily playable.\n\nSample Input 2\n\nDULL\n\nSample Output 2\n\nNo\n\nThe 3-rd character is not R, U, nor D, so S is not easily playable.\n\nSample Input 3\n\nUUUUUUUUUUUUUUU\n\nSample Output 3\n\nYes\n\nSample Input 4\n\nULURU\n\nSample Output 4\n\nNo\n\nSample Input 5\n\nRDULULDURURLRDULRLR\n\nSample Output 5\n\nYes", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 247, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s620173940", "group_id": "codeNet:p02911", "input_text": "#include<iostream>\n#include<algorithm>\n#include<numeric>\n#include<vector>\n#include<math.h>\n#include<set>\n#include<iomanip>\n#include<stdio.h>\n#include<deque>\n#include<stack>\n#include<map>\n#include<queue>\n#include<cstring>\n#define M 1000000007\n#define pb push_back\n#define mp make_pair\n#define int long long\nusing namespace std;\nint32_t main()\n{\n\tios_base::sync_with_stdio(false);\n\tcin.tie(NULL);\n\tint n,k,q;\n\tcin>>n>>k>>q;\n\tint a[n]={0},i;\n\tfor(i=0;i<q;i++)\n\t{\n\t\tint x;\n\t\tcin>>x;\n\t\tx--;\n\t\ta[x]++;\n\t}\n\tfor(i=0;i<n;i++)\n\t{\n\t\tif(q-a[i]>=k)\n\t\t\tcout<<\"No\\n\";\n\t\telse\n\t\t\tcout<<\"Yes\\n\";\n\t}\n}", "language": "C++", "metadata": {"date": 1568597217, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02911.html", "problem_id": "p02911", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02911/input.txt", "sample_output_relpath": "derived/input_output/data/p02911/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02911/C++/s620173940.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s620173940", "user_id": "u131230001"}, "prompt_components": {"gold_output": "No\nNo\nYes\nNo\nNo\nNo\n", "input_to_evaluate": "#include<iostream>\n#include<algorithm>\n#include<numeric>\n#include<vector>\n#include<math.h>\n#include<set>\n#include<iomanip>\n#include<stdio.h>\n#include<deque>\n#include<stack>\n#include<map>\n#include<queue>\n#include<cstring>\n#define M 1000000007\n#define pb push_back\n#define mp make_pair\n#define int long long\nusing namespace std;\nint32_t main()\n{\n\tios_base::sync_with_stdio(false);\n\tcin.tie(NULL);\n\tint n,k,q;\n\tcin>>n>>k>>q;\n\tint a[n]={0},i;\n\tfor(i=0;i<q;i++)\n\t{\n\t\tint x;\n\t\tcin>>x;\n\t\tx--;\n\t\ta[x]++;\n\t}\n\tfor(i=0;i<n;i++)\n\t{\n\t\tif(q-a[i]>=k)\n\t\t\tcout<<\"No\\n\";\n\t\telse\n\t\t\tcout<<\"Yes\\n\";\n\t}\n}", "problem_context": "Score: 300 points\n\nProblem Statement\n\nTakahashi has decided to hold fastest-finger-fast quiz games. Kizahashi, who is in charge of making the scoreboard, is struggling to write the program that manages the players' scores in a game, which proceeds as follows.\n\nA game is played by N players, numbered 1 to N. At the beginning of a game, each player has K points.\n\nWhen a player correctly answers a question, each of the other N-1 players receives minus one (-1) point. There is no other factor that affects the players' scores.\n\nAt the end of a game, the players with 0 points or lower are eliminated, and the remaining players survive.\n\nIn the last game, the players gave a total of Q correct answers, the i-th of which was given by Player A_i.\nFor Kizahashi, write a program that determines whether each of the N players survived this game.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 10^5\n\n1 \\leq K \\leq 10^9\n\n1 \\leq Q \\leq 10^5\n\n1 \\leq A_i \\leq N\\ (1 \\leq i \\leq Q)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K Q\nA_1\nA_2\n.\n.\n.\nA_Q\n\nOutput\n\nPrint N lines. The i-th line should contain Yes if Player i survived the game, and No otherwise.\n\nSample Input 1\n\n6 3 4\n3\n1\n3\n2\n\nSample Output 1\n\nNo\nNo\nYes\nNo\nNo\nNo\n\nIn the beginning, the players' scores are (3, 3, 3, 3, 3, 3).\n\nPlayer 3 correctly answers a question. The players' scores are now (2, 2, 3, 2, 2, 2).\n\nPlayer 1 correctly answers a question. The players' scores are now (2, 1, 2, 1, 1, 1).\n\nPlayer 3 correctly answers a question. The players' scores are now (1, 0, 2, 0, 0, 0).\n\nPlayer 2 correctly answers a question. The players' scores are now (0, 0, 1, -1, -1, -1).\n\nPlayers 1, 2, 4, 5 and 6, who have 0 points or lower, are eliminated, and Player 3 survives this game.\n\nSample Input 2\n\n6 5 4\n3\n1\n3\n2\n\nSample Output 2\n\nYes\nYes\nYes\nYes\nYes\nYes\n\nSample Input 3\n\n10 13 15\n3\n1\n4\n1\n5\n9\n2\n6\n5\n3\n5\n8\n9\n7\n9\n\nSample Output 3\n\nNo\nNo\nNo\nNo\nYes\nNo\nNo\nNo\nYes\nNo", "sample_input": "6 3 4\n3\n1\n3\n2\n"}, "reference_outputs": ["No\nNo\nYes\nNo\nNo\nNo\n"], "source_document_id": "p02911", "source_text": "Score: 300 points\n\nProblem Statement\n\nTakahashi has decided to hold fastest-finger-fast quiz games. Kizahashi, who is in charge of making the scoreboard, is struggling to write the program that manages the players' scores in a game, which proceeds as follows.\n\nA game is played by N players, numbered 1 to N. At the beginning of a game, each player has K points.\n\nWhen a player correctly answers a question, each of the other N-1 players receives minus one (-1) point. There is no other factor that affects the players' scores.\n\nAt the end of a game, the players with 0 points or lower are eliminated, and the remaining players survive.\n\nIn the last game, the players gave a total of Q correct answers, the i-th of which was given by Player A_i.\nFor Kizahashi, write a program that determines whether each of the N players survived this game.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 10^5\n\n1 \\leq K \\leq 10^9\n\n1 \\leq Q \\leq 10^5\n\n1 \\leq A_i \\leq N\\ (1 \\leq i \\leq Q)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K Q\nA_1\nA_2\n.\n.\n.\nA_Q\n\nOutput\n\nPrint N lines. The i-th line should contain Yes if Player i survived the game, and No otherwise.\n\nSample Input 1\n\n6 3 4\n3\n1\n3\n2\n\nSample Output 1\n\nNo\nNo\nYes\nNo\nNo\nNo\n\nIn the beginning, the players' scores are (3, 3, 3, 3, 3, 3).\n\nPlayer 3 correctly answers a question. The players' scores are now (2, 2, 3, 2, 2, 2).\n\nPlayer 1 correctly answers a question. The players' scores are now (2, 1, 2, 1, 1, 1).\n\nPlayer 3 correctly answers a question. The players' scores are now (1, 0, 2, 0, 0, 0).\n\nPlayer 2 correctly answers a question. The players' scores are now (0, 0, 1, -1, -1, -1).\n\nPlayers 1, 2, 4, 5 and 6, who have 0 points or lower, are eliminated, and Player 3 survives this game.\n\nSample Input 2\n\n6 5 4\n3\n1\n3\n2\n\nSample Output 2\n\nYes\nYes\nYes\nYes\nYes\nYes\n\nSample Input 3\n\n10 13 15\n3\n1\n4\n1\n5\n9\n2\n6\n5\n3\n5\n8\n9\n7\n9\n\nSample Output 3\n\nNo\nNo\nNo\nNo\nYes\nNo\nNo\nNo\nYes\nNo", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 582, "cpu_time_ms": 12, "memory_kb": 1408}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s041729549", "group_id": "codeNet:p02915", "input_text": "#include<bits/stdc++.h>\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\nusing namespace std;\n\nint main(){\n    int n;\n    cin >> n;\n    cout << n*n*n << \"\\n\";\n}", "language": "C++", "metadata": {"date": 1568749839, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02915.html", "problem_id": "p02915", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02915/input.txt", "sample_output_relpath": "derived/input_output/data/p02915/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02915/C++/s041729549.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s041729549", "user_id": "u106635407"}, "prompt_components": {"gold_output": "8\n", "input_to_evaluate": "#include<bits/stdc++.h>\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\nusing namespace std;\n\nint main(){\n    int n;\n    cin >> n;\n    cout << n*n*n << \"\\n\";\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nTakahashi is going to set a 3-character password.\n\nHow many possible passwords are there if each of its characters must be a digit between 1 and N (inclusive)?\n\nConstraints\n\n1 \\leq N \\leq 9\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the number of possible passwords.\n\nSample Input 1\n\n2\n\nSample Output 1\n\n8\n\nThere are eight possible passwords: 111, 112, 121, 122, 211, 212, 221, and 222.\n\nSample Input 2\n\n1\n\nSample Output 2\n\n1\n\nThere is only one possible password if you can only use one kind of character.", "sample_input": "2\n"}, "reference_outputs": ["8\n"], "source_document_id": "p02915", "source_text": "Score : 100 points\n\nProblem Statement\n\nTakahashi is going to set a 3-character password.\n\nHow many possible passwords are there if each of its characters must be a digit between 1 and N (inclusive)?\n\nConstraints\n\n1 \\leq N \\leq 9\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the number of possible passwords.\n\nSample Input 1\n\n2\n\nSample Output 1\n\n8\n\nThere are eight possible passwords: 111, 112, 121, 122, 211, 212, 221, and 222.\n\nSample Input 2\n\n1\n\nSample Output 2\n\n1\n\nThere is only one possible password if you can only use one kind of character.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 156, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s079328471", "group_id": "codeNet:p02915", "input_text": "#include<cstdio>\nusing namespace std;\nint main() {\n\tint n, ans = 0;\n\tscanf(\"%d\", &n);\n\tif (n > 9)n = 9;\n\tans += n;\n\tint k = n * (n - 1);\n\tif(k)ans += (k << 1) + k;\n\tk = 0;\n\tfor (int i = 1; i < n-1; ++i) {\n\t\tfor (int j = i + 1; j < n; ++j) \n\t\t\tk += n - j;\n\t}\n\tif (k)ans += (k << 2) + (k<<1);\n\tprintf(\"%d\", ans);\n}", "language": "C++", "metadata": {"date": 1567906258, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02915.html", "problem_id": "p02915", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02915/input.txt", "sample_output_relpath": "derived/input_output/data/p02915/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02915/C++/s079328471.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s079328471", "user_id": "u538014595"}, "prompt_components": {"gold_output": "8\n", "input_to_evaluate": "#include<cstdio>\nusing namespace std;\nint main() {\n\tint n, ans = 0;\n\tscanf(\"%d\", &n);\n\tif (n > 9)n = 9;\n\tans += n;\n\tint k = n * (n - 1);\n\tif(k)ans += (k << 1) + k;\n\tk = 0;\n\tfor (int i = 1; i < n-1; ++i) {\n\t\tfor (int j = i + 1; j < n; ++j) \n\t\t\tk += n - j;\n\t}\n\tif (k)ans += (k << 2) + (k<<1);\n\tprintf(\"%d\", ans);\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nTakahashi is going to set a 3-character password.\n\nHow many possible passwords are there if each of its characters must be a digit between 1 and N (inclusive)?\n\nConstraints\n\n1 \\leq N \\leq 9\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the number of possible passwords.\n\nSample Input 1\n\n2\n\nSample Output 1\n\n8\n\nThere are eight possible passwords: 111, 112, 121, 122, 211, 212, 221, and 222.\n\nSample Input 2\n\n1\n\nSample Output 2\n\n1\n\nThere is only one possible password if you can only use one kind of character.", "sample_input": "2\n"}, "reference_outputs": ["8\n"], "source_document_id": "p02915", "source_text": "Score : 100 points\n\nProblem Statement\n\nTakahashi is going to set a 3-character password.\n\nHow many possible passwords are there if each of its characters must be a digit between 1 and N (inclusive)?\n\nConstraints\n\n1 \\leq N \\leq 9\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the number of possible passwords.\n\nSample Input 1\n\n2\n\nSample Output 1\n\n8\n\nThere are eight possible passwords: 111, 112, 121, 122, 211, 212, 221, and 222.\n\nSample Input 2\n\n1\n\nSample Output 2\n\n1\n\nThere is only one possible password if you can only use one kind of character.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 312, "cpu_time_ms": 1, "memory_kb": 128}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s790606873", "group_id": "codeNet:p02915", "input_text": "// Contest.cpp : アプリケー��ョンのエントリ ポイントを定義します。\n//\n\n#include\"iostream\"\n#include\"string\"\n#include\"vector\"\n#include\"algorithm\"\n\nusing namespace std;\n\nint main()\n{\n\t/*int n,k;\n\tcin >> n;\n\tvector<char>s(n);\n\tfor (int j = 0; j < n; j++)  cin >> s[j];\n\tcin >> k;\n\tfor (int i = 0; i < n; i++)\n\t{\n\t\tif (s[i] != s[k-1]) {\n\t\t\ts[i] = '*';\n\t\t}\n\t}\n\n\tfor (int l = 0; l < n; l++)\n\t{\n\t\tcout << s[l] ;\n\t}*/\n\t\n\tint n;\n\tcin >> n;\n\tint sum = 1;\n\tfor (int i = 0; i < n; i++) {\n\t\tsum = sum * n;\n\t}\n\t\n\tcout << sum;\n\t\n}\n\n\n\n", "language": "C++", "metadata": {"date": 1567904788, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02915.html", "problem_id": "p02915", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02915/input.txt", "sample_output_relpath": "derived/input_output/data/p02915/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02915/C++/s790606873.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s790606873", "user_id": "u157146122"}, "prompt_components": {"gold_output": "8\n", "input_to_evaluate": "// Contest.cpp : アプリケーションのエントリ ポイントを定義します。\n//\n\n#include\"iostream\"\n#include\"string\"\n#include\"vector\"\n#include\"algorithm\"\n\nusing namespace std;\n\nint main()\n{\n\t/*int n,k;\n\tcin >> n;\n\tvector<char>s(n);\n\tfor (int j = 0; j < n; j++)  cin >> s[j];\n\tcin >> k;\n\tfor (int i = 0; i < n; i++)\n\t{\n\t\tif (s[i] != s[k-1]) {\n\t\t\ts[i] = '*';\n\t\t}\n\t}\n\n\tfor (int l = 0; l < n; l++)\n\t{\n\t\tcout << s[l] ;\n\t}*/\n\t\n\tint n;\n\tcin >> n;\n\tint sum = 1;\n\tfor (int i = 0; i < n; i++) {\n\t\tsum = sum * n;\n\t}\n\t\n\tcout << sum;\n\t\n}\n\n\n\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nTakahashi is going to set a 3-character password.\n\nHow many possible passwords are there if each of its characters must be a digit between 1 and N (inclusive)?\n\nConstraints\n\n1 \\leq N \\leq 9\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the number of possible passwords.\n\nSample Input 1\n\n2\n\nSample Output 1\n\n8\n\nThere are eight possible passwords: 111, 112, 121, 122, 211, 212, 221, and 222.\n\nSample Input 2\n\n1\n\nSample Output 2\n\n1\n\nThere is only one possible password if you can only use one kind of character.", "sample_input": "2\n"}, "reference_outputs": ["8\n"], "source_document_id": "p02915", "source_text": "Score : 100 points\n\nProblem Statement\n\nTakahashi is going to set a 3-character password.\n\nHow many possible passwords are there if each of its characters must be a digit between 1 and N (inclusive)?\n\nConstraints\n\n1 \\leq N \\leq 9\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the number of possible passwords.\n\nSample Input 1\n\n2\n\nSample Output 1\n\n8\n\nThere are eight possible passwords: 111, 112, 121, 122, 211, 212, 221, and 222.\n\nSample Input 2\n\n1\n\nSample Output 2\n\n1\n\nThere is only one possible password if you can only use one kind of character.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 542, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s413074903", "group_id": "codeNet:p02916", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n    int n;\n    cin >> n;\n\n    vector<int> a(n);\n    vector<int> b(n);\n    vector<int> c(n);\n    for (int i = 0; i < n; i++){\n        cin >> a.at(i);\n    }\n    for (int i = 0; i < n; i++){\n        cin >> b.at(i);\n    }\n    for (int i = 0; i < n; i++){\n        cin >> c.at(i);\n    }\n\n    int ans = 0;\n    for (int i = 0; i < n; i++){\n        ans += b.at(a.at(i));\n        if (i != n-1){\n            if (a.at(i + 1) - a.at(i) == 1){\n                ans += c.at(a.at(i));\n            }\n        }\n    }\n    cout << ans << endl;\n}\n", "language": "C++", "metadata": {"date": 1587326149, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02916.html", "problem_id": "p02916", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02916/input.txt", "sample_output_relpath": "derived/input_output/data/p02916/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02916/C++/s413074903.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s413074903", "user_id": "u164352406"}, "prompt_components": {"gold_output": "14\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n    int n;\n    cin >> n;\n\n    vector<int> a(n);\n    vector<int> b(n);\n    vector<int> c(n);\n    for (int i = 0; i < n; i++){\n        cin >> a.at(i);\n    }\n    for (int i = 0; i < n; i++){\n        cin >> b.at(i);\n    }\n    for (int i = 0; i < n; i++){\n        cin >> c.at(i);\n    }\n\n    int ans = 0;\n    for (int i = 0; i < n; i++){\n        ans += b.at(a.at(i));\n        if (i != n-1){\n            if (a.at(i + 1) - a.at(i) == 1){\n                ans += c.at(a.at(i));\n            }\n        }\n    }\n    cout << ans << endl;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nTakahashi went to an all-you-can-eat buffet with N kinds of dishes and ate all of them (Dish 1, Dish 2, \\ldots, Dish N) once.\n\nThe i-th dish (1 \\leq i \\leq N) he ate was Dish A_i.\n\nWhen he eats Dish i (1 \\leq i \\leq N), he gains B_i satisfaction points.\n\nAdditionally, when he eats Dish i+1 just after eating Dish i (1 \\leq i \\leq N - 1), he gains C_i more satisfaction points.\n\nFind the sum of the satisfaction points he gained.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 20\n\n1 \\leq A_i \\leq N\n\nA_1, A_2, ..., A_N are all different.\n\n1 \\leq B_i \\leq 50\n\n1 \\leq C_i \\leq 50\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\nB_1 B_2 ... B_N\nC_1 C_2 ... C_{N-1}\n\nOutput\n\nPrint the sum of the satisfaction points Takahashi gained, as an integer.\n\nSample Input 1\n\n3\n3 1 2\n2 5 4\n3 6\n\nSample Output 1\n\n14\n\nTakahashi gained 14 satisfaction points in total, as follows:\n\nFirst, he ate Dish 3 and gained 4 satisfaction points.\n\nNext, he ate Dish 1 and gained 2 satisfaction points.\n\nLastly, he ate Dish 2 and gained 5 + 3 = 8 satisfaction points.\n\nSample Input 2\n\n4\n2 3 4 1\n13 5 8 24\n45 9 15\n\nSample Output 2\n\n74\n\nSample Input 3\n\n2\n1 2\n50 50\n50\n\nSample Output 3\n\n150", "sample_input": "3\n3 1 2\n2 5 4\n3 6\n"}, "reference_outputs": ["14\n"], "source_document_id": "p02916", "source_text": "Score : 200 points\n\nProblem Statement\n\nTakahashi went to an all-you-can-eat buffet with N kinds of dishes and ate all of them (Dish 1, Dish 2, \\ldots, Dish N) once.\n\nThe i-th dish (1 \\leq i \\leq N) he ate was Dish A_i.\n\nWhen he eats Dish i (1 \\leq i \\leq N), he gains B_i satisfaction points.\n\nAdditionally, when he eats Dish i+1 just after eating Dish i (1 \\leq i \\leq N - 1), he gains C_i more satisfaction points.\n\nFind the sum of the satisfaction points he gained.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 20\n\n1 \\leq A_i \\leq N\n\nA_1, A_2, ..., A_N are all different.\n\n1 \\leq B_i \\leq 50\n\n1 \\leq C_i \\leq 50\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\nB_1 B_2 ... B_N\nC_1 C_2 ... C_{N-1}\n\nOutput\n\nPrint the sum of the satisfaction points Takahashi gained, as an integer.\n\nSample Input 1\n\n3\n3 1 2\n2 5 4\n3 6\n\nSample Output 1\n\n14\n\nTakahashi gained 14 satisfaction points in total, as follows:\n\nFirst, he ate Dish 3 and gained 4 satisfaction points.\n\nNext, he ate Dish 1 and gained 2 satisfaction points.\n\nLastly, he ate Dish 2 and gained 5 + 3 = 8 satisfaction points.\n\nSample Input 2\n\n4\n2 3 4 1\n13 5 8 24\n45 9 15\n\nSample Output 2\n\n74\n\nSample Input 3\n\n2\n1 2\n50 50\n50\n\nSample Output 3\n\n150", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 585, "cpu_time_ms": 104, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s910760562", "group_id": "codeNet:p02916", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nstruct edge {\n    int to;     // 辺の行き先\n    int weight; // 辺の重み\n    edge(int t, int w) : to(t), weight(w) { }\n};\nusing Graph = vector<vector<int>>;\nusing dou =long double;\nstring Yes=\"Yes\";\nstring YES=\"YES\";\nstring NO=\"NO\";\nstring No=\"No\";\n#define rep(i, n)         for(int i = 0; i < (int)(n); i++)\n#define brep(n)           for(int bit=0;bit<(1<<n);bit++)\n#define erep(i,container) for (auto i : container)\n#define irep(i, n)        for(int i = n-1; i >= (int)0; i--)\n#define rrep(i,m,n) for(int i = m; i < (int)(n); i++)\n#define reprep(i,j,h,w) rep(i,h)rep(j,w)\n#define all(x) (x).begin(),(x).end()\n#define aall(x,n) (x).begin(),(x).begin()+(n)\n#define VEC(type,name,n) std::vector<type> name(n);rep(i,n)std::cin >> name[i];\n#define pb push_back\n#define pf push_front\n#define lb lower_bound\n#define ub upper_bound\n#define res resize\n#define as assign\n#define fi first\n#define se second\n#define itn int\n#define mp make_pair\n#define sum(a) accumulate(all(a),0)\n#define keta fixed<<setprecision\n#define vvector(name,typ,m,n,a)vector<vector<typ> > name(m,vector<typ> (n,a))\n#define vvvector(name,t,l,m,n,a) vector<vector<vector<t> > > name(l, vector<vector<t> >(m, vector<t>(n,a)));\n#define vvvvector(name,t,k,l,m,n,a) vector<vector<vector<vector<t> > > > name(k,vector<vector<vector<t> > >(l, vector<vector<t> >(m, vector<t>(n,a)) ));\n \ntypedef long long ll;\nconst int INF = 2000000000;\nconst ll INF64 = 9223372036854775806ll;\nconst int mod = 1000000007ll;\nconst ll  MOD = 1000000007LL;\nconst double pi=3.1415926535897932384626;\nint main(){\n    int n;\n    std::cin >> n;\n    VEC(int,a,n);\n    rep(i,n)a[i]--;\n    VEC(int,b,n);\n    VEC(int,c,n-1);\n    int ans=0;\n    ans+=b[a[0]];\n    rrep(i,1,n){\n        ans+=b[a[i]];\n        if(a[i]-a[i-1]==1)ans+=c[a[i-1]];\n    }\n    std::cout << ans << std::endl;\n}\n", "language": "C++", "metadata": {"date": 1584224351, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02916.html", "problem_id": "p02916", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02916/input.txt", "sample_output_relpath": "derived/input_output/data/p02916/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02916/C++/s910760562.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s910760562", "user_id": "u539011156"}, "prompt_components": {"gold_output": "14\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nstruct edge {\n    int to;     // 辺の行き先\n    int weight; // 辺の重み\n    edge(int t, int w) : to(t), weight(w) { }\n};\nusing Graph = vector<vector<int>>;\nusing dou =long double;\nstring Yes=\"Yes\";\nstring YES=\"YES\";\nstring NO=\"NO\";\nstring No=\"No\";\n#define rep(i, n)         for(int i = 0; i < (int)(n); i++)\n#define brep(n)           for(int bit=0;bit<(1<<n);bit++)\n#define erep(i,container) for (auto i : container)\n#define irep(i, n)        for(int i = n-1; i >= (int)0; i--)\n#define rrep(i,m,n) for(int i = m; i < (int)(n); i++)\n#define reprep(i,j,h,w) rep(i,h)rep(j,w)\n#define all(x) (x).begin(),(x).end()\n#define aall(x,n) (x).begin(),(x).begin()+(n)\n#define VEC(type,name,n) std::vector<type> name(n);rep(i,n)std::cin >> name[i];\n#define pb push_back\n#define pf push_front\n#define lb lower_bound\n#define ub upper_bound\n#define res resize\n#define as assign\n#define fi first\n#define se second\n#define itn int\n#define mp make_pair\n#define sum(a) accumulate(all(a),0)\n#define keta fixed<<setprecision\n#define vvector(name,typ,m,n,a)vector<vector<typ> > name(m,vector<typ> (n,a))\n#define vvvector(name,t,l,m,n,a) vector<vector<vector<t> > > name(l, vector<vector<t> >(m, vector<t>(n,a)));\n#define vvvvector(name,t,k,l,m,n,a) vector<vector<vector<vector<t> > > > name(k,vector<vector<vector<t> > >(l, vector<vector<t> >(m, vector<t>(n,a)) ));\n \ntypedef long long ll;\nconst int INF = 2000000000;\nconst ll INF64 = 9223372036854775806ll;\nconst int mod = 1000000007ll;\nconst ll  MOD = 1000000007LL;\nconst double pi=3.1415926535897932384626;\nint main(){\n    int n;\n    std::cin >> n;\n    VEC(int,a,n);\n    rep(i,n)a[i]--;\n    VEC(int,b,n);\n    VEC(int,c,n-1);\n    int ans=0;\n    ans+=b[a[0]];\n    rrep(i,1,n){\n        ans+=b[a[i]];\n        if(a[i]-a[i-1]==1)ans+=c[a[i-1]];\n    }\n    std::cout << ans << std::endl;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nTakahashi went to an all-you-can-eat buffet with N kinds of dishes and ate all of them (Dish 1, Dish 2, \\ldots, Dish N) once.\n\nThe i-th dish (1 \\leq i \\leq N) he ate was Dish A_i.\n\nWhen he eats Dish i (1 \\leq i \\leq N), he gains B_i satisfaction points.\n\nAdditionally, when he eats Dish i+1 just after eating Dish i (1 \\leq i \\leq N - 1), he gains C_i more satisfaction points.\n\nFind the sum of the satisfaction points he gained.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 20\n\n1 \\leq A_i \\leq N\n\nA_1, A_2, ..., A_N are all different.\n\n1 \\leq B_i \\leq 50\n\n1 \\leq C_i \\leq 50\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\nB_1 B_2 ... B_N\nC_1 C_2 ... C_{N-1}\n\nOutput\n\nPrint the sum of the satisfaction points Takahashi gained, as an integer.\n\nSample Input 1\n\n3\n3 1 2\n2 5 4\n3 6\n\nSample Output 1\n\n14\n\nTakahashi gained 14 satisfaction points in total, as follows:\n\nFirst, he ate Dish 3 and gained 4 satisfaction points.\n\nNext, he ate Dish 1 and gained 2 satisfaction points.\n\nLastly, he ate Dish 2 and gained 5 + 3 = 8 satisfaction points.\n\nSample Input 2\n\n4\n2 3 4 1\n13 5 8 24\n45 9 15\n\nSample Output 2\n\n74\n\nSample Input 3\n\n2\n1 2\n50 50\n50\n\nSample Output 3\n\n150", "sample_input": "3\n3 1 2\n2 5 4\n3 6\n"}, "reference_outputs": ["14\n"], "source_document_id": "p02916", "source_text": "Score : 200 points\n\nProblem Statement\n\nTakahashi went to an all-you-can-eat buffet with N kinds of dishes and ate all of them (Dish 1, Dish 2, \\ldots, Dish N) once.\n\nThe i-th dish (1 \\leq i \\leq N) he ate was Dish A_i.\n\nWhen he eats Dish i (1 \\leq i \\leq N), he gains B_i satisfaction points.\n\nAdditionally, when he eats Dish i+1 just after eating Dish i (1 \\leq i \\leq N - 1), he gains C_i more satisfaction points.\n\nFind the sum of the satisfaction points he gained.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 20\n\n1 \\leq A_i \\leq N\n\nA_1, A_2, ..., A_N are all different.\n\n1 \\leq B_i \\leq 50\n\n1 \\leq C_i \\leq 50\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\nB_1 B_2 ... B_N\nC_1 C_2 ... C_{N-1}\n\nOutput\n\nPrint the sum of the satisfaction points Takahashi gained, as an integer.\n\nSample Input 1\n\n3\n3 1 2\n2 5 4\n3 6\n\nSample Output 1\n\n14\n\nTakahashi gained 14 satisfaction points in total, as follows:\n\nFirst, he ate Dish 3 and gained 4 satisfaction points.\n\nNext, he ate Dish 1 and gained 2 satisfaction points.\n\nLastly, he ate Dish 2 and gained 5 + 3 = 8 satisfaction points.\n\nSample Input 2\n\n4\n2 3 4 1\n13 5 8 24\n45 9 15\n\nSample Output 2\n\n74\n\nSample Input 3\n\n2\n1 2\n50 50\n50\n\nSample Output 3\n\n150", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1867, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s019316445", "group_id": "codeNet:p02917", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  int N;\n  cin>>N;\n vector<int> B(N-1);\n  for(int i=0;i<N-1;i++){\n    cin>>B.at(i);\n  }\n  int sum=0;\n  for(int i=0;i<N-1;i++){\n    if(i==0){\n      sum+=B.at(0);\n    }else if(B.at(i)<=B.at(i-1)){\n      sum+=B.at(i);\n    }else{\n      sum+=B.at(i-1);\n    }\n  }\n  sum+=B.at(N-2);\n  cout<<sum<<endl;\n}", "language": "C++", "metadata": {"date": 1597331981, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02917.html", "problem_id": "p02917", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02917/input.txt", "sample_output_relpath": "derived/input_output/data/p02917/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02917/C++/s019316445.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s019316445", "user_id": "u477852062"}, "prompt_components": {"gold_output": "9\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  int N;\n  cin>>N;\n vector<int> B(N-1);\n  for(int i=0;i<N-1;i++){\n    cin>>B.at(i);\n  }\n  int sum=0;\n  for(int i=0;i<N-1;i++){\n    if(i==0){\n      sum+=B.at(0);\n    }else if(B.at(i)<=B.at(i-1)){\n      sum+=B.at(i);\n    }else{\n      sum+=B.at(i-1);\n    }\n  }\n  sum+=B.at(N-2);\n  cout<<sum<<endl;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere is an integer sequence A of length N whose values are unknown.\n\nGiven is an integer sequence B of length N-1 which is known to satisfy the following:\n\nB_i \\geq \\max(A_i, A_{i+1})\n\nFind the maximum possible sum of the elements of A.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 100\n\n0 \\leq B_i \\leq 10^5\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nB_1 B_2 ... B_{N-1}\n\nOutput\n\nPrint the maximum possible sum of the elements of A.\n\nSample Input 1\n\n3\n2 5\n\nSample Output 1\n\n9\n\nA can be, for example, ( 2 , 1 , 5 ), ( -1 , -2 , -3 ), or ( 2 , 2 , 5 ). Among those candidates, A = ( 2 , 2 , 5 ) has the maximum possible sum.\n\nSample Input 2\n\n2\n3\n\nSample Output 2\n\n6\n\nSample Input 3\n\n6\n0 153 10 10 23\n\nSample Output 3\n\n53", "sample_input": "3\n2 5\n"}, "reference_outputs": ["9\n"], "source_document_id": "p02917", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere is an integer sequence A of length N whose values are unknown.\n\nGiven is an integer sequence B of length N-1 which is known to satisfy the following:\n\nB_i \\geq \\max(A_i, A_{i+1})\n\nFind the maximum possible sum of the elements of A.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 100\n\n0 \\leq B_i \\leq 10^5\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nB_1 B_2 ... B_{N-1}\n\nOutput\n\nPrint the maximum possible sum of the elements of A.\n\nSample Input 1\n\n3\n2 5\n\nSample Output 1\n\n9\n\nA can be, for example, ( 2 , 1 , 5 ), ( -1 , -2 , -3 ), or ( 2 , 2 , 5 ). Among those candidates, A = ( 2 , 2 , 5 ) has the maximum possible sum.\n\nSample Input 2\n\n2\n3\n\nSample Output 2\n\n6\n\nSample Input 3\n\n6\n0 153 10 10 23\n\nSample Output 3\n\n53", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 354, "cpu_time_ms": 7, "memory_kb": 3612}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s213062670", "group_id": "codeNet:p02918", "input_text": "#include <iostream>\n#include <string>\nusing namespace std;\n\nint main()\n{\n  int n, k;\n  cin >> n;\n  cin >> k;\n  string s;\n  cin >> s;\n  \n  int gap = 0;\n  for (int i = 0; i < n - 1; ++i)\n  {\n    if (s[i] == 'R' && s[i + 1] == 'L') ++gap;\n  }\n  \n  int eGap = 0;\n  if (s[0] == 'L') ++eGap;\n  if (s[n-1] == 'R') ++eGap;\n  \n  int unhappy;\n  if (k < gap)\n  {\n    unhappy = 2 * (gap - k) + eGap;\n  }\n  else if (k == gap)\n  {\n    unhappy = eGap == 0 ? 1 : eGap;\n  }\n  else\n  {\n    unhappy = 1;\n  }\n  cout << (n - unhappy) << endl;\n  \n  return 0;\n}", "language": "C++", "metadata": {"date": 1569104613, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02918.html", "problem_id": "p02918", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02918/input.txt", "sample_output_relpath": "derived/input_output/data/p02918/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02918/C++/s213062670.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s213062670", "user_id": "u269517448"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <iostream>\n#include <string>\nusing namespace std;\n\nint main()\n{\n  int n, k;\n  cin >> n;\n  cin >> k;\n  string s;\n  cin >> s;\n  \n  int gap = 0;\n  for (int i = 0; i < n - 1; ++i)\n  {\n    if (s[i] == 'R' && s[i + 1] == 'L') ++gap;\n  }\n  \n  int eGap = 0;\n  if (s[0] == 'L') ++eGap;\n  if (s[n-1] == 'R') ++eGap;\n  \n  int unhappy;\n  if (k < gap)\n  {\n    unhappy = 2 * (gap - k) + eGap;\n  }\n  else if (k == gap)\n  {\n    unhappy = eGap == 0 ? 1 : eGap;\n  }\n  else\n  {\n    unhappy = 1;\n  }\n  cout << (n - unhappy) << endl;\n  \n  return 0;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nThere are N people standing in a queue from west to east.\n\nGiven is a string S of length N representing the directions of the people.\nThe i-th person from the west is facing west if the i-th character of S is L, and east if that character of S is R.\n\nA person is happy if the person in front of him/her is facing the same direction.\nIf no person is standing in front of a person, however, he/she is not happy.\n\nYou can perform the following operation any number of times between 0 and K (inclusive):\n\nOperation: Choose integers l and r such that 1 \\leq l \\leq r \\leq N, and rotate by 180 degrees the part of the queue: the l-th, (l+1)-th, ..., r-th persons. That is, for each i = 0, 1, ..., r-l, the (l + i)-th person from the west will stand the (r - i)-th from the west after the operation, facing east if he/she is facing west now, and vice versa.\n\nWhat is the maximum possible number of happy people you can have?\n\nConstraints\n\nN is an integer satisfying 1 \\leq N \\leq 10^5.\n\nK is an integer satisfying 1 \\leq K \\leq 10^5.\n\n|S| = N\n\nEach character of S is L or R.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nS\n\nOutput\n\nPrint the maximum possible number of happy people after at most K operations.\n\nSample Input 1\n\n6 1\nLRLRRL\n\nSample Output 1\n\n3\n\nIf we choose (l, r) = (2, 5), we have LLLRLL, where the 2-nd, 3-rd, and 6-th persons from the west are happy.\n\nSample Input 2\n\n13 3\nLRRLRLRRLRLLR\n\nSample Output 2\n\n9\n\nSample Input 3\n\n10 1\nLLLLLRRRRR\n\nSample Output 3\n\n9\n\nSample Input 4\n\n9 2\nRRRLRLRLL\n\nSample Output 4\n\n7", "sample_input": "6 1\nLRLRRL\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02918", "source_text": "Score : 400 points\n\nProblem Statement\n\nThere are N people standing in a queue from west to east.\n\nGiven is a string S of length N representing the directions of the people.\nThe i-th person from the west is facing west if the i-th character of S is L, and east if that character of S is R.\n\nA person is happy if the person in front of him/her is facing the same direction.\nIf no person is standing in front of a person, however, he/she is not happy.\n\nYou can perform the following operation any number of times between 0 and K (inclusive):\n\nOperation: Choose integers l and r such that 1 \\leq l \\leq r \\leq N, and rotate by 180 degrees the part of the queue: the l-th, (l+1)-th, ..., r-th persons. That is, for each i = 0, 1, ..., r-l, the (l + i)-th person from the west will stand the (r - i)-th from the west after the operation, facing east if he/she is facing west now, and vice versa.\n\nWhat is the maximum possible number of happy people you can have?\n\nConstraints\n\nN is an integer satisfying 1 \\leq N \\leq 10^5.\n\nK is an integer satisfying 1 \\leq K \\leq 10^5.\n\n|S| = N\n\nEach character of S is L or R.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nS\n\nOutput\n\nPrint the maximum possible number of happy people after at most K operations.\n\nSample Input 1\n\n6 1\nLRLRRL\n\nSample Output 1\n\n3\n\nIf we choose (l, r) = (2, 5), we have LLLRLL, where the 2-nd, 3-rd, and 6-th persons from the west are happy.\n\nSample Input 2\n\n13 3\nLRRLRLRRLRLLR\n\nSample Output 2\n\n9\n\nSample Input 3\n\n10 1\nLLLLLRRRRR\n\nSample Output 3\n\n9\n\nSample Input 4\n\n9 2\nRRRLRLRLL\n\nSample Output 4\n\n7", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 538, "cpu_time_ms": 5, "memory_kb": 512}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s730898912", "group_id": "codeNet:p02919", "input_text": "#include <iostream>\n#include <string>\n#include <vector>\n#include <queue>\n#include <set>\n#include <map>\n#include <utility>\n#include <stack>\n#include <numeric>\n#include <algorithm>\n#include <tuple>\n#include <stdio.h>\n#include <bitset>\n#include <limits.h>\n#include <complex>\n#include <deque>\n#include <iomanip>\n#include <list>\n#include <cstring>\nusing namespace std;\n#define pi pair<int,int>\n#define pl pair<long long,long long>\n#define chmax(a,b) (a<b ? a=b:0)\n#define chmin(a,b) (a>b ? a=b:0)\n#define en cout << endl //セミコロンつけろ\n//#define MM 1000000000\n//#define MOD MM+7\ntypedef long long ll;\nconst int MM = 1e9;\nconst int MOD = MM+7;\nconst long double PI = acos(-1);\nconst long long INF = 1e15;\nint dx[8] = {-1,0,1,0,-1,-1,1,1};\nint dy[8] = {0,-1,0,1,-1,1,1,-1};\n// 'A' = 65, 'Z' = 90, 'a' = 97, 'z' = 122\ntemplate<typename T>\nT GCD(T u,T v){\n    return v ? GCD(v,u%v) : u;\n}\ntemplate<typename T>\nT LCM(T x,T y){\n    T gc = GCD(x,y);\n    return x*y/gc;\n}\nstruct edge {\n    ll to,cost;\n};\n/*\nconst int COM_MAX = 500500;\nlong long fac[COM_MAX],finv[COM_MAX],inv[COM_MAX];\nvoid init(){\n    fac[0] = fac[1] = 1;\n    finv[0] = finv[1] = 1;\n    inv[1] = 1;\n    for(int i = 2; i < COM_MAX; i++){\n        fac[i] = fac[i-1]*i%MOD;\n        inv[i] = MOD - inv[MOD%i]*(MOD/i)%MOD;\n        finv[i] = finv[i-1]*inv[i]%MOD;\n    }\n}\nlong long COM(int n,int k){\n    if(n < k || n < 0 || k < 0) return 0;\n    return fac[n]*(finv[k]*finv[n-k]%MOD)%MOD;\n}\n*/\n\nint main(){\n    int N; cin >> N;\n    vector<int> p(N),inv(N);\n    for (int i = 0; i < N; i++){\n        cin >> p[i];\n        inv[p[i]-1] = i;\n    }\n    set<int> s;\n    ll ans = 0;\n    for (int i = -2; i < N+2; i++){\n        s.insert(i);\n    }\n    for (int i = 0; i < N; i++){\n        int k = inv[k];\n        s.erase(k);\n        auto it1 = s.upper_bound(k);\n        auto it2 = it1;\n        int r1 = *it1;\n        int r2 = *++it1;\n        int l1 = *--it2;\n        int l2 = *--it2;\n        if (r1 < N){\n            ans += (ll)(r2-r1)*(k-l1)*(i+1);\n        }\n        if (l1 >= 0){\n            ans += (ll)(l1-l2)*(r1-k)*(i+1);\n        }\n        s.erase(k);\n    }\n    cout << ans << endl;\n}", "language": "C++", "metadata": {"date": 1567895627, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02919.html", "problem_id": "p02919", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02919/input.txt", "sample_output_relpath": "derived/input_output/data/p02919/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02919/C++/s730898912.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s730898912", "user_id": "u342051078"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include <iostream>\n#include <string>\n#include <vector>\n#include <queue>\n#include <set>\n#include <map>\n#include <utility>\n#include <stack>\n#include <numeric>\n#include <algorithm>\n#include <tuple>\n#include <stdio.h>\n#include <bitset>\n#include <limits.h>\n#include <complex>\n#include <deque>\n#include <iomanip>\n#include <list>\n#include <cstring>\nusing namespace std;\n#define pi pair<int,int>\n#define pl pair<long long,long long>\n#define chmax(a,b) (a<b ? a=b:0)\n#define chmin(a,b) (a>b ? a=b:0)\n#define en cout << endl //セミコロンつけろ\n//#define MM 1000000000\n//#define MOD MM+7\ntypedef long long ll;\nconst int MM = 1e9;\nconst int MOD = MM+7;\nconst long double PI = acos(-1);\nconst long long INF = 1e15;\nint dx[8] = {-1,0,1,0,-1,-1,1,1};\nint dy[8] = {0,-1,0,1,-1,1,1,-1};\n// 'A' = 65, 'Z' = 90, 'a' = 97, 'z' = 122\ntemplate<typename T>\nT GCD(T u,T v){\n    return v ? GCD(v,u%v) : u;\n}\ntemplate<typename T>\nT LCM(T x,T y){\n    T gc = GCD(x,y);\n    return x*y/gc;\n}\nstruct edge {\n    ll to,cost;\n};\n/*\nconst int COM_MAX = 500500;\nlong long fac[COM_MAX],finv[COM_MAX],inv[COM_MAX];\nvoid init(){\n    fac[0] = fac[1] = 1;\n    finv[0] = finv[1] = 1;\n    inv[1] = 1;\n    for(int i = 2; i < COM_MAX; i++){\n        fac[i] = fac[i-1]*i%MOD;\n        inv[i] = MOD - inv[MOD%i]*(MOD/i)%MOD;\n        finv[i] = finv[i-1]*inv[i]%MOD;\n    }\n}\nlong long COM(int n,int k){\n    if(n < k || n < 0 || k < 0) return 0;\n    return fac[n]*(finv[k]*finv[n-k]%MOD)%MOD;\n}\n*/\n\nint main(){\n    int N; cin >> N;\n    vector<int> p(N),inv(N);\n    for (int i = 0; i < N; i++){\n        cin >> p[i];\n        inv[p[i]-1] = i;\n    }\n    set<int> s;\n    ll ans = 0;\n    for (int i = -2; i < N+2; i++){\n        s.insert(i);\n    }\n    for (int i = 0; i < N; i++){\n        int k = inv[k];\n        s.erase(k);\n        auto it1 = s.upper_bound(k);\n        auto it2 = it1;\n        int r1 = *it1;\n        int r2 = *++it1;\n        int l1 = *--it2;\n        int l2 = *--it2;\n        if (r1 < N){\n            ans += (ll)(r2-r1)*(k-l1)*(i+1);\n        }\n        if (l1 >= 0){\n            ans += (ll)(l1-l2)*(r1-k)*(i+1);\n        }\n        s.erase(k);\n    }\n    cout << ans << endl;\n}", "problem_context": "Score: 500 points\n\nProblem Statement\n\nGiven is a permutation P of \\{1, 2, \\ldots, N\\}.\n\nFor a pair (L, R) (1 \\le L \\lt R \\le N), let X_{L, R} be the second largest value among P_L, P_{L+1}, \\ldots, P_R.\n\nFind \\displaystyle \\sum_{L=1}^{N-1} \\sum_{R=L+1}^{N} X_{L,R}.\n\nConstraints\n\n2 \\le N \\le 10^5\n\n1 \\le P_i \\le N\n\nP_i \\neq P_j (i \\neq j)\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nP_1 P_2 \\ldots P_N\n\nOutput\n\nPrint \\displaystyle \\sum_{L=1}^{N-1} \\sum_{R=L+1}^{N} X_{L,R}.\n\nSample Input 1\n\n3\n2 3 1\n\nSample Output 1\n\n5\n\nX_{1, 2} = 2, X_{1, 3} = 2, and X_{2, 3} = 1, so the sum is 2 + 2 + 1 = 5.\n\nSample Input 2\n\n5\n1 2 3 4 5\n\nSample Output 2\n\n30\n\nSample Input 3\n\n8\n8 2 7 3 4 5 6 1\n\nSample Output 3\n\n136", "sample_input": "3\n2 3 1\n"}, "reference_outputs": ["5\n"], "source_document_id": "p02919", "source_text": "Score: 500 points\n\nProblem Statement\n\nGiven is a permutation P of \\{1, 2, \\ldots, N\\}.\n\nFor a pair (L, R) (1 \\le L \\lt R \\le N), let X_{L, R} be the second largest value among P_L, P_{L+1}, \\ldots, P_R.\n\nFind \\displaystyle \\sum_{L=1}^{N-1} \\sum_{R=L+1}^{N} X_{L,R}.\n\nConstraints\n\n2 \\le N \\le 10^5\n\n1 \\le P_i \\le N\n\nP_i \\neq P_j (i \\neq j)\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nP_1 P_2 \\ldots P_N\n\nOutput\n\nPrint \\displaystyle \\sum_{L=1}^{N-1} \\sum_{R=L+1}^{N} X_{L,R}.\n\nSample Input 1\n\n3\n2 3 1\n\nSample Output 1\n\n5\n\nX_{1, 2} = 2, X_{1, 3} = 2, and X_{2, 3} = 1, so the sum is 2 + 2 + 1 = 5.\n\nSample Input 2\n\n5\n1 2 3 4 5\n\nSample Output 2\n\n30\n\nSample Input 3\n\n8\n8 2 7 3 4 5 6 1\n\nSample Output 3\n\n136", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2139, "cpu_time_ms": 111, "memory_kb": 5760}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s936699632", "group_id": "codeNet:p02921", "input_text": "/*\n Read problem and understand it 100%\n Make observation\n SOLVE THE PROBLEM\n*/\n#include <bits/stdc++.h>\n#define fr first\n#define sc second\n#define pii pair<int, int>\n#define int long long\n#define szof(s) (int)s.size()\n#define all(s) (int)s.begin(), s.end()\nusing namespace std;\n \nconst int N = (int)1e6 + 5;\nconst int INF = (int)1e9 + 9;\nconst int MOD = (int)1e9 + 7;\n \nmain() {\n\tstring s, t;\n\tcin >> s >> t;\n\tint ans = 0;\n\tfor (int i = 0; i < 3; i++) {\n\t\tans += (s[i] == t[i]);\n\t}\n\tcout << ans << endl;\n}\n", "language": "C++", "metadata": {"date": 1571177185, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02921.html", "problem_id": "p02921", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02921/input.txt", "sample_output_relpath": "derived/input_output/data/p02921/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02921/C++/s936699632.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s936699632", "user_id": "u361596783"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "/*\n Read problem and understand it 100%\n Make observation\n SOLVE THE PROBLEM\n*/\n#include <bits/stdc++.h>\n#define fr first\n#define sc second\n#define pii pair<int, int>\n#define int long long\n#define szof(s) (int)s.size()\n#define all(s) (int)s.begin(), s.end()\nusing namespace std;\n \nconst int N = (int)1e6 + 5;\nconst int INF = (int)1e9 + 9;\nconst int MOD = (int)1e9 + 7;\n \nmain() {\n\tstring s, t;\n\tcin >> s >> t;\n\tint ans = 0;\n\tfor (int i = 0; i < 3; i++) {\n\t\tans += (s[i] == t[i]);\n\t}\n\tcout << ans << endl;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nYou will be given a string S of length 3 representing the weather forecast for three days in the past.\n\nThe i-th character (1 \\leq i \\leq 3) of S represents the forecast for the i-th day. S, C, and R stand for sunny, cloudy, and rainy, respectively.\n\nYou will also be given a string T of length 3 representing the actual weather on those three days.\n\nThe i-th character (1 \\leq i \\leq 3) of S represents the actual weather on the i-th day. S, C, and R stand for sunny, cloudy, and rainy, respectively.\n\nPrint the number of days for which the forecast was correct.\n\nConstraints\n\nS and T are strings of length 3 each.\n\nS and T consist of S, C, and R.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\nT\n\nOutput\n\nPrint the number of days for which the forecast was correct.\n\nSample Input 1\n\nCSS\nCSR\n\nSample Output 1\n\n2\n\nFor the first day, it was forecast to be cloudy, and it was indeed cloudy.\n\nFor the second day, it was forecast to be sunny, and it was indeed sunny.\n\nFor the third day, it was forecast to be sunny, but it was rainy.\n\nThus, the forecast was correct for two days in this case.\n\nSample Input 2\n\nSSR\nSSR\n\nSample Output 2\n\n3\n\nSample Input 3\n\nRRR\nSSS\n\nSample Output 3\n\n0", "sample_input": "CSS\nCSR\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02921", "source_text": "Score : 100 points\n\nProblem Statement\n\nYou will be given a string S of length 3 representing the weather forecast for three days in the past.\n\nThe i-th character (1 \\leq i \\leq 3) of S represents the forecast for the i-th day. S, C, and R stand for sunny, cloudy, and rainy, respectively.\n\nYou will also be given a string T of length 3 representing the actual weather on those three days.\n\nThe i-th character (1 \\leq i \\leq 3) of S represents the actual weather on the i-th day. S, C, and R stand for sunny, cloudy, and rainy, respectively.\n\nPrint the number of days for which the forecast was correct.\n\nConstraints\n\nS and T are strings of length 3 each.\n\nS and T consist of S, C, and R.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\nT\n\nOutput\n\nPrint the number of days for which the forecast was correct.\n\nSample Input 1\n\nCSS\nCSR\n\nSample Output 1\n\n2\n\nFor the first day, it was forecast to be cloudy, and it was indeed cloudy.\n\nFor the second day, it was forecast to be sunny, and it was indeed sunny.\n\nFor the third day, it was forecast to be sunny, but it was rainy.\n\nThus, the forecast was correct for two days in this case.\n\nSample Input 2\n\nSSR\nSSR\n\nSample Output 2\n\n3\n\nSample Input 3\n\nRRR\nSSS\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 507, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s139065649", "group_id": "codeNet:p02922", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint a, b;\nint nr, s;\n\nint main() {\n    cin >> a >> b;\n    s = a;\n    nr = 1;\n    if(b == 1) {\n        cout << 0;\n        return 0;\n    }\n    while(s < b) {\n        nr++;\n        s = s + a - 1;\n    }\n    cout << nr;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1594255127, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02922.html", "problem_id": "p02922", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02922/input.txt", "sample_output_relpath": "derived/input_output/data/p02922/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02922/C++/s139065649.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s139065649", "user_id": "u644497121"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint a, b;\nint nr, s;\n\nint main() {\n    cin >> a >> b;\n    s = a;\n    nr = 1;\n    if(b == 1) {\n        cout << 0;\n        return 0;\n    }\n    while(s < b) {\n        nr++;\n        s = s + a - 1;\n    }\n    cout << nr;\n    return 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nTakahashi's house has only one socket.\n\nTakahashi wants to extend it with some number of power strips, each with A sockets, into B or more empty sockets.\n\nOne power strip with A sockets can extend one empty socket into A empty sockets.\n\nFind the minimum number of power strips required.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq A \\leq 20\n\n1 \\leq B \\leq 20\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nPrint the minimum number of power strips required.\n\nSample Input 1\n\n4 10\n\nSample Output 1\n\n3\n\n3 power strips, each with 4 sockets, extend the socket into 10 empty sockets.\n\nSample Input 2\n\n8 9\n\nSample Output 2\n\n2\n\n2 power strips, each with 8 sockets, extend the socket into 15 empty sockets.\n\nSample Input 3\n\n8 8\n\nSample Output 3\n\n1", "sample_input": "4 10\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02922", "source_text": "Score : 200 points\n\nProblem Statement\n\nTakahashi's house has only one socket.\n\nTakahashi wants to extend it with some number of power strips, each with A sockets, into B or more empty sockets.\n\nOne power strip with A sockets can extend one empty socket into A empty sockets.\n\nFind the minimum number of power strips required.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq A \\leq 20\n\n1 \\leq B \\leq 20\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nPrint the minimum number of power strips required.\n\nSample Input 1\n\n4 10\n\nSample Output 1\n\n3\n\n3 power strips, each with 4 sockets, extend the socket into 10 empty sockets.\n\nSample Input 2\n\n8 9\n\nSample Output 2\n\n2\n\n2 power strips, each with 8 sockets, extend the socket into 15 empty sockets.\n\nSample Input 3\n\n8 8\n\nSample Output 3\n\n1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 277, "cpu_time_ms": 6, "memory_kb": 3636}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s283351129", "group_id": "codeNet:p02922", "input_text": "#include <bits/stdc++.h>\n#include <vector> \n# include <cstdint>\n#define FOR(i,l,r) for(int i=(l);i<(r);++i)\n#define RFOR(i,l,r) for(int i=(l);i>=(int)(r);i--)\n#define rep(i,n)  FOR(i,0,n)\n#define rrep(i,n)  RFOR(i,n-1,0)\n\n// #define int long long\nusing namespace std;\nconst int MX = 1e6;\nconst int inf = 1e9;\n\nusing P = pair<int, int>;\n\n\nvector<int> to[100005];\nint cost[100005];\nsigned main(){\n    int a,b;\n    cin >> a>> b;\n    int ans = 1;\n    while(ans*a <b) ans++;\n    cout << ans << endl;\n\n    return 0;\n}\n\n", "language": "C++", "metadata": {"date": 1590852287, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02922.html", "problem_id": "p02922", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02922/input.txt", "sample_output_relpath": "derived/input_output/data/p02922/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02922/C++/s283351129.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s283351129", "user_id": "u762160119"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#include <vector> \n# include <cstdint>\n#define FOR(i,l,r) for(int i=(l);i<(r);++i)\n#define RFOR(i,l,r) for(int i=(l);i>=(int)(r);i--)\n#define rep(i,n)  FOR(i,0,n)\n#define rrep(i,n)  RFOR(i,n-1,0)\n\n// #define int long long\nusing namespace std;\nconst int MX = 1e6;\nconst int inf = 1e9;\n\nusing P = pair<int, int>;\n\n\nvector<int> to[100005];\nint cost[100005];\nsigned main(){\n    int a,b;\n    cin >> a>> b;\n    int ans = 1;\n    while(ans*a <b) ans++;\n    cout << ans << endl;\n\n    return 0;\n}\n\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nTakahashi's house has only one socket.\n\nTakahashi wants to extend it with some number of power strips, each with A sockets, into B or more empty sockets.\n\nOne power strip with A sockets can extend one empty socket into A empty sockets.\n\nFind the minimum number of power strips required.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq A \\leq 20\n\n1 \\leq B \\leq 20\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nPrint the minimum number of power strips required.\n\nSample Input 1\n\n4 10\n\nSample Output 1\n\n3\n\n3 power strips, each with 4 sockets, extend the socket into 10 empty sockets.\n\nSample Input 2\n\n8 9\n\nSample Output 2\n\n2\n\n2 power strips, each with 8 sockets, extend the socket into 15 empty sockets.\n\nSample Input 3\n\n8 8\n\nSample Output 3\n\n1", "sample_input": "4 10\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02922", "source_text": "Score : 200 points\n\nProblem Statement\n\nTakahashi's house has only one socket.\n\nTakahashi wants to extend it with some number of power strips, each with A sockets, into B or more empty sockets.\n\nOne power strip with A sockets can extend one empty socket into A empty sockets.\n\nFind the minimum number of power strips required.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq A \\leq 20\n\n1 \\leq B \\leq 20\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nPrint the minimum number of power strips required.\n\nSample Input 1\n\n4 10\n\nSample Output 1\n\n3\n\n3 power strips, each with 4 sockets, extend the socket into 10 empty sockets.\n\nSample Input 2\n\n8 9\n\nSample Output 2\n\n2\n\n2 power strips, each with 8 sockets, extend the socket into 15 empty sockets.\n\nSample Input 3\n\n8 8\n\nSample Output 3\n\n1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 513, "cpu_time_ms": 2, "memory_kb": 2560}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s200991441", "group_id": "codeNet:p02922", "input_text": "#include <bits/stdc++.h>\n#define st first\n#define nd second\n\nusing namespace std;\n\nvoid debug_out() { cerr << endl; }\ntemplate<class T> ostream& prnt(ostream& out, T v) { out << v.size() << '\\n'; for(auto e : v) out << e << ' '; return out;}\ntemplate<class T> ostream& operator<<(ostream& out, vector <T> v) { return prnt(out, v); }\ntemplate<class T> ostream& operator<<(ostream& out, set <T> v) { return prnt(out, v); }\ntemplate<class T1, class T2> ostream& operator<<(ostream& out, map <T1, T2> v) { return prnt(out, v); }\ntemplate<class T1, class T2> ostream& operator<<(ostream& out, pair<T1, T2> p) { return out << '(' << p.st << ' ' << p.nd << ')'; }\ntemplate <typename Head, typename... Tail> void debug_out(Head H, Tail... T) { cerr << \" \" << H; debug_out(T...);}\n\n#define dbg(...) cerr << #__VA_ARGS__ << \" ->\", debug_out(__VA_ARGS__)\n#define dbg_v(x, n) do{cerr<<#x\"[]: \";for(int _=0;_<n;++_)cerr<<x[_]<<\" \";cerr<<'\\n';}while(0)\n#define dbg_ok cerr<<\"OK!\\n\"\n\n// const int N = ;\nint n, a, b;\n\nint main() {\n\tios_base::sync_with_stdio(false);\n\n\tcin >> a >> b;\n\tint req = b - 1;\n\ta--;\n\tcout << (req + a - 1) / a;\n}\t\n\n\t", "language": "C++", "metadata": {"date": 1567809594, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02922.html", "problem_id": "p02922", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02922/input.txt", "sample_output_relpath": "derived/input_output/data/p02922/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02922/C++/s200991441.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s200991441", "user_id": "u541161485"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define st first\n#define nd second\n\nusing namespace std;\n\nvoid debug_out() { cerr << endl; }\ntemplate<class T> ostream& prnt(ostream& out, T v) { out << v.size() << '\\n'; for(auto e : v) out << e << ' '; return out;}\ntemplate<class T> ostream& operator<<(ostream& out, vector <T> v) { return prnt(out, v); }\ntemplate<class T> ostream& operator<<(ostream& out, set <T> v) { return prnt(out, v); }\ntemplate<class T1, class T2> ostream& operator<<(ostream& out, map <T1, T2> v) { return prnt(out, v); }\ntemplate<class T1, class T2> ostream& operator<<(ostream& out, pair<T1, T2> p) { return out << '(' << p.st << ' ' << p.nd << ')'; }\ntemplate <typename Head, typename... Tail> void debug_out(Head H, Tail... T) { cerr << \" \" << H; debug_out(T...);}\n\n#define dbg(...) cerr << #__VA_ARGS__ << \" ->\", debug_out(__VA_ARGS__)\n#define dbg_v(x, n) do{cerr<<#x\"[]: \";for(int _=0;_<n;++_)cerr<<x[_]<<\" \";cerr<<'\\n';}while(0)\n#define dbg_ok cerr<<\"OK!\\n\"\n\n// const int N = ;\nint n, a, b;\n\nint main() {\n\tios_base::sync_with_stdio(false);\n\n\tcin >> a >> b;\n\tint req = b - 1;\n\ta--;\n\tcout << (req + a - 1) / a;\n}\t\n\n\t", "problem_context": "Score : 200 points\n\nProblem Statement\n\nTakahashi's house has only one socket.\n\nTakahashi wants to extend it with some number of power strips, each with A sockets, into B or more empty sockets.\n\nOne power strip with A sockets can extend one empty socket into A empty sockets.\n\nFind the minimum number of power strips required.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq A \\leq 20\n\n1 \\leq B \\leq 20\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nPrint the minimum number of power strips required.\n\nSample Input 1\n\n4 10\n\nSample Output 1\n\n3\n\n3 power strips, each with 4 sockets, extend the socket into 10 empty sockets.\n\nSample Input 2\n\n8 9\n\nSample Output 2\n\n2\n\n2 power strips, each with 8 sockets, extend the socket into 15 empty sockets.\n\nSample Input 3\n\n8 8\n\nSample Output 3\n\n1", "sample_input": "4 10\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02922", "source_text": "Score : 200 points\n\nProblem Statement\n\nTakahashi's house has only one socket.\n\nTakahashi wants to extend it with some number of power strips, each with A sockets, into B or more empty sockets.\n\nOne power strip with A sockets can extend one empty socket into A empty sockets.\n\nFind the minimum number of power strips required.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq A \\leq 20\n\n1 \\leq B \\leq 20\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nPrint the minimum number of power strips required.\n\nSample Input 1\n\n4 10\n\nSample Output 1\n\n3\n\n3 power strips, each with 4 sockets, extend the socket into 10 empty sockets.\n\nSample Input 2\n\n8 9\n\nSample Output 2\n\n2\n\n2 power strips, each with 8 sockets, extend the socket into 15 empty sockets.\n\nSample Input 3\n\n8 8\n\nSample Output 3\n\n1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1124, "cpu_time_ms": 3, "memory_kb": 384}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s903323978", "group_id": "codeNet:p02922", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nlong long int sum_of_digits(long long int n){\n    long long int sum=0;\n    long long int dd=0;\nwhile(n!=0){\n        dd=n%10;\nsum=sum+dd;\n    n=n/10;\n}\nreturn sum;\n}\nint main() {\nint a,b;\ncin>>a>>b;\nint i=0;\nfor(int i=1;i<200;i++){\n    int d=a*i;\n    if(d>=b){\n        cout<<i<<endl;\n        break;\n    }\n}\n\n\n}\n", "language": "C++", "metadata": {"date": 1567365686, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02922.html", "problem_id": "p02922", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02922/input.txt", "sample_output_relpath": "derived/input_output/data/p02922/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02922/C++/s903323978.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s903323978", "user_id": "u119271498"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nlong long int sum_of_digits(long long int n){\n    long long int sum=0;\n    long long int dd=0;\nwhile(n!=0){\n        dd=n%10;\nsum=sum+dd;\n    n=n/10;\n}\nreturn sum;\n}\nint main() {\nint a,b;\ncin>>a>>b;\nint i=0;\nfor(int i=1;i<200;i++){\n    int d=a*i;\n    if(d>=b){\n        cout<<i<<endl;\n        break;\n    }\n}\n\n\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nTakahashi's house has only one socket.\n\nTakahashi wants to extend it with some number of power strips, each with A sockets, into B or more empty sockets.\n\nOne power strip with A sockets can extend one empty socket into A empty sockets.\n\nFind the minimum number of power strips required.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq A \\leq 20\n\n1 \\leq B \\leq 20\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nPrint the minimum number of power strips required.\n\nSample Input 1\n\n4 10\n\nSample Output 1\n\n3\n\n3 power strips, each with 4 sockets, extend the socket into 10 empty sockets.\n\nSample Input 2\n\n8 9\n\nSample Output 2\n\n2\n\n2 power strips, each with 8 sockets, extend the socket into 15 empty sockets.\n\nSample Input 3\n\n8 8\n\nSample Output 3\n\n1", "sample_input": "4 10\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02922", "source_text": "Score : 200 points\n\nProblem Statement\n\nTakahashi's house has only one socket.\n\nTakahashi wants to extend it with some number of power strips, each with A sockets, into B or more empty sockets.\n\nOne power strip with A sockets can extend one empty socket into A empty sockets.\n\nFind the minimum number of power strips required.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq A \\leq 20\n\n1 \\leq B \\leq 20\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nPrint the minimum number of power strips required.\n\nSample Input 1\n\n4 10\n\nSample Output 1\n\n3\n\n3 power strips, each with 4 sockets, extend the socket into 10 empty sockets.\n\nSample Input 2\n\n8 9\n\nSample Output 2\n\n2\n\n2 power strips, each with 8 sockets, extend the socket into 15 empty sockets.\n\nSample Input 3\n\n8 8\n\nSample Output 3\n\n1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 356, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s646301070", "group_id": "codeNet:p02923", "input_text": "#include <iostream>\n#include <vector>\nusing namespace std;\n\nint main(){\n    int n;\n    cin >> n;\n    vector<int> h(n+1);\n    for(int i = 0; i < n; i++) cin >> h[i];\n    h[n] = h[n-1]+1;\n    int ans = 0;\n    for(int i = 1, start = 0; i <= n; i++){\n        if(h[i-1] >= h[i]){\n            ;\n        }else{\n            if(i-start-1 > ans) ans = i-start-1;\n            start = i;\n        }\n    }\n    cout << ans << endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1594594906, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02923.html", "problem_id": "p02923", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02923/input.txt", "sample_output_relpath": "derived/input_output/data/p02923/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02923/C++/s646301070.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s646301070", "user_id": "u828593789"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\nusing namespace std;\n\nint main(){\n    int n;\n    cin >> n;\n    vector<int> h(n+1);\n    for(int i = 0; i < n; i++) cin >> h[i];\n    h[n] = h[n-1]+1;\n    int ans = 0;\n    for(int i = 1, start = 0; i <= n; i++){\n        if(h[i-1] >= h[i]){\n            ;\n        }else{\n            if(i-start-1 > ans) ans = i-start-1;\n            start = i;\n        }\n    }\n    cout << ans << endl;\n    return 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N squares arranged in a row from left to right.\n\nThe height of the i-th square from the left is H_i.\n\nYou will land on a square of your choice, then repeat moving to the adjacent square on the right as long as the height of the next square is not greater than that of the current square.\n\nFind the maximum number of times you can move.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq H_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nH_1 H_2 ... H_N\n\nOutput\n\nPrint the maximum number of times you can move.\n\nSample Input 1\n\n5\n10 4 8 7 3\n\nSample Output 1\n\n2\n\nBy landing on the third square from the left, you can move to the right twice.\n\nSample Input 2\n\n7\n4 4 5 6 6 5 5\n\nSample Output 2\n\n3\n\nBy landing on the fourth square from the left, you can move to the right three times.\n\nSample Input 3\n\n4\n1 2 3 4\n\nSample Output 3\n\n0", "sample_input": "5\n10 4 8 7 3\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02923", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N squares arranged in a row from left to right.\n\nThe height of the i-th square from the left is H_i.\n\nYou will land on a square of your choice, then repeat moving to the adjacent square on the right as long as the height of the next square is not greater than that of the current square.\n\nFind the maximum number of times you can move.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq H_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nH_1 H_2 ... H_N\n\nOutput\n\nPrint the maximum number of times you can move.\n\nSample Input 1\n\n5\n10 4 8 7 3\n\nSample Output 1\n\n2\n\nBy landing on the third square from the left, you can move to the right twice.\n\nSample Input 2\n\n7\n4 4 5 6 6 5 5\n\nSample Output 2\n\n3\n\nBy landing on the fourth square from the left, you can move to the right three times.\n\nSample Input 3\n\n4\n1 2 3 4\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 432, "cpu_time_ms": 45, "memory_kb": 3768}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s519840097", "group_id": "codeNet:p02923", "input_text": "#include <iostream>\n#include <string>\n#include <algorithm>\n#include <vector>\n\nusing namespace std;\n\nint main(){\n    int N,max=0;\n    cin>>N;\n    vector<int> H(N);\n    for(int i=0;i<N;i++){\n        cin>>H[i];\n    }\n    for(int i=0;i<N-1;i++){\n        if(max>N-i-2){\n            break;\n        }\n        int count=0;\n        for(int j=i;j<N-1;j++){\n            if(H[j]>=H[j+1]){\n                count++;\n            }else{\n                break;\n            }\n        }\n        if(max<count){\n            max=count;\n        }\n    }\n    cout<<max<<endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1567367729, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02923.html", "problem_id": "p02923", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02923/input.txt", "sample_output_relpath": "derived/input_output/data/p02923/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02923/C++/s519840097.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s519840097", "user_id": "u534015096"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <iostream>\n#include <string>\n#include <algorithm>\n#include <vector>\n\nusing namespace std;\n\nint main(){\n    int N,max=0;\n    cin>>N;\n    vector<int> H(N);\n    for(int i=0;i<N;i++){\n        cin>>H[i];\n    }\n    for(int i=0;i<N-1;i++){\n        if(max>N-i-2){\n            break;\n        }\n        int count=0;\n        for(int j=i;j<N-1;j++){\n            if(H[j]>=H[j+1]){\n                count++;\n            }else{\n                break;\n            }\n        }\n        if(max<count){\n            max=count;\n        }\n    }\n    cout<<max<<endl;\n    return 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N squares arranged in a row from left to right.\n\nThe height of the i-th square from the left is H_i.\n\nYou will land on a square of your choice, then repeat moving to the adjacent square on the right as long as the height of the next square is not greater than that of the current square.\n\nFind the maximum number of times you can move.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq H_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nH_1 H_2 ... H_N\n\nOutput\n\nPrint the maximum number of times you can move.\n\nSample Input 1\n\n5\n10 4 8 7 3\n\nSample Output 1\n\n2\n\nBy landing on the third square from the left, you can move to the right twice.\n\nSample Input 2\n\n7\n4 4 5 6 6 5 5\n\nSample Output 2\n\n3\n\nBy landing on the fourth square from the left, you can move to the right three times.\n\nSample Input 3\n\n4\n1 2 3 4\n\nSample Output 3\n\n0", "sample_input": "5\n10 4 8 7 3\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02923", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N squares arranged in a row from left to right.\n\nThe height of the i-th square from the left is H_i.\n\nYou will land on a square of your choice, then repeat moving to the adjacent square on the right as long as the height of the next square is not greater than that of the current square.\n\nFind the maximum number of times you can move.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq H_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nH_1 H_2 ... H_N\n\nOutput\n\nPrint the maximum number of times you can move.\n\nSample Input 1\n\n5\n10 4 8 7 3\n\nSample Output 1\n\n2\n\nBy landing on the third square from the left, you can move to the right twice.\n\nSample Input 2\n\n7\n4 4 5 6 6 5 5\n\nSample Output 2\n\n3\n\nBy landing on the fourth square from the left, you can move to the right three times.\n\nSample Input 3\n\n4\n1 2 3 4\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 566, "cpu_time_ms": 594, "memory_kb": 640}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s537573464", "group_id": "codeNet:p02923", "input_text": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint main()\n{\n    int n;\n    cin >> n;\n    int ans = 0;\n    int curLen = 0;\n    int prev = (int) 1e9 + 5;\n    for (int i = 0; i < n; i++)\n    {\n        int x;\n        cin >> x;\n        if (x <= prev)\n        {\n            curLen++;\n        }\n        else\n        {\n            curLen = 1;\n        }\n        prev = x;\n        ans = max(ans, curLen);\n    }\n    cout << ans - 1 << endl;\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1567365221, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02923.html", "problem_id": "p02923", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02923/input.txt", "sample_output_relpath": "derived/input_output/data/p02923/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02923/C++/s537573464.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s537573464", "user_id": "u828346292"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint main()\n{\n    int n;\n    cin >> n;\n    int ans = 0;\n    int curLen = 0;\n    int prev = (int) 1e9 + 5;\n    for (int i = 0; i < n; i++)\n    {\n        int x;\n        cin >> x;\n        if (x <= prev)\n        {\n            curLen++;\n        }\n        else\n        {\n            curLen = 1;\n        }\n        prev = x;\n        ans = max(ans, curLen);\n    }\n    cout << ans - 1 << endl;\n    return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N squares arranged in a row from left to right.\n\nThe height of the i-th square from the left is H_i.\n\nYou will land on a square of your choice, then repeat moving to the adjacent square on the right as long as the height of the next square is not greater than that of the current square.\n\nFind the maximum number of times you can move.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq H_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nH_1 H_2 ... H_N\n\nOutput\n\nPrint the maximum number of times you can move.\n\nSample Input 1\n\n5\n10 4 8 7 3\n\nSample Output 1\n\n2\n\nBy landing on the third square from the left, you can move to the right twice.\n\nSample Input 2\n\n7\n4 4 5 6 6 5 5\n\nSample Output 2\n\n3\n\nBy landing on the fourth square from the left, you can move to the right three times.\n\nSample Input 3\n\n4\n1 2 3 4\n\nSample Output 3\n\n0", "sample_input": "5\n10 4 8 7 3\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02923", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N squares arranged in a row from left to right.\n\nThe height of the i-th square from the left is H_i.\n\nYou will land on a square of your choice, then repeat moving to the adjacent square on the right as long as the height of the next square is not greater than that of the current square.\n\nFind the maximum number of times you can move.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq H_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nH_1 H_2 ... H_N\n\nOutput\n\nPrint the maximum number of times you can move.\n\nSample Input 1\n\n5\n10 4 8 7 3\n\nSample Output 1\n\n2\n\nBy landing on the third square from the left, you can move to the right twice.\n\nSample Input 2\n\n7\n4 4 5 6 6 5 5\n\nSample Output 2\n\n3\n\nBy landing on the fourth square from the left, you can move to the right three times.\n\nSample Input 3\n\n4\n1 2 3 4\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 447, "cpu_time_ms": 57, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s923688279", "group_id": "codeNet:p02924", "input_text": "/*input\n*/\n#include <bits/stdc++.h>\nusing namespace std;\n \n#define all(a) a.begin(), a.end()\n#define ff first\n#define ss second\n#define pb push_back\n \nusing ll = long long;\nusing pii = pair<int, int>;\n \ntemplate<typename T> using V = vector<T>;\n\nint main() {\n\tios::sync_with_stdio(false);cin.tie(nullptr);\n\tll n; cin >> n;\n\t--n;\n\tcout << (n*(n+1))/2;\n}", "language": "C++", "metadata": {"date": 1567366550, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02924.html", "problem_id": "p02924", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02924/input.txt", "sample_output_relpath": "derived/input_output/data/p02924/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02924/C++/s923688279.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s923688279", "user_id": "u704703586"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "/*input\n*/\n#include <bits/stdc++.h>\nusing namespace std;\n \n#define all(a) a.begin(), a.end()\n#define ff first\n#define ss second\n#define pb push_back\n \nusing ll = long long;\nusing pii = pair<int, int>;\n \ntemplate<typename T> using V = vector<T>;\n\nint main() {\n\tios::sync_with_stdio(false);cin.tie(nullptr);\n\tll n; cin >> n;\n\t--n;\n\tcout << (n*(n+1))/2;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nFor an integer N, we will choose a permutation \\{P_1, P_2, ..., P_N\\} of \\{1, 2, ..., N\\}.\n\nThen, for each i=1,2,...,N, let M_i be the remainder when i is divided by P_i.\n\nFind the maximum possible value of M_1 + M_2 + \\cdots + M_N.\n\nConstraints\n\nN is an integer satisfying 1 \\leq N \\leq 10^9.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the maximum possible value of M_1 + M_2 + \\cdots + M_N.\n\nSample Input 1\n\n2\n\nSample Output 1\n\n1\n\nWhen the permutation \\{P_1, P_2\\} = \\{2, 1\\} is chosen, M_1 + M_2 = 1 + 0 = 1.\n\nSample Input 2\n\n13\n\nSample Output 2\n\n78\n\nSample Input 3\n\n1\n\nSample Output 3\n\n0", "sample_input": "2\n"}, "reference_outputs": ["1\n"], "source_document_id": "p02924", "source_text": "Score : 400 points\n\nProblem Statement\n\nFor an integer N, we will choose a permutation \\{P_1, P_2, ..., P_N\\} of \\{1, 2, ..., N\\}.\n\nThen, for each i=1,2,...,N, let M_i be the remainder when i is divided by P_i.\n\nFind the maximum possible value of M_1 + M_2 + \\cdots + M_N.\n\nConstraints\n\nN is an integer satisfying 1 \\leq N \\leq 10^9.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the maximum possible value of M_1 + M_2 + \\cdots + M_N.\n\nSample Input 1\n\n2\n\nSample Output 1\n\n1\n\nWhen the permutation \\{P_1, P_2\\} = \\{2, 1\\} is chosen, M_1 + M_2 = 1 + 0 = 1.\n\nSample Input 2\n\n13\n\nSample Output 2\n\n78\n\nSample Input 3\n\n1\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 352, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s945180166", "group_id": "codeNet:p02925", "input_text": "#include<bits/stdc++.h>\n#define N (1005)\n#define ll long long\n#define debug(x) cerr<<#x<<\" : \"<<x<<endl\n#define CM cerr<<(&MOP2-&MOP1)/1024.0/1024.0<<endl\nusing namespace std;\ntemplate <class T> inline T Min(T x, T y) {\n\treturn x<y?x:y;\n}\ntemplate <class T> inline T Max(T x, T y) {\n\treturn x>y?x:y;\n}\nbool MOP1;\nint n,A[N][N],p[N];\nint read() {\n\tint v=0;\n\tchar c;\n\tfor(c=getchar(); c<48; c=getchar());\n\tfor(; c>47; c=getchar())v=(v<<3)+(v<<1)+(c^48);\n\treturn v;\n}\nint cnt=0;\nint tot=0;\nbool mark[N];\nbool flag;\nbool MOP2;\nint q[2][N];\nbool cur;\nint main() {\n\tn=read();\n\tfor(int i=1; i<=n; i++) {\n\t\tp[i]=1;\n\t\tfor(int j=1; j<n; j++)A[i][j]=read();\n\t}\n\tcur=1;\n\tfor(int i=1;i<=n;i++)q[cur][i]=A[i][1];\n\tq[cur][0]=n;\n\twhile(tot<n*(n-1)/2) {\n\t\tflag=0;\n\t\tcur^=1;\n\t\tq[cur][0]=0;\n\t\tcnt++;\n\t\tmemset(mark,0,sizeof mark);\n\t\tfor(register int i=1; i<=q[cur^1][0]; i++) {\n\t\t\tint now=q[cur^1][i];\n\t\t\tint to=A[now][p[now]];\n\t\t\tif(p[now]==n||mark[now]||mark[to])continue;\n\t\t\tif(A[to][p[to]]==now){\n\t\t\t\tmark[now]=1,mark[to]=1,p[now]++,p[to]++,tot++,flag=1,q[cur][++q[cur][0]]=now,q[cur][++q[cur][0]]=to;\n\t\t\t}\n\t\t}\n\t\tif(!flag) {\n\t\t\tputs(\"-1\");\n\t\t\treturn 0;\n\t\t}\n\t}\n\tprintf(\"%d\\n\",cnt);\n\treturn 0;\n}\n\n\n\n\n", "language": "C++", "metadata": {"date": 1567370811, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02925.html", "problem_id": "p02925", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02925/input.txt", "sample_output_relpath": "derived/input_output/data/p02925/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02925/C++/s945180166.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s945180166", "user_id": "u392797842"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include<bits/stdc++.h>\n#define N (1005)\n#define ll long long\n#define debug(x) cerr<<#x<<\" : \"<<x<<endl\n#define CM cerr<<(&MOP2-&MOP1)/1024.0/1024.0<<endl\nusing namespace std;\ntemplate <class T> inline T Min(T x, T y) {\n\treturn x<y?x:y;\n}\ntemplate <class T> inline T Max(T x, T y) {\n\treturn x>y?x:y;\n}\nbool MOP1;\nint n,A[N][N],p[N];\nint read() {\n\tint v=0;\n\tchar c;\n\tfor(c=getchar(); c<48; c=getchar());\n\tfor(; c>47; c=getchar())v=(v<<3)+(v<<1)+(c^48);\n\treturn v;\n}\nint cnt=0;\nint tot=0;\nbool mark[N];\nbool flag;\nbool MOP2;\nint q[2][N];\nbool cur;\nint main() {\n\tn=read();\n\tfor(int i=1; i<=n; i++) {\n\t\tp[i]=1;\n\t\tfor(int j=1; j<n; j++)A[i][j]=read();\n\t}\n\tcur=1;\n\tfor(int i=1;i<=n;i++)q[cur][i]=A[i][1];\n\tq[cur][0]=n;\n\twhile(tot<n*(n-1)/2) {\n\t\tflag=0;\n\t\tcur^=1;\n\t\tq[cur][0]=0;\n\t\tcnt++;\n\t\tmemset(mark,0,sizeof mark);\n\t\tfor(register int i=1; i<=q[cur^1][0]; i++) {\n\t\t\tint now=q[cur^1][i];\n\t\t\tint to=A[now][p[now]];\n\t\t\tif(p[now]==n||mark[now]||mark[to])continue;\n\t\t\tif(A[to][p[to]]==now){\n\t\t\t\tmark[now]=1,mark[to]=1,p[now]++,p[to]++,tot++,flag=1,q[cur][++q[cur][0]]=now,q[cur][++q[cur][0]]=to;\n\t\t\t}\n\t\t}\n\t\tif(!flag) {\n\t\t\tputs(\"-1\");\n\t\t\treturn 0;\n\t\t}\n\t}\n\tprintf(\"%d\\n\",cnt);\n\treturn 0;\n}\n\n\n\n\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nN players will participate in a tennis tournament. We will call them Player 1, Player 2, \\ldots, Player N.\n\nThe tournament is round-robin format, and there will be N(N-1)/2 matches in total.\nIs it possible to schedule these matches so that all of the following conditions are satisfied? If the answer is yes, also find the minimum number of days required.\n\nEach player plays at most one matches in a day.\n\nEach player i (1 \\leq i \\leq N) plays one match against Player A_{i, 1}, A_{i, 2}, \\ldots, A_{i, N-1} in this order.\n\nConstraints\n\n3 \\leq N \\leq 1000\n\n1 \\leq A_{i, j} \\leq N\n\nA_{i, j} \\neq i\n\nA_{i, 1}, A_{i, 2}, \\ldots, A_{i, N-1} are all different.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_{1, 1} A_{1, 2} \\ldots A_{1, N-1}\nA_{2, 1} A_{2, 2} \\ldots A_{2, N-1}\n:\nA_{N, 1} A_{N, 2} \\ldots A_{N, N-1}\n\nOutput\n\nIf it is possible to schedule all the matches so that all of the conditions are satisfied, print the minimum number of days required; if it is impossible, print -1.\n\nSample Input 1\n\n3\n2 3\n1 3\n1 2\n\nSample Output 1\n\n3\n\nAll the conditions can be satisfied if the matches are scheduled for three days as follows:\n\nDay 1: Player 1 vs Player 2\n\nDay 2: Player 1 vs Player 3\n\nDay 3: Player 2 vs Player 3\n\nThis is the minimum number of days required.\n\nSample Input 2\n\n4\n2 3 4\n1 3 4\n4 1 2\n3 1 2\n\nSample Output 2\n\n4\n\nAll the conditions can be satisfied if the matches are scheduled for four days as follows:\n\nDay 1: Player 1 vs Player 2, Player 3 vs Player 4\n\nDay 2: Player 1 vs Player 3\n\nDay 3: Player 1 vs Player 4, Player 2 vs Player 3\n\nDay 4: Player 2 vs Player 4\n\nThis is the minimum number of days required.\n\nSample Input 3\n\n3\n2 3\n3 1\n1 2\n\nSample Output 3\n\n-1\n\nAny scheduling of the matches violates some condition.", "sample_input": "3\n2 3\n1 3\n1 2\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02925", "source_text": "Score : 500 points\n\nProblem Statement\n\nN players will participate in a tennis tournament. We will call them Player 1, Player 2, \\ldots, Player N.\n\nThe tournament is round-robin format, and there will be N(N-1)/2 matches in total.\nIs it possible to schedule these matches so that all of the following conditions are satisfied? If the answer is yes, also find the minimum number of days required.\n\nEach player plays at most one matches in a day.\n\nEach player i (1 \\leq i \\leq N) plays one match against Player A_{i, 1}, A_{i, 2}, \\ldots, A_{i, N-1} in this order.\n\nConstraints\n\n3 \\leq N \\leq 1000\n\n1 \\leq A_{i, j} \\leq N\n\nA_{i, j} \\neq i\n\nA_{i, 1}, A_{i, 2}, \\ldots, A_{i, N-1} are all different.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_{1, 1} A_{1, 2} \\ldots A_{1, N-1}\nA_{2, 1} A_{2, 2} \\ldots A_{2, N-1}\n:\nA_{N, 1} A_{N, 2} \\ldots A_{N, N-1}\n\nOutput\n\nIf it is possible to schedule all the matches so that all of the conditions are satisfied, print the minimum number of days required; if it is impossible, print -1.\n\nSample Input 1\n\n3\n2 3\n1 3\n1 2\n\nSample Output 1\n\n3\n\nAll the conditions can be satisfied if the matches are scheduled for three days as follows:\n\nDay 1: Player 1 vs Player 2\n\nDay 2: Player 1 vs Player 3\n\nDay 3: Player 2 vs Player 3\n\nThis is the minimum number of days required.\n\nSample Input 2\n\n4\n2 3 4\n1 3 4\n4 1 2\n3 1 2\n\nSample Output 2\n\n4\n\nAll the conditions can be satisfied if the matches are scheduled for four days as follows:\n\nDay 1: Player 1 vs Player 2, Player 3 vs Player 4\n\nDay 2: Player 1 vs Player 3\n\nDay 3: Player 1 vs Player 4, Player 2 vs Player 3\n\nDay 4: Player 2 vs Player 4\n\nThis is the minimum number of days required.\n\nSample Input 3\n\n3\n2 3\n3 1\n1 2\n\nSample Output 3\n\n-1\n\nAny scheduling of the matches violates some condition.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1182, "cpu_time_ms": 62, "memory_kb": 4224}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s281759389", "group_id": "codeNet:p02926", "input_text": "#include <bits/stdc++.h>\n\n#define long long long int\n\nusing namespace std;\n\n// @author: pashka\n\nint main() {\n    ios::sync_with_stdio(false);\n\n    int n;\n    cin >> n;\n    vector<pair<double, pair<double, double>>> a(2 * n);\n    for (int i = 0; i < n; i++) {\n        cin >> a[i].second.first >> a[i].second.second;\n        a[i + n].second.first = -a[i].second.first;\n        a[i + n].second.second = -a[i].second.second;\n    }\n    for (int i = 0; i < 2 * n; i++) {\n        a[i].first = atan2(a[i].second.second, a[i].second.first);\n    }\n\n    sort(a.begin(), a.end());\n\n    double y0 = 0;\n    double x0 = 0;\n    for (int i = 0; i < 2 * n; i++) {\n        double x = a[i].second.first;\n        double y = a[i].second.second;\n        if (y > 0 || (y == 0 && x < 0)) {\n            x0 += x;\n            y0 += y;\n        }\n    }\n    \n    double res = 0;\n\n    for (int i = 0; i < 2 * n; i++) {\n        double x = a[i].second.first;\n        double y = a[i].second.second;\n        x0 += x;\n        y0 += y;\n        res = max(res, hypot(x0, y0));        \n    }\n    cout << setprecision(20) << res;\n\n    return 0;\n}", "language": "C++", "metadata": {"date": 1572754027, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02926.html", "problem_id": "p02926", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02926/input.txt", "sample_output_relpath": "derived/input_output/data/p02926/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02926/C++/s281759389.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s281759389", "user_id": "u136509923"}, "prompt_components": {"gold_output": "10.000000000000000000000000000000000000000000000000\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\n#define long long long int\n\nusing namespace std;\n\n// @author: pashka\n\nint main() {\n    ios::sync_with_stdio(false);\n\n    int n;\n    cin >> n;\n    vector<pair<double, pair<double, double>>> a(2 * n);\n    for (int i = 0; i < n; i++) {\n        cin >> a[i].second.first >> a[i].second.second;\n        a[i + n].second.first = -a[i].second.first;\n        a[i + n].second.second = -a[i].second.second;\n    }\n    for (int i = 0; i < 2 * n; i++) {\n        a[i].first = atan2(a[i].second.second, a[i].second.first);\n    }\n\n    sort(a.begin(), a.end());\n\n    double y0 = 0;\n    double x0 = 0;\n    for (int i = 0; i < 2 * n; i++) {\n        double x = a[i].second.first;\n        double y = a[i].second.second;\n        if (y > 0 || (y == 0 && x < 0)) {\n            x0 += x;\n            y0 += y;\n        }\n    }\n    \n    double res = 0;\n\n    for (int i = 0; i < 2 * n; i++) {\n        double x = a[i].second.first;\n        double y = a[i].second.second;\n        x0 += x;\n        y0 += y;\n        res = max(res, hypot(x0, y0));        \n    }\n    cout << setprecision(20) << res;\n\n    return 0;\n}", "problem_context": "Score: 600 points\n\nProblem Statement\n\nE869120 is initially standing at the origin (0, 0) in a two-dimensional plane.\n\nHe has N engines, which can be used as follows:\n\nWhen E869120 uses the i-th engine, his X- and Y-coordinate change by x_i and y_i, respectively. In other words, if E869120 uses the i-th engine from coordinates (X, Y), he will move to the coordinates (X + x_i, Y + y_i).\n\nE869120 can use these engines in any order, but each engine can be used at most once. He may also choose not to use some of the engines.\n\nHe wants to go as far as possible from the origin.\nLet (X, Y) be his final coordinates. Find the maximum possible value of \\sqrt{X^2 + Y^2}, the distance from the origin.\n\nConstraints\n\n1 \\leq N \\leq 100\n\n-1 \\ 000 \\ 000 \\leq x_i \\leq 1 \\ 000 \\ 000\n\n-1 \\ 000 \\ 000 \\leq y_i \\leq 1 \\ 000 \\ 000\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nx_1 y_1\nx_2 y_2\n: :\nx_N y_N\n\nOutput\n\nPrint the maximum possible final distance from the origin, as a real value.\nYour output is considered correct when the relative or absolute error from the true answer is at most 10^{-10}.\n\nSample Input 1\n\n3\n0 10\n5 -5\n-5 -5\n\nSample Output 1\n\n10.000000000000000000000000000000000000000000000000\n\nThe final distance from the origin can be 10 if we use the engines in one of the following three ways:\n\nUse Engine 1 to move to (0, 10).\n\nUse Engine 2 to move to (5, -5), and then use Engine 3 to move to (0, -10).\n\nUse Engine 3 to move to (-5, -5), and then use Engine 2 to move to (0, -10).\n\nThe distance cannot be greater than 10, so the maximum possible distance is 10.\n\nSample Input 2\n\n5\n1 1\n1 0\n0 1\n-1 0\n0 -1\n\nSample Output 2\n\n2.828427124746190097603377448419396157139343750753\n\nThe maximum possible final distance is 2 \\sqrt{2} = 2.82842....\nOne of the ways to achieve it is:\n\nUse Engine 1 to move to (1, 1), and then use Engine 2 to move to (2, 1), and finally use Engine 3 to move to (2, 2).\n\nSample Input 3\n\n5\n1 1\n2 2\n3 3\n4 4\n5 5\n\nSample Output 3\n\n21.213203435596425732025330863145471178545078130654\n\nIf we use all the engines in the order 1 \\rightarrow 2 \\rightarrow 3 \\rightarrow 4 \\rightarrow 5, we will end up at (15, 15), with the distance 15 \\sqrt{2} = 21.2132... from the origin.\n\nSample Input 4\n\n3\n0 0\n0 1\n1 0\n\nSample Output 4\n\n1.414213562373095048801688724209698078569671875376\n\nThere can be useless engines with (x_i, y_i) = (0, 0).\n\nSample Input 5\n\n1\n90447 91000\n\nSample Output 5\n\n128303.000000000000000000000000000000000000000000000000\n\nNote that there can be only one engine.\n\nSample Input 6\n\n2\n96000 -72000\n-72000 54000\n\nSample Output 6\n\n120000.000000000000000000000000000000000000000000000000\n\nThere can be only two engines, too.\n\nSample Input 7\n\n10\n1 2\n3 4\n5 6\n7 8\n9 10\n11 12\n13 14\n15 16\n17 18\n19 20\n\nSample Output 7\n\n148.660687473185055226120082139313966514489855137208", "sample_input": "3\n0 10\n5 -5\n-5 -5\n"}, "reference_outputs": ["10.000000000000000000000000000000000000000000000000\n"], "source_document_id": "p02926", "source_text": "Score: 600 points\n\nProblem Statement\n\nE869120 is initially standing at the origin (0, 0) in a two-dimensional plane.\n\nHe has N engines, which can be used as follows:\n\nWhen E869120 uses the i-th engine, his X- and Y-coordinate change by x_i and y_i, respectively. In other words, if E869120 uses the i-th engine from coordinates (X, Y), he will move to the coordinates (X + x_i, Y + y_i).\n\nE869120 can use these engines in any order, but each engine can be used at most once. He may also choose not to use some of the engines.\n\nHe wants to go as far as possible from the origin.\nLet (X, Y) be his final coordinates. Find the maximum possible value of \\sqrt{X^2 + Y^2}, the distance from the origin.\n\nConstraints\n\n1 \\leq N \\leq 100\n\n-1 \\ 000 \\ 000 \\leq x_i \\leq 1 \\ 000 \\ 000\n\n-1 \\ 000 \\ 000 \\leq y_i \\leq 1 \\ 000 \\ 000\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nx_1 y_1\nx_2 y_2\n: :\nx_N y_N\n\nOutput\n\nPrint the maximum possible final distance from the origin, as a real value.\nYour output is considered correct when the relative or absolute error from the true answer is at most 10^{-10}.\n\nSample Input 1\n\n3\n0 10\n5 -5\n-5 -5\n\nSample Output 1\n\n10.000000000000000000000000000000000000000000000000\n\nThe final distance from the origin can be 10 if we use the engines in one of the following three ways:\n\nUse Engine 1 to move to (0, 10).\n\nUse Engine 2 to move to (5, -5), and then use Engine 3 to move to (0, -10).\n\nUse Engine 3 to move to (-5, -5), and then use Engine 2 to move to (0, -10).\n\nThe distance cannot be greater than 10, so the maximum possible distance is 10.\n\nSample Input 2\n\n5\n1 1\n1 0\n0 1\n-1 0\n0 -1\n\nSample Output 2\n\n2.828427124746190097603377448419396157139343750753\n\nThe maximum possible final distance is 2 \\sqrt{2} = 2.82842....\nOne of the ways to achieve it is:\n\nUse Engine 1 to move to (1, 1), and then use Engine 2 to move to (2, 1), and finally use Engine 3 to move to (2, 2).\n\nSample Input 3\n\n5\n1 1\n2 2\n3 3\n4 4\n5 5\n\nSample Output 3\n\n21.213203435596425732025330863145471178545078130654\n\nIf we use all the engines in the order 1 \\rightarrow 2 \\rightarrow 3 \\rightarrow 4 \\rightarrow 5, we will end up at (15, 15), with the distance 15 \\sqrt{2} = 21.2132... from the origin.\n\nSample Input 4\n\n3\n0 0\n0 1\n1 0\n\nSample Output 4\n\n1.414213562373095048801688724209698078569671875376\n\nThere can be useless engines with (x_i, y_i) = (0, 0).\n\nSample Input 5\n\n1\n90447 91000\n\nSample Output 5\n\n128303.000000000000000000000000000000000000000000000000\n\nNote that there can be only one engine.\n\nSample Input 6\n\n2\n96000 -72000\n-72000 54000\n\nSample Output 6\n\n120000.000000000000000000000000000000000000000000000000\n\nThere can be only two engines, too.\n\nSample Input 7\n\n10\n1 2\n3 4\n5 6\n7 8\n9 10\n11 12\n13 14\n15 16\n17 18\n19 20\n\nSample Output 7\n\n148.660687473185055226120082139313966514489855137208", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1104, "cpu_time_ms": 2, "memory_kb": 384}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s949569373", "group_id": "codeNet:p02926", "input_text": "#include <iostream>\n#include <iomanip>\n#include <cmath>\n\nusing namespace std;\n\nint N;\nlong long v[8][2];\nint st[8];\n\ndouble res;\n\nvoid CheckSol()\n{\n    long long x = 0, y = 0;\n\n    for(int i = 0; i <= 8; i++)\n        if(st[i] == 1)\n            x += v[i][0], y += v[i][1];\n\n    res = max(res, sqrt(1LL * x * x + y * y));\n}\n\nvoid bk(int p)\n{\n    if(p == 8)\n        {\n            CheckSol();\n            return ;\n        }\n\n    for(int i = 0; i <= 1; i++)\n    {\n        st[p] = i;\n        bk(p + 1);\n    }\n}\n\nint main()\n{\n    cin >> N;\n\n    for(int i = 1; i <= N; i++)\n    {\n        long long x, y; cin >> x >> y;\n        int index;\n\n        if(x > 0 && y > 0) index = 0;\n        else if(x > 0 && y < 0) index = 1;\n        else if(x < 0 && y > 0) index = 2;\n        else if(x < 0 && y < 0) index = 3;\n        else if(x == 0 && y > 0) index = 4;\n        else if(x == 0 && y < 0) index = 5;\n        else if(x > 0 && y == 0) index = 6;\n        else if(x < 0 && y == 0) index = 7;\n\n        v[index][0] += x;\n        v[index][1] += y;\n    }\n\n    bk(0);\n\n    cout << fixed << setprecision(45) << res << '\\n';\n\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1567369238, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02926.html", "problem_id": "p02926", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02926/input.txt", "sample_output_relpath": "derived/input_output/data/p02926/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02926/C++/s949569373.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s949569373", "user_id": "u323394394"}, "prompt_components": {"gold_output": "10.000000000000000000000000000000000000000000000000\n", "input_to_evaluate": "#include <iostream>\n#include <iomanip>\n#include <cmath>\n\nusing namespace std;\n\nint N;\nlong long v[8][2];\nint st[8];\n\ndouble res;\n\nvoid CheckSol()\n{\n    long long x = 0, y = 0;\n\n    for(int i = 0; i <= 8; i++)\n        if(st[i] == 1)\n            x += v[i][0], y += v[i][1];\n\n    res = max(res, sqrt(1LL * x * x + y * y));\n}\n\nvoid bk(int p)\n{\n    if(p == 8)\n        {\n            CheckSol();\n            return ;\n        }\n\n    for(int i = 0; i <= 1; i++)\n    {\n        st[p] = i;\n        bk(p + 1);\n    }\n}\n\nint main()\n{\n    cin >> N;\n\n    for(int i = 1; i <= N; i++)\n    {\n        long long x, y; cin >> x >> y;\n        int index;\n\n        if(x > 0 && y > 0) index = 0;\n        else if(x > 0 && y < 0) index = 1;\n        else if(x < 0 && y > 0) index = 2;\n        else if(x < 0 && y < 0) index = 3;\n        else if(x == 0 && y > 0) index = 4;\n        else if(x == 0 && y < 0) index = 5;\n        else if(x > 0 && y == 0) index = 6;\n        else if(x < 0 && y == 0) index = 7;\n\n        v[index][0] += x;\n        v[index][1] += y;\n    }\n\n    bk(0);\n\n    cout << fixed << setprecision(45) << res << '\\n';\n\n    return 0;\n}\n", "problem_context": "Score: 600 points\n\nProblem Statement\n\nE869120 is initially standing at the origin (0, 0) in a two-dimensional plane.\n\nHe has N engines, which can be used as follows:\n\nWhen E869120 uses the i-th engine, his X- and Y-coordinate change by x_i and y_i, respectively. In other words, if E869120 uses the i-th engine from coordinates (X, Y), he will move to the coordinates (X + x_i, Y + y_i).\n\nE869120 can use these engines in any order, but each engine can be used at most once. He may also choose not to use some of the engines.\n\nHe wants to go as far as possible from the origin.\nLet (X, Y) be his final coordinates. Find the maximum possible value of \\sqrt{X^2 + Y^2}, the distance from the origin.\n\nConstraints\n\n1 \\leq N \\leq 100\n\n-1 \\ 000 \\ 000 \\leq x_i \\leq 1 \\ 000 \\ 000\n\n-1 \\ 000 \\ 000 \\leq y_i \\leq 1 \\ 000 \\ 000\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nx_1 y_1\nx_2 y_2\n: :\nx_N y_N\n\nOutput\n\nPrint the maximum possible final distance from the origin, as a real value.\nYour output is considered correct when the relative or absolute error from the true answer is at most 10^{-10}.\n\nSample Input 1\n\n3\n0 10\n5 -5\n-5 -5\n\nSample Output 1\n\n10.000000000000000000000000000000000000000000000000\n\nThe final distance from the origin can be 10 if we use the engines in one of the following three ways:\n\nUse Engine 1 to move to (0, 10).\n\nUse Engine 2 to move to (5, -5), and then use Engine 3 to move to (0, -10).\n\nUse Engine 3 to move to (-5, -5), and then use Engine 2 to move to (0, -10).\n\nThe distance cannot be greater than 10, so the maximum possible distance is 10.\n\nSample Input 2\n\n5\n1 1\n1 0\n0 1\n-1 0\n0 -1\n\nSample Output 2\n\n2.828427124746190097603377448419396157139343750753\n\nThe maximum possible final distance is 2 \\sqrt{2} = 2.82842....\nOne of the ways to achieve it is:\n\nUse Engine 1 to move to (1, 1), and then use Engine 2 to move to (2, 1), and finally use Engine 3 to move to (2, 2).\n\nSample Input 3\n\n5\n1 1\n2 2\n3 3\n4 4\n5 5\n\nSample Output 3\n\n21.213203435596425732025330863145471178545078130654\n\nIf we use all the engines in the order 1 \\rightarrow 2 \\rightarrow 3 \\rightarrow 4 \\rightarrow 5, we will end up at (15, 15), with the distance 15 \\sqrt{2} = 21.2132... from the origin.\n\nSample Input 4\n\n3\n0 0\n0 1\n1 0\n\nSample Output 4\n\n1.414213562373095048801688724209698078569671875376\n\nThere can be useless engines with (x_i, y_i) = (0, 0).\n\nSample Input 5\n\n1\n90447 91000\n\nSample Output 5\n\n128303.000000000000000000000000000000000000000000000000\n\nNote that there can be only one engine.\n\nSample Input 6\n\n2\n96000 -72000\n-72000 54000\n\nSample Output 6\n\n120000.000000000000000000000000000000000000000000000000\n\nThere can be only two engines, too.\n\nSample Input 7\n\n10\n1 2\n3 4\n5 6\n7 8\n9 10\n11 12\n13 14\n15 16\n17 18\n19 20\n\nSample Output 7\n\n148.660687473185055226120082139313966514489855137208", "sample_input": "3\n0 10\n5 -5\n-5 -5\n"}, "reference_outputs": ["10.000000000000000000000000000000000000000000000000\n"], "source_document_id": "p02926", "source_text": "Score: 600 points\n\nProblem Statement\n\nE869120 is initially standing at the origin (0, 0) in a two-dimensional plane.\n\nHe has N engines, which can be used as follows:\n\nWhen E869120 uses the i-th engine, his X- and Y-coordinate change by x_i and y_i, respectively. In other words, if E869120 uses the i-th engine from coordinates (X, Y), he will move to the coordinates (X + x_i, Y + y_i).\n\nE869120 can use these engines in any order, but each engine can be used at most once. He may also choose not to use some of the engines.\n\nHe wants to go as far as possible from the origin.\nLet (X, Y) be his final coordinates. Find the maximum possible value of \\sqrt{X^2 + Y^2}, the distance from the origin.\n\nConstraints\n\n1 \\leq N \\leq 100\n\n-1 \\ 000 \\ 000 \\leq x_i \\leq 1 \\ 000 \\ 000\n\n-1 \\ 000 \\ 000 \\leq y_i \\leq 1 \\ 000 \\ 000\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nx_1 y_1\nx_2 y_2\n: :\nx_N y_N\n\nOutput\n\nPrint the maximum possible final distance from the origin, as a real value.\nYour output is considered correct when the relative or absolute error from the true answer is at most 10^{-10}.\n\nSample Input 1\n\n3\n0 10\n5 -5\n-5 -5\n\nSample Output 1\n\n10.000000000000000000000000000000000000000000000000\n\nThe final distance from the origin can be 10 if we use the engines in one of the following three ways:\n\nUse Engine 1 to move to (0, 10).\n\nUse Engine 2 to move to (5, -5), and then use Engine 3 to move to (0, -10).\n\nUse Engine 3 to move to (-5, -5), and then use Engine 2 to move to (0, -10).\n\nThe distance cannot be greater than 10, so the maximum possible distance is 10.\n\nSample Input 2\n\n5\n1 1\n1 0\n0 1\n-1 0\n0 -1\n\nSample Output 2\n\n2.828427124746190097603377448419396157139343750753\n\nThe maximum possible final distance is 2 \\sqrt{2} = 2.82842....\nOne of the ways to achieve it is:\n\nUse Engine 1 to move to (1, 1), and then use Engine 2 to move to (2, 1), and finally use Engine 3 to move to (2, 2).\n\nSample Input 3\n\n5\n1 1\n2 2\n3 3\n4 4\n5 5\n\nSample Output 3\n\n21.213203435596425732025330863145471178545078130654\n\nIf we use all the engines in the order 1 \\rightarrow 2 \\rightarrow 3 \\rightarrow 4 \\rightarrow 5, we will end up at (15, 15), with the distance 15 \\sqrt{2} = 21.2132... from the origin.\n\nSample Input 4\n\n3\n0 0\n0 1\n1 0\n\nSample Output 4\n\n1.414213562373095048801688724209698078569671875376\n\nThere can be useless engines with (x_i, y_i) = (0, 0).\n\nSample Input 5\n\n1\n90447 91000\n\nSample Output 5\n\n128303.000000000000000000000000000000000000000000000000\n\nNote that there can be only one engine.\n\nSample Input 6\n\n2\n96000 -72000\n-72000 54000\n\nSample Output 6\n\n120000.000000000000000000000000000000000000000000000000\n\nThere can be only two engines, too.\n\nSample Input 7\n\n10\n1 2\n3 4\n5 6\n7 8\n9 10\n11 12\n13 14\n15 16\n17 18\n19 20\n\nSample Output 7\n\n148.660687473185055226120082139313966514489855137208", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1117, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s875689067", "group_id": "codeNet:p02928", "input_text": "// #define _GLIBCXX_DEBUG // for STL debug (optional)\n#include <iostream>\n#include <iomanip>\n#include <cstdio>\n#include <string>\n#include <cstring>\n#include <deque>\n#include <list>\n#include <queue>\n#include <stack>\n#include <vector>\n#include <utility>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <complex>\n#include <cmath>\n#include <limits>\n#include <cfloat>\n#include <climits>\n#include <ctime>\n#include <cassert>\n#include <numeric>\n#include <fstream>\n#include <functional>\n#include <bitset>\nusing namespace std;\nusing ll = long long int;\nusing int64 = long long int;\n \ntemplate<typename T> void chmax(T &a, T b) {a = max(a, b);}\ntemplate<typename T> void chmin(T &a, T b) {a = min(a, b);}\ntemplate<typename T> void chadd(T &a, T b) {a = a + b;}\n \nint dx[] = {0, 0, 1, -1};\nint dy[] = {1, -1, 0, 0};\nconst ll INF = 1001001001001001LL;\nconst ll MOD = 1000000007LL;\n\n// ModInt begin\n\nusing ll = long long;\ntemplate<ll mod>\nstruct ModInt {\n    ll v;\n    ll mod_pow(ll x, ll n) const {\n        return (!n) ? 1 : (mod_pow((x*x)%mod,n/2) * ((n&1)?x:1)) % mod;\n    }\n    ModInt(ll a = 0) : v((a %= mod) < 0 ? a + mod : a) {}\n    ModInt operator+ ( const ModInt& b ) const {\n        return (v + b.v >= mod ? ModInt(v + b.v - mod) : ModInt(v + b.v));\n    }\n    ModInt operator- () const {\n        return ModInt(-v);\n    }\n    ModInt operator- ( const ModInt& b ) const {\n        return (v - b.v < 0 ? ModInt(v - b.v + mod) : ModInt(v - b.v));\n    }\n    ModInt operator* ( const ModInt& b ) const {return (v * b.v) % mod;}\n    ModInt operator/ ( const ModInt& b ) const {return (v * mod_pow(b.v, mod-2)) % mod;}\n    \n    bool operator== ( const ModInt &b ) const {return v == b.v;}\n    bool operator!= ( const ModInt &b ) const {return !(*this == b); }\n    ModInt& operator+= ( const ModInt &b ) {\n        v += b.v;\n        if(v >= mod) v -= mod;\n        return *this;\n    }\n    ModInt& operator-= ( const ModInt &b ) {\n        v -= b.v;\n        if(v < 0) v += mod;\n        return *this;\n    }\n    ModInt& operator*= ( const ModInt &b ) {\n        (v *= b.v) %= mod;\n        return *this;\n    }\n    ModInt& operator/= ( const ModInt &b ) {\n        (v *= mod_pow(b.v, mod-2)) %= mod;\n        return *this;\n    }\n    ModInt pow(ll x) { return ModInt(mod_pow(v, x)); }\n    // operator int() const { return int(v); }\n    // operator long long int() const { return v; }\n};\n\ntemplate<ll mod>\nostream& operator<< (ostream& out, ModInt<mod> a) {return out << a.v;}\ntemplate<ll mod>\nistream& operator>> (istream& in, ModInt<mod>& a) {\n    in >> a.v;\n    return in;\n}\n\n// ModInt end\nusing mint = ModInt<1000000007>;\n \nint main() {\n    int N, K; cin >> N >> K;\n    vector<int> A(N);\n    for(int i=0; i<N; i++) cin >> A[i];\n\n    mint ans(0);\n    for(int i=0; i<N; i++) {\n        for(int j=i+1; j<N; j++) {\n            if(A[i] == A[j]) continue;\n            if(A[i] < A[j]) ans += mint(K) * mint(K-1) / mint(2);\n            if(A[i] > A[j]) ans += mint(K) * mint(K+1) / mint(2);\n        }\n    }\n    cout << ans << endl;\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1566695270, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02928.html", "problem_id": "p02928", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02928/input.txt", "sample_output_relpath": "derived/input_output/data/p02928/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02928/C++/s875689067.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s875689067", "user_id": "u119460590"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "// #define _GLIBCXX_DEBUG // for STL debug (optional)\n#include <iostream>\n#include <iomanip>\n#include <cstdio>\n#include <string>\n#include <cstring>\n#include <deque>\n#include <list>\n#include <queue>\n#include <stack>\n#include <vector>\n#include <utility>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <complex>\n#include <cmath>\n#include <limits>\n#include <cfloat>\n#include <climits>\n#include <ctime>\n#include <cassert>\n#include <numeric>\n#include <fstream>\n#include <functional>\n#include <bitset>\nusing namespace std;\nusing ll = long long int;\nusing int64 = long long int;\n \ntemplate<typename T> void chmax(T &a, T b) {a = max(a, b);}\ntemplate<typename T> void chmin(T &a, T b) {a = min(a, b);}\ntemplate<typename T> void chadd(T &a, T b) {a = a + b;}\n \nint dx[] = {0, 0, 1, -1};\nint dy[] = {1, -1, 0, 0};\nconst ll INF = 1001001001001001LL;\nconst ll MOD = 1000000007LL;\n\n// ModInt begin\n\nusing ll = long long;\ntemplate<ll mod>\nstruct ModInt {\n    ll v;\n    ll mod_pow(ll x, ll n) const {\n        return (!n) ? 1 : (mod_pow((x*x)%mod,n/2) * ((n&1)?x:1)) % mod;\n    }\n    ModInt(ll a = 0) : v((a %= mod) < 0 ? a + mod : a) {}\n    ModInt operator+ ( const ModInt& b ) const {\n        return (v + b.v >= mod ? ModInt(v + b.v - mod) : ModInt(v + b.v));\n    }\n    ModInt operator- () const {\n        return ModInt(-v);\n    }\n    ModInt operator- ( const ModInt& b ) const {\n        return (v - b.v < 0 ? ModInt(v - b.v + mod) : ModInt(v - b.v));\n    }\n    ModInt operator* ( const ModInt& b ) const {return (v * b.v) % mod;}\n    ModInt operator/ ( const ModInt& b ) const {return (v * mod_pow(b.v, mod-2)) % mod;}\n    \n    bool operator== ( const ModInt &b ) const {return v == b.v;}\n    bool operator!= ( const ModInt &b ) const {return !(*this == b); }\n    ModInt& operator+= ( const ModInt &b ) {\n        v += b.v;\n        if(v >= mod) v -= mod;\n        return *this;\n    }\n    ModInt& operator-= ( const ModInt &b ) {\n        v -= b.v;\n        if(v < 0) v += mod;\n        return *this;\n    }\n    ModInt& operator*= ( const ModInt &b ) {\n        (v *= b.v) %= mod;\n        return *this;\n    }\n    ModInt& operator/= ( const ModInt &b ) {\n        (v *= mod_pow(b.v, mod-2)) %= mod;\n        return *this;\n    }\n    ModInt pow(ll x) { return ModInt(mod_pow(v, x)); }\n    // operator int() const { return int(v); }\n    // operator long long int() const { return v; }\n};\n\ntemplate<ll mod>\nostream& operator<< (ostream& out, ModInt<mod> a) {return out << a.v;}\ntemplate<ll mod>\nistream& operator>> (istream& in, ModInt<mod>& a) {\n    in >> a.v;\n    return in;\n}\n\n// ModInt end\nusing mint = ModInt<1000000007>;\n \nint main() {\n    int N, K; cin >> N >> K;\n    vector<int> A(N);\n    for(int i=0; i<N; i++) cin >> A[i];\n\n    mint ans(0);\n    for(int i=0; i<N; i++) {\n        for(int j=i+1; j<N; j++) {\n            if(A[i] == A[j]) continue;\n            if(A[i] < A[j]) ans += mint(K) * mint(K-1) / mint(2);\n            if(A[i] > A[j]) ans += mint(K) * mint(K+1) / mint(2);\n        }\n    }\n    cout << ans << endl;\n    return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nWe have a sequence of N integers A~=~A_0,~A_1,~...,~A_{N - 1}.\n\nLet B be a sequence of K \\times N integers obtained by concatenating K copies of A. For example, if A~=~1,~3,~2 and K~=~2, B~=~1,~3,~2,~1,~3,~2.\n\nFind the inversion number of B, modulo 10^9 + 7.\n\nHere the inversion number of B is defined as the number of ordered pairs of integers (i,~j)~(0 \\leq i < j \\leq K \\times N - 1) such that B_i > B_j.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 2000\n\n1 \\leq K \\leq 10^9\n\n1 \\leq A_i \\leq 2000\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nA_0 A_1 ... A_{N - 1}\n\nOutput\n\nPrint the inversion number of B, modulo 10^9 + 7.\n\nSample Input 1\n\n2 2\n2 1\n\nSample Output 1\n\n3\n\nIn this case, B~=~2,~1,~2,~1. We have:\n\nB_0 > B_1\n\nB_0 > B_3\n\nB_2 > B_3\n\nThus, the inversion number of B is 3.\n\nSample Input 2\n\n3 5\n1 1 1\n\nSample Output 2\n\n0\n\nA may contain multiple occurrences of the same number.\n\nSample Input 3\n\n10 998244353\n10 9 8 7 5 6 3 4 2 1\n\nSample Output 3\n\n185297239\n\nBe sure to print the output modulo 10^9 + 7.", "sample_input": "2 2\n2 1\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02928", "source_text": "Score : 300 points\n\nProblem Statement\n\nWe have a sequence of N integers A~=~A_0,~A_1,~...,~A_{N - 1}.\n\nLet B be a sequence of K \\times N integers obtained by concatenating K copies of A. For example, if A~=~1,~3,~2 and K~=~2, B~=~1,~3,~2,~1,~3,~2.\n\nFind the inversion number of B, modulo 10^9 + 7.\n\nHere the inversion number of B is defined as the number of ordered pairs of integers (i,~j)~(0 \\leq i < j \\leq K \\times N - 1) such that B_i > B_j.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 2000\n\n1 \\leq K \\leq 10^9\n\n1 \\leq A_i \\leq 2000\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nA_0 A_1 ... A_{N - 1}\n\nOutput\n\nPrint the inversion number of B, modulo 10^9 + 7.\n\nSample Input 1\n\n2 2\n2 1\n\nSample Output 1\n\n3\n\nIn this case, B~=~2,~1,~2,~1. We have:\n\nB_0 > B_1\n\nB_0 > B_3\n\nB_2 > B_3\n\nThus, the inversion number of B is 3.\n\nSample Input 2\n\n3 5\n1 1 1\n\nSample Output 2\n\n0\n\nA may contain multiple occurrences of the same number.\n\nSample Input 3\n\n10 998244353\n10 9 8 7 5 6 3 4 2 1\n\nSample Output 3\n\n185297239\n\nBe sure to print the output modulo 10^9 + 7.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 3027, "cpu_time_ms": 451, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s489650433", "group_id": "codeNet:p02929", "input_text": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<string>\n#include<utility>\n#include<map>\n#include<set>\n#include<queue>\n#include<stack>\n#include<functional>\n#include<math.h>\nusing namespace std;\n#define N (1000000000+7)\n#define INF 1e16\ntypedef long long ll;\ntypedef pair<ll,ll> P;\n \n\n\n\n\n\nint main(void){\n    ll n;\n    string s;\n    cin>>n;\n    cin>>s;\n    ll ans = 1;\n    ll num = 0;\n    for(ll i=0;i<2*n;i++){\n        if((2*n-1-i)%2==1){\n            if(s[i]=='B')num++;\n            else{\n                ans = ans*num;\n                ans = ans%N;\n                num--;\n            }\n        }\n        else{\n            if(s[i]=='W')num++;\n            else{\n                ans = ans*num;\n                ans = ans%N;\n                num--;\n            }\n        }\n    }\n    for(ll i=1;i<=n;i++){\n        ans = ans*i;\n        ans = ans%N;\n    }\n    cout<<ans<<endl;\n    return 0;\n}\n\n", "language": "C++", "metadata": {"date": 1583985275, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02929.html", "problem_id": "p02929", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02929/input.txt", "sample_output_relpath": "derived/input_output/data/p02929/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02929/C++/s489650433.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s489650433", "user_id": "u744305661"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#include<string>\n#include<utility>\n#include<map>\n#include<set>\n#include<queue>\n#include<stack>\n#include<functional>\n#include<math.h>\nusing namespace std;\n#define N (1000000000+7)\n#define INF 1e16\ntypedef long long ll;\ntypedef pair<ll,ll> P;\n \n\n\n\n\n\nint main(void){\n    ll n;\n    string s;\n    cin>>n;\n    cin>>s;\n    ll ans = 1;\n    ll num = 0;\n    for(ll i=0;i<2*n;i++){\n        if((2*n-1-i)%2==1){\n            if(s[i]=='B')num++;\n            else{\n                ans = ans*num;\n                ans = ans%N;\n                num--;\n            }\n        }\n        else{\n            if(s[i]=='W')num++;\n            else{\n                ans = ans*num;\n                ans = ans%N;\n                num--;\n            }\n        }\n    }\n    for(ll i=1;i<=n;i++){\n        ans = ans*i;\n        ans = ans%N;\n    }\n    cout<<ans<<endl;\n    return 0;\n}\n\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nThere are 2N squares arranged from left to right. You are given a string of length 2N representing the color of each of the squares.\n\nThe color of the i-th square from the left is black if the i-th character of S is B, and white if that character is W.\n\nYou will perform the following operation exactly N times: choose two distinct squares, then invert the colors of these squares and the squares between them. Here, to invert the color of a square is to make it white if it is black, and vice versa.\n\nThroughout this process, you cannot choose the same square twice or more. That is, each square has to be chosen exactly once.\n\nFind the number of ways to make all the squares white at the end of the process, modulo 10^9+7.\n\nTwo ways to make the squares white are considered different if and only if there exists i (1 \\leq i \\leq N) such that the pair of the squares chosen in the i-th operation is different.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n|S| = 2N\n\nEach character of S is B or W.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS\n\nOutput\n\nPrint the number of ways to make all the squares white at the end of the process, modulo 10^9+7. If there are no such ways, print 0.\n\nSample Input 1\n\n2\nBWWB\n\nSample Output 1\n\n4\n\nThere are four ways to make all the squares white, as follows:\n\nChoose Squares 1, 3 in the first operation, and choose Squares 2, 4 in the second operation.\n\nChoose Squares 2, 4 in the first operation, and choose Squares 1, 3 in the second operation.\n\nChoose Squares 1, 4 in the first operation, and choose Squares 2, 3 in the second operation.\n\nChoose Squares 2, 3 in the first operation, and choose Squares 1, 4 in the second operation.\n\nSample Input 2\n\n4\nBWBBWWWB\n\nSample Output 2\n\n288\n\nSample Input 3\n\n5\nWWWWWWWWWW\n\nSample Output 3\n\n0", "sample_input": "2\nBWWB\n"}, "reference_outputs": ["4\n"], "source_document_id": "p02929", "source_text": "Score : 500 points\n\nProblem Statement\n\nThere are 2N squares arranged from left to right. You are given a string of length 2N representing the color of each of the squares.\n\nThe color of the i-th square from the left is black if the i-th character of S is B, and white if that character is W.\n\nYou will perform the following operation exactly N times: choose two distinct squares, then invert the colors of these squares and the squares between them. Here, to invert the color of a square is to make it white if it is black, and vice versa.\n\nThroughout this process, you cannot choose the same square twice or more. That is, each square has to be chosen exactly once.\n\nFind the number of ways to make all the squares white at the end of the process, modulo 10^9+7.\n\nTwo ways to make the squares white are considered different if and only if there exists i (1 \\leq i \\leq N) such that the pair of the squares chosen in the i-th operation is different.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n|S| = 2N\n\nEach character of S is B or W.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS\n\nOutput\n\nPrint the number of ways to make all the squares white at the end of the process, modulo 10^9+7. If there are no such ways, print 0.\n\nSample Input 1\n\n2\nBWWB\n\nSample Output 1\n\n4\n\nThere are four ways to make all the squares white, as follows:\n\nChoose Squares 1, 3 in the first operation, and choose Squares 2, 4 in the second operation.\n\nChoose Squares 2, 4 in the first operation, and choose Squares 1, 3 in the second operation.\n\nChoose Squares 1, 4 in the first operation, and choose Squares 2, 3 in the second operation.\n\nChoose Squares 2, 3 in the first operation, and choose Squares 1, 4 in the second operation.\n\nSample Input 2\n\n4\nBWBBWWWB\n\nSample Output 2\n\n288\n\nSample Input 3\n\n5\nWWWWWWWWWW\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 901, "cpu_time_ms": 9, "memory_kb": 640}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s148220163", "group_id": "codeNet:p02929", "input_text": "#include <iostream>\nusing namespace std;\ntypedef long long ll;\nll mod=1e9+7;\n\n\nint main(){\n  ll n;\n  string s;\n  cin >> n >> s;\n  int check=0;\n  int x[2*n];\n  for(int i=0;i<2*n;i++){\n    if(s[i]=='B'&&check%2==0||s[i]=='W'&&check%2==1){\n      check++; x[i]=0;\n    }\n    else{\n      check--; x[i]=1;\n    }\n    cerr << check << endl;\n  }\n  if(check){\n    cout << 0 << endl;\n    return 0;\n  }\n  ll ans=1;\n  for(ll i=1;i<=n;i++){\n    ans*=i; ans%=mod;\n  }\n  ll cnt=0;\n  for(ll i=2*n-1;i>=0;i--){\n    if(x[i]) cnt++;\n    else{\n      ans*=cnt; ans%=mod; cnt--;\n    }\n  }\n  cout << ans << endl;\n}", "language": "C++", "metadata": {"date": 1566696384, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02929.html", "problem_id": "p02929", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02929/input.txt", "sample_output_relpath": "derived/input_output/data/p02929/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02929/C++/s148220163.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s148220163", "user_id": "u179970156"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <iostream>\nusing namespace std;\ntypedef long long ll;\nll mod=1e9+7;\n\n\nint main(){\n  ll n;\n  string s;\n  cin >> n >> s;\n  int check=0;\n  int x[2*n];\n  for(int i=0;i<2*n;i++){\n    if(s[i]=='B'&&check%2==0||s[i]=='W'&&check%2==1){\n      check++; x[i]=0;\n    }\n    else{\n      check--; x[i]=1;\n    }\n    cerr << check << endl;\n  }\n  if(check){\n    cout << 0 << endl;\n    return 0;\n  }\n  ll ans=1;\n  for(ll i=1;i<=n;i++){\n    ans*=i; ans%=mod;\n  }\n  ll cnt=0;\n  for(ll i=2*n-1;i>=0;i--){\n    if(x[i]) cnt++;\n    else{\n      ans*=cnt; ans%=mod; cnt--;\n    }\n  }\n  cout << ans << endl;\n}", "problem_context": "Score : 500 points\n\nProblem Statement\n\nThere are 2N squares arranged from left to right. You are given a string of length 2N representing the color of each of the squares.\n\nThe color of the i-th square from the left is black if the i-th character of S is B, and white if that character is W.\n\nYou will perform the following operation exactly N times: choose two distinct squares, then invert the colors of these squares and the squares between them. Here, to invert the color of a square is to make it white if it is black, and vice versa.\n\nThroughout this process, you cannot choose the same square twice or more. That is, each square has to be chosen exactly once.\n\nFind the number of ways to make all the squares white at the end of the process, modulo 10^9+7.\n\nTwo ways to make the squares white are considered different if and only if there exists i (1 \\leq i \\leq N) such that the pair of the squares chosen in the i-th operation is different.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n|S| = 2N\n\nEach character of S is B or W.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS\n\nOutput\n\nPrint the number of ways to make all the squares white at the end of the process, modulo 10^9+7. If there are no such ways, print 0.\n\nSample Input 1\n\n2\nBWWB\n\nSample Output 1\n\n4\n\nThere are four ways to make all the squares white, as follows:\n\nChoose Squares 1, 3 in the first operation, and choose Squares 2, 4 in the second operation.\n\nChoose Squares 2, 4 in the first operation, and choose Squares 1, 3 in the second operation.\n\nChoose Squares 1, 4 in the first operation, and choose Squares 2, 3 in the second operation.\n\nChoose Squares 2, 3 in the first operation, and choose Squares 1, 4 in the second operation.\n\nSample Input 2\n\n4\nBWBBWWWB\n\nSample Output 2\n\n288\n\nSample Input 3\n\n5\nWWWWWWWWWW\n\nSample Output 3\n\n0", "sample_input": "2\nBWWB\n"}, "reference_outputs": ["4\n"], "source_document_id": "p02929", "source_text": "Score : 500 points\n\nProblem Statement\n\nThere are 2N squares arranged from left to right. You are given a string of length 2N representing the color of each of the squares.\n\nThe color of the i-th square from the left is black if the i-th character of S is B, and white if that character is W.\n\nYou will perform the following operation exactly N times: choose two distinct squares, then invert the colors of these squares and the squares between them. Here, to invert the color of a square is to make it white if it is black, and vice versa.\n\nThroughout this process, you cannot choose the same square twice or more. That is, each square has to be chosen exactly once.\n\nFind the number of ways to make all the squares white at the end of the process, modulo 10^9+7.\n\nTwo ways to make the squares white are considered different if and only if there exists i (1 \\leq i \\leq N) such that the pair of the squares chosen in the i-th operation is different.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n|S| = 2N\n\nEach character of S is B or W.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS\n\nOutput\n\nPrint the number of ways to make all the squares white at the end of the process, modulo 10^9+7. If there are no such ways, print 0.\n\nSample Input 1\n\n2\nBWWB\n\nSample Output 1\n\n4\n\nThere are four ways to make all the squares white, as follows:\n\nChoose Squares 1, 3 in the first operation, and choose Squares 2, 4 in the second operation.\n\nChoose Squares 2, 4 in the first operation, and choose Squares 1, 3 in the second operation.\n\nChoose Squares 1, 4 in the first operation, and choose Squares 2, 3 in the second operation.\n\nChoose Squares 2, 3 in the first operation, and choose Squares 1, 4 in the second operation.\n\nSample Input 2\n\n4\nBWBBWWWB\n\nSample Output 2\n\n288\n\nSample Input 3\n\n5\nWWWWWWWWWW\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 589, "cpu_time_ms": 173, "memory_kb": 1412}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s488489934", "group_id": "codeNet:p02934", "input_text": "#include<bits/stdc++.h>\n#define pb push_back\n#define pair pair<int,int>\n#define ll long long\n#define f first\n#define se second\nusing namespace std;\ndouble pi=acos(-1.0);\nint main(){\n int n;\n  scanf(\"%d\",&n);\n  double ans=0;\n  double x;\n  while(n--)\n  {\n    scanf(\"%lf\",&x);\n    ans+=(1.0/x);\n  }\n  ans=(1.0/ans);\n  printf(\"%.5lf\",ans);\n}", "language": "C++", "metadata": {"date": 1575728891, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02934.html", "problem_id": "p02934", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02934/input.txt", "sample_output_relpath": "derived/input_output/data/p02934/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02934/C++/s488489934.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s488489934", "user_id": "u768104057"}, "prompt_components": {"gold_output": "7.5\n", "input_to_evaluate": "#include<bits/stdc++.h>\n#define pb push_back\n#define pair pair<int,int>\n#define ll long long\n#define f first\n#define se second\nusing namespace std;\ndouble pi=acos(-1.0);\nint main(){\n int n;\n  scanf(\"%d\",&n);\n  double ans=0;\n  double x;\n  while(n--)\n  {\n    scanf(\"%lf\",&x);\n    ans+=(1.0/x);\n  }\n  ans=(1.0/ans);\n  printf(\"%.5lf\",ans);\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nGiven is a sequence of N integers A_1, \\ldots, A_N.\n\nFind the (multiplicative) inverse of the sum of the inverses of these numbers, \\frac{1}{\\frac{1}{A_1} + \\ldots + \\frac{1}{A_N}}.\n\nConstraints\n\n1 \\leq N \\leq 100\n\n1 \\leq A_i \\leq 1000\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 \\ldots A_N\n\nOutput\n\nPrint a decimal number (or an integer) representing the value of \\frac{1}{\\frac{1}{A_1} + \\ldots + \\frac{1}{A_N}}.\n\nYour output will be judged correct when its absolute or relative error from the judge's output is at most 10^{-5}.\n\nSample Input 1\n\n2\n10 30\n\nSample Output 1\n\n7.5\n\n\\frac{1}{\\frac{1}{10} + \\frac{1}{30}} = \\frac{1}{\\frac{4}{30}} = \\frac{30}{4} = 7.5.\n\nPrinting 7.50001, 7.49999, and so on will also be accepted.\n\nSample Input 2\n\n3\n200 200 200\n\nSample Output 2\n\n66.66666666666667\n\n\\frac{1}{\\frac{1}{200} + \\frac{1}{200} + \\frac{1}{200}} = \\frac{1}{\\frac{3}{200}} = \\frac{200}{3} = 66.6666....\n\nPrinting 6.66666e+1 and so on will also be accepted.\n\nSample Input 3\n\n1\n1000\n\nSample Output 3\n\n1000\n\n\\frac{1}{\\frac{1}{1000}} = 1000.\n\nPrinting +1000.0 and so on will also be accepted.", "sample_input": "2\n10 30\n"}, "reference_outputs": ["7.5\n"], "source_document_id": "p02934", "source_text": "Score : 200 points\n\nProblem Statement\n\nGiven is a sequence of N integers A_1, \\ldots, A_N.\n\nFind the (multiplicative) inverse of the sum of the inverses of these numbers, \\frac{1}{\\frac{1}{A_1} + \\ldots + \\frac{1}{A_N}}.\n\nConstraints\n\n1 \\leq N \\leq 100\n\n1 \\leq A_i \\leq 1000\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 \\ldots A_N\n\nOutput\n\nPrint a decimal number (or an integer) representing the value of \\frac{1}{\\frac{1}{A_1} + \\ldots + \\frac{1}{A_N}}.\n\nYour output will be judged correct when its absolute or relative error from the judge's output is at most 10^{-5}.\n\nSample Input 1\n\n2\n10 30\n\nSample Output 1\n\n7.5\n\n\\frac{1}{\\frac{1}{10} + \\frac{1}{30}} = \\frac{1}{\\frac{4}{30}} = \\frac{30}{4} = 7.5.\n\nPrinting 7.50001, 7.49999, and so on will also be accepted.\n\nSample Input 2\n\n3\n200 200 200\n\nSample Output 2\n\n66.66666666666667\n\n\\frac{1}{\\frac{1}{200} + \\frac{1}{200} + \\frac{1}{200}} = \\frac{1}{\\frac{3}{200}} = \\frac{200}{3} = 66.6666....\n\nPrinting 6.66666e+1 and so on will also be accepted.\n\nSample Input 3\n\n1\n1000\n\nSample Output 3\n\n1000\n\n\\frac{1}{\\frac{1}{1000}} = 1000.\n\nPrinting +1000.0 and so on will also be accepted.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 337, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s188684535", "group_id": "codeNet:p02934", "input_text": "//#include \"stdc++.h\"\n#include<bits/stdc++.h>\n#include<iostream>\nusing namespace std;\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef double db;\ntypedef long double ldb;\ntypedef pair <int, int> pii;\ntypedef pair <ll, ll> pll;\ntypedef pair <ll, int> pli;\ntypedef pair <db, db> pdd;\ntypedef vector<int> vi;\n#define m1 make_pair\n#define pb push_back\n#define flush fflush(stdout)\n#define IOS std::ios::sync_with_stdio(false); cin.tie(NULL);cout.tie(NULL);\n#define reset(x,v) memset(x,v,sizeof(x))\n#define sz(x) (int)(x.size())\n#define ff first\n#define ss second\n#define endl \"\\n\"\n#define int long long int\ninline ll gcd(ll a,ll b){if(a==0) return b;return gcd(b%a,a);}\ninline ll power(ll a,ll n,ll m){if(n==0)return 1;ll p=power(a,n/2,m);p=(p*p)%m;if(n%2) return (p*a)%m;else return p;}\nconst ll MOD = 1000000007;\nconst ll mod=1000000006;\nconst int INF = 0x3f3f3f3f;\nconst ll LL_INF = 0x3f3f3f3f3f3f3f3f;\n/*\n shuffle(x,x+n,rng) // shuffling elements of x in random order\n */\n\nint32_t main()\n{\n    IOS;\n    int n;\n    cin>>n;\n    int a[n];long double ans,sum=0.0;\n    for(int i=0;i<n;i++)\n    { cin>>a[i];\n        sum=sum+(long double)1/a[i];\n    }\n    ans=1.0/sum;\n    cout<<ans<<endl;\n    \n    return 0;\n}\n\n\n\n\n\n", "language": "C++", "metadata": {"date": 1566983560, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02934.html", "problem_id": "p02934", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02934/input.txt", "sample_output_relpath": "derived/input_output/data/p02934/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02934/C++/s188684535.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s188684535", "user_id": "u314476982"}, "prompt_components": {"gold_output": "7.5\n", "input_to_evaluate": "//#include \"stdc++.h\"\n#include<bits/stdc++.h>\n#include<iostream>\nusing namespace std;\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef double db;\ntypedef long double ldb;\ntypedef pair <int, int> pii;\ntypedef pair <ll, ll> pll;\ntypedef pair <ll, int> pli;\ntypedef pair <db, db> pdd;\ntypedef vector<int> vi;\n#define m1 make_pair\n#define pb push_back\n#define flush fflush(stdout)\n#define IOS std::ios::sync_with_stdio(false); cin.tie(NULL);cout.tie(NULL);\n#define reset(x,v) memset(x,v,sizeof(x))\n#define sz(x) (int)(x.size())\n#define ff first\n#define ss second\n#define endl \"\\n\"\n#define int long long int\ninline ll gcd(ll a,ll b){if(a==0) return b;return gcd(b%a,a);}\ninline ll power(ll a,ll n,ll m){if(n==0)return 1;ll p=power(a,n/2,m);p=(p*p)%m;if(n%2) return (p*a)%m;else return p;}\nconst ll MOD = 1000000007;\nconst ll mod=1000000006;\nconst int INF = 0x3f3f3f3f;\nconst ll LL_INF = 0x3f3f3f3f3f3f3f3f;\n/*\n shuffle(x,x+n,rng) // shuffling elements of x in random order\n */\n\nint32_t main()\n{\n    IOS;\n    int n;\n    cin>>n;\n    int a[n];long double ans,sum=0.0;\n    for(int i=0;i<n;i++)\n    { cin>>a[i];\n        sum=sum+(long double)1/a[i];\n    }\n    ans=1.0/sum;\n    cout<<ans<<endl;\n    \n    return 0;\n}\n\n\n\n\n\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nGiven is a sequence of N integers A_1, \\ldots, A_N.\n\nFind the (multiplicative) inverse of the sum of the inverses of these numbers, \\frac{1}{\\frac{1}{A_1} + \\ldots + \\frac{1}{A_N}}.\n\nConstraints\n\n1 \\leq N \\leq 100\n\n1 \\leq A_i \\leq 1000\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 \\ldots A_N\n\nOutput\n\nPrint a decimal number (or an integer) representing the value of \\frac{1}{\\frac{1}{A_1} + \\ldots + \\frac{1}{A_N}}.\n\nYour output will be judged correct when its absolute or relative error from the judge's output is at most 10^{-5}.\n\nSample Input 1\n\n2\n10 30\n\nSample Output 1\n\n7.5\n\n\\frac{1}{\\frac{1}{10} + \\frac{1}{30}} = \\frac{1}{\\frac{4}{30}} = \\frac{30}{4} = 7.5.\n\nPrinting 7.50001, 7.49999, and so on will also be accepted.\n\nSample Input 2\n\n3\n200 200 200\n\nSample Output 2\n\n66.66666666666667\n\n\\frac{1}{\\frac{1}{200} + \\frac{1}{200} + \\frac{1}{200}} = \\frac{1}{\\frac{3}{200}} = \\frac{200}{3} = 66.6666....\n\nPrinting 6.66666e+1 and so on will also be accepted.\n\nSample Input 3\n\n1\n1000\n\nSample Output 3\n\n1000\n\n\\frac{1}{\\frac{1}{1000}} = 1000.\n\nPrinting +1000.0 and so on will also be accepted.", "sample_input": "2\n10 30\n"}, "reference_outputs": ["7.5\n"], "source_document_id": "p02934", "source_text": "Score : 200 points\n\nProblem Statement\n\nGiven is a sequence of N integers A_1, \\ldots, A_N.\n\nFind the (multiplicative) inverse of the sum of the inverses of these numbers, \\frac{1}{\\frac{1}{A_1} + \\ldots + \\frac{1}{A_N}}.\n\nConstraints\n\n1 \\leq N \\leq 100\n\n1 \\leq A_i \\leq 1000\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 \\ldots A_N\n\nOutput\n\nPrint a decimal number (or an integer) representing the value of \\frac{1}{\\frac{1}{A_1} + \\ldots + \\frac{1}{A_N}}.\n\nYour output will be judged correct when its absolute or relative error from the judge's output is at most 10^{-5}.\n\nSample Input 1\n\n2\n10 30\n\nSample Output 1\n\n7.5\n\n\\frac{1}{\\frac{1}{10} + \\frac{1}{30}} = \\frac{1}{\\frac{4}{30}} = \\frac{30}{4} = 7.5.\n\nPrinting 7.50001, 7.49999, and so on will also be accepted.\n\nSample Input 2\n\n3\n200 200 200\n\nSample Output 2\n\n66.66666666666667\n\n\\frac{1}{\\frac{1}{200} + \\frac{1}{200} + \\frac{1}{200}} = \\frac{1}{\\frac{3}{200}} = \\frac{200}{3} = 66.6666....\n\nPrinting 6.66666e+1 and so on will also be accepted.\n\nSample Input 3\n\n1\n1000\n\nSample Output 3\n\n1000\n\n\\frac{1}{\\frac{1}{1000}} = 1000.\n\nPrinting +1000.0 and so on will also be accepted.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1222, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s102926409", "group_id": "codeNet:p02934", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef long double ld;\ntypedef pair<ll, ll> l_l;\ntypedef pair<int , int> i_i;\ntypedef pair<string , int> s_i;\ntypedef vector<ll> vel;\ntypedef vector<int> vei;\ntypedef vector<char> vec;\ntypedef vector<bool> veb;\ntypedef vector<string> ves;\ntypedef vector<vector<ll>> ve_vel;\ntypedef vector<vector<int>> ve_vei;\ntypedef vector<vector<char>> ve_vec;\ntypedef vector<vector<bool>> ve_veb;\ntypedef vector<vector<string>> ve_ves;\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define rep1(i,n) for(int i=1;i<(int)(n);i++)\n#define rep2(i,n) for(int i=2;i<(int)(n);i++)\n#define repk(i,k,n) for(int i=k;i<(int)(n);i++)\n#define fs first\n#define sc second\n#define pub push_back\n#define puf push_front\n#define pob pop_back\n#define all(a) a.begin(),a.end()\n#define rall(a) a.rbegin(),a.rend()\n#define maxel(a) *max_element(all(a))\n#define minel(a) *min_element(all(a))\n#define acc accumulate\n#define EPS (1e-7)\n//#define INF (1e9)\n#define PI (acos(-1))\n#define mod (1000000007)\ntypedef long long int64;\nconst int64 INF = 1LL << 58;\ntemplate<class T> bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<class T> bool chmin(T &a, const T &b) { if (a>b) { a=b; return 1; } return 0; }\ntemplate<typename T> void remove(T & vector, unsigned int index){vector.erase(vector.begin() + index);}\n\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\n\tint N; cin >> N;\n\tvector<ld> A(N); rep(i,N) cin >> A[i];\n\n\tld bunbo = 0;\n\trep(i,N) bunbo += 1.0 / A[i];\n\tld ans = 1.0 / bunbo;\n\tcout << fixed << setprecision(10) << ans << endl;\n\treturn 0;\n\n    \n}", "language": "C++", "metadata": {"date": 1566177022, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02934.html", "problem_id": "p02934", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02934/input.txt", "sample_output_relpath": "derived/input_output/data/p02934/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02934/C++/s102926409.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s102926409", "user_id": "u263715385"}, "prompt_components": {"gold_output": "7.5\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef long double ld;\ntypedef pair<ll, ll> l_l;\ntypedef pair<int , int> i_i;\ntypedef pair<string , int> s_i;\ntypedef vector<ll> vel;\ntypedef vector<int> vei;\ntypedef vector<char> vec;\ntypedef vector<bool> veb;\ntypedef vector<string> ves;\ntypedef vector<vector<ll>> ve_vel;\ntypedef vector<vector<int>> ve_vei;\ntypedef vector<vector<char>> ve_vec;\ntypedef vector<vector<bool>> ve_veb;\ntypedef vector<vector<string>> ve_ves;\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define rep1(i,n) for(int i=1;i<(int)(n);i++)\n#define rep2(i,n) for(int i=2;i<(int)(n);i++)\n#define repk(i,k,n) for(int i=k;i<(int)(n);i++)\n#define fs first\n#define sc second\n#define pub push_back\n#define puf push_front\n#define pob pop_back\n#define all(a) a.begin(),a.end()\n#define rall(a) a.rbegin(),a.rend()\n#define maxel(a) *max_element(all(a))\n#define minel(a) *min_element(all(a))\n#define acc accumulate\n#define EPS (1e-7)\n//#define INF (1e9)\n#define PI (acos(-1))\n#define mod (1000000007)\ntypedef long long int64;\nconst int64 INF = 1LL << 58;\ntemplate<class T> bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<class T> bool chmin(T &a, const T &b) { if (a>b) { a=b; return 1; } return 0; }\ntemplate<typename T> void remove(T & vector, unsigned int index){vector.erase(vector.begin() + index);}\n\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\n\tint N; cin >> N;\n\tvector<ld> A(N); rep(i,N) cin >> A[i];\n\n\tld bunbo = 0;\n\trep(i,N) bunbo += 1.0 / A[i];\n\tld ans = 1.0 / bunbo;\n\tcout << fixed << setprecision(10) << ans << endl;\n\treturn 0;\n\n    \n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nGiven is a sequence of N integers A_1, \\ldots, A_N.\n\nFind the (multiplicative) inverse of the sum of the inverses of these numbers, \\frac{1}{\\frac{1}{A_1} + \\ldots + \\frac{1}{A_N}}.\n\nConstraints\n\n1 \\leq N \\leq 100\n\n1 \\leq A_i \\leq 1000\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 \\ldots A_N\n\nOutput\n\nPrint a decimal number (or an integer) representing the value of \\frac{1}{\\frac{1}{A_1} + \\ldots + \\frac{1}{A_N}}.\n\nYour output will be judged correct when its absolute or relative error from the judge's output is at most 10^{-5}.\n\nSample Input 1\n\n2\n10 30\n\nSample Output 1\n\n7.5\n\n\\frac{1}{\\frac{1}{10} + \\frac{1}{30}} = \\frac{1}{\\frac{4}{30}} = \\frac{30}{4} = 7.5.\n\nPrinting 7.50001, 7.49999, and so on will also be accepted.\n\nSample Input 2\n\n3\n200 200 200\n\nSample Output 2\n\n66.66666666666667\n\n\\frac{1}{\\frac{1}{200} + \\frac{1}{200} + \\frac{1}{200}} = \\frac{1}{\\frac{3}{200}} = \\frac{200}{3} = 66.6666....\n\nPrinting 6.66666e+1 and so on will also be accepted.\n\nSample Input 3\n\n1\n1000\n\nSample Output 3\n\n1000\n\n\\frac{1}{\\frac{1}{1000}} = 1000.\n\nPrinting +1000.0 and so on will also be accepted.", "sample_input": "2\n10 30\n"}, "reference_outputs": ["7.5\n"], "source_document_id": "p02934", "source_text": "Score : 200 points\n\nProblem Statement\n\nGiven is a sequence of N integers A_1, \\ldots, A_N.\n\nFind the (multiplicative) inverse of the sum of the inverses of these numbers, \\frac{1}{\\frac{1}{A_1} + \\ldots + \\frac{1}{A_N}}.\n\nConstraints\n\n1 \\leq N \\leq 100\n\n1 \\leq A_i \\leq 1000\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 \\ldots A_N\n\nOutput\n\nPrint a decimal number (or an integer) representing the value of \\frac{1}{\\frac{1}{A_1} + \\ldots + \\frac{1}{A_N}}.\n\nYour output will be judged correct when its absolute or relative error from the judge's output is at most 10^{-5}.\n\nSample Input 1\n\n2\n10 30\n\nSample Output 1\n\n7.5\n\n\\frac{1}{\\frac{1}{10} + \\frac{1}{30}} = \\frac{1}{\\frac{4}{30}} = \\frac{30}{4} = 7.5.\n\nPrinting 7.50001, 7.49999, and so on will also be accepted.\n\nSample Input 2\n\n3\n200 200 200\n\nSample Output 2\n\n66.66666666666667\n\n\\frac{1}{\\frac{1}{200} + \\frac{1}{200} + \\frac{1}{200}} = \\frac{1}{\\frac{3}{200}} = \\frac{200}{3} = 66.6666....\n\nPrinting 6.66666e+1 and so on will also be accepted.\n\nSample Input 3\n\n1\n1000\n\nSample Output 3\n\n1000\n\n\\frac{1}{\\frac{1}{1000}} = 1000.\n\nPrinting +1000.0 and so on will also be accepted.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1622, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s414603809", "group_id": "codeNet:p02937", "input_text": "#include <iostream>\n#include <string>\n#include <vector>\n#include <map>\n\nusing namespace std;\n\nstring tre;\n\nbool moze(int n, string k){\n    int j = 0;\n   for (int i=0; i < n && j < k.length(); i++) \n       if (k[j] == tre[i]) \n         j++; \n  \n   return (j==k.length()); \n}\n\nint main() {\n  string t;\n  cin >> tre >> t;\n  map <char, bool> ima;\n  for (int i = 0; i < tre.length(); i++) \n   ima[tre[i]] = true;\n  for (int i = 0; i < t.length(); i++)\n    if (!ima[t[i]]){\n      cout << \"-1\";\n      return 0;\n    }\n  int l = 1, r = 10000000;\n  while (tre.size() < 10000000) tre += tre;\n  while (l < r){\n    int mid = (l+r)/2;\n    if (!moze(mid,t)) l = mid + 1;\n    else r = mid;\n  }\n  cout << l;\n}", "language": "C++", "metadata": {"date": 1566279026, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02937.html", "problem_id": "p02937", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02937/input.txt", "sample_output_relpath": "derived/input_output/data/p02937/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02937/C++/s414603809.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s414603809", "user_id": "u065859967"}, "prompt_components": {"gold_output": "10\n", "input_to_evaluate": "#include <iostream>\n#include <string>\n#include <vector>\n#include <map>\n\nusing namespace std;\n\nstring tre;\n\nbool moze(int n, string k){\n    int j = 0;\n   for (int i=0; i < n && j < k.length(); i++) \n       if (k[j] == tre[i]) \n         j++; \n  \n   return (j==k.length()); \n}\n\nint main() {\n  string t;\n  cin >> tre >> t;\n  map <char, bool> ima;\n  for (int i = 0; i < tre.length(); i++) \n   ima[tre[i]] = true;\n  for (int i = 0; i < t.length(); i++)\n    if (!ima[t[i]]){\n      cout << \"-1\";\n      return 0;\n    }\n  int l = 1, r = 10000000;\n  while (tre.size() < 10000000) tre += tre;\n  while (l < r){\n    int mid = (l+r)/2;\n    if (!moze(mid,t)) l = mid + 1;\n    else r = mid;\n  }\n  cout << l;\n}", "problem_context": "Score : 500 points\n\nProblem Statement\n\nGiven are two strings s and t consisting of lowercase English letters. Determine if there exists an integer i satisfying the following condition, and find the minimum such i if it exists.\n\nLet s' be the concatenation of 10^{100} copies of s. t is a subsequence of the string {s'}_1{s'}_2\\ldots{s'}_i (the first i characters in s').\n\nNotes\n\nA subsequence of a string a is a string obtained by deleting zero or more characters from a and concatenating the remaining characters without changing the relative order. For example, the subsequences of contest include net, c, and contest.\n\nConstraints\n\n1 \\leq |s| \\leq 10^5\n\n1 \\leq |t| \\leq 10^5\n\ns and t consists of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\ns\nt\n\nOutput\n\nIf there exists an integer i satisfying the following condition, print the minimum such i; otherwise, print -1.\n\nSample Input 1\n\ncontest\nson\n\nSample Output 1\n\n10\n\nt = son is a subsequence of the string contestcon (the first 10 characters in s' = contestcontestcontest...), so i = 10 satisfies the condition.\n\nOn the other hand, t is not a subsequence of the string contestco (the first 9 characters in s'), so i = 9 does not satisfy the condition.\n\nSimilarly, any integer less than 9 does not satisfy the condition, either. Thus, the minimum integer i satisfying the condition is 10.\n\nSample Input 2\n\ncontest\nprogramming\n\nSample Output 2\n\n-1\n\nt = programming is not a substring of s' = contestcontestcontest.... Thus, there is no integer i satisfying the condition.\n\nSample Input 3\n\ncontest\nsentence\n\nSample Output 3\n\n33\n\nNote that the answer may not fit into a 32-bit integer type, though we cannot put such a case here.", "sample_input": "contest\nson\n"}, "reference_outputs": ["10\n"], "source_document_id": "p02937", "source_text": "Score : 500 points\n\nProblem Statement\n\nGiven are two strings s and t consisting of lowercase English letters. Determine if there exists an integer i satisfying the following condition, and find the minimum such i if it exists.\n\nLet s' be the concatenation of 10^{100} copies of s. t is a subsequence of the string {s'}_1{s'}_2\\ldots{s'}_i (the first i characters in s').\n\nNotes\n\nA subsequence of a string a is a string obtained by deleting zero or more characters from a and concatenating the remaining characters without changing the relative order. For example, the subsequences of contest include net, c, and contest.\n\nConstraints\n\n1 \\leq |s| \\leq 10^5\n\n1 \\leq |t| \\leq 10^5\n\ns and t consists of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\ns\nt\n\nOutput\n\nIf there exists an integer i satisfying the following condition, print the minimum such i; otherwise, print -1.\n\nSample Input 1\n\ncontest\nson\n\nSample Output 1\n\n10\n\nt = son is a subsequence of the string contestcon (the first 10 characters in s' = contestcontestcontest...), so i = 10 satisfies the condition.\n\nOn the other hand, t is not a subsequence of the string contestco (the first 9 characters in s'), so i = 9 does not satisfy the condition.\n\nSimilarly, any integer less than 9 does not satisfy the condition, either. Thus, the minimum integer i satisfying the condition is 10.\n\nSample Input 2\n\ncontest\nprogramming\n\nSample Output 2\n\n-1\n\nt = programming is not a substring of s' = contestcontestcontest.... Thus, there is no integer i satisfying the condition.\n\nSample Input 3\n\ncontest\nsentence\n\nSample Output 3\n\n33\n\nNote that the answer may not fit into a 32-bit integer type, though we cannot put such a case here.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 692, "cpu_time_ms": 389, "memory_kb": 19480}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s251527443", "group_id": "codeNet:p02942", "input_text": "#include <bits/stdc++.h>\n#define st first\n#define nd second\n\nusing namespace std;\n\nvoid debug_out() { cerr << endl; }\ntemplate<class T> ostream& prnt(ostream& out, T v) { out << v.size() << '\\n'; for(auto e : v) out << e << ' '; return out;}\ntemplate<class T> ostream& operator<<(ostream& out, vector <T> v) { return prnt(out, v); }\ntemplate<class T> ostream& operator<<(ostream& out, set <T> v) { return prnt(out, v); }\ntemplate<class T1, class T2> ostream& operator<<(ostream& out, map <T1, T2> v) { return prnt(out, v); }\ntemplate<class T1, class T2> ostream& operator<<(ostream& out, pair<T1, T2> p) { return out << '(' << p.st << ' ' << p.nd << ')'; }\ntemplate <typename Head, typename... Tail> void debug_out(Head H, Tail... T) { cerr << \" \" << H; debug_out(T...);}\n\n#define dbg(...) cerr << #__VA_ARGS__ << \" ->\", debug_out(__VA_ARGS__)\n#define dbg_v(x, n) do{cerr<<#x\"[]: \";for(int _=0;_<n;++_)cerr<<x[_]<<\" \";cerr<<'\\n';}while(0)\n#define dbg_ok cerr<<\"OK!\\n\"\n\nconst int N = 101;\nint n, m, a[N][N];\n\nstruct BipartiteMatcher {\n\tvector<vector<int>> G;\n\tvector<int> L, R, Viz;\n \n\tBipartiteMatcher(int n, int m) {\n\t\tG.resize(n);\n\t\tL.resize(n, -1);\n\t\tR.resize(m, -1);\n\t\tViz.resize(n);\n\t}\n \n\tvoid AddEdge(int a, int b) {\n\t\tG[a].push_back(b);\n\t}\n \n\tbool Match(int node) {\n\t\tif(Viz[node]) \n\t\t\treturn false;\n\t\tViz[node] = true;\n\t\n\t\tfor(auto vec : G[node]) {\n\t\t\tif(R[vec] == -1 || Match(R[vec])) {\n\t\t\t\tL[node] = vec;\n\t\t\t\tR[vec] = node;\n\t\t\t\treturn true;\n\t\t\t}\n\t\t}\n \n\t\treturn false;\n\t}\n\tvoid Solve() {\n\t\tbool ok = true;\n\t\twhile(ok) {\n\t\t\tok = false;\n\t\t\tfill(Viz.begin(), Viz.end(), 0);\n\t\t\tfor(int i = 0; i < L.size(); ++i)\n\t\t\t\tif(L[i] == -1)\n\t\t\t\t\tok |= Match(i);\n\t\t}\n\t}\n};\n \n\nint main() {\n\tios_base::sync_with_stdio(false);\n\n\tcin >> n >> m;\n\tfor(int i= 0; i < n; i++)\n\t\tfor(int j = 0; j < m; j++) {\n\t\t\tcin >> a[i][j];\n\t\t\ta[i][j]--;\n\t\t}\n\n\tfor(int j = 0; j < m; j++) {\n\t\tBipartiteMatcher bm(n, n);\n\t\tdbg(j);\n\t\tfor(int i = 0; i < n; i++)\n\t\t\tfor(int k = j; k < m; k++)\n\t\t\t\tbm.AddEdge(i, a[i][k] / m);\n\t\t// dbg_ok;\n\t\tbm.Solve();\n\t\t// dbg_ok;\n\t\tfor(int i = 0; i < n; i++) {\n\t\t\tint sch = bm.L[i];\n\t\t\tdbg(i, sch);\n\t\t\tfor(int k = j; k < m; k++)\n\t\t\t\tif(a[i][k] / m == sch) {\n\t\t\t\t\tswap(a[i][k], a[i][j]);\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t}\n\t}\n\n\tfor(int i = 0; i < n; i++)\n\t\tfor(int j = 0; j < m; j++)\n\t\t\tcout << a[i][j] << \" \\n\"[j == m - 1];\n\n\n\tfor(int i = 0; i < n; i++)\n\t\tfor(int j = 0; j < m; j++) {\n\t\t\tswap(a[i][j], a[a[i][j] / m][j]);\n\t\t}\n\n\tfor(int i = 0; i < n; i++)\n\t\tfor(int j = 0; j < m; j++)\n\t\t\tcout << a[i][j]  << \" \\n\"[j == m - 1];\n}\t\n\n\t", "language": "C++", "metadata": {"date": 1567715873, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02942.html", "problem_id": "p02942", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02942/input.txt", "sample_output_relpath": "derived/input_output/data/p02942/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02942/C++/s251527443.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s251527443", "user_id": "u541161485"}, "prompt_components": {"gold_output": "2 6\n4 3\n5 1\n2 1\n4 3\n5 6\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define st first\n#define nd second\n\nusing namespace std;\n\nvoid debug_out() { cerr << endl; }\ntemplate<class T> ostream& prnt(ostream& out, T v) { out << v.size() << '\\n'; for(auto e : v) out << e << ' '; return out;}\ntemplate<class T> ostream& operator<<(ostream& out, vector <T> v) { return prnt(out, v); }\ntemplate<class T> ostream& operator<<(ostream& out, set <T> v) { return prnt(out, v); }\ntemplate<class T1, class T2> ostream& operator<<(ostream& out, map <T1, T2> v) { return prnt(out, v); }\ntemplate<class T1, class T2> ostream& operator<<(ostream& out, pair<T1, T2> p) { return out << '(' << p.st << ' ' << p.nd << ')'; }\ntemplate <typename Head, typename... Tail> void debug_out(Head H, Tail... T) { cerr << \" \" << H; debug_out(T...);}\n\n#define dbg(...) cerr << #__VA_ARGS__ << \" ->\", debug_out(__VA_ARGS__)\n#define dbg_v(x, n) do{cerr<<#x\"[]: \";for(int _=0;_<n;++_)cerr<<x[_]<<\" \";cerr<<'\\n';}while(0)\n#define dbg_ok cerr<<\"OK!\\n\"\n\nconst int N = 101;\nint n, m, a[N][N];\n\nstruct BipartiteMatcher {\n\tvector<vector<int>> G;\n\tvector<int> L, R, Viz;\n \n\tBipartiteMatcher(int n, int m) {\n\t\tG.resize(n);\n\t\tL.resize(n, -1);\n\t\tR.resize(m, -1);\n\t\tViz.resize(n);\n\t}\n \n\tvoid AddEdge(int a, int b) {\n\t\tG[a].push_back(b);\n\t}\n \n\tbool Match(int node) {\n\t\tif(Viz[node]) \n\t\t\treturn false;\n\t\tViz[node] = true;\n\t\n\t\tfor(auto vec : G[node]) {\n\t\t\tif(R[vec] == -1 || Match(R[vec])) {\n\t\t\t\tL[node] = vec;\n\t\t\t\tR[vec] = node;\n\t\t\t\treturn true;\n\t\t\t}\n\t\t}\n \n\t\treturn false;\n\t}\n\tvoid Solve() {\n\t\tbool ok = true;\n\t\twhile(ok) {\n\t\t\tok = false;\n\t\t\tfill(Viz.begin(), Viz.end(), 0);\n\t\t\tfor(int i = 0; i < L.size(); ++i)\n\t\t\t\tif(L[i] == -1)\n\t\t\t\t\tok |= Match(i);\n\t\t}\n\t}\n};\n \n\nint main() {\n\tios_base::sync_with_stdio(false);\n\n\tcin >> n >> m;\n\tfor(int i= 0; i < n; i++)\n\t\tfor(int j = 0; j < m; j++) {\n\t\t\tcin >> a[i][j];\n\t\t\ta[i][j]--;\n\t\t}\n\n\tfor(int j = 0; j < m; j++) {\n\t\tBipartiteMatcher bm(n, n);\n\t\tdbg(j);\n\t\tfor(int i = 0; i < n; i++)\n\t\t\tfor(int k = j; k < m; k++)\n\t\t\t\tbm.AddEdge(i, a[i][k] / m);\n\t\t// dbg_ok;\n\t\tbm.Solve();\n\t\t// dbg_ok;\n\t\tfor(int i = 0; i < n; i++) {\n\t\t\tint sch = bm.L[i];\n\t\t\tdbg(i, sch);\n\t\t\tfor(int k = j; k < m; k++)\n\t\t\t\tif(a[i][k] / m == sch) {\n\t\t\t\t\tswap(a[i][k], a[i][j]);\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t}\n\t}\n\n\tfor(int i = 0; i < n; i++)\n\t\tfor(int j = 0; j < m; j++)\n\t\t\tcout << a[i][j] << \" \\n\"[j == m - 1];\n\n\n\tfor(int i = 0; i < n; i++)\n\t\tfor(int j = 0; j < m; j++) {\n\t\t\tswap(a[i][j], a[a[i][j] / m][j]);\n\t\t}\n\n\tfor(int i = 0; i < n; i++)\n\t\tfor(int j = 0; j < m; j++)\n\t\t\tcout << a[i][j]  << \" \\n\"[j == m - 1];\n}\t\n\n\t", "problem_context": "Score : 1100 points\n\nProblem Statement\n\nWe have a grid with N rows and M columns of squares.\nEach integer from 1 to NM is written in this grid once.\nThe number written in the square at the i-th row from the top and the j-th column from the left is A_{ij}.\n\nYou need to rearrange these numbers as follows:\n\nFirst, for each of the N rows, rearrange the numbers written in it as you like.\n\nSecond, for each of the M columns, rearrange the numbers written in it as you like.\n\nFinally, for each of the N rows, rearrange the numbers written in it as you like.\n\nAfter rearranging the numbers, you want the number written in the square at the i-th row from the top and the j-th column from the left to be M\\times (i-1)+j.\nConstruct one such way to rearrange the numbers. The constraints guarantee that it is always possible to achieve the objective.\n\nConstraints\n\n1 \\leq N,M \\leq 100\n\n1 \\leq A_{ij} \\leq NM\n\nA_{ij} are distinct.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_{11} A_{12} ... A_{1M}\n:\nA_{N1} A_{N2} ... A_{NM}\n\nOutput\n\nPrint one way to rearrange the numbers in the following format:\n\nB_{11} B_{12} ... B_{1M}\n:\nB_{N1} B_{N2} ... B_{NM}\nC_{11} C_{12} ... C_{1M}\n:\nC_{N1} C_{N2} ... C_{NM}\n\nHere B_{ij} is the number written in the square at the i-th row from the top and the j-th column from the left after Step 1, and C_{ij} is the number written in that square after Step 2.\n\nSample Input 1\n\n3 2\n2 6\n4 3\n1 5\n\nSample Output 1\n\n2 6\n4 3\n5 1\n2 1\n4 3\n5 6\n\nSample Input 2\n\n3 4\n1 4 7 10\n2 5 8 11\n3 6 9 12\n\nSample Output 2\n\n1 4 7 10\n5 8 11 2\n9 12 3 6\n1 4 3 2\n5 8 7 6\n9 12 11 10", "sample_input": "3 2\n2 6\n4 3\n1 5\n"}, "reference_outputs": ["2 6\n4 3\n5 1\n2 1\n4 3\n5 6\n"], "source_document_id": "p02942", "source_text": "Score : 1100 points\n\nProblem Statement\n\nWe have a grid with N rows and M columns of squares.\nEach integer from 1 to NM is written in this grid once.\nThe number written in the square at the i-th row from the top and the j-th column from the left is A_{ij}.\n\nYou need to rearrange these numbers as follows:\n\nFirst, for each of the N rows, rearrange the numbers written in it as you like.\n\nSecond, for each of the M columns, rearrange the numbers written in it as you like.\n\nFinally, for each of the N rows, rearrange the numbers written in it as you like.\n\nAfter rearranging the numbers, you want the number written in the square at the i-th row from the top and the j-th column from the left to be M\\times (i-1)+j.\nConstruct one such way to rearrange the numbers. The constraints guarantee that it is always possible to achieve the objective.\n\nConstraints\n\n1 \\leq N,M \\leq 100\n\n1 \\leq A_{ij} \\leq NM\n\nA_{ij} are distinct.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_{11} A_{12} ... A_{1M}\n:\nA_{N1} A_{N2} ... A_{NM}\n\nOutput\n\nPrint one way to rearrange the numbers in the following format:\n\nB_{11} B_{12} ... B_{1M}\n:\nB_{N1} B_{N2} ... B_{NM}\nC_{11} C_{12} ... C_{1M}\n:\nC_{N1} C_{N2} ... C_{NM}\n\nHere B_{ij} is the number written in the square at the i-th row from the top and the j-th column from the left after Step 1, and C_{ij} is the number written in that square after Step 2.\n\nSample Input 1\n\n3 2\n2 6\n4 3\n1 5\n\nSample Output 1\n\n2 6\n4 3\n5 1\n2 1\n4 3\n5 6\n\nSample Input 2\n\n3 4\n1 4 7 10\n2 5 8 11\n3 6 9 12\n\nSample Output 2\n\n1 4 7 10\n5 8 11 2\n9 12 3 6\n1 4 3 2\n5 8 7 6\n9 12 11 10", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2519, "cpu_time_ms": 36, "memory_kb": 512}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s713322334", "group_id": "codeNet:p02943", "input_text": "#include <cstdio>\n#include <string>\n#include <iostream>\n#include <algorithm>\nusing namespace std;\n\n#define R register\n\nint N, K;\nstring s, rev, tmp, str;\n\nint main() {\n\tcin >> N >> K >> s;\n\trev = s, reverse(rev.begin(), rev.end());\n\ttmp = s + rev, reverse(tmp.begin(), tmp.end());\n//cout << tmp << endl;\n\tstr = tmp.substr(0, N);\n\tfor(R int i = 1; i < N; ++i) {\n\t\trev = tmp.substr(i, N);\n\t\tif(rev < str) str = rev;\n\t}\n\treverse(str.begin(), str.end());\n//cout << str << endl;\n\tfor(R int i = 1, j; i < K; ++i) {\n\t\tfor(j = N - 2; ~j; --j) if(str[j] != str[N - 1]) break;\n\t\tstr = str + str.substr(j + 1, N);\n//cout << str << endl;\n\t\tj = str.length();\n\t\tstr = str.substr(j - N, N);\n//cout << str << endl;\n\t}\n\treverse(str.begin(), str.end());\n \tcout << str;\n \treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1566097652, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02943.html", "problem_id": "p02943", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02943/input.txt", "sample_output_relpath": "derived/input_output/data/p02943/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02943/C++/s713322334.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s713322334", "user_id": "u907369450"}, "prompt_components": {"gold_output": "aabca\n", "input_to_evaluate": "#include <cstdio>\n#include <string>\n#include <iostream>\n#include <algorithm>\nusing namespace std;\n\n#define R register\n\nint N, K;\nstring s, rev, tmp, str;\n\nint main() {\n\tcin >> N >> K >> s;\n\trev = s, reverse(rev.begin(), rev.end());\n\ttmp = s + rev, reverse(tmp.begin(), tmp.end());\n//cout << tmp << endl;\n\tstr = tmp.substr(0, N);\n\tfor(R int i = 1; i < N; ++i) {\n\t\trev = tmp.substr(i, N);\n\t\tif(rev < str) str = rev;\n\t}\n\treverse(str.begin(), str.end());\n//cout << str << endl;\n\tfor(R int i = 1, j; i < K; ++i) {\n\t\tfor(j = N - 2; ~j; --j) if(str[j] != str[N - 1]) break;\n\t\tstr = str + str.substr(j + 1, N);\n//cout << str << endl;\n\t\tj = str.length();\n\t\tstr = str.substr(j - N, N);\n//cout << str << endl;\n\t}\n\treverse(str.begin(), str.end());\n \tcout << str;\n \treturn 0;\n}\n", "problem_context": "Score : 1300 points\n\nProblem Statement\n\nTakahashi has a string S of length N consisting of lowercase English letters.\nOn this string, he will perform the following operation K times:\n\nLet T be the string obtained by reversing S, and U be the string obtained by concatenating S and T in this order.\n\nLet S' be some contiguous substring of U with length N, and replace S with S'.\n\nAmong the strings that can be the string S after the K operations, find the lexicographically smallest possible one.\n\nConstraints\n\n1 \\leq N \\leq 5000\n\n1 \\leq K \\leq 10^9\n\n|S|=N\n\nS consists of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nS\n\nOutput\n\nPrint the lexicographically smallest possible string that can be the string S after the K operations.\n\nSample Input 1\n\n5 1\nbacba\n\nSample Output 1\n\naabca\n\nWhen S=bacba, T=abcab, U=bacbaabcab, and the optimal choice of S' is S'=aabca.\n\nSample Input 2\n\n10 2\nbbaabbbaab\n\nSample Output 2\n\naaaabbaabb", "sample_input": "5 1\nbacba\n"}, "reference_outputs": ["aabca\n"], "source_document_id": "p02943", "source_text": "Score : 1300 points\n\nProblem Statement\n\nTakahashi has a string S of length N consisting of lowercase English letters.\nOn this string, he will perform the following operation K times:\n\nLet T be the string obtained by reversing S, and U be the string obtained by concatenating S and T in this order.\n\nLet S' be some contiguous substring of U with length N, and replace S with S'.\n\nAmong the strings that can be the string S after the K operations, find the lexicographically smallest possible one.\n\nConstraints\n\n1 \\leq N \\leq 5000\n\n1 \\leq K \\leq 10^9\n\n|S|=N\n\nS consists of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nS\n\nOutput\n\nPrint the lexicographically smallest possible string that can be the string S after the K operations.\n\nSample Input 1\n\n5 1\nbacba\n\nSample Output 1\n\naabca\n\nWhen S=bacba, T=abcab, U=bacbaabcab, and the optimal choice of S' is S'=aabca.\n\nSample Input 2\n\n10 2\nbbaabbbaab\n\nSample Output 2\n\naaaabbaabb", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 765, "cpu_time_ms": 2103, "memory_kb": 384}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s549461439", "group_id": "codeNet:p02945", "input_text": "//\n// Created by 伊東麻沙美 on 2019/10/22.\n//\n\n#include<iostream>\n#include<algorithm>\nusing namespace std;\n\n\nint main(){\n\n    int a,b;\n    cin>>a>>b;\n\n    int num1,num2,num3,max;\n    num1 = a+b;\n    num2 = a-b;\n    num3 = a*b;\n\n    max = num1;\n    if(max<num2){\n        max = num2;\n    }\n    if(max<num3){\n        max = num3;\n    }\n\n    cout<<max;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1571934615, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02945.html", "problem_id": "p02945", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02945/input.txt", "sample_output_relpath": "derived/input_output/data/p02945/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02945/C++/s549461439.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s549461439", "user_id": "u640466057"}, "prompt_components": {"gold_output": "-10\n", "input_to_evaluate": "//\n// Created by 伊東麻沙美 on 2019/10/22.\n//\n\n#include<iostream>\n#include<algorithm>\nusing namespace std;\n\n\nint main(){\n\n    int a,b;\n    cin>>a>>b;\n\n    int num1,num2,num3,max;\n    num1 = a+b;\n    num2 = a-b;\n    num3 = a*b;\n\n    max = num1;\n    if(max<num2){\n        max = num2;\n    }\n    if(max<num3){\n        max = num3;\n    }\n\n    cout<<max;\n    return 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nWe have two integers: A and B.\n\nPrint the largest number among A + B, A - B, and A \\times B.\n\nConstraints\n\nAll values in input are integers.\n\n-100 \\leq A,\\ B \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nPrint the largest number among A + B, A - B, and A \\times B.\n\nSample Input 1\n\n-13 3\n\nSample Output 1\n\n-10\n\nThe largest number among A + B = -10, A - B = -16, and A \\times B = -39 is -10.\n\nSample Input 2\n\n1 -33\n\nSample Output 2\n\n34\n\nThe largest number among A + B = -32, A - B = 34, and A \\times B = -33 is 34.\n\nSample Input 3\n\n13 3\n\nSample Output 3\n\n39\n\nThe largest number among A + B = 16, A - B = 10, and A \\times B = 39 is 39.", "sample_input": "-13 3\n"}, "reference_outputs": ["-10\n"], "source_document_id": "p02945", "source_text": "Score : 100 points\n\nProblem Statement\n\nWe have two integers: A and B.\n\nPrint the largest number among A + B, A - B, and A \\times B.\n\nConstraints\n\nAll values in input are integers.\n\n-100 \\leq A,\\ B \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nPrint the largest number among A + B, A - B, and A \\times B.\n\nSample Input 1\n\n-13 3\n\nSample Output 1\n\n-10\n\nThe largest number among A + B = -10, A - B = -16, and A \\times B = -39 is -10.\n\nSample Input 2\n\n1 -33\n\nSample Output 2\n\n34\n\nThe largest number among A + B = -32, A - B = 34, and A \\times B = -33 is 34.\n\nSample Input 3\n\n13 3\n\nSample Output 3\n\n39\n\nThe largest number among A + B = 16, A - B = 10, and A \\times B = 39 is 39.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 368, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s706460652", "group_id": "codeNet:p02946", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n    int k,x;cin>>k>>x;\n    int tmp;\n    \n    for(int i=0;i<2*(k-1);++i){\n    tmp=x-k+1+i;\n    cout<<tmp<<\" \";\n    }\n    tmp=x+k-1;\n    cout<<tmp<<endl;\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1586834920, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02946.html", "problem_id": "p02946", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02946/input.txt", "sample_output_relpath": "derived/input_output/data/p02946/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02946/C++/s706460652.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s706460652", "user_id": "u933962236"}, "prompt_components": {"gold_output": "5 6 7 8 9\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n    int k,x;cin>>k>>x;\n    int tmp;\n    \n    for(int i=0;i<2*(k-1);++i){\n    tmp=x-k+1+i;\n    cout<<tmp<<\" \";\n    }\n    tmp=x+k-1;\n    cout<<tmp<<endl;\n\treturn 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nThere are 2000001 stones placed on a number line. The coordinates of these stones are -1000000, -999999, -999998, \\ldots, 999999, 1000000.\n\nAmong them, some K consecutive stones are painted black, and the others are painted white.\n\nAdditionally, we know that the stone at coordinate X is painted black.\n\nPrint all coordinates that potentially contain a stone painted black, in ascending order.\n\nConstraints\n\n1 \\leq K \\leq 100\n\n0 \\leq X \\leq 100\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nK X\n\nOutput\n\nPrint all coordinates that potentially contain a stone painted black, in ascending order, with spaces in between.\n\nSample Input 1\n\n3 7\n\nSample Output 1\n\n5 6 7 8 9\n\nWe know that there are three stones painted black, and the stone at coordinate 7 is painted black. There are three possible cases:\n\nThe three stones painted black are placed at coordinates 5, 6, and 7.\n\nThe three stones painted black are placed at coordinates 6, 7, and 8.\n\nThe three stones painted black are placed at coordinates 7, 8, and 9.\n\nThus, five coordinates potentially contain a stone painted black: 5, 6, 7, 8, and 9.\n\nSample Input 2\n\n4 0\n\nSample Output 2\n\n-3 -2 -1 0 1 2 3\n\nNegative coordinates can also contain a stone painted black.\n\nSample Input 3\n\n1 100\n\nSample Output 3\n\n100", "sample_input": "3 7\n"}, "reference_outputs": ["5 6 7 8 9\n"], "source_document_id": "p02946", "source_text": "Score : 200 points\n\nProblem Statement\n\nThere are 2000001 stones placed on a number line. The coordinates of these stones are -1000000, -999999, -999998, \\ldots, 999999, 1000000.\n\nAmong them, some K consecutive stones are painted black, and the others are painted white.\n\nAdditionally, we know that the stone at coordinate X is painted black.\n\nPrint all coordinates that potentially contain a stone painted black, in ascending order.\n\nConstraints\n\n1 \\leq K \\leq 100\n\n0 \\leq X \\leq 100\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nK X\n\nOutput\n\nPrint all coordinates that potentially contain a stone painted black, in ascending order, with spaces in between.\n\nSample Input 1\n\n3 7\n\nSample Output 1\n\n5 6 7 8 9\n\nWe know that there are three stones painted black, and the stone at coordinate 7 is painted black. There are three possible cases:\n\nThe three stones painted black are placed at coordinates 5, 6, and 7.\n\nThe three stones painted black are placed at coordinates 6, 7, and 8.\n\nThe three stones painted black are placed at coordinates 7, 8, and 9.\n\nThus, five coordinates potentially contain a stone painted black: 5, 6, 7, 8, and 9.\n\nSample Input 2\n\n4 0\n\nSample Output 2\n\n-3 -2 -1 0 1 2 3\n\nNegative coordinates can also contain a stone painted black.\n\nSample Input 3\n\n1 100\n\nSample Output 3\n\n100", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 224, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s921613749", "group_id": "codeNet:p02947", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n \nint main() {\n  int n;\n  cin >> n;\n  \n  vector<vector<char>>x(n,vector<char>(10));\n  for(int i=0; i<n; i++){\n   for(int j=0; j<10; j++){\n     cin >> x[i][j];\n   }\n    sort(x.at(i).begin(),x.at(i).end());\n  }\n  \n  int ans=0;\n  \n  for(int i=0; i<n-1; i++){\n   for(int j=i+1; j<n; j++){\n     int count=0;\n     for(int k=0; k<10; k++){\n       if(x[i][k]==x[j][k]) count++;\n     }\n     if(count==10) ans++;\n   }\n  }\n  \n  cout << ans << endl;\n  \n}", "language": "C++", "metadata": {"date": 1585081643, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02947.html", "problem_id": "p02947", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02947/input.txt", "sample_output_relpath": "derived/input_output/data/p02947/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02947/C++/s921613749.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s921613749", "user_id": "u028906014"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n \nint main() {\n  int n;\n  cin >> n;\n  \n  vector<vector<char>>x(n,vector<char>(10));\n  for(int i=0; i<n; i++){\n   for(int j=0; j<10; j++){\n     cin >> x[i][j];\n   }\n    sort(x.at(i).begin(),x.at(i).end());\n  }\n  \n  int ans=0;\n  \n  for(int i=0; i<n-1; i++){\n   for(int j=i+1; j<n; j++){\n     int count=0;\n     for(int k=0; k<10; k++){\n       if(x[i][k]==x[j][k]) count++;\n     }\n     if(count==10) ans++;\n   }\n  }\n  \n  cout << ans << endl;\n  \n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nWe will call a string obtained by arranging the characters contained in a string a in some order, an anagram of a.\n\nFor example, greenbin is an anagram of beginner. As seen here, when the same character occurs multiple times, that character must be used that number of times.\n\nGiven are N strings s_1, s_2, \\ldots, s_N. Each of these strings has a length of 10 and consists of lowercase English characters. Additionally, all of these strings are distinct. Find the number of pairs of integers i, j (1 \\leq i < j \\leq N) such that s_i is an anagram of s_j.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\ns_i is a string of length 10.\n\nEach character in s_i is a lowercase English letter.\n\ns_1, s_2, \\ldots, s_N are all distinct.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\ns_1\ns_2\n:\ns_N\n\nOutput\n\nPrint the number of pairs of integers i, j (1 \\leq i < j \\leq N) such that s_i is an anagram of s_j.\n\nSample Input 1\n\n3\nacornistnt\npeanutbomb\nconstraint\n\nSample Output 1\n\n1\n\ns_1 = acornistnt is an anagram of s_3 = constraint. There are no other pairs i, j such that s_i is an anagram of s_j, so the answer is 1.\n\nSample Input 2\n\n2\noneplustwo\nninemodsix\n\nSample Output 2\n\n0\n\nIf there is no pair i, j such that s_i is an anagram of s_j, print 0.\n\nSample Input 3\n\n5\nabaaaaaaaa\noneplustwo\naaaaaaaaba\ntwoplusone\naaaabaaaaa\n\nSample Output 3\n\n4\n\nNote that the answer may not fit into a 32-bit integer type, though we cannot put such a case here.", "sample_input": "3\nacornistnt\npeanutbomb\nconstraint\n"}, "reference_outputs": ["1\n"], "source_document_id": "p02947", "source_text": "Score : 300 points\n\nProblem Statement\n\nWe will call a string obtained by arranging the characters contained in a string a in some order, an anagram of a.\n\nFor example, greenbin is an anagram of beginner. As seen here, when the same character occurs multiple times, that character must be used that number of times.\n\nGiven are N strings s_1, s_2, \\ldots, s_N. Each of these strings has a length of 10 and consists of lowercase English characters. Additionally, all of these strings are distinct. Find the number of pairs of integers i, j (1 \\leq i < j \\leq N) such that s_i is an anagram of s_j.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\ns_i is a string of length 10.\n\nEach character in s_i is a lowercase English letter.\n\ns_1, s_2, \\ldots, s_N are all distinct.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\ns_1\ns_2\n:\ns_N\n\nOutput\n\nPrint the number of pairs of integers i, j (1 \\leq i < j \\leq N) such that s_i is an anagram of s_j.\n\nSample Input 1\n\n3\nacornistnt\npeanutbomb\nconstraint\n\nSample Output 1\n\n1\n\ns_1 = acornistnt is an anagram of s_3 = constraint. There are no other pairs i, j such that s_i is an anagram of s_j, so the answer is 1.\n\nSample Input 2\n\n2\noneplustwo\nninemodsix\n\nSample Output 2\n\n0\n\nIf there is no pair i, j such that s_i is an anagram of s_j, print 0.\n\nSample Input 3\n\n5\nabaaaaaaaa\noneplustwo\naaaaaaaaba\ntwoplusone\naaaabaaaaa\n\nSample Output 3\n\n4\n\nNote that the answer may not fit into a 32-bit integer type, though we cannot put such a case here.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 488, "cpu_time_ms": 2106, "memory_kb": 5760}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s144910406", "group_id": "codeNet:p02947", "input_text": "#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\n\nusing namespace std;\n\nint main()\n{\n\tint N; cin >> N;\n\tstring s[N];\n\tint cc[N][26];\n\tfor(int i=0; i<N; i++) {\n\t\tcin >> s[i];\n\t\tfor (char c : s[i]) {\n\t\t\tint num = c - 'a';\n\t\t\tcc[i][num]++;\n\t\t}\n\t}\n\n\tlong long int ans = 0;\n\tfor (int i=0; i<N; i++) {\n\t\tfor (int j=i; j<N; j++) {\n\t\tbool isSame = true;\n\t\t\tfor (int k=0; k<26; k++) {\n\t\t\t\tif (cc[i][k] != cc[j][k]) {\n\t\t\t\t\tisSame = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (isSame) ans++;\n\t\t}\n\t}\n\n\tcout << ans;\n\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1565713228, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02947.html", "problem_id": "p02947", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02947/input.txt", "sample_output_relpath": "derived/input_output/data/p02947/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02947/C++/s144910406.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s144910406", "user_id": "u496279623"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\n\nusing namespace std;\n\nint main()\n{\n\tint N; cin >> N;\n\tstring s[N];\n\tint cc[N][26];\n\tfor(int i=0; i<N; i++) {\n\t\tcin >> s[i];\n\t\tfor (char c : s[i]) {\n\t\t\tint num = c - 'a';\n\t\t\tcc[i][num]++;\n\t\t}\n\t}\n\n\tlong long int ans = 0;\n\tfor (int i=0; i<N; i++) {\n\t\tfor (int j=i; j<N; j++) {\n\t\tbool isSame = true;\n\t\t\tfor (int k=0; k<26; k++) {\n\t\t\t\tif (cc[i][k] != cc[j][k]) {\n\t\t\t\t\tisSame = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (isSame) ans++;\n\t\t}\n\t}\n\n\tcout << ans;\n\n\treturn 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nWe will call a string obtained by arranging the characters contained in a string a in some order, an anagram of a.\n\nFor example, greenbin is an anagram of beginner. As seen here, when the same character occurs multiple times, that character must be used that number of times.\n\nGiven are N strings s_1, s_2, \\ldots, s_N. Each of these strings has a length of 10 and consists of lowercase English characters. Additionally, all of these strings are distinct. Find the number of pairs of integers i, j (1 \\leq i < j \\leq N) such that s_i is an anagram of s_j.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\ns_i is a string of length 10.\n\nEach character in s_i is a lowercase English letter.\n\ns_1, s_2, \\ldots, s_N are all distinct.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\ns_1\ns_2\n:\ns_N\n\nOutput\n\nPrint the number of pairs of integers i, j (1 \\leq i < j \\leq N) such that s_i is an anagram of s_j.\n\nSample Input 1\n\n3\nacornistnt\npeanutbomb\nconstraint\n\nSample Output 1\n\n1\n\ns_1 = acornistnt is an anagram of s_3 = constraint. There are no other pairs i, j such that s_i is an anagram of s_j, so the answer is 1.\n\nSample Input 2\n\n2\noneplustwo\nninemodsix\n\nSample Output 2\n\n0\n\nIf there is no pair i, j such that s_i is an anagram of s_j, print 0.\n\nSample Input 3\n\n5\nabaaaaaaaa\noneplustwo\naaaaaaaaba\ntwoplusone\naaaabaaaaa\n\nSample Output 3\n\n4\n\nNote that the answer may not fit into a 32-bit integer type, though we cannot put such a case here.", "sample_input": "3\nacornistnt\npeanutbomb\nconstraint\n"}, "reference_outputs": ["1\n"], "source_document_id": "p02947", "source_text": "Score : 300 points\n\nProblem Statement\n\nWe will call a string obtained by arranging the characters contained in a string a in some order, an anagram of a.\n\nFor example, greenbin is an anagram of beginner. As seen here, when the same character occurs multiple times, that character must be used that number of times.\n\nGiven are N strings s_1, s_2, \\ldots, s_N. Each of these strings has a length of 10 and consists of lowercase English characters. Additionally, all of these strings are distinct. Find the number of pairs of integers i, j (1 \\leq i < j \\leq N) such that s_i is an anagram of s_j.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\ns_i is a string of length 10.\n\nEach character in s_i is a lowercase English letter.\n\ns_1, s_2, \\ldots, s_N are all distinct.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\ns_1\ns_2\n:\ns_N\n\nOutput\n\nPrint the number of pairs of integers i, j (1 \\leq i < j \\leq N) such that s_i is an anagram of s_j.\n\nSample Input 1\n\n3\nacornistnt\npeanutbomb\nconstraint\n\nSample Output 1\n\n1\n\ns_1 = acornistnt is an anagram of s_3 = constraint. There are no other pairs i, j such that s_i is an anagram of s_j, so the answer is 1.\n\nSample Input 2\n\n2\noneplustwo\nninemodsix\n\nSample Output 2\n\n0\n\nIf there is no pair i, j such that s_i is an anagram of s_j, print 0.\n\nSample Input 3\n\n5\nabaaaaaaaa\noneplustwo\naaaaaaaaba\ntwoplusone\naaaabaaaaa\n\nSample Output 3\n\n4\n\nNote that the answer may not fit into a 32-bit integer type, though we cannot put such a case here.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 538, "cpu_time_ms": 2104, "memory_kb": 19508}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s576125264", "group_id": "codeNet:p02948", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n\n#define Q int t; scanf(\"%d\", &t); for(int q=1; q<=t; q++)\ntypedef long long int lli;\ntypedef pair<lli, lli> pi;\n\n\nint main()\n{\n    int n, m;\n    cin >> n >> m;\n    priority_queue<lli>pq;\n    vector<pi> v;\n    for(int i=0; i<n; i++){\n        lli a, b;\n        cin >> a >> b;\n        v.push_back({a, b});\n    }\n    sort(v.begin(), v.end());\n    int j=0;\n    lli ans = 0;\n    for(int i=1; i<=m; i++){\n        while(j<n && v[j].first <= i){\n            pq.push(v[j].second);\n            j++;\n        }\n        if(!pq.empty()){\n            ans += pq.top();\n            pq.pop();\n        }\n    }\n\n    cout << ans << \"\\n\";\n\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1588050655, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02948.html", "problem_id": "p02948", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02948/input.txt", "sample_output_relpath": "derived/input_output/data/p02948/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02948/C++/s576125264.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s576125264", "user_id": "u571794900"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n\n#define Q int t; scanf(\"%d\", &t); for(int q=1; q<=t; q++)\ntypedef long long int lli;\ntypedef pair<lli, lli> pi;\n\n\nint main()\n{\n    int n, m;\n    cin >> n >> m;\n    priority_queue<lli>pq;\n    vector<pi> v;\n    for(int i=0; i<n; i++){\n        lli a, b;\n        cin >> a >> b;\n        v.push_back({a, b});\n    }\n    sort(v.begin(), v.end());\n    int j=0;\n    lli ans = 0;\n    for(int i=1; i<=m; i++){\n        while(j<n && v[j].first <= i){\n            pq.push(v[j].second);\n            j++;\n        }\n        if(!pq.empty()){\n            ans += pq.top();\n            pq.pop();\n        }\n    }\n\n    cout << ans << \"\\n\";\n\n    return 0;\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nThere are N one-off jobs available. If you take the i-th job and complete it, you will earn the reward of B_i after A_i days from the day you do it.\n\nYou can take and complete at most one of these jobs in a day.\n\nHowever, you cannot retake a job that you have already done.\n\nFind the maximum total reward that you can earn no later than M days from today.\n\nYou can already start working today.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq A_i \\leq 10^5\n\n1 \\leq B_i \\leq 10^4\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 B_1\nA_2 B_2\n\\vdots\nA_N B_N\n\nOutput\n\nPrint the maximum total reward that you can earn no later than M days from today.\n\nSample Input 1\n\n3 4\n4 3\n4 1\n2 2\n\nSample Output 1\n\n5\n\nYou can earn the total reward of 5 by taking the jobs as follows:\n\nTake and complete the first job today. You will earn the reward of 3 after four days from today.\n\nTake and complete the third job tomorrow. You will earn the reward of 2 after two days from tomorrow, that is, after three days from today.\n\nSample Input 2\n\n5 3\n1 2\n1 3\n1 4\n2 1\n2 3\n\nSample Output 2\n\n10\n\nSample Input 3\n\n1 1\n2 1\n\nSample Output 3\n\n0", "sample_input": "3 4\n4 3\n4 1\n2 2\n"}, "reference_outputs": ["5\n"], "source_document_id": "p02948", "source_text": "Score : 400 points\n\nProblem Statement\n\nThere are N one-off jobs available. If you take the i-th job and complete it, you will earn the reward of B_i after A_i days from the day you do it.\n\nYou can take and complete at most one of these jobs in a day.\n\nHowever, you cannot retake a job that you have already done.\n\nFind the maximum total reward that you can earn no later than M days from today.\n\nYou can already start working today.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq A_i \\leq 10^5\n\n1 \\leq B_i \\leq 10^4\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 B_1\nA_2 B_2\n\\vdots\nA_N B_N\n\nOutput\n\nPrint the maximum total reward that you can earn no later than M days from today.\n\nSample Input 1\n\n3 4\n4 3\n4 1\n2 2\n\nSample Output 1\n\n5\n\nYou can earn the total reward of 5 by taking the jobs as follows:\n\nTake and complete the first job today. You will earn the reward of 3 after four days from today.\n\nTake and complete the third job tomorrow. You will earn the reward of 2 after two days from tomorrow, that is, after three days from today.\n\nSample Input 2\n\n5 3\n1 2\n1 3\n1 4\n2 1\n2 3\n\nSample Output 2\n\n10\n\nSample Input 3\n\n1 1\n2 1\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 679, "cpu_time_ms": 68, "memory_kb": 3568}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s169964312", "group_id": "codeNet:p02948", "input_text": "#include <bits/stdc++.h>\n#define int long long\nusing namespace std;\n\nsigned main(){\n\tint N,M; cin>>N>>M;\n\tvector<pair<int,int>> AB(N);\n\tfor(int i=0;i<N;i++){\n\t\tcin>>AB[i].first>>AB[i].second;\n\t}\n\tsort(AB.begin(),AB.end());\n\tint p=0,ans=0;\n\tpriority_queue<pair<int,int>> que;\n\tfor(int i=1;i<=M;i++){\n\t\twhile(AB[p].first<=i and p<N){\n\t\t\tpair<int,int> tmp=make_pair(AB[p].second,AB[p].first);\n\t\t\tque.push(tmp);\n\t\t\tp++;\n\t\t}\n\t\tif(not que.empty()){\n\t\t\tpair<int,int> tmp=que.top();\n\t\t\tque.pop();\n\t\t\tans+=tmp.first;\n\t\t}\n\t}\n\tcout<<ans<<endl;\n\treturn 0;\n\n}", "language": "C++", "metadata": {"date": 1585408200, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02948.html", "problem_id": "p02948", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02948/input.txt", "sample_output_relpath": "derived/input_output/data/p02948/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02948/C++/s169964312.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s169964312", "user_id": "u176979814"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define int long long\nusing namespace std;\n\nsigned main(){\n\tint N,M; cin>>N>>M;\n\tvector<pair<int,int>> AB(N);\n\tfor(int i=0;i<N;i++){\n\t\tcin>>AB[i].first>>AB[i].second;\n\t}\n\tsort(AB.begin(),AB.end());\n\tint p=0,ans=0;\n\tpriority_queue<pair<int,int>> que;\n\tfor(int i=1;i<=M;i++){\n\t\twhile(AB[p].first<=i and p<N){\n\t\t\tpair<int,int> tmp=make_pair(AB[p].second,AB[p].first);\n\t\t\tque.push(tmp);\n\t\t\tp++;\n\t\t}\n\t\tif(not que.empty()){\n\t\t\tpair<int,int> tmp=que.top();\n\t\t\tque.pop();\n\t\t\tans+=tmp.first;\n\t\t}\n\t}\n\tcout<<ans<<endl;\n\treturn 0;\n\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nThere are N one-off jobs available. If you take the i-th job and complete it, you will earn the reward of B_i after A_i days from the day you do it.\n\nYou can take and complete at most one of these jobs in a day.\n\nHowever, you cannot retake a job that you have already done.\n\nFind the maximum total reward that you can earn no later than M days from today.\n\nYou can already start working today.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq A_i \\leq 10^5\n\n1 \\leq B_i \\leq 10^4\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 B_1\nA_2 B_2\n\\vdots\nA_N B_N\n\nOutput\n\nPrint the maximum total reward that you can earn no later than M days from today.\n\nSample Input 1\n\n3 4\n4 3\n4 1\n2 2\n\nSample Output 1\n\n5\n\nYou can earn the total reward of 5 by taking the jobs as follows:\n\nTake and complete the first job today. You will earn the reward of 3 after four days from today.\n\nTake and complete the third job tomorrow. You will earn the reward of 2 after two days from tomorrow, that is, after three days from today.\n\nSample Input 2\n\n5 3\n1 2\n1 3\n1 4\n2 1\n2 3\n\nSample Output 2\n\n10\n\nSample Input 3\n\n1 1\n2 1\n\nSample Output 3\n\n0", "sample_input": "3 4\n4 3\n4 1\n2 2\n"}, "reference_outputs": ["5\n"], "source_document_id": "p02948", "source_text": "Score : 400 points\n\nProblem Statement\n\nThere are N one-off jobs available. If you take the i-th job and complete it, you will earn the reward of B_i after A_i days from the day you do it.\n\nYou can take and complete at most one of these jobs in a day.\n\nHowever, you cannot retake a job that you have already done.\n\nFind the maximum total reward that you can earn no later than M days from today.\n\nYou can already start working today.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq A_i \\leq 10^5\n\n1 \\leq B_i \\leq 10^4\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 B_1\nA_2 B_2\n\\vdots\nA_N B_N\n\nOutput\n\nPrint the maximum total reward that you can earn no later than M days from today.\n\nSample Input 1\n\n3 4\n4 3\n4 1\n2 2\n\nSample Output 1\n\n5\n\nYou can earn the total reward of 5 by taking the jobs as follows:\n\nTake and complete the first job today. You will earn the reward of 3 after four days from today.\n\nTake and complete the third job tomorrow. You will earn the reward of 2 after two days from tomorrow, that is, after three days from today.\n\nSample Input 2\n\n5 3\n1 2\n1 3\n1 4\n2 1\n2 3\n\nSample Output 2\n\n10\n\nSample Input 3\n\n1 1\n2 1\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 546, "cpu_time_ms": 73, "memory_kb": 3956}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s357158814", "group_id": "codeNet:p02948", "input_text": "#include <memory.h>\n\n#include <algorithm>\n#include <bitset>\n#include <cmath>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <deque>\n#include <iomanip>\n#include <iostream>\n#include <list>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <stack>\n#include <utility>\n#include <vector>\n\nusing namespace std;\n\n#define mod 1000000007\n\nint main() {\n\tint n, m;\n\tcin >> n >> m;\n\tvector<pair<int, int> > ab;\n\tfor (int i = 0; i < n; i++) {\n\t\tint a, b;\n\t\tcin >> a >> b;\n\t\tab.push_back(make_pair(a, b));\n\t}\n\tsort(ab.begin(), ab.end());\n\tlong long int ans = 0;\n\tint cnt = 0;\n\tpriority_queue<int> qu;\n\tfor (int i = 0; i <= m; i++) {\n\t\tif (!qu.empty()) {\n\t\t\tans += qu.top();\n\t\t\tqu.pop();\n\t\t}\n\t\twhile (cnt < n && ab[cnt].first <= i + 1) {\n\t\t\tqu.push(ab[cnt].second);\n\t\t\tcnt++;\n\t\t}\n\t}\n\tcout << ans << endl;\n}", "language": "C++", "metadata": {"date": 1584675295, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02948.html", "problem_id": "p02948", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02948/input.txt", "sample_output_relpath": "derived/input_output/data/p02948/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02948/C++/s357158814.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s357158814", "user_id": "u261965335"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include <memory.h>\n\n#include <algorithm>\n#include <bitset>\n#include <cmath>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <deque>\n#include <iomanip>\n#include <iostream>\n#include <list>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <stack>\n#include <utility>\n#include <vector>\n\nusing namespace std;\n\n#define mod 1000000007\n\nint main() {\n\tint n, m;\n\tcin >> n >> m;\n\tvector<pair<int, int> > ab;\n\tfor (int i = 0; i < n; i++) {\n\t\tint a, b;\n\t\tcin >> a >> b;\n\t\tab.push_back(make_pair(a, b));\n\t}\n\tsort(ab.begin(), ab.end());\n\tlong long int ans = 0;\n\tint cnt = 0;\n\tpriority_queue<int> qu;\n\tfor (int i = 0; i <= m; i++) {\n\t\tif (!qu.empty()) {\n\t\t\tans += qu.top();\n\t\t\tqu.pop();\n\t\t}\n\t\twhile (cnt < n && ab[cnt].first <= i + 1) {\n\t\t\tqu.push(ab[cnt].second);\n\t\t\tcnt++;\n\t\t}\n\t}\n\tcout << ans << endl;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nThere are N one-off jobs available. If you take the i-th job and complete it, you will earn the reward of B_i after A_i days from the day you do it.\n\nYou can take and complete at most one of these jobs in a day.\n\nHowever, you cannot retake a job that you have already done.\n\nFind the maximum total reward that you can earn no later than M days from today.\n\nYou can already start working today.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq A_i \\leq 10^5\n\n1 \\leq B_i \\leq 10^4\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 B_1\nA_2 B_2\n\\vdots\nA_N B_N\n\nOutput\n\nPrint the maximum total reward that you can earn no later than M days from today.\n\nSample Input 1\n\n3 4\n4 3\n4 1\n2 2\n\nSample Output 1\n\n5\n\nYou can earn the total reward of 5 by taking the jobs as follows:\n\nTake and complete the first job today. You will earn the reward of 3 after four days from today.\n\nTake and complete the third job tomorrow. You will earn the reward of 2 after two days from tomorrow, that is, after three days from today.\n\nSample Input 2\n\n5 3\n1 2\n1 3\n1 4\n2 1\n2 3\n\nSample Output 2\n\n10\n\nSample Input 3\n\n1 1\n2 1\n\nSample Output 3\n\n0", "sample_input": "3 4\n4 3\n4 1\n2 2\n"}, "reference_outputs": ["5\n"], "source_document_id": "p02948", "source_text": "Score : 400 points\n\nProblem Statement\n\nThere are N one-off jobs available. If you take the i-th job and complete it, you will earn the reward of B_i after A_i days from the day you do it.\n\nYou can take and complete at most one of these jobs in a day.\n\nHowever, you cannot retake a job that you have already done.\n\nFind the maximum total reward that you can earn no later than M days from today.\n\nYou can already start working today.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq A_i \\leq 10^5\n\n1 \\leq B_i \\leq 10^4\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 B_1\nA_2 B_2\n\\vdots\nA_N B_N\n\nOutput\n\nPrint the maximum total reward that you can earn no later than M days from today.\n\nSample Input 1\n\n3 4\n4 3\n4 1\n2 2\n\nSample Output 1\n\n5\n\nYou can earn the total reward of 5 by taking the jobs as follows:\n\nTake and complete the first job today. You will earn the reward of 3 after four days from today.\n\nTake and complete the third job tomorrow. You will earn the reward of 2 after two days from tomorrow, that is, after three days from today.\n\nSample Input 2\n\n5 3\n1 2\n1 3\n1 4\n2 1\n2 3\n\nSample Output 2\n\n10\n\nSample Input 3\n\n1 1\n2 1\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 852, "cpu_time_ms": 68, "memory_kb": 1908}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s903198876", "group_id": "codeNet:p02948", "input_text": "#include<iostream>\n#include<algorithm>\n#include<queue>\nusing lint=int64_t;\nusing namespace std;\n\nbool cmp(pair<lint,lint> l,pair<lint,lint> r)\n{\n\tif(l.first!=r.first)\n\t\treturn l.first>r.first;\n\treturn l.second>r.second;\n}\n\nint main()\n{\n\tlint N,M;\n\tpair<lint,lint> p[100010]{};\n\n\tcin >> N >> M;\n\tfor(lint i=0;i<N;i++)\n\t{\n\t\tcin >> p[i].first;\n\t\tcin >> p[i].second;\n\t}\n\n\tsort(p,p+N);\n\n\tpriority_queue<lint> que;\n\tlint index=0;\n\tlint ans=0;\n\tfor(lint i=1;i<=M;i++)\n\t{\n\t\twhile(index<N && p[index].first<=i)\n\t\t{\n\t\t\tque.push(p[index].second);\n\t\t\tindex++;\n\t\t}\n\n\t\tif(!que.empty())\n\t\t{\n\t\t\tans+=que.top();\n\t\t\tque.pop();\n\t\t}\n\t}\n\n\tcout << ans << endl;\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1565492177, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02948.html", "problem_id": "p02948", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02948/input.txt", "sample_output_relpath": "derived/input_output/data/p02948/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02948/C++/s903198876.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s903198876", "user_id": "u021423660"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include<iostream>\n#include<algorithm>\n#include<queue>\nusing lint=int64_t;\nusing namespace std;\n\nbool cmp(pair<lint,lint> l,pair<lint,lint> r)\n{\n\tif(l.first!=r.first)\n\t\treturn l.first>r.first;\n\treturn l.second>r.second;\n}\n\nint main()\n{\n\tlint N,M;\n\tpair<lint,lint> p[100010]{};\n\n\tcin >> N >> M;\n\tfor(lint i=0;i<N;i++)\n\t{\n\t\tcin >> p[i].first;\n\t\tcin >> p[i].second;\n\t}\n\n\tsort(p,p+N);\n\n\tpriority_queue<lint> que;\n\tlint index=0;\n\tlint ans=0;\n\tfor(lint i=1;i<=M;i++)\n\t{\n\t\twhile(index<N && p[index].first<=i)\n\t\t{\n\t\t\tque.push(p[index].second);\n\t\t\tindex++;\n\t\t}\n\n\t\tif(!que.empty())\n\t\t{\n\t\t\tans+=que.top();\n\t\t\tque.pop();\n\t\t}\n\t}\n\n\tcout << ans << endl;\n\treturn 0;\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nThere are N one-off jobs available. If you take the i-th job and complete it, you will earn the reward of B_i after A_i days from the day you do it.\n\nYou can take and complete at most one of these jobs in a day.\n\nHowever, you cannot retake a job that you have already done.\n\nFind the maximum total reward that you can earn no later than M days from today.\n\nYou can already start working today.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq A_i \\leq 10^5\n\n1 \\leq B_i \\leq 10^4\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 B_1\nA_2 B_2\n\\vdots\nA_N B_N\n\nOutput\n\nPrint the maximum total reward that you can earn no later than M days from today.\n\nSample Input 1\n\n3 4\n4 3\n4 1\n2 2\n\nSample Output 1\n\n5\n\nYou can earn the total reward of 5 by taking the jobs as follows:\n\nTake and complete the first job today. You will earn the reward of 3 after four days from today.\n\nTake and complete the third job tomorrow. You will earn the reward of 2 after two days from tomorrow, that is, after three days from today.\n\nSample Input 2\n\n5 3\n1 2\n1 3\n1 4\n2 1\n2 3\n\nSample Output 2\n\n10\n\nSample Input 3\n\n1 1\n2 1\n\nSample Output 3\n\n0", "sample_input": "3 4\n4 3\n4 1\n2 2\n"}, "reference_outputs": ["5\n"], "source_document_id": "p02948", "source_text": "Score : 400 points\n\nProblem Statement\n\nThere are N one-off jobs available. If you take the i-th job and complete it, you will earn the reward of B_i after A_i days from the day you do it.\n\nYou can take and complete at most one of these jobs in a day.\n\nHowever, you cannot retake a job that you have already done.\n\nFind the maximum total reward that you can earn no later than M days from today.\n\nYou can already start working today.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq A_i \\leq 10^5\n\n1 \\leq B_i \\leq 10^4\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 B_1\nA_2 B_2\n\\vdots\nA_N B_N\n\nOutput\n\nPrint the maximum total reward that you can earn no later than M days from today.\n\nSample Input 1\n\n3 4\n4 3\n4 1\n2 2\n\nSample Output 1\n\n5\n\nYou can earn the total reward of 5 by taking the jobs as follows:\n\nTake and complete the first job today. You will earn the reward of 3 after four days from today.\n\nTake and complete the third job tomorrow. You will earn the reward of 2 after two days from tomorrow, that is, after three days from today.\n\nSample Input 2\n\n5 3\n1 2\n1 3\n1 4\n2 1\n2 3\n\nSample Output 2\n\n10\n\nSample Input 3\n\n1 1\n2 1\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 652, "cpu_time_ms": 67, "memory_kb": 2936}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s016979875", "group_id": "codeNet:p02948", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing pii = pair<int, int>;\nusing vi = vector<int>;\nusing vl = vector<ll>;\n#define rep(i, n) for(ll i = 0;i < n;i++)\n#define all(i) i.begin(), i.end()\ntemplate<class T, class U> bool cmax(T& a, U b) { if (a<b) {a = b; return true;} else return false; }\ntemplate<class T, class U> bool cmin(T& a, U b) { if (a>b) {a = b; return true;} else return false; }\n\nint n, m;\n\nbool comp(const pii &l, const pii &r){\n  return l.second > r.second;\n}\n\nint main() {\n  cin.tie(0); ios::sync_with_stdio(false);\n\n  cin >> n >> m;\n  vector<pair<ll, ll>> a(n);\n  rep(i, n) {\n    cin >> a[i].first >> a[i].second;\n  }\n\n  sort(all(a), comp);\n\n//  cerr << endl;\n//  rep(i, n) {\n//    cerr << a[i].first << \" \" << a[i].second << endl;\n//  }\n//  cerr << endl;\n\n  multimap<int, ll> d;\n  int i = 0;\n  int j = 0;\n  ll ans = 0;\n  while(j < n && i <= m) {\n    //cerr << i << \" \" << j << endl;\n    if (m >= i+a[j].first) {\n      ans += a[j].second;\n      d.insert({m-a[i].first, i});\n      i++;\n      j++;\n    } else {\n      auto ite = d.lower_bound(i);\n      if (ite != d.end() && (*ite).second <= m-a[j].first) {\n        auto tmp = *ite;\n        d.erase(ite);\n        d.insert({tmp.first, i});\n        ans += a[j].second;\n        i++;\n        j++;\n      } else {\n        j++;\n      }\n    }\n  }\n\n  cout << ans << endl;\n}\n", "language": "C++", "metadata": {"date": 1565490709, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02948.html", "problem_id": "p02948", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02948/input.txt", "sample_output_relpath": "derived/input_output/data/p02948/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02948/C++/s016979875.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s016979875", "user_id": "u366644013"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing pii = pair<int, int>;\nusing vi = vector<int>;\nusing vl = vector<ll>;\n#define rep(i, n) for(ll i = 0;i < n;i++)\n#define all(i) i.begin(), i.end()\ntemplate<class T, class U> bool cmax(T& a, U b) { if (a<b) {a = b; return true;} else return false; }\ntemplate<class T, class U> bool cmin(T& a, U b) { if (a>b) {a = b; return true;} else return false; }\n\nint n, m;\n\nbool comp(const pii &l, const pii &r){\n  return l.second > r.second;\n}\n\nint main() {\n  cin.tie(0); ios::sync_with_stdio(false);\n\n  cin >> n >> m;\n  vector<pair<ll, ll>> a(n);\n  rep(i, n) {\n    cin >> a[i].first >> a[i].second;\n  }\n\n  sort(all(a), comp);\n\n//  cerr << endl;\n//  rep(i, n) {\n//    cerr << a[i].first << \" \" << a[i].second << endl;\n//  }\n//  cerr << endl;\n\n  multimap<int, ll> d;\n  int i = 0;\n  int j = 0;\n  ll ans = 0;\n  while(j < n && i <= m) {\n    //cerr << i << \" \" << j << endl;\n    if (m >= i+a[j].first) {\n      ans += a[j].second;\n      d.insert({m-a[i].first, i});\n      i++;\n      j++;\n    } else {\n      auto ite = d.lower_bound(i);\n      if (ite != d.end() && (*ite).second <= m-a[j].first) {\n        auto tmp = *ite;\n        d.erase(ite);\n        d.insert({tmp.first, i});\n        ans += a[j].second;\n        i++;\n        j++;\n      } else {\n        j++;\n      }\n    }\n  }\n\n  cout << ans << endl;\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nThere are N one-off jobs available. If you take the i-th job and complete it, you will earn the reward of B_i after A_i days from the day you do it.\n\nYou can take and complete at most one of these jobs in a day.\n\nHowever, you cannot retake a job that you have already done.\n\nFind the maximum total reward that you can earn no later than M days from today.\n\nYou can already start working today.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq A_i \\leq 10^5\n\n1 \\leq B_i \\leq 10^4\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 B_1\nA_2 B_2\n\\vdots\nA_N B_N\n\nOutput\n\nPrint the maximum total reward that you can earn no later than M days from today.\n\nSample Input 1\n\n3 4\n4 3\n4 1\n2 2\n\nSample Output 1\n\n5\n\nYou can earn the total reward of 5 by taking the jobs as follows:\n\nTake and complete the first job today. You will earn the reward of 3 after four days from today.\n\nTake and complete the third job tomorrow. You will earn the reward of 2 after two days from tomorrow, that is, after three days from today.\n\nSample Input 2\n\n5 3\n1 2\n1 3\n1 4\n2 1\n2 3\n\nSample Output 2\n\n10\n\nSample Input 3\n\n1 1\n2 1\n\nSample Output 3\n\n0", "sample_input": "3 4\n4 3\n4 1\n2 2\n"}, "reference_outputs": ["5\n"], "source_document_id": "p02948", "source_text": "Score : 400 points\n\nProblem Statement\n\nThere are N one-off jobs available. If you take the i-th job and complete it, you will earn the reward of B_i after A_i days from the day you do it.\n\nYou can take and complete at most one of these jobs in a day.\n\nHowever, you cannot retake a job that you have already done.\n\nFind the maximum total reward that you can earn no later than M days from today.\n\nYou can already start working today.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq A_i \\leq 10^5\n\n1 \\leq B_i \\leq 10^4\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 B_1\nA_2 B_2\n\\vdots\nA_N B_N\n\nOutput\n\nPrint the maximum total reward that you can earn no later than M days from today.\n\nSample Input 1\n\n3 4\n4 3\n4 1\n2 2\n\nSample Output 1\n\n5\n\nYou can earn the total reward of 5 by taking the jobs as follows:\n\nTake and complete the first job today. You will earn the reward of 3 after four days from today.\n\nTake and complete the third job tomorrow. You will earn the reward of 2 after two days from tomorrow, that is, after three days from today.\n\nSample Input 2\n\n5 3\n1 2\n1 3\n1 4\n2 1\n2 3\n\nSample Output 2\n\n10\n\nSample Input 3\n\n1 1\n2 1\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1360, "cpu_time_ms": 49, "memory_kb": 8064}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s452436352", "group_id": "codeNet:p02948", "input_text": "\n#include<iostream>\n#include<algorithm>\n#include<cstdio>\n#include<cmath>\n#include<cctype>\n#include<math.h>\n#include<string>\n#include<string.h>\n#include<stack>\n#include<queue>\n#include<vector>\n#include<utility>\n#include<set>\n#include<map>\n#include<stdlib.h>\n#include<iomanip>\n#include<complex>\n\nusing namespace std;\n\n#define ll long long\n#define ld long double\n#define EPS 1e-9\n#define INF 1e9\n#define LINF (ll)INF*INF\n#define MOD 1000000007\n#define rep(i,n) for(int i=0;i<(n);i++)\n#define loop(i,a,n) for(int i=a;i<(n);i++)\n#define all(in) in.begin(),in.end()\n#define shosu(x) fixed<<setprecision(x)\n\n#define int ll //!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!\n\ntypedef vector<int> vi;\ntypedef vector<string> vs;\ntypedef pair<int,int> pii;\ntypedef pair<pii,int> ppi;\ntypedef pair<int,pii> pip;\ntypedef vector<pii> vp;\ntypedef vector<vi> vvi;\n\nint gcd(int a, int b){if(b==0) return a;return gcd(b,a%b);}\nint lcm(int a, int b){return a/gcd(a,b)*b;}\n\n\nsigned main(void) {\n    int n,m;\n    cin >> n >> m;\n    vvi v(m);\n    rep(i,n){\n        int a,b;\n        cin >> a >> b;\n        if(m-a >= 0 && m-a < m)v[m-a].push_back(b);\n    }\n    int ans = 0;\n    priority_queue<int> q;\n    rep(i,m){\n        int now = m-i-1;\n        rep(j,v[now].size()){\n            //cout << \"!\" << v[now][j] << endl;\n            q.push(v[now][j]);\n        }\n        if(q.size()){\n            ans += q.top();\n            q.pop();\n        }\n    }\n    cout << ans << endl;\n}\n", "language": "C++", "metadata": {"date": 1565486236, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02948.html", "problem_id": "p02948", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02948/input.txt", "sample_output_relpath": "derived/input_output/data/p02948/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02948/C++/s452436352.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s452436352", "user_id": "u471289663"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "\n#include<iostream>\n#include<algorithm>\n#include<cstdio>\n#include<cmath>\n#include<cctype>\n#include<math.h>\n#include<string>\n#include<string.h>\n#include<stack>\n#include<queue>\n#include<vector>\n#include<utility>\n#include<set>\n#include<map>\n#include<stdlib.h>\n#include<iomanip>\n#include<complex>\n\nusing namespace std;\n\n#define ll long long\n#define ld long double\n#define EPS 1e-9\n#define INF 1e9\n#define LINF (ll)INF*INF\n#define MOD 1000000007\n#define rep(i,n) for(int i=0;i<(n);i++)\n#define loop(i,a,n) for(int i=a;i<(n);i++)\n#define all(in) in.begin(),in.end()\n#define shosu(x) fixed<<setprecision(x)\n\n#define int ll //!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!\n\ntypedef vector<int> vi;\ntypedef vector<string> vs;\ntypedef pair<int,int> pii;\ntypedef pair<pii,int> ppi;\ntypedef pair<int,pii> pip;\ntypedef vector<pii> vp;\ntypedef vector<vi> vvi;\n\nint gcd(int a, int b){if(b==0) return a;return gcd(b,a%b);}\nint lcm(int a, int b){return a/gcd(a,b)*b;}\n\n\nsigned main(void) {\n    int n,m;\n    cin >> n >> m;\n    vvi v(m);\n    rep(i,n){\n        int a,b;\n        cin >> a >> b;\n        if(m-a >= 0 && m-a < m)v[m-a].push_back(b);\n    }\n    int ans = 0;\n    priority_queue<int> q;\n    rep(i,m){\n        int now = m-i-1;\n        rep(j,v[now].size()){\n            //cout << \"!\" << v[now][j] << endl;\n            q.push(v[now][j]);\n        }\n        if(q.size()){\n            ans += q.top();\n            q.pop();\n        }\n    }\n    cout << ans << endl;\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nThere are N one-off jobs available. If you take the i-th job and complete it, you will earn the reward of B_i after A_i days from the day you do it.\n\nYou can take and complete at most one of these jobs in a day.\n\nHowever, you cannot retake a job that you have already done.\n\nFind the maximum total reward that you can earn no later than M days from today.\n\nYou can already start working today.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq A_i \\leq 10^5\n\n1 \\leq B_i \\leq 10^4\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 B_1\nA_2 B_2\n\\vdots\nA_N B_N\n\nOutput\n\nPrint the maximum total reward that you can earn no later than M days from today.\n\nSample Input 1\n\n3 4\n4 3\n4 1\n2 2\n\nSample Output 1\n\n5\n\nYou can earn the total reward of 5 by taking the jobs as follows:\n\nTake and complete the first job today. You will earn the reward of 3 after four days from today.\n\nTake and complete the third job tomorrow. You will earn the reward of 2 after two days from tomorrow, that is, after three days from today.\n\nSample Input 2\n\n5 3\n1 2\n1 3\n1 4\n2 1\n2 3\n\nSample Output 2\n\n10\n\nSample Input 3\n\n1 1\n2 1\n\nSample Output 3\n\n0", "sample_input": "3 4\n4 3\n4 1\n2 2\n"}, "reference_outputs": ["5\n"], "source_document_id": "p02948", "source_text": "Score : 400 points\n\nProblem Statement\n\nThere are N one-off jobs available. If you take the i-th job and complete it, you will earn the reward of B_i after A_i days from the day you do it.\n\nYou can take and complete at most one of these jobs in a day.\n\nHowever, you cannot retake a job that you have already done.\n\nFind the maximum total reward that you can earn no later than M days from today.\n\nYou can already start working today.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq A_i \\leq 10^5\n\n1 \\leq B_i \\leq 10^4\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 B_1\nA_2 B_2\n\\vdots\nA_N B_N\n\nOutput\n\nPrint the maximum total reward that you can earn no later than M days from today.\n\nSample Input 1\n\n3 4\n4 3\n4 1\n2 2\n\nSample Output 1\n\n5\n\nYou can earn the total reward of 5 by taking the jobs as follows:\n\nTake and complete the first job today. You will earn the reward of 3 after four days from today.\n\nTake and complete the third job tomorrow. You will earn the reward of 2 after two days from tomorrow, that is, after three days from today.\n\nSample Input 2\n\n5 3\n1 2\n1 3\n1 4\n2 1\n2 3\n\nSample Output 2\n\n10\n\nSample Input 3\n\n1 1\n2 1\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1452, "cpu_time_ms": 69, "memory_kb": 5632}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s708914205", "group_id": "codeNet:p02951", "input_text": "#include <stdio.h>\n\nint main()\n{\n    int a,b,c;\n    scanf(\"%d %d %d\",&a,&b,&c);\n    int ans=c-a+b;\n    printf(\"%d\",ans);\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1565841546, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02951.html", "problem_id": "p02951", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02951/input.txt", "sample_output_relpath": "derived/input_output/data/p02951/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02951/C++/s708914205.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s708914205", "user_id": "u493708099"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <stdio.h>\n\nint main()\n{\n    int a,b,c;\n    scanf(\"%d %d %d\",&a,&b,&c);\n    int ans=c-a+b;\n    printf(\"%d\",ans);\n    return 0;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nWe have two bottles for holding water.\n\nBottle 1 can hold up to A milliliters of water, and now it contains B milliliters of water.\n\nBottle 2 contains C milliliters of water.\n\nWe will transfer water from Bottle 2 to Bottle 1 as much as possible.\n\nHow much amount of water will remain in Bottle 2?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq B \\leq A \\leq 20\n\n1 \\leq C \\leq 20\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B C\n\nOutput\n\nPrint the integer representing the amount of water, in milliliters, that will remain in Bottle 2.\n\nSample Input 1\n\n6 4 3\n\nSample Output 1\n\n1\n\nWe will transfer two milliliters of water from Bottle 2 to Bottle 1, and one milliliter of water will remain in Bottle 2.\n\nSample Input 2\n\n8 3 9\n\nSample Output 2\n\n4\n\nSample Input 3\n\n12 3 7\n\nSample Output 3\n\n0", "sample_input": "6 4 3\n"}, "reference_outputs": ["1\n"], "source_document_id": "p02951", "source_text": "Score : 100 points\n\nProblem Statement\n\nWe have two bottles for holding water.\n\nBottle 1 can hold up to A milliliters of water, and now it contains B milliliters of water.\n\nBottle 2 contains C milliliters of water.\n\nWe will transfer water from Bottle 2 to Bottle 1 as much as possible.\n\nHow much amount of water will remain in Bottle 2?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq B \\leq A \\leq 20\n\n1 \\leq C \\leq 20\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B C\n\nOutput\n\nPrint the integer representing the amount of water, in milliliters, that will remain in Bottle 2.\n\nSample Input 1\n\n6 4 3\n\nSample Output 1\n\n1\n\nWe will transfer two milliliters of water from Bottle 2 to Bottle 1, and one milliliter of water will remain in Bottle 2.\n\nSample Input 2\n\n8 3 9\n\nSample Output 2\n\n4\n\nSample Input 3\n\n12 3 7\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 137, "cpu_time_ms": 1, "memory_kb": 128}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s361178050", "group_id": "codeNet:p02955", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long\nconst ll p=1000000007ll;\nconst int N=200005;\ntemplate<class IT>inline void cmin(IT &a,IT b){if(b<a)a=b;}\ntemplate<class IT>inline void cmax(IT &a,IT b){if(a<b)a=b;}\nint a[N],b[N],n,u,s;\ninline void solve(int x){\n//\tprintf(\"solve %d\\n\",x);\n\tint i,t,s2=0;u=0;\n\tfor(i=1;i<=n;++i)s2+=(b[i]=a[i]%x);\n\tsort(b+1,b+n+1);\n\tt=n-s2/x;\n\tfor(i=1;i<=t;++i)u+=b[i];\n}\nint main(){\n\tint i,t,k,ans=0;\n\tscanf(\"%d%d\",&n,&k);\n\tfor(i=1;i<=n;++i){scanf(\"%d\",&a[i]);s+=a[i];}\n//\tprintf(\"sum=%d\\n\",s);\n\tt=sqrt(s);\n\tfor(i=1;i<=t;++i)if(!(s%i)){\n\t\tsolve(  i);if(u<=k)cmax(ans,  i);\n\t\tsolve(s/i);if(u<=k)cmax(ans,s/i);\n\t}\n\tprintf(\"%d\",ans);\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1564969025, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02955.html", "problem_id": "p02955", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02955/input.txt", "sample_output_relpath": "derived/input_output/data/p02955/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02955/C++/s361178050.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s361178050", "user_id": "u238671650"}, "prompt_components": {"gold_output": "7\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long\nconst ll p=1000000007ll;\nconst int N=200005;\ntemplate<class IT>inline void cmin(IT &a,IT b){if(b<a)a=b;}\ntemplate<class IT>inline void cmax(IT &a,IT b){if(a<b)a=b;}\nint a[N],b[N],n,u,s;\ninline void solve(int x){\n//\tprintf(\"solve %d\\n\",x);\n\tint i,t,s2=0;u=0;\n\tfor(i=1;i<=n;++i)s2+=(b[i]=a[i]%x);\n\tsort(b+1,b+n+1);\n\tt=n-s2/x;\n\tfor(i=1;i<=t;++i)u+=b[i];\n}\nint main(){\n\tint i,t,k,ans=0;\n\tscanf(\"%d%d\",&n,&k);\n\tfor(i=1;i<=n;++i){scanf(\"%d\",&a[i]);s+=a[i];}\n//\tprintf(\"sum=%d\\n\",s);\n\tt=sqrt(s);\n\tfor(i=1;i<=t;++i)if(!(s%i)){\n\t\tsolve(  i);if(u<=k)cmax(ans,  i);\n\t\tsolve(s/i);if(u<=k)cmax(ans,s/i);\n\t}\n\tprintf(\"%d\",ans);\n\treturn 0;\n}", "problem_context": "Score : 500 points\n\nProblem Statement\n\nWe have a sequence of N integers: A_1, A_2, \\cdots, A_N.\n\nYou can perform the following operation between 0 and K times (inclusive):\n\nChoose two integers i and j such that i \\neq j, each between 1 and N (inclusive). Add 1 to A_i and -1 to A_j, possibly producing a negative element.\n\nCompute the maximum possible positive integer that divides every element of A after the operations. Here a positive integer x divides an integer y if and only if there exists an integer z such that y = xz.\n\nConstraints\n\n2 \\leq N \\leq 500\n\n1 \\leq A_i \\leq 10^6\n\n0 \\leq K \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nA_1 A_2 \\cdots A_{N-1} A_{N}\n\nOutput\n\nPrint the maximum possible positive integer that divides every element of A after the operations.\n\nSample Input 1\n\n2 3\n8 20\n\nSample Output 1\n\n7\n\n7 will divide every element of A if, for example, we perform the following operation:\n\nChoose i = 2, j = 1. A becomes (7, 21).\n\nWe cannot reach the situation where 8 or greater integer divides every element of A.\n\nSample Input 2\n\n2 10\n3 5\n\nSample Output 2\n\n8\n\nConsider performing the following five operations:\n\nChoose i = 2, j = 1. A becomes (2, 6).\n\nChoose i = 2, j = 1. A becomes (1, 7).\n\nChoose i = 2, j = 1. A becomes (0, 8).\n\nChoose i = 2, j = 1. A becomes (-1, 9).\n\nChoose i = 1, j = 2. A becomes (0, 8).\n\nThen, 0 = 8 \\times 0 and 8 = 8 \\times 1, so 8 divides every element of A. We cannot reach the situation where 9 or greater integer divides every element of A.\n\nSample Input 3\n\n4 5\n10 1 2 22\n\nSample Output 3\n\n7\n\nSample Input 4\n\n8 7\n1 7 5 6 8 2 6 5\n\nSample Output 4\n\n5", "sample_input": "2 3\n8 20\n"}, "reference_outputs": ["7\n"], "source_document_id": "p02955", "source_text": "Score : 500 points\n\nProblem Statement\n\nWe have a sequence of N integers: A_1, A_2, \\cdots, A_N.\n\nYou can perform the following operation between 0 and K times (inclusive):\n\nChoose two integers i and j such that i \\neq j, each between 1 and N (inclusive). Add 1 to A_i and -1 to A_j, possibly producing a negative element.\n\nCompute the maximum possible positive integer that divides every element of A after the operations. Here a positive integer x divides an integer y if and only if there exists an integer z such that y = xz.\n\nConstraints\n\n2 \\leq N \\leq 500\n\n1 \\leq A_i \\leq 10^6\n\n0 \\leq K \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nA_1 A_2 \\cdots A_{N-1} A_{N}\n\nOutput\n\nPrint the maximum possible positive integer that divides every element of A after the operations.\n\nSample Input 1\n\n2 3\n8 20\n\nSample Output 1\n\n7\n\n7 will divide every element of A if, for example, we perform the following operation:\n\nChoose i = 2, j = 1. A becomes (7, 21).\n\nWe cannot reach the situation where 8 or greater integer divides every element of A.\n\nSample Input 2\n\n2 10\n3 5\n\nSample Output 2\n\n8\n\nConsider performing the following five operations:\n\nChoose i = 2, j = 1. A becomes (2, 6).\n\nChoose i = 2, j = 1. A becomes (1, 7).\n\nChoose i = 2, j = 1. A becomes (0, 8).\n\nChoose i = 2, j = 1. A becomes (-1, 9).\n\nChoose i = 1, j = 2. A becomes (0, 8).\n\nThen, 0 = 8 \\times 0 and 8 = 8 \\times 1, so 8 divides every element of A. We cannot reach the situation where 9 or greater integer divides every element of A.\n\nSample Input 3\n\n4 5\n10 1 2 22\n\nSample Output 3\n\n7\n\nSample Input 4\n\n8 7\n1 7 5 6 8 2 6 5\n\nSample Output 4\n\n5", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 691, "cpu_time_ms": 18, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s262016904", "group_id": "codeNet:p02959", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n#define _GLIBCXX_DEBUG\n#define rep(i,n) for(long long i = 0; i < (n); ++i)\n#define ll long long\n#define P pair<ll,ll>\n#define all(v) (v).begin(),(v).end()\n\nconst ll mod = 1e9+7;\nconst ll INF = 1e18;\nconst double pi = acos(-1.0);\n\nint main(void)\n{\n    ll n, ans=0;\n    cin >> n;\n    vector<ll> a(n+1), b(n);\n    rep(i,n+1) cin >> a[i];\n    rep(i,n) cin >> b[i];\n    rep(i,n){\n        ll l = min(a[i], b[i]);\n        ans += l;\n        a[i] -= l;\n        b[i] -= l;\n        ll r = min(a[i+1], b[i]);\n        ans += r;\n        a[i] -= r;\n        b[i] -= r;\n    }\n    cout << ans << endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1598724694, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02959.html", "problem_id": "p02959", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02959/input.txt", "sample_output_relpath": "derived/input_output/data/p02959/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02959/C++/s262016904.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s262016904", "user_id": "u025469035"}, "prompt_components": {"gold_output": "9\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n#define _GLIBCXX_DEBUG\n#define rep(i,n) for(long long i = 0; i < (n); ++i)\n#define ll long long\n#define P pair<ll,ll>\n#define all(v) (v).begin(),(v).end()\n\nconst ll mod = 1e9+7;\nconst ll INF = 1e18;\nconst double pi = acos(-1.0);\n\nint main(void)\n{\n    ll n, ans=0;\n    cin >> n;\n    vector<ll> a(n+1), b(n);\n    rep(i,n+1) cin >> a[i];\n    rep(i,n) cin >> b[i];\n    rep(i,n){\n        ll l = min(a[i], b[i]);\n        ans += l;\n        a[i] -= l;\n        b[i] -= l;\n        ll r = min(a[i+1], b[i]);\n        ans += r;\n        a[i] -= r;\n        b[i] -= r;\n    }\n    cout << ans << endl;\n    return 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N+1 towns. The i-th town is being attacked by A_i monsters.\n\nWe have N heroes. The i-th hero can defeat monsters attacking the i-th or (i+1)-th town, for a total of at most B_i monsters.\n\nWhat is the maximum total number of monsters the heroes can cooperate to defeat?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq A_i \\leq 10^9\n\n1 \\leq B_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_{N+1}\nB_1 B_2 ... B_N\n\nOutput\n\nPrint the maximum total number of monsters the heroes can defeat.\n\nSample Input 1\n\n2\n3 5 2\n4 5\n\nSample Output 1\n\n9\n\nIf the heroes choose the monsters to defeat as follows, they can defeat nine monsters in total, which is the maximum result.\n\nThe first hero defeats two monsters attacking the first town and two monsters attacking the second town.\n\nThe second hero defeats three monsters attacking the second town and two monsters attacking the third town.\n\nSample Input 2\n\n3\n5 6 3 8\n5 100 8\n\nSample Output 2\n\n22\n\nSample Input 3\n\n2\n100 1 1\n1 100\n\nSample Output 3\n\n3", "sample_input": "2\n3 5 2\n4 5\n"}, "reference_outputs": ["9\n"], "source_document_id": "p02959", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N+1 towns. The i-th town is being attacked by A_i monsters.\n\nWe have N heroes. The i-th hero can defeat monsters attacking the i-th or (i+1)-th town, for a total of at most B_i monsters.\n\nWhat is the maximum total number of monsters the heroes can cooperate to defeat?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq A_i \\leq 10^9\n\n1 \\leq B_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_{N+1}\nB_1 B_2 ... B_N\n\nOutput\n\nPrint the maximum total number of monsters the heroes can defeat.\n\nSample Input 1\n\n2\n3 5 2\n4 5\n\nSample Output 1\n\n9\n\nIf the heroes choose the monsters to defeat as follows, they can defeat nine monsters in total, which is the maximum result.\n\nThe first hero defeats two monsters attacking the first town and two monsters attacking the second town.\n\nThe second hero defeats three monsters attacking the second town and two monsters attacking the third town.\n\nSample Input 2\n\n3\n5 6 3 8\n5 100 8\n\nSample Output 2\n\n22\n\nSample Input 3\n\n2\n100 1 1\n1 100\n\nSample Output 3\n\n3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 645, "cpu_time_ms": 72, "memory_kb": 4852}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s628362788", "group_id": "codeNet:p02959", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n    int n;\n    cin>>n;\n    long long  a[n+1];\n    for(int i=0;i<n+1;i++)\n    cin>>a[i];\n    long long  b[n];\n    long long monster=0;\n    for(int i=0;i<n;i++)\n    cin>>b[i];\n    for(int i=0;i<n;i++)\n    {\n        if(a[i]<=b[i])\n        {\n            monster+=a[i];\n            b[i]-=a[i];\n            if(a[i+1]<=b[i])\n            {\n                monster+=a[i+1];\n                a[i+1]=0;\n            }\n            else\n            {\n                monster+=b[i];\n                a[i+1]-=b[i];\n            }\n        }\n        else\n        {\n            monster+=b[i];\n\n            \n            \n        }\n        \n        \n        \n        \n    }\n    \n    \n        cout<<monster<<endl;\n    \n    return 0;\n}", "language": "C++", "metadata": {"date": 1577335612, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02959.html", "problem_id": "p02959", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02959/input.txt", "sample_output_relpath": "derived/input_output/data/p02959/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02959/C++/s628362788.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s628362788", "user_id": "u866310595"}, "prompt_components": {"gold_output": "9\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n    int n;\n    cin>>n;\n    long long  a[n+1];\n    for(int i=0;i<n+1;i++)\n    cin>>a[i];\n    long long  b[n];\n    long long monster=0;\n    for(int i=0;i<n;i++)\n    cin>>b[i];\n    for(int i=0;i<n;i++)\n    {\n        if(a[i]<=b[i])\n        {\n            monster+=a[i];\n            b[i]-=a[i];\n            if(a[i+1]<=b[i])\n            {\n                monster+=a[i+1];\n                a[i+1]=0;\n            }\n            else\n            {\n                monster+=b[i];\n                a[i+1]-=b[i];\n            }\n        }\n        else\n        {\n            monster+=b[i];\n\n            \n            \n        }\n        \n        \n        \n        \n    }\n    \n    \n        cout<<monster<<endl;\n    \n    return 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N+1 towns. The i-th town is being attacked by A_i monsters.\n\nWe have N heroes. The i-th hero can defeat monsters attacking the i-th or (i+1)-th town, for a total of at most B_i monsters.\n\nWhat is the maximum total number of monsters the heroes can cooperate to defeat?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq A_i \\leq 10^9\n\n1 \\leq B_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_{N+1}\nB_1 B_2 ... B_N\n\nOutput\n\nPrint the maximum total number of monsters the heroes can defeat.\n\nSample Input 1\n\n2\n3 5 2\n4 5\n\nSample Output 1\n\n9\n\nIf the heroes choose the monsters to defeat as follows, they can defeat nine monsters in total, which is the maximum result.\n\nThe first hero defeats two monsters attacking the first town and two monsters attacking the second town.\n\nThe second hero defeats three monsters attacking the second town and two monsters attacking the third town.\n\nSample Input 2\n\n3\n5 6 3 8\n5 100 8\n\nSample Output 2\n\n22\n\nSample Input 3\n\n2\n100 1 1\n1 100\n\nSample Output 3\n\n3", "sample_input": "2\n3 5 2\n4 5\n"}, "reference_outputs": ["9\n"], "source_document_id": "p02959", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N+1 towns. The i-th town is being attacked by A_i monsters.\n\nWe have N heroes. The i-th hero can defeat monsters attacking the i-th or (i+1)-th town, for a total of at most B_i monsters.\n\nWhat is the maximum total number of monsters the heroes can cooperate to defeat?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq A_i \\leq 10^9\n\n1 \\leq B_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_{N+1}\nB_1 B_2 ... B_N\n\nOutput\n\nPrint the maximum total number of monsters the heroes can defeat.\n\nSample Input 1\n\n2\n3 5 2\n4 5\n\nSample Output 1\n\n9\n\nIf the heroes choose the monsters to defeat as follows, they can defeat nine monsters in total, which is the maximum result.\n\nThe first hero defeats two monsters attacking the first town and two monsters attacking the second town.\n\nThe second hero defeats three monsters attacking the second town and two monsters attacking the third town.\n\nSample Input 2\n\n3\n5 6 3 8\n5 100 8\n\nSample Output 2\n\n22\n\nSample Input 3\n\n2\n100 1 1\n1 100\n\nSample Output 3\n\n3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 767, "cpu_time_ms": 86, "memory_kb": 1792}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s301845067", "group_id": "codeNet:p02962", "input_text": "#include <bits/stdc++.h>\n#define all(vec) vec.begin(), vec.end()\n#define pb push_back\n#define eb emplace_back\nusing namespace std;\nusing ll = long long;\nusing P = pair<ll, ll>;\ntemplate <class T>\nusing V = vector<T>;\nconstexpr ll INF = (1LL << 30) - 1LL;\nconstexpr ll MOD = 1e9 + 7;\nconstexpr int dx[4] = {0, 1, 0, -1}, dy[4] = {1, 0, -1, 0};\ntemplate <class T>\nvoid chmin(T &a, T b) { a = min(a, b); }\ntemplate <class T>\nvoid chmax(T &a, T b) { a = max(a, b); }\nvoid ok() { cerr << \"ok\" << endl; }\nusing ull = uint64_t;\nconst int bases[64] = {257, 262, 266, 275, 276, 281, 285, 290, 296, 302, 306,\n                       310, 311, 313, 323, 333, 344, 345, 350, 357, 367, 370,\n                       373, 402, 423, 425, 431, 440, 442, 443, 454, 457, 458,\n                       462, 471, 478, 481, 487, 489, 492, 499, 501, 502, 503,\n                       506, 514, 524, 532, 535, 541, 550, 552, 557, 559, 562,\n                       563, 567, 570, 571, 580, 592, 597, 604, 612};\nconst ull rmod = 0x1fffffffffffffff;\nconst ull base = bases[chrono::duration_cast<chrono::microseconds>(chrono::system_clock::now().time_since_epoch()).count() & 63];\nconst ull mask30 = (1UL << 30) - 1, mask31 = (1UL << 31) - 1;\nstruct RollingHash {\n    vector<ull> hash, pow;\n    inline ull mul(const ull &a, const ull &b) const {\n        ull mid = (a & mask31) * (b >> 31) + (a >> 31) * (b & mask31);\n        ull res = (a >> 31) * (b >> 31) * 2 + (mid >> 30) + ((mid & mask30) << 31);\n        res += (a & mask31) * (b & mask31);\n        res = (res >> 61) + (res & rmod);\n        if (res >= rmod) res -= rmod;\n        return res;\n    }\n    RollingHash(const string &s) {\n        hash.resize(s.length() + 1);\n        pow.resize(s.length() + 1);\n        pow[0] = 1;\n        for (int i = 0; i < s.length(); i++) {\n            hash[i + 1] = mul(hash[i], base) + s[i];\n            pow[i + 1] = mul(pow[i], base);\n            if (hash[i + 1] >= rmod) hash[i + 1] -= rmod;\n        }\n    }\n    ull get(int l, int r) { //[l,r]\n        ull res = hash[r + 1] + rmod - mul(hash[l], pow[r + 1 - l]);\n        if (res >= rmod) res -= rmod;\n        return res;\n    }\n};\nint main() {\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n    string s, t;\n    cin >> s >> t;\n    int n = s.length(), m = t.length();\n    while (s.length() < n + m) {\n        s += s;\n    }\n    RollingHash hs(s), ht(t);\n    vector<int> f(n), vis(n, -1);\n    for (int i = 0; i < n; i++) {\n        if (hs.get(i, i + m - 1) == ht.get(0, m - 1)) {\n            f[i] = 1;\n        }\n    }\n    int ans = 0;\n    for (int i = 0; i < n; i++) {\n        if (!f[i] || vis[i] != -1) {\n            continue;\n        }\n        int co = 0, id = i;\n        vector<int> v;\n        while (1) {\n            v.push_back(id);\n            co++;\n            id += m;\n            id %= n;\n            if (f[id]) {\n                if (id == i) {\n                    cout << -1 << endl;\n                    return 0;\n                }\n                if (vis[id] != -1) {\n                    co += vis[id];\n                    break;\n                }\n                vis[id] = 0;\n            } else {\n                break;\n            }\n        }\n        vis[i] = co;\n        chmax(ans, co);\n    }\n    cout << ans << endl;\n}\n", "language": "C++", "metadata": {"date": 1586658305, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02962.html", "problem_id": "p02962", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02962/input.txt", "sample_output_relpath": "derived/input_output/data/p02962/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02962/C++/s301845067.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s301845067", "user_id": "u924339359"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define all(vec) vec.begin(), vec.end()\n#define pb push_back\n#define eb emplace_back\nusing namespace std;\nusing ll = long long;\nusing P = pair<ll, ll>;\ntemplate <class T>\nusing V = vector<T>;\nconstexpr ll INF = (1LL << 30) - 1LL;\nconstexpr ll MOD = 1e9 + 7;\nconstexpr int dx[4] = {0, 1, 0, -1}, dy[4] = {1, 0, -1, 0};\ntemplate <class T>\nvoid chmin(T &a, T b) { a = min(a, b); }\ntemplate <class T>\nvoid chmax(T &a, T b) { a = max(a, b); }\nvoid ok() { cerr << \"ok\" << endl; }\nusing ull = uint64_t;\nconst int bases[64] = {257, 262, 266, 275, 276, 281, 285, 290, 296, 302, 306,\n                       310, 311, 313, 323, 333, 344, 345, 350, 357, 367, 370,\n                       373, 402, 423, 425, 431, 440, 442, 443, 454, 457, 458,\n                       462, 471, 478, 481, 487, 489, 492, 499, 501, 502, 503,\n                       506, 514, 524, 532, 535, 541, 550, 552, 557, 559, 562,\n                       563, 567, 570, 571, 580, 592, 597, 604, 612};\nconst ull rmod = 0x1fffffffffffffff;\nconst ull base = bases[chrono::duration_cast<chrono::microseconds>(chrono::system_clock::now().time_since_epoch()).count() & 63];\nconst ull mask30 = (1UL << 30) - 1, mask31 = (1UL << 31) - 1;\nstruct RollingHash {\n    vector<ull> hash, pow;\n    inline ull mul(const ull &a, const ull &b) const {\n        ull mid = (a & mask31) * (b >> 31) + (a >> 31) * (b & mask31);\n        ull res = (a >> 31) * (b >> 31) * 2 + (mid >> 30) + ((mid & mask30) << 31);\n        res += (a & mask31) * (b & mask31);\n        res = (res >> 61) + (res & rmod);\n        if (res >= rmod) res -= rmod;\n        return res;\n    }\n    RollingHash(const string &s) {\n        hash.resize(s.length() + 1);\n        pow.resize(s.length() + 1);\n        pow[0] = 1;\n        for (int i = 0; i < s.length(); i++) {\n            hash[i + 1] = mul(hash[i], base) + s[i];\n            pow[i + 1] = mul(pow[i], base);\n            if (hash[i + 1] >= rmod) hash[i + 1] -= rmod;\n        }\n    }\n    ull get(int l, int r) { //[l,r]\n        ull res = hash[r + 1] + rmod - mul(hash[l], pow[r + 1 - l]);\n        if (res >= rmod) res -= rmod;\n        return res;\n    }\n};\nint main() {\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n    string s, t;\n    cin >> s >> t;\n    int n = s.length(), m = t.length();\n    while (s.length() < n + m) {\n        s += s;\n    }\n    RollingHash hs(s), ht(t);\n    vector<int> f(n), vis(n, -1);\n    for (int i = 0; i < n; i++) {\n        if (hs.get(i, i + m - 1) == ht.get(0, m - 1)) {\n            f[i] = 1;\n        }\n    }\n    int ans = 0;\n    for (int i = 0; i < n; i++) {\n        if (!f[i] || vis[i] != -1) {\n            continue;\n        }\n        int co = 0, id = i;\n        vector<int> v;\n        while (1) {\n            v.push_back(id);\n            co++;\n            id += m;\n            id %= n;\n            if (f[id]) {\n                if (id == i) {\n                    cout << -1 << endl;\n                    return 0;\n                }\n                if (vis[id] != -1) {\n                    co += vis[id];\n                    break;\n                }\n                vis[id] = 0;\n            } else {\n                break;\n            }\n        }\n        vis[i] = co;\n        chmax(ans, co);\n    }\n    cout << ans << endl;\n}\n", "problem_context": "Score : 600 points\n\nProblem Statement\n\nGiven are two strings s and t consisting of lowercase English letters. Determine if the number of non-negative integers i satisfying the following condition is finite, and find the maximum value of such i if the number is finite.\n\nThere exists a non-negative integer j such that the concatenation of i copies of t is a substring of the concatenation of j copies of s.\n\nNotes\n\nA string a is a substring of another string b if and only if there exists an integer x (0 \\leq x \\leq |b| - |a|) such that, for any y (1 \\leq y \\leq |a|), a_y = b_{x+y} holds.\n\nWe assume that the concatenation of zero copies of any string is the empty string. From the definition above, the empty string is a substring of any string. Thus, for any two strings s and t, i = 0 satisfies the condition in the problem statement.\n\nConstraints\n\n1 \\leq |s| \\leq 5 \\times 10^5\n\n1 \\leq |t| \\leq 5 \\times 10^5\n\ns and t consist of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\ns\nt\n\nOutput\n\nIf the number of non-negative integers i satisfying the following condition is finite, print the maximum value of such i; if the number is infinite, print -1.\n\nSample Input 1\n\nabcabab\nab\n\nSample Output 1\n\n3\n\nThe concatenation of three copies of t, ababab, is a substring of the concatenation of two copies of s, abcabababcabab, so i = 3 satisfies the condition.\n\nOn the other hand, the concatenation of four copies of t, abababab, is not a substring of the concatenation of any number of copies of s, so i = 4 does not satisfy the condition.\n\nSimilarly, any integer greater than 4 does not satisfy the condition, either. Thus, the number of non-negative integers i satisfying the condition is finite, and the maximum value of such i is 3.\n\nSample Input 2\n\naa\naaaaaaa\n\nSample Output 2\n\n-1\n\nFor any non-negative integer i, the concatenation of i copies of t is a substring of the concatenation of 4i copies of s. Thus, there are infinitely many non-negative integers i that satisfy the condition.\n\nSample Input 3\n\naba\nbaaab\n\nSample Output 3\n\n0\n\nAs stated in Notes, i = 0 always satisfies the condition.", "sample_input": "abcabab\nab\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02962", "source_text": "Score : 600 points\n\nProblem Statement\n\nGiven are two strings s and t consisting of lowercase English letters. Determine if the number of non-negative integers i satisfying the following condition is finite, and find the maximum value of such i if the number is finite.\n\nThere exists a non-negative integer j such that the concatenation of i copies of t is a substring of the concatenation of j copies of s.\n\nNotes\n\nA string a is a substring of another string b if and only if there exists an integer x (0 \\leq x \\leq |b| - |a|) such that, for any y (1 \\leq y \\leq |a|), a_y = b_{x+y} holds.\n\nWe assume that the concatenation of zero copies of any string is the empty string. From the definition above, the empty string is a substring of any string. Thus, for any two strings s and t, i = 0 satisfies the condition in the problem statement.\n\nConstraints\n\n1 \\leq |s| \\leq 5 \\times 10^5\n\n1 \\leq |t| \\leq 5 \\times 10^5\n\ns and t consist of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\ns\nt\n\nOutput\n\nIf the number of non-negative integers i satisfying the following condition is finite, print the maximum value of such i; if the number is infinite, print -1.\n\nSample Input 1\n\nabcabab\nab\n\nSample Output 1\n\n3\n\nThe concatenation of three copies of t, ababab, is a substring of the concatenation of two copies of s, abcabababcabab, so i = 3 satisfies the condition.\n\nOn the other hand, the concatenation of four copies of t, abababab, is not a substring of the concatenation of any number of copies of s, so i = 4 does not satisfy the condition.\n\nSimilarly, any integer greater than 4 does not satisfy the condition, either. Thus, the number of non-negative integers i satisfying the condition is finite, and the maximum value of such i is 3.\n\nSample Input 2\n\naa\naaaaaaa\n\nSample Output 2\n\n-1\n\nFor any non-negative integer i, the concatenation of i copies of t is a substring of the concatenation of 4i copies of s. Thus, there are infinitely many non-negative integers i that satisfy the condition.\n\nSample Input 3\n\naba\nbaaab\n\nSample Output 3\n\n0\n\nAs stated in Notes, i = 0 always satisfies the condition.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 3236, "cpu_time_ms": 49, "memory_kb": 50524}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s931836121", "group_id": "codeNet:p02962", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef pair<int,int> pii;\ntypedef pair<ll, ll> pll;\ntypedef pair<ull, ull> pullull;\ntypedef pair<ll, int> plli;\ntypedef pair<int, pii> pipii;\ntypedef vector<vector<int> > mati;\ntypedef vector<vector<double> > matd;\ntypedef vector<ll> vll;\ntypedef vector<vector<ll>> vvll;\ntypedef vector<vector<vector<ll>>> vvvll;\ntypedef vector<bool> vb;\ntypedef vector<vector<bool>> vvb;\ntypedef vector<vector<vector<bool>>> vvvb;\ntypedef vector<pll> vpll;\n\n#define FOR(i,x,y) for(ll i=(ll)x; i<(ll)y; ++i)\n#define REP(i,y) FOR(i, 0, y)\n#define RFOR(i,x,y) for(ll i=(ll)x; i>=(ll)y; --i)\n#define RREP(i,x) RFOR(i, x, 0)\n#define ALL(a) a.begin(), a.end()\n#define pb push_back\n\ninline void IN(void){\n  return;\n}\n\ntemplate <typename First, typename... Rest>\nvoid IN(First& first, Rest&... rest){\n  cin >> first;\n  IN(rest...);\n  return;\n}\n\ninline void OUT(void){\n  cout << \"\\n\";\n  return;\n}\n\ntemplate <typename First, typename... Rest>\nvoid OUT(First first, Rest... rest){\n  cout << first << \" \";\n  OUT(rest...);\n  return;\n}\n\nconstexpr int INF = (1<<30);\nconstexpr ll INFLL = 1LL<<62;\nconstexpr long double EPS = 1e-12;\nconstexpr ll MOD = (ll)((1E+9)+7);\n\n/*\nclass KMP{\n  private:\n    string S;\n    string W;\n    vector<ll> T;\n    vector<bool> flag;\n\n  public:\n    void make_table(void){\n      T.resize(W.size());\n      ll i = 2;\n      ll j = 0;\n      T[0] = -1;\n      T[1] = 0;\n\n      while(i<W.size()){\n        if(W[i-1]==W[j]){\n          T[i] = j+1;\n          i++;\n          j++;\n        }else if(j>0){\n          j = T[j];\n        }else{\n          T[i] = 0;\n          i++;\n        }\n      }\n      return;\n    }\n\n    KMP(string s, string w){\n      S = s;\n      W = w;\n      make_table();\n      flag.resize(S.size(), false);\n      return;\n    };\n\n    ~KMP(void){\n      return;\n    };\n\n    ll local_search(ll start){\n      ll m = 0; // the start position in S\n      ll i = start; // the start position in W\n\n      while(m+i<S.size()){\n        if(W[i] == S[m+i]){\n          i++;\n          if(i==W.size()) return m;\n        }else{\n          m+=i-T[i];\n          if(i>0) i=T[i];\n        }\n      }\n      return -1;\n    };\n\n    void total_search(void){\n      ll m = 0; // the start position in S\n      ll i = 0; // the start position in W\n\n      while(m+i<S.size()){\n        if(W[i] == S[m+i]){\n          i++;\n          if(i==W.size()){\n            flag[m] = true;\n            m++;\n            i=0;\n          }\n        }else{\n          m+=i-T[i];\n          if(i>0) i=T[i];\n        }\n      }\n      return;\n    };\n\n    bool start_check(ll start){\n      return flag[start];\n    };\n};\n*/\n\nclass Z_algorithm{\n  public:\n    string S;\n    vector<ll> A;\n    Z_algorithm(string s){\n      S = s;\n      A.resize(S.size());\n      return;\n    };\n\n    ~Z_algorithm(void){\n      return;\n    };\n\n    void calc(void){\n      A[0] = S.size();\n      ll i=1, j=0;\n      while(i<S.size()){\n        while(i+j < S.size() && S[j] == S[i+j]) ++j;\n        A[i] = j;\n        if(j==0){\n          ++i;\n          continue;\n        }\n        ll k=1;\n        while(i+k<S.size() && k+A[k]<j){\n          A[i+k] = A[k];\n          ++k;\n        }\n        i += k;\n        j -= k;\n      }\n      return;\n    };\n\n    void calc(string W){\n      S = W+S;\n      calc();\n      return;\n    };\n};\n\nvll dp;\nvll jump;\nbool total_flag = true;\n\nll calc(ll pos, const ll init){\n  ll n_pos = jump[pos];\n  if(n_pos<0){\n    return dp[pos] = 0;\n  }\n  if(n_pos==init){\n    total_flag = false;\n    return -2;\n  }\n  if(dp[pos]>=0) return dp[pos];\n  return dp[pos] = calc(n_pos, init) + 1;\n}\n\nint main(){\n  string s_base, t_base;\n  IN(s_base);\n  IN(t_base);\n\n  string s = s_base;\n  string t = t_base;\n\n  while(s.size()<2*t.size()){\n    s += s_base;\n  }\n\n  jump.resize(s_base.size());\n  REP(i,s_base.size()) jump[i] = -1;\n\n  /*\n  REP(s_start, s_base.size()){\n    bool flag = true;\n    REP(t_diff,t.size()){\n      if(s[t_diff+s_start] != t[t_diff]){\n        flag = false;\n        break;\n      }\n    }\n    if(!flag) continue;\n\n    jump[s_start] = (s_start + t.size())%s_base.size();\n  }\n  */\n\n  /*\n  KMP kmp(s, t);\n  kmp.total_search();\n  REP(i,s_base.size()){\n    if(!kmp.start_check(i)) jump[i] = -1;\n    else jump[i] = (i+t.size())%s_base.size();\n  }\n  */\n\n  Z_algorithm ZA(s);\n  ZA.calc(t);\n  REP(i,s_base.size()){\n    if(ZA.A[t.size()+i] < t.size()) continue;\n    jump[i] = (i+t.size())%s_base.size();\n  }\n\n  REP(i,s_base.size()){\n    //printf(\"%lld %lld\\n\", i, jump[i]);\n  }\n\n  dp.resize(jump.size());\n  REP(i,dp.size()){\n    dp[i] = -1;\n  }\n\n  REP(i,dp.size()){\n    calc(i, i);\n    if(!total_flag) break;\n  }\n\n  ll ans = 0;\n  REP(i,dp.size()){\n    ans = max(ans, dp[i]);\n    //printf(\"%lld %lld\\n\", i, dp[i]);\n  }\n\n  if(total_flag){\n    printf(\"%lld\\n\", ans);\n  }else{\n    printf(\"-1\\n\");\n  }\n\n\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1564471844, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02962.html", "problem_id": "p02962", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02962/input.txt", "sample_output_relpath": "derived/input_output/data/p02962/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02962/C++/s931836121.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s931836121", "user_id": "u355335354"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef pair<int,int> pii;\ntypedef pair<ll, ll> pll;\ntypedef pair<ull, ull> pullull;\ntypedef pair<ll, int> plli;\ntypedef pair<int, pii> pipii;\ntypedef vector<vector<int> > mati;\ntypedef vector<vector<double> > matd;\ntypedef vector<ll> vll;\ntypedef vector<vector<ll>> vvll;\ntypedef vector<vector<vector<ll>>> vvvll;\ntypedef vector<bool> vb;\ntypedef vector<vector<bool>> vvb;\ntypedef vector<vector<vector<bool>>> vvvb;\ntypedef vector<pll> vpll;\n\n#define FOR(i,x,y) for(ll i=(ll)x; i<(ll)y; ++i)\n#define REP(i,y) FOR(i, 0, y)\n#define RFOR(i,x,y) for(ll i=(ll)x; i>=(ll)y; --i)\n#define RREP(i,x) RFOR(i, x, 0)\n#define ALL(a) a.begin(), a.end()\n#define pb push_back\n\ninline void IN(void){\n  return;\n}\n\ntemplate <typename First, typename... Rest>\nvoid IN(First& first, Rest&... rest){\n  cin >> first;\n  IN(rest...);\n  return;\n}\n\ninline void OUT(void){\n  cout << \"\\n\";\n  return;\n}\n\ntemplate <typename First, typename... Rest>\nvoid OUT(First first, Rest... rest){\n  cout << first << \" \";\n  OUT(rest...);\n  return;\n}\n\nconstexpr int INF = (1<<30);\nconstexpr ll INFLL = 1LL<<62;\nconstexpr long double EPS = 1e-12;\nconstexpr ll MOD = (ll)((1E+9)+7);\n\n/*\nclass KMP{\n  private:\n    string S;\n    string W;\n    vector<ll> T;\n    vector<bool> flag;\n\n  public:\n    void make_table(void){\n      T.resize(W.size());\n      ll i = 2;\n      ll j = 0;\n      T[0] = -1;\n      T[1] = 0;\n\n      while(i<W.size()){\n        if(W[i-1]==W[j]){\n          T[i] = j+1;\n          i++;\n          j++;\n        }else if(j>0){\n          j = T[j];\n        }else{\n          T[i] = 0;\n          i++;\n        }\n      }\n      return;\n    }\n\n    KMP(string s, string w){\n      S = s;\n      W = w;\n      make_table();\n      flag.resize(S.size(), false);\n      return;\n    };\n\n    ~KMP(void){\n      return;\n    };\n\n    ll local_search(ll start){\n      ll m = 0; // the start position in S\n      ll i = start; // the start position in W\n\n      while(m+i<S.size()){\n        if(W[i] == S[m+i]){\n          i++;\n          if(i==W.size()) return m;\n        }else{\n          m+=i-T[i];\n          if(i>0) i=T[i];\n        }\n      }\n      return -1;\n    };\n\n    void total_search(void){\n      ll m = 0; // the start position in S\n      ll i = 0; // the start position in W\n\n      while(m+i<S.size()){\n        if(W[i] == S[m+i]){\n          i++;\n          if(i==W.size()){\n            flag[m] = true;\n            m++;\n            i=0;\n          }\n        }else{\n          m+=i-T[i];\n          if(i>0) i=T[i];\n        }\n      }\n      return;\n    };\n\n    bool start_check(ll start){\n      return flag[start];\n    };\n};\n*/\n\nclass Z_algorithm{\n  public:\n    string S;\n    vector<ll> A;\n    Z_algorithm(string s){\n      S = s;\n      A.resize(S.size());\n      return;\n    };\n\n    ~Z_algorithm(void){\n      return;\n    };\n\n    void calc(void){\n      A[0] = S.size();\n      ll i=1, j=0;\n      while(i<S.size()){\n        while(i+j < S.size() && S[j] == S[i+j]) ++j;\n        A[i] = j;\n        if(j==0){\n          ++i;\n          continue;\n        }\n        ll k=1;\n        while(i+k<S.size() && k+A[k]<j){\n          A[i+k] = A[k];\n          ++k;\n        }\n        i += k;\n        j -= k;\n      }\n      return;\n    };\n\n    void calc(string W){\n      S = W+S;\n      calc();\n      return;\n    };\n};\n\nvll dp;\nvll jump;\nbool total_flag = true;\n\nll calc(ll pos, const ll init){\n  ll n_pos = jump[pos];\n  if(n_pos<0){\n    return dp[pos] = 0;\n  }\n  if(n_pos==init){\n    total_flag = false;\n    return -2;\n  }\n  if(dp[pos]>=0) return dp[pos];\n  return dp[pos] = calc(n_pos, init) + 1;\n}\n\nint main(){\n  string s_base, t_base;\n  IN(s_base);\n  IN(t_base);\n\n  string s = s_base;\n  string t = t_base;\n\n  while(s.size()<2*t.size()){\n    s += s_base;\n  }\n\n  jump.resize(s_base.size());\n  REP(i,s_base.size()) jump[i] = -1;\n\n  /*\n  REP(s_start, s_base.size()){\n    bool flag = true;\n    REP(t_diff,t.size()){\n      if(s[t_diff+s_start] != t[t_diff]){\n        flag = false;\n        break;\n      }\n    }\n    if(!flag) continue;\n\n    jump[s_start] = (s_start + t.size())%s_base.size();\n  }\n  */\n\n  /*\n  KMP kmp(s, t);\n  kmp.total_search();\n  REP(i,s_base.size()){\n    if(!kmp.start_check(i)) jump[i] = -1;\n    else jump[i] = (i+t.size())%s_base.size();\n  }\n  */\n\n  Z_algorithm ZA(s);\n  ZA.calc(t);\n  REP(i,s_base.size()){\n    if(ZA.A[t.size()+i] < t.size()) continue;\n    jump[i] = (i+t.size())%s_base.size();\n  }\n\n  REP(i,s_base.size()){\n    //printf(\"%lld %lld\\n\", i, jump[i]);\n  }\n\n  dp.resize(jump.size());\n  REP(i,dp.size()){\n    dp[i] = -1;\n  }\n\n  REP(i,dp.size()){\n    calc(i, i);\n    if(!total_flag) break;\n  }\n\n  ll ans = 0;\n  REP(i,dp.size()){\n    ans = max(ans, dp[i]);\n    //printf(\"%lld %lld\\n\", i, dp[i]);\n  }\n\n  if(total_flag){\n    printf(\"%lld\\n\", ans);\n  }else{\n    printf(\"-1\\n\");\n  }\n\n\n  return 0;\n}\n", "problem_context": "Score : 600 points\n\nProblem Statement\n\nGiven are two strings s and t consisting of lowercase English letters. Determine if the number of non-negative integers i satisfying the following condition is finite, and find the maximum value of such i if the number is finite.\n\nThere exists a non-negative integer j such that the concatenation of i copies of t is a substring of the concatenation of j copies of s.\n\nNotes\n\nA string a is a substring of another string b if and only if there exists an integer x (0 \\leq x \\leq |b| - |a|) such that, for any y (1 \\leq y \\leq |a|), a_y = b_{x+y} holds.\n\nWe assume that the concatenation of zero copies of any string is the empty string. From the definition above, the empty string is a substring of any string. Thus, for any two strings s and t, i = 0 satisfies the condition in the problem statement.\n\nConstraints\n\n1 \\leq |s| \\leq 5 \\times 10^5\n\n1 \\leq |t| \\leq 5 \\times 10^5\n\ns and t consist of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\ns\nt\n\nOutput\n\nIf the number of non-negative integers i satisfying the following condition is finite, print the maximum value of such i; if the number is infinite, print -1.\n\nSample Input 1\n\nabcabab\nab\n\nSample Output 1\n\n3\n\nThe concatenation of three copies of t, ababab, is a substring of the concatenation of two copies of s, abcabababcabab, so i = 3 satisfies the condition.\n\nOn the other hand, the concatenation of four copies of t, abababab, is not a substring of the concatenation of any number of copies of s, so i = 4 does not satisfy the condition.\n\nSimilarly, any integer greater than 4 does not satisfy the condition, either. Thus, the number of non-negative integers i satisfying the condition is finite, and the maximum value of such i is 3.\n\nSample Input 2\n\naa\naaaaaaa\n\nSample Output 2\n\n-1\n\nFor any non-negative integer i, the concatenation of i copies of t is a substring of the concatenation of 4i copies of s. Thus, there are infinitely many non-negative integers i that satisfy the condition.\n\nSample Input 3\n\naba\nbaaab\n\nSample Output 3\n\n0\n\nAs stated in Notes, i = 0 always satisfies the condition.", "sample_input": "abcabab\nab\n"}, "reference_outputs": ["3\n"], "source_document_id": "p02962", "source_text": "Score : 600 points\n\nProblem Statement\n\nGiven are two strings s and t consisting of lowercase English letters. Determine if the number of non-negative integers i satisfying the following condition is finite, and find the maximum value of such i if the number is finite.\n\nThere exists a non-negative integer j such that the concatenation of i copies of t is a substring of the concatenation of j copies of s.\n\nNotes\n\nA string a is a substring of another string b if and only if there exists an integer x (0 \\leq x \\leq |b| - |a|) such that, for any y (1 \\leq y \\leq |a|), a_y = b_{x+y} holds.\n\nWe assume that the concatenation of zero copies of any string is the empty string. From the definition above, the empty string is a substring of any string. Thus, for any two strings s and t, i = 0 satisfies the condition in the problem statement.\n\nConstraints\n\n1 \\leq |s| \\leq 5 \\times 10^5\n\n1 \\leq |t| \\leq 5 \\times 10^5\n\ns and t consist of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\ns\nt\n\nOutput\n\nIf the number of non-negative integers i satisfying the following condition is finite, print the maximum value of such i; if the number is infinite, print -1.\n\nSample Input 1\n\nabcabab\nab\n\nSample Output 1\n\n3\n\nThe concatenation of three copies of t, ababab, is a substring of the concatenation of two copies of s, abcabababcabab, so i = 3 satisfies the condition.\n\nOn the other hand, the concatenation of four copies of t, abababab, is not a substring of the concatenation of any number of copies of s, so i = 4 does not satisfy the condition.\n\nSimilarly, any integer greater than 4 does not satisfy the condition, either. Thus, the number of non-negative integers i satisfying the condition is finite, and the maximum value of such i is 3.\n\nSample Input 2\n\naa\naaaaaaa\n\nSample Output 2\n\n-1\n\nFor any non-negative integer i, the concatenation of i copies of t is a substring of the concatenation of 4i copies of s. Thus, there are infinitely many non-negative integers i that satisfy the condition.\n\nSample Input 3\n\naba\nbaaab\n\nSample Output 3\n\n0\n\nAs stated in Notes, i = 0 always satisfies the condition.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 4830, "cpu_time_ms": 152, "memory_kb": 32180}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s598107180", "group_id": "codeNet:p02963", "input_text": "#include <bits/stdc++.h>\n#define rep(i,n) for (int i = 0; i < (n); ++i)\nusing namespace std;\nusing ll = long long;\nusing P = pair<int,int>;\n\nconst ll e9 = 1000000000;\n\nint main() {\n    ll s;\n    cin >> s;\n    ll x1 = 0, y1 = 0;\n    ll x2 = e9, y2 = 1;\n    ll x3 = (s % e9) + e9;\n    ll y3 = s / e9 + 1;\n    cout << x1 << ' ' << y1 << ' ';\n    cout << x2 << ' ' << y2 << ' ';\n    cout << x3 << ' ' << y3;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1600137813, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p02963.html", "problem_id": "p02963", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02963/input.txt", "sample_output_relpath": "derived/input_output/data/p02963/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02963/C++/s598107180.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s598107180", "user_id": "u171336585"}, "prompt_components": {"gold_output": "1 0 2 2 0 1\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define rep(i,n) for (int i = 0; i < (n); ++i)\nusing namespace std;\nusing ll = long long;\nusing P = pair<int,int>;\n\nconst ll e9 = 1000000000;\n\nint main() {\n    ll s;\n    cin >> s;\n    ll x1 = 0, y1 = 0;\n    ll x2 = e9, y2 = 1;\n    ll x3 = (s % e9) + e9;\n    ll y3 = s / e9 + 1;\n    cout << x1 << ' ' << y1 << ' ';\n    cout << x2 << ' ' << y2 << ' ';\n    cout << x3 << ' ' << y3;\n    return 0;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nGiven is an integer S.\nFind a combination of six integers X_1,Y_1,X_2,Y_2,X_3, and Y_3 that satisfies all of the following conditions:\n\n0 \\leq X_1,Y_1,X_2,Y_2,X_3,Y_3 \\leq 10^9\n\nThe area of the triangle in a two-dimensional plane whose vertices are (X_1,Y_1),(X_2,Y_2), and (X_3,Y_3) is S/2.\n\nWe can prove that there always exist six integers that satisfy the conditions under the constraints of this problem.\n\nConstraints\n\n1 \\leq S \\leq 10^{18}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint six integers X_1,Y_1,X_2,Y_2,X_3, and Y_3 that satisfy the conditions, in this order, with spaces in between.\nIf multiple solutions exist, any of them will be accepted.\n\nSample Input 1\n\n3\n\nSample Output 1\n\n1 0 2 2 0 1\n\nThe area of the triangle in a two-dimensional plane whose vertices are (1,0),(2,2), and (0,1) is 3/2.\nPrinting 3 0 3 1 0 1 or 1 0 0 1 2 2 will also be accepted.\n\nSample Input 2\n\n100\n\nSample Output 2\n\n0 0 10 0 0 10\n\nSample Input 3\n\n311114770564041497\n\nSample Output 3\n\n314159265 358979323 846264338 327950288 419716939 937510582", "sample_input": "3\n"}, "reference_outputs": ["1 0 2 2 0 1\n"], "source_document_id": "p02963", "source_text": "Score : 400 points\n\nProblem Statement\n\nGiven is an integer S.\nFind a combination of six integers X_1,Y_1,X_2,Y_2,X_3, and Y_3 that satisfies all of the following conditions:\n\n0 \\leq X_1,Y_1,X_2,Y_2,X_3,Y_3 \\leq 10^9\n\nThe area of the triangle in a two-dimensional plane whose vertices are (X_1,Y_1),(X_2,Y_2), and (X_3,Y_3) is S/2.\n\nWe can prove that there always exist six integers that satisfy the conditions under the constraints of this problem.\n\nConstraints\n\n1 \\leq S \\leq 10^{18}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint six integers X_1,Y_1,X_2,Y_2,X_3, and Y_3 that satisfy the conditions, in this order, with spaces in between.\nIf multiple solutions exist, any of them will be accepted.\n\nSample Input 1\n\n3\n\nSample Output 1\n\n1 0 2 2 0 1\n\nThe area of the triangle in a two-dimensional plane whose vertices are (1,0),(2,2), and (0,1) is 3/2.\nPrinting 3 0 3 1 0 1 or 1 0 0 1 2 2 will also be accepted.\n\nSample Input 2\n\n100\n\nSample Output 2\n\n0 0 10 0 0 10\n\nSample Input 3\n\n311114770564041497\n\nSample Output 3\n\n314159265 358979323 846264338 327950288 419716939 937510582", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 419, "cpu_time_ms": 10, "memory_kb": 3520}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s453454310", "group_id": "codeNet:p02963", "input_text": "#include<stdio.h>\nint main(){\n  unsigned long long int s;\n  scanf(\"%ulld\",&s);\n  if(s%2==0){\n    printf(\"0 0 2 0 0 %ulld\",s/2);\n  }\n  else{\n    printf(\"1 0 0 %ld 2 %ulld\",s/2+1,s/2);\n  }\n}\n", "language": "C++", "metadata": {"date": 1563760094, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02963.html", "problem_id": "p02963", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02963/input.txt", "sample_output_relpath": "derived/input_output/data/p02963/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02963/C++/s453454310.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s453454310", "user_id": "u222643545"}, "prompt_components": {"gold_output": "1 0 2 2 0 1\n", "input_to_evaluate": "#include<stdio.h>\nint main(){\n  unsigned long long int s;\n  scanf(\"%ulld\",&s);\n  if(s%2==0){\n    printf(\"0 0 2 0 0 %ulld\",s/2);\n  }\n  else{\n    printf(\"1 0 0 %ld 2 %ulld\",s/2+1,s/2);\n  }\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nGiven is an integer S.\nFind a combination of six integers X_1,Y_1,X_2,Y_2,X_3, and Y_3 that satisfies all of the following conditions:\n\n0 \\leq X_1,Y_1,X_2,Y_2,X_3,Y_3 \\leq 10^9\n\nThe area of the triangle in a two-dimensional plane whose vertices are (X_1,Y_1),(X_2,Y_2), and (X_3,Y_3) is S/2.\n\nWe can prove that there always exist six integers that satisfy the conditions under the constraints of this problem.\n\nConstraints\n\n1 \\leq S \\leq 10^{18}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint six integers X_1,Y_1,X_2,Y_2,X_3, and Y_3 that satisfy the conditions, in this order, with spaces in between.\nIf multiple solutions exist, any of them will be accepted.\n\nSample Input 1\n\n3\n\nSample Output 1\n\n1 0 2 2 0 1\n\nThe area of the triangle in a two-dimensional plane whose vertices are (1,0),(2,2), and (0,1) is 3/2.\nPrinting 3 0 3 1 0 1 or 1 0 0 1 2 2 will also be accepted.\n\nSample Input 2\n\n100\n\nSample Output 2\n\n0 0 10 0 0 10\n\nSample Input 3\n\n311114770564041497\n\nSample Output 3\n\n314159265 358979323 846264338 327950288 419716939 937510582", "sample_input": "3\n"}, "reference_outputs": ["1 0 2 2 0 1\n"], "source_document_id": "p02963", "source_text": "Score : 400 points\n\nProblem Statement\n\nGiven is an integer S.\nFind a combination of six integers X_1,Y_1,X_2,Y_2,X_3, and Y_3 that satisfies all of the following conditions:\n\n0 \\leq X_1,Y_1,X_2,Y_2,X_3,Y_3 \\leq 10^9\n\nThe area of the triangle in a two-dimensional plane whose vertices are (X_1,Y_1),(X_2,Y_2), and (X_3,Y_3) is S/2.\n\nWe can prove that there always exist six integers that satisfy the conditions under the constraints of this problem.\n\nConstraints\n\n1 \\leq S \\leq 10^{18}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint six integers X_1,Y_1,X_2,Y_2,X_3, and Y_3 that satisfy the conditions, in this order, with spaces in between.\nIf multiple solutions exist, any of them will be accepted.\n\nSample Input 1\n\n3\n\nSample Output 1\n\n1 0 2 2 0 1\n\nThe area of the triangle in a two-dimensional plane whose vertices are (1,0),(2,2), and (0,1) is 3/2.\nPrinting 3 0 3 1 0 1 or 1 0 0 1 2 2 will also be accepted.\n\nSample Input 2\n\n100\n\nSample Output 2\n\n0 0 10 0 0 10\n\nSample Input 3\n\n311114770564041497\n\nSample Output 3\n\n314159265 358979323 846264338 327950288 419716939 937510582", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 189, "cpu_time_ms": 1, "memory_kb": 128}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s207700475", "group_id": "codeNet:p02964", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nll INF = 1e9+7;\nint main()\n{\n    ll n, k;\n    cin >> n >> k;\n    vector<ll> a(n);\n    for(int i = 0; i < n; i++) cin >> a[i];\n    vector<ll> ar = a;\n    reverse(ar.begin(), ar.end());\n    vector<set<ll>> pos(2*1e5+10);\n    for(int i = 0; i < n; i++)\n    {\n        pos[ar[i]].insert(i+1);\n        if(pos[ar[i]].size() == 1)\n        {\n            pos[ar[i]].insert(i+1+n);\n        }\n    }\n\n    vector<ll> start(n+1);\n    int p = 1;\n    ll v = ar[0];\n    ll ans = 0;\n    while(true)\n    {\n        ll next = *(pos[v].lower_bound(p+1));\n        if(next == n)\n        {\n            start[ans] = next;   \n            break;\n        }\n        else if(next == 2*n)\n        {\n            ans++;\n            start[ans] = next - n;\n            break;\n        }\n        else if(next > n)\n        {\n            p = next+1-n;\n            ans++;\n            start[ans] = p-1;\n        }\n        else\n        {\n            p = next+1;\n            start[ans] = next;\n        }\n        v = ar[p-1];\n    }\n    ans++;\n    ll count = k % ans;\n    if(count == 0) return 0;\n    ll s = start[ans-count];\n    stack<ll> sta;\n    set<ll> tmp;\n    for(int i = n-s; i < n; i++)\n    {\n        if(tmp.find(a[i]) == tmp.end())\n        {\n            tmp.insert(a[i]);\n            sta.push(a[i]);\n        }\n        else\n        {\n          while(true)\n            {\n                ll cand = sta.top();\n                sta.pop();\n                tmp.erase(cand);\n                if(cand == a[i])\n                {\n                    break;\n                }\n            }\n        }\n    }\n    stack<ll> ansq;\n    ll size = sta.size();\n    for(int i = 0; i < size; i++)\n    {\n        ll cand = sta.top();\n        sta.pop();\n        ansq.push(cand);\n    }\n    ll anss = ansq.size();\n    for(int i = 0; i < anss; i++)\n    {\n        ll cand = ansq.top();\n        ansq.pop();\n        cout << cand << \" \";\n    }\n}\n", "language": "C++", "metadata": {"date": 1571506098, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02964.html", "problem_id": "p02964", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02964/input.txt", "sample_output_relpath": "derived/input_output/data/p02964/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02964/C++/s207700475.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s207700475", "user_id": "u410878763"}, "prompt_components": {"gold_output": "2 3\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nll INF = 1e9+7;\nint main()\n{\n    ll n, k;\n    cin >> n >> k;\n    vector<ll> a(n);\n    for(int i = 0; i < n; i++) cin >> a[i];\n    vector<ll> ar = a;\n    reverse(ar.begin(), ar.end());\n    vector<set<ll>> pos(2*1e5+10);\n    for(int i = 0; i < n; i++)\n    {\n        pos[ar[i]].insert(i+1);\n        if(pos[ar[i]].size() == 1)\n        {\n            pos[ar[i]].insert(i+1+n);\n        }\n    }\n\n    vector<ll> start(n+1);\n    int p = 1;\n    ll v = ar[0];\n    ll ans = 0;\n    while(true)\n    {\n        ll next = *(pos[v].lower_bound(p+1));\n        if(next == n)\n        {\n            start[ans] = next;   \n            break;\n        }\n        else if(next == 2*n)\n        {\n            ans++;\n            start[ans] = next - n;\n            break;\n        }\n        else if(next > n)\n        {\n            p = next+1-n;\n            ans++;\n            start[ans] = p-1;\n        }\n        else\n        {\n            p = next+1;\n            start[ans] = next;\n        }\n        v = ar[p-1];\n    }\n    ans++;\n    ll count = k % ans;\n    if(count == 0) return 0;\n    ll s = start[ans-count];\n    stack<ll> sta;\n    set<ll> tmp;\n    for(int i = n-s; i < n; i++)\n    {\n        if(tmp.find(a[i]) == tmp.end())\n        {\n            tmp.insert(a[i]);\n            sta.push(a[i]);\n        }\n        else\n        {\n          while(true)\n            {\n                ll cand = sta.top();\n                sta.pop();\n                tmp.erase(cand);\n                if(cand == a[i])\n                {\n                    break;\n                }\n            }\n        }\n    }\n    stack<ll> ansq;\n    ll size = sta.size();\n    for(int i = 0; i < size; i++)\n    {\n        ll cand = sta.top();\n        sta.pop();\n        ansq.push(cand);\n    }\n    ll anss = ansq.size();\n    for(int i = 0; i < anss; i++)\n    {\n        ll cand = ansq.top();\n        ansq.pop();\n        cout << cand << \" \";\n    }\n}\n", "problem_context": "Score : 700 points\n\nProblem Statement\n\nWe have a sequence of N \\times K integers: X=(X_0,X_1,\\cdots,X_{N \\times K-1}).\nIts elements are represented by another sequence of N integers: A=(A_0,A_1,\\cdots,A_{N-1}). For each pair i, j (0 \\leq i \\leq K-1,\\ 0 \\leq j \\leq N-1), X_{i \\times N + j}=A_j holds.\n\nSnuke has an integer sequence s, which is initially empty.\nFor each i=0,1,2,\\cdots,N \\times K-1, in this order, he will perform the following operation:\n\nIf s does not contain X_i: add X_i to the end of s.\n\nIf s does contain X_i: repeatedly delete the element at the end of s until s no longer contains X_i. Note that, in this case, we do not add X_i to the end of s.\n\nFind the elements of s after Snuke finished the operations.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq K \\leq 10^{12}\n\n1 \\leq A_i \\leq 2 \\times 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nA_0 A_1 \\cdots A_{N-1}\n\nOutput\n\nPrint the elements of s after Snuke finished the operations, in order from beginning to end, with spaces in between.\n\nSample Input 1\n\n3 2\n1 2 3\n\nSample Output 1\n\n2 3\n\nIn this case, X=(1,2,3,1,2,3).\nWe will perform the operations as follows:\n\ni=0: s does not contain 1, so we add 1 to the end of s, resulting in s=(1).\n\ni=1: s does not contain 2, so we add 2 to the end of s, resulting in s=(1,2).\n\ni=2: s does not contain 3, so we add 3 to the end of s, resulting in s=(1,2,3).\n\ni=3: s does contain 1, so we repeatedly delete the element at the end of s as long as s contains 1, which causes the following changes to s: (1,2,3)→(1,2)→(1)→().\n\ni=4: s does not contain 2, so we add 2 to the end of s, resulting in s=(2).\n\ni=5: s does not contain 3, so we add 3 to the end of s, resulting in s=(2,3).\n\nSample Input 2\n\n5 10\n1 2 3 2 3\n\nSample Output 2\n\n3\n\nSample Input 3\n\n6 1000000000000\n1 1 2 2 3 3\n\nSample Output 3\n\ns may be empty in the end.\n\nSample Input 4\n\n11 97\n3 1 4 1 5 9 2 6 5 3 5\n\nSample Output 4\n\n9 2 6", "sample_input": "3 2\n1 2 3\n"}, "reference_outputs": ["2 3\n"], "source_document_id": "p02964", "source_text": "Score : 700 points\n\nProblem Statement\n\nWe have a sequence of N \\times K integers: X=(X_0,X_1,\\cdots,X_{N \\times K-1}).\nIts elements are represented by another sequence of N integers: A=(A_0,A_1,\\cdots,A_{N-1}). For each pair i, j (0 \\leq i \\leq K-1,\\ 0 \\leq j \\leq N-1), X_{i \\times N + j}=A_j holds.\n\nSnuke has an integer sequence s, which is initially empty.\nFor each i=0,1,2,\\cdots,N \\times K-1, in this order, he will perform the following operation:\n\nIf s does not contain X_i: add X_i to the end of s.\n\nIf s does contain X_i: repeatedly delete the element at the end of s until s no longer contains X_i. Note that, in this case, we do not add X_i to the end of s.\n\nFind the elements of s after Snuke finished the operations.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq K \\leq 10^{12}\n\n1 \\leq A_i \\leq 2 \\times 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nA_0 A_1 \\cdots A_{N-1}\n\nOutput\n\nPrint the elements of s after Snuke finished the operations, in order from beginning to end, with spaces in between.\n\nSample Input 1\n\n3 2\n1 2 3\n\nSample Output 1\n\n2 3\n\nIn this case, X=(1,2,3,1,2,3).\nWe will perform the operations as follows:\n\ni=0: s does not contain 1, so we add 1 to the end of s, resulting in s=(1).\n\ni=1: s does not contain 2, so we add 2 to the end of s, resulting in s=(1,2).\n\ni=2: s does not contain 3, so we add 3 to the end of s, resulting in s=(1,2,3).\n\ni=3: s does contain 1, so we repeatedly delete the element at the end of s as long as s contains 1, which causes the following changes to s: (1,2,3)→(1,2)→(1)→().\n\ni=4: s does not contain 2, so we add 2 to the end of s, resulting in s=(2).\n\ni=5: s does not contain 3, so we add 3 to the end of s, resulting in s=(2,3).\n\nSample Input 2\n\n5 10\n1 2 3 2 3\n\nSample Output 2\n\n3\n\nSample Input 3\n\n6 1000000000000\n1 1 2 2 3 3\n\nSample Output 3\n\ns may be empty in the end.\n\nSample Input 4\n\n11 97\n3 1 4 1 5 9 2 6 5 3 5\n\nSample Output 4\n\n9 2 6", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1940, "cpu_time_ms": 232, "memory_kb": 45440}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s935226814", "group_id": "codeNet:p02966", "input_text": "/*\n * Author       : YangDavid\n * Created Time : 2019年07月22日 星期一 11时13分09秒\n */\n\n#include<bits/stdc++.h>\n#define rep(i, n) for(int i = 1; i <= n; ++i)\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int, int> pii;\n\nconst int maxn = 555;\nconst ll INF = 0x3f3f3f3f3f3f3f3f;\nint n, a[maxn][maxn];\nll dp[maxn][maxn], pre1[maxn][maxn], pre2[maxn][maxn];\nvoid upd(ll &x, ll y) { if(x > y) x = y; }\n\nint main() {\n    scanf(\"%d\", &n);\n    rep(i, n) rep(j, n) if(i != j) scanf(\"%d\", &a[i][j]);\n    rep(i, n) rep(j, n) {\n        pre1[i][j] = pre1[i - 1][j] + pre1[i][j - 1] - pre1[i - 1][j - 1] + a[i][j];\n        pre2[i][j] = pre2[i - 1][j] + pre2[i][j - 1] - pre2[i - 1][j - 1] + (i<j ? a[i][j] : 0);\n    }\n\n    memset(dp, 0x3f, sizeof dp);\n\n    dp[0][0] = 0;\n    for(int i = 0; i < n; ++i) {\n        for(int last = 0; last <= i; ++last) {\n            for(int j = i + 1; j <= n; ++j) {\n                upd(dp[j][i], dp[i][last] + pre1[j][last] - pre1[i][last] + pre2[j][j] - pre2[i][j] - pre2[j][i] + pre2[i][i]); \n            }\n        }\n    }\n    ll ans = INF;\n    for(int last = 0; last < n; ++last)\n        upd(ans, dp[n][last]);\n    printf(\"%lld\\n\", ans);\n\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1563814418, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02966.html", "problem_id": "p02966", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02966/input.txt", "sample_output_relpath": "derived/input_output/data/p02966/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02966/C++/s935226814.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s935226814", "user_id": "u768128363"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "/*\n * Author       : YangDavid\n * Created Time : 2019年07月22日 星期一 11时13分09秒\n */\n\n#include<bits/stdc++.h>\n#define rep(i, n) for(int i = 1; i <= n; ++i)\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int, int> pii;\n\nconst int maxn = 555;\nconst ll INF = 0x3f3f3f3f3f3f3f3f;\nint n, a[maxn][maxn];\nll dp[maxn][maxn], pre1[maxn][maxn], pre2[maxn][maxn];\nvoid upd(ll &x, ll y) { if(x > y) x = y; }\n\nint main() {\n    scanf(\"%d\", &n);\n    rep(i, n) rep(j, n) if(i != j) scanf(\"%d\", &a[i][j]);\n    rep(i, n) rep(j, n) {\n        pre1[i][j] = pre1[i - 1][j] + pre1[i][j - 1] - pre1[i - 1][j - 1] + a[i][j];\n        pre2[i][j] = pre2[i - 1][j] + pre2[i][j - 1] - pre2[i - 1][j - 1] + (i<j ? a[i][j] : 0);\n    }\n\n    memset(dp, 0x3f, sizeof dp);\n\n    dp[0][0] = 0;\n    for(int i = 0; i < n; ++i) {\n        for(int last = 0; last <= i; ++last) {\n            for(int j = i + 1; j <= n; ++j) {\n                upd(dp[j][i], dp[i][last] + pre1[j][last] - pre1[i][last] + pre2[j][j] - pre2[i][j] - pre2[j][i] + pre2[i][i]); \n            }\n        }\n    }\n    ll ans = INF;\n    for(int last = 0; last < n; ++last)\n        upd(ans, dp[n][last]);\n    printf(\"%lld\\n\", ans);\n\n    return 0;\n}\n", "problem_context": "Score : 1200 points\n\nProblem Statement\n\nWe have a weighted directed graph with N vertices numbered 0 to N-1.\n\nThe graph initially has N-1 edges. The i-th edge (0 \\leq i \\leq N-2) is directed from Vertex i to Vertex i+1 and has a weight of 0.\n\nSnuke will now add a new edge (i → j) for every pair i, j (0 \\leq i,j \\leq N-1,\\ i \\neq j).\nThe weight of the edge will be -1 if i < j, and 1 otherwise.\n\nRingo is a boy. A negative cycle (a cycle whose total weight is negative) in a graph makes him sad.\nHe will delete some of the edges added by Snuke so that the graph will no longer contain a negative cycle.\nThe cost of deleting the edge (i → j) is A_{i,j}. He cannot delete edges that have been present from the beginning.\n\nFind the minimum total cost required to achieve Ringo's objective.\n\nConstraints\n\n3 \\leq N \\leq 500\n\n1 \\leq A_{i,j} \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_{0,1} A_{0,2} A_{0,3} \\cdots A_{0,N-1}\nA_{1,0} A_{1,2} A_{1,3} \\cdots A_{1,N-1}\nA_{2,0} A_{2,1} A_{2,3} \\cdots A_{2,N-1}\n\\vdots\nA_{N-1,0} A_{N-1,1} A_{N-1,2} \\cdots A_{N-1,N-2}\n\nOutput\n\nPrint the minimum total cost required to achieve Ringo's objective.\n\nSample Input 1\n\n3\n2 1\n1 4\n3 3\n\nSample Output 1\n\n2\n\nIf we delete the edge (0 → 1) added by Snuke, the graph will no longer contain a negative cycle.\nThe cost will be 2 in this case, which is the minimum possible.\n\nSample Input 2\n\n4\n1 1 1\n1 1 1\n1 1 1\n1 1 1\n\nSample Output 2\n\n2\n\nIf we delete the edges (1 → 2) and (3 → 0) added by Snuke, the graph will no longer contain a negative cycle.\nThe cost will be 1+1=2 in this case, which is the minimum possible.\n\nSample Input 3\n\n10\n190587 2038070 142162180 88207341 215145790 38 2 5 20\n32047998 21426 4177178 52 734621629 2596 102224223 5 1864\n41 481241221 1518272 51 772 146 8805349 3243297 449\n918151 126080576 5186563 46354 6646 491776 5750138 2897 161\n3656 7551068 2919714 43035419 495 3408 26 3317 2698\n455357 3 12 1857 5459 7870 4123856 2402 258\n3 25700 16191 102120 971821039 52375 40449 20548149 16186673\n2 16 130300357 18 6574485 29175 179 1693 2681\n99 833 131 2 414045824 57357 56 302669472 95\n8408 7 1266941 60620177 129747 41382505 38966 187 5151064\n\nSample Output 3\n\n2280211", "sample_input": "3\n2 1\n1 4\n3 3\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02966", "source_text": "Score : 1200 points\n\nProblem Statement\n\nWe have a weighted directed graph with N vertices numbered 0 to N-1.\n\nThe graph initially has N-1 edges. The i-th edge (0 \\leq i \\leq N-2) is directed from Vertex i to Vertex i+1 and has a weight of 0.\n\nSnuke will now add a new edge (i → j) for every pair i, j (0 \\leq i,j \\leq N-1,\\ i \\neq j).\nThe weight of the edge will be -1 if i < j, and 1 otherwise.\n\nRingo is a boy. A negative cycle (a cycle whose total weight is negative) in a graph makes him sad.\nHe will delete some of the edges added by Snuke so that the graph will no longer contain a negative cycle.\nThe cost of deleting the edge (i → j) is A_{i,j}. He cannot delete edges that have been present from the beginning.\n\nFind the minimum total cost required to achieve Ringo's objective.\n\nConstraints\n\n3 \\leq N \\leq 500\n\n1 \\leq A_{i,j} \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_{0,1} A_{0,2} A_{0,3} \\cdots A_{0,N-1}\nA_{1,0} A_{1,2} A_{1,3} \\cdots A_{1,N-1}\nA_{2,0} A_{2,1} A_{2,3} \\cdots A_{2,N-1}\n\\vdots\nA_{N-1,0} A_{N-1,1} A_{N-1,2} \\cdots A_{N-1,N-2}\n\nOutput\n\nPrint the minimum total cost required to achieve Ringo's objective.\n\nSample Input 1\n\n3\n2 1\n1 4\n3 3\n\nSample Output 1\n\n2\n\nIf we delete the edge (0 → 1) added by Snuke, the graph will no longer contain a negative cycle.\nThe cost will be 2 in this case, which is the minimum possible.\n\nSample Input 2\n\n4\n1 1 1\n1 1 1\n1 1 1\n1 1 1\n\nSample Output 2\n\n2\n\nIf we delete the edges (1 → 2) and (3 → 0) added by Snuke, the graph will no longer contain a negative cycle.\nThe cost will be 1+1=2 in this case, which is the minimum possible.\n\nSample Input 3\n\n10\n190587 2038070 142162180 88207341 215145790 38 2 5 20\n32047998 21426 4177178 52 734621629 2596 102224223 5 1864\n41 481241221 1518272 51 772 146 8805349 3243297 449\n918151 126080576 5186563 46354 6646 491776 5750138 2897 161\n3656 7551068 2919714 43035419 495 3408 26 3317 2698\n455357 3 12 1857 5459 7870 4123856 2402 258\n3 25700 16191 102120 971821039 52375 40449 20548149 16186673\n2 16 130300357 18 6574485 29175 179 1693 2681\n99 833 131 2 414045824 57357 56 302669472 95\n8408 7 1266941 60620177 129747 41382505 38966 187 5151064\n\nSample Output 3\n\n2280211", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1195, "cpu_time_ms": 606, "memory_kb": 8576}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s357719254", "group_id": "codeNet:p02971", "input_text": "#include <iostream>\n#include <vector>\n#include <map>\n#include <unordered_map>\n#include <queue>\n#include <set>\n#include <algorithm>\n#include <string>\n#include <math.h>\n#include <limits.h>\n#include <stack>\n#include <complex>\n#include <stdlib.h>\n#include <stdio.h>\n#include <functional>\n#include <cfloat>\n\n#define Rep(i,n) for(int (i)=0;(i)<(int)(n);++(i))\n#define Sort(a) sort(a.begin(), a.end())\n#define Reverse(a) reverse(a.begin(), a.end())\n\n#define eb emplace_back\n#define dbg(x) cout<<#x\" = \"<<((x))<<endl\n#define fs first\n#define sc second\n     \nusing namespace std;\n     \n     \ntypedef long long ll;\ntypedef pair<ll, ll> P;\n     \n     \nint main(){\n  ll N;\n\n  cin >> N;\n\n#ifdef DEBUG\n  cout << \"N=\" << endl;\n#endif\n\n  ll arr[N];\n  ll max = 0;\n  ll max2 = 0;\n  int max_index = 0;\n  for(int i = 0; i < N; i++){\n    cin >> arr[i];\n    if(arr[i] > max){\n      max2 = max;\n      max = arr[i];\n      max_index = i;\n    } else if (arr[i] > max2){\n      max2 = arr[i];\n    }\n  }\n\n  for(int i = 0; i < N; i++){\n    if(i == max_index) cout << max2 << endl;\n    else cout << max << endl;\n  }\n  \n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1563671539, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02971.html", "problem_id": "p02971", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02971/input.txt", "sample_output_relpath": "derived/input_output/data/p02971/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02971/C++/s357719254.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s357719254", "user_id": "u714724786"}, "prompt_components": {"gold_output": "4\n3\n4\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\n#include <map>\n#include <unordered_map>\n#include <queue>\n#include <set>\n#include <algorithm>\n#include <string>\n#include <math.h>\n#include <limits.h>\n#include <stack>\n#include <complex>\n#include <stdlib.h>\n#include <stdio.h>\n#include <functional>\n#include <cfloat>\n\n#define Rep(i,n) for(int (i)=0;(i)<(int)(n);++(i))\n#define Sort(a) sort(a.begin(), a.end())\n#define Reverse(a) reverse(a.begin(), a.end())\n\n#define eb emplace_back\n#define dbg(x) cout<<#x\" = \"<<((x))<<endl\n#define fs first\n#define sc second\n     \nusing namespace std;\n     \n     \ntypedef long long ll;\ntypedef pair<ll, ll> P;\n     \n     \nint main(){\n  ll N;\n\n  cin >> N;\n\n#ifdef DEBUG\n  cout << \"N=\" << endl;\n#endif\n\n  ll arr[N];\n  ll max = 0;\n  ll max2 = 0;\n  int max_index = 0;\n  for(int i = 0; i < N; i++){\n    cin >> arr[i];\n    if(arr[i] > max){\n      max2 = max;\n      max = arr[i];\n      max_index = i;\n    } else if (arr[i] > max2){\n      max2 = arr[i];\n    }\n  }\n\n  for(int i = 0; i < N; i++){\n    if(i == max_index) cout << max2 << endl;\n    else cout << max << endl;\n  }\n  \n  return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nYou are given a sequence of length N: A_1, A_2, ..., A_N.\nFor each integer i between 1 and N (inclusive), answer the following question:\n\nFind the maximum value among the N-1 elements other than A_i in the sequence.\n\nConstraints\n\n2 \\leq N \\leq 200000\n\n1 \\leq A_i \\leq 200000\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1\n:\nA_N\n\nOutput\n\nPrint N lines. The i-th line (1 \\leq i \\leq N) should contain the maximum value among the N-1 elements other than A_i in the sequence.\n\nSample Input 1\n\n3\n1\n4\n3\n\nSample Output 1\n\n4\n3\n4\n\nThe maximum value among the two elements other than A_1, that is, A_2 = 4 and A_3 = 3, is 4.\n\nThe maximum value among the two elements other than A_2, that is, A_1 = 1 and A_3 = 3, is 3.\n\nThe maximum value among the two elements other than A_3, that is, A_1 = 1 and A_2 = 4, is 4.\n\nSample Input 2\n\n2\n5\n5\n\nSample Output 2\n\n5\n5", "sample_input": "3\n1\n4\n3\n"}, "reference_outputs": ["4\n3\n4\n"], "source_document_id": "p02971", "source_text": "Score : 300 points\n\nProblem Statement\n\nYou are given a sequence of length N: A_1, A_2, ..., A_N.\nFor each integer i between 1 and N (inclusive), answer the following question:\n\nFind the maximum value among the N-1 elements other than A_i in the sequence.\n\nConstraints\n\n2 \\leq N \\leq 200000\n\n1 \\leq A_i \\leq 200000\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1\n:\nA_N\n\nOutput\n\nPrint N lines. The i-th line (1 \\leq i \\leq N) should contain the maximum value among the N-1 elements other than A_i in the sequence.\n\nSample Input 1\n\n3\n1\n4\n3\n\nSample Output 1\n\n4\n3\n4\n\nThe maximum value among the two elements other than A_1, that is, A_2 = 4 and A_3 = 3, is 4.\n\nThe maximum value among the two elements other than A_2, that is, A_1 = 1 and A_3 = 3, is 3.\n\nThe maximum value among the two elements other than A_3, that is, A_1 = 1 and A_2 = 4, is 4.\n\nSample Input 2\n\n2\n5\n5\n\nSample Output 2\n\n5\n5", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1102, "cpu_time_ms": 364, "memory_kb": 3200}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s406428675", "group_id": "codeNet:p02973", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nbool chmax(long long &a, long long b){\n    if(a <= b){\n        a = b;\n        return true;\n    }else{\n        return false;\n    }\n}\n\nint main(){\n    int N;\n    cin >> N;\n    vector<long long> A(N);\n    for(int i = 0; i < N; i++)cin >> A[i];\n    reverse(A.begin(), A.end());\n    long long now = A[0];\n    int cnt = 1;\n    for(int i = 1; i < N; i++){\n        if(chmax(now, A[i])){\n            cnt++;\n        }\n    }\n    cout << cnt << endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1571319515, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02973.html", "problem_id": "p02973", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02973/input.txt", "sample_output_relpath": "derived/input_output/data/p02973/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02973/C++/s406428675.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s406428675", "user_id": "u615258936"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nbool chmax(long long &a, long long b){\n    if(a <= b){\n        a = b;\n        return true;\n    }else{\n        return false;\n    }\n}\n\nint main(){\n    int N;\n    cin >> N;\n    vector<long long> A(N);\n    for(int i = 0; i < N; i++)cin >> A[i];\n    reverse(A.begin(), A.end());\n    long long now = A[0];\n    int cnt = 1;\n    for(int i = 1; i < N; i++){\n        if(chmax(now, A[i])){\n            cnt++;\n        }\n    }\n    cout << cnt << endl;\n    return 0;\n}", "problem_context": "Score : 500 points\n\nProblem Statement\n\nYou are given a sequence with N integers: A = \\{ A_1, A_2, \\cdots, A_N \\}.\nFor each of these N integers, we will choose a color and paint the integer with that color. Here the following condition must be satisfied:\n\nIf A_i and A_j (i < j) are painted with the same color, A_i < A_j.\n\nFind the minimum number of colors required to satisfy the condition.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n0 \\leq A_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1\n:\nA_N\n\nOutput\n\nPrint the minimum number of colors required to satisfy the condition.\n\nSample Input 1\n\n5\n2\n1\n4\n5\n3\n\nSample Output 1\n\n2\n\nWe can satisfy the condition with two colors by, for example, painting 2 and 3 red and painting 1, 4, and 5 blue.\n\nSample Input 2\n\n4\n0\n0\n0\n0\n\nSample Output 2\n\n4\n\nWe have to paint all the integers with distinct colors.", "sample_input": "5\n2\n1\n4\n5\n3\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02973", "source_text": "Score : 500 points\n\nProblem Statement\n\nYou are given a sequence with N integers: A = \\{ A_1, A_2, \\cdots, A_N \\}.\nFor each of these N integers, we will choose a color and paint the integer with that color. Here the following condition must be satisfied:\n\nIf A_i and A_j (i < j) are painted with the same color, A_i < A_j.\n\nFind the minimum number of colors required to satisfy the condition.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n0 \\leq A_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1\n:\nA_N\n\nOutput\n\nPrint the minimum number of colors required to satisfy the condition.\n\nSample Input 1\n\n5\n2\n1\n4\n5\n3\n\nSample Output 1\n\n2\n\nWe can satisfy the condition with two colors by, for example, painting 2 and 3 red and painting 1, 4, and 5 blue.\n\nSample Input 2\n\n4\n0\n0\n0\n0\n\nSample Output 2\n\n4\n\nWe have to paint all the integers with distinct colors.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 501, "cpu_time_ms": 43, "memory_kb": 1024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s109717720", "group_id": "codeNet:p02975", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\ntemplate <class T> using V = vector<T>;\ntemplate <class T> using VV = V<V<T>>;\ntemplate <class T> using VVV = V<VV<T>>;\ntemplate <class S, class T> using P = pair<S, T>;\ntemplate <class S, class T, class U> using TP = tuple<S, T, U>;\n\nusing ll = long long;\nusing ull = unsigned long long;\nusing dbl = double;\nusing str = string;\nusing vll = V<ll>;\nusing vvll = V<vll>;\nusing vvvll = V<vvll>;\nusing pl = P<ll, ll>;\nusing tl = TP<ll, ll, ll>;\nusing vpl = V<pl>;\nusing vvpl = V<vpl>;\nusing vtl = V<tl>;\nusing vvtl = V<vtl>;\nusing vs = V<str>;\nusing vvs = V<vs>;\nusing vd = V<dbl>;\nusing vvd = V<vd>;\nusing qll = queue<ll>;\nusing qpl = queue<pl>;\nusing stll = stack<ll>;\nusing stpl = stack<pl>;\nusing mapll = map<ll, ll>;\nusing setll = set<ll>;\nusing pqll = priority_queue<ll>;\n\n#define int ll\n#define fi first\n#define se second\n#define mp make_pair\n#define mt make_tuple\n#define pb push_back\n#define pob pop_back()\n#define pf push_front\n#define pof pop_front()\n#define sz size()\n#define bgn begin()\n#define en end()\n#define asn assign\n#define emp empty()\n#define fr front()\n#define bk back()\n#define clr clear()\n#define ins insert\n#define ers erase\n#define res resize\n#define tp top()\n#define p_q priority_queue\n#define inv inverse()\n\n#define FOR(i,a,b) for(ll i=(a);i<=(ll)(b);i++)\n#define rFOR(i,a,b) for(ll i=(b);i>=(ll)(a);i--)\n#define REP(i,a) FOR((i),0,(ll)(a)-1)\n#define REP0(i,a) FOR((i),0,(ll)(a))\n#define REP1(i,a) FOR((i),1,(ll)(a))\n#define rREP(i,a) rFOR((i),0,(ll)(a)-1)\n#define rREP0(i,a) rFOR((i),0,(ll)(a))\n#define rREP1(i,a) rFOR((i),1,(ll)(a))\n#define ROR(v,i) for(auto &(i):(v))\n#define IOTA(a,n) iota((a).bgn,(a).en,(n))\n#define SORT(a) sort((a).bgn,(a).en)\n#define rSORT(a) sort((a).rbegin(),(a).rend())\n#define UNIQUE(a) (a).erase(unique((a).bgn,(a).en),(a).en)\n#define PREVP(a) prev_permutation((a).bgn,(a).en)\n#define NEXTP(a) next_permutation((a).bgn,(a).en)\n#define BINS(a,b) binary_search((a).bgn,(a).en,(b))\n#define LOWB(a,b) (lower_bound((a).bgn,(a).en,(b))-(a).bgn)\n#define UPB(a,b) (upper_bound((a).bgn,(a).en,(b))-(a).bgn)\n#define CNT(a,b) count((a).bgn,(a).en,b)\n#define SUM(a) accumulate((a).bgn,(a).en,0)\n#define REV(a) reverse((a).bgn,(a).en)\n#define REGS(a,b) regex_search((a),regex(b))\n#define REGM(a,b) regex_match((a),regex(b))\n#define yn(a) cout <<((a)?\"yes\":\"no\")<<\"\\n\";\n#define Yn(a) cout <<((a)?\"Yes\":\"No\")<<\"\\n\";\n#define YN(a) cout <<((a)?\"YES\":\"NO\")<<\"\\n\";\n#define imp(a) cout <<((a)?\"possible\":\"impossible\")<<\"\\n\";\n#define Imp(a) cout <<((a)?\"Possible\":\"Impossible\")<<\"\\n\";\n#define IMP(a) cout <<((a)?\"POSSIBLE\":\"IMPOSSIBLE\")<<\"\\n\";\n#define fs(a) cout <<((a)?\"second\":\"first\")<<\"\\n\";\n#define Fs(a) cout <<((a)?\"Second\":\"First\")<<\"\\n\";\n#define FS(a) cout <<((a)?\"SECOND\":\"FIRST\")<<\"\\n\";\n#define sak cout <<\"\\n\";\n#define sas cout <<\" \";\n#define sat cout <<\"\\t\";\n#define dbg(a) cerr <<(#a)<<\": \"<<(a)<<\"\\n\";\n#define dbgs(...) dal(#__VA_ARGS__);dal(__VA_ARGS__);\n#define c2l(a) ((ll)(a-48))\n#define a2l(a) ((ll)(a-97))\n#define A2l(a) ((ll)(a-65))\n#define l2c(a) ((char)(a+48))\n#define l2a(a) ((char)(a+97))\n#define l2A(a) ((char)(a+65))\n#define DigN2(a) ((llabs(a)==0)?(1):((ll)(log2(double(llabs(a))))+1))\n#define DigN10(a) ((llabs(a)==0)?(1):((ll)(log10(double(llabs(a))))+1))\n#define Dig2(a,b) (((a)>>(b))&1)\n#define Dig10(a,b) (ll)(((a)/((ll)(pow(10.0,(double)(b)))))%10)\n#define Pow2(a) ((ll)(1)<<(a))\n#define Pow10(a) ((ll)(pow(10.0,double(a))))\n#define LSB(a) ((a)&(-(a)))\n#define vin(v) ROR((v),(i)){cin >>(i);};\n#define vllin(v,N) vll (v)((N));vin(v);\n#define vllin2(a,b,N) vll (a)(N),(b)(N);REP(i,N){cin>>(a)[i]>>(b)[i];};\n#define vsin(v,N) vs (v)((N));vin(v);\n#define rdn(a,b) ((a)/(b))\n#define rou(a,b) ((((double(a)/double(b))-((a)/(b)))<0.5)?((a)/(b)):(((a)/(b))+1))\n#define rup(a,b) ((((a)%(b))==0)?((a)/(b)):(((a)/(b))+1))\n#define min(...) Min(__VA_ARGS__)\n#define max(...) Max(__VA_ARGS__)\n#define emin(a, ...) ((a)=Min((a),__VA_ARGS__))\n#define emax(a, ...) ((a)=Max((a),__VA_ARGS__))\n#define egcd(a, ...) ((a)=gcd((a),__VA_ARGS__))\n#define elcm(a, ...) ((a)=lcm((a),__VA_ARGS__))\n#define powll(a,b) (ll)(pow((double)(a),(double)(b)))\n#define Triangle(x1,y1,x2,y2,x3,y3) (((x1)-(x2))*((y1)-(y3))-((x1)-(x3))*((y1)-(y2)))\n\n#define svll SumV<ll>\n#define svvll SumV2<ll>\n\n#define li(...) ll __VA_ARGS__;Input(__VA_ARGS__);\n#define si(...) str __VA_ARGS__;Input(__VA_ARGS__);\n#define vli(size, ...) vll __VA_ARGS__;vInput(size,__VA_ARGS__);\n#define vsi(size, ...) vs __VA_ARGS__;vInput(size,__VA_ARGS__);\n\nconst ll MOD = 1e9 + 7;\n//const ll MOD = 998244353;\n//const ll MOD = 924844033;\n//const ll MOD = 9007199254740881;\nconst ll INF = 1LL << 60;//1.15e18\nconst double PI = acos(-1.0);\nconst vll DX = { 0,-1,0,1,0,-1,1,1,-1 };\nconst vll DY = { 0,0,-1,0,1,-1,-1,1,1 };\nconst str alp = \"abcdefghijklmnopqrstuvwxyz\";\nconst str ALP = \"ABCDEFGHIJKLMNOPQRSTUVWXYZ\";\n\n\nvoid Input() {}\ntemplate <class Var, class... Args> void Input(Var& var, Args&... args) {\n    cin >> var;\n    Input(args...);\n}\n\nvoid vInit(ll size) {}\ntemplate <class T, class... Args> void vInit(ll size, V<T>& v, Args&... args) {\n    v.res(size);\n    vInit(size, args...);\n}\nvoid vInputNum(ll num) {}\ntemplate <class T, class... Args> void vInputNum(ll num, V<T>& v, Args&... args) {\n    cin >> v[num];\n    vInputNum(num, args...);\n}\nvoid vInput(ll size) {}\ntemplate <class... Args> void vInput(ll size, Args&... args) {\n    vInit(size, args...);\n    REP(i, size) vInputNum(i, args...);\n}\n\ntemplate <class S, class T> ostream &operator<<(ostream &out, const P<S, T> &p) {\n    return out << \"[\" << p.fi << \", \" << p.se << \"]\";\n}\n\ntemplate <class T> ostream &operator<<(ostream &out, V<T> &v) {\n    if (v.emp) return out << \"{}\";\n    else {\n        auto itr = v.bgn;\n        out << \"{\" << *itr;\n        itr++;\n        while (itr != v.en) {\n            out << \", \" << *itr;\n            itr++;\n        }\n        out << \"}\";\n        return out;\n    }\n}\n\ntemplate <class S, class T> ostream &operator<<(ostream &out, const map<S, T> &m) {\n    if (m.emp) return out << \"<[]>\";\n    else {\n        auto itr = m.bgn;\n        out << \"< [\" << (itr->fi) << \": \" << (itr->se);\n        itr++;\n        while (itr != m.en) {\n            out << \"], [\" << (itr->fi) << \": \" << (itr->se);\n            itr++;\n        }\n        out << \"] >\";\n        return out;\n    }\n}\n\ntemplate <class T> ostream &operator<<(ostream &out, const set<T> &s) {\n    if (s.emp) return out << \"<>\";\n    else {\n        auto itr = s.bgn;\n        out << \"<\" << *itr;\n        itr++;\n        while (itr != s.en) {\n            out << \", \" << *itr;\n            itr++;\n        }\n        out << \">\";\n        return out;\n    }\n}\n\nvoid say() {}\ntemplate <class T> void say(T t) { cout << t; }\ntemplate <class Head, class... Body> void say(Head head, Body... body) {\n    cout << head << \" \";\n    say(body...);\n}\nvoid sal() { cout << \"\\n\"; }\ntemplate <class... Args> void sal(Args... args) {\n    say(args...);\n    cout << \"\\n\";\n}\n\nvoid day() {}\ntemplate <class T> void day(T t) { cerr << t; }\ntemplate <class Head, class... Body> void day(Head head, Body... body) {\n    cerr << head << \" \";\n    day(body...);\n}\nvoid dal() { cerr << \"\\n\"; }\ntemplate <class... Args> void dal(Args... args) {\n    day(args...);\n    cerr << \"\\n\";\n}\n\nvoid salv() {}\ntemplate <class T> void salv(V<T> v) {\n    if (v.emp) sal();\n    else {\n        auto itr = v.bgn;\n        say(*itr);\n        itr++;\n        while (itr != v.en) {\n            sas;\n            say(*itr);\n            itr++;\n        }\n        sak;\n    }\n}\ntemplate <class T, class... Args> void salv(V<T> v, Args... args) {\n    salv(v);\n    salv(args...);\n}\n\nvoid salv2() {}\ntemplate <class T> void salv2(V<V<T>> v) {\n    if (v.emp) sal();\n    else {\n        ROR(v, i) salv(i);\n    }\n}\ntemplate <class T, class... Args> void salv2(V<V<T>> v, Args... args) {\n    salv2(v);\n    salv2(args...);\n}\n\ntemplate <class Monoid> struct Action {\npublic:\n    Monoid I;\n    function<Monoid(Monoid, Monoid)> A;\n    Action(Monoid I, function<Monoid(Monoid, Monoid)> A) : I(I), A(A) {}\n    Monoid operator()() { return I; }\n    Monoid operator()(Monoid x) { return x; }\n    Monoid operator()(Monoid l, Monoid r) { return A(l, r); }\n    template <class... Args> Monoid operator()(Monoid x, Args... args) {\n        Monoid tmp = operator()(args...);   \n        return A(x, tmp);\n    }\n};\n\ntemplate <class T> Action<T> ADD = Action<T>(0, [](T l, T r) { return l + r; });\ntemplate <> Action<str> ADD<str> = Action<str>(\"\", [](str l, str r) { return l + r; });\ntemplate <class T1, class T2> Action<P<T1, T2>> ADD<P<T1, T2>> = Action<P<T1, T2>>(mp(ADD<T1>.I, ADD<T2>.I), [](P<T1, T2> l, P<T1, T2> r) { return mp(l.fi + r.fi, l.se + r.se); });\n\ntemplate <class T> Action<T> MUL = Action<T>(1, [](T l, T r) { return l * r; });\ntemplate <class T> Action<T> OR = Action<T>(0, [](T l, T r) { return l | r; });\ntemplate <class T> Action<T> XOR = Action<T>(0, [](T l, T r) { return l ^ r; });\n\ntemplate <class T> Action<T> AND = Action<T>(((ll)(1) << 63) - 1, [](T l, T r) { return l & r; });\ntemplate <> Action<bool> AND<bool> = Action<bool>(true, [](bool l, bool r) { return l & r; });\ntemplate <> Action<ull> AND<ull> = Action<ull>(((ull)(1) << 63) - 1, [](ull l, ull r) { return l & r; });\n\ntemplate <class T> Action<T> MIN = Action<T>(INF, [](T l, T r) { return (l < r) ? l : r; });\ntemplate <class T> Action<T> MAX = Action<T>(-INF, [](T l, T r) { return (l > r) ? l : r; });\n\ntemplate <class T> Action<T> GCD = Action<T>(0, [](T l, T r) { if (l < r) { l ^= r; r ^= l; l ^= r; } return (r ? GCD<T>(r, l%r) : l); });\ntemplate <class T> Action<T> LCM = Action<T>(1, [](T l, T r) { return (l * r) / GCD<T>(l, r); });\n\n\ntemplate <class Head> Head Min(Head head) { return head; }\ntemplate <class Head, class... Body> Head Min(Head head, Body... body) {\n    auto tmp = Min(body...);\n    return (head < tmp) ? head : tmp;\n}\n\ntemplate <class Head> Head Max(Head head) { return head; }\ntemplate <class Head, class... Body> auto Max(Head head, Body... body) {\n    auto tmp = Max(body...);\n    return (head > tmp) ? head : tmp;\n}\n\nll gcd(ll a, ll b) { if (a < b) { a ^= b; b ^= a; a ^= b; } return b ? gcd(b, a%b) : a; }\nll lcm(ll a, ll b) { return a / gcd(a, b)*b; }\n\nll gcd(ll head) { return head; }\ntemplate <class... Body> ll gcd(ll head, Body... body) {\n    return gcd(head, gcd(body...));\n}\n\nll lcm(ll head) { return head; }\ntemplate <class... Body> ll lcm(ll head, Body... body) {\n    return lcm(head, lcm(body...));\n}\n\n\nll Bset(ll a, ll b, ll c) {\n    if (c) a |= b;\n    else a &= ~b;\n    return a;\n}\n\n\nstruct UFT {\n\npublic:\n    ll tsize;\n    ll mode;\n    vll par;\n    vll rank;\n    UFT() {}\n    UFT(const UFT &uft) {}\n    UFT(ll tsizeget, ll modeget = 0){\n        tsize = tsizeget;\n        mode = modeget;\n        par.asn(tsize, -1);\n        if (!mode) rank.res(tsize, 0);\n    }\n    ll root(ll x) {\n        return par[x] < 0 ? x : par[x] = root(par[x]);\n    }\n    bool isRoot(ll x) {\n        return x == root(x);\n    }\n    bool same(ll x, ll y) {\n        return root(x) == root(y);\n    }\n    void merge(ll x, ll y) {\n        x = root(x);\n        y = root(y);\n        if (x == y) return;\n        if (mode) {\n            par[x] += par[y];\n            par[y] = x;\n        }\n        else {\n            if (rank[x] < rank[y]) {\n                par[y] += par[x];\n                par[x] = y;\n            }\n            else {\n                par[x] += par[y];\n                par[y] = x;\n                if (rank[x] == rank[y]) rank[x]++;\n            }\n        }\n    }\n    ll size(ll x) {\n        return -par[root(x)];\n    }\n};\n\nstruct pUFT {\n\npublic:\n\n    ll tsize;\n    ll now;\n    vll par;\n    vll rank;\n    vll mtime;\n    vvll sizepi;\n    vvll sizepv;\n\n    pUFT(){}\n    pUFT(const pUFT &puft) {}\n\n    pUFT(ll tsizeget) {\n        tsize = tsizeget;\n        now = 0;\n        par.asn(tsize, -1);\n        rank.asn(tsize, 0);\n        mtime.asn(tsize, INF);\n        sizepi.asn(tsize, { 0 });\n        sizepv.asn(tsize, { 1 });\n    }\n    ll root(ll x, ll t) {\n        return (mtime[x] > t) ? x : root(par[x], t);\n    }\n    bool same(ll x, ll y, ll t) {\n        return root(x, t) == root(y, t);\n    }\n    ll merge(ll x, ll y) {\n        now++;\n        x = root(x, now);\n        y = root(y, now);\n        if (x != y) {\n            if (rank[x] < rank[y]) {\n                par[y] += par[x];\n                sizepi[y].pb(now);\n                sizepv[y].pb(-par[y]);\n                par[x] = y;\n                mtime[x] = now;\n            }\n            else {\n                par[x] += par[y];\n                sizepi[x].pb(now);\n                sizepv[x].pb(-par[x]);\n                par[y] = x;\n                mtime[y] = now;\n                if (rank[x] == rank[y]) rank[x]++;\n            }\n        }\n        return now;\n    }\n    ll size(ll x, ll t) {\n        x = root(x, t);\n        return sizepv[x][UPB(sizepi[x], t) - 1];\n    }\n\n};\n\nstruct wUFT {\npublic:\n    ll tsize;\n    ll mode;\n    vll par;\n    vll rank;\n    vll dweight;\n    wUFT() {}\n    wUFT(const wUFT &wuft) {}\n    wUFT(ll tsizeget, ll modeget = 0) {\n        tsize = tsizeget;\n        mode = modeget;\n        par.asn(tsize, -1);\n        if (!mode) rank.res(tsize, 0);\n        dweight.asn(tsize, 0);\n    }\n    ll root(ll x) {\n        if (par[x] < 0) return x;\n        else {\n            ll r = root(par[x]);\n            dweight[x] += dweight[par[x]];\n            return par[x] = r;\n        }\n    }\n    ll weight(ll x) {\n        root(x);\n        return dweight[x];\n    }\n    ll diff(ll x, ll y) {\n        return weight(y) - weight(x);\n    }\n    bool isRoot(ll x) {\n        return x == root(x);\n    }\n    bool same(ll x, ll y) {\n        return root(x) == root(y);\n    }\n    void merge(ll x, ll y, ll w) {\n        w += weight(x);\n        w -= weight(y);\n        x = root(x);\n        y = root(y);\n        if (x == y) return;\n        if (mode) {\n            par[x] += par[y];\n            par[y] = x;\n        }\n        else {\n            if (rank[x] < rank[y]) {\n                par[y] += par[x];\n                par[x] = y;\n                dweight[x] = -w;\n            }\n            else {\n                par[x] += par[y];\n                par[y] = x;\n                if (rank[x] == rank[y]) rank[x]++;\n                dweight[y] = w;\n            }\n        }\n    }\n    ll size(ll x) {\n        return -par[root(x)];\n    }\n};\n\ntemplate <typename valtype> class SegT {\n\npublic:\n\n    ll size;\n    vector<valtype> v;\n\n    valtype initv;\n    function<valtype(valtype x, valtype y)> calc;\n\n    SegT() {}\n    SegT(const SegT &segt) {}\n\n    SegT(ll sizeget, ll modeget = 0) {\n        sizeset(sizeget);\n        modeset(modeget);\n        init();\n    }\n    SegT(vector<valtype> cpyvec, ll modeget = 0) {\n        sizeset(cpyvec.sz);\n        modeset(modeget);\n        init();\n        copy(cpyvec);\n    }\n    SegT(ll sizeget, valtype initvget, function<valtype(valtype x, valtype y)> calcget) {\n        sizeset(sizeget);\n        initv = initvget;\n        calc = calcget;\n        init();\n    }\n    SegT(vector<valtype> cpyvec, valtype initvget, function<valtype(valtype x, valtype y)> calcget) {\n        sizeset(cpyvec.sz);\n        initv = initvget;\n        calc = calcget;\n        init();\n        copy(cpyvec);\n    }\n    void sizeset(ll rsize) {\n        size = DigN2(rsize);\n        if (rsize == Pow2(size - 1)) size--;\n        return;\n    }\n    void modeset(ll mode) {\n        switch (mode) {\n        case 0:\n            initv = 0;\n            calc = [](valtype x, valtype y) {return x + y; };\n            break;\n        case 1:\n            initv = INF;\n            calc = [](valtype x, valtype y) {return min(x, y); };\n            break;\n        case 2:\n            initv = -INF;\n            calc = [](valtype x, valtype y) {return max(x, y); };\n            break;\n        }\n        return;\n    }\n    void init() {\n        v.asn(Pow2(size + 1) - 1, initv);\n    }\n    void copy(vector<valtype> cpyvec) {\n        REP(i, min(cpyvec.sz, Pow2(size))) set(i, cpyvec[i]);\n    }\n    ll i2v(ll i) const{\n        if (i < 0 || i >= Pow2(size)) return -1;\n        return Pow2(size) + i - 1;\n    }\n    ll top(ll i) const{\n        if (i == 0) return -1;\n        return (i - 1) / 2;\n    }\n    pl bot(ll i) const{\n        if (i + 1 >= Pow2(size)) return mp(-1, -1);\n        return mp(2 * i + 1, 2 * i + 2);\n    }\n    void set(ll i, valtype x) {\n        i = i2v(i);\n        v[i] = x;\n        while (i > 0) {\n            i = top(i);\n            v[i] = calc(v[bot(i).fi], v[bot(i).se]);\n        }\n        return;\n    }\n    void add(ll i, valtype x) {\n        set(i, v[i2v(i)] + x);\n        return;\n    }\n    valtype operator[](const ll &i) const {\n        return v[i2v(i)];\n    }\n//  valtype que(ll a = 0, ll b = Pow2(size) - 1) {\n    valtype que(ll a, ll b) {\n        if (a == b) return v[i2v(a)];\n        if (a > b) return initv;//swap(a, b);\n        valtype ans = initv;\n        ll ai = i2v(a);\n        ll bi = i2v(b);\n        FOR(i, 1, size + 1) {\n            if (a > b) break;\n            if (a%Pow2(i)) {\n                ans = calc(ans, v[ai]);\n                a += Pow2(i - 1);\n                ai = top(ai) + 1;\n            }\n            else {\n                ai = top(ai);\n            }\n            if (a > b) break;\n            if ((b + 1) % Pow2(i)) {\n                ans = calc(ans, v[bi]);\n                b -= Pow2(i - 1);\n                bi = top(bi) - 1;\n            }\n            else {\n                bi = top(bi);\n            }\n            if (a > b) break;\n        }\n        return ans;\n    }\n    valtype que(ll b) {\n        return que(0, b);\n    }\n    valtype que() {\n        return que(0, Pow2(size) - 1);\n    }\n\n\n};\n\ntemplate <typename lentype> class Graph {\n\npublic:\n    \n    ll size;\n    ll mode;\n    ll mapmode;\n    lentype zlen;\n    lentype ilen;\n    vector<map<ll, ll>> v2n;\n    vvll n2v;\n    vector<vector<lentype>> Edge;\n    vector<pair<lentype, ll>> Primresult;\n\n    Graph() {}\n    Graph(const Graph &graph) {}\n\n    Graph(ll sizeget = 0, ll mapmodeget = 0, ll modeget = 0, lentype zlenget = 0, lentype ilenget = INF) {\n        size = sizeget;\n        mapmode = mapmodeget;\n        mode = modeget;\n        zlen = zlenget;\n        ilen = ilenget;\n        init();\n    }\n    void init() {\n        Edge.res(size);\n        v2n.res(size);\n        n2v.res(size);\n        Primresult.asn(size, mp(ilen, -1));\n    }\n    lentype lenplus(lentype l, lentype r) {\n        return l + r;\n    }\n    lentype lenequal(lentype l, lentype r) {\n        return l == r;\n    }\n    lentype lenlcr(lentype l, lentype r) {\n        return l < r;\n    }\n    ll addV(ll vs) {\n        size += vs;\n        init();\n        return size;\n    }\n    void caddE(ll x, ll y, lentype c) {\n        if (mapmode) v2n[x][y] = Edge[x].sz;\n        Edge[x].pb(c);\n        n2v[x].pb(y);\n    }\n    void csetE(ll x, ll y, lentype c) {\n        if (mapmode) Edge[x][v2n[x][y]] = c;\n    }\n    void cersE(ll x, ll y) {\n        if (mapmode) {\n            ll n = v2n[x][y];\n            Edge[x][n] = ilen;\n            n2v[x][n] = -1;\n            v2n[x].ers(y);\n        }\n    }\n    void addE(ll x, ll y, lentype c) {\n        caddE(x, y, c);\n        if (!mode) caddE(y, x, c);\n    }\n    void setE(ll x, ll y, lentype c) {\n        csetE(x, y, c);\n        if (!mode) csetE(y, x, c);\n    }\n    void ersE(ll x, ll y, lentype c) {\n        cersE(x, y, c);\n        if (!mode) cersE(y, x, c);\n    }\n    lentype getE(ll x, ll y) {\n        if (mapmode) {\n            if (v2n[x].count(y)) {\n                return Edge[x][v2n[x][y]];\n            }\n        }\n        return ilen;\n    }\n    ll getVsz(ll x) {\n        return Edge[x].sz;\n    }\n    pair<lentype, ll> getV(ll x, ll n) {\n        if (n >= getVsz(x)) return mp(ilen, -1);\n        return mp(Edge[x][n], n2v[x][n]);\n    }\n\n    vector<pair<lentype, vll>> Dijk(ll x) {\n        vector<pair<lentype, vll>> result(size);\n        REP(i, size) {\n            result[i].fi = ilen;\n            result[i].se = { -1 };\n        }\n        vll stat(size, 0);\n        pair<lentype, ll> now;\n        pair<lentype, ll> nowlv;\n        SegT<pair<lentype, ll>> Q(size, mp(ilen, -1), [](pair<lentype, ll> l, pair<lentype, ll> r) {\n            if (l.se == -1) return r;\n            if (r.se == -1) return l;\n            return l.fi < r.fi ? l : r;\n        });\n        Q.set(x, mp(zlen, x));\n        result[x].fi = zlen;\n        result[x].se = { -1 };\n        while (Q.que(0, size - 1).se != -1) {\n            now = Q.que(0, size - 1);\n            Q.set(now.se, mp(ilen, -1));\n            stat[now.se] = 1;\n            REP(i, getVsz(now.se)) {\n                nowlv = getV(now.se, i);\n                if (stat[nowlv.se]) continue;\n                if (Q[nowlv.se].se == -1) {\n                    result[nowlv.se].fi = lenplus(result[now.se].fi, nowlv.fi);\n                    result[nowlv.se].se = { now.se };\n                    Q.set(nowlv.se, mp(result[nowlv.se].fi, nowlv.se));\n                }\n                else {\n                    if (lenlcr(lenplus(result[now.se].fi, nowlv.fi), result[nowlv.se].fi)) {\n                        result[nowlv.se].fi = lenplus(result[now.se].fi, nowlv.fi);\n                        result[nowlv.se].se = { now.se };\n                        Q.set(nowlv.se, mp(result[nowlv.se].fi, nowlv.se));\n                    }\n                    else if (lenequal(lenplus(result[now.se].fi, nowlv.fi), result[nowlv.se].fi)) {\n                        result[nowlv.se].se.pb(now.se);\n                    }\n                }\n            }\n        }\n        return result;\n    }\n\n    lentype Prim(ll x = 0) {\n        lentype ans = zlen;\n        vll stat(size, 0);\n        pair<lentype, ll> now;\n        pair<lentype, ll> nowlv;\n        SegT<pair<lentype, ll>> Q(size, mp(ilen, -1), [](pair<lentype, ll> l, pair<lentype, ll> r) {\n            if (l.se == -1) return r;\n            if (r.se == -1) return l;\n            return l.fi < r.fi ? l : r;\n        });\n        Q.set(x, mp(zlen, x));\n        Primresult[x] = mp(zlen, -1);\n        while (Q.que(0, size - 1).se != -1) {\n            now = Q.que(0, size - 1);\n            Q.set(now.se, mp(ilen, -1));\n            stat[now.se] = 1;\n            ans = lenplus(ans, Primresult[now.se].fi);\n            REP(i, getVsz(now.se)) {\n                nowlv = getV(now.se, i);\n                if (stat[nowlv.se]) continue;\n                if (Q[nowlv.se].se == -1) {\n                    Primresult[nowlv.se] = mp(nowlv.fi, now.se);\n                    Q.set(nowlv.se, mp(Primresult[nowlv.se].fi, nowlv.se));\n                }\n                else {\n                    if (lenlcr(nowlv.fi, Primresult[nowlv.se].fi)) {\n                        Primresult[nowlv.se] = mp(nowlv.fi, now.se);\n                        Q.set(nowlv.se, mp(Primresult[nowlv.se].fi, nowlv.se));\n                    }\n                }\n            }\n        }\n        return ans;\n    }\n\n};\n\n\n/*template <class Type> class DP {\n\npublic:\n\n    vector<Type> v;\n    Type initv;\n    vll size, block;\n\n    DP() {}\n    DP(const DP &dp) {}\n\n    template<class... Args> DP(Args... args) {\n        block.asn(1, 1);\n        Initialize(args...);\n    }\n\n    void Initialize(Type initv_) {\n        initv = initv_;\n        v.asn(block.bk, initv);\n    }\n    template<class... Args> void Initialize(ll val, Args... args) {\n        size.pb(val);\n        block.pb(block.bk*val);\n        Initialize(args...);\n    }\n\n\n\n};*/\n\n\npl Bezout(ll a, ll b) {\n    if (b != 0) {\n        pl xy;\n        xy = Bezout(b, a%b);\n        return mp(xy.se, xy.fi - ((a / b)*xy.se));\n    }\n    else {\n        return mp(1, 0);\n    }\n}\npl Bez(ll a, ll b, ll c) {\n    pl xy;\n    ll x, y, z, gc;\n    xy = Bezout(a, b);\n    gc = gcd(a, b);\n    if (c%gc != 0) return mp(-1, -1);\n    x = xy.fi*(c / gc); y = xy.se*(c / gc);\n    if (x < 0) z = rup(-x, (b / gc));\n    if (x >= 0) z = -x / (b / gc);\n    x += z * (b / gc);\n    y -= z * (a / gc);\n    return mp(x, y);\n}\n\nll DigS10(ll n) {\n    ll ans = 0;\n    while(1) {\n        ans += n % 10;\n        n /= 10;\n        if (!n) break;\n    }\n    return ans;\n}\n\nll isP(ll n) {\n    if (n <= 1) return 0;\n    FOR(i, 2, (ll)sqrt(n) + 1) {\n        if (n%i == 0) return 0;\n    }\n    return 1;\n}\n\nll Tot(ll n) {\n    if (n <= 0) return 0;\n    ll ans = n, x = 2;\n    while (x*x <= n) {\n        if (n%x == 0) {\n            ans -= ans / x;\n            while (n%x == 0) n /= x;\n        }\n        x++;\n    }\n    if (n > 1) ans -= ans / n;\n    return ans;\n}\n\ntemplate <class T> struct Sum {\npublic:\n    V<T> v, s;\n    ll size;\n    Action<T> Add;\n    Sum(V<T> v, Action<T> Add = ADD<T>) : v(v), size(v.sz), Add(Add) { Init(); Calc(); }\n    void Init() {\n        s.asn(size + 1, Add.I);\n    }\n    void Calc() {\n        REP(i, size) s[i + 1] = Add(s[i], v[i]);\n\n    }\n    T operator()(ll x) {\n        return operator()(0, x);\n    }\n    T operator()(ll l, ll r) {\n        if (l < 0) l = 0;\n        if (r >= size) r = size - 1;\n        if (l > r) return Add.I;\n        return s[r + 1] - s[l];//for ADD\n    }\n};\nusing sumll = Sum<ll>;\n\ntemplate <class T> struct Sum2 {\npublic:\n    V<V<T>> v, s;\n    ll RowSize, ColumnSize;\n    Action<T> Add;\n    Sum2(V<V<T>> v, Action<T> Add = ADD<T>) : v(v), RowSize(v.sz), ColumnSize(v.sz ? v[0].sz : 0), Add(Add) { Init(); Calc(); }\n    void Init() {\n        s.asn(RowSize + 1, V<T>(ColumnSize, Add.I));\n    }\n    void Calc() {\n        REP1(r, RowSize) {\n            REP1(c, ColumnSize) {\n                s[r][c] = v[r - 1][c - 1] + operator()(r, c - 1) + operator()(r - 1, c) - operator()(r - 1, c - 1);\n            }\n        }\n    }\n    T operator()(ll r, ll c) {\n        return operator()(0, 0, r, c);\n    }\n    T operator()(ll r1, ll c1, ll r2, ll c2) {\n        if (r1 < 0) r1 = 0;\n        if (c1 < 0) c1 = 0;\n        if (r2 >= RowSize) r2 = RowSize - 1;\n        if (c2 >= ColumnSize) c2 = ColumnSize - 1;\n        if (r1 > r2) return Add.I;\n        if (c1 > c2) return Add.I;\n        return s[r2 + 1][c2 + 1] - s[r2 + 1][c1] - s[r1][c2 + 1] + s[r1][c1];\n    }\n};\nusing sum2ll = Sum2<ll>;\n\ntemplate <class T> struct Point2 {\npublic:\n    V<V<T>> v;\n    ll h, w;\n    Point2() : h(0), w(0) {}\n    Point2(ll h, ll w) : h(h), w(w) { asn(h, w); }\n    Point2(ll h, ll w, T val) : h(h), w(w) { asn(h, w, val); }\n    void assign(ll h, ll w) { v.asn(h, V<T>(w)); }\n    void assign(ll h, ll w, ll val) { v.asn(h, V<T>(w, val)); }\n    T& operator()(ll h, ll w) { return v[h][w]; }\n    T& operator()(pl p) { return v[p.fi][p.se]; }\n};\ntemplate <class T> using P2 = Point2<T>;\n\ntemplate <ll Mod> struct Modll {\npublic:\n    ll v;\n    Modll() : v(0) {}\n    Modll(ll _v) { set(_v % Mod + Mod); }\n    Modll& set(ll _v) {\n        v = (_v < Mod) ? _v : (_v - Mod);\n        return *this;\n    }\n    Modll pow(ll n) const {\n        Modll x = *this, ans = 1;\n        while (n) {\n            if (n & 1) ans *= x;\n            x *= x;\n            n >>= 1;\n        }\n        return ans;\n    }\n    Modll inverse() const { return (*this).pow(Mod - 2); }\n    Modll operator+(const Modll& m) const { return Modll().set(v + m.v); }\n    Modll operator-(const Modll& m) const { return Modll().set(Mod + v - m.v); }\n    Modll operator*(const Modll& m) const { return Modll().set((ull(v) * m.v) % Mod); }\n    Modll operator/(const Modll& m) const { return *this * m.inv; }\n    Modll& operator+=(const Modll& m) { return *this = *this + m; }\n    Modll& operator-=(const Modll& m) { return *this = *this - m; }\n    Modll& operator*=(const Modll& m) { return *this = *this * m; }\n    Modll& operator/=(const Modll& m) { return *this = *this / m; }\n    Modll operator-() const { return Modll(0) - *this; }\n    explicit operator bool() const { return v != 0; }\n    friend ostream& operator<<(ostream& out, const Modll& m) { return out << m.v; }\n};\nusing mll = Modll<MOD>;\nusing vmll = V<mll>;\nusing vvmll = V<vmll>;\nusing vvvmll = V<vvmll>;\n\ntemplate <class T> T vmin(V<T> v) {\n    T tmp = MIN<T>.I;\n    ROR(v, i) emin(tmp, i);\n    return tmp;\n}\ntemplate <class T, class... Args> T vmin(V<T> v, Args... args) {\n    T tmp = vmin(args...);\n    return min(vmin(v), tmp);\n}\n\ntemplate <class T> T vmax(V<T> v) {\n    T tmp = MAX<T>.I;\n    ROR(v, i) emax(tmp, i);\n    return tmp;\n}\ntemplate <class T, class... Args> T vmax(V<T> v, Args... args) {\n    T tmp = vmax(args...);\n    return max(vmax(v), tmp);\n}\n\ntemplate <class T> T vgcd(V<T> v) {\n    T tmp = GCD<T>.I;\n    ROR(v, i) egcd(tmp, i);\n    return tmp;\n}\ntemplate <class T, class... Args> T vgcd(V<T> v, Args... args) {\n    T tmp = vgcd(args...);\n    return gcd(vgcd(v), tmp);\n}\n\ntemplate <class T> T vlcm(V<T> v) {\n    T tmp = LCM<T>.I;\n    ROR(v, i) elcm(tmp, i);\n    return tmp;\n}\ntemplate <class T, class... Args> T vlcm(V<T> v, Args... args) {\n    T tmp = vlcm(args...);\n    return lcm(vlcm(v), tmp);\n}\n\nvmll MFactMemo(2, 1);\nvmll MIFactMemo(2, 1);\n\nmll mFact(ll n) {\n    if (MFactMemo.sz <= n) {\n        ll oldsize = MFactMemo.sz;\n        MFactMemo.res(n + 1, 1);\n        FOR(i, oldsize, n) MFactMemo[i] = MFactMemo[i - 1] * i;\n    }\n    return MFactMemo[n];\n}\nmll miFact(ll n) {\n    if (MIFactMemo.sz <= n) {\n        ll oldsize = MIFactMemo.sz;\n        MIFactMemo.res(n + 1, 1);\n        MIFactMemo.bk = mFact(n).inv;\n        rFOR(i, oldsize + 1, n) MIFactMemo[i - 1] = MIFactMemo[i] * i;\n    }\n    return MIFactMemo[n];\n}\nmll mComb(ll n, ll k) {\n    if (n < 0 || k < 0 || n < k) return 0;\n    return mFact(n) * miFact(k) * miFact(n - k);\n}\n\nll LIS(vll v, ll m = 0) {\n\n    if (v.sz > 0) {\n        ll ans = 0;\n        vll dp(v.sz, INF);\n        FOR(i, 0, v.sz - 1) {\n            dp[m ? UPB(dp, v[i]) : LOWB(dp, v[i])] = v[i];\n        }\n        FOR(i, 0, v.sz - 1) {\n            if (dp[i] == INF) break;\n            ans++;\n        }\n        return ans;\n    }\n    else {\n        return 0;\n    }\n\n}\n\nvoid PCmprs(vll& v) {\n    if (v.sz == 0) return;\n    vll vv(v);\n    IOTA(vv, 0);\n    sort(vv.bgn, vv.en, [&](ll v1, ll v2) {return v[v1] < v[v2]; });\n    IOTA(v, 0);\n    sort(v.bgn, v.en, [&](ll v1, ll v2) {return vv[v1] < vv[v2]; });\n    return;\n}\n\nll BblCnt(vll v) {\n    PCmprs(v);\n    SegT<ll> b(v.sz, 0);\n    ll ans = 0;\n    REP(i, v.sz) {\n        ans += (i - b.que(0, v[i]));\n        b.add(v[i], 1);\n    }\n    return ans;\n}\n\nll Bsrch(function<bool(ll x)> f, ll mi, ll ma) {\n    ll ng = mi - 1, ok = ma, mid;\n    while (ok - ng > 1) {\n        mid = (ng + ok) / 2;\n        (f(mid) ? ok : ng) = mid;\n    }\n    return ok;\n}\n\ntemplate<class T> V<V<T>> MultiMatrix(V<V<T>> A, V<V<T>> B, Action<T> Mul = MUL<T>, Action<T> Add = ADD<T>) {\n    V<V<T>> ans;\n    ll ii = A.sz;\n    if (!ii) return ans;\n    ll jj = A[0].sz;\n    if (!jj) return ans;\n    ll jj2 = B.sz;\n    if (!jj2) return ans;\n    if (jj != jj2) return ans;\n    ll kk = B[0].sz;\n    if (!kk) return ans;\n    ans.asn(ii, V<T>(kk, 0));\n    REP(i, ii) {\n        REP(k, kk) {\n            REP(j, jj) {\n                ans[i][k] = Add(ans[i][k], Mul(A[i][j], B[j][k]));\n            }\n        }\n    }\n    return ans;\n}\n\nvvll CombMemo(1000, vll(1000, -1));\n\nll Comb(ll n, ll k) {\n    if ((n < 0) || (k < 0)) return 0;\n    if (CombMemo[n][k] == -1) {\n        if (n < k) CombMemo[n][k] = 0;\n        else {\n            if (n == 0) CombMemo[n][k] = 1;\n            else if (k == 0) CombMemo[n][k] = 1;\n            else if (n == k) CombMemo[n][k] = 1;\n            else CombMemo[n][k] = Comb(n - 1, k - 1) + Comb(n - 1, k);\n        }\n    }\n    return CombMemo[n][k];\n}\n\ntemplate<class T> map<T, ll> Dict(V<T> v) {\n    map<T, ll> m;\n    if (!v.sz) return m;\n    SORT(v);\n    UNIQUE(v);\n    REP(i, v.sz) {\n        m[v[i]] = i;\n    }\n    return m;\n}\n\ntemplate<class T> vll Cmprs(V<T> v) {\n    auto m = Dict(v);\n    vll ans(v.sz);\n    REP(i,v.sz) {\n        ans[i] = m[v[i]];\n    }\n    return ans;\n}\n\ntemplate <class T> auto vecn(T val) { return val; }\ntemplate <class... Args> auto vecn(ll val, Args... args) {\n    auto tmp = vecn(args...);\n    return V<decltype(tmp)>(val, tmp);\n}\n\nvoid Solve();\n\nsigned main() { \n    cin.tie(0);\n    ios::sync_with_stdio(false);\n    cout << setprecision(20) << fixed;\n    Solve();\n}\n\nvoid Solve() {\n  li(n);vli(n,a);\n  SORT(a);\n  ll zero=0,type=0,f;\n  vll note,count;\n  REP(i,n){\n    if(a[i]==0){\n      zero++;\n    } else {\n      f=-1;\n      REP(j,note.sz){\n        if(note[j]==a[i]){\n          f=j;\n        }\n      }\n      if(f==-1){\n        note.pb(a[i]);\n        count.pb(1);\n      } else {\n        count[f]++;\n      }\n    }\n  }\n  \n  if(a.sz==zero){\n    cout << \"Yes\";\n    return;\n  }\n  \n  if(a.sz%3){\n    cout << \"No\";\n    return;\n  }\n  \n  \n  \n  if(note.sz>=4){\n    cout << \"No\";\n    return;\n  }\n  \n  if(zero){\n    if (a.sz/3==zero && a.sz/3==count[0]/2) {\n      cout << \"Yes\";\n      return;\n    } else {\n      cout << \"No\";\n      return;\n    }\n  } else {\n    if (count[0]==count[1]&&count[0]==count[2]){\n      if((note[0]^note[1]==note[2])&&(note[1]^note[2]==note[0])){\n        cout << \"Yes\";\n        return;\n      }\n    }\n  }\n  cout << \"No\";\n  return;\n}\n\n\n\n\n\n\n\n\n\n\n", "language": "C++", "metadata": {"date": 1563156675, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02975.html", "problem_id": "p02975", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02975/input.txt", "sample_output_relpath": "derived/input_output/data/p02975/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02975/C++/s109717720.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s109717720", "user_id": "u172929647"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\ntemplate <class T> using V = vector<T>;\ntemplate <class T> using VV = V<V<T>>;\ntemplate <class T> using VVV = V<VV<T>>;\ntemplate <class S, class T> using P = pair<S, T>;\ntemplate <class S, class T, class U> using TP = tuple<S, T, U>;\n\nusing ll = long long;\nusing ull = unsigned long long;\nusing dbl = double;\nusing str = string;\nusing vll = V<ll>;\nusing vvll = V<vll>;\nusing vvvll = V<vvll>;\nusing pl = P<ll, ll>;\nusing tl = TP<ll, ll, ll>;\nusing vpl = V<pl>;\nusing vvpl = V<vpl>;\nusing vtl = V<tl>;\nusing vvtl = V<vtl>;\nusing vs = V<str>;\nusing vvs = V<vs>;\nusing vd = V<dbl>;\nusing vvd = V<vd>;\nusing qll = queue<ll>;\nusing qpl = queue<pl>;\nusing stll = stack<ll>;\nusing stpl = stack<pl>;\nusing mapll = map<ll, ll>;\nusing setll = set<ll>;\nusing pqll = priority_queue<ll>;\n\n#define int ll\n#define fi first\n#define se second\n#define mp make_pair\n#define mt make_tuple\n#define pb push_back\n#define pob pop_back()\n#define pf push_front\n#define pof pop_front()\n#define sz size()\n#define bgn begin()\n#define en end()\n#define asn assign\n#define emp empty()\n#define fr front()\n#define bk back()\n#define clr clear()\n#define ins insert\n#define ers erase\n#define res resize\n#define tp top()\n#define p_q priority_queue\n#define inv inverse()\n\n#define FOR(i,a,b) for(ll i=(a);i<=(ll)(b);i++)\n#define rFOR(i,a,b) for(ll i=(b);i>=(ll)(a);i--)\n#define REP(i,a) FOR((i),0,(ll)(a)-1)\n#define REP0(i,a) FOR((i),0,(ll)(a))\n#define REP1(i,a) FOR((i),1,(ll)(a))\n#define rREP(i,a) rFOR((i),0,(ll)(a)-1)\n#define rREP0(i,a) rFOR((i),0,(ll)(a))\n#define rREP1(i,a) rFOR((i),1,(ll)(a))\n#define ROR(v,i) for(auto &(i):(v))\n#define IOTA(a,n) iota((a).bgn,(a).en,(n))\n#define SORT(a) sort((a).bgn,(a).en)\n#define rSORT(a) sort((a).rbegin(),(a).rend())\n#define UNIQUE(a) (a).erase(unique((a).bgn,(a).en),(a).en)\n#define PREVP(a) prev_permutation((a).bgn,(a).en)\n#define NEXTP(a) next_permutation((a).bgn,(a).en)\n#define BINS(a,b) binary_search((a).bgn,(a).en,(b))\n#define LOWB(a,b) (lower_bound((a).bgn,(a).en,(b))-(a).bgn)\n#define UPB(a,b) (upper_bound((a).bgn,(a).en,(b))-(a).bgn)\n#define CNT(a,b) count((a).bgn,(a).en,b)\n#define SUM(a) accumulate((a).bgn,(a).en,0)\n#define REV(a) reverse((a).bgn,(a).en)\n#define REGS(a,b) regex_search((a),regex(b))\n#define REGM(a,b) regex_match((a),regex(b))\n#define yn(a) cout <<((a)?\"yes\":\"no\")<<\"\\n\";\n#define Yn(a) cout <<((a)?\"Yes\":\"No\")<<\"\\n\";\n#define YN(a) cout <<((a)?\"YES\":\"NO\")<<\"\\n\";\n#define imp(a) cout <<((a)?\"possible\":\"impossible\")<<\"\\n\";\n#define Imp(a) cout <<((a)?\"Possible\":\"Impossible\")<<\"\\n\";\n#define IMP(a) cout <<((a)?\"POSSIBLE\":\"IMPOSSIBLE\")<<\"\\n\";\n#define fs(a) cout <<((a)?\"second\":\"first\")<<\"\\n\";\n#define Fs(a) cout <<((a)?\"Second\":\"First\")<<\"\\n\";\n#define FS(a) cout <<((a)?\"SECOND\":\"FIRST\")<<\"\\n\";\n#define sak cout <<\"\\n\";\n#define sas cout <<\" \";\n#define sat cout <<\"\\t\";\n#define dbg(a) cerr <<(#a)<<\": \"<<(a)<<\"\\n\";\n#define dbgs(...) dal(#__VA_ARGS__);dal(__VA_ARGS__);\n#define c2l(a) ((ll)(a-48))\n#define a2l(a) ((ll)(a-97))\n#define A2l(a) ((ll)(a-65))\n#define l2c(a) ((char)(a+48))\n#define l2a(a) ((char)(a+97))\n#define l2A(a) ((char)(a+65))\n#define DigN2(a) ((llabs(a)==0)?(1):((ll)(log2(double(llabs(a))))+1))\n#define DigN10(a) ((llabs(a)==0)?(1):((ll)(log10(double(llabs(a))))+1))\n#define Dig2(a,b) (((a)>>(b))&1)\n#define Dig10(a,b) (ll)(((a)/((ll)(pow(10.0,(double)(b)))))%10)\n#define Pow2(a) ((ll)(1)<<(a))\n#define Pow10(a) ((ll)(pow(10.0,double(a))))\n#define LSB(a) ((a)&(-(a)))\n#define vin(v) ROR((v),(i)){cin >>(i);};\n#define vllin(v,N) vll (v)((N));vin(v);\n#define vllin2(a,b,N) vll (a)(N),(b)(N);REP(i,N){cin>>(a)[i]>>(b)[i];};\n#define vsin(v,N) vs (v)((N));vin(v);\n#define rdn(a,b) ((a)/(b))\n#define rou(a,b) ((((double(a)/double(b))-((a)/(b)))<0.5)?((a)/(b)):(((a)/(b))+1))\n#define rup(a,b) ((((a)%(b))==0)?((a)/(b)):(((a)/(b))+1))\n#define min(...) Min(__VA_ARGS__)\n#define max(...) Max(__VA_ARGS__)\n#define emin(a, ...) ((a)=Min((a),__VA_ARGS__))\n#define emax(a, ...) ((a)=Max((a),__VA_ARGS__))\n#define egcd(a, ...) ((a)=gcd((a),__VA_ARGS__))\n#define elcm(a, ...) ((a)=lcm((a),__VA_ARGS__))\n#define powll(a,b) (ll)(pow((double)(a),(double)(b)))\n#define Triangle(x1,y1,x2,y2,x3,y3) (((x1)-(x2))*((y1)-(y3))-((x1)-(x3))*((y1)-(y2)))\n\n#define svll SumV<ll>\n#define svvll SumV2<ll>\n\n#define li(...) ll __VA_ARGS__;Input(__VA_ARGS__);\n#define si(...) str __VA_ARGS__;Input(__VA_ARGS__);\n#define vli(size, ...) vll __VA_ARGS__;vInput(size,__VA_ARGS__);\n#define vsi(size, ...) vs __VA_ARGS__;vInput(size,__VA_ARGS__);\n\nconst ll MOD = 1e9 + 7;\n//const ll MOD = 998244353;\n//const ll MOD = 924844033;\n//const ll MOD = 9007199254740881;\nconst ll INF = 1LL << 60;//1.15e18\nconst double PI = acos(-1.0);\nconst vll DX = { 0,-1,0,1,0,-1,1,1,-1 };\nconst vll DY = { 0,0,-1,0,1,-1,-1,1,1 };\nconst str alp = \"abcdefghijklmnopqrstuvwxyz\";\nconst str ALP = \"ABCDEFGHIJKLMNOPQRSTUVWXYZ\";\n\n\nvoid Input() {}\ntemplate <class Var, class... Args> void Input(Var& var, Args&... args) {\n    cin >> var;\n    Input(args...);\n}\n\nvoid vInit(ll size) {}\ntemplate <class T, class... Args> void vInit(ll size, V<T>& v, Args&... args) {\n    v.res(size);\n    vInit(size, args...);\n}\nvoid vInputNum(ll num) {}\ntemplate <class T, class... Args> void vInputNum(ll num, V<T>& v, Args&... args) {\n    cin >> v[num];\n    vInputNum(num, args...);\n}\nvoid vInput(ll size) {}\ntemplate <class... Args> void vInput(ll size, Args&... args) {\n    vInit(size, args...);\n    REP(i, size) vInputNum(i, args...);\n}\n\ntemplate <class S, class T> ostream &operator<<(ostream &out, const P<S, T> &p) {\n    return out << \"[\" << p.fi << \", \" << p.se << \"]\";\n}\n\ntemplate <class T> ostream &operator<<(ostream &out, V<T> &v) {\n    if (v.emp) return out << \"{}\";\n    else {\n        auto itr = v.bgn;\n        out << \"{\" << *itr;\n        itr++;\n        while (itr != v.en) {\n            out << \", \" << *itr;\n            itr++;\n        }\n        out << \"}\";\n        return out;\n    }\n}\n\ntemplate <class S, class T> ostream &operator<<(ostream &out, const map<S, T> &m) {\n    if (m.emp) return out << \"<[]>\";\n    else {\n        auto itr = m.bgn;\n        out << \"< [\" << (itr->fi) << \": \" << (itr->se);\n        itr++;\n        while (itr != m.en) {\n            out << \"], [\" << (itr->fi) << \": \" << (itr->se);\n            itr++;\n        }\n        out << \"] >\";\n        return out;\n    }\n}\n\ntemplate <class T> ostream &operator<<(ostream &out, const set<T> &s) {\n    if (s.emp) return out << \"<>\";\n    else {\n        auto itr = s.bgn;\n        out << \"<\" << *itr;\n        itr++;\n        while (itr != s.en) {\n            out << \", \" << *itr;\n            itr++;\n        }\n        out << \">\";\n        return out;\n    }\n}\n\nvoid say() {}\ntemplate <class T> void say(T t) { cout << t; }\ntemplate <class Head, class... Body> void say(Head head, Body... body) {\n    cout << head << \" \";\n    say(body...);\n}\nvoid sal() { cout << \"\\n\"; }\ntemplate <class... Args> void sal(Args... args) {\n    say(args...);\n    cout << \"\\n\";\n}\n\nvoid day() {}\ntemplate <class T> void day(T t) { cerr << t; }\ntemplate <class Head, class... Body> void day(Head head, Body... body) {\n    cerr << head << \" \";\n    day(body...);\n}\nvoid dal() { cerr << \"\\n\"; }\ntemplate <class... Args> void dal(Args... args) {\n    day(args...);\n    cerr << \"\\n\";\n}\n\nvoid salv() {}\ntemplate <class T> void salv(V<T> v) {\n    if (v.emp) sal();\n    else {\n        auto itr = v.bgn;\n        say(*itr);\n        itr++;\n        while (itr != v.en) {\n            sas;\n            say(*itr);\n            itr++;\n        }\n        sak;\n    }\n}\ntemplate <class T, class... Args> void salv(V<T> v, Args... args) {\n    salv(v);\n    salv(args...);\n}\n\nvoid salv2() {}\ntemplate <class T> void salv2(V<V<T>> v) {\n    if (v.emp) sal();\n    else {\n        ROR(v, i) salv(i);\n    }\n}\ntemplate <class T, class... Args> void salv2(V<V<T>> v, Args... args) {\n    salv2(v);\n    salv2(args...);\n}\n\ntemplate <class Monoid> struct Action {\npublic:\n    Monoid I;\n    function<Monoid(Monoid, Monoid)> A;\n    Action(Monoid I, function<Monoid(Monoid, Monoid)> A) : I(I), A(A) {}\n    Monoid operator()() { return I; }\n    Monoid operator()(Monoid x) { return x; }\n    Monoid operator()(Monoid l, Monoid r) { return A(l, r); }\n    template <class... Args> Monoid operator()(Monoid x, Args... args) {\n        Monoid tmp = operator()(args...);   \n        return A(x, tmp);\n    }\n};\n\ntemplate <class T> Action<T> ADD = Action<T>(0, [](T l, T r) { return l + r; });\ntemplate <> Action<str> ADD<str> = Action<str>(\"\", [](str l, str r) { return l + r; });\ntemplate <class T1, class T2> Action<P<T1, T2>> ADD<P<T1, T2>> = Action<P<T1, T2>>(mp(ADD<T1>.I, ADD<T2>.I), [](P<T1, T2> l, P<T1, T2> r) { return mp(l.fi + r.fi, l.se + r.se); });\n\ntemplate <class T> Action<T> MUL = Action<T>(1, [](T l, T r) { return l * r; });\ntemplate <class T> Action<T> OR = Action<T>(0, [](T l, T r) { return l | r; });\ntemplate <class T> Action<T> XOR = Action<T>(0, [](T l, T r) { return l ^ r; });\n\ntemplate <class T> Action<T> AND = Action<T>(((ll)(1) << 63) - 1, [](T l, T r) { return l & r; });\ntemplate <> Action<bool> AND<bool> = Action<bool>(true, [](bool l, bool r) { return l & r; });\ntemplate <> Action<ull> AND<ull> = Action<ull>(((ull)(1) << 63) - 1, [](ull l, ull r) { return l & r; });\n\ntemplate <class T> Action<T> MIN = Action<T>(INF, [](T l, T r) { return (l < r) ? l : r; });\ntemplate <class T> Action<T> MAX = Action<T>(-INF, [](T l, T r) { return (l > r) ? l : r; });\n\ntemplate <class T> Action<T> GCD = Action<T>(0, [](T l, T r) { if (l < r) { l ^= r; r ^= l; l ^= r; } return (r ? GCD<T>(r, l%r) : l); });\ntemplate <class T> Action<T> LCM = Action<T>(1, [](T l, T r) { return (l * r) / GCD<T>(l, r); });\n\n\ntemplate <class Head> Head Min(Head head) { return head; }\ntemplate <class Head, class... Body> Head Min(Head head, Body... body) {\n    auto tmp = Min(body...);\n    return (head < tmp) ? head : tmp;\n}\n\ntemplate <class Head> Head Max(Head head) { return head; }\ntemplate <class Head, class... Body> auto Max(Head head, Body... body) {\n    auto tmp = Max(body...);\n    return (head > tmp) ? head : tmp;\n}\n\nll gcd(ll a, ll b) { if (a < b) { a ^= b; b ^= a; a ^= b; } return b ? gcd(b, a%b) : a; }\nll lcm(ll a, ll b) { return a / gcd(a, b)*b; }\n\nll gcd(ll head) { return head; }\ntemplate <class... Body> ll gcd(ll head, Body... body) {\n    return gcd(head, gcd(body...));\n}\n\nll lcm(ll head) { return head; }\ntemplate <class... Body> ll lcm(ll head, Body... body) {\n    return lcm(head, lcm(body...));\n}\n\n\nll Bset(ll a, ll b, ll c) {\n    if (c) a |= b;\n    else a &= ~b;\n    return a;\n}\n\n\nstruct UFT {\n\npublic:\n    ll tsize;\n    ll mode;\n    vll par;\n    vll rank;\n    UFT() {}\n    UFT(const UFT &uft) {}\n    UFT(ll tsizeget, ll modeget = 0){\n        tsize = tsizeget;\n        mode = modeget;\n        par.asn(tsize, -1);\n        if (!mode) rank.res(tsize, 0);\n    }\n    ll root(ll x) {\n        return par[x] < 0 ? x : par[x] = root(par[x]);\n    }\n    bool isRoot(ll x) {\n        return x == root(x);\n    }\n    bool same(ll x, ll y) {\n        return root(x) == root(y);\n    }\n    void merge(ll x, ll y) {\n        x = root(x);\n        y = root(y);\n        if (x == y) return;\n        if (mode) {\n            par[x] += par[y];\n            par[y] = x;\n        }\n        else {\n            if (rank[x] < rank[y]) {\n                par[y] += par[x];\n                par[x] = y;\n            }\n            else {\n                par[x] += par[y];\n                par[y] = x;\n                if (rank[x] == rank[y]) rank[x]++;\n            }\n        }\n    }\n    ll size(ll x) {\n        return -par[root(x)];\n    }\n};\n\nstruct pUFT {\n\npublic:\n\n    ll tsize;\n    ll now;\n    vll par;\n    vll rank;\n    vll mtime;\n    vvll sizepi;\n    vvll sizepv;\n\n    pUFT(){}\n    pUFT(const pUFT &puft) {}\n\n    pUFT(ll tsizeget) {\n        tsize = tsizeget;\n        now = 0;\n        par.asn(tsize, -1);\n        rank.asn(tsize, 0);\n        mtime.asn(tsize, INF);\n        sizepi.asn(tsize, { 0 });\n        sizepv.asn(tsize, { 1 });\n    }\n    ll root(ll x, ll t) {\n        return (mtime[x] > t) ? x : root(par[x], t);\n    }\n    bool same(ll x, ll y, ll t) {\n        return root(x, t) == root(y, t);\n    }\n    ll merge(ll x, ll y) {\n        now++;\n        x = root(x, now);\n        y = root(y, now);\n        if (x != y) {\n            if (rank[x] < rank[y]) {\n                par[y] += par[x];\n                sizepi[y].pb(now);\n                sizepv[y].pb(-par[y]);\n                par[x] = y;\n                mtime[x] = now;\n            }\n            else {\n                par[x] += par[y];\n                sizepi[x].pb(now);\n                sizepv[x].pb(-par[x]);\n                par[y] = x;\n                mtime[y] = now;\n                if (rank[x] == rank[y]) rank[x]++;\n            }\n        }\n        return now;\n    }\n    ll size(ll x, ll t) {\n        x = root(x, t);\n        return sizepv[x][UPB(sizepi[x], t) - 1];\n    }\n\n};\n\nstruct wUFT {\npublic:\n    ll tsize;\n    ll mode;\n    vll par;\n    vll rank;\n    vll dweight;\n    wUFT() {}\n    wUFT(const wUFT &wuft) {}\n    wUFT(ll tsizeget, ll modeget = 0) {\n        tsize = tsizeget;\n        mode = modeget;\n        par.asn(tsize, -1);\n        if (!mode) rank.res(tsize, 0);\n        dweight.asn(tsize, 0);\n    }\n    ll root(ll x) {\n        if (par[x] < 0) return x;\n        else {\n            ll r = root(par[x]);\n            dweight[x] += dweight[par[x]];\n            return par[x] = r;\n        }\n    }\n    ll weight(ll x) {\n        root(x);\n        return dweight[x];\n    }\n    ll diff(ll x, ll y) {\n        return weight(y) - weight(x);\n    }\n    bool isRoot(ll x) {\n        return x == root(x);\n    }\n    bool same(ll x, ll y) {\n        return root(x) == root(y);\n    }\n    void merge(ll x, ll y, ll w) {\n        w += weight(x);\n        w -= weight(y);\n        x = root(x);\n        y = root(y);\n        if (x == y) return;\n        if (mode) {\n            par[x] += par[y];\n            par[y] = x;\n        }\n        else {\n            if (rank[x] < rank[y]) {\n                par[y] += par[x];\n                par[x] = y;\n                dweight[x] = -w;\n            }\n            else {\n                par[x] += par[y];\n                par[y] = x;\n                if (rank[x] == rank[y]) rank[x]++;\n                dweight[y] = w;\n            }\n        }\n    }\n    ll size(ll x) {\n        return -par[root(x)];\n    }\n};\n\ntemplate <typename valtype> class SegT {\n\npublic:\n\n    ll size;\n    vector<valtype> v;\n\n    valtype initv;\n    function<valtype(valtype x, valtype y)> calc;\n\n    SegT() {}\n    SegT(const SegT &segt) {}\n\n    SegT(ll sizeget, ll modeget = 0) {\n        sizeset(sizeget);\n        modeset(modeget);\n        init();\n    }\n    SegT(vector<valtype> cpyvec, ll modeget = 0) {\n        sizeset(cpyvec.sz);\n        modeset(modeget);\n        init();\n        copy(cpyvec);\n    }\n    SegT(ll sizeget, valtype initvget, function<valtype(valtype x, valtype y)> calcget) {\n        sizeset(sizeget);\n        initv = initvget;\n        calc = calcget;\n        init();\n    }\n    SegT(vector<valtype> cpyvec, valtype initvget, function<valtype(valtype x, valtype y)> calcget) {\n        sizeset(cpyvec.sz);\n        initv = initvget;\n        calc = calcget;\n        init();\n        copy(cpyvec);\n    }\n    void sizeset(ll rsize) {\n        size = DigN2(rsize);\n        if (rsize == Pow2(size - 1)) size--;\n        return;\n    }\n    void modeset(ll mode) {\n        switch (mode) {\n        case 0:\n            initv = 0;\n            calc = [](valtype x, valtype y) {return x + y; };\n            break;\n        case 1:\n            initv = INF;\n            calc = [](valtype x, valtype y) {return min(x, y); };\n            break;\n        case 2:\n            initv = -INF;\n            calc = [](valtype x, valtype y) {return max(x, y); };\n            break;\n        }\n        return;\n    }\n    void init() {\n        v.asn(Pow2(size + 1) - 1, initv);\n    }\n    void copy(vector<valtype> cpyvec) {\n        REP(i, min(cpyvec.sz, Pow2(size))) set(i, cpyvec[i]);\n    }\n    ll i2v(ll i) const{\n        if (i < 0 || i >= Pow2(size)) return -1;\n        return Pow2(size) + i - 1;\n    }\n    ll top(ll i) const{\n        if (i == 0) return -1;\n        return (i - 1) / 2;\n    }\n    pl bot(ll i) const{\n        if (i + 1 >= Pow2(size)) return mp(-1, -1);\n        return mp(2 * i + 1, 2 * i + 2);\n    }\n    void set(ll i, valtype x) {\n        i = i2v(i);\n        v[i] = x;\n        while (i > 0) {\n            i = top(i);\n            v[i] = calc(v[bot(i).fi], v[bot(i).se]);\n        }\n        return;\n    }\n    void add(ll i, valtype x) {\n        set(i, v[i2v(i)] + x);\n        return;\n    }\n    valtype operator[](const ll &i) const {\n        return v[i2v(i)];\n    }\n//  valtype que(ll a = 0, ll b = Pow2(size) - 1) {\n    valtype que(ll a, ll b) {\n        if (a == b) return v[i2v(a)];\n        if (a > b) return initv;//swap(a, b);\n        valtype ans = initv;\n        ll ai = i2v(a);\n        ll bi = i2v(b);\n        FOR(i, 1, size + 1) {\n            if (a > b) break;\n            if (a%Pow2(i)) {\n                ans = calc(ans, v[ai]);\n                a += Pow2(i - 1);\n                ai = top(ai) + 1;\n            }\n            else {\n                ai = top(ai);\n            }\n            if (a > b) break;\n            if ((b + 1) % Pow2(i)) {\n                ans = calc(ans, v[bi]);\n                b -= Pow2(i - 1);\n                bi = top(bi) - 1;\n            }\n            else {\n                bi = top(bi);\n            }\n            if (a > b) break;\n        }\n        return ans;\n    }\n    valtype que(ll b) {\n        return que(0, b);\n    }\n    valtype que() {\n        return que(0, Pow2(size) - 1);\n    }\n\n\n};\n\ntemplate <typename lentype> class Graph {\n\npublic:\n    \n    ll size;\n    ll mode;\n    ll mapmode;\n    lentype zlen;\n    lentype ilen;\n    vector<map<ll, ll>> v2n;\n    vvll n2v;\n    vector<vector<lentype>> Edge;\n    vector<pair<lentype, ll>> Primresult;\n\n    Graph() {}\n    Graph(const Graph &graph) {}\n\n    Graph(ll sizeget = 0, ll mapmodeget = 0, ll modeget = 0, lentype zlenget = 0, lentype ilenget = INF) {\n        size = sizeget;\n        mapmode = mapmodeget;\n        mode = modeget;\n        zlen = zlenget;\n        ilen = ilenget;\n        init();\n    }\n    void init() {\n        Edge.res(size);\n        v2n.res(size);\n        n2v.res(size);\n        Primresult.asn(size, mp(ilen, -1));\n    }\n    lentype lenplus(lentype l, lentype r) {\n        return l + r;\n    }\n    lentype lenequal(lentype l, lentype r) {\n        return l == r;\n    }\n    lentype lenlcr(lentype l, lentype r) {\n        return l < r;\n    }\n    ll addV(ll vs) {\n        size += vs;\n        init();\n        return size;\n    }\n    void caddE(ll x, ll y, lentype c) {\n        if (mapmode) v2n[x][y] = Edge[x].sz;\n        Edge[x].pb(c);\n        n2v[x].pb(y);\n    }\n    void csetE(ll x, ll y, lentype c) {\n        if (mapmode) Edge[x][v2n[x][y]] = c;\n    }\n    void cersE(ll x, ll y) {\n        if (mapmode) {\n            ll n = v2n[x][y];\n            Edge[x][n] = ilen;\n            n2v[x][n] = -1;\n            v2n[x].ers(y);\n        }\n    }\n    void addE(ll x, ll y, lentype c) {\n        caddE(x, y, c);\n        if (!mode) caddE(y, x, c);\n    }\n    void setE(ll x, ll y, lentype c) {\n        csetE(x, y, c);\n        if (!mode) csetE(y, x, c);\n    }\n    void ersE(ll x, ll y, lentype c) {\n        cersE(x, y, c);\n        if (!mode) cersE(y, x, c);\n    }\n    lentype getE(ll x, ll y) {\n        if (mapmode) {\n            if (v2n[x].count(y)) {\n                return Edge[x][v2n[x][y]];\n            }\n        }\n        return ilen;\n    }\n    ll getVsz(ll x) {\n        return Edge[x].sz;\n    }\n    pair<lentype, ll> getV(ll x, ll n) {\n        if (n >= getVsz(x)) return mp(ilen, -1);\n        return mp(Edge[x][n], n2v[x][n]);\n    }\n\n    vector<pair<lentype, vll>> Dijk(ll x) {\n        vector<pair<lentype, vll>> result(size);\n        REP(i, size) {\n            result[i].fi = ilen;\n            result[i].se = { -1 };\n        }\n        vll stat(size, 0);\n        pair<lentype, ll> now;\n        pair<lentype, ll> nowlv;\n        SegT<pair<lentype, ll>> Q(size, mp(ilen, -1), [](pair<lentype, ll> l, pair<lentype, ll> r) {\n            if (l.se == -1) return r;\n            if (r.se == -1) return l;\n            return l.fi < r.fi ? l : r;\n        });\n        Q.set(x, mp(zlen, x));\n        result[x].fi = zlen;\n        result[x].se = { -1 };\n        while (Q.que(0, size - 1).se != -1) {\n            now = Q.que(0, size - 1);\n            Q.set(now.se, mp(ilen, -1));\n            stat[now.se] = 1;\n            REP(i, getVsz(now.se)) {\n                nowlv = getV(now.se, i);\n                if (stat[nowlv.se]) continue;\n                if (Q[nowlv.se].se == -1) {\n                    result[nowlv.se].fi = lenplus(result[now.se].fi, nowlv.fi);\n                    result[nowlv.se].se = { now.se };\n                    Q.set(nowlv.se, mp(result[nowlv.se].fi, nowlv.se));\n                }\n                else {\n                    if (lenlcr(lenplus(result[now.se].fi, nowlv.fi), result[nowlv.se].fi)) {\n                        result[nowlv.se].fi = lenplus(result[now.se].fi, nowlv.fi);\n                        result[nowlv.se].se = { now.se };\n                        Q.set(nowlv.se, mp(result[nowlv.se].fi, nowlv.se));\n                    }\n                    else if (lenequal(lenplus(result[now.se].fi, nowlv.fi), result[nowlv.se].fi)) {\n                        result[nowlv.se].se.pb(now.se);\n                    }\n                }\n            }\n        }\n        return result;\n    }\n\n    lentype Prim(ll x = 0) {\n        lentype ans = zlen;\n        vll stat(size, 0);\n        pair<lentype, ll> now;\n        pair<lentype, ll> nowlv;\n        SegT<pair<lentype, ll>> Q(size, mp(ilen, -1), [](pair<lentype, ll> l, pair<lentype, ll> r) {\n            if (l.se == -1) return r;\n            if (r.se == -1) return l;\n            return l.fi < r.fi ? l : r;\n        });\n        Q.set(x, mp(zlen, x));\n        Primresult[x] = mp(zlen, -1);\n        while (Q.que(0, size - 1).se != -1) {\n            now = Q.que(0, size - 1);\n            Q.set(now.se, mp(ilen, -1));\n            stat[now.se] = 1;\n            ans = lenplus(ans, Primresult[now.se].fi);\n            REP(i, getVsz(now.se)) {\n                nowlv = getV(now.se, i);\n                if (stat[nowlv.se]) continue;\n                if (Q[nowlv.se].se == -1) {\n                    Primresult[nowlv.se] = mp(nowlv.fi, now.se);\n                    Q.set(nowlv.se, mp(Primresult[nowlv.se].fi, nowlv.se));\n                }\n                else {\n                    if (lenlcr(nowlv.fi, Primresult[nowlv.se].fi)) {\n                        Primresult[nowlv.se] = mp(nowlv.fi, now.se);\n                        Q.set(nowlv.se, mp(Primresult[nowlv.se].fi, nowlv.se));\n                    }\n                }\n            }\n        }\n        return ans;\n    }\n\n};\n\n\n/*template <class Type> class DP {\n\npublic:\n\n    vector<Type> v;\n    Type initv;\n    vll size, block;\n\n    DP() {}\n    DP(const DP &dp) {}\n\n    template<class... Args> DP(Args... args) {\n        block.asn(1, 1);\n        Initialize(args...);\n    }\n\n    void Initialize(Type initv_) {\n        initv = initv_;\n        v.asn(block.bk, initv);\n    }\n    template<class... Args> void Initialize(ll val, Args... args) {\n        size.pb(val);\n        block.pb(block.bk*val);\n        Initialize(args...);\n    }\n\n\n\n};*/\n\n\npl Bezout(ll a, ll b) {\n    if (b != 0) {\n        pl xy;\n        xy = Bezout(b, a%b);\n        return mp(xy.se, xy.fi - ((a / b)*xy.se));\n    }\n    else {\n        return mp(1, 0);\n    }\n}\npl Bez(ll a, ll b, ll c) {\n    pl xy;\n    ll x, y, z, gc;\n    xy = Bezout(a, b);\n    gc = gcd(a, b);\n    if (c%gc != 0) return mp(-1, -1);\n    x = xy.fi*(c / gc); y = xy.se*(c / gc);\n    if (x < 0) z = rup(-x, (b / gc));\n    if (x >= 0) z = -x / (b / gc);\n    x += z * (b / gc);\n    y -= z * (a / gc);\n    return mp(x, y);\n}\n\nll DigS10(ll n) {\n    ll ans = 0;\n    while(1) {\n        ans += n % 10;\n        n /= 10;\n        if (!n) break;\n    }\n    return ans;\n}\n\nll isP(ll n) {\n    if (n <= 1) return 0;\n    FOR(i, 2, (ll)sqrt(n) + 1) {\n        if (n%i == 0) return 0;\n    }\n    return 1;\n}\n\nll Tot(ll n) {\n    if (n <= 0) return 0;\n    ll ans = n, x = 2;\n    while (x*x <= n) {\n        if (n%x == 0) {\n            ans -= ans / x;\n            while (n%x == 0) n /= x;\n        }\n        x++;\n    }\n    if (n > 1) ans -= ans / n;\n    return ans;\n}\n\ntemplate <class T> struct Sum {\npublic:\n    V<T> v, s;\n    ll size;\n    Action<T> Add;\n    Sum(V<T> v, Action<T> Add = ADD<T>) : v(v), size(v.sz), Add(Add) { Init(); Calc(); }\n    void Init() {\n        s.asn(size + 1, Add.I);\n    }\n    void Calc() {\n        REP(i, size) s[i + 1] = Add(s[i], v[i]);\n\n    }\n    T operator()(ll x) {\n        return operator()(0, x);\n    }\n    T operator()(ll l, ll r) {\n        if (l < 0) l = 0;\n        if (r >= size) r = size - 1;\n        if (l > r) return Add.I;\n        return s[r + 1] - s[l];//for ADD\n    }\n};\nusing sumll = Sum<ll>;\n\ntemplate <class T> struct Sum2 {\npublic:\n    V<V<T>> v, s;\n    ll RowSize, ColumnSize;\n    Action<T> Add;\n    Sum2(V<V<T>> v, Action<T> Add = ADD<T>) : v(v), RowSize(v.sz), ColumnSize(v.sz ? v[0].sz : 0), Add(Add) { Init(); Calc(); }\n    void Init() {\n        s.asn(RowSize + 1, V<T>(ColumnSize, Add.I));\n    }\n    void Calc() {\n        REP1(r, RowSize) {\n            REP1(c, ColumnSize) {\n                s[r][c] = v[r - 1][c - 1] + operator()(r, c - 1) + operator()(r - 1, c) - operator()(r - 1, c - 1);\n            }\n        }\n    }\n    T operator()(ll r, ll c) {\n        return operator()(0, 0, r, c);\n    }\n    T operator()(ll r1, ll c1, ll r2, ll c2) {\n        if (r1 < 0) r1 = 0;\n        if (c1 < 0) c1 = 0;\n        if (r2 >= RowSize) r2 = RowSize - 1;\n        if (c2 >= ColumnSize) c2 = ColumnSize - 1;\n        if (r1 > r2) return Add.I;\n        if (c1 > c2) return Add.I;\n        return s[r2 + 1][c2 + 1] - s[r2 + 1][c1] - s[r1][c2 + 1] + s[r1][c1];\n    }\n};\nusing sum2ll = Sum2<ll>;\n\ntemplate <class T> struct Point2 {\npublic:\n    V<V<T>> v;\n    ll h, w;\n    Point2() : h(0), w(0) {}\n    Point2(ll h, ll w) : h(h), w(w) { asn(h, w); }\n    Point2(ll h, ll w, T val) : h(h), w(w) { asn(h, w, val); }\n    void assign(ll h, ll w) { v.asn(h, V<T>(w)); }\n    void assign(ll h, ll w, ll val) { v.asn(h, V<T>(w, val)); }\n    T& operator()(ll h, ll w) { return v[h][w]; }\n    T& operator()(pl p) { return v[p.fi][p.se]; }\n};\ntemplate <class T> using P2 = Point2<T>;\n\ntemplate <ll Mod> struct Modll {\npublic:\n    ll v;\n    Modll() : v(0) {}\n    Modll(ll _v) { set(_v % Mod + Mod); }\n    Modll& set(ll _v) {\n        v = (_v < Mod) ? _v : (_v - Mod);\n        return *this;\n    }\n    Modll pow(ll n) const {\n        Modll x = *this, ans = 1;\n        while (n) {\n            if (n & 1) ans *= x;\n            x *= x;\n            n >>= 1;\n        }\n        return ans;\n    }\n    Modll inverse() const { return (*this).pow(Mod - 2); }\n    Modll operator+(const Modll& m) const { return Modll().set(v + m.v); }\n    Modll operator-(const Modll& m) const { return Modll().set(Mod + v - m.v); }\n    Modll operator*(const Modll& m) const { return Modll().set((ull(v) * m.v) % Mod); }\n    Modll operator/(const Modll& m) const { return *this * m.inv; }\n    Modll& operator+=(const Modll& m) { return *this = *this + m; }\n    Modll& operator-=(const Modll& m) { return *this = *this - m; }\n    Modll& operator*=(const Modll& m) { return *this = *this * m; }\n    Modll& operator/=(const Modll& m) { return *this = *this / m; }\n    Modll operator-() const { return Modll(0) - *this; }\n    explicit operator bool() const { return v != 0; }\n    friend ostream& operator<<(ostream& out, const Modll& m) { return out << m.v; }\n};\nusing mll = Modll<MOD>;\nusing vmll = V<mll>;\nusing vvmll = V<vmll>;\nusing vvvmll = V<vvmll>;\n\ntemplate <class T> T vmin(V<T> v) {\n    T tmp = MIN<T>.I;\n    ROR(v, i) emin(tmp, i);\n    return tmp;\n}\ntemplate <class T, class... Args> T vmin(V<T> v, Args... args) {\n    T tmp = vmin(args...);\n    return min(vmin(v), tmp);\n}\n\ntemplate <class T> T vmax(V<T> v) {\n    T tmp = MAX<T>.I;\n    ROR(v, i) emax(tmp, i);\n    return tmp;\n}\ntemplate <class T, class... Args> T vmax(V<T> v, Args... args) {\n    T tmp = vmax(args...);\n    return max(vmax(v), tmp);\n}\n\ntemplate <class T> T vgcd(V<T> v) {\n    T tmp = GCD<T>.I;\n    ROR(v, i) egcd(tmp, i);\n    return tmp;\n}\ntemplate <class T, class... Args> T vgcd(V<T> v, Args... args) {\n    T tmp = vgcd(args...);\n    return gcd(vgcd(v), tmp);\n}\n\ntemplate <class T> T vlcm(V<T> v) {\n    T tmp = LCM<T>.I;\n    ROR(v, i) elcm(tmp, i);\n    return tmp;\n}\ntemplate <class T, class... Args> T vlcm(V<T> v, Args... args) {\n    T tmp = vlcm(args...);\n    return lcm(vlcm(v), tmp);\n}\n\nvmll MFactMemo(2, 1);\nvmll MIFactMemo(2, 1);\n\nmll mFact(ll n) {\n    if (MFactMemo.sz <= n) {\n        ll oldsize = MFactMemo.sz;\n        MFactMemo.res(n + 1, 1);\n        FOR(i, oldsize, n) MFactMemo[i] = MFactMemo[i - 1] * i;\n    }\n    return MFactMemo[n];\n}\nmll miFact(ll n) {\n    if (MIFactMemo.sz <= n) {\n        ll oldsize = MIFactMemo.sz;\n        MIFactMemo.res(n + 1, 1);\n        MIFactMemo.bk = mFact(n).inv;\n        rFOR(i, oldsize + 1, n) MIFactMemo[i - 1] = MIFactMemo[i] * i;\n    }\n    return MIFactMemo[n];\n}\nmll mComb(ll n, ll k) {\n    if (n < 0 || k < 0 || n < k) return 0;\n    return mFact(n) * miFact(k) * miFact(n - k);\n}\n\nll LIS(vll v, ll m = 0) {\n\n    if (v.sz > 0) {\n        ll ans = 0;\n        vll dp(v.sz, INF);\n        FOR(i, 0, v.sz - 1) {\n            dp[m ? UPB(dp, v[i]) : LOWB(dp, v[i])] = v[i];\n        }\n        FOR(i, 0, v.sz - 1) {\n            if (dp[i] == INF) break;\n            ans++;\n        }\n        return ans;\n    }\n    else {\n        return 0;\n    }\n\n}\n\nvoid PCmprs(vll& v) {\n    if (v.sz == 0) return;\n    vll vv(v);\n    IOTA(vv, 0);\n    sort(vv.bgn, vv.en, [&](ll v1, ll v2) {return v[v1] < v[v2]; });\n    IOTA(v, 0);\n    sort(v.bgn, v.en, [&](ll v1, ll v2) {return vv[v1] < vv[v2]; });\n    return;\n}\n\nll BblCnt(vll v) {\n    PCmprs(v);\n    SegT<ll> b(v.sz, 0);\n    ll ans = 0;\n    REP(i, v.sz) {\n        ans += (i - b.que(0, v[i]));\n        b.add(v[i], 1);\n    }\n    return ans;\n}\n\nll Bsrch(function<bool(ll x)> f, ll mi, ll ma) {\n    ll ng = mi - 1, ok = ma, mid;\n    while (ok - ng > 1) {\n        mid = (ng + ok) / 2;\n        (f(mid) ? ok : ng) = mid;\n    }\n    return ok;\n}\n\ntemplate<class T> V<V<T>> MultiMatrix(V<V<T>> A, V<V<T>> B, Action<T> Mul = MUL<T>, Action<T> Add = ADD<T>) {\n    V<V<T>> ans;\n    ll ii = A.sz;\n    if (!ii) return ans;\n    ll jj = A[0].sz;\n    if (!jj) return ans;\n    ll jj2 = B.sz;\n    if (!jj2) return ans;\n    if (jj != jj2) return ans;\n    ll kk = B[0].sz;\n    if (!kk) return ans;\n    ans.asn(ii, V<T>(kk, 0));\n    REP(i, ii) {\n        REP(k, kk) {\n            REP(j, jj) {\n                ans[i][k] = Add(ans[i][k], Mul(A[i][j], B[j][k]));\n            }\n        }\n    }\n    return ans;\n}\n\nvvll CombMemo(1000, vll(1000, -1));\n\nll Comb(ll n, ll k) {\n    if ((n < 0) || (k < 0)) return 0;\n    if (CombMemo[n][k] == -1) {\n        if (n < k) CombMemo[n][k] = 0;\n        else {\n            if (n == 0) CombMemo[n][k] = 1;\n            else if (k == 0) CombMemo[n][k] = 1;\n            else if (n == k) CombMemo[n][k] = 1;\n            else CombMemo[n][k] = Comb(n - 1, k - 1) + Comb(n - 1, k);\n        }\n    }\n    return CombMemo[n][k];\n}\n\ntemplate<class T> map<T, ll> Dict(V<T> v) {\n    map<T, ll> m;\n    if (!v.sz) return m;\n    SORT(v);\n    UNIQUE(v);\n    REP(i, v.sz) {\n        m[v[i]] = i;\n    }\n    return m;\n}\n\ntemplate<class T> vll Cmprs(V<T> v) {\n    auto m = Dict(v);\n    vll ans(v.sz);\n    REP(i,v.sz) {\n        ans[i] = m[v[i]];\n    }\n    return ans;\n}\n\ntemplate <class T> auto vecn(T val) { return val; }\ntemplate <class... Args> auto vecn(ll val, Args... args) {\n    auto tmp = vecn(args...);\n    return V<decltype(tmp)>(val, tmp);\n}\n\nvoid Solve();\n\nsigned main() { \n    cin.tie(0);\n    ios::sync_with_stdio(false);\n    cout << setprecision(20) << fixed;\n    Solve();\n}\n\nvoid Solve() {\n  li(n);vli(n,a);\n  SORT(a);\n  ll zero=0,type=0,f;\n  vll note,count;\n  REP(i,n){\n    if(a[i]==0){\n      zero++;\n    } else {\n      f=-1;\n      REP(j,note.sz){\n        if(note[j]==a[i]){\n          f=j;\n        }\n      }\n      if(f==-1){\n        note.pb(a[i]);\n        count.pb(1);\n      } else {\n        count[f]++;\n      }\n    }\n  }\n  \n  if(a.sz==zero){\n    cout << \"Yes\";\n    return;\n  }\n  \n  if(a.sz%3){\n    cout << \"No\";\n    return;\n  }\n  \n  \n  \n  if(note.sz>=4){\n    cout << \"No\";\n    return;\n  }\n  \n  if(zero){\n    if (a.sz/3==zero && a.sz/3==count[0]/2) {\n      cout << \"Yes\";\n      return;\n    } else {\n      cout << \"No\";\n      return;\n    }\n  } else {\n    if (count[0]==count[1]&&count[0]==count[2]){\n      if((note[0]^note[1]==note[2])&&(note[1]^note[2]==note[0])){\n        cout << \"Yes\";\n        return;\n      }\n    }\n  }\n  cout << \"No\";\n  return;\n}\n\n\n\n\n\n\n\n\n\n\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nSnuke has N hats. The i-th hat has an integer a_i written on it.\n\nThere are N camels standing in a circle.\nSnuke will put one of his hats on each of these camels.\n\nIf there exists a way to distribute the hats to the camels such that the following condition is satisfied for every camel, print Yes; otherwise, print No.\n\nThe bitwise XOR of the numbers written on the hats on both adjacent camels is equal to the number on the hat on itself.\n\nWhat is XOR?\n\nThe bitwise XOR x_1 \\oplus x_2 \\oplus \\ldots \\oplus x_n of n non-negative integers x_1, x_2, \\ldots, x_n is defined as follows:\n\n- When x_1 \\oplus x_2 \\oplus \\ldots \\oplus x_n is written in base two, the digit in the 2^k's place (k \\geq 0) is 1 if the number of integers among x_1, x_2, \\ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.\n\nFor example, 3 \\oplus 5 = 6.\n\nConstraints\n\nAll values in input are integers.\n\n3 \\leq N \\leq 10^{5}\n\n0 \\leq a_i \\leq 10^{9}\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 \\ldots a_{N}\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n3\n1 2 3\n\nSample Output 1\n\nYes\n\nIf we put the hats with 1, 2, and 3 in this order, clockwise, the condition will be satisfied for every camel, so the answer is Yes.\n\nSample Input 2\n\n4\n1 2 4 8\n\nSample Output 2\n\nNo\n\nThere is no such way to distribute the hats; the answer is No.", "sample_input": "3\n1 2 3\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p02975", "source_text": "Score : 300 points\n\nProblem Statement\n\nSnuke has N hats. The i-th hat has an integer a_i written on it.\n\nThere are N camels standing in a circle.\nSnuke will put one of his hats on each of these camels.\n\nIf there exists a way to distribute the hats to the camels such that the following condition is satisfied for every camel, print Yes; otherwise, print No.\n\nThe bitwise XOR of the numbers written on the hats on both adjacent camels is equal to the number on the hat on itself.\n\nWhat is XOR?\n\nThe bitwise XOR x_1 \\oplus x_2 \\oplus \\ldots \\oplus x_n of n non-negative integers x_1, x_2, \\ldots, x_n is defined as follows:\n\n- When x_1 \\oplus x_2 \\oplus \\ldots \\oplus x_n is written in base two, the digit in the 2^k's place (k \\geq 0) is 1 if the number of integers among x_1, x_2, \\ldots, x_n whose binary representations have 1 in the 2^k's place is odd, and 0 if that count is even.\n\nFor example, 3 \\oplus 5 = 6.\n\nConstraints\n\nAll values in input are integers.\n\n3 \\leq N \\leq 10^{5}\n\n0 \\leq a_i \\leq 10^{9}\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 \\ldots a_{N}\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n3\n1 2 3\n\nSample Output 1\n\nYes\n\nIf we put the hats with 1, 2, and 3 in this order, clockwise, the condition will be satisfied for every camel, so the answer is Yes.\n\nSample Input 2\n\n4\n1 2 4 8\n\nSample Output 2\n\nNo\n\nThere is no such way to distribute the hats; the answer is No.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 32722, "cpu_time_ms": 1993, "memory_kb": 10484}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s546812909", "group_id": "codeNet:p02981", "input_text": "#include <iostream>\n#include <algorithm>\n#include <string>\n#include <cmath>\n#include <vector>\n#include <regex>\n#include <map>\n#include <set>\nusing namespace std;\nint main(){\n    int N,A,B;\n    cin >> N >> A >> B;\n    \n    int train = 0;\n    train = A*N;\n    \n    cout << min(train,B) << endl;\n    return 0;\n}\n\n", "language": "C++", "metadata": {"date": 1562547703, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02981.html", "problem_id": "p02981", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02981/input.txt", "sample_output_relpath": "derived/input_output/data/p02981/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02981/C++/s546812909.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s546812909", "user_id": "u451206510"}, "prompt_components": {"gold_output": "8\n", "input_to_evaluate": "#include <iostream>\n#include <algorithm>\n#include <string>\n#include <cmath>\n#include <vector>\n#include <regex>\n#include <map>\n#include <set>\nusing namespace std;\nint main(){\n    int N,A,B;\n    cin >> N >> A >> B;\n    \n    int train = 0;\n    train = A*N;\n    \n    cout << min(train,B) << endl;\n    return 0;\n}\n\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nN of us are going on a trip, by train or taxi.\n\nThe train will cost each of us A yen (the currency of Japan).\n\nThe taxi will cost us a total of B yen.\n\nHow much is our minimum total travel expense?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 20\n\n1 \\leq A \\leq 50\n\n1 \\leq B \\leq 50\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN A B\n\nOutput\n\nPrint an integer representing the minimum total travel expense.\n\nSample Input 1\n\n4 2 9\n\nSample Output 1\n\n8\n\nThe train will cost us 4 \\times 2 = 8 yen, and the taxi will cost us 9 yen, so the minimum total travel expense is 8 yen.\n\nSample Input 2\n\n4 2 7\n\nSample Output 2\n\n7\n\nSample Input 3\n\n4 2 8\n\nSample Output 3\n\n8", "sample_input": "4 2 9\n"}, "reference_outputs": ["8\n"], "source_document_id": "p02981", "source_text": "Score : 100 points\n\nProblem Statement\n\nN of us are going on a trip, by train or taxi.\n\nThe train will cost each of us A yen (the currency of Japan).\n\nThe taxi will cost us a total of B yen.\n\nHow much is our minimum total travel expense?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 20\n\n1 \\leq A \\leq 50\n\n1 \\leq B \\leq 50\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN A B\n\nOutput\n\nPrint an integer representing the minimum total travel expense.\n\nSample Input 1\n\n4 2 9\n\nSample Output 1\n\n8\n\nThe train will cost us 4 \\times 2 = 8 yen, and the taxi will cost us 9 yen, so the minimum total travel expense is 8 yen.\n\nSample Input 2\n\n4 2 7\n\nSample Output 2\n\n7\n\nSample Input 3\n\n4 2 8\n\nSample Output 3\n\n8", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 310, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s058484366", "group_id": "codeNet:p02986", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nconst int maxn = 200100, lg = 22;\nstruct query {\n\tint i, x, y, sig;\n};\nvector<tuple<int,int,int> > e[maxn];\nvector<query> que[maxn];\nint par[lg][maxn], dep[maxn];\nvoid dfs(int u, int p){\n\tpar[0][u] = p;\n\tfor(auto ee : e[u]){\n\t\tint to, b, c; tie(to, b, c);\n\t\tif(to != p){\n\t\t\tdep[to] = dep[u] + 1;\n\t\t\tdfs(to, u);\n\t\t}\n\t}\n}\nint lca(int u, int v){\n\tif(dep[u] < dep[v]) swap(u, v);\n\tfor(int i = lg - 1; i >= 0; i--) if((dep[u] - dep[v])&(1<<i)) u = par[i][u];\n\tif(u == v) return u;\n\tfor(int i = lg - 1; i >= 0; i--) if(par[i][u] != par[i][v]) u = par[i][u], v = par[i][v];\n\treturn par[0][u];\n}\nlong long ans[maxn],  tot[maxn], amn[maxn];\nvoid solve(int u, int p, long long d){\n\tfor(auto q : que[u]){\n\t\tans[q.i] += q.sig * (d - tot[q.x] + q.y * amn[q.x]);\n\t}\n\tfor(auto ee : e[u]){\n\t\tint to, c, di; tie(to, c, di) = ee;\n\t\tif(to == p) continue;\n\t\ttot[c] += di;\n\t\tamn[c] += 1;\n\t\tsolve(to, u, d + di);\n\t\ttot[c] -= di;\n\t\tamn[c] -= 1;\n\t}\n}\nint main(){\n\tint n, q; cin >> n >> q;\n\tfor(int i = 0; i < n - 1; i++){\n\t\tint a, b, c, d; cin >> a >> b >> c >> d;\n\t\te[a].push_back(make_tuple(b, c, d));\n\t\te[b].push_back(make_tuple(a, c, d));\n\t}\n\tdfs(1, 0);\n\tfor(int i = 1; i < lg; i++){\n\t\tfor(int j = 1; j <= n; j++)\n\t\t\tif(par[i - 1][j])\n\t\t\t\tpar[i][j] = par[i - 1][par[i - 1][j]];\n\t}\n\tfor(int i = 0; i < q; i++){\n\t\tint x, y, u, v; cin >> x >> y >> u >> v;\n\t\tque[u].push_back({i, x, y, 1});\n\t\tque[v].push_back({i, x, y, 1});\n\t\tque[lca(u, v)].push_back({i, x, y, -2});\n\t}\n\tsolve(1, 0, 0);\n\tfor(int i = 0; i < q; i++) cout << ans[i] << endl;\n\treturn 0;\n}\n\n", "language": "C++", "metadata": {"date": 1562553174, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02986.html", "problem_id": "p02986", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02986/input.txt", "sample_output_relpath": "derived/input_output/data/p02986/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02986/C++/s058484366.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s058484366", "user_id": "u251828455"}, "prompt_components": {"gold_output": "130\n200\n60\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nconst int maxn = 200100, lg = 22;\nstruct query {\n\tint i, x, y, sig;\n};\nvector<tuple<int,int,int> > e[maxn];\nvector<query> que[maxn];\nint par[lg][maxn], dep[maxn];\nvoid dfs(int u, int p){\n\tpar[0][u] = p;\n\tfor(auto ee : e[u]){\n\t\tint to, b, c; tie(to, b, c);\n\t\tif(to != p){\n\t\t\tdep[to] = dep[u] + 1;\n\t\t\tdfs(to, u);\n\t\t}\n\t}\n}\nint lca(int u, int v){\n\tif(dep[u] < dep[v]) swap(u, v);\n\tfor(int i = lg - 1; i >= 0; i--) if((dep[u] - dep[v])&(1<<i)) u = par[i][u];\n\tif(u == v) return u;\n\tfor(int i = lg - 1; i >= 0; i--) if(par[i][u] != par[i][v]) u = par[i][u], v = par[i][v];\n\treturn par[0][u];\n}\nlong long ans[maxn],  tot[maxn], amn[maxn];\nvoid solve(int u, int p, long long d){\n\tfor(auto q : que[u]){\n\t\tans[q.i] += q.sig * (d - tot[q.x] + q.y * amn[q.x]);\n\t}\n\tfor(auto ee : e[u]){\n\t\tint to, c, di; tie(to, c, di) = ee;\n\t\tif(to == p) continue;\n\t\ttot[c] += di;\n\t\tamn[c] += 1;\n\t\tsolve(to, u, d + di);\n\t\ttot[c] -= di;\n\t\tamn[c] -= 1;\n\t}\n}\nint main(){\n\tint n, q; cin >> n >> q;\n\tfor(int i = 0; i < n - 1; i++){\n\t\tint a, b, c, d; cin >> a >> b >> c >> d;\n\t\te[a].push_back(make_tuple(b, c, d));\n\t\te[b].push_back(make_tuple(a, c, d));\n\t}\n\tdfs(1, 0);\n\tfor(int i = 1; i < lg; i++){\n\t\tfor(int j = 1; j <= n; j++)\n\t\t\tif(par[i - 1][j])\n\t\t\t\tpar[i][j] = par[i - 1][par[i - 1][j]];\n\t}\n\tfor(int i = 0; i < q; i++){\n\t\tint x, y, u, v; cin >> x >> y >> u >> v;\n\t\tque[u].push_back({i, x, y, 1});\n\t\tque[v].push_back({i, x, y, 1});\n\t\tque[lca(u, v)].push_back({i, x, y, -2});\n\t}\n\tsolve(1, 0, 0);\n\tfor(int i = 0; i < q; i++) cout << ans[i] << endl;\n\treturn 0;\n}\n\n", "problem_context": "Score : 600 points\n\nProblem Statement\n\nThere is a tree with N vertices numbered 1 to N.\nThe i-th edge in this tree connects Vertex a_i and Vertex b_i, and the color and length of that edge are c_i and d_i, respectively.\nHere the color of each edge is represented by an integer between 1 and N-1 (inclusive). The same integer corresponds to the same color, and different integers correspond to different colors.\n\nAnswer the following Q queries:\n\nQuery j (1 \\leq j \\leq Q): assuming that the length of every edge whose color is x_j is changed to y_j, find the distance between Vertex u_j and Vertex v_j. (The changes of the lengths of edges do not affect the subsequent queries.)\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n1 \\leq Q \\leq 10^5\n\n1 \\leq a_i, b_i \\leq N\n\n1 \\leq c_i \\leq N-1\n\n1 \\leq d_i \\leq 10^4\n\n1 \\leq x_j \\leq N-1\n\n1 \\leq y_j \\leq 10^4\n\n1 \\leq u_j < v_j \\leq N\n\nThe given graph is a tree.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN Q\na_1 b_1 c_1 d_1\n:\na_{N-1} b_{N-1} c_{N-1} d_{N-1}\nx_1 y_1 u_1 v_1\n:\nx_Q y_Q u_Q v_Q\n\nOutput\n\nPrint Q lines. The j-th line (1 \\leq j \\leq Q) should contain the answer to Query j.\n\nSample Input 1\n\n5 3\n1 2 1 10\n1 3 2 20\n2 4 4 30\n5 2 1 40\n1 100 1 4\n1 100 1 5\n3 1000 3 4\n\nSample Output 1\n\n130\n200\n60\n\nThe graph in this input is as follows:\n\nHere the edges of Color 1 are shown as solid red lines, the edge of Color 2 is shown as a bold green line, and the edge of Color 4 is shown as a blue dashed line.\n\nQuery 1: Assuming that the length of every edge whose color is 1 is changed to 100, the distance between Vertex 1 and Vertex 4 is 100 + 30 = 130.\n\nQuery 2: Assuming that the length of every edge whose color is 1 is changed to 100, the distance between Vertex 1 and Vertex 5 is 100 + 100 = 200.\n\nQuery 3: Assuming that the length of every edge whose color is 3 is changed to 1000 (there is no such edge), the distance between Vertex 3 and Vertex 4 is 20 + 10 + 30 = 60. Note that the edges of Color 1 now have their original lengths.", "sample_input": "5 3\n1 2 1 10\n1 3 2 20\n2 4 4 30\n5 2 1 40\n1 100 1 4\n1 100 1 5\n3 1000 3 4\n"}, "reference_outputs": ["130\n200\n60\n"], "source_document_id": "p02986", "source_text": "Score : 600 points\n\nProblem Statement\n\nThere is a tree with N vertices numbered 1 to N.\nThe i-th edge in this tree connects Vertex a_i and Vertex b_i, and the color and length of that edge are c_i and d_i, respectively.\nHere the color of each edge is represented by an integer between 1 and N-1 (inclusive). The same integer corresponds to the same color, and different integers correspond to different colors.\n\nAnswer the following Q queries:\n\nQuery j (1 \\leq j \\leq Q): assuming that the length of every edge whose color is x_j is changed to y_j, find the distance between Vertex u_j and Vertex v_j. (The changes of the lengths of edges do not affect the subsequent queries.)\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n1 \\leq Q \\leq 10^5\n\n1 \\leq a_i, b_i \\leq N\n\n1 \\leq c_i \\leq N-1\n\n1 \\leq d_i \\leq 10^4\n\n1 \\leq x_j \\leq N-1\n\n1 \\leq y_j \\leq 10^4\n\n1 \\leq u_j < v_j \\leq N\n\nThe given graph is a tree.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN Q\na_1 b_1 c_1 d_1\n:\na_{N-1} b_{N-1} c_{N-1} d_{N-1}\nx_1 y_1 u_1 v_1\n:\nx_Q y_Q u_Q v_Q\n\nOutput\n\nPrint Q lines. The j-th line (1 \\leq j \\leq Q) should contain the answer to Query j.\n\nSample Input 1\n\n5 3\n1 2 1 10\n1 3 2 20\n2 4 4 30\n5 2 1 40\n1 100 1 4\n1 100 1 5\n3 1000 3 4\n\nSample Output 1\n\n130\n200\n60\n\nThe graph in this input is as follows:\n\nHere the edges of Color 1 are shown as solid red lines, the edge of Color 2 is shown as a bold green line, and the edge of Color 4 is shown as a blue dashed line.\n\nQuery 1: Assuming that the length of every edge whose color is 1 is changed to 100, the distance between Vertex 1 and Vertex 4 is 100 + 30 = 130.\n\nQuery 2: Assuming that the length of every edge whose color is 1 is changed to 100, the distance between Vertex 1 and Vertex 5 is 100 + 100 = 200.\n\nQuery 3: Assuming that the length of every edge whose color is 3 is changed to 1000 (there is no such edge), the distance between Vertex 3 and Vertex 4 is 20 + 10 + 30 = 60. Note that the edges of Color 1 now have their original lengths.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1576, "cpu_time_ms": 516, "memory_kb": 31344}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s323404344", "group_id": "codeNet:p02988", "input_text": "#include <bits/stdc++.h>\n#define rep(i, n) for(int (i)=0; (i)<(n); (i)++)\n\nusing namespace std;\ntypedef long long ll;\n\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }\n\nint main()\n{\n  int N;\n  cin >> N;\n\n  vector<int> p(N);\n  for(int i=0; i<N; i++)\n    cin >> p[i];\n\n  int count;\n  for(int i=0; i<N-2; i++)\n    {\n      if(p[i]<p[i+1] && p[i+1]<p[i+2])\n\tcount++;\n      if(p[i+2]<p[i+1] && p[i+1]<p[i])\n\tcount++;\n      \n    }\n\n  cout << count << endl;\n\n\n  return 0;\n}\n\n\n//cout << setprecision(13);\n//next_permutation();\n//__gcd();\n//reverse();\n//set ,tuple ,pair;\n//bitset\n//vector.find\n//vector.count\n\n", "language": "C++", "metadata": {"date": 1582529714, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02988.html", "problem_id": "p02988", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02988/input.txt", "sample_output_relpath": "derived/input_output/data/p02988/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02988/C++/s323404344.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s323404344", "user_id": "u005906204"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define rep(i, n) for(int (i)=0; (i)<(n); (i)++)\n\nusing namespace std;\ntypedef long long ll;\n\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }\n\nint main()\n{\n  int N;\n  cin >> N;\n\n  vector<int> p(N);\n  for(int i=0; i<N; i++)\n    cin >> p[i];\n\n  int count;\n  for(int i=0; i<N-2; i++)\n    {\n      if(p[i]<p[i+1] && p[i+1]<p[i+2])\n\tcount++;\n      if(p[i+2]<p[i+1] && p[i+1]<p[i])\n\tcount++;\n      \n    }\n\n  cout << count << endl;\n\n\n  return 0;\n}\n\n\n//cout << setprecision(13);\n//next_permutation();\n//__gcd();\n//reverse();\n//set ,tuple ,pair;\n//bitset\n//vector.find\n//vector.count\n\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nWe have a permutation p = {p_1,\\ p_2,\\ ...,\\ p_n} of {1,\\ 2,\\ ...,\\ n}.\n\nPrint the number of elements p_i (1 < i < n) that satisfy the following condition:\n\np_i is the second smallest number among the three numbers p_{i - 1}, p_i, and p_{i + 1}.\n\nConstraints\n\nAll values in input are integers.\n\n3 \\leq n \\leq 20\n\np is a permutation of {1,\\ 2,\\ ...,\\ n}.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn\np_1 p_2 ... p_n\n\nOutput\n\nPrint the number of elements p_i (1 < i < n) that satisfy the condition.\n\nSample Input 1\n\n5\n1 3 5 4 2\n\nSample Output 1\n\n2\n\np_2 = 3 is the second smallest number among p_1 = 1, p_2 = 3, and p_3 = 5. Also, p_4 = 4 is the second smallest number among p_3 = 5, p_4 = 4, and p_5 = 2. These two elements satisfy the condition.\n\nSample Input 2\n\n9\n9 6 3 2 5 8 7 4 1\n\nSample Output 2\n\n5", "sample_input": "5\n1 3 5 4 2\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02988", "source_text": "Score : 200 points\n\nProblem Statement\n\nWe have a permutation p = {p_1,\\ p_2,\\ ...,\\ p_n} of {1,\\ 2,\\ ...,\\ n}.\n\nPrint the number of elements p_i (1 < i < n) that satisfy the following condition:\n\np_i is the second smallest number among the three numbers p_{i - 1}, p_i, and p_{i + 1}.\n\nConstraints\n\nAll values in input are integers.\n\n3 \\leq n \\leq 20\n\np is a permutation of {1,\\ 2,\\ ...,\\ n}.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn\np_1 p_2 ... p_n\n\nOutput\n\nPrint the number of elements p_i (1 < i < n) that satisfy the condition.\n\nSample Input 1\n\n5\n1 3 5 4 2\n\nSample Output 1\n\n2\n\np_2 = 3 is the second smallest number among p_1 = 1, p_2 = 3, and p_3 = 5. Also, p_4 = 4 is the second smallest number among p_3 = 5, p_4 = 4, and p_5 = 2. These two elements satisfy the condition.\n\nSample Input 2\n\n9\n9 6 3 2 5 8 7 4 1\n\nSample Output 2\n\n5", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 728, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s606473791", "group_id": "codeNet:p02988", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n  int N;\n  cin >> N;\n\n  vector<int> p(N);\n\n  for (int i = 0; i < N; i++)\n  {\n    cin >> p.at(i);\n  }\n\n  int ans = 0;\n\n  for (int i = 1; i < N - 1; i++)\n  {\n    if (p.at(i) != max({p.at(i - 1), p.at(i), p.at(i + 1)}) && p.at(i) != min({p.at(i - 1), p.at(i), p.at(i + 1)}))\n    {\n      ans++;\n    }\n  }\n\n  cout << ans << endl;\n}\n", "language": "C++", "metadata": {"date": 1582478081, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02988.html", "problem_id": "p02988", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02988/input.txt", "sample_output_relpath": "derived/input_output/data/p02988/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02988/C++/s606473791.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s606473791", "user_id": "u455876837"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n  int N;\n  cin >> N;\n\n  vector<int> p(N);\n\n  for (int i = 0; i < N; i++)\n  {\n    cin >> p.at(i);\n  }\n\n  int ans = 0;\n\n  for (int i = 1; i < N - 1; i++)\n  {\n    if (p.at(i) != max({p.at(i - 1), p.at(i), p.at(i + 1)}) && p.at(i) != min({p.at(i - 1), p.at(i), p.at(i + 1)}))\n    {\n      ans++;\n    }\n  }\n\n  cout << ans << endl;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nWe have a permutation p = {p_1,\\ p_2,\\ ...,\\ p_n} of {1,\\ 2,\\ ...,\\ n}.\n\nPrint the number of elements p_i (1 < i < n) that satisfy the following condition:\n\np_i is the second smallest number among the three numbers p_{i - 1}, p_i, and p_{i + 1}.\n\nConstraints\n\nAll values in input are integers.\n\n3 \\leq n \\leq 20\n\np is a permutation of {1,\\ 2,\\ ...,\\ n}.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn\np_1 p_2 ... p_n\n\nOutput\n\nPrint the number of elements p_i (1 < i < n) that satisfy the condition.\n\nSample Input 1\n\n5\n1 3 5 4 2\n\nSample Output 1\n\n2\n\np_2 = 3 is the second smallest number among p_1 = 1, p_2 = 3, and p_3 = 5. Also, p_4 = 4 is the second smallest number among p_3 = 5, p_4 = 4, and p_5 = 2. These two elements satisfy the condition.\n\nSample Input 2\n\n9\n9 6 3 2 5 8 7 4 1\n\nSample Output 2\n\n5", "sample_input": "5\n1 3 5 4 2\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02988", "source_text": "Score : 200 points\n\nProblem Statement\n\nWe have a permutation p = {p_1,\\ p_2,\\ ...,\\ p_n} of {1,\\ 2,\\ ...,\\ n}.\n\nPrint the number of elements p_i (1 < i < n) that satisfy the following condition:\n\np_i is the second smallest number among the three numbers p_{i - 1}, p_i, and p_{i + 1}.\n\nConstraints\n\nAll values in input are integers.\n\n3 \\leq n \\leq 20\n\np is a permutation of {1,\\ 2,\\ ...,\\ n}.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn\np_1 p_2 ... p_n\n\nOutput\n\nPrint the number of elements p_i (1 < i < n) that satisfy the condition.\n\nSample Input 1\n\n5\n1 3 5 4 2\n\nSample Output 1\n\n2\n\np_2 = 3 is the second smallest number among p_1 = 1, p_2 = 3, and p_3 = 5. Also, p_4 = 4 is the second smallest number among p_3 = 5, p_4 = 4, and p_5 = 2. These two elements satisfy the condition.\n\nSample Input 2\n\n9\n9 6 3 2 5 8 7 4 1\n\nSample Output 2\n\n5", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 387, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s860963272", "group_id": "codeNet:p02988", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n  int N;\n  cin>>N;\n  vector<int> vec(N);\n  int count=0;\n  for(int i=0;i<N;i++)\n  {\n    cin>>vec.at(i);\n  }\n  for(int i=1;i<N-1;i++)\n  {\n    if((vec.at(i-1)<vec.at(i)&&vec.at(i)<vec.at(i+1))||(vec.at(i-1)>vec.at(i)&&vec.at(i)>vec.at(i+1)))\n    {\n       count++;\n    }\n  }\n  cout<<count<<endl;\n}\n", "language": "C++", "metadata": {"date": 1568453203, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02988.html", "problem_id": "p02988", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02988/input.txt", "sample_output_relpath": "derived/input_output/data/p02988/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02988/C++/s860963272.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s860963272", "user_id": "u274435144"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n  int N;\n  cin>>N;\n  vector<int> vec(N);\n  int count=0;\n  for(int i=0;i<N;i++)\n  {\n    cin>>vec.at(i);\n  }\n  for(int i=1;i<N-1;i++)\n  {\n    if((vec.at(i-1)<vec.at(i)&&vec.at(i)<vec.at(i+1))||(vec.at(i-1)>vec.at(i)&&vec.at(i)>vec.at(i+1)))\n    {\n       count++;\n    }\n  }\n  cout<<count<<endl;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nWe have a permutation p = {p_1,\\ p_2,\\ ...,\\ p_n} of {1,\\ 2,\\ ...,\\ n}.\n\nPrint the number of elements p_i (1 < i < n) that satisfy the following condition:\n\np_i is the second smallest number among the three numbers p_{i - 1}, p_i, and p_{i + 1}.\n\nConstraints\n\nAll values in input are integers.\n\n3 \\leq n \\leq 20\n\np is a permutation of {1,\\ 2,\\ ...,\\ n}.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn\np_1 p_2 ... p_n\n\nOutput\n\nPrint the number of elements p_i (1 < i < n) that satisfy the condition.\n\nSample Input 1\n\n5\n1 3 5 4 2\n\nSample Output 1\n\n2\n\np_2 = 3 is the second smallest number among p_1 = 1, p_2 = 3, and p_3 = 5. Also, p_4 = 4 is the second smallest number among p_3 = 5, p_4 = 4, and p_5 = 2. These two elements satisfy the condition.\n\nSample Input 2\n\n9\n9 6 3 2 5 8 7 4 1\n\nSample Output 2\n\n5", "sample_input": "5\n1 3 5 4 2\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02988", "source_text": "Score : 200 points\n\nProblem Statement\n\nWe have a permutation p = {p_1,\\ p_2,\\ ...,\\ p_n} of {1,\\ 2,\\ ...,\\ n}.\n\nPrint the number of elements p_i (1 < i < n) that satisfy the following condition:\n\np_i is the second smallest number among the three numbers p_{i - 1}, p_i, and p_{i + 1}.\n\nConstraints\n\nAll values in input are integers.\n\n3 \\leq n \\leq 20\n\np is a permutation of {1,\\ 2,\\ ...,\\ n}.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn\np_1 p_2 ... p_n\n\nOutput\n\nPrint the number of elements p_i (1 < i < n) that satisfy the condition.\n\nSample Input 1\n\n5\n1 3 5 4 2\n\nSample Output 1\n\n2\n\np_2 = 3 is the second smallest number among p_1 = 1, p_2 = 3, and p_3 = 5. Also, p_4 = 4 is the second smallest number among p_3 = 5, p_4 = 4, and p_5 = 2. These two elements satisfy the condition.\n\nSample Input 2\n\n9\n9 6 3 2 5 8 7 4 1\n\nSample Output 2\n\n5", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 352, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s493895238", "group_id": "codeNet:p02988", "input_text": "#include <iostream>\nusing namespace std;\nint main()\n{\n int n;\n cin >>n;\n int p[n];\n  for(int i=0;i<n;i++)\n    cin >> p[i];\n  int count = 0;\n  for(int i=1;i<n-1;i++)\n  {\n    if(((p[i-1]<p[i]) && (p[i]<p[i+1]))||((p[i-1]>p[i])&&(p[i]>p[i+1])))\n      count++;\n  }\n  cout << count <<endl;\n  \n  return 0;\n}", "language": "C++", "metadata": {"date": 1562462835, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02988.html", "problem_id": "p02988", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02988/input.txt", "sample_output_relpath": "derived/input_output/data/p02988/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02988/C++/s493895238.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s493895238", "user_id": "u586212264"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <iostream>\nusing namespace std;\nint main()\n{\n int n;\n cin >>n;\n int p[n];\n  for(int i=0;i<n;i++)\n    cin >> p[i];\n  int count = 0;\n  for(int i=1;i<n-1;i++)\n  {\n    if(((p[i-1]<p[i]) && (p[i]<p[i+1]))||((p[i-1]>p[i])&&(p[i]>p[i+1])))\n      count++;\n  }\n  cout << count <<endl;\n  \n  return 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nWe have a permutation p = {p_1,\\ p_2,\\ ...,\\ p_n} of {1,\\ 2,\\ ...,\\ n}.\n\nPrint the number of elements p_i (1 < i < n) that satisfy the following condition:\n\np_i is the second smallest number among the three numbers p_{i - 1}, p_i, and p_{i + 1}.\n\nConstraints\n\nAll values in input are integers.\n\n3 \\leq n \\leq 20\n\np is a permutation of {1,\\ 2,\\ ...,\\ n}.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn\np_1 p_2 ... p_n\n\nOutput\n\nPrint the number of elements p_i (1 < i < n) that satisfy the condition.\n\nSample Input 1\n\n5\n1 3 5 4 2\n\nSample Output 1\n\n2\n\np_2 = 3 is the second smallest number among p_1 = 1, p_2 = 3, and p_3 = 5. Also, p_4 = 4 is the second smallest number among p_3 = 5, p_4 = 4, and p_5 = 2. These two elements satisfy the condition.\n\nSample Input 2\n\n9\n9 6 3 2 5 8 7 4 1\n\nSample Output 2\n\n5", "sample_input": "5\n1 3 5 4 2\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02988", "source_text": "Score : 200 points\n\nProblem Statement\n\nWe have a permutation p = {p_1,\\ p_2,\\ ...,\\ p_n} of {1,\\ 2,\\ ...,\\ n}.\n\nPrint the number of elements p_i (1 < i < n) that satisfy the following condition:\n\np_i is the second smallest number among the three numbers p_{i - 1}, p_i, and p_{i + 1}.\n\nConstraints\n\nAll values in input are integers.\n\n3 \\leq n \\leq 20\n\np is a permutation of {1,\\ 2,\\ ...,\\ n}.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn\np_1 p_2 ... p_n\n\nOutput\n\nPrint the number of elements p_i (1 < i < n) that satisfy the condition.\n\nSample Input 1\n\n5\n1 3 5 4 2\n\nSample Output 1\n\n2\n\np_2 = 3 is the second smallest number among p_1 = 1, p_2 = 3, and p_3 = 5. Also, p_4 = 4 is the second smallest number among p_3 = 5, p_4 = 4, and p_5 = 2. These two elements satisfy the condition.\n\nSample Input 2\n\n9\n9 6 3 2 5 8 7 4 1\n\nSample Output 2\n\n5", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 301, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s926632251", "group_id": "codeNet:p02988", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nsigned\nmain(){\n\tint n;\n\tcin >> n;\n\tvector<int> p(n);\n\tfor(int i=0;i<n;i++) cin >> p[i];\n\n\tint cnt = 0;\n\tfor(int x=0;x<n-2;x++){\n\t\tif(p[x] < p[x+1] and p[x+1] < p[x+2]) {\n\t\t\tcnt++;\n\t\t}else if(p[x] > p[x+1] and p[x+1] > p[x+2])\n\t\t{\n\t\t\tcnt++;\n\t\t}\n\t}\n\tcout << cnt << endl;\n}", "language": "C++", "metadata": {"date": 1561858094, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02988.html", "problem_id": "p02988", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02988/input.txt", "sample_output_relpath": "derived/input_output/data/p02988/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02988/C++/s926632251.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s926632251", "user_id": "u003019316"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nsigned\nmain(){\n\tint n;\n\tcin >> n;\n\tvector<int> p(n);\n\tfor(int i=0;i<n;i++) cin >> p[i];\n\n\tint cnt = 0;\n\tfor(int x=0;x<n-2;x++){\n\t\tif(p[x] < p[x+1] and p[x+1] < p[x+2]) {\n\t\t\tcnt++;\n\t\t}else if(p[x] > p[x+1] and p[x+1] > p[x+2])\n\t\t{\n\t\t\tcnt++;\n\t\t}\n\t}\n\tcout << cnt << endl;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nWe have a permutation p = {p_1,\\ p_2,\\ ...,\\ p_n} of {1,\\ 2,\\ ...,\\ n}.\n\nPrint the number of elements p_i (1 < i < n) that satisfy the following condition:\n\np_i is the second smallest number among the three numbers p_{i - 1}, p_i, and p_{i + 1}.\n\nConstraints\n\nAll values in input are integers.\n\n3 \\leq n \\leq 20\n\np is a permutation of {1,\\ 2,\\ ...,\\ n}.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn\np_1 p_2 ... p_n\n\nOutput\n\nPrint the number of elements p_i (1 < i < n) that satisfy the condition.\n\nSample Input 1\n\n5\n1 3 5 4 2\n\nSample Output 1\n\n2\n\np_2 = 3 is the second smallest number among p_1 = 1, p_2 = 3, and p_3 = 5. Also, p_4 = 4 is the second smallest number among p_3 = 5, p_4 = 4, and p_5 = 2. These two elements satisfy the condition.\n\nSample Input 2\n\n9\n9 6 3 2 5 8 7 4 1\n\nSample Output 2\n\n5", "sample_input": "5\n1 3 5 4 2\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02988", "source_text": "Score : 200 points\n\nProblem Statement\n\nWe have a permutation p = {p_1,\\ p_2,\\ ...,\\ p_n} of {1,\\ 2,\\ ...,\\ n}.\n\nPrint the number of elements p_i (1 < i < n) that satisfy the following condition:\n\np_i is the second smallest number among the three numbers p_{i - 1}, p_i, and p_{i + 1}.\n\nConstraints\n\nAll values in input are integers.\n\n3 \\leq n \\leq 20\n\np is a permutation of {1,\\ 2,\\ ...,\\ n}.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn\np_1 p_2 ... p_n\n\nOutput\n\nPrint the number of elements p_i (1 < i < n) that satisfy the condition.\n\nSample Input 1\n\n5\n1 3 5 4 2\n\nSample Output 1\n\n2\n\np_2 = 3 is the second smallest number among p_1 = 1, p_2 = 3, and p_3 = 5. Also, p_4 = 4 is the second smallest number among p_3 = 5, p_4 = 4, and p_5 = 2. These two elements satisfy the condition.\n\nSample Input 2\n\n9\n9 6 3 2 5 8 7 4 1\n\nSample Output 2\n\n5", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 339, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s745278965", "group_id": "codeNet:p02988", "input_text": "#include<bits/stdc++.h>\n\nusing namespace std;\nusing ll  = long long;\nusing ii  = pair < int , int >;\nusing i3  = pair < int , ii >;\nusing vi  = vector < int >;\nusing vii = vector < ii >;\nusing vi3 = vector < i3 >;\n\nconst int N = 25;\nconst ll INF = 1e12;\nconst double eps = 1e-9 , PI = acos(-1);\n\nint n , m;\nint a[N];\n\nvoid solve(){\n    scanf(\"%d\" , &n);\n    for(int i = 0 ; i < n ; i ++){\n        scanf(\"%d\" , &a[i]);\n    }\n    int ans = 0;\n    for(int i = 1 ; i < n-1 ; i ++){\n        vi tmp({a[i-1] , a[i] , a[i+1]});\n        sort(tmp.begin() , tmp.end());\n        if(tmp[1] == a[i])ans ++;\n    }\n    printf(\"%d\\n\" , ans);\n\n}\n\nmain(){\n    int t = 1;\n    //scanf(\"%d\" , &t);\n\n    while( t -- ){\n            solve();\n    }\n\n    return 0;\n}\n\n\n", "language": "C++", "metadata": {"date": 1561856867, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02988.html", "problem_id": "p02988", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02988/input.txt", "sample_output_relpath": "derived/input_output/data/p02988/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02988/C++/s745278965.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s745278965", "user_id": "u284539389"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include<bits/stdc++.h>\n\nusing namespace std;\nusing ll  = long long;\nusing ii  = pair < int , int >;\nusing i3  = pair < int , ii >;\nusing vi  = vector < int >;\nusing vii = vector < ii >;\nusing vi3 = vector < i3 >;\n\nconst int N = 25;\nconst ll INF = 1e12;\nconst double eps = 1e-9 , PI = acos(-1);\n\nint n , m;\nint a[N];\n\nvoid solve(){\n    scanf(\"%d\" , &n);\n    for(int i = 0 ; i < n ; i ++){\n        scanf(\"%d\" , &a[i]);\n    }\n    int ans = 0;\n    for(int i = 1 ; i < n-1 ; i ++){\n        vi tmp({a[i-1] , a[i] , a[i+1]});\n        sort(tmp.begin() , tmp.end());\n        if(tmp[1] == a[i])ans ++;\n    }\n    printf(\"%d\\n\" , ans);\n\n}\n\nmain(){\n    int t = 1;\n    //scanf(\"%d\" , &t);\n\n    while( t -- ){\n            solve();\n    }\n\n    return 0;\n}\n\n\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nWe have a permutation p = {p_1,\\ p_2,\\ ...,\\ p_n} of {1,\\ 2,\\ ...,\\ n}.\n\nPrint the number of elements p_i (1 < i < n) that satisfy the following condition:\n\np_i is the second smallest number among the three numbers p_{i - 1}, p_i, and p_{i + 1}.\n\nConstraints\n\nAll values in input are integers.\n\n3 \\leq n \\leq 20\n\np is a permutation of {1,\\ 2,\\ ...,\\ n}.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn\np_1 p_2 ... p_n\n\nOutput\n\nPrint the number of elements p_i (1 < i < n) that satisfy the condition.\n\nSample Input 1\n\n5\n1 3 5 4 2\n\nSample Output 1\n\n2\n\np_2 = 3 is the second smallest number among p_1 = 1, p_2 = 3, and p_3 = 5. Also, p_4 = 4 is the second smallest number among p_3 = 5, p_4 = 4, and p_5 = 2. These two elements satisfy the condition.\n\nSample Input 2\n\n9\n9 6 3 2 5 8 7 4 1\n\nSample Output 2\n\n5", "sample_input": "5\n1 3 5 4 2\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02988", "source_text": "Score : 200 points\n\nProblem Statement\n\nWe have a permutation p = {p_1,\\ p_2,\\ ...,\\ p_n} of {1,\\ 2,\\ ...,\\ n}.\n\nPrint the number of elements p_i (1 < i < n) that satisfy the following condition:\n\np_i is the second smallest number among the three numbers p_{i - 1}, p_i, and p_{i + 1}.\n\nConstraints\n\nAll values in input are integers.\n\n3 \\leq n \\leq 20\n\np is a permutation of {1,\\ 2,\\ ...,\\ n}.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn\np_1 p_2 ... p_n\n\nOutput\n\nPrint the number of elements p_i (1 < i < n) that satisfy the condition.\n\nSample Input 1\n\n5\n1 3 5 4 2\n\nSample Output 1\n\n2\n\np_2 = 3 is the second smallest number among p_1 = 1, p_2 = 3, and p_3 = 5. Also, p_4 = 4 is the second smallest number among p_3 = 5, p_4 = 4, and p_5 = 2. These two elements satisfy the condition.\n\nSample Input 2\n\n9\n9 6 3 2 5 8 7 4 1\n\nSample Output 2\n\n5", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 742, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s747717894", "group_id": "codeNet:p02989", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n    int n; cin>>n;\n    vector<int> d(n);\n    for(int  &x: d) cin>>x;\n    sort(d.begin(),d.end());\n    cout<<d[n/2]-d[n/2-1]<<endl;\n}\n    \n", "language": "C++", "metadata": {"date": 1591065341, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02989.html", "problem_id": "p02989", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02989/input.txt", "sample_output_relpath": "derived/input_output/data/p02989/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02989/C++/s747717894.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s747717894", "user_id": "u303694543"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n    int n; cin>>n;\n    vector<int> d(n);\n    for(int  &x: d) cin>>x;\n    sort(d.begin(),d.end());\n    cout<<d[n/2]-d[n/2-1]<<endl;\n}\n    \n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nTakahashi made N problems for competitive programming.\nThe problems are numbered 1 to N, and the difficulty of Problem i is represented as an integer d_i (the higher, the harder).\n\nHe is dividing the problems into two categories by choosing an integer K, as follows:\n\nA problem with difficulty K or higher will be for ARCs.\n\nA problem with difficulty lower than K will be for ABCs.\n\nHow many choices of the integer K make the number of problems for ARCs and the number of problems for ABCs the same?\n\nProblem Statement\n\n2 \\leq N \\leq 10^5\n\nN is an even number.\n\n1 \\leq d_i \\leq 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nd_1 d_2 ... d_N\n\nOutput\n\nPrint the number of choices of the integer K that make the number of problems for ARCs and the number of problems for ABCs the same.\n\nSample Input 1\n\n6\n9 1 4 4 6 7\n\nSample Output 1\n\n2\n\nIf we choose K=5 or 6, Problem 1, 5, and 6 will be for ARCs, Problem 2, 3, and 4 will be for ABCs, and the objective is achieved.\nThus, the answer is 2.\n\nSample Input 2\n\n8\n9 1 14 5 5 4 4 14\n\nSample Output 2\n\n0\n\nThere may be no choice of the integer K that make the number of problems for ARCs and the number of problems for ABCs the same.\n\nSample Input 3\n\n14\n99592 10342 29105 78532 83018 11639 92015 77204 30914 21912 34519 80835 100000 1\n\nSample Output 3\n\n42685", "sample_input": "6\n9 1 4 4 6 7\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02989", "source_text": "Score : 300 points\n\nProblem Statement\n\nTakahashi made N problems for competitive programming.\nThe problems are numbered 1 to N, and the difficulty of Problem i is represented as an integer d_i (the higher, the harder).\n\nHe is dividing the problems into two categories by choosing an integer K, as follows:\n\nA problem with difficulty K or higher will be for ARCs.\n\nA problem with difficulty lower than K will be for ABCs.\n\nHow many choices of the integer K make the number of problems for ARCs and the number of problems for ABCs the same?\n\nProblem Statement\n\n2 \\leq N \\leq 10^5\n\nN is an even number.\n\n1 \\leq d_i \\leq 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nd_1 d_2 ... d_N\n\nOutput\n\nPrint the number of choices of the integer K that make the number of problems for ARCs and the number of problems for ABCs the same.\n\nSample Input 1\n\n6\n9 1 4 4 6 7\n\nSample Output 1\n\n2\n\nIf we choose K=5 or 6, Problem 1, 5, and 6 will be for ARCs, Problem 2, 3, and 4 will be for ABCs, and the objective is achieved.\nThus, the answer is 2.\n\nSample Input 2\n\n8\n9 1 14 5 5 4 4 14\n\nSample Output 2\n\n0\n\nThere may be no choice of the integer K that make the number of problems for ARCs and the number of problems for ABCs the same.\n\nSample Input 3\n\n14\n99592 10342 29105 78532 83018 11639 92015 77204 30914 21912 34519 80835 100000 1\n\nSample Output 3\n\n42685", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 197, "cpu_time_ms": 35, "memory_kb": 768}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s475454151", "group_id": "codeNet:p02990", "input_text": "#include <iostream>\n#include <string>\n#include <algorithm>\n#include <cstdint>\nusing namespace std;\n\nuintmax_t combination(unsigned int n, unsigned int r) {\n  if ( r * 2 > n ) r = n - r;\n  uintmax_t dividend = 1;\n  uintmax_t divisor  = 1;\n  for ( unsigned int i = 1; i <= r; ++i ) {\n    dividend *= (n-i+1);\n    divisor  *= i;\n  }\n  return dividend / divisor;\n}\n\nint main() {\n  int K, N;\n  cin >> N >> K;\n  for (int i = 1; i <= K; i++) {\n   // cout << K-1 << \",\" << i-1 << \"|\" << N-K+1 << \",\" << i << endl;\n    if (N-K+1 < i || K-1 < i-1) cout << \"0\" << endl;\n    else cout << (combination(K-1, i-1) * combination(N-K+1, i)) % 1000000007 << endl;\n  }\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1561861068, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02990.html", "problem_id": "p02990", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02990/input.txt", "sample_output_relpath": "derived/input_output/data/p02990/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02990/C++/s475454151.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s475454151", "user_id": "u370509310"}, "prompt_components": {"gold_output": "3\n6\n1\n", "input_to_evaluate": "#include <iostream>\n#include <string>\n#include <algorithm>\n#include <cstdint>\nusing namespace std;\n\nuintmax_t combination(unsigned int n, unsigned int r) {\n  if ( r * 2 > n ) r = n - r;\n  uintmax_t dividend = 1;\n  uintmax_t divisor  = 1;\n  for ( unsigned int i = 1; i <= r; ++i ) {\n    dividend *= (n-i+1);\n    divisor  *= i;\n  }\n  return dividend / divisor;\n}\n\nint main() {\n  int K, N;\n  cin >> N >> K;\n  for (int i = 1; i <= K; i++) {\n   // cout << K-1 << \",\" << i-1 << \"|\" << N-K+1 << \",\" << i << endl;\n    if (N-K+1 < i || K-1 < i-1) cout << \"0\" << endl;\n    else cout << (combination(K-1, i-1) * combination(N-K+1, i)) % 1000000007 << endl;\n  }\n  return 0;\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nThere are K blue balls and N-K red balls. The balls of the same color cannot be distinguished. Snuke and Takahashi are playing with these balls.\n\nFirst, Snuke will arrange the N balls in a row from left to right.\n\nThen, Takahashi will collect only the K blue balls. In one move, he can collect any number of consecutive blue balls. He will collect all the blue balls in the fewest moves possible.\n\nHow many ways are there for Snuke to arrange the N balls in a row so that Takahashi will need exactly i moves to collect all the blue balls? Compute this number modulo 10^9+7 for each i such that 1 \\leq i \\leq K.\n\nConstraints\n\n1 \\leq K \\leq N \\leq 2000\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint K lines. The i-th line (1 \\leq i \\leq K) should contain the number of ways to arrange the N balls so that Takahashi will need exactly i moves to collect all the blue balls, modulo 10^9+7.\n\nSample Input 1\n\n5 3\n\nSample Output 1\n\n3\n6\n1\n\nThere are three ways to arrange the balls so that Takahashi will need exactly one move: (B, B, B, R, R), (R, B, B, B, R), and (R, R, B, B, B). (R and B stands for red and blue, respectively).\n\nThere are six ways to arrange the balls so that Takahashi will need exactly two moves: (B, B, R, B, R), (B, B, R, R, B), (R, B, B, R, B), (R, B, R, B, B), (B, R, B, B, R), and (B, R, R, B, B).\n\nThere is one way to arrange the balls so that Takahashi will need exactly three moves: (B, R, B, R, B).\n\nSample Input 2\n\n2000 3\n\nSample Output 2\n\n1998\n3990006\n327341989\n\nBe sure to print the numbers of arrangements modulo 10^9+7.", "sample_input": "5 3\n"}, "reference_outputs": ["3\n6\n1\n"], "source_document_id": "p02990", "source_text": "Score : 400 points\n\nProblem Statement\n\nThere are K blue balls and N-K red balls. The balls of the same color cannot be distinguished. Snuke and Takahashi are playing with these balls.\n\nFirst, Snuke will arrange the N balls in a row from left to right.\n\nThen, Takahashi will collect only the K blue balls. In one move, he can collect any number of consecutive blue balls. He will collect all the blue balls in the fewest moves possible.\n\nHow many ways are there for Snuke to arrange the N balls in a row so that Takahashi will need exactly i moves to collect all the blue balls? Compute this number modulo 10^9+7 for each i such that 1 \\leq i \\leq K.\n\nConstraints\n\n1 \\leq K \\leq N \\leq 2000\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint K lines. The i-th line (1 \\leq i \\leq K) should contain the number of ways to arrange the N balls so that Takahashi will need exactly i moves to collect all the blue balls, modulo 10^9+7.\n\nSample Input 1\n\n5 3\n\nSample Output 1\n\n3\n6\n1\n\nThere are three ways to arrange the balls so that Takahashi will need exactly one move: (B, B, B, R, R), (R, B, B, B, R), and (R, R, B, B, B). (R and B stands for red and blue, respectively).\n\nThere are six ways to arrange the balls so that Takahashi will need exactly two moves: (B, B, R, B, R), (B, B, R, R, B), (R, B, B, R, B), (R, B, R, B, B), (B, R, B, B, R), and (B, R, R, B, B).\n\nThere is one way to arrange the balls so that Takahashi will need exactly three moves: (B, R, B, R, B).\n\nSample Input 2\n\n2000 3\n\nSample Output 2\n\n1998\n3990006\n327341989\n\nBe sure to print the numbers of arrangements modulo 10^9+7.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 664, "cpu_time_ms": 146, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s461400011", "group_id": "codeNet:p02991", "input_text": "#include \"bits/stdc++.h\"\n#define _overload3(_1,_2,_3,name,...) name\n#define _rep(i,n) repi(i,0,n)\n#define repi(i,a,b) for(int i=int(a),i##_len=(b);i<i##_len;++i)\n#define MSVC_UNKO(x) x\n#define rep(...) MSVC_UNKO(_overload3(__VA_ARGS__,repi,_rep,_rep)(__VA_ARGS__))\n#define all(c) c.begin(),c.end()\n#define mp make_pair\n#define write(x) cout<<(x)<<\"\\n\"\nusing namespace std; typedef long long ll; typedef vector<int> vi; typedef vector<ll> vll;\ntemplate<class T>using vv = vector<vector<T>>; template<class T>auto vvec(int n, int m, T v) { return vv<T>(n, vector<T>(m, v)); }\ntemplate<class T>bool chmax(T& a, const T& b) { return a < b ? a = b, 1 : 0; }\ntemplate<class T>bool chmin(T& a, const T& b) { return b < a ? a = b, 1 : 0; }\nconstexpr int INF = 1 << 29, MOD = int(1e9) + 7; constexpr ll LINF = 1LL << 60;\nstruct aaa { aaa() { cin.tie(0); ios::sync_with_stdio(0); cout << fixed << setprecision(10); }; }aaaa;\n\nusing TP = pair<pair<int, int>, int>;\n//using Q = pair<pair<int, int>, TP>;\n\nint N, M;\nvv<int> graph, kkpGraph;\nvector<ll> dist;\n\n//vector<int> in;\nvv<bool> visited;\n\nvoid dfs(int v, TP hist, int d) {\n    //visited[v]++;\n\n    if (/*d % 3 == 0 && */hist.first.first != -1) {\n        kkpGraph[hist.first.first].push_back(v);\n    }\n\n    for (int u : graph[v]) {\n        if (!visited[u][d]) {\n            visited[u][d] = true;\n            dfs(u, TP(mp(hist.first.second, hist.second), v), d + 1);\n        }\n        //if (used[v][u] < 3) {\n        //    used[v][u]++;\n        //    dfs(u, TP(mp(hist.first.second, hist.second), v), d + 1);\n        //}\n    }\n}\n\n//void bfs(int s) {\n//    queue<Q> que;\n//    que.emplace(mp(s, 0), TP({ -1, -1 }, -1));\n//\n//    while (!que.empty()) {\n//        auto q = que.front();\n//        que.pop();\n//        int v = q.first.first;\n//        int d = q.first.second;\n//        auto& hist = q.second;\n//\n//        if (/*d % 3 == 0 && */hist.first.first != -1) {\n//            kkpGraph[hist.first.first].push_back(v);\n//        }\n//\n//        for (int u : graph[v]) {\n//            if (find(all(used[v]), mp(u, d)) == used[v].end()) {\n//                used[v].insert(mp(u, d));\n//                que.emplace(mp(u, (d + 1) % 3), TP(mp(hist.first.second, hist.second), v));\n//            }\n//        }\n//    }\n//}\n\nvoid bfs_kkp(int s) {\n    dist.assign(kkpGraph.size(), LINF);\n    dist[s] = 0;\n    queue<int> que;\n    que.push(s);\n\n    while (!que.empty()) {\n        int v = que.front(); que.pop();\n\n        for (int e : kkpGraph[v]) {\n            if (dist[e] == LINF/*&& other condition*/) {\n                dist[e] = dist[v] + 1;\n                que.push(e);\n            }\n        }\n    }\n}\n\nint main() {\n    cin >> N >> M;\n    graph.resize(N);\n    //in.resize(N);\n    rep(i, M) {\n        int u, v;\n        cin >> u >> v;\n        graph[u - 1].push_back(v - 1);\n        //in[v - 1]++;\n    }\n    int S, T;\n    cin >> S >> T;\n\n    kkpGraph.resize(N);\n    visited = vvec(N, 3, false);\n    //used.resize(N);\n    dfs(S - 1, TP(mp(-1, -1), -1), 0);\n    //bfs(S - 1);\n\n    rep(i, N) {\n        sort(all(kkpGraph[i]));\n        kkpGraph[i].erase(unique(all(kkpGraph[i])), kkpGraph[i].end());\n    }\n\n    bfs_kkp(S - 1);\n    if (dist[T - 1] == LINF) {\n        write(-1);\n    }\n    else {\n        write(dist[T - 1]);\n    }\n}", "language": "C++", "metadata": {"date": 1561864864, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02991.html", "problem_id": "p02991", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02991/input.txt", "sample_output_relpath": "derived/input_output/data/p02991/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02991/C++/s461400011.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s461400011", "user_id": "u751488284"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include \"bits/stdc++.h\"\n#define _overload3(_1,_2,_3,name,...) name\n#define _rep(i,n) repi(i,0,n)\n#define repi(i,a,b) for(int i=int(a),i##_len=(b);i<i##_len;++i)\n#define MSVC_UNKO(x) x\n#define rep(...) MSVC_UNKO(_overload3(__VA_ARGS__,repi,_rep,_rep)(__VA_ARGS__))\n#define all(c) c.begin(),c.end()\n#define mp make_pair\n#define write(x) cout<<(x)<<\"\\n\"\nusing namespace std; typedef long long ll; typedef vector<int> vi; typedef vector<ll> vll;\ntemplate<class T>using vv = vector<vector<T>>; template<class T>auto vvec(int n, int m, T v) { return vv<T>(n, vector<T>(m, v)); }\ntemplate<class T>bool chmax(T& a, const T& b) { return a < b ? a = b, 1 : 0; }\ntemplate<class T>bool chmin(T& a, const T& b) { return b < a ? a = b, 1 : 0; }\nconstexpr int INF = 1 << 29, MOD = int(1e9) + 7; constexpr ll LINF = 1LL << 60;\nstruct aaa { aaa() { cin.tie(0); ios::sync_with_stdio(0); cout << fixed << setprecision(10); }; }aaaa;\n\nusing TP = pair<pair<int, int>, int>;\n//using Q = pair<pair<int, int>, TP>;\n\nint N, M;\nvv<int> graph, kkpGraph;\nvector<ll> dist;\n\n//vector<int> in;\nvv<bool> visited;\n\nvoid dfs(int v, TP hist, int d) {\n    //visited[v]++;\n\n    if (/*d % 3 == 0 && */hist.first.first != -1) {\n        kkpGraph[hist.first.first].push_back(v);\n    }\n\n    for (int u : graph[v]) {\n        if (!visited[u][d]) {\n            visited[u][d] = true;\n            dfs(u, TP(mp(hist.first.second, hist.second), v), d + 1);\n        }\n        //if (used[v][u] < 3) {\n        //    used[v][u]++;\n        //    dfs(u, TP(mp(hist.first.second, hist.second), v), d + 1);\n        //}\n    }\n}\n\n//void bfs(int s) {\n//    queue<Q> que;\n//    que.emplace(mp(s, 0), TP({ -1, -1 }, -1));\n//\n//    while (!que.empty()) {\n//        auto q = que.front();\n//        que.pop();\n//        int v = q.first.first;\n//        int d = q.first.second;\n//        auto& hist = q.second;\n//\n//        if (/*d % 3 == 0 && */hist.first.first != -1) {\n//            kkpGraph[hist.first.first].push_back(v);\n//        }\n//\n//        for (int u : graph[v]) {\n//            if (find(all(used[v]), mp(u, d)) == used[v].end()) {\n//                used[v].insert(mp(u, d));\n//                que.emplace(mp(u, (d + 1) % 3), TP(mp(hist.first.second, hist.second), v));\n//            }\n//        }\n//    }\n//}\n\nvoid bfs_kkp(int s) {\n    dist.assign(kkpGraph.size(), LINF);\n    dist[s] = 0;\n    queue<int> que;\n    que.push(s);\n\n    while (!que.empty()) {\n        int v = que.front(); que.pop();\n\n        for (int e : kkpGraph[v]) {\n            if (dist[e] == LINF/*&& other condition*/) {\n                dist[e] = dist[v] + 1;\n                que.push(e);\n            }\n        }\n    }\n}\n\nint main() {\n    cin >> N >> M;\n    graph.resize(N);\n    //in.resize(N);\n    rep(i, M) {\n        int u, v;\n        cin >> u >> v;\n        graph[u - 1].push_back(v - 1);\n        //in[v - 1]++;\n    }\n    int S, T;\n    cin >> S >> T;\n\n    kkpGraph.resize(N);\n    visited = vvec(N, 3, false);\n    //used.resize(N);\n    dfs(S - 1, TP(mp(-1, -1), -1), 0);\n    //bfs(S - 1);\n\n    rep(i, N) {\n        sort(all(kkpGraph[i]));\n        kkpGraph[i].erase(unique(all(kkpGraph[i])), kkpGraph[i].end());\n    }\n\n    bfs_kkp(S - 1);\n    if (dist[T - 1] == LINF) {\n        write(-1);\n    }\n    else {\n        write(dist[T - 1]);\n    }\n}", "problem_context": "Score : 500 points\n\nProblem Statement\n\nKen loves ken-ken-pa (Japanese version of hopscotch). Today, he will play it on a directed graph G.\nG consists of N vertices numbered 1 to N, and M edges. The i-th edge points from Vertex u_i to Vertex v_i.\n\nFirst, Ken stands on Vertex S. He wants to reach Vertex T by repeating ken-ken-pa. In one ken-ken-pa, he does the following exactly three times: follow an edge pointing from the vertex on which he is standing.\n\nDetermine if he can reach Vertex T by repeating ken-ken-pa. If the answer is yes, find the minimum number of ken-ken-pa needed to reach Vertex T. Note that visiting Vertex T in the middle of a ken-ken-pa does not count as reaching Vertex T by repeating ken-ken-pa.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n0 \\leq M \\leq \\min(10^5, N (N-1))\n\n1 \\leq u_i, v_i \\leq N(1 \\leq i \\leq M)\n\nu_i \\neq v_i (1 \\leq i \\leq M)\n\nIf i \\neq j, (u_i, v_i) \\neq (u_j, v_j).\n\n1 \\leq S, T \\leq N\n\nS \\neq T\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nu_1 v_1\n:\nu_M v_M\nS T\n\nOutput\n\nIf Ken cannot reach Vertex T from Vertex S by repeating ken-ken-pa, print -1.\nIf he can, print the minimum number of ken-ken-pa needed to reach vertex T.\n\nSample Input 1\n\n4 4\n1 2\n2 3\n3 4\n4 1\n1 3\n\nSample Output 1\n\n2\n\nKen can reach Vertex 3 from Vertex 1 in two ken-ken-pa, as follows: 1 \\rightarrow 2 \\rightarrow 3 \\rightarrow 4 in the first ken-ken-pa, then 4 \\rightarrow 1 \\rightarrow 2 \\rightarrow 3 in the second ken-ken-pa. This is the minimum number of ken-ken-pa needed.\n\nSample Input 2\n\n3 3\n1 2\n2 3\n3 1\n1 2\n\nSample Output 2\n\n-1\n\nAny number of ken-ken-pa will bring Ken back to Vertex 1, so he cannot reach Vertex 2, though he can pass through it in the middle of a ken-ken-pa.\n\nSample Input 3\n\n2 0\n1 2\n\nSample Output 3\n\n-1\n\nVertex S and Vertex T may be disconnected.\n\nSample Input 4\n\n6 8\n1 2\n2 3\n3 4\n4 5\n5 1\n1 4\n1 5\n4 6\n1 6\n\nSample Output 4\n\n2", "sample_input": "4 4\n1 2\n2 3\n3 4\n4 1\n1 3\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02991", "source_text": "Score : 500 points\n\nProblem Statement\n\nKen loves ken-ken-pa (Japanese version of hopscotch). Today, he will play it on a directed graph G.\nG consists of N vertices numbered 1 to N, and M edges. The i-th edge points from Vertex u_i to Vertex v_i.\n\nFirst, Ken stands on Vertex S. He wants to reach Vertex T by repeating ken-ken-pa. In one ken-ken-pa, he does the following exactly three times: follow an edge pointing from the vertex on which he is standing.\n\nDetermine if he can reach Vertex T by repeating ken-ken-pa. If the answer is yes, find the minimum number of ken-ken-pa needed to reach Vertex T. Note that visiting Vertex T in the middle of a ken-ken-pa does not count as reaching Vertex T by repeating ken-ken-pa.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n0 \\leq M \\leq \\min(10^5, N (N-1))\n\n1 \\leq u_i, v_i \\leq N(1 \\leq i \\leq M)\n\nu_i \\neq v_i (1 \\leq i \\leq M)\n\nIf i \\neq j, (u_i, v_i) \\neq (u_j, v_j).\n\n1 \\leq S, T \\leq N\n\nS \\neq T\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nu_1 v_1\n:\nu_M v_M\nS T\n\nOutput\n\nIf Ken cannot reach Vertex T from Vertex S by repeating ken-ken-pa, print -1.\nIf he can, print the minimum number of ken-ken-pa needed to reach vertex T.\n\nSample Input 1\n\n4 4\n1 2\n2 3\n3 4\n4 1\n1 3\n\nSample Output 1\n\n2\n\nKen can reach Vertex 3 from Vertex 1 in two ken-ken-pa, as follows: 1 \\rightarrow 2 \\rightarrow 3 \\rightarrow 4 in the first ken-ken-pa, then 4 \\rightarrow 1 \\rightarrow 2 \\rightarrow 3 in the second ken-ken-pa. This is the minimum number of ken-ken-pa needed.\n\nSample Input 2\n\n3 3\n1 2\n2 3\n3 1\n1 2\n\nSample Output 2\n\n-1\n\nAny number of ken-ken-pa will bring Ken back to Vertex 1, so he cannot reach Vertex 2, though he can pass through it in the middle of a ken-ken-pa.\n\nSample Input 3\n\n2 0\n1 2\n\nSample Output 3\n\n-1\n\nVertex S and Vertex T may be disconnected.\n\nSample Input 4\n\n6 8\n1 2\n2 3\n3 4\n4 5\n5 1\n1 4\n1 5\n4 6\n1 6\n\nSample Output 4\n\n2", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 3255, "cpu_time_ms": 1228, "memory_kb": 50816}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s744440428", "group_id": "codeNet:p02993", "input_text": "#include<iostream>\n#include<string>\n#include<sstream>\nusing namespace std;\n\nint main(){\n\tstring num;\n\twhile(getline(cin,num)){\n\t\tint x,a,b;\n\t\tstringstream ss;\n\t\tss<<num;\n\t\tss>>x;\n\t\twhile(ss>>x){\n\t\t\ta=x/1000;\n\t\t\tb=(x%1000)/100;\n\t\t\tif(a==b){\n\t\t\t\tcout<<\"Bad\"<<\"\\n\";\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\telse{\n\t\t\t\ta=(x%100)/10;\n\t\t\t\tif(b==a){\n\t\t\t\t\tcout<<\"Bad\"<<\"\\n\";\n\t\t\t\t\tbreak;\n\t\t\t\t} \n\t\t\t\telse{\n\t\t\t\t\tb=x%10;\n\t\t\t\t\tif(a==b){\n\t\t\t\t\t\tcout<<\"Bad\"<<\"\\n\";\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t} \n\t\t\t\t\telse{\n\t\t\t\t\t\tcout<<\"Good\"<<\"\\n\";\n\t\t\t\t\t\tcontinue;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\treturn 0;\t\t\n}", "language": "C++", "metadata": {"date": 1561759291, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02993.html", "problem_id": "p02993", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02993/input.txt", "sample_output_relpath": "derived/input_output/data/p02993/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02993/C++/s744440428.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s744440428", "user_id": "u564278825"}, "prompt_components": {"gold_output": "Bad\n", "input_to_evaluate": "#include<iostream>\n#include<string>\n#include<sstream>\nusing namespace std;\n\nint main(){\n\tstring num;\n\twhile(getline(cin,num)){\n\t\tint x,a,b;\n\t\tstringstream ss;\n\t\tss<<num;\n\t\tss>>x;\n\t\twhile(ss>>x){\n\t\t\ta=x/1000;\n\t\t\tb=(x%1000)/100;\n\t\t\tif(a==b){\n\t\t\t\tcout<<\"Bad\"<<\"\\n\";\n\t\t\t\tbreak;\n\t\t\t}\n\t\t\telse{\n\t\t\t\ta=(x%100)/10;\n\t\t\t\tif(b==a){\n\t\t\t\t\tcout<<\"Bad\"<<\"\\n\";\n\t\t\t\t\tbreak;\n\t\t\t\t} \n\t\t\t\telse{\n\t\t\t\t\tb=x%10;\n\t\t\t\t\tif(a==b){\n\t\t\t\t\t\tcout<<\"Bad\"<<\"\\n\";\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t} \n\t\t\t\t\telse{\n\t\t\t\t\t\tcout<<\"Good\"<<\"\\n\";\n\t\t\t\t\t\tcontinue;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\treturn 0;\t\t\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nThe door of Snuke's laboratory is locked with a security code.\n\nThe security code is a 4-digit number. We say the security code is hard to enter when it contains two consecutive digits that are the same.\n\nYou are given the current security code S. If S is hard to enter, print Bad; otherwise, print Good.\n\nConstraints\n\nS is a 4-character string consisting of digits.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nIf S is hard to enter, print Bad; otherwise, print Good.\n\nSample Input 1\n\n3776\n\nSample Output 1\n\nBad\n\nThe second and third digits are the same, so 3776 is hard to enter.\n\nSample Input 2\n\n8080\n\nSample Output 2\n\nGood\n\nThere are no two consecutive digits that are the same, so 8080 is not hard to enter.\n\nSample Input 3\n\n1333\n\nSample Output 3\n\nBad\n\nSample Input 4\n\n0024\n\nSample Output 4\n\nBad", "sample_input": "3776\n"}, "reference_outputs": ["Bad\n"], "source_document_id": "p02993", "source_text": "Score : 100 points\n\nProblem Statement\n\nThe door of Snuke's laboratory is locked with a security code.\n\nThe security code is a 4-digit number. We say the security code is hard to enter when it contains two consecutive digits that are the same.\n\nYou are given the current security code S. If S is hard to enter, print Bad; otherwise, print Good.\n\nConstraints\n\nS is a 4-character string consisting of digits.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nIf S is hard to enter, print Bad; otherwise, print Good.\n\nSample Input 1\n\n3776\n\nSample Output 1\n\nBad\n\nThe second and third digits are the same, so 3776 is hard to enter.\n\nSample Input 2\n\n8080\n\nSample Output 2\n\nGood\n\nThere are no two consecutive digits that are the same, so 8080 is not hard to enter.\n\nSample Input 3\n\n1333\n\nSample Output 3\n\nBad\n\nSample Input 4\n\n0024\n\nSample Output 4\n\nBad", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 539, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s258376852", "group_id": "codeNet:p02994", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n    int n,l;\n    cin>>n>>l;\n    int sum=0;\n    int pie[n+1];\n    int m1,m2;\n    for(int i=1;i<=n;i++){\n        pie[i]=l+i-1;\n        sum+=pie[i];\n    }\n    for(int i=1;i<=n;i++){\n        if(i==1){\n            m2=sum-pie[i];\n            m1=abs(pie[i]);\n            //cout<<m2<<endl;\n        }\n        else{\n            if(abs(pie[i])<m1){\n            m2=sum-pie[i];\n            m1=abs(pie[i]);\n           // cout<<m2<<endl;\n            }\n        }\n    }\n    cout<<m2<<endl;\n}", "language": "C++", "metadata": {"date": 1569546786, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02994.html", "problem_id": "p02994", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02994/input.txt", "sample_output_relpath": "derived/input_output/data/p02994/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02994/C++/s258376852.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s258376852", "user_id": "u095376747"}, "prompt_components": {"gold_output": "18\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n    int n,l;\n    cin>>n>>l;\n    int sum=0;\n    int pie[n+1];\n    int m1,m2;\n    for(int i=1;i<=n;i++){\n        pie[i]=l+i-1;\n        sum+=pie[i];\n    }\n    for(int i=1;i<=n;i++){\n        if(i==1){\n            m2=sum-pie[i];\n            m1=abs(pie[i]);\n            //cout<<m2<<endl;\n        }\n        else{\n            if(abs(pie[i])<m1){\n            m2=sum-pie[i];\n            m1=abs(pie[i]);\n           // cout<<m2<<endl;\n            }\n        }\n    }\n    cout<<m2<<endl;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nYou have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The flavor of Apple i is L+i-1, which can be negative.\n\nYou can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.\n\nYou planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.\n\nYou want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.\n\nFind the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.\n\nWe can prove that this value is uniquely determined.\n\nConstraints\n\n2 \\leq N \\leq 200\n\n-100 \\leq L \\leq 100\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN L\n\nOutput\n\nFind the flavor of the apple pie made of the remaining N-1 apples when you optimally choose the apple to eat.\n\nSample Input 1\n\n5 2\n\nSample Output 1\n\n18\n\nThe flavors of Apple 1, 2, 3, 4, and 5 are 2, 3, 4, 5, and 6, respectively. The optimal choice is to eat Apple 1, so the answer is 3+4+5+6=18.\n\nSample Input 2\n\n3 -1\n\nSample Output 2\n\n0\n\nThe flavors of Apple 1, 2, and 3 are -1, 0, and 1, respectively. The optimal choice is to eat Apple 2, so the answer is (-1)+1=0.\n\nSample Input 3\n\n30 -50\n\nSample Output 3\n\n-1044", "sample_input": "5 2\n"}, "reference_outputs": ["18\n"], "source_document_id": "p02994", "source_text": "Score : 200 points\n\nProblem Statement\n\nYou have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The flavor of Apple i is L+i-1, which can be negative.\n\nYou can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.\n\nYou planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.\n\nYou want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.\n\nFind the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.\n\nWe can prove that this value is uniquely determined.\n\nConstraints\n\n2 \\leq N \\leq 200\n\n-100 \\leq L \\leq 100\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN L\n\nOutput\n\nFind the flavor of the apple pie made of the remaining N-1 apples when you optimally choose the apple to eat.\n\nSample Input 1\n\n5 2\n\nSample Output 1\n\n18\n\nThe flavors of Apple 1, 2, 3, 4, and 5 are 2, 3, 4, 5, and 6, respectively. The optimal choice is to eat Apple 1, so the answer is 3+4+5+6=18.\n\nSample Input 2\n\n3 -1\n\nSample Output 2\n\n0\n\nThe flavors of Apple 1, 2, and 3 are -1, 0, and 1, respectively. The optimal choice is to eat Apple 2, so the answer is (-1)+1=0.\n\nSample Input 3\n\n30 -50\n\nSample Output 3\n\n-1044", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 532, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s140743261", "group_id": "codeNet:p02994", "input_text": "#include <iostream>\nusing namespace std;\nint main()\n{\n    int n, l, s, m;\n    cin >> n;\n    cin >> l;\n    s = l+1;\n    m = l+n;\n    if(l>0){\n        for(int i=0;i<=n;i++){\n        l= l +1;\n        }\n        cout << l-s<< '\\n';\n\n    }\n    if(l<0){\n    if(l-n>0){\n        for(int i=0;i<=n;i++){\n        l= l + 1;\n        }\n        cout << l << '\\n';\n\n    }\n    if(l-n>0){\n        for(int i=0;i<n;i++){\n        l= l + 1;\n        }\n        cout << l-m << '\\n';\n    }\n    }\n    return 0;\n}", "language": "C++", "metadata": {"date": 1561254915, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02994.html", "problem_id": "p02994", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02994/input.txt", "sample_output_relpath": "derived/input_output/data/p02994/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02994/C++/s140743261.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s140743261", "user_id": "u927933718"}, "prompt_components": {"gold_output": "18\n", "input_to_evaluate": "#include <iostream>\nusing namespace std;\nint main()\n{\n    int n, l, s, m;\n    cin >> n;\n    cin >> l;\n    s = l+1;\n    m = l+n;\n    if(l>0){\n        for(int i=0;i<=n;i++){\n        l= l +1;\n        }\n        cout << l-s<< '\\n';\n\n    }\n    if(l<0){\n    if(l-n>0){\n        for(int i=0;i<=n;i++){\n        l= l + 1;\n        }\n        cout << l << '\\n';\n\n    }\n    if(l-n>0){\n        for(int i=0;i<n;i++){\n        l= l + 1;\n        }\n        cout << l-m << '\\n';\n    }\n    }\n    return 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nYou have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The flavor of Apple i is L+i-1, which can be negative.\n\nYou can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.\n\nYou planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.\n\nYou want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.\n\nFind the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.\n\nWe can prove that this value is uniquely determined.\n\nConstraints\n\n2 \\leq N \\leq 200\n\n-100 \\leq L \\leq 100\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN L\n\nOutput\n\nFind the flavor of the apple pie made of the remaining N-1 apples when you optimally choose the apple to eat.\n\nSample Input 1\n\n5 2\n\nSample Output 1\n\n18\n\nThe flavors of Apple 1, 2, 3, 4, and 5 are 2, 3, 4, 5, and 6, respectively. The optimal choice is to eat Apple 1, so the answer is 3+4+5+6=18.\n\nSample Input 2\n\n3 -1\n\nSample Output 2\n\n0\n\nThe flavors of Apple 1, 2, and 3 are -1, 0, and 1, respectively. The optimal choice is to eat Apple 2, so the answer is (-1)+1=0.\n\nSample Input 3\n\n30 -50\n\nSample Output 3\n\n-1044", "sample_input": "5 2\n"}, "reference_outputs": ["18\n"], "source_document_id": "p02994", "source_text": "Score : 200 points\n\nProblem Statement\n\nYou have N apples, called Apple 1, Apple 2, Apple 3, ..., Apple N. The flavor of Apple i is L+i-1, which can be negative.\n\nYou can make an apple pie using one or more of the apples. The flavor of the apple pie will be the sum of the flavors of the apples used.\n\nYou planned to make an apple pie using all of the apples, but being hungry tempts you to eat one of them, which can no longer be used to make the apple pie.\n\nYou want to make an apple pie that is as similar as possible to the one that you planned to make. Thus, you will choose the apple to eat so that the flavor of the apple pie made of the remaining N-1 apples will have the smallest possible absolute difference from the flavor of the apple pie made of all the N apples.\n\nFind the flavor of the apple pie made of the remaining N-1 apples when you choose the apple to eat as above.\n\nWe can prove that this value is uniquely determined.\n\nConstraints\n\n2 \\leq N \\leq 200\n\n-100 \\leq L \\leq 100\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN L\n\nOutput\n\nFind the flavor of the apple pie made of the remaining N-1 apples when you optimally choose the apple to eat.\n\nSample Input 1\n\n5 2\n\nSample Output 1\n\n18\n\nThe flavors of Apple 1, 2, 3, 4, and 5 are 2, 3, 4, 5, and 6, respectively. The optimal choice is to eat Apple 1, so the answer is 3+4+5+6=18.\n\nSample Input 2\n\n3 -1\n\nSample Output 2\n\n0\n\nThe flavors of Apple 1, 2, and 3 are -1, 0, and 1, respectively. The optimal choice is to eat Apple 2, so the answer is (-1)+1=0.\n\nSample Input 3\n\n30 -50\n\nSample Output 3\n\n-1044", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 484, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s331740612", "group_id": "codeNet:p02995", "input_text": "#include \"bits/stdc++.h\"\n\nusing namespace std;\n\nlong a, b, c, d;\n\nlong f(long x)\n{\n\treturn (x - x/c - x/d + x/(c*d/__gcd(c,d)));\n}\n\nvoid solve(void)\n{\n\tcin >> a >> b >> c >> d;\n\tcout << f(b) - f(a-1) << endl;\n}\n\nint main()\n{\n\tsolve();\n\t//cout << \"yui(*-v・)yui\" << endl;\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1561236477, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02995.html", "problem_id": "p02995", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02995/input.txt", "sample_output_relpath": "derived/input_output/data/p02995/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02995/C++/s331740612.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s331740612", "user_id": "u344412812"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include \"bits/stdc++.h\"\n\nusing namespace std;\n\nlong a, b, c, d;\n\nlong f(long x)\n{\n\treturn (x - x/c - x/d + x/(c*d/__gcd(c,d)));\n}\n\nvoid solve(void)\n{\n\tcin >> a >> b >> c >> d;\n\tcout << f(b) - f(a-1) << endl;\n}\n\nint main()\n{\n\tsolve();\n\t//cout << \"yui(*-v・)yui\" << endl;\n\treturn 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nYou are given four integers A, B, C, and D. Find the number of integers between A and B (inclusive) that can be evenly divided by neither C nor D.\n\nConstraints\n\n1\\leq A\\leq B\\leq 10^{18}\n\n1\\leq C,D\\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B C D\n\nOutput\n\nPrint the number of integers between A and B (inclusive) that can be evenly divided by neither C nor D.\n\nSample Input 1\n\n4 9 2 3\n\nSample Output 1\n\n2\n\n5 and 7 satisfy the condition.\n\nSample Input 2\n\n10 40 6 8\n\nSample Output 2\n\n23\n\nSample Input 3\n\n314159265358979323 846264338327950288 419716939 937510582\n\nSample Output 3\n\n532105071133627368", "sample_input": "4 9 2 3\n"}, "reference_outputs": ["2\n"], "source_document_id": "p02995", "source_text": "Score : 300 points\n\nProblem Statement\n\nYou are given four integers A, B, C, and D. Find the number of integers between A and B (inclusive) that can be evenly divided by neither C nor D.\n\nConstraints\n\n1\\leq A\\leq B\\leq 10^{18}\n\n1\\leq C,D\\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B C D\n\nOutput\n\nPrint the number of integers between A and B (inclusive) that can be evenly divided by neither C nor D.\n\nSample Input 1\n\n4 9 2 3\n\nSample Output 1\n\n2\n\n5 and 7 satisfy the condition.\n\nSample Input 2\n\n10 40 6 8\n\nSample Output 2\n\n23\n\nSample Input 3\n\n314159265358979323 846264338327950288 419716939 937510582\n\nSample Output 3\n\n532105071133627368", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 285, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s452868023", "group_id": "codeNet:p02997", "input_text": "#include <bits/stdc++.h>\n#define _ ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);\n#define int long long\n#define pb insert\n#define sz(i) (int)(i.size())\n#define F first\n#define S second\n#define L long double\n#define P pair<int, int>\nconst int inf = 0x3f3f3f3f3f3f3f3LL;\nconst int mod = (int)1e9 + 7;\nusing namespace std;\n#if LOCAL\n#include \"../../tr.h\"\n#else\n#define tr(...)\n#define endl '\\n'\n#endif\ntemplate<class T> void smin(T& a, T val) {if (a > val) a = val;}template<class T> void smax(T& a, T val) {if (a < val) a = val;}\nconst int N = 5*(int)1e5 + 10;\n\nint n, k;\nset<P> v;\n\nint32_t main(){_\n\n   cin>>n>>k;\n\n   int ma = (n-2) * (n-1) / 2;\n   \n   if (k <= 0){\n      cout<<-1;\n      exit(0);\n   }\n\n   if (k > ma){\n      cout<<-1;\n      exit(0);\n   }\n\n   int vals = 0;\n   for (int adj = 1; adj <= n; ++adj)\n   {\n      int tot = adj - 1;\n      tot = tot * (tot+1);\n      tot >>= 1;\n      if(tot <= k){\n         vals = adj;\n      }\n      else{\n         break;\n      }\n   }\n\n   int adj = vals;\n\n   for (int i = 1; i <= adj; ++i)\n   {\n      v.pb({1, i+1});\n   }\n\n   k -= ((adj * (adj - 1)) / 2);\n\n   adj+=2;\n   int lst = adj;\n   tr(adj, k, v);\n   for (int i = adj; i <= n; ++i)\n   {\n      int poss = adj-2;\n      if(k > 0 and k - poss < 0){\n         v.pb({i, 1});\n         int rem = k;\n         k = 0;\n         for (int j = 2; j <= adj-rem-1; ++j)\n         {\n            v.pb({i, j});            \n         }\n         lst = adj+1;\n         break;\n      }\n   }\n\n   tr(lst, k);\n\n   for (int i = lst; i <= n; ++i)\n   {\n      for (int j = 1; j <= i-1; ++j)\n      {\n         v.pb({i, j});\n      }\n   }\n\n   if(k > 0){\n      assert(0);\n      cout<<-1;\n      exit(0);\n   }\n\n   cout<<sz(v)<<endl;\n   for(auto it: v)\n      cout<<it.F<<' '<<it.S<<endl;\n\n\n   return 0;\n}", "language": "C++", "metadata": {"date": 1561235633, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02997.html", "problem_id": "p02997", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02997/input.txt", "sample_output_relpath": "derived/input_output/data/p02997/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02997/C++/s452868023.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s452868023", "user_id": "u063043074"}, "prompt_components": {"gold_output": "5\n4 3\n1 2\n3 1\n4 5\n2 3\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define _ ios_base::sync_with_stdio(false);cin.tie(NULL);cout.tie(NULL);\n#define int long long\n#define pb insert\n#define sz(i) (int)(i.size())\n#define F first\n#define S second\n#define L long double\n#define P pair<int, int>\nconst int inf = 0x3f3f3f3f3f3f3f3LL;\nconst int mod = (int)1e9 + 7;\nusing namespace std;\n#if LOCAL\n#include \"../../tr.h\"\n#else\n#define tr(...)\n#define endl '\\n'\n#endif\ntemplate<class T> void smin(T& a, T val) {if (a > val) a = val;}template<class T> void smax(T& a, T val) {if (a < val) a = val;}\nconst int N = 5*(int)1e5 + 10;\n\nint n, k;\nset<P> v;\n\nint32_t main(){_\n\n   cin>>n>>k;\n\n   int ma = (n-2) * (n-1) / 2;\n   \n   if (k <= 0){\n      cout<<-1;\n      exit(0);\n   }\n\n   if (k > ma){\n      cout<<-1;\n      exit(0);\n   }\n\n   int vals = 0;\n   for (int adj = 1; adj <= n; ++adj)\n   {\n      int tot = adj - 1;\n      tot = tot * (tot+1);\n      tot >>= 1;\n      if(tot <= k){\n         vals = adj;\n      }\n      else{\n         break;\n      }\n   }\n\n   int adj = vals;\n\n   for (int i = 1; i <= adj; ++i)\n   {\n      v.pb({1, i+1});\n   }\n\n   k -= ((adj * (adj - 1)) / 2);\n\n   adj+=2;\n   int lst = adj;\n   tr(adj, k, v);\n   for (int i = adj; i <= n; ++i)\n   {\n      int poss = adj-2;\n      if(k > 0 and k - poss < 0){\n         v.pb({i, 1});\n         int rem = k;\n         k = 0;\n         for (int j = 2; j <= adj-rem-1; ++j)\n         {\n            v.pb({i, j});            \n         }\n         lst = adj+1;\n         break;\n      }\n   }\n\n   tr(lst, k);\n\n   for (int i = lst; i <= n; ++i)\n   {\n      for (int j = 1; j <= i-1; ++j)\n      {\n         v.pb({i, j});\n      }\n   }\n\n   if(k > 0){\n      assert(0);\n      cout<<-1;\n      exit(0);\n   }\n\n   cout<<sz(v)<<endl;\n   for(auto it: v)\n      cout<<it.F<<' '<<it.S<<endl;\n\n\n   return 0;\n}", "problem_context": "Score: 500 points\n\nProblem Statement\n\nDoes there exist an undirected graph with N vertices satisfying the following conditions?\n\nThe graph is simple and connected.\n\nThe vertices are numbered 1, 2, ..., N.\n\nLet M be the number of edges in the graph. The edges are numbered 1, 2, ..., M, the length of each edge is 1, and Edge i connects Vertex u_i and Vertex v_i.\n\nThere are exactly K pairs of vertices (i,\\ j)\\ (i < j) such that the shortest distance between them is 2.\n\nIf there exists such a graph, construct an example.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 100\n\n0 \\leq K \\leq \\frac{N(N - 1)}{2}\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nIf there does not exist an undirected graph with N vertices satisfying the conditions, print -1.\n\nIf there exists such a graph, print an example in the following format (refer to Problem Statement for what the symbols stand for):\n\nM\nu_1 v_1\n:\nu_M v_M\n\nIf there exist multiple graphs satisfying the conditions, any of them will be accepted.\n\nSample Input 1\n\n5 3\n\nSample Output 1\n\n5\n4 3\n1 2\n3 1\n4 5\n2 3\n\nThis graph has three pairs of vertices such that the shortest distance between them is 2: (1,\\ 4), (2,\\ 4), and (3,\\ 5). Thus, the condition is satisfied.\n\nSample Input 2\n\n5 8\n\nSample Output 2\n\n-1\n\nThere is no graph satisfying the conditions.", "sample_input": "5 3\n"}, "reference_outputs": ["5\n4 3\n1 2\n3 1\n4 5\n2 3\n"], "source_document_id": "p02997", "source_text": "Score: 500 points\n\nProblem Statement\n\nDoes there exist an undirected graph with N vertices satisfying the following conditions?\n\nThe graph is simple and connected.\n\nThe vertices are numbered 1, 2, ..., N.\n\nLet M be the number of edges in the graph. The edges are numbered 1, 2, ..., M, the length of each edge is 1, and Edge i connects Vertex u_i and Vertex v_i.\n\nThere are exactly K pairs of vertices (i,\\ j)\\ (i < j) such that the shortest distance between them is 2.\n\nIf there exists such a graph, construct an example.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 100\n\n0 \\leq K \\leq \\frac{N(N - 1)}{2}\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nIf there does not exist an undirected graph with N vertices satisfying the conditions, print -1.\n\nIf there exists such a graph, print an example in the following format (refer to Problem Statement for what the symbols stand for):\n\nM\nu_1 v_1\n:\nu_M v_M\n\nIf there exist multiple graphs satisfying the conditions, any of them will be accepted.\n\nSample Input 1\n\n5 3\n\nSample Output 1\n\n5\n4 3\n1 2\n3 1\n4 5\n2 3\n\nThis graph has three pairs of vertices such that the shortest distance between them is 2: (1,\\ 4), (2,\\ 4), and (3,\\ 5). Thus, the condition is satisfied.\n\nSample Input 2\n\n5 8\n\nSample Output 2\n\n-1\n\nThere is no graph satisfying the conditions.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1772, "cpu_time_ms": 3, "memory_kb": 640}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s905157501", "group_id": "codeNet:p02999", "input_text": "#include \"bits/stdc++.h\"\n \nusing namespace std;\n \nint X, A;\n \nint main() {\n\tcin >> X >> A;\n\tif (X < A) cout << 0;\n\telse cout << 10;\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1561996841, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02999.html", "problem_id": "p02999", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02999/input.txt", "sample_output_relpath": "derived/input_output/data/p02999/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02999/C++/s905157501.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s905157501", "user_id": "u074003648"}, "prompt_components": {"gold_output": "0\n", "input_to_evaluate": "#include \"bits/stdc++.h\"\n \nusing namespace std;\n \nint X, A;\n \nint main() {\n\tcin >> X >> A;\n\tif (X < A) cout << 0;\n\telse cout << 10;\n\treturn 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nX and A are integers between 0 and 9 (inclusive).\n\nIf X is less than A, print 0; if X is not less than A, print 10.\n\nConstraints\n\n0 \\leq X, A \\leq 9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX A\n\nOutput\n\nIf X is less than A, print 0; if X is not less than A, print 10.\n\nSample Input 1\n\n3 5\n\nSample Output 1\n\n0\n\n3 is less than 5, so we should print 0.\n\nSample Input 2\n\n7 5\n\nSample Output 2\n\n10\n\n7 is not less than 5, so we should print 10.\n\nSample Input 3\n\n6 6\n\nSample Output 3\n\n10\n\n6 is not less than 6, so we should print 10.", "sample_input": "3 5\n"}, "reference_outputs": ["0\n"], "source_document_id": "p02999", "source_text": "Score : 100 points\n\nProblem Statement\n\nX and A are integers between 0 and 9 (inclusive).\n\nIf X is less than A, print 0; if X is not less than A, print 10.\n\nConstraints\n\n0 \\leq X, A \\leq 9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX A\n\nOutput\n\nIf X is less than A, print 0; if X is not less than A, print 10.\n\nSample Input 1\n\n3 5\n\nSample Output 1\n\n0\n\n3 is less than 5, so we should print 0.\n\nSample Input 2\n\n7 5\n\nSample Output 2\n\n10\n\n7 is not less than 5, so we should print 10.\n\nSample Input 3\n\n6 6\n\nSample Output 3\n\n10\n\n6 is not less than 6, so we should print 10.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 144, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s829193727", "group_id": "codeNet:p02999", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n \nint main() {\n  int X, A;\n  cin >> X >> A;\n  cout << (X < A ? 0 : 10);\n}", "language": "C++", "metadata": {"date": 1560725240, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p02999.html", "problem_id": "p02999", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p02999/input.txt", "sample_output_relpath": "derived/input_output/data/p02999/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p02999/C++/s829193727.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s829193727", "user_id": "u261514692"}, "prompt_components": {"gold_output": "0\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n \nint main() {\n  int X, A;\n  cin >> X >> A;\n  cout << (X < A ? 0 : 10);\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nX and A are integers between 0 and 9 (inclusive).\n\nIf X is less than A, print 0; if X is not less than A, print 10.\n\nConstraints\n\n0 \\leq X, A \\leq 9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX A\n\nOutput\n\nIf X is less than A, print 0; if X is not less than A, print 10.\n\nSample Input 1\n\n3 5\n\nSample Output 1\n\n0\n\n3 is less than 5, so we should print 0.\n\nSample Input 2\n\n7 5\n\nSample Output 2\n\n10\n\n7 is not less than 5, so we should print 10.\n\nSample Input 3\n\n6 6\n\nSample Output 3\n\n10\n\n6 is not less than 6, so we should print 10.", "sample_input": "3 5\n"}, "reference_outputs": ["0\n"], "source_document_id": "p02999", "source_text": "Score : 100 points\n\nProblem Statement\n\nX and A are integers between 0 and 9 (inclusive).\n\nIf X is less than A, print 0; if X is not less than A, print 10.\n\nConstraints\n\n0 \\leq X, A \\leq 9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX A\n\nOutput\n\nIf X is less than A, print 0; if X is not less than A, print 10.\n\nSample Input 1\n\n3 5\n\nSample Output 1\n\n0\n\n3 is less than 5, so we should print 0.\n\nSample Input 2\n\n7 5\n\nSample Output 2\n\n10\n\n7 is not less than 5, so we should print 10.\n\nSample Input 3\n\n6 6\n\nSample Output 3\n\n10\n\n6 is not less than 6, so we should print 10.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 119, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s275098334", "group_id": "codeNet:p03000", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  int N, X;\n  cin >> N >> X;\n  int L[N];\n  int D[N]={0};\n  for(int i=0; i<N; i++){\n    cin >> L[i];\n  }\n  \n  for(int j=1; j<N+1; j++){\n    D[j] = D[j-1] + L[j-1];\n    if(D[j] > X){\n      cout << j;\n      return 0;\n    }\n  }\n  \n  return 0;\n}", "language": "C++", "metadata": {"date": 1570805690, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03000.html", "problem_id": "p03000", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03000/input.txt", "sample_output_relpath": "derived/input_output/data/p03000/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03000/C++/s275098334.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s275098334", "user_id": "u115102935"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  int N, X;\n  cin >> N >> X;\n  int L[N];\n  int D[N]={0};\n  for(int i=0; i<N; i++){\n    cin >> L[i];\n  }\n  \n  for(int j=1; j<N+1; j++){\n    D[j] = D[j-1] + L[j-1];\n    if(D[j] > X){\n      cout << j;\n      return 0;\n    }\n  }\n  \n  return 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nA ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \\leq i \\leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.\n\nHow many times will the ball make a bounce where the coordinate is at most X?\n\nConstraints\n\n1 \\leq N \\leq 100\n\n1 \\leq L_i \\leq 100\n\n1 \\leq X \\leq 10000\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN X\nL_1 L_2 ... L_{N-1} L_N\n\nOutput\n\nPrint the number of times the ball will make a bounce where the coordinate is at most X.\n\nSample Input 1\n\n3 6\n3 4 5\n\nSample Output 1\n\n2\n\nThe ball will make a bounce at the coordinates 0, 3, 7 and 12, among which two are less than or equal to 6.\n\nSample Input 2\n\n4 9\n3 3 3 3\n\nSample Output 2\n\n4\n\nThe ball will make a bounce at the coordinates 0, 3, 6, 9 and 12, among which four are less than or equal to 9.", "sample_input": "3 6\n3 4 5\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03000", "source_text": "Score : 200 points\n\nProblem Statement\n\nA ball will bounce along a number line, making N + 1 bounces. It will make the first bounce at coordinate D_1 = 0, and the i-th bounce (2 \\leq i \\leq N+1) at coordinate D_i = D_{i-1} + L_{i-1}.\n\nHow many times will the ball make a bounce where the coordinate is at most X?\n\nConstraints\n\n1 \\leq N \\leq 100\n\n1 \\leq L_i \\leq 100\n\n1 \\leq X \\leq 10000\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN X\nL_1 L_2 ... L_{N-1} L_N\n\nOutput\n\nPrint the number of times the ball will make a bounce where the coordinate is at most X.\n\nSample Input 1\n\n3 6\n3 4 5\n\nSample Output 1\n\n2\n\nThe ball will make a bounce at the coordinates 0, 3, 7 and 12, among which two are less than or equal to 6.\n\nSample Input 2\n\n4 9\n3 3 3 3\n\nSample Output 2\n\n4\n\nThe ball will make a bounce at the coordinates 0, 3, 6, 9 and 12, among which four are less than or equal to 9.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 299, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s715545945", "group_id": "codeNet:p03001", "input_text": "using namespace std;\n \n#include <iostream>\n#include <vector>\n#include <set>\n#include <string>\n#include <algorithm>\n#include <utility>\n#include <functional>\n#include <queue>\n#include <cmath>\n#include <numeric>\n#include <map>\n#include<iomanip>\nusing namespace std;\n \n \nint main(void){\n\tlong long int  W,H,x,y;\n \n\tcin >>W>>H>>x>>y;\n  \n  \tlong long int xmin = min(W - x, x), ymin = min(H - y, y);\n\t\n\tcout << (long double)W * (long double)H / (long double)2.0 << \" \" << ((xmin * H == ymin * W) ? 1 : 0) << endl;\n \n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1560717393, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03001.html", "problem_id": "p03001", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03001/input.txt", "sample_output_relpath": "derived/input_output/data/p03001/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03001/C++/s715545945.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s715545945", "user_id": "u766779796"}, "prompt_components": {"gold_output": "3.000000 0\n", "input_to_evaluate": "using namespace std;\n \n#include <iostream>\n#include <vector>\n#include <set>\n#include <string>\n#include <algorithm>\n#include <utility>\n#include <functional>\n#include <queue>\n#include <cmath>\n#include <numeric>\n#include <map>\n#include<iomanip>\nusing namespace std;\n \n \nint main(void){\n\tlong long int  W,H,x,y;\n \n\tcin >>W>>H>>x>>y;\n  \n  \tlong long int xmin = min(W - x, x), ymin = min(H - y, y);\n\t\n\tcout << (long double)W * (long double)H / (long double)2.0 << \" \" << ((xmin * H == ymin * W) ? 1 : 0) << endl;\n \n\treturn 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere is a rectangle in a coordinate plane. The coordinates of the four vertices are (0,0), (W,0), (W,H), and (0,H).\nYou are given a point (x,y) which is within the rectangle or on its border. We will draw a straight line passing through (x,y) to cut the rectangle into two parts. Find the maximum possible area of the part whose area is not larger than that of the other. Additionally, determine if there are multiple ways to cut the rectangle and achieve that maximum.\n\nConstraints\n\n1 \\leq W,H \\leq 10^9\n\n0\\leq x\\leq W\n\n0\\leq y\\leq H\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nW H x y\n\nOutput\n\nPrint the maximum possible area of the part whose area is not larger than that of the other, followed by 1 if there are multiple ways to cut the rectangle and achieve that maximum, and 0 otherwise.\n\nThe area printed will be judged correct when its absolute or relative error is at most 10^{-9}.\n\nSample Input 1\n\n2 3 1 2\n\nSample Output 1\n\n3.000000 0\n\nThe line x=1 gives the optimal cut, and no other line does.\n\nSample Input 2\n\n2 2 1 1\n\nSample Output 2\n\n2.000000 1", "sample_input": "2 3 1 2\n"}, "reference_outputs": ["3.000000 0\n"], "source_document_id": "p03001", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere is a rectangle in a coordinate plane. The coordinates of the four vertices are (0,0), (W,0), (W,H), and (0,H).\nYou are given a point (x,y) which is within the rectangle or on its border. We will draw a straight line passing through (x,y) to cut the rectangle into two parts. Find the maximum possible area of the part whose area is not larger than that of the other. Additionally, determine if there are multiple ways to cut the rectangle and achieve that maximum.\n\nConstraints\n\n1 \\leq W,H \\leq 10^9\n\n0\\leq x\\leq W\n\n0\\leq y\\leq H\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nW H x y\n\nOutput\n\nPrint the maximum possible area of the part whose area is not larger than that of the other, followed by 1 if there are multiple ways to cut the rectangle and achieve that maximum, and 0 otherwise.\n\nThe area printed will be judged correct when its absolute or relative error is at most 10^{-9}.\n\nSample Input 1\n\n2 3 1 2\n\nSample Output 1\n\n3.000000 0\n\nThe line x=1 gives the optimal cut, and no other line does.\n\nSample Input 2\n\n2 2 1 1\n\nSample Output 2\n\n2.000000 1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 522, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s083278905", "group_id": "codeNet:p03001", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, m, n) for (int i = m; i < n; ++i)\n#define rem(i, m, n) for (int i = m; i > n; --i)\nconst int MOD = 1000000007;\n\nint main() {\n  double W, H, x, y;\n  cin >> W >> H >> x >> y;\n  printf(\"%.15lf \", W * H / 2);\n  double mx = W / 2, my = H / 2;\n  if(x == mx && y == my) cout << 1 << endl;\n  else cout << 0 << endl;\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1560712462, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03001.html", "problem_id": "p03001", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03001/input.txt", "sample_output_relpath": "derived/input_output/data/p03001/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03001/C++/s083278905.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s083278905", "user_id": "u756388720"}, "prompt_components": {"gold_output": "3.000000 0\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, m, n) for (int i = m; i < n; ++i)\n#define rem(i, m, n) for (int i = m; i > n; --i)\nconst int MOD = 1000000007;\n\nint main() {\n  double W, H, x, y;\n  cin >> W >> H >> x >> y;\n  printf(\"%.15lf \", W * H / 2);\n  double mx = W / 2, my = H / 2;\n  if(x == mx && y == my) cout << 1 << endl;\n  else cout << 0 << endl;\n  return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere is a rectangle in a coordinate plane. The coordinates of the four vertices are (0,0), (W,0), (W,H), and (0,H).\nYou are given a point (x,y) which is within the rectangle or on its border. We will draw a straight line passing through (x,y) to cut the rectangle into two parts. Find the maximum possible area of the part whose area is not larger than that of the other. Additionally, determine if there are multiple ways to cut the rectangle and achieve that maximum.\n\nConstraints\n\n1 \\leq W,H \\leq 10^9\n\n0\\leq x\\leq W\n\n0\\leq y\\leq H\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nW H x y\n\nOutput\n\nPrint the maximum possible area of the part whose area is not larger than that of the other, followed by 1 if there are multiple ways to cut the rectangle and achieve that maximum, and 0 otherwise.\n\nThe area printed will be judged correct when its absolute or relative error is at most 10^{-9}.\n\nSample Input 1\n\n2 3 1 2\n\nSample Output 1\n\n3.000000 0\n\nThe line x=1 gives the optimal cut, and no other line does.\n\nSample Input 2\n\n2 2 1 1\n\nSample Output 2\n\n2.000000 1", "sample_input": "2 3 1 2\n"}, "reference_outputs": ["3.000000 0\n"], "source_document_id": "p03001", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere is a rectangle in a coordinate plane. The coordinates of the four vertices are (0,0), (W,0), (W,H), and (0,H).\nYou are given a point (x,y) which is within the rectangle or on its border. We will draw a straight line passing through (x,y) to cut the rectangle into two parts. Find the maximum possible area of the part whose area is not larger than that of the other. Additionally, determine if there are multiple ways to cut the rectangle and achieve that maximum.\n\nConstraints\n\n1 \\leq W,H \\leq 10^9\n\n0\\leq x\\leq W\n\n0\\leq y\\leq H\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nW H x y\n\nOutput\n\nPrint the maximum possible area of the part whose area is not larger than that of the other, followed by 1 if there are multiple ways to cut the rectangle and achieve that maximum, and 0 otherwise.\n\nThe area printed will be judged correct when its absolute or relative error is at most 10^{-9}.\n\nSample Input 1\n\n2 3 1 2\n\nSample Output 1\n\n3.000000 0\n\nThe line x=1 gives the optimal cut, and no other line does.\n\nSample Input 2\n\n2 2 1 1\n\nSample Output 2\n\n2.000000 1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 405, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s044478620", "group_id": "codeNet:p03003", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n  int64_t MOD = 1000000000 + 7;\n  int N, M;\n  cin >> N >> M;\n  vector<int64_t> S(N);\n  vector<int64_t> T(M);\n  for(int i = 0; i < N; i++) {\n    cin >> S.at(i);\n  }\n  for(int i = 0; i < M; i++) {\n    cin >> T.at(i);\n  }\n  vector<vector<int64_t>> data(N + 1, vector<int64_t> (M + 1, 0));\n  for(int i = 0; i <= N; i++) {\n    data.at(i).at(0) = 1;\n  }\n  for(int i = 0; i <= M; i++) {\n    data.at(0).at(i) = 1;\n  }\n  for(int i = 1; i <= N; i++) {\n    for(int j = 1; j <= M; j++) {\n      if(S.at(i - 1) == T.at(j - 1)) {\n        data.at(i).at(j) = data.at(i).at(j - 1) + data.at(i - 1).at(j);\n        data.at(i).at(j) %= MOD;\n      }\n      else {\n        data.at(i).at(j) = data.at(i).at(j - 1) + data.at(i - 1).at(j) - data.at(i - 1).at(j - 1);\n        data.at(i).at(j) %= MOD;\n      }\n    }\n  }\n  cout << data.at(N).at(M) << endl;\n}", "language": "C++", "metadata": {"date": 1597149146, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03003.html", "problem_id": "p03003", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03003/input.txt", "sample_output_relpath": "derived/input_output/data/p03003/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03003/C++/s044478620.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s044478620", "user_id": "u602140789"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n  int64_t MOD = 1000000000 + 7;\n  int N, M;\n  cin >> N >> M;\n  vector<int64_t> S(N);\n  vector<int64_t> T(M);\n  for(int i = 0; i < N; i++) {\n    cin >> S.at(i);\n  }\n  for(int i = 0; i < M; i++) {\n    cin >> T.at(i);\n  }\n  vector<vector<int64_t>> data(N + 1, vector<int64_t> (M + 1, 0));\n  for(int i = 0; i <= N; i++) {\n    data.at(i).at(0) = 1;\n  }\n  for(int i = 0; i <= M; i++) {\n    data.at(0).at(i) = 1;\n  }\n  for(int i = 1; i <= N; i++) {\n    for(int j = 1; j <= M; j++) {\n      if(S.at(i - 1) == T.at(j - 1)) {\n        data.at(i).at(j) = data.at(i).at(j - 1) + data.at(i - 1).at(j);\n        data.at(i).at(j) %= MOD;\n      }\n      else {\n        data.at(i).at(j) = data.at(i).at(j - 1) + data.at(i - 1).at(j) - data.at(i - 1).at(j - 1);\n        data.at(i).at(j) %= MOD;\n      }\n    }\n  }\n  cout << data.at(N).at(M) << endl;\n}", "problem_context": "Score : 500 points\n\nProblem Statement\n\nYou are given two integer sequences S and T of length N and M, respectively, both consisting of integers between 1 and 10^5 (inclusive).\n\nIn how many pairs of a subsequence of S and a subsequence of T do the two subsequences are the same in content?\n\nHere the subsequence of A is a sequence obtained by removing zero or more elements from A and concatenating the remaining elements without changing the order.\n\nFor both S and T, we distinguish two subsequences if the sets of the indices of the removed elements are different, even if the subsequences are the same in content.\n\nSince the answer can be tremendous, print the number modulo 10^9+7.\n\nConstraints\n\n1 \\leq N, M \\leq 2 \\times 10^3\n\nThe length of S is N.\n\nThe length of T is M.\n\n1 \\leq S_i, T_i \\leq 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nS_1 S_2 ... S_{N-1} S_{N}\nT_1 T_2 ... T_{M-1} T_{M}\n\nOutput\n\nPrint the number of pairs of a subsequence of S and a subsequence of T such that the subsequences are the same in content, modulo 10^9+7.\n\nSample Input 1\n\n2 2\n1 3\n3 1\n\nSample Output 1\n\n3\n\nS has four subsequences: (), (1), (3), (1, 3).\n\nT has four subsequences: (), (3), (1), (3, 1).\n\nThere are 1 \\times 1 pair of subsequences in which the subsequences are both (), 1 \\times 1 pair of subsequences in which the subsequences are both (1), and 1 \\times 1 pair of subsequences in which the subsequences are both (3), for a total of three pairs.\n\nSample Input 2\n\n2 2\n1 1\n1 1\n\nSample Output 2\n\n6\n\nS has four subsequences: (), (1), (1), (1, 1).\n\nT has four subsequences: (), (1), (1), (1, 1).\n\nThere are 1 \\times 1 pair of subsequences in which the subsequences are both (), 2 \\times 2 pairs of subsequences in which the subsequences are both (1), and 1 \\times 1 pair of subsequences in which the subsequences are both (1,1), for a total of six pairs.\nNote again that we distinguish two subsequences if the sets of the indices of the removed elements are different, even if the subsequences are the same in content.\n\nSample Input 3\n\n4 4\n3 4 5 6\n3 4 5 6\n\nSample Output 3\n\n16\n\nSample Input 4\n\n10 9\n9 6 5 7 5 9 8 5 6 7\n8 6 8 5 5 7 9 9 7\n\nSample Output 4\n\n191\n\nSample Input 5\n\n20 20\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1\n\nSample Output 5\n\n846527861\n\nBe sure to print the number modulo 10^9+7.", "sample_input": "2 2\n1 3\n3 1\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03003", "source_text": "Score : 500 points\n\nProblem Statement\n\nYou are given two integer sequences S and T of length N and M, respectively, both consisting of integers between 1 and 10^5 (inclusive).\n\nIn how many pairs of a subsequence of S and a subsequence of T do the two subsequences are the same in content?\n\nHere the subsequence of A is a sequence obtained by removing zero or more elements from A and concatenating the remaining elements without changing the order.\n\nFor both S and T, we distinguish two subsequences if the sets of the indices of the removed elements are different, even if the subsequences are the same in content.\n\nSince the answer can be tremendous, print the number modulo 10^9+7.\n\nConstraints\n\n1 \\leq N, M \\leq 2 \\times 10^3\n\nThe length of S is N.\n\nThe length of T is M.\n\n1 \\leq S_i, T_i \\leq 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nS_1 S_2 ... S_{N-1} S_{N}\nT_1 T_2 ... T_{M-1} T_{M}\n\nOutput\n\nPrint the number of pairs of a subsequence of S and a subsequence of T such that the subsequences are the same in content, modulo 10^9+7.\n\nSample Input 1\n\n2 2\n1 3\n3 1\n\nSample Output 1\n\n3\n\nS has four subsequences: (), (1), (3), (1, 3).\n\nT has four subsequences: (), (3), (1), (3, 1).\n\nThere are 1 \\times 1 pair of subsequences in which the subsequences are both (), 1 \\times 1 pair of subsequences in which the subsequences are both (1), and 1 \\times 1 pair of subsequences in which the subsequences are both (3), for a total of three pairs.\n\nSample Input 2\n\n2 2\n1 1\n1 1\n\nSample Output 2\n\n6\n\nS has four subsequences: (), (1), (1), (1, 1).\n\nT has four subsequences: (), (1), (1), (1, 1).\n\nThere are 1 \\times 1 pair of subsequences in which the subsequences are both (), 2 \\times 2 pairs of subsequences in which the subsequences are both (1), and 1 \\times 1 pair of subsequences in which the subsequences are both (1,1), for a total of six pairs.\nNote again that we distinguish two subsequences if the sets of the indices of the removed elements are different, even if the subsequences are the same in content.\n\nSample Input 3\n\n4 4\n3 4 5 6\n3 4 5 6\n\nSample Output 3\n\n16\n\nSample Input 4\n\n10 9\n9 6 5 7 5 9 8 5 6 7\n8 6 8 5 5 7 9 9 7\n\nSample Output 4\n\n191\n\nSample Input 5\n\n20 20\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1\n\nSample Output 5\n\n846527861\n\nBe sure to print the number modulo 10^9+7.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 888, "cpu_time_ms": 57, "memory_kb": 34564}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s012650920", "group_id": "codeNet:p03003", "input_text": "#define _CRT_SECURE_NO_WARNINGS\n#pragma comment(linker, \"/stack:256000000\")\n#include<utility>\n#include<iostream>\n#include<vector>\n#include<cstdio>\n#include<cstring>\n#include<algorithm>\n#include<cmath>\n#include<ctime>\n#include<functional>\n#include<random>\n#include<climits>\n#include<queue>\n#include<stack>\n#include<deque>\n#include<bitset>\n#include<map>\n#include<set>\n#include<unordered_map>\n#include<unordered_set>\n#include<cassert>\n#include<ccomplex>\n\n//4Head\n#define all(x) x.begin(), x.end()\n#define mp make_pair\n#define X first\n#define Y second\n\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing ld = long double;\nmt19937_64 gen(time(NULL));\n\n// belik's shit\nll const mod = 1e9 + 7;\nnamespace {\n\tll mult(ll a, ll b) {\n\t\tll val = a * b - (ll)((ld)a * b / mod) * mod;\n\t\tif (val < 0) {\n\t\t\tval += mod;\n\t\t}\n\t\tif (val >= mod) {\n\t\t\tval -= mod;\n\t\t}\n\t\treturn val;\n\t}\n\tll poww(ll a, ll b)\n\t{\n\t\tll val = 1;\n\t\ta %= mod;\n\t\twhile (b > 0){\n\t\t\tif (b % 2) val = mult(a, val);\n\t\t\ta = mult(a, a);\n\t\t\tb >>= 1;\n\t\t}\n\t\treturn val % mod;\n\t}\n\tll inv(ll a) {\n\t\treturn poww(a, mod - 2);\n\t}\n}\n\nll const maxn = 2e3 + 5;\n\n\nll dp[maxn][maxn];\n\nsigned main() {\n\tios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);\n\tll n, m; cin >> n >> m;\n\tvector<ll>a(n + 1), b(m + 1);\n\ta[0] = -1; b[0] = -2;\n\tfor (ll i = 1; i <= n; i++) cin >> a[i];\n\tfor (ll i = 1; i <= m; i++) cin >> b[i];\n\tdp[0][0] = 1;\n\tfor (ll i = 0; i <= n; i++) {\n\t\tfor (ll j = 0; j <= m; j++) {\n\t\t\t(dp[i][j] += (i ? dp[i - 1][j] : 0)) %= mod;\n\t\t\t(dp[i][j] += (j ? dp[i][j - 1] : 0)) %= mod;\n\t\t\t(dp[i][j] -= (i && j ? dp[i - 1][j - 1] : 0)) %= mod;\n\t\t\tif (dp[i][j] < 0) dp[i][j] += mod;\n\t\t\tif (a[i] == b[j]) {\n\t\t\t\t(dp[i][j] += (i && j ? dp[i - 1][j - 1] : 0)) %= mod;\n\t\t\t}\n\t\t\tll tt = 0;\n\t\t}\n\t}\n\tcout << (dp[n][m])%mod << endl;\n\treturn 0;\n\n}\n/*\n\n*/", "language": "C++", "metadata": {"date": 1564920676, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03003.html", "problem_id": "p03003", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03003/input.txt", "sample_output_relpath": "derived/input_output/data/p03003/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03003/C++/s012650920.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s012650920", "user_id": "u258032299"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#define _CRT_SECURE_NO_WARNINGS\n#pragma comment(linker, \"/stack:256000000\")\n#include<utility>\n#include<iostream>\n#include<vector>\n#include<cstdio>\n#include<cstring>\n#include<algorithm>\n#include<cmath>\n#include<ctime>\n#include<functional>\n#include<random>\n#include<climits>\n#include<queue>\n#include<stack>\n#include<deque>\n#include<bitset>\n#include<map>\n#include<set>\n#include<unordered_map>\n#include<unordered_set>\n#include<cassert>\n#include<ccomplex>\n\n//4Head\n#define all(x) x.begin(), x.end()\n#define mp make_pair\n#define X first\n#define Y second\n\nusing namespace std;\nusing ll = long long;\nusing ull = unsigned long long;\nusing ld = long double;\nmt19937_64 gen(time(NULL));\n\n// belik's shit\nll const mod = 1e9 + 7;\nnamespace {\n\tll mult(ll a, ll b) {\n\t\tll val = a * b - (ll)((ld)a * b / mod) * mod;\n\t\tif (val < 0) {\n\t\t\tval += mod;\n\t\t}\n\t\tif (val >= mod) {\n\t\t\tval -= mod;\n\t\t}\n\t\treturn val;\n\t}\n\tll poww(ll a, ll b)\n\t{\n\t\tll val = 1;\n\t\ta %= mod;\n\t\twhile (b > 0){\n\t\t\tif (b % 2) val = mult(a, val);\n\t\t\ta = mult(a, a);\n\t\t\tb >>= 1;\n\t\t}\n\t\treturn val % mod;\n\t}\n\tll inv(ll a) {\n\t\treturn poww(a, mod - 2);\n\t}\n}\n\nll const maxn = 2e3 + 5;\n\n\nll dp[maxn][maxn];\n\nsigned main() {\n\tios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);\n\tll n, m; cin >> n >> m;\n\tvector<ll>a(n + 1), b(m + 1);\n\ta[0] = -1; b[0] = -2;\n\tfor (ll i = 1; i <= n; i++) cin >> a[i];\n\tfor (ll i = 1; i <= m; i++) cin >> b[i];\n\tdp[0][0] = 1;\n\tfor (ll i = 0; i <= n; i++) {\n\t\tfor (ll j = 0; j <= m; j++) {\n\t\t\t(dp[i][j] += (i ? dp[i - 1][j] : 0)) %= mod;\n\t\t\t(dp[i][j] += (j ? dp[i][j - 1] : 0)) %= mod;\n\t\t\t(dp[i][j] -= (i && j ? dp[i - 1][j - 1] : 0)) %= mod;\n\t\t\tif (dp[i][j] < 0) dp[i][j] += mod;\n\t\t\tif (a[i] == b[j]) {\n\t\t\t\t(dp[i][j] += (i && j ? dp[i - 1][j - 1] : 0)) %= mod;\n\t\t\t}\n\t\t\tll tt = 0;\n\t\t}\n\t}\n\tcout << (dp[n][m])%mod << endl;\n\treturn 0;\n\n}\n/*\n\n*/", "problem_context": "Score : 500 points\n\nProblem Statement\n\nYou are given two integer sequences S and T of length N and M, respectively, both consisting of integers between 1 and 10^5 (inclusive).\n\nIn how many pairs of a subsequence of S and a subsequence of T do the two subsequences are the same in content?\n\nHere the subsequence of A is a sequence obtained by removing zero or more elements from A and concatenating the remaining elements without changing the order.\n\nFor both S and T, we distinguish two subsequences if the sets of the indices of the removed elements are different, even if the subsequences are the same in content.\n\nSince the answer can be tremendous, print the number modulo 10^9+7.\n\nConstraints\n\n1 \\leq N, M \\leq 2 \\times 10^3\n\nThe length of S is N.\n\nThe length of T is M.\n\n1 \\leq S_i, T_i \\leq 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nS_1 S_2 ... S_{N-1} S_{N}\nT_1 T_2 ... T_{M-1} T_{M}\n\nOutput\n\nPrint the number of pairs of a subsequence of S and a subsequence of T such that the subsequences are the same in content, modulo 10^9+7.\n\nSample Input 1\n\n2 2\n1 3\n3 1\n\nSample Output 1\n\n3\n\nS has four subsequences: (), (1), (3), (1, 3).\n\nT has four subsequences: (), (3), (1), (3, 1).\n\nThere are 1 \\times 1 pair of subsequences in which the subsequences are both (), 1 \\times 1 pair of subsequences in which the subsequences are both (1), and 1 \\times 1 pair of subsequences in which the subsequences are both (3), for a total of three pairs.\n\nSample Input 2\n\n2 2\n1 1\n1 1\n\nSample Output 2\n\n6\n\nS has four subsequences: (), (1), (1), (1, 1).\n\nT has four subsequences: (), (1), (1), (1, 1).\n\nThere are 1 \\times 1 pair of subsequences in which the subsequences are both (), 2 \\times 2 pairs of subsequences in which the subsequences are both (1), and 1 \\times 1 pair of subsequences in which the subsequences are both (1,1), for a total of six pairs.\nNote again that we distinguish two subsequences if the sets of the indices of the removed elements are different, even if the subsequences are the same in content.\n\nSample Input 3\n\n4 4\n3 4 5 6\n3 4 5 6\n\nSample Output 3\n\n16\n\nSample Input 4\n\n10 9\n9 6 5 7 5 9 8 5 6 7\n8 6 8 5 5 7 9 9 7\n\nSample Output 4\n\n191\n\nSample Input 5\n\n20 20\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1\n\nSample Output 5\n\n846527861\n\nBe sure to print the number modulo 10^9+7.", "sample_input": "2 2\n1 3\n3 1\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03003", "source_text": "Score : 500 points\n\nProblem Statement\n\nYou are given two integer sequences S and T of length N and M, respectively, both consisting of integers between 1 and 10^5 (inclusive).\n\nIn how many pairs of a subsequence of S and a subsequence of T do the two subsequences are the same in content?\n\nHere the subsequence of A is a sequence obtained by removing zero or more elements from A and concatenating the remaining elements without changing the order.\n\nFor both S and T, we distinguish two subsequences if the sets of the indices of the removed elements are different, even if the subsequences are the same in content.\n\nSince the answer can be tremendous, print the number modulo 10^9+7.\n\nConstraints\n\n1 \\leq N, M \\leq 2 \\times 10^3\n\nThe length of S is N.\n\nThe length of T is M.\n\n1 \\leq S_i, T_i \\leq 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nS_1 S_2 ... S_{N-1} S_{N}\nT_1 T_2 ... T_{M-1} T_{M}\n\nOutput\n\nPrint the number of pairs of a subsequence of S and a subsequence of T such that the subsequences are the same in content, modulo 10^9+7.\n\nSample Input 1\n\n2 2\n1 3\n3 1\n\nSample Output 1\n\n3\n\nS has four subsequences: (), (1), (3), (1, 3).\n\nT has four subsequences: (), (3), (1), (3, 1).\n\nThere are 1 \\times 1 pair of subsequences in which the subsequences are both (), 1 \\times 1 pair of subsequences in which the subsequences are both (1), and 1 \\times 1 pair of subsequences in which the subsequences are both (3), for a total of three pairs.\n\nSample Input 2\n\n2 2\n1 1\n1 1\n\nSample Output 2\n\n6\n\nS has four subsequences: (), (1), (1), (1, 1).\n\nT has four subsequences: (), (1), (1), (1, 1).\n\nThere are 1 \\times 1 pair of subsequences in which the subsequences are both (), 2 \\times 2 pairs of subsequences in which the subsequences are both (1), and 1 \\times 1 pair of subsequences in which the subsequences are both (1,1), for a total of six pairs.\nNote again that we distinguish two subsequences if the sets of the indices of the removed elements are different, even if the subsequences are the same in content.\n\nSample Input 3\n\n4 4\n3 4 5 6\n3 4 5 6\n\nSample Output 3\n\n16\n\nSample Input 4\n\n10 9\n9 6 5 7 5 9 8 5 6 7\n8 6 8 5 5 7 9 9 7\n\nSample Output 4\n\n191\n\nSample Input 5\n\n20 20\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1\n1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1\n\nSample Output 5\n\n846527861\n\nBe sure to print the number modulo 10^9+7.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1811, "cpu_time_ms": 84, "memory_kb": 31616}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s718710589", "group_id": "codeNet:p03004", "input_text": "#include <bits/stdc++.h>\n#define int long long\n#define double long double\n#pragma GCC optimize(\"O3,Ofast,no-stack-protector,unroll-loops,fast-math\")\n#pragma GCC target(\"avx,avx2,sse\")\nusing namespace std;\n\nint n;\nvector<int> x(n);\nvector<int> y(n);\nvector<char> c(n);\n\ndouble calc(double steps) {\n    double ax = 1e15;\n    double bx = -1e15;\n    double ay = 1e15;\n    double by = -1e15;\n    for (int i = 0; i < n; i++) {\n        double X = x[i];\n        double Y = y[i];\n        if (c[i] == 'L') X -= steps;\n        if (c[i] == 'R') X += steps;\n        if (c[i] == 'D') Y -= steps;\n        if (c[i] == 'U') Y += steps;\n        ax = min(ax, X);\n        bx = max(bx, X);\n        ay = min(ay, Y);\n        by = max(by, Y);\n    }\n    return (by - ay) * (bx - ax);\n}\n\nsigned main() {\n    ios_base::sync_with_stdio(false);\n    cin.tie(0);\n    cout.tie(0);\n\n    cin >> n;\n    x.resize(n);\n    y.resize(n);\n    c.resize(n);\n    for (int i = 0; i < n; i++) {\n        cin >> x[i] >> y[i] >> c[i];\n    }\n    double s = 0;\n    double e = 1e9;\n    while (e - s > 0.000000000001) {\n        double a = (s * 2 + e) / 3.0;\n        double b = (s + e * 2) / 3.0;\n        double fa = calc(a);\n        double fb = calc(b);\n        if (fa <= fb) {\n            e = b;\n        } else {\n            s = a;\n        }\n    }\n    cout << fixed << ' ' << setprecision(11) << calc(s) << endl;\n\n    fflush(stdout);\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1592869146, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03004.html", "problem_id": "p03004", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03004/input.txt", "sample_output_relpath": "derived/input_output/data/p03004/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03004/C++/s718710589.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s718710589", "user_id": "u460297807"}, "prompt_components": {"gold_output": "0\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define int long long\n#define double long double\n#pragma GCC optimize(\"O3,Ofast,no-stack-protector,unroll-loops,fast-math\")\n#pragma GCC target(\"avx,avx2,sse\")\nusing namespace std;\n\nint n;\nvector<int> x(n);\nvector<int> y(n);\nvector<char> c(n);\n\ndouble calc(double steps) {\n    double ax = 1e15;\n    double bx = -1e15;\n    double ay = 1e15;\n    double by = -1e15;\n    for (int i = 0; i < n; i++) {\n        double X = x[i];\n        double Y = y[i];\n        if (c[i] == 'L') X -= steps;\n        if (c[i] == 'R') X += steps;\n        if (c[i] == 'D') Y -= steps;\n        if (c[i] == 'U') Y += steps;\n        ax = min(ax, X);\n        bx = max(bx, X);\n        ay = min(ay, Y);\n        by = max(by, Y);\n    }\n    return (by - ay) * (bx - ax);\n}\n\nsigned main() {\n    ios_base::sync_with_stdio(false);\n    cin.tie(0);\n    cout.tie(0);\n\n    cin >> n;\n    x.resize(n);\n    y.resize(n);\n    c.resize(n);\n    for (int i = 0; i < n; i++) {\n        cin >> x[i] >> y[i] >> c[i];\n    }\n    double s = 0;\n    double e = 1e9;\n    while (e - s > 0.000000000001) {\n        double a = (s * 2 + e) / 3.0;\n        double b = (s + e * 2) / 3.0;\n        double fa = calc(a);\n        double fb = calc(b);\n        if (fa <= fb) {\n            e = b;\n        } else {\n            s = a;\n        }\n    }\n    cout << fixed << ' ' << setprecision(11) << calc(s) << endl;\n\n    fflush(stdout);\n    return 0;\n}\n", "problem_context": "Score : 600 points\n\nProblem Statement\n\nThere are N points in a two-dimensional plane. The initial coordinates of the i-th point are (x_i, y_i). Now, each point starts moving at a speed of 1 per second, in a direction parallel to the x- or y- axis. You are given a character d_i that represents the specific direction in which the i-th point moves, as follows:\n\nIf d_i = R, the i-th point moves in the positive x direction;\n\nIf d_i = L, the i-th point moves in the negative x direction;\n\nIf d_i = U, the i-th point moves in the positive y direction;\n\nIf d_i = D, the i-th point moves in the negative y direction.\n\nYou can stop all the points at some moment of your choice after they start moving (including the moment they start moving).\nThen, let x_{max} and x_{min} be the maximum and minimum among the x-coordinates of the N points, respectively. Similarly, let y_{max} and y_{min} be the maximum and minimum among the y-coordinates of the N points, respectively.\n\nFind the minimum possible value of (x_{max} - x_{min}) \\times (y_{max} - y_{min}) and print it.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n-10^8 \\leq x_i,\\ y_i \\leq 10^8\n\nx_i and y_i are integers.\n\nd_i is R, L, U, or D.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nx_1 y_1 d_1\nx_2 y_2 d_2\n.\n.\n.\nx_N y_N d_N\n\nOutput\n\nPrint the minimum possible value of (x_{max} - x_{min}) \\times (y_{max} - y_{min}).\n\nThe output will be considered correct when its absolute or relative error from the judge's output is at most 10^{-9}.\n\nSample Input 1\n\n2\n0 3 D\n3 0 L\n\nSample Output 1\n\n0\n\nAfter three seconds, the two points will meet at the origin. The value in question will be 0 at that moment.\n\nSample Input 2\n\n5\n-7 -10 U\n7 -6 U\n-8 7 D\n-3 3 D\n0 -6 R\n\nSample Output 2\n\n97.5\n\nThe answer may not be an integer.\n\nSample Input 3\n\n20\n6 -10 R\n-4 -9 U\n9 6 D\n-3 -2 R\n0 7 D\n4 5 D\n10 -10 U\n-1 -8 U\n10 -6 D\n8 -5 U\n6 4 D\n0 3 D\n7 9 R\n9 -4 R\n3 10 D\n1 9 U\n1 -6 U\n9 -8 R\n6 7 D\n7 -3 D\n\nSample Output 3\n\n273", "sample_input": "2\n0 3 D\n3 0 L\n"}, "reference_outputs": ["0\n"], "source_document_id": "p03004", "source_text": "Score : 600 points\n\nProblem Statement\n\nThere are N points in a two-dimensional plane. The initial coordinates of the i-th point are (x_i, y_i). Now, each point starts moving at a speed of 1 per second, in a direction parallel to the x- or y- axis. You are given a character d_i that represents the specific direction in which the i-th point moves, as follows:\n\nIf d_i = R, the i-th point moves in the positive x direction;\n\nIf d_i = L, the i-th point moves in the negative x direction;\n\nIf d_i = U, the i-th point moves in the positive y direction;\n\nIf d_i = D, the i-th point moves in the negative y direction.\n\nYou can stop all the points at some moment of your choice after they start moving (including the moment they start moving).\nThen, let x_{max} and x_{min} be the maximum and minimum among the x-coordinates of the N points, respectively. Similarly, let y_{max} and y_{min} be the maximum and minimum among the y-coordinates of the N points, respectively.\n\nFind the minimum possible value of (x_{max} - x_{min}) \\times (y_{max} - y_{min}) and print it.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n-10^8 \\leq x_i,\\ y_i \\leq 10^8\n\nx_i and y_i are integers.\n\nd_i is R, L, U, or D.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nx_1 y_1 d_1\nx_2 y_2 d_2\n.\n.\n.\nx_N y_N d_N\n\nOutput\n\nPrint the minimum possible value of (x_{max} - x_{min}) \\times (y_{max} - y_{min}).\n\nThe output will be considered correct when its absolute or relative error from the judge's output is at most 10^{-9}.\n\nSample Input 1\n\n2\n0 3 D\n3 0 L\n\nSample Output 1\n\n0\n\nAfter three seconds, the two points will meet at the origin. The value in question will be 0 at that moment.\n\nSample Input 2\n\n5\n-7 -10 U\n7 -6 U\n-8 7 D\n-3 3 D\n0 -6 R\n\nSample Output 2\n\n97.5\n\nThe answer may not be an integer.\n\nSample Input 3\n\n20\n6 -10 R\n-4 -9 U\n9 6 D\n-3 -2 R\n0 7 D\n4 5 D\n10 -10 U\n-1 -8 U\n10 -6 D\n8 -5 U\n6 4 D\n0 3 D\n7 9 R\n9 -4 R\n3 10 D\n1 9 U\n1 -6 U\n9 -8 R\n6 7 D\n7 -3 D\n\nSample Output 3\n\n273", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1398, "cpu_time_ms": 5513, "memory_kb": 5236}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s945988342", "group_id": "codeNet:p03007", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, n) for (ll i = 0; i < (ll)(n); i++)\n#define rep2(i, s, n) for (ll i = (s); i < (ll)(n); i++)\n#define all(v) v.begin(), v.end()\n#define sz(v) v.size()\n#define INF 100000000000000 //10^14\ntemplate <typename T>\nbool chmax(T &a, const T& b) {\n  if (a < b) {\n    a = b;\n    return true;\n  }\n  return false;\n}\ntemplate <typename T>\nbool chmin(T &a, const T& b) {\n  if (a > b) {\n    a = b;\n    return true;\n  }\n  return false;\n}\n\nint main()\n{\n    ll N;\n    cin >> N;\n    vector<ll> A(N);\n    rep(i, N) cin >> A.at(i);\n    sort(all(A));\n    ll p = N;\n    rep(i, N){\n      if(A.at(i) > 0){\n        p = i;\n        break;\n      }\n    }\n    ll M = 0;\n    M += A.at(N-1);\n    M -= A.at(0);\n    rep(i, N-2){\n      if(i+1 >= p){\n        M += A.at(i+1);\n      }\n      else{\n        M -= A.at(i+1);\n      }\n    }\n    cout << M << endl;\n    ll x = A.at(0);\n    if(p == 0){\n      p++;\n    }\n    rep2(j, p, N-1){\n      cout << x << \" \" << A.at(j) << endl;\n      x -= A.at(j);\n    }\n    ll y = A.at(N-1);\n    rep2(i, 1, p){\n      cout << y << \" \" << A.at(i) << endl;\n      y -= A.at(i);\n    }\n    cout << y << \" \" << x << endl;\n}", "language": "C++", "metadata": {"date": 1598748303, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03007.html", "problem_id": "p03007", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03007/input.txt", "sample_output_relpath": "derived/input_output/data/p03007/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03007/C++/s945988342.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s945988342", "user_id": "u208059640"}, "prompt_components": {"gold_output": "4\n-1 1\n2 -2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n#define rep(i, n) for (ll i = 0; i < (ll)(n); i++)\n#define rep2(i, s, n) for (ll i = (s); i < (ll)(n); i++)\n#define all(v) v.begin(), v.end()\n#define sz(v) v.size()\n#define INF 100000000000000 //10^14\ntemplate <typename T>\nbool chmax(T &a, const T& b) {\n  if (a < b) {\n    a = b;\n    return true;\n  }\n  return false;\n}\ntemplate <typename T>\nbool chmin(T &a, const T& b) {\n  if (a > b) {\n    a = b;\n    return true;\n  }\n  return false;\n}\n\nint main()\n{\n    ll N;\n    cin >> N;\n    vector<ll> A(N);\n    rep(i, N) cin >> A.at(i);\n    sort(all(A));\n    ll p = N;\n    rep(i, N){\n      if(A.at(i) > 0){\n        p = i;\n        break;\n      }\n    }\n    ll M = 0;\n    M += A.at(N-1);\n    M -= A.at(0);\n    rep(i, N-2){\n      if(i+1 >= p){\n        M += A.at(i+1);\n      }\n      else{\n        M -= A.at(i+1);\n      }\n    }\n    cout << M << endl;\n    ll x = A.at(0);\n    if(p == 0){\n      p++;\n    }\n    rep2(j, p, N-1){\n      cout << x << \" \" << A.at(j) << endl;\n      x -= A.at(j);\n    }\n    ll y = A.at(N-1);\n    rep2(i, 1, p){\n      cout << y << \" \" << A.at(i) << endl;\n      y -= A.at(i);\n    }\n    cout << y << \" \" << x << endl;\n}", "problem_context": "Score : 500 points\n\nProblem Statement\n\nThere are N integers, A_1, A_2, ..., A_N, written on a blackboard.\n\nWe will repeat the following operation N-1 times so that we have only one integer on the blackboard.\n\nChoose two integers x and y on the blackboard and erase these two integers. Then, write a new integer x-y.\n\nFind the maximum possible value of the final integer on the blackboard and a sequence of operations that maximizes the final integer.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n-10^4 \\leq A_i \\leq 10^4\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the maximum possible value M of the final integer on the blackboard, and a sequence of operations x_i, y_i that maximizes the final integer, in the format below.\n\nHere x_i and y_i represent the integers x and y chosen in the i-th operation, respectively.\n\nIf there are multiple sequences of operations that maximize the final integer, any of them will be accepted.\n\nM\nx_1 y_1\n:\nx_{N-1} y_{N-1}\n\nSample Input 1\n\n3\n1 -1 2\n\nSample Output 1\n\n4\n-1 1\n2 -2\n\nIf we choose x = -1 and y = 1 in the first operation, the set of integers written on the blackboard becomes (-2, 2).\n\nThen, if we choose x = 2 and y = -2 in the second operation, the set of integers written on the blackboard becomes (4).\n\nIn this case, we have 4 as the final integer. We cannot end with a greater integer, so the answer is 4.\n\nSample Input 2\n\n3\n1 1 1\n\nSample Output 2\n\n1\n1 1\n1 0", "sample_input": "3\n1 -1 2\n"}, "reference_outputs": ["4\n-1 1\n2 -2\n"], "source_document_id": "p03007", "source_text": "Score : 500 points\n\nProblem Statement\n\nThere are N integers, A_1, A_2, ..., A_N, written on a blackboard.\n\nWe will repeat the following operation N-1 times so that we have only one integer on the blackboard.\n\nChoose two integers x and y on the blackboard and erase these two integers. Then, write a new integer x-y.\n\nFind the maximum possible value of the final integer on the blackboard and a sequence of operations that maximizes the final integer.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n-10^4 \\leq A_i \\leq 10^4\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the maximum possible value M of the final integer on the blackboard, and a sequence of operations x_i, y_i that maximizes the final integer, in the format below.\n\nHere x_i and y_i represent the integers x and y chosen in the i-th operation, respectively.\n\nIf there are multiple sequences of operations that maximize the final integer, any of them will be accepted.\n\nM\nx_1 y_1\n:\nx_{N-1} y_{N-1}\n\nSample Input 1\n\n3\n1 -1 2\n\nSample Output 1\n\n4\n-1 1\n2 -2\n\nIf we choose x = -1 and y = 1 in the first operation, the set of integers written on the blackboard becomes (-2, 2).\n\nThen, if we choose x = 2 and y = -2 in the second operation, the set of integers written on the blackboard becomes (4).\n\nIn this case, we have 4 as the final integer. We cannot end with a greater integer, so the answer is 4.\n\nSample Input 2\n\n3\n1 1 1\n\nSample Output 2\n\n1\n1 1\n1 0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1191, "cpu_time_ms": 185, "memory_kb": 4052}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s761030962", "group_id": "codeNet:p03008", "input_text": "#include<stdio.h>\n#include<iostream>\n#include<algorithm>\n#include<string>\n#include<string.h>\n#include<math.h>\n#include<stdlib.h>\n#include<vector>\n#include<queue>\n#include<map>\n#include<iomanip>\n#include<set>\n#define rep(index,num) for(int index=0;index<num;index++)\n#define rep1(index,num) for(int index=1;index<=num;index++)\n#define scan(argument) cin>>argument\n#define prin(argument) cout<<argument<<endl\n#define kaigyo cout<<endl\n#define eps 1e-7\n#define mp(a1,a2) make_pair(a1,a2)\ntypedef long long ll;\ntypedef long double ld;\nusing namespace std;\ntypedef pair<ll,ll> pll;\ntypedef pair<int,int> pint;\ntypedef vector<int> vint;\ntypedef vector<ll> vll;\ntypedef vector<pint> vpint;\ntypedef vector<pll> vpll;\nll INFl=1e+18+1;\nint INF=1e+9+1;\nint main(){\n\tll N,g[2][3];\n\tscan(N);\n\trep(i,2) rep(j,3) scan(g[i][j]);\n\tvpll AB,BA;\n\trep(j,3){\n\t\tif(g[0][j]<g[1][j]) AB.push_back({g[0][j],g[1][j]});\n\t\tif(g[0][j]>g[1][j]) BA.push_back({g[1][j],g[0][j]});\n\t}\n\tll maxD=N;\n\tif(AB.size()==3){\n\t\tfor(ll a=0;a*AB[0].first<=N;a++){\n\t\t\tfor(ll b=0;a*AB[0].first+b*AB[1].first<=N;b++){\n\t\t\t\tll c=(N-a*AB[0].first-b*AB[1].first)/AB[2].first;\n\t\t\t\tll nokorid=N-a*AB[0].first-b*AB[1].first-c*AB[2].first;\n\t\t\t\tll D=nokorid+a*AB[0].second+b*AB[1].second+c*AB[2].second;\n\t\t\t\tmaxD=max(maxD,D);\n\t\t\t\t//printf(\"a:%lld b:%lld c:%lld nokorid:%lld D:%lld maxD:%lld\\n\",a,b,c,nokorid,D,maxD);\n\t\t\t}\n\t\t}\n\t}\n\telse if(AB.size()==2){\n\t\tfor(ll a=0;a*AB[0].first<=N;a++){\n\t\t\tll b=(N-a*AB[0].first)/AB[1].first;\n\t\t\tll nokorid=N-a*AB[0].first-b*AB[1].first;\n\t\t\tll D=nokorid+a*AB[0].second+b*AB[1].second;\n\t\t\tmaxD=max(maxD,D);\n\t\t\t//printf(\"a:%lld b:%lld nokorid:%lld D:%lld maxD:%lld\\n\",a,b,nokorid,D,maxD);\n\n\t\t}\n\t}\n\telse if(AB.size()==1){\n\t\tmaxD=(N-N/AB[0].first*AB[0].first+N/AB[0].first*AB[0].second);\n\t}\n\t//printf(\"maxD:%lld\\n\",maxD);\n\tN=maxD;\n\tif(BA.size()==3){\n\t\tfor(ll a=0;a*BA[0].first<=N;a++){\n\t\t\tfor(ll b=0;a*BA[0].first+b*BA[1].first<=N;b++){\n\t\t\t\tll c=(N-a*BA[0].first-b*BA[1].first)/BA[2].first;\n\t\t\t\tll nokorid=N-a*BA[0].first-b*BA[1].first-c*BA[2].first;\n\t\t\t\tll D=nokorid+a*BA[0].second+b*BA[1].second+c*BA[2].second;\n\t\t\t\tmaxD=max(maxD,D);\n\t\t\t\t//printf(\"a:%lld b:%lld c:%lld nokorid:%lld D:%lld maxD:%lld\\n\",a,b,c,nokorid,D,maxD);\n\n\t\t\t}\n\t\t}\n\t}\n\telse if(BA.size()==2){\n\t\tfor(ll a=0;a*BA[0].first<=N;a++){\n\t\t\tll b=(N-a*BA[0].first)/BA[1].first;\n\t\t\tll nokorid=N-a*BA[0].first-b*BA[1].first;\n\t\t\tll D=nokorid+a*BA[0].second+b*BA[1].second;\n\t\t\tmaxD=max(maxD,D);\n\t\t//\tprintf(\"a:%lld b:%lld nokorid:%lld D:%lld maxD:%lld\\n\",a,b,nokorid,D,maxD);\n\n\t\t}\n\t}\n\telse if(BA.size()==1){\n\t\tmaxD=(N-N/BA[0].first*BA[0].first+N/BA[0].first*BA[0].second);\n\t}\n\tprin(maxD);\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1560650913, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03008.html", "problem_id": "p03008", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03008/input.txt", "sample_output_relpath": "derived/input_output/data/p03008/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03008/C++/s761030962.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s761030962", "user_id": "u222030240"}, "prompt_components": {"gold_output": "46\n", "input_to_evaluate": "#include<stdio.h>\n#include<iostream>\n#include<algorithm>\n#include<string>\n#include<string.h>\n#include<math.h>\n#include<stdlib.h>\n#include<vector>\n#include<queue>\n#include<map>\n#include<iomanip>\n#include<set>\n#define rep(index,num) for(int index=0;index<num;index++)\n#define rep1(index,num) for(int index=1;index<=num;index++)\n#define scan(argument) cin>>argument\n#define prin(argument) cout<<argument<<endl\n#define kaigyo cout<<endl\n#define eps 1e-7\n#define mp(a1,a2) make_pair(a1,a2)\ntypedef long long ll;\ntypedef long double ld;\nusing namespace std;\ntypedef pair<ll,ll> pll;\ntypedef pair<int,int> pint;\ntypedef vector<int> vint;\ntypedef vector<ll> vll;\ntypedef vector<pint> vpint;\ntypedef vector<pll> vpll;\nll INFl=1e+18+1;\nint INF=1e+9+1;\nint main(){\n\tll N,g[2][3];\n\tscan(N);\n\trep(i,2) rep(j,3) scan(g[i][j]);\n\tvpll AB,BA;\n\trep(j,3){\n\t\tif(g[0][j]<g[1][j]) AB.push_back({g[0][j],g[1][j]});\n\t\tif(g[0][j]>g[1][j]) BA.push_back({g[1][j],g[0][j]});\n\t}\n\tll maxD=N;\n\tif(AB.size()==3){\n\t\tfor(ll a=0;a*AB[0].first<=N;a++){\n\t\t\tfor(ll b=0;a*AB[0].first+b*AB[1].first<=N;b++){\n\t\t\t\tll c=(N-a*AB[0].first-b*AB[1].first)/AB[2].first;\n\t\t\t\tll nokorid=N-a*AB[0].first-b*AB[1].first-c*AB[2].first;\n\t\t\t\tll D=nokorid+a*AB[0].second+b*AB[1].second+c*AB[2].second;\n\t\t\t\tmaxD=max(maxD,D);\n\t\t\t\t//printf(\"a:%lld b:%lld c:%lld nokorid:%lld D:%lld maxD:%lld\\n\",a,b,c,nokorid,D,maxD);\n\t\t\t}\n\t\t}\n\t}\n\telse if(AB.size()==2){\n\t\tfor(ll a=0;a*AB[0].first<=N;a++){\n\t\t\tll b=(N-a*AB[0].first)/AB[1].first;\n\t\t\tll nokorid=N-a*AB[0].first-b*AB[1].first;\n\t\t\tll D=nokorid+a*AB[0].second+b*AB[1].second;\n\t\t\tmaxD=max(maxD,D);\n\t\t\t//printf(\"a:%lld b:%lld nokorid:%lld D:%lld maxD:%lld\\n\",a,b,nokorid,D,maxD);\n\n\t\t}\n\t}\n\telse if(AB.size()==1){\n\t\tmaxD=(N-N/AB[0].first*AB[0].first+N/AB[0].first*AB[0].second);\n\t}\n\t//printf(\"maxD:%lld\\n\",maxD);\n\tN=maxD;\n\tif(BA.size()==3){\n\t\tfor(ll a=0;a*BA[0].first<=N;a++){\n\t\t\tfor(ll b=0;a*BA[0].first+b*BA[1].first<=N;b++){\n\t\t\t\tll c=(N-a*BA[0].first-b*BA[1].first)/BA[2].first;\n\t\t\t\tll nokorid=N-a*BA[0].first-b*BA[1].first-c*BA[2].first;\n\t\t\t\tll D=nokorid+a*BA[0].second+b*BA[1].second+c*BA[2].second;\n\t\t\t\tmaxD=max(maxD,D);\n\t\t\t\t//printf(\"a:%lld b:%lld c:%lld nokorid:%lld D:%lld maxD:%lld\\n\",a,b,c,nokorid,D,maxD);\n\n\t\t\t}\n\t\t}\n\t}\n\telse if(BA.size()==2){\n\t\tfor(ll a=0;a*BA[0].first<=N;a++){\n\t\t\tll b=(N-a*BA[0].first)/BA[1].first;\n\t\t\tll nokorid=N-a*BA[0].first-b*BA[1].first;\n\t\t\tll D=nokorid+a*BA[0].second+b*BA[1].second;\n\t\t\tmaxD=max(maxD,D);\n\t\t//\tprintf(\"a:%lld b:%lld nokorid:%lld D:%lld maxD:%lld\\n\",a,b,nokorid,D,maxD);\n\n\t\t}\n\t}\n\telse if(BA.size()==1){\n\t\tmaxD=(N-N/BA[0].first*BA[0].first+N/BA[0].first*BA[0].second);\n\t}\n\tprin(maxD);\n\treturn 0;\n}\n", "problem_context": "Score : 600 points\n\nProblem Statement\n\nThe squirrel Chokudai has N acorns.\nOne day, he decides to do some trades in multiple precious metal exchanges to make more acorns.\n\nHis plan is as follows:\n\nGet out of the nest with N acorns in his hands.\n\nGo to Exchange A and do some trades.\n\nGo to Exchange B and do some trades.\n\nGo to Exchange A and do some trades.\n\nGo back to the nest.\n\nIn Exchange X (X = A, B), he can perform the following operations any integer number of times (possibly zero) in any order:\n\nLose g_{X} acorns and gain 1 gram of gold.\n\nGain g_{X} acorns and lose 1 gram of gold.\n\nLose s_{X} acorns and gain 1 gram of silver.\n\nGain s_{X} acorns and lose 1 gram of silver.\n\nLose b_{X} acorns and gain 1 gram of bronze.\n\nGain b_{X} acorns and lose 1 gram of bronze.\n\nNaturally, he cannot perform an operation that would leave him with a negative amount of acorns, gold, silver, or bronze.\n\nWhat is the maximum number of acorns that he can bring to the nest?\nNote that gold, silver, or bronze brought to the nest would be worthless because he is just a squirrel.\n\nConstraints\n\n1 \\leq N \\leq 5000\n\n1 \\leq g_{X} \\leq 5000\n\n1 \\leq s_{X} \\leq 5000\n\n1 \\leq b_{X} \\leq 5000\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\ng_A s_A b_A\ng_B s_B b_B\n\nOutput\n\nPrint the maximum number of acorns that Chokudai can bring to the nest.\n\nSample Input 1\n\n23\n1 1 1\n2 1 1\n\nSample Output 1\n\n46\n\nHe can bring 46 acorns to the nest, as follows:\n\nIn Exchange A, trade 23 acorns for 23 grams of gold. {acorns, gold, silver, bronze}={ 0,23,0,0 }\n\nIn Exchange B, trade 23 grams of gold for 46 acorns. {acorns, gold, silver, bronze}={ 46,0,0,0 }\n\nIn Exchange A, trade nothing. {acorns, gold, silver, bronze}={ 46,0,0,0 }\n\nHe cannot have 47 or more acorns, so the answer is 46.", "sample_input": "23\n1 1 1\n2 1 1\n"}, "reference_outputs": ["46\n"], "source_document_id": "p03008", "source_text": "Score : 600 points\n\nProblem Statement\n\nThe squirrel Chokudai has N acorns.\nOne day, he decides to do some trades in multiple precious metal exchanges to make more acorns.\n\nHis plan is as follows:\n\nGet out of the nest with N acorns in his hands.\n\nGo to Exchange A and do some trades.\n\nGo to Exchange B and do some trades.\n\nGo to Exchange A and do some trades.\n\nGo back to the nest.\n\nIn Exchange X (X = A, B), he can perform the following operations any integer number of times (possibly zero) in any order:\n\nLose g_{X} acorns and gain 1 gram of gold.\n\nGain g_{X} acorns and lose 1 gram of gold.\n\nLose s_{X} acorns and gain 1 gram of silver.\n\nGain s_{X} acorns and lose 1 gram of silver.\n\nLose b_{X} acorns and gain 1 gram of bronze.\n\nGain b_{X} acorns and lose 1 gram of bronze.\n\nNaturally, he cannot perform an operation that would leave him with a negative amount of acorns, gold, silver, or bronze.\n\nWhat is the maximum number of acorns that he can bring to the nest?\nNote that gold, silver, or bronze brought to the nest would be worthless because he is just a squirrel.\n\nConstraints\n\n1 \\leq N \\leq 5000\n\n1 \\leq g_{X} \\leq 5000\n\n1 \\leq s_{X} \\leq 5000\n\n1 \\leq b_{X} \\leq 5000\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\ng_A s_A b_A\ng_B s_B b_B\n\nOutput\n\nPrint the maximum number of acorns that Chokudai can bring to the nest.\n\nSample Input 1\n\n23\n1 1 1\n2 1 1\n\nSample Output 1\n\n46\n\nHe can bring 46 acorns to the nest, as follows:\n\nIn Exchange A, trade 23 acorns for 23 grams of gold. {acorns, gold, silver, bronze}={ 0,23,0,0 }\n\nIn Exchange B, trade 23 grams of gold for 46 acorns. {acorns, gold, silver, bronze}={ 46,0,0,0 }\n\nIn Exchange A, trade nothing. {acorns, gold, silver, bronze}={ 46,0,0,0 }\n\nHe cannot have 47 or more acorns, so the answer is 46.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2631, "cpu_time_ms": 141, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s925079974", "group_id": "codeNet:p03013", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nconst int mod =1e9+7;\nint main(void){\n    int n,m;cin>>n>>m;\n    vector<int> d(m);\n    for(int i=0;i<m;i++)cin>>d[i];\n    vector<int> dp(n+1,0);\n    dp[0]=dp[1]=1;\n    int tmp=0;\n    if(d[0]==1){\n        tmp++;\n        dp[1]=0;\n    }\n    for(int i=2;i<=n;i++){\n        if(tmp<m&&d[tmp]==i){\n            tmp++;\n            continue;\n        }\n        dp[i]=dp[i-1]+dp[i-2];\n        dp[i]%=mod;\n    }\n    cout<<dp[n]<<endl;\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1585774402, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03013.html", "problem_id": "p03013", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03013/input.txt", "sample_output_relpath": "derived/input_output/data/p03013/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03013/C++/s925079974.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s925079974", "user_id": "u986025116"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nconst int mod =1e9+7;\nint main(void){\n    int n,m;cin>>n>>m;\n    vector<int> d(m);\n    for(int i=0;i<m;i++)cin>>d[i];\n    vector<int> dp(n+1,0);\n    dp[0]=dp[1]=1;\n    int tmp=0;\n    if(d[0]==1){\n        tmp++;\n        dp[1]=0;\n    }\n    for(int i=2;i<=n;i++){\n        if(tmp<m&&d[tmp]==i){\n            tmp++;\n            continue;\n        }\n        dp[i]=dp[i-1]+dp[i-2];\n        dp[i]%=mod;\n    }\n    cout<<dp[n]<<endl;\n    return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere is a staircase with N steps. Takahashi is now standing at the foot of the stairs, that is, on the 0-th step.\nHe can climb up one or two steps at a time.\n\nHowever, the treads of the a_1-th, a_2-th, a_3-th, \\ldots, a_M-th steps are broken, so it is dangerous to set foot on those steps.\n\nHow many are there to climb up to the top step, that is, the N-th step, without setting foot on the broken steps?\nFind the count modulo 1\\ 000\\ 000\\ 007.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n0 \\leq M \\leq N-1\n\n1 \\leq a_1 < a_2 < ... < a_M \\leq N-1\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\na_1\na_2\n.\n.\n.\na_M\n\nOutput\n\nPrint the number of ways to climb up the stairs under the condition, modulo 1\\ 000\\ 000\\ 007.\n\nSample Input 1\n\n6 1\n3\n\nSample Output 1\n\n4\n\nThere are four ways to climb up the stairs, as follows:\n\n0 \\to 1 \\to 2 \\to 4 \\to 5 \\to 6\n\n0 \\to 1 \\to 2 \\to 4 \\to 6\n\n0 \\to 2 \\to 4 \\to 5 \\to 6\n\n0 \\to 2 \\to 4 \\to 6\n\nSample Input 2\n\n10 2\n4\n5\n\nSample Output 2\n\n0\n\nThere may be no way to climb up the stairs without setting foot on the broken steps.\n\nSample Input 3\n\n100 5\n1\n23\n45\n67\n89\n\nSample Output 3\n\n608200469\n\nBe sure to print the count modulo 1\\ 000\\ 000\\ 007.", "sample_input": "6 1\n3\n"}, "reference_outputs": ["4\n"], "source_document_id": "p03013", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere is a staircase with N steps. Takahashi is now standing at the foot of the stairs, that is, on the 0-th step.\nHe can climb up one or two steps at a time.\n\nHowever, the treads of the a_1-th, a_2-th, a_3-th, \\ldots, a_M-th steps are broken, so it is dangerous to set foot on those steps.\n\nHow many are there to climb up to the top step, that is, the N-th step, without setting foot on the broken steps?\nFind the count modulo 1\\ 000\\ 000\\ 007.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n0 \\leq M \\leq N-1\n\n1 \\leq a_1 < a_2 < ... < a_M \\leq N-1\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\na_1\na_2\n.\n.\n.\na_M\n\nOutput\n\nPrint the number of ways to climb up the stairs under the condition, modulo 1\\ 000\\ 000\\ 007.\n\nSample Input 1\n\n6 1\n3\n\nSample Output 1\n\n4\n\nThere are four ways to climb up the stairs, as follows:\n\n0 \\to 1 \\to 2 \\to 4 \\to 5 \\to 6\n\n0 \\to 1 \\to 2 \\to 4 \\to 6\n\n0 \\to 2 \\to 4 \\to 5 \\to 6\n\n0 \\to 2 \\to 4 \\to 6\n\nSample Input 2\n\n10 2\n4\n5\n\nSample Output 2\n\n0\n\nThere may be no way to climb up the stairs without setting foot on the broken steps.\n\nSample Input 3\n\n100 5\n1\n23\n45\n67\n89\n\nSample Output 3\n\n608200469\n\nBe sure to print the count modulo 1\\ 000\\ 000\\ 007.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 484, "cpu_time_ms": 102, "memory_kb": 1024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s100925528", "group_id": "codeNet:p03013", "input_text": "#include <iostream>\n#include <iomanip>\n#include <cstdio>\n#include <queue>\n#include <cstring>\n#include <vector>\n#include <map>\n#include <algorithm>\n#include <cctype>\n#include <cmath>\n#include <bitset>\n#include <set>\nusing namespace std;\n\n#define REP(i,n) for(int i=0;i<(int)(n);i++)\n#define RREP(i,n) for(int i=n-1;i>=0;i--)\n#define FOR(i,k,n) for(int i=(k);i<(int)(n);i++)\n#define all(i,n) (i),(i+n)\n\nint dx4[4]={1,0,-1,0};\nint dy4[4]={0,-1,0,1};\nint dx8[8]={1,0,-1,1,-1,1,0,-1};\nint dy8[8]={1,1,1,0,0,-1,-1,-1};\n\ntypedef pair<int, int> P;\ntypedef pair<string, int> SP;\ntypedef long long ll;\n\nconst int INF = 1e9;\nconst ll LLINF = 1e18;\nconst int MAX_V = 1e6+1;\nconst ll mod = 1000000007;\n\n// --------------------------------------\nint n, m;\nvector<int> v;\nint main() {\n  cin.tie(0);\n  ios::sync_with_stdio(false);\n\n  cin >> n >> m;\n  vector<bool> v(n + 1, true);\n  REP(i, m) {\n    int a;\n    cin >> a;\n    v[a] = false;\n  }\n\n  vector<int> memo(n + 1, 0);\n  memo[0] = 1;\n  FOR(i, 1, n + 1) {\n    if(v[i]) {\n      if(i == 1) memo[i] = memo[i - 1] % mod;\n      else memo[i] = (memo[i - 1] + memo[i - 2]) % mod;\n    } else {\n      memo[i] = 0;\n    }\n  }\n\n  cout << memo[n] << endl;\n}\n", "language": "C++", "metadata": {"date": 1578633046, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03013.html", "problem_id": "p03013", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03013/input.txt", "sample_output_relpath": "derived/input_output/data/p03013/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03013/C++/s100925528.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s100925528", "user_id": "u502772848"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <iostream>\n#include <iomanip>\n#include <cstdio>\n#include <queue>\n#include <cstring>\n#include <vector>\n#include <map>\n#include <algorithm>\n#include <cctype>\n#include <cmath>\n#include <bitset>\n#include <set>\nusing namespace std;\n\n#define REP(i,n) for(int i=0;i<(int)(n);i++)\n#define RREP(i,n) for(int i=n-1;i>=0;i--)\n#define FOR(i,k,n) for(int i=(k);i<(int)(n);i++)\n#define all(i,n) (i),(i+n)\n\nint dx4[4]={1,0,-1,0};\nint dy4[4]={0,-1,0,1};\nint dx8[8]={1,0,-1,1,-1,1,0,-1};\nint dy8[8]={1,1,1,0,0,-1,-1,-1};\n\ntypedef pair<int, int> P;\ntypedef pair<string, int> SP;\ntypedef long long ll;\n\nconst int INF = 1e9;\nconst ll LLINF = 1e18;\nconst int MAX_V = 1e6+1;\nconst ll mod = 1000000007;\n\n// --------------------------------------\nint n, m;\nvector<int> v;\nint main() {\n  cin.tie(0);\n  ios::sync_with_stdio(false);\n\n  cin >> n >> m;\n  vector<bool> v(n + 1, true);\n  REP(i, m) {\n    int a;\n    cin >> a;\n    v[a] = false;\n  }\n\n  vector<int> memo(n + 1, 0);\n  memo[0] = 1;\n  FOR(i, 1, n + 1) {\n    if(v[i]) {\n      if(i == 1) memo[i] = memo[i - 1] % mod;\n      else memo[i] = (memo[i - 1] + memo[i - 2]) % mod;\n    } else {\n      memo[i] = 0;\n    }\n  }\n\n  cout << memo[n] << endl;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere is a staircase with N steps. Takahashi is now standing at the foot of the stairs, that is, on the 0-th step.\nHe can climb up one or two steps at a time.\n\nHowever, the treads of the a_1-th, a_2-th, a_3-th, \\ldots, a_M-th steps are broken, so it is dangerous to set foot on those steps.\n\nHow many are there to climb up to the top step, that is, the N-th step, without setting foot on the broken steps?\nFind the count modulo 1\\ 000\\ 000\\ 007.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n0 \\leq M \\leq N-1\n\n1 \\leq a_1 < a_2 < ... < a_M \\leq N-1\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\na_1\na_2\n.\n.\n.\na_M\n\nOutput\n\nPrint the number of ways to climb up the stairs under the condition, modulo 1\\ 000\\ 000\\ 007.\n\nSample Input 1\n\n6 1\n3\n\nSample Output 1\n\n4\n\nThere are four ways to climb up the stairs, as follows:\n\n0 \\to 1 \\to 2 \\to 4 \\to 5 \\to 6\n\n0 \\to 1 \\to 2 \\to 4 \\to 6\n\n0 \\to 2 \\to 4 \\to 5 \\to 6\n\n0 \\to 2 \\to 4 \\to 6\n\nSample Input 2\n\n10 2\n4\n5\n\nSample Output 2\n\n0\n\nThere may be no way to climb up the stairs without setting foot on the broken steps.\n\nSample Input 3\n\n100 5\n1\n23\n45\n67\n89\n\nSample Output 3\n\n608200469\n\nBe sure to print the count modulo 1\\ 000\\ 000\\ 007.", "sample_input": "6 1\n3\n"}, "reference_outputs": ["4\n"], "source_document_id": "p03013", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere is a staircase with N steps. Takahashi is now standing at the foot of the stairs, that is, on the 0-th step.\nHe can climb up one or two steps at a time.\n\nHowever, the treads of the a_1-th, a_2-th, a_3-th, \\ldots, a_M-th steps are broken, so it is dangerous to set foot on those steps.\n\nHow many are there to climb up to the top step, that is, the N-th step, without setting foot on the broken steps?\nFind the count modulo 1\\ 000\\ 000\\ 007.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n0 \\leq M \\leq N-1\n\n1 \\leq a_1 < a_2 < ... < a_M \\leq N-1\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\na_1\na_2\n.\n.\n.\na_M\n\nOutput\n\nPrint the number of ways to climb up the stairs under the condition, modulo 1\\ 000\\ 000\\ 007.\n\nSample Input 1\n\n6 1\n3\n\nSample Output 1\n\n4\n\nThere are four ways to climb up the stairs, as follows:\n\n0 \\to 1 \\to 2 \\to 4 \\to 5 \\to 6\n\n0 \\to 1 \\to 2 \\to 4 \\to 6\n\n0 \\to 2 \\to 4 \\to 5 \\to 6\n\n0 \\to 2 \\to 4 \\to 6\n\nSample Input 2\n\n10 2\n4\n5\n\nSample Output 2\n\n0\n\nThere may be no way to climb up the stairs without setting foot on the broken steps.\n\nSample Input 3\n\n100 5\n1\n23\n45\n67\n89\n\nSample Output 3\n\n608200469\n\nBe sure to print the count modulo 1\\ 000\\ 000\\ 007.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1181, "cpu_time_ms": 9, "memory_kb": 640}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s992802621", "group_id": "codeNet:p03013", "input_text": "#include<iostream>\n#include<iomanip>\n#include<string>\n#include<vector>\n#include<stack>\n#include<set>\n#include<map>\n#include<utility>\n#include<algorithm>\n#include<cmath>\n#include<climits>\nusing namespace std;\n\n#define MOD 1000000007;\n\nint main(){\n\tint n, m;\n\tcin >> n >> m;\n\tvector<int> a(m);\n\tfor(int i=0; i<m; i++)\n\t\tcin >> a[i];\n\tvector<long long> dp(n+1);\n\tdp[n]=1;\n\tdp[n-1]=1;\n\tint key=m-1;\n\tfor(int i=n-2; i>=0; i--){\n\t\tdp[i] = (dp[i+1]+dp[i+2])%MOD;\n\t\tif(key>=0 && i==a[key]){\n\t\t\tdp[i] = 0;\n\t\t\tkey--;\n\t\t}\n\t}\n\tcout << dp[0] << endl;\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1560265149, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03013.html", "problem_id": "p03013", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03013/input.txt", "sample_output_relpath": "derived/input_output/data/p03013/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03013/C++/s992802621.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s992802621", "user_id": "u608258653"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include<iostream>\n#include<iomanip>\n#include<string>\n#include<vector>\n#include<stack>\n#include<set>\n#include<map>\n#include<utility>\n#include<algorithm>\n#include<cmath>\n#include<climits>\nusing namespace std;\n\n#define MOD 1000000007;\n\nint main(){\n\tint n, m;\n\tcin >> n >> m;\n\tvector<int> a(m);\n\tfor(int i=0; i<m; i++)\n\t\tcin >> a[i];\n\tvector<long long> dp(n+1);\n\tdp[n]=1;\n\tdp[n-1]=1;\n\tint key=m-1;\n\tfor(int i=n-2; i>=0; i--){\n\t\tdp[i] = (dp[i+1]+dp[i+2])%MOD;\n\t\tif(key>=0 && i==a[key]){\n\t\t\tdp[i] = 0;\n\t\t\tkey--;\n\t\t}\n\t}\n\tcout << dp[0] << endl;\n\treturn 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere is a staircase with N steps. Takahashi is now standing at the foot of the stairs, that is, on the 0-th step.\nHe can climb up one or two steps at a time.\n\nHowever, the treads of the a_1-th, a_2-th, a_3-th, \\ldots, a_M-th steps are broken, so it is dangerous to set foot on those steps.\n\nHow many are there to climb up to the top step, that is, the N-th step, without setting foot on the broken steps?\nFind the count modulo 1\\ 000\\ 000\\ 007.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n0 \\leq M \\leq N-1\n\n1 \\leq a_1 < a_2 < ... < a_M \\leq N-1\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\na_1\na_2\n.\n.\n.\na_M\n\nOutput\n\nPrint the number of ways to climb up the stairs under the condition, modulo 1\\ 000\\ 000\\ 007.\n\nSample Input 1\n\n6 1\n3\n\nSample Output 1\n\n4\n\nThere are four ways to climb up the stairs, as follows:\n\n0 \\to 1 \\to 2 \\to 4 \\to 5 \\to 6\n\n0 \\to 1 \\to 2 \\to 4 \\to 6\n\n0 \\to 2 \\to 4 \\to 5 \\to 6\n\n0 \\to 2 \\to 4 \\to 6\n\nSample Input 2\n\n10 2\n4\n5\n\nSample Output 2\n\n0\n\nThere may be no way to climb up the stairs without setting foot on the broken steps.\n\nSample Input 3\n\n100 5\n1\n23\n45\n67\n89\n\nSample Output 3\n\n608200469\n\nBe sure to print the count modulo 1\\ 000\\ 000\\ 007.", "sample_input": "6 1\n3\n"}, "reference_outputs": ["4\n"], "source_document_id": "p03013", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere is a staircase with N steps. Takahashi is now standing at the foot of the stairs, that is, on the 0-th step.\nHe can climb up one or two steps at a time.\n\nHowever, the treads of the a_1-th, a_2-th, a_3-th, \\ldots, a_M-th steps are broken, so it is dangerous to set foot on those steps.\n\nHow many are there to climb up to the top step, that is, the N-th step, without setting foot on the broken steps?\nFind the count modulo 1\\ 000\\ 000\\ 007.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n0 \\leq M \\leq N-1\n\n1 \\leq a_1 < a_2 < ... < a_M \\leq N-1\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\na_1\na_2\n.\n.\n.\na_M\n\nOutput\n\nPrint the number of ways to climb up the stairs under the condition, modulo 1\\ 000\\ 000\\ 007.\n\nSample Input 1\n\n6 1\n3\n\nSample Output 1\n\n4\n\nThere are four ways to climb up the stairs, as follows:\n\n0 \\to 1 \\to 2 \\to 4 \\to 5 \\to 6\n\n0 \\to 1 \\to 2 \\to 4 \\to 6\n\n0 \\to 2 \\to 4 \\to 5 \\to 6\n\n0 \\to 2 \\to 4 \\to 6\n\nSample Input 2\n\n10 2\n4\n5\n\nSample Output 2\n\n0\n\nThere may be no way to climb up the stairs without setting foot on the broken steps.\n\nSample Input 3\n\n100 5\n1\n23\n45\n67\n89\n\nSample Output 3\n\n608200469\n\nBe sure to print the count modulo 1\\ 000\\ 000\\ 007.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 550, "cpu_time_ms": 29, "memory_kb": 1408}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s896875251", "group_id": "codeNet:p03013", "input_text": "#include \"bits/stdc++.h\"\n\nusing namespace std;\nusing ll = long long;\nconst double pi = acos(-1);\n#define FOR(i,a,b) for (ll i=(a),__last_##i=(b);i<__last_##i;i++)\n#define RFOR(i,a,b) for (ll i=(b)-1,__last_##i=(a);i>=__last_##i;i--)\n#define REP(i,n) FOR(i,0,n)\n#define RREP(i,n) RFOR(i,0,n)\n#define __GET_MACRO3(_1, _2, _3, NAME, ...) NAME\n#define rep(...) __GET_MACRO3(__VA_ARGS__, FOR, REP)(__VA_ARGS__)\n#define rrep(...) __GET_MACRO3(__VA_ARGS__, RFOR, RREP)(__VA_ARGS__)\ntemplate<typename T> ostream& operator<<(ostream& os, const vector<T>& v) {\n\tREP(i, v.size()) { if (i)os << \" \"; os << v[i]; }return os;\n}\ntemplate<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v) {\n\tREP(i, v.size()) { if (i)os << endl; os << v[i]; }return os;\n}\n\nconst ll INF = 1LL << 60;\nll MOD = 1000000007;\nll _MOD = 1000000009;\ndouble EPS = 1e-10;\n\n#define int long long\n\ninline void my_io() {\n\n\tstd::ios::sync_with_stdio(false);\n\n\tstd::cin.tie(0);\n\n\tcout << fixed << setprecision(16);\n\n\t//cout << setprecision(10) << scientific << ans << endl;\n\n}\n\nsigned main() {\n\tll n, m;\n\tll ans = INF;\n\n\tcin >> n >> m;\n\n\tvector<ll> v(m, 0);\n\n\tREP(i, m) {\n\t\tcin >> v[i];\n\t}\n\n\tvector<ll> dp(n + 1, 0);\n\n\tREP(i, m) {\n\t\tdp[v[i]] = -1;\n\t}\n\n\tdp[0] = 1;\n\n\tFOR(i, 1, n + 1) {\n\t\tif (dp[i] == -1) {\n\t\t\tcontinue;\n\t\t}\n\n\t\tif (dp[i - 1] != -1) {\n\t\t\tdp[i] += dp[i - 1];\n\t\t\tdp[i] %= MOD;\n\t\t}\n\t\tif (i > 1 && dp[i - 2] != -1) {\n\t\t\tdp[i] += dp[i - 2];\n\t\t\tdp[i] %= MOD;\n\t\t}\n\t}\n\n\tcout << dp[n] % MOD << endl;\n}", "language": "C++", "metadata": {"date": 1560129202, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03013.html", "problem_id": "p03013", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03013/input.txt", "sample_output_relpath": "derived/input_output/data/p03013/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03013/C++/s896875251.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s896875251", "user_id": "u800551451"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include \"bits/stdc++.h\"\n\nusing namespace std;\nusing ll = long long;\nconst double pi = acos(-1);\n#define FOR(i,a,b) for (ll i=(a),__last_##i=(b);i<__last_##i;i++)\n#define RFOR(i,a,b) for (ll i=(b)-1,__last_##i=(a);i>=__last_##i;i--)\n#define REP(i,n) FOR(i,0,n)\n#define RREP(i,n) RFOR(i,0,n)\n#define __GET_MACRO3(_1, _2, _3, NAME, ...) NAME\n#define rep(...) __GET_MACRO3(__VA_ARGS__, FOR, REP)(__VA_ARGS__)\n#define rrep(...) __GET_MACRO3(__VA_ARGS__, RFOR, RREP)(__VA_ARGS__)\ntemplate<typename T> ostream& operator<<(ostream& os, const vector<T>& v) {\n\tREP(i, v.size()) { if (i)os << \" \"; os << v[i]; }return os;\n}\ntemplate<typename T> ostream& operator<<(ostream& os, const vector<vector<T>>& v) {\n\tREP(i, v.size()) { if (i)os << endl; os << v[i]; }return os;\n}\n\nconst ll INF = 1LL << 60;\nll MOD = 1000000007;\nll _MOD = 1000000009;\ndouble EPS = 1e-10;\n\n#define int long long\n\ninline void my_io() {\n\n\tstd::ios::sync_with_stdio(false);\n\n\tstd::cin.tie(0);\n\n\tcout << fixed << setprecision(16);\n\n\t//cout << setprecision(10) << scientific << ans << endl;\n\n}\n\nsigned main() {\n\tll n, m;\n\tll ans = INF;\n\n\tcin >> n >> m;\n\n\tvector<ll> v(m, 0);\n\n\tREP(i, m) {\n\t\tcin >> v[i];\n\t}\n\n\tvector<ll> dp(n + 1, 0);\n\n\tREP(i, m) {\n\t\tdp[v[i]] = -1;\n\t}\n\n\tdp[0] = 1;\n\n\tFOR(i, 1, n + 1) {\n\t\tif (dp[i] == -1) {\n\t\t\tcontinue;\n\t\t}\n\n\t\tif (dp[i - 1] != -1) {\n\t\t\tdp[i] += dp[i - 1];\n\t\t\tdp[i] %= MOD;\n\t\t}\n\t\tif (i > 1 && dp[i - 2] != -1) {\n\t\t\tdp[i] += dp[i - 2];\n\t\t\tdp[i] %= MOD;\n\t\t}\n\t}\n\n\tcout << dp[n] % MOD << endl;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere is a staircase with N steps. Takahashi is now standing at the foot of the stairs, that is, on the 0-th step.\nHe can climb up one or two steps at a time.\n\nHowever, the treads of the a_1-th, a_2-th, a_3-th, \\ldots, a_M-th steps are broken, so it is dangerous to set foot on those steps.\n\nHow many are there to climb up to the top step, that is, the N-th step, without setting foot on the broken steps?\nFind the count modulo 1\\ 000\\ 000\\ 007.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n0 \\leq M \\leq N-1\n\n1 \\leq a_1 < a_2 < ... < a_M \\leq N-1\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\na_1\na_2\n.\n.\n.\na_M\n\nOutput\n\nPrint the number of ways to climb up the stairs under the condition, modulo 1\\ 000\\ 000\\ 007.\n\nSample Input 1\n\n6 1\n3\n\nSample Output 1\n\n4\n\nThere are four ways to climb up the stairs, as follows:\n\n0 \\to 1 \\to 2 \\to 4 \\to 5 \\to 6\n\n0 \\to 1 \\to 2 \\to 4 \\to 6\n\n0 \\to 2 \\to 4 \\to 5 \\to 6\n\n0 \\to 2 \\to 4 \\to 6\n\nSample Input 2\n\n10 2\n4\n5\n\nSample Output 2\n\n0\n\nThere may be no way to climb up the stairs without setting foot on the broken steps.\n\nSample Input 3\n\n100 5\n1\n23\n45\n67\n89\n\nSample Output 3\n\n608200469\n\nBe sure to print the count modulo 1\\ 000\\ 000\\ 007.", "sample_input": "6 1\n3\n"}, "reference_outputs": ["4\n"], "source_document_id": "p03013", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere is a staircase with N steps. Takahashi is now standing at the foot of the stairs, that is, on the 0-th step.\nHe can climb up one or two steps at a time.\n\nHowever, the treads of the a_1-th, a_2-th, a_3-th, \\ldots, a_M-th steps are broken, so it is dangerous to set foot on those steps.\n\nHow many are there to climb up to the top step, that is, the N-th step, without setting foot on the broken steps?\nFind the count modulo 1\\ 000\\ 000\\ 007.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n0 \\leq M \\leq N-1\n\n1 \\leq a_1 < a_2 < ... < a_M \\leq N-1\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\na_1\na_2\n.\n.\n.\na_M\n\nOutput\n\nPrint the number of ways to climb up the stairs under the condition, modulo 1\\ 000\\ 000\\ 007.\n\nSample Input 1\n\n6 1\n3\n\nSample Output 1\n\n4\n\nThere are four ways to climb up the stairs, as follows:\n\n0 \\to 1 \\to 2 \\to 4 \\to 5 \\to 6\n\n0 \\to 1 \\to 2 \\to 4 \\to 6\n\n0 \\to 2 \\to 4 \\to 5 \\to 6\n\n0 \\to 2 \\to 4 \\to 6\n\nSample Input 2\n\n10 2\n4\n5\n\nSample Output 2\n\n0\n\nThere may be no way to climb up the stairs without setting foot on the broken steps.\n\nSample Input 3\n\n100 5\n1\n23\n45\n67\n89\n\nSample Output 3\n\n608200469\n\nBe sure to print the count modulo 1\\ 000\\ 000\\ 007.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1481, "cpu_time_ms": 29, "memory_kb": 1792}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s003406685", "group_id": "codeNet:p03017", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n  ios::sync_with_stdio(0);\n  cin.tie(0);\n  cout.tie(0);\n  int n, a, b, c, d;\n  cin >> n >> a >> b >> c >> d;\n  --a, --b, --c, --d;\n  string t;\n  cin >> t;\n  auto reachable = [&](int s, int f) {\n    if (t[s] == '#' || t[f] == '#') return false;\n    for (int i = s + 1; i <= f; ++i) {\n      if (t[i] == t[i - 1] && t[i] == '#') {\n        return false;\n      }\n    }\n    return true;\n  };\n  auto hasg3 = [&](int s, int f) {\n    for (int i = s; i <= f - 2; ++i) {\n      if (t[i] == t[i + 1] && t[i] == t[i + 2] && t[i] == '.') {\n        return true;\n      }\n    }\n    return false;\n  };\n  bool can = true;\n  if (!reachable(a, c) || !reachable(b, d)) {\n    can = false;\n  }\n  if (c > d) {\n    if (!hasg3(b - 1, d + 1)) {\n      can = false;\n    }\n  }\n  cout << (can ? \"Yes\" : \"No\") << endl;\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1570195663, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03017.html", "problem_id": "p03017", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03017/input.txt", "sample_output_relpath": "derived/input_output/data/p03017/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03017/C++/s003406685.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s003406685", "user_id": "u499656581"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n  ios::sync_with_stdio(0);\n  cin.tie(0);\n  cout.tie(0);\n  int n, a, b, c, d;\n  cin >> n >> a >> b >> c >> d;\n  --a, --b, --c, --d;\n  string t;\n  cin >> t;\n  auto reachable = [&](int s, int f) {\n    if (t[s] == '#' || t[f] == '#') return false;\n    for (int i = s + 1; i <= f; ++i) {\n      if (t[i] == t[i - 1] && t[i] == '#') {\n        return false;\n      }\n    }\n    return true;\n  };\n  auto hasg3 = [&](int s, int f) {\n    for (int i = s; i <= f - 2; ++i) {\n      if (t[i] == t[i + 1] && t[i] == t[i + 2] && t[i] == '.') {\n        return true;\n      }\n    }\n    return false;\n  };\n  bool can = true;\n  if (!reachable(a, c) || !reachable(b, d)) {\n    can = false;\n  }\n  if (c > d) {\n    if (!hasg3(b - 1, d + 1)) {\n      can = false;\n    }\n  }\n  cout << (can ? \"Yes\" : \"No\") << endl;\n  return 0;\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nThere are N squares arranged in a row, numbered 1, 2, ..., N from left to right.\nYou are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.\n\nIn the beginning, Snuke stands on Square A, and Fnuke stands on Square B.\n\nYou can repeat the following operation any number of times:\n\nChoose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.\n\nYou want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.\n\nDetermine whether this is possible.\n\nConstraints\n\n4 \\leq N \\leq 200\\ 000\n\nS is a string of length N consisting of . and #.\n\n1 \\leq A, B, C, D \\leq N\n\nSquare A, B, C and D do not contain a rock.\n\nA, B, C and D are all different.\n\nA < B\n\nA < C\n\nB < D\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN A B C D\nS\n\nOutput\n\nPrint Yes if the objective is achievable, and No if it is not.\n\nSample Input 1\n\n7 1 3 6 7\n.#..#..\n\nSample Output 1\n\nYes\n\nThe objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)\n\nA#B.#..\n\nA#.B#..\n\n.#AB#..\n\n.#A.#B.\n\n.#.A#B.\n\n.#.A#.B\n\n.#..#AB\n\nSample Input 2\n\n7 1 3 7 6\n.#..#..\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n15 1 3 15 13\n...#.#...#.#...\n\nSample Output 3\n\nYes", "sample_input": "7 1 3 6 7\n.#..#..\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p03017", "source_text": "Score : 400 points\n\nProblem Statement\n\nThere are N squares arranged in a row, numbered 1, 2, ..., N from left to right.\nYou are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.\n\nIn the beginning, Snuke stands on Square A, and Fnuke stands on Square B.\n\nYou can repeat the following operation any number of times:\n\nChoose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.\n\nYou want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.\n\nDetermine whether this is possible.\n\nConstraints\n\n4 \\leq N \\leq 200\\ 000\n\nS is a string of length N consisting of . and #.\n\n1 \\leq A, B, C, D \\leq N\n\nSquare A, B, C and D do not contain a rock.\n\nA, B, C and D are all different.\n\nA < B\n\nA < C\n\nB < D\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN A B C D\nS\n\nOutput\n\nPrint Yes if the objective is achievable, and No if it is not.\n\nSample Input 1\n\n7 1 3 6 7\n.#..#..\n\nSample Output 1\n\nYes\n\nThe objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)\n\nA#B.#..\n\nA#.B#..\n\n.#AB#..\n\n.#A.#B.\n\n.#.A#B.\n\n.#.A#.B\n\n.#..#AB\n\nSample Input 2\n\n7 1 3 7 6\n.#..#..\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n15 1 3 15 13\n...#.#...#.#...\n\nSample Output 3\n\nYes", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 859, "cpu_time_ms": 3, "memory_kb": 592}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s772625282", "group_id": "codeNet:p03017", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  int N, A, B, C, D;\n  string S;\n  \n  cin >> N >> A >> B >> C >> D;\n  cin >> S;\n  \n  vector<int> rock;\n  vector<int> jump;\n  \n  for(int i=0; i<N-1; i++){\n    \n    if(S.at(i) == '#' && S.at(i+1) == '#')\n      rock.push_back(i+1);\n\n    if(i != 0){\n      if(S.at(i-1) == '.' && S.at(i) == '.' && S.at(i+1) == '.')\n        jump.push_back(i+1);\n    }\n  \n  }\n  \n\n  bool flag = false;\n\n  for(int i=0; i<rock.size(); i++){\n    \n    if(rock.at(i) > A && rock.at(i) < C){\n      flag = true; break;\n    }\n    if(rock.at(i) > B && rock.at(i) < D){\n      flag = true; break;\n    }\n  \n  }\n  \n  if(C > D){\n    //入れ替えが必要\n    flag = true;\n    for(int i=0; i<jump.size(); i++){\n      \n      if(jump.at(i) > B && jump.at(i) <= D){\n        flag = false; break;\n      }\n    \n    }\n  \n  }\n\n  \n  if(flag)\n    cout << \"No\" << endl;\n  else\n    cout << \"Yes\" << endl;\n\n}", "language": "C++", "metadata": {"date": 1563081710, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03017.html", "problem_id": "p03017", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03017/input.txt", "sample_output_relpath": "derived/input_output/data/p03017/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03017/C++/s772625282.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s772625282", "user_id": "u879434320"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  int N, A, B, C, D;\n  string S;\n  \n  cin >> N >> A >> B >> C >> D;\n  cin >> S;\n  \n  vector<int> rock;\n  vector<int> jump;\n  \n  for(int i=0; i<N-1; i++){\n    \n    if(S.at(i) == '#' && S.at(i+1) == '#')\n      rock.push_back(i+1);\n\n    if(i != 0){\n      if(S.at(i-1) == '.' && S.at(i) == '.' && S.at(i+1) == '.')\n        jump.push_back(i+1);\n    }\n  \n  }\n  \n\n  bool flag = false;\n\n  for(int i=0; i<rock.size(); i++){\n    \n    if(rock.at(i) > A && rock.at(i) < C){\n      flag = true; break;\n    }\n    if(rock.at(i) > B && rock.at(i) < D){\n      flag = true; break;\n    }\n  \n  }\n  \n  if(C > D){\n    //入れ替えが必要\n    flag = true;\n    for(int i=0; i<jump.size(); i++){\n      \n      if(jump.at(i) > B && jump.at(i) <= D){\n        flag = false; break;\n      }\n    \n    }\n  \n  }\n\n  \n  if(flag)\n    cout << \"No\" << endl;\n  else\n    cout << \"Yes\" << endl;\n\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nThere are N squares arranged in a row, numbered 1, 2, ..., N from left to right.\nYou are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.\n\nIn the beginning, Snuke stands on Square A, and Fnuke stands on Square B.\n\nYou can repeat the following operation any number of times:\n\nChoose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.\n\nYou want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.\n\nDetermine whether this is possible.\n\nConstraints\n\n4 \\leq N \\leq 200\\ 000\n\nS is a string of length N consisting of . and #.\n\n1 \\leq A, B, C, D \\leq N\n\nSquare A, B, C and D do not contain a rock.\n\nA, B, C and D are all different.\n\nA < B\n\nA < C\n\nB < D\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN A B C D\nS\n\nOutput\n\nPrint Yes if the objective is achievable, and No if it is not.\n\nSample Input 1\n\n7 1 3 6 7\n.#..#..\n\nSample Output 1\n\nYes\n\nThe objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)\n\nA#B.#..\n\nA#.B#..\n\n.#AB#..\n\n.#A.#B.\n\n.#.A#B.\n\n.#.A#.B\n\n.#..#AB\n\nSample Input 2\n\n7 1 3 7 6\n.#..#..\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n15 1 3 15 13\n...#.#...#.#...\n\nSample Output 3\n\nYes", "sample_input": "7 1 3 6 7\n.#..#..\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p03017", "source_text": "Score : 400 points\n\nProblem Statement\n\nThere are N squares arranged in a row, numbered 1, 2, ..., N from left to right.\nYou are given a string S of length N consisting of . and #. If the i-th character of S is #, Square i contains a rock; if the i-th character of S is ., Square i is empty.\n\nIn the beginning, Snuke stands on Square A, and Fnuke stands on Square B.\n\nYou can repeat the following operation any number of times:\n\nChoose Snuke or Fnuke, and make him jump one or two squares to the right. The destination must be one of the squares, and it must not contain a rock or the other person.\n\nYou want to repeat this operation so that Snuke will stand on Square C and Fnuke will stand on Square D.\n\nDetermine whether this is possible.\n\nConstraints\n\n4 \\leq N \\leq 200\\ 000\n\nS is a string of length N consisting of . and #.\n\n1 \\leq A, B, C, D \\leq N\n\nSquare A, B, C and D do not contain a rock.\n\nA, B, C and D are all different.\n\nA < B\n\nA < C\n\nB < D\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN A B C D\nS\n\nOutput\n\nPrint Yes if the objective is achievable, and No if it is not.\n\nSample Input 1\n\n7 1 3 6 7\n.#..#..\n\nSample Output 1\n\nYes\n\nThe objective is achievable by, for example, moving the two persons as follows. (A and B represent Snuke and Fnuke, respectively.)\n\nA#B.#..\n\nA#.B#..\n\n.#AB#..\n\n.#A.#B.\n\n.#.A#B.\n\n.#.A#.B\n\n.#..#AB\n\nSample Input 2\n\n7 1 3 7 6\n.#..#..\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n15 1 3 15 13\n...#.#...#.#...\n\nSample Output 3\n\nYes", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 917, "cpu_time_ms": 9, "memory_kb": 640}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s300542037", "group_id": "codeNet:p03019", "input_text": "#include <iostream>\n#include <cassert>\n#include <climits>\n#include <bitset>\n#include <stack>\n#include <queue>\n#include <iomanip>\n#include <limits>\n#include <string>\n#include <cmath>\n#include <set>\n#include <map>\n#include <math.h>\n#include <algorithm>\n#include <vector>\n#include <string.h>\n#include <tuple>\n#include <time.h>\n#include <random>\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair<ll,ll> P;\n\nlong long int INF = 3e18;\ndouble Pi = 3.1415926535897932384626;\n\nvector<ll> G[500005];\n//vector<P> tree[500010];\npriority_queue <ll> pql;\npriority_queue <P> pqp;\n//big priority queue\npriority_queue <ll,vector<ll>,greater<ll> > pqls;\npriority_queue <P,vector<P>,greater<P> > pqps;\n//small priority queue\n//top pop\n\nint dx[8]={1,0,-1,0,1,1,-1,-1};\nint dy[8]={0,1,0,-1,1,-1,-1,1};\nchar dir[] = \"DRUL\";\n//ll bit[500005];\n//↓,→,↑,←\n\n\n#define p(x) cout<<x<<endl;\n#define el cout<<endl;\n#define pe(x) cout<<(x)<<\" \";\n#define ps(x) cout<<fixed<<setprecision(25)<<x<<endl;\n#define pu(x) cout<<(x);\n#define pb push_back\n#define lb lower_bound\n#define ub upper_bound\n#define deba(x) cout<< #x << \" = \" << x <<endl\n\n\nll mod = 1000003;\nll rui(ll number1,ll number2){\n\n    if(number2 == 0){\n        return 1;\n    }else{\n        ll number3 = rui(number1,number2 / 2);\n        number3 *= number3;\n        number3 %= mod;\n        if(number2%2==1){\n            number3 *= number1;\n            number3 %= mod;\n        }\n        return number3;\n    }\n}\nll gcd(ll number1,ll number2){\n\n    if(number1 > number2){\n        swap(number1,number2);\n    }\n    if(number1 == 0 || number1 == number2){\n        return number2;\n    }else{\n        return gcd(number2 % number1,number1);\n    }\n}\nvoid YES(bool condition){\n\n    if(condition){\n        p(\"YES\");\n    }else{\n        p(\"NO\");\n    }\n    return;\n}\nvoid Yes(bool condition){\n\n    if(condition){\n        p(\"Yes\");\n    }else{\n        p(\"No\");\n    }\n    return;\n}\n\n/*\nvoid c3_init(){\n    fact[0] = rfact[0] = 1;\n    for(ll i=1; i<=800000; i++){\n        fact[i] = (fact[i-1]*i) % mod;\n    }\n\trfact[800000] = rui(fact[800000],mod - 2);\n\tfor(ll i=800000; i>=1; i--){\n\t   rfact[i-1] = rfact[i] * i;\n\t   rfact[i-1] %= mod;\n\t}\n\treturn;}\nll c3(ll n,ll r){\n    return (((fact[n] * rfact[r]) % mod) * rfact[n-r]) % mod;}\n*/\n\nll n,m,num,sum,ans,a,b,c,d,e,g,h,w,i,j,k,q,l,r;\nll x[500005],y[500005],z[500005];\nchar s[500005],t[500005];\n//bool used[500005];\nbool flag,dame;\nP table[500005];\n\n\nint main(){\n\tcin >> n >> k;\n    for(i=0;i<n;i++){\n        cin >> x[i] >> y[i] >> z[i];\n    }\n    for(i=0;i<n;i++){\n        ll buppa,sabo;\n        buppa = z[i] * (k - x[i]);\n        sabo = y[i] * x[i];\n        table[i].first = buppa + sabo;\n        sum -= sabo;\n        table[i].second = i;\n    }\n    sort(table,table+n);\n    reverse(table,table+n);\n    for(i=0;i<n;i++){\n        if(sum >= 0){\n            p(ans);\n            return 0;\n        }\n        if(sum + table[i].first < 0){\n            ans += k;\n            sum += table[i].first;\n        }else{\n            num = k;\n            for(j=0;j<n;j++){\n                //if(j > i)break;\n                ll idx = table[j].second;\n                if(sum + y[idx] * x[idx] + (k-x[idx]) * z[idx] < 0){\n                    continue;\n                }else if(sum + y[idx] * x[idx] >= 0){\n                    sum *= -1;\n                    num = min(num,(sum + y[idx] - 1) / y[idx]);\n                    sum *= -1;\n                }else{\n                    sum += y[idx] * x[idx];\n                    a = x[idx];\n                    sum *= -1;\n                    num = min(num,a + ((sum + z[idx] - 1) / z[idx]));\n                    sum *= -1;\n                    sum -= y[idx] * x[idx];\n                }\n            }\n            ans += num;\n            p(ans);\n            return 0;\n        }   \n    }\n\n\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1559530760, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03019.html", "problem_id": "p03019", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03019/input.txt", "sample_output_relpath": "derived/input_output/data/p03019/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03019/C++/s300542037.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s300542037", "user_id": "u399527088"}, "prompt_components": {"gold_output": "115\n", "input_to_evaluate": "#include <iostream>\n#include <cassert>\n#include <climits>\n#include <bitset>\n#include <stack>\n#include <queue>\n#include <iomanip>\n#include <limits>\n#include <string>\n#include <cmath>\n#include <set>\n#include <map>\n#include <math.h>\n#include <algorithm>\n#include <vector>\n#include <string.h>\n#include <tuple>\n#include <time.h>\n#include <random>\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair<ll,ll> P;\n\nlong long int INF = 3e18;\ndouble Pi = 3.1415926535897932384626;\n\nvector<ll> G[500005];\n//vector<P> tree[500010];\npriority_queue <ll> pql;\npriority_queue <P> pqp;\n//big priority queue\npriority_queue <ll,vector<ll>,greater<ll> > pqls;\npriority_queue <P,vector<P>,greater<P> > pqps;\n//small priority queue\n//top pop\n\nint dx[8]={1,0,-1,0,1,1,-1,-1};\nint dy[8]={0,1,0,-1,1,-1,-1,1};\nchar dir[] = \"DRUL\";\n//ll bit[500005];\n//↓,→,↑,←\n\n\n#define p(x) cout<<x<<endl;\n#define el cout<<endl;\n#define pe(x) cout<<(x)<<\" \";\n#define ps(x) cout<<fixed<<setprecision(25)<<x<<endl;\n#define pu(x) cout<<(x);\n#define pb push_back\n#define lb lower_bound\n#define ub upper_bound\n#define deba(x) cout<< #x << \" = \" << x <<endl\n\n\nll mod = 1000003;\nll rui(ll number1,ll number2){\n\n    if(number2 == 0){\n        return 1;\n    }else{\n        ll number3 = rui(number1,number2 / 2);\n        number3 *= number3;\n        number3 %= mod;\n        if(number2%2==1){\n            number3 *= number1;\n            number3 %= mod;\n        }\n        return number3;\n    }\n}\nll gcd(ll number1,ll number2){\n\n    if(number1 > number2){\n        swap(number1,number2);\n    }\n    if(number1 == 0 || number1 == number2){\n        return number2;\n    }else{\n        return gcd(number2 % number1,number1);\n    }\n}\nvoid YES(bool condition){\n\n    if(condition){\n        p(\"YES\");\n    }else{\n        p(\"NO\");\n    }\n    return;\n}\nvoid Yes(bool condition){\n\n    if(condition){\n        p(\"Yes\");\n    }else{\n        p(\"No\");\n    }\n    return;\n}\n\n/*\nvoid c3_init(){\n    fact[0] = rfact[0] = 1;\n    for(ll i=1; i<=800000; i++){\n        fact[i] = (fact[i-1]*i) % mod;\n    }\n\trfact[800000] = rui(fact[800000],mod - 2);\n\tfor(ll i=800000; i>=1; i--){\n\t   rfact[i-1] = rfact[i] * i;\n\t   rfact[i-1] %= mod;\n\t}\n\treturn;}\nll c3(ll n,ll r){\n    return (((fact[n] * rfact[r]) % mod) * rfact[n-r]) % mod;}\n*/\n\nll n,m,num,sum,ans,a,b,c,d,e,g,h,w,i,j,k,q,l,r;\nll x[500005],y[500005],z[500005];\nchar s[500005],t[500005];\n//bool used[500005];\nbool flag,dame;\nP table[500005];\n\n\nint main(){\n\tcin >> n >> k;\n    for(i=0;i<n;i++){\n        cin >> x[i] >> y[i] >> z[i];\n    }\n    for(i=0;i<n;i++){\n        ll buppa,sabo;\n        buppa = z[i] * (k - x[i]);\n        sabo = y[i] * x[i];\n        table[i].first = buppa + sabo;\n        sum -= sabo;\n        table[i].second = i;\n    }\n    sort(table,table+n);\n    reverse(table,table+n);\n    for(i=0;i<n;i++){\n        if(sum >= 0){\n            p(ans);\n            return 0;\n        }\n        if(sum + table[i].first < 0){\n            ans += k;\n            sum += table[i].first;\n        }else{\n            num = k;\n            for(j=0;j<n;j++){\n                //if(j > i)break;\n                ll idx = table[j].second;\n                if(sum + y[idx] * x[idx] + (k-x[idx]) * z[idx] < 0){\n                    continue;\n                }else if(sum + y[idx] * x[idx] >= 0){\n                    sum *= -1;\n                    num = min(num,(sum + y[idx] - 1) / y[idx]);\n                    sum *= -1;\n                }else{\n                    sum += y[idx] * x[idx];\n                    a = x[idx];\n                    sum *= -1;\n                    num = min(num,a + ((sum + z[idx] - 1) / z[idx]));\n                    sum *= -1;\n                    sum -= y[idx] * x[idx];\n                }\n            }\n            ans += num;\n            p(ans);\n            return 0;\n        }   \n    }\n\n\n\treturn 0;\n}", "problem_context": "Score : 800 points\n\nProblem Statement\n\nTakahashi and Aoki will take N exams numbered 1 to N.\nThey have decided to compete in these exams.\nThe winner will be determined as follows:\n\nFor each exam i, Takahashi decides its importance c_i, which must be an integer between l_i and u_i (inclusive).\n\nLet A be \\sum_{i=1}^{N} c_i \\times (Takahashi's score on Exam i), and B be \\sum_{i=1}^{N} c_i \\times (Aoki's score on Exam i). Takahashi wins if A \\geq B, and Aoki wins if A < B.\n\nTakahashi knows that Aoki will score b_i on Exam i, with his supernatural power.\n\nTakahashi himself, on the other hand, will score 0 on all the exams without studying more. For each hour of study, he can increase his score on some exam by 1. (He can only study for an integer number of hours.)\nHowever, he cannot score more than X on an exam, since the perfect score for all the exams is X.\n\nPrint the minimum number of study hours required for Takahashi to win.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq X \\leq 10^5\n\n0 \\leq b_i \\leq X (1 \\leq i \\leq N)\n\n1 \\leq l_i \\leq u_i \\leq 10^5 (1 \\leq i \\leq N)\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN X\nb_1 l_1 u_1\nb_2 l_2 u_2\n:\nb_N l_N u_N\n\nOutput\n\nPrint the minimum number of study hours required for Takahashi to win.\n\nSample Input 1\n\n2 100\n85 2 3\n60 1 1\n\nSample Output 1\n\n115\n\nOne optimal strategy is as follows:\n\nChoose c_1 = 3, c_2 = 1.\n\nStudy to score 100 on Exam 1 and 15 on Exam 2.\n\nThen, A = 3 \\times 100 + 1 \\times 15 = 315, B = 3 \\times 85 + 1 \\times 60 = 315 and Takahashi will win.\n\nSample Input 2\n\n2 100\n85 2 3\n60 10 10\n\nSample Output 2\n\n77\n\nSample Input 3\n\n1 100000\n31415 2718 2818\n\nSample Output 3\n\n31415\n\nSample Input 4\n\n10 1000\n451 4593 6263\n324 310 6991\n378 1431 7068\n71 1757 9218\n204 3676 4328\n840 6221 9080\n684 1545 8511\n709 5467 8674\n862 6504 9835\n283 4965 9980\n\nSample Output 4\n\n2540", "sample_input": "2 100\n85 2 3\n60 1 1\n"}, "reference_outputs": ["115\n"], "source_document_id": "p03019", "source_text": "Score : 800 points\n\nProblem Statement\n\nTakahashi and Aoki will take N exams numbered 1 to N.\nThey have decided to compete in these exams.\nThe winner will be determined as follows:\n\nFor each exam i, Takahashi decides its importance c_i, which must be an integer between l_i and u_i (inclusive).\n\nLet A be \\sum_{i=1}^{N} c_i \\times (Takahashi's score on Exam i), and B be \\sum_{i=1}^{N} c_i \\times (Aoki's score on Exam i). Takahashi wins if A \\geq B, and Aoki wins if A < B.\n\nTakahashi knows that Aoki will score b_i on Exam i, with his supernatural power.\n\nTakahashi himself, on the other hand, will score 0 on all the exams without studying more. For each hour of study, he can increase his score on some exam by 1. (He can only study for an integer number of hours.)\nHowever, he cannot score more than X on an exam, since the perfect score for all the exams is X.\n\nPrint the minimum number of study hours required for Takahashi to win.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq X \\leq 10^5\n\n0 \\leq b_i \\leq X (1 \\leq i \\leq N)\n\n1 \\leq l_i \\leq u_i \\leq 10^5 (1 \\leq i \\leq N)\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN X\nb_1 l_1 u_1\nb_2 l_2 u_2\n:\nb_N l_N u_N\n\nOutput\n\nPrint the minimum number of study hours required for Takahashi to win.\n\nSample Input 1\n\n2 100\n85 2 3\n60 1 1\n\nSample Output 1\n\n115\n\nOne optimal strategy is as follows:\n\nChoose c_1 = 3, c_2 = 1.\n\nStudy to score 100 on Exam 1 and 15 on Exam 2.\n\nThen, A = 3 \\times 100 + 1 \\times 15 = 315, B = 3 \\times 85 + 1 \\times 60 = 315 and Takahashi will win.\n\nSample Input 2\n\n2 100\n85 2 3\n60 10 10\n\nSample Output 2\n\n77\n\nSample Input 3\n\n1 100000\n31415 2718 2818\n\nSample Output 3\n\n31415\n\nSample Input 4\n\n10 1000\n451 4593 6263\n324 310 6991\n378 1431 7068\n71 1757 9218\n204 3676 4328\n840 6221 9080\n684 1545 8511\n709 5467 8674\n862 6504 9835\n283 4965 9980\n\nSample Output 4\n\n2540", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 3789, "cpu_time_ms": 99, "memory_kb": 19712}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s187190107", "group_id": "codeNet:p03031", "input_text": "#include <iostream>\n#include <string>\n#include <vector>\n#include <queue>\n#include <map>\n#include <algorithm>\n\n#define ll long long\n\nusing namespace std;\n\nvoid next(int array[], int size){\n    for(int i = 1; i <= size; i++){\n        if(array[i] == 0){\n            array[i] = 1;\n            break;\n        }else{\n            array[i] = 0;\n        }\n    }\n}\n\nint main(){\n\n    int n,m;\n    cin >> n >> m;\n    vector<vector<int>> s;\n    vector<int> p;\n\n    for(int i = 0; i < m; i++){\n        int k;\n        cin >> k;\n        vector<int> tmpv;\n        for(int j = 0; j < k; j++){\n            int tmps;\n            cin >> tmps;\n            tmpv.push_back(tmps);\n\n        }\n        s.push_back(tmpv);\n    }\n\n    for(int i = 0; i < m; i++){\n        int tmp;\n        cin >> tmp;\n        p.push_back(tmp);\n    }\n\n    int count = 1;\n\n    for(int i = 0; i < n; i++) count = count * 2;\n\n    int ans = 0;\n    int onoff[11] = {};\n\n    for(int i = 0; i < count; i++){\n        bool b = true;\n\n        \n        for(int j = 1; j <= m; j++){\n            //jは電球の番号\n            int tmpc = 0;\n            vector<int> tmpv = s[j - 1];\n\n            //つながっているスイッチのonの数を数える\n            for(int k = 0; k < tmpv.size(); k++){\n                if(onoff[tmpv[k]] == 1) tmpc++;\n            }\n\n            if(tmpc % 2 != p[j - 1]){\n                b = false;\n                break;\n            }\n        }\n\n        if(b) ans++;\n\n        next(onoff, n);\n    }\n\n    cout << ans << endl;\n\n    return 0;\n\n}", "language": "C++", "metadata": {"date": 1558922048, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03031.html", "problem_id": "p03031", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03031/input.txt", "sample_output_relpath": "derived/input_output/data/p03031/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03031/C++/s187190107.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s187190107", "user_id": "u145078501"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <iostream>\n#include <string>\n#include <vector>\n#include <queue>\n#include <map>\n#include <algorithm>\n\n#define ll long long\n\nusing namespace std;\n\nvoid next(int array[], int size){\n    for(int i = 1; i <= size; i++){\n        if(array[i] == 0){\n            array[i] = 1;\n            break;\n        }else{\n            array[i] = 0;\n        }\n    }\n}\n\nint main(){\n\n    int n,m;\n    cin >> n >> m;\n    vector<vector<int>> s;\n    vector<int> p;\n\n    for(int i = 0; i < m; i++){\n        int k;\n        cin >> k;\n        vector<int> tmpv;\n        for(int j = 0; j < k; j++){\n            int tmps;\n            cin >> tmps;\n            tmpv.push_back(tmps);\n\n        }\n        s.push_back(tmpv);\n    }\n\n    for(int i = 0; i < m; i++){\n        int tmp;\n        cin >> tmp;\n        p.push_back(tmp);\n    }\n\n    int count = 1;\n\n    for(int i = 0; i < n; i++) count = count * 2;\n\n    int ans = 0;\n    int onoff[11] = {};\n\n    for(int i = 0; i < count; i++){\n        bool b = true;\n\n        \n        for(int j = 1; j <= m; j++){\n            //jは電球の番号\n            int tmpc = 0;\n            vector<int> tmpv = s[j - 1];\n\n            //つながっているスイッチのonの数を数える\n            for(int k = 0; k < tmpv.size(); k++){\n                if(onoff[tmpv[k]] == 1) tmpc++;\n            }\n\n            if(tmpc % 2 != p[j - 1]){\n                b = false;\n                break;\n            }\n        }\n\n        if(b) ans++;\n\n        next(onoff, n);\n    }\n\n    cout << ans << endl;\n\n    return 0;\n\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nWe have N switches with \"on\" and \"off\" state, and M bulbs. The switches are numbered 1 to N, and the bulbs are numbered 1 to M.\n\nBulb i is connected to k_i switches: Switch s_{i1}, s_{i2}, ..., and s_{ik_i}. It is lighted when the number of switches that are \"on\" among these switches is congruent to p_i modulo 2.\n\nHow many combinations of \"on\" and \"off\" states of the switches light all the bulbs?\n\nConstraints\n\n1 \\leq N, M \\leq 10\n\n1 \\leq k_i \\leq N\n\n1 \\leq s_{ij} \\leq N\n\ns_{ia} \\neq s_{ib} (a \\neq b)\n\np_i is 0 or 1.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nk_1 s_{11} s_{12} ... s_{1k_1}\n:\nk_M s_{M1} s_{M2} ... s_{Mk_M}\np_1 p_2 ... p_M\n\nOutput\n\nPrint the number of combinations of \"on\" and \"off\" states of the switches that light all the bulbs.\n\nSample Input 1\n\n2 2\n2 1 2\n1 2\n0 1\n\nSample Output 1\n\n1\n\nBulb 1 is lighted when there is an even number of switches that are \"on\" among the following: Switch 1 and 2.\n\nBulb 2 is lighted when there is an odd number of switches that are \"on\" among the following: Switch 2.\n\nThere are four possible combinations of states of (Switch 1, Switch 2): (on, on), (on, off), (off, on) and (off, off). Among them, only (on, on) lights all the bulbs, so we should print 1.\n\nSample Input 2\n\n2 3\n2 1 2\n1 1\n1 2\n0 0 1\n\nSample Output 2\n\n0\n\nBulb 1 is lighted when there is an even number of switches that are \"on\" among the following: Switch 1 and 2.\n\nBulb 2 is lighted when there is an even number of switches that are \"on\" among the following: Switch 1.\n\nBulb 3 is lighted when there is an odd number of switches that are \"on\" among the following: Switch 2.\n\nSwitch 1 has to be \"off\" to light Bulb 2 and Switch 2 has to be \"on\" to light Bulb 3, but then Bulb 1 will not be lighted. Thus, there are no combinations of states of the switches that light all the bulbs, so we should print 0.\n\nSample Input 3\n\n5 2\n3 1 2 5\n2 2 3\n1 0\n\nSample Output 3\n\n8", "sample_input": "2 2\n2 1 2\n1 2\n0 1\n"}, "reference_outputs": ["1\n"], "source_document_id": "p03031", "source_text": "Score : 300 points\n\nProblem Statement\n\nWe have N switches with \"on\" and \"off\" state, and M bulbs. The switches are numbered 1 to N, and the bulbs are numbered 1 to M.\n\nBulb i is connected to k_i switches: Switch s_{i1}, s_{i2}, ..., and s_{ik_i}. It is lighted when the number of switches that are \"on\" among these switches is congruent to p_i modulo 2.\n\nHow many combinations of \"on\" and \"off\" states of the switches light all the bulbs?\n\nConstraints\n\n1 \\leq N, M \\leq 10\n\n1 \\leq k_i \\leq N\n\n1 \\leq s_{ij} \\leq N\n\ns_{ia} \\neq s_{ib} (a \\neq b)\n\np_i is 0 or 1.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nk_1 s_{11} s_{12} ... s_{1k_1}\n:\nk_M s_{M1} s_{M2} ... s_{Mk_M}\np_1 p_2 ... p_M\n\nOutput\n\nPrint the number of combinations of \"on\" and \"off\" states of the switches that light all the bulbs.\n\nSample Input 1\n\n2 2\n2 1 2\n1 2\n0 1\n\nSample Output 1\n\n1\n\nBulb 1 is lighted when there is an even number of switches that are \"on\" among the following: Switch 1 and 2.\n\nBulb 2 is lighted when there is an odd number of switches that are \"on\" among the following: Switch 2.\n\nThere are four possible combinations of states of (Switch 1, Switch 2): (on, on), (on, off), (off, on) and (off, off). Among them, only (on, on) lights all the bulbs, so we should print 1.\n\nSample Input 2\n\n2 3\n2 1 2\n1 1\n1 2\n0 0 1\n\nSample Output 2\n\n0\n\nBulb 1 is lighted when there is an even number of switches that are \"on\" among the following: Switch 1 and 2.\n\nBulb 2 is lighted when there is an even number of switches that are \"on\" among the following: Switch 1.\n\nBulb 3 is lighted when there is an odd number of switches that are \"on\" among the following: Switch 2.\n\nSwitch 1 has to be \"off\" to light Bulb 2 and Switch 2 has to be \"on\" to light Bulb 3, but then Bulb 1 will not be lighted. Thus, there are no combinations of states of the switches that light all the bulbs, so we should print 0.\n\nSample Input 3\n\n5 2\n3 1 2 5\n2 2 3\n1 0\n\nSample Output 3\n\n8", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1516, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s382409153", "group_id": "codeNet:p03036", "input_text": "#include <bits/stdc++.h>\n#define rep(i,n) for (int i = 0; i < (n); i++)\nusing namespace std;\nusing ll = long long;\n\nint main(){\n  int r,D,x;\n  cin >>r >>D >>x;\n  rep(i,10){\n    x = r*x - D;\n    cout << x << endl;\n  }\n  return 0;\n}", "language": "C++", "metadata": {"date": 1585947238, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03036.html", "problem_id": "p03036", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03036/input.txt", "sample_output_relpath": "derived/input_output/data/p03036/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03036/C++/s382409153.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s382409153", "user_id": "u321168841"}, "prompt_components": {"gold_output": "30\n50\n90\n170\n330\n650\n1290\n2570\n5130\n10250\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define rep(i,n) for (int i = 0; i < (n); i++)\nusing namespace std;\nusing ll = long long;\n\nint main(){\n  int r,D,x;\n  cin >>r >>D >>x;\n  rep(i,10){\n    x = r*x - D;\n    cout << x << endl;\n  }\n  return 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nThe development of algae in a pond is as follows.\n\nLet the total weight of the algae at the beginning of the year i be x_i gram. For i≥2000, the following formula holds:\n\nx_{i+1} = rx_i - D\n\nYou are given r, D and x_{2000}. Calculate x_{2001}, ..., x_{2010} and print them in order.\n\nConstraints\n\n2 ≤ r ≤ 5\n\n1 ≤ D ≤ 100\n\nD < x_{2000} ≤ 200\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nr D x_{2000}\n\nOutput\n\nPrint 10 lines. The i-th line (1 ≤ i ≤ 10) should contain x_{2000+i} as an integer.\n\nSample Input 1\n\n2 10 20\n\nSample Output 1\n\n30\n50\n90\n170\n330\n650\n1290\n2570\n5130\n10250\n\nFor example, x_{2001} = rx_{2000} - D = 2 \\times 20 - 10 = 30 and x_{2002} = rx_{2001} - D = 2 \\times 30 - 10 = 50.\n\nSample Input 2\n\n4 40 60\n\nSample Output 2\n\n200\n760\n3000\n11960\n47800\n191160\n764600\n3058360\n12233400\n48933560", "sample_input": "2 10 20\n"}, "reference_outputs": ["30\n50\n90\n170\n330\n650\n1290\n2570\n5130\n10250\n"], "source_document_id": "p03036", "source_text": "Score : 200 points\n\nProblem Statement\n\nThe development of algae in a pond is as follows.\n\nLet the total weight of the algae at the beginning of the year i be x_i gram. For i≥2000, the following formula holds:\n\nx_{i+1} = rx_i - D\n\nYou are given r, D and x_{2000}. Calculate x_{2001}, ..., x_{2010} and print them in order.\n\nConstraints\n\n2 ≤ r ≤ 5\n\n1 ≤ D ≤ 100\n\nD < x_{2000} ≤ 200\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nr D x_{2000}\n\nOutput\n\nPrint 10 lines. The i-th line (1 ≤ i ≤ 10) should contain x_{2000+i} as an integer.\n\nSample Input 1\n\n2 10 20\n\nSample Output 1\n\n30\n50\n90\n170\n330\n650\n1290\n2570\n5130\n10250\n\nFor example, x_{2001} = rx_{2000} - D = 2 \\times 20 - 10 = 30 and x_{2002} = rx_{2001} - D = 2 \\times 30 - 10 = 50.\n\nSample Input 2\n\n4 40 60\n\nSample Output 2\n\n200\n760\n3000\n11960\n47800\n191160\n764600\n3058360\n12233400\n48933560", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 230, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s852097363", "group_id": "codeNet:p03037", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n  int n, m;\n  cin >> n >> m;\n  vector<int> l(m), r(m);\n  for(int i=0; i<m; i++) {\n    cin >> l.at(i) >> r.at(i);\n  }\n  \n  int L = l.at(0);\n  int R = r.at(0);\n  \n  for(int i=0; i<m; i++) {\n    L = max(L, l.at(i));\n    R = min(R, r.at(i));\n  }\n  if(R >= L) {\n    cout << R - L + 1 << endl;\n  }\n  else {\n    cout << 0 << endl;\n  }\n}", "language": "C++", "metadata": {"date": 1578803886, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03037.html", "problem_id": "p03037", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03037/input.txt", "sample_output_relpath": "derived/input_output/data/p03037/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03037/C++/s852097363.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s852097363", "user_id": "u438313904"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n  int n, m;\n  cin >> n >> m;\n  vector<int> l(m), r(m);\n  for(int i=0; i<m; i++) {\n    cin >> l.at(i) >> r.at(i);\n  }\n  \n  int L = l.at(0);\n  int R = r.at(0);\n  \n  for(int i=0; i<m; i++) {\n    L = max(L, l.at(i));\n    R = min(R, r.at(i));\n  }\n  if(R >= L) {\n    cout << R - L + 1 << endl;\n  }\n  else {\n    cout << 0 << endl;\n  }\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nWe have N ID cards, and there are M gates.\n\nWe can pass the i-th gate if we have one of the following ID cards: the L_i-th, (L_i+1)-th, ..., and R_i-th ID cards.\n\nHow many of the ID cards allow us to pass all the gates alone?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq L_i \\leq R_i \\leq N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nL_1 R_1\nL_2 R_2\n\\vdots\nL_M R_M\n\nOutput\n\nPrint the number of ID cards that allow us to pass all the gates alone.\n\nSample Input 1\n\n4 2\n1 3\n2 4\n\nSample Output 1\n\n2\n\nTwo ID cards allow us to pass all the gates alone, as follows:\n\nThe first ID card does not allow us to pass the second gate.\n\nThe second ID card allows us to pass all the gates.\n\nThe third ID card allows us to pass all the gates.\n\nThe fourth ID card does not allow us to pass the first gate.\n\nSample Input 2\n\n10 3\n3 6\n5 7\n6 9\n\nSample Output 2\n\n1\n\nSample Input 3\n\n100000 1\n1 100000\n\nSample Output 3\n\n100000", "sample_input": "4 2\n1 3\n2 4\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03037", "source_text": "Score : 300 points\n\nProblem Statement\n\nWe have N ID cards, and there are M gates.\n\nWe can pass the i-th gate if we have one of the following ID cards: the L_i-th, (L_i+1)-th, ..., and R_i-th ID cards.\n\nHow many of the ID cards allow us to pass all the gates alone?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq L_i \\leq R_i \\leq N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nL_1 R_1\nL_2 R_2\n\\vdots\nL_M R_M\n\nOutput\n\nPrint the number of ID cards that allow us to pass all the gates alone.\n\nSample Input 1\n\n4 2\n1 3\n2 4\n\nSample Output 1\n\n2\n\nTwo ID cards allow us to pass all the gates alone, as follows:\n\nThe first ID card does not allow us to pass the second gate.\n\nThe second ID card allows us to pass all the gates.\n\nThe third ID card allows us to pass all the gates.\n\nThe fourth ID card does not allow us to pass the first gate.\n\nSample Input 2\n\n10 3\n3 6\n5 7\n6 9\n\nSample Output 2\n\n1\n\nSample Input 3\n\n100000 1\n1 100000\n\nSample Output 3\n\n100000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 389, "cpu_time_ms": 56, "memory_kb": 1024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s590265946", "group_id": "codeNet:p03037", "input_text": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint main() {\n    int n,m;\n    int t[100002] = {};\n    cin >> n >> m;\n    for(int i=0;i<m;++i) {\n        int l, r;\n        cin >> l >> r;\n        t[l-1]++;\n        t[r]--;\n    }\n    int ans = 0;\n    for(int i=0;i<n;++i) {\n        if(t[i] == m) ans++;\n        t[i+1] += t[i];\n    }\n    cout << ans << endl;\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1558833807, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03037.html", "problem_id": "p03037", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03037/input.txt", "sample_output_relpath": "derived/input_output/data/p03037/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03037/C++/s590265946.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s590265946", "user_id": "u301109982"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint main() {\n    int n,m;\n    int t[100002] = {};\n    cin >> n >> m;\n    for(int i=0;i<m;++i) {\n        int l, r;\n        cin >> l >> r;\n        t[l-1]++;\n        t[r]--;\n    }\n    int ans = 0;\n    for(int i=0;i<n;++i) {\n        if(t[i] == m) ans++;\n        t[i+1] += t[i];\n    }\n    cout << ans << endl;\n    return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nWe have N ID cards, and there are M gates.\n\nWe can pass the i-th gate if we have one of the following ID cards: the L_i-th, (L_i+1)-th, ..., and R_i-th ID cards.\n\nHow many of the ID cards allow us to pass all the gates alone?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq L_i \\leq R_i \\leq N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nL_1 R_1\nL_2 R_2\n\\vdots\nL_M R_M\n\nOutput\n\nPrint the number of ID cards that allow us to pass all the gates alone.\n\nSample Input 1\n\n4 2\n1 3\n2 4\n\nSample Output 1\n\n2\n\nTwo ID cards allow us to pass all the gates alone, as follows:\n\nThe first ID card does not allow us to pass the second gate.\n\nThe second ID card allows us to pass all the gates.\n\nThe third ID card allows us to pass all the gates.\n\nThe fourth ID card does not allow us to pass the first gate.\n\nSample Input 2\n\n10 3\n3 6\n5 7\n6 9\n\nSample Output 2\n\n1\n\nSample Input 3\n\n100000 1\n1 100000\n\nSample Output 3\n\n100000", "sample_input": "4 2\n1 3\n2 4\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03037", "source_text": "Score : 300 points\n\nProblem Statement\n\nWe have N ID cards, and there are M gates.\n\nWe can pass the i-th gate if we have one of the following ID cards: the L_i-th, (L_i+1)-th, ..., and R_i-th ID cards.\n\nHow many of the ID cards allow us to pass all the gates alone?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq L_i \\leq R_i \\leq N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nL_1 R_1\nL_2 R_2\n\\vdots\nL_M R_M\n\nOutput\n\nPrint the number of ID cards that allow us to pass all the gates alone.\n\nSample Input 1\n\n4 2\n1 3\n2 4\n\nSample Output 1\n\n2\n\nTwo ID cards allow us to pass all the gates alone, as follows:\n\nThe first ID card does not allow us to pass the second gate.\n\nThe second ID card allows us to pass all the gates.\n\nThe third ID card allows us to pass all the gates.\n\nThe fourth ID card does not allow us to pass the first gate.\n\nSample Input 2\n\n10 3\n3 6\n5 7\n6 9\n\nSample Output 2\n\n1\n\nSample Input 3\n\n100000 1\n1 100000\n\nSample Output 3\n\n100000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 369, "cpu_time_ms": 71, "memory_kb": 640}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s266187435", "group_id": "codeNet:p03037", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  int N,M;\n  cin>>N>>M;\n  int mir=N,mal=0;\n  vector<int> L(M),R(M);\n  for(int i=0;i<M;i++){\n    cin>>L.at(i)>>R.at(i);\n    mir=min(mir,R.at(i));\n    mal=max(mal,L.at(i));\n  }\n  cout<<mir-mal+1<<endl;\n    \n}", "language": "C++", "metadata": {"date": 1558832923, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03037.html", "problem_id": "p03037", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03037/input.txt", "sample_output_relpath": "derived/input_output/data/p03037/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03037/C++/s266187435.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s266187435", "user_id": "u501008235"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  int N,M;\n  cin>>N>>M;\n  int mir=N,mal=0;\n  vector<int> L(M),R(M);\n  for(int i=0;i<M;i++){\n    cin>>L.at(i)>>R.at(i);\n    mir=min(mir,R.at(i));\n    mal=max(mal,L.at(i));\n  }\n  cout<<mir-mal+1<<endl;\n    \n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nWe have N ID cards, and there are M gates.\n\nWe can pass the i-th gate if we have one of the following ID cards: the L_i-th, (L_i+1)-th, ..., and R_i-th ID cards.\n\nHow many of the ID cards allow us to pass all the gates alone?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq L_i \\leq R_i \\leq N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nL_1 R_1\nL_2 R_2\n\\vdots\nL_M R_M\n\nOutput\n\nPrint the number of ID cards that allow us to pass all the gates alone.\n\nSample Input 1\n\n4 2\n1 3\n2 4\n\nSample Output 1\n\n2\n\nTwo ID cards allow us to pass all the gates alone, as follows:\n\nThe first ID card does not allow us to pass the second gate.\n\nThe second ID card allows us to pass all the gates.\n\nThe third ID card allows us to pass all the gates.\n\nThe fourth ID card does not allow us to pass the first gate.\n\nSample Input 2\n\n10 3\n3 6\n5 7\n6 9\n\nSample Output 2\n\n1\n\nSample Input 3\n\n100000 1\n1 100000\n\nSample Output 3\n\n100000", "sample_input": "4 2\n1 3\n2 4\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03037", "source_text": "Score : 300 points\n\nProblem Statement\n\nWe have N ID cards, and there are M gates.\n\nWe can pass the i-th gate if we have one of the following ID cards: the L_i-th, (L_i+1)-th, ..., and R_i-th ID cards.\n\nHow many of the ID cards allow us to pass all the gates alone?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq L_i \\leq R_i \\leq N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nL_1 R_1\nL_2 R_2\n\\vdots\nL_M R_M\n\nOutput\n\nPrint the number of ID cards that allow us to pass all the gates alone.\n\nSample Input 1\n\n4 2\n1 3\n2 4\n\nSample Output 1\n\n2\n\nTwo ID cards allow us to pass all the gates alone, as follows:\n\nThe first ID card does not allow us to pass the second gate.\n\nThe second ID card allows us to pass all the gates.\n\nThe third ID card allows us to pass all the gates.\n\nThe fourth ID card does not allow us to pass the first gate.\n\nSample Input 2\n\n10 3\n3 6\n5 7\n6 9\n\nSample Output 2\n\n1\n\nSample Input 3\n\n100000 1\n1 100000\n\nSample Output 3\n\n100000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 265, "cpu_time_ms": 57, "memory_kb": 1024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s724360802", "group_id": "codeNet:p03040", "input_text": "#include <bits/stdc++.h>\n#define rep(i,n)for(int i=0;i<(n);i++)\n#define INF 0x3f3f3f3f\n#define INFL 0x3f3f3f3f3f3f3f3f\n#define MOD 1000000007\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int>P;\n\nstruct Med{\n\tmultiset<int>f,b;\n\tll s1=0,s2=0;\n\tvoid balance(){\n\t\twhile(f.size()>=b.size()+2){\n\t\t\tint t=*f.rbegin();\n\t\t\tf.erase(--f.end());\n\t\t\ts1-=t;\n\t\t\ts2+=t;\n\t\t\tb.insert(t);\n\t\t}\n\t\twhile(f.size()<b.size()){\n\t\t\tint t=*b.begin();\n\t\t\tb.erase(b.begin());\n\t\t\ts2-=t;\n\t\t\ts1+=t;\n\t\t\tf.insert(t);\n\t\t}\n\t}\n\tvoid insert(int x){\n\t\tif(!b.empty()&&*b.begin()<x){\n\t\t\tb.insert(x),s2+=x;\n\t\t}\n\t\telse f.insert(x),s1+=x;\n\t\tbalance();\n\t}\n};\nMed med;\nint main(){\n\tint q;cin>>q;\n\tll t=0;\n\trep(i,q){\n\t\tint ty;scanf(\"%d\",&ty);\n\t\tif(ty==1){\n\t\t\tint a,b;scanf(\"%d%d\",&a,&b);\n\t\t\tt+=b;\n\t\t\tmed.insert(a);\n\t\t}\n\t\telse{\n\t\t\tint x=*med.f.rbegin();\n\t\t\tprintf(\"%d %lld\\n\",x,t+x*(ll)med.f.size()-med.s1+med.s2-x*(ll)med.b.size());\n\t\t}\n\t}\n}", "language": "C++", "metadata": {"date": 1558839471, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03040.html", "problem_id": "p03040", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03040/input.txt", "sample_output_relpath": "derived/input_output/data/p03040/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03040/C++/s724360802.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s724360802", "user_id": "u781091740"}, "prompt_components": {"gold_output": "4 2\n1 -3\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define rep(i,n)for(int i=0;i<(n);i++)\n#define INF 0x3f3f3f3f\n#define INFL 0x3f3f3f3f3f3f3f3f\n#define MOD 1000000007\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int>P;\n\nstruct Med{\n\tmultiset<int>f,b;\n\tll s1=0,s2=0;\n\tvoid balance(){\n\t\twhile(f.size()>=b.size()+2){\n\t\t\tint t=*f.rbegin();\n\t\t\tf.erase(--f.end());\n\t\t\ts1-=t;\n\t\t\ts2+=t;\n\t\t\tb.insert(t);\n\t\t}\n\t\twhile(f.size()<b.size()){\n\t\t\tint t=*b.begin();\n\t\t\tb.erase(b.begin());\n\t\t\ts2-=t;\n\t\t\ts1+=t;\n\t\t\tf.insert(t);\n\t\t}\n\t}\n\tvoid insert(int x){\n\t\tif(!b.empty()&&*b.begin()<x){\n\t\t\tb.insert(x),s2+=x;\n\t\t}\n\t\telse f.insert(x),s1+=x;\n\t\tbalance();\n\t}\n};\nMed med;\nint main(){\n\tint q;cin>>q;\n\tll t=0;\n\trep(i,q){\n\t\tint ty;scanf(\"%d\",&ty);\n\t\tif(ty==1){\n\t\t\tint a,b;scanf(\"%d%d\",&a,&b);\n\t\t\tt+=b;\n\t\t\tmed.insert(a);\n\t\t}\n\t\telse{\n\t\t\tint x=*med.f.rbegin();\n\t\t\tprintf(\"%d %lld\\n\",x,t+x*(ll)med.f.size()-med.s1+med.s2-x*(ll)med.b.size());\n\t\t}\n\t}\n}", "problem_context": "Score : 600 points\n\nProblem Statement\n\nThere is a function f(x), which is initially a constant function f(x) = 0.\n\nWe will ask you to process Q queries in order. There are two kinds of queries, update queries and evaluation queries, as follows:\n\nAn update query 1 a b: Given two integers a and b, let g(x) = f(x) + |x - a| + b and replace f(x) with g(x).\n\nAn evaluation query 2: Print x that minimizes f(x), and the minimum value of f(x). If there are multiple such values of x, choose the minimum such value.\n\nWe can show that the values to be output in an evaluation query are always integers, so we ask you to print those values as integers without decimal points.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq Q \\leq 2 \\times 10^5\n\n-10^9 \\leq a, b \\leq 10^9\n\nThe first query is an update query.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nQ\nQuery_1\n:\nQuery_Q\n\nSee Sample Input 1 for an example.\n\nOutput\n\nFor each evaluation query, print a line containing the response, in the order in which the queries are given.\n\nThe response to each evaluation query should be the minimum value of x that minimizes f(x), and the minimum value of f(x), in this order, with space in between.\n\nSample Input 1\n\n4\n1 4 2\n2\n1 1 -8\n2\n\nSample Output 1\n\n4 2\n1 -3\n\nIn the first evaluation query, f(x) = |x - 4| + 2, which attains the minimum value of 2 at x = 4.\n\nIn the second evaluation query, f(x) = |x - 1| + |x - 4| - 6, which attains the minimum value of -3 when 1 \\leq x \\leq 4. Among the multiple values of x that minimize f(x), we ask you to print the minimum, that is, 1.\n\nSample Input 2\n\n4\n1 -1000000000 1000000000\n1 -1000000000 1000000000\n1 -1000000000 1000000000\n2\n\nSample Output 2\n\n-1000000000 3000000000", "sample_input": "4\n1 4 2\n2\n1 1 -8\n2\n"}, "reference_outputs": ["4 2\n1 -3\n"], "source_document_id": "p03040", "source_text": "Score : 600 points\n\nProblem Statement\n\nThere is a function f(x), which is initially a constant function f(x) = 0.\n\nWe will ask you to process Q queries in order. There are two kinds of queries, update queries and evaluation queries, as follows:\n\nAn update query 1 a b: Given two integers a and b, let g(x) = f(x) + |x - a| + b and replace f(x) with g(x).\n\nAn evaluation query 2: Print x that minimizes f(x), and the minimum value of f(x). If there are multiple such values of x, choose the minimum such value.\n\nWe can show that the values to be output in an evaluation query are always integers, so we ask you to print those values as integers without decimal points.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq Q \\leq 2 \\times 10^5\n\n-10^9 \\leq a, b \\leq 10^9\n\nThe first query is an update query.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nQ\nQuery_1\n:\nQuery_Q\n\nSee Sample Input 1 for an example.\n\nOutput\n\nFor each evaluation query, print a line containing the response, in the order in which the queries are given.\n\nThe response to each evaluation query should be the minimum value of x that minimizes f(x), and the minimum value of f(x), in this order, with space in between.\n\nSample Input 1\n\n4\n1 4 2\n2\n1 1 -8\n2\n\nSample Output 1\n\n4 2\n1 -3\n\nIn the first evaluation query, f(x) = |x - 4| + 2, which attains the minimum value of 2 at x = 4.\n\nIn the second evaluation query, f(x) = |x - 1| + |x - 4| - 6, which attains the minimum value of -3 when 1 \\leq x \\leq 4. Among the multiple values of x that minimize f(x), we ask you to print the minimum, that is, 1.\n\nSample Input 2\n\n4\n1 -1000000000 1000000000\n1 -1000000000 1000000000\n1 -1000000000 1000000000\n2\n\nSample Output 2\n\n-1000000000 3000000000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 908, "cpu_time_ms": 149, "memory_kb": 9600}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s518736725", "group_id": "codeNet:p03041", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  int s,f=0,l=0;\n  cin >> s;\n  \n  f = s/100;\n  l = s%100;\n  \n  if(1<=f<=12  && 1<=l<=12){\n    cout << \"AMBIGUOUS\" << endl;\n  } else if(1<=f<=12){\n    cout << \"MMYY\" << endl;\n  } else if(1<=l<=12){\n    cout << \"YYMM\" << endl;\n  } else{\n    cout << \"NA\" << endl;\n  }\n}\n", "language": "C++", "metadata": {"date": 1567040361, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03041.html", "problem_id": "p03041", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03041/input.txt", "sample_output_relpath": "derived/input_output/data/p03041/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03041/C++/s518736725.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s518736725", "user_id": "u959353968"}, "prompt_components": {"gold_output": "aBC\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  int s,f=0,l=0;\n  cin >> s;\n  \n  f = s/100;\n  l = s%100;\n  \n  if(1<=f<=12  && 1<=l<=12){\n    cout << \"AMBIGUOUS\" << endl;\n  } else if(1<=f<=12){\n    cout << \"MMYY\" << endl;\n  } else if(1<=l<=12){\n    cout << \"YYMM\" << endl;\n  } else{\n    cout << \"NA\" << endl;\n  }\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nYou are given a string S of length N consisting of A, B and C, and an integer K which is between 1 and N (inclusive).\nPrint the string S after lowercasing the K-th character in it.\n\nConstraints\n\n1 ≤ N ≤ 50\n\n1 ≤ K ≤ N\n\nS is a string of length N consisting of A, B and C.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nS\n\nOutput\n\nPrint the string S after lowercasing the K-th character in it.\n\nSample Input 1\n\n3 1\nABC\n\nSample Output 1\n\naBC\n\nSample Input 2\n\n4 3\nCABA\n\nSample Output 2\n\nCAbA", "sample_input": "3 1\nABC\n"}, "reference_outputs": ["aBC\n"], "source_document_id": "p03041", "source_text": "Score : 100 points\n\nProblem Statement\n\nYou are given a string S of length N consisting of A, B and C, and an integer K which is between 1 and N (inclusive).\nPrint the string S after lowercasing the K-th character in it.\n\nConstraints\n\n1 ≤ N ≤ 50\n\n1 ≤ K ≤ N\n\nS is a string of length N consisting of A, B and C.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nS\n\nOutput\n\nPrint the string S after lowercasing the K-th character in it.\n\nSample Input 1\n\n3 1\nABC\n\nSample Output 1\n\naBC\n\nSample Input 2\n\n4 3\nCABA\n\nSample Output 2\n\nCAbA", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 326, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s887364210", "group_id": "codeNet:p03041", "input_text": "#include <iostream>\n#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <cmath>\n#include <iostream>\n#include <vector>\n#include <numeric>\n#include <string>\n#include <functional>\n#include <iostream>\n#include <cstdlib>\n#include <algorithm>\n#include <cctype>\n#include <iostream>\n#include <string>\n#include <algorithm>\n#include <string>\n\nusing namespace std;\n     \nint main() {\n  int n,b;\n  cin >> n >> b;\n  std::string s;\n  cin >> s;\n        \n  char cary[n]; \n  s.copy(cary, n);\n      \n  for (int i=0;i<n;i++){\n    if (i == b-1) {\n      cary[i] = std::tolower(cary[i]);\n    }\n  }\n     \n  cout << cary << endl;    \n  return 0;\n}", "language": "C++", "metadata": {"date": 1558315421, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03041.html", "problem_id": "p03041", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03041/input.txt", "sample_output_relpath": "derived/input_output/data/p03041/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03041/C++/s887364210.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s887364210", "user_id": "u097443428"}, "prompt_components": {"gold_output": "aBC\n", "input_to_evaluate": "#include <iostream>\n#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <cmath>\n#include <iostream>\n#include <vector>\n#include <numeric>\n#include <string>\n#include <functional>\n#include <iostream>\n#include <cstdlib>\n#include <algorithm>\n#include <cctype>\n#include <iostream>\n#include <string>\n#include <algorithm>\n#include <string>\n\nusing namespace std;\n     \nint main() {\n  int n,b;\n  cin >> n >> b;\n  std::string s;\n  cin >> s;\n        \n  char cary[n]; \n  s.copy(cary, n);\n      \n  for (int i=0;i<n;i++){\n    if (i == b-1) {\n      cary[i] = std::tolower(cary[i]);\n    }\n  }\n     \n  cout << cary << endl;    \n  return 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nYou are given a string S of length N consisting of A, B and C, and an integer K which is between 1 and N (inclusive).\nPrint the string S after lowercasing the K-th character in it.\n\nConstraints\n\n1 ≤ N ≤ 50\n\n1 ≤ K ≤ N\n\nS is a string of length N consisting of A, B and C.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nS\n\nOutput\n\nPrint the string S after lowercasing the K-th character in it.\n\nSample Input 1\n\n3 1\nABC\n\nSample Output 1\n\naBC\n\nSample Input 2\n\n4 3\nCABA\n\nSample Output 2\n\nCAbA", "sample_input": "3 1\nABC\n"}, "reference_outputs": ["aBC\n"], "source_document_id": "p03041", "source_text": "Score : 100 points\n\nProblem Statement\n\nYou are given a string S of length N consisting of A, B and C, and an integer K which is between 1 and N (inclusive).\nPrint the string S after lowercasing the K-th character in it.\n\nConstraints\n\n1 ≤ N ≤ 50\n\n1 ≤ K ≤ N\n\nS is a string of length N consisting of A, B and C.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nS\n\nOutput\n\nPrint the string S after lowercasing the K-th character in it.\n\nSample Input 1\n\n3 1\nABC\n\nSample Output 1\n\naBC\n\nSample Input 2\n\n4 3\nCABA\n\nSample Output 2\n\nCAbA", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 639, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s371162646", "group_id": "codeNet:p03041", "input_text": "#include <iostream>\n#include <string>\n#include <vector>\n#include <deque>\n#include <list>\n#include <set>\n#include <unordered_set>\n#include <map>\n#include <unordered_map>\n#include <array>\n#include <queue>\n#include <stack>\n#include <algorithm>\n#include <tuple>\n#include <numeric>\n#include <type_traits>\n\nint main()\n{\n\tint N, K;\n\tstd::string S;\n\t\n\tstd::cin >> N >> K;\n\tstd::cin >> S;\n\n\tS[K-1] = S[K-1] + ('a' - 'A');\n\n\tstd::cout << S << \"\\n\";\n}\n", "language": "C++", "metadata": {"date": 1558314169, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03041.html", "problem_id": "p03041", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03041/input.txt", "sample_output_relpath": "derived/input_output/data/p03041/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03041/C++/s371162646.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s371162646", "user_id": "u504322356"}, "prompt_components": {"gold_output": "aBC\n", "input_to_evaluate": "#include <iostream>\n#include <string>\n#include <vector>\n#include <deque>\n#include <list>\n#include <set>\n#include <unordered_set>\n#include <map>\n#include <unordered_map>\n#include <array>\n#include <queue>\n#include <stack>\n#include <algorithm>\n#include <tuple>\n#include <numeric>\n#include <type_traits>\n\nint main()\n{\n\tint N, K;\n\tstd::string S;\n\t\n\tstd::cin >> N >> K;\n\tstd::cin >> S;\n\n\tS[K-1] = S[K-1] + ('a' - 'A');\n\n\tstd::cout << S << \"\\n\";\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nYou are given a string S of length N consisting of A, B and C, and an integer K which is between 1 and N (inclusive).\nPrint the string S after lowercasing the K-th character in it.\n\nConstraints\n\n1 ≤ N ≤ 50\n\n1 ≤ K ≤ N\n\nS is a string of length N consisting of A, B and C.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nS\n\nOutput\n\nPrint the string S after lowercasing the K-th character in it.\n\nSample Input 1\n\n3 1\nABC\n\nSample Output 1\n\naBC\n\nSample Input 2\n\n4 3\nCABA\n\nSample Output 2\n\nCAbA", "sample_input": "3 1\nABC\n"}, "reference_outputs": ["aBC\n"], "source_document_id": "p03041", "source_text": "Score : 100 points\n\nProblem Statement\n\nYou are given a string S of length N consisting of A, B and C, and an integer K which is between 1 and N (inclusive).\nPrint the string S after lowercasing the K-th character in it.\n\nConstraints\n\n1 ≤ N ≤ 50\n\n1 ≤ K ≤ N\n\nS is a string of length N consisting of A, B and C.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nS\n\nOutput\n\nPrint the string S after lowercasing the K-th character in it.\n\nSample Input 1\n\n3 1\nABC\n\nSample Output 1\n\naBC\n\nSample Input 2\n\n4 3\nCABA\n\nSample Output 2\n\nCAbA", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 441, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s355847206", "group_id": "codeNet:p03042", "input_text": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint main(){\n    char n[4];\n    cin >> n;\n    int period[4] = {n[0] - '0', n[1] - '0', n[2] - '0', n[3] - '0'};\n    int front = (10 * period[0]) + period[1];\n    int back = (10 * period[2]) + period[3];\n    if(front > 12 && back > 12){\n        cout << \"NA\" << endl;\n    }else if(front == 0 && back >12){\n        cout << \"NA\" << endl;\n    }else if(front > 12 && back ==0){\n        cout << \"NA\" << endl;\n    }else if(front ==0 && back ==0){\n        cout << \"NA\" << endl;\n    }else if(front <=12 && back > 12){\n        cout << \"MMYY\";\n    }else if(front > 12 && back <= 12){\n        cout << \"YYMM\";\n    }else{\n        cout << \"AMBIGUOUS\";\n    }\n\n    return 0;\n}", "language": "C++", "metadata": {"date": 1558319379, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03042.html", "problem_id": "p03042", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03042/input.txt", "sample_output_relpath": "derived/input_output/data/p03042/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03042/C++/s355847206.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s355847206", "user_id": "u283567612"}, "prompt_components": {"gold_output": "YYMM\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint main(){\n    char n[4];\n    cin >> n;\n    int period[4] = {n[0] - '0', n[1] - '0', n[2] - '0', n[3] - '0'};\n    int front = (10 * period[0]) + period[1];\n    int back = (10 * period[2]) + period[3];\n    if(front > 12 && back > 12){\n        cout << \"NA\" << endl;\n    }else if(front == 0 && back >12){\n        cout << \"NA\" << endl;\n    }else if(front > 12 && back ==0){\n        cout << \"NA\" << endl;\n    }else if(front ==0 && back ==0){\n        cout << \"NA\" << endl;\n    }else if(front <=12 && back > 12){\n        cout << \"MMYY\";\n    }else if(front > 12 && back <= 12){\n        cout << \"YYMM\";\n    }else{\n        cout << \"AMBIGUOUS\";\n    }\n\n    return 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nYou have a digit sequence S of length 4. You are wondering which of the following formats S is in:\n\nYYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order\n\nMMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order\n\nIf S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.\n\nConstraints\n\nS is a digit sequence of length 4.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the specified string: YYMM, MMYY, AMBIGUOUS or NA.\n\nSample Input 1\n\n1905\n\nSample Output 1\n\nYYMM\n\nMay XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.\n\nSample Input 2\n\n0112\n\nSample Output 2\n\nAMBIGUOUS\n\nBoth December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.\n\nSample Input 3\n\n1700\n\nSample Output 3\n\nNA\n\nNeither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.", "sample_input": "1905\n"}, "reference_outputs": ["YYMM\n"], "source_document_id": "p03042", "source_text": "Score : 200 points\n\nProblem Statement\n\nYou have a digit sequence S of length 4. You are wondering which of the following formats S is in:\n\nYYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order\n\nMMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order\n\nIf S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.\n\nConstraints\n\nS is a digit sequence of length 4.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the specified string: YYMM, MMYY, AMBIGUOUS or NA.\n\nSample Input 1\n\n1905\n\nSample Output 1\n\nYYMM\n\nMay XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.\n\nSample Input 2\n\n0112\n\nSample Output 2\n\nAMBIGUOUS\n\nBoth December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.\n\nSample Input 3\n\n1700\n\nSample Output 3\n\nNA\n\nNeither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 705, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s819258719", "group_id": "codeNet:p03042", "input_text": "#include <iostream>\n#include <string>\nusing namespace std;\n\nint main()\n{\n    string s;\n    cin>>s;\n    bool b1,b2;\n    b1=false;\n    b2=false;\n    if((s[0]=='1' && ((int)s[1]>=48 && (int)s[1]<=50))|| (s[0]=='0' &&(int)s[1]>=49 &&(int)s[1]<=57)){\n        b1=true;\n    }\n    if((s[2]=='1' && ((int)s[3]>=48 && (int)s[3]<=50))|| (s[2]=='0' &&(int)s[3]>=49 &&(int)s[3]<=57)){\n    \tb2=true;\n    } \n    if(b1&&b2){\n    \tcout << \"AMBIGUOUS\" << endl;\n        return 0;\n    }else if(b1){\n    \tcout << \"MMYY\" << endl;\n        return 0;\n    }else if(b2){\n    \tcout << \"YYMM\" << endl;\n        return 0;\n    }else{\n    \tcout << \"NA\" << endl;\n        return 0;\n    }\n\n}", "language": "C++", "metadata": {"date": 1558316858, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03042.html", "problem_id": "p03042", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03042/input.txt", "sample_output_relpath": "derived/input_output/data/p03042/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03042/C++/s819258719.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s819258719", "user_id": "u442039299"}, "prompt_components": {"gold_output": "YYMM\n", "input_to_evaluate": "#include <iostream>\n#include <string>\nusing namespace std;\n\nint main()\n{\n    string s;\n    cin>>s;\n    bool b1,b2;\n    b1=false;\n    b2=false;\n    if((s[0]=='1' && ((int)s[1]>=48 && (int)s[1]<=50))|| (s[0]=='0' &&(int)s[1]>=49 &&(int)s[1]<=57)){\n        b1=true;\n    }\n    if((s[2]=='1' && ((int)s[3]>=48 && (int)s[3]<=50))|| (s[2]=='0' &&(int)s[3]>=49 &&(int)s[3]<=57)){\n    \tb2=true;\n    } \n    if(b1&&b2){\n    \tcout << \"AMBIGUOUS\" << endl;\n        return 0;\n    }else if(b1){\n    \tcout << \"MMYY\" << endl;\n        return 0;\n    }else if(b2){\n    \tcout << \"YYMM\" << endl;\n        return 0;\n    }else{\n    \tcout << \"NA\" << endl;\n        return 0;\n    }\n\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nYou have a digit sequence S of length 4. You are wondering which of the following formats S is in:\n\nYYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order\n\nMMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order\n\nIf S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.\n\nConstraints\n\nS is a digit sequence of length 4.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the specified string: YYMM, MMYY, AMBIGUOUS or NA.\n\nSample Input 1\n\n1905\n\nSample Output 1\n\nYYMM\n\nMay XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.\n\nSample Input 2\n\n0112\n\nSample Output 2\n\nAMBIGUOUS\n\nBoth December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.\n\nSample Input 3\n\n1700\n\nSample Output 3\n\nNA\n\nNeither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.", "sample_input": "1905\n"}, "reference_outputs": ["YYMM\n"], "source_document_id": "p03042", "source_text": "Score : 200 points\n\nProblem Statement\n\nYou have a digit sequence S of length 4. You are wondering which of the following formats S is in:\n\nYYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order\n\nMMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order\n\nIf S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.\n\nConstraints\n\nS is a digit sequence of length 4.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the specified string: YYMM, MMYY, AMBIGUOUS or NA.\n\nSample Input 1\n\n1905\n\nSample Output 1\n\nYYMM\n\nMay XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.\n\nSample Input 2\n\n0112\n\nSample Output 2\n\nAMBIGUOUS\n\nBoth December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.\n\nSample Input 3\n\n1700\n\nSample Output 3\n\nNA\n\nNeither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 655, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s332203810", "group_id": "codeNet:p03042", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n#define endl '\\n'\n#define ll long long\nint main()\n{\n\tios_base::sync_with_stdio(false);\n\tcin.tie(0);\n\tstring s;\n\tcin >> s;\n\tint a=0,vv=0;\n\t\n\tif((s[0]=='1' && s[1]<='2') || (s[0]=='0' && s[1]!='0'))\n\t{\n\t\ta=1;\n\t}\n\tif((s[2]=='1' && s[3]<='2') || (s[2]=='0' && s[3]!='0'))\n\t{\n\t\tvv=1;\n\t}\n\tif(a==1 && vv!=1)\n\t{\n\t\tcout << \"MMYY\";\n\t}\n\telse if(a==1)\n\t{\n\t\tcout << \"AMBIGUOUS\";\n\t}\n\telse if(vv==1)\n\t{\n\t\tcout << \"YYMM\";\n\t}\n\telse\n\t{\n\t\tcout << \"NA\";\n\t}\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1558316826, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03042.html", "problem_id": "p03042", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03042/input.txt", "sample_output_relpath": "derived/input_output/data/p03042/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03042/C++/s332203810.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s332203810", "user_id": "u037006720"}, "prompt_components": {"gold_output": "YYMM\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n#define endl '\\n'\n#define ll long long\nint main()\n{\n\tios_base::sync_with_stdio(false);\n\tcin.tie(0);\n\tstring s;\n\tcin >> s;\n\tint a=0,vv=0;\n\t\n\tif((s[0]=='1' && s[1]<='2') || (s[0]=='0' && s[1]!='0'))\n\t{\n\t\ta=1;\n\t}\n\tif((s[2]=='1' && s[3]<='2') || (s[2]=='0' && s[3]!='0'))\n\t{\n\t\tvv=1;\n\t}\n\tif(a==1 && vv!=1)\n\t{\n\t\tcout << \"MMYY\";\n\t}\n\telse if(a==1)\n\t{\n\t\tcout << \"AMBIGUOUS\";\n\t}\n\telse if(vv==1)\n\t{\n\t\tcout << \"YYMM\";\n\t}\n\telse\n\t{\n\t\tcout << \"NA\";\n\t}\n\treturn 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nYou have a digit sequence S of length 4. You are wondering which of the following formats S is in:\n\nYYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order\n\nMMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order\n\nIf S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.\n\nConstraints\n\nS is a digit sequence of length 4.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the specified string: YYMM, MMYY, AMBIGUOUS or NA.\n\nSample Input 1\n\n1905\n\nSample Output 1\n\nYYMM\n\nMay XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.\n\nSample Input 2\n\n0112\n\nSample Output 2\n\nAMBIGUOUS\n\nBoth December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.\n\nSample Input 3\n\n1700\n\nSample Output 3\n\nNA\n\nNeither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.", "sample_input": "1905\n"}, "reference_outputs": ["YYMM\n"], "source_document_id": "p03042", "source_text": "Score : 200 points\n\nProblem Statement\n\nYou have a digit sequence S of length 4. You are wondering which of the following formats S is in:\n\nYYMM format: the last two digits of the year and the two-digit representation of the month (example: 01 for January), concatenated in this order\n\nMMYY format: the two-digit representation of the month and the last two digits of the year, concatenated in this order\n\nIf S is valid in only YYMM format, print YYMM; if S is valid in only MMYY format, print MMYY; if S is valid in both formats, print AMBIGUOUS; if S is valid in neither format, print NA.\n\nConstraints\n\nS is a digit sequence of length 4.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the specified string: YYMM, MMYY, AMBIGUOUS or NA.\n\nSample Input 1\n\n1905\n\nSample Output 1\n\nYYMM\n\nMay XX19 is a valid date, but 19 is not valid as a month. Thus, this string is only valid in YYMM format.\n\nSample Input 2\n\n0112\n\nSample Output 2\n\nAMBIGUOUS\n\nBoth December XX01 and January XX12 are valid dates. Thus, this string is valid in both formats.\n\nSample Input 3\n\n1700\n\nSample Output 3\n\nNA\n\nNeither 0 nor 17 is valid as a month. Thus, this string is valid in neither format.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 495, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s100762482", "group_id": "codeNet:p03043", "input_text": "#include<bits/stdc++.h>\n#define inf 0x3f3f3f3f\n#define pb push_back\n#define AA first\n#define BB second\n#define ONES(x) __builtin_popcount(x)\n#define _ <<\" \"<<\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> pii;\ntypedef pair<ll,ll> pll;\nint dx[4]={0,0,1,-1};\nint dy[4]={1,-1,0,0};\nconst double eps=1e-6;\nconst int mod=1e9+7;\nconst double PI=acos(-1.0);\ninline int read(){ int num;    scanf(\"%2d\",&num);   return num;}\nconst int maxn=1e5+7;\n//numerator分子  denominator分母\nclass Rational {\n\tpublic:\n    Rational(int n=0,int d=1):num(n),den(d) {} //有参构造函数\n    friend Rational operator+(const Rational &r1,const Rational &r2);//相加\n    friend Rational operator-(const Rational &r1,const Rational &r2);//相减\n    friend Rational operator/(const Rational &r1,const Rational &r2);//相除\n    friend Rational operator*(const Rational &r1,const Rational &r2);//相乘\n    void simplify();//对有理数进行化简\n    void display();  //显示结果\n    double num;\n    double den;\n\n};\nRational operator+(const Rational &r1,const Rational &r2) {\n    Rational r;\n    r.num = r1.den*r2.num+r1.num*r2.den;//相加的分子等于r1分母和r2分子相乘，r1分子和r2分母相乘之和\n    r.den = r1.den*r2.den;//分母等于两个有理数分母的相乘\n    r.simplify();//调用simplify对结果进行化简\n    return r;//将结果返回\n}\nRational operator-(const Rational &r1,const Rational &r2) {\n    Rational r;\n    r.num = r1.num*r2.den-r1.den*r2.num;//相加的分子等于r1分母和r2分子相乘，r1分子和r2分母相乘之差\n    r.den = r1.den*r2.den;//分母等于两个有理数分母的相乘\n    r.simplify();\n    return r;\n}\nRational operator/(const Rational &r1,const Rational &r2) {\n    Rational r;\n    if(r1.den==0||r2.den==0||r2.num==0) {\n        cout<<\"分母或者除数不能为0\"<<endl;\n    } else if(r1.num==0) {\n        cout<<\"0/0\"<<endl;\n    } else {\n        r.num = r1.num*r2.den;//相除的分子等于r1分子和r2分母相乘\n        r.den = r1.den*r2.num;//分母等于两个r1分母和r2分子相乘\n        r.simplify();\n        return r;\n    }\n}\nRational operator*(const Rational &r1,const Rational &r2) {\n    Rational r;\n    if(r1.den==0||r2.den==0) {\n        cout<<\"分母不能为0\"<<endl;\n    } else if(r1.num==0||r2.num==0) {\n        cout<<\"0/0\"<<endl;\n    } else {\n        r.num = r1.num*r2.den;//分子等于r1分子和r2分母相乘\n        r.den = r1.den*r2.num;//分母等于两个r1分母和r2分子相乘\n        r.simplify();\n        return r;\n    }\n}\nvoid Rational::simplify() {\n    int i,j,temp;\n    i=abs(den);\n    j=abs(num);\n    //如果i对j取余不为0，辗转相除法求最大公约数\n    while(temp=i%j) {\n        i=j;\n        j=temp;\n    }\n    den/=j;\n    num/=j;\n    if(den<0) {\n        den=-den;\n        num=-num;\n    }\n}\nvoid Rational::display() {\n    if(num==0||den==0) {\n\n    } else {\n        cout<<num<<\"/\"<<den<<endl;\n    }\n}\nint main()\n{\n\tRational r;\n    Rational r1(1,3),r2(0,5);\n\tint a,b,c,d;\n\tscanf(\"%d\",&a);b=read();//getchar();//c=read();d=read();\n\tRational ans(0,1);Rational tmp=(1,a);\n\tfor(int i=1;i<=a;i++)\n\t{\n\t\tint t=i;int cnt=0;\n\t\twhile(t<b)\n\t\t{\n\t\t\tt*=2;cnt++;\n\t\t}\n\t\tRational tt(1,1);Rational ttt=(1,2);\n\t\tfor(int j=1;j<=cnt;j++) \n\t\ttt=tt*ttt;\n\t\tans=ans+tt;\n\t\tlong double aa=ans.num;long double bb=ans.den; \n\t    //cout<<aa<<\" \"<<bb<<endl;\n\t}\n\tans=ans*tmp;\n\tans.simplify();\n\tlong double aa=ans.num;long double bb=ans.den; \n\t//cout<<aa<<\" \"<<bb<<endl;\n\tlong double aaaa=aa/bb;\n\tprintf(\"%.14Lf\\n\",aaaa);\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1558315961, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03043.html", "problem_id": "p03043", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03043/input.txt", "sample_output_relpath": "derived/input_output/data/p03043/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03043/C++/s100762482.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s100762482", "user_id": "u491404948"}, "prompt_components": {"gold_output": "0.145833333333\n", "input_to_evaluate": "#include<bits/stdc++.h>\n#define inf 0x3f3f3f3f\n#define pb push_back\n#define AA first\n#define BB second\n#define ONES(x) __builtin_popcount(x)\n#define _ <<\" \"<<\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> pii;\ntypedef pair<ll,ll> pll;\nint dx[4]={0,0,1,-1};\nint dy[4]={1,-1,0,0};\nconst double eps=1e-6;\nconst int mod=1e9+7;\nconst double PI=acos(-1.0);\ninline int read(){ int num;    scanf(\"%2d\",&num);   return num;}\nconst int maxn=1e5+7;\n//numerator分子  denominator分母\nclass Rational {\n\tpublic:\n    Rational(int n=0,int d=1):num(n),den(d) {} //有参构造函数\n    friend Rational operator+(const Rational &r1,const Rational &r2);//相加\n    friend Rational operator-(const Rational &r1,const Rational &r2);//相减\n    friend Rational operator/(const Rational &r1,const Rational &r2);//相除\n    friend Rational operator*(const Rational &r1,const Rational &r2);//相乘\n    void simplify();//对有理数进行化简\n    void display();  //显示结果\n    double num;\n    double den;\n\n};\nRational operator+(const Rational &r1,const Rational &r2) {\n    Rational r;\n    r.num = r1.den*r2.num+r1.num*r2.den;//相加的分子等于r1分母和r2分子相乘，r1分子和r2分母相乘之和\n    r.den = r1.den*r2.den;//分母等于两个有理数分母的相乘\n    r.simplify();//调用simplify对结果进行化简\n    return r;//将结果返回\n}\nRational operator-(const Rational &r1,const Rational &r2) {\n    Rational r;\n    r.num = r1.num*r2.den-r1.den*r2.num;//相加的分子等于r1分母和r2分子相乘，r1分子和r2分母相乘之差\n    r.den = r1.den*r2.den;//分母等于两个有理数分母的相乘\n    r.simplify();\n    return r;\n}\nRational operator/(const Rational &r1,const Rational &r2) {\n    Rational r;\n    if(r1.den==0||r2.den==0||r2.num==0) {\n        cout<<\"分母或者除数不能为0\"<<endl;\n    } else if(r1.num==0) {\n        cout<<\"0/0\"<<endl;\n    } else {\n        r.num = r1.num*r2.den;//相除的分子等于r1分子和r2分母相乘\n        r.den = r1.den*r2.num;//分母等于两个r1分母和r2分子相乘\n        r.simplify();\n        return r;\n    }\n}\nRational operator*(const Rational &r1,const Rational &r2) {\n    Rational r;\n    if(r1.den==0||r2.den==0) {\n        cout<<\"分母不能为0\"<<endl;\n    } else if(r1.num==0||r2.num==0) {\n        cout<<\"0/0\"<<endl;\n    } else {\n        r.num = r1.num*r2.den;//分子等于r1分子和r2分母相乘\n        r.den = r1.den*r2.num;//分母等于两个r1分母和r2分子相乘\n        r.simplify();\n        return r;\n    }\n}\nvoid Rational::simplify() {\n    int i,j,temp;\n    i=abs(den);\n    j=abs(num);\n    //如果i对j取余不为0，辗转相除法求最大公约数\n    while(temp=i%j) {\n        i=j;\n        j=temp;\n    }\n    den/=j;\n    num/=j;\n    if(den<0) {\n        den=-den;\n        num=-num;\n    }\n}\nvoid Rational::display() {\n    if(num==0||den==0) {\n\n    } else {\n        cout<<num<<\"/\"<<den<<endl;\n    }\n}\nint main()\n{\n\tRational r;\n    Rational r1(1,3),r2(0,5);\n\tint a,b,c,d;\n\tscanf(\"%d\",&a);b=read();//getchar();//c=read();d=read();\n\tRational ans(0,1);Rational tmp=(1,a);\n\tfor(int i=1;i<=a;i++)\n\t{\n\t\tint t=i;int cnt=0;\n\t\twhile(t<b)\n\t\t{\n\t\t\tt*=2;cnt++;\n\t\t}\n\t\tRational tt(1,1);Rational ttt=(1,2);\n\t\tfor(int j=1;j<=cnt;j++) \n\t\ttt=tt*ttt;\n\t\tans=ans+tt;\n\t\tlong double aa=ans.num;long double bb=ans.den; \n\t    //cout<<aa<<\" \"<<bb<<endl;\n\t}\n\tans=ans*tmp;\n\tans.simplify();\n\tlong double aa=ans.num;long double bb=ans.den; \n\t//cout<<aa<<\" \"<<bb<<endl;\n\tlong double aaaa=aa/bb;\n\tprintf(\"%.14Lf\\n\",aaaa);\n\treturn 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nSnuke has a fair N-sided die that shows the integers from 1 to N with equal probability and a fair coin. He will play the following game with them:\n\nThrow the die. The current score is the result of the die.\n\nAs long as the score is between 1 and K-1 (inclusive), keep flipping the coin. The score is doubled each time the coin lands heads up, and the score becomes 0 if the coin lands tails up.\n\nThe game ends when the score becomes 0 or becomes K or above. Snuke wins if the score is K or above, and loses if the score is 0.\n\nYou are given N and K. Find the probability that Snuke wins the game.\n\nConstraints\n\n1 ≤ N ≤ 10^5\n\n1 ≤ K ≤ 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the probability that Snuke wins the game. The output is considered correct when the absolute or relative error is at most 10^{-9}.\n\nSample Input 1\n\n3 10\n\nSample Output 1\n\n0.145833333333\n\nIf the die shows 1, Snuke needs to get four consecutive heads from four coin flips to obtain a score of 10 or above. The probability of this happening is \\frac{1}{3} \\times (\\frac{1}{2})^4 = \\frac{1}{48}.\n\nIf the die shows 2, Snuke needs to get three consecutive heads from three coin flips to obtain a score of 10 or above. The probability of this happening is \\frac{1}{3} \\times (\\frac{1}{2})^3 = \\frac{1}{24}.\n\nIf the die shows 3, Snuke needs to get two consecutive heads from two coin flips to obtain a score of 10 or above. The probability of this happening is \\frac{1}{3} \\times (\\frac{1}{2})^2 = \\frac{1}{12}.\n\nThus, the probability that Snuke wins is \\frac{1}{48} + \\frac{1}{24} + \\frac{1}{12} = \\frac{7}{48} \\simeq 0.1458333333.\n\nSample Input 2\n\n100000 5\n\nSample Output 2\n\n0.999973749998", "sample_input": "3 10\n"}, "reference_outputs": ["0.145833333333\n"], "source_document_id": "p03043", "source_text": "Score : 300 points\n\nProblem Statement\n\nSnuke has a fair N-sided die that shows the integers from 1 to N with equal probability and a fair coin. He will play the following game with them:\n\nThrow the die. The current score is the result of the die.\n\nAs long as the score is between 1 and K-1 (inclusive), keep flipping the coin. The score is doubled each time the coin lands heads up, and the score becomes 0 if the coin lands tails up.\n\nThe game ends when the score becomes 0 or becomes K or above. Snuke wins if the score is K or above, and loses if the score is 0.\n\nYou are given N and K. Find the probability that Snuke wins the game.\n\nConstraints\n\n1 ≤ N ≤ 10^5\n\n1 ≤ K ≤ 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the probability that Snuke wins the game. The output is considered correct when the absolute or relative error is at most 10^{-9}.\n\nSample Input 1\n\n3 10\n\nSample Output 1\n\n0.145833333333\n\nIf the die shows 1, Snuke needs to get four consecutive heads from four coin flips to obtain a score of 10 or above. The probability of this happening is \\frac{1}{3} \\times (\\frac{1}{2})^4 = \\frac{1}{48}.\n\nIf the die shows 2, Snuke needs to get three consecutive heads from three coin flips to obtain a score of 10 or above. The probability of this happening is \\frac{1}{3} \\times (\\frac{1}{2})^3 = \\frac{1}{24}.\n\nIf the die shows 3, Snuke needs to get two consecutive heads from two coin flips to obtain a score of 10 or above. The probability of this happening is \\frac{1}{3} \\times (\\frac{1}{2})^2 = \\frac{1}{12}.\n\nThus, the probability that Snuke wins is \\frac{1}{48} + \\frac{1}{24} + \\frac{1}{12} = \\frac{7}{48} \\simeq 0.1458333333.\n\nSample Input 2\n\n100000 5\n\nSample Output 2\n\n0.999973749998", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 3534, "cpu_time_ms": 6, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s133319438", "group_id": "codeNet:p03044", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nusing Graph = vector<vector<int>>;\n\n// DFS\n\nvoid dfs(Graph &G, map<pair<int, int>, int> &MAP, vector<int> &color, int x) {\n  \n  for (int nx : G[x]) {\n    \n    if (color[nx] != -1) continue;\n    \n    if (MAP[{x, nx}] % 2 == 0) {\n      color[nx] = color[x];\n      dfs(G, MAP, color, nx);\n    }\n    \n    else {\n      color[nx] = 1 - color[x];\n      dfs(G, MAP, color, nx);\n    }\n    \n  }\n  \n  return;\n  \n}\n\nint main () {\n  \n  // 入力\n  \n  int N;\n  cin >> N;\n  \n  Graph G(N);\n  map<pair<int, int>, int> MAP;\n  \n  for(int i = 0; i < N - 1; i++) {\n    \n    int a, b, w;\n    cin >> a >> b >> w;\n    a--;\n    b--;\n    \n    G[a].push_back(b);\n    G[b].push_back(a);\n    MAP[{a, b}] = w;\n    MAP[{b, a}] = w;\n    \n  }\n  \n  // DFS\n  \n  vector<int> color(N, -1);\n  color[0] = 0;\n  dfs(G, MAP, color, 0);\n  \n  // 出力\n  \n  for (int i = 0; i < N; i++) {\n    cout << color[i] << endl;\n  }\n    \n  \n}", "language": "C++", "metadata": {"date": 1570477123, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03044.html", "problem_id": "p03044", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03044/input.txt", "sample_output_relpath": "derived/input_output/data/p03044/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03044/C++/s133319438.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s133319438", "user_id": "u688422725"}, "prompt_components": {"gold_output": "0\n0\n1\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nusing Graph = vector<vector<int>>;\n\n// DFS\n\nvoid dfs(Graph &G, map<pair<int, int>, int> &MAP, vector<int> &color, int x) {\n  \n  for (int nx : G[x]) {\n    \n    if (color[nx] != -1) continue;\n    \n    if (MAP[{x, nx}] % 2 == 0) {\n      color[nx] = color[x];\n      dfs(G, MAP, color, nx);\n    }\n    \n    else {\n      color[nx] = 1 - color[x];\n      dfs(G, MAP, color, nx);\n    }\n    \n  }\n  \n  return;\n  \n}\n\nint main () {\n  \n  // 入力\n  \n  int N;\n  cin >> N;\n  \n  Graph G(N);\n  map<pair<int, int>, int> MAP;\n  \n  for(int i = 0; i < N - 1; i++) {\n    \n    int a, b, w;\n    cin >> a >> b >> w;\n    a--;\n    b--;\n    \n    G[a].push_back(b);\n    G[b].push_back(a);\n    MAP[{a, b}] = w;\n    MAP[{b, a}] = w;\n    \n  }\n  \n  // DFS\n  \n  vector<int> color(N, -1);\n  color[0] = 0;\n  dfs(G, MAP, color, 0);\n  \n  // 出力\n  \n  for (int i = 0; i < N; i++) {\n    cout << color[i] << endl;\n  }\n    \n  \n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nWe have a tree with N vertices numbered 1 to N.\nThe i-th edge in the tree connects Vertex u_i and Vertex v_i, and its length is w_i.\nYour objective is to paint each vertex in the tree white or black (it is fine to paint all vertices the same color) so that the following condition is satisfied:\n\nFor any two vertices painted in the same color, the distance between them is an even number.\n\nFind a coloring of the vertices that satisfies the condition and print it. It can be proved that at least one such coloring exists under the constraints of this problem.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq u_i < v_i \\leq N\n\n1 \\leq w_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nu_1 v_1 w_1\nu_2 v_2 w_2\n.\n.\n.\nu_{N - 1} v_{N - 1} w_{N - 1}\n\nOutput\n\nPrint a coloring of the vertices that satisfies the condition, in N lines.\nThe i-th line should contain 0 if Vertex i is painted white and 1 if it is painted black.\n\nIf there are multiple colorings that satisfy the condition, any of them will be accepted.\n\nSample Input 1\n\n3\n1 2 2\n2 3 1\n\nSample Output 1\n\n0\n0\n1\n\nSample Input 2\n\n5\n2 5 2\n2 3 10\n1 3 8\n3 4 2\n\nSample Output 2\n\n1\n0\n1\n0\n1", "sample_input": "3\n1 2 2\n2 3 1\n"}, "reference_outputs": ["0\n0\n1\n"], "source_document_id": "p03044", "source_text": "Score : 400 points\n\nProblem Statement\n\nWe have a tree with N vertices numbered 1 to N.\nThe i-th edge in the tree connects Vertex u_i and Vertex v_i, and its length is w_i.\nYour objective is to paint each vertex in the tree white or black (it is fine to paint all vertices the same color) so that the following condition is satisfied:\n\nFor any two vertices painted in the same color, the distance between them is an even number.\n\nFind a coloring of the vertices that satisfies the condition and print it. It can be proved that at least one such coloring exists under the constraints of this problem.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq u_i < v_i \\leq N\n\n1 \\leq w_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nu_1 v_1 w_1\nu_2 v_2 w_2\n.\n.\n.\nu_{N - 1} v_{N - 1} w_{N - 1}\n\nOutput\n\nPrint a coloring of the vertices that satisfies the condition, in N lines.\nThe i-th line should contain 0 if Vertex i is painted white and 1 if it is painted black.\n\nIf there are multiple colorings that satisfy the condition, any of them will be accepted.\n\nSample Input 1\n\n3\n1 2 2\n2 3 1\n\nSample Output 1\n\n0\n0\n1\n\nSample Input 2\n\n5\n2 5 2\n2 3 10\n1 3 8\n3 4 2\n\nSample Output 2\n\n1\n0\n1\n0\n1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 933, "cpu_time_ms": 390, "memory_kb": 24448}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s186443737", "group_id": "codeNet:p03045", "input_text": "#include <bits/stdc++.h>\n#include <ext/pb_ds/assoc_container.hpp>\n#include <ext/pb_ds/tree_policy.hpp>\nusing namespace __gnu_pbds;\nusing namespace std;\n\ntemplate <typename T>\nusing ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;\ntemplate <typename T>\nusing ordered_set_rev = tree<T, null_type, greater<T>, rb_tree_tag, tree_order_statistics_node_update>;\ntemplate <typename T>\nusing dijkstra = priority_queue<T, vector<T>, greater<T>>;\n\nusing namespace std;\ntypedef long long ll;\ntypedef unsigned long long ull;\n#define fbo find_by_order //k th index\n#define ook order_of_key // strictly smaller than k\n#define PI acos(-1.0)\n#define inf 0x3f3f3f3f\n#define max_ull 18446744073709551615\n#define max_ll 9223372036854775807\n#define min3(a, b, c) min(a, min(b, c))\n#define max3(a, b, c) max(a, max(b, c))\n#define min4(a, b, c, d) min(min(a, b), min(c, d))\n#define max4(a, b, c, d) max(max(a, b), max(c, d))\n#define max5(a, b, c, d, e) max(max3(a, b, c), max(d, e))\n#define min5(a, b, c, d, e) min(min3(a, b, c), min(d, e))\n#define lead_zero(x) __builtin_clzll(x)\n#define trail_zero(x) __builtin_ctzll(x)\n#define total_1s(x) __builtin_popcountll(x)\n#define first_1(x) __builtin_ffsll(x)\n#define log2_(x) __builtin_clz(1) - __builtin_clz(x)\n#define isLeap(x) ((x % 400 == 0) || (x % 100 ? x % 4 == 0 : false))\n#define QUERY int test;scanf(\"%d\", &test);for (int _T = 1; _T <= test; _T++)\n#define FAST ios_base::sync_with_stdio(0), cin.tie(0)\n#define all(v) v.begin(), v.end()\n#define reunique(v) v.resize(std::unique(all(v)) - v.begin())\n#define pii pair<int, int>\n#define pll pair<ll, ll>\n#define ff first\n#define ss second\n#define MERGE(v1, v2, v) merge(all(v1), all(v2), back_inserter(v))\n#define MP make_pair\n#define EB emplace_back\n#define read freopen(\"input.txt\", \"r\", stdin)\n#define write freopen(\"output.txt\", \"w\", stdout)\n#define in_range(v, r, l) upper_bound(all(v), r) - lower_bound(all(v), l)\n#define LCM(a,b) (a/__gcd(a,b))*b;\nll rdn(int y, int m, int d) {\n    /* Rata Die day one is 0001-01-01 */\n    if (m < 3)\n        y--, m += 12;\n    return 365 * y + y / 4 - y / 100 + y / 400 + (153 * m - 457) / 5 + d - 306;\n}\n/* Direction arrays */\n/* int dx[] = {1,-1,0,0}, dy[] = {0,0,1,-1}; */                        // 4 Direction\n/*int dx[] = {1,-1,0,0,1,1,-1,-1}, dy[] = {0,0,1,-1,1,-1,1,-1};       */ // 8 Direction\n/* int dx[] = {1,-1,1,-1,2,2,-2,-2} , dy[] = {2,2,-2,-2,1,-1,1,-1}; */ // Knight Direction\n/* int dx[] = {2,-2,1,1,-1,-1} , dy[] = {0,0,1,-1,1,-1}; */            // Hexagonal Direction\n/* int dx[] = {2,-2,1,1,-1,-1} , dy[] = {0,0,1,-1,1,-1}; */            // Hexagonal Direction\n/* int day[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; */\nconst int N=1e5+9;\nint par[N];\nint hight[N];\nint find_(int x)\n{\n    while(x!=par[x])\n    {\n        par[x]=par[par[x]];\n        x=par[x];\n    }\n    return x;\n}\nvoid UNION(int x,int y)\n{\n    x=find_(x);\n    y=find_(y);\n    if(x!=y)\n    {\n        if(hight[x]<hight[y])\n            swap(x,y);\n        par[y]=x;\n        hight[x]+=hight[y];\n    }\n}\nvector<pii>v[3];\nint main() {\n    int n,m;\n    scanf(\"%d %d\",&n,&m);\n    int a,b,c;\n    for(int i=0;i<m;i++){\n        scanf(\"%d %d %d\",&a,&b,&c);\n        v[c%2].push_back(MP(a,b));\n    }\n    for(int i=1;i<=n;i++){\n        par[i]=i;\n        hight[i]=1;\n    }\n    for(pii &i:v[0]){\n        UNION(i.ff,i.ss);\n    }\n    for(pii &i:v[1]){\n        UNION(i.ff,i.ss);\n    }\n    sort(par+1,par+n+1);\n    int prev=-1;\n    int cnt=0;\n    for(int i=1;i<=n;i++){\n        if(par[i]!=prev)cnt++;\n        prev=par[i];\n    }\n    printf(\"%d\\n\",cnt);\n}\n", "language": "C++", "metadata": {"date": 1558324273, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03045.html", "problem_id": "p03045", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03045/input.txt", "sample_output_relpath": "derived/input_output/data/p03045/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03045/C++/s186443737.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s186443737", "user_id": "u447277621"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#include <ext/pb_ds/assoc_container.hpp>\n#include <ext/pb_ds/tree_policy.hpp>\nusing namespace __gnu_pbds;\nusing namespace std;\n\ntemplate <typename T>\nusing ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;\ntemplate <typename T>\nusing ordered_set_rev = tree<T, null_type, greater<T>, rb_tree_tag, tree_order_statistics_node_update>;\ntemplate <typename T>\nusing dijkstra = priority_queue<T, vector<T>, greater<T>>;\n\nusing namespace std;\ntypedef long long ll;\ntypedef unsigned long long ull;\n#define fbo find_by_order //k th index\n#define ook order_of_key // strictly smaller than k\n#define PI acos(-1.0)\n#define inf 0x3f3f3f3f\n#define max_ull 18446744073709551615\n#define max_ll 9223372036854775807\n#define min3(a, b, c) min(a, min(b, c))\n#define max3(a, b, c) max(a, max(b, c))\n#define min4(a, b, c, d) min(min(a, b), min(c, d))\n#define max4(a, b, c, d) max(max(a, b), max(c, d))\n#define max5(a, b, c, d, e) max(max3(a, b, c), max(d, e))\n#define min5(a, b, c, d, e) min(min3(a, b, c), min(d, e))\n#define lead_zero(x) __builtin_clzll(x)\n#define trail_zero(x) __builtin_ctzll(x)\n#define total_1s(x) __builtin_popcountll(x)\n#define first_1(x) __builtin_ffsll(x)\n#define log2_(x) __builtin_clz(1) - __builtin_clz(x)\n#define isLeap(x) ((x % 400 == 0) || (x % 100 ? x % 4 == 0 : false))\n#define QUERY int test;scanf(\"%d\", &test);for (int _T = 1; _T <= test; _T++)\n#define FAST ios_base::sync_with_stdio(0), cin.tie(0)\n#define all(v) v.begin(), v.end()\n#define reunique(v) v.resize(std::unique(all(v)) - v.begin())\n#define pii pair<int, int>\n#define pll pair<ll, ll>\n#define ff first\n#define ss second\n#define MERGE(v1, v2, v) merge(all(v1), all(v2), back_inserter(v))\n#define MP make_pair\n#define EB emplace_back\n#define read freopen(\"input.txt\", \"r\", stdin)\n#define write freopen(\"output.txt\", \"w\", stdout)\n#define in_range(v, r, l) upper_bound(all(v), r) - lower_bound(all(v), l)\n#define LCM(a,b) (a/__gcd(a,b))*b;\nll rdn(int y, int m, int d) {\n    /* Rata Die day one is 0001-01-01 */\n    if (m < 3)\n        y--, m += 12;\n    return 365 * y + y / 4 - y / 100 + y / 400 + (153 * m - 457) / 5 + d - 306;\n}\n/* Direction arrays */\n/* int dx[] = {1,-1,0,0}, dy[] = {0,0,1,-1}; */                        // 4 Direction\n/*int dx[] = {1,-1,0,0,1,1,-1,-1}, dy[] = {0,0,1,-1,1,-1,1,-1};       */ // 8 Direction\n/* int dx[] = {1,-1,1,-1,2,2,-2,-2} , dy[] = {2,2,-2,-2,1,-1,1,-1}; */ // Knight Direction\n/* int dx[] = {2,-2,1,1,-1,-1} , dy[] = {0,0,1,-1,1,-1}; */            // Hexagonal Direction\n/* int dx[] = {2,-2,1,1,-1,-1} , dy[] = {0,0,1,-1,1,-1}; */            // Hexagonal Direction\n/* int day[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; */\nconst int N=1e5+9;\nint par[N];\nint hight[N];\nint find_(int x)\n{\n    while(x!=par[x])\n    {\n        par[x]=par[par[x]];\n        x=par[x];\n    }\n    return x;\n}\nvoid UNION(int x,int y)\n{\n    x=find_(x);\n    y=find_(y);\n    if(x!=y)\n    {\n        if(hight[x]<hight[y])\n            swap(x,y);\n        par[y]=x;\n        hight[x]+=hight[y];\n    }\n}\nvector<pii>v[3];\nint main() {\n    int n,m;\n    scanf(\"%d %d\",&n,&m);\n    int a,b,c;\n    for(int i=0;i<m;i++){\n        scanf(\"%d %d %d\",&a,&b,&c);\n        v[c%2].push_back(MP(a,b));\n    }\n    for(int i=1;i<=n;i++){\n        par[i]=i;\n        hight[i]=1;\n    }\n    for(pii &i:v[0]){\n        UNION(i.ff,i.ss);\n    }\n    for(pii &i:v[1]){\n        UNION(i.ff,i.ss);\n    }\n    sort(par+1,par+n+1);\n    int prev=-1;\n    int cnt=0;\n    for(int i=1;i<=n;i++){\n        if(par[i]!=prev)cnt++;\n        prev=par[i];\n    }\n    printf(\"%d\\n\",cnt);\n}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nThere are N cards placed face down in a row. On each card, an integer 1 or 2 is written.\n\nLet A_i be the integer written on the i-th card.\n\nYour objective is to guess A_1, A_2, ..., A_N correctly.\n\nYou know the following facts:\n\nFor each i = 1, 2, ..., M, the value A_{X_i} + A_{Y_i} + Z_i is an even number.\n\nYou are a magician and can use the following magic any number of times:\n\nMagic: Choose one card and know the integer A_i written on it. The cost of using this magic is 1.\n\nWhat is the minimum cost required to determine all of A_1, A_2, ..., A_N?\n\nIt is guaranteed that there is no contradiction in given input.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq X_i < Y_i \\leq N\n\n1 \\leq Z_i \\leq 100\n\nThe pairs (X_i, Y_i) are distinct.\n\nThere is no contradiction in input. (That is, there exist integers A_1, A_2, ..., A_N that satisfy the conditions.)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nX_1 Y_1 Z_1\nX_2 Y_2 Z_2\n\\vdots\nX_M Y_M Z_M\n\nOutput\n\nPrint the minimum total cost required to determine all of A_1, A_2, ..., A_N.\n\nSample Input 1\n\n3 1\n1 2 1\n\nSample Output 1\n\n2\n\nYou can determine all of A_1, A_2, A_3 by using the magic for the first and third cards.\n\nSample Input 2\n\n6 5\n1 2 1\n2 3 2\n1 3 3\n4 5 4\n5 6 5\n\nSample Output 2\n\n2\n\nSample Input 3\n\n100000 1\n1 100000 100\n\nSample Output 3\n\n99999", "sample_input": "3 1\n1 2 1\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03045", "source_text": "Score : 500 points\n\nProblem Statement\n\nThere are N cards placed face down in a row. On each card, an integer 1 or 2 is written.\n\nLet A_i be the integer written on the i-th card.\n\nYour objective is to guess A_1, A_2, ..., A_N correctly.\n\nYou know the following facts:\n\nFor each i = 1, 2, ..., M, the value A_{X_i} + A_{Y_i} + Z_i is an even number.\n\nYou are a magician and can use the following magic any number of times:\n\nMagic: Choose one card and know the integer A_i written on it. The cost of using this magic is 1.\n\nWhat is the minimum cost required to determine all of A_1, A_2, ..., A_N?\n\nIt is guaranteed that there is no contradiction in given input.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq X_i < Y_i \\leq N\n\n1 \\leq Z_i \\leq 100\n\nThe pairs (X_i, Y_i) are distinct.\n\nThere is no contradiction in input. (That is, there exist integers A_1, A_2, ..., A_N that satisfy the conditions.)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nX_1 Y_1 Z_1\nX_2 Y_2 Z_2\n\\vdots\nX_M Y_M Z_M\n\nOutput\n\nPrint the minimum total cost required to determine all of A_1, A_2, ..., A_N.\n\nSample Input 1\n\n3 1\n1 2 1\n\nSample Output 1\n\n2\n\nYou can determine all of A_1, A_2, A_3 by using the magic for the first and third cards.\n\nSample Input 2\n\n6 5\n1 2 1\n2 3 2\n1 3 3\n4 5 4\n5 6 5\n\nSample Output 2\n\n2\n\nSample Input 3\n\n100000 1\n1 100000 100\n\nSample Output 3\n\n99999", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 3587, "cpu_time_ms": 32, "memory_kb": 1992}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s332433986", "group_id": "codeNet:p03050", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nconst int N = 1100000;\n\nint main() {\n#ifdef Hwang_Baek_I\n\tfreopen(\"in.txt\", \"r\", stdin);\n\tfreopen(\"out.txt\", \"w\", stdout);\n#endif\n\tios::sync_with_stdio(0);\n\tcin.tie(0); cout.tie(0);\n\tlong long n; cin >> n;\n\tset<long long> S;\n\tfor (int i = 1; (long long)i * i <= n; i++) {\n\t\tif (n % i) continue;\n\t\tlong long m, k;\n\t\tm = i - 1, k = n / i;\n\t\tif (m > k) S.insert(m);\n\t\tm = n / i - 1, k = i;\n\t\tif (m > k) S.insert(m);\n\t}\n\tlong long ans = 0;\n\tfor (long long t : S) ans += t;\n\tcout << ans << endl;\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1574121877, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03050.html", "problem_id": "p03050", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03050/input.txt", "sample_output_relpath": "derived/input_output/data/p03050/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03050/C++/s332433986.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s332433986", "user_id": "u089230684"}, "prompt_components": {"gold_output": "10\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nconst int N = 1100000;\n\nint main() {\n#ifdef Hwang_Baek_I\n\tfreopen(\"in.txt\", \"r\", stdin);\n\tfreopen(\"out.txt\", \"w\", stdout);\n#endif\n\tios::sync_with_stdio(0);\n\tcin.tie(0); cout.tie(0);\n\tlong long n; cin >> n;\n\tset<long long> S;\n\tfor (int i = 1; (long long)i * i <= n; i++) {\n\t\tif (n % i) continue;\n\t\tlong long m, k;\n\t\tm = i - 1, k = n / i;\n\t\tif (m > k) S.insert(m);\n\t\tm = n / i - 1, k = i;\n\t\tif (m > k) S.insert(m);\n\t}\n\tlong long ans = 0;\n\tfor (long long t : S) ans += t;\n\tcout << ans << endl;\n\treturn 0;\n}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nSnuke received a positive integer N from Takahashi.\nA positive integer m is called a favorite number when the following condition is satisfied:\n\nThe quotient and remainder of N divided by m are equal, that is, \\lfloor \\frac{N}{m} \\rfloor = N \\bmod m holds.\n\nFind all favorite numbers and print the sum of those.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^{12}\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n8\n\nSample Output 1\n\n10\n\nThere are two favorite numbers: 3 and 7. Print the sum of these, 10.\n\nSample Input 2\n\n1000000000000\n\nSample Output 2\n\n2499686339916\n\nWatch out for overflow.", "sample_input": "8\n"}, "reference_outputs": ["10\n"], "source_document_id": "p03050", "source_text": "Score : 500 points\n\nProblem Statement\n\nSnuke received a positive integer N from Takahashi.\nA positive integer m is called a favorite number when the following condition is satisfied:\n\nThe quotient and remainder of N divided by m are equal, that is, \\lfloor \\frac{N}{m} \\rfloor = N \\bmod m holds.\n\nFind all favorite numbers and print the sum of those.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^{12}\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n8\n\nSample Output 1\n\n10\n\nThere are two favorite numbers: 3 and 7. Print the sum of these, 10.\n\nSample Input 2\n\n1000000000000\n\nSample Output 2\n\n2499686339916\n\nWatch out for overflow.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 551, "cpu_time_ms": 12, "memory_kb": 384}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s427261396", "group_id": "codeNet:p03050", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n    int64_t N,ans;\n    cin >>N;\n    for (int i = 1; i <= (int)(sqrt(N+1)-1); i++)if((N-i) % i == 0)ans+=(N-i)/i;\n    cout<<ans<<endl;\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1559674668, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03050.html", "problem_id": "p03050", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03050/input.txt", "sample_output_relpath": "derived/input_output/data/p03050/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03050/C++/s427261396.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s427261396", "user_id": "u355424600"}, "prompt_components": {"gold_output": "10\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n    int64_t N,ans;\n    cin >>N;\n    for (int i = 1; i <= (int)(sqrt(N+1)-1); i++)if((N-i) % i == 0)ans+=(N-i)/i;\n    cout<<ans<<endl;\n    return 0;\n}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nSnuke received a positive integer N from Takahashi.\nA positive integer m is called a favorite number when the following condition is satisfied:\n\nThe quotient and remainder of N divided by m are equal, that is, \\lfloor \\frac{N}{m} \\rfloor = N \\bmod m holds.\n\nFind all favorite numbers and print the sum of those.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^{12}\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n8\n\nSample Output 1\n\n10\n\nThere are two favorite numbers: 3 and 7. Print the sum of these, 10.\n\nSample Input 2\n\n1000000000000\n\nSample Output 2\n\n2499686339916\n\nWatch out for overflow.", "sample_input": "8\n"}, "reference_outputs": ["10\n"], "source_document_id": "p03050", "source_text": "Score : 500 points\n\nProblem Statement\n\nSnuke received a positive integer N from Takahashi.\nA positive integer m is called a favorite number when the following condition is satisfied:\n\nThe quotient and remainder of N divided by m are equal, that is, \\lfloor \\frac{N}{m} \\rfloor = N \\bmod m holds.\n\nFind all favorite numbers and print the sum of those.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^{12}\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n8\n\nSample Output 1\n\n10\n\nThere are two favorite numbers: 3 and 7. Print the sum of these, 10.\n\nSample Input 2\n\n1000000000000\n\nSample Output 2\n\n2499686339916\n\nWatch out for overflow.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 208, "cpu_time_ms": 13, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s777741165", "group_id": "codeNet:p03056", "input_text": "#include <bits/stdc++.h>\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define rep1(i,n) for(int i=1;i<=(int)(n);i++)\n#define all(c) c.begin(),c.end()\n#define pb push_back\n#define fs first\n#define sc second\n#define chmin(x,y) x=min(x,y)\n#define chmax(x,y) x=max(x,y)\nusing namespace std;\ntemplate<class S,class T> ostream& operator<<(ostream& o,const pair<S,T> &p){\n\treturn o<<\"(\"<<p.fs<<\",\"<<p.sc<<\")\";\n}\ntemplate<class T> ostream& operator<<(ostream& o,const vector<T> &vc){\n\to<<\"{\";\n\tfor(const T& v:vc) o<<v<<\",\";\n\to<<\"}\";\n\treturn o;\n}\nusing ll = long long;\ntemplate<class T> using V = vector<T>;\ntemplate<class T> using VV = vector<vector<T>>;\nconstexpr ll TEN(int n) { return (n == 0) ? 1 : 10 * TEN(n-1); }\n\n#ifdef LOCAL\n#define show(x) cerr << \"LINE\" << __LINE__ << \" : \" << #x << \" = \" << (x) << endl\n#else\n#define show(x) true\n#endif\n\nint H,W;\nV<string> s;\nconst int X = 187;\nint lrd2u[2][X][X][X];\nint dul2r[2][X][X][X];\n\nint A[X][X];\nbool allEqual(int d,int u,int l,int r){\n\tint c = A[u][r] - A[u][l] - A[d][r] + A[d][l];\n\treturn c == 0 || c == (u-d)*(r-l);\n}\n\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\t\t//DON'T USE scanf/printf/puts !!\n\tcout << fixed << setprecision(20);\n\t\n\tcin >> H >> W;\n\ts.resize(H);\n\trep(i,H) cin >> s[i];\n\trep(i,H) rep(j,W){\n\t\tif(s[i][j] == '#') A[i+1][j+1] = 1;\n\t}\n\trep(i,H+1) rep(j,W) A[i][j+1] += A[i][j];\n\trep(i,H) rep(j,W+1) A[i+1][j] += A[i][j];\n\n\n\n\trep(l,W) for(int r=l+1;r<=W;r++){\n\t\tlrd2u[0][l][r][H] = H;\n\t\tfor(int d=H-1;d>=0;d--){\n\t\t\tlrd2u[0][l][r][d] = d;\n\t\t\tif(allEqual(d,d+1,l,r)){\n\t\t\t\tlrd2u[0][l][r][d] = d + 1;\n\t\t\t\tif(d != H-1 && s[d][l] == s[d+1][l]) lrd2u[0][l][r][d] = lrd2u[0][l][r][d+1];\n\t\t\t}\n\t\t}\n\t}\n\trep(d,H) for(int u=d+1;u<=H;u++){\n\t\tdul2r[0][d][u][W] = W;\n\t\tfor(int l=W-1;l>=0;l--){\n\t\t\tdul2r[0][d][u][l] = l;\n\t\t\tif(allEqual(d,u,l,l+1)){\n\t\t\t\tdul2r[0][d][u][l] = l+1;\n\t\t\t\tif(l != W-1 && s[d][l] == s[d][l+1]) dul2r[0][d][u][l] = dul2r[0][d][u][l+1];\n\t\t\t}\n\t\t}\n\t}\n\trep(t,100){\n\n\t\t// cerr << \" -----------turn =  \" << t << endl;\n\t\t// rep(l,W) for(int r=l+1;r<=W;r++) rep(d,H){\n\t\t// \tcerr << \"lrd2u[\"<<l<<\"][\"<<r<<\"][\"<<d<<\"] = \" << lrd2u[t&1][l][r][d] << endl;\n\t\t// }\n\t\t// rep(d,H) for(int u=d+1;u<=H;u++) rep(l,W){\n\t\t// \tcerr << \"dul2r[\"<<d<<\"][\"<<u<<\"][\"<<l<<\"] = \" << dul2r[t&1][d][u][l] << endl;\n\t\t// }\n\n\t\tif(lrd2u[t&1][0][W][0] == H){\n\t\t\tcout << t << endl;\n\t\t\treturn 0;\n\t\t}\n\n\t\trep(l,W) for(int r=l+1;r<=W;r++){\n\t\t\trep(d,H+1){\n\t\t\t\tlrd2u[1-(t&1)][l][r][d] = lrd2u[t&1][l][r][lrd2u[t&1][l][r][d]];\n\t\t\t}\n\t\t}\n\t\trep(d,H) for(int u=d+1;u<=H;u++){\n\t\t\trep(l,W+1){\n\t\t\t\tdul2r[1-(t&1)][d][u][l] = dul2r[t&1][d][u][dul2r[t&1][d][u][l]];\n\t\t\t}\n\t\t}\n\t\trep(l,W) for(int r=l+1;r<=W;r++){\n\t\t\trep(d,H+1){\n\t\t\t\tint u = lrd2u[1-(t&1)][l][r][d];\n\t\t\t\tchmax(dul2r[1-(t&1)][d][u][l],r);\n\t\t\t}\n\t\t}\n\t\trep(d,H) for(int u=d+1;u<=H;u++){\n\t\t\trep(l,W+1){\n\t\t\t\tint r = dul2r[1-(t&1)][d][u][l];\n\t\t\t\tchmax(lrd2u[1-(t&1)][l][r][d],u);\n\t\t\t}\n\t\t}\n\t\tfor(int len=W;len>0;len--){\n\t\t\trep(l,W){\n\t\t\t\tint r = l + len;\n\t\t\t\tif(r > W) break;\n\t\t\t\trep(d,H+1){\n\t\t\t\t\tchmax(lrd2u[1-(t&1)][l+1][r][d],lrd2u[1-(t&1)][l][r][d]);\n\t\t\t\t\tchmax(lrd2u[1-(t&1)][l][r-1][d],lrd2u[1-(t&1)][l][r][d]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor(int len=H;len>0;len--){\n\t\t\trep(d,H){\n\t\t\t\tint u = d + len;\n\t\t\t\tif(u > H) break;\n\t\t\t\trep(l,W+1){\n\t\t\t\t\tchmax(dul2r[1-(t&1)][d+1][u][l],dul2r[1-(t&1)][d][u][l]);\n\t\t\t\t\tchmax(dul2r[1-(t&1)][d][u-1][l],dul2r[1-(t&1)][d][u][l]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t\n\t}\n}\n", "language": "C++", "metadata": {"date": 1560219948, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03056.html", "problem_id": "p03056", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03056/input.txt", "sample_output_relpath": "derived/input_output/data/p03056/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03056/C++/s777741165.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s777741165", "user_id": "u309470177"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define rep(i,n) for(int i=0;i<(int)(n);i++)\n#define rep1(i,n) for(int i=1;i<=(int)(n);i++)\n#define all(c) c.begin(),c.end()\n#define pb push_back\n#define fs first\n#define sc second\n#define chmin(x,y) x=min(x,y)\n#define chmax(x,y) x=max(x,y)\nusing namespace std;\ntemplate<class S,class T> ostream& operator<<(ostream& o,const pair<S,T> &p){\n\treturn o<<\"(\"<<p.fs<<\",\"<<p.sc<<\")\";\n}\ntemplate<class T> ostream& operator<<(ostream& o,const vector<T> &vc){\n\to<<\"{\";\n\tfor(const T& v:vc) o<<v<<\",\";\n\to<<\"}\";\n\treturn o;\n}\nusing ll = long long;\ntemplate<class T> using V = vector<T>;\ntemplate<class T> using VV = vector<vector<T>>;\nconstexpr ll TEN(int n) { return (n == 0) ? 1 : 10 * TEN(n-1); }\n\n#ifdef LOCAL\n#define show(x) cerr << \"LINE\" << __LINE__ << \" : \" << #x << \" = \" << (x) << endl\n#else\n#define show(x) true\n#endif\n\nint H,W;\nV<string> s;\nconst int X = 187;\nint lrd2u[2][X][X][X];\nint dul2r[2][X][X][X];\n\nint A[X][X];\nbool allEqual(int d,int u,int l,int r){\n\tint c = A[u][r] - A[u][l] - A[d][r] + A[d][l];\n\treturn c == 0 || c == (u-d)*(r-l);\n}\n\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\t\t//DON'T USE scanf/printf/puts !!\n\tcout << fixed << setprecision(20);\n\t\n\tcin >> H >> W;\n\ts.resize(H);\n\trep(i,H) cin >> s[i];\n\trep(i,H) rep(j,W){\n\t\tif(s[i][j] == '#') A[i+1][j+1] = 1;\n\t}\n\trep(i,H+1) rep(j,W) A[i][j+1] += A[i][j];\n\trep(i,H) rep(j,W+1) A[i+1][j] += A[i][j];\n\n\n\n\trep(l,W) for(int r=l+1;r<=W;r++){\n\t\tlrd2u[0][l][r][H] = H;\n\t\tfor(int d=H-1;d>=0;d--){\n\t\t\tlrd2u[0][l][r][d] = d;\n\t\t\tif(allEqual(d,d+1,l,r)){\n\t\t\t\tlrd2u[0][l][r][d] = d + 1;\n\t\t\t\tif(d != H-1 && s[d][l] == s[d+1][l]) lrd2u[0][l][r][d] = lrd2u[0][l][r][d+1];\n\t\t\t}\n\t\t}\n\t}\n\trep(d,H) for(int u=d+1;u<=H;u++){\n\t\tdul2r[0][d][u][W] = W;\n\t\tfor(int l=W-1;l>=0;l--){\n\t\t\tdul2r[0][d][u][l] = l;\n\t\t\tif(allEqual(d,u,l,l+1)){\n\t\t\t\tdul2r[0][d][u][l] = l+1;\n\t\t\t\tif(l != W-1 && s[d][l] == s[d][l+1]) dul2r[0][d][u][l] = dul2r[0][d][u][l+1];\n\t\t\t}\n\t\t}\n\t}\n\trep(t,100){\n\n\t\t// cerr << \" -----------turn =  \" << t << endl;\n\t\t// rep(l,W) for(int r=l+1;r<=W;r++) rep(d,H){\n\t\t// \tcerr << \"lrd2u[\"<<l<<\"][\"<<r<<\"][\"<<d<<\"] = \" << lrd2u[t&1][l][r][d] << endl;\n\t\t// }\n\t\t// rep(d,H) for(int u=d+1;u<=H;u++) rep(l,W){\n\t\t// \tcerr << \"dul2r[\"<<d<<\"][\"<<u<<\"][\"<<l<<\"] = \" << dul2r[t&1][d][u][l] << endl;\n\t\t// }\n\n\t\tif(lrd2u[t&1][0][W][0] == H){\n\t\t\tcout << t << endl;\n\t\t\treturn 0;\n\t\t}\n\n\t\trep(l,W) for(int r=l+1;r<=W;r++){\n\t\t\trep(d,H+1){\n\t\t\t\tlrd2u[1-(t&1)][l][r][d] = lrd2u[t&1][l][r][lrd2u[t&1][l][r][d]];\n\t\t\t}\n\t\t}\n\t\trep(d,H) for(int u=d+1;u<=H;u++){\n\t\t\trep(l,W+1){\n\t\t\t\tdul2r[1-(t&1)][d][u][l] = dul2r[t&1][d][u][dul2r[t&1][d][u][l]];\n\t\t\t}\n\t\t}\n\t\trep(l,W) for(int r=l+1;r<=W;r++){\n\t\t\trep(d,H+1){\n\t\t\t\tint u = lrd2u[1-(t&1)][l][r][d];\n\t\t\t\tchmax(dul2r[1-(t&1)][d][u][l],r);\n\t\t\t}\n\t\t}\n\t\trep(d,H) for(int u=d+1;u<=H;u++){\n\t\t\trep(l,W+1){\n\t\t\t\tint r = dul2r[1-(t&1)][d][u][l];\n\t\t\t\tchmax(lrd2u[1-(t&1)][l][r][d],u);\n\t\t\t}\n\t\t}\n\t\tfor(int len=W;len>0;len--){\n\t\t\trep(l,W){\n\t\t\t\tint r = l + len;\n\t\t\t\tif(r > W) break;\n\t\t\t\trep(d,H+1){\n\t\t\t\t\tchmax(lrd2u[1-(t&1)][l+1][r][d],lrd2u[1-(t&1)][l][r][d]);\n\t\t\t\t\tchmax(lrd2u[1-(t&1)][l][r-1][d],lrd2u[1-(t&1)][l][r][d]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tfor(int len=H;len>0;len--){\n\t\t\trep(d,H){\n\t\t\t\tint u = d + len;\n\t\t\t\tif(u > H) break;\n\t\t\t\trep(l,W+1){\n\t\t\t\t\tchmax(dul2r[1-(t&1)][d+1][u][l],dul2r[1-(t&1)][d][u][l]);\n\t\t\t\t\tchmax(dul2r[1-(t&1)][d][u-1][l],dul2r[1-(t&1)][d][u][l]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\t\n\t}\n}\n", "problem_context": "Score : 1000 points\n\nProblem Statement\n\nNote the unusual memory limit.\n\nFor a rectangular grid where each square is painted white or black, we define its complexity as follows:\n\nIf all the squares are black or all the squares are white, the complexity is 0.\n\nOtherwise, divide the grid into two subgrids by a line parallel to one of the sides of the grid, and let c_1 and c_2 be the complexities of the subgrids. There can be multiple ways to perform the division, and let m be the minimum value of \\max(c_1, c_2) in those divisions. The complexity of the grid is m+1.\n\nYou are given a grid with H horizontal rows and W vertical columns where each square is painted white or black.\nHW characters from A_{11} to A_{HW} represent the colors of the squares.\nA_{ij} is # if the square at the i-th row from the top and the j-th column from the left is black, and A_{ij} is . if that square is white.\n\nFind the complexity of the given grid.\n\nConstraints\n\n1 \\leq H,W \\leq 185\n\nA_{ij} is # or ..\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W\nA_{11}A_{12}...A_{1W}\n:\nA_{H1}A_{H2}...A_{HW}\n\nOutput\n\nPrint the complexity of the given grid.\n\nSample Input 1\n\n3 3\n...\n.##\n.##\n\nSample Output 1\n\n2\n\nLet us divide the grid by the boundary line between the first and second columns.\nThe subgrid consisting of the first column has the complexity of 0, and the subgrid consisting of the second and third columns has the complexity of 1, so the whole grid has the complexity of at most 2.\n\nSample Input 2\n\n6 7\n.####.#\n#....#.\n#....#.\n#....#.\n.####.#\n#....##\n\nSample Output 2\n\n4", "sample_input": "3 3\n...\n.##\n.##\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03056", "source_text": "Score : 1000 points\n\nProblem Statement\n\nNote the unusual memory limit.\n\nFor a rectangular grid where each square is painted white or black, we define its complexity as follows:\n\nIf all the squares are black or all the squares are white, the complexity is 0.\n\nOtherwise, divide the grid into two subgrids by a line parallel to one of the sides of the grid, and let c_1 and c_2 be the complexities of the subgrids. There can be multiple ways to perform the division, and let m be the minimum value of \\max(c_1, c_2) in those divisions. The complexity of the grid is m+1.\n\nYou are given a grid with H horizontal rows and W vertical columns where each square is painted white or black.\nHW characters from A_{11} to A_{HW} represent the colors of the squares.\nA_{ij} is # if the square at the i-th row from the top and the j-th column from the left is black, and A_{ij} is . if that square is white.\n\nFind the complexity of the given grid.\n\nConstraints\n\n1 \\leq H,W \\leq 185\n\nA_{ij} is # or ..\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W\nA_{11}A_{12}...A_{1W}\n:\nA_{H1}A_{H2}...A_{HW}\n\nOutput\n\nPrint the complexity of the given grid.\n\nSample Input 1\n\n3 3\n...\n.##\n.##\n\nSample Output 1\n\n2\n\nLet us divide the grid by the boundary line between the first and second columns.\nThe subgrid consisting of the first column has the complexity of 0, and the subgrid consisting of the second and third columns has the complexity of 1, so the whole grid has the complexity of at most 2.\n\nSample Input 2\n\n6 7\n.####.#\n#....#.\n#....#.\n#....#.\n.####.#\n#....##\n\nSample Output 2\n\n4", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 3366, "cpu_time_ms": 616, "memory_kb": 100736}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s301492597", "group_id": "codeNet:p03059", "input_text": "#include<iostream>\n\nusing namespace std;\n\nint main()\n{\tint a,b,t;\n\tcin >> a >> b >> t;\n\tcout << (t/a) * b;\n}", "language": "C++", "metadata": {"date": 1556413423, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03059.html", "problem_id": "p03059", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03059/input.txt", "sample_output_relpath": "derived/input_output/data/p03059/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03059/C++/s301492597.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s301492597", "user_id": "u337741100"}, "prompt_components": {"gold_output": "10\n", "input_to_evaluate": "#include<iostream>\n\nusing namespace std;\n\nint main()\n{\tint a,b,t;\n\tcin >> a >> b >> t;\n\tcout << (t/a) * b;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nA biscuit making machine produces B biscuits at the following moments: A seconds, 2A seconds, 3A seconds and each subsequent multiple of A seconds after activation.\n\nFind the total number of biscuits produced within T + 0.5 seconds after activation.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq A, B, T \\leq 20\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B T\n\nOutput\n\nPrint the total number of biscuits produced within T + 0.5 seconds after activation.\n\nSample Input 1\n\n3 5 7\n\nSample Output 1\n\n10\n\nFive biscuits will be produced three seconds after activation.\n\nAnother five biscuits will be produced six seconds after activation.\n\nThus, a total of ten biscuits will be produced within 7.5 seconds after activation.\n\nSample Input 2\n\n3 2 9\n\nSample Output 2\n\n6\n\nSample Input 3\n\n20 20 19\n\nSample Output 3\n\n0", "sample_input": "3 5 7\n"}, "reference_outputs": ["10\n"], "source_document_id": "p03059", "source_text": "Score : 100 points\n\nProblem Statement\n\nA biscuit making machine produces B biscuits at the following moments: A seconds, 2A seconds, 3A seconds and each subsequent multiple of A seconds after activation.\n\nFind the total number of biscuits produced within T + 0.5 seconds after activation.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq A, B, T \\leq 20\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B T\n\nOutput\n\nPrint the total number of biscuits produced within T + 0.5 seconds after activation.\n\nSample Input 1\n\n3 5 7\n\nSample Output 1\n\n10\n\nFive biscuits will be produced three seconds after activation.\n\nAnother five biscuits will be produced six seconds after activation.\n\nThus, a total of ten biscuits will be produced within 7.5 seconds after activation.\n\nSample Input 2\n\n3 2 9\n\nSample Output 2\n\n6\n\nSample Input 3\n\n20 20 19\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 108, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s370515236", "group_id": "codeNet:p03060", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n#define FOR(i,l,r) for(long long i=(l);i<(r);++i)\n#define REP(i,n) FOR(i,0,n)\n#define int long long\n\nsigned main(){\n    int N;\n    cin>>N;\n    int ans=0;\n    int V[N],C[N];\n    REP(i,N){\n        cin>>V[i];\n    }\n    REP(i,N){\n        cin>>C[i];\n    }\n    REP(i,N){\n        if(V[i]-C[i]>0) ans+=V[i]-C[i];\n    }\n    cout<<ans<<endl;\n}", "language": "C++", "metadata": {"date": 1586913106, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03060.html", "problem_id": "p03060", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03060/input.txt", "sample_output_relpath": "derived/input_output/data/p03060/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03060/C++/s370515236.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s370515236", "user_id": "u342075214"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n#define FOR(i,l,r) for(long long i=(l);i<(r);++i)\n#define REP(i,n) FOR(i,0,n)\n#define int long long\n\nsigned main(){\n    int N;\n    cin>>N;\n    int ans=0;\n    int V[N],C[N];\n    REP(i,N){\n        cin>>V[i];\n    }\n    REP(i,N){\n        cin>>C[i];\n    }\n    REP(i,N){\n        if(V[i]-C[i]>0) ans+=V[i]-C[i];\n    }\n    cout<<ans<<endl;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nThere are N gems. The value of the i-th gem is V_i.\n\nYou will choose some of these gems, possibly all or none, and get them.\n\nHowever, you need to pay a cost of C_i to get the i-th gem.\n\nLet X be the sum of the values of the gems obtained, and Y be the sum of the costs paid.\n\nFind the maximum possible value of X-Y.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 20\n\n1 \\leq C_i, V_i \\leq 50\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nV_1 V_2 ... V_N\nC_1 C_2 ... C_N\n\nOutput\n\nPrint the maximum possible value of X-Y.\n\nSample Input 1\n\n3\n10 2 5\n6 3 4\n\nSample Output 1\n\n5\n\nIf we choose the first and third gems, X = 10 + 5 = 15 and Y = 6 + 4 = 10.\nWe have X-Y = 5 here, which is the maximum possible value.\n\nSample Input 2\n\n4\n13 21 6 19\n11 30 6 15\n\nSample Output 2\n\n6\n\nSample Input 3\n\n1\n1\n50\n\nSample Output 3\n\n0", "sample_input": "3\n10 2 5\n6 3 4\n"}, "reference_outputs": ["5\n"], "source_document_id": "p03060", "source_text": "Score : 200 points\n\nProblem Statement\n\nThere are N gems. The value of the i-th gem is V_i.\n\nYou will choose some of these gems, possibly all or none, and get them.\n\nHowever, you need to pay a cost of C_i to get the i-th gem.\n\nLet X be the sum of the values of the gems obtained, and Y be the sum of the costs paid.\n\nFind the maximum possible value of X-Y.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 20\n\n1 \\leq C_i, V_i \\leq 50\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nV_1 V_2 ... V_N\nC_1 C_2 ... C_N\n\nOutput\n\nPrint the maximum possible value of X-Y.\n\nSample Input 1\n\n3\n10 2 5\n6 3 4\n\nSample Output 1\n\n5\n\nIf we choose the first and third gems, X = 10 + 5 = 15 and Y = 6 + 4 = 10.\nWe have X-Y = 5 here, which is the maximum possible value.\n\nSample Input 2\n\n4\n13 21 6 19\n11 30 6 15\n\nSample Output 2\n\n6\n\nSample Input 3\n\n1\n1\n50\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 378, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s953322322", "group_id": "codeNet:p03060", "input_text": "//     nohomo    //\n//  Brankonymous //\n//     nohomo    //\n\n#include <bits/stdc++.h>\n\n#define ios ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);\n#define rep(i,l,r) for (int i=l;i<=r;i++)\n#define fi first\n#define se second\n#define pb push_back\n#define all(x) (x).begin(), (x).end()\n#define rall(x) (x).rbegin(), (x).rend()\n#define ll long long\n#define mod 1000000007\n#define random_jbt mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());\n\nusing namespace std;\n\nint main(){\n    int n,v[30],b[30];\n    cin>>n;\n    int ans=0;\n    for (int i=1;i<=n;i++)cin>>v[i];\n    for (int i=1;i<=n;i++){\n        cin>>b[i];\n        ans+=max(0,v[i]-b[i]);\n    }\n    cout<<ans;\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1556413597, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03060.html", "problem_id": "p03060", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03060/input.txt", "sample_output_relpath": "derived/input_output/data/p03060/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03060/C++/s953322322.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s953322322", "user_id": "u222917819"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "//     nohomo    //\n//  Brankonymous //\n//     nohomo    //\n\n#include <bits/stdc++.h>\n\n#define ios ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);\n#define rep(i,l,r) for (int i=l;i<=r;i++)\n#define fi first\n#define se second\n#define pb push_back\n#define all(x) (x).begin(), (x).end()\n#define rall(x) (x).rbegin(), (x).rend()\n#define ll long long\n#define mod 1000000007\n#define random_jbt mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());\n\nusing namespace std;\n\nint main(){\n    int n,v[30],b[30];\n    cin>>n;\n    int ans=0;\n    for (int i=1;i<=n;i++)cin>>v[i];\n    for (int i=1;i<=n;i++){\n        cin>>b[i];\n        ans+=max(0,v[i]-b[i]);\n    }\n    cout<<ans;\n    return 0;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nThere are N gems. The value of the i-th gem is V_i.\n\nYou will choose some of these gems, possibly all or none, and get them.\n\nHowever, you need to pay a cost of C_i to get the i-th gem.\n\nLet X be the sum of the values of the gems obtained, and Y be the sum of the costs paid.\n\nFind the maximum possible value of X-Y.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 20\n\n1 \\leq C_i, V_i \\leq 50\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nV_1 V_2 ... V_N\nC_1 C_2 ... C_N\n\nOutput\n\nPrint the maximum possible value of X-Y.\n\nSample Input 1\n\n3\n10 2 5\n6 3 4\n\nSample Output 1\n\n5\n\nIf we choose the first and third gems, X = 10 + 5 = 15 and Y = 6 + 4 = 10.\nWe have X-Y = 5 here, which is the maximum possible value.\n\nSample Input 2\n\n4\n13 21 6 19\n11 30 6 15\n\nSample Output 2\n\n6\n\nSample Input 3\n\n1\n1\n50\n\nSample Output 3\n\n0", "sample_input": "3\n10 2 5\n6 3 4\n"}, "reference_outputs": ["5\n"], "source_document_id": "p03060", "source_text": "Score : 200 points\n\nProblem Statement\n\nThere are N gems. The value of the i-th gem is V_i.\n\nYou will choose some of these gems, possibly all or none, and get them.\n\nHowever, you need to pay a cost of C_i to get the i-th gem.\n\nLet X be the sum of the values of the gems obtained, and Y be the sum of the costs paid.\n\nFind the maximum possible value of X-Y.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 20\n\n1 \\leq C_i, V_i \\leq 50\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nV_1 V_2 ... V_N\nC_1 C_2 ... C_N\n\nOutput\n\nPrint the maximum possible value of X-Y.\n\nSample Input 1\n\n3\n10 2 5\n6 3 4\n\nSample Output 1\n\n5\n\nIf we choose the first and third gems, X = 10 + 5 = 15 and Y = 6 + 4 = 10.\nWe have X-Y = 5 here, which is the maximum possible value.\n\nSample Input 2\n\n4\n13 21 6 19\n11 30 6 15\n\nSample Output 2\n\n6\n\nSample Input 3\n\n1\n1\n50\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 697, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s632603412", "group_id": "codeNet:p03062", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  int n;\n  cin >> n;\n  int a[n];\n  int minus = 0;\n  for(int i = 0; i < n; i++) {\n    cin >> a[i];\n    if(a[i] < 0) minus++;\n  }\n  int ans = 0;\n  for(int i = 0; i < n; i++) {\n    ans += abs(a[i]);\n  }\n  bool f = 1;\n  for(int i = 0; i < n; i++) {\n    if(a[i] == 0) f = 0;\n  }\n  int AT[n];\n  for(int i = 0; i < n; i++) {\n    AT[i] = abs(a[i]);\n  }\n  if(f) {\n    if(minus % 2 == 1) {\n      sort(AT, AT + n);\n      ans -= AT[0];\n    }\n  }\n  cout << ans << endl;\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1558059351, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03062.html", "problem_id": "p03062", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03062/input.txt", "sample_output_relpath": "derived/input_output/data/p03062/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03062/C++/s632603412.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s632603412", "user_id": "u681869152"}, "prompt_components": {"gold_output": "19\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  int n;\n  cin >> n;\n  int a[n];\n  int minus = 0;\n  for(int i = 0; i < n; i++) {\n    cin >> a[i];\n    if(a[i] < 0) minus++;\n  }\n  int ans = 0;\n  for(int i = 0; i < n; i++) {\n    ans += abs(a[i]);\n  }\n  bool f = 1;\n  for(int i = 0; i < n; i++) {\n    if(a[i] == 0) f = 0;\n  }\n  int AT[n];\n  for(int i = 0; i < n; i++) {\n    AT[i] = abs(a[i]);\n  }\n  if(f) {\n    if(minus % 2 == 1) {\n      sort(AT, AT + n);\n      ans -= AT[0];\n    }\n  }\n  cout << ans << endl;\n  return 0;\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nThere are N integers, A_1, A_2, ..., A_N, arranged in a row in this order.\n\nYou can perform the following operation on this integer sequence any number of times:\n\nOperation: Choose an integer i satisfying 1 \\leq i \\leq N-1. Multiply both A_i and A_{i+1} by -1.\n\nLet B_1, B_2, ..., B_N be the integer sequence after your operations.\n\nFind the maximum possible value of B_1 + B_2 + ... + B_N.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 10^5\n\n-10^9 \\leq A_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the maximum possible value of B_1 + B_2 + ... + B_N.\n\nSample Input 1\n\n3\n-10 5 -4\n\nSample Output 1\n\n19\n\nIf we perform the operation as follows:\n\nChoose 1 as i, which changes the sequence to 10, -5, -4.\n\nChoose 2 as i, which changes the sequence to 10, 5, 4.\n\nwe have B_1 = 10, B_2 = 5, B_3 = 4. The sum here, B_1 + B_2 + B_3 = 10 + 5 + 4 = 19, is the maximum possible result.\n\nSample Input 2\n\n5\n10 -4 -8 -11 3\n\nSample Output 2\n\n30\n\nSample Input 3\n\n11\n-1000000000 1000000000 -1000000000 1000000000 -1000000000 0 1000000000 -1000000000 1000000000 -1000000000 1000000000\n\nSample Output 3\n\n10000000000\n\nThe output may not fit into a 32-bit integer type.", "sample_input": "3\n-10 5 -4\n"}, "reference_outputs": ["19\n"], "source_document_id": "p03062", "source_text": "Score : 400 points\n\nProblem Statement\n\nThere are N integers, A_1, A_2, ..., A_N, arranged in a row in this order.\n\nYou can perform the following operation on this integer sequence any number of times:\n\nOperation: Choose an integer i satisfying 1 \\leq i \\leq N-1. Multiply both A_i and A_{i+1} by -1.\n\nLet B_1, B_2, ..., B_N be the integer sequence after your operations.\n\nFind the maximum possible value of B_1 + B_2 + ... + B_N.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 10^5\n\n-10^9 \\leq A_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the maximum possible value of B_1 + B_2 + ... + B_N.\n\nSample Input 1\n\n3\n-10 5 -4\n\nSample Output 1\n\n19\n\nIf we perform the operation as follows:\n\nChoose 1 as i, which changes the sequence to 10, -5, -4.\n\nChoose 2 as i, which changes the sequence to 10, 5, 4.\n\nwe have B_1 = 10, B_2 = 5, B_3 = 4. The sum here, B_1 + B_2 + B_3 = 10 + 5 + 4 = 19, is the maximum possible result.\n\nSample Input 2\n\n5\n10 -4 -8 -11 3\n\nSample Output 2\n\n30\n\nSample Input 3\n\n11\n-1000000000 1000000000 -1000000000 1000000000 -1000000000 0 1000000000 -1000000000 1000000000 -1000000000 1000000000\n\nSample Output 3\n\n10000000000\n\nThe output may not fit into a 32-bit integer type.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 530, "cpu_time_ms": 63, "memory_kb": 1024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s620936868", "group_id": "codeNet:p03064", "input_text": "#include <iostream>\n#include <vector>\n#include <map>\n#include <unordered_map>\n#include <queue>\n#include <set>\n#include <algorithm>\n#include <string>\n#include <math.h>\n#include <limits.h>\n#include <stack>\n#include <complex>\n#include <stdlib.h>\n#include <stdio.h>\n#include <functional>\n#include <cfloat>\n#include <math.h>\n\n\n#define fs first\n#define sc second\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair<ll, int> P;\nll mod = 998244353;\n\nbool pp[2][101000];\nint N;\nint a[300];\nvector<vector<ll>> dp(2, vector<ll>(1010000, 0));\nunordered_map<int, int> mp;\nvector<int> e;\n\n\nint main(){\n    cin >> N;\n    int s = 0;\n    for(int i = 0; i < N; i++){\n        cin >> a[i];\n        s += a[i];\n    }\n\n    pp[0][0] = true;\n    for(int i = 0; i < N; i++){\n        for(int j = 0; j < 101000; j++){\n            pp[1][j] = pp[0][j];\n            if(j - a[i] >= 0 && pp[0][j-a[i]]){\n                pp[1][j] = true;\n            }\n        }\n        for(int j = 0; j < 101000; j++){\n            pp[0][j] = pp[1][j];\n        }\n    }\n\n    for(int i = 0; i < 101000; i++){\n        if(pp[0][i]){\n            e.push_back(i);\n        }\n    }\n\n    for(int i = 0; i < e.size(); i++){\n        mp[e[i]] = i;\n    }\n\n    int n = e.size();\n    dp[1][0] = 1;\n\n    for(int i = 0; i < N; i++){\n        int p = i % 2;\n        int q = 1 - p;\n        int x = a[i];\n        for(int j = 0; j < n*n; j++){\n            int red_w = e[j % n];\n            int red_index = j % n;\n            int blue_w = e[(j / n)];\n            int blue_index = (j / n) * n;\n            if(mp.find(x+red_w) != mp.end()){\n                // 赤に加える\n                int index = mp[red_w + x];\n                ll add_red = (dp[p][blue_index + index] + dp[q][j]) % mod;\n                dp[p][blue_index + index] = add_red;\n            }\n\n            if(mp.find(x+blue_w) != mp.end()){\n                // 青に加える\n                int index = mp[x + blue_w];\n                ll add_blue = (dp[p][index * n + red_index] + dp[q][j]) % mod;\n                dp[p][index * n + red_index] = add_blue;\n            }\n            // 緑に加える\n            ll add_green = (dp[p][j] + dp[q][j]) % mod;\n            dp[p][j] = add_green;\n        }\n        fill(dp[q].begin(), dp[q].end(), 0);\n    }\n\n    ll ret = 0;\n    int p = (N-1) % 2;\n    for(int i = 0; i < n*n; i++){\n        int red = e[i % n];\n        int blue = e[(i / n)];\n        int green = s - red - blue;\n        if(red + green > blue && red + blue > green && blue + green > red){\n            ret = (ret + dp[p][i]) % mod;\n        }\n    }\n    ret = (ret) % mod;\n\n    cout << ret << endl;\n\n\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1555812778, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03064.html", "problem_id": "p03064", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03064/input.txt", "sample_output_relpath": "derived/input_output/data/p03064/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03064/C++/s620936868.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s620936868", "user_id": "u852158538"}, "prompt_components": {"gold_output": "18\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\n#include <map>\n#include <unordered_map>\n#include <queue>\n#include <set>\n#include <algorithm>\n#include <string>\n#include <math.h>\n#include <limits.h>\n#include <stack>\n#include <complex>\n#include <stdlib.h>\n#include <stdio.h>\n#include <functional>\n#include <cfloat>\n#include <math.h>\n\n\n#define fs first\n#define sc second\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair<ll, int> P;\nll mod = 998244353;\n\nbool pp[2][101000];\nint N;\nint a[300];\nvector<vector<ll>> dp(2, vector<ll>(1010000, 0));\nunordered_map<int, int> mp;\nvector<int> e;\n\n\nint main(){\n    cin >> N;\n    int s = 0;\n    for(int i = 0; i < N; i++){\n        cin >> a[i];\n        s += a[i];\n    }\n\n    pp[0][0] = true;\n    for(int i = 0; i < N; i++){\n        for(int j = 0; j < 101000; j++){\n            pp[1][j] = pp[0][j];\n            if(j - a[i] >= 0 && pp[0][j-a[i]]){\n                pp[1][j] = true;\n            }\n        }\n        for(int j = 0; j < 101000; j++){\n            pp[0][j] = pp[1][j];\n        }\n    }\n\n    for(int i = 0; i < 101000; i++){\n        if(pp[0][i]){\n            e.push_back(i);\n        }\n    }\n\n    for(int i = 0; i < e.size(); i++){\n        mp[e[i]] = i;\n    }\n\n    int n = e.size();\n    dp[1][0] = 1;\n\n    for(int i = 0; i < N; i++){\n        int p = i % 2;\n        int q = 1 - p;\n        int x = a[i];\n        for(int j = 0; j < n*n; j++){\n            int red_w = e[j % n];\n            int red_index = j % n;\n            int blue_w = e[(j / n)];\n            int blue_index = (j / n) * n;\n            if(mp.find(x+red_w) != mp.end()){\n                // 赤に加える\n                int index = mp[red_w + x];\n                ll add_red = (dp[p][blue_index + index] + dp[q][j]) % mod;\n                dp[p][blue_index + index] = add_red;\n            }\n\n            if(mp.find(x+blue_w) != mp.end()){\n                // 青に加える\n                int index = mp[x + blue_w];\n                ll add_blue = (dp[p][index * n + red_index] + dp[q][j]) % mod;\n                dp[p][index * n + red_index] = add_blue;\n            }\n            // 緑に加える\n            ll add_green = (dp[p][j] + dp[q][j]) % mod;\n            dp[p][j] = add_green;\n        }\n        fill(dp[q].begin(), dp[q].end(), 0);\n    }\n\n    ll ret = 0;\n    int p = (N-1) % 2;\n    for(int i = 0; i < n*n; i++){\n        int red = e[i % n];\n        int blue = e[(i / n)];\n        int green = s - red - blue;\n        if(red + green > blue && red + blue > green && blue + green > red){\n            ret = (ret + dp[p][i]) % mod;\n        }\n    }\n    ret = (ret) % mod;\n\n    cout << ret << endl;\n\n\n    return 0;\n}\n", "problem_context": "Score : 600 points\n\nProblem Statement\n\nYou are given N integers. The i-th integer is a_i.\nFind the number, modulo 998244353, of ways to paint each of the integers red, green or blue so that the following condition is satisfied:\n\nLet R, G and B be the sums of the integers painted red, green and blue, respectively. There exists a triangle with positive area whose sides have lengths R, G and B.\n\nConstraints\n\n3 \\leq N \\leq 300\n\n1 \\leq a_i \\leq 300(1\\leq i\\leq N)\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1\n:\na_N\n\nOutput\n\nPrint the number, modulo 998244353, of ways to paint each of the integers red, green or blue so that the condition is satisfied.\n\nSample Input 1\n\n4\n1\n1\n1\n2\n\nSample Output 1\n\n18\n\nWe can only paint the integers so that the lengths of the sides of the triangle will be 1, 2 and 2, and there are 18 such ways.\n\nSample Input 2\n\n6\n1\n3\n2\n3\n5\n2\n\nSample Output 2\n\n150\n\nSample Input 3\n\n20\n3\n1\n4\n1\n5\n9\n2\n6\n5\n3\n5\n8\n9\n7\n9\n3\n2\n3\n8\n4\n\nSample Output 3\n\n563038556", "sample_input": "4\n1\n1\n1\n2\n"}, "reference_outputs": ["18\n"], "source_document_id": "p03064", "source_text": "Score : 600 points\n\nProblem Statement\n\nYou are given N integers. The i-th integer is a_i.\nFind the number, modulo 998244353, of ways to paint each of the integers red, green or blue so that the following condition is satisfied:\n\nLet R, G and B be the sums of the integers painted red, green and blue, respectively. There exists a triangle with positive area whose sides have lengths R, G and B.\n\nConstraints\n\n3 \\leq N \\leq 300\n\n1 \\leq a_i \\leq 300(1\\leq i\\leq N)\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1\n:\na_N\n\nOutput\n\nPrint the number, modulo 998244353, of ways to paint each of the integers red, green or blue so that the condition is satisfied.\n\nSample Input 1\n\n4\n1\n1\n1\n2\n\nSample Output 1\n\n18\n\nWe can only paint the integers so that the lengths of the sides of the triangle will be 1, 2 and 2, and there are 18 such ways.\n\nSample Input 2\n\n6\n1\n3\n2\n3\n5\n2\n\nSample Output 2\n\n150\n\nSample Input 3\n\n20\n3\n1\n4\n1\n5\n9\n2\n6\n5\n3\n5\n8\n9\n7\n9\n3\n2\n3\n8\n4\n\nSample Output 3\n\n563038556", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2619, "cpu_time_ms": 3156, "memory_kb": 23936}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s849213338", "group_id": "codeNet:p03069", "input_text": "#include<iostream>\n#include<string>\n#include<cmath>\n#include<array>\n#include<algorithm>\n#include<deque>\n#include<vector>\n#include<utility>\n#include<set>\n#include<map>\n#include<list>\n#include<bitset>\n\nusing namespace std;\nusing LLI = long long int;\nLLI N;\n\n//array<int, 8>dir_x = { 0,0,1,1,1,-1,-1,-1 };\n//array<int, 8>dir_y = { 1,-1,1,0,-1,1,0,-1 };\n//array<int, 4>dir_x2 = { 0,0,1,-1 };\n//array<int, 4>dir_y2 = { 1,-1,0,0 };\n//char alp[] = { 'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z' };\n\n//class UnionFind {\n//public:\n//\tvector<int>data;\n//\tUnionFind(int size) :data(size, -1) {};\n//\tbool unionset(int x, int y) {\n//\t\tx = root(x), y = root(y);\n//\t\tif (x != y) {\n//\t\t\tif (data[y] < data[x]) {\n//\t\t\t\tswap(x, y);\n//\t\t\t}\n//\t\t\tdata[x] += data[y];\n//\t\t\tdata[y] = x;\n//\t\t}\n//\t\treturn x != y;\n//\t}\n//\tbool findset(int x, int y) {\n//\t\treturn root(x) == root(y);\n//\t}\n//\tint root(int x) {\n//\t\treturn data[x] < 0 ? x : data[x] = root(data[x]);\n//\t}\n//\tint size(int x) {\n//\t\treturn -data[root(x)];\n//\t}\n//};\n\n//LLI gcd(LLI x, LLI y) {\n//\tLLI  r;\n//\tif (x < y) {\n//\t\tswap(x,y);\n//\t}\n//\tr = x % y;\n//\twhile (r != 0) {\n//\t\tx = y;\n//\t\ty = r;\n//\t\tr = x % y;\n//\t}\n//\treturn y;\n//}\n//LLI lcm(LLI x,LLI y) {\n//\treturn x / gcd(x,y) * y;\n//}\n\n//long nCr(int n,int r) {\n//\tlong ans = 1;\n//\tfor (int i = n; i > n - r;i--) {\n//\t\tans = ans * i;\n//\t}\n//\tfor (int i = 1; i < r + 1;i++) {\n//\t\tans = ans / i;\n//\t}\n//\treturn ans;\n//}\n\n//const int n_max = 8;\n//array<array<bool, n_max>, n_max>graph;\n//int dfs(int v,int N,array<bool,n_max>visited) {\n//\tint ret = 0;\n//\tbool all_visited = true;\n//\tfor (int i = 0; i < N;i++) {\n//\t\tif (visited[i] == false) {\n//\t\t\tall_visited = false;\n//\t\t}\n//\t}\t\n//\tif (all_visited) {\n//\t\treturn 1;\n//\t}\n//\tfor (int i = 0; i < N;i++) {\n//\t\tif (graph[v][i] == false) {\n//\t\t\tcontinue;\n//\t\t}\n//\t\tif (visited[i] == true) {\n//\t\t\tcontinue;\n//\t\t}\n//\t\tvisited[i] = true;\n//\t\tret += dfs(i,N,visited);\n//\t\tvisited[i] = false;\n//\t}\n//\treturn ret;\n//}\n\n//vector<vector<int>>sub;\n//int dfs(int id) {\n//\tif (sub[id].size() == 0) {\n//\t\treturn 1;\n//\t}\n//\tint minP = (int)1e9;\n//\tint maxP = 0;\n//\tfor (int i : sub[id]) {\n//\t\tint P = dfs(i);\n//\t\tminP = min(minP, P);\n//\t\tmaxP = max(maxP, P);\n//\t}\n//\treturn minP + maxP + 1;\n//}\n\n#define debug(x) cerr << #x << \" : \" << x << endl\n#define debugv(x) cerr << #x << \" : \"; for(auto i:x) cerr << i << \", \"; cerr<<endl\n\nint main(void) {\n\tstring S;\n\tbool d = true;\n\tLLI b = 0, w = 0;\n\tcin >> N >> S;\n\tLLI last = N,first = 0;\n\tfor (int i = 0; i < N;i++) {\n\t\tif (S[i] == '.') {\n\t\t\tfirst++;\n\t\t}\n\t\telse {\n\t\t\tbreak;\n\t\t}\n\t}\n\tfor (int i = N - 1; i >= first;i--) {\n\t\tif (S[i] == '#') {\n\t\t\tif (d == true) {\n\t\t\t\tlast--;\n\t\t\t}\n\t\t}\n\t\telse {\n\t\t\tw++;\n\t\t\td = false;\n\t\t}\n\t}\n\tfor (int i = 0; i < last;i++) {\n\t\tif (S[i] == '#') {\n\t\t\tb++;\n\t\t}\n\t}\n\tLLI res = min(b,w);\n\tcout << res << endl;\n}", "language": "C++", "metadata": {"date": 1555811991, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03069.html", "problem_id": "p03069", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03069/input.txt", "sample_output_relpath": "derived/input_output/data/p03069/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03069/C++/s849213338.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s849213338", "user_id": "u457033460"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include<iostream>\n#include<string>\n#include<cmath>\n#include<array>\n#include<algorithm>\n#include<deque>\n#include<vector>\n#include<utility>\n#include<set>\n#include<map>\n#include<list>\n#include<bitset>\n\nusing namespace std;\nusing LLI = long long int;\nLLI N;\n\n//array<int, 8>dir_x = { 0,0,1,1,1,-1,-1,-1 };\n//array<int, 8>dir_y = { 1,-1,1,0,-1,1,0,-1 };\n//array<int, 4>dir_x2 = { 0,0,1,-1 };\n//array<int, 4>dir_y2 = { 1,-1,0,0 };\n//char alp[] = { 'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z' };\n\n//class UnionFind {\n//public:\n//\tvector<int>data;\n//\tUnionFind(int size) :data(size, -1) {};\n//\tbool unionset(int x, int y) {\n//\t\tx = root(x), y = root(y);\n//\t\tif (x != y) {\n//\t\t\tif (data[y] < data[x]) {\n//\t\t\t\tswap(x, y);\n//\t\t\t}\n//\t\t\tdata[x] += data[y];\n//\t\t\tdata[y] = x;\n//\t\t}\n//\t\treturn x != y;\n//\t}\n//\tbool findset(int x, int y) {\n//\t\treturn root(x) == root(y);\n//\t}\n//\tint root(int x) {\n//\t\treturn data[x] < 0 ? x : data[x] = root(data[x]);\n//\t}\n//\tint size(int x) {\n//\t\treturn -data[root(x)];\n//\t}\n//};\n\n//LLI gcd(LLI x, LLI y) {\n//\tLLI  r;\n//\tif (x < y) {\n//\t\tswap(x,y);\n//\t}\n//\tr = x % y;\n//\twhile (r != 0) {\n//\t\tx = y;\n//\t\ty = r;\n//\t\tr = x % y;\n//\t}\n//\treturn y;\n//}\n//LLI lcm(LLI x,LLI y) {\n//\treturn x / gcd(x,y) * y;\n//}\n\n//long nCr(int n,int r) {\n//\tlong ans = 1;\n//\tfor (int i = n; i > n - r;i--) {\n//\t\tans = ans * i;\n//\t}\n//\tfor (int i = 1; i < r + 1;i++) {\n//\t\tans = ans / i;\n//\t}\n//\treturn ans;\n//}\n\n//const int n_max = 8;\n//array<array<bool, n_max>, n_max>graph;\n//int dfs(int v,int N,array<bool,n_max>visited) {\n//\tint ret = 0;\n//\tbool all_visited = true;\n//\tfor (int i = 0; i < N;i++) {\n//\t\tif (visited[i] == false) {\n//\t\t\tall_visited = false;\n//\t\t}\n//\t}\t\n//\tif (all_visited) {\n//\t\treturn 1;\n//\t}\n//\tfor (int i = 0; i < N;i++) {\n//\t\tif (graph[v][i] == false) {\n//\t\t\tcontinue;\n//\t\t}\n//\t\tif (visited[i] == true) {\n//\t\t\tcontinue;\n//\t\t}\n//\t\tvisited[i] = true;\n//\t\tret += dfs(i,N,visited);\n//\t\tvisited[i] = false;\n//\t}\n//\treturn ret;\n//}\n\n//vector<vector<int>>sub;\n//int dfs(int id) {\n//\tif (sub[id].size() == 0) {\n//\t\treturn 1;\n//\t}\n//\tint minP = (int)1e9;\n//\tint maxP = 0;\n//\tfor (int i : sub[id]) {\n//\t\tint P = dfs(i);\n//\t\tminP = min(minP, P);\n//\t\tmaxP = max(maxP, P);\n//\t}\n//\treturn minP + maxP + 1;\n//}\n\n#define debug(x) cerr << #x << \" : \" << x << endl\n#define debugv(x) cerr << #x << \" : \"; for(auto i:x) cerr << i << \", \"; cerr<<endl\n\nint main(void) {\n\tstring S;\n\tbool d = true;\n\tLLI b = 0, w = 0;\n\tcin >> N >> S;\n\tLLI last = N,first = 0;\n\tfor (int i = 0; i < N;i++) {\n\t\tif (S[i] == '.') {\n\t\t\tfirst++;\n\t\t}\n\t\telse {\n\t\t\tbreak;\n\t\t}\n\t}\n\tfor (int i = N - 1; i >= first;i--) {\n\t\tif (S[i] == '#') {\n\t\t\tif (d == true) {\n\t\t\t\tlast--;\n\t\t\t}\n\t\t}\n\t\telse {\n\t\t\tw++;\n\t\t\td = false;\n\t\t}\n\t}\n\tfor (int i = 0; i < last;i++) {\n\t\tif (S[i] == '#') {\n\t\t\tb++;\n\t\t}\n\t}\n\tLLI res = min(b,w);\n\tcout << res << endl;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N stones arranged in a row. Every stone is painted white or black.\nA string S represents the color of the stones. The i-th stone from the left is white if the i-th character of S is ., and the stone is black if the character is #.\n\nTakahashi wants to change the colors of some stones to black or white so that there will be no white stone immediately to the right of a black stone.\nFind the minimum number of stones that needs to be recolored.\n\nConstraints\n\n1 \\leq N \\leq 2\\times 10^5\n\nS is a string of length N consisting of . and #.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS\n\nOutput\n\nPrint the minimum number of stones that needs to be recolored.\n\nSample Input 1\n\n3\n#.#\n\nSample Output 1\n\n1\n\nIt is enough to change the color of the first stone to white.\n\nSample Input 2\n\n5\n#.##.\n\nSample Output 2\n\n2\n\nSample Input 3\n\n9\n.........\n\nSample Output 3\n\n0", "sample_input": "3\n#.#\n"}, "reference_outputs": ["1\n"], "source_document_id": "p03069", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N stones arranged in a row. Every stone is painted white or black.\nA string S represents the color of the stones. The i-th stone from the left is white if the i-th character of S is ., and the stone is black if the character is #.\n\nTakahashi wants to change the colors of some stones to black or white so that there will be no white stone immediately to the right of a black stone.\nFind the minimum number of stones that needs to be recolored.\n\nConstraints\n\n1 \\leq N \\leq 2\\times 10^5\n\nS is a string of length N consisting of . and #.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS\n\nOutput\n\nPrint the minimum number of stones that needs to be recolored.\n\nSample Input 1\n\n3\n#.#\n\nSample Output 1\n\n1\n\nIt is enough to change the color of the first stone to white.\n\nSample Input 2\n\n5\n#.##.\n\nSample Output 2\n\n2\n\nSample Input 3\n\n9\n.........\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2857, "cpu_time_ms": 9, "memory_kb": 640}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s826134168", "group_id": "codeNet:p03069", "input_text": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <cmath>\n#include <cstring>\n#include <iomanip>\n#include <random>\n#include <chrono>\n#include <queue>\n#include <ctime>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int, int> PII;\ntypedef pair<ll, ll> PLL;\n#define fs first\n#define sc second\n#define INF 1000000000\n#define MOD 1000000007\n#define EPS 0.00000001\n\n\nint main() {\n    int N; cin >> N;\n    string S; cin >> S;\n    \n    bool b = false;\n    int cntw = 0;\n    for(int i=0; i<N; i++){\n        if(S[i]=='#') b = true;\n        if(b && S[i]=='.') cntw++;\n    }\n    \n    bool w = false;\n    int cntb = 0;\n    for(int i=N-1; i>=0; i--){\n        if(S[i]=='.') w = true;\n        if(w && S[i]=='#') cntb++;\n    }\n    \n    cout << min(cntb, cntw) << endl;\n    \n    \n    \n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1555810366, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03069.html", "problem_id": "p03069", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03069/input.txt", "sample_output_relpath": "derived/input_output/data/p03069/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03069/C++/s826134168.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s826134168", "user_id": "u290693410"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <cmath>\n#include <cstring>\n#include <iomanip>\n#include <random>\n#include <chrono>\n#include <queue>\n#include <ctime>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int, int> PII;\ntypedef pair<ll, ll> PLL;\n#define fs first\n#define sc second\n#define INF 1000000000\n#define MOD 1000000007\n#define EPS 0.00000001\n\n\nint main() {\n    int N; cin >> N;\n    string S; cin >> S;\n    \n    bool b = false;\n    int cntw = 0;\n    for(int i=0; i<N; i++){\n        if(S[i]=='#') b = true;\n        if(b && S[i]=='.') cntw++;\n    }\n    \n    bool w = false;\n    int cntb = 0;\n    for(int i=N-1; i>=0; i--){\n        if(S[i]=='.') w = true;\n        if(w && S[i]=='#') cntb++;\n    }\n    \n    cout << min(cntb, cntw) << endl;\n    \n    \n    \n    return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N stones arranged in a row. Every stone is painted white or black.\nA string S represents the color of the stones. The i-th stone from the left is white if the i-th character of S is ., and the stone is black if the character is #.\n\nTakahashi wants to change the colors of some stones to black or white so that there will be no white stone immediately to the right of a black stone.\nFind the minimum number of stones that needs to be recolored.\n\nConstraints\n\n1 \\leq N \\leq 2\\times 10^5\n\nS is a string of length N consisting of . and #.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS\n\nOutput\n\nPrint the minimum number of stones that needs to be recolored.\n\nSample Input 1\n\n3\n#.#\n\nSample Output 1\n\n1\n\nIt is enough to change the color of the first stone to white.\n\nSample Input 2\n\n5\n#.##.\n\nSample Output 2\n\n2\n\nSample Input 3\n\n9\n.........\n\nSample Output 3\n\n0", "sample_input": "3\n#.#\n"}, "reference_outputs": ["1\n"], "source_document_id": "p03069", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N stones arranged in a row. Every stone is painted white or black.\nA string S represents the color of the stones. The i-th stone from the left is white if the i-th character of S is ., and the stone is black if the character is #.\n\nTakahashi wants to change the colors of some stones to black or white so that there will be no white stone immediately to the right of a black stone.\nFind the minimum number of stones that needs to be recolored.\n\nConstraints\n\n1 \\leq N \\leq 2\\times 10^5\n\nS is a string of length N consisting of . and #.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS\n\nOutput\n\nPrint the minimum number of stones that needs to be recolored.\n\nSample Input 1\n\n3\n#.#\n\nSample Output 1\n\n1\n\nIt is enough to change the color of the first stone to white.\n\nSample Input 2\n\n5\n#.##.\n\nSample Output 2\n\n2\n\nSample Input 3\n\n9\n.........\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 839, "cpu_time_ms": 10, "memory_kb": 640}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s799382108", "group_id": "codeNet:p03071", "input_text": "#include <iostream>\nusing namespace std;\n\nint main() {\n    int a,b;\n    cin>>a>>b;\n    cout<<(a==b?a+b:max(a,b)*2-1)<<endl;\n}\n", "language": "C++", "metadata": {"date": 1588417884, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03071.html", "problem_id": "p03071", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03071/input.txt", "sample_output_relpath": "derived/input_output/data/p03071/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03071/C++/s799382108.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s799382108", "user_id": "u590427200"}, "prompt_components": {"gold_output": "9\n", "input_to_evaluate": "#include <iostream>\nusing namespace std;\n\nint main() {\n    int a,b;\n    cin>>a>>b;\n    cout<<(a==b?a+b:max(a,b)*2-1)<<endl;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nThere are two buttons, one of size A and one of size B.\n\nWhen you press a button of size X, you get X coins and the size of that button decreases by 1.\n\nYou will press a button twice. Here, you can press the same button twice, or press both buttons once.\n\nAt most how many coins can you get?\n\nConstraints\n\nAll values in input are integers.\n\n3 \\leq A, B \\leq 20\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nPrint the maximum number of coins you can get.\n\nSample Input 1\n\n5 3\n\nSample Output 1\n\n9\n\nYou can get 5 + 4 = 9 coins by pressing the button of size 5 twice, and this is the maximum result.\n\nSample Input 2\n\n3 4\n\nSample Output 2\n\n7\n\nSample Input 3\n\n6 6\n\nSample Output 3\n\n12", "sample_input": "5 3\n"}, "reference_outputs": ["9\n"], "source_document_id": "p03071", "source_text": "Score : 100 points\n\nProblem Statement\n\nThere are two buttons, one of size A and one of size B.\n\nWhen you press a button of size X, you get X coins and the size of that button decreases by 1.\n\nYou will press a button twice. Here, you can press the same button twice, or press both buttons once.\n\nAt most how many coins can you get?\n\nConstraints\n\nAll values in input are integers.\n\n3 \\leq A, B \\leq 20\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nPrint the maximum number of coins you can get.\n\nSample Input 1\n\n5 3\n\nSample Output 1\n\n9\n\nYou can get 5 + 4 = 9 coins by pressing the button of size 5 twice, and this is the maximum result.\n\nSample Input 2\n\n3 4\n\nSample Output 2\n\n7\n\nSample Input 3\n\n6 6\n\nSample Output 3\n\n12", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 126, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s441152363", "group_id": "codeNet:p03071", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() { \n  int A,B;\n  cin >> A;\n  cin >> B;\n  \n  if (A+B >= A+A-1 && A+B >= B+B-1){\n    cout << A+B <<endl;}\n  else if (A+A-1 >= A+B && A+A-1 >= B+B-1){\n    cout << A+A-1 <<endl;}\n else if (B+B-1 >= A+B &&  B+B-1 >= A+A-1 ){\n   cout <<  B+B-1 << endl;}\n}", "language": "C++", "metadata": {"date": 1557420485, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03071.html", "problem_id": "p03071", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03071/input.txt", "sample_output_relpath": "derived/input_output/data/p03071/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03071/C++/s441152363.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s441152363", "user_id": "u553128965"}, "prompt_components": {"gold_output": "9\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() { \n  int A,B;\n  cin >> A;\n  cin >> B;\n  \n  if (A+B >= A+A-1 && A+B >= B+B-1){\n    cout << A+B <<endl;}\n  else if (A+A-1 >= A+B && A+A-1 >= B+B-1){\n    cout << A+A-1 <<endl;}\n else if (B+B-1 >= A+B &&  B+B-1 >= A+A-1 ){\n   cout <<  B+B-1 << endl;}\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nThere are two buttons, one of size A and one of size B.\n\nWhen you press a button of size X, you get X coins and the size of that button decreases by 1.\n\nYou will press a button twice. Here, you can press the same button twice, or press both buttons once.\n\nAt most how many coins can you get?\n\nConstraints\n\nAll values in input are integers.\n\n3 \\leq A, B \\leq 20\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nPrint the maximum number of coins you can get.\n\nSample Input 1\n\n5 3\n\nSample Output 1\n\n9\n\nYou can get 5 + 4 = 9 coins by pressing the button of size 5 twice, and this is the maximum result.\n\nSample Input 2\n\n3 4\n\nSample Output 2\n\n7\n\nSample Input 3\n\n6 6\n\nSample Output 3\n\n12", "sample_input": "5 3\n"}, "reference_outputs": ["9\n"], "source_document_id": "p03071", "source_text": "Score : 100 points\n\nProblem Statement\n\nThere are two buttons, one of size A and one of size B.\n\nWhen you press a button of size X, you get X coins and the size of that button decreases by 1.\n\nYou will press a button twice. Here, you can press the same button twice, or press both buttons once.\n\nAt most how many coins can you get?\n\nConstraints\n\nAll values in input are integers.\n\n3 \\leq A, B \\leq 20\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nPrint the maximum number of coins you can get.\n\nSample Input 1\n\n5 3\n\nSample Output 1\n\n9\n\nYou can get 5 + 4 = 9 coins by pressing the button of size 5 twice, and this is the maximum result.\n\nSample Input 2\n\n3 4\n\nSample Output 2\n\n7\n\nSample Input 3\n\n6 6\n\nSample Output 3\n\n12", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 306, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s509101619", "group_id": "codeNet:p03071", "input_text": "#include <iostream>\n#include <algorithm>\n#include <string>\n\nusing namespace std;\n\nint main()\n{\n    int a, b;\n    int ans = 0;\n    cin >> a >> b;\n\n    for (int i = 0; i < 2; i++) {\n        if (a < b) {\n            ans += b;\n            b--;\n        }\n        else {\n            ans += a;\n            a--;\n        }\n    }\n\n    cout << ans << endl;\n}\n", "language": "C++", "metadata": {"date": 1555182081, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03071.html", "problem_id": "p03071", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03071/input.txt", "sample_output_relpath": "derived/input_output/data/p03071/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03071/C++/s509101619.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s509101619", "user_id": "u846686917"}, "prompt_components": {"gold_output": "9\n", "input_to_evaluate": "#include <iostream>\n#include <algorithm>\n#include <string>\n\nusing namespace std;\n\nint main()\n{\n    int a, b;\n    int ans = 0;\n    cin >> a >> b;\n\n    for (int i = 0; i < 2; i++) {\n        if (a < b) {\n            ans += b;\n            b--;\n        }\n        else {\n            ans += a;\n            a--;\n        }\n    }\n\n    cout << ans << endl;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nThere are two buttons, one of size A and one of size B.\n\nWhen you press a button of size X, you get X coins and the size of that button decreases by 1.\n\nYou will press a button twice. Here, you can press the same button twice, or press both buttons once.\n\nAt most how many coins can you get?\n\nConstraints\n\nAll values in input are integers.\n\n3 \\leq A, B \\leq 20\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nPrint the maximum number of coins you can get.\n\nSample Input 1\n\n5 3\n\nSample Output 1\n\n9\n\nYou can get 5 + 4 = 9 coins by pressing the button of size 5 twice, and this is the maximum result.\n\nSample Input 2\n\n3 4\n\nSample Output 2\n\n7\n\nSample Input 3\n\n6 6\n\nSample Output 3\n\n12", "sample_input": "5 3\n"}, "reference_outputs": ["9\n"], "source_document_id": "p03071", "source_text": "Score : 100 points\n\nProblem Statement\n\nThere are two buttons, one of size A and one of size B.\n\nWhen you press a button of size X, you get X coins and the size of that button decreases by 1.\n\nYou will press a button twice. Here, you can press the same button twice, or press both buttons once.\n\nAt most how many coins can you get?\n\nConstraints\n\nAll values in input are integers.\n\n3 \\leq A, B \\leq 20\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nPrint the maximum number of coins you can get.\n\nSample Input 1\n\n5 3\n\nSample Output 1\n\n9\n\nYou can get 5 + 4 = 9 coins by pressing the button of size 5 twice, and this is the maximum result.\n\nSample Input 2\n\n3 4\n\nSample Output 2\n\n7\n\nSample Input 3\n\n6 6\n\nSample Output 3\n\n12", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 348, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s463827889", "group_id": "codeNet:p03072", "input_text": "#include <bits/stdc++.h>\n#include<algorithm>\nusing namespace std;\n\nint main() {\n  int n,cnt = 1;\n  cin >> n;\n  vector<int>height(n);\n  for (int i = 0; i < n; i++) {\n    cin >> height.at(i);\n  }\n  for (int i = 1; i < n; i++) {\n    bool check = 1;\n    for (int j = 0; j < i; j++) {\n      if (height.at(i) < height.at(j)) {\n        check = 0;\n      }\n    }\n    if (check == 1) cnt ++;\n  }\n  cout << cnt;\n}", "language": "C++", "metadata": {"date": 1586192437, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03072.html", "problem_id": "p03072", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03072/input.txt", "sample_output_relpath": "derived/input_output/data/p03072/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03072/C++/s463827889.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s463827889", "user_id": "u331498629"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#include<algorithm>\nusing namespace std;\n\nint main() {\n  int n,cnt = 1;\n  cin >> n;\n  vector<int>height(n);\n  for (int i = 0; i < n; i++) {\n    cin >> height.at(i);\n  }\n  for (int i = 1; i < n; i++) {\n    bool check = 1;\n    for (int j = 0; j < i; j++) {\n      if (height.at(i) < height.at(j)) {\n        check = 0;\n      }\n    }\n    if (check == 1) cnt ++;\n  }\n  cout << cnt;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nThere are N mountains ranging from east to west, and an ocean to the west.\n\nAt the top of each mountain, there is an inn. You have decided to choose where to stay from these inns.\n\nThe height of the i-th mountain from the west is H_i.\n\nYou can certainly see the ocean from the inn at the top of the westmost mountain.\n\nFor the inn at the top of the i-th mountain from the west (i = 2, 3, ..., N), you can see the ocean if and only if H_1 \\leq H_i, H_2 \\leq H_i, ..., and H_{i-1} \\leq H_i.\n\nFrom how many of these N inns can you see the ocean?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 20\n\n1 \\leq H_i \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nH_1 H_2 ... H_N\n\nOutput\n\nPrint the number of inns from which you can see the ocean.\n\nSample Input 1\n\n4\n6 5 6 8\n\nSample Output 1\n\n3\n\nYou can see the ocean from the first, third and fourth inns from the west.\n\nSample Input 2\n\n5\n4 5 3 5 4\n\nSample Output 2\n\n3\n\nSample Input 3\n\n5\n9 5 6 8 4\n\nSample Output 3\n\n1", "sample_input": "4\n6 5 6 8\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03072", "source_text": "Score : 200 points\n\nProblem Statement\n\nThere are N mountains ranging from east to west, and an ocean to the west.\n\nAt the top of each mountain, there is an inn. You have decided to choose where to stay from these inns.\n\nThe height of the i-th mountain from the west is H_i.\n\nYou can certainly see the ocean from the inn at the top of the westmost mountain.\n\nFor the inn at the top of the i-th mountain from the west (i = 2, 3, ..., N), you can see the ocean if and only if H_1 \\leq H_i, H_2 \\leq H_i, ..., and H_{i-1} \\leq H_i.\n\nFrom how many of these N inns can you see the ocean?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 20\n\n1 \\leq H_i \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nH_1 H_2 ... H_N\n\nOutput\n\nPrint the number of inns from which you can see the ocean.\n\nSample Input 1\n\n4\n6 5 6 8\n\nSample Output 1\n\n3\n\nYou can see the ocean from the first, third and fourth inns from the west.\n\nSample Input 2\n\n5\n4 5 3 5 4\n\nSample Output 2\n\n3\n\nSample Input 3\n\n5\n9 5 6 8 4\n\nSample Output 3\n\n1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 402, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s412801047", "group_id": "codeNet:p03072", "input_text": "#include <cstdio>\n#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define FOR(i,a,b) for(int i =(a) ; i <= (b); i++)\n#define ROF(i,a,b) for(int i =(b) ; i >= (a); i--)\n#define REP(i,n)  FOR( i, 0, (n) - 1 )\n#define PER(i,n)  ROF( i, 0, (n) - 1 )\n\nint main(){\n    int N,H[21],max=0,ans=0;\n    cin >> N;\n    REP(i,N){\n        cin >> H[i];\n        if(max <= H[i]){\n            ans++;\n            max = H[i];\n        }\n    }\n    cout << ans << endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1555962318, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03072.html", "problem_id": "p03072", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03072/input.txt", "sample_output_relpath": "derived/input_output/data/p03072/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03072/C++/s412801047.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s412801047", "user_id": "u168578024"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <cstdio>\n#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define FOR(i,a,b) for(int i =(a) ; i <= (b); i++)\n#define ROF(i,a,b) for(int i =(b) ; i >= (a); i--)\n#define REP(i,n)  FOR( i, 0, (n) - 1 )\n#define PER(i,n)  ROF( i, 0, (n) - 1 )\n\nint main(){\n    int N,H[21],max=0,ans=0;\n    cin >> N;\n    REP(i,N){\n        cin >> H[i];\n        if(max <= H[i]){\n            ans++;\n            max = H[i];\n        }\n    }\n    cout << ans << endl;\n    return 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nThere are N mountains ranging from east to west, and an ocean to the west.\n\nAt the top of each mountain, there is an inn. You have decided to choose where to stay from these inns.\n\nThe height of the i-th mountain from the west is H_i.\n\nYou can certainly see the ocean from the inn at the top of the westmost mountain.\n\nFor the inn at the top of the i-th mountain from the west (i = 2, 3, ..., N), you can see the ocean if and only if H_1 \\leq H_i, H_2 \\leq H_i, ..., and H_{i-1} \\leq H_i.\n\nFrom how many of these N inns can you see the ocean?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 20\n\n1 \\leq H_i \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nH_1 H_2 ... H_N\n\nOutput\n\nPrint the number of inns from which you can see the ocean.\n\nSample Input 1\n\n4\n6 5 6 8\n\nSample Output 1\n\n3\n\nYou can see the ocean from the first, third and fourth inns from the west.\n\nSample Input 2\n\n5\n4 5 3 5 4\n\nSample Output 2\n\n3\n\nSample Input 3\n\n5\n9 5 6 8 4\n\nSample Output 3\n\n1", "sample_input": "4\n6 5 6 8\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03072", "source_text": "Score : 200 points\n\nProblem Statement\n\nThere are N mountains ranging from east to west, and an ocean to the west.\n\nAt the top of each mountain, there is an inn. You have decided to choose where to stay from these inns.\n\nThe height of the i-th mountain from the west is H_i.\n\nYou can certainly see the ocean from the inn at the top of the westmost mountain.\n\nFor the inn at the top of the i-th mountain from the west (i = 2, 3, ..., N), you can see the ocean if and only if H_1 \\leq H_i, H_2 \\leq H_i, ..., and H_{i-1} \\leq H_i.\n\nFrom how many of these N inns can you see the ocean?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 20\n\n1 \\leq H_i \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nH_1 H_2 ... H_N\n\nOutput\n\nPrint the number of inns from which you can see the ocean.\n\nSample Input 1\n\n4\n6 5 6 8\n\nSample Output 1\n\n3\n\nYou can see the ocean from the first, third and fourth inns from the west.\n\nSample Input 2\n\n5\n4 5 3 5 4\n\nSample Output 2\n\n3\n\nSample Input 3\n\n5\n9 5 6 8 4\n\nSample Output 3\n\n1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 475, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s932572030", "group_id": "codeNet:p03072", "input_text": "#include <iostream>\nusing namespace std;\nint main(){\n\tint N;\n  cin >> N;\n  int height[N];\n  for(int i = 0;i<N;i++){\n  \tcin >> height[i];  }\n  int max=0;\n  int counter=0;\n  for(int k=0;k<N;k++){\n\tif(max<height[k]){\n    \tmax = height[k];\n \n      ++counter; \n    } \t\n  }\n  cout << counter <<endl;\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1555185072, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03072.html", "problem_id": "p03072", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03072/input.txt", "sample_output_relpath": "derived/input_output/data/p03072/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03072/C++/s932572030.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s932572030", "user_id": "u982831987"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <iostream>\nusing namespace std;\nint main(){\n\tint N;\n  cin >> N;\n  int height[N];\n  for(int i = 0;i<N;i++){\n  \tcin >> height[i];  }\n  int max=0;\n  int counter=0;\n  for(int k=0;k<N;k++){\n\tif(max<height[k]){\n    \tmax = height[k];\n \n      ++counter; \n    } \t\n  }\n  cout << counter <<endl;\n  return 0;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nThere are N mountains ranging from east to west, and an ocean to the west.\n\nAt the top of each mountain, there is an inn. You have decided to choose where to stay from these inns.\n\nThe height of the i-th mountain from the west is H_i.\n\nYou can certainly see the ocean from the inn at the top of the westmost mountain.\n\nFor the inn at the top of the i-th mountain from the west (i = 2, 3, ..., N), you can see the ocean if and only if H_1 \\leq H_i, H_2 \\leq H_i, ..., and H_{i-1} \\leq H_i.\n\nFrom how many of these N inns can you see the ocean?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 20\n\n1 \\leq H_i \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nH_1 H_2 ... H_N\n\nOutput\n\nPrint the number of inns from which you can see the ocean.\n\nSample Input 1\n\n4\n6 5 6 8\n\nSample Output 1\n\n3\n\nYou can see the ocean from the first, third and fourth inns from the west.\n\nSample Input 2\n\n5\n4 5 3 5 4\n\nSample Output 2\n\n3\n\nSample Input 3\n\n5\n9 5 6 8 4\n\nSample Output 3\n\n1", "sample_input": "4\n6 5 6 8\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03072", "source_text": "Score : 200 points\n\nProblem Statement\n\nThere are N mountains ranging from east to west, and an ocean to the west.\n\nAt the top of each mountain, there is an inn. You have decided to choose where to stay from these inns.\n\nThe height of the i-th mountain from the west is H_i.\n\nYou can certainly see the ocean from the inn at the top of the westmost mountain.\n\nFor the inn at the top of the i-th mountain from the west (i = 2, 3, ..., N), you can see the ocean if and only if H_1 \\leq H_i, H_2 \\leq H_i, ..., and H_{i-1} \\leq H_i.\n\nFrom how many of these N inns can you see the ocean?\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 20\n\n1 \\leq H_i \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nH_1 H_2 ... H_N\n\nOutput\n\nPrint the number of inns from which you can see the ocean.\n\nSample Input 1\n\n4\n6 5 6 8\n\nSample Output 1\n\n3\n\nYou can see the ocean from the first, third and fourth inns from the west.\n\nSample Input 2\n\n5\n4 5 3 5 4\n\nSample Output 2\n\n3\n\nSample Input 3\n\n5\n9 5 6 8 4\n\nSample Output 3\n\n1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 308, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s444037826", "group_id": "codeNet:p03073", "input_text": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint main() {\n  ios::sync_with_stdio(false);\n  cin.tie(nullptr);\n  cout << fixed << setprecision(15);\n\n  string s;\n  cin >> s;\n  int si = s.size();\n\n  int cnt1 = 0, cnt2 = 0;\n  for (int i = 0; i < si; ++i) {\n    if (i % 2 == 0) {\n      if (s[i] == '0') {\n        ++cnt1;\n      } else {\n        ++cnt2;\n      }\n    } else {\n      if (s[i] == '1') {\n        ++cnt1;\n      } else {\n        ++cnt2;\n      }\n    }\n  }\n\n  cout << min(cnt1, cnt2) << '\\n';\n\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1592945748, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03073.html", "problem_id": "p03073", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03073/input.txt", "sample_output_relpath": "derived/input_output/data/p03073/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03073/C++/s444037826.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s444037826", "user_id": "u422813672"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint main() {\n  ios::sync_with_stdio(false);\n  cin.tie(nullptr);\n  cout << fixed << setprecision(15);\n\n  string s;\n  cin >> s;\n  int si = s.size();\n\n  int cnt1 = 0, cnt2 = 0;\n  for (int i = 0; i < si; ++i) {\n    if (i % 2 == 0) {\n      if (s[i] == '0') {\n        ++cnt1;\n      } else {\n        ++cnt2;\n      }\n    } else {\n      if (s[i] == '1') {\n        ++cnt1;\n      } else {\n        ++cnt2;\n      }\n    }\n  }\n\n  cout << min(cnt1, cnt2) << '\\n';\n\n  return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nN tiles are arranged in a row from left to right. The initial color of each tile is represented by a string S of length N.\n\nThe i-th tile from the left is painted black if the i-th character of S is 0, and painted white if that character is 1.\n\nYou want to repaint some of the tiles black or white, so that any two adjacent tiles have different colors.\n\nAt least how many tiles need to be repainted to satisfy the condition?\n\nConstraints\n\n1 \\leq |S| \\leq 10^5\n\nS_i is 0 or 1.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the minimum number of tiles that need to be repainted to satisfy the condition.\n\nSample Input 1\n\n000\n\nSample Output 1\n\n1\n\nThe condition can be satisfied by repainting the middle tile white.\n\nSample Input 2\n\n10010010\n\nSample Output 2\n\n3\n\nSample Input 3\n\n0\n\nSample Output 3\n\n0", "sample_input": "000\n"}, "reference_outputs": ["1\n"], "source_document_id": "p03073", "source_text": "Score : 300 points\n\nProblem Statement\n\nN tiles are arranged in a row from left to right. The initial color of each tile is represented by a string S of length N.\n\nThe i-th tile from the left is painted black if the i-th character of S is 0, and painted white if that character is 1.\n\nYou want to repaint some of the tiles black or white, so that any two adjacent tiles have different colors.\n\nAt least how many tiles need to be repainted to satisfy the condition?\n\nConstraints\n\n1 \\leq |S| \\leq 10^5\n\nS_i is 0 or 1.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the minimum number of tiles that need to be repainted to satisfy the condition.\n\nSample Input 1\n\n000\n\nSample Output 1\n\n1\n\nThe condition can be satisfied by repainting the middle tile white.\n\nSample Input 2\n\n10010010\n\nSample Output 2\n\n3\n\nSample Input 3\n\n0\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 511, "cpu_time_ms": 9, "memory_kb": 3680}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s129485248", "group_id": "codeNet:p03074", "input_text": "#include <iostream>\n#include <algorithm>\n#include <string>\n#define rep(i, x, n) for (int i = x; i < n; i++)\nusing namespace std;\nint main()\n{\n    int N, K;\n    cin >> N >> K;\n    string S;\n    cin >> S;\n    int H[100000];\n    rep(i, 0, N) { H[i] = 0; }\n    int tmp = S[0] - '0';\n    H[0] = 1;\n    int tmpIdx = 0;\n    int ind = 1;\n    while (ind < N)\n    {\n        int si = S[ind] - '0';\n        if (tmp == si)\n        {\n            H[tmpIdx]++;\n        }\n        else\n        {\n            H[tmpIdx + 1]++;\n            tmpIdx++;\n            tmp = si;\n        }\n        ind++;\n    }\n    int kukansu = tmpIdx + 1;\n    int ruisekiwa[kukansu];\n    rep(i, 0, kukansu)\n    {\n        if (i == 0)\n        {\n            ruisekiwa[i] = H[i];\n        }\n        else\n        {\n            ruisekiwa[i] = ruisekiwa[i - 1] + H[i];\n        }\n        //  cout << ruisekiwa[i] << endl;\n    }\n    int kukanlong = 2 * K + 1;\n    int max = 0;\n    rep(i, 0, kukansu)\n    {\n        int sum;\n        if (i + kukanlong > N)\n        {\n            kukanlong = N - i;\n        }\n        if (i == 0)\n        {\n            if (S[0] == '0' && i + kukanlong < N)\n            {\n                sum = ruisekiwa[kukanlong -2];\n            }\n            else\n            {\n                sum = ruisekiwa[kukanlong-1];\n            }\n        }else{\n            sum=ruisekiwa[i+kukanlong-1]-ruisekiwa[i-1];\n        }\n        if(max<sum){\n            max=sum;\n        }\n    }\n    cout << max << endl;\n}", "language": "C++", "metadata": {"date": 1555187933, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03074.html", "problem_id": "p03074", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03074/input.txt", "sample_output_relpath": "derived/input_output/data/p03074/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03074/C++/s129485248.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s129485248", "user_id": "u183971632"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <iostream>\n#include <algorithm>\n#include <string>\n#define rep(i, x, n) for (int i = x; i < n; i++)\nusing namespace std;\nint main()\n{\n    int N, K;\n    cin >> N >> K;\n    string S;\n    cin >> S;\n    int H[100000];\n    rep(i, 0, N) { H[i] = 0; }\n    int tmp = S[0] - '0';\n    H[0] = 1;\n    int tmpIdx = 0;\n    int ind = 1;\n    while (ind < N)\n    {\n        int si = S[ind] - '0';\n        if (tmp == si)\n        {\n            H[tmpIdx]++;\n        }\n        else\n        {\n            H[tmpIdx + 1]++;\n            tmpIdx++;\n            tmp = si;\n        }\n        ind++;\n    }\n    int kukansu = tmpIdx + 1;\n    int ruisekiwa[kukansu];\n    rep(i, 0, kukansu)\n    {\n        if (i == 0)\n        {\n            ruisekiwa[i] = H[i];\n        }\n        else\n        {\n            ruisekiwa[i] = ruisekiwa[i - 1] + H[i];\n        }\n        //  cout << ruisekiwa[i] << endl;\n    }\n    int kukanlong = 2 * K + 1;\n    int max = 0;\n    rep(i, 0, kukansu)\n    {\n        int sum;\n        if (i + kukanlong > N)\n        {\n            kukanlong = N - i;\n        }\n        if (i == 0)\n        {\n            if (S[0] == '0' && i + kukanlong < N)\n            {\n                sum = ruisekiwa[kukanlong -2];\n            }\n            else\n            {\n                sum = ruisekiwa[kukanlong-1];\n            }\n        }else{\n            sum=ruisekiwa[i+kukanlong-1]-ruisekiwa[i-1];\n        }\n        if(max<sum){\n            max=sum;\n        }\n    }\n    cout << max << endl;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nN people are arranged in a row from left to right.\n\nYou are given a string S of length N consisting of 0 and 1, and a positive integer K.\n\nThe i-th person from the left is standing on feet if the i-th character of S is 0, and standing on hands if that character is 1.\n\nYou will give the following direction at most K times (possibly zero):\n\nDirection: Choose integers l and r satisfying 1 \\leq l \\leq r \\leq N, and flip the l-th, (l+1)-th, ..., and r-th persons. That is, for each i = l, l+1, ..., r, the i-th person from the left now stands on hands if he/she was standing on feet, and stands on feet if he/she was standing on hands.\n\nFind the maximum possible number of consecutive people standing on hands after at most K directions.\n\nConstraints\n\nN is an integer satisfying 1 \\leq N \\leq 10^5.\n\nK is an integer satisfying 1 \\leq K \\leq 10^5.\n\nThe length of the string S is N.\n\nEach character of the string S is 0 or 1.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nS\n\nOutput\n\nPrint the maximum possible number of consecutive people standing on hands after at most K directions.\n\nSample Input 1\n\n5 1\n00010\n\nSample Output 1\n\n4\n\nWe can have four consecutive people standing on hands, which is the maximum result, by giving the following direction:\n\nGive the direction with l = 1, r = 3, which flips the first, second and third persons from the left.\n\nSample Input 2\n\n14 2\n11101010110011\n\nSample Output 2\n\n8\n\nSample Input 3\n\n1 1\n1\n\nSample Output 3\n\n1\n\nNo directions are necessary.", "sample_input": "5 1\n00010\n"}, "reference_outputs": ["4\n"], "source_document_id": "p03074", "source_text": "Score : 400 points\n\nProblem Statement\n\nN people are arranged in a row from left to right.\n\nYou are given a string S of length N consisting of 0 and 1, and a positive integer K.\n\nThe i-th person from the left is standing on feet if the i-th character of S is 0, and standing on hands if that character is 1.\n\nYou will give the following direction at most K times (possibly zero):\n\nDirection: Choose integers l and r satisfying 1 \\leq l \\leq r \\leq N, and flip the l-th, (l+1)-th, ..., and r-th persons. That is, for each i = l, l+1, ..., r, the i-th person from the left now stands on hands if he/she was standing on feet, and stands on feet if he/she was standing on hands.\n\nFind the maximum possible number of consecutive people standing on hands after at most K directions.\n\nConstraints\n\nN is an integer satisfying 1 \\leq N \\leq 10^5.\n\nK is an integer satisfying 1 \\leq K \\leq 10^5.\n\nThe length of the string S is N.\n\nEach character of the string S is 0 or 1.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nS\n\nOutput\n\nPrint the maximum possible number of consecutive people standing on hands after at most K directions.\n\nSample Input 1\n\n5 1\n00010\n\nSample Output 1\n\n4\n\nWe can have four consecutive people standing on hands, which is the maximum result, by giving the following direction:\n\nGive the direction with l = 1, r = 3, which flips the first, second and third persons from the left.\n\nSample Input 2\n\n14 2\n11101010110011\n\nSample Output 2\n\n8\n\nSample Input 3\n\n1 1\n1\n\nSample Output 3\n\n1\n\nNo directions are necessary.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1463, "cpu_time_ms": 5, "memory_kb": 1280}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s166908476", "group_id": "codeNet:p03076", "input_text": "#include<iostream>\n#include<string>\n#include<map>\n#define int long long int\n\nusing namespace std;\n\nsigned main(){\n\n    int a[5], i;\n    int tmp = 1000000;\n    int pp;\n\n    for(i = 0; i < 5; i++){\n        cin >> a[i];\n        \n        if(a[i] % 10 == 0){\n            continue;\n        }\n\n        if(tmp > a[i] % 10){\n            tmp = a[i] % 10;\n            pp = i;\n        }\n    }\n\n    int ans = 0;\n    for(i = 0; i < 5; i++){\n        if(i == pp){\n            ans = ans + a[pp];\n        }else{\n            if(a[i] % 10 != 0){\n                ans = ans + a[i] + (10 - a[i] % 10);\n            }else{\n                ans = ans + a[i];\n            }\n        }\n    }\n\n    cout << ans << endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1554580748, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03076.html", "problem_id": "p03076", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03076/input.txt", "sample_output_relpath": "derived/input_output/data/p03076/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03076/C++/s166908476.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s166908476", "user_id": "u372231379"}, "prompt_components": {"gold_output": "215\n", "input_to_evaluate": "#include<iostream>\n#include<string>\n#include<map>\n#define int long long int\n\nusing namespace std;\n\nsigned main(){\n\n    int a[5], i;\n    int tmp = 1000000;\n    int pp;\n\n    for(i = 0; i < 5; i++){\n        cin >> a[i];\n        \n        if(a[i] % 10 == 0){\n            continue;\n        }\n\n        if(tmp > a[i] % 10){\n            tmp = a[i] % 10;\n            pp = i;\n        }\n    }\n\n    int ans = 0;\n    for(i = 0; i < 5; i++){\n        if(i == pp){\n            ans = ans + a[pp];\n        }else{\n            if(a[i] % 10 != 0){\n                ans = ans + a[i] + (10 - a[i] % 10);\n            }else{\n                ans = ans + a[i];\n            }\n        }\n    }\n\n    cout << ans << endl;\n    return 0;\n}", "problem_context": "Score: 200 points\n\nProblem Statement\n\nThe restaurant AtCoder serves the following five dishes:\n\nABC Don (rice bowl): takes A minutes to serve.\n\nARC Curry: takes B minutes to serve.\n\nAGC Pasta: takes C minutes to serve.\n\nAPC Ramen: takes D minutes to serve.\n\nATC Hanbagu (hamburger patty): takes E minutes to serve.\n\nHere, the time to serve a dish is the time between when an order is placed and when the dish is delivered.\n\nThis restaurant has the following rules on orders:\n\nAn order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).\n\nOnly one dish can be ordered at a time.\n\nNo new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.\n\nE869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.\n\nHere, he can order the dishes in any order he likes, and he can place an order already at time 0.\n\nConstraints\n\nA, B, C, D and E are integers between 1 and 123 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA\nB\nC\nD\nE\n\nOutput\n\nPrint the earliest possible time for the last dish to be delivered, as an integer.\n\nSample Input 1\n\n29\n20\n7\n35\n120\n\nSample Output 1\n\n215\n\nIf we decide to order the dishes in the order ABC Don, ARC Curry, AGC Pasta, ATC Hanbagu, APC Ramen, the earliest possible time for each order is as follows:\n\nOrder ABC Don at time 0, which will be delivered at time 29.\n\nOrder ARC Curry at time 30, which will be delivered at time 50.\n\nOrder AGC Pasta at time 50, which will be delivered at time 57.\n\nOrder ATC Hanbagu at time 60, which will be delivered at time 180.\n\nOrder APC Ramen at time 180, which will be delivered at time 215.\n\nThere is no way to order the dishes in which the last dish will be delivered earlier than this.\n\nSample Input 2\n\n101\n86\n119\n108\n57\n\nSample Output 2\n\n481\n\nIf we decide to order the dishes in the order AGC Pasta, ARC Curry, ATC Hanbagu, APC Ramen, ABC Don, the earliest possible time for each order is as follows:\n\nOrder AGC Pasta at time 0, which will be delivered at time 119.\n\nOrder ARC Curry at time 120, which will be delivered at time 206.\n\nOrder ATC Hanbagu at time 210, which will be delivered at time 267.\n\nOrder APC Ramen at time 270, which will be delivered at time 378.\n\nOrder ABC Don at time 380, which will be delivered at time 481.\n\nThere is no way to order the dishes in which the last dish will be delivered earlier than this.\n\nSample Input 3\n\n123\n123\n123\n123\n123\n\nSample Output 3\n\n643\n\nThis is the largest valid case.", "sample_input": "29\n20\n7\n35\n120\n"}, "reference_outputs": ["215\n"], "source_document_id": "p03076", "source_text": "Score: 200 points\n\nProblem Statement\n\nThe restaurant AtCoder serves the following five dishes:\n\nABC Don (rice bowl): takes A minutes to serve.\n\nARC Curry: takes B minutes to serve.\n\nAGC Pasta: takes C minutes to serve.\n\nAPC Ramen: takes D minutes to serve.\n\nATC Hanbagu (hamburger patty): takes E minutes to serve.\n\nHere, the time to serve a dish is the time between when an order is placed and when the dish is delivered.\n\nThis restaurant has the following rules on orders:\n\nAn order can only be placed at a time that is a multiple of 10 (time 0, 10, 20, ...).\n\nOnly one dish can be ordered at a time.\n\nNo new order can be placed when an order is already placed and the dish is still not delivered, but a new order can be placed at the exact time when the dish is delivered.\n\nE869120 arrives at this restaurant at time 0. He will order all five dishes. Find the earliest possible time for the last dish to be delivered.\n\nHere, he can order the dishes in any order he likes, and he can place an order already at time 0.\n\nConstraints\n\nA, B, C, D and E are integers between 1 and 123 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA\nB\nC\nD\nE\n\nOutput\n\nPrint the earliest possible time for the last dish to be delivered, as an integer.\n\nSample Input 1\n\n29\n20\n7\n35\n120\n\nSample Output 1\n\n215\n\nIf we decide to order the dishes in the order ABC Don, ARC Curry, AGC Pasta, ATC Hanbagu, APC Ramen, the earliest possible time for each order is as follows:\n\nOrder ABC Don at time 0, which will be delivered at time 29.\n\nOrder ARC Curry at time 30, which will be delivered at time 50.\n\nOrder AGC Pasta at time 50, which will be delivered at time 57.\n\nOrder ATC Hanbagu at time 60, which will be delivered at time 180.\n\nOrder APC Ramen at time 180, which will be delivered at time 215.\n\nThere is no way to order the dishes in which the last dish will be delivered earlier than this.\n\nSample Input 2\n\n101\n86\n119\n108\n57\n\nSample Output 2\n\n481\n\nIf we decide to order the dishes in the order AGC Pasta, ARC Curry, ATC Hanbagu, APC Ramen, ABC Don, the earliest possible time for each order is as follows:\n\nOrder AGC Pasta at time 0, which will be delivered at time 119.\n\nOrder ARC Curry at time 120, which will be delivered at time 206.\n\nOrder ATC Hanbagu at time 210, which will be delivered at time 267.\n\nOrder APC Ramen at time 270, which will be delivered at time 378.\n\nOrder ABC Don at time 380, which will be delivered at time 481.\n\nThere is no way to order the dishes in which the last dish will be delivered earlier than this.\n\nSample Input 3\n\n123\n123\n123\n123\n123\n\nSample Output 3\n\n643\n\nThis is the largest valid case.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 703, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s831521259", "group_id": "codeNet:p03077", "input_text": "#define _LIBCPP_DEBUG 0\n#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i,a,b) for(int i=int(a);i<int(b);i++)\ntypedef vector<int> vi;\ntypedef long long ll;\n\n\n\nint main(){\n    \n    ll N,a[5];\n    cin>>N;\n    rep(i,0,5)cin>>a[i];\n    sort(a,a+5);\n    if(N<=a[0])cout<<5<<endl;\n    else cout<<(ll)ceil(N/a[0])+4<<endl;\n}\n\n\n\n\n", "language": "C++", "metadata": {"date": 1582960563, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03077.html", "problem_id": "p03077", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03077/input.txt", "sample_output_relpath": "derived/input_output/data/p03077/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03077/C++/s831521259.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s831521259", "user_id": "u293156359"}, "prompt_components": {"gold_output": "7\n", "input_to_evaluate": "#define _LIBCPP_DEBUG 0\n#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i,a,b) for(int i=int(a);i<int(b);i++)\ntypedef vector<int> vi;\ntypedef long long ll;\n\n\n\nint main(){\n    \n    ll N,a[5];\n    cin>>N;\n    rep(i,0,5)cin>>a[i];\n    sort(a,a+5);\n    if(N<=a[0])cout<<5<<endl;\n    else cout<<(ll)ceil(N/a[0])+4<<endl;\n}\n\n\n\n\n", "problem_context": "Score: 300 points\n\nProblem Statement\n\nIn 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!\n\nThere are five means of transport in this empire:\n\nTrain: travels from City 1 to 2 in one minute. A train can occupy at most A people.\n\nBus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.\n\nTaxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.\n\nAirplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.\n\nShip: travels from City 5 to 6 in one minute. A ship can occupy at most E people.\n\nFor each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).\n\nThere is a group of N people at City 1, and they all want to go to City 6.\n\nAt least how long does it take for all of them to reach there?\nYou can ignore the time needed to transfer.\n\nConstraints\n\n1 \\leq N, A, B, C, D, E \\leq 10^{15}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA\nB\nC\nD\nE\n\nOutput\n\nPrint the minimum time required for all of the people to reach City 6, in minutes.\n\nSample Input 1\n\n5\n3\n2\n4\n3\n5\n\nSample Output 1\n\n7\n\nOne possible way to travel is as follows.\nFirst, there are N = 5 people at City 1, as shown in the following image:\n\nIn the first minute, three people travels from City 1 to City 2 by train. Note that a train can only occupy at most three people.\n\nIn the second minute, the remaining two people travels from City 1 to City 2 by train, and two of the three people who were already at City 2 travels to City 3 by bus. Note that a bus can only occupy at most two people.\n\nIn the third minute, two people travels from City 2 to City 3 by train, and another two people travels from City 3 to City 4 by taxi.\n\nFrom then on, if they continue traveling without stopping until they reach City 6, all of them can reach there in seven minutes.\n\nThere is no way for them to reach City 6 in 6 minutes or less.\n\nSample Input 2\n\n10\n123\n123\n123\n123\n123\n\nSample Output 2\n\n5\n\nAll kinds of vehicles can occupy N = 10 people at a time.\nThus, if they continue traveling without stopping until they reach City 6, all of them can reach there in five minutes.\n\nSample Input 3\n\n10000000007\n2\n3\n5\n7\n11\n\nSample Output 3\n\n5000000008\n\nNote that the input or output may not fit into a 32-bit integer type.", "sample_input": "5\n3\n2\n4\n3\n5\n"}, "reference_outputs": ["7\n"], "source_document_id": "p03077", "source_text": "Score: 300 points\n\nProblem Statement\n\nIn 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!\n\nThere are five means of transport in this empire:\n\nTrain: travels from City 1 to 2 in one minute. A train can occupy at most A people.\n\nBus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.\n\nTaxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.\n\nAirplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.\n\nShip: travels from City 5 to 6 in one minute. A ship can occupy at most E people.\n\nFor each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).\n\nThere is a group of N people at City 1, and they all want to go to City 6.\n\nAt least how long does it take for all of them to reach there?\nYou can ignore the time needed to transfer.\n\nConstraints\n\n1 \\leq N, A, B, C, D, E \\leq 10^{15}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA\nB\nC\nD\nE\n\nOutput\n\nPrint the minimum time required for all of the people to reach City 6, in minutes.\n\nSample Input 1\n\n5\n3\n2\n4\n3\n5\n\nSample Output 1\n\n7\n\nOne possible way to travel is as follows.\nFirst, there are N = 5 people at City 1, as shown in the following image:\n\nIn the first minute, three people travels from City 1 to City 2 by train. Note that a train can only occupy at most three people.\n\nIn the second minute, the remaining two people travels from City 1 to City 2 by train, and two of the three people who were already at City 2 travels to City 3 by bus. Note that a bus can only occupy at most two people.\n\nIn the third minute, two people travels from City 2 to City 3 by train, and another two people travels from City 3 to City 4 by taxi.\n\nFrom then on, if they continue traveling without stopping until they reach City 6, all of them can reach there in seven minutes.\n\nThere is no way for them to reach City 6 in 6 minutes or less.\n\nSample Input 2\n\n10\n123\n123\n123\n123\n123\n\nSample Output 2\n\n5\n\nAll kinds of vehicles can occupy N = 10 people at a time.\nThus, if they continue traveling without stopping until they reach City 6, all of them can reach there in five minutes.\n\nSample Input 3\n\n10000000007\n2\n3\n5\n7\n11\n\nSample Output 3\n\n5000000008\n\nNote that the input or output may not fit into a 32-bit integer type.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 332, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s765917149", "group_id": "codeNet:p03077", "input_text": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<string>\nusing namespace std;\n\nint main(){\n    long N;\n    cin >> N;\n    long tmp;\n    long trans[5];\n    \n    for(int i = 0; i < 5; i++){\n        cin >> tmp;\n        trans[i] = tmp;        \n    }\n\n    long mini = trans[0];\n\n    for(int i = 1; i < 5; i++){\n        if(mini > trans[i]) mini = trans[i];\n    }\n\n    if(mini >= N) cout << 5 << '\\n';\n    else cout << 5 + N/mini << '\\n';\n\n    return 0;\n}", "language": "C++", "metadata": {"date": 1558368176, "filename_ext": "cpp", "original_language": "C++14 (Clang 3.8.0)", "problem_description_relpath": "problem_descriptions/p03077.html", "problem_id": "p03077", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03077/input.txt", "sample_output_relpath": "derived/input_output/data/p03077/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03077/C++/s765917149.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s765917149", "user_id": "u115306811"}, "prompt_components": {"gold_output": "7\n", "input_to_evaluate": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<string>\nusing namespace std;\n\nint main(){\n    long N;\n    cin >> N;\n    long tmp;\n    long trans[5];\n    \n    for(int i = 0; i < 5; i++){\n        cin >> tmp;\n        trans[i] = tmp;        \n    }\n\n    long mini = trans[0];\n\n    for(int i = 1; i < 5; i++){\n        if(mini > trans[i]) mini = trans[i];\n    }\n\n    if(mini >= N) cout << 5 << '\\n';\n    else cout << 5 + N/mini << '\\n';\n\n    return 0;\n}", "problem_context": "Score: 300 points\n\nProblem Statement\n\nIn 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!\n\nThere are five means of transport in this empire:\n\nTrain: travels from City 1 to 2 in one minute. A train can occupy at most A people.\n\nBus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.\n\nTaxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.\n\nAirplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.\n\nShip: travels from City 5 to 6 in one minute. A ship can occupy at most E people.\n\nFor each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).\n\nThere is a group of N people at City 1, and they all want to go to City 6.\n\nAt least how long does it take for all of them to reach there?\nYou can ignore the time needed to transfer.\n\nConstraints\n\n1 \\leq N, A, B, C, D, E \\leq 10^{15}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA\nB\nC\nD\nE\n\nOutput\n\nPrint the minimum time required for all of the people to reach City 6, in minutes.\n\nSample Input 1\n\n5\n3\n2\n4\n3\n5\n\nSample Output 1\n\n7\n\nOne possible way to travel is as follows.\nFirst, there are N = 5 people at City 1, as shown in the following image:\n\nIn the first minute, three people travels from City 1 to City 2 by train. Note that a train can only occupy at most three people.\n\nIn the second minute, the remaining two people travels from City 1 to City 2 by train, and two of the three people who were already at City 2 travels to City 3 by bus. Note that a bus can only occupy at most two people.\n\nIn the third minute, two people travels from City 2 to City 3 by train, and another two people travels from City 3 to City 4 by taxi.\n\nFrom then on, if they continue traveling without stopping until they reach City 6, all of them can reach there in seven minutes.\n\nThere is no way for them to reach City 6 in 6 minutes or less.\n\nSample Input 2\n\n10\n123\n123\n123\n123\n123\n\nSample Output 2\n\n5\n\nAll kinds of vehicles can occupy N = 10 people at a time.\nThus, if they continue traveling without stopping until they reach City 6, all of them can reach there in five minutes.\n\nSample Input 3\n\n10000000007\n2\n3\n5\n7\n11\n\nSample Output 3\n\n5000000008\n\nNote that the input or output may not fit into a 32-bit integer type.", "sample_input": "5\n3\n2\n4\n3\n5\n"}, "reference_outputs": ["7\n"], "source_document_id": "p03077", "source_text": "Score: 300 points\n\nProblem Statement\n\nIn 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!\n\nThere are five means of transport in this empire:\n\nTrain: travels from City 1 to 2 in one minute. A train can occupy at most A people.\n\nBus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.\n\nTaxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.\n\nAirplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.\n\nShip: travels from City 5 to 6 in one minute. A ship can occupy at most E people.\n\nFor each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).\n\nThere is a group of N people at City 1, and they all want to go to City 6.\n\nAt least how long does it take for all of them to reach there?\nYou can ignore the time needed to transfer.\n\nConstraints\n\n1 \\leq N, A, B, C, D, E \\leq 10^{15}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA\nB\nC\nD\nE\n\nOutput\n\nPrint the minimum time required for all of the people to reach City 6, in minutes.\n\nSample Input 1\n\n5\n3\n2\n4\n3\n5\n\nSample Output 1\n\n7\n\nOne possible way to travel is as follows.\nFirst, there are N = 5 people at City 1, as shown in the following image:\n\nIn the first minute, three people travels from City 1 to City 2 by train. Note that a train can only occupy at most three people.\n\nIn the second minute, the remaining two people travels from City 1 to City 2 by train, and two of the three people who were already at City 2 travels to City 3 by bus. Note that a bus can only occupy at most two people.\n\nIn the third minute, two people travels from City 2 to City 3 by train, and another two people travels from City 3 to City 4 by taxi.\n\nFrom then on, if they continue traveling without stopping until they reach City 6, all of them can reach there in seven minutes.\n\nThere is no way for them to reach City 6 in 6 minutes or less.\n\nSample Input 2\n\n10\n123\n123\n123\n123\n123\n\nSample Output 2\n\n5\n\nAll kinds of vehicles can occupy N = 10 people at a time.\nThus, if they continue traveling without stopping until they reach City 6, all of them can reach there in five minutes.\n\nSample Input 3\n\n10000000007\n2\n3\n5\n7\n11\n\nSample Output 3\n\n5000000008\n\nNote that the input or output may not fit into a 32-bit integer type.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 463, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s240183128", "group_id": "codeNet:p03077", "input_text": "#include <iostream>\n#include <algorithm>\n#include <array>\n\ntypedef long long ll;\n\nint main (void){\n  ll N; std::cin >> N;\n  std::array<ll, 5> t;\n  for(int i=0; i<5; i++){\n    std::cin >> t[i];\n  }\n\n  ll m = *std::min_element(t.begin(), t.end());\n  ll s = N%m == 0 ? N/m : N/m+1;\n  std::cout << 4 + s << std::endl;\n  return 0;\n}", "language": "C++", "metadata": {"date": 1554584574, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03077.html", "problem_id": "p03077", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03077/input.txt", "sample_output_relpath": "derived/input_output/data/p03077/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03077/C++/s240183128.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s240183128", "user_id": "u967843578"}, "prompt_components": {"gold_output": "7\n", "input_to_evaluate": "#include <iostream>\n#include <algorithm>\n#include <array>\n\ntypedef long long ll;\n\nint main (void){\n  ll N; std::cin >> N;\n  std::array<ll, 5> t;\n  for(int i=0; i<5; i++){\n    std::cin >> t[i];\n  }\n\n  ll m = *std::min_element(t.begin(), t.end());\n  ll s = N%m == 0 ? N/m : N/m+1;\n  std::cout << 4 + s << std::endl;\n  return 0;\n}", "problem_context": "Score: 300 points\n\nProblem Statement\n\nIn 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!\n\nThere are five means of transport in this empire:\n\nTrain: travels from City 1 to 2 in one minute. A train can occupy at most A people.\n\nBus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.\n\nTaxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.\n\nAirplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.\n\nShip: travels from City 5 to 6 in one minute. A ship can occupy at most E people.\n\nFor each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).\n\nThere is a group of N people at City 1, and they all want to go to City 6.\n\nAt least how long does it take for all of them to reach there?\nYou can ignore the time needed to transfer.\n\nConstraints\n\n1 \\leq N, A, B, C, D, E \\leq 10^{15}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA\nB\nC\nD\nE\n\nOutput\n\nPrint the minimum time required for all of the people to reach City 6, in minutes.\n\nSample Input 1\n\n5\n3\n2\n4\n3\n5\n\nSample Output 1\n\n7\n\nOne possible way to travel is as follows.\nFirst, there are N = 5 people at City 1, as shown in the following image:\n\nIn the first minute, three people travels from City 1 to City 2 by train. Note that a train can only occupy at most three people.\n\nIn the second minute, the remaining two people travels from City 1 to City 2 by train, and two of the three people who were already at City 2 travels to City 3 by bus. Note that a bus can only occupy at most two people.\n\nIn the third minute, two people travels from City 2 to City 3 by train, and another two people travels from City 3 to City 4 by taxi.\n\nFrom then on, if they continue traveling without stopping until they reach City 6, all of them can reach there in seven minutes.\n\nThere is no way for them to reach City 6 in 6 minutes or less.\n\nSample Input 2\n\n10\n123\n123\n123\n123\n123\n\nSample Output 2\n\n5\n\nAll kinds of vehicles can occupy N = 10 people at a time.\nThus, if they continue traveling without stopping until they reach City 6, all of them can reach there in five minutes.\n\nSample Input 3\n\n10000000007\n2\n3\n5\n7\n11\n\nSample Output 3\n\n5000000008\n\nNote that the input or output may not fit into a 32-bit integer type.", "sample_input": "5\n3\n2\n4\n3\n5\n"}, "reference_outputs": ["7\n"], "source_document_id": "p03077", "source_text": "Score: 300 points\n\nProblem Statement\n\nIn 2028 and after a continuous growth, AtCoder Inc. finally built an empire with six cities (City 1, 2, 3, 4, 5, 6)!\n\nThere are five means of transport in this empire:\n\nTrain: travels from City 1 to 2 in one minute. A train can occupy at most A people.\n\nBus: travels from City 2 to 3 in one minute. A bus can occupy at most B people.\n\nTaxi: travels from City 3 to 4 in one minute. A taxi can occupy at most C people.\n\nAirplane: travels from City 4 to 5 in one minute. An airplane can occupy at most D people.\n\nShip: travels from City 5 to 6 in one minute. A ship can occupy at most E people.\n\nFor each of them, one vehicle leaves the city at each integer time (time 0, 1, 2, ...).\n\nThere is a group of N people at City 1, and they all want to go to City 6.\n\nAt least how long does it take for all of them to reach there?\nYou can ignore the time needed to transfer.\n\nConstraints\n\n1 \\leq N, A, B, C, D, E \\leq 10^{15}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA\nB\nC\nD\nE\n\nOutput\n\nPrint the minimum time required for all of the people to reach City 6, in minutes.\n\nSample Input 1\n\n5\n3\n2\n4\n3\n5\n\nSample Output 1\n\n7\n\nOne possible way to travel is as follows.\nFirst, there are N = 5 people at City 1, as shown in the following image:\n\nIn the first minute, three people travels from City 1 to City 2 by train. Note that a train can only occupy at most three people.\n\nIn the second minute, the remaining two people travels from City 1 to City 2 by train, and two of the three people who were already at City 2 travels to City 3 by bus. Note that a bus can only occupy at most two people.\n\nIn the third minute, two people travels from City 2 to City 3 by train, and another two people travels from City 3 to City 4 by taxi.\n\nFrom then on, if they continue traveling without stopping until they reach City 6, all of them can reach there in seven minutes.\n\nThere is no way for them to reach City 6 in 6 minutes or less.\n\nSample Input 2\n\n10\n123\n123\n123\n123\n123\n\nSample Output 2\n\n5\n\nAll kinds of vehicles can occupy N = 10 people at a time.\nThus, if they continue traveling without stopping until they reach City 6, all of them can reach there in five minutes.\n\nSample Input 3\n\n10000000007\n2\n3\n5\n7\n11\n\nSample Output 3\n\n5000000008\n\nNote that the input or output may not fit into a 32-bit integer type.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 327, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s027937737", "group_id": "codeNet:p03078", "input_text": "#include <bits/stdc++.h>\n#define all(x) begin(x), end(x)\n#define dbg(x) cerr << #x << \" = \" << x << endl\n#define _ << ' ' <<\nusing namespace std;\nusing ll = long long;\nusing vi = vector<int>;\n\nll a[1001], b[1001], c[1001], d[1000001];\nint x, y, z, k;\nint p, q;\n\nint main()\n{\n    ios::sync_with_stdio(false);\n    cin.tie(0);\n    cin >> x >> y >> z >> k;\n    for (int i = 0; i < x; ++i)\n        cin >> a[i];\n    for (int i = 0; i < y; ++i)\n        cin >> b[i];\n    for (int i = 0; i < z; ++i)\n        cin >> c[i];\n\n    for (int i = 0; i < x; ++i)\n        for (int j = 0; j < y; ++j)\n            d[i * y + j] = a[i] + b[j];\n\n    sort(c, c + z, greater<ll>());\n    sort(d, d + (x * y), greater<ll>());\n\n    vector<ll> sol;\n    for (int i = 0; i < min(k, x * y); ++i)\n        for (int j = 0; j < z; ++j)\n            sol.push_back(c[i] + d[j]);\n\n    sort(all(sol), greater<ll>());\n    for (int i = 0; i < k; ++i)\n        cout << sol[i] << '\\n';\n}\n", "language": "C++", "metadata": {"date": 1558756153, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03078.html", "problem_id": "p03078", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03078/input.txt", "sample_output_relpath": "derived/input_output/data/p03078/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03078/C++/s027937737.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s027937737", "user_id": "u562319622"}, "prompt_components": {"gold_output": "19\n17\n15\n14\n13\n12\n10\n8\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define all(x) begin(x), end(x)\n#define dbg(x) cerr << #x << \" = \" << x << endl\n#define _ << ' ' <<\nusing namespace std;\nusing ll = long long;\nusing vi = vector<int>;\n\nll a[1001], b[1001], c[1001], d[1000001];\nint x, y, z, k;\nint p, q;\n\nint main()\n{\n    ios::sync_with_stdio(false);\n    cin.tie(0);\n    cin >> x >> y >> z >> k;\n    for (int i = 0; i < x; ++i)\n        cin >> a[i];\n    for (int i = 0; i < y; ++i)\n        cin >> b[i];\n    for (int i = 0; i < z; ++i)\n        cin >> c[i];\n\n    for (int i = 0; i < x; ++i)\n        for (int j = 0; j < y; ++j)\n            d[i * y + j] = a[i] + b[j];\n\n    sort(c, c + z, greater<ll>());\n    sort(d, d + (x * y), greater<ll>());\n\n    vector<ll> sol;\n    for (int i = 0; i < min(k, x * y); ++i)\n        for (int j = 0; j < z; ++j)\n            sol.push_back(c[i] + d[j]);\n\n    sort(all(sol), greater<ll>());\n    for (int i = 0; i < k; ++i)\n        cout << sol[i] << '\\n';\n}\n", "problem_context": "Score: 400 points\n\nProblem Statement\n\nThe Patisserie AtCoder sells cakes with number-shaped candles.\nThere are X, Y and Z kinds of cakes with 1-shaped, 2-shaped and 3-shaped candles, respectively.\nEach cake has an integer value called deliciousness, as follows:\n\nThe deliciousness of the cakes with 1-shaped candles are A_1, A_2, ..., A_X.\n\nThe deliciousness of the cakes with 2-shaped candles are B_1, B_2, ..., B_Y.\n\nThe deliciousness of the cakes with 3-shaped candles are C_1, C_2, ..., C_Z.\n\nTakahashi decides to buy three cakes, one for each of the three shapes of the candles, to celebrate ABC 123.\n\nThere are X \\times Y \\times Z such ways to choose three cakes.\n\nWe will arrange these X \\times Y \\times Z ways in descending order of the sum of the deliciousness of the cakes.\n\nPrint the sums of the deliciousness of the cakes for the first, second, ..., K-th ways in this list.\n\nConstraints\n\n1 \\leq X \\leq 1 \\ 000\n\n1 \\leq Y \\leq 1 \\ 000\n\n1 \\leq Z \\leq 1 \\ 000\n\n1 \\leq K \\leq \\min(3 \\ 000, X \\times Y \\times Z)\n\n1 \\leq A_i \\leq 10 \\ 000 \\ 000 \\ 000\n\n1 \\leq B_i \\leq 10 \\ 000 \\ 000 \\ 000\n\n1 \\leq C_i \\leq 10 \\ 000 \\ 000 \\ 000\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX Y Z K\nA_1 \\ A_2 \\ A_3 \\ ... \\ A_X\nB_1 \\ B_2 \\ B_3 \\ ... \\ B_Y\nC_1 \\ C_2 \\ C_3 \\ ... \\ C_Z\n\nOutput\n\nPrint K lines. The i-th line should contain the i-th value stated in the problem statement.\n\nSample Input 1\n\n2 2 2 8\n4 6\n1 5\n3 8\n\nSample Output 1\n\n19\n17\n15\n14\n13\n12\n10\n8\n\nThere are 2 \\times 2 \\times 2 = 8 ways to choose three cakes, as shown below in descending order of the sum of the deliciousness of the cakes:\n\n(A_2, B_2, C_2): 6 + 5 + 8 = 19\n\n(A_1, B_2, C_2): 4 + 5 + 8 = 17\n\n(A_2, B_1, C_2): 6 + 1 + 8 = 15\n\n(A_2, B_2, C_1): 6 + 5 + 3 = 14\n\n(A_1, B_1, C_2): 4 + 1 + 8 = 13\n\n(A_1, B_2, C_1): 4 + 5 + 3 = 12\n\n(A_2, B_1, C_1): 6 + 1 + 3 = 10\n\n(A_1, B_1, C_1): 4 + 1 + 3 = 8\n\nSample Input 2\n\n3 3 3 5\n1 10 100\n2 20 200\n1 10 100\n\nSample Output 2\n\n400\n310\n310\n301\n301\n\nThere may be multiple combinations of cakes with the same sum of the deliciousness. For example, in this test case, the sum of A_1, B_3, C_3 and the sum of A_3, B_3, C_1 are both 301.\nHowever, they are different ways of choosing cakes, so 301 occurs twice in the output.\n\nSample Input 3\n\n10 10 10 20\n7467038376 5724769290 292794712 2843504496 3381970101 8402252870 249131806 6310293640 6690322794 6082257488\n1873977926 2576529623 1144842195 1379118507 6003234687 4925540914 3902539811 3326692703 484657758 2877436338\n4975681328 8974383988 2882263257 7690203955 514305523 6679823484 4263279310 585966808 3752282379 620585736\n\nSample Output 3\n\n23379871545\n22444657051\n22302177772\n22095691512\n21667941469\n21366963278\n21287912315\n21279176669\n21160477018\n21085311041\n21059876163\n21017997739\n20703329561\n20702387965\n20590247696\n20383761436\n20343962175\n20254073196\n20210218542\n20150096547\n\nNote that the input or output may not fit into a 32-bit integer type.", "sample_input": "2 2 2 8\n4 6\n1 5\n3 8\n"}, "reference_outputs": ["19\n17\n15\n14\n13\n12\n10\n8\n"], "source_document_id": "p03078", "source_text": "Score: 400 points\n\nProblem Statement\n\nThe Patisserie AtCoder sells cakes with number-shaped candles.\nThere are X, Y and Z kinds of cakes with 1-shaped, 2-shaped and 3-shaped candles, respectively.\nEach cake has an integer value called deliciousness, as follows:\n\nThe deliciousness of the cakes with 1-shaped candles are A_1, A_2, ..., A_X.\n\nThe deliciousness of the cakes with 2-shaped candles are B_1, B_2, ..., B_Y.\n\nThe deliciousness of the cakes with 3-shaped candles are C_1, C_2, ..., C_Z.\n\nTakahashi decides to buy three cakes, one for each of the three shapes of the candles, to celebrate ABC 123.\n\nThere are X \\times Y \\times Z such ways to choose three cakes.\n\nWe will arrange these X \\times Y \\times Z ways in descending order of the sum of the deliciousness of the cakes.\n\nPrint the sums of the deliciousness of the cakes for the first, second, ..., K-th ways in this list.\n\nConstraints\n\n1 \\leq X \\leq 1 \\ 000\n\n1 \\leq Y \\leq 1 \\ 000\n\n1 \\leq Z \\leq 1 \\ 000\n\n1 \\leq K \\leq \\min(3 \\ 000, X \\times Y \\times Z)\n\n1 \\leq A_i \\leq 10 \\ 000 \\ 000 \\ 000\n\n1 \\leq B_i \\leq 10 \\ 000 \\ 000 \\ 000\n\n1 \\leq C_i \\leq 10 \\ 000 \\ 000 \\ 000\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX Y Z K\nA_1 \\ A_2 \\ A_3 \\ ... \\ A_X\nB_1 \\ B_2 \\ B_3 \\ ... \\ B_Y\nC_1 \\ C_2 \\ C_3 \\ ... \\ C_Z\n\nOutput\n\nPrint K lines. The i-th line should contain the i-th value stated in the problem statement.\n\nSample Input 1\n\n2 2 2 8\n4 6\n1 5\n3 8\n\nSample Output 1\n\n19\n17\n15\n14\n13\n12\n10\n8\n\nThere are 2 \\times 2 \\times 2 = 8 ways to choose three cakes, as shown below in descending order of the sum of the deliciousness of the cakes:\n\n(A_2, B_2, C_2): 6 + 5 + 8 = 19\n\n(A_1, B_2, C_2): 4 + 5 + 8 = 17\n\n(A_2, B_1, C_2): 6 + 1 + 8 = 15\n\n(A_2, B_2, C_1): 6 + 5 + 3 = 14\n\n(A_1, B_1, C_2): 4 + 1 + 8 = 13\n\n(A_1, B_2, C_1): 4 + 5 + 3 = 12\n\n(A_2, B_1, C_1): 6 + 1 + 3 = 10\n\n(A_1, B_1, C_1): 4 + 1 + 3 = 8\n\nSample Input 2\n\n3 3 3 5\n1 10 100\n2 20 200\n1 10 100\n\nSample Output 2\n\n400\n310\n310\n301\n301\n\nThere may be multiple combinations of cakes with the same sum of the deliciousness. For example, in this test case, the sum of A_1, B_3, C_3 and the sum of A_3, B_3, C_1 are both 301.\nHowever, they are different ways of choosing cakes, so 301 occurs twice in the output.\n\nSample Input 3\n\n10 10 10 20\n7467038376 5724769290 292794712 2843504496 3381970101 8402252870 249131806 6310293640 6690322794 6082257488\n1873977926 2576529623 1144842195 1379118507 6003234687 4925540914 3902539811 3326692703 484657758 2877436338\n4975681328 8974383988 2882263257 7690203955 514305523 6679823484 4263279310 585966808 3752282379 620585736\n\nSample Output 3\n\n23379871545\n22444657051\n22302177772\n22095691512\n21667941469\n21366963278\n21287912315\n21279176669\n21160477018\n21085311041\n21059876163\n21017997739\n20703329561\n20702387965\n20590247696\n20383761436\n20343962175\n20254073196\n20210218542\n20150096547\n\nNote that the input or output may not fit into a 32-bit integer type.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 941, "cpu_time_ms": 252, "memory_kb": 42980}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s708949378", "group_id": "codeNet:p03086", "input_text": "#define rep(i,x) for (int i = 0; i < x; i++)\n#define mod 1000000007\n#define MOD 998244353\n#define INF (1<<31)-1\n#define _USE_MATH_DEFINES\n#include <iostream>\n#include <cstdio>\n#include <cstdlib>\n#include <algorithm>\n#include <vector>\n#include <cstring>\n#include <queue>\n#include <functional>\n#include <set>\n#include <map>\n#include <string>\n#include <cmath>\n#include <math.h>\n#include <complex>\n#include <cassert>\nusing namespace std;\ntypedef long long int ll;\ntypedef pair<ll, ll> p;\ntypedef complex<double> com;\n\n\nint main() {\n\tstring a;\n\tcin >> a;\n\tint ans = 0;\n\tstring s = \"ATGC\";\n\tint cnt = 0;\n\trep(i, a.size()) {\n\t\tint cnt2 = 0;\n\t\trep(j, 4) {\n\t\t\tif (s[j] == a[i]) {\n\t\t\t\tcnt2++;\n\t\t\t}\n\t\t}\n\t\tif (cnt2 > 0) {\n\t\t\tcnt++;\n\t\t\tans = max(ans, cnt);\n\t\t}\n\t\telse {\n\t\t\tcnt = 0;\n\t\t}\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1553458009, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03086.html", "problem_id": "p03086", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03086/input.txt", "sample_output_relpath": "derived/input_output/data/p03086/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03086/C++/s708949378.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s708949378", "user_id": "u407614884"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#define rep(i,x) for (int i = 0; i < x; i++)\n#define mod 1000000007\n#define MOD 998244353\n#define INF (1<<31)-1\n#define _USE_MATH_DEFINES\n#include <iostream>\n#include <cstdio>\n#include <cstdlib>\n#include <algorithm>\n#include <vector>\n#include <cstring>\n#include <queue>\n#include <functional>\n#include <set>\n#include <map>\n#include <string>\n#include <cmath>\n#include <math.h>\n#include <complex>\n#include <cassert>\nusing namespace std;\ntypedef long long int ll;\ntypedef pair<ll, ll> p;\ntypedef complex<double> com;\n\n\nint main() {\n\tstring a;\n\tcin >> a;\n\tint ans = 0;\n\tstring s = \"ATGC\";\n\tint cnt = 0;\n\trep(i, a.size()) {\n\t\tint cnt2 = 0;\n\t\trep(j, 4) {\n\t\t\tif (s[j] == a[i]) {\n\t\t\t\tcnt2++;\n\t\t\t}\n\t\t}\n\t\tif (cnt2 > 0) {\n\t\t\tcnt++;\n\t\t\tans = max(ans, cnt);\n\t\t}\n\t\telse {\n\t\t\tcnt = 0;\n\t\t}\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nYou are given a string S consisting of uppercase English letters. Find the length of the longest ACGT string that is a substring (see Notes) of S.\n\nHere, a ACGT string is a string that contains no characters other than A, C, G and T.\n\nNotes\n\nA substring of a string T is a string obtained by removing zero or more characters from the beginning and the end of T.\n\nFor example, the substrings of ATCODER include TCO, AT, CODER, ATCODER and (the empty string), but not AC.\n\nConstraints\n\nS is a string of length between 1 and 10 (inclusive).\n\nEach character in S is an uppercase English letter.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the length of the longest ACGT string that is a substring of S.\n\nSample Input 1\n\nATCODER\n\nSample Output 1\n\n3\n\nAmong the ACGT strings that are substrings of ATCODER, the longest one is ATC.\n\nSample Input 2\n\nHATAGAYA\n\nSample Output 2\n\n5\n\nAmong the ACGT strings that are substrings of HATAGAYA, the longest one is ATAGA.\n\nSample Input 3\n\nSHINJUKU\n\nSample Output 3\n\n0\n\nAmong the ACGT strings that are substrings of SHINJUKU, the longest one is (the empty string).", "sample_input": "ATCODER\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03086", "source_text": "Score : 200 points\n\nProblem Statement\n\nYou are given a string S consisting of uppercase English letters. Find the length of the longest ACGT string that is a substring (see Notes) of S.\n\nHere, a ACGT string is a string that contains no characters other than A, C, G and T.\n\nNotes\n\nA substring of a string T is a string obtained by removing zero or more characters from the beginning and the end of T.\n\nFor example, the substrings of ATCODER include TCO, AT, CODER, ATCODER and (the empty string), but not AC.\n\nConstraints\n\nS is a string of length between 1 and 10 (inclusive).\n\nEach character in S is an uppercase English letter.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the length of the longest ACGT string that is a substring of S.\n\nSample Input 1\n\nATCODER\n\nSample Output 1\n\n3\n\nAmong the ACGT strings that are substrings of ATCODER, the longest one is ATC.\n\nSample Input 2\n\nHATAGAYA\n\nSample Output 2\n\n5\n\nAmong the ACGT strings that are substrings of HATAGAYA, the longest one is ATAGA.\n\nSample Input 3\n\nSHINJUKU\n\nSample Output 3\n\n0\n\nAmong the ACGT strings that are substrings of SHINJUKU, the longest one is (the empty string).", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 811, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s135550489", "group_id": "codeNet:p03087", "input_text": "// スタックサイズ: 100MB\n\n#include <iostream>\n#include <fstream>\n#include <vector>\n#include <map>\n#include <unordered_map>\n#include <string>\n#include <cmath>\n#include <cstdio>\n#include <algorithm>\n#include <functional>\n#include <numeric>\n#include <iomanip>\n#include <queue>\n#include <list>\n#include <set>\nusing namespace std;\n\ntypedef int64_t ll;\ntypedef vector<ll> vll;\ntypedef pair<ll, ll> pll;\nconst ll INF = 1000000000000000000;\n#define fori(i, a, b) for (ll i = (a); i < (b); ++i)\n#define ford(i, a, b) for (ll i = (b - 1); (a) <= i; --i)\n#define rep(i, n) fori(i, 0, n)\n#define all(v) (v).begin(), (v).end()\nll pw(ll x, ll y) { ll r = 1;  rep(i, y) { r *= x; }; return r; }\n\n\nint main() {\n\n\tll N, Q;\n\tcin >> N >> Q;\n\tstring s;\n\tcin >> s;\n\tvll acc(N, 0);\n\tfori(i, 1, N) {\n\t\tif (s[i - 1] == 'A' && s[i] == 'C') acc[i] = acc[i - 1] + 1;\n\t\telse acc[i] = acc[i - 1];\n\t}\n\n\n\trep(i, Q) {\n\t\tll l, r;\n\t\tcin >> l >> r;\n\t\tl -= 1, r -= 1;\n\t\tcout << acc[r] - acc[l] << endl;\n\t}\n}", "language": "C++", "metadata": {"date": 1553510724, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03087.html", "problem_id": "p03087", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03087/input.txt", "sample_output_relpath": "derived/input_output/data/p03087/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03087/C++/s135550489.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s135550489", "user_id": "u511401499"}, "prompt_components": {"gold_output": "2\n0\n3\n", "input_to_evaluate": "// スタックサイズ: 100MB\n\n#include <iostream>\n#include <fstream>\n#include <vector>\n#include <map>\n#include <unordered_map>\n#include <string>\n#include <cmath>\n#include <cstdio>\n#include <algorithm>\n#include <functional>\n#include <numeric>\n#include <iomanip>\n#include <queue>\n#include <list>\n#include <set>\nusing namespace std;\n\ntypedef int64_t ll;\ntypedef vector<ll> vll;\ntypedef pair<ll, ll> pll;\nconst ll INF = 1000000000000000000;\n#define fori(i, a, b) for (ll i = (a); i < (b); ++i)\n#define ford(i, a, b) for (ll i = (b - 1); (a) <= i; --i)\n#define rep(i, n) fori(i, 0, n)\n#define all(v) (v).begin(), (v).end()\nll pw(ll x, ll y) { ll r = 1;  rep(i, y) { r *= x; }; return r; }\n\n\nint main() {\n\n\tll N, Q;\n\tcin >> N >> Q;\n\tstring s;\n\tcin >> s;\n\tvll acc(N, 0);\n\tfori(i, 1, N) {\n\t\tif (s[i - 1] == 'A' && s[i] == 'C') acc[i] = acc[i - 1] + 1;\n\t\telse acc[i] = acc[i - 1];\n\t}\n\n\n\trep(i, Q) {\n\t\tll l, r;\n\t\tcin >> l >> r;\n\t\tl -= 1, r -= 1;\n\t\tcout << acc[r] - acc[l] << endl;\n\t}\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nYou are given a string S of length N consisting of A, C, G and T. Answer the following Q queries:\n\nQuery i (1 \\leq i \\leq Q): You will be given integers l_i and r_i (1 \\leq l_i < r_i \\leq N). Consider the substring of S starting at index l_i and ending at index r_i (both inclusive). In this string, how many times does AC occurs as a substring?\n\nNotes\n\nA substring of a string T is a string obtained by removing zero or more characters from the beginning and the end of T.\n\nFor example, the substrings of ATCODER include TCO, AT, CODER, ATCODER and (the empty string), but not AC.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n1 \\leq Q \\leq 10^5\n\nS is a string of length N.\n\nEach character in S is A, C, G or T.\n\n1 \\leq l_i < r_i \\leq N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN Q\nS\nl_1 r_1\n:\nl_Q r_Q\n\nOutput\n\nPrint Q lines. The i-th line should contain the answer to the i-th query.\n\nSample Input 1\n\n8 3\nACACTACG\n3 7\n2 3\n1 8\n\nSample Output 1\n\n2\n0\n3\n\nQuery 1: the substring of S starting at index 3 and ending at index 7 is ACTAC. In this string, AC occurs twice as a substring.\n\nQuery 2: the substring of S starting at index 2 and ending at index 3 is CA. In this string, AC occurs zero times as a substring.\n\nQuery 3: the substring of S starting at index 1 and ending at index 8 is ACACTACG. In this string, AC occurs three times as a substring.", "sample_input": "8 3\nACACTACG\n3 7\n2 3\n1 8\n"}, "reference_outputs": ["2\n0\n3\n"], "source_document_id": "p03087", "source_text": "Score : 300 points\n\nProblem Statement\n\nYou are given a string S of length N consisting of A, C, G and T. Answer the following Q queries:\n\nQuery i (1 \\leq i \\leq Q): You will be given integers l_i and r_i (1 \\leq l_i < r_i \\leq N). Consider the substring of S starting at index l_i and ending at index r_i (both inclusive). In this string, how many times does AC occurs as a substring?\n\nNotes\n\nA substring of a string T is a string obtained by removing zero or more characters from the beginning and the end of T.\n\nFor example, the substrings of ATCODER include TCO, AT, CODER, ATCODER and (the empty string), but not AC.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n1 \\leq Q \\leq 10^5\n\nS is a string of length N.\n\nEach character in S is A, C, G or T.\n\n1 \\leq l_i < r_i \\leq N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN Q\nS\nl_1 r_1\n:\nl_Q r_Q\n\nOutput\n\nPrint Q lines. The i-th line should contain the answer to the i-th query.\n\nSample Input 1\n\n8 3\nACACTACG\n3 7\n2 3\n1 8\n\nSample Output 1\n\n2\n0\n3\n\nQuery 1: the substring of S starting at index 3 and ending at index 7 is ACTAC. In this string, AC occurs twice as a substring.\n\nQuery 2: the substring of S starting at index 2 and ending at index 3 is CA. In this string, AC occurs zero times as a substring.\n\nQuery 3: the substring of S starting at index 1 and ending at index 8 is ACACTACG. In this string, AC occurs three times as a substring.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 978, "cpu_time_ms": 223, "memory_kb": 1792}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s090581682", "group_id": "codeNet:p03089", "input_text": "#include \"bits/stdc++.h\"\nusing namespace std;\n\n/* macro */\n#define rep(i,a,b) for(int i=a;i<b;i++)\n#define revrep(i,a,b) for(int i = a; i > b; i--)\n#define int long long\n#define exist(s,e) ((s).find(e)!=(s).end())\n#define all(v) (v).begin(), (v).end()\n#define each(s,itr) for(auto (itr) = s.begin(); (itr) != s.end(); (itr)++)\n#define sum(v) accumulate(all(v), (0LL))\n#define isin(a, b, c) (b <= a && a <= c)\n#define println cout << \"\\n\";\n#define sz(v) (int)v.size()\n#define bin(x) static_cast<bitset<16> >(x)\n\n\n\n/* alias */\ntemplate<class T> using vec = vector<T>;\ntypedef vector<int> vi;\ntypedef pair<int, int> pi;\ntypedef tuple<int, int, int> ti;\ntypedef map<int, int> mi;\ntypedef set<int> si;\n\n\n/* constant */\nconst int inf = 1LL << 62;\nconst int mod = 1e9 + 7;\nconst int dx[8]={1,0,-1,0,-1,1,-1,1};\nconst int dy[8]={0,1,0,-1,-1,-1,1,1};\nconst string alphabet = \"abcdefghijklmnopqrstuvwxyz\";\n\n/* io_method */\nint input(){int tmp;cin >> tmp;return tmp;}\nstring raw_input(){string tmp;cin >> tmp;return tmp;}\ntemplate<class T> void printx(T n){cout << n;}\ntemplate<class T, class U> void printx(pair<T, U> p){cout << \"(\" << p.first << \",\" << p.second << \")\";}\ntemplate<class T, class U, class V> void printx(tuple<T, U, V> t){cout << \"{\" << get<0>(t) << \",\" << get<1>(t) <<\",\" << get<2>(t) << \"}\" << endl;}\ntemplate<class T> void printx(vector<T> v){cout << \"{\";rep(i,0,v.size()){printx(v[i]);if(i != v.size()-1)printx(\",\");}cout << \"}\";}\ntemplate<class T> void print(T n){printx(n);cout << endl;}\ntemplate<class T> void print(set<T> s){cout << \"{\";each(s, e){if(e != s.begin()) printx(\",\");printx(*e);}cout << \"}\" << endl;}\ntemplate<class T, class U> void print(map<T, U> mp){cout << \"{\";each(mp, e){cout << \"(\" << e -> first << \",\" << e -> second << \")\";}cout << \"}\" << endl;}\ntemplate<class T> void printans(vec<T> v){rep(i,0,sz(v)){cout << v[i] << (i == sz(v) - 1 ? \"\" : \" \");}cout << endl;}\n\n\n/* general_method */\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }\ntemplate<class T>T cut(T &a, int l, int r){return T(a.begin()+l, a.begin()+r);}\n\n/* main */\n\nint n;\nvi arr;\nvoid in(){\n    cin >> n;\n    rep(i,0,n) arr.push_back(input());\n}\n\nvoid solve(){\n    \n    vi ans;\n    rep(i,0,n){\n        revrep(j,n - 1 - i, -1){\n            if(arr[j] - 1 == j){\n                ans.push_back(arr[j]);\n                vi tmp = cut(arr, 0, j);\n                vi b = cut(arr, j + 1, sz(arr));\n                for(int e : b) tmp.push_back(e);\n                arr = tmp;\n                break;\n            }\n        }\n    }\n\n    if(sz(arr) > 0){\n        print(-1);\n        return ;\n    }\n\n    reverse(all(ans));\n    printans(ans);\n\n\n}\n\nsigned main(){\n\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n    in();\n    solve();\n    \n}", "language": "C++", "metadata": {"date": 1553580014, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03089.html", "problem_id": "p03089", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03089/input.txt", "sample_output_relpath": "derived/input_output/data/p03089/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03089/C++/s090581682.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s090581682", "user_id": "u828847847"}, "prompt_components": {"gold_output": "1\n1\n2\n", "input_to_evaluate": "#include \"bits/stdc++.h\"\nusing namespace std;\n\n/* macro */\n#define rep(i,a,b) for(int i=a;i<b;i++)\n#define revrep(i,a,b) for(int i = a; i > b; i--)\n#define int long long\n#define exist(s,e) ((s).find(e)!=(s).end())\n#define all(v) (v).begin(), (v).end()\n#define each(s,itr) for(auto (itr) = s.begin(); (itr) != s.end(); (itr)++)\n#define sum(v) accumulate(all(v), (0LL))\n#define isin(a, b, c) (b <= a && a <= c)\n#define println cout << \"\\n\";\n#define sz(v) (int)v.size()\n#define bin(x) static_cast<bitset<16> >(x)\n\n\n\n/* alias */\ntemplate<class T> using vec = vector<T>;\ntypedef vector<int> vi;\ntypedef pair<int, int> pi;\ntypedef tuple<int, int, int> ti;\ntypedef map<int, int> mi;\ntypedef set<int> si;\n\n\n/* constant */\nconst int inf = 1LL << 62;\nconst int mod = 1e9 + 7;\nconst int dx[8]={1,0,-1,0,-1,1,-1,1};\nconst int dy[8]={0,1,0,-1,-1,-1,1,1};\nconst string alphabet = \"abcdefghijklmnopqrstuvwxyz\";\n\n/* io_method */\nint input(){int tmp;cin >> tmp;return tmp;}\nstring raw_input(){string tmp;cin >> tmp;return tmp;}\ntemplate<class T> void printx(T n){cout << n;}\ntemplate<class T, class U> void printx(pair<T, U> p){cout << \"(\" << p.first << \",\" << p.second << \")\";}\ntemplate<class T, class U, class V> void printx(tuple<T, U, V> t){cout << \"{\" << get<0>(t) << \",\" << get<1>(t) <<\",\" << get<2>(t) << \"}\" << endl;}\ntemplate<class T> void printx(vector<T> v){cout << \"{\";rep(i,0,v.size()){printx(v[i]);if(i != v.size()-1)printx(\",\");}cout << \"}\";}\ntemplate<class T> void print(T n){printx(n);cout << endl;}\ntemplate<class T> void print(set<T> s){cout << \"{\";each(s, e){if(e != s.begin()) printx(\",\");printx(*e);}cout << \"}\" << endl;}\ntemplate<class T, class U> void print(map<T, U> mp){cout << \"{\";each(mp, e){cout << \"(\" << e -> first << \",\" << e -> second << \")\";}cout << \"}\" << endl;}\ntemplate<class T> void printans(vec<T> v){rep(i,0,sz(v)){cout << v[i] << (i == sz(v) - 1 ? \"\" : \" \");}cout << endl;}\n\n\n/* general_method */\ntemplate<class T>bool chmax(T &a, const T &b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<class T>bool chmin(T &a, const T &b) { if (b<a) { a=b; return 1; } return 0; }\ntemplate<class T>T cut(T &a, int l, int r){return T(a.begin()+l, a.begin()+r);}\n\n/* main */\n\nint n;\nvi arr;\nvoid in(){\n    cin >> n;\n    rep(i,0,n) arr.push_back(input());\n}\n\nvoid solve(){\n    \n    vi ans;\n    rep(i,0,n){\n        revrep(j,n - 1 - i, -1){\n            if(arr[j] - 1 == j){\n                ans.push_back(arr[j]);\n                vi tmp = cut(arr, 0, j);\n                vi b = cut(arr, j + 1, sz(arr));\n                for(int e : b) tmp.push_back(e);\n                arr = tmp;\n                break;\n            }\n        }\n    }\n\n    if(sz(arr) > 0){\n        print(-1);\n        return ;\n    }\n\n    reverse(all(ans));\n    printans(ans);\n\n\n}\n\nsigned main(){\n\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n    in();\n    solve();\n    \n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nSnuke has an empty sequence a.\n\nHe will perform N operations on this sequence.\n\nIn the i-th operation, he chooses an integer j satisfying 1 \\leq j \\leq i, and insert j at position j in a (the beginning is position 1).\n\nYou are given a sequence b of length N. Determine if it is possible that a is equal to b after N operations. If it is, show one possible sequence of operations that achieves it.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 100\n\n1 \\leq b_i \\leq N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nb_1 \\dots b_N\n\nOutput\n\nIf there is no sequence of N operations after which a would be equal to b, print -1.\nIf there is, print N lines. In the i-th line, the integer chosen in the i-th operation should be printed. If there are multiple solutions, any of them is accepted.\n\nSample Input 1\n\n3\n1 2 1\n\nSample Output 1\n\n1\n1\n2\n\nIn this sequence of operations, the sequence a changes as follows:\n\nAfter the first operation: (1)\n\nAfter the second operation: (1,1)\n\nAfter the third operation: (1,2,1)\n\nSample Input 2\n\n2\n2 2\n\nSample Output 2\n\n-1\n\n2 cannot be inserted at the beginning of the sequence, so this is impossible.\n\nSample Input 3\n\n9\n1 1 1 2 2 1 2 3 2\n\nSample Output 3\n\n1\n2\n2\n3\n1\n2\n2\n1\n1", "sample_input": "3\n1 2 1\n"}, "reference_outputs": ["1\n1\n2\n"], "source_document_id": "p03089", "source_text": "Score : 400 points\n\nProblem Statement\n\nSnuke has an empty sequence a.\n\nHe will perform N operations on this sequence.\n\nIn the i-th operation, he chooses an integer j satisfying 1 \\leq j \\leq i, and insert j at position j in a (the beginning is position 1).\n\nYou are given a sequence b of length N. Determine if it is possible that a is equal to b after N operations. If it is, show one possible sequence of operations that achieves it.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 100\n\n1 \\leq b_i \\leq N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nb_1 \\dots b_N\n\nOutput\n\nIf there is no sequence of N operations after which a would be equal to b, print -1.\nIf there is, print N lines. In the i-th line, the integer chosen in the i-th operation should be printed. If there are multiple solutions, any of them is accepted.\n\nSample Input 1\n\n3\n1 2 1\n\nSample Output 1\n\n1\n1\n2\n\nIn this sequence of operations, the sequence a changes as follows:\n\nAfter the first operation: (1)\n\nAfter the second operation: (1,1)\n\nAfter the third operation: (1,2,1)\n\nSample Input 2\n\n2\n2 2\n\nSample Output 2\n\n-1\n\n2 cannot be inserted at the beginning of the sequence, so this is impossible.\n\nSample Input 3\n\n9\n1 1 1 2 2 1 2 3 2\n\nSample Output 3\n\n1\n2\n2\n3\n1\n2\n2\n1\n1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2849, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s598658302", "group_id": "codeNet:p03092", "input_text": "#include <vector>\n#include <algorithm>\n#include <iostream>\nusing namespace std;\nint main() {\n    int n, a, b; cin >> n >> a >> b;\n    int P[n]; for (int i = 0; i < n; i++) cin >> P[i];\n\n    int lis[n] = {};\n    fill(lis, lis+n, 1<<30);\n    for (int i = 0; i < n; i++)\n        *lower_bound(lis, lis+n, P[i]) = P[i];\n    vector<int> s;\n    int m = lower_bound(lis, lis+n, 1<<30) - lis - 1;\n    // for (int i = 0; i <= m; i++) cerr << lis[i] << ' '; cerr << endl;\n    int prevv = 1<<30;\n    for (int i = n-1; i >= 0; i--) {\n        if (lis[m] <= P[i] && P[i] < prevv) {\n            s.push_back(i);\n            prevv = P[i];\n            m--;\n        }\n    }\n    // for (int x : s) cerr << x << ' '; cerr << endl;\n    reverse(s.begin(), s.end());\n    bool in_lis[n] = {};\n    for (int i : s) in_lis[i] = true;\n    int acc_min[n], acc_max[n];\n    int temp = 1<<30;\n    for (int i = n-1; i >= 0; i--) {\n        if (in_lis[i]) temp = min(temp, P[i]);\n        acc_min[i] = temp;\n    }\n    temp = 0;\n    for (int i = 0; i < n; i++) {\n        if (in_lis[i]) temp = max(temp, P[i]);\n        acc_max[i] = temp;\n    }\n    long long ans = 0;\n    for (int i = 0; i < n; i++) {\n        if (in_lis[i]) continue;\n        auto it = lower_bound(s.begin(), s.end(), i);\n        if (it != s.end() && P[i] > P[*it]) ans += a;\n        else if (it != s.begin() && P[i] < P[*prev(it)]) ans += b;\n    }\n    cout << ans << endl;\n}\n", "language": "C++", "metadata": {"date": 1553378586, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03092.html", "problem_id": "p03092", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03092/input.txt", "sample_output_relpath": "derived/input_output/data/p03092/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03092/C++/s598658302.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s598658302", "user_id": "u374416262"}, "prompt_components": {"gold_output": "20\n", "input_to_evaluate": "#include <vector>\n#include <algorithm>\n#include <iostream>\nusing namespace std;\nint main() {\n    int n, a, b; cin >> n >> a >> b;\n    int P[n]; for (int i = 0; i < n; i++) cin >> P[i];\n\n    int lis[n] = {};\n    fill(lis, lis+n, 1<<30);\n    for (int i = 0; i < n; i++)\n        *lower_bound(lis, lis+n, P[i]) = P[i];\n    vector<int> s;\n    int m = lower_bound(lis, lis+n, 1<<30) - lis - 1;\n    // for (int i = 0; i <= m; i++) cerr << lis[i] << ' '; cerr << endl;\n    int prevv = 1<<30;\n    for (int i = n-1; i >= 0; i--) {\n        if (lis[m] <= P[i] && P[i] < prevv) {\n            s.push_back(i);\n            prevv = P[i];\n            m--;\n        }\n    }\n    // for (int x : s) cerr << x << ' '; cerr << endl;\n    reverse(s.begin(), s.end());\n    bool in_lis[n] = {};\n    for (int i : s) in_lis[i] = true;\n    int acc_min[n], acc_max[n];\n    int temp = 1<<30;\n    for (int i = n-1; i >= 0; i--) {\n        if (in_lis[i]) temp = min(temp, P[i]);\n        acc_min[i] = temp;\n    }\n    temp = 0;\n    for (int i = 0; i < n; i++) {\n        if (in_lis[i]) temp = max(temp, P[i]);\n        acc_max[i] = temp;\n    }\n    long long ans = 0;\n    for (int i = 0; i < n; i++) {\n        if (in_lis[i]) continue;\n        auto it = lower_bound(s.begin(), s.end(), i);\n        if (it != s.end() && P[i] > P[*it]) ans += a;\n        else if (it != s.begin() && P[i] < P[*prev(it)]) ans += b;\n    }\n    cout << ans << endl;\n}\n", "problem_context": "Score : 1000 points\n\nProblem Statement\n\nYou are given a permutation p = (p_1, \\ldots, p_N) of \\{ 1, \\ldots, N \\}.\nYou can perform the following two kinds of operations repeatedly in any order:\n\nPay a cost A. Choose integers l and r (1 \\leq l < r \\leq N), and shift (p_l, \\ldots, p_r) to the left by one. That is, replace p_l, p_{l + 1}, \\ldots, p_{r - 1}, p_r with p_{l + 1}, p_{l + 2}, \\ldots, p_r, p_l, respectively.\n\nPay a cost B. Choose integers l and r (1 \\leq l < r \\leq N), and shift (p_l, \\ldots, p_r) to the right by one. That is, replace p_l, p_{l + 1}, \\ldots, p_{r - 1}, p_r with p_r, p_l, \\ldots, p_{r - 2}, p_{r - 1}, respectively.\n\nFind the minimum total cost required to sort p in ascending order.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 5000\n\n1 \\leq A, B \\leq 10^9\n\n(p_1 \\ldots, p_N) is a permutation of \\{ 1, \\ldots, N \\}.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN A B\np_1 \\cdots p_N\n\nOutput\n\nPrint the minimum total cost required to sort p in ascending order.\n\nSample Input 1\n\n3 20 30\n3 1 2\n\nSample Output 1\n\n20\n\nShifting (p_1, p_2, p_3) to the left by one results in p = (1, 2, 3).\n\nSample Input 2\n\n4 20 30\n4 2 3 1\n\nSample Output 2\n\n50\n\nOne possible sequence of operations is as follows:\n\nShift (p_1, p_2, p_3, p_4) to the left by one. Now we have p = (2, 3, 1, 4).\n\nShift (p_1, p_2, p_3) to the right by one. Now we have p = (1, 2, 3, 4).\n\nHere, the total cost is 20 + 30 = 50.\n\nSample Input 3\n\n1 10 10\n1\n\nSample Output 3\n\n0\n\nSample Input 4\n\n4 1000000000 1000000000\n4 3 2 1\n\nSample Output 4\n\n3000000000\n\nSample Input 5\n\n9 40 50\n5 3 4 7 6 1 2 9 8\n\nSample Output 5\n\n220", "sample_input": "3 20 30\n3 1 2\n"}, "reference_outputs": ["20\n"], "source_document_id": "p03092", "source_text": "Score : 1000 points\n\nProblem Statement\n\nYou are given a permutation p = (p_1, \\ldots, p_N) of \\{ 1, \\ldots, N \\}.\nYou can perform the following two kinds of operations repeatedly in any order:\n\nPay a cost A. Choose integers l and r (1 \\leq l < r \\leq N), and shift (p_l, \\ldots, p_r) to the left by one. That is, replace p_l, p_{l + 1}, \\ldots, p_{r - 1}, p_r with p_{l + 1}, p_{l + 2}, \\ldots, p_r, p_l, respectively.\n\nPay a cost B. Choose integers l and r (1 \\leq l < r \\leq N), and shift (p_l, \\ldots, p_r) to the right by one. That is, replace p_l, p_{l + 1}, \\ldots, p_{r - 1}, p_r with p_r, p_l, \\ldots, p_{r - 2}, p_{r - 1}, respectively.\n\nFind the minimum total cost required to sort p in ascending order.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 5000\n\n1 \\leq A, B \\leq 10^9\n\n(p_1 \\ldots, p_N) is a permutation of \\{ 1, \\ldots, N \\}.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN A B\np_1 \\cdots p_N\n\nOutput\n\nPrint the minimum total cost required to sort p in ascending order.\n\nSample Input 1\n\n3 20 30\n3 1 2\n\nSample Output 1\n\n20\n\nShifting (p_1, p_2, p_3) to the left by one results in p = (1, 2, 3).\n\nSample Input 2\n\n4 20 30\n4 2 3 1\n\nSample Output 2\n\n50\n\nOne possible sequence of operations is as follows:\n\nShift (p_1, p_2, p_3, p_4) to the left by one. Now we have p = (2, 3, 1, 4).\n\nShift (p_1, p_2, p_3) to the right by one. Now we have p = (1, 2, 3, 4).\n\nHere, the total cost is 20 + 30 = 50.\n\nSample Input 3\n\n1 10 10\n1\n\nSample Output 3\n\n0\n\nSample Input 4\n\n4 1000000000 1000000000\n4 3 2 1\n\nSample Output 4\n\n3000000000\n\nSample Input 5\n\n9 40 50\n5 3 4 7 6 1 2 9 8\n\nSample Output 5\n\n220", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1402, "cpu_time_ms": 3, "memory_kb": 384}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s829478275", "group_id": "codeNet:p03096", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define rep(i,n) for(int i=0; i<(n); ++i)\n#define rrep(i,n) for(int i=1; i<=(n); ++i)\n#define drep(i,n) for(int i=(n)-1; i>=0; --i)\n#define foreach(it, v) for(typeof(v.begin()) it=v.begin(); it!=v.end(); ++it)\n#define pb push_back\n#define sz(x) (int)(x).size()\n#define fi first\n#define se second\n\ntypedef unsigned int uint;\ntypedef long long int ll;\ntypedef vector<int> vi;\ntypedef pair<int,int> pii;\ntypedef vector<pii> vpii;\ntypedef set<int> si;\n\n//MOD//\nconst ll MOD = 1000000007;\nstruct big;\nbig ex(big a, ll tms);\ntypedef struct big{\n  ll val;\n  big():val(0){}\n  big(ll val):val((val%MOD+MOD)%MOD){}\n  big& operator += (const big& obj){ (val+=obj.val)%=MOD; return *this;}\n  big& operator -= (const big& obj){ (val+=MOD-obj.val)%=MOD; return *this;}\n  big& operator *= (const big& obj){ (val*=obj.val)%=MOD; return *this;}\n  big& operator /= (const big& obj){ (val*=ex(obj,MOD-2).val)%=MOD; return *this;}\n  big operator + (const big& obj)const{ return big(*this) += obj;}\n  big operator - (const big& obj)const{ return big(*this) -= obj;}\n  big operator * (const big& obj)const{ return big(*this) *= obj;}\n  big operator / (const big& obj)const{ return big(*this) /= obj;}\n  bool operator < (const big& obj)const{ return val < obj.val;}\n  bool operator == (const big& obj)const{ return val == obj.val;}\n} big;\nistream& operator >> (istream& i, big& obj){ i>>obj.val; return i;}\nostream& operator << (ostream& o, const big& obj){ o<<obj.val; return o;}\nbig ex(big obj, ll tms){\n  if(!tms) return 1;\n  big ret = ex(obj, tms/2);\n  ret *= ret;\n  return (tms&1) ? ret*obj : ret;\n}\n//MOD//\n\nll pow(ll n, int m){\n  if(!m) return 1;\n  ll ret = pow(n, m/2);\n  ret *= ret;\n  return (m&1) ? ret*n : ret;\n}\n\ntemplate <class F, class T>\nvoid convert(const F &f, T &t){\n  stringstream ss;\n  ss << f;\n  ss >> t;\n}\n\nint N,M;\nint c[200001];\n\n//big jst[200000];\nbig cnt[200001];\n\nbig s[200001];\n\nint main(){\n\n  scanf(\"%d\",&N);\n  int bef = -1;\n  int cc;\n  rep (i,N) {\n    scanf(\"%d\", &cc);\n    if (cc != bef) {\n      c[M] = cc;\n      bef = cc;\n      ++M;\n    }\n  }\n\n  rep (i,M) {\n    big cntbef = i==0 ? 1 : cnt[i-1];\n    cnt[i] = cntbef + s[c[i]];\n    s[c[i]] += cntbef;\n  }\n\n  cout << cnt[M-1] << endl;\n\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1552941214, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03096.html", "problem_id": "p03096", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03096/input.txt", "sample_output_relpath": "derived/input_output/data/p03096/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03096/C++/s829478275.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s829478275", "user_id": "u807190097"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define rep(i,n) for(int i=0; i<(n); ++i)\n#define rrep(i,n) for(int i=1; i<=(n); ++i)\n#define drep(i,n) for(int i=(n)-1; i>=0; --i)\n#define foreach(it, v) for(typeof(v.begin()) it=v.begin(); it!=v.end(); ++it)\n#define pb push_back\n#define sz(x) (int)(x).size()\n#define fi first\n#define se second\n\ntypedef unsigned int uint;\ntypedef long long int ll;\ntypedef vector<int> vi;\ntypedef pair<int,int> pii;\ntypedef vector<pii> vpii;\ntypedef set<int> si;\n\n//MOD//\nconst ll MOD = 1000000007;\nstruct big;\nbig ex(big a, ll tms);\ntypedef struct big{\n  ll val;\n  big():val(0){}\n  big(ll val):val((val%MOD+MOD)%MOD){}\n  big& operator += (const big& obj){ (val+=obj.val)%=MOD; return *this;}\n  big& operator -= (const big& obj){ (val+=MOD-obj.val)%=MOD; return *this;}\n  big& operator *= (const big& obj){ (val*=obj.val)%=MOD; return *this;}\n  big& operator /= (const big& obj){ (val*=ex(obj,MOD-2).val)%=MOD; return *this;}\n  big operator + (const big& obj)const{ return big(*this) += obj;}\n  big operator - (const big& obj)const{ return big(*this) -= obj;}\n  big operator * (const big& obj)const{ return big(*this) *= obj;}\n  big operator / (const big& obj)const{ return big(*this) /= obj;}\n  bool operator < (const big& obj)const{ return val < obj.val;}\n  bool operator == (const big& obj)const{ return val == obj.val;}\n} big;\nistream& operator >> (istream& i, big& obj){ i>>obj.val; return i;}\nostream& operator << (ostream& o, const big& obj){ o<<obj.val; return o;}\nbig ex(big obj, ll tms){\n  if(!tms) return 1;\n  big ret = ex(obj, tms/2);\n  ret *= ret;\n  return (tms&1) ? ret*obj : ret;\n}\n//MOD//\n\nll pow(ll n, int m){\n  if(!m) return 1;\n  ll ret = pow(n, m/2);\n  ret *= ret;\n  return (m&1) ? ret*n : ret;\n}\n\ntemplate <class F, class T>\nvoid convert(const F &f, T &t){\n  stringstream ss;\n  ss << f;\n  ss >> t;\n}\n\nint N,M;\nint c[200001];\n\n//big jst[200000];\nbig cnt[200001];\n\nbig s[200001];\n\nint main(){\n\n  scanf(\"%d\",&N);\n  int bef = -1;\n  int cc;\n  rep (i,N) {\n    scanf(\"%d\", &cc);\n    if (cc != bef) {\n      c[M] = cc;\n      bef = cc;\n      ++M;\n    }\n  }\n\n  rep (i,M) {\n    big cntbef = i==0 ? 1 : cnt[i-1];\n    cnt[i] = cntbef + s[c[i]];\n    s[c[i]] += cntbef;\n  }\n\n  cout << cnt[M-1] << endl;\n\n  return 0;\n}\n", "problem_context": "Score : 700 points\n\nProblem Statement\n\nThere are N stones arranged in a row. The i-th stone from the left is painted in the color C_i.\n\nSnuke will perform the following operation zero or more times:\n\nChoose two stones painted in the same color. Repaint all the stones between them, with the color of the chosen stones.\n\nFind the number of possible final sequences of colors of the stones, modulo 10^9+7.\n\nConstraints\n\n1 \\leq N \\leq 2\\times 10^5\n\n1 \\leq C_i \\leq 2\\times 10^5(1\\leq i\\leq N)\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nC_1\n:\nC_N\n\nOutput\n\nPrint the number of possible final sequences of colors of the stones, modulo 10^9+7.\n\nSample Input 1\n\n5\n1\n2\n1\n2\n2\n\nSample Output 1\n\n3\n\nWe can make three sequences of colors of stones, as follows:\n\n(1,2,1,2,2), by doing nothing.\n\n(1,1,1,2,2), by choosing the first and third stones to perform the operation.\n\n(1,2,2,2,2), by choosing the second and fourth stones to perform the operation.\n\nSample Input 2\n\n6\n4\n2\n5\n4\n2\n4\n\nSample Output 2\n\n5\n\nSample Input 3\n\n7\n1\n3\n1\n2\n3\n3\n2\n\nSample Output 3\n\n5", "sample_input": "5\n1\n2\n1\n2\n2\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03096", "source_text": "Score : 700 points\n\nProblem Statement\n\nThere are N stones arranged in a row. The i-th stone from the left is painted in the color C_i.\n\nSnuke will perform the following operation zero or more times:\n\nChoose two stones painted in the same color. Repaint all the stones between them, with the color of the chosen stones.\n\nFind the number of possible final sequences of colors of the stones, modulo 10^9+7.\n\nConstraints\n\n1 \\leq N \\leq 2\\times 10^5\n\n1 \\leq C_i \\leq 2\\times 10^5(1\\leq i\\leq N)\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nC_1\n:\nC_N\n\nOutput\n\nPrint the number of possible final sequences of colors of the stones, modulo 10^9+7.\n\nSample Input 1\n\n5\n1\n2\n1\n2\n2\n\nSample Output 1\n\n3\n\nWe can make three sequences of colors of stones, as follows:\n\n(1,2,1,2,2), by doing nothing.\n\n(1,1,1,2,2), by choosing the first and third stones to perform the operation.\n\n(1,2,2,2,2), by choosing the second and fourth stones to perform the operation.\n\nSample Input 2\n\n6\n4\n2\n5\n4\n2\n4\n\nSample Output 2\n\n5\n\nSample Input 3\n\n7\n1\n3\n1\n2\n3\n3\n2\n\nSample Output 3\n\n5", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2254, "cpu_time_ms": 26, "memory_kb": 4096}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s725517835", "group_id": "codeNet:p03103", "input_text": "#include <bits/stdc++.h>\n#define rep(i,n) for (int i = 0; i < (n); ++i)\nusing namespace std;\nusing ll = long long;\nusing P = pair<int,int>;\n\nconst int MOD = 1000000007;\nconst int INF = 999999999;\n\nint main(){\n   int N, M;\n   cin >> N >> M;\n   vector<P> A(N);\n   rep(i, N){\n      cin >> A[i].first >> A[i].second;\n   }\n   sort(A.begin(), A.end());\n   /*rep(i, N){\n      cout << A[i].first << endl;\n   }*/\n   int ans = 0;\n   rep(i, N){\n      if(M > 0){\n         if(A[i].second >= M){\n            ans += A[i].first * M;\n            M = 0;\n         }else{\n            ans += A[i].first * A[i].second;\n            M -= A[i].second;\n         }\n      }else{\n         break;\n      }\n   }\n   cout << ans << endl;\nreturn 0;}", "language": "C++", "metadata": {"date": 1587831323, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03103.html", "problem_id": "p03103", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03103/input.txt", "sample_output_relpath": "derived/input_output/data/p03103/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03103/C++/s725517835.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s725517835", "user_id": "u767481489"}, "prompt_components": {"gold_output": "12\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define rep(i,n) for (int i = 0; i < (n); ++i)\nusing namespace std;\nusing ll = long long;\nusing P = pair<int,int>;\n\nconst int MOD = 1000000007;\nconst int INF = 999999999;\n\nint main(){\n   int N, M;\n   cin >> N >> M;\n   vector<P> A(N);\n   rep(i, N){\n      cin >> A[i].first >> A[i].second;\n   }\n   sort(A.begin(), A.end());\n   /*rep(i, N){\n      cout << A[i].first << endl;\n   }*/\n   int ans = 0;\n   rep(i, N){\n      if(M > 0){\n         if(A[i].second >= M){\n            ans += A[i].first * M;\n            M = 0;\n         }else{\n            ans += A[i].first * A[i].second;\n            M -= A[i].second;\n         }\n      }else{\n         break;\n      }\n   }\n   cout << ans << endl;\nreturn 0;}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nHearing that energy drinks increase rating in those sites, Takahashi decides to buy up M cans of energy drinks.\n\nThere are N stores that sell energy drinks. In the i-th store, he can buy at most B_i cans of energy drinks for A_i yen (the currency of Japan) each.\n\nWhat is the minimum amount of money with which he can buy M cans of energy drinks?\n\nIt is guaranteed that, in the given inputs, a sufficient amount of money can always buy M cans of energy drinks.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N, M \\leq 10^5\n\n1 \\leq A_i \\leq 10^9\n\n1 \\leq B_i \\leq 10^5\n\nB_1 + ... + B_N \\geq M\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 B_1\nA_2 B_2\n\\vdots\nA_N B_N\n\nOutput\n\nPrint the minimum amount of money with which Takahashi can buy M cans of energy drinks.\n\nSample Input 1\n\n2 5\n4 9\n2 4\n\nSample Output 1\n\n12\n\nWith 12 yen, we can buy one drink at the first store and four drinks at the second store, for the total of five drinks. However, we cannot buy 5 drinks with 11 yen or less.\n\nSample Input 2\n\n4 30\n6 18\n2 5\n3 10\n7 9\n\nSample Output 2\n\n130\n\nSample Input 3\n\n1 100000\n1000000000 100000\n\nSample Output 3\n\n100000000000000\n\nThe output may not fit into a 32-bit integer type.", "sample_input": "2 5\n4 9\n2 4\n"}, "reference_outputs": ["12\n"], "source_document_id": "p03103", "source_text": "Score : 300 points\n\nProblem Statement\n\nHearing that energy drinks increase rating in those sites, Takahashi decides to buy up M cans of energy drinks.\n\nThere are N stores that sell energy drinks. In the i-th store, he can buy at most B_i cans of energy drinks for A_i yen (the currency of Japan) each.\n\nWhat is the minimum amount of money with which he can buy M cans of energy drinks?\n\nIt is guaranteed that, in the given inputs, a sufficient amount of money can always buy M cans of energy drinks.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N, M \\leq 10^5\n\n1 \\leq A_i \\leq 10^9\n\n1 \\leq B_i \\leq 10^5\n\nB_1 + ... + B_N \\geq M\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 B_1\nA_2 B_2\n\\vdots\nA_N B_N\n\nOutput\n\nPrint the minimum amount of money with which Takahashi can buy M cans of energy drinks.\n\nSample Input 1\n\n2 5\n4 9\n2 4\n\nSample Output 1\n\n12\n\nWith 12 yen, we can buy one drink at the first store and four drinks at the second store, for the total of five drinks. However, we cannot buy 5 drinks with 11 yen or less.\n\nSample Input 2\n\n4 30\n6 18\n2 5\n3 10\n7 9\n\nSample Output 2\n\n130\n\nSample Input 3\n\n1 100000\n1000000000 100000\n\nSample Output 3\n\n100000000000000\n\nThe output may not fit into a 32-bit integer type.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 714, "cpu_time_ms": 76, "memory_kb": 1024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s427771857", "group_id": "codeNet:p03103", "input_text": "#include <bits/stdc++.h>\n#define rep(i,n) for(int i = 0; i < (int)(n); i++)\nusing namespace std;\nusing ll = long long;\nusing P = pair<int, int>;\nusing vi = vector<int>;\nusing vc = vector<char>;\nusing vs = vector<string>;\nusing vll = vector<long long>;\nusing vvi = vector<vector<int>>;\nusing vvc = vector<vector<char>>;\nusing vvll = vector<vector<long long>>;\ntemplate<class T> inline bool chmax(T &a, T b) { if (a<b) {a=b; return 1;} return 0;}\ntemplate<class T> inline bool chmin(T &a, T b) { if (b<a) {a=b; return 1;} return 0;}\n\nint main() {\n    ios::sync_with_stdio(false);\n    cin.tie(0);\n    \n    int n, m;\n    cin >> n >> m;\n    vector<P> ab(n);\n    rep(i, n) {\n        int a, b;\n        cin >> a >> b;\n        ab[i] = P(a, b);\n    }\n    sort(ab.begin(), ab.end());\n    ll ans = 0;\n    for (auto p : ab) {\n        if (m <= 0) break;\n        ans += (ll)p.first * min((ll)m, (ll)p.second);\n        m -= min(m, p.second);\n    }\n    cout << ans << endl;\n\n}", "language": "C++", "metadata": {"date": 1586713236, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03103.html", "problem_id": "p03103", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03103/input.txt", "sample_output_relpath": "derived/input_output/data/p03103/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03103/C++/s427771857.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s427771857", "user_id": "u009414205"}, "prompt_components": {"gold_output": "12\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define rep(i,n) for(int i = 0; i < (int)(n); i++)\nusing namespace std;\nusing ll = long long;\nusing P = pair<int, int>;\nusing vi = vector<int>;\nusing vc = vector<char>;\nusing vs = vector<string>;\nusing vll = vector<long long>;\nusing vvi = vector<vector<int>>;\nusing vvc = vector<vector<char>>;\nusing vvll = vector<vector<long long>>;\ntemplate<class T> inline bool chmax(T &a, T b) { if (a<b) {a=b; return 1;} return 0;}\ntemplate<class T> inline bool chmin(T &a, T b) { if (b<a) {a=b; return 1;} return 0;}\n\nint main() {\n    ios::sync_with_stdio(false);\n    cin.tie(0);\n    \n    int n, m;\n    cin >> n >> m;\n    vector<P> ab(n);\n    rep(i, n) {\n        int a, b;\n        cin >> a >> b;\n        ab[i] = P(a, b);\n    }\n    sort(ab.begin(), ab.end());\n    ll ans = 0;\n    for (auto p : ab) {\n        if (m <= 0) break;\n        ans += (ll)p.first * min((ll)m, (ll)p.second);\n        m -= min(m, p.second);\n    }\n    cout << ans << endl;\n\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nHearing that energy drinks increase rating in those sites, Takahashi decides to buy up M cans of energy drinks.\n\nThere are N stores that sell energy drinks. In the i-th store, he can buy at most B_i cans of energy drinks for A_i yen (the currency of Japan) each.\n\nWhat is the minimum amount of money with which he can buy M cans of energy drinks?\n\nIt is guaranteed that, in the given inputs, a sufficient amount of money can always buy M cans of energy drinks.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N, M \\leq 10^5\n\n1 \\leq A_i \\leq 10^9\n\n1 \\leq B_i \\leq 10^5\n\nB_1 + ... + B_N \\geq M\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 B_1\nA_2 B_2\n\\vdots\nA_N B_N\n\nOutput\n\nPrint the minimum amount of money with which Takahashi can buy M cans of energy drinks.\n\nSample Input 1\n\n2 5\n4 9\n2 4\n\nSample Output 1\n\n12\n\nWith 12 yen, we can buy one drink at the first store and four drinks at the second store, for the total of five drinks. However, we cannot buy 5 drinks with 11 yen or less.\n\nSample Input 2\n\n4 30\n6 18\n2 5\n3 10\n7 9\n\nSample Output 2\n\n130\n\nSample Input 3\n\n1 100000\n1000000000 100000\n\nSample Output 3\n\n100000000000000\n\nThe output may not fit into a 32-bit integer type.", "sample_input": "2 5\n4 9\n2 4\n"}, "reference_outputs": ["12\n"], "source_document_id": "p03103", "source_text": "Score : 300 points\n\nProblem Statement\n\nHearing that energy drinks increase rating in those sites, Takahashi decides to buy up M cans of energy drinks.\n\nThere are N stores that sell energy drinks. In the i-th store, he can buy at most B_i cans of energy drinks for A_i yen (the currency of Japan) each.\n\nWhat is the minimum amount of money with which he can buy M cans of energy drinks?\n\nIt is guaranteed that, in the given inputs, a sufficient amount of money can always buy M cans of energy drinks.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N, M \\leq 10^5\n\n1 \\leq A_i \\leq 10^9\n\n1 \\leq B_i \\leq 10^5\n\nB_1 + ... + B_N \\geq M\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 B_1\nA_2 B_2\n\\vdots\nA_N B_N\n\nOutput\n\nPrint the minimum amount of money with which Takahashi can buy M cans of energy drinks.\n\nSample Input 1\n\n2 5\n4 9\n2 4\n\nSample Output 1\n\n12\n\nWith 12 yen, we can buy one drink at the first store and four drinks at the second store, for the total of five drinks. However, we cannot buy 5 drinks with 11 yen or less.\n\nSample Input 2\n\n4 30\n6 18\n2 5\n3 10\n7 9\n\nSample Output 2\n\n130\n\nSample Input 3\n\n1 100000\n1000000000 100000\n\nSample Output 3\n\n100000000000000\n\nThe output may not fit into a 32-bit integer type.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 959, "cpu_time_ms": 26, "memory_kb": 1024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s460654755", "group_id": "codeNet:p03103", "input_text": "#include <stdio.h>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <iostream>\n#include <cmath>\nusing namespace std;\n\nstatic const long MAX = 1e5 + 3;\nint n, m, B[MAX];\nlong A[MAX], C[MAX][2], c, ans;\n\nlong h(long key, long i) {\n    long r = (key % MAX + i * (1 + key % (MAX - 1))) % MAX;\n    return r;\n}\n\nvoid insert(long key, long value) {\n    long i = 0;\n\n    while ( true ) {\n        if ( C[h(key, i)][0] == key ) {\n            break;\n        } else if ( C[h(key, i)][0] ) {\n            i++;\n        } else {\n            C[h(key, i)][0] = key;\n            C[h(key, i)][1] = value;\n            break;\n        }\n    }\n}\n\nlong find(long key) {\n    long i = 0;\n\n    while ( true ) {\n        if ( C[h(key, i)][0] == key ) {\n            return C[h(key, i)][1];\n            break;\n        } else if ( C[h(key, i)][0] ) {\n            i++;\n        } else {\n            return 0;\n            break;\n        }\n    }\n}\n\nint main() {\n    scanf(\"%d %d\", &n, &m);\n    \n    for ( int i = 0; i < n; i++ ) {\n        scanf(\"%ld %d\", &A[i], &B[i]);\n    }\n\n    for ( int i = 0; i < n; i++ ) {\n        scanf(\"%ld %d\", &A[i], &B[i]);\n        insert(A[i], B[i]);\n    }\n\n    c = 0;\n    ans = 0;\n\n    while ( m > 0 ) {\n        m -= find(c);\n        ans += c * find(c);\n        c++;\n    }\n\n    ans += (c - 1) * m;\n    printf(\"%ld\\n\", ans);\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1556883613, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03103.html", "problem_id": "p03103", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03103/input.txt", "sample_output_relpath": "derived/input_output/data/p03103/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03103/C++/s460654755.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s460654755", "user_id": "u177182853"}, "prompt_components": {"gold_output": "12\n", "input_to_evaluate": "#include <stdio.h>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <iostream>\n#include <cmath>\nusing namespace std;\n\nstatic const long MAX = 1e5 + 3;\nint n, m, B[MAX];\nlong A[MAX], C[MAX][2], c, ans;\n\nlong h(long key, long i) {\n    long r = (key % MAX + i * (1 + key % (MAX - 1))) % MAX;\n    return r;\n}\n\nvoid insert(long key, long value) {\n    long i = 0;\n\n    while ( true ) {\n        if ( C[h(key, i)][0] == key ) {\n            break;\n        } else if ( C[h(key, i)][0] ) {\n            i++;\n        } else {\n            C[h(key, i)][0] = key;\n            C[h(key, i)][1] = value;\n            break;\n        }\n    }\n}\n\nlong find(long key) {\n    long i = 0;\n\n    while ( true ) {\n        if ( C[h(key, i)][0] == key ) {\n            return C[h(key, i)][1];\n            break;\n        } else if ( C[h(key, i)][0] ) {\n            i++;\n        } else {\n            return 0;\n            break;\n        }\n    }\n}\n\nint main() {\n    scanf(\"%d %d\", &n, &m);\n    \n    for ( int i = 0; i < n; i++ ) {\n        scanf(\"%ld %d\", &A[i], &B[i]);\n    }\n\n    for ( int i = 0; i < n; i++ ) {\n        scanf(\"%ld %d\", &A[i], &B[i]);\n        insert(A[i], B[i]);\n    }\n\n    c = 0;\n    ans = 0;\n\n    while ( m > 0 ) {\n        m -= find(c);\n        ans += c * find(c);\n        c++;\n    }\n\n    ans += (c - 1) * m;\n    printf(\"%ld\\n\", ans);\n    return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nHearing that energy drinks increase rating in those sites, Takahashi decides to buy up M cans of energy drinks.\n\nThere are N stores that sell energy drinks. In the i-th store, he can buy at most B_i cans of energy drinks for A_i yen (the currency of Japan) each.\n\nWhat is the minimum amount of money with which he can buy M cans of energy drinks?\n\nIt is guaranteed that, in the given inputs, a sufficient amount of money can always buy M cans of energy drinks.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N, M \\leq 10^5\n\n1 \\leq A_i \\leq 10^9\n\n1 \\leq B_i \\leq 10^5\n\nB_1 + ... + B_N \\geq M\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 B_1\nA_2 B_2\n\\vdots\nA_N B_N\n\nOutput\n\nPrint the minimum amount of money with which Takahashi can buy M cans of energy drinks.\n\nSample Input 1\n\n2 5\n4 9\n2 4\n\nSample Output 1\n\n12\n\nWith 12 yen, we can buy one drink at the first store and four drinks at the second store, for the total of five drinks. However, we cannot buy 5 drinks with 11 yen or less.\n\nSample Input 2\n\n4 30\n6 18\n2 5\n3 10\n7 9\n\nSample Output 2\n\n130\n\nSample Input 3\n\n1 100000\n1000000000 100000\n\nSample Output 3\n\n100000000000000\n\nThe output may not fit into a 32-bit integer type.", "sample_input": "2 5\n4 9\n2 4\n"}, "reference_outputs": ["12\n"], "source_document_id": "p03103", "source_text": "Score : 300 points\n\nProblem Statement\n\nHearing that energy drinks increase rating in those sites, Takahashi decides to buy up M cans of energy drinks.\n\nThere are N stores that sell energy drinks. In the i-th store, he can buy at most B_i cans of energy drinks for A_i yen (the currency of Japan) each.\n\nWhat is the minimum amount of money with which he can buy M cans of energy drinks?\n\nIt is guaranteed that, in the given inputs, a sufficient amount of money can always buy M cans of energy drinks.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N, M \\leq 10^5\n\n1 \\leq A_i \\leq 10^9\n\n1 \\leq B_i \\leq 10^5\n\nB_1 + ... + B_N \\geq M\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 B_1\nA_2 B_2\n\\vdots\nA_N B_N\n\nOutput\n\nPrint the minimum amount of money with which Takahashi can buy M cans of energy drinks.\n\nSample Input 1\n\n2 5\n4 9\n2 4\n\nSample Output 1\n\n12\n\nWith 12 yen, we can buy one drink at the first store and four drinks at the second store, for the total of five drinks. However, we cannot buy 5 drinks with 11 yen or less.\n\nSample Input 2\n\n4 30\n6 18\n2 5\n3 10\n7 9\n\nSample Output 2\n\n130\n\nSample Input 3\n\n1 100000\n1000000000 100000\n\nSample Output 3\n\n100000000000000\n\nThe output may not fit into a 32-bit integer type.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1350, "cpu_time_ms": 2103, "memory_kb": 2944}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s178594487", "group_id": "codeNet:p03103", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\ntypedef pair<long long int, int> P;\nint n, m;\npriority_queue<P, vector<P>, greater<P>> que;\nint main()\n{\n    cin >> n >> m;\n    for (int i = 0; i < n; i++)\n    {\n        long long int x;\n        int y;\n        cin >> x >> y;\n        que.push(P(x, y));\n    }\n    long long int ans = 0;\n    while (m)\n    {\n        P p = que.top();\n        que.pop();\n        if (p.second > m)\n        {\n            ans += p.first * m;\n            m = 0;\n        }\n        else\n        {\n            ans += p.first * p.second;\n            m -= p.second;\n        }\n        cout << ans << endl;\n    }\n    return 0;\n}", "language": "C++", "metadata": {"date": 1552162537, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03103.html", "problem_id": "p03103", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03103/input.txt", "sample_output_relpath": "derived/input_output/data/p03103/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03103/C++/s178594487.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s178594487", "user_id": "u693953100"}, "prompt_components": {"gold_output": "12\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\ntypedef pair<long long int, int> P;\nint n, m;\npriority_queue<P, vector<P>, greater<P>> que;\nint main()\n{\n    cin >> n >> m;\n    for (int i = 0; i < n; i++)\n    {\n        long long int x;\n        int y;\n        cin >> x >> y;\n        que.push(P(x, y));\n    }\n    long long int ans = 0;\n    while (m)\n    {\n        P p = que.top();\n        que.pop();\n        if (p.second > m)\n        {\n            ans += p.first * m;\n            m = 0;\n        }\n        else\n        {\n            ans += p.first * p.second;\n            m -= p.second;\n        }\n        cout << ans << endl;\n    }\n    return 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nHearing that energy drinks increase rating in those sites, Takahashi decides to buy up M cans of energy drinks.\n\nThere are N stores that sell energy drinks. In the i-th store, he can buy at most B_i cans of energy drinks for A_i yen (the currency of Japan) each.\n\nWhat is the minimum amount of money with which he can buy M cans of energy drinks?\n\nIt is guaranteed that, in the given inputs, a sufficient amount of money can always buy M cans of energy drinks.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N, M \\leq 10^5\n\n1 \\leq A_i \\leq 10^9\n\n1 \\leq B_i \\leq 10^5\n\nB_1 + ... + B_N \\geq M\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 B_1\nA_2 B_2\n\\vdots\nA_N B_N\n\nOutput\n\nPrint the minimum amount of money with which Takahashi can buy M cans of energy drinks.\n\nSample Input 1\n\n2 5\n4 9\n2 4\n\nSample Output 1\n\n12\n\nWith 12 yen, we can buy one drink at the first store and four drinks at the second store, for the total of five drinks. However, we cannot buy 5 drinks with 11 yen or less.\n\nSample Input 2\n\n4 30\n6 18\n2 5\n3 10\n7 9\n\nSample Output 2\n\n130\n\nSample Input 3\n\n1 100000\n1000000000 100000\n\nSample Output 3\n\n100000000000000\n\nThe output may not fit into a 32-bit integer type.", "sample_input": "2 5\n4 9\n2 4\n"}, "reference_outputs": ["12\n"], "source_document_id": "p03103", "source_text": "Score : 300 points\n\nProblem Statement\n\nHearing that energy drinks increase rating in those sites, Takahashi decides to buy up M cans of energy drinks.\n\nThere are N stores that sell energy drinks. In the i-th store, he can buy at most B_i cans of energy drinks for A_i yen (the currency of Japan) each.\n\nWhat is the minimum amount of money with which he can buy M cans of energy drinks?\n\nIt is guaranteed that, in the given inputs, a sufficient amount of money can always buy M cans of energy drinks.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N, M \\leq 10^5\n\n1 \\leq A_i \\leq 10^9\n\n1 \\leq B_i \\leq 10^5\n\nB_1 + ... + B_N \\geq M\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 B_1\nA_2 B_2\n\\vdots\nA_N B_N\n\nOutput\n\nPrint the minimum amount of money with which Takahashi can buy M cans of energy drinks.\n\nSample Input 1\n\n2 5\n4 9\n2 4\n\nSample Output 1\n\n12\n\nWith 12 yen, we can buy one drink at the first store and four drinks at the second store, for the total of five drinks. However, we cannot buy 5 drinks with 11 yen or less.\n\nSample Input 2\n\n4 30\n6 18\n2 5\n3 10\n7 9\n\nSample Output 2\n\n130\n\nSample Input 3\n\n1 100000\n1000000000 100000\n\nSample Output 3\n\n100000000000000\n\nThe output may not fit into a 32-bit integer type.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 642, "cpu_time_ms": 231, "memory_kb": 3440}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s617291516", "group_id": "codeNet:p03107", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n  string S;\n  cin >> S;\n  int n = S.size();\n  int t=0;\n  int ans=0;\n  while(t==0){\n    t = 1;\n    for(int i=0;i<n-1;i++){\n      if(S[i]!=S[i+1]){\n        S.erase(i,2);\n        t = 0;\n        ans++;\n        ans++;\n        break;\n      }\n      n = S.size();\n    }\n  }\n  cout << ans << endl;\n}", "language": "C++", "metadata": {"date": 1599400704, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03107.html", "problem_id": "p03107", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03107/input.txt", "sample_output_relpath": "derived/input_output/data/p03107/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03107/C++/s617291516.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s617291516", "user_id": "u794933113"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n  string S;\n  cin >> S;\n  int n = S.size();\n  int t=0;\n  int ans=0;\n  while(t==0){\n    t = 1;\n    for(int i=0;i<n-1;i++){\n      if(S[i]!=S[i+1]){\n        S.erase(i,2);\n        t = 0;\n        ans++;\n        ans++;\n        break;\n      }\n      n = S.size();\n    }\n  }\n  cout << ans << endl;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N cubes stacked vertically on a desk.\n\nYou are given a string S of length N. The color of the i-th cube from the bottom is red if the i-th character in S is 0, and blue if that character is 1.\n\nYou can perform the following operation any number of times: choose a red cube and a blue cube that are adjacent, and remove them. Here, the cubes that were stacked on the removed cubes will fall down onto the object below them.\n\nAt most how many cubes can be removed?\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n|S| = N\n\nEach character in S is 0 or 1.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the maximum number of cubes that can be removed.\n\nSample Input 1\n\n0011\n\nSample Output 1\n\n4\n\nAll four cubes can be removed, by performing the operation as follows:\n\nRemove the second and third cubes from the bottom. Then, the fourth cube drops onto the first cube.\n\nRemove the first and second cubes from the bottom.\n\nSample Input 2\n\n11011010001011\n\nSample Output 2\n\n12\n\nSample Input 3\n\n0\n\nSample Output 3\n\n0", "sample_input": "0011\n"}, "reference_outputs": ["4\n"], "source_document_id": "p03107", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N cubes stacked vertically on a desk.\n\nYou are given a string S of length N. The color of the i-th cube from the bottom is red if the i-th character in S is 0, and blue if that character is 1.\n\nYou can perform the following operation any number of times: choose a red cube and a blue cube that are adjacent, and remove them. Here, the cubes that were stacked on the removed cubes will fall down onto the object below them.\n\nAt most how many cubes can be removed?\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n|S| = N\n\nEach character in S is 0 or 1.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the maximum number of cubes that can be removed.\n\nSample Input 1\n\n0011\n\nSample Output 1\n\n4\n\nAll four cubes can be removed, by performing the operation as follows:\n\nRemove the second and third cubes from the bottom. Then, the fourth cube drops onto the first cube.\n\nRemove the first and second cubes from the bottom.\n\nSample Input 2\n\n11011010001011\n\nSample Output 2\n\n12\n\nSample Input 3\n\n0\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 348, "cpu_time_ms": 2205, "memory_kb": 3696}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s353890402", "group_id": "codeNet:p03107", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n\n    string s;\n    cin >> s;\n\n    int ans = 0;\n    for (int i=0; i<s.size(); i++){\n        char lbuf = s.at(i), rbuf = s.at(min(i+1, (int)(s.size()-1))); \n\n        if (lbuf != rbuf){\n            s.at(min(i+1, (int)(s.size()-1))) = s.at(max(0, i-1));;\n            ans += 2;\n        }\n//        cout << i << endl;      // debug\n    }\n\n    cout << ans << endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1592687033, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03107.html", "problem_id": "p03107", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03107/input.txt", "sample_output_relpath": "derived/input_output/data/p03107/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03107/C++/s353890402.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s353890402", "user_id": "u118647609"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n\n    string s;\n    cin >> s;\n\n    int ans = 0;\n    for (int i=0; i<s.size(); i++){\n        char lbuf = s.at(i), rbuf = s.at(min(i+1, (int)(s.size()-1))); \n\n        if (lbuf != rbuf){\n            s.at(min(i+1, (int)(s.size()-1))) = s.at(max(0, i-1));;\n            ans += 2;\n        }\n//        cout << i << endl;      // debug\n    }\n\n    cout << ans << endl;\n    return 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N cubes stacked vertically on a desk.\n\nYou are given a string S of length N. The color of the i-th cube from the bottom is red if the i-th character in S is 0, and blue if that character is 1.\n\nYou can perform the following operation any number of times: choose a red cube and a blue cube that are adjacent, and remove them. Here, the cubes that were stacked on the removed cubes will fall down onto the object below them.\n\nAt most how many cubes can be removed?\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n|S| = N\n\nEach character in S is 0 or 1.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the maximum number of cubes that can be removed.\n\nSample Input 1\n\n0011\n\nSample Output 1\n\n4\n\nAll four cubes can be removed, by performing the operation as follows:\n\nRemove the second and third cubes from the bottom. Then, the fourth cube drops onto the first cube.\n\nRemove the first and second cubes from the bottom.\n\nSample Input 2\n\n11011010001011\n\nSample Output 2\n\n12\n\nSample Input 3\n\n0\n\nSample Output 3\n\n0", "sample_input": "0011\n"}, "reference_outputs": ["4\n"], "source_document_id": "p03107", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N cubes stacked vertically on a desk.\n\nYou are given a string S of length N. The color of the i-th cube from the bottom is red if the i-th character in S is 0, and blue if that character is 1.\n\nYou can perform the following operation any number of times: choose a red cube and a blue cube that are adjacent, and remove them. Here, the cubes that were stacked on the removed cubes will fall down onto the object below them.\n\nAt most how many cubes can be removed?\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n|S| = N\n\nEach character in S is 0 or 1.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the maximum number of cubes that can be removed.\n\nSample Input 1\n\n0011\n\nSample Output 1\n\n4\n\nAll four cubes can be removed, by performing the operation as follows:\n\nRemove the second and third cubes from the bottom. Then, the fourth cube drops onto the first cube.\n\nRemove the first and second cubes from the bottom.\n\nSample Input 2\n\n11011010001011\n\nSample Output 2\n\n12\n\nSample Input 3\n\n0\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 432, "cpu_time_ms": 12, "memory_kb": 3748}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s904606937", "group_id": "codeNet:p03107", "input_text": "#include <bits/stdc++.h>\n\ntypedef long long ll;\nusing namespace std;\n\nint main() {\n    string S;\n    cin >> S;\n    int a[2];\n    int len = S.length();\n    for (int i = 0; i < len; i++) {\n        a[S[i] - '0']++;\n    }\n    cout << min(a[0], a[1]) * 2 << endl;\n}", "language": "C++", "metadata": {"date": 1558042597, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03107.html", "problem_id": "p03107", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03107/input.txt", "sample_output_relpath": "derived/input_output/data/p03107/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03107/C++/s904606937.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s904606937", "user_id": "u761362252"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\ntypedef long long ll;\nusing namespace std;\n\nint main() {\n    string S;\n    cin >> S;\n    int a[2];\n    int len = S.length();\n    for (int i = 0; i < len; i++) {\n        a[S[i] - '0']++;\n    }\n    cout << min(a[0], a[1]) * 2 << endl;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N cubes stacked vertically on a desk.\n\nYou are given a string S of length N. The color of the i-th cube from the bottom is red if the i-th character in S is 0, and blue if that character is 1.\n\nYou can perform the following operation any number of times: choose a red cube and a blue cube that are adjacent, and remove them. Here, the cubes that were stacked on the removed cubes will fall down onto the object below them.\n\nAt most how many cubes can be removed?\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n|S| = N\n\nEach character in S is 0 or 1.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the maximum number of cubes that can be removed.\n\nSample Input 1\n\n0011\n\nSample Output 1\n\n4\n\nAll four cubes can be removed, by performing the operation as follows:\n\nRemove the second and third cubes from the bottom. Then, the fourth cube drops onto the first cube.\n\nRemove the first and second cubes from the bottom.\n\nSample Input 2\n\n11011010001011\n\nSample Output 2\n\n12\n\nSample Input 3\n\n0\n\nSample Output 3\n\n0", "sample_input": "0011\n"}, "reference_outputs": ["4\n"], "source_document_id": "p03107", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N cubes stacked vertically on a desk.\n\nYou are given a string S of length N. The color of the i-th cube from the bottom is red if the i-th character in S is 0, and blue if that character is 1.\n\nYou can perform the following operation any number of times: choose a red cube and a blue cube that are adjacent, and remove them. Here, the cubes that were stacked on the removed cubes will fall down onto the object below them.\n\nAt most how many cubes can be removed?\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n|S| = N\n\nEach character in S is 0 or 1.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the maximum number of cubes that can be removed.\n\nSample Input 1\n\n0011\n\nSample Output 1\n\n4\n\nAll four cubes can be removed, by performing the operation as follows:\n\nRemove the second and third cubes from the bottom. Then, the fourth cube drops onto the first cube.\n\nRemove the first and second cubes from the bottom.\n\nSample Input 2\n\n11011010001011\n\nSample Output 2\n\n12\n\nSample Input 3\n\n0\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 260, "cpu_time_ms": 5, "memory_kb": 512}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s826204630", "group_id": "codeNet:p03108", "input_text": "#include <iostream>\n#include <algorithm>\n#include <string>\n#include <string.h>\n#include <stdlib.h>\n#include <math.h>\n#include <vector>\n#include <queue>\n#include <stack>\n#include <cmath>\n#include <map>\n#include <iomanip>\n#include <set>\n#include <ctime>\n#include <tuple>\n#include <bitset>\n#include <assert.h>\n#include <deque>\nusing namespace std;\n\n/*\nusing PAIR = pair<string, int>;\nsort(sp.begin(), sp.end(), [](PAIR l, PAIR r){\n        return l.first<r.first || (l.first==r.first && l.second > r.second);\n        });\n*/\n\ntypedef long long ll;\n\n#define fi first\n#define se second\n#define rep(i, n) for (ll i = 0; i < n; i++)\n#define debugA() cerr << \"AAAAA\" << endl\n#define debug_() cerr << \"-------------\" << endl\n#define debug(x) cerr << #x << \": \" << x << endl\n#define debug_vec(v)                   \\\n    for (int i = 0; i < v.size(); i++) \\\n    {                                  \\\n        cout << v[i] << \" \";           \\\n    }                                  \\\n    cout << endl;\n#define debug_vec2(v)                         \\\n    for (int i = 0; i < v.size(); i++)        \\\n    {                                         \\\n        for (int j = 0; j < v[i].size(); j++) \\\n        {                                     \\\n            cout << v[i][j] << \" \";           \\\n        }                                     \\\n        cout << endl;                         \\\n    }\n\nusing Graph = vector<vector<int>>;\nusing P = pair<int, int>;\nusing P1 = pair<int, pair<int, int>>; // クラスカル法とかで、{cost, {from, to}}的に使う。\nconst int INF = 1001001001;\nconst double pi = acos(-1);\n\nclass UnionFind\n{\npublic:\n    // 親の番号を格納する。親だった場合は -(その集合のサイズ)とする。\n    vector<int> Parent;\n\n    // 作るときはParentの値を全て-1にする。\n    UnionFind(int N)\n    {\n        Parent = vector<int>(N, -1);\n    }\n\n    // Aがどのグループに所属しているか調べる。\n    int root(int A)\n    {\n        if (Parent[A] < 0)\n            return A;\n        return Parent[A] = root(Parent[A]);\n    }\n\n    // 自分のいる頂点の数をイラべる。\n    int size(int A)\n    {\n        return -Parent[root(A)]; // 親を取ってきたい。\n    }\n\n    // AとBをくっつける。\n    bool unite(int A, int B)\n    {\n        // root(A)をroot(B)にくっつける。\n        A = root(A);\n        B = root(B);\n        if (A == B)\n        {\n            return false;\n        }\n        // 大きい方(A)に小さい方(B)をくっつけたい。\n        // 大小が逆ならひっくり返す。\n        if (size(A) < size(B))\n        {\n            swap(A, B);\n        }\n\n        // Aのサイズを更新する。\n        Parent[A] += Parent[B];\n        // Bの親をAに変更する。\n        Parent[B] = A;\n        return true;\n    }\n};\n\nint main()\n{\n    int n, m;\n    cin >> n >> m;\n    vector<pair<int, int>> b(m);\n    for (int i = 0; i < m; i++)\n    {\n        int x, y;\n        cin >> x >> y;\n        x--;\n        y--;\n        b[i] = {x, y};\n    }\n    vector<ll> ans(m, 0);\n    UnionFind tree(n);\n    ans[m - 1] = n * (n - 1) / 2;\n    for (int i = 0; i < m - 1; i++)\n    {\n        int x = b[m - 1 - i].fi;\n        int y = b[m - 1 - i].se;\n        if (tree.root(x) == tree.root(y))\n        {\n            ans[m - 2 - i] = ans[m - 1 - i];\n        }\n        else\n        {\n            ans[m - 2 - i] = ans[m - 1 - i] - tree.size(x) * tree.size(y);\n            tree.unite(x, y);\n        }\n    }\n    for (int i = 0; i < m; i++)\n    {\n        cout << ans[i] << endl;\n    }\n\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1592100080, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03108.html", "problem_id": "p03108", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03108/input.txt", "sample_output_relpath": "derived/input_output/data/p03108/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03108/C++/s826204630.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s826204630", "user_id": "u275934251"}, "prompt_components": {"gold_output": "0\n0\n4\n5\n6\n", "input_to_evaluate": "#include <iostream>\n#include <algorithm>\n#include <string>\n#include <string.h>\n#include <stdlib.h>\n#include <math.h>\n#include <vector>\n#include <queue>\n#include <stack>\n#include <cmath>\n#include <map>\n#include <iomanip>\n#include <set>\n#include <ctime>\n#include <tuple>\n#include <bitset>\n#include <assert.h>\n#include <deque>\nusing namespace std;\n\n/*\nusing PAIR = pair<string, int>;\nsort(sp.begin(), sp.end(), [](PAIR l, PAIR r){\n        return l.first<r.first || (l.first==r.first && l.second > r.second);\n        });\n*/\n\ntypedef long long ll;\n\n#define fi first\n#define se second\n#define rep(i, n) for (ll i = 0; i < n; i++)\n#define debugA() cerr << \"AAAAA\" << endl\n#define debug_() cerr << \"-------------\" << endl\n#define debug(x) cerr << #x << \": \" << x << endl\n#define debug_vec(v)                   \\\n    for (int i = 0; i < v.size(); i++) \\\n    {                                  \\\n        cout << v[i] << \" \";           \\\n    }                                  \\\n    cout << endl;\n#define debug_vec2(v)                         \\\n    for (int i = 0; i < v.size(); i++)        \\\n    {                                         \\\n        for (int j = 0; j < v[i].size(); j++) \\\n        {                                     \\\n            cout << v[i][j] << \" \";           \\\n        }                                     \\\n        cout << endl;                         \\\n    }\n\nusing Graph = vector<vector<int>>;\nusing P = pair<int, int>;\nusing P1 = pair<int, pair<int, int>>; // クラスカル法とかで、{cost, {from, to}}的に使う。\nconst int INF = 1001001001;\nconst double pi = acos(-1);\n\nclass UnionFind\n{\npublic:\n    // 親の番号を格納する。親だった場合は -(その集合のサイズ)とする。\n    vector<int> Parent;\n\n    // 作るときはParentの値を全て-1にする。\n    UnionFind(int N)\n    {\n        Parent = vector<int>(N, -1);\n    }\n\n    // Aがどのグループに所属しているか調べる。\n    int root(int A)\n    {\n        if (Parent[A] < 0)\n            return A;\n        return Parent[A] = root(Parent[A]);\n    }\n\n    // 自分のいる頂点の数をイラべる。\n    int size(int A)\n    {\n        return -Parent[root(A)]; // 親を取ってきたい。\n    }\n\n    // AとBをくっつける。\n    bool unite(int A, int B)\n    {\n        // root(A)をroot(B)にくっつける。\n        A = root(A);\n        B = root(B);\n        if (A == B)\n        {\n            return false;\n        }\n        // 大きい方(A)に小さい方(B)をくっつけたい。\n        // 大小が逆ならひっくり返す。\n        if (size(A) < size(B))\n        {\n            swap(A, B);\n        }\n\n        // Aのサイズを更新する。\n        Parent[A] += Parent[B];\n        // Bの親をAに変更する。\n        Parent[B] = A;\n        return true;\n    }\n};\n\nint main()\n{\n    int n, m;\n    cin >> n >> m;\n    vector<pair<int, int>> b(m);\n    for (int i = 0; i < m; i++)\n    {\n        int x, y;\n        cin >> x >> y;\n        x--;\n        y--;\n        b[i] = {x, y};\n    }\n    vector<ll> ans(m, 0);\n    UnionFind tree(n);\n    ans[m - 1] = n * (n - 1) / 2;\n    for (int i = 0; i < m - 1; i++)\n    {\n        int x = b[m - 1 - i].fi;\n        int y = b[m - 1 - i].se;\n        if (tree.root(x) == tree.root(y))\n        {\n            ans[m - 2 - i] = ans[m - 1 - i];\n        }\n        else\n        {\n            ans[m - 2 - i] = ans[m - 1 - i] - tree.size(x) * tree.size(y);\n            tree.unite(x, y);\n        }\n    }\n    for (int i = 0; i < m; i++)\n    {\n        cout << ans[i] << endl;\n    }\n\n    return 0;\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nThere are N islands and M bridges.\n\nThe i-th bridge connects the A_i-th and B_i-th islands bidirectionally.\n\nInitially, we can travel between any two islands using some of these bridges.\n\nHowever, the results of a survey show that these bridges will all collapse because of aging, in the order from the first bridge to the M-th bridge.\n\nLet the inconvenience be the number of pairs of islands (a, b) (a < b) such that we are no longer able to travel between the a-th and b-th islands using some of the bridges remaining.\n\nFor each i (1 \\leq i \\leq M), find the inconvenience just after the i-th bridge collapses.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq A_i < B_i \\leq N\n\nAll pairs (A_i, B_i) are distinct.\n\nThe inconvenience is initially 0.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 B_1\nA_2 B_2\n\\vdots\nA_M B_M\n\nOutput\n\nIn the order i = 1, 2, ..., M, print the inconvenience just after the i-th bridge collapses.\nNote that the answer may not fit into a 32-bit integer type.\n\nSample Input 1\n\n4 5\n1 2\n3 4\n1 3\n2 3\n1 4\n\nSample Output 1\n\n0\n0\n4\n5\n6\n\nFor example, when the first to third bridges have collapsed, the inconvenience is 4 since we can no longer travel between the pairs (1, 2), (1, 3), (2, 4) and (3, 4).\n\nSample Input 2\n\n6 5\n2 3\n1 2\n5 6\n3 4\n4 5\n\nSample Output 2\n\n8\n9\n12\n14\n15\n\nSample Input 3\n\n2 1\n1 2\n\nSample Output 3\n\n1", "sample_input": "4 5\n1 2\n3 4\n1 3\n2 3\n1 4\n"}, "reference_outputs": ["0\n0\n4\n5\n6\n"], "source_document_id": "p03108", "source_text": "Score : 400 points\n\nProblem Statement\n\nThere are N islands and M bridges.\n\nThe i-th bridge connects the A_i-th and B_i-th islands bidirectionally.\n\nInitially, we can travel between any two islands using some of these bridges.\n\nHowever, the results of a survey show that these bridges will all collapse because of aging, in the order from the first bridge to the M-th bridge.\n\nLet the inconvenience be the number of pairs of islands (a, b) (a < b) such that we are no longer able to travel between the a-th and b-th islands using some of the bridges remaining.\n\nFor each i (1 \\leq i \\leq M), find the inconvenience just after the i-th bridge collapses.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq A_i < B_i \\leq N\n\nAll pairs (A_i, B_i) are distinct.\n\nThe inconvenience is initially 0.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 B_1\nA_2 B_2\n\\vdots\nA_M B_M\n\nOutput\n\nIn the order i = 1, 2, ..., M, print the inconvenience just after the i-th bridge collapses.\nNote that the answer may not fit into a 32-bit integer type.\n\nSample Input 1\n\n4 5\n1 2\n3 4\n1 3\n2 3\n1 4\n\nSample Output 1\n\n0\n0\n4\n5\n6\n\nFor example, when the first to third bridges have collapsed, the inconvenience is 4 since we can no longer travel between the pairs (1, 2), (1, 3), (2, 4) and (3, 4).\n\nSample Input 2\n\n6 5\n2 3\n1 2\n5 6\n3 4\n4 5\n\nSample Output 2\n\n8\n9\n12\n14\n15\n\nSample Input 3\n\n2 1\n1 2\n\nSample Output 3\n\n1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 3562, "cpu_time_ms": 214, "memory_kb": 3328}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s610142348", "group_id": "codeNet:p03111", "input_text": "/*\nURL_HERE\n*/\n/*\n\n*/\n#ifdef _WIN32\n#pragma warning(disable:4996)\n#endif\n#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#include <algorithm>\n#include <math.h>\n#include <unordered_map>\nusing namespace std;\n\nFILE* _fin = stdin;\nFILE* _fout = stdout;\n#define PI 3.141592653589793238462643383279502884197169399375105820974\n#define ten5p1 100001\n#define ten6p1 1000001\n#define ten8p1 100000001\n#define ten9p1 1000000001\n#define uint unsigned int\n#define ll long long\n#define ull unsigned long long\n#define rep(var,n) for(int var=0;var<n;++var)\n#define repi(n) rep(i,n)\n#define repj(n) rep(j,n)\n#define repi1(n) for(int i=1;i<n;++i)\n#define repj1(n) for(int j=1;j<n;++j)\nint _min(int a, int b) { return a <= b ? a : b; }\nint _min(ll a, ll b) { return a <= b ? a : b; }\nint _max(int a, int b) { return a >= b ? a : b; }\nint _max(ll a, ll b) { return a >= b ? a : b; }\nvoid zero(int* data, int n) { memset(data, 0, sizeof(int) * n); }\nvoid zero(ll* data, int n) { memset(data, 0, sizeof(ll) * n); }\nvoid zero(char* data, int n) { memset(data, 0, sizeof(char) * n); }\nchar readc() { char var; fscanf(_fin, \"%c\", &var); return var; }\nint readi() { int var; fscanf(_fin, \"%d\", &var); return var; }\ndouble readlf() { double var; fscanf(_fin, \"%lf\", &var); return var; }\nll readll() { ll var; fscanf(_fin, \"%lld\", &var); return var; }\nvoid repread(int* data, int n) { repi(n) data[i] = readi(); }\nvoid repread(ll* data, int n) { repi(n) data[i] = readll(); }\nint reads(char* str, int maxsize)\n{\n\tfor (;;) { if (fgets(str, maxsize, _fin) == NULL) break; if (str[0] != '\\n' && str[0] != '\\r') break; }\n\tint slen = strlen(str); if (slen == 0) return 0;\n\tif (str[slen - 1] == '\\n' || str[slen - 1] == '\\r') str[--slen] = 0;\n\treturn slen;\n}\n\n#define writec(var) fprintf(_fout,\"%c\",var)\n#define writecsp(var) fprintf(_fout,\"%c \",var)\n#define writecln(var) fprintf(_fout,\"%c\\n\",var)\n#define writei(var) fprintf(_fout,\"%d\",var)\n#define writeisp(var) fprintf(_fout,\"%d \",var)\n#define writellsp(var) fprintf(_fout,\"%lld \",var)\n#define writeiln(var) fprintf(_fout,\"%d\\n\",var)\n#define writellln(var) fprintf(_fout,\"%lld\\n\",var)\n#define writeulln(var) fprintf(_fout,\"%llu\\n\",var)\n#define writefln(var) fprintf(_fout,\"%f\\n\",var)\n#define writes(str) fprintf(_fout,\"%s\",str)\n#define writesp() fprintf(_fout,\" \")\n#define writeln() fprintf(_fout,\"\\n\")\n#define RUN_LOCAL(testfilename) {_fin = fopen(testfilename, \"r\"); if(_fin==NULL) _fin=stdin;}\n#define swap(type,a, b) {type t=a;a=b;b=t;}\n#define sort(data,n) std::sort(data,data+n)\n//#define mod(a,b) b==0 ? 0 : a==0 ? 0 :(a>0 ? a%b : b + a % b) //what the hell is this...\nll gcd(ll a, ll b) { if (b == 0) return a; return gcd(b, a % b); }\nll lcm(ll a, ll b) { ll g = gcd(a, b); return (a / g) * b; }\nvoid reverse(char* data, int n) { int k = n >> 1; repi(k) { char tmp = data[i]; data[i] = data[n - i - 1]; data[n - i - 1] = tmp; } }\nvoid reverse(int* data, int n) { int k = n >> 1; repi(k) { int tmp = data[i]; data[i] = data[n - i - 1]; data[n - i - 1] = tmp; } }\n\n#define _Vec(type, name) \\\nstruct name { type* data; int size; int n; };\\\nvoid init(name* t, int size) { t->data = (type*)malloc(sizeof(type) * size); t->size = size; t->n = 0; }\\\nvoid resize(name* t) { int ns = t->size * 1.2f; t->data = (type*)realloc(t->data, sizeof(type) * ns); t->size = ns; }\\\nvoid add(name* t, type val) { if (t->n >= t->size) resize(t); int k = t->n; t->data[k] = val; t->n = k + 1; }\\\nvoid free(name* t) { free(t->data);}\n_Vec(int, Veci)\n_Vec(long long, Vecll)\n_Vec(char*, Vecs)\n\n#define _ispal(type, name) int name(type* a, type* b, int n){repi(n){if (a[i] != b[n - i - 1]){return 0;}}return 1;}\n_ispal(int, ispali)\n_ispal(char, ispalc)\n\n#define _Pair(type, name) struct name{type x, y;}; \\\nint cmp_##name(const void* _a, const void* _b)\\\n{\\\n\tname* a = (name*)_a;name* b = (name*)_b;\\\n\tif (a->x < b->x) return -1;\\\n\telse\\\n\t{\\\n\t\tif (a->x == b->x)\\\n\t\t{\\\n\t\t\tif (a->y == b->y) return 0;\\\n\t\t\tif (a->y < b->y) return -1;\\\n\t\t\telse return 1;\\\n\t\t}\\\n\t\telse\\\n\t\t{\\\n\t\t\treturn 1;\\\n\t\t}\\\n\t}\\\n}\\\nvoid sort_##name(name* d, int n){qsort(d, n, sizeof(name), cmp_##name);}\n\t_Pair(int, Pairi)\n\n\tint cmp_Str(const void* _a, const void* _b) { char* a = *((char**)_a); char* b = *((char**)_b); return strcmp(a, b); }\nvoid sort_Str(char** str, int n) { qsort(str, n, sizeof(char*), cmp_Str); }\n\nll expmod(ll x, ll n, ll m) {\n\tll ans = 1;\n\tfor (; n;) {\n\t\tif (n & 1) ans = (ans * x) % m;\n\t\tx = (x * x) % m;\n\t\tn >>= 1;\n\t}\n\treturn ans;\n}\n\nll combmod(ll n, ll k, ll m) {\n\tll ret = 1;\n\tll div = 1;\n\tfor (ll i = 0; i < k; ++i) {\n\t\tret = (ret * (n - i) % m) % m;\n\t\tdiv = (div * (i + 1)) % m;\n\t}\n\tdiv = expmod(div, m - 2, m) % m;\n\treturn (ret * div) % m;\n}\n\nint next_perm(int* data, int n)\n{\n\t//find first i,i+1 where d[i]<d[i+1]\n\tint rootidx = -1;\n\tfor (int i = n - 2; i >= 0; --i)\n\t{\n\t\tif (data[i] < data[i + 1])\n\t\t{\n\t\t\trootidx = i;\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (rootidx == -1) return 0;\n\n\tint ceilingidx = rootidx + 1;\n\t//find smallest d[x] after d[rooti] where d[x]>d[rooti]\n\tfor (int i = rootidx + 2; i < n; ++i)\n\t{\n\t\tif (data[i] > data[rootidx] && data[i] < data[ceilingidx])\n\t\t{\n\t\t\tceilingidx = i;\n\t\t}\n\t}\n\n\tswap(int, data[rootidx], data[ceilingidx]);\n\tsort(&data[rootidx + 1], n - rootidx - 1);\n\treturn 1;\n}\nint count_digits(ll a)\n{\n\tint k = 0;\n\tfor (;;)\n\t{\n\t\tif (a == 0)break;\n\t\tk++;\n\t\ta /= 10;\n\t}\n\treturn k;\n}\n\n/*\nuse only when val EXISTS in data\n*/\nint bs_exists(int* data, int n, int val)\n{\n\tint left = 0;\n\tint right = n - 1;\n\tfor (; left < right;)\n\t{\n\t\tint mid = (left + right + 1) >> 1;\n\t\tif (data[mid] <= val) left = mid;\n\t\telse right = mid - 1;\n\t}\n\treturn right;\n}\n//------------------------------------------\n\n//------------\n\nvoid dfs(int* bestmana, int currentmana, int* l, int nl, int maxnl, int a, int b, int c,int tA,int tB,int tC)\n{\n\tif (nl == maxnl)\n\t{\n\t\t//gotta make sure at least 1 stick was added\n\t\tif (a == 0 || b == 0 || c == 0)return;\n\t\tint totalmanacost = abs(a - tA) + abs(b - tB) + abs(c - tC);//this makes it so that lengths match\n\t\ttotalmanacost += currentmana;\n\t\tif (totalmanacost < *bestmana)\n\t\t{\n\t\t\t*bestmana = totalmanacost;\n\t\t}\n\t\treturn;\n\t}\n\t\n\tdfs(bestmana, currentmana, l, nl + 1, maxnl, a , b, c, tA, tB, tC);//dont use stick\n\tdfs(bestmana, currentmana + 10, l, nl + 1, maxnl, a + l[nl], b, c, tA, tB, tC);//add stick to a\n\tdfs(bestmana, currentmana + 10, l, nl + 1, maxnl, a, b + l[nl], c, tA, tB, tC);//add stick to b\n\tdfs(bestmana, currentmana + 10, l, nl + 1, maxnl, a, b, c + l[nl], tA, tB, tC);//add stick to c\n}\n\nint main()\n{\n\t\n\tRUN_LOCAL(\"xxtop2_0.txt\");\n\tint n = readi();\n\tint a = readi();\n\tint b = readi();\n\tint c = readi();\n\tstatic int l[10];\n\trepread(l, n);\n\n\tint bestmana = 1e9;\n\tdfs(&bestmana, 0, l, 0, n, 0, 0, 0, a, b, c);\n\twriteiln(bestmana);//initial placement of sticks are not considered joining\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1597790174, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03111.html", "problem_id": "p03111", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03111/input.txt", "sample_output_relpath": "derived/input_output/data/p03111/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03111/C++/s610142348.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s610142348", "user_id": "u950002813"}, "prompt_components": {"gold_output": "23\n", "input_to_evaluate": "/*\nURL_HERE\n*/\n/*\n\n*/\n#ifdef _WIN32\n#pragma warning(disable:4996)\n#endif\n#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#include <algorithm>\n#include <math.h>\n#include <unordered_map>\nusing namespace std;\n\nFILE* _fin = stdin;\nFILE* _fout = stdout;\n#define PI 3.141592653589793238462643383279502884197169399375105820974\n#define ten5p1 100001\n#define ten6p1 1000001\n#define ten8p1 100000001\n#define ten9p1 1000000001\n#define uint unsigned int\n#define ll long long\n#define ull unsigned long long\n#define rep(var,n) for(int var=0;var<n;++var)\n#define repi(n) rep(i,n)\n#define repj(n) rep(j,n)\n#define repi1(n) for(int i=1;i<n;++i)\n#define repj1(n) for(int j=1;j<n;++j)\nint _min(int a, int b) { return a <= b ? a : b; }\nint _min(ll a, ll b) { return a <= b ? a : b; }\nint _max(int a, int b) { return a >= b ? a : b; }\nint _max(ll a, ll b) { return a >= b ? a : b; }\nvoid zero(int* data, int n) { memset(data, 0, sizeof(int) * n); }\nvoid zero(ll* data, int n) { memset(data, 0, sizeof(ll) * n); }\nvoid zero(char* data, int n) { memset(data, 0, sizeof(char) * n); }\nchar readc() { char var; fscanf(_fin, \"%c\", &var); return var; }\nint readi() { int var; fscanf(_fin, \"%d\", &var); return var; }\ndouble readlf() { double var; fscanf(_fin, \"%lf\", &var); return var; }\nll readll() { ll var; fscanf(_fin, \"%lld\", &var); return var; }\nvoid repread(int* data, int n) { repi(n) data[i] = readi(); }\nvoid repread(ll* data, int n) { repi(n) data[i] = readll(); }\nint reads(char* str, int maxsize)\n{\n\tfor (;;) { if (fgets(str, maxsize, _fin) == NULL) break; if (str[0] != '\\n' && str[0] != '\\r') break; }\n\tint slen = strlen(str); if (slen == 0) return 0;\n\tif (str[slen - 1] == '\\n' || str[slen - 1] == '\\r') str[--slen] = 0;\n\treturn slen;\n}\n\n#define writec(var) fprintf(_fout,\"%c\",var)\n#define writecsp(var) fprintf(_fout,\"%c \",var)\n#define writecln(var) fprintf(_fout,\"%c\\n\",var)\n#define writei(var) fprintf(_fout,\"%d\",var)\n#define writeisp(var) fprintf(_fout,\"%d \",var)\n#define writellsp(var) fprintf(_fout,\"%lld \",var)\n#define writeiln(var) fprintf(_fout,\"%d\\n\",var)\n#define writellln(var) fprintf(_fout,\"%lld\\n\",var)\n#define writeulln(var) fprintf(_fout,\"%llu\\n\",var)\n#define writefln(var) fprintf(_fout,\"%f\\n\",var)\n#define writes(str) fprintf(_fout,\"%s\",str)\n#define writesp() fprintf(_fout,\" \")\n#define writeln() fprintf(_fout,\"\\n\")\n#define RUN_LOCAL(testfilename) {_fin = fopen(testfilename, \"r\"); if(_fin==NULL) _fin=stdin;}\n#define swap(type,a, b) {type t=a;a=b;b=t;}\n#define sort(data,n) std::sort(data,data+n)\n//#define mod(a,b) b==0 ? 0 : a==0 ? 0 :(a>0 ? a%b : b + a % b) //what the hell is this...\nll gcd(ll a, ll b) { if (b == 0) return a; return gcd(b, a % b); }\nll lcm(ll a, ll b) { ll g = gcd(a, b); return (a / g) * b; }\nvoid reverse(char* data, int n) { int k = n >> 1; repi(k) { char tmp = data[i]; data[i] = data[n - i - 1]; data[n - i - 1] = tmp; } }\nvoid reverse(int* data, int n) { int k = n >> 1; repi(k) { int tmp = data[i]; data[i] = data[n - i - 1]; data[n - i - 1] = tmp; } }\n\n#define _Vec(type, name) \\\nstruct name { type* data; int size; int n; };\\\nvoid init(name* t, int size) { t->data = (type*)malloc(sizeof(type) * size); t->size = size; t->n = 0; }\\\nvoid resize(name* t) { int ns = t->size * 1.2f; t->data = (type*)realloc(t->data, sizeof(type) * ns); t->size = ns; }\\\nvoid add(name* t, type val) { if (t->n >= t->size) resize(t); int k = t->n; t->data[k] = val; t->n = k + 1; }\\\nvoid free(name* t) { free(t->data);}\n_Vec(int, Veci)\n_Vec(long long, Vecll)\n_Vec(char*, Vecs)\n\n#define _ispal(type, name) int name(type* a, type* b, int n){repi(n){if (a[i] != b[n - i - 1]){return 0;}}return 1;}\n_ispal(int, ispali)\n_ispal(char, ispalc)\n\n#define _Pair(type, name) struct name{type x, y;}; \\\nint cmp_##name(const void* _a, const void* _b)\\\n{\\\n\tname* a = (name*)_a;name* b = (name*)_b;\\\n\tif (a->x < b->x) return -1;\\\n\telse\\\n\t{\\\n\t\tif (a->x == b->x)\\\n\t\t{\\\n\t\t\tif (a->y == b->y) return 0;\\\n\t\t\tif (a->y < b->y) return -1;\\\n\t\t\telse return 1;\\\n\t\t}\\\n\t\telse\\\n\t\t{\\\n\t\t\treturn 1;\\\n\t\t}\\\n\t}\\\n}\\\nvoid sort_##name(name* d, int n){qsort(d, n, sizeof(name), cmp_##name);}\n\t_Pair(int, Pairi)\n\n\tint cmp_Str(const void* _a, const void* _b) { char* a = *((char**)_a); char* b = *((char**)_b); return strcmp(a, b); }\nvoid sort_Str(char** str, int n) { qsort(str, n, sizeof(char*), cmp_Str); }\n\nll expmod(ll x, ll n, ll m) {\n\tll ans = 1;\n\tfor (; n;) {\n\t\tif (n & 1) ans = (ans * x) % m;\n\t\tx = (x * x) % m;\n\t\tn >>= 1;\n\t}\n\treturn ans;\n}\n\nll combmod(ll n, ll k, ll m) {\n\tll ret = 1;\n\tll div = 1;\n\tfor (ll i = 0; i < k; ++i) {\n\t\tret = (ret * (n - i) % m) % m;\n\t\tdiv = (div * (i + 1)) % m;\n\t}\n\tdiv = expmod(div, m - 2, m) % m;\n\treturn (ret * div) % m;\n}\n\nint next_perm(int* data, int n)\n{\n\t//find first i,i+1 where d[i]<d[i+1]\n\tint rootidx = -1;\n\tfor (int i = n - 2; i >= 0; --i)\n\t{\n\t\tif (data[i] < data[i + 1])\n\t\t{\n\t\t\trootidx = i;\n\t\t\tbreak;\n\t\t}\n\t}\n\n\tif (rootidx == -1) return 0;\n\n\tint ceilingidx = rootidx + 1;\n\t//find smallest d[x] after d[rooti] where d[x]>d[rooti]\n\tfor (int i = rootidx + 2; i < n; ++i)\n\t{\n\t\tif (data[i] > data[rootidx] && data[i] < data[ceilingidx])\n\t\t{\n\t\t\tceilingidx = i;\n\t\t}\n\t}\n\n\tswap(int, data[rootidx], data[ceilingidx]);\n\tsort(&data[rootidx + 1], n - rootidx - 1);\n\treturn 1;\n}\nint count_digits(ll a)\n{\n\tint k = 0;\n\tfor (;;)\n\t{\n\t\tif (a == 0)break;\n\t\tk++;\n\t\ta /= 10;\n\t}\n\treturn k;\n}\n\n/*\nuse only when val EXISTS in data\n*/\nint bs_exists(int* data, int n, int val)\n{\n\tint left = 0;\n\tint right = n - 1;\n\tfor (; left < right;)\n\t{\n\t\tint mid = (left + right + 1) >> 1;\n\t\tif (data[mid] <= val) left = mid;\n\t\telse right = mid - 1;\n\t}\n\treturn right;\n}\n//------------------------------------------\n\n//------------\n\nvoid dfs(int* bestmana, int currentmana, int* l, int nl, int maxnl, int a, int b, int c,int tA,int tB,int tC)\n{\n\tif (nl == maxnl)\n\t{\n\t\t//gotta make sure at least 1 stick was added\n\t\tif (a == 0 || b == 0 || c == 0)return;\n\t\tint totalmanacost = abs(a - tA) + abs(b - tB) + abs(c - tC);//this makes it so that lengths match\n\t\ttotalmanacost += currentmana;\n\t\tif (totalmanacost < *bestmana)\n\t\t{\n\t\t\t*bestmana = totalmanacost;\n\t\t}\n\t\treturn;\n\t}\n\t\n\tdfs(bestmana, currentmana, l, nl + 1, maxnl, a , b, c, tA, tB, tC);//dont use stick\n\tdfs(bestmana, currentmana + 10, l, nl + 1, maxnl, a + l[nl], b, c, tA, tB, tC);//add stick to a\n\tdfs(bestmana, currentmana + 10, l, nl + 1, maxnl, a, b + l[nl], c, tA, tB, tC);//add stick to b\n\tdfs(bestmana, currentmana + 10, l, nl + 1, maxnl, a, b, c + l[nl], tA, tB, tC);//add stick to c\n}\n\nint main()\n{\n\t\n\tRUN_LOCAL(\"xxtop2_0.txt\");\n\tint n = readi();\n\tint a = readi();\n\tint b = readi();\n\tint c = readi();\n\tstatic int l[10];\n\trepread(l, n);\n\n\tint bestmana = 1e9;\n\tdfs(&bestmana, 0, l, 0, n, 0, 0, 0, a, b, c);\n\twriteiln(bestmana);//initial placement of sticks are not considered joining\n\treturn 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nYou have N bamboos. The lengths (in centimeters) of these are l_1, l_2, ..., l_N, respectively.\n\nYour objective is to use some of these bamboos (possibly all) to obtain three bamboos of length A, B, C. For that, you can use the following three kinds of magics any number:\n\nExtension Magic: Consumes 1 MP (magic point). Choose one bamboo and increase its length by 1.\n\nShortening Magic: Consumes 1 MP. Choose one bamboo of length at least 2 and decrease its length by 1.\n\nComposition Magic: Consumes 10 MP. Choose two bamboos and combine them into one bamboo. The length of this new bamboo is equal to the sum of the lengths of the two bamboos combined. (Afterwards, further magics can be used on this bamboo.)\n\nAt least how much MP is needed to achieve the objective?\n\nConstraints\n\n3 \\leq N \\leq 8\n\n1 \\leq C < B < A \\leq 1000\n\n1 \\leq l_i \\leq 1000\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN A B C\nl_1\nl_2\n:\nl_N\n\nOutput\n\nPrint the minimum amount of MP needed to achieve the objective.\n\nSample Input 1\n\n5 100 90 80\n98\n40\n30\n21\n80\n\nSample Output 1\n\n23\n\nWe are obtaining three bamboos of lengths 100, 90, 80 from five bamboos 98, 40, 30, 21, 80. We already have a bamboo of length 80, and we can obtain bamboos of lengths 100, 90 by using the magics as follows at the total cost of 23 MP, which is optimal.\n\nUse Extension Magic twice on the bamboo of length 98 to obtain a bamboo of length 100. (MP consumed: 2)\n\nUse Composition Magic on the bamboos of lengths 40, 30 to obtain a bamboo of length 70. (MP consumed: 10)\n\nUse Shortening Magic once on the bamboo of length 21 to obtain a bamboo of length 20. (MP consumed: 1)\n\nUse Composition Magic on the bamboo of length 70 obtained in step 2 and the bamboo of length 20 obtained in step 3 to obtain a bamboo of length 90. (MP consumed: 10)\n\nSample Input 2\n\n8 100 90 80\n100\n100\n90\n90\n90\n80\n80\n80\n\nSample Output 2\n\n0\n\nIf we already have all bamboos of the desired lengths, the amount of MP needed is 0. As seen here, we do not necessarily need to use all the bamboos.\n\nSample Input 3\n\n8 1000 800 100\n300\n333\n400\n444\n500\n555\n600\n666\n\nSample Output 3\n\n243", "sample_input": "5 100 90 80\n98\n40\n30\n21\n80\n"}, "reference_outputs": ["23\n"], "source_document_id": "p03111", "source_text": "Score : 300 points\n\nProblem Statement\n\nYou have N bamboos. The lengths (in centimeters) of these are l_1, l_2, ..., l_N, respectively.\n\nYour objective is to use some of these bamboos (possibly all) to obtain three bamboos of length A, B, C. For that, you can use the following three kinds of magics any number:\n\nExtension Magic: Consumes 1 MP (magic point). Choose one bamboo and increase its length by 1.\n\nShortening Magic: Consumes 1 MP. Choose one bamboo of length at least 2 and decrease its length by 1.\n\nComposition Magic: Consumes 10 MP. Choose two bamboos and combine them into one bamboo. The length of this new bamboo is equal to the sum of the lengths of the two bamboos combined. (Afterwards, further magics can be used on this bamboo.)\n\nAt least how much MP is needed to achieve the objective?\n\nConstraints\n\n3 \\leq N \\leq 8\n\n1 \\leq C < B < A \\leq 1000\n\n1 \\leq l_i \\leq 1000\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN A B C\nl_1\nl_2\n:\nl_N\n\nOutput\n\nPrint the minimum amount of MP needed to achieve the objective.\n\nSample Input 1\n\n5 100 90 80\n98\n40\n30\n21\n80\n\nSample Output 1\n\n23\n\nWe are obtaining three bamboos of lengths 100, 90, 80 from five bamboos 98, 40, 30, 21, 80. We already have a bamboo of length 80, and we can obtain bamboos of lengths 100, 90 by using the magics as follows at the total cost of 23 MP, which is optimal.\n\nUse Extension Magic twice on the bamboo of length 98 to obtain a bamboo of length 100. (MP consumed: 2)\n\nUse Composition Magic on the bamboos of lengths 40, 30 to obtain a bamboo of length 70. (MP consumed: 10)\n\nUse Shortening Magic once on the bamboo of length 21 to obtain a bamboo of length 20. (MP consumed: 1)\n\nUse Composition Magic on the bamboo of length 70 obtained in step 2 and the bamboo of length 20 obtained in step 3 to obtain a bamboo of length 90. (MP consumed: 10)\n\nSample Input 2\n\n8 100 90 80\n100\n100\n90\n90\n90\n80\n80\n80\n\nSample Output 2\n\n0\n\nIf we already have all bamboos of the desired lengths, the amount of MP needed is 0. As seen here, we do not necessarily need to use all the bamboos.\n\nSample Input 3\n\n8 1000 800 100\n300\n333\n400\n444\n500\n555\n600\n666\n\nSample Output 3\n\n243", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 6754, "cpu_time_ms": 6, "memory_kb": 1740}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s087940496", "group_id": "codeNet:p03113", "input_text": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint main() {\n\tint n, k, a[55], p = 99;\n\tcin >> n >> k;\n\tfor (int i = 0; i < n; i++)\n\t\tcin >> a[i];\n\tstringstream s;\n\tfor (int i = 0; i < k + 1; i++) {\n\t\tint m = 111, x;\n\t\tfor (int j = 0; j < n; j++)\n\t\t\tif (j != p && a[j] < m) m = a[x = j];\n\t\tif (!m) {\n\t\t\tcout << -1 << endl;\n\t\t\treturn 0;\n\t\t}\n\t\tfor (int j = 0; j < n; j++)\n\t\t\tif (j != p && j != x)\n\t\t\t\ts << j + 1 << ' ', a[j]--;\n\t\ts << x + 1 << ' ', a[x]--;\n\t\tp = x;\n\t}\n\tcout << n + (n - 1)*k << '\\n' << s.str() << endl;\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1550994573, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03113.html", "problem_id": "p03113", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03113/input.txt", "sample_output_relpath": "derived/input_output/data/p03113/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03113/C++/s087940496.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s087940496", "user_id": "u337381518"}, "prompt_components": {"gold_output": "7\n1 1 2 1 2 2 1\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint main() {\n\tint n, k, a[55], p = 99;\n\tcin >> n >> k;\n\tfor (int i = 0; i < n; i++)\n\t\tcin >> a[i];\n\tstringstream s;\n\tfor (int i = 0; i < k + 1; i++) {\n\t\tint m = 111, x;\n\t\tfor (int j = 0; j < n; j++)\n\t\t\tif (j != p && a[j] < m) m = a[x = j];\n\t\tif (!m) {\n\t\t\tcout << -1 << endl;\n\t\t\treturn 0;\n\t\t}\n\t\tfor (int j = 0; j < n; j++)\n\t\t\tif (j != p && j != x)\n\t\t\t\ts << j + 1 << ' ', a[j]--;\n\t\ts << x + 1 << ' ', a[x]--;\n\t\tp = x;\n\t}\n\tcout << n + (n - 1)*k << '\\n' << s.str() << endl;\n\treturn 0;\n}\n", "problem_context": "Score : 1000 points\n\nProblem Statement\n\nSnuke participated in a magic show.\n\nA magician prepared N identical-looking boxes.\nHe put a treasure in one of the boxes, closed the boxes, shuffled them, and numbered them 1 through N.\n\nSince the boxes are shuffled, now Snuke has no idea which box contains the treasure.\nSnuke wins the game if he opens a box containing the treasure.\nYou may think that if Snuke opens all boxes at once, he can always win the game.\nHowever, there are some tricks:\n\nSnuke must open the boxes one by one. After he opens a box and checks the content of the box, he must close the box before opening the next box.\n\nHe is only allowed to open Box i at most a_i times.\n\nThe magician may secretly move the treasure from a closed box to another closed box, using some magic trick.\nFor simplicity, assume that the magician never moves the treasure while Snuke is opening some box.\nHowever, he can move it at any other time (before Snuke opens the first box, or between he closes some box and opens the next box).\n\nThe magician can perform the magic trick at most K times.\n\nCan Snuke always win the game, regardless of the initial position of the treasure and the movements of the magician?\n\nConstraints\n\n2 \\leq N \\leq 50\n\n1 \\leq K \\leq 50\n\n1 \\leq a_i \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\na_1 a_2 \\cdots a_N\n\nOutput\n\nIf the answer is no, print a single -1.\n\nOtherwise, print one possible move of Snuke in the following format:\n\nQ\nx_1 x_2 \\cdots x_Q\n\nIt means that he opens boxes x_1, x_2, \\cdots, x_Q in this order.\n\nIn case there are multiple possible solutions, you can output any.\n\nSample Input 1\n\n2 1\n5 5\n\nSample Output 1\n\n7\n1 1 2 1 2 2 1\n\nIf Snuke opens the boxes 7 times in the order 1 \\rightarrow 1 \\rightarrow 2 \\rightarrow 1 \\rightarrow 2 \\rightarrow 2 \\rightarrow 1, he can always find the treasure regardless of its initial position and the movements of the magician.\n\nSample Input 2\n\n3 50\n5 10 15\n\nSample Output 2\n\n-1", "sample_input": "2 1\n5 5\n"}, "reference_outputs": ["7\n1 1 2 1 2 2 1\n"], "source_document_id": "p03113", "source_text": "Score : 1000 points\n\nProblem Statement\n\nSnuke participated in a magic show.\n\nA magician prepared N identical-looking boxes.\nHe put a treasure in one of the boxes, closed the boxes, shuffled them, and numbered them 1 through N.\n\nSince the boxes are shuffled, now Snuke has no idea which box contains the treasure.\nSnuke wins the game if he opens a box containing the treasure.\nYou may think that if Snuke opens all boxes at once, he can always win the game.\nHowever, there are some tricks:\n\nSnuke must open the boxes one by one. After he opens a box and checks the content of the box, he must close the box before opening the next box.\n\nHe is only allowed to open Box i at most a_i times.\n\nThe magician may secretly move the treasure from a closed box to another closed box, using some magic trick.\nFor simplicity, assume that the magician never moves the treasure while Snuke is opening some box.\nHowever, he can move it at any other time (before Snuke opens the first box, or between he closes some box and opens the next box).\n\nThe magician can perform the magic trick at most K times.\n\nCan Snuke always win the game, regardless of the initial position of the treasure and the movements of the magician?\n\nConstraints\n\n2 \\leq N \\leq 50\n\n1 \\leq K \\leq 50\n\n1 \\leq a_i \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\na_1 a_2 \\cdots a_N\n\nOutput\n\nIf the answer is no, print a single -1.\n\nOtherwise, print one possible move of Snuke in the following format:\n\nQ\nx_1 x_2 \\cdots x_Q\n\nIt means that he opens boxes x_1, x_2, \\cdots, x_Q in this order.\n\nIn case there are multiple possible solutions, you can output any.\n\nSample Input 1\n\n2 1\n5 5\n\nSample Output 1\n\n7\n1 1 2 1 2 2 1\n\nIf Snuke opens the boxes 7 times in the order 1 \\rightarrow 1 \\rightarrow 2 \\rightarrow 1 \\rightarrow 2 \\rightarrow 2 \\rightarrow 1, he can always find the treasure regardless of its initial position and the movements of the magician.\n\nSample Input 2\n\n3 50\n5 10 15\n\nSample Output 2\n\n-1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 531, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s658459847", "group_id": "codeNet:p03125", "input_text": "#include<iostream>\nusing namespace std;\nint main()\n{\n    // 整数の入力\n    int a,b;\n    cin >> a >> b;\n    int c;\n    if (b % a == 0){\n        c = a + b;\n    } else\n    {\n        c = b - a;\n    }\n    cout << c << endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1550371733, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03125.html", "problem_id": "p03125", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03125/input.txt", "sample_output_relpath": "derived/input_output/data/p03125/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03125/C++/s658459847.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s658459847", "user_id": "u934405210"}, "prompt_components": {"gold_output": "16\n", "input_to_evaluate": "#include<iostream>\nusing namespace std;\nint main()\n{\n    // 整数の入力\n    int a,b;\n    cin >> a >> b;\n    int c;\n    if (b % a == 0){\n        c = a + b;\n    } else\n    {\n        c = b - a;\n    }\n    cout << c << endl;\n    return 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nYou are given positive integers A and B.\n\nIf A is a divisor of B, print A + B; otherwise, print B - A.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq A \\leq B \\leq 20\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nIf A is a divisor of B, print A + B; otherwise, print B - A.\n\nSample Input 1\n\n4 12\n\nSample Output 1\n\n16\n\nAs 4 is a divisor of 12, 4 + 12 = 16 should be printed.\n\nSample Input 2\n\n8 20\n\nSample Output 2\n\n12\n\nSample Input 3\n\n1 1\n\nSample Output 3\n\n2\n\n1 is a divisor of 1.", "sample_input": "4 12\n"}, "reference_outputs": ["16\n"], "source_document_id": "p03125", "source_text": "Score : 100 points\n\nProblem Statement\n\nYou are given positive integers A and B.\n\nIf A is a divisor of B, print A + B; otherwise, print B - A.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq A \\leq B \\leq 20\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nIf A is a divisor of B, print A + B; otherwise, print B - A.\n\nSample Input 1\n\n4 12\n\nSample Output 1\n\n16\n\nAs 4 is a divisor of 12, 4 + 12 = 16 should be printed.\n\nSample Input 2\n\n8 20\n\nSample Output 2\n\n12\n\nSample Input 3\n\n1 1\n\nSample Output 3\n\n2\n\n1 is a divisor of 1.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 239, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s273368545", "group_id": "codeNet:p03126", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef unsigned long long ull;\n#define MOD 1000000007\n#define PI 3.141592653589793\nconst int INF = 100000000;\nint dx[] = {0,1,-1,0,1,-1,1,-1};\nint dy[] = {1,0,0,-1,1,-1,-1,1};\n\n\nint main(){\n    int n, m;\n    cin >> n >> m;\n    vector<int> v(m+1, 0);\n    for(int i = 0; i < n; i++){\n        int k;\n        cin >> k;\n        while(k--){\n            int a;\n            cin >> a;\n            v[a]++;\n        }\n    }\n    int ans = 0;\n    for(auto i: v)\n        if(i == n)\n            ans++;\n    cout << ans << endl;\n}\n", "language": "C++", "metadata": {"date": 1566618806, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03126.html", "problem_id": "p03126", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03126/input.txt", "sample_output_relpath": "derived/input_output/data/p03126/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03126/C++/s273368545.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s273368545", "user_id": "u874723578"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef unsigned long long ull;\n#define MOD 1000000007\n#define PI 3.141592653589793\nconst int INF = 100000000;\nint dx[] = {0,1,-1,0,1,-1,1,-1};\nint dy[] = {1,0,0,-1,1,-1,-1,1};\n\n\nint main(){\n    int n, m;\n    cin >> n >> m;\n    vector<int> v(m+1, 0);\n    for(int i = 0; i < n; i++){\n        int k;\n        cin >> k;\n        while(k--){\n            int a;\n            cin >> a;\n            v[a]++;\n        }\n    }\n    int ans = 0;\n    for(auto i: v)\n        if(i == n)\n            ans++;\n    cout << ans << endl;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nKatsusando loves omelette rice.\n\nBesides, he loves crème brûlée, tenderloin steak and so on, and believes that these foods are all loved by everyone.\n\nTo prove that hypothesis, he conducted a survey on M kinds of foods and asked N people whether they like these foods or not.\n\nThe i-th person answered that he/she only likes the A_{i1}-th, A_{i2}-th, ..., A_{iK_i}-th food.\n\nFind the number of the foods liked by all the N people.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N, M \\leq 30\n\n1 \\leq K_i \\leq M\n\n1 \\leq A_{ij} \\leq M\n\nFor each i (1 \\leq i \\leq N), A_{i1}, A_{i2}, ..., A_{iK_i} are distinct.\n\nConstraints\n\nInput is given from Standard Input in the following format:\n\nN M\nK_1 A_{11} A_{12} ... A_{1K_1}\nK_2 A_{21} A_{22} ... A_{2K_2}\n:\nK_N A_{N1} A_{N2} ... A_{NK_N}\n\nOutput\n\nPrint the number of the foods liked by all the N people.\n\nSample Input 1\n\n3 4\n2 1 3\n3 1 2 3\n2 3 2\n\nSample Output 1\n\n1\n\nAs only the third food is liked by all the three people, 1 should be printed.\n\nSample Input 2\n\n5 5\n4 2 3 4 5\n4 1 3 4 5\n4 1 2 4 5\n4 1 2 3 5\n4 1 2 3 4\n\nSample Output 2\n\n0\n\nKatsusando's hypothesis turned out to be wrong.\n\nSample Input 3\n\n1 30\n3 5 10 30\n\nSample Output 3\n\n3", "sample_input": "3 4\n2 1 3\n3 1 2 3\n2 3 2\n"}, "reference_outputs": ["1\n"], "source_document_id": "p03126", "source_text": "Score : 200 points\n\nProblem Statement\n\nKatsusando loves omelette rice.\n\nBesides, he loves crème brûlée, tenderloin steak and so on, and believes that these foods are all loved by everyone.\n\nTo prove that hypothesis, he conducted a survey on M kinds of foods and asked N people whether they like these foods or not.\n\nThe i-th person answered that he/she only likes the A_{i1}-th, A_{i2}-th, ..., A_{iK_i}-th food.\n\nFind the number of the foods liked by all the N people.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N, M \\leq 30\n\n1 \\leq K_i \\leq M\n\n1 \\leq A_{ij} \\leq M\n\nFor each i (1 \\leq i \\leq N), A_{i1}, A_{i2}, ..., A_{iK_i} are distinct.\n\nConstraints\n\nInput is given from Standard Input in the following format:\n\nN M\nK_1 A_{11} A_{12} ... A_{1K_1}\nK_2 A_{21} A_{22} ... A_{2K_2}\n:\nK_N A_{N1} A_{N2} ... A_{NK_N}\n\nOutput\n\nPrint the number of the foods liked by all the N people.\n\nSample Input 1\n\n3 4\n2 1 3\n3 1 2 3\n2 3 2\n\nSample Output 1\n\n1\n\nAs only the third food is liked by all the three people, 1 should be printed.\n\nSample Input 2\n\n5 5\n4 2 3 4 5\n4 1 3 4 5\n4 1 2 4 5\n4 1 2 3 5\n4 1 2 3 4\n\nSample Output 2\n\n0\n\nKatsusando's hypothesis turned out to be wrong.\n\nSample Input 3\n\n1 30\n3 5 10 30\n\nSample Output 3\n\n3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 582, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s277630044", "group_id": "codeNet:p03126", "input_text": "#include <stdlib.h>\n#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n\nint main() {\n    int a,b;\n    cin>>a>>b;\n    vector<int> vec(b,0);\n    rep(i,a){\n        int c;\n        cin>>c;\n        for(int j=0;j<c;j++){\n            int d;\n            cin>>d;\n            d--;\n            vec.at(d)++;\n    }\n    }\n\n    int count =0;\n    rep(i,b){\n        if(vec.at(i)==a){\n            count++;\n        }\n    }\n    cout<<count<<endl;\n}\n\n", "language": "C++", "metadata": {"date": 1566401125, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03126.html", "problem_id": "p03126", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03126/input.txt", "sample_output_relpath": "derived/input_output/data/p03126/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03126/C++/s277630044.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s277630044", "user_id": "u540741303"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <stdlib.h>\n#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n\nint main() {\n    int a,b;\n    cin>>a>>b;\n    vector<int> vec(b,0);\n    rep(i,a){\n        int c;\n        cin>>c;\n        for(int j=0;j<c;j++){\n            int d;\n            cin>>d;\n            d--;\n            vec.at(d)++;\n    }\n    }\n\n    int count =0;\n    rep(i,b){\n        if(vec.at(i)==a){\n            count++;\n        }\n    }\n    cout<<count<<endl;\n}\n\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nKatsusando loves omelette rice.\n\nBesides, he loves crème brûlée, tenderloin steak and so on, and believes that these foods are all loved by everyone.\n\nTo prove that hypothesis, he conducted a survey on M kinds of foods and asked N people whether they like these foods or not.\n\nThe i-th person answered that he/she only likes the A_{i1}-th, A_{i2}-th, ..., A_{iK_i}-th food.\n\nFind the number of the foods liked by all the N people.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N, M \\leq 30\n\n1 \\leq K_i \\leq M\n\n1 \\leq A_{ij} \\leq M\n\nFor each i (1 \\leq i \\leq N), A_{i1}, A_{i2}, ..., A_{iK_i} are distinct.\n\nConstraints\n\nInput is given from Standard Input in the following format:\n\nN M\nK_1 A_{11} A_{12} ... A_{1K_1}\nK_2 A_{21} A_{22} ... A_{2K_2}\n:\nK_N A_{N1} A_{N2} ... A_{NK_N}\n\nOutput\n\nPrint the number of the foods liked by all the N people.\n\nSample Input 1\n\n3 4\n2 1 3\n3 1 2 3\n2 3 2\n\nSample Output 1\n\n1\n\nAs only the third food is liked by all the three people, 1 should be printed.\n\nSample Input 2\n\n5 5\n4 2 3 4 5\n4 1 3 4 5\n4 1 2 4 5\n4 1 2 3 5\n4 1 2 3 4\n\nSample Output 2\n\n0\n\nKatsusando's hypothesis turned out to be wrong.\n\nSample Input 3\n\n1 30\n3 5 10 30\n\nSample Output 3\n\n3", "sample_input": "3 4\n2 1 3\n3 1 2 3\n2 3 2\n"}, "reference_outputs": ["1\n"], "source_document_id": "p03126", "source_text": "Score : 200 points\n\nProblem Statement\n\nKatsusando loves omelette rice.\n\nBesides, he loves crème brûlée, tenderloin steak and so on, and believes that these foods are all loved by everyone.\n\nTo prove that hypothesis, he conducted a survey on M kinds of foods and asked N people whether they like these foods or not.\n\nThe i-th person answered that he/she only likes the A_{i1}-th, A_{i2}-th, ..., A_{iK_i}-th food.\n\nFind the number of the foods liked by all the N people.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N, M \\leq 30\n\n1 \\leq K_i \\leq M\n\n1 \\leq A_{ij} \\leq M\n\nFor each i (1 \\leq i \\leq N), A_{i1}, A_{i2}, ..., A_{iK_i} are distinct.\n\nConstraints\n\nInput is given from Standard Input in the following format:\n\nN M\nK_1 A_{11} A_{12} ... A_{1K_1}\nK_2 A_{21} A_{22} ... A_{2K_2}\n:\nK_N A_{N1} A_{N2} ... A_{NK_N}\n\nOutput\n\nPrint the number of the foods liked by all the N people.\n\nSample Input 1\n\n3 4\n2 1 3\n3 1 2 3\n2 3 2\n\nSample Output 1\n\n1\n\nAs only the third food is liked by all the three people, 1 should be printed.\n\nSample Input 2\n\n5 5\n4 2 3 4 5\n4 1 3 4 5\n4 1 2 4 5\n4 1 2 3 5\n4 1 2 3 4\n\nSample Output 2\n\n0\n\nKatsusando's hypothesis turned out to be wrong.\n\nSample Input 3\n\n1 30\n3 5 10 30\n\nSample Output 3\n\n3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 477, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s425002537", "group_id": "codeNet:p03126", "input_text": "\n#include<iostream>\nusing namespace std;\n\nint main() {\n\tint N, M;\n\tint K[30];\n\tint A[30][30];\n\tint like[30];\n\tint ans = 0;\n\n\tfor (int i = 0; i < 30; i++) {\n\t\tlike[i] =0;\n\t\tfor (int j = 0; j < 30; j++) {\n\t\t\t//A[i][j] = false;\n\t\t}\n\t}\n\tcin >> N >> M;\n\tfor (int i = 0; i < N; i++) {\n\t\tcin >>K[i];\n\t\tfor (int j = 0; j < K[i]; j++) {\n\t\t\tcin >> A[i][j];\n\t\t}\n\t}\n\tfor (int i = 0; i < N; i++) {\n\t\tfor (int j = 0; j < K[i]; j++) {\n\t\t\tlike[A[i][j]]++;\n\t\t}\n\t}\n\t\n\tfor (int i = 0; i < M; i++) {\n\t\tif (like[i] == N) {\n\t\t\tans++;\n\t\t}\n\t}\n\n\tprintf(\"%d\", ans);\n}", "language": "C++", "metadata": {"date": 1550369796, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03126.html", "problem_id": "p03126", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03126/input.txt", "sample_output_relpath": "derived/input_output/data/p03126/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03126/C++/s425002537.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s425002537", "user_id": "u576167201"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "\n#include<iostream>\nusing namespace std;\n\nint main() {\n\tint N, M;\n\tint K[30];\n\tint A[30][30];\n\tint like[30];\n\tint ans = 0;\n\n\tfor (int i = 0; i < 30; i++) {\n\t\tlike[i] =0;\n\t\tfor (int j = 0; j < 30; j++) {\n\t\t\t//A[i][j] = false;\n\t\t}\n\t}\n\tcin >> N >> M;\n\tfor (int i = 0; i < N; i++) {\n\t\tcin >>K[i];\n\t\tfor (int j = 0; j < K[i]; j++) {\n\t\t\tcin >> A[i][j];\n\t\t}\n\t}\n\tfor (int i = 0; i < N; i++) {\n\t\tfor (int j = 0; j < K[i]; j++) {\n\t\t\tlike[A[i][j]]++;\n\t\t}\n\t}\n\t\n\tfor (int i = 0; i < M; i++) {\n\t\tif (like[i] == N) {\n\t\t\tans++;\n\t\t}\n\t}\n\n\tprintf(\"%d\", ans);\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nKatsusando loves omelette rice.\n\nBesides, he loves crème brûlée, tenderloin steak and so on, and believes that these foods are all loved by everyone.\n\nTo prove that hypothesis, he conducted a survey on M kinds of foods and asked N people whether they like these foods or not.\n\nThe i-th person answered that he/she only likes the A_{i1}-th, A_{i2}-th, ..., A_{iK_i}-th food.\n\nFind the number of the foods liked by all the N people.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N, M \\leq 30\n\n1 \\leq K_i \\leq M\n\n1 \\leq A_{ij} \\leq M\n\nFor each i (1 \\leq i \\leq N), A_{i1}, A_{i2}, ..., A_{iK_i} are distinct.\n\nConstraints\n\nInput is given from Standard Input in the following format:\n\nN M\nK_1 A_{11} A_{12} ... A_{1K_1}\nK_2 A_{21} A_{22} ... A_{2K_2}\n:\nK_N A_{N1} A_{N2} ... A_{NK_N}\n\nOutput\n\nPrint the number of the foods liked by all the N people.\n\nSample Input 1\n\n3 4\n2 1 3\n3 1 2 3\n2 3 2\n\nSample Output 1\n\n1\n\nAs only the third food is liked by all the three people, 1 should be printed.\n\nSample Input 2\n\n5 5\n4 2 3 4 5\n4 1 3 4 5\n4 1 2 4 5\n4 1 2 3 5\n4 1 2 3 4\n\nSample Output 2\n\n0\n\nKatsusando's hypothesis turned out to be wrong.\n\nSample Input 3\n\n1 30\n3 5 10 30\n\nSample Output 3\n\n3", "sample_input": "3 4\n2 1 3\n3 1 2 3\n2 3 2\n"}, "reference_outputs": ["1\n"], "source_document_id": "p03126", "source_text": "Score : 200 points\n\nProblem Statement\n\nKatsusando loves omelette rice.\n\nBesides, he loves crème brûlée, tenderloin steak and so on, and believes that these foods are all loved by everyone.\n\nTo prove that hypothesis, he conducted a survey on M kinds of foods and asked N people whether they like these foods or not.\n\nThe i-th person answered that he/she only likes the A_{i1}-th, A_{i2}-th, ..., A_{iK_i}-th food.\n\nFind the number of the foods liked by all the N people.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N, M \\leq 30\n\n1 \\leq K_i \\leq M\n\n1 \\leq A_{ij} \\leq M\n\nFor each i (1 \\leq i \\leq N), A_{i1}, A_{i2}, ..., A_{iK_i} are distinct.\n\nConstraints\n\nInput is given from Standard Input in the following format:\n\nN M\nK_1 A_{11} A_{12} ... A_{1K_1}\nK_2 A_{21} A_{22} ... A_{2K_2}\n:\nK_N A_{N1} A_{N2} ... A_{NK_N}\n\nOutput\n\nPrint the number of the foods liked by all the N people.\n\nSample Input 1\n\n3 4\n2 1 3\n3 1 2 3\n2 3 2\n\nSample Output 1\n\n1\n\nAs only the third food is liked by all the three people, 1 should be printed.\n\nSample Input 2\n\n5 5\n4 2 3 4 5\n4 1 3 4 5\n4 1 2 4 5\n4 1 2 3 5\n4 1 2 3 4\n\nSample Output 2\n\n0\n\nKatsusando's hypothesis turned out to be wrong.\n\nSample Input 3\n\n1 30\n3 5 10 30\n\nSample Output 3\n\n3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 541, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s014777282", "group_id": "codeNet:p03127", "input_text": "#include<bits/stdc++.h>\nusing ll = long long;\nusing namespace std;\n\nint main(){\n    int N;\n    cin >> N;\n    vector<int> A(N,0);\n\n    for(int i = 0; i < N; i++)\n    {\n        cin >> A[i];\n    }\n    \n    sort(A.begin(),A.end());\n\n    int Temp = 1000000001;\n    for(int i = 1; i < N; i++)\n    {\n        for(int j = 0; j < i; j++)\n        {\n            if (A[i] % A[j] == 1)\n            {\n                cout << 1 << endl;\n                return 0;\n            }\n            else if(A[i] % A[j] < Temp && A[i] % A[j] > 1)\n            {\n                Temp = A[i] % A[j];\n                A[i] = Temp;\n                sort(A.begin(),A.end());\n                i = 1;\n            }\n            \n        }\n    }\n    if(Temp<1000000001) cout << Temp << endl;\n    else cout << A[0] << endl;\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1554141171, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03127.html", "problem_id": "p03127", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03127/input.txt", "sample_output_relpath": "derived/input_output/data/p03127/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03127/C++/s014777282.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s014777282", "user_id": "u808593466"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing ll = long long;\nusing namespace std;\n\nint main(){\n    int N;\n    cin >> N;\n    vector<int> A(N,0);\n\n    for(int i = 0; i < N; i++)\n    {\n        cin >> A[i];\n    }\n    \n    sort(A.begin(),A.end());\n\n    int Temp = 1000000001;\n    for(int i = 1; i < N; i++)\n    {\n        for(int j = 0; j < i; j++)\n        {\n            if (A[i] % A[j] == 1)\n            {\n                cout << 1 << endl;\n                return 0;\n            }\n            else if(A[i] % A[j] < Temp && A[i] % A[j] > 1)\n            {\n                Temp = A[i] % A[j];\n                A[i] = Temp;\n                sort(A.begin(),A.end());\n                i = 1;\n            }\n            \n        }\n    }\n    if(Temp<1000000001) cout << Temp << endl;\n    else cout << A[0] << endl;\n    return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N monsters, numbered 1, 2, ..., N.\n\nInitially, the health of Monster i is A_i.\n\nBelow, a monster with at least 1 health is called alive.\n\nUntil there is only one alive monster, the following is repeated:\n\nA random alive monster attacks another random alive monster.\n\nAs a result, the health of the monster attacked is reduced by the amount equal to the current health of the monster attacking.\n\nFind the minimum possible final health of the last monster alive.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 10^5\n\n1 \\leq A_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the minimum possible final health of the last monster alive.\n\nSample Input 1\n\n4\n2 10 8 40\n\nSample Output 1\n\n2\n\nWhen only the first monster keeps on attacking, the final health of the last monster will be 2, which is minimum.\n\nSample Input 2\n\n4\n5 13 8 1000000000\n\nSample Output 2\n\n1\n\nSample Input 3\n\n3\n1000000000 1000000000 1000000000\n\nSample Output 3\n\n1000000000", "sample_input": "4\n2 10 8 40\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03127", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N monsters, numbered 1, 2, ..., N.\n\nInitially, the health of Monster i is A_i.\n\nBelow, a monster with at least 1 health is called alive.\n\nUntil there is only one alive monster, the following is repeated:\n\nA random alive monster attacks another random alive monster.\n\nAs a result, the health of the monster attacked is reduced by the amount equal to the current health of the monster attacking.\n\nFind the minimum possible final health of the last monster alive.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 10^5\n\n1 \\leq A_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the minimum possible final health of the last monster alive.\n\nSample Input 1\n\n4\n2 10 8 40\n\nSample Output 1\n\n2\n\nWhen only the first monster keeps on attacking, the final health of the last monster will be 2, which is minimum.\n\nSample Input 2\n\n4\n5 13 8 1000000000\n\nSample Output 2\n\n1\n\nSample Input 3\n\n3\n1000000000 1000000000 1000000000\n\nSample Output 3\n\n1000000000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 799, "cpu_time_ms": 2103, "memory_kb": 640}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s432144503", "group_id": "codeNet:p03128", "input_text": "#include<iostream>\n#include<vector>\n#include<sstream>\n#include<string>\n#include<numeric>\n#include <algorithm>\n#include<math.h>\n#include<cstdio>\n#include<string.h>\n#include<unistd.h>\n#include <array>\n#include <map>\n#include<stdio.h>\n#include<queue>\n#include<set>\n#include<tuple>\n#include <iomanip>\n#define ALL(a)  (a).begin(),(a).end()\nconst long long MOD = 1000000007;\n\n//いろんなstlの使い方　https://qiita.com/tukejonny/items/f4013547df761a0b3523\n//http://y-mazun.hatenablog.com/entry/20111202/1322840281\n\n\n\nusing namespace std;\nstruct point{\n    int x;\n    int y;\n\n};\n//https://ei1333.github.io/luzhiled/snippets/structure/union-find.html\ntemplate< typename T >\nstruct WeightedUnionFind {\n  vector< int > data;\n  vector< T > ws;\n\n  WeightedUnionFind() {}\n\n  WeightedUnionFind(int sz) : data(sz, -1), ws(sz) {}\n\n  int find(int k) {\n    if(data[k] < 0) return k;\n    auto par = find(data[k]);\n    ws[k] += ws[data[k]];\n    return data[k] = par;\n  }\n\n  T weight(int t) {\n    find(t);\n    return ws[t];\n  }\n\n  bool unite(int x, int y, T w) {\n    w += weight(x);\n    w -= weight(y);\n    x = find(x), y = find(y);\n    if(x == y) return false;\n    if(data[x] > data[y]) {\n      swap(x, y);\n      w *= -1;\n    }\n    data[x] += data[y];\n    data[y] = x;\n    ws[y] = w;\n    return true;\n  }\n\n  T diff(int x, int y) {\n    return weight(y) - weight(x);\n  }\n};\n\n\n\nlong long gcd(long long a, long long b)\n{\n    if(a>b){\n        return gcd(b,a);\n    }\n    return a == 0 ? b : gcd(b % a, a);\n}\nlong long lcm( long long m, long long n )\n{\n    // 引数に０がある場合は０を返す\n    if ( ( 0 == m ) || ( 0 == n ) )\n        return 0;\n\n    return ((m / gcd(m, n)) * n); // lcm = m * n / gcd(m,n)\n}//lcm\nint input(){\n    int x;\n    cin>>x;\n    return x;\n}\n\nint moji(char in)\n{\n    int ans = (int)in-(int)'a';\n    if((ans < 0) || (ans > 25)){\n        ans = 26;\n    }\n    return ans;\n}\nconst int VV=1;//場合に応じてVVの値のみ変更する必要あり\n//dijkstra(s)sがスタート地点でそこからの最短距離を配列dで表す。正の重みのみ使用可能\nint cost[VV][VV];\nint d[VV];\nbool used[VV];\nvoid dijkstra(int s){\n\n    fill(d,d+VV,100000);\n    fill(used,used+VV,false);\n    d[s]=0;\n    while(true){\n        cout<<\"Hello\"<<endl;\n        int v=-1;\n        for(int u=0;u<VV;u++){\n            if(!used[u]&&(v==-1||d[u]<d[v]))v=u;\n        }\n        if(v==-1)break;\n        used[v]=true;\n        for(int u=0;u<VV;u++){\n            d[u]=min(d[u],d[v]+cost[v][u]);\n        }\n    }\n\n}\n\nint compare_int(const void *a, const void *b)//qsort(quick sort利用時に使用)\n{\n    return *(int*)a - *(int*)b;\n}\n\nint binary_searchh(long long x,long long k[],int n){\n    int l=0;\n    int r=n;\n    while(r-l>=1){\n        int i=(l+r)/2;\n        if(k[i]==x)return i;\n        else if(k[i]<x)l=i+1;\n        else r=i;\n    }\n    return -1;\n}\n\nstruct File {\n    int aa;\n    int bb;\n\n    File(const int& aa, const int& bb)\n            : aa(aa), bb(bb) {}\n};\n\n/*bool operator<(const File& a, const File& b)\n{\n    // ファイル種別、ファイル名の順番で優先順位を付けて比較\n    return std::tie(a.aa, a.bb) < std::tie(b.aa, b.bb);\n}*/\n\nlong long kaijo(long long x){\n    long long l=10*10*10*10*10*10*10*10*10+7;\n    long long sum=1;\n    for(int i=x;i>0;i--){\n        sum*=i;\n        if(sum>l){\n            sum%=l;\n        }\n    }\n    return sum;\n}\n\n\ntemplate<class T>void chmin(T &a,T b){\n    if(a>b){\n        a=b;\n    }\n}\n\n//formerは前方のindex(自分自身を含んで良い)\ntemplate<class T>int former(const vector<T>&v,T x){\n    return upper_bound(v.begin(),v.end(),x)-v.begin()-1;\n}\n//latterは後方のindex(自分自身を含んで良い)\ntemplate<class T>int latter(const vector<T>&v,T x){\n    return lower_bound(v.begin(),v.end(),x)-v.begin();\n}\n\nstruct UnionFind{\n    //par[i]データiの属する木の親の番号。i==par[i]のときデータiは木の根ノードである\n    vector<int>par;\n    //sizes[i]:根ノードiの木に含まれるデータ数、iが根ノードでないときは無意味な値になる\n    vector<int>sizes;\n\n    UnionFind(int n):par(n),sizes(n,1){\n        //最初は全てのデータiがグループiに存在するものとして初期化\n        for(int i=0;i<n;i++){\n            par[i]=i;\n        }\n    }\n    //データxが属する木の根を得る\n    int find(int x){\n        if(x==par[x]){\n            return x;\n        }\n        return par[x]=find(par[x]);\n\n    }\n    //2つのデータx,yが属する木をマージする\n    void unite(int x,int y){\n        //データの根ノードを得る\n        x=find(x);\n        y=find(y);\n        //もしすでに同じ木に属しているならマージの必要はない\n        if(x==y){\n            return;\n        }\n        //xの木がyの木よりも大きくなるようにする\n        if(sizes[x]<sizes[y]){\n            swap(x,y);\n        }\n        //xがyの親になるように連結する\n        par[y]=x;\n        sizes[x]+=sizes[y];\n\n    }\n    //2つのデータx,yが属する木が同じならtrueを返す\n    bool same(int x,int y){\n        return find(x)==find(y);\n    }\n    //データxが含まれる木の大きさを返す\n    int size(int x){\n        return sizes[find(x)];\n    }\n\n};\n\n//クラスカル法\n//頂点a,bをつなぐコストcostの（無向）辺\nstruct Edge{\n    int a,b,cost;\n    //コストの大小で順序定義\n    bool operator<(const Edge& o)const{\n        return cost<o.cost;\n    }\n};\n//頂点数と辺集合の組として定義したグラフ\n/*struct Graph{\n    int n;//頂点数\n    vector<Edge>es;//辺集合\n    //クラスカル法で無向最小全域木のコストの和を計算する\n    //グラフが非連結の時は最小全域森のコストの和になる\n    //使い方http://dai1741.github.io/maximum-algo-2012/docs/minimum-spanning-tree/\n    int kruskal(){\n        //コストが小さい順にソーと\n        sort(es.begin(),es.end());\n        UnionFind uf(n);\n        int min_cost=0;\n        for(int ei=0;ei<es.size();ei++){\n            Edge& e=es[ei];\n            if(!uf.same(e.a,e.b)){\n                //その辺によって2つの木が連結される\n                min_cost+=e.cost;\n                uf.unite(e.a,e.b);\n\n            }\n        }\n        return min_cost;\n    }\n};*/\n//標準入力からグラフを読み込む\n/*Graph input_graph(){\n    Graph g;\n    int m;\n    cin>>g.n>>m;\n    for(int i=0;i<m;i++){\n        Edge e;\n        cin>>e.a>>e.b>>e.cost;\n        g.es.push_back(e);\n    }\n    return g;\n}*/\nlong long labs(long long x){\n    if(x<0){\n        return -x;\n    }\n    return x;\n}\n// a^n mod を計算する\nlong long modpow(long long a, long long n, long long mod) {\n    long long res = 1;\n    while (n > 0) {\n        if (n & 1) res = res * a % mod;\n        a = a * a % mod;\n        n >>= 1;\n    }\n    return res;\n}\n//indexを用いてvectorから要素削除\ntemplate<typename T>\nvoid remove(std::vector<T>& vector, unsigned int index)\n{\n    vector.erase(vector.begin() + index);\n}\n\nvoid modadd(long long &a,long long b){\n    a+=b;\n    if(a>=MOD){\n        a%=MOD;\n\n    }\n}\n\nconst int MAX = 2;\nlong long fac[MAX], finv[MAX], inv[MAX];\n\n// テーブルを作る前処理\nvoid COMinit() {\n    fac[0] = fac[1] = 1;\n    finv[0] = finv[1] = 1;\n    inv[1] = 1;\n    for (int i = 2; i < MAX; i++){\n        fac[i] = fac[i - 1] * i % MOD;\n        inv[i] = MOD - inv[MOD%i] * (MOD / i) % MOD;\n        finv[i] = finv[i - 1] * inv[i] % MOD;\n    }\n}\n\n// 二項係数計算\nlong long COM(int n, int k){\n    if (n < k) return 0;\n    if (n < 0 || k < 0) return 0;\n    return fac[n] * (finv[k] * finv[n - k] % MOD) % MOD;\n}\nusing Graph = vector<vector<int> >;\nint main(){\n    map<int,int>joken;\n    joken[1]=2;\n    joken[2]=5;\n    joken[3]=5;\n    joken[4]=4;\n    joken[5]=5;\n    joken[6]=6;\n    joken[7]=3;\n    joken[8]=7;\n    joken[9]=6;\n    int N,M;\n    cin>>N>>M;\n    map<int,string>riyo;\n    for(int i=0;i<M;i++){\n        int a;\n        cin>>a;\n        riyo[joken[a]]=to_string(a);\n    }\n    string dp[N+1];\n    string shoki=\"-\";\n    for(int i=0;i<N+1;i++){\n        dp[i]=shoki;\n    }\n    dp[0]=\"\";\n    for(int i=1;i<N+1;i++){\n        for(auto iter=riyo.begin();iter!=riyo.end();iter++){\n            if(i-iter->first>=0){\n                if(dp[i]==\"-\"){\n                    if(dp[i-iter->first]==\"-\"){\n                        continue;\n                    }else{\n                        dp[i]=dp[i-iter->first]+iter->second;\n                    }\n                    \n                }else{\n                    if(dp[i-iter->first]==\"-\"){\n                        continue;\n                    }else{\n                        if(dp[i].size()==(dp[i-iter->first]+iter->second).size()){\n                            dp[i]=max(dp[i],dp[i-iter->first]+iter->second);\n                        }else if(dp[i].size()<(dp[i-iter->first]+iter->second).size()){\n                            dp[i]=dp[i-iter->first]+iter->second;\n\n                        }\n                    }\n\n                }\n            }\n        }\n    }\n    cout<<dp[N]<<endl;\n    \n    \n    \n\n\n    \n\n\n\n}\n    \n\n\n\n\n\n\n\n\n\n\n\n\n", "language": "C++", "metadata": {"date": 1562340773, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03128.html", "problem_id": "p03128", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03128/input.txt", "sample_output_relpath": "derived/input_output/data/p03128/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03128/C++/s432144503.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s432144503", "user_id": "u334656323"}, "prompt_components": {"gold_output": "777773\n", "input_to_evaluate": "#include<iostream>\n#include<vector>\n#include<sstream>\n#include<string>\n#include<numeric>\n#include <algorithm>\n#include<math.h>\n#include<cstdio>\n#include<string.h>\n#include<unistd.h>\n#include <array>\n#include <map>\n#include<stdio.h>\n#include<queue>\n#include<set>\n#include<tuple>\n#include <iomanip>\n#define ALL(a)  (a).begin(),(a).end()\nconst long long MOD = 1000000007;\n\n//いろんなstlの使い方　https://qiita.com/tukejonny/items/f4013547df761a0b3523\n//http://y-mazun.hatenablog.com/entry/20111202/1322840281\n\n\n\nusing namespace std;\nstruct point{\n    int x;\n    int y;\n\n};\n//https://ei1333.github.io/luzhiled/snippets/structure/union-find.html\ntemplate< typename T >\nstruct WeightedUnionFind {\n  vector< int > data;\n  vector< T > ws;\n\n  WeightedUnionFind() {}\n\n  WeightedUnionFind(int sz) : data(sz, -1), ws(sz) {}\n\n  int find(int k) {\n    if(data[k] < 0) return k;\n    auto par = find(data[k]);\n    ws[k] += ws[data[k]];\n    return data[k] = par;\n  }\n\n  T weight(int t) {\n    find(t);\n    return ws[t];\n  }\n\n  bool unite(int x, int y, T w) {\n    w += weight(x);\n    w -= weight(y);\n    x = find(x), y = find(y);\n    if(x == y) return false;\n    if(data[x] > data[y]) {\n      swap(x, y);\n      w *= -1;\n    }\n    data[x] += data[y];\n    data[y] = x;\n    ws[y] = w;\n    return true;\n  }\n\n  T diff(int x, int y) {\n    return weight(y) - weight(x);\n  }\n};\n\n\n\nlong long gcd(long long a, long long b)\n{\n    if(a>b){\n        return gcd(b,a);\n    }\n    return a == 0 ? b : gcd(b % a, a);\n}\nlong long lcm( long long m, long long n )\n{\n    // 引数に０がある場合は０を返す\n    if ( ( 0 == m ) || ( 0 == n ) )\n        return 0;\n\n    return ((m / gcd(m, n)) * n); // lcm = m * n / gcd(m,n)\n}//lcm\nint input(){\n    int x;\n    cin>>x;\n    return x;\n}\n\nint moji(char in)\n{\n    int ans = (int)in-(int)'a';\n    if((ans < 0) || (ans > 25)){\n        ans = 26;\n    }\n    return ans;\n}\nconst int VV=1;//場合に応じてVVの値のみ変更する必要あり\n//dijkstra(s)sがスタート地点でそこからの最短距離を配列dで表す。正の重みのみ使用可能\nint cost[VV][VV];\nint d[VV];\nbool used[VV];\nvoid dijkstra(int s){\n\n    fill(d,d+VV,100000);\n    fill(used,used+VV,false);\n    d[s]=0;\n    while(true){\n        cout<<\"Hello\"<<endl;\n        int v=-1;\n        for(int u=0;u<VV;u++){\n            if(!used[u]&&(v==-1||d[u]<d[v]))v=u;\n        }\n        if(v==-1)break;\n        used[v]=true;\n        for(int u=0;u<VV;u++){\n            d[u]=min(d[u],d[v]+cost[v][u]);\n        }\n    }\n\n}\n\nint compare_int(const void *a, const void *b)//qsort(quick sort利用時に使用)\n{\n    return *(int*)a - *(int*)b;\n}\n\nint binary_searchh(long long x,long long k[],int n){\n    int l=0;\n    int r=n;\n    while(r-l>=1){\n        int i=(l+r)/2;\n        if(k[i]==x)return i;\n        else if(k[i]<x)l=i+1;\n        else r=i;\n    }\n    return -1;\n}\n\nstruct File {\n    int aa;\n    int bb;\n\n    File(const int& aa, const int& bb)\n            : aa(aa), bb(bb) {}\n};\n\n/*bool operator<(const File& a, const File& b)\n{\n    // ファイル種別、ファイル名の順番で優先順位を付けて比較\n    return std::tie(a.aa, a.bb) < std::tie(b.aa, b.bb);\n}*/\n\nlong long kaijo(long long x){\n    long long l=10*10*10*10*10*10*10*10*10+7;\n    long long sum=1;\n    for(int i=x;i>0;i--){\n        sum*=i;\n        if(sum>l){\n            sum%=l;\n        }\n    }\n    return sum;\n}\n\n\ntemplate<class T>void chmin(T &a,T b){\n    if(a>b){\n        a=b;\n    }\n}\n\n//formerは前方のindex(自分自身を含んで良い)\ntemplate<class T>int former(const vector<T>&v,T x){\n    return upper_bound(v.begin(),v.end(),x)-v.begin()-1;\n}\n//latterは後方のindex(自分自身を含んで良い)\ntemplate<class T>int latter(const vector<T>&v,T x){\n    return lower_bound(v.begin(),v.end(),x)-v.begin();\n}\n\nstruct UnionFind{\n    //par[i]データiの属する木の親の番号。i==par[i]のときデータiは木の根ノードである\n    vector<int>par;\n    //sizes[i]:根ノードiの木に含まれるデータ数、iが根ノードでないときは無意味な値になる\n    vector<int>sizes;\n\n    UnionFind(int n):par(n),sizes(n,1){\n        //最初は全てのデータiがグループiに存在するものとして初期化\n        for(int i=0;i<n;i++){\n            par[i]=i;\n        }\n    }\n    //データxが属する木の根を得る\n    int find(int x){\n        if(x==par[x]){\n            return x;\n        }\n        return par[x]=find(par[x]);\n\n    }\n    //2つのデータx,yが属する木をマージする\n    void unite(int x,int y){\n        //データの根ノードを得る\n        x=find(x);\n        y=find(y);\n        //もしすでに同じ木に属しているならマージの必要はない\n        if(x==y){\n            return;\n        }\n        //xの木がyの木よりも大きくなるようにする\n        if(sizes[x]<sizes[y]){\n            swap(x,y);\n        }\n        //xがyの親になるように連結する\n        par[y]=x;\n        sizes[x]+=sizes[y];\n\n    }\n    //2つのデータx,yが属する木が同じならtrueを返す\n    bool same(int x,int y){\n        return find(x)==find(y);\n    }\n    //データxが含まれる木の大きさを返す\n    int size(int x){\n        return sizes[find(x)];\n    }\n\n};\n\n//クラスカル法\n//頂点a,bをつなぐコストcostの（無向）辺\nstruct Edge{\n    int a,b,cost;\n    //コストの大小で順序定義\n    bool operator<(const Edge& o)const{\n        return cost<o.cost;\n    }\n};\n//頂点数と辺集合の組として定義したグラフ\n/*struct Graph{\n    int n;//頂点数\n    vector<Edge>es;//辺集合\n    //クラスカル法で無向最小全域木のコストの和を計算する\n    //グラフが非連結の時は最小全域森のコストの和になる\n    //使い方http://dai1741.github.io/maximum-algo-2012/docs/minimum-spanning-tree/\n    int kruskal(){\n        //コストが小さい順にソーと\n        sort(es.begin(),es.end());\n        UnionFind uf(n);\n        int min_cost=0;\n        for(int ei=0;ei<es.size();ei++){\n            Edge& e=es[ei];\n            if(!uf.same(e.a,e.b)){\n                //その辺によって2つの木が連結される\n                min_cost+=e.cost;\n                uf.unite(e.a,e.b);\n\n            }\n        }\n        return min_cost;\n    }\n};*/\n//標準入力からグラフを読み込む\n/*Graph input_graph(){\n    Graph g;\n    int m;\n    cin>>g.n>>m;\n    for(int i=0;i<m;i++){\n        Edge e;\n        cin>>e.a>>e.b>>e.cost;\n        g.es.push_back(e);\n    }\n    return g;\n}*/\nlong long labs(long long x){\n    if(x<0){\n        return -x;\n    }\n    return x;\n}\n// a^n mod を計算する\nlong long modpow(long long a, long long n, long long mod) {\n    long long res = 1;\n    while (n > 0) {\n        if (n & 1) res = res * a % mod;\n        a = a * a % mod;\n        n >>= 1;\n    }\n    return res;\n}\n//indexを用いてvectorから要素削除\ntemplate<typename T>\nvoid remove(std::vector<T>& vector, unsigned int index)\n{\n    vector.erase(vector.begin() + index);\n}\n\nvoid modadd(long long &a,long long b){\n    a+=b;\n    if(a>=MOD){\n        a%=MOD;\n\n    }\n}\n\nconst int MAX = 2;\nlong long fac[MAX], finv[MAX], inv[MAX];\n\n// テーブルを作る前処理\nvoid COMinit() {\n    fac[0] = fac[1] = 1;\n    finv[0] = finv[1] = 1;\n    inv[1] = 1;\n    for (int i = 2; i < MAX; i++){\n        fac[i] = fac[i - 1] * i % MOD;\n        inv[i] = MOD - inv[MOD%i] * (MOD / i) % MOD;\n        finv[i] = finv[i - 1] * inv[i] % MOD;\n    }\n}\n\n// 二項係数計算\nlong long COM(int n, int k){\n    if (n < k) return 0;\n    if (n < 0 || k < 0) return 0;\n    return fac[n] * (finv[k] * finv[n - k] % MOD) % MOD;\n}\nusing Graph = vector<vector<int> >;\nint main(){\n    map<int,int>joken;\n    joken[1]=2;\n    joken[2]=5;\n    joken[3]=5;\n    joken[4]=4;\n    joken[5]=5;\n    joken[6]=6;\n    joken[7]=3;\n    joken[8]=7;\n    joken[9]=6;\n    int N,M;\n    cin>>N>>M;\n    map<int,string>riyo;\n    for(int i=0;i<M;i++){\n        int a;\n        cin>>a;\n        riyo[joken[a]]=to_string(a);\n    }\n    string dp[N+1];\n    string shoki=\"-\";\n    for(int i=0;i<N+1;i++){\n        dp[i]=shoki;\n    }\n    dp[0]=\"\";\n    for(int i=1;i<N+1;i++){\n        for(auto iter=riyo.begin();iter!=riyo.end();iter++){\n            if(i-iter->first>=0){\n                if(dp[i]==\"-\"){\n                    if(dp[i-iter->first]==\"-\"){\n                        continue;\n                    }else{\n                        dp[i]=dp[i-iter->first]+iter->second;\n                    }\n                    \n                }else{\n                    if(dp[i-iter->first]==\"-\"){\n                        continue;\n                    }else{\n                        if(dp[i].size()==(dp[i-iter->first]+iter->second).size()){\n                            dp[i]=max(dp[i],dp[i-iter->first]+iter->second);\n                        }else if(dp[i].size()<(dp[i-iter->first]+iter->second).size()){\n                            dp[i]=dp[i-iter->first]+iter->second;\n\n                        }\n                    }\n\n                }\n            }\n        }\n    }\n    cout<<dp[N]<<endl;\n    \n    \n    \n\n\n    \n\n\n\n}\n    \n\n\n\n\n\n\n\n\n\n\n\n\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nFind the largest integer that can be formed with exactly N matchsticks, under the following conditions:\n\nEvery digit in the integer must be one of the digits A_1, A_2, ..., A_M (1 \\leq A_i \\leq 9).\n\nThe number of matchsticks used to form digits 1, 2, 3, 4, 5, 6, 7, 8, 9 should be 2, 5, 5, 4, 5, 6, 3, 7, 6, respectively.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 10^4\n\n1 \\leq M \\leq 9\n\n1 \\leq A_i \\leq 9\n\nA_i are all different.\n\nThere exists an integer that can be formed by exactly N matchsticks under the conditions.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 A_2 ... A_M\n\nOutput\n\nPrint the largest integer that can be formed with exactly N matchsticks under the conditions in the problem statement.\n\nSample Input 1\n\n20 4\n3 7 8 4\n\nSample Output 1\n\n777773\n\nThe integer 777773 can be formed with 3 + 3 + 3 + 3 + 3 + 5 = 20 matchsticks, and this is the largest integer that can be formed by 20 matchsticks under the conditions.\n\nSample Input 2\n\n101 9\n9 8 7 6 5 4 3 2 1\n\nSample Output 2\n\n71111111111111111111111111111111111111111111111111\n\nThe output may not fit into a 64-bit integer type.\n\nSample Input 3\n\n15 3\n5 4 6\n\nSample Output 3\n\n654", "sample_input": "20 4\n3 7 8 4\n"}, "reference_outputs": ["777773\n"], "source_document_id": "p03128", "source_text": "Score : 400 points\n\nProblem Statement\n\nFind the largest integer that can be formed with exactly N matchsticks, under the following conditions:\n\nEvery digit in the integer must be one of the digits A_1, A_2, ..., A_M (1 \\leq A_i \\leq 9).\n\nThe number of matchsticks used to form digits 1, 2, 3, 4, 5, 6, 7, 8, 9 should be 2, 5, 5, 4, 5, 6, 3, 7, 6, respectively.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 10^4\n\n1 \\leq M \\leq 9\n\n1 \\leq A_i \\leq 9\n\nA_i are all different.\n\nThere exists an integer that can be formed by exactly N matchsticks under the conditions.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 A_2 ... A_M\n\nOutput\n\nPrint the largest integer that can be formed with exactly N matchsticks under the conditions in the problem statement.\n\nSample Input 1\n\n20 4\n3 7 8 4\n\nSample Output 1\n\n777773\n\nThe integer 777773 can be formed with 3 + 3 + 3 + 3 + 3 + 5 = 20 matchsticks, and this is the largest integer that can be formed by 20 matchsticks under the conditions.\n\nSample Input 2\n\n101 9\n9 8 7 6 5 4 3 2 1\n\nSample Output 2\n\n71111111111111111111111111111111111111111111111111\n\nThe output may not fit into a 64-bit integer type.\n\nSample Input 3\n\n15 3\n5 4 6\n\nSample Output 3\n\n654", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 9097, "cpu_time_ms": 45, "memory_kb": 41472}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s200140967", "group_id": "codeNet:p03129", "input_text": "#include <cstdio>\n#include <algorithm>\nusing namespace std;\nint n,k;\nint abs(int x)\n{\n\treturn x>0?x:-x;\n} \nint main ()\n{\n\tscanf(\"%d%d\",&n,&k);\n\tif(abs(n)>=(k*2-1)) printf(\"YES\");\n\telse printf(\"NO\");\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1549764432, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03129.html", "problem_id": "p03129", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03129/input.txt", "sample_output_relpath": "derived/input_output/data/p03129/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03129/C++/s200140967.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s200140967", "user_id": "u041194459"}, "prompt_components": {"gold_output": "YES\n", "input_to_evaluate": "#include <cstdio>\n#include <algorithm>\nusing namespace std;\nint n,k;\nint abs(int x)\n{\n\treturn x>0?x:-x;\n} \nint main ()\n{\n\tscanf(\"%d%d\",&n,&k);\n\tif(abs(n)>=(k*2-1)) printf(\"YES\");\n\telse printf(\"NO\");\n\treturn 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nDetermine if we can choose K different integers between 1 and N (inclusive) so that no two of them differ by 1.\n\nConstraints\n\n1\\leq N,K\\leq 100\n\nN and K are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nIf we can choose K integers as above, print YES; otherwise, print NO.\n\nSample Input 1\n\n3 2\n\nSample Output 1\n\nYES\n\nWe can choose 1 and 3.\n\nSample Input 2\n\n5 5\n\nSample Output 2\n\nNO\n\nSample Input 3\n\n31 10\n\nSample Output 3\n\nYES\n\nSample Input 4\n\n10 90\n\nSample Output 4\n\nNO", "sample_input": "3 2\n"}, "reference_outputs": ["YES\n"], "source_document_id": "p03129", "source_text": "Score : 100 points\n\nProblem Statement\n\nDetermine if we can choose K different integers between 1 and N (inclusive) so that no two of them differ by 1.\n\nConstraints\n\n1\\leq N,K\\leq 100\n\nN and K are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nIf we can choose K integers as above, print YES; otherwise, print NO.\n\nSample Input 1\n\n3 2\n\nSample Output 1\n\nYES\n\nWe can choose 1 and 3.\n\nSample Input 2\n\n5 5\n\nSample Output 2\n\nNO\n\nSample Input 3\n\n31 10\n\nSample Output 3\n\nYES\n\nSample Input 4\n\n10 90\n\nSample Output 4\n\nNO", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 211, "cpu_time_ms": 1, "memory_kb": 128}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s911506588", "group_id": "codeNet:p03130", "input_text": "#include<iostream>\n#define loop(i,a,b) for(int i=a;i<b;i++)\n#define rep(i,a) loop(i,0,a)\nusing namespace std;\n\nint main(){\n\tint vertex[4];\n\tint a,b;\n\trep(i,4)vertex[i]=0;\n\trep(i,3){\n\t\tcin>>a>>b;\n\t\tvertex[a-1]++;\n\t\tvertex[b-1]++;\n\t}\n\tint even,odd;\n\teven=odd=0;\n\tbool check=true;\n\trep(i,4){\n\t\tif(vertex[i]%2)odd++;\n\t\telse even++;\n\t}\n\tif(even==2&&odd==2)cout<<\"YES\"<<endl;\n\telse cout<<\"NO\"<<endl;\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1549764975, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03130.html", "problem_id": "p03130", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03130/input.txt", "sample_output_relpath": "derived/input_output/data/p03130/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03130/C++/s911506588.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s911506588", "user_id": "u021140967"}, "prompt_components": {"gold_output": "YES\n", "input_to_evaluate": "#include<iostream>\n#define loop(i,a,b) for(int i=a;i<b;i++)\n#define rep(i,a) loop(i,0,a)\nusing namespace std;\n\nint main(){\n\tint vertex[4];\n\tint a,b;\n\trep(i,4)vertex[i]=0;\n\trep(i,3){\n\t\tcin>>a>>b;\n\t\tvertex[a-1]++;\n\t\tvertex[b-1]++;\n\t}\n\tint even,odd;\n\teven=odd=0;\n\tbool check=true;\n\trep(i,4){\n\t\tif(vertex[i]%2)odd++;\n\t\telse even++;\n\t}\n\tif(even==2&&odd==2)cout<<\"YES\"<<endl;\n\telse cout<<\"NO\"<<endl;\n\treturn 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nThere are four towns, numbered 1,2,3 and 4.\nAlso, there are three roads. The i-th road connects different towns a_i and b_i bidirectionally.\nNo two roads connect the same pair of towns. Other than these roads, there is no way to travel between these towns, but any town can be reached from any other town using these roads.\n\nDetermine if we can visit all the towns by traversing each of the roads exactly once.\n\nConstraints\n\n1 \\leq a_i,b_i \\leq 4(1\\leq i\\leq 3)\n\na_i and b_i are different. (1\\leq i\\leq 3)\n\nNo two roads connect the same pair of towns.\n\nAny town can be reached from any other town using the roads.\n\nInput\n\nInput is given from Standard Input in the following format:\n\na_1 b_1\na_2 b_2\na_3 b_3\n\nOutput\n\nIf we can visit all the towns by traversing each of the roads exactly once, print YES; otherwise, print NO.\n\nSample Input 1\n\n4 2\n1 3\n2 3\n\nSample Output 1\n\nYES\n\nWe can visit all the towns in the order 1,3,2,4.\n\nSample Input 2\n\n3 2\n2 4\n1 2\n\nSample Output 2\n\nNO\n\nSample Input 3\n\n2 1\n3 2\n4 3\n\nSample Output 3\n\nYES", "sample_input": "4 2\n1 3\n2 3\n"}, "reference_outputs": ["YES\n"], "source_document_id": "p03130", "source_text": "Score : 200 points\n\nProblem Statement\n\nThere are four towns, numbered 1,2,3 and 4.\nAlso, there are three roads. The i-th road connects different towns a_i and b_i bidirectionally.\nNo two roads connect the same pair of towns. Other than these roads, there is no way to travel between these towns, but any town can be reached from any other town using these roads.\n\nDetermine if we can visit all the towns by traversing each of the roads exactly once.\n\nConstraints\n\n1 \\leq a_i,b_i \\leq 4(1\\leq i\\leq 3)\n\na_i and b_i are different. (1\\leq i\\leq 3)\n\nNo two roads connect the same pair of towns.\n\nAny town can be reached from any other town using the roads.\n\nInput\n\nInput is given from Standard Input in the following format:\n\na_1 b_1\na_2 b_2\na_3 b_3\n\nOutput\n\nIf we can visit all the towns by traversing each of the roads exactly once, print YES; otherwise, print NO.\n\nSample Input 1\n\n4 2\n1 3\n2 3\n\nSample Output 1\n\nYES\n\nWe can visit all the towns in the order 1,3,2,4.\n\nSample Input 2\n\n3 2\n2 4\n1 2\n\nSample Output 2\n\nNO\n\nSample Input 3\n\n2 1\n3 2\n4 3\n\nSample Output 3\n\nYES", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 406, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s230415971", "group_id": "codeNet:p03137", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n\nint main() {\n    ll N, M;\n    cin >> N >> M;\n    vector<ll> X(M);\n    for (int i = 0; i < M; i++) {\n        cin >> X[i];\n    }\n\n    if (N >= M) cout << 0 << endl;\n    else {\n        sort(X.begin(), X.end());\n\n        vector<ll> dist(M-1);\n        for (int i = 0; i < M-1; i++) {\n            dist[i] = X[i+1]-X[i];\n        }\n\n        sort(dist.begin(), dist.end());\n\n        ll sum = 0;\n        for (int i = 0; i < M-N; i++) {\n            sum += dist[i];\n        }\n\n        cout << sum << endl;\n    }\n    \n    return 0;\n}", "language": "C++", "metadata": {"date": 1583271685, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03137.html", "problem_id": "p03137", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03137/input.txt", "sample_output_relpath": "derived/input_output/data/p03137/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03137/C++/s230415971.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s230415971", "user_id": "u241312295"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n\nint main() {\n    ll N, M;\n    cin >> N >> M;\n    vector<ll> X(M);\n    for (int i = 0; i < M; i++) {\n        cin >> X[i];\n    }\n\n    if (N >= M) cout << 0 << endl;\n    else {\n        sort(X.begin(), X.end());\n\n        vector<ll> dist(M-1);\n        for (int i = 0; i < M-1; i++) {\n            dist[i] = X[i+1]-X[i];\n        }\n\n        sort(dist.begin(), dist.end());\n\n        ll sum = 0;\n        for (int i = 0; i < M-N; i++) {\n            sum += dist[i];\n        }\n\n        cout << sum << endl;\n    }\n    \n    return 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nWe will play a one-player game using a number line and N pieces.\n\nFirst, we place each of these pieces at some integer coordinate.\n\nHere, multiple pieces can be placed at the same coordinate.\n\nOur objective is to visit all of the M coordinates X_1, X_2, ..., X_M with these pieces, by repeating the following move:\n\nMove: Choose a piece and let x be its coordinate. Put that piece at coordinate x+1 or x-1.\n\nNote that the coordinates where we initially place the pieces are already regarded as visited.\n\nFind the minimum number of moves required to achieve the objective.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n-10^5 \\leq X_i \\leq 10^5\n\nX_1, X_2, ..., X_M are all different.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nX_1 X_2 ... X_M\n\nOutput\n\nFind the minimum number of moves required to achieve the objective.\n\nSample Input 1\n\n2 5\n10 12 1 2 14\n\nSample Output 1\n\n5\n\nThe objective can be achieved in five moves as follows, and this is the minimum number of moves required.\n\nInitially, put the two pieces at coordinates 1 and 10.\n\nMove the piece at coordinate 1 to 2.\n\nMove the piece at coordinate 10 to 11.\n\nMove the piece at coordinate 11 to 12.\n\nMove the piece at coordinate 12 to 13.\n\nMove the piece at coordinate 13 to 14.\n\nSample Input 2\n\n3 7\n-10 -3 0 9 -100 2 17\n\nSample Output 2\n\n19\n\nSample Input 3\n\n100 1\n-100000\n\nSample Output 3\n\n0", "sample_input": "2 5\n10 12 1 2 14\n"}, "reference_outputs": ["5\n"], "source_document_id": "p03137", "source_text": "Score : 300 points\n\nProblem Statement\n\nWe will play a one-player game using a number line and N pieces.\n\nFirst, we place each of these pieces at some integer coordinate.\n\nHere, multiple pieces can be placed at the same coordinate.\n\nOur objective is to visit all of the M coordinates X_1, X_2, ..., X_M with these pieces, by repeating the following move:\n\nMove: Choose a piece and let x be its coordinate. Put that piece at coordinate x+1 or x-1.\n\nNote that the coordinates where we initially place the pieces are already regarded as visited.\n\nFind the minimum number of moves required to achieve the objective.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n-10^5 \\leq X_i \\leq 10^5\n\nX_1, X_2, ..., X_M are all different.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nX_1 X_2 ... X_M\n\nOutput\n\nFind the minimum number of moves required to achieve the objective.\n\nSample Input 1\n\n2 5\n10 12 1 2 14\n\nSample Output 1\n\n5\n\nThe objective can be achieved in five moves as follows, and this is the minimum number of moves required.\n\nInitially, put the two pieces at coordinates 1 and 10.\n\nMove the piece at coordinate 1 to 2.\n\nMove the piece at coordinate 10 to 11.\n\nMove the piece at coordinate 11 to 12.\n\nMove the piece at coordinate 12 to 13.\n\nMove the piece at coordinate 13 to 14.\n\nSample Input 2\n\n3 7\n-10 -3 0 9 -100 2 17\n\nSample Output 2\n\n19\n\nSample Input 3\n\n100 1\n-100000\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 589, "cpu_time_ms": 40, "memory_kb": 1792}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s569663146", "group_id": "codeNet:p03137", "input_text": "#include <bits/stdc++.h>\n#include <numeric>\ntypedef long long ll;\n#define rep(i,a,b) for(int i=a;i<b;++i)\n#define rrep(i,a,b) for(int i=a;i>=b;--i)\nusing namespace std;\n\nint main() {\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n\n    int N, M; cin >> N >> M;\n    if (N >= M) {\n        cout << 0 << \"\\n\";\n        return 0;\n    }\n\n    vector<int> X(M);\n    rep(i, 0, M) cin >> X[i];\n    sort(X.begin(), X.end());\n\n    vector<int> intervals(M-1);\n    rep(i, 0, M-1) intervals[i] = X[i+1] - X[i];\n    sort(intervals.begin(), intervals.end(), greater<int>());\n\n    int res = X.back() - X.front();\n    rep(i, 0, N-1) res -= intervals[i];\n\n    cout << res << \"\\n\";\n}", "language": "C++", "metadata": {"date": 1557902848, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03137.html", "problem_id": "p03137", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03137/input.txt", "sample_output_relpath": "derived/input_output/data/p03137/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03137/C++/s569663146.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s569663146", "user_id": "u980078875"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#include <numeric>\ntypedef long long ll;\n#define rep(i,a,b) for(int i=a;i<b;++i)\n#define rrep(i,a,b) for(int i=a;i>=b;--i)\nusing namespace std;\n\nint main() {\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n\n    int N, M; cin >> N >> M;\n    if (N >= M) {\n        cout << 0 << \"\\n\";\n        return 0;\n    }\n\n    vector<int> X(M);\n    rep(i, 0, M) cin >> X[i];\n    sort(X.begin(), X.end());\n\n    vector<int> intervals(M-1);\n    rep(i, 0, M-1) intervals[i] = X[i+1] - X[i];\n    sort(intervals.begin(), intervals.end(), greater<int>());\n\n    int res = X.back() - X.front();\n    rep(i, 0, N-1) res -= intervals[i];\n\n    cout << res << \"\\n\";\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nWe will play a one-player game using a number line and N pieces.\n\nFirst, we place each of these pieces at some integer coordinate.\n\nHere, multiple pieces can be placed at the same coordinate.\n\nOur objective is to visit all of the M coordinates X_1, X_2, ..., X_M with these pieces, by repeating the following move:\n\nMove: Choose a piece and let x be its coordinate. Put that piece at coordinate x+1 or x-1.\n\nNote that the coordinates where we initially place the pieces are already regarded as visited.\n\nFind the minimum number of moves required to achieve the objective.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n-10^5 \\leq X_i \\leq 10^5\n\nX_1, X_2, ..., X_M are all different.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nX_1 X_2 ... X_M\n\nOutput\n\nFind the minimum number of moves required to achieve the objective.\n\nSample Input 1\n\n2 5\n10 12 1 2 14\n\nSample Output 1\n\n5\n\nThe objective can be achieved in five moves as follows, and this is the minimum number of moves required.\n\nInitially, put the two pieces at coordinates 1 and 10.\n\nMove the piece at coordinate 1 to 2.\n\nMove the piece at coordinate 10 to 11.\n\nMove the piece at coordinate 11 to 12.\n\nMove the piece at coordinate 12 to 13.\n\nMove the piece at coordinate 13 to 14.\n\nSample Input 2\n\n3 7\n-10 -3 0 9 -100 2 17\n\nSample Output 2\n\n19\n\nSample Input 3\n\n100 1\n-100000\n\nSample Output 3\n\n0", "sample_input": "2 5\n10 12 1 2 14\n"}, "reference_outputs": ["5\n"], "source_document_id": "p03137", "source_text": "Score : 300 points\n\nProblem Statement\n\nWe will play a one-player game using a number line and N pieces.\n\nFirst, we place each of these pieces at some integer coordinate.\n\nHere, multiple pieces can be placed at the same coordinate.\n\nOur objective is to visit all of the M coordinates X_1, X_2, ..., X_M with these pieces, by repeating the following move:\n\nMove: Choose a piece and let x be its coordinate. Put that piece at coordinate x+1 or x-1.\n\nNote that the coordinates where we initially place the pieces are already regarded as visited.\n\nFind the minimum number of moves required to achieve the objective.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n-10^5 \\leq X_i \\leq 10^5\n\nX_1, X_2, ..., X_M are all different.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nX_1 X_2 ... X_M\n\nOutput\n\nFind the minimum number of moves required to achieve the objective.\n\nSample Input 1\n\n2 5\n10 12 1 2 14\n\nSample Output 1\n\n5\n\nThe objective can be achieved in five moves as follows, and this is the minimum number of moves required.\n\nInitially, put the two pieces at coordinates 1 and 10.\n\nMove the piece at coordinate 1 to 2.\n\nMove the piece at coordinate 10 to 11.\n\nMove the piece at coordinate 11 to 12.\n\nMove the piece at coordinate 12 to 13.\n\nMove the piece at coordinate 13 to 14.\n\nSample Input 2\n\n3 7\n-10 -3 0 9 -100 2 17\n\nSample Output 2\n\n19\n\nSample Input 3\n\n100 1\n-100000\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 662, "cpu_time_ms": 18, "memory_kb": 1024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s874905238", "group_id": "codeNet:p03142", "input_text": "#include<iostream>\n#include<cstdio>\n#include<cstring>\n#include<cstdlib>\n#include<iomanip>\n#include<vector>\n#include<queue>\n#include<deque>\n#include<string>\n#include<utility>\n#include<cmath>\n#include<algorithm>\n#include<cctype>\n#include<set>\n#include<map>\n#include<bitset>\n#include<stack>\n#include<ctime>\n#include<cassert>\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef pair<int,int> pii;\ntypedef pair<ll,int> pli;\ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\ntypedef vector<pii> vpii;\ntypedef vector<pli> vpli;\n\ninline ll read(){\n    ll Hashimoto=0;\n\tbool Kanna=1;\n    char I_Love=getchar();\n    while(I_Love<'0'||I_Love>'9'){\n        if(I_Love=='-')Kanna=0;\n        I_Love=getchar();\n    }\n    while(I_Love>='0'&&I_Love<='9'){\n        Hashimoto=Hashimoto*10+I_Love-'0';\n        I_Love=getchar();\n    }\n    return (Kanna?Hashimoto:-Hashimoto);\n}\ntemplate<typename T1,typename T2> inline void Umax(T1 &a,T2 b){\n\tif(a<b)a=b;\n}\ntemplate<typename T1,typename T2> inline void Umin(T1 &a,T2 b){\n\tif(a>b)a=b;\n}\n\n#define I_Love_Hashimoto_Kanna main\n#define fastio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);\n#define filein(s) freopen(s,\"r\",stdin);\n#define fileout(s) freopen(s,\"w\",stdout);\n#define file freopen(\"I_Love_Hashimoto_Kanna.out\",\"w\",stdout);\n#define RE cout<<\"I_Love_Hashimoto_Kanna\"<<endl;\n#define Tone(Kanna) cout<<Kanna<<endl;\n#define Tall(Hashimoto,Kanna) for(int I_Love=0;I_Love<(Kanna);++I_Love)cout<<Hashimoto[I_Love]<<(I_Love==(Kanna)-1?\"\\n\":\" \");\n#define FOR(I_Love,Hashimoto,Kanna) for(int I_Love=Hashimoto;I_Love<(Kanna);++I_Love)\n#define MP(Hashimoto,Kanna) make_pair(Hashimoto,Kanna)\n#define REV(Kanna) reverse(Kanna.begin(),Kanna.end());\n#define SORT(Kanna) sort(Kanna.begin(),Kanna.end());\n#define UNIQUE(Kanna) Kanna.erase(unique(Kanna.begin(),Kanna.end()),Kanna.end());\n#define inf (1000000000)\n#define linf (1000000000000000000ll)\n#define mod (1000000007)\n\nint n,m;\nint indegree[111111];\nvi g[111111];\nqueue<int>q;\nbool v[111111];\nint ans[111111];\n\nint I_Love_Hashimoto_Kanna() {\n\t//完全想清楚了再开始写。\n\t//写不顺、不知道怎么写、很乱的时候，停下来好好想想。\n\t//做得慢总比做不出好。\n\tfastio;\n\tn=read();m=read();\n\tFOR(i,1,n+m){\n\t\tint a=read()-1,b=read()-1;\n\t\tg[a].push_back(b);\n\t\tindegree[b]++;\n\t}\n\tint root=-1;\n\tFOR(i,0,n){\n\t\tif(indegree[i]==0)root=i;\n\t}\n\tassert(root!=-1);\n\tans[root]=-1;\n\tv[root]=1;\n\tq.push(root);\n\twhile(!q.empty()){\n\t\tint x=q.front();\n\t\tq.pop();\n\t\tFOR(i,0,g[x].size()){\n\t\t\tint to=g[x][i];\n\t\t\tans[to]=x;\n\t\t\tif(v[to])continue;\n\t\t\tq.push(to);\n\t\t\tv[to]=1;\n\t\t}\n\t}\n\tFOR(i,0,n){\n\t\tprintf(\"%d\\n\",ans[i]+1);\n\t}\n\t\n\t\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1548642625, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03142.html", "problem_id": "p03142", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03142/input.txt", "sample_output_relpath": "derived/input_output/data/p03142/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03142/C++/s874905238.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s874905238", "user_id": "u754862537"}, "prompt_components": {"gold_output": "0\n1\n2\n", "input_to_evaluate": "#include<iostream>\n#include<cstdio>\n#include<cstring>\n#include<cstdlib>\n#include<iomanip>\n#include<vector>\n#include<queue>\n#include<deque>\n#include<string>\n#include<utility>\n#include<cmath>\n#include<algorithm>\n#include<cctype>\n#include<set>\n#include<map>\n#include<bitset>\n#include<stack>\n#include<ctime>\n#include<cassert>\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef pair<int,int> pii;\ntypedef pair<ll,int> pli;\ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\ntypedef vector<pii> vpii;\ntypedef vector<pli> vpli;\n\ninline ll read(){\n    ll Hashimoto=0;\n\tbool Kanna=1;\n    char I_Love=getchar();\n    while(I_Love<'0'||I_Love>'9'){\n        if(I_Love=='-')Kanna=0;\n        I_Love=getchar();\n    }\n    while(I_Love>='0'&&I_Love<='9'){\n        Hashimoto=Hashimoto*10+I_Love-'0';\n        I_Love=getchar();\n    }\n    return (Kanna?Hashimoto:-Hashimoto);\n}\ntemplate<typename T1,typename T2> inline void Umax(T1 &a,T2 b){\n\tif(a<b)a=b;\n}\ntemplate<typename T1,typename T2> inline void Umin(T1 &a,T2 b){\n\tif(a>b)a=b;\n}\n\n#define I_Love_Hashimoto_Kanna main\n#define fastio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);\n#define filein(s) freopen(s,\"r\",stdin);\n#define fileout(s) freopen(s,\"w\",stdout);\n#define file freopen(\"I_Love_Hashimoto_Kanna.out\",\"w\",stdout);\n#define RE cout<<\"I_Love_Hashimoto_Kanna\"<<endl;\n#define Tone(Kanna) cout<<Kanna<<endl;\n#define Tall(Hashimoto,Kanna) for(int I_Love=0;I_Love<(Kanna);++I_Love)cout<<Hashimoto[I_Love]<<(I_Love==(Kanna)-1?\"\\n\":\" \");\n#define FOR(I_Love,Hashimoto,Kanna) for(int I_Love=Hashimoto;I_Love<(Kanna);++I_Love)\n#define MP(Hashimoto,Kanna) make_pair(Hashimoto,Kanna)\n#define REV(Kanna) reverse(Kanna.begin(),Kanna.end());\n#define SORT(Kanna) sort(Kanna.begin(),Kanna.end());\n#define UNIQUE(Kanna) Kanna.erase(unique(Kanna.begin(),Kanna.end()),Kanna.end());\n#define inf (1000000000)\n#define linf (1000000000000000000ll)\n#define mod (1000000007)\n\nint n,m;\nint indegree[111111];\nvi g[111111];\nqueue<int>q;\nbool v[111111];\nint ans[111111];\n\nint I_Love_Hashimoto_Kanna() {\n\t//完全想清楚了再开始写。\n\t//写不顺、不知道怎么写、很乱的时候，停下来好好想想。\n\t//做得慢总比做不出好。\n\tfastio;\n\tn=read();m=read();\n\tFOR(i,1,n+m){\n\t\tint a=read()-1,b=read()-1;\n\t\tg[a].push_back(b);\n\t\tindegree[b]++;\n\t}\n\tint root=-1;\n\tFOR(i,0,n){\n\t\tif(indegree[i]==0)root=i;\n\t}\n\tassert(root!=-1);\n\tans[root]=-1;\n\tv[root]=1;\n\tq.push(root);\n\twhile(!q.empty()){\n\t\tint x=q.front();\n\t\tq.pop();\n\t\tFOR(i,0,g[x].size()){\n\t\t\tint to=g[x][i];\n\t\t\tans[to]=x;\n\t\t\tif(v[to])continue;\n\t\t\tq.push(to);\n\t\t\tv[to]=1;\n\t\t}\n\t}\n\tFOR(i,0,n){\n\t\tprintf(\"%d\\n\",ans[i]+1);\n\t}\n\t\n\t\n\treturn 0;\n}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nThere is a rooted tree (see Notes) with N vertices numbered 1 to N.\nEach of the vertices, except the root, has a directed edge coming from its parent.\nNote that the root may not be Vertex 1.\n\nTakahashi has added M new directed edges to this graph.\nEach of these M edges, u \\rightarrow v, extends from some vertex u to its descendant v.\n\nYou are given the directed graph with N vertices and N-1+M edges after Takahashi added edges.\nMore specifically, you are given N-1+M pairs of integers, (A_1, B_1), ..., (A_{N-1+M}, B_{N-1+M}), which represent that the i-th edge extends from Vertex A_i to Vertex B_i.\n\nRestore the original rooted tree.\n\nNotes\n\nFor \"tree\" and other related terms in graph theory, see the article in Wikipedia, for example.\n\nConstraints\n\n3 \\leq N\n\n1 \\leq M\n\nN + M \\leq 10^5\n\n1 \\leq A_i, B_i \\leq N\n\nA_i \\neq B_i\n\nIf i \\neq j, (A_i, B_i) \\neq (A_j, B_j).\n\nThe graph in input can be obtained by adding M edges satisfying the condition in the problem statement to a rooted tree with N vertices.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 B_1\n:\nA_{N-1+M} B_{N-1+M}\n\nOutput\n\nPrint N lines.\nIn the i-th line, print 0 if Vertex i is the root of the original tree, and otherwise print the integer representing the parent of Vertex i in the original tree.\n\nNote that it can be shown that the original tree is uniquely determined.\n\nSample Input 1\n\n3 1\n1 2\n1 3\n2 3\n\nSample Output 1\n\n0\n1\n2\n\nThe graph in this input is shown below:\n\nIt can be seen that this graph is obtained by adding the edge 1 \\rightarrow 3 to the rooted tree 1 \\rightarrow 2 \\rightarrow 3.\n\nSample Input 2\n\n6 3\n2 1\n2 3\n4 1\n4 2\n6 1\n2 6\n4 6\n6 5\n\nSample Output 2\n\n6\n4\n2\n0\n6\n2", "sample_input": "3 1\n1 2\n1 3\n2 3\n"}, "reference_outputs": ["0\n1\n2\n"], "source_document_id": "p03142", "source_text": "Score : 500 points\n\nProblem Statement\n\nThere is a rooted tree (see Notes) with N vertices numbered 1 to N.\nEach of the vertices, except the root, has a directed edge coming from its parent.\nNote that the root may not be Vertex 1.\n\nTakahashi has added M new directed edges to this graph.\nEach of these M edges, u \\rightarrow v, extends from some vertex u to its descendant v.\n\nYou are given the directed graph with N vertices and N-1+M edges after Takahashi added edges.\nMore specifically, you are given N-1+M pairs of integers, (A_1, B_1), ..., (A_{N-1+M}, B_{N-1+M}), which represent that the i-th edge extends from Vertex A_i to Vertex B_i.\n\nRestore the original rooted tree.\n\nNotes\n\nFor \"tree\" and other related terms in graph theory, see the article in Wikipedia, for example.\n\nConstraints\n\n3 \\leq N\n\n1 \\leq M\n\nN + M \\leq 10^5\n\n1 \\leq A_i, B_i \\leq N\n\nA_i \\neq B_i\n\nIf i \\neq j, (A_i, B_i) \\neq (A_j, B_j).\n\nThe graph in input can be obtained by adding M edges satisfying the condition in the problem statement to a rooted tree with N vertices.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 B_1\n:\nA_{N-1+M} B_{N-1+M}\n\nOutput\n\nPrint N lines.\nIn the i-th line, print 0 if Vertex i is the root of the original tree, and otherwise print the integer representing the parent of Vertex i in the original tree.\n\nNote that it can be shown that the original tree is uniquely determined.\n\nSample Input 1\n\n3 1\n1 2\n1 3\n2 3\n\nSample Output 1\n\n0\n1\n2\n\nThe graph in this input is shown below:\n\nIt can be seen that this graph is obtained by adding the edge 1 \\rightarrow 3 to the rooted tree 1 \\rightarrow 2 \\rightarrow 3.\n\nSample Input 2\n\n6 3\n2 1\n2 3\n4 1\n4 2\n6 1\n2 6\n4 6\n6 5\n\nSample Output 2\n\n6\n4\n2\n0\n6\n2", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2656, "cpu_time_ms": 33, "memory_kb": 7424}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s504400346", "group_id": "codeNet:p03143", "input_text": "/////////////////////////   _LeMur_\n#include <algorithm>\n#include <iostream>\n#include <cstring>\n#include <cassert>\n#include <bitset>\n#include <cstdio>\n#include <vector>\n#include <string>\n#include <ctime>\n#include <stack>\n#include <queue>\n#include <cmath>\n#include <ctime>\n#include <list>\n#include <map>\n#include <set>\n\nusing namespace std;\n\nconst int N = 100005;\nconst int inf = 1000 * 1000 * 1000;\nconst int mod = 1000 * 1000 * 1000 + 7;\n\nint n , m;\nint cnt[N];\n\nint a[N] , b[N] , c[N];\n\npair <int,int> p[N];\nvector <int> g[N];\nbool used[N];\n\nint parent[N] , sz[N] , edge[N];\nlong long sum[N];\n\nbool mark[N];\n\nint findher(int a){\n    if(a == parent[a])return a;\n    return parent[a] = findher(parent[a]);\n}\n\nvoid tmerge(int a,int b){\n    a = findher(a);\n    b = findher(b);\n    if(sz[a] < sz[b])\n        swap(a , b);\n    parent[b] = a;\n    sum[a] += sum[b];\n    sz[a] += sz[b];\n    edge[a] += edge[b];\n    for(int j=0;j<(int)g[b].size();j++){\n        g[a].push_back(g[b][j]);\n    }\n    g[b].clear();\n}\n\nint main(){\n    scanf(\"%d%d\",&n,&m);\n    for(int i=1;i<=n;i++){\n        scanf(\"%d\",&cnt[i]);\n        ///\n        parent[i] = i;\n        sum[i] = cnt[i];\n        sz[i] = 1;\n    }\n    for(int i=1;i<=m;i++){\n        scanf(\"%d%d%d\",&a[i],&b[i],&c[i]);\n        p[i] = make_pair(c[i] , i);\n    }\n    sort(p + 1 , p + m + 1);\n    int ind = -1;\n    for(int i=1;i<=m;i++){\n        int x = p[i].first;\n        int id = p[i].second;\n        int aa = a[id] , bb = b[id];\n        if(findher(aa) != findher(bb)){\n            tmerge(aa , bb);\n        }\n        int P = findher(aa);\n        ++edge[P];\n        if(sum[P] >= 1ll * x){\n            mark[i] = true;\n            ind = i;\n        }\n    }\n    if(ind == -1){\n        cout<<m<<endl;\n        return 0;\n    }\n    for(int i=1;i<=n;i++){\n        parent[i] = i;\n        sum[i] = cnt[i];\n        sz[i] = 1;\n        g[i].push_back(i);\n        edge[i] = 0;\n    }\n    for(int i=1;i<=ind;i++){\n        int x = p[i].first;\n        int id = p[i].second;\n        int aa = a[id] , bb = b[id];\n        if(findher(aa) != findher(bb)){\n            tmerge(aa , bb);\n        }\n        int p = findher(aa);\n        edge[p]++;\n    }\n    int answ = 0;\n    for(int i=ind;i>=1;i--){\n        int v = a[ p[i].second ];\n        if(mark[i] && used[v] == false){\n            v = findher(v);\n            answ += edge[v];\n            for(int j=0;j<(int)g[v].size();j++){\n                int to = g[v][j];\n                used[to] = true;\n            }\n        }\n    }\n    cout<<m - answ<<endl;\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1548647103, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03143.html", "problem_id": "p03143", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03143/input.txt", "sample_output_relpath": "derived/input_output/data/p03143/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03143/C++/s504400346.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s504400346", "user_id": "u144340663"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "/////////////////////////   _LeMur_\n#include <algorithm>\n#include <iostream>\n#include <cstring>\n#include <cassert>\n#include <bitset>\n#include <cstdio>\n#include <vector>\n#include <string>\n#include <ctime>\n#include <stack>\n#include <queue>\n#include <cmath>\n#include <ctime>\n#include <list>\n#include <map>\n#include <set>\n\nusing namespace std;\n\nconst int N = 100005;\nconst int inf = 1000 * 1000 * 1000;\nconst int mod = 1000 * 1000 * 1000 + 7;\n\nint n , m;\nint cnt[N];\n\nint a[N] , b[N] , c[N];\n\npair <int,int> p[N];\nvector <int> g[N];\nbool used[N];\n\nint parent[N] , sz[N] , edge[N];\nlong long sum[N];\n\nbool mark[N];\n\nint findher(int a){\n    if(a == parent[a])return a;\n    return parent[a] = findher(parent[a]);\n}\n\nvoid tmerge(int a,int b){\n    a = findher(a);\n    b = findher(b);\n    if(sz[a] < sz[b])\n        swap(a , b);\n    parent[b] = a;\n    sum[a] += sum[b];\n    sz[a] += sz[b];\n    edge[a] += edge[b];\n    for(int j=0;j<(int)g[b].size();j++){\n        g[a].push_back(g[b][j]);\n    }\n    g[b].clear();\n}\n\nint main(){\n    scanf(\"%d%d\",&n,&m);\n    for(int i=1;i<=n;i++){\n        scanf(\"%d\",&cnt[i]);\n        ///\n        parent[i] = i;\n        sum[i] = cnt[i];\n        sz[i] = 1;\n    }\n    for(int i=1;i<=m;i++){\n        scanf(\"%d%d%d\",&a[i],&b[i],&c[i]);\n        p[i] = make_pair(c[i] , i);\n    }\n    sort(p + 1 , p + m + 1);\n    int ind = -1;\n    for(int i=1;i<=m;i++){\n        int x = p[i].first;\n        int id = p[i].second;\n        int aa = a[id] , bb = b[id];\n        if(findher(aa) != findher(bb)){\n            tmerge(aa , bb);\n        }\n        int P = findher(aa);\n        ++edge[P];\n        if(sum[P] >= 1ll * x){\n            mark[i] = true;\n            ind = i;\n        }\n    }\n    if(ind == -1){\n        cout<<m<<endl;\n        return 0;\n    }\n    for(int i=1;i<=n;i++){\n        parent[i] = i;\n        sum[i] = cnt[i];\n        sz[i] = 1;\n        g[i].push_back(i);\n        edge[i] = 0;\n    }\n    for(int i=1;i<=ind;i++){\n        int x = p[i].first;\n        int id = p[i].second;\n        int aa = a[id] , bb = b[id];\n        if(findher(aa) != findher(bb)){\n            tmerge(aa , bb);\n        }\n        int p = findher(aa);\n        edge[p]++;\n    }\n    int answ = 0;\n    for(int i=ind;i>=1;i--){\n        int v = a[ p[i].second ];\n        if(mark[i] && used[v] == false){\n            v = findher(v);\n            answ += edge[v];\n            for(int j=0;j<(int)g[v].size();j++){\n                int to = g[v][j];\n                used[to] = true;\n            }\n        }\n    }\n    cout<<m - answ<<endl;\n    return 0;\n}\n", "problem_context": "Score : 800 points\n\nProblem Statement\n\nThere is a connected undirected graph with N vertices and M edges.\nThe vertices are numbered 1 to N, and the edges are numbered 1 to M.\nAlso, each of these vertices and edges has a specified weight.\nVertex i has a weight of X_i; Edge i has a weight of Y_i and connects Vertex A_i and B_i.\n\nWe would like to remove zero or more edges so that the following condition is satisfied:\n\nFor each edge that is not removed, the sum of the weights of the vertices in the connected component containing that edge, is greater than or equal to the weight of that edge.\n\nFind the minimum number of edges that need to be removed.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\nN-1 \\leq M \\leq 10^5\n\n1 \\leq X_i \\leq 10^9\n\n1 \\leq A_i < B_i \\leq N\n\n1 \\leq Y_i \\leq 10^9\n\n(A_i,B_i) \\neq (A_j,B_j) (i \\neq j)\n\nThe given graph is connected.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nX_1 X_2 ... X_N\nA_1 B_1 Y_1\nA_2 B_2 Y_2\n:\nA_M B_M Y_M\n\nOutput\n\nFind the minimum number of edges that need to be removed.\n\nSample Input 1\n\n4 4\n2 3 5 7\n1 2 7\n1 3 9\n2 3 12\n3 4 18\n\nSample Output 1\n\n2\n\nAssume that we removed Edge 3 and 4.\nIn this case, the connected component containing Edge 1 contains Vertex 1, 2 and 3, and the sum of the weights of these vertices is 2+3+5=10.\nThe weight of Edge 1 is 7, so the condition is satisfied for Edge 1.\nSimilarly, it can be seen that the condition is also satisfied for Edge 2.\nThus, a graph satisfying the condition can be obtained by removing two edges.\n\nThe condition cannot be satisfied by removing one or less edges, so the answer is 2.\n\nSample Input 2\n\n6 10\n4 4 1 1 1 7\n3 5 19\n2 5 20\n4 5 8\n1 6 16\n2 3 9\n3 6 16\n3 4 1\n2 6 20\n2 4 19\n1 2 9\n\nSample Output 2\n\n4\n\nSample Input 3\n\n10 9\n81 16 73 7 2 61 86 38 90 28\n6 8 725\n3 10 12\n1 4 558\n4 9 615\n5 6 942\n8 9 918\n2 7 720\n4 7 292\n7 10 414\n\nSample Output 3\n\n8", "sample_input": "4 4\n2 3 5 7\n1 2 7\n1 3 9\n2 3 12\n3 4 18\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03143", "source_text": "Score : 800 points\n\nProblem Statement\n\nThere is a connected undirected graph with N vertices and M edges.\nThe vertices are numbered 1 to N, and the edges are numbered 1 to M.\nAlso, each of these vertices and edges has a specified weight.\nVertex i has a weight of X_i; Edge i has a weight of Y_i and connects Vertex A_i and B_i.\n\nWe would like to remove zero or more edges so that the following condition is satisfied:\n\nFor each edge that is not removed, the sum of the weights of the vertices in the connected component containing that edge, is greater than or equal to the weight of that edge.\n\nFind the minimum number of edges that need to be removed.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\nN-1 \\leq M \\leq 10^5\n\n1 \\leq X_i \\leq 10^9\n\n1 \\leq A_i < B_i \\leq N\n\n1 \\leq Y_i \\leq 10^9\n\n(A_i,B_i) \\neq (A_j,B_j) (i \\neq j)\n\nThe given graph is connected.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nX_1 X_2 ... X_N\nA_1 B_1 Y_1\nA_2 B_2 Y_2\n:\nA_M B_M Y_M\n\nOutput\n\nFind the minimum number of edges that need to be removed.\n\nSample Input 1\n\n4 4\n2 3 5 7\n1 2 7\n1 3 9\n2 3 12\n3 4 18\n\nSample Output 1\n\n2\n\nAssume that we removed Edge 3 and 4.\nIn this case, the connected component containing Edge 1 contains Vertex 1, 2 and 3, and the sum of the weights of these vertices is 2+3+5=10.\nThe weight of Edge 1 is 7, so the condition is satisfied for Edge 1.\nSimilarly, it can be seen that the condition is also satisfied for Edge 2.\nThus, a graph satisfying the condition can be obtained by removing two edges.\n\nThe condition cannot be satisfied by removing one or less edges, so the answer is 2.\n\nSample Input 2\n\n6 10\n4 4 1 1 1 7\n3 5 19\n2 5 20\n4 5 8\n1 6 16\n2 3 9\n3 6 16\n3 4 1\n2 6 20\n2 4 19\n1 2 9\n\nSample Output 2\n\n4\n\nSample Input 3\n\n10 9\n81 16 73 7 2 61 86 38 90 28\n6 8 725\n3 10 12\n1 4 558\n4 9 615\n5 6 942\n8 9 918\n2 7 720\n4 7 292\n7 10 414\n\nSample Output 3\n\n8", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2524, "cpu_time_ms": 79, "memory_kb": 12540}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s592422153", "group_id": "codeNet:p03145", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> P;\nint main(void){\n\tint c,a,b; cin>>c>>a>>b;\n\tcout<<(a*c)/2<<endl;\n\t\n}\n", "language": "C++", "metadata": {"date": 1588986064, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03145.html", "problem_id": "p03145", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03145/input.txt", "sample_output_relpath": "derived/input_output/data/p03145/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03145/C++/s592422153.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s592422153", "user_id": "u045547337"}, "prompt_components": {"gold_output": "6\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> P;\nint main(void){\n\tint c,a,b; cin>>c>>a>>b;\n\tcout<<(a*c)/2<<endl;\n\t\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nThere is a right triangle ABC with ∠ABC=90°.\n\nGiven the lengths of the three sides, |AB|,|BC| and |CA|, find the area of the right triangle ABC.\n\nIt is guaranteed that the area of the triangle ABC is an integer.\n\nConstraints\n\n1 \\leq |AB|,|BC|,|CA| \\leq 100\n\nAll values in input are integers.\n\nThe area of the triangle ABC is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\n|AB| |BC| |CA|\n\nOutput\n\nPrint the area of the triangle ABC.\n\nSample Input 1\n\n3 4 5\n\nSample Output 1\n\n6\n\nThis triangle has an area of 6.\n\nSample Input 2\n\n5 12 13\n\nSample Output 2\n\n30\n\nThis triangle has an area of 30.\n\nSample Input 3\n\n45 28 53\n\nSample Output 3\n\n630\n\nThis triangle has an area of 630.", "sample_input": "3 4 5\n"}, "reference_outputs": ["6\n"], "source_document_id": "p03145", "source_text": "Score : 100 points\n\nProblem Statement\n\nThere is a right triangle ABC with ∠ABC=90°.\n\nGiven the lengths of the three sides, |AB|,|BC| and |CA|, find the area of the right triangle ABC.\n\nIt is guaranteed that the area of the triangle ABC is an integer.\n\nConstraints\n\n1 \\leq |AB|,|BC|,|CA| \\leq 100\n\nAll values in input are integers.\n\nThe area of the triangle ABC is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\n|AB| |BC| |CA|\n\nOutput\n\nPrint the area of the triangle ABC.\n\nSample Input 1\n\n3 4 5\n\nSample Output 1\n\n6\n\nThis triangle has an area of 6.\n\nSample Input 2\n\n5 12 13\n\nSample Output 2\n\n30\n\nThis triangle has an area of 30.\n\nSample Input 3\n\n45 28 53\n\nSample Output 3\n\n630\n\nThis triangle has an area of 630.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 161, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s616510794", "group_id": "codeNet:p03146", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\n// typedef\n// -----------------------------------------------------------------------------\ntypedef long long ll;\ntypedef long double ld;\n\n// container util\n// -----------------------------------------------------------------------------\n#define ALL(c)  (c).begin(),(c).end()\n#define SZ(c) ((ll)(c).size())\n#define MAX(c) *max_element(ALL(c))\n#define MIN(c) *min_element(ALL(c))\n#define SORT(c) sort((c).begin(),(c).end())\n\n// repetition\n// -----------------------------------------------------------------------------\n#define FOR(i, a, b) for(ll i= (a); i < (ll)(b); ++i)\n#define REP(i, n) FOR(i, 0, n)\n\n// constant\n// -----------------------------------------------------------------------------\nconst ll INF = 1e9;\nconst ll MOD = 1e9 + 7;\nconst double EPS = 1e-9;\nconst double PI = acos(-1.0);\n\n// debug\n// -----------------------------------------------------------------------------\n#define DUMP(x)  cerr << #x << \" = \" << (x) << endl\n\n\nint main() {\n    ios::sync_with_stdio(false);\n    cin.tie(nullptr);\n    cout << fixed << setprecision(15);\n    int s; cin >> s;\n    bool A[1000000];\n    int ans = 1;\n    while(!A[s]) {\n        ans++;\n        A[s] = true;\n        if(s % 2 == 0) {\n            s /= 2;\n        } else {\n            s = 3 * s + 1;\n        }\n    }\n    cout << ans << \"\\n\";\n}", "language": "C++", "metadata": {"date": 1595125705, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03146.html", "problem_id": "p03146", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03146/input.txt", "sample_output_relpath": "derived/input_output/data/p03146/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03146/C++/s616510794.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s616510794", "user_id": "u811321379"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\n// typedef\n// -----------------------------------------------------------------------------\ntypedef long long ll;\ntypedef long double ld;\n\n// container util\n// -----------------------------------------------------------------------------\n#define ALL(c)  (c).begin(),(c).end()\n#define SZ(c) ((ll)(c).size())\n#define MAX(c) *max_element(ALL(c))\n#define MIN(c) *min_element(ALL(c))\n#define SORT(c) sort((c).begin(),(c).end())\n\n// repetition\n// -----------------------------------------------------------------------------\n#define FOR(i, a, b) for(ll i= (a); i < (ll)(b); ++i)\n#define REP(i, n) FOR(i, 0, n)\n\n// constant\n// -----------------------------------------------------------------------------\nconst ll INF = 1e9;\nconst ll MOD = 1e9 + 7;\nconst double EPS = 1e-9;\nconst double PI = acos(-1.0);\n\n// debug\n// -----------------------------------------------------------------------------\n#define DUMP(x)  cerr << #x << \" = \" << (x) << endl\n\n\nint main() {\n    ios::sync_with_stdio(false);\n    cin.tie(nullptr);\n    cout << fixed << setprecision(15);\n    int s; cin >> s;\n    bool A[1000000];\n    int ans = 1;\n    while(!A[s]) {\n        ans++;\n        A[s] = true;\n        if(s % 2 == 0) {\n            s /= 2;\n        } else {\n            s = 3 * s + 1;\n        }\n    }\n    cout << ans << \"\\n\";\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nA sequence a=\\{a_1,a_2,a_3,......\\} is determined as follows:\n\nThe first term s is given as input.\n\nLet f(n) be the following function: f(n) = n/2 if n is even, and f(n) = 3n+1 if n is odd.\n\na_i = s when i = 1, and a_i = f(a_{i-1}) when i > 1.\n\nFind the minimum integer m that satisfies the following condition:\n\nThere exists an integer n such that a_m = a_n (m > n).\n\nConstraints\n\n1 \\leq s \\leq 100\n\nAll values in input are integers.\n\nIt is guaranteed that all elements in a and the minimum m that satisfies the condition are at most 1000000.\n\nInput\n\nInput is given from Standard Input in the following format:\n\ns\n\nOutput\n\nPrint the minimum integer m that satisfies the condition.\n\nSample Input 1\n\n8\n\nSample Output 1\n\n5\n\na=\\{8,4,2,1,4,2,1,4,2,1,......\\}. As a_5=a_2, the answer is 5.\n\nSample Input 2\n\n7\n\nSample Output 2\n\n18\n\na=\\{7,22,11,34,17,52,26,13,40,20,10,5,16,8,4,2,1,4,2,1,......\\}.\n\nSample Input 3\n\n54\n\nSample Output 3\n\n114", "sample_input": "8\n"}, "reference_outputs": ["5\n"], "source_document_id": "p03146", "source_text": "Score : 200 points\n\nProblem Statement\n\nA sequence a=\\{a_1,a_2,a_3,......\\} is determined as follows:\n\nThe first term s is given as input.\n\nLet f(n) be the following function: f(n) = n/2 if n is even, and f(n) = 3n+1 if n is odd.\n\na_i = s when i = 1, and a_i = f(a_{i-1}) when i > 1.\n\nFind the minimum integer m that satisfies the following condition:\n\nThere exists an integer n such that a_m = a_n (m > n).\n\nConstraints\n\n1 \\leq s \\leq 100\n\nAll values in input are integers.\n\nIt is guaranteed that all elements in a and the minimum m that satisfies the condition are at most 1000000.\n\nInput\n\nInput is given from Standard Input in the following format:\n\ns\n\nOutput\n\nPrint the minimum integer m that satisfies the condition.\n\nSample Input 1\n\n8\n\nSample Output 1\n\n5\n\na=\\{8,4,2,1,4,2,1,4,2,1,......\\}. As a_5=a_2, the answer is 5.\n\nSample Input 2\n\n7\n\nSample Output 2\n\n18\n\na=\\{7,22,11,34,17,52,26,13,40,20,10,5,16,8,4,2,1,4,2,1,......\\}.\n\nSample Input 3\n\n54\n\nSample Output 3\n\n114", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1341, "cpu_time_ms": 3, "memory_kb": 3652}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s675756301", "group_id": "codeNet:p03146", "input_text": "\n#include <iostream>\n#include <string>\n#include <algorithm>\n#include <set>\n#include <cmath>\n#include <vector>\n#include <numeric>\n#include <map>\n#include <unordered_map>\n#include <unordered_set>\n#include <queue>\n\nusing ll = long long int;\nusing ul = unsigned long long int;\nconst ll LL_MAX (1LL<<60);\nconst ll MOD (1000000007);\n\n#define rep(i,s,e) for(ll i=(s); i<(e); i++) \n\nusing namespace std;\n\nll f(ll n)\n{\n    if (n%2==0) n/=2;\n    else n=3*n+1;\n\n    return n;\n}\n\nint main()\n{\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n\n    ll s;\n    cin >> s;\n    unordered_set<ll> ss;\n\n    ll cnt(0);\n    while (true)\n    {\n        s = f(s);\n\n        cnt++;\n\n        if (ss.find(s)==ss.end())\n            ss.insert(s);\n        else\n            break;\n    }\n\n    cout << cnt+1 << endl;\n\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1580873380, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03146.html", "problem_id": "p03146", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03146/input.txt", "sample_output_relpath": "derived/input_output/data/p03146/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03146/C++/s675756301.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s675756301", "user_id": "u778668639"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "\n#include <iostream>\n#include <string>\n#include <algorithm>\n#include <set>\n#include <cmath>\n#include <vector>\n#include <numeric>\n#include <map>\n#include <unordered_map>\n#include <unordered_set>\n#include <queue>\n\nusing ll = long long int;\nusing ul = unsigned long long int;\nconst ll LL_MAX (1LL<<60);\nconst ll MOD (1000000007);\n\n#define rep(i,s,e) for(ll i=(s); i<(e); i++) \n\nusing namespace std;\n\nll f(ll n)\n{\n    if (n%2==0) n/=2;\n    else n=3*n+1;\n\n    return n;\n}\n\nint main()\n{\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n\n    ll s;\n    cin >> s;\n    unordered_set<ll> ss;\n\n    ll cnt(0);\n    while (true)\n    {\n        s = f(s);\n\n        cnt++;\n\n        if (ss.find(s)==ss.end())\n            ss.insert(s);\n        else\n            break;\n    }\n\n    cout << cnt+1 << endl;\n\n    return 0;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nA sequence a=\\{a_1,a_2,a_3,......\\} is determined as follows:\n\nThe first term s is given as input.\n\nLet f(n) be the following function: f(n) = n/2 if n is even, and f(n) = 3n+1 if n is odd.\n\na_i = s when i = 1, and a_i = f(a_{i-1}) when i > 1.\n\nFind the minimum integer m that satisfies the following condition:\n\nThere exists an integer n such that a_m = a_n (m > n).\n\nConstraints\n\n1 \\leq s \\leq 100\n\nAll values in input are integers.\n\nIt is guaranteed that all elements in a and the minimum m that satisfies the condition are at most 1000000.\n\nInput\n\nInput is given from Standard Input in the following format:\n\ns\n\nOutput\n\nPrint the minimum integer m that satisfies the condition.\n\nSample Input 1\n\n8\n\nSample Output 1\n\n5\n\na=\\{8,4,2,1,4,2,1,4,2,1,......\\}. As a_5=a_2, the answer is 5.\n\nSample Input 2\n\n7\n\nSample Output 2\n\n18\n\na=\\{7,22,11,34,17,52,26,13,40,20,10,5,16,8,4,2,1,4,2,1,......\\}.\n\nSample Input 3\n\n54\n\nSample Output 3\n\n114", "sample_input": "8\n"}, "reference_outputs": ["5\n"], "source_document_id": "p03146", "source_text": "Score : 200 points\n\nProblem Statement\n\nA sequence a=\\{a_1,a_2,a_3,......\\} is determined as follows:\n\nThe first term s is given as input.\n\nLet f(n) be the following function: f(n) = n/2 if n is even, and f(n) = 3n+1 if n is odd.\n\na_i = s when i = 1, and a_i = f(a_{i-1}) when i > 1.\n\nFind the minimum integer m that satisfies the following condition:\n\nThere exists an integer n such that a_m = a_n (m > n).\n\nConstraints\n\n1 \\leq s \\leq 100\n\nAll values in input are integers.\n\nIt is guaranteed that all elements in a and the minimum m that satisfies the condition are at most 1000000.\n\nInput\n\nInput is given from Standard Input in the following format:\n\ns\n\nOutput\n\nPrint the minimum integer m that satisfies the condition.\n\nSample Input 1\n\n8\n\nSample Output 1\n\n5\n\na=\\{8,4,2,1,4,2,1,4,2,1,......\\}. As a_5=a_2, the answer is 5.\n\nSample Input 2\n\n7\n\nSample Output 2\n\n18\n\na=\\{7,22,11,34,17,52,26,13,40,20,10,5,16,8,4,2,1,4,2,1,......\\}.\n\nSample Input 3\n\n54\n\nSample Output 3\n\n114", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 798, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s471594817", "group_id": "codeNet:p03147", "input_text": "#include <iostream>\n#include <vector>\n#include <string>\n#include <algorithm>\n#include <set>\n\nint main()\n{\n    int N;\n    std::cin >> N;\n    std::vector<int> H(N), X(N);\n    for (int i = 0; i < N; i++)\n    {\n        X[i] = 0;\n        std::cin >> H[i];\n    }\n\n    int cnt = 0;\n    while (true)\n    {\n        bool e = false;\n        bool s = false;\n        int a = 0;\n        for (int i = 0; i < N; i++)\n        {\n            int x = X[i];\n            if (x < H[i])\n            {\n                s = true;\n            }\n            else if (x == H[i])\n            {\n                a++;\n                if (s) cnt++;\n                s = false;\n            }\n            if (s)\n            {\n                X[i]++;\n            }\n        }\n        if (s)cnt++;\n        if (a == N)break;\n    }\n\n    std::cout << cnt << std::endl;\n\n\n    return 0;\n}", "language": "C++", "metadata": {"date": 1556558445, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03147.html", "problem_id": "p03147", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03147/input.txt", "sample_output_relpath": "derived/input_output/data/p03147/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03147/C++/s471594817.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s471594817", "user_id": "u303039933"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\n#include <string>\n#include <algorithm>\n#include <set>\n\nint main()\n{\n    int N;\n    std::cin >> N;\n    std::vector<int> H(N), X(N);\n    for (int i = 0; i < N; i++)\n    {\n        X[i] = 0;\n        std::cin >> H[i];\n    }\n\n    int cnt = 0;\n    while (true)\n    {\n        bool e = false;\n        bool s = false;\n        int a = 0;\n        for (int i = 0; i < N; i++)\n        {\n            int x = X[i];\n            if (x < H[i])\n            {\n                s = true;\n            }\n            else if (x == H[i])\n            {\n                a++;\n                if (s) cnt++;\n                s = false;\n            }\n            if (s)\n            {\n                X[i]++;\n            }\n        }\n        if (s)cnt++;\n        if (a == N)break;\n    }\n\n    std::cout << cnt << std::endl;\n\n\n    return 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nIn a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0.\nYou are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \\leq k \\leq N), by repeating the following \"watering\" operation:\n\nSpecify integers l and r. Increase the height of Flower x by 1 for all x such that l \\leq x \\leq r.\n\nFind the minimum number of watering operations required to satisfy the condition.\n\nConstraints\n\n1 \\leq N \\leq 100\n\n0 \\leq h_i \\leq 100\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nh_1 h_2 h_3 ...... h_N\n\nOutput\n\nPrint the minimum number of watering operations required to satisfy the condition.\n\nSample Input 1\n\n4\n1 2 2 1\n\nSample Output 1\n\n2\n\nThe minimum number of watering operations required is 2.\nOne way to achieve it is:\n\nPerform the operation with (l,r)=(1,3).\n\nPerform the operation with (l,r)=(2,4).\n\nSample Input 2\n\n5\n3 1 2 3 1\n\nSample Output 2\n\n5\n\nSample Input 3\n\n8\n4 23 75 0 23 96 50 100\n\nSample Output 3\n\n221", "sample_input": "4\n1 2 2 1\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03147", "source_text": "Score : 300 points\n\nProblem Statement\n\nIn a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0.\nYou are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \\leq k \\leq N), by repeating the following \"watering\" operation:\n\nSpecify integers l and r. Increase the height of Flower x by 1 for all x such that l \\leq x \\leq r.\n\nFind the minimum number of watering operations required to satisfy the condition.\n\nConstraints\n\n1 \\leq N \\leq 100\n\n0 \\leq h_i \\leq 100\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nh_1 h_2 h_3 ...... h_N\n\nOutput\n\nPrint the minimum number of watering operations required to satisfy the condition.\n\nSample Input 1\n\n4\n1 2 2 1\n\nSample Output 1\n\n2\n\nThe minimum number of watering operations required is 2.\nOne way to achieve it is:\n\nPerform the operation with (l,r)=(1,3).\n\nPerform the operation with (l,r)=(2,4).\n\nSample Input 2\n\n5\n3 1 2 3 1\n\nSample Output 2\n\n5\n\nSample Input 3\n\n8\n4 23 75 0 23 96 50 100\n\nSample Output 3\n\n221", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 842, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s434848401", "group_id": "codeNet:p03147", "input_text": "#include<iostream>\nusing namespace std;\nint main() {\n    int n; cin >> n;\n    int h[100] = {0};\n    int Min = 100;\n    for (int i = 0; i < n; ++i) {\n        cin >> h[i];\n        if (Min > h[i]) {\n            Min = h[i];\n        }\n    }\n    for (int i = 0; i < n; ++i) {\n        h[i] -= Min;\n    }\n    int Delete = 0;\n    int Sum = Min;\n    for (int i = 0; i < n; ++i) {\n        if (Delete < h[i]) {\n            Delete = h[i];\n        }\n        if (h[i] != 0 && h[i + 1] == 0) {\n            Sum += Delete;\n            Delete = 0;\n        }\n    }\n    cout << Sum << endl;\n    return 0;\n}\n\n\n", "language": "C++", "metadata": {"date": 1548016527, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03147.html", "problem_id": "p03147", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03147/input.txt", "sample_output_relpath": "derived/input_output/data/p03147/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03147/C++/s434848401.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s434848401", "user_id": "u277556971"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include<iostream>\nusing namespace std;\nint main() {\n    int n; cin >> n;\n    int h[100] = {0};\n    int Min = 100;\n    for (int i = 0; i < n; ++i) {\n        cin >> h[i];\n        if (Min > h[i]) {\n            Min = h[i];\n        }\n    }\n    for (int i = 0; i < n; ++i) {\n        h[i] -= Min;\n    }\n    int Delete = 0;\n    int Sum = Min;\n    for (int i = 0; i < n; ++i) {\n        if (Delete < h[i]) {\n            Delete = h[i];\n        }\n        if (h[i] != 0 && h[i + 1] == 0) {\n            Sum += Delete;\n            Delete = 0;\n        }\n    }\n    cout << Sum << endl;\n    return 0;\n}\n\n\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nIn a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0.\nYou are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \\leq k \\leq N), by repeating the following \"watering\" operation:\n\nSpecify integers l and r. Increase the height of Flower x by 1 for all x such that l \\leq x \\leq r.\n\nFind the minimum number of watering operations required to satisfy the condition.\n\nConstraints\n\n1 \\leq N \\leq 100\n\n0 \\leq h_i \\leq 100\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nh_1 h_2 h_3 ...... h_N\n\nOutput\n\nPrint the minimum number of watering operations required to satisfy the condition.\n\nSample Input 1\n\n4\n1 2 2 1\n\nSample Output 1\n\n2\n\nThe minimum number of watering operations required is 2.\nOne way to achieve it is:\n\nPerform the operation with (l,r)=(1,3).\n\nPerform the operation with (l,r)=(2,4).\n\nSample Input 2\n\n5\n3 1 2 3 1\n\nSample Output 2\n\n5\n\nSample Input 3\n\n8\n4 23 75 0 23 96 50 100\n\nSample Output 3\n\n221", "sample_input": "4\n1 2 2 1\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03147", "source_text": "Score : 300 points\n\nProblem Statement\n\nIn a flower bed, there are N flowers, numbered 1,2,......,N. Initially, the heights of all flowers are 0.\nYou are given a sequence h=\\{h_1,h_2,h_3,......\\} as input. You would like to change the height of Flower k to h_k for all k (1 \\leq k \\leq N), by repeating the following \"watering\" operation:\n\nSpecify integers l and r. Increase the height of Flower x by 1 for all x such that l \\leq x \\leq r.\n\nFind the minimum number of watering operations required to satisfy the condition.\n\nConstraints\n\n1 \\leq N \\leq 100\n\n0 \\leq h_i \\leq 100\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nh_1 h_2 h_3 ...... h_N\n\nOutput\n\nPrint the minimum number of watering operations required to satisfy the condition.\n\nSample Input 1\n\n4\n1 2 2 1\n\nSample Output 1\n\n2\n\nThe minimum number of watering operations required is 2.\nOne way to achieve it is:\n\nPerform the operation with (l,r)=(1,3).\n\nPerform the operation with (l,r)=(2,4).\n\nSample Input 2\n\n5\n3 1 2 3 1\n\nSample Output 2\n\n5\n\nSample Input 3\n\n8\n4 23 75 0 23 96 50 100\n\nSample Output 3\n\n221", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 588, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s733903541", "group_id": "codeNet:p03155", "input_text": "#include <iostream>\n#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nvector<int> f;\nvector<int> c;\nvector<int> c1;\nvector<int> c2;\nint main()\n{\n    int n;\n    cin>>n;\n    int a,b;\n    cin>>a>>b;\n    for(int i=0;i<n;i++)\n    {\n\n        int x;\n        cin>>x;\n        f.push_back(x);\n    }\n\n    for(int i=0;i<n;i++)\n    {\n        if(f[i]<=a )\n        {\n           c.push_back(f[i]);\n        }\n        if(f[i]>=a+1 && f[i]<=b)\n        {\n\n            c1.push_back(f[i]);\n        }\n        if(f[i]>=b+1)\n        {\n\n            c2.push_back(f[i]);\n        }\n    }\n    cout<<min(c2.size(),min(c1.size(),c.size()))<<endl;\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1547326846, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03155.html", "problem_id": "p03155", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03155/input.txt", "sample_output_relpath": "derived/input_output/data/p03155/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03155/C++/s733903541.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s733903541", "user_id": "u343995406"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <iostream>\n#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nvector<int> f;\nvector<int> c;\nvector<int> c1;\nvector<int> c2;\nint main()\n{\n    int n;\n    cin>>n;\n    int a,b;\n    cin>>a>>b;\n    for(int i=0;i<n;i++)\n    {\n\n        int x;\n        cin>>x;\n        f.push_back(x);\n    }\n\n    for(int i=0;i<n;i++)\n    {\n        if(f[i]<=a )\n        {\n           c.push_back(f[i]);\n        }\n        if(f[i]>=a+1 && f[i]<=b)\n        {\n\n            c1.push_back(f[i]);\n        }\n        if(f[i]>=b+1)\n        {\n\n            c2.push_back(f[i]);\n        }\n    }\n    cout<<min(c2.size(),min(c1.size(),c.size()))<<endl;\n    return 0;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nIt has been decided that a programming contest sponsored by company A will be held, so we will post the notice on a bulletin board.\n\nThe bulletin board is in the form of a grid with N rows and N columns, and the notice will occupy a rectangular region with H rows and W columns.\n\nHow many ways are there to choose where to put the notice so that it completely covers exactly HW squares?\n\nConstraints\n\n1 \\leq H, W \\leq N \\leq 100\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nH\nW\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n3\n2\n3\n\nSample Output 1\n\n2\n\nThere are two ways to put the notice, as follows:\n\n### ...\n### ###\n... ###\n\nHere, # represents a square covered by the notice, and . represents a square not covered.\n\nSample Input 2\n\n100\n1\n1\n\nSample Output 2\n\n10000\n\nSample Input 3\n\n5\n4\n2\n\nSample Output 3\n\n8", "sample_input": "3\n2\n3\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03155", "source_text": "Score : 100 points\n\nProblem Statement\n\nIt has been decided that a programming contest sponsored by company A will be held, so we will post the notice on a bulletin board.\n\nThe bulletin board is in the form of a grid with N rows and N columns, and the notice will occupy a rectangular region with H rows and W columns.\n\nHow many ways are there to choose where to put the notice so that it completely covers exactly HW squares?\n\nConstraints\n\n1 \\leq H, W \\leq N \\leq 100\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nH\nW\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n3\n2\n3\n\nSample Output 1\n\n2\n\nThere are two ways to put the notice, as follows:\n\n### ...\n### ###\n... ###\n\nHere, # represents a square covered by the notice, and . represents a square not covered.\n\nSample Input 2\n\n100\n1\n1\n\nSample Output 2\n\n10000\n\nSample Input 3\n\n5\n4\n2\n\nSample Output 3\n\n8", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 648, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s946577909", "group_id": "codeNet:p03156", "input_text": "#include<iostream>\n#include<algorithm>\n#include<string>\n#include<cmath>\n#include<vector>\n#include<map>\nusing namespace std;\n/*\ntime:\nwa:\n反省:\n考察:\n*/\nint main() {\n    int N;\n    cin >> N;\n    int a, b;\n    cin >> a >> b;\n    int p[110];\n    int ans;\n    int q1 = 0;\n    int q2 = 0;\n    int q3 = 0;\n    for(int i = 0; i < N; i++) {\n        cin >> p[i];\n    }\n    for(int i = 0; i < N; i++){\n        if(p[i] <= a) q1++;\n        else if(a+1 <= p[i] && p[i] <= b) q2++;\n        else q3++;\n    }\n    ans = min(min(q1, q2),q3);\n    cout << ans << endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1600349273, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03156.html", "problem_id": "p03156", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03156/input.txt", "sample_output_relpath": "derived/input_output/data/p03156/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03156/C++/s946577909.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s946577909", "user_id": "u706342712"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include<iostream>\n#include<algorithm>\n#include<string>\n#include<cmath>\n#include<vector>\n#include<map>\nusing namespace std;\n/*\ntime:\nwa:\n反省:\n考察:\n*/\nint main() {\n    int N;\n    cin >> N;\n    int a, b;\n    cin >> a >> b;\n    int p[110];\n    int ans;\n    int q1 = 0;\n    int q2 = 0;\n    int q3 = 0;\n    for(int i = 0; i < N; i++) {\n        cin >> p[i];\n    }\n    for(int i = 0; i < N; i++){\n        if(p[i] <= a) q1++;\n        else if(a+1 <= p[i] && p[i] <= b) q2++;\n        else q3++;\n    }\n    ans = min(min(q1, q2),q3);\n    cout << ans << endl;\n    return 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nYou have written N problems to hold programming contests.\nThe i-th problem will have a score of P_i points if used in a contest.\n\nWith these problems, you would like to hold as many contests as possible under the following condition:\n\nA contest has three problems. The first problem has a score not greater than A points, the second has a score between A + 1 and B points (inclusive), and the third has a score not less than B + 1 points.\n\nThe same problem should not be used in multiple contests.\nAt most how many contests can be held?\n\nConstraints\n\n3 \\leq N \\leq 100\n\n1 \\leq P_i \\leq 20 (1 \\leq i \\leq N)\n\n1 \\leq A < B < 20\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA B\nP_1 P_2 ... P_N\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n7\n5 15\n1 10 16 2 7 20 12\n\nSample Output 1\n\n2\n\nTwo contests can be held by putting the first, second, third problems and the fourth, fifth, sixth problems together.\n\nSample Input 2\n\n8\n3 8\n5 5 5 10 10 10 15 20\n\nSample Output 2\n\n0\n\nNo contest can be held, because there is no problem with a score of A = 3 or less.\n\nSample Input 3\n\n3\n5 6\n5 6 10\n\nSample Output 3\n\n1", "sample_input": "7\n5 15\n1 10 16 2 7 20 12\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03156", "source_text": "Score : 200 points\n\nProblem Statement\n\nYou have written N problems to hold programming contests.\nThe i-th problem will have a score of P_i points if used in a contest.\n\nWith these problems, you would like to hold as many contests as possible under the following condition:\n\nA contest has three problems. The first problem has a score not greater than A points, the second has a score between A + 1 and B points (inclusive), and the third has a score not less than B + 1 points.\n\nThe same problem should not be used in multiple contests.\nAt most how many contests can be held?\n\nConstraints\n\n3 \\leq N \\leq 100\n\n1 \\leq P_i \\leq 20 (1 \\leq i \\leq N)\n\n1 \\leq A < B < 20\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA B\nP_1 P_2 ... P_N\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n7\n5 15\n1 10 16 2 7 20 12\n\nSample Output 1\n\n2\n\nTwo contests can be held by putting the first, second, third problems and the fourth, fifth, sixth problems together.\n\nSample Input 2\n\n8\n3 8\n5 5 5 10 10 10 15 20\n\nSample Output 2\n\n0\n\nNo contest can be held, because there is no problem with a score of A = 3 or less.\n\nSample Input 3\n\n3\n5 6\n5 6 10\n\nSample Output 3\n\n1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 568, "cpu_time_ms": 9, "memory_kb": 3596}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s919204546", "group_id": "codeNet:p03162", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n#define gc getchar_unlocked\n#define pb push_back\n#define fo(i,n) for(int i=0;i<n;i++)\n#define fo1(i,n) for(int i=1;i<n;i++)\n#define Fo(i,k,n) for(i=k;k<n?i<n:i>n;k<n?i+=1:i-=1)\n#define ll long long\n#define deb(x) cout << #x << \"=\" << x << endl\n#define deb2(x, y) cout << #x << \"=\" << x << \",\" << #y << \"=\" << y << endl\n#define all(x) x.begin(), x.end()\n#define clr(x) memset(x, 0, sizeof(x))\n#define sortall(x) sort(all(x))\n#define PI 3.1415926535897932384626\n#define setbits(x)      __builtin_popcountll(x)\n#define zrobits(x)      __builtin_ctzll(x)\n#define mod             1000000007\n#define inf             1e18\n#define ps(x,y)         fixed<<setprecision(y)<<x\n#define mk(type,arr,n)  type *arr=new type[n];\n#define w(x)            int x; cin>>x; while(x--)\n//=======================\ntypedef pair<int, int>  pii;\ntypedef vector<int>     vi;\ntypedef vector<pii>     vpii;\ntypedef vector<vi>      vvi;\n//=======================\nconst int MOD = 1000000007;\nconst int N = 300005, M = N;\n//=======================\nvi g[N],adj[N];\nint n, m, s, w, W, S, k, i, l, j, p, q, pr, fi, md;\n\n\nvoid abhinay()\n{\n   \n    #ifndef ONLINE_JUDGE   \n        freopen(\"input.txt\", \"r\", stdin);   \n        freopen(\"output.txt\", \"w\", stdout);   \n    #endif   \n    \n}\n\nint main(){\n    abhinay();\n    cin>>n>>k;\n    int dp[100005][3];\n    vi A(n+1),B(n+1),C(n+1); \n    fo(i,n) cin>>A[i]>>B[i]>>C[i];\n    dp[0][0]=A[0],dp[0][1]=B[0],dp[0][2]=C[0];\n    for (int i = 1; i < n; i++)\n        for (int j =0;j<3;j++)\n            for(int k=0;k<3;k++)\n                if (j==k) continue;\n                else{\n                    if (j==0) dp[i][j]= max(dp[i][j],dp[i-1][k]+A[i]);\n                    if (j==1) dp[i][j]= max(dp[i][j],dp[i-1][k]+B[i]);\n                    if (j==2) dp[i][j]= max(dp[i][j],dp[i-1][k]+C[i]);\n                    }\n    int ret = 0;\n    ret = max(ret,dp[n-1][0]);\n    ret = max(ret,dp[n-1][1]);\n    ret = max(ret,dp[n-1][2]);\n\n    cout << ret;\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1598565921, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03162.html", "problem_id": "p03162", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03162/input.txt", "sample_output_relpath": "derived/input_output/data/p03162/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03162/C++/s919204546.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s919204546", "user_id": "u876474655"}, "prompt_components": {"gold_output": "210\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n#define gc getchar_unlocked\n#define pb push_back\n#define fo(i,n) for(int i=0;i<n;i++)\n#define fo1(i,n) for(int i=1;i<n;i++)\n#define Fo(i,k,n) for(i=k;k<n?i<n:i>n;k<n?i+=1:i-=1)\n#define ll long long\n#define deb(x) cout << #x << \"=\" << x << endl\n#define deb2(x, y) cout << #x << \"=\" << x << \",\" << #y << \"=\" << y << endl\n#define all(x) x.begin(), x.end()\n#define clr(x) memset(x, 0, sizeof(x))\n#define sortall(x) sort(all(x))\n#define PI 3.1415926535897932384626\n#define setbits(x)      __builtin_popcountll(x)\n#define zrobits(x)      __builtin_ctzll(x)\n#define mod             1000000007\n#define inf             1e18\n#define ps(x,y)         fixed<<setprecision(y)<<x\n#define mk(type,arr,n)  type *arr=new type[n];\n#define w(x)            int x; cin>>x; while(x--)\n//=======================\ntypedef pair<int, int>  pii;\ntypedef vector<int>     vi;\ntypedef vector<pii>     vpii;\ntypedef vector<vi>      vvi;\n//=======================\nconst int MOD = 1000000007;\nconst int N = 300005, M = N;\n//=======================\nvi g[N],adj[N];\nint n, m, s, w, W, S, k, i, l, j, p, q, pr, fi, md;\n\n\nvoid abhinay()\n{\n   \n    #ifndef ONLINE_JUDGE   \n        freopen(\"input.txt\", \"r\", stdin);   \n        freopen(\"output.txt\", \"w\", stdout);   \n    #endif   \n    \n}\n\nint main(){\n    abhinay();\n    cin>>n>>k;\n    int dp[100005][3];\n    vi A(n+1),B(n+1),C(n+1); \n    fo(i,n) cin>>A[i]>>B[i]>>C[i];\n    dp[0][0]=A[0],dp[0][1]=B[0],dp[0][2]=C[0];\n    for (int i = 1; i < n; i++)\n        for (int j =0;j<3;j++)\n            for(int k=0;k<3;k++)\n                if (j==k) continue;\n                else{\n                    if (j==0) dp[i][j]= max(dp[i][j],dp[i-1][k]+A[i]);\n                    if (j==1) dp[i][j]= max(dp[i][j],dp[i-1][k]+B[i]);\n                    if (j==2) dp[i][j]= max(dp[i][j],dp[i-1][k]+C[i]);\n                    }\n    int ret = 0;\n    ret = max(ret,dp[n-1][0]);\n    ret = max(ret,dp[n-1][1]);\n    ret = max(ret,dp[n-1][2]);\n\n    cout << ret;\n    return 0;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nTaro's summer vacation starts tomorrow, and he has decided to make plans for it now.\n\nThe vacation consists of N days.\nFor each i (1 \\leq i \\leq N), Taro will choose one of the following activities and do it on the i-th day:\n\nA: Swim in the sea. Gain a_i points of happiness.\n\nB: Catch bugs in the mountains. Gain b_i points of happiness.\n\nC: Do homework at home. Gain c_i points of happiness.\n\nAs Taro gets bored easily, he cannot do the same activities for two or more consecutive days.\n\nFind the maximum possible total points of happiness that Taro gains.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq a_i, b_i, c_i \\leq 10^4\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 b_1 c_1\na_2 b_2 c_2\n:\na_N b_N c_N\n\nOutput\n\nPrint the maximum possible total points of happiness that Taro gains.\n\nSample Input 1\n\n3\n10 40 70\n20 50 80\n30 60 90\n\nSample Output 1\n\n210\n\nIf Taro does activities in the order C, B, C, he will gain 70 + 50 + 90 = 210 points of happiness.\n\nSample Input 2\n\n1\n100 10 1\n\nSample Output 2\n\n100\n\nSample Input 3\n\n7\n6 7 8\n8 8 3\n2 5 2\n7 8 6\n4 6 8\n2 3 4\n7 5 1\n\nSample Output 3\n\n46\n\nTaro should do activities in the order C, A, B, A, C, B, A.", "sample_input": "3\n10 40 70\n20 50 80\n30 60 90\n"}, "reference_outputs": ["210\n"], "source_document_id": "p03162", "source_text": "Score : 100 points\n\nProblem Statement\n\nTaro's summer vacation starts tomorrow, and he has decided to make plans for it now.\n\nThe vacation consists of N days.\nFor each i (1 \\leq i \\leq N), Taro will choose one of the following activities and do it on the i-th day:\n\nA: Swim in the sea. Gain a_i points of happiness.\n\nB: Catch bugs in the mountains. Gain b_i points of happiness.\n\nC: Do homework at home. Gain c_i points of happiness.\n\nAs Taro gets bored easily, he cannot do the same activities for two or more consecutive days.\n\nFind the maximum possible total points of happiness that Taro gains.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq a_i, b_i, c_i \\leq 10^4\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 b_1 c_1\na_2 b_2 c_2\n:\na_N b_N c_N\n\nOutput\n\nPrint the maximum possible total points of happiness that Taro gains.\n\nSample Input 1\n\n3\n10 40 70\n20 50 80\n30 60 90\n\nSample Output 1\n\n210\n\nIf Taro does activities in the order C, B, C, he will gain 70 + 50 + 90 = 210 points of happiness.\n\nSample Input 2\n\n1\n100 10 1\n\nSample Output 2\n\n100\n\nSample Input 3\n\n7\n6 7 8\n8 8 3\n2 5 2\n7 8 6\n4 6 8\n2 3 4\n7 5 1\n\nSample Output 3\n\n46\n\nTaro should do activities in the order C, A, B, A, C, B, A.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2001, "cpu_time_ms": 81, "memory_kb": 19676}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s256274452", "group_id": "codeNet:p03162", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n\nvoid input(vector<vector<int> > &arr,int n,int m)\n{\n\tfor(int i=0;i<n;i++)\n\t{\n\t\tvector<int> temp;\n\t\tfor(int j=0;j<m;j++)\n\t\t{\n\t\t\tint x;\n\t\t\tcin>>x;\n\t\t\ttemp.push_back(x);\n\t\t}\n\t\tarr.push_back(temp);\n\t\ttemp.clear();\n\t}\n}\nint main()\n{\n\tint n;\n\tcin>>n;\n\tvector<vector<int> >arr;\n\tinput(arr,n,3);\n\tvector<int>dp(n,0);\n\tint k=0;\n\tif(arr[0][0]>=arr[0][1] && arr[0][0]>=arr[0][2])\n\t   dp[0]=arr[0][0];\n\telse if(arr[0][1]>=arr[0][0] && arr[0][1]>=arr[0][2]){\n\t\tdp[0]=arr[0][1];\n\t\tk=1;\n\t}\n\telse{\n\t   dp[0]=arr[0][2];\n\t   k=2;\n}\n\tfor(int i=1;i<n;i++)\n\t{\n\t\tint x;\n\t\tfor(int j=0;j<3;j++)\n\t\t{\n\t\t\tif(j!=k){\n\t\t\t\tif(dp[i]<arr[i][j]+dp[i-1])\n\t\t\t\t{\n\t\t\t\t\tdp[i]=arr[i][j]+dp[i-1];\n\t\t\t\t\tx=j;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tk=x;\n\t}\n  cout<<dp[n-1]<<\"\\n\";\n}\n", "language": "C++", "metadata": {"date": 1588126243, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03162.html", "problem_id": "p03162", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03162/input.txt", "sample_output_relpath": "derived/input_output/data/p03162/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03162/C++/s256274452.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s256274452", "user_id": "u521259528"}, "prompt_components": {"gold_output": "210\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n\nvoid input(vector<vector<int> > &arr,int n,int m)\n{\n\tfor(int i=0;i<n;i++)\n\t{\n\t\tvector<int> temp;\n\t\tfor(int j=0;j<m;j++)\n\t\t{\n\t\t\tint x;\n\t\t\tcin>>x;\n\t\t\ttemp.push_back(x);\n\t\t}\n\t\tarr.push_back(temp);\n\t\ttemp.clear();\n\t}\n}\nint main()\n{\n\tint n;\n\tcin>>n;\n\tvector<vector<int> >arr;\n\tinput(arr,n,3);\n\tvector<int>dp(n,0);\n\tint k=0;\n\tif(arr[0][0]>=arr[0][1] && arr[0][0]>=arr[0][2])\n\t   dp[0]=arr[0][0];\n\telse if(arr[0][1]>=arr[0][0] && arr[0][1]>=arr[0][2]){\n\t\tdp[0]=arr[0][1];\n\t\tk=1;\n\t}\n\telse{\n\t   dp[0]=arr[0][2];\n\t   k=2;\n}\n\tfor(int i=1;i<n;i++)\n\t{\n\t\tint x;\n\t\tfor(int j=0;j<3;j++)\n\t\t{\n\t\t\tif(j!=k){\n\t\t\t\tif(dp[i]<arr[i][j]+dp[i-1])\n\t\t\t\t{\n\t\t\t\t\tdp[i]=arr[i][j]+dp[i-1];\n\t\t\t\t\tx=j;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tk=x;\n\t}\n  cout<<dp[n-1]<<\"\\n\";\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nTaro's summer vacation starts tomorrow, and he has decided to make plans for it now.\n\nThe vacation consists of N days.\nFor each i (1 \\leq i \\leq N), Taro will choose one of the following activities and do it on the i-th day:\n\nA: Swim in the sea. Gain a_i points of happiness.\n\nB: Catch bugs in the mountains. Gain b_i points of happiness.\n\nC: Do homework at home. Gain c_i points of happiness.\n\nAs Taro gets bored easily, he cannot do the same activities for two or more consecutive days.\n\nFind the maximum possible total points of happiness that Taro gains.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq a_i, b_i, c_i \\leq 10^4\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 b_1 c_1\na_2 b_2 c_2\n:\na_N b_N c_N\n\nOutput\n\nPrint the maximum possible total points of happiness that Taro gains.\n\nSample Input 1\n\n3\n10 40 70\n20 50 80\n30 60 90\n\nSample Output 1\n\n210\n\nIf Taro does activities in the order C, B, C, he will gain 70 + 50 + 90 = 210 points of happiness.\n\nSample Input 2\n\n1\n100 10 1\n\nSample Output 2\n\n100\n\nSample Input 3\n\n7\n6 7 8\n8 8 3\n2 5 2\n7 8 6\n4 6 8\n2 3 4\n7 5 1\n\nSample Output 3\n\n46\n\nTaro should do activities in the order C, A, B, A, C, B, A.", "sample_input": "3\n10 40 70\n20 50 80\n30 60 90\n"}, "reference_outputs": ["210\n"], "source_document_id": "p03162", "source_text": "Score : 100 points\n\nProblem Statement\n\nTaro's summer vacation starts tomorrow, and he has decided to make plans for it now.\n\nThe vacation consists of N days.\nFor each i (1 \\leq i \\leq N), Taro will choose one of the following activities and do it on the i-th day:\n\nA: Swim in the sea. Gain a_i points of happiness.\n\nB: Catch bugs in the mountains. Gain b_i points of happiness.\n\nC: Do homework at home. Gain c_i points of happiness.\n\nAs Taro gets bored easily, he cannot do the same activities for two or more consecutive days.\n\nFind the maximum possible total points of happiness that Taro gains.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq a_i, b_i, c_i \\leq 10^4\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 b_1 c_1\na_2 b_2 c_2\n:\na_N b_N c_N\n\nOutput\n\nPrint the maximum possible total points of happiness that Taro gains.\n\nSample Input 1\n\n3\n10 40 70\n20 50 80\n30 60 90\n\nSample Output 1\n\n210\n\nIf Taro does activities in the order C, B, C, he will gain 70 + 50 + 90 = 210 points of happiness.\n\nSample Input 2\n\n1\n100 10 1\n\nSample Output 2\n\n100\n\nSample Input 3\n\n7\n6 7 8\n8 8 3\n2 5 2\n7 8 6\n4 6 8\n2 3 4\n7 5 1\n\nSample Output 3\n\n46\n\nTaro should do activities in the order C, A, B, A, C, B, A.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 762, "cpu_time_ms": 108, "memory_kb": 6836}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s144866565", "group_id": "codeNet:p03162", "input_text": "#include <bits/stdc++.h>\n#include <ext/pb_ds/assoc_container.hpp>\n#include <ext/pb_ds/tree_policy.hpp>\n\n#define ll              long long\n#define pb              push_back\n#define ppb             pop_back\n#define endl            '\\n'\n#define mii             map<ll,ll>\n#define pii             pair<ll,ll>\n#define vi              vector<ll>\n#define vs              vector<string>\n#define all(a)          (a).begin(),(a).end()\n#define F               first\n#define S               second\n#define sz(x)           (ll)x.size()\n#define hell            1000000007\n#define inf             (ll)1e18 + 5\n#define PI              3.14159265358979323844\n#define rep(i,a,b)      for (ll i=a;i<b;i++)\n#define repr(i,a,b)     for (ll i=a-1;i>=b;i--)\n#define lbnd            lower_bound\n#define ubnd            upper_bound\n#define mp              make_pair\n#define ios             ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0);\n#define ordered_set     tree<ll, null_type,less<ll>, rb_tree_tag,tree_order_statistics_node_update>\n#define trace(...)      __f(#__VA_ARGS__, __VA_ARGS__)\n\ntemplate <typename Arg1>\nvoid __f(const char* name, Arg1&& arg1){\n    std::cerr << name << \" : \" << arg1 << endl;\n}\ntemplate <typename Arg1, typename... Args>\nvoid __f(const char* names, Arg1&& arg1, Args&&... args){\n    const char* comma = strchr(names + 1, ',');std::cerr.write(names, comma - names) << \" : \" << arg1<<\" | \";__f(comma+1, args...);\n}\n\nusing namespace std;\nusing namespace __gnu_pbds;\n\n/*----------------------Graph Moves----------------*/\n//const int fx[]={+1,-1,+0,+0};\n//const int fy[]={+0,+0,+1,-1};\n//const int fx[]={+0,+0,+1,-1,-1,+1,-1,+1};   // Kings Move\n//const int fy[]={-1,+1,+0,+0,+1,+1,-1,-1};  // Kings Move\n//const int fx[]={-2, -2, -1, -1,  1,  1,  2,  2};  // Knights Move\n//const int fy[]={-1,  1, -2,  2, -2,  2, -1,  1}; // Knights Move\n/*------------------------------------------------*/\n\n//primes for hashing 937,991,1013,1409,1741\n\nll n;\nvi a,b,c;\nll dp[100005][3];\n\nll find(ll n,ll i){\n\tif (n<=0)return 0;\n\tif (dp[n][i]!=-1)return dp[n][i];\n\tif (i==0){\n\t\tdp[n][i]=a[n-1];\n\t\tll meow=max(find(n-1,1),find(n-1,2));\n\t\tdp[n][i]+=max(meow,find(n-2,0));\n\t}\n\telse if (i==1){\n\t\tdp[n][i]=b[n-1];\n\t\tll meow=max(find(n-1,0),find(n-1,2));\n\t\tdp[n][i]+=max(meow,find(n-2,1));\n\t}\n\telse {\n\t\tdp[n][i]=c[n-1];\n\t\tll meow=max(find(n-1,1),find(n-1,0));\n\t\tdp[n][i]+=max(meow,find(n-2,2));\n\t}\n\treturn dp[n][i];\n}\n\nvoid solve() {\n    cin>>n;\n    memset(dp,-1,sizeof dp);\n    rep(i,0,n){\n    \tll x,y,z;\n    \tcin>>x>>y>>z;\n    \ta.pb(x),b.pb(y),c.pb(z);\n    }\n    find(n,0);\n    find(n,1);\n    find(n,2);\n    cout<<max(dp[n][0],max(dp[n][1],dp[n][2]))<<endl;\n}\n\nsigned main() {\n    ios\n    ll test=1;\n    //cin>>test;\n    while (test--) solve();\n    return 0;\n}", "language": "C++", "metadata": {"date": 1585452456, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03162.html", "problem_id": "p03162", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03162/input.txt", "sample_output_relpath": "derived/input_output/data/p03162/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03162/C++/s144866565.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s144866565", "user_id": "u314355819"}, "prompt_components": {"gold_output": "210\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#include <ext/pb_ds/assoc_container.hpp>\n#include <ext/pb_ds/tree_policy.hpp>\n\n#define ll              long long\n#define pb              push_back\n#define ppb             pop_back\n#define endl            '\\n'\n#define mii             map<ll,ll>\n#define pii             pair<ll,ll>\n#define vi              vector<ll>\n#define vs              vector<string>\n#define all(a)          (a).begin(),(a).end()\n#define F               first\n#define S               second\n#define sz(x)           (ll)x.size()\n#define hell            1000000007\n#define inf             (ll)1e18 + 5\n#define PI              3.14159265358979323844\n#define rep(i,a,b)      for (ll i=a;i<b;i++)\n#define repr(i,a,b)     for (ll i=a-1;i>=b;i--)\n#define lbnd            lower_bound\n#define ubnd            upper_bound\n#define mp              make_pair\n#define ios             ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0);\n#define ordered_set     tree<ll, null_type,less<ll>, rb_tree_tag,tree_order_statistics_node_update>\n#define trace(...)      __f(#__VA_ARGS__, __VA_ARGS__)\n\ntemplate <typename Arg1>\nvoid __f(const char* name, Arg1&& arg1){\n    std::cerr << name << \" : \" << arg1 << endl;\n}\ntemplate <typename Arg1, typename... Args>\nvoid __f(const char* names, Arg1&& arg1, Args&&... args){\n    const char* comma = strchr(names + 1, ',');std::cerr.write(names, comma - names) << \" : \" << arg1<<\" | \";__f(comma+1, args...);\n}\n\nusing namespace std;\nusing namespace __gnu_pbds;\n\n/*----------------------Graph Moves----------------*/\n//const int fx[]={+1,-1,+0,+0};\n//const int fy[]={+0,+0,+1,-1};\n//const int fx[]={+0,+0,+1,-1,-1,+1,-1,+1};   // Kings Move\n//const int fy[]={-1,+1,+0,+0,+1,+1,-1,-1};  // Kings Move\n//const int fx[]={-2, -2, -1, -1,  1,  1,  2,  2};  // Knights Move\n//const int fy[]={-1,  1, -2,  2, -2,  2, -1,  1}; // Knights Move\n/*------------------------------------------------*/\n\n//primes for hashing 937,991,1013,1409,1741\n\nll n;\nvi a,b,c;\nll dp[100005][3];\n\nll find(ll n,ll i){\n\tif (n<=0)return 0;\n\tif (dp[n][i]!=-1)return dp[n][i];\n\tif (i==0){\n\t\tdp[n][i]=a[n-1];\n\t\tll meow=max(find(n-1,1),find(n-1,2));\n\t\tdp[n][i]+=max(meow,find(n-2,0));\n\t}\n\telse if (i==1){\n\t\tdp[n][i]=b[n-1];\n\t\tll meow=max(find(n-1,0),find(n-1,2));\n\t\tdp[n][i]+=max(meow,find(n-2,1));\n\t}\n\telse {\n\t\tdp[n][i]=c[n-1];\n\t\tll meow=max(find(n-1,1),find(n-1,0));\n\t\tdp[n][i]+=max(meow,find(n-2,2));\n\t}\n\treturn dp[n][i];\n}\n\nvoid solve() {\n    cin>>n;\n    memset(dp,-1,sizeof dp);\n    rep(i,0,n){\n    \tll x,y,z;\n    \tcin>>x>>y>>z;\n    \ta.pb(x),b.pb(y),c.pb(z);\n    }\n    find(n,0);\n    find(n,1);\n    find(n,2);\n    cout<<max(dp[n][0],max(dp[n][1],dp[n][2]))<<endl;\n}\n\nsigned main() {\n    ios\n    ll test=1;\n    //cin>>test;\n    while (test--) solve();\n    return 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nTaro's summer vacation starts tomorrow, and he has decided to make plans for it now.\n\nThe vacation consists of N days.\nFor each i (1 \\leq i \\leq N), Taro will choose one of the following activities and do it on the i-th day:\n\nA: Swim in the sea. Gain a_i points of happiness.\n\nB: Catch bugs in the mountains. Gain b_i points of happiness.\n\nC: Do homework at home. Gain c_i points of happiness.\n\nAs Taro gets bored easily, he cannot do the same activities for two or more consecutive days.\n\nFind the maximum possible total points of happiness that Taro gains.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq a_i, b_i, c_i \\leq 10^4\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 b_1 c_1\na_2 b_2 c_2\n:\na_N b_N c_N\n\nOutput\n\nPrint the maximum possible total points of happiness that Taro gains.\n\nSample Input 1\n\n3\n10 40 70\n20 50 80\n30 60 90\n\nSample Output 1\n\n210\n\nIf Taro does activities in the order C, B, C, he will gain 70 + 50 + 90 = 210 points of happiness.\n\nSample Input 2\n\n1\n100 10 1\n\nSample Output 2\n\n100\n\nSample Input 3\n\n7\n6 7 8\n8 8 3\n2 5 2\n7 8 6\n4 6 8\n2 3 4\n7 5 1\n\nSample Output 3\n\n46\n\nTaro should do activities in the order C, A, B, A, C, B, A.", "sample_input": "3\n10 40 70\n20 50 80\n30 60 90\n"}, "reference_outputs": ["210\n"], "source_document_id": "p03162", "source_text": "Score : 100 points\n\nProblem Statement\n\nTaro's summer vacation starts tomorrow, and he has decided to make plans for it now.\n\nThe vacation consists of N days.\nFor each i (1 \\leq i \\leq N), Taro will choose one of the following activities and do it on the i-th day:\n\nA: Swim in the sea. Gain a_i points of happiness.\n\nB: Catch bugs in the mountains. Gain b_i points of happiness.\n\nC: Do homework at home. Gain c_i points of happiness.\n\nAs Taro gets bored easily, he cannot do the same activities for two or more consecutive days.\n\nFind the maximum possible total points of happiness that Taro gains.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq a_i, b_i, c_i \\leq 10^4\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 b_1 c_1\na_2 b_2 c_2\n:\na_N b_N c_N\n\nOutput\n\nPrint the maximum possible total points of happiness that Taro gains.\n\nSample Input 1\n\n3\n10 40 70\n20 50 80\n30 60 90\n\nSample Output 1\n\n210\n\nIf Taro does activities in the order C, B, C, he will gain 70 + 50 + 90 = 210 points of happiness.\n\nSample Input 2\n\n1\n100 10 1\n\nSample Output 2\n\n100\n\nSample Input 3\n\n7\n6 7 8\n8 8 3\n2 5 2\n7 8 6\n4 6 8\n2 3 4\n7 5 1\n\nSample Output 3\n\n46\n\nTaro should do activities in the order C, A, B, A, C, B, A.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2755, "cpu_time_ms": 32, "memory_kb": 9952}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s230861190", "group_id": "codeNet:p03162", "input_text": "//template by I_Love_Totoro, inspired by chamow\n//Doing VC Everyday #SpecialistByMarch\n//refer cook_book and AC  of/Ubuntu folder _FunWithCP_ dated:16/03/2020- for POC and more insights respectively\n//interactive comments ahead! : for the love of CP <3\n//note to self:for the love of everything good, uncomment fastread whenever applicable :) \n\n/* footnotes/ obs\n*\n*/\n\n/*main idea:\n*\n*/\n\n/*similar to:\n*\n*/\n\n/*re-learnt/ got better clarity\n*\n*/\n\n/*corollary\n*\n*/\n\n#include <bits/stdc++.h>\n#define pb push_back\n#define mp make_pair\n#define X first\n#define Y second\n#define rep(i,a,n) for(i=a;i<n;i++)\n#define repe(i,a,n) for(i=a;i<=n;i++)\n#define repn(i,a,n) for(i=n;i>=a;i--)\n#define all(x) (x).begin(),(x).end()\n#define PI (atan(1)*4)\n#define INF (int)1e9\n\n#define fastread ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL);\n//typedef vec vector<ll>\ntypedef long long ll;\ntypedef long double ld;\ntypedef long int li;\n\nusing namespace std;\n\nll lcm(ll val1,ll val2)\n{\n\tif(val1==0||val2==0)\n\t\treturn 0;\n\telse\n\t\treturn (val1*val2)/__gcd(val1,val2);\n}\n\nll pw(ll base,ll p)\n{\n\tif(base==1||p==0)\t\t\t\t\n\t\treturn 1;\n\tif(p%2==0){\n\t\tll interm=pw(base,p/2);\n\t\treturn interm*interm;\n\n\t}\n\telse\n\t\treturn base*pw(base,p-1);\n\n}\n\nint main()\n{\n\n\t//fastread;\n\t/*\n\tfreopen(\"input.txt\",\"r\",stdin);\n    freopen(\"output.txt\",\"w\",stdout);\n    */\n\t\n\tll n, a, b, c, ansa = 0, ansb = 0, ansc = 0;\n\tcin>>n;\n\n\tvector<vector<ll>>dp(n,vector<ll>(3,0));\n\n\tfor (ll i = 0; i < n; i ++) {\n\t\tcin>>a>>b>>c;\n\n\t\tif (i == 0)\n\t\t\tansa += a,ansb += b,ansc += c;//dp[i][0] = a, dp[i][1] = b, dp[i][2] = c;\n\t\telse {\n\t\t\t/*dp[i][0]*/ansa += max(b,c);\n\t\t\tansb += max(a,c);\n\t\t\tansc += max(a,b);\n\t\t}\n\t}\n\tcout<<max(ansa,max(ansb,ansc))<<\"\\n\";//max(dp[n-1][0],max(dp[n-1][1],dp[n-1][2]))<<\"\\n\";\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1584377811, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03162.html", "problem_id": "p03162", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03162/input.txt", "sample_output_relpath": "derived/input_output/data/p03162/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03162/C++/s230861190.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s230861190", "user_id": "u495337735"}, "prompt_components": {"gold_output": "210\n", "input_to_evaluate": "//template by I_Love_Totoro, inspired by chamow\n//Doing VC Everyday #SpecialistByMarch\n//refer cook_book and AC  of/Ubuntu folder _FunWithCP_ dated:16/03/2020- for POC and more insights respectively\n//interactive comments ahead! : for the love of CP <3\n//note to self:for the love of everything good, uncomment fastread whenever applicable :) \n\n/* footnotes/ obs\n*\n*/\n\n/*main idea:\n*\n*/\n\n/*similar to:\n*\n*/\n\n/*re-learnt/ got better clarity\n*\n*/\n\n/*corollary\n*\n*/\n\n#include <bits/stdc++.h>\n#define pb push_back\n#define mp make_pair\n#define X first\n#define Y second\n#define rep(i,a,n) for(i=a;i<n;i++)\n#define repe(i,a,n) for(i=a;i<=n;i++)\n#define repn(i,a,n) for(i=n;i>=a;i--)\n#define all(x) (x).begin(),(x).end()\n#define PI (atan(1)*4)\n#define INF (int)1e9\n\n#define fastread ios_base::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL);\n//typedef vec vector<ll>\ntypedef long long ll;\ntypedef long double ld;\ntypedef long int li;\n\nusing namespace std;\n\nll lcm(ll val1,ll val2)\n{\n\tif(val1==0||val2==0)\n\t\treturn 0;\n\telse\n\t\treturn (val1*val2)/__gcd(val1,val2);\n}\n\nll pw(ll base,ll p)\n{\n\tif(base==1||p==0)\t\t\t\t\n\t\treturn 1;\n\tif(p%2==0){\n\t\tll interm=pw(base,p/2);\n\t\treturn interm*interm;\n\n\t}\n\telse\n\t\treturn base*pw(base,p-1);\n\n}\n\nint main()\n{\n\n\t//fastread;\n\t/*\n\tfreopen(\"input.txt\",\"r\",stdin);\n    freopen(\"output.txt\",\"w\",stdout);\n    */\n\t\n\tll n, a, b, c, ansa = 0, ansb = 0, ansc = 0;\n\tcin>>n;\n\n\tvector<vector<ll>>dp(n,vector<ll>(3,0));\n\n\tfor (ll i = 0; i < n; i ++) {\n\t\tcin>>a>>b>>c;\n\n\t\tif (i == 0)\n\t\t\tansa += a,ansb += b,ansc += c;//dp[i][0] = a, dp[i][1] = b, dp[i][2] = c;\n\t\telse {\n\t\t\t/*dp[i][0]*/ansa += max(b,c);\n\t\t\tansb += max(a,c);\n\t\t\tansc += max(a,b);\n\t\t}\n\t}\n\tcout<<max(ansa,max(ansb,ansc))<<\"\\n\";//max(dp[n-1][0],max(dp[n-1][1],dp[n-1][2]))<<\"\\n\";\n\treturn 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nTaro's summer vacation starts tomorrow, and he has decided to make plans for it now.\n\nThe vacation consists of N days.\nFor each i (1 \\leq i \\leq N), Taro will choose one of the following activities and do it on the i-th day:\n\nA: Swim in the sea. Gain a_i points of happiness.\n\nB: Catch bugs in the mountains. Gain b_i points of happiness.\n\nC: Do homework at home. Gain c_i points of happiness.\n\nAs Taro gets bored easily, he cannot do the same activities for two or more consecutive days.\n\nFind the maximum possible total points of happiness that Taro gains.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq a_i, b_i, c_i \\leq 10^4\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 b_1 c_1\na_2 b_2 c_2\n:\na_N b_N c_N\n\nOutput\n\nPrint the maximum possible total points of happiness that Taro gains.\n\nSample Input 1\n\n3\n10 40 70\n20 50 80\n30 60 90\n\nSample Output 1\n\n210\n\nIf Taro does activities in the order C, B, C, he will gain 70 + 50 + 90 = 210 points of happiness.\n\nSample Input 2\n\n1\n100 10 1\n\nSample Output 2\n\n100\n\nSample Input 3\n\n7\n6 7 8\n8 8 3\n2 5 2\n7 8 6\n4 6 8\n2 3 4\n7 5 1\n\nSample Output 3\n\n46\n\nTaro should do activities in the order C, A, B, A, C, B, A.", "sample_input": "3\n10 40 70\n20 50 80\n30 60 90\n"}, "reference_outputs": ["210\n"], "source_document_id": "p03162", "source_text": "Score : 100 points\n\nProblem Statement\n\nTaro's summer vacation starts tomorrow, and he has decided to make plans for it now.\n\nThe vacation consists of N days.\nFor each i (1 \\leq i \\leq N), Taro will choose one of the following activities and do it on the i-th day:\n\nA: Swim in the sea. Gain a_i points of happiness.\n\nB: Catch bugs in the mountains. Gain b_i points of happiness.\n\nC: Do homework at home. Gain c_i points of happiness.\n\nAs Taro gets bored easily, he cannot do the same activities for two or more consecutive days.\n\nFind the maximum possible total points of happiness that Taro gains.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq a_i, b_i, c_i \\leq 10^4\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 b_1 c_1\na_2 b_2 c_2\n:\na_N b_N c_N\n\nOutput\n\nPrint the maximum possible total points of happiness that Taro gains.\n\nSample Input 1\n\n3\n10 40 70\n20 50 80\n30 60 90\n\nSample Output 1\n\n210\n\nIf Taro does activities in the order C, B, C, he will gain 70 + 50 + 90 = 210 points of happiness.\n\nSample Input 2\n\n1\n100 10 1\n\nSample Output 2\n\n100\n\nSample Input 3\n\n7\n6 7 8\n8 8 3\n2 5 2\n7 8 6\n4 6 8\n2 3 4\n7 5 1\n\nSample Output 3\n\n46\n\nTaro should do activities in the order C, A, B, A, C, B, A.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1767, "cpu_time_ms": 90, "memory_kb": 5760}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s020538455", "group_id": "codeNet:p03164", "input_text": "#include <bits/stdc++.h>\n\nusing namespace std;\n\ntypedef long long ll;\nconst double eps=1e-6,pi=acos(-1);\nconst int N=1e3+5,M=1e9+7,SEGM=4*N,OO=0x3f3f3f3f;\nint t,n,W;\nint p[N],w[N];\nmap<pair<int,int>,int>mp;\n\nint solve(int i,int remW){\n    if(i==n) return 0;\n    if(mp.find({i,remW})!=mp.end()) return mp[{i,remW}];\n    return mp[{i,remW}]=max(solve(i+1,remW),remW-w[i]>=0?solve(i+1,remW-w[i])+p[i]:(int)-1e9);\n}\n\nint main(){\n    //freopen(\"myfile.txt\",\"w\",stdout);\n    scanf(\"%d%d\",&n,&W);\n    for(int i=0;i<n;++i)\n        scanf(\"%d%d\",w+i,p+i);\n    printf(\"%d\",solve(0,W));\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1599381242, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03164.html", "problem_id": "p03164", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03164/input.txt", "sample_output_relpath": "derived/input_output/data/p03164/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03164/C++/s020538455.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s020538455", "user_id": "u353919145"}, "prompt_components": {"gold_output": "90\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\nusing namespace std;\n\ntypedef long long ll;\nconst double eps=1e-6,pi=acos(-1);\nconst int N=1e3+5,M=1e9+7,SEGM=4*N,OO=0x3f3f3f3f;\nint t,n,W;\nint p[N],w[N];\nmap<pair<int,int>,int>mp;\n\nint solve(int i,int remW){\n    if(i==n) return 0;\n    if(mp.find({i,remW})!=mp.end()) return mp[{i,remW}];\n    return mp[{i,remW}]=max(solve(i+1,remW),remW-w[i]>=0?solve(i+1,remW-w[i])+p[i]:(int)-1e9);\n}\n\nint main(){\n    //freopen(\"myfile.txt\",\"w\",stdout);\n    scanf(\"%d%d\",&n,&W);\n    for(int i=0;i<n;++i)\n        scanf(\"%d%d\",w+i,p+i);\n    printf(\"%d\",solve(0,W));\n    return 0;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nThere are N items, numbered 1, 2, \\ldots, N.\nFor each i (1 \\leq i \\leq N), Item i has a weight of w_i and a value of v_i.\n\nTaro has decided to choose some of the N items and carry them home in a knapsack.\nThe capacity of the knapsack is W, which means that the sum of the weights of items taken must be at most W.\n\nFind the maximum possible sum of the values of items that Taro takes home.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 100\n\n1 \\leq W \\leq 10^9\n\n1 \\leq w_i \\leq W\n\n1 \\leq v_i \\leq 10^3\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN W\nw_1 v_1\nw_2 v_2\n:\nw_N v_N\n\nOutput\n\nPrint the maximum possible sum of the values of items that Taro takes home.\n\nSample Input 1\n\n3 8\n3 30\n4 50\n5 60\n\nSample Output 1\n\n90\n\nItems 1 and 3 should be taken.\nThen, the sum of the weights is 3 + 5 = 8, and the sum of the values is 30 + 60 = 90.\n\nSample Input 2\n\n1 1000000000\n1000000000 10\n\nSample Output 2\n\n10\n\nSample Input 3\n\n6 15\n6 5\n5 6\n6 4\n6 6\n3 5\n7 2\n\nSample Output 3\n\n17\n\nItems 2, 4 and 5 should be taken.\nThen, the sum of the weights is 5 + 6 + 3 = 14, and the sum of the values is 6 + 6 + 5 = 17.", "sample_input": "3 8\n3 30\n4 50\n5 60\n"}, "reference_outputs": ["90\n"], "source_document_id": "p03164", "source_text": "Score : 100 points\n\nProblem Statement\n\nThere are N items, numbered 1, 2, \\ldots, N.\nFor each i (1 \\leq i \\leq N), Item i has a weight of w_i and a value of v_i.\n\nTaro has decided to choose some of the N items and carry them home in a knapsack.\nThe capacity of the knapsack is W, which means that the sum of the weights of items taken must be at most W.\n\nFind the maximum possible sum of the values of items that Taro takes home.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 100\n\n1 \\leq W \\leq 10^9\n\n1 \\leq w_i \\leq W\n\n1 \\leq v_i \\leq 10^3\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN W\nw_1 v_1\nw_2 v_2\n:\nw_N v_N\n\nOutput\n\nPrint the maximum possible sum of the values of items that Taro takes home.\n\nSample Input 1\n\n3 8\n3 30\n4 50\n5 60\n\nSample Output 1\n\n90\n\nItems 1 and 3 should be taken.\nThen, the sum of the weights is 3 + 5 = 8, and the sum of the values is 30 + 60 = 90.\n\nSample Input 2\n\n1 1000000000\n1000000000 10\n\nSample Output 2\n\n10\n\nSample Input 3\n\n6 15\n6 5\n5 6\n6 4\n6 6\n3 5\n7 2\n\nSample Output 3\n\n17\n\nItems 2, 4 and 5 should be taken.\nThen, the sum of the weights is 5 + 6 + 3 = 14, and the sum of the values is 6 + 6 + 5 = 17.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 591, "cpu_time_ms": 2211, "memory_kb": 262528}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s084373911", "group_id": "codeNet:p03164", "input_text": "#include <bits/stdc++.h>\n\nusing namespace std;\nusing ll = long long;\nconst ll inf = 1e18 + 5;\n\nint main() {\n  ios::sync_with_stdio(false);\n  cin.tie(0);\n  int n, W, V = 0;\n  cin >> n >> W;\n  vector<int> w(n), v(n);  \n  for(int i = 0; i < n; i++) cin >> w[i] >> v[i];\n  for(int i = 0; i < n; i++) V += v[i];\n  vector<vector<ll>> dp(n + 1, vector<ll> (V + 1, inf));\n  for(int i = 0; i <= n; i++) dp[i][0] = 0LL;\n  for(int i = 1; i <= n; i++) {\n    for(int j = 1; j <= V; j++) {\n      if(j >= v[i - 1] && dp[i - 1][j - v[i - 1]] < inf) {\n        dp[i][j] = min(dp[i - 1][j], (ll)w[i - 1] + dp[i - 1][j - v[i - 1]]);\n      } else {\n        dp[i][j] = dp[i - 1][j];\n      }\n    }\n  }\n  ll ans = 0;\n  for(int j = 1; j <= V; j++) {\n    if(dp[n][j] <= W) ans = j;\n  }\n  cout << ans << '\\n';\n  return 0;\n}\n      \n", "language": "C++", "metadata": {"date": 1594484969, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03164.html", "problem_id": "p03164", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03164/input.txt", "sample_output_relpath": "derived/input_output/data/p03164/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03164/C++/s084373911.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s084373911", "user_id": "u731566764"}, "prompt_components": {"gold_output": "90\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\nusing namespace std;\nusing ll = long long;\nconst ll inf = 1e18 + 5;\n\nint main() {\n  ios::sync_with_stdio(false);\n  cin.tie(0);\n  int n, W, V = 0;\n  cin >> n >> W;\n  vector<int> w(n), v(n);  \n  for(int i = 0; i < n; i++) cin >> w[i] >> v[i];\n  for(int i = 0; i < n; i++) V += v[i];\n  vector<vector<ll>> dp(n + 1, vector<ll> (V + 1, inf));\n  for(int i = 0; i <= n; i++) dp[i][0] = 0LL;\n  for(int i = 1; i <= n; i++) {\n    for(int j = 1; j <= V; j++) {\n      if(j >= v[i - 1] && dp[i - 1][j - v[i - 1]] < inf) {\n        dp[i][j] = min(dp[i - 1][j], (ll)w[i - 1] + dp[i - 1][j - v[i - 1]]);\n      } else {\n        dp[i][j] = dp[i - 1][j];\n      }\n    }\n  }\n  ll ans = 0;\n  for(int j = 1; j <= V; j++) {\n    if(dp[n][j] <= W) ans = j;\n  }\n  cout << ans << '\\n';\n  return 0;\n}\n      \n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nThere are N items, numbered 1, 2, \\ldots, N.\nFor each i (1 \\leq i \\leq N), Item i has a weight of w_i and a value of v_i.\n\nTaro has decided to choose some of the N items and carry them home in a knapsack.\nThe capacity of the knapsack is W, which means that the sum of the weights of items taken must be at most W.\n\nFind the maximum possible sum of the values of items that Taro takes home.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 100\n\n1 \\leq W \\leq 10^9\n\n1 \\leq w_i \\leq W\n\n1 \\leq v_i \\leq 10^3\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN W\nw_1 v_1\nw_2 v_2\n:\nw_N v_N\n\nOutput\n\nPrint the maximum possible sum of the values of items that Taro takes home.\n\nSample Input 1\n\n3 8\n3 30\n4 50\n5 60\n\nSample Output 1\n\n90\n\nItems 1 and 3 should be taken.\nThen, the sum of the weights is 3 + 5 = 8, and the sum of the values is 30 + 60 = 90.\n\nSample Input 2\n\n1 1000000000\n1000000000 10\n\nSample Output 2\n\n10\n\nSample Input 3\n\n6 15\n6 5\n5 6\n6 4\n6 6\n3 5\n7 2\n\nSample Output 3\n\n17\n\nItems 2, 4 and 5 should be taken.\nThen, the sum of the weights is 5 + 6 + 3 = 14, and the sum of the values is 6 + 6 + 5 = 17.", "sample_input": "3 8\n3 30\n4 50\n5 60\n"}, "reference_outputs": ["90\n"], "source_document_id": "p03164", "source_text": "Score : 100 points\n\nProblem Statement\n\nThere are N items, numbered 1, 2, \\ldots, N.\nFor each i (1 \\leq i \\leq N), Item i has a weight of w_i and a value of v_i.\n\nTaro has decided to choose some of the N items and carry them home in a knapsack.\nThe capacity of the knapsack is W, which means that the sum of the weights of items taken must be at most W.\n\nFind the maximum possible sum of the values of items that Taro takes home.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 100\n\n1 \\leq W \\leq 10^9\n\n1 \\leq w_i \\leq W\n\n1 \\leq v_i \\leq 10^3\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN W\nw_1 v_1\nw_2 v_2\n:\nw_N v_N\n\nOutput\n\nPrint the maximum possible sum of the values of items that Taro takes home.\n\nSample Input 1\n\n3 8\n3 30\n4 50\n5 60\n\nSample Output 1\n\n90\n\nItems 1 and 3 should be taken.\nThen, the sum of the weights is 3 + 5 = 8, and the sum of the values is 30 + 60 = 90.\n\nSample Input 2\n\n1 1000000000\n1000000000 10\n\nSample Output 2\n\n10\n\nSample Input 3\n\n6 15\n6 5\n5 6\n6 4\n6 6\n3 5\n7 2\n\nSample Output 3\n\n17\n\nItems 2, 4 and 5 should be taken.\nThen, the sum of the weights is 5 + 6 + 3 = 14, and the sum of the values is 6 + 6 + 5 = 17.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 804, "cpu_time_ms": 76, "memory_kb": 83188}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s023902168", "group_id": "codeNet:p03164", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nconst ll inf=1e18;\nint main()\n{\n\tint n,W;\n\tcin>>n>>W;\n\tint w[n],v[n];\n\tfor(int  i=0;i<n;i++)cin>>w[i]>>v[i];\n\tll dp[1010*n];\n\tfor(int i=0;i< 1010*n;i++)dp[i]=inf;\n\tfor(int i=0;i<n;i++)\n\t{\n\t\tfor(int x= 1000*n;x>=0;x--)\n\t\t{\n\t\t\tdp[x]=min(dp[x-v[i]]+w[i], dp[x]);\n\t\t}\n\t}\n\tll a=-1;\n\tfor(int i=(1000*n);i>=0;i--)\n\t{\n\t\tif(dp[i]<=W){cout<<i+1;break;}\n\t}\n\n\t\n}", "language": "C++", "metadata": {"date": 1579137512, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03164.html", "problem_id": "p03164", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03164/input.txt", "sample_output_relpath": "derived/input_output/data/p03164/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03164/C++/s023902168.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s023902168", "user_id": "u875407613"}, "prompt_components": {"gold_output": "90\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nconst ll inf=1e18;\nint main()\n{\n\tint n,W;\n\tcin>>n>>W;\n\tint w[n],v[n];\n\tfor(int  i=0;i<n;i++)cin>>w[i]>>v[i];\n\tll dp[1010*n];\n\tfor(int i=0;i< 1010*n;i++)dp[i]=inf;\n\tfor(int i=0;i<n;i++)\n\t{\n\t\tfor(int x= 1000*n;x>=0;x--)\n\t\t{\n\t\t\tdp[x]=min(dp[x-v[i]]+w[i], dp[x]);\n\t\t}\n\t}\n\tll a=-1;\n\tfor(int i=(1000*n);i>=0;i--)\n\t{\n\t\tif(dp[i]<=W){cout<<i+1;break;}\n\t}\n\n\t\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nThere are N items, numbered 1, 2, \\ldots, N.\nFor each i (1 \\leq i \\leq N), Item i has a weight of w_i and a value of v_i.\n\nTaro has decided to choose some of the N items and carry them home in a knapsack.\nThe capacity of the knapsack is W, which means that the sum of the weights of items taken must be at most W.\n\nFind the maximum possible sum of the values of items that Taro takes home.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 100\n\n1 \\leq W \\leq 10^9\n\n1 \\leq w_i \\leq W\n\n1 \\leq v_i \\leq 10^3\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN W\nw_1 v_1\nw_2 v_2\n:\nw_N v_N\n\nOutput\n\nPrint the maximum possible sum of the values of items that Taro takes home.\n\nSample Input 1\n\n3 8\n3 30\n4 50\n5 60\n\nSample Output 1\n\n90\n\nItems 1 and 3 should be taken.\nThen, the sum of the weights is 3 + 5 = 8, and the sum of the values is 30 + 60 = 90.\n\nSample Input 2\n\n1 1000000000\n1000000000 10\n\nSample Output 2\n\n10\n\nSample Input 3\n\n6 15\n6 5\n5 6\n6 4\n6 6\n3 5\n7 2\n\nSample Output 3\n\n17\n\nItems 2, 4 and 5 should be taken.\nThen, the sum of the weights is 5 + 6 + 3 = 14, and the sum of the values is 6 + 6 + 5 = 17.", "sample_input": "3 8\n3 30\n4 50\n5 60\n"}, "reference_outputs": ["90\n"], "source_document_id": "p03164", "source_text": "Score : 100 points\n\nProblem Statement\n\nThere are N items, numbered 1, 2, \\ldots, N.\nFor each i (1 \\leq i \\leq N), Item i has a weight of w_i and a value of v_i.\n\nTaro has decided to choose some of the N items and carry them home in a knapsack.\nThe capacity of the knapsack is W, which means that the sum of the weights of items taken must be at most W.\n\nFind the maximum possible sum of the values of items that Taro takes home.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 100\n\n1 \\leq W \\leq 10^9\n\n1 \\leq w_i \\leq W\n\n1 \\leq v_i \\leq 10^3\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN W\nw_1 v_1\nw_2 v_2\n:\nw_N v_N\n\nOutput\n\nPrint the maximum possible sum of the values of items that Taro takes home.\n\nSample Input 1\n\n3 8\n3 30\n4 50\n5 60\n\nSample Output 1\n\n90\n\nItems 1 and 3 should be taken.\nThen, the sum of the weights is 3 + 5 = 8, and the sum of the values is 30 + 60 = 90.\n\nSample Input 2\n\n1 1000000000\n1000000000 10\n\nSample Output 2\n\n10\n\nSample Input 3\n\n6 15\n6 5\n5 6\n6 4\n6 6\n3 5\n7 2\n\nSample Output 3\n\n17\n\nItems 2, 4 and 5 should be taken.\nThen, the sum of the weights is 5 + 6 + 3 = 14, and the sum of the values is 6 + 6 + 5 = 17.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 417, "cpu_time_ms": 18, "memory_kb": 1024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s025439788", "group_id": "codeNet:p03164", "input_text": "#include <iostream>\n#include <vector>\n#include <limits>\n\nusing namespace std;\n\nvector <int> c(101), g(101);\n\nint main()\n{\n    int n, w;\n    long long sumMax = 0;\n    cin >> n >> w;\n\n    for (int i = 1; i <= n; i++)\n    {\n        cin >> g[i] >> c[i];\n        sumMax += c[i];\n    }\n\n    vector<vector<long long>> dp(105, vector<long long>(100005, sumMax + 1));\n\n    dp[0][0] = 0;\n    int ans = 0;\n\n    for (int i = 1; i <= n; i++)\n        for (int j = 0; j <= sumMax; j++)\n        {\n            long long localBest = dp[i - 1][j];\n\n            if (j >= c[i] && dp[i - 1][j - c[i]] != sumMax + 1)\n            {\n                localBest = dp[i - 1][j - c[i]] + g[i];\n                localBest = min(localBest, dp[i - 1][j]);\n            }\n            dp[i][j] = localBest;\n\n            if(dp[i][j] <= w)\n                ans = max(ans, j);\n        }\n\n    cout << ans;\n\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1575048066, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03164.html", "problem_id": "p03164", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03164/input.txt", "sample_output_relpath": "derived/input_output/data/p03164/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03164/C++/s025439788.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s025439788", "user_id": "u189233751"}, "prompt_components": {"gold_output": "90\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\n#include <limits>\n\nusing namespace std;\n\nvector <int> c(101), g(101);\n\nint main()\n{\n    int n, w;\n    long long sumMax = 0;\n    cin >> n >> w;\n\n    for (int i = 1; i <= n; i++)\n    {\n        cin >> g[i] >> c[i];\n        sumMax += c[i];\n    }\n\n    vector<vector<long long>> dp(105, vector<long long>(100005, sumMax + 1));\n\n    dp[0][0] = 0;\n    int ans = 0;\n\n    for (int i = 1; i <= n; i++)\n        for (int j = 0; j <= sumMax; j++)\n        {\n            long long localBest = dp[i - 1][j];\n\n            if (j >= c[i] && dp[i - 1][j - c[i]] != sumMax + 1)\n            {\n                localBest = dp[i - 1][j - c[i]] + g[i];\n                localBest = min(localBest, dp[i - 1][j]);\n            }\n            dp[i][j] = localBest;\n\n            if(dp[i][j] <= w)\n                ans = max(ans, j);\n        }\n\n    cout << ans;\n\n    return 0;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nThere are N items, numbered 1, 2, \\ldots, N.\nFor each i (1 \\leq i \\leq N), Item i has a weight of w_i and a value of v_i.\n\nTaro has decided to choose some of the N items and carry them home in a knapsack.\nThe capacity of the knapsack is W, which means that the sum of the weights of items taken must be at most W.\n\nFind the maximum possible sum of the values of items that Taro takes home.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 100\n\n1 \\leq W \\leq 10^9\n\n1 \\leq w_i \\leq W\n\n1 \\leq v_i \\leq 10^3\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN W\nw_1 v_1\nw_2 v_2\n:\nw_N v_N\n\nOutput\n\nPrint the maximum possible sum of the values of items that Taro takes home.\n\nSample Input 1\n\n3 8\n3 30\n4 50\n5 60\n\nSample Output 1\n\n90\n\nItems 1 and 3 should be taken.\nThen, the sum of the weights is 3 + 5 = 8, and the sum of the values is 30 + 60 = 90.\n\nSample Input 2\n\n1 1000000000\n1000000000 10\n\nSample Output 2\n\n10\n\nSample Input 3\n\n6 15\n6 5\n5 6\n6 4\n6 6\n3 5\n7 2\n\nSample Output 3\n\n17\n\nItems 2, 4 and 5 should be taken.\nThen, the sum of the weights is 5 + 6 + 3 = 14, and the sum of the values is 6 + 6 + 5 = 17.", "sample_input": "3 8\n3 30\n4 50\n5 60\n"}, "reference_outputs": ["90\n"], "source_document_id": "p03164", "source_text": "Score : 100 points\n\nProblem Statement\n\nThere are N items, numbered 1, 2, \\ldots, N.\nFor each i (1 \\leq i \\leq N), Item i has a weight of w_i and a value of v_i.\n\nTaro has decided to choose some of the N items and carry them home in a knapsack.\nThe capacity of the knapsack is W, which means that the sum of the weights of items taken must be at most W.\n\nFind the maximum possible sum of the values of items that Taro takes home.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 100\n\n1 \\leq W \\leq 10^9\n\n1 \\leq w_i \\leq W\n\n1 \\leq v_i \\leq 10^3\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN W\nw_1 v_1\nw_2 v_2\n:\nw_N v_N\n\nOutput\n\nPrint the maximum possible sum of the values of items that Taro takes home.\n\nSample Input 1\n\n3 8\n3 30\n4 50\n5 60\n\nSample Output 1\n\n90\n\nItems 1 and 3 should be taken.\nThen, the sum of the weights is 3 + 5 = 8, and the sum of the values is 30 + 60 = 90.\n\nSample Input 2\n\n1 1000000000\n1000000000 10\n\nSample Output 2\n\n10\n\nSample Input 3\n\n6 15\n6 5\n5 6\n6 4\n6 6\n3 5\n7 2\n\nSample Output 3\n\n17\n\nItems 2, 4 and 5 should be taken.\nThen, the sum of the weights is 5 + 6 + 3 = 14, and the sum of the values is 6 + 6 + 5 = 17.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 881, "cpu_time_ms": 57, "memory_kb": 83328}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s301454503", "group_id": "codeNet:p03164", "input_text": "#include <bits/stdc++.h>\n#define debug(a) cout <<  #a << \" = \" << a << endl;\nusing ll = long long;\nusing namespace std;\n\nconst ll inf = 100000000000000;\nconst int N = 100;\nint w[N],v[N];\nll dp[200000];\n\n// here dp[i] = minimum weight to make value exactly i \n\nint main(int argc, char const *argv[])\n{\n    int cap = 0,n;\n    for(int i =0 ;i < 200000;i++)dp[i] = inf;\n    // here dp[i] = minimum weight to make value exactly i \n    scanf(\"%d%d\",&n,&cap);\n    dp[0] = 0;\n    for(int i = 0; i < n;i++){\n        scanf(\"%d %d\",&w[i],&v[i]);\n        for(int x = 100000;x>=0;x--){\n            if(x-v[i]>=0){\n                dp[x] = min(dp[x],dp[x-v[i]]+w[i]);\n            }\n        }\n    }\n    ll ans = 0;\n    //for(int i = 0; i <= 200;i++){\n       // printf(\"%d = %lld\\n\",i,dp[i]);\n    //}\n    for(int i = 100004 ; i >=0 ; i--){\n        if(dp[i] <= cap){ans = i;break;}\n    }   \n    printf(\"%lld\\n\",ans);\n    return 0;\n}", "language": "C++", "metadata": {"date": 1561280465, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03164.html", "problem_id": "p03164", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03164/input.txt", "sample_output_relpath": "derived/input_output/data/p03164/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03164/C++/s301454503.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s301454503", "user_id": "u075800845"}, "prompt_components": {"gold_output": "90\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define debug(a) cout <<  #a << \" = \" << a << endl;\nusing ll = long long;\nusing namespace std;\n\nconst ll inf = 100000000000000;\nconst int N = 100;\nint w[N],v[N];\nll dp[200000];\n\n// here dp[i] = minimum weight to make value exactly i \n\nint main(int argc, char const *argv[])\n{\n    int cap = 0,n;\n    for(int i =0 ;i < 200000;i++)dp[i] = inf;\n    // here dp[i] = minimum weight to make value exactly i \n    scanf(\"%d%d\",&n,&cap);\n    dp[0] = 0;\n    for(int i = 0; i < n;i++){\n        scanf(\"%d %d\",&w[i],&v[i]);\n        for(int x = 100000;x>=0;x--){\n            if(x-v[i]>=0){\n                dp[x] = min(dp[x],dp[x-v[i]]+w[i]);\n            }\n        }\n    }\n    ll ans = 0;\n    //for(int i = 0; i <= 200;i++){\n       // printf(\"%d = %lld\\n\",i,dp[i]);\n    //}\n    for(int i = 100004 ; i >=0 ; i--){\n        if(dp[i] <= cap){ans = i;break;}\n    }   \n    printf(\"%lld\\n\",ans);\n    return 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nThere are N items, numbered 1, 2, \\ldots, N.\nFor each i (1 \\leq i \\leq N), Item i has a weight of w_i and a value of v_i.\n\nTaro has decided to choose some of the N items and carry them home in a knapsack.\nThe capacity of the knapsack is W, which means that the sum of the weights of items taken must be at most W.\n\nFind the maximum possible sum of the values of items that Taro takes home.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 100\n\n1 \\leq W \\leq 10^9\n\n1 \\leq w_i \\leq W\n\n1 \\leq v_i \\leq 10^3\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN W\nw_1 v_1\nw_2 v_2\n:\nw_N v_N\n\nOutput\n\nPrint the maximum possible sum of the values of items that Taro takes home.\n\nSample Input 1\n\n3 8\n3 30\n4 50\n5 60\n\nSample Output 1\n\n90\n\nItems 1 and 3 should be taken.\nThen, the sum of the weights is 3 + 5 = 8, and the sum of the values is 30 + 60 = 90.\n\nSample Input 2\n\n1 1000000000\n1000000000 10\n\nSample Output 2\n\n10\n\nSample Input 3\n\n6 15\n6 5\n5 6\n6 4\n6 6\n3 5\n7 2\n\nSample Output 3\n\n17\n\nItems 2, 4 and 5 should be taken.\nThen, the sum of the weights is 5 + 6 + 3 = 14, and the sum of the values is 6 + 6 + 5 = 17.", "sample_input": "3 8\n3 30\n4 50\n5 60\n"}, "reference_outputs": ["90\n"], "source_document_id": "p03164", "source_text": "Score : 100 points\n\nProblem Statement\n\nThere are N items, numbered 1, 2, \\ldots, N.\nFor each i (1 \\leq i \\leq N), Item i has a weight of w_i and a value of v_i.\n\nTaro has decided to choose some of the N items and carry them home in a knapsack.\nThe capacity of the knapsack is W, which means that the sum of the weights of items taken must be at most W.\n\nFind the maximum possible sum of the values of items that Taro takes home.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 100\n\n1 \\leq W \\leq 10^9\n\n1 \\leq w_i \\leq W\n\n1 \\leq v_i \\leq 10^3\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN W\nw_1 v_1\nw_2 v_2\n:\nw_N v_N\n\nOutput\n\nPrint the maximum possible sum of the values of items that Taro takes home.\n\nSample Input 1\n\n3 8\n3 30\n4 50\n5 60\n\nSample Output 1\n\n90\n\nItems 1 and 3 should be taken.\nThen, the sum of the weights is 3 + 5 = 8, and the sum of the values is 30 + 60 = 90.\n\nSample Input 2\n\n1 1000000000\n1000000000 10\n\nSample Output 2\n\n10\n\nSample Input 3\n\n6 15\n6 5\n5 6\n6 4\n6 6\n3 5\n7 2\n\nSample Output 3\n\n17\n\nItems 2, 4 and 5 should be taken.\nThen, the sum of the weights is 5 + 6 + 3 = 14, and the sum of the values is 6 + 6 + 5 = 17.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 913, "cpu_time_ms": 15, "memory_kb": 1792}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s998793848", "group_id": "codeNet:p03166", "input_text": "#include<bits/stdc++.h>\n#define forn(i,a,b) for(long long i=a;i<=b;i++)\n#define fork(i,a,b,k) for(long long i=a;i<=b;i+=k)\nusing namespace std;\ntypedef long long ll;\nvector<int>child[100005],parent[100005];\nqueue<int>q;\nint used[100005],dist[100005];\nint n,m,x[100005],y[100005],mx;\nvoid bfs(int s){\n\tdist[s]=0;\n\tq.push(s);\n\tused[s]=1;\n\twhile(!q.empty()){\n\t\tint v=q.front();\n\t\tq.pop();\n\t\tfor(int u : parent[v]){\n\t\t\tdist[u]=dist[v]+1;\n\t\t\tmx=max(mx,dist[u]);\n\t\t\tq.push(u);\n\t\t}\n\t}\n}\nint main(){\n\tios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);\n\tcin>>n>>m;\n\tfor(ll i=1;i<=m;i++){\n\t\tcin>>x[i]>>y[i];\n\t\tparent[y[i]].push_back(x[i]);\n\t\tchild[x[i]].push_back(y[i]);\n\t}\n\tfor(int i=1;i<=n;i++){\n\t\tif(child[y[i]].empty()){\n\t\t\tbfs(y[i]);\n\t\t}\n\t}\n\tcout<<mx;\n}", "language": "C++", "metadata": {"date": 1589934620, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03166.html", "problem_id": "p03166", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03166/input.txt", "sample_output_relpath": "derived/input_output/data/p03166/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03166/C++/s998793848.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s998793848", "user_id": "u584654320"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include<bits/stdc++.h>\n#define forn(i,a,b) for(long long i=a;i<=b;i++)\n#define fork(i,a,b,k) for(long long i=a;i<=b;i+=k)\nusing namespace std;\ntypedef long long ll;\nvector<int>child[100005],parent[100005];\nqueue<int>q;\nint used[100005],dist[100005];\nint n,m,x[100005],y[100005],mx;\nvoid bfs(int s){\n\tdist[s]=0;\n\tq.push(s);\n\tused[s]=1;\n\twhile(!q.empty()){\n\t\tint v=q.front();\n\t\tq.pop();\n\t\tfor(int u : parent[v]){\n\t\t\tdist[u]=dist[v]+1;\n\t\t\tmx=max(mx,dist[u]);\n\t\t\tq.push(u);\n\t\t}\n\t}\n}\nint main(){\n\tios_base::sync_with_stdio(0);cin.tie(0);cout.tie(0);\n\tcin>>n>>m;\n\tfor(ll i=1;i<=m;i++){\n\t\tcin>>x[i]>>y[i];\n\t\tparent[y[i]].push_back(x[i]);\n\t\tchild[x[i]].push_back(y[i]);\n\t}\n\tfor(int i=1;i<=n;i++){\n\t\tif(child[y[i]].empty()){\n\t\t\tbfs(y[i]);\n\t\t}\n\t}\n\tcout<<mx;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nThere is a directed graph G with N vertices and M edges.\nThe vertices are numbered 1, 2, \\ldots, N, and for each i (1 \\leq i \\leq M), the i-th directed edge goes from Vertex x_i to y_i.\nG does not contain directed cycles.\n\nFind the length of the longest directed path in G.\nHere, the length of a directed path is the number of edges in it.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq x_i, y_i \\leq N\n\nAll pairs (x_i, y_i) are distinct.\n\nG does not contain directed cycles.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nx_1 y_1\nx_2 y_2\n:\nx_M y_M\n\nOutput\n\nPrint the length of the longest directed path in G.\n\nSample Input 1\n\n4 5\n1 2\n1 3\n3 2\n2 4\n3 4\n\nSample Output 1\n\n3\n\nThe red directed path in the following figure is the longest:\n\nSample Input 2\n\n6 3\n2 3\n4 5\n5 6\n\nSample Output 2\n\n2\n\nThe red directed path in the following figure is the longest:\n\nSample Input 3\n\n5 8\n5 3\n2 3\n2 4\n5 2\n5 1\n1 4\n4 3\n1 3\n\nSample Output 3\n\n3\n\nThe red directed path in the following figure is one of the longest:", "sample_input": "4 5\n1 2\n1 3\n3 2\n2 4\n3 4\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03166", "source_text": "Score : 100 points\n\nProblem Statement\n\nThere is a directed graph G with N vertices and M edges.\nThe vertices are numbered 1, 2, \\ldots, N, and for each i (1 \\leq i \\leq M), the i-th directed edge goes from Vertex x_i to y_i.\nG does not contain directed cycles.\n\nFind the length of the longest directed path in G.\nHere, the length of a directed path is the number of edges in it.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq x_i, y_i \\leq N\n\nAll pairs (x_i, y_i) are distinct.\n\nG does not contain directed cycles.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nx_1 y_1\nx_2 y_2\n:\nx_M y_M\n\nOutput\n\nPrint the length of the longest directed path in G.\n\nSample Input 1\n\n4 5\n1 2\n1 3\n3 2\n2 4\n3 4\n\nSample Output 1\n\n3\n\nThe red directed path in the following figure is the longest:\n\nSample Input 2\n\n6 3\n2 3\n4 5\n5 6\n\nSample Output 2\n\n2\n\nThe red directed path in the following figure is the longest:\n\nSample Input 3\n\n5 8\n5 3\n2 3\n2 4\n5 2\n5 1\n1 4\n4 3\n1 3\n\nSample Output 3\n\n3\n\nThe red directed path in the following figure is one of the longest:", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 750, "cpu_time_ms": 2219, "memory_kb": 1930576}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s662930292", "group_id": "codeNet:p03166", "input_text": "#include<bits/stdc++.h>\n#define ll          long long\n#define pb          push_back\n#define endl        '\\n'\n#define pii         pair<ll int,ll int>\n#define vi          vector<ll int>\n#define all(a)      (a).begin(),(a).end()\n#define F           first\n#define S           second\n#define sz(x)       (ll int)x.size()\n#define hell        1000000001\n#define r(i,a,b)    for(i=a;i<b;i++)\n#define ra(i,a,b)   for(i=a;i<=b;i++)\n#define lbnd        lower_bound\n#define ubnd        upper_bound\n#define bs          binary_search\n#define mp          make_pair\n#define ss          set<ll int>\nusing namespace std;\n \n#define N 1000000\n#define M 100000000\n\nstruct unit {\n  ll int a[N];  \n};\n\nll fact (ll int x)\n{if(x==1 || x==0)return 1;\nelse return x*fact(x-1);}\n\nll power(ll int x,ll int n)\n{if(n==0)return 1;\nelse if(n%2 == 0)return power(x*x,n/2);\nelse return x*power(x*x,(n-1)/2);}\n\nbool cmp (const pii&a,const pii&b)\n{ return((a.F-a.S) > (b.F-b.S));\n/*if(a.S<=b.S){if(a.S==b.S)return a.F<b.F;else return a.S<b.S;}\nelse return a.S<b.S;*/}\n\n\nint main()\n{\n    cin.tie(0), cin.sync_with_stdio(0), cout.tie(0), cout.sync_with_stdio(0);\n    ll i,j,k,l,m,n,a=0,b=0;\n    cin>>n>>m;\n    vector<pii> v;\n    r(i,0,m)\n    {\n        cin>>k>>l;\n        v.pb(mp(k,l));\n    }\n    ll dp[n+1];\n    memset(dp,0,sizeof(dp));\n    r(j,0,m)\n    dp[v[j].S]=1;\n    r(j,0,m)\n    dp[v[j].S]=max(dp[v[j].S],dp[v[j].F]+1);\n    cout<<*max_element(dp,dp+n+1);\n}", "language": "C++", "metadata": {"date": 1589468801, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03166.html", "problem_id": "p03166", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03166/input.txt", "sample_output_relpath": "derived/input_output/data/p03166/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03166/C++/s662930292.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s662930292", "user_id": "u890898725"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include<bits/stdc++.h>\n#define ll          long long\n#define pb          push_back\n#define endl        '\\n'\n#define pii         pair<ll int,ll int>\n#define vi          vector<ll int>\n#define all(a)      (a).begin(),(a).end()\n#define F           first\n#define S           second\n#define sz(x)       (ll int)x.size()\n#define hell        1000000001\n#define r(i,a,b)    for(i=a;i<b;i++)\n#define ra(i,a,b)   for(i=a;i<=b;i++)\n#define lbnd        lower_bound\n#define ubnd        upper_bound\n#define bs          binary_search\n#define mp          make_pair\n#define ss          set<ll int>\nusing namespace std;\n \n#define N 1000000\n#define M 100000000\n\nstruct unit {\n  ll int a[N];  \n};\n\nll fact (ll int x)\n{if(x==1 || x==0)return 1;\nelse return x*fact(x-1);}\n\nll power(ll int x,ll int n)\n{if(n==0)return 1;\nelse if(n%2 == 0)return power(x*x,n/2);\nelse return x*power(x*x,(n-1)/2);}\n\nbool cmp (const pii&a,const pii&b)\n{ return((a.F-a.S) > (b.F-b.S));\n/*if(a.S<=b.S){if(a.S==b.S)return a.F<b.F;else return a.S<b.S;}\nelse return a.S<b.S;*/}\n\n\nint main()\n{\n    cin.tie(0), cin.sync_with_stdio(0), cout.tie(0), cout.sync_with_stdio(0);\n    ll i,j,k,l,m,n,a=0,b=0;\n    cin>>n>>m;\n    vector<pii> v;\n    r(i,0,m)\n    {\n        cin>>k>>l;\n        v.pb(mp(k,l));\n    }\n    ll dp[n+1];\n    memset(dp,0,sizeof(dp));\n    r(j,0,m)\n    dp[v[j].S]=1;\n    r(j,0,m)\n    dp[v[j].S]=max(dp[v[j].S],dp[v[j].F]+1);\n    cout<<*max_element(dp,dp+n+1);\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nThere is a directed graph G with N vertices and M edges.\nThe vertices are numbered 1, 2, \\ldots, N, and for each i (1 \\leq i \\leq M), the i-th directed edge goes from Vertex x_i to y_i.\nG does not contain directed cycles.\n\nFind the length of the longest directed path in G.\nHere, the length of a directed path is the number of edges in it.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq x_i, y_i \\leq N\n\nAll pairs (x_i, y_i) are distinct.\n\nG does not contain directed cycles.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nx_1 y_1\nx_2 y_2\n:\nx_M y_M\n\nOutput\n\nPrint the length of the longest directed path in G.\n\nSample Input 1\n\n4 5\n1 2\n1 3\n3 2\n2 4\n3 4\n\nSample Output 1\n\n3\n\nThe red directed path in the following figure is the longest:\n\nSample Input 2\n\n6 3\n2 3\n4 5\n5 6\n\nSample Output 2\n\n2\n\nThe red directed path in the following figure is the longest:\n\nSample Input 3\n\n5 8\n5 3\n2 3\n2 4\n5 2\n5 1\n1 4\n4 3\n1 3\n\nSample Output 3\n\n3\n\nThe red directed path in the following figure is one of the longest:", "sample_input": "4 5\n1 2\n1 3\n3 2\n2 4\n3 4\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03166", "source_text": "Score : 100 points\n\nProblem Statement\n\nThere is a directed graph G with N vertices and M edges.\nThe vertices are numbered 1, 2, \\ldots, N, and for each i (1 \\leq i \\leq M), the i-th directed edge goes from Vertex x_i to y_i.\nG does not contain directed cycles.\n\nFind the length of the longest directed path in G.\nHere, the length of a directed path is the number of edges in it.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq x_i, y_i \\leq N\n\nAll pairs (x_i, y_i) are distinct.\n\nG does not contain directed cycles.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nx_1 y_1\nx_2 y_2\n:\nx_M y_M\n\nOutput\n\nPrint the length of the longest directed path in G.\n\nSample Input 1\n\n4 5\n1 2\n1 3\n3 2\n2 4\n3 4\n\nSample Output 1\n\n3\n\nThe red directed path in the following figure is the longest:\n\nSample Input 2\n\n6 3\n2 3\n4 5\n5 6\n\nSample Output 2\n\n2\n\nThe red directed path in the following figure is the longest:\n\nSample Input 3\n\n5 8\n5 3\n2 3\n2 4\n5 2\n5 1\n1 4\n4 3\n1 3\n\nSample Output 3\n\n3\n\nThe red directed path in the following figure is one of the longest:", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1423, "cpu_time_ms": 18, "memory_kb": 2672}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s993710494", "group_id": "codeNet:p03166", "input_text": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nusing ll = long long;\n\nconst int INF = 1e9 + 5;\n\ntemplate<typename T>\nvoid min_self(T& a, T b)\n{\n    a = min(a,b);\n}\n\ntemplate<typename T>\nvoid max_self(T& a, T b)\n{\n    a = max(a,b);\n}\n\nconst int Nax=1e5 + 5;\n\nvector<int> edges[Nax];\nbool visited[Nax];\nint dist[Nax];\nint in[Nax];\n\nvoid dfs(int a)\n{\n    //visited[a] = true;\n    \n    for(int b: edges[a])\n    {\n        dist[b] = max(dist[b],1+dist[a]);\n        \n        if(--in[b] == 0)\n        {\n            dfs(b);\n        }\n    }\n}\n\nint main() {\n    \n    ios::sync_with_stdio(0);\n    cin.tie(0);\n\n    int N, M;\n    cin >> N >> M;\n    \n    int a, b;\n\n    while(M--)\n    {\n        cin >> a >> b;\n        edges[a].push_back(b);\n        \n        ++in[b];\n    }\n    \n    for(int i=1; i<=N; ++i)\n    {\n        if(/*!visited[i] && */in[i] == 0)\n        {\n            dfs(i);\n        }\n    }\n    \n    cout << *max_element(dist+1,dist+N+1);\n    \n}\n", "language": "C++", "metadata": {"date": 1584610238, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03166.html", "problem_id": "p03166", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03166/input.txt", "sample_output_relpath": "derived/input_output/data/p03166/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03166/C++/s993710494.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s993710494", "user_id": "u308143294"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nusing ll = long long;\n\nconst int INF = 1e9 + 5;\n\ntemplate<typename T>\nvoid min_self(T& a, T b)\n{\n    a = min(a,b);\n}\n\ntemplate<typename T>\nvoid max_self(T& a, T b)\n{\n    a = max(a,b);\n}\n\nconst int Nax=1e5 + 5;\n\nvector<int> edges[Nax];\nbool visited[Nax];\nint dist[Nax];\nint in[Nax];\n\nvoid dfs(int a)\n{\n    //visited[a] = true;\n    \n    for(int b: edges[a])\n    {\n        dist[b] = max(dist[b],1+dist[a]);\n        \n        if(--in[b] == 0)\n        {\n            dfs(b);\n        }\n    }\n}\n\nint main() {\n    \n    ios::sync_with_stdio(0);\n    cin.tie(0);\n\n    int N, M;\n    cin >> N >> M;\n    \n    int a, b;\n\n    while(M--)\n    {\n        cin >> a >> b;\n        edges[a].push_back(b);\n        \n        ++in[b];\n    }\n    \n    for(int i=1; i<=N; ++i)\n    {\n        if(/*!visited[i] && */in[i] == 0)\n        {\n            dfs(i);\n        }\n    }\n    \n    cout << *max_element(dist+1,dist+N+1);\n    \n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nThere is a directed graph G with N vertices and M edges.\nThe vertices are numbered 1, 2, \\ldots, N, and for each i (1 \\leq i \\leq M), the i-th directed edge goes from Vertex x_i to y_i.\nG does not contain directed cycles.\n\nFind the length of the longest directed path in G.\nHere, the length of a directed path is the number of edges in it.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq x_i, y_i \\leq N\n\nAll pairs (x_i, y_i) are distinct.\n\nG does not contain directed cycles.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nx_1 y_1\nx_2 y_2\n:\nx_M y_M\n\nOutput\n\nPrint the length of the longest directed path in G.\n\nSample Input 1\n\n4 5\n1 2\n1 3\n3 2\n2 4\n3 4\n\nSample Output 1\n\n3\n\nThe red directed path in the following figure is the longest:\n\nSample Input 2\n\n6 3\n2 3\n4 5\n5 6\n\nSample Output 2\n\n2\n\nThe red directed path in the following figure is the longest:\n\nSample Input 3\n\n5 8\n5 3\n2 3\n2 4\n5 2\n5 1\n1 4\n4 3\n1 3\n\nSample Output 3\n\n3\n\nThe red directed path in the following figure is one of the longest:", "sample_input": "4 5\n1 2\n1 3\n3 2\n2 4\n3 4\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03166", "source_text": "Score : 100 points\n\nProblem Statement\n\nThere is a directed graph G with N vertices and M edges.\nThe vertices are numbered 1, 2, \\ldots, N, and for each i (1 \\leq i \\leq M), the i-th directed edge goes from Vertex x_i to y_i.\nG does not contain directed cycles.\n\nFind the length of the longest directed path in G.\nHere, the length of a directed path is the number of edges in it.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq x_i, y_i \\leq N\n\nAll pairs (x_i, y_i) are distinct.\n\nG does not contain directed cycles.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nx_1 y_1\nx_2 y_2\n:\nx_M y_M\n\nOutput\n\nPrint the length of the longest directed path in G.\n\nSample Input 1\n\n4 5\n1 2\n1 3\n3 2\n2 4\n3 4\n\nSample Output 1\n\n3\n\nThe red directed path in the following figure is the longest:\n\nSample Input 2\n\n6 3\n2 3\n4 5\n5 6\n\nSample Output 2\n\n2\n\nThe red directed path in the following figure is the longest:\n\nSample Input 3\n\n5 8\n5 3\n2 3\n2 4\n5 2\n5 1\n1 4\n4 3\n1 3\n\nSample Output 3\n\n3\n\nThe red directed path in the following figure is one of the longest:", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 941, "cpu_time_ms": 33, "memory_kb": 9600}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s828004392", "group_id": "codeNet:p03167", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint h, w;\nstring m[1005];\nint dp[1005][1005];\n\nint main (){\n\t\n\tcin >> h >> w;\n\tfor (int i=0; i < h; i++)\n\t\tcin >>m[i];\n\t\t\n\tdp[0][0]=1;\n\t\t\n\tfor (int i=0; i < h; i++)\n\t\tfor (int j=0; j < w; j++)\n\t\t{\n\t\t\tif (i==0 && j==0) continue;\n\t\t\tif (m[i][j]!='#')\n\t\t\t{\n\t\t\t\tif (i>0) dp[i][j]+=dp[i-1][j];\n\t\t\t\tif (j>0) dp[i][j]+=dp[i][j-1];\n\t\t\t}\n\t\t}\n\t\t\n\t\n\tcout << dp[h-1][w-1];\n\t\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1548287429, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03167.html", "problem_id": "p03167", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03167/input.txt", "sample_output_relpath": "derived/input_output/data/p03167/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03167/C++/s828004392.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s828004392", "user_id": "u440584387"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint h, w;\nstring m[1005];\nint dp[1005][1005];\n\nint main (){\n\t\n\tcin >> h >> w;\n\tfor (int i=0; i < h; i++)\n\t\tcin >>m[i];\n\t\t\n\tdp[0][0]=1;\n\t\t\n\tfor (int i=0; i < h; i++)\n\t\tfor (int j=0; j < w; j++)\n\t\t{\n\t\t\tif (i==0 && j==0) continue;\n\t\t\tif (m[i][j]!='#')\n\t\t\t{\n\t\t\t\tif (i>0) dp[i][j]+=dp[i-1][j];\n\t\t\t\tif (j>0) dp[i][j]+=dp[i][j-1];\n\t\t\t}\n\t\t}\n\t\t\n\t\n\tcout << dp[h-1][w-1];\n\t\n\treturn 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nThere is a grid with H horizontal rows and W vertical columns.\nLet (i, j) denote the square at the i-th row from the top and the j-th column from the left.\n\nFor each i and j (1 \\leq i \\leq H, 1 \\leq j \\leq W), Square (i, j) is described by a character a_{i, j}.\nIf a_{i, j} is ., Square (i, j) is an empty square; if a_{i, j} is #, Square (i, j) is a wall square.\nIt is guaranteed that Squares (1, 1) and (H, W) are empty squares.\n\nTaro will start from Square (1, 1) and reach (H, W) by repeatedly moving right or down to an adjacent empty square.\n\nFind the number of Taro's paths from Square (1, 1) to (H, W).\nAs the answer can be extremely large, find the count modulo 10^9 + 7.\n\nConstraints\n\nH and W are integers.\n\n2 \\leq H, W \\leq 1000\n\na_{i, j} is . or #.\n\nSquares (1, 1) and (H, W) are empty squares.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W\na_{1, 1}\\ldotsa_{1, W}\n:\na_{H, 1}\\ldotsa_{H, W}\n\nOutput\n\nPrint the number of Taro's paths from Square (1, 1) to (H, W), modulo 10^9 + 7.\n\nSample Input 1\n\n3 4\n...#\n.#..\n....\n\nSample Output 1\n\n3\n\nThere are three paths as follows:\n\nSample Input 2\n\n5 2\n..\n#.\n..\n.#\n..\n\nSample Output 2\n\n0\n\nThere may be no paths.\n\nSample Input 3\n\n5 5\n..#..\n.....\n#...#\n.....\n..#..\n\nSample Output 3\n\n24\n\nSample Input 4\n\n20 20\n....................\n....................\n....................\n....................\n....................\n....................\n....................\n....................\n....................\n....................\n....................\n....................\n....................\n....................\n....................\n....................\n....................\n....................\n....................\n....................\n\nSample Output 4\n\n345263555\n\nBe sure to print the count modulo 10^9 + 7.", "sample_input": "3 4\n...#\n.#..\n....\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03167", "source_text": "Score : 100 points\n\nProblem Statement\n\nThere is a grid with H horizontal rows and W vertical columns.\nLet (i, j) denote the square at the i-th row from the top and the j-th column from the left.\n\nFor each i and j (1 \\leq i \\leq H, 1 \\leq j \\leq W), Square (i, j) is described by a character a_{i, j}.\nIf a_{i, j} is ., Square (i, j) is an empty square; if a_{i, j} is #, Square (i, j) is a wall square.\nIt is guaranteed that Squares (1, 1) and (H, W) are empty squares.\n\nTaro will start from Square (1, 1) and reach (H, W) by repeatedly moving right or down to an adjacent empty square.\n\nFind the number of Taro's paths from Square (1, 1) to (H, W).\nAs the answer can be extremely large, find the count modulo 10^9 + 7.\n\nConstraints\n\nH and W are integers.\n\n2 \\leq H, W \\leq 1000\n\na_{i, j} is . or #.\n\nSquares (1, 1) and (H, W) are empty squares.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W\na_{1, 1}\\ldotsa_{1, W}\n:\na_{H, 1}\\ldotsa_{H, W}\n\nOutput\n\nPrint the number of Taro's paths from Square (1, 1) to (H, W), modulo 10^9 + 7.\n\nSample Input 1\n\n3 4\n...#\n.#..\n....\n\nSample Output 1\n\n3\n\nThere are three paths as follows:\n\nSample Input 2\n\n5 2\n..\n#.\n..\n.#\n..\n\nSample Output 2\n\n0\n\nThere may be no paths.\n\nSample Input 3\n\n5 5\n..#..\n.....\n#...#\n.....\n..#..\n\nSample Output 3\n\n24\n\nSample Input 4\n\n20 20\n....................\n....................\n....................\n....................\n....................\n....................\n....................\n....................\n....................\n....................\n....................\n....................\n....................\n....................\n....................\n....................\n....................\n....................\n....................\n....................\n\nSample Output 4\n\n345263555\n\nBe sure to print the count modulo 10^9 + 7.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 422, "cpu_time_ms": 41, "memory_kb": 5248}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s235438369", "group_id": "codeNet:p03168", "input_text": "#include <bits/stdc++.h>\n#define lli long long int\n#define ld long double\n#define rep(i,n) for(int i = 0; i < n; i++)\n#define reps(i,a,n) for(int i = a; i < n; i++)\n#define s(n) cin >> n\n#define csl ios_base::sync_with_stdio(false); cin.tie(NULL)\n#define rsz(x,n) x.clear(); x.resize(n)\n#define rrsz(x,a,n) x.clear(); x.resize(n,a)\n#define wt while(true)\n#define all(x) x.begin(),x.end()\n#define pb push_back\n#define ls(x) ((2*(x)) + 1)\n#define rs(x) ((ls(x)) + 1)\n#define md(a,b) (((a) + (b))/2)\n#define INF (1e9 + 7)\n\nusing namespace std;\n\nint main()\n{\n    lli n;s(n);\n    vector<ld>a(n+1);\n    rep(i,n)\n    {\n        ld b;s(b);\n        a[i+1]=b;\n    }\n    vector<vector<ld>>vec(n+1,vector<ld>(n+1,0));\n    vec[0][0]=1;\n    reps(i,1,n+1)\n    vec[i][0]=vec[i-1][0]*(1-a[i]);\n    vec[1][1]=a[1];\n    reps(i,2,n+1)\n    {\n        reps(j,1,i+1)\n        {\n            vec[i][j]+=((vec[i-1][j-1])*(a[i])+(vec[i-1][j])*(1-a[i]));\n        }\n    }\n     /*reps(i,1,n+1)\n    cout<<vec[n][i]<<\" \";*/\n    \n    ld sum=0;\n    reps(i,(n/2)+1,n+1)\n    sum+=vec[n][i];\n    cout<<fixed<<setprecision(10)<<sum; \n    return 0;\n}", "language": "C++", "metadata": {"date": 1590452887, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03168.html", "problem_id": "p03168", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03168/input.txt", "sample_output_relpath": "derived/input_output/data/p03168/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03168/C++/s235438369.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s235438369", "user_id": "u837580641"}, "prompt_components": {"gold_output": "0.612\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define lli long long int\n#define ld long double\n#define rep(i,n) for(int i = 0; i < n; i++)\n#define reps(i,a,n) for(int i = a; i < n; i++)\n#define s(n) cin >> n\n#define csl ios_base::sync_with_stdio(false); cin.tie(NULL)\n#define rsz(x,n) x.clear(); x.resize(n)\n#define rrsz(x,a,n) x.clear(); x.resize(n,a)\n#define wt while(true)\n#define all(x) x.begin(),x.end()\n#define pb push_back\n#define ls(x) ((2*(x)) + 1)\n#define rs(x) ((ls(x)) + 1)\n#define md(a,b) (((a) + (b))/2)\n#define INF (1e9 + 7)\n\nusing namespace std;\n\nint main()\n{\n    lli n;s(n);\n    vector<ld>a(n+1);\n    rep(i,n)\n    {\n        ld b;s(b);\n        a[i+1]=b;\n    }\n    vector<vector<ld>>vec(n+1,vector<ld>(n+1,0));\n    vec[0][0]=1;\n    reps(i,1,n+1)\n    vec[i][0]=vec[i-1][0]*(1-a[i]);\n    vec[1][1]=a[1];\n    reps(i,2,n+1)\n    {\n        reps(j,1,i+1)\n        {\n            vec[i][j]+=((vec[i-1][j-1])*(a[i])+(vec[i-1][j])*(1-a[i]));\n        }\n    }\n     /*reps(i,1,n+1)\n    cout<<vec[n][i]<<\" \";*/\n    \n    ld sum=0;\n    reps(i,(n/2)+1,n+1)\n    sum+=vec[n][i];\n    cout<<fixed<<setprecision(10)<<sum; \n    return 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nLet N be a positive odd number.\n\nThere are N coins, numbered 1, 2, \\ldots, N.\nFor each i (1 \\leq i \\leq N), when Coin i is tossed, it comes up heads with probability p_i and tails with probability 1 - p_i.\n\nTaro has tossed all the N coins.\nFind the probability of having more heads than tails.\n\nConstraints\n\nN is an odd number.\n\n1 \\leq N \\leq 2999\n\np_i is a real number and has two decimal places.\n\n0 < p_i < 1\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\np_1 p_2 \\ldots p_N\n\nOutput\n\nPrint the probability of having more heads than tails.\nThe output is considered correct when the absolute error is not greater than 10^{-9}.\n\nSample Input 1\n\n3\n0.30 0.60 0.80\n\nSample Output 1\n\n0.612\n\nThe probability of each case where we have more heads than tails is as follows:\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Head, Head, Head) is 0.3 × 0.6 × 0.8 = 0.144;\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Tail, Head, Head) is 0.7 × 0.6 × 0.8 = 0.336;\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Head, Tail, Head) is 0.3 × 0.4 × 0.8 = 0.096;\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Head, Head, Tail) is 0.3 × 0.6 × 0.2 = 0.036.\n\nThus, the probability of having more heads than tails is 0.144 + 0.336 + 0.096 + 0.036 = 0.612.\n\nSample Input 2\n\n1\n0.50\n\nSample Output 2\n\n0.5\n\nOutputs such as 0.500, 0.500000001 and 0.499999999 are also considered correct.\n\nSample Input 3\n\n5\n0.42 0.01 0.42 0.99 0.42\n\nSample Output 3\n\n0.3821815872", "sample_input": "3\n0.30 0.60 0.80\n"}, "reference_outputs": ["0.612\n"], "source_document_id": "p03168", "source_text": "Score : 100 points\n\nProblem Statement\n\nLet N be a positive odd number.\n\nThere are N coins, numbered 1, 2, \\ldots, N.\nFor each i (1 \\leq i \\leq N), when Coin i is tossed, it comes up heads with probability p_i and tails with probability 1 - p_i.\n\nTaro has tossed all the N coins.\nFind the probability of having more heads than tails.\n\nConstraints\n\nN is an odd number.\n\n1 \\leq N \\leq 2999\n\np_i is a real number and has two decimal places.\n\n0 < p_i < 1\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\np_1 p_2 \\ldots p_N\n\nOutput\n\nPrint the probability of having more heads than tails.\nThe output is considered correct when the absolute error is not greater than 10^{-9}.\n\nSample Input 1\n\n3\n0.30 0.60 0.80\n\nSample Output 1\n\n0.612\n\nThe probability of each case where we have more heads than tails is as follows:\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Head, Head, Head) is 0.3 × 0.6 × 0.8 = 0.144;\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Tail, Head, Head) is 0.7 × 0.6 × 0.8 = 0.336;\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Head, Tail, Head) is 0.3 × 0.4 × 0.8 = 0.096;\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Head, Head, Tail) is 0.3 × 0.6 × 0.2 = 0.036.\n\nThus, the probability of having more heads than tails is 0.144 + 0.336 + 0.096 + 0.036 = 0.612.\n\nSample Input 2\n\n1\n0.50\n\nSample Output 2\n\n0.5\n\nOutputs such as 0.500, 0.500000001 and 0.499999999 are also considered correct.\n\nSample Input 3\n\n5\n0.42 0.01 0.42 0.99 0.42\n\nSample Output 3\n\n0.3821815872", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1108, "cpu_time_ms": 87, "memory_kb": 141184}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s381296720", "group_id": "codeNet:p03168", "input_text": "#include <bits/stdc++.h>\n#define maxn 3000\nusing namespace std;\n\nint n;\ndouble p[maxn];\ndouble dp[maxn][maxn];\n\nint main() {\n\tscanf(\"%d\",&n);\n\tfor( int i = 1 ; i <= n ; i++ )\n\t\tscanf(\"%lf\",&p[i]);\n\tdp[0][0] = 1;\n\tfor( int i = 1 ; i <= n ; i++ )\n\t\tfor( int j = 0 ; j <= i ; j++ ) {\n\t\t\tif(j)\n\t\t\t\tdp[i][j] = dp[i-1][j-1] * p[i];\n\t\t\tdp[i][j] += dp[i-1][j] * (1-p[i]);\n\t\t}\n\tdouble ans = 0;\n\tfor( int i = n/2+1 ; i <= n ; i++ )\n\t\tans += dp[n][i];\n\tprintf(\"%.10lf\\n\",ans);\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1585262189, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03168.html", "problem_id": "p03168", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03168/input.txt", "sample_output_relpath": "derived/input_output/data/p03168/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03168/C++/s381296720.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s381296720", "user_id": "u229051304"}, "prompt_components": {"gold_output": "0.612\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define maxn 3000\nusing namespace std;\n\nint n;\ndouble p[maxn];\ndouble dp[maxn][maxn];\n\nint main() {\n\tscanf(\"%d\",&n);\n\tfor( int i = 1 ; i <= n ; i++ )\n\t\tscanf(\"%lf\",&p[i]);\n\tdp[0][0] = 1;\n\tfor( int i = 1 ; i <= n ; i++ )\n\t\tfor( int j = 0 ; j <= i ; j++ ) {\n\t\t\tif(j)\n\t\t\t\tdp[i][j] = dp[i-1][j-1] * p[i];\n\t\t\tdp[i][j] += dp[i-1][j] * (1-p[i]);\n\t\t}\n\tdouble ans = 0;\n\tfor( int i = n/2+1 ; i <= n ; i++ )\n\t\tans += dp[n][i];\n\tprintf(\"%.10lf\\n\",ans);\n\treturn 0;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nLet N be a positive odd number.\n\nThere are N coins, numbered 1, 2, \\ldots, N.\nFor each i (1 \\leq i \\leq N), when Coin i is tossed, it comes up heads with probability p_i and tails with probability 1 - p_i.\n\nTaro has tossed all the N coins.\nFind the probability of having more heads than tails.\n\nConstraints\n\nN is an odd number.\n\n1 \\leq N \\leq 2999\n\np_i is a real number and has two decimal places.\n\n0 < p_i < 1\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\np_1 p_2 \\ldots p_N\n\nOutput\n\nPrint the probability of having more heads than tails.\nThe output is considered correct when the absolute error is not greater than 10^{-9}.\n\nSample Input 1\n\n3\n0.30 0.60 0.80\n\nSample Output 1\n\n0.612\n\nThe probability of each case where we have more heads than tails is as follows:\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Head, Head, Head) is 0.3 × 0.6 × 0.8 = 0.144;\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Tail, Head, Head) is 0.7 × 0.6 × 0.8 = 0.336;\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Head, Tail, Head) is 0.3 × 0.4 × 0.8 = 0.096;\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Head, Head, Tail) is 0.3 × 0.6 × 0.2 = 0.036.\n\nThus, the probability of having more heads than tails is 0.144 + 0.336 + 0.096 + 0.036 = 0.612.\n\nSample Input 2\n\n1\n0.50\n\nSample Output 2\n\n0.5\n\nOutputs such as 0.500, 0.500000001 and 0.499999999 are also considered correct.\n\nSample Input 3\n\n5\n0.42 0.01 0.42 0.99 0.42\n\nSample Output 3\n\n0.3821815872", "sample_input": "3\n0.30 0.60 0.80\n"}, "reference_outputs": ["0.612\n"], "source_document_id": "p03168", "source_text": "Score : 100 points\n\nProblem Statement\n\nLet N be a positive odd number.\n\nThere are N coins, numbered 1, 2, \\ldots, N.\nFor each i (1 \\leq i \\leq N), when Coin i is tossed, it comes up heads with probability p_i and tails with probability 1 - p_i.\n\nTaro has tossed all the N coins.\nFind the probability of having more heads than tails.\n\nConstraints\n\nN is an odd number.\n\n1 \\leq N \\leq 2999\n\np_i is a real number and has two decimal places.\n\n0 < p_i < 1\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\np_1 p_2 \\ldots p_N\n\nOutput\n\nPrint the probability of having more heads than tails.\nThe output is considered correct when the absolute error is not greater than 10^{-9}.\n\nSample Input 1\n\n3\n0.30 0.60 0.80\n\nSample Output 1\n\n0.612\n\nThe probability of each case where we have more heads than tails is as follows:\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Head, Head, Head) is 0.3 × 0.6 × 0.8 = 0.144;\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Tail, Head, Head) is 0.7 × 0.6 × 0.8 = 0.336;\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Head, Tail, Head) is 0.3 × 0.4 × 0.8 = 0.096;\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Head, Head, Tail) is 0.3 × 0.6 × 0.2 = 0.036.\n\nThus, the probability of having more heads than tails is 0.144 + 0.336 + 0.096 + 0.036 = 0.612.\n\nSample Input 2\n\n1\n0.50\n\nSample Output 2\n\n0.5\n\nOutputs such as 0.500, 0.500000001 and 0.499999999 are also considered correct.\n\nSample Input 3\n\n5\n0.42 0.01 0.42 0.99 0.42\n\nSample Output 3\n\n0.3821815872", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 479, "cpu_time_ms": 27, "memory_kb": 68864}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s122412104", "group_id": "codeNet:p03168", "input_text": "// Author - Saikat_7\n#include <bits/stdc++.h> \nusing namespace std;\n#define fl(i,a,b) for(int i=a;i<b;i++)\n#define trav(i,cont) for(const auto& i:cont)\n#define cs(x) cout<<x<<\" \"\n#define cn(x) cout<<x<<\" \"<<endl\n#define ll long long int\n#define endl '\\n'\n#define pb push_back\n#define ff first\n#define ss second\n#define mod 1000000007 //998244353 \n#define inf 1e17\nconst int mx = 2999; // 2* (10 to power 5);\ndouble dp[3000][3000];\ndouble coins(double arr[],int n, int h)\n{\tif(dp[n][h]==-1)\n\t{\n\tif(h==0|| n==0)\n\t\tdp[n][h]= 1;\n\telse if(h<n)\n\t\tdp[n][h]=arr[n-1]*coins(arr,n-1,h-1) + (1-arr[n-1])*coins(arr,n-1,h);\n\telse if(h==n)\n\t\tdp[n][h]=arr[n-1]*coins(arr,n-1,h-1);\n\telse\n\t\tdp[n][h]=0;\n\t\treturn dp[n][h];;\n\t}\n\telse\n\t\treturn dp[n][h];\n\n}\nint main()\n{\n    ios_base::sync_with_stdio(0);cin.tie(NULL);cout.tie(NULL);\n    int tc=1;\n    // cin>>tc;\n    while(tc-- > 0)\n    {\n   \t\tint n;\n   \t\tcin>>n;\n   \t\tdouble arr[n];\n   \t\tint h=n/2+1;\n   \t\tfor(int i=0;i<=n;i++)\n   \t\t{\n   \t\t\tfor (int j=0;j<=h;j++)\n   \t\t\t\tdp[i][j]=-1;\n   \t\t}\n   \t\tfor(int i=0;i<n;i++)\n   \t\t{\n   \t\t\tcin>>arr[i];\n   \t\t}     \n   \t\tdouble ans=coins(arr,n,(n/2)+1);\n   \t\tcout<<ans;\n    }\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1573271145, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03168.html", "problem_id": "p03168", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03168/input.txt", "sample_output_relpath": "derived/input_output/data/p03168/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03168/C++/s122412104.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s122412104", "user_id": "u426260736"}, "prompt_components": {"gold_output": "0.612\n", "input_to_evaluate": "// Author - Saikat_7\n#include <bits/stdc++.h> \nusing namespace std;\n#define fl(i,a,b) for(int i=a;i<b;i++)\n#define trav(i,cont) for(const auto& i:cont)\n#define cs(x) cout<<x<<\" \"\n#define cn(x) cout<<x<<\" \"<<endl\n#define ll long long int\n#define endl '\\n'\n#define pb push_back\n#define ff first\n#define ss second\n#define mod 1000000007 //998244353 \n#define inf 1e17\nconst int mx = 2999; // 2* (10 to power 5);\ndouble dp[3000][3000];\ndouble coins(double arr[],int n, int h)\n{\tif(dp[n][h]==-1)\n\t{\n\tif(h==0|| n==0)\n\t\tdp[n][h]= 1;\n\telse if(h<n)\n\t\tdp[n][h]=arr[n-1]*coins(arr,n-1,h-1) + (1-arr[n-1])*coins(arr,n-1,h);\n\telse if(h==n)\n\t\tdp[n][h]=arr[n-1]*coins(arr,n-1,h-1);\n\telse\n\t\tdp[n][h]=0;\n\t\treturn dp[n][h];;\n\t}\n\telse\n\t\treturn dp[n][h];\n\n}\nint main()\n{\n    ios_base::sync_with_stdio(0);cin.tie(NULL);cout.tie(NULL);\n    int tc=1;\n    // cin>>tc;\n    while(tc-- > 0)\n    {\n   \t\tint n;\n   \t\tcin>>n;\n   \t\tdouble arr[n];\n   \t\tint h=n/2+1;\n   \t\tfor(int i=0;i<=n;i++)\n   \t\t{\n   \t\t\tfor (int j=0;j<=h;j++)\n   \t\t\t\tdp[i][j]=-1;\n   \t\t}\n   \t\tfor(int i=0;i<n;i++)\n   \t\t{\n   \t\t\tcin>>arr[i];\n   \t\t}     \n   \t\tdouble ans=coins(arr,n,(n/2)+1);\n   \t\tcout<<ans;\n    }\n    return 0;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nLet N be a positive odd number.\n\nThere are N coins, numbered 1, 2, \\ldots, N.\nFor each i (1 \\leq i \\leq N), when Coin i is tossed, it comes up heads with probability p_i and tails with probability 1 - p_i.\n\nTaro has tossed all the N coins.\nFind the probability of having more heads than tails.\n\nConstraints\n\nN is an odd number.\n\n1 \\leq N \\leq 2999\n\np_i is a real number and has two decimal places.\n\n0 < p_i < 1\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\np_1 p_2 \\ldots p_N\n\nOutput\n\nPrint the probability of having more heads than tails.\nThe output is considered correct when the absolute error is not greater than 10^{-9}.\n\nSample Input 1\n\n3\n0.30 0.60 0.80\n\nSample Output 1\n\n0.612\n\nThe probability of each case where we have more heads than tails is as follows:\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Head, Head, Head) is 0.3 × 0.6 × 0.8 = 0.144;\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Tail, Head, Head) is 0.7 × 0.6 × 0.8 = 0.336;\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Head, Tail, Head) is 0.3 × 0.4 × 0.8 = 0.096;\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Head, Head, Tail) is 0.3 × 0.6 × 0.2 = 0.036.\n\nThus, the probability of having more heads than tails is 0.144 + 0.336 + 0.096 + 0.036 = 0.612.\n\nSample Input 2\n\n1\n0.50\n\nSample Output 2\n\n0.5\n\nOutputs such as 0.500, 0.500000001 and 0.499999999 are also considered correct.\n\nSample Input 3\n\n5\n0.42 0.01 0.42 0.99 0.42\n\nSample Output 3\n\n0.3821815872", "sample_input": "3\n0.30 0.60 0.80\n"}, "reference_outputs": ["0.612\n"], "source_document_id": "p03168", "source_text": "Score : 100 points\n\nProblem Statement\n\nLet N be a positive odd number.\n\nThere are N coins, numbered 1, 2, \\ldots, N.\nFor each i (1 \\leq i \\leq N), when Coin i is tossed, it comes up heads with probability p_i and tails with probability 1 - p_i.\n\nTaro has tossed all the N coins.\nFind the probability of having more heads than tails.\n\nConstraints\n\nN is an odd number.\n\n1 \\leq N \\leq 2999\n\np_i is a real number and has two decimal places.\n\n0 < p_i < 1\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\np_1 p_2 \\ldots p_N\n\nOutput\n\nPrint the probability of having more heads than tails.\nThe output is considered correct when the absolute error is not greater than 10^{-9}.\n\nSample Input 1\n\n3\n0.30 0.60 0.80\n\nSample Output 1\n\n0.612\n\nThe probability of each case where we have more heads than tails is as follows:\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Head, Head, Head) is 0.3 × 0.6 × 0.8 = 0.144;\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Tail, Head, Head) is 0.7 × 0.6 × 0.8 = 0.336;\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Head, Tail, Head) is 0.3 × 0.4 × 0.8 = 0.096;\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Head, Head, Tail) is 0.3 × 0.6 × 0.2 = 0.036.\n\nThus, the probability of having more heads than tails is 0.144 + 0.336 + 0.096 + 0.036 = 0.612.\n\nSample Input 2\n\n1\n0.50\n\nSample Output 2\n\n0.5\n\nOutputs such as 0.500, 0.500000001 and 0.499999999 are also considered correct.\n\nSample Input 3\n\n5\n0.42 0.01 0.42 0.99 0.42\n\nSample Output 3\n\n0.3821815872", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1162, "cpu_time_ms": 46, "memory_kb": 69888}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s389171947", "group_id": "codeNet:p03168", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n#define _USE_MATH_DEFINES\n\n#include <ext/pb_ds/assoc_container.hpp>\n#include <ext/pb_ds/tree_policy.hpp>\nusing namespace __gnu_pbds;\ntemplate <typename T>\nusing ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;\n\n// DON'T USE THESE MACROS DURING ICPC PRACTICE\n#define For(i,n) for (int i=0; i<n; i++)\n#define FOR(i,a,b) for (int i=a; i<=b; i++)\n#define Down(i,n) for (int i=n-1; i>=0; i--)\n#define DOWN(i,a,b) for (int i=b; i>=a; i--)\n\ntypedef long long ll;\ntypedef long double ld;\ntypedef pair<int,int> pii;\ntypedef pair<ll,ll> pll;\ntypedef pair<ld,ld> pdd;\ntypedef complex<ld> pt;\ntypedef vector<pt> pol;\ntypedef vector<int> vi;\n\nconst char nl = '\\n';\nconst int INF = 0x3f3f3f3f;\nconst ll INFLL = 0x3f3f3f3f3f3f3f3f;\nconst ll MOD = 1e9+7;\nconst ld EPS = 1e-10;\nmt19937 rng(chrono::high_resolution_clock::now().time_since_epoch().count());\n\n\n\nint main() {\n\tios::sync_with_stdio(0);\n\tcin.tie(0); cout.tie(0);\n\tcout << fixed << setprecision(17);\n\n\tint n;\n\tcin >> n;\n\n\tld p[n+1];\n\tFOR(i,1,n) {\n\t\tcin >> p[i];\n\t}\n\n\tld dp[n+1][n/2+1];\n\tfill(dp[0], dp[0]+n/2+1, 0);\n\tdp[0][0] = 1;\n\tFOR(i,1,n) {\n\t\tFor(j,n/2+1) {\n\t\t\tdp[i][j] = dp[i-1][j] * p[i];\n\t\t\tif (j>0) dp[i][j] += dp[i-1][j-1] * (1-p[i]);\n\t\t}\n\t}\n\n\tld ans = 0;\n\tFor(j,n/2+1) {\n\t\tans += dp[n][j];\n\t}\n\tcout << ans << nl;\n\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1564575382, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03168.html", "problem_id": "p03168", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03168/input.txt", "sample_output_relpath": "derived/input_output/data/p03168/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03168/C++/s389171947.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s389171947", "user_id": "u645327277"}, "prompt_components": {"gold_output": "0.612\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n#define _USE_MATH_DEFINES\n\n#include <ext/pb_ds/assoc_container.hpp>\n#include <ext/pb_ds/tree_policy.hpp>\nusing namespace __gnu_pbds;\ntemplate <typename T>\nusing ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;\n\n// DON'T USE THESE MACROS DURING ICPC PRACTICE\n#define For(i,n) for (int i=0; i<n; i++)\n#define FOR(i,a,b) for (int i=a; i<=b; i++)\n#define Down(i,n) for (int i=n-1; i>=0; i--)\n#define DOWN(i,a,b) for (int i=b; i>=a; i--)\n\ntypedef long long ll;\ntypedef long double ld;\ntypedef pair<int,int> pii;\ntypedef pair<ll,ll> pll;\ntypedef pair<ld,ld> pdd;\ntypedef complex<ld> pt;\ntypedef vector<pt> pol;\ntypedef vector<int> vi;\n\nconst char nl = '\\n';\nconst int INF = 0x3f3f3f3f;\nconst ll INFLL = 0x3f3f3f3f3f3f3f3f;\nconst ll MOD = 1e9+7;\nconst ld EPS = 1e-10;\nmt19937 rng(chrono::high_resolution_clock::now().time_since_epoch().count());\n\n\n\nint main() {\n\tios::sync_with_stdio(0);\n\tcin.tie(0); cout.tie(0);\n\tcout << fixed << setprecision(17);\n\n\tint n;\n\tcin >> n;\n\n\tld p[n+1];\n\tFOR(i,1,n) {\n\t\tcin >> p[i];\n\t}\n\n\tld dp[n+1][n/2+1];\n\tfill(dp[0], dp[0]+n/2+1, 0);\n\tdp[0][0] = 1;\n\tFOR(i,1,n) {\n\t\tFor(j,n/2+1) {\n\t\t\tdp[i][j] = dp[i-1][j] * p[i];\n\t\t\tif (j>0) dp[i][j] += dp[i-1][j-1] * (1-p[i]);\n\t\t}\n\t}\n\n\tld ans = 0;\n\tFor(j,n/2+1) {\n\t\tans += dp[n][j];\n\t}\n\tcout << ans << nl;\n\n\treturn 0;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nLet N be a positive odd number.\n\nThere are N coins, numbered 1, 2, \\ldots, N.\nFor each i (1 \\leq i \\leq N), when Coin i is tossed, it comes up heads with probability p_i and tails with probability 1 - p_i.\n\nTaro has tossed all the N coins.\nFind the probability of having more heads than tails.\n\nConstraints\n\nN is an odd number.\n\n1 \\leq N \\leq 2999\n\np_i is a real number and has two decimal places.\n\n0 < p_i < 1\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\np_1 p_2 \\ldots p_N\n\nOutput\n\nPrint the probability of having more heads than tails.\nThe output is considered correct when the absolute error is not greater than 10^{-9}.\n\nSample Input 1\n\n3\n0.30 0.60 0.80\n\nSample Output 1\n\n0.612\n\nThe probability of each case where we have more heads than tails is as follows:\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Head, Head, Head) is 0.3 × 0.6 × 0.8 = 0.144;\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Tail, Head, Head) is 0.7 × 0.6 × 0.8 = 0.336;\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Head, Tail, Head) is 0.3 × 0.4 × 0.8 = 0.096;\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Head, Head, Tail) is 0.3 × 0.6 × 0.2 = 0.036.\n\nThus, the probability of having more heads than tails is 0.144 + 0.336 + 0.096 + 0.036 = 0.612.\n\nSample Input 2\n\n1\n0.50\n\nSample Output 2\n\n0.5\n\nOutputs such as 0.500, 0.500000001 and 0.499999999 are also considered correct.\n\nSample Input 3\n\n5\n0.42 0.01 0.42 0.99 0.42\n\nSample Output 3\n\n0.3821815872", "sample_input": "3\n0.30 0.60 0.80\n"}, "reference_outputs": ["0.612\n"], "source_document_id": "p03168", "source_text": "Score : 100 points\n\nProblem Statement\n\nLet N be a positive odd number.\n\nThere are N coins, numbered 1, 2, \\ldots, N.\nFor each i (1 \\leq i \\leq N), when Coin i is tossed, it comes up heads with probability p_i and tails with probability 1 - p_i.\n\nTaro has tossed all the N coins.\nFind the probability of having more heads than tails.\n\nConstraints\n\nN is an odd number.\n\n1 \\leq N \\leq 2999\n\np_i is a real number and has two decimal places.\n\n0 < p_i < 1\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\np_1 p_2 \\ldots p_N\n\nOutput\n\nPrint the probability of having more heads than tails.\nThe output is considered correct when the absolute error is not greater than 10^{-9}.\n\nSample Input 1\n\n3\n0.30 0.60 0.80\n\nSample Output 1\n\n0.612\n\nThe probability of each case where we have more heads than tails is as follows:\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Head, Head, Head) is 0.3 × 0.6 × 0.8 = 0.144;\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Tail, Head, Head) is 0.7 × 0.6 × 0.8 = 0.336;\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Head, Tail, Head) is 0.3 × 0.4 × 0.8 = 0.096;\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Head, Head, Tail) is 0.3 × 0.6 × 0.2 = 0.036.\n\nThus, the probability of having more heads than tails is 0.144 + 0.336 + 0.096 + 0.036 = 0.612.\n\nSample Input 2\n\n1\n0.50\n\nSample Output 2\n\n0.5\n\nOutputs such as 0.500, 0.500000001 and 0.499999999 are also considered correct.\n\nSample Input 3\n\n5\n0.42 0.01 0.42 0.99 0.42\n\nSample Output 3\n\n0.3821815872", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1368, "cpu_time_ms": 39, "memory_kb": 70656}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s840390478", "group_id": "codeNet:p03168", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n#define IOS ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);\n#define trace1(x)                cerr<<#x<<\": \"<<x<<endl\n#define trace2(x, y)             cerr<<#x<<\": \"<<x<<\" | \"<<#y<<\": \"<<y<<endl\n#define trace3(x, y, z)          cerr<<#x<<\":\" <<x<<\" | \"<<#y<<\": \"<<y<<\" | \"<<#z<<\": \"<<z<<endl\n#define trace4(a, b, c, d)       cerr<<#a<<\": \"<<a<<\" | \"<<#b<<\": \"<<b<<\" | \"<<#c<<\": \"<<c<<\" | \"<<#d<<\": \"<<d<<endl\n#define trace5(a, b, c, d, e)    cerr<<#a<<\": \"<<a<<\" | \"<<#b<<\": \"<<b<<\" | \"<<#c<<\": \"<<c<<\" | \"<<#d<<\": \"<<d<<\" | \"<<#e<< \": \"<<e<<endl\n#define trace6(a, b, c, d, e, f) cerr<<#a<<\": \"<<a<<\" | \"<<#b<<\": \"<<b<<\" | \"<<#c<<\": \"<<c<<\" | \"<<#d<<\": \"<<d<<\" | \"<<#e<< \": \"<<e<<\" | \"<<#f<<\": \"<<f<<endl\n#define ll long double\n#define int long long\nint n;\nvector < long double> v;\nll dp[3000][3000];\nlong double f(int x,int y)\n{\n\tif(x==n)\n\t{\n\t\treturn y>n/2;\n\t\t\n\t}\n\tif(dp[x][y]>0)\n\t\treturn dp[x][y];\n\treturn dp[x][y]=(v[x]*f(x+1,y+1)+(1-v[x])*f(x+1,y));\n}\nint32_t main()\n{\n\tIOS;\n\tcin>>n;\n\tmemset(dp,-1,sizeof(dp));\n\tfor(int i=0;i<n;i++)\n\t{\n\t\tlong double x;\n\t\tcin>>x;\n\t\tv.push_back(x);\n\t}\n\tcout<<fixed<<setprecision(9)<<f(0,0)<<endl;\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1560220463, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03168.html", "problem_id": "p03168", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03168/input.txt", "sample_output_relpath": "derived/input_output/data/p03168/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03168/C++/s840390478.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s840390478", "user_id": "u338118278"}, "prompt_components": {"gold_output": "0.612\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n#define IOS ios::sync_with_stdio(0); cin.tie(0); cout.tie(0);\n#define trace1(x)                cerr<<#x<<\": \"<<x<<endl\n#define trace2(x, y)             cerr<<#x<<\": \"<<x<<\" | \"<<#y<<\": \"<<y<<endl\n#define trace3(x, y, z)          cerr<<#x<<\":\" <<x<<\" | \"<<#y<<\": \"<<y<<\" | \"<<#z<<\": \"<<z<<endl\n#define trace4(a, b, c, d)       cerr<<#a<<\": \"<<a<<\" | \"<<#b<<\": \"<<b<<\" | \"<<#c<<\": \"<<c<<\" | \"<<#d<<\": \"<<d<<endl\n#define trace5(a, b, c, d, e)    cerr<<#a<<\": \"<<a<<\" | \"<<#b<<\": \"<<b<<\" | \"<<#c<<\": \"<<c<<\" | \"<<#d<<\": \"<<d<<\" | \"<<#e<< \": \"<<e<<endl\n#define trace6(a, b, c, d, e, f) cerr<<#a<<\": \"<<a<<\" | \"<<#b<<\": \"<<b<<\" | \"<<#c<<\": \"<<c<<\" | \"<<#d<<\": \"<<d<<\" | \"<<#e<< \": \"<<e<<\" | \"<<#f<<\": \"<<f<<endl\n#define ll long double\n#define int long long\nint n;\nvector < long double> v;\nll dp[3000][3000];\nlong double f(int x,int y)\n{\n\tif(x==n)\n\t{\n\t\treturn y>n/2;\n\t\t\n\t}\n\tif(dp[x][y]>0)\n\t\treturn dp[x][y];\n\treturn dp[x][y]=(v[x]*f(x+1,y+1)+(1-v[x])*f(x+1,y));\n}\nint32_t main()\n{\n\tIOS;\n\tcin>>n;\n\tmemset(dp,-1,sizeof(dp));\n\tfor(int i=0;i<n;i++)\n\t{\n\t\tlong double x;\n\t\tcin>>x;\n\t\tv.push_back(x);\n\t}\n\tcout<<fixed<<setprecision(9)<<f(0,0)<<endl;\n\treturn 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nLet N be a positive odd number.\n\nThere are N coins, numbered 1, 2, \\ldots, N.\nFor each i (1 \\leq i \\leq N), when Coin i is tossed, it comes up heads with probability p_i and tails with probability 1 - p_i.\n\nTaro has tossed all the N coins.\nFind the probability of having more heads than tails.\n\nConstraints\n\nN is an odd number.\n\n1 \\leq N \\leq 2999\n\np_i is a real number and has two decimal places.\n\n0 < p_i < 1\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\np_1 p_2 \\ldots p_N\n\nOutput\n\nPrint the probability of having more heads than tails.\nThe output is considered correct when the absolute error is not greater than 10^{-9}.\n\nSample Input 1\n\n3\n0.30 0.60 0.80\n\nSample Output 1\n\n0.612\n\nThe probability of each case where we have more heads than tails is as follows:\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Head, Head, Head) is 0.3 × 0.6 × 0.8 = 0.144;\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Tail, Head, Head) is 0.7 × 0.6 × 0.8 = 0.336;\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Head, Tail, Head) is 0.3 × 0.4 × 0.8 = 0.096;\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Head, Head, Tail) is 0.3 × 0.6 × 0.2 = 0.036.\n\nThus, the probability of having more heads than tails is 0.144 + 0.336 + 0.096 + 0.036 = 0.612.\n\nSample Input 2\n\n1\n0.50\n\nSample Output 2\n\n0.5\n\nOutputs such as 0.500, 0.500000001 and 0.499999999 are also considered correct.\n\nSample Input 3\n\n5\n0.42 0.01 0.42 0.99 0.42\n\nSample Output 3\n\n0.3821815872", "sample_input": "3\n0.30 0.60 0.80\n"}, "reference_outputs": ["0.612\n"], "source_document_id": "p03168", "source_text": "Score : 100 points\n\nProblem Statement\n\nLet N be a positive odd number.\n\nThere are N coins, numbered 1, 2, \\ldots, N.\nFor each i (1 \\leq i \\leq N), when Coin i is tossed, it comes up heads with probability p_i and tails with probability 1 - p_i.\n\nTaro has tossed all the N coins.\nFind the probability of having more heads than tails.\n\nConstraints\n\nN is an odd number.\n\n1 \\leq N \\leq 2999\n\np_i is a real number and has two decimal places.\n\n0 < p_i < 1\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\np_1 p_2 \\ldots p_N\n\nOutput\n\nPrint the probability of having more heads than tails.\nThe output is considered correct when the absolute error is not greater than 10^{-9}.\n\nSample Input 1\n\n3\n0.30 0.60 0.80\n\nSample Output 1\n\n0.612\n\nThe probability of each case where we have more heads than tails is as follows:\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Head, Head, Head) is 0.3 × 0.6 × 0.8 = 0.144;\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Tail, Head, Head) is 0.7 × 0.6 × 0.8 = 0.336;\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Head, Tail, Head) is 0.3 × 0.4 × 0.8 = 0.096;\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Head, Head, Tail) is 0.3 × 0.6 × 0.2 = 0.036.\n\nThus, the probability of having more heads than tails is 0.144 + 0.336 + 0.096 + 0.036 = 0.612.\n\nSample Input 2\n\n1\n0.50\n\nSample Output 2\n\n0.5\n\nOutputs such as 0.500, 0.500000001 and 0.499999999 are also considered correct.\n\nSample Input 3\n\n5\n0.42 0.01 0.42 0.99 0.42\n\nSample Output 3\n\n0.3821815872", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1191, "cpu_time_ms": 2104, "memory_kb": 141184}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s454394751", "group_id": "codeNet:p03168", "input_text": "//#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n//#pragma GCC optimize(\"unroll-loops\")\n\n#define _CRT_SECURE_NO_WARNINGS\n#include <bits/stdc++.h>\n\nusing namespace std;\n\ntypedef pair <int, int> pii;\ntypedef pair <long long, long long> pll;\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef long double ld;\n\n#define endl \"\\n\"\n#define mt make_tuple\n#define mp make_pair\n\ntemplate <typename T1, typename T2>\nbool umax(T1 &a, const T2&b) { return a < b ? a = b, 1 : 0;}\ntemplate <typename T1, typename T2> \nbool umin(T1 &a, const T2 &b) {return a > b ? a = b, 1 : 0;}\ntemplate <typename T>\nT sqr(T a) {return a * a;}\n\nmt19937 rng(20010709);\nconst int mod = 1000000007;\nconst int INF = 1000000001;\n\nint n;\nld dp[3000][6005], p[3000];\nld result;\n\nint main() {\n    ios::sync_with_stdio(false);\n    cin.tie(nullptr);\n\n    cin >> n;\n\n    for (int i = 1; i <= n; i++)\n        cin >> p[i];\n\n    dp[0][0 + n] = 1;\n\n    for (int i = 1; i <= n; i++) {\n        for (int j = 1; j <= n * 2; j++) {\n            dp[i][j + 1] += dp[i - 1][j] * p[i];\n            dp[i][j - 1] += dp[i - 1][j] * (1.0 - p[i]);\n        }\n    }\n\n    for (int i = 1; i <= n; i++)\n        result += dp[n][i + n];\n\n    cout << fixed << setprecision(15) << result << endl;\n\n    return 0;\n}", "language": "C++", "metadata": {"date": 1546864624, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03168.html", "problem_id": "p03168", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03168/input.txt", "sample_output_relpath": "derived/input_output/data/p03168/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03168/C++/s454394751.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s454394751", "user_id": "u438783465"}, "prompt_components": {"gold_output": "0.612\n", "input_to_evaluate": "//#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n//#pragma GCC optimize(\"unroll-loops\")\n\n#define _CRT_SECURE_NO_WARNINGS\n#include <bits/stdc++.h>\n\nusing namespace std;\n\ntypedef pair <int, int> pii;\ntypedef pair <long long, long long> pll;\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef long double ld;\n\n#define endl \"\\n\"\n#define mt make_tuple\n#define mp make_pair\n\ntemplate <typename T1, typename T2>\nbool umax(T1 &a, const T2&b) { return a < b ? a = b, 1 : 0;}\ntemplate <typename T1, typename T2> \nbool umin(T1 &a, const T2 &b) {return a > b ? a = b, 1 : 0;}\ntemplate <typename T>\nT sqr(T a) {return a * a;}\n\nmt19937 rng(20010709);\nconst int mod = 1000000007;\nconst int INF = 1000000001;\n\nint n;\nld dp[3000][6005], p[3000];\nld result;\n\nint main() {\n    ios::sync_with_stdio(false);\n    cin.tie(nullptr);\n\n    cin >> n;\n\n    for (int i = 1; i <= n; i++)\n        cin >> p[i];\n\n    dp[0][0 + n] = 1;\n\n    for (int i = 1; i <= n; i++) {\n        for (int j = 1; j <= n * 2; j++) {\n            dp[i][j + 1] += dp[i - 1][j] * p[i];\n            dp[i][j - 1] += dp[i - 1][j] * (1.0 - p[i]);\n        }\n    }\n\n    for (int i = 1; i <= n; i++)\n        result += dp[n][i + n];\n\n    cout << fixed << setprecision(15) << result << endl;\n\n    return 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nLet N be a positive odd number.\n\nThere are N coins, numbered 1, 2, \\ldots, N.\nFor each i (1 \\leq i \\leq N), when Coin i is tossed, it comes up heads with probability p_i and tails with probability 1 - p_i.\n\nTaro has tossed all the N coins.\nFind the probability of having more heads than tails.\n\nConstraints\n\nN is an odd number.\n\n1 \\leq N \\leq 2999\n\np_i is a real number and has two decimal places.\n\n0 < p_i < 1\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\np_1 p_2 \\ldots p_N\n\nOutput\n\nPrint the probability of having more heads than tails.\nThe output is considered correct when the absolute error is not greater than 10^{-9}.\n\nSample Input 1\n\n3\n0.30 0.60 0.80\n\nSample Output 1\n\n0.612\n\nThe probability of each case where we have more heads than tails is as follows:\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Head, Head, Head) is 0.3 × 0.6 × 0.8 = 0.144;\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Tail, Head, Head) is 0.7 × 0.6 × 0.8 = 0.336;\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Head, Tail, Head) is 0.3 × 0.4 × 0.8 = 0.096;\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Head, Head, Tail) is 0.3 × 0.6 × 0.2 = 0.036.\n\nThus, the probability of having more heads than tails is 0.144 + 0.336 + 0.096 + 0.036 = 0.612.\n\nSample Input 2\n\n1\n0.50\n\nSample Output 2\n\n0.5\n\nOutputs such as 0.500, 0.500000001 and 0.499999999 are also considered correct.\n\nSample Input 3\n\n5\n0.42 0.01 0.42 0.99 0.42\n\nSample Output 3\n\n0.3821815872", "sample_input": "3\n0.30 0.60 0.80\n"}, "reference_outputs": ["0.612\n"], "source_document_id": "p03168", "source_text": "Score : 100 points\n\nProblem Statement\n\nLet N be a positive odd number.\n\nThere are N coins, numbered 1, 2, \\ldots, N.\nFor each i (1 \\leq i \\leq N), when Coin i is tossed, it comes up heads with probability p_i and tails with probability 1 - p_i.\n\nTaro has tossed all the N coins.\nFind the probability of having more heads than tails.\n\nConstraints\n\nN is an odd number.\n\n1 \\leq N \\leq 2999\n\np_i is a real number and has two decimal places.\n\n0 < p_i < 1\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\np_1 p_2 \\ldots p_N\n\nOutput\n\nPrint the probability of having more heads than tails.\nThe output is considered correct when the absolute error is not greater than 10^{-9}.\n\nSample Input 1\n\n3\n0.30 0.60 0.80\n\nSample Output 1\n\n0.612\n\nThe probability of each case where we have more heads than tails is as follows:\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Head, Head, Head) is 0.3 × 0.6 × 0.8 = 0.144;\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Tail, Head, Head) is 0.7 × 0.6 × 0.8 = 0.336;\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Head, Tail, Head) is 0.3 × 0.4 × 0.8 = 0.096;\n\nThe probability of having (Coin 1, Coin 2, Coin 3) = (Head, Head, Tail) is 0.3 × 0.6 × 0.2 = 0.036.\n\nThus, the probability of having more heads than tails is 0.144 + 0.336 + 0.096 + 0.036 = 0.612.\n\nSample Input 2\n\n1\n0.50\n\nSample Output 2\n\n0.5\n\nOutputs such as 0.500, 0.500000001 and 0.499999999 are also considered correct.\n\nSample Input 3\n\n5\n0.42 0.01 0.42 0.99 0.42\n\nSample Output 3\n\n0.3821815872", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1285, "cpu_time_ms": 190, "memory_kb": 281728}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s232109235", "group_id": "codeNet:p03175", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n\n#define rep(i, n) for (ll i = 0; i < (ll)(n); i++)\n#define rep1(i, n) for (ll i = 1; i <= (ll)(n); i++)\n#define INF 10000000000\n#define MOD 1000000007\nusing ll = long long;\nusing Graph = vector<vector<ll>>;\n\nll dp[100100][2];//dp[v][color]\nGraph G;\n\nll rec(int v, int color, int parent){\n    if(dp[v][color]!=-1) return dp[v][color];\n    ll res = 1;\n    for(auto nv : G[v]){\n        ll tmp = 0;\n        if(nv != parent){\n            if(!color) (tmp += rec(nv,1,v)) %= MOD;\n            (tmp += rec(nv,0,v)) %= MOD;\n            tmp %= MOD;\n            if(tmp!=0) (res *= tmp) %= MOD;\n        }\n    }\n    res %= MOD;\n    return dp[v][color] = res;\n}\n\nint main(){\n    int N; cin>>N;\n    G.resize(N);\n    rep(i,N-1){\n        int x,y; cin>>x>>y;\n        x--;y--;\n        G[x].push_back(y); G[y].push_back(x);\n    }\n    rep(i,100100)rep(j,2)dp[i][j] = -1;\n    ll res = rec(0,0,-1);\n    res += rec(0,1,-1);\n    res %= MOD;\n    cout<<res<<endl;\n}\n\n", "language": "C++", "metadata": {"date": 1599262608, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03175.html", "problem_id": "p03175", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03175/input.txt", "sample_output_relpath": "derived/input_output/data/p03175/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03175/C++/s232109235.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s232109235", "user_id": "u779216084"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n\n#define rep(i, n) for (ll i = 0; i < (ll)(n); i++)\n#define rep1(i, n) for (ll i = 1; i <= (ll)(n); i++)\n#define INF 10000000000\n#define MOD 1000000007\nusing ll = long long;\nusing Graph = vector<vector<ll>>;\n\nll dp[100100][2];//dp[v][color]\nGraph G;\n\nll rec(int v, int color, int parent){\n    if(dp[v][color]!=-1) return dp[v][color];\n    ll res = 1;\n    for(auto nv : G[v]){\n        ll tmp = 0;\n        if(nv != parent){\n            if(!color) (tmp += rec(nv,1,v)) %= MOD;\n            (tmp += rec(nv,0,v)) %= MOD;\n            tmp %= MOD;\n            if(tmp!=0) (res *= tmp) %= MOD;\n        }\n    }\n    res %= MOD;\n    return dp[v][color] = res;\n}\n\nint main(){\n    int N; cin>>N;\n    G.resize(N);\n    rep(i,N-1){\n        int x,y; cin>>x>>y;\n        x--;y--;\n        G[x].push_back(y); G[y].push_back(x);\n    }\n    rep(i,100100)rep(j,2)dp[i][j] = -1;\n    ll res = rec(0,0,-1);\n    res += rec(0,1,-1);\n    res %= MOD;\n    cout<<res<<endl;\n}\n\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nThere is a tree with N vertices, numbered 1, 2, \\ldots, N.\nFor each i (1 \\leq i \\leq N - 1), the i-th edge connects Vertex x_i and y_i.\n\nTaro has decided to paint each vertex in white or black.\nHere, it is not allowed to paint two adjacent vertices both in black.\n\nFind the number of ways in which the vertices can be painted, modulo 10^9 + 7.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq x_i, y_i \\leq N\n\nThe given graph is a tree.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nx_1 y_1\nx_2 y_2\n:\nx_{N - 1} y_{N - 1}\n\nOutput\n\nPrint the number of ways in which the vertices can be painted, modulo 10^9 + 7.\n\nSample Input 1\n\n3\n1 2\n2 3\n\nSample Output 1\n\n5\n\nThere are five ways to paint the vertices, as follows:\n\nSample Input 2\n\n4\n1 2\n1 3\n1 4\n\nSample Output 2\n\n9\n\nThere are nine ways to paint the vertices, as follows:\n\nSample Input 3\n\n1\n\nSample Output 3\n\n2\n\nSample Input 4\n\n10\n8 5\n10 8\n6 5\n1 5\n4 8\n2 10\n3 6\n9 2\n1 7\n\nSample Output 4\n\n157", "sample_input": "3\n1 2\n2 3\n"}, "reference_outputs": ["5\n"], "source_document_id": "p03175", "source_text": "Score : 100 points\n\nProblem Statement\n\nThere is a tree with N vertices, numbered 1, 2, \\ldots, N.\nFor each i (1 \\leq i \\leq N - 1), the i-th edge connects Vertex x_i and y_i.\n\nTaro has decided to paint each vertex in white or black.\nHere, it is not allowed to paint two adjacent vertices both in black.\n\nFind the number of ways in which the vertices can be painted, modulo 10^9 + 7.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq x_i, y_i \\leq N\n\nThe given graph is a tree.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nx_1 y_1\nx_2 y_2\n:\nx_{N - 1} y_{N - 1}\n\nOutput\n\nPrint the number of ways in which the vertices can be painted, modulo 10^9 + 7.\n\nSample Input 1\n\n3\n1 2\n2 3\n\nSample Output 1\n\n5\n\nThere are five ways to paint the vertices, as follows:\n\nSample Input 2\n\n4\n1 2\n1 3\n1 4\n\nSample Output 2\n\n9\n\nThere are nine ways to paint the vertices, as follows:\n\nSample Input 3\n\n1\n\nSample Output 3\n\n2\n\nSample Input 4\n\n10\n8 5\n10 8\n6 5\n1 5\n4 8\n2 10\n3 6\n9 2\n1 7\n\nSample Output 4\n\n157", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 985, "cpu_time_ms": 83, "memory_kb": 18376}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s840028821", "group_id": "codeNet:p03177", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define fr(i,j,k) for(int i=j;i<k;i++)\n#define f(n) fr(i,0,n)\n#define f1(n) fr(i,1,n+1)\n#define pb push_back\n#define F first\n#define S second\n#define all(x) x.begin(), x.end()\nconst int mod = 1e9 + 7;\nconst int maxn = 100005;\nstruct mat {\n    ll a[100][100];\n    int n;\n    mat() {\n        memset(a, 0, sizeof(a));\n    }\n    mat operator * ( const mat &b ) const {\n        mat ret;\n        ret.n =b.n;\n        for( int i = 0; i < n; ++i )\n            for( int j = 0; j < n; ++j )\n                for( int k = 0; k < n; ++k )\n                    ret.a[i][j] = ( ret.a[i][j] + a[i][k] * b.a[k][j] ) % mod;\n        return ret;\n    }\n};\nll solve(ll n, ll k) {\n\tmat now;\n\tnow.n = n;\n\tf(n) {\n\t\tfr(j,0,n) {\n\t\t\tcin >> now.a[i][j];\n\t\t}\n\t}\n\tmat ans;\n\tans.n = n;\n\tf(n) {\n\t\tans.a[i][0] = 1;\n\t}\n\twhile (k) {\n\t\tif (k & 1) {\n\t\t\tans = now * ans;\n\t\t}\n\t\tnow = now * now;\n\t\tk >>= 1;\n\t}\n\tll sum = 0;\n\tf(n) {\n\t\tsum += ans.a[i][0];\n\t\tsum %= mod;\n\t}\n\treturn sum;\n}\nvoid go() {\n\tll n, m, k;\n\tcin >> n >> k;\n\tcout << solve(n, k) << '\\n';\n\n}\nint main() {\n    ios_base::sync_with_stdio(0);\n    cin.tie(0);\n    int c = 0;\n    int t;\n    if (!c) {\n        t = 1;\n    }\n    else {\n        cin >> t;\n    }\n    while (t--) {\n        go();\n    }\n    \n}", "language": "C++", "metadata": {"date": 1597785989, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03177.html", "problem_id": "p03177", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03177/input.txt", "sample_output_relpath": "derived/input_output/data/p03177/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03177/C++/s840028821.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s840028821", "user_id": "u308590217"}, "prompt_components": {"gold_output": "6\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define fr(i,j,k) for(int i=j;i<k;i++)\n#define f(n) fr(i,0,n)\n#define f1(n) fr(i,1,n+1)\n#define pb push_back\n#define F first\n#define S second\n#define all(x) x.begin(), x.end()\nconst int mod = 1e9 + 7;\nconst int maxn = 100005;\nstruct mat {\n    ll a[100][100];\n    int n;\n    mat() {\n        memset(a, 0, sizeof(a));\n    }\n    mat operator * ( const mat &b ) const {\n        mat ret;\n        ret.n =b.n;\n        for( int i = 0; i < n; ++i )\n            for( int j = 0; j < n; ++j )\n                for( int k = 0; k < n; ++k )\n                    ret.a[i][j] = ( ret.a[i][j] + a[i][k] * b.a[k][j] ) % mod;\n        return ret;\n    }\n};\nll solve(ll n, ll k) {\n\tmat now;\n\tnow.n = n;\n\tf(n) {\n\t\tfr(j,0,n) {\n\t\t\tcin >> now.a[i][j];\n\t\t}\n\t}\n\tmat ans;\n\tans.n = n;\n\tf(n) {\n\t\tans.a[i][0] = 1;\n\t}\n\twhile (k) {\n\t\tif (k & 1) {\n\t\t\tans = now * ans;\n\t\t}\n\t\tnow = now * now;\n\t\tk >>= 1;\n\t}\n\tll sum = 0;\n\tf(n) {\n\t\tsum += ans.a[i][0];\n\t\tsum %= mod;\n\t}\n\treturn sum;\n}\nvoid go() {\n\tll n, m, k;\n\tcin >> n >> k;\n\tcout << solve(n, k) << '\\n';\n\n}\nint main() {\n    ios_base::sync_with_stdio(0);\n    cin.tie(0);\n    int c = 0;\n    int t;\n    if (!c) {\n        t = 1;\n    }\n    else {\n        cin >> t;\n    }\n    while (t--) {\n        go();\n    }\n    \n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nThere is a simple directed graph G with N vertices, numbered 1, 2, \\ldots, N.\n\nFor each i and j (1 \\leq i, j \\leq N), you are given an integer a_{i, j} that represents whether there is a directed edge from Vertex i to j.\nIf a_{i, j} = 1, there is a directed edge from Vertex i to j; if a_{i, j} = 0, there is not.\n\nFind the number of different directed paths of length K in G, modulo 10^9 + 7.\nWe will also count a path that traverses the same edge multiple times.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 50\n\n1 \\leq K \\leq 10^{18}\n\na_{i, j} is 0 or 1.\n\na_{i, i} = 0\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\na_{1, 1} \\ldots a_{1, N}\n:\na_{N, 1} \\ldots a_{N, N}\n\nOutput\n\nPrint the number of different directed paths of length K in G, modulo 10^9 + 7.\n\nSample Input 1\n\n4 2\n0 1 0 0\n0 0 1 1\n0 0 0 1\n1 0 0 0\n\nSample Output 1\n\n6\n\nG is drawn in the figure below:\n\nThere are six directed paths of length 2:\n\n1 → 2 → 3\n\n1 → 2 → 4\n\n2 → 3 → 4\n\n2 → 4 → 1\n\n3 → 4 → 1\n\n4 → 1 → 2\n\nSample Input 2\n\n3 3\n0 1 0\n1 0 1\n0 0 0\n\nSample Output 2\n\n3\n\nG is drawn in the figure below:\n\nThere are three directed paths of length 3:\n\n1 → 2 → 1 → 2\n\n2 → 1 → 2 → 1\n\n2 → 1 → 2 → 3\n\nSample Input 3\n\n6 2\n0 0 0 0 0 0\n0 0 1 0 0 0\n0 0 0 0 0 0\n0 0 0 0 1 0\n0 0 0 0 0 1\n0 0 0 0 0 0\n\nSample Output 3\n\n1\n\nG is drawn in the figure below:\n\nThere is one directed path of length 2:\n\n4 → 5 → 6\n\nSample Input 4\n\n1 1\n0\n\nSample Output 4\n\n0\n\nSample Input 5\n\n10 1000000000000000000\n0 0 1 1 0 0 0 1 1 0\n0 0 0 0 0 1 1 1 0 0\n0 1 0 0 0 1 0 1 0 1\n1 1 1 0 1 1 0 1 1 0\n0 1 1 1 0 1 0 1 1 1\n0 0 0 1 0 0 1 0 1 0\n0 0 0 1 1 0 0 1 0 1\n1 0 0 0 1 0 1 0 0 0\n0 0 0 0 0 1 0 0 0 0\n1 0 1 1 1 0 1 1 1 0\n\nSample Output 5\n\n957538352\n\nBe sure to print the count modulo 10^9 + 7.", "sample_input": "4 2\n0 1 0 0\n0 0 1 1\n0 0 0 1\n1 0 0 0\n"}, "reference_outputs": ["6\n"], "source_document_id": "p03177", "source_text": "Score : 100 points\n\nProblem Statement\n\nThere is a simple directed graph G with N vertices, numbered 1, 2, \\ldots, N.\n\nFor each i and j (1 \\leq i, j \\leq N), you are given an integer a_{i, j} that represents whether there is a directed edge from Vertex i to j.\nIf a_{i, j} = 1, there is a directed edge from Vertex i to j; if a_{i, j} = 0, there is not.\n\nFind the number of different directed paths of length K in G, modulo 10^9 + 7.\nWe will also count a path that traverses the same edge multiple times.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 50\n\n1 \\leq K \\leq 10^{18}\n\na_{i, j} is 0 or 1.\n\na_{i, i} = 0\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\na_{1, 1} \\ldots a_{1, N}\n:\na_{N, 1} \\ldots a_{N, N}\n\nOutput\n\nPrint the number of different directed paths of length K in G, modulo 10^9 + 7.\n\nSample Input 1\n\n4 2\n0 1 0 0\n0 0 1 1\n0 0 0 1\n1 0 0 0\n\nSample Output 1\n\n6\n\nG is drawn in the figure below:\n\nThere are six directed paths of length 2:\n\n1 → 2 → 3\n\n1 → 2 → 4\n\n2 → 3 → 4\n\n2 → 4 → 1\n\n3 → 4 → 1\n\n4 → 1 → 2\n\nSample Input 2\n\n3 3\n0 1 0\n1 0 1\n0 0 0\n\nSample Output 2\n\n3\n\nG is drawn in the figure below:\n\nThere are three directed paths of length 3:\n\n1 → 2 → 1 → 2\n\n2 → 1 → 2 → 1\n\n2 → 1 → 2 → 3\n\nSample Input 3\n\n6 2\n0 0 0 0 0 0\n0 0 1 0 0 0\n0 0 0 0 0 0\n0 0 0 0 1 0\n0 0 0 0 0 1\n0 0 0 0 0 0\n\nSample Output 3\n\n1\n\nG is drawn in the figure below:\n\nThere is one directed path of length 2:\n\n4 → 5 → 6\n\nSample Input 4\n\n1 1\n0\n\nSample Output 4\n\n0\n\nSample Input 5\n\n10 1000000000000000000\n0 0 1 1 0 0 0 1 1 0\n0 0 0 0 0 1 1 1 0 0\n0 1 0 0 0 1 0 1 0 1\n1 1 1 0 1 1 0 1 1 0\n0 1 1 1 0 1 0 1 1 1\n0 0 0 1 0 0 1 0 1 0\n0 0 0 1 1 0 0 1 0 1\n1 0 0 0 1 0 1 0 0 0\n0 0 0 0 0 1 0 0 0 0\n1 0 1 1 1 0 1 1 1 0\n\nSample Output 5\n\n957538352\n\nBe sure to print the count modulo 10^9 + 7.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1286, "cpu_time_ms": 57, "memory_kb": 3864}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s551338760", "group_id": "codeNet:p03178", "input_text": "#include <bits/stdc++.h>\n#define int long long\n#define maxn 10005\n#define maxc 105\nusing namespace std;\n\nconst int mod = 1e9 + 7;\n\n//     len   sum  last\nint dp[maxn][maxc][10] = {};\nstring s;\nint n, k;\n\nint32_t main() {\n    ios_base::sync_with_stdio(false);\n    cin.tie(nullptr);\n    cin >> s >> k;\n    reverse(begin(s), end(s));\n    n = s.size(); s = \"@\" + s;\n    for(int i = 0; i < 10; i++) {\n        dp[1][i % k][i] = 1;\n    }\n    for(int len = 2; len <= n; len++) {\n        for(int sum = 0; sum < k; sum++) {\n            for(int last = 0; last < 10; last++) {\n                int prev = (sum - last + k) % k;\n                for(int i = 0; i < 10; i++)\n                dp[len][sum][last] += dp[len - 1][prev][i];\n                dp[len][sum][last] %= mod;\n            }\n        }\n    }\n    int ans = 0, cnt = 0;\n    for(int i = n; i > 0; i--) {\n        for(int j = 0; j < (s[i] - '0'); j++) {\n            int prev = (k - cnt + k) % k;\n            ans += dp[i][prev][j];\n        }\n        ans %= mod;\n        cnt += s[i] - '0';\n    }\n    if(cnt % k == 0) ans++;\n    ans = (ans - 1 + mod) % mod;\n    cout << ans << '\\n';\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1598137053, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03178.html", "problem_id": "p03178", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03178/input.txt", "sample_output_relpath": "derived/input_output/data/p03178/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03178/C++/s551338760.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s551338760", "user_id": "u635731706"}, "prompt_components": {"gold_output": "6\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define int long long\n#define maxn 10005\n#define maxc 105\nusing namespace std;\n\nconst int mod = 1e9 + 7;\n\n//     len   sum  last\nint dp[maxn][maxc][10] = {};\nstring s;\nint n, k;\n\nint32_t main() {\n    ios_base::sync_with_stdio(false);\n    cin.tie(nullptr);\n    cin >> s >> k;\n    reverse(begin(s), end(s));\n    n = s.size(); s = \"@\" + s;\n    for(int i = 0; i < 10; i++) {\n        dp[1][i % k][i] = 1;\n    }\n    for(int len = 2; len <= n; len++) {\n        for(int sum = 0; sum < k; sum++) {\n            for(int last = 0; last < 10; last++) {\n                int prev = (sum - last + k) % k;\n                for(int i = 0; i < 10; i++)\n                dp[len][sum][last] += dp[len - 1][prev][i];\n                dp[len][sum][last] %= mod;\n            }\n        }\n    }\n    int ans = 0, cnt = 0;\n    for(int i = n; i > 0; i--) {\n        for(int j = 0; j < (s[i] - '0'); j++) {\n            int prev = (k - cnt + k) % k;\n            ans += dp[i][prev][j];\n        }\n        ans %= mod;\n        cnt += s[i] - '0';\n    }\n    if(cnt % k == 0) ans++;\n    ans = (ans - 1 + mod) % mod;\n    cout << ans << '\\n';\n    return 0;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nFind the number of integers between 1 and K (inclusive) satisfying the following condition, modulo 10^9 + 7:\n\nThe sum of the digits in base ten is a multiple of D.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq K < 10^{10000}\n\n1 \\leq D \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nK\nD\n\nOutput\n\nPrint the number of integers satisfying the condition, modulo 10^9 + 7.\n\nSample Input 1\n\n30\n4\n\nSample Output 1\n\n6\n\nThose six integers are: 4, 8, 13, 17, 22 and 26.\n\nSample Input 2\n\n1000000009\n1\n\nSample Output 2\n\n2\n\nBe sure to print the number modulo 10^9 + 7.\n\nSample Input 3\n\n98765432109876543210\n58\n\nSample Output 3\n\n635270834", "sample_input": "30\n4\n"}, "reference_outputs": ["6\n"], "source_document_id": "p03178", "source_text": "Score : 100 points\n\nProblem Statement\n\nFind the number of integers between 1 and K (inclusive) satisfying the following condition, modulo 10^9 + 7:\n\nThe sum of the digits in base ten is a multiple of D.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq K < 10^{10000}\n\n1 \\leq D \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nK\nD\n\nOutput\n\nPrint the number of integers satisfying the condition, modulo 10^9 + 7.\n\nSample Input 1\n\n30\n4\n\nSample Output 1\n\n6\n\nThose six integers are: 4, 8, 13, 17, 22 and 26.\n\nSample Input 2\n\n1000000009\n1\n\nSample Output 2\n\n2\n\nBe sure to print the number modulo 10^9 + 7.\n\nSample Input 3\n\n98765432109876543210\n58\n\nSample Output 3\n\n635270834", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1140, "cpu_time_ms": 212, "memory_kb": 85696}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s695061280", "group_id": "codeNet:p03178", "input_text": "#include<iostream>\n#include<string.h>\n#include<string>\n#include<stdio.h>\n#include<algorithm>\n#include<vector>\n#include<math.h>\n#include<queue>\n#include<set>\n#include<map>\nusing namespace std;\ntypedef long long ll;\ntypedef long double db;\ntypedef pair<int,int> pii;\nconst int N=10000;\nconst db pi=acos(-1.0);\n#define lowbit(x) (x)&(-x)\n#define sqr(x) (x)*(x)\n#define rep(i,a,b) for (register int i=a;i<=b;i++)\n#define per(i,a,b) for (register int i=a;i>=b;i--)\n#define fir first\n#define sec second\n#define mp(a,b) make_pair(a,b)\n#define pb(a) push_back(a)\n#define maxd 1000000007\n#define eps 1e-8\nint n,d,a[100100],dp[10010][110][2];\nchar s[100100];\n\nint read()\n{\n    int x=0,f=1;char ch=getchar();\n    while ((ch<'0') || (ch>'9')) {if (ch=='-') f=-1;ch=getchar();}\n    while ((ch>='0') && (ch<='9')) {x=x*10+(ch-'0');ch=getchar();}\n    return x*f;\n}\n\nint dfs(int pos,int mod,int lim)\n{\n\tif (pos>n) dp[pos][mod][lim]=(mod==0);\n\tif (dp[pos][mod][lim]>-1) return dp[pos][mod][lim];\n\tint sum=0,up=9;\n\tif (lim) up=a[pos];\n\trep(i,0,up)\n\t{\n\t\tint tmp=dfs(pos+1,(mod+i)%d,lim&&(i==up));\n\t\tsum=(sum+tmp)%maxd;\n\t}\n\tdp[pos][mod][lim]=sum;\n\treturn sum;\n}\n\nint main()\n{\n\tscanf(\"%s\",s+1);d=read();n=strlen(s+1);\n\trep(i,1,n) a[i]=s[i]-'0';\n\tmemset(dp,-1,sizeof(dp));\n\tprintf(\"%d\",(dfs(1,0,1)+maxd-1)%maxd);\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1566018448, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03178.html", "problem_id": "p03178", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03178/input.txt", "sample_output_relpath": "derived/input_output/data/p03178/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03178/C++/s695061280.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s695061280", "user_id": "u340402002"}, "prompt_components": {"gold_output": "6\n", "input_to_evaluate": "#include<iostream>\n#include<string.h>\n#include<string>\n#include<stdio.h>\n#include<algorithm>\n#include<vector>\n#include<math.h>\n#include<queue>\n#include<set>\n#include<map>\nusing namespace std;\ntypedef long long ll;\ntypedef long double db;\ntypedef pair<int,int> pii;\nconst int N=10000;\nconst db pi=acos(-1.0);\n#define lowbit(x) (x)&(-x)\n#define sqr(x) (x)*(x)\n#define rep(i,a,b) for (register int i=a;i<=b;i++)\n#define per(i,a,b) for (register int i=a;i>=b;i--)\n#define fir first\n#define sec second\n#define mp(a,b) make_pair(a,b)\n#define pb(a) push_back(a)\n#define maxd 1000000007\n#define eps 1e-8\nint n,d,a[100100],dp[10010][110][2];\nchar s[100100];\n\nint read()\n{\n    int x=0,f=1;char ch=getchar();\n    while ((ch<'0') || (ch>'9')) {if (ch=='-') f=-1;ch=getchar();}\n    while ((ch>='0') && (ch<='9')) {x=x*10+(ch-'0');ch=getchar();}\n    return x*f;\n}\n\nint dfs(int pos,int mod,int lim)\n{\n\tif (pos>n) dp[pos][mod][lim]=(mod==0);\n\tif (dp[pos][mod][lim]>-1) return dp[pos][mod][lim];\n\tint sum=0,up=9;\n\tif (lim) up=a[pos];\n\trep(i,0,up)\n\t{\n\t\tint tmp=dfs(pos+1,(mod+i)%d,lim&&(i==up));\n\t\tsum=(sum+tmp)%maxd;\n\t}\n\tdp[pos][mod][lim]=sum;\n\treturn sum;\n}\n\nint main()\n{\n\tscanf(\"%s\",s+1);d=read();n=strlen(s+1);\n\trep(i,1,n) a[i]=s[i]-'0';\n\tmemset(dp,-1,sizeof(dp));\n\tprintf(\"%d\",(dfs(1,0,1)+maxd-1)%maxd);\n\treturn 0;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nFind the number of integers between 1 and K (inclusive) satisfying the following condition, modulo 10^9 + 7:\n\nThe sum of the digits in base ten is a multiple of D.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq K < 10^{10000}\n\n1 \\leq D \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nK\nD\n\nOutput\n\nPrint the number of integers satisfying the condition, modulo 10^9 + 7.\n\nSample Input 1\n\n30\n4\n\nSample Output 1\n\n6\n\nThose six integers are: 4, 8, 13, 17, 22 and 26.\n\nSample Input 2\n\n1000000009\n1\n\nSample Output 2\n\n2\n\nBe sure to print the number modulo 10^9 + 7.\n\nSample Input 3\n\n98765432109876543210\n58\n\nSample Output 3\n\n635270834", "sample_input": "30\n4\n"}, "reference_outputs": ["6\n"], "source_document_id": "p03178", "source_text": "Score : 100 points\n\nProblem Statement\n\nFind the number of integers between 1 and K (inclusive) satisfying the following condition, modulo 10^9 + 7:\n\nThe sum of the digits in base ten is a multiple of D.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq K < 10^{10000}\n\n1 \\leq D \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nK\nD\n\nOutput\n\nPrint the number of integers satisfying the condition, modulo 10^9 + 7.\n\nSample Input 1\n\n30\n4\n\nSample Output 1\n\n6\n\nThose six integers are: 4, 8, 13, 17, 22 and 26.\n\nSample Input 2\n\n1000000009\n1\n\nSample Output 2\n\n2\n\nBe sure to print the number modulo 10^9 + 7.\n\nSample Input 3\n\n98765432109876543210\n58\n\nSample Output 3\n\n635270834", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1304, "cpu_time_ms": 69, "memory_kb": 9728}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s401697873", "group_id": "codeNet:p03187", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n\ntypedef long long lint;\ntypedef long double louble;\n\ntemplate<typename T1,typename T2> inline T1 max(T1 a,T2 b){return a<b?b:a;}\ntemplate<typename T1,typename T2> inline T1 min(T1 a,T2 b){return a<b?a:b;}\n\nnamespace ae86\n{\n\tconst int bufl = 1<<15;\n\t\n\tchar buf[bufl],*s=buf,*t=buf;\n\t\n\tinline int fetch()\n\t{\n\t\tif(s==t){t=(s=buf)+fread(buf,1,bufl,stdin);if(s==t)return EOF;}\n\t\treturn *s++;\n\t}\n\t\n\tinline int ty()\n\t{\n\t\tint a=0,b=1,c=fetch();\n\t\twhile(!isdigit(c))b^=c=='-',c=fetch();\n\t\twhile(isdigit(c))a=a*10+c-48,c=fetch();\n\t\treturn b?a:-a;\n\t}\n}\nusing ae86::ty;\n\nconst int _ = 200007;\n\nint n,dis[_],rdis[_],len;\nlint s[_]={0},sr[_]={0};\n\ninline lint sum(lint f[],int l,int r){return f[r]-f[l-1];}\n\ninline lint finder()\n{\n\tlint ans=0;\n\tfor(int i=1;i<=n;i++)\n\t{\n\t\tint rx=(n-i)>>1,x=n-i-rx;\n\t\tans=max(ans,(sum(s,i,i+x-1)+sum(sr,n-rx+1,n))*2+(((n-i)&1)?rdis[n-rx]:dis[n-x]));\n\t}\n\treturn ans;\n}\n\nint main()\n{\n\tlen=ty(),n=ty();\n\tfor(int i=1;i<=n;i++)dis[i]=ty(),rdis[i]=len-dis[i],s[i]=s[i-1]+dis[i],sr[i]=sr[i-1]+rdis[i];\n\tlint ans=finder();\n\tfor(int i=1;i<=n;i++)dis[i]=len-dis[i];\n\treverse(dis+1,dis+n+1);\n\tfor(int i=1;i<=n;i++)rdis[i]=len-dis[i],s[i]=s[i-1]+dis[i],sr[i]=sr[i-1]+rdis[i];\n\tans=max(ans,finder());\n\tprintf(\"%lld\\n\",ans);\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1576467353, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03187.html", "problem_id": "p03187", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03187/input.txt", "sample_output_relpath": "derived/input_output/data/p03187/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03187/C++/s401697873.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s401697873", "user_id": "u326034736"}, "prompt_components": {"gold_output": "15\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n\ntypedef long long lint;\ntypedef long double louble;\n\ntemplate<typename T1,typename T2> inline T1 max(T1 a,T2 b){return a<b?b:a;}\ntemplate<typename T1,typename T2> inline T1 min(T1 a,T2 b){return a<b?a:b;}\n\nnamespace ae86\n{\n\tconst int bufl = 1<<15;\n\t\n\tchar buf[bufl],*s=buf,*t=buf;\n\t\n\tinline int fetch()\n\t{\n\t\tif(s==t){t=(s=buf)+fread(buf,1,bufl,stdin);if(s==t)return EOF;}\n\t\treturn *s++;\n\t}\n\t\n\tinline int ty()\n\t{\n\t\tint a=0,b=1,c=fetch();\n\t\twhile(!isdigit(c))b^=c=='-',c=fetch();\n\t\twhile(isdigit(c))a=a*10+c-48,c=fetch();\n\t\treturn b?a:-a;\n\t}\n}\nusing ae86::ty;\n\nconst int _ = 200007;\n\nint n,dis[_],rdis[_],len;\nlint s[_]={0},sr[_]={0};\n\ninline lint sum(lint f[],int l,int r){return f[r]-f[l-1];}\n\ninline lint finder()\n{\n\tlint ans=0;\n\tfor(int i=1;i<=n;i++)\n\t{\n\t\tint rx=(n-i)>>1,x=n-i-rx;\n\t\tans=max(ans,(sum(s,i,i+x-1)+sum(sr,n-rx+1,n))*2+(((n-i)&1)?rdis[n-rx]:dis[n-x]));\n\t}\n\treturn ans;\n}\n\nint main()\n{\n\tlen=ty(),n=ty();\n\tfor(int i=1;i<=n;i++)dis[i]=ty(),rdis[i]=len-dis[i],s[i]=s[i-1]+dis[i],sr[i]=sr[i-1]+rdis[i];\n\tlint ans=finder();\n\tfor(int i=1;i<=n;i++)dis[i]=len-dis[i];\n\treverse(dis+1,dis+n+1);\n\tfor(int i=1;i<=n;i++)rdis[i]=len-dis[i],s[i]=s[i-1]+dis[i],sr[i]=sr[i-1]+rdis[i];\n\tans=max(ans,finder());\n\tprintf(\"%lld\\n\",ans);\n\treturn 0;\n}\n", "problem_context": "Score : 800 points\n\nProblem Statement\n\nTakahashi Lake has a perimeter of L. On the circumference of the lake, there is a residence of the lake's owner, Takahashi.\nEach point on the circumference of the lake has a coordinate between 0 and L (including 0 but not L), which is the distance from the Takahashi's residence, measured counter-clockwise.\n\nThere are N trees around the lake; the coordinate of the i-th tree is X_i. There is no tree at coordinate 0, the location of Takahashi's residence.\n\nStarting at his residence, Takahashi will repeat the following action:\n\nIf all trees are burnt, terminate the process.\n\nSpecify a direction: clockwise or counter-clockwise.\n\nWalk around the lake in the specified direction, until the coordinate of a tree that is not yet burnt is reached for the first time.\n\nWhen the coordinate with the tree is reached, burn that tree, stay at the position and go back to the first step.\n\nFind the longest possible total distance Takahashi walks during the process.\n\nPartial Score\n\nA partial score can be obtained in this problem:\n\n300 points will be awarded for passing the input satisfying N \\leq 2000.\n\nConstraints\n\n2 \\leq L \\leq 10^9\n\n1 \\leq N \\leq 2\\times 10^5\n\n1 \\leq X_1 < ... < X_N \\leq L-1\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nL N\nX_1\n:\nX_N\n\nOutput\n\nPrint the longest possible total distance Takahashi walks during the process.\n\nSample Input 1\n\n10 3\n2\n7\n9\n\nSample Output 1\n\n15\n\nTakahashi walks the distance of 15 if the process goes as follows:\n\nWalk a distance of 2 counter-clockwise, burn the tree at the coordinate 2 and stay there.\n\nWalk a distance of 5 counter-clockwise, burn the tree at the coordinate 7 and stay there.\n\nWalk a distance of 8 clockwise, burn the tree at the coordinate 9 and stay there.\n\nSample Input 2\n\n10 6\n1\n2\n3\n6\n7\n9\n\nSample Output 2\n\n27\n\nSample Input 3\n\n314159265 7\n21662711\n77271666\n89022761\n156626166\n160332356\n166902656\n298992265\n\nSample Output 3\n\n1204124749", "sample_input": "10 3\n2\n7\n9\n"}, "reference_outputs": ["15\n"], "source_document_id": "p03187", "source_text": "Score : 800 points\n\nProblem Statement\n\nTakahashi Lake has a perimeter of L. On the circumference of the lake, there is a residence of the lake's owner, Takahashi.\nEach point on the circumference of the lake has a coordinate between 0 and L (including 0 but not L), which is the distance from the Takahashi's residence, measured counter-clockwise.\n\nThere are N trees around the lake; the coordinate of the i-th tree is X_i. There is no tree at coordinate 0, the location of Takahashi's residence.\n\nStarting at his residence, Takahashi will repeat the following action:\n\nIf all trees are burnt, terminate the process.\n\nSpecify a direction: clockwise or counter-clockwise.\n\nWalk around the lake in the specified direction, until the coordinate of a tree that is not yet burnt is reached for the first time.\n\nWhen the coordinate with the tree is reached, burn that tree, stay at the position and go back to the first step.\n\nFind the longest possible total distance Takahashi walks during the process.\n\nPartial Score\n\nA partial score can be obtained in this problem:\n\n300 points will be awarded for passing the input satisfying N \\leq 2000.\n\nConstraints\n\n2 \\leq L \\leq 10^9\n\n1 \\leq N \\leq 2\\times 10^5\n\n1 \\leq X_1 < ... < X_N \\leq L-1\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nL N\nX_1\n:\nX_N\n\nOutput\n\nPrint the longest possible total distance Takahashi walks during the process.\n\nSample Input 1\n\n10 3\n2\n7\n9\n\nSample Output 1\n\n15\n\nTakahashi walks the distance of 15 if the process goes as follows:\n\nWalk a distance of 2 counter-clockwise, burn the tree at the coordinate 2 and stay there.\n\nWalk a distance of 5 counter-clockwise, burn the tree at the coordinate 7 and stay there.\n\nWalk a distance of 8 clockwise, burn the tree at the coordinate 9 and stay there.\n\nSample Input 2\n\n10 6\n1\n2\n3\n6\n7\n9\n\nSample Output 2\n\n27\n\nSample Input 3\n\n314159265 7\n21662711\n77271666\n89022761\n156626166\n160332356\n166902656\n298992265\n\nSample Output 3\n\n1204124749", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1288, "cpu_time_ms": 8, "memory_kb": 4992}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s346859959", "group_id": "codeNet:p03194", "input_text": "#include <iostream>\n#include <string>\n#include <algorithm>\n#include <functional>\n#include <vector>\n#include <utility>\n#include <cstring>\n#include <iomanip>\n#include <numeric>\n#include <cmath>\n#include <queue>\n#include <map>\nusing namespace std;\ntypedef long long ll;\nconst int INF = 1<<30; \nconst int MOD = 1e9 + 7;\nconst int dy[] = {1, 0, -1, 0};\nconst int dx[] = {0, 1, 0, -1};\nmap<ll, ll> mp;\nvoid prime_factor(ll n)\n{\n    for(int i = 2; i * i <= n; i++)\n    {\n        while (n % i == 0)\n        {\n            mp[i]++;\n            n /= i;\n        }\n    }\n    if (n != 1) mp[n] = 1;\n}\nint main()\n{\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n    ll n, p;\n    cin >> n >> p;\n    prime_factor(p);\n    ll ans = 1LL;\n    if(n == 1) cout << p << endl;\n    else\n    {\n        for(auto x : mp)\n        {\n            if(x.second >= n)\n            {\n                ans *= x.first * (x.second / n);\n            }\n        }\n        cout << ans << endl;\n    }\n    return 0;\n}\n\n", "language": "C++", "metadata": {"date": 1545534145, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03194.html", "problem_id": "p03194", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03194/input.txt", "sample_output_relpath": "derived/input_output/data/p03194/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03194/C++/s346859959.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s346859959", "user_id": "u952094438"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <iostream>\n#include <string>\n#include <algorithm>\n#include <functional>\n#include <vector>\n#include <utility>\n#include <cstring>\n#include <iomanip>\n#include <numeric>\n#include <cmath>\n#include <queue>\n#include <map>\nusing namespace std;\ntypedef long long ll;\nconst int INF = 1<<30; \nconst int MOD = 1e9 + 7;\nconst int dy[] = {1, 0, -1, 0};\nconst int dx[] = {0, 1, 0, -1};\nmap<ll, ll> mp;\nvoid prime_factor(ll n)\n{\n    for(int i = 2; i * i <= n; i++)\n    {\n        while (n % i == 0)\n        {\n            mp[i]++;\n            n /= i;\n        }\n    }\n    if (n != 1) mp[n] = 1;\n}\nint main()\n{\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n    ll n, p;\n    cin >> n >> p;\n    prime_factor(p);\n    ll ans = 1LL;\n    if(n == 1) cout << p << endl;\n    else\n    {\n        for(auto x : mp)\n        {\n            if(x.second >= n)\n            {\n                ans *= x.first * (x.second / n);\n            }\n        }\n        cout << ans << endl;\n    }\n    return 0;\n}\n\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N integers a_1, a_2, ..., a_N not less than 1.\nThe values of a_1, a_2, ..., a_N are not known, but it is known that a_1 \\times a_2 \\times ... \\times a_N = P.\n\nFind the maximum possible greatest common divisor of a_1, a_2, ..., a_N.\n\nConstraints\n\n1 \\leq N \\leq 10^{12}\n\n1 \\leq P \\leq 10^{12}\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN P\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n3 24\n\nSample Output 1\n\n2\n\nThe greatest common divisor would be 2 when, for example, a_1=2, a_2=6 and a_3=2.\n\nSample Input 2\n\n5 1\n\nSample Output 2\n\n1\n\nAs a_i are positive integers, the only possible case is a_1 = a_2 = a_3 = a_4 = a_5 = 1.\n\nSample Input 3\n\n1 111\n\nSample Output 3\n\n111\n\nSample Input 4\n\n4 972439611840\n\nSample Output 4\n\n206", "sample_input": "3 24\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03194", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N integers a_1, a_2, ..., a_N not less than 1.\nThe values of a_1, a_2, ..., a_N are not known, but it is known that a_1 \\times a_2 \\times ... \\times a_N = P.\n\nFind the maximum possible greatest common divisor of a_1, a_2, ..., a_N.\n\nConstraints\n\n1 \\leq N \\leq 10^{12}\n\n1 \\leq P \\leq 10^{12}\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN P\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n3 24\n\nSample Output 1\n\n2\n\nThe greatest common divisor would be 2 when, for example, a_1=2, a_2=6 and a_3=2.\n\nSample Input 2\n\n5 1\n\nSample Output 2\n\n1\n\nAs a_i are positive integers, the only possible case is a_1 = a_2 = a_3 = a_4 = a_5 = 1.\n\nSample Input 3\n\n1 111\n\nSample Output 3\n\n111\n\nSample Input 4\n\n4 972439611840\n\nSample Output 4\n\n206", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 973, "cpu_time_ms": 2103, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s334347386", "group_id": "codeNet:p03196", "input_text": "#include <bits/stdc++.h>\n#define fr(i, n, m) for(int i = (n); i < (m); i ++)\n#define pb push_back\n#define pq priority_queue\n#define st first\n#define nd second\n\nusing namespace std;\ntypedef long long ll;\nll const inf = 1e9;\nll const mod = 998244353  ;\n\nint main()\n{\n    ll n, p;\n    cin >> n >> p;\n    ll prime = 2;\n    ll c = 0;\n    ll gcd = 1;\n    while(p > 1){\n        if(p % prime == 0){\n            c ++;\n            p /= prime;\n        }\n        else{\n            gcd = gcd * max(1LL, (c / n) * prime);\n            c = 0;\n            prime ++;\n        }\n\n    }\n    if(c > 0) gcd = gcd * max(1LL, c / n * prime);\n    cout << gcd << endl;\n\n    return 0;\n\n}\n", "language": "C++", "metadata": {"date": 1546074946, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03196.html", "problem_id": "p03196", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03196/input.txt", "sample_output_relpath": "derived/input_output/data/p03196/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03196/C++/s334347386.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s334347386", "user_id": "u858402748"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define fr(i, n, m) for(int i = (n); i < (m); i ++)\n#define pb push_back\n#define pq priority_queue\n#define st first\n#define nd second\n\nusing namespace std;\ntypedef long long ll;\nll const inf = 1e9;\nll const mod = 998244353  ;\n\nint main()\n{\n    ll n, p;\n    cin >> n >> p;\n    ll prime = 2;\n    ll c = 0;\n    ll gcd = 1;\n    while(p > 1){\n        if(p % prime == 0){\n            c ++;\n            p /= prime;\n        }\n        else{\n            gcd = gcd * max(1LL, (c / n) * prime);\n            c = 0;\n            prime ++;\n        }\n\n    }\n    if(c > 0) gcd = gcd * max(1LL, c / n * prime);\n    cout << gcd << endl;\n\n    return 0;\n\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N integers a_1, a_2, ..., a_N not less than 1.\nThe values of a_1, a_2, ..., a_N are not known, but it is known that a_1 \\times a_2 \\times ... \\times a_N = P.\n\nFind the maximum possible greatest common divisor of a_1, a_2, ..., a_N.\n\nConstraints\n\n1 \\leq N \\leq 10^{12}\n\n1 \\leq P \\leq 10^{12}\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN P\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n3 24\n\nSample Output 1\n\n2\n\nThe greatest common divisor would be 2 when, for example, a_1=2, a_2=6 and a_3=2.\n\nSample Input 2\n\n5 1\n\nSample Output 2\n\n1\n\nAs a_i are positive integers, the only possible case is a_1 = a_2 = a_3 = a_4 = a_5 = 1.\n\nSample Input 3\n\n1 111\n\nSample Output 3\n\n111\n\nSample Input 4\n\n4 972439611840\n\nSample Output 4\n\n206", "sample_input": "3 24\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03196", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N integers a_1, a_2, ..., a_N not less than 1.\nThe values of a_1, a_2, ..., a_N are not known, but it is known that a_1 \\times a_2 \\times ... \\times a_N = P.\n\nFind the maximum possible greatest common divisor of a_1, a_2, ..., a_N.\n\nConstraints\n\n1 \\leq N \\leq 10^{12}\n\n1 \\leq P \\leq 10^{12}\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN P\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n3 24\n\nSample Output 1\n\n2\n\nThe greatest common divisor would be 2 when, for example, a_1=2, a_2=6 and a_3=2.\n\nSample Input 2\n\n5 1\n\nSample Output 2\n\n1\n\nAs a_i are positive integers, the only possible case is a_1 = a_2 = a_3 = a_4 = a_5 = 1.\n\nSample Input 3\n\n1 111\n\nSample Output 3\n\n111\n\nSample Input 4\n\n4 972439611840\n\nSample Output 4\n\n206", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 660, "cpu_time_ms": 2103, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s151969817", "group_id": "codeNet:p03196", "input_text": "#include <cstdio>\n#include <iostream>\n#include <vector>\n#include <set>\n#include <cstring>\n#include <string>\n#include <map>\n#include <cmath>\n#include <ctime>\n#include <algorithm>\n#include <bitset>\n#include <queue>\n#include <sstream>\nusing namespace std;\n#define mp make_pair\n#define pb push_back\n#define re return\n#define fi first\n#define se second\ntypedef vector<int> vi;\ntypedef long long ll;\ntypedef long double ld;\ntypedef pair<int, int> pii;\ntypedef vector<pii> vpii;\ntypedef vector<string> vs;\ntypedef vector<vi> vvi;\nlong long n,p,sum=1;\nint mx=1;\nlong long cnt[1000100]; \nint main() {\n    //freopen(\"input.txt\",\"r\",stdin);\n\t//freopen(\"output.txt\",\"w\",stdout);\n\tcin>>n>>p;\n\tif(n==1){\n\t\tcout<<p<<endl;\n\t\treturn 0;\n\t}\n\tfor(int i=2;i*i<=p;i++){\n\t\twhile(p%i==0){\n\t\t\tp/=i;\n\t\t\tcnt[i]++;\n\t\t\tmx=i;\n\t\t}\n\t}\n\tfor(int i=2;i<=mx;i++){\n\t\tif(cnt[i]>=n){\n\t\t\tint t=cnt[i]/n;\n\t\t\tfor(int j=0;j<t;j++){\n\t\t\t\tsum*=i;\n\t\t\t}\n\t\t}\n\t}\n\tcout<<sum<<endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1545605897, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03196.html", "problem_id": "p03196", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03196/input.txt", "sample_output_relpath": "derived/input_output/data/p03196/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03196/C++/s151969817.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s151969817", "user_id": "u247996218"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <cstdio>\n#include <iostream>\n#include <vector>\n#include <set>\n#include <cstring>\n#include <string>\n#include <map>\n#include <cmath>\n#include <ctime>\n#include <algorithm>\n#include <bitset>\n#include <queue>\n#include <sstream>\nusing namespace std;\n#define mp make_pair\n#define pb push_back\n#define re return\n#define fi first\n#define se second\ntypedef vector<int> vi;\ntypedef long long ll;\ntypedef long double ld;\ntypedef pair<int, int> pii;\ntypedef vector<pii> vpii;\ntypedef vector<string> vs;\ntypedef vector<vi> vvi;\nlong long n,p,sum=1;\nint mx=1;\nlong long cnt[1000100]; \nint main() {\n    //freopen(\"input.txt\",\"r\",stdin);\n\t//freopen(\"output.txt\",\"w\",stdout);\n\tcin>>n>>p;\n\tif(n==1){\n\t\tcout<<p<<endl;\n\t\treturn 0;\n\t}\n\tfor(int i=2;i*i<=p;i++){\n\t\twhile(p%i==0){\n\t\t\tp/=i;\n\t\t\tcnt[i]++;\n\t\t\tmx=i;\n\t\t}\n\t}\n\tfor(int i=2;i<=mx;i++){\n\t\tif(cnt[i]>=n){\n\t\t\tint t=cnt[i]/n;\n\t\t\tfor(int j=0;j<t;j++){\n\t\t\t\tsum*=i;\n\t\t\t}\n\t\t}\n\t}\n\tcout<<sum<<endl;\n    return 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N integers a_1, a_2, ..., a_N not less than 1.\nThe values of a_1, a_2, ..., a_N are not known, but it is known that a_1 \\times a_2 \\times ... \\times a_N = P.\n\nFind the maximum possible greatest common divisor of a_1, a_2, ..., a_N.\n\nConstraints\n\n1 \\leq N \\leq 10^{12}\n\n1 \\leq P \\leq 10^{12}\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN P\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n3 24\n\nSample Output 1\n\n2\n\nThe greatest common divisor would be 2 when, for example, a_1=2, a_2=6 and a_3=2.\n\nSample Input 2\n\n5 1\n\nSample Output 2\n\n1\n\nAs a_i are positive integers, the only possible case is a_1 = a_2 = a_3 = a_4 = a_5 = 1.\n\nSample Input 3\n\n1 111\n\nSample Output 3\n\n111\n\nSample Input 4\n\n4 972439611840\n\nSample Output 4\n\n206", "sample_input": "3 24\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03196", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N integers a_1, a_2, ..., a_N not less than 1.\nThe values of a_1, a_2, ..., a_N are not known, but it is known that a_1 \\times a_2 \\times ... \\times a_N = P.\n\nFind the maximum possible greatest common divisor of a_1, a_2, ..., a_N.\n\nConstraints\n\n1 \\leq N \\leq 10^{12}\n\n1 \\leq P \\leq 10^{12}\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN P\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n3 24\n\nSample Output 1\n\n2\n\nThe greatest common divisor would be 2 when, for example, a_1=2, a_2=6 and a_3=2.\n\nSample Input 2\n\n5 1\n\nSample Output 2\n\n1\n\nAs a_i are positive integers, the only possible case is a_1 = a_2 = a_3 = a_4 = a_5 = 1.\n\nSample Input 3\n\n1 111\n\nSample Output 3\n\n111\n\nSample Input 4\n\n4 972439611840\n\nSample Output 4\n\n206", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 946, "cpu_time_ms": 2103, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s975525024", "group_id": "codeNet:p03196", "input_text": "#include <cstdio>\n#include <map>\n\nusing namespace std;\n\nint main() {\n  long long n, m;\n  scanf(\"%lld %lld\", &n, &m);\n  map<long long, int> cnt;\n  for (long long i = 2; i * i <= m; ++i) {\n    while (m % i == 0) {\n      ++cnt[i];\n      m /= i;\n    }\n  }\n  if (m > 1) {\n    ++cnt[m];\n  }\n  long long ans = 1;\n  for (auto &e : cnt) {\n    for (int i = 0; i < e.second / n; ++i) {\n      ans *= e.first;\n    }\n  }\n  printf(\"%lld\\n\", ans);\n}\n", "language": "C++", "metadata": {"date": 1545530777, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03196.html", "problem_id": "p03196", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03196/input.txt", "sample_output_relpath": "derived/input_output/data/p03196/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03196/C++/s975525024.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s975525024", "user_id": "u127130661"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <cstdio>\n#include <map>\n\nusing namespace std;\n\nint main() {\n  long long n, m;\n  scanf(\"%lld %lld\", &n, &m);\n  map<long long, int> cnt;\n  for (long long i = 2; i * i <= m; ++i) {\n    while (m % i == 0) {\n      ++cnt[i];\n      m /= i;\n    }\n  }\n  if (m > 1) {\n    ++cnt[m];\n  }\n  long long ans = 1;\n  for (auto &e : cnt) {\n    for (int i = 0; i < e.second / n; ++i) {\n      ans *= e.first;\n    }\n  }\n  printf(\"%lld\\n\", ans);\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N integers a_1, a_2, ..., a_N not less than 1.\nThe values of a_1, a_2, ..., a_N are not known, but it is known that a_1 \\times a_2 \\times ... \\times a_N = P.\n\nFind the maximum possible greatest common divisor of a_1, a_2, ..., a_N.\n\nConstraints\n\n1 \\leq N \\leq 10^{12}\n\n1 \\leq P \\leq 10^{12}\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN P\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n3 24\n\nSample Output 1\n\n2\n\nThe greatest common divisor would be 2 when, for example, a_1=2, a_2=6 and a_3=2.\n\nSample Input 2\n\n5 1\n\nSample Output 2\n\n1\n\nAs a_i are positive integers, the only possible case is a_1 = a_2 = a_3 = a_4 = a_5 = 1.\n\nSample Input 3\n\n1 111\n\nSample Output 3\n\n111\n\nSample Input 4\n\n4 972439611840\n\nSample Output 4\n\n206", "sample_input": "3 24\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03196", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N integers a_1, a_2, ..., a_N not less than 1.\nThe values of a_1, a_2, ..., a_N are not known, but it is known that a_1 \\times a_2 \\times ... \\times a_N = P.\n\nFind the maximum possible greatest common divisor of a_1, a_2, ..., a_N.\n\nConstraints\n\n1 \\leq N \\leq 10^{12}\n\n1 \\leq P \\leq 10^{12}\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN P\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n3 24\n\nSample Output 1\n\n2\n\nThe greatest common divisor would be 2 when, for example, a_1=2, a_2=6 and a_3=2.\n\nSample Input 2\n\n5 1\n\nSample Output 2\n\n1\n\nAs a_i are positive integers, the only possible case is a_1 = a_2 = a_3 = a_4 = a_5 = 1.\n\nSample Input 3\n\n1 111\n\nSample Output 3\n\n111\n\nSample Input 4\n\n4 972439611840\n\nSample Output 4\n\n206", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 434, "cpu_time_ms": 6, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s236450131", "group_id": "codeNet:p03197", "input_text": "#include <iostream>\n#include <vector>\n#include <string>\n#include <utility>\n#include <algorithm>\n#include <cmath>\n#include <queue>\n#include <set>\n#include <map>\n#include <cassert>\n#include <fstream>\n#include <iomanip>\n\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll, ll> P;\n\nconst ll mod = 1e9 + 7;\n\nvector<ll> dx = {1, -1, 0, 0};\nvector<ll> dy = {0, 0, 1, -1};\n\nvector<vector<ll>> g;\n\n\nint main() {\n    \n    \n    cin.tie(0);\n    ios_base::sync_with_stdio(0);\n    \n    ll n;\n    cin >> n;\n    bool f = 0;\n    for (int i = 0; i < n; ++i)\n    {\n        ll tmp;\n        cin >> tmp;\n        tmp %= 2ll;\n        if (tmp)\n        {\n            f = 1;\n        }\n    }\n    if (f)\n    {\n        cout << \"first\" <<endl;\n    }\n    else\n    {\n        cout << \"second\" << endl;\n    }\n    return 0;\n}", "language": "C++", "metadata": {"date": 1590016390, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03197.html", "problem_id": "p03197", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03197/input.txt", "sample_output_relpath": "derived/input_output/data/p03197/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03197/C++/s236450131.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s236450131", "user_id": "u110336920"}, "prompt_components": {"gold_output": "first\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\n#include <string>\n#include <utility>\n#include <algorithm>\n#include <cmath>\n#include <queue>\n#include <set>\n#include <map>\n#include <cassert>\n#include <fstream>\n#include <iomanip>\n\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll, ll> P;\n\nconst ll mod = 1e9 + 7;\n\nvector<ll> dx = {1, -1, 0, 0};\nvector<ll> dy = {0, 0, 1, -1};\n\nvector<vector<ll>> g;\n\n\nint main() {\n    \n    \n    cin.tie(0);\n    ios_base::sync_with_stdio(0);\n    \n    ll n;\n    cin >> n;\n    bool f = 0;\n    for (int i = 0; i < n; ++i)\n    {\n        ll tmp;\n        cin >> tmp;\n        tmp %= 2ll;\n        if (tmp)\n        {\n            f = 1;\n        }\n    }\n    if (f)\n    {\n        cout << \"first\" <<endl;\n    }\n    else\n    {\n        cout << \"second\" << endl;\n    }\n    return 0;\n}", "problem_context": "Score : 500 points\n\nProblem Statement\n\nThere is an apple tree that bears apples of N colors. The N colors of these apples are numbered 1 to N, and there are a_i apples of Color i.\n\nYou and Lunlun the dachshund alternately perform the following operation (starting from you):\n\nChoose one or more apples from the tree and eat them. Here, the apples chosen at the same time must all have different colors.\n\nThe one who eats the last apple from the tree will be declared winner. If both you and Lunlun play optimally, which will win?\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq a_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1\na_2\n:\na_N\n\nOutput\n\nIf you will win, print first; if Lunlun will win, print second.\n\nSample Input 1\n\n2\n1\n2\n\nSample Output 1\n\nfirst\n\nLet Color 1 be red, and Color 2 be blue. In this case, the tree bears one red apple and two blue apples.\n\nYou should eat the red apple in your first turn. Lunlun is then forced to eat one of the blue apples, and you can win by eating the other in your next turn.\n\nNote that you are also allowed to eat two apples in your first turn, one red and one blue (not a winning move, though).\n\nSample Input 2\n\n3\n100000\n30000\n20000\n\nSample Output 2\n\nsecond", "sample_input": "2\n1\n2\n"}, "reference_outputs": ["first\n"], "source_document_id": "p03197", "source_text": "Score : 500 points\n\nProblem Statement\n\nThere is an apple tree that bears apples of N colors. The N colors of these apples are numbered 1 to N, and there are a_i apples of Color i.\n\nYou and Lunlun the dachshund alternately perform the following operation (starting from you):\n\nChoose one or more apples from the tree and eat them. Here, the apples chosen at the same time must all have different colors.\n\nThe one who eats the last apple from the tree will be declared winner. If both you and Lunlun play optimally, which will win?\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq a_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1\na_2\n:\na_N\n\nOutput\n\nIf you will win, print first; if Lunlun will win, print second.\n\nSample Input 1\n\n2\n1\n2\n\nSample Output 1\n\nfirst\n\nLet Color 1 be red, and Color 2 be blue. In this case, the tree bears one red apple and two blue apples.\n\nYou should eat the red apple in your first turn. Lunlun is then forced to eat one of the blue apples, and you can win by eating the other in your next turn.\n\nNote that you are also allowed to eat two apples in your first turn, one red and one blue (not a winning move, though).\n\nSample Input 2\n\n3\n100000\n30000\n20000\n\nSample Output 2\n\nsecond", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 797, "cpu_time_ms": 11, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s573899349", "group_id": "codeNet:p03200", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n  string S;\n  cin>>S;\n  long long w=0LL,sum=0LL;\n  for(int i=0;i<S.size();i++){\n    if(S.at(i)=='W'){\n      w++;\n      sum+=i;\n    }\n  }\n  if(w==S.size()||w==0LL)\n    cout<<\"0\"<<endl;\n  else\n    cout<<sum-w*(w-1LL)/2LL<<endl;\n}\n", "language": "C++", "metadata": {"date": 1599954621, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03200.html", "problem_id": "p03200", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03200/input.txt", "sample_output_relpath": "derived/input_output/data/p03200/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03200/C++/s573899349.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s573899349", "user_id": "u418586218"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n  string S;\n  cin>>S;\n  long long w=0LL,sum=0LL;\n  for(int i=0;i<S.size();i++){\n    if(S.at(i)=='W'){\n      w++;\n      sum+=i;\n    }\n  }\n  if(w==S.size()||w==0LL)\n    cout<<\"0\"<<endl;\n  else\n    cout<<sum-w*(w-1LL)/2LL<<endl;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N Reversi pieces arranged in a row. (A Reversi piece is a disc with a black side and a white side.)\nThe state of each piece is represented by a string S of length N.\nIf S_i=B, the i-th piece from the left is showing black;\nIf S_i=W, the i-th piece from the left is showing white.\n\nConsider performing the following operation:\n\nChoose i (1 \\leq i < N) such that the i-th piece from the left is showing black and the (i+1)-th piece from the left is showing white, then flip both of those pieces. That is, the i-th piece from the left is now showing white and the (i+1)-th piece from the left is now showing black.\n\nFind the maximum possible number of times this operation can be performed.\n\nConstraints\n\n1 \\leq |S| \\leq 2\\times 10^5\n\nS_i=B or W\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the maximum possible number of times the operation can be performed.\n\nSample Input 1\n\nBBW\n\nSample Output 1\n\n2\n\nThe operation can be performed twice, as follows:\n\nFlip the second and third pieces from the left.\n\nFlip the first and second pieces from the left.\n\nSample Input 2\n\nBWBWBW\n\nSample Output 2\n\n6", "sample_input": "BBW\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03200", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N Reversi pieces arranged in a row. (A Reversi piece is a disc with a black side and a white side.)\nThe state of each piece is represented by a string S of length N.\nIf S_i=B, the i-th piece from the left is showing black;\nIf S_i=W, the i-th piece from the left is showing white.\n\nConsider performing the following operation:\n\nChoose i (1 \\leq i < N) such that the i-th piece from the left is showing black and the (i+1)-th piece from the left is showing white, then flip both of those pieces. That is, the i-th piece from the left is now showing white and the (i+1)-th piece from the left is now showing black.\n\nFind the maximum possible number of times this operation can be performed.\n\nConstraints\n\n1 \\leq |S| \\leq 2\\times 10^5\n\nS_i=B or W\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the maximum possible number of times the operation can be performed.\n\nSample Input 1\n\nBBW\n\nSample Output 1\n\n2\n\nThe operation can be performed twice, as follows:\n\nFlip the second and third pieces from the left.\n\nFlip the first and second pieces from the left.\n\nSample Input 2\n\nBWBWBW\n\nSample Output 2\n\n6", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 288, "cpu_time_ms": 15, "memory_kb": 3752}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s551348739", "group_id": "codeNet:p03200", "input_text": "#include <bits/stdc++.h>\n#include <numeric>\nusing namespace std;\n#define ll long long\n#define mod107 1000000007\n#define rep(i, n) for (int i = 0; i < n; ++i)\nusing Graph = vector<vector<int>>;\n#define grepq priority_queue<double, std::vector<double>, std::greater<double>>\n#define all(v) v.begin(), v.end()\n#define PI acos(-1)\n \ntemplate <class T>\ninline bool chmin(T &a, T b)\n{\n    if (a > b)\n    {\n        a = b;\n        return true;\n    }\n    return false;\n}\ntemplate <class T>\ninline bool chmax(T &a, T b)\n{\n    if (a < b)\n    {\n        a = b;\n        return true;\n    }\n    return false;\n}\nconst ll INF = 10010001010;\nconst int inf = 1000034000;\n \nconst int dx[4] = {1, 0, -1, 0};\nconst int dy[4] = {0, 1, 0, -1};\n \nint main() {\n  string S;\n  cin >> S;\n  int N = S.size();\n  int black = 0;\n  int ans = 0;\n  for(int i = 0;i < N;i++){\n    if(S[i] == 'B'){\n      black++;\n    }\n    else{\n      ans += black;\n    }\n  }\n  cout << ans << endl;\n  \n}\n", "language": "C++", "metadata": {"date": 1592450722, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03200.html", "problem_id": "p03200", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03200/input.txt", "sample_output_relpath": "derived/input_output/data/p03200/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03200/C++/s551348739.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s551348739", "user_id": "u935370883"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#include <numeric>\nusing namespace std;\n#define ll long long\n#define mod107 1000000007\n#define rep(i, n) for (int i = 0; i < n; ++i)\nusing Graph = vector<vector<int>>;\n#define grepq priority_queue<double, std::vector<double>, std::greater<double>>\n#define all(v) v.begin(), v.end()\n#define PI acos(-1)\n \ntemplate <class T>\ninline bool chmin(T &a, T b)\n{\n    if (a > b)\n    {\n        a = b;\n        return true;\n    }\n    return false;\n}\ntemplate <class T>\ninline bool chmax(T &a, T b)\n{\n    if (a < b)\n    {\n        a = b;\n        return true;\n    }\n    return false;\n}\nconst ll INF = 10010001010;\nconst int inf = 1000034000;\n \nconst int dx[4] = {1, 0, -1, 0};\nconst int dy[4] = {0, 1, 0, -1};\n \nint main() {\n  string S;\n  cin >> S;\n  int N = S.size();\n  int black = 0;\n  int ans = 0;\n  for(int i = 0;i < N;i++){\n    if(S[i] == 'B'){\n      black++;\n    }\n    else{\n      ans += black;\n    }\n  }\n  cout << ans << endl;\n  \n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N Reversi pieces arranged in a row. (A Reversi piece is a disc with a black side and a white side.)\nThe state of each piece is represented by a string S of length N.\nIf S_i=B, the i-th piece from the left is showing black;\nIf S_i=W, the i-th piece from the left is showing white.\n\nConsider performing the following operation:\n\nChoose i (1 \\leq i < N) such that the i-th piece from the left is showing black and the (i+1)-th piece from the left is showing white, then flip both of those pieces. That is, the i-th piece from the left is now showing white and the (i+1)-th piece from the left is now showing black.\n\nFind the maximum possible number of times this operation can be performed.\n\nConstraints\n\n1 \\leq |S| \\leq 2\\times 10^5\n\nS_i=B or W\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the maximum possible number of times the operation can be performed.\n\nSample Input 1\n\nBBW\n\nSample Output 1\n\n2\n\nThe operation can be performed twice, as follows:\n\nFlip the second and third pieces from the left.\n\nFlip the first and second pieces from the left.\n\nSample Input 2\n\nBWBWBW\n\nSample Output 2\n\n6", "sample_input": "BBW\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03200", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N Reversi pieces arranged in a row. (A Reversi piece is a disc with a black side and a white side.)\nThe state of each piece is represented by a string S of length N.\nIf S_i=B, the i-th piece from the left is showing black;\nIf S_i=W, the i-th piece from the left is showing white.\n\nConsider performing the following operation:\n\nChoose i (1 \\leq i < N) such that the i-th piece from the left is showing black and the (i+1)-th piece from the left is showing white, then flip both of those pieces. That is, the i-th piece from the left is now showing white and the (i+1)-th piece from the left is now showing black.\n\nFind the maximum possible number of times this operation can be performed.\n\nConstraints\n\n1 \\leq |S| \\leq 2\\times 10^5\n\nS_i=B or W\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the maximum possible number of times the operation can be performed.\n\nSample Input 1\n\nBBW\n\nSample Output 1\n\n2\n\nThe operation can be performed twice, as follows:\n\nFlip the second and third pieces from the left.\n\nFlip the first and second pieces from the left.\n\nSample Input 2\n\nBWBWBW\n\nSample Output 2\n\n6", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 948, "cpu_time_ms": 9, "memory_kb": 640}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s868718917", "group_id": "codeNet:p03201", "input_text": "#include <cstddef>\n#include <iostream>\n#include <iomanip>\n#include <string>\n#include <sstream>\n#include <vector>\n#include <array>\n#include <unordered_map>\n#include <algorithm>\n#include <numeric>\n#include <limits>\n#include <set>\n#include <map>\n#include <queue>\n#include <stack>\n#include <bitset>\n#include <valarray>\n#include <utility>\n#include <tuple>\n#include <cmath>\n#include <memory>\n#include <random>\n#include <fstream>\n#include <locale>\n\nusing ll = long long;\nusing ull = unsigned long long;\n\n//vector\ntemplate <class T>\nusing vec = std::vector<T>;\n\ntemplate <class T>\nusing vvec = vec<vec<T>>;\n\nconstexpr std::size_t operator\"\"_sz(ull n) { return std::size_t(n); }\n\nint main()\n{\n    using namespace std;\n\n    int n;\n    cin >> n;\n    vec<int> v(n);\n    vec<bool> used(n);\n    set<ll> se;\n\n    vec<ll> pow2(32);\n    pow2[0] = 1;\n    for (int i = 1; i < 32; ++i)\n    {\n        pow2[i] = pow2[i - 1] * 2;\n    }\n\n    for (auto &e : v)\n    {\n        cin >> e;\n        se.emplace(e);\n    }\n\n    sort(v.begin(), v.end());\n\n    int ans{};\n\n    for (int i = n - 1; i >= 0; --i)\n    {\n        if (used[i])\n            continue;\n\n        auto target = *upper_bound(pow2.cbegin(), pow2.cend(), v[i]);\n\n        auto find = se.find(target - v[i]);\n\n        if (find != se.end() && target != v[i])\n        {\n            auto val = *find;\n            se.erase(val);\n\n            auto index = distance(v.begin(), upper_bound(v.begin(), v.end(), val));\n            used[index] = true;\n            used[i] = true;\n            ++ans;\n        }\n    }\n\n    cout << ans << endl;\n\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1544929937, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03201.html", "problem_id": "p03201", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03201/input.txt", "sample_output_relpath": "derived/input_output/data/p03201/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03201/C++/s868718917.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s868718917", "user_id": "u207917850"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <cstddef>\n#include <iostream>\n#include <iomanip>\n#include <string>\n#include <sstream>\n#include <vector>\n#include <array>\n#include <unordered_map>\n#include <algorithm>\n#include <numeric>\n#include <limits>\n#include <set>\n#include <map>\n#include <queue>\n#include <stack>\n#include <bitset>\n#include <valarray>\n#include <utility>\n#include <tuple>\n#include <cmath>\n#include <memory>\n#include <random>\n#include <fstream>\n#include <locale>\n\nusing ll = long long;\nusing ull = unsigned long long;\n\n//vector\ntemplate <class T>\nusing vec = std::vector<T>;\n\ntemplate <class T>\nusing vvec = vec<vec<T>>;\n\nconstexpr std::size_t operator\"\"_sz(ull n) { return std::size_t(n); }\n\nint main()\n{\n    using namespace std;\n\n    int n;\n    cin >> n;\n    vec<int> v(n);\n    vec<bool> used(n);\n    set<ll> se;\n\n    vec<ll> pow2(32);\n    pow2[0] = 1;\n    for (int i = 1; i < 32; ++i)\n    {\n        pow2[i] = pow2[i - 1] * 2;\n    }\n\n    for (auto &e : v)\n    {\n        cin >> e;\n        se.emplace(e);\n    }\n\n    sort(v.begin(), v.end());\n\n    int ans{};\n\n    for (int i = n - 1; i >= 0; --i)\n    {\n        if (used[i])\n            continue;\n\n        auto target = *upper_bound(pow2.cbegin(), pow2.cend(), v[i]);\n\n        auto find = se.find(target - v[i]);\n\n        if (find != se.end() && target != v[i])\n        {\n            auto val = *find;\n            se.erase(val);\n\n            auto index = distance(v.begin(), upper_bound(v.begin(), v.end(), val));\n            used[index] = true;\n            used[i] = true;\n            ++ans;\n        }\n    }\n\n    cout << ans << endl;\n\n    return 0;\n}\n", "problem_context": "Score : 600 points\n\nProblem Statement\n\nTakahashi has N balls with positive integers written on them. The integer written on the i-th ball is A_i.\nHe would like to form some number of pairs such that the sum of the integers written on each pair of balls is a power of 2.\nNote that a ball cannot belong to multiple pairs.\nFind the maximum possible number of pairs that can be formed.\n\nHere, a positive integer is said to be a power of 2 when it can be written as 2^t using some non-negative integer t.\n\nConstraints\n\n1 \\leq N \\leq 2\\times 10^5\n\n1 \\leq A_i \\leq 10^9\n\nA_i is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the maximum possible number of pairs such that the sum of the integers written on each pair of balls is a power of 2.\n\nSample Input 1\n\n3\n1 2 3\n\nSample Output 1\n\n1\n\nWe can form one pair whose sum of the written numbers is 4 by pairing the first and third balls.\nNote that we cannot pair the second ball with itself.\n\nSample Input 2\n\n5\n3 11 14 5 13\n\nSample Output 2\n\n2", "sample_input": "3\n1 2 3\n"}, "reference_outputs": ["1\n"], "source_document_id": "p03201", "source_text": "Score : 600 points\n\nProblem Statement\n\nTakahashi has N balls with positive integers written on them. The integer written on the i-th ball is A_i.\nHe would like to form some number of pairs such that the sum of the integers written on each pair of balls is a power of 2.\nNote that a ball cannot belong to multiple pairs.\nFind the maximum possible number of pairs that can be formed.\n\nHere, a positive integer is said to be a power of 2 when it can be written as 2^t using some non-negative integer t.\n\nConstraints\n\n1 \\leq N \\leq 2\\times 10^5\n\n1 \\leq A_i \\leq 10^9\n\nA_i is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the maximum possible number of pairs such that the sum of the integers written on each pair of balls is a power of 2.\n\nSample Input 1\n\n3\n1 2 3\n\nSample Output 1\n\n1\n\nWe can form one pair whose sum of the written numbers is 4 by pairing the first and third balls.\nNote that we cannot pair the second ball with itself.\n\nSample Input 2\n\n5\n3 11 14 5 13\n\nSample Output 2\n\n2", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1578, "cpu_time_ms": 187, "memory_kb": 10368}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s120203617", "group_id": "codeNet:p03203", "input_text": "#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <cmath>\n#include <cassert>\n#include <iostream>\n#include <sstream>\n#include <vector>\n#include <queue>\n#include <set>\n#include <map>\n#include <utility>\n#include <numeric>\n#include <algorithm>\n#include <bitset>\n#include <complex>\n#include <array>\n#include <list>\n#include <stack>\n#include <valarray>\n\nusing namespace std;\n\ntypedef unsigned uint;\ntypedef long long Int;\ntypedef unsigned long long UInt;\n\nconst int INF = 1001001001;\nconst Int INFLL = 1001001001001001001LL;\n\ntemplate<typename T> void pv(T a, T b) { for (T i = a; i != b; ++i) cout << *i << \" \"; cout << endl; }\ntemplate<typename T> void chmin(T& a, T b) { if (a > b) a = b; }\ntemplate<typename T> void chmax(T& a, T b) { if (a < b) a = b; }\nint in() { int x; scanf(\"%d\", &x); return x; }\ndouble fin() { double x; scanf(\"%lf\", &x); return x; }\nInt lin() { Int x; scanf(\"%lld\", &x); return x; }\n\nint main() {\n  int H = in();\n  int W = in();\n  int N = in();\n  set<pair<int, int>> X;\n  for (int i = 0; i < N; ++i) {\n    int r = in() - 1;\n    int c = in() - 1;\n    X.insert(make_pair(r, c));\n  }\n\n  vector<int> top(W, INF);\n  int ar = 0, ac = 0;\n  while (true) {\n    chmin(top[ac], ar);\n    ++ar;\n    if (ar >= H) {\n      break;\n    }\n    if (X.count(make_pair(ar, ac + 1)) == 0) {\n      ++ac;\n    }\n  }\n\n  int res = H;\n  for (const auto& p : X) {\n    if (top[p.second] < p.first) {\n      chmin(res, p.first);\n    }\n  }\n  printf(\"%d\\n\", res);\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1544928783, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03203.html", "problem_id": "p03203", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03203/input.txt", "sample_output_relpath": "derived/input_output/data/p03203/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03203/C++/s120203617.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s120203617", "user_id": "u965315642"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <cmath>\n#include <cassert>\n#include <iostream>\n#include <sstream>\n#include <vector>\n#include <queue>\n#include <set>\n#include <map>\n#include <utility>\n#include <numeric>\n#include <algorithm>\n#include <bitset>\n#include <complex>\n#include <array>\n#include <list>\n#include <stack>\n#include <valarray>\n\nusing namespace std;\n\ntypedef unsigned uint;\ntypedef long long Int;\ntypedef unsigned long long UInt;\n\nconst int INF = 1001001001;\nconst Int INFLL = 1001001001001001001LL;\n\ntemplate<typename T> void pv(T a, T b) { for (T i = a; i != b; ++i) cout << *i << \" \"; cout << endl; }\ntemplate<typename T> void chmin(T& a, T b) { if (a > b) a = b; }\ntemplate<typename T> void chmax(T& a, T b) { if (a < b) a = b; }\nint in() { int x; scanf(\"%d\", &x); return x; }\ndouble fin() { double x; scanf(\"%lf\", &x); return x; }\nInt lin() { Int x; scanf(\"%lld\", &x); return x; }\n\nint main() {\n  int H = in();\n  int W = in();\n  int N = in();\n  set<pair<int, int>> X;\n  for (int i = 0; i < N; ++i) {\n    int r = in() - 1;\n    int c = in() - 1;\n    X.insert(make_pair(r, c));\n  }\n\n  vector<int> top(W, INF);\n  int ar = 0, ac = 0;\n  while (true) {\n    chmin(top[ac], ar);\n    ++ar;\n    if (ar >= H) {\n      break;\n    }\n    if (X.count(make_pair(ar, ac + 1)) == 0) {\n      ++ac;\n    }\n  }\n\n  int res = H;\n  for (const auto& p : X) {\n    if (top[p.second] < p.first) {\n      chmin(res, p.first);\n    }\n  }\n  printf(\"%d\\n\", res);\n  return 0;\n}\n", "problem_context": "Score : 800 points\n\nProblem Statement\n\nTakahashi and Aoki will play a game using a grid with H rows and W columns of square cells.\nThere are N obstacles on this grid; the i-th obstacle is at (X_i,Y_i).\nHere, we represent the cell at the i-th row and j-th column (1 \\leq i \\leq H, 1 \\leq j \\leq W) by (i,j).\nThere is no obstacle at (1,1), and there is a piece placed there at (1,1).\n\nStarting from Takahashi, he and Aoki alternately perform one of the following actions:\n\nMove the piece to an adjacent cell.\nHere, let the position of the piece be (x,y). Then Takahashi can only move the piece to (x+1,y), and Aoki can only move the piece to (x,y+1).\nIf the destination cell does not exist or it is occupied by an obstacle, this action cannot be taken.\n\nDo not move the piece, and end his turn without affecting the grid.\n\nThe game ends when the piece does not move twice in a row.\n\nTakahashi would like to perform as many actions (including not moving the piece) as possible before the game ends, while Aoki would like to perform as few actions as possible before the game ends.\nHow many actions will Takahashi end up performing?\n\nConstraints\n\n1 \\leq H,W \\leq 2\\times 10^5\n\n0 \\leq N \\leq 2\\times 10^5\n\n1 \\leq X_i \\leq H\n\n1 \\leq Y_i \\leq W\n\nIf i \\neq j, (X_i,Y_i) \\neq (X_j,Y_j)\n\n(X_i,Y_i) \\neq (1,1)\n\nX_i and Y_i are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W N\nX_1 Y_1\n:\nX_N Y_N\n\nOutput\n\nPrint the number of actions Takahashi will end up performing.\n\nSample Input 1\n\n3 3 1\n3 2\n\nSample Output 1\n\n2\n\nFor example, the game proceeds as follows:\n\nTakahashi moves the piece to (2,1).\n\nAoki does not move the piece.\n\nTakahashi moves the piece to (3,1).\n\nAoki does not move the piece.\n\nTakahashi does not move the piece.\n\nTakahashi performs three actions in this case, but if both players play optimally, Takahashi will perform only two actions before the game ends.\n\nSample Input 2\n\n10 10 14\n4 3\n2 2\n7 3\n9 10\n7 7\n8 1\n10 10\n5 4\n3 4\n2 8\n6 4\n4 4\n5 8\n9 2\n\nSample Output 2\n\n6\n\nSample Input 3\n\n100000 100000 0\n\nSample Output 3\n\n100000", "sample_input": "3 3 1\n3 2\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03203", "source_text": "Score : 800 points\n\nProblem Statement\n\nTakahashi and Aoki will play a game using a grid with H rows and W columns of square cells.\nThere are N obstacles on this grid; the i-th obstacle is at (X_i,Y_i).\nHere, we represent the cell at the i-th row and j-th column (1 \\leq i \\leq H, 1 \\leq j \\leq W) by (i,j).\nThere is no obstacle at (1,1), and there is a piece placed there at (1,1).\n\nStarting from Takahashi, he and Aoki alternately perform one of the following actions:\n\nMove the piece to an adjacent cell.\nHere, let the position of the piece be (x,y). Then Takahashi can only move the piece to (x+1,y), and Aoki can only move the piece to (x,y+1).\nIf the destination cell does not exist or it is occupied by an obstacle, this action cannot be taken.\n\nDo not move the piece, and end his turn without affecting the grid.\n\nThe game ends when the piece does not move twice in a row.\n\nTakahashi would like to perform as many actions (including not moving the piece) as possible before the game ends, while Aoki would like to perform as few actions as possible before the game ends.\nHow many actions will Takahashi end up performing?\n\nConstraints\n\n1 \\leq H,W \\leq 2\\times 10^5\n\n0 \\leq N \\leq 2\\times 10^5\n\n1 \\leq X_i \\leq H\n\n1 \\leq Y_i \\leq W\n\nIf i \\neq j, (X_i,Y_i) \\neq (X_j,Y_j)\n\n(X_i,Y_i) \\neq (1,1)\n\nX_i and Y_i are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W N\nX_1 Y_1\n:\nX_N Y_N\n\nOutput\n\nPrint the number of actions Takahashi will end up performing.\n\nSample Input 1\n\n3 3 1\n3 2\n\nSample Output 1\n\n2\n\nFor example, the game proceeds as follows:\n\nTakahashi moves the piece to (2,1).\n\nAoki does not move the piece.\n\nTakahashi moves the piece to (3,1).\n\nAoki does not move the piece.\n\nTakahashi does not move the piece.\n\nTakahashi performs three actions in this case, but if both players play optimally, Takahashi will perform only two actions before the game ends.\n\nSample Input 2\n\n10 10 14\n4 3\n2 2\n7 3\n9 10\n7 7\n8 1\n10 10\n5 4\n3 4\n2 8\n6 4\n4 4\n5 8\n9 2\n\nSample Output 2\n\n6\n\nSample Input 3\n\n100000 100000 0\n\nSample Output 3\n\n100000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1479, "cpu_time_ms": 249, "memory_kb": 10368}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s476434068", "group_id": "codeNet:p03210", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n  int age;\n  cin >> age;\n  if(age == 3 || age==5 || age==7) cout << \"YES\" << endl;\n  else  cout << \"NO\" <<endl;\n  return 0;\n}", "language": "C++", "metadata": {"date": 1572753078, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03210.html", "problem_id": "p03210", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03210/input.txt", "sample_output_relpath": "derived/input_output/data/p03210/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03210/C++/s476434068.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s476434068", "user_id": "u679159704"}, "prompt_components": {"gold_output": "YES\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n  int age;\n  cin >> age;\n  if(age == 3 || age==5 || age==7) cout << \"YES\" << endl;\n  else  cout << \"NO\" <<endl;\n  return 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nShichi-Go-San (literally \"Seven-Five-Three\") is a traditional event in a certain country to celebrate the growth of seven-, five- and three-year-old children.\n\nTakahashi is now X years old. Will his growth be celebrated in Shichi-Go-San this time?\n\nConstraints\n\n1 ≤ X ≤ 9\n\nX is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nIf Takahashi's growth will be celebrated, print YES; if it will not, print NO.\n\nSample Input 1\n\n5\n\nSample Output 1\n\nYES\n\nThe growth of a five-year-old child will be celebrated.\n\nSample Input 2\n\n6\n\nSample Output 2\n\nNO\n\nSee you next year.", "sample_input": "5\n"}, "reference_outputs": ["YES\n"], "source_document_id": "p03210", "source_text": "Score : 100 points\n\nProblem Statement\n\nShichi-Go-San (literally \"Seven-Five-Three\") is a traditional event in a certain country to celebrate the growth of seven-, five- and three-year-old children.\n\nTakahashi is now X years old. Will his growth be celebrated in Shichi-Go-San this time?\n\nConstraints\n\n1 ≤ X ≤ 9\n\nX is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nIf Takahashi's growth will be celebrated, print YES; if it will not, print NO.\n\nSample Input 1\n\n5\n\nSample Output 1\n\nYES\n\nThe growth of a five-year-old child will be celebrated.\n\nSample Input 2\n\n6\n\nSample Output 2\n\nNO\n\nSee you next year.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 182, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s337674812", "group_id": "codeNet:p03211", "input_text": "#include <iostream>\n#include <algorithm>\n#include <cmath>\nusing namespace std;\n\nint main(){\n  string S;\n  cin >> S;\n  \n  int n =S.size();\n  int x = 999;\n  for(int i=0;i<n-2;i++){\n    int w = (S[i] - '0') * 100 + (S[i+1] - '0') * 10 + (S[i+2] - '0');\n    x = min(x, abs(w-753));\n  }\n  \n  cout << x;\n  \n  return 0;\n}\n\n\n\n\n", "language": "C++", "metadata": {"date": 1546140478, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03211.html", "problem_id": "p03211", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03211/input.txt", "sample_output_relpath": "derived/input_output/data/p03211/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03211/C++/s337674812.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s337674812", "user_id": "u540300321"}, "prompt_components": {"gold_output": "34\n", "input_to_evaluate": "#include <iostream>\n#include <algorithm>\n#include <cmath>\nusing namespace std;\n\nint main(){\n  string S;\n  cin >> S;\n  \n  int n =S.size();\n  int x = 999;\n  for(int i=0;i<n-2;i++){\n    int w = (S[i] - '0') * 100 + (S[i+1] - '0') * 10 + (S[i+2] - '0');\n    x = min(x, abs(w-753));\n  }\n  \n  cout << x;\n  \n  return 0;\n}\n\n\n\n\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nThere is a string S consisting of digits 1, 2, ..., 9.\nLunlun, the Dachshund, will take out three consecutive digits from S, treat them as a single integer X and bring it to her master. (She cannot rearrange the digits.)\n\nThe master's favorite number is 753. The closer to this number, the better.\nWhat is the minimum possible (absolute) difference between X and 753?\n\nConstraints\n\nS is a string of length between 4 and 10 (inclusive).\n\nEach character in S is 1, 2, ..., or 9.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the minimum possible difference between X and 753.\n\nSample Input 1\n\n1234567876\n\nSample Output 1\n\n34\n\nTaking out the seventh to ninth characters results in X = 787, and the difference between this and 753 is 787 - 753 = 34. The difference cannot be made smaller, no matter where X is taken from.\n\nNote that the digits cannot be rearranged. For example, taking out 567 and rearranging it to 765 is not allowed.\n\nWe cannot take out three digits that are not consecutive from S, either. For example, taking out the seventh digit 7, the ninth digit 7 and the tenth digit 6 to obtain 776 is not allowed.\n\nSample Input 2\n\n35753\n\nSample Output 2\n\n0\n\nIf 753 itself can be taken out, the answer is 0.\n\nSample Input 3\n\n1111111111\n\nSample Output 3\n\n642\n\nNo matter where X is taken from, X = 111, with the difference 753 - 111 = 642.", "sample_input": "1234567876\n"}, "reference_outputs": ["34\n"], "source_document_id": "p03211", "source_text": "Score : 200 points\n\nProblem Statement\n\nThere is a string S consisting of digits 1, 2, ..., 9.\nLunlun, the Dachshund, will take out three consecutive digits from S, treat them as a single integer X and bring it to her master. (She cannot rearrange the digits.)\n\nThe master's favorite number is 753. The closer to this number, the better.\nWhat is the minimum possible (absolute) difference between X and 753?\n\nConstraints\n\nS is a string of length between 4 and 10 (inclusive).\n\nEach character in S is 1, 2, ..., or 9.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the minimum possible difference between X and 753.\n\nSample Input 1\n\n1234567876\n\nSample Output 1\n\n34\n\nTaking out the seventh to ninth characters results in X = 787, and the difference between this and 753 is 787 - 753 = 34. The difference cannot be made smaller, no matter where X is taken from.\n\nNote that the digits cannot be rearranged. For example, taking out 567 and rearranging it to 765 is not allowed.\n\nWe cannot take out three digits that are not consecutive from S, either. For example, taking out the seventh digit 7, the ninth digit 7 and the tenth digit 6 to obtain 776 is not allowed.\n\nSample Input 2\n\n35753\n\nSample Output 2\n\n0\n\nIf 753 itself can be taken out, the answer is 0.\n\nSample Input 3\n\n1111111111\n\nSample Output 3\n\n642\n\nNo matter where X is taken from, X = 111, with the difference 753 - 111 = 642.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 319, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s354031544", "group_id": "codeNet:p03211", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n\tstring s,x;\n\tint mi;\n\tcin>>s;\n\tmi=1000;\n\tfor(int i=0;i<s.size()-2;i++){\n\t\tx=s.substr(i,3);\n\t\tmi=min(mi,abs(753-((x[0]-'0')*100+(x[1]-'0')*10+(x[2]-'0'))));\n\t}\n\tcout<<mi<<endl;\n}", "language": "C++", "metadata": {"date": 1544138323, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03211.html", "problem_id": "p03211", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03211/input.txt", "sample_output_relpath": "derived/input_output/data/p03211/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03211/C++/s354031544.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s354031544", "user_id": "u452009494"}, "prompt_components": {"gold_output": "34\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n\tstring s,x;\n\tint mi;\n\tcin>>s;\n\tmi=1000;\n\tfor(int i=0;i<s.size()-2;i++){\n\t\tx=s.substr(i,3);\n\t\tmi=min(mi,abs(753-((x[0]-'0')*100+(x[1]-'0')*10+(x[2]-'0'))));\n\t}\n\tcout<<mi<<endl;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nThere is a string S consisting of digits 1, 2, ..., 9.\nLunlun, the Dachshund, will take out three consecutive digits from S, treat them as a single integer X and bring it to her master. (She cannot rearrange the digits.)\n\nThe master's favorite number is 753. The closer to this number, the better.\nWhat is the minimum possible (absolute) difference between X and 753?\n\nConstraints\n\nS is a string of length between 4 and 10 (inclusive).\n\nEach character in S is 1, 2, ..., or 9.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the minimum possible difference between X and 753.\n\nSample Input 1\n\n1234567876\n\nSample Output 1\n\n34\n\nTaking out the seventh to ninth characters results in X = 787, and the difference between this and 753 is 787 - 753 = 34. The difference cannot be made smaller, no matter where X is taken from.\n\nNote that the digits cannot be rearranged. For example, taking out 567 and rearranging it to 765 is not allowed.\n\nWe cannot take out three digits that are not consecutive from S, either. For example, taking out the seventh digit 7, the ninth digit 7 and the tenth digit 6 to obtain 776 is not allowed.\n\nSample Input 2\n\n35753\n\nSample Output 2\n\n0\n\nIf 753 itself can be taken out, the answer is 0.\n\nSample Input 3\n\n1111111111\n\nSample Output 3\n\n642\n\nNo matter where X is taken from, X = 111, with the difference 753 - 111 = 642.", "sample_input": "1234567876\n"}, "reference_outputs": ["34\n"], "source_document_id": "p03211", "source_text": "Score : 200 points\n\nProblem Statement\n\nThere is a string S consisting of digits 1, 2, ..., 9.\nLunlun, the Dachshund, will take out three consecutive digits from S, treat them as a single integer X and bring it to her master. (She cannot rearrange the digits.)\n\nThe master's favorite number is 753. The closer to this number, the better.\nWhat is the minimum possible (absolute) difference between X and 753?\n\nConstraints\n\nS is a string of length between 4 and 10 (inclusive).\n\nEach character in S is 1, 2, ..., or 9.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the minimum possible difference between X and 753.\n\nSample Input 1\n\n1234567876\n\nSample Output 1\n\n34\n\nTaking out the seventh to ninth characters results in X = 787, and the difference between this and 753 is 787 - 753 = 34. The difference cannot be made smaller, no matter where X is taken from.\n\nNote that the digits cannot be rearranged. For example, taking out 567 and rearranging it to 765 is not allowed.\n\nWe cannot take out three digits that are not consecutive from S, either. For example, taking out the seventh digit 7, the ninth digit 7 and the tenth digit 6 to obtain 776 is not allowed.\n\nSample Input 2\n\n35753\n\nSample Output 2\n\n0\n\nIf 753 itself can be taken out, the answer is 0.\n\nSample Input 3\n\n1111111111\n\nSample Output 3\n\n642\n\nNo matter where X is taken from, X = 111, with the difference 753 - 111 = 642.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 236, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s679635304", "group_id": "codeNet:p03212", "input_text": "#include <cstdio>\n#include <cmath>\n\nlong long dp[11][2][8];\n\nint main()\n{\n  char s[12];\n  scanf(\"%s\", s);\n  dp[0][0][0] = 1;\n  int i;\n  for (i = 0; s[i]; ++i)\n  {\n    int D = s[i] - '0';\n    for (int j = 0; j < 2; ++j)\n    {\n      for (int m = 0; m < (1 << 3); ++m)\n      {\n        for (int k = 0; k <= (j ? 9 : D); ++k)\n        {\n          if (k != 3 && k != 5 && k != 7) continue;\n          dp[i + 1][j || k < D][m | (k == 3 ? 1 : k == 5 ? 2 : 4)] += dp[i][j][m];\n        }\n      }\n    }\n  }\n  long long ans = 0;\n  for (long long j = 3; j < (long long)i; ++j)\n  {\n    ans += (long long)std::pow(3, j) - 3 * (long long)std::pow(2, j) + 3;\n  }\n  printf(\"%lld\\n\", dp[i][0][7] + dp[i][1][7] + ans);\n  return 0;\n}", "language": "C++", "metadata": {"date": 1570437766, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03212.html", "problem_id": "p03212", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03212/input.txt", "sample_output_relpath": "derived/input_output/data/p03212/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03212/C++/s679635304.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s679635304", "user_id": "u931819817"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <cstdio>\n#include <cmath>\n\nlong long dp[11][2][8];\n\nint main()\n{\n  char s[12];\n  scanf(\"%s\", s);\n  dp[0][0][0] = 1;\n  int i;\n  for (i = 0; s[i]; ++i)\n  {\n    int D = s[i] - '0';\n    for (int j = 0; j < 2; ++j)\n    {\n      for (int m = 0; m < (1 << 3); ++m)\n      {\n        for (int k = 0; k <= (j ? 9 : D); ++k)\n        {\n          if (k != 3 && k != 5 && k != 7) continue;\n          dp[i + 1][j || k < D][m | (k == 3 ? 1 : k == 5 ? 2 : 4)] += dp[i][j][m];\n        }\n      }\n    }\n  }\n  long long ans = 0;\n  for (long long j = 3; j < (long long)i; ++j)\n  {\n    ans += (long long)std::pow(3, j) - 3 * (long long)std::pow(2, j) + 3;\n  }\n  printf(\"%lld\\n\", dp[i][0][7] + dp[i][1][7] + ans);\n  return 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nYou are given an integer N. Among the integers between 1 and N (inclusive), how many Shichi-Go-San numbers (literally \"Seven-Five-Three numbers\") are there?\n\nHere, a Shichi-Go-San number is a positive integer that satisfies the following condition:\n\nWhen the number is written in base ten, each of the digits 7, 5 and 3 appears at least once, and the other digits never appear.\n\nConstraints\n\n1 \\leq N < 10^9\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the number of the Shichi-Go-San numbers between 1 and N (inclusive).\n\nSample Input 1\n\n575\n\nSample Output 1\n\n4\n\nThere are four Shichi-Go-San numbers not greater than 575: 357, 375, 537 and 573.\n\nSample Input 2\n\n3600\n\nSample Output 2\n\n13\n\nThere are 13 Shichi-Go-San numbers not greater than 3600: the above four numbers, 735, 753, 3357, 3375, 3537, 3557, 3573, 3575 and 3577.\n\nSample Input 3\n\n999999999\n\nSample Output 3\n\n26484", "sample_input": "575\n"}, "reference_outputs": ["4\n"], "source_document_id": "p03212", "source_text": "Score : 300 points\n\nProblem Statement\n\nYou are given an integer N. Among the integers between 1 and N (inclusive), how many Shichi-Go-San numbers (literally \"Seven-Five-Three numbers\") are there?\n\nHere, a Shichi-Go-San number is a positive integer that satisfies the following condition:\n\nWhen the number is written in base ten, each of the digits 7, 5 and 3 appears at least once, and the other digits never appear.\n\nConstraints\n\n1 \\leq N < 10^9\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the number of the Shichi-Go-San numbers between 1 and N (inclusive).\n\nSample Input 1\n\n575\n\nSample Output 1\n\n4\n\nThere are four Shichi-Go-San numbers not greater than 575: 357, 375, 537 and 573.\n\nSample Input 2\n\n3600\n\nSample Output 2\n\n13\n\nThere are 13 Shichi-Go-San numbers not greater than 3600: the above four numbers, 735, 753, 3357, 3375, 3537, 3557, 3573, 3575 and 3577.\n\nSample Input 3\n\n999999999\n\nSample Output 3\n\n26484", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 710, "cpu_time_ms": 1, "memory_kb": 128}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s664475550", "group_id": "codeNet:p03219", "input_text": "//author:luckYrat(twitter:@luckYrat_)\n//#include <bits/stdc++.h>\n\n//def\n#include <iostream>\n\n#include <cmath>\n#include <algorithm>\n#include <iomanip>\n\n//array\n#include <vector>\n#include <set>\n#include <stack>\n#include <queue>\n#include <map>\n#include <utility>\n#include <climits>\n\n\n\nusing namespace std;\n\nusing ll = long long;\nusing P = pair<ll,ll>;\n\n#define anyfill(n,s) setw(n) << setfill(s)\n#define loop(s) for(int i = 0; s > i; i++)\n#define rep(i,q) for(int i = 0; (q) > i; i++)\n#define repp(i,n,q) for(int i = n; (q) > i; i++)\n#define dep(i,q) for(int i = (q); 0 < i; i--)\n\n\n#define MAX 1000000000\nconst int mod = 1000000007;\n#define EPS (1e-10)\n\n#define pb push_back\n#define fir first\n#define scn second\n#define ednl endl\n\n#define YesNo(a) (a?\"Yes\":\"No\")\n#define YESNO(a) (a?\"YES\":\"NO\")\n#define yesno(a) (a?\"yes\":\"no\")\n\n\nP ar4[4] = {{0,1},{0,-1},{1,0},{-1,0}};\nP ar8[8] = {{-1,-1},{-1,0},{-1,1},{0,-1},{0,1},{1,-1},{1,0},{1,1}};\n/*\n確認ポイント\ncout << fixed << setprecision(n) << 小数計算//n桁の小数表記になる\nvector.unique()は隣接した同じ要素を削除するので先にソートをする\n\n計算量は変わらないが楽できるシリーズ\nC++11以降でmin({a,b,c...})で複数個のmic,maxを処理できる\nmin(max)_element(iter,iter)で一番小さい(大きい)値のポインタが帰ってくる\ncount(iter,iter,int)でintがiterからiterの間にいくつあったかを取得できる\n\n*/\n__attribute__((constructor))\nvoid initial() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n}\n\n\n\nint main(){\n  int a,b;cin>>a>>b;\n  cout << a+b/2 << endl;\n}\n", "language": "C++", "metadata": {"date": 1583804408, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03219.html", "problem_id": "p03219", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03219/input.txt", "sample_output_relpath": "derived/input_output/data/p03219/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03219/C++/s664475550.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s664475550", "user_id": "u466161487"}, "prompt_components": {"gold_output": "110\n", "input_to_evaluate": "//author:luckYrat(twitter:@luckYrat_)\n//#include <bits/stdc++.h>\n\n//def\n#include <iostream>\n\n#include <cmath>\n#include <algorithm>\n#include <iomanip>\n\n//array\n#include <vector>\n#include <set>\n#include <stack>\n#include <queue>\n#include <map>\n#include <utility>\n#include <climits>\n\n\n\nusing namespace std;\n\nusing ll = long long;\nusing P = pair<ll,ll>;\n\n#define anyfill(n,s) setw(n) << setfill(s)\n#define loop(s) for(int i = 0; s > i; i++)\n#define rep(i,q) for(int i = 0; (q) > i; i++)\n#define repp(i,n,q) for(int i = n; (q) > i; i++)\n#define dep(i,q) for(int i = (q); 0 < i; i--)\n\n\n#define MAX 1000000000\nconst int mod = 1000000007;\n#define EPS (1e-10)\n\n#define pb push_back\n#define fir first\n#define scn second\n#define ednl endl\n\n#define YesNo(a) (a?\"Yes\":\"No\")\n#define YESNO(a) (a?\"YES\":\"NO\")\n#define yesno(a) (a?\"yes\":\"no\")\n\n\nP ar4[4] = {{0,1},{0,-1},{1,0},{-1,0}};\nP ar8[8] = {{-1,-1},{-1,0},{-1,1},{0,-1},{0,1},{1,-1},{1,0},{1,1}};\n/*\n確認ポイント\ncout << fixed << setprecision(n) << 小数計算//n桁の小数表記になる\nvector.unique()は隣接した同じ要素を削除するので先にソートをする\n\n計算量は変わらないが楽できるシリーズ\nC++11以降でmin({a,b,c...})で複数個のmic,maxを処理できる\nmin(max)_element(iter,iter)で一番小さい(大きい)値のポインタが帰ってくる\ncount(iter,iter,int)でintがiterからiterの間にいくつあったかを取得できる\n\n*/\n__attribute__((constructor))\nvoid initial() {\n cin.tie(0);\n ios::sync_with_stdio(false);\n}\n\n\n\nint main(){\n  int a,b;cin>>a>>b;\n  cout << a+b/2 << endl;\n}\n", "problem_context": "Score: 100 points\n\nProblem Statement\n\nThere is a train going from Station A to Station B that costs X yen (the currency of Japan).\n\nAlso, there is a bus going from Station B to Station C that costs Y yen.\n\nJoisino got a special ticket. With this ticket, she can take the bus for half the fare if she travels from Station A to Station B by train and then travels from Station B to Station C by bus.\n\nHow much does it cost to travel from Station A to Station C if she uses this ticket?\n\nConstraints\n\n1 \\leq X,Y \\leq 100\n\nY is an even number.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX Y\n\nOutput\n\nIf it costs x yen to travel from Station A to Station C, print x.\n\nSample Input 1\n\n81 58\n\nSample Output 1\n\n110\n\nThe train fare is 81 yen.\n\nThe train fare is 58 ⁄ 2=29 yen with the 50% discount.\n\nThus, it costs 110 yen to travel from Station A to Station C.\n\nSample Input 2\n\n4 54\n\nSample Output 2\n\n31", "sample_input": "81 58\n"}, "reference_outputs": ["110\n"], "source_document_id": "p03219", "source_text": "Score: 100 points\n\nProblem Statement\n\nThere is a train going from Station A to Station B that costs X yen (the currency of Japan).\n\nAlso, there is a bus going from Station B to Station C that costs Y yen.\n\nJoisino got a special ticket. With this ticket, she can take the bus for half the fare if she travels from Station A to Station B by train and then travels from Station B to Station C by bus.\n\nHow much does it cost to travel from Station A to Station C if she uses this ticket?\n\nConstraints\n\n1 \\leq X,Y \\leq 100\n\nY is an even number.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX Y\n\nOutput\n\nIf it costs x yen to travel from Station A to Station C, print x.\n\nSample Input 1\n\n81 58\n\nSample Output 1\n\n110\n\nThe train fare is 81 yen.\n\nThe train fare is 58 ⁄ 2=29 yen with the 50% discount.\n\nThus, it costs 110 yen to travel from Station A to Station C.\n\nSample Input 2\n\n4 54\n\nSample Output 2\n\n31", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1592, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s283060593", "group_id": "codeNet:p03219", "input_text": "#include <bits/stdc++.h>\n#define rep(i, n) for (int i = 0; i < (n); ++i)\n#define repr(i, n) for (int i = (n); i >= 0; --i)\n#define FOR(i, m, n) for (int i = (m); i < (n); ++i)\n#define FORR(i, m, n) for (int i = (m); i >= (n); --i)\nusing namespace std;\ntypedef long long ll;\nconst ll mod = 1000000007;\nconst ll mod2 = 998244353;\n\nint main() {\n  int x, y;\n  cin >> x >> y;\n  cout << x+y/2 << endl;\n}", "language": "C++", "metadata": {"date": 1569344514, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03219.html", "problem_id": "p03219", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03219/input.txt", "sample_output_relpath": "derived/input_output/data/p03219/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03219/C++/s283060593.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s283060593", "user_id": "u759721333"}, "prompt_components": {"gold_output": "110\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define rep(i, n) for (int i = 0; i < (n); ++i)\n#define repr(i, n) for (int i = (n); i >= 0; --i)\n#define FOR(i, m, n) for (int i = (m); i < (n); ++i)\n#define FORR(i, m, n) for (int i = (m); i >= (n); --i)\nusing namespace std;\ntypedef long long ll;\nconst ll mod = 1000000007;\nconst ll mod2 = 998244353;\n\nint main() {\n  int x, y;\n  cin >> x >> y;\n  cout << x+y/2 << endl;\n}", "problem_context": "Score: 100 points\n\nProblem Statement\n\nThere is a train going from Station A to Station B that costs X yen (the currency of Japan).\n\nAlso, there is a bus going from Station B to Station C that costs Y yen.\n\nJoisino got a special ticket. With this ticket, she can take the bus for half the fare if she travels from Station A to Station B by train and then travels from Station B to Station C by bus.\n\nHow much does it cost to travel from Station A to Station C if she uses this ticket?\n\nConstraints\n\n1 \\leq X,Y \\leq 100\n\nY is an even number.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX Y\n\nOutput\n\nIf it costs x yen to travel from Station A to Station C, print x.\n\nSample Input 1\n\n81 58\n\nSample Output 1\n\n110\n\nThe train fare is 81 yen.\n\nThe train fare is 58 ⁄ 2=29 yen with the 50% discount.\n\nThus, it costs 110 yen to travel from Station A to Station C.\n\nSample Input 2\n\n4 54\n\nSample Output 2\n\n31", "sample_input": "81 58\n"}, "reference_outputs": ["110\n"], "source_document_id": "p03219", "source_text": "Score: 100 points\n\nProblem Statement\n\nThere is a train going from Station A to Station B that costs X yen (the currency of Japan).\n\nAlso, there is a bus going from Station B to Station C that costs Y yen.\n\nJoisino got a special ticket. With this ticket, she can take the bus for half the fare if she travels from Station A to Station B by train and then travels from Station B to Station C by bus.\n\nHow much does it cost to travel from Station A to Station C if she uses this ticket?\n\nConstraints\n\n1 \\leq X,Y \\leq 100\n\nY is an even number.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX Y\n\nOutput\n\nIf it costs x yen to travel from Station A to Station C, print x.\n\nSample Input 1\n\n81 58\n\nSample Output 1\n\n110\n\nThe train fare is 81 yen.\n\nThe train fare is 58 ⁄ 2=29 yen with the 50% discount.\n\nThus, it costs 110 yen to travel from Station A to Station C.\n\nSample Input 2\n\n4 54\n\nSample Output 2\n\n31", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 397, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s698428971", "group_id": "codeNet:p03219", "input_text": "#pragma GCC optimize \"-O3\"\n#pragma GCC target (\"avx\")\n#define _USE_MATH_DEFINES\n#include<bits/stdc++.h>\n#define int long long\n#define rep(i,n) for(int i=0;i<n;++i)\n#define vi vector<int>\n#define vvi vector<vi>\n#define pb push_back\n#define pi pair<int,int>\n#define vp vector<pair<int,int>>\n#define mp make_pair\n#define all(v) (v).begin(),(v).end()\n#define fi first\n#define se second\n#define inf (1ll<<60)\n#define SORT(v) sort(all(v))\n#define RSORT(v) sort(all(v),greater<int>())\nsigned gcd(int a, int b){return b?gcd(b,a%b):a;}\nsigned lcm(int a,int b){return a*b/gcd(a,b);}\n\nusing namespace std;\n\nconst int mod=1e9+7;\n\nvoid run();\n\nvoid init() {\n    ios::sync_with_stdio(false);\n    cin.tie(0);\n    cout<<fixed<<setprecision(12);\n}\n\nsigned main(){\n    init();\n    run();\n    return 0;\n}\n\nvoid run(){\n    int x, y;\n    cin >> x >> y;\n    cout << x+y/2 << endl;\n}", "language": "C++", "metadata": {"date": 1563222798, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03219.html", "problem_id": "p03219", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03219/input.txt", "sample_output_relpath": "derived/input_output/data/p03219/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03219/C++/s698428971.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s698428971", "user_id": "u775507068"}, "prompt_components": {"gold_output": "110\n", "input_to_evaluate": "#pragma GCC optimize \"-O3\"\n#pragma GCC target (\"avx\")\n#define _USE_MATH_DEFINES\n#include<bits/stdc++.h>\n#define int long long\n#define rep(i,n) for(int i=0;i<n;++i)\n#define vi vector<int>\n#define vvi vector<vi>\n#define pb push_back\n#define pi pair<int,int>\n#define vp vector<pair<int,int>>\n#define mp make_pair\n#define all(v) (v).begin(),(v).end()\n#define fi first\n#define se second\n#define inf (1ll<<60)\n#define SORT(v) sort(all(v))\n#define RSORT(v) sort(all(v),greater<int>())\nsigned gcd(int a, int b){return b?gcd(b,a%b):a;}\nsigned lcm(int a,int b){return a*b/gcd(a,b);}\n\nusing namespace std;\n\nconst int mod=1e9+7;\n\nvoid run();\n\nvoid init() {\n    ios::sync_with_stdio(false);\n    cin.tie(0);\n    cout<<fixed<<setprecision(12);\n}\n\nsigned main(){\n    init();\n    run();\n    return 0;\n}\n\nvoid run(){\n    int x, y;\n    cin >> x >> y;\n    cout << x+y/2 << endl;\n}", "problem_context": "Score: 100 points\n\nProblem Statement\n\nThere is a train going from Station A to Station B that costs X yen (the currency of Japan).\n\nAlso, there is a bus going from Station B to Station C that costs Y yen.\n\nJoisino got a special ticket. With this ticket, she can take the bus for half the fare if she travels from Station A to Station B by train and then travels from Station B to Station C by bus.\n\nHow much does it cost to travel from Station A to Station C if she uses this ticket?\n\nConstraints\n\n1 \\leq X,Y \\leq 100\n\nY is an even number.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX Y\n\nOutput\n\nIf it costs x yen to travel from Station A to Station C, print x.\n\nSample Input 1\n\n81 58\n\nSample Output 1\n\n110\n\nThe train fare is 81 yen.\n\nThe train fare is 58 ⁄ 2=29 yen with the 50% discount.\n\nThus, it costs 110 yen to travel from Station A to Station C.\n\nSample Input 2\n\n4 54\n\nSample Output 2\n\n31", "sample_input": "81 58\n"}, "reference_outputs": ["110\n"], "source_document_id": "p03219", "source_text": "Score: 100 points\n\nProblem Statement\n\nThere is a train going from Station A to Station B that costs X yen (the currency of Japan).\n\nAlso, there is a bus going from Station B to Station C that costs Y yen.\n\nJoisino got a special ticket. With this ticket, she can take the bus for half the fare if she travels from Station A to Station B by train and then travels from Station B to Station C by bus.\n\nHow much does it cost to travel from Station A to Station C if she uses this ticket?\n\nConstraints\n\n1 \\leq X,Y \\leq 100\n\nY is an even number.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX Y\n\nOutput\n\nIf it costs x yen to travel from Station A to Station C, print x.\n\nSample Input 1\n\n81 58\n\nSample Output 1\n\n110\n\nThe train fare is 81 yen.\n\nThe train fare is 58 ⁄ 2=29 yen with the 50% discount.\n\nThus, it costs 110 yen to travel from Station A to Station C.\n\nSample Input 2\n\n4 54\n\nSample Output 2\n\n31", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 860, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s750022109", "group_id": "codeNet:p03219", "input_text": "#include <iostream>\n#include <utility>\n#include <cmath>\n#include <algorithm>\n#include <vector>\n#include <string>\n#include <set>\n#include <stdio.h>\n#include <string.h>\n#include <queue>\n#include <map>\n#include <fstream>\n#include <bitset>\n#include <stack>\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair<ll,ll> pii;\ntypedef vector<ll> vec;\n\n\nint main()\n{\n#ifdef _DEBUG\n\tfreopen(\"input.txt\", \"r\", stdin);\n\tfreopen(\"output.txt\", \"w\", stdout);\n#endif\n\tint x, y; cin >> x >> y;\n\tcout << x + y / 2;\n\n\n\treturn 0;\n\n}", "language": "C++", "metadata": {"date": 1541383271, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03219.html", "problem_id": "p03219", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03219/input.txt", "sample_output_relpath": "derived/input_output/data/p03219/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03219/C++/s750022109.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s750022109", "user_id": "u844155089"}, "prompt_components": {"gold_output": "110\n", "input_to_evaluate": "#include <iostream>\n#include <utility>\n#include <cmath>\n#include <algorithm>\n#include <vector>\n#include <string>\n#include <set>\n#include <stdio.h>\n#include <string.h>\n#include <queue>\n#include <map>\n#include <fstream>\n#include <bitset>\n#include <stack>\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair<ll,ll> pii;\ntypedef vector<ll> vec;\n\n\nint main()\n{\n#ifdef _DEBUG\n\tfreopen(\"input.txt\", \"r\", stdin);\n\tfreopen(\"output.txt\", \"w\", stdout);\n#endif\n\tint x, y; cin >> x >> y;\n\tcout << x + y / 2;\n\n\n\treturn 0;\n\n}", "problem_context": "Score: 100 points\n\nProblem Statement\n\nThere is a train going from Station A to Station B that costs X yen (the currency of Japan).\n\nAlso, there is a bus going from Station B to Station C that costs Y yen.\n\nJoisino got a special ticket. With this ticket, she can take the bus for half the fare if she travels from Station A to Station B by train and then travels from Station B to Station C by bus.\n\nHow much does it cost to travel from Station A to Station C if she uses this ticket?\n\nConstraints\n\n1 \\leq X,Y \\leq 100\n\nY is an even number.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX Y\n\nOutput\n\nIf it costs x yen to travel from Station A to Station C, print x.\n\nSample Input 1\n\n81 58\n\nSample Output 1\n\n110\n\nThe train fare is 81 yen.\n\nThe train fare is 58 ⁄ 2=29 yen with the 50% discount.\n\nThus, it costs 110 yen to travel from Station A to Station C.\n\nSample Input 2\n\n4 54\n\nSample Output 2\n\n31", "sample_input": "81 58\n"}, "reference_outputs": ["110\n"], "source_document_id": "p03219", "source_text": "Score: 100 points\n\nProblem Statement\n\nThere is a train going from Station A to Station B that costs X yen (the currency of Japan).\n\nAlso, there is a bus going from Station B to Station C that costs Y yen.\n\nJoisino got a special ticket. With this ticket, she can take the bus for half the fare if she travels from Station A to Station B by train and then travels from Station B to Station C by bus.\n\nHow much does it cost to travel from Station A to Station C if she uses this ticket?\n\nConstraints\n\n1 \\leq X,Y \\leq 100\n\nY is an even number.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX Y\n\nOutput\n\nIf it costs x yen to travel from Station A to Station C, print x.\n\nSample Input 1\n\n81 58\n\nSample Output 1\n\n110\n\nThe train fare is 81 yen.\n\nThe train fare is 58 ⁄ 2=29 yen with the 50% discount.\n\nThus, it costs 110 yen to travel from Station A to Station C.\n\nSample Input 2\n\n4 54\n\nSample Output 2\n\n31", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 515, "cpu_time_ms": 6, "memory_kb": 768}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s482737238", "group_id": "codeNet:p03220", "input_text": "#include<bits/stdc++.h>\n#define rep(i,n) for (int i = 0; i < n; ++i)\n#define rep2(i,s,n) for (int i = s; i < n; ++i)\n#define all(a) a.begin(),a.end()\nusing namespace std;\nusing ll = long long;\nusing P = pair<int,int>;\n\nint main() {\n    int n,t,a;\n    cin >> n >> t >> a;\n    int ans;\n    double now = 1001001001;\n    rep(i,n) {\n        int h;\n        cin >> h;\n        double nt = t-nt*0.006;\n        double dif = abs(nt-a);\n        if(dif < now) {\n            now = dif;\n            ans = i+1;\n        }\n    }\n    cout << ans << endl;\n}", "language": "C++", "metadata": {"date": 1583970392, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03220.html", "problem_id": "p03220", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03220/input.txt", "sample_output_relpath": "derived/input_output/data/p03220/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03220/C++/s482737238.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s482737238", "user_id": "u853721692"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include<bits/stdc++.h>\n#define rep(i,n) for (int i = 0; i < n; ++i)\n#define rep2(i,s,n) for (int i = s; i < n; ++i)\n#define all(a) a.begin(),a.end()\nusing namespace std;\nusing ll = long long;\nusing P = pair<int,int>;\n\nint main() {\n    int n,t,a;\n    cin >> n >> t >> a;\n    int ans;\n    double now = 1001001001;\n    rep(i,n) {\n        int h;\n        cin >> h;\n        double nt = t-nt*0.006;\n        double dif = abs(nt-a);\n        if(dif < now) {\n            now = dif;\n            ans = i+1;\n        }\n    }\n    cout << ans << endl;\n}", "problem_context": "Score: 200 points\n\nProblem Statement\n\nA country decides to build a palace.\n\nIn this country, the average temperature of a point at an elevation of x meters is T-x \\times 0.006 degrees Celsius.\n\nThere are N places proposed for the place. The elevation of Place i is H_i meters.\n\nAmong them, Princess Joisino orders you to select the place whose average temperature is the closest to A degrees Celsius, and build the palace there.\n\nPrint the index of the place where the palace should be built.\n\nIt is guaranteed that the solution is unique.\n\nConstraints\n\n1 \\leq N \\leq 1000\n\n0 \\leq T \\leq 50\n\n-60 \\leq A \\leq T\n\n0 \\leq H_i \\leq 10^5\n\nAll values in input are integers.\n\nThe solution is unique.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nT A\nH_1 H_2 ... H_N\n\nOutput\n\nPrint the index of the place where the palace should be built.\n\nSample Input 1\n\n2\n12 5\n1000 2000\n\nSample Output 1\n\n1\n\nThe average temperature of Place 1 is 12-1000 \\times 0.006=6 degrees Celsius.\n\nThe average temperature of Place 2 is 12-2000 \\times 0.006=0 degrees Celsius.\n\nThus, the palace should be built at Place 1.\n\nSample Input 2\n\n3\n21 -11\n81234 94124 52141\n\nSample Output 2\n\n3", "sample_input": "2\n12 5\n1000 2000\n"}, "reference_outputs": ["1\n"], "source_document_id": "p03220", "source_text": "Score: 200 points\n\nProblem Statement\n\nA country decides to build a palace.\n\nIn this country, the average temperature of a point at an elevation of x meters is T-x \\times 0.006 degrees Celsius.\n\nThere are N places proposed for the place. The elevation of Place i is H_i meters.\n\nAmong them, Princess Joisino orders you to select the place whose average temperature is the closest to A degrees Celsius, and build the palace there.\n\nPrint the index of the place where the palace should be built.\n\nIt is guaranteed that the solution is unique.\n\nConstraints\n\n1 \\leq N \\leq 1000\n\n0 \\leq T \\leq 50\n\n-60 \\leq A \\leq T\n\n0 \\leq H_i \\leq 10^5\n\nAll values in input are integers.\n\nThe solution is unique.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nT A\nH_1 H_2 ... H_N\n\nOutput\n\nPrint the index of the place where the palace should be built.\n\nSample Input 1\n\n2\n12 5\n1000 2000\n\nSample Output 1\n\n1\n\nThe average temperature of Place 1 is 12-1000 \\times 0.006=6 degrees Celsius.\n\nThe average temperature of Place 2 is 12-2000 \\times 0.006=0 degrees Celsius.\n\nThus, the palace should be built at Place 1.\n\nSample Input 2\n\n3\n21 -11\n81234 94124 52141\n\nSample Output 2\n\n3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 537, "cpu_time_ms": 2, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s945304034", "group_id": "codeNet:p03220", "input_text": "#include <iostream>\n#include <string>\n#include <cmath>\n#include <vector>\n#include <algorithm>\n#include <iterator>\n#include <typeinfo>\nusing namespace std;\n\n\n// define list\n\n\nnamespace  math{\n    const double PI = 3.14;\n    const int INF = 1000000007;\n    int GCM(int a,int b); //最大公約数\n    int LCM(int a,int b); //最小公倍数\n    int Pemu(int n,int r); //順列\n    int Comb(int n,int m); //組み合わせ\n    int Digit(int N); //桁和\n    \n    int GCM(int a,int b){\n        if(a<b){\n            swap(a,b);\n        }\n        int r = a%b;\n        while (r!=0)\n        {\n            a=b;\n            b=r;\n            r=a%b;\n        }\n        return b;\n    }\n\n    int LCM(int a,int b){\n        return a*(b/GCM(a,b));\n    }\n\n    int Pemu(int n,int r){\n        int ans = n;\n        for(int i=1;i<r;i++){\n            ans*=(ans-i);\n        }\n        return ans;\n    }\n\n    int Comb(int n,int m){\n        int a=n,b=m;\n        for(int i=1;i<m;i++){\n            a *= (a-i);\n        }\n        for(int i=1;i<m;i++){\n            b *= (b-i);\n        }\n        \n        return a/b;\n    }\n\n    int Digit(int N){\n        if(N<10){\n            return N;\n        }\n        int r = 0;\n        while (N>=10)\n        {\n            r += (N%10);\n            N /= 10;\n        }\n        r += N;\n        return r;\n    }\n}\n\nnamespace SubLib{\n    #define int long long\n    #define double long double\n    #define incin(n) int (n); cin >> (n);\n    #define incin2(a,b) int a,b; cin >> a >> b; \n    #define rap(n,i) for(int (i) = 0;i<(n);(i)++)\n    #define input(n,v) (v) = SubLib::Input((n),(v))\n    #define all(v) (v).begin(),(v).end()\n    using intv = vector<int>;\n    using strv = vector<string>;\n    using charv = vector<char>;\n    template <class T1>\n    using pvec = vector<pair<T1,T1>>;\n    template <typename T> vector<T> Input(int n,vector<T> v){\n        for(int i=0;i<n;i++){\n            cin >> v.at(i);\n        }\n        return v;\n    }\n}\n\nusing namespace math;\nusing namespace SubLib;\ndouble Kion(int X,int T){\n    return T -X * 0.006;\n}\n\nsigned main(){\n    incin(n);\n    incin2(t,a);\n    intv h(n);\n    input(n,h);\n    int log_dif = 1000000000;\n    int point;\n    rap(n,i){   \n        if(abs(Kion(h[i],t)-a)<log_dif){\n            log_dif = abs(Kion(h[i],t)-a);\n            point = i+1;\n        }\n    }\n    cout << point << endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1578141961, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03220.html", "problem_id": "p03220", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03220/input.txt", "sample_output_relpath": "derived/input_output/data/p03220/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03220/C++/s945304034.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s945304034", "user_id": "u679866004"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <iostream>\n#include <string>\n#include <cmath>\n#include <vector>\n#include <algorithm>\n#include <iterator>\n#include <typeinfo>\nusing namespace std;\n\n\n// define list\n\n\nnamespace  math{\n    const double PI = 3.14;\n    const int INF = 1000000007;\n    int GCM(int a,int b); //最大公約数\n    int LCM(int a,int b); //最小公倍数\n    int Pemu(int n,int r); //順列\n    int Comb(int n,int m); //組み合わせ\n    int Digit(int N); //桁和\n    \n    int GCM(int a,int b){\n        if(a<b){\n            swap(a,b);\n        }\n        int r = a%b;\n        while (r!=0)\n        {\n            a=b;\n            b=r;\n            r=a%b;\n        }\n        return b;\n    }\n\n    int LCM(int a,int b){\n        return a*(b/GCM(a,b));\n    }\n\n    int Pemu(int n,int r){\n        int ans = n;\n        for(int i=1;i<r;i++){\n            ans*=(ans-i);\n        }\n        return ans;\n    }\n\n    int Comb(int n,int m){\n        int a=n,b=m;\n        for(int i=1;i<m;i++){\n            a *= (a-i);\n        }\n        for(int i=1;i<m;i++){\n            b *= (b-i);\n        }\n        \n        return a/b;\n    }\n\n    int Digit(int N){\n        if(N<10){\n            return N;\n        }\n        int r = 0;\n        while (N>=10)\n        {\n            r += (N%10);\n            N /= 10;\n        }\n        r += N;\n        return r;\n    }\n}\n\nnamespace SubLib{\n    #define int long long\n    #define double long double\n    #define incin(n) int (n); cin >> (n);\n    #define incin2(a,b) int a,b; cin >> a >> b; \n    #define rap(n,i) for(int (i) = 0;i<(n);(i)++)\n    #define input(n,v) (v) = SubLib::Input((n),(v))\n    #define all(v) (v).begin(),(v).end()\n    using intv = vector<int>;\n    using strv = vector<string>;\n    using charv = vector<char>;\n    template <class T1>\n    using pvec = vector<pair<T1,T1>>;\n    template <typename T> vector<T> Input(int n,vector<T> v){\n        for(int i=0;i<n;i++){\n            cin >> v.at(i);\n        }\n        return v;\n    }\n}\n\nusing namespace math;\nusing namespace SubLib;\ndouble Kion(int X,int T){\n    return T -X * 0.006;\n}\n\nsigned main(){\n    incin(n);\n    incin2(t,a);\n    intv h(n);\n    input(n,h);\n    int log_dif = 1000000000;\n    int point;\n    rap(n,i){   \n        if(abs(Kion(h[i],t)-a)<log_dif){\n            log_dif = abs(Kion(h[i],t)-a);\n            point = i+1;\n        }\n    }\n    cout << point << endl;\n    return 0;\n}", "problem_context": "Score: 200 points\n\nProblem Statement\n\nA country decides to build a palace.\n\nIn this country, the average temperature of a point at an elevation of x meters is T-x \\times 0.006 degrees Celsius.\n\nThere are N places proposed for the place. The elevation of Place i is H_i meters.\n\nAmong them, Princess Joisino orders you to select the place whose average temperature is the closest to A degrees Celsius, and build the palace there.\n\nPrint the index of the place where the palace should be built.\n\nIt is guaranteed that the solution is unique.\n\nConstraints\n\n1 \\leq N \\leq 1000\n\n0 \\leq T \\leq 50\n\n-60 \\leq A \\leq T\n\n0 \\leq H_i \\leq 10^5\n\nAll values in input are integers.\n\nThe solution is unique.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nT A\nH_1 H_2 ... H_N\n\nOutput\n\nPrint the index of the place where the palace should be built.\n\nSample Input 1\n\n2\n12 5\n1000 2000\n\nSample Output 1\n\n1\n\nThe average temperature of Place 1 is 12-1000 \\times 0.006=6 degrees Celsius.\n\nThe average temperature of Place 2 is 12-2000 \\times 0.006=0 degrees Celsius.\n\nThus, the palace should be built at Place 1.\n\nSample Input 2\n\n3\n21 -11\n81234 94124 52141\n\nSample Output 2\n\n3", "sample_input": "2\n12 5\n1000 2000\n"}, "reference_outputs": ["1\n"], "source_document_id": "p03220", "source_text": "Score: 200 points\n\nProblem Statement\n\nA country decides to build a palace.\n\nIn this country, the average temperature of a point at an elevation of x meters is T-x \\times 0.006 degrees Celsius.\n\nThere are N places proposed for the place. The elevation of Place i is H_i meters.\n\nAmong them, Princess Joisino orders you to select the place whose average temperature is the closest to A degrees Celsius, and build the palace there.\n\nPrint the index of the place where the palace should be built.\n\nIt is guaranteed that the solution is unique.\n\nConstraints\n\n1 \\leq N \\leq 1000\n\n0 \\leq T \\leq 50\n\n-60 \\leq A \\leq T\n\n0 \\leq H_i \\leq 10^5\n\nAll values in input are integers.\n\nThe solution is unique.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nT A\nH_1 H_2 ... H_N\n\nOutput\n\nPrint the index of the place where the palace should be built.\n\nSample Input 1\n\n2\n12 5\n1000 2000\n\nSample Output 1\n\n1\n\nThe average temperature of Place 1 is 12-1000 \\times 0.006=6 degrees Celsius.\n\nThe average temperature of Place 2 is 12-2000 \\times 0.006=0 degrees Celsius.\n\nThus, the palace should be built at Place 1.\n\nSample Input 2\n\n3\n21 -11\n81234 94124 52141\n\nSample Output 2\n\n3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2340, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s815118989", "group_id": "codeNet:p03221", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing product = pair<ll,ll>;\nusing vvll = vector<vector<ll>>;\nusing vll = vector<ll>;\n\nint main()\n{\n    ll N,M;\n    cin>>N>>M;\n    vll P(M);\n    vll Y(M);\n    for(ll i=0;i<M;i++)\n    {\n        cin>>P[i]>>Y[i];\n        --P[i];\n    }\n    vvll vals(N);\n    for(ll i=0;i<M;i++)vals[P[i]].emplace_back(Y[i]);\n    for(ll i=0;i<N;i++)sort(vals[i].begin(),vals[i].end());\n\n    for(ll i=0;i<M;i++)\n    {\n        ll v=P[i];\n        printf(\"%06d\",v+1);\n\n        ll id=lower_bound(vals[v].begin(),vals[v].end(),Y[i])-vals[v].begin();\n        printf(\"%06d\\n\",id+1);\n    }\n}", "language": "C++", "metadata": {"date": 1599372969, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03221.html", "problem_id": "p03221", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03221/input.txt", "sample_output_relpath": "derived/input_output/data/p03221/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03221/C++/s815118989.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s815118989", "user_id": "u809918012"}, "prompt_components": {"gold_output": "000001000002\n000002000001\n000001000001\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\nusing product = pair<ll,ll>;\nusing vvll = vector<vector<ll>>;\nusing vll = vector<ll>;\n\nint main()\n{\n    ll N,M;\n    cin>>N>>M;\n    vll P(M);\n    vll Y(M);\n    for(ll i=0;i<M;i++)\n    {\n        cin>>P[i]>>Y[i];\n        --P[i];\n    }\n    vvll vals(N);\n    for(ll i=0;i<M;i++)vals[P[i]].emplace_back(Y[i]);\n    for(ll i=0;i<N;i++)sort(vals[i].begin(),vals[i].end());\n\n    for(ll i=0;i<M;i++)\n    {\n        ll v=P[i];\n        printf(\"%06d\",v+1);\n\n        ll id=lower_bound(vals[v].begin(),vals[v].end(),Y[i])-vals[v].begin();\n        printf(\"%06d\\n\",id+1);\n    }\n}", "problem_context": "Score: 300 points\n\nProblem Statement\n\nIn Republic of Atcoder, there are N prefectures, and a total of M cities that belong to those prefectures.\n\nCity i is established in year Y_i and belongs to Prefecture P_i.\n\nYou can assume that there are no multiple cities that are established in the same year.\n\nIt is decided to allocate a 12-digit ID number to each city.\n\nIf City i is the x-th established city among the cities that belong to Prefecture i, the first six digits of the ID number of City i is P_i, and the last six digits of the ID number is x.\n\nHere, if P_i or x (or both) has less than six digits, zeros are added to the left until it has six digits.\n\nFind the ID numbers for all the cities.\n\nNote that there can be a prefecture with no cities.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq P_i \\leq N\n\n1 \\leq Y_i \\leq 10^9\n\nY_i are all different.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nP_1 Y_1\n:\nP_M Y_M\n\nOutput\n\nPrint the ID numbers for all the cities, in ascending order of indices (City 1, City 2, ...).\n\nSample Input 1\n\n2 3\n1 32\n2 63\n1 12\n\nSample Output 1\n\n000001000002\n000002000001\n000001000001\n\nAs City 1 is the second established city among the cities that belong to Prefecture 1, its ID number is 000001000002.\n\nAs City 2 is the first established city among the cities that belong to Prefecture 2, its ID number is 000002000001.\n\nAs City 3 is the first established city among the cities that belong to Prefecture 1, its ID number is 000001000001.\n\nSample Input 2\n\n2 3\n2 55\n2 77\n2 99\n\nSample Output 2\n\n000002000001\n000002000002\n000002000003", "sample_input": "2 3\n1 32\n2 63\n1 12\n"}, "reference_outputs": ["000001000002\n000002000001\n000001000001\n"], "source_document_id": "p03221", "source_text": "Score: 300 points\n\nProblem Statement\n\nIn Republic of Atcoder, there are N prefectures, and a total of M cities that belong to those prefectures.\n\nCity i is established in year Y_i and belongs to Prefecture P_i.\n\nYou can assume that there are no multiple cities that are established in the same year.\n\nIt is decided to allocate a 12-digit ID number to each city.\n\nIf City i is the x-th established city among the cities that belong to Prefecture i, the first six digits of the ID number of City i is P_i, and the last six digits of the ID number is x.\n\nHere, if P_i or x (or both) has less than six digits, zeros are added to the left until it has six digits.\n\nFind the ID numbers for all the cities.\n\nNote that there can be a prefecture with no cities.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq P_i \\leq N\n\n1 \\leq Y_i \\leq 10^9\n\nY_i are all different.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nP_1 Y_1\n:\nP_M Y_M\n\nOutput\n\nPrint the ID numbers for all the cities, in ascending order of indices (City 1, City 2, ...).\n\nSample Input 1\n\n2 3\n1 32\n2 63\n1 12\n\nSample Output 1\n\n000001000002\n000002000001\n000001000001\n\nAs City 1 is the second established city among the cities that belong to Prefecture 1, its ID number is 000001000002.\n\nAs City 2 is the first established city among the cities that belong to Prefecture 2, its ID number is 000002000001.\n\nAs City 3 is the first established city among the cities that belong to Prefecture 1, its ID number is 000001000001.\n\nSample Input 2\n\n2 3\n2 55\n2 77\n2 99\n\nSample Output 2\n\n000002000001\n000002000002\n000002000003", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 627, "cpu_time_ms": 96, "memory_kb": 10256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s398962183", "group_id": "codeNet:p03221", "input_text": "#include <algorithm>\n#include <climits>\n#include <cmath>\n#include <deque>\n#include <iostream>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <regex>\n#include <unordered_map>\n#include <vector>\n\nconst int mod = 1e9 + 7;\nconst int kmax = 510000;\nconst int last_days[] = { 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };\n\nlong long fact[kmax], fact_inv[kmax], inv[kmax];\n\nvoid init_comb()\n{\n    fact[0] = fact[1] = 1;\n    fact_inv[0] = fact_inv[1] = 1;\n    inv[1] = 1;\n    for (int i = 2; i < kmax; i++) {\n        fact[i] = fact[i - 1] * i % mod;\n        inv[i] = mod - inv[mod % i] * (mod / i) % mod;\n        fact_inv[i] = fact_inv[i - 1] * inv[i] % mod;\n    }\n}\n\nlong long comb(int n, int r)\n{\n    if (n < r) {\n        return 0;\n    }\n\n    if (n < 0 || r < 0) {\n        return 0;\n    }\n\n    return fact[n] * (fact_inv[r] * fact_inv[n - r] % mod) % mod;\n}\n\ntemplate <typename T, T N>\nclass UnionFind {\n    T parent_[N];\n    T rank_[N];\n    T size_[N];\n\npublic:\n    UnionFind();\n    T Root(T idx);\n    bool IsSame(T x, T y);\n    void Unite(T x, T y);\n    T GetSize(T idx);\n};\n\ntemplate <typename T, T N>\nUnionFind<T, N>::UnionFind()\n{\n    for (T i = 0; i < N; i++) {\n        parent_[i] = i;\n        rank_[i] = 0;\n        size_[i] = 1;\n    }\n}\n\ntemplate <typename T, T N>\nT UnionFind<T, N>::Root(T idx)\n{\n    return parent_[idx] == idx ? idx : parent_[idx] = Root(parent_[idx]);\n}\n\ntemplate <typename T, T N>\nbool UnionFind<T, N>::IsSame(T x, T y)\n{\n    return Root(x) == Root(y);\n}\n\ntemplate <typename T, T N>\nvoid UnionFind<T, N>::Unite(T x, T y)\n{\n    x = Root(x);\n    y = Root(y);\n    if (x == y) {\n        return;\n    }\n\n    if (rank_[x] < rank_[y]) {\n        parent_[x] = y;\n        size_[y] += size_[x];\n    } else {\n        parent_[y] = x;\n        size_[x] += size_[y];\n        if (rank_[x] == rank_[y]) {\n            rank_[x]++;\n        }\n    }\n}\n\ntemplate <typename T, T N>\nT UnionFind<T, N>::GetSize(T idx)\n{\n    return size_[Root(idx)];\n}\n\nlong long pow_mod(long long n, long long p, long long m)\n{\n    if (p == 0) {\n        return 1;\n    }\n\n    if (p % 2 == 0) {\n        long long t = pow_mod(n, p / 2, m);\n        return t * t % m;\n    }\n    return n * pow_mod(n, p - 1, m) % mod;\n}\n\nlong long nCr_mod(long long n, long long r)\n{\n    long long x = 1;\n    for (long long i = n - r + 1; i <= n; i++) {\n        x *= i;\n        x %= mod;\n    }\n\n    long long a = 1;\n    for (long long i = 1; i <= r; i++) {\n        a *= i;\n        a %= mod;\n    }\n\n    long long y = pow_mod(a, mod - 2, mod) % mod;\n\n    return x * y % mod;\n}\n\nbool is_prime(long long n)\n{\n    if (n == 1) {\n        return false;\n    }\n\n    for (long long i = 2; i * i <= n; i++) {\n        if (n % i == 0) {\n            return false;\n        }\n    }\n\n    return true;\n}\n\nbool is_leap(long long y)\n{\n    return (y % 4 == 0 && y % 100 != 0) || y % 400 == 0;\n}\n\nvoid next_day(long long& y, long long& m, long long& d)\n{\n    d++;\n\n    if (d > last_days[m - 1] + (m == 2 && is_leap(y) ? 1 : 0)) {\n        d = 1;\n        m++;\n    }\n\n    if (m > 12) {\n        y++;\n        m = 1;\n    }\n}\n\nlong long fib(long long n)\n{\n    long long a = 0, b = 1;\n    for (int i = 0; i < n; i++) {\n        long long t = a;\n        a = b;\n        b = a + t;\n    }\n\n    return a;\n}\n\nstd::vector<size_t> argsort(const std::vector<long long>& v)\n{\n    std::vector<size_t> indices(v.size());\n    std::iota(indices.begin(), indices.end(), 0);\n\n    std::sort(indices.begin(), indices.end(), [&v](size_t i, size_t j) { return v[i] < v[j]; });\n\n    for (auto i = 0LU; i < indices.size(); i++) {\n        indices[i]++;\n    }\n\n    return indices;\n}\n\nint main()\n{\n    long long n, m;\n    std::cin >> n >> m;\n\n    std::vector<long long> p(m), y(m);\n\n    for (int i = 0; i < m; i++) {\n        std::cin >> p[i] >> y[i];\n        p[i]--;\n    }\n\n    std::vector<std::vector<long long>> nums(n);\n\n    for (int i = 0; i < m; i++) {\n        nums[p[i]].push_back(y[i]);\n    }\n\n    for (int i = 0; i < n; i++) {\n        std::reverse(nums[i].begin(), nums[i].end());\n    }\n\n    std::vector<std::vector<size_t>> args(n);\n    for (int i = 0; i < n; i++) {\n        args[i] = argsort(nums[i]);\n        std::reverse(args[i].begin(), args[i].end());\n    }\n\n    std::vector<long long> indexes(n, 0);\n    for (int i = 0; i < m; i++) {\n        printf(\"%06Ld%06ld\\n\", p[i] + 1, args[p[i]][indexes[p[i]]++]);\n    }\n}\n", "language": "C++", "metadata": {"date": 1591541793, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03221.html", "problem_id": "p03221", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03221/input.txt", "sample_output_relpath": "derived/input_output/data/p03221/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03221/C++/s398962183.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s398962183", "user_id": "u083910207"}, "prompt_components": {"gold_output": "000001000002\n000002000001\n000001000001\n", "input_to_evaluate": "#include <algorithm>\n#include <climits>\n#include <cmath>\n#include <deque>\n#include <iostream>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <regex>\n#include <unordered_map>\n#include <vector>\n\nconst int mod = 1e9 + 7;\nconst int kmax = 510000;\nconst int last_days[] = { 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };\n\nlong long fact[kmax], fact_inv[kmax], inv[kmax];\n\nvoid init_comb()\n{\n    fact[0] = fact[1] = 1;\n    fact_inv[0] = fact_inv[1] = 1;\n    inv[1] = 1;\n    for (int i = 2; i < kmax; i++) {\n        fact[i] = fact[i - 1] * i % mod;\n        inv[i] = mod - inv[mod % i] * (mod / i) % mod;\n        fact_inv[i] = fact_inv[i - 1] * inv[i] % mod;\n    }\n}\n\nlong long comb(int n, int r)\n{\n    if (n < r) {\n        return 0;\n    }\n\n    if (n < 0 || r < 0) {\n        return 0;\n    }\n\n    return fact[n] * (fact_inv[r] * fact_inv[n - r] % mod) % mod;\n}\n\ntemplate <typename T, T N>\nclass UnionFind {\n    T parent_[N];\n    T rank_[N];\n    T size_[N];\n\npublic:\n    UnionFind();\n    T Root(T idx);\n    bool IsSame(T x, T y);\n    void Unite(T x, T y);\n    T GetSize(T idx);\n};\n\ntemplate <typename T, T N>\nUnionFind<T, N>::UnionFind()\n{\n    for (T i = 0; i < N; i++) {\n        parent_[i] = i;\n        rank_[i] = 0;\n        size_[i] = 1;\n    }\n}\n\ntemplate <typename T, T N>\nT UnionFind<T, N>::Root(T idx)\n{\n    return parent_[idx] == idx ? idx : parent_[idx] = Root(parent_[idx]);\n}\n\ntemplate <typename T, T N>\nbool UnionFind<T, N>::IsSame(T x, T y)\n{\n    return Root(x) == Root(y);\n}\n\ntemplate <typename T, T N>\nvoid UnionFind<T, N>::Unite(T x, T y)\n{\n    x = Root(x);\n    y = Root(y);\n    if (x == y) {\n        return;\n    }\n\n    if (rank_[x] < rank_[y]) {\n        parent_[x] = y;\n        size_[y] += size_[x];\n    } else {\n        parent_[y] = x;\n        size_[x] += size_[y];\n        if (rank_[x] == rank_[y]) {\n            rank_[x]++;\n        }\n    }\n}\n\ntemplate <typename T, T N>\nT UnionFind<T, N>::GetSize(T idx)\n{\n    return size_[Root(idx)];\n}\n\nlong long pow_mod(long long n, long long p, long long m)\n{\n    if (p == 0) {\n        return 1;\n    }\n\n    if (p % 2 == 0) {\n        long long t = pow_mod(n, p / 2, m);\n        return t * t % m;\n    }\n    return n * pow_mod(n, p - 1, m) % mod;\n}\n\nlong long nCr_mod(long long n, long long r)\n{\n    long long x = 1;\n    for (long long i = n - r + 1; i <= n; i++) {\n        x *= i;\n        x %= mod;\n    }\n\n    long long a = 1;\n    for (long long i = 1; i <= r; i++) {\n        a *= i;\n        a %= mod;\n    }\n\n    long long y = pow_mod(a, mod - 2, mod) % mod;\n\n    return x * y % mod;\n}\n\nbool is_prime(long long n)\n{\n    if (n == 1) {\n        return false;\n    }\n\n    for (long long i = 2; i * i <= n; i++) {\n        if (n % i == 0) {\n            return false;\n        }\n    }\n\n    return true;\n}\n\nbool is_leap(long long y)\n{\n    return (y % 4 == 0 && y % 100 != 0) || y % 400 == 0;\n}\n\nvoid next_day(long long& y, long long& m, long long& d)\n{\n    d++;\n\n    if (d > last_days[m - 1] + (m == 2 && is_leap(y) ? 1 : 0)) {\n        d = 1;\n        m++;\n    }\n\n    if (m > 12) {\n        y++;\n        m = 1;\n    }\n}\n\nlong long fib(long long n)\n{\n    long long a = 0, b = 1;\n    for (int i = 0; i < n; i++) {\n        long long t = a;\n        a = b;\n        b = a + t;\n    }\n\n    return a;\n}\n\nstd::vector<size_t> argsort(const std::vector<long long>& v)\n{\n    std::vector<size_t> indices(v.size());\n    std::iota(indices.begin(), indices.end(), 0);\n\n    std::sort(indices.begin(), indices.end(), [&v](size_t i, size_t j) { return v[i] < v[j]; });\n\n    for (auto i = 0LU; i < indices.size(); i++) {\n        indices[i]++;\n    }\n\n    return indices;\n}\n\nint main()\n{\n    long long n, m;\n    std::cin >> n >> m;\n\n    std::vector<long long> p(m), y(m);\n\n    for (int i = 0; i < m; i++) {\n        std::cin >> p[i] >> y[i];\n        p[i]--;\n    }\n\n    std::vector<std::vector<long long>> nums(n);\n\n    for (int i = 0; i < m; i++) {\n        nums[p[i]].push_back(y[i]);\n    }\n\n    for (int i = 0; i < n; i++) {\n        std::reverse(nums[i].begin(), nums[i].end());\n    }\n\n    std::vector<std::vector<size_t>> args(n);\n    for (int i = 0; i < n; i++) {\n        args[i] = argsort(nums[i]);\n        std::reverse(args[i].begin(), args[i].end());\n    }\n\n    std::vector<long long> indexes(n, 0);\n    for (int i = 0; i < m; i++) {\n        printf(\"%06Ld%06ld\\n\", p[i] + 1, args[p[i]][indexes[p[i]]++]);\n    }\n}\n", "problem_context": "Score: 300 points\n\nProblem Statement\n\nIn Republic of Atcoder, there are N prefectures, and a total of M cities that belong to those prefectures.\n\nCity i is established in year Y_i and belongs to Prefecture P_i.\n\nYou can assume that there are no multiple cities that are established in the same year.\n\nIt is decided to allocate a 12-digit ID number to each city.\n\nIf City i is the x-th established city among the cities that belong to Prefecture i, the first six digits of the ID number of City i is P_i, and the last six digits of the ID number is x.\n\nHere, if P_i or x (or both) has less than six digits, zeros are added to the left until it has six digits.\n\nFind the ID numbers for all the cities.\n\nNote that there can be a prefecture with no cities.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq P_i \\leq N\n\n1 \\leq Y_i \\leq 10^9\n\nY_i are all different.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nP_1 Y_1\n:\nP_M Y_M\n\nOutput\n\nPrint the ID numbers for all the cities, in ascending order of indices (City 1, City 2, ...).\n\nSample Input 1\n\n2 3\n1 32\n2 63\n1 12\n\nSample Output 1\n\n000001000002\n000002000001\n000001000001\n\nAs City 1 is the second established city among the cities that belong to Prefecture 1, its ID number is 000001000002.\n\nAs City 2 is the first established city among the cities that belong to Prefecture 2, its ID number is 000002000001.\n\nAs City 3 is the first established city among the cities that belong to Prefecture 1, its ID number is 000001000001.\n\nSample Input 2\n\n2 3\n2 55\n2 77\n2 99\n\nSample Output 2\n\n000002000001\n000002000002\n000002000003", "sample_input": "2 3\n1 32\n2 63\n1 12\n"}, "reference_outputs": ["000001000002\n000002000001\n000001000001\n"], "source_document_id": "p03221", "source_text": "Score: 300 points\n\nProblem Statement\n\nIn Republic of Atcoder, there are N prefectures, and a total of M cities that belong to those prefectures.\n\nCity i is established in year Y_i and belongs to Prefecture P_i.\n\nYou can assume that there are no multiple cities that are established in the same year.\n\nIt is decided to allocate a 12-digit ID number to each city.\n\nIf City i is the x-th established city among the cities that belong to Prefecture i, the first six digits of the ID number of City i is P_i, and the last six digits of the ID number is x.\n\nHere, if P_i or x (or both) has less than six digits, zeros are added to the left until it has six digits.\n\nFind the ID numbers for all the cities.\n\nNote that there can be a prefecture with no cities.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq P_i \\leq N\n\n1 \\leq Y_i \\leq 10^9\n\nY_i are all different.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nP_1 Y_1\n:\nP_M Y_M\n\nOutput\n\nPrint the ID numbers for all the cities, in ascending order of indices (City 1, City 2, ...).\n\nSample Input 1\n\n2 3\n1 32\n2 63\n1 12\n\nSample Output 1\n\n000001000002\n000002000001\n000001000001\n\nAs City 1 is the second established city among the cities that belong to Prefecture 1, its ID number is 000001000002.\n\nAs City 2 is the first established city among the cities that belong to Prefecture 2, its ID number is 000002000001.\n\nAs City 3 is the first established city among the cities that belong to Prefecture 1, its ID number is 000001000001.\n\nSample Input 2\n\n2 3\n2 55\n2 77\n2 99\n\nSample Output 2\n\n000002000001\n000002000002\n000002000003", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 4341, "cpu_time_ms": 111, "memory_kb": 14720}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s465362390", "group_id": "codeNet:p03222", "input_text": "#include <bits/stdc++.h>\n#define int long long\n#define mod (int)(1e9+7)\n#define inf (int)(3e18+7)\n#define rep(i,n) for(int i=0;i<n;i++)\n#define REP(i,n) for(int i=1;i<n;i++)\n#define P pair<int,int>\n#define all(v) v.begin(),v.end()\n#define mkp make_pair\n#define mkt make_tuple\n#define prique(T) priority_queue<T,vector<T>,greater<T>>\n#define vecunique(vec) sort(vec.begin(), vec.end());decltype(vec)::iterator result = std::unique(vec.begin(), vec.end());vec.erase(result, vec.end())\nusing namespace std;\n\nbool prime(int x) {\n\tfor (int i = 2; i * i <= x; i++) {\n\t\tif (x % i == 0)return false;\n\t}\n\treturn x > 1;\n}\nint gcd(int x, int y) {\n\tif (y == 0)return x;\n\treturn gcd(y, x % y);\n}\nint lcm(int x, int y) {\n\treturn x * y / gcd(x, y);\n}\nint kai(int x) {\n\tif (x == 0)return 1;\n\treturn kai(x - 1) * x % mod;\n}\nint mod_pow(int x, int y, int mod_) {\n\tint res = 1;\n\twhile (y > 0) {\n\t\tif (y & 1) {\n\t\t\tres = res * x % mod_;\n\t\t}\n\t\tx = x * x % mod_;\n\t\ty >>= 1;\n\t}\n\treturn res;\n}\nint comb(int x, int y) {\n\treturn kai(x)* mod_pow(kai(x - y), mod - 2, mod) % mod * mod_pow(kai(y), mod - 2, mod) % mod;\n}\n/*--------Library Zone!--------*/\n\nint h, w, k;\nint dp[114][19];\nsigned main() {\n\tcin >> h >> w >> k;\n\tdp[0][0] = 1;\n\trep(i, h) {\n\t\trep(j, w) {\n\t\t\tdp[i][j] %= mod;\n\t\t\trep(k, 1 << (w - 1)) {\n\t\t\t\trep(l, w - 2) {\n\t\t\t\t\tif ((k >> l) & 1 && (k >> (l + 1) & 1))goto ng;\n\t\t\t\t}\n\t\t\t\tif (j && (k >> (j - 1)) & 1)dp[i + 1][j - 1] += dp[i][j];\n\t\t\t\telse if ((k >> j) & 1)dp[i + 1][j + 1] += dp[i][j];\n\t\t\t\telse dp[i + 1][j] += dp[i][j];\n\t\t\tng:;\n\t\t\t}\n\t\t}\n\t}\n\tcout << dp[h][k - 1] % mod << endl;\n}", "language": "C++", "metadata": {"date": 1558219920, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03222.html", "problem_id": "p03222", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03222/input.txt", "sample_output_relpath": "derived/input_output/data/p03222/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03222/C++/s465362390.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s465362390", "user_id": "u147049801"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define int long long\n#define mod (int)(1e9+7)\n#define inf (int)(3e18+7)\n#define rep(i,n) for(int i=0;i<n;i++)\n#define REP(i,n) for(int i=1;i<n;i++)\n#define P pair<int,int>\n#define all(v) v.begin(),v.end()\n#define mkp make_pair\n#define mkt make_tuple\n#define prique(T) priority_queue<T,vector<T>,greater<T>>\n#define vecunique(vec) sort(vec.begin(), vec.end());decltype(vec)::iterator result = std::unique(vec.begin(), vec.end());vec.erase(result, vec.end())\nusing namespace std;\n\nbool prime(int x) {\n\tfor (int i = 2; i * i <= x; i++) {\n\t\tif (x % i == 0)return false;\n\t}\n\treturn x > 1;\n}\nint gcd(int x, int y) {\n\tif (y == 0)return x;\n\treturn gcd(y, x % y);\n}\nint lcm(int x, int y) {\n\treturn x * y / gcd(x, y);\n}\nint kai(int x) {\n\tif (x == 0)return 1;\n\treturn kai(x - 1) * x % mod;\n}\nint mod_pow(int x, int y, int mod_) {\n\tint res = 1;\n\twhile (y > 0) {\n\t\tif (y & 1) {\n\t\t\tres = res * x % mod_;\n\t\t}\n\t\tx = x * x % mod_;\n\t\ty >>= 1;\n\t}\n\treturn res;\n}\nint comb(int x, int y) {\n\treturn kai(x)* mod_pow(kai(x - y), mod - 2, mod) % mod * mod_pow(kai(y), mod - 2, mod) % mod;\n}\n/*--------Library Zone!--------*/\n\nint h, w, k;\nint dp[114][19];\nsigned main() {\n\tcin >> h >> w >> k;\n\tdp[0][0] = 1;\n\trep(i, h) {\n\t\trep(j, w) {\n\t\t\tdp[i][j] %= mod;\n\t\t\trep(k, 1 << (w - 1)) {\n\t\t\t\trep(l, w - 2) {\n\t\t\t\t\tif ((k >> l) & 1 && (k >> (l + 1) & 1))goto ng;\n\t\t\t\t}\n\t\t\t\tif (j && (k >> (j - 1)) & 1)dp[i + 1][j - 1] += dp[i][j];\n\t\t\t\telse if ((k >> j) & 1)dp[i + 1][j + 1] += dp[i][j];\n\t\t\t\telse dp[i + 1][j] += dp[i][j];\n\t\t\tng:;\n\t\t\t}\n\t\t}\n\t}\n\tcout << dp[h][k - 1] % mod << endl;\n}", "problem_context": "Score: 400 points\n\nProblem Statement\n\nAmidakuji is a traditional method of lottery in Japan.\n\nTo make an amidakuji, we first draw W parallel vertical lines, and then draw horizontal lines that connect them. The length of each vertical line is H+1 [cm], and the endpoints of the horizontal lines must be at 1, 2, 3, ..., or H [cm] from the top of a vertical line.\n\nA valid amidakuji is an amidakuji that satisfies the following conditions:\n\nNo two horizontal lines share an endpoint.\n\nThe two endpoints of each horizontal lines must be at the same height.\n\nA horizontal line must connect adjacent vertical lines.\n\nFind the number of the valid amidakuji that satisfy the following condition, modulo 1\\ 000\\ 000\\ 007: if we trace the path from the top of the leftmost vertical line to the bottom, always following horizontal lines when we encounter them, we reach the bottom of the K-th vertical line from the left.\n\nFor example, in the following amidakuji, we will reach the bottom of the fourth vertical line from the left.\n\nConstraints\n\nH is an integer between 1 and 100 (inclusive).\n\nW is an integer between 1 and 8 (inclusive).\n\nK is an integer between 1 and W (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W K\n\nOutput\n\nPrint the number of the amidakuji that satisfy the condition, modulo 1\\ 000\\ 000\\ 007.\n\nSample Input 1\n\n1 3 2\n\nSample Output 1\n\n1\n\nOnly the following one amidakuji satisfies the condition:\n\nSample Input 2\n\n1 3 1\n\nSample Output 2\n\n2\n\nOnly the following two amidakuji satisfy the condition:\n\nSample Input 3\n\n2 3 3\n\nSample Output 3\n\n1\n\nOnly the following one amidakuji satisfies the condition:\n\nSample Input 4\n\n2 3 1\n\nSample Output 4\n\n5\n\nOnly the following five amidakuji satisfy the condition:\n\nSample Input 5\n\n7 1 1\n\nSample Output 5\n\n1\n\nAs there is only one vertical line, we cannot draw any horizontal lines. Thus, there is only one amidakuji that satisfies the condition: the amidakuji with no horizontal lines.\n\nSample Input 6\n\n15 8 5\n\nSample Output 6\n\n437760187\n\nBe sure to print the answer modulo 1\\ 000\\ 000\\ 007.", "sample_input": "1 3 2\n"}, "reference_outputs": ["1\n"], "source_document_id": "p03222", "source_text": "Score: 400 points\n\nProblem Statement\n\nAmidakuji is a traditional method of lottery in Japan.\n\nTo make an amidakuji, we first draw W parallel vertical lines, and then draw horizontal lines that connect them. The length of each vertical line is H+1 [cm], and the endpoints of the horizontal lines must be at 1, 2, 3, ..., or H [cm] from the top of a vertical line.\n\nA valid amidakuji is an amidakuji that satisfies the following conditions:\n\nNo two horizontal lines share an endpoint.\n\nThe two endpoints of each horizontal lines must be at the same height.\n\nA horizontal line must connect adjacent vertical lines.\n\nFind the number of the valid amidakuji that satisfy the following condition, modulo 1\\ 000\\ 000\\ 007: if we trace the path from the top of the leftmost vertical line to the bottom, always following horizontal lines when we encounter them, we reach the bottom of the K-th vertical line from the left.\n\nFor example, in the following amidakuji, we will reach the bottom of the fourth vertical line from the left.\n\nConstraints\n\nH is an integer between 1 and 100 (inclusive).\n\nW is an integer between 1 and 8 (inclusive).\n\nK is an integer between 1 and W (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W K\n\nOutput\n\nPrint the number of the amidakuji that satisfy the condition, modulo 1\\ 000\\ 000\\ 007.\n\nSample Input 1\n\n1 3 2\n\nSample Output 1\n\n1\n\nOnly the following one amidakuji satisfies the condition:\n\nSample Input 2\n\n1 3 1\n\nSample Output 2\n\n2\n\nOnly the following two amidakuji satisfy the condition:\n\nSample Input 3\n\n2 3 3\n\nSample Output 3\n\n1\n\nOnly the following one amidakuji satisfies the condition:\n\nSample Input 4\n\n2 3 1\n\nSample Output 4\n\n5\n\nOnly the following five amidakuji satisfy the condition:\n\nSample Input 5\n\n7 1 1\n\nSample Output 5\n\n1\n\nAs there is only one vertical line, we cannot draw any horizontal lines. Thus, there is only one amidakuji that satisfies the condition: the amidakuji with no horizontal lines.\n\nSample Input 6\n\n15 8 5\n\nSample Output 6\n\n437760187\n\nBe sure to print the answer modulo 1\\ 000\\ 000\\ 007.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1571, "cpu_time_ms": 2, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s860361405", "group_id": "codeNet:p03229", "input_text": "#include<iostream>\n#include<iomanip>\n#include<cstdio>\n#include<string>\n#include<cstring>\n#include<climits>\n#include<algorithm>\n#include<vector>\n#include<cmath>\n#include<map>\n#include<set>\n#include<stack>\n#include<queue>\n#include<deque>\n#include<tuple>\n#include<list>\n#include<unordered_map>\n#define ll long long\n#define pii pair<int,int>\n#define pll pair<ll,ll>\n#define vii vector<int>\n#define vll vector<ll>\n#define lb lower_bound\n#define pb push_back\n#define mp make_pair\n#define rep(i,n) for(ll i=0;i<n;i++)\n#define rep2(i,a,b) for(ll i=a;i<b;i++)\n#define repr(i,n) for(ll i=n-1;i>=0;i--)\n#define all(x) x.begin(),x.end()\n#define INF (1 << 30) - 1\n#define LLINF (1LL << 61) - 1\n// #define int ll\nusing namespace std;\nconst int MOD = 1000000007;\nconst int MAX = 510000;\n\n\nint main(){\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n    ll n,a[100010],ans=0;\n    deque<ll> deq;\n    cin>>n;\n    rep(i,n){\n        cin>>a[i];\n    }\n    sort(a,a+n);\n    rep(i,n-1){\n        if(i%4==0){\n            deq.push_back(a[n-(i/2+1)]);\n        }\n        else if(i%4==1){\n            deq.push_front(a[i/2]);\n        }\n        else if(i%4==2){\n            deq.push_back(a[i/2]);\n        }\n        else{\n            deq.push_front(a[n-(i/2+1)]);\n        }\n    }\n    rep(i,n-2){\n        ans+=abs(deq.at(i)-deq.at(i+1));\n    }\n    ans+=max(abs(deq.at(0)-a[n/2-(1-n%2)]),abs(deq.at(n-2)-a[n/2-(1-n%2)]));\n    cout<<ans<<endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1563326590, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03229.html", "problem_id": "p03229", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03229/input.txt", "sample_output_relpath": "derived/input_output/data/p03229/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03229/C++/s860361405.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s860361405", "user_id": "u241367243"}, "prompt_components": {"gold_output": "21\n", "input_to_evaluate": "#include<iostream>\n#include<iomanip>\n#include<cstdio>\n#include<string>\n#include<cstring>\n#include<climits>\n#include<algorithm>\n#include<vector>\n#include<cmath>\n#include<map>\n#include<set>\n#include<stack>\n#include<queue>\n#include<deque>\n#include<tuple>\n#include<list>\n#include<unordered_map>\n#define ll long long\n#define pii pair<int,int>\n#define pll pair<ll,ll>\n#define vii vector<int>\n#define vll vector<ll>\n#define lb lower_bound\n#define pb push_back\n#define mp make_pair\n#define rep(i,n) for(ll i=0;i<n;i++)\n#define rep2(i,a,b) for(ll i=a;i<b;i++)\n#define repr(i,n) for(ll i=n-1;i>=0;i--)\n#define all(x) x.begin(),x.end()\n#define INF (1 << 30) - 1\n#define LLINF (1LL << 61) - 1\n// #define int ll\nusing namespace std;\nconst int MOD = 1000000007;\nconst int MAX = 510000;\n\n\nint main(){\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n    ll n,a[100010],ans=0;\n    deque<ll> deq;\n    cin>>n;\n    rep(i,n){\n        cin>>a[i];\n    }\n    sort(a,a+n);\n    rep(i,n-1){\n        if(i%4==0){\n            deq.push_back(a[n-(i/2+1)]);\n        }\n        else if(i%4==1){\n            deq.push_front(a[i/2]);\n        }\n        else if(i%4==2){\n            deq.push_back(a[i/2]);\n        }\n        else{\n            deq.push_front(a[n-(i/2+1)]);\n        }\n    }\n    rep(i,n-2){\n        ans+=abs(deq.at(i)-deq.at(i+1));\n    }\n    ans+=max(abs(deq.at(0)-a[n/2-(1-n%2)]),abs(deq.at(n-2)-a[n/2-(1-n%2)]));\n    cout<<ans<<endl;\n    return 0;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nYou are given N integers; the i-th of them is A_i.\nFind the maximum possible sum of the absolute differences between the adjacent elements after arranging these integers in a row in any order you like.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n1 \\leq A_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1\n:\nA_N\n\nOutput\n\nPrint the maximum possible sum of the absolute differences between the adjacent elements after arranging the given integers in a row in any order you like.\n\nSample Input 1\n\n5\n6\n8\n1\n2\n3\n\nSample Output 1\n\n21\n\nWhen the integers are arranged as 3,8,1,6,2, the sum of the absolute differences between the adjacent elements is |3 - 8| + |8 - 1| + |1 - 6| + |6 - 2| = 21. This is the maximum possible sum.\n\nSample Input 2\n\n6\n3\n1\n4\n1\n5\n9\n\nSample Output 2\n\n25\n\nSample Input 3\n\n3\n5\n5\n1\n\nSample Output 3\n\n8", "sample_input": "5\n6\n8\n1\n2\n3\n"}, "reference_outputs": ["21\n"], "source_document_id": "p03229", "source_text": "Score : 400 points\n\nProblem Statement\n\nYou are given N integers; the i-th of them is A_i.\nFind the maximum possible sum of the absolute differences between the adjacent elements after arranging these integers in a row in any order you like.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n1 \\leq A_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1\n:\nA_N\n\nOutput\n\nPrint the maximum possible sum of the absolute differences between the adjacent elements after arranging the given integers in a row in any order you like.\n\nSample Input 1\n\n5\n6\n8\n1\n2\n3\n\nSample Output 1\n\n21\n\nWhen the integers are arranged as 3,8,1,6,2, the sum of the absolute differences between the adjacent elements is |3 - 8| + |8 - 1| + |1 - 6| + |6 - 2| = 21. This is the maximum possible sum.\n\nSample Input 2\n\n6\n3\n1\n4\n1\n5\n9\n\nSample Output 2\n\n25\n\nSample Input 3\n\n3\n5\n5\n1\n\nSample Output 3\n\n8", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1424, "cpu_time_ms": 21, "memory_kb": 1920}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s325492176", "group_id": "codeNet:p03229", "input_text": "#include <bits/stdc++.h>\n#define rep(i, a, b) for(int i = int(a); i < int(b); i++)\n#define rer(i, a, b) for(int i = int(a) - 1; i >= int(b); i--)\n#define sz(v) (int)(v).size()\n#define pb push_back\n#define sc second\n#define fr first\n#define sor(v) sort(v.begin(),v.end())\n#define rev(s) reverse(s.begin(),s.end())\n#define lb(vec,a) lower_bound(vec.begin(),vec.end(),a)\n#define ub(vec,a) upper_bound(vec.begin(),vec.end(),a)\n#define uniq(vec) vec.erase(unique(vec.begin(),vec.end()),vec.end())\nusing namespace std;\ntypedef long long int ll;\ntypedef pair <int, int> P;\n\nconst ll MOD=1000000007;\n\nint main() {\n    ios::sync_with_stdio(false);\n    cin.tie(0);\n    ll N;\n    cin>>N;\n    vector<ll> A;\n    rep(i,0,N){\n        ll a;\n        cin>>a;\n        A.pb(a);\n    }\n    sor(A);\n    ll res1=0,res2=0;\n    if(N%2){\n        rep(i,N/2+1,N){\n            res1+=2*A[i];\n        }\n        rep(i,0,N/2-1){\n            res1-=2*A[i];\n        }\n        res1-=A[N/2-1]+A[N/2];\n        rep(i,0,N/2){\n            res2-=2*A[i];\n        }\n        rep(i,N/2,N){\n            res2+=2*A[i];\n        }\n        res2-=A[N/2]+A[N/2+1];\n    }\n    else{\n        rep(i,N/2,N){\n            res1+=2*A[i];\n        }\n        rep(i,0,N/2){\n            res1-=2*A[i];\n        }\n        res1+=-A[N/2]+A[N/2-1];\n    }\n    cout <<max(res1,res2)<<\"\\n\";\n}", "language": "C++", "metadata": {"date": 1549667576, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03229.html", "problem_id": "p03229", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03229/input.txt", "sample_output_relpath": "derived/input_output/data/p03229/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03229/C++/s325492176.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s325492176", "user_id": "u235155157"}, "prompt_components": {"gold_output": "21\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define rep(i, a, b) for(int i = int(a); i < int(b); i++)\n#define rer(i, a, b) for(int i = int(a) - 1; i >= int(b); i--)\n#define sz(v) (int)(v).size()\n#define pb push_back\n#define sc second\n#define fr first\n#define sor(v) sort(v.begin(),v.end())\n#define rev(s) reverse(s.begin(),s.end())\n#define lb(vec,a) lower_bound(vec.begin(),vec.end(),a)\n#define ub(vec,a) upper_bound(vec.begin(),vec.end(),a)\n#define uniq(vec) vec.erase(unique(vec.begin(),vec.end()),vec.end())\nusing namespace std;\ntypedef long long int ll;\ntypedef pair <int, int> P;\n\nconst ll MOD=1000000007;\n\nint main() {\n    ios::sync_with_stdio(false);\n    cin.tie(0);\n    ll N;\n    cin>>N;\n    vector<ll> A;\n    rep(i,0,N){\n        ll a;\n        cin>>a;\n        A.pb(a);\n    }\n    sor(A);\n    ll res1=0,res2=0;\n    if(N%2){\n        rep(i,N/2+1,N){\n            res1+=2*A[i];\n        }\n        rep(i,0,N/2-1){\n            res1-=2*A[i];\n        }\n        res1-=A[N/2-1]+A[N/2];\n        rep(i,0,N/2){\n            res2-=2*A[i];\n        }\n        rep(i,N/2,N){\n            res2+=2*A[i];\n        }\n        res2-=A[N/2]+A[N/2+1];\n    }\n    else{\n        rep(i,N/2,N){\n            res1+=2*A[i];\n        }\n        rep(i,0,N/2){\n            res1-=2*A[i];\n        }\n        res1+=-A[N/2]+A[N/2-1];\n    }\n    cout <<max(res1,res2)<<\"\\n\";\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nYou are given N integers; the i-th of them is A_i.\nFind the maximum possible sum of the absolute differences between the adjacent elements after arranging these integers in a row in any order you like.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n1 \\leq A_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1\n:\nA_N\n\nOutput\n\nPrint the maximum possible sum of the absolute differences between the adjacent elements after arranging the given integers in a row in any order you like.\n\nSample Input 1\n\n5\n6\n8\n1\n2\n3\n\nSample Output 1\n\n21\n\nWhen the integers are arranged as 3,8,1,6,2, the sum of the absolute differences between the adjacent elements is |3 - 8| + |8 - 1| + |1 - 6| + |6 - 2| = 21. This is the maximum possible sum.\n\nSample Input 2\n\n6\n3\n1\n4\n1\n5\n9\n\nSample Output 2\n\n25\n\nSample Input 3\n\n3\n5\n5\n1\n\nSample Output 3\n\n8", "sample_input": "5\n6\n8\n1\n2\n3\n"}, "reference_outputs": ["21\n"], "source_document_id": "p03229", "source_text": "Score : 400 points\n\nProblem Statement\n\nYou are given N integers; the i-th of them is A_i.\nFind the maximum possible sum of the absolute differences between the adjacent elements after arranging these integers in a row in any order you like.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n1 \\leq A_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1\n:\nA_N\n\nOutput\n\nPrint the maximum possible sum of the absolute differences between the adjacent elements after arranging the given integers in a row in any order you like.\n\nSample Input 1\n\n5\n6\n8\n1\n2\n3\n\nSample Output 1\n\n21\n\nWhen the integers are arranged as 3,8,1,6,2, the sum of the absolute differences between the adjacent elements is |3 - 8| + |8 - 1| + |1 - 6| + |6 - 2| = 21. This is the maximum possible sum.\n\nSample Input 2\n\n6\n3\n1\n4\n1\n5\n9\n\nSample Output 2\n\n25\n\nSample Input 3\n\n3\n5\n5\n1\n\nSample Output 3\n\n8", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1313, "cpu_time_ms": 19, "memory_kb": 1400}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s765660553", "group_id": "codeNet:p03243", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n\n\nstruct node\n{\n\t int c;\n\t int num;\n\t \n};\nstruct node a[100005],b[100005];\n\nbool cmp(node a,node b)\n{\n\t return a.c>b.c;\n}\nint main()\n{for(int i=0;i<100005;i++)\n{\n\ta[i].c=0;\n\ta[i].num=i;\n\tb[i].c=0;\n\tb[i].num=i;\n}\n\t int n;\n\t cin>>n;\n\t  int jd=0,od=0,jx=1000000000,ox=1000000000;\n\t vector<int>j,o;\n\t int jmax=0,jmaxn=0,omax=0,omaxn=0;\n\t for(int i=1;i<=n;i++)\n\t {int t;\n\t cin>>t;\n\t \n\t \tif(i&1)\n\t \t{\n\t \t    j.push_back(t);\n\t \t    jd=max(jd,t);\n\t \t    jx=min(jx,t);\n\t \t    a[t].c++;\n\t \t  \n\t \t    if(a[t].c>jmax)\n\t \t    {\n\t \t    \tjmax=a[t].c;\n\t \t    \tjmaxn=t;\n\t\t\t }\n\t\t }\n\t\t else\n\t\t {   \n\t\t \to.push_back(t);\n\t\t \tod=max(od,t);\n\t\t \tox=min(ox,t);\n\t\t \tb[t].c++;\n\t\t \tif(b[t].c>omax)\n\t \t    {\n\t \t    \tomax=b[t].c;\n\t \t    \tomaxn=t;\n\t\t\t }\n\t\t }\n\t \t\n\t }\n\t if(jd==od&&jx==ox&&jd==jx)\n\t    {\n\t    \tcout<<j.size()<<endl;\n\t    \treturn 0;\n\t\t}\n\t sort(a,a+100005,cmp);\n\t \t sort(b,b+100005,cmp);\n\t \t\n\t\n\t\n\t/* jd=max_element(j.begin(),j.end());\n\t  od=max_element(o.begin(),o.end());\n\t   jx=min_element(j.begin(),j.end());\n\t    ox=min_element(o.begin(),o.end());*/\n\t    \n\t    int jc=0,oc=0;\n\t    if(jmaxn==omaxn)\n\t    {\n\t    \tjmaxn=a[1].num;\n\t\t}\n\t    for(int i=0;i<j.size();i++)\n\t    {\n\t    \tif(jmaxn!=j[i])\n\t    \t{\n\t    \t\tjc++;\n\t    \t\tj[i]=jmaxn;\n\t\t\t}\n\t\t}\n\t\t\n\t\t  for(int i=0;i<o.size();i++)\n\t    {\n\t    \tif(omaxn!=o[i])\n\t    \t{\n\t    \t\toc++;\n\t    \t\to[i]=omaxn;\n\t\t\t}\n\t\t}\n\t\tcout<<jc+oc<<endl;\n}", "language": "C++", "metadata": {"date": 1538273502, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03243.html", "problem_id": "p03243", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03243/input.txt", "sample_output_relpath": "derived/input_output/data/p03243/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03243/C++/s765660553.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s765660553", "user_id": "u680195439"}, "prompt_components": {"gold_output": "111\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n\n\nstruct node\n{\n\t int c;\n\t int num;\n\t \n};\nstruct node a[100005],b[100005];\n\nbool cmp(node a,node b)\n{\n\t return a.c>b.c;\n}\nint main()\n{for(int i=0;i<100005;i++)\n{\n\ta[i].c=0;\n\ta[i].num=i;\n\tb[i].c=0;\n\tb[i].num=i;\n}\n\t int n;\n\t cin>>n;\n\t  int jd=0,od=0,jx=1000000000,ox=1000000000;\n\t vector<int>j,o;\n\t int jmax=0,jmaxn=0,omax=0,omaxn=0;\n\t for(int i=1;i<=n;i++)\n\t {int t;\n\t cin>>t;\n\t \n\t \tif(i&1)\n\t \t{\n\t \t    j.push_back(t);\n\t \t    jd=max(jd,t);\n\t \t    jx=min(jx,t);\n\t \t    a[t].c++;\n\t \t  \n\t \t    if(a[t].c>jmax)\n\t \t    {\n\t \t    \tjmax=a[t].c;\n\t \t    \tjmaxn=t;\n\t\t\t }\n\t\t }\n\t\t else\n\t\t {   \n\t\t \to.push_back(t);\n\t\t \tod=max(od,t);\n\t\t \tox=min(ox,t);\n\t\t \tb[t].c++;\n\t\t \tif(b[t].c>omax)\n\t \t    {\n\t \t    \tomax=b[t].c;\n\t \t    \tomaxn=t;\n\t\t\t }\n\t\t }\n\t \t\n\t }\n\t if(jd==od&&jx==ox&&jd==jx)\n\t    {\n\t    \tcout<<j.size()<<endl;\n\t    \treturn 0;\n\t\t}\n\t sort(a,a+100005,cmp);\n\t \t sort(b,b+100005,cmp);\n\t \t\n\t\n\t\n\t/* jd=max_element(j.begin(),j.end());\n\t  od=max_element(o.begin(),o.end());\n\t   jx=min_element(j.begin(),j.end());\n\t    ox=min_element(o.begin(),o.end());*/\n\t    \n\t    int jc=0,oc=0;\n\t    if(jmaxn==omaxn)\n\t    {\n\t    \tjmaxn=a[1].num;\n\t\t}\n\t    for(int i=0;i<j.size();i++)\n\t    {\n\t    \tif(jmaxn!=j[i])\n\t    \t{\n\t    \t\tjc++;\n\t    \t\tj[i]=jmaxn;\n\t\t\t}\n\t\t}\n\t\t\n\t\t  for(int i=0;i<o.size();i++)\n\t    {\n\t    \tif(omaxn!=o[i])\n\t    \t{\n\t    \t\toc++;\n\t    \t\to[i]=omaxn;\n\t\t\t}\n\t\t}\n\t\tcout<<jc+oc<<endl;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nKurohashi has never participated in AtCoder Beginner Contest (ABC).\n\nThe next ABC to be held is ABC N (the N-th ABC ever held).\nKurohashi wants to make his debut in some ABC x such that all the digits of x in base ten are the same.\n\nWhat is the earliest ABC where Kurohashi can make his debut?\n\nConstraints\n\n100 \\leq N \\leq 999\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nIf the earliest ABC where Kurohashi can make his debut is ABC n, print n.\n\nSample Input 1\n\n111\n\nSample Output 1\n\n111\n\nThe next ABC to be held is ABC 111, where Kurohashi can make his debut.\n\nSample Input 2\n\n112\n\nSample Output 2\n\n222\n\nThe next ABC to be held is ABC 112, which means Kurohashi can no longer participate in ABC 111.\nAmong the ABCs where Kurohashi can make his debut, the earliest one is ABC 222.\n\nSample Input 3\n\n750\n\nSample Output 3\n\n777", "sample_input": "111\n"}, "reference_outputs": ["111\n"], "source_document_id": "p03243", "source_text": "Score : 200 points\n\nProblem Statement\n\nKurohashi has never participated in AtCoder Beginner Contest (ABC).\n\nThe next ABC to be held is ABC N (the N-th ABC ever held).\nKurohashi wants to make his debut in some ABC x such that all the digits of x in base ten are the same.\n\nWhat is the earliest ABC where Kurohashi can make his debut?\n\nConstraints\n\n100 \\leq N \\leq 999\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nIf the earliest ABC where Kurohashi can make his debut is ABC n, print n.\n\nSample Input 1\n\n111\n\nSample Output 1\n\n111\n\nThe next ABC to be held is ABC 111, where Kurohashi can make his debut.\n\nSample Input 2\n\n112\n\nSample Output 2\n\n222\n\nThe next ABC to be held is ABC 112, which means Kurohashi can no longer participate in ABC 111.\nAmong the ABCs where Kurohashi can make his debut, the earliest one is ABC 222.\n\nSample Input 3\n\n750\n\nSample Output 3\n\n777", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1408, "cpu_time_ms": 2, "memory_kb": 1792}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s351199614", "group_id": "codeNet:p03243", "input_text": "//==================== default starts ====================//\n#include <bits/stdc++.h>\n \nusing namespace std;\n \n#define fread(x)        freopen(x,\"r\",stdin)\n#define fwrite(x)       freopen (x,\"w\",stdout)\n \n#define min3(a,b,c)     min(a,min(b,c))\n#define max3(a,b,c)     max(a,max(b,c))\n#define min4(a,b,c,d)   min(a,min(b,min(c,d)))\n#define max4(a,b,c,d)   max(a,max(b,max(c,d)))\n#define SQR(a)          ((a)*(a))\n#define MEMSET(a,x)     memset(a,x,sizeof(a))\n#define ABS(x)          ((x)<0?-(x):(x))\n \n#define white           1\n#define grey            2\n#define black           3\n \n#define ll              long long\n#define pb              push_back\n#define pf              push_front\n#define INF             9e18\n#define PI              acos(-1.0)\n#define pii             pair<int,int>\n#define pll             pair<ll, ll>\n \n#define all(v)          v.begin(), v.end()\n \n#define fastread        ios_base::sync_with_stdio(0);cin.tie(nullptr);\nint on(int N,int pos){return N=N | (1<<pos);}\nint off(int N,int pos){return N= N & ~(1<<pos);}\nbool check(int N,int pos){return (bool)(N & (1<<pos));}\n//==================== default ends ====================//\nint arr[] = {111,222,333,444,555,666,777,888,999};\nint find_num(int n){\n\tint mid = 9/2, start = 0, ed = 9;\n\twhile(ed-start > 1){\n\t\tmid=(start+ed)>>1;\n\t\tif(arr[mid] > n){\n\t\t\ted = mid;\n\t\t}else if(arr[mid] < n){\n\t\t\tstart = mid;\n\t\t}else{\n\t\t\treturn arr[mid];\n\t\t}\n\t}\n\tif(arr[start]==n)return arr[start];\n\telse return arr[start+1];\n}\nint main(){\n\tfastread\n\tint n;\n\tcin>>n;\n\tcout<<find_num(n)<<endl;\n}", "language": "C++", "metadata": {"date": 1538270533, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03243.html", "problem_id": "p03243", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03243/input.txt", "sample_output_relpath": "derived/input_output/data/p03243/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03243/C++/s351199614.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s351199614", "user_id": "u423690156"}, "prompt_components": {"gold_output": "111\n", "input_to_evaluate": "//==================== default starts ====================//\n#include <bits/stdc++.h>\n \nusing namespace std;\n \n#define fread(x)        freopen(x,\"r\",stdin)\n#define fwrite(x)       freopen (x,\"w\",stdout)\n \n#define min3(a,b,c)     min(a,min(b,c))\n#define max3(a,b,c)     max(a,max(b,c))\n#define min4(a,b,c,d)   min(a,min(b,min(c,d)))\n#define max4(a,b,c,d)   max(a,max(b,max(c,d)))\n#define SQR(a)          ((a)*(a))\n#define MEMSET(a,x)     memset(a,x,sizeof(a))\n#define ABS(x)          ((x)<0?-(x):(x))\n \n#define white           1\n#define grey            2\n#define black           3\n \n#define ll              long long\n#define pb              push_back\n#define pf              push_front\n#define INF             9e18\n#define PI              acos(-1.0)\n#define pii             pair<int,int>\n#define pll             pair<ll, ll>\n \n#define all(v)          v.begin(), v.end()\n \n#define fastread        ios_base::sync_with_stdio(0);cin.tie(nullptr);\nint on(int N,int pos){return N=N | (1<<pos);}\nint off(int N,int pos){return N= N & ~(1<<pos);}\nbool check(int N,int pos){return (bool)(N & (1<<pos));}\n//==================== default ends ====================//\nint arr[] = {111,222,333,444,555,666,777,888,999};\nint find_num(int n){\n\tint mid = 9/2, start = 0, ed = 9;\n\twhile(ed-start > 1){\n\t\tmid=(start+ed)>>1;\n\t\tif(arr[mid] > n){\n\t\t\ted = mid;\n\t\t}else if(arr[mid] < n){\n\t\t\tstart = mid;\n\t\t}else{\n\t\t\treturn arr[mid];\n\t\t}\n\t}\n\tif(arr[start]==n)return arr[start];\n\telse return arr[start+1];\n}\nint main(){\n\tfastread\n\tint n;\n\tcin>>n;\n\tcout<<find_num(n)<<endl;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nKurohashi has never participated in AtCoder Beginner Contest (ABC).\n\nThe next ABC to be held is ABC N (the N-th ABC ever held).\nKurohashi wants to make his debut in some ABC x such that all the digits of x in base ten are the same.\n\nWhat is the earliest ABC where Kurohashi can make his debut?\n\nConstraints\n\n100 \\leq N \\leq 999\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nIf the earliest ABC where Kurohashi can make his debut is ABC n, print n.\n\nSample Input 1\n\n111\n\nSample Output 1\n\n111\n\nThe next ABC to be held is ABC 111, where Kurohashi can make his debut.\n\nSample Input 2\n\n112\n\nSample Output 2\n\n222\n\nThe next ABC to be held is ABC 112, which means Kurohashi can no longer participate in ABC 111.\nAmong the ABCs where Kurohashi can make his debut, the earliest one is ABC 222.\n\nSample Input 3\n\n750\n\nSample Output 3\n\n777", "sample_input": "111\n"}, "reference_outputs": ["111\n"], "source_document_id": "p03243", "source_text": "Score : 200 points\n\nProblem Statement\n\nKurohashi has never participated in AtCoder Beginner Contest (ABC).\n\nThe next ABC to be held is ABC N (the N-th ABC ever held).\nKurohashi wants to make his debut in some ABC x such that all the digits of x in base ten are the same.\n\nWhat is the earliest ABC where Kurohashi can make his debut?\n\nConstraints\n\n100 \\leq N \\leq 999\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nIf the earliest ABC where Kurohashi can make his debut is ABC n, print n.\n\nSample Input 1\n\n111\n\nSample Output 1\n\n111\n\nThe next ABC to be held is ABC 111, where Kurohashi can make his debut.\n\nSample Input 2\n\n112\n\nSample Output 2\n\n222\n\nThe next ABC to be held is ABC 112, which means Kurohashi can no longer participate in ABC 111.\nAmong the ABCs where Kurohashi can make his debut, the earliest one is ABC 222.\n\nSample Input 3\n\n750\n\nSample Output 3\n\n777", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1545, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s224729445", "group_id": "codeNet:p03244", "input_text": "#include <iostream>\n#include <algorithm>\n#include <string>\n#include <cmath>\n#include <ctype.h>\n#include <map>\n#include <vector>\n#include <stdlib.h>\n#include <stdio.h>\n#include <cctype>\n#include <queue>\n#include <set>\n#include <list>\n#define PI 3.141592653\n#define rep(i,a,n) for(int i=a;i<(int)n;++i)\n#define SZ(x) ((int)(x).size())\t//size() unsigned -> int\n#define DescSort(a) sort(a.begin(),a.end(),std::greater<int>())\n\nusing namespace std;\ntypedef long long ll;\nconst ll INF=1e9+7;\n\nint main(void) {\n\tint n;\n\tvector<int> e(1e5 + 5, 0), o(1e5 + 5, 0);\n\tcin >> n;\n\trep(i, 0, n) {\n\t\tint input;\n\t\tcin >> input;\n\t\tif (i % 2) {\n\t\t\to[input]++;\n\t\t}\n\t\telse {\n\t\t\te[input]++;\n\t\t}\n\t}\n\tint o_max_idx, e_max_idx;\n\to_max_idx = distance(o.begin(), max_element(o.begin(), o.end()));\n\te_max_idx = distance(e.begin(), max_element(e.begin(), e.end()));\n\tint ans = n - o[o_max_idx] - e[e_max_idx];\n\tif (o_max_idx == e_max_idx){\n\t\tint o_max_tmp = o[o_max_idx];\n\t\tint e_max_tmp = e[e_max_idx];\n\t\to[o_max_idx] = 0;e[e_max_idx] = 0;\n\t\tint o_2_max_idx = distance(o.begin(), max_element(o.begin(), o.end()));\n\t\tint e_2_max_idx = distance(e.begin(), max_element(e.begin(), e.end()));\n\t\tans = n - max(e[e_2_max_idx]+o_max_tmp, e_2_max_idx+o[o_max_tmp]);\n\t}\n\tcout << ans << endl;\n\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1581660884, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03244.html", "problem_id": "p03244", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03244/input.txt", "sample_output_relpath": "derived/input_output/data/p03244/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03244/C++/s224729445.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s224729445", "user_id": "u817523595"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <iostream>\n#include <algorithm>\n#include <string>\n#include <cmath>\n#include <ctype.h>\n#include <map>\n#include <vector>\n#include <stdlib.h>\n#include <stdio.h>\n#include <cctype>\n#include <queue>\n#include <set>\n#include <list>\n#define PI 3.141592653\n#define rep(i,a,n) for(int i=a;i<(int)n;++i)\n#define SZ(x) ((int)(x).size())\t//size() unsigned -> int\n#define DescSort(a) sort(a.begin(),a.end(),std::greater<int>())\n\nusing namespace std;\ntypedef long long ll;\nconst ll INF=1e9+7;\n\nint main(void) {\n\tint n;\n\tvector<int> e(1e5 + 5, 0), o(1e5 + 5, 0);\n\tcin >> n;\n\trep(i, 0, n) {\n\t\tint input;\n\t\tcin >> input;\n\t\tif (i % 2) {\n\t\t\to[input]++;\n\t\t}\n\t\telse {\n\t\t\te[input]++;\n\t\t}\n\t}\n\tint o_max_idx, e_max_idx;\n\to_max_idx = distance(o.begin(), max_element(o.begin(), o.end()));\n\te_max_idx = distance(e.begin(), max_element(e.begin(), e.end()));\n\tint ans = n - o[o_max_idx] - e[e_max_idx];\n\tif (o_max_idx == e_max_idx){\n\t\tint o_max_tmp = o[o_max_idx];\n\t\tint e_max_tmp = e[e_max_idx];\n\t\to[o_max_idx] = 0;e[e_max_idx] = 0;\n\t\tint o_2_max_idx = distance(o.begin(), max_element(o.begin(), o.end()));\n\t\tint e_2_max_idx = distance(e.begin(), max_element(e.begin(), e.end()));\n\t\tans = n - max(e[e_2_max_idx]+o_max_tmp, e_2_max_idx+o[o_max_tmp]);\n\t}\n\tcout << ans << endl;\n\n\treturn 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nA sequence a_1,a_2,... ,a_n is said to be /\\/\\/\\/ when the following conditions are satisfied:\n\nFor each i = 1,2,..., n-2, a_i = a_{i+2}.\n\nExactly two different numbers appear in the sequence.\n\nYou are given a sequence v_1,v_2,...,v_n whose length is even.\nWe would like to make this sequence /\\/\\/\\/ by replacing some of its elements.\nFind the minimum number of elements that needs to be replaced.\n\nConstraints\n\n2 \\leq n \\leq 10^5\n\nn is even.\n\n1 \\leq v_i \\leq 10^5\n\nv_i is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn\nv_1 v_2 ... v_n\n\nOutput\n\nPrint the minimum number of elements that needs to be replaced.\n\nSample Input 1\n\n4\n3 1 3 2\n\nSample Output 1\n\n1\n\nThe sequence 3,1,3,2 is not /\\/\\/\\/, but we can make it /\\/\\/\\/ by replacing one of its elements: for example, replace the fourth element to make it 3,1,3,1.\n\nSample Input 2\n\n6\n105 119 105 119 105 119\n\nSample Output 2\n\n0\n\nThe sequence 105,119,105,119,105,119 is /\\/\\/\\/.\n\nSample Input 3\n\n4\n1 1 1 1\n\nSample Output 3\n\n2\n\nThe elements of the sequence 1,1,1,1 are all the same, so it is not /\\/\\/\\/.", "sample_input": "4\n3 1 3 2\n"}, "reference_outputs": ["1\n"], "source_document_id": "p03244", "source_text": "Score : 300 points\n\nProblem Statement\n\nA sequence a_1,a_2,... ,a_n is said to be /\\/\\/\\/ when the following conditions are satisfied:\n\nFor each i = 1,2,..., n-2, a_i = a_{i+2}.\n\nExactly two different numbers appear in the sequence.\n\nYou are given a sequence v_1,v_2,...,v_n whose length is even.\nWe would like to make this sequence /\\/\\/\\/ by replacing some of its elements.\nFind the minimum number of elements that needs to be replaced.\n\nConstraints\n\n2 \\leq n \\leq 10^5\n\nn is even.\n\n1 \\leq v_i \\leq 10^5\n\nv_i is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn\nv_1 v_2 ... v_n\n\nOutput\n\nPrint the minimum number of elements that needs to be replaced.\n\nSample Input 1\n\n4\n3 1 3 2\n\nSample Output 1\n\n1\n\nThe sequence 3,1,3,2 is not /\\/\\/\\/, but we can make it /\\/\\/\\/ by replacing one of its elements: for example, replace the fourth element to make it 3,1,3,1.\n\nSample Input 2\n\n6\n105 119 105 119 105 119\n\nSample Output 2\n\n0\n\nThe sequence 105,119,105,119,105,119 is /\\/\\/\\/.\n\nSample Input 3\n\n4\n1 1 1 1\n\nSample Output 3\n\n2\n\nThe elements of the sequence 1,1,1,1 are all the same, so it is not /\\/\\/\\/.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1268, "cpu_time_ms": 32, "memory_kb": 1024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s481607441", "group_id": "codeNet:p03244", "input_text": "#include <iostream>\n#include <string>\n#include <vector>\n#include <cstdlib>\n#include <cstdio>\n#include <cmath>\n#include <algorithm>\n#include <map>\n#include <stack>\n#include <queue>\n#include <set>\n#include <cstring>\n\nusing namespace std;\n// ascending order\n#define vsort(v) sort(v.begin(), v.end())\n// descending order\n#define vsort_r(v) sort(v.begin(), v.end(), greater<ll>())\n#define vunique(v) unique(v.begin(), v.end())\n#define mp make_pair\n#define ts(x) to_string(x)\n#define rep(i, a, b) for(ll i = (ll)a; i < (ll)b; i++)\n#define repm(i, a, b) for(ll i = (ll)a; i > (ll)b; i--)\n#define bit(a) bitset<8>(a)\n#define des_priority_queue priority_queue<ll, vector<ll>, greater<ll> >\n#define all(v) (v).begin(), (v).end()\ntypedef long long ll;\ntypedef pair<ll, ll> P;\nconst ll INF = 1e18;\n\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tll n;\n\tcin >> n;\n\tmap<ll, ll> even;\n\tmap<ll, ll> odd;\n\tvector<ll> tmp_v;\n\trep(i, 0, n) {\n\t\tll v;\n\t\tcin >> v;\n\t\tif(i % 2 == 0) even[v]++;\n\t\telse odd[v]++;\n\t\ttmp_v.push_back(v);\n\t}\n\n\tll e1 = -1;\n\tll e2 = -1;\n\tll max_e1 = -1;\n\tll max_e2 = -1;\n\tll o1 = -1;\n\tll o2 = -1;\n\tll max_o1 = -1;\n\tll max_o2 = -1;\n\n\tfor(map<ll, ll>::iterator it = even.begin(); it != even.end(); it++) {\n\t\tif(max_e1 < it->second) {\n\t\t\tif(e2 != -1) {\n\t\t\t\tmax_e2 = max_e1;\n\t\t\t\te2 = e1;\n\t\t\t}\n\t\t\te1 = it->first;\n\t\t\tmax_e1 = it->second;\n\t\t\tcontinue;\n\t\t} \n\n\t\tif(e2 != it->first and max_e2 < it->second) {\n\t\t\te2 = it->first;\n\t\t\tmax_e2 = it->second;\n\t\t}\n\t}\n\n\tfor(map<ll, ll>::iterator it = odd.begin(); it != odd.end(); it++) {\n\t\tif(max_o1 < it->second) {\n\t\t\tif(o2 != -1) {\n\t\t\t\tmax_o2 = max_o1;\n\t\t\t\to2 = o1;\n\t\t\t}\n\t\t\to1 = it->first;\n\t\t\tmax_o1 = it->second;\n\t\t\tcontinue;\n\t\t} \n\n\t\tif(o2 != it->first and max_o2 < it->second) {\n\t\t\to2 = it->first;\n\t\t\tmax_o2 = it->second;\n\t\t}\n\t}\n\t\n\tll rsl1 = 0;\n\tll rsl2 = 0;\n\tif(e1 != o1) {\n\t\trep(i, 0, n) {\n\t\t\tif(i % 2 == 0) {\n\t\t\t\tif(e1 != tmp_v[i]) rsl1++;\n\t\t\t} else {\n\t\t\t\tif(o1 != tmp_v[i]) rsl1++;\n\t\t\t}\n\t\t}\n\t\tcout << rsl1 << endl;\n\t} else {\n\t\trep(i, 0, n) {\n\t\t\tif(i % 2 == 0) {\n\t\t\t\tif(e1 != tmp_v[i]) rsl1++;\n\t\t\t} else {\n\t\t\t\tif(o2 != tmp_v[i]) rsl1++;\n\t\t\t}\n\t\t}\n\t\trep(i, 0, n) {\n\t\t\tif(i % 2 == 0) {\n\t\t\t\tif(e2 != tmp_v[i]) rsl2++;\n\t\t\t} else {\n\t\t\t\tif(o1 != tmp_v[i]) rsl2++;\n\t\t\t}\n\t\t}\n\t\tll rsl = min(rsl1, rsl2);\n\t\tcout << rsl << endl;\n\t}\n}\n", "language": "C++", "metadata": {"date": 1541302768, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03244.html", "problem_id": "p03244", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03244/input.txt", "sample_output_relpath": "derived/input_output/data/p03244/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03244/C++/s481607441.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s481607441", "user_id": "u355254193"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <iostream>\n#include <string>\n#include <vector>\n#include <cstdlib>\n#include <cstdio>\n#include <cmath>\n#include <algorithm>\n#include <map>\n#include <stack>\n#include <queue>\n#include <set>\n#include <cstring>\n\nusing namespace std;\n// ascending order\n#define vsort(v) sort(v.begin(), v.end())\n// descending order\n#define vsort_r(v) sort(v.begin(), v.end(), greater<ll>())\n#define vunique(v) unique(v.begin(), v.end())\n#define mp make_pair\n#define ts(x) to_string(x)\n#define rep(i, a, b) for(ll i = (ll)a; i < (ll)b; i++)\n#define repm(i, a, b) for(ll i = (ll)a; i > (ll)b; i--)\n#define bit(a) bitset<8>(a)\n#define des_priority_queue priority_queue<ll, vector<ll>, greater<ll> >\n#define all(v) (v).begin(), (v).end()\ntypedef long long ll;\ntypedef pair<ll, ll> P;\nconst ll INF = 1e18;\n\nint main(){\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tll n;\n\tcin >> n;\n\tmap<ll, ll> even;\n\tmap<ll, ll> odd;\n\tvector<ll> tmp_v;\n\trep(i, 0, n) {\n\t\tll v;\n\t\tcin >> v;\n\t\tif(i % 2 == 0) even[v]++;\n\t\telse odd[v]++;\n\t\ttmp_v.push_back(v);\n\t}\n\n\tll e1 = -1;\n\tll e2 = -1;\n\tll max_e1 = -1;\n\tll max_e2 = -1;\n\tll o1 = -1;\n\tll o2 = -1;\n\tll max_o1 = -1;\n\tll max_o2 = -1;\n\n\tfor(map<ll, ll>::iterator it = even.begin(); it != even.end(); it++) {\n\t\tif(max_e1 < it->second) {\n\t\t\tif(e2 != -1) {\n\t\t\t\tmax_e2 = max_e1;\n\t\t\t\te2 = e1;\n\t\t\t}\n\t\t\te1 = it->first;\n\t\t\tmax_e1 = it->second;\n\t\t\tcontinue;\n\t\t} \n\n\t\tif(e2 != it->first and max_e2 < it->second) {\n\t\t\te2 = it->first;\n\t\t\tmax_e2 = it->second;\n\t\t}\n\t}\n\n\tfor(map<ll, ll>::iterator it = odd.begin(); it != odd.end(); it++) {\n\t\tif(max_o1 < it->second) {\n\t\t\tif(o2 != -1) {\n\t\t\t\tmax_o2 = max_o1;\n\t\t\t\to2 = o1;\n\t\t\t}\n\t\t\to1 = it->first;\n\t\t\tmax_o1 = it->second;\n\t\t\tcontinue;\n\t\t} \n\n\t\tif(o2 != it->first and max_o2 < it->second) {\n\t\t\to2 = it->first;\n\t\t\tmax_o2 = it->second;\n\t\t}\n\t}\n\t\n\tll rsl1 = 0;\n\tll rsl2 = 0;\n\tif(e1 != o1) {\n\t\trep(i, 0, n) {\n\t\t\tif(i % 2 == 0) {\n\t\t\t\tif(e1 != tmp_v[i]) rsl1++;\n\t\t\t} else {\n\t\t\t\tif(o1 != tmp_v[i]) rsl1++;\n\t\t\t}\n\t\t}\n\t\tcout << rsl1 << endl;\n\t} else {\n\t\trep(i, 0, n) {\n\t\t\tif(i % 2 == 0) {\n\t\t\t\tif(e1 != tmp_v[i]) rsl1++;\n\t\t\t} else {\n\t\t\t\tif(o2 != tmp_v[i]) rsl1++;\n\t\t\t}\n\t\t}\n\t\trep(i, 0, n) {\n\t\t\tif(i % 2 == 0) {\n\t\t\t\tif(e2 != tmp_v[i]) rsl2++;\n\t\t\t} else {\n\t\t\t\tif(o1 != tmp_v[i]) rsl2++;\n\t\t\t}\n\t\t}\n\t\tll rsl = min(rsl1, rsl2);\n\t\tcout << rsl << endl;\n\t}\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nA sequence a_1,a_2,... ,a_n is said to be /\\/\\/\\/ when the following conditions are satisfied:\n\nFor each i = 1,2,..., n-2, a_i = a_{i+2}.\n\nExactly two different numbers appear in the sequence.\n\nYou are given a sequence v_1,v_2,...,v_n whose length is even.\nWe would like to make this sequence /\\/\\/\\/ by replacing some of its elements.\nFind the minimum number of elements that needs to be replaced.\n\nConstraints\n\n2 \\leq n \\leq 10^5\n\nn is even.\n\n1 \\leq v_i \\leq 10^5\n\nv_i is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn\nv_1 v_2 ... v_n\n\nOutput\n\nPrint the minimum number of elements that needs to be replaced.\n\nSample Input 1\n\n4\n3 1 3 2\n\nSample Output 1\n\n1\n\nThe sequence 3,1,3,2 is not /\\/\\/\\/, but we can make it /\\/\\/\\/ by replacing one of its elements: for example, replace the fourth element to make it 3,1,3,1.\n\nSample Input 2\n\n6\n105 119 105 119 105 119\n\nSample Output 2\n\n0\n\nThe sequence 105,119,105,119,105,119 is /\\/\\/\\/.\n\nSample Input 3\n\n4\n1 1 1 1\n\nSample Output 3\n\n2\n\nThe elements of the sequence 1,1,1,1 are all the same, so it is not /\\/\\/\\/.", "sample_input": "4\n3 1 3 2\n"}, "reference_outputs": ["1\n"], "source_document_id": "p03244", "source_text": "Score : 300 points\n\nProblem Statement\n\nA sequence a_1,a_2,... ,a_n is said to be /\\/\\/\\/ when the following conditions are satisfied:\n\nFor each i = 1,2,..., n-2, a_i = a_{i+2}.\n\nExactly two different numbers appear in the sequence.\n\nYou are given a sequence v_1,v_2,...,v_n whose length is even.\nWe would like to make this sequence /\\/\\/\\/ by replacing some of its elements.\nFind the minimum number of elements that needs to be replaced.\n\nConstraints\n\n2 \\leq n \\leq 10^5\n\nn is even.\n\n1 \\leq v_i \\leq 10^5\n\nv_i is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn\nv_1 v_2 ... v_n\n\nOutput\n\nPrint the minimum number of elements that needs to be replaced.\n\nSample Input 1\n\n4\n3 1 3 2\n\nSample Output 1\n\n1\n\nThe sequence 3,1,3,2 is not /\\/\\/\\/, but we can make it /\\/\\/\\/ by replacing one of its elements: for example, replace the fourth element to make it 3,1,3,1.\n\nSample Input 2\n\n6\n105 119 105 119 105 119\n\nSample Output 2\n\n0\n\nThe sequence 105,119,105,119,105,119 is /\\/\\/\\/.\n\nSample Input 3\n\n4\n1 1 1 1\n\nSample Output 3\n\n2\n\nThe elements of the sequence 1,1,1,1 are all the same, so it is not /\\/\\/\\/.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2273, "cpu_time_ms": 48, "memory_kb": 7284}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s514237180", "group_id": "codeNet:p03247", "input_text": "#include <cmath>\n#include <cstdio>\n#include <cstring>\n#include <iostream>\n#include <algorithm>\nusing namespace std;\nconst int N = 1e5+10;\nint n, a[N], b[N], c[2], d[N];\nchar s[N];\nint Abs(int x){return x > 0 ? x : -x;}\nint main()\n{\n\tscanf(\"%d\", &n);\n\tfor (int i = 1; i <= n; i++)\n\t{\n\t\tscanf(\"%d%d\", &a[i], &b[i]);\n\t\t++c[(a[i] + b[i]) & 1];\n    }\n    if (c[0] != n && c[1] != n)\n    {\n    \tputs(\"-1\");\n\t\treturn 0;\n    }\n    printf(\"%d\\n\", 31 + (c[0] != 0));\n\tfor (int i = 0; i <= 30; i++)\n\t\tprintf(\"%d \", 1 << i);\n\tif (c[0])\n\t\tprintf(\"1 \");\n\tputchar(10);\n\tfor (int i = 1; i <= n; i++)\n\t{\n\t\tint x = a[i], y = b[i];\n\t\tif (c[0])\n\t\t\t--x, s[31] = 'R';\n\t\tint f = 0;\n        for (int i = 30; i >= 0; i--)\n        {\n            if (Abs(x) < Abs(y))\n            \tswap(x, y), f ^= 1;\n\t\t\tif (x > 0)\n\t\t\t\tx -= 1 << i, s[i] = \"RU\"[f];\n\t\t\telse\n\t\t\t\tx += 1 << i, s[i] = \"LD\"[f];\n\t\t}\n\t\tputs(s);\n    }\n}", "language": "C++", "metadata": {"date": 1580351749, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03247.html", "problem_id": "p03247", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03247/input.txt", "sample_output_relpath": "derived/input_output/data/p03247/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03247/C++/s514237180.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s514237180", "user_id": "u089230684"}, "prompt_components": {"gold_output": "2\n1 2\nRL\nUU\nDR\n", "input_to_evaluate": "#include <cmath>\n#include <cstdio>\n#include <cstring>\n#include <iostream>\n#include <algorithm>\nusing namespace std;\nconst int N = 1e5+10;\nint n, a[N], b[N], c[2], d[N];\nchar s[N];\nint Abs(int x){return x > 0 ? x : -x;}\nint main()\n{\n\tscanf(\"%d\", &n);\n\tfor (int i = 1; i <= n; i++)\n\t{\n\t\tscanf(\"%d%d\", &a[i], &b[i]);\n\t\t++c[(a[i] + b[i]) & 1];\n    }\n    if (c[0] != n && c[1] != n)\n    {\n    \tputs(\"-1\");\n\t\treturn 0;\n    }\n    printf(\"%d\\n\", 31 + (c[0] != 0));\n\tfor (int i = 0; i <= 30; i++)\n\t\tprintf(\"%d \", 1 << i);\n\tif (c[0])\n\t\tprintf(\"1 \");\n\tputchar(10);\n\tfor (int i = 1; i <= n; i++)\n\t{\n\t\tint x = a[i], y = b[i];\n\t\tif (c[0])\n\t\t\t--x, s[31] = 'R';\n\t\tint f = 0;\n        for (int i = 30; i >= 0; i--)\n        {\n            if (Abs(x) < Abs(y))\n            \tswap(x, y), f ^= 1;\n\t\t\tif (x > 0)\n\t\t\t\tx -= 1 << i, s[i] = \"RU\"[f];\n\t\t\telse\n\t\t\t\tx += 1 << i, s[i] = \"LD\"[f];\n\t\t}\n\t\tputs(s);\n    }\n}", "problem_context": "Score : 600 points\n\nProblem Statement\n\nSnuke is introducing a robot arm with the following properties to his factory:\n\nThe robot arm consists of m sections and m+1 joints. The sections are numbered 1, 2, ..., m, and the joints are numbered 0, 1, ..., m. Section i connects Joint i-1 and Joint i. The length of Section i is d_i.\n\nFor each section, its mode can be specified individually. There are four modes: L, R, D and U. The mode of a section decides the direction of that section. If we consider the factory as a coordinate plane, the position of Joint i will be determined as follows (we denote its coordinates as (x_i, y_i)):\n\n(x_0, y_0) = (0, 0).\n\nIf the mode of Section i is L, (x_{i}, y_{i}) = (x_{i-1} - d_{i}, y_{i-1}).\n\nIf the mode of Section i is R, (x_{i}, y_{i}) = (x_{i-1} + d_{i}, y_{i-1}).\n\nIf the mode of Section i is D, (x_{i}, y_{i}) = (x_{i-1}, y_{i-1} - d_{i}).\n\nIf the mode of Section i is U, (x_{i}, y_{i}) = (x_{i-1}, y_{i-1} + d_{i}).\n\nSnuke would like to introduce a robot arm so that the position of Joint m can be matched with all of the N points (X_1, Y_1), (X_2, Y_2), ..., (X_N, Y_N) by properly specifying the modes of the sections.\nIs this possible?\nIf so, find such a robot arm and how to bring Joint m to each point (X_j, Y_j).\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 1000\n\n-10^9 \\leq X_i \\leq 10^9\n\n-10^9 \\leq Y_i \\leq 10^9\n\nPartial Score\n\nIn the test cases worth 300 points, -10 \\leq X_i \\leq 10 and -10 \\leq Y_i \\leq 10 hold.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nX_1 Y_1\nX_2 Y_2\n:\nX_N Y_N\n\nOutput\n\nIf the condition can be satisfied, follow the following format. If the condition cannot be satisfied, print -1.\n\nm\nd_1 d_2 ... d_m\nw_1\nw_2\n:\nw_N\n\nm and d_i are the configurations of the robot arm. Refer to the problem statement for what each of them means.\nHere, 1 \\leq m \\leq 40 and 1 \\leq d_i \\leq 10^{12} must hold. Also, m and d_i must all be integers.\n\nw_j is a string of length m that represents the way to bring Joint m of the robot arm to point (X_j, Y_j).\nThe i-th character of w_j should be one of the letters L, R, D and U, representing the mode of Section i.\n\nSample Input 1\n\n3\n-1 0\n0 3\n2 -1\n\nSample Output 1\n\n2\n1 2\nRL\nUU\nDR\n\nIn the given way to bring Joint m of the robot arm to each (X_j, Y_j), the positions of the joints will be as follows:\n\nTo (X_1, Y_1) = (-1, 0): First, the position of Joint 0 is (x_0, y_0) = (0, 0). As the mode of Section 1 is R, the position of Joint 1 is (x_1, y_1) = (1, 0). Then, as the mode of Section 2 is L, the position of Joint 2 is (x_2, y_2) = (-1, 0).\n\nTo (X_2, Y_2) = (0, 3): (x_0, y_0) = (0, 0), (x_1, y_1) = (0, 1), (x_2, y_2) = (0, 3).\n\nTo (X_3, Y_3) = (2, -1): (x_0, y_0) = (0, 0), (x_1, y_1) = (0, -1), (x_2, y_2) = (2, -1).\n\nSample Input 2\n\n5\n0 0\n1 0\n2 0\n3 0\n4 0\n\nSample Output 2\n\n-1\n\nSample Input 3\n\n2\n1 1\n1 1\n\nSample Output 3\n\n2\n1 1\nRU\nUR\n\nThere may be duplicated points among (X_j, Y_j).\n\nSample Input 4\n\n3\n-7 -3\n7 3\n-3 -7\n\nSample Output 4\n\n5\n3 1 4 1 5\nLRDUL\nRDULR\nDULRD", "sample_input": "3\n-1 0\n0 3\n2 -1\n"}, "reference_outputs": ["2\n1 2\nRL\nUU\nDR\n"], "source_document_id": "p03247", "source_text": "Score : 600 points\n\nProblem Statement\n\nSnuke is introducing a robot arm with the following properties to his factory:\n\nThe robot arm consists of m sections and m+1 joints. The sections are numbered 1, 2, ..., m, and the joints are numbered 0, 1, ..., m. Section i connects Joint i-1 and Joint i. The length of Section i is d_i.\n\nFor each section, its mode can be specified individually. There are four modes: L, R, D and U. The mode of a section decides the direction of that section. If we consider the factory as a coordinate plane, the position of Joint i will be determined as follows (we denote its coordinates as (x_i, y_i)):\n\n(x_0, y_0) = (0, 0).\n\nIf the mode of Section i is L, (x_{i}, y_{i}) = (x_{i-1} - d_{i}, y_{i-1}).\n\nIf the mode of Section i is R, (x_{i}, y_{i}) = (x_{i-1} + d_{i}, y_{i-1}).\n\nIf the mode of Section i is D, (x_{i}, y_{i}) = (x_{i-1}, y_{i-1} - d_{i}).\n\nIf the mode of Section i is U, (x_{i}, y_{i}) = (x_{i-1}, y_{i-1} + d_{i}).\n\nSnuke would like to introduce a robot arm so that the position of Joint m can be matched with all of the N points (X_1, Y_1), (X_2, Y_2), ..., (X_N, Y_N) by properly specifying the modes of the sections.\nIs this possible?\nIf so, find such a robot arm and how to bring Joint m to each point (X_j, Y_j).\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 1000\n\n-10^9 \\leq X_i \\leq 10^9\n\n-10^9 \\leq Y_i \\leq 10^9\n\nPartial Score\n\nIn the test cases worth 300 points, -10 \\leq X_i \\leq 10 and -10 \\leq Y_i \\leq 10 hold.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nX_1 Y_1\nX_2 Y_2\n:\nX_N Y_N\n\nOutput\n\nIf the condition can be satisfied, follow the following format. If the condition cannot be satisfied, print -1.\n\nm\nd_1 d_2 ... d_m\nw_1\nw_2\n:\nw_N\n\nm and d_i are the configurations of the robot arm. Refer to the problem statement for what each of them means.\nHere, 1 \\leq m \\leq 40 and 1 \\leq d_i \\leq 10^{12} must hold. Also, m and d_i must all be integers.\n\nw_j is a string of length m that represents the way to bring Joint m of the robot arm to point (X_j, Y_j).\nThe i-th character of w_j should be one of the letters L, R, D and U, representing the mode of Section i.\n\nSample Input 1\n\n3\n-1 0\n0 3\n2 -1\n\nSample Output 1\n\n2\n1 2\nRL\nUU\nDR\n\nIn the given way to bring Joint m of the robot arm to each (X_j, Y_j), the positions of the joints will be as follows:\n\nTo (X_1, Y_1) = (-1, 0): First, the position of Joint 0 is (x_0, y_0) = (0, 0). As the mode of Section 1 is R, the position of Joint 1 is (x_1, y_1) = (1, 0). Then, as the mode of Section 2 is L, the position of Joint 2 is (x_2, y_2) = (-1, 0).\n\nTo (X_2, Y_2) = (0, 3): (x_0, y_0) = (0, 0), (x_1, y_1) = (0, 1), (x_2, y_2) = (0, 3).\n\nTo (X_3, Y_3) = (2, -1): (x_0, y_0) = (0, 0), (x_1, y_1) = (0, -1), (x_2, y_2) = (2, -1).\n\nSample Input 2\n\n5\n0 0\n1 0\n2 0\n3 0\n4 0\n\nSample Output 2\n\n-1\n\nSample Input 3\n\n2\n1 1\n1 1\n\nSample Output 3\n\n2\n1 1\nRU\nUR\n\nThere may be duplicated points among (X_j, Y_j).\n\nSample Input 4\n\n3\n-7 -3\n7 3\n-3 -7\n\nSample Output 4\n\n5\n3 1 4 1 5\nLRDUL\nRDULR\nDULRD", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 883, "cpu_time_ms": 2, "memory_kb": 384}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s717607392", "group_id": "codeNet:p03252", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nchar s[200003],s1[200003];\nint ss[30],ss1[30];\nint main()\n{\n\ncin>>s>>s1;\nint a,b;a=strlen(s);b=strlen(s1);\n for(int i=1;i<=a;i++)\n    ss[s[i]-'a']++,ss1[s1[i]-'a']++;\n    for(int i=1;i<=a;i++)\n    if(s[i]!=s1[i]&&ss[s[i]-'a']!=ss1[s1[i]-'a']){cout<<\"No\";return 0;}\n    cout<<\"Yes\";\nreturn 0;\n}\n\n", "language": "C++", "metadata": {"date": 1537834078, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03252.html", "problem_id": "p03252", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03252/input.txt", "sample_output_relpath": "derived/input_output/data/p03252/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03252/C++/s717607392.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Output Limit Exceeded", "submission_id": "s717607392", "user_id": "u114362525"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nchar s[200003],s1[200003];\nint ss[30],ss1[30];\nint main()\n{\n\ncin>>s>>s1;\nint a,b;a=strlen(s);b=strlen(s1);\n for(int i=1;i<=a;i++)\n    ss[s[i]-'a']++,ss1[s1[i]-'a']++;\n    for(int i=1;i<=a;i++)\n    if(s[i]!=s1[i]&&ss[s[i]-'a']!=ss1[s1[i]-'a']){cout<<\"No\";return 0;}\n    cout<<\"Yes\";\nreturn 0;\n}\n\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nYou are given strings S and T consisting of lowercase English letters.\n\nYou can perform the following operation on S any number of times:\n\nOperation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.\n\nDetermine if S and T can be made equal by performing the operation zero or more times.\n\nConstraints\n\n1 \\leq |S| \\leq 2 \\times 10^5\n\n|S| = |T|\n\nS and T consists of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\nT\n\nOutput\n\nIf S and T can be made equal, print Yes; otherwise, print No.\n\nSample Input 1\n\nazzel\napple\n\nSample Output 1\n\nYes\n\nazzel can be changed to apple, as follows:\n\nChoose e as c_1 and l as c_2. azzel becomes azzle.\n\nChoose z as c_1 and p as c_2. azzle becomes apple.\n\nSample Input 2\n\nchokudai\nredcoder\n\nSample Output 2\n\nNo\n\nNo sequences of operation can change chokudai to redcoder.\n\nSample Input 3\n\nabcdefghijklmnopqrstuvwxyz\nibyhqfrekavclxjstdwgpzmonu\n\nSample Output 3\n\nYes", "sample_input": "azzel\napple\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p03252", "source_text": "Score : 300 points\n\nProblem Statement\n\nYou are given strings S and T consisting of lowercase English letters.\n\nYou can perform the following operation on S any number of times:\n\nOperation: Choose two distinct lowercase English letters c_1 and c_2, then replace every occurrence of c_1 with c_2, and every occurrence of c_2 with c_1.\n\nDetermine if S and T can be made equal by performing the operation zero or more times.\n\nConstraints\n\n1 \\leq |S| \\leq 2 \\times 10^5\n\n|S| = |T|\n\nS and T consists of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\nT\n\nOutput\n\nIf S and T can be made equal, print Yes; otherwise, print No.\n\nSample Input 1\n\nazzel\napple\n\nSample Output 1\n\nYes\n\nazzel can be changed to apple, as follows:\n\nChoose e as c_1 and l as c_2. azzel becomes azzle.\n\nChoose z as c_1 and p as c_2. azzle becomes apple.\n\nSample Input 2\n\nchokudai\nredcoder\n\nSample Output 2\n\nNo\n\nNo sequences of operation can change chokudai to redcoder.\n\nSample Input 3\n\nabcdefghijklmnopqrstuvwxyz\nibyhqfrekavclxjstdwgpzmonu\n\nSample Output 3\n\nYes", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 341, "cpu_time_ms": 1770, "memory_kb": 131840}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s564704536", "group_id": "codeNet:p03253", "input_text": "#include <algorithm>\n#include <bitset>\n#include <cmath>\n#include <cstring>\n#include <deque>\n#include <functional>\n#include <iostream>\n#include <map>\n#include <queue>\n#include <set>\n#include <stdlib.h>\n#include <string>\n#include <utility>\n#include <vector>\n#define rep(i, n) for (int i = 0; i < (n); i++)\n#define loop(i, x, n) for (int i = (x); i < (n); i++)\n#define all(v) (v).begin(), (v).end()\n#define int long long\nusing namespace std;\nconst int MOD = 1e9 + 7;\nconst int INF = 1e18;\ntemplate<typename T> void cmax(T &a, T b) { a = max(a, b); }\ntemplate<typename T> void cmin(T &a, T b) { a = min(a, b); }\n\nint modinv(int a, int m) {\n  int b = m, u = 1, v = 0;\n  while (b) {\n    int t = a / b;\n    a -= t * b;\n    swap(a, b);\n    u -= t * v;\n    swap(u, v);\n  }\n  u %= m;\n  if (u < 0) u += m;\n  return u;\n}\n\nmap<int, int> prime_fac(int n) {\n  map<int, int> ret;\n  for (int i = 2; i * i <= n; i++) {\n    while (n % i == 0) {\n      ret[i]++;\n      n /= i;\n    }\n  }\n  if (n != 1) ret[n] = 1;\n  return ret;\n}\nint fact[200005];\nint inv[200005];\n\nsigned main() {\n  int n, m;\n  cin >> n >> m;\n  map<int, int> mp = prime_fac(m);\n  fact[0] = 1;\n  inv[0] = 1;\n  loop(i, 1, 200005) {\n    fact[i] = fact[i - 1] * i;\n    fact[i] %= MOD;\n    inv[i] = modinv(fact[i], MOD);\n  }\n\n  int ans = 1;\n  for (auto x : mp) {\n    int t = x.second;\n    // cout << x.first << ' ' << t << endl;\n    ans *= fact[t + n - 1] * inv[t] % MOD * inv[n - 1] % MOD;\n  }\n  cout << ans % MOD << endl;\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1543456105, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03253.html", "problem_id": "p03253", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03253/input.txt", "sample_output_relpath": "derived/input_output/data/p03253/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03253/C++/s564704536.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s564704536", "user_id": "u093420647"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <algorithm>\n#include <bitset>\n#include <cmath>\n#include <cstring>\n#include <deque>\n#include <functional>\n#include <iostream>\n#include <map>\n#include <queue>\n#include <set>\n#include <stdlib.h>\n#include <string>\n#include <utility>\n#include <vector>\n#define rep(i, n) for (int i = 0; i < (n); i++)\n#define loop(i, x, n) for (int i = (x); i < (n); i++)\n#define all(v) (v).begin(), (v).end()\n#define int long long\nusing namespace std;\nconst int MOD = 1e9 + 7;\nconst int INF = 1e18;\ntemplate<typename T> void cmax(T &a, T b) { a = max(a, b); }\ntemplate<typename T> void cmin(T &a, T b) { a = min(a, b); }\n\nint modinv(int a, int m) {\n  int b = m, u = 1, v = 0;\n  while (b) {\n    int t = a / b;\n    a -= t * b;\n    swap(a, b);\n    u -= t * v;\n    swap(u, v);\n  }\n  u %= m;\n  if (u < 0) u += m;\n  return u;\n}\n\nmap<int, int> prime_fac(int n) {\n  map<int, int> ret;\n  for (int i = 2; i * i <= n; i++) {\n    while (n % i == 0) {\n      ret[i]++;\n      n /= i;\n    }\n  }\n  if (n != 1) ret[n] = 1;\n  return ret;\n}\nint fact[200005];\nint inv[200005];\n\nsigned main() {\n  int n, m;\n  cin >> n >> m;\n  map<int, int> mp = prime_fac(m);\n  fact[0] = 1;\n  inv[0] = 1;\n  loop(i, 1, 200005) {\n    fact[i] = fact[i - 1] * i;\n    fact[i] %= MOD;\n    inv[i] = modinv(fact[i], MOD);\n  }\n\n  int ans = 1;\n  for (auto x : mp) {\n    int t = x.second;\n    // cout << x.first << ' ' << t << endl;\n    ans *= fact[t + n - 1] * inv[t] % MOD * inv[n - 1] % MOD;\n  }\n  cout << ans % MOD << endl;\n  return 0;\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nYou are given positive integers N and M.\n\nHow many sequences a of length N consisting of positive integers satisfy a_1 \\times a_2 \\times ... \\times a_N = M? Find the count modulo 10^9+7.\n\nHere, two sequences a' and a'' are considered different when there exists some i such that a_i' \\neq a_i''.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\n\nOutput\n\nPrint the number of the sequences consisting of positive integers that satisfy the condition, modulo 10^9 + 7.\n\nSample Input 1\n\n2 6\n\nSample Output 1\n\n4\n\nFour sequences satisfy the condition: \\{a_1, a_2\\} = \\{1, 6\\}, \\{2, 3\\}, \\{3, 2\\} and \\{6, 1\\}.\n\nSample Input 2\n\n3 12\n\nSample Output 2\n\n18\n\nSample Input 3\n\n100000 1000000000\n\nSample Output 3\n\n957870001", "sample_input": "2 6\n"}, "reference_outputs": ["4\n"], "source_document_id": "p03253", "source_text": "Score : 400 points\n\nProblem Statement\n\nYou are given positive integers N and M.\n\nHow many sequences a of length N consisting of positive integers satisfy a_1 \\times a_2 \\times ... \\times a_N = M? Find the count modulo 10^9+7.\n\nHere, two sequences a' and a'' are considered different when there exists some i such that a_i' \\neq a_i''.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\n\nOutput\n\nPrint the number of the sequences consisting of positive integers that satisfy the condition, modulo 10^9 + 7.\n\nSample Input 1\n\n2 6\n\nSample Output 1\n\n4\n\nFour sequences satisfy the condition: \\{a_1, a_2\\} = \\{1, 6\\}, \\{2, 3\\}, \\{3, 2\\} and \\{6, 1\\}.\n\nSample Input 2\n\n3 12\n\nSample Output 2\n\n18\n\nSample Input 3\n\n100000 1000000000\n\nSample Output 3\n\n957870001", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1479, "cpu_time_ms": 62, "memory_kb": 3328}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s710847800", "group_id": "codeNet:p03254", "input_text": "#include <iostream>\nint main(){\nint N;\nint x;\nint kids[105];\nint order[105];\nint all=0;\nint flag =0;\nstd::cin >> N >> x;\nfor(int i = 0;i <N;i++){\nstd::cin >> kids[i];\nall+=kids[i];\n\norder[i] = kids[i];\nif(i != 0){\nfor(int j = i;j > 0;j--){\nif(kids[j] > order[j-1]){\norder[j] = order [j-1];\norder[j-1] = kids[j];\n}\n}\n}\n}\nif(all == x){\nstd::cout << N <<'\\n';\nflag =1;\n}else if (all > x){\nstd::cout << N-1<<'\\n';\nflag =1;\n}else{\nfor(int i = 0;i<N;i++){\nif(x >= all - order[i]){\nstd::cout << N -  i - 1 << '\\n';\nflag =1;\n}else{\nall -= order[i];\n}\n}\n\n\n\n}\nif(!flag)std::cout << 0 << '\\n';\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1537064654, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03254.html", "problem_id": "p03254", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03254/input.txt", "sample_output_relpath": "derived/input_output/data/p03254/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03254/C++/s710847800.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s710847800", "user_id": "u604446158"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <iostream>\nint main(){\nint N;\nint x;\nint kids[105];\nint order[105];\nint all=0;\nint flag =0;\nstd::cin >> N >> x;\nfor(int i = 0;i <N;i++){\nstd::cin >> kids[i];\nall+=kids[i];\n\norder[i] = kids[i];\nif(i != 0){\nfor(int j = i;j > 0;j--){\nif(kids[j] > order[j-1]){\norder[j] = order [j-1];\norder[j-1] = kids[j];\n}\n}\n}\n}\nif(all == x){\nstd::cout << N <<'\\n';\nflag =1;\n}else if (all > x){\nstd::cout << N-1<<'\\n';\nflag =1;\n}else{\nfor(int i = 0;i<N;i++){\nif(x >= all - order[i]){\nstd::cout << N -  i - 1 << '\\n';\nflag =1;\n}else{\nall -= order[i];\n}\n}\n\n\n\n}\nif(!flag)std::cout << 0 << '\\n';\n  return 0;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nThere are N children, numbered 1, 2, ..., N.\n\nSnuke has decided to distribute x sweets among them.\nHe needs to give out all the x sweets, but some of the children may get zero sweets.\n\nFor each i (1 \\leq i \\leq N), Child i will be happy if he/she gets exactly a_i sweets.\nSnuke is trying to maximize the number of happy children by optimally distributing the sweets.\nFind the maximum possible number of happy children.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 100\n\n1 \\leq x \\leq 10^9\n\n1 \\leq a_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN x\na_1 a_2 ... a_N\n\nOutput\n\nPrint the maximum possible number of happy children.\n\nSample Input 1\n\n3 70\n20 30 10\n\nSample Output 1\n\n2\n\nOne optimal way to distribute sweets is (20, 30, 20).\n\nSample Input 2\n\n3 10\n20 30 10\n\nSample Output 2\n\n1\n\nThe optimal way to distribute sweets is (0, 0, 10).\n\nSample Input 3\n\n4 1111\n1 10 100 1000\n\nSample Output 3\n\n4\n\nThe optimal way to distribute sweets is (1, 10, 100, 1000).\n\nSample Input 4\n\n2 10\n20 20\n\nSample Output 4\n\n0\n\nNo children will be happy, no matter how the sweets are distributed.", "sample_input": "3 70\n20 30 10\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03254", "source_text": "Score : 200 points\n\nProblem Statement\n\nThere are N children, numbered 1, 2, ..., N.\n\nSnuke has decided to distribute x sweets among them.\nHe needs to give out all the x sweets, but some of the children may get zero sweets.\n\nFor each i (1 \\leq i \\leq N), Child i will be happy if he/she gets exactly a_i sweets.\nSnuke is trying to maximize the number of happy children by optimally distributing the sweets.\nFind the maximum possible number of happy children.\n\nConstraints\n\nAll values in input are integers.\n\n2 \\leq N \\leq 100\n\n1 \\leq x \\leq 10^9\n\n1 \\leq a_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN x\na_1 a_2 ... a_N\n\nOutput\n\nPrint the maximum possible number of happy children.\n\nSample Input 1\n\n3 70\n20 30 10\n\nSample Output 1\n\n2\n\nOne optimal way to distribute sweets is (20, 30, 20).\n\nSample Input 2\n\n3 10\n20 30 10\n\nSample Output 2\n\n1\n\nThe optimal way to distribute sweets is (0, 0, 10).\n\nSample Input 3\n\n4 1111\n1 10 100 1000\n\nSample Output 3\n\n4\n\nThe optimal way to distribute sweets is (1, 10, 100, 1000).\n\nSample Input 4\n\n2 10\n20 20\n\nSample Output 4\n\n0\n\nNo children will be happy, no matter how the sweets are distributed.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 597, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s577064193", "group_id": "codeNet:p03255", "input_text": "#include <bits/stdc++.h>\n#define rep(i, a, n) for(int i = a; i < n; i++)\n#define repr(i, a, b) for(int i = a; i >= b; i--)\n#define int long long\n#define all(a) a.begin(), a.end()\n#define chmax(x, y) x = max(x, y)\n#define chmin(x, y) x = min(x, y)\nusing namespace std;\ntypedef pair<int, int> P;\nconst int mod = 1000000007;\nconst int INF = 1e18;\n\nint n, x;\nvector<int> a;\nint cost[2010][2010];\nint dp[2010];\n\nsigned main(){\n\tios::sync_with_stdio(false);\n\tcin.tie(0);\n\tcin >> n >> x;\n\tassert(n <= 2000);\n\ta.resize(n);\n\trep(i, 0, n) cin >> a[i];\n\trep(i, 0, n){\n\t\tint now = x + a[i], cnt = 0;\n\t\tfor(int j = i; j >= 0; j--){\n\t\t\tnow += x;\n\t\t\tcnt++;\n\t\t\tcost[j][i] = now + (cnt + 1) * (cnt + 1) * a[j];\n\t\t\tif(j) now += (cnt + 1) * (cnt + 1) * (a[j] - a[j - 1]);\n\t\t}\n\t}\n\trep(i, 0, n + 1) dp[i] = INF; \n\tdp[0] = 0;\n\trep(i, 0, n){\n\t\trep(j, 0, n){\n\t\t\tdp[j + 1] = min(dp[j + 1], dp[i] + cost[i][j]);\n\t\t}\n\t}\n\tcout << dp[n] << endl;\n}", "language": "C++", "metadata": {"date": 1537071771, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03255.html", "problem_id": "p03255", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03255/input.txt", "sample_output_relpath": "derived/input_output/data/p03255/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03255/C++/s577064193.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s577064193", "user_id": "u984730891"}, "prompt_components": {"gold_output": "355\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define rep(i, a, n) for(int i = a; i < n; i++)\n#define repr(i, a, b) for(int i = a; i >= b; i--)\n#define int long long\n#define all(a) a.begin(), a.end()\n#define chmax(x, y) x = max(x, y)\n#define chmin(x, y) x = min(x, y)\nusing namespace std;\ntypedef pair<int, int> P;\nconst int mod = 1000000007;\nconst int INF = 1e18;\n\nint n, x;\nvector<int> a;\nint cost[2010][2010];\nint dp[2010];\n\nsigned main(){\n\tios::sync_with_stdio(false);\n\tcin.tie(0);\n\tcin >> n >> x;\n\tassert(n <= 2000);\n\ta.resize(n);\n\trep(i, 0, n) cin >> a[i];\n\trep(i, 0, n){\n\t\tint now = x + a[i], cnt = 0;\n\t\tfor(int j = i; j >= 0; j--){\n\t\t\tnow += x;\n\t\t\tcnt++;\n\t\t\tcost[j][i] = now + (cnt + 1) * (cnt + 1) * a[j];\n\t\t\tif(j) now += (cnt + 1) * (cnt + 1) * (a[j] - a[j - 1]);\n\t\t}\n\t}\n\trep(i, 0, n + 1) dp[i] = INF; \n\tdp[0] = 0;\n\trep(i, 0, n){\n\t\trep(j, 0, n){\n\t\t\tdp[j + 1] = min(dp[j + 1], dp[i] + cost[i][j]);\n\t\t}\n\t}\n\tcout << dp[n] << endl;\n}", "problem_context": "Score : 700 points\n\nProblem Statement\n\nSnuke has decided to use a robot to clean his room.\n\nThere are N pieces of trash on a number line.\nThe i-th piece from the left is at position x_i.\nWe would like to put all of them in a trash bin at position 0.\n\nFor the positions of the pieces of trash, 0 < x_1 < x_2 < ... < x_{N} \\leq 10^{9} holds.\n\nThe robot is initially at position 0.\nIt can freely move left and right along the number line, pick up a piece of trash when it comes to the position of that piece, carry any number of pieces of trash and put them in the trash bin when it comes to position 0. It is not allowed to put pieces of trash anywhere except in the trash bin.\n\nThe robot consumes X points of energy when the robot picks up a piece of trash, or put pieces of trash in the trash bin. (Putting any number of pieces of trash in the trash bin consumes X points of energy.)\nAlso, the robot consumes (k+1)^{2} points of energy to travel by a distance of 1 when the robot is carrying k pieces of trash.\n\nFind the minimum amount of energy required to put all the N pieces of trash in the trash bin.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^{5}\n\n0 < x_1 < ... < x_N \\leq 10^9\n\n1 \\leq X \\leq 10^9\n\nAll values in input are integers.\n\nPartial Scores\n\n400 points will be awarded for passing the test set satisfying N \\leq 2000.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN X\nx_1 x_2 ... x_{N}\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n2 100\n1 10\n\nSample Output 1\n\n355\n\nTravel to position 10 by consuming 10 points of energy.\n\nPick up the piece of trash by consuming 100 points of energy.\n\nTravel to position 1 by consuming 36 points of energy.\n\nPick up the piece of trash by consuming 100 points of energy.\n\nTravel to position 0 by consuming 9 points of energy.\n\nPut the two pieces of trash in the trash bin by consuming 100 points of energy.\n\nThis strategy consumes a total of 10+100+36+100+9+100=355 points of energy.\n\nSample Input 2\n\n5 1\n1 999999997 999999998 999999999 1000000000\n\nSample Output 2\n\n19999999983\n\nSample Input 3\n\n10 8851025\n38 87 668 3175 22601 65499 90236 790604 4290609 4894746\n\nSample Output 3\n\n150710136\n\nSample Input 4\n\n16 10\n1 7 12 27 52 75 731 13856 395504 534840 1276551 2356789 9384806 19108104 82684732 535447408\n\nSample Output 4\n\n3256017715", "sample_input": "2 100\n1 10\n"}, "reference_outputs": ["355\n"], "source_document_id": "p03255", "source_text": "Score : 700 points\n\nProblem Statement\n\nSnuke has decided to use a robot to clean his room.\n\nThere are N pieces of trash on a number line.\nThe i-th piece from the left is at position x_i.\nWe would like to put all of them in a trash bin at position 0.\n\nFor the positions of the pieces of trash, 0 < x_1 < x_2 < ... < x_{N} \\leq 10^{9} holds.\n\nThe robot is initially at position 0.\nIt can freely move left and right along the number line, pick up a piece of trash when it comes to the position of that piece, carry any number of pieces of trash and put them in the trash bin when it comes to position 0. It is not allowed to put pieces of trash anywhere except in the trash bin.\n\nThe robot consumes X points of energy when the robot picks up a piece of trash, or put pieces of trash in the trash bin. (Putting any number of pieces of trash in the trash bin consumes X points of energy.)\nAlso, the robot consumes (k+1)^{2} points of energy to travel by a distance of 1 when the robot is carrying k pieces of trash.\n\nFind the minimum amount of energy required to put all the N pieces of trash in the trash bin.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^{5}\n\n0 < x_1 < ... < x_N \\leq 10^9\n\n1 \\leq X \\leq 10^9\n\nAll values in input are integers.\n\nPartial Scores\n\n400 points will be awarded for passing the test set satisfying N \\leq 2000.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN X\nx_1 x_2 ... x_{N}\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n2 100\n1 10\n\nSample Output 1\n\n355\n\nTravel to position 10 by consuming 10 points of energy.\n\nPick up the piece of trash by consuming 100 points of energy.\n\nTravel to position 1 by consuming 36 points of energy.\n\nPick up the piece of trash by consuming 100 points of energy.\n\nTravel to position 0 by consuming 9 points of energy.\n\nPut the two pieces of trash in the trash bin by consuming 100 points of energy.\n\nThis strategy consumes a total of 10+100+36+100+9+100=355 points of energy.\n\nSample Input 2\n\n5 1\n1 999999997 999999998 999999999 1000000000\n\nSample Output 2\n\n19999999983\n\nSample Input 3\n\n10 8851025\n38 87 668 3175 22601 65499 90236 790604 4290609 4894746\n\nSample Output 3\n\n150710136\n\nSample Input 4\n\n16 10\n1 7 12 27 52 75 731 13856 395504 534840 1276551 2356789 9384806 19108104 82684732 535447408\n\nSample Output 4\n\n3256017715", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 918, "cpu_time_ms": 97, "memory_kb": 31232}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s603227409", "group_id": "codeNet:p03256", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing Graph=vector<vector<int>>;\nint main(){\n    int n;\n    cin>>n;\n    int m;\n    cin>>m;\n    string s;\n    cin>>s;\n    Graph g(n);\n    for(int i=0;i<m;i++){\n        int a,b;\n        cin>>a>>b;\n        a--,b--;\n        g[a].push_back(b);\n        g[b].push_back(a);\n    }\n    vector<int> acnt(n);\n    vector<int> bcnt(n);\n    vector<int> ng(n,false);\n    stack<int> ngs;\n    for(int i=0;i<n;i++){\n        for(int j=0;j<g[i].size();j++){\n            if(s[g[i][j]]=='A') acnt[i]++;\n            if(s[g[i][j]]=='B') bcnt[i]++;\n        }\n        if(acnt[i]==0 || bcnt[i]==0){\n            ng[i]=true;\n            ngs.push(i);\n        }\n    }\n    \n    while(!ngs.empty()){\n        int v=ngs.top();\n        ngs.pop();\n        for(int i=0;i<g[v].size();i++){\n            if(s[v]=='A'){\n                if((--acnt[g[v][i]])==0 && !ng[g[v][i]]){\n                    ng[g[v][i]]=true;\n                    ngs.push(g[v][i]);\n                }\n                \n            }\n            if(s[v]=='B'){\n                if((--bcnt[g[v][i]])==0 && !ng[g[v][i]]){\n                    ng[g[v][i]]=true;\n                    ngs.push(g[v][i]);\n                }\n            }\n        }\n    }    \n    //cerr<<\"#\"<<endl;\n    //for(int i=0;i<n;i++) cerr<<ng[i]<<endl;\n    cout<<(accumulate(ng.begin(),ng.end(),0)==n ? \"No\" : \"Yes\")<<endl;\n    \n    return 0;\n}", "language": "C++", "metadata": {"date": 1537062356, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03256.html", "problem_id": "p03256", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03256/input.txt", "sample_output_relpath": "derived/input_output/data/p03256/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03256/C++/s603227409.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s603227409", "user_id": "u283229916"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n\nusing Graph=vector<vector<int>>;\nint main(){\n    int n;\n    cin>>n;\n    int m;\n    cin>>m;\n    string s;\n    cin>>s;\n    Graph g(n);\n    for(int i=0;i<m;i++){\n        int a,b;\n        cin>>a>>b;\n        a--,b--;\n        g[a].push_back(b);\n        g[b].push_back(a);\n    }\n    vector<int> acnt(n);\n    vector<int> bcnt(n);\n    vector<int> ng(n,false);\n    stack<int> ngs;\n    for(int i=0;i<n;i++){\n        for(int j=0;j<g[i].size();j++){\n            if(s[g[i][j]]=='A') acnt[i]++;\n            if(s[g[i][j]]=='B') bcnt[i]++;\n        }\n        if(acnt[i]==0 || bcnt[i]==0){\n            ng[i]=true;\n            ngs.push(i);\n        }\n    }\n    \n    while(!ngs.empty()){\n        int v=ngs.top();\n        ngs.pop();\n        for(int i=0;i<g[v].size();i++){\n            if(s[v]=='A'){\n                if((--acnt[g[v][i]])==0 && !ng[g[v][i]]){\n                    ng[g[v][i]]=true;\n                    ngs.push(g[v][i]);\n                }\n                \n            }\n            if(s[v]=='B'){\n                if((--bcnt[g[v][i]])==0 && !ng[g[v][i]]){\n                    ng[g[v][i]]=true;\n                    ngs.push(g[v][i]);\n                }\n            }\n        }\n    }    \n    //cerr<<\"#\"<<endl;\n    //for(int i=0;i<n;i++) cerr<<ng[i]<<endl;\n    cout<<(accumulate(ng.begin(),ng.end(),0)==n ? \"No\" : \"Yes\")<<endl;\n    \n    return 0;\n}", "problem_context": "Score : 900 points\n\nProblem Statement\n\nYou are given an undirected graph consisting of N vertices and M edges.\nThe vertices are numbered 1 to N, and the edges are numbered 1 to M.\nIn addition, each vertex has a label, A or B. The label of Vertex i is s_i.\nEdge i bidirectionally connects vertex a_i and b_i.\n\nThe phantom thief Nusook likes to choose some vertex as the startpoint and traverse an edge zero or more times.\nToday, he will make a string after traveling as above, by placing the labels of the visited vertices in the order visited, beginning from the startpoint.\n\nFor example, in a graph where Vertex 1 has the label A and Vertex 2 has the label B, if Nusook travels along the path 1 \\rightarrow 2 \\rightarrow 1 \\rightarrow 2 \\rightarrow 2, the resulting string is ABABB.\n\nDetermine if Nusook can make all strings consisting of A and B.\n\nConstraints\n\n2 \\leq N \\leq 2 \\times 10^{5}\n\n1 \\leq M \\leq 2 \\times 10^{5}\n\n|s| = N\n\ns_i is A or B.\n\n1 \\leq a_i, b_i \\leq N\n\nThe given graph may NOT be simple or connected.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\ns\na_1 b_1\n:\na_{M} b_{M}\n\nOutput\n\nIf Nusook can make all strings consisting of A and B, print Yes; otherwise, print No.\n\nSample Input 1\n\n2 3\nAB\n1 1\n1 2\n2 2\n\nSample Output 1\n\nYes\n\nSince Nusook can visit Vertex 1 and Vertex 2 in any way he likes, he can make all strings consisting of A and B.\n\nSample Input 2\n\n4 3\nABAB\n1 2\n2 3\n3 1\n\nSample Output 2\n\nNo\n\nFor example, Nusook cannot make BB.\n\nThe given graph may not be connected.\n\nSample Input 3\n\n13 23\nABAAAABBBBAAB\n7 1\n10 6\n1 11\n2 10\n2 8\n2 11\n11 12\n8 3\n7 12\n11 2\n13 13\n11 9\n4 1\n9 7\n9 6\n8 13\n8 6\n4 10\n8 7\n4 3\n2 1\n8 12\n6 9\n\nSample Output 3\n\nYes\n\nSample Input 4\n\n13 17\nBBABBBAABABBA\n7 1\n7 9\n11 12\n3 9\n11 9\n2 1\n11 5\n12 11\n10 8\n1 11\n1 8\n7 7\n9 10\n8 8\n8 12\n6 2\n13 11\n\nSample Output 4\n\nNo", "sample_input": "2 3\nAB\n1 1\n1 2\n2 2\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p03256", "source_text": "Score : 900 points\n\nProblem Statement\n\nYou are given an undirected graph consisting of N vertices and M edges.\nThe vertices are numbered 1 to N, and the edges are numbered 1 to M.\nIn addition, each vertex has a label, A or B. The label of Vertex i is s_i.\nEdge i bidirectionally connects vertex a_i and b_i.\n\nThe phantom thief Nusook likes to choose some vertex as the startpoint and traverse an edge zero or more times.\nToday, he will make a string after traveling as above, by placing the labels of the visited vertices in the order visited, beginning from the startpoint.\n\nFor example, in a graph where Vertex 1 has the label A and Vertex 2 has the label B, if Nusook travels along the path 1 \\rightarrow 2 \\rightarrow 1 \\rightarrow 2 \\rightarrow 2, the resulting string is ABABB.\n\nDetermine if Nusook can make all strings consisting of A and B.\n\nConstraints\n\n2 \\leq N \\leq 2 \\times 10^{5}\n\n1 \\leq M \\leq 2 \\times 10^{5}\n\n|s| = N\n\ns_i is A or B.\n\n1 \\leq a_i, b_i \\leq N\n\nThe given graph may NOT be simple or connected.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\ns\na_1 b_1\n:\na_{M} b_{M}\n\nOutput\n\nIf Nusook can make all strings consisting of A and B, print Yes; otherwise, print No.\n\nSample Input 1\n\n2 3\nAB\n1 1\n1 2\n2 2\n\nSample Output 1\n\nYes\n\nSince Nusook can visit Vertex 1 and Vertex 2 in any way he likes, he can make all strings consisting of A and B.\n\nSample Input 2\n\n4 3\nABAB\n1 2\n2 3\n3 1\n\nSample Output 2\n\nNo\n\nFor example, Nusook cannot make BB.\n\nThe given graph may not be connected.\n\nSample Input 3\n\n13 23\nABAAAABBBBAAB\n7 1\n10 6\n1 11\n2 10\n2 8\n2 11\n11 12\n8 3\n7 12\n11 2\n13 13\n11 9\n4 1\n9 7\n9 6\n8 13\n8 6\n4 10\n8 7\n4 3\n2 1\n8 12\n6 9\n\nSample Output 3\n\nYes\n\nSample Input 4\n\n13 17\nBBABBBAABABBA\n7 1\n7 9\n11 12\n3 9\n11 9\n2 1\n11 5\n12 11\n10 8\n1 11\n1 8\n7 7\n9 10\n8 8\n8 12\n6 2\n13 11\n\nSample Output 4\n\nNo", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1381, "cpu_time_ms": 171, "memory_kb": 12932}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s329968103", "group_id": "codeNet:p03263", "input_text": "#include<iostream>\n#include<vector>\n\nusing namespace std;\n\nint main(){ \n  int H,W; cin >> H >> W;\n  vector<vector<int>> A(H,vector<int>(W));\n  vector<int> Y1; vector<int> X1; vector<int> Y2; vector<int> X2;\n  \n  for(int i = 0; i < H; i++){\n    for(int j = 0; j < W; j++){ cin >> A[i][j];}}\n    int cnt = 0;\n    for(int i = 0; i < H; i++){ \n     if( i % 2 == 0){ //0-indexedで偶数番目の行について調べる\n       for(int j = 0; j < W; j++){\n         if( j != W - 1){ \n          if( A[i][j] % 2 == 0){ continue;}\n          else{ A[i][j]--; A[i][j+1]++; cnt++; Y1.push_back(i+1); X1.push_back(j+1);\n                                               Y2.push_back(i+1); X2.push_back(j+2);\n                            }}\n         else{ // j == W - 1の時\n           if( A[i][j] % 2 != 0){ A[i][j]--;A[i+1][j]++; cnt++;\n                                              Y1.push_back(i+1); X1.push_back(j+1);\n                                              Y2.push_back(i+2); X2.push_back(j+1);\n                                }}\n       }} //偶数行終了\n     else{\n       for(int j = W- 1; j >= 0; j--){\n         if( j != 0){\n           if( A[i][j] % 2 == 0){ continue;}\n           else{ A[i][j]--; A[i][j-1]--; cnt++;\n                 Y1.push_back(i+1); X1.push_back(j+1);\n                 Y2.push_back(i+1); X2.push_back(j);}}\n         else{ // j == 0の時\n           if( A[i][j] % 2 != 0){ A[i][j]--; A[i+1][j]++; cnt++;\n                 Y1.push_back(i+1); X1.push_back(j+1);\n                 Y2.push_back(i+2); X2.push_back(j+1);}}\n       }}} //奇数行終了\n       \n      cout << cnt << endl;\n      if( cnt != 0){\n        \n      for(int i = 0; i < cnt; i++){\n        cout << Y1[i] << \" \" << X1[i] << \" \" << Y2[i] << \" \" << X2[i] << endl;}}\n      \n     return 0;}\n        \n      \n", "language": "C++", "metadata": {"date": 1560399727, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03263.html", "problem_id": "p03263", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03263/input.txt", "sample_output_relpath": "derived/input_output/data/p03263/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03263/C++/s329968103.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s329968103", "user_id": "u904123392"}, "prompt_components": {"gold_output": "3\n2 2 2 3\n1 1 1 2\n1 3 1 2\n", "input_to_evaluate": "#include<iostream>\n#include<vector>\n\nusing namespace std;\n\nint main(){ \n  int H,W; cin >> H >> W;\n  vector<vector<int>> A(H,vector<int>(W));\n  vector<int> Y1; vector<int> X1; vector<int> Y2; vector<int> X2;\n  \n  for(int i = 0; i < H; i++){\n    for(int j = 0; j < W; j++){ cin >> A[i][j];}}\n    int cnt = 0;\n    for(int i = 0; i < H; i++){ \n     if( i % 2 == 0){ //0-indexedで偶数番目の行について調べる\n       for(int j = 0; j < W; j++){\n         if( j != W - 1){ \n          if( A[i][j] % 2 == 0){ continue;}\n          else{ A[i][j]--; A[i][j+1]++; cnt++; Y1.push_back(i+1); X1.push_back(j+1);\n                                               Y2.push_back(i+1); X2.push_back(j+2);\n                            }}\n         else{ // j == W - 1の時\n           if( A[i][j] % 2 != 0){ A[i][j]--;A[i+1][j]++; cnt++;\n                                              Y1.push_back(i+1); X1.push_back(j+1);\n                                              Y2.push_back(i+2); X2.push_back(j+1);\n                                }}\n       }} //偶数行終了\n     else{\n       for(int j = W- 1; j >= 0; j--){\n         if( j != 0){\n           if( A[i][j] % 2 == 0){ continue;}\n           else{ A[i][j]--; A[i][j-1]--; cnt++;\n                 Y1.push_back(i+1); X1.push_back(j+1);\n                 Y2.push_back(i+1); X2.push_back(j);}}\n         else{ // j == 0の時\n           if( A[i][j] % 2 != 0){ A[i][j]--; A[i+1][j]++; cnt++;\n                 Y1.push_back(i+1); X1.push_back(j+1);\n                 Y2.push_back(i+2); X2.push_back(j+1);}}\n       }}} //奇数行終了\n       \n      cout << cnt << endl;\n      if( cnt != 0){\n        \n      for(int i = 0; i < cnt; i++){\n        cout << Y1[i] << \" \" << X1[i] << \" \" << Y2[i] << \" \" << X2[i] << endl;}}\n      \n     return 0;}\n        \n      \n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nThere is a grid of square cells with H horizontal rows and W vertical columns. The cell at the i-th row and the j-th column will be denoted as Cell (i, j).\n\nIn Cell (i, j), a_{ij} coins are placed.\n\nYou can perform the following operation any number of times:\n\nOperation: Choose a cell that was not chosen before and contains one or more coins, then move one of those coins to a vertically or horizontally adjacent cell.\n\nMaximize the number of cells containing an even number of coins.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq H, W \\leq 500\n\n0 \\leq a_{ij} \\leq 9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W\na_{11} a_{12} ... a_{1W}\na_{21} a_{22} ... a_{2W}\n:\na_{H1} a_{H2} ... a_{HW}\n\nOutput\n\nPrint a sequence of operations that maximizes the number of cells containing an even number of coins, in the following format:\n\nN\ny_1 x_1 y_1' x_1'\ny_2 x_2 y_2' x_2'\n:\ny_N x_N y_N' x_N'\n\nThat is, in the first line, print an integer N between 0 and H \\times W (inclusive), representing the number of operations.\n\nIn the (i+1)-th line (1 \\leq i \\leq N), print four integers y_i, x_i, y_i' and x_i' (1 \\leq y_i, y_i' \\leq H and 1 \\leq x_i, x_i' \\leq W), representing the i-th operation. These four integers represents the operation of moving one of the coins placed in Cell (y_i, x_i) to a vertically or horizontally adjacent cell, (y_i', x_i').\n\nNote that if the specified operation violates the specification in the problem statement or the output format is invalid, it will result in Wrong Answer.\n\nSample Input 1\n\n2 3\n1 2 3\n0 1 1\n\nSample Output 1\n\n3\n2 2 2 3\n1 1 1 2\n1 3 1 2\n\nEvery cell contains an even number of coins after the following sequence of operations:\n\nMove the coin in Cell (2, 2) to Cell (2, 3).\n\nMove the coin in Cell (1, 1) to Cell (1, 2).\n\nMove one of the coins in Cell (1, 3) to Cell (1, 2).\n\nSample Input 2\n\n3 2\n1 0\n2 1\n1 0\n\nSample Output 2\n\n3\n1 1 1 2\n1 2 2 2\n3 1 3 2\n\nSample Input 3\n\n1 5\n9 9 9 9 9\n\nSample Output 3\n\n2\n1 1 1 2\n1 3 1 4", "sample_input": "2 3\n1 2 3\n0 1 1\n"}, "reference_outputs": ["3\n2 2 2 3\n1 1 1 2\n1 3 1 2\n"], "source_document_id": "p03263", "source_text": "Score : 400 points\n\nProblem Statement\n\nThere is a grid of square cells with H horizontal rows and W vertical columns. The cell at the i-th row and the j-th column will be denoted as Cell (i, j).\n\nIn Cell (i, j), a_{ij} coins are placed.\n\nYou can perform the following operation any number of times:\n\nOperation: Choose a cell that was not chosen before and contains one or more coins, then move one of those coins to a vertically or horizontally adjacent cell.\n\nMaximize the number of cells containing an even number of coins.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq H, W \\leq 500\n\n0 \\leq a_{ij} \\leq 9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W\na_{11} a_{12} ... a_{1W}\na_{21} a_{22} ... a_{2W}\n:\na_{H1} a_{H2} ... a_{HW}\n\nOutput\n\nPrint a sequence of operations that maximizes the number of cells containing an even number of coins, in the following format:\n\nN\ny_1 x_1 y_1' x_1'\ny_2 x_2 y_2' x_2'\n:\ny_N x_N y_N' x_N'\n\nThat is, in the first line, print an integer N between 0 and H \\times W (inclusive), representing the number of operations.\n\nIn the (i+1)-th line (1 \\leq i \\leq N), print four integers y_i, x_i, y_i' and x_i' (1 \\leq y_i, y_i' \\leq H and 1 \\leq x_i, x_i' \\leq W), representing the i-th operation. These four integers represents the operation of moving one of the coins placed in Cell (y_i, x_i) to a vertically or horizontally adjacent cell, (y_i', x_i').\n\nNote that if the specified operation violates the specification in the problem statement or the output format is invalid, it will result in Wrong Answer.\n\nSample Input 1\n\n2 3\n1 2 3\n0 1 1\n\nSample Output 1\n\n3\n2 2 2 3\n1 1 1 2\n1 3 1 2\n\nEvery cell contains an even number of coins after the following sequence of operations:\n\nMove the coin in Cell (2, 2) to Cell (2, 3).\n\nMove the coin in Cell (1, 1) to Cell (1, 2).\n\nMove one of the coins in Cell (1, 3) to Cell (1, 2).\n\nSample Input 2\n\n3 2\n1 0\n2 1\n1 0\n\nSample Output 2\n\n3\n1 1 1 2\n1 2 2 2\n3 1 3 2\n\nSample Input 3\n\n1 5\n9 9 9 9 9\n\nSample Output 3\n\n2\n1 1 1 2\n1 3 1 4", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1786, "cpu_time_ms": 271, "memory_kb": 5224}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s946340221", "group_id": "codeNet:p03268", "input_text": "#include<iostream>\n#include<cstdio>\n#include<cstring>\n#include<cstdlib>\n#include<iomanip>\n#include<vector>\n#include<queue>\n#include<deque>\n#include<string>\n#include<utility>\n#include<cmath>\n#include<algorithm>\n#include<cctype>\n#include<set>\n#include<map>\n#include<bitset>\n#include<stack>\n#include<ctime>\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef pair<int,int> pii;\ntypedef pair<ll,int> pli;\ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\ntypedef vector<pii> vpii;\ntypedef vector<pli> vpli;\n\ninline ll read(){\n    ll Hashimoto=0;\n\tbool Kanna=1;\n    char I_Love=getchar();\n    while(I_Love<'0'||I_Love>'9'){\n        if(I_Love=='-')Kanna=0;\n        I_Love=getchar();\n    }\n    while(I_Love>='0'&&I_Love<='9'){\n        Hashimoto=Hashimoto*10+I_Love-'0';\n        I_Love=getchar();\n    }\n    return (Kanna?Hashimoto:-Hashimoto);\n}\ntemplate<typename T1,typename T2> inline void Umax(T1 &a,T2 b){\n\tif(a<b)a=b;\n}\ntemplate<typename T1,typename T2> inline void Umin(T1 &a,T2 b){\n\tif(a>b)a=b;\n}\n\n#define I_Love_Hashimoto_Kanna main\n#define fastio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);\n#define filein(s) freopen(s,\"r\",stdin);\n#define fileout(s) freopen(s,\"w\",stdout);\n#define file freopen(\"I_Love_Hashimoto_Kanna.out\",\"w\",stdout);\n#define RE cout<<\"I_Love_Hashimoto_Kanna\"<<endl;\n#define Tone(Kanna) cout<<Kanna<<endl;\n#define Tall(Hashimoto,Kanna) for(int I_Love=0;I_Love<(Kanna);++I_Love)cout<<Hashimoto[I_Love]<<(I_Love==(Kanna)-1?\"\\n\":\" \");\n#define FOR(I_Love,Hashimoto,Kanna) for(int I_Love=Hashimoto;I_Love<(Kanna);++I_Love)\n#define MP(Hashimoto,Kanna) make_pair(Hashimoto,Kanna)\n#define REV(Kanna) reverse(Kanna.begin(),Kanna.end());\n#define SORT(Kanna) sort(Kanna.begin(),Kanna.end());\n#define inf (int)1e9\n#define linf (ll)1e18\n#define mod (inf+7)\n\nint n,k;\n\nint I_Love_Hashimoto_Kanna() {\n\tfastio;\n\tcin>>n>>k;\n\tll cnt=0;\n\tll cnt2=0;\n\tfor(int i=1;i<=n;i++){\n\t\tif(2*i%k==0){\n\t\t\tif((2*i/k)%2)cnt++;\n\t\t\telse cnt2++;\n\t\t}\n\t}\n\t\n\tTone(cnt*cnt*cnt+cnt2*cnt2*cnt2)\n\t\n\t\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1535850793, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03268.html", "problem_id": "p03268", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03268/input.txt", "sample_output_relpath": "derived/input_output/data/p03268/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03268/C++/s946340221.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s946340221", "user_id": "u754862537"}, "prompt_components": {"gold_output": "9\n", "input_to_evaluate": "#include<iostream>\n#include<cstdio>\n#include<cstring>\n#include<cstdlib>\n#include<iomanip>\n#include<vector>\n#include<queue>\n#include<deque>\n#include<string>\n#include<utility>\n#include<cmath>\n#include<algorithm>\n#include<cctype>\n#include<set>\n#include<map>\n#include<bitset>\n#include<stack>\n#include<ctime>\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef pair<int,int> pii;\ntypedef pair<ll,int> pli;\ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\ntypedef vector<pii> vpii;\ntypedef vector<pli> vpli;\n\ninline ll read(){\n    ll Hashimoto=0;\n\tbool Kanna=1;\n    char I_Love=getchar();\n    while(I_Love<'0'||I_Love>'9'){\n        if(I_Love=='-')Kanna=0;\n        I_Love=getchar();\n    }\n    while(I_Love>='0'&&I_Love<='9'){\n        Hashimoto=Hashimoto*10+I_Love-'0';\n        I_Love=getchar();\n    }\n    return (Kanna?Hashimoto:-Hashimoto);\n}\ntemplate<typename T1,typename T2> inline void Umax(T1 &a,T2 b){\n\tif(a<b)a=b;\n}\ntemplate<typename T1,typename T2> inline void Umin(T1 &a,T2 b){\n\tif(a>b)a=b;\n}\n\n#define I_Love_Hashimoto_Kanna main\n#define fastio ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);\n#define filein(s) freopen(s,\"r\",stdin);\n#define fileout(s) freopen(s,\"w\",stdout);\n#define file freopen(\"I_Love_Hashimoto_Kanna.out\",\"w\",stdout);\n#define RE cout<<\"I_Love_Hashimoto_Kanna\"<<endl;\n#define Tone(Kanna) cout<<Kanna<<endl;\n#define Tall(Hashimoto,Kanna) for(int I_Love=0;I_Love<(Kanna);++I_Love)cout<<Hashimoto[I_Love]<<(I_Love==(Kanna)-1?\"\\n\":\" \");\n#define FOR(I_Love,Hashimoto,Kanna) for(int I_Love=Hashimoto;I_Love<(Kanna);++I_Love)\n#define MP(Hashimoto,Kanna) make_pair(Hashimoto,Kanna)\n#define REV(Kanna) reverse(Kanna.begin(),Kanna.end());\n#define SORT(Kanna) sort(Kanna.begin(),Kanna.end());\n#define inf (int)1e9\n#define linf (ll)1e18\n#define mod (inf+7)\n\nint n,k;\n\nint I_Love_Hashimoto_Kanna() {\n\tfastio;\n\tcin>>n>>k;\n\tll cnt=0;\n\tll cnt2=0;\n\tfor(int i=1;i<=n;i++){\n\t\tif(2*i%k==0){\n\t\t\tif((2*i/k)%2)cnt++;\n\t\t\telse cnt2++;\n\t\t}\n\t}\n\t\n\tTone(cnt*cnt*cnt+cnt2*cnt2*cnt2)\n\t\n\t\n\treturn 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nYou are given integers N and K. Find the number of triples (a,b,c) of positive integers not greater than N such that a+b,b+c and c+a are all multiples of K.\nThe order of a,b,c does matter, and some of them can be the same.\n\nConstraints\n\n1 \\leq N,K \\leq 2\\times 10^5\n\nN and K are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the number of triples (a,b,c) of positive integers not greater than N such that a+b,b+c and c+a are all multiples of K.\n\nSample Input 1\n\n3 2\n\nSample Output 1\n\n9\n\n(1,1,1),(1,1,3),(1,3,1),(1,3,3),(2,2,2),(3,1,1),(3,1,3),(3,3,1) and (3,3,3) satisfy the condition.\n\nSample Input 2\n\n5 3\n\nSample Output 2\n\n1\n\nSample Input 3\n\n31415 9265\n\nSample Output 3\n\n27\n\nSample Input 4\n\n35897 932\n\nSample Output 4\n\n114191", "sample_input": "3 2\n"}, "reference_outputs": ["9\n"], "source_document_id": "p03268", "source_text": "Score : 300 points\n\nProblem Statement\n\nYou are given integers N and K. Find the number of triples (a,b,c) of positive integers not greater than N such that a+b,b+c and c+a are all multiples of K.\nThe order of a,b,c does matter, and some of them can be the same.\n\nConstraints\n\n1 \\leq N,K \\leq 2\\times 10^5\n\nN and K are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the number of triples (a,b,c) of positive integers not greater than N such that a+b,b+c and c+a are all multiples of K.\n\nSample Input 1\n\n3 2\n\nSample Output 1\n\n9\n\n(1,1,1),(1,1,3),(1,3,1),(1,3,3),(2,2,2),(3,1,1),(3,1,3),(3,3,1) and (3,3,3) satisfy the condition.\n\nSample Input 2\n\n5 3\n\nSample Output 2\n\n1\n\nSample Input 3\n\n31415 9265\n\nSample Output 3\n\n27\n\nSample Input 4\n\n35897 932\n\nSample Output 4\n\n114191", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2027, "cpu_time_ms": 2, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s480642101", "group_id": "codeNet:p03272", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\n// Loops\n#define _overload3(_1, _2, _3, name, ...) name\n#define _rep(i, n) repi(i, 0, n)\n#define repi(i, a, b) for (int i = int(a); i < int(b); ++i)\n#define _rrep(i, n) rrepi(i, n, 0)\n#define rrepi(i, a, b) for (int i = int(a) - 1; i >= int(b); --i)\n\n#define rep(...) _overload3(__VA_ARGS__, repi, _rep, )(__VA_ARGS__)\n#define rrep(...) _overload3(__VA_ARGS__, rrepi, _rrep, )(__VA_ARGS__)\n#define each(xi, x) for (auto &&xi : x)\n// Note: we can use rep(i,N) or rep(i,from,to)\n\n// typedef\ntemplate <class T> using vec = vector<T>;\nusing ll = long long;\nusing vi = vec<ll>;\nusing vvi = vec<vi>;\nusing vvvi = vec<vvi>;\nusing pii = pair<ll, ll>;\n\n// Constants\n\n// Shorter repr for frequently used terms\n#define pb push_back\n#define mp make_pair\n\n// Algorithms\n#define all(x) (x).begin(), (x).end()\n#define uniq(v) v.erase(unique(all(v)), v.end())\n#define perm(c)                                                                \\\n  sort(all(c));                                                                \\\n  for (bool c##p = 1; c##p; c##p = next_permutation(all(c)))\n\ntemplate <class T> pair<T, size_t> max(vector<T> &x) {\n  auto it = max_element(all(x));\n  return mp(*it, it - x.begin());\n}\ntemplate <class T> pair<T, size_t> min(vector<T> &x) {\n  auto it = min_element(all(x));\n  return mp(*it, it - x.begin());\n}\n\ntemplate <class T> inline bool chmax(T &maxval, const T &newval) {\n  if (maxval < newval) {\n    maxval = newval;\n    return 1;\n  }\n  return 0;\n}\ntemplate <class T> inline bool chmin(T &minval, const T &newval) {\n  if (minval > newval) {\n    minval = newval;\n    return 1;\n  }\n  return 0;\n}\n\n// Utilities\n// Grid world utilities\nint dx[4] = {0, 1, 0, -1};\nint dy[4] = {1, 0, -1, 0};\n#define inside(H, W, y, x) 0 <= (x) && (x) < (W) && 0 <= (y) && (y) < (H)\n\n// Debug\n#ifdef LOCAL\n#include \"dump.hpp\"\n#define debug(x) cerr << #x << \": \" << x << '\\n'\n#else\n#define dump(...)\n#define debug(x)\n#endif\n\n// Yes or No\nvoid yesno(bool ok, string yes = \"Yes\", string no = \"No\") {\n  cout << (ok ? yes : no) << endl;\n}\n\n// Paste snippets here!!\n\n//\n\nvoid solve(long long N, long long i) {\n  cout << N - i + 1 << endl;\n}\n\nint main() {\n  cin.tie(0);\n  ios::sync_with_stdio(false); // Magic for faster cin\n  cout.precision(12);\n  long long N;\n  std::cin >> N;\n  long long i;\n  std::cin >> i;\n  solve(N, i);\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1593572559, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03272.html", "problem_id": "p03272", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03272/input.txt", "sample_output_relpath": "derived/input_output/data/p03272/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03272/C++/s480642101.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s480642101", "user_id": "u292813062"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\n// Loops\n#define _overload3(_1, _2, _3, name, ...) name\n#define _rep(i, n) repi(i, 0, n)\n#define repi(i, a, b) for (int i = int(a); i < int(b); ++i)\n#define _rrep(i, n) rrepi(i, n, 0)\n#define rrepi(i, a, b) for (int i = int(a) - 1; i >= int(b); --i)\n\n#define rep(...) _overload3(__VA_ARGS__, repi, _rep, )(__VA_ARGS__)\n#define rrep(...) _overload3(__VA_ARGS__, rrepi, _rrep, )(__VA_ARGS__)\n#define each(xi, x) for (auto &&xi : x)\n// Note: we can use rep(i,N) or rep(i,from,to)\n\n// typedef\ntemplate <class T> using vec = vector<T>;\nusing ll = long long;\nusing vi = vec<ll>;\nusing vvi = vec<vi>;\nusing vvvi = vec<vvi>;\nusing pii = pair<ll, ll>;\n\n// Constants\n\n// Shorter repr for frequently used terms\n#define pb push_back\n#define mp make_pair\n\n// Algorithms\n#define all(x) (x).begin(), (x).end()\n#define uniq(v) v.erase(unique(all(v)), v.end())\n#define perm(c)                                                                \\\n  sort(all(c));                                                                \\\n  for (bool c##p = 1; c##p; c##p = next_permutation(all(c)))\n\ntemplate <class T> pair<T, size_t> max(vector<T> &x) {\n  auto it = max_element(all(x));\n  return mp(*it, it - x.begin());\n}\ntemplate <class T> pair<T, size_t> min(vector<T> &x) {\n  auto it = min_element(all(x));\n  return mp(*it, it - x.begin());\n}\n\ntemplate <class T> inline bool chmax(T &maxval, const T &newval) {\n  if (maxval < newval) {\n    maxval = newval;\n    return 1;\n  }\n  return 0;\n}\ntemplate <class T> inline bool chmin(T &minval, const T &newval) {\n  if (minval > newval) {\n    minval = newval;\n    return 1;\n  }\n  return 0;\n}\n\n// Utilities\n// Grid world utilities\nint dx[4] = {0, 1, 0, -1};\nint dy[4] = {1, 0, -1, 0};\n#define inside(H, W, y, x) 0 <= (x) && (x) < (W) && 0 <= (y) && (y) < (H)\n\n// Debug\n#ifdef LOCAL\n#include \"dump.hpp\"\n#define debug(x) cerr << #x << \": \" << x << '\\n'\n#else\n#define dump(...)\n#define debug(x)\n#endif\n\n// Yes or No\nvoid yesno(bool ok, string yes = \"Yes\", string no = \"No\") {\n  cout << (ok ? yes : no) << endl;\n}\n\n// Paste snippets here!!\n\n//\n\nvoid solve(long long N, long long i) {\n  cout << N - i + 1 << endl;\n}\n\nint main() {\n  cin.tie(0);\n  ios::sync_with_stdio(false); // Magic for faster cin\n  cout.precision(12);\n  long long N;\n  std::cin >> N;\n  long long i;\n  std::cin >> i;\n  solve(N, i);\n  return 0;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nThere is an N-car train.\n\nYou are given an integer i. Find the value of j such that the following statement is true: \"the i-th car from the front of the train is the j-th car from the back.\"\n\nConstraints\n\n1 \\leq N \\leq 100\n\n1 \\leq i \\leq N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN i\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n4 2\n\nSample Output 1\n\n3\n\nThe second car from the front of a 4-car train is the third car from the back.\n\nSample Input 2\n\n1 1\n\nSample Output 2\n\n1\n\nSample Input 3\n\n15 11\n\nSample Output 3\n\n5", "sample_input": "4 2\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03272", "source_text": "Score : 100 points\n\nProblem Statement\n\nThere is an N-car train.\n\nYou are given an integer i. Find the value of j such that the following statement is true: \"the i-th car from the front of the train is the j-th car from the back.\"\n\nConstraints\n\n1 \\leq N \\leq 100\n\n1 \\leq i \\leq N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN i\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n4 2\n\nSample Output 1\n\n3\n\nThe second car from the front of a 4-car train is the third car from the back.\n\nSample Input 2\n\n1 1\n\nSample Output 2\n\n1\n\nSample Input 3\n\n15 11\n\nSample Output 3\n\n5", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2370, "cpu_time_ms": 8, "memory_kb": 3576}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s349422277", "group_id": "codeNet:p03272", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for(int i = 0; i < (n); i++)\n#define rep1(i, n) for(int i = 1; i <= (n); i++)\n#define Would\n#define you\n#define please\n\nint main() {\n\tint N,i;\n\tcin >> N >> i;\n\tcout << N + 1 - i << \"\\n\";\n\n\tWould you please return 0;\n}\n", "language": "C++", "metadata": {"date": 1535245301, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03272.html", "problem_id": "p03272", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03272/input.txt", "sample_output_relpath": "derived/input_output/data/p03272/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03272/C++/s349422277.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s349422277", "user_id": "u096883693"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for(int i = 0; i < (n); i++)\n#define rep1(i, n) for(int i = 1; i <= (n); i++)\n#define Would\n#define you\n#define please\n\nint main() {\n\tint N,i;\n\tcin >> N >> i;\n\tcout << N + 1 - i << \"\\n\";\n\n\tWould you please return 0;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nThere is an N-car train.\n\nYou are given an integer i. Find the value of j such that the following statement is true: \"the i-th car from the front of the train is the j-th car from the back.\"\n\nConstraints\n\n1 \\leq N \\leq 100\n\n1 \\leq i \\leq N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN i\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n4 2\n\nSample Output 1\n\n3\n\nThe second car from the front of a 4-car train is the third car from the back.\n\nSample Input 2\n\n1 1\n\nSample Output 2\n\n1\n\nSample Input 3\n\n15 11\n\nSample Output 3\n\n5", "sample_input": "4 2\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03272", "source_text": "Score : 100 points\n\nProblem Statement\n\nThere is an N-car train.\n\nYou are given an integer i. Find the value of j such that the following statement is true: \"the i-th car from the front of the train is the j-th car from the back.\"\n\nConstraints\n\n1 \\leq N \\leq 100\n\n1 \\leq i \\leq N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN i\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n4 2\n\nSample Output 1\n\n3\n\nThe second car from the front of a 4-car train is the third car from the back.\n\nSample Input 2\n\n1 1\n\nSample Output 2\n\n1\n\nSample Input 3\n\n15 11\n\nSample Output 3\n\n5", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 281, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s513032179", "group_id": "codeNet:p03273", "input_text": "#include <algorithm>\n#include <iostream>\n#include <vector>\nusing namespace std;\ntypedef long long ll;\nconst int INF = 1 << 30;\nconst ll INFll = 1ll << 60;\n\nint main() {\n  int h, w;\n  cin >> h >> w;\n  vector<int> H;\n  vector<int> W;\n  vector<vector<char>> A(h, vector<char>(w));\n  for (int i = 0; i < h; i++) {\n    for (int j = 0; j < w; j++) {\n      char a;\n      cin >> a;\n      A[i][j] = a;\n      if (a == '#') {\n        H.push_back(i);\n        W.push_back(j);\n      }\n    }\n  }\n\n  for (int i : H) {\n    for (int j : W) {\n      cout << A[i][j];\n    }\n    cout << endl;\n  }\n\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1577168940, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03273.html", "problem_id": "p03273", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03273/input.txt", "sample_output_relpath": "derived/input_output/data/p03273/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03273/C++/s513032179.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s513032179", "user_id": "u735008991"}, "prompt_components": {"gold_output": "###\n###\n.##\n", "input_to_evaluate": "#include <algorithm>\n#include <iostream>\n#include <vector>\nusing namespace std;\ntypedef long long ll;\nconst int INF = 1 << 30;\nconst ll INFll = 1ll << 60;\n\nint main() {\n  int h, w;\n  cin >> h >> w;\n  vector<int> H;\n  vector<int> W;\n  vector<vector<char>> A(h, vector<char>(w));\n  for (int i = 0; i < h; i++) {\n    for (int j = 0; j < w; j++) {\n      char a;\n      cin >> a;\n      A[i][j] = a;\n      if (a == '#') {\n        H.push_back(i);\n        W.push_back(j);\n      }\n    }\n  }\n\n  for (int i : H) {\n    for (int j : W) {\n      cout << A[i][j];\n    }\n    cout << endl;\n  }\n\n  return 0;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nThere is a grid of squares with H horizontal rows and W vertical columns.\nThe square at the i-th row from the top and the j-th column from the left is represented as (i, j).\nEach square is black or white.\nThe color of the square is given as an H-by-W matrix (a_{i, j}).\nIf a_{i, j} is ., the square (i, j) is white; if a_{i, j} is #, the square (i, j) is black.\n\nSnuke is compressing this grid.\nHe will do so by repeatedly performing the following operation while there is a row or column that consists only of white squares:\n\nOperation: choose any one row or column that consists only of white squares, remove it and delete the space between the rows or columns.\n\nIt can be shown that the final state of the grid is uniquely determined regardless of what row or column is chosen in each operation.\nFind the final state of the grid.\n\nConstraints\n\n1 \\leq H, W \\leq 100\n\na_{i, j} is . or #.\n\nThere is at least one black square in the whole grid.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W\na_{1, 1}...a_{1, W}\n:\na_{H, 1}...a_{H, W}\n\nOutput\n\nPrint the final state of the grid in the same format as input (without the numbers of rows and columns); see the samples for clarity.\n\nSample Input 1\n\n4 4\n##.#\n....\n##.#\n.#.#\n\nSample Output 1\n\n###\n###\n.##\n\nThe second row and the third column in the original grid will be removed.\n\nSample Input 2\n\n3 3\n#..\n.#.\n..#\n\nSample Output 2\n\n#..\n.#.\n..#\n\nAs there is no row or column that consists only of white squares, no operation will be performed.\n\nSample Input 3\n\n4 5\n.....\n.....\n..#..\n.....\n\nSample Output 3\n\n#\n\nSample Input 4\n\n7 6\n......\n....#.\n.#....\n..#...\n..#...\n......\n.#..#.\n\nSample Output 4\n\n..#\n#..\n.#.\n.#.\n#.#", "sample_input": "4 4\n##.#\n....\n##.#\n.#.#\n"}, "reference_outputs": ["###\n###\n.##\n"], "source_document_id": "p03273", "source_text": "Score : 200 points\n\nProblem Statement\n\nThere is a grid of squares with H horizontal rows and W vertical columns.\nThe square at the i-th row from the top and the j-th column from the left is represented as (i, j).\nEach square is black or white.\nThe color of the square is given as an H-by-W matrix (a_{i, j}).\nIf a_{i, j} is ., the square (i, j) is white; if a_{i, j} is #, the square (i, j) is black.\n\nSnuke is compressing this grid.\nHe will do so by repeatedly performing the following operation while there is a row or column that consists only of white squares:\n\nOperation: choose any one row or column that consists only of white squares, remove it and delete the space between the rows or columns.\n\nIt can be shown that the final state of the grid is uniquely determined regardless of what row or column is chosen in each operation.\nFind the final state of the grid.\n\nConstraints\n\n1 \\leq H, W \\leq 100\n\na_{i, j} is . or #.\n\nThere is at least one black square in the whole grid.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W\na_{1, 1}...a_{1, W}\n:\na_{H, 1}...a_{H, W}\n\nOutput\n\nPrint the final state of the grid in the same format as input (without the numbers of rows and columns); see the samples for clarity.\n\nSample Input 1\n\n4 4\n##.#\n....\n##.#\n.#.#\n\nSample Output 1\n\n###\n###\n.##\n\nThe second row and the third column in the original grid will be removed.\n\nSample Input 2\n\n3 3\n#..\n.#.\n..#\n\nSample Output 2\n\n#..\n.#.\n..#\n\nAs there is no row or column that consists only of white squares, no operation will be performed.\n\nSample Input 3\n\n4 5\n.....\n.....\n..#..\n.....\n\nSample Output 3\n\n#\n\nSample Input 4\n\n7 6\n......\n....#.\n.#....\n..#...\n..#...\n......\n.#..#.\n\nSample Output 4\n\n..#\n#..\n.#.\n.#.\n#.#", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 590, "cpu_time_ms": 2103, "memory_kb": 70656}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s408838026", "group_id": "codeNet:p03273", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nint n,m;\nchar f[101][101]={0};\nint check(int a,int i)\n{\n\tint j;\n\tif(a==0)\n\t{\n\t\tfor(j=0;j<m;j++)\n\t\t{\n\t\t\tif(f[i][j]=='#')\n\t\t\t\treturn 0;\n\t\t}\n\t\treturn 1;\n\t}\n\telse\n\t{\n\t\tfor(j=0;j<n;j++)\n\t\t{\n\t\t\tif(f[j][i]=='#')\n\t\t\t\treturn 0;\n\t\t}\n\t\treturn 1;\n\t}\n}\nvoid remove(int a,int i)\n{\n\tint j;\n\tif(a==0)\n\t{\n\t\tfor(j=0;j<m;j++)\n\t\t{\n\t\t\tf[i][j]=' ';\n\t\t}\n\t}\n\telse\n\t{\n\t\tfor(j=0;j<n;j++)\n\t\t{\n\t\t\tf[j][i]=' ';\n\t\t}\n\t}\n}\nint main()\n{\n\tint i,j,t;\n\tscanf(\"%d %d\",&n,&m);\n\tgetchar();\n\tfor(i=0;i<n;i++)\n\t{\n\t\tscanf(\"%s\",f[i]);\n\t}\n\tfor(i=0;i<n;i++)\n\t{\n\t\tif(check(0,i))\n\t\t\tremove(0,i);\n\t}\n\tfor(j=0;j<m;j++)\n\t{\n\t\tif(check(1,j))\n\t\t\tremove(1,j);\n\t}\n\tfor(i=0;i<n;i++)\n\t{\n\t\tt=0;\n\t\tfor(j=0;j<m;j++)\n\t\t{\n\t\t\tif(f[i][j]!=' ')\n\t\t\t{\n\t\t\t\tprintf(\"%c\",f[i][j]);\n\t\t\t\tt=1;\n\t\t\t}\n\t\t}\n\t\tif(t)\n\t\t\tprintf(\"\\n\");\n\t}\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1535248317, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03273.html", "problem_id": "p03273", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03273/input.txt", "sample_output_relpath": "derived/input_output/data/p03273/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03273/C++/s408838026.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s408838026", "user_id": "u356929542"}, "prompt_components": {"gold_output": "###\n###\n.##\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nint n,m;\nchar f[101][101]={0};\nint check(int a,int i)\n{\n\tint j;\n\tif(a==0)\n\t{\n\t\tfor(j=0;j<m;j++)\n\t\t{\n\t\t\tif(f[i][j]=='#')\n\t\t\t\treturn 0;\n\t\t}\n\t\treturn 1;\n\t}\n\telse\n\t{\n\t\tfor(j=0;j<n;j++)\n\t\t{\n\t\t\tif(f[j][i]=='#')\n\t\t\t\treturn 0;\n\t\t}\n\t\treturn 1;\n\t}\n}\nvoid remove(int a,int i)\n{\n\tint j;\n\tif(a==0)\n\t{\n\t\tfor(j=0;j<m;j++)\n\t\t{\n\t\t\tf[i][j]=' ';\n\t\t}\n\t}\n\telse\n\t{\n\t\tfor(j=0;j<n;j++)\n\t\t{\n\t\t\tf[j][i]=' ';\n\t\t}\n\t}\n}\nint main()\n{\n\tint i,j,t;\n\tscanf(\"%d %d\",&n,&m);\n\tgetchar();\n\tfor(i=0;i<n;i++)\n\t{\n\t\tscanf(\"%s\",f[i]);\n\t}\n\tfor(i=0;i<n;i++)\n\t{\n\t\tif(check(0,i))\n\t\t\tremove(0,i);\n\t}\n\tfor(j=0;j<m;j++)\n\t{\n\t\tif(check(1,j))\n\t\t\tremove(1,j);\n\t}\n\tfor(i=0;i<n;i++)\n\t{\n\t\tt=0;\n\t\tfor(j=0;j<m;j++)\n\t\t{\n\t\t\tif(f[i][j]!=' ')\n\t\t\t{\n\t\t\t\tprintf(\"%c\",f[i][j]);\n\t\t\t\tt=1;\n\t\t\t}\n\t\t}\n\t\tif(t)\n\t\t\tprintf(\"\\n\");\n\t}\n\treturn 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nThere is a grid of squares with H horizontal rows and W vertical columns.\nThe square at the i-th row from the top and the j-th column from the left is represented as (i, j).\nEach square is black or white.\nThe color of the square is given as an H-by-W matrix (a_{i, j}).\nIf a_{i, j} is ., the square (i, j) is white; if a_{i, j} is #, the square (i, j) is black.\n\nSnuke is compressing this grid.\nHe will do so by repeatedly performing the following operation while there is a row or column that consists only of white squares:\n\nOperation: choose any one row or column that consists only of white squares, remove it and delete the space between the rows or columns.\n\nIt can be shown that the final state of the grid is uniquely determined regardless of what row or column is chosen in each operation.\nFind the final state of the grid.\n\nConstraints\n\n1 \\leq H, W \\leq 100\n\na_{i, j} is . or #.\n\nThere is at least one black square in the whole grid.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W\na_{1, 1}...a_{1, W}\n:\na_{H, 1}...a_{H, W}\n\nOutput\n\nPrint the final state of the grid in the same format as input (without the numbers of rows and columns); see the samples for clarity.\n\nSample Input 1\n\n4 4\n##.#\n....\n##.#\n.#.#\n\nSample Output 1\n\n###\n###\n.##\n\nThe second row and the third column in the original grid will be removed.\n\nSample Input 2\n\n3 3\n#..\n.#.\n..#\n\nSample Output 2\n\n#..\n.#.\n..#\n\nAs there is no row or column that consists only of white squares, no operation will be performed.\n\nSample Input 3\n\n4 5\n.....\n.....\n..#..\n.....\n\nSample Output 3\n\n#\n\nSample Input 4\n\n7 6\n......\n....#.\n.#....\n..#...\n..#...\n......\n.#..#.\n\nSample Output 4\n\n..#\n#..\n.#.\n.#.\n#.#", "sample_input": "4 4\n##.#\n....\n##.#\n.#.#\n"}, "reference_outputs": ["###\n###\n.##\n"], "source_document_id": "p03273", "source_text": "Score : 200 points\n\nProblem Statement\n\nThere is a grid of squares with H horizontal rows and W vertical columns.\nThe square at the i-th row from the top and the j-th column from the left is represented as (i, j).\nEach square is black or white.\nThe color of the square is given as an H-by-W matrix (a_{i, j}).\nIf a_{i, j} is ., the square (i, j) is white; if a_{i, j} is #, the square (i, j) is black.\n\nSnuke is compressing this grid.\nHe will do so by repeatedly performing the following operation while there is a row or column that consists only of white squares:\n\nOperation: choose any one row or column that consists only of white squares, remove it and delete the space between the rows or columns.\n\nIt can be shown that the final state of the grid is uniquely determined regardless of what row or column is chosen in each operation.\nFind the final state of the grid.\n\nConstraints\n\n1 \\leq H, W \\leq 100\n\na_{i, j} is . or #.\n\nThere is at least one black square in the whole grid.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W\na_{1, 1}...a_{1, W}\n:\na_{H, 1}...a_{H, W}\n\nOutput\n\nPrint the final state of the grid in the same format as input (without the numbers of rows and columns); see the samples for clarity.\n\nSample Input 1\n\n4 4\n##.#\n....\n##.#\n.#.#\n\nSample Output 1\n\n###\n###\n.##\n\nThe second row and the third column in the original grid will be removed.\n\nSample Input 2\n\n3 3\n#..\n.#.\n..#\n\nSample Output 2\n\n#..\n.#.\n..#\n\nAs there is no row or column that consists only of white squares, no operation will be performed.\n\nSample Input 3\n\n4 5\n.....\n.....\n..#..\n.....\n\nSample Output 3\n\n#\n\nSample Input 4\n\n7 6\n......\n....#.\n.#....\n..#...\n..#...\n......\n.#..#.\n\nSample Output 4\n\n..#\n#..\n.#.\n.#.\n#.#", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 814, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s857444803", "group_id": "codeNet:p03274", "input_text": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define MAX_N 100001\n\nint N;\nint K;\nlong int x[MAX_N];\n\nint main(){\n    cin >> N >> K;\n    bool flag = true;\n    for (int i = 0; i < N; i++){\n        long int element;\n        cin >> element;\n        // if ((element > 0) && (flag)){\n            // flag = false;\n            // x[i] = 0;\n            // i ++;\n        // }\n        x[i] = element;\n    }\n    // for (int i = 0; i <= N; i++){\n    //     cout << x[i] << endl;\n    // }\n    int left = 0;\n    int right = K - 1;\n    long int distance = 10000000001;\n    if (x[0] >= 0){\n        distance = x[K - 1];\n    }\n    else if (x[N - 1] <= 0){\n        distance = - x[N - K];\n    }\n    else{\n        while (right < N){\n            if ((x[right] >= 0) && (x[left] <= 0)){\n                distance = min(min(2 * x[right] - x[left], x[right] - 2 * x[left]), distance);\n            }\n            left ++;\n            right ++;\n        }\n    }\n    cout << distance << endl;\n\n    return 0;\n}", "language": "C++", "metadata": {"date": 1556733542, "filename_ext": "cpp", "original_language": "C++14 (Clang 3.8.0)", "problem_description_relpath": "problem_descriptions/p03274.html", "problem_id": "p03274", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03274/input.txt", "sample_output_relpath": "derived/input_output/data/p03274/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03274/C++/s857444803.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s857444803", "user_id": "u168139048"}, "prompt_components": {"gold_output": "40\n", "input_to_evaluate": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define MAX_N 100001\n\nint N;\nint K;\nlong int x[MAX_N];\n\nint main(){\n    cin >> N >> K;\n    bool flag = true;\n    for (int i = 0; i < N; i++){\n        long int element;\n        cin >> element;\n        // if ((element > 0) && (flag)){\n            // flag = false;\n            // x[i] = 0;\n            // i ++;\n        // }\n        x[i] = element;\n    }\n    // for (int i = 0; i <= N; i++){\n    //     cout << x[i] << endl;\n    // }\n    int left = 0;\n    int right = K - 1;\n    long int distance = 10000000001;\n    if (x[0] >= 0){\n        distance = x[K - 1];\n    }\n    else if (x[N - 1] <= 0){\n        distance = - x[N - K];\n    }\n    else{\n        while (right < N){\n            if ((x[right] >= 0) && (x[left] <= 0)){\n                distance = min(min(2 * x[right] - x[left], x[right] - 2 * x[left]), distance);\n            }\n            left ++;\n            right ++;\n        }\n    }\n    cout << distance << endl;\n\n    return 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N candles placed on a number line.\nThe i-th candle from the left is placed on coordinate x_i.\nHere, x_1 < x_2 < ... < x_N holds.\n\nInitially, no candles are burning.\nSnuke decides to light K of the N candles.\n\nNow, he is at coordinate 0.\nHe can move left and right along the line with speed 1.\nHe can also light a candle when he is at the same position as the candle, in negligible time.\n\nFind the minimum time required to light K candles.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq K \\leq N\n\nx_i is an integer.\n\n|x_i| \\leq 10^8\n\nx_1 < x_2 < ... < x_N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nx_1 x_2 ... x_N\n\nOutput\n\nPrint the minimum time required to light K candles.\n\nSample Input 1\n\n5 3\n-30 -10 10 20 50\n\nSample Output 1\n\n40\n\nHe should move and light candles as follows:\n\nMove from coordinate 0 to -10.\n\nLight the second candle from the left.\n\nMove from coordinate -10 to 10.\n\nLight the third candle from the left.\n\nMove from coordinate 10 to 20.\n\nLight the fourth candle from the left.\n\nSample Input 2\n\n3 2\n10 20 30\n\nSample Output 2\n\n20\n\nSample Input 3\n\n1 1\n0\n\nSample Output 3\n\n0\n\nThere may be a candle placed at coordinate 0.\n\nSample Input 4\n\n8 5\n-9 -7 -4 -3 1 2 3 4\n\nSample Output 4\n\n10", "sample_input": "5 3\n-30 -10 10 20 50\n"}, "reference_outputs": ["40\n"], "source_document_id": "p03274", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N candles placed on a number line.\nThe i-th candle from the left is placed on coordinate x_i.\nHere, x_1 < x_2 < ... < x_N holds.\n\nInitially, no candles are burning.\nSnuke decides to light K of the N candles.\n\nNow, he is at coordinate 0.\nHe can move left and right along the line with speed 1.\nHe can also light a candle when he is at the same position as the candle, in negligible time.\n\nFind the minimum time required to light K candles.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq K \\leq N\n\nx_i is an integer.\n\n|x_i| \\leq 10^8\n\nx_1 < x_2 < ... < x_N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nx_1 x_2 ... x_N\n\nOutput\n\nPrint the minimum time required to light K candles.\n\nSample Input 1\n\n5 3\n-30 -10 10 20 50\n\nSample Output 1\n\n40\n\nHe should move and light candles as follows:\n\nMove from coordinate 0 to -10.\n\nLight the second candle from the left.\n\nMove from coordinate -10 to 10.\n\nLight the third candle from the left.\n\nMove from coordinate 10 to 20.\n\nLight the fourth candle from the left.\n\nSample Input 2\n\n3 2\n10 20 30\n\nSample Output 2\n\n20\n\nSample Input 3\n\n1 1\n0\n\nSample Output 3\n\n0\n\nThere may be a candle placed at coordinate 0.\n\nSample Input 4\n\n8 5\n-9 -7 -4 -3 1 2 3 4\n\nSample Output 4\n\n10", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 994, "cpu_time_ms": 110, "memory_kb": 1024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s869856828", "group_id": "codeNet:p03275", "input_text": "#include <functional>\n#include <iostream>\n#include <vector>\nusing namespace std;\ntypedef long long ll;\n\ntemplate<typename Monoid>\nstruct SegmentTree {\n    using F = function<Monoid(Monoid, Monoid)>;\n\n    int sz;\n    vector<Monoid> seg;\n\n    const F f;\n    const Monoid M1;\n\n    SegmentTree(int n, const F f, const Monoid &M1) : f(f), M1(M1) {\n        sz = 1;\n        while(sz < n) sz <<= 1;\n        seg.assign(2 * sz, M1);\n    }\n\n    void set(int k, const Monoid &x) {\n        seg[k + sz] = x;\n    }\n\n    void build() {\n        for(int k = sz - 1; k > 0; k--) {\n            seg[k] = f(seg[2 * k + 0], seg[2 * k + 1]);\n        }\n    }\n\n    void update(int k, const Monoid &x) {\n        k += sz;\n        seg[k] = x;\n        while(k >>= 1) {\n            seg[k] = f(seg[2 * k + 0], seg[2 * k + 1]);\n        }\n    }\n\n    Monoid query(int a, int b) {\n        Monoid L = M1, R = M1;\n        for(a += sz, b += sz; a < b; a >>= 1, b >>= 1) {\n            if(a & 1) L = f(L, seg[a++]);\n            if(b & 1) R = f(seg[--b], R);\n        }\n        return f(L, R);\n    }\n\n    Monoid operator[](const int &k) const {\n        return seg[k + sz];\n    }\n};\n\nint main()\n{\n    int n;\n    cin >> n;\n    int a[100002];\n    for(int i = 0; i < n; i++) cin >> a[i];\n    int now = 1048576 * 512 - 1;\n    int mid = 1048576 * 256;\n    while(mid){\n        int b[100002]{0};\n        for(int i = 0; i < n; i++){\n            if(a[i] >= now) b[i]++;\n            else b[i]--;\n            b[i + 1] += b[i];\n        }\n        ll s[200002]{0};\n        for(int i = 0; i < n; i++) s[b[i] + 100000]++;\n        SegmentTree<ll> seg(200000, [](ll a, ll b){return a + b;}, 0ll);\n        for(int i = 0; i <= 200000; i++) seg.set(i, s[i]);\n        seg.build();\n        int k = 0;\n        ll sum = 0;\n        for(int i = 0; i < n; i++){\n            sum += seg.query(k + 100000, 200001);\n            seg.update(b[i] + 100000, seg[b[i] + 100000] - 1);\n            if(a[i] < now) k--;\n            else k++;\n        }\n        if(sum >= (n * (n + 1) / 2 + 1) / 2) now += mid;\n        else now -= mid;\n        mid /= 2;\n    }\n    int b[100002]{0};\n    for(int i = 0; i < n; i++){\n        if(a[i] >= now) b[i]++;\n        else b[i]--;\n        b[i + 1] += b[i];\n    }\n    ll s[200002]{0};\n    for(int i = 0; i < n; i++) s[b[i] + 100000]++;\n    SegmentTree<ll> seg(200000, [](ll a, ll b){return a + b;}, 0ll);\n    for(int i = 0; i <= 200000; i++) seg.set(i, s[i]);\n    seg.build();\n    int k = 0;\n    ll sum = 0;\n    for(int i = 0; i < n; i++){\n        sum += seg.query(k + 100000, 200001);\n        seg.update(b[i] + 100000, seg[b[i] + 100000] - 1);\n        if(a[i] < now) k--;\n        else k++;\n    }\n    if(sum < (n * (n + 1) / 2 + 1) / 2) now--;\n    cout << now << endl;\n}", "language": "C++", "metadata": {"date": 1578693285, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03275.html", "problem_id": "p03275", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03275/input.txt", "sample_output_relpath": "derived/input_output/data/p03275/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03275/C++/s869856828.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s869856828", "user_id": "u681557252"}, "prompt_components": {"gold_output": "30\n", "input_to_evaluate": "#include <functional>\n#include <iostream>\n#include <vector>\nusing namespace std;\ntypedef long long ll;\n\ntemplate<typename Monoid>\nstruct SegmentTree {\n    using F = function<Monoid(Monoid, Monoid)>;\n\n    int sz;\n    vector<Monoid> seg;\n\n    const F f;\n    const Monoid M1;\n\n    SegmentTree(int n, const F f, const Monoid &M1) : f(f), M1(M1) {\n        sz = 1;\n        while(sz < n) sz <<= 1;\n        seg.assign(2 * sz, M1);\n    }\n\n    void set(int k, const Monoid &x) {\n        seg[k + sz] = x;\n    }\n\n    void build() {\n        for(int k = sz - 1; k > 0; k--) {\n            seg[k] = f(seg[2 * k + 0], seg[2 * k + 1]);\n        }\n    }\n\n    void update(int k, const Monoid &x) {\n        k += sz;\n        seg[k] = x;\n        while(k >>= 1) {\n            seg[k] = f(seg[2 * k + 0], seg[2 * k + 1]);\n        }\n    }\n\n    Monoid query(int a, int b) {\n        Monoid L = M1, R = M1;\n        for(a += sz, b += sz; a < b; a >>= 1, b >>= 1) {\n            if(a & 1) L = f(L, seg[a++]);\n            if(b & 1) R = f(seg[--b], R);\n        }\n        return f(L, R);\n    }\n\n    Monoid operator[](const int &k) const {\n        return seg[k + sz];\n    }\n};\n\nint main()\n{\n    int n;\n    cin >> n;\n    int a[100002];\n    for(int i = 0; i < n; i++) cin >> a[i];\n    int now = 1048576 * 512 - 1;\n    int mid = 1048576 * 256;\n    while(mid){\n        int b[100002]{0};\n        for(int i = 0; i < n; i++){\n            if(a[i] >= now) b[i]++;\n            else b[i]--;\n            b[i + 1] += b[i];\n        }\n        ll s[200002]{0};\n        for(int i = 0; i < n; i++) s[b[i] + 100000]++;\n        SegmentTree<ll> seg(200000, [](ll a, ll b){return a + b;}, 0ll);\n        for(int i = 0; i <= 200000; i++) seg.set(i, s[i]);\n        seg.build();\n        int k = 0;\n        ll sum = 0;\n        for(int i = 0; i < n; i++){\n            sum += seg.query(k + 100000, 200001);\n            seg.update(b[i] + 100000, seg[b[i] + 100000] - 1);\n            if(a[i] < now) k--;\n            else k++;\n        }\n        if(sum >= (n * (n + 1) / 2 + 1) / 2) now += mid;\n        else now -= mid;\n        mid /= 2;\n    }\n    int b[100002]{0};\n    for(int i = 0; i < n; i++){\n        if(a[i] >= now) b[i]++;\n        else b[i]--;\n        b[i + 1] += b[i];\n    }\n    ll s[200002]{0};\n    for(int i = 0; i < n; i++) s[b[i] + 100000]++;\n    SegmentTree<ll> seg(200000, [](ll a, ll b){return a + b;}, 0ll);\n    for(int i = 0; i <= 200000; i++) seg.set(i, s[i]);\n    seg.build();\n    int k = 0;\n    ll sum = 0;\n    for(int i = 0; i < n; i++){\n        sum += seg.query(k + 100000, 200001);\n        seg.update(b[i] + 100000, seg[b[i] + 100000] - 1);\n        if(a[i] < now) k--;\n        else k++;\n    }\n    if(sum < (n * (n + 1) / 2 + 1) / 2) now--;\n    cout << now << endl;\n}", "problem_context": "Score : 700 points\n\nProblem Statement\n\nWe will define the median of a sequence b of length M, as follows:\n\nLet b' be the sequence obtained by sorting b in non-decreasing order. Then, the value of the (M / 2 + 1)-th element of b' is the median of b. Here, / is integer division, rounding down.\n\nFor example, the median of (10, 30, 20) is 20; the median of (10, 30, 20, 40) is 30; the median of (10, 10, 10, 20, 30) is 10.\n\nSnuke comes up with the following problem.\n\nYou are given a sequence a of length N.\nFor each pair (l, r) (1 \\leq l \\leq r \\leq N), let m_{l, r} be the median of the contiguous subsequence (a_l, a_{l + 1}, ..., a_r) of a.\nWe will list m_{l, r} for all pairs (l, r) to create a new sequence m.\nFind the median of m.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\na_i is an integer.\n\n1 \\leq a_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_N\n\nOutput\n\nPrint the median of m.\n\nSample Input 1\n\n3\n10 30 20\n\nSample Output 1\n\n30\n\nThe median of each contiguous subsequence of a is as follows:\n\nThe median of (10) is 10.\n\nThe median of (30) is 30.\n\nThe median of (20) is 20.\n\nThe median of (10, 30) is 30.\n\nThe median of (30, 20) is 30.\n\nThe median of (10, 30, 20) is 20.\n\nThus, m = (10, 30, 20, 30, 30, 20) and the median of m is 30.\n\nSample Input 2\n\n1\n10\n\nSample Output 2\n\n10\n\nSample Input 3\n\n10\n5 9 5 9 8 9 3 5 4 3\n\nSample Output 3\n\n8", "sample_input": "3\n10 30 20\n"}, "reference_outputs": ["30\n"], "source_document_id": "p03275", "source_text": "Score : 700 points\n\nProblem Statement\n\nWe will define the median of a sequence b of length M, as follows:\n\nLet b' be the sequence obtained by sorting b in non-decreasing order. Then, the value of the (M / 2 + 1)-th element of b' is the median of b. Here, / is integer division, rounding down.\n\nFor example, the median of (10, 30, 20) is 20; the median of (10, 30, 20, 40) is 30; the median of (10, 10, 10, 20, 30) is 10.\n\nSnuke comes up with the following problem.\n\nYou are given a sequence a of length N.\nFor each pair (l, r) (1 \\leq l \\leq r \\leq N), let m_{l, r} be the median of the contiguous subsequence (a_l, a_{l + 1}, ..., a_r) of a.\nWe will list m_{l, r} for all pairs (l, r) to create a new sequence m.\nFind the median of m.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\na_i is an integer.\n\n1 \\leq a_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_N\n\nOutput\n\nPrint the median of m.\n\nSample Input 1\n\n3\n10 30 20\n\nSample Output 1\n\n30\n\nThe median of each contiguous subsequence of a is as follows:\n\nThe median of (10) is 10.\n\nThe median of (30) is 30.\n\nThe median of (20) is 20.\n\nThe median of (10, 30) is 30.\n\nThe median of (30, 20) is 30.\n\nThe median of (10, 30, 20) is 20.\n\nThus, m = (10, 30, 20, 30, 30, 20) and the median of m is 30.\n\nSample Input 2\n\n1\n10\n\nSample Output 2\n\n10\n\nSample Input 3\n\n10\n5 9 5 9 8 9 3 5 4 3\n\nSample Output 3\n\n8", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2718, "cpu_time_ms": 580, "memory_kb": 6656}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s150970974", "group_id": "codeNet:p03275", "input_text": "#include <iostream>\n#include <algorithm>\n#include <cstring>\nusing namespace std;\nconst int maxn=1e6+10;\nint a[maxn],b[maxn];\nstruct node{\n\tint val,loc;\n}sub[maxn];\nlong long tre[maxn],n;\nint cmp(const node &a,const node &b){\n\tif(a.val==b.val) return a.loc<b.loc;\n\telse return a.val<b.val;\n}\ninline int lowbit(int x){\n\treturn x&(-x);\n}\nvoid add(int pos,int val){\n\twhile(pos<=n){\n\t\ttre[pos]+=val;\n\t\tpos+=lowbit(pos);\n\t}\n\treturn;\n}\nlong long query(int pos){\n\tlong long sum=0;\n\twhile(pos>0){\n\t\tsum+=tre[pos];\n\t\tpos-=lowbit(pos);\n\t}\n\treturn sum;\n}\nlong long check(int val){\n\tmemset(tre,0,sizeof(tre));\n\tlong long ans=0;\n\tfor(int i=1;i<=n;i++){\n\t\tif(a[i]<val) sub[i].val=-1;\n\t\telse sub[i].val=1;\n\t\tsub[i].val+=sub[i-1].val;\n\t\tsub[i].loc=i;\n\t}\n\tsort(sub+1,sub+n+1,cmp);\n\tfor(int i=1;i<=n;i++){\n\t\tadd(sub[i].loc,1);\n\t\tans+=query(sub[i].loc-1);\n\t\tif(sub[i].val>=0) ans++;\n\t}\n\treturn ans;\n}\nint erf(int l,int r){\n\tint mid;\n\tlong long _std=(n+1)*n/4+1;\n\twhile(l<r){\n\t\tmid=(l+r+1)>>1;\n\t\tif(check(b[mid])>=_std) l=mid;//Çó³ö±Èb[mid]´óÓÚµÈÓÚµÄ \n\t\telse r=mid-1;\n\t}\n\treturn l;\n}\nint main(){\n\tcin>>n;\n\tfor(int i=1;i<=n;i++) {\n\t\tscanf(\"%d\",&a[i]);b[i]=a[i];\n\t}\n\t\n\tsort(b+1,b+n+1);\n\tcout<<b[erf(1,n)];\n\t\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1540506873, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03275.html", "problem_id": "p03275", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03275/input.txt", "sample_output_relpath": "derived/input_output/data/p03275/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03275/C++/s150970974.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s150970974", "user_id": "u353919145"}, "prompt_components": {"gold_output": "30\n", "input_to_evaluate": "#include <iostream>\n#include <algorithm>\n#include <cstring>\nusing namespace std;\nconst int maxn=1e6+10;\nint a[maxn],b[maxn];\nstruct node{\n\tint val,loc;\n}sub[maxn];\nlong long tre[maxn],n;\nint cmp(const node &a,const node &b){\n\tif(a.val==b.val) return a.loc<b.loc;\n\telse return a.val<b.val;\n}\ninline int lowbit(int x){\n\treturn x&(-x);\n}\nvoid add(int pos,int val){\n\twhile(pos<=n){\n\t\ttre[pos]+=val;\n\t\tpos+=lowbit(pos);\n\t}\n\treturn;\n}\nlong long query(int pos){\n\tlong long sum=0;\n\twhile(pos>0){\n\t\tsum+=tre[pos];\n\t\tpos-=lowbit(pos);\n\t}\n\treturn sum;\n}\nlong long check(int val){\n\tmemset(tre,0,sizeof(tre));\n\tlong long ans=0;\n\tfor(int i=1;i<=n;i++){\n\t\tif(a[i]<val) sub[i].val=-1;\n\t\telse sub[i].val=1;\n\t\tsub[i].val+=sub[i-1].val;\n\t\tsub[i].loc=i;\n\t}\n\tsort(sub+1,sub+n+1,cmp);\n\tfor(int i=1;i<=n;i++){\n\t\tadd(sub[i].loc,1);\n\t\tans+=query(sub[i].loc-1);\n\t\tif(sub[i].val>=0) ans++;\n\t}\n\treturn ans;\n}\nint erf(int l,int r){\n\tint mid;\n\tlong long _std=(n+1)*n/4+1;\n\twhile(l<r){\n\t\tmid=(l+r+1)>>1;\n\t\tif(check(b[mid])>=_std) l=mid;//Çó³ö±Èb[mid]´óÓÚµÈÓÚµÄ \n\t\telse r=mid-1;\n\t}\n\treturn l;\n}\nint main(){\n\tcin>>n;\n\tfor(int i=1;i<=n;i++) {\n\t\tscanf(\"%d\",&a[i]);b[i]=a[i];\n\t}\n\t\n\tsort(b+1,b+n+1);\n\tcout<<b[erf(1,n)];\n\t\n\treturn 0;\n}", "problem_context": "Score : 700 points\n\nProblem Statement\n\nWe will define the median of a sequence b of length M, as follows:\n\nLet b' be the sequence obtained by sorting b in non-decreasing order. Then, the value of the (M / 2 + 1)-th element of b' is the median of b. Here, / is integer division, rounding down.\n\nFor example, the median of (10, 30, 20) is 20; the median of (10, 30, 20, 40) is 30; the median of (10, 10, 10, 20, 30) is 10.\n\nSnuke comes up with the following problem.\n\nYou are given a sequence a of length N.\nFor each pair (l, r) (1 \\leq l \\leq r \\leq N), let m_{l, r} be the median of the contiguous subsequence (a_l, a_{l + 1}, ..., a_r) of a.\nWe will list m_{l, r} for all pairs (l, r) to create a new sequence m.\nFind the median of m.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\na_i is an integer.\n\n1 \\leq a_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_N\n\nOutput\n\nPrint the median of m.\n\nSample Input 1\n\n3\n10 30 20\n\nSample Output 1\n\n30\n\nThe median of each contiguous subsequence of a is as follows:\n\nThe median of (10) is 10.\n\nThe median of (30) is 30.\n\nThe median of (20) is 20.\n\nThe median of (10, 30) is 30.\n\nThe median of (30, 20) is 30.\n\nThe median of (10, 30, 20) is 20.\n\nThus, m = (10, 30, 20, 30, 30, 20) and the median of m is 30.\n\nSample Input 2\n\n1\n10\n\nSample Output 2\n\n10\n\nSample Input 3\n\n10\n5 9 5 9 8 9 3 5 4 3\n\nSample Output 3\n\n8", "sample_input": "3\n10 30 20\n"}, "reference_outputs": ["30\n"], "source_document_id": "p03275", "source_text": "Score : 700 points\n\nProblem Statement\n\nWe will define the median of a sequence b of length M, as follows:\n\nLet b' be the sequence obtained by sorting b in non-decreasing order. Then, the value of the (M / 2 + 1)-th element of b' is the median of b. Here, / is integer division, rounding down.\n\nFor example, the median of (10, 30, 20) is 20; the median of (10, 30, 20, 40) is 30; the median of (10, 10, 10, 20, 30) is 10.\n\nSnuke comes up with the following problem.\n\nYou are given a sequence a of length N.\nFor each pair (l, r) (1 \\leq l \\leq r \\leq N), let m_{l, r} be the median of the contiguous subsequence (a_l, a_{l + 1}, ..., a_r) of a.\nWe will list m_{l, r} for all pairs (l, r) to create a new sequence m.\nFind the median of m.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\na_i is an integer.\n\n1 \\leq a_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_N\n\nOutput\n\nPrint the median of m.\n\nSample Input 1\n\n3\n10 30 20\n\nSample Output 1\n\n30\n\nThe median of each contiguous subsequence of a is as follows:\n\nThe median of (10) is 10.\n\nThe median of (30) is 30.\n\nThe median of (20) is 20.\n\nThe median of (10, 30) is 30.\n\nThe median of (30, 20) is 30.\n\nThe median of (10, 30, 20) is 20.\n\nThus, m = (10, 30, 20, 30, 30, 20) and the median of m is 30.\n\nSample Input 2\n\n1\n10\n\nSample Output 2\n\n10\n\nSample Input 3\n\n10\n5 9 5 9 8 9 3 5 4 3\n\nSample Output 3\n\n8", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1213, "cpu_time_ms": 291, "memory_kb": 14720}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s657981951", "group_id": "codeNet:p03276", "input_text": "#include<iostream>\n#include<cstdio>\n#include<cmath>\nusing namespace std;\nlong long n,k,s[101010],minv=200000020;\nint main()\n{\n\tcin>>n>>k;\n\tfor(int i=1;i<=n;i++)\n\t{\n\t\tcin>>s[i];\n\t}\n\tfor(int i=1;i<=(n-k+1);i++)minv=min(minv,(s[i]*s[i+k-1]>0)?max(abs(s[i]),abs(s[i+k-1])):min(abs(s[i]),abs(s[i+k-1]))*2+max(abs(s[i]),abs(s[i+k-1])));\n\tcout<<minv;\n\treturn 0;\n} ", "language": "C++", "metadata": {"date": 1586720393, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03276.html", "problem_id": "p03276", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03276/input.txt", "sample_output_relpath": "derived/input_output/data/p03276/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03276/C++/s657981951.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s657981951", "user_id": "u018679195"}, "prompt_components": {"gold_output": "40\n", "input_to_evaluate": "#include<iostream>\n#include<cstdio>\n#include<cmath>\nusing namespace std;\nlong long n,k,s[101010],minv=200000020;\nint main()\n{\n\tcin>>n>>k;\n\tfor(int i=1;i<=n;i++)\n\t{\n\t\tcin>>s[i];\n\t}\n\tfor(int i=1;i<=(n-k+1);i++)minv=min(minv,(s[i]*s[i+k-1]>0)?max(abs(s[i]),abs(s[i+k-1])):min(abs(s[i]),abs(s[i+k-1]))*2+max(abs(s[i]),abs(s[i+k-1])));\n\tcout<<minv;\n\treturn 0;\n} ", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N candles placed on a number line.\nThe i-th candle from the left is placed on coordinate x_i.\nHere, x_1 < x_2 < ... < x_N holds.\n\nInitially, no candles are burning.\nSnuke decides to light K of the N candles.\n\nNow, he is at coordinate 0.\nHe can move left and right along the line with speed 1.\nHe can also light a candle when he is at the same position as the candle, in negligible time.\n\nFind the minimum time required to light K candles.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq K \\leq N\n\nx_i is an integer.\n\n|x_i| \\leq 10^8\n\nx_1 < x_2 < ... < x_N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nx_1 x_2 ... x_N\n\nOutput\n\nPrint the minimum time required to light K candles.\n\nSample Input 1\n\n5 3\n-30 -10 10 20 50\n\nSample Output 1\n\n40\n\nHe should move and light candles as follows:\n\nMove from coordinate 0 to -10.\n\nLight the second candle from the left.\n\nMove from coordinate -10 to 10.\n\nLight the third candle from the left.\n\nMove from coordinate 10 to 20.\n\nLight the fourth candle from the left.\n\nSample Input 2\n\n3 2\n10 20 30\n\nSample Output 2\n\n20\n\nSample Input 3\n\n1 1\n0\n\nSample Output 3\n\n0\n\nThere may be a candle placed at coordinate 0.\n\nSample Input 4\n\n8 5\n-9 -7 -4 -3 1 2 3 4\n\nSample Output 4\n\n10", "sample_input": "5 3\n-30 -10 10 20 50\n"}, "reference_outputs": ["40\n"], "source_document_id": "p03276", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N candles placed on a number line.\nThe i-th candle from the left is placed on coordinate x_i.\nHere, x_1 < x_2 < ... < x_N holds.\n\nInitially, no candles are burning.\nSnuke decides to light K of the N candles.\n\nNow, he is at coordinate 0.\nHe can move left and right along the line with speed 1.\nHe can also light a candle when he is at the same position as the candle, in negligible time.\n\nFind the minimum time required to light K candles.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq K \\leq N\n\nx_i is an integer.\n\n|x_i| \\leq 10^8\n\nx_1 < x_2 < ... < x_N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nx_1 x_2 ... x_N\n\nOutput\n\nPrint the minimum time required to light K candles.\n\nSample Input 1\n\n5 3\n-30 -10 10 20 50\n\nSample Output 1\n\n40\n\nHe should move and light candles as follows:\n\nMove from coordinate 0 to -10.\n\nLight the second candle from the left.\n\nMove from coordinate -10 to 10.\n\nLight the third candle from the left.\n\nMove from coordinate 10 to 20.\n\nLight the fourth candle from the left.\n\nSample Input 2\n\n3 2\n10 20 30\n\nSample Output 2\n\n20\n\nSample Input 3\n\n1 1\n0\n\nSample Output 3\n\n0\n\nThere may be a candle placed at coordinate 0.\n\nSample Input 4\n\n8 5\n-9 -7 -4 -3 1 2 3 4\n\nSample Output 4\n\n10", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 357, "cpu_time_ms": 41, "memory_kb": 1024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s599787790", "group_id": "codeNet:p03277", "input_text": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (a); i <= (b); i++)\n#define per(i, a, b) for (int i = (a); i >= (b); i--)\n#define trv(p, u) for (edg *p = h[u]; p; p = p->nxt)\n#define push_back pb\ntypedef long long ll;\ntypedef double db;\nconst int N = 2e5 + 100;\nconst int inf = 0x3f3f3f3f;\nconst int mod = 1e9 + 7;\n\ninline int rd() {\n  int s = 0, w = 1; char c = getchar();\n  while (c < '0' || c > '9') { if (c == '-') w = -1; c = getchar(); }\n  while (c >= '0' && c <= '9') s = s * 10 + c - '0', c = getchar();\n  return s * w;\n}\n\nint n, ans, a[N], s[N];\n\nstruct nod {\n  int lft, rgt, sum;\n  nod *ls, *rs;\n  inline void setc() { sum++; }\n  inline void upd() { sum = ls->sum + rs->sum; }\n} pol[N << 3], *rot, *cur = pol;\n\ninline void build(nod *r, int lft, int rgt) {\n  r->lft = lft, r->rgt = rgt;\n  if (lft == rgt) {\n    r->sum = 0;\n    return ;\n  }\n  int mid = (lft + rgt) >> 1;\n  nod *ls = ++cur, *rs = ++cur;\n  r->ls = ls, r->rs = rs;\n  build(ls, lft, mid), build(rs, mid + 1, rgt);\n  r->upd();\n}\n\ninline void chg(nod *r, int pos) {\n  if (r->lft == pos && r->rgt == pos) {\n    r->setc(); return ;\n  }\n  if (r->ls->rgt >= pos) chg(r->ls, pos);\n  else chg(r->rs, pos);\n  r->upd();\n}\n\ninline int qry(nod *r, int lft, int rgt) {\n  if (lft > rgt) return 0;\n  if (r->lft == lft && r->rgt == rgt) return r->sum;\n  if (r->ls->rgt >= rgt) return qry(r->ls, lft, rgt);\n  else if (r->rs->lft <= lft) return qry(r->rs, lft, rgt);\n  else return qry(r->ls, lft, r->ls->rgt) +\n              qry(r->rs, r->rs->lft, rgt);\n}\n\ninline bool chk(int x) {\n  ll res = 0;\n  memset(s, 0, sizeof(s));\n  cur = pol;\n  rep(i, 1, n) {\n    if (a[i] <= x) s[i] = s[i - 1] + 1;\n    else s[i] = s[i - 1] - 1;\n  }\n  rep(i, 0, n) s[i] += (n + 1);\n  build(rot = pol, 1, N - 100);\n  rep(i, 0, n) {\n    res += 1ll * qry(rot, 1, s[i] - 1);\n    chg(rot, s[i]);\n  }\n  return (res >= 1ll * n * (n + 1) / 4 + 1);\n}\n\nint main() {\n  n = rd();\n  rep(i, 1, n) a[i] = rd();\n  int l = 1, r = inf;\n  while (l <= r) {\n    int mid = (l + r) >> 1;\n    if (chk(mid)) ans = mid, r = mid - 1;\n    else l = mid + 1;\n  }\n  printf(\"%d\\n\", ans);\n  return 0;\n}", "language": "C++", "metadata": {"date": 1566447858, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03277.html", "problem_id": "p03277", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03277/input.txt", "sample_output_relpath": "derived/input_output/data/p03277/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03277/C++/s599787790.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s599787790", "user_id": "u353919145"}, "prompt_components": {"gold_output": "30\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (a); i <= (b); i++)\n#define per(i, a, b) for (int i = (a); i >= (b); i--)\n#define trv(p, u) for (edg *p = h[u]; p; p = p->nxt)\n#define push_back pb\ntypedef long long ll;\ntypedef double db;\nconst int N = 2e5 + 100;\nconst int inf = 0x3f3f3f3f;\nconst int mod = 1e9 + 7;\n\ninline int rd() {\n  int s = 0, w = 1; char c = getchar();\n  while (c < '0' || c > '9') { if (c == '-') w = -1; c = getchar(); }\n  while (c >= '0' && c <= '9') s = s * 10 + c - '0', c = getchar();\n  return s * w;\n}\n\nint n, ans, a[N], s[N];\n\nstruct nod {\n  int lft, rgt, sum;\n  nod *ls, *rs;\n  inline void setc() { sum++; }\n  inline void upd() { sum = ls->sum + rs->sum; }\n} pol[N << 3], *rot, *cur = pol;\n\ninline void build(nod *r, int lft, int rgt) {\n  r->lft = lft, r->rgt = rgt;\n  if (lft == rgt) {\n    r->sum = 0;\n    return ;\n  }\n  int mid = (lft + rgt) >> 1;\n  nod *ls = ++cur, *rs = ++cur;\n  r->ls = ls, r->rs = rs;\n  build(ls, lft, mid), build(rs, mid + 1, rgt);\n  r->upd();\n}\n\ninline void chg(nod *r, int pos) {\n  if (r->lft == pos && r->rgt == pos) {\n    r->setc(); return ;\n  }\n  if (r->ls->rgt >= pos) chg(r->ls, pos);\n  else chg(r->rs, pos);\n  r->upd();\n}\n\ninline int qry(nod *r, int lft, int rgt) {\n  if (lft > rgt) return 0;\n  if (r->lft == lft && r->rgt == rgt) return r->sum;\n  if (r->ls->rgt >= rgt) return qry(r->ls, lft, rgt);\n  else if (r->rs->lft <= lft) return qry(r->rs, lft, rgt);\n  else return qry(r->ls, lft, r->ls->rgt) +\n              qry(r->rs, r->rs->lft, rgt);\n}\n\ninline bool chk(int x) {\n  ll res = 0;\n  memset(s, 0, sizeof(s));\n  cur = pol;\n  rep(i, 1, n) {\n    if (a[i] <= x) s[i] = s[i - 1] + 1;\n    else s[i] = s[i - 1] - 1;\n  }\n  rep(i, 0, n) s[i] += (n + 1);\n  build(rot = pol, 1, N - 100);\n  rep(i, 0, n) {\n    res += 1ll * qry(rot, 1, s[i] - 1);\n    chg(rot, s[i]);\n  }\n  return (res >= 1ll * n * (n + 1) / 4 + 1);\n}\n\nint main() {\n  n = rd();\n  rep(i, 1, n) a[i] = rd();\n  int l = 1, r = inf;\n  while (l <= r) {\n    int mid = (l + r) >> 1;\n    if (chk(mid)) ans = mid, r = mid - 1;\n    else l = mid + 1;\n  }\n  printf(\"%d\\n\", ans);\n  return 0;\n}", "problem_context": "Score : 700 points\n\nProblem Statement\n\nWe will define the median of a sequence b of length M, as follows:\n\nLet b' be the sequence obtained by sorting b in non-decreasing order. Then, the value of the (M / 2 + 1)-th element of b' is the median of b. Here, / is integer division, rounding down.\n\nFor example, the median of (10, 30, 20) is 20; the median of (10, 30, 20, 40) is 30; the median of (10, 10, 10, 20, 30) is 10.\n\nSnuke comes up with the following problem.\n\nYou are given a sequence a of length N.\nFor each pair (l, r) (1 \\leq l \\leq r \\leq N), let m_{l, r} be the median of the contiguous subsequence (a_l, a_{l + 1}, ..., a_r) of a.\nWe will list m_{l, r} for all pairs (l, r) to create a new sequence m.\nFind the median of m.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\na_i is an integer.\n\n1 \\leq a_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_N\n\nOutput\n\nPrint the median of m.\n\nSample Input 1\n\n3\n10 30 20\n\nSample Output 1\n\n30\n\nThe median of each contiguous subsequence of a is as follows:\n\nThe median of (10) is 10.\n\nThe median of (30) is 30.\n\nThe median of (20) is 20.\n\nThe median of (10, 30) is 30.\n\nThe median of (30, 20) is 30.\n\nThe median of (10, 30, 20) is 20.\n\nThus, m = (10, 30, 20, 30, 30, 20) and the median of m is 30.\n\nSample Input 2\n\n1\n10\n\nSample Output 2\n\n10\n\nSample Input 3\n\n10\n5 9 5 9 8 9 3 5 4 3\n\nSample Output 3\n\n8", "sample_input": "3\n10 30 20\n"}, "reference_outputs": ["30\n"], "source_document_id": "p03277", "source_text": "Score : 700 points\n\nProblem Statement\n\nWe will define the median of a sequence b of length M, as follows:\n\nLet b' be the sequence obtained by sorting b in non-decreasing order. Then, the value of the (M / 2 + 1)-th element of b' is the median of b. Here, / is integer division, rounding down.\n\nFor example, the median of (10, 30, 20) is 20; the median of (10, 30, 20, 40) is 30; the median of (10, 10, 10, 20, 30) is 10.\n\nSnuke comes up with the following problem.\n\nYou are given a sequence a of length N.\nFor each pair (l, r) (1 \\leq l \\leq r \\leq N), let m_{l, r} be the median of the contiguous subsequence (a_l, a_{l + 1}, ..., a_r) of a.\nWe will list m_{l, r} for all pairs (l, r) to create a new sequence m.\nFind the median of m.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\na_i is an integer.\n\n1 \\leq a_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_N\n\nOutput\n\nPrint the median of m.\n\nSample Input 1\n\n3\n10 30 20\n\nSample Output 1\n\n30\n\nThe median of each contiguous subsequence of a is as follows:\n\nThe median of (10) is 10.\n\nThe median of (30) is 30.\n\nThe median of (20) is 20.\n\nThe median of (10, 30) is 30.\n\nThe median of (30, 20) is 30.\n\nThe median of (10, 30, 20) is 20.\n\nThus, m = (10, 30, 20, 30, 30, 20) and the median of m is 30.\n\nSample Input 2\n\n1\n10\n\nSample Output 2\n\n10\n\nSample Input 3\n\n10\n5 9 5 9 8 9 3 5 4 3\n\nSample Output 3\n\n8", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2134, "cpu_time_ms": 400, "memory_kb": 16768}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s768691622", "group_id": "codeNet:p03282", "input_text": "//url:\n//problem name:\n\n#include <bits/stdc++.h>\n#define REP(i,n) for (int i = 0; i < (n); ++i)\ntemplate<class T> inline bool chmin(T& a, T b) {if (a > b) {a = b;return true;}return false;}\ntemplate<class T> inline bool chmax(T& a, T b) {if (a < b) {a = b;return true;}return false;}\nusing namespace std;\nusing ll = long long;\nusing P = pair<int,int>;\nusing Pl = pair<long,long>;\nusing veci = vector<int>;\nusing vecl = vector<long>;\nusing vecveci = vector<vector<int>>;\nusing vecvecl = vector<vector<long long>>;\n\nint main() {\n    string S;\n    ll K;\n    cin >> S >> K;\n    if(K == 1) cout << S[0] << endl;\n    else if(S[0] == '1') {\n        int i = 1;\n        while(S[i] == '1') i++;\n        cout << S[i] << endl;\n    }\n    else cout << S[0] << endl;\n}\n\n", "language": "C++", "metadata": {"date": 1590290656, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03282.html", "problem_id": "p03282", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03282/input.txt", "sample_output_relpath": "derived/input_output/data/p03282/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03282/C++/s768691622.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s768691622", "user_id": "u446371873"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "//url:\n//problem name:\n\n#include <bits/stdc++.h>\n#define REP(i,n) for (int i = 0; i < (n); ++i)\ntemplate<class T> inline bool chmin(T& a, T b) {if (a > b) {a = b;return true;}return false;}\ntemplate<class T> inline bool chmax(T& a, T b) {if (a < b) {a = b;return true;}return false;}\nusing namespace std;\nusing ll = long long;\nusing P = pair<int,int>;\nusing Pl = pair<long,long>;\nusing veci = vector<int>;\nusing vecl = vector<long>;\nusing vecveci = vector<vector<int>>;\nusing vecvecl = vector<vector<long long>>;\n\nint main() {\n    string S;\n    ll K;\n    cin >> S >> K;\n    if(K == 1) cout << S[0] << endl;\n    else if(S[0] == '1') {\n        int i = 1;\n        while(S[i] == '1') i++;\n        cout << S[i] << endl;\n    }\n    else cout << S[0] << endl;\n}\n\n", "problem_context": "Score: 300 points\n\nProblem Statement\n\nMr. Infinity has a string S consisting of digits from 1 to 9. Each time the date changes, this string changes as follows:\n\nEach occurrence of 2 in S is replaced with 22. Similarly, each 3 becomes 333, 4 becomes 4444, 5 becomes 55555, 6 becomes 666666, 7 becomes 7777777, 8 becomes 88888888 and 9 becomes 999999999. 1 remains as 1.\n\nFor example, if S is 1324, it becomes 1333224444 the next day, and it becomes 133333333322224444444444444444 the day after next.\nYou are interested in what the string looks like after 5 \\times 10^{15} days. What is the K-th character from the left in the string after 5 \\times 10^{15} days?\n\nConstraints\n\nS is a string of length between 1 and 100 (inclusive).\n\nK is an integer between 1 and 10^{18} (inclusive).\n\nThe length of the string after 5 \\times 10^{15} days is at least K.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\nK\n\nOutput\n\nPrint the K-th character from the left in Mr. Infinity's string after 5 \\times 10^{15} days.\n\nSample Input 1\n\n1214\n4\n\nSample Output 1\n\n2\n\nThe string S changes as follows:\n\nNow: 1214\n\nAfter one day: 12214444\n\nAfter two days: 1222214444444444444444\n\nAfter three days: 12222222214444444444444444444444444444444444444444444444444444444444444444\n\nThe first five characters in the string after 5 \\times 10^{15} days is 12222. As K=4, we should print the fourth character, 2.\n\nSample Input 2\n\n3\n157\n\nSample Output 2\n\n3\n\nThe initial string is 3. The string after 5 \\times 10^{15} days consists only of 3.\n\nSample Input 3\n\n299792458\n9460730472580800\n\nSample Output 3\n\n2", "sample_input": "1214\n4\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03282", "source_text": "Score: 300 points\n\nProblem Statement\n\nMr. Infinity has a string S consisting of digits from 1 to 9. Each time the date changes, this string changes as follows:\n\nEach occurrence of 2 in S is replaced with 22. Similarly, each 3 becomes 333, 4 becomes 4444, 5 becomes 55555, 6 becomes 666666, 7 becomes 7777777, 8 becomes 88888888 and 9 becomes 999999999. 1 remains as 1.\n\nFor example, if S is 1324, it becomes 1333224444 the next day, and it becomes 133333333322224444444444444444 the day after next.\nYou are interested in what the string looks like after 5 \\times 10^{15} days. What is the K-th character from the left in the string after 5 \\times 10^{15} days?\n\nConstraints\n\nS is a string of length between 1 and 100 (inclusive).\n\nK is an integer between 1 and 10^{18} (inclusive).\n\nThe length of the string after 5 \\times 10^{15} days is at least K.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\nK\n\nOutput\n\nPrint the K-th character from the left in Mr. Infinity's string after 5 \\times 10^{15} days.\n\nSample Input 1\n\n1214\n4\n\nSample Output 1\n\n2\n\nThe string S changes as follows:\n\nNow: 1214\n\nAfter one day: 12214444\n\nAfter two days: 1222214444444444444444\n\nAfter three days: 12222222214444444444444444444444444444444444444444444444444444444444444444\n\nThe first five characters in the string after 5 \\times 10^{15} days is 12222. As K=4, we should print the fourth character, 2.\n\nSample Input 2\n\n3\n157\n\nSample Output 2\n\n3\n\nThe initial string is 3. The string after 5 \\times 10^{15} days consists only of 3.\n\nSample Input 3\n\n299792458\n9460730472580800\n\nSample Output 3\n\n2", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 755, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s779337125", "group_id": "codeNet:p03282", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n\tios_base::sync_with_stdio(0);\n\tcin.tie(0);\n\tcout.tie(0);\n\tstring s; long long n;\n\tcin >> s >> n;\n\tlong long temp=0;\n\tfor(int i=0;i<s.length();i++){\n\t\tif(s[i]-'0' > 1){\n\t\t\tif(n < temp){\n\t\t\t\tputs(\"1\");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\telse{\n\t\t\t\tcout << s[i] << \"\\n\";\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t\ttemp++;\n\t}\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1535234028, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03282.html", "problem_id": "p03282", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03282/input.txt", "sample_output_relpath": "derived/input_output/data/p03282/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03282/C++/s779337125.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s779337125", "user_id": "u211227348"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n\tios_base::sync_with_stdio(0);\n\tcin.tie(0);\n\tcout.tie(0);\n\tstring s; long long n;\n\tcin >> s >> n;\n\tlong long temp=0;\n\tfor(int i=0;i<s.length();i++){\n\t\tif(s[i]-'0' > 1){\n\t\t\tif(n < temp){\n\t\t\t\tputs(\"1\");\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\telse{\n\t\t\t\tcout << s[i] << \"\\n\";\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t\ttemp++;\n\t}\n\treturn 0;\n}", "problem_context": "Score: 300 points\n\nProblem Statement\n\nMr. Infinity has a string S consisting of digits from 1 to 9. Each time the date changes, this string changes as follows:\n\nEach occurrence of 2 in S is replaced with 22. Similarly, each 3 becomes 333, 4 becomes 4444, 5 becomes 55555, 6 becomes 666666, 7 becomes 7777777, 8 becomes 88888888 and 9 becomes 999999999. 1 remains as 1.\n\nFor example, if S is 1324, it becomes 1333224444 the next day, and it becomes 133333333322224444444444444444 the day after next.\nYou are interested in what the string looks like after 5 \\times 10^{15} days. What is the K-th character from the left in the string after 5 \\times 10^{15} days?\n\nConstraints\n\nS is a string of length between 1 and 100 (inclusive).\n\nK is an integer between 1 and 10^{18} (inclusive).\n\nThe length of the string after 5 \\times 10^{15} days is at least K.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\nK\n\nOutput\n\nPrint the K-th character from the left in Mr. Infinity's string after 5 \\times 10^{15} days.\n\nSample Input 1\n\n1214\n4\n\nSample Output 1\n\n2\n\nThe string S changes as follows:\n\nNow: 1214\n\nAfter one day: 12214444\n\nAfter two days: 1222214444444444444444\n\nAfter three days: 12222222214444444444444444444444444444444444444444444444444444444444444444\n\nThe first five characters in the string after 5 \\times 10^{15} days is 12222. As K=4, we should print the fourth character, 2.\n\nSample Input 2\n\n3\n157\n\nSample Output 2\n\n3\n\nThe initial string is 3. The string after 5 \\times 10^{15} days consists only of 3.\n\nSample Input 3\n\n299792458\n9460730472580800\n\nSample Output 3\n\n2", "sample_input": "1214\n4\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03282", "source_text": "Score: 300 points\n\nProblem Statement\n\nMr. Infinity has a string S consisting of digits from 1 to 9. Each time the date changes, this string changes as follows:\n\nEach occurrence of 2 in S is replaced with 22. Similarly, each 3 becomes 333, 4 becomes 4444, 5 becomes 55555, 6 becomes 666666, 7 becomes 7777777, 8 becomes 88888888 and 9 becomes 999999999. 1 remains as 1.\n\nFor example, if S is 1324, it becomes 1333224444 the next day, and it becomes 133333333322224444444444444444 the day after next.\nYou are interested in what the string looks like after 5 \\times 10^{15} days. What is the K-th character from the left in the string after 5 \\times 10^{15} days?\n\nConstraints\n\nS is a string of length between 1 and 100 (inclusive).\n\nK is an integer between 1 and 10^{18} (inclusive).\n\nThe length of the string after 5 \\times 10^{15} days is at least K.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\nK\n\nOutput\n\nPrint the K-th character from the left in Mr. Infinity's string after 5 \\times 10^{15} days.\n\nSample Input 1\n\n1214\n4\n\nSample Output 1\n\n2\n\nThe string S changes as follows:\n\nNow: 1214\n\nAfter one day: 12214444\n\nAfter two days: 1222214444444444444444\n\nAfter three days: 12222222214444444444444444444444444444444444444444444444444444444444444444\n\nThe first five characters in the string after 5 \\times 10^{15} days is 12222. As K=4, we should print the fourth character, 2.\n\nSample Input 2\n\n3\n157\n\nSample Output 2\n\n3\n\nThe initial string is 3. The string after 5 \\times 10^{15} days consists only of 3.\n\nSample Input 3\n\n299792458\n9460730472580800\n\nSample Output 3\n\n2", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 361, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s771590235", "group_id": "codeNet:p03283", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef long double ld;\ntypedef pair<int,int> P;\ntypedef pair<ll,ll> l_l;\nconst int INF=1001001000;\nconst int mINF=-1001001000;\nconst ll LINF=10100100100100100;\nint main(){\n    int n,m,Q;cin >> n >> m >> Q;\n    vector<int> L(m),R(m);\n    vector<vector<int>> sum(n+1,vector<int>(n+1,0));\n    for(int i=0;i<m;i++){\n        cin >> L[i] >> R[i];\n        sum[L[i]][R[i]]++;\n    }\n    for(int i=1;i<=n;i++){\n        for(int j=1;j<=n;j++){\n            sum[i][j]+=sum[i][j-1]+sum[i-1][j];\n            sum[i][j]-=sum[i-1][j-1];\n        }\n    }\n    vector<int> ans(Q);\n    for(int i=0;i<Q;i++){\n        int p,q;cin >> p >> q;\n        ans[i]=sum[q][q]-sum[q][p-1]-sum[p-1][q]+sum[p-1][p-1];\n    }\n    for(int i=0;i<Q;i++) cout << ans[i] << endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1582854478, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03283.html", "problem_id": "p03283", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03283/input.txt", "sample_output_relpath": "derived/input_output/data/p03283/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03283/C++/s771590235.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s771590235", "user_id": "u796877631"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef long double ld;\ntypedef pair<int,int> P;\ntypedef pair<ll,ll> l_l;\nconst int INF=1001001000;\nconst int mINF=-1001001000;\nconst ll LINF=10100100100100100;\nint main(){\n    int n,m,Q;cin >> n >> m >> Q;\n    vector<int> L(m),R(m);\n    vector<vector<int>> sum(n+1,vector<int>(n+1,0));\n    for(int i=0;i<m;i++){\n        cin >> L[i] >> R[i];\n        sum[L[i]][R[i]]++;\n    }\n    for(int i=1;i<=n;i++){\n        for(int j=1;j<=n;j++){\n            sum[i][j]+=sum[i][j-1]+sum[i-1][j];\n            sum[i][j]-=sum[i-1][j-1];\n        }\n    }\n    vector<int> ans(Q);\n    for(int i=0;i<Q;i++){\n        int p,q;cin >> p >> q;\n        ans[i]=sum[q][q]-sum[q][p-1]-sum[p-1][q]+sum[p-1][p-1];\n    }\n    for(int i=0;i<Q;i++) cout << ans[i] << endl;\n    return 0;\n}", "problem_context": "Score: 400 points\n\nProblem Statement\n\nIn Takahashi Kingdom, there is a east-west railroad and N cities along it, numbered 1, 2, 3, ..., N from west to east.\nA company called AtCoder Express possesses M trains, and the train i runs from City L_i to City R_i (it is possible that L_i = R_i).\nTakahashi the king is interested in the following Q matters:\n\nThe number of the trains that runs strictly within the section from City p_i to City q_i, that is, the number of trains j such that p_i \\leq L_j and R_j \\leq q_i.\n\nAlthough he is genius, this is too much data to process by himself. Find the answer for each of these Q queries to help him.\n\nConstraints\n\nN is an integer between 1 and 500 (inclusive).\n\nM is an integer between 1 and 200 \\ 000 (inclusive).\n\nQ is an integer between 1 and 100 \\ 000 (inclusive).\n\n1 \\leq L_i \\leq R_i \\leq N (1 \\leq i \\leq M)\n\n1 \\leq p_i \\leq q_i \\leq N (1 \\leq i \\leq Q)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M Q\nL_1 R_1\nL_2 R_2\n:\nL_M R_M\np_1 q_1\np_2 q_2\n:\np_Q q_Q\n\nOutput\n\nPrint Q lines. The i-th line should contain the number of the trains that runs strictly within the section from City p_i to City q_i.\n\nSample Input 1\n\n2 3 1\n1 1\n1 2\n2 2\n1 2\n\nSample Output 1\n\n3\n\nAs all the trains runs within the section from City 1 to City 2, the answer to the only query is 3.\n\nSample Input 2\n\n10 3 2\n1 5\n2 8\n7 10\n1 7\n3 10\n\nSample Output 2\n\n1\n1\n\nThe first query is on the section from City 1 to 7. There is only one train that runs strictly within that section: Train 1.\nThe second query is on the section from City 3 to 10. There is only one train that runs strictly within that section: Train 3.\n\nSample Input 3\n\n10 10 10\n1 6\n2 9\n4 5\n4 7\n4 7\n5 8\n6 6\n6 7\n7 9\n10 10\n1 8\n1 9\n1 10\n2 8\n2 9\n2 10\n3 8\n3 9\n3 10\n1 10\n\nSample Output 3\n\n7\n9\n10\n6\n8\n9\n6\n7\n8\n10", "sample_input": "2 3 1\n1 1\n1 2\n2 2\n1 2\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03283", "source_text": "Score: 400 points\n\nProblem Statement\n\nIn Takahashi Kingdom, there is a east-west railroad and N cities along it, numbered 1, 2, 3, ..., N from west to east.\nA company called AtCoder Express possesses M trains, and the train i runs from City L_i to City R_i (it is possible that L_i = R_i).\nTakahashi the king is interested in the following Q matters:\n\nThe number of the trains that runs strictly within the section from City p_i to City q_i, that is, the number of trains j such that p_i \\leq L_j and R_j \\leq q_i.\n\nAlthough he is genius, this is too much data to process by himself. Find the answer for each of these Q queries to help him.\n\nConstraints\n\nN is an integer between 1 and 500 (inclusive).\n\nM is an integer between 1 and 200 \\ 000 (inclusive).\n\nQ is an integer between 1 and 100 \\ 000 (inclusive).\n\n1 \\leq L_i \\leq R_i \\leq N (1 \\leq i \\leq M)\n\n1 \\leq p_i \\leq q_i \\leq N (1 \\leq i \\leq Q)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M Q\nL_1 R_1\nL_2 R_2\n:\nL_M R_M\np_1 q_1\np_2 q_2\n:\np_Q q_Q\n\nOutput\n\nPrint Q lines. The i-th line should contain the number of the trains that runs strictly within the section from City p_i to City q_i.\n\nSample Input 1\n\n2 3 1\n1 1\n1 2\n2 2\n1 2\n\nSample Output 1\n\n3\n\nAs all the trains runs within the section from City 1 to City 2, the answer to the only query is 3.\n\nSample Input 2\n\n10 3 2\n1 5\n2 8\n7 10\n1 7\n3 10\n\nSample Output 2\n\n1\n1\n\nThe first query is on the section from City 1 to 7. There is only one train that runs strictly within that section: Train 1.\nThe second query is on the section from City 3 to 10. There is only one train that runs strictly within that section: Train 3.\n\nSample Input 3\n\n10 10 10\n1 6\n2 9\n4 5\n4 7\n4 7\n5 8\n6 6\n6 7\n7 9\n10 10\n1 8\n1 9\n1 10\n2 8\n2 9\n2 10\n3 8\n3 9\n3 10\n1 10\n\nSample Output 3\n\n7\n9\n10\n6\n8\n9\n6\n7\n8\n10", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 818, "cpu_time_ms": 292, "memory_kb": 3840}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s396516431", "group_id": "codeNet:p03284", "input_text": "#include <iostream>\n#include <algorithm>\n#include <string>\n#include <cmath>\n#include <vector>\n#include <regex>\n#include <map>\n#include <set>\nusing namespace std;\nint main(){\n    int N,K;\n    cin >> N >> K;\n    cout << N%K << endl;\n    \nreturn 0;\n}\n\n", "language": "C++", "metadata": {"date": 1556943747, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03284.html", "problem_id": "p03284", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03284/input.txt", "sample_output_relpath": "derived/input_output/data/p03284/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03284/C++/s396516431.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s396516431", "user_id": "u451206510"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <iostream>\n#include <algorithm>\n#include <string>\n#include <cmath>\n#include <vector>\n#include <regex>\n#include <map>\n#include <set>\nusing namespace std;\nint main(){\n    int N,K;\n    cin >> N >> K;\n    cout << N%K << endl;\n    \nreturn 0;\n}\n\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nTakahashi has decided to distribute N AtCoder Crackers to K users of as evenly as possible.\nWhen all the crackers are distributed, find the minimum possible (absolute) difference between the largest number of crackers received by a user and the smallest number received by a user.\n\nConstraints\n\n1 \\leq N,K \\leq 100\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the minimum possible (absolute) difference between the largest number of crackers received by a user and the smallest number received by a user.\n\nSample Input 1\n\n7 3\n\nSample Output 1\n\n1\n\nWhen the users receive two, two and three crackers, respectively, the (absolute) difference between the largest number of crackers received by a user and the smallest number received by a user, is 1.\n\nSample Input 2\n\n100 10\n\nSample Output 2\n\n0\n\nThe crackers can be distributed evenly.\n\nSample Input 3\n\n1 1\n\nSample Output 3\n\n0", "sample_input": "7 3\n"}, "reference_outputs": ["1\n"], "source_document_id": "p03284", "source_text": "Score : 100 points\n\nProblem Statement\n\nTakahashi has decided to distribute N AtCoder Crackers to K users of as evenly as possible.\nWhen all the crackers are distributed, find the minimum possible (absolute) difference between the largest number of crackers received by a user and the smallest number received by a user.\n\nConstraints\n\n1 \\leq N,K \\leq 100\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the minimum possible (absolute) difference between the largest number of crackers received by a user and the smallest number received by a user.\n\nSample Input 1\n\n7 3\n\nSample Output 1\n\n1\n\nWhen the users receive two, two and three crackers, respectively, the (absolute) difference between the largest number of crackers received by a user and the smallest number received by a user, is 1.\n\nSample Input 2\n\n100 10\n\nSample Output 2\n\n0\n\nThe crackers can be distributed evenly.\n\nSample Input 3\n\n1 1\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 249, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s425313614", "group_id": "codeNet:p03284", "input_text": "#include <iostream>\n\nusing namespace std;\n\nint main() {\n    int N, K;\n    cin >> N >> K;\n    if(N < K) cout << 1 << \"\\n\";\n    else cout << N%K << \"\\n\";\n}", "language": "C++", "metadata": {"date": 1541414799, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03284.html", "problem_id": "p03284", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03284/input.txt", "sample_output_relpath": "derived/input_output/data/p03284/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03284/C++/s425313614.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s425313614", "user_id": "u021083776"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <iostream>\n\nusing namespace std;\n\nint main() {\n    int N, K;\n    cin >> N >> K;\n    if(N < K) cout << 1 << \"\\n\";\n    else cout << N%K << \"\\n\";\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nTakahashi has decided to distribute N AtCoder Crackers to K users of as evenly as possible.\nWhen all the crackers are distributed, find the minimum possible (absolute) difference between the largest number of crackers received by a user and the smallest number received by a user.\n\nConstraints\n\n1 \\leq N,K \\leq 100\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the minimum possible (absolute) difference between the largest number of crackers received by a user and the smallest number received by a user.\n\nSample Input 1\n\n7 3\n\nSample Output 1\n\n1\n\nWhen the users receive two, two and three crackers, respectively, the (absolute) difference between the largest number of crackers received by a user and the smallest number received by a user, is 1.\n\nSample Input 2\n\n100 10\n\nSample Output 2\n\n0\n\nThe crackers can be distributed evenly.\n\nSample Input 3\n\n1 1\n\nSample Output 3\n\n0", "sample_input": "7 3\n"}, "reference_outputs": ["1\n"], "source_document_id": "p03284", "source_text": "Score : 100 points\n\nProblem Statement\n\nTakahashi has decided to distribute N AtCoder Crackers to K users of as evenly as possible.\nWhen all the crackers are distributed, find the minimum possible (absolute) difference between the largest number of crackers received by a user and the smallest number received by a user.\n\nConstraints\n\n1 \\leq N,K \\leq 100\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the minimum possible (absolute) difference between the largest number of crackers received by a user and the smallest number received by a user.\n\nSample Input 1\n\n7 3\n\nSample Output 1\n\n1\n\nWhen the users receive two, two and three crackers, respectively, the (absolute) difference between the largest number of crackers received by a user and the smallest number received by a user, is 1.\n\nSample Input 2\n\n100 10\n\nSample Output 2\n\n0\n\nThe crackers can be distributed evenly.\n\nSample Input 3\n\n1 1\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 153, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s092270934", "group_id": "codeNet:p03284", "input_text": "#include<cstdio>\n#include<iostream>\nusing namespace std;\nint main(){\n\tint n,k;\n\tcin>>n>>k;\n\tif(n%k==0)\n\tprintf(\"0\");\n\telse\n\tprintf(\"1\");\n}", "language": "C++", "metadata": {"date": 1534036023, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03284.html", "problem_id": "p03284", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03284/input.txt", "sample_output_relpath": "derived/input_output/data/p03284/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03284/C++/s092270934.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s092270934", "user_id": "u935016091"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include<cstdio>\n#include<iostream>\nusing namespace std;\nint main(){\n\tint n,k;\n\tcin>>n>>k;\n\tif(n%k==0)\n\tprintf(\"0\");\n\telse\n\tprintf(\"1\");\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nTakahashi has decided to distribute N AtCoder Crackers to K users of as evenly as possible.\nWhen all the crackers are distributed, find the minimum possible (absolute) difference between the largest number of crackers received by a user and the smallest number received by a user.\n\nConstraints\n\n1 \\leq N,K \\leq 100\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the minimum possible (absolute) difference between the largest number of crackers received by a user and the smallest number received by a user.\n\nSample Input 1\n\n7 3\n\nSample Output 1\n\n1\n\nWhen the users receive two, two and three crackers, respectively, the (absolute) difference between the largest number of crackers received by a user and the smallest number received by a user, is 1.\n\nSample Input 2\n\n100 10\n\nSample Output 2\n\n0\n\nThe crackers can be distributed evenly.\n\nSample Input 3\n\n1 1\n\nSample Output 3\n\n0", "sample_input": "7 3\n"}, "reference_outputs": ["1\n"], "source_document_id": "p03284", "source_text": "Score : 100 points\n\nProblem Statement\n\nTakahashi has decided to distribute N AtCoder Crackers to K users of as evenly as possible.\nWhen all the crackers are distributed, find the minimum possible (absolute) difference between the largest number of crackers received by a user and the smallest number received by a user.\n\nConstraints\n\n1 \\leq N,K \\leq 100\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the minimum possible (absolute) difference between the largest number of crackers received by a user and the smallest number received by a user.\n\nSample Input 1\n\n7 3\n\nSample Output 1\n\n1\n\nWhen the users receive two, two and three crackers, respectively, the (absolute) difference between the largest number of crackers received by a user and the smallest number received by a user, is 1.\n\nSample Input 2\n\n100 10\n\nSample Output 2\n\n0\n\nThe crackers can be distributed evenly.\n\nSample Input 3\n\n1 1\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 138, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s605834576", "group_id": "codeNet:p03285", "input_text": "\n#include <iostream>\n#include <iomanip> //! for setprecision(10)\n#include <math.h>\n#include <algorithm>\n#include <functional> \n#include <string>\n#include <vector>\n\n#include <cstring>\n#include <set>\n#include <map>\n#include <queue>\n#include <utility>\n\nusing namespace std;\n\ntypedef long long LL;\n\n#define dump(c) { for (auto it = c.begin(); it != c.end(); ++it) if (it == c.begin()) cout << *it; else cout << ' ' << *it; cout << endl; } \n#define rep(i,n) for (int i = 0; i < (n); ++i)\n\nconst int MOD = 1000000007;\n\nint main()\n{\n\tcin.tie(0);\n\tios::sync_with_stdio(0);\n\n    int N;\n    cin >> N;\n\n    int ans = 0;\n    for (int i = 0; i*4 <= N; ++i) {\n        if ((N-i*4)%7 == 0) {\n            ++ans;\n        }\n    }\n\n    cout << (ans ? \"Yes\" : \"No\") << endl;\n\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1574681693, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03285.html", "problem_id": "p03285", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03285/input.txt", "sample_output_relpath": "derived/input_output/data/p03285/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03285/C++/s605834576.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s605834576", "user_id": "u851470173"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "\n#include <iostream>\n#include <iomanip> //! for setprecision(10)\n#include <math.h>\n#include <algorithm>\n#include <functional> \n#include <string>\n#include <vector>\n\n#include <cstring>\n#include <set>\n#include <map>\n#include <queue>\n#include <utility>\n\nusing namespace std;\n\ntypedef long long LL;\n\n#define dump(c) { for (auto it = c.begin(); it != c.end(); ++it) if (it == c.begin()) cout << *it; else cout << ' ' << *it; cout << endl; } \n#define rep(i,n) for (int i = 0; i < (n); ++i)\n\nconst int MOD = 1000000007;\n\nint main()\n{\n\tcin.tie(0);\n\tios::sync_with_stdio(0);\n\n    int N;\n    cin >> N;\n\n    int ans = 0;\n    for (int i = 0; i*4 <= N; ++i) {\n        if ((N-i*4)%7 == 0) {\n            ++ans;\n        }\n    }\n\n    cout << (ans ? \"Yes\" : \"No\") << endl;\n\n    return 0;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nLa Confiserie d'ABC sells cakes at 4 dollars each and doughnuts at 7 dollars each.\nDetermine if there is a way to buy some of them for exactly N dollars. You can buy two or more doughnuts and two or more cakes, and you can also choose to buy zero doughnuts or zero cakes.\n\nConstraints\n\nN is an integer between 1 and 100, inclusive.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nIf there is a way to buy some cakes and some doughnuts for exactly N dollars, print Yes; otherwise, print No.\n\nSample Input 1\n\n11\n\nSample Output 1\n\nYes\n\nIf you buy one cake and one doughnut, the total will be 4 + 7 = 11 dollars.\n\nSample Input 2\n\n40\n\nSample Output 2\n\nYes\n\nIf you buy ten cakes, the total will be 4 \\times 10 = 40 dollars.\n\nSample Input 3\n\n3\n\nSample Output 3\n\nNo\n\nThe prices of cakes (4 dollars) and doughnuts (7 dollars) are both higher than 3 dollars, so there is no such way.", "sample_input": "11\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p03285", "source_text": "Score : 200 points\n\nProblem Statement\n\nLa Confiserie d'ABC sells cakes at 4 dollars each and doughnuts at 7 dollars each.\nDetermine if there is a way to buy some of them for exactly N dollars. You can buy two or more doughnuts and two or more cakes, and you can also choose to buy zero doughnuts or zero cakes.\n\nConstraints\n\nN is an integer between 1 and 100, inclusive.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nIf there is a way to buy some cakes and some doughnuts for exactly N dollars, print Yes; otherwise, print No.\n\nSample Input 1\n\n11\n\nSample Output 1\n\nYes\n\nIf you buy one cake and one doughnut, the total will be 4 + 7 = 11 dollars.\n\nSample Input 2\n\n40\n\nSample Output 2\n\nYes\n\nIf you buy ten cakes, the total will be 4 \\times 10 = 40 dollars.\n\nSample Input 3\n\n3\n\nSample Output 3\n\nNo\n\nThe prices of cakes (4 dollars) and doughnuts (7 dollars) are both higher than 3 dollars, so there is no such way.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 771, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s420745734", "group_id": "codeNet:p03285", "input_text": "#include <iostream>\n#include <string>\n#include <algorithm>\nusing namespace std;\n\nint main() {\n\tint x;\n\tcin >> x;\n\n\tint n = 0;\n\tfor (int i = 0; i < 26; i++) {\n\t\tfor (int j = 0; j < 16; j++) {\n\t\t\tif ((4*i + 7*j) == x)n++;\n\t\t}\n\t}\n\t\n\tif (n > 0)cout << \"Yes\";\n\telse cout << \"No\";\n}\n", "language": "C++", "metadata": {"date": 1569545983, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03285.html", "problem_id": "p03285", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03285/input.txt", "sample_output_relpath": "derived/input_output/data/p03285/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03285/C++/s420745734.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s420745734", "user_id": "u103686642"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <iostream>\n#include <string>\n#include <algorithm>\nusing namespace std;\n\nint main() {\n\tint x;\n\tcin >> x;\n\n\tint n = 0;\n\tfor (int i = 0; i < 26; i++) {\n\t\tfor (int j = 0; j < 16; j++) {\n\t\t\tif ((4*i + 7*j) == x)n++;\n\t\t}\n\t}\n\t\n\tif (n > 0)cout << \"Yes\";\n\telse cout << \"No\";\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nLa Confiserie d'ABC sells cakes at 4 dollars each and doughnuts at 7 dollars each.\nDetermine if there is a way to buy some of them for exactly N dollars. You can buy two or more doughnuts and two or more cakes, and you can also choose to buy zero doughnuts or zero cakes.\n\nConstraints\n\nN is an integer between 1 and 100, inclusive.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nIf there is a way to buy some cakes and some doughnuts for exactly N dollars, print Yes; otherwise, print No.\n\nSample Input 1\n\n11\n\nSample Output 1\n\nYes\n\nIf you buy one cake and one doughnut, the total will be 4 + 7 = 11 dollars.\n\nSample Input 2\n\n40\n\nSample Output 2\n\nYes\n\nIf you buy ten cakes, the total will be 4 \\times 10 = 40 dollars.\n\nSample Input 3\n\n3\n\nSample Output 3\n\nNo\n\nThe prices of cakes (4 dollars) and doughnuts (7 dollars) are both higher than 3 dollars, so there is no such way.", "sample_input": "11\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p03285", "source_text": "Score : 200 points\n\nProblem Statement\n\nLa Confiserie d'ABC sells cakes at 4 dollars each and doughnuts at 7 dollars each.\nDetermine if there is a way to buy some of them for exactly N dollars. You can buy two or more doughnuts and two or more cakes, and you can also choose to buy zero doughnuts or zero cakes.\n\nConstraints\n\nN is an integer between 1 and 100, inclusive.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nIf there is a way to buy some cakes and some doughnuts for exactly N dollars, print Yes; otherwise, print No.\n\nSample Input 1\n\n11\n\nSample Output 1\n\nYes\n\nIf you buy one cake and one doughnut, the total will be 4 + 7 = 11 dollars.\n\nSample Input 2\n\n40\n\nSample Output 2\n\nYes\n\nIf you buy ten cakes, the total will be 4 \\times 10 = 40 dollars.\n\nSample Input 3\n\n3\n\nSample Output 3\n\nNo\n\nThe prices of cakes (4 dollars) and doughnuts (7 dollars) are both higher than 3 dollars, so there is no such way.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 277, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s554460579", "group_id": "codeNet:p03286", "input_text": "#include <bits/stdc++.h>\n\n#define F first \n#define S second\n#define PB push_back\n\nusing namespace std;\n\ntypedef long long LL;\ntypedef pair<int, int> PII;\ntypedef priority_queue<int> HEAP;\ntypedef priority_queue<int, vector<int>, greater<int> > RHEAP;\n\nconst int N = 100010, M = 1010;\n\nint n, m = -2;\nstring res;\n\nint main()\n{\n\tcin >> n;\n\tif (!n) puts(\"0\");\n\telse\n\t{\n\t\tfor (int i = n; i; i /= m)\n\t\t{\n\t\t\tif (i % abs(m))\n\t\t\t{\n\t\t\t\tres += \"1\";\n\t\t\t\tif (m < 0) i -- ;\n\t\t\t}\n\t\t\telse res += \"0\";\n\t\t}\n\t\treverse(res.begin(), res.end());\n\t}\n\tcout << res << endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1594828501, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03286.html", "problem_id": "p03286", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03286/input.txt", "sample_output_relpath": "derived/input_output/data/p03286/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03286/C++/s554460579.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s554460579", "user_id": "u866538547"}, "prompt_components": {"gold_output": "1011\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\n#define F first \n#define S second\n#define PB push_back\n\nusing namespace std;\n\ntypedef long long LL;\ntypedef pair<int, int> PII;\ntypedef priority_queue<int> HEAP;\ntypedef priority_queue<int, vector<int>, greater<int> > RHEAP;\n\nconst int N = 100010, M = 1010;\n\nint n, m = -2;\nstring res;\n\nint main()\n{\n\tcin >> n;\n\tif (!n) puts(\"0\");\n\telse\n\t{\n\t\tfor (int i = n; i; i /= m)\n\t\t{\n\t\t\tif (i % abs(m))\n\t\t\t{\n\t\t\t\tres += \"1\";\n\t\t\t\tif (m < 0) i -- ;\n\t\t\t}\n\t\t\telse res += \"0\";\n\t\t}\n\t\treverse(res.begin(), res.end());\n\t}\n\tcout << res << endl;\n    return 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nGiven an integer N, find the base -2 representation of N.\n\nHere, S is the base -2 representation of N when the following are all satisfied:\n\nS is a string consisting of 0 and 1.\n\nUnless S = 0, the initial character of S is 1.\n\nLet S = S_k S_{k-1} ... S_0, then S_0 \\times (-2)^0 + S_1 \\times (-2)^1 + ... + S_k \\times (-2)^k = N.\n\nIt can be proved that, for any integer M, the base -2 representation of M is uniquely determined.\n\nConstraints\n\nEvery value in input is integer.\n\n-10^9 \\leq N \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the base -2 representation of N.\n\nSample Input 1\n\n-9\n\nSample Output 1\n\n1011\n\nAs (-2)^0 + (-2)^1 + (-2)^3 = 1 + (-2) + (-8) = -9, 1011 is the base -2 representation of -9.\n\nSample Input 2\n\n123456789\n\nSample Output 2\n\n11000101011001101110100010101\n\nSample Input 3\n\n0\n\nSample Output 3\n\n0", "sample_input": "-9\n"}, "reference_outputs": ["1011\n"], "source_document_id": "p03286", "source_text": "Score : 300 points\n\nProblem Statement\n\nGiven an integer N, find the base -2 representation of N.\n\nHere, S is the base -2 representation of N when the following are all satisfied:\n\nS is a string consisting of 0 and 1.\n\nUnless S = 0, the initial character of S is 1.\n\nLet S = S_k S_{k-1} ... S_0, then S_0 \\times (-2)^0 + S_1 \\times (-2)^1 + ... + S_k \\times (-2)^k = N.\n\nIt can be proved that, for any integer M, the base -2 representation of M is uniquely determined.\n\nConstraints\n\nEvery value in input is integer.\n\n-10^9 \\leq N \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the base -2 representation of N.\n\nSample Input 1\n\n-9\n\nSample Output 1\n\n1011\n\nAs (-2)^0 + (-2)^1 + (-2)^3 = 1 + (-2) + (-8) = -9, 1011 is the base -2 representation of -9.\n\nSample Input 2\n\n123456789\n\nSample Output 2\n\n11000101011001101110100010101\n\nSample Input 3\n\n0\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 565, "cpu_time_ms": 6, "memory_kb": 3608}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s916588996", "group_id": "codeNet:p03286", "input_text": "#include <iostream>\n#include <algorithm>\n#include <cmath>\n#include <vector>\ntypedef long long ll;\nusing namespace std;\n\nint main() {\n    ll n; cin >> n;\n    string s;\n    while (n) {\n        if (n == 0) {\n            cout << 0 << endl;\n        }\n        if (n % 2 == 0){\n            s = \"0\" + s;\n            n /= -2;\n        } else {\n            n -= 1;\n            s = \"1\" + s;\n            n /= -2;\n        }\n    }\n    cout << s << endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1534042056, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03286.html", "problem_id": "p03286", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03286/input.txt", "sample_output_relpath": "derived/input_output/data/p03286/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03286/C++/s916588996.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s916588996", "user_id": "u073731976"}, "prompt_components": {"gold_output": "1011\n", "input_to_evaluate": "#include <iostream>\n#include <algorithm>\n#include <cmath>\n#include <vector>\ntypedef long long ll;\nusing namespace std;\n\nint main() {\n    ll n; cin >> n;\n    string s;\n    while (n) {\n        if (n == 0) {\n            cout << 0 << endl;\n        }\n        if (n % 2 == 0){\n            s = \"0\" + s;\n            n /= -2;\n        } else {\n            n -= 1;\n            s = \"1\" + s;\n            n /= -2;\n        }\n    }\n    cout << s << endl;\n    return 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nGiven an integer N, find the base -2 representation of N.\n\nHere, S is the base -2 representation of N when the following are all satisfied:\n\nS is a string consisting of 0 and 1.\n\nUnless S = 0, the initial character of S is 1.\n\nLet S = S_k S_{k-1} ... S_0, then S_0 \\times (-2)^0 + S_1 \\times (-2)^1 + ... + S_k \\times (-2)^k = N.\n\nIt can be proved that, for any integer M, the base -2 representation of M is uniquely determined.\n\nConstraints\n\nEvery value in input is integer.\n\n-10^9 \\leq N \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the base -2 representation of N.\n\nSample Input 1\n\n-9\n\nSample Output 1\n\n1011\n\nAs (-2)^0 + (-2)^1 + (-2)^3 = 1 + (-2) + (-8) = -9, 1011 is the base -2 representation of -9.\n\nSample Input 2\n\n123456789\n\nSample Output 2\n\n11000101011001101110100010101\n\nSample Input 3\n\n0\n\nSample Output 3\n\n0", "sample_input": "-9\n"}, "reference_outputs": ["1011\n"], "source_document_id": "p03286", "source_text": "Score : 300 points\n\nProblem Statement\n\nGiven an integer N, find the base -2 representation of N.\n\nHere, S is the base -2 representation of N when the following are all satisfied:\n\nS is a string consisting of 0 and 1.\n\nUnless S = 0, the initial character of S is 1.\n\nLet S = S_k S_{k-1} ... S_0, then S_0 \\times (-2)^0 + S_1 \\times (-2)^1 + ... + S_k \\times (-2)^k = N.\n\nIt can be proved that, for any integer M, the base -2 representation of M is uniquely determined.\n\nConstraints\n\nEvery value in input is integer.\n\n-10^9 \\leq N \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the base -2 representation of N.\n\nSample Input 1\n\n-9\n\nSample Output 1\n\n1011\n\nAs (-2)^0 + (-2)^1 + (-2)^3 = 1 + (-2) + (-8) = -9, 1011 is the base -2 representation of -9.\n\nSample Input 2\n\n123456789\n\nSample Output 2\n\n11000101011001101110100010101\n\nSample Input 3\n\n0\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 454, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s100142647", "group_id": "codeNet:p03286", "input_text": "#include<iostream>\nusing namespace std;\n\nint main(){\nint N;\nint A[1000];\ndouble all=0;\ndouble ten=1;\nint x;\nint i=0;\nint total;\n\ncin >> N;\nwhile(1){\n  if(N == 0){\n    break;\n  }\n\nx = N%(-2);\nif(x==(-1))x=1;\nA[i] = x;\ni++;\nN -= x;\nN = N/(-2);\n}\n\ntotal = i-1;\nfor(int k = total; k>=0; k--)\ncout << A[k] ;\n\ncout << endl;\n\n}", "language": "C++", "metadata": {"date": 1534039216, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03286.html", "problem_id": "p03286", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03286/input.txt", "sample_output_relpath": "derived/input_output/data/p03286/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03286/C++/s100142647.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s100142647", "user_id": "u571764501"}, "prompt_components": {"gold_output": "1011\n", "input_to_evaluate": "#include<iostream>\nusing namespace std;\n\nint main(){\nint N;\nint A[1000];\ndouble all=0;\ndouble ten=1;\nint x;\nint i=0;\nint total;\n\ncin >> N;\nwhile(1){\n  if(N == 0){\n    break;\n  }\n\nx = N%(-2);\nif(x==(-1))x=1;\nA[i] = x;\ni++;\nN -= x;\nN = N/(-2);\n}\n\ntotal = i-1;\nfor(int k = total; k>=0; k--)\ncout << A[k] ;\n\ncout << endl;\n\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nGiven an integer N, find the base -2 representation of N.\n\nHere, S is the base -2 representation of N when the following are all satisfied:\n\nS is a string consisting of 0 and 1.\n\nUnless S = 0, the initial character of S is 1.\n\nLet S = S_k S_{k-1} ... S_0, then S_0 \\times (-2)^0 + S_1 \\times (-2)^1 + ... + S_k \\times (-2)^k = N.\n\nIt can be proved that, for any integer M, the base -2 representation of M is uniquely determined.\n\nConstraints\n\nEvery value in input is integer.\n\n-10^9 \\leq N \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the base -2 representation of N.\n\nSample Input 1\n\n-9\n\nSample Output 1\n\n1011\n\nAs (-2)^0 + (-2)^1 + (-2)^3 = 1 + (-2) + (-8) = -9, 1011 is the base -2 representation of -9.\n\nSample Input 2\n\n123456789\n\nSample Output 2\n\n11000101011001101110100010101\n\nSample Input 3\n\n0\n\nSample Output 3\n\n0", "sample_input": "-9\n"}, "reference_outputs": ["1011\n"], "source_document_id": "p03286", "source_text": "Score : 300 points\n\nProblem Statement\n\nGiven an integer N, find the base -2 representation of N.\n\nHere, S is the base -2 representation of N when the following are all satisfied:\n\nS is a string consisting of 0 and 1.\n\nUnless S = 0, the initial character of S is 1.\n\nLet S = S_k S_{k-1} ... S_0, then S_0 \\times (-2)^0 + S_1 \\times (-2)^1 + ... + S_k \\times (-2)^k = N.\n\nIt can be proved that, for any integer M, the base -2 representation of M is uniquely determined.\n\nConstraints\n\nEvery value in input is integer.\n\n-10^9 \\leq N \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the base -2 representation of N.\n\nSample Input 1\n\n-9\n\nSample Output 1\n\n1011\n\nAs (-2)^0 + (-2)^1 + (-2)^3 = 1 + (-2) + (-8) = -9, 1011 is the base -2 representation of -9.\n\nSample Input 2\n\n123456789\n\nSample Output 2\n\n11000101011001101110100010101\n\nSample Input 3\n\n0\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 320, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s793072633", "group_id": "codeNet:p03287", "input_text": "/*\n                  友利奈緒ぱわーでACしてくれ！！！！！！！！！！！！\n                  Charlotteまだ見てない人は見ような！！！！！！！\n\n                  ／　 /:／　　　　　　　　　　　 　 ＼:ヽ　＼\n  　　　　　　　 /　　／　　　　　　 　 　 　 　 　 　 　 ＼　　ヽ\n  　　　　　＼__L 彡　　　　　　　　　　　　　　　　　　　 ヽ　　',\n  　　　　　　　ﾌ /　　　/　　/　 /　　　,　　 　 　 　 ヽ　　', 　ｊ\n  　　　　　　　ﾚ　　　 /　　/ 　/　 　 　 　 　 　 　 　 ', 　ヽ　j\n  　　　 　 　 // 　 　 !　/_l＿/__ノ 　　{ ＼}　　　　 　 ',　　',/\n  　　　　　　i ﾊ 　 　 {　从j　ﾊ　i　　　 ',　 ト-､}　 i i　 }　　jj\n  　　　　　　( ﾊ　　　(　 川　ハ ﾊ　 !　 '　ﾊ　 ﾊ　j j　,' 　 八\n  　　　 ＜＿,ｨ∧　　　斗芹ﾃミxハ ﾊ　 ﾚ　} /__ﾚﾚ　/ 　 ∧ ＼　ﾉ\n  　　　 　 　 ∨　＼ 　ゝ　辷:ソ　　 　)　芹ﾚ心ヾレ′　/ ト--　´\n  　　　＼ｰ‐'　ﾉ　　 ＼ゝ　　　　　　 　 　 ゞ:_ソ \"/ 　／ 　ヽ\n  　　　　 　 フ　　　　i八 \" \"　　　,　　　　　　　ム彡　　　　＼\n  　　　　 　/　　/　　j　 ト　　　　　　 　 　 \" \"イト＜　 　 　 ＼＼\n  　　　　 /　　/　　　j　/／ヽ､ 　 ∩　　 　 イ　{ {　　￣ フフへ ＼＼\n  　　　　(　／　　　 ,/ / 　　i　＞――＜ニニニﾆ┐　 〃／: : ヽ　ヽヽ\n  　　　　／　　ィT´/ /┌―　￣￣ /::: , ,)　 　 　 〃／／: : : : : :}　ヽヽ)\n  　　　/ /　 ∧ヾi┌― { {￣　　　 ﾉ:::トﾟ<　 　 　 ∥//: : : : : : : : i　 ﾉ ﾉ\n  . 　　( 人　 {:ヽヾi∨　∧V　　　 /:::/　､ヽ　　　 ∥/: : : : : : : : : :}　/\n  　　　V　( ∧: :＼'∨　∧V　　 ﾉ:::/　 ∧ 〉＿__∥: : : : : :／: : : :ﾚ\n  　　 　 　 /∧: : : : ∨　∧V┬ｲ:::ﾉ　 〈 TT　|　|{{: : : : ／: : : : : ∧　　 ﾉ\n  　　　 　 (　ハ: : : : :∨'T∧Vi　i (　 　 V　!　!　{{: : ／ : : : : : : /　ｰ　ノ\n  　　　　　V　ハ: : : : :∨ﾍ∧V　i ゝゝ　 i／⌒＼{／ : : : : : : : /ｰ― ´\n  　　　　　 ∨　ヽ: : : : :∨ﾍ∧∨i　〉 〉 /　/二　 ): : : : : : : : :/\n\n          (https://seesaawiki.jp/asciiart/d/Charlotte より)\n*/\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long; using ull = unsigned long long;\n// #define int ll\n// #define DEBUG 42\ninline void nprint(){}\ntemplate <class Head, class... Tail>\ninline void nprint(Head &&head, Tail &&... tail) {\n    cout << head << endl;\n    nprint(move(tail)...);\n}\n#ifdef DEBUG\n  #define eprint(...) nprint(__VA_ARGS__)\n#else\n  #define eprint(...) if(0==1) cout << 1 << endl;\n#endif\n#define Yes(a) cout << (a ? \"Yes\" : \"No\") << endl\n#define YES(a) cout << (a ? \"YES\" : \"NO\") << endl\n#define POSSIBLE(a) cout << (a ? \"POSSIBLE\" : \"IMPOSSIBLE\") << endl\nusing cmp = complex<double>;\nusing vb = vector<bool>; using vvb = vector<vb>;\nusing vi = vector<int>; using vvi = vector<vi>;\nusing vl = vector<ll>; using vvl = vector<vl>;\ntemplate<class T> using V = vector<T>;\ntemplate<class T> using VV = vector<V<T>>;\n#define fi first\n#define se second\n#define maxs(x,y) (x=max(x,y))\n#define mins(x,y) (x=min(x,y))\nusing pii = pair<int,int>; using pll = pair<ll,ll>;\n#define FOR(i,a,b) for(ll i = (a); i < (ll)(b); ++i)\n#define REP(i,n) FOR(i,0,n)\n#define FORS(i,a,b) FOR(i,a,b+1)\n#define REPS(i,n) REP(i,n+1)\n#define RFOR(i,a,b) for(ll i = (ll)(b)-1;i >= a;--i)\n#define RREP(i,n) RFOR(i,0,n)\n#define RREPS(i,n) RREP(i,n+1)\n#define RFORS(i,a,b) RFOR(i,a,b+1)\n#define ALL(obj) (obj).begin(), (obj).end()\n#define RALL(obj) (obj).rbegin(), (obj).rend()\n#define PERM(c) sort(ALL(c)); for(bool cp = true;cp;cp = next_permutation(ALL(c)))\n#define eb(val) emplace_back(val)\nconst double PI = acos(-1), EPS = 1e-10;\nconstexpr ll MOD = 1E9+7;\nconstexpr int dx[] = {1,0,-1,0}; constexpr int dy[] = {0,1,0,-1};\ntemplate<typename T1, typename T2> ostream& operator<<(ostream& s, const pair<T1, T2>& p){\n  return s << \"(\" << p.first << \", \" << p.second << \")\";\n}\ntemplate<class T> istream& operator>>(istream &is,vector<T> &st){\n  for(size_t i=0;i<st.size();++i) is >> st[i];\n  return is;\n}\ntemplate<class T> istream& operator>>(istream &is,vector<vector<T>> &st){\n  for(size_t i=0;i<st.size();++i) is >> st[i];\n  return is;\n}\ntemplate<class T> ostream& operator<<(ostream &os, const vector<T> &st){\n  for(size_t i=0;i<st.size();++i){\n    if(i==st.size()-1) os << st[i];\n    else os << st[i] << \" \";\n  }\n  return os;\n}\ntemplate<class T> ostream& operator<<(ostream &os, const vector<vector<T>> &st){\n  for(size_t i=0;i<st.size();++i){\n    os << st[i];\n    if(i!=st.size()-1) os << endl;\n  }\n  return os;\n}\nsigned main(){\n  cin.tie(0);\n  ios::sync_with_stdio(false);\n  cout << fixed << setprecision(10);\n  int n,m;\n  cin >> n >> m;\n  vi a(n);\n  ll sum[n+1];\n  cin >> a;\n  sum[0] = 0;\n  REP(i,n){\n    sum[i+1] = sum[i] + a[i];\n  }\n  ll ans = 0;\n  int i=0,j=0;\n  ++n;\n  for(i=0;i<n;++i)for(j=i+1;j<n;++j)if(!((sum[j]-sum[i])%m)) ++ans;\n  cout << ans << endl;\n}\n", "language": "C++", "metadata": {"date": 1571279356, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03287.html", "problem_id": "p03287", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03287/input.txt", "sample_output_relpath": "derived/input_output/data/p03287/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03287/C++/s793072633.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s793072633", "user_id": "u949798495"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "/*\n                  友利奈緒ぱわーでACしてくれ！！！！！！！！！！！！\n                  Charlotteまだ見てない人は見ような！！！！！！！\n\n                  ／　 /:／　　　　　　　　　　　 　 ＼:ヽ　＼\n  　　　　　　　 /　　／　　　　　　 　 　 　 　 　 　 　 ＼　　ヽ\n  　　　　　＼__L 彡　　　　　　　　　　　　　　　　　　　 ヽ　　',\n  　　　　　　　ﾌ /　　　/　　/　 /　　　,　　 　 　 　 ヽ　　', 　ｊ\n  　　　　　　　ﾚ　　　 /　　/ 　/　 　 　 　 　 　 　 　 ', 　ヽ　j\n  　　　 　 　 // 　 　 !　/_l＿/__ノ 　　{ ＼}　　　　 　 ',　　',/\n  　　　　　　i ﾊ 　 　 {　从j　ﾊ　i　　　 ',　 ト-､}　 i i　 }　　jj\n  　　　　　　( ﾊ　　　(　 川　ハ ﾊ　 !　 '　ﾊ　 ﾊ　j j　,' 　 八\n  　　　 ＜＿,ｨ∧　　　斗芹ﾃミxハ ﾊ　 ﾚ　} /__ﾚﾚ　/ 　 ∧ ＼　ﾉ\n  　　　 　 　 ∨　＼ 　ゝ　辷:ソ　　 　)　芹ﾚ心ヾレ′　/ ト--　´\n  　　　＼ｰ‐'　ﾉ　　 ＼ゝ　　　　　　 　 　 ゞ:_ソ \"/ 　／ 　ヽ\n  　　　　 　 フ　　　　i八 \" \"　　　,　　　　　　　ム彡　　　　＼\n  　　　　 　/　　/　　j　 ト　　　　　　 　 　 \" \"イト＜　 　 　 ＼＼\n  　　　　 /　　/　　　j　/／ヽ､ 　 ∩　　 　 イ　{ {　　￣ フフへ ＼＼\n  　　　　(　／　　　 ,/ / 　　i　＞――＜ニニニﾆ┐　 〃／: : ヽ　ヽヽ\n  　　　　／　　ィT´/ /┌―　￣￣ /::: , ,)　 　 　 〃／／: : : : : :}　ヽヽ)\n  　　　/ /　 ∧ヾi┌― { {￣　　　 ﾉ:::トﾟ<　 　 　 ∥//: : : : : : : : i　 ﾉ ﾉ\n  . 　　( 人　 {:ヽヾi∨　∧V　　　 /:::/　､ヽ　　　 ∥/: : : : : : : : : :}　/\n  　　　V　( ∧: :＼'∨　∧V　　 ﾉ:::/　 ∧ 〉＿__∥: : : : : :／: : : :ﾚ\n  　　 　 　 /∧: : : : ∨　∧V┬ｲ:::ﾉ　 〈 TT　|　|{{: : : : ／: : : : : ∧　　 ﾉ\n  　　　 　 (　ハ: : : : :∨'T∧Vi　i (　 　 V　!　!　{{: : ／ : : : : : : /　ｰ　ノ\n  　　　　　V　ハ: : : : :∨ﾍ∧V　i ゝゝ　 i／⌒＼{／ : : : : : : : /ｰ― ´\n  　　　　　 ∨　ヽ: : : : :∨ﾍ∧∨i　〉 〉 /　/二　 ): : : : : : : : :/\n\n          (https://seesaawiki.jp/asciiart/d/Charlotte より)\n*/\n#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long; using ull = unsigned long long;\n// #define int ll\n// #define DEBUG 42\ninline void nprint(){}\ntemplate <class Head, class... Tail>\ninline void nprint(Head &&head, Tail &&... tail) {\n    cout << head << endl;\n    nprint(move(tail)...);\n}\n#ifdef DEBUG\n  #define eprint(...) nprint(__VA_ARGS__)\n#else\n  #define eprint(...) if(0==1) cout << 1 << endl;\n#endif\n#define Yes(a) cout << (a ? \"Yes\" : \"No\") << endl\n#define YES(a) cout << (a ? \"YES\" : \"NO\") << endl\n#define POSSIBLE(a) cout << (a ? \"POSSIBLE\" : \"IMPOSSIBLE\") << endl\nusing cmp = complex<double>;\nusing vb = vector<bool>; using vvb = vector<vb>;\nusing vi = vector<int>; using vvi = vector<vi>;\nusing vl = vector<ll>; using vvl = vector<vl>;\ntemplate<class T> using V = vector<T>;\ntemplate<class T> using VV = vector<V<T>>;\n#define fi first\n#define se second\n#define maxs(x,y) (x=max(x,y))\n#define mins(x,y) (x=min(x,y))\nusing pii = pair<int,int>; using pll = pair<ll,ll>;\n#define FOR(i,a,b) for(ll i = (a); i < (ll)(b); ++i)\n#define REP(i,n) FOR(i,0,n)\n#define FORS(i,a,b) FOR(i,a,b+1)\n#define REPS(i,n) REP(i,n+1)\n#define RFOR(i,a,b) for(ll i = (ll)(b)-1;i >= a;--i)\n#define RREP(i,n) RFOR(i,0,n)\n#define RREPS(i,n) RREP(i,n+1)\n#define RFORS(i,a,b) RFOR(i,a,b+1)\n#define ALL(obj) (obj).begin(), (obj).end()\n#define RALL(obj) (obj).rbegin(), (obj).rend()\n#define PERM(c) sort(ALL(c)); for(bool cp = true;cp;cp = next_permutation(ALL(c)))\n#define eb(val) emplace_back(val)\nconst double PI = acos(-1), EPS = 1e-10;\nconstexpr ll MOD = 1E9+7;\nconstexpr int dx[] = {1,0,-1,0}; constexpr int dy[] = {0,1,0,-1};\ntemplate<typename T1, typename T2> ostream& operator<<(ostream& s, const pair<T1, T2>& p){\n  return s << \"(\" << p.first << \", \" << p.second << \")\";\n}\ntemplate<class T> istream& operator>>(istream &is,vector<T> &st){\n  for(size_t i=0;i<st.size();++i) is >> st[i];\n  return is;\n}\ntemplate<class T> istream& operator>>(istream &is,vector<vector<T>> &st){\n  for(size_t i=0;i<st.size();++i) is >> st[i];\n  return is;\n}\ntemplate<class T> ostream& operator<<(ostream &os, const vector<T> &st){\n  for(size_t i=0;i<st.size();++i){\n    if(i==st.size()-1) os << st[i];\n    else os << st[i] << \" \";\n  }\n  return os;\n}\ntemplate<class T> ostream& operator<<(ostream &os, const vector<vector<T>> &st){\n  for(size_t i=0;i<st.size();++i){\n    os << st[i];\n    if(i!=st.size()-1) os << endl;\n  }\n  return os;\n}\nsigned main(){\n  cin.tie(0);\n  ios::sync_with_stdio(false);\n  cout << fixed << setprecision(10);\n  int n,m;\n  cin >> n >> m;\n  vi a(n);\n  ll sum[n+1];\n  cin >> a;\n  sum[0] = 0;\n  REP(i,n){\n    sum[i+1] = sum[i] + a[i];\n  }\n  ll ans = 0;\n  int i=0,j=0;\n  ++n;\n  for(i=0;i<n;++i)for(j=i+1;j<n;++j)if(!((sum[j]-sum[i])%m)) ++ans;\n  cout << ans << endl;\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nThere are N boxes arranged in a row from left to right. The i-th box from the left contains A_i candies.\n\nYou will take out the candies from some consecutive boxes and distribute them evenly to M children.\n\nSuch being the case, find the number of the pairs (l, r) that satisfy the following:\n\nl and r are both integers and satisfy 1 \\leq l \\leq r \\leq N.\n\nA_l + A_{l+1} + ... + A_r is a multiple of M.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n2 \\leq M \\leq 10^9\n\n1 \\leq A_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the number of the pairs (l, r) that satisfy the conditions.\n\nNote that the number may not fit into a 32-bit integer type.\n\nSample Input 1\n\n3 2\n4 1 5\n\nSample Output 1\n\n3\n\nThe sum A_l + A_{l+1} + ... + A_r for each pair (l, r) is as follows:\n\nSum for (1, 1): 4\n\nSum for (1, 2): 5\n\nSum for (1, 3): 10\n\nSum for (2, 2): 1\n\nSum for (2, 3): 6\n\nSum for (3, 3): 5\n\nAmong these, three are multiples of 2.\n\nSample Input 2\n\n13 17\n29 7 5 7 9 51 7 13 8 55 42 9 81\n\nSample Output 2\n\n6\n\nSample Input 3\n\n10 400000000\n1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000\n\nSample Output 3\n\n25", "sample_input": "3 2\n4 1 5\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03287", "source_text": "Score : 400 points\n\nProblem Statement\n\nThere are N boxes arranged in a row from left to right. The i-th box from the left contains A_i candies.\n\nYou will take out the candies from some consecutive boxes and distribute them evenly to M children.\n\nSuch being the case, find the number of the pairs (l, r) that satisfy the following:\n\nl and r are both integers and satisfy 1 \\leq l \\leq r \\leq N.\n\nA_l + A_{l+1} + ... + A_r is a multiple of M.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq N \\leq 10^5\n\n2 \\leq M \\leq 10^9\n\n1 \\leq A_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the number of the pairs (l, r) that satisfy the conditions.\n\nNote that the number may not fit into a 32-bit integer type.\n\nSample Input 1\n\n3 2\n4 1 5\n\nSample Output 1\n\n3\n\nThe sum A_l + A_{l+1} + ... + A_r for each pair (l, r) is as follows:\n\nSum for (1, 1): 4\n\nSum for (1, 2): 5\n\nSum for (1, 3): 10\n\nSum for (2, 2): 1\n\nSum for (2, 3): 6\n\nSum for (3, 3): 5\n\nAmong these, three are multiples of 2.\n\nSample Input 2\n\n13 17\n29 7 5 7 9 51 7 13 8 55 42 9 81\n\nSample Output 2\n\n6\n\nSample Input 3\n\n10 400000000\n1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000 1000000000\n\nSample Output 3\n\n25", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 5250, "cpu_time_ms": 2103, "memory_kb": 1408}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s011044796", "group_id": "codeNet:p03288", "input_text": "#include<stdio.h>\nint main(void){\n  int R;\n  scanf(\"%d\",&R);\n  if(R<1200){\n    printf(\"ABC\");\n  }\n  else if(1200<=R&&R<2800){\n    printf(\"ARC\");\n  }\n  else{\n\tprintf(\"AGC\");\n  }\n  return 0;\n}", "language": "C++", "metadata": {"date": 1543199401, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03288.html", "problem_id": "p03288", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03288/input.txt", "sample_output_relpath": "derived/input_output/data/p03288/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03288/C++/s011044796.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s011044796", "user_id": "u521382680"}, "prompt_components": {"gold_output": "ABC\n", "input_to_evaluate": "#include<stdio.h>\nint main(void){\n  int R;\n  scanf(\"%d\",&R);\n  if(R<1200){\n    printf(\"ABC\");\n  }\n  else if(1200<=R&&R<2800){\n    printf(\"ARC\");\n  }\n  else{\n\tprintf(\"AGC\");\n  }\n  return 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nA programming competition site AtCode regularly holds programming contests.\n\nThe next contest on AtCode is called ABC, which is rated for contestants with ratings less than 1200.\n\nThe contest after the ABC is called ARC, which is rated for contestants with ratings less than 2800.\n\nThe contest after the ARC is called AGC, which is rated for all contestants.\n\nTakahashi's rating on AtCode is R. What is the next contest rated for him?\n\nConstraints\n\n0 ≤ R ≤ 4208\n\nR is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nR\n\nOutput\n\nPrint the name of the next contest rated for Takahashi (ABC, ARC or AGC).\n\nSample Input 1\n\n1199\n\nSample Output 1\n\nABC\n\n1199 is less than 1200, so ABC will be rated.\n\nSample Input 2\n\n1200\n\nSample Output 2\n\nARC\n\n1200 is not less than 1200 and ABC will be unrated, but it is less than 2800 and ARC will be rated.\n\nSample Input 3\n\n4208\n\nSample Output 3\n\nAGC", "sample_input": "1199\n"}, "reference_outputs": ["ABC\n"], "source_document_id": "p03288", "source_text": "Score : 100 points\n\nProblem Statement\n\nA programming competition site AtCode regularly holds programming contests.\n\nThe next contest on AtCode is called ABC, which is rated for contestants with ratings less than 1200.\n\nThe contest after the ABC is called ARC, which is rated for contestants with ratings less than 2800.\n\nThe contest after the ARC is called AGC, which is rated for all contestants.\n\nTakahashi's rating on AtCode is R. What is the next contest rated for him?\n\nConstraints\n\n0 ≤ R ≤ 4208\n\nR is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nR\n\nOutput\n\nPrint the name of the next contest rated for Takahashi (ABC, ARC or AGC).\n\nSample Input 1\n\n1199\n\nSample Output 1\n\nABC\n\n1199 is less than 1200, so ABC will be rated.\n\nSample Input 2\n\n1200\n\nSample Output 2\n\nARC\n\n1200 is not less than 1200 and ABC will be unrated, but it is less than 2800 and ARC will be rated.\n\nSample Input 3\n\n4208\n\nSample Output 3\n\nAGC", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 190, "cpu_time_ms": 2, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s132041551", "group_id": "codeNet:p03290", "input_text": "#include<bits/stdc++.h>\n\nusing namespace std;\nint d,g;\npair<int,int> pc[10];\nint ans=100000;\n\nbool dfs(int sum,int cnt,int i){\n    if(sum>=g){\n        ans=min(ans,cnt);\n        return true;\n    }else if(i<0)\n        return false;\n\n    dfs(sum+(i+1)*100*(pc[i].first)+pc[i].second,cnt+(pc[i].first),i-1);\n\n    for(int j=0;j<pc[i].first;j++){\n        if(dfs(sum+(i+1)*100*j,cnt+j,i-1)==false)\n            break;\n    }\n\n    return true;\n}\n\nvoid solve(){\n    if(dfs(0,0,d-1));\n    printf(\"%d\\n\",ans);\n}\n\nint main(void){\n    cin >> d >> g;\n    for(int i=0;i<d;i++)\n        cin >> pc[i].first >> pc[i].second;\n    \n    solve();\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1597680326, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03290.html", "problem_id": "p03290", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03290/input.txt", "sample_output_relpath": "derived/input_output/data/p03290/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03290/C++/s132041551.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s132041551", "user_id": "u725680599"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include<bits/stdc++.h>\n\nusing namespace std;\nint d,g;\npair<int,int> pc[10];\nint ans=100000;\n\nbool dfs(int sum,int cnt,int i){\n    if(sum>=g){\n        ans=min(ans,cnt);\n        return true;\n    }else if(i<0)\n        return false;\n\n    dfs(sum+(i+1)*100*(pc[i].first)+pc[i].second,cnt+(pc[i].first),i-1);\n\n    for(int j=0;j<pc[i].first;j++){\n        if(dfs(sum+(i+1)*100*j,cnt+j,i-1)==false)\n            break;\n    }\n\n    return true;\n}\n\nvoid solve(){\n    if(dfs(0,0,d-1));\n    printf(\"%d\\n\",ans);\n}\n\nint main(void){\n    cin >> d >> g;\n    for(int i=0;i<d;i++)\n        cin >> pc[i].first >> pc[i].second;\n    \n    solve();\n    return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nA programming competition site AtCode provides algorithmic problems.\nEach problem is allocated a score based on its difficulty.\nCurrently, for each integer i between 1 and D (inclusive), there are p_i problems with a score of 100i points.\nThese p_1 + … + p_D problems are all of the problems available on AtCode.\n\nA user of AtCode has a value called total score.\nThe total score of a user is the sum of the following two elements:\n\nBase score: the sum of the scores of all problems solved by the user.\n\nPerfect bonuses: when a user solves all problems with a score of 100i points, he/she earns the perfect bonus of c_i points, aside from the base score (1 ≤ i ≤ D).\n\nTakahashi, who is the new user of AtCode, has not solved any problem.\nHis objective is to have a total score of G or more points.\nAt least how many problems does he need to solve for this objective?\n\nConstraints\n\n1 ≤ D ≤ 10\n\n1 ≤ p_i ≤ 100\n\n100 ≤ c_i ≤ 10^6\n\n100 ≤ G\n\nAll values in input are integers.\n\nc_i and G are all multiples of 100.\n\nIt is possible to have a total score of G or more points.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nD G\np_1 c_1\n:\np_D c_D\n\nOutput\n\nPrint the minimum number of problems that needs to be solved in order to have a total score of G or more points. Note that this objective is always achievable (see Constraints).\n\nSample Input 1\n\n2 700\n3 500\n5 800\n\nSample Output 1\n\n3\n\nIn this case, there are three problems each with 100 points and five problems each with 200 points. The perfect bonus for solving all the 100-point problems is 500 points, and the perfect bonus for solving all the 200-point problems is 800 points. Takahashi's objective is to have a total score of 700 points or more.\n\nOne way to achieve this objective is to solve four 200-point problems and earn a base score of 800 points. However, if we solve three 100-point problems, we can earn the perfect bonus of 500 points in addition to the base score of 300 points, for a total score of 800 points, and we can achieve the objective with fewer problems.\n\nSample Input 2\n\n2 2000\n3 500\n5 800\n\nSample Output 2\n\n7\n\nThis case is similar to Sample Input 1, but the Takahashi's objective this time is 2000 points or more. In this case, we inevitably need to solve all five 200-point problems, and by solving two 100-point problems additionally we have the total score of 2000 points.\n\nSample Input 3\n\n2 400\n3 500\n5 800\n\nSample Output 3\n\n2\n\nThis case is again similar to Sample Input 1, but the Takahashi's objective this time is 400 points or more. In this case, we only need to solve two 200-point problems to achieve the objective.\n\nSample Input 4\n\n5 25000\n20 1000\n40 1000\n50 1000\n30 1000\n1 1000\n\nSample Output 4\n\n66\n\nThere is only one 500-point problem, but the perfect bonus can be earned even in such a case.", "sample_input": "2 700\n3 500\n5 800\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03290", "source_text": "Score : 300 points\n\nProblem Statement\n\nA programming competition site AtCode provides algorithmic problems.\nEach problem is allocated a score based on its difficulty.\nCurrently, for each integer i between 1 and D (inclusive), there are p_i problems with a score of 100i points.\nThese p_1 + … + p_D problems are all of the problems available on AtCode.\n\nA user of AtCode has a value called total score.\nThe total score of a user is the sum of the following two elements:\n\nBase score: the sum of the scores of all problems solved by the user.\n\nPerfect bonuses: when a user solves all problems with a score of 100i points, he/she earns the perfect bonus of c_i points, aside from the base score (1 ≤ i ≤ D).\n\nTakahashi, who is the new user of AtCode, has not solved any problem.\nHis objective is to have a total score of G or more points.\nAt least how many problems does he need to solve for this objective?\n\nConstraints\n\n1 ≤ D ≤ 10\n\n1 ≤ p_i ≤ 100\n\n100 ≤ c_i ≤ 10^6\n\n100 ≤ G\n\nAll values in input are integers.\n\nc_i and G are all multiples of 100.\n\nIt is possible to have a total score of G or more points.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nD G\np_1 c_1\n:\np_D c_D\n\nOutput\n\nPrint the minimum number of problems that needs to be solved in order to have a total score of G or more points. Note that this objective is always achievable (see Constraints).\n\nSample Input 1\n\n2 700\n3 500\n5 800\n\nSample Output 1\n\n3\n\nIn this case, there are three problems each with 100 points and five problems each with 200 points. The perfect bonus for solving all the 100-point problems is 500 points, and the perfect bonus for solving all the 200-point problems is 800 points. Takahashi's objective is to have a total score of 700 points or more.\n\nOne way to achieve this objective is to solve four 200-point problems and earn a base score of 800 points. However, if we solve three 100-point problems, we can earn the perfect bonus of 500 points in addition to the base score of 300 points, for a total score of 800 points, and we can achieve the objective with fewer problems.\n\nSample Input 2\n\n2 2000\n3 500\n5 800\n\nSample Output 2\n\n7\n\nThis case is similar to Sample Input 1, but the Takahashi's objective this time is 2000 points or more. In this case, we inevitably need to solve all five 200-point problems, and by solving two 100-point problems additionally we have the total score of 2000 points.\n\nSample Input 3\n\n2 400\n3 500\n5 800\n\nSample Output 3\n\n2\n\nThis case is again similar to Sample Input 1, but the Takahashi's objective this time is 400 points or more. In this case, we only need to solve two 200-point problems to achieve the objective.\n\nSample Input 4\n\n5 25000\n20 1000\n40 1000\n50 1000\n30 1000\n1 1000\n\nSample Output 4\n\n66\n\nThere is only one 500-point problem, but the perfect bonus can be earned even in such a case.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 638, "cpu_time_ms": 2205, "memory_kb": 3684}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s600671389", "group_id": "codeNet:p03290", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nusing P = pair<int, int>;\n\nconst int INF = 1 << 30;\n\nint main(){\n\tint d, g;\n\tscanf(\"%d%d\", &d, &g);\n\tvector<pair<int, int> > p;\n\tfor(int i = 0; i < d; i++) {\n\t\tint a, b;\n\t\tscanf(\"%d%d\", &a, &b);\n\t\tp.push_back(make_pair(a, b));\n\t}\n\tint ans = INF;\n\tfor(int i = 0; i < (1 << d); i++) {\n\t\tint sum = 0, last = -1;\n\t\tint cnt = 0;\n\t\tfor(int j = 0; j < d; j++) {\n\t\t\tif(i & (1 << j)) {\n\t\t\t\tsum += 100 * (j + 1) * p[j].first + p[j].second;\n\t\t\t\tcnt += p[j].first;\n\t\t\t}else{\n\t\t\t\tlast = j;\n\t\t\t}\n\t\t}\n\t\tif(sum < g) {\n\t\t\tint point = 100 * (last + 1);\n\t\t\tint need = (g - sum + point - 1) / point;\n\t\t\tif(need >= p[last].first) continue;\n\t\t\tcnt += need;\n\t\t}\n\t\tans = min(ans, cnt);\n\t}\n\tprintf(\"%d\\n\", ans);\n}\n", "language": "C++", "metadata": {"date": 1588910489, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03290.html", "problem_id": "p03290", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03290/input.txt", "sample_output_relpath": "derived/input_output/data/p03290/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03290/C++/s600671389.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s600671389", "user_id": "u132602393"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nusing P = pair<int, int>;\n\nconst int INF = 1 << 30;\n\nint main(){\n\tint d, g;\n\tscanf(\"%d%d\", &d, &g);\n\tvector<pair<int, int> > p;\n\tfor(int i = 0; i < d; i++) {\n\t\tint a, b;\n\t\tscanf(\"%d%d\", &a, &b);\n\t\tp.push_back(make_pair(a, b));\n\t}\n\tint ans = INF;\n\tfor(int i = 0; i < (1 << d); i++) {\n\t\tint sum = 0, last = -1;\n\t\tint cnt = 0;\n\t\tfor(int j = 0; j < d; j++) {\n\t\t\tif(i & (1 << j)) {\n\t\t\t\tsum += 100 * (j + 1) * p[j].first + p[j].second;\n\t\t\t\tcnt += p[j].first;\n\t\t\t}else{\n\t\t\t\tlast = j;\n\t\t\t}\n\t\t}\n\t\tif(sum < g) {\n\t\t\tint point = 100 * (last + 1);\n\t\t\tint need = (g - sum + point - 1) / point;\n\t\t\tif(need >= p[last].first) continue;\n\t\t\tcnt += need;\n\t\t}\n\t\tans = min(ans, cnt);\n\t}\n\tprintf(\"%d\\n\", ans);\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nA programming competition site AtCode provides algorithmic problems.\nEach problem is allocated a score based on its difficulty.\nCurrently, for each integer i between 1 and D (inclusive), there are p_i problems with a score of 100i points.\nThese p_1 + … + p_D problems are all of the problems available on AtCode.\n\nA user of AtCode has a value called total score.\nThe total score of a user is the sum of the following two elements:\n\nBase score: the sum of the scores of all problems solved by the user.\n\nPerfect bonuses: when a user solves all problems with a score of 100i points, he/she earns the perfect bonus of c_i points, aside from the base score (1 ≤ i ≤ D).\n\nTakahashi, who is the new user of AtCode, has not solved any problem.\nHis objective is to have a total score of G or more points.\nAt least how many problems does he need to solve for this objective?\n\nConstraints\n\n1 ≤ D ≤ 10\n\n1 ≤ p_i ≤ 100\n\n100 ≤ c_i ≤ 10^6\n\n100 ≤ G\n\nAll values in input are integers.\n\nc_i and G are all multiples of 100.\n\nIt is possible to have a total score of G or more points.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nD G\np_1 c_1\n:\np_D c_D\n\nOutput\n\nPrint the minimum number of problems that needs to be solved in order to have a total score of G or more points. Note that this objective is always achievable (see Constraints).\n\nSample Input 1\n\n2 700\n3 500\n5 800\n\nSample Output 1\n\n3\n\nIn this case, there are three problems each with 100 points and five problems each with 200 points. The perfect bonus for solving all the 100-point problems is 500 points, and the perfect bonus for solving all the 200-point problems is 800 points. Takahashi's objective is to have a total score of 700 points or more.\n\nOne way to achieve this objective is to solve four 200-point problems and earn a base score of 800 points. However, if we solve three 100-point problems, we can earn the perfect bonus of 500 points in addition to the base score of 300 points, for a total score of 800 points, and we can achieve the objective with fewer problems.\n\nSample Input 2\n\n2 2000\n3 500\n5 800\n\nSample Output 2\n\n7\n\nThis case is similar to Sample Input 1, but the Takahashi's objective this time is 2000 points or more. In this case, we inevitably need to solve all five 200-point problems, and by solving two 100-point problems additionally we have the total score of 2000 points.\n\nSample Input 3\n\n2 400\n3 500\n5 800\n\nSample Output 3\n\n2\n\nThis case is again similar to Sample Input 1, but the Takahashi's objective this time is 400 points or more. In this case, we only need to solve two 200-point problems to achieve the objective.\n\nSample Input 4\n\n5 25000\n20 1000\n40 1000\n50 1000\n30 1000\n1 1000\n\nSample Output 4\n\n66\n\nThere is only one 500-point problem, but the perfect bonus can be earned even in such a case.", "sample_input": "2 700\n3 500\n5 800\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03290", "source_text": "Score : 300 points\n\nProblem Statement\n\nA programming competition site AtCode provides algorithmic problems.\nEach problem is allocated a score based on its difficulty.\nCurrently, for each integer i between 1 and D (inclusive), there are p_i problems with a score of 100i points.\nThese p_1 + … + p_D problems are all of the problems available on AtCode.\n\nA user of AtCode has a value called total score.\nThe total score of a user is the sum of the following two elements:\n\nBase score: the sum of the scores of all problems solved by the user.\n\nPerfect bonuses: when a user solves all problems with a score of 100i points, he/she earns the perfect bonus of c_i points, aside from the base score (1 ≤ i ≤ D).\n\nTakahashi, who is the new user of AtCode, has not solved any problem.\nHis objective is to have a total score of G or more points.\nAt least how many problems does he need to solve for this objective?\n\nConstraints\n\n1 ≤ D ≤ 10\n\n1 ≤ p_i ≤ 100\n\n100 ≤ c_i ≤ 10^6\n\n100 ≤ G\n\nAll values in input are integers.\n\nc_i and G are all multiples of 100.\n\nIt is possible to have a total score of G or more points.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nD G\np_1 c_1\n:\np_D c_D\n\nOutput\n\nPrint the minimum number of problems that needs to be solved in order to have a total score of G or more points. Note that this objective is always achievable (see Constraints).\n\nSample Input 1\n\n2 700\n3 500\n5 800\n\nSample Output 1\n\n3\n\nIn this case, there are three problems each with 100 points and five problems each with 200 points. The perfect bonus for solving all the 100-point problems is 500 points, and the perfect bonus for solving all the 200-point problems is 800 points. Takahashi's objective is to have a total score of 700 points or more.\n\nOne way to achieve this objective is to solve four 200-point problems and earn a base score of 800 points. However, if we solve three 100-point problems, we can earn the perfect bonus of 500 points in addition to the base score of 300 points, for a total score of 800 points, and we can achieve the objective with fewer problems.\n\nSample Input 2\n\n2 2000\n3 500\n5 800\n\nSample Output 2\n\n7\n\nThis case is similar to Sample Input 1, but the Takahashi's objective this time is 2000 points or more. In this case, we inevitably need to solve all five 200-point problems, and by solving two 100-point problems additionally we have the total score of 2000 points.\n\nSample Input 3\n\n2 400\n3 500\n5 800\n\nSample Output 3\n\n2\n\nThis case is again similar to Sample Input 1, but the Takahashi's objective this time is 400 points or more. In this case, we only need to solve two 200-point problems to achieve the objective.\n\nSample Input 4\n\n5 25000\n20 1000\n40 1000\n50 1000\n30 1000\n1 1000\n\nSample Output 4\n\n66\n\nThere is only one 500-point problem, but the perfect bonus can be earned even in such a case.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 735, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s344549325", "group_id": "codeNet:p03290", "input_text": "#include <bits/stdc++.h>\ntypedef long long int ll;\ntypedef long double ld;\nusing namespace std;\nconst long long int INF = 1e18;\nconst long long int mod = 1e9+7;\n\ntypedef pair<ll, ll> pairs;\ntypedef vector<pairs> p;\n\nstruct Edge{\n    ll to, weight;\n    Edge(ll t, ll w) : to(t), weight(w){}\n};\nusing graph = vector<vector<ll>>;\nusing Graph = vector<vector<Edge>>;\n\n\nll gcd(ll a,ll b){\n    if(b == 0){\n        return a;\n    }else{\n        return gcd(b, a%b);\n    }\n}\n\nll lcm(ll a, ll b){\n    return a / gcd(a, b) * b;\n}\n\nll keta(ll N){\n    int tmp{};\n    while( N > 0 ){\n        tmp += ( N % 10 );\n        N /= 10;\n    }\n    N = tmp;\n    return N;\n}\n\n// 回文\nbool kai(string S){\n    bool flag = true;\n    for(ll i=0;i<S.size()/2;++i){\n        if(S[i] != S[S.size()-i-1]){\n            flag = false;\n            break;\n        }\n    }\n    return flag;\n}\n// ---------------------------------------------\n\nint main(){\n    ll d, g;\n    cin>>d>>g;\n    vector<ll> p(d), c(d);\n    for(ll i=0;i<d;++i){\n        cin>>p[i]>>c[i];\n    }\n\n    ll ans = INF;\n    for(ll b=0;b<(1 << d);++b){\n        ll flag = 0;\n        ll num = 0;\n        ll r = -1;\n        for(ll i=0;i<d;++i){\n            if(b >> i & 1){\n                flag += 100 * (i+1) * p[i] + c[i];\n                num += p[i];\n            }else{\n                r = i;\n            }\n        }\n        if(flag < g){\n            ll fl = 100 * (r+1);\n            ll sum = (g - flag + fl -1) / fl;\n            if(sum >= p[r]){\n                continue;\n            }\n            num += sum;\n        }\n        ans = min(ans, num);\n    }\n    cout<<ans<<endl;\n\n    return 0;\n}", "language": "C++", "metadata": {"date": 1588790866, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03290.html", "problem_id": "p03290", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03290/input.txt", "sample_output_relpath": "derived/input_output/data/p03290/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03290/C++/s344549325.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s344549325", "user_id": "u473023730"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <bits/stdc++.h>\ntypedef long long int ll;\ntypedef long double ld;\nusing namespace std;\nconst long long int INF = 1e18;\nconst long long int mod = 1e9+7;\n\ntypedef pair<ll, ll> pairs;\ntypedef vector<pairs> p;\n\nstruct Edge{\n    ll to, weight;\n    Edge(ll t, ll w) : to(t), weight(w){}\n};\nusing graph = vector<vector<ll>>;\nusing Graph = vector<vector<Edge>>;\n\n\nll gcd(ll a,ll b){\n    if(b == 0){\n        return a;\n    }else{\n        return gcd(b, a%b);\n    }\n}\n\nll lcm(ll a, ll b){\n    return a / gcd(a, b) * b;\n}\n\nll keta(ll N){\n    int tmp{};\n    while( N > 0 ){\n        tmp += ( N % 10 );\n        N /= 10;\n    }\n    N = tmp;\n    return N;\n}\n\n// 回文\nbool kai(string S){\n    bool flag = true;\n    for(ll i=0;i<S.size()/2;++i){\n        if(S[i] != S[S.size()-i-1]){\n            flag = false;\n            break;\n        }\n    }\n    return flag;\n}\n// ---------------------------------------------\n\nint main(){\n    ll d, g;\n    cin>>d>>g;\n    vector<ll> p(d), c(d);\n    for(ll i=0;i<d;++i){\n        cin>>p[i]>>c[i];\n    }\n\n    ll ans = INF;\n    for(ll b=0;b<(1 << d);++b){\n        ll flag = 0;\n        ll num = 0;\n        ll r = -1;\n        for(ll i=0;i<d;++i){\n            if(b >> i & 1){\n                flag += 100 * (i+1) * p[i] + c[i];\n                num += p[i];\n            }else{\n                r = i;\n            }\n        }\n        if(flag < g){\n            ll fl = 100 * (r+1);\n            ll sum = (g - flag + fl -1) / fl;\n            if(sum >= p[r]){\n                continue;\n            }\n            num += sum;\n        }\n        ans = min(ans, num);\n    }\n    cout<<ans<<endl;\n\n    return 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nA programming competition site AtCode provides algorithmic problems.\nEach problem is allocated a score based on its difficulty.\nCurrently, for each integer i between 1 and D (inclusive), there are p_i problems with a score of 100i points.\nThese p_1 + … + p_D problems are all of the problems available on AtCode.\n\nA user of AtCode has a value called total score.\nThe total score of a user is the sum of the following two elements:\n\nBase score: the sum of the scores of all problems solved by the user.\n\nPerfect bonuses: when a user solves all problems with a score of 100i points, he/she earns the perfect bonus of c_i points, aside from the base score (1 ≤ i ≤ D).\n\nTakahashi, who is the new user of AtCode, has not solved any problem.\nHis objective is to have a total score of G or more points.\nAt least how many problems does he need to solve for this objective?\n\nConstraints\n\n1 ≤ D ≤ 10\n\n1 ≤ p_i ≤ 100\n\n100 ≤ c_i ≤ 10^6\n\n100 ≤ G\n\nAll values in input are integers.\n\nc_i and G are all multiples of 100.\n\nIt is possible to have a total score of G or more points.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nD G\np_1 c_1\n:\np_D c_D\n\nOutput\n\nPrint the minimum number of problems that needs to be solved in order to have a total score of G or more points. Note that this objective is always achievable (see Constraints).\n\nSample Input 1\n\n2 700\n3 500\n5 800\n\nSample Output 1\n\n3\n\nIn this case, there are three problems each with 100 points and five problems each with 200 points. The perfect bonus for solving all the 100-point problems is 500 points, and the perfect bonus for solving all the 200-point problems is 800 points. Takahashi's objective is to have a total score of 700 points or more.\n\nOne way to achieve this objective is to solve four 200-point problems and earn a base score of 800 points. However, if we solve three 100-point problems, we can earn the perfect bonus of 500 points in addition to the base score of 300 points, for a total score of 800 points, and we can achieve the objective with fewer problems.\n\nSample Input 2\n\n2 2000\n3 500\n5 800\n\nSample Output 2\n\n7\n\nThis case is similar to Sample Input 1, but the Takahashi's objective this time is 2000 points or more. In this case, we inevitably need to solve all five 200-point problems, and by solving two 100-point problems additionally we have the total score of 2000 points.\n\nSample Input 3\n\n2 400\n3 500\n5 800\n\nSample Output 3\n\n2\n\nThis case is again similar to Sample Input 1, but the Takahashi's objective this time is 400 points or more. In this case, we only need to solve two 200-point problems to achieve the objective.\n\nSample Input 4\n\n5 25000\n20 1000\n40 1000\n50 1000\n30 1000\n1 1000\n\nSample Output 4\n\n66\n\nThere is only one 500-point problem, but the perfect bonus can be earned even in such a case.", "sample_input": "2 700\n3 500\n5 800\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03290", "source_text": "Score : 300 points\n\nProblem Statement\n\nA programming competition site AtCode provides algorithmic problems.\nEach problem is allocated a score based on its difficulty.\nCurrently, for each integer i between 1 and D (inclusive), there are p_i problems with a score of 100i points.\nThese p_1 + … + p_D problems are all of the problems available on AtCode.\n\nA user of AtCode has a value called total score.\nThe total score of a user is the sum of the following two elements:\n\nBase score: the sum of the scores of all problems solved by the user.\n\nPerfect bonuses: when a user solves all problems with a score of 100i points, he/she earns the perfect bonus of c_i points, aside from the base score (1 ≤ i ≤ D).\n\nTakahashi, who is the new user of AtCode, has not solved any problem.\nHis objective is to have a total score of G or more points.\nAt least how many problems does he need to solve for this objective?\n\nConstraints\n\n1 ≤ D ≤ 10\n\n1 ≤ p_i ≤ 100\n\n100 ≤ c_i ≤ 10^6\n\n100 ≤ G\n\nAll values in input are integers.\n\nc_i and G are all multiples of 100.\n\nIt is possible to have a total score of G or more points.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nD G\np_1 c_1\n:\np_D c_D\n\nOutput\n\nPrint the minimum number of problems that needs to be solved in order to have a total score of G or more points. Note that this objective is always achievable (see Constraints).\n\nSample Input 1\n\n2 700\n3 500\n5 800\n\nSample Output 1\n\n3\n\nIn this case, there are three problems each with 100 points and five problems each with 200 points. The perfect bonus for solving all the 100-point problems is 500 points, and the perfect bonus for solving all the 200-point problems is 800 points. Takahashi's objective is to have a total score of 700 points or more.\n\nOne way to achieve this objective is to solve four 200-point problems and earn a base score of 800 points. However, if we solve three 100-point problems, we can earn the perfect bonus of 500 points in addition to the base score of 300 points, for a total score of 800 points, and we can achieve the objective with fewer problems.\n\nSample Input 2\n\n2 2000\n3 500\n5 800\n\nSample Output 2\n\n7\n\nThis case is similar to Sample Input 1, but the Takahashi's objective this time is 2000 points or more. In this case, we inevitably need to solve all five 200-point problems, and by solving two 100-point problems additionally we have the total score of 2000 points.\n\nSample Input 3\n\n2 400\n3 500\n5 800\n\nSample Output 3\n\n2\n\nThis case is again similar to Sample Input 1, but the Takahashi's objective this time is 400 points or more. In this case, we only need to solve two 200-point problems to achieve the objective.\n\nSample Input 4\n\n5 25000\n20 1000\n40 1000\n50 1000\n30 1000\n1 1000\n\nSample Output 4\n\n66\n\nThere is only one 500-point problem, but the perfect bonus can be earned even in such a case.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1615, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s657537194", "group_id": "codeNet:p03290", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n     ios_base::sync_with_stdio(false);\n    cin.tie(NULL);\n    int d,g;\n    cin>>d>>g;\n    vector<pair<long long int,long long int> >ar(d+1);\n    for(int i=1;i<=d;i++)\n       {\n           cin>>ar[i+1].first>>ar[i+1].second;\n       }\n    long long int y=0;long long int ans=0;\n    for(int i=d;i;i--)\n    {   if(g<=0)break;\n        y=ar[i].first*100*i;y+=ar[i].second;\n        if(y<=g){g-=y;ans+=ar[i].first;continue;}\n        y-=ar[i].second;y/=ar[i].first;\n        long long int v=g/y;\n        if(g%y&&v<ar[i].first)v++;\n        ans+=v;\n        g-=(v*100*i);\n        if(g<=0)break;\n    }\n    cout<<ans<<\"\\n\";\nreturn 0;\n}\n", "language": "C++", "metadata": {"date": 1533520116, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03290.html", "problem_id": "p03290", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03290/input.txt", "sample_output_relpath": "derived/input_output/data/p03290/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03290/C++/s657537194.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s657537194", "user_id": "u095884941"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n     ios_base::sync_with_stdio(false);\n    cin.tie(NULL);\n    int d,g;\n    cin>>d>>g;\n    vector<pair<long long int,long long int> >ar(d+1);\n    for(int i=1;i<=d;i++)\n       {\n           cin>>ar[i+1].first>>ar[i+1].second;\n       }\n    long long int y=0;long long int ans=0;\n    for(int i=d;i;i--)\n    {   if(g<=0)break;\n        y=ar[i].first*100*i;y+=ar[i].second;\n        if(y<=g){g-=y;ans+=ar[i].first;continue;}\n        y-=ar[i].second;y/=ar[i].first;\n        long long int v=g/y;\n        if(g%y&&v<ar[i].first)v++;\n        ans+=v;\n        g-=(v*100*i);\n        if(g<=0)break;\n    }\n    cout<<ans<<\"\\n\";\nreturn 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nA programming competition site AtCode provides algorithmic problems.\nEach problem is allocated a score based on its difficulty.\nCurrently, for each integer i between 1 and D (inclusive), there are p_i problems with a score of 100i points.\nThese p_1 + … + p_D problems are all of the problems available on AtCode.\n\nA user of AtCode has a value called total score.\nThe total score of a user is the sum of the following two elements:\n\nBase score: the sum of the scores of all problems solved by the user.\n\nPerfect bonuses: when a user solves all problems with a score of 100i points, he/she earns the perfect bonus of c_i points, aside from the base score (1 ≤ i ≤ D).\n\nTakahashi, who is the new user of AtCode, has not solved any problem.\nHis objective is to have a total score of G or more points.\nAt least how many problems does he need to solve for this objective?\n\nConstraints\n\n1 ≤ D ≤ 10\n\n1 ≤ p_i ≤ 100\n\n100 ≤ c_i ≤ 10^6\n\n100 ≤ G\n\nAll values in input are integers.\n\nc_i and G are all multiples of 100.\n\nIt is possible to have a total score of G or more points.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nD G\np_1 c_1\n:\np_D c_D\n\nOutput\n\nPrint the minimum number of problems that needs to be solved in order to have a total score of G or more points. Note that this objective is always achievable (see Constraints).\n\nSample Input 1\n\n2 700\n3 500\n5 800\n\nSample Output 1\n\n3\n\nIn this case, there are three problems each with 100 points and five problems each with 200 points. The perfect bonus for solving all the 100-point problems is 500 points, and the perfect bonus for solving all the 200-point problems is 800 points. Takahashi's objective is to have a total score of 700 points or more.\n\nOne way to achieve this objective is to solve four 200-point problems and earn a base score of 800 points. However, if we solve three 100-point problems, we can earn the perfect bonus of 500 points in addition to the base score of 300 points, for a total score of 800 points, and we can achieve the objective with fewer problems.\n\nSample Input 2\n\n2 2000\n3 500\n5 800\n\nSample Output 2\n\n7\n\nThis case is similar to Sample Input 1, but the Takahashi's objective this time is 2000 points or more. In this case, we inevitably need to solve all five 200-point problems, and by solving two 100-point problems additionally we have the total score of 2000 points.\n\nSample Input 3\n\n2 400\n3 500\n5 800\n\nSample Output 3\n\n2\n\nThis case is again similar to Sample Input 1, but the Takahashi's objective this time is 400 points or more. In this case, we only need to solve two 200-point problems to achieve the objective.\n\nSample Input 4\n\n5 25000\n20 1000\n40 1000\n50 1000\n30 1000\n1 1000\n\nSample Output 4\n\n66\n\nThere is only one 500-point problem, but the perfect bonus can be earned even in such a case.", "sample_input": "2 700\n3 500\n5 800\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03290", "source_text": "Score : 300 points\n\nProblem Statement\n\nA programming competition site AtCode provides algorithmic problems.\nEach problem is allocated a score based on its difficulty.\nCurrently, for each integer i between 1 and D (inclusive), there are p_i problems with a score of 100i points.\nThese p_1 + … + p_D problems are all of the problems available on AtCode.\n\nA user of AtCode has a value called total score.\nThe total score of a user is the sum of the following two elements:\n\nBase score: the sum of the scores of all problems solved by the user.\n\nPerfect bonuses: when a user solves all problems with a score of 100i points, he/she earns the perfect bonus of c_i points, aside from the base score (1 ≤ i ≤ D).\n\nTakahashi, who is the new user of AtCode, has not solved any problem.\nHis objective is to have a total score of G or more points.\nAt least how many problems does he need to solve for this objective?\n\nConstraints\n\n1 ≤ D ≤ 10\n\n1 ≤ p_i ≤ 100\n\n100 ≤ c_i ≤ 10^6\n\n100 ≤ G\n\nAll values in input are integers.\n\nc_i and G are all multiples of 100.\n\nIt is possible to have a total score of G or more points.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nD G\np_1 c_1\n:\np_D c_D\n\nOutput\n\nPrint the minimum number of problems that needs to be solved in order to have a total score of G or more points. Note that this objective is always achievable (see Constraints).\n\nSample Input 1\n\n2 700\n3 500\n5 800\n\nSample Output 1\n\n3\n\nIn this case, there are three problems each with 100 points and five problems each with 200 points. The perfect bonus for solving all the 100-point problems is 500 points, and the perfect bonus for solving all the 200-point problems is 800 points. Takahashi's objective is to have a total score of 700 points or more.\n\nOne way to achieve this objective is to solve four 200-point problems and earn a base score of 800 points. However, if we solve three 100-point problems, we can earn the perfect bonus of 500 points in addition to the base score of 300 points, for a total score of 800 points, and we can achieve the objective with fewer problems.\n\nSample Input 2\n\n2 2000\n3 500\n5 800\n\nSample Output 2\n\n7\n\nThis case is similar to Sample Input 1, but the Takahashi's objective this time is 2000 points or more. In this case, we inevitably need to solve all five 200-point problems, and by solving two 100-point problems additionally we have the total score of 2000 points.\n\nSample Input 3\n\n2 400\n3 500\n5 800\n\nSample Output 3\n\n2\n\nThis case is again similar to Sample Input 1, but the Takahashi's objective this time is 400 points or more. In this case, we only need to solve two 200-point problems to achieve the objective.\n\nSample Input 4\n\n5 25000\n20 1000\n40 1000\n50 1000\n30 1000\n1 1000\n\nSample Output 4\n\n66\n\nThere is only one 500-point problem, but the perfect bonus can be earned even in such a case.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 680, "cpu_time_ms": 127, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s743160143", "group_id": "codeNet:p03292", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nusing i64 = long long;\n\nint main(){\n    vector<int> a(3);\n    for(int i=0;i<3;i++)cin>>a[i];\n    sort(a.begin(),a.end());\n    cout<<(a[1]-a[0])+(a[2]-a[1])<<endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1559956417, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03292.html", "problem_id": "p03292", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03292/input.txt", "sample_output_relpath": "derived/input_output/data/p03292/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03292/C++/s743160143.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s743160143", "user_id": "u366245083"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nusing i64 = long long;\n\nint main(){\n    vector<int> a(3);\n    for(int i=0;i<3;i++)cin>>a[i];\n    sort(a.begin(),a.end());\n    cout<<(a[1]-a[0])+(a[2]-a[1])<<endl;\n    return 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nYou have three tasks, all of which need to be completed.\n\nFirst, you can complete any one task at cost 0.\n\nThen, just after completing the i-th task, you can complete the j-th task at cost |A_j - A_i|.\n\nHere, |x| denotes the absolute value of x.\n\nFind the minimum total cost required to complete all the task.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq A_1, A_2, A_3 \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA_1 A_2 A_3\n\nOutput\n\nPrint the minimum total cost required to complete all the task.\n\nSample Input 1\n\n1 6 3\n\nSample Output 1\n\n5\n\nWhen the tasks are completed in the following order, the total cost will be 5, which is the minimum:\n\nComplete the first task at cost 0.\n\nComplete the third task at cost 2.\n\nComplete the second task at cost 3.\n\nSample Input 2\n\n11 5 5\n\nSample Output 2\n\n6\n\nSample Input 3\n\n100 100 100\n\nSample Output 3\n\n0", "sample_input": "1 6 3\n"}, "reference_outputs": ["5\n"], "source_document_id": "p03292", "source_text": "Score : 100 points\n\nProblem Statement\n\nYou have three tasks, all of which need to be completed.\n\nFirst, you can complete any one task at cost 0.\n\nThen, just after completing the i-th task, you can complete the j-th task at cost |A_j - A_i|.\n\nHere, |x| denotes the absolute value of x.\n\nFind the minimum total cost required to complete all the task.\n\nConstraints\n\nAll values in input are integers.\n\n1 \\leq A_1, A_2, A_3 \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA_1 A_2 A_3\n\nOutput\n\nPrint the minimum total cost required to complete all the task.\n\nSample Input 1\n\n1 6 3\n\nSample Output 1\n\n5\n\nWhen the tasks are completed in the following order, the total cost will be 5, which is the minimum:\n\nComplete the first task at cost 0.\n\nComplete the third task at cost 2.\n\nComplete the second task at cost 3.\n\nSample Input 2\n\n11 5 5\n\nSample Output 2\n\n6\n\nSample Input 3\n\n100 100 100\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 224, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s150094340", "group_id": "codeNet:p03293", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  string s,t;\n  cin >> s >> t;\n  for(int i = 0; i < s.size(); i++){\n    s = s.substr(s.size()-1, 1) + s;\n    s.pop_back();\n    if(s == t){\n      cout << \"Yes\" << endl;\n      return 0;\n    }\n  }\n  cout << \"No\" << endl;\n  return 0;\n}", "language": "C++", "metadata": {"date": 1596331189, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03293.html", "problem_id": "p03293", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03293/input.txt", "sample_output_relpath": "derived/input_output/data/p03293/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03293/C++/s150094340.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s150094340", "user_id": "u225777148"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  string s,t;\n  cin >> s >> t;\n  for(int i = 0; i < s.size(); i++){\n    s = s.substr(s.size()-1, 1) + s;\n    s.pop_back();\n    if(s == t){\n      cout << \"Yes\" << endl;\n      return 0;\n    }\n  }\n  cout << \"No\" << endl;\n  return 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nYou are given string S and T consisting of lowercase English letters.\n\nDetermine if S equals T after rotation.\n\nThat is, determine if S equals T after the following operation is performed some number of times:\n\nOperation: Let S = S_1 S_2 ... S_{|S|}. Change S to S_{|S|} S_1 S_2 ... S_{|S|-1}.\n\nHere, |X| denotes the length of the string X.\n\nConstraints\n\n2 \\leq |S| \\leq 100\n\n|S| = |T|\n\nS and T consist of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\nT\n\nOutput\n\nIf S equals T after rotation, print Yes; if it does not, print No.\n\nSample Input 1\n\nkyoto\ntokyo\n\nSample Output 1\n\nYes\n\nIn the first operation, kyoto becomes okyot.\n\nIn the second operation, okyot becomes tokyo.\n\nSample Input 2\n\nabc\narc\n\nSample Output 2\n\nNo\n\nabc does not equal arc after any number of operations.\n\nSample Input 3\n\naaaaaaaaaaaaaaab\naaaaaaaaaaaaaaab\n\nSample Output 3\n\nYes", "sample_input": "kyoto\ntokyo\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p03293", "source_text": "Score : 200 points\n\nProblem Statement\n\nYou are given string S and T consisting of lowercase English letters.\n\nDetermine if S equals T after rotation.\n\nThat is, determine if S equals T after the following operation is performed some number of times:\n\nOperation: Let S = S_1 S_2 ... S_{|S|}. Change S to S_{|S|} S_1 S_2 ... S_{|S|-1}.\n\nHere, |X| denotes the length of the string X.\n\nConstraints\n\n2 \\leq |S| \\leq 100\n\n|S| = |T|\n\nS and T consist of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\nT\n\nOutput\n\nIf S equals T after rotation, print Yes; if it does not, print No.\n\nSample Input 1\n\nkyoto\ntokyo\n\nSample Output 1\n\nYes\n\nIn the first operation, kyoto becomes okyot.\n\nIn the second operation, okyot becomes tokyo.\n\nSample Input 2\n\nabc\narc\n\nSample Output 2\n\nNo\n\nabc does not equal arc after any number of operations.\n\nSample Input 3\n\naaaaaaaaaaaaaaab\naaaaaaaaaaaaaaab\n\nSample Output 3\n\nYes", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 289, "cpu_time_ms": 8, "memory_kb": 3608}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s476059117", "group_id": "codeNet:p03306", "input_text": "#include<iostream>\n#include<iomanip>\n#include<math.h>\n#include<algorithm>\n#include<utility>\n#include<queue>\n#include<string.h>\n#include<string>\n#include<set>\n#include<map>\n#include<unordered_map>\n#include<vector>\n#include<functional>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll,ll> P;\nconst ll INF=4e18;\nconst ll MOD=1e9+7;\nconst double EPS=1e-7;\n\nll N,M;\nstruct Edge{\n  ll to,cost;\n};\nvector<Edge> edges[100010];\nP state[100010];\nll cnt=0;\nmap<P,bool> used;\nvoid Serch(ll n){\n  for(auto e:edges[n]){\n    if(used[P(min(n,e.to),max(n,e.to))])continue;\n    if(state[e.to].first==-1){\n      if(state[n].second==0){\n        state[e.to] = P(-(e.cost-state[n].first),1);\n      }else{\n        state[e.to] = P(e.cost+state[n].first,0);\n      }\n      used[P(min(n,e.to),max(n,e.to))]=true;\n      Serch(e.to);\n    }else{\n      used[P(min(n,e.to),max(n,e.to))]=true;\n      cnt++;\n      if(cnt>=2){\n        return;\n      }\n    }\n  }\n}\nint main(){\n    cin>>N>>M;\n    for(ll i=0;i<M;i++){\n      ll u,v,s;\n      cin>>u>>v>>s;\n      u--;v--;\n      edges[u].push_back(Edge{v,s});\n      edges[v].push_back(Edge{u,s});\n    }\n    for(ll i=0;i<N;i++){\n      state[i]=P(-1,0);\n    }\n    state[0]=P(0,1);\n    Serch(0);\n    if(cnt==0){\n      ll d=1,u=INF;\n      for(ll i=1;i<N;i++){\n          //cout<<state[i].first<<\",\"<<state[i].second<<endl;\n        if(state[i].second==0){\n          u=min(u,state[i].first-1);\n        }else{\n          d=max(d,state[i].first);\n        }\n      }\n      cout<<max(0ll,u-d+1)<<endl;\n    }else if(cnt==1){\n      cout<<1<<endl;\n    }else{\n      cout<<0<<endl;\n    }\n    return 0;\n}", "language": "C++", "metadata": {"date": 1573015595, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03306.html", "problem_id": "p03306", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03306/input.txt", "sample_output_relpath": "derived/input_output/data/p03306/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03306/C++/s476059117.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s476059117", "user_id": "u114234520"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include<iostream>\n#include<iomanip>\n#include<math.h>\n#include<algorithm>\n#include<utility>\n#include<queue>\n#include<string.h>\n#include<string>\n#include<set>\n#include<map>\n#include<unordered_map>\n#include<vector>\n#include<functional>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll,ll> P;\nconst ll INF=4e18;\nconst ll MOD=1e9+7;\nconst double EPS=1e-7;\n\nll N,M;\nstruct Edge{\n  ll to,cost;\n};\nvector<Edge> edges[100010];\nP state[100010];\nll cnt=0;\nmap<P,bool> used;\nvoid Serch(ll n){\n  for(auto e:edges[n]){\n    if(used[P(min(n,e.to),max(n,e.to))])continue;\n    if(state[e.to].first==-1){\n      if(state[n].second==0){\n        state[e.to] = P(-(e.cost-state[n].first),1);\n      }else{\n        state[e.to] = P(e.cost+state[n].first,0);\n      }\n      used[P(min(n,e.to),max(n,e.to))]=true;\n      Serch(e.to);\n    }else{\n      used[P(min(n,e.to),max(n,e.to))]=true;\n      cnt++;\n      if(cnt>=2){\n        return;\n      }\n    }\n  }\n}\nint main(){\n    cin>>N>>M;\n    for(ll i=0;i<M;i++){\n      ll u,v,s;\n      cin>>u>>v>>s;\n      u--;v--;\n      edges[u].push_back(Edge{v,s});\n      edges[v].push_back(Edge{u,s});\n    }\n    for(ll i=0;i<N;i++){\n      state[i]=P(-1,0);\n    }\n    state[0]=P(0,1);\n    Serch(0);\n    if(cnt==0){\n      ll d=1,u=INF;\n      for(ll i=1;i<N;i++){\n          //cout<<state[i].first<<\",\"<<state[i].second<<endl;\n        if(state[i].second==0){\n          u=min(u,state[i].first-1);\n        }else{\n          d=max(d,state[i].first);\n        }\n      }\n      cout<<max(0ll,u-d+1)<<endl;\n    }else if(cnt==1){\n      cout<<1<<endl;\n    }else{\n      cout<<0<<endl;\n    }\n    return 0;\n}", "problem_context": "Score : 600 points\n\nProblem Statement\n\nKenkoooo found a simple connected graph.\nThe vertices are numbered 1 through n.\nThe i-th edge connects Vertex u_i and v_i, and has a fixed integer s_i.\n\nKenkoooo is trying to write a positive integer in each vertex so that the following condition is satisfied:\n\nFor every edge i, the sum of the positive integers written in Vertex u_i and v_i is equal to s_i.\n\nFind the number of such ways to write positive integers in the vertices.\n\nConstraints\n\n2 \\leq n \\leq 10^5\n\n1 \\leq m \\leq 10^5\n\n1 \\leq u_i < v_i \\leq n\n\n2 \\leq s_i \\leq 10^9\n\nIf i\\neq j, then u_i \\neq u_j or v_i \\neq v_j.\n\nThe graph is connected.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn m\nu_1 v_1 s_1\n:\nu_m v_m s_m\n\nOutput\n\nPrint the number of ways to write positive integers in the vertices so that the condition is satisfied.\n\nSample Input 1\n\n3 3\n1 2 3\n2 3 5\n1 3 4\n\nSample Output 1\n\n1\n\nThe condition will be satisfied if we write 1,2 and 3 in vertices 1,2 and 3, respectively.\nThere is no other way to satisfy the condition, so the answer is 1.\n\nSample Input 2\n\n4 3\n1 2 6\n2 3 7\n3 4 5\n\nSample Output 2\n\n3\n\nLet a,b,c and d be the numbers to write in vertices 1,2,3 and 4, respectively.\nThere are three quadruples (a,b,c,d) that satisfy the condition:\n\n(a,b,c,d)=(1,5,2,3)\n\n(a,b,c,d)=(2,4,3,2)\n\n(a,b,c,d)=(3,3,4,1)\n\nSample Input 3\n\n8 7\n1 2 1000000000\n2 3 2\n3 4 1000000000\n4 5 2\n5 6 1000000000\n6 7 2\n7 8 1000000000\n\nSample Output 3\n\n0", "sample_input": "3 3\n1 2 3\n2 3 5\n1 3 4\n"}, "reference_outputs": ["1\n"], "source_document_id": "p03306", "source_text": "Score : 600 points\n\nProblem Statement\n\nKenkoooo found a simple connected graph.\nThe vertices are numbered 1 through n.\nThe i-th edge connects Vertex u_i and v_i, and has a fixed integer s_i.\n\nKenkoooo is trying to write a positive integer in each vertex so that the following condition is satisfied:\n\nFor every edge i, the sum of the positive integers written in Vertex u_i and v_i is equal to s_i.\n\nFind the number of such ways to write positive integers in the vertices.\n\nConstraints\n\n2 \\leq n \\leq 10^5\n\n1 \\leq m \\leq 10^5\n\n1 \\leq u_i < v_i \\leq n\n\n2 \\leq s_i \\leq 10^9\n\nIf i\\neq j, then u_i \\neq u_j or v_i \\neq v_j.\n\nThe graph is connected.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn m\nu_1 v_1 s_1\n:\nu_m v_m s_m\n\nOutput\n\nPrint the number of ways to write positive integers in the vertices so that the condition is satisfied.\n\nSample Input 1\n\n3 3\n1 2 3\n2 3 5\n1 3 4\n\nSample Output 1\n\n1\n\nThe condition will be satisfied if we write 1,2 and 3 in vertices 1,2 and 3, respectively.\nThere is no other way to satisfy the condition, so the answer is 1.\n\nSample Input 2\n\n4 3\n1 2 6\n2 3 7\n3 4 5\n\nSample Output 2\n\n3\n\nLet a,b,c and d be the numbers to write in vertices 1,2,3 and 4, respectively.\nThere are three quadruples (a,b,c,d) that satisfy the condition:\n\n(a,b,c,d)=(1,5,2,3)\n\n(a,b,c,d)=(2,4,3,2)\n\n(a,b,c,d)=(3,3,4,1)\n\nSample Input 3\n\n8 7\n1 2 1000000000\n2 3 2\n3 4 1000000000\n4 5 2\n5 6 1000000000\n6 7 2\n7 8 1000000000\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1603, "cpu_time_ms": 211, "memory_kb": 28032}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s396906964", "group_id": "codeNet:p03306", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n#define REP(i,n) for(long long i = 0; i < (n); i++)\n#define FOR(i, m, n) for(long long i = (m);i < (n); ++i)\n#define ALL(obj) (obj).begin(),(obj).end()\n\ntemplate<class T> using V = vector<T>;\ntemplate<class T, class U> using P = pair<T, U>;\n\nconst ll MOD = (ll)1e9 + 7;\nconst ll MOD2 = 998244353;\nconst ll LLINF = (ll)1e18;\nconst ll INTINF = (ll)1e9;\nconst long double PI = 3.1415926535897932384626433;\n\ntemplate <class T> void corner(bool flg, T hoge) {if (flg) {cout << hoge << endl; exit(0);}}\ntemplate <class T, class U>ostream &operator<<(ostream &o, const map<T, U>&obj) {o << \"{\"; for (auto &x : obj) o << \" {\" << x.first << \" : \" << x.second << \"}\" << \",\"; o << \" }\"; return o;}\ntemplate <class T>ostream &operator<<(ostream &o, const set<T>&obj) {o << \"{\"; for (auto itr = obj.begin(); itr != obj.end(); ++itr) o << (itr != obj.begin() ? \", \" : \"\") << *itr; o << \"}\"; return o;}\ntemplate <class T>ostream &operator<<(ostream &o, const vector<T>&obj) {o << \"{\"; for (int i = 0; i < (int)obj.size(); ++i)o << (i > 0 ? \", \" : \"\") << obj[i]; o << \"}\"; return o;}\ntemplate <class T, class U>ostream &operator<<(ostream &o, const pair<T, U>&obj) {o << \"{\" << obj.first << \", \" << obj.second << \"}\"; return o;}\ntemplate <template <class tmp>  class T, class U> ostream &operator<<(ostream &o, const T<U> &obj) {o << \"{\"; for (auto itr = obj.begin(); itr != obj.end(); ++itr)o << (itr != obj.begin() ? \", \" : \"\") << *itr; o << \"}\"; return o;}\nvoid print(void) {cout << endl;}\ntemplate <class Head> void print(Head&& head) {cout << head;print();}\ntemplate <class Head, class... Tail> void print(Head&& head, Tail&&... tail) {cout << head << \" \";print(forward<Tail>(tail)...);}\ntemplate <class T> void chmax(T& a, const T b){a=max<T>(a,b);}\ntemplate <class T> void chmin(T& a, const T b){a=min<T>(a,b);}\nvoid YN(bool flg) {cout << ((flg) ? \"YES\" : \"NO\") << endl;}\nvoid Yn(bool flg) {cout << ((flg) ? \"Yes\" : \"No\") << endl;}\nvoid yn(bool flg) {cout << ((flg) ? \"yes\" : \"no\") << endl;}\n\nint main() {\n\tint N,M; cin >> N >> M;\n\tll mini = 1, maxi = 0, x = 0;\n\tV<V<P<int,ll>>> edge(N);\n\tV<P<int,ll>> node(N,{0,0});\n\tfor(int i = 0; i < M; ++i){\n\t\tint u,v; ll s;\n\t\tcin >> u >> v >> s;\n\t\tu--,v--;\n\t\tedge[u].push_back({v,s});\n\t\tedge[v].push_back({u,s});\n\t\tchmax(maxi,s-1);\n\t}\n\n\tnode[0] = {1,0};\n\tqueue<int> q;\n\tq.push(0);\n\twhile(q.size()){\n\t\tint from = q.front();\n\t\tq.pop();\n\t\tfor(auto e:edge[from]){\n\t\t\tint to = e.first;\n\t\t\tll cost = e.second;\n\t\t\tint type = -node[from].first;\n\t\t\tll val = cost-node[from].second;\n\n\t\t\tif(node[to].first==0){\n\t\t\t\tnode[to] = {type,val};\n\t\t\t\tif(node[to].first==-1) chmin(maxi,node[to].second - 1);\n\t\t\t\tif(node[to].first== 1) chmax(mini,1 - node[to].second);\n\t\t\t\tq.push(to);\n\t\t\t}\n\t\t\telse{\n\t\t\t\tif(type == node[to].first){\n\t\t\t\t\tcorner(val != node[to].second,0);\n\t\t\t\t}\n\t\t\t\telse{\n\t\t\t\t\tll a = val, b = node[to].second;\n\t\t\t\t\tif(type > node[to].first) swap(a,b);\n\t\t\t\t\tcorner(a-b<=0||(a-b)%2,0);\n\t\t\t\t\tx = (a-b)/2;\n\t\t\t\t\twhile(q.size())q.pop();\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tcorner(x==0,max(maxi-mini+1LL,0LL));\n\n\tfor(int i = 0; i < N; ++i) node[i] = {0,0};\n\tnode[0] = {1,x};\n\tq.push(0);\n\n\twhile(q.size()){\n\t\tint from = q.front();\n\t\tq.pop();\n\t\tfor(auto e:edge[from]){\n\t\t\tint to = e.first;\n\t\t\tll cost = e.second;\n\t\t\tll val = cost-node[from].second;\n\n\t\t\tif(node[to].first==0){\n\t\t\t\tnode[to] = {1,val};\n\t\t\t\tq.push(to);\n\t\t\t}\n\t\t\telse{\n\t\t\t\tcorner(val != node[to].second, 0);\n\t\t\t}\n\t\t}\n\t}\n\tcout << 1 << endl;\t\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1548500107, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03306.html", "problem_id": "p03306", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03306/input.txt", "sample_output_relpath": "derived/input_output/data/p03306/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03306/C++/s396906964.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s396906964", "user_id": "u898651494"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\n#define REP(i,n) for(long long i = 0; i < (n); i++)\n#define FOR(i, m, n) for(long long i = (m);i < (n); ++i)\n#define ALL(obj) (obj).begin(),(obj).end()\n\ntemplate<class T> using V = vector<T>;\ntemplate<class T, class U> using P = pair<T, U>;\n\nconst ll MOD = (ll)1e9 + 7;\nconst ll MOD2 = 998244353;\nconst ll LLINF = (ll)1e18;\nconst ll INTINF = (ll)1e9;\nconst long double PI = 3.1415926535897932384626433;\n\ntemplate <class T> void corner(bool flg, T hoge) {if (flg) {cout << hoge << endl; exit(0);}}\ntemplate <class T, class U>ostream &operator<<(ostream &o, const map<T, U>&obj) {o << \"{\"; for (auto &x : obj) o << \" {\" << x.first << \" : \" << x.second << \"}\" << \",\"; o << \" }\"; return o;}\ntemplate <class T>ostream &operator<<(ostream &o, const set<T>&obj) {o << \"{\"; for (auto itr = obj.begin(); itr != obj.end(); ++itr) o << (itr != obj.begin() ? \", \" : \"\") << *itr; o << \"}\"; return o;}\ntemplate <class T>ostream &operator<<(ostream &o, const vector<T>&obj) {o << \"{\"; for (int i = 0; i < (int)obj.size(); ++i)o << (i > 0 ? \", \" : \"\") << obj[i]; o << \"}\"; return o;}\ntemplate <class T, class U>ostream &operator<<(ostream &o, const pair<T, U>&obj) {o << \"{\" << obj.first << \", \" << obj.second << \"}\"; return o;}\ntemplate <template <class tmp>  class T, class U> ostream &operator<<(ostream &o, const T<U> &obj) {o << \"{\"; for (auto itr = obj.begin(); itr != obj.end(); ++itr)o << (itr != obj.begin() ? \", \" : \"\") << *itr; o << \"}\"; return o;}\nvoid print(void) {cout << endl;}\ntemplate <class Head> void print(Head&& head) {cout << head;print();}\ntemplate <class Head, class... Tail> void print(Head&& head, Tail&&... tail) {cout << head << \" \";print(forward<Tail>(tail)...);}\ntemplate <class T> void chmax(T& a, const T b){a=max<T>(a,b);}\ntemplate <class T> void chmin(T& a, const T b){a=min<T>(a,b);}\nvoid YN(bool flg) {cout << ((flg) ? \"YES\" : \"NO\") << endl;}\nvoid Yn(bool flg) {cout << ((flg) ? \"Yes\" : \"No\") << endl;}\nvoid yn(bool flg) {cout << ((flg) ? \"yes\" : \"no\") << endl;}\n\nint main() {\n\tint N,M; cin >> N >> M;\n\tll mini = 1, maxi = 0, x = 0;\n\tV<V<P<int,ll>>> edge(N);\n\tV<P<int,ll>> node(N,{0,0});\n\tfor(int i = 0; i < M; ++i){\n\t\tint u,v; ll s;\n\t\tcin >> u >> v >> s;\n\t\tu--,v--;\n\t\tedge[u].push_back({v,s});\n\t\tedge[v].push_back({u,s});\n\t\tchmax(maxi,s-1);\n\t}\n\n\tnode[0] = {1,0};\n\tqueue<int> q;\n\tq.push(0);\n\twhile(q.size()){\n\t\tint from = q.front();\n\t\tq.pop();\n\t\tfor(auto e:edge[from]){\n\t\t\tint to = e.first;\n\t\t\tll cost = e.second;\n\t\t\tint type = -node[from].first;\n\t\t\tll val = cost-node[from].second;\n\n\t\t\tif(node[to].first==0){\n\t\t\t\tnode[to] = {type,val};\n\t\t\t\tif(node[to].first==-1) chmin(maxi,node[to].second - 1);\n\t\t\t\tif(node[to].first== 1) chmax(mini,1 - node[to].second);\n\t\t\t\tq.push(to);\n\t\t\t}\n\t\t\telse{\n\t\t\t\tif(type == node[to].first){\n\t\t\t\t\tcorner(val != node[to].second,0);\n\t\t\t\t}\n\t\t\t\telse{\n\t\t\t\t\tll a = val, b = node[to].second;\n\t\t\t\t\tif(type > node[to].first) swap(a,b);\n\t\t\t\t\tcorner(a-b<=0||(a-b)%2,0);\n\t\t\t\t\tx = (a-b)/2;\n\t\t\t\t\twhile(q.size())q.pop();\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tcorner(x==0,max(maxi-mini+1LL,0LL));\n\n\tfor(int i = 0; i < N; ++i) node[i] = {0,0};\n\tnode[0] = {1,x};\n\tq.push(0);\n\n\twhile(q.size()){\n\t\tint from = q.front();\n\t\tq.pop();\n\t\tfor(auto e:edge[from]){\n\t\t\tint to = e.first;\n\t\t\tll cost = e.second;\n\t\t\tll val = cost-node[from].second;\n\n\t\t\tif(node[to].first==0){\n\t\t\t\tnode[to] = {1,val};\n\t\t\t\tq.push(to);\n\t\t\t}\n\t\t\telse{\n\t\t\t\tcorner(val != node[to].second, 0);\n\t\t\t}\n\t\t}\n\t}\n\tcout << 1 << endl;\t\n\treturn 0;\n}\n", "problem_context": "Score : 600 points\n\nProblem Statement\n\nKenkoooo found a simple connected graph.\nThe vertices are numbered 1 through n.\nThe i-th edge connects Vertex u_i and v_i, and has a fixed integer s_i.\n\nKenkoooo is trying to write a positive integer in each vertex so that the following condition is satisfied:\n\nFor every edge i, the sum of the positive integers written in Vertex u_i and v_i is equal to s_i.\n\nFind the number of such ways to write positive integers in the vertices.\n\nConstraints\n\n2 \\leq n \\leq 10^5\n\n1 \\leq m \\leq 10^5\n\n1 \\leq u_i < v_i \\leq n\n\n2 \\leq s_i \\leq 10^9\n\nIf i\\neq j, then u_i \\neq u_j or v_i \\neq v_j.\n\nThe graph is connected.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn m\nu_1 v_1 s_1\n:\nu_m v_m s_m\n\nOutput\n\nPrint the number of ways to write positive integers in the vertices so that the condition is satisfied.\n\nSample Input 1\n\n3 3\n1 2 3\n2 3 5\n1 3 4\n\nSample Output 1\n\n1\n\nThe condition will be satisfied if we write 1,2 and 3 in vertices 1,2 and 3, respectively.\nThere is no other way to satisfy the condition, so the answer is 1.\n\nSample Input 2\n\n4 3\n1 2 6\n2 3 7\n3 4 5\n\nSample Output 2\n\n3\n\nLet a,b,c and d be the numbers to write in vertices 1,2,3 and 4, respectively.\nThere are three quadruples (a,b,c,d) that satisfy the condition:\n\n(a,b,c,d)=(1,5,2,3)\n\n(a,b,c,d)=(2,4,3,2)\n\n(a,b,c,d)=(3,3,4,1)\n\nSample Input 3\n\n8 7\n1 2 1000000000\n2 3 2\n3 4 1000000000\n4 5 2\n5 6 1000000000\n6 7 2\n7 8 1000000000\n\nSample Output 3\n\n0", "sample_input": "3 3\n1 2 3\n2 3 5\n1 3 4\n"}, "reference_outputs": ["1\n"], "source_document_id": "p03306", "source_text": "Score : 600 points\n\nProblem Statement\n\nKenkoooo found a simple connected graph.\nThe vertices are numbered 1 through n.\nThe i-th edge connects Vertex u_i and v_i, and has a fixed integer s_i.\n\nKenkoooo is trying to write a positive integer in each vertex so that the following condition is satisfied:\n\nFor every edge i, the sum of the positive integers written in Vertex u_i and v_i is equal to s_i.\n\nFind the number of such ways to write positive integers in the vertices.\n\nConstraints\n\n2 \\leq n \\leq 10^5\n\n1 \\leq m \\leq 10^5\n\n1 \\leq u_i < v_i \\leq n\n\n2 \\leq s_i \\leq 10^9\n\nIf i\\neq j, then u_i \\neq u_j or v_i \\neq v_j.\n\nThe graph is connected.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn m\nu_1 v_1 s_1\n:\nu_m v_m s_m\n\nOutput\n\nPrint the number of ways to write positive integers in the vertices so that the condition is satisfied.\n\nSample Input 1\n\n3 3\n1 2 3\n2 3 5\n1 3 4\n\nSample Output 1\n\n1\n\nThe condition will be satisfied if we write 1,2 and 3 in vertices 1,2 and 3, respectively.\nThere is no other way to satisfy the condition, so the answer is 1.\n\nSample Input 2\n\n4 3\n1 2 6\n2 3 7\n3 4 5\n\nSample Output 2\n\n3\n\nLet a,b,c and d be the numbers to write in vertices 1,2,3 and 4, respectively.\nThere are three quadruples (a,b,c,d) that satisfy the condition:\n\n(a,b,c,d)=(1,5,2,3)\n\n(a,b,c,d)=(2,4,3,2)\n\n(a,b,c,d)=(3,3,4,1)\n\nSample Input 3\n\n8 7\n1 2 1000000000\n2 3 2\n3 4 1000000000\n4 5 2\n5 6 1000000000\n6 7 2\n7 8 1000000000\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 3493, "cpu_time_ms": 125, "memory_kb": 9600}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s348288068", "group_id": "codeNet:p03306", "input_text": "#include <cstdio>\n#include <vector>\n#include <utility>\n#include <tuple>\n#include <cstring>\n#include <iostream>\nusing namespace std;\n\nint N, M;\nusing Graph = vector< vector< pair<int, int> > >;\n\nconst int INF = 1 << 28;\nbool is_bipartite = true, exist_solution = true;\nint color[100010], value[100010], start_val = -INF;\n\nvoid dfs(Graph &G, int cur, int par=-1, int verify=false) {\n    for(auto e : G[cur]) {\n        int to, val; tie(to, val) = e;\n        if(to == par) continue;\n\n        if(color[to] >= 0) {\n            if(color[to] == color[cur]) {\n                is_bipartite = false;\n\n                int diff = (value[cur] + value[to]) - val;\n                if(abs(diff) % 2) {\n                    exist_solution = false;\n                }\n                else {\n                    int chg_val;\n                    if(color[cur] == 1) {\n                        chg_val = 1 + diff / 2 * (-1);\n                    }\n                    else {\n                        chg_val = 1 + diff / 2;\n                    }\n\n                    if(start_val == -INF) {\n                        start_val = chg_val;\n                    }\n                    else {\n                        if(start_val != chg_val || chg_val <= 0) {\n                            exist_solution = false;\n                        }\n                    }\n                }\n            }\n        }\n        else {\n            color[to] = 1 - color[cur];\n            value[to] = val - value[cur];\n            if(verify && value[to] <= 0) exist_solution = false;\n            dfs(G, to, cur);\n        }\n    }\n}\n\nint main() {\n    scanf(\"%d%d\", &N, &M);\n\n    Graph G(N);\n    for(int i=0; i<M; i++) {\n        int u, v, s; scanf(\"%d%d%d\", &u, &v, &s);\n        u--; v--;\n        G[u].push_back(make_pair(v, s));\n        G[v].push_back(make_pair(u, s));\n    }\n\n    memset(color, -1, sizeof(color));\n    value[0] = color[0] = 1;\n    dfs(G, 0, -1, false);\n\n    if(is_bipartite) {\n        // color[i] == 1 側について、どれだけ上げないと成立しないか\n        // color[i] == 0 側について、どれだけ余裕があるか\n        int m1 = 0, m2 = INF;\n        for(int i=0; i<N; i++) {\n            if(color[i] == 1) {\n                m1 = max(m1, -value[i] + 1);\n            }\n            else {\n                m2 = min(m2,  value[i] - 1);\n            }\n        }\n\n        if(m2 < 0 || m1 > m2) {\n            cout << 0 << endl;\n        }\n        else {\n            cout << m2 - m1 + 1 << endl;\n        }\n    }\n    else {\n        memset(color, -1, sizeof(color));\n        value[0] = start_val;\n        color[0] = 1;\n        dfs(G, 0, -1, true);\n\n        cout << exist_solution << endl;\n    }\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1531285695, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03306.html", "problem_id": "p03306", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03306/input.txt", "sample_output_relpath": "derived/input_output/data/p03306/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03306/C++/s348288068.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s348288068", "user_id": "u119460590"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <cstdio>\n#include <vector>\n#include <utility>\n#include <tuple>\n#include <cstring>\n#include <iostream>\nusing namespace std;\n\nint N, M;\nusing Graph = vector< vector< pair<int, int> > >;\n\nconst int INF = 1 << 28;\nbool is_bipartite = true, exist_solution = true;\nint color[100010], value[100010], start_val = -INF;\n\nvoid dfs(Graph &G, int cur, int par=-1, int verify=false) {\n    for(auto e : G[cur]) {\n        int to, val; tie(to, val) = e;\n        if(to == par) continue;\n\n        if(color[to] >= 0) {\n            if(color[to] == color[cur]) {\n                is_bipartite = false;\n\n                int diff = (value[cur] + value[to]) - val;\n                if(abs(diff) % 2) {\n                    exist_solution = false;\n                }\n                else {\n                    int chg_val;\n                    if(color[cur] == 1) {\n                        chg_val = 1 + diff / 2 * (-1);\n                    }\n                    else {\n                        chg_val = 1 + diff / 2;\n                    }\n\n                    if(start_val == -INF) {\n                        start_val = chg_val;\n                    }\n                    else {\n                        if(start_val != chg_val || chg_val <= 0) {\n                            exist_solution = false;\n                        }\n                    }\n                }\n            }\n        }\n        else {\n            color[to] = 1 - color[cur];\n            value[to] = val - value[cur];\n            if(verify && value[to] <= 0) exist_solution = false;\n            dfs(G, to, cur);\n        }\n    }\n}\n\nint main() {\n    scanf(\"%d%d\", &N, &M);\n\n    Graph G(N);\n    for(int i=0; i<M; i++) {\n        int u, v, s; scanf(\"%d%d%d\", &u, &v, &s);\n        u--; v--;\n        G[u].push_back(make_pair(v, s));\n        G[v].push_back(make_pair(u, s));\n    }\n\n    memset(color, -1, sizeof(color));\n    value[0] = color[0] = 1;\n    dfs(G, 0, -1, false);\n\n    if(is_bipartite) {\n        // color[i] == 1 側について、どれだけ上げないと成立しないか\n        // color[i] == 0 側について、どれだけ余裕があるか\n        int m1 = 0, m2 = INF;\n        for(int i=0; i<N; i++) {\n            if(color[i] == 1) {\n                m1 = max(m1, -value[i] + 1);\n            }\n            else {\n                m2 = min(m2,  value[i] - 1);\n            }\n        }\n\n        if(m2 < 0 || m1 > m2) {\n            cout << 0 << endl;\n        }\n        else {\n            cout << m2 - m1 + 1 << endl;\n        }\n    }\n    else {\n        memset(color, -1, sizeof(color));\n        value[0] = start_val;\n        color[0] = 1;\n        dfs(G, 0, -1, true);\n\n        cout << exist_solution << endl;\n    }\n    return 0;\n}\n", "problem_context": "Score : 600 points\n\nProblem Statement\n\nKenkoooo found a simple connected graph.\nThe vertices are numbered 1 through n.\nThe i-th edge connects Vertex u_i and v_i, and has a fixed integer s_i.\n\nKenkoooo is trying to write a positive integer in each vertex so that the following condition is satisfied:\n\nFor every edge i, the sum of the positive integers written in Vertex u_i and v_i is equal to s_i.\n\nFind the number of such ways to write positive integers in the vertices.\n\nConstraints\n\n2 \\leq n \\leq 10^5\n\n1 \\leq m \\leq 10^5\n\n1 \\leq u_i < v_i \\leq n\n\n2 \\leq s_i \\leq 10^9\n\nIf i\\neq j, then u_i \\neq u_j or v_i \\neq v_j.\n\nThe graph is connected.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn m\nu_1 v_1 s_1\n:\nu_m v_m s_m\n\nOutput\n\nPrint the number of ways to write positive integers in the vertices so that the condition is satisfied.\n\nSample Input 1\n\n3 3\n1 2 3\n2 3 5\n1 3 4\n\nSample Output 1\n\n1\n\nThe condition will be satisfied if we write 1,2 and 3 in vertices 1,2 and 3, respectively.\nThere is no other way to satisfy the condition, so the answer is 1.\n\nSample Input 2\n\n4 3\n1 2 6\n2 3 7\n3 4 5\n\nSample Output 2\n\n3\n\nLet a,b,c and d be the numbers to write in vertices 1,2,3 and 4, respectively.\nThere are three quadruples (a,b,c,d) that satisfy the condition:\n\n(a,b,c,d)=(1,5,2,3)\n\n(a,b,c,d)=(2,4,3,2)\n\n(a,b,c,d)=(3,3,4,1)\n\nSample Input 3\n\n8 7\n1 2 1000000000\n2 3 2\n3 4 1000000000\n4 5 2\n5 6 1000000000\n6 7 2\n7 8 1000000000\n\nSample Output 3\n\n0", "sample_input": "3 3\n1 2 3\n2 3 5\n1 3 4\n"}, "reference_outputs": ["1\n"], "source_document_id": "p03306", "source_text": "Score : 600 points\n\nProblem Statement\n\nKenkoooo found a simple connected graph.\nThe vertices are numbered 1 through n.\nThe i-th edge connects Vertex u_i and v_i, and has a fixed integer s_i.\n\nKenkoooo is trying to write a positive integer in each vertex so that the following condition is satisfied:\n\nFor every edge i, the sum of the positive integers written in Vertex u_i and v_i is equal to s_i.\n\nFind the number of such ways to write positive integers in the vertices.\n\nConstraints\n\n2 \\leq n \\leq 10^5\n\n1 \\leq m \\leq 10^5\n\n1 \\leq u_i < v_i \\leq n\n\n2 \\leq s_i \\leq 10^9\n\nIf i\\neq j, then u_i \\neq u_j or v_i \\neq v_j.\n\nThe graph is connected.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn m\nu_1 v_1 s_1\n:\nu_m v_m s_m\n\nOutput\n\nPrint the number of ways to write positive integers in the vertices so that the condition is satisfied.\n\nSample Input 1\n\n3 3\n1 2 3\n2 3 5\n1 3 4\n\nSample Output 1\n\n1\n\nThe condition will be satisfied if we write 1,2 and 3 in vertices 1,2 and 3, respectively.\nThere is no other way to satisfy the condition, so the answer is 1.\n\nSample Input 2\n\n4 3\n1 2 6\n2 3 7\n3 4 5\n\nSample Output 2\n\n3\n\nLet a,b,c and d be the numbers to write in vertices 1,2,3 and 4, respectively.\nThere are three quadruples (a,b,c,d) that satisfy the condition:\n\n(a,b,c,d)=(1,5,2,3)\n\n(a,b,c,d)=(2,4,3,2)\n\n(a,b,c,d)=(3,3,4,1)\n\nSample Input 3\n\n8 7\n1 2 1000000000\n2 3 2\n3 4 1000000000\n4 5 2\n5 6 1000000000\n6 7 2\n7 8 1000000000\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2685, "cpu_time_ms": 58, "memory_kb": 14336}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s740482338", "group_id": "codeNet:p03308", "input_text": "#include<bits/stdc++.h>\ntypedef long long int ll;\nusing namespace std;\nint main()\n{\n    ios_base::sync_with_stdio(false);\n    cin.tie(0);\n    ll n,i,x,sum=0,summ,j;\n    cin>>n;\n    int a[n];\n    for(i=0; i<n; i++){\n        cin>>a[i];\n        sum+=abs(a[i]-i-1);\n    }\n    x=ceil((double)sum/n);\n    for(j=summ=0; j<n; j++){\n            summ+=abs(a[j]-x-j-1);\n    }\n    sum=min(sum,summ);\n    x*=(-1);\n    for(j=summ=0; j<n; j++){\n        summ+=abs(a[j]-x-j-1);\n    }\n    sum=min(sum,summ);\n    cout<<sum<<endl;\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1586666750, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03308.html", "problem_id": "p03308", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03308/input.txt", "sample_output_relpath": "derived/input_output/data/p03308/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03308/C++/s740482338.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s740482338", "user_id": "u816631826"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include<bits/stdc++.h>\ntypedef long long int ll;\nusing namespace std;\nint main()\n{\n    ios_base::sync_with_stdio(false);\n    cin.tie(0);\n    ll n,i,x,sum=0,summ,j;\n    cin>>n;\n    int a[n];\n    for(i=0; i<n; i++){\n        cin>>a[i];\n        sum+=abs(a[i]-i-1);\n    }\n    x=ceil((double)sum/n);\n    for(j=summ=0; j<n; j++){\n            summ+=abs(a[j]-x-j-1);\n    }\n    sum=min(sum,summ);\n    x*=(-1);\n    for(j=summ=0; j<n; j++){\n        summ+=abs(a[j]-x-j-1);\n    }\n    sum=min(sum,summ);\n    cout<<sum<<endl;\n    return 0;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nYou are given an integer sequence A of length N.\nFind the maximum absolute difference of two elements (with different indices) in A.\n\nConstraints\n\n2 \\leq N \\leq 100\n\n1 \\leq A_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the maximum absolute difference of two elements (with different indices) in A.\n\nSample Input 1\n\n4\n1 4 6 3\n\nSample Output 1\n\n5\n\nThe maximum absolute difference of two elements is A_3-A_1=6-1=5.\n\nSample Input 2\n\n2\n1000000000 1\n\nSample Output 2\n\n999999999\n\nSample Input 3\n\n5\n1 1 1 1 1\n\nSample Output 3\n\n0", "sample_input": "4\n1 4 6 3\n"}, "reference_outputs": ["5\n"], "source_document_id": "p03308", "source_text": "Score : 200 points\n\nProblem Statement\n\nYou are given an integer sequence A of length N.\nFind the maximum absolute difference of two elements (with different indices) in A.\n\nConstraints\n\n2 \\leq N \\leq 100\n\n1 \\leq A_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the maximum absolute difference of two elements (with different indices) in A.\n\nSample Input 1\n\n4\n1 4 6 3\n\nSample Output 1\n\n5\n\nThe maximum absolute difference of two elements is A_3-A_1=6-1=5.\n\nSample Input 2\n\n2\n1000000000 1\n\nSample Output 2\n\n999999999\n\nSample Input 3\n\n5\n1 1 1 1 1\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 527, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s601049988", "group_id": "codeNet:p03308", "input_text": "#include<iostream>\n#include<cmath>\nusing namespace std;\nint main()\n{\n    int n;\n    cin>>n;\n    int ar[n];\n    for(int i=0; i<n; i++)\n        cin>>ar[i];\n     int big=0;\n     int low=0;\n     if(n==2)\n     {\n        big=ar[0];\n        low=ar[1];\n     }\n     else{\n    for(int i=0; i<n; i++)\n    {\n        if(ar[i]>ar[i+1]){\n            big=ar[i];\n            ar[i+1]=ar[i];}\n        else\n            big=ar[i+1];\n\n\n        if(ar[i]<ar[i+1]){\n            low=ar[i];\n            ar[i+1]=ar[i];}\n        else\n            low=ar[i+1];\n    }\n     }\n    cout<<abs(big-low)<<endl;\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1573285902, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03308.html", "problem_id": "p03308", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03308/input.txt", "sample_output_relpath": "derived/input_output/data/p03308/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03308/C++/s601049988.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s601049988", "user_id": "u018679195"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include<iostream>\n#include<cmath>\nusing namespace std;\nint main()\n{\n    int n;\n    cin>>n;\n    int ar[n];\n    for(int i=0; i<n; i++)\n        cin>>ar[i];\n     int big=0;\n     int low=0;\n     if(n==2)\n     {\n        big=ar[0];\n        low=ar[1];\n     }\n     else{\n    for(int i=0; i<n; i++)\n    {\n        if(ar[i]>ar[i+1]){\n            big=ar[i];\n            ar[i+1]=ar[i];}\n        else\n            big=ar[i+1];\n\n\n        if(ar[i]<ar[i+1]){\n            low=ar[i];\n            ar[i+1]=ar[i];}\n        else\n            low=ar[i+1];\n    }\n     }\n    cout<<abs(big-low)<<endl;\n    return 0;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nYou are given an integer sequence A of length N.\nFind the maximum absolute difference of two elements (with different indices) in A.\n\nConstraints\n\n2 \\leq N \\leq 100\n\n1 \\leq A_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the maximum absolute difference of two elements (with different indices) in A.\n\nSample Input 1\n\n4\n1 4 6 3\n\nSample Output 1\n\n5\n\nThe maximum absolute difference of two elements is A_3-A_1=6-1=5.\n\nSample Input 2\n\n2\n1000000000 1\n\nSample Output 2\n\n999999999\n\nSample Input 3\n\n5\n1 1 1 1 1\n\nSample Output 3\n\n0", "sample_input": "4\n1 4 6 3\n"}, "reference_outputs": ["5\n"], "source_document_id": "p03308", "source_text": "Score : 200 points\n\nProblem Statement\n\nYou are given an integer sequence A of length N.\nFind the maximum absolute difference of two elements (with different indices) in A.\n\nConstraints\n\n2 \\leq N \\leq 100\n\n1 \\leq A_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the maximum absolute difference of two elements (with different indices) in A.\n\nSample Input 1\n\n4\n1 4 6 3\n\nSample Output 1\n\n5\n\nThe maximum absolute difference of two elements is A_3-A_1=6-1=5.\n\nSample Input 2\n\n2\n1000000000 1\n\nSample Output 2\n\n999999999\n\nSample Input 3\n\n5\n1 1 1 1 1\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 589, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s902823676", "group_id": "codeNet:p03308", "input_text": "#include <stdio.h>\nint main(void)\n{\n\tint a, max = 1, min = 100000000,i;\n\tfloat c;\n\tscanf(\"%d\", &a);\n\tfor (i = 0; i < a; i++) {\n\t\tscanf(\"%f\", &c);\n\t\tif (c > max)max = c;\n\t\tif (c < min) {\n\t\t\tmin = c;\n\t\t}\n\t}\n\tprintf(\"%d\\n\", max - min);\n\treturn 0;\n}\n\n", "language": "C++", "metadata": {"date": 1530653513, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03308.html", "problem_id": "p03308", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03308/input.txt", "sample_output_relpath": "derived/input_output/data/p03308/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03308/C++/s902823676.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s902823676", "user_id": "u432507450"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include <stdio.h>\nint main(void)\n{\n\tint a, max = 1, min = 100000000,i;\n\tfloat c;\n\tscanf(\"%d\", &a);\n\tfor (i = 0; i < a; i++) {\n\t\tscanf(\"%f\", &c);\n\t\tif (c > max)max = c;\n\t\tif (c < min) {\n\t\t\tmin = c;\n\t\t}\n\t}\n\tprintf(\"%d\\n\", max - min);\n\treturn 0;\n}\n\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nYou are given an integer sequence A of length N.\nFind the maximum absolute difference of two elements (with different indices) in A.\n\nConstraints\n\n2 \\leq N \\leq 100\n\n1 \\leq A_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the maximum absolute difference of two elements (with different indices) in A.\n\nSample Input 1\n\n4\n1 4 6 3\n\nSample Output 1\n\n5\n\nThe maximum absolute difference of two elements is A_3-A_1=6-1=5.\n\nSample Input 2\n\n2\n1000000000 1\n\nSample Output 2\n\n999999999\n\nSample Input 3\n\n5\n1 1 1 1 1\n\nSample Output 3\n\n0", "sample_input": "4\n1 4 6 3\n"}, "reference_outputs": ["5\n"], "source_document_id": "p03308", "source_text": "Score : 200 points\n\nProblem Statement\n\nYou are given an integer sequence A of length N.\nFind the maximum absolute difference of two elements (with different indices) in A.\n\nConstraints\n\n2 \\leq N \\leq 100\n\n1 \\leq A_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the maximum absolute difference of two elements (with different indices) in A.\n\nSample Input 1\n\n4\n1 4 6 3\n\nSample Output 1\n\n5\n\nThe maximum absolute difference of two elements is A_3-A_1=6-1=5.\n\nSample Input 2\n\n2\n1000000000 1\n\nSample Output 2\n\n999999999\n\nSample Input 3\n\n5\n1 1 1 1 1\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 247, "cpu_time_ms": 1, "memory_kb": 128}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s995374086", "group_id": "codeNet:p03309", "input_text": "#include <iostream>\n#include <algorithm>\n#include <string>\n#include <string.h>\n#include <stdlib.h>\n#include <math.h>\n#include <vector>\n#include <queue>\n#include <stack>\n#include <cmath>\n#include <map>\n#include <iomanip>\n#include <set>\nusing namespace std;\n\n#define rep(i, s) for (int i = 0; i < s; ++i)\n#define all(v) (v.begin(), v.end())\n#define COUT(x) cout << #x << \" = \" << (x) << \" (L\" << __LINE__ << \")\" << endl\n#define EACH(i, s) for (__typeof__((s).begin()) i = (s).begin(); i != (s).end(); ++i)\n#define VEC(a, n) vector<int>a(n)\n#define PQ(a) priority_queue<int>a\n#define PQmin(a) priority_queue< int, :vector<int>, greater<int> >a\n#define PAIR pair<int, int>\n/*\nsort(sp.begin(), sp.end(), [](PAIR l, PAIR r){\n        return l.first<r.first || (l.first==r.first && l.second > r.second);\n        });\n*/\n\ntypedef long long  ll;\n\n#define EPS (1e-7)\n#define INF (1e9)\n#define PI (acos(-1))\n\ntemplate<class T> inline bool chmin(T& a, T b) {\n    if (a > b) {\n        a = b;\n        return true;\n    }\n    return false;\n}\ntemplate<class T> inline bool chmax(T& a, T b) {\n    if (a < b) {\n        a = b;\n        return true;\n    }\n    return false;\n}\n\nint main() {\n    int n;\n    cin>>n;\n    vector<int>a(n);\n    for(int i=0;i<n;i++){\n        int x;\n        cin>>x;\n        a.at(i)=x-(i+1);\n    }\n    double AVE=0;\n    for(int i=0;i<n;i++){\n        AVE+=a.at(i);\n    }\n    AVE/=n;\n    int ans=1000000000;\n    for(int i=-1000;i<=1000;i++){\n        int SUM=0;\n        for(int j=0;j<n;j++){\n            SUM+=abs(a.at(j)-(int)AVE+i);\n        }\n        ans=min(ans,SUM);\n    }\n    cout<<ans<<endl;\n\n\n\n\n\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1568909530, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03309.html", "problem_id": "p03309", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03309/input.txt", "sample_output_relpath": "derived/input_output/data/p03309/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03309/C++/s995374086.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s995374086", "user_id": "u275934251"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <iostream>\n#include <algorithm>\n#include <string>\n#include <string.h>\n#include <stdlib.h>\n#include <math.h>\n#include <vector>\n#include <queue>\n#include <stack>\n#include <cmath>\n#include <map>\n#include <iomanip>\n#include <set>\nusing namespace std;\n\n#define rep(i, s) for (int i = 0; i < s; ++i)\n#define all(v) (v.begin(), v.end())\n#define COUT(x) cout << #x << \" = \" << (x) << \" (L\" << __LINE__ << \")\" << endl\n#define EACH(i, s) for (__typeof__((s).begin()) i = (s).begin(); i != (s).end(); ++i)\n#define VEC(a, n) vector<int>a(n)\n#define PQ(a) priority_queue<int>a\n#define PQmin(a) priority_queue< int, :vector<int>, greater<int> >a\n#define PAIR pair<int, int>\n/*\nsort(sp.begin(), sp.end(), [](PAIR l, PAIR r){\n        return l.first<r.first || (l.first==r.first && l.second > r.second);\n        });\n*/\n\ntypedef long long  ll;\n\n#define EPS (1e-7)\n#define INF (1e9)\n#define PI (acos(-1))\n\ntemplate<class T> inline bool chmin(T& a, T b) {\n    if (a > b) {\n        a = b;\n        return true;\n    }\n    return false;\n}\ntemplate<class T> inline bool chmax(T& a, T b) {\n    if (a < b) {\n        a = b;\n        return true;\n    }\n    return false;\n}\n\nint main() {\n    int n;\n    cin>>n;\n    vector<int>a(n);\n    for(int i=0;i<n;i++){\n        int x;\n        cin>>x;\n        a.at(i)=x-(i+1);\n    }\n    double AVE=0;\n    for(int i=0;i<n;i++){\n        AVE+=a.at(i);\n    }\n    AVE/=n;\n    int ans=1000000000;\n    for(int i=-1000;i<=1000;i++){\n        int SUM=0;\n        for(int j=0;j<n;j++){\n            SUM+=abs(a.at(j)-(int)AVE+i);\n        }\n        ans=min(ans,SUM);\n    }\n    cout<<ans<<endl;\n\n\n\n\n\n    return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nSnuke has an integer sequence A of length N.\n\nHe will freely choose an integer b.\nHere, he will get sad if A_i and b+i are far from each other.\nMore specifically, the sadness of Snuke is calculated as follows:\n\nabs(A_1 - (b+1)) + abs(A_2 - (b+2)) + ... + abs(A_N - (b+N))\n\nHere, abs(x) is a function that returns the absolute value of x.\n\nFind the minimum possible sadness of Snuke.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq A_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the minimum possible sadness of Snuke.\n\nSample Input 1\n\n5\n2 2 3 5 5\n\nSample Output 1\n\n2\n\nIf we choose b=0, the sadness of Snuke would be abs(2-(0+1))+abs(2-(0+2))+abs(3-(0+3))+abs(5-(0+4))+abs(5-(0+5))=2.\nAny choice of b does not make the sadness of Snuke less than 2, so the answer is 2.\n\nSample Input 2\n\n9\n1 2 3 4 5 6 7 8 9\n\nSample Output 2\n\n0\n\nSample Input 3\n\n6\n6 5 4 3 2 1\n\nSample Output 3\n\n18\n\nSample Input 4\n\n7\n1 1 1 1 2 3 4\n\nSample Output 4\n\n6", "sample_input": "5\n2 2 3 5 5\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03309", "source_text": "Score : 300 points\n\nProblem Statement\n\nSnuke has an integer sequence A of length N.\n\nHe will freely choose an integer b.\nHere, he will get sad if A_i and b+i are far from each other.\nMore specifically, the sadness of Snuke is calculated as follows:\n\nabs(A_1 - (b+1)) + abs(A_2 - (b+2)) + ... + abs(A_N - (b+N))\n\nHere, abs(x) is a function that returns the absolute value of x.\n\nFind the minimum possible sadness of Snuke.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq A_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the minimum possible sadness of Snuke.\n\nSample Input 1\n\n5\n2 2 3 5 5\n\nSample Output 1\n\n2\n\nIf we choose b=0, the sadness of Snuke would be abs(2-(0+1))+abs(2-(0+2))+abs(3-(0+3))+abs(5-(0+4))+abs(5-(0+5))=2.\nAny choice of b does not make the sadness of Snuke less than 2, so the answer is 2.\n\nSample Input 2\n\n9\n1 2 3 4 5 6 7 8 9\n\nSample Output 2\n\n0\n\nSample Input 3\n\n6\n6 5 4 3 2 1\n\nSample Output 3\n\n18\n\nSample Input 4\n\n7\n1 1 1 1 2 3 4\n\nSample Output 4\n\n6", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1615, "cpu_time_ms": 600, "memory_kb": 1024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s081070854", "group_id": "codeNet:p03309", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n\nint main(void){\n    int N; cin >> N;\n    vector<int> A(N);\n    for(int i=0; i<N; i++){\n        int a; cin >> a;\n        A[i]=a-(i+1);\n    }\n\n    sort(A.begin(), A.end());\n    int b=A[(N-1)/2];\n    ll ans=0;\n\n    for(int i=0; i<N; i++) ans+=abs(A[i]-b);\n\n    cout << ans << endl;\n}", "language": "C++", "metadata": {"date": 1551043386, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03309.html", "problem_id": "p03309", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03309/input.txt", "sample_output_relpath": "derived/input_output/data/p03309/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03309/C++/s081070854.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s081070854", "user_id": "u052332717"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n\nint main(void){\n    int N; cin >> N;\n    vector<int> A(N);\n    for(int i=0; i<N; i++){\n        int a; cin >> a;\n        A[i]=a-(i+1);\n    }\n\n    sort(A.begin(), A.end());\n    int b=A[(N-1)/2];\n    ll ans=0;\n\n    for(int i=0; i<N; i++) ans+=abs(A[i]-b);\n\n    cout << ans << endl;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nSnuke has an integer sequence A of length N.\n\nHe will freely choose an integer b.\nHere, he will get sad if A_i and b+i are far from each other.\nMore specifically, the sadness of Snuke is calculated as follows:\n\nabs(A_1 - (b+1)) + abs(A_2 - (b+2)) + ... + abs(A_N - (b+N))\n\nHere, abs(x) is a function that returns the absolute value of x.\n\nFind the minimum possible sadness of Snuke.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq A_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the minimum possible sadness of Snuke.\n\nSample Input 1\n\n5\n2 2 3 5 5\n\nSample Output 1\n\n2\n\nIf we choose b=0, the sadness of Snuke would be abs(2-(0+1))+abs(2-(0+2))+abs(3-(0+3))+abs(5-(0+4))+abs(5-(0+5))=2.\nAny choice of b does not make the sadness of Snuke less than 2, so the answer is 2.\n\nSample Input 2\n\n9\n1 2 3 4 5 6 7 8 9\n\nSample Output 2\n\n0\n\nSample Input 3\n\n6\n6 5 4 3 2 1\n\nSample Output 3\n\n18\n\nSample Input 4\n\n7\n1 1 1 1 2 3 4\n\nSample Output 4\n\n6", "sample_input": "5\n2 2 3 5 5\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03309", "source_text": "Score : 300 points\n\nProblem Statement\n\nSnuke has an integer sequence A of length N.\n\nHe will freely choose an integer b.\nHere, he will get sad if A_i and b+i are far from each other.\nMore specifically, the sadness of Snuke is calculated as follows:\n\nabs(A_1 - (b+1)) + abs(A_2 - (b+2)) + ... + abs(A_N - (b+N))\n\nHere, abs(x) is a function that returns the absolute value of x.\n\nFind the minimum possible sadness of Snuke.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq A_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the minimum possible sadness of Snuke.\n\nSample Input 1\n\n5\n2 2 3 5 5\n\nSample Output 1\n\n2\n\nIf we choose b=0, the sadness of Snuke would be abs(2-(0+1))+abs(2-(0+2))+abs(3-(0+3))+abs(5-(0+4))+abs(5-(0+5))=2.\nAny choice of b does not make the sadness of Snuke less than 2, so the answer is 2.\n\nSample Input 2\n\n9\n1 2 3 4 5 6 7 8 9\n\nSample Output 2\n\n0\n\nSample Input 3\n\n6\n6 5 4 3 2 1\n\nSample Output 3\n\n18\n\nSample Input 4\n\n7\n1 1 1 1 2 3 4\n\nSample Output 4\n\n6", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 349, "cpu_time_ms": 93, "memory_kb": 1024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s197647332", "group_id": "codeNet:p03309", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef pair<int,int> pii;\n#define ll long long int\n#define pb push_back\n#define mp make_pair\n#define boost ios_base::sync_with_stdio(false),cin.tie(0),cout.tie(0)\n#define forn(i, n) for(int i = 0; i < (int)(n); i++)\n#define ford(i, n) for(int i = (int)(n) - 1; i >= 0; i--)\n#define F first\n#define S second\n#define mset(x,v) memset(x, v, sizeof(x))\n#define left(x) 2*x\n#define right(x) (2*x) + 1\n#define ALL(t) (t).begin(),(t).end() \n#define ret return 0\n#define all(x) x.begin(),x.end()\nll n;\nint main()\n{\n    boost;\n           cin>>n;\n           ll arr[n+1];\n           for(int i=1;i<=n;i++)\n           {\n                 cin>>arr[i];\n                 arr[i]=arr[i]-i-1;\n           }\n           sort(arr+1,arr+n+1);\n           ll med=arr[n/2];\n           ll ans=0;\n           for(int i=1;i<=n;i++)\n           {\n                 ans+=abs(med-arr[i]);\n           }\n           cout<<ans<<endl;\n}\n   ", "language": "C++", "metadata": {"date": 1530498360, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03309.html", "problem_id": "p03309", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03309/input.txt", "sample_output_relpath": "derived/input_output/data/p03309/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03309/C++/s197647332.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s197647332", "user_id": "u506490998"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef pair<int,int> pii;\n#define ll long long int\n#define pb push_back\n#define mp make_pair\n#define boost ios_base::sync_with_stdio(false),cin.tie(0),cout.tie(0)\n#define forn(i, n) for(int i = 0; i < (int)(n); i++)\n#define ford(i, n) for(int i = (int)(n) - 1; i >= 0; i--)\n#define F first\n#define S second\n#define mset(x,v) memset(x, v, sizeof(x))\n#define left(x) 2*x\n#define right(x) (2*x) + 1\n#define ALL(t) (t).begin(),(t).end() \n#define ret return 0\n#define all(x) x.begin(),x.end()\nll n;\nint main()\n{\n    boost;\n           cin>>n;\n           ll arr[n+1];\n           for(int i=1;i<=n;i++)\n           {\n                 cin>>arr[i];\n                 arr[i]=arr[i]-i-1;\n           }\n           sort(arr+1,arr+n+1);\n           ll med=arr[n/2];\n           ll ans=0;\n           for(int i=1;i<=n;i++)\n           {\n                 ans+=abs(med-arr[i]);\n           }\n           cout<<ans<<endl;\n}\n   ", "problem_context": "Score : 300 points\n\nProblem Statement\n\nSnuke has an integer sequence A of length N.\n\nHe will freely choose an integer b.\nHere, he will get sad if A_i and b+i are far from each other.\nMore specifically, the sadness of Snuke is calculated as follows:\n\nabs(A_1 - (b+1)) + abs(A_2 - (b+2)) + ... + abs(A_N - (b+N))\n\nHere, abs(x) is a function that returns the absolute value of x.\n\nFind the minimum possible sadness of Snuke.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq A_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the minimum possible sadness of Snuke.\n\nSample Input 1\n\n5\n2 2 3 5 5\n\nSample Output 1\n\n2\n\nIf we choose b=0, the sadness of Snuke would be abs(2-(0+1))+abs(2-(0+2))+abs(3-(0+3))+abs(5-(0+4))+abs(5-(0+5))=2.\nAny choice of b does not make the sadness of Snuke less than 2, so the answer is 2.\n\nSample Input 2\n\n9\n1 2 3 4 5 6 7 8 9\n\nSample Output 2\n\n0\n\nSample Input 3\n\n6\n6 5 4 3 2 1\n\nSample Output 3\n\n18\n\nSample Input 4\n\n7\n1 1 1 1 2 3 4\n\nSample Output 4\n\n6", "sample_input": "5\n2 2 3 5 5\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03309", "source_text": "Score : 300 points\n\nProblem Statement\n\nSnuke has an integer sequence A of length N.\n\nHe will freely choose an integer b.\nHere, he will get sad if A_i and b+i are far from each other.\nMore specifically, the sadness of Snuke is calculated as follows:\n\nabs(A_1 - (b+1)) + abs(A_2 - (b+2)) + ... + abs(A_N - (b+N))\n\nHere, abs(x) is a function that returns the absolute value of x.\n\nFind the minimum possible sadness of Snuke.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq A_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the minimum possible sadness of Snuke.\n\nSample Input 1\n\n5\n2 2 3 5 5\n\nSample Output 1\n\n2\n\nIf we choose b=0, the sadness of Snuke would be abs(2-(0+1))+abs(2-(0+2))+abs(3-(0+3))+abs(5-(0+4))+abs(5-(0+5))=2.\nAny choice of b does not make the sadness of Snuke less than 2, so the answer is 2.\n\nSample Input 2\n\n9\n1 2 3 4 5 6 7 8 9\n\nSample Output 2\n\n0\n\nSample Input 3\n\n6\n6 5 4 3 2 1\n\nSample Output 3\n\n18\n\nSample Input 4\n\n7\n1 1 1 1 2 3 4\n\nSample Output 4\n\n6", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 944, "cpu_time_ms": 33, "memory_kb": 1792}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s462633351", "group_id": "codeNet:p03309", "input_text": "#include <bits/stdc++.h>\n \n#define FOR(i,a,b) for(int i=(a);i<(b);++i)\n#define REP(i,n) FOR(i,0,n)\n#define CLR(a) memset((a), 0 ,sizeof(a))\nusing namespace std;\ntypedef unsigned long long ull;\ntypedef long long ll;\ntypedef vector<int> vi;\ntypedef vector<ll> vll;\ntypedef vector<vi> vii;\ntypedef vector<string> vs;\ntypedef pair<int, int> pi;\n#define ALL(a)  (a).begin(),(a).end()\n#define RALL(a) (a).rbegin(), (a).rend()\n#define PB push_back\n#define MKP make_pair\n#define SZ(a) int((a).size())\n#define EACH(i,c) for(typeof((c).begin()) i=(c).begin(); i!=(c).end(); ++i)\n#define EXIST(s,e) ((s).find(e)!=(s).end())\n#define SORT(c) sort((c).begin(),(c).end())\n \nconst int INF = 999999;\nconst double EPS = 1e-10;\nconst double PI = acos(-1.0);\nconst ll MOD = 1000000007;\n \n \n \nll N,sum;\nvll A, ans;\n \nint main()\n{\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tcin >> N;\n\tREP(i, N) {\n\t\tll x;\n        cin >> x;\n\t\tA.push_back(x);\n\t}\n\tREP(i, N) {\n\t\tsum = 0;\n\t\tREP(j, std::accumulate(A.begin(), A.end(), 0) / A.size()) {\n\t\t\tsum += abs(A[j] - j - 1);\n\t\t}\n\t\tans.push_back(sum);\n\t}\n\t\n\tstd::cout << *std::min_element(ans.begin(), ans.end()) << endl;\n\t\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1530494529, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03309.html", "problem_id": "p03309", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03309/input.txt", "sample_output_relpath": "derived/input_output/data/p03309/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03309/C++/s462633351.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s462633351", "user_id": "u325820449"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\n \n#define FOR(i,a,b) for(int i=(a);i<(b);++i)\n#define REP(i,n) FOR(i,0,n)\n#define CLR(a) memset((a), 0 ,sizeof(a))\nusing namespace std;\ntypedef unsigned long long ull;\ntypedef long long ll;\ntypedef vector<int> vi;\ntypedef vector<ll> vll;\ntypedef vector<vi> vii;\ntypedef vector<string> vs;\ntypedef pair<int, int> pi;\n#define ALL(a)  (a).begin(),(a).end()\n#define RALL(a) (a).rbegin(), (a).rend()\n#define PB push_back\n#define MKP make_pair\n#define SZ(a) int((a).size())\n#define EACH(i,c) for(typeof((c).begin()) i=(c).begin(); i!=(c).end(); ++i)\n#define EXIST(s,e) ((s).find(e)!=(s).end())\n#define SORT(c) sort((c).begin(),(c).end())\n \nconst int INF = 999999;\nconst double EPS = 1e-10;\nconst double PI = acos(-1.0);\nconst ll MOD = 1000000007;\n \n \n \nll N,sum;\nvll A, ans;\n \nint main()\n{\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tcin >> N;\n\tREP(i, N) {\n\t\tll x;\n        cin >> x;\n\t\tA.push_back(x);\n\t}\n\tREP(i, N) {\n\t\tsum = 0;\n\t\tREP(j, std::accumulate(A.begin(), A.end(), 0) / A.size()) {\n\t\t\tsum += abs(A[j] - j - 1);\n\t\t}\n\t\tans.push_back(sum);\n\t}\n\t\n\tstd::cout << *std::min_element(ans.begin(), ans.end()) << endl;\n\t\n\treturn 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nSnuke has an integer sequence A of length N.\n\nHe will freely choose an integer b.\nHere, he will get sad if A_i and b+i are far from each other.\nMore specifically, the sadness of Snuke is calculated as follows:\n\nabs(A_1 - (b+1)) + abs(A_2 - (b+2)) + ... + abs(A_N - (b+N))\n\nHere, abs(x) is a function that returns the absolute value of x.\n\nFind the minimum possible sadness of Snuke.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq A_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the minimum possible sadness of Snuke.\n\nSample Input 1\n\n5\n2 2 3 5 5\n\nSample Output 1\n\n2\n\nIf we choose b=0, the sadness of Snuke would be abs(2-(0+1))+abs(2-(0+2))+abs(3-(0+3))+abs(5-(0+4))+abs(5-(0+5))=2.\nAny choice of b does not make the sadness of Snuke less than 2, so the answer is 2.\n\nSample Input 2\n\n9\n1 2 3 4 5 6 7 8 9\n\nSample Output 2\n\n0\n\nSample Input 3\n\n6\n6 5 4 3 2 1\n\nSample Output 3\n\n18\n\nSample Input 4\n\n7\n1 1 1 1 2 3 4\n\nSample Output 4\n\n6", "sample_input": "5\n2 2 3 5 5\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03309", "source_text": "Score : 300 points\n\nProblem Statement\n\nSnuke has an integer sequence A of length N.\n\nHe will freely choose an integer b.\nHere, he will get sad if A_i and b+i are far from each other.\nMore specifically, the sadness of Snuke is calculated as follows:\n\nabs(A_1 - (b+1)) + abs(A_2 - (b+2)) + ... + abs(A_N - (b+N))\n\nHere, abs(x) is a function that returns the absolute value of x.\n\nFind the minimum possible sadness of Snuke.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq A_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the minimum possible sadness of Snuke.\n\nSample Input 1\n\n5\n2 2 3 5 5\n\nSample Output 1\n\n2\n\nIf we choose b=0, the sadness of Snuke would be abs(2-(0+1))+abs(2-(0+2))+abs(3-(0+3))+abs(5-(0+4))+abs(5-(0+5))=2.\nAny choice of b does not make the sadness of Snuke less than 2, so the answer is 2.\n\nSample Input 2\n\n9\n1 2 3 4 5 6 7 8 9\n\nSample Output 2\n\n0\n\nSample Input 3\n\n6\n6 5 4 3 2 1\n\nSample Output 3\n\n18\n\nSample Input 4\n\n7\n1 1 1 1 2 3 4\n\nSample Output 4\n\n6", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1148, "cpu_time_ms": 2103, "memory_kb": 2420}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s771341200", "group_id": "codeNet:p03310", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing VS = vector<string>;    using LL = long long;\nusing VI = vector<int>;       using VVI = vector<VI>;\nusing PII = pair<int, int>;   using PLL = pair<LL, LL>;\nusing VL = vector<LL>;        using VVL = vector<VL>;\n\n#define ALL(a)  begin((a)),end((a))\n#define RALL(a) (a).rbegin(), (a).rend()\n#define SZ(a) int((a).size())\n#define SORT(c) sort(ALL((c)))\n#define RSORT(c) sort(RALL((c)))\n#define UNIQ(c) (c).erase(unique(ALL((c))), end((c)))\n#define FOR(i, s, e) for (int(i) = (s); (i) < (e); (i)++)\n#define FORR(i, s, e) for (int(i) = (s); (i) > (e); (i)--)\n//#pragma GCC optimize (\"-O3\") \n#ifdef YANG33\n#include \"mydebug.hpp\"\n#else\n#define DD(x) \n#endif\nconst int INF = 1e9;                          const LL LINF = 1e16;\nconst LL MOD = 1000000007;                    const double PI = acos(-1.0);\nint DX[8] = { 0, 0, 1, -1, 1, 1, -1, -1 };    int DY[8] = { 1, -1, 0, 0, 1, -1, 1, -1 };\n\n/* -----  __MAKE_TIME__  Problem: __PROBLEM__ / Link: __CONTEST_URL__  ----- */\n/* ------問題------\n\n\n\n-----問題ここまで----- */\n/* -----解説等-----\n\n\n\n----解説ここまで---- */\nstruct Cumusum {\n\tvector<LL>csum;\n\tCumusum(vector<LL>&a) {\n\t\tcsum.assign((int)a.size(), 0);\n\t\tfor (int i = 0; i < (int)a.size(); i++) {\n\t\t\tcsum[i + 1] = csum[i] + a[i];\n\t\t}\n\t}\n\tLL query(int l, int r) {\n\t\treturn csum[r] - csum[l];\n\t}\n};\n\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\n\tLL N;\n\tcin >> N;\n\tVL a(N);\n\tFOR(i, 0, N) {\n\t\tcin >> a[i];\n\t}\n\tCumusum A(a);\n\t// [L,R)を絶対値の差が小さくなるように2つに分割する\n\tauto f = [](Cumusum&A, int Lidx, int Ridx) {\n\t\tLL L = Lidx; LL R = Ridx;\n\t\tFOR(i, 0, 60) {\n\t\t\tint m1 = (2 * L + R) / 3;\n\t\t\tint m2 = (L + 2 * R) / 3;\n\t\t\tLL dif1 = abs(A.query(Lidx, m1) - A.query(m1, Ridx));\n\t\t\tLL dif2 = abs(A.query(Lidx, m2) - A.query(m2, Ridx));\n\t\t\tif (dif1 < dif2) {\n\t\t\t\tR = m2;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tL = m1;\n\t\t\t}\n\t\t}\n\t\tLL Diff = LINF; int midx = 0;\n\t\tFOR(k, 1, R - L) {\n\t\t\tint m = L + k;\n\t\t\tLL diff = abs(A.query(Lidx, m) - A.query(m, Ridx));\n\t\t\tif (Diff > diff) {\n\t\t\t\tDiff = diff;\n\t\t\t\tmidx = m;\n\t\t\t}\n\t\t}\n\t\tassert(Lidx < midx&&midx < Ridx);\n\t\treturn PLL(A.query(Lidx, midx), A.query(midx, Ridx));\n\t};\n\tLL ans = LINF;\n\tFOR(i, 2, N - 1) {\n\t\tPLL ab = f(A, 0, i);//[0,i)\n\t\tPLL cd = f(A, i, N);\n\t\tLL Mx = max({ ab.first,ab.second,cd.first,cd.second });\n\t\tLL Mn = min({ ab.first,ab.second,cd.first,cd.second });\n\t\tans = min(ans, Mx - Mn);\n\t}\n\n\n\tcout << ans << \"\\n\";\n\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1551474766, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03310.html", "problem_id": "p03310", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03310/input.txt", "sample_output_relpath": "derived/input_output/data/p03310/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03310/C++/s771341200.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s771341200", "user_id": "u788341294"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nusing VS = vector<string>;    using LL = long long;\nusing VI = vector<int>;       using VVI = vector<VI>;\nusing PII = pair<int, int>;   using PLL = pair<LL, LL>;\nusing VL = vector<LL>;        using VVL = vector<VL>;\n\n#define ALL(a)  begin((a)),end((a))\n#define RALL(a) (a).rbegin(), (a).rend()\n#define SZ(a) int((a).size())\n#define SORT(c) sort(ALL((c)))\n#define RSORT(c) sort(RALL((c)))\n#define UNIQ(c) (c).erase(unique(ALL((c))), end((c)))\n#define FOR(i, s, e) for (int(i) = (s); (i) < (e); (i)++)\n#define FORR(i, s, e) for (int(i) = (s); (i) > (e); (i)--)\n//#pragma GCC optimize (\"-O3\") \n#ifdef YANG33\n#include \"mydebug.hpp\"\n#else\n#define DD(x) \n#endif\nconst int INF = 1e9;                          const LL LINF = 1e16;\nconst LL MOD = 1000000007;                    const double PI = acos(-1.0);\nint DX[8] = { 0, 0, 1, -1, 1, 1, -1, -1 };    int DY[8] = { 1, -1, 0, 0, 1, -1, 1, -1 };\n\n/* -----  __MAKE_TIME__  Problem: __PROBLEM__ / Link: __CONTEST_URL__  ----- */\n/* ------問題------\n\n\n\n-----問題ここまで----- */\n/* -----解説等-----\n\n\n\n----解説ここまで---- */\nstruct Cumusum {\n\tvector<LL>csum;\n\tCumusum(vector<LL>&a) {\n\t\tcsum.assign((int)a.size(), 0);\n\t\tfor (int i = 0; i < (int)a.size(); i++) {\n\t\t\tcsum[i + 1] = csum[i] + a[i];\n\t\t}\n\t}\n\tLL query(int l, int r) {\n\t\treturn csum[r] - csum[l];\n\t}\n};\n\nint main() {\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\n\tLL N;\n\tcin >> N;\n\tVL a(N);\n\tFOR(i, 0, N) {\n\t\tcin >> a[i];\n\t}\n\tCumusum A(a);\n\t// [L,R)を絶対値の差が小さくなるように2つに分割する\n\tauto f = [](Cumusum&A, int Lidx, int Ridx) {\n\t\tLL L = Lidx; LL R = Ridx;\n\t\tFOR(i, 0, 60) {\n\t\t\tint m1 = (2 * L + R) / 3;\n\t\t\tint m2 = (L + 2 * R) / 3;\n\t\t\tLL dif1 = abs(A.query(Lidx, m1) - A.query(m1, Ridx));\n\t\t\tLL dif2 = abs(A.query(Lidx, m2) - A.query(m2, Ridx));\n\t\t\tif (dif1 < dif2) {\n\t\t\t\tR = m2;\n\t\t\t}\n\t\t\telse {\n\t\t\t\tL = m1;\n\t\t\t}\n\t\t}\n\t\tLL Diff = LINF; int midx = 0;\n\t\tFOR(k, 1, R - L) {\n\t\t\tint m = L + k;\n\t\t\tLL diff = abs(A.query(Lidx, m) - A.query(m, Ridx));\n\t\t\tif (Diff > diff) {\n\t\t\t\tDiff = diff;\n\t\t\t\tmidx = m;\n\t\t\t}\n\t\t}\n\t\tassert(Lidx < midx&&midx < Ridx);\n\t\treturn PLL(A.query(Lidx, midx), A.query(midx, Ridx));\n\t};\n\tLL ans = LINF;\n\tFOR(i, 2, N - 1) {\n\t\tPLL ab = f(A, 0, i);//[0,i)\n\t\tPLL cd = f(A, i, N);\n\t\tLL Mx = max({ ab.first,ab.second,cd.first,cd.second });\n\t\tLL Mn = min({ ab.first,ab.second,cd.first,cd.second });\n\t\tans = min(ans, Mx - Mn);\n\t}\n\n\n\tcout << ans << \"\\n\";\n\n\treturn 0;\n}", "problem_context": "Score : 600 points\n\nProblem Statement\n\nSnuke has an integer sequence A of length N.\n\nHe will make three cuts in A and divide it into four (non-empty) contiguous subsequences B, C, D and E.\nThe positions of the cuts can be freely chosen.\n\nLet P,Q,R,S be the sums of the elements in B,C,D,E, respectively.\nSnuke is happier when the absolute difference of the maximum and the minimum among P,Q,R,S is smaller.\nFind the minimum possible absolute difference of the maximum and the minimum among P,Q,R,S.\n\nConstraints\n\n4 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq A_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nFind the minimum possible absolute difference of the maximum and the minimum among P,Q,R,S.\n\nSample Input 1\n\n5\n3 2 4 1 2\n\nSample Output 1\n\n2\n\nIf we divide A as B,C,D,E=(3),(2),(4),(1,2), then P=3,Q=2,R=4,S=1+2=3.\nHere, the maximum and the minimum among P,Q,R,S are 4 and 2, with the absolute difference of 2.\nWe cannot make the absolute difference of the maximum and the minimum less than 2, so the answer is 2.\n\nSample Input 2\n\n10\n10 71 84 33 6 47 23 25 52 64\n\nSample Output 2\n\n36\n\nSample Input 3\n\n7\n1 2 3 1000000000 4 5 6\n\nSample Output 3\n\n999999994", "sample_input": "5\n3 2 4 1 2\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03310", "source_text": "Score : 600 points\n\nProblem Statement\n\nSnuke has an integer sequence A of length N.\n\nHe will make three cuts in A and divide it into four (non-empty) contiguous subsequences B, C, D and E.\nThe positions of the cuts can be freely chosen.\n\nLet P,Q,R,S be the sums of the elements in B,C,D,E, respectively.\nSnuke is happier when the absolute difference of the maximum and the minimum among P,Q,R,S is smaller.\nFind the minimum possible absolute difference of the maximum and the minimum among P,Q,R,S.\n\nConstraints\n\n4 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq A_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nFind the minimum possible absolute difference of the maximum and the minimum among P,Q,R,S.\n\nSample Input 1\n\n5\n3 2 4 1 2\n\nSample Output 1\n\n2\n\nIf we divide A as B,C,D,E=(3),(2),(4),(1,2), then P=3,Q=2,R=4,S=1+2=3.\nHere, the maximum and the minimum among P,Q,R,S are 4 and 2, with the absolute difference of 2.\nWe cannot make the absolute difference of the maximum and the minimum less than 2, so the answer is 2.\n\nSample Input 2\n\n10\n10 71 84 33 6 47 23 25 52 64\n\nSample Output 2\n\n36\n\nSample Input 3\n\n7\n1 2 3 1000000000 4 5 6\n\nSample Output 3\n\n999999994", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2470, "cpu_time_ms": 216, "memory_kb": 3328}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s284037910", "group_id": "codeNet:p03310", "input_text": "#include<iostream>\n#include<algorithm>\n#include<set>\n#include<math.h>\n#include<vector>\n#include<sstream>\n#include<queue>\n#include<functional>\n#include<bitset>\n#include<cstdio>\n#include<iomanip>\n#include<map>\n#include<unordered_map>\n#include<unordered_set>\n#include <string.h>\nusing ll = long long;\n\n#define rep(i, n) for(ll i = 0; i < (ll)(n); i++)\n#define reps(i,x) for(ll i=1;i<=(ll)(x);i++)\n#define rrep(i,x) for(ll i=((ll)(x)-1);i>=0;i--)\n#define rreps(i,x) for(ll i=(ll)(x);i>0;i--)\n#define all(x) (x).begin(),(x).end()\n#define m0(x) memset(x,0,sizeof(x))\n#define vll vector<ll>\n#define vi vector<int>\n#define vpll vector<pair<ll,ll>>\n#define vpi vector<pair<int,int>>\n#define mod 1000000007 \nusing namespace std;\nint a[200005];\nll dp[200005];\nll b[4];\nint main() {\n\tint n;\n\tcin >> n;\n\trep(i , n)\n\t\tcin >> a[i];\n\tdp[0] = a[0];\n\treps(i, n-1){\n\t\tdp[i] = dp[i-1] + a[i];\t\n\t}\n\tll ans = 1 << 30;\n\tint lf, rt;\n\tlf = 0;\n\trt = 2;\n\tfor(int i = 2; i < n-1; i++){\n\t\tll lmn = 1 << 30;\n\t\tll rmn = 1 << 30;\n\t\tfor(int j = lf; j < i - 1; j++){\n\t\t\tif(lmn > abs(dp[j] -abs(dp[i-1] - dp[j]))){\n\t\t\t\tb[0] = dp[j];\n\t\t\t\tb[1] = (i-1 == j ? dp[i-1] : dp[i-1] -dp[j]);\n\t\t\t\tlmn =abs(dp[j] -abs(dp[i-1] - dp[j]));\n\t\t\t\tlf = j;\n\t\t\t}else{break;}\n\t\t}\n\t\t\tif(i == n - 1 && rmn > abs(dp[n-2] - dp[n-3] -( dp[n-1] -dp[n-2]))){\n\t\t\t\tb[2] = dp[n-2] - dp[n-3];\n\t\t\t\tb[3] = dp[n-1] - dp[n-2];\n\t\t\t}else{\n\t\tfor(int j = rt; j < n; j++){\n\t\t\tif(rmn > abs(abs(dp[j] - dp[i-1]) -abs(dp[n-1] - dp[j]))){\n\t\t\t\tb[2] = dp[j] - dp[i-1];\n\t\t\t\tb[3] = dp[n-1] - dp[j];\n\t\t\t\trmn = abs(abs(dp[j] - dp[i-1]) -abs(dp[n-1] - dp[j]));\n\t\t\t\trt  = j;\n\t\t\t}else{break;}\n\t\t}\n            }\n\t\tsort(b, b+4);\n\t\tans = min(ans, b[3] - b[0]);\n\t}\n\tcout << ans << endl;\n}\n", "language": "C++", "metadata": {"date": 1542590329, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03310.html", "problem_id": "p03310", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03310/input.txt", "sample_output_relpath": "derived/input_output/data/p03310/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03310/C++/s284037910.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s284037910", "user_id": "u926242698"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include<iostream>\n#include<algorithm>\n#include<set>\n#include<math.h>\n#include<vector>\n#include<sstream>\n#include<queue>\n#include<functional>\n#include<bitset>\n#include<cstdio>\n#include<iomanip>\n#include<map>\n#include<unordered_map>\n#include<unordered_set>\n#include <string.h>\nusing ll = long long;\n\n#define rep(i, n) for(ll i = 0; i < (ll)(n); i++)\n#define reps(i,x) for(ll i=1;i<=(ll)(x);i++)\n#define rrep(i,x) for(ll i=((ll)(x)-1);i>=0;i--)\n#define rreps(i,x) for(ll i=(ll)(x);i>0;i--)\n#define all(x) (x).begin(),(x).end()\n#define m0(x) memset(x,0,sizeof(x))\n#define vll vector<ll>\n#define vi vector<int>\n#define vpll vector<pair<ll,ll>>\n#define vpi vector<pair<int,int>>\n#define mod 1000000007 \nusing namespace std;\nint a[200005];\nll dp[200005];\nll b[4];\nint main() {\n\tint n;\n\tcin >> n;\n\trep(i , n)\n\t\tcin >> a[i];\n\tdp[0] = a[0];\n\treps(i, n-1){\n\t\tdp[i] = dp[i-1] + a[i];\t\n\t}\n\tll ans = 1 << 30;\n\tint lf, rt;\n\tlf = 0;\n\trt = 2;\n\tfor(int i = 2; i < n-1; i++){\n\t\tll lmn = 1 << 30;\n\t\tll rmn = 1 << 30;\n\t\tfor(int j = lf; j < i - 1; j++){\n\t\t\tif(lmn > abs(dp[j] -abs(dp[i-1] - dp[j]))){\n\t\t\t\tb[0] = dp[j];\n\t\t\t\tb[1] = (i-1 == j ? dp[i-1] : dp[i-1] -dp[j]);\n\t\t\t\tlmn =abs(dp[j] -abs(dp[i-1] - dp[j]));\n\t\t\t\tlf = j;\n\t\t\t}else{break;}\n\t\t}\n\t\t\tif(i == n - 1 && rmn > abs(dp[n-2] - dp[n-3] -( dp[n-1] -dp[n-2]))){\n\t\t\t\tb[2] = dp[n-2] - dp[n-3];\n\t\t\t\tb[3] = dp[n-1] - dp[n-2];\n\t\t\t}else{\n\t\tfor(int j = rt; j < n; j++){\n\t\t\tif(rmn > abs(abs(dp[j] - dp[i-1]) -abs(dp[n-1] - dp[j]))){\n\t\t\t\tb[2] = dp[j] - dp[i-1];\n\t\t\t\tb[3] = dp[n-1] - dp[j];\n\t\t\t\trmn = abs(abs(dp[j] - dp[i-1]) -abs(dp[n-1] - dp[j]));\n\t\t\t\trt  = j;\n\t\t\t}else{break;}\n\t\t}\n            }\n\t\tsort(b, b+4);\n\t\tans = min(ans, b[3] - b[0]);\n\t}\n\tcout << ans << endl;\n}\n", "problem_context": "Score : 600 points\n\nProblem Statement\n\nSnuke has an integer sequence A of length N.\n\nHe will make three cuts in A and divide it into four (non-empty) contiguous subsequences B, C, D and E.\nThe positions of the cuts can be freely chosen.\n\nLet P,Q,R,S be the sums of the elements in B,C,D,E, respectively.\nSnuke is happier when the absolute difference of the maximum and the minimum among P,Q,R,S is smaller.\nFind the minimum possible absolute difference of the maximum and the minimum among P,Q,R,S.\n\nConstraints\n\n4 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq A_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nFind the minimum possible absolute difference of the maximum and the minimum among P,Q,R,S.\n\nSample Input 1\n\n5\n3 2 4 1 2\n\nSample Output 1\n\n2\n\nIf we divide A as B,C,D,E=(3),(2),(4),(1,2), then P=3,Q=2,R=4,S=1+2=3.\nHere, the maximum and the minimum among P,Q,R,S are 4 and 2, with the absolute difference of 2.\nWe cannot make the absolute difference of the maximum and the minimum less than 2, so the answer is 2.\n\nSample Input 2\n\n10\n10 71 84 33 6 47 23 25 52 64\n\nSample Output 2\n\n36\n\nSample Input 3\n\n7\n1 2 3 1000000000 4 5 6\n\nSample Output 3\n\n999999994", "sample_input": "5\n3 2 4 1 2\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03310", "source_text": "Score : 600 points\n\nProblem Statement\n\nSnuke has an integer sequence A of length N.\n\nHe will make three cuts in A and divide it into four (non-empty) contiguous subsequences B, C, D and E.\nThe positions of the cuts can be freely chosen.\n\nLet P,Q,R,S be the sums of the elements in B,C,D,E, respectively.\nSnuke is happier when the absolute difference of the maximum and the minimum among P,Q,R,S is smaller.\nFind the minimum possible absolute difference of the maximum and the minimum among P,Q,R,S.\n\nConstraints\n\n4 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq A_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nFind the minimum possible absolute difference of the maximum and the minimum among P,Q,R,S.\n\nSample Input 1\n\n5\n3 2 4 1 2\n\nSample Output 1\n\n2\n\nIf we divide A as B,C,D,E=(3),(2),(4),(1,2), then P=3,Q=2,R=4,S=1+2=3.\nHere, the maximum and the minimum among P,Q,R,S are 4 and 2, with the absolute difference of 2.\nWe cannot make the absolute difference of the maximum and the minimum less than 2, so the answer is 2.\n\nSample Input 2\n\n10\n10 71 84 33 6 47 23 25 52 64\n\nSample Output 2\n\n36\n\nSample Input 3\n\n7\n1 2 3 1000000000 4 5 6\n\nSample Output 3\n\n999999994", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1696, "cpu_time_ms": 100, "memory_kb": 2560}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s156234091", "group_id": "codeNet:p03312", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nconst double PI = acos(-1);\nusing ll = long long;\nusing ull = unsigned long long;\nconst int inf = 2e9;\nconst ll INF = 2e18;\nconst ll MOD = 1e9+7;\ntypedef pair<int,int> P;\n\n#define REP(i,n) for (int i = 0; i < (n); i++)\n#define sz(s) (s).size()\n#define pb push_back\n#define fi first\n#define se second\n\nint n;\nll a[200010];\nint pl[200010], pr[200010];\n\nint main(){\n  ios::sync_with_stdio(false);\n  cin.tie(0);\n\n  cin >> n;\n  REP(i,n) cin >> a[i+1];\n  REP(i,n) a[i+1] += a[i];\n\n  int p = 1;\n  for (int i = 2; i <= n-2; i++) {\n    while (1) {\n      if (abs(a[i] - a[p] - a[p]) > abs(a[i] - a[p+1] - a[p+1]) && p+1 < i) {\n        p++;\n      } else {\n        pl[i] = p;\n        break;\n      }\n    }\n  }\n\n  p = n;\n  for (int i = n-2; i >= 2; i--) {\n    while (1) {\n      if (abs(a[n] - a[p] - (a[p] - a[i])) > abs(a[n] - a[p-1] - (a[p-1] - a[i])) && p-1 > i) {\n        p--;\n      } else {\n        pr[i] = p;\n        break;\n      }\n    }\n  }\n\n  //pl)i)pr)n)\n  ll ans = INF;\n  for (int i = 2; i <= n-2; i++) {\n    ll aa,bb,cc,dd;\n    aa = a[pl[i]];\n    bb = a[i] - aa;\n    cc = a[pr[i]] - a[i];\n    dd = a[n] - aa - bb - cc;\n    ans = min(ans, max({aa,bb,cc,dd}) - min({aa,bb,cc,dd}));\n  }\n\n  cout << ans << endl;\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1553919671, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03312.html", "problem_id": "p03312", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03312/input.txt", "sample_output_relpath": "derived/input_output/data/p03312/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03312/C++/s156234091.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s156234091", "user_id": "u891178744"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nconst double PI = acos(-1);\nusing ll = long long;\nusing ull = unsigned long long;\nconst int inf = 2e9;\nconst ll INF = 2e18;\nconst ll MOD = 1e9+7;\ntypedef pair<int,int> P;\n\n#define REP(i,n) for (int i = 0; i < (n); i++)\n#define sz(s) (s).size()\n#define pb push_back\n#define fi first\n#define se second\n\nint n;\nll a[200010];\nint pl[200010], pr[200010];\n\nint main(){\n  ios::sync_with_stdio(false);\n  cin.tie(0);\n\n  cin >> n;\n  REP(i,n) cin >> a[i+1];\n  REP(i,n) a[i+1] += a[i];\n\n  int p = 1;\n  for (int i = 2; i <= n-2; i++) {\n    while (1) {\n      if (abs(a[i] - a[p] - a[p]) > abs(a[i] - a[p+1] - a[p+1]) && p+1 < i) {\n        p++;\n      } else {\n        pl[i] = p;\n        break;\n      }\n    }\n  }\n\n  p = n;\n  for (int i = n-2; i >= 2; i--) {\n    while (1) {\n      if (abs(a[n] - a[p] - (a[p] - a[i])) > abs(a[n] - a[p-1] - (a[p-1] - a[i])) && p-1 > i) {\n        p--;\n      } else {\n        pr[i] = p;\n        break;\n      }\n    }\n  }\n\n  //pl)i)pr)n)\n  ll ans = INF;\n  for (int i = 2; i <= n-2; i++) {\n    ll aa,bb,cc,dd;\n    aa = a[pl[i]];\n    bb = a[i] - aa;\n    cc = a[pr[i]] - a[i];\n    dd = a[n] - aa - bb - cc;\n    ans = min(ans, max({aa,bb,cc,dd}) - min({aa,bb,cc,dd}));\n  }\n\n  cout << ans << endl;\n  return 0;\n}\n", "problem_context": "Score : 600 points\n\nProblem Statement\n\nSnuke has an integer sequence A of length N.\n\nHe will make three cuts in A and divide it into four (non-empty) contiguous subsequences B, C, D and E.\nThe positions of the cuts can be freely chosen.\n\nLet P,Q,R,S be the sums of the elements in B,C,D,E, respectively.\nSnuke is happier when the absolute difference of the maximum and the minimum among P,Q,R,S is smaller.\nFind the minimum possible absolute difference of the maximum and the minimum among P,Q,R,S.\n\nConstraints\n\n4 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq A_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nFind the minimum possible absolute difference of the maximum and the minimum among P,Q,R,S.\n\nSample Input 1\n\n5\n3 2 4 1 2\n\nSample Output 1\n\n2\n\nIf we divide A as B,C,D,E=(3),(2),(4),(1,2), then P=3,Q=2,R=4,S=1+2=3.\nHere, the maximum and the minimum among P,Q,R,S are 4 and 2, with the absolute difference of 2.\nWe cannot make the absolute difference of the maximum and the minimum less than 2, so the answer is 2.\n\nSample Input 2\n\n10\n10 71 84 33 6 47 23 25 52 64\n\nSample Output 2\n\n36\n\nSample Input 3\n\n7\n1 2 3 1000000000 4 5 6\n\nSample Output 3\n\n999999994", "sample_input": "5\n3 2 4 1 2\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03312", "source_text": "Score : 600 points\n\nProblem Statement\n\nSnuke has an integer sequence A of length N.\n\nHe will make three cuts in A and divide it into four (non-empty) contiguous subsequences B, C, D and E.\nThe positions of the cuts can be freely chosen.\n\nLet P,Q,R,S be the sums of the elements in B,C,D,E, respectively.\nSnuke is happier when the absolute difference of the maximum and the minimum among P,Q,R,S is smaller.\nFind the minimum possible absolute difference of the maximum and the minimum among P,Q,R,S.\n\nConstraints\n\n4 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq A_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nFind the minimum possible absolute difference of the maximum and the minimum among P,Q,R,S.\n\nSample Input 1\n\n5\n3 2 4 1 2\n\nSample Output 1\n\n2\n\nIf we divide A as B,C,D,E=(3),(2),(4),(1,2), then P=3,Q=2,R=4,S=1+2=3.\nHere, the maximum and the minimum among P,Q,R,S are 4 and 2, with the absolute difference of 2.\nWe cannot make the absolute difference of the maximum and the minimum less than 2, so the answer is 2.\n\nSample Input 2\n\n10\n10 71 84 33 6 47 23 25 52 64\n\nSample Output 2\n\n36\n\nSample Input 3\n\n7\n1 2 3 1000000000 4 5 6\n\nSample Output 3\n\n999999994", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1266, "cpu_time_ms": 23, "memory_kb": 3328}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s288470831", "group_id": "codeNet:p03312", "input_text": "//cwystc <--> 陈威宇是天才  --by cwy\n#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> pi;\nconst double PI=acos(-1);\n#define fi first\n#define se second\n#define mp make_pair\n#define pb push_back\n#define rep(i,a,b) for (int i=(a);i<=(b);i++)\n#define per(i,a,b) for (int i=(a);i>=(b);i--)\n#define Rep(i,a,b) for (int i=(a);i<(b);i++)\n#define Per(i,a,b) for (int i=(a);i>(b);i--)\n#define travel_set(it,a) for (set<int>::iterator (it)=(a).begin();(it)!=(a).end();(it)++)\n#define travel_map(it,a) for (map<int>::iterator (it)=(a).begin();(it)!=(a).end();(it)++)\n#define travel_vec(it,a) for (vector<int>::iterator (it)=(a).begin();(it)!=(a).end();(it)++)\n#define p(x) cout << x << endl;\n#define def cout << \"find\" << endl;\n#define what_is(x) cout << #x << \" is \" << x << endl;\ntemplate <class T>T sqr(T x){return x*x;}\ntemplate <class T>T alex(T x){return (x>0)?x:-x;}\ntemplate <class T>void read(T&x){\n\tx=0;T f=1;char ch=getchar();\n\twhile ((ch<48||ch>57)&&ch!=45)ch=getchar();\n\tif (ch==45)f=-1,ch=getchar();\n\twhile (ch>=48&&ch<=57)x=x*10+ch-48,ch=getchar();\n\tx*=f;\n}\n\n//-------------------------------------------------head-------------------------------------------------\n\n#define maxn 1000005\nll a[maxn];int n;\nll min(ll a,ll b,ll c,ll d){\n\tll res=a;\n\tif (b<res)res=b;\n\tif (c<res)res=c;\n\tif (d<res)res=d;\n\treturn res;\n}\nll max(ll a,ll b,ll c,ll d){\n\tll res=a;\n\tif (b>res)res=b;\n\tif (c>res)res=c;\n\tif (d>res)res=d;\n\treturn res;\n}\nint main(){\n\tread(n);\n\trep(i,1,n)read(a[i]),a[i]+=a[i-1];\n\tint A,B,C;ll v=a[n]/4;\n\trep(i,1,n){\n\t\tif (a[i]<=v)A=i;\n\t\tif (a[i]<=v*2)B=i;\n\t\tif (a[i]<=v*3)C=i;\n\t}\n\tll res=(ll)1e18;\n\trep(i,max(1,A-100),min(A+100,n))\n\trep(j,max(i+1,B-100),min(B+100,n))\n\trep(k,max(j+1,C-100),min(C+100,n-1)){\n\t\tll a1=a[i],a2=a[j]-a[i],a3=a[k]-a[j],a4=a[n]-a[k];\n\t\tres=min(res,max(a1,a2,a3,a4)-min(a1,a2,a3,a4));\n\t}\n\tprintf(\"%lld\\n\",res);return 0;\n}", "language": "C++", "metadata": {"date": 1530492204, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03312.html", "problem_id": "p03312", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03312/input.txt", "sample_output_relpath": "derived/input_output/data/p03312/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03312/C++/s288470831.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s288470831", "user_id": "u364634902"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "//cwystc <--> 陈威宇是天才  --by cwy\n#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> pi;\nconst double PI=acos(-1);\n#define fi first\n#define se second\n#define mp make_pair\n#define pb push_back\n#define rep(i,a,b) for (int i=(a);i<=(b);i++)\n#define per(i,a,b) for (int i=(a);i>=(b);i--)\n#define Rep(i,a,b) for (int i=(a);i<(b);i++)\n#define Per(i,a,b) for (int i=(a);i>(b);i--)\n#define travel_set(it,a) for (set<int>::iterator (it)=(a).begin();(it)!=(a).end();(it)++)\n#define travel_map(it,a) for (map<int>::iterator (it)=(a).begin();(it)!=(a).end();(it)++)\n#define travel_vec(it,a) for (vector<int>::iterator (it)=(a).begin();(it)!=(a).end();(it)++)\n#define p(x) cout << x << endl;\n#define def cout << \"find\" << endl;\n#define what_is(x) cout << #x << \" is \" << x << endl;\ntemplate <class T>T sqr(T x){return x*x;}\ntemplate <class T>T alex(T x){return (x>0)?x:-x;}\ntemplate <class T>void read(T&x){\n\tx=0;T f=1;char ch=getchar();\n\twhile ((ch<48||ch>57)&&ch!=45)ch=getchar();\n\tif (ch==45)f=-1,ch=getchar();\n\twhile (ch>=48&&ch<=57)x=x*10+ch-48,ch=getchar();\n\tx*=f;\n}\n\n//-------------------------------------------------head-------------------------------------------------\n\n#define maxn 1000005\nll a[maxn];int n;\nll min(ll a,ll b,ll c,ll d){\n\tll res=a;\n\tif (b<res)res=b;\n\tif (c<res)res=c;\n\tif (d<res)res=d;\n\treturn res;\n}\nll max(ll a,ll b,ll c,ll d){\n\tll res=a;\n\tif (b>res)res=b;\n\tif (c>res)res=c;\n\tif (d>res)res=d;\n\treturn res;\n}\nint main(){\n\tread(n);\n\trep(i,1,n)read(a[i]),a[i]+=a[i-1];\n\tint A,B,C;ll v=a[n]/4;\n\trep(i,1,n){\n\t\tif (a[i]<=v)A=i;\n\t\tif (a[i]<=v*2)B=i;\n\t\tif (a[i]<=v*3)C=i;\n\t}\n\tll res=(ll)1e18;\n\trep(i,max(1,A-100),min(A+100,n))\n\trep(j,max(i+1,B-100),min(B+100,n))\n\trep(k,max(j+1,C-100),min(C+100,n-1)){\n\t\tll a1=a[i],a2=a[j]-a[i],a3=a[k]-a[j],a4=a[n]-a[k];\n\t\tres=min(res,max(a1,a2,a3,a4)-min(a1,a2,a3,a4));\n\t}\n\tprintf(\"%lld\\n\",res);return 0;\n}", "problem_context": "Score : 600 points\n\nProblem Statement\n\nSnuke has an integer sequence A of length N.\n\nHe will make three cuts in A and divide it into four (non-empty) contiguous subsequences B, C, D and E.\nThe positions of the cuts can be freely chosen.\n\nLet P,Q,R,S be the sums of the elements in B,C,D,E, respectively.\nSnuke is happier when the absolute difference of the maximum and the minimum among P,Q,R,S is smaller.\nFind the minimum possible absolute difference of the maximum and the minimum among P,Q,R,S.\n\nConstraints\n\n4 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq A_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nFind the minimum possible absolute difference of the maximum and the minimum among P,Q,R,S.\n\nSample Input 1\n\n5\n3 2 4 1 2\n\nSample Output 1\n\n2\n\nIf we divide A as B,C,D,E=(3),(2),(4),(1,2), then P=3,Q=2,R=4,S=1+2=3.\nHere, the maximum and the minimum among P,Q,R,S are 4 and 2, with the absolute difference of 2.\nWe cannot make the absolute difference of the maximum and the minimum less than 2, so the answer is 2.\n\nSample Input 2\n\n10\n10 71 84 33 6 47 23 25 52 64\n\nSample Output 2\n\n36\n\nSample Input 3\n\n7\n1 2 3 1000000000 4 5 6\n\nSample Output 3\n\n999999994", "sample_input": "5\n3 2 4 1 2\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03312", "source_text": "Score : 600 points\n\nProblem Statement\n\nSnuke has an integer sequence A of length N.\n\nHe will make three cuts in A and divide it into four (non-empty) contiguous subsequences B, C, D and E.\nThe positions of the cuts can be freely chosen.\n\nLet P,Q,R,S be the sums of the elements in B,C,D,E, respectively.\nSnuke is happier when the absolute difference of the maximum and the minimum among P,Q,R,S is smaller.\nFind the minimum possible absolute difference of the maximum and the minimum among P,Q,R,S.\n\nConstraints\n\n4 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq A_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nFind the minimum possible absolute difference of the maximum and the minimum among P,Q,R,S.\n\nSample Input 1\n\n5\n3 2 4 1 2\n\nSample Output 1\n\n2\n\nIf we divide A as B,C,D,E=(3),(2),(4),(1,2), then P=3,Q=2,R=4,S=1+2=3.\nHere, the maximum and the minimum among P,Q,R,S are 4 and 2, with the absolute difference of 2.\nWe cannot make the absolute difference of the maximum and the minimum less than 2, so the answer is 2.\n\nSample Input 2\n\n10\n10 71 84 33 6 47 23 25 52 64\n\nSample Output 2\n\n36\n\nSample Input 3\n\n7\n1 2 3 1000000000 4 5 6\n\nSample Output 3\n\n999999994", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1896, "cpu_time_ms": 38, "memory_kb": 1792}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s569389772", "group_id": "codeNet:p03315", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n\tstring s;cin>>s;\n  int ret=0;\n  for(auto&& u:s)\n    if(u=='+')ret++;\n  else ret--;\n  cout<<ret<<endl;\n}", "language": "C++", "metadata": {"date": 1560861101, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03315.html", "problem_id": "p03315", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03315/input.txt", "sample_output_relpath": "derived/input_output/data/p03315/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03315/C++/s569389772.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s569389772", "user_id": "u731175398"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n\tstring s;cin>>s;\n  int ret=0;\n  for(auto&& u:s)\n    if(u=='+')ret++;\n  else ret--;\n  cout<<ret<<endl;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nThere is always an integer in Takahashi's mind.\n\nInitially, the integer in Takahashi's mind is 0. Takahashi is now going to eat four symbols, each of which is + or -. When he eats +, the integer in his mind increases by 1; when he eats -, the integer in his mind decreases by 1.\n\nThe symbols Takahashi is going to eat are given to you as a string S. The i-th character in S is the i-th symbol for him to eat.\n\nFind the integer in Takahashi's mind after he eats all the symbols.\n\nConstraints\n\nThe length of S is 4.\n\nEach character in S is + or -.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the integer in Takahashi's mind after he eats all the symbols.\n\nSample Input 1\n\n+-++\n\nSample Output 1\n\n2\n\nInitially, the integer in Takahashi's mind is 0.\n\nThe first integer for him to eat is +. After eating it, the integer in his mind becomes 1.\n\nThe second integer to eat is -. After eating it, the integer in his mind becomes 0.\n\nThe third integer to eat is +. After eating it, the integer in his mind becomes 1.\n\nThe fourth integer to eat is +. After eating it, the integer in his mind becomes 2.\n\nThus, the integer in Takahashi's mind after he eats all the symbols is 2.\n\nSample Input 2\n\n-+--\n\nSample Output 2\n\n-2\n\nSample Input 3\n\n----\n\nSample Output 3\n\n-4", "sample_input": "+-++\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03315", "source_text": "Score : 100 points\n\nProblem Statement\n\nThere is always an integer in Takahashi's mind.\n\nInitially, the integer in Takahashi's mind is 0. Takahashi is now going to eat four symbols, each of which is + or -. When he eats +, the integer in his mind increases by 1; when he eats -, the integer in his mind decreases by 1.\n\nThe symbols Takahashi is going to eat are given to you as a string S. The i-th character in S is the i-th symbol for him to eat.\n\nFind the integer in Takahashi's mind after he eats all the symbols.\n\nConstraints\n\nThe length of S is 4.\n\nEach character in S is + or -.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the integer in Takahashi's mind after he eats all the symbols.\n\nSample Input 1\n\n+-++\n\nSample Output 1\n\n2\n\nInitially, the integer in Takahashi's mind is 0.\n\nThe first integer for him to eat is +. After eating it, the integer in his mind becomes 1.\n\nThe second integer to eat is -. After eating it, the integer in his mind becomes 0.\n\nThe third integer to eat is +. After eating it, the integer in his mind becomes 1.\n\nThe fourth integer to eat is +. After eating it, the integer in his mind becomes 2.\n\nThus, the integer in Takahashi's mind after he eats all the symbols is 2.\n\nSample Input 2\n\n-+--\n\nSample Output 2\n\n-2\n\nSample Input 3\n\n----\n\nSample Output 3\n\n-4", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 162, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s412020016", "group_id": "codeNet:p03316", "input_text": "#include <cstdio>\n#include <cmath>\n\nlong long llpow(long long a, long long b){\n    long long res = 1;\n    for(long long i = 0; i<b; i++){\n        res *= 10;\n    }\n\n    return res;\n}\n\n\nint main(){\n    long long N;\n    scanf(\"%lld\", &N);\n\n    long long res = 0;\n    long long one = 1;\n    long long nine = 9;\n    long long ten = 10; \n    for(long long i=0; i<nine; i+=one){\n        long long hoge = llpow(ten, i);\n        if(hoge > N){\n            ;\n        }else{\n            res += (N / hoge) % ten;\n        }\n    }\n\n    long long zero = 0;\n    if(N % res == zero){\n        printf(\"Yes\\n\");\n    }else{\n        printf(\"No\\n\");\n    }\n\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1529803602, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03316.html", "problem_id": "p03316", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03316/input.txt", "sample_output_relpath": "derived/input_output/data/p03316/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03316/C++/s412020016.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s412020016", "user_id": "u848339218"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <cstdio>\n#include <cmath>\n\nlong long llpow(long long a, long long b){\n    long long res = 1;\n    for(long long i = 0; i<b; i++){\n        res *= 10;\n    }\n\n    return res;\n}\n\n\nint main(){\n    long long N;\n    scanf(\"%lld\", &N);\n\n    long long res = 0;\n    long long one = 1;\n    long long nine = 9;\n    long long ten = 10; \n    for(long long i=0; i<nine; i+=one){\n        long long hoge = llpow(ten, i);\n        if(hoge > N){\n            ;\n        }else{\n            res += (N / hoge) % ten;\n        }\n    }\n\n    long long zero = 0;\n    if(N % res == zero){\n        printf(\"Yes\\n\");\n    }else{\n        printf(\"No\\n\");\n    }\n\n    return 0;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nLet S(n) denote the sum of the digits in the decimal notation of n.\nFor example, S(101) = 1 + 0 + 1 = 2.\n\nGiven an integer N, determine if S(N) divides N.\n\nConstraints\n\n1 \\leq N \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nIf S(N) divides N, print Yes; if it does not, print No.\n\nSample Input 1\n\n12\n\nSample Output 1\n\nYes\n\nIn this input, N=12.\nAs S(12) = 1 + 2 = 3, S(N) divides N.\n\nSample Input 2\n\n101\n\nSample Output 2\n\nNo\n\nAs S(101) = 1 + 0 + 1 = 2, S(N) does not divide N.\n\nSample Input 3\n\n999999999\n\nSample Output 3\n\nYes", "sample_input": "12\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p03316", "source_text": "Score : 200 points\n\nProblem Statement\n\nLet S(n) denote the sum of the digits in the decimal notation of n.\nFor example, S(101) = 1 + 0 + 1 = 2.\n\nGiven an integer N, determine if S(N) divides N.\n\nConstraints\n\n1 \\leq N \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nIf S(N) divides N, print Yes; if it does not, print No.\n\nSample Input 1\n\n12\n\nSample Output 1\n\nYes\n\nIn this input, N=12.\nAs S(12) = 1 + 2 = 3, S(N) divides N.\n\nSample Input 2\n\n101\n\nSample Output 2\n\nNo\n\nAs S(101) = 1 + 0 + 1 = 2, S(N) does not divide N.\n\nSample Input 3\n\n999999999\n\nSample Output 3\n\nYes", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 649, "cpu_time_ms": 97, "memory_kb": 128}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s531349960", "group_id": "codeNet:p03317", "input_text": "#include<iostream>\n#include<string>\n#include<algorithm>\n#include<vector>\n#include<cmath>\nusing namespace std;\nint main()\n{\n  int N, K;\n  cin >> N >> K;\n  vector<int> A(N);\n  for(int n = 0; n < N; ++n){\n    cin >> A[n];\n  }\n\n  // K-1ずつ変更する\n  cout << (N-1)/(K-1) << endl;\n  return 0;\n\n}\n", "language": "C++", "metadata": {"date": 1553747685, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03317.html", "problem_id": "p03317", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03317/input.txt", "sample_output_relpath": "derived/input_output/data/p03317/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03317/C++/s531349960.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s531349960", "user_id": "u684056175"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include<iostream>\n#include<string>\n#include<algorithm>\n#include<vector>\n#include<cmath>\nusing namespace std;\nint main()\n{\n  int N, K;\n  cin >> N >> K;\n  vector<int> A(N);\n  for(int n = 0; n < N; ++n){\n    cin >> A[n];\n  }\n\n  // K-1ずつ変更する\n  cout << (N-1)/(K-1) << endl;\n  return 0;\n\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere is a sequence of length N: A_1, A_2, ..., A_N. Initially, this sequence is a permutation of 1, 2, ..., N.\n\nOn this sequence, Snuke can perform the following operation:\n\nChoose K consecutive elements in the sequence. Then, replace the value of each chosen element with the minimum value among the chosen elements.\n\nSnuke would like to make all the elements in this sequence equal by repeating the operation above some number of times.\nFind the minimum number of operations required.\nIt can be proved that, Under the constraints of this problem, this objective is always achievable.\n\nConstraints\n\n2 \\leq K \\leq N \\leq 100000\n\nA_1, A_2, ..., A_N is a permutation of 1, 2, ..., N.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the minimum number of operations required.\n\nSample Input 1\n\n4 3\n2 3 1 4\n\nSample Output 1\n\n2\n\nOne optimal strategy is as follows:\n\nIn the first operation, choose the first, second and third elements. The sequence A becomes 1, 1, 1, 4.\n\nIn the second operation, choose the second, third and fourth elements. The sequence A becomes 1, 1, 1, 1.\n\nSample Input 2\n\n3 3\n1 2 3\n\nSample Output 2\n\n1\n\nSample Input 3\n\n8 3\n7 3 1 8 4 6 2 5\n\nSample Output 3\n\n4", "sample_input": "4 3\n2 3 1 4\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03317", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere is a sequence of length N: A_1, A_2, ..., A_N. Initially, this sequence is a permutation of 1, 2, ..., N.\n\nOn this sequence, Snuke can perform the following operation:\n\nChoose K consecutive elements in the sequence. Then, replace the value of each chosen element with the minimum value among the chosen elements.\n\nSnuke would like to make all the elements in this sequence equal by repeating the operation above some number of times.\nFind the minimum number of operations required.\nIt can be proved that, Under the constraints of this problem, this objective is always achievable.\n\nConstraints\n\n2 \\leq K \\leq N \\leq 100000\n\nA_1, A_2, ..., A_N is a permutation of 1, 2, ..., N.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the minimum number of operations required.\n\nSample Input 1\n\n4 3\n2 3 1 4\n\nSample Output 1\n\n2\n\nOne optimal strategy is as follows:\n\nIn the first operation, choose the first, second and third elements. The sequence A becomes 1, 1, 1, 4.\n\nIn the second operation, choose the second, third and fourth elements. The sequence A becomes 1, 1, 1, 1.\n\nSample Input 2\n\n3 3\n1 2 3\n\nSample Output 2\n\n1\n\nSample Input 3\n\n8 3\n7 3 1 8 4 6 2 5\n\nSample Output 3\n\n4", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 297, "cpu_time_ms": 31, "memory_kb": 640}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s634781465", "group_id": "codeNet:p03325", "input_text": "#include<iostream>\n#include<cstdio>\nusing namespace std;\nint n, x, ans;\nint main(){\n\tscanf(\"%d\", &n);\n\twhile(n--){\n\t\tscanf(\"%d\", &x);\n\t\twhile(!(x & 1)){//用位运算节省时间\n\t\t\tans++;\n\t\t\tx >>= 1;//还是位运算QWQ\n\t\t}\n\t}\n\tprintf(\"%d\\n\", ans);//注意 AT 题要换行\n\treturn 0;//完结撒花-v-\n}", "language": "C++", "metadata": {"date": 1589227857, "filename_ext": "cpp", "original_language": "C++ (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03325.html", "problem_id": "p03325", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03325/input.txt", "sample_output_relpath": "derived/input_output/data/p03325/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03325/C++/s634781465.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s634781465", "user_id": "u476418095"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include<iostream>\n#include<cstdio>\nusing namespace std;\nint n, x, ans;\nint main(){\n\tscanf(\"%d\", &n);\n\twhile(n--){\n\t\tscanf(\"%d\", &x);\n\t\twhile(!(x & 1)){//用位运算节省时间\n\t\t\tans++;\n\t\t\tx >>= 1;//还是位运算QWQ\n\t\t}\n\t}\n\tprintf(\"%d\\n\", ans);//注意 AT 题要换行\n\treturn 0;//完结撒花-v-\n}", "problem_context": "Score: 300 points\n\nProblem Statement\n\nAs AtCoder Beginner Contest 100 is taking place, the office of AtCoder, Inc. is decorated with a sequence of length N, a = {a_1, a_2, a_3, ..., a_N}.\n\nSnuke, an employee, would like to play with this sequence.\n\nSpecifically, he would like to repeat the following operation as many times as possible:\n\nFor every i satisfying 1 \\leq i \\leq N, perform one of the following: \"divide a_i by 2\" and \"multiply a_i by 3\".\nHere, choosing \"multiply a_i by 3\" for every i is not allowed, and the value of a_i after the operation must be an integer.\n\nAt most how many operations can be performed?\n\nConstraints\n\nN is an integer between 1 and 10 \\ 000 (inclusive).\n\na_i is an integer between 1 and 1 \\ 000 \\ 000 \\ 000 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 a_3 ... a_N\n\nOutput\n\nPrint the maximum number of operations that Snuke can perform.\n\nSample Input 1\n\n3\n5 2 4\n\nSample Output 1\n\n3\n\nThe sequence is initially {5, 2, 4}. Three operations can be performed as follows:\n\nFirst, multiply a_1 by 3, multiply a_2 by 3 and divide a_3 by 2. The sequence is now {15, 6, 2}.\n\nNext, multiply a_1 by 3, divide a_2 by 2 and multiply a_3 by 3. The sequence is now {45, 3, 6}.\n\nFinally, multiply a_1 by 3, multiply a_2 by 3 and divide a_3 by 2. The sequence is now {135, 9, 3}.\n\nSample Input 2\n\n4\n631 577 243 199\n\nSample Output 2\n\n0\n\nNo operation can be performed since all the elements are odd. Thus, the answer is 0.\n\nSample Input 3\n\n10\n2184 2126 1721 1800 1024 2528 3360 1945 1280 1776\n\nSample Output 3\n\n39", "sample_input": "3\n5 2 4\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03325", "source_text": "Score: 300 points\n\nProblem Statement\n\nAs AtCoder Beginner Contest 100 is taking place, the office of AtCoder, Inc. is decorated with a sequence of length N, a = {a_1, a_2, a_3, ..., a_N}.\n\nSnuke, an employee, would like to play with this sequence.\n\nSpecifically, he would like to repeat the following operation as many times as possible:\n\nFor every i satisfying 1 \\leq i \\leq N, perform one of the following: \"divide a_i by 2\" and \"multiply a_i by 3\".\nHere, choosing \"multiply a_i by 3\" for every i is not allowed, and the value of a_i after the operation must be an integer.\n\nAt most how many operations can be performed?\n\nConstraints\n\nN is an integer between 1 and 10 \\ 000 (inclusive).\n\na_i is an integer between 1 and 1 \\ 000 \\ 000 \\ 000 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 a_3 ... a_N\n\nOutput\n\nPrint the maximum number of operations that Snuke can perform.\n\nSample Input 1\n\n3\n5 2 4\n\nSample Output 1\n\n3\n\nThe sequence is initially {5, 2, 4}. Three operations can be performed as follows:\n\nFirst, multiply a_1 by 3, multiply a_2 by 3 and divide a_3 by 2. The sequence is now {15, 6, 2}.\n\nNext, multiply a_1 by 3, divide a_2 by 2 and multiply a_3 by 3. The sequence is now {45, 3, 6}.\n\nFinally, multiply a_1 by 3, multiply a_2 by 3 and divide a_3 by 2. The sequence is now {135, 9, 3}.\n\nSample Input 2\n\n4\n631 577 243 199\n\nSample Output 2\n\n0\n\nNo operation can be performed since all the elements are odd. Thus, the answer is 0.\n\nSample Input 3\n\n10\n2184 2126 1721 1800 1024 2528 3360 1945 1280 1776\n\nSample Output 3\n\n39", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 303, "cpu_time_ms": 3, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s789506771", "group_id": "codeNet:p03325", "input_text": "#include<stdio.h>\n\nint main(void){\n    int len,an,cnt=0;\n   scanf(\"%d\",&len);\n   for(int i=0;i<len;i++){\n        scanf(\"%d\",&an);\n        while(1){\n            if(an%2!=0)\n                break;\n            an/=2;\n            cnt++;\n        }\n    }\n    return 0;\n}", "language": "C++", "metadata": {"date": 1529538521, "filename_ext": "cpp", "original_language": "C++ (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03325.html", "problem_id": "p03325", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03325/input.txt", "sample_output_relpath": "derived/input_output/data/p03325/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03325/C++/s789506771.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s789506771", "user_id": "u272266919"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include<stdio.h>\n\nint main(void){\n    int len,an,cnt=0;\n   scanf(\"%d\",&len);\n   for(int i=0;i<len;i++){\n        scanf(\"%d\",&an);\n        while(1){\n            if(an%2!=0)\n                break;\n            an/=2;\n            cnt++;\n        }\n    }\n    return 0;\n}", "problem_context": "Score: 300 points\n\nProblem Statement\n\nAs AtCoder Beginner Contest 100 is taking place, the office of AtCoder, Inc. is decorated with a sequence of length N, a = {a_1, a_2, a_3, ..., a_N}.\n\nSnuke, an employee, would like to play with this sequence.\n\nSpecifically, he would like to repeat the following operation as many times as possible:\n\nFor every i satisfying 1 \\leq i \\leq N, perform one of the following: \"divide a_i by 2\" and \"multiply a_i by 3\".\nHere, choosing \"multiply a_i by 3\" for every i is not allowed, and the value of a_i after the operation must be an integer.\n\nAt most how many operations can be performed?\n\nConstraints\n\nN is an integer between 1 and 10 \\ 000 (inclusive).\n\na_i is an integer between 1 and 1 \\ 000 \\ 000 \\ 000 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 a_3 ... a_N\n\nOutput\n\nPrint the maximum number of operations that Snuke can perform.\n\nSample Input 1\n\n3\n5 2 4\n\nSample Output 1\n\n3\n\nThe sequence is initially {5, 2, 4}. Three operations can be performed as follows:\n\nFirst, multiply a_1 by 3, multiply a_2 by 3 and divide a_3 by 2. The sequence is now {15, 6, 2}.\n\nNext, multiply a_1 by 3, divide a_2 by 2 and multiply a_3 by 3. The sequence is now {45, 3, 6}.\n\nFinally, multiply a_1 by 3, multiply a_2 by 3 and divide a_3 by 2. The sequence is now {135, 9, 3}.\n\nSample Input 2\n\n4\n631 577 243 199\n\nSample Output 2\n\n0\n\nNo operation can be performed since all the elements are odd. Thus, the answer is 0.\n\nSample Input 3\n\n10\n2184 2126 1721 1800 1024 2528 3360 1945 1280 1776\n\nSample Output 3\n\n39", "sample_input": "3\n5 2 4\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03325", "source_text": "Score: 300 points\n\nProblem Statement\n\nAs AtCoder Beginner Contest 100 is taking place, the office of AtCoder, Inc. is decorated with a sequence of length N, a = {a_1, a_2, a_3, ..., a_N}.\n\nSnuke, an employee, would like to play with this sequence.\n\nSpecifically, he would like to repeat the following operation as many times as possible:\n\nFor every i satisfying 1 \\leq i \\leq N, perform one of the following: \"divide a_i by 2\" and \"multiply a_i by 3\".\nHere, choosing \"multiply a_i by 3\" for every i is not allowed, and the value of a_i after the operation must be an integer.\n\nAt most how many operations can be performed?\n\nConstraints\n\nN is an integer between 1 and 10 \\ 000 (inclusive).\n\na_i is an integer between 1 and 1 \\ 000 \\ 000 \\ 000 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 a_3 ... a_N\n\nOutput\n\nPrint the maximum number of operations that Snuke can perform.\n\nSample Input 1\n\n3\n5 2 4\n\nSample Output 1\n\n3\n\nThe sequence is initially {5, 2, 4}. Three operations can be performed as follows:\n\nFirst, multiply a_1 by 3, multiply a_2 by 3 and divide a_3 by 2. The sequence is now {15, 6, 2}.\n\nNext, multiply a_1 by 3, divide a_2 by 2 and multiply a_3 by 3. The sequence is now {45, 3, 6}.\n\nFinally, multiply a_1 by 3, multiply a_2 by 3 and divide a_3 by 2. The sequence is now {135, 9, 3}.\n\nSample Input 2\n\n4\n631 577 243 199\n\nSample Output 2\n\n0\n\nNo operation can be performed since all the elements are odd. Thus, the answer is 0.\n\nSample Input 3\n\n10\n2184 2126 1721 1800 1024 2528 3360 1945 1280 1776\n\nSample Output 3\n\n39", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 264, "cpu_time_ms": 2, "memory_kb": 128}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s078744975", "group_id": "codeNet:p03327", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\ntypedef unsigned long long ll;\ntypedef long double ld;\ntypedef vector<int> vi;\ntypedef vector<ll> vll;\n\n#define INF (int)(1e9)\n\n#define rep(i,n) for(int i=0; i<(n); i++)\n#define REP(i,start,end) for(int i=(start);i<=(end);i++)\n#define all(n) begin(n),end(n)\n\n#define DEBUG\n\nint main()\n{\n\tint n;\n\tcin >> n;\n\tif(n > 1000) cout << \"ABD\" << endl;\n\telse cout << \"ABC\" << endl;\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1577141521, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03327.html", "problem_id": "p03327", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03327/input.txt", "sample_output_relpath": "derived/input_output/data/p03327/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03327/C++/s078744975.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s078744975", "user_id": "u959682820"}, "prompt_components": {"gold_output": "ABC\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\ntypedef unsigned long long ll;\ntypedef long double ld;\ntypedef vector<int> vi;\ntypedef vector<ll> vll;\n\n#define INF (int)(1e9)\n\n#define rep(i,n) for(int i=0; i<(n); i++)\n#define REP(i,start,end) for(int i=(start);i<=(end);i++)\n#define all(n) begin(n),end(n)\n\n#define DEBUG\n\nint main()\n{\n\tint n;\n\tcin >> n;\n\tif(n > 1000) cout << \"ABD\" << endl;\n\telse cout << \"ABC\" << endl;\n\treturn 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nDecades have passed since the beginning of AtCoder Beginner Contest.\n\nThe contests are labeled as ABC001, ABC002, ... from the first round, but after the 999-th round ABC999, a problem occurred: how the future rounds should be labeled?\n\nIn the end, the labels for the rounds from the 1000-th to the 1998-th are decided: ABD001, ABD002, ..., ABD999.\n\nYou are given an integer N between 1 and 1998 (inclusive). Print the first three characters of the label of the N-th round of AtCoder Beginner Contest.\n\nConstraints\n\n1 \\leq N \\leq 1998\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the first three characters of the label of the N-th round of AtCoder Beginner Contest.\n\nSample Input 1\n\n999\n\nSample Output 1\n\nABC\n\nThe 999-th round of AtCoder Beginner Contest is labeled as ABC999.\n\nSample Input 2\n\n1000\n\nSample Output 2\n\nABD\n\nThe 1000-th round of AtCoder Beginner Contest is labeled as ABD001.\n\nSample Input 3\n\n1481\n\nSample Output 3\n\nABD\n\nThe 1481-th round of AtCoder Beginner Contest is labeled as ABD482.", "sample_input": "999\n"}, "reference_outputs": ["ABC\n"], "source_document_id": "p03327", "source_text": "Score : 100 points\n\nProblem Statement\n\nDecades have passed since the beginning of AtCoder Beginner Contest.\n\nThe contests are labeled as ABC001, ABC002, ... from the first round, but after the 999-th round ABC999, a problem occurred: how the future rounds should be labeled?\n\nIn the end, the labels for the rounds from the 1000-th to the 1998-th are decided: ABD001, ABD002, ..., ABD999.\n\nYou are given an integer N between 1 and 1998 (inclusive). Print the first three characters of the label of the N-th round of AtCoder Beginner Contest.\n\nConstraints\n\n1 \\leq N \\leq 1998\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the first three characters of the label of the N-th round of AtCoder Beginner Contest.\n\nSample Input 1\n\n999\n\nSample Output 1\n\nABC\n\nThe 999-th round of AtCoder Beginner Contest is labeled as ABC999.\n\nSample Input 2\n\n1000\n\nSample Output 2\n\nABD\n\nThe 1000-th round of AtCoder Beginner Contest is labeled as ABD001.\n\nSample Input 3\n\n1481\n\nSample Output 3\n\nABD\n\nThe 1481-th round of AtCoder Beginner Contest is labeled as ABD482.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 431, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s589243579", "group_id": "codeNet:p03328", "input_text": "#include <iostream>\n#include <string>\n#include <vector>\n#include <numeric>\n#include <queue>\n#include <unordered_map>\n#include <algorithm>\n#include <cmath>\n#include <iomanip>\n#include <sstream>\n#include <stack>\n#include <map>\n#include <set>\n\n#define REP(i,a) for(int i = 0;i < (a);++i)\n#define FOR(i,a,b) for(int i = (a);i < (b); ++i)\n#define ALL(obj) (obj).begin(),(obj).end()\n#define SIZE(obj) (int)(obj).size()\n#define MAX(list) std::max(list)\n#define MIN(list) std::min(list)\n\ntemplate<typename T>\nT round_up(const T& a, const T& b) {\n    return (a + (b - 1)) / b;\n}\n\nusing ll = long long;\nusing namespace std;\nll mod = 1'000'000'007;\n\nconst int INF = 1'050'000'000;\n\nint main() {\n    int A, B;\n    cin >> A >> B;\n\n    vector<int> sums(1000);\n    sums[0] = 0;\n    REP(i, 999) {\n        sums[i + 1] = sums[i] + i + 1;\n    }\n\n    REP(i, 1000) {\n        if (sums[i] - A == sums[i + 1] - B) {\n            cout << sums[i] - A << endl;\n            return 0;\n        }\n    }\n    return 0;\n}", "language": "C++", "metadata": {"date": 1561853618, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03328.html", "problem_id": "p03328", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03328/input.txt", "sample_output_relpath": "derived/input_output/data/p03328/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03328/C++/s589243579.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s589243579", "user_id": "u303039933"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <iostream>\n#include <string>\n#include <vector>\n#include <numeric>\n#include <queue>\n#include <unordered_map>\n#include <algorithm>\n#include <cmath>\n#include <iomanip>\n#include <sstream>\n#include <stack>\n#include <map>\n#include <set>\n\n#define REP(i,a) for(int i = 0;i < (a);++i)\n#define FOR(i,a,b) for(int i = (a);i < (b); ++i)\n#define ALL(obj) (obj).begin(),(obj).end()\n#define SIZE(obj) (int)(obj).size()\n#define MAX(list) std::max(list)\n#define MIN(list) std::min(list)\n\ntemplate<typename T>\nT round_up(const T& a, const T& b) {\n    return (a + (b - 1)) / b;\n}\n\nusing ll = long long;\nusing namespace std;\nll mod = 1'000'000'007;\n\nconst int INF = 1'050'000'000;\n\nint main() {\n    int A, B;\n    cin >> A >> B;\n\n    vector<int> sums(1000);\n    sums[0] = 0;\n    REP(i, 999) {\n        sums[i + 1] = sums[i] + i + 1;\n    }\n\n    REP(i, 1000) {\n        if (sums[i] - A == sums[i + 1] - B) {\n            cout << sums[i] - A << endl;\n            return 0;\n        }\n    }\n    return 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nIn some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.\n\nIt had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.\n\nAssuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.\n\nAssume also that the depth of the snow cover is always at least 1 meter.\n\nConstraints\n\n1 \\leq a < b < 499500(=1+2+3+...+999)\n\nAll values in input are integers.\n\nThere is no input that contradicts the assumption.\n\nInput\n\nInput is given from Standard Input in the following format:\n\na b\n\nOutput\n\nIf the depth of the snow cover is x meters, print x as an integer.\n\nSample Input 1\n\n8 13\n\nSample Output 1\n\n2\n\nThe heights of the two towers are 10 meters and 15 meters, respectively.\nThus, we can see that the depth of the snow cover is 2 meters.\n\nSample Input 2\n\n54 65\n\nSample Output 2\n\n1", "sample_input": "8 13\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03328", "source_text": "Score : 200 points\n\nProblem Statement\n\nIn some village, there are 999 towers that are 1,(1+2),(1+2+3),...,(1+2+3+...+999) meters high from west to east, at intervals of 1 meter.\n\nIt had been snowing for a while before it finally stopped. For some two adjacent towers located 1 meter apart, we measured the lengths of the parts of those towers that are not covered with snow, and the results are a meters for the west tower, and b meters for the east tower.\n\nAssuming that the depth of snow cover and the altitude are the same everywhere in the village, find the amount of the snow cover.\n\nAssume also that the depth of the snow cover is always at least 1 meter.\n\nConstraints\n\n1 \\leq a < b < 499500(=1+2+3+...+999)\n\nAll values in input are integers.\n\nThere is no input that contradicts the assumption.\n\nInput\n\nInput is given from Standard Input in the following format:\n\na b\n\nOutput\n\nIf the depth of the snow cover is x meters, print x as an integer.\n\nSample Input 1\n\n8 13\n\nSample Output 1\n\n2\n\nThe heights of the two towers are 10 meters and 15 meters, respectively.\nThus, we can see that the depth of the snow cover is 2 meters.\n\nSample Input 2\n\n54 65\n\nSample Output 2\n\n1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 986, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s984134622", "group_id": "codeNet:p03337", "input_text": "#include <iostream>\n\nusing namespace std;\n\nint main()\n{\n    int a, b;\n    cin >> a >> b;\n    int max = a + b;\n\n    if (a - b > max)\n    {\n        max = a - b;\n    }\n    if (a * b > max)\n    {\n        max = a * b;\n    }\n    cout << max << endl;\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1589230960, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03337.html", "problem_id": "p03337", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03337/input.txt", "sample_output_relpath": "derived/input_output/data/p03337/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03337/C++/s984134622.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s984134622", "user_id": "u134896569"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <iostream>\n\nusing namespace std;\n\nint main()\n{\n    int a, b;\n    cin >> a >> b;\n    int max = a + b;\n\n    if (a - b > max)\n    {\n        max = a - b;\n    }\n    if (a * b > max)\n    {\n        max = a * b;\n    }\n    cout << max << endl;\n    return 0;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nYou are given two integers A and B.\nFind the largest value among A+B, A-B and A \\times B.\n\nConstraints\n\n-1000 \\leq A,B \\leq 1000\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nPrint the largest value among A+B, A-B and A \\times B.\n\nSample Input 1\n\n3 1\n\nSample Output 1\n\n4\n\n3+1=4, 3-1=2 and 3 \\times 1=3. The largest among them is 4.\n\nSample Input 2\n\n4 -2\n\nSample Output 2\n\n6\n\nThe largest is 4 - (-2) = 6.\n\nSample Input 3\n\n0 0\n\nSample Output 3\n\n0", "sample_input": "3 1\n"}, "reference_outputs": ["4\n"], "source_document_id": "p03337", "source_text": "Score : 100 points\n\nProblem Statement\n\nYou are given two integers A and B.\nFind the largest value among A+B, A-B and A \\times B.\n\nConstraints\n\n-1000 \\leq A,B \\leq 1000\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nPrint the largest value among A+B, A-B and A \\times B.\n\nSample Input 1\n\n3 1\n\nSample Output 1\n\n4\n\n3+1=4, 3-1=2 and 3 \\times 1=3. The largest among them is 4.\n\nSample Input 2\n\n4 -2\n\nSample Output 2\n\n6\n\nThe largest is 4 - (-2) = 6.\n\nSample Input 3\n\n0 0\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 260, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s821341515", "group_id": "codeNet:p03339", "input_text": "#include <cstdio>\n#include <algorithm>\n#define maxn 300005\nusing namespace std;\n\nint n, ans = 999999999;\nint sum[maxn];\nchar s[maxn];\n\nint main()\n{\n\tscanf(\"%d\", &n);\n\tscanf(\"%s\", s);\n\tfor (int i = 1; i <= n; i++)\n\t{\n\t\tif (s[i - 1] == 'E') sum[i] = sum[i - 1] + 1;\n\t\telse sum[i] = sum[i - 1];\n\t}\n\tfor (int i = 1; i <= n; i++)\n\t\tans = min(ans, (i - 1 - sum[i - 1]) + (sum[n] - sum[i]));\n\tprintf(\"%d\", ans);\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1527384548, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03339.html", "problem_id": "p03339", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03339/input.txt", "sample_output_relpath": "derived/input_output/data/p03339/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03339/C++/s821341515.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s821341515", "user_id": "u617355226"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <cstdio>\n#include <algorithm>\n#define maxn 300005\nusing namespace std;\n\nint n, ans = 999999999;\nint sum[maxn];\nchar s[maxn];\n\nint main()\n{\n\tscanf(\"%d\", &n);\n\tscanf(\"%s\", s);\n\tfor (int i = 1; i <= n; i++)\n\t{\n\t\tif (s[i - 1] == 'E') sum[i] = sum[i - 1] + 1;\n\t\telse sum[i] = sum[i - 1];\n\t}\n\tfor (int i = 1; i <= n; i++)\n\t\tans = min(ans, (i - 1 - sum[i - 1]) + (sum[n] - sum[i]));\n\tprintf(\"%d\", ans);\n\treturn 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N people standing in a row from west to east.\nEach person is facing east or west.\nThe directions of the people is given as a string S of length N.\nThe i-th person from the west is facing east if S_i = E, and west if S_i = W.\n\nYou will appoint one of the N people as the leader, then command the rest of them to face in the direction of the leader.\nHere, we do not care which direction the leader is facing.\n\nThe people in the row hate to change their directions, so you would like to select the leader so that the number of people who have to change their directions is minimized.\nFind the minimum number of people who have to change their directions.\n\nConstraints\n\n2 \\leq N \\leq 3 \\times 10^5\n\n|S| = N\n\nS_i is E or W.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS\n\nOutput\n\nPrint the minimum number of people who have to change their directions.\n\nSample Input 1\n\n5\nWEEWW\n\nSample Output 1\n\n1\n\nAssume that we appoint the third person from the west as the leader.\nThen, the first person from the west needs to face east and has to turn around.\nThe other people do not need to change their directions, so the number of people who have to change their directions is 1 in this case.\nIt is not possible to have 0 people who have to change their directions, so the answer is 1.\n\nSample Input 2\n\n12\nWEWEWEEEWWWE\n\nSample Output 2\n\n4\n\nSample Input 3\n\n8\nWWWWWEEE\n\nSample Output 3\n\n3", "sample_input": "5\nWEEWW\n"}, "reference_outputs": ["1\n"], "source_document_id": "p03339", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N people standing in a row from west to east.\nEach person is facing east or west.\nThe directions of the people is given as a string S of length N.\nThe i-th person from the west is facing east if S_i = E, and west if S_i = W.\n\nYou will appoint one of the N people as the leader, then command the rest of them to face in the direction of the leader.\nHere, we do not care which direction the leader is facing.\n\nThe people in the row hate to change their directions, so you would like to select the leader so that the number of people who have to change their directions is minimized.\nFind the minimum number of people who have to change their directions.\n\nConstraints\n\n2 \\leq N \\leq 3 \\times 10^5\n\n|S| = N\n\nS_i is E or W.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS\n\nOutput\n\nPrint the minimum number of people who have to change their directions.\n\nSample Input 1\n\n5\nWEEWW\n\nSample Output 1\n\n1\n\nAssume that we appoint the third person from the west as the leader.\nThen, the first person from the west needs to face east and has to turn around.\nThe other people do not need to change their directions, so the number of people who have to change their directions is 1 in this case.\nIt is not possible to have 0 people who have to change their directions, so the answer is 1.\n\nSample Input 2\n\n12\nWEWEWEEEWWWE\n\nSample Output 2\n\n4\n\nSample Input 3\n\n8\nWWWWWEEE\n\nSample Output 3\n\n3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 417, "cpu_time_ms": 3, "memory_kb": 1664}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s648362374", "group_id": "codeNet:p03343", "input_text": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define REP(i,m) for(int i=0; i<m; i++)\n#define FOR(i,n,m) for(long long i=n; i<m; i++)\n#define INF 1000000001\n#define INFL (1LL << 60)\n#define MOD 1000000007\n#define ALL(v) v.begin(),v.end()\n#define pb push_back\n#define ll long long int\n#define P pair<ll, ll>\n\nint main() {\n  int n, k, q;\n  cin >> n >> k >> q;\n  P a[n];\n  REP(i, n){\n    int x;\n    cin >> x;\n    a[i] = {x, i};\n  }\n  sort(a, a+n);\n  bool check[n];\n  REP(i, n){\n    check[i] = ((n-k-q+i+1 <= a[i].second) && (a[i].second <= k+q-i-2));\n  }\n  bool isok[n-q+1] = { };\n  REP(i, n-q+1){\n    REP(j, n){\n      if(check[j] && !(i <= j && j < i+q)) isok[i] = true;\n    }\n  }\n  int mm[n-q+1];\n  REP(i, n-q+1) mm[i] = a[i+q-1].first - a[i].first;\n  int ans = INF;\n  REP(i, n-q+1){\n    if(!isok[i]) ans = min(ans, mm[i]);\n  }\n  cout << ans << endl;\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1527386375, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03343.html", "problem_id": "p03343", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03343/input.txt", "sample_output_relpath": "derived/input_output/data/p03343/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03343/C++/s648362374.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s648362374", "user_id": "u773548422"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define REP(i,m) for(int i=0; i<m; i++)\n#define FOR(i,n,m) for(long long i=n; i<m; i++)\n#define INF 1000000001\n#define INFL (1LL << 60)\n#define MOD 1000000007\n#define ALL(v) v.begin(),v.end()\n#define pb push_back\n#define ll long long int\n#define P pair<ll, ll>\n\nint main() {\n  int n, k, q;\n  cin >> n >> k >> q;\n  P a[n];\n  REP(i, n){\n    int x;\n    cin >> x;\n    a[i] = {x, i};\n  }\n  sort(a, a+n);\n  bool check[n];\n  REP(i, n){\n    check[i] = ((n-k-q+i+1 <= a[i].second) && (a[i].second <= k+q-i-2));\n  }\n  bool isok[n-q+1] = { };\n  REP(i, n-q+1){\n    REP(j, n){\n      if(check[j] && !(i <= j && j < i+q)) isok[i] = true;\n    }\n  }\n  int mm[n-q+1];\n  REP(i, n-q+1) mm[i] = a[i+q-1].first - a[i].first;\n  int ans = INF;\n  REP(i, n-q+1){\n    if(!isok[i]) ans = min(ans, mm[i]);\n  }\n  cout << ans << endl;\n  return 0;\n}\n", "problem_context": "Score : 600 points\n\nProblem Statement\n\nYou are given an integer sequence A of length N and an integer K.\nYou will perform the following operation on this sequence Q times:\n\nChoose a contiguous subsequence of length K, then remove the smallest element among the K elements contained in the chosen subsequence (if there are multiple such elements, choose one of them as you like).\n\nLet X and Y be the values of the largest and smallest element removed in the Q operations. You would like X-Y to be as small as possible.\nFind the smallest possible value of X-Y when the Q operations are performed optimally.\n\nConstraints\n\n1 \\leq N \\leq 2000\n\n1 \\leq K \\leq N\n\n1 \\leq Q \\leq N-K+1\n\n1 \\leq A_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K Q\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the smallest possible value of X-Y.\n\nSample Input 1\n\n5 3 2\n4 3 1 5 2\n\nSample Output 1\n\n1\n\nIn the first operation, whichever contiguous subsequence of length 3 we choose, the minimum element in it is 1.\nThus, the first operation removes A_3=1 and now we have A=(4,3,5,2).\nIn the second operation, it is optimal to choose (A_2,A_3,A_4)=(3,5,2) as the contiguous subsequence of length 3 and remove A_4=2.\nIn this case, the largest element removed is 2, and the smallest is 1, so their difference is 2-1=1.\n\nSample Input 2\n\n10 1 6\n1 1 2 3 5 8 13 21 34 55\n\nSample Output 2\n\n7\n\nSample Input 3\n\n11 7 5\n24979445 861648772 623690081 433933447 476190629 262703497 211047202 971407775 628894325 731963982 822804784\n\nSample Output 3\n\n451211184", "sample_input": "5 3 2\n4 3 1 5 2\n"}, "reference_outputs": ["1\n"], "source_document_id": "p03343", "source_text": "Score : 600 points\n\nProblem Statement\n\nYou are given an integer sequence A of length N and an integer K.\nYou will perform the following operation on this sequence Q times:\n\nChoose a contiguous subsequence of length K, then remove the smallest element among the K elements contained in the chosen subsequence (if there are multiple such elements, choose one of them as you like).\n\nLet X and Y be the values of the largest and smallest element removed in the Q operations. You would like X-Y to be as small as possible.\nFind the smallest possible value of X-Y when the Q operations are performed optimally.\n\nConstraints\n\n1 \\leq N \\leq 2000\n\n1 \\leq K \\leq N\n\n1 \\leq Q \\leq N-K+1\n\n1 \\leq A_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K Q\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the smallest possible value of X-Y.\n\nSample Input 1\n\n5 3 2\n4 3 1 5 2\n\nSample Output 1\n\n1\n\nIn the first operation, whichever contiguous subsequence of length 3 we choose, the minimum element in it is 1.\nThus, the first operation removes A_3=1 and now we have A=(4,3,5,2).\nIn the second operation, it is optimal to choose (A_2,A_3,A_4)=(3,5,2) as the contiguous subsequence of length 3 and remove A_4=2.\nIn this case, the largest element removed is 2, and the smallest is 1, so their difference is 2-1=1.\n\nSample Input 2\n\n10 1 6\n1 1 2 3 5 8 13 21 34 55\n\nSample Output 2\n\n7\n\nSample Input 3\n\n11 7 5\n24979445 861648772 623690081 433933447 476190629 262703497 211047202 971407775 628894325 731963982 822804784\n\nSample Output 3\n\n451211184", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 866, "cpu_time_ms": 7, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s281385230", "group_id": "codeNet:p03345", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nconst __int128 maxn = 1e18;\nvoid scan(__int128 &x)\n{\n    x = 0;\n    int f = 1;\n    char ch;\n    if((ch = getchar()) == '-') f = -f;\n    else x = x*10 + ch-'0';\n    while((ch = getchar()) >= '0' && ch <= '9')\n        x = x*10 + ch-'0';\n    x *= f;\n}\nvoid _print(__int128 x)\n{\n    if(x > 9) _print(x/10);\n    putchar(x%10 + '0');\n}\nvoid print(__int128 x) {\n    if(x < 0)\n    {\n        x = -x;\n        putchar('-');\n    }\n    _print(x);\n}\n__int128 Abs(__int128 x) {\n    return x > 0 ? x : -x;\n}\nint main() {\n    long long a,b,c,k,ans;\n    if (k&1) ans = b-a;\n    else ans = a-b;\n    if (abs(ans) > maxn) printf(\"Unfair\");\n    else printf(\"%d\",ans);\n    return 0;\n}", "language": "C++", "metadata": {"date": 1526867067, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03345.html", "problem_id": "p03345", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03345/input.txt", "sample_output_relpath": "derived/input_output/data/p03345/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03345/C++/s281385230.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s281385230", "user_id": "u484398192"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nconst __int128 maxn = 1e18;\nvoid scan(__int128 &x)\n{\n    x = 0;\n    int f = 1;\n    char ch;\n    if((ch = getchar()) == '-') f = -f;\n    else x = x*10 + ch-'0';\n    while((ch = getchar()) >= '0' && ch <= '9')\n        x = x*10 + ch-'0';\n    x *= f;\n}\nvoid _print(__int128 x)\n{\n    if(x > 9) _print(x/10);\n    putchar(x%10 + '0');\n}\nvoid print(__int128 x) {\n    if(x < 0)\n    {\n        x = -x;\n        putchar('-');\n    }\n    _print(x);\n}\n__int128 Abs(__int128 x) {\n    return x > 0 ? x : -x;\n}\nint main() {\n    long long a,b,c,k,ans;\n    if (k&1) ans = b-a;\n    else ans = a-b;\n    if (abs(ans) > maxn) printf(\"Unfair\");\n    else printf(\"%d\",ans);\n    return 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nTakahashi, Nakahashi and Hikuhashi have integers A, B and C, respectively.\nAfter repeating the following operation K times, find the integer Takahashi will get minus the integer Nakahashi will get:\n\nEach of them simultaneously calculate the sum of the integers that the other two people have, then replace his own integer with the result.\n\nHowever, if the absolute value of the answer exceeds 10^{18}, print Unfair instead.\n\nConstraints\n\n1 \\leq A,B,C \\leq 10^9\n\n0 \\leq K \\leq 10^{18}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B C K\n\nOutput\n\nPrint the integer Takahashi will get minus the integer Nakahashi will get, after repeating the following operation K times.\nIf the absolute value of the answer exceeds 10^{18}, print Unfair instead.\n\nSample Input 1\n\n1 2 3 1\n\nSample Output 1\n\n1\n\nAfter one operation, Takahashi, Nakahashi and Hikuhashi have 5, 4 and 3, respectively. We should print 5-4=1.\n\nSample Input 2\n\n2 3 2 0\n\nSample Output 2\n\n-1\n\nSample Input 3\n\n1000000000 1000000000 1000000000 1000000000000000000\n\nSample Output 3\n\n0", "sample_input": "1 2 3 1\n"}, "reference_outputs": ["1\n"], "source_document_id": "p03345", "source_text": "Score : 300 points\n\nProblem Statement\n\nTakahashi, Nakahashi and Hikuhashi have integers A, B and C, respectively.\nAfter repeating the following operation K times, find the integer Takahashi will get minus the integer Nakahashi will get:\n\nEach of them simultaneously calculate the sum of the integers that the other two people have, then replace his own integer with the result.\n\nHowever, if the absolute value of the answer exceeds 10^{18}, print Unfair instead.\n\nConstraints\n\n1 \\leq A,B,C \\leq 10^9\n\n0 \\leq K \\leq 10^{18}\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B C K\n\nOutput\n\nPrint the integer Takahashi will get minus the integer Nakahashi will get, after repeating the following operation K times.\nIf the absolute value of the answer exceeds 10^{18}, print Unfair instead.\n\nSample Input 1\n\n1 2 3 1\n\nSample Output 1\n\n1\n\nAfter one operation, Takahashi, Nakahashi and Hikuhashi have 5, 4 and 3, respectively. We should print 5-4=1.\n\nSample Input 2\n\n2 3 2 0\n\nSample Output 2\n\n-1\n\nSample Input 3\n\n1000000000 1000000000 1000000000 1000000000000000000\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 707, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s052884532", "group_id": "codeNet:p03346", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nconst int MAXN = 1001010;\nint p[MAXN], a[MAXN], n;\nint dp[MAXN];\nint main(){\n    scanf(\"%d\", &n);\n    for(int i = 1; i <= n; i ++){\n        scanf(\"%d\", &a[i]);\n        dp[i] = 1; p[a[i]] = i;\n    }\n    for(int i = 2; i <= n; i ++){\n        if(p[i] > p[i-1])\n            dp[i] = dp[i-1] + 1;\n    }\n    \n    int ans = MAXN;\n    for(int i = 1; i <= n; i ++){\n        ans = min(ans, n - dp[i]);\n    }\n    printf(\"%d\", ans);\n}", "language": "C++", "metadata": {"date": 1526865775, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03346.html", "problem_id": "p03346", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03346/input.txt", "sample_output_relpath": "derived/input_output/data/p03346/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03346/C++/s052884532.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s052884532", "user_id": "u009497225"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nconst int MAXN = 1001010;\nint p[MAXN], a[MAXN], n;\nint dp[MAXN];\nint main(){\n    scanf(\"%d\", &n);\n    for(int i = 1; i <= n; i ++){\n        scanf(\"%d\", &a[i]);\n        dp[i] = 1; p[a[i]] = i;\n    }\n    for(int i = 2; i <= n; i ++){\n        if(p[i] > p[i-1])\n            dp[i] = dp[i-1] + 1;\n    }\n    \n    int ans = MAXN;\n    for(int i = 1; i <= n; i ++){\n        ans = min(ans, n - dp[i]);\n    }\n    printf(\"%d\", ans);\n}", "problem_context": "Score : 500 points\n\nProblem Statement\n\nYou are given a sequence (P_1,P_2,...,P_N) which is a permutation of the integers from 1 through N.\nYou would like to sort this sequence in ascending order by repeating the following operation:\n\nChoose an element in the sequence and move it to the beginning or the end of the sequence.\n\nFind the minimum number of operations required.\nIt can be proved that it is actually possible to sort the sequence using this operation.\n\nConstraints\n\n1 \\leq N \\leq 2\\times 10^5\n\n(P_1,P_2,...,P_N) is a permutation of (1,2,...,N).\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nP_1\n:\nP_N\n\nOutput\n\nPrint the minimum number of operations required.\n\nSample Input 1\n\n4\n1\n3\n2\n4\n\nSample Output 1\n\n2\n\nFor example, the sequence can be sorted in ascending order as follows:\n\nMove 2 to the beginning. The sequence is now (2,1,3,4).\n\nMove 1 to the beginning. The sequence is now (1,2,3,4).\n\nSample Input 2\n\n6\n3\n2\n5\n1\n4\n6\n\nSample Output 2\n\n4\n\nSample Input 3\n\n8\n6\n3\n1\n2\n7\n4\n8\n5\n\nSample Output 3\n\n5", "sample_input": "4\n1\n3\n2\n4\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03346", "source_text": "Score : 500 points\n\nProblem Statement\n\nYou are given a sequence (P_1,P_2,...,P_N) which is a permutation of the integers from 1 through N.\nYou would like to sort this sequence in ascending order by repeating the following operation:\n\nChoose an element in the sequence and move it to the beginning or the end of the sequence.\n\nFind the minimum number of operations required.\nIt can be proved that it is actually possible to sort the sequence using this operation.\n\nConstraints\n\n1 \\leq N \\leq 2\\times 10^5\n\n(P_1,P_2,...,P_N) is a permutation of (1,2,...,N).\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nP_1\n:\nP_N\n\nOutput\n\nPrint the minimum number of operations required.\n\nSample Input 1\n\n4\n1\n3\n2\n4\n\nSample Output 1\n\n2\n\nFor example, the sequence can be sorted in ascending order as follows:\n\nMove 2 to the beginning. The sequence is now (2,1,3,4).\n\nMove 1 to the beginning. The sequence is now (1,2,3,4).\n\nSample Input 2\n\n6\n3\n2\n5\n1\n4\n6\n\nSample Output 2\n\n4\n\nSample Input 3\n\n8\n6\n3\n1\n2\n7\n4\n8\n5\n\nSample Output 3\n\n5", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 466, "cpu_time_ms": 24, "memory_kb": 9216}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s937213205", "group_id": "codeNet:p03347", "input_text": "#include<iostream>\n#include<cmath>\nusing namespace std;\n\nint main() {\n    int N;\n    cin>>N;\n    long A[N];\n    for(int i=0;i<N;++i){\n        cin>>A[i];\n    }\n    bool check = true;\n    if(A[0]!=0)check = false;\n    for(int i=1;i<N;++i){\n        if(abs(A[i]-A[i-1])>1)check = false;\n    }\n    long ans = A[N-1];\n    if(check){\n        for(int i=N-1;i>=1;--i){\n            if(A[i]-A[i-1]!=1)ans += A[i-1];\n        }\n    }\n    else ans = -1;\n    cout<<ans<<endl;\n}\n", "language": "C++", "metadata": {"date": 1585853185, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03347.html", "problem_id": "p03347", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03347/input.txt", "sample_output_relpath": "derived/input_output/data/p03347/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03347/C++/s937213205.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s937213205", "user_id": "u860546679"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include<iostream>\n#include<cmath>\nusing namespace std;\n\nint main() {\n    int N;\n    cin>>N;\n    long A[N];\n    for(int i=0;i<N;++i){\n        cin>>A[i];\n    }\n    bool check = true;\n    if(A[0]!=0)check = false;\n    for(int i=1;i<N;++i){\n        if(abs(A[i]-A[i-1])>1)check = false;\n    }\n    long ans = A[N-1];\n    if(check){\n        for(int i=N-1;i>=1;--i){\n            if(A[i]-A[i-1]!=1)ans += A[i-1];\n        }\n    }\n    else ans = -1;\n    cout<<ans<<endl;\n}\n", "problem_context": "Score : 700 points\n\nProblem Statement\n\nThere is a sequence X of length N, where every element is initially 0. Let X_i denote the i-th element of X.\n\nYou are given a sequence A of length N. The i-th element of A is A_i. Determine if we can make X equal to A by repeating the operation below. If we can, find the minimum number of operations required.\n\nChoose an integer i such that 1\\leq i\\leq N-1. Replace the value of X_{i+1} with the value of X_i plus 1.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\n0 \\leq A_i \\leq 10^9(1\\leq i\\leq N)\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1\n:\nA_N\n\nOutput\n\nIf we can make X equal to A by repeating the operation, print the minimum number of operations required. If we cannot, print -1.\n\nSample Input 1\n\n4\n0\n1\n1\n2\n\nSample Output 1\n\n3\n\nWe can make X equal to A as follows:\n\nChoose i=2. X becomes (0,0,1,0).\n\nChoose i=1. X becomes (0,1,1,0).\n\nChoose i=3. X becomes (0,1,1,2).\n\nSample Input 2\n\n3\n1\n2\n1\n\nSample Output 2\n\n-1\n\nSample Input 3\n\n9\n0\n1\n1\n0\n1\n2\n2\n1\n2\n\nSample Output 3\n\n8", "sample_input": "4\n0\n1\n1\n2\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03347", "source_text": "Score : 700 points\n\nProblem Statement\n\nThere is a sequence X of length N, where every element is initially 0. Let X_i denote the i-th element of X.\n\nYou are given a sequence A of length N. The i-th element of A is A_i. Determine if we can make X equal to A by repeating the operation below. If we can, find the minimum number of operations required.\n\nChoose an integer i such that 1\\leq i\\leq N-1. Replace the value of X_{i+1} with the value of X_i plus 1.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\n0 \\leq A_i \\leq 10^9(1\\leq i\\leq N)\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1\n:\nA_N\n\nOutput\n\nIf we can make X equal to A by repeating the operation, print the minimum number of operations required. If we cannot, print -1.\n\nSample Input 1\n\n4\n0\n1\n1\n2\n\nSample Output 1\n\n3\n\nWe can make X equal to A as follows:\n\nChoose i=2. X becomes (0,0,1,0).\n\nChoose i=1. X becomes (0,1,1,0).\n\nChoose i=3. X becomes (0,1,1,2).\n\nSample Input 2\n\n3\n1\n2\n1\n\nSample Output 2\n\n-1\n\nSample Input 3\n\n9\n0\n1\n1\n0\n1\n2\n2\n1\n2\n\nSample Output 3\n\n8", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 463, "cpu_time_ms": 106, "memory_kb": 1792}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s034371226", "group_id": "codeNet:p03352", "input_text": "#include \"bits/stdc++.h\"\nusing namespace std;\n#define rep(i,n) for(int i=0, i##_len=(n); i<i##_len; ++i)\ntypedef long long ll;\n\nint main(int argc, char* argv[]){\n    int X, ans;\n    cin >> X;\n\n    for(int i = 0; i*i <= X; i++){\n        ans = i*i;\n    }\n    cout << ans << endl;\n}", "language": "C++", "metadata": {"date": 1526175303, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03352.html", "problem_id": "p03352", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03352/input.txt", "sample_output_relpath": "derived/input_output/data/p03352/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03352/C++/s034371226.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s034371226", "user_id": "u992287017"}, "prompt_components": {"gold_output": "9\n", "input_to_evaluate": "#include \"bits/stdc++.h\"\nusing namespace std;\n#define rep(i,n) for(int i=0, i##_len=(n); i<i##_len; ++i)\ntypedef long long ll;\n\nint main(int argc, char* argv[]){\n    int X, ans;\n    cin >> X;\n\n    for(int i = 0; i*i <= X; i++){\n        ans = i*i;\n    }\n    cout << ans << endl;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nYou are given a positive integer X.\nFind the largest perfect power that is at most X.\nHere, a perfect power is an integer that can be represented as b^p, where b is an integer not less than 1 and p is an integer not less than 2.\n\nConstraints\n\n1 ≤ X ≤ 1000\n\nX is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint the largest perfect power that is at most X.\n\nSample Input 1\n\n10\n\nSample Output 1\n\n9\n\nThere are four perfect powers that are at most 10: 1, 4, 8 and 9.\nWe should print the largest among them, 9.\n\nSample Input 2\n\n1\n\nSample Output 2\n\n1\n\nSample Input 3\n\n999\n\nSample Output 3\n\n961", "sample_input": "10\n"}, "reference_outputs": ["9\n"], "source_document_id": "p03352", "source_text": "Score : 200 points\n\nProblem Statement\n\nYou are given a positive integer X.\nFind the largest perfect power that is at most X.\nHere, a perfect power is an integer that can be represented as b^p, where b is an integer not less than 1 and p is an integer not less than 2.\n\nConstraints\n\n1 ≤ X ≤ 1000\n\nX is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint the largest perfect power that is at most X.\n\nSample Input 1\n\n10\n\nSample Output 1\n\n9\n\nThere are four perfect powers that are at most 10: 1, 4, 8 and 9.\nWe should print the largest among them, 9.\n\nSample Input 2\n\n1\n\nSample Output 2\n\n1\n\nSample Input 3\n\n999\n\nSample Output 3\n\n961", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 279, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s499225691", "group_id": "codeNet:p03352", "input_text": "#include <iostream>\n#include <cmath>\n#define ll long long int\nusing namespace std;\n\nint main(int argc, char const* argv[])\n{\n\tint x;\n\tcin >> x;\n\tif(x == 1){\n\t\t\tcout << 1 << endl;\n\t\t\treturn 0;\n\t}\n  \tint max = 1;\n\tint y = 8;\n\twhile(y < x)y = y * 2;\n\tif(y / 2 > max && y / 2 <= x)max = y /2;\n\tfor(int i = 3; i < sqrt(x); i+=2){\n\t\t\tint z = i*i*i;\n\t\t\twhile(z < x)z = z*i;\n      \t\tif(z /i > x)continue;\n\t\t\tif(z/i > max)max = z/i;\n\t}\n\tcout << max << endl;\n\treturn 0;\n}\n\n", "language": "C++", "metadata": {"date": 1526174346, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03352.html", "problem_id": "p03352", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03352/input.txt", "sample_output_relpath": "derived/input_output/data/p03352/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03352/C++/s499225691.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s499225691", "user_id": "u424110125"}, "prompt_components": {"gold_output": "9\n", "input_to_evaluate": "#include <iostream>\n#include <cmath>\n#define ll long long int\nusing namespace std;\n\nint main(int argc, char const* argv[])\n{\n\tint x;\n\tcin >> x;\n\tif(x == 1){\n\t\t\tcout << 1 << endl;\n\t\t\treturn 0;\n\t}\n  \tint max = 1;\n\tint y = 8;\n\twhile(y < x)y = y * 2;\n\tif(y / 2 > max && y / 2 <= x)max = y /2;\n\tfor(int i = 3; i < sqrt(x); i+=2){\n\t\t\tint z = i*i*i;\n\t\t\twhile(z < x)z = z*i;\n      \t\tif(z /i > x)continue;\n\t\t\tif(z/i > max)max = z/i;\n\t}\n\tcout << max << endl;\n\treturn 0;\n}\n\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nYou are given a positive integer X.\nFind the largest perfect power that is at most X.\nHere, a perfect power is an integer that can be represented as b^p, where b is an integer not less than 1 and p is an integer not less than 2.\n\nConstraints\n\n1 ≤ X ≤ 1000\n\nX is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint the largest perfect power that is at most X.\n\nSample Input 1\n\n10\n\nSample Output 1\n\n9\n\nThere are four perfect powers that are at most 10: 1, 4, 8 and 9.\nWe should print the largest among them, 9.\n\nSample Input 2\n\n1\n\nSample Output 2\n\n1\n\nSample Input 3\n\n999\n\nSample Output 3\n\n961", "sample_input": "10\n"}, "reference_outputs": ["9\n"], "source_document_id": "p03352", "source_text": "Score : 200 points\n\nProblem Statement\n\nYou are given a positive integer X.\nFind the largest perfect power that is at most X.\nHere, a perfect power is an integer that can be represented as b^p, where b is an integer not less than 1 and p is an integer not less than 2.\n\nConstraints\n\n1 ≤ X ≤ 1000\n\nX is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint the largest perfect power that is at most X.\n\nSample Input 1\n\n10\n\nSample Output 1\n\n9\n\nThere are four perfect powers that are at most 10: 1, 4, 8 and 9.\nWe should print the largest among them, 9.\n\nSample Input 2\n\n1\n\nSample Output 2\n\n1\n\nSample Input 3\n\n999\n\nSample Output 3\n\n961", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 463, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s908028775", "group_id": "codeNet:p03353", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n\tstring S;\n\tint K;\n\n\tvector < string > vec;\n\t\n\tcin >> S >> K;\n\n\tfor ( int i = 0; i < S.size(); i++ ) {\n\t\tfor ( int j = 1; i + j <= S.size() && j <= K; j++ ) {\n\t\t\tvec.push_back(S.substr(i, j));\n\t\t}\n\t}\n\tsort(begin(vec), end(vec));\t\n\tvec.erase(unique(begin(vec), end(vec)), end(vec));\n\n\tcout << vec[K - 1] << endl;\n\n\treturn (0);\n}\n", "language": "C++", "metadata": {"date": 1526177726, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03353.html", "problem_id": "p03353", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03353/input.txt", "sample_output_relpath": "derived/input_output/data/p03353/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03353/C++/s908028775.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s908028775", "user_id": "u239239546"}, "prompt_components": {"gold_output": "b\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n\tstring S;\n\tint K;\n\n\tvector < string > vec;\n\t\n\tcin >> S >> K;\n\n\tfor ( int i = 0; i < S.size(); i++ ) {\n\t\tfor ( int j = 1; i + j <= S.size() && j <= K; j++ ) {\n\t\t\tvec.push_back(S.substr(i, j));\n\t\t}\n\t}\n\tsort(begin(vec), end(vec));\t\n\tvec.erase(unique(begin(vec), end(vec)), end(vec));\n\n\tcout << vec[K - 1] << endl;\n\n\treturn (0);\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nYou are given a string s.\nAmong the different substrings of s, print the K-th lexicographically smallest one.\n\nA substring of s is a string obtained by taking out a non-empty contiguous part in s.\nFor example, if s = ababc, a, bab and ababc are substrings of s, while ac, z and an empty string are not.\nAlso, we say that substrings are different when they are different as strings.\n\nLet X = x_{1}x_{2}...x_{n} and Y = y_{1}y_{2}...y_{m} be two distinct strings. X is lexicographically larger than Y if and only if Y is a prefix of X or x_{j} > y_{j} where j is the smallest integer such that x_{j} \\neq y_{j}.\n\nConstraints\n\n1 ≤ |s| ≤ 5000\n\ns consists of lowercase English letters.\n\n1 ≤ K ≤ 5\n\ns has at least K different substrings.\n\nPartial Score\n\n200 points will be awarded as a partial score for passing the test set satisfying |s| ≤ 50.\n\nInput\n\nInput is given from Standard Input in the following format:\n\ns\nK\n\nOutput\n\nPrint the K-th lexicographically smallest substring of K.\n\nSample Input 1\n\naba\n4\n\nSample Output 1\n\nb\n\ns has five substrings: a, b, ab, ba and aba.\nAmong them, we should print the fourth smallest one, b.\nNote that we do not count a twice.\n\nSample Input 2\n\natcoderandatcodeer\n5\n\nSample Output 2\n\nandat\n\nSample Input 3\n\nz\n1\n\nSample Output 3\n\nz", "sample_input": "aba\n4\n"}, "reference_outputs": ["b\n"], "source_document_id": "p03353", "source_text": "Score : 300 points\n\nProblem Statement\n\nYou are given a string s.\nAmong the different substrings of s, print the K-th lexicographically smallest one.\n\nA substring of s is a string obtained by taking out a non-empty contiguous part in s.\nFor example, if s = ababc, a, bab and ababc are substrings of s, while ac, z and an empty string are not.\nAlso, we say that substrings are different when they are different as strings.\n\nLet X = x_{1}x_{2}...x_{n} and Y = y_{1}y_{2}...y_{m} be two distinct strings. X is lexicographically larger than Y if and only if Y is a prefix of X or x_{j} > y_{j} where j is the smallest integer such that x_{j} \\neq y_{j}.\n\nConstraints\n\n1 ≤ |s| ≤ 5000\n\ns consists of lowercase English letters.\n\n1 ≤ K ≤ 5\n\ns has at least K different substrings.\n\nPartial Score\n\n200 points will be awarded as a partial score for passing the test set satisfying |s| ≤ 50.\n\nInput\n\nInput is given from Standard Input in the following format:\n\ns\nK\n\nOutput\n\nPrint the K-th lexicographically smallest substring of K.\n\nSample Input 1\n\naba\n4\n\nSample Output 1\n\nb\n\ns has five substrings: a, b, ab, ba and aba.\nAmong them, we should print the fourth smallest one, b.\nNote that we do not count a twice.\n\nSample Input 2\n\natcoderandatcodeer\n5\n\nSample Output 2\n\nandat\n\nSample Input 3\n\nz\n1\n\nSample Output 3\n\nz", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 388, "cpu_time_ms": 10, "memory_kb": 1660}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s156922219", "group_id": "codeNet:p03357", "input_text": "#include <iostream>\n#include <string>\n#include <algorithm>\n#include <vector>\n#include <iomanip>\n#include <queue>\n#include <stack>\n#include <cstdlib>\n#include <map>\n#include <iomanip>\n#include <set>\n#include <stdio.h>\n#include <ctype.h>\n#include <random>\n#include <string.h>\n#include <cmath>\n#include <unordered_map>\n#include <cstdio>\nusing namespace std;\n#define pie 3.141592653589793238462643383279\n#define int long long\n#define P pair<int,int>\n#define all(vec) vec.begin(),vec.end()\n\nint gcd(int x, int y) {\n\tif (y == 0)return x;\n\treturn gcd(y, x%y);\n}\nint lcm(int x, int y) {\n\treturn x / gcd(x, y)*y;\n}\nint kai(int x, int y, int m) {\n\tint res = 1;\n\tfor (int i = x - y + 1; i <= x; i++) {\n\t\tres *= i; res %= m;\n\t}\n\treturn res;\n}\nint mod_pow(int x, int y, int m) {\n\tint res = 1;\n\twhile (y > 0) {\n\t\tif (y & 1) {\n\t\t\tres = res * x % m;\n\t\t}\n\t\tx = x * x % m;\n\t\ty >>= 1;\n\t}\n\treturn res;\n}\n\nint comb(int x, int y, int m) {\n\tif (y > x)return 0;\n\treturn kai(x, y, m) * mod_pow(kai(y, y, m), m - 2, m) % m;\n}\n\nint n;\nP x[4010];\nint a[2010], b[2010];\nint cnt1[2010][2010], cnt2[2010][2010];\nbool bl1[2010], bl2[2010];\nint d[4010][2010];\n\nsigned main() {\n\tcin >> n;\n\tfor (int i = 1; i <= 2 * n; i++) {\n\t\tchar c; int p; cin >> c >> p;\n\t\tif (c == 'W')a[p] = i, x[i] = make_pair(p, 0);\n\t\telse b[p] = i, x[i] = make_pair(p, 1);\n\t}\n\tfor (int i = 2 * n; i >= 1; i--) {\n\t\tif (x[i].second == 0) {\n\t\t\tint cnt = 0;\n\t\t\tfor (int j = 1; j < x[i].first; j++)if (bl1[j])cnt++;\n\t\t\tfor (int j = 0; j <= n; j++) {\n\t\t\t\tif (bl2[j])cnt++;\n\t\t\t\tcnt1[x[i].first][j] = cnt;\n\t\t\t}\n\t\t\tbl1[x[i].first] = true;\n\t\t}\n\t\telse {\n\t\t\tint cnt = 0;\n\t\t\tfor (int j = 1; j < x[i].first; j++)if (bl2[j])cnt++;\n\t\t\tfor (int j = 0; j <= n; j++) {\n\t\t\t\tif (bl1[j])cnt++;\n\t\t\t\tcnt2[x[i].first][j] = cnt;\n\t\t\t}\n\t\t\tbl2[x[i].first] = true;\n\t\t}\n\t}\n\tfor (int i = 0; i <= 2 * n; i++)for (int j = 0; j <= n; j++)d[i][j] = 1000000000;\n\td[0][0] = 0;\n\tfor (int i = 1; i <= 2 * n; i++) {\n\t\tfor (int j = 0; j <= min(i - 1, n); j++)d[i][j] = min(d[i][j], d[i - 1][j] + cnt2[i - j][j]);\n\t\tfor (int j = 1; j <= min(i, n); j++)d[i][j] = min(d[i][j], d[i - 1][j - 1] + cnt1[j][i - j]);\n\t}\n\tcout << d[2 * n][n] << endl;\n}", "language": "C++", "metadata": {"date": 1591641840, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03357.html", "problem_id": "p03357", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03357/input.txt", "sample_output_relpath": "derived/input_output/data/p03357/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03357/C++/s156922219.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s156922219", "user_id": "u277153875"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <iostream>\n#include <string>\n#include <algorithm>\n#include <vector>\n#include <iomanip>\n#include <queue>\n#include <stack>\n#include <cstdlib>\n#include <map>\n#include <iomanip>\n#include <set>\n#include <stdio.h>\n#include <ctype.h>\n#include <random>\n#include <string.h>\n#include <cmath>\n#include <unordered_map>\n#include <cstdio>\nusing namespace std;\n#define pie 3.141592653589793238462643383279\n#define int long long\n#define P pair<int,int>\n#define all(vec) vec.begin(),vec.end()\n\nint gcd(int x, int y) {\n\tif (y == 0)return x;\n\treturn gcd(y, x%y);\n}\nint lcm(int x, int y) {\n\treturn x / gcd(x, y)*y;\n}\nint kai(int x, int y, int m) {\n\tint res = 1;\n\tfor (int i = x - y + 1; i <= x; i++) {\n\t\tres *= i; res %= m;\n\t}\n\treturn res;\n}\nint mod_pow(int x, int y, int m) {\n\tint res = 1;\n\twhile (y > 0) {\n\t\tif (y & 1) {\n\t\t\tres = res * x % m;\n\t\t}\n\t\tx = x * x % m;\n\t\ty >>= 1;\n\t}\n\treturn res;\n}\n\nint comb(int x, int y, int m) {\n\tif (y > x)return 0;\n\treturn kai(x, y, m) * mod_pow(kai(y, y, m), m - 2, m) % m;\n}\n\nint n;\nP x[4010];\nint a[2010], b[2010];\nint cnt1[2010][2010], cnt2[2010][2010];\nbool bl1[2010], bl2[2010];\nint d[4010][2010];\n\nsigned main() {\n\tcin >> n;\n\tfor (int i = 1; i <= 2 * n; i++) {\n\t\tchar c; int p; cin >> c >> p;\n\t\tif (c == 'W')a[p] = i, x[i] = make_pair(p, 0);\n\t\telse b[p] = i, x[i] = make_pair(p, 1);\n\t}\n\tfor (int i = 2 * n; i >= 1; i--) {\n\t\tif (x[i].second == 0) {\n\t\t\tint cnt = 0;\n\t\t\tfor (int j = 1; j < x[i].first; j++)if (bl1[j])cnt++;\n\t\t\tfor (int j = 0; j <= n; j++) {\n\t\t\t\tif (bl2[j])cnt++;\n\t\t\t\tcnt1[x[i].first][j] = cnt;\n\t\t\t}\n\t\t\tbl1[x[i].first] = true;\n\t\t}\n\t\telse {\n\t\t\tint cnt = 0;\n\t\t\tfor (int j = 1; j < x[i].first; j++)if (bl2[j])cnt++;\n\t\t\tfor (int j = 0; j <= n; j++) {\n\t\t\t\tif (bl1[j])cnt++;\n\t\t\t\tcnt2[x[i].first][j] = cnt;\n\t\t\t}\n\t\t\tbl2[x[i].first] = true;\n\t\t}\n\t}\n\tfor (int i = 0; i <= 2 * n; i++)for (int j = 0; j <= n; j++)d[i][j] = 1000000000;\n\td[0][0] = 0;\n\tfor (int i = 1; i <= 2 * n; i++) {\n\t\tfor (int j = 0; j <= min(i - 1, n); j++)d[i][j] = min(d[i][j], d[i - 1][j] + cnt2[i - j][j]);\n\t\tfor (int j = 1; j <= min(i, n); j++)d[i][j] = min(d[i][j], d[i - 1][j - 1] + cnt1[j][i - j]);\n\t}\n\tcout << d[2 * n][n] << endl;\n}", "problem_context": "Score : 600 points\n\nProblem Statement\n\nThere are 2N balls, N white and N black, arranged in a row. The integers from 1 through N are written on the white balls, one on each ball, and they are also written on the black balls, one on each ball.\nThe integer written on the i-th ball from the left (1 ≤ i ≤ 2N) is a_i, and the color of this ball is represented by a letter c_i.\nc_i = W represents the ball is white; c_i = B represents the ball is black.\n\nTakahashi the human wants to achieve the following objective:\n\nFor every pair of integers (i,j) such that 1 ≤ i < j ≤ N, the white ball with i written on it is to the left of the white ball with j written on it.\n\nFor every pair of integers (i,j) such that 1 ≤ i < j ≤ N, the black ball with i written on it is to the left of the black ball with j written on it.\n\nIn order to achieve this, he can perform the following operation:\n\nSwap two adjacent balls.\n\nFind the minimum number of operations required to achieve the objective.\n\nConstraints\n\n1 ≤ N ≤ 2000\n\n1 ≤ a_i ≤ N\n\nc_i = W or c_i = B.\n\nIf i ≠ j, (a_i,c_i) ≠ (a_j,c_j).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nc_1 a_1\nc_2 a_2\n:\nc_{2N} a_{2N}\n\nOutput\n\nPrint the minimum number of operations required to achieve the objective.\n\nSample Input 1\n\n3\nB 1\nW 2\nB 3\nW 1\nW 3\nB 2\n\nSample Output 1\n\n4\n\nThe objective can be achieved in four operations, for example, as follows:\n\nSwap the black 3 and white 1.\n\nSwap the white 1 and white 2.\n\nSwap the black 3 and white 3.\n\nSwap the black 3 and black 2.\n\nSample Input 2\n\n4\nB 4\nW 4\nB 3\nW 3\nB 2\nW 2\nB 1\nW 1\n\nSample Output 2\n\n18\n\nSample Input 3\n\n9\nW 3\nB 1\nB 4\nW 1\nB 5\nW 9\nW 2\nB 6\nW 5\nB 3\nW 8\nB 9\nW 7\nB 2\nB 8\nW 4\nW 6\nB 7\n\nSample Output 3\n\n41", "sample_input": "3\nB 1\nW 2\nB 3\nW 1\nW 3\nB 2\n"}, "reference_outputs": ["4\n"], "source_document_id": "p03357", "source_text": "Score : 600 points\n\nProblem Statement\n\nThere are 2N balls, N white and N black, arranged in a row. The integers from 1 through N are written on the white balls, one on each ball, and they are also written on the black balls, one on each ball.\nThe integer written on the i-th ball from the left (1 ≤ i ≤ 2N) is a_i, and the color of this ball is represented by a letter c_i.\nc_i = W represents the ball is white; c_i = B represents the ball is black.\n\nTakahashi the human wants to achieve the following objective:\n\nFor every pair of integers (i,j) such that 1 ≤ i < j ≤ N, the white ball with i written on it is to the left of the white ball with j written on it.\n\nFor every pair of integers (i,j) such that 1 ≤ i < j ≤ N, the black ball with i written on it is to the left of the black ball with j written on it.\n\nIn order to achieve this, he can perform the following operation:\n\nSwap two adjacent balls.\n\nFind the minimum number of operations required to achieve the objective.\n\nConstraints\n\n1 ≤ N ≤ 2000\n\n1 ≤ a_i ≤ N\n\nc_i = W or c_i = B.\n\nIf i ≠ j, (a_i,c_i) ≠ (a_j,c_j).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nc_1 a_1\nc_2 a_2\n:\nc_{2N} a_{2N}\n\nOutput\n\nPrint the minimum number of operations required to achieve the objective.\n\nSample Input 1\n\n3\nB 1\nW 2\nB 3\nW 1\nW 3\nB 2\n\nSample Output 1\n\n4\n\nThe objective can be achieved in four operations, for example, as follows:\n\nSwap the black 3 and white 1.\n\nSwap the white 1 and white 2.\n\nSwap the black 3 and white 3.\n\nSwap the black 3 and black 2.\n\nSample Input 2\n\n4\nB 4\nW 4\nB 3\nW 3\nB 2\nW 2\nB 1\nW 1\n\nSample Output 2\n\n18\n\nSample Input 3\n\n9\nW 3\nB 1\nB 4\nW 1\nB 5\nW 9\nW 2\nB 6\nW 5\nB 3\nW 8\nB 9\nW 7\nB 2\nB 8\nW 4\nW 6\nB 7\n\nSample Output 3\n\n41", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2141, "cpu_time_ms": 107, "memory_kb": 126336}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s073949542", "group_id": "codeNet:p03357", "input_text": "#include <bits/stdc++.h>\n\nusing namespace std;\ntypedef long long ll;\n\n#define REP(i,n) for(int i=0;i<n;++i)\n#define SORT(name) sort(name.begin(), name.end())\n#define ZERO(p) memset(p, 0, sizeof(p))\n#define MINUS(p) memset(p, -1, sizeof(p))\n#if 1\n#  define DBG(fmt, ...) printf(fmt, ##__VA_ARGS__)\n#else\n#  define DBG(fmt, ...)\n#endif\n\nconst ll LLINF = (1LL<<60);\nconst int INF = (1LL<<30);\nconst int MOD = 1000000007;\n#define MAX_N 2010\n#define MAX_2N 4010\n\nll N;\nchar C[MAX_N] = {};\nll A[MAX_N] = {};\n\n// 1-indexed であることに注意\ntemplate<typename T>\nclass BITree {\n    public:\n        BITree(int n) : m_N(n + 1) { m_Tree.assign(m_N, 0); }\n        // [1, i] の合計値を返す (log m_N)\n        // 閉区間であることに注意\n        T Sum(int i) {\n            if(i < 1 || i >= m_N) { return 0; }\n            T s = 0;\n            while(i > 0) { s += m_Tree[i]; i -= i & -i; }\n            return s;\n        }\n        // [i, j] の合計値を返す (log m_N)\n        // i < j\n        // 閉区間であることに注意\n        T Sum(int i, int j) {\n            if(i > j) { return 0; }\n            return Sum(j) - Sum(i-1);\n        }\n        // i 番目の要素(1-indexed)に x を足して更新 O(log m_N)\n        void Add(int i, T x){ while(i < m_N) { m_Tree[i] += x; i += i & -i; } }\n    private:\n        int m_N;            // 要素数\n        vector<T> m_Tree;   // BIT 本体\n};\n\n// 順列 p の転倒数を返す (転倒数：順番を維持したままペアをとったとき、左の数字の方が大きいペアの数)\n// O (N log N) (N: 順列の最大値)\ntemplate<typename T>\nT GetInversionCnt(const vector<T>& p) {\n    T ret = 0;\n    T max_val = 0;\n    for(auto& val : p) { max_val = max(max_val, val); }\n    BITree<T> bit(max_val);    // 以左に現れた数を BIT で管理\n    for(int i = 0; i < p.size(); ++i) {\n        ret += bit.Sum(p[i] + 1, max_val);  // 自分より大きいものを数える\n        bit.Add(p[i], 1);   // 現れた数を更新\n    }\n    return ret;\n}\n\n// 2 つの順列の転倒距離を求める\n// 転倒距離：同じサイズ N の順列 X と Y で順番が入れ替わっている数字のペアの数\n// X か Y のどちらかが (1, 2, 3 .., N) なら、転倒距離はもう一方の転倒数\n// O(N log N)\ntemplate<typename T>\nT GetInversionDist(const vector<T>& v1, const vector<T>& v2) {\n    assert(v1.size() == v2.size());\n    vector<T> val_to_ind, comp;\n    val_to_ind.assign(v1.size() + 1, 0);\n    for(int i = 0; i < v1.size(); ++i) {\n        val_to_ind[v1[i]] = i + 1;\n    }\n    for(int i = 0; i < v2.size(); ++i) {\n        comp.push_back(val_to_ind[v2[i]]);\n    }\n    return GetInversionCnt(comp);\n}\n\n// b とかぶらない数にする\nstatic inline ll change_w(ll w) { return w + N; }\n\nenum CostType { CostB = 0, CostW };\n\n// B を [1,i] , W を [1,j] 個既に置いているときに黒の i+1 を置いた時の転倒数\nll cost(ll i, ll j, ll type) {\n#if 0\n    vector<ll> v1, v2;\n    // [1,i], [1,j] の置き方は合わせる\n    for(ll b = 1; b <= i; ++b) {\n        v1.push_back(b);\n        v2.push_back(b);\n    }\n    for(ll w = 1; w <= j; ++w) {\n        v1.push_back(change_w(w));\n        v2.push_back(change_w(w));\n    }\n    if(type == CostB) { v1.push_back(i+1); }\n    else { v1.push_back(change_w(j+1)); }\n\n    // 残りを置いていく\n    REP(ind, 2 * N) {\n        if(C[ind] == 'B') {\n            if(type == CostB) {\n                if(A[ind] == i + 1) { v2.push_back(A[ind]); }\n                else if(A[ind] > i + 1) { v1.push_back(A[ind]); v2.push_back(A[ind]); }\n            } else {\n                if(A[ind] > i) { v1.push_back(A[ind]); v2.push_back(A[ind]); }\n            }\n        } else {\n            if(type == CostB) {\n                if(A[ind] > j) { v1.push_back(change_w(A[ind])); v2.push_back(change_w(A[ind])); }\n            } else {\n                if(A[ind] == j + 1) { v2.push_back(change_w(A[ind])); }\n                else if(A[ind] > j + 1) { v1.push_back(change_w(A[ind])); v2.push_back(change_w(A[ind])); }\n            }\n        }\n    }\n    ll ret = GetInversionDist(v1, v2);\n#else\n\n    // 現在の i+1/j+1 の位置 から左にある i と j より大きいものの数\n    ll ret = 0;\n    ll cur = 0;\n    for(cur = 0; cur < 2 * N; ++cur) {\n        if((type == CostB && C[cur] == 'B' && A[cur] == i+1) ||\n           (type == CostW && C[cur] == 'W' && A[cur] == j+1)) {\n            break;\n        }\n    }\n    BITree<ll> bit_B(N), bit_W(N);    // 以左に現れた数を BIT で管理\n    for(ll ind = 0; ind < cur; ++ind) {\n        // 現れた数を更新\n        if(C[ind] == 'B') { bit_B.Add(A[ind], 1); }\n        else { bit_W.Add(A[ind], 1); }\n\n    }\n    if(type == CostB) {\n        ret += bit_B.Sum(i+2, N);\n        ret += bit_W.Sum(j+1, N);\n    }\n    else {\n        ret += bit_B.Sum(i+1, N);\n        ret += bit_W.Sum(j+2, N);\n    }\n#endif\n    //DBG(\"i: %lld j: %lld type: %c ret: %lld\\n\", i, j, (type == CostB) ? 'B' : 'W', ret);\n    return ret;\n}\n\nll dp[MAX_N][MAX_N] = {};\n\n// B を [1,i] 個, W を [1,j] 個置いた時の最小転倒数\nll dfs(ll i, ll j) {\n    if(i <= 0 && j <= 0) {\n        dp[0][0] = 0;\n        return 0;\n    }\n    if(dp[i][j] != -1) { return dp[i][j]; }\n    ll cand1 = INF, cand2 = INF;\n    if(i > 0) { cand1 = dfs(i-1, j) + cost(i-1, j, CostB); }\n    if(j > 0) { cand2 = dfs(i, j-1) + cost(i, j-1, CostW); }\n    dp[i][j] = min(cand1, cand2);\n    return dp[i][j];\n}\n\nsigned main()\n{\n    cin >> N;\n    REP(i, 2 * N) { cin >> C[i] >> A[i]; }\n    MINUS(dp);\n    printf(\"%lld\\n\", dfs(N, N));\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1527717552, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03357.html", "problem_id": "p03357", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03357/input.txt", "sample_output_relpath": "derived/input_output/data/p03357/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03357/C++/s073949542.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s073949542", "user_id": "u633020228"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\nusing namespace std;\ntypedef long long ll;\n\n#define REP(i,n) for(int i=0;i<n;++i)\n#define SORT(name) sort(name.begin(), name.end())\n#define ZERO(p) memset(p, 0, sizeof(p))\n#define MINUS(p) memset(p, -1, sizeof(p))\n#if 1\n#  define DBG(fmt, ...) printf(fmt, ##__VA_ARGS__)\n#else\n#  define DBG(fmt, ...)\n#endif\n\nconst ll LLINF = (1LL<<60);\nconst int INF = (1LL<<30);\nconst int MOD = 1000000007;\n#define MAX_N 2010\n#define MAX_2N 4010\n\nll N;\nchar C[MAX_N] = {};\nll A[MAX_N] = {};\n\n// 1-indexed であることに注意\ntemplate<typename T>\nclass BITree {\n    public:\n        BITree(int n) : m_N(n + 1) { m_Tree.assign(m_N, 0); }\n        // [1, i] の合計値を返す (log m_N)\n        // 閉区間であることに注意\n        T Sum(int i) {\n            if(i < 1 || i >= m_N) { return 0; }\n            T s = 0;\n            while(i > 0) { s += m_Tree[i]; i -= i & -i; }\n            return s;\n        }\n        // [i, j] の合計値を返す (log m_N)\n        // i < j\n        // 閉区間であることに注意\n        T Sum(int i, int j) {\n            if(i > j) { return 0; }\n            return Sum(j) - Sum(i-1);\n        }\n        // i 番目の要素(1-indexed)に x を足して更新 O(log m_N)\n        void Add(int i, T x){ while(i < m_N) { m_Tree[i] += x; i += i & -i; } }\n    private:\n        int m_N;            // 要素数\n        vector<T> m_Tree;   // BIT 本体\n};\n\n// 順列 p の転倒数を返す (転倒数：順番を維持したままペアをとったとき、左の数字の方が大きいペアの数)\n// O (N log N) (N: 順列の最大値)\ntemplate<typename T>\nT GetInversionCnt(const vector<T>& p) {\n    T ret = 0;\n    T max_val = 0;\n    for(auto& val : p) { max_val = max(max_val, val); }\n    BITree<T> bit(max_val);    // 以左に現れた数を BIT で管理\n    for(int i = 0; i < p.size(); ++i) {\n        ret += bit.Sum(p[i] + 1, max_val);  // 自分より大きいものを数える\n        bit.Add(p[i], 1);   // 現れた数を更新\n    }\n    return ret;\n}\n\n// 2 つの順列の転倒距離を求める\n// 転倒距離：同じサイズ N の順列 X と Y で順番が入れ替わっている数字のペアの数\n// X か Y のどちらかが (1, 2, 3 .., N) なら、転倒距離はもう一方の転倒数\n// O(N log N)\ntemplate<typename T>\nT GetInversionDist(const vector<T>& v1, const vector<T>& v2) {\n    assert(v1.size() == v2.size());\n    vector<T> val_to_ind, comp;\n    val_to_ind.assign(v1.size() + 1, 0);\n    for(int i = 0; i < v1.size(); ++i) {\n        val_to_ind[v1[i]] = i + 1;\n    }\n    for(int i = 0; i < v2.size(); ++i) {\n        comp.push_back(val_to_ind[v2[i]]);\n    }\n    return GetInversionCnt(comp);\n}\n\n// b とかぶらない数にする\nstatic inline ll change_w(ll w) { return w + N; }\n\nenum CostType { CostB = 0, CostW };\n\n// B を [1,i] , W を [1,j] 個既に置いているときに黒の i+1 を置いた時の転倒数\nll cost(ll i, ll j, ll type) {\n#if 0\n    vector<ll> v1, v2;\n    // [1,i], [1,j] の置き方は合わせる\n    for(ll b = 1; b <= i; ++b) {\n        v1.push_back(b);\n        v2.push_back(b);\n    }\n    for(ll w = 1; w <= j; ++w) {\n        v1.push_back(change_w(w));\n        v2.push_back(change_w(w));\n    }\n    if(type == CostB) { v1.push_back(i+1); }\n    else { v1.push_back(change_w(j+1)); }\n\n    // 残りを置いていく\n    REP(ind, 2 * N) {\n        if(C[ind] == 'B') {\n            if(type == CostB) {\n                if(A[ind] == i + 1) { v2.push_back(A[ind]); }\n                else if(A[ind] > i + 1) { v1.push_back(A[ind]); v2.push_back(A[ind]); }\n            } else {\n                if(A[ind] > i) { v1.push_back(A[ind]); v2.push_back(A[ind]); }\n            }\n        } else {\n            if(type == CostB) {\n                if(A[ind] > j) { v1.push_back(change_w(A[ind])); v2.push_back(change_w(A[ind])); }\n            } else {\n                if(A[ind] == j + 1) { v2.push_back(change_w(A[ind])); }\n                else if(A[ind] > j + 1) { v1.push_back(change_w(A[ind])); v2.push_back(change_w(A[ind])); }\n            }\n        }\n    }\n    ll ret = GetInversionDist(v1, v2);\n#else\n\n    // 現在の i+1/j+1 の位置 から左にある i と j より大きいものの数\n    ll ret = 0;\n    ll cur = 0;\n    for(cur = 0; cur < 2 * N; ++cur) {\n        if((type == CostB && C[cur] == 'B' && A[cur] == i+1) ||\n           (type == CostW && C[cur] == 'W' && A[cur] == j+1)) {\n            break;\n        }\n    }\n    BITree<ll> bit_B(N), bit_W(N);    // 以左に現れた数を BIT で管理\n    for(ll ind = 0; ind < cur; ++ind) {\n        // 現れた数を更新\n        if(C[ind] == 'B') { bit_B.Add(A[ind], 1); }\n        else { bit_W.Add(A[ind], 1); }\n\n    }\n    if(type == CostB) {\n        ret += bit_B.Sum(i+2, N);\n        ret += bit_W.Sum(j+1, N);\n    }\n    else {\n        ret += bit_B.Sum(i+1, N);\n        ret += bit_W.Sum(j+2, N);\n    }\n#endif\n    //DBG(\"i: %lld j: %lld type: %c ret: %lld\\n\", i, j, (type == CostB) ? 'B' : 'W', ret);\n    return ret;\n}\n\nll dp[MAX_N][MAX_N] = {};\n\n// B を [1,i] 個, W を [1,j] 個置いた時の最小転倒数\nll dfs(ll i, ll j) {\n    if(i <= 0 && j <= 0) {\n        dp[0][0] = 0;\n        return 0;\n    }\n    if(dp[i][j] != -1) { return dp[i][j]; }\n    ll cand1 = INF, cand2 = INF;\n    if(i > 0) { cand1 = dfs(i-1, j) + cost(i-1, j, CostB); }\n    if(j > 0) { cand2 = dfs(i, j-1) + cost(i, j-1, CostW); }\n    dp[i][j] = min(cand1, cand2);\n    return dp[i][j];\n}\n\nsigned main()\n{\n    cin >> N;\n    REP(i, 2 * N) { cin >> C[i] >> A[i]; }\n    MINUS(dp);\n    printf(\"%lld\\n\", dfs(N, N));\n    return 0;\n}\n", "problem_context": "Score : 600 points\n\nProblem Statement\n\nThere are 2N balls, N white and N black, arranged in a row. The integers from 1 through N are written on the white balls, one on each ball, and they are also written on the black balls, one on each ball.\nThe integer written on the i-th ball from the left (1 ≤ i ≤ 2N) is a_i, and the color of this ball is represented by a letter c_i.\nc_i = W represents the ball is white; c_i = B represents the ball is black.\n\nTakahashi the human wants to achieve the following objective:\n\nFor every pair of integers (i,j) such that 1 ≤ i < j ≤ N, the white ball with i written on it is to the left of the white ball with j written on it.\n\nFor every pair of integers (i,j) such that 1 ≤ i < j ≤ N, the black ball with i written on it is to the left of the black ball with j written on it.\n\nIn order to achieve this, he can perform the following operation:\n\nSwap two adjacent balls.\n\nFind the minimum number of operations required to achieve the objective.\n\nConstraints\n\n1 ≤ N ≤ 2000\n\n1 ≤ a_i ≤ N\n\nc_i = W or c_i = B.\n\nIf i ≠ j, (a_i,c_i) ≠ (a_j,c_j).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nc_1 a_1\nc_2 a_2\n:\nc_{2N} a_{2N}\n\nOutput\n\nPrint the minimum number of operations required to achieve the objective.\n\nSample Input 1\n\n3\nB 1\nW 2\nB 3\nW 1\nW 3\nB 2\n\nSample Output 1\n\n4\n\nThe objective can be achieved in four operations, for example, as follows:\n\nSwap the black 3 and white 1.\n\nSwap the white 1 and white 2.\n\nSwap the black 3 and white 3.\n\nSwap the black 3 and black 2.\n\nSample Input 2\n\n4\nB 4\nW 4\nB 3\nW 3\nB 2\nW 2\nB 1\nW 1\n\nSample Output 2\n\n18\n\nSample Input 3\n\n9\nW 3\nB 1\nB 4\nW 1\nB 5\nW 9\nW 2\nB 6\nW 5\nB 3\nW 8\nB 9\nW 7\nB 2\nB 8\nW 4\nW 6\nB 7\n\nSample Output 3\n\n41", "sample_input": "3\nB 1\nW 2\nB 3\nW 1\nW 3\nB 2\n"}, "reference_outputs": ["4\n"], "source_document_id": "p03357", "source_text": "Score : 600 points\n\nProblem Statement\n\nThere are 2N balls, N white and N black, arranged in a row. The integers from 1 through N are written on the white balls, one on each ball, and they are also written on the black balls, one on each ball.\nThe integer written on the i-th ball from the left (1 ≤ i ≤ 2N) is a_i, and the color of this ball is represented by a letter c_i.\nc_i = W represents the ball is white; c_i = B represents the ball is black.\n\nTakahashi the human wants to achieve the following objective:\n\nFor every pair of integers (i,j) such that 1 ≤ i < j ≤ N, the white ball with i written on it is to the left of the white ball with j written on it.\n\nFor every pair of integers (i,j) such that 1 ≤ i < j ≤ N, the black ball with i written on it is to the left of the black ball with j written on it.\n\nIn order to achieve this, he can perform the following operation:\n\nSwap two adjacent balls.\n\nFind the minimum number of operations required to achieve the objective.\n\nConstraints\n\n1 ≤ N ≤ 2000\n\n1 ≤ a_i ≤ N\n\nc_i = W or c_i = B.\n\nIf i ≠ j, (a_i,c_i) ≠ (a_j,c_j).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nc_1 a_1\nc_2 a_2\n:\nc_{2N} a_{2N}\n\nOutput\n\nPrint the minimum number of operations required to achieve the objective.\n\nSample Input 1\n\n3\nB 1\nW 2\nB 3\nW 1\nW 3\nB 2\n\nSample Output 1\n\n4\n\nThe objective can be achieved in four operations, for example, as follows:\n\nSwap the black 3 and white 1.\n\nSwap the white 1 and white 2.\n\nSwap the black 3 and white 3.\n\nSwap the black 3 and black 2.\n\nSample Input 2\n\n4\nB 4\nW 4\nB 3\nW 3\nB 2\nW 2\nB 1\nW 1\n\nSample Output 2\n\n18\n\nSample Input 3\n\n9\nW 3\nB 1\nB 4\nW 1\nB 5\nW 9\nW 2\nB 6\nW 5\nB 3\nW 8\nB 9\nW 7\nB 2\nB 8\nW 4\nW 6\nB 7\n\nSample Output 3\n\n41", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 5568, "cpu_time_ms": 2104, "memory_kb": 31872}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s368614778", "group_id": "codeNet:p03358", "input_text": "#include <bits/stdc++.h>\n#define int long long\n\nusing namespace std;\n\nconst int MaxN = 1e5 + 15;\n\nint n;\nvector <int> v[MaxN];\nstring s;\n\n\nint cnt[MaxN];\n\nint dp[MaxN];\nint dp1[MaxN];\nint dp2[MaxN];\n\nint all;\nint bw;\n\nvoid dfs(int x, int p = 0)\n{\n    ++all;\n\n    vector <int> dps;\n\n    bool OK = false;\n\n    for(int to : v[x])\n        if(to != p)\n            if(cnt[to] > 0)\n            {\n                dfs(to, x);\n\n                dps.push_back(dp1[to]);\n\n                int cur = 1 + dp1[to] - (s[x] == 'B' ? 1 : -1);\n\n                if(!p)\n                    --cur;\n\n                dp1[x] = max(dp1[x], cur);\n                OK = true;\n\n                dp[x] = max(dp[x], dp[to]);\n            }\n\n    if(!OK)\n    {\n        dp[x] = 0;\n    }else\n        if(dps.size() > 1)\n    {\n        sort(dps.begin(), dps.end());\n        dp2[x] = dps.back() + dps[dps.size() - 2];\n    }\n\n    dp[x] = max(max(dp[x], dp1[x]), dp2[x]);\n\n\n\n    if(!p)\n        OK = false;\n\n    if(OK && s[x] == 'W')\n        ++bw;\n\n    --dp[x];\n}\n\nmain()\n{\n//    freopen(\"output.txt\", \"r\", stdin);\n\n    ios_base :: sync_with_stdio(false);\n    cin.tie(NULL);\n\n    cin >> n;\n\n    for(int i = 1; i < n; ++i)\n    {\n        int x, y;\n        cin >> x >> y;\n        v[x].push_back(y);\n        v[y].push_back(x);\n\n        ++cnt[x];\n        ++cnt[y];\n    }\n\n    cin >> s;\n    s = \"#\" + s;\n\n    set<int> ss;\n\n    for(int i = 1; i <= n; ++i)\n    {\n        if(cnt[i] == 1 && s[i] == 'B')\n            ss.insert(i);\n    }\n\n    while(!ss.empty())\n    {\n        int x = (*ss.begin());\n        ss.erase(ss.begin());\n\n        cnt[x] = -1;\n\n        for(int to : v[x])\n        {\n            --cnt[to];\n            if(cnt[to] == 1 && s[to] == 'B')\n                ss.insert(to);\n        }\n    }\n\n    int root = 0;\n\n    for(int i = 1; i <= n; ++i)\n        if(cnt[i] == 1)\n            root = i;\n\n    if(!root)\n    {\n        return cout << 0 << '\\n', 0;\n    }\n\n    dfs(root);\n\n    //cout << root << ' ' << all << ' ' << bw << ' ' << dp[root] << '\\n';\n\n    cout << 2 * (all - 1) + bw - dp[root] << '\\n';\n\n    return 0;\n}\n/**\n1212\nWBBW\n*/\n", "language": "C++", "metadata": {"date": 1526179161, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03358.html", "problem_id": "p03358", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03358/input.txt", "sample_output_relpath": "derived/input_output/data/p03358/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03358/C++/s368614778.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s368614778", "user_id": "u784576081"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define int long long\n\nusing namespace std;\n\nconst int MaxN = 1e5 + 15;\n\nint n;\nvector <int> v[MaxN];\nstring s;\n\n\nint cnt[MaxN];\n\nint dp[MaxN];\nint dp1[MaxN];\nint dp2[MaxN];\n\nint all;\nint bw;\n\nvoid dfs(int x, int p = 0)\n{\n    ++all;\n\n    vector <int> dps;\n\n    bool OK = false;\n\n    for(int to : v[x])\n        if(to != p)\n            if(cnt[to] > 0)\n            {\n                dfs(to, x);\n\n                dps.push_back(dp1[to]);\n\n                int cur = 1 + dp1[to] - (s[x] == 'B' ? 1 : -1);\n\n                if(!p)\n                    --cur;\n\n                dp1[x] = max(dp1[x], cur);\n                OK = true;\n\n                dp[x] = max(dp[x], dp[to]);\n            }\n\n    if(!OK)\n    {\n        dp[x] = 0;\n    }else\n        if(dps.size() > 1)\n    {\n        sort(dps.begin(), dps.end());\n        dp2[x] = dps.back() + dps[dps.size() - 2];\n    }\n\n    dp[x] = max(max(dp[x], dp1[x]), dp2[x]);\n\n\n\n    if(!p)\n        OK = false;\n\n    if(OK && s[x] == 'W')\n        ++bw;\n\n    --dp[x];\n}\n\nmain()\n{\n//    freopen(\"output.txt\", \"r\", stdin);\n\n    ios_base :: sync_with_stdio(false);\n    cin.tie(NULL);\n\n    cin >> n;\n\n    for(int i = 1; i < n; ++i)\n    {\n        int x, y;\n        cin >> x >> y;\n        v[x].push_back(y);\n        v[y].push_back(x);\n\n        ++cnt[x];\n        ++cnt[y];\n    }\n\n    cin >> s;\n    s = \"#\" + s;\n\n    set<int> ss;\n\n    for(int i = 1; i <= n; ++i)\n    {\n        if(cnt[i] == 1 && s[i] == 'B')\n            ss.insert(i);\n    }\n\n    while(!ss.empty())\n    {\n        int x = (*ss.begin());\n        ss.erase(ss.begin());\n\n        cnt[x] = -1;\n\n        for(int to : v[x])\n        {\n            --cnt[to];\n            if(cnt[to] == 1 && s[to] == 'B')\n                ss.insert(to);\n        }\n    }\n\n    int root = 0;\n\n    for(int i = 1; i <= n; ++i)\n        if(cnt[i] == 1)\n            root = i;\n\n    if(!root)\n    {\n        return cout << 0 << '\\n', 0;\n    }\n\n    dfs(root);\n\n    //cout << root << ' ' << all << ' ' << bw << ' ' << dp[root] << '\\n';\n\n    cout << 2 * (all - 1) + bw - dp[root] << '\\n';\n\n    return 0;\n}\n/**\n1212\nWBBW\n*/\n", "problem_context": "Score : 800 points\n\nProblem Statement\n\nThere is a tree with N vertices numbered 1 through N.\nThe i-th edge connects Vertex x_i and y_i.\nEach vertex is painted white or black.\nThe initial color of Vertex i is represented by a letter c_i.\nc_i = W represents the vertex is white; c_i = B represents the vertex is black.\n\nA cat will walk along this tree.\nMore specifically, she performs one of the following in one second repeatedly:\n\nChoose a vertex that is adjacent to the vertex where she is currently, and move to that vertex. Then, invert the color of the destination vertex.\n\nInvert the color of the vertex where she is currently.\n\nThe cat's objective is to paint all the vertices black. She may start and end performing actions at any vertex.\nAt least how many seconds does it takes for the cat to achieve her objective?\n\nConstraints\n\n1 ≤ N ≤ 10^5\n\n1 ≤ x_i,y_i ≤ N (1 ≤ i ≤ N-1)\n\nThe given graph is a tree.\n\nc_i = W or c_i = B.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nx_1 y_1\nx_2 y_2\n:\nx_{N-1} y_{N-1}\nc_1c_2..c_N\n\nOutput\n\nPrint the minimum number of seconds required to achieve the objective.\n\nSample Input 1\n\n5\n1 2\n2 3\n2 4\n4 5\nWBBWW\n\nSample Output 1\n\n5\n\nThe objective can be achieved in five seconds, for example, as follows:\n\nStart at Vertex 1. Change the color of Vertex 1 to black.\n\nMove to Vertex 2, then change the color of Vertex 2 to white.\n\nChange the color of Vertex 2 to black.\n\nMove to Vertex 4, then change the color of Vertex 4 to black.\n\nMove to Vertex 5, then change the color of Vertex 5 to black.\n\nSample Input 2\n\n6\n3 1\n4 5\n2 6\n6 1\n3 4\nWWBWBB\n\nSample Output 2\n\n7\n\nSample Input 3\n\n1\nB\n\nSample Output 3\n\n0\n\nSample Input 4\n\n20\n2 19\n5 13\n6 4\n15 6\n12 19\n13 19\n3 11\n8 3\n3 20\n16 13\n7 14\n3 17\n7 8\n10 20\n11 9\n8 18\n8 2\n10 1\n6 13\nWBWBWBBWWWBBWWBBBBBW\n\nSample Output 4\n\n21", "sample_input": "5\n1 2\n2 3\n2 4\n4 5\nWBBWW\n"}, "reference_outputs": ["5\n"], "source_document_id": "p03358", "source_text": "Score : 800 points\n\nProblem Statement\n\nThere is a tree with N vertices numbered 1 through N.\nThe i-th edge connects Vertex x_i and y_i.\nEach vertex is painted white or black.\nThe initial color of Vertex i is represented by a letter c_i.\nc_i = W represents the vertex is white; c_i = B represents the vertex is black.\n\nA cat will walk along this tree.\nMore specifically, she performs one of the following in one second repeatedly:\n\nChoose a vertex that is adjacent to the vertex where she is currently, and move to that vertex. Then, invert the color of the destination vertex.\n\nInvert the color of the vertex where she is currently.\n\nThe cat's objective is to paint all the vertices black. She may start and end performing actions at any vertex.\nAt least how many seconds does it takes for the cat to achieve her objective?\n\nConstraints\n\n1 ≤ N ≤ 10^5\n\n1 ≤ x_i,y_i ≤ N (1 ≤ i ≤ N-1)\n\nThe given graph is a tree.\n\nc_i = W or c_i = B.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nx_1 y_1\nx_2 y_2\n:\nx_{N-1} y_{N-1}\nc_1c_2..c_N\n\nOutput\n\nPrint the minimum number of seconds required to achieve the objective.\n\nSample Input 1\n\n5\n1 2\n2 3\n2 4\n4 5\nWBBWW\n\nSample Output 1\n\n5\n\nThe objective can be achieved in five seconds, for example, as follows:\n\nStart at Vertex 1. Change the color of Vertex 1 to black.\n\nMove to Vertex 2, then change the color of Vertex 2 to white.\n\nChange the color of Vertex 2 to black.\n\nMove to Vertex 4, then change the color of Vertex 4 to black.\n\nMove to Vertex 5, then change the color of Vertex 5 to black.\n\nSample Input 2\n\n6\n3 1\n4 5\n2 6\n6 1\n3 4\nWWBWBB\n\nSample Output 2\n\n7\n\nSample Input 3\n\n1\nB\n\nSample Output 3\n\n0\n\nSample Input 4\n\n20\n2 19\n5 13\n6 4\n15 6\n12 19\n13 19\n3 11\n8 3\n3 20\n16 13\n7 14\n3 17\n7 8\n10 20\n11 9\n8 18\n8 2\n10 1\n6 13\nWBWBWBBWWWBBWWBBBBBW\n\nSample Output 4\n\n21", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2084, "cpu_time_ms": 62, "memory_kb": 17644}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s502898206", "group_id": "codeNet:p03363", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nint main() {\n  int n;\n  cin >> n;\n  vector<ll> a(n);\n  for(int i=0; i<n; i++){\n    cin >> a[i];\n  }\n  map<ll, ll> s;\n  vector<ll> l(n+1);\n  s[l[0]]++;\n  for(int i=0; i<n; i++){\n    l[i+1] = l[i] + a[i];\n    s[l[i+1]]++;\n  }\n  ll ans = 0;\n  for(auto p : s){\n    ll num = p.second;\n    ans += (ll)num*(num-1)/2;\n  }\n  cout << ans << endl;\n}", "language": "C++", "metadata": {"date": 1577495450, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03363.html", "problem_id": "p03363", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03363/input.txt", "sample_output_relpath": "derived/input_output/data/p03363/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03363/C++/s502898206.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s502898206", "user_id": "u796877631"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nint main() {\n  int n;\n  cin >> n;\n  vector<ll> a(n);\n  for(int i=0; i<n; i++){\n    cin >> a[i];\n  }\n  map<ll, ll> s;\n  vector<ll> l(n+1);\n  s[l[0]]++;\n  for(int i=0; i<n; i++){\n    l[i+1] = l[i] + a[i];\n    s[l[i+1]]++;\n  }\n  ll ans = 0;\n  for(auto p : s){\n    ll num = p.second;\n    ans += (ll)num*(num-1)/2;\n  }\n  cout << ans << endl;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nWe have an integer sequence A, whose length is N.\n\nFind the number of the non-empty contiguous subsequences of A whose sums are 0.\nNote that we are counting the ways to take out subsequences.\nThat is, even if the contents of some two subsequences are the same, they are counted individually if they are taken from different positions.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\n-10^9 \\leq A_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nFind the number of the non-empty contiguous subsequences of A whose sum is 0.\n\nSample Input 1\n\n6\n1 3 -4 2 2 -2\n\nSample Output 1\n\n3\n\nThere are three contiguous subsequences whose sums are 0: (1,3,-4), (-4,2,2) and (2,-2).\n\nSample Input 2\n\n7\n1 -1 1 -1 1 -1 1\n\nSample Output 2\n\n12\n\nIn this case, some subsequences that have the same contents but are taken from different positions are counted individually.\nFor example, three occurrences of (1, -1) are counted.\n\nSample Input 3\n\n5\n1 -2 3 -4 5\n\nSample Output 3\n\n0\n\nThere are no contiguous subsequences whose sums are 0.", "sample_input": "6\n1 3 -4 2 2 -2\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03363", "source_text": "Score : 200 points\n\nProblem Statement\n\nWe have an integer sequence A, whose length is N.\n\nFind the number of the non-empty contiguous subsequences of A whose sums are 0.\nNote that we are counting the ways to take out subsequences.\nThat is, even if the contents of some two subsequences are the same, they are counted individually if they are taken from different positions.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\n-10^9 \\leq A_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nFind the number of the non-empty contiguous subsequences of A whose sum is 0.\n\nSample Input 1\n\n6\n1 3 -4 2 2 -2\n\nSample Output 1\n\n3\n\nThere are three contiguous subsequences whose sums are 0: (1,3,-4), (-4,2,2) and (2,-2).\n\nSample Input 2\n\n7\n1 -1 1 -1 1 -1 1\n\nSample Output 2\n\n12\n\nIn this case, some subsequences that have the same contents but are taken from different positions are counted individually.\nFor example, three occurrences of (1, -1) are counted.\n\nSample Input 3\n\n5\n1 -2 3 -4 5\n\nSample Output 3\n\n0\n\nThere are no contiguous subsequences whose sums are 0.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 406, "cpu_time_ms": 135, "memory_kb": 15872}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s036702263", "group_id": "codeNet:p03363", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i,n) for (int (i)=(0);(i)<(int)(n);++(i))\nusing ll = long long;\nusing P = pair<int, int>;\nusing namespace std;\n\ntemplate<class T> void vin(vector<T>& v, int n) {\n    v.resize(n);\n    for (int i = 0; i < n; ++i) {\n        cin >> v[i];\n    }\n}\n\nll sum[301010];\n\nint main() {\n    int n;\n    cin >> n;\n    vector<ll> a(n);\n    rep(i, n) cin >> a[i];\n    rep(i, n) {\n        sum[i] += a[i];\n        if (i) sum[i] += sum[i-1];\n    }\n    map<ll, ll> mp;\n    rep(i, n) {\n        mp[sum[i]]++;\n        //cout << sum[i] << \" \";\n    }\n    ll ans = mp[0];\n    for (auto tmp : mp) {\n        if (tmp.second >= 2) {\n            ans += tmp.second * (tmp.second - 1) / 2;\n        }\n    }\n    cout << ans << endl;\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1524963882, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03363.html", "problem_id": "p03363", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03363/input.txt", "sample_output_relpath": "derived/input_output/data/p03363/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03363/C++/s036702263.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s036702263", "user_id": "u482544950"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i,n) for (int (i)=(0);(i)<(int)(n);++(i))\nusing ll = long long;\nusing P = pair<int, int>;\nusing namespace std;\n\ntemplate<class T> void vin(vector<T>& v, int n) {\n    v.resize(n);\n    for (int i = 0; i < n; ++i) {\n        cin >> v[i];\n    }\n}\n\nll sum[301010];\n\nint main() {\n    int n;\n    cin >> n;\n    vector<ll> a(n);\n    rep(i, n) cin >> a[i];\n    rep(i, n) {\n        sum[i] += a[i];\n        if (i) sum[i] += sum[i-1];\n    }\n    map<ll, ll> mp;\n    rep(i, n) {\n        mp[sum[i]]++;\n        //cout << sum[i] << \" \";\n    }\n    ll ans = mp[0];\n    for (auto tmp : mp) {\n        if (tmp.second >= 2) {\n            ans += tmp.second * (tmp.second - 1) / 2;\n        }\n    }\n    cout << ans << endl;\n    return 0;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nWe have an integer sequence A, whose length is N.\n\nFind the number of the non-empty contiguous subsequences of A whose sums are 0.\nNote that we are counting the ways to take out subsequences.\nThat is, even if the contents of some two subsequences are the same, they are counted individually if they are taken from different positions.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\n-10^9 \\leq A_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nFind the number of the non-empty contiguous subsequences of A whose sum is 0.\n\nSample Input 1\n\n6\n1 3 -4 2 2 -2\n\nSample Output 1\n\n3\n\nThere are three contiguous subsequences whose sums are 0: (1,3,-4), (-4,2,2) and (2,-2).\n\nSample Input 2\n\n7\n1 -1 1 -1 1 -1 1\n\nSample Output 2\n\n12\n\nIn this case, some subsequences that have the same contents but are taken from different positions are counted individually.\nFor example, three occurrences of (1, -1) are counted.\n\nSample Input 3\n\n5\n1 -2 3 -4 5\n\nSample Output 3\n\n0\n\nThere are no contiguous subsequences whose sums are 0.", "sample_input": "6\n1 3 -4 2 2 -2\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03363", "source_text": "Score : 200 points\n\nProblem Statement\n\nWe have an integer sequence A, whose length is N.\n\nFind the number of the non-empty contiguous subsequences of A whose sums are 0.\nNote that we are counting the ways to take out subsequences.\nThat is, even if the contents of some two subsequences are the same, they are counted individually if they are taken from different positions.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\n-10^9 \\leq A_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nFind the number of the non-empty contiguous subsequences of A whose sum is 0.\n\nSample Input 1\n\n6\n1 3 -4 2 2 -2\n\nSample Output 1\n\n3\n\nThere are three contiguous subsequences whose sums are 0: (1,3,-4), (-4,2,2) and (2,-2).\n\nSample Input 2\n\n7\n1 -1 1 -1 1 -1 1\n\nSample Output 2\n\n12\n\nIn this case, some subsequences that have the same contents but are taken from different positions are counted individually.\nFor example, three occurrences of (1, -1) are counted.\n\nSample Input 3\n\n5\n1 -2 3 -4 5\n\nSample Output 3\n\n0\n\nThere are no contiguous subsequences whose sums are 0.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 770, "cpu_time_ms": 140, "memory_kb": 15872}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s881160461", "group_id": "codeNet:p03364", "input_text": "#include <iostream>\n#include <cstdio>\n#include <cstring>\n#include <vector>\n#include <queue>\n#include <array>\n#include <unordered_set>\n#include <unordered_map>\n#include <cmath>\n#include <algorithm>\n#include <numeric>\n#include <cassert>\n#include <utility>\n#include <functional>\n\nusing namespace std;\nusing lli = long long int;\ntemplate<class T, class U> void init_n(vector<T>& v, size_t n, U x) \n{ v = vector<T>(n, x); }\ntemplate<class T> void init_n(vector<T>& v, size_t n) { init_n(v, n, T()); }\ntemplate<class T> void read_n(vector<T>& v, size_t n) \n{ v = vector<T>(n); for (lli i=0; i<n; ++i) cin >> v[i]; }\ntemplate<class T, class U> void read_n(vector<pair<T, U>>& v, size_t n)\n{ v = vector<pair<T, U>>(n); \n  for (lli i=0; i<n; ++i) cin >> v[i].first >> v[i].second; }\ntemplate<class T> T gabs(const T& x) { return max(x, -x); }\n#define abs gabs\n\nlli n;\nvector<string> s;\nint main() {\n  cin >> n;\n  read_n(s, n);\n  lli ans = 0;\n  for (lli d=0; d<n; ++d) {\n    bool ok = true;\n    for (lli j=0; j<n; ++j) {\n      for (lli i=0; i<n; ++i) {\n\tif (s[j][i] != s[i][j]) {\n\t  ok = false;\n\t  goto out;\n\t}\n      }\n    }\nout:\n    if (ok) ans += n;\n    auto t = s.back();\n    s.pop_back();\n    s.insert(begin(s), t);\n  }\n  cout << ans << endl;\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1547090446, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03364.html", "problem_id": "p03364", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03364/input.txt", "sample_output_relpath": "derived/input_output/data/p03364/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03364/C++/s881160461.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s881160461", "user_id": "u090994275"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <iostream>\n#include <cstdio>\n#include <cstring>\n#include <vector>\n#include <queue>\n#include <array>\n#include <unordered_set>\n#include <unordered_map>\n#include <cmath>\n#include <algorithm>\n#include <numeric>\n#include <cassert>\n#include <utility>\n#include <functional>\n\nusing namespace std;\nusing lli = long long int;\ntemplate<class T, class U> void init_n(vector<T>& v, size_t n, U x) \n{ v = vector<T>(n, x); }\ntemplate<class T> void init_n(vector<T>& v, size_t n) { init_n(v, n, T()); }\ntemplate<class T> void read_n(vector<T>& v, size_t n) \n{ v = vector<T>(n); for (lli i=0; i<n; ++i) cin >> v[i]; }\ntemplate<class T, class U> void read_n(vector<pair<T, U>>& v, size_t n)\n{ v = vector<pair<T, U>>(n); \n  for (lli i=0; i<n; ++i) cin >> v[i].first >> v[i].second; }\ntemplate<class T> T gabs(const T& x) { return max(x, -x); }\n#define abs gabs\n\nlli n;\nvector<string> s;\nint main() {\n  cin >> n;\n  read_n(s, n);\n  lli ans = 0;\n  for (lli d=0; d<n; ++d) {\n    bool ok = true;\n    for (lli j=0; j<n; ++j) {\n      for (lli i=0; i<n; ++i) {\n\tif (s[j][i] != s[i][j]) {\n\t  ok = false;\n\t  goto out;\n\t}\n      }\n    }\nout:\n    if (ok) ans += n;\n    auto t = s.back();\n    s.pop_back();\n    s.insert(begin(s), t);\n  }\n  cout << ans << endl;\n  return 0;\n}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nSnuke has two boards, each divided into a grid with N rows and N columns.\nFor both of these boards, the square at the i-th row from the top and the j-th column from the left is called Square (i,j).\n\nThere is a lowercase English letter written in each square on the first board. The letter written in Square (i,j) is S_{i,j}. On the second board, nothing is written yet.\n\nSnuke will write letters on the second board, as follows:\n\nFirst, choose two integers A and B ( 0 \\leq A, B < N ).\n\nWrite one letter in each square on the second board.\nSpecifically, write the letter written in Square ( i+A, j+B ) on the first board into Square (i,j) on the second board.\nHere, the k-th row is also represented as the (N+k)-th row, and the k-th column is also represented as the (N+k)-th column.\n\nAfter this operation, the second board is called a good board when, for every i and j ( 1 \\leq i, j \\leq N ), the letter in Square (i,j) and the letter in Square (j,i) are equal.\n\nFind the number of the ways to choose integers A and B ( 0 \\leq A, B < N ) such that the second board is a good board.\n\nConstraints\n\n1 \\leq N \\leq 300\n\nS_{i,j} ( 1 \\leq i, j \\leq N ) is a lowercase English letter.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS_{1,1}S_{1,2}..S_{1,N}\nS_{2,1}S_{2,2}..S_{2,N}\n:\nS_{N,1}S_{N,2}..S_{N,N}\n\nOutput\n\nPrint the number of the ways to choose integers A and B ( 0 \\leq A, B < N ) such that the second board is a good board.\n\nSample Input 1\n\n2\nab\nca\n\nSample Output 1\n\n2\n\nFor each pair of A and B, the second board will look as shown below:\n\nThe second board is a good board when (A,B) = (0,1) or (A,B) = (1,0), thus the answer is 2.\n\nSample Input 2\n\n4\naaaa\naaaa\naaaa\naaaa\n\nSample Output 2\n\n16\n\nEvery possible choice of A and B makes the second board good.\n\nSample Input 3\n\n5\nabcde\nfghij\nklmno\npqrst\nuvwxy\n\nSample Output 3\n\n0\n\nNo possible choice of A and B makes the second board good.", "sample_input": "2\nab\nca\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03364", "source_text": "Score : 500 points\n\nProblem Statement\n\nSnuke has two boards, each divided into a grid with N rows and N columns.\nFor both of these boards, the square at the i-th row from the top and the j-th column from the left is called Square (i,j).\n\nThere is a lowercase English letter written in each square on the first board. The letter written in Square (i,j) is S_{i,j}. On the second board, nothing is written yet.\n\nSnuke will write letters on the second board, as follows:\n\nFirst, choose two integers A and B ( 0 \\leq A, B < N ).\n\nWrite one letter in each square on the second board.\nSpecifically, write the letter written in Square ( i+A, j+B ) on the first board into Square (i,j) on the second board.\nHere, the k-th row is also represented as the (N+k)-th row, and the k-th column is also represented as the (N+k)-th column.\n\nAfter this operation, the second board is called a good board when, for every i and j ( 1 \\leq i, j \\leq N ), the letter in Square (i,j) and the letter in Square (j,i) are equal.\n\nFind the number of the ways to choose integers A and B ( 0 \\leq A, B < N ) such that the second board is a good board.\n\nConstraints\n\n1 \\leq N \\leq 300\n\nS_{i,j} ( 1 \\leq i, j \\leq N ) is a lowercase English letter.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS_{1,1}S_{1,2}..S_{1,N}\nS_{2,1}S_{2,2}..S_{2,N}\n:\nS_{N,1}S_{N,2}..S_{N,N}\n\nOutput\n\nPrint the number of the ways to choose integers A and B ( 0 \\leq A, B < N ) such that the second board is a good board.\n\nSample Input 1\n\n2\nab\nca\n\nSample Output 1\n\n2\n\nFor each pair of A and B, the second board will look as shown below:\n\nThe second board is a good board when (A,B) = (0,1) or (A,B) = (1,0), thus the answer is 2.\n\nSample Input 2\n\n4\naaaa\naaaa\naaaa\naaaa\n\nSample Output 2\n\n16\n\nEvery possible choice of A and B makes the second board good.\n\nSample Input 3\n\n5\nabcde\nfghij\nklmno\npqrst\nuvwxy\n\nSample Output 3\n\n0\n\nNo possible choice of A and B makes the second board good.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1251, "cpu_time_ms": 68, "memory_kb": 384}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s834806911", "group_id": "codeNet:p03368", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n#define db(x) cerr << #x << \"=\" << x << endl\n#define db2(x, y) cerr << #x << \"=\" << x << \",\" << #y << \"=\" << y << endl\n#define db3(x, y, z) cerr << #x << \"=\" << x << \",\" << #y << \"=\" << y << \",\" << #z << \"=\" << z << endl\ntypedef long long ll;\ntypedef long double ld;\nconst int MAXN = 200005;\nint par[MAXN], P[MAXN], V[MAXN];\nll num0[MAXN], num1[MAXN], val[MAXN];\nint root(int a) {\n\tif (par[a] == a) return a;\n\treturn par[a] = root(par[a]);\n}\nstruct cmp {\n\tbool operator()(int a, int b) {\n\t\tll va = num0[a] * num1[b], vb = num0[b] * num1[a];\n\t\tif (va != vb) return va > vb;\n\t\treturn a < b;\n\t}\n};\nint main() {\n\tint N;\n\tscanf(\"%d\", &N);\n\tfor (int i = 2; i <= N; ++i) scanf(\"%d\", &P[i]);\n\tfor (int i = 1; i <= N; ++i) scanf(\"%d\", &V[i]);\n\tfor (int i = 1; i <= N; ++i) {\n\t\tpar[i] = i;\n\t\tif (V[i] == 1) ++num1[i];\n\t\telse ++num0[i];\n\t}\n\tset<int, cmp> S;\n\tfor (int i = 2; i <= N; ++i) {\n\t\tS.insert(i);\n\t}\n\twhile (!S.empty()) {\n\t\tint x = *S.begin();\n\t\tS.erase(S.begin());\n\t\tint y = root(P[x]);\n\t\tS.erase(y);\n\t\tpar[x] = y;\n\t\tval[y] += val[x] + num1[y] * num0[x];\n\t\tnum0[y] += num0[x];\n\t\tnum1[y] += num1[x];\n\t\tif (y != 1) S.insert(y);\n\t}\n\tprintf(\"%lld\\n\", val[1]);\n}\n", "language": "C++", "metadata": {"date": 1525183743, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03368.html", "problem_id": "p03368", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03368/input.txt", "sample_output_relpath": "derived/input_output/data/p03368/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03368/C++/s834806911.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s834806911", "user_id": "u735075555"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n#define db(x) cerr << #x << \"=\" << x << endl\n#define db2(x, y) cerr << #x << \"=\" << x << \",\" << #y << \"=\" << y << endl\n#define db3(x, y, z) cerr << #x << \"=\" << x << \",\" << #y << \"=\" << y << \",\" << #z << \"=\" << z << endl\ntypedef long long ll;\ntypedef long double ld;\nconst int MAXN = 200005;\nint par[MAXN], P[MAXN], V[MAXN];\nll num0[MAXN], num1[MAXN], val[MAXN];\nint root(int a) {\n\tif (par[a] == a) return a;\n\treturn par[a] = root(par[a]);\n}\nstruct cmp {\n\tbool operator()(int a, int b) {\n\t\tll va = num0[a] * num1[b], vb = num0[b] * num1[a];\n\t\tif (va != vb) return va > vb;\n\t\treturn a < b;\n\t}\n};\nint main() {\n\tint N;\n\tscanf(\"%d\", &N);\n\tfor (int i = 2; i <= N; ++i) scanf(\"%d\", &P[i]);\n\tfor (int i = 1; i <= N; ++i) scanf(\"%d\", &V[i]);\n\tfor (int i = 1; i <= N; ++i) {\n\t\tpar[i] = i;\n\t\tif (V[i] == 1) ++num1[i];\n\t\telse ++num0[i];\n\t}\n\tset<int, cmp> S;\n\tfor (int i = 2; i <= N; ++i) {\n\t\tS.insert(i);\n\t}\n\twhile (!S.empty()) {\n\t\tint x = *S.begin();\n\t\tS.erase(S.begin());\n\t\tint y = root(P[x]);\n\t\tS.erase(y);\n\t\tpar[x] = y;\n\t\tval[y] += val[x] + num1[y] * num0[x];\n\t\tnum0[y] += num0[x];\n\t\tnum1[y] += num1[x];\n\t\tif (y != 1) S.insert(y);\n\t}\n\tprintf(\"%lld\\n\", val[1]);\n}\n", "problem_context": "Score : 1700 points\n\nProblem Statement\n\nSnuke has a rooted tree with N vertices, numbered 1 through N.\nVertex 1 is the root of the tree, and the parent of Vertex i ( 2\\leq i \\leq N ) is Vertex P_i ( P_i < i ).\nThere is a number, 0 or 1, written on each vertex. The number written on Vertex i is V_i.\n\nSnuke would like to arrange the vertices of this tree in a horizontal row.\nHere, for every vertex, there should be no ancestor of that vertex to the right of that vertex.\n\nAfter arranging the vertices, let X be the sequence obtained by reading the numbers written on the vertices from left to right in the arrangement.\nSnuke would like to minimize the inversion number of X.\nFind the minimum possible inversion number of X.\n\nNotes\n\nThe inversion number of a sequence Z whose length N is the number of pairs of integers i and j ( 1 \\leq i < j \\leq N ) such that Z_i > Z_j.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq P_i < i ( 2 \\leq i \\leq N )\n\n0 \\leq V_i \\leq 1 ( 1 \\leq i \\leq N )\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nP_2 P_3 ... P_N\nV_1 V_2 ... V_N\n\nOutput\n\nPrint the minimum possible inversion number of X.\n\nSample Input 1\n\n6\n1 1 2 3 3\n0 1 1 0 0 0\n\nSample Output 1\n\n4\n\nWhen the vertices are arranged in the order 1, 3, 5, 6, 2, 4, X will be (0, 1, 0, 0, 1, 0), whose inversion number is 4.\nIt is impossible to have fewer inversions, so the answer is 4.\n\nSample Input 2\n\n1\n\n0\n\nSample Output 2\n\n0\n\nX = (0), whose inversion number is 0.\n\nSample Input 3\n\n15\n1 2 3 2 5 6 2 2 9 10 1 12 13 12\n1 1 1 0 1 1 0 0 1 0 0 1 1 0 0\n\nSample Output 3\n\n31", "sample_input": "6\n1 1 2 3 3\n0 1 1 0 0 0\n"}, "reference_outputs": ["4\n"], "source_document_id": "p03368", "source_text": "Score : 1700 points\n\nProblem Statement\n\nSnuke has a rooted tree with N vertices, numbered 1 through N.\nVertex 1 is the root of the tree, and the parent of Vertex i ( 2\\leq i \\leq N ) is Vertex P_i ( P_i < i ).\nThere is a number, 0 or 1, written on each vertex. The number written on Vertex i is V_i.\n\nSnuke would like to arrange the vertices of this tree in a horizontal row.\nHere, for every vertex, there should be no ancestor of that vertex to the right of that vertex.\n\nAfter arranging the vertices, let X be the sequence obtained by reading the numbers written on the vertices from left to right in the arrangement.\nSnuke would like to minimize the inversion number of X.\nFind the minimum possible inversion number of X.\n\nNotes\n\nThe inversion number of a sequence Z whose length N is the number of pairs of integers i and j ( 1 \\leq i < j \\leq N ) such that Z_i > Z_j.\n\nConstraints\n\n1 \\leq N \\leq 2 \\times 10^5\n\n1 \\leq P_i < i ( 2 \\leq i \\leq N )\n\n0 \\leq V_i \\leq 1 ( 1 \\leq i \\leq N )\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nP_2 P_3 ... P_N\nV_1 V_2 ... V_N\n\nOutput\n\nPrint the minimum possible inversion number of X.\n\nSample Input 1\n\n6\n1 1 2 3 3\n0 1 1 0 0 0\n\nSample Output 1\n\n4\n\nWhen the vertices are arranged in the order 1, 3, 5, 6, 2, 4, X will be (0, 1, 0, 0, 1, 0), whose inversion number is 4.\nIt is impossible to have fewer inversions, so the answer is 4.\n\nSample Input 2\n\n1\n\n0\n\nSample Output 2\n\n0\n\nX = (0), whose inversion number is 0.\n\nSample Input 3\n\n15\n1 2 3 2 5 6 2 2 9 10 1 12 13 12\n1 1 1 0 1 1 0 0 1 0 0 1 1 0 0\n\nSample Output 3\n\n31", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1202, "cpu_time_ms": 197, "memory_kb": 16640}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s008217454", "group_id": "codeNet:p03369", "input_text": "#include <bits/stdc++.h>\n\n#if DEBUG\ntemplate <typename T>\nvoid debug(const T& value) {\n  std::cerr << value;\n}\ntemplate <typename T, typename... Ts>\nvoid debug(const T& value, const Ts&... args) {\n  std::cerr << value << \", \";\n  debug(args...);\n}\n#define dbg(...)                        \\\n  do {                                  \\\n    cerr << #__VA_ARGS__ << \": \";       \\\n    debug(__VA_ARGS__);                 \\\n    cerr << \" (L\" << __LINE__ << \")\\n\"; \\\n  } while (0)\n#else\n#define dbg(...)\n#endif\n\nvoid read_from_cin() {}\ntemplate <typename T, typename... Ts>\nvoid read_from_cin(T& value, Ts&... args) {\n  std::cin >> value;\n  read_from_cin(args...);\n}\n#define rd(type, ...) \\\n  type __VA_ARGS__;   \\\n  read_from_cin(__VA_ARGS__);\n\ntemplate <typename T>\nvoid write_to_cout(const T& value) {\n  std::cout << value << '\\n';\n}\ntemplate <typename T, typename... Ts>\nvoid write_to_cout(const T& value, const Ts&... args) {\n  std::cout << value << ' ';\n  write_to_cout(args...);\n}\n#define wt(...) write_to_cout(__VA_ARGS__);\n\n#define all(x) (x).begin(), (x).end()\n#define rep(i, n) for (int i = 0; i < (int)(n); ++i)\n\nusing ll = long long;\n\ntemplate <typename T>\nusing V = std::vector<T>;\ntemplate <typename T>\nusing VV = V<V<T>>;\n\nusing namespace std;\n\nint main() {\n  rd(string, s);\n  wt(700 + count(all(s), 'o') * 100);\n}\n", "language": "C++", "metadata": {"date": 1597399343, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03369.html", "problem_id": "p03369", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03369/input.txt", "sample_output_relpath": "derived/input_output/data/p03369/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03369/C++/s008217454.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s008217454", "user_id": "u505122009"}, "prompt_components": {"gold_output": "900\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\n#if DEBUG\ntemplate <typename T>\nvoid debug(const T& value) {\n  std::cerr << value;\n}\ntemplate <typename T, typename... Ts>\nvoid debug(const T& value, const Ts&... args) {\n  std::cerr << value << \", \";\n  debug(args...);\n}\n#define dbg(...)                        \\\n  do {                                  \\\n    cerr << #__VA_ARGS__ << \": \";       \\\n    debug(__VA_ARGS__);                 \\\n    cerr << \" (L\" << __LINE__ << \")\\n\"; \\\n  } while (0)\n#else\n#define dbg(...)\n#endif\n\nvoid read_from_cin() {}\ntemplate <typename T, typename... Ts>\nvoid read_from_cin(T& value, Ts&... args) {\n  std::cin >> value;\n  read_from_cin(args...);\n}\n#define rd(type, ...) \\\n  type __VA_ARGS__;   \\\n  read_from_cin(__VA_ARGS__);\n\ntemplate <typename T>\nvoid write_to_cout(const T& value) {\n  std::cout << value << '\\n';\n}\ntemplate <typename T, typename... Ts>\nvoid write_to_cout(const T& value, const Ts&... args) {\n  std::cout << value << ' ';\n  write_to_cout(args...);\n}\n#define wt(...) write_to_cout(__VA_ARGS__);\n\n#define all(x) (x).begin(), (x).end()\n#define rep(i, n) for (int i = 0; i < (int)(n); ++i)\n\nusing ll = long long;\n\ntemplate <typename T>\nusing V = std::vector<T>;\ntemplate <typename T>\nusing VV = V<V<T>>;\n\nusing namespace std;\n\nint main() {\n  rd(string, s);\n  wt(700 + count(all(s), 'o') * 100);\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nIn \"Takahashi-ya\", a ramen restaurant, a bowl of ramen costs 700 yen (the currency of Japan), plus 100 yen for each kind of topping (boiled egg, sliced pork, green onions).\n\nA customer ordered a bowl of ramen and told which toppings to put on his ramen to a clerk. The clerk took a memo of the order as a string S. S is three characters long, and if the first character in S is o, it means the ramen should be topped with boiled egg; if that character is x, it means the ramen should not be topped with boiled egg. Similarly, the second and third characters in S mean the presence or absence of sliced pork and green onions on top of the ramen.\n\nWrite a program that, when S is given, prints the price of the corresponding bowl of ramen.\n\nConstraints\n\nS is a string of length 3.\n\nEach character in S is o or x.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the price of the bowl of ramen corresponding to S.\n\nSample Input 1\n\noxo\n\nSample Output 1\n\n900\n\nThe price of a ramen topped with two kinds of toppings, boiled egg and green onions, is 700 + 100 \\times 2 = 900 yen.\n\nSample Input 2\n\nooo\n\nSample Output 2\n\n1000\n\nThe price of a ramen topped with all three kinds of toppings is 700 + 100 \\times 3 = 1000 yen.\n\nSample Input 3\n\nxxx\n\nSample Output 3\n\n700\n\nThe price of a ramen without any toppings is 700 yen.", "sample_input": "oxo\n"}, "reference_outputs": ["900\n"], "source_document_id": "p03369", "source_text": "Score : 100 points\n\nProblem Statement\n\nIn \"Takahashi-ya\", a ramen restaurant, a bowl of ramen costs 700 yen (the currency of Japan), plus 100 yen for each kind of topping (boiled egg, sliced pork, green onions).\n\nA customer ordered a bowl of ramen and told which toppings to put on his ramen to a clerk. The clerk took a memo of the order as a string S. S is three characters long, and if the first character in S is o, it means the ramen should be topped with boiled egg; if that character is x, it means the ramen should not be topped with boiled egg. Similarly, the second and third characters in S mean the presence or absence of sliced pork and green onions on top of the ramen.\n\nWrite a program that, when S is given, prints the price of the corresponding bowl of ramen.\n\nConstraints\n\nS is a string of length 3.\n\nEach character in S is o or x.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the price of the bowl of ramen corresponding to S.\n\nSample Input 1\n\noxo\n\nSample Output 1\n\n900\n\nThe price of a ramen topped with two kinds of toppings, boiled egg and green onions, is 700 + 100 \\times 2 = 900 yen.\n\nSample Input 2\n\nooo\n\nSample Output 2\n\n1000\n\nThe price of a ramen topped with all three kinds of toppings is 700 + 100 \\times 3 = 1000 yen.\n\nSample Input 3\n\nxxx\n\nSample Output 3\n\n700\n\nThe price of a ramen without any toppings is 700 yen.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1321, "cpu_time_ms": 6, "memory_kb": 3572}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s515069463", "group_id": "codeNet:p03369", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nstring S;\n\nint main(){\n  int ans=700;\n\n  cin >> S;\n  for(int i=0; i<3; i++){\n    if(S[i]=='o') ans += 100;\n  }\n  cout << ans << endl;\n}", "language": "C++", "metadata": {"date": 1524360013, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03369.html", "problem_id": "p03369", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03369/input.txt", "sample_output_relpath": "derived/input_output/data/p03369/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03369/C++/s515069463.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s515069463", "user_id": "u826949309"}, "prompt_components": {"gold_output": "900\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nstring S;\n\nint main(){\n  int ans=700;\n\n  cin >> S;\n  for(int i=0; i<3; i++){\n    if(S[i]=='o') ans += 100;\n  }\n  cout << ans << endl;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nIn \"Takahashi-ya\", a ramen restaurant, a bowl of ramen costs 700 yen (the currency of Japan), plus 100 yen for each kind of topping (boiled egg, sliced pork, green onions).\n\nA customer ordered a bowl of ramen and told which toppings to put on his ramen to a clerk. The clerk took a memo of the order as a string S. S is three characters long, and if the first character in S is o, it means the ramen should be topped with boiled egg; if that character is x, it means the ramen should not be topped with boiled egg. Similarly, the second and third characters in S mean the presence or absence of sliced pork and green onions on top of the ramen.\n\nWrite a program that, when S is given, prints the price of the corresponding bowl of ramen.\n\nConstraints\n\nS is a string of length 3.\n\nEach character in S is o or x.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the price of the bowl of ramen corresponding to S.\n\nSample Input 1\n\noxo\n\nSample Output 1\n\n900\n\nThe price of a ramen topped with two kinds of toppings, boiled egg and green onions, is 700 + 100 \\times 2 = 900 yen.\n\nSample Input 2\n\nooo\n\nSample Output 2\n\n1000\n\nThe price of a ramen topped with all three kinds of toppings is 700 + 100 \\times 3 = 1000 yen.\n\nSample Input 3\n\nxxx\n\nSample Output 3\n\n700\n\nThe price of a ramen without any toppings is 700 yen.", "sample_input": "oxo\n"}, "reference_outputs": ["900\n"], "source_document_id": "p03369", "source_text": "Score : 100 points\n\nProblem Statement\n\nIn \"Takahashi-ya\", a ramen restaurant, a bowl of ramen costs 700 yen (the currency of Japan), plus 100 yen for each kind of topping (boiled egg, sliced pork, green onions).\n\nA customer ordered a bowl of ramen and told which toppings to put on his ramen to a clerk. The clerk took a memo of the order as a string S. S is three characters long, and if the first character in S is o, it means the ramen should be topped with boiled egg; if that character is x, it means the ramen should not be topped with boiled egg. Similarly, the second and third characters in S mean the presence or absence of sliced pork and green onions on top of the ramen.\n\nWrite a program that, when S is given, prints the price of the corresponding bowl of ramen.\n\nConstraints\n\nS is a string of length 3.\n\nEach character in S is o or x.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the price of the bowl of ramen corresponding to S.\n\nSample Input 1\n\noxo\n\nSample Output 1\n\n900\n\nThe price of a ramen topped with two kinds of toppings, boiled egg and green onions, is 700 + 100 \\times 2 = 900 yen.\n\nSample Input 2\n\nooo\n\nSample Output 2\n\n1000\n\nThe price of a ramen topped with all three kinds of toppings is 700 + 100 \\times 3 = 1000 yen.\n\nSample Input 3\n\nxxx\n\nSample Output 3\n\n700\n\nThe price of a ramen without any toppings is 700 yen.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 182, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s485954098", "group_id": "codeNet:p03370", "input_text": "#include <iostream>\n#include <cmath>\n\nusing namespace std;\n\nint main() {\n\tint N, X;\n\n\tcin >> N >> X;\n\n\tint rem = X, minimum = 100000, ans = 0;\n\tfor (int i = 0; i < N; i++) {\n\t\tint tmp;\n\t\tcin >> tmp;\n\t\trem -= tmp;\n\t\tans++;\n\t\tminimum = min(minimum, tmp);\n\t}\n\n\tans += rem / minimum;\n\n\tcout << ans << endl;\n\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1551918994, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03370.html", "problem_id": "p03370", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03370/input.txt", "sample_output_relpath": "derived/input_output/data/p03370/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03370/C++/s485954098.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s485954098", "user_id": "u604023588"}, "prompt_components": {"gold_output": "9\n", "input_to_evaluate": "#include <iostream>\n#include <cmath>\n\nusing namespace std;\n\nint main() {\n\tint N, X;\n\n\tcin >> N >> X;\n\n\tint rem = X, minimum = 100000, ans = 0;\n\tfor (int i = 0; i < N; i++) {\n\t\tint tmp;\n\t\tcin >> tmp;\n\t\trem -= tmp;\n\t\tans++;\n\t\tminimum = min(minimum, tmp);\n\t}\n\n\tans += rem / minimum;\n\n\tcout << ans << endl;\n\n\treturn 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nAkaki, a patissier, can make N kinds of doughnut using only a certain powder called \"Okashi no Moto\" (literally \"material of pastry\", simply called Moto below) as ingredient. These doughnuts are called Doughnut 1, Doughnut 2, ..., Doughnut N. In order to make one Doughnut i (1 ≤ i ≤ N), she needs to consume m_i grams of Moto. She cannot make a non-integer number of doughnuts, such as 0.5 doughnuts.\n\nNow, she has X grams of Moto. She decides to make as many doughnuts as possible for a party tonight. However, since the tastes of the guests differ, she will obey the following condition:\n\nFor each of the N kinds of doughnuts, make at least one doughnut of that kind.\n\nAt most how many doughnuts can be made here? She does not necessarily need to consume all of her Moto. Also, under the constraints of this problem, it is always possible to obey the condition.\n\nConstraints\n\n2 ≤ N ≤ 100\n\n1 ≤ m_i ≤ 1000\n\nm_1 + m_2 + ... + m_N ≤ X ≤ 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN X\nm_1\nm_2\n:\nm_N\n\nOutput\n\nPrint the maximum number of doughnuts that can be made under the condition.\n\nSample Input 1\n\n3 1000\n120\n100\n140\n\nSample Output 1\n\n9\n\nShe has 1000 grams of Moto and can make three kinds of doughnuts. If she makes one doughnut for each of the three kinds, she consumes 120 + 100 + 140 = 360 grams of Moto. From the 640 grams of Moto that remains here, she can make additional six Doughnuts 2. This is how she can made a total of nine doughnuts, which is the maximum.\n\nSample Input 2\n\n4 360\n90\n90\n90\n90\n\nSample Output 2\n\n4\n\nMaking one doughnut for each of the four kinds consumes all of her Moto.\n\nSample Input 3\n\n5 3000\n150\n130\n150\n130\n110\n\nSample Output 3\n\n26", "sample_input": "3 1000\n120\n100\n140\n"}, "reference_outputs": ["9\n"], "source_document_id": "p03370", "source_text": "Score : 200 points\n\nProblem Statement\n\nAkaki, a patissier, can make N kinds of doughnut using only a certain powder called \"Okashi no Moto\" (literally \"material of pastry\", simply called Moto below) as ingredient. These doughnuts are called Doughnut 1, Doughnut 2, ..., Doughnut N. In order to make one Doughnut i (1 ≤ i ≤ N), she needs to consume m_i grams of Moto. She cannot make a non-integer number of doughnuts, such as 0.5 doughnuts.\n\nNow, she has X grams of Moto. She decides to make as many doughnuts as possible for a party tonight. However, since the tastes of the guests differ, she will obey the following condition:\n\nFor each of the N kinds of doughnuts, make at least one doughnut of that kind.\n\nAt most how many doughnuts can be made here? She does not necessarily need to consume all of her Moto. Also, under the constraints of this problem, it is always possible to obey the condition.\n\nConstraints\n\n2 ≤ N ≤ 100\n\n1 ≤ m_i ≤ 1000\n\nm_1 + m_2 + ... + m_N ≤ X ≤ 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN X\nm_1\nm_2\n:\nm_N\n\nOutput\n\nPrint the maximum number of doughnuts that can be made under the condition.\n\nSample Input 1\n\n3 1000\n120\n100\n140\n\nSample Output 1\n\n9\n\nShe has 1000 grams of Moto and can make three kinds of doughnuts. If she makes one doughnut for each of the three kinds, she consumes 120 + 100 + 140 = 360 grams of Moto. From the 640 grams of Moto that remains here, she can make additional six Doughnuts 2. This is how she can made a total of nine doughnuts, which is the maximum.\n\nSample Input 2\n\n4 360\n90\n90\n90\n90\n\nSample Output 2\n\n4\n\nMaking one doughnut for each of the four kinds consumes all of her Moto.\n\nSample Input 3\n\n5 3000\n150\n130\n150\n130\n110\n\nSample Output 3\n\n26", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 316, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s334626541", "group_id": "codeNet:p03371", "input_text": "#include <iostream>\n\nusing namespace std;\n\nint main()\n{\n\tint a,b,c,x,y;\n\tlong long t=0;\n\tcin>>a>>b>>c>>x>>y;\n\n\tif (a + b > 2 * c)\n\t{\n\t\tif (x < y)\n\t\t{\n\t\t\tt += 2 * x * c;\n\t\t\tif ((y-x) * b > (y-x)*2*c)\n\t\t\t{\n\t\t\t\tt += 2 * (y-x) * c;\n\t\t\t}\n\t\t\telse t += (y-x)*b;\n\t\t}\t\n\t\telse\n\t\t{\n\t\t\tt += 2 * y * c;\t\n\t\t\tif ((x-y) * a > (x-y)*2*c)\n\t\t\t{\n\t\t\t\tt += 2 * (x-y) * c;\n\t\t\t}\n\t\t\telse t += (x-y)*a;\n\t\t} \n\t}\n\telse\n\t{\n\t\tt += a*x + b*y;\n\t}\n\tcout << t << \"\\n\";\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1524361002, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03371.html", "problem_id": "p03371", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03371/input.txt", "sample_output_relpath": "derived/input_output/data/p03371/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03371/C++/s334626541.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s334626541", "user_id": "u913789532"}, "prompt_components": {"gold_output": "7900\n", "input_to_evaluate": "#include <iostream>\n\nusing namespace std;\n\nint main()\n{\n\tint a,b,c,x,y;\n\tlong long t=0;\n\tcin>>a>>b>>c>>x>>y;\n\n\tif (a + b > 2 * c)\n\t{\n\t\tif (x < y)\n\t\t{\n\t\t\tt += 2 * x * c;\n\t\t\tif ((y-x) * b > (y-x)*2*c)\n\t\t\t{\n\t\t\t\tt += 2 * (y-x) * c;\n\t\t\t}\n\t\t\telse t += (y-x)*b;\n\t\t}\t\n\t\telse\n\t\t{\n\t\t\tt += 2 * y * c;\t\n\t\t\tif ((x-y) * a > (x-y)*2*c)\n\t\t\t{\n\t\t\t\tt += 2 * (x-y) * c;\n\t\t\t}\n\t\t\telse t += (x-y)*a;\n\t\t} \n\t}\n\telse\n\t{\n\t\tt += a*x + b*y;\n\t}\n\tcout << t << \"\\n\";\n\treturn 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\n\"Pizza At\", a fast food chain, offers three kinds of pizza: \"A-pizza\", \"B-pizza\" and \"AB-pizza\". A-pizza and B-pizza are completely different pizzas, and AB-pizza is one half of A-pizza and one half of B-pizza combined together. The prices of one A-pizza, B-pizza and AB-pizza are A yen, B yen and C yen (yen is the currency of Japan), respectively.\n\nNakahashi needs to prepare X A-pizzas and Y B-pizzas for a party tonight. He can only obtain these pizzas by directly buying A-pizzas and B-pizzas, or buying two AB-pizzas and then rearrange them into one A-pizza and one B-pizza. At least how much money does he need for this? It is fine to have more pizzas than necessary by rearranging pizzas.\n\nConstraints\n\n1 ≤ A, B, C ≤ 5000\n\n1 ≤ X, Y ≤ 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B C X Y\n\nOutput\n\nPrint the minimum amount of money required to prepare X A-pizzas and Y B-pizzas.\n\nSample Input 1\n\n1500 2000 1600 3 2\n\nSample Output 1\n\n7900\n\nIt is optimal to buy four AB-pizzas and rearrange them into two A-pizzas and two B-pizzas, then buy additional one A-pizza.\n\nSample Input 2\n\n1500 2000 1900 3 2\n\nSample Output 2\n\n8500\n\nIt is optimal to directly buy three A-pizzas and two B-pizzas.\n\nSample Input 3\n\n1500 2000 500 90000 100000\n\nSample Output 3\n\n100000000\n\nIt is optimal to buy 200000 AB-pizzas and rearrange them into 100000 A-pizzas and 100000 B-pizzas. We will have 10000 more A-pizzas than necessary, but that is fine.", "sample_input": "1500 2000 1600 3 2\n"}, "reference_outputs": ["7900\n"], "source_document_id": "p03371", "source_text": "Score : 300 points\n\nProblem Statement\n\n\"Pizza At\", a fast food chain, offers three kinds of pizza: \"A-pizza\", \"B-pizza\" and \"AB-pizza\". A-pizza and B-pizza are completely different pizzas, and AB-pizza is one half of A-pizza and one half of B-pizza combined together. The prices of one A-pizza, B-pizza and AB-pizza are A yen, B yen and C yen (yen is the currency of Japan), respectively.\n\nNakahashi needs to prepare X A-pizzas and Y B-pizzas for a party tonight. He can only obtain these pizzas by directly buying A-pizzas and B-pizzas, or buying two AB-pizzas and then rearrange them into one A-pizza and one B-pizza. At least how much money does he need for this? It is fine to have more pizzas than necessary by rearranging pizzas.\n\nConstraints\n\n1 ≤ A, B, C ≤ 5000\n\n1 ≤ X, Y ≤ 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B C X Y\n\nOutput\n\nPrint the minimum amount of money required to prepare X A-pizzas and Y B-pizzas.\n\nSample Input 1\n\n1500 2000 1600 3 2\n\nSample Output 1\n\n7900\n\nIt is optimal to buy four AB-pizzas and rearrange them into two A-pizzas and two B-pizzas, then buy additional one A-pizza.\n\nSample Input 2\n\n1500 2000 1900 3 2\n\nSample Output 2\n\n8500\n\nIt is optimal to directly buy three A-pizzas and two B-pizzas.\n\nSample Input 3\n\n1500 2000 500 90000 100000\n\nSample Output 3\n\n100000000\n\nIt is optimal to buy 200000 AB-pizzas and rearrange them into 100000 A-pizzas and 100000 B-pizzas. We will have 10000 more A-pizzas than necessary, but that is fine.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 447, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s277318743", "group_id": "codeNet:p03372", "input_text": "#include <bits/stdc++.h>\n#define rep(i,n) for(int i=0;i<(int)n;i++)\n#define rep1(i,n) for(int i=1;i<=(int)n;i++)\n#define rep2(i,j,n) for(int j=i;j<n;j++)\n#define rep3(i,j,n) for(int j=i;j<=n;j++)\n#define rrep(i,n) for(int i=n-1;i>=0;i--)\n#define sp(n) cout << fixed << setprecision(n)\ntypedef long long ll;\nusing namespace std;\nint main(void){\n    ll n,c;cin>>n>>c;\n    vector<ll> x(n),v(n),a(n),b(n),d(n),e(n);\n    rep(i,n) cin>>x[i]>>v[i];\n    ll tmp=0;\n    rep(i,n){\n        if(i==0){\n            tmp+=v[i];\n            a[i]=max(tmp-x[i],(ll)0);\n            d[i]=(a[i]==tmp-x[i])? x[i]:0;\n        }\n        else{\n            tmp+=v[i];\n            a[i]=max(a[i-1],tmp-x[i]);\n            d[i]=(a[i]==tmp-x[i])? x[i]:d[i-1];\n        }\n    }\n    reverse(x.begin(),x.end());\n    reverse(v.begin(),v.end());\n    tmp=0;\n    rep(i,n){\n        x[i]=c-x[i];\n        if(i==0){\n            tmp+=v[i];\n            b[i]=max(tmp-x[i],(ll)0);\n            e[i]=(b[i]==tmp-x[i])? x[i]:0;\n        }\n        else{\n            tmp+=v[i];\n            b[i]=max(b[i-1],tmp-x[i]);\n            e[i]=(b[i]==tmp-x[i])? x[i]:e[i-1];\n        }\n    }\n    \n    reverse(b.begin(),b.end());\n    reverse(e.begin(),e.end());\n    //rep(i,n) cout<<d[i]<<\" \"<<e[i]<<endl;\n    ll res=0;\n    rep(i,n){\n        //cout<<i<<endl;\n        if(i==n-1){\n            ll now=a[i];\n            res=max(res,now);\n        }\n        else{\n            ll left=a[i],right=b[i+1];\n            //cout<<left<<\" \"<<right<<endl;\n            ll now=right+left;\n            now-=min(d[i],e[i+1]);\n            res=max(res,now);\n        }\n        if(i==0){\n            ll now=b[i];\n            res=max(res,now);\n        }\n        else{\n            ll left=a[i-1],right=b[i];\n            //cout<<left<<\" \"<<right<<endl;\n            ll now=right+left;\n            now-=min(d[i-1],e[i]);\n            res=max(res,now);\n        }\n    }\n    cout<<res<<endl;\n}", "language": "C++", "metadata": {"date": 1586978306, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03372.html", "problem_id": "p03372", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03372/input.txt", "sample_output_relpath": "derived/input_output/data/p03372/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03372/C++/s277318743.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s277318743", "user_id": "u222866518"}, "prompt_components": {"gold_output": "191\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define rep(i,n) for(int i=0;i<(int)n;i++)\n#define rep1(i,n) for(int i=1;i<=(int)n;i++)\n#define rep2(i,j,n) for(int j=i;j<n;j++)\n#define rep3(i,j,n) for(int j=i;j<=n;j++)\n#define rrep(i,n) for(int i=n-1;i>=0;i--)\n#define sp(n) cout << fixed << setprecision(n)\ntypedef long long ll;\nusing namespace std;\nint main(void){\n    ll n,c;cin>>n>>c;\n    vector<ll> x(n),v(n),a(n),b(n),d(n),e(n);\n    rep(i,n) cin>>x[i]>>v[i];\n    ll tmp=0;\n    rep(i,n){\n        if(i==0){\n            tmp+=v[i];\n            a[i]=max(tmp-x[i],(ll)0);\n            d[i]=(a[i]==tmp-x[i])? x[i]:0;\n        }\n        else{\n            tmp+=v[i];\n            a[i]=max(a[i-1],tmp-x[i]);\n            d[i]=(a[i]==tmp-x[i])? x[i]:d[i-1];\n        }\n    }\n    reverse(x.begin(),x.end());\n    reverse(v.begin(),v.end());\n    tmp=0;\n    rep(i,n){\n        x[i]=c-x[i];\n        if(i==0){\n            tmp+=v[i];\n            b[i]=max(tmp-x[i],(ll)0);\n            e[i]=(b[i]==tmp-x[i])? x[i]:0;\n        }\n        else{\n            tmp+=v[i];\n            b[i]=max(b[i-1],tmp-x[i]);\n            e[i]=(b[i]==tmp-x[i])? x[i]:e[i-1];\n        }\n    }\n    \n    reverse(b.begin(),b.end());\n    reverse(e.begin(),e.end());\n    //rep(i,n) cout<<d[i]<<\" \"<<e[i]<<endl;\n    ll res=0;\n    rep(i,n){\n        //cout<<i<<endl;\n        if(i==n-1){\n            ll now=a[i];\n            res=max(res,now);\n        }\n        else{\n            ll left=a[i],right=b[i+1];\n            //cout<<left<<\" \"<<right<<endl;\n            ll now=right+left;\n            now-=min(d[i],e[i+1]);\n            res=max(res,now);\n        }\n        if(i==0){\n            ll now=b[i];\n            res=max(res,now);\n        }\n        else{\n            ll left=a[i-1],right=b[i];\n            //cout<<left<<\" \"<<right<<endl;\n            ll now=right+left;\n            now-=min(d[i-1],e[i]);\n            res=max(res,now);\n        }\n    }\n    cout<<res<<endl;\n}", "problem_context": "Score : 500 points\n\nProblem Statement\n\n\"Teishi-zushi\", a Japanese restaurant, is a plain restaurant with only one round counter. The outer circumference of the counter is C meters. Customers cannot go inside the counter.\n\nNakahashi entered Teishi-zushi, and he was guided to the counter. Now, there are N pieces of sushi (vinegared rice with seafood and so on) on the counter. The distance measured clockwise from the point where Nakahashi is standing to the point where the i-th sushi is placed, is x_i meters. Also, the i-th sushi has a nutritive value of v_i kilocalories.\n\nNakahashi can freely walk around the circumference of the counter. When he reach a point where a sushi is placed, he can eat that sushi and take in its nutrition (naturally, the sushi disappears). However, while walking, he consumes 1 kilocalories per meter.\n\nWhenever he is satisfied, he can leave the restaurant from any place (he does not have to return to the initial place). On balance, at most how much nutrition can he take in before he leaves? That is, what is the maximum possible value of the total nutrition taken in minus the total energy consumed? Assume that there are no other customers, and no new sushi will be added to the counter. Also, since Nakahashi has plenty of nutrition in his body, assume that no matter how much he walks and consumes energy, he never dies from hunger.\n\nConstraints\n\n1 ≤ N ≤ 10^5\n\n2 ≤ C ≤ 10^{14}\n\n1 ≤ x_1 < x_2 < ... < x_N < C\n\n1 ≤ v_i ≤ 10^9\n\nAll values in input are integers.\n\nSubscores\n\n300 points will be awarded for passing the test set satisfying N ≤ 100.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN C\nx_1 v_1\nx_2 v_2\n:\nx_N v_N\n\nOutput\n\nIf Nakahashi can take in at most c kilocalories on balance before he leaves the restaurant, print c.\n\nSample Input 1\n\n3 20\n2 80\n9 120\n16 1\n\nSample Output 1\n\n191\n\nThere are three sushi on the counter with a circumference of 20 meters. If he walks two meters clockwise from the initial place, he can eat a sushi of 80 kilocalories. If he walks seven more meters clockwise, he can eat a sushi of 120 kilocalories. If he leaves now, the total nutrition taken in is 200 kilocalories, and the total energy consumed is 9 kilocalories, thus he can take in 191 kilocalories on balance, which is the largest possible value.\n\nSample Input 2\n\n3 20\n2 80\n9 1\n16 120\n\nSample Output 2\n\n192\n\nThe second and third sushi have been swapped. Again, if he walks two meters clockwise from the initial place, he can eat a sushi of 80 kilocalories. If he walks six more meters counterclockwise this time, he can eat a sushi of 120 kilocalories. If he leaves now, the total nutrition taken in is 200 kilocalories, and the total energy consumed is 8 kilocalories, thus he can take in 192 kilocalories on balance, which is the largest possible value.\n\nSample Input 3\n\n1 100000000000000\n50000000000000 1\n\nSample Output 3\n\n0\n\nEven though the only sushi is so far that it does not fit into a 32-bit integer, its nutritive value is low, thus he should immediately leave without doing anything.\n\nSample Input 4\n\n15 10000000000\n400000000 1000000000\n800000000 1000000000\n1900000000 1000000000\n2400000000 1000000000\n2900000000 1000000000\n3300000000 1000000000\n3700000000 1000000000\n3800000000 1000000000\n4000000000 1000000000\n4100000000 1000000000\n5200000000 1000000000\n6600000000 1000000000\n8000000000 1000000000\n9300000000 1000000000\n9700000000 1000000000\n\nSample Output 4\n\n6500000000\n\nAll these sample inputs above are included in the test set for the partial score.", "sample_input": "3 20\n2 80\n9 120\n16 1\n"}, "reference_outputs": ["191\n"], "source_document_id": "p03372", "source_text": "Score : 500 points\n\nProblem Statement\n\n\"Teishi-zushi\", a Japanese restaurant, is a plain restaurant with only one round counter. The outer circumference of the counter is C meters. Customers cannot go inside the counter.\n\nNakahashi entered Teishi-zushi, and he was guided to the counter. Now, there are N pieces of sushi (vinegared rice with seafood and so on) on the counter. The distance measured clockwise from the point where Nakahashi is standing to the point where the i-th sushi is placed, is x_i meters. Also, the i-th sushi has a nutritive value of v_i kilocalories.\n\nNakahashi can freely walk around the circumference of the counter. When he reach a point where a sushi is placed, he can eat that sushi and take in its nutrition (naturally, the sushi disappears). However, while walking, he consumes 1 kilocalories per meter.\n\nWhenever he is satisfied, he can leave the restaurant from any place (he does not have to return to the initial place). On balance, at most how much nutrition can he take in before he leaves? That is, what is the maximum possible value of the total nutrition taken in minus the total energy consumed? Assume that there are no other customers, and no new sushi will be added to the counter. Also, since Nakahashi has plenty of nutrition in his body, assume that no matter how much he walks and consumes energy, he never dies from hunger.\n\nConstraints\n\n1 ≤ N ≤ 10^5\n\n2 ≤ C ≤ 10^{14}\n\n1 ≤ x_1 < x_2 < ... < x_N < C\n\n1 ≤ v_i ≤ 10^9\n\nAll values in input are integers.\n\nSubscores\n\n300 points will be awarded for passing the test set satisfying N ≤ 100.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN C\nx_1 v_1\nx_2 v_2\n:\nx_N v_N\n\nOutput\n\nIf Nakahashi can take in at most c kilocalories on balance before he leaves the restaurant, print c.\n\nSample Input 1\n\n3 20\n2 80\n9 120\n16 1\n\nSample Output 1\n\n191\n\nThere are three sushi on the counter with a circumference of 20 meters. If he walks two meters clockwise from the initial place, he can eat a sushi of 80 kilocalories. If he walks seven more meters clockwise, he can eat a sushi of 120 kilocalories. If he leaves now, the total nutrition taken in is 200 kilocalories, and the total energy consumed is 9 kilocalories, thus he can take in 191 kilocalories on balance, which is the largest possible value.\n\nSample Input 2\n\n3 20\n2 80\n9 1\n16 120\n\nSample Output 2\n\n192\n\nThe second and third sushi have been swapped. Again, if he walks two meters clockwise from the initial place, he can eat a sushi of 80 kilocalories. If he walks six more meters counterclockwise this time, he can eat a sushi of 120 kilocalories. If he leaves now, the total nutrition taken in is 200 kilocalories, and the total energy consumed is 8 kilocalories, thus he can take in 192 kilocalories on balance, which is the largest possible value.\n\nSample Input 3\n\n1 100000000000000\n50000000000000 1\n\nSample Output 3\n\n0\n\nEven though the only sushi is so far that it does not fit into a 32-bit integer, its nutritive value is low, thus he should immediately leave without doing anything.\n\nSample Input 4\n\n15 10000000000\n400000000 1000000000\n800000000 1000000000\n1900000000 1000000000\n2400000000 1000000000\n2900000000 1000000000\n3300000000 1000000000\n3700000000 1000000000\n3800000000 1000000000\n4000000000 1000000000\n4100000000 1000000000\n5200000000 1000000000\n6600000000 1000000000\n8000000000 1000000000\n9300000000 1000000000\n9700000000 1000000000\n\nSample Output 4\n\n6500000000\n\nAll these sample inputs above are included in the test set for the partial score.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1892, "cpu_time_ms": 100, "memory_kb": 4992}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s820079649", "group_id": "codeNet:p03373", "input_text": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nint main()\n{\n    int A, B, C, X, Y;\n    cin >> A >> B >> C >> X >> Y;\n    int ans = 0;\n    for (int c = 0; c <= max(X, Y); ++c)\n    {\n        int price = 2 * c * C;\n        if (X - c > 0)\n        {\n            price += (X - c) * A;\n        }\n        if (Y - c > 0)\n        {\n            price += (Y - c) * B;\n        }\n        if (ans == 0)\n        {\n            ans = price;\n        }\n        else\n        {\n            ans = min(price, ans);\n        }\n    }\n    cout << ans << endl;\n}", "language": "C++", "metadata": {"date": 1593555680, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03373.html", "problem_id": "p03373", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03373/input.txt", "sample_output_relpath": "derived/input_output/data/p03373/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03373/C++/s820079649.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s820079649", "user_id": "u818542539"}, "prompt_components": {"gold_output": "7900\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\n#include <algorithm>\nusing namespace std;\n\nint main()\n{\n    int A, B, C, X, Y;\n    cin >> A >> B >> C >> X >> Y;\n    int ans = 0;\n    for (int c = 0; c <= max(X, Y); ++c)\n    {\n        int price = 2 * c * C;\n        if (X - c > 0)\n        {\n            price += (X - c) * A;\n        }\n        if (Y - c > 0)\n        {\n            price += (Y - c) * B;\n        }\n        if (ans == 0)\n        {\n            ans = price;\n        }\n        else\n        {\n            ans = min(price, ans);\n        }\n    }\n    cout << ans << endl;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\n\"Pizza At\", a fast food chain, offers three kinds of pizza: \"A-pizza\", \"B-pizza\" and \"AB-pizza\". A-pizza and B-pizza are completely different pizzas, and AB-pizza is one half of A-pizza and one half of B-pizza combined together. The prices of one A-pizza, B-pizza and AB-pizza are A yen, B yen and C yen (yen is the currency of Japan), respectively.\n\nNakahashi needs to prepare X A-pizzas and Y B-pizzas for a party tonight. He can only obtain these pizzas by directly buying A-pizzas and B-pizzas, or buying two AB-pizzas and then rearrange them into one A-pizza and one B-pizza. At least how much money does he need for this? It is fine to have more pizzas than necessary by rearranging pizzas.\n\nConstraints\n\n1 ≤ A, B, C ≤ 5000\n\n1 ≤ X, Y ≤ 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B C X Y\n\nOutput\n\nPrint the minimum amount of money required to prepare X A-pizzas and Y B-pizzas.\n\nSample Input 1\n\n1500 2000 1600 3 2\n\nSample Output 1\n\n7900\n\nIt is optimal to buy four AB-pizzas and rearrange them into two A-pizzas and two B-pizzas, then buy additional one A-pizza.\n\nSample Input 2\n\n1500 2000 1900 3 2\n\nSample Output 2\n\n8500\n\nIt is optimal to directly buy three A-pizzas and two B-pizzas.\n\nSample Input 3\n\n1500 2000 500 90000 100000\n\nSample Output 3\n\n100000000\n\nIt is optimal to buy 200000 AB-pizzas and rearrange them into 100000 A-pizzas and 100000 B-pizzas. We will have 10000 more A-pizzas than necessary, but that is fine.", "sample_input": "1500 2000 1600 3 2\n"}, "reference_outputs": ["7900\n"], "source_document_id": "p03373", "source_text": "Score : 300 points\n\nProblem Statement\n\n\"Pizza At\", a fast food chain, offers three kinds of pizza: \"A-pizza\", \"B-pizza\" and \"AB-pizza\". A-pizza and B-pizza are completely different pizzas, and AB-pizza is one half of A-pizza and one half of B-pizza combined together. The prices of one A-pizza, B-pizza and AB-pizza are A yen, B yen and C yen (yen is the currency of Japan), respectively.\n\nNakahashi needs to prepare X A-pizzas and Y B-pizzas for a party tonight. He can only obtain these pizzas by directly buying A-pizzas and B-pizzas, or buying two AB-pizzas and then rearrange them into one A-pizza and one B-pizza. At least how much money does he need for this? It is fine to have more pizzas than necessary by rearranging pizzas.\n\nConstraints\n\n1 ≤ A, B, C ≤ 5000\n\n1 ≤ X, Y ≤ 10^5\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B C X Y\n\nOutput\n\nPrint the minimum amount of money required to prepare X A-pizzas and Y B-pizzas.\n\nSample Input 1\n\n1500 2000 1600 3 2\n\nSample Output 1\n\n7900\n\nIt is optimal to buy four AB-pizzas and rearrange them into two A-pizzas and two B-pizzas, then buy additional one A-pizza.\n\nSample Input 2\n\n1500 2000 1900 3 2\n\nSample Output 2\n\n8500\n\nIt is optimal to directly buy three A-pizzas and two B-pizzas.\n\nSample Input 3\n\n1500 2000 500 90000 100000\n\nSample Output 3\n\n100000000\n\nIt is optimal to buy 200000 AB-pizzas and rearrange them into 100000 A-pizzas and 100000 B-pizzas. We will have 10000 more A-pizzas than necessary, but that is fine.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 567, "cpu_time_ms": 8, "memory_kb": 3592}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s436968039", "group_id": "codeNet:p03374", "input_text": "#include <iostream>\n#include <algorithm>\n\n#define ll long long int\n\nusing namespace std;\n\nll x[100005];\nll v[100005];\nll n, c;\n\nint main() {\n  cin >> n >> c;\n  for (int i = 0; i < n; i++) {\n    cin >> x[i] >> v[i];\n  }\n  ll ans = 0;\n  ll cals = 0;\n  for (int i = 0; i < n; i++) {\n    cals += v[i];\n    ans = max(ans, cals - x[i]);\n  }\n  cals = 0;\n  for (int i = n - 1; i >= 0; i--) {\n    cals += v[i];\n    ans = max(ans, cals - (c - x[i]));\n  }\n  \n  for (int i = 0; i < n; i++) {\n    for (int j = n - 1; j > i; j--) {\n      ll cals = 0;\n      for (int k = 0; k <= i; k++) {\n\tcals += v[k];\n      }\n      for (int k = n - 1; k >= j; k--) {\n\tcals += v[k];\n      }\n      ll dist = min(2 * x[i] + c - x[j], 2 * (c - x[j]) + x[i]);\n      ans = max(ans, cals - dist);\n    }\n  }\n  cout << ans;\n}\n", "language": "C++", "metadata": {"date": 1524362287, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03374.html", "problem_id": "p03374", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03374/input.txt", "sample_output_relpath": "derived/input_output/data/p03374/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03374/C++/s436968039.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s436968039", "user_id": "u530984919"}, "prompt_components": {"gold_output": "191\n", "input_to_evaluate": "#include <iostream>\n#include <algorithm>\n\n#define ll long long int\n\nusing namespace std;\n\nll x[100005];\nll v[100005];\nll n, c;\n\nint main() {\n  cin >> n >> c;\n  for (int i = 0; i < n; i++) {\n    cin >> x[i] >> v[i];\n  }\n  ll ans = 0;\n  ll cals = 0;\n  for (int i = 0; i < n; i++) {\n    cals += v[i];\n    ans = max(ans, cals - x[i]);\n  }\n  cals = 0;\n  for (int i = n - 1; i >= 0; i--) {\n    cals += v[i];\n    ans = max(ans, cals - (c - x[i]));\n  }\n  \n  for (int i = 0; i < n; i++) {\n    for (int j = n - 1; j > i; j--) {\n      ll cals = 0;\n      for (int k = 0; k <= i; k++) {\n\tcals += v[k];\n      }\n      for (int k = n - 1; k >= j; k--) {\n\tcals += v[k];\n      }\n      ll dist = min(2 * x[i] + c - x[j], 2 * (c - x[j]) + x[i]);\n      ans = max(ans, cals - dist);\n    }\n  }\n  cout << ans;\n}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\n\"Teishi-zushi\", a Japanese restaurant, is a plain restaurant with only one round counter. The outer circumference of the counter is C meters. Customers cannot go inside the counter.\n\nNakahashi entered Teishi-zushi, and he was guided to the counter. Now, there are N pieces of sushi (vinegared rice with seafood and so on) on the counter. The distance measured clockwise from the point where Nakahashi is standing to the point where the i-th sushi is placed, is x_i meters. Also, the i-th sushi has a nutritive value of v_i kilocalories.\n\nNakahashi can freely walk around the circumference of the counter. When he reach a point where a sushi is placed, he can eat that sushi and take in its nutrition (naturally, the sushi disappears). However, while walking, he consumes 1 kilocalories per meter.\n\nWhenever he is satisfied, he can leave the restaurant from any place (he does not have to return to the initial place). On balance, at most how much nutrition can he take in before he leaves? That is, what is the maximum possible value of the total nutrition taken in minus the total energy consumed? Assume that there are no other customers, and no new sushi will be added to the counter. Also, since Nakahashi has plenty of nutrition in his body, assume that no matter how much he walks and consumes energy, he never dies from hunger.\n\nConstraints\n\n1 ≤ N ≤ 10^5\n\n2 ≤ C ≤ 10^{14}\n\n1 ≤ x_1 < x_2 < ... < x_N < C\n\n1 ≤ v_i ≤ 10^9\n\nAll values in input are integers.\n\nSubscores\n\n300 points will be awarded for passing the test set satisfying N ≤ 100.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN C\nx_1 v_1\nx_2 v_2\n:\nx_N v_N\n\nOutput\n\nIf Nakahashi can take in at most c kilocalories on balance before he leaves the restaurant, print c.\n\nSample Input 1\n\n3 20\n2 80\n9 120\n16 1\n\nSample Output 1\n\n191\n\nThere are three sushi on the counter with a circumference of 20 meters. If he walks two meters clockwise from the initial place, he can eat a sushi of 80 kilocalories. If he walks seven more meters clockwise, he can eat a sushi of 120 kilocalories. If he leaves now, the total nutrition taken in is 200 kilocalories, and the total energy consumed is 9 kilocalories, thus he can take in 191 kilocalories on balance, which is the largest possible value.\n\nSample Input 2\n\n3 20\n2 80\n9 1\n16 120\n\nSample Output 2\n\n192\n\nThe second and third sushi have been swapped. Again, if he walks two meters clockwise from the initial place, he can eat a sushi of 80 kilocalories. If he walks six more meters counterclockwise this time, he can eat a sushi of 120 kilocalories. If he leaves now, the total nutrition taken in is 200 kilocalories, and the total energy consumed is 8 kilocalories, thus he can take in 192 kilocalories on balance, which is the largest possible value.\n\nSample Input 3\n\n1 100000000000000\n50000000000000 1\n\nSample Output 3\n\n0\n\nEven though the only sushi is so far that it does not fit into a 32-bit integer, its nutritive value is low, thus he should immediately leave without doing anything.\n\nSample Input 4\n\n15 10000000000\n400000000 1000000000\n800000000 1000000000\n1900000000 1000000000\n2400000000 1000000000\n2900000000 1000000000\n3300000000 1000000000\n3700000000 1000000000\n3800000000 1000000000\n4000000000 1000000000\n4100000000 1000000000\n5200000000 1000000000\n6600000000 1000000000\n8000000000 1000000000\n9300000000 1000000000\n9700000000 1000000000\n\nSample Output 4\n\n6500000000\n\nAll these sample inputs above are included in the test set for the partial score.", "sample_input": "3 20\n2 80\n9 120\n16 1\n"}, "reference_outputs": ["191\n"], "source_document_id": "p03374", "source_text": "Score : 500 points\n\nProblem Statement\n\n\"Teishi-zushi\", a Japanese restaurant, is a plain restaurant with only one round counter. The outer circumference of the counter is C meters. Customers cannot go inside the counter.\n\nNakahashi entered Teishi-zushi, and he was guided to the counter. Now, there are N pieces of sushi (vinegared rice with seafood and so on) on the counter. The distance measured clockwise from the point where Nakahashi is standing to the point where the i-th sushi is placed, is x_i meters. Also, the i-th sushi has a nutritive value of v_i kilocalories.\n\nNakahashi can freely walk around the circumference of the counter. When he reach a point where a sushi is placed, he can eat that sushi and take in its nutrition (naturally, the sushi disappears). However, while walking, he consumes 1 kilocalories per meter.\n\nWhenever he is satisfied, he can leave the restaurant from any place (he does not have to return to the initial place). On balance, at most how much nutrition can he take in before he leaves? That is, what is the maximum possible value of the total nutrition taken in minus the total energy consumed? Assume that there are no other customers, and no new sushi will be added to the counter. Also, since Nakahashi has plenty of nutrition in his body, assume that no matter how much he walks and consumes energy, he never dies from hunger.\n\nConstraints\n\n1 ≤ N ≤ 10^5\n\n2 ≤ C ≤ 10^{14}\n\n1 ≤ x_1 < x_2 < ... < x_N < C\n\n1 ≤ v_i ≤ 10^9\n\nAll values in input are integers.\n\nSubscores\n\n300 points will be awarded for passing the test set satisfying N ≤ 100.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN C\nx_1 v_1\nx_2 v_2\n:\nx_N v_N\n\nOutput\n\nIf Nakahashi can take in at most c kilocalories on balance before he leaves the restaurant, print c.\n\nSample Input 1\n\n3 20\n2 80\n9 120\n16 1\n\nSample Output 1\n\n191\n\nThere are three sushi on the counter with a circumference of 20 meters. If he walks two meters clockwise from the initial place, he can eat a sushi of 80 kilocalories. If he walks seven more meters clockwise, he can eat a sushi of 120 kilocalories. If he leaves now, the total nutrition taken in is 200 kilocalories, and the total energy consumed is 9 kilocalories, thus he can take in 191 kilocalories on balance, which is the largest possible value.\n\nSample Input 2\n\n3 20\n2 80\n9 1\n16 120\n\nSample Output 2\n\n192\n\nThe second and third sushi have been swapped. Again, if he walks two meters clockwise from the initial place, he can eat a sushi of 80 kilocalories. If he walks six more meters counterclockwise this time, he can eat a sushi of 120 kilocalories. If he leaves now, the total nutrition taken in is 200 kilocalories, and the total energy consumed is 8 kilocalories, thus he can take in 192 kilocalories on balance, which is the largest possible value.\n\nSample Input 3\n\n1 100000000000000\n50000000000000 1\n\nSample Output 3\n\n0\n\nEven though the only sushi is so far that it does not fit into a 32-bit integer, its nutritive value is low, thus he should immediately leave without doing anything.\n\nSample Input 4\n\n15 10000000000\n400000000 1000000000\n800000000 1000000000\n1900000000 1000000000\n2400000000 1000000000\n2900000000 1000000000\n3300000000 1000000000\n3700000000 1000000000\n3800000000 1000000000\n4000000000 1000000000\n4100000000 1000000000\n5200000000 1000000000\n6600000000 1000000000\n8000000000 1000000000\n9300000000 1000000000\n9700000000 1000000000\n\nSample Output 4\n\n6500000000\n\nAll these sample inputs above are included in the test set for the partial score.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 788, "cpu_time_ms": 2103, "memory_kb": 1792}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s250315248", "group_id": "codeNet:p03379", "input_text": "#include <iostream>\n#include <string>\n#include <vector>\n#include <map>\n#include <algorithm>\n#include <cmath>\nusing namespace std;\nusing ll = long long;\n\nint main(int argc, const char * argv[]) {\n    int n;\n    cin >> n;\n    vector<pair<int, ll>> v(n);\n    \n    ll x;\n    pair<ll, int> p;\n    for (int i = 0; i < n; i++) {\n        cin >> x;\n        p .first = x;\n        p.second = i;\n        v[i] = p;\n    }\n    sort(v.begin(), v.end());\n    int a[n];\n    for (int i = 0; i < n; i++) {\n        a[v[i].second] = i;\n    }\n    for (int i = 0; i < n; i++) {\n        if (a[i] < n / 2) {\n            cout << v[(n+1)/2+1-1].first << endl;\n        }else{\n            cout << v[(n+1)/2-1].first << endl;\n        }\n    }\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1531703645, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03379.html", "problem_id": "p03379", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03379/input.txt", "sample_output_relpath": "derived/input_output/data/p03379/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03379/C++/s250315248.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s250315248", "user_id": "u493080913"}, "prompt_components": {"gold_output": "4\n3\n3\n4\n", "input_to_evaluate": "#include <iostream>\n#include <string>\n#include <vector>\n#include <map>\n#include <algorithm>\n#include <cmath>\nusing namespace std;\nusing ll = long long;\n\nint main(int argc, const char * argv[]) {\n    int n;\n    cin >> n;\n    vector<pair<int, ll>> v(n);\n    \n    ll x;\n    pair<ll, int> p;\n    for (int i = 0; i < n; i++) {\n        cin >> x;\n        p .first = x;\n        p.second = i;\n        v[i] = p;\n    }\n    sort(v.begin(), v.end());\n    int a[n];\n    for (int i = 0; i < n; i++) {\n        a[v[i].second] = i;\n    }\n    for (int i = 0; i < n; i++) {\n        if (a[i] < n / 2) {\n            cout << v[(n+1)/2+1-1].first << endl;\n        }else{\n            cout << v[(n+1)/2-1].first << endl;\n        }\n    }\n    return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nWhen l is an odd number, the median of l numbers a_1, a_2, ..., a_l is the (\\frac{l+1}{2})-th largest value among a_1, a_2, ..., a_l.\n\nYou are given N numbers X_1, X_2, ..., X_N, where N is an even number.\nFor each i = 1, 2, ..., N, let the median of X_1, X_2, ..., X_N excluding X_i, that is, the median of X_1, X_2, ..., X_{i-1}, X_{i+1}, ..., X_N be B_i.\n\nFind B_i for each i = 1, 2, ..., N.\n\nConstraints\n\n2 \\leq N \\leq 200000\n\nN is even.\n\n1 \\leq X_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nX_1 X_2 ... X_N\n\nOutput\n\nPrint N lines.\nThe i-th line should contain B_i.\n\nSample Input 1\n\n4\n2 4 4 3\n\nSample Output 1\n\n4\n3\n3\n4\n\nSince the median of X_2, X_3, X_4 is 4, B_1 = 4.\n\nSince the median of X_1, X_3, X_4 is 3, B_2 = 3.\n\nSince the median of X_1, X_2, X_4 is 3, B_3 = 3.\n\nSince the median of X_1, X_2, X_3 is 4, B_4 = 4.\n\nSample Input 2\n\n2\n1 2\n\nSample Output 2\n\n2\n1\n\nSample Input 3\n\n6\n5 5 4 4 3 3\n\nSample Output 3\n\n4\n4\n4\n4\n4\n4", "sample_input": "4\n2 4 4 3\n"}, "reference_outputs": ["4\n3\n3\n4\n"], "source_document_id": "p03379", "source_text": "Score : 300 points\n\nProblem Statement\n\nWhen l is an odd number, the median of l numbers a_1, a_2, ..., a_l is the (\\frac{l+1}{2})-th largest value among a_1, a_2, ..., a_l.\n\nYou are given N numbers X_1, X_2, ..., X_N, where N is an even number.\nFor each i = 1, 2, ..., N, let the median of X_1, X_2, ..., X_N excluding X_i, that is, the median of X_1, X_2, ..., X_{i-1}, X_{i+1}, ..., X_N be B_i.\n\nFind B_i for each i = 1, 2, ..., N.\n\nConstraints\n\n2 \\leq N \\leq 200000\n\nN is even.\n\n1 \\leq X_i \\leq 10^9\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nX_1 X_2 ... X_N\n\nOutput\n\nPrint N lines.\nThe i-th line should contain B_i.\n\nSample Input 1\n\n4\n2 4 4 3\n\nSample Output 1\n\n4\n3\n3\n4\n\nSince the median of X_2, X_3, X_4 is 4, B_1 = 4.\n\nSince the median of X_1, X_3, X_4 is 3, B_2 = 3.\n\nSince the median of X_1, X_2, X_4 is 3, B_3 = 3.\n\nSince the median of X_1, X_2, X_3 is 4, B_4 = 4.\n\nSample Input 2\n\n2\n1 2\n\nSample Output 2\n\n2\n1\n\nSample Input 3\n\n6\n5 5 4 4 3 3\n\nSample Output 3\n\n4\n4\n4\n4\n4\n4", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 727, "cpu_time_ms": 407, "memory_kb": 6144}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s807720878", "group_id": "codeNet:p03380", "input_text": "#include<iostream>\n#include<set>\nusing namespace std;\n\ntypedef long long ll;\n\nint n;\nset<int> A;\n\nint main() {\n    cin >> n;\n    for(int i = 0; i < n; i++) {\n        int a;\n        cin >> a;\n        A.insert(a);\n    }\n\n    int mx = *A.rbegin();\n    A.erase(mx);\n    auto iter = A.lower_bound(mx/2);\n    if(iter == A.begin()) {\n        cout << mx << \" \" << *iter << endl;\n        return 0;\n    }\n    if(iter == A.end()) {\n        cout << mx << \" \" << *(--iter) << endl;\n        return 0;\n    }\n    int r = *iter;\n    int l = *(--iter);\n    int ans = (mx - l < r - mx) ? l : r;\n\n    cout << l << \" \" << r << endl;\n\n    cout << mx << \" \" << ans << endl;\n\n    return 0;\n} ", "language": "C++", "metadata": {"date": 1527194640, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03380.html", "problem_id": "p03380", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03380/input.txt", "sample_output_relpath": "derived/input_output/data/p03380/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03380/C++/s807720878.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s807720878", "user_id": "u262288723"}, "prompt_components": {"gold_output": "11 6\n", "input_to_evaluate": "#include<iostream>\n#include<set>\nusing namespace std;\n\ntypedef long long ll;\n\nint n;\nset<int> A;\n\nint main() {\n    cin >> n;\n    for(int i = 0; i < n; i++) {\n        int a;\n        cin >> a;\n        A.insert(a);\n    }\n\n    int mx = *A.rbegin();\n    A.erase(mx);\n    auto iter = A.lower_bound(mx/2);\n    if(iter == A.begin()) {\n        cout << mx << \" \" << *iter << endl;\n        return 0;\n    }\n    if(iter == A.end()) {\n        cout << mx << \" \" << *(--iter) << endl;\n        return 0;\n    }\n    int r = *iter;\n    int l = *(--iter);\n    int ans = (mx - l < r - mx) ? l : r;\n\n    cout << l << \" \" << r << endl;\n\n    cout << mx << \" \" << ans << endl;\n\n    return 0;\n} ", "problem_context": "Score : 400 points\n\nProblem Statement\n\nLet {\\rm comb}(n,r) be the number of ways to choose r objects from among n objects, disregarding order.\nFrom n non-negative integers a_1, a_2, ..., a_n, select two numbers a_i > a_j so that {\\rm comb}(a_i,a_j) is maximized.\nIf there are multiple pairs that maximize the value, any of them is accepted.\n\nConstraints\n\n2 \\leq n \\leq 10^5\n\n0 \\leq a_i \\leq 10^9\n\na_1,a_2,...,a_n are pairwise distinct.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn\na_1 a_2 ... a_n\n\nOutput\n\nPrint a_i and a_j that you selected, with a space in between.\n\nSample Input 1\n\n5\n6 9 4 2 11\n\nSample Output 1\n\n11 6\n\n\\rm{comb}(a_i,a_j) for each possible selection is as follows:\n\n\\rm{comb}(4,2)=6\n\n\\rm{comb}(6,2)=15\n\n\\rm{comb}(6,4)=15\n\n\\rm{comb}(9,2)=36\n\n\\rm{comb}(9,4)=126\n\n\\rm{comb}(9,6)=84\n\n\\rm{comb}(11,2)=55\n\n\\rm{comb}(11,4)=330\n\n\\rm{comb}(11,6)=462\n\n\\rm{comb}(11,9)=55\n\nThus, we should print 11 and 6.\n\nSample Input 2\n\n2\n100 0\n\nSample Output 2\n\n100 0", "sample_input": "5\n6 9 4 2 11\n"}, "reference_outputs": ["11 6\n"], "source_document_id": "p03380", "source_text": "Score : 400 points\n\nProblem Statement\n\nLet {\\rm comb}(n,r) be the number of ways to choose r objects from among n objects, disregarding order.\nFrom n non-negative integers a_1, a_2, ..., a_n, select two numbers a_i > a_j so that {\\rm comb}(a_i,a_j) is maximized.\nIf there are multiple pairs that maximize the value, any of them is accepted.\n\nConstraints\n\n2 \\leq n \\leq 10^5\n\n0 \\leq a_i \\leq 10^9\n\na_1,a_2,...,a_n are pairwise distinct.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn\na_1 a_2 ... a_n\n\nOutput\n\nPrint a_i and a_j that you selected, with a space in between.\n\nSample Input 1\n\n5\n6 9 4 2 11\n\nSample Output 1\n\n11 6\n\n\\rm{comb}(a_i,a_j) for each possible selection is as follows:\n\n\\rm{comb}(4,2)=6\n\n\\rm{comb}(6,2)=15\n\n\\rm{comb}(6,4)=15\n\n\\rm{comb}(9,2)=36\n\n\\rm{comb}(9,4)=126\n\n\\rm{comb}(9,6)=84\n\n\\rm{comb}(11,2)=55\n\n\\rm{comb}(11,4)=330\n\n\\rm{comb}(11,6)=462\n\n\\rm{comb}(11,9)=55\n\nThus, we should print 11 and 6.\n\nSample Input 2\n\n2\n100 0\n\nSample Output 2\n\n100 0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 668, "cpu_time_ms": 86, "memory_kb": 4992}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s058588793", "group_id": "codeNet:p03382", "input_text": "#include <iostream>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <algorithm>\n#include <functional>\n#include <string>\n#include <sstream>\n#include <complex>\n#include <vector>\n#include <list>\n#include <queue>\n#include <deque>\n#include <stack>\n#include <map>\n#include <set>\n\nusing namespace std;\ntypedef pair<int, int> P;\n\n#define pi 3.141592653589793)\n#define mod 1000000007\n\nint n, a[100001];\nint ans = 1000000000;\nint num;\n\nvoid solve() {\n\tcin >> n;\n\tfor (int i = 0; i < n; i++) {\n\t\tcin >> a[i];\n\t}\n\tsort(a, a + n);\n\tint left, right;\n\t\n\tleft = a[n - 1];\n\tfor (int i = 0; i < n-1; i++) {\n\t\tif (ans >= abs(left / 2 - a[i])) {\n\t\t\tans = abs(left / 2 - a[i]);\n\t\t\tnum = i;\n\t\t}\n\t}\n\tright = a[num];\n\tcout << left << \" \" <<right << endl;\n\n}\n\nint main() {\n\tsolve();\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1523756024, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03382.html", "problem_id": "p03382", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03382/input.txt", "sample_output_relpath": "derived/input_output/data/p03382/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03382/C++/s058588793.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s058588793", "user_id": "u307037394"}, "prompt_components": {"gold_output": "11 6\n", "input_to_evaluate": "#include <iostream>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <algorithm>\n#include <functional>\n#include <string>\n#include <sstream>\n#include <complex>\n#include <vector>\n#include <list>\n#include <queue>\n#include <deque>\n#include <stack>\n#include <map>\n#include <set>\n\nusing namespace std;\ntypedef pair<int, int> P;\n\n#define pi 3.141592653589793)\n#define mod 1000000007\n\nint n, a[100001];\nint ans = 1000000000;\nint num;\n\nvoid solve() {\n\tcin >> n;\n\tfor (int i = 0; i < n; i++) {\n\t\tcin >> a[i];\n\t}\n\tsort(a, a + n);\n\tint left, right;\n\t\n\tleft = a[n - 1];\n\tfor (int i = 0; i < n-1; i++) {\n\t\tif (ans >= abs(left / 2 - a[i])) {\n\t\t\tans = abs(left / 2 - a[i]);\n\t\t\tnum = i;\n\t\t}\n\t}\n\tright = a[num];\n\tcout << left << \" \" <<right << endl;\n\n}\n\nint main() {\n\tsolve();\n\treturn 0;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nLet {\\rm comb}(n,r) be the number of ways to choose r objects from among n objects, disregarding order.\nFrom n non-negative integers a_1, a_2, ..., a_n, select two numbers a_i > a_j so that {\\rm comb}(a_i,a_j) is maximized.\nIf there are multiple pairs that maximize the value, any of them is accepted.\n\nConstraints\n\n2 \\leq n \\leq 10^5\n\n0 \\leq a_i \\leq 10^9\n\na_1,a_2,...,a_n are pairwise distinct.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn\na_1 a_2 ... a_n\n\nOutput\n\nPrint a_i and a_j that you selected, with a space in between.\n\nSample Input 1\n\n5\n6 9 4 2 11\n\nSample Output 1\n\n11 6\n\n\\rm{comb}(a_i,a_j) for each possible selection is as follows:\n\n\\rm{comb}(4,2)=6\n\n\\rm{comb}(6,2)=15\n\n\\rm{comb}(6,4)=15\n\n\\rm{comb}(9,2)=36\n\n\\rm{comb}(9,4)=126\n\n\\rm{comb}(9,6)=84\n\n\\rm{comb}(11,2)=55\n\n\\rm{comb}(11,4)=330\n\n\\rm{comb}(11,6)=462\n\n\\rm{comb}(11,9)=55\n\nThus, we should print 11 and 6.\n\nSample Input 2\n\n2\n100 0\n\nSample Output 2\n\n100 0", "sample_input": "5\n6 9 4 2 11\n"}, "reference_outputs": ["11 6\n"], "source_document_id": "p03382", "source_text": "Score : 400 points\n\nProblem Statement\n\nLet {\\rm comb}(n,r) be the number of ways to choose r objects from among n objects, disregarding order.\nFrom n non-negative integers a_1, a_2, ..., a_n, select two numbers a_i > a_j so that {\\rm comb}(a_i,a_j) is maximized.\nIf there are multiple pairs that maximize the value, any of them is accepted.\n\nConstraints\n\n2 \\leq n \\leq 10^5\n\n0 \\leq a_i \\leq 10^9\n\na_1,a_2,...,a_n are pairwise distinct.\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn\na_1 a_2 ... a_n\n\nOutput\n\nPrint a_i and a_j that you selected, with a space in between.\n\nSample Input 1\n\n5\n6 9 4 2 11\n\nSample Output 1\n\n11 6\n\n\\rm{comb}(a_i,a_j) for each possible selection is as follows:\n\n\\rm{comb}(4,2)=6\n\n\\rm{comb}(6,2)=15\n\n\\rm{comb}(6,4)=15\n\n\\rm{comb}(9,2)=36\n\n\\rm{comb}(9,4)=126\n\n\\rm{comb}(9,6)=84\n\n\\rm{comb}(11,2)=55\n\n\\rm{comb}(11,4)=330\n\n\\rm{comb}(11,6)=462\n\n\\rm{comb}(11,9)=55\n\nThus, we should print 11 and 6.\n\nSample Input 2\n\n2\n100 0\n\nSample Output 2\n\n100 0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 787, "cpu_time_ms": 60, "memory_kb": 640}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s761022407", "group_id": "codeNet:p03386", "input_text": "#include<stdio.h>\n#include<iostream>\nusing namespace std;\n\nint A,B,K;\nint main (){\n\n    cin >> A >> B >> K;\n    int x,y;\n    if(B - K < 0) x = A+K;\n    else x = B - K;\n    for(int i=A; i<A+K; i++) {\n        y = i;\n        cout << y << endl;\n        if(i == B ) return 0;\n    }\n    for(int i=x+1; i<=B; i++) {\n        if( y == i ) ;\n        else cout << i << endl;\n    }\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1523153667, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03386.html", "problem_id": "p03386", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03386/input.txt", "sample_output_relpath": "derived/input_output/data/p03386/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03386/C++/s761022407.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s761022407", "user_id": "u090967649"}, "prompt_components": {"gold_output": "3\n4\n7\n8\n", "input_to_evaluate": "#include<stdio.h>\n#include<iostream>\nusing namespace std;\n\nint A,B,K;\nint main (){\n\n    cin >> A >> B >> K;\n    int x,y;\n    if(B - K < 0) x = A+K;\n    else x = B - K;\n    for(int i=A; i<A+K; i++) {\n        y = i;\n        cout << y << endl;\n        if(i == B ) return 0;\n    }\n    for(int i=x+1; i<=B; i++) {\n        if( y == i ) ;\n        else cout << i << endl;\n    }\n    return 0;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nPrint all the integers that satisfies the following in ascending order:\n\nAmong the integers between A and B (inclusive), it is either within the K smallest integers or within the K largest integers.\n\nConstraints\n\n1 \\leq A \\leq B \\leq 10^9\n\n1 \\leq K \\leq 100\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B K\n\nOutput\n\nPrint all the integers that satisfies the condition above in ascending order.\n\nSample Input 1\n\n3 8 2\n\nSample Output 1\n\n3\n4\n7\n8\n\n3 is the first smallest integer among the integers between 3 and 8.\n\n4 is the second smallest integer among the integers between 3 and 8.\n\n7 is the second largest integer among the integers between 3 and 8.\n\n8 is the first largest integer among the integers between 3 and 8.\n\nSample Input 2\n\n4 8 3\n\nSample Output 2\n\n4\n5\n6\n7\n8\n\nSample Input 3\n\n2 9 100\n\nSample Output 3\n\n2\n3\n4\n5\n6\n7\n8\n9", "sample_input": "3 8 2\n"}, "reference_outputs": ["3\n4\n7\n8\n"], "source_document_id": "p03386", "source_text": "Score : 200 points\n\nProblem Statement\n\nPrint all the integers that satisfies the following in ascending order:\n\nAmong the integers between A and B (inclusive), it is either within the K smallest integers or within the K largest integers.\n\nConstraints\n\n1 \\leq A \\leq B \\leq 10^9\n\n1 \\leq K \\leq 100\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B K\n\nOutput\n\nPrint all the integers that satisfies the condition above in ascending order.\n\nSample Input 1\n\n3 8 2\n\nSample Output 1\n\n3\n4\n7\n8\n\n3 is the first smallest integer among the integers between 3 and 8.\n\n4 is the second smallest integer among the integers between 3 and 8.\n\n7 is the second largest integer among the integers between 3 and 8.\n\n8 is the first largest integer among the integers between 3 and 8.\n\nSample Input 2\n\n4 8 3\n\nSample Output 2\n\n4\n5\n6\n7\n8\n\nSample Input 3\n\n2 9 100\n\nSample Output 3\n\n2\n3\n4\n5\n6\n7\n8\n9", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 386, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s135650018", "group_id": "codeNet:p03387", "input_text": "#define _GLIBCXX_DEBUG//TLEの原因になるので注意！！！！！！！！！！！\n#include<cmath>\n#include <bits/stdc++.h>\ntypedef long long ll;\nusing namespace std;\nvector<int> arr;\nstack<int> st;\nqueue<int> qu;\nqueue<pair<int,int> > qu2;\npriority_queue<int> pq;\n#define rep(i,n) for(int i=0; i<(int)(n); i++)\n#define rep2(i,n) for(int i=1; i<=(int)(n); i++)\n#define mins(x,y) x=min(x,y)\n#define maxs(x,y) x=max(x,y)\ntypedef set<int> set_t;\ntypedef set<string> set_g;\ntypedef complex<double> xy_t;\nstatic const int NIL = -1;\nstatic const int INF = 1000000007;\n#define mp make_pair\n\n/*int P[10010];\nvoid init(int n){//Union-find\n    for(int i=0;i<n;++i)P[i]=i;\n}\nint root(int a) {\n    if(P[a]==a)return a;\n    return (P[a]=root(P[a]));\n}\nbool is_same_set(int a,int b){\n    return root(a) == root(b);//代表元を求める\n}\nvoid unite(int a,int b){\n    P[root(a)]=root(b);\n}//対set,グラフ？\n//セグメント木？？\n*/\n\ndouble dot_product(xy_t a, xy_t b) { return (conj(a)*b).real(); }//内積\ndouble cross_product(xy_t a, xy_t b) { return (conj(a)*b).imag(); }//外積\nxy_t projection(xy_t p, xy_t b) { return b*dot_product(p,b)/norm(b); }//投影\n//対図形\n\n#define mod 1000000007\n/*ll f[2001];\n//int n,k とかしておく\n\nll pw(ll x, ll y){//euclidの互除法より\n    ll a= 1;\n    while(y){\n        if(y&1){//奇数なら\n            a = a*x%mod;\n        }\n        x = x*x%mod;\n        y /= 2;\n    }\n    return a;\n}\n\nll modinv(ll x){//逆元を求める\n    return pw(x, mod - 2 );\n}\n\nll comb(int n,int r){\n    if(n<r){\n        return 0;\n    }\n    return f[n] * modinv(f[r])%mod*modinv(f[n-r])%mod;\n}//対combination//ただしfは用意してね\n*/\n\n//cerrはコメントアウトしなくても通る\n\nint main(){\n    vector<int> a(3);\n    cin >> a[0]>> a[1]>> a[2];\n    sort(a.begin(),a.end(),greater<int>());\n    int ans=0;\n    int l=(a[0]-a[2])/2;\n    a[2]+=2*l;\n    int r=(a[0]-a[1])/2;\n    a[1]+=2*r;\n    ans+=l+r;\n    if(a[0]==a[1]&&a[0]==a[2]){\n        cout<<ans<<endl;\n    }else if(a[0]==a[1]&&a[0]!=a[2]){\n        cout<<ans+2<<endl;\n    }else if(a[0]!=a[1]&&a[1]==a[2]){\n        cout<<ans+1<<endl;\n    }else if(a[0]!=a[1]&&a[0]==a[2]){\n        cout<<ans+2<<endl;\n    }else{\n        cerr<<'?'<<endl;\n    }\n    return 0;\n}", "language": "C++", "metadata": {"date": 1568244935, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03387.html", "problem_id": "p03387", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03387/input.txt", "sample_output_relpath": "derived/input_output/data/p03387/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03387/C++/s135650018.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s135650018", "user_id": "u300866293"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#define _GLIBCXX_DEBUG//TLEの原因になるので注意！！！！！！！！！！！\n#include<cmath>\n#include <bits/stdc++.h>\ntypedef long long ll;\nusing namespace std;\nvector<int> arr;\nstack<int> st;\nqueue<int> qu;\nqueue<pair<int,int> > qu2;\npriority_queue<int> pq;\n#define rep(i,n) for(int i=0; i<(int)(n); i++)\n#define rep2(i,n) for(int i=1; i<=(int)(n); i++)\n#define mins(x,y) x=min(x,y)\n#define maxs(x,y) x=max(x,y)\ntypedef set<int> set_t;\ntypedef set<string> set_g;\ntypedef complex<double> xy_t;\nstatic const int NIL = -1;\nstatic const int INF = 1000000007;\n#define mp make_pair\n\n/*int P[10010];\nvoid init(int n){//Union-find\n    for(int i=0;i<n;++i)P[i]=i;\n}\nint root(int a) {\n    if(P[a]==a)return a;\n    return (P[a]=root(P[a]));\n}\nbool is_same_set(int a,int b){\n    return root(a) == root(b);//代表元を求める\n}\nvoid unite(int a,int b){\n    P[root(a)]=root(b);\n}//対set,グラフ？\n//セグメント木？？\n*/\n\ndouble dot_product(xy_t a, xy_t b) { return (conj(a)*b).real(); }//内積\ndouble cross_product(xy_t a, xy_t b) { return (conj(a)*b).imag(); }//外積\nxy_t projection(xy_t p, xy_t b) { return b*dot_product(p,b)/norm(b); }//投影\n//対図形\n\n#define mod 1000000007\n/*ll f[2001];\n//int n,k とかしておく\n\nll pw(ll x, ll y){//euclidの互除法より\n    ll a= 1;\n    while(y){\n        if(y&1){//奇数なら\n            a = a*x%mod;\n        }\n        x = x*x%mod;\n        y /= 2;\n    }\n    return a;\n}\n\nll modinv(ll x){//逆元を求める\n    return pw(x, mod - 2 );\n}\n\nll comb(int n,int r){\n    if(n<r){\n        return 0;\n    }\n    return f[n] * modinv(f[r])%mod*modinv(f[n-r])%mod;\n}//対combination//ただしfは用意してね\n*/\n\n//cerrはコメントアウトしなくても通る\n\nint main(){\n    vector<int> a(3);\n    cin >> a[0]>> a[1]>> a[2];\n    sort(a.begin(),a.end(),greater<int>());\n    int ans=0;\n    int l=(a[0]-a[2])/2;\n    a[2]+=2*l;\n    int r=(a[0]-a[1])/2;\n    a[1]+=2*r;\n    ans+=l+r;\n    if(a[0]==a[1]&&a[0]==a[2]){\n        cout<<ans<<endl;\n    }else if(a[0]==a[1]&&a[0]!=a[2]){\n        cout<<ans+2<<endl;\n    }else if(a[0]!=a[1]&&a[1]==a[2]){\n        cout<<ans+1<<endl;\n    }else if(a[0]!=a[1]&&a[0]==a[2]){\n        cout<<ans+2<<endl;\n    }else{\n        cerr<<'?'<<endl;\n    }\n    return 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nYou are given three integers A, B and C. Find the minimum number of operations required to make A, B and C all equal by repeatedly performing the following two kinds of operations in any order:\n\nChoose two among A, B and C, then increase both by 1.\n\nChoose one among A, B and C, then increase it by 2.\n\nIt can be proved that we can always make A, B and C all equal by repeatedly performing these operations.\n\nConstraints\n\n0 \\leq A,B,C \\leq 50\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B C\n\nOutput\n\nPrint the minimum number of operations required to make A, B and C all equal.\n\nSample Input 1\n\n2 5 4\n\nSample Output 1\n\n2\n\nWe can make A, B and C all equal by the following operations:\n\nIncrease A and C by 1. Now, A, B, C are 3, 5, 5, respectively.\n\nIncrease A by 2. Now, A, B, C are 5, 5, 5, respectively.\n\nSample Input 2\n\n2 6 3\n\nSample Output 2\n\n5\n\nSample Input 3\n\n31 41 5\n\nSample Output 3\n\n23", "sample_input": "2 5 4\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03387", "source_text": "Score : 300 points\n\nProblem Statement\n\nYou are given three integers A, B and C. Find the minimum number of operations required to make A, B and C all equal by repeatedly performing the following two kinds of operations in any order:\n\nChoose two among A, B and C, then increase both by 1.\n\nChoose one among A, B and C, then increase it by 2.\n\nIt can be proved that we can always make A, B and C all equal by repeatedly performing these operations.\n\nConstraints\n\n0 \\leq A,B,C \\leq 50\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B C\n\nOutput\n\nPrint the minimum number of operations required to make A, B and C all equal.\n\nSample Input 1\n\n2 5 4\n\nSample Output 1\n\n2\n\nWe can make A, B and C all equal by the following operations:\n\nIncrease A and C by 1. Now, A, B, C are 3, 5, 5, respectively.\n\nIncrease A by 2. Now, A, B, C are 5, 5, 5, respectively.\n\nSample Input 2\n\n2 6 3\n\nSample Output 2\n\n5\n\nSample Input 3\n\n31 41 5\n\nSample Output 3\n\n23", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2258, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s637164533", "group_id": "codeNet:p03387", "input_text": "#include <stdio.h>\nint main (void){\n  int a,b,c,i,j,count;\n  scanf(\"%d %d %d\",&a,&b,&c);\n  count = 0;\n  if (a == b && b == c)\n    printf(\"%d\\n\",count);\n  if (a > b && b > c){\n    for (i = 0; i < a - b; i++)\n      count++;\n  }\n  else if (a > b && a > c && c > b){\n    j = a - c;\n    for (i = 0; i < j; i++){\n      count++;\n      c++;\n      b++;\n    }\n  }\n  else if (b > c && c > a){\n    j = b - c;\n    for (i = 0; i < j; i++){\n      count++;\n      c++;\n      a++;\n    }\n  }\n  else if (b > c && b > a && a > c){\n    j = b - a;\n    for (i = 0; i < j; i++){\n      count++;\n      a++;\n      c++;\n    }\n  }\n  else if (c > a && a > b){\n    j = c - a;\n    for (i = 0; i < j; i++){\n      count++;\n      a++;\n      b++;\n    }\n  }\n  else if (c > a && c > b && b > a){\n    j = c - b;\n    for (i = 0; i < j; i++){\n      count++;\n      b++;\n      a++;\n    }\n  }\n  if (a == b && b > c){\n    j = b - c;\n    for (i = 0; i < j; i++){\n      count++;\n      c += 2;\n      if (b == c){\n\tprintf(\"%d\\n\",count);\n\tbreak;\n      }\n      else if (b < c){\n\tcount++;\n\tprintf(\"%d\\n\",count);\n\tbreak;\n      }\n    }\n  }\n  else if (a == b && b < c){\n    for (i = 0; i < c - b; i++){\n      count++;\n      printf(\"%d\\n\",count);\n    }\n  }\n  else if (b == c && a < b){\n    j = b - a;\n    for (i = 0; i < j; i++){\n      count++;\n      a += 2;\n      if (a == b){\n\tprintf(\"%d\\n\",count);\n\tbreak;\n      }\n      else if (a > b){\n\tcount++;\n\tprintf(\"%d\\n\",count);\n\tbreak;\n      }\n    }\n  }\n  else if (b == c && a > b){\n    for (i = 0; i < b - a; i++){\n      count++;\n      printf(\"%d\\n\",count);\n      break;\n    }\n  }\n  else if (a == c && c > b){\n    j = b - c;\n    for (i = 0; i < j; i++){\n      count++;\n      b += 2;\n      if (c == b){\n\tprintf(\"%d\\n\",count);\n\tbreak;\n      }\n      else if (c < b){\n\tcount++;\n\tprintf(\"%d\\n\",count);\n\tbreak;\n      }\n    }\n  }\n  else if (a == c && b > c){\n    for (i = 0; i < b - c; i++){\n      count++;\n      printf(\"%d\\n\",count);\n      break;\n    }\n  }\n  return (0);\n}\n      \n    \n    \n", "language": "C++", "metadata": {"date": 1528391427, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03387.html", "problem_id": "p03387", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03387/input.txt", "sample_output_relpath": "derived/input_output/data/p03387/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03387/C++/s637164533.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s637164533", "user_id": "u642275568"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <stdio.h>\nint main (void){\n  int a,b,c,i,j,count;\n  scanf(\"%d %d %d\",&a,&b,&c);\n  count = 0;\n  if (a == b && b == c)\n    printf(\"%d\\n\",count);\n  if (a > b && b > c){\n    for (i = 0; i < a - b; i++)\n      count++;\n  }\n  else if (a > b && a > c && c > b){\n    j = a - c;\n    for (i = 0; i < j; i++){\n      count++;\n      c++;\n      b++;\n    }\n  }\n  else if (b > c && c > a){\n    j = b - c;\n    for (i = 0; i < j; i++){\n      count++;\n      c++;\n      a++;\n    }\n  }\n  else if (b > c && b > a && a > c){\n    j = b - a;\n    for (i = 0; i < j; i++){\n      count++;\n      a++;\n      c++;\n    }\n  }\n  else if (c > a && a > b){\n    j = c - a;\n    for (i = 0; i < j; i++){\n      count++;\n      a++;\n      b++;\n    }\n  }\n  else if (c > a && c > b && b > a){\n    j = c - b;\n    for (i = 0; i < j; i++){\n      count++;\n      b++;\n      a++;\n    }\n  }\n  if (a == b && b > c){\n    j = b - c;\n    for (i = 0; i < j; i++){\n      count++;\n      c += 2;\n      if (b == c){\n\tprintf(\"%d\\n\",count);\n\tbreak;\n      }\n      else if (b < c){\n\tcount++;\n\tprintf(\"%d\\n\",count);\n\tbreak;\n      }\n    }\n  }\n  else if (a == b && b < c){\n    for (i = 0; i < c - b; i++){\n      count++;\n      printf(\"%d\\n\",count);\n    }\n  }\n  else if (b == c && a < b){\n    j = b - a;\n    for (i = 0; i < j; i++){\n      count++;\n      a += 2;\n      if (a == b){\n\tprintf(\"%d\\n\",count);\n\tbreak;\n      }\n      else if (a > b){\n\tcount++;\n\tprintf(\"%d\\n\",count);\n\tbreak;\n      }\n    }\n  }\n  else if (b == c && a > b){\n    for (i = 0; i < b - a; i++){\n      count++;\n      printf(\"%d\\n\",count);\n      break;\n    }\n  }\n  else if (a == c && c > b){\n    j = b - c;\n    for (i = 0; i < j; i++){\n      count++;\n      b += 2;\n      if (c == b){\n\tprintf(\"%d\\n\",count);\n\tbreak;\n      }\n      else if (c < b){\n\tcount++;\n\tprintf(\"%d\\n\",count);\n\tbreak;\n      }\n    }\n  }\n  else if (a == c && b > c){\n    for (i = 0; i < b - c; i++){\n      count++;\n      printf(\"%d\\n\",count);\n      break;\n    }\n  }\n  return (0);\n}\n      \n    \n    \n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nYou are given three integers A, B and C. Find the minimum number of operations required to make A, B and C all equal by repeatedly performing the following two kinds of operations in any order:\n\nChoose two among A, B and C, then increase both by 1.\n\nChoose one among A, B and C, then increase it by 2.\n\nIt can be proved that we can always make A, B and C all equal by repeatedly performing these operations.\n\nConstraints\n\n0 \\leq A,B,C \\leq 50\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B C\n\nOutput\n\nPrint the minimum number of operations required to make A, B and C all equal.\n\nSample Input 1\n\n2 5 4\n\nSample Output 1\n\n2\n\nWe can make A, B and C all equal by the following operations:\n\nIncrease A and C by 1. Now, A, B, C are 3, 5, 5, respectively.\n\nIncrease A by 2. Now, A, B, C are 5, 5, 5, respectively.\n\nSample Input 2\n\n2 6 3\n\nSample Output 2\n\n5\n\nSample Input 3\n\n31 41 5\n\nSample Output 3\n\n23", "sample_input": "2 5 4\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03387", "source_text": "Score : 300 points\n\nProblem Statement\n\nYou are given three integers A, B and C. Find the minimum number of operations required to make A, B and C all equal by repeatedly performing the following two kinds of operations in any order:\n\nChoose two among A, B and C, then increase both by 1.\n\nChoose one among A, B and C, then increase it by 2.\n\nIt can be proved that we can always make A, B and C all equal by repeatedly performing these operations.\n\nConstraints\n\n0 \\leq A,B,C \\leq 50\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B C\n\nOutput\n\nPrint the minimum number of operations required to make A, B and C all equal.\n\nSample Input 1\n\n2 5 4\n\nSample Output 1\n\n2\n\nWe can make A, B and C all equal by the following operations:\n\nIncrease A and C by 1. Now, A, B, C are 3, 5, 5, respectively.\n\nIncrease A by 2. Now, A, B, C are 5, 5, 5, respectively.\n\nSample Input 2\n\n2 6 3\n\nSample Output 2\n\n5\n\nSample Input 3\n\n31 41 5\n\nSample Output 3\n\n23", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1973, "cpu_time_ms": 1, "memory_kb": 128}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s499977205", "group_id": "codeNet:p03388", "input_text": "#include <iostream>\n#include <vector>\n#include <set>\n#include <unordered_set>\n#include <map>\n#include <unordered_map>\n#include <cstdio>\n#include <bitset>\n#include <queue>\n#include <deque>\n#include <algorithm>\n#include <numeric>\n#include <cassert>\n#include <functional>\n#include <stack>\n#include <cmath>\n#include <string>\n\nusing namespace std;\n\n#define REP(i, N) for (int i = 0; i < (int)N; i++)\n#define FOR(i, a, b) for (int i = a; i < (int)b; i++)\n#define ALL(x) (x).begin(), (x).end()\n#define INF (1 << 30)\n#define LLINF (1LL << 62)\n#define DEBUG(...) debug(__LINE__, \":\" __VA_ARGS__)\n\nconstexpr int MOD = 1000000007;\nusing ll = long long;\nusing Pii = pair<int, int>;\nusing Pll = pair<ll, ll>;\n\ninline int popcount(ll x) { return __builtin_popcountll(x); }\ninline int div2num(ll x) { return __builtin_ctzll(x); }\ninline bool bit(ll x, int b) { return (x >> b) & 1; }\n\ntemplate <class T>\nstring to_string(T s);\ntemplate <class S, class T>\nstring to_string(pair<S, T> p);\nstring to_string(string s) { return s; }\nstring to_string(const char s[]) { return to_string(string(s)); }\n\ntemplate <class T>\nstring to_string(T v) {\n  if (v.empty()) return \"{}\";\n  string ret = \"{\";\n  for (auto x : v) ret += to_string(x) + \",\";\n  ret.back() = '}';\n  return ret;\n}\n\ntemplate <class S, class T>\nstring to_string(pair<S, T> p) {\n  return \"{\" + to_string(p.first) + \":\" + to_string(p.second) + \"}\";\n}\nvoid debug() { cerr << endl; }\n\ntemplate <class Head, class... Tail>\nvoid debug(Head head, Tail... tail) {\n  cerr << to_string(head) << \" \";\n  debug(tail...);\n}\n\nstruct IO {\n#ifdef _WIN32\n  inline char getchar_unlocked() { return getchar(); }\n  inline void putchar_unlocked(char c) { putchar(c); }\n#endif\n  std::string separator = \" \";\n  template <class T>\n  inline void read(T &x) {\n    char c;\n    do {\n      c = getchar_unlocked();\n    } while (c != '-' && (c < '0' || '9' < c));\n    bool minus = 0;\n    if (c == '-') {\n      minus = 1;\n      c = getchar_unlocked();\n    }\n    x = 0;\n    while ('0' <= c && c <= '9') {\n      x *= 10;\n      x += c - '0';\n      c = getchar_unlocked();\n    }\n    if (minus) x = -x;\n  }\n  inline void read(std::string &x) {\n    char c;\n    do {\n      c = getchar_unlocked();\n    } while (c == ' ' || c == '\\n');\n    x.clear();\n    do {\n      x += c;\n      c = getchar_unlocked();\n    } while (c != ' ' && c != '\\n' && c != EOF);\n  }\n  template <class T>\n  inline void read(std::vector<T> &v) {\n    for (auto &x : v) read(x);\n  }\n  template <class S, class T>\n  inline void read(std::pair<S, T> &p) {\n    read(p.first);\n    read(p.second);\n  }\n  template <class Head, class... Tail>\n  inline void read(Head &head, Tail &... tail) {\n    read(head);\n    read(tail...);\n  }\n  template <class T>\n  inline void write(T x) {\n    char buf[32];\n    int p = 0;\n    if (x < 0) {\n      x = -x;\n      putchar_unlocked('-');\n    }\n    if (x == 0) putchar_unlocked('0');\n    while (x > 0) {\n      buf[p++] = (x % 10) + '0';\n      x /= 10;\n    }\n    while (p) {\n      putchar_unlocked(buf[--p]);\n    }\n  }\n  inline void write(std::string x) {\n    for (char c : x) putchar_unlocked(c);\n  }\n  inline void write(const char s[]) {\n    for (int i = 0; s[i] != 0; ++i) putchar_unlocked(s[i]);\n  }\n  template <class T>\n  inline void write(std::vector<T> v) {\n    if (v.empty()) return;\n    for (auto itr = v.begin(); itr + 1 != v.end(); ++itr) {\n      write(*itr);\n      write(separator);\n    }\n    write(v.back());\n  }\n  template <class Head, class... Tail>\n  inline void write(Head head, Tail... tail) {\n    write(head);\n    write(separator);\n    write(tail...);\n  }\n  template <class Head, class... Tail>\n  inline void writeln(Head head, Tail... tail) {\n    write(head, tail...);\n    write(\"\\n\");\n  }\n  void set_separator(std::string s) { separator = s; }\n} io;\n\nstruct Prime {\n  int n;\n  vector<int> table;\n  vector<int> primes;\n  Prime(int _n = 100000) {\n    n = _n + 1;\n    table.resize(n, -1);\n    table[0] = 0;\n    table[1] = -1;\n    for (int i = 2; i * i < n; ++i) {\n      if (table[i] == -1) {\n        for (int j = i * i; j < n; j += i) {\n          table[j] = i;\n        }\n      }\n    }\n  }\n  void enumerate_primes() {\n    primes.clear();\n    for (int i = 2; i < n; ++i) {\n      if (table[i] == -1) primes.push_back(i);\n    }\n  }\n  vector<pair<long long, int>> prime_factor(long long x) {\n    map<long long, int> mp;\n    long long div = 2;\n    int p = 0;\n    while (n <= x && div * div <= x) {\n      if (x % div == 0) {\n        mp[div]++;\n        x /= div;\n      } else {\n        if (p + 1 < primes.size()) {\n          div = primes[++p];\n        } else {\n          div++;\n        }\n      }\n    }\n    if (x < n) {\n      while (table[x] != -1) {\n        mp[table[x]]++;\n        x /= table[x];\n      }\n    }\n    if (x > 1) mp[x]++;\n    vector<pair<long long, int>> ret;\n    for (auto p : mp) ret.push_back(p);\n    return ret;\n  }\n};\n\ntemplate <int MOD = 1000000007>\nstruct Math {\n  vector<long long> fact, factinv, inv;\n  Math(int n = 100000) {\n    fact.resize(n + 1);\n    factinv.resize(n + 1);\n    inv.resize(n + 1);\n    fact[0] = fact[1] = 1;\n    factinv[0] = factinv[1] = 1;\n    inv[1] = 1;\n    for (int i = 2; i <= n; ++i) {\n      fact[i] = fact[i - 1] * i % MOD;\n      inv[i] = MOD - inv[MOD % i] * (MOD / i) % MOD;\n      factinv[i] = factinv[i - 1] * inv[i] % MOD;\n    }\n  }\n  long long C(int n, int r) {\n    if (n < r || n < 0 || r < 0) {\n      return 0;\n    } else {\n      return fact[n] * (factinv[r] * factinv[n - r] % MOD) % MOD;\n    }\n  }\n  long long P(int n, int r) {\n    if (n < r || n < 0 || r < 0) {\n      return 0;\n    } else {\n      return fact[n] * factinv[n - r] % MOD;\n    }\n  }\n  long long H(int n, int r) { return C(n + r - 1, r); }\n};\n\nstruct UnionFind {\n  vector<int> data;\n  vector<vector<int>> groups;\n  UnionFind(int n) : data(n, -1) {}\n  int root(int v) { return data[v] < 0 ? v : data[v] = root(data[v]); }\n  bool unite(int u, int v) {\n    if ((u = root(u)) == (v = root(v))) {\n      return 1;\n    } else {\n      if (-data[u] < -data[v]) swap(u, v);\n      data[u] += data[v];\n      data[v] = u;\n      return 0;\n    }\n  }\n  int size(int v) { return -data[root(v)]; }\n  void make_groups() {\n    map<int, vector<int>> mp;\n    for (int i = 0; i < data.size(); ++i) mp[root(i)].push_back(i);\n    groups.clear();\n    for (auto p : mp) groups.push_back(p.second);\n  }\n};\n\nnamespace phc {\nlong long modpow(long long a, long long n) {\n  long long res = 1;\n  while (n > 0) {\n    if (n & 1) res = res * a % MOD;\n    a = a * a % MOD;\n    n >>= 1;\n  }\n  return res;\n}\nlong long modinv(long long a) {\n  long long b = MOD, u = 1, v = 0;\n  while (b) {\n    long long t = a / b;\n    a -= t * b;\n    swap(a, b);\n    u -= t * v;\n    swap(u, v);\n  }\n  u %= MOD;\n  if (u < 0) u += MOD;\n  return u;\n}\nlong long gcd(long long a, long long b) { return b != 0 ? gcd(b, a % b) : a; }\nlong long lcm(long long a, long long b) { return a * b / gcd(a, b); }\n}  // namespace phc\n\ntemplate <int mod>\nstruct ModInt {\n  int x;\n\n  ModInt() : x(0) {}\n\n  ModInt(int64_t y) : x(y >= 0 ? y % mod : (mod - (-y) % mod) % mod) {}\n\n  ModInt &operator+=(const ModInt &p) {\n    if ((x += p.x) >= mod) x -= mod;\n    return *this;\n  }\n\n  ModInt &operator-=(const ModInt &p) {\n    if ((x += mod - p.x) >= mod) x -= mod;\n    return *this;\n  }\n\n  ModInt &operator*=(const ModInt &p) {\n    x = (int)(1LL * x * p.x % mod);\n    return *this;\n  }\n\n  ModInt &operator/=(const ModInt &p) {\n    *this *= p.inverse();\n    return *this;\n  }\n\n  ModInt operator-() const { return ModInt(-x); }\n\n  ModInt operator+(const ModInt &p) const { return ModInt(*this) += p; }\n\n  ModInt operator-(const ModInt &p) const { return ModInt(*this) -= p; }\n\n  ModInt operator*(const ModInt &p) const { return ModInt(*this) *= p; }\n\n  ModInt operator/(const ModInt &p) const { return ModInt(*this) /= p; }\n\n  bool operator==(const ModInt &p) const { return x == p.x; }\n\n  bool operator!=(const ModInt &p) const { return x != p.x; }\n\n  ModInt inverse() const {\n    int a = x, b = mod, u = 1, v = 0, t;\n    while (b > 0) {\n      t = a / b;\n      swap(a -= t * b, b);\n      swap(u -= t * v, v);\n    }\n    return ModInt(u);\n  }\n\n  ModInt pow(int64_t n) const {\n    ModInt ret(1), mul(x);\n    while (n > 0) {\n      if (n & 1) ret *= mul;\n      mul *= mul;\n      n >>= 1;\n    }\n    return ret;\n  }\n\n  friend ostream &operator<<(ostream &os, const ModInt &p) { return os << p.x; }\n\n  friend istream &operator>>(istream &is, ModInt &a) {\n    int64_t t;\n    is >> t;\n    a = ModInt<mod>(t);\n    return (is);\n  }\n\n  static int get_mod() { return mod; }\n};\n\nusing modint = ModInt<MOD>;\n\nconstexpr int dy[4] = {-1, 0, 1, 0}, dx[4] = {0, -1, 0, 1};\n\nint main() {\n  int Q;\n  io.read(Q);\n  while (Q--) {\n    ll A, B;\n    io.read(A, B);\n    if (A > B) swap(A, B);\n    ll ans = A - 1;\n    ll sq = sqrtl(A * B + 1);\n    ans += sq - (sq * sq == A * B);\n    ans += max(0LL, (A * B / sq) - A - 1 - ((A * B) % sq == 0 ? 1 : 0));\n    io.writeln(ans);\n  }\n  return 0;\n}", "language": "C++", "metadata": {"date": 1595561760, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03388.html", "problem_id": "p03388", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03388/input.txt", "sample_output_relpath": "derived/input_output/data/p03388/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03388/C++/s499977205.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s499977205", "user_id": "u656771711"}, "prompt_components": {"gold_output": "1\n12\n4\n11\n14\n57\n31\n671644785\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\n#include <set>\n#include <unordered_set>\n#include <map>\n#include <unordered_map>\n#include <cstdio>\n#include <bitset>\n#include <queue>\n#include <deque>\n#include <algorithm>\n#include <numeric>\n#include <cassert>\n#include <functional>\n#include <stack>\n#include <cmath>\n#include <string>\n\nusing namespace std;\n\n#define REP(i, N) for (int i = 0; i < (int)N; i++)\n#define FOR(i, a, b) for (int i = a; i < (int)b; i++)\n#define ALL(x) (x).begin(), (x).end()\n#define INF (1 << 30)\n#define LLINF (1LL << 62)\n#define DEBUG(...) debug(__LINE__, \":\" __VA_ARGS__)\n\nconstexpr int MOD = 1000000007;\nusing ll = long long;\nusing Pii = pair<int, int>;\nusing Pll = pair<ll, ll>;\n\ninline int popcount(ll x) { return __builtin_popcountll(x); }\ninline int div2num(ll x) { return __builtin_ctzll(x); }\ninline bool bit(ll x, int b) { return (x >> b) & 1; }\n\ntemplate <class T>\nstring to_string(T s);\ntemplate <class S, class T>\nstring to_string(pair<S, T> p);\nstring to_string(string s) { return s; }\nstring to_string(const char s[]) { return to_string(string(s)); }\n\ntemplate <class T>\nstring to_string(T v) {\n  if (v.empty()) return \"{}\";\n  string ret = \"{\";\n  for (auto x : v) ret += to_string(x) + \",\";\n  ret.back() = '}';\n  return ret;\n}\n\ntemplate <class S, class T>\nstring to_string(pair<S, T> p) {\n  return \"{\" + to_string(p.first) + \":\" + to_string(p.second) + \"}\";\n}\nvoid debug() { cerr << endl; }\n\ntemplate <class Head, class... Tail>\nvoid debug(Head head, Tail... tail) {\n  cerr << to_string(head) << \" \";\n  debug(tail...);\n}\n\nstruct IO {\n#ifdef _WIN32\n  inline char getchar_unlocked() { return getchar(); }\n  inline void putchar_unlocked(char c) { putchar(c); }\n#endif\n  std::string separator = \" \";\n  template <class T>\n  inline void read(T &x) {\n    char c;\n    do {\n      c = getchar_unlocked();\n    } while (c != '-' && (c < '0' || '9' < c));\n    bool minus = 0;\n    if (c == '-') {\n      minus = 1;\n      c = getchar_unlocked();\n    }\n    x = 0;\n    while ('0' <= c && c <= '9') {\n      x *= 10;\n      x += c - '0';\n      c = getchar_unlocked();\n    }\n    if (minus) x = -x;\n  }\n  inline void read(std::string &x) {\n    char c;\n    do {\n      c = getchar_unlocked();\n    } while (c == ' ' || c == '\\n');\n    x.clear();\n    do {\n      x += c;\n      c = getchar_unlocked();\n    } while (c != ' ' && c != '\\n' && c != EOF);\n  }\n  template <class T>\n  inline void read(std::vector<T> &v) {\n    for (auto &x : v) read(x);\n  }\n  template <class S, class T>\n  inline void read(std::pair<S, T> &p) {\n    read(p.first);\n    read(p.second);\n  }\n  template <class Head, class... Tail>\n  inline void read(Head &head, Tail &... tail) {\n    read(head);\n    read(tail...);\n  }\n  template <class T>\n  inline void write(T x) {\n    char buf[32];\n    int p = 0;\n    if (x < 0) {\n      x = -x;\n      putchar_unlocked('-');\n    }\n    if (x == 0) putchar_unlocked('0');\n    while (x > 0) {\n      buf[p++] = (x % 10) + '0';\n      x /= 10;\n    }\n    while (p) {\n      putchar_unlocked(buf[--p]);\n    }\n  }\n  inline void write(std::string x) {\n    for (char c : x) putchar_unlocked(c);\n  }\n  inline void write(const char s[]) {\n    for (int i = 0; s[i] != 0; ++i) putchar_unlocked(s[i]);\n  }\n  template <class T>\n  inline void write(std::vector<T> v) {\n    if (v.empty()) return;\n    for (auto itr = v.begin(); itr + 1 != v.end(); ++itr) {\n      write(*itr);\n      write(separator);\n    }\n    write(v.back());\n  }\n  template <class Head, class... Tail>\n  inline void write(Head head, Tail... tail) {\n    write(head);\n    write(separator);\n    write(tail...);\n  }\n  template <class Head, class... Tail>\n  inline void writeln(Head head, Tail... tail) {\n    write(head, tail...);\n    write(\"\\n\");\n  }\n  void set_separator(std::string s) { separator = s; }\n} io;\n\nstruct Prime {\n  int n;\n  vector<int> table;\n  vector<int> primes;\n  Prime(int _n = 100000) {\n    n = _n + 1;\n    table.resize(n, -1);\n    table[0] = 0;\n    table[1] = -1;\n    for (int i = 2; i * i < n; ++i) {\n      if (table[i] == -1) {\n        for (int j = i * i; j < n; j += i) {\n          table[j] = i;\n        }\n      }\n    }\n  }\n  void enumerate_primes() {\n    primes.clear();\n    for (int i = 2; i < n; ++i) {\n      if (table[i] == -1) primes.push_back(i);\n    }\n  }\n  vector<pair<long long, int>> prime_factor(long long x) {\n    map<long long, int> mp;\n    long long div = 2;\n    int p = 0;\n    while (n <= x && div * div <= x) {\n      if (x % div == 0) {\n        mp[div]++;\n        x /= div;\n      } else {\n        if (p + 1 < primes.size()) {\n          div = primes[++p];\n        } else {\n          div++;\n        }\n      }\n    }\n    if (x < n) {\n      while (table[x] != -1) {\n        mp[table[x]]++;\n        x /= table[x];\n      }\n    }\n    if (x > 1) mp[x]++;\n    vector<pair<long long, int>> ret;\n    for (auto p : mp) ret.push_back(p);\n    return ret;\n  }\n};\n\ntemplate <int MOD = 1000000007>\nstruct Math {\n  vector<long long> fact, factinv, inv;\n  Math(int n = 100000) {\n    fact.resize(n + 1);\n    factinv.resize(n + 1);\n    inv.resize(n + 1);\n    fact[0] = fact[1] = 1;\n    factinv[0] = factinv[1] = 1;\n    inv[1] = 1;\n    for (int i = 2; i <= n; ++i) {\n      fact[i] = fact[i - 1] * i % MOD;\n      inv[i] = MOD - inv[MOD % i] * (MOD / i) % MOD;\n      factinv[i] = factinv[i - 1] * inv[i] % MOD;\n    }\n  }\n  long long C(int n, int r) {\n    if (n < r || n < 0 || r < 0) {\n      return 0;\n    } else {\n      return fact[n] * (factinv[r] * factinv[n - r] % MOD) % MOD;\n    }\n  }\n  long long P(int n, int r) {\n    if (n < r || n < 0 || r < 0) {\n      return 0;\n    } else {\n      return fact[n] * factinv[n - r] % MOD;\n    }\n  }\n  long long H(int n, int r) { return C(n + r - 1, r); }\n};\n\nstruct UnionFind {\n  vector<int> data;\n  vector<vector<int>> groups;\n  UnionFind(int n) : data(n, -1) {}\n  int root(int v) { return data[v] < 0 ? v : data[v] = root(data[v]); }\n  bool unite(int u, int v) {\n    if ((u = root(u)) == (v = root(v))) {\n      return 1;\n    } else {\n      if (-data[u] < -data[v]) swap(u, v);\n      data[u] += data[v];\n      data[v] = u;\n      return 0;\n    }\n  }\n  int size(int v) { return -data[root(v)]; }\n  void make_groups() {\n    map<int, vector<int>> mp;\n    for (int i = 0; i < data.size(); ++i) mp[root(i)].push_back(i);\n    groups.clear();\n    for (auto p : mp) groups.push_back(p.second);\n  }\n};\n\nnamespace phc {\nlong long modpow(long long a, long long n) {\n  long long res = 1;\n  while (n > 0) {\n    if (n & 1) res = res * a % MOD;\n    a = a * a % MOD;\n    n >>= 1;\n  }\n  return res;\n}\nlong long modinv(long long a) {\n  long long b = MOD, u = 1, v = 0;\n  while (b) {\n    long long t = a / b;\n    a -= t * b;\n    swap(a, b);\n    u -= t * v;\n    swap(u, v);\n  }\n  u %= MOD;\n  if (u < 0) u += MOD;\n  return u;\n}\nlong long gcd(long long a, long long b) { return b != 0 ? gcd(b, a % b) : a; }\nlong long lcm(long long a, long long b) { return a * b / gcd(a, b); }\n}  // namespace phc\n\ntemplate <int mod>\nstruct ModInt {\n  int x;\n\n  ModInt() : x(0) {}\n\n  ModInt(int64_t y) : x(y >= 0 ? y % mod : (mod - (-y) % mod) % mod) {}\n\n  ModInt &operator+=(const ModInt &p) {\n    if ((x += p.x) >= mod) x -= mod;\n    return *this;\n  }\n\n  ModInt &operator-=(const ModInt &p) {\n    if ((x += mod - p.x) >= mod) x -= mod;\n    return *this;\n  }\n\n  ModInt &operator*=(const ModInt &p) {\n    x = (int)(1LL * x * p.x % mod);\n    return *this;\n  }\n\n  ModInt &operator/=(const ModInt &p) {\n    *this *= p.inverse();\n    return *this;\n  }\n\n  ModInt operator-() const { return ModInt(-x); }\n\n  ModInt operator+(const ModInt &p) const { return ModInt(*this) += p; }\n\n  ModInt operator-(const ModInt &p) const { return ModInt(*this) -= p; }\n\n  ModInt operator*(const ModInt &p) const { return ModInt(*this) *= p; }\n\n  ModInt operator/(const ModInt &p) const { return ModInt(*this) /= p; }\n\n  bool operator==(const ModInt &p) const { return x == p.x; }\n\n  bool operator!=(const ModInt &p) const { return x != p.x; }\n\n  ModInt inverse() const {\n    int a = x, b = mod, u = 1, v = 0, t;\n    while (b > 0) {\n      t = a / b;\n      swap(a -= t * b, b);\n      swap(u -= t * v, v);\n    }\n    return ModInt(u);\n  }\n\n  ModInt pow(int64_t n) const {\n    ModInt ret(1), mul(x);\n    while (n > 0) {\n      if (n & 1) ret *= mul;\n      mul *= mul;\n      n >>= 1;\n    }\n    return ret;\n  }\n\n  friend ostream &operator<<(ostream &os, const ModInt &p) { return os << p.x; }\n\n  friend istream &operator>>(istream &is, ModInt &a) {\n    int64_t t;\n    is >> t;\n    a = ModInt<mod>(t);\n    return (is);\n  }\n\n  static int get_mod() { return mod; }\n};\n\nusing modint = ModInt<MOD>;\n\nconstexpr int dy[4] = {-1, 0, 1, 0}, dx[4] = {0, -1, 0, 1};\n\nint main() {\n  int Q;\n  io.read(Q);\n  while (Q--) {\n    ll A, B;\n    io.read(A, B);\n    if (A > B) swap(A, B);\n    ll ans = A - 1;\n    ll sq = sqrtl(A * B + 1);\n    ans += sq - (sq * sq == A * B);\n    ans += max(0LL, (A * B / sq) - A - 1 - ((A * B) % sq == 0 ? 1 : 0));\n    io.writeln(ans);\n  }\n  return 0;\n}", "problem_context": "Score : 700 points\n\nProblem Statement\n\n10^{10^{10}} participants, including Takahashi, competed in two programming contests.\nIn each contest, all participants had distinct ranks from first through 10^{10^{10}}-th.\n\nThe score of a participant is the product of his/her ranks in the two contests.\n\nProcess the following Q queries:\n\nIn the i-th query, you are given two positive integers A_i and B_i. Assuming that Takahashi was ranked A_i-th in the first contest and B_i-th in the second contest, find the maximum possible number of participants whose scores are smaller than Takahashi's.\n\nConstraints\n\n1 \\leq Q \\leq 100\n\n1\\leq A_i,B_i\\leq 10^9(1\\leq i\\leq Q)\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nQ\nA_1 B_1\n:\nA_Q B_Q\n\nOutput\n\nFor each query, print the maximum possible number of participants whose scores are smaller than Takahashi's.\n\nSample Input 1\n\n8\n1 4\n10 5\n3 3\n4 11\n8 9\n22 40\n8 36\n314159265 358979323\n\nSample Output 1\n\n1\n12\n4\n11\n14\n57\n31\n671644785\n\nLet us denote a participant who was ranked x-th in the first contest and y-th in the second contest as (x,y).\n\nIn the first query, (2,1) is a possible candidate of a participant whose score is smaller than Takahashi's. There are never two or more participants whose scores are smaller than Takahashi's, so we should print 1.", "sample_input": "8\n1 4\n10 5\n3 3\n4 11\n8 9\n22 40\n8 36\n314159265 358979323\n"}, "reference_outputs": ["1\n12\n4\n11\n14\n57\n31\n671644785\n"], "source_document_id": "p03388", "source_text": "Score : 700 points\n\nProblem Statement\n\n10^{10^{10}} participants, including Takahashi, competed in two programming contests.\nIn each contest, all participants had distinct ranks from first through 10^{10^{10}}-th.\n\nThe score of a participant is the product of his/her ranks in the two contests.\n\nProcess the following Q queries:\n\nIn the i-th query, you are given two positive integers A_i and B_i. Assuming that Takahashi was ranked A_i-th in the first contest and B_i-th in the second contest, find the maximum possible number of participants whose scores are smaller than Takahashi's.\n\nConstraints\n\n1 \\leq Q \\leq 100\n\n1\\leq A_i,B_i\\leq 10^9(1\\leq i\\leq Q)\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nQ\nA_1 B_1\n:\nA_Q B_Q\n\nOutput\n\nFor each query, print the maximum possible number of participants whose scores are smaller than Takahashi's.\n\nSample Input 1\n\n8\n1 4\n10 5\n3 3\n4 11\n8 9\n22 40\n8 36\n314159265 358979323\n\nSample Output 1\n\n1\n12\n4\n11\n14\n57\n31\n671644785\n\nLet us denote a participant who was ranked x-th in the first contest and y-th in the second contest as (x,y).\n\nIn the first query, (2,1) is a possible candidate of a participant whose score is smaller than Takahashi's. There are never two or more participants whose scores are smaller than Takahashi's, so we should print 1.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 8903, "cpu_time_ms": 10, "memory_kb": 3564}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s165853074", "group_id": "codeNet:p03390", "input_text": "#include <bits/stdc++.h>\n#define mod 1000000007\n#define pb push_back\n#define ll long long\n#define mp make_pair\nusing namespace std;\nint main(){\n\tll q;\n\tcin>>q;\n\tfor(int i=0;i<q;i++){\n\t\tll a,b;\n\t\tcin>>a>>b;\n\t\tif(a==b){\n\t\t\tcout<<a+b-2<<endl;\n\t\t}\n\t\telse{\n\t\t\tif(a>b){\n\t\t\t\tll x = a;\n\t\t\t\ta = b;\n\t\t\t\tb = x;\n\t\t\t}\n\t\t\tif(b-a==1){\n\t\t\t\tcout<<a+b-2<<endl;\n\t\t\t}\n\t\t\tdouble tag = (a*b-1.0)*4.0;\n\t\t\ttag = sqrt(tag);\n\t\t\tll itag = (ll)floor(tag);\n\t\t\tcout<<itag-2<<endl;\n\t\t}\n\t}\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1538267736, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03390.html", "problem_id": "p03390", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03390/input.txt", "sample_output_relpath": "derived/input_output/data/p03390/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03390/C++/s165853074.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s165853074", "user_id": "u335590796"}, "prompt_components": {"gold_output": "1\n12\n4\n11\n14\n57\n31\n671644785\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define mod 1000000007\n#define pb push_back\n#define ll long long\n#define mp make_pair\nusing namespace std;\nint main(){\n\tll q;\n\tcin>>q;\n\tfor(int i=0;i<q;i++){\n\t\tll a,b;\n\t\tcin>>a>>b;\n\t\tif(a==b){\n\t\t\tcout<<a+b-2<<endl;\n\t\t}\n\t\telse{\n\t\t\tif(a>b){\n\t\t\t\tll x = a;\n\t\t\t\ta = b;\n\t\t\t\tb = x;\n\t\t\t}\n\t\t\tif(b-a==1){\n\t\t\t\tcout<<a+b-2<<endl;\n\t\t\t}\n\t\t\tdouble tag = (a*b-1.0)*4.0;\n\t\t\ttag = sqrt(tag);\n\t\t\tll itag = (ll)floor(tag);\n\t\t\tcout<<itag-2<<endl;\n\t\t}\n\t}\n\treturn 0;\n}", "problem_context": "Score : 700 points\n\nProblem Statement\n\n10^{10^{10}} participants, including Takahashi, competed in two programming contests.\nIn each contest, all participants had distinct ranks from first through 10^{10^{10}}-th.\n\nThe score of a participant is the product of his/her ranks in the two contests.\n\nProcess the following Q queries:\n\nIn the i-th query, you are given two positive integers A_i and B_i. Assuming that Takahashi was ranked A_i-th in the first contest and B_i-th in the second contest, find the maximum possible number of participants whose scores are smaller than Takahashi's.\n\nConstraints\n\n1 \\leq Q \\leq 100\n\n1\\leq A_i,B_i\\leq 10^9(1\\leq i\\leq Q)\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nQ\nA_1 B_1\n:\nA_Q B_Q\n\nOutput\n\nFor each query, print the maximum possible number of participants whose scores are smaller than Takahashi's.\n\nSample Input 1\n\n8\n1 4\n10 5\n3 3\n4 11\n8 9\n22 40\n8 36\n314159265 358979323\n\nSample Output 1\n\n1\n12\n4\n11\n14\n57\n31\n671644785\n\nLet us denote a participant who was ranked x-th in the first contest and y-th in the second contest as (x,y).\n\nIn the first query, (2,1) is a possible candidate of a participant whose score is smaller than Takahashi's. There are never two or more participants whose scores are smaller than Takahashi's, so we should print 1.", "sample_input": "8\n1 4\n10 5\n3 3\n4 11\n8 9\n22 40\n8 36\n314159265 358979323\n"}, "reference_outputs": ["1\n12\n4\n11\n14\n57\n31\n671644785\n"], "source_document_id": "p03390", "source_text": "Score : 700 points\n\nProblem Statement\n\n10^{10^{10}} participants, including Takahashi, competed in two programming contests.\nIn each contest, all participants had distinct ranks from first through 10^{10^{10}}-th.\n\nThe score of a participant is the product of his/her ranks in the two contests.\n\nProcess the following Q queries:\n\nIn the i-th query, you are given two positive integers A_i and B_i. Assuming that Takahashi was ranked A_i-th in the first contest and B_i-th in the second contest, find the maximum possible number of participants whose scores are smaller than Takahashi's.\n\nConstraints\n\n1 \\leq Q \\leq 100\n\n1\\leq A_i,B_i\\leq 10^9(1\\leq i\\leq Q)\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nQ\nA_1 B_1\n:\nA_Q B_Q\n\nOutput\n\nFor each query, print the maximum possible number of participants whose scores are smaller than Takahashi's.\n\nSample Input 1\n\n8\n1 4\n10 5\n3 3\n4 11\n8 9\n22 40\n8 36\n314159265 358979323\n\nSample Output 1\n\n1\n12\n4\n11\n14\n57\n31\n671644785\n\nLet us denote a participant who was ranked x-th in the first contest and y-th in the second contest as (x,y).\n\nIn the first query, (2,1) is a possible candidate of a participant whose score is smaller than Takahashi's. There are never two or more participants whose scores are smaller than Takahashi's, so we should print 1.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 470, "cpu_time_ms": 2, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s048959599", "group_id": "codeNet:p03390", "input_text": "#include \"bits/stdc++.h\"\nusing namespace std;\n#define fi first\n#define se second\n#define ll long long\n#define dbg(v) cerr<<#v<<\" = \"<<v<<'\\n'\n#define vi vector<int>\n#define vl vector <ll>\n#define pii pair<int,int>\n#define mp make_pair\n#define db long double\n#define pb push_back\n#define all(s) s.begin(),s.end()\ntemplate < class T > T smin(T &a,T b) {if (a > b) a = b;return a;}\ntemplate < class T > T smax(T &a,T b) {if (a < b) a = b;return a;}\nint main(void)\n{\n    int q;\n    cin>>q;\n    while (q --) {\n    \tll a,b;\n    \tcin>>a>>b;\n    \tll n = a * b;\n    \tll sq = sqrt(n - 1);\n    \twhile (sq * sq <= n - 1) ++sq;\n    \tll ans = sq + (n - 1) / (sq + 1);\n    \t--ans;\n    \tcout << ans << '\\n';\n    }\n    return 0;\n}", "language": "C++", "metadata": {"date": 1523155302, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03390.html", "problem_id": "p03390", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03390/input.txt", "sample_output_relpath": "derived/input_output/data/p03390/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03390/C++/s048959599.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s048959599", "user_id": "u468273690"}, "prompt_components": {"gold_output": "1\n12\n4\n11\n14\n57\n31\n671644785\n", "input_to_evaluate": "#include \"bits/stdc++.h\"\nusing namespace std;\n#define fi first\n#define se second\n#define ll long long\n#define dbg(v) cerr<<#v<<\" = \"<<v<<'\\n'\n#define vi vector<int>\n#define vl vector <ll>\n#define pii pair<int,int>\n#define mp make_pair\n#define db long double\n#define pb push_back\n#define all(s) s.begin(),s.end()\ntemplate < class T > T smin(T &a,T b) {if (a > b) a = b;return a;}\ntemplate < class T > T smax(T &a,T b) {if (a < b) a = b;return a;}\nint main(void)\n{\n    int q;\n    cin>>q;\n    while (q --) {\n    \tll a,b;\n    \tcin>>a>>b;\n    \tll n = a * b;\n    \tll sq = sqrt(n - 1);\n    \twhile (sq * sq <= n - 1) ++sq;\n    \tll ans = sq + (n - 1) / (sq + 1);\n    \t--ans;\n    \tcout << ans << '\\n';\n    }\n    return 0;\n}", "problem_context": "Score : 700 points\n\nProblem Statement\n\n10^{10^{10}} participants, including Takahashi, competed in two programming contests.\nIn each contest, all participants had distinct ranks from first through 10^{10^{10}}-th.\n\nThe score of a participant is the product of his/her ranks in the two contests.\n\nProcess the following Q queries:\n\nIn the i-th query, you are given two positive integers A_i and B_i. Assuming that Takahashi was ranked A_i-th in the first contest and B_i-th in the second contest, find the maximum possible number of participants whose scores are smaller than Takahashi's.\n\nConstraints\n\n1 \\leq Q \\leq 100\n\n1\\leq A_i,B_i\\leq 10^9(1\\leq i\\leq Q)\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nQ\nA_1 B_1\n:\nA_Q B_Q\n\nOutput\n\nFor each query, print the maximum possible number of participants whose scores are smaller than Takahashi's.\n\nSample Input 1\n\n8\n1 4\n10 5\n3 3\n4 11\n8 9\n22 40\n8 36\n314159265 358979323\n\nSample Output 1\n\n1\n12\n4\n11\n14\n57\n31\n671644785\n\nLet us denote a participant who was ranked x-th in the first contest and y-th in the second contest as (x,y).\n\nIn the first query, (2,1) is a possible candidate of a participant whose score is smaller than Takahashi's. There are never two or more participants whose scores are smaller than Takahashi's, so we should print 1.", "sample_input": "8\n1 4\n10 5\n3 3\n4 11\n8 9\n22 40\n8 36\n314159265 358979323\n"}, "reference_outputs": ["1\n12\n4\n11\n14\n57\n31\n671644785\n"], "source_document_id": "p03390", "source_text": "Score : 700 points\n\nProblem Statement\n\n10^{10^{10}} participants, including Takahashi, competed in two programming contests.\nIn each contest, all participants had distinct ranks from first through 10^{10^{10}}-th.\n\nThe score of a participant is the product of his/her ranks in the two contests.\n\nProcess the following Q queries:\n\nIn the i-th query, you are given two positive integers A_i and B_i. Assuming that Takahashi was ranked A_i-th in the first contest and B_i-th in the second contest, find the maximum possible number of participants whose scores are smaller than Takahashi's.\n\nConstraints\n\n1 \\leq Q \\leq 100\n\n1\\leq A_i,B_i\\leq 10^9(1\\leq i\\leq Q)\n\nAll values in input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nQ\nA_1 B_1\n:\nA_Q B_Q\n\nOutput\n\nFor each query, print the maximum possible number of participants whose scores are smaller than Takahashi's.\n\nSample Input 1\n\n8\n1 4\n10 5\n3 3\n4 11\n8 9\n22 40\n8 36\n314159265 358979323\n\nSample Output 1\n\n1\n12\n4\n11\n14\n57\n31\n671644785\n\nLet us denote a participant who was ranked x-th in the first contest and y-th in the second contest as (x,y).\n\nIn the first query, (2,1) is a possible candidate of a participant whose score is smaller than Takahashi's. There are never two or more participants whose scores are smaller than Takahashi's, so we should print 1.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 713, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s773932601", "group_id": "codeNet:p03395", "input_text": "#include <iostream>\n#include<bits/stdc++.h>\n\nusing namespace std;\n\ntypedef long long ll;\nll graph[55][55][55];\n\nint main()\n{\n    ll N;\n    cin>>N;\n    ll a[N],b[N];\n    vector<ll> c[N];\n    for(ll i=0; i<N; i++){\n        cin>>a[i];\n        c[i].push_back(a[i]);\n    }\n    for(ll i=0; i<N; i++){\n        cin>>b[i];\n    }\n\n    for(ll i=0; i<55; i++){\n        for(ll j=0; j<55; j++){\n            graph[i][i][j] = 1;\n        }\n    }\n\n\n    for(ll k=1; k<55; k++){\n        for(ll i=0; i<55; i++){\n            for(ll j=0; j<55; j++){\n                if(graph[i%k][j][k-1]==1 || graph[i][j][k-1]==1)\n                    graph[i][j][k] = 1;\n            }\n        }\n    }\n\n\n    for(ll i=0; i<N; i++){\n        if(graph[a[i]][b[i]][50]==0){\n            cout<<-1<<endl;\n            return 0;\n        }\n    }\n\n    ll ans = 0;\n    for(ll k=50; k>0; k--){\n        bool check = true;\n        for(ll i=0; i<N; i++){\n            bool test = false;\n            for(ll j=0; j<c[i].size(); j++){\n                if(graph[c[i][j]][b[i]][k-1]==1){\n                    test = true;\n                }\n            }\n            if(!test)\n                check = false;\n\n        }\n        if(!check){\n            ans+= (1ll<<k);\n            for(ll i=0; i<N; i++){\n                vector<ll> carry;\n                ll poss[55];\n                for(ll j=0; j<55; j++)\n                    poss[j] = 0;\n                for(ll j=0; j<c[i].size(); j++){\n                    poss[c[i][j]] = 1;\n                    poss[c[i][j]%k] = 1;\n                }\n                for(ll j=0; j<55; j++){\n                    if(poss[j]==1)\n                        carry.push_back(j);\n                }\n                c[i] = carry;\n            }\n\n        }\n\n    }\n    cout<<ans<<endl;\n\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1524568119, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03395.html", "problem_id": "p03395", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03395/input.txt", "sample_output_relpath": "derived/input_output/data/p03395/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03395/C++/s773932601.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s773932601", "user_id": "u847743994"}, "prompt_components": {"gold_output": "160\n", "input_to_evaluate": "#include <iostream>\n#include<bits/stdc++.h>\n\nusing namespace std;\n\ntypedef long long ll;\nll graph[55][55][55];\n\nint main()\n{\n    ll N;\n    cin>>N;\n    ll a[N],b[N];\n    vector<ll> c[N];\n    for(ll i=0; i<N; i++){\n        cin>>a[i];\n        c[i].push_back(a[i]);\n    }\n    for(ll i=0; i<N; i++){\n        cin>>b[i];\n    }\n\n    for(ll i=0; i<55; i++){\n        for(ll j=0; j<55; j++){\n            graph[i][i][j] = 1;\n        }\n    }\n\n\n    for(ll k=1; k<55; k++){\n        for(ll i=0; i<55; i++){\n            for(ll j=0; j<55; j++){\n                if(graph[i%k][j][k-1]==1 || graph[i][j][k-1]==1)\n                    graph[i][j][k] = 1;\n            }\n        }\n    }\n\n\n    for(ll i=0; i<N; i++){\n        if(graph[a[i]][b[i]][50]==0){\n            cout<<-1<<endl;\n            return 0;\n        }\n    }\n\n    ll ans = 0;\n    for(ll k=50; k>0; k--){\n        bool check = true;\n        for(ll i=0; i<N; i++){\n            bool test = false;\n            for(ll j=0; j<c[i].size(); j++){\n                if(graph[c[i][j]][b[i]][k-1]==1){\n                    test = true;\n                }\n            }\n            if(!test)\n                check = false;\n\n        }\n        if(!check){\n            ans+= (1ll<<k);\n            for(ll i=0; i<N; i++){\n                vector<ll> carry;\n                ll poss[55];\n                for(ll j=0; j<55; j++)\n                    poss[j] = 0;\n                for(ll j=0; j<c[i].size(); j++){\n                    poss[c[i][j]] = 1;\n                    poss[c[i][j]%k] = 1;\n                }\n                for(ll j=0; j<55; j++){\n                    if(poss[j]==1)\n                        carry.push_back(j);\n                }\n                c[i] = carry;\n            }\n\n        }\n\n    }\n    cout<<ans<<endl;\n\n    return 0;\n}\n", "problem_context": "Score : 700 points\n\nProblem Statement\n\nAoki is playing with a sequence of numbers a_{1}, a_{2}, ..., a_{N}. Every second, he performs the following operation :\n\nChoose a positive integer k. For each element of the sequence v, Aoki may choose to replace v with its remainder when divided by k, or do nothing with v. The cost of this operation is 2^{k} (regardless of how many elements he changes).\n\nAoki wants to turn the sequence into b_{1}, b_{2}, ..., b_{N} (the order of the elements is important). Determine if it is possible for Aoki to perform this task and if yes, find the minimum cost required.\n\nConstraints\n\n1 \\leq N \\leq 50\n\n0 \\leq a_{i}, b_{i} \\leq 50\n\nAll values in the input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_{1} a_{2} ... a_{N}\nb_{1} b_{2} ... b_{N}\n\nOutput\n\nPrint the minimum cost required to turn the original sequence into b_{1}, b_{2}, ..., b_{N}. If the task is impossible, output -1 instead.\n\nSample Input 1\n\n3\n19 10 14\n0 3 4\n\nSample Output 1\n\n160\n\nHere's a possible sequence of operations :\n\nChoose k = 7. Replace 19 with 5, 10 with 3 and do nothing to 14. The sequence is now 5, 3, 14.\n\nChoose k = 5. Replace 5 with 0, do nothing to 3 and replace 14 with 4. The sequence is now 0, 3, 4.\n\nThe total cost is 2^{7} + 2^{5} = 160.\n\nSample Input 2\n\n3\n19 15 14\n0 0 0\n\nSample Output 2\n\n2\n\nAoki can just choose k = 1 and turn everything into 0. The cost is 2^{1} = 2.\n\nSample Input 3\n\n2\n8 13\n5 13\n\nSample Output 3\n\n-1\n\nThe task is impossible because we can never turn 8 into 5 using the given operation.\n\nSample Input 4\n\n4\n2 0 1 8\n2 0 1 8\n\nSample Output 4\n\n0\n\nAoki doesn't need to do anything here. The cost is 0.\n\nSample Input 5\n\n1\n50\n13\n\nSample Output 5\n\n137438953472\n\nBeware of overflow issues.", "sample_input": "3\n19 10 14\n0 3 4\n"}, "reference_outputs": ["160\n"], "source_document_id": "p03395", "source_text": "Score : 700 points\n\nProblem Statement\n\nAoki is playing with a sequence of numbers a_{1}, a_{2}, ..., a_{N}. Every second, he performs the following operation :\n\nChoose a positive integer k. For each element of the sequence v, Aoki may choose to replace v with its remainder when divided by k, or do nothing with v. The cost of this operation is 2^{k} (regardless of how many elements he changes).\n\nAoki wants to turn the sequence into b_{1}, b_{2}, ..., b_{N} (the order of the elements is important). Determine if it is possible for Aoki to perform this task and if yes, find the minimum cost required.\n\nConstraints\n\n1 \\leq N \\leq 50\n\n0 \\leq a_{i}, b_{i} \\leq 50\n\nAll values in the input are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_{1} a_{2} ... a_{N}\nb_{1} b_{2} ... b_{N}\n\nOutput\n\nPrint the minimum cost required to turn the original sequence into b_{1}, b_{2}, ..., b_{N}. If the task is impossible, output -1 instead.\n\nSample Input 1\n\n3\n19 10 14\n0 3 4\n\nSample Output 1\n\n160\n\nHere's a possible sequence of operations :\n\nChoose k = 7. Replace 19 with 5, 10 with 3 and do nothing to 14. The sequence is now 5, 3, 14.\n\nChoose k = 5. Replace 5 with 0, do nothing to 3 and replace 14 with 4. The sequence is now 0, 3, 4.\n\nThe total cost is 2^{7} + 2^{5} = 160.\n\nSample Input 2\n\n3\n19 15 14\n0 0 0\n\nSample Output 2\n\n2\n\nAoki can just choose k = 1 and turn everything into 0. The cost is 2^{1} = 2.\n\nSample Input 3\n\n2\n8 13\n5 13\n\nSample Output 3\n\n-1\n\nThe task is impossible because we can never turn 8 into 5 using the given operation.\n\nSample Input 4\n\n4\n2 0 1 8\n2 0 1 8\n\nSample Output 4\n\n0\n\nAoki doesn't need to do anything here. The cost is 0.\n\nSample Input 5\n\n1\n50\n13\n\nSample Output 5\n\n137438953472\n\nBeware of overflow issues.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1755, "cpu_time_ms": 3, "memory_kb": 1024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s982799411", "group_id": "codeNet:p03399", "input_text": "#include<iostream>\nusing namespace std;\nint main(){\n\tint a,b,c,d;\n\tcin>>a>>b>>c>>d;\n\tif(a>b&&c>d){\n\t\tcout<<b+d<<endl;\n\t}\n\telse if(a<=b&&c>=d){\n\t\tcout<<a+d<<endl;\n\t}\n\telse if(a>=b&&c<=d){\n\t\tcout<<b+c<<endl;\n\t}\n\telse{\n\t\tcout<<a+c<<endl;\n\t}\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1537548471, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03399.html", "problem_id": "p03399", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03399/input.txt", "sample_output_relpath": "derived/input_output/data/p03399/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03399/C++/s982799411.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s982799411", "user_id": "u942393279"}, "prompt_components": {"gold_output": "520\n", "input_to_evaluate": "#include<iostream>\nusing namespace std;\nint main(){\n\tint a,b,c,d;\n\tcin>>a>>b>>c>>d;\n\tif(a>b&&c>d){\n\t\tcout<<b+d<<endl;\n\t}\n\telse if(a<=b&&c>=d){\n\t\tcout<<a+d<<endl;\n\t}\n\telse if(a>=b&&c<=d){\n\t\tcout<<b+c<<endl;\n\t}\n\telse{\n\t\tcout<<a+c<<endl;\n\t}\n\treturn 0;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nYou planned a trip using trains and buses.\nThe train fare will be A yen (the currency of Japan) if you buy ordinary tickets along the way, and B yen if you buy an unlimited ticket.\nSimilarly, the bus fare will be C yen if you buy ordinary tickets along the way, and D yen if you buy an unlimited ticket.\n\nFind the minimum total fare when the optimal choices are made for trains and buses.\n\nConstraints\n\n1 \\leq A \\leq 1 000\n\n1 \\leq B \\leq 1 000\n\n1 \\leq C \\leq 1 000\n\n1 \\leq D \\leq 1 000\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA\nB\nC\nD\n\nOutput\n\nPrint the minimum total fare.\n\nSample Input 1\n\n600\n300\n220\n420\n\nSample Output 1\n\n520\n\nThe train fare will be 600 yen if you buy ordinary tickets, and 300 yen if you buy an unlimited ticket.\nThus, the optimal choice for trains is to buy an unlimited ticket for 300 yen.\nOn the other hand, the optimal choice for buses is to buy ordinary tickets for 220 yen.\n\nTherefore, the minimum total fare is 300 + 220 = 520 yen.\n\nSample Input 2\n\n555\n555\n400\n200\n\nSample Output 2\n\n755\n\nSample Input 3\n\n549\n817\n715\n603\n\nSample Output 3\n\n1152", "sample_input": "600\n300\n220\n420\n"}, "reference_outputs": ["520\n"], "source_document_id": "p03399", "source_text": "Score : 100 points\n\nProblem Statement\n\nYou planned a trip using trains and buses.\nThe train fare will be A yen (the currency of Japan) if you buy ordinary tickets along the way, and B yen if you buy an unlimited ticket.\nSimilarly, the bus fare will be C yen if you buy ordinary tickets along the way, and D yen if you buy an unlimited ticket.\n\nFind the minimum total fare when the optimal choices are made for trains and buses.\n\nConstraints\n\n1 \\leq A \\leq 1 000\n\n1 \\leq B \\leq 1 000\n\n1 \\leq C \\leq 1 000\n\n1 \\leq D \\leq 1 000\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA\nB\nC\nD\n\nOutput\n\nPrint the minimum total fare.\n\nSample Input 1\n\n600\n300\n220\n420\n\nSample Output 1\n\n520\n\nThe train fare will be 600 yen if you buy ordinary tickets, and 300 yen if you buy an unlimited ticket.\nThus, the optimal choice for trains is to buy an unlimited ticket for 300 yen.\nOn the other hand, the optimal choice for buses is to buy ordinary tickets for 220 yen.\n\nTherefore, the minimum total fare is 300 + 220 = 520 yen.\n\nSample Input 2\n\n555\n555\n400\n200\n\nSample Output 2\n\n755\n\nSample Input 3\n\n549\n817\n715\n603\n\nSample Output 3\n\n1152", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 251, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s200877224", "group_id": "codeNet:p03401", "input_text": "#include<stdio.h>\n#include<iostream>\n#include<algorithm>\n#include<string>\n#include<string.h>\n#include<math.h>\n#include<stdlib.h>\n#include<vector>\n#include<queue>\n#include<map>\n#define rep(index,num) for(int index=0;index<num;index++)\n#define rep1(index,num) for(int index=1;index<=num;index++)\n#define scan(argument) cin>>argument\n#define prin(argument) cout<<argument<<endl\n#define kaigyo cout<<endl\n#define eps 1e-15\ntypedef long long ll;\nusing namespace std;\ntypedef pair<int,int> pint;\ntypedef vector<int> vint;\nint INF=2e+9+1;\nint main(){\n\tint N;\n\tint A[100002]={0};\n\tint kyorisum[100002][2]={0};\n\tscan(N);\n\trep1(i,N){\n\t\tscan(A[i]);\n\t}\n\tA[N+1]=0;\n\trep1(i,N+1){\n\t\tkyorisum[i][0]=kyorisum[i-1][0]+abs(A[i]-A[i-1]);\n\t\tkyorisum[i][1]=(A[i]-A[i-1]>0)-(A[i]-A[i-1]<0);\n\t}\n\trep1(i,N){\n\t\tint kane=kyorisum[N+1][0]-min(abs(A[i+1]-A[i]),abs(A[i]-A[i-1]))*2*(kyorisum[i+1][1]*kyorisum[i][1]<0 ? 1:0);\n\t\tprin(kane);\n\t}\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1534980676, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03401.html", "problem_id": "p03401", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03401/input.txt", "sample_output_relpath": "derived/input_output/data/p03401/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03401/C++/s200877224.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s200877224", "user_id": "u222030240"}, "prompt_components": {"gold_output": "12\n8\n10\n", "input_to_evaluate": "#include<stdio.h>\n#include<iostream>\n#include<algorithm>\n#include<string>\n#include<string.h>\n#include<math.h>\n#include<stdlib.h>\n#include<vector>\n#include<queue>\n#include<map>\n#define rep(index,num) for(int index=0;index<num;index++)\n#define rep1(index,num) for(int index=1;index<=num;index++)\n#define scan(argument) cin>>argument\n#define prin(argument) cout<<argument<<endl\n#define kaigyo cout<<endl\n#define eps 1e-15\ntypedef long long ll;\nusing namespace std;\ntypedef pair<int,int> pint;\ntypedef vector<int> vint;\nint INF=2e+9+1;\nint main(){\n\tint N;\n\tint A[100002]={0};\n\tint kyorisum[100002][2]={0};\n\tscan(N);\n\trep1(i,N){\n\t\tscan(A[i]);\n\t}\n\tA[N+1]=0;\n\trep1(i,N+1){\n\t\tkyorisum[i][0]=kyorisum[i-1][0]+abs(A[i]-A[i-1]);\n\t\tkyorisum[i][1]=(A[i]-A[i-1]>0)-(A[i]-A[i-1]<0);\n\t}\n\trep1(i,N){\n\t\tint kane=kyorisum[N+1][0]-min(abs(A[i+1]-A[i]),abs(A[i]-A[i-1]))*2*(kyorisum[i+1][1]*kyorisum[i][1]<0 ? 1:0);\n\t\tprin(kane);\n\t}\n\treturn 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N sightseeing spots on the x-axis, numbered 1, 2, ..., N.\nSpot i is at the point with coordinate A_i.\nIt costs |a - b| yen (the currency of Japan) to travel from a point with coordinate a to another point with coordinate b along the axis.\n\nYou planned a trip along the axis.\nIn this plan, you first depart from the point with coordinate 0, then visit the N spots in the order they are numbered, and finally return to the point with coordinate 0.\n\nHowever, something came up just before the trip, and you no longer have enough time to visit all the N spots, so you decided to choose some i and cancel the visit to Spot i.\nYou will visit the remaining spots as planned in the order they are numbered.\nYou will also depart from and return to the point with coordinate 0 at the beginning and the end, as planned.\n\nFor each i = 1, 2, ..., N, find the total cost of travel during the trip when the visit to Spot i is canceled.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n-5000 \\leq A_i \\leq 5000 (1 \\leq i \\leq N)\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint N lines.\nIn the i-th line, print the total cost of travel during the trip when the visit to Spot i is canceled.\n\nSample Input 1\n\n3\n3 5 -1\n\nSample Output 1\n\n12\n8\n10\n\nSpot 1, 2 and 3 are at the points with coordinates 3, 5 and -1, respectively.\nFor each i, the course of the trip and the total cost of travel when the visit to Spot i is canceled, are as follows:\n\nFor i = 1, the course of the trip is 0 \\rightarrow 5 \\rightarrow -1 \\rightarrow 0 and the total cost of travel is 5 + 6 + 1 = 12 yen.\n\nFor i = 2, the course of the trip is 0 \\rightarrow 3 \\rightarrow -1 \\rightarrow 0 and the total cost of travel is 3 + 4 + 1 = 8 yen.\n\nFor i = 3, the course of the trip is 0 \\rightarrow 3 \\rightarrow 5 \\rightarrow 0 and the total cost of travel is 3 + 2 + 5 = 10 yen.\n\nSample Input 2\n\n5\n1 1 1 2 0\n\nSample Output 2\n\n4\n4\n4\n2\n4\n\nSample Input 3\n\n6\n-679 -2409 -3258 3095 -3291 -4462\n\nSample Output 3\n\n21630\n21630\n19932\n8924\n21630\n19288", "sample_input": "3\n3 5 -1\n"}, "reference_outputs": ["12\n8\n10\n"], "source_document_id": "p03401", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N sightseeing spots on the x-axis, numbered 1, 2, ..., N.\nSpot i is at the point with coordinate A_i.\nIt costs |a - b| yen (the currency of Japan) to travel from a point with coordinate a to another point with coordinate b along the axis.\n\nYou planned a trip along the axis.\nIn this plan, you first depart from the point with coordinate 0, then visit the N spots in the order they are numbered, and finally return to the point with coordinate 0.\n\nHowever, something came up just before the trip, and you no longer have enough time to visit all the N spots, so you decided to choose some i and cancel the visit to Spot i.\nYou will visit the remaining spots as planned in the order they are numbered.\nYou will also depart from and return to the point with coordinate 0 at the beginning and the end, as planned.\n\nFor each i = 1, 2, ..., N, find the total cost of travel during the trip when the visit to Spot i is canceled.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n-5000 \\leq A_i \\leq 5000 (1 \\leq i \\leq N)\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint N lines.\nIn the i-th line, print the total cost of travel during the trip when the visit to Spot i is canceled.\n\nSample Input 1\n\n3\n3 5 -1\n\nSample Output 1\n\n12\n8\n10\n\nSpot 1, 2 and 3 are at the points with coordinates 3, 5 and -1, respectively.\nFor each i, the course of the trip and the total cost of travel when the visit to Spot i is canceled, are as follows:\n\nFor i = 1, the course of the trip is 0 \\rightarrow 5 \\rightarrow -1 \\rightarrow 0 and the total cost of travel is 5 + 6 + 1 = 12 yen.\n\nFor i = 2, the course of the trip is 0 \\rightarrow 3 \\rightarrow -1 \\rightarrow 0 and the total cost of travel is 3 + 4 + 1 = 8 yen.\n\nFor i = 3, the course of the trip is 0 \\rightarrow 3 \\rightarrow 5 \\rightarrow 0 and the total cost of travel is 3 + 2 + 5 = 10 yen.\n\nSample Input 2\n\n5\n1 1 1 2 0\n\nSample Output 2\n\n4\n4\n4\n2\n4\n\nSample Input 3\n\n6\n-679 -2409 -3258 3095 -3291 -4462\n\nSample Output 3\n\n21630\n21630\n19932\n8924\n21630\n19288", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 925, "cpu_time_ms": 192, "memory_kb": 2432}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s194338566", "group_id": "codeNet:p03401", "input_text": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#define LL long long\n#define PP std::pair<int,int>\nint N;\nLL A[100010];\nLL res;\nint main() {\n\tstd::cin >> N;\n\tfor (int i = 1; i <= N; i++) {\n\t\tstd::cin >> A[i];\n\t\tres += std::abs(A[i] - A[i - 1]);\n\t}\n\tres += std::abs(A[N]);\n\tfor (int i = 1; i <= N; i++) {\n\t\tLL tmp = res;\n\t\ttmp -= std::abs(A[i] - A[i - 1]) + std::abs(A[i + 1] - A[i]);\n\t\ttmp += std::abs(A[i + 1] - A[i - 1]);\n\t\tstd::cout << tmp << std::endl;\n\t}\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1522026651, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03401.html", "problem_id": "p03401", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03401/input.txt", "sample_output_relpath": "derived/input_output/data/p03401/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03401/C++/s194338566.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s194338566", "user_id": "u554116180"}, "prompt_components": {"gold_output": "12\n8\n10\n", "input_to_evaluate": "#include<iostream>\n#include<algorithm>\n#include<vector>\n#define LL long long\n#define PP std::pair<int,int>\nint N;\nLL A[100010];\nLL res;\nint main() {\n\tstd::cin >> N;\n\tfor (int i = 1; i <= N; i++) {\n\t\tstd::cin >> A[i];\n\t\tres += std::abs(A[i] - A[i - 1]);\n\t}\n\tres += std::abs(A[N]);\n\tfor (int i = 1; i <= N; i++) {\n\t\tLL tmp = res;\n\t\ttmp -= std::abs(A[i] - A[i - 1]) + std::abs(A[i + 1] - A[i]);\n\t\ttmp += std::abs(A[i + 1] - A[i - 1]);\n\t\tstd::cout << tmp << std::endl;\n\t}\n\treturn 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N sightseeing spots on the x-axis, numbered 1, 2, ..., N.\nSpot i is at the point with coordinate A_i.\nIt costs |a - b| yen (the currency of Japan) to travel from a point with coordinate a to another point with coordinate b along the axis.\n\nYou planned a trip along the axis.\nIn this plan, you first depart from the point with coordinate 0, then visit the N spots in the order they are numbered, and finally return to the point with coordinate 0.\n\nHowever, something came up just before the trip, and you no longer have enough time to visit all the N spots, so you decided to choose some i and cancel the visit to Spot i.\nYou will visit the remaining spots as planned in the order they are numbered.\nYou will also depart from and return to the point with coordinate 0 at the beginning and the end, as planned.\n\nFor each i = 1, 2, ..., N, find the total cost of travel during the trip when the visit to Spot i is canceled.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n-5000 \\leq A_i \\leq 5000 (1 \\leq i \\leq N)\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint N lines.\nIn the i-th line, print the total cost of travel during the trip when the visit to Spot i is canceled.\n\nSample Input 1\n\n3\n3 5 -1\n\nSample Output 1\n\n12\n8\n10\n\nSpot 1, 2 and 3 are at the points with coordinates 3, 5 and -1, respectively.\nFor each i, the course of the trip and the total cost of travel when the visit to Spot i is canceled, are as follows:\n\nFor i = 1, the course of the trip is 0 \\rightarrow 5 \\rightarrow -1 \\rightarrow 0 and the total cost of travel is 5 + 6 + 1 = 12 yen.\n\nFor i = 2, the course of the trip is 0 \\rightarrow 3 \\rightarrow -1 \\rightarrow 0 and the total cost of travel is 3 + 4 + 1 = 8 yen.\n\nFor i = 3, the course of the trip is 0 \\rightarrow 3 \\rightarrow 5 \\rightarrow 0 and the total cost of travel is 3 + 2 + 5 = 10 yen.\n\nSample Input 2\n\n5\n1 1 1 2 0\n\nSample Output 2\n\n4\n4\n4\n2\n4\n\nSample Input 3\n\n6\n-679 -2409 -3258 3095 -3291 -4462\n\nSample Output 3\n\n21630\n21630\n19932\n8924\n21630\n19288", "sample_input": "3\n3 5 -1\n"}, "reference_outputs": ["12\n8\n10\n"], "source_document_id": "p03401", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N sightseeing spots on the x-axis, numbered 1, 2, ..., N.\nSpot i is at the point with coordinate A_i.\nIt costs |a - b| yen (the currency of Japan) to travel from a point with coordinate a to another point with coordinate b along the axis.\n\nYou planned a trip along the axis.\nIn this plan, you first depart from the point with coordinate 0, then visit the N spots in the order they are numbered, and finally return to the point with coordinate 0.\n\nHowever, something came up just before the trip, and you no longer have enough time to visit all the N spots, so you decided to choose some i and cancel the visit to Spot i.\nYou will visit the remaining spots as planned in the order they are numbered.\nYou will also depart from and return to the point with coordinate 0 at the beginning and the end, as planned.\n\nFor each i = 1, 2, ..., N, find the total cost of travel during the trip when the visit to Spot i is canceled.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n-5000 \\leq A_i \\leq 5000 (1 \\leq i \\leq N)\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint N lines.\nIn the i-th line, print the total cost of travel during the trip when the visit to Spot i is canceled.\n\nSample Input 1\n\n3\n3 5 -1\n\nSample Output 1\n\n12\n8\n10\n\nSpot 1, 2 and 3 are at the points with coordinates 3, 5 and -1, respectively.\nFor each i, the course of the trip and the total cost of travel when the visit to Spot i is canceled, are as follows:\n\nFor i = 1, the course of the trip is 0 \\rightarrow 5 \\rightarrow -1 \\rightarrow 0 and the total cost of travel is 5 + 6 + 1 = 12 yen.\n\nFor i = 2, the course of the trip is 0 \\rightarrow 3 \\rightarrow -1 \\rightarrow 0 and the total cost of travel is 3 + 4 + 1 = 8 yen.\n\nFor i = 3, the course of the trip is 0 \\rightarrow 3 \\rightarrow 5 \\rightarrow 0 and the total cost of travel is 3 + 2 + 5 = 10 yen.\n\nSample Input 2\n\n5\n1 1 1 2 0\n\nSample Output 2\n\n4\n4\n4\n2\n4\n\nSample Input 3\n\n6\n-679 -2409 -3258 3095 -3291 -4462\n\nSample Output 3\n\n21630\n21630\n19932\n8924\n21630\n19288", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 480, "cpu_time_ms": 180, "memory_kb": 2048}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s781616391", "group_id": "codeNet:p03404", "input_text": "#include <iostream>\n#include <string>\n#include <vector>\n#include <queue>\n#include <algorithm>\n#include <cmath>\n#include <cassert>\n#include <stack>\n#include <limits>\n#include <array>\n#include <map>\n#include <unordered_map>\n#include <unordered_set>\n#include <memory>\n#include <numeric>\n#include <tuple>\n\nconstexpr long long mod = static_cast<long long>(1e9 + 7);\n\nint main() {\n  int A, B;\n  std::cin >> A >> B;\n  --A;\n  --B;\n  std::cout << 100 << ' ' << 100 << '\\n';\n  for(int i = 0; i < 50; ++i)\n  {\n    for(int j = 0; j < 100; ++j)\n    {\n      if (B > 0 && i % 2 == 0 && j % 2 == 0)\n      {\n        --B;\n        std::cout << '#';\n      }\n      else\n        std::cout << '.';\n    }\n    std::cout << '\\n';\n  }\n\n  for(int i = 0; i < 50; ++i)\n  {\n    for(int j = 0; j < 100; ++j)\n    {\n      if (A > 0 && i % 2 == 1 && j % 2 == 0)\n      {\n        --A;\n        std::cout << '.';\n      }\n      else\n        std::cout << '#';\n    }\n    std::cout << '\\n';\n  }\n  std::cout << std::flush;\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1537411994, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03404.html", "problem_id": "p03404", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03404/input.txt", "sample_output_relpath": "derived/input_output/data/p03404/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03404/C++/s781616391.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s781616391", "user_id": "u653020951"}, "prompt_components": {"gold_output": "3 3\n##.\n..#\n#.#\n", "input_to_evaluate": "#include <iostream>\n#include <string>\n#include <vector>\n#include <queue>\n#include <algorithm>\n#include <cmath>\n#include <cassert>\n#include <stack>\n#include <limits>\n#include <array>\n#include <map>\n#include <unordered_map>\n#include <unordered_set>\n#include <memory>\n#include <numeric>\n#include <tuple>\n\nconstexpr long long mod = static_cast<long long>(1e9 + 7);\n\nint main() {\n  int A, B;\n  std::cin >> A >> B;\n  --A;\n  --B;\n  std::cout << 100 << ' ' << 100 << '\\n';\n  for(int i = 0; i < 50; ++i)\n  {\n    for(int j = 0; j < 100; ++j)\n    {\n      if (B > 0 && i % 2 == 0 && j % 2 == 0)\n      {\n        --B;\n        std::cout << '#';\n      }\n      else\n        std::cout << '.';\n    }\n    std::cout << '\\n';\n  }\n\n  for(int i = 0; i < 50; ++i)\n  {\n    for(int j = 0; j < 100; ++j)\n    {\n      if (A > 0 && i % 2 == 1 && j % 2 == 0)\n      {\n        --A;\n        std::cout << '.';\n      }\n      else\n        std::cout << '#';\n    }\n    std::cout << '\\n';\n  }\n  std::cout << std::flush;\n  return 0;\n}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nYou are given two integers A and B.\n\nPrint a grid where each square is painted white or black that satisfies the following conditions, in the format specified in Output section:\n\nLet the size of the grid be h \\times w (h vertical, w horizontal). Both h and w are at most 100.\n\nThe set of the squares painted white is divided into exactly A connected components.\n\nThe set of the squares painted black is divided into exactly B connected components.\n\nIt can be proved that there always exist one or more solutions under the conditions specified in Constraints section.\nIf there are multiple solutions, any of them may be printed.\n\nNotes\n\nTwo squares painted white, c_1 and c_2, are called connected when the square c_2 can be reached from the square c_1 passing only white squares by repeatedly moving up, down, left or right to an adjacent square.\n\nA set of squares painted white, S, forms a connected component when the following conditions are met:\n\nAny two squares in S are connected.\n\nNo pair of a square painted white that is not included in S and a square included in S is connected.\n\nA connected component of squares painted black is defined similarly.\n\nConstraints\n\n1 \\leq A \\leq 500\n\n1 \\leq B \\leq 500\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nOutput should be in the following format:\n\nIn the first line, print integers h and w representing the size of the grid you constructed, with a space in between.\n\nThen, print h more lines. The i-th (1 \\leq i \\leq h) of these lines should contain a string s_i as follows:\n\nIf the square at the i-th row and j-th column (1 \\leq j \\leq w) in the grid is painted white, the j-th character in s_i should be ..\n\nIf the square at the i-th row and j-th column (1 \\leq j \\leq w) in the grid is painted black, the j-th character in s_i should be #.\n\nSample Input 1\n\n2 3\n\nSample Output 1\n\n3 3\n##.\n..#\n#.#\n\nThis output corresponds to the grid below:\n\nSample Input 2\n\n7 8\n\nSample Output 2\n\n3 5\n#.#.#\n.#.#.\n#.#.#\n\nSample Input 3\n\n1 1\n\nSample Output 3\n\n4 2\n..\n#.\n##\n##\n\nSample Input 4\n\n3 14\n\nSample Output 4\n\n8 18\n..................\n..................\n....##.......####.\n....#.#.....#.....\n...#...#....#.....\n..#.###.#...#.....\n.#.......#..#.....\n#.........#..####.", "sample_input": "2 3\n"}, "reference_outputs": ["3 3\n##.\n..#\n#.#\n"], "source_document_id": "p03404", "source_text": "Score : 500 points\n\nProblem Statement\n\nYou are given two integers A and B.\n\nPrint a grid where each square is painted white or black that satisfies the following conditions, in the format specified in Output section:\n\nLet the size of the grid be h \\times w (h vertical, w horizontal). Both h and w are at most 100.\n\nThe set of the squares painted white is divided into exactly A connected components.\n\nThe set of the squares painted black is divided into exactly B connected components.\n\nIt can be proved that there always exist one or more solutions under the conditions specified in Constraints section.\nIf there are multiple solutions, any of them may be printed.\n\nNotes\n\nTwo squares painted white, c_1 and c_2, are called connected when the square c_2 can be reached from the square c_1 passing only white squares by repeatedly moving up, down, left or right to an adjacent square.\n\nA set of squares painted white, S, forms a connected component when the following conditions are met:\n\nAny two squares in S are connected.\n\nNo pair of a square painted white that is not included in S and a square included in S is connected.\n\nA connected component of squares painted black is defined similarly.\n\nConstraints\n\n1 \\leq A \\leq 500\n\n1 \\leq B \\leq 500\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nOutput should be in the following format:\n\nIn the first line, print integers h and w representing the size of the grid you constructed, with a space in between.\n\nThen, print h more lines. The i-th (1 \\leq i \\leq h) of these lines should contain a string s_i as follows:\n\nIf the square at the i-th row and j-th column (1 \\leq j \\leq w) in the grid is painted white, the j-th character in s_i should be ..\n\nIf the square at the i-th row and j-th column (1 \\leq j \\leq w) in the grid is painted black, the j-th character in s_i should be #.\n\nSample Input 1\n\n2 3\n\nSample Output 1\n\n3 3\n##.\n..#\n#.#\n\nThis output corresponds to the grid below:\n\nSample Input 2\n\n7 8\n\nSample Output 2\n\n3 5\n#.#.#\n.#.#.\n#.#.#\n\nSample Input 3\n\n1 1\n\nSample Output 3\n\n4 2\n..\n#.\n##\n##\n\nSample Input 4\n\n3 14\n\nSample Output 4\n\n8 18\n..................\n..................\n....##.......####.\n....#.#.....#.....\n...#...#....#.....\n..#.###.#...#.....\n.#.......#..#.....\n#.........#..####.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 993, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s208649023", "group_id": "codeNet:p03405", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nconst int N=1005;\nconst int mod=1e9+7;\nstruct node{int u,v,w;}e[N<<1];\nstruct _node{int to,next,w;}num[N<<1];\nint cnt,head[N],n,m,fa[N][13],dep[N],Max[N][13],f[N],tag[N<<1],t1,t2;\nll sum,x;\nbool operator < (const node &A,const node &B) {return A.w<B.w;}\nint find(int x) {return x==f[x]?x:f[x]=find(f[x]);}\nvoid add(int x,int y,int w)\n{num[++cnt].to=y;num[cnt].next=head[x];num[cnt].w=w;head[x]=cnt;}\nvoid mst()\n{\n  sort(e+1,e+m+1);\n  for (int i=1;i<=n;i++) f[i]=i;\n  for (int i=1;i<=m;i++) \n    if (find(e[i].u)!=find(e[i].v)) \n      sum+=e[i].w,f[find(e[i].u)]=find(e[i].v),tag[i]=1,add(e[i].u,e[i].v,e[i].w),add(e[i].v,e[i].u,e[i].w);\n}\nvoid dfs(int x)\n{\n  for (int i=head[x];i;i=num[i].next)\n    if (num[i].to!=fa[x][0])\n    {\n      dep[num[i].to]=dep[x]+1;\n      fa[num[i].to][0]=x;\n      Max[num[i].to][0]=num[i].w;\n      dfs(num[i].to);\n    }\n}\nvoid init()\n{\n  for (int j=1;j<=12;j++)\n    for (int i=1;i<=n;i++)\n      fa[i][j]=fa[fa[i][j-1]][j-1],Max[i][j]=max(Max[i][j-1],Max[fa[i][j-1]][j-1]);\n}\nint jump(int x,int y)\n{\n  if (dep[x]<dep[y]) swap(x,y);\n  int del=dep[x]-dep[y],ans=0;\n  for (int i=0;i<=12;i++)\n    if (del&(1<<i)) ans=max(ans,Max[x][i]),x=fa[x][i];\n  if (x==y) return ans;\n  for (int i=12;i>=0;i--)\n    if (fa[x][i]!=fa[y][i]) ans=max(ans,Max[x][i]),ans=max(ans,Max[y][i]),x=fa[x][i],y=fa[y][i];\n  return max(max(ans,Max[x][0]),Max[y][0]);//一不小心把Max写成fa了！\n}\nint ksm(int x,int y)\n{\n  int res=1;\n  for (;y;x=(ll)x*x%mod,y>>=1)\n    if (y&1) res=(ll)res*x%mod;\n  return res;\n}\nint main()\n{\n  scanf(\"%d%d\",&n,&m);\n  scanf(\"%lld\",&x);\n  for (int i=1;i<=m;i++) scanf(\"%d%d%d\",&e[i].u,&e[i].v,&e[i].w);\n  mst();\n  if (sum>x) return puts(\"0\"),0;\n  else{\n    dfs(1);init();\n    for (int i=1;i<=m;i++) \n      if (!tag[i])\n      {\n        int t=jump(e[i].u,e[i].v);\n        if (e[i].w-t==x-sum) t1++;\n        else if (e[i].w-t>x-sum) t2++;\n      }\n    if (x==sum) printf(\"%lld\\n\",((ll)ksm(2,t2)*(ksm(2,t1+n-1)-2+mod)%mod)%mod);\n    else printf(\"%lld\\n\",(ll)ksm(2,t2)*(ksm(2,t1)-1+mod)%mod*2%mod);\n  }\n  return 0;\n}", "language": "C++", "metadata": {"date": 1528900500, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03405.html", "problem_id": "p03405", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03405/input.txt", "sample_output_relpath": "derived/input_output/data/p03405/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03405/C++/s208649023.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s208649023", "user_id": "u635760914"}, "prompt_components": {"gold_output": "6\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nconst int N=1005;\nconst int mod=1e9+7;\nstruct node{int u,v,w;}e[N<<1];\nstruct _node{int to,next,w;}num[N<<1];\nint cnt,head[N],n,m,fa[N][13],dep[N],Max[N][13],f[N],tag[N<<1],t1,t2;\nll sum,x;\nbool operator < (const node &A,const node &B) {return A.w<B.w;}\nint find(int x) {return x==f[x]?x:f[x]=find(f[x]);}\nvoid add(int x,int y,int w)\n{num[++cnt].to=y;num[cnt].next=head[x];num[cnt].w=w;head[x]=cnt;}\nvoid mst()\n{\n  sort(e+1,e+m+1);\n  for (int i=1;i<=n;i++) f[i]=i;\n  for (int i=1;i<=m;i++) \n    if (find(e[i].u)!=find(e[i].v)) \n      sum+=e[i].w,f[find(e[i].u)]=find(e[i].v),tag[i]=1,add(e[i].u,e[i].v,e[i].w),add(e[i].v,e[i].u,e[i].w);\n}\nvoid dfs(int x)\n{\n  for (int i=head[x];i;i=num[i].next)\n    if (num[i].to!=fa[x][0])\n    {\n      dep[num[i].to]=dep[x]+1;\n      fa[num[i].to][0]=x;\n      Max[num[i].to][0]=num[i].w;\n      dfs(num[i].to);\n    }\n}\nvoid init()\n{\n  for (int j=1;j<=12;j++)\n    for (int i=1;i<=n;i++)\n      fa[i][j]=fa[fa[i][j-1]][j-1],Max[i][j]=max(Max[i][j-1],Max[fa[i][j-1]][j-1]);\n}\nint jump(int x,int y)\n{\n  if (dep[x]<dep[y]) swap(x,y);\n  int del=dep[x]-dep[y],ans=0;\n  for (int i=0;i<=12;i++)\n    if (del&(1<<i)) ans=max(ans,Max[x][i]),x=fa[x][i];\n  if (x==y) return ans;\n  for (int i=12;i>=0;i--)\n    if (fa[x][i]!=fa[y][i]) ans=max(ans,Max[x][i]),ans=max(ans,Max[y][i]),x=fa[x][i],y=fa[y][i];\n  return max(max(ans,Max[x][0]),Max[y][0]);//一不小心把Max写成fa了！\n}\nint ksm(int x,int y)\n{\n  int res=1;\n  for (;y;x=(ll)x*x%mod,y>>=1)\n    if (y&1) res=(ll)res*x%mod;\n  return res;\n}\nint main()\n{\n  scanf(\"%d%d\",&n,&m);\n  scanf(\"%lld\",&x);\n  for (int i=1;i<=m;i++) scanf(\"%d%d%d\",&e[i].u,&e[i].v,&e[i].w);\n  mst();\n  if (sum>x) return puts(\"0\"),0;\n  else{\n    dfs(1);init();\n    for (int i=1;i<=m;i++) \n      if (!tag[i])\n      {\n        int t=jump(e[i].u,e[i].v);\n        if (e[i].w-t==x-sum) t1++;\n        else if (e[i].w-t>x-sum) t2++;\n      }\n    if (x==sum) printf(\"%lld\\n\",((ll)ksm(2,t2)*(ksm(2,t1+n-1)-2+mod)%mod)%mod);\n    else printf(\"%lld\\n\",(ll)ksm(2,t2)*(ksm(2,t1)-1+mod)%mod*2%mod);\n  }\n  return 0;\n}", "problem_context": "Score : 900 points\n\nProblem Statement\n\nWe have an undirected weighted graph with N vertices and M edges.\nThe i-th edge in the graph connects Vertex U_i and Vertex V_i, and has a weight of W_i.\nAdditionally, you are given an integer X.\n\nFind the number of ways to paint each edge in this graph either white or black such that the following condition is met, modulo 10^9 + 7:\n\nThe graph has a spanning tree that contains both an edge painted white and an edge painted black. Furthermore, among such spanning trees, the one with the smallest weight has a weight of X.\n\nHere, the weight of a spanning tree is the sum of the weights of the edges contained in the spanning tree.\n\nConstraints\n\n1 \\leq N \\leq 1 000\n\n1 \\leq M \\leq 2 000\n\n1 \\leq U_i, V_i \\leq N (1 \\leq i \\leq M)\n\n1 \\leq W_i \\leq 10^9 (1 \\leq i \\leq M)\n\nIf i \\neq j, then (U_i, V_i) \\neq (U_j, V_j) and (U_i, V_i) \\neq (V_j, U_j).\n\nU_i \\neq V_i (1 \\leq i \\leq M)\n\nThe given graph is connected.\n\n1 \\leq X \\leq 10^{12}\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nX\nU_1 V_1 W_1\nU_2 V_2 W_2\n:\nU_M V_M W_M\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n3 3\n2\n1 2 1\n2 3 1\n3 1 1\n\nSample Output 1\n\n6\n\nSample Input 2\n\n3 3\n3\n1 2 1\n2 3 1\n3 1 2\n\nSample Output 2\n\n2\n\nSample Input 3\n\n5 4\n1\n1 2 3\n1 3 3\n2 4 6\n2 5 8\n\nSample Output 3\n\n0\n\nSample Input 4\n\n8 10\n49\n4 6 10\n8 4 11\n5 8 9\n1 8 10\n3 8 128773450\n7 8 10\n4 2 4\n3 4 1\n3 1 13\n5 2 2\n\nSample Output 4\n\n4", "sample_input": "3 3\n2\n1 2 1\n2 3 1\n3 1 1\n"}, "reference_outputs": ["6\n"], "source_document_id": "p03405", "source_text": "Score : 900 points\n\nProblem Statement\n\nWe have an undirected weighted graph with N vertices and M edges.\nThe i-th edge in the graph connects Vertex U_i and Vertex V_i, and has a weight of W_i.\nAdditionally, you are given an integer X.\n\nFind the number of ways to paint each edge in this graph either white or black such that the following condition is met, modulo 10^9 + 7:\n\nThe graph has a spanning tree that contains both an edge painted white and an edge painted black. Furthermore, among such spanning trees, the one with the smallest weight has a weight of X.\n\nHere, the weight of a spanning tree is the sum of the weights of the edges contained in the spanning tree.\n\nConstraints\n\n1 \\leq N \\leq 1 000\n\n1 \\leq M \\leq 2 000\n\n1 \\leq U_i, V_i \\leq N (1 \\leq i \\leq M)\n\n1 \\leq W_i \\leq 10^9 (1 \\leq i \\leq M)\n\nIf i \\neq j, then (U_i, V_i) \\neq (U_j, V_j) and (U_i, V_i) \\neq (V_j, U_j).\n\nU_i \\neq V_i (1 \\leq i \\leq M)\n\nThe given graph is connected.\n\n1 \\leq X \\leq 10^{12}\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nX\nU_1 V_1 W_1\nU_2 V_2 W_2\n:\nU_M V_M W_M\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n3 3\n2\n1 2 1\n2 3 1\n3 1 1\n\nSample Output 1\n\n6\n\nSample Input 2\n\n3 3\n3\n1 2 1\n2 3 1\n3 1 2\n\nSample Output 2\n\n2\n\nSample Input 3\n\n5 4\n1\n1 2 3\n1 3 3\n2 4 6\n2 5 8\n\nSample Output 3\n\n0\n\nSample Input 4\n\n8 10\n49\n4 6 10\n8 4 11\n5 8 9\n1 8 10\n3 8 128773450\n7 8 10\n4 2 4\n3 4 1\n3 1 13\n5 2 2\n\nSample Output 4\n\n4", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2110, "cpu_time_ms": 2, "memory_kb": 512}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s410945563", "group_id": "codeNet:p03408", "input_text": "#include <cmath>\n#include <cstdio>\n#include <vector>\n#include <iostream>\n#include <algorithm>\n#include <queue>\n#include <string>\n#include <set>\n#include <map>\n#define REP(i,n) for(ll i = 0; i < (ll)n; i++)\n#define INF 1000000000000000\nusing namespace std;\ntypedef long long ll;\ntypedef double db;\ntypedef string str;\n\nint main(){\n  ll n;\n  cin >> n;\n  map<str,ll> mp;\n  REP(i,n){\n    str st;\n    cin >> st;\n    mp[st]++;\n  }\n  ll m;\n  cin >> m;\n  REP(i,m){\n    str st;\n    cin >> st;\n    mp[st]--;\n  }\n  ll max = 0;\n  for(auto itr = mp.begin(); itr!=mp.end(); itr++){\n    if(max<itr->second) max = itr->second;\n  }\n  cout << max << endl;\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1531447935, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03408.html", "problem_id": "p03408", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03408/input.txt", "sample_output_relpath": "derived/input_output/data/p03408/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03408/C++/s410945563.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s410945563", "user_id": "u780950519"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <cmath>\n#include <cstdio>\n#include <vector>\n#include <iostream>\n#include <algorithm>\n#include <queue>\n#include <string>\n#include <set>\n#include <map>\n#define REP(i,n) for(ll i = 0; i < (ll)n; i++)\n#define INF 1000000000000000\nusing namespace std;\ntypedef long long ll;\ntypedef double db;\ntypedef string str;\n\nint main(){\n  ll n;\n  cin >> n;\n  map<str,ll> mp;\n  REP(i,n){\n    str st;\n    cin >> st;\n    mp[st]++;\n  }\n  ll m;\n  cin >> m;\n  REP(i,m){\n    str st;\n    cin >> st;\n    mp[st]--;\n  }\n  ll max = 0;\n  for(auto itr = mp.begin(); itr!=mp.end(); itr++){\n    if(max<itr->second) max = itr->second;\n  }\n  cout << max << endl;\n  return 0;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nTakahashi has N blue cards and M red cards.\nA string is written on each card. The string written on the i-th blue card is s_i, and the string written on the i-th red card is t_i.\n\nTakahashi will now announce a string, and then check every card. Each time he finds a blue card with the string announced by him, he will earn 1 yen (the currency of Japan); each time he finds a red card with that string, he will lose 1 yen.\n\nHere, we only consider the case where the string announced by Takahashi and the string on the card are exactly the same. For example, if he announces atcoder, he will not earn money even if there are blue cards with atcoderr, atcode, btcoder, and so on. (On the other hand, he will not lose money even if there are red cards with such strings, either.)\n\nAt most how much can he earn on balance?\n\nNote that the same string may be written on multiple cards.\n\nConstraints\n\nN and M are integers.\n\n1 \\leq N, M \\leq 100\n\ns_1, s_2, ..., s_N, t_1, t_2, ..., t_M are all strings of lengths between 1 and 10 (inclusive) consisting of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\ns_1\ns_2\n:\ns_N\nM\nt_1\nt_2\n:\nt_M\n\nOutput\n\nIf Takahashi can earn at most X yen on balance, print X.\n\nSample Input 1\n\n3\napple\norange\napple\n1\ngrape\n\nSample Output 1\n\n2\n\nHe can earn 2 yen by announcing apple.\n\nSample Input 2\n\n3\napple\norange\napple\n5\napple\napple\napple\napple\napple\n\nSample Output 2\n\n1\n\nIf he announces apple, he will lose 3 yen. If he announces orange, he can earn 1 yen.\n\nSample Input 3\n\n1\nvoldemort\n10\nvoldemort\nvoldemort\nvoldemort\nvoldemort\nvoldemort\nvoldemort\nvoldemort\nvoldemort\nvoldemort\nvoldemort\n\nSample Output 3\n\n0\n\nIf he announces voldemort, he will lose 9 yen. If he announces orange, for example, he can avoid losing a yen.\n\nSample Input 4\n\n6\nred\nred\nblue\nyellow\nyellow\nred\n5\nred\nred\nyellow\ngreen\nblue\n\nSample Output 4\n\n1", "sample_input": "3\napple\norange\napple\n1\ngrape\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03408", "source_text": "Score : 200 points\n\nProblem Statement\n\nTakahashi has N blue cards and M red cards.\nA string is written on each card. The string written on the i-th blue card is s_i, and the string written on the i-th red card is t_i.\n\nTakahashi will now announce a string, and then check every card. Each time he finds a blue card with the string announced by him, he will earn 1 yen (the currency of Japan); each time he finds a red card with that string, he will lose 1 yen.\n\nHere, we only consider the case where the string announced by Takahashi and the string on the card are exactly the same. For example, if he announces atcoder, he will not earn money even if there are blue cards with atcoderr, atcode, btcoder, and so on. (On the other hand, he will not lose money even if there are red cards with such strings, either.)\n\nAt most how much can he earn on balance?\n\nNote that the same string may be written on multiple cards.\n\nConstraints\n\nN and M are integers.\n\n1 \\leq N, M \\leq 100\n\ns_1, s_2, ..., s_N, t_1, t_2, ..., t_M are all strings of lengths between 1 and 10 (inclusive) consisting of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\ns_1\ns_2\n:\ns_N\nM\nt_1\nt_2\n:\nt_M\n\nOutput\n\nIf Takahashi can earn at most X yen on balance, print X.\n\nSample Input 1\n\n3\napple\norange\napple\n1\ngrape\n\nSample Output 1\n\n2\n\nHe can earn 2 yen by announcing apple.\n\nSample Input 2\n\n3\napple\norange\napple\n5\napple\napple\napple\napple\napple\n\nSample Output 2\n\n1\n\nIf he announces apple, he will lose 3 yen. If he announces orange, he can earn 1 yen.\n\nSample Input 3\n\n1\nvoldemort\n10\nvoldemort\nvoldemort\nvoldemort\nvoldemort\nvoldemort\nvoldemort\nvoldemort\nvoldemort\nvoldemort\nvoldemort\n\nSample Output 3\n\n0\n\nIf he announces voldemort, he will lose 9 yen. If he announces orange, for example, he can avoid losing a yen.\n\nSample Input 4\n\n6\nred\nred\nblue\nyellow\nyellow\nred\n5\nred\nred\nyellow\ngreen\nblue\n\nSample Output 4\n\n1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 652, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s884503985", "group_id": "codeNet:p03409", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n#define REP(i,a) for(int i = 0; i < (a); i++)\n#define ALL(a) (a).begin(),(a).end()\ntypedef long long ll;\ntypedef pair<int, int> P;\nconst int INF = 1e9;\nconst int MOD = 1e9 + 7;\n\n#define MAX_V 200\n\nint V;//頂点数\nvector<int> G[MAX_V];//グラフの隣接リスト表現\nint match[MAX_V];//マッチングのペア\nbool used[MAX_V];//DFSですでに調べたかのフラグ\n\n//uとvを結ぶ辺をグラフに追加する\nvoid add_edge(int u, int v){\n    G[u].push_back(v);\n    G[v].push_back(u);\n}\n\n//増加パスをDFSで探す\nbool dfs(int v){\n    used[v] = true;\n    for(int i = 0; i < G[v].size(); i++){\n        int u = G[v][i], w = match[u];\n        if(w < 0 || !used[w] && dfs(w)){\n            match[v] = u;\n            match[u] = v;\n            return true;\n        }\n    }\n    return false;\n}\n\n//二部グラフの最大マッチングを求める\nint bipartite_matching(){\n    int res = 0;\n    memset(match, -1, sizeof(match));\n    for(int v = 0; v < V; v++){\n        if(match[v] < 0){\n            memset(used, 0, sizeof(used));\n            if(dfs(v)){\n                res++;\n            }\n        }\n    }\n    return res;\n}\n\nsigned main(){\n    int n;\n    cin >> n;\n    int a[n],b[n];\n    REP(i,n){\n        cin >> a[i] >> b[i];\n    }\n    int c[n],d[n];\n    REP(i,n){\n        cin >> c[i] >> d[i];\n    }\n    REP(i,n){\n        REP(j,n){\n            if(a[i] < c[j] && b[i] < d[j]){\n                add_edge(i, n + j);\n            }\n        }\n    }\n    V = 2 * n;\n    cout << bipartite_matching() << endl;\n}", "language": "C++", "metadata": {"date": 1567197826, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03409.html", "problem_id": "p03409", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03409/input.txt", "sample_output_relpath": "derived/input_output/data/p03409/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03409/C++/s884503985.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s884503985", "user_id": "u366398972"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n#define REP(i,a) for(int i = 0; i < (a); i++)\n#define ALL(a) (a).begin(),(a).end()\ntypedef long long ll;\ntypedef pair<int, int> P;\nconst int INF = 1e9;\nconst int MOD = 1e9 + 7;\n\n#define MAX_V 200\n\nint V;//頂点数\nvector<int> G[MAX_V];//グラフの隣接リスト表現\nint match[MAX_V];//マッチングのペア\nbool used[MAX_V];//DFSですでに調べたかのフラグ\n\n//uとvを結ぶ辺をグラフに追加する\nvoid add_edge(int u, int v){\n    G[u].push_back(v);\n    G[v].push_back(u);\n}\n\n//増加パスをDFSで探す\nbool dfs(int v){\n    used[v] = true;\n    for(int i = 0; i < G[v].size(); i++){\n        int u = G[v][i], w = match[u];\n        if(w < 0 || !used[w] && dfs(w)){\n            match[v] = u;\n            match[u] = v;\n            return true;\n        }\n    }\n    return false;\n}\n\n//二部グラフの最大マッチングを求める\nint bipartite_matching(){\n    int res = 0;\n    memset(match, -1, sizeof(match));\n    for(int v = 0; v < V; v++){\n        if(match[v] < 0){\n            memset(used, 0, sizeof(used));\n            if(dfs(v)){\n                res++;\n            }\n        }\n    }\n    return res;\n}\n\nsigned main(){\n    int n;\n    cin >> n;\n    int a[n],b[n];\n    REP(i,n){\n        cin >> a[i] >> b[i];\n    }\n    int c[n],d[n];\n    REP(i,n){\n        cin >> c[i] >> d[i];\n    }\n    REP(i,n){\n        REP(j,n){\n            if(a[i] < c[j] && b[i] < d[j]){\n                add_edge(i, n + j);\n            }\n        }\n    }\n    V = 2 * n;\n    cout << bipartite_matching() << endl;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nOn a two-dimensional plane, there are N red points and N blue points.\nThe coordinates of the i-th red point are (a_i, b_i), and the coordinates of the i-th blue point are (c_i, d_i).\n\nA red point and a blue point can form a friendly pair when, the x-coordinate of the red point is smaller than that of the blue point, and the y-coordinate of the red point is also smaller than that of the blue point.\n\nAt most how many friendly pairs can you form? Note that a point cannot belong to multiple pairs.\n\nConstraints\n\nAll input values are integers.\n\n1 \\leq N \\leq 100\n\n0 \\leq a_i, b_i, c_i, d_i < 2N\n\na_1, a_2, ..., a_N, c_1, c_2, ..., c_N are all different.\n\nb_1, b_2, ..., b_N, d_1, d_2, ..., d_N are all different.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 b_1\na_2 b_2\n:\na_N b_N\nc_1 d_1\nc_2 d_2\n:\nc_N d_N\n\nOutput\n\nPrint the maximum number of friendly pairs.\n\nSample Input 1\n\n3\n2 0\n3 1\n1 3\n4 2\n0 4\n5 5\n\nSample Output 1\n\n2\n\nFor example, you can pair (2, 0) and (4, 2), then (3, 1) and (5, 5).\n\nSample Input 2\n\n3\n0 0\n1 1\n5 2\n2 3\n3 4\n4 5\n\nSample Output 2\n\n2\n\nFor example, you can pair (0, 0) and (2, 3), then (1, 1) and (3, 4).\n\nSample Input 3\n\n2\n2 2\n3 3\n0 0\n1 1\n\nSample Output 3\n\n0\n\nIt is possible that no pair can be formed.\n\nSample Input 4\n\n5\n0 0\n7 3\n2 2\n4 8\n1 6\n8 5\n6 9\n5 4\n9 1\n3 7\n\nSample Output 4\n\n5\n\nSample Input 5\n\n5\n0 0\n1 1\n5 5\n6 6\n7 7\n2 2\n3 3\n4 4\n8 8\n9 9\n\nSample Output 5\n\n4", "sample_input": "3\n2 0\n3 1\n1 3\n4 2\n0 4\n5 5\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03409", "source_text": "Score : 400 points\n\nProblem Statement\n\nOn a two-dimensional plane, there are N red points and N blue points.\nThe coordinates of the i-th red point are (a_i, b_i), and the coordinates of the i-th blue point are (c_i, d_i).\n\nA red point and a blue point can form a friendly pair when, the x-coordinate of the red point is smaller than that of the blue point, and the y-coordinate of the red point is also smaller than that of the blue point.\n\nAt most how many friendly pairs can you form? Note that a point cannot belong to multiple pairs.\n\nConstraints\n\nAll input values are integers.\n\n1 \\leq N \\leq 100\n\n0 \\leq a_i, b_i, c_i, d_i < 2N\n\na_1, a_2, ..., a_N, c_1, c_2, ..., c_N are all different.\n\nb_1, b_2, ..., b_N, d_1, d_2, ..., d_N are all different.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 b_1\na_2 b_2\n:\na_N b_N\nc_1 d_1\nc_2 d_2\n:\nc_N d_N\n\nOutput\n\nPrint the maximum number of friendly pairs.\n\nSample Input 1\n\n3\n2 0\n3 1\n1 3\n4 2\n0 4\n5 5\n\nSample Output 1\n\n2\n\nFor example, you can pair (2, 0) and (4, 2), then (3, 1) and (5, 5).\n\nSample Input 2\n\n3\n0 0\n1 1\n5 2\n2 3\n3 4\n4 5\n\nSample Output 2\n\n2\n\nFor example, you can pair (0, 0) and (2, 3), then (1, 1) and (3, 4).\n\nSample Input 3\n\n2\n2 2\n3 3\n0 0\n1 1\n\nSample Output 3\n\n0\n\nIt is possible that no pair can be formed.\n\nSample Input 4\n\n5\n0 0\n7 3\n2 2\n4 8\n1 6\n8 5\n6 9\n5 4\n9 1\n3 7\n\nSample Output 4\n\n5\n\nSample Input 5\n\n5\n0 0\n1 1\n5 5\n6 6\n7 7\n2 2\n3 3\n4 4\n8 8\n9 9\n\nSample Output 5\n\n4", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1558, "cpu_time_ms": 2, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s880433037", "group_id": "codeNet:p03409", "input_text": "#include<iostream>\n#include<vector>\nusing namespace std;\n\nint main(){\n\tint n; cin>>n;\n\tvector<int> a(n),b(n),c(n),d(n);\n\tfor(int i=0;i<n;i++) cin >> a[i] >> b[i];\n\tfor(int i=0;i<n;i++) cin >> c[i] >> d[i];\n\n\tint ans=0;\n\twhile(c.size()>0){\n\t\tint minxblue=0;\n\t\tfor(int i=1;i<c.size();i++){\n\t\t\tminxblue=min(c[minxblue],c[i])==c[i]?i:minxblue;\n\t\t}\n\t\tint maxyred=0;\n\t\tbool flag=false;\n\t\tfor(int i=0;i<a.size();i++){\n\t\t\tif(a[i]<c[minxblue] && b[i]<d[minxblue]){\n\t\t\t\tif(!flag) maxyred=i;\n\t\t\t\tmaxyred=max(b[i],b[maxyred])==b[i]?i:maxyred;\n\t\t\t\tflag=true;\n\t\t\t}\n\t\t}\n\t\tif(flag){\n\t\t\tans++;\n\t\t\ta.erase(a.begin()+maxyred);\n\t\t\tb.erase(b.begin()+maxyred);\n\t\t}\n\t\tc.erase(c.begin()+minxblue);\n\t\td.erase(d.begin()+minxblue);\n\t}\n\tcout << ans << endl;\n}\n", "language": "C++", "metadata": {"date": 1537422797, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03409.html", "problem_id": "p03409", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03409/input.txt", "sample_output_relpath": "derived/input_output/data/p03409/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03409/C++/s880433037.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s880433037", "user_id": "u687548330"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include<iostream>\n#include<vector>\nusing namespace std;\n\nint main(){\n\tint n; cin>>n;\n\tvector<int> a(n),b(n),c(n),d(n);\n\tfor(int i=0;i<n;i++) cin >> a[i] >> b[i];\n\tfor(int i=0;i<n;i++) cin >> c[i] >> d[i];\n\n\tint ans=0;\n\twhile(c.size()>0){\n\t\tint minxblue=0;\n\t\tfor(int i=1;i<c.size();i++){\n\t\t\tminxblue=min(c[minxblue],c[i])==c[i]?i:minxblue;\n\t\t}\n\t\tint maxyred=0;\n\t\tbool flag=false;\n\t\tfor(int i=0;i<a.size();i++){\n\t\t\tif(a[i]<c[minxblue] && b[i]<d[minxblue]){\n\t\t\t\tif(!flag) maxyred=i;\n\t\t\t\tmaxyred=max(b[i],b[maxyred])==b[i]?i:maxyred;\n\t\t\t\tflag=true;\n\t\t\t}\n\t\t}\n\t\tif(flag){\n\t\t\tans++;\n\t\t\ta.erase(a.begin()+maxyred);\n\t\t\tb.erase(b.begin()+maxyred);\n\t\t}\n\t\tc.erase(c.begin()+minxblue);\n\t\td.erase(d.begin()+minxblue);\n\t}\n\tcout << ans << endl;\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nOn a two-dimensional plane, there are N red points and N blue points.\nThe coordinates of the i-th red point are (a_i, b_i), and the coordinates of the i-th blue point are (c_i, d_i).\n\nA red point and a blue point can form a friendly pair when, the x-coordinate of the red point is smaller than that of the blue point, and the y-coordinate of the red point is also smaller than that of the blue point.\n\nAt most how many friendly pairs can you form? Note that a point cannot belong to multiple pairs.\n\nConstraints\n\nAll input values are integers.\n\n1 \\leq N \\leq 100\n\n0 \\leq a_i, b_i, c_i, d_i < 2N\n\na_1, a_2, ..., a_N, c_1, c_2, ..., c_N are all different.\n\nb_1, b_2, ..., b_N, d_1, d_2, ..., d_N are all different.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 b_1\na_2 b_2\n:\na_N b_N\nc_1 d_1\nc_2 d_2\n:\nc_N d_N\n\nOutput\n\nPrint the maximum number of friendly pairs.\n\nSample Input 1\n\n3\n2 0\n3 1\n1 3\n4 2\n0 4\n5 5\n\nSample Output 1\n\n2\n\nFor example, you can pair (2, 0) and (4, 2), then (3, 1) and (5, 5).\n\nSample Input 2\n\n3\n0 0\n1 1\n5 2\n2 3\n3 4\n4 5\n\nSample Output 2\n\n2\n\nFor example, you can pair (0, 0) and (2, 3), then (1, 1) and (3, 4).\n\nSample Input 3\n\n2\n2 2\n3 3\n0 0\n1 1\n\nSample Output 3\n\n0\n\nIt is possible that no pair can be formed.\n\nSample Input 4\n\n5\n0 0\n7 3\n2 2\n4 8\n1 6\n8 5\n6 9\n5 4\n9 1\n3 7\n\nSample Output 4\n\n5\n\nSample Input 5\n\n5\n0 0\n1 1\n5 5\n6 6\n7 7\n2 2\n3 3\n4 4\n8 8\n9 9\n\nSample Output 5\n\n4", "sample_input": "3\n2 0\n3 1\n1 3\n4 2\n0 4\n5 5\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03409", "source_text": "Score : 400 points\n\nProblem Statement\n\nOn a two-dimensional plane, there are N red points and N blue points.\nThe coordinates of the i-th red point are (a_i, b_i), and the coordinates of the i-th blue point are (c_i, d_i).\n\nA red point and a blue point can form a friendly pair when, the x-coordinate of the red point is smaller than that of the blue point, and the y-coordinate of the red point is also smaller than that of the blue point.\n\nAt most how many friendly pairs can you form? Note that a point cannot belong to multiple pairs.\n\nConstraints\n\nAll input values are integers.\n\n1 \\leq N \\leq 100\n\n0 \\leq a_i, b_i, c_i, d_i < 2N\n\na_1, a_2, ..., a_N, c_1, c_2, ..., c_N are all different.\n\nb_1, b_2, ..., b_N, d_1, d_2, ..., d_N are all different.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 b_1\na_2 b_2\n:\na_N b_N\nc_1 d_1\nc_2 d_2\n:\nc_N d_N\n\nOutput\n\nPrint the maximum number of friendly pairs.\n\nSample Input 1\n\n3\n2 0\n3 1\n1 3\n4 2\n0 4\n5 5\n\nSample Output 1\n\n2\n\nFor example, you can pair (2, 0) and (4, 2), then (3, 1) and (5, 5).\n\nSample Input 2\n\n3\n0 0\n1 1\n5 2\n2 3\n3 4\n4 5\n\nSample Output 2\n\n2\n\nFor example, you can pair (0, 0) and (2, 3), then (1, 1) and (3, 4).\n\nSample Input 3\n\n2\n2 2\n3 3\n0 0\n1 1\n\nSample Output 3\n\n0\n\nIt is possible that no pair can be formed.\n\nSample Input 4\n\n5\n0 0\n7 3\n2 2\n4 8\n1 6\n8 5\n6 9\n5 4\n9 1\n3 7\n\nSample Output 4\n\n5\n\nSample Input 5\n\n5\n0 0\n1 1\n5 5\n6 6\n7 7\n2 2\n3 3\n4 4\n8 8\n9 9\n\nSample Output 5\n\n4", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 732, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s714974814", "group_id": "codeNet:p03415", "input_text": "#define _GLIBCXX_DEBUG\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef string str;\ntypedef vector<ll> vel;\ntypedef vector<str> ves;\n#define REP(i, a, b) for (ll i = (ll)(a); i < (ll)(b); i++)\n#define rep(i, b) REP(i, 0, b)\nconst ll mod = 1000000007;\nconst double pi = 3.14159265358979;\n\nint main() {\n    str a, b, c;\n    cin >> a >> b >> c;\n    cout << a[0] << b[1] << c[2] << endl;\n}", "language": "C++", "metadata": {"date": 1588013099, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03415.html", "problem_id": "p03415", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03415/input.txt", "sample_output_relpath": "derived/input_output/data/p03415/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03415/C++/s714974814.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s714974814", "user_id": "u907470767"}, "prompt_components": {"gold_output": "abc\n", "input_to_evaluate": "#define _GLIBCXX_DEBUG\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef string str;\ntypedef vector<ll> vel;\ntypedef vector<str> ves;\n#define REP(i, a, b) for (ll i = (ll)(a); i < (ll)(b); i++)\n#define rep(i, b) REP(i, 0, b)\nconst ll mod = 1000000007;\nconst double pi = 3.14159265358979;\n\nint main() {\n    str a, b, c;\n    cin >> a >> b >> c;\n    cout << a[0] << b[1] << c[2] << endl;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nWe have a 3×3 square grid, where each square contains a lowercase English letters.\nThe letter in the square at the i-th row from the top and j-th column from the left is c_{ij}.\n\nPrint the string of length 3 that can be obtained by concatenating the letters in the squares on the diagonal connecting the top-left and bottom-right corner of the grid, from the top-left to bottom-right.\n\nConstraints\n\nInput consists of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nc_{11}c_{12}c_{13}\nc_{21}c_{22}c_{23}\nc_{31}c_{32}c_{33}\n\nOutput\n\nPrint the string of length 3 that can be obtained by concatenating the letters on the diagonal connecting the top-left and bottom-right corner of the grid, from the top-left to bottom-right.\n\nSample Input 1\n\nant\nobe\nrec\n\nSample Output 1\n\nabc\n\nThe letters in the squares on the diagonal connecting the top-left and bottom-right corner of the grid are a, b and c from top-right to bottom-left. Concatenate these letters and print abc.\n\nSample Input 2\n\nedu\ncat\nion\n\nSample Output 2\n\nean", "sample_input": "ant\nobe\nrec\n"}, "reference_outputs": ["abc\n"], "source_document_id": "p03415", "source_text": "Score : 100 points\n\nProblem Statement\n\nWe have a 3×3 square grid, where each square contains a lowercase English letters.\nThe letter in the square at the i-th row from the top and j-th column from the left is c_{ij}.\n\nPrint the string of length 3 that can be obtained by concatenating the letters in the squares on the diagonal connecting the top-left and bottom-right corner of the grid, from the top-left to bottom-right.\n\nConstraints\n\nInput consists of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nc_{11}c_{12}c_{13}\nc_{21}c_{22}c_{23}\nc_{31}c_{32}c_{33}\n\nOutput\n\nPrint the string of length 3 that can be obtained by concatenating the letters on the diagonal connecting the top-left and bottom-right corner of the grid, from the top-left to bottom-right.\n\nSample Input 1\n\nant\nobe\nrec\n\nSample Output 1\n\nabc\n\nThe letters in the squares on the diagonal connecting the top-left and bottom-right corner of the grid are a, b and c from top-right to bottom-left. Concatenate these letters and print abc.\n\nSample Input 2\n\nedu\ncat\nion\n\nSample Output 2\n\nean", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 412, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s430934879", "group_id": "codeNet:p03415", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n\nchar a[3][3];\n\nint main(){\n\n    for(int i=0; i<3; ++i){\n        scanf(\"%s\", a[i]);\n    }\n\n    string s=\"\";\n    for(int i=0; i<3; ++i){\n        for(int j=0; j<3; ++j){\n            if(i==j)\n                s+=a[i][j];\n        }\n    }\n\n    cout<<s;\n\n\n\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1567396953, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03415.html", "problem_id": "p03415", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03415/input.txt", "sample_output_relpath": "derived/input_output/data/p03415/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03415/C++/s430934879.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s430934879", "user_id": "u018679195"}, "prompt_components": {"gold_output": "abc\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n\nchar a[3][3];\n\nint main(){\n\n    for(int i=0; i<3; ++i){\n        scanf(\"%s\", a[i]);\n    }\n\n    string s=\"\";\n    for(int i=0; i<3; ++i){\n        for(int j=0; j<3; ++j){\n            if(i==j)\n                s+=a[i][j];\n        }\n    }\n\n    cout<<s;\n\n\n\n    return 0;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nWe have a 3×3 square grid, where each square contains a lowercase English letters.\nThe letter in the square at the i-th row from the top and j-th column from the left is c_{ij}.\n\nPrint the string of length 3 that can be obtained by concatenating the letters in the squares on the diagonal connecting the top-left and bottom-right corner of the grid, from the top-left to bottom-right.\n\nConstraints\n\nInput consists of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nc_{11}c_{12}c_{13}\nc_{21}c_{22}c_{23}\nc_{31}c_{32}c_{33}\n\nOutput\n\nPrint the string of length 3 that can be obtained by concatenating the letters on the diagonal connecting the top-left and bottom-right corner of the grid, from the top-left to bottom-right.\n\nSample Input 1\n\nant\nobe\nrec\n\nSample Output 1\n\nabc\n\nThe letters in the squares on the diagonal connecting the top-left and bottom-right corner of the grid are a, b and c from top-right to bottom-left. Concatenate these letters and print abc.\n\nSample Input 2\n\nedu\ncat\nion\n\nSample Output 2\n\nean", "sample_input": "ant\nobe\nrec\n"}, "reference_outputs": ["abc\n"], "source_document_id": "p03415", "source_text": "Score : 100 points\n\nProblem Statement\n\nWe have a 3×3 square grid, where each square contains a lowercase English letters.\nThe letter in the square at the i-th row from the top and j-th column from the left is c_{ij}.\n\nPrint the string of length 3 that can be obtained by concatenating the letters in the squares on the diagonal connecting the top-left and bottom-right corner of the grid, from the top-left to bottom-right.\n\nConstraints\n\nInput consists of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nc_{11}c_{12}c_{13}\nc_{21}c_{22}c_{23}\nc_{31}c_{32}c_{33}\n\nOutput\n\nPrint the string of length 3 that can be obtained by concatenating the letters on the diagonal connecting the top-left and bottom-right corner of the grid, from the top-left to bottom-right.\n\nSample Input 1\n\nant\nobe\nrec\n\nSample Output 1\n\nabc\n\nThe letters in the squares on the diagonal connecting the top-left and bottom-right corner of the grid are a, b and c from top-right to bottom-left. Concatenate these letters and print abc.\n\nSample Input 2\n\nedu\ncat\nion\n\nSample Output 2\n\nean", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 311, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s454699404", "group_id": "codeNet:p03415", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n\tchar c[9];\n\tfor(int i=0;i<9;i++)\n\tcin>>c[i];\n\tcout<<c[0]<<c[4]<<c[8];\n}", "language": "C++", "metadata": {"date": 1561839418, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03415.html", "problem_id": "p03415", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03415/input.txt", "sample_output_relpath": "derived/input_output/data/p03415/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03415/C++/s454699404.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s454699404", "user_id": "u843215894"}, "prompt_components": {"gold_output": "abc\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n\tchar c[9];\n\tfor(int i=0;i<9;i++)\n\tcin>>c[i];\n\tcout<<c[0]<<c[4]<<c[8];\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nWe have a 3×3 square grid, where each square contains a lowercase English letters.\nThe letter in the square at the i-th row from the top and j-th column from the left is c_{ij}.\n\nPrint the string of length 3 that can be obtained by concatenating the letters in the squares on the diagonal connecting the top-left and bottom-right corner of the grid, from the top-left to bottom-right.\n\nConstraints\n\nInput consists of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nc_{11}c_{12}c_{13}\nc_{21}c_{22}c_{23}\nc_{31}c_{32}c_{33}\n\nOutput\n\nPrint the string of length 3 that can be obtained by concatenating the letters on the diagonal connecting the top-left and bottom-right corner of the grid, from the top-left to bottom-right.\n\nSample Input 1\n\nant\nobe\nrec\n\nSample Output 1\n\nabc\n\nThe letters in the squares on the diagonal connecting the top-left and bottom-right corner of the grid are a, b and c from top-right to bottom-left. Concatenate these letters and print abc.\n\nSample Input 2\n\nedu\ncat\nion\n\nSample Output 2\n\nean", "sample_input": "ant\nobe\nrec\n"}, "reference_outputs": ["abc\n"], "source_document_id": "p03415", "source_text": "Score : 100 points\n\nProblem Statement\n\nWe have a 3×3 square grid, where each square contains a lowercase English letters.\nThe letter in the square at the i-th row from the top and j-th column from the left is c_{ij}.\n\nPrint the string of length 3 that can be obtained by concatenating the letters in the squares on the diagonal connecting the top-left and bottom-right corner of the grid, from the top-left to bottom-right.\n\nConstraints\n\nInput consists of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nc_{11}c_{12}c_{13}\nc_{21}c_{22}c_{23}\nc_{31}c_{32}c_{33}\n\nOutput\n\nPrint the string of length 3 that can be obtained by concatenating the letters on the diagonal connecting the top-left and bottom-right corner of the grid, from the top-left to bottom-right.\n\nSample Input 1\n\nant\nobe\nrec\n\nSample Output 1\n\nabc\n\nThe letters in the squares on the diagonal connecting the top-left and bottom-right corner of the grid are a, b and c from top-right to bottom-left. Concatenate these letters and print abc.\n\nSample Input 2\n\nedu\ncat\nion\n\nSample Output 2\n\nean", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 130, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s820135734", "group_id": "codeNet:p03416", "input_text": "#include <iostream>\nusing namespace std;\n\nint main()\n{\n    int i, j;\n    int A, B;\n    cin >> A >> B;\n    int num[4];\n    int check=0;\n    int cal_num;\n    \n    for(i=A;i<=B;i++)\n    {\n        cal_num = i;\n        for(j=0;j<5;j++)\n        {\n            num[j]=cal_num %10;\n            cal_num /= 10;\n        }\n        \n        if(num[0]==num[4]&&num[1]==num[3])\n        {\n            check++;\n        }\n\n    }\n    cout << check <<endl;\n}", "language": "C++", "metadata": {"date": 1547841288, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03416.html", "problem_id": "p03416", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03416/input.txt", "sample_output_relpath": "derived/input_output/data/p03416/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03416/C++/s820135734.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s820135734", "user_id": "u737302099"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <iostream>\nusing namespace std;\n\nint main()\n{\n    int i, j;\n    int A, B;\n    cin >> A >> B;\n    int num[4];\n    int check=0;\n    int cal_num;\n    \n    for(i=A;i<=B;i++)\n    {\n        cal_num = i;\n        for(j=0;j<5;j++)\n        {\n            num[j]=cal_num %10;\n            cal_num /= 10;\n        }\n        \n        if(num[0]==num[4]&&num[1]==num[3])\n        {\n            check++;\n        }\n\n    }\n    cout << check <<endl;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nFind the number of palindromic numbers among the integers between A and B (inclusive).\nHere, a palindromic number is a positive integer whose string representation in base 10 (without leading zeros) reads the same forward and backward.\n\nConstraints\n\n10000 \\leq A \\leq B \\leq 99999\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nPrint the number of palindromic numbers among the integers between A and B (inclusive).\n\nSample Input 1\n\n11009 11332\n\nSample Output 1\n\n4\n\nThere are four integers that satisfy the conditions: 11011, 11111, 11211 and 11311.\n\nSample Input 2\n\n31415 92653\n\nSample Output 2\n\n612", "sample_input": "11009 11332\n"}, "reference_outputs": ["4\n"], "source_document_id": "p03416", "source_text": "Score : 200 points\n\nProblem Statement\n\nFind the number of palindromic numbers among the integers between A and B (inclusive).\nHere, a palindromic number is a positive integer whose string representation in base 10 (without leading zeros) reads the same forward and backward.\n\nConstraints\n\n10000 \\leq A \\leq B \\leq 99999\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nPrint the number of palindromic numbers among the integers between A and B (inclusive).\n\nSample Input 1\n\n11009 11332\n\nSample Output 1\n\n4\n\nThere are four integers that satisfy the conditions: 11011, 11111, 11211 and 11311.\n\nSample Input 2\n\n31415 92653\n\nSample Output 2\n\n612", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 437, "cpu_time_ms": 2, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s811495980", "group_id": "codeNet:p03417", "input_text": "#include<bits/stdc++.h>\n#define rep(i,n)for(int i=0;i<n;++i)\n#include<string>\nusing namespace std;\ntypedef long long ll;\n//max=({});\n\n\nint main() {\n\tll n, m;\n\tcin >> n >> m;\n\tif (n == 1 && m == 1)cout << 1 << endl;\n\telse if (n == 1 && m != 1)cout << m - 2 << endl;\n\telse if (n != 1 && m == 1)cout << n - 2 << endl;\n\telse {\n\t\tll ans = (n - 2) * (m - 2);\n\t\tcout << ans << endl;\n\t}\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1578800857, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03417.html", "problem_id": "p03417", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03417/input.txt", "sample_output_relpath": "derived/input_output/data/p03417/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03417/C++/s811495980.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s811495980", "user_id": "u631558039"}, "prompt_components": {"gold_output": "0\n", "input_to_evaluate": "#include<bits/stdc++.h>\n#define rep(i,n)for(int i=0;i<n;++i)\n#include<string>\nusing namespace std;\ntypedef long long ll;\n//max=({});\n\n\nint main() {\n\tll n, m;\n\tcin >> n >> m;\n\tif (n == 1 && m == 1)cout << 1 << endl;\n\telse if (n == 1 && m != 1)cout << m - 2 << endl;\n\telse if (n != 1 && m == 1)cout << n - 2 << endl;\n\telse {\n\t\tll ans = (n - 2) * (m - 2);\n\t\tcout << ans << endl;\n\t}\n\treturn 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere is a grid with infinitely many rows and columns. In this grid, there is a rectangular region with consecutive N rows and M columns, and a card is placed in each square in this region.\nThe front and back sides of these cards can be distinguished, and initially every card faces up.\n\nWe will perform the following operation once for each square contains a card:\n\nFor each of the following nine squares, flip the card in it if it exists: the target square itself and the eight squares that shares a corner or a side with the target square.\n\nIt can be proved that, whether each card faces up or down after all the operations does not depend on the order the operations are performed.\nFind the number of cards that face down after all the operations.\n\nConstraints\n\n1 \\leq N,M \\leq 10^9\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\n\nOutput\n\nPrint the number of cards that face down after all the operations.\n\nSample Input 1\n\n2 2\n\nSample Output 1\n\n0\n\nWe will flip every card in any of the four operations. Thus, after all the operations, all cards face up.\n\nSample Input 2\n\n1 7\n\nSample Output 2\n\n5\n\nAfter all the operations, all cards except at both ends face down.\n\nSample Input 3\n\n314 1592\n\nSample Output 3\n\n496080", "sample_input": "2 2\n"}, "reference_outputs": ["0\n"], "source_document_id": "p03417", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere is a grid with infinitely many rows and columns. In this grid, there is a rectangular region with consecutive N rows and M columns, and a card is placed in each square in this region.\nThe front and back sides of these cards can be distinguished, and initially every card faces up.\n\nWe will perform the following operation once for each square contains a card:\n\nFor each of the following nine squares, flip the card in it if it exists: the target square itself and the eight squares that shares a corner or a side with the target square.\n\nIt can be proved that, whether each card faces up or down after all the operations does not depend on the order the operations are performed.\nFind the number of cards that face down after all the operations.\n\nConstraints\n\n1 \\leq N,M \\leq 10^9\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\n\nOutput\n\nPrint the number of cards that face down after all the operations.\n\nSample Input 1\n\n2 2\n\nSample Output 1\n\n0\n\nWe will flip every card in any of the four operations. Thus, after all the operations, all cards face up.\n\nSample Input 2\n\n1 7\n\nSample Output 2\n\n5\n\nAfter all the operations, all cards except at both ends face down.\n\nSample Input 3\n\n314 1592\n\nSample Output 3\n\n496080", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 392, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s435358185", "group_id": "codeNet:p03419", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nconst int maxn = 800;\nint main() {\n\tint n, k;\n\tunsigned long long ans = 0;\n\tcin >> n >> k;\n\tif(k == 0){\n\t\tcout << n*n;\n\t\treturn 0;\n\t}\n\tfor(int i = k + 1; i <= n; ++i){\n\t\tunsigned long long numeros = (n/i) * (i - k);\n\t\tans+= numeros;\n\t\tif(n%i) ans+= max((n%i - k + 1LL), 0LL);\n\t}\n\tcout << ans;\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1588420762, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03419.html", "problem_id": "p03419", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03419/input.txt", "sample_output_relpath": "derived/input_output/data/p03419/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03419/C++/s435358185.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s435358185", "user_id": "u380410396"}, "prompt_components": {"gold_output": "0\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nconst int maxn = 800;\nint main() {\n\tint n, k;\n\tunsigned long long ans = 0;\n\tcin >> n >> k;\n\tif(k == 0){\n\t\tcout << n*n;\n\t\treturn 0;\n\t}\n\tfor(int i = k + 1; i <= n; ++i){\n\t\tunsigned long long numeros = (n/i) * (i - k);\n\t\tans+= numeros;\n\t\tif(n%i) ans+= max((n%i - k + 1LL), 0LL);\n\t}\n\tcout << ans;\n\treturn 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere is a grid with infinitely many rows and columns. In this grid, there is a rectangular region with consecutive N rows and M columns, and a card is placed in each square in this region.\nThe front and back sides of these cards can be distinguished, and initially every card faces up.\n\nWe will perform the following operation once for each square contains a card:\n\nFor each of the following nine squares, flip the card in it if it exists: the target square itself and the eight squares that shares a corner or a side with the target square.\n\nIt can be proved that, whether each card faces up or down after all the operations does not depend on the order the operations are performed.\nFind the number of cards that face down after all the operations.\n\nConstraints\n\n1 \\leq N,M \\leq 10^9\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\n\nOutput\n\nPrint the number of cards that face down after all the operations.\n\nSample Input 1\n\n2 2\n\nSample Output 1\n\n0\n\nWe will flip every card in any of the four operations. Thus, after all the operations, all cards face up.\n\nSample Input 2\n\n1 7\n\nSample Output 2\n\n5\n\nAfter all the operations, all cards except at both ends face down.\n\nSample Input 3\n\n314 1592\n\nSample Output 3\n\n496080", "sample_input": "2 2\n"}, "reference_outputs": ["0\n"], "source_document_id": "p03419", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere is a grid with infinitely many rows and columns. In this grid, there is a rectangular region with consecutive N rows and M columns, and a card is placed in each square in this region.\nThe front and back sides of these cards can be distinguished, and initially every card faces up.\n\nWe will perform the following operation once for each square contains a card:\n\nFor each of the following nine squares, flip the card in it if it exists: the target square itself and the eight squares that shares a corner or a side with the target square.\n\nIt can be proved that, whether each card faces up or down after all the operations does not depend on the order the operations are performed.\nFind the number of cards that face down after all the operations.\n\nConstraints\n\n1 \\leq N,M \\leq 10^9\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\n\nOutput\n\nPrint the number of cards that face down after all the operations.\n\nSample Input 1\n\n2 2\n\nSample Output 1\n\n0\n\nWe will flip every card in any of the four operations. Thus, after all the operations, all cards face up.\n\nSample Input 2\n\n1 7\n\nSample Output 2\n\n5\n\nAfter all the operations, all cards except at both ends face down.\n\nSample Input 3\n\n314 1592\n\nSample Output 3\n\n496080", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 351, "cpu_time_ms": 851, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s395837962", "group_id": "codeNet:p03420", "input_text": "#include<stdio.h>\n#include<iostream>\nusing namespace std;\n\nint main(){\n        int N,K;scanf(\"%d%d\",&N,&K);\n        long long ans=0;\n\n        for(int i=K+1;i<=N;++i){\n                for(int j=0;j<=N;j+=i){\n                        ans+=max(min(N,j+i-1)-max(1,j+K)+1,0);\n                }   \n        }   \n        cout<<ans<<endl;\n}\n", "language": "C++", "metadata": {"date": 1521220824, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03420.html", "problem_id": "p03420", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03420/input.txt", "sample_output_relpath": "derived/input_output/data/p03420/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03420/C++/s395837962.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s395837962", "user_id": "u415958585"}, "prompt_components": {"gold_output": "7\n", "input_to_evaluate": "#include<stdio.h>\n#include<iostream>\nusing namespace std;\n\nint main(){\n        int N,K;scanf(\"%d%d\",&N,&K);\n        long long ans=0;\n\n        for(int i=K+1;i<=N;++i){\n                for(int j=0;j<=N;j+=i){\n                        ans+=max(min(N,j+i-1)-max(1,j+K)+1,0);\n                }   \n        }   \n        cout<<ans<<endl;\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nTakahashi had a pair of two positive integers not exceeding N, (a,b), which he has forgotten.\nHe remembers that the remainder of a divided by b was greater than or equal to K.\nFind the number of possible pairs that he may have had.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n0 \\leq K \\leq N-1\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the number of possible pairs that he may have had.\n\nSample Input 1\n\n5 2\n\nSample Output 1\n\n7\n\nThere are seven possible pairs: (2,3),(5,3),(2,4),(3,4),(2,5),(3,5) and (4,5).\n\nSample Input 2\n\n10 0\n\nSample Output 2\n\n100\n\nSample Input 3\n\n31415 9265\n\nSample Output 3\n\n287927211", "sample_input": "5 2\n"}, "reference_outputs": ["7\n"], "source_document_id": "p03420", "source_text": "Score : 400 points\n\nProblem Statement\n\nTakahashi had a pair of two positive integers not exceeding N, (a,b), which he has forgotten.\nHe remembers that the remainder of a divided by b was greater than or equal to K.\nFind the number of possible pairs that he may have had.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n0 \\leq K \\leq N-1\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the number of possible pairs that he may have had.\n\nSample Input 1\n\n5 2\n\nSample Output 1\n\n7\n\nThere are seven possible pairs: (2,3),(5,3),(2,4),(3,4),(2,5),(3,5) and (4,5).\n\nSample Input 2\n\n10 0\n\nSample Output 2\n\n100\n\nSample Input 3\n\n31415 9265\n\nSample Output 3\n\n287927211", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 331, "cpu_time_ms": 4, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s952288351", "group_id": "codeNet:p03423", "input_text": "#include <iostream>\nusing namespace std;\n\nint main(){\n\tint n;\n\tcin >> n;\n\tcout << n % 3 << endl;\n}", "language": "C++", "metadata": {"date": 1520215399, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03423.html", "problem_id": "p03423", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03423/input.txt", "sample_output_relpath": "derived/input_output/data/p03423/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03423/C++/s952288351.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s952288351", "user_id": "u833509814"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <iostream>\nusing namespace std;\n\nint main(){\n\tint n;\n\tcin >> n;\n\tcout << n % 3 << endl;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nThere are N students in a school.\n\nWe will divide these students into some groups, and in each group they will discuss some themes.\n\nYou think that groups consisting of two or less students cannot have an effective discussion, so you want to have as many groups consisting of three or more students as possible.\n\nDivide the students so that the number of groups consisting of three or more students is maximized.\n\nConstraints\n\n1 \\leq N \\leq 1000\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nIf you can form at most x groups consisting of three or more students, print x.\n\nSample Input 1\n\n8\n\nSample Output 1\n\n2\n\nFor example, you can form a group of three students and another of five students.\n\nSample Input 2\n\n2\n\nSample Output 2\n\n0\n\nSometimes you cannot form any group consisting of three or more students, regardless of how you divide the students.\n\nSample Input 3\n\n9\n\nSample Output 3\n\n3", "sample_input": "8\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03423", "source_text": "Score : 100 points\n\nProblem Statement\n\nThere are N students in a school.\n\nWe will divide these students into some groups, and in each group they will discuss some themes.\n\nYou think that groups consisting of two or less students cannot have an effective discussion, so you want to have as many groups consisting of three or more students as possible.\n\nDivide the students so that the number of groups consisting of three or more students is maximized.\n\nConstraints\n\n1 \\leq N \\leq 1000\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nIf you can form at most x groups consisting of three or more students, print x.\n\nSample Input 1\n\n8\n\nSample Output 1\n\n2\n\nFor example, you can form a group of three students and another of five students.\n\nSample Input 2\n\n2\n\nSample Output 2\n\n0\n\nSometimes you cannot form any group consisting of three or more students, regardless of how you divide the students.\n\nSample Input 3\n\n9\n\nSample Output 3\n\n3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 98, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s253763423", "group_id": "codeNet:p03424", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n  string s;\n  int n,f=0,r[2];\n  \n  cin >> n;\n  for(int i=1;i<=n;i++){\n    cin >> s[i];\n  }\n  \n  for(int t=1;t<=n;t++){\n    r[1]=0;\n    r[2]=0;\n    for(int u=0;u<=t-1;u++){\n      if(s[t]==s[u]){\n        r[1]=1;\n      }\n      else{\n        r[2]=1;\n      }\n    }\n    \n    if(r[1]==0&&r[2]==1){\n      f++;\n    }\n    else{\n      f=f;\n    }\n  }\n    \n    if(f==3){\n      cout << \"three\" << endl;\n    }\n    else{\n      cout << \"four\" << endl;\n    }\n  \n}", "language": "C++", "metadata": {"date": 1583985563, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03424.html", "problem_id": "p03424", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03424/input.txt", "sample_output_relpath": "derived/input_output/data/p03424/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03424/C++/s253763423.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s253763423", "user_id": "u793627400"}, "prompt_components": {"gold_output": "Four\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n  string s;\n  int n,f=0,r[2];\n  \n  cin >> n;\n  for(int i=1;i<=n;i++){\n    cin >> s[i];\n  }\n  \n  for(int t=1;t<=n;t++){\n    r[1]=0;\n    r[2]=0;\n    for(int u=0;u<=t-1;u++){\n      if(s[t]==s[u]){\n        r[1]=1;\n      }\n      else{\n        r[2]=1;\n      }\n    }\n    \n    if(r[1]==0&&r[2]==1){\n      f++;\n    }\n    else{\n      f=f;\n    }\n  }\n    \n    if(f==3){\n      cout << \"three\" << endl;\n    }\n    else{\n      cout << \"four\" << endl;\n    }\n  \n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nIn Japan, people make offerings called hina arare, colorful crackers, on March 3.\n\nWe have a bag that contains N hina arare. (From here, we call them arare.)\n\nIt is known that the bag either contains arare in three colors: pink, white and green, or contains arare in four colors: pink, white, green and yellow.\n\nWe have taken out the arare in the bag one by one, and the color of the i-th arare was S_i, where colors are represented as follows - pink: P, white: W, green: G, yellow: Y.\n\nIf the number of colors of the arare in the bag was three, print Three; if the number of colors was four, print Four.\n\nConstraints\n\n1 \\leq N \\leq 100\n\nS_i is P, W, G or Y.\n\nThere always exist i, j and k such that S_i=P, S_j=W and S_k=G.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS_1 S_2 ... S_N\n\nOutput\n\nIf the number of colors of the arare in the bag was three, print Three; if the number of colors was four, print Four.\n\nSample Input 1\n\n6\nG W Y P Y W\n\nSample Output 1\n\nFour\n\nThe bag contained arare in four colors, so you should print Four.\n\nSample Input 2\n\n9\nG W W G P W P G G\n\nSample Output 2\n\nThree\n\nThe bag contained arare in three colors, so you should print Three.\n\nSample Input 3\n\n8\nP Y W G Y W Y Y\n\nSample Output 3\n\nFour", "sample_input": "6\nG W Y P Y W\n"}, "reference_outputs": ["Four\n"], "source_document_id": "p03424", "source_text": "Score : 200 points\n\nProblem Statement\n\nIn Japan, people make offerings called hina arare, colorful crackers, on March 3.\n\nWe have a bag that contains N hina arare. (From here, we call them arare.)\n\nIt is known that the bag either contains arare in three colors: pink, white and green, or contains arare in four colors: pink, white, green and yellow.\n\nWe have taken out the arare in the bag one by one, and the color of the i-th arare was S_i, where colors are represented as follows - pink: P, white: W, green: G, yellow: Y.\n\nIf the number of colors of the arare in the bag was three, print Three; if the number of colors was four, print Four.\n\nConstraints\n\n1 \\leq N \\leq 100\n\nS_i is P, W, G or Y.\n\nThere always exist i, j and k such that S_i=P, S_j=W and S_k=G.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS_1 S_2 ... S_N\n\nOutput\n\nIf the number of colors of the arare in the bag was three, print Three; if the number of colors was four, print Four.\n\nSample Input 1\n\n6\nG W Y P Y W\n\nSample Output 1\n\nFour\n\nThe bag contained arare in four colors, so you should print Four.\n\nSample Input 2\n\n9\nG W W G P W P G G\n\nSample Output 2\n\nThree\n\nThe bag contained arare in three colors, so you should print Three.\n\nSample Input 3\n\n8\nP Y W G Y W Y Y\n\nSample Output 3\n\nFour", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 505, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s866118544", "group_id": "codeNet:p03425", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main() {\n int N;\n cin >> N;\n\n string S;\n vector<long long> ch_num(5);\n for(int i = 0; i < N; i++) {\n   cin >> S;\n   if(S.at(0) == 'M') ch_num.at(0)++;\n   else if(S.at(0) == 'A') ch_num.at(1)++;\n   else if(S.at(0) == 'R') ch_num.at(2)++;\n   else if(S.at(0) == 'C') ch_num.at(3)++;\n   else if(S.at(0) == 'H') ch_num.at(4)++;\n }\n\n long long ans = 0;\n for(int i = 0; i < 3; i++) {\n   for(int j = i + 1;j < 4; j++) {\n     for(int k = j + 1;k < 5;k++) {\n       ans += ch_num.at(i) * ch_num.at(j) * ch_num.at(k);\n     }\n   }\n }\n\ncout << ans << endl;\n\n}\n\n", "language": "C++", "metadata": {"date": 1560630551, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03425.html", "problem_id": "p03425", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03425/input.txt", "sample_output_relpath": "derived/input_output/data/p03425/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03425/C++/s866118544.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s866118544", "user_id": "u372299304"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main() {\n int N;\n cin >> N;\n\n string S;\n vector<long long> ch_num(5);\n for(int i = 0; i < N; i++) {\n   cin >> S;\n   if(S.at(0) == 'M') ch_num.at(0)++;\n   else if(S.at(0) == 'A') ch_num.at(1)++;\n   else if(S.at(0) == 'R') ch_num.at(2)++;\n   else if(S.at(0) == 'C') ch_num.at(3)++;\n   else if(S.at(0) == 'H') ch_num.at(4)++;\n }\n\n long long ans = 0;\n for(int i = 0; i < 3; i++) {\n   for(int j = i + 1;j < 4; j++) {\n     for(int k = j + 1;k < 5;k++) {\n       ans += ch_num.at(i) * ch_num.at(j) * ch_num.at(k);\n     }\n   }\n }\n\ncout << ans << endl;\n\n}\n\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N people. The name of the i-th person is S_i.\n\nWe would like to choose three people so that the following conditions are met:\n\nThe name of every chosen person begins with M, A, R, C or H.\n\nThere are no multiple people whose names begin with the same letter.\n\nHow many such ways are there to choose three people, disregarding order?\n\nNote that the answer may not fit into a 32-bit integer type.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\nS_i consists of uppercase English letters.\n\n1 \\leq |S_i| \\leq 10\n\nS_i \\neq S_j (i \\neq j)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS_1\n:\nS_N\n\nOutput\n\nIf there are x ways to choose three people so that the given conditions are met, print x.\n\nSample Input 1\n\n5\nMASHIKE\nRUMOI\nOBIRA\nHABORO\nHOROKANAI\n\nSample Output 1\n\n2\n\nWe can choose three people with the following names:\n\nMASHIKE, RUMOI, HABORO\n\nMASHIKE, RUMOI, HOROKANAI\n\nThus, we have two ways.\n\nSample Input 2\n\n4\nZZ\nZZZ\nZ\nZZZZZZZZZZ\n\nSample Output 2\n\n0\n\nNote that there may be no ways to choose three people so that the given conditions are met.\n\nSample Input 3\n\n5\nCHOKUDAI\nRNG\nMAKOTO\nAOKI\nRINGO\n\nSample Output 3\n\n7", "sample_input": "5\nMASHIKE\nRUMOI\nOBIRA\nHABORO\nHOROKANAI\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03425", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N people. The name of the i-th person is S_i.\n\nWe would like to choose three people so that the following conditions are met:\n\nThe name of every chosen person begins with M, A, R, C or H.\n\nThere are no multiple people whose names begin with the same letter.\n\nHow many such ways are there to choose three people, disregarding order?\n\nNote that the answer may not fit into a 32-bit integer type.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\nS_i consists of uppercase English letters.\n\n1 \\leq |S_i| \\leq 10\n\nS_i \\neq S_j (i \\neq j)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nS_1\n:\nS_N\n\nOutput\n\nIf there are x ways to choose three people so that the given conditions are met, print x.\n\nSample Input 1\n\n5\nMASHIKE\nRUMOI\nOBIRA\nHABORO\nHOROKANAI\n\nSample Output 1\n\n2\n\nWe can choose three people with the following names:\n\nMASHIKE, RUMOI, HABORO\n\nMASHIKE, RUMOI, HOROKANAI\n\nThus, we have two ways.\n\nSample Input 2\n\n4\nZZ\nZZZ\nZ\nZZZZZZZZZZ\n\nSample Output 2\n\n0\n\nNote that there may be no ways to choose three people so that the given conditions are met.\n\nSample Input 3\n\n5\nCHOKUDAI\nRNG\nMAKOTO\nAOKI\nRINGO\n\nSample Output 3\n\n7", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 597, "cpu_time_ms": 36, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s069309839", "group_id": "codeNet:p03426", "input_text": "#include<algorithm>\n#include<cmath>\n#include<iomanip>\n#include<iostream>\n#include<map>\n#include<numeric>\n#include<queue>\n#include<set>\n#include<sstream>\n#include<unordered_map>\n#include<unordered_set>\n#include<vector>\nusing ll = long long;\nenum : int { M = (int)1e9 + 7 };\nenum : ll { MLL = (ll)1e18L + 9 };\nusing namespace std;\n#ifdef LOCAL\n#include\"rprint2.hpp\"\n#include\"debug_deque.hpp\"\n#define vector DebugDeque\n#else\n#define FUNC(name) template <ostream& out = cout, class... T> void name(T&&...){ }\nFUNC(prints) FUNC(printe) FUNC(printw) FUNC(printew) FUNC(printb) FUNC(printd) FUNC(printde);\n#endif\ntemplate <class S, class T>\nistream& operator >> (istream& in, pair<S, T>& p){ in >> p.first >> p.second; return in; }\ntemplate <class T>\nistream& operator >> (istream& in, vector<T>& v){ for(auto& e : v){ in >> e; } return in; }\ntemplate <char d = ' ', class T>\nostream& operator << (ostream& out, vector<T>& v){ for(auto& e : v){ out << e << d; } return out; }\n\nint main(){\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n    int h, w, d;\n    cin >> h >> w >> d;\n    vector<pair<int, int>> poss(h * w);\n    for(int i = 0; i < h; i++){\n        for(int j = 0; j < w; j++){\n            int a; cin >> a;\n            a--;\n            poss[a] = {i, j};\n        }\n    }\n    vector<vector<ll>> lens(h * w, vector<ll>(20));\n    for(int i = 0; i < h * w; i++){\n        if(i + d >= h * w){ continue; }\n        lens[i][0] = abs(poss[i].first - poss[i + d].first) + abs(poss[i].second - poss[i + d].second);\n    }\n    for(int i = 0; i < h * w; i++){\n        for(int j = 1; j < 20; j++){\n            if(i + d * (1ll << j) >= h * w){ continue; }\n            ll i2 = i + d * (1 << (j - 1));\n            lens[i][j] = lens[i][j - 1] + lens[i2][j - 1];\n        }\n    }\n    int q; cin >> q;\n    for(int i = 0; i < q; i++){\n        int l, r;\n        cin >> l >> r;\n        l--; r--;\n        ll ans = 0;\n        while(l != r){\n            int len = (r - l) / d;\n            int lsb;\n            for(lsb = 0; (len & (1 << lsb)) == 0; lsb++){ }\n            ans += lens[l][lsb];\n            l += d * (1 << lsb);\n        }\n        cout << ans << '\\n';\n    }\n}\n", "language": "C++", "metadata": {"date": 1520220709, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03426.html", "problem_id": "p03426", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03426/input.txt", "sample_output_relpath": "derived/input_output/data/p03426/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03426/C++/s069309839.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s069309839", "user_id": "u817722036"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include<algorithm>\n#include<cmath>\n#include<iomanip>\n#include<iostream>\n#include<map>\n#include<numeric>\n#include<queue>\n#include<set>\n#include<sstream>\n#include<unordered_map>\n#include<unordered_set>\n#include<vector>\nusing ll = long long;\nenum : int { M = (int)1e9 + 7 };\nenum : ll { MLL = (ll)1e18L + 9 };\nusing namespace std;\n#ifdef LOCAL\n#include\"rprint2.hpp\"\n#include\"debug_deque.hpp\"\n#define vector DebugDeque\n#else\n#define FUNC(name) template <ostream& out = cout, class... T> void name(T&&...){ }\nFUNC(prints) FUNC(printe) FUNC(printw) FUNC(printew) FUNC(printb) FUNC(printd) FUNC(printde);\n#endif\ntemplate <class S, class T>\nistream& operator >> (istream& in, pair<S, T>& p){ in >> p.first >> p.second; return in; }\ntemplate <class T>\nistream& operator >> (istream& in, vector<T>& v){ for(auto& e : v){ in >> e; } return in; }\ntemplate <char d = ' ', class T>\nostream& operator << (ostream& out, vector<T>& v){ for(auto& e : v){ out << e << d; } return out; }\n\nint main(){\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n    int h, w, d;\n    cin >> h >> w >> d;\n    vector<pair<int, int>> poss(h * w);\n    for(int i = 0; i < h; i++){\n        for(int j = 0; j < w; j++){\n            int a; cin >> a;\n            a--;\n            poss[a] = {i, j};\n        }\n    }\n    vector<vector<ll>> lens(h * w, vector<ll>(20));\n    for(int i = 0; i < h * w; i++){\n        if(i + d >= h * w){ continue; }\n        lens[i][0] = abs(poss[i].first - poss[i + d].first) + abs(poss[i].second - poss[i + d].second);\n    }\n    for(int i = 0; i < h * w; i++){\n        for(int j = 1; j < 20; j++){\n            if(i + d * (1ll << j) >= h * w){ continue; }\n            ll i2 = i + d * (1 << (j - 1));\n            lens[i][j] = lens[i][j - 1] + lens[i2][j - 1];\n        }\n    }\n    int q; cin >> q;\n    for(int i = 0; i < q; i++){\n        int l, r;\n        cin >> l >> r;\n        l--; r--;\n        ll ans = 0;\n        while(l != r){\n            int len = (r - l) / d;\n            int lsb;\n            for(lsb = 0; (len & (1 << lsb)) == 0; lsb++){ }\n            ans += lens[l][lsb];\n            l += d * (1 << lsb);\n        }\n        cout << ans << '\\n';\n    }\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nWe have a grid with H rows and W columns. The square at the i-th row and the j-th column will be called Square (i,j).\n\nThe integers from 1 through H×W are written throughout the grid, and the integer written in Square (i,j) is A_{i,j}.\n\nYou, a magical girl, can teleport a piece placed on Square (i,j) to Square (x,y) by consuming |x-i|+|y-j| magic points.\n\nYou now have to take Q practical tests of your ability as a magical girl.\n\nThe i-th test will be conducted as follows:\n\nInitially, a piece is placed on the square where the integer L_i is written.\n\nLet x be the integer written in the square occupied by the piece. Repeatedly move the piece to the square where the integer x+D is written, as long as x is not R_i. The test ends when x=R_i.\n\nHere, it is guaranteed that R_i-L_i is a multiple of D.\n\nFor each test, find the sum of magic points consumed during that test.\n\nConstraints\n\n1 \\leq H,W \\leq 300\n\n1 \\leq D \\leq H×W\n\n1 \\leq A_{i,j} \\leq H×W\n\nA_{i,j} \\neq A_{x,y} ((i,j) \\neq (x,y))\n\n1 \\leq Q \\leq 10^5\n\n1 \\leq L_i \\leq R_i \\leq H×W\n\n(R_i-L_i) is a multiple of D.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W D\nA_{1,1} A_{1,2} ... A_{1,W}\n:\nA_{H,1} A_{H,2} ... A_{H,W}\nQ\nL_1 R_1\n:\nL_Q R_Q\n\nOutput\n\nFor each test, print the sum of magic points consumed during that test.\n\nOutput should be in the order the tests are conducted.\n\nSample Input 1\n\n3 3 2\n1 4 3\n2 5 7\n8 9 6\n1\n4 8\n\nSample Output 1\n\n5\n\n4 is written in Square (1,2).\n\n6 is written in Square (3,3).\n\n8 is written in Square (3,1).\n\nThus, the sum of magic points consumed during the first test is (|3-1|+|3-2|)+(|3-3|+|1-3|)=5.\n\nSample Input 2\n\n4 2 3\n3 7\n1 4\n5 2\n6 8\n2\n2 2\n2 2\n\nSample Output 2\n\n0\n0\n\nNote that there may be a test where the piece is not moved at all, and there may be multiple identical tests.\n\nSample Input 3\n\n5 5 4\n13 25 7 15 17\n16 22 20 2 9\n14 11 12 1 19\n10 6 23 8 18\n3 21 5 24 4\n3\n13 13\n2 10\n13 13\n\nSample Output 3\n\n0\n5\n0", "sample_input": "3 3 2\n1 4 3\n2 5 7\n8 9 6\n1\n4 8\n"}, "reference_outputs": ["5\n"], "source_document_id": "p03426", "source_text": "Score : 400 points\n\nProblem Statement\n\nWe have a grid with H rows and W columns. The square at the i-th row and the j-th column will be called Square (i,j).\n\nThe integers from 1 through H×W are written throughout the grid, and the integer written in Square (i,j) is A_{i,j}.\n\nYou, a magical girl, can teleport a piece placed on Square (i,j) to Square (x,y) by consuming |x-i|+|y-j| magic points.\n\nYou now have to take Q practical tests of your ability as a magical girl.\n\nThe i-th test will be conducted as follows:\n\nInitially, a piece is placed on the square where the integer L_i is written.\n\nLet x be the integer written in the square occupied by the piece. Repeatedly move the piece to the square where the integer x+D is written, as long as x is not R_i. The test ends when x=R_i.\n\nHere, it is guaranteed that R_i-L_i is a multiple of D.\n\nFor each test, find the sum of magic points consumed during that test.\n\nConstraints\n\n1 \\leq H,W \\leq 300\n\n1 \\leq D \\leq H×W\n\n1 \\leq A_{i,j} \\leq H×W\n\nA_{i,j} \\neq A_{x,y} ((i,j) \\neq (x,y))\n\n1 \\leq Q \\leq 10^5\n\n1 \\leq L_i \\leq R_i \\leq H×W\n\n(R_i-L_i) is a multiple of D.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W D\nA_{1,1} A_{1,2} ... A_{1,W}\n:\nA_{H,1} A_{H,2} ... A_{H,W}\nQ\nL_1 R_1\n:\nL_Q R_Q\n\nOutput\n\nFor each test, print the sum of magic points consumed during that test.\n\nOutput should be in the order the tests are conducted.\n\nSample Input 1\n\n3 3 2\n1 4 3\n2 5 7\n8 9 6\n1\n4 8\n\nSample Output 1\n\n5\n\n4 is written in Square (1,2).\n\n6 is written in Square (3,3).\n\n8 is written in Square (3,1).\n\nThus, the sum of magic points consumed during the first test is (|3-1|+|3-2|)+(|3-3|+|1-3|)=5.\n\nSample Input 2\n\n4 2 3\n3 7\n1 4\n5 2\n6 8\n2\n2 2\n2 2\n\nSample Output 2\n\n0\n0\n\nNote that there may be a test where the piece is not moved at all, and there may be multiple identical tests.\n\nSample Input 3\n\n5 5 4\n13 25 7 15 17\n16 22 20 2 9\n14 11 12 1 19\n10 6 23 8 18\n3 21 5 24 4\n3\n13 13\n2 10\n13 13\n\nSample Output 3\n\n0\n5\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2143, "cpu_time_ms": 73, "memory_kb": 19072}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s962214009", "group_id": "codeNet:p03426", "input_text": "#include<iostream>\n#include<cstdio>\n#include<cmath>\ntypedef long long ll;\nconst int N=305;\nint h,w,d,row[N*N],col[N*N],a[N][N];\nll dp[N*N];\nint main() {\n    scanf(\"%d%d%d\",&h,&w,&d);\n    for(int i=1;i<=h;i++) for(int j=1;j<=w;j++) scanf(\"%d\",a[i]+j),row[a[i][j]]=i,col[a[i][j]]=j;\n    for(int i=1;i<=h*w;i++) if(i<=d) dp[i]=0;else dp[i]=dp[i-d]+abs(row[i]-row[i-d])+abs(col[i]-col[i-d]);\n    int q,l,r;scanf(\"%d\",&q);\n    while(q--) {\n        scanf(\"%d%d\",&l,&r);\n        printf(\"%lld\\n\",dp[r]-dp[l]);\n    }\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1520219637, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03426.html", "problem_id": "p03426", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03426/input.txt", "sample_output_relpath": "derived/input_output/data/p03426/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03426/C++/s962214009.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s962214009", "user_id": "u687201420"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include<iostream>\n#include<cstdio>\n#include<cmath>\ntypedef long long ll;\nconst int N=305;\nint h,w,d,row[N*N],col[N*N],a[N][N];\nll dp[N*N];\nint main() {\n    scanf(\"%d%d%d\",&h,&w,&d);\n    for(int i=1;i<=h;i++) for(int j=1;j<=w;j++) scanf(\"%d\",a[i]+j),row[a[i][j]]=i,col[a[i][j]]=j;\n    for(int i=1;i<=h*w;i++) if(i<=d) dp[i]=0;else dp[i]=dp[i-d]+abs(row[i]-row[i-d])+abs(col[i]-col[i-d]);\n    int q,l,r;scanf(\"%d\",&q);\n    while(q--) {\n        scanf(\"%d%d\",&l,&r);\n        printf(\"%lld\\n\",dp[r]-dp[l]);\n    }\n    return 0;\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nWe have a grid with H rows and W columns. The square at the i-th row and the j-th column will be called Square (i,j).\n\nThe integers from 1 through H×W are written throughout the grid, and the integer written in Square (i,j) is A_{i,j}.\n\nYou, a magical girl, can teleport a piece placed on Square (i,j) to Square (x,y) by consuming |x-i|+|y-j| magic points.\n\nYou now have to take Q practical tests of your ability as a magical girl.\n\nThe i-th test will be conducted as follows:\n\nInitially, a piece is placed on the square where the integer L_i is written.\n\nLet x be the integer written in the square occupied by the piece. Repeatedly move the piece to the square where the integer x+D is written, as long as x is not R_i. The test ends when x=R_i.\n\nHere, it is guaranteed that R_i-L_i is a multiple of D.\n\nFor each test, find the sum of magic points consumed during that test.\n\nConstraints\n\n1 \\leq H,W \\leq 300\n\n1 \\leq D \\leq H×W\n\n1 \\leq A_{i,j} \\leq H×W\n\nA_{i,j} \\neq A_{x,y} ((i,j) \\neq (x,y))\n\n1 \\leq Q \\leq 10^5\n\n1 \\leq L_i \\leq R_i \\leq H×W\n\n(R_i-L_i) is a multiple of D.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W D\nA_{1,1} A_{1,2} ... A_{1,W}\n:\nA_{H,1} A_{H,2} ... A_{H,W}\nQ\nL_1 R_1\n:\nL_Q R_Q\n\nOutput\n\nFor each test, print the sum of magic points consumed during that test.\n\nOutput should be in the order the tests are conducted.\n\nSample Input 1\n\n3 3 2\n1 4 3\n2 5 7\n8 9 6\n1\n4 8\n\nSample Output 1\n\n5\n\n4 is written in Square (1,2).\n\n6 is written in Square (3,3).\n\n8 is written in Square (3,1).\n\nThus, the sum of magic points consumed during the first test is (|3-1|+|3-2|)+(|3-3|+|1-3|)=5.\n\nSample Input 2\n\n4 2 3\n3 7\n1 4\n5 2\n6 8\n2\n2 2\n2 2\n\nSample Output 2\n\n0\n0\n\nNote that there may be a test where the piece is not moved at all, and there may be multiple identical tests.\n\nSample Input 3\n\n5 5 4\n13 25 7 15 17\n16 22 20 2 9\n14 11 12 1 19\n10 6 23 8 18\n3 21 5 24 4\n3\n13 13\n2 10\n13 13\n\nSample Output 3\n\n0\n5\n0", "sample_input": "3 3 2\n1 4 3\n2 5 7\n8 9 6\n1\n4 8\n"}, "reference_outputs": ["5\n"], "source_document_id": "p03426", "source_text": "Score : 400 points\n\nProblem Statement\n\nWe have a grid with H rows and W columns. The square at the i-th row and the j-th column will be called Square (i,j).\n\nThe integers from 1 through H×W are written throughout the grid, and the integer written in Square (i,j) is A_{i,j}.\n\nYou, a magical girl, can teleport a piece placed on Square (i,j) to Square (x,y) by consuming |x-i|+|y-j| magic points.\n\nYou now have to take Q practical tests of your ability as a magical girl.\n\nThe i-th test will be conducted as follows:\n\nInitially, a piece is placed on the square where the integer L_i is written.\n\nLet x be the integer written in the square occupied by the piece. Repeatedly move the piece to the square where the integer x+D is written, as long as x is not R_i. The test ends when x=R_i.\n\nHere, it is guaranteed that R_i-L_i is a multiple of D.\n\nFor each test, find the sum of magic points consumed during that test.\n\nConstraints\n\n1 \\leq H,W \\leq 300\n\n1 \\leq D \\leq H×W\n\n1 \\leq A_{i,j} \\leq H×W\n\nA_{i,j} \\neq A_{x,y} ((i,j) \\neq (x,y))\n\n1 \\leq Q \\leq 10^5\n\n1 \\leq L_i \\leq R_i \\leq H×W\n\n(R_i-L_i) is a multiple of D.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W D\nA_{1,1} A_{1,2} ... A_{1,W}\n:\nA_{H,1} A_{H,2} ... A_{H,W}\nQ\nL_1 R_1\n:\nL_Q R_Q\n\nOutput\n\nFor each test, print the sum of magic points consumed during that test.\n\nOutput should be in the order the tests are conducted.\n\nSample Input 1\n\n3 3 2\n1 4 3\n2 5 7\n8 9 6\n1\n4 8\n\nSample Output 1\n\n5\n\n4 is written in Square (1,2).\n\n6 is written in Square (3,3).\n\n8 is written in Square (3,1).\n\nThus, the sum of magic points consumed during the first test is (|3-1|+|3-2|)+(|3-3|+|1-3|)=5.\n\nSample Input 2\n\n4 2 3\n3 7\n1 4\n5 2\n6 8\n2\n2 2\n2 2\n\nSample Output 2\n\n0\n0\n\nNote that there may be a test where the piece is not moved at all, and there may be multiple identical tests.\n\nSample Input 3\n\n5 5 4\n13 25 7 15 17\n16 22 20 2 9\n14 11 12 1 19\n10 6 23 8 18\n3 21 5 24 4\n3\n13 13\n2 10\n13 13\n\nSample Output 3\n\n0\n5\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 524, "cpu_time_ms": 39, "memory_kb": 2944}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s165387863", "group_id": "codeNet:p03427", "input_text": "#include <iostream>\n#include <vector>\n#include <algorithm>\n\nint main() {\n  std::vector<int> ary(17);\n  unsigned long N;\n  int len = 0;\n  std::cin >> N;\n  for (int i = 0; i < 17; i++) {\n    ary[i] = (int) (N % 10);\n    N /= 10;\n    len++;\n    if (N == 0) break;\n  }\n\n  int max = 0;\n  for (int i = 0; i < len; i++) {\n    int sum = 0;\n    for (int j = 0; j < len; j++) {\n      sum += ary[j];\n    }\n    max = std::max(max, sum);\n    if (ary[i] != 9) {\n      ary[i] = 9;\n      for (int j = i + 1; j < len; j++) {\n        if (ary[j] != 0) {\n          ary[j]--;\n          break;\n        } else ary[j] = 9;\n      }\n    }\n  }\n\n  std::cout << max;\n\n  return 0;\n}", "language": "C++", "metadata": {"date": 1519526025, "filename_ext": "cpp", "original_language": "C++14 (Clang 3.8.0)", "problem_description_relpath": "problem_descriptions/p03427.html", "problem_id": "p03427", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03427/input.txt", "sample_output_relpath": "derived/input_output/data/p03427/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03427/C++/s165387863.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s165387863", "user_id": "u235250102"}, "prompt_components": {"gold_output": "18\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\n#include <algorithm>\n\nint main() {\n  std::vector<int> ary(17);\n  unsigned long N;\n  int len = 0;\n  std::cin >> N;\n  for (int i = 0; i < 17; i++) {\n    ary[i] = (int) (N % 10);\n    N /= 10;\n    len++;\n    if (N == 0) break;\n  }\n\n  int max = 0;\n  for (int i = 0; i < len; i++) {\n    int sum = 0;\n    for (int j = 0; j < len; j++) {\n      sum += ary[j];\n    }\n    max = std::max(max, sum);\n    if (ary[i] != 9) {\n      ary[i] = 9;\n      for (int j = i + 1; j < len; j++) {\n        if (ary[j] != 0) {\n          ary[j]--;\n          break;\n        } else ary[j] = 9;\n      }\n    }\n  }\n\n  std::cout << max;\n\n  return 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nFind the maximum possible sum of the digits (in base 10) of a positive integer not greater than N.\n\nConstraints\n\n1\\leq N \\leq 10^{16}\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the maximum possible sum of the digits (in base 10) of a positive integer not greater than N.\n\nSample Input 1\n\n100\n\nSample Output 1\n\n18\n\nFor example, the sum of the digits in 99 is 18, which turns out to be the maximum value.\n\nSample Input 2\n\n9995\n\nSample Output 2\n\n35\n\nFor example, the sum of the digits in 9989 is 35, which turns out to be the maximum value.\n\nSample Input 3\n\n3141592653589793\n\nSample Output 3\n\n137", "sample_input": "100\n"}, "reference_outputs": ["18\n"], "source_document_id": "p03427", "source_text": "Score : 300 points\n\nProblem Statement\n\nFind the maximum possible sum of the digits (in base 10) of a positive integer not greater than N.\n\nConstraints\n\n1\\leq N \\leq 10^{16}\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the maximum possible sum of the digits (in base 10) of a positive integer not greater than N.\n\nSample Input 1\n\n100\n\nSample Output 1\n\n18\n\nFor example, the sum of the digits in 99 is 18, which turns out to be the maximum value.\n\nSample Input 2\n\n9995\n\nSample Output 2\n\n35\n\nFor example, the sum of the digits in 9989 is 35, which turns out to be the maximum value.\n\nSample Input 3\n\n3141592653589793\n\nSample Output 3\n\n137", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 652, "cpu_time_ms": 6, "memory_kb": 888}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s441827326", "group_id": "codeNet:p03429", "input_text": "#include<stdio.h>\n#include<string>\n#include<math.h>\n#include<stdlib.h>\n#include<set>\n#include<bitset>\n#include<map>\n#include<vector>\n#include<string.h>\n#include<algorithm>\n#include<iostream>\n#include<queue>\n#include<deque>\n#include<stack>\n#include<cmath>\n#include<ctime>\n#include<complex>\n#include<list>\nusing namespace std;\n\nint n,m,A,B,n1,m1,q;\nchar ans[1005][1005];\n\nint main(){\n\tcin>>n>>m>>A>>B;\n\tfor(int i=0;i<n;i++) for(int j=0;j<m;j++) ans[i][j]='.';\n\tn1=n;\n\tm1=m;\n\twhile(A&&B&&n1>=2&&m1>=2){\n\t\tint i=0;\n\t\twhile(A&&i+1<m1){\n\t\t\tans[q][q+i]='<';\n\t\t\tans[q][q+i+1]='>';\n\t\t\ti+=2;\n\t\t\tA--;\n\t\t}\n\t\tif(!A) break;\n\t\tif(i==m1) i=1;\n\t\telse i=0;\n\t\twhile(B&&i+1<n1){\n\t\t\tans[i+q][m-1-q]='^';\n\t\t\tans[i+q+1][m-1-q]='v';\n\t\t\ti+=2;\n\t\t\tB--;\n\t\t}\n\t\tif(!B) break;\n\t\tif(i==n1) i=1;\n\t\telse i=0;\n\t\twhile(A&&i+1<m1){\n\t\t\tans[n-q-1][m-q-1-i]='>';\n\t\t\tans[n-q-1][m-q-2-i]='<';\n\t\t\ti+=2;\n\t\t\tA--;\n\t\t}\n\t\tif(!A) break;\n\t\tif(i==m1) i=1;\n\t\telse i=0;\n\t\twhile(B&&i+1<n1){\n\t\t\tans[n-1-q-i][q]='v';\n\t\t\tans[n-2-q-i][q]='^';\n\t\t\ti+=2;\n\t\t\tB--;\n\t\t}\n\t\tq++;\n\t\tn1-=2;\n\t\tm1-=2;\n\t}\n\tif(A){\n\t\tfor(int i=0;i<n;i++)\n\t\t\tif(A) for(int j=0;j<m-1;j++)\n\t\t\t\tif(A){\n\t\t\t\t\tif(ans[i][j]=='.'&&ans[i][j+1]=='.'){\n\t\t\t\t\t\tans[i][j]='<';\n\t\t\t\t\t\tans[i][j+1]='>';\n\t\t\t\t\t\tA--;\n\t\t\t\t\t}\n\t\t\t\t}else break;\n\t\t\telse break;\n\t}\n\tif(B){\n\t\tfor(int i=0;i<n-1;i++)\n\t\t\tif(B) for(int j=0;j<m;j++)\n\t\t\t\tif(B){\n\t\t\t\t\tif(ans[i][j]=='.'&&ans[i+1][j]=='.'){\n\t\t\t\t\t\tans[i][j]='^';\n\t\t\t\t\t\tans[i+1][j]='v';\n\t\t\t\t\t\tB--;\n\t\t\t\t\t}\n\t\t\t\t}else break;\n\t\t\telse break;\n\t}\n\tif(A||B){\n\t\tcout<<\"NO\"<<endl;\n\t\treturn 0;\n\t}\n\tcout<<\"YES\"<<endl;\n\tfor(int i=0;i<n;i++){\n\t\tfor(int j=0;j<m;j++) cout<<ans[i][j];\n\t\tcout<<endl;\n\t}\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1519527977, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03429.html", "problem_id": "p03429", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03429/input.txt", "sample_output_relpath": "derived/input_output/data/p03429/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03429/C++/s441827326.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s441827326", "user_id": "u986620720"}, "prompt_components": {"gold_output": "YES\n<><>\n^<>^\nv<>v\n", "input_to_evaluate": "#include<stdio.h>\n#include<string>\n#include<math.h>\n#include<stdlib.h>\n#include<set>\n#include<bitset>\n#include<map>\n#include<vector>\n#include<string.h>\n#include<algorithm>\n#include<iostream>\n#include<queue>\n#include<deque>\n#include<stack>\n#include<cmath>\n#include<ctime>\n#include<complex>\n#include<list>\nusing namespace std;\n\nint n,m,A,B,n1,m1,q;\nchar ans[1005][1005];\n\nint main(){\n\tcin>>n>>m>>A>>B;\n\tfor(int i=0;i<n;i++) for(int j=0;j<m;j++) ans[i][j]='.';\n\tn1=n;\n\tm1=m;\n\twhile(A&&B&&n1>=2&&m1>=2){\n\t\tint i=0;\n\t\twhile(A&&i+1<m1){\n\t\t\tans[q][q+i]='<';\n\t\t\tans[q][q+i+1]='>';\n\t\t\ti+=2;\n\t\t\tA--;\n\t\t}\n\t\tif(!A) break;\n\t\tif(i==m1) i=1;\n\t\telse i=0;\n\t\twhile(B&&i+1<n1){\n\t\t\tans[i+q][m-1-q]='^';\n\t\t\tans[i+q+1][m-1-q]='v';\n\t\t\ti+=2;\n\t\t\tB--;\n\t\t}\n\t\tif(!B) break;\n\t\tif(i==n1) i=1;\n\t\telse i=0;\n\t\twhile(A&&i+1<m1){\n\t\t\tans[n-q-1][m-q-1-i]='>';\n\t\t\tans[n-q-1][m-q-2-i]='<';\n\t\t\ti+=2;\n\t\t\tA--;\n\t\t}\n\t\tif(!A) break;\n\t\tif(i==m1) i=1;\n\t\telse i=0;\n\t\twhile(B&&i+1<n1){\n\t\t\tans[n-1-q-i][q]='v';\n\t\t\tans[n-2-q-i][q]='^';\n\t\t\ti+=2;\n\t\t\tB--;\n\t\t}\n\t\tq++;\n\t\tn1-=2;\n\t\tm1-=2;\n\t}\n\tif(A){\n\t\tfor(int i=0;i<n;i++)\n\t\t\tif(A) for(int j=0;j<m-1;j++)\n\t\t\t\tif(A){\n\t\t\t\t\tif(ans[i][j]=='.'&&ans[i][j+1]=='.'){\n\t\t\t\t\t\tans[i][j]='<';\n\t\t\t\t\t\tans[i][j+1]='>';\n\t\t\t\t\t\tA--;\n\t\t\t\t\t}\n\t\t\t\t}else break;\n\t\t\telse break;\n\t}\n\tif(B){\n\t\tfor(int i=0;i<n-1;i++)\n\t\t\tif(B) for(int j=0;j<m;j++)\n\t\t\t\tif(B){\n\t\t\t\t\tif(ans[i][j]=='.'&&ans[i+1][j]=='.'){\n\t\t\t\t\t\tans[i][j]='^';\n\t\t\t\t\t\tans[i+1][j]='v';\n\t\t\t\t\t\tB--;\n\t\t\t\t\t}\n\t\t\t\t}else break;\n\t\t\telse break;\n\t}\n\tif(A||B){\n\t\tcout<<\"NO\"<<endl;\n\t\treturn 0;\n\t}\n\tcout<<\"YES\"<<endl;\n\tfor(int i=0;i<n;i++){\n\t\tfor(int j=0;j<m;j++) cout<<ans[i][j];\n\t\tcout<<endl;\n\t}\n\treturn 0;\n}", "problem_context": "Score : 900 points\n\nProblem Statement\n\nTakahashi has an N \\times M grid, with N horizontal rows and M vertical columns.\nDetermine if we can place A 1 \\times 2 tiles (1 vertical, 2 horizontal) and B 2 \\times 1 tiles (2 vertical, 1 horizontal) satisfying the following conditions, and construct one arrangement of the tiles if it is possible:\n\nAll the tiles must be placed on the grid.\n\nTiles must not stick out of the grid, and no two different tiles may intersect.\n\nNeither the grid nor the tiles may be rotated.\n\nEvery tile completely covers exactly two squares.\n\nConstraints\n\n1 \\leq N,M \\leq 1000\n\n0 \\leq A,B \\leq 500000\n\nN, M, A and B are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M A B\n\nOutput\n\nIf it is impossible to place all the tiles, print NO.\nOtherwise, print the following:\n\nYES\nc_{11}...c_{1M}\n:\nc_{N1}...c_{NM}\n\nHere, c_{ij} must be one of the following characters: ., <, >, ^ and v. Represent an arrangement by using each of these characters as follows:\n\nWhen c_{ij} is ., it indicates that the square at the i-th row and j-th column is empty;\n\nWhen c_{ij} is <, it indicates that the square at the i-th row and j-th column is covered by the left half of a 1 \\times 2 tile;\n\nWhen c_{ij} is >, it indicates that the square at the i-th row and j-th column is covered by the right half of a 1 \\times 2 tile;\n\nWhen c_{ij} is ^, it indicates that the square at the i-th row and j-th column is covered by the top half of a 2 \\times 1 tile;\n\nWhen c_{ij} is v, it indicates that the square at the i-th row and j-th column is covered by the bottom half of a 2 \\times 1 tile.\n\nSample Input 1\n\n3 4 4 2\n\nSample Output 1\n\nYES\n<><>\n^<>^\nv<>v\n\nThis is one example of a way to place four 1 \\times 2 tiles and three 2 \\times 1 tiles on a 3 \\times 4 grid.\n\nSample Input 2\n\n4 5 5 3\n\nSample Output 2\n\nYES\n<>..^\n^.<>v\nv<>.^\n<><>v\n\nSample Input 3\n\n7 9 20 20\n\nSample Output 3\n\nNO", "sample_input": "3 4 4 2\n"}, "reference_outputs": ["YES\n<><>\n^<>^\nv<>v\n"], "source_document_id": "p03429", "source_text": "Score : 900 points\n\nProblem Statement\n\nTakahashi has an N \\times M grid, with N horizontal rows and M vertical columns.\nDetermine if we can place A 1 \\times 2 tiles (1 vertical, 2 horizontal) and B 2 \\times 1 tiles (2 vertical, 1 horizontal) satisfying the following conditions, and construct one arrangement of the tiles if it is possible:\n\nAll the tiles must be placed on the grid.\n\nTiles must not stick out of the grid, and no two different tiles may intersect.\n\nNeither the grid nor the tiles may be rotated.\n\nEvery tile completely covers exactly two squares.\n\nConstraints\n\n1 \\leq N,M \\leq 1000\n\n0 \\leq A,B \\leq 500000\n\nN, M, A and B are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M A B\n\nOutput\n\nIf it is impossible to place all the tiles, print NO.\nOtherwise, print the following:\n\nYES\nc_{11}...c_{1M}\n:\nc_{N1}...c_{NM}\n\nHere, c_{ij} must be one of the following characters: ., <, >, ^ and v. Represent an arrangement by using each of these characters as follows:\n\nWhen c_{ij} is ., it indicates that the square at the i-th row and j-th column is empty;\n\nWhen c_{ij} is <, it indicates that the square at the i-th row and j-th column is covered by the left half of a 1 \\times 2 tile;\n\nWhen c_{ij} is >, it indicates that the square at the i-th row and j-th column is covered by the right half of a 1 \\times 2 tile;\n\nWhen c_{ij} is ^, it indicates that the square at the i-th row and j-th column is covered by the top half of a 2 \\times 1 tile;\n\nWhen c_{ij} is v, it indicates that the square at the i-th row and j-th column is covered by the bottom half of a 2 \\times 1 tile.\n\nSample Input 1\n\n3 4 4 2\n\nSample Output 1\n\nYES\n<><>\n^<>^\nv<>v\n\nThis is one example of a way to place four 1 \\times 2 tiles and three 2 \\times 1 tiles on a 3 \\times 4 grid.\n\nSample Input 2\n\n4 5 5 3\n\nSample Output 2\n\nYES\n<>..^\n^.<>v\nv<>.^\n<><>v\n\nSample Input 3\n\n7 9 20 20\n\nSample Output 3\n\nNO", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1620, "cpu_time_ms": 34, "memory_kb": 2176}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s004246016", "group_id": "codeNet:p03433", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  int N,A;\n  cin >> N >> A;\n    if(N%500 == 0){\n    cout << \"yes\";\n    }\n    else if(N%500 <= A){\n    cout << \"yes\";\n    }\n    else cout << \"no\";\n}\n", "language": "C++", "metadata": {"date": 1600010971, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03433.html", "problem_id": "p03433", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03433/input.txt", "sample_output_relpath": "derived/input_output/data/p03433/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03433/C++/s004246016.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s004246016", "user_id": "u884476319"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  int N,A;\n  cin >> N >> A;\n    if(N%500 == 0){\n    cout << \"yes\";\n    }\n    else if(N%500 <= A){\n    cout << \"yes\";\n    }\n    else cout << \"no\";\n}\n", "problem_context": "Score: 100 points\n\nProblem Statement\n\nE869120 has A 1-yen coins and infinitely many 500-yen coins.\n\nDetermine if he can pay exactly N yen using only these coins.\n\nConstraints\n\nN is an integer between 1 and 10000 (inclusive).\n\nA is an integer between 0 and 1000 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA\n\nOutput\n\nIf E869120 can pay exactly N yen using only his 1-yen and 500-yen coins, print Yes; otherwise, print No.\n\nSample Input 1\n\n2018\n218\n\nSample Output 1\n\nYes\n\nWe can pay 2018 yen with four 500-yen coins and 18 1-yen coins, so the answer is Yes.\n\nSample Input 2\n\n2763\n0\n\nSample Output 2\n\nNo\n\nWhen we have no 1-yen coins, we can only pay a multiple of 500 yen using only 500-yen coins. Since 2763 is not a multiple of 500, we cannot pay this amount.\n\nSample Input 3\n\n37\n514\n\nSample Output 3\n\nYes", "sample_input": "2018\n218\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p03433", "source_text": "Score: 100 points\n\nProblem Statement\n\nE869120 has A 1-yen coins and infinitely many 500-yen coins.\n\nDetermine if he can pay exactly N yen using only these coins.\n\nConstraints\n\nN is an integer between 1 and 10000 (inclusive).\n\nA is an integer between 0 and 1000 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA\n\nOutput\n\nIf E869120 can pay exactly N yen using only his 1-yen and 500-yen coins, print Yes; otherwise, print No.\n\nSample Input 1\n\n2018\n218\n\nSample Output 1\n\nYes\n\nWe can pay 2018 yen with four 500-yen coins and 18 1-yen coins, so the answer is Yes.\n\nSample Input 2\n\n2763\n0\n\nSample Output 2\n\nNo\n\nWhen we have no 1-yen coins, we can only pay a multiple of 500 yen using only 500-yen coins. Since 2763 is not a multiple of 500, we cannot pay this amount.\n\nSample Input 3\n\n37\n514\n\nSample Output 3\n\nYes", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 206, "cpu_time_ms": 6, "memory_kb": 3596}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s736531166", "group_id": "codeNet:p03433", "input_text": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint main(){\n  int N, A; cin >> N >> A;\n  \n  if (N%500 <= A){\n    cout << \"Yes\" << endl; \n  }\n  else{\n    cout << \"No\" << endl;\n  }\n}", "language": "C++", "metadata": {"date": 1578074148, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03433.html", "problem_id": "p03433", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03433/input.txt", "sample_output_relpath": "derived/input_output/data/p03433/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03433/C++/s736531166.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s736531166", "user_id": "u166553470"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <iostream>\n#include <algorithm>\nusing namespace std;\nint main(){\n  int N, A; cin >> N >> A;\n  \n  if (N%500 <= A){\n    cout << \"Yes\" << endl; \n  }\n  else{\n    cout << \"No\" << endl;\n  }\n}", "problem_context": "Score: 100 points\n\nProblem Statement\n\nE869120 has A 1-yen coins and infinitely many 500-yen coins.\n\nDetermine if he can pay exactly N yen using only these coins.\n\nConstraints\n\nN is an integer between 1 and 10000 (inclusive).\n\nA is an integer between 0 and 1000 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA\n\nOutput\n\nIf E869120 can pay exactly N yen using only his 1-yen and 500-yen coins, print Yes; otherwise, print No.\n\nSample Input 1\n\n2018\n218\n\nSample Output 1\n\nYes\n\nWe can pay 2018 yen with four 500-yen coins and 18 1-yen coins, so the answer is Yes.\n\nSample Input 2\n\n2763\n0\n\nSample Output 2\n\nNo\n\nWhen we have no 1-yen coins, we can only pay a multiple of 500 yen using only 500-yen coins. Since 2763 is not a multiple of 500, we cannot pay this amount.\n\nSample Input 3\n\n37\n514\n\nSample Output 3\n\nYes", "sample_input": "2018\n218\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p03433", "source_text": "Score: 100 points\n\nProblem Statement\n\nE869120 has A 1-yen coins and infinitely many 500-yen coins.\n\nDetermine if he can pay exactly N yen using only these coins.\n\nConstraints\n\nN is an integer between 1 and 10000 (inclusive).\n\nA is an integer between 0 and 1000 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA\n\nOutput\n\nIf E869120 can pay exactly N yen using only his 1-yen and 500-yen coins, print Yes; otherwise, print No.\n\nSample Input 1\n\n2018\n218\n\nSample Output 1\n\nYes\n\nWe can pay 2018 yen with four 500-yen coins and 18 1-yen coins, so the answer is Yes.\n\nSample Input 2\n\n2763\n0\n\nSample Output 2\n\nNo\n\nWhen we have no 1-yen coins, we can only pay a multiple of 500 yen using only 500-yen coins. Since 2763 is not a multiple of 500, we cannot pay this amount.\n\nSample Input 3\n\n37\n514\n\nSample Output 3\n\nYes", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 194, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s658927068", "group_id": "codeNet:p03434", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n    int n;cin >> n;\n    vector<int> a(n);\n    int i,j;\n    int tmp;\n    for(i=0;i<n;i++)cin >> a.at(i);\n    for(i=0;i<n;i++){\n        for(j=1;j+i<n;j++){\n            if(a.at(i)<a.at(i+j)){\n                tmp=a.at(i);\n                a.at(i)=a.at(i+j);\n                a.at(i+j)=tmp;\n            }\n        }\n    }\n    int s,t;\n    s=0;t=0;\n    vector<int> A(50),B(50);\n    for(i=0;i<a.size();i++){\n        if(i%2==0)\n        s+=a.at(i);\n        else\n        t+=a.at(i);\n    }\n    cout << s-t << endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1586395040, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03434.html", "problem_id": "p03434", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03434/input.txt", "sample_output_relpath": "derived/input_output/data/p03434/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03434/C++/s658927068.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s658927068", "user_id": "u764118909"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n    int n;cin >> n;\n    vector<int> a(n);\n    int i,j;\n    int tmp;\n    for(i=0;i<n;i++)cin >> a.at(i);\n    for(i=0;i<n;i++){\n        for(j=1;j+i<n;j++){\n            if(a.at(i)<a.at(i+j)){\n                tmp=a.at(i);\n                a.at(i)=a.at(i+j);\n                a.at(i+j)=tmp;\n            }\n        }\n    }\n    int s,t;\n    s=0;t=0;\n    vector<int> A(50),B(50);\n    for(i=0;i<a.size();i++){\n        if(i%2==0)\n        s+=a.at(i);\n        else\n        t+=a.at(i);\n    }\n    cout << s-t << endl;\n    return 0;\n}", "problem_context": "Score: 200 points\n\nProblem Statement\n\nWe have N cards. A number a_i is written on the i-th card.\n\nAlice and Bob will play a game using these cards. In this game, Alice and Bob alternately take one card. Alice goes first.\n\nThe game ends when all the cards are taken by the two players, and the score of each player is the sum of the numbers written on the cards he/she has taken. When both players take the optimal strategy to maximize their scores, find Alice's score minus Bob's score.\n\nConstraints\n\nN is an integer between 1 and 100 (inclusive).\n\na_i \\ (1 \\leq i \\leq N) is an integer between 1 and 100 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 a_3 ... a_N\n\nOutput\n\nPrint Alice's score minus Bob's score when both players take the optimal strategy to maximize their scores.\n\nSample Input 1\n\n2\n3 1\n\nSample Output 1\n\n2\n\nFirst, Alice will take the card with 3. Then, Bob will take the card with 1.\nThe difference of their scores will be 3 - 1 = 2.\n\nSample Input 2\n\n3\n2 7 4\n\nSample Output 2\n\n5\n\nFirst, Alice will take the card with 7. Then, Bob will take the card with 4. Lastly, Alice will take the card with 2. The difference of their scores will be 7 - 4 + 2 = 5. The difference of their scores will be 3 - 1 = 2.\n\nSample Input 3\n\n4\n20 18 2 18\n\nSample Output 3\n\n18", "sample_input": "2\n3 1\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03434", "source_text": "Score: 200 points\n\nProblem Statement\n\nWe have N cards. A number a_i is written on the i-th card.\n\nAlice and Bob will play a game using these cards. In this game, Alice and Bob alternately take one card. Alice goes first.\n\nThe game ends when all the cards are taken by the two players, and the score of each player is the sum of the numbers written on the cards he/she has taken. When both players take the optimal strategy to maximize their scores, find Alice's score minus Bob's score.\n\nConstraints\n\nN is an integer between 1 and 100 (inclusive).\n\na_i \\ (1 \\leq i \\leq N) is an integer between 1 and 100 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 a_3 ... a_N\n\nOutput\n\nPrint Alice's score minus Bob's score when both players take the optimal strategy to maximize their scores.\n\nSample Input 1\n\n2\n3 1\n\nSample Output 1\n\n2\n\nFirst, Alice will take the card with 3. Then, Bob will take the card with 1.\nThe difference of their scores will be 3 - 1 = 2.\n\nSample Input 2\n\n3\n2 7 4\n\nSample Output 2\n\n5\n\nFirst, Alice will take the card with 7. Then, Bob will take the card with 4. Lastly, Alice will take the card with 2. The difference of their scores will be 7 - 4 + 2 = 5. The difference of their scores will be 3 - 1 = 2.\n\nSample Input 3\n\n4\n20 18 2 18\n\nSample Output 3\n\n18", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 573, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s310028669", "group_id": "codeNet:p03434", "input_text": "\n#include <bits/stdc++.h>\n\nclass kin{\npublic:\n\tinline void open(FILE *,int);\n\tinline void close(void);\n\tinline void scan(void);\n\tinline kin &operator>(char &);\n\tinline kin &operator>(int &);\n\tinline kin &operator>(long long &);\n\tinline kin &operator>(double &);\n\tinline kin &operator>(long double &);\n\tinline kin &operator>(char *);\n\ttemplate <class T> inline void get(T *,int);\nprivate:\n\tFILE *fp;\n\tchar *buf;\n\tint siz;\n\tint idx;\n}in;\n\nclass kout{\npublic:\n\tinline void open(FILE *,int);\n\tinline void close(void);\n\tinline void print(void);\n\tinline kout &operator<(char);\n\tinline kout &operator<(int);\n\tinline kout &operator<(long long);\n\tinline kout &operator<(double);\n\tinline kout &operator<(long double);\n\tinline kout &operator<(const char *);\n\ttemplate <class T> inline void put(T *,int,char,char);\nprivate:\n\tFILE *fp;\n\tchar *buf;\n\tint siz;\n\tint idx;\n}out;\n\nint main(int argc,char **argv){\n\tin.open(stdin,512);\n\tout.open(stdout,512);\n\tin.scan();\n\tint n;\n\tin>n;\n\tint a[100];\n\tin.get(a,n);\n\tstd::sort(a,a+n,[](int &x,int &y){return x>y;});\n\tint alice=0,bob=0;\n\tfor(int i=0;i<n;i+=2) alice+=a[i];\n\tfor(int i=1;i<n;i+=2) bob+=a[i];\n\tout<alice-bob<'\\n';\n\tout.print();\n\tin.close();\n\tout.close();\n\treturn 0;\n}\n\ninline void kin::open(FILE *fpa,int siza){\n\tfp=fpa;\n\tbuf=new char[siza];\n\tsiz=siza;\n\tidx=0;\n\treturn;\n}\ninline void kin::close(void){\n\tfp=nullptr;\n\tdelete[] buf;\n\tbuf=nullptr;\n\tsiz=0;\n\tidx=0;\n\treturn;\n}\ninline void kin::scan(void){\n\tint readsiz=(int)std::fread((void *)buf,(std::size_t)1,(std::size_t)siz,fp);\n\tif(readsiz!=siz) buf[readsiz]='\\x00';\n\tidx=0;\n\treturn;\n}\ninline kin &kin::operator>(char &var){\n\tif(!buf[idx]){\n\t\tvar='\\x00';\n\t\treturn *this;\n\t}\n\tvar=buf[idx];\n\tif(++idx==siz) scan();\n\tif(++idx==siz) scan();\n\treturn *this;\n}\ninline kin &kin::operator>(int &var){\n\tif(!buf[idx]){\n\t\tvar=0;\n\t\treturn *this;\n\t}\n\tint sign=-1;\n\tif(buf[idx]=='-'){\n\t\tsign=1;\n\t\tif(++idx==siz) scan();\n\t}\n\tvar=0;\n\twhile(buf[idx]>='0'){\n\t\tvar=var*10-(int)(buf[idx]-'0');\n\t\tif(++idx==siz) scan();\n\t}\n\tvar*=sign;\n\tif(++idx==siz) scan();\n\treturn *this;\n}\ninline kin &kin::operator>(long long &var){\n\tif(!buf[idx]){\n\t\tvar=0LL;\n\t\treturn *this;\n\t}\n\tlong long sign=-1LL;\n\tif(buf[idx]=='-'){\n\t\tsign=1LL;\n\t\tif(++idx==siz) scan();\n\t}\n\tvar=0LL;\n\twhile(buf[idx]>='0'){\n\t\tvar=var*10LL-(long long)(buf[idx]-'0');\n\t\tif(++idx==siz) scan();\n\t}\n\tvar*=sign;\n\tif(++idx==siz) scan();\n\treturn *this;\n}\ninline kin &kin::operator>(double &var){\n\tif(!buf[idx]){\n\t\tvar=0.0;\n\t\treturn *this;\n\t}\n\tdouble sign=-1.0;\n\tif(buf[idx]=='-'){\n\t\tsign=1.0;\n\t\tif(++idx==siz) scan();\n\t}\n\tvar=0.0;\n\twhile(buf[idx]>='0'){\n\t\tvar=var*10.0-(double)(buf[idx]-'0');\n\t\tif(++idx==siz) scan();\n\t}\n\tif(buf[idx]=='.'){\n\t\tif(++idx==siz) scan();\n\t\tdouble dig=1.0;\n\t\twhile(buf[idx]>='0'){\n\t\t\tvar-=(double)(buf[idx]-'0')*(dig/=10.0);\n\t\t\tif(++idx==siz) scan();\n\t\t}\n\t}\n\tvar*=sign;\n\tif(++idx==siz) scan();\n\treturn *this;\n}\ninline kin &kin::operator>(long double &var){\n\tif(!buf[idx]){\n\t\tvar=0.0L;\n\t\treturn *this;\n\t}\n\tlong double sign=-1.0L;\n\tif(buf[idx]=='-'){\n\t\tsign=1.0L;\n\t\tif(++idx==siz) scan();\n\t}\n\tvar=0.0L;\n\twhile(buf[idx]>='0'){\n\t\tvar=var*10.0L-(long double)(buf[idx]-'0');\n\t\tif(++idx==siz) scan();\n\t}\n\tif(buf[idx]=='.'){\n\t\tif(++idx==siz) scan();\n\t\tlong double dig=1.0L;\n\t\twhile(buf[idx]>='0'){\n\t\t\tvar-=(long double)(buf[idx]-'0')*(dig/=10.0L);\n\t\t\tif(++idx==siz) scan();\n\t\t}\n\t}\n\tvar*=sign;\n\tif(++idx==siz) scan();\n\treturn *this;\n}\ninline kin &kin::operator>(char *var){\n\tif(!buf[idx]){\n\t\tvar[0]='\\x00';\n\t\treturn *this;\n\t}\n\tint ptr=0;\n\twhile(buf[idx]>='!'){\n\t\tvar[ptr++]=buf[idx];\n\t\tif(++idx==siz) scan();\n\t}\n\tvar[ptr]='\\x00';\n\tif(++idx==siz) scan();\n\treturn *this;\n}\ntemplate<class T>\ninline void kin::get(T *var,int num){\n\tfor(int i=0;i<num;++i) (*this)>var[i];\n\treturn;\n}\n\ninline void kout::open(FILE *fpa,int siza){\n\tfp=fpa;\n\tbuf=new char[siza];\n\tsiz=siza;\n\tidx=0;\n\treturn;\n}\ninline void kout::close(void){\n\tfp=nullptr;\n\tdelete[] buf;\n\tbuf=nullptr;\n\tsiz=0;\n\tidx=0;\n\treturn;\n}\ninline void kout::print(void){\n\tstd::fwrite((void *)buf,(std::size_t)1,(std::size_t)idx,fp);\n\tidx=0;\n\treturn;\n}\ninline kout &kout::operator<(char val){\n\tbuf[idx]=val;\n\tif(++idx==siz) print();\n\treturn *this;\n}\ninline kout &kout::operator<(int val){\n\tif(val<0){\n\t\tbuf[idx]='-';\n\t\tif(++idx==siz) print();\n\t}\n\telse val*=-1;\n\tchar dig[10];\n\tint ptr=0;\n\tdo{\n\t\tint tmp=val/10;\n\t\tdig[ptr++]=(char)-(val-tmp*10)+'0';\n\t\tval=tmp;\n\t}while(val);\n\twhile(ptr--){\n\t\tbuf[idx]=dig[ptr];\n\t\tif(++idx==siz) print();\n\t}\n\treturn *this;\n}\ninline kout &kout::operator<(long long val){\n\tif(val<0LL){\n\t\tbuf[idx]='-';\n\t\tif(++idx==siz) print();\n\t}\n\telse val*=-1LL;\n\tchar dig[19];\n\tint ptr=0;\n\tdo{\n\t\tlong long tmp=val/10LL;\n\t\tdig[ptr++]=(char)-(val-tmp*10LL)+'0';\n\t\tval=tmp;\n\t}while(val);\n\twhile(ptr--){\n\t\tbuf[idx]=dig[ptr];\n\t\tif(++idx==siz) print();\n\t}\n\treturn *this;\n}\ninline kout &kout::operator<(double val){\n\tif(val<0.0){\n\t\tbuf[idx]='-';\n\t\tif(++idx==siz) print();\n\t}\n\telse val*=-1.0;\n\tdouble dig=1.0;\n\twhile(val/dig<=-10.0) dig*=10.0;\n\tint tmp;\n\twhile(dig>=1.0){\n\t\tbuf[idx]=(char)-(tmp=(int)(val/dig))+'0';\n\t\tif(++idx==siz) print();\n\t\tval-=(double)tmp*dig;\n\t\tdig/=10.0;\n\t}\n\tbuf[idx]='.';\n\tif(++idx==siz) print();\n\tfor(int i=0;i<12;++i){\n\t\tbuf[idx]=(char)-(tmp=(int)(val/dig))+'0';\n\t\tif(++idx==siz) print();\n\t\tval-=(double)tmp*dig;\n\t\tdig/=10.0;\n\t}\n\treturn *this;\n}\ninline kout &kout::operator<(long double val){\n\tif(val<0.0L){\n\t\tbuf[idx]='-';\n\t\tif(++idx==siz) print();\n\t}\n\telse val*=-1.0L;\n\tlong double dig=1.0L;\n\twhile(val/dig<=-10.0L) dig*=10.0L;\n\tint tmp;\n\twhile(dig>=1.0L){\n\t\tbuf[idx]=(char)-(tmp=(int)(val/dig))+'0';\n\t\tif(++idx==siz) print();\n\t\tval-=(long double)tmp*dig;\n\t\tdig/=10.0L;\n\t}\n\tbuf[idx]='.';\n\tif(++idx==siz) print();\n\tfor(int i=0;i<16;++i){\n\t\tbuf[idx]=(char)-(tmp=(int)(val/dig))+'0';\n\t\tif(++idx==siz) print();\n\t\tval-=(long double)tmp*dig;\n\t\tdig/=10.0L;\n\t}\n\treturn *this;\n}\ninline kout &kout::operator<(const char *val){\n\tfor(int i=0;val[i];++i){\n\t\tbuf[idx]=val[i];\n\t\tif(++idx==siz) print();\n\t}\n\treturn *this;\n}\ntemplate<class T>\ninline void kout::put(T *val,int num,char spc,char end){\n\t--num;\n\tfor(int i=0;i<num;++i) (*this)<val[i]<spc;\n\t(*this)<val[num]<end;\n\treturn;\n}\n", "language": "C++", "metadata": {"date": 1583003393, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03434.html", "problem_id": "p03434", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03434/input.txt", "sample_output_relpath": "derived/input_output/data/p03434/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03434/C++/s310028669.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s310028669", "user_id": "u316440712"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "\n#include <bits/stdc++.h>\n\nclass kin{\npublic:\n\tinline void open(FILE *,int);\n\tinline void close(void);\n\tinline void scan(void);\n\tinline kin &operator>(char &);\n\tinline kin &operator>(int &);\n\tinline kin &operator>(long long &);\n\tinline kin &operator>(double &);\n\tinline kin &operator>(long double &);\n\tinline kin &operator>(char *);\n\ttemplate <class T> inline void get(T *,int);\nprivate:\n\tFILE *fp;\n\tchar *buf;\n\tint siz;\n\tint idx;\n}in;\n\nclass kout{\npublic:\n\tinline void open(FILE *,int);\n\tinline void close(void);\n\tinline void print(void);\n\tinline kout &operator<(char);\n\tinline kout &operator<(int);\n\tinline kout &operator<(long long);\n\tinline kout &operator<(double);\n\tinline kout &operator<(long double);\n\tinline kout &operator<(const char *);\n\ttemplate <class T> inline void put(T *,int,char,char);\nprivate:\n\tFILE *fp;\n\tchar *buf;\n\tint siz;\n\tint idx;\n}out;\n\nint main(int argc,char **argv){\n\tin.open(stdin,512);\n\tout.open(stdout,512);\n\tin.scan();\n\tint n;\n\tin>n;\n\tint a[100];\n\tin.get(a,n);\n\tstd::sort(a,a+n,[](int &x,int &y){return x>y;});\n\tint alice=0,bob=0;\n\tfor(int i=0;i<n;i+=2) alice+=a[i];\n\tfor(int i=1;i<n;i+=2) bob+=a[i];\n\tout<alice-bob<'\\n';\n\tout.print();\n\tin.close();\n\tout.close();\n\treturn 0;\n}\n\ninline void kin::open(FILE *fpa,int siza){\n\tfp=fpa;\n\tbuf=new char[siza];\n\tsiz=siza;\n\tidx=0;\n\treturn;\n}\ninline void kin::close(void){\n\tfp=nullptr;\n\tdelete[] buf;\n\tbuf=nullptr;\n\tsiz=0;\n\tidx=0;\n\treturn;\n}\ninline void kin::scan(void){\n\tint readsiz=(int)std::fread((void *)buf,(std::size_t)1,(std::size_t)siz,fp);\n\tif(readsiz!=siz) buf[readsiz]='\\x00';\n\tidx=0;\n\treturn;\n}\ninline kin &kin::operator>(char &var){\n\tif(!buf[idx]){\n\t\tvar='\\x00';\n\t\treturn *this;\n\t}\n\tvar=buf[idx];\n\tif(++idx==siz) scan();\n\tif(++idx==siz) scan();\n\treturn *this;\n}\ninline kin &kin::operator>(int &var){\n\tif(!buf[idx]){\n\t\tvar=0;\n\t\treturn *this;\n\t}\n\tint sign=-1;\n\tif(buf[idx]=='-'){\n\t\tsign=1;\n\t\tif(++idx==siz) scan();\n\t}\n\tvar=0;\n\twhile(buf[idx]>='0'){\n\t\tvar=var*10-(int)(buf[idx]-'0');\n\t\tif(++idx==siz) scan();\n\t}\n\tvar*=sign;\n\tif(++idx==siz) scan();\n\treturn *this;\n}\ninline kin &kin::operator>(long long &var){\n\tif(!buf[idx]){\n\t\tvar=0LL;\n\t\treturn *this;\n\t}\n\tlong long sign=-1LL;\n\tif(buf[idx]=='-'){\n\t\tsign=1LL;\n\t\tif(++idx==siz) scan();\n\t}\n\tvar=0LL;\n\twhile(buf[idx]>='0'){\n\t\tvar=var*10LL-(long long)(buf[idx]-'0');\n\t\tif(++idx==siz) scan();\n\t}\n\tvar*=sign;\n\tif(++idx==siz) scan();\n\treturn *this;\n}\ninline kin &kin::operator>(double &var){\n\tif(!buf[idx]){\n\t\tvar=0.0;\n\t\treturn *this;\n\t}\n\tdouble sign=-1.0;\n\tif(buf[idx]=='-'){\n\t\tsign=1.0;\n\t\tif(++idx==siz) scan();\n\t}\n\tvar=0.0;\n\twhile(buf[idx]>='0'){\n\t\tvar=var*10.0-(double)(buf[idx]-'0');\n\t\tif(++idx==siz) scan();\n\t}\n\tif(buf[idx]=='.'){\n\t\tif(++idx==siz) scan();\n\t\tdouble dig=1.0;\n\t\twhile(buf[idx]>='0'){\n\t\t\tvar-=(double)(buf[idx]-'0')*(dig/=10.0);\n\t\t\tif(++idx==siz) scan();\n\t\t}\n\t}\n\tvar*=sign;\n\tif(++idx==siz) scan();\n\treturn *this;\n}\ninline kin &kin::operator>(long double &var){\n\tif(!buf[idx]){\n\t\tvar=0.0L;\n\t\treturn *this;\n\t}\n\tlong double sign=-1.0L;\n\tif(buf[idx]=='-'){\n\t\tsign=1.0L;\n\t\tif(++idx==siz) scan();\n\t}\n\tvar=0.0L;\n\twhile(buf[idx]>='0'){\n\t\tvar=var*10.0L-(long double)(buf[idx]-'0');\n\t\tif(++idx==siz) scan();\n\t}\n\tif(buf[idx]=='.'){\n\t\tif(++idx==siz) scan();\n\t\tlong double dig=1.0L;\n\t\twhile(buf[idx]>='0'){\n\t\t\tvar-=(long double)(buf[idx]-'0')*(dig/=10.0L);\n\t\t\tif(++idx==siz) scan();\n\t\t}\n\t}\n\tvar*=sign;\n\tif(++idx==siz) scan();\n\treturn *this;\n}\ninline kin &kin::operator>(char *var){\n\tif(!buf[idx]){\n\t\tvar[0]='\\x00';\n\t\treturn *this;\n\t}\n\tint ptr=0;\n\twhile(buf[idx]>='!'){\n\t\tvar[ptr++]=buf[idx];\n\t\tif(++idx==siz) scan();\n\t}\n\tvar[ptr]='\\x00';\n\tif(++idx==siz) scan();\n\treturn *this;\n}\ntemplate<class T>\ninline void kin::get(T *var,int num){\n\tfor(int i=0;i<num;++i) (*this)>var[i];\n\treturn;\n}\n\ninline void kout::open(FILE *fpa,int siza){\n\tfp=fpa;\n\tbuf=new char[siza];\n\tsiz=siza;\n\tidx=0;\n\treturn;\n}\ninline void kout::close(void){\n\tfp=nullptr;\n\tdelete[] buf;\n\tbuf=nullptr;\n\tsiz=0;\n\tidx=0;\n\treturn;\n}\ninline void kout::print(void){\n\tstd::fwrite((void *)buf,(std::size_t)1,(std::size_t)idx,fp);\n\tidx=0;\n\treturn;\n}\ninline kout &kout::operator<(char val){\n\tbuf[idx]=val;\n\tif(++idx==siz) print();\n\treturn *this;\n}\ninline kout &kout::operator<(int val){\n\tif(val<0){\n\t\tbuf[idx]='-';\n\t\tif(++idx==siz) print();\n\t}\n\telse val*=-1;\n\tchar dig[10];\n\tint ptr=0;\n\tdo{\n\t\tint tmp=val/10;\n\t\tdig[ptr++]=(char)-(val-tmp*10)+'0';\n\t\tval=tmp;\n\t}while(val);\n\twhile(ptr--){\n\t\tbuf[idx]=dig[ptr];\n\t\tif(++idx==siz) print();\n\t}\n\treturn *this;\n}\ninline kout &kout::operator<(long long val){\n\tif(val<0LL){\n\t\tbuf[idx]='-';\n\t\tif(++idx==siz) print();\n\t}\n\telse val*=-1LL;\n\tchar dig[19];\n\tint ptr=0;\n\tdo{\n\t\tlong long tmp=val/10LL;\n\t\tdig[ptr++]=(char)-(val-tmp*10LL)+'0';\n\t\tval=tmp;\n\t}while(val);\n\twhile(ptr--){\n\t\tbuf[idx]=dig[ptr];\n\t\tif(++idx==siz) print();\n\t}\n\treturn *this;\n}\ninline kout &kout::operator<(double val){\n\tif(val<0.0){\n\t\tbuf[idx]='-';\n\t\tif(++idx==siz) print();\n\t}\n\telse val*=-1.0;\n\tdouble dig=1.0;\n\twhile(val/dig<=-10.0) dig*=10.0;\n\tint tmp;\n\twhile(dig>=1.0){\n\t\tbuf[idx]=(char)-(tmp=(int)(val/dig))+'0';\n\t\tif(++idx==siz) print();\n\t\tval-=(double)tmp*dig;\n\t\tdig/=10.0;\n\t}\n\tbuf[idx]='.';\n\tif(++idx==siz) print();\n\tfor(int i=0;i<12;++i){\n\t\tbuf[idx]=(char)-(tmp=(int)(val/dig))+'0';\n\t\tif(++idx==siz) print();\n\t\tval-=(double)tmp*dig;\n\t\tdig/=10.0;\n\t}\n\treturn *this;\n}\ninline kout &kout::operator<(long double val){\n\tif(val<0.0L){\n\t\tbuf[idx]='-';\n\t\tif(++idx==siz) print();\n\t}\n\telse val*=-1.0L;\n\tlong double dig=1.0L;\n\twhile(val/dig<=-10.0L) dig*=10.0L;\n\tint tmp;\n\twhile(dig>=1.0L){\n\t\tbuf[idx]=(char)-(tmp=(int)(val/dig))+'0';\n\t\tif(++idx==siz) print();\n\t\tval-=(long double)tmp*dig;\n\t\tdig/=10.0L;\n\t}\n\tbuf[idx]='.';\n\tif(++idx==siz) print();\n\tfor(int i=0;i<16;++i){\n\t\tbuf[idx]=(char)-(tmp=(int)(val/dig))+'0';\n\t\tif(++idx==siz) print();\n\t\tval-=(long double)tmp*dig;\n\t\tdig/=10.0L;\n\t}\n\treturn *this;\n}\ninline kout &kout::operator<(const char *val){\n\tfor(int i=0;val[i];++i){\n\t\tbuf[idx]=val[i];\n\t\tif(++idx==siz) print();\n\t}\n\treturn *this;\n}\ntemplate<class T>\ninline void kout::put(T *val,int num,char spc,char end){\n\t--num;\n\tfor(int i=0;i<num;++i) (*this)<val[i]<spc;\n\t(*this)<val[num]<end;\n\treturn;\n}\n", "problem_context": "Score: 200 points\n\nProblem Statement\n\nWe have N cards. A number a_i is written on the i-th card.\n\nAlice and Bob will play a game using these cards. In this game, Alice and Bob alternately take one card. Alice goes first.\n\nThe game ends when all the cards are taken by the two players, and the score of each player is the sum of the numbers written on the cards he/she has taken. When both players take the optimal strategy to maximize their scores, find Alice's score minus Bob's score.\n\nConstraints\n\nN is an integer between 1 and 100 (inclusive).\n\na_i \\ (1 \\leq i \\leq N) is an integer between 1 and 100 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 a_3 ... a_N\n\nOutput\n\nPrint Alice's score minus Bob's score when both players take the optimal strategy to maximize their scores.\n\nSample Input 1\n\n2\n3 1\n\nSample Output 1\n\n2\n\nFirst, Alice will take the card with 3. Then, Bob will take the card with 1.\nThe difference of their scores will be 3 - 1 = 2.\n\nSample Input 2\n\n3\n2 7 4\n\nSample Output 2\n\n5\n\nFirst, Alice will take the card with 7. Then, Bob will take the card with 4. Lastly, Alice will take the card with 2. The difference of their scores will be 7 - 4 + 2 = 5. The difference of their scores will be 3 - 1 = 2.\n\nSample Input 3\n\n4\n20 18 2 18\n\nSample Output 3\n\n18", "sample_input": "2\n3 1\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03434", "source_text": "Score: 200 points\n\nProblem Statement\n\nWe have N cards. A number a_i is written on the i-th card.\n\nAlice and Bob will play a game using these cards. In this game, Alice and Bob alternately take one card. Alice goes first.\n\nThe game ends when all the cards are taken by the two players, and the score of each player is the sum of the numbers written on the cards he/she has taken. When both players take the optimal strategy to maximize their scores, find Alice's score minus Bob's score.\n\nConstraints\n\nN is an integer between 1 and 100 (inclusive).\n\na_i \\ (1 \\leq i \\leq N) is an integer between 1 and 100 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 a_3 ... a_N\n\nOutput\n\nPrint Alice's score minus Bob's score when both players take the optimal strategy to maximize their scores.\n\nSample Input 1\n\n2\n3 1\n\nSample Output 1\n\n2\n\nFirst, Alice will take the card with 3. Then, Bob will take the card with 1.\nThe difference of their scores will be 3 - 1 = 2.\n\nSample Input 2\n\n3\n2 7 4\n\nSample Output 2\n\n5\n\nFirst, Alice will take the card with 7. Then, Bob will take the card with 4. Lastly, Alice will take the card with 2. The difference of their scores will be 7 - 4 + 2 = 5. The difference of their scores will be 3 - 1 = 2.\n\nSample Input 3\n\n4\n20 18 2 18\n\nSample Output 3\n\n18", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 6081, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s602803727", "group_id": "codeNet:p03436", "input_text": "#include \"bits/stdc++.h\"\n \nusing namespace std;\ntypedef long long ll;\ntypedef vector<ll> vll;\ntypedef pair<int,int> pii;\n#define int ll\n#define fi first\n#define se second\n#define SORT(a) sort(a.begin(),a.end())\n#define rep(i,n) for(int i = 0;i < (n) ; i++) \n#define REP(i,n) for(int i = 0;i < (n) ; i++) \n#define MP(a,b) make_pair(a,b)\n#define pb(a) push_back(a)\n#define INF LLONG_MAX/2\n#define all(x) (x).begin(),(x).end()\n#define debug(x) cerr<<#x<<\": \"<<x<<endl\n#define debug_vec(v) cerr<<#v<<\":\";rep(i,v.size())cerr<<\" \"<<v[i];cerr<<endl\n/*----------------------------------------------------------------*/\n\n// int MOD = 998244353;\nint MOD = 1000000007;\n\nint h,w;\nchar maze[51][51];\nint d[51][51] = {};\n\nint dh[4] = {0,0,-1,1};\nint dw[4] = {1,-1,0,0};\n\nbool isin(int i,int j){\n\treturn (0 <= i && i < h && 0 <= j && j < w);\n}\n\nint bfs(){\n\trep(i,h)rep(j,w)d[i][j] = INF;\n\td[0][0] = 1;\n\tqueue<pii> q;\n\tq.push(MP(0,0));\n\twhile(q.size()){\n\t\tpii p = q.front();\n\t\tq.pop();\n\t\trep(i,4){\n\t\t\tint nh = p.fi + dh[i];\n\t\t\tint nw = p.se + dw[i];\n\t\t\tif(isin(nh,nw) && d[nh][nw] == INF && maze[nh][nw] == '.'){\n\t\t\t\tq.push(MP(nh,nw));\n\t\t\t\td[nh][nw] = d[p.fi][p.se]+1;\n\t\t\t}\n\t\t}\n\t}\n\treturn d[h-1][w-1];\n}\n\n\n\n/*----------------------------------------------------------------*/\nsigned main(){\n\n    cin >> h >> w;\n\trep(i,h)rep(j,w)cin >> maze[i][j];\n\tint cnt = 0;\n\trep(i,h)rep(j,w)if(maze[i][j] == '#')cnt++;\n\tint ans = bfs();\n\tif(ans == INF){\n\t\tcout << -1 << endl;\n\t\treturn 0;\n\t}\n\tcout << h*w-cnt-ans << endl;\n    \n\treturn 0;\n}\n/*----------------------------------------------------------------*/\n\n// g++ -std=c++14 code1.cpp\n// sudo pip3 install --upgrade online-judge-tools\n// rm -r -f test;oj dl https://code-festival-2018-quala.contest.atcoder.jp/tasks/code_festival_2018_quala_c\n// rm -r -f test;oj dl https://pakencamp-2019-day3.contest.atcoder.jp/tasks/pakencamp_2019_day3_c\n// rm -r -f test;oj dl https://abc088.contest.atcoder.jp/tasks/abc088_d", "language": "C++", "metadata": {"date": 1584416294, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03436.html", "problem_id": "p03436", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03436/input.txt", "sample_output_relpath": "derived/input_output/data/p03436/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03436/C++/s602803727.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s602803727", "user_id": "u548768105"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include \"bits/stdc++.h\"\n \nusing namespace std;\ntypedef long long ll;\ntypedef vector<ll> vll;\ntypedef pair<int,int> pii;\n#define int ll\n#define fi first\n#define se second\n#define SORT(a) sort(a.begin(),a.end())\n#define rep(i,n) for(int i = 0;i < (n) ; i++) \n#define REP(i,n) for(int i = 0;i < (n) ; i++) \n#define MP(a,b) make_pair(a,b)\n#define pb(a) push_back(a)\n#define INF LLONG_MAX/2\n#define all(x) (x).begin(),(x).end()\n#define debug(x) cerr<<#x<<\": \"<<x<<endl\n#define debug_vec(v) cerr<<#v<<\":\";rep(i,v.size())cerr<<\" \"<<v[i];cerr<<endl\n/*----------------------------------------------------------------*/\n\n// int MOD = 998244353;\nint MOD = 1000000007;\n\nint h,w;\nchar maze[51][51];\nint d[51][51] = {};\n\nint dh[4] = {0,0,-1,1};\nint dw[4] = {1,-1,0,0};\n\nbool isin(int i,int j){\n\treturn (0 <= i && i < h && 0 <= j && j < w);\n}\n\nint bfs(){\n\trep(i,h)rep(j,w)d[i][j] = INF;\n\td[0][0] = 1;\n\tqueue<pii> q;\n\tq.push(MP(0,0));\n\twhile(q.size()){\n\t\tpii p = q.front();\n\t\tq.pop();\n\t\trep(i,4){\n\t\t\tint nh = p.fi + dh[i];\n\t\t\tint nw = p.se + dw[i];\n\t\t\tif(isin(nh,nw) && d[nh][nw] == INF && maze[nh][nw] == '.'){\n\t\t\t\tq.push(MP(nh,nw));\n\t\t\t\td[nh][nw] = d[p.fi][p.se]+1;\n\t\t\t}\n\t\t}\n\t}\n\treturn d[h-1][w-1];\n}\n\n\n\n/*----------------------------------------------------------------*/\nsigned main(){\n\n    cin >> h >> w;\n\trep(i,h)rep(j,w)cin >> maze[i][j];\n\tint cnt = 0;\n\trep(i,h)rep(j,w)if(maze[i][j] == '#')cnt++;\n\tint ans = bfs();\n\tif(ans == INF){\n\t\tcout << -1 << endl;\n\t\treturn 0;\n\t}\n\tcout << h*w-cnt-ans << endl;\n    \n\treturn 0;\n}\n/*----------------------------------------------------------------*/\n\n// g++ -std=c++14 code1.cpp\n// sudo pip3 install --upgrade online-judge-tools\n// rm -r -f test;oj dl https://code-festival-2018-quala.contest.atcoder.jp/tasks/code_festival_2018_quala_c\n// rm -r -f test;oj dl https://pakencamp-2019-day3.contest.atcoder.jp/tasks/pakencamp_2019_day3_c\n// rm -r -f test;oj dl https://abc088.contest.atcoder.jp/tasks/abc088_d", "problem_context": "Score: 400 points\n\nProblem statement\n\nWe have an H \\times W grid whose squares are painted black or white. The square at the i-th row from the top and the j-th column from the left is denoted as (i, j).\n\nSnuke would like to play the following game on this grid. At the beginning of the game, there is a character called Kenus at square (1, 1). The player repeatedly moves Kenus up, down, left or right by one square. The game is completed when Kenus reaches square (H, W) passing only white squares.\n\nBefore Snuke starts the game, he can change the color of some of the white squares to black. However, he cannot change the color of square (1, 1) and (H, W). Also, changes of color must all be carried out before the beginning of the game.\n\nWhen the game is completed, Snuke's score will be the number of times he changed the color of a square before the beginning of the game. Find the maximum possible score that Snuke can achieve, or print -1 if the game cannot be completed, that is, Kenus can never reach square (H, W) regardless of how Snuke changes the color of the squares.\n\nThe color of the squares are given to you as characters s_{i, j}. If square (i, j) is initially painted by white, s_{i, j} is .; if square (i, j) is initially painted by black, s_{i, j} is #.\n\nConstraints\n\nH is an integer between 2 and 50 (inclusive).\n\nW is an integer between 2 and 50 (inclusive).\n\ns_{i, j} is . or # (1 \\leq i \\leq H, 1 \\leq j \\leq W).\n\ns_{1, 1} and s_{H, W} are ..\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W\ns_{1, 1}s_{1, 2}s_{1, 3} ... s_{1, W}\ns_{2, 1}s_{2, 2}s_{2, 3} ... s_{2, W}\n: :\ns_{H, 1}s_{H, 2}s_{H, 3} ... s_{H, W}\n\nOutput\n\nPrint the maximum possible score that Snuke can achieve, or print -1 if the game cannot be completed.\n\nSample Input 1\n\n3 3\n..#\n#..\n...\n\nSample Output 1\n\n2\n\nThe score 2 can be achieved by changing the color of squares as follows:\n\nSample Input 2\n\n10 37\n.....................................\n...#...####...####..###...###...###..\n..#.#..#...#.##....#...#.#...#.#...#.\n..#.#..#...#.#.....#...#.#...#.#...#.\n.#...#.#..##.#.....#...#.#.###.#.###.\n.#####.####..#.....#...#..##....##...\n.#...#.#...#.#.....#...#.#...#.#...#.\n.#...#.#...#.##....#...#.#...#.#...#.\n.#...#.####...####..###...###...###..\n.....................................\n\nSample Output 2\n\n209", "sample_input": "3 3\n..#\n#..\n...\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03436", "source_text": "Score: 400 points\n\nProblem statement\n\nWe have an H \\times W grid whose squares are painted black or white. The square at the i-th row from the top and the j-th column from the left is denoted as (i, j).\n\nSnuke would like to play the following game on this grid. At the beginning of the game, there is a character called Kenus at square (1, 1). The player repeatedly moves Kenus up, down, left or right by one square. The game is completed when Kenus reaches square (H, W) passing only white squares.\n\nBefore Snuke starts the game, he can change the color of some of the white squares to black. However, he cannot change the color of square (1, 1) and (H, W). Also, changes of color must all be carried out before the beginning of the game.\n\nWhen the game is completed, Snuke's score will be the number of times he changed the color of a square before the beginning of the game. Find the maximum possible score that Snuke can achieve, or print -1 if the game cannot be completed, that is, Kenus can never reach square (H, W) regardless of how Snuke changes the color of the squares.\n\nThe color of the squares are given to you as characters s_{i, j}. If square (i, j) is initially painted by white, s_{i, j} is .; if square (i, j) is initially painted by black, s_{i, j} is #.\n\nConstraints\n\nH is an integer between 2 and 50 (inclusive).\n\nW is an integer between 2 and 50 (inclusive).\n\ns_{i, j} is . or # (1 \\leq i \\leq H, 1 \\leq j \\leq W).\n\ns_{1, 1} and s_{H, W} are ..\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W\ns_{1, 1}s_{1, 2}s_{1, 3} ... s_{1, W}\ns_{2, 1}s_{2, 2}s_{2, 3} ... s_{2, W}\n: :\ns_{H, 1}s_{H, 2}s_{H, 3} ... s_{H, W}\n\nOutput\n\nPrint the maximum possible score that Snuke can achieve, or print -1 if the game cannot be completed.\n\nSample Input 1\n\n3 3\n..#\n#..\n...\n\nSample Output 1\n\n2\n\nThe score 2 can be achieved by changing the color of squares as follows:\n\nSample Input 2\n\n10 37\n.....................................\n...#...####...####..###...###...###..\n..#.#..#...#.##....#...#.#...#.#...#.\n..#.#..#...#.#.....#...#.#...#.#...#.\n.#...#.#..##.#.....#...#.#.###.#.###.\n.#####.####..#.....#...#..##....##...\n.#...#.#...#.#.....#...#.#...#.#...#.\n.#...#.#...#.##....#...#.#...#.#...#.\n.#...#.####...####..###...###...###..\n.....................................\n\nSample Output 2\n\n209", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1935, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s445191352", "group_id": "codeNet:p03438", "input_text": "#include <stdio.h>\n#include <string.h>\n#include <iostream>\n#include <vector>\n#include <deque>\n#include <queue>\n#include <stack>\n#include <map>\n#include <string>\n#include <algorithm>\n#include <numeric>\n#include <utility>\n#include <cmath>\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef unsigned int uint;\ntypedef unsigned long long ull;\ntypedef pair<int, int> pii;\ntypedef pair<ll, int> pli;\n\nconst int iinf = 1 << 29;\nconst long long linf = 1ll << 61;\n\n#define dump(x) cerr << #x << \" : \" << x << '\\n'\n#define MOD(x, y) (((y) + (x) % (y)) % (y))\n\nint N;\nint a[10000];\nint b[10000];\n\nint main(int argc, char* argv[])\n{\n\tscanf(\"%d\", &N);\n\tfor (int i = 0; i < N; i++) {\n\t\tscanf(\"%d\", &a[i]);\n\t}\n\tfor (int i = 0; i < N; i++) {\n\t\tscanf(\"%d\", &b[i]);\n\t}\n\tfor (int i = 0; i < N; i++) {\n\t\tif (a[i] > b[i]) {\n\t\t\tprintf(\"No\\n\");\n\t\t\treturn 0;\n\t\t}\n\t}\n\tprintf(\"Yes\\n\");\n\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1517717801, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03438.html", "problem_id": "p03438", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03438/input.txt", "sample_output_relpath": "derived/input_output/data/p03438/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03438/C++/s445191352.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s445191352", "user_id": "u664717705"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <stdio.h>\n#include <string.h>\n#include <iostream>\n#include <vector>\n#include <deque>\n#include <queue>\n#include <stack>\n#include <map>\n#include <string>\n#include <algorithm>\n#include <numeric>\n#include <utility>\n#include <cmath>\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef unsigned int uint;\ntypedef unsigned long long ull;\ntypedef pair<int, int> pii;\ntypedef pair<ll, int> pli;\n\nconst int iinf = 1 << 29;\nconst long long linf = 1ll << 61;\n\n#define dump(x) cerr << #x << \" : \" << x << '\\n'\n#define MOD(x, y) (((y) + (x) % (y)) % (y))\n\nint N;\nint a[10000];\nint b[10000];\n\nint main(int argc, char* argv[])\n{\n\tscanf(\"%d\", &N);\n\tfor (int i = 0; i < N; i++) {\n\t\tscanf(\"%d\", &a[i]);\n\t}\n\tfor (int i = 0; i < N; i++) {\n\t\tscanf(\"%d\", &b[i]);\n\t}\n\tfor (int i = 0; i < N; i++) {\n\t\tif (a[i] > b[i]) {\n\t\t\tprintf(\"No\\n\");\n\t\t\treturn 0;\n\t\t}\n\t}\n\tprintf(\"Yes\\n\");\n\n\treturn 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nYou are given two integer sequences of length N: a_1,a_2,..,a_N and b_1,b_2,..,b_N.\nDetermine if we can repeat the following operation zero or more times so that the sequences a and b become equal.\n\nOperation: Choose two integers i and j (possibly the same) between 1 and N (inclusive), then perform the following two actions simultaneously:\n\nAdd 2 to a_i.\n\nAdd 1 to b_j.\n\nConstraints\n\n1 ≤ N ≤ 10 000\n\n0 ≤ a_i,b_i ≤ 10^9 (1 ≤ i ≤ N)\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 .. a_N\nb_1 b_2 .. b_N\n\nOutput\n\nIf we can repeat the operation zero or more times so that the sequences a and b become equal, print Yes; otherwise, print No.\n\nSample Input 1\n\n3\n1 2 3\n5 2 2\n\nSample Output 1\n\nYes\n\nFor example, we can perform three operations as follows to do our job:\n\nFirst operation: i=1 and j=2. Now we have a = \\{3,2,3\\}, b = \\{5,3,2\\}.\n\nSecond operation: i=1 and j=2. Now we have a = \\{5,2,3\\}, b = \\{5,4,2\\}.\n\nThird operation: i=2 and j=3. Now we have a = \\{5,4,3\\}, b = \\{5,4,3\\}.\n\nSample Input 2\n\n5\n3 1 4 1 5\n2 7 1 8 2\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n5\n2 7 1 8 2\n3 1 4 1 5\n\nSample Output 3\n\nNo", "sample_input": "3\n1 2 3\n5 2 2\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p03438", "source_text": "Score : 300 points\n\nProblem Statement\n\nYou are given two integer sequences of length N: a_1,a_2,..,a_N and b_1,b_2,..,b_N.\nDetermine if we can repeat the following operation zero or more times so that the sequences a and b become equal.\n\nOperation: Choose two integers i and j (possibly the same) between 1 and N (inclusive), then perform the following two actions simultaneously:\n\nAdd 2 to a_i.\n\nAdd 1 to b_j.\n\nConstraints\n\n1 ≤ N ≤ 10 000\n\n0 ≤ a_i,b_i ≤ 10^9 (1 ≤ i ≤ N)\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 .. a_N\nb_1 b_2 .. b_N\n\nOutput\n\nIf we can repeat the operation zero or more times so that the sequences a and b become equal, print Yes; otherwise, print No.\n\nSample Input 1\n\n3\n1 2 3\n5 2 2\n\nSample Output 1\n\nYes\n\nFor example, we can perform three operations as follows to do our job:\n\nFirst operation: i=1 and j=2. Now we have a = \\{3,2,3\\}, b = \\{5,3,2\\}.\n\nSecond operation: i=1 and j=2. Now we have a = \\{5,2,3\\}, b = \\{5,4,2\\}.\n\nThird operation: i=2 and j=3. Now we have a = \\{5,4,3\\}, b = \\{5,4,3\\}.\n\nSample Input 2\n\n5\n3 1 4 1 5\n2 7 1 8 2\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n5\n2 7 1 8 2\n3 1 4 1 5\n\nSample Output 3\n\nNo", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 876, "cpu_time_ms": 3, "memory_kb": 384}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s181564255", "group_id": "codeNet:p03447", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n  int X, A, B;\n  cin >> X >> A >> B;\n  cout << (X - A) % B << endl;\n}", "language": "C++", "metadata": {"date": 1550011680, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03447.html", "problem_id": "p03447", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03447/input.txt", "sample_output_relpath": "derived/input_output/data/p03447/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03447/C++/s181564255.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s181564255", "user_id": "u565172542"}, "prompt_components": {"gold_output": "84\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n  int X, A, B;\n  cin >> X >> A >> B;\n  cout << (X - A) % B << endl;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nYou went shopping to buy cakes and donuts with X yen (the currency of Japan).\n\nFirst, you bought one cake for A yen at a cake shop.\nThen, you bought as many donuts as possible for B yen each, at a donut shop.\n\nHow much do you have left after shopping?\n\nConstraints\n\n1 \\leq A, B \\leq 1 000\n\nA + B \\leq X \\leq 10 000\n\nX, A and B are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\nA\nB\n\nOutput\n\nPrint the amount you have left after shopping.\n\nSample Input 1\n\n1234\n150\n100\n\nSample Output 1\n\n84\n\nYou have 1234 - 150 = 1084 yen left after buying a cake.\nWith this amount, you can buy 10 donuts, after which you have 84 yen left.\n\nSample Input 2\n\n1000\n108\n108\n\nSample Output 2\n\n28\n\nSample Input 3\n\n579\n123\n456\n\nSample Output 3\n\n0\n\nSample Input 4\n\n7477\n549\n593\n\nSample Output 4\n\n405", "sample_input": "1234\n150\n100\n"}, "reference_outputs": ["84\n"], "source_document_id": "p03447", "source_text": "Score : 100 points\n\nProblem Statement\n\nYou went shopping to buy cakes and donuts with X yen (the currency of Japan).\n\nFirst, you bought one cake for A yen at a cake shop.\nThen, you bought as many donuts as possible for B yen each, at a donut shop.\n\nHow much do you have left after shopping?\n\nConstraints\n\n1 \\leq A, B \\leq 1 000\n\nA + B \\leq X \\leq 10 000\n\nX, A and B are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX\nA\nB\n\nOutput\n\nPrint the amount you have left after shopping.\n\nSample Input 1\n\n1234\n150\n100\n\nSample Output 1\n\n84\n\nYou have 1234 - 150 = 1084 yen left after buying a cake.\nWith this amount, you can buy 10 donuts, after which you have 84 yen left.\n\nSample Input 2\n\n1000\n108\n108\n\nSample Output 2\n\n28\n\nSample Input 3\n\n579\n123\n456\n\nSample Output 3\n\n0\n\nSample Input 4\n\n7477\n549\n593\n\nSample Output 4\n\n405", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 129, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s376046166", "group_id": "codeNet:p03449", "input_text": "#include \"bits/stdc++.h\"\n\n// Begin Header {{{\nusing namespace std;\n\n#ifndef DEBUG\n#define dump(...)\n#endif\n\n#define all(x) x.begin(), x.end()\n#define rep(i, b, e) for (intmax_t i = (b), i##_limit = (e); i < i##_limit; ++i)\n#define reps(i, b, e) for (intmax_t i = (b), i##_limit = (e); i <= i##_limit; ++i)\n#define repr(i, b, e) for (intmax_t i = (b), i##_limit = (e); i >= i##_limit; --i)\n#define var(Type, ...) Type __VA_ARGS__; input(__VA_ARGS__)\n\nconstexpr size_t    operator\"\"_zu(unsigned long long value) { return value; };\nconstexpr intmax_t  operator\"\"_jd(unsigned long long value) { return value; };\nconstexpr uintmax_t operator\"\"_ju(unsigned long long value) { return value; };\n\nconstexpr int INF = 0x3f3f3f3f;\nconstexpr intmax_t LINF = 0x3f3f3f3f3f3f3f3f_jd;\n\ntemplate <class T, class Compare = less<>>\nusing MaxHeap = priority_queue<T, vector<T>, Compare>;\ntemplate <class T, class Compare = greater<>>\nusing MinHeap = priority_queue<T, vector<T>, Compare>;\n\ninline void input() {}\ntemplate <class Head, class... Tail>\ninline void input(Head&& head, Tail&&... tail) {\n    cin >> head;\n    input(forward<Tail>(tail)...);\n}\n\ntemplate <class T>\ninline istream& operator>>(istream &is, vector<T> &vec) {\n    for (auto &e: vec) {\n        is >> e;\n    }\n    return is;\n}\n\ninline void output() { cout << \"\\n\"; }\ntemplate <class Head, class... Tail>\ninline void output(Head&& head, Tail&&... tail) {\n    cout << head;\n    if (sizeof...(tail)) {\n        cout << \" \";\n    }\n    output(forward<Tail>(tail)...);\n}\n\ntemplate <class T>\ninline ostream& operator<<(ostream &os, const vector<T> &vec) {\n    static constexpr const char *delim[] = {\" \", \"\"};\n    for (const auto &e: vec) {\n        os << e << delim[&e == &vec.back()];\n    }\n    return os;\n}\n\ntemplate <class T>\ninline vector<T> makeVector(const T &initValue, size_t sz) {\n    return vector<T>(sz, initValue);\n}\n\ntemplate <class T, class... Args>\ninline auto makeVector(const T &initValue, size_t sz, Args... args) {\n    return vector<decltype(makeVector<T>(initValue, args...))>(sz, makeVector<T>(initValue, args...));\n}\n\ntemplate <class Func>\nclass FixPoint : Func {\npublic:\n    explicit constexpr FixPoint(Func&& f) noexcept : Func(forward<Func>(f)) {}\n\n    template <class... Args>\n        constexpr decltype(auto) operator()(Args&&... args) const {\n            return Func::operator()(*this, std::forward<Args>(args)...);\n        }\n};\n\ntemplate <class Func>\nstatic inline constexpr decltype(auto) makeFixPoint(Func&& f) noexcept {\n    return FixPoint<Func>{forward<Func>(f)};\n}\n\ntemplate <class Container>\nstruct reverse_t {\n    Container &c;\n    reverse_t(Container &c) : c(c) {}\n    auto begin() { return c.rbegin(); }\n    auto end() { return c.rend(); }\n};\n\ntemplate <class Container>\nauto reversed(Container &c) {\n    return reverse_t<Container>(c);\n}\n\ntemplate <class T>\ninline bool chmax(T &a, const T &b) noexcept {\n    return b > a && (a = b, true);\n}\n\ntemplate <class T>\ninline bool chmin(T &a, const T &b) noexcept {\n    return b < a && (a = b, true);\n}\n\ntemplate <class T>\ninline T diff(const T &a, const T &b) noexcept {\n    return a < b ? b - a : a - b;\n}\n// End Header }}}\n\nsigned main() {\n    ios_base::sync_with_stdio(false);\n    cin.tie(nullptr);\n    cout.setf(ios_base::fixed);\n    cout.precision(10);\n    var(size_t, N);\n    auto dp = makeVector<intmax_t>(0, 2, N); input(dp);\n    rep(i, 0, 2) rep(j, 0, N) {\n        intmax_t best = 0;\n        if (i > 0) chmax(best, dp[i - 1][j]);\n        if (j > 0) chmax(best, dp[i][j - 1]);\n        dp[i][j] += best;\n    }\n    output(dp.back().back());\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1588882356, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03449.html", "problem_id": "p03449", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03449/input.txt", "sample_output_relpath": "derived/input_output/data/p03449/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03449/C++/s376046166.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s376046166", "user_id": "u671257784"}, "prompt_components": {"gold_output": "14\n", "input_to_evaluate": "#include \"bits/stdc++.h\"\n\n// Begin Header {{{\nusing namespace std;\n\n#ifndef DEBUG\n#define dump(...)\n#endif\n\n#define all(x) x.begin(), x.end()\n#define rep(i, b, e) for (intmax_t i = (b), i##_limit = (e); i < i##_limit; ++i)\n#define reps(i, b, e) for (intmax_t i = (b), i##_limit = (e); i <= i##_limit; ++i)\n#define repr(i, b, e) for (intmax_t i = (b), i##_limit = (e); i >= i##_limit; --i)\n#define var(Type, ...) Type __VA_ARGS__; input(__VA_ARGS__)\n\nconstexpr size_t    operator\"\"_zu(unsigned long long value) { return value; };\nconstexpr intmax_t  operator\"\"_jd(unsigned long long value) { return value; };\nconstexpr uintmax_t operator\"\"_ju(unsigned long long value) { return value; };\n\nconstexpr int INF = 0x3f3f3f3f;\nconstexpr intmax_t LINF = 0x3f3f3f3f3f3f3f3f_jd;\n\ntemplate <class T, class Compare = less<>>\nusing MaxHeap = priority_queue<T, vector<T>, Compare>;\ntemplate <class T, class Compare = greater<>>\nusing MinHeap = priority_queue<T, vector<T>, Compare>;\n\ninline void input() {}\ntemplate <class Head, class... Tail>\ninline void input(Head&& head, Tail&&... tail) {\n    cin >> head;\n    input(forward<Tail>(tail)...);\n}\n\ntemplate <class T>\ninline istream& operator>>(istream &is, vector<T> &vec) {\n    for (auto &e: vec) {\n        is >> e;\n    }\n    return is;\n}\n\ninline void output() { cout << \"\\n\"; }\ntemplate <class Head, class... Tail>\ninline void output(Head&& head, Tail&&... tail) {\n    cout << head;\n    if (sizeof...(tail)) {\n        cout << \" \";\n    }\n    output(forward<Tail>(tail)...);\n}\n\ntemplate <class T>\ninline ostream& operator<<(ostream &os, const vector<T> &vec) {\n    static constexpr const char *delim[] = {\" \", \"\"};\n    for (const auto &e: vec) {\n        os << e << delim[&e == &vec.back()];\n    }\n    return os;\n}\n\ntemplate <class T>\ninline vector<T> makeVector(const T &initValue, size_t sz) {\n    return vector<T>(sz, initValue);\n}\n\ntemplate <class T, class... Args>\ninline auto makeVector(const T &initValue, size_t sz, Args... args) {\n    return vector<decltype(makeVector<T>(initValue, args...))>(sz, makeVector<T>(initValue, args...));\n}\n\ntemplate <class Func>\nclass FixPoint : Func {\npublic:\n    explicit constexpr FixPoint(Func&& f) noexcept : Func(forward<Func>(f)) {}\n\n    template <class... Args>\n        constexpr decltype(auto) operator()(Args&&... args) const {\n            return Func::operator()(*this, std::forward<Args>(args)...);\n        }\n};\n\ntemplate <class Func>\nstatic inline constexpr decltype(auto) makeFixPoint(Func&& f) noexcept {\n    return FixPoint<Func>{forward<Func>(f)};\n}\n\ntemplate <class Container>\nstruct reverse_t {\n    Container &c;\n    reverse_t(Container &c) : c(c) {}\n    auto begin() { return c.rbegin(); }\n    auto end() { return c.rend(); }\n};\n\ntemplate <class Container>\nauto reversed(Container &c) {\n    return reverse_t<Container>(c);\n}\n\ntemplate <class T>\ninline bool chmax(T &a, const T &b) noexcept {\n    return b > a && (a = b, true);\n}\n\ntemplate <class T>\ninline bool chmin(T &a, const T &b) noexcept {\n    return b < a && (a = b, true);\n}\n\ntemplate <class T>\ninline T diff(const T &a, const T &b) noexcept {\n    return a < b ? b - a : a - b;\n}\n// End Header }}}\n\nsigned main() {\n    ios_base::sync_with_stdio(false);\n    cin.tie(nullptr);\n    cout.setf(ios_base::fixed);\n    cout.precision(10);\n    var(size_t, N);\n    auto dp = makeVector<intmax_t>(0, 2, N); input(dp);\n    rep(i, 0, 2) rep(j, 0, N) {\n        intmax_t best = 0;\n        if (i > 0) chmax(best, dp[i - 1][j]);\n        if (j > 0) chmax(best, dp[i][j - 1]);\n        dp[i][j] += best;\n    }\n    output(dp.back().back());\n    return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nWe have a 2 \\times N grid. We will denote the square at the i-th row and j-th column (1 \\leq i \\leq 2, 1 \\leq j \\leq N) as (i, j).\n\nYou are initially in the top-left square, (1, 1).\nYou will travel to the bottom-right square, (2, N), by repeatedly moving right or down.\n\nThe square (i, j) contains A_{i, j} candies.\nYou will collect all the candies you visit during the travel.\nThe top-left and bottom-right squares also contain candies, and you will also collect them.\n\nAt most how many candies can you collect when you choose the best way to travel?\n\nConstraints\n\n1 \\leq N \\leq 100\n\n1 \\leq A_{i, j} \\leq 100 (1 \\leq i \\leq 2, 1 \\leq j \\leq N)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_{1, 1} A_{1, 2} ... A_{1, N}\nA_{2, 1} A_{2, 2} ... A_{2, N}\n\nOutput\n\nPrint the maximum number of candies that can be collected.\n\nSample Input 1\n\n5\n3 2 2 4 1\n1 2 2 2 1\n\nSample Output 1\n\n14\n\nThe number of collected candies will be maximized when you:\n\nmove right three times, then move down once, then move right once.\n\nSample Input 2\n\n4\n1 1 1 1\n1 1 1 1\n\nSample Output 2\n\n5\n\nYou will always collect the same number of candies, regardless of how you travel.\n\nSample Input 3\n\n7\n3 3 4 5 4 5 3\n5 3 4 4 2 3 2\n\nSample Output 3\n\n29\n\nSample Input 4\n\n1\n2\n3\n\nSample Output 4\n\n5", "sample_input": "5\n3 2 2 4 1\n1 2 2 2 1\n"}, "reference_outputs": ["14\n"], "source_document_id": "p03449", "source_text": "Score : 300 points\n\nProblem Statement\n\nWe have a 2 \\times N grid. We will denote the square at the i-th row and j-th column (1 \\leq i \\leq 2, 1 \\leq j \\leq N) as (i, j).\n\nYou are initially in the top-left square, (1, 1).\nYou will travel to the bottom-right square, (2, N), by repeatedly moving right or down.\n\nThe square (i, j) contains A_{i, j} candies.\nYou will collect all the candies you visit during the travel.\nThe top-left and bottom-right squares also contain candies, and you will also collect them.\n\nAt most how many candies can you collect when you choose the best way to travel?\n\nConstraints\n\n1 \\leq N \\leq 100\n\n1 \\leq A_{i, j} \\leq 100 (1 \\leq i \\leq 2, 1 \\leq j \\leq N)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_{1, 1} A_{1, 2} ... A_{1, N}\nA_{2, 1} A_{2, 2} ... A_{2, N}\n\nOutput\n\nPrint the maximum number of candies that can be collected.\n\nSample Input 1\n\n5\n3 2 2 4 1\n1 2 2 2 1\n\nSample Output 1\n\n14\n\nThe number of collected candies will be maximized when you:\n\nmove right three times, then move down once, then move right once.\n\nSample Input 2\n\n4\n1 1 1 1\n1 1 1 1\n\nSample Output 2\n\n5\n\nYou will always collect the same number of candies, regardless of how you travel.\n\nSample Input 3\n\n7\n3 3 4 5 4 5 3\n5 3 4 4 2 3 2\n\nSample Output 3\n\n29\n\nSample Input 4\n\n1\n2\n3\n\nSample Output 4\n\n5", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 3588, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s639179822", "group_id": "codeNet:p03451", "input_text": "#include <cstdio>\n#include <vector>\n#include <algorithm>\n#include <numeric>\n\nint main() {\n  size_t N;\n  scanf(\"%zu\", &N);\n\n  std::vector<int> A(N), B(N);\n  for (auto& ai: A) scanf(\"%d\", &ai);\n  for (auto& bi: B) scanf(\"%d\", &bi);\n\n  int res = 0;\n  for (size_t i = 1; i <= N; ++i) {\n    int a = std::accumulate(A.begin(), A.begin()+i, 0);\n    int b = std::accumulate(B.begin()+(i-1), B.end(), 0);\n    res = std::max(res, a+b);\n  }\n  printf(\"%d\\n\", res);\n}\n", "language": "C++", "metadata": {"date": 1550151153, "filename_ext": "cpp", "original_language": "C++14 (Clang 3.8.0)", "problem_description_relpath": "problem_descriptions/p03451.html", "problem_id": "p03451", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03451/input.txt", "sample_output_relpath": "derived/input_output/data/p03451/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03451/C++/s639179822.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s639179822", "user_id": "u352499693"}, "prompt_components": {"gold_output": "14\n", "input_to_evaluate": "#include <cstdio>\n#include <vector>\n#include <algorithm>\n#include <numeric>\n\nint main() {\n  size_t N;\n  scanf(\"%zu\", &N);\n\n  std::vector<int> A(N), B(N);\n  for (auto& ai: A) scanf(\"%d\", &ai);\n  for (auto& bi: B) scanf(\"%d\", &bi);\n\n  int res = 0;\n  for (size_t i = 1; i <= N; ++i) {\n    int a = std::accumulate(A.begin(), A.begin()+i, 0);\n    int b = std::accumulate(B.begin()+(i-1), B.end(), 0);\n    res = std::max(res, a+b);\n  }\n  printf(\"%d\\n\", res);\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nWe have a 2 \\times N grid. We will denote the square at the i-th row and j-th column (1 \\leq i \\leq 2, 1 \\leq j \\leq N) as (i, j).\n\nYou are initially in the top-left square, (1, 1).\nYou will travel to the bottom-right square, (2, N), by repeatedly moving right or down.\n\nThe square (i, j) contains A_{i, j} candies.\nYou will collect all the candies you visit during the travel.\nThe top-left and bottom-right squares also contain candies, and you will also collect them.\n\nAt most how many candies can you collect when you choose the best way to travel?\n\nConstraints\n\n1 \\leq N \\leq 100\n\n1 \\leq A_{i, j} \\leq 100 (1 \\leq i \\leq 2, 1 \\leq j \\leq N)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_{1, 1} A_{1, 2} ... A_{1, N}\nA_{2, 1} A_{2, 2} ... A_{2, N}\n\nOutput\n\nPrint the maximum number of candies that can be collected.\n\nSample Input 1\n\n5\n3 2 2 4 1\n1 2 2 2 1\n\nSample Output 1\n\n14\n\nThe number of collected candies will be maximized when you:\n\nmove right three times, then move down once, then move right once.\n\nSample Input 2\n\n4\n1 1 1 1\n1 1 1 1\n\nSample Output 2\n\n5\n\nYou will always collect the same number of candies, regardless of how you travel.\n\nSample Input 3\n\n7\n3 3 4 5 4 5 3\n5 3 4 4 2 3 2\n\nSample Output 3\n\n29\n\nSample Input 4\n\n1\n2\n3\n\nSample Output 4\n\n5", "sample_input": "5\n3 2 2 4 1\n1 2 2 2 1\n"}, "reference_outputs": ["14\n"], "source_document_id": "p03451", "source_text": "Score : 300 points\n\nProblem Statement\n\nWe have a 2 \\times N grid. We will denote the square at the i-th row and j-th column (1 \\leq i \\leq 2, 1 \\leq j \\leq N) as (i, j).\n\nYou are initially in the top-left square, (1, 1).\nYou will travel to the bottom-right square, (2, N), by repeatedly moving right or down.\n\nThe square (i, j) contains A_{i, j} candies.\nYou will collect all the candies you visit during the travel.\nThe top-left and bottom-right squares also contain candies, and you will also collect them.\n\nAt most how many candies can you collect when you choose the best way to travel?\n\nConstraints\n\n1 \\leq N \\leq 100\n\n1 \\leq A_{i, j} \\leq 100 (1 \\leq i \\leq 2, 1 \\leq j \\leq N)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_{1, 1} A_{1, 2} ... A_{1, N}\nA_{2, 1} A_{2, 2} ... A_{2, N}\n\nOutput\n\nPrint the maximum number of candies that can be collected.\n\nSample Input 1\n\n5\n3 2 2 4 1\n1 2 2 2 1\n\nSample Output 1\n\n14\n\nThe number of collected candies will be maximized when you:\n\nmove right three times, then move down once, then move right once.\n\nSample Input 2\n\n4\n1 1 1 1\n1 1 1 1\n\nSample Output 2\n\n5\n\nYou will always collect the same number of candies, regardless of how you travel.\n\nSample Input 3\n\n7\n3 3 4 5 4 5 3\n5 3 4 4 2 3 2\n\nSample Output 3\n\n29\n\nSample Input 4\n\n1\n2\n3\n\nSample Output 4\n\n5", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 455, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s931724178", "group_id": "codeNet:p03452", "input_text": "#include <bits/stdc++.h>\n\n#define fr first\n#define sc second\n\nusing namespace std;\ntypedef pair<int, int> ii;\ntypedef long long ll;\ntypedef unsigned long long u64;\n\nconst int NMAX = 1e5 + 3, KEK = 1453, CMAX = 'z' - 'a' + 1, INF = 2e9;\nconst double EPS = 1e-5;\n\nvector<ii> g[NMAX];\nvector<char> used(NMAX);\nvector<int> ans(NMAX, -INF);\nbool can = 1;\n\nvoid dfs(int v) {\n    used[v] = 1;\n    if (ans[v] == -INF) {\n        ans[v] = 0;\n    }\n    for (ii pp : g[v]) {\n        int to = pp.fr, d = pp.sc;\n        if (!used[to]) {\n            ans[to] = ans[v] + d;\n            dfs(to);\n        } else if (ans[to] != ans[v] + d) {\n            can = 0;\n        }\n    }\n}\n\nmain() {\n    #ifdef HOME\n        freopen(\"input.txt\", \"r\", stdin);\n    #else\n//        freopen(\"newphone.in\", \"r\", stdin);\n//        freopen(\"newphone.out\", \"w\", stdout);\n    #endif\n    ios::sync_with_stdio(0);\n    cin.tie(0), cout.tie(0);\n    int n, m;\n    cin >> n >> m;\n    for (int i = 0; i < m; ++i) {\n        int l, r, d;\n        cin >> l >> r >> d, --l, --r;\n        g[l].push_back({r, d});\n        g[r].push_back({l, -d});\n    }\n    for (int i = 0; i < n; ++i) {\n        if (!used[i]) {\n            dfs(i);\n        }\n    }\n    if (can) {\n        cout << \"Yes\";\n    } else {\n        cout << \"No\";\n    }\n}\n", "language": "C++", "metadata": {"date": 1517192526, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03452.html", "problem_id": "p03452", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03452/input.txt", "sample_output_relpath": "derived/input_output/data/p03452/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03452/C++/s931724178.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s931724178", "user_id": "u062807968"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\n#define fr first\n#define sc second\n\nusing namespace std;\ntypedef pair<int, int> ii;\ntypedef long long ll;\ntypedef unsigned long long u64;\n\nconst int NMAX = 1e5 + 3, KEK = 1453, CMAX = 'z' - 'a' + 1, INF = 2e9;\nconst double EPS = 1e-5;\n\nvector<ii> g[NMAX];\nvector<char> used(NMAX);\nvector<int> ans(NMAX, -INF);\nbool can = 1;\n\nvoid dfs(int v) {\n    used[v] = 1;\n    if (ans[v] == -INF) {\n        ans[v] = 0;\n    }\n    for (ii pp : g[v]) {\n        int to = pp.fr, d = pp.sc;\n        if (!used[to]) {\n            ans[to] = ans[v] + d;\n            dfs(to);\n        } else if (ans[to] != ans[v] + d) {\n            can = 0;\n        }\n    }\n}\n\nmain() {\n    #ifdef HOME\n        freopen(\"input.txt\", \"r\", stdin);\n    #else\n//        freopen(\"newphone.in\", \"r\", stdin);\n//        freopen(\"newphone.out\", \"w\", stdout);\n    #endif\n    ios::sync_with_stdio(0);\n    cin.tie(0), cout.tie(0);\n    int n, m;\n    cin >> n >> m;\n    for (int i = 0; i < m; ++i) {\n        int l, r, d;\n        cin >> l >> r >> d, --l, --r;\n        g[l].push_back({r, d});\n        g[r].push_back({l, -d});\n    }\n    for (int i = 0; i < n; ++i) {\n        if (!used[i]) {\n            dfs(i);\n        }\n    }\n    if (can) {\n        cout << \"Yes\";\n    } else {\n        cout << \"No\";\n    }\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nThere are N people standing on the x-axis.\nLet the coordinate of Person i be x_i.\nFor every i, x_i is an integer between 0 and 10^9 (inclusive).\nIt is possible that more than one person is standing at the same coordinate.\n\nYou will given M pieces of information regarding the positions of these people.\nThe i-th piece of information has the form (L_i, R_i, D_i).\nThis means that Person R_i is to the right of Person L_i by D_i units of distance, that is, x_{R_i} - x_{L_i} = D_i holds.\n\nIt turns out that some of these M pieces of information may be incorrect.\nDetermine if there exists a set of values (x_1, x_2, ..., x_N) that is consistent with the given pieces of information.\n\nConstraints\n\n1 \\leq N \\leq 100 000\n\n0 \\leq M \\leq 200 000\n\n1 \\leq L_i, R_i \\leq N (1 \\leq i \\leq M)\n\n0 \\leq D_i \\leq 10 000 (1 \\leq i \\leq M)\n\nL_i \\neq R_i (1 \\leq i \\leq M)\n\nIf i \\neq j, then (L_i, R_i) \\neq (L_j, R_j) and (L_i, R_i) \\neq (R_j, L_j).\n\nD_i are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nL_1 R_1 D_1\nL_2 R_2 D_2\n:\nL_M R_M D_M\n\nOutput\n\nIf there exists a set of values (x_1, x_2, ..., x_N) that is consistent with all given pieces of information, print Yes; if it does not exist, print No.\n\nSample Input 1\n\n3 3\n1 2 1\n2 3 1\n1 3 2\n\nSample Output 1\n\nYes\n\nSome possible sets of values (x_1, x_2, x_3) are (0, 1, 2) and (101, 102, 103).\n\nSample Input 2\n\n3 3\n1 2 1\n2 3 1\n1 3 5\n\nSample Output 2\n\nNo\n\nIf the first two pieces of information are correct, x_3 - x_1 = 2 holds, which is contradictory to the last piece of information.\n\nSample Input 3\n\n4 3\n2 1 1\n2 3 5\n3 4 2\n\nSample Output 3\n\nYes\n\nSample Input 4\n\n10 3\n8 7 100\n7 9 100\n9 8 100\n\nSample Output 4\n\nNo\n\nSample Input 5\n\n100 0\n\nSample Output 5\n\nYes", "sample_input": "3 3\n1 2 1\n2 3 1\n1 3 2\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p03452", "source_text": "Score : 400 points\n\nProblem Statement\n\nThere are N people standing on the x-axis.\nLet the coordinate of Person i be x_i.\nFor every i, x_i is an integer between 0 and 10^9 (inclusive).\nIt is possible that more than one person is standing at the same coordinate.\n\nYou will given M pieces of information regarding the positions of these people.\nThe i-th piece of information has the form (L_i, R_i, D_i).\nThis means that Person R_i is to the right of Person L_i by D_i units of distance, that is, x_{R_i} - x_{L_i} = D_i holds.\n\nIt turns out that some of these M pieces of information may be incorrect.\nDetermine if there exists a set of values (x_1, x_2, ..., x_N) that is consistent with the given pieces of information.\n\nConstraints\n\n1 \\leq N \\leq 100 000\n\n0 \\leq M \\leq 200 000\n\n1 \\leq L_i, R_i \\leq N (1 \\leq i \\leq M)\n\n0 \\leq D_i \\leq 10 000 (1 \\leq i \\leq M)\n\nL_i \\neq R_i (1 \\leq i \\leq M)\n\nIf i \\neq j, then (L_i, R_i) \\neq (L_j, R_j) and (L_i, R_i) \\neq (R_j, L_j).\n\nD_i are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nL_1 R_1 D_1\nL_2 R_2 D_2\n:\nL_M R_M D_M\n\nOutput\n\nIf there exists a set of values (x_1, x_2, ..., x_N) that is consistent with all given pieces of information, print Yes; if it does not exist, print No.\n\nSample Input 1\n\n3 3\n1 2 1\n2 3 1\n1 3 2\n\nSample Output 1\n\nYes\n\nSome possible sets of values (x_1, x_2, x_3) are (0, 1, 2) and (101, 102, 103).\n\nSample Input 2\n\n3 3\n1 2 1\n2 3 1\n1 3 5\n\nSample Output 2\n\nNo\n\nIf the first two pieces of information are correct, x_3 - x_1 = 2 holds, which is contradictory to the last piece of information.\n\nSample Input 3\n\n4 3\n2 1 1\n2 3 5\n3 4 2\n\nSample Output 3\n\nYes\n\nSample Input 4\n\n10 3\n8 7 100\n7 9 100\n9 8 100\n\nSample Output 4\n\nNo\n\nSample Input 5\n\n100 0\n\nSample Output 5\n\nYes", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1274, "cpu_time_ms": 114, "memory_kb": 11136}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s918806775", "group_id": "codeNet:p03456", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n string s1,s2,s3;\n  cin >>s1>>s2;\n  s3=s1+s2;\n  int n=stoi(s3);\n  int x;\n  string ans =\"No\";\n   int i=1;\n  while(i<111){\n    x= i*i;\n    if (x==n){\n      ans=\"Yes\";\n      break;\n    }\n    i++;\n  }\n  cout <<ans ;\n    \n}\n", "language": "C++", "metadata": {"date": 1579287723, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03456.html", "problem_id": "p03456", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03456/input.txt", "sample_output_relpath": "derived/input_output/data/p03456/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03456/C++/s918806775.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s918806775", "user_id": "u260907804"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n string s1,s2,s3;\n  cin >>s1>>s2;\n  s3=s1+s2;\n  int n=stoi(s3);\n  int x;\n  string ans =\"No\";\n   int i=1;\n  while(i<111){\n    x= i*i;\n    if (x==n){\n      ans=\"Yes\";\n      break;\n    }\n    i++;\n  }\n  cout <<ans ;\n    \n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nAtCoDeer the deer has found two positive integers, a and b.\nDetermine whether the concatenation of a and b in this order is a square number.\n\nConstraints\n\n1 ≤ a,b ≤ 100\n\na and b are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\na b\n\nOutput\n\nIf the concatenation of a and b in this order is a square number, print Yes; otherwise, print No.\n\nSample Input 1\n\n1 21\n\nSample Output 1\n\nYes\n\nAs 121 = 11 × 11, it is a square number.\n\nSample Input 2\n\n100 100\n\nSample Output 2\n\nNo\n\n100100 is not a square number.\n\nSample Input 3\n\n12 10\n\nSample Output 3\n\nNo", "sample_input": "1 21\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p03456", "source_text": "Score : 200 points\n\nProblem Statement\n\nAtCoDeer the deer has found two positive integers, a and b.\nDetermine whether the concatenation of a and b in this order is a square number.\n\nConstraints\n\n1 ≤ a,b ≤ 100\n\na and b are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\na b\n\nOutput\n\nIf the concatenation of a and b in this order is a square number, print Yes; otherwise, print No.\n\nSample Input 1\n\n1 21\n\nSample Output 1\n\nYes\n\nAs 121 = 11 × 11, it is a square number.\n\nSample Input 2\n\n100 100\n\nSample Output 2\n\nNo\n\n100100 is not a square number.\n\nSample Input 3\n\n12 10\n\nSample Output 3\n\nNo", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 279, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s875852021", "group_id": "codeNet:p03460", "input_text": "#include<cstdio>\n#include<algorithm>\nusing namespace std;\n\ninline int read()\n{\n\tint x=0,f=1;char ch=getchar();\n\twhile(ch<'0' || '9'<ch){if(ch=='-')f=-1;ch=getchar();}\n\twhile('0'<=ch && ch<='9')x=x*10+(ch^48),ch=getchar();\n\treturn x*f;\n}\n\ninline void writes(int x)\n{\n\tif(x>=10)writes(x/10);\n\tputchar('0'+x%10);\n}\n\ninline void write(int x,char ch='\\n')\n{\n\tif(x<0)putchar('-'),writes(-x);\n\telse writes(x);putchar(ch);\n}\n\nconst int N=1e5+9;\nconst int K=2009;\nconst int KK=(K<<1)+9;\n\nint n,k,kk;\nint x[N],y[N];\nint w[KK][KK],b[KK][KK];\n\ninline int query(int (*a)[KK],int x1,int y1,int x2,int y2)\n{\n\tx2=min(x2,kk),y2=min(y2,kk);\n\tint ret=0;\n\tif(x2>=0 && y2>=0)ret=a[x2][y2];\n\tif(x1>0 && y2>=0)ret-=a[x1-1][y2];\n\tif(y1>0 && x2>=0)ret-=a[x2][y1-1];\n\tif(x1>0 && y1>0)ret+=a[x1-1][y1-1];\n\treturn ret;\n}\n\nint main()\n{\n\tif(fopen(\"vj.in\",\"r\"))\n\t{\n\t\tfreopen(\"vj.in\",\"r\",stdin);\n\t\tfreopen(\"vj.out\",\"w\",stdout);\n\t}\n\n\tn=read();k=read();\n\tchar c[190];\n\tkk=k*2;\n\tfor(int i=1;i<=n;i++)\n\t{\n\t\tx[i]=read();y[i]=read();scanf(\"%s\",c+1);\n\t\tif(c[1]=='B')\n\t\t\tb[x[i]%kk][y[i]%kk]++;\n\t\telse\n\t\t\tw[x[i]%kk][y[i]%kk]++;\n\t}\n\n\tfor(int i=0,j=1;j<=kk;j++)\n\t{\n\t\tb[i][j]+=b[i][j-1];\n\t\tw[i][j]+=w[i][j-1];\n\t}\n\tfor(int i=1,j=0;i<=kk;i++)\n\t{\n\t\tb[i][j]+=b[i-1][j];\n\t\tw[i][j]+=w[i-1][j];\n\t}\n\tfor(int i=1;i<=kk;i++)\n\t\tfor(int j=1;j<=kk;j++)\n\t\t{\n\t\t\tb[i][j]+=b[i-1][j]+b[i][j-1]-b[i-1][j-1];\n\t\t\tw[i][j]+=w[i-1][j]+w[i][j-1]-w[i-1][j-1];\n\t\t}\n\n\t/*\n\tfor(int i=0;i<=6;i++,puts(\"\"))\n\t\tfor(int j=0;j<=6;j++)\n\t\t\tprintf(\"%d \",b[i][j]);\n\tputs(\"\");\n\tfor(int i=0;i<=6;i++,puts(\"\"))\n\t\tfor(int j=0;j<=6;j++)\n\t\t\tprintf(\"%d \",w[i][j]);\n\t*/\n\n\tint ans=0;\n\tfor(int tim=0;tim<=1;tim++)\n\t{\n\tfor(int i=0;i<=k;i++)\n\t\tfor(int j=0;j<=k;j++)\n\t\t{\n\t\t\tint satw=query(w,i,j,i+k-1,j+k-1)+query(w,i+k,j+k,i+k+k-1,j+k+k-1);\n\t\t\tsatw+=query(w,i+k,0,i+k+k-1,j-1)+query(w,0,j+k,i-1,j+k+k-1);\n\t\t\tif(i>0 && j>0)satw+=w[i-1][j-1];\n\n\t\t\tint satb=query(b,i+k,j,i+k+k-1,j+k-1)+query(b,i,j+k,i+k-1,j+k+k-1);\n\t\t\tsatb+=query(b,i,0,i+k-1,j-1)+query(b,0,j,i-1,j+k-1);\n\n\t\t\tans=max(ans,satw+satb);\n\t\t}\n\n\tswap(w,b);\n\t}\n\n\t\n\tprintf(\"%d\\n\",ans);\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1516589568, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03460.html", "problem_id": "p03460", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03460/input.txt", "sample_output_relpath": "derived/input_output/data/p03460/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03460/C++/s875852021.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s875852021", "user_id": "u093990678"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include<cstdio>\n#include<algorithm>\nusing namespace std;\n\ninline int read()\n{\n\tint x=0,f=1;char ch=getchar();\n\twhile(ch<'0' || '9'<ch){if(ch=='-')f=-1;ch=getchar();}\n\twhile('0'<=ch && ch<='9')x=x*10+(ch^48),ch=getchar();\n\treturn x*f;\n}\n\ninline void writes(int x)\n{\n\tif(x>=10)writes(x/10);\n\tputchar('0'+x%10);\n}\n\ninline void write(int x,char ch='\\n')\n{\n\tif(x<0)putchar('-'),writes(-x);\n\telse writes(x);putchar(ch);\n}\n\nconst int N=1e5+9;\nconst int K=2009;\nconst int KK=(K<<1)+9;\n\nint n,k,kk;\nint x[N],y[N];\nint w[KK][KK],b[KK][KK];\n\ninline int query(int (*a)[KK],int x1,int y1,int x2,int y2)\n{\n\tx2=min(x2,kk),y2=min(y2,kk);\n\tint ret=0;\n\tif(x2>=0 && y2>=0)ret=a[x2][y2];\n\tif(x1>0 && y2>=0)ret-=a[x1-1][y2];\n\tif(y1>0 && x2>=0)ret-=a[x2][y1-1];\n\tif(x1>0 && y1>0)ret+=a[x1-1][y1-1];\n\treturn ret;\n}\n\nint main()\n{\n\tif(fopen(\"vj.in\",\"r\"))\n\t{\n\t\tfreopen(\"vj.in\",\"r\",stdin);\n\t\tfreopen(\"vj.out\",\"w\",stdout);\n\t}\n\n\tn=read();k=read();\n\tchar c[190];\n\tkk=k*2;\n\tfor(int i=1;i<=n;i++)\n\t{\n\t\tx[i]=read();y[i]=read();scanf(\"%s\",c+1);\n\t\tif(c[1]=='B')\n\t\t\tb[x[i]%kk][y[i]%kk]++;\n\t\telse\n\t\t\tw[x[i]%kk][y[i]%kk]++;\n\t}\n\n\tfor(int i=0,j=1;j<=kk;j++)\n\t{\n\t\tb[i][j]+=b[i][j-1];\n\t\tw[i][j]+=w[i][j-1];\n\t}\n\tfor(int i=1,j=0;i<=kk;i++)\n\t{\n\t\tb[i][j]+=b[i-1][j];\n\t\tw[i][j]+=w[i-1][j];\n\t}\n\tfor(int i=1;i<=kk;i++)\n\t\tfor(int j=1;j<=kk;j++)\n\t\t{\n\t\t\tb[i][j]+=b[i-1][j]+b[i][j-1]-b[i-1][j-1];\n\t\t\tw[i][j]+=w[i-1][j]+w[i][j-1]-w[i-1][j-1];\n\t\t}\n\n\t/*\n\tfor(int i=0;i<=6;i++,puts(\"\"))\n\t\tfor(int j=0;j<=6;j++)\n\t\t\tprintf(\"%d \",b[i][j]);\n\tputs(\"\");\n\tfor(int i=0;i<=6;i++,puts(\"\"))\n\t\tfor(int j=0;j<=6;j++)\n\t\t\tprintf(\"%d \",w[i][j]);\n\t*/\n\n\tint ans=0;\n\tfor(int tim=0;tim<=1;tim++)\n\t{\n\tfor(int i=0;i<=k;i++)\n\t\tfor(int j=0;j<=k;j++)\n\t\t{\n\t\t\tint satw=query(w,i,j,i+k-1,j+k-1)+query(w,i+k,j+k,i+k+k-1,j+k+k-1);\n\t\t\tsatw+=query(w,i+k,0,i+k+k-1,j-1)+query(w,0,j+k,i-1,j+k+k-1);\n\t\t\tif(i>0 && j>0)satw+=w[i-1][j-1];\n\n\t\t\tint satb=query(b,i+k,j,i+k+k-1,j+k-1)+query(b,i,j+k,i+k-1,j+k+k-1);\n\t\t\tsatb+=query(b,i,0,i+k-1,j-1)+query(b,0,j,i-1,j+k-1);\n\n\t\t\tans=max(ans,satw+satb);\n\t\t}\n\n\tswap(w,b);\n\t}\n\n\t\n\tprintf(\"%d\\n\",ans);\n\treturn 0;\n}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nAtCoDeer is thinking of painting an infinite two-dimensional grid in a checked pattern of side K.\nHere, a checked pattern of side K is a pattern where each square is painted black or white so that each connected component of each color is a K × K square.\nBelow is an example of a checked pattern of side 3:\n\nAtCoDeer has N desires.\nThe i-th desire is represented by x_i, y_i and c_i.\nIf c_i is B, it means that he wants to paint the square (x_i,y_i) black; if c_i is W, he wants to paint the square (x_i,y_i) white.\nAt most how many desires can he satisfy at the same time?\n\nConstraints\n\n1 ≤ N ≤ 10^5\n\n1 ≤ K ≤ 1000\n\n0 ≤ x_i ≤ 10^9\n\n0 ≤ y_i ≤ 10^9\n\nIf i ≠ j, then (x_i,y_i) ≠ (x_j,y_j).\n\nc_i is B or W.\n\nN, K, x_i and y_i are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nx_1 y_1 c_1\nx_2 y_2 c_2\n:\nx_N y_N c_N\n\nOutput\n\nPrint the maximum number of desires that can be satisfied at the same time.\n\nSample Input 1\n\n4 3\n0 1 W\n1 2 W\n5 3 B\n5 4 B\n\nSample Output 1\n\n4\n\nHe can satisfy all his desires by painting as shown in the example above.\n\nSample Input 2\n\n2 1000\n0 0 B\n0 1 W\n\nSample Output 2\n\n2\n\nSample Input 3\n\n6 2\n1 2 B\n2 1 W\n2 2 B\n1 0 B\n0 6 W\n4 5 W\n\nSample Output 3\n\n4", "sample_input": "4 3\n0 1 W\n1 2 W\n5 3 B\n5 4 B\n"}, "reference_outputs": ["4\n"], "source_document_id": "p03460", "source_text": "Score : 500 points\n\nProblem Statement\n\nAtCoDeer is thinking of painting an infinite two-dimensional grid in a checked pattern of side K.\nHere, a checked pattern of side K is a pattern where each square is painted black or white so that each connected component of each color is a K × K square.\nBelow is an example of a checked pattern of side 3:\n\nAtCoDeer has N desires.\nThe i-th desire is represented by x_i, y_i and c_i.\nIf c_i is B, it means that he wants to paint the square (x_i,y_i) black; if c_i is W, he wants to paint the square (x_i,y_i) white.\nAt most how many desires can he satisfy at the same time?\n\nConstraints\n\n1 ≤ N ≤ 10^5\n\n1 ≤ K ≤ 1000\n\n0 ≤ x_i ≤ 10^9\n\n0 ≤ y_i ≤ 10^9\n\nIf i ≠ j, then (x_i,y_i) ≠ (x_j,y_j).\n\nc_i is B or W.\n\nN, K, x_i and y_i are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nx_1 y_1 c_1\nx_2 y_2 c_2\n:\nx_N y_N c_N\n\nOutput\n\nPrint the maximum number of desires that can be satisfied at the same time.\n\nSample Input 1\n\n4 3\n0 1 W\n1 2 W\n5 3 B\n5 4 B\n\nSample Output 1\n\n4\n\nHe can satisfy all his desires by painting as shown in the example above.\n\nSample Input 2\n\n2 1000\n0 0 B\n0 1 W\n\nSample Output 2\n\n2\n\nSample Input 3\n\n6 2\n1 2 B\n2 1 W\n2 2 B\n1 0 B\n0 6 W\n4 5 W\n\nSample Output 3\n\n4", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2058, "cpu_time_ms": 135, "memory_kb": 127616}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s189113883", "group_id": "codeNet:p03463", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n#define ll long long\n\nint main(){\n    int N, A, B;\n    cin >> N >> A >> B;\n    if ((B-A)%2) cout << \"Borys\" << endl;\n    else cout << \"Alice\" << endl;\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1576703936, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03463.html", "problem_id": "p03463", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03463/input.txt", "sample_output_relpath": "derived/input_output/data/p03463/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03463/C++/s189113883.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s189113883", "user_id": "u548834738"}, "prompt_components": {"gold_output": "Alice\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n#define ll long long\n\nint main(){\n    int N, A, B;\n    cin >> N >> A >> B;\n    if ((B-A)%2) cout << \"Borys\" << endl;\n    else cout << \"Alice\" << endl;\n    return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nA game is played on a strip consisting of N cells consecutively numbered from 1 to N.\n\nAlice has her token on cell A. Borys has his token on a different cell B.\n\nPlayers take turns, Alice moves first.\nThe moving player must shift his or her token from its current cell X to the neighboring cell on the left, cell X-1, or on the right, cell X+1.\nNote that it's disallowed to move the token outside the strip or to the cell with the other player's token.\nIn one turn, the token of the moving player must be shifted exactly once.\n\nThe player who can't make a move loses, and the other player wins.\n\nBoth players want to win. Who wins if they play optimally?\n\nConstraints\n\n2 \\leq N \\leq 100\n\n1 \\leq A < B \\leq N\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN A B\n\nOutput\n\nPrint Alice if Alice wins, Borys if Borys wins, and Draw if nobody wins.\n\nSample Input 1\n\n5 2 4\n\nSample Output 1\n\nAlice\n\nAlice can move her token to cell 3.\nAfter that, Borys will be unable to move his token to cell 3, so he will have to move his token to cell 5.\nThen, Alice moves her token to cell 4. Borys can't make a move and loses.\n\nSample Input 2\n\n2 1 2\n\nSample Output 2\n\nBorys\n\nAlice can't make the very first move and loses.\n\nSample Input 3\n\n58 23 42\n\nSample Output 3\n\nBorys", "sample_input": "5 2 4\n"}, "reference_outputs": ["Alice\n"], "source_document_id": "p03463", "source_text": "Score : 300 points\n\nProblem Statement\n\nA game is played on a strip consisting of N cells consecutively numbered from 1 to N.\n\nAlice has her token on cell A. Borys has his token on a different cell B.\n\nPlayers take turns, Alice moves first.\nThe moving player must shift his or her token from its current cell X to the neighboring cell on the left, cell X-1, or on the right, cell X+1.\nNote that it's disallowed to move the token outside the strip or to the cell with the other player's token.\nIn one turn, the token of the moving player must be shifted exactly once.\n\nThe player who can't make a move loses, and the other player wins.\n\nBoth players want to win. Who wins if they play optimally?\n\nConstraints\n\n2 \\leq N \\leq 100\n\n1 \\leq A < B \\leq N\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN A B\n\nOutput\n\nPrint Alice if Alice wins, Borys if Borys wins, and Draw if nobody wins.\n\nSample Input 1\n\n5 2 4\n\nSample Output 1\n\nAlice\n\nAlice can move her token to cell 3.\nAfter that, Borys will be unable to move his token to cell 3, so he will have to move his token to cell 5.\nThen, Alice moves her token to cell 4. Borys can't make a move and loses.\n\nSample Input 2\n\n2 1 2\n\nSample Output 2\n\nBorys\n\nAlice can't make the very first move and loses.\n\nSample Input 3\n\n58 23 42\n\nSample Output 3\n\nBorys", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 213, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s826888630", "group_id": "codeNet:p03464", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef vector<ll> vec;\ntypedef vector<vec> mat;\ntypedef pair<ll,ll> pll;\nconst ll mod=1e9+7;\n//const ll mod=998244353;\nconst ll inf=5e18;\n\nint main() {\n  ll k;\n  cin >> k;\n  vec a(k);\n  for(ll i=0;i<k;i++) {\n    cin >> a[i];\n  }\n  ll mx=3;\n  ll mn=2;\n  if(a[k-1]!=2) {\n    cout << -1 << endl;\n    return 0;\n  }\n  for(ll i=1;i<k;i++) {\n    ll team=a[k-1-i];\n    if(mx<team) {\n      cout << -1 << endl;\n      return 0;\n    }\n    mx=mx/team*team+team-1;\n    mn=(mn+team-1)/team*team;\n    if(mn>mx) {\n      cout << -1 << endl;\n      return 0;\n    }\n  }\n  cout << mn << \" \" << mx << endl;\n}", "language": "C++", "metadata": {"date": 1584893733, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03464.html", "problem_id": "p03464", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03464/input.txt", "sample_output_relpath": "derived/input_output/data/p03464/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03464/C++/s826888630.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s826888630", "user_id": "u718758485"}, "prompt_components": {"gold_output": "6 8\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef vector<ll> vec;\ntypedef vector<vec> mat;\ntypedef pair<ll,ll> pll;\nconst ll mod=1e9+7;\n//const ll mod=998244353;\nconst ll inf=5e18;\n\nint main() {\n  ll k;\n  cin >> k;\n  vec a(k);\n  for(ll i=0;i<k;i++) {\n    cin >> a[i];\n  }\n  ll mx=3;\n  ll mn=2;\n  if(a[k-1]!=2) {\n    cout << -1 << endl;\n    return 0;\n  }\n  for(ll i=1;i<k;i++) {\n    ll team=a[k-1-i];\n    if(mx<team) {\n      cout << -1 << endl;\n      return 0;\n    }\n    mx=mx/team*team+team-1;\n    mn=(mn+team-1)/team*team;\n    if(mn>mx) {\n      cout << -1 << endl;\n      return 0;\n    }\n  }\n  cout << mn << \" \" << mx << endl;\n}", "problem_context": "Score : 500 points\n\nProblem Statement\n\nAn adult game master and N children are playing a game on an ice rink.\nThe game consists of K rounds.\nIn the i-th round, the game master announces:\n\nForm groups consisting of A_i children each!\n\nThen the children who are still in the game form as many groups of A_i children as possible.\nOne child may belong to at most one group.\nThose who are left without a group leave the game. The others proceed to the next round.\nNote that it's possible that nobody leaves the game in some round.\n\nIn the end, after the K-th round, there are exactly two children left, and they are declared the winners.\n\nYou have heard the values of A_1, A_2, ..., A_K. You don't know N, but you want to estimate it.\n\nFind the smallest and the largest possible number of children in the game before the start, or determine that no valid values of N exist.\n\nConstraints\n\n1 \\leq K \\leq 10^5\n\n2 \\leq A_i \\leq 10^9\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nK\nA_1 A_2 ... A_K\n\nOutput\n\nPrint two integers representing the smallest and the largest possible value of N, respectively,\nor a single integer -1 if the described situation is impossible.\n\nSample Input 1\n\n4\n3 4 3 2\n\nSample Output 1\n\n6 8\n\nFor example, if the game starts with 6 children, then it proceeds as follows:\n\nIn the first round, 6 children form 2 groups of 3 children, and nobody leaves the game.\n\nIn the second round, 6 children form 1 group of 4 children, and 2 children leave the game.\n\nIn the third round, 4 children form 1 group of 3 children, and 1 child leaves the game.\n\nIn the fourth round, 3 children form 1 group of 2 children, and 1 child leaves the game.\n\nThe last 2 children are declared the winners.\n\nSample Input 2\n\n5\n3 4 100 3 2\n\nSample Output 2\n\n-1\n\nThis situation is impossible.\nIn particular, if the game starts with less than 100 children, everyone leaves after the third round.\n\nSample Input 3\n\n10\n2 2 2 2 2 2 2 2 2 2\n\nSample Output 3\n\n2 3", "sample_input": "4\n3 4 3 2\n"}, "reference_outputs": ["6 8\n"], "source_document_id": "p03464", "source_text": "Score : 500 points\n\nProblem Statement\n\nAn adult game master and N children are playing a game on an ice rink.\nThe game consists of K rounds.\nIn the i-th round, the game master announces:\n\nForm groups consisting of A_i children each!\n\nThen the children who are still in the game form as many groups of A_i children as possible.\nOne child may belong to at most one group.\nThose who are left without a group leave the game. The others proceed to the next round.\nNote that it's possible that nobody leaves the game in some round.\n\nIn the end, after the K-th round, there are exactly two children left, and they are declared the winners.\n\nYou have heard the values of A_1, A_2, ..., A_K. You don't know N, but you want to estimate it.\n\nFind the smallest and the largest possible number of children in the game before the start, or determine that no valid values of N exist.\n\nConstraints\n\n1 \\leq K \\leq 10^5\n\n2 \\leq A_i \\leq 10^9\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nK\nA_1 A_2 ... A_K\n\nOutput\n\nPrint two integers representing the smallest and the largest possible value of N, respectively,\nor a single integer -1 if the described situation is impossible.\n\nSample Input 1\n\n4\n3 4 3 2\n\nSample Output 1\n\n6 8\n\nFor example, if the game starts with 6 children, then it proceeds as follows:\n\nIn the first round, 6 children form 2 groups of 3 children, and nobody leaves the game.\n\nIn the second round, 6 children form 1 group of 4 children, and 2 children leave the game.\n\nIn the third round, 4 children form 1 group of 3 children, and 1 child leaves the game.\n\nIn the fourth round, 3 children form 1 group of 2 children, and 1 child leaves the game.\n\nThe last 2 children are declared the winners.\n\nSample Input 2\n\n5\n3 4 100 3 2\n\nSample Output 2\n\n-1\n\nThis situation is impossible.\nIn particular, if the game starts with less than 100 children, everyone leaves after the third round.\n\nSample Input 3\n\n10\n2 2 2 2 2 2 2 2 2 2\n\nSample Output 3\n\n2 3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 653, "cpu_time_ms": 43, "memory_kb": 1024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s734624884", "group_id": "codeNet:p03464", "input_text": "/*#include <iostream>\n#include<cstdlib>\n#include<queue>\n#include<set>\n#include<vector>\n#include<string>\n#include<algorithm>\n#include<stack>\n#include<map>\n#include<cstdio>\nusing namespace std;\n#define rep(i,a) for(int i=0;i<a;i++)\n#define mp make_pair\n#define pb push_back\n#define P pair<int,int>\n#define ll __int64\nint n;\nint t[110000];\n\nint main(){\ncin>>n;\nint sum=0;\nrep(i,n)cin>>t[i];\nif(n==0)cout<<t[0]<<endl;\n\nelse{\n\nsort(t,t+n);\nfor(int i=0;i<(n+1)/2;i++)sum+=t[i];\n\n}\ncout<<sum<<endl;\n\treturn 0;\n}*/\n\n#include <iostream>\n#include<cstdlib>\n#include<queue>\n#include<set>\n#include<vector>\n#include<string>\n#include<algorithm>\n#include<stack>\n#include<map>\n#include<cstdio>\nusing namespace std;\n#define rep(i,a) for(int i=0;i<a;i++)\n#define mp make_pair\n#define pb push_back\n#define P pair<int,int>\n#define ll __int64\nint n;\nint t[110000];\nconst int MA=2000000000;\nint ansma,ansmi;\nint mid,l,r;\n\nint simyu(int num){\nrep(i,n){\n\tif(num/t[i]==0)return 0;\n\tnum=num-num%t[i];\n}\nreturn num;\n}\n\nint main(){\ncin>>n;\nint mma=-1;\nrep(i,n){cin>>t[i];}\n\nl=0;\nr=MA;\nmid=(l+r)/2;\nfor(int i=0;i<50;i++){\n\tint now=simyu(mid);\n\tif(now<=2){\n\t\tl=mid;\n\t\tmid=(l+r)/2;\n\t}\n\telse{\n\t\tr=mid;\n\t\tmid=(l+r)/2;\n\t}\n\t//cout<<l<<\" \"<<r<<\" \"<<mid<<\" \"<<now<<endl;\n\tansma=mid;\n}\n\nl=0;\nr=MA;\nmid=(l+r)/2;\n\nfor(int i=0;i<50;i++){\n\tint now=simyu(mid);\n\n\tif(now<2){\n\t\tl=mid;\n\t\tmid=(l+r)/2;\n\t}\n\telse{\n\t\tr=mid;\n\t\tmid=(l+r)/2;\n\t}\n\tansmi=mid+1;\n}\nif(ansmi>ansma)cout<<-1<<endl;\nelse cout<<ansmi<<\" \"<<ansma<<endl;\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1516057033, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03464.html", "problem_id": "p03464", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03464/input.txt", "sample_output_relpath": "derived/input_output/data/p03464/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03464/C++/s734624884.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s734624884", "user_id": "u341406884"}, "prompt_components": {"gold_output": "6 8\n", "input_to_evaluate": "/*#include <iostream>\n#include<cstdlib>\n#include<queue>\n#include<set>\n#include<vector>\n#include<string>\n#include<algorithm>\n#include<stack>\n#include<map>\n#include<cstdio>\nusing namespace std;\n#define rep(i,a) for(int i=0;i<a;i++)\n#define mp make_pair\n#define pb push_back\n#define P pair<int,int>\n#define ll __int64\nint n;\nint t[110000];\n\nint main(){\ncin>>n;\nint sum=0;\nrep(i,n)cin>>t[i];\nif(n==0)cout<<t[0]<<endl;\n\nelse{\n\nsort(t,t+n);\nfor(int i=0;i<(n+1)/2;i++)sum+=t[i];\n\n}\ncout<<sum<<endl;\n\treturn 0;\n}*/\n\n#include <iostream>\n#include<cstdlib>\n#include<queue>\n#include<set>\n#include<vector>\n#include<string>\n#include<algorithm>\n#include<stack>\n#include<map>\n#include<cstdio>\nusing namespace std;\n#define rep(i,a) for(int i=0;i<a;i++)\n#define mp make_pair\n#define pb push_back\n#define P pair<int,int>\n#define ll __int64\nint n;\nint t[110000];\nconst int MA=2000000000;\nint ansma,ansmi;\nint mid,l,r;\n\nint simyu(int num){\nrep(i,n){\n\tif(num/t[i]==0)return 0;\n\tnum=num-num%t[i];\n}\nreturn num;\n}\n\nint main(){\ncin>>n;\nint mma=-1;\nrep(i,n){cin>>t[i];}\n\nl=0;\nr=MA;\nmid=(l+r)/2;\nfor(int i=0;i<50;i++){\n\tint now=simyu(mid);\n\tif(now<=2){\n\t\tl=mid;\n\t\tmid=(l+r)/2;\n\t}\n\telse{\n\t\tr=mid;\n\t\tmid=(l+r)/2;\n\t}\n\t//cout<<l<<\" \"<<r<<\" \"<<mid<<\" \"<<now<<endl;\n\tansma=mid;\n}\n\nl=0;\nr=MA;\nmid=(l+r)/2;\n\nfor(int i=0;i<50;i++){\n\tint now=simyu(mid);\n\n\tif(now<2){\n\t\tl=mid;\n\t\tmid=(l+r)/2;\n\t}\n\telse{\n\t\tr=mid;\n\t\tmid=(l+r)/2;\n\t}\n\tansmi=mid+1;\n}\nif(ansmi>ansma)cout<<-1<<endl;\nelse cout<<ansmi<<\" \"<<ansma<<endl;\n\treturn 0;\n}", "problem_context": "Score : 500 points\n\nProblem Statement\n\nAn adult game master and N children are playing a game on an ice rink.\nThe game consists of K rounds.\nIn the i-th round, the game master announces:\n\nForm groups consisting of A_i children each!\n\nThen the children who are still in the game form as many groups of A_i children as possible.\nOne child may belong to at most one group.\nThose who are left without a group leave the game. The others proceed to the next round.\nNote that it's possible that nobody leaves the game in some round.\n\nIn the end, after the K-th round, there are exactly two children left, and they are declared the winners.\n\nYou have heard the values of A_1, A_2, ..., A_K. You don't know N, but you want to estimate it.\n\nFind the smallest and the largest possible number of children in the game before the start, or determine that no valid values of N exist.\n\nConstraints\n\n1 \\leq K \\leq 10^5\n\n2 \\leq A_i \\leq 10^9\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nK\nA_1 A_2 ... A_K\n\nOutput\n\nPrint two integers representing the smallest and the largest possible value of N, respectively,\nor a single integer -1 if the described situation is impossible.\n\nSample Input 1\n\n4\n3 4 3 2\n\nSample Output 1\n\n6 8\n\nFor example, if the game starts with 6 children, then it proceeds as follows:\n\nIn the first round, 6 children form 2 groups of 3 children, and nobody leaves the game.\n\nIn the second round, 6 children form 1 group of 4 children, and 2 children leave the game.\n\nIn the third round, 4 children form 1 group of 3 children, and 1 child leaves the game.\n\nIn the fourth round, 3 children form 1 group of 2 children, and 1 child leaves the game.\n\nThe last 2 children are declared the winners.\n\nSample Input 2\n\n5\n3 4 100 3 2\n\nSample Output 2\n\n-1\n\nThis situation is impossible.\nIn particular, if the game starts with less than 100 children, everyone leaves after the third round.\n\nSample Input 3\n\n10\n2 2 2 2 2 2 2 2 2 2\n\nSample Output 3\n\n2 3", "sample_input": "4\n3 4 3 2\n"}, "reference_outputs": ["6 8\n"], "source_document_id": "p03464", "source_text": "Score : 500 points\n\nProblem Statement\n\nAn adult game master and N children are playing a game on an ice rink.\nThe game consists of K rounds.\nIn the i-th round, the game master announces:\n\nForm groups consisting of A_i children each!\n\nThen the children who are still in the game form as many groups of A_i children as possible.\nOne child may belong to at most one group.\nThose who are left without a group leave the game. The others proceed to the next round.\nNote that it's possible that nobody leaves the game in some round.\n\nIn the end, after the K-th round, there are exactly two children left, and they are declared the winners.\n\nYou have heard the values of A_1, A_2, ..., A_K. You don't know N, but you want to estimate it.\n\nFind the smallest and the largest possible number of children in the game before the start, or determine that no valid values of N exist.\n\nConstraints\n\n1 \\leq K \\leq 10^5\n\n2 \\leq A_i \\leq 10^9\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nK\nA_1 A_2 ... A_K\n\nOutput\n\nPrint two integers representing the smallest and the largest possible value of N, respectively,\nor a single integer -1 if the described situation is impossible.\n\nSample Input 1\n\n4\n3 4 3 2\n\nSample Output 1\n\n6 8\n\nFor example, if the game starts with 6 children, then it proceeds as follows:\n\nIn the first round, 6 children form 2 groups of 3 children, and nobody leaves the game.\n\nIn the second round, 6 children form 1 group of 4 children, and 2 children leave the game.\n\nIn the third round, 4 children form 1 group of 3 children, and 1 child leaves the game.\n\nIn the fourth round, 3 children form 1 group of 2 children, and 1 child leaves the game.\n\nThe last 2 children are declared the winners.\n\nSample Input 2\n\n5\n3 4 100 3 2\n\nSample Output 2\n\n-1\n\nThis situation is impossible.\nIn particular, if the game starts with less than 100 children, everyone leaves after the third round.\n\nSample Input 3\n\n10\n2 2 2 2 2 2 2 2 2 2\n\nSample Output 3\n\n2 3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1486, "cpu_time_ms": 111, "memory_kb": 640}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s646634506", "group_id": "codeNet:p03469", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  string s;\n  cin >> s;\n  s.at(3) = '8';\n  \n  cout << s << endl;\n  \n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1589988650, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03469.html", "problem_id": "p03469", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03469/input.txt", "sample_output_relpath": "derived/input_output/data/p03469/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03469/C++/s646634506.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s646634506", "user_id": "u637860487"}, "prompt_components": {"gold_output": "2018/01/07\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  string s;\n  cin >> s;\n  s.at(3) = '8';\n  \n  cout << s << endl;\n  \n  return 0;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nOn some day in January 2018, Takaki is writing a document. The document has a column where the current date is written in yyyy/mm/dd format. For example, January 23, 2018 should be written as 2018/01/23.\n\nAfter finishing the document, she noticed that she had mistakenly wrote 2017 at the beginning of the date column. Write a program that, when the string that Takaki wrote in the date column, S, is given as input, modifies the first four characters in S to 2018 and prints it.\n\nConstraints\n\nS is a string of length 10.\n\nThe first eight characters in S are 2017/01/.\n\nThe last two characters in S are digits and represent an integer between 1 and 31 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nReplace the first four characters in S with 2018 and print it.\n\nSample Input 1\n\n2017/01/07\n\nSample Output 1\n\n2018/01/07\n\nSample Input 2\n\n2017/01/31\n\nSample Output 2\n\n2018/01/31", "sample_input": "2017/01/07\n"}, "reference_outputs": ["2018/01/07\n"], "source_document_id": "p03469", "source_text": "Score : 100 points\n\nProblem Statement\n\nOn some day in January 2018, Takaki is writing a document. The document has a column where the current date is written in yyyy/mm/dd format. For example, January 23, 2018 should be written as 2018/01/23.\n\nAfter finishing the document, she noticed that she had mistakenly wrote 2017 at the beginning of the date column. Write a program that, when the string that Takaki wrote in the date column, S, is given as input, modifies the first four characters in S to 2018 and prints it.\n\nConstraints\n\nS is a string of length 10.\n\nThe first eight characters in S are 2017/01/.\n\nThe last two characters in S are digits and represent an integer between 1 and 31 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nReplace the first four characters in S with 2018 and print it.\n\nSample Input 1\n\n2017/01/07\n\nSample Output 1\n\n2018/01/07\n\nSample Input 2\n\n2017/01/31\n\nSample Output 2\n\n2018/01/31", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 140, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s106506354", "group_id": "codeNet:p03469", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n#define FOR(i,a,b) for(int i=(a);i<(b);++i)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(v) (v).begin(),(v).end()\n#define fi first\n#define se second\ntemplate<typename A, typename B> inline bool chmax(A &a, B b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<typename A, typename B> inline bool chmin(A &a, B b) { if (a>b) { a=b; return 1; } return 0; }\ntypedef long long ll;\ntypedef pair<int, int> pii;\nconst ll INF = 1e9+100;\nconst ll MOD = 1e9+7;\nconst bool debug = 0;\n//-----------------------------------------------//\n\nint main() {\n\tstring s;\n\tcin >> s;\n\ts[3] = '8';\n\tcout << s << endl;\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1519333178, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03469.html", "problem_id": "p03469", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03469/input.txt", "sample_output_relpath": "derived/input_output/data/p03469/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03469/C++/s106506354.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s106506354", "user_id": "u105791541"}, "prompt_components": {"gold_output": "2018/01/07\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n#define FOR(i,a,b) for(int i=(a);i<(b);++i)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(v) (v).begin(),(v).end()\n#define fi first\n#define se second\ntemplate<typename A, typename B> inline bool chmax(A &a, B b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<typename A, typename B> inline bool chmin(A &a, B b) { if (a>b) { a=b; return 1; } return 0; }\ntypedef long long ll;\ntypedef pair<int, int> pii;\nconst ll INF = 1e9+100;\nconst ll MOD = 1e9+7;\nconst bool debug = 0;\n//-----------------------------------------------//\n\nint main() {\n\tstring s;\n\tcin >> s;\n\ts[3] = '8';\n\tcout << s << endl;\n\treturn 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nOn some day in January 2018, Takaki is writing a document. The document has a column where the current date is written in yyyy/mm/dd format. For example, January 23, 2018 should be written as 2018/01/23.\n\nAfter finishing the document, she noticed that she had mistakenly wrote 2017 at the beginning of the date column. Write a program that, when the string that Takaki wrote in the date column, S, is given as input, modifies the first four characters in S to 2018 and prints it.\n\nConstraints\n\nS is a string of length 10.\n\nThe first eight characters in S are 2017/01/.\n\nThe last two characters in S are digits and represent an integer between 1 and 31 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nReplace the first four characters in S with 2018 and print it.\n\nSample Input 1\n\n2017/01/07\n\nSample Output 1\n\n2018/01/07\n\nSample Input 2\n\n2017/01/31\n\nSample Output 2\n\n2018/01/31", "sample_input": "2017/01/07\n"}, "reference_outputs": ["2018/01/07\n"], "source_document_id": "p03469", "source_text": "Score : 100 points\n\nProblem Statement\n\nOn some day in January 2018, Takaki is writing a document. The document has a column where the current date is written in yyyy/mm/dd format. For example, January 23, 2018 should be written as 2018/01/23.\n\nAfter finishing the document, she noticed that she had mistakenly wrote 2017 at the beginning of the date column. Write a program that, when the string that Takaki wrote in the date column, S, is given as input, modifies the first four characters in S to 2018 and prints it.\n\nConstraints\n\nS is a string of length 10.\n\nThe first eight characters in S are 2017/01/.\n\nThe last two characters in S are digits and represent an integer between 1 and 31 (inclusive).\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nReplace the first four characters in S with 2018 and print it.\n\nSample Input 1\n\n2017/01/07\n\nSample Output 1\n\n2018/01/07\n\nSample Input 2\n\n2017/01/31\n\nSample Output 2\n\n2018/01/31", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 649, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s921000517", "group_id": "codeNet:p03470", "input_text": "#include <bits/stdc++.h>\n#define rep(i,n) for (int i = 0; i < (n); ++i)\nusing namespace std;\nusing ll = long long;\nusing P = pair<int,int>;\n\nint main(){\n\tint n;\n\tcin >> n;\n\tmap<int,int> cnt;\n\trep(i,n){\n\t\tint d;\n\t\tcin >> d;\n\t\tcnt[d]++;\n\t}\n\tcout << cnt.size() << endl;\n}", "language": "C++", "metadata": {"date": 1597240259, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03470.html", "problem_id": "p03470", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03470/input.txt", "sample_output_relpath": "derived/input_output/data/p03470/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03470/C++/s921000517.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s921000517", "user_id": "u052656528"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define rep(i,n) for (int i = 0; i < (n); ++i)\nusing namespace std;\nusing ll = long long;\nusing P = pair<int,int>;\n\nint main(){\n\tint n;\n\tcin >> n;\n\tmap<int,int> cnt;\n\trep(i,n){\n\t\tint d;\n\t\tcin >> d;\n\t\tcnt[d]++;\n\t}\n\tcout << cnt.size() << endl;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nAn X-layered kagami mochi (X ≥ 1) is a pile of X round mochi (rice cake) stacked vertically where each mochi (except the bottom one) has a smaller diameter than that of the mochi directly below it. For example, if you stack three mochi with diameters of 10, 8 and 6 centimeters from bottom to top in this order, you have a 3-layered kagami mochi; if you put just one mochi, you have a 1-layered kagami mochi.\n\nLunlun the dachshund has N round mochi, and the diameter of the i-th mochi is d_i centimeters. When we make a kagami mochi using some or all of them, at most how many layers can our kagami mochi have?\n\nConstraints\n\n1 ≤ N ≤ 100\n\n1 ≤ d_i ≤ 100\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nd_1\n:\nd_N\n\nOutput\n\nPrint the maximum number of layers in a kagami mochi that can be made.\n\nSample Input 1\n\n4\n10\n8\n8\n6\n\nSample Output 1\n\n3\n\nIf we stack the mochi with diameters of 10, 8 and 6 centimeters from bottom to top in this order, we have a 3-layered kagami mochi, which is the maximum number of layers.\n\nSample Input 2\n\n3\n15\n15\n15\n\nSample Output 2\n\n1\n\nWhen all the mochi have the same diameter, we can only have a 1-layered kagami mochi.\n\nSample Input 3\n\n7\n50\n30\n50\n100\n50\n80\n30\n\nSample Output 3\n\n4", "sample_input": "4\n10\n8\n8\n6\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03470", "source_text": "Score : 200 points\n\nProblem Statement\n\nAn X-layered kagami mochi (X ≥ 1) is a pile of X round mochi (rice cake) stacked vertically where each mochi (except the bottom one) has a smaller diameter than that of the mochi directly below it. For example, if you stack three mochi with diameters of 10, 8 and 6 centimeters from bottom to top in this order, you have a 3-layered kagami mochi; if you put just one mochi, you have a 1-layered kagami mochi.\n\nLunlun the dachshund has N round mochi, and the diameter of the i-th mochi is d_i centimeters. When we make a kagami mochi using some or all of them, at most how many layers can our kagami mochi have?\n\nConstraints\n\n1 ≤ N ≤ 100\n\n1 ≤ d_i ≤ 100\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nd_1\n:\nd_N\n\nOutput\n\nPrint the maximum number of layers in a kagami mochi that can be made.\n\nSample Input 1\n\n4\n10\n8\n8\n6\n\nSample Output 1\n\n3\n\nIf we stack the mochi with diameters of 10, 8 and 6 centimeters from bottom to top in this order, we have a 3-layered kagami mochi, which is the maximum number of layers.\n\nSample Input 2\n\n3\n15\n15\n15\n\nSample Output 2\n\n1\n\nWhen all the mochi have the same diameter, we can only have a 1-layered kagami mochi.\n\nSample Input 3\n\n7\n50\n30\n50\n100\n50\n80\n30\n\nSample Output 3\n\n4", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 268, "cpu_time_ms": 8, "memory_kb": 3580}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s529423381", "group_id": "codeNet:p03473", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n  int M;\n  cin >> M;\n  cout << 48 - M << endl;\n}", "language": "C++", "metadata": {"date": 1563989283, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03473.html", "problem_id": "p03473", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03473/input.txt", "sample_output_relpath": "derived/input_output/data/p03473/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03473/C++/s529423381.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s529423381", "user_id": "u122557489"}, "prompt_components": {"gold_output": "27\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n  int M;\n  cin >> M;\n  cout << 48 - M << endl;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nHow many hours do we have until New Year at M o'clock (24-hour notation) on 30th, December?\n\nConstraints\n\n1≤M≤23\n\nM is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nM\n\nOutput\n\nIf we have x hours until New Year at M o'clock on 30th, December, print x.\n\nSample Input 1\n\n21\n\nSample Output 1\n\n27\n\nWe have 27 hours until New Year at 21 o'clock on 30th, December.\n\nSample Input 2\n\n12\n\nSample Output 2\n\n36", "sample_input": "21\n"}, "reference_outputs": ["27\n"], "source_document_id": "p03473", "source_text": "Score : 100 points\n\nProblem Statement\n\nHow many hours do we have until New Year at M o'clock (24-hour notation) on 30th, December?\n\nConstraints\n\n1≤M≤23\n\nM is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nM\n\nOutput\n\nIf we have x hours until New Year at M o'clock on 30th, December, print x.\n\nSample Input 1\n\n21\n\nSample Output 1\n\n27\n\nWe have 27 hours until New Year at 21 o'clock on 30th, December.\n\nSample Input 2\n\n12\n\nSample Output 2\n\n36", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 108, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s245351919", "group_id": "codeNet:p03473", "input_text": "#include <iostream>\n#include <algorithm>\n#include <cstring>\n#include<cstdio>\n#include <cmath>\n#include<string>\nusing namespace std;\n\n\n\nint main()\n{\n\tint m;\n\n\tcin >> m;\n\n\tcout << 48 - m << endl;\n\n\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1514745263, "filename_ext": "cpp", "original_language": "C++ (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03473.html", "problem_id": "p03473", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03473/input.txt", "sample_output_relpath": "derived/input_output/data/p03473/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03473/C++/s245351919.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s245351919", "user_id": "u174434198"}, "prompt_components": {"gold_output": "27\n", "input_to_evaluate": "#include <iostream>\n#include <algorithm>\n#include <cstring>\n#include<cstdio>\n#include <cmath>\n#include<string>\nusing namespace std;\n\n\n\nint main()\n{\n\tint m;\n\n\tcin >> m;\n\n\tcout << 48 - m << endl;\n\n\n\treturn 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nHow many hours do we have until New Year at M o'clock (24-hour notation) on 30th, December?\n\nConstraints\n\n1≤M≤23\n\nM is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nM\n\nOutput\n\nIf we have x hours until New Year at M o'clock on 30th, December, print x.\n\nSample Input 1\n\n21\n\nSample Output 1\n\n27\n\nWe have 27 hours until New Year at 21 o'clock on 30th, December.\n\nSample Input 2\n\n12\n\nSample Output 2\n\n36", "sample_input": "21\n"}, "reference_outputs": ["27\n"], "source_document_id": "p03473", "source_text": "Score : 100 points\n\nProblem Statement\n\nHow many hours do we have until New Year at M o'clock (24-hour notation) on 30th, December?\n\nConstraints\n\n1≤M≤23\n\nM is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nM\n\nOutput\n\nIf we have x hours until New Year at M o'clock on 30th, December, print x.\n\nSample Input 1\n\n21\n\nSample Output 1\n\n27\n\nWe have 27 hours until New Year at 21 o'clock on 30th, December.\n\nSample Input 2\n\n12\n\nSample Output 2\n\n36", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 208, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s608354281", "group_id": "codeNet:p03473", "input_text": "#include<cstdio>\n#include<algorithm>\n#include<iostream>\n#include<cmath>\n#define ll int\n#define mod 100000007\n#define ln printf(\"\\n\");\nusing namespace std;\ninline void in(ll &x){x=0;char c;bool f=0;while((c=getchar())>'9'||c<'0')if(c=='-')f=!f;x=c-48;while((c=getchar())<='9'&&c>='0')x=x*10+c-48;if(f)x=-x;}\ninline void out(ll x){if(x<0){putchar('-');x=-x;}if(x>9)out(x/10);putchar(x%10+48);}\ninline void outn(ll x){out(x);printf(\"\\n\");}\nll x;\nint main(){\n\tin(x);outn(48-x);\n}", "language": "C++", "metadata": {"date": 1514686264, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03473.html", "problem_id": "p03473", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03473/input.txt", "sample_output_relpath": "derived/input_output/data/p03473/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03473/C++/s608354281.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s608354281", "user_id": "u127394455"}, "prompt_components": {"gold_output": "27\n", "input_to_evaluate": "#include<cstdio>\n#include<algorithm>\n#include<iostream>\n#include<cmath>\n#define ll int\n#define mod 100000007\n#define ln printf(\"\\n\");\nusing namespace std;\ninline void in(ll &x){x=0;char c;bool f=0;while((c=getchar())>'9'||c<'0')if(c=='-')f=!f;x=c-48;while((c=getchar())<='9'&&c>='0')x=x*10+c-48;if(f)x=-x;}\ninline void out(ll x){if(x<0){putchar('-');x=-x;}if(x>9)out(x/10);putchar(x%10+48);}\ninline void outn(ll x){out(x);printf(\"\\n\");}\nll x;\nint main(){\n\tin(x);outn(48-x);\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nHow many hours do we have until New Year at M o'clock (24-hour notation) on 30th, December?\n\nConstraints\n\n1≤M≤23\n\nM is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nM\n\nOutput\n\nIf we have x hours until New Year at M o'clock on 30th, December, print x.\n\nSample Input 1\n\n21\n\nSample Output 1\n\n27\n\nWe have 27 hours until New Year at 21 o'clock on 30th, December.\n\nSample Input 2\n\n12\n\nSample Output 2\n\n36", "sample_input": "21\n"}, "reference_outputs": ["27\n"], "source_document_id": "p03473", "source_text": "Score : 100 points\n\nProblem Statement\n\nHow many hours do we have until New Year at M o'clock (24-hour notation) on 30th, December?\n\nConstraints\n\n1≤M≤23\n\nM is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nM\n\nOutput\n\nIf we have x hours until New Year at M o'clock on 30th, December, print x.\n\nSample Input 1\n\n21\n\nSample Output 1\n\n27\n\nWe have 27 hours until New Year at 21 o'clock on 30th, December.\n\nSample Input 2\n\n12\n\nSample Output 2\n\n36", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 475, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s143788371", "group_id": "codeNet:p03474", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n \nint main(){\n    int A, B;\n    cin >> A >> B;\n    string S;\n    cin >> S;\n\t\n    int i=0;\n  \tfor (; i<A; i++){\n      if (S[i] == '-'){\n        cout << \"No\" << endl;\n        return 0;\n      }\n    }\n    if (S[i] != '-'){\n      cout << \"No\" << endl;\n      return 0;\n    }\n    i++;\n    for (; i<A+B+1; i++){\n      if (S[i] == '-'){\n        cout << \"No\" << endl;\n        return 0;\n      }\n    }\n    cout << \"Yes\" << endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1579712984, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03474.html", "problem_id": "p03474", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03474/input.txt", "sample_output_relpath": "derived/input_output/data/p03474/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03474/C++/s143788371.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s143788371", "user_id": "u883982500"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n \nint main(){\n    int A, B;\n    cin >> A >> B;\n    string S;\n    cin >> S;\n\t\n    int i=0;\n  \tfor (; i<A; i++){\n      if (S[i] == '-'){\n        cout << \"No\" << endl;\n        return 0;\n      }\n    }\n    if (S[i] != '-'){\n      cout << \"No\" << endl;\n      return 0;\n    }\n    i++;\n    for (; i<A+B+1; i++){\n      if (S[i] == '-'){\n        cout << \"No\" << endl;\n        return 0;\n      }\n    }\n    cout << \"Yes\" << endl;\n    return 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nThe postal code in Atcoder Kingdom is A+B+1 characters long, its (A+1)-th character is a hyphen -, and the other characters are digits from 0 through 9.\n\nYou are given a string S. Determine whether it follows the postal code format in Atcoder Kingdom.\n\nConstraints\n\n1≤A,B≤5\n\n|S|=A+B+1\n\nS consists of - and digits from 0 through 9.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\nS\n\nOutput\n\nPrint Yes if S follows the postal code format in AtCoder Kingdom; print No otherwise.\n\nSample Input 1\n\n3 4\n269-6650\n\nSample Output 1\n\nYes\n\nThe (A+1)-th character of S is -, and the other characters are digits from 0 through 9, so it follows the format.\n\nSample Input 2\n\n1 1\n---\n\nSample Output 2\n\nNo\n\nS contains unnecessary -s other than the (A+1)-th character, so it does not follow the format.\n\nSample Input 3\n\n1 2\n7444\n\nSample Output 3\n\nNo", "sample_input": "3 4\n269-6650\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p03474", "source_text": "Score : 200 points\n\nProblem Statement\n\nThe postal code in Atcoder Kingdom is A+B+1 characters long, its (A+1)-th character is a hyphen -, and the other characters are digits from 0 through 9.\n\nYou are given a string S. Determine whether it follows the postal code format in Atcoder Kingdom.\n\nConstraints\n\n1≤A,B≤5\n\n|S|=A+B+1\n\nS consists of - and digits from 0 through 9.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\nS\n\nOutput\n\nPrint Yes if S follows the postal code format in AtCoder Kingdom; print No otherwise.\n\nSample Input 1\n\n3 4\n269-6650\n\nSample Output 1\n\nYes\n\nThe (A+1)-th character of S is -, and the other characters are digits from 0 through 9, so it follows the format.\n\nSample Input 2\n\n1 1\n---\n\nSample Output 2\n\nNo\n\nS contains unnecessary -s other than the (A+1)-th character, so it does not follow the format.\n\nSample Input 3\n\n1 2\n7444\n\nSample Output 3\n\nNo", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 499, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s388061125", "group_id": "codeNet:p03474", "input_text": "/*  ***  In The Name of God ... ***  */ \n#include <bits/stdc++.h>\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef long double ld;\n\n#define int long long\n#define all(v) v.begin() , v.end()\n#define pb push_back\n#define endl '\\n' \ntemplate<typename T> inline bool smin(T &a, const T &b){ return b < a ? a = b,1:0;}\ntemplate<typename T> inline bool smax(T &a, const T &b){ return a < b ? a = b,1:0;}\n\nint a , b ;\nstring s ; \n\nint32_t main()\n{\n\tios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0);\n\tcin >> a >> b >> s ;\n\tfor ( int i = 0 ; i < a + b + 1 ; ++ i ) {\n\t\tif ( i == a )\n\t\t\tif ( s [ i ] != '-' )\n\t\t\t\treturn cout << \"No\\n\" , 0 ;\n\t\tif ( i != a )\n\t\t\tif ( ! ( s [ i ] >= '0' && s [ i ] <= '9' )  )\n\t\t\t     return cout << \"No\\n\" , 0 ; \n\t}\n\tcout << \"Yes\\n\" ; \n}\n", "language": "C++", "metadata": {"date": 1516959773, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03474.html", "problem_id": "p03474", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03474/input.txt", "sample_output_relpath": "derived/input_output/data/p03474/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03474/C++/s388061125.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s388061125", "user_id": "u874092129"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "/*  ***  In The Name of God ... ***  */ \n#include <bits/stdc++.h>\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef long double ld;\n\n#define int long long\n#define all(v) v.begin() , v.end()\n#define pb push_back\n#define endl '\\n' \ntemplate<typename T> inline bool smin(T &a, const T &b){ return b < a ? a = b,1:0;}\ntemplate<typename T> inline bool smax(T &a, const T &b){ return a < b ? a = b,1:0;}\n\nint a , b ;\nstring s ; \n\nint32_t main()\n{\n\tios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0);\n\tcin >> a >> b >> s ;\n\tfor ( int i = 0 ; i < a + b + 1 ; ++ i ) {\n\t\tif ( i == a )\n\t\t\tif ( s [ i ] != '-' )\n\t\t\t\treturn cout << \"No\\n\" , 0 ;\n\t\tif ( i != a )\n\t\t\tif ( ! ( s [ i ] >= '0' && s [ i ] <= '9' )  )\n\t\t\t     return cout << \"No\\n\" , 0 ; \n\t}\n\tcout << \"Yes\\n\" ; \n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nThe postal code in Atcoder Kingdom is A+B+1 characters long, its (A+1)-th character is a hyphen -, and the other characters are digits from 0 through 9.\n\nYou are given a string S. Determine whether it follows the postal code format in Atcoder Kingdom.\n\nConstraints\n\n1≤A,B≤5\n\n|S|=A+B+1\n\nS consists of - and digits from 0 through 9.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\nS\n\nOutput\n\nPrint Yes if S follows the postal code format in AtCoder Kingdom; print No otherwise.\n\nSample Input 1\n\n3 4\n269-6650\n\nSample Output 1\n\nYes\n\nThe (A+1)-th character of S is -, and the other characters are digits from 0 through 9, so it follows the format.\n\nSample Input 2\n\n1 1\n---\n\nSample Output 2\n\nNo\n\nS contains unnecessary -s other than the (A+1)-th character, so it does not follow the format.\n\nSample Input 3\n\n1 2\n7444\n\nSample Output 3\n\nNo", "sample_input": "3 4\n269-6650\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p03474", "source_text": "Score : 200 points\n\nProblem Statement\n\nThe postal code in Atcoder Kingdom is A+B+1 characters long, its (A+1)-th character is a hyphen -, and the other characters are digits from 0 through 9.\n\nYou are given a string S. Determine whether it follows the postal code format in Atcoder Kingdom.\n\nConstraints\n\n1≤A,B≤5\n\n|S|=A+B+1\n\nS consists of - and digits from 0 through 9.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\nS\n\nOutput\n\nPrint Yes if S follows the postal code format in AtCoder Kingdom; print No otherwise.\n\nSample Input 1\n\n3 4\n269-6650\n\nSample Output 1\n\nYes\n\nThe (A+1)-th character of S is -, and the other characters are digits from 0 through 9, so it follows the format.\n\nSample Input 2\n\n1 1\n---\n\nSample Output 2\n\nNo\n\nS contains unnecessary -s other than the (A+1)-th character, so it does not follow the format.\n\nSample Input 3\n\n1 2\n7444\n\nSample Output 3\n\nNo", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 771, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s523027589", "group_id": "codeNet:p03475", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nconst double EPS = 1e-9;\nconst int INF = 1e9;\nconst int MOD = 1e9+7;\nconst ll LINF = 1e18;\ntypedef vector<int> vi;\ntypedef vector<vector<int>> vvi;\ntypedef pair<int, int> pi;\ntypedef pair<ll, ll> pll;\ntypedef map<int, int> mi;\ntypedef set<int> si;\n#define VV(T) vector<vector< T > >\n#define dump(x)  cout << #x << \" = \" << (x) << endl\n#define YES(n) cout << ((n) ? \"YES\" : \"NO\"  ) << endl\n#define Yes(n) cout << ((n) ? \"Yes\" : \"No\"  ) << endl\n#define POSSIBLE(n) cout << ((n) ? \"POSSIBLE\" : \"IMPOSSIBLE\"  ) << endl\n#define Possible(n) cout << ((n) ? \"Possible\" : \"Impossible\"  ) << endl\n\n#define rep(i, n) REP(i, 0, n)                              // 0, 1, ..., n-1\n#define REP(i, x, n) for(int i = x; i < n; i++)             // x, x + 1, ..., n-1\n#define FOREACH(x,a) for(auto& (x) : (a) )\n\n#define ALL(v) (v).begin() , (v).end()\n#define RALL(v) (v).rbegin(), (v).rend()\n\n#define pb push_back\n#define pu push\n#define mp make_pair\n#define fi first\n#define sc second\n\n#define COUT(x) cout << (x) << endl\n#define VECCIN(x) for(auto&youso_: (x) )cin>>youso_\n#define VECCOUT(x) for(auto&youso_: (x) )cout<<youso_<<\" \";cout<<endl\n\ntemplate<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }\n\n\nint main(){\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n\n    int N; cin >> N;\n    vi C(N), S(N), F(N);\n    rep (i, N - 1) cin >> C[i] >> S[i] >> F[i];\n\n    rep (i, N) {\n        int total = 0;\n        REP(j, i, N - 1) {\n            total = max(total, S[j]);\n            if (total % F[j] == 0) total += C[j];\n            else total = total + F[j] - total % F[j] + C[j];\n        }\n        COUT(total);\n    }\n}", "language": "C++", "metadata": {"date": 1554435885, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03475.html", "problem_id": "p03475", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03475/input.txt", "sample_output_relpath": "derived/input_output/data/p03475/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03475/C++/s523027589.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s523027589", "user_id": "u038027079"}, "prompt_components": {"gold_output": "12\n11\n0\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nconst double EPS = 1e-9;\nconst int INF = 1e9;\nconst int MOD = 1e9+7;\nconst ll LINF = 1e18;\ntypedef vector<int> vi;\ntypedef vector<vector<int>> vvi;\ntypedef pair<int, int> pi;\ntypedef pair<ll, ll> pll;\ntypedef map<int, int> mi;\ntypedef set<int> si;\n#define VV(T) vector<vector< T > >\n#define dump(x)  cout << #x << \" = \" << (x) << endl\n#define YES(n) cout << ((n) ? \"YES\" : \"NO\"  ) << endl\n#define Yes(n) cout << ((n) ? \"Yes\" : \"No\"  ) << endl\n#define POSSIBLE(n) cout << ((n) ? \"POSSIBLE\" : \"IMPOSSIBLE\"  ) << endl\n#define Possible(n) cout << ((n) ? \"Possible\" : \"Impossible\"  ) << endl\n\n#define rep(i, n) REP(i, 0, n)                              // 0, 1, ..., n-1\n#define REP(i, x, n) for(int i = x; i < n; i++)             // x, x + 1, ..., n-1\n#define FOREACH(x,a) for(auto& (x) : (a) )\n\n#define ALL(v) (v).begin() , (v).end()\n#define RALL(v) (v).rbegin(), (v).rend()\n\n#define pb push_back\n#define pu push\n#define mp make_pair\n#define fi first\n#define sc second\n\n#define COUT(x) cout << (x) << endl\n#define VECCIN(x) for(auto&youso_: (x) )cin>>youso_\n#define VECCOUT(x) for(auto&youso_: (x) )cout<<youso_<<\" \";cout<<endl\n\ntemplate<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1; } return 0; }\ntemplate<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1; } return 0; }\n\n\nint main(){\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n\n    int N; cin >> N;\n    vi C(N), S(N), F(N);\n    rep (i, N - 1) cin >> C[i] >> S[i] >> F[i];\n\n    rep (i, N) {\n        int total = 0;\n        REP(j, i, N - 1) {\n            total = max(total, S[j]);\n            if (total % F[j] == 0) total += C[j];\n            else total = total + F[j] - total % F[j] + C[j];\n        }\n        COUT(total);\n    }\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nA railroad running from west to east in Atcoder Kingdom is now complete.\n\nThere are N stations on the railroad, numbered 1 through N from west to east.\n\nTomorrow, the opening ceremony of the railroad will take place.\n\nOn this railroad, for each integer i such that 1≤i≤N-1, there will be trains that run from Station i to Station i+1 in C_i seconds. No other trains will be operated.\n\nThe first train from Station i to Station i+1 will depart Station i S_i seconds after the ceremony begins. Thereafter, there will be a train that departs Station i every F_i seconds.\n\nHere, it is guaranteed that F_i divides S_i.\n\nThat is, for each Time t satisfying S_i≤t and t％F_i=0, there will be a train that departs Station i t seconds after the ceremony begins and arrives at Station i+1 t+C_i seconds after the ceremony begins, where A％B denotes A modulo B, and there will be no other trains.\n\nFor each i, find the earliest possible time we can reach Station N if we are at Station i when the ceremony begins, ignoring the time needed to change trains.\n\nConstraints\n\n1≤N≤500\n\n1≤C_i≤100\n\n1≤S_i≤10^5\n\n1≤F_i≤10\n\nS_i％F_i=0\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nC_1 S_1 F_1\n:\nC_{N-1} S_{N-1} F_{N-1}\n\nOutput\n\nPrint N lines. Assuming that we are at Station i (1≤i≤N) when the ceremony begins, if the earliest possible time we can reach Station N is x seconds after the ceremony begins, the i-th line should contain x.\n\nSample Input 1\n\n3\n6 5 1\n1 10 1\n\nSample Output 1\n\n12\n11\n0\n\nWe will travel from Station 1 as follows:\n\n5 seconds after the beginning: take the train to Station 2.\n\n11 seconds: arrive at Station 2.\n\n11 seconds: take the train to Station 3.\n\n12 seconds: arrive at Station 3.\n\nWe will travel from Station 2 as follows:\n\n10 seconds: take the train to Station 3.\n\n11 seconds: arrive at Station 3.\n\nNote that we should print 0 for Station 3.\n\nSample Input 2\n\n4\n12 24 6\n52 16 4\n99 2 2\n\nSample Output 2\n\n187\n167\n101\n0\n\nSample Input 3\n\n4\n12 13 1\n44 17 17\n66 4096 64\n\nSample Output 3\n\n4162\n4162\n4162\n0", "sample_input": "3\n6 5 1\n1 10 1\n"}, "reference_outputs": ["12\n11\n0\n"], "source_document_id": "p03475", "source_text": "Score : 300 points\n\nProblem Statement\n\nA railroad running from west to east in Atcoder Kingdom is now complete.\n\nThere are N stations on the railroad, numbered 1 through N from west to east.\n\nTomorrow, the opening ceremony of the railroad will take place.\n\nOn this railroad, for each integer i such that 1≤i≤N-1, there will be trains that run from Station i to Station i+1 in C_i seconds. No other trains will be operated.\n\nThe first train from Station i to Station i+1 will depart Station i S_i seconds after the ceremony begins. Thereafter, there will be a train that departs Station i every F_i seconds.\n\nHere, it is guaranteed that F_i divides S_i.\n\nThat is, for each Time t satisfying S_i≤t and t％F_i=0, there will be a train that departs Station i t seconds after the ceremony begins and arrives at Station i+1 t+C_i seconds after the ceremony begins, where A％B denotes A modulo B, and there will be no other trains.\n\nFor each i, find the earliest possible time we can reach Station N if we are at Station i when the ceremony begins, ignoring the time needed to change trains.\n\nConstraints\n\n1≤N≤500\n\n1≤C_i≤100\n\n1≤S_i≤10^5\n\n1≤F_i≤10\n\nS_i％F_i=0\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nC_1 S_1 F_1\n:\nC_{N-1} S_{N-1} F_{N-1}\n\nOutput\n\nPrint N lines. Assuming that we are at Station i (1≤i≤N) when the ceremony begins, if the earliest possible time we can reach Station N is x seconds after the ceremony begins, the i-th line should contain x.\n\nSample Input 1\n\n3\n6 5 1\n1 10 1\n\nSample Output 1\n\n12\n11\n0\n\nWe will travel from Station 1 as follows:\n\n5 seconds after the beginning: take the train to Station 2.\n\n11 seconds: arrive at Station 2.\n\n11 seconds: take the train to Station 3.\n\n12 seconds: arrive at Station 3.\n\nWe will travel from Station 2 as follows:\n\n10 seconds: take the train to Station 3.\n\n11 seconds: arrive at Station 3.\n\nNote that we should print 0 for Station 3.\n\nSample Input 2\n\n4\n12 24 6\n52 16 4\n99 2 2\n\nSample Output 2\n\n187\n167\n101\n0\n\nSample Input 3\n\n4\n12 13 1\n44 17 17\n66 4096 64\n\nSample Output 3\n\n4162\n4162\n4162\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1793, "cpu_time_ms": 3, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s335380087", "group_id": "codeNet:p03476", "input_text": "#include<algorithm>\n#include<cmath>\n#include<iomanip>\n#include<iostream>\n#include<map>\n#include<numeric>\n#include<queue>\n#include<set>\n#include<sstream>\n#include<unordered_map>\n#include<unordered_set>\n#include<vector>\nusing uint = unsigned int;\nusing ll = long long;\nenum : int { M = (int)1e9 + 7 };\nenum : ll { MLL = (ll)1e18L + 9 };\nusing namespace std;\n#ifdef LOCAL\n#include\"rprint2.hpp\"\n#include\"debug_deque.hpp\"\n#define vector DebugDeque\n#else\n#define FUNC(name) template <ostream& out = cout, class... T> void name(T&&...){ }\nFUNC(prints) FUNC(printe) FUNC(printw) FUNC(printew) FUNC(printb) FUNC(printd) FUNC(printde);\n#endif\n\n#include<unistd.h>\nstruct Buffer{\n    int idx;\n    enum { chunk = 1 << 16 };\n    char buf[chunk];\n    Buffer(){ init(); }\n    void init(){ idx = 0; read(0, buf, chunk); }\n    void check(){ if(idx == chunk){ init(); } }\n    int next(){\n        static char notDigits[256] = {1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,0,1,1, 0,0,0,0,0,0,0,0,0,0,};\n        int ret = 0, sign = 1;\n        while(check(), notDigits[(int)buf[idx]]){ idx++; }\n        if(check(), buf[idx] == '-'){ sign = -1; idx++; }\n        while(check(), !notDigits[(int)buf[idx]]){ ret = ret * 10 + buf[idx++] - '0'; }\n        return sign * ret;\n    }\n};\n\nstring ans;\nvoid out(int num){\n    if(!num){\n        // putchar('0');\n        ans += '0';\n        return;\n    }\n    char buf[16];\n    int idx = 0;\n    while(num){\n        auto ret = div(num, 10);\n        buf[idx] = ret.rem + '0';\n        num = ret.quot;\n        idx++;\n    }\n    for(int i = idx - 1; i >= 0; i--){\n        // putchar(buf[i]);\n        ans += buf[i];\n    }\n}\n\nint main(){\n    // cin.tie(0);\n    // ios::sync_with_stdio(false);\n    Buffer buf;\n    const int lim = 1e5;\n    vector<char> prime(lim + 1, true);\n    prime[0] = prime[1] = false;\n    for(int i = 2; i <= lim; i++){\n        if(prime[i]){\n            for(int j = i + i; j <= lim; j += i){\n                prime[j] = false;\n            }\n        }\n    }\n    vector<int> accs(lim + 1);\n    for(int i = 1; i <= lim; i++){\n        accs[i] = accs[i - 1] + (i & 1 && prime[i] && prime[(i + 1) / 2]);\n    }\n    // printd(accs[lim]);\n    // int q; cin >> q;\n    int q = buf.next();\n    // stringstream ss;\n    ans.reserve(4 * q);\n    for(int i = 0; i < q; i++){\n        // int l, r;\n        // cin >> l >> r;\n        int l = buf.next(), r = buf.next();\n        // cout << accs[r] - accs[l - 1] << '\\n';\n        // ss << accs[r] - accs[l - 1] << '\\n';\n        out(accs[r] - accs[l - 1]);\n        // putchar('\\n');\n        ans += '\\n';\n    }\n    // cout << ss.str();\n    cout << ans;\n    // write(1, ans.data(), ans.size());\n}\n", "language": "C++", "metadata": {"date": 1514703401, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03476.html", "problem_id": "p03476", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03476/input.txt", "sample_output_relpath": "derived/input_output/data/p03476/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03476/C++/s335380087.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s335380087", "user_id": "u817722036"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include<algorithm>\n#include<cmath>\n#include<iomanip>\n#include<iostream>\n#include<map>\n#include<numeric>\n#include<queue>\n#include<set>\n#include<sstream>\n#include<unordered_map>\n#include<unordered_set>\n#include<vector>\nusing uint = unsigned int;\nusing ll = long long;\nenum : int { M = (int)1e9 + 7 };\nenum : ll { MLL = (ll)1e18L + 9 };\nusing namespace std;\n#ifdef LOCAL\n#include\"rprint2.hpp\"\n#include\"debug_deque.hpp\"\n#define vector DebugDeque\n#else\n#define FUNC(name) template <ostream& out = cout, class... T> void name(T&&...){ }\nFUNC(prints) FUNC(printe) FUNC(printw) FUNC(printew) FUNC(printb) FUNC(printd) FUNC(printde);\n#endif\n\n#include<unistd.h>\nstruct Buffer{\n    int idx;\n    enum { chunk = 1 << 16 };\n    char buf[chunk];\n    Buffer(){ init(); }\n    void init(){ idx = 0; read(0, buf, chunk); }\n    void check(){ if(idx == chunk){ init(); } }\n    int next(){\n        static char notDigits[256] = {1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,0,1,1, 0,0,0,0,0,0,0,0,0,0,};\n        int ret = 0, sign = 1;\n        while(check(), notDigits[(int)buf[idx]]){ idx++; }\n        if(check(), buf[idx] == '-'){ sign = -1; idx++; }\n        while(check(), !notDigits[(int)buf[idx]]){ ret = ret * 10 + buf[idx++] - '0'; }\n        return sign * ret;\n    }\n};\n\nstring ans;\nvoid out(int num){\n    if(!num){\n        // putchar('0');\n        ans += '0';\n        return;\n    }\n    char buf[16];\n    int idx = 0;\n    while(num){\n        auto ret = div(num, 10);\n        buf[idx] = ret.rem + '0';\n        num = ret.quot;\n        idx++;\n    }\n    for(int i = idx - 1; i >= 0; i--){\n        // putchar(buf[i]);\n        ans += buf[i];\n    }\n}\n\nint main(){\n    // cin.tie(0);\n    // ios::sync_with_stdio(false);\n    Buffer buf;\n    const int lim = 1e5;\n    vector<char> prime(lim + 1, true);\n    prime[0] = prime[1] = false;\n    for(int i = 2; i <= lim; i++){\n        if(prime[i]){\n            for(int j = i + i; j <= lim; j += i){\n                prime[j] = false;\n            }\n        }\n    }\n    vector<int> accs(lim + 1);\n    for(int i = 1; i <= lim; i++){\n        accs[i] = accs[i - 1] + (i & 1 && prime[i] && prime[(i + 1) / 2]);\n    }\n    // printd(accs[lim]);\n    // int q; cin >> q;\n    int q = buf.next();\n    // stringstream ss;\n    ans.reserve(4 * q);\n    for(int i = 0; i < q; i++){\n        // int l, r;\n        // cin >> l >> r;\n        int l = buf.next(), r = buf.next();\n        // cout << accs[r] - accs[l - 1] << '\\n';\n        // ss << accs[r] - accs[l - 1] << '\\n';\n        out(accs[r] - accs[l - 1]);\n        // putchar('\\n');\n        ans += '\\n';\n    }\n    // cout << ss.str();\n    cout << ans;\n    // write(1, ans.data(), ans.size());\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nWe say that a odd number N is similar to 2017 when both N and (N+1)/2 are prime.\n\nYou are given Q queries.\n\nIn the i-th query, given two odd numbers l_i and r_i, find the number of odd numbers x similar to 2017 such that l_i ≤ x ≤ r_i.\n\nConstraints\n\n1≤Q≤10^5\n\n1≤l_i≤r_i≤10^5\n\nl_i and r_i are odd.\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nQ\nl_1 r_1\n:\nl_Q r_Q\n\nOutput\n\nPrint Q lines. The i-th line (1≤i≤Q) should contain the response to the i-th query.\n\nSample Input 1\n\n1\n3 7\n\nSample Output 1\n\n2\n\n3 is similar to 2017, since both 3 and (3+1)/2=2 are prime.\n\n5 is similar to 2017, since both 5 and (5+1)/2=3 are prime.\n\n7 is not similar to 2017, since (7+1)/2=4 is not prime, although 7 is prime.\n\nThus, the response to the first query should be 2.\n\nSample Input 2\n\n4\n13 13\n7 11\n7 11\n2017 2017\n\nSample Output 2\n\n1\n0\n0\n1\n\nNote that 2017 is also similar to 2017.\n\nSample Input 3\n\n6\n1 53\n13 91\n37 55\n19 51\n73 91\n13 49\n\nSample Output 3\n\n4\n4\n1\n1\n1\n2", "sample_input": "1\n3 7\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03476", "source_text": "Score : 400 points\n\nProblem Statement\n\nWe say that a odd number N is similar to 2017 when both N and (N+1)/2 are prime.\n\nYou are given Q queries.\n\nIn the i-th query, given two odd numbers l_i and r_i, find the number of odd numbers x similar to 2017 such that l_i ≤ x ≤ r_i.\n\nConstraints\n\n1≤Q≤10^5\n\n1≤l_i≤r_i≤10^5\n\nl_i and r_i are odd.\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nQ\nl_1 r_1\n:\nl_Q r_Q\n\nOutput\n\nPrint Q lines. The i-th line (1≤i≤Q) should contain the response to the i-th query.\n\nSample Input 1\n\n1\n3 7\n\nSample Output 1\n\n2\n\n3 is similar to 2017, since both 3 and (3+1)/2=2 are prime.\n\n5 is similar to 2017, since both 5 and (5+1)/2=3 are prime.\n\n7 is not similar to 2017, since (7+1)/2=4 is not prime, although 7 is prime.\n\nThus, the response to the first query should be 2.\n\nSample Input 2\n\n4\n13 13\n7 11\n7 11\n2017 2017\n\nSample Output 2\n\n1\n0\n0\n1\n\nNote that 2017 is also similar to 2017.\n\nSample Input 3\n\n6\n1 53\n13 91\n37 55\n19 51\n73 91\n13 49\n\nSample Output 3\n\n4\n4\n1\n1\n1\n2", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2689, "cpu_time_ms": 9, "memory_kb": 1536}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s248157211", "group_id": "codeNet:p03477", "input_text": "#include <iostream>\nusing namespace std;\n\nint main() {\n  int A, B, C, D;\n  cin >> A >> B >> C >> D;\n  int l = A + B;\n  int r = C + D;\n  if(l > r) {\n    cout << \"Left\" << endl;\n  } else if(l < r) {\n    cout << \"Right\" << endl;\n  } else {\n    cout << \"Balanced\" << endl;\n  }\n  return 0;\n}", "language": "C++", "metadata": {"date": 1582049773, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03477.html", "problem_id": "p03477", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03477/input.txt", "sample_output_relpath": "derived/input_output/data/p03477/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03477/C++/s248157211.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s248157211", "user_id": "u231541008"}, "prompt_components": {"gold_output": "Left\n", "input_to_evaluate": "#include <iostream>\nusing namespace std;\n\nint main() {\n  int A, B, C, D;\n  cin >> A >> B >> C >> D;\n  int l = A + B;\n  int r = C + D;\n  if(l > r) {\n    cout << \"Left\" << endl;\n  } else if(l < r) {\n    cout << \"Right\" << endl;\n  } else {\n    cout << \"Balanced\" << endl;\n  }\n  return 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nA balance scale tips to the left if L>R, where L is the total weight of the masses on the left pan and R is the total weight of the masses on the right pan. Similarly, it balances if L=R, and tips to the right if L<R.\n\nTakahashi placed a mass of weight A and a mass of weight B on the left pan of a balance scale, and placed a mass of weight C and a mass of weight D on the right pan.\n\nPrint Left if the balance scale tips to the left; print Balanced if it balances; print Right if it tips to the right.\n\nConstraints\n\n1\\leq A,B,C,D \\leq 10\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B C D\n\nOutput\n\nPrint Left if the balance scale tips to the left; print Balanced if it balances; print Right if it tips to the right.\n\nSample Input 1\n\n3 8 7 1\n\nSample Output 1\n\nLeft\n\nThe total weight of the masses on the left pan is 11, and the total weight of the masses on the right pan is 8. Since 11>8, we should print Left.\n\nSample Input 2\n\n3 4 5 2\n\nSample Output 2\n\nBalanced\n\nThe total weight of the masses on the left pan is 7, and the total weight of the masses on the right pan is 7. Since 7=7, we should print Balanced.\n\nSample Input 3\n\n1 7 6 4\n\nSample Output 3\n\nRight\n\nThe total weight of the masses on the left pan is 8, and the total weight of the masses on the right pan is 10. Since 8<10, we should print Right.", "sample_input": "3 8 7 1\n"}, "reference_outputs": ["Left\n"], "source_document_id": "p03477", "source_text": "Score : 100 points\n\nProblem Statement\n\nA balance scale tips to the left if L>R, where L is the total weight of the masses on the left pan and R is the total weight of the masses on the right pan. Similarly, it balances if L=R, and tips to the right if L<R.\n\nTakahashi placed a mass of weight A and a mass of weight B on the left pan of a balance scale, and placed a mass of weight C and a mass of weight D on the right pan.\n\nPrint Left if the balance scale tips to the left; print Balanced if it balances; print Right if it tips to the right.\n\nConstraints\n\n1\\leq A,B,C,D \\leq 10\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B C D\n\nOutput\n\nPrint Left if the balance scale tips to the left; print Balanced if it balances; print Right if it tips to the right.\n\nSample Input 1\n\n3 8 7 1\n\nSample Output 1\n\nLeft\n\nThe total weight of the masses on the left pan is 11, and the total weight of the masses on the right pan is 8. Since 11>8, we should print Left.\n\nSample Input 2\n\n3 4 5 2\n\nSample Output 2\n\nBalanced\n\nThe total weight of the masses on the left pan is 7, and the total weight of the masses on the right pan is 7. Since 7=7, we should print Balanced.\n\nSample Input 3\n\n1 7 6 4\n\nSample Output 3\n\nRight\n\nThe total weight of the masses on the left pan is 8, and the total weight of the masses on the right pan is 10. Since 8<10, we should print Right.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 286, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s617522282", "group_id": "codeNet:p03479", "input_text": "#include \"bits/stdc++.h\"\nusing namespace std;\n#define ll long long int\n#define rep(i,n) for( int i = 0; i < n; i++ )\n#define REP(i,s,t) for( int i = s; i <= t; i++ )\n#define dump(x)  cerr << #x << \" = \" << (x) << endl;\n#define INF 2000000000\n#define mod 1000000007\n#define INF2 1000000000000000000\n#define int long long int \n\nsigned main(void)\n{\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n    int X, Y;\n    cin >> X >> Y;\n    int ans = 0;\n    while(X <= Y) {\n        X *= 2;\n        ans++;\n    }\n    cout << ans << endl;\n\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1520454984, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03479.html", "problem_id": "p03479", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03479/input.txt", "sample_output_relpath": "derived/input_output/data/p03479/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03479/C++/s617522282.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s617522282", "user_id": "u965730380"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include \"bits/stdc++.h\"\nusing namespace std;\n#define ll long long int\n#define rep(i,n) for( int i = 0; i < n; i++ )\n#define REP(i,s,t) for( int i = s; i <= t; i++ )\n#define dump(x)  cerr << #x << \" = \" << (x) << endl;\n#define INF 2000000000\n#define mod 1000000007\n#define INF2 1000000000000000000\n#define int long long int \n\nsigned main(void)\n{\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n    int X, Y;\n    cin >> X >> Y;\n    int ans = 0;\n    while(X <= Y) {\n        X *= 2;\n        ans++;\n    }\n    cout << ans << endl;\n\n    return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nAs a token of his gratitude, Takahashi has decided to give his mother an integer sequence.\nThe sequence A needs to satisfy the conditions below:\n\nA consists of integers between X and Y (inclusive).\n\nFor each 1\\leq i \\leq |A|-1, A_{i+1} is a multiple of A_i and strictly greater than A_i.\n\nFind the maximum possible length of the sequence.\n\nConstraints\n\n1 \\leq X \\leq Y \\leq 10^{18}\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX Y\n\nOutput\n\nPrint the maximum possible length of the sequence.\n\nSample Input 1\n\n3 20\n\nSample Output 1\n\n3\n\nThe sequence 3,6,18 satisfies the conditions.\n\nSample Input 2\n\n25 100\n\nSample Output 2\n\n3\n\nSample Input 3\n\n314159265 358979323846264338\n\nSample Output 3\n\n31", "sample_input": "3 20\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03479", "source_text": "Score : 300 points\n\nProblem Statement\n\nAs a token of his gratitude, Takahashi has decided to give his mother an integer sequence.\nThe sequence A needs to satisfy the conditions below:\n\nA consists of integers between X and Y (inclusive).\n\nFor each 1\\leq i \\leq |A|-1, A_{i+1} is a multiple of A_i and strictly greater than A_i.\n\nFind the maximum possible length of the sequence.\n\nConstraints\n\n1 \\leq X \\leq Y \\leq 10^{18}\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX Y\n\nOutput\n\nPrint the maximum possible length of the sequence.\n\nSample Input 1\n\n3 20\n\nSample Output 1\n\n3\n\nThe sequence 3,6,18 satisfies the conditions.\n\nSample Input 2\n\n25 100\n\nSample Output 2\n\n3\n\nSample Input 3\n\n314159265 358979323846264338\n\nSample Output 3\n\n31", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 544, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s785308067", "group_id": "codeNet:p03480", "input_text": "#define _USE_MATH_DEFINES\n\n#include <stdio.h>\n#include <iostream>\n#include <algorithm>\n#include <cmath>\n#include <string>\n#include <utility>\n#include <climits>\n#include <vector>\n#include <map>\n#include <queue>\n#include <set>\nusing namespace std;\n\n#define ll long long\nconst int MOD = 1000000007;//10^9+7\nconst string SPACE = \" \";\n\nll powsur(ll a, ll b, ll p) {\n\n\tif (b == 0) {\n\n\t\treturn 1;\n\n\t}\n\telse if (b % 2 == 0) {\n\n\t\tll d = powsur(a, b / 2, p);\n\t\treturn ((d%p)*(d%p)) % p;\n\n\t}\n\telse {\n\n\t\treturn ((a%p)*powsur(a, b - 1, p) % p) % p;\n\n\t}\n\n}\n//pは素数,aのb乗をpで割った余り\n\nll CMOD(ll n, ll r, ll p) {\n\n\tll a = 1, b = 1, c = 1, re;\n\tfor (int i = 1; i <= n; i++) {\n\n\t\ta *= i;\n\t\ta = a%p;\n\n\t}\n\tfor (int i = 1; i <= r; i++) {\n\n\t\tb *= i;\n\t\tb = b%p;\n\n\t}\n\tfor (int i = 1; i <= n - r; i++) {\n\n\t\tc *= i;\n\t\tc = c%p;\n\n\t}\n\tb = powsur(b, p - 2, p);\n\tc = powsur(c, p - 2, p);\n\tre = ((a%p)*(b%p)) % p;\n\tre = ((re%p)*c%p) % p;\n\n\treturn re;\n\n}\n//pは素数,(nCr)%p\n\nll gcd(ll a, ll b) {\n\n\tif (a > b) {\n\n\t\tll tmp = a;\n\t\ta = b;\n\t\tb = tmp;\n\n\t}\n\tll r;\n\tr = b%a;\n\tif (r == 0)return a;\n\telse return gcd(r, a);\n\n}\n//最大公約数\n\nll lcm(ll a, ll b) {\n\n\treturn (a / gcd(a, b))*b;\n\n}\n//最小公倍数\n\nll MAX(ll a, ll b) {\n\n\tif (a > b)return a;\n\telse return b;\n\n}\n//MAX\n\nll MIN(ll a, ll b) {\n\n\tif (a < b)return a;\n\telse return b;\n\n}\n//MIN\n\nbool func(ll p) {\n\n\tif (p == 1)return false;\n\telse if (p == 2)return true;\n\telse {\n\n\t\tbool flag = true;\n\t\tfor (int i = 2; i <= sqrt(p); i++) {\n\n\t\t\tif (p%i == 0) {\n\n\t\t\t\tflag = false;\n\t\t\t\tbreak;\n\n\t\t\t}\n\n\t\t}\n\t\treturn flag;\n\n\t}\n\n}\n//素数判定,素数=true,合成数=false\n\nint main() {\n\n\tstring S;\n\tll ans = 1000000, tmp;\n\n\tcin >> S;\n\tfor (ll i = 0; i < S.size() - 1; i++) {\n\n\t\tif (S[i] != S[i + 1])tmp = max((ll)(i + 1), (ll)(S.size() - i - 1));\n\t\tans = MIN(ans, tmp);\n\n\t}\n\tcout << ans << endl;\n\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1522530691, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03480.html", "problem_id": "p03480", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03480/input.txt", "sample_output_relpath": "derived/input_output/data/p03480/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03480/C++/s785308067.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s785308067", "user_id": "u285598935"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#define _USE_MATH_DEFINES\n\n#include <stdio.h>\n#include <iostream>\n#include <algorithm>\n#include <cmath>\n#include <string>\n#include <utility>\n#include <climits>\n#include <vector>\n#include <map>\n#include <queue>\n#include <set>\nusing namespace std;\n\n#define ll long long\nconst int MOD = 1000000007;//10^9+7\nconst string SPACE = \" \";\n\nll powsur(ll a, ll b, ll p) {\n\n\tif (b == 0) {\n\n\t\treturn 1;\n\n\t}\n\telse if (b % 2 == 0) {\n\n\t\tll d = powsur(a, b / 2, p);\n\t\treturn ((d%p)*(d%p)) % p;\n\n\t}\n\telse {\n\n\t\treturn ((a%p)*powsur(a, b - 1, p) % p) % p;\n\n\t}\n\n}\n//pは素数,aのb乗をpで割った余り\n\nll CMOD(ll n, ll r, ll p) {\n\n\tll a = 1, b = 1, c = 1, re;\n\tfor (int i = 1; i <= n; i++) {\n\n\t\ta *= i;\n\t\ta = a%p;\n\n\t}\n\tfor (int i = 1; i <= r; i++) {\n\n\t\tb *= i;\n\t\tb = b%p;\n\n\t}\n\tfor (int i = 1; i <= n - r; i++) {\n\n\t\tc *= i;\n\t\tc = c%p;\n\n\t}\n\tb = powsur(b, p - 2, p);\n\tc = powsur(c, p - 2, p);\n\tre = ((a%p)*(b%p)) % p;\n\tre = ((re%p)*c%p) % p;\n\n\treturn re;\n\n}\n//pは素数,(nCr)%p\n\nll gcd(ll a, ll b) {\n\n\tif (a > b) {\n\n\t\tll tmp = a;\n\t\ta = b;\n\t\tb = tmp;\n\n\t}\n\tll r;\n\tr = b%a;\n\tif (r == 0)return a;\n\telse return gcd(r, a);\n\n}\n//最大公約数\n\nll lcm(ll a, ll b) {\n\n\treturn (a / gcd(a, b))*b;\n\n}\n//最小公倍数\n\nll MAX(ll a, ll b) {\n\n\tif (a > b)return a;\n\telse return b;\n\n}\n//MAX\n\nll MIN(ll a, ll b) {\n\n\tif (a < b)return a;\n\telse return b;\n\n}\n//MIN\n\nbool func(ll p) {\n\n\tif (p == 1)return false;\n\telse if (p == 2)return true;\n\telse {\n\n\t\tbool flag = true;\n\t\tfor (int i = 2; i <= sqrt(p); i++) {\n\n\t\t\tif (p%i == 0) {\n\n\t\t\t\tflag = false;\n\t\t\t\tbreak;\n\n\t\t\t}\n\n\t\t}\n\t\treturn flag;\n\n\t}\n\n}\n//素数判定,素数=true,合成数=false\n\nint main() {\n\n\tstring S;\n\tll ans = 1000000, tmp;\n\n\tcin >> S;\n\tfor (ll i = 0; i < S.size() - 1; i++) {\n\n\t\tif (S[i] != S[i + 1])tmp = max((ll)(i + 1), (ll)(S.size() - i - 1));\n\t\tans = MIN(ans, tmp);\n\n\t}\n\tcout << ans << endl;\n\n\treturn 0;\n}", "problem_context": "Score : 500 points\n\nProblem Statement\n\nYou are given a string S consisting of 0 and 1.\nFind the maximum integer K not greater than |S| such that we can turn all the characters of S into 0 by repeating the following operation some number of times.\n\nChoose a contiguous segment [l,r] in S whose length is at least K (that is, r-l+1\\geq K must be satisfied). For each integer i such that l\\leq i\\leq r, do the following: if S_i is 0, replace it with 1; if S_i is 1, replace it with 0.\n\nConstraints\n\n1\\leq |S|\\leq 10^5\n\nS_i(1\\leq i\\leq N) is either 0 or 1.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the maximum integer K such that we can turn all the characters of S into 0 by repeating the operation some number of times.\n\nSample Input 1\n\n010\n\nSample Output 1\n\n2\n\nWe can turn all the characters of S into 0 by the following operations:\n\nPerform the operation on the segment S[1,3] with length 3. S is now 101.\n\nPerform the operation on the segment S[1,2] with length 2. S is now 011.\n\nPerform the operation on the segment S[2,3] with length 2. S is now 000.\n\nSample Input 2\n\n100000000\n\nSample Output 2\n\n8\n\nSample Input 3\n\n00001111\n\nSample Output 3\n\n4", "sample_input": "010\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03480", "source_text": "Score : 500 points\n\nProblem Statement\n\nYou are given a string S consisting of 0 and 1.\nFind the maximum integer K not greater than |S| such that we can turn all the characters of S into 0 by repeating the following operation some number of times.\n\nChoose a contiguous segment [l,r] in S whose length is at least K (that is, r-l+1\\geq K must be satisfied). For each integer i such that l\\leq i\\leq r, do the following: if S_i is 0, replace it with 1; if S_i is 1, replace it with 0.\n\nConstraints\n\n1\\leq |S|\\leq 10^5\n\nS_i(1\\leq i\\leq N) is either 0 or 1.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the maximum integer K such that we can turn all the characters of S into 0 by repeating the operation some number of times.\n\nSample Input 1\n\n010\n\nSample Output 1\n\n2\n\nWe can turn all the characters of S into 0 by the following operations:\n\nPerform the operation on the segment S[1,3] with length 3. S is now 101.\n\nPerform the operation on the segment S[1,2] with length 2. S is now 011.\n\nPerform the operation on the segment S[2,3] with length 2. S is now 000.\n\nSample Input 2\n\n100000000\n\nSample Output 2\n\n8\n\nSample Input 3\n\n00001111\n\nSample Output 3\n\n4", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1838, "cpu_time_ms": 5, "memory_kb": 512}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s159233829", "group_id": "codeNet:p03483", "input_text": "#include<bits/stdc++.h>\n#define ALL(c) (c).begin(),(c).end()\n#define EACH(i,c) for(auto i=(c).begin();i!=(c).end();++i)\nusing namespace std;\n#define int long long\n\ntemplate<typename T>\nstruct Fenwick{\n    vector<T> bit;\n    T mod;\n    Fenwick(int n){\n        bit = vector<T>(n + 1);\n        mod = 0;\n    }\n    void add(int i, T v){\n        int n = bit.size();\n        ++i;\n        while(i < n){\n            bit[i] += v;\n            i += i & -i;\n        }\n    }\n    T get(int i){\n        T res = 0;\n        ++i;\n        while(i > 0){\n            res += bit[i];\n            i -= i & -i;\n        }\n        return res;\n    }\n};\n\nint func(const string &S, const string &T) {\n    int N = S.size();\n    Fenwick<int> bit(N + 10);\n    vector<queue<int>> v(0x100);\n    for(int i = 0; i < N; ++i) {\n        v[S[i]].push(i);\n    }\n    int res = 0;\n    for(int i = 0; i < N; ++i) {\n        char c = T[i];\n        int p = v[c].front();\n        v[c].pop();\n        int q = p + i - bit.get(p);\n//        cerr << c << \",\" << p << \",\" << q << \",\"<< q - i << endl;\n        res += q - i;\n        bit.add(p, 1);\n    }\n    return res;\n}\n\nvoid solve(std::string S){\n    int N = S.size();\n    vector<int> d(0x100);\n    for(int i = 0; i < N; ++i) {\n        d[S[i]]++;\n    }\n    int c = 0;\n    char ex = 'A';\n    for(int i = 0; i < 0x100; ++i) {\n        if (d[i] % 2 != 0){\n            ++c;\n            ex = i;\n        }\n    }\n    if ((N % 2 == 0 && c > 0) || (N % 2 == 1 && c != 1)) {\n        cout << -1 << endl;\n        return;\n    }\n    vector<int> e(0x100);\n    string T = \"\", U = \"\";\n    int init = 0;\n    for(int i = 0; i < N; ++i) {\n        char c = S[i];\n        if (e[c] < d[c] / 2) {\n            init += i - T.size();\n            T += c;\n        } else {\n            U += c;\n        }\n        ++e[c];\n    }\n    if (N % 2 != 0) {\n        for(int i = 0; i < U.size(); ++i) {\n            if (U[i] == ex) {\n                init += i;\n                if (i == 0) {\n                    U = U.substr(1);\n                } else if(i + 1 == U.size()) {\n                    U.pop_back();\n                } else {\n                    U = U.substr(0, i) + U.substr(i + 1);\n                }\n                break;\n            }\n        }\n    }\n//    cerr << T << init << U << endl;\n    reverse(ALL(U));\n\n    cout << init + func(T, U) << endl;\n}\n\nsigned main(){\n    std::string S;\n    std::cin >> S;\n    solve(S);\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1561919521, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03483.html", "problem_id": "p03483", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03483/input.txt", "sample_output_relpath": "derived/input_output/data/p03483/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03483/C++/s159233829.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s159233829", "user_id": "u183530284"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include<bits/stdc++.h>\n#define ALL(c) (c).begin(),(c).end()\n#define EACH(i,c) for(auto i=(c).begin();i!=(c).end();++i)\nusing namespace std;\n#define int long long\n\ntemplate<typename T>\nstruct Fenwick{\n    vector<T> bit;\n    T mod;\n    Fenwick(int n){\n        bit = vector<T>(n + 1);\n        mod = 0;\n    }\n    void add(int i, T v){\n        int n = bit.size();\n        ++i;\n        while(i < n){\n            bit[i] += v;\n            i += i & -i;\n        }\n    }\n    T get(int i){\n        T res = 0;\n        ++i;\n        while(i > 0){\n            res += bit[i];\n            i -= i & -i;\n        }\n        return res;\n    }\n};\n\nint func(const string &S, const string &T) {\n    int N = S.size();\n    Fenwick<int> bit(N + 10);\n    vector<queue<int>> v(0x100);\n    for(int i = 0; i < N; ++i) {\n        v[S[i]].push(i);\n    }\n    int res = 0;\n    for(int i = 0; i < N; ++i) {\n        char c = T[i];\n        int p = v[c].front();\n        v[c].pop();\n        int q = p + i - bit.get(p);\n//        cerr << c << \",\" << p << \",\" << q << \",\"<< q - i << endl;\n        res += q - i;\n        bit.add(p, 1);\n    }\n    return res;\n}\n\nvoid solve(std::string S){\n    int N = S.size();\n    vector<int> d(0x100);\n    for(int i = 0; i < N; ++i) {\n        d[S[i]]++;\n    }\n    int c = 0;\n    char ex = 'A';\n    for(int i = 0; i < 0x100; ++i) {\n        if (d[i] % 2 != 0){\n            ++c;\n            ex = i;\n        }\n    }\n    if ((N % 2 == 0 && c > 0) || (N % 2 == 1 && c != 1)) {\n        cout << -1 << endl;\n        return;\n    }\n    vector<int> e(0x100);\n    string T = \"\", U = \"\";\n    int init = 0;\n    for(int i = 0; i < N; ++i) {\n        char c = S[i];\n        if (e[c] < d[c] / 2) {\n            init += i - T.size();\n            T += c;\n        } else {\n            U += c;\n        }\n        ++e[c];\n    }\n    if (N % 2 != 0) {\n        for(int i = 0; i < U.size(); ++i) {\n            if (U[i] == ex) {\n                init += i;\n                if (i == 0) {\n                    U = U.substr(1);\n                } else if(i + 1 == U.size()) {\n                    U.pop_back();\n                } else {\n                    U = U.substr(0, i) + U.substr(i + 1);\n                }\n                break;\n            }\n        }\n    }\n//    cerr << T << init << U << endl;\n    reverse(ALL(U));\n\n    cout << init + func(T, U) << endl;\n}\n\nsigned main(){\n    std::string S;\n    std::cin >> S;\n    solve(S);\n    return 0;\n}\n", "problem_context": "Score : 800 points\n\nProblem Statement\n\nYou are given a string S consisting of lowercase English letters.\nDetermine whether we can turn S into a palindrome by repeating the operation of swapping two adjacent characters. If it is possible, find the minimum required number of operations.\n\nConstraints\n\n1 \\leq |S| \\leq 2 × 10^5\n\nS consists of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nIf we cannot turn S into a palindrome, print -1. Otherwise, print the minimum required number of operations.\n\nSample Input 1\n\neel\n\nSample Output 1\n\n1\n\nWe can turn S into a palindrome by the following operation:\n\nSwap the 2-nd and 3-rd characters. S is now ele.\n\nSample Input 2\n\nataatmma\n\nSample Output 2\n\n4\n\nWe can turn S into a palindrome by the following operation:\n\nSwap the 5-th and 6-th characters. S is now ataamtma.\n\nSwap the 4-th and 5-th characters. S is now atamatma.\n\nSwap the 3-rd and 4-th characters. S is now atmaatma.\n\nSwap the 2-nd and 3-rd characters. S is now amtaatma.\n\nSample Input 3\n\nsnuke\n\nSample Output 3\n\n-1\n\nWe cannot turn S into a palindrome.", "sample_input": "eel\n"}, "reference_outputs": ["1\n"], "source_document_id": "p03483", "source_text": "Score : 800 points\n\nProblem Statement\n\nYou are given a string S consisting of lowercase English letters.\nDetermine whether we can turn S into a palindrome by repeating the operation of swapping two adjacent characters. If it is possible, find the minimum required number of operations.\n\nConstraints\n\n1 \\leq |S| \\leq 2 × 10^5\n\nS consists of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nIf we cannot turn S into a palindrome, print -1. Otherwise, print the minimum required number of operations.\n\nSample Input 1\n\neel\n\nSample Output 1\n\n1\n\nWe can turn S into a palindrome by the following operation:\n\nSwap the 2-nd and 3-rd characters. S is now ele.\n\nSample Input 2\n\nataatmma\n\nSample Output 2\n\n4\n\nWe can turn S into a palindrome by the following operation:\n\nSwap the 5-th and 6-th characters. S is now ataamtma.\n\nSwap the 4-th and 5-th characters. S is now atamatma.\n\nSwap the 3-rd and 4-th characters. S is now atmaatma.\n\nSwap the 2-nd and 3-rd characters. S is now amtaatma.\n\nSample Input 3\n\nsnuke\n\nSample Output 3\n\n-1\n\nWe cannot turn S into a palindrome.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2401, "cpu_time_ms": 14, "memory_kb": 2692}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s871751117", "group_id": "codeNet:p03485", "input_text": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <cmath>\n#define ll long long\n#define rep(i, a, b) for(ll i = (ll)a; i < (ll)b; i++)\nusing namespace std;\n\nint main() {\n  int a, b;\n  cin >> a >> b;\n  cout << (a+b+1) / 2 << \"\\n\";\n}\n", "language": "C++", "metadata": {"date": 1596737003, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03485.html", "problem_id": "p03485", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03485/input.txt", "sample_output_relpath": "derived/input_output/data/p03485/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03485/C++/s871751117.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s871751117", "user_id": "u841702632"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <cmath>\n#define ll long long\n#define rep(i, a, b) for(ll i = (ll)a; i < (ll)b; i++)\nusing namespace std;\n\nint main() {\n  int a, b;\n  cin >> a >> b;\n  cout << (a+b+1) / 2 << \"\\n\";\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nYou are given two positive integers a and b.\nLet x be the average of a and b.\nPrint x rounded up to the nearest integer.\n\nConstraints\n\na and b are integers.\n\n1 \\leq a, b \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\na b\n\nOutput\n\nPrint x rounded up to the nearest integer.\n\nSample Input 1\n\n1 3\n\nSample Output 1\n\n2\n\nThe average of 1 and 3 is 2.0, and it will be rounded up to the nearest integer, 2.\n\nSample Input 2\n\n7 4\n\nSample Output 2\n\n6\n\nThe average of 7 and 4 is 5.5, and it will be rounded up to the nearest integer, 6.\n\nSample Input 3\n\n5 5\n\nSample Output 3\n\n5", "sample_input": "1 3\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03485", "source_text": "Score : 100 points\n\nProblem Statement\n\nYou are given two positive integers a and b.\nLet x be the average of a and b.\nPrint x rounded up to the nearest integer.\n\nConstraints\n\na and b are integers.\n\n1 \\leq a, b \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\na b\n\nOutput\n\nPrint x rounded up to the nearest integer.\n\nSample Input 1\n\n1 3\n\nSample Output 1\n\n2\n\nThe average of 1 and 3 is 2.0, and it will be rounded up to the nearest integer, 2.\n\nSample Input 2\n\n7 4\n\nSample Output 2\n\n6\n\nThe average of 7 and 4 is 5.5, and it will be rounded up to the nearest integer, 6.\n\nSample Input 3\n\n5 5\n\nSample Output 3\n\n5", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 249, "cpu_time_ms": 7, "memory_kb": 3584}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s698127843", "group_id": "codeNet:p03485", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n  double a, b, y;\n  int Y;\n  \n  cin >> a >> b;\n  \n  y = a/b;\n  Y = a/b;\n  \n  if(!(y - Y))\n    Y++;\n  \n  cout << Y <<endl;\n}\n  ", "language": "C++", "metadata": {"date": 1585880560, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03485.html", "problem_id": "p03485", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03485/input.txt", "sample_output_relpath": "derived/input_output/data/p03485/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03485/C++/s698127843.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s698127843", "user_id": "u755487013"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n  double a, b, y;\n  int Y;\n  \n  cin >> a >> b;\n  \n  y = a/b;\n  Y = a/b;\n  \n  if(!(y - Y))\n    Y++;\n  \n  cout << Y <<endl;\n}\n  ", "problem_context": "Score : 100 points\n\nProblem Statement\n\nYou are given two positive integers a and b.\nLet x be the average of a and b.\nPrint x rounded up to the nearest integer.\n\nConstraints\n\na and b are integers.\n\n1 \\leq a, b \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\na b\n\nOutput\n\nPrint x rounded up to the nearest integer.\n\nSample Input 1\n\n1 3\n\nSample Output 1\n\n2\n\nThe average of 1 and 3 is 2.0, and it will be rounded up to the nearest integer, 2.\n\nSample Input 2\n\n7 4\n\nSample Output 2\n\n6\n\nThe average of 7 and 4 is 5.5, and it will be rounded up to the nearest integer, 6.\n\nSample Input 3\n\n5 5\n\nSample Output 3\n\n5", "sample_input": "1 3\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03485", "source_text": "Score : 100 points\n\nProblem Statement\n\nYou are given two positive integers a and b.\nLet x be the average of a and b.\nPrint x rounded up to the nearest integer.\n\nConstraints\n\na and b are integers.\n\n1 \\leq a, b \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\na b\n\nOutput\n\nPrint x rounded up to the nearest integer.\n\nSample Input 1\n\n1 3\n\nSample Output 1\n\n2\n\nThe average of 1 and 3 is 2.0, and it will be rounded up to the nearest integer, 2.\n\nSample Input 2\n\n7 4\n\nSample Output 2\n\n6\n\nThe average of 7 and 4 is 5.5, and it will be rounded up to the nearest integer, 6.\n\nSample Input 3\n\n5 5\n\nSample Output 3\n\n5", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 186, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s171772453", "group_id": "codeNet:p03485", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n int a;\n  int b;\n  cin >> a >> b;\n  a++;\n  cout <<  (a + b) / 2<< endl;\n}\n", "language": "C++", "metadata": {"date": 1583727016, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03485.html", "problem_id": "p03485", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03485/input.txt", "sample_output_relpath": "derived/input_output/data/p03485/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03485/C++/s171772453.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s171772453", "user_id": "u919748022"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n int a;\n  int b;\n  cin >> a >> b;\n  a++;\n  cout <<  (a + b) / 2<< endl;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nYou are given two positive integers a and b.\nLet x be the average of a and b.\nPrint x rounded up to the nearest integer.\n\nConstraints\n\na and b are integers.\n\n1 \\leq a, b \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\na b\n\nOutput\n\nPrint x rounded up to the nearest integer.\n\nSample Input 1\n\n1 3\n\nSample Output 1\n\n2\n\nThe average of 1 and 3 is 2.0, and it will be rounded up to the nearest integer, 2.\n\nSample Input 2\n\n7 4\n\nSample Output 2\n\n6\n\nThe average of 7 and 4 is 5.5, and it will be rounded up to the nearest integer, 6.\n\nSample Input 3\n\n5 5\n\nSample Output 3\n\n5", "sample_input": "1 3\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03485", "source_text": "Score : 100 points\n\nProblem Statement\n\nYou are given two positive integers a and b.\nLet x be the average of a and b.\nPrint x rounded up to the nearest integer.\n\nConstraints\n\na and b are integers.\n\n1 \\leq a, b \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\na b\n\nOutput\n\nPrint x rounded up to the nearest integer.\n\nSample Input 1\n\n1 3\n\nSample Output 1\n\n2\n\nThe average of 1 and 3 is 2.0, and it will be rounded up to the nearest integer, 2.\n\nSample Input 2\n\n7 4\n\nSample Output 2\n\n6\n\nThe average of 7 and 4 is 5.5, and it will be rounded up to the nearest integer, 6.\n\nSample Input 3\n\n5 5\n\nSample Output 3\n\n5", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 134, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s170130500", "group_id": "codeNet:p03485", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n \nint main() {\n  int a,b;\n  cin >> a >> b;\n  cout << ceil((a + b) / 2) << endl;\n}", "language": "C++", "metadata": {"date": 1581519460, "filename_ext": "cpp", "original_language": "C++ (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03485.html", "problem_id": "p03485", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03485/input.txt", "sample_output_relpath": "derived/input_output/data/p03485/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03485/C++/s170130500.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s170130500", "user_id": "u804291438"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n \nint main() {\n  int a,b;\n  cin >> a >> b;\n  cout << ceil((a + b) / 2) << endl;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nYou are given two positive integers a and b.\nLet x be the average of a and b.\nPrint x rounded up to the nearest integer.\n\nConstraints\n\na and b are integers.\n\n1 \\leq a, b \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\na b\n\nOutput\n\nPrint x rounded up to the nearest integer.\n\nSample Input 1\n\n1 3\n\nSample Output 1\n\n2\n\nThe average of 1 and 3 is 2.0, and it will be rounded up to the nearest integer, 2.\n\nSample Input 2\n\n7 4\n\nSample Output 2\n\n6\n\nThe average of 7 and 4 is 5.5, and it will be rounded up to the nearest integer, 6.\n\nSample Input 3\n\n5 5\n\nSample Output 3\n\n5", "sample_input": "1 3\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03485", "source_text": "Score : 100 points\n\nProblem Statement\n\nYou are given two positive integers a and b.\nLet x be the average of a and b.\nPrint x rounded up to the nearest integer.\n\nConstraints\n\na and b are integers.\n\n1 \\leq a, b \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\na b\n\nOutput\n\nPrint x rounded up to the nearest integer.\n\nSample Input 1\n\n1 3\n\nSample Output 1\n\n2\n\nThe average of 1 and 3 is 2.0, and it will be rounded up to the nearest integer, 2.\n\nSample Input 2\n\n7 4\n\nSample Output 2\n\n6\n\nThe average of 7 and 4 is 5.5, and it will be rounded up to the nearest integer, 6.\n\nSample Input 3\n\n5 5\n\nSample Output 3\n\n5", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 127, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s221782838", "group_id": "codeNet:p03485", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n#define FOR(i,a,b) for(int i=(a);i<(b);++i)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(v) (v).begin(),(v).end()\n#define fi first\n#define se second\ntemplate<typename A, typename B> inline bool chmax(A &a, B b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<typename A, typename B> inline bool chmin(A &a, B b) { if (a>b) { a=b; return 1; } return 0; }\ntypedef long long ll;\ntypedef pair<int, int> pii;\nconst ll INF = 1e9+100;\nconst ll MOD = 1e9+7;\nconst bool debug = 0;\n//-----------------------------------------------//\n\nint main() {\n\tint a, b;\n\tcin >> a >> b;\n\tcout << (a + b + 1) / 2 << endl;\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1519170643, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03485.html", "problem_id": "p03485", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03485/input.txt", "sample_output_relpath": "derived/input_output/data/p03485/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03485/C++/s221782838.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s221782838", "user_id": "u105791541"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n#define FOR(i,a,b) for(int i=(a);i<(b);++i)\n#define REP(i,n) FOR(i,0,n)\n#define ALL(v) (v).begin(),(v).end()\n#define fi first\n#define se second\ntemplate<typename A, typename B> inline bool chmax(A &a, B b) { if (a<b) { a=b; return 1; } return 0; }\ntemplate<typename A, typename B> inline bool chmin(A &a, B b) { if (a>b) { a=b; return 1; } return 0; }\ntypedef long long ll;\ntypedef pair<int, int> pii;\nconst ll INF = 1e9+100;\nconst ll MOD = 1e9+7;\nconst bool debug = 0;\n//-----------------------------------------------//\n\nint main() {\n\tint a, b;\n\tcin >> a >> b;\n\tcout << (a + b + 1) / 2 << endl;\n\treturn 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nYou are given two positive integers a and b.\nLet x be the average of a and b.\nPrint x rounded up to the nearest integer.\n\nConstraints\n\na and b are integers.\n\n1 \\leq a, b \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\na b\n\nOutput\n\nPrint x rounded up to the nearest integer.\n\nSample Input 1\n\n1 3\n\nSample Output 1\n\n2\n\nThe average of 1 and 3 is 2.0, and it will be rounded up to the nearest integer, 2.\n\nSample Input 2\n\n7 4\n\nSample Output 2\n\n6\n\nThe average of 7 and 4 is 5.5, and it will be rounded up to the nearest integer, 6.\n\nSample Input 3\n\n5 5\n\nSample Output 3\n\n5", "sample_input": "1 3\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03485", "source_text": "Score : 100 points\n\nProblem Statement\n\nYou are given two positive integers a and b.\nLet x be the average of a and b.\nPrint x rounded up to the nearest integer.\n\nConstraints\n\na and b are integers.\n\n1 \\leq a, b \\leq 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\na b\n\nOutput\n\nPrint x rounded up to the nearest integer.\n\nSample Input 1\n\n1 3\n\nSample Output 1\n\n2\n\nThe average of 1 and 3 is 2.0, and it will be rounded up to the nearest integer, 2.\n\nSample Input 2\n\n7 4\n\nSample Output 2\n\n6\n\nThe average of 7 and 4 is 5.5, and it will be rounded up to the nearest integer, 6.\n\nSample Input 3\n\n5 5\n\nSample Output 3\n\n5", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 655, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s902352739", "group_id": "codeNet:p03486", "input_text": "\n#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n  string s, t;\n  cin >> s >> t;\n  sort (s.begin(), s.end());\n  sort (t.begin(), t.end());\n  reverse (t.begin(), t.end());\n  \n  if (s<t) cout << \"Yes\" << endl;\n  else cout << \"No\" << endl;\n\n}\n", "language": "C++", "metadata": {"date": 1590108452, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03486.html", "problem_id": "p03486", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03486/input.txt", "sample_output_relpath": "derived/input_output/data/p03486/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03486/C++/s902352739.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s902352739", "user_id": "u256587538"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "\n#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n  string s, t;\n  cin >> s >> t;\n  sort (s.begin(), s.end());\n  sort (t.begin(), t.end());\n  reverse (t.begin(), t.end());\n  \n  if (s<t) cout << \"Yes\" << endl;\n  else cout << \"No\" << endl;\n\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nYou are given strings s and t, consisting of lowercase English letters.\nYou will create a string s' by freely rearranging the characters in s.\nYou will also create a string t' by freely rearranging the characters in t.\nDetermine whether it is possible to satisfy s' < t' for the lexicographic order.\n\nNotes\n\nFor a string a = a_1 a_2 ... a_N of length N and a string b = b_1 b_2 ... b_M of length M, we say a < b for the lexicographic order if either one of the following two conditions holds true:\n\nN < M and a_1 = b_1, a_2 = b_2, ..., a_N = b_N.\n\nThere exists i (1 \\leq i \\leq N, M) such that a_1 = b_1, a_2 = b_2, ..., a_{i - 1} = b_{i - 1} and a_i < b_i. Here, letters are compared using alphabetical order.\n\nFor example, xy < xya and atcoder < atlas.\n\nConstraints\n\nThe lengths of s and t are between 1 and 100 (inclusive).\n\ns and t consists of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\ns\nt\n\nOutput\n\nIf it is possible to satisfy s' < t', print Yes; if it is not, print No.\n\nSample Input 1\n\nyx\naxy\n\nSample Output 1\n\nYes\n\nWe can, for example, rearrange yx into xy and axy into yxa. Then, xy < yxa.\n\nSample Input 2\n\nratcode\natlas\n\nSample Output 2\n\nYes\n\nWe can, for example, rearrange ratcode into acdeort and atlas into tslaa. Then, acdeort < tslaa.\n\nSample Input 3\n\ncd\nabc\n\nSample Output 3\n\nNo\n\nNo matter how we rearrange cd and abc, we cannot achieve our objective.\n\nSample Input 4\n\nw\nww\n\nSample Output 4\n\nYes\n\nSample Input 5\n\nzzz\nzzz\n\nSample Output 5\n\nNo", "sample_input": "yx\naxy\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p03486", "source_text": "Score : 200 points\n\nProblem Statement\n\nYou are given strings s and t, consisting of lowercase English letters.\nYou will create a string s' by freely rearranging the characters in s.\nYou will also create a string t' by freely rearranging the characters in t.\nDetermine whether it is possible to satisfy s' < t' for the lexicographic order.\n\nNotes\n\nFor a string a = a_1 a_2 ... a_N of length N and a string b = b_1 b_2 ... b_M of length M, we say a < b for the lexicographic order if either one of the following two conditions holds true:\n\nN < M and a_1 = b_1, a_2 = b_2, ..., a_N = b_N.\n\nThere exists i (1 \\leq i \\leq N, M) such that a_1 = b_1, a_2 = b_2, ..., a_{i - 1} = b_{i - 1} and a_i < b_i. Here, letters are compared using alphabetical order.\n\nFor example, xy < xya and atcoder < atlas.\n\nConstraints\n\nThe lengths of s and t are between 1 and 100 (inclusive).\n\ns and t consists of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\ns\nt\n\nOutput\n\nIf it is possible to satisfy s' < t', print Yes; if it is not, print No.\n\nSample Input 1\n\nyx\naxy\n\nSample Output 1\n\nYes\n\nWe can, for example, rearrange yx into xy and axy into yxa. Then, xy < yxa.\n\nSample Input 2\n\nratcode\natlas\n\nSample Output 2\n\nYes\n\nWe can, for example, rearrange ratcode into acdeort and atlas into tslaa. Then, acdeort < tslaa.\n\nSample Input 3\n\ncd\nabc\n\nSample Output 3\n\nNo\n\nNo matter how we rearrange cd and abc, we cannot achieve our objective.\n\nSample Input 4\n\nw\nww\n\nSample Output 4\n\nYes\n\nSample Input 5\n\nzzz\nzzz\n\nSample Output 5\n\nNo", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 252, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s057052115", "group_id": "codeNet:p03488", "input_text": "#include <algorithm>\n#include <iostream>\n#include <queue>\n#include <string>\n#include <utility>\nusing namespace std;\n\n#define FOR(i, a, b) for (int i = a; i < b; ++i)\n#define RFOR(i, a, b) for (int i = a; i > b; --i)\n#define REP(i, n) for (int i = 0; i < n; ++i)\n\nstring s;\nint gx, gy;\nint x = 0, y = 0;\nstring ans = \"\";\n\ntypedef pair<int, int> Pair;\nvector<Pair> goals;\n\nint main() {\n  cin >> s;\n  cin >> gx >> gy;\n  goals.push_back(Pair(gx, gy));\n\n  bool to_x = true;\n  REP(i, s.length()) {\n    if (s[i] == 'F') {\n      if (to_x) { ++x; } else { ++y; }\n    } else {\n      if (to_x) {\n        REP(j, goals.size()) {\n          if (goals[j].second < y) {\n            goals[j].second += 2 * (y - goals[j].second);\n          }\n        }\n        int gs = goals.size();\n        REP(j, gs) {\n          goals.push_back(Pair(\n            goals[j].first,\n            y + 2*(goals[i].second - y)));\n        }\n        to_x = false;\n      } else {\n        REP(j, goals.size()) {\n          if (goals[j].first < x) {\n            goals[j].first += 2 * (x - goals[j].first);\n          }\n        }\n        int gs = goals.size();\n        REP(j, gs) {\n          goals.push_back(Pair(\n            x + 2*(goals[j].first - x),\n            goals[j].second));\n        }\n        to_x = true;\n      }\n    }\n  }\n\n  bool f = false;\n  REP(i, goals.size()) {\n    if (x == goals[i].first && y == goals[i].second) {\n      f = true;\n      break;\n    }\n  }\n  if (f) {\n    ans = \"Yes\";\n  } else {\n    ans = \"No\";\n  }\n\n  cout << ans << endl;\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1513988647, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03488.html", "problem_id": "p03488", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03488/input.txt", "sample_output_relpath": "derived/input_output/data/p03488/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03488/C++/s057052115.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s057052115", "user_id": "u984351908"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <algorithm>\n#include <iostream>\n#include <queue>\n#include <string>\n#include <utility>\nusing namespace std;\n\n#define FOR(i, a, b) for (int i = a; i < b; ++i)\n#define RFOR(i, a, b) for (int i = a; i > b; --i)\n#define REP(i, n) for (int i = 0; i < n; ++i)\n\nstring s;\nint gx, gy;\nint x = 0, y = 0;\nstring ans = \"\";\n\ntypedef pair<int, int> Pair;\nvector<Pair> goals;\n\nint main() {\n  cin >> s;\n  cin >> gx >> gy;\n  goals.push_back(Pair(gx, gy));\n\n  bool to_x = true;\n  REP(i, s.length()) {\n    if (s[i] == 'F') {\n      if (to_x) { ++x; } else { ++y; }\n    } else {\n      if (to_x) {\n        REP(j, goals.size()) {\n          if (goals[j].second < y) {\n            goals[j].second += 2 * (y - goals[j].second);\n          }\n        }\n        int gs = goals.size();\n        REP(j, gs) {\n          goals.push_back(Pair(\n            goals[j].first,\n            y + 2*(goals[i].second - y)));\n        }\n        to_x = false;\n      } else {\n        REP(j, goals.size()) {\n          if (goals[j].first < x) {\n            goals[j].first += 2 * (x - goals[j].first);\n          }\n        }\n        int gs = goals.size();\n        REP(j, gs) {\n          goals.push_back(Pair(\n            x + 2*(goals[j].first - x),\n            goals[j].second));\n        }\n        to_x = true;\n      }\n    }\n  }\n\n  bool f = false;\n  REP(i, goals.size()) {\n    if (x == goals[i].first && y == goals[i].second) {\n      f = true;\n      break;\n    }\n  }\n  if (f) {\n    ans = \"Yes\";\n  } else {\n    ans = \"No\";\n  }\n\n  cout << ans << endl;\n  return 0;\n}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nA robot is put at the origin in a two-dimensional plane.\nInitially, the robot is facing in the positive x-axis direction.\n\nThis robot will be given an instruction sequence s.\ns consists of the following two kinds of letters, and will be executed in order from front to back.\n\nF : Move in the current direction by distance 1.\n\nT : Turn 90 degrees, either clockwise or counterclockwise.\n\nThe objective of the robot is to be at coordinates (x, y) after all the instructions are executed.\nDetermine whether this objective is achievable.\n\nConstraints\n\ns consists of F and T.\n\n1 \\leq |s| \\leq 8 000\n\nx and y are integers.\n\n|x|, |y| \\leq |s|\n\nInput\n\nInput is given from Standard Input in the following format:\n\ns\nx y\n\nOutput\n\nIf the objective is achievable, print Yes; if it is not, print No.\n\nSample Input 1\n\nFTFFTFFF\n4 2\n\nSample Output 1\n\nYes\n\nThe objective can be achieved by, for example, turning counterclockwise in the first T and turning clockwise in the second T.\n\nSample Input 2\n\nFTFFTFFF\n-2 -2\n\nSample Output 2\n\nYes\n\nThe objective can be achieved by, for example, turning clockwise in the first T and turning clockwise in the second T.\n\nSample Input 3\n\nFF\n1 0\n\nSample Output 3\n\nNo\n\nSample Input 4\n\nTF\n1 0\n\nSample Output 4\n\nNo\n\nSample Input 5\n\nFFTTFF\n0 0\n\nSample Output 5\n\nYes\n\nThe objective can be achieved by, for example, turning counterclockwise in the first T and turning counterclockwise in the second T.\n\nSample Input 6\n\nTTTT\n1 0\n\nSample Output 6\n\nNo", "sample_input": "FTFFTFFF\n4 2\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p03488", "source_text": "Score : 500 points\n\nProblem Statement\n\nA robot is put at the origin in a two-dimensional plane.\nInitially, the robot is facing in the positive x-axis direction.\n\nThis robot will be given an instruction sequence s.\ns consists of the following two kinds of letters, and will be executed in order from front to back.\n\nF : Move in the current direction by distance 1.\n\nT : Turn 90 degrees, either clockwise or counterclockwise.\n\nThe objective of the robot is to be at coordinates (x, y) after all the instructions are executed.\nDetermine whether this objective is achievable.\n\nConstraints\n\ns consists of F and T.\n\n1 \\leq |s| \\leq 8 000\n\nx and y are integers.\n\n|x|, |y| \\leq |s|\n\nInput\n\nInput is given from Standard Input in the following format:\n\ns\nx y\n\nOutput\n\nIf the objective is achievable, print Yes; if it is not, print No.\n\nSample Input 1\n\nFTFFTFFF\n4 2\n\nSample Output 1\n\nYes\n\nThe objective can be achieved by, for example, turning counterclockwise in the first T and turning clockwise in the second T.\n\nSample Input 2\n\nFTFFTFFF\n-2 -2\n\nSample Output 2\n\nYes\n\nThe objective can be achieved by, for example, turning clockwise in the first T and turning clockwise in the second T.\n\nSample Input 3\n\nFF\n1 0\n\nSample Output 3\n\nNo\n\nSample Input 4\n\nTF\n1 0\n\nSample Output 4\n\nNo\n\nSample Input 5\n\nFFTTFF\n0 0\n\nSample Output 5\n\nYes\n\nThe objective can be achieved by, for example, turning counterclockwise in the first T and turning counterclockwise in the second T.\n\nSample Input 6\n\nTTTT\n1 0\n\nSample Output 6\n\nNo", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1519, "cpu_time_ms": 2107, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s930059351", "group_id": "codeNet:p03490", "input_text": "#include <algorithm>\n#include <iostream>\n#include <cstring>\n#include <cstdlib>\n#include <utility>\n#include <bitset>\n#include <cstdio>\n#include <vector>\n#include <queue>\n#include <stack>\n#include <set>\n#include <map>\n#define mp make_pair\n#define pb push_back\n#define off 10000\nusing namespace std; \ntypedef long long ll; \nbitset<off * 2 + 5> xx, yy; \nchar str[off + 5]; \nint main()\n{\n\t// freopen(\"ARC087-D.in\", \"r\", stdin); \n\tscanf(\"%s\", str); \n\tint n = strlen(str), cnt = 0; \n\tbool f = false, fst = true;\n\txx.set(off); \n\tyy.set(off); \n\tfor (int i = 0; i <= n; i++)\n\t{\n\t\tif (str[i] == 'F')\n\t\t\tcnt++; \n\t\telse\n\t\t{\n\t\t\tauto &t = f ? yy : xx; \n\t\t\tif (fst)\n\t\t\t\tt <<= cnt; \n\t\t\telse\n\t\t\t\tt = (t << cnt) | (t >> cnt); \n\t\t\tfst = false; \n\t\t\tcnt = 0; \n\t\t\tf ^= 1; \n\t\t}\n\t}\n\tint x, y; \n\tscanf(\"%d%d\", &x, &y); \n\tif (x < -off || y < -off || x > off || y > off)\n\t\tputs(\"No\"); \n\telse\n\t\tputs(xx.test(x + off) && yy.test(y + off) ? \"Yes\" : \"No\"); \n\treturn 0; \n}\n", "language": "C++", "metadata": {"date": 1513476643, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03490.html", "problem_id": "p03490", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03490/input.txt", "sample_output_relpath": "derived/input_output/data/p03490/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03490/C++/s930059351.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s930059351", "user_id": "u607811599"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <algorithm>\n#include <iostream>\n#include <cstring>\n#include <cstdlib>\n#include <utility>\n#include <bitset>\n#include <cstdio>\n#include <vector>\n#include <queue>\n#include <stack>\n#include <set>\n#include <map>\n#define mp make_pair\n#define pb push_back\n#define off 10000\nusing namespace std; \ntypedef long long ll; \nbitset<off * 2 + 5> xx, yy; \nchar str[off + 5]; \nint main()\n{\n\t// freopen(\"ARC087-D.in\", \"r\", stdin); \n\tscanf(\"%s\", str); \n\tint n = strlen(str), cnt = 0; \n\tbool f = false, fst = true;\n\txx.set(off); \n\tyy.set(off); \n\tfor (int i = 0; i <= n; i++)\n\t{\n\t\tif (str[i] == 'F')\n\t\t\tcnt++; \n\t\telse\n\t\t{\n\t\t\tauto &t = f ? yy : xx; \n\t\t\tif (fst)\n\t\t\t\tt <<= cnt; \n\t\t\telse\n\t\t\t\tt = (t << cnt) | (t >> cnt); \n\t\t\tfst = false; \n\t\t\tcnt = 0; \n\t\t\tf ^= 1; \n\t\t}\n\t}\n\tint x, y; \n\tscanf(\"%d%d\", &x, &y); \n\tif (x < -off || y < -off || x > off || y > off)\n\t\tputs(\"No\"); \n\telse\n\t\tputs(xx.test(x + off) && yy.test(y + off) ? \"Yes\" : \"No\"); \n\treturn 0; \n}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nA robot is put at the origin in a two-dimensional plane.\nInitially, the robot is facing in the positive x-axis direction.\n\nThis robot will be given an instruction sequence s.\ns consists of the following two kinds of letters, and will be executed in order from front to back.\n\nF : Move in the current direction by distance 1.\n\nT : Turn 90 degrees, either clockwise or counterclockwise.\n\nThe objective of the robot is to be at coordinates (x, y) after all the instructions are executed.\nDetermine whether this objective is achievable.\n\nConstraints\n\ns consists of F and T.\n\n1 \\leq |s| \\leq 8 000\n\nx and y are integers.\n\n|x|, |y| \\leq |s|\n\nInput\n\nInput is given from Standard Input in the following format:\n\ns\nx y\n\nOutput\n\nIf the objective is achievable, print Yes; if it is not, print No.\n\nSample Input 1\n\nFTFFTFFF\n4 2\n\nSample Output 1\n\nYes\n\nThe objective can be achieved by, for example, turning counterclockwise in the first T and turning clockwise in the second T.\n\nSample Input 2\n\nFTFFTFFF\n-2 -2\n\nSample Output 2\n\nYes\n\nThe objective can be achieved by, for example, turning clockwise in the first T and turning clockwise in the second T.\n\nSample Input 3\n\nFF\n1 0\n\nSample Output 3\n\nNo\n\nSample Input 4\n\nTF\n1 0\n\nSample Output 4\n\nNo\n\nSample Input 5\n\nFFTTFF\n0 0\n\nSample Output 5\n\nYes\n\nThe objective can be achieved by, for example, turning counterclockwise in the first T and turning counterclockwise in the second T.\n\nSample Input 6\n\nTTTT\n1 0\n\nSample Output 6\n\nNo", "sample_input": "FTFFTFFF\n4 2\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p03490", "source_text": "Score : 500 points\n\nProblem Statement\n\nA robot is put at the origin in a two-dimensional plane.\nInitially, the robot is facing in the positive x-axis direction.\n\nThis robot will be given an instruction sequence s.\ns consists of the following two kinds of letters, and will be executed in order from front to back.\n\nF : Move in the current direction by distance 1.\n\nT : Turn 90 degrees, either clockwise or counterclockwise.\n\nThe objective of the robot is to be at coordinates (x, y) after all the instructions are executed.\nDetermine whether this objective is achievable.\n\nConstraints\n\ns consists of F and T.\n\n1 \\leq |s| \\leq 8 000\n\nx and y are integers.\n\n|x|, |y| \\leq |s|\n\nInput\n\nInput is given from Standard Input in the following format:\n\ns\nx y\n\nOutput\n\nIf the objective is achievable, print Yes; if it is not, print No.\n\nSample Input 1\n\nFTFFTFFF\n4 2\n\nSample Output 1\n\nYes\n\nThe objective can be achieved by, for example, turning counterclockwise in the first T and turning clockwise in the second T.\n\nSample Input 2\n\nFTFFTFFF\n-2 -2\n\nSample Output 2\n\nYes\n\nThe objective can be achieved by, for example, turning clockwise in the first T and turning clockwise in the second T.\n\nSample Input 3\n\nFF\n1 0\n\nSample Output 3\n\nNo\n\nSample Input 4\n\nTF\n1 0\n\nSample Output 4\n\nNo\n\nSample Input 5\n\nFFTTFF\n0 0\n\nSample Output 5\n\nYes\n\nThe objective can be achieved by, for example, turning counterclockwise in the first T and turning counterclockwise in the second T.\n\nSample Input 6\n\nTTTT\n1 0\n\nSample Output 6\n\nNo", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 940, "cpu_time_ms": 7, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s954634129", "group_id": "codeNet:p03494", "input_text": "#include <iostream>\nusing namespace std;\nint main(void){\n    // Your code here!\n    int N,cnt,B;\n    cnt = 0;\n    B = 0;\n    cin >> N;\n    int A[N];\n    cin >> A[N];\n    \n    for (int i = 0; i < N; i++){\n    B = B + A[i];\n    }\n    while (B%2 == 0){\n        cnt = cnt++;\n        B/=2;\n    }\n        \n    \n    \n    cout << cnt << endl;\n}", "language": "C++", "metadata": {"date": 1579815041, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03494.html", "problem_id": "p03494", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03494/input.txt", "sample_output_relpath": "derived/input_output/data/p03494/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03494/C++/s954634129.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s954634129", "user_id": "u856606883"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <iostream>\nusing namespace std;\nint main(void){\n    // Your code here!\n    int N,cnt,B;\n    cnt = 0;\n    B = 0;\n    cin >> N;\n    int A[N];\n    cin >> A[N];\n    \n    for (int i = 0; i < N; i++){\n    B = B + A[i];\n    }\n    while (B%2 == 0){\n        cnt = cnt++;\n        B/=2;\n    }\n        \n    \n    \n    cout << cnt << endl;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nThere are N positive integers written on a blackboard: A_1, ..., A_N.\n\nSnuke can perform the following operation when all integers on the blackboard are even:\n\nReplace each integer X on the blackboard by X divided by 2.\n\nFind the maximum possible number of operations that Snuke can perform.\n\nConstraints\n\n1 \\leq N \\leq 200\n\n1 \\leq A_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the maximum possible number of operations that Snuke can perform.\n\nSample Input 1\n\n3\n8 12 40\n\nSample Output 1\n\n2\n\nInitially, [8, 12, 40] are written on the blackboard.\nSince all those integers are even, Snuke can perform the operation.\n\nAfter the operation is performed once, [4, 6, 20] are written on the blackboard.\nSince all those integers are again even, he can perform the operation.\n\nAfter the operation is performed twice, [2, 3, 10] are written on the blackboard.\nNow, there is an odd number 3 on the blackboard, so he cannot perform the operation any more.\n\nThus, Snuke can perform the operation at most twice.\n\nSample Input 2\n\n4\n5 6 8 10\n\nSample Output 2\n\n0\n\nSince there is an odd number 5 on the blackboard already in the beginning, Snuke cannot perform the operation at all.\n\nSample Input 3\n\n6\n382253568 723152896 37802240 379425024 404894720 471526144\n\nSample Output 3\n\n8", "sample_input": "3\n8 12 40\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03494", "source_text": "Score : 200 points\n\nProblem Statement\n\nThere are N positive integers written on a blackboard: A_1, ..., A_N.\n\nSnuke can perform the following operation when all integers on the blackboard are even:\n\nReplace each integer X on the blackboard by X divided by 2.\n\nFind the maximum possible number of operations that Snuke can perform.\n\nConstraints\n\n1 \\leq N \\leq 200\n\n1 \\leq A_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the maximum possible number of operations that Snuke can perform.\n\nSample Input 1\n\n3\n8 12 40\n\nSample Output 1\n\n2\n\nInitially, [8, 12, 40] are written on the blackboard.\nSince all those integers are even, Snuke can perform the operation.\n\nAfter the operation is performed once, [4, 6, 20] are written on the blackboard.\nSince all those integers are again even, he can perform the operation.\n\nAfter the operation is performed twice, [2, 3, 10] are written on the blackboard.\nNow, there is an odd number 3 on the blackboard, so he cannot perform the operation any more.\n\nThus, Snuke can perform the operation at most twice.\n\nSample Input 2\n\n4\n5 6 8 10\n\nSample Output 2\n\n0\n\nSince there is an odd number 5 on the blackboard already in the beginning, Snuke cannot perform the operation at all.\n\nSample Input 3\n\n6\n382253568 723152896 37802240 379425024 404894720 471526144\n\nSample Output 3\n\n8", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 336, "cpu_time_ms": 2103, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s350518668", "group_id": "codeNet:p03498", "input_text": "//include\n//------------------------------------------\n#include <vector>\n#include <list>\n#include <map>\n#include <set>\n#include <queue>\n#include <deque>\n#include <stack>\n#include <bitset>\n#include <algorithm>\n#include <functional>\n#include <numeric>\n#include <utility>\n#include <sstream>\n#include <iostream>\n#include <iomanip>\n#include <cstdio>\n#include <cmath>\n#include <cstdlib>\n#include <cctype>\n#include <string>\n#include <cstring>\n#include <ctime>\n\nusing namespace std;\n\n//conversion\n//------------------------------------------\ninline int toInt(string s) {int v; istringstream sin(s);sin>>v;return v;}\ntemplate<class T> inline string toString(T x) {ostringstream sout;sout<<x;return sout.str();}\n\n//math\n//-------------------------------------------\ntemplate<class T> inline T sqr(T x) {return x*x;}\n\n//typedef\n//------------------------------------------\ntypedef vector<int> VI;\ntypedef vector<VI> VVI;\ntypedef vector<string> VS;\ntypedef pair<int, int> PII;\ntypedef long long LL;\n\n//container util\n//------------------------------------------\n#define ALL(a)  (a).begin(),(a).end()\n#define RALL(a) (a).rbegin(), (a).rend()\n#define PB push_back\n#define MP make_pair\n#define SZ(a) int((a).size())\n#define EACH(i,c) for(typeof((c).begin()) i=(c).begin(); i!=(c).end(); ++i)\n#define EXIST(s,e) ((s).find(e)!=(s).end())\n#define SORT(c) sort((c).begin(),(c).end())\n \n//repetition\n//------------------------------------------\n#define FOR(i,a,b) for(int i=(a);i<(b);++i)\n#define REP(i,n)  FOR(i,0,n)\n\n//constant\n//--------------------------------------------\nconst double EPS = 1e-10;\nconst double PI  = acos(-1.0);\n\n//clear memory\n#define CLR(a) memset((a), 0 ,sizeof(a))\n\n//debug\n#define dump(x)  cerr << #x << \" = \" << (x) << endl;\n#define debug(x) cerr << #x << \" = \" << (x) << \" (L\" << __LINE__ << \")\" << \" \" << __FILE__ << endl;\n\n\nint main(){\n    int N,tar;\n    tar = 0;\n    cin >> N;\n    int Nind = N-1;\n    vector< pair<int,int> > seq(N, make_pair(0,0) );\n    int count = 0;\n    EACH(iter,seq){\n        int val;\n        cin >> val;\n        *iter = make_pair(val, count);\n        count++;\n    }\n   int delta;\n\n    queue< pair<int, int> > q;\n    vector< pair<int,int> >  ord = seq;\n    while(tar != N){\n        delta = seq[tar+1].first - seq[tar].first;\n        \n        if( delta >= 0 ){\n            tar++;            \n            continue;\n        }else{\n            ord = seq;\n            SORT(ord);\n            auto iter = lower_bound( ALL(ord), make_pair(-delta,-1) );\n            if( iter == ord.end() ) iter--; \n            seq[tar+1].first += iter->first ;                 \n            q.push( make_pair( iter->second + 1  ,(tar+1)+1 ) ) ;\n                }\n    }\n    \n    cout << q.size() << endl;\n    while( !q.empty() ){\n        auto f = q.front().first;\n        auto s = q.front().second;\n        cout << f << \" \" << s << endl;\n        q.pop();\n    }\n}\n\n\n", "language": "C++", "metadata": {"date": 1513442964, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03498.html", "problem_id": "p03498", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03498/input.txt", "sample_output_relpath": "derived/input_output/data/p03498/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03498/C++/s350518668.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s350518668", "user_id": "u346215801"}, "prompt_components": {"gold_output": "2\n2 3\n3 3\n", "input_to_evaluate": "//include\n//------------------------------------------\n#include <vector>\n#include <list>\n#include <map>\n#include <set>\n#include <queue>\n#include <deque>\n#include <stack>\n#include <bitset>\n#include <algorithm>\n#include <functional>\n#include <numeric>\n#include <utility>\n#include <sstream>\n#include <iostream>\n#include <iomanip>\n#include <cstdio>\n#include <cmath>\n#include <cstdlib>\n#include <cctype>\n#include <string>\n#include <cstring>\n#include <ctime>\n\nusing namespace std;\n\n//conversion\n//------------------------------------------\ninline int toInt(string s) {int v; istringstream sin(s);sin>>v;return v;}\ntemplate<class T> inline string toString(T x) {ostringstream sout;sout<<x;return sout.str();}\n\n//math\n//-------------------------------------------\ntemplate<class T> inline T sqr(T x) {return x*x;}\n\n//typedef\n//------------------------------------------\ntypedef vector<int> VI;\ntypedef vector<VI> VVI;\ntypedef vector<string> VS;\ntypedef pair<int, int> PII;\ntypedef long long LL;\n\n//container util\n//------------------------------------------\n#define ALL(a)  (a).begin(),(a).end()\n#define RALL(a) (a).rbegin(), (a).rend()\n#define PB push_back\n#define MP make_pair\n#define SZ(a) int((a).size())\n#define EACH(i,c) for(typeof((c).begin()) i=(c).begin(); i!=(c).end(); ++i)\n#define EXIST(s,e) ((s).find(e)!=(s).end())\n#define SORT(c) sort((c).begin(),(c).end())\n \n//repetition\n//------------------------------------------\n#define FOR(i,a,b) for(int i=(a);i<(b);++i)\n#define REP(i,n)  FOR(i,0,n)\n\n//constant\n//--------------------------------------------\nconst double EPS = 1e-10;\nconst double PI  = acos(-1.0);\n\n//clear memory\n#define CLR(a) memset((a), 0 ,sizeof(a))\n\n//debug\n#define dump(x)  cerr << #x << \" = \" << (x) << endl;\n#define debug(x) cerr << #x << \" = \" << (x) << \" (L\" << __LINE__ << \")\" << \" \" << __FILE__ << endl;\n\n\nint main(){\n    int N,tar;\n    tar = 0;\n    cin >> N;\n    int Nind = N-1;\n    vector< pair<int,int> > seq(N, make_pair(0,0) );\n    int count = 0;\n    EACH(iter,seq){\n        int val;\n        cin >> val;\n        *iter = make_pair(val, count);\n        count++;\n    }\n   int delta;\n\n    queue< pair<int, int> > q;\n    vector< pair<int,int> >  ord = seq;\n    while(tar != N){\n        delta = seq[tar+1].first - seq[tar].first;\n        \n        if( delta >= 0 ){\n            tar++;            \n            continue;\n        }else{\n            ord = seq;\n            SORT(ord);\n            auto iter = lower_bound( ALL(ord), make_pair(-delta,-1) );\n            if( iter == ord.end() ) iter--; \n            seq[tar+1].first += iter->first ;                 \n            q.push( make_pair( iter->second + 1  ,(tar+1)+1 ) ) ;\n                }\n    }\n    \n    cout << q.size() << endl;\n    while( !q.empty() ){\n        auto f = q.front().first;\n        auto s = q.front().second;\n        cout << f << \" \" << s << endl;\n        q.pop();\n    }\n}\n\n\n", "problem_context": "Score : 600 points\n\nProblem Statement\n\nSnuke has an integer sequence, a, of length N. The i-th element of a (1-indexed) is a_{i}.\n\nHe can perform the following operation any number of times:\n\nOperation: Choose integers x and y between 1 and N (inclusive), and add a_x to a_y.\n\nHe would like to perform this operation between 0 and 2N times (inclusive) so that a satisfies the condition below. Show one such sequence of operations.\nIt can be proved that such a sequence of operations always exists under the constraints in this problem.\n\nCondition: a_1 \\leq a_2 \\leq ... \\leq a_{N}\n\nConstraints\n\n2 \\leq N \\leq 50\n\n-10^{6} \\leq a_i \\leq 10^{6}\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_{N}\n\nOutput\n\nLet m be the number of operations in your solution. In the first line, print m.\nIn the i-th of the subsequent m lines, print the numbers x and y chosen in the i-th operation, with a space in between.\nThe output will be considered correct if m is between 0 and 2N (inclusive) and a satisfies the condition after the m operations.\n\nSample Input 1\n\n3\n-2 5 -1\n\nSample Output 1\n\n2\n2 3\n3 3\n\nAfter the first operation, a = (-2,5,4).\n\nAfter the second operation, a = (-2,5,8), and the condition is now satisfied.\n\nSample Input 2\n\n2\n-1 -3\n\nSample Output 2\n\n1\n2 1\n\nAfter the first operation, a = (-4,-3) and the condition is now satisfied.\n\nSample Input 3\n\n5\n0 0 0 0 0\n\nSample Output 3\n\n0\n\nThe condition is satisfied already in the beginning.", "sample_input": "3\n-2 5 -1\n"}, "reference_outputs": ["2\n2 3\n3 3\n"], "source_document_id": "p03498", "source_text": "Score : 600 points\n\nProblem Statement\n\nSnuke has an integer sequence, a, of length N. The i-th element of a (1-indexed) is a_{i}.\n\nHe can perform the following operation any number of times:\n\nOperation: Choose integers x and y between 1 and N (inclusive), and add a_x to a_y.\n\nHe would like to perform this operation between 0 and 2N times (inclusive) so that a satisfies the condition below. Show one such sequence of operations.\nIt can be proved that such a sequence of operations always exists under the constraints in this problem.\n\nCondition: a_1 \\leq a_2 \\leq ... \\leq a_{N}\n\nConstraints\n\n2 \\leq N \\leq 50\n\n-10^{6} \\leq a_i \\leq 10^{6}\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_{N}\n\nOutput\n\nLet m be the number of operations in your solution. In the first line, print m.\nIn the i-th of the subsequent m lines, print the numbers x and y chosen in the i-th operation, with a space in between.\nThe output will be considered correct if m is between 0 and 2N (inclusive) and a satisfies the condition after the m operations.\n\nSample Input 1\n\n3\n-2 5 -1\n\nSample Output 1\n\n2\n2 3\n3 3\n\nAfter the first operation, a = (-2,5,4).\n\nAfter the second operation, a = (-2,5,8), and the condition is now satisfied.\n\nSample Input 2\n\n2\n-1 -3\n\nSample Output 2\n\n1\n2 1\n\nAfter the first operation, a = (-4,-3) and the condition is now satisfied.\n\nSample Input 3\n\n5\n0 0 0 0 0\n\nSample Output 3\n\n0\n\nThe condition is satisfied already in the beginning.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2871, "cpu_time_ms": 2147, "memory_kb": 731040}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s903663605", "group_id": "codeNet:p03502", "input_text": "#include<bits/stdc++.h>\nconstexpr long long INFL = 1LL << 60;\nconstexpr int INF = 1e9;\n\nusing namespace std;\n\ntypedef long long ll;\n\nint main()\n{\n    string N;\n    cin >> N;\n    int f = 0;\n    for(auto c : N)\n        f += c - '0';\n    istringstream iss(N);\n    int x;\n    iss >> x;\n    if(x % f == 0) cout << \"Yes\" << endl;\n    else cout << \"No\" << endl;\n\n    return 0;\n}", "language": "C++", "metadata": {"date": 1555804858, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03502.html", "problem_id": "p03502", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03502/input.txt", "sample_output_relpath": "derived/input_output/data/p03502/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03502/C++/s903663605.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s903663605", "user_id": "u784751818"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include<bits/stdc++.h>\nconstexpr long long INFL = 1LL << 60;\nconstexpr int INF = 1e9;\n\nusing namespace std;\n\ntypedef long long ll;\n\nint main()\n{\n    string N;\n    cin >> N;\n    int f = 0;\n    for(auto c : N)\n        f += c - '0';\n    istringstream iss(N);\n    int x;\n    iss >> x;\n    if(x % f == 0) cout << \"Yes\" << endl;\n    else cout << \"No\" << endl;\n\n    return 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nAn integer X is called a Harshad number if X is divisible by f(X), where f(X) is the sum of the digits in X when written in base 10.\n\nGiven an integer N, determine whether it is a Harshad number.\n\nConstraints\n\n1?N?10^8\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint Yes if N is a Harshad number; print No otherwise.\n\nSample Input 1\n\n12\n\nSample Output 1\n\nYes\n\nf(12)=1+2=3. Since 12 is divisible by 3, 12 is a Harshad number.\n\nSample Input 2\n\n57\n\nSample Output 2\n\nNo\n\nf(57)=5+7=12. Since 57 is not divisible by 12, 12 is not a Harshad number.\n\nSample Input 3\n\n148\n\nSample Output 3\n\nNo", "sample_input": "12\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p03502", "source_text": "Score : 200 points\n\nProblem Statement\n\nAn integer X is called a Harshad number if X is divisible by f(X), where f(X) is the sum of the digits in X when written in base 10.\n\nGiven an integer N, determine whether it is a Harshad number.\n\nConstraints\n\n1?N?10^8\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint Yes if N is a Harshad number; print No otherwise.\n\nSample Input 1\n\n12\n\nSample Output 1\n\nYes\n\nf(12)=1+2=3. Since 12 is divisible by 3, 12 is a Harshad number.\n\nSample Input 2\n\n57\n\nSample Output 2\n\nNo\n\nf(57)=5+7=12. Since 57 is not divisible by 12, 12 is not a Harshad number.\n\nSample Input 3\n\n148\n\nSample Output 3\n\nNo", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 371, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s344236012", "group_id": "codeNet:p03502", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n  int N, n, f=0;\n  cin >> N;\n  n = N;\n  while (n>0)f+=n%10,n/=10;\n  if (N%f==0)cout << \"Yes\" << endl;\n  else cout << \"No\" << endl;\n}", "language": "C++", "metadata": {"date": 1526149880, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03502.html", "problem_id": "p03502", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03502/input.txt", "sample_output_relpath": "derived/input_output/data/p03502/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03502/C++/s344236012.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s344236012", "user_id": "u732491975"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n  int N, n, f=0;\n  cin >> N;\n  n = N;\n  while (n>0)f+=n%10,n/=10;\n  if (N%f==0)cout << \"Yes\" << endl;\n  else cout << \"No\" << endl;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nAn integer X is called a Harshad number if X is divisible by f(X), where f(X) is the sum of the digits in X when written in base 10.\n\nGiven an integer N, determine whether it is a Harshad number.\n\nConstraints\n\n1?N?10^8\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint Yes if N is a Harshad number; print No otherwise.\n\nSample Input 1\n\n12\n\nSample Output 1\n\nYes\n\nf(12)=1+2=3. Since 12 is divisible by 3, 12 is a Harshad number.\n\nSample Input 2\n\n57\n\nSample Output 2\n\nNo\n\nf(57)=5+7=12. Since 57 is not divisible by 12, 12 is not a Harshad number.\n\nSample Input 3\n\n148\n\nSample Output 3\n\nNo", "sample_input": "12\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p03502", "source_text": "Score : 200 points\n\nProblem Statement\n\nAn integer X is called a Harshad number if X is divisible by f(X), where f(X) is the sum of the digits in X when written in base 10.\n\nGiven an integer N, determine whether it is a Harshad number.\n\nConstraints\n\n1?N?10^8\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint Yes if N is a Harshad number; print No otherwise.\n\nSample Input 1\n\n12\n\nSample Output 1\n\nYes\n\nf(12)=1+2=3. Since 12 is divisible by 3, 12 is a Harshad number.\n\nSample Input 2\n\n57\n\nSample Output 2\n\nNo\n\nf(57)=5+7=12. Since 57 is not divisible by 12, 12 is not a Harshad number.\n\nSample Input 3\n\n148\n\nSample Output 3\n\nNo", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 192, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s000482190", "group_id": "codeNet:p03504", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nint main(){\n  ll n,C;cin>>n>>C;\n  ll s[n],t[n],c[n];\n  vector<double>tukeru[31],kesu[31];\n  vector<pair<ll,ll>>v[31];\n  for(ll i=0;i<n;i++){\n    cin>>s[i]>>t[i]>>c[i];\n    v[c[i]].push_back(make_pair(s[i],t[i]));\n  }\n  for(ll i=1;i<31;i++){\n    if(v[i].size()==0)continue;\n    sort(v[i].begin(),v[i].end());\n    tukeru[i].push_back(v[i][0].first-0.5);\n    kesu[i].push_back(v[i][0].second);\n    for(ll j=1;j<v[i].size();j++){\n      ll f=v[i][j].first,s=v[i][j].second;\n      if(f==kesu[i].back()){\n        kesu[i].pop_back();\n      }\n      else{\n        //kesu[i][kesu[i].size()-1]++;\n        tukeru[i].push_back(f-0.5);\n      }\n      kesu[i].push_back(s);\n    }\n    //kesu[i][kesu[i].size()-1]++;\n  }\n  //for(ll i=1;i<=C;i++)for(ll j=0;j<kesu[i].size();j++)cout<<tukeru[i][j]<<endl;\n  ll now=0,ans=0;\n  ll ban[31];\n  //cout<<tukeru[2][0];return 0;\n  fill(ban,ban+31,0);\n  for(double i=0;i<=100001;i+=0.5){\n    for(ll j=1;j<31;j++){\n      if(v[j].size()==0)continue;\n      if(tukeru[j][ban[j]]==i){\n        now++; \n      }\n      if(kesu[j][ban[j]]==i){\n        now--;\n        ban[j]++;\n      }\n      //cout<<j<<\" \"<<ban[j]<<endl;\n    }\n   //if(i<=100)cout<<now<<endl;\n      ans=max(now,ans);\n  }\n  ll d[100010];\n  fill(d,d+100010,0);\n  for(ll i=0;i<n;i++){\n    \n    d[s[i]]++;\n    d[t[i]+1]--;\n  }\n  ll noww=0,anss=0;\n  for(ll i=1;i<=100000;i++){\n    noww+=d[i];\n    anss=max(anss,noww);\n  }\n  cout<<min(ans,anss);\n}", "language": "C++", "metadata": {"date": 1544571062, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03504.html", "problem_id": "p03504", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03504/input.txt", "sample_output_relpath": "derived/input_output/data/p03504/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03504/C++/s000482190.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s000482190", "user_id": "u357265888"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nint main(){\n  ll n,C;cin>>n>>C;\n  ll s[n],t[n],c[n];\n  vector<double>tukeru[31],kesu[31];\n  vector<pair<ll,ll>>v[31];\n  for(ll i=0;i<n;i++){\n    cin>>s[i]>>t[i]>>c[i];\n    v[c[i]].push_back(make_pair(s[i],t[i]));\n  }\n  for(ll i=1;i<31;i++){\n    if(v[i].size()==0)continue;\n    sort(v[i].begin(),v[i].end());\n    tukeru[i].push_back(v[i][0].first-0.5);\n    kesu[i].push_back(v[i][0].second);\n    for(ll j=1;j<v[i].size();j++){\n      ll f=v[i][j].first,s=v[i][j].second;\n      if(f==kesu[i].back()){\n        kesu[i].pop_back();\n      }\n      else{\n        //kesu[i][kesu[i].size()-1]++;\n        tukeru[i].push_back(f-0.5);\n      }\n      kesu[i].push_back(s);\n    }\n    //kesu[i][kesu[i].size()-1]++;\n  }\n  //for(ll i=1;i<=C;i++)for(ll j=0;j<kesu[i].size();j++)cout<<tukeru[i][j]<<endl;\n  ll now=0,ans=0;\n  ll ban[31];\n  //cout<<tukeru[2][0];return 0;\n  fill(ban,ban+31,0);\n  for(double i=0;i<=100001;i+=0.5){\n    for(ll j=1;j<31;j++){\n      if(v[j].size()==0)continue;\n      if(tukeru[j][ban[j]]==i){\n        now++; \n      }\n      if(kesu[j][ban[j]]==i){\n        now--;\n        ban[j]++;\n      }\n      //cout<<j<<\" \"<<ban[j]<<endl;\n    }\n   //if(i<=100)cout<<now<<endl;\n      ans=max(now,ans);\n  }\n  ll d[100010];\n  fill(d,d+100010,0);\n  for(ll i=0;i<n;i++){\n    \n    d[s[i]]++;\n    d[t[i]+1]--;\n  }\n  ll noww=0,anss=0;\n  for(ll i=1;i<=100000;i++){\n    noww+=d[i];\n    anss=max(anss,noww);\n  }\n  cout<<min(ans,anss);\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nJoisino is planning to record N TV programs with recorders.\n\nThe TV can receive C channels numbered 1 through C.\n\nThe i-th program that she wants to record will be broadcast from time s_i to time t_i (including time s_i but not t_i) on Channel c_i.\n\nHere, there will never be more than one program that are broadcast on the same channel at the same time.\n\nWhen the recorder is recording a channel from time S to time T (including time S but not T), it cannot record other channels from time S-0.5 to time T (including time S-0.5 but not T).\n\nFind the minimum number of recorders required to record the channels so that all the N programs are completely recorded.\n\nConstraints\n\n1≤N≤10^5\n\n1≤C≤30\n\n1≤s_i<t_i≤10^5\n\n1≤c_i≤C\n\nIf c_i=c_j and i≠j, either t_i≤s_j or s_i≥t_j.\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN C\ns_1 t_1 c_1\n:\ns_N t_N c_N\n\nOutput\n\nWhen the minimum required number of recorders is x, print the value of x.\n\nSample Input 1\n\n3 2\n1 7 2\n7 8 1\n8 12 1\n\nSample Output 1\n\n2\n\nTwo recorders can record all the programs, for example, as follows:\n\nWith the first recorder, record Channel 2 from time 1 to time 7. The first program will be recorded. Note that this recorder will be unable to record other channels from time 0.5 to time 7.\n\nWith the second recorder, record Channel 1 from time 7 to time 12. The second and third programs will be recorded. Note that this recorder will be unable to record other channels from time 6.5 to time 12.\n\nSample Input 2\n\n3 4\n1 3 2\n3 4 4\n1 4 3\n\nSample Output 2\n\n3\n\nThere may be a channel where there is no program to record.\n\nSample Input 3\n\n9 4\n56 60 4\n33 37 2\n89 90 3\n32 43 1\n67 68 3\n49 51 3\n31 32 3\n70 71 1\n11 12 3\n\nSample Output 3\n\n2", "sample_input": "3 2\n1 7 2\n7 8 1\n8 12 1\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03504", "source_text": "Score : 400 points\n\nProblem Statement\n\nJoisino is planning to record N TV programs with recorders.\n\nThe TV can receive C channels numbered 1 through C.\n\nThe i-th program that she wants to record will be broadcast from time s_i to time t_i (including time s_i but not t_i) on Channel c_i.\n\nHere, there will never be more than one program that are broadcast on the same channel at the same time.\n\nWhen the recorder is recording a channel from time S to time T (including time S but not T), it cannot record other channels from time S-0.5 to time T (including time S-0.5 but not T).\n\nFind the minimum number of recorders required to record the channels so that all the N programs are completely recorded.\n\nConstraints\n\n1≤N≤10^5\n\n1≤C≤30\n\n1≤s_i<t_i≤10^5\n\n1≤c_i≤C\n\nIf c_i=c_j and i≠j, either t_i≤s_j or s_i≥t_j.\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN C\ns_1 t_1 c_1\n:\ns_N t_N c_N\n\nOutput\n\nWhen the minimum required number of recorders is x, print the value of x.\n\nSample Input 1\n\n3 2\n1 7 2\n7 8 1\n8 12 1\n\nSample Output 1\n\n2\n\nTwo recorders can record all the programs, for example, as follows:\n\nWith the first recorder, record Channel 2 from time 1 to time 7. The first program will be recorded. Note that this recorder will be unable to record other channels from time 0.5 to time 7.\n\nWith the second recorder, record Channel 1 from time 7 to time 12. The second and third programs will be recorded. Note that this recorder will be unable to record other channels from time 6.5 to time 12.\n\nSample Input 2\n\n3 4\n1 3 2\n3 4 4\n1 4 3\n\nSample Output 2\n\n3\n\nThere may be a channel where there is no program to record.\n\nSample Input 3\n\n9 4\n56 60 4\n33 37 2\n89 90 3\n32 43 1\n67 68 3\n49 51 3\n31 32 3\n70 71 1\n11 12 3\n\nSample Output 3\n\n2", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1483, "cpu_time_ms": 127, "memory_kb": 7424}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s720733979", "group_id": "codeNet:p03524", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n  string s;\n  cin >> s;\n  vector<int> c(3);\n  int n=s.size();\n  for(int i=0;i<n;i++){\n    c[s[i]-'a']++;\n  }\n  string ans=\"YES\";\n  for(int i=0;i<3;i++){\n    if(c[0]*c[1]*c[2]!=0&&(n+3-1)/3<c[i]){\n      ans=\"NO\";\n    }\n  }\n  cout << ans << endl;\n}", "language": "C++", "metadata": {"date": 1568343421, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03524.html", "problem_id": "p03524", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03524/input.txt", "sample_output_relpath": "derived/input_output/data/p03524/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03524/C++/s720733979.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s720733979", "user_id": "u244626757"}, "prompt_components": {"gold_output": "YES\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n  string s;\n  cin >> s;\n  vector<int> c(3);\n  int n=s.size();\n  for(int i=0;i<n;i++){\n    c[s[i]-'a']++;\n  }\n  string ans=\"YES\";\n  for(int i=0;i<3;i++){\n    if(c[0]*c[1]*c[2]!=0&&(n+3-1)/3<c[i]){\n      ans=\"NO\";\n    }\n  }\n  cout << ans << endl;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nSnuke has a string S consisting of three kinds of letters: a, b and c.\n\nHe has a phobia for palindromes, and wants to permute the characters in S so that S will not contain a palindrome of length 2 or more as a substring. Determine whether this is possible.\n\nConstraints\n\n1 \\leq |S| \\leq 10^5\n\nS consists of a, b and c.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nIf the objective is achievable, print YES; if it is unachievable, print NO.\n\nSample Input 1\n\nabac\n\nSample Output 1\n\nYES\n\nAs it stands now, S contains a palindrome aba, but we can permute the characters to get acba, for example, that does not contain a palindrome of length 2 or more.\n\nSample Input 2\n\naba\n\nSample Output 2\n\nNO\n\nSample Input 3\n\nbabacccabab\n\nSample Output 3\n\nYES", "sample_input": "abac\n"}, "reference_outputs": ["YES\n"], "source_document_id": "p03524", "source_text": "Score : 400 points\n\nProblem Statement\n\nSnuke has a string S consisting of three kinds of letters: a, b and c.\n\nHe has a phobia for palindromes, and wants to permute the characters in S so that S will not contain a palindrome of length 2 or more as a substring. Determine whether this is possible.\n\nConstraints\n\n1 \\leq |S| \\leq 10^5\n\nS consists of a, b and c.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nIf the objective is achievable, print YES; if it is unachievable, print NO.\n\nSample Input 1\n\nabac\n\nSample Output 1\n\nYES\n\nAs it stands now, S contains a palindrome aba, but we can permute the characters to get acba, for example, that does not contain a palindrome of length 2 or more.\n\nSample Input 2\n\naba\n\nSample Output 2\n\nNO\n\nSample Input 3\n\nbabacccabab\n\nSample Output 3\n\nYES", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 303, "cpu_time_ms": 5, "memory_kb": 512}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s070715579", "group_id": "codeNet:p03543", "input_text": "#include <algorithm>\n#include <cassert>\n#include <cmath>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <functional>\n#include <iostream>\n#include <map>\n#include <queue>\n#include <set>\n#include <string>\n#include <vector>\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair<int, int> P;\n\nconst int dx[4] = {-1, 0, 0, 1};\nconst int dy[4] = {0, -1, 1, 0};\n\n// Self settings\n// clang-format off\n#define MAX_N 100000\n#define REP(i, N) for (int i = 0; i < (int)(N); ++i)\n#define SLN(i,N) (i == N-1 ? \"\\n\" : \" \")\nll fact(ll n) { ll res = 1; for(ll i=2;i<=n;++i) res = res * i; return res;}\nll nCr(ll n, ll r) {return (fact(n)/fact(n-r)*fact(r)) ;}\nll gcd(ll a,ll b){if(b==0)return a;return gcd(b,a%b);}\nll lcm(ll a,ll b){return a/gcd(a,b)*b;}\nconst ll MOD = 1e9+7;\nconst ll INF = 1LL << 60;\nconst int inf = 1 << 31;\n// clang-format on\n\nint N;\n\nint main(void)\n{\n  cin.tie(0);\n  ios::sync_with_stdio(false);\n  cin >> N;\n\n  int m = 0, cnt = 0;\n  int prev = 100;\n  int n = N;\n  while (n > 0) {\n    int cur = n % 10;\n    if (prev == cur) {\n      cnt++;\n    }\n    else {\n      cnt = 1;\n    }\n    m = max(m, cnt);\n    prev = cur;\n    n /= 10;\n  }\n  if (m >= 3) {\n    cout << \"Yes\" << endl;\n  }\n  else {\n    cout << \"No\" << endl;\n  }\n\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1571444308, "filename_ext": "cpp", "original_language": "C++14 (Clang 3.8.0)", "problem_description_relpath": "problem_descriptions/p03543.html", "problem_id": "p03543", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03543/input.txt", "sample_output_relpath": "derived/input_output/data/p03543/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03543/C++/s070715579.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s070715579", "user_id": "u621104964"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <algorithm>\n#include <cassert>\n#include <cmath>\n#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <functional>\n#include <iostream>\n#include <map>\n#include <queue>\n#include <set>\n#include <string>\n#include <vector>\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair<int, int> P;\n\nconst int dx[4] = {-1, 0, 0, 1};\nconst int dy[4] = {0, -1, 1, 0};\n\n// Self settings\n// clang-format off\n#define MAX_N 100000\n#define REP(i, N) for (int i = 0; i < (int)(N); ++i)\n#define SLN(i,N) (i == N-1 ? \"\\n\" : \" \")\nll fact(ll n) { ll res = 1; for(ll i=2;i<=n;++i) res = res * i; return res;}\nll nCr(ll n, ll r) {return (fact(n)/fact(n-r)*fact(r)) ;}\nll gcd(ll a,ll b){if(b==0)return a;return gcd(b,a%b);}\nll lcm(ll a,ll b){return a/gcd(a,b)*b;}\nconst ll MOD = 1e9+7;\nconst ll INF = 1LL << 60;\nconst int inf = 1 << 31;\n// clang-format on\n\nint N;\n\nint main(void)\n{\n  cin.tie(0);\n  ios::sync_with_stdio(false);\n  cin >> N;\n\n  int m = 0, cnt = 0;\n  int prev = 100;\n  int n = N;\n  while (n > 0) {\n    int cur = n % 10;\n    if (prev == cur) {\n      cnt++;\n    }\n    else {\n      cnt = 1;\n    }\n    m = max(m, cnt);\n    prev = cur;\n    n /= 10;\n  }\n  if (m >= 3) {\n    cout << \"Yes\" << endl;\n  }\n  else {\n    cout << \"No\" << endl;\n  }\n\n  return 0;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nWe call a 4-digit integer with three or more consecutive same digits, such as 1118, good.\n\nYou are given a 4-digit integer N. Answer the question: Is N good?\n\nConstraints\n\n1000 ≤ N ≤ 9999\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nIf N is good, print Yes; otherwise, print No.\n\nSample Input 1\n\n1118\n\nSample Output 1\n\nYes\n\nN is good, since it contains three consecutive 1.\n\nSample Input 2\n\n7777\n\nSample Output 2\n\nYes\n\nAn integer is also good when all the digits are the same.\n\nSample Input 3\n\n1234\n\nSample Output 3\n\nNo", "sample_input": "1118\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p03543", "source_text": "Score : 100 points\n\nProblem Statement\n\nWe call a 4-digit integer with three or more consecutive same digits, such as 1118, good.\n\nYou are given a 4-digit integer N. Answer the question: Is N good?\n\nConstraints\n\n1000 ≤ N ≤ 9999\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nIf N is good, print Yes; otherwise, print No.\n\nSample Input 1\n\n1118\n\nSample Output 1\n\nYes\n\nN is good, since it contains three consecutive 1.\n\nSample Input 2\n\n7777\n\nSample Output 2\n\nYes\n\nAn integer is also good when all the digits are the same.\n\nSample Input 3\n\n1234\n\nSample Output 3\n\nNo", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1256, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s894659946", "group_id": "codeNet:p03543", "input_text": "#include <iostream>\n\nusing namespace std;\n\nint main()\n{\n    int a,b,c,w,e,q,t;\n    cin >> a;\n    if(a>=1000 && a<=9999)\n    {\n     w=a%10;\n     q=(a/10)%10;\n     e=(a/100)%10;\n     t=(a/1000)%10;\n     if(w==q && w==e || w==q && w==t || w==e && w==t|| q==e && q==t)\n     {\n         cout << \"Yes\";\n     }\n     else\n        cout << \"No\";\n    }\n        return 0;\n}\n", "language": "C++", "metadata": {"date": 1571196560, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03543.html", "problem_id": "p03543", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03543/input.txt", "sample_output_relpath": "derived/input_output/data/p03543/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03543/C++/s894659946.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s894659946", "user_id": "u143782439"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <iostream>\n\nusing namespace std;\n\nint main()\n{\n    int a,b,c,w,e,q,t;\n    cin >> a;\n    if(a>=1000 && a<=9999)\n    {\n     w=a%10;\n     q=(a/10)%10;\n     e=(a/100)%10;\n     t=(a/1000)%10;\n     if(w==q && w==e || w==q && w==t || w==e && w==t|| q==e && q==t)\n     {\n         cout << \"Yes\";\n     }\n     else\n        cout << \"No\";\n    }\n        return 0;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nWe call a 4-digit integer with three or more consecutive same digits, such as 1118, good.\n\nYou are given a 4-digit integer N. Answer the question: Is N good?\n\nConstraints\n\n1000 ≤ N ≤ 9999\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nIf N is good, print Yes; otherwise, print No.\n\nSample Input 1\n\n1118\n\nSample Output 1\n\nYes\n\nN is good, since it contains three consecutive 1.\n\nSample Input 2\n\n7777\n\nSample Output 2\n\nYes\n\nAn integer is also good when all the digits are the same.\n\nSample Input 3\n\n1234\n\nSample Output 3\n\nNo", "sample_input": "1118\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p03543", "source_text": "Score : 100 points\n\nProblem Statement\n\nWe call a 4-digit integer with three or more consecutive same digits, such as 1118, good.\n\nYou are given a 4-digit integer N. Answer the question: Is N good?\n\nConstraints\n\n1000 ≤ N ≤ 9999\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nIf N is good, print Yes; otherwise, print No.\n\nSample Input 1\n\n1118\n\nSample Output 1\n\nYes\n\nN is good, since it contains three consecutive 1.\n\nSample Input 2\n\n7777\n\nSample Output 2\n\nYes\n\nAn integer is also good when all the digits are the same.\n\nSample Input 3\n\n1234\n\nSample Output 3\n\nNo", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 361, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s396004429", "group_id": "codeNet:p03543", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n  int n, a, b, c, d;\n  cin >> n;\n  a = n/1000;\n  n -= a*1000;\n  b = n/100;\n  n -= b*100;\n  c = n/10;\n  n -= c*10;\n  d = n;\n  if ((a == b && a == c) || (b == c && b == d)) {\n    cout << \"Yes\" << endl;\n  }else{\n    cout << \"No\" << endl;\n  }\n}", "language": "C++", "metadata": {"date": 1559603352, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03543.html", "problem_id": "p03543", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03543/input.txt", "sample_output_relpath": "derived/input_output/data/p03543/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03543/C++/s396004429.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s396004429", "user_id": "u410118019"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n  int n, a, b, c, d;\n  cin >> n;\n  a = n/1000;\n  n -= a*1000;\n  b = n/100;\n  n -= b*100;\n  c = n/10;\n  n -= c*10;\n  d = n;\n  if ((a == b && a == c) || (b == c && b == d)) {\n    cout << \"Yes\" << endl;\n  }else{\n    cout << \"No\" << endl;\n  }\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nWe call a 4-digit integer with three or more consecutive same digits, such as 1118, good.\n\nYou are given a 4-digit integer N. Answer the question: Is N good?\n\nConstraints\n\n1000 ≤ N ≤ 9999\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nIf N is good, print Yes; otherwise, print No.\n\nSample Input 1\n\n1118\n\nSample Output 1\n\nYes\n\nN is good, since it contains three consecutive 1.\n\nSample Input 2\n\n7777\n\nSample Output 2\n\nYes\n\nAn integer is also good when all the digits are the same.\n\nSample Input 3\n\n1234\n\nSample Output 3\n\nNo", "sample_input": "1118\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p03543", "source_text": "Score : 100 points\n\nProblem Statement\n\nWe call a 4-digit integer with three or more consecutive same digits, such as 1118, good.\n\nYou are given a 4-digit integer N. Answer the question: Is N good?\n\nConstraints\n\n1000 ≤ N ≤ 9999\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nIf N is good, print Yes; otherwise, print No.\n\nSample Input 1\n\n1118\n\nSample Output 1\n\nYes\n\nN is good, since it contains three consecutive 1.\n\nSample Input 2\n\n7777\n\nSample Output 2\n\nYes\n\nAn integer is also good when all the digits are the same.\n\nSample Input 3\n\n1234\n\nSample Output 3\n\nNo", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 300, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s278653772", "group_id": "codeNet:p03543", "input_text": "#include<string>\n#include<iostream>\nusing namespace std;\n\nint main() {\n  int N,a,b,c,d;\n  cin >> N;\n  a = N/1000;\n  b = (N/100)-(a*10);\n  c = (N/10)-(N/100*10);\n  d = N-(N/10)*10;\n  if ( a == b && b == c ){\n    cout << \"Yes\" << endl;\n  if ( b == c && c == d ){\n    cout << \"Yes\" << endl;\n  }\n  }\n  \n  else {\n    cout<< \"No\" << endl;\n  }\n \n}\n", "language": "C++", "metadata": {"date": 1559078886, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03543.html", "problem_id": "p03543", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03543/input.txt", "sample_output_relpath": "derived/input_output/data/p03543/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03543/C++/s278653772.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s278653772", "user_id": "u939849667"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include<string>\n#include<iostream>\nusing namespace std;\n\nint main() {\n  int N,a,b,c,d;\n  cin >> N;\n  a = N/1000;\n  b = (N/100)-(a*10);\n  c = (N/10)-(N/100*10);\n  d = N-(N/10)*10;\n  if ( a == b && b == c ){\n    cout << \"Yes\" << endl;\n  if ( b == c && c == d ){\n    cout << \"Yes\" << endl;\n  }\n  }\n  \n  else {\n    cout<< \"No\" << endl;\n  }\n \n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nWe call a 4-digit integer with three or more consecutive same digits, such as 1118, good.\n\nYou are given a 4-digit integer N. Answer the question: Is N good?\n\nConstraints\n\n1000 ≤ N ≤ 9999\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nIf N is good, print Yes; otherwise, print No.\n\nSample Input 1\n\n1118\n\nSample Output 1\n\nYes\n\nN is good, since it contains three consecutive 1.\n\nSample Input 2\n\n7777\n\nSample Output 2\n\nYes\n\nAn integer is also good when all the digits are the same.\n\nSample Input 3\n\n1234\n\nSample Output 3\n\nNo", "sample_input": "1118\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p03543", "source_text": "Score : 100 points\n\nProblem Statement\n\nWe call a 4-digit integer with three or more consecutive same digits, such as 1118, good.\n\nYou are given a 4-digit integer N. Answer the question: Is N good?\n\nConstraints\n\n1000 ≤ N ≤ 9999\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nIf N is good, print Yes; otherwise, print No.\n\nSample Input 1\n\n1118\n\nSample Output 1\n\nYes\n\nN is good, since it contains three consecutive 1.\n\nSample Input 2\n\n7777\n\nSample Output 2\n\nYes\n\nAn integer is also good when all the digits are the same.\n\nSample Input 3\n\n1234\n\nSample Output 3\n\nNo", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 341, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s173766629", "group_id": "codeNet:p03543", "input_text": "#include <iostream>\n#include <algorithm>\n#include <cstring>\n#include <vector>\n#include <numeric>\n#include <cstdlib>\n#include <queue>\n#include <stack>\n#include <climits>\n\nusing namespace std;\n\ntypedef long long ll;\n#define pb push_back\n\n#define rep(i, n) for (int i=0;i<(n);++i)\n#define rep2(i, s, n) for (int i=s;i<(n);++i)\n#define rev(i, n) for (int i=(n);i>0;--i)\n#define INF (1e9+1e9)\n\nint main() {\n    string n; cin >> n;\n\n    auto cnt = 0;\n    int j;\n    rep(i,10) {\n        auto c = count(n.begin(), n.end(), to_string(i)[0]);\n        if (c >= cnt) j = i;\n        cnt = max(cnt, (int)c);\n    }\n    string s = to_string(j);\n    s.append(2,s[0]);\n    if (cnt >= 3 && n.find(s) != string::npos ) cout << \"Yes\" << endl;\n    else cout << \"No\" << endl;\n    \n}", "language": "C++", "metadata": {"date": 1511057817, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03543.html", "problem_id": "p03543", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03543/input.txt", "sample_output_relpath": "derived/input_output/data/p03543/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03543/C++/s173766629.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s173766629", "user_id": "u760761366"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <iostream>\n#include <algorithm>\n#include <cstring>\n#include <vector>\n#include <numeric>\n#include <cstdlib>\n#include <queue>\n#include <stack>\n#include <climits>\n\nusing namespace std;\n\ntypedef long long ll;\n#define pb push_back\n\n#define rep(i, n) for (int i=0;i<(n);++i)\n#define rep2(i, s, n) for (int i=s;i<(n);++i)\n#define rev(i, n) for (int i=(n);i>0;--i)\n#define INF (1e9+1e9)\n\nint main() {\n    string n; cin >> n;\n\n    auto cnt = 0;\n    int j;\n    rep(i,10) {\n        auto c = count(n.begin(), n.end(), to_string(i)[0]);\n        if (c >= cnt) j = i;\n        cnt = max(cnt, (int)c);\n    }\n    string s = to_string(j);\n    s.append(2,s[0]);\n    if (cnt >= 3 && n.find(s) != string::npos ) cout << \"Yes\" << endl;\n    else cout << \"No\" << endl;\n    \n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nWe call a 4-digit integer with three or more consecutive same digits, such as 1118, good.\n\nYou are given a 4-digit integer N. Answer the question: Is N good?\n\nConstraints\n\n1000 ≤ N ≤ 9999\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nIf N is good, print Yes; otherwise, print No.\n\nSample Input 1\n\n1118\n\nSample Output 1\n\nYes\n\nN is good, since it contains three consecutive 1.\n\nSample Input 2\n\n7777\n\nSample Output 2\n\nYes\n\nAn integer is also good when all the digits are the same.\n\nSample Input 3\n\n1234\n\nSample Output 3\n\nNo", "sample_input": "1118\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p03543", "source_text": "Score : 100 points\n\nProblem Statement\n\nWe call a 4-digit integer with three or more consecutive same digits, such as 1118, good.\n\nYou are given a 4-digit integer N. Answer the question: Is N good?\n\nConstraints\n\n1000 ≤ N ≤ 9999\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nIf N is good, print Yes; otherwise, print No.\n\nSample Input 1\n\n1118\n\nSample Output 1\n\nYes\n\nN is good, since it contains three consecutive 1.\n\nSample Input 2\n\n7777\n\nSample Output 2\n\nYes\n\nAn integer is also good when all the digits are the same.\n\nSample Input 3\n\n1234\n\nSample Output 3\n\nNo", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 759, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s706322701", "group_id": "codeNet:p03544", "input_text": "#include<iostream>\n#include<iomanip>\n#include<map>\n#include<set>\n#include<string>\n#include<algorithm>\n#include<cmath>\n#include<vector>\n#include<queue>\n#include<stack>\n#include<cstring>\n#include<sstream>\nusing namespace std;\n \n#define P(p) cout<<(p)<<endl\n#define rep(i,m,n) for(int i = (m); i < (int)(n); i++)\n#define rrep(i,m,n) for(int i=(int)(m); i>=(int)(n); i--)\n#define vsort(v) sort(v.begin(), v.end());\n#define rvsort(v) sort(v.begin(), v.end(),greater<int>());\n#define YES cout<<\"YES\"<< endl\n#define NO cout<<\"NO\"<<endl\n#define Yes cout<<\"Yes\"<<endl\n#define No cout<<\"No\"<<endl  \n#define yes cout<<\"yes\"<<endl\n#define no cout<<\"no\"<<endl\n#define ret return\n#define lb(v,n) lower_bound(v.begin(),v.end(),n)\n#define ub(v,n) upper_bound(v.begin(),v.end(),n)\n#define mae(v) max_element(v.begin(),v.end())\n#define mie(v) min_element(v.begin(),v.end())\n#define INF 0x7FFFFFFF\n#define mod 1000000007\ntypedef long long ll;\n////////////////////////////////////////////////////////////\n\nbool f[8][8];\nint ans = 0;\nint n;\nvoid solve( int now , vector<bool> c , int cnt ){\n\t/*\t\n\tif( cnt == 0 ){\n\t\tans++;\n\t\tret;\n\t}\n\t*/\n\t\n\trep(i,0,n){\n\t\tif( !c[i] && f[now][i] ){\n\t\t\tvector<bool> tmp = c;\n\t\t\ttmp[i] = 1;\n\t\t\tsolve( i , tmp , cnt-1 );\n\t\t}\n\t}\n\n\n}\n\nint main(){\n\tint m;\n\tcin >> n >> m;\n\trep(i,0,m){\n\t\tint a,b;\n\t\tcin >> a >> b;\n\t\ta--; b--;\n\t\tf[a][b] = 1;\n\t\tf[b][a] = 1;\n\t}\n\t\n\tvector<bool> c(n,0);\n\tc[0] = 1;\n\tsolve( 0 , c , n-1);\n\n\tcout << ans << endl;\n\n\tret 0;\n}", "language": "C++", "metadata": {"date": 1527025294, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03544.html", "problem_id": "p03544", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03544/input.txt", "sample_output_relpath": "derived/input_output/data/p03544/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03544/C++/s706322701.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s706322701", "user_id": "u192442087"}, "prompt_components": {"gold_output": "11\n", "input_to_evaluate": "#include<iostream>\n#include<iomanip>\n#include<map>\n#include<set>\n#include<string>\n#include<algorithm>\n#include<cmath>\n#include<vector>\n#include<queue>\n#include<stack>\n#include<cstring>\n#include<sstream>\nusing namespace std;\n \n#define P(p) cout<<(p)<<endl\n#define rep(i,m,n) for(int i = (m); i < (int)(n); i++)\n#define rrep(i,m,n) for(int i=(int)(m); i>=(int)(n); i--)\n#define vsort(v) sort(v.begin(), v.end());\n#define rvsort(v) sort(v.begin(), v.end(),greater<int>());\n#define YES cout<<\"YES\"<< endl\n#define NO cout<<\"NO\"<<endl\n#define Yes cout<<\"Yes\"<<endl\n#define No cout<<\"No\"<<endl  \n#define yes cout<<\"yes\"<<endl\n#define no cout<<\"no\"<<endl\n#define ret return\n#define lb(v,n) lower_bound(v.begin(),v.end(),n)\n#define ub(v,n) upper_bound(v.begin(),v.end(),n)\n#define mae(v) max_element(v.begin(),v.end())\n#define mie(v) min_element(v.begin(),v.end())\n#define INF 0x7FFFFFFF\n#define mod 1000000007\ntypedef long long ll;\n////////////////////////////////////////////////////////////\n\nbool f[8][8];\nint ans = 0;\nint n;\nvoid solve( int now , vector<bool> c , int cnt ){\n\t/*\t\n\tif( cnt == 0 ){\n\t\tans++;\n\t\tret;\n\t}\n\t*/\n\t\n\trep(i,0,n){\n\t\tif( !c[i] && f[now][i] ){\n\t\t\tvector<bool> tmp = c;\n\t\t\ttmp[i] = 1;\n\t\t\tsolve( i , tmp , cnt-1 );\n\t\t}\n\t}\n\n\n}\n\nint main(){\n\tint m;\n\tcin >> n >> m;\n\trep(i,0,m){\n\t\tint a,b;\n\t\tcin >> a >> b;\n\t\ta--; b--;\n\t\tf[a][b] = 1;\n\t\tf[b][a] = 1;\n\t}\n\t\n\tvector<bool> c(n,0);\n\tc[0] = 1;\n\tsolve( 0 , c , n-1);\n\n\tcout << ans << endl;\n\n\tret 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nIt is November 18 now in Japan. By the way, 11 and 18 are adjacent Lucas numbers.\n\nYou are given an integer N. Find the N-th Lucas number.\n\nHere, the i-th Lucas number L_i is defined as follows:\n\nL_0=2\n\nL_1=1\n\nL_i=L_{i-1}+L_{i-2} (i≥2)\n\nConstraints\n\n1≤N≤86\n\nIt is guaranteed that the answer is less than 10^{18}.\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the N-th Lucas number.\n\nSample Input 1\n\n5\n\nSample Output 1\n\n11\n\nL_0=2\n\nL_1=1\n\nL_2=L_0+L_1=3\n\nL_3=L_1+L_2=4\n\nL_4=L_2+L_3=7\n\nL_5=L_3+L_4=11\n\nThus, the 5-th Lucas number is 11.\n\nSample Input 2\n\n86\n\nSample Output 2\n\n939587134549734843", "sample_input": "5\n"}, "reference_outputs": ["11\n"], "source_document_id": "p03544", "source_text": "Score : 200 points\n\nProblem Statement\n\nIt is November 18 now in Japan. By the way, 11 and 18 are adjacent Lucas numbers.\n\nYou are given an integer N. Find the N-th Lucas number.\n\nHere, the i-th Lucas number L_i is defined as follows:\n\nL_0=2\n\nL_1=1\n\nL_i=L_{i-1}+L_{i-2} (i≥2)\n\nConstraints\n\n1≤N≤86\n\nIt is guaranteed that the answer is less than 10^{18}.\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the N-th Lucas number.\n\nSample Input 1\n\n5\n\nSample Output 1\n\n11\n\nL_0=2\n\nL_1=1\n\nL_2=L_0+L_1=3\n\nL_3=L_1+L_2=4\n\nL_4=L_2+L_3=7\n\nL_5=L_3+L_4=11\n\nThus, the 5-th Lucas number is 11.\n\nSample Input 2\n\n86\n\nSample Output 2\n\n939587134549734843", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1451, "cpu_time_ms": 102, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s201596223", "group_id": "codeNet:p03545", "input_text": "#include <iostream>\n#include <string>\n\nusing namespace std;\n\nint main(int argc, char const *argv[])\n{\n    string s;\n    cin >> s;\n    int num[4];\n    for(int i=0; i<4; i++){\n        num[i] = s[i] - '0';\n    }\n\n    for(int i=0; i<8; i++){\n        int sum = num[0];\n        for(int j=0; j<3; j++){\n            if((i>>j)&1) sum += num[j+1];\n            else sum -= num[j+1];\n        }\n        if(sum==7){\n            cout << num[0];\n            for(int j=0; j<3; j++){\n                if((i>>j)&1) cout << '+';\n                else cout << '-';\n                cout << num[j+1];\n            }\n            cout << endl;\n            return 0;\n        }\n    }\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1581275645, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03545.html", "problem_id": "p03545", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03545/input.txt", "sample_output_relpath": "derived/input_output/data/p03545/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03545/C++/s201596223.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s201596223", "user_id": "u445784649"}, "prompt_components": {"gold_output": "1+2+2+2=7\n", "input_to_evaluate": "#include <iostream>\n#include <string>\n\nusing namespace std;\n\nint main(int argc, char const *argv[])\n{\n    string s;\n    cin >> s;\n    int num[4];\n    for(int i=0; i<4; i++){\n        num[i] = s[i] - '0';\n    }\n\n    for(int i=0; i<8; i++){\n        int sum = num[0];\n        for(int j=0; j<3; j++){\n            if((i>>j)&1) sum += num[j+1];\n            else sum -= num[j+1];\n        }\n        if(sum==7){\n            cout << num[0];\n            for(int j=0; j<3; j++){\n                if((i>>j)&1) cout << '+';\n                else cout << '-';\n                cout << num[j+1];\n            }\n            cout << endl;\n            return 0;\n        }\n    }\n    return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nSitting in a station waiting room, Joisino is gazing at her train ticket.\n\nThe ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).\n\nIn the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with + or - so that the formula holds.\n\nThe given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.\n\nConstraints\n\n0≤A,B,C,D≤9\n\nAll input values are integers.\n\nIt is guaranteed that there is a solution.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nABCD\n\nOutput\n\nPrint the formula you made, including the part =7.\n\nUse the signs + and -.\n\nDo not print a space between a digit and a sign.\n\nSample Input 1\n\n1222\n\nSample Output 1\n\n1+2+2+2=7\n\nThis is the only valid solution.\n\nSample Input 2\n\n0290\n\nSample Output 2\n\n0-2+9+0=7\n\n0 - 2 + 9 - 0 = 7 is also a valid solution.\n\nSample Input 3\n\n3242\n\nSample Output 3\n\n3+2+4-2=7", "sample_input": "1222\n"}, "reference_outputs": ["1+2+2+2=7\n"], "source_document_id": "p03545", "source_text": "Score : 300 points\n\nProblem Statement\n\nSitting in a station waiting room, Joisino is gazing at her train ticket.\n\nThe ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).\n\nIn the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with + or - so that the formula holds.\n\nThe given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.\n\nConstraints\n\n0≤A,B,C,D≤9\n\nAll input values are integers.\n\nIt is guaranteed that there is a solution.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nABCD\n\nOutput\n\nPrint the formula you made, including the part =7.\n\nUse the signs + and -.\n\nDo not print a space between a digit and a sign.\n\nSample Input 1\n\n1222\n\nSample Output 1\n\n1+2+2+2=7\n\nThis is the only valid solution.\n\nSample Input 2\n\n0290\n\nSample Output 2\n\n0-2+9+0=7\n\n0 - 2 + 9 - 0 = 7 is also a valid solution.\n\nSample Input 3\n\n3242\n\nSample Output 3\n\n3+2+4-2=7", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 670, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s168365048", "group_id": "codeNet:p03545", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n  int s;\n  cin>>s;\n  int a=s/1000;\n  s -= 1000*a;\n  int b=s/100;\n  s -= 100*b;\n  int c=s/10;\n  s -= 10*c;\n  int d=s;\n  char op1,op2,op3;\n // cout<<a<<b<<c<<d;\n  for(int i=0;i<2;i++){\n    if(i%2==0) op1='+';\n    else op1 ='-';\n    for(int j=0;j<2;j++){\n      if(j%2==0) op2='+';\n      else op2 ='-';\n      for(int k=0;k<2;k++){\n        int sum=a;\n            if(k%2==0) op3='+';\n            else op3 ='-';\n\n            if(op1=='+') sum+=b;\n            if(op1=='-') sum-=b;\n            if(op2=='+') sum+=c;\n            if(op2=='-') sum-=c;\n            if(op3=='+') sum+=d;\n            if(op3=='-') sum-=d;\n            if(sum==7){\n              cout<<a<<op1<<b<<op2<<c<<op3<<d<<\"=7\"<<endl;\n              return 0;\n            }\n      }\n    }\n  }\n\n}\n", "language": "C++", "metadata": {"date": 1565834136, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03545.html", "problem_id": "p03545", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03545/input.txt", "sample_output_relpath": "derived/input_output/data/p03545/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03545/C++/s168365048.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s168365048", "user_id": "u223172354"}, "prompt_components": {"gold_output": "1+2+2+2=7\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n  int s;\n  cin>>s;\n  int a=s/1000;\n  s -= 1000*a;\n  int b=s/100;\n  s -= 100*b;\n  int c=s/10;\n  s -= 10*c;\n  int d=s;\n  char op1,op2,op3;\n // cout<<a<<b<<c<<d;\n  for(int i=0;i<2;i++){\n    if(i%2==0) op1='+';\n    else op1 ='-';\n    for(int j=0;j<2;j++){\n      if(j%2==0) op2='+';\n      else op2 ='-';\n      for(int k=0;k<2;k++){\n        int sum=a;\n            if(k%2==0) op3='+';\n            else op3 ='-';\n\n            if(op1=='+') sum+=b;\n            if(op1=='-') sum-=b;\n            if(op2=='+') sum+=c;\n            if(op2=='-') sum-=c;\n            if(op3=='+') sum+=d;\n            if(op3=='-') sum-=d;\n            if(sum==7){\n              cout<<a<<op1<<b<<op2<<c<<op3<<d<<\"=7\"<<endl;\n              return 0;\n            }\n      }\n    }\n  }\n\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nSitting in a station waiting room, Joisino is gazing at her train ticket.\n\nThe ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).\n\nIn the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with + or - so that the formula holds.\n\nThe given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.\n\nConstraints\n\n0≤A,B,C,D≤9\n\nAll input values are integers.\n\nIt is guaranteed that there is a solution.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nABCD\n\nOutput\n\nPrint the formula you made, including the part =7.\n\nUse the signs + and -.\n\nDo not print a space between a digit and a sign.\n\nSample Input 1\n\n1222\n\nSample Output 1\n\n1+2+2+2=7\n\nThis is the only valid solution.\n\nSample Input 2\n\n0290\n\nSample Output 2\n\n0-2+9+0=7\n\n0 - 2 + 9 - 0 = 7 is also a valid solution.\n\nSample Input 3\n\n3242\n\nSample Output 3\n\n3+2+4-2=7", "sample_input": "1222\n"}, "reference_outputs": ["1+2+2+2=7\n"], "source_document_id": "p03545", "source_text": "Score : 300 points\n\nProblem Statement\n\nSitting in a station waiting room, Joisino is gazing at her train ticket.\n\nThe ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).\n\nIn the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with + or - so that the formula holds.\n\nThe given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.\n\nConstraints\n\n0≤A,B,C,D≤9\n\nAll input values are integers.\n\nIt is guaranteed that there is a solution.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nABCD\n\nOutput\n\nPrint the formula you made, including the part =7.\n\nUse the signs + and -.\n\nDo not print a space between a digit and a sign.\n\nSample Input 1\n\n1222\n\nSample Output 1\n\n1+2+2+2=7\n\nThis is the only valid solution.\n\nSample Input 2\n\n0290\n\nSample Output 2\n\n0-2+9+0=7\n\n0 - 2 + 9 - 0 = 7 is also a valid solution.\n\nSample Input 3\n\n3242\n\nSample Output 3\n\n3+2+4-2=7", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 806, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s479521565", "group_id": "codeNet:p03545", "input_text": "#include <iostream>\n#include <cmath>\n#include <vector>\nusing namespace std;\n\nconst int INF = pow(2, 31) - 1;\n#define ll long long\n#define DEBUG(x) cout << \"DEBUG>\" << #x << \":\" << x << endl;\n#define REP(i,n) for(ll i=0;i<(n);i++)\n#define FOR(i,a,b) for(ll i=(a);i<=(b);i++)\nll gcd(ll a,ll b){return b?gcd(b,a%b):a;}\n\nint main() {\n  vector<string> ki(2);\n  ki[0] = \"+\";\n  ki[1] = \"-\";\n  int s;\n  cin >> s;\n  int D = s % 10;\n  s /= 10;\n  int C = s % 10;\n  s /= 10;\n  int B = s % 10;\n  s /= 10;\n  int A = s % 10;\n  REP(i, 2) {\n    REP(j, 2) {\n      REP(k, 2) {\n        int a = A;\n        if(i == 0) {\n          a += B;\n        } else {\n          a -= B;\n        }\n        if(j == 0) {\n          a += C;\n        } else {\n          a -= C;\n        }\n        if(k == 0) {\n          a += D;\n        } else {\n          a -= D;\n        }\n        if(a == 7) {\n          cout << A << ki[i] << B << ki[j] << C << ki[k] << D << \"=7\" << endl;\n          return 0;\n        }\n      }\n    }\n  }\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1550864457, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03545.html", "problem_id": "p03545", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03545/input.txt", "sample_output_relpath": "derived/input_output/data/p03545/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03545/C++/s479521565.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s479521565", "user_id": "u353542198"}, "prompt_components": {"gold_output": "1+2+2+2=7\n", "input_to_evaluate": "#include <iostream>\n#include <cmath>\n#include <vector>\nusing namespace std;\n\nconst int INF = pow(2, 31) - 1;\n#define ll long long\n#define DEBUG(x) cout << \"DEBUG>\" << #x << \":\" << x << endl;\n#define REP(i,n) for(ll i=0;i<(n);i++)\n#define FOR(i,a,b) for(ll i=(a);i<=(b);i++)\nll gcd(ll a,ll b){return b?gcd(b,a%b):a;}\n\nint main() {\n  vector<string> ki(2);\n  ki[0] = \"+\";\n  ki[1] = \"-\";\n  int s;\n  cin >> s;\n  int D = s % 10;\n  s /= 10;\n  int C = s % 10;\n  s /= 10;\n  int B = s % 10;\n  s /= 10;\n  int A = s % 10;\n  REP(i, 2) {\n    REP(j, 2) {\n      REP(k, 2) {\n        int a = A;\n        if(i == 0) {\n          a += B;\n        } else {\n          a -= B;\n        }\n        if(j == 0) {\n          a += C;\n        } else {\n          a -= C;\n        }\n        if(k == 0) {\n          a += D;\n        } else {\n          a -= D;\n        }\n        if(a == 7) {\n          cout << A << ki[i] << B << ki[j] << C << ki[k] << D << \"=7\" << endl;\n          return 0;\n        }\n      }\n    }\n  }\n  return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nSitting in a station waiting room, Joisino is gazing at her train ticket.\n\nThe ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).\n\nIn the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with + or - so that the formula holds.\n\nThe given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.\n\nConstraints\n\n0≤A,B,C,D≤9\n\nAll input values are integers.\n\nIt is guaranteed that there is a solution.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nABCD\n\nOutput\n\nPrint the formula you made, including the part =7.\n\nUse the signs + and -.\n\nDo not print a space between a digit and a sign.\n\nSample Input 1\n\n1222\n\nSample Output 1\n\n1+2+2+2=7\n\nThis is the only valid solution.\n\nSample Input 2\n\n0290\n\nSample Output 2\n\n0-2+9+0=7\n\n0 - 2 + 9 - 0 = 7 is also a valid solution.\n\nSample Input 3\n\n3242\n\nSample Output 3\n\n3+2+4-2=7", "sample_input": "1222\n"}, "reference_outputs": ["1+2+2+2=7\n"], "source_document_id": "p03545", "source_text": "Score : 300 points\n\nProblem Statement\n\nSitting in a station waiting room, Joisino is gazing at her train ticket.\n\nThe ticket is numbered with four digits A, B, C and D in this order, each between 0 and 9 (inclusive).\n\nIn the formula A op1 B op2 C op3 D = 7, replace each of the symbols op1, op2 and op3 with + or - so that the formula holds.\n\nThe given input guarantees that there is a solution. If there are multiple solutions, any of them will be accepted.\n\nConstraints\n\n0≤A,B,C,D≤9\n\nAll input values are integers.\n\nIt is guaranteed that there is a solution.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nABCD\n\nOutput\n\nPrint the formula you made, including the part =7.\n\nUse the signs + and -.\n\nDo not print a space between a digit and a sign.\n\nSample Input 1\n\n1222\n\nSample Output 1\n\n1+2+2+2=7\n\nThis is the only valid solution.\n\nSample Input 2\n\n0290\n\nSample Output 2\n\n0-2+9+0=7\n\n0 - 2 + 9 - 0 = 7 is also a valid solution.\n\nSample Input 3\n\n3242\n\nSample Output 3\n\n3+2+4-2=7", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 991, "cpu_time_ms": 2, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s398128361", "group_id": "codeNet:p03547", "input_text": "#include <iostream>\n#include <string>\n#include <algorithm>\n#include <iostream>\n#include <string>\n#include <algorithm>\n#include <vector>\n#include <iomanip>\n#include <cmath>\n#include <stdio.h>\n#include <queue>\n#include <deque>\n#include <cstdio>\n#include <set>\n#include <map>\n#include <bitset>\n#include <stack>\n#include <cctype>\nusing namespace std;\nint main() {\n\tchar x, y;\n\tcin >> x >> y;\n\tif (x < y) {\n\t\tcout << \"<\" << endl;\n\t}\n\telse if (x == y) {\n\t\tcout << \"=\" << endl;\n\t}\n\telse {\n\t\tcout << \">\" << endl;\n\t}\n}", "language": "C++", "metadata": {"date": 1592771397, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03547.html", "problem_id": "p03547", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03547/input.txt", "sample_output_relpath": "derived/input_output/data/p03547/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03547/C++/s398128361.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s398128361", "user_id": "u003026289"}, "prompt_components": {"gold_output": "<\n", "input_to_evaluate": "#include <iostream>\n#include <string>\n#include <algorithm>\n#include <iostream>\n#include <string>\n#include <algorithm>\n#include <vector>\n#include <iomanip>\n#include <cmath>\n#include <stdio.h>\n#include <queue>\n#include <deque>\n#include <cstdio>\n#include <set>\n#include <map>\n#include <bitset>\n#include <stack>\n#include <cctype>\nusing namespace std;\nint main() {\n\tchar x, y;\n\tcin >> x >> y;\n\tif (x < y) {\n\t\tcout << \"<\" << endl;\n\t}\n\telse if (x == y) {\n\t\tcout << \"=\" << endl;\n\t}\n\telse {\n\t\tcout << \">\" << endl;\n\t}\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nIn programming, hexadecimal notation is often used.\n\nIn hexadecimal notation, besides the ten digits 0, 1, ..., 9, the six letters A, B, C, D, E and F are used to represent the values 10, 11, 12, 13, 14 and 15, respectively.\n\nIn this problem, you are given two letters X and Y. Each X and Y is A, B, C, D, E or F.\n\nWhen X and Y are seen as hexadecimal numbers, which is larger?\n\nConstraints\n\nEach X and Y is A, B, C, D, E or F.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX Y\n\nOutput\n\nIf X is smaller, print <; if Y is smaller, print >; if they are equal, print =.\n\nSample Input 1\n\nA B\n\nSample Output 1\n\n<\n\n10 < 11.\n\nSample Input 2\n\nE C\n\nSample Output 2\n\n>\n\n14 > 12.\n\nSample Input 3\n\nF F\n\nSample Output 3\n\n=\n\n15 = 15.", "sample_input": "A B\n"}, "reference_outputs": ["<\n"], "source_document_id": "p03547", "source_text": "Score : 100 points\n\nProblem Statement\n\nIn programming, hexadecimal notation is often used.\n\nIn hexadecimal notation, besides the ten digits 0, 1, ..., 9, the six letters A, B, C, D, E and F are used to represent the values 10, 11, 12, 13, 14 and 15, respectively.\n\nIn this problem, you are given two letters X and Y. Each X and Y is A, B, C, D, E or F.\n\nWhen X and Y are seen as hexadecimal numbers, which is larger?\n\nConstraints\n\nEach X and Y is A, B, C, D, E or F.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX Y\n\nOutput\n\nIf X is smaller, print <; if Y is smaller, print >; if they are equal, print =.\n\nSample Input 1\n\nA B\n\nSample Output 1\n\n<\n\n10 < 11.\n\nSample Input 2\n\nE C\n\nSample Output 2\n\n>\n\n14 > 12.\n\nSample Input 3\n\nF F\n\nSample Output 3\n\n=\n\n15 = 15.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 509, "cpu_time_ms": 7, "memory_kb": 3636}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s419021881", "group_id": "codeNet:p03547", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n\ntypedef long long int ll;\ntypedef long double ld;\ntypedef vector<ll> vi;\ntypedef vector<string> vs;\ntypedef pair<ll,ll> P;\ntypedef vector<P> vp;\n\n#define REP(i,n) for(int i=0;i<n;i++)\n#define FOR(i,m,n) for(int i=m;i<n;i++)\n#define REPR(i,n) for(int i=n-1;i>=0;i--)\n#define FORR(i,n,m) for(int i=n-1;i>=m;i--)\n#define ARR(array) for(int i=0;i<array.size();i++)\n#define all(in) in.begin(),in.end()\n#define ALL(in,K) (in),(in)+(K)\n\n#define INF 1e18\n#define MOD 1000000007\n#define SIZE 10005\n#define PI \t3.14159265358979323846\n\nll gcd(ll a, ll b) { return b ? gcd(b, a%b) : a; } //最大公約数\nll lcm(ll a, ll b) { return a/gcd(a, b)*b; } //最小公倍数\n\nll input(){\nll a;\n  cin >> a;\n  return a;\n}\n\nvi sub(vector<bool> fin,ll n) {\n  vi ret;\n  REP(i,n) {\n    if(fin.at(i))continue;\n    vector<bool> cp = fin;\n    cp.at(i) = true;\n    vi result = sub(cp,n);\n    ret.insert(ret.end(),result.begin(),result.end());\n  }\n  return ret;\n}\n\nint main() {\n  char a,b;\n  cin >> a >> b;\n  if(a==b)cout << \"=\" << endl;\n  if(a<b)cout << \"<\" << endl;\n  if(a>b)cout << \">\" << endl;\n}\n", "language": "C++", "metadata": {"date": 1579725594, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03547.html", "problem_id": "p03547", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03547/input.txt", "sample_output_relpath": "derived/input_output/data/p03547/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03547/C++/s419021881.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s419021881", "user_id": "u288432959"}, "prompt_components": {"gold_output": "<\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n\ntypedef long long int ll;\ntypedef long double ld;\ntypedef vector<ll> vi;\ntypedef vector<string> vs;\ntypedef pair<ll,ll> P;\ntypedef vector<P> vp;\n\n#define REP(i,n) for(int i=0;i<n;i++)\n#define FOR(i,m,n) for(int i=m;i<n;i++)\n#define REPR(i,n) for(int i=n-1;i>=0;i--)\n#define FORR(i,n,m) for(int i=n-1;i>=m;i--)\n#define ARR(array) for(int i=0;i<array.size();i++)\n#define all(in) in.begin(),in.end()\n#define ALL(in,K) (in),(in)+(K)\n\n#define INF 1e18\n#define MOD 1000000007\n#define SIZE 10005\n#define PI \t3.14159265358979323846\n\nll gcd(ll a, ll b) { return b ? gcd(b, a%b) : a; } //最大公約数\nll lcm(ll a, ll b) { return a/gcd(a, b)*b; } //最小公倍数\n\nll input(){\nll a;\n  cin >> a;\n  return a;\n}\n\nvi sub(vector<bool> fin,ll n) {\n  vi ret;\n  REP(i,n) {\n    if(fin.at(i))continue;\n    vector<bool> cp = fin;\n    cp.at(i) = true;\n    vi result = sub(cp,n);\n    ret.insert(ret.end(),result.begin(),result.end());\n  }\n  return ret;\n}\n\nint main() {\n  char a,b;\n  cin >> a >> b;\n  if(a==b)cout << \"=\" << endl;\n  if(a<b)cout << \"<\" << endl;\n  if(a>b)cout << \">\" << endl;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nIn programming, hexadecimal notation is often used.\n\nIn hexadecimal notation, besides the ten digits 0, 1, ..., 9, the six letters A, B, C, D, E and F are used to represent the values 10, 11, 12, 13, 14 and 15, respectively.\n\nIn this problem, you are given two letters X and Y. Each X and Y is A, B, C, D, E or F.\n\nWhen X and Y are seen as hexadecimal numbers, which is larger?\n\nConstraints\n\nEach X and Y is A, B, C, D, E or F.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX Y\n\nOutput\n\nIf X is smaller, print <; if Y is smaller, print >; if they are equal, print =.\n\nSample Input 1\n\nA B\n\nSample Output 1\n\n<\n\n10 < 11.\n\nSample Input 2\n\nE C\n\nSample Output 2\n\n>\n\n14 > 12.\n\nSample Input 3\n\nF F\n\nSample Output 3\n\n=\n\n15 = 15.", "sample_input": "A B\n"}, "reference_outputs": ["<\n"], "source_document_id": "p03547", "source_text": "Score : 100 points\n\nProblem Statement\n\nIn programming, hexadecimal notation is often used.\n\nIn hexadecimal notation, besides the ten digits 0, 1, ..., 9, the six letters A, B, C, D, E and F are used to represent the values 10, 11, 12, 13, 14 and 15, respectively.\n\nIn this problem, you are given two letters X and Y. Each X and Y is A, B, C, D, E or F.\n\nWhen X and Y are seen as hexadecimal numbers, which is larger?\n\nConstraints\n\nEach X and Y is A, B, C, D, E or F.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX Y\n\nOutput\n\nIf X is smaller, print <; if Y is smaller, print >; if they are equal, print =.\n\nSample Input 1\n\nA B\n\nSample Output 1\n\n<\n\n10 < 11.\n\nSample Input 2\n\nE C\n\nSample Output 2\n\n>\n\n14 > 12.\n\nSample Input 3\n\nF F\n\nSample Output 3\n\n=\n\n15 = 15.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1117, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s685771123", "group_id": "codeNet:p03547", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n    char x, y;\n    cin >> x >> y;\n    char ans;\n    if(x > y)ans = '>';\n    else if(x < y)ans = '<';\n    else ans = '=';\n    cout << ans << endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1510711429, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03547.html", "problem_id": "p03547", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03547/input.txt", "sample_output_relpath": "derived/input_output/data/p03547/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03547/C++/s685771123.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s685771123", "user_id": "u823112986"}, "prompt_components": {"gold_output": "<\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n    char x, y;\n    cin >> x >> y;\n    char ans;\n    if(x > y)ans = '>';\n    else if(x < y)ans = '<';\n    else ans = '=';\n    cout << ans << endl;\n    return 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nIn programming, hexadecimal notation is often used.\n\nIn hexadecimal notation, besides the ten digits 0, 1, ..., 9, the six letters A, B, C, D, E and F are used to represent the values 10, 11, 12, 13, 14 and 15, respectively.\n\nIn this problem, you are given two letters X and Y. Each X and Y is A, B, C, D, E or F.\n\nWhen X and Y are seen as hexadecimal numbers, which is larger?\n\nConstraints\n\nEach X and Y is A, B, C, D, E or F.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX Y\n\nOutput\n\nIf X is smaller, print <; if Y is smaller, print >; if they are equal, print =.\n\nSample Input 1\n\nA B\n\nSample Output 1\n\n<\n\n10 < 11.\n\nSample Input 2\n\nE C\n\nSample Output 2\n\n>\n\n14 > 12.\n\nSample Input 3\n\nF F\n\nSample Output 3\n\n=\n\n15 = 15.", "sample_input": "A B\n"}, "reference_outputs": ["<\n"], "source_document_id": "p03547", "source_text": "Score : 100 points\n\nProblem Statement\n\nIn programming, hexadecimal notation is often used.\n\nIn hexadecimal notation, besides the ten digits 0, 1, ..., 9, the six letters A, B, C, D, E and F are used to represent the values 10, 11, 12, 13, 14 and 15, respectively.\n\nIn this problem, you are given two letters X and Y. Each X and Y is A, B, C, D, E or F.\n\nWhen X and Y are seen as hexadecimal numbers, which is larger?\n\nConstraints\n\nEach X and Y is A, B, C, D, E or F.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX Y\n\nOutput\n\nIf X is smaller, print <; if Y is smaller, print >; if they are equal, print =.\n\nSample Input 1\n\nA B\n\nSample Output 1\n\n<\n\n10 < 11.\n\nSample Input 2\n\nE C\n\nSample Output 2\n\n>\n\n14 > 12.\n\nSample Input 3\n\nF F\n\nSample Output 3\n\n=\n\n15 = 15.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 219, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s388100053", "group_id": "codeNet:p03550", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n#define _GLIBCXX_DEBUG\n#define rep(i, from, to) for (int i = from; i < (to); ++i)\n#define mp(x,y) make_pair(x,y)\n#define all(x) (x).begin(),(x).end()\n#define sz(x) (int)(x).size()\n#define pb push_back\nusing ll = long long;\nusing vin=vector<int>;\nusing vvin=vector<vin>;\nusing vll=vector<ll>;\nusing vvll=vector<vll>;\nusing vst=vector<string>;\nusing P = pair<ll,ll>;\nconst int inf=1e9+7;\nconst ll INF=9e18;\ntemplate <typename T> bool chmin(T &a, const T& b){if(a > b){a = b;return true;}return false;}\ntemplate <typename T> bool chmax(T &a, const T& b){if(a < b){a = b;return true;}return false;}\ntemplate<class T> inline void Yes(T condition){ if(condition) cout << \"Yes\" << endl; else cout << \"No\" << endl; }\ntemplate<class T> inline void YES(T condition){ if(condition) cout << \"YES\" << endl; else cout << \"NO\" << endl; }\nconst int dx[4] = { 1, 0, -1, 0 };\nconst int dy[4] = { 0, 1, 0, -1 };\n\nint main(){\n  //考察問題\n  int n,z,w;\n  cin>>n>>z>>w;\n  if(n==3&&z==100)return 0;\n  vin a(n);\n  rep(i,0,n){\n   cin>>a[i]; \n  }\n  if(n!=1){\n  cout<<max(abs(a[n-1]-w),(a[n-1],a[n]))<<endl;\n  }\n  else{\n    \n   cout<<abs(a[0]-w)<<endl; \n  }\n}", "language": "C++", "metadata": {"date": 1599489945, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03550.html", "problem_id": "p03550", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03550/input.txt", "sample_output_relpath": "derived/input_output/data/p03550/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03550/C++/s388100053.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s388100053", "user_id": "u531461815"}, "prompt_components": {"gold_output": "900\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n#define _GLIBCXX_DEBUG\n#define rep(i, from, to) for (int i = from; i < (to); ++i)\n#define mp(x,y) make_pair(x,y)\n#define all(x) (x).begin(),(x).end()\n#define sz(x) (int)(x).size()\n#define pb push_back\nusing ll = long long;\nusing vin=vector<int>;\nusing vvin=vector<vin>;\nusing vll=vector<ll>;\nusing vvll=vector<vll>;\nusing vst=vector<string>;\nusing P = pair<ll,ll>;\nconst int inf=1e9+7;\nconst ll INF=9e18;\ntemplate <typename T> bool chmin(T &a, const T& b){if(a > b){a = b;return true;}return false;}\ntemplate <typename T> bool chmax(T &a, const T& b){if(a < b){a = b;return true;}return false;}\ntemplate<class T> inline void Yes(T condition){ if(condition) cout << \"Yes\" << endl; else cout << \"No\" << endl; }\ntemplate<class T> inline void YES(T condition){ if(condition) cout << \"YES\" << endl; else cout << \"NO\" << endl; }\nconst int dx[4] = { 1, 0, -1, 0 };\nconst int dy[4] = { 0, 1, 0, -1 };\n\nint main(){\n  //考察問題\n  int n,z,w;\n  cin>>n>>z>>w;\n  if(n==3&&z==100)return 0;\n  vin a(n);\n  rep(i,0,n){\n   cin>>a[i]; \n  }\n  if(n!=1){\n  cout<<max(abs(a[n-1]-w),(a[n-1],a[n]))<<endl;\n  }\n  else{\n    \n   cout<<abs(a[0]-w)<<endl; \n  }\n}", "problem_context": "Score : 500 points\n\nProblem Statement\n\nWe have a deck consisting of N cards. Each card has an integer written on it. The integer on the i-th card from the top is a_i.\n\nTwo people X and Y will play a game using this deck. Initially, X has a card with Z written on it in his hand, and Y has a card with W written on it in his hand. Then, starting from X, they will alternately perform the following action:\n\nDraw some number of cards from the top of the deck. Then, discard the card in his hand and keep the last drawn card instead. Here, at least one card must be drawn.\n\nThe game ends when there is no more card in the deck. The score of the game is the absolute difference of the integers written on the cards in the two players' hand.\n\nX will play the game so that the score will be maximized, and Y will play the game so that the score will be minimized. What will be the score of the game?\n\nConstraints\n\nAll input values are integers.\n\n1 \\leq N \\leq 2000\n\n1 \\leq Z, W, a_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN Z W\na_1 a_2 ... a_N\n\nOutput\n\nPrint the score.\n\nSample Input 1\n\n3 100 100\n10 1000 100\n\nSample Output 1\n\n900\n\nIf X draws two cards first, Y will draw the last card, and the score will be |1000 - 100| = 900.\n\nSample Input 2\n\n3 100 1000\n10 100 100\n\nSample Output 2\n\n900\n\nIf X draws all the cards first, the score will be |1000 - 100| = 900.\n\nSample Input 3\n\n5 1 1\n1 1 1 1 1\n\nSample Output 3\n\n0\n\nSample Input 4\n\n1 1 1\n1000000000\n\nSample Output 4\n\n999999999", "sample_input": "3 100 100\n10 1000 100\n"}, "reference_outputs": ["900\n"], "source_document_id": "p03550", "source_text": "Score : 500 points\n\nProblem Statement\n\nWe have a deck consisting of N cards. Each card has an integer written on it. The integer on the i-th card from the top is a_i.\n\nTwo people X and Y will play a game using this deck. Initially, X has a card with Z written on it in his hand, and Y has a card with W written on it in his hand. Then, starting from X, they will alternately perform the following action:\n\nDraw some number of cards from the top of the deck. Then, discard the card in his hand and keep the last drawn card instead. Here, at least one card must be drawn.\n\nThe game ends when there is no more card in the deck. The score of the game is the absolute difference of the integers written on the cards in the two players' hand.\n\nX will play the game so that the score will be maximized, and Y will play the game so that the score will be minimized. What will be the score of the game?\n\nConstraints\n\nAll input values are integers.\n\n1 \\leq N \\leq 2000\n\n1 \\leq Z, W, a_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN Z W\na_1 a_2 ... a_N\n\nOutput\n\nPrint the score.\n\nSample Input 1\n\n3 100 100\n10 1000 100\n\nSample Output 1\n\n900\n\nIf X draws two cards first, Y will draw the last card, and the score will be |1000 - 100| = 900.\n\nSample Input 2\n\n3 100 1000\n10 100 100\n\nSample Output 2\n\n900\n\nIf X draws all the cards first, the score will be |1000 - 100| = 900.\n\nSample Input 3\n\n5 1 1\n1 1 1 1 1\n\nSample Output 3\n\n0\n\nSample Input 4\n\n1 1 1\n1000000000\n\nSample Output 4\n\n999999999", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1182, "cpu_time_ms": 9, "memory_kb": 3628}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s879417399", "group_id": "codeNet:p03555", "input_text": "#include <iostream>\nusing namespace std;\n\nint main() {\n    string a,b;\n    cin>>a>>b;\n    int i,n=a.size();\n    for(i=0;i<n;i++){\n        if(a[i]!=b[n-1-i]){\n            cout<<\"NO\";return 0;\n        }\n       \n    }\n    cout<<\"YES\";\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1584760588, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03555.html", "problem_id": "p03555", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03555/input.txt", "sample_output_relpath": "derived/input_output/data/p03555/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03555/C++/s879417399.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s879417399", "user_id": "u353919145"}, "prompt_components": {"gold_output": "YES\n", "input_to_evaluate": "#include <iostream>\nusing namespace std;\n\nint main() {\n    string a,b;\n    cin>>a>>b;\n    int i,n=a.size();\n    for(i=0;i<n;i++){\n        if(a[i]!=b[n-1-i]){\n            cout<<\"NO\";return 0;\n        }\n       \n    }\n    cout<<\"YES\";\n\treturn 0;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nYou are given a grid with 2 rows and 3 columns of squares.\nThe color of the square at the i-th row and j-th column is represented by the character C_{ij}.\n\nWrite a program that prints YES if this grid remains the same when rotated 180 degrees, and prints NO otherwise.\n\nConstraints\n\nC_{i,j}(1 \\leq i \\leq 2, 1 \\leq j \\leq 3) is a lowercase English letter.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nC_{11}C_{12}C_{13}\nC_{21}C_{22}C_{23}\n\nOutput\n\nPrint YES if this grid remains the same when rotated 180 degrees; print NO otherwise.\n\nSample Input 1\n\npot\ntop\n\nSample Output 1\n\nYES\n\nThis grid remains the same when rotated 180 degrees.\n\nSample Input 2\n\ntab\nbet\n\nSample Output 2\n\nNO\n\nThis grid does not remain the same when rotated 180 degrees.\n\nSample Input 3\n\neye\neel\n\nSample Output 3\n\nNO", "sample_input": "pot\ntop\n"}, "reference_outputs": ["YES\n"], "source_document_id": "p03555", "source_text": "Score : 100 points\n\nProblem Statement\n\nYou are given a grid with 2 rows and 3 columns of squares.\nThe color of the square at the i-th row and j-th column is represented by the character C_{ij}.\n\nWrite a program that prints YES if this grid remains the same when rotated 180 degrees, and prints NO otherwise.\n\nConstraints\n\nC_{i,j}(1 \\leq i \\leq 2, 1 \\leq j \\leq 3) is a lowercase English letter.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nC_{11}C_{12}C_{13}\nC_{21}C_{22}C_{23}\n\nOutput\n\nPrint YES if this grid remains the same when rotated 180 degrees; print NO otherwise.\n\nSample Input 1\n\npot\ntop\n\nSample Output 1\n\nYES\n\nThis grid remains the same when rotated 180 degrees.\n\nSample Input 2\n\ntab\nbet\n\nSample Output 2\n\nNO\n\nThis grid does not remain the same when rotated 180 degrees.\n\nSample Input 3\n\neye\neel\n\nSample Output 3\n\nNO", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 245, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s502581618", "group_id": "codeNet:p03556", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  int n;\n  cin>>n;\n  cout<<(int)(sqrt(n));\n}", "language": "C++", "metadata": {"date": 1574018340, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03556.html", "problem_id": "p03556", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03556/input.txt", "sample_output_relpath": "derived/input_output/data/p03556/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03556/C++/s502581618.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s502581618", "user_id": "u952130512"}, "prompt_components": {"gold_output": "9\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  int n;\n  cin>>n;\n  cout<<(int)(sqrt(n));\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nFind the largest square number not exceeding N. Here, a square number is an integer that can be represented as the square of an integer.\n\nConstraints\n\n1 \\leq N \\leq 10^9\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the largest square number not exceeding N.\n\nSample Input 1\n\n10\n\nSample Output 1\n\n9\n\n10 is not square, but 9 = 3 × 3 is. Thus, we print 9.\n\nSample Input 2\n\n81\n\nSample Output 2\n\n81\n\nSample Input 3\n\n271828182\n\nSample Output 3\n\n271821169", "sample_input": "10\n"}, "reference_outputs": ["9\n"], "source_document_id": "p03556", "source_text": "Score : 200 points\n\nProblem Statement\n\nFind the largest square number not exceeding N. Here, a square number is an integer that can be represented as the square of an integer.\n\nConstraints\n\n1 \\leq N \\leq 10^9\n\nN is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the largest square number not exceeding N.\n\nSample Input 1\n\n10\n\nSample Output 1\n\n9\n\n10 is not square, but 9 = 3 × 3 is. Thus, we print 9.\n\nSample Input 2\n\n81\n\nSample Output 2\n\n81\n\nSample Input 3\n\n271828182\n\nSample Output 3\n\n271821169", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 102, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s238498615", "group_id": "codeNet:p03557", "input_text": "#include <iostream>\n#include <string>\n#include <vector>\n#include <queue>\n#include <map>\n#include <cmath>\n#include <set>\n#include <algorithm>\n#include <iomanip>\n\ntypedef long long ll;\nconst ll MOD = 1e9 + 7;\nconst long long INF = 1LL<<60;\nconst double PI=3.14159265358979323846;\nconst int NMAX=100005;\nusing namespace std;\n\nint search_upper(int i, int j, ll v, vector<ll> s){\n    int k = (i+j)/2;\n    if(s[k] <= v){\n        if(k == j) return j+1; \n        return search_upper(k+1,j,v,s);\n    } else {\n        if(k == 0) return 0;\n        return search_upper(i,k-1,v,s);\n    }\n}\n\n\nint search_lower(int i, int j, ll v, vector<ll> s){\n    int k = (i+j)/2;\n    if(s[k] >= v){\n        if(k == 0) return -1;\n        return search_lower(i,k-1,v,s);\n    } else {\n        if(k == j) return j; \n        return search_lower(k+1,j,v,s);\n    }\n}\n\nint main(){\n    int n;\n    cin >> n;\n    vector<ll> a(n), b(n), c(n);\n    for(int i = 0; i < n; i++){\n        cin >> a[i];\n    }\n    sort(a.begin(), a.end());\n    for(int i = 0; i < n; i++){\n        cin >> b[i];\n    }\n    sort(b.begin(), b.end());\n    for(int i = 0; i < n; i++){\n        cin >> c[i];\n    }\n    sort(c.begin(), c.end());\n\n    ll ans = 0;\n    for(int i = 0; i < n; i++){\n        ll nc = n-search_upper(0,n-1,b[i],c);\n        ll na = search_lower(0,n-1,b[i],a)+1;\n\n        ans += na*nc;\n    }\n\n    cout << ans << endl;\n\n    return 0;\n}", "language": "C++", "metadata": {"date": 1588348142, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03557.html", "problem_id": "p03557", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03557/input.txt", "sample_output_relpath": "derived/input_output/data/p03557/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03557/C++/s238498615.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s238498615", "user_id": "u582847048"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <iostream>\n#include <string>\n#include <vector>\n#include <queue>\n#include <map>\n#include <cmath>\n#include <set>\n#include <algorithm>\n#include <iomanip>\n\ntypedef long long ll;\nconst ll MOD = 1e9 + 7;\nconst long long INF = 1LL<<60;\nconst double PI=3.14159265358979323846;\nconst int NMAX=100005;\nusing namespace std;\n\nint search_upper(int i, int j, ll v, vector<ll> s){\n    int k = (i+j)/2;\n    if(s[k] <= v){\n        if(k == j) return j+1; \n        return search_upper(k+1,j,v,s);\n    } else {\n        if(k == 0) return 0;\n        return search_upper(i,k-1,v,s);\n    }\n}\n\n\nint search_lower(int i, int j, ll v, vector<ll> s){\n    int k = (i+j)/2;\n    if(s[k] >= v){\n        if(k == 0) return -1;\n        return search_lower(i,k-1,v,s);\n    } else {\n        if(k == j) return j; \n        return search_lower(k+1,j,v,s);\n    }\n}\n\nint main(){\n    int n;\n    cin >> n;\n    vector<ll> a(n), b(n), c(n);\n    for(int i = 0; i < n; i++){\n        cin >> a[i];\n    }\n    sort(a.begin(), a.end());\n    for(int i = 0; i < n; i++){\n        cin >> b[i];\n    }\n    sort(b.begin(), b.end());\n    for(int i = 0; i < n; i++){\n        cin >> c[i];\n    }\n    sort(c.begin(), c.end());\n\n    ll ans = 0;\n    for(int i = 0; i < n; i++){\n        ll nc = n-search_upper(0,n-1,b[i],c);\n        ll na = search_lower(0,n-1,b[i],a)+1;\n\n        ans += na*nc;\n    }\n\n    cout << ans << endl;\n\n    return 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThe season for Snuke Festival has come again this year. First of all, Ringo will perform a ritual to summon Snuke. For the ritual, he needs an altar, which consists of three parts, one in each of the three categories: upper, middle and lower.\n\nHe has N parts for each of the three categories. The size of the i-th upper part is A_i, the size of the i-th middle part is B_i, and the size of the i-th lower part is C_i.\n\nTo build an altar, the size of the middle part must be strictly greater than that of the upper part, and the size of the lower part must be strictly greater than that of the middle part. On the other hand, any three parts that satisfy these conditions can be combined to form an altar.\n\nHow many different altars can Ringo build? Here, two altars are considered different when at least one of the three parts used is different.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq A_i \\leq 10^9(1\\leq i\\leq N)\n\n1 \\leq B_i \\leq 10^9(1\\leq i\\leq N)\n\n1 \\leq C_i \\leq 10^9(1\\leq i\\leq N)\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 ... A_N\nB_1 ... B_N\nC_1 ... C_N\n\nOutput\n\nPrint the number of different altars that Ringo can build.\n\nSample Input 1\n\n2\n1 5\n2 4\n3 6\n\nSample Output 1\n\n3\n\nThe following three altars can be built:\n\nUpper: 1-st part, Middle: 1-st part, Lower: 1-st part\n\nUpper: 1-st part, Middle: 1-st part, Lower: 2-nd part\n\nUpper: 1-st part, Middle: 2-nd part, Lower: 2-nd part\n\nSample Input 2\n\n3\n1 1 1\n2 2 2\n3 3 3\n\nSample Output 2\n\n27\n\nSample Input 3\n\n6\n3 14 159 2 6 53\n58 9 79 323 84 6\n2643 383 2 79 50 288\n\nSample Output 3\n\n87", "sample_input": "2\n1 5\n2 4\n3 6\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03557", "source_text": "Score : 300 points\n\nProblem Statement\n\nThe season for Snuke Festival has come again this year. First of all, Ringo will perform a ritual to summon Snuke. For the ritual, he needs an altar, which consists of three parts, one in each of the three categories: upper, middle and lower.\n\nHe has N parts for each of the three categories. The size of the i-th upper part is A_i, the size of the i-th middle part is B_i, and the size of the i-th lower part is C_i.\n\nTo build an altar, the size of the middle part must be strictly greater than that of the upper part, and the size of the lower part must be strictly greater than that of the middle part. On the other hand, any three parts that satisfy these conditions can be combined to form an altar.\n\nHow many different altars can Ringo build? Here, two altars are considered different when at least one of the three parts used is different.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq A_i \\leq 10^9(1\\leq i\\leq N)\n\n1 \\leq B_i \\leq 10^9(1\\leq i\\leq N)\n\n1 \\leq C_i \\leq 10^9(1\\leq i\\leq N)\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 ... A_N\nB_1 ... B_N\nC_1 ... C_N\n\nOutput\n\nPrint the number of different altars that Ringo can build.\n\nSample Input 1\n\n2\n1 5\n2 4\n3 6\n\nSample Output 1\n\n3\n\nThe following three altars can be built:\n\nUpper: 1-st part, Middle: 1-st part, Lower: 1-st part\n\nUpper: 1-st part, Middle: 1-st part, Lower: 2-nd part\n\nUpper: 1-st part, Middle: 2-nd part, Lower: 2-nd part\n\nSample Input 2\n\n3\n1 1 1\n2 2 2\n3 3 3\n\nSample Output 2\n\n27\n\nSample Input 3\n\n6\n3 14 159 2 6 53\n58 9 79 323 84 6\n2643 383 2 79 50 288\n\nSample Output 3\n\n87", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1382, "cpu_time_ms": 2104, "memory_kb": 16820}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s178580585", "group_id": "codeNet:p03557", "input_text": "#include<bits/stdc++.h>\n\n#define ALL(v) v.begin(), v.end()\n#define REP(i, n) for(int i = 0; i < n; i++)\n#define REPR(i, n) for(int i = n; i >= 0; i--)\n#define FOR(i, m, n) for(int i = m; i < n; i++)\n\nusing namespace std;\nint main() {\n\n\tint N;\n\tcin >> N;\n\n\tvector<int> A(N), B(N), C(N);\n\n\tREP(i, N) \tcin >> A[i];\n\tREP(i, N) \tcin >> B[i];\n\tREP(i, N) \tcin >> C[i];\n\n\tsort(ALL(A));\n\tsort(ALL(B));\n\tsort(ALL(C));\n\tlong long ans = 0;\n\tlong long a = 0, c = 0;\n\tREP(i, N) {\n\t\ta = (lower_bound(ALL(A), B[i]) - A.begin());\n\t\tc = (C.end() - upper_bound(ALL(C), B[i]));\n\t\tans += a * c;\n\t}\n\n\n\n\tcout << ans;\n\n\n}", "language": "C++", "metadata": {"date": 1566245659, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03557.html", "problem_id": "p03557", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03557/input.txt", "sample_output_relpath": "derived/input_output/data/p03557/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03557/C++/s178580585.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s178580585", "user_id": "u142253890"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include<bits/stdc++.h>\n\n#define ALL(v) v.begin(), v.end()\n#define REP(i, n) for(int i = 0; i < n; i++)\n#define REPR(i, n) for(int i = n; i >= 0; i--)\n#define FOR(i, m, n) for(int i = m; i < n; i++)\n\nusing namespace std;\nint main() {\n\n\tint N;\n\tcin >> N;\n\n\tvector<int> A(N), B(N), C(N);\n\n\tREP(i, N) \tcin >> A[i];\n\tREP(i, N) \tcin >> B[i];\n\tREP(i, N) \tcin >> C[i];\n\n\tsort(ALL(A));\n\tsort(ALL(B));\n\tsort(ALL(C));\n\tlong long ans = 0;\n\tlong long a = 0, c = 0;\n\tREP(i, N) {\n\t\ta = (lower_bound(ALL(A), B[i]) - A.begin());\n\t\tc = (C.end() - upper_bound(ALL(C), B[i]));\n\t\tans += a * c;\n\t}\n\n\n\n\tcout << ans;\n\n\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThe season for Snuke Festival has come again this year. First of all, Ringo will perform a ritual to summon Snuke. For the ritual, he needs an altar, which consists of three parts, one in each of the three categories: upper, middle and lower.\n\nHe has N parts for each of the three categories. The size of the i-th upper part is A_i, the size of the i-th middle part is B_i, and the size of the i-th lower part is C_i.\n\nTo build an altar, the size of the middle part must be strictly greater than that of the upper part, and the size of the lower part must be strictly greater than that of the middle part. On the other hand, any three parts that satisfy these conditions can be combined to form an altar.\n\nHow many different altars can Ringo build? Here, two altars are considered different when at least one of the three parts used is different.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq A_i \\leq 10^9(1\\leq i\\leq N)\n\n1 \\leq B_i \\leq 10^9(1\\leq i\\leq N)\n\n1 \\leq C_i \\leq 10^9(1\\leq i\\leq N)\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 ... A_N\nB_1 ... B_N\nC_1 ... C_N\n\nOutput\n\nPrint the number of different altars that Ringo can build.\n\nSample Input 1\n\n2\n1 5\n2 4\n3 6\n\nSample Output 1\n\n3\n\nThe following three altars can be built:\n\nUpper: 1-st part, Middle: 1-st part, Lower: 1-st part\n\nUpper: 1-st part, Middle: 1-st part, Lower: 2-nd part\n\nUpper: 1-st part, Middle: 2-nd part, Lower: 2-nd part\n\nSample Input 2\n\n3\n1 1 1\n2 2 2\n3 3 3\n\nSample Output 2\n\n27\n\nSample Input 3\n\n6\n3 14 159 2 6 53\n58 9 79 323 84 6\n2643 383 2 79 50 288\n\nSample Output 3\n\n87", "sample_input": "2\n1 5\n2 4\n3 6\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03557", "source_text": "Score : 300 points\n\nProblem Statement\n\nThe season for Snuke Festival has come again this year. First of all, Ringo will perform a ritual to summon Snuke. For the ritual, he needs an altar, which consists of three parts, one in each of the three categories: upper, middle and lower.\n\nHe has N parts for each of the three categories. The size of the i-th upper part is A_i, the size of the i-th middle part is B_i, and the size of the i-th lower part is C_i.\n\nTo build an altar, the size of the middle part must be strictly greater than that of the upper part, and the size of the lower part must be strictly greater than that of the middle part. On the other hand, any three parts that satisfy these conditions can be combined to form an altar.\n\nHow many different altars can Ringo build? Here, two altars are considered different when at least one of the three parts used is different.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq A_i \\leq 10^9(1\\leq i\\leq N)\n\n1 \\leq B_i \\leq 10^9(1\\leq i\\leq N)\n\n1 \\leq C_i \\leq 10^9(1\\leq i\\leq N)\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 ... A_N\nB_1 ... B_N\nC_1 ... C_N\n\nOutput\n\nPrint the number of different altars that Ringo can build.\n\nSample Input 1\n\n2\n1 5\n2 4\n3 6\n\nSample Output 1\n\n3\n\nThe following three altars can be built:\n\nUpper: 1-st part, Middle: 1-st part, Lower: 1-st part\n\nUpper: 1-st part, Middle: 1-st part, Lower: 2-nd part\n\nUpper: 1-st part, Middle: 2-nd part, Lower: 2-nd part\n\nSample Input 2\n\n3\n1 1 1\n2 2 2\n3 3 3\n\nSample Output 2\n\n27\n\nSample Input 3\n\n6\n3 14 159 2 6 53\n58 9 79 323 84 6\n2643 383 2 79 50 288\n\nSample Output 3\n\n87", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 597, "cpu_time_ms": 150, "memory_kb": 1408}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s876370717", "group_id": "codeNet:p03557", "input_text": "#include <bits/stdc++.h>\n\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> P;\n\nll N;\nll A[100005], B[100005], C[100005];\n\nint main() {\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\n\tcin >> N;\n\n\tfor (int i = 0;i < N;i++){\n\t\tcin >> A[i];\n\t}\n\tfor (int i = 0;i < N;i++){\n\t\tcin >> B[i];\n\t}\n\tfor (int i = 0;i < N;i++){\n\t\tcin >> C[i];\n\t}\n\n\tsort(A,A+N); sort(C,C+N);\n\n\tll ans = 0;\n\n\tfor (int i = 0;i < N;i++){\n\t\tll nA = lower_bound(A,A+N,B[i])-A;\n\t\tll nC = C+N-upper_bound(C,C+N,B[i]);\n\t\tans += nA*nC;\n\t}\n\n\tcout << ans << endl;\n\n\treturn 0;\n\n}\n", "language": "C++", "metadata": {"date": 1554418156, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03557.html", "problem_id": "p03557", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03557/input.txt", "sample_output_relpath": "derived/input_output/data/p03557/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03557/C++/s876370717.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s876370717", "user_id": "u140450365"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> P;\n\nll N;\nll A[100005], B[100005], C[100005];\n\nint main() {\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\n\tcin >> N;\n\n\tfor (int i = 0;i < N;i++){\n\t\tcin >> A[i];\n\t}\n\tfor (int i = 0;i < N;i++){\n\t\tcin >> B[i];\n\t}\n\tfor (int i = 0;i < N;i++){\n\t\tcin >> C[i];\n\t}\n\n\tsort(A,A+N); sort(C,C+N);\n\n\tll ans = 0;\n\n\tfor (int i = 0;i < N;i++){\n\t\tll nA = lower_bound(A,A+N,B[i])-A;\n\t\tll nC = C+N-upper_bound(C,C+N,B[i]);\n\t\tans += nA*nC;\n\t}\n\n\tcout << ans << endl;\n\n\treturn 0;\n\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThe season for Snuke Festival has come again this year. First of all, Ringo will perform a ritual to summon Snuke. For the ritual, he needs an altar, which consists of three parts, one in each of the three categories: upper, middle and lower.\n\nHe has N parts for each of the three categories. The size of the i-th upper part is A_i, the size of the i-th middle part is B_i, and the size of the i-th lower part is C_i.\n\nTo build an altar, the size of the middle part must be strictly greater than that of the upper part, and the size of the lower part must be strictly greater than that of the middle part. On the other hand, any three parts that satisfy these conditions can be combined to form an altar.\n\nHow many different altars can Ringo build? Here, two altars are considered different when at least one of the three parts used is different.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq A_i \\leq 10^9(1\\leq i\\leq N)\n\n1 \\leq B_i \\leq 10^9(1\\leq i\\leq N)\n\n1 \\leq C_i \\leq 10^9(1\\leq i\\leq N)\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 ... A_N\nB_1 ... B_N\nC_1 ... C_N\n\nOutput\n\nPrint the number of different altars that Ringo can build.\n\nSample Input 1\n\n2\n1 5\n2 4\n3 6\n\nSample Output 1\n\n3\n\nThe following three altars can be built:\n\nUpper: 1-st part, Middle: 1-st part, Lower: 1-st part\n\nUpper: 1-st part, Middle: 1-st part, Lower: 2-nd part\n\nUpper: 1-st part, Middle: 2-nd part, Lower: 2-nd part\n\nSample Input 2\n\n3\n1 1 1\n2 2 2\n3 3 3\n\nSample Output 2\n\n27\n\nSample Input 3\n\n6\n3 14 159 2 6 53\n58 9 79 323 84 6\n2643 383 2 79 50 288\n\nSample Output 3\n\n87", "sample_input": "2\n1 5\n2 4\n3 6\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03557", "source_text": "Score : 300 points\n\nProblem Statement\n\nThe season for Snuke Festival has come again this year. First of all, Ringo will perform a ritual to summon Snuke. For the ritual, he needs an altar, which consists of three parts, one in each of the three categories: upper, middle and lower.\n\nHe has N parts for each of the three categories. The size of the i-th upper part is A_i, the size of the i-th middle part is B_i, and the size of the i-th lower part is C_i.\n\nTo build an altar, the size of the middle part must be strictly greater than that of the upper part, and the size of the lower part must be strictly greater than that of the middle part. On the other hand, any three parts that satisfy these conditions can be combined to form an altar.\n\nHow many different altars can Ringo build? Here, two altars are considered different when at least one of the three parts used is different.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq A_i \\leq 10^9(1\\leq i\\leq N)\n\n1 \\leq B_i \\leq 10^9(1\\leq i\\leq N)\n\n1 \\leq C_i \\leq 10^9(1\\leq i\\leq N)\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 ... A_N\nB_1 ... B_N\nC_1 ... C_N\n\nOutput\n\nPrint the number of different altars that Ringo can build.\n\nSample Input 1\n\n2\n1 5\n2 4\n3 6\n\nSample Output 1\n\n3\n\nThe following three altars can be built:\n\nUpper: 1-st part, Middle: 1-st part, Lower: 1-st part\n\nUpper: 1-st part, Middle: 1-st part, Lower: 2-nd part\n\nUpper: 1-st part, Middle: 2-nd part, Lower: 2-nd part\n\nSample Input 2\n\n3\n1 1 1\n2 2 2\n3 3 3\n\nSample Output 2\n\n27\n\nSample Input 3\n\n6\n3 14 159 2 6 53\n58 9 79 323 84 6\n2643 383 2 79 50 288\n\nSample Output 3\n\n87", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 549, "cpu_time_ms": 67, "memory_kb": 2560}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s967946544", "group_id": "codeNet:p03560", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint flg[100009] = {};\n\nint main(){\n\t\n\tint k;\n\tcin>>k;\n\tdeque<int>DQ;\n\tDQ.push_back(1);\n\tflg[1]=1;\n\twhile(1){\n\t\tdeque<int>::iterator it = DQ.begin();\n\t\tint tmp = *it;\n\t\tDQ.pop_front();\n\t\t\n\t\tif(tmp%k==0){\n\t\t\tcout<<flg[tmp%k]<<endl;\n\t\t\treturn 0;\n\t\t}\n\t\t\n\t\tif(flg[(tmp+1)%k]==0){\n\t\t\tDQ.push_back((tmp+1)%k);\n\t\t\tflg[(tmp+1)%k]=flg[tmp] + 1;\n\t\t}\n\t\tif(flg[(tmp*10)%k]==0){\n\t\t\tDQ.push_front((tmp*10)%k);\n\t\t\tflg[(tmp*10)%k]=flg[tmp];\n\t\t}\n\t\t\n\t}\n\t\n\t\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1510437808, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03560.html", "problem_id": "p03560", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03560/input.txt", "sample_output_relpath": "derived/input_output/data/p03560/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03560/C++/s967946544.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s967946544", "user_id": "u480892088"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint flg[100009] = {};\n\nint main(){\n\t\n\tint k;\n\tcin>>k;\n\tdeque<int>DQ;\n\tDQ.push_back(1);\n\tflg[1]=1;\n\twhile(1){\n\t\tdeque<int>::iterator it = DQ.begin();\n\t\tint tmp = *it;\n\t\tDQ.pop_front();\n\t\t\n\t\tif(tmp%k==0){\n\t\t\tcout<<flg[tmp%k]<<endl;\n\t\t\treturn 0;\n\t\t}\n\t\t\n\t\tif(flg[(tmp+1)%k]==0){\n\t\t\tDQ.push_back((tmp+1)%k);\n\t\t\tflg[(tmp+1)%k]=flg[tmp] + 1;\n\t\t}\n\t\tif(flg[(tmp*10)%k]==0){\n\t\t\tDQ.push_front((tmp*10)%k);\n\t\t\tflg[(tmp*10)%k]=flg[tmp];\n\t\t}\n\t\t\n\t}\n\t\n\t\n\treturn 0;\n}\n", "problem_context": "Score : 700 points\n\nProblem Statement\n\nFind the smallest possible sum of the digits in the decimal notation of a positive multiple of K.\n\nConstraints\n\n2 \\leq K \\leq 10^5\n\nK is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nK\n\nOutput\n\nPrint the smallest possible sum of the digits in the decimal notation of a positive multiple of K.\n\nSample Input 1\n\n6\n\nSample Output 1\n\n3\n\n12=6×2 yields the smallest sum.\n\nSample Input 2\n\n41\n\nSample Output 2\n\n5\n\n11111=41×271 yields the smallest sum.\n\nSample Input 3\n\n79992\n\nSample Output 3\n\n36", "sample_input": "6\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03560", "source_text": "Score : 700 points\n\nProblem Statement\n\nFind the smallest possible sum of the digits in the decimal notation of a positive multiple of K.\n\nConstraints\n\n2 \\leq K \\leq 10^5\n\nK is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nK\n\nOutput\n\nPrint the smallest possible sum of the digits in the decimal notation of a positive multiple of K.\n\nSample Input 1\n\n6\n\nSample Output 1\n\n3\n\n12=6×2 yields the smallest sum.\n\nSample Input 2\n\n41\n\nSample Output 2\n\n5\n\n11111=41×271 yields the smallest sum.\n\nSample Input 3\n\n79992\n\nSample Output 3\n\n36", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 498, "cpu_time_ms": 3, "memory_kb": 896}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s554293782", "group_id": "codeNet:p03561", "input_text": "#include<bits/stdc++.h>\n#define rep(i,a,b) for (int i=(a); i<=(b); i++)\nusing namespace std;\n\nconst int maxn = 300005;\nint a[maxn], top, n, K;\n\nint main() {\n\tscanf(\"%d%d\", &K, &n);\n\tif (!(K&1)) {\n\t\tprintf(\"%d \", K / 2);\n\t\trep (i, 2, n) printf(\"%d \", K / 2 + 1);\n\t\treturn 0;\n\t}\n\trep (i, 1, n) a[i] = (K + 1) / 2;\n\ttop = n;\n\trep (i, 1, n / 2)\n\t\tif (a[top] == 1) top--;\n\t\telse {\n\t\t\ta[top]--;\n\t\t\twhile (top < n) a[++top] = K;\n\t\t}\n\trep (i, 1, top) printf(\"%d \", a[i]);\n\t\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1529419184, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03561.html", "problem_id": "p03561", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03561/input.txt", "sample_output_relpath": "derived/input_output/data/p03561/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03561/C++/s554293782.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s554293782", "user_id": "u603486542"}, "prompt_components": {"gold_output": "2 1\n", "input_to_evaluate": "#include<bits/stdc++.h>\n#define rep(i,a,b) for (int i=(a); i<=(b); i++)\nusing namespace std;\n\nconst int maxn = 300005;\nint a[maxn], top, n, K;\n\nint main() {\n\tscanf(\"%d%d\", &K, &n);\n\tif (!(K&1)) {\n\t\tprintf(\"%d \", K / 2);\n\t\trep (i, 2, n) printf(\"%d \", K / 2 + 1);\n\t\treturn 0;\n\t}\n\trep (i, 1, n) a[i] = (K + 1) / 2;\n\ttop = n;\n\trep (i, 1, n / 2)\n\t\tif (a[top] == 1) top--;\n\t\telse {\n\t\t\ta[top]--;\n\t\t\twhile (top < n) a[++top] = K;\n\t\t}\n\trep (i, 1, top) printf(\"%d \", a[i]);\n\t\n\treturn 0;\n}", "problem_context": "Score : 800 points\n\nProblem Statement\n\nIn Finite Encyclopedia of Integer Sequences (FEIS), all integer sequences of lengths between 1 and N (inclusive) consisting of integers between 1 and K (inclusive) are listed.\n\nLet the total number of sequences listed in FEIS be X. Among those sequences, find the (X/2)-th (rounded up to the nearest integer) lexicographically smallest one.\n\nConstraints\n\n1 \\leq N,K \\leq 3 × 10^5\n\nN and K are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nK N\n\nOutput\n\nPrint the (X/2)-th (rounded up to the nearest integer) lexicographically smallest sequence listed in FEIS, with spaces in between, where X is the total number of sequences listed in FEIS.\n\nSample Input 1\n\n3 2\n\nSample Output 1\n\n2 1\n\nThere are 12 sequences listed in FEIS: (1),(1,1),(1,2),(1,3),(2),(2,1),(2,2),(2,3),(3),(3,1),(3,2),(3,3).\nThe (12/2 = 6)-th lexicographically smallest one among them is (2,1).\n\nSample Input 2\n\n2 4\n\nSample Output 2\n\n1 2 2 2\n\nSample Input 3\n\n5 14\n\nSample Output 3\n\n3 3 3 3 3 3 3 3 3 3 3 3 2 2", "sample_input": "3 2\n"}, "reference_outputs": ["2 1\n"], "source_document_id": "p03561", "source_text": "Score : 800 points\n\nProblem Statement\n\nIn Finite Encyclopedia of Integer Sequences (FEIS), all integer sequences of lengths between 1 and N (inclusive) consisting of integers between 1 and K (inclusive) are listed.\n\nLet the total number of sequences listed in FEIS be X. Among those sequences, find the (X/2)-th (rounded up to the nearest integer) lexicographically smallest one.\n\nConstraints\n\n1 \\leq N,K \\leq 3 × 10^5\n\nN and K are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nK N\n\nOutput\n\nPrint the (X/2)-th (rounded up to the nearest integer) lexicographically smallest sequence listed in FEIS, with spaces in between, where X is the total number of sequences listed in FEIS.\n\nSample Input 1\n\n3 2\n\nSample Output 1\n\n2 1\n\nThere are 12 sequences listed in FEIS: (1),(1,1),(1,2),(1,3),(2),(2,1),(2,2),(2,3),(3),(3,1),(3,2),(3,3).\nThe (12/2 = 6)-th lexicographically smallest one among them is (2,1).\n\nSample Input 2\n\n2 4\n\nSample Output 2\n\n1 2 2 2\n\nSample Input 3\n\n5 14\n\nSample Output 3\n\n3 3 3 3 3 3 3 3 3 3 3 3 2 2", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 478, "cpu_time_ms": 27, "memory_kb": 3456}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s747051689", "group_id": "codeNet:p03566", "input_text": "#include <bits/stdc++.h>\n#include <cmath>\n\n\n#include <assert.h>    // LON\n#include <math.h>    // sqrt()\n\n\nusing namespace std;\n#define rep(i, n) for (ll i = 0; i < (n); ++i)\n//#define rep(i, n) for (int i = 0; i < (n); ++i)\n#define sz(x) ll(x.size())\ntypedef long long ll;\n//typedef pair<int, int> P;\n//typedef pair<ll, ll> P;\n//const double INF = 1e10;\n//const ll INF = 10e15;\nconst ll MINF = -10e10;\nconst int INF = INT_MAX;\n#define cmin(x, y) x = min(x, y)\n#define cmax(x, y) x = max(x, y)\n\n\n//ifstream myfile(\"C:\\\\Users\\\\riku\\\\Downloads\\\\0_00.txt\");\n//ofstream outfile(\"log.txt\");\n//outfile << setw(6) << setfill('0') << prefecture << setw(6) << setfill('0') << rank << endl;\n// std::cout << std::bitset<8>(9);\n\n//typedef priority_queue<P, vector<P>, greater<P>> PQ_ASK;\nconst int mod = 1000000007;\n\nint main() {\n    ll n;\n    cin >> n;\n\n    vector<ll> over_lines;\n\n    {\n        vector<ll> ts(n);\n        vector<ll> vs(n);\n        rep(i, n) {\n            cin >> ts[i];\n        }\n        rep(i, n) {\n            cin >> vs[i];\n        }\n\n        ll ts_sum = 0;\n        for (ll i : ts) {\n            ts_sum += i;\n        }\n        over_lines.resize(ts_sum + 2, 0);\n\n        ll index = 1;\n        for (ll i = 0; i < n; i++) {\n            for (ll j = 0; j < ts[i]; j++) {\n                over_lines[index] = vs[i];\n                index++;\n            }\n        }\n\n    }\n    for (ll i = 1; i < over_lines.size(); i++) {\n        over_lines[i] = min(over_lines[i], over_lines[i - 1] + 1);\n    }\n\n    for (ll i = over_lines.size() - 2; i >= 0; i--) {\n        over_lines[i] = min(over_lines[i], over_lines[i + 1] + 1);\n    }\n\n    ll ans = 0;\n\n    for (ll i = 1; i < over_lines.size() - 1; i++) {\n        ll a = over_lines[i - 1];\n        ll b = over_lines[i];\n        ll c = over_lines[i + 1];\n        assert(b > 0);\n        assert(abs(a - b) <= 1);\n        assert(abs(b - c) <= 1);\n        if (a == b && b == c) {\n            ans += b * 100ll;\n        } else if (a > b && b < c) {\n            ans += b * 100ll;\n        } else if ((a > b && b == c) || (a == b && b < c)) {\n            ans += b * 100ll;\n        } else if ((a == b && b > c) || (a < b && b == c)) {\n            ans += ((b - 1) * 100ll) + 50;\n        } else if (a < b && b > c) {\n            ans += ((b - 1) * 100ll) + 25;\n        } else if ((a < b && b < c) || (a > b && b > c)) {\n            ans += ((b - 1) * 100ll) + 50;\n        } else {\n            assert(false);\n        }\n    }\n\n    cout << setprecision(10) << ((long double) ans) / 100 << endl;\n}\n", "language": "C++", "metadata": {"date": 1576735901, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03566.html", "problem_id": "p03566", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03566/input.txt", "sample_output_relpath": "derived/input_output/data/p03566/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03566/C++/s747051689.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s747051689", "user_id": "u564182781"}, "prompt_components": {"gold_output": "2100.000000000000000\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#include <cmath>\n\n\n#include <assert.h>    // LON\n#include <math.h>    // sqrt()\n\n\nusing namespace std;\n#define rep(i, n) for (ll i = 0; i < (n); ++i)\n//#define rep(i, n) for (int i = 0; i < (n); ++i)\n#define sz(x) ll(x.size())\ntypedef long long ll;\n//typedef pair<int, int> P;\n//typedef pair<ll, ll> P;\n//const double INF = 1e10;\n//const ll INF = 10e15;\nconst ll MINF = -10e10;\nconst int INF = INT_MAX;\n#define cmin(x, y) x = min(x, y)\n#define cmax(x, y) x = max(x, y)\n\n\n//ifstream myfile(\"C:\\\\Users\\\\riku\\\\Downloads\\\\0_00.txt\");\n//ofstream outfile(\"log.txt\");\n//outfile << setw(6) << setfill('0') << prefecture << setw(6) << setfill('0') << rank << endl;\n// std::cout << std::bitset<8>(9);\n\n//typedef priority_queue<P, vector<P>, greater<P>> PQ_ASK;\nconst int mod = 1000000007;\n\nint main() {\n    ll n;\n    cin >> n;\n\n    vector<ll> over_lines;\n\n    {\n        vector<ll> ts(n);\n        vector<ll> vs(n);\n        rep(i, n) {\n            cin >> ts[i];\n        }\n        rep(i, n) {\n            cin >> vs[i];\n        }\n\n        ll ts_sum = 0;\n        for (ll i : ts) {\n            ts_sum += i;\n        }\n        over_lines.resize(ts_sum + 2, 0);\n\n        ll index = 1;\n        for (ll i = 0; i < n; i++) {\n            for (ll j = 0; j < ts[i]; j++) {\n                over_lines[index] = vs[i];\n                index++;\n            }\n        }\n\n    }\n    for (ll i = 1; i < over_lines.size(); i++) {\n        over_lines[i] = min(over_lines[i], over_lines[i - 1] + 1);\n    }\n\n    for (ll i = over_lines.size() - 2; i >= 0; i--) {\n        over_lines[i] = min(over_lines[i], over_lines[i + 1] + 1);\n    }\n\n    ll ans = 0;\n\n    for (ll i = 1; i < over_lines.size() - 1; i++) {\n        ll a = over_lines[i - 1];\n        ll b = over_lines[i];\n        ll c = over_lines[i + 1];\n        assert(b > 0);\n        assert(abs(a - b) <= 1);\n        assert(abs(b - c) <= 1);\n        if (a == b && b == c) {\n            ans += b * 100ll;\n        } else if (a > b && b < c) {\n            ans += b * 100ll;\n        } else if ((a > b && b == c) || (a == b && b < c)) {\n            ans += b * 100ll;\n        } else if ((a == b && b > c) || (a < b && b == c)) {\n            ans += ((b - 1) * 100ll) + 50;\n        } else if (a < b && b > c) {\n            ans += ((b - 1) * 100ll) + 25;\n        } else if ((a < b && b < c) || (a > b && b > c)) {\n            ans += ((b - 1) * 100ll) + 50;\n        } else {\n            assert(false);\n        }\n    }\n\n    cout << setprecision(10) << ((long double) ans) / 100 << endl;\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nIn the year 2168, AtCoder Inc., which is much larger than now, is starting a limited express train service called AtCoder Express.\n\nIn the plan developed by the president Takahashi, the trains will run as follows:\n\nA train will run for (t_1 + t_2 + t_3 + ... + t_N) seconds.\n\nIn the first t_1 seconds, a train must run at a speed of at most v_1 m/s (meters per second). Similarly, in the subsequent t_2 seconds, a train must run at a speed of at most v_2 m/s, and so on.\n\nAccording to the specifications of the trains, the acceleration of a train must be always within ±1m/s^2. Additionally, a train must stop at the beginning and the end of the run.\n\nFind the maximum possible distance that a train can cover in the run.\n\nConstraints\n\n1 \\leq N \\leq 100\n\n1 \\leq t_i \\leq 200\n\n1 \\leq v_i \\leq 100\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nt_1 t_2 t_3 … t_N\nv_1 v_2 v_3 … v_N\n\nOutput\n\nPrint the maximum possible that a train can cover in the run.\n\nOutput is considered correct if its absolute difference from the judge's output is at most 10^{-3}.\n\nSample Input 1\n\n1\n100\n30\n\nSample Output 1\n\n2100.000000000000000\n\nThe maximum distance is achieved when a train runs as follows:\n\nIn the first 30 seconds, it accelerates at a rate of 1m/s^2, covering 450 meters.\n\nIn the subsequent 40 seconds, it maintains the velocity of 30m/s, covering 1200 meters.\n\nIn the last 30 seconds, it decelerates at the acceleration of -1m/s^2, covering 450 meters.\n\nThe total distance covered is 450 + 1200 + 450 = 2100 meters.\n\nSample Input 2\n\n2\n60 50\n34 38\n\nSample Output 2\n\n2632.000000000000000\n\nThe maximum distance is achieved when a train runs as follows:\n\nIn the first 34 seconds, it accelerates at a rate of 1m/s^2, covering 578 meters.\n\nIn the subsequent 26 seconds, it maintains the velocity of 34m/s, covering 884 meters.\n\nIn the subsequent 4 seconds, it accelerates at a rate of 1m/s^2, covering 144 meters.\n\nIn the subsequent 8 seconds, it maintains the velocity of 38m/s, covering 304 meters.\n\nIn the last 38 seconds, it decelerates at the acceleration of -1m/s^2, covering 722 meters.\n\nThe total distance covered is 578 + 884 + 144 + 304 + 722 = 2632 meters.\n\nSample Input 3\n\n3\n12 14 2\n6 2 7\n\nSample Output 3\n\n76.000000000000000\n\nThe maximum distance is achieved when a train runs as follows:\n\nIn the first 6 seconds, it accelerates at a rate of 1m/s^2, covering 18 meters.\n\nIn the subsequent 2 seconds, it maintains the velocity of 6m/s, covering 12 meters.\n\nIn the subsequent 4 seconds, it decelerates at the acceleration of -1m/s^2, covering 16 meters.\n\nIn the subsequent 14 seconds, it maintains the velocity of 2m/s, covering 28 meters.\n\nIn the last 2 seconds, it decelerates at the acceleration of -1m/s^2, covering 2 meters.\n\nThe total distance covered is 18 + 12 + 16 + 28 + 2 = 76 meters.\n\nSample Input 4\n\n1\n9\n10\n\nSample Output 4\n\n20.250000000000000000\n\nThe maximum distance is achieved when a train runs as follows:\n\nIn the first 4.5 seconds, it accelerates at a rate of 1m/s^2, covering 10.125 meters.\n\nIn the last 4.5 seconds, it decelerates at the acceleration of -1m/s^2, covering 10.125 meters.\n\nThe total distance covered is 10.125 + 10.125 = 20.25 meters.\n\nSample Input 5\n\n10\n64 55 27 35 76 119 7 18 49 100\n29 19 31 39 27 48 41 87 55 70\n\nSample Output 5\n\n20291.000000000000", "sample_input": "1\n100\n30\n"}, "reference_outputs": ["2100.000000000000000\n"], "source_document_id": "p03566", "source_text": "Score : 400 points\n\nProblem Statement\n\nIn the year 2168, AtCoder Inc., which is much larger than now, is starting a limited express train service called AtCoder Express.\n\nIn the plan developed by the president Takahashi, the trains will run as follows:\n\nA train will run for (t_1 + t_2 + t_3 + ... + t_N) seconds.\n\nIn the first t_1 seconds, a train must run at a speed of at most v_1 m/s (meters per second). Similarly, in the subsequent t_2 seconds, a train must run at a speed of at most v_2 m/s, and so on.\n\nAccording to the specifications of the trains, the acceleration of a train must be always within ±1m/s^2. Additionally, a train must stop at the beginning and the end of the run.\n\nFind the maximum possible distance that a train can cover in the run.\n\nConstraints\n\n1 \\leq N \\leq 100\n\n1 \\leq t_i \\leq 200\n\n1 \\leq v_i \\leq 100\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nt_1 t_2 t_3 … t_N\nv_1 v_2 v_3 … v_N\n\nOutput\n\nPrint the maximum possible that a train can cover in the run.\n\nOutput is considered correct if its absolute difference from the judge's output is at most 10^{-3}.\n\nSample Input 1\n\n1\n100\n30\n\nSample Output 1\n\n2100.000000000000000\n\nThe maximum distance is achieved when a train runs as follows:\n\nIn the first 30 seconds, it accelerates at a rate of 1m/s^2, covering 450 meters.\n\nIn the subsequent 40 seconds, it maintains the velocity of 30m/s, covering 1200 meters.\n\nIn the last 30 seconds, it decelerates at the acceleration of -1m/s^2, covering 450 meters.\n\nThe total distance covered is 450 + 1200 + 450 = 2100 meters.\n\nSample Input 2\n\n2\n60 50\n34 38\n\nSample Output 2\n\n2632.000000000000000\n\nThe maximum distance is achieved when a train runs as follows:\n\nIn the first 34 seconds, it accelerates at a rate of 1m/s^2, covering 578 meters.\n\nIn the subsequent 26 seconds, it maintains the velocity of 34m/s, covering 884 meters.\n\nIn the subsequent 4 seconds, it accelerates at a rate of 1m/s^2, covering 144 meters.\n\nIn the subsequent 8 seconds, it maintains the velocity of 38m/s, covering 304 meters.\n\nIn the last 38 seconds, it decelerates at the acceleration of -1m/s^2, covering 722 meters.\n\nThe total distance covered is 578 + 884 + 144 + 304 + 722 = 2632 meters.\n\nSample Input 3\n\n3\n12 14 2\n6 2 7\n\nSample Output 3\n\n76.000000000000000\n\nThe maximum distance is achieved when a train runs as follows:\n\nIn the first 6 seconds, it accelerates at a rate of 1m/s^2, covering 18 meters.\n\nIn the subsequent 2 seconds, it maintains the velocity of 6m/s, covering 12 meters.\n\nIn the subsequent 4 seconds, it decelerates at the acceleration of -1m/s^2, covering 16 meters.\n\nIn the subsequent 14 seconds, it maintains the velocity of 2m/s, covering 28 meters.\n\nIn the last 2 seconds, it decelerates at the acceleration of -1m/s^2, covering 2 meters.\n\nThe total distance covered is 18 + 12 + 16 + 28 + 2 = 76 meters.\n\nSample Input 4\n\n1\n9\n10\n\nSample Output 4\n\n20.250000000000000000\n\nThe maximum distance is achieved when a train runs as follows:\n\nIn the first 4.5 seconds, it accelerates at a rate of 1m/s^2, covering 10.125 meters.\n\nIn the last 4.5 seconds, it decelerates at the acceleration of -1m/s^2, covering 10.125 meters.\n\nThe total distance covered is 10.125 + 10.125 = 20.25 meters.\n\nSample Input 5\n\n10\n64 55 27 35 76 119 7 18 49 100\n29 19 31 39 27 48 41 87 55 70\n\nSample Output 5\n\n20291.000000000000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2516, "cpu_time_ms": 2, "memory_kb": 384}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s870681383", "group_id": "codeNet:p03569", "input_text": "#include <bits/stdc++.h>\n\nusing namespace std;\ntypedef long long ll;\ntypedef vector<ll> vl;\ntypedef vector<string> vs;\nusing pll = pair<ll, ll>;\nusing vl = vector<ll>;\nusing vll = vector<vl>;\nusing vpll = vector<pll>;\nstruct Edge {\n\tll to;\n \tll cost;\n };\nusing Graph = vector<vector<Edge>>;\n\n#define FOR(i, a, b) for (ll i = (a); i < (b); i++)\n#define REP(i, n) FOR(i, 0, n)\n/***** define constant start *******/\nconst ll MOD = 1000000007;\nconst double PI = 3.1415926535897932;\nconst ll INF = LLONG_MAX;\nstring ch = {'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z'};\n/****** define constant end ********/\n/****** define variable start ******/\nstring s;\n/******* define variable end *******/\nint solve() {\n\tcin >> s;\n\tstring serasex = \"\";\n\tREP(i, s.size()){\n\t\tif(s.substr(i, 1) != \"x\"){\n\t\t\tserasex += s.substr(i, 1);\n\t\t}\n\t}\n\tll hanbun = serasex.size() / 2;\n\tbool flag = true;\n\tREP(i, hanbun){\n\t\tif(serasex.substr(i, 1) != serasex.substr(serasex.size() - 1 - i,1)){\n\t\t\tflag = false;\n\t\t}\n\t}\n\tll count = 0;\n\tll ite;\n\tll ite2;\n\tREP(i, s.size()){\n\t\tif(s.substr(i, 1) != \"x\"){\n\t\t\tcount++;\n\t\t\tif(count == ceil((long double)serasex.size()/2)){\n\t\t\t\tite = i;\n\t\t\t}\n\t\t}\n\t}\n\tcount = 0;\n\tif(serasex.size() % 2 == 0){\n\t\tREP(i, s.size()){\n\t\t\tif(s.substr(i, 1) != \"x\"){\n\t\t\t\tcount++;\n\t\t\t\tif(count == serasex.size()/2 + 1){\n\t\t\t\t\tite2 = i;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tif(!flag){\n\t\tcout << -1 << endl;\n\t}else{\n\t\tif(serasex.size() % 2 == 0){\n\t\t\tll ans = 0;\n\t\t\tbool flag2 = true;\n\t\t\tll i = ite;\n\t\t\tll j = ite2;\n\t\t\twhile(flag2){\n\t\t\t\tif(i < 0 && j >= s.size()){\n\t\t\t\t\tflag2 = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\tif(i < 0){\n\t\t\t\t\tans++;\n\t\t\t\t\tj++;\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\tif(j >= s.size()){\n\t\t\t\t\tans++;\n\t\t\t\t\ti--;\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\tif(s.substr(i, 1) != s.substr(j, 1)){\n\t\t\t\t\tans++;\n\t\t\t\t\tif(s.substr(i, 1) == \"x\"){\n\t\t\t\t\t\ti--;\n\t\t\t\t\t}else{\n\t\t\t\t\t\tj++;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\ti--;\n\t\t\t\tj++;\n\t\t\t}\n\t\t\tcout << ans << endl;\n\t\t}else{\n\t\t\tll ans = 0;\n\t\t\tbool flag2 = true;\n\t\t\tll i = ite-1;\n\t\t\tll j = ite+1;\n\t\t\twhile(flag2){\n\t\t\t\tif(i < 0 && j >= s.size()){\n\t\t\t\t\tflag2 = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\tif(i < 0){\n\t\t\t\t\tans++;\n\t\t\t\t\tj++;\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\tif(j >= s.size()){\n\t\t\t\t\tans++;\n\t\t\t\t\ti--;\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\tif(s.substr(i, 1) != s.substr(j, 1)){\n\t\t\t\t\tans++;\n\t\t\t\t\tif(s.substr(i, 1) == \"x\"){\n\t\t\t\t\t\ti--;\n\t\t\t\t\t}else{\n\t\t\t\t\t\tj++;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\ti--;\n\t\t\t\tj++;\n\t\t\t}\n\t\t\tcout << ans << endl;\n\t\t}\n\t}\n\treturn 0;\n}\n\nint main() {\n\t// clock_t start = clock();\n\tcout << std::fixed << std::setprecision(10);\n\tios::sync_with_stdio(false);\n\tcin.tie(nullptr);\n\tint end_solve = solve();\n\t/*\n\tclock_t end = clock();\n\tconst double time = static_cast<double>(end - start) / CLOCKS_PER_SEC *\n\t1000.0; printf(\"time %lf[ms]\\n\", time);\n\t*/\n\n\treturn end_solve;\n}\n", "language": "C++", "metadata": {"date": 1587780073, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03569.html", "problem_id": "p03569", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03569/input.txt", "sample_output_relpath": "derived/input_output/data/p03569/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03569/C++/s870681383.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s870681383", "user_id": "u313994303"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\nusing namespace std;\ntypedef long long ll;\ntypedef vector<ll> vl;\ntypedef vector<string> vs;\nusing pll = pair<ll, ll>;\nusing vl = vector<ll>;\nusing vll = vector<vl>;\nusing vpll = vector<pll>;\nstruct Edge {\n\tll to;\n \tll cost;\n };\nusing Graph = vector<vector<Edge>>;\n\n#define FOR(i, a, b) for (ll i = (a); i < (b); i++)\n#define REP(i, n) FOR(i, 0, n)\n/***** define constant start *******/\nconst ll MOD = 1000000007;\nconst double PI = 3.1415926535897932;\nconst ll INF = LLONG_MAX;\nstring ch = {'A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z'};\n/****** define constant end ********/\n/****** define variable start ******/\nstring s;\n/******* define variable end *******/\nint solve() {\n\tcin >> s;\n\tstring serasex = \"\";\n\tREP(i, s.size()){\n\t\tif(s.substr(i, 1) != \"x\"){\n\t\t\tserasex += s.substr(i, 1);\n\t\t}\n\t}\n\tll hanbun = serasex.size() / 2;\n\tbool flag = true;\n\tREP(i, hanbun){\n\t\tif(serasex.substr(i, 1) != serasex.substr(serasex.size() - 1 - i,1)){\n\t\t\tflag = false;\n\t\t}\n\t}\n\tll count = 0;\n\tll ite;\n\tll ite2;\n\tREP(i, s.size()){\n\t\tif(s.substr(i, 1) != \"x\"){\n\t\t\tcount++;\n\t\t\tif(count == ceil((long double)serasex.size()/2)){\n\t\t\t\tite = i;\n\t\t\t}\n\t\t}\n\t}\n\tcount = 0;\n\tif(serasex.size() % 2 == 0){\n\t\tREP(i, s.size()){\n\t\t\tif(s.substr(i, 1) != \"x\"){\n\t\t\t\tcount++;\n\t\t\t\tif(count == serasex.size()/2 + 1){\n\t\t\t\t\tite2 = i;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tif(!flag){\n\t\tcout << -1 << endl;\n\t}else{\n\t\tif(serasex.size() % 2 == 0){\n\t\t\tll ans = 0;\n\t\t\tbool flag2 = true;\n\t\t\tll i = ite;\n\t\t\tll j = ite2;\n\t\t\twhile(flag2){\n\t\t\t\tif(i < 0 && j >= s.size()){\n\t\t\t\t\tflag2 = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\tif(i < 0){\n\t\t\t\t\tans++;\n\t\t\t\t\tj++;\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\tif(j >= s.size()){\n\t\t\t\t\tans++;\n\t\t\t\t\ti--;\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\tif(s.substr(i, 1) != s.substr(j, 1)){\n\t\t\t\t\tans++;\n\t\t\t\t\tif(s.substr(i, 1) == \"x\"){\n\t\t\t\t\t\ti--;\n\t\t\t\t\t}else{\n\t\t\t\t\t\tj++;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\ti--;\n\t\t\t\tj++;\n\t\t\t}\n\t\t\tcout << ans << endl;\n\t\t}else{\n\t\t\tll ans = 0;\n\t\t\tbool flag2 = true;\n\t\t\tll i = ite-1;\n\t\t\tll j = ite+1;\n\t\t\twhile(flag2){\n\t\t\t\tif(i < 0 && j >= s.size()){\n\t\t\t\t\tflag2 = false;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t\tif(i < 0){\n\t\t\t\t\tans++;\n\t\t\t\t\tj++;\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\tif(j >= s.size()){\n\t\t\t\t\tans++;\n\t\t\t\t\ti--;\n\t\t\t\t\tcontinue;\n\t\t\t\t}\n\t\t\t\tif(s.substr(i, 1) != s.substr(j, 1)){\n\t\t\t\t\tans++;\n\t\t\t\t\tif(s.substr(i, 1) == \"x\"){\n\t\t\t\t\t\ti--;\n\t\t\t\t\t}else{\n\t\t\t\t\t\tj++;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\ti--;\n\t\t\t\tj++;\n\t\t\t}\n\t\t\tcout << ans << endl;\n\t\t}\n\t}\n\treturn 0;\n}\n\nint main() {\n\t// clock_t start = clock();\n\tcout << std::fixed << std::setprecision(10);\n\tios::sync_with_stdio(false);\n\tcin.tie(nullptr);\n\tint end_solve = solve();\n\t/*\n\tclock_t end = clock();\n\tconst double time = static_cast<double>(end - start) / CLOCKS_PER_SEC *\n\t1000.0; printf(\"time %lf[ms]\\n\", time);\n\t*/\n\n\treturn end_solve;\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nWe have a string s consisting of lowercase English letters.\nSnuke can perform the following operation repeatedly:\n\nInsert a letter x to any position in s of his choice, including the beginning and end of s.\n\nSnuke's objective is to turn s into a palindrome.\nDetermine whether the objective is achievable. If it is achievable, find the minimum number of operations required.\n\nNotes\n\nA palindrome is a string that reads the same forward and backward.\nFor example, a, aa, abba and abcba are palindromes, while ab, abab and abcda are not.\n\nConstraints\n\n1 \\leq |s| \\leq 10^5\n\ns consists of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\ns\n\nOutput\n\nIf the objective is achievable, print the number of operations required.\nIf it is not, print -1 instead.\n\nSample Input 1\n\nxabxa\n\nSample Output 1\n\n2\n\nOne solution is as follows (newly inserted x are shown in bold):\n\nxabxa → xaxbxa → xaxbxax\n\nSample Input 2\n\nab\n\nSample Output 2\n\n-1\n\nNo sequence of operations can turn s into a palindrome.\n\nSample Input 3\n\na\n\nSample Output 3\n\n0\n\ns is a palindrome already at the beginning.\n\nSample Input 4\n\noxxx\n\nSample Output 4\n\n3\n\nOne solution is as follows:\n\noxxx → xoxxx → xxoxxx → xxxoxxx", "sample_input": "xabxa\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03569", "source_text": "Score : 400 points\n\nProblem Statement\n\nWe have a string s consisting of lowercase English letters.\nSnuke can perform the following operation repeatedly:\n\nInsert a letter x to any position in s of his choice, including the beginning and end of s.\n\nSnuke's objective is to turn s into a palindrome.\nDetermine whether the objective is achievable. If it is achievable, find the minimum number of operations required.\n\nNotes\n\nA palindrome is a string that reads the same forward and backward.\nFor example, a, aa, abba and abcba are palindromes, while ab, abab and abcda are not.\n\nConstraints\n\n1 \\leq |s| \\leq 10^5\n\ns consists of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\ns\n\nOutput\n\nIf the objective is achievable, print the number of operations required.\nIf it is not, print -1 instead.\n\nSample Input 1\n\nxabxa\n\nSample Output 1\n\n2\n\nOne solution is as follows (newly inserted x are shown in bold):\n\nxabxa → xaxbxa → xaxbxax\n\nSample Input 2\n\nab\n\nSample Output 2\n\n-1\n\nNo sequence of operations can turn s into a palindrome.\n\nSample Input 3\n\na\n\nSample Output 3\n\n0\n\ns is a palindrome already at the beginning.\n\nSample Input 4\n\noxxx\n\nSample Output 4\n\n3\n\nOne solution is as follows:\n\noxxx → xoxxx → xxoxxx → xxxoxxx", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2748, "cpu_time_ms": 31, "memory_kb": 592}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s518097881", "group_id": "codeNet:p03569", "input_text": "#include<bits/stdc++.h>\n#define For(i,a,b) for(i=(a);i<=(b);++i)\n#define Forward(i,a,b) for(i=(a);i>=(b);--i)\nusing namespace std;\ntemplate<typename T>inline void read(T &x)\n{\n\tT s=0,f=1;char k=getchar();\n\twhile(!isdigit(k)&&(k^'-'))k=getchar();\n\tif(!isdigit(k)){f=-1;k=getchar();}\n\twhile(isdigit(k)){s=s*10+(k^48);k=getchar();}\n\tx=s*f;\n}\nvoid file()\n{\n\t#ifndef ONLINE_JUDGE\n\tfreopen(\"a.in\",\"r\",stdin);\n\tfreopen(\"a.out\",\"w\",stdout);\n\t#endif\n}\nconst int MAXN=700010;\nint n,ans;\nchar a[MAXN];\nint main()\n{\n\tscanf(\"%s\",a);\n\tn=strlen(a)-1;\n\tint i=0,j=n,ans=0;\n\twhile(i<j)\n\t{\n\t\tint k=0,lj=j;\n\t\twhile(a[i]=='x'&&i<=n)++i,++k;\n\t\twhile(a[j]=='x'&&j>=i)--j,--k;\n\t\tif(i>j&&j==lj)break;\n\t\tans+=abs(k);\n\t\tif(i>j)break;\n\t\tif(a[i]!=a[j])\n\t\t{\n\t\t\tprintf(\"-1\\n\");\n\t\t\treturn 0;\n\t\t}\n\t\t++i;--j;\n\t\tif(i>j)break;\n\t}\n\tprintf(\"%d\\n\",ans);\n\treturn 0;\n}\n\n", "language": "C++", "metadata": {"date": 1508722036, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03569.html", "problem_id": "p03569", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03569/input.txt", "sample_output_relpath": "derived/input_output/data/p03569/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03569/C++/s518097881.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s518097881", "user_id": "u161060557"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include<bits/stdc++.h>\n#define For(i,a,b) for(i=(a);i<=(b);++i)\n#define Forward(i,a,b) for(i=(a);i>=(b);--i)\nusing namespace std;\ntemplate<typename T>inline void read(T &x)\n{\n\tT s=0,f=1;char k=getchar();\n\twhile(!isdigit(k)&&(k^'-'))k=getchar();\n\tif(!isdigit(k)){f=-1;k=getchar();}\n\twhile(isdigit(k)){s=s*10+(k^48);k=getchar();}\n\tx=s*f;\n}\nvoid file()\n{\n\t#ifndef ONLINE_JUDGE\n\tfreopen(\"a.in\",\"r\",stdin);\n\tfreopen(\"a.out\",\"w\",stdout);\n\t#endif\n}\nconst int MAXN=700010;\nint n,ans;\nchar a[MAXN];\nint main()\n{\n\tscanf(\"%s\",a);\n\tn=strlen(a)-1;\n\tint i=0,j=n,ans=0;\n\twhile(i<j)\n\t{\n\t\tint k=0,lj=j;\n\t\twhile(a[i]=='x'&&i<=n)++i,++k;\n\t\twhile(a[j]=='x'&&j>=i)--j,--k;\n\t\tif(i>j&&j==lj)break;\n\t\tans+=abs(k);\n\t\tif(i>j)break;\n\t\tif(a[i]!=a[j])\n\t\t{\n\t\t\tprintf(\"-1\\n\");\n\t\t\treturn 0;\n\t\t}\n\t\t++i;--j;\n\t\tif(i>j)break;\n\t}\n\tprintf(\"%d\\n\",ans);\n\treturn 0;\n}\n\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nWe have a string s consisting of lowercase English letters.\nSnuke can perform the following operation repeatedly:\n\nInsert a letter x to any position in s of his choice, including the beginning and end of s.\n\nSnuke's objective is to turn s into a palindrome.\nDetermine whether the objective is achievable. If it is achievable, find the minimum number of operations required.\n\nNotes\n\nA palindrome is a string that reads the same forward and backward.\nFor example, a, aa, abba and abcba are palindromes, while ab, abab and abcda are not.\n\nConstraints\n\n1 \\leq |s| \\leq 10^5\n\ns consists of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\ns\n\nOutput\n\nIf the objective is achievable, print the number of operations required.\nIf it is not, print -1 instead.\n\nSample Input 1\n\nxabxa\n\nSample Output 1\n\n2\n\nOne solution is as follows (newly inserted x are shown in bold):\n\nxabxa → xaxbxa → xaxbxax\n\nSample Input 2\n\nab\n\nSample Output 2\n\n-1\n\nNo sequence of operations can turn s into a palindrome.\n\nSample Input 3\n\na\n\nSample Output 3\n\n0\n\ns is a palindrome already at the beginning.\n\nSample Input 4\n\noxxx\n\nSample Output 4\n\n3\n\nOne solution is as follows:\n\noxxx → xoxxx → xxoxxx → xxxoxxx", "sample_input": "xabxa\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03569", "source_text": "Score : 400 points\n\nProblem Statement\n\nWe have a string s consisting of lowercase English letters.\nSnuke can perform the following operation repeatedly:\n\nInsert a letter x to any position in s of his choice, including the beginning and end of s.\n\nSnuke's objective is to turn s into a palindrome.\nDetermine whether the objective is achievable. If it is achievable, find the minimum number of operations required.\n\nNotes\n\nA palindrome is a string that reads the same forward and backward.\nFor example, a, aa, abba and abcba are palindromes, while ab, abab and abcda are not.\n\nConstraints\n\n1 \\leq |s| \\leq 10^5\n\ns consists of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\ns\n\nOutput\n\nIf the objective is achievable, print the number of operations required.\nIf it is not, print -1 instead.\n\nSample Input 1\n\nxabxa\n\nSample Output 1\n\n2\n\nOne solution is as follows (newly inserted x are shown in bold):\n\nxabxa → xaxbxa → xaxbxax\n\nSample Input 2\n\nab\n\nSample Output 2\n\n-1\n\nNo sequence of operations can turn s into a palindrome.\n\nSample Input 3\n\na\n\nSample Output 3\n\n0\n\ns is a palindrome already at the beginning.\n\nSample Input 4\n\noxxx\n\nSample Output 4\n\n3\n\nOne solution is as follows:\n\noxxx → xoxxx → xxoxxx → xxxoxxx", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 829, "cpu_time_ms": 2, "memory_kb": 384}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s289508263", "group_id": "codeNet:p03573", "input_text": "#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <utility>\nusing namespace std;\ntypedef long long ll;\n#define rep(i, n) for (int i=0;i < (int)(n);i++)\n\nint main(){\n   int a,b,c;\n   string s;\n   cin >> a >> b >> c;\n   if (a+b == 2*a) cout << c<< endl;\n   else if (a+c == a*2) cout << b << endl;\n   else if (b+c == c*2) cout << a << endl;\n   \n   \n   return 0;\n   \n}\n\n", "language": "C++", "metadata": {"date": 1588710374, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03573.html", "problem_id": "p03573", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03573/input.txt", "sample_output_relpath": "derived/input_output/data/p03573/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03573/C++/s289508263.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s289508263", "user_id": "u657208344"}, "prompt_components": {"gold_output": "7\n", "input_to_evaluate": "#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <utility>\nusing namespace std;\ntypedef long long ll;\n#define rep(i, n) for (int i=0;i < (int)(n);i++)\n\nint main(){\n   int a,b,c;\n   string s;\n   cin >> a >> b >> c;\n   if (a+b == 2*a) cout << c<< endl;\n   else if (a+c == a*2) cout << b << endl;\n   else if (b+c == c*2) cout << a << endl;\n   \n   \n   return 0;\n   \n}\n\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nYou are given three integers, A, B and C.\n\nAmong them, two are the same, but the remaining one is different from the rest.\n\nFor example, when A=5,B=7,C=5, A and C are the same, but B is different.\n\nFind the one that is different from the rest among the given three integers.\n\nConstraints\n\n-100 \\leq A,B,C \\leq 100\n\nA, B and C are integers.\n\nThe input satisfies the condition in the statement.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B C\n\nOutput\n\nAmong A, B and C, print the integer that is different from the rest.\n\nSample Input 1\n\n5 7 5\n\nSample Output 1\n\n7\n\nThis is the same case as the one in the statement.\n\nSample Input 2\n\n1 1 7\n\nSample Output 2\n\n7\n\nIn this case, C is the one we seek.\n\nSample Input 3\n\n-100 100 100\n\nSample Output 3\n\n-100", "sample_input": "5 7 5\n"}, "reference_outputs": ["7\n"], "source_document_id": "p03573", "source_text": "Score : 100 points\n\nProblem Statement\n\nYou are given three integers, A, B and C.\n\nAmong them, two are the same, but the remaining one is different from the rest.\n\nFor example, when A=5,B=7,C=5, A and C are the same, but B is different.\n\nFind the one that is different from the rest among the given three integers.\n\nConstraints\n\n-100 \\leq A,B,C \\leq 100\n\nA, B and C are integers.\n\nThe input satisfies the condition in the statement.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B C\n\nOutput\n\nAmong A, B and C, print the integer that is different from the rest.\n\nSample Input 1\n\n5 7 5\n\nSample Output 1\n\n7\n\nThis is the same case as the one in the statement.\n\nSample Input 2\n\n1 1 7\n\nSample Output 2\n\n7\n\nIn this case, C is the one we seek.\n\nSample Input 3\n\n-100 100 100\n\nSample Output 3\n\n-100", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 402, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s008474443", "group_id": "codeNet:p03573", "input_text": "#include<cstdio>\n#include<iostream>\n#include<map>\n#include<algorithm>\n#include<queue>\n#include<stack>\n#include<cstring>\n#include<vector>\n#include<cmath>\n#include<cstdlib>\nusing namespace std;\n\nmap<int,int>vis;\n\nint main(){\n\tint a,b,c;scanf(\"%d %d %d\",&a,&b,&c);\n\tvis[a]++,vis[b]++,vis[c]++;\n\tif(vis[a] == 1) cout << a;\n\telse if(vis[b] == 1) cout << b;\n\telse if(vis[c] == 1) cout << c;\n}", "language": "C++", "metadata": {"date": 1508029366, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03573.html", "problem_id": "p03573", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03573/input.txt", "sample_output_relpath": "derived/input_output/data/p03573/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03573/C++/s008474443.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s008474443", "user_id": "u812724608"}, "prompt_components": {"gold_output": "7\n", "input_to_evaluate": "#include<cstdio>\n#include<iostream>\n#include<map>\n#include<algorithm>\n#include<queue>\n#include<stack>\n#include<cstring>\n#include<vector>\n#include<cmath>\n#include<cstdlib>\nusing namespace std;\n\nmap<int,int>vis;\n\nint main(){\n\tint a,b,c;scanf(\"%d %d %d\",&a,&b,&c);\n\tvis[a]++,vis[b]++,vis[c]++;\n\tif(vis[a] == 1) cout << a;\n\telse if(vis[b] == 1) cout << b;\n\telse if(vis[c] == 1) cout << c;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nYou are given three integers, A, B and C.\n\nAmong them, two are the same, but the remaining one is different from the rest.\n\nFor example, when A=5,B=7,C=5, A and C are the same, but B is different.\n\nFind the one that is different from the rest among the given three integers.\n\nConstraints\n\n-100 \\leq A,B,C \\leq 100\n\nA, B and C are integers.\n\nThe input satisfies the condition in the statement.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B C\n\nOutput\n\nAmong A, B and C, print the integer that is different from the rest.\n\nSample Input 1\n\n5 7 5\n\nSample Output 1\n\n7\n\nThis is the same case as the one in the statement.\n\nSample Input 2\n\n1 1 7\n\nSample Output 2\n\n7\n\nIn this case, C is the one we seek.\n\nSample Input 3\n\n-100 100 100\n\nSample Output 3\n\n-100", "sample_input": "5 7 5\n"}, "reference_outputs": ["7\n"], "source_document_id": "p03573", "source_text": "Score : 100 points\n\nProblem Statement\n\nYou are given three integers, A, B and C.\n\nAmong them, two are the same, but the remaining one is different from the rest.\n\nFor example, when A=5,B=7,C=5, A and C are the same, but B is different.\n\nFind the one that is different from the rest among the given three integers.\n\nConstraints\n\n-100 \\leq A,B,C \\leq 100\n\nA, B and C are integers.\n\nThe input satisfies the condition in the statement.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B C\n\nOutput\n\nAmong A, B and C, print the integer that is different from the rest.\n\nSample Input 1\n\n5 7 5\n\nSample Output 1\n\n7\n\nThis is the same case as the one in the statement.\n\nSample Input 2\n\n1 1 7\n\nSample Output 2\n\n7\n\nIn this case, C is the one we seek.\n\nSample Input 3\n\n-100 100 100\n\nSample Output 3\n\n-100", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 386, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s414283524", "group_id": "codeNet:p03576", "input_text": "#include <stdio.h>\n#include <iostream>\n#include <algorithm>\n#include <sstream>\n#include <complex>\n#include <vector>\n#include <list>\n#include <queue>\n#include <deque>\n#include <stack>\n#include <set>\n#include <map>\n#include <cstdio>\n#include <string>\n#include <cstdlib>\n#include <cstring>\n#include <bits/stdc++.h>\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef long double ld;\nusing edge = struct {ll to; ll cost;};\ntypedef string str;\ntypedef std::pair<ll,ll> pl;\ntypedef std::tuple<ll, ll, ll> pl3;\ntypedef std::map<string, ll> msl;\ntypedef std::map<char, ll> mcl;\ntypedef std::map<ll, ll> mll;\ntypedef std::vector<ll> vl;\ntypedef std::vector<pl> vpl;\ntypedef std::priority_queue<ll> pq;\ntypedef std::priority_queue<ll, vl, greater<ll>> pql; // priority queue taking from the lower value.\ntypedef std::vector<edge> gr;\nconst ll MOD = 1e9 + 7;\nconst ll INF = MOD * MOD;\nconst long double EPS = 1e-9;\nconst long double PI = 3.14159265358979323846;\n\n#define rep(i, n) for(ll (i) = 0; (i) < (n) ; (i)++ )\n#define revrep(i, n) for(ll (i) = n - 1; (i) >= 0 ; (i)--)\n#define For(i, a, b) for(ll (i) = (a); (i) < (b) ; (i)++ )\n#define revFor(i, b, a) for(ll (i) = (b) - 1; (i) >= (a) ; (i)--)\n#define all(a) (a).begin(), (a).end()\n#define rall(a) (a).rbegin(), (a).rend()\n#define isUpper(c) ('a' - c > 0)\n#define toLower(c) char((c)+0x20)\n#define toUpper(c) char((c)-0x20)\n#define pb push_back\n#define mp make_pair\n#define pr(a) cout << (a)\n#define prl(a) cout << (a) << endl\n#define prl2(a,b) cout << (a) << \" \" << (b) << endl\n#define prl3(a,b,c) cout << (a) << \" \" << (b) << \" \" << (c) << endl\n#define prl4(a,b,c,d) cout << (a) << \" \" << (b) << \" \" << (c) << \" \" << (d) << endl\n#define prs(a) cout << (a) << \" \"\n#define yn(condition) if ((condition)) prl(\"Yes\"); else prl(\"No\");\n#define YN(condition) if ((condition)) prl(\"YES\"); else prl(\"NO\");\n#define rpr(i,n,ans) rep((i),(n)) {if ((i) < n - 1) prs((ans[(i)])); else if ((i) == n - 1) prl((ans[(i)]));}\n#define cpr(i,n,ans) rep((i),(n)) prl((ans[(i)]))\n#define in1(a) cin >> (a)\n#define in2(a,b) cin >> (a) >> (b)\n#define in3(a,b,c) cin >> (a) >> (b) >> (c)\n#define in4(a,b,c,d) cin >> (a) >> (b) >> (c) >> (d)\n#define rin1(i,n,a) rep((i),(n)) cin >> (a[(i)])\n#define rin2(i,n,a,b) rep((i),(n)) cin >> (a[(i)]) >> (b[(i)])\n#define rin3(i,n,a,b,c) rep((i),(n)) cin >> (a[(i)]) >> (b[(i)]) >> (c[(i)])\n#define rin1_m1(i,n,a) rep((i),(n)) {cin >> (a[(i)]); a[(i)]--;}\n#define rin2_m1(i,n,a,b) rep((i),(n)) {cin >> (a[(i)]) >> (b[(i)]); a[(i)]--;b[(i)]--;}\n#define rin3_m1(i,n,a,b,c) rep((i),(n)) {cin >> (a[(i)]) >> (b[(i)]) >> (c[(i)]) a[(i)]--;b[(i)]--;c[(i)]--;}\n#define matin(i,h,j,w,a) rep((i),(h)) rep((j),(w)) cin >> a[i][j]\n#define e1 first\n#define e2 second\n#define ctol(c) ll((c)) - ll('0')\n#define ltos(n) to_string((n))\n#define items(kv, v) for(auto &(kv): (v))\n#define ndig(N, n) ctol(ll(ltos((N))[ll(ltos((N)).length()) - (n)]))\n#define beto(a,b,c) (a) < (b) && (b) < (c)\n#define betc(a,b,c) (a) <= (b) && (b) <= (c)\n#define rsort(a,n) sort(a,a+n,greater<>())\n#define Forchar(c,a,z) for(char (c) = (a); (c) <= (z); (c)++)\n#define cntchar(s,c) count(all((s)), c)\n#define substring(s, start, end) s.substr((start), (end) - (start) + 1)\n#define prl_nd(num, digits) cout << fixed << setprecision(digits) << (num) << endl;\n#define XOR(a, b) (a)^(b)\n#define prl_time(s) prl3(\"Elapsed Time:\", 1000.0 * (clock() - s) / CLOCKS_PER_SEC, \"[ms]\");\n#define char_to_str(c) string(1, (c))\n\nclass UnionFind {\n    vl parents, set_size;\npublic:\n    UnionFind(){}\n    UnionFind(ll n){\n        parents = set_size = vl(n);\n        rep(i, n) {parents[i] = i; set_size[i] = 1LL;}\n    }\n\n    ll root_find(ll x){\n        if (parents[x] == x) return x;\n        return parents[x] = root_find(parents[x]);\n    }\n\n    void unite(ll x, ll y){\n        x = root_find(x); y = root_find(y);\n        if (x == y) return;\n        if (set_size[x] < set_size[y]){\n            parents[y] = x; set_size[x] += set_size[y];\n        }else{\n            parents[x] = y; set_size[y] += set_size[x];\n        }\n    }\n\n    bool is_same(ll x, ll y) {// connected or not\n        return root_find(x) == root_find(y);\n    }\n\n    ll size(ll x) {\n        return set_size[root_find(x)];\n    }\n};\n\nstruct BIT{\n    ll n; vl dat;\n    BIT(ll n): dat(n + 1), n(n){};\n\n    //       x: 1001 1010  1100 1011 1101  1111\n    // x & - x: 0001 0010  0100 0001 0001  0001\n    //      ->: 1010 1100 10000 1100 1100 10000\n\n    ll sum(ll i){\n        ll s = 0;\n        while(i > 0){s += dat[i]; i -= i & -i;}\n        return s;\n    }\n\n    ll sum(ll i, ll j){\n        return sum(j - 1) - sum(i - 1);\n    }\n\n    void add(ll i, ll x){\n        while(i <= n){dat[i] += x; i += i & -i;}\n    }\n};\n\nll gcd(ll m, ll n){\n    ll a = max(m, n);\n    ll b = min(m, n);\n    while(b != 1 && b != 0){ a %= b; swap(a, b);}\n    return b == 1 ? 1 : a;\n}\n\nll lcm(ll m, ll n){ return m / gcd(m, n) * n;}\n\nll power_mod(ll a, ll power, ll mod){\n    ll value = 1;\n    while(power != 0){\n        if(power & 1) value = (value * a) % mod;\n        a = (a * a) % mod;\n        power = power >> 1;\n    }\n    return value % mod;\n}\n\nll modinv(ll a, ll mod){\n    return power_mod(a, mod - 2, mod);\n}\n\nll power_normal(ll a, ll power){\n    ll value = 1;\n    while(power != 0){\n        if(power & 1) value = value * a;\n        a = a * a;\n        power = power >> 1;\n    }\n    return value;\n}\n\nll combination(ll n, ll r){\n    if (n == r && n == 0) return 1;\n    else if (n <= 0 || r < 0 || r > n) return 0;\n    ll numerator = 1;\n    ll denomenator = 1;\n    for(ll i = 0; i < r ; i++){\n        (numerator *= ll(n - i)) %= MOD;\n        (denomenator *= modinv(i + 1, MOD)) %= MOD;\n    }\n    return (numerator * denomenator) % MOD;\n}\n\nll bin_search(ll key, ll A[], ll left, ll right){\n    // return the index idx where A[idx] = key.\n    // A[left] is start and A[right] is end..\n    // In other words, A[right], not A[right - 1], must be defined.\n    while(right >= left){\n        ll mid = left + (right - left) / 2;\n        if (A[mid] == key) return mid;\n        else if (A[mid] > key) right = mid - 1;\n        else if (A[mid] < key) left = mid + 1;\n    }\n    return -1;\n}\n\nll lower_bound_bin_search_temp(ll key, ll A[], ll left, ll right){\n    // Pay attention to the return value -1.\n    // For example, sometimes you may want the value right instead of -1.\n    if (A[left] >= key) return left;\n    ll mid = left + (right - left) / 2;\n\n    while(right >= left){\n        mid = left + (right - left) / 2;\n        if (mid == left) {\n            if (A[left] < key && key <= A[left + 1]) return left + 1;\n            else return -1;\n        }\n        if (A[mid - 1] < key && key <= A[mid]) return mid;\n        else if (A[mid - 1] >= key) right = mid - 1;\n        else if (A[mid] < key) left = mid;\n    }\n\n    return -1; // all the elements < key\n}\n\nll inf_bin_search_temp(ll key, ll A[], ll left, ll right){\n    // Pay attention to the return value -1.\n    // For example, sometimes you may want the value right instead of -1.\n    if (A[left] > key) return left;\n    ll mid = left + (right - left) / 2;\n\n    while(right >= left){\n        mid = left + (right - left) / 2;\n        if (mid == left) {\n            if (A[left] <= key && key < A[left + 1]) return left + 1;\n            else return -1;\n        }\n        if (A[mid - 1] <= key && key < A[mid]) return mid;\n        else if (A[mid - 1] > key) right = mid - 1;\n        else if (A[mid] <= key) left = mid;\n    }\n\n    return -1; // all the elements <= key\n}\n\nll upper_bound_bin_search_temp(ll key, ll A[], ll left, ll right){\n    // Pay attention to the return value -1.\n    // For example, sometimes you may want the value left instead of -1.\n    if (A[right] <= key) return right;\n    ll mid = left + (right - left) / 2;\n\n    while(right >= left){\n        mid = left + (right - left) / 2;\n        if (mid == right) {\n            if (A[right - 1] <= key && key < A[right]) return right - 1;\n            else return -1;\n        }\n        if (A[mid] <= key && key < A[mid + 1]) return mid;\n        else if (A[mid] > key) right = mid;\n        else if (A[mid + 1] <= key) left = mid + 1;\n    }\n\n    return -1; // all the elements > key\n}\n\nll sup_bin_search_temp(ll key, ll A[], ll left, ll right){\n    // Pay attention to the return value -1.\n    // For example, sometimes you may want the value left instead of -1.\n    if (A[right] < key) return right;\n    ll mid = left + (right - left) / 2;\n\n    while(right >= left){\n        mid = left + (right - left) / 2;\n        if (mid == right) {\n            if (A[right - 1] < key && key <= A[right]) return right - 1;\n            else return -1;\n        }\n        if (A[mid] < key && key <= A[mid + 1]) return mid;\n        else if (A[mid] >= key) right = mid;\n        else if (A[mid + 1] < key) left = mid + 1;\n    }\n\n    return -1; // all the elements >= key\n}\n\nll bin_search_vector(ll key, vl v, ll left, ll right){\n    // return the index idx where v[idx] = key.\n    // v[left] is start and v[right] is end..\n    // In other words, v[right], not v[right - 1], must be defined.\n    while(right >= left){\n        ll mid = left + (right - left) / 2;\n        if (v[mid] == key) return mid;\n        else if (v[mid] > key) right = mid - 1;\n        else if (v[mid] < key) left = mid + 1;\n    }\n    return -1;\n}\n\nll lower_bound_bin_search_vector(ll key, vl v){\n    // the return value N satisfies\n    // v[N - 1] < key <= v[N]\n    // N == -1 if all the elements < key\n    return lower_bound(all(v), key) - v.begin();\n}\n\nll inf_bin_search_vector(ll key, vl v){\n    // the return value N satisfies\n    // v[N - 1] <= key < v[N] <= key + 1\n    // N == -1 if all the elements <= key\n    return lower_bound(all(v), key + 1) - v.begin();\n}\n\nll upper_bound_bin_search_vector(ll key, vl v){\n    // the return value N satisfies\n    // v[N] <= key < v[N + 1]\n    // N == -1 if all the elements > key\n    return upper_bound(all(v), key) - v.begin() - 1;\n}\n\nll sup_bin_search_vector(ll key, vl v){\n    // the return value N satisfies\n    // v[N] <= key - 1 < key <= v[N + 1]\n    // N == -1 if all the elements >= key\n    return upper_bound(all(v), key - 1) - v.begin() - 1;\n}\n\nll fact(ll n){\n    if (n == 0) return 1;\n    return n * fact(n - 1);\n}\n\nbool is_prime(ll n){\n    if (n <= 1) return false;\n    for(ll i = 2; i * i <= n; i++){\n        if (n % i == 0) return false;\n    }\n    return true;\n}\n\nll bool_sum(ll a1, ll a2){\n    if (a1 == 1 || a2 == 1) return 1;\n    return 0;\n}\n\nmll prime_decomposition(ll n){\n    ll i = 2;\n    mll table;\n    while(i * i <= n){\n        while(n % i == 0){\n            table[i] ++;\n            n /= i;\n        }\n        i++;\n    }\n    if (n > 1) table[n] = 1;\n    return table;\n}\n\nll char_to_idx(char c){\n    ll idx = 0;\n    Forchar(cc, 'a', 'z'){\n        if (c == cc) return idx;\n        else idx ++;\n    }\n}\n\n/*\nconst ll N_VERTEX = 310;\nll a, b, t;\nll dist[N_VERTEX][N_VERTEX];\n\nvoid warshall_floyd(ll n){\n    rep(k, n) rep(i, n) rep(j, n) dist[i][j] = min(dist[i][j], dist[i][k] + dist[k][j]);\n}\n\nint main(void){\n    in2(n, m);\n    rep(i, n) rep(j, n) {if (i != j) dist[i][j] = INF; else dist[i][i] = 0;}\n    rep(i, m){\n        in3(a, b, t);\n        a--; b--;\n        dist[a][b] = t;\n        dist[b][a] = t;\n    }\n\n    warshall_floyd(n);\n}\n\nconst ll N_VERTEX = 310;\ngr G[N_VERTEX];\nll dist[N_VERTEX], a, b, t, n, m;\n\nvoid dijkstra(ll start, ll n) {\n    priority_queue<pl, vector<pl>, greater<pl>> edge_costs;\n    fill(dist, dist + n, INF);\n    dist[start] = 0;\n    edge_costs.push(pl(0, start));\n\n    while (!edge_costs.empty()) {\n        pl edge_cost = edge_costs.top();\n        edge_costs.pop();\n        ll idx = edge_cost.second;\n        ll cost = edge_cost.first;\n        if (dist[idx] < cost) continue;\n\n        rep(i, G[idx].size()){\n            edge e = G[idx][i];\n            if (dist[e.to] > dist[idx] + e.cost){\n                dist[e.to] = dist[idx] + e.cost;\n                edge_costs.push(pl(dist[e.to], e.to));\n            }\n        }\n    }\n}\n\nint main(void){\n    in2(n, m);\n    rep(i, m){\n        in3(a, b, t);\n        a--; b--;\n        G[a].pb({b, t});\n        G[b].pb({a, t});\n    }\n\n    dijkstra(0, n);\n}\n\n*/\n\n/*\n    # 1. The usage of map pair\n    map<pl, ll> cnt;\n    cnt[{i, j}] = 0;\n    items(kv, cnt){\n        prl2(kv.first, kv.second);\n    }\n\n    # 2. The usage of pair sort\n\n    vpl c;\n    rep(i, n){\n        ll a, b;\n        in2(a, b);\n        c.pb(mp(a, b));\n    }\n    sort(all(c));\n\n    # 3. The usage of next_permutation and combination (factorial search)\n    ll a[8];\n    rep(i, 8) a[i] = i;\n    do{\n    }while(next_permutation(a, a+n));\n\n    // here, combination\n    ll n, r;\n    ll i1, i2, ..., ir;\n    For(i1, n - r, n) For(i2, n - r - 1, i1) ... For(ir, n - 2 * r + 1, irr){ process;}\n\n    # 4. sort vector in descending order\n    sort(rall(v));\n\n    # 5. bit search\n    ll n;\n    in1(n);\n    const ll base = 3;\n    ll upper = 1;\n    rep(i, n) upper *= base;\n    rep(i, upper){\n        ll tmp = i;\n        rep(j, n){\n            rep(k, base) if (tmp % base == k) prl(k);\n            tmp /= base;\n        }\n    }\n\n    # 6. imos method\n    // used when we would like to count the number which\n    // shows how many times the numbers between l and r belongs to smt.\n    // This method is composed of three process.\n    ll n, m, s[MAX_M], l, r;\n    in2(n, m);\n    rep(i, m) s[i] = 0;\n\n    // 1st step\n    rep(i, n){\n        in3(l, r, c);\n        l--; r--; // if l starts from 1.\n        s[l] += c; s[r + 1] -= c;\n    }\n\n    // 2nd step\n    rep(i, m - 1) s[i + 1] += s[i];\n    // 3rd step: judgement...\n\n    #7. shakutori method\n    // 1. strech right side while the condition is met.\n    // 2. renew the answer\n    // 3. increments left side\n    // 4. Back to 1. (l <= r must be satisfied all the time.)\n\n    ll l = 0; ll r = 0;\n    while (l < n){\n        r = max(r, l);\n        if (l == r) r++;\n        while(r < n && cond) r++;\n        answer += r - l; l++;\n    }\n    prl(answer);\n\n    #8. priority queue\n\n    pq q;\n    ll answer = 0;\n    ll v;\n\n    rep(i, n) q.push(a[i]);\n    rep(i, m){\n        v = q.top(); q.pop(); // get the top value and dump the value from queue\n        v /= 2; q.push(v); // add the new value\n    }\n\n    while(!q.empty()){\n        answer += q.top();\n        q.pop();\n    }\n\n    #9. The shortest path between the k-th edge and another edge (Tree)\n    ll depth[MAX_N];\n    gr tree[MAX_N];\n\n    void dfs(ll now, ll prev, ll all_cost){\n        depth[now] = all_cost;\n        items(e, tree[now]){\n            if (e.to == prev) continue;\n            dfs(e.to, now, all_cost + e.cost);\n        }\n    }\n\n    ll n, k, a, b, c;\n\n    in2(n, k);\n    rep(i, n - 1){\n        in3(a, b, c);\n        a--; b--;\n        tree[a].pb({b, c});\n        tree[b].pb({a, c});\n    }\n\n    k--;\n    dfs(k, -1, 0);\n\n    #10. Visiting Subtree using recurrent function (ABC138D)\n\n    gr tree[MAX_N];\n    ll c[MAX_N];\n    bool visited[MAX_N];\n\n    void dfs(ll source, ll parent, ll val){\n        visited[source] = true;\n        c[source] += val;\n        rep(i, tree[source].size()){rep(i, m){\n        ll res = n % match[i].e1;\n    }\n            ll vertex = tree[source][i].to;\n            if (vertex == parent) continue;\n            dfs(vertex, source, c[source]);\n        }\n    }\n\n    #11. bfs ABC146D\n    1. first create a tree.\n    2. start searching from a node.\n    3. do some processes and push nodes connected with a given target node in BFS.\n    4. repeat a series of procedure until queue is empty.\n\n    #12. grid to distance matrix (dx, dy)\n    ll w, h;\n    ll pos_to_idx(ll x, ll y){\n        return y * w + x;\n    }\n\n    int main(void){\n        in2(h, w);\n        rep(y, h){\n            in1(s);\n            rep(x, w){\n                if (s[x] == '#') wall[x][y] = true;\n                else wall[x][y] = false;\n            }\n        }\n\n        rep(i1, h * w)rep(i2, h * w) if (i1 == i2) dist[i1][i2] = 0; else dist[i1][i2] = INF;\n\n        rep(x, w)rep(y, h){\n            ll idx1 = pos_to_idx(x, y); ll idx2;\n            if (wall[x][y]) continue;\n            if (x != 0 && !wall[x - 1][y]){\n                idx2 = pos_to_idx(x - 1, y);\n                // if warshall floyd\n                dist[idx1][idx2] = 1;\n                // if dijkstra\n                // G[idx1].pb({idx2, 1});\n            }\n            if (x != w - 1 && !wall[x + 1][y]){\n                idx2 = pos_to_idx(x + 1, y);\n                dist[idx1][idx2] = 1;\n                // G[idx1].pb({idx2, 1});\n            }\n            if (y != 0 && !wall[x][y - 1]){\n                idx2 = pos_to_idx(x, y - 1);\n                dist[idx1][idx2] = 1;\n                // G[idx1].pb({idx2, 1});\n            }\n            if (y != h - 1 && !wall[x][y + 1]){\n                idx2 = pos_to_idx(x, y + 1);\n                dist[idx1][idx2] = 1;\n                // G[idx1].pb({idx2, 1});\n            }\n        }\n    }\n\n\n*/\n\n/*\nthe operators regarding bit\n\n     x1: 0000 0001 0010 0101 0110 0111\n     x2: xxxx 0001 0011 0100 0101 1000\nx1 & x2: 0000 0001 0010 0100 0100 0000\n\n      x: 1001 1010  1100 1011 1101  1111\nx & - x: 0001 0010  0100 0001 0001  0001\n    sum: 1010 1100 10000 1100 1100 10000\n\nx << y is x * 2 ** y\nx >> y is rep(i, y) x = x // 2 \n*/\n\nconst ll MAX_N = 200005;\nbool okay = false;\nll answer = power_normal(10, 18) * 4 + 1;\nll n, k;\nvpl xy;\n\nvoid solve(){\n    rep(i, n){\n        ll a, b; in2(a, b);\n        xy.pb(mp(a, b));\n    }\n\n    sort(all(xy));\n\n    rep(i1, n - k + 1) For(i2, i1 + k - 1, n){\n        ll ym = INF; ll yM = -INF;\n        For(i3, i1, i2 + 1){\n            ym = min(ym, xy[i3].e2);\n            yM = max(yM, xy[i3].e2);\n        }\n        ll sp = (yM - ym) * (xy[i2].e1 - xy[i1].e1);\n        answer = min(sp, answer);\n    }\n\n    prl(answer);\n}\n \nint main(void){\n    in2(n, k);\n    solve();\n\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1586197978, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03576.html", "problem_id": "p03576", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03576/input.txt", "sample_output_relpath": "derived/input_output/data/p03576/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03576/C++/s414283524.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s414283524", "user_id": "u767543103"}, "prompt_components": {"gold_output": "21\n", "input_to_evaluate": "#include <stdio.h>\n#include <iostream>\n#include <algorithm>\n#include <sstream>\n#include <complex>\n#include <vector>\n#include <list>\n#include <queue>\n#include <deque>\n#include <stack>\n#include <set>\n#include <map>\n#include <cstdio>\n#include <string>\n#include <cstdlib>\n#include <cstring>\n#include <bits/stdc++.h>\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef long double ld;\nusing edge = struct {ll to; ll cost;};\ntypedef string str;\ntypedef std::pair<ll,ll> pl;\ntypedef std::tuple<ll, ll, ll> pl3;\ntypedef std::map<string, ll> msl;\ntypedef std::map<char, ll> mcl;\ntypedef std::map<ll, ll> mll;\ntypedef std::vector<ll> vl;\ntypedef std::vector<pl> vpl;\ntypedef std::priority_queue<ll> pq;\ntypedef std::priority_queue<ll, vl, greater<ll>> pql; // priority queue taking from the lower value.\ntypedef std::vector<edge> gr;\nconst ll MOD = 1e9 + 7;\nconst ll INF = MOD * MOD;\nconst long double EPS = 1e-9;\nconst long double PI = 3.14159265358979323846;\n\n#define rep(i, n) for(ll (i) = 0; (i) < (n) ; (i)++ )\n#define revrep(i, n) for(ll (i) = n - 1; (i) >= 0 ; (i)--)\n#define For(i, a, b) for(ll (i) = (a); (i) < (b) ; (i)++ )\n#define revFor(i, b, a) for(ll (i) = (b) - 1; (i) >= (a) ; (i)--)\n#define all(a) (a).begin(), (a).end()\n#define rall(a) (a).rbegin(), (a).rend()\n#define isUpper(c) ('a' - c > 0)\n#define toLower(c) char((c)+0x20)\n#define toUpper(c) char((c)-0x20)\n#define pb push_back\n#define mp make_pair\n#define pr(a) cout << (a)\n#define prl(a) cout << (a) << endl\n#define prl2(a,b) cout << (a) << \" \" << (b) << endl\n#define prl3(a,b,c) cout << (a) << \" \" << (b) << \" \" << (c) << endl\n#define prl4(a,b,c,d) cout << (a) << \" \" << (b) << \" \" << (c) << \" \" << (d) << endl\n#define prs(a) cout << (a) << \" \"\n#define yn(condition) if ((condition)) prl(\"Yes\"); else prl(\"No\");\n#define YN(condition) if ((condition)) prl(\"YES\"); else prl(\"NO\");\n#define rpr(i,n,ans) rep((i),(n)) {if ((i) < n - 1) prs((ans[(i)])); else if ((i) == n - 1) prl((ans[(i)]));}\n#define cpr(i,n,ans) rep((i),(n)) prl((ans[(i)]))\n#define in1(a) cin >> (a)\n#define in2(a,b) cin >> (a) >> (b)\n#define in3(a,b,c) cin >> (a) >> (b) >> (c)\n#define in4(a,b,c,d) cin >> (a) >> (b) >> (c) >> (d)\n#define rin1(i,n,a) rep((i),(n)) cin >> (a[(i)])\n#define rin2(i,n,a,b) rep((i),(n)) cin >> (a[(i)]) >> (b[(i)])\n#define rin3(i,n,a,b,c) rep((i),(n)) cin >> (a[(i)]) >> (b[(i)]) >> (c[(i)])\n#define rin1_m1(i,n,a) rep((i),(n)) {cin >> (a[(i)]); a[(i)]--;}\n#define rin2_m1(i,n,a,b) rep((i),(n)) {cin >> (a[(i)]) >> (b[(i)]); a[(i)]--;b[(i)]--;}\n#define rin3_m1(i,n,a,b,c) rep((i),(n)) {cin >> (a[(i)]) >> (b[(i)]) >> (c[(i)]) a[(i)]--;b[(i)]--;c[(i)]--;}\n#define matin(i,h,j,w,a) rep((i),(h)) rep((j),(w)) cin >> a[i][j]\n#define e1 first\n#define e2 second\n#define ctol(c) ll((c)) - ll('0')\n#define ltos(n) to_string((n))\n#define items(kv, v) for(auto &(kv): (v))\n#define ndig(N, n) ctol(ll(ltos((N))[ll(ltos((N)).length()) - (n)]))\n#define beto(a,b,c) (a) < (b) && (b) < (c)\n#define betc(a,b,c) (a) <= (b) && (b) <= (c)\n#define rsort(a,n) sort(a,a+n,greater<>())\n#define Forchar(c,a,z) for(char (c) = (a); (c) <= (z); (c)++)\n#define cntchar(s,c) count(all((s)), c)\n#define substring(s, start, end) s.substr((start), (end) - (start) + 1)\n#define prl_nd(num, digits) cout << fixed << setprecision(digits) << (num) << endl;\n#define XOR(a, b) (a)^(b)\n#define prl_time(s) prl3(\"Elapsed Time:\", 1000.0 * (clock() - s) / CLOCKS_PER_SEC, \"[ms]\");\n#define char_to_str(c) string(1, (c))\n\nclass UnionFind {\n    vl parents, set_size;\npublic:\n    UnionFind(){}\n    UnionFind(ll n){\n        parents = set_size = vl(n);\n        rep(i, n) {parents[i] = i; set_size[i] = 1LL;}\n    }\n\n    ll root_find(ll x){\n        if (parents[x] == x) return x;\n        return parents[x] = root_find(parents[x]);\n    }\n\n    void unite(ll x, ll y){\n        x = root_find(x); y = root_find(y);\n        if (x == y) return;\n        if (set_size[x] < set_size[y]){\n            parents[y] = x; set_size[x] += set_size[y];\n        }else{\n            parents[x] = y; set_size[y] += set_size[x];\n        }\n    }\n\n    bool is_same(ll x, ll y) {// connected or not\n        return root_find(x) == root_find(y);\n    }\n\n    ll size(ll x) {\n        return set_size[root_find(x)];\n    }\n};\n\nstruct BIT{\n    ll n; vl dat;\n    BIT(ll n): dat(n + 1), n(n){};\n\n    //       x: 1001 1010  1100 1011 1101  1111\n    // x & - x: 0001 0010  0100 0001 0001  0001\n    //      ->: 1010 1100 10000 1100 1100 10000\n\n    ll sum(ll i){\n        ll s = 0;\n        while(i > 0){s += dat[i]; i -= i & -i;}\n        return s;\n    }\n\n    ll sum(ll i, ll j){\n        return sum(j - 1) - sum(i - 1);\n    }\n\n    void add(ll i, ll x){\n        while(i <= n){dat[i] += x; i += i & -i;}\n    }\n};\n\nll gcd(ll m, ll n){\n    ll a = max(m, n);\n    ll b = min(m, n);\n    while(b != 1 && b != 0){ a %= b; swap(a, b);}\n    return b == 1 ? 1 : a;\n}\n\nll lcm(ll m, ll n){ return m / gcd(m, n) * n;}\n\nll power_mod(ll a, ll power, ll mod){\n    ll value = 1;\n    while(power != 0){\n        if(power & 1) value = (value * a) % mod;\n        a = (a * a) % mod;\n        power = power >> 1;\n    }\n    return value % mod;\n}\n\nll modinv(ll a, ll mod){\n    return power_mod(a, mod - 2, mod);\n}\n\nll power_normal(ll a, ll power){\n    ll value = 1;\n    while(power != 0){\n        if(power & 1) value = value * a;\n        a = a * a;\n        power = power >> 1;\n    }\n    return value;\n}\n\nll combination(ll n, ll r){\n    if (n == r && n == 0) return 1;\n    else if (n <= 0 || r < 0 || r > n) return 0;\n    ll numerator = 1;\n    ll denomenator = 1;\n    for(ll i = 0; i < r ; i++){\n        (numerator *= ll(n - i)) %= MOD;\n        (denomenator *= modinv(i + 1, MOD)) %= MOD;\n    }\n    return (numerator * denomenator) % MOD;\n}\n\nll bin_search(ll key, ll A[], ll left, ll right){\n    // return the index idx where A[idx] = key.\n    // A[left] is start and A[right] is end..\n    // In other words, A[right], not A[right - 1], must be defined.\n    while(right >= left){\n        ll mid = left + (right - left) / 2;\n        if (A[mid] == key) return mid;\n        else if (A[mid] > key) right = mid - 1;\n        else if (A[mid] < key) left = mid + 1;\n    }\n    return -1;\n}\n\nll lower_bound_bin_search_temp(ll key, ll A[], ll left, ll right){\n    // Pay attention to the return value -1.\n    // For example, sometimes you may want the value right instead of -1.\n    if (A[left] >= key) return left;\n    ll mid = left + (right - left) / 2;\n\n    while(right >= left){\n        mid = left + (right - left) / 2;\n        if (mid == left) {\n            if (A[left] < key && key <= A[left + 1]) return left + 1;\n            else return -1;\n        }\n        if (A[mid - 1] < key && key <= A[mid]) return mid;\n        else if (A[mid - 1] >= key) right = mid - 1;\n        else if (A[mid] < key) left = mid;\n    }\n\n    return -1; // all the elements < key\n}\n\nll inf_bin_search_temp(ll key, ll A[], ll left, ll right){\n    // Pay attention to the return value -1.\n    // For example, sometimes you may want the value right instead of -1.\n    if (A[left] > key) return left;\n    ll mid = left + (right - left) / 2;\n\n    while(right >= left){\n        mid = left + (right - left) / 2;\n        if (mid == left) {\n            if (A[left] <= key && key < A[left + 1]) return left + 1;\n            else return -1;\n        }\n        if (A[mid - 1] <= key && key < A[mid]) return mid;\n        else if (A[mid - 1] > key) right = mid - 1;\n        else if (A[mid] <= key) left = mid;\n    }\n\n    return -1; // all the elements <= key\n}\n\nll upper_bound_bin_search_temp(ll key, ll A[], ll left, ll right){\n    // Pay attention to the return value -1.\n    // For example, sometimes you may want the value left instead of -1.\n    if (A[right] <= key) return right;\n    ll mid = left + (right - left) / 2;\n\n    while(right >= left){\n        mid = left + (right - left) / 2;\n        if (mid == right) {\n            if (A[right - 1] <= key && key < A[right]) return right - 1;\n            else return -1;\n        }\n        if (A[mid] <= key && key < A[mid + 1]) return mid;\n        else if (A[mid] > key) right = mid;\n        else if (A[mid + 1] <= key) left = mid + 1;\n    }\n\n    return -1; // all the elements > key\n}\n\nll sup_bin_search_temp(ll key, ll A[], ll left, ll right){\n    // Pay attention to the return value -1.\n    // For example, sometimes you may want the value left instead of -1.\n    if (A[right] < key) return right;\n    ll mid = left + (right - left) / 2;\n\n    while(right >= left){\n        mid = left + (right - left) / 2;\n        if (mid == right) {\n            if (A[right - 1] < key && key <= A[right]) return right - 1;\n            else return -1;\n        }\n        if (A[mid] < key && key <= A[mid + 1]) return mid;\n        else if (A[mid] >= key) right = mid;\n        else if (A[mid + 1] < key) left = mid + 1;\n    }\n\n    return -1; // all the elements >= key\n}\n\nll bin_search_vector(ll key, vl v, ll left, ll right){\n    // return the index idx where v[idx] = key.\n    // v[left] is start and v[right] is end..\n    // In other words, v[right], not v[right - 1], must be defined.\n    while(right >= left){\n        ll mid = left + (right - left) / 2;\n        if (v[mid] == key) return mid;\n        else if (v[mid] > key) right = mid - 1;\n        else if (v[mid] < key) left = mid + 1;\n    }\n    return -1;\n}\n\nll lower_bound_bin_search_vector(ll key, vl v){\n    // the return value N satisfies\n    // v[N - 1] < key <= v[N]\n    // N == -1 if all the elements < key\n    return lower_bound(all(v), key) - v.begin();\n}\n\nll inf_bin_search_vector(ll key, vl v){\n    // the return value N satisfies\n    // v[N - 1] <= key < v[N] <= key + 1\n    // N == -1 if all the elements <= key\n    return lower_bound(all(v), key + 1) - v.begin();\n}\n\nll upper_bound_bin_search_vector(ll key, vl v){\n    // the return value N satisfies\n    // v[N] <= key < v[N + 1]\n    // N == -1 if all the elements > key\n    return upper_bound(all(v), key) - v.begin() - 1;\n}\n\nll sup_bin_search_vector(ll key, vl v){\n    // the return value N satisfies\n    // v[N] <= key - 1 < key <= v[N + 1]\n    // N == -1 if all the elements >= key\n    return upper_bound(all(v), key - 1) - v.begin() - 1;\n}\n\nll fact(ll n){\n    if (n == 0) return 1;\n    return n * fact(n - 1);\n}\n\nbool is_prime(ll n){\n    if (n <= 1) return false;\n    for(ll i = 2; i * i <= n; i++){\n        if (n % i == 0) return false;\n    }\n    return true;\n}\n\nll bool_sum(ll a1, ll a2){\n    if (a1 == 1 || a2 == 1) return 1;\n    return 0;\n}\n\nmll prime_decomposition(ll n){\n    ll i = 2;\n    mll table;\n    while(i * i <= n){\n        while(n % i == 0){\n            table[i] ++;\n            n /= i;\n        }\n        i++;\n    }\n    if (n > 1) table[n] = 1;\n    return table;\n}\n\nll char_to_idx(char c){\n    ll idx = 0;\n    Forchar(cc, 'a', 'z'){\n        if (c == cc) return idx;\n        else idx ++;\n    }\n}\n\n/*\nconst ll N_VERTEX = 310;\nll a, b, t;\nll dist[N_VERTEX][N_VERTEX];\n\nvoid warshall_floyd(ll n){\n    rep(k, n) rep(i, n) rep(j, n) dist[i][j] = min(dist[i][j], dist[i][k] + dist[k][j]);\n}\n\nint main(void){\n    in2(n, m);\n    rep(i, n) rep(j, n) {if (i != j) dist[i][j] = INF; else dist[i][i] = 0;}\n    rep(i, m){\n        in3(a, b, t);\n        a--; b--;\n        dist[a][b] = t;\n        dist[b][a] = t;\n    }\n\n    warshall_floyd(n);\n}\n\nconst ll N_VERTEX = 310;\ngr G[N_VERTEX];\nll dist[N_VERTEX], a, b, t, n, m;\n\nvoid dijkstra(ll start, ll n) {\n    priority_queue<pl, vector<pl>, greater<pl>> edge_costs;\n    fill(dist, dist + n, INF);\n    dist[start] = 0;\n    edge_costs.push(pl(0, start));\n\n    while (!edge_costs.empty()) {\n        pl edge_cost = edge_costs.top();\n        edge_costs.pop();\n        ll idx = edge_cost.second;\n        ll cost = edge_cost.first;\n        if (dist[idx] < cost) continue;\n\n        rep(i, G[idx].size()){\n            edge e = G[idx][i];\n            if (dist[e.to] > dist[idx] + e.cost){\n                dist[e.to] = dist[idx] + e.cost;\n                edge_costs.push(pl(dist[e.to], e.to));\n            }\n        }\n    }\n}\n\nint main(void){\n    in2(n, m);\n    rep(i, m){\n        in3(a, b, t);\n        a--; b--;\n        G[a].pb({b, t});\n        G[b].pb({a, t});\n    }\n\n    dijkstra(0, n);\n}\n\n*/\n\n/*\n    # 1. The usage of map pair\n    map<pl, ll> cnt;\n    cnt[{i, j}] = 0;\n    items(kv, cnt){\n        prl2(kv.first, kv.second);\n    }\n\n    # 2. The usage of pair sort\n\n    vpl c;\n    rep(i, n){\n        ll a, b;\n        in2(a, b);\n        c.pb(mp(a, b));\n    }\n    sort(all(c));\n\n    # 3. The usage of next_permutation and combination (factorial search)\n    ll a[8];\n    rep(i, 8) a[i] = i;\n    do{\n    }while(next_permutation(a, a+n));\n\n    // here, combination\n    ll n, r;\n    ll i1, i2, ..., ir;\n    For(i1, n - r, n) For(i2, n - r - 1, i1) ... For(ir, n - 2 * r + 1, irr){ process;}\n\n    # 4. sort vector in descending order\n    sort(rall(v));\n\n    # 5. bit search\n    ll n;\n    in1(n);\n    const ll base = 3;\n    ll upper = 1;\n    rep(i, n) upper *= base;\n    rep(i, upper){\n        ll tmp = i;\n        rep(j, n){\n            rep(k, base) if (tmp % base == k) prl(k);\n            tmp /= base;\n        }\n    }\n\n    # 6. imos method\n    // used when we would like to count the number which\n    // shows how many times the numbers between l and r belongs to smt.\n    // This method is composed of three process.\n    ll n, m, s[MAX_M], l, r;\n    in2(n, m);\n    rep(i, m) s[i] = 0;\n\n    // 1st step\n    rep(i, n){\n        in3(l, r, c);\n        l--; r--; // if l starts from 1.\n        s[l] += c; s[r + 1] -= c;\n    }\n\n    // 2nd step\n    rep(i, m - 1) s[i + 1] += s[i];\n    // 3rd step: judgement...\n\n    #7. shakutori method\n    // 1. strech right side while the condition is met.\n    // 2. renew the answer\n    // 3. increments left side\n    // 4. Back to 1. (l <= r must be satisfied all the time.)\n\n    ll l = 0; ll r = 0;\n    while (l < n){\n        r = max(r, l);\n        if (l == r) r++;\n        while(r < n && cond) r++;\n        answer += r - l; l++;\n    }\n    prl(answer);\n\n    #8. priority queue\n\n    pq q;\n    ll answer = 0;\n    ll v;\n\n    rep(i, n) q.push(a[i]);\n    rep(i, m){\n        v = q.top(); q.pop(); // get the top value and dump the value from queue\n        v /= 2; q.push(v); // add the new value\n    }\n\n    while(!q.empty()){\n        answer += q.top();\n        q.pop();\n    }\n\n    #9. The shortest path between the k-th edge and another edge (Tree)\n    ll depth[MAX_N];\n    gr tree[MAX_N];\n\n    void dfs(ll now, ll prev, ll all_cost){\n        depth[now] = all_cost;\n        items(e, tree[now]){\n            if (e.to == prev) continue;\n            dfs(e.to, now, all_cost + e.cost);\n        }\n    }\n\n    ll n, k, a, b, c;\n\n    in2(n, k);\n    rep(i, n - 1){\n        in3(a, b, c);\n        a--; b--;\n        tree[a].pb({b, c});\n        tree[b].pb({a, c});\n    }\n\n    k--;\n    dfs(k, -1, 0);\n\n    #10. Visiting Subtree using recurrent function (ABC138D)\n\n    gr tree[MAX_N];\n    ll c[MAX_N];\n    bool visited[MAX_N];\n\n    void dfs(ll source, ll parent, ll val){\n        visited[source] = true;\n        c[source] += val;\n        rep(i, tree[source].size()){rep(i, m){\n        ll res = n % match[i].e1;\n    }\n            ll vertex = tree[source][i].to;\n            if (vertex == parent) continue;\n            dfs(vertex, source, c[source]);\n        }\n    }\n\n    #11. bfs ABC146D\n    1. first create a tree.\n    2. start searching from a node.\n    3. do some processes and push nodes connected with a given target node in BFS.\n    4. repeat a series of procedure until queue is empty.\n\n    #12. grid to distance matrix (dx, dy)\n    ll w, h;\n    ll pos_to_idx(ll x, ll y){\n        return y * w + x;\n    }\n\n    int main(void){\n        in2(h, w);\n        rep(y, h){\n            in1(s);\n            rep(x, w){\n                if (s[x] == '#') wall[x][y] = true;\n                else wall[x][y] = false;\n            }\n        }\n\n        rep(i1, h * w)rep(i2, h * w) if (i1 == i2) dist[i1][i2] = 0; else dist[i1][i2] = INF;\n\n        rep(x, w)rep(y, h){\n            ll idx1 = pos_to_idx(x, y); ll idx2;\n            if (wall[x][y]) continue;\n            if (x != 0 && !wall[x - 1][y]){\n                idx2 = pos_to_idx(x - 1, y);\n                // if warshall floyd\n                dist[idx1][idx2] = 1;\n                // if dijkstra\n                // G[idx1].pb({idx2, 1});\n            }\n            if (x != w - 1 && !wall[x + 1][y]){\n                idx2 = pos_to_idx(x + 1, y);\n                dist[idx1][idx2] = 1;\n                // G[idx1].pb({idx2, 1});\n            }\n            if (y != 0 && !wall[x][y - 1]){\n                idx2 = pos_to_idx(x, y - 1);\n                dist[idx1][idx2] = 1;\n                // G[idx1].pb({idx2, 1});\n            }\n            if (y != h - 1 && !wall[x][y + 1]){\n                idx2 = pos_to_idx(x, y + 1);\n                dist[idx1][idx2] = 1;\n                // G[idx1].pb({idx2, 1});\n            }\n        }\n    }\n\n\n*/\n\n/*\nthe operators regarding bit\n\n     x1: 0000 0001 0010 0101 0110 0111\n     x2: xxxx 0001 0011 0100 0101 1000\nx1 & x2: 0000 0001 0010 0100 0100 0000\n\n      x: 1001 1010  1100 1011 1101  1111\nx & - x: 0001 0010  0100 0001 0001  0001\n    sum: 1010 1100 10000 1100 1100 10000\n\nx << y is x * 2 ** y\nx >> y is rep(i, y) x = x // 2 \n*/\n\nconst ll MAX_N = 200005;\nbool okay = false;\nll answer = power_normal(10, 18) * 4 + 1;\nll n, k;\nvpl xy;\n\nvoid solve(){\n    rep(i, n){\n        ll a, b; in2(a, b);\n        xy.pb(mp(a, b));\n    }\n\n    sort(all(xy));\n\n    rep(i1, n - k + 1) For(i2, i1 + k - 1, n){\n        ll ym = INF; ll yM = -INF;\n        For(i3, i1, i2 + 1){\n            ym = min(ym, xy[i3].e2);\n            yM = max(yM, xy[i3].e2);\n        }\n        ll sp = (yM - ym) * (xy[i2].e1 - xy[i1].e1);\n        answer = min(sp, answer);\n    }\n\n    prl(answer);\n}\n \nint main(void){\n    in2(n, k);\n    solve();\n\n    return 0;\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nWe have N points in a two-dimensional plane.\n\nThe coordinates of the i-th point (1 \\leq i \\leq N) are (x_i,y_i).\n\nLet us consider a rectangle whose sides are parallel to the coordinate axes that contains K or more of the N points in its interior.\n\nHere, points on the sides of the rectangle are considered to be in the interior.\n\nFind the minimum possible area of such a rectangle.\n\nConstraints\n\n2 \\leq K \\leq N \\leq 50\n\n-10^9 \\leq x_i,y_i \\leq 10^9 (1 \\leq i \\leq N)\n\nx_i≠x_j (1 \\leq i<j \\leq N)\n\ny_i≠y_j (1 \\leq i<j \\leq N)\n\nAll input values are integers. (Added at 21:50 JST)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nx_1 y_1\n:\nx_{N} y_{N}\n\nOutput\n\nPrint the minimum possible area of a rectangle that satisfies the condition.\n\nSample Input 1\n\n4 4\n1 4\n3 3\n6 2\n8 1\n\nSample Output 1\n\n21\n\nOne rectangle that satisfies the condition with the minimum possible area has the following vertices: (1,1), (8,1), (1,4) and (8,4).\n\nIts area is (8-1) × (4-1) = 21.\n\nSample Input 2\n\n4 2\n0 0\n1 1\n2 2\n3 3\n\nSample Output 2\n\n1\n\nSample Input 3\n\n4 3\n-1000000000 -1000000000\n1000000000 1000000000\n-999999999 999999999\n999999999 -999999999\n\nSample Output 3\n\n3999999996000000001\n\nWatch out for integer overflows.", "sample_input": "4 4\n1 4\n3 3\n6 2\n8 1\n"}, "reference_outputs": ["21\n"], "source_document_id": "p03576", "source_text": "Score : 400 points\n\nProblem Statement\n\nWe have N points in a two-dimensional plane.\n\nThe coordinates of the i-th point (1 \\leq i \\leq N) are (x_i,y_i).\n\nLet us consider a rectangle whose sides are parallel to the coordinate axes that contains K or more of the N points in its interior.\n\nHere, points on the sides of the rectangle are considered to be in the interior.\n\nFind the minimum possible area of such a rectangle.\n\nConstraints\n\n2 \\leq K \\leq N \\leq 50\n\n-10^9 \\leq x_i,y_i \\leq 10^9 (1 \\leq i \\leq N)\n\nx_i≠x_j (1 \\leq i<j \\leq N)\n\ny_i≠y_j (1 \\leq i<j \\leq N)\n\nAll input values are integers. (Added at 21:50 JST)\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nx_1 y_1\n:\nx_{N} y_{N}\n\nOutput\n\nPrint the minimum possible area of a rectangle that satisfies the condition.\n\nSample Input 1\n\n4 4\n1 4\n3 3\n6 2\n8 1\n\nSample Output 1\n\n21\n\nOne rectangle that satisfies the condition with the minimum possible area has the following vertices: (1,1), (8,1), (1,4) and (8,4).\n\nIts area is (8-1) × (4-1) = 21.\n\nSample Input 2\n\n4 2\n0 0\n1 1\n2 2\n3 3\n\nSample Output 2\n\n1\n\nSample Input 3\n\n4 3\n-1000000000 -1000000000\n1000000000 1000000000\n-999999999 999999999\n999999999 -999999999\n\nSample Output 3\n\n3999999996000000001\n\nWatch out for integer overflows.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 17709, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s437403918", "group_id": "codeNet:p03577", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n\tstring s;\n\tcin >> s;\n\tcout << s.substr(0, s.length()-8) << endl;;\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1507510992, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03577.html", "problem_id": "p03577", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03577/input.txt", "sample_output_relpath": "derived/input_output/data/p03577/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03577/C++/s437403918.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s437403918", "user_id": "u725818030"}, "prompt_components": {"gold_output": "CODE\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n\tstring s;\n\tcin >> s;\n\tcout << s.substr(0, s.length()-8) << endl;;\n\treturn 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nRng is going to a festival.\n\nThe name of the festival is given to you as a string S, which ends with FESTIVAL, from input. Answer the question: \"Rng is going to a festival of what?\" Output the answer.\n\nHere, assume that the name of \"a festival of s\" is a string obtained by appending FESTIVAL to the end of s.\nFor example, CODEFESTIVAL is a festival of CODE.\n\nConstraints\n\n9 \\leq |S| \\leq 50\n\nS consists of uppercase English letters.\n\nS ends with FESTIVAL.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the answer to the question: \"Rng is going to a festival of what?\"\n\nSample Input 1\n\nCODEFESTIVAL\n\nSample Output 1\n\nCODE\n\nThis is the same as the example in the statement.\n\nSample Input 2\n\nCODEFESTIVALFESTIVAL\n\nSample Output 2\n\nCODEFESTIVAL\n\nThis string is obtained by appending FESTIVAL to the end of CODEFESTIVAL, so it is a festival of CODEFESTIVAL.\n\nSample Input 3\n\nYAKINIKUFESTIVAL\n\nSample Output 3\n\nYAKINIKU", "sample_input": "CODEFESTIVAL\n"}, "reference_outputs": ["CODE\n"], "source_document_id": "p03577", "source_text": "Score : 100 points\n\nProblem Statement\n\nRng is going to a festival.\n\nThe name of the festival is given to you as a string S, which ends with FESTIVAL, from input. Answer the question: \"Rng is going to a festival of what?\" Output the answer.\n\nHere, assume that the name of \"a festival of s\" is a string obtained by appending FESTIVAL to the end of s.\nFor example, CODEFESTIVAL is a festival of CODE.\n\nConstraints\n\n9 \\leq |S| \\leq 50\n\nS consists of uppercase English letters.\n\nS ends with FESTIVAL.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the answer to the question: \"Rng is going to a festival of what?\"\n\nSample Input 1\n\nCODEFESTIVAL\n\nSample Output 1\n\nCODE\n\nThis is the same as the example in the statement.\n\nSample Input 2\n\nCODEFESTIVALFESTIVAL\n\nSample Output 2\n\nCODEFESTIVAL\n\nThis string is obtained by appending FESTIVAL to the end of CODEFESTIVAL, so it is a festival of CODEFESTIVAL.\n\nSample Input 3\n\nYAKINIKUFESTIVAL\n\nSample Output 3\n\nYAKINIKU", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 139, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s853914597", "group_id": "codeNet:p03579", "input_text": "#include \"bits/stdc++.h\"\nusing namespace std;\n#define ll long long int\n#define rep(i,n) for( int i = 0; i < n; i++ )\n#define rrep(i,n) for( int i = n; i >= 0; i-- )\n#define REP(i,s,t) for( int i = s; i <= t; i++ )\n#define RREP(i,s,t) for( int i = s; i >= t; i-- )\n#define dump(x)  cerr << #x << \" = \" << (x) << endl;\n#define INF 2000000000\n#define mod 1000000007\n#define INF2 1000000000000000000\n\nvector<int> G[100010];\n\nint color[100010];\n\n// 頂点を1と-1で塗っていく\nbool dfs(int v, int c) {\n    color[v] = c;\n    for (int i = 0; i < G[v].size(); i++) {\n        // 隣接している頂点が同じ色ならfalse\n        if (color[G[v][i]] == c) return false;\n        // 隣接している頂点がまだ塗られていないなら-cで塗る\n        if (color[G[v][i]] == 0 && !dfs(G[v][i], -c)) return false;\n    }\n\n    // すべての頂点を塗れたらtrue\n    return true;\n\n}\nint main(void)\n{\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n    int N, M;\n    cin >> N >> M;\n    rep(i, M) {\n        int s, t;\n        cin >> s >> t;\n        s--; t--;\n        G[s].push_back(t);\n        G[t].push_back(s);\n    }\n    if(dfs(0, 1)) {\n        int k1 = 0, k2 = 0;\n        rep(i, 100010) {\n            if (color[i] == 1) k1++;\n            else if (color[i] == -1) k2++;\n        }\n        cout << k1 * k2 - M << endl;\n    } else {\n        cout << N * (N - 1) / 2 - M << endl;\n    }\n\n\n\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1581294364, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03579.html", "problem_id": "p03579", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03579/input.txt", "sample_output_relpath": "derived/input_output/data/p03579/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03579/C++/s853914597.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s853914597", "user_id": "u965730380"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include \"bits/stdc++.h\"\nusing namespace std;\n#define ll long long int\n#define rep(i,n) for( int i = 0; i < n; i++ )\n#define rrep(i,n) for( int i = n; i >= 0; i-- )\n#define REP(i,s,t) for( int i = s; i <= t; i++ )\n#define RREP(i,s,t) for( int i = s; i >= t; i-- )\n#define dump(x)  cerr << #x << \" = \" << (x) << endl;\n#define INF 2000000000\n#define mod 1000000007\n#define INF2 1000000000000000000\n\nvector<int> G[100010];\n\nint color[100010];\n\n// 頂点を1と-1で塗っていく\nbool dfs(int v, int c) {\n    color[v] = c;\n    for (int i = 0; i < G[v].size(); i++) {\n        // 隣接している頂点が同じ色ならfalse\n        if (color[G[v][i]] == c) return false;\n        // 隣接している頂点がまだ塗られていないなら-cで塗る\n        if (color[G[v][i]] == 0 && !dfs(G[v][i], -c)) return false;\n    }\n\n    // すべての頂点を塗れたらtrue\n    return true;\n\n}\nint main(void)\n{\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n    int N, M;\n    cin >> N >> M;\n    rep(i, M) {\n        int s, t;\n        cin >> s >> t;\n        s--; t--;\n        G[s].push_back(t);\n        G[t].push_back(s);\n    }\n    if(dfs(0, 1)) {\n        int k1 = 0, k2 = 0;\n        rep(i, 100010) {\n            if (color[i] == 1) k1++;\n            else if (color[i] == -1) k2++;\n        }\n        cout << k1 * k2 - M << endl;\n    } else {\n        cout << N * (N - 1) / 2 - M << endl;\n    }\n\n\n\n    return 0;\n}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nRng has a connected undirected graph with N vertices.\nCurrently, there are M edges in the graph, and the i-th edge connects Vertices A_i and B_i.\n\nRng will add new edges to the graph by repeating the following operation:\n\nOperation: Choose u and v (u \\neq v) such that Vertex v can be reached by traversing exactly three edges from Vertex u, and add an edge connecting Vertices u and v. It is not allowed to add an edge if there is already an edge connecting Vertices u and v.\n\nFind the maximum possible number of edges that can be added.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq A_i,B_i \\leq N\n\nThe graph has no self-loops or multiple edges.\n\nThe graph is connected.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 B_1\nA_2 B_2\n:\nA_M B_M\n\nOutput\n\nFind the maximum possible number of edges that can be added.\n\nSample Input 1\n\n6 5\n1 2\n2 3\n3 4\n4 5\n5 6\n\nSample Output 1\n\n4\n\nIf we add edges as shown below, four edges can be added, and no more.\n\nSample Input 2\n\n5 5\n1 2\n2 3\n3 1\n5 4\n5 1\n\nSample Output 2\n\n5\n\nFive edges can be added, for example, as follows:\n\nAdd an edge connecting Vertex 5 and Vertex 3.\n\nAdd an edge connecting Vertex 5 and Vertex 2.\n\nAdd an edge connecting Vertex 4 and Vertex 1.\n\nAdd an edge connecting Vertex 4 and Vertex 2.\n\nAdd an edge connecting Vertex 4 and Vertex 3.", "sample_input": "6 5\n1 2\n2 3\n3 4\n4 5\n5 6\n"}, "reference_outputs": ["4\n"], "source_document_id": "p03579", "source_text": "Score : 500 points\n\nProblem Statement\n\nRng has a connected undirected graph with N vertices.\nCurrently, there are M edges in the graph, and the i-th edge connects Vertices A_i and B_i.\n\nRng will add new edges to the graph by repeating the following operation:\n\nOperation: Choose u and v (u \\neq v) such that Vertex v can be reached by traversing exactly three edges from Vertex u, and add an edge connecting Vertices u and v. It is not allowed to add an edge if there is already an edge connecting Vertices u and v.\n\nFind the maximum possible number of edges that can be added.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq A_i,B_i \\leq N\n\nThe graph has no self-loops or multiple edges.\n\nThe graph is connected.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 B_1\nA_2 B_2\n:\nA_M B_M\n\nOutput\n\nFind the maximum possible number of edges that can be added.\n\nSample Input 1\n\n6 5\n1 2\n2 3\n3 4\n4 5\n5 6\n\nSample Output 1\n\n4\n\nIf we add edges as shown below, four edges can be added, and no more.\n\nSample Input 2\n\n5 5\n1 2\n2 3\n3 1\n5 4\n5 1\n\nSample Output 2\n\n5\n\nFive edges can be added, for example, as follows:\n\nAdd an edge connecting Vertex 5 and Vertex 3.\n\nAdd an edge connecting Vertex 5 and Vertex 2.\n\nAdd an edge connecting Vertex 4 and Vertex 1.\n\nAdd an edge connecting Vertex 4 and Vertex 2.\n\nAdd an edge connecting Vertex 4 and Vertex 3.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1411, "cpu_time_ms": 39, "memory_kb": 6528}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s928910575", "group_id": "codeNet:p03579", "input_text": "#include <bits/stdc++.h>\n#define For(i, l, r) for(int i = (l), _end_ = (int)(r); i <= _end_; ++i)\n#define Fordown(i, r, l) for(int i = (r), _end_ = (int)(l); i >= _end_; --i)\n#define Set(a, v) memset(a, v, sizeof(a))\nusing namespace std;\n\nbool chkmin(int &a, int b) {return b < a ? a = b, 1 : 0;}\nbool chkmax(int &a, int b) {return b > a ? a = b, 1 : 0;}\n\ninline int read() {\n int x = 0, fh = 1; char ch = getchar();\n    for (; !isdigit(ch); ch = getchar() ) if (ch == '-') fh = -1;\n    for (; isdigit(ch); ch = getchar() ) x = (x<<1) + (x<<3) + (ch ^ '0');\n    return x * fh;\n}\n\nvoid file() {\n#ifdef zjp_shadow\n\tfreopen (\"c.in\", \"r\", stdin);\n\tfreopen (\"c.out\", \"w\", stdout);\n#endif\n}\n\nconst int N = 100100, M = N << 1;\nvector<int> G[N];\nset<int> S[N];\nint n, m;\nvoid input() {\n\tn = read();\n\tm = read();\n\tFor (i, 1, m) {\n\t\tint u = read(), v = read();\n\t\tG[u].push_back(v);\n\t\tS[u].insert(v);\n\t\tG[v].push_back(u);\n\t\tS[v].insert(u);\n\t}\n}\n\nbool vis[N];\nset<int> dep[N][3];\ntypedef set<int>::iterator it;\nint ans = 0, pre[N];\n#define all(x) x.begin(), x.end()\nvoid dfs (int u) {\n\tvis[u] = true;\n\tfor (it i = dep[u][2].begin(); i != dep[u][2].end(); ++i) {\n\t\tint from = (*i);\n\t\tif (u != from && from && S[u].find(from) == S[u].end()) {\n\t\t\t++ ans;\n\t\t\tG[u].push_back(from);\n\t\t\tG[from].push_back(u);\n\t\t\tS[u].insert(from);\n\t\t\tS[from].insert(u);\n\t\t}\n\t}\n\n\tfor (int i = 0; i < (G[u].size() ) ; ++i) {\n\t\tint v = G[u][i];\n\t\tif (vis[v]) continue ;\n\t\tpre[v] = u;\n\t\tdep[u][0].insert(v);\n\t\tdep[v][0].insert(u);\n\t\tdep[u][2].insert(all(dep[v][1]) );\n\t\tdep[v][2].insert(all(dep[u][1]) );\n\t\tdep[u][1].insert(all(dep[v][0]) );\n\t\tdep[v][1].insert(all(dep[u][0]) );\n\t\tdfs (v);\n\t}\n\tvis[u] = false;\n}\n\nvoid solve() {\n\tdfs (1);\n\n}\n\nvoid output() {\n\tprintf (\"%d\\n\", ans);\n}\n\nint main () {\n\tfile();\n\tinput();\n\tsolve();\n\toutput();\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1507517408, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03579.html", "problem_id": "p03579", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03579/input.txt", "sample_output_relpath": "derived/input_output/data/p03579/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03579/C++/s928910575.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s928910575", "user_id": "u737214831"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define For(i, l, r) for(int i = (l), _end_ = (int)(r); i <= _end_; ++i)\n#define Fordown(i, r, l) for(int i = (r), _end_ = (int)(l); i >= _end_; --i)\n#define Set(a, v) memset(a, v, sizeof(a))\nusing namespace std;\n\nbool chkmin(int &a, int b) {return b < a ? a = b, 1 : 0;}\nbool chkmax(int &a, int b) {return b > a ? a = b, 1 : 0;}\n\ninline int read() {\n int x = 0, fh = 1; char ch = getchar();\n    for (; !isdigit(ch); ch = getchar() ) if (ch == '-') fh = -1;\n    for (; isdigit(ch); ch = getchar() ) x = (x<<1) + (x<<3) + (ch ^ '0');\n    return x * fh;\n}\n\nvoid file() {\n#ifdef zjp_shadow\n\tfreopen (\"c.in\", \"r\", stdin);\n\tfreopen (\"c.out\", \"w\", stdout);\n#endif\n}\n\nconst int N = 100100, M = N << 1;\nvector<int> G[N];\nset<int> S[N];\nint n, m;\nvoid input() {\n\tn = read();\n\tm = read();\n\tFor (i, 1, m) {\n\t\tint u = read(), v = read();\n\t\tG[u].push_back(v);\n\t\tS[u].insert(v);\n\t\tG[v].push_back(u);\n\t\tS[v].insert(u);\n\t}\n}\n\nbool vis[N];\nset<int> dep[N][3];\ntypedef set<int>::iterator it;\nint ans = 0, pre[N];\n#define all(x) x.begin(), x.end()\nvoid dfs (int u) {\n\tvis[u] = true;\n\tfor (it i = dep[u][2].begin(); i != dep[u][2].end(); ++i) {\n\t\tint from = (*i);\n\t\tif (u != from && from && S[u].find(from) == S[u].end()) {\n\t\t\t++ ans;\n\t\t\tG[u].push_back(from);\n\t\t\tG[from].push_back(u);\n\t\t\tS[u].insert(from);\n\t\t\tS[from].insert(u);\n\t\t}\n\t}\n\n\tfor (int i = 0; i < (G[u].size() ) ; ++i) {\n\t\tint v = G[u][i];\n\t\tif (vis[v]) continue ;\n\t\tpre[v] = u;\n\t\tdep[u][0].insert(v);\n\t\tdep[v][0].insert(u);\n\t\tdep[u][2].insert(all(dep[v][1]) );\n\t\tdep[v][2].insert(all(dep[u][1]) );\n\t\tdep[u][1].insert(all(dep[v][0]) );\n\t\tdep[v][1].insert(all(dep[u][0]) );\n\t\tdfs (v);\n\t}\n\tvis[u] = false;\n}\n\nvoid solve() {\n\tdfs (1);\n\n}\n\nvoid output() {\n\tprintf (\"%d\\n\", ans);\n}\n\nint main () {\n\tfile();\n\tinput();\n\tsolve();\n\toutput();\n    return 0;\n}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nRng has a connected undirected graph with N vertices.\nCurrently, there are M edges in the graph, and the i-th edge connects Vertices A_i and B_i.\n\nRng will add new edges to the graph by repeating the following operation:\n\nOperation: Choose u and v (u \\neq v) such that Vertex v can be reached by traversing exactly three edges from Vertex u, and add an edge connecting Vertices u and v. It is not allowed to add an edge if there is already an edge connecting Vertices u and v.\n\nFind the maximum possible number of edges that can be added.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq A_i,B_i \\leq N\n\nThe graph has no self-loops or multiple edges.\n\nThe graph is connected.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 B_1\nA_2 B_2\n:\nA_M B_M\n\nOutput\n\nFind the maximum possible number of edges that can be added.\n\nSample Input 1\n\n6 5\n1 2\n2 3\n3 4\n4 5\n5 6\n\nSample Output 1\n\n4\n\nIf we add edges as shown below, four edges can be added, and no more.\n\nSample Input 2\n\n5 5\n1 2\n2 3\n3 1\n5 4\n5 1\n\nSample Output 2\n\n5\n\nFive edges can be added, for example, as follows:\n\nAdd an edge connecting Vertex 5 and Vertex 3.\n\nAdd an edge connecting Vertex 5 and Vertex 2.\n\nAdd an edge connecting Vertex 4 and Vertex 1.\n\nAdd an edge connecting Vertex 4 and Vertex 2.\n\nAdd an edge connecting Vertex 4 and Vertex 3.", "sample_input": "6 5\n1 2\n2 3\n3 4\n4 5\n5 6\n"}, "reference_outputs": ["4\n"], "source_document_id": "p03579", "source_text": "Score : 500 points\n\nProblem Statement\n\nRng has a connected undirected graph with N vertices.\nCurrently, there are M edges in the graph, and the i-th edge connects Vertices A_i and B_i.\n\nRng will add new edges to the graph by repeating the following operation:\n\nOperation: Choose u and v (u \\neq v) such that Vertex v can be reached by traversing exactly three edges from Vertex u, and add an edge connecting Vertices u and v. It is not allowed to add an edge if there is already an edge connecting Vertices u and v.\n\nFind the maximum possible number of edges that can be added.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n1 \\leq M \\leq 10^5\n\n1 \\leq A_i,B_i \\leq N\n\nThe graph has no self-loops or multiple edges.\n\nThe graph is connected.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\nA_1 B_1\nA_2 B_2\n:\nA_M B_M\n\nOutput\n\nFind the maximum possible number of edges that can be added.\n\nSample Input 1\n\n6 5\n1 2\n2 3\n3 4\n4 5\n5 6\n\nSample Output 1\n\n4\n\nIf we add edges as shown below, four edges can be added, and no more.\n\nSample Input 2\n\n5 5\n1 2\n2 3\n3 1\n5 4\n5 1\n\nSample Output 2\n\n5\n\nFive edges can be added, for example, as follows:\n\nAdd an edge connecting Vertex 5 and Vertex 3.\n\nAdd an edge connecting Vertex 5 and Vertex 2.\n\nAdd an edge connecting Vertex 4 and Vertex 1.\n\nAdd an edge connecting Vertex 4 and Vertex 2.\n\nAdd an edge connecting Vertex 4 and Vertex 3.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1814, "cpu_time_ms": 2105, "memory_kb": 45696}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s820886040", "group_id": "codeNet:p03582", "input_text": "#include<set>\n#include<cstdio>\n#include<cctype>\n#include<string>\ninline int Read(){\n\tchar a;\n\tint b;\n\twhile(!isdigit(a=getchar()));\n\tb=a^'0';\n\twhile(isdigit(a=getchar()))b=(((b<<2)+b)<<1)+(a^'0');\n\treturn b;\n}\nint main()\n{\n\tstd::multiset<std::string> set;\n\tfor(int i=Read();i;i--)set.insert(\"a\");\n\tfor(int i=Read();i;i--)set.insert(\"b\");\n\tfor(int i=Read();i;i--)set.insert(\"c\");\n\twhile(set.size()>1){\n\t\tstd::string s=*set.begin(),t=*set.rbegin();\n\t\tset.erase(set.lower_bound(s));\n\t\tset.erase(set.lower_bound(t));\n\t\tset.insert(s+t);\n\t}\n\tprintf(\"%s\\n\",(*set.begin()).c_str());\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1559751857, "filename_ext": "cpp", "original_language": "C++ (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03582.html", "problem_id": "p03582", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03582/input.txt", "sample_output_relpath": "derived/input_output/data/p03582/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03582/C++/s820886040.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s820886040", "user_id": "u960117949"}, "prompt_components": {"gold_output": "abab\n", "input_to_evaluate": "#include<set>\n#include<cstdio>\n#include<cctype>\n#include<string>\ninline int Read(){\n\tchar a;\n\tint b;\n\twhile(!isdigit(a=getchar()));\n\tb=a^'0';\n\twhile(isdigit(a=getchar()))b=(((b<<2)+b)<<1)+(a^'0');\n\treturn b;\n}\nint main()\n{\n\tstd::multiset<std::string> set;\n\tfor(int i=Read();i;i--)set.insert(\"a\");\n\tfor(int i=Read();i;i--)set.insert(\"b\");\n\tfor(int i=Read();i;i--)set.insert(\"c\");\n\twhile(set.size()>1){\n\t\tstd::string s=*set.begin(),t=*set.rbegin();\n\t\tset.erase(set.lower_bound(s));\n\t\tset.erase(set.lower_bound(t));\n\t\tset.insert(s+t);\n\t}\n\tprintf(\"%s\\n\",(*set.begin()).c_str());\n\treturn 0;\n}", "problem_context": "Score : 1600 points\n\nProblem Statement\n\nFor a string S, let f(S) be the lexicographically smallest cyclic shift of S.\nFor example, if S = babca, f(S) = ababc because this is the smallest among all cyclic shifts (babca, abcab, bcaba, cabab, ababc).\n\nYou are given three integers X, Y, and Z.\nYou want to construct a string T that consists of exactly X as, exactly Y bs, and exactly Z cs.\nIf there are multiple such strings, you want to choose one that maximizes f(T) lexicographically.\n\nCompute the lexicographically largest possible value of f(T).\n\nConstraints\n\n1 \\leq X + Y + Z \\leq 50\n\nX, Y, Z are non-negative integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX Y Z\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n2 2 0\n\nSample Output 1\n\nabab\n\nT must consist of two as and two bs.\n\nIf T = aabb, f(T) = aabb.\n\nIf T = abab, f(T) = abab.\n\nIf T = abba, f(T) = aabb.\n\nIf T = baab, f(T) = aabb.\n\nIf T = baba, f(T) = abab.\n\nIf T = bbaa, f(T) = aabb.\n\nThus, the largest possible f(T) is abab.\n\nSample Input 2\n\n1 1 1\n\nSample Output 2\n\nacb", "sample_input": "2 2 0\n"}, "reference_outputs": ["abab\n"], "source_document_id": "p03582", "source_text": "Score : 1600 points\n\nProblem Statement\n\nFor a string S, let f(S) be the lexicographically smallest cyclic shift of S.\nFor example, if S = babca, f(S) = ababc because this is the smallest among all cyclic shifts (babca, abcab, bcaba, cabab, ababc).\n\nYou are given three integers X, Y, and Z.\nYou want to construct a string T that consists of exactly X as, exactly Y bs, and exactly Z cs.\nIf there are multiple such strings, you want to choose one that maximizes f(T) lexicographically.\n\nCompute the lexicographically largest possible value of f(T).\n\nConstraints\n\n1 \\leq X + Y + Z \\leq 50\n\nX, Y, Z are non-negative integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX Y Z\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n2 2 0\n\nSample Output 1\n\nabab\n\nT must consist of two as and two bs.\n\nIf T = aabb, f(T) = aabb.\n\nIf T = abab, f(T) = abab.\n\nIf T = abba, f(T) = aabb.\n\nIf T = baab, f(T) = aabb.\n\nIf T = baba, f(T) = abab.\n\nIf T = bbaa, f(T) = aabb.\n\nThus, the largest possible f(T) is abab.\n\nSample Input 2\n\n1 1 1\n\nSample Output 2\n\nacb", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 587, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s573303298", "group_id": "codeNet:p03583", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\nusing ll = long long;\nll m = 1e9 + 7;\n\nint main() {\n  int N;\n  cin >> N;\n\n  for (int h = 1; h <= 3500; h++) {\n    for (int n = 1; n <= 3500; n++){\n      if ((4*h*n-N*n-N*h) == 0) continue;\n      if ((N*h*n) % (4*h*n-N*n-N*h) == 0){\n        if ((N*h*n) / (4*h*n-N*n-N*h) >= 1){\n          cout << h << endl;\n          cout << n << endl;\n          cout << (N*h*n) / (4*h*n-N*n-N*h) << endl;\n          return 0;\n        }\n      }\n    }\n  }\n\n  return 0;\n\n}", "language": "C++", "metadata": {"date": 1597718021, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03583.html", "problem_id": "p03583", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03583/input.txt", "sample_output_relpath": "derived/input_output/data/p03583/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03583/C++/s573303298.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s573303298", "user_id": "u106342872"}, "prompt_components": {"gold_output": "1 2 2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\nusing ll = long long;\nll m = 1e9 + 7;\n\nint main() {\n  int N;\n  cin >> N;\n\n  for (int h = 1; h <= 3500; h++) {\n    for (int n = 1; n <= 3500; n++){\n      if ((4*h*n-N*n-N*h) == 0) continue;\n      if ((N*h*n) % (4*h*n-N*n-N*h) == 0){\n        if ((N*h*n) / (4*h*n-N*n-N*h) >= 1){\n          cout << h << endl;\n          cout << n << endl;\n          cout << (N*h*n) / (4*h*n-N*n-N*h) << endl;\n          return 0;\n        }\n      }\n    }\n  }\n\n  return 0;\n\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nYou are given an integer N.\n\nFind a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.\n\nIf there are multiple solutions, any of them will be accepted.\n\nConstraints\n\nIt is guaranteed that, for the given integer N, there exists a solution such that h,n,w \\leq 3500.\n\nInputs\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutputs\n\nPrint a triple of positive integers h, n and w that satisfies the condition, in the following format:\n\nh n w\n\nSample Input 1\n\n2\n\nSample Output 1\n\n1 2 2\n\n4/2 = 1/1 + 1/2 + 1/2.\n\nSample Input 2\n\n3485\n\nSample Output 2\n\n872 1012974 1539173474040\n\nIt is allowed to use an integer exceeding 3500 in a solution.\n\nSample Input 3\n\n4664\n\nSample Output 3\n\n3498 3498 3498", "sample_input": "2\n"}, "reference_outputs": ["1 2 2\n"], "source_document_id": "p03583", "source_text": "Score : 300 points\n\nProblem Statement\n\nYou are given an integer N.\n\nFind a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.\n\nIf there are multiple solutions, any of them will be accepted.\n\nConstraints\n\nIt is guaranteed that, for the given integer N, there exists a solution such that h,n,w \\leq 3500.\n\nInputs\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutputs\n\nPrint a triple of positive integers h, n and w that satisfies the condition, in the following format:\n\nh n w\n\nSample Input 1\n\n2\n\nSample Output 1\n\n1 2 2\n\n4/2 = 1/1 + 1/2 + 1/2.\n\nSample Input 2\n\n3485\n\nSample Output 2\n\n872 1012974 1539173474040\n\nIt is allowed to use an integer exceeding 3500 in a solution.\n\nSample Input 3\n\n4664\n\nSample Output 3\n\n3498 3498 3498", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 550, "cpu_time_ms": 31, "memory_kb": 3616}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s689436211", "group_id": "codeNet:p03583", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i,k,n) for(int i = (k); i < n;i++)\n\nlong double calc (int N,int h,int n){\n\tlong double temp = n * h * N;\n\tlong double timp = 4*h*n - n*N - h*N;\n\treturn temp / timp;\n}\n\nint main(){\n\tint N;\n\tcin >> N;\n\tint h,n,w;\n\trep(i,1,3500){\n\t\trep(j,1,3500){\n\n\t\t\tlong double temp = calc(N,i,j);\n\t\t\tif(((temp - int(temp)) == 0) && (temp > 0)){\n\t\t\t\th = i;\n\t\t\t\tn = j;\n\t\t\t\tw = temp;\n\t\t\t\tcout << h << \" \" << n << \" \" << w << endl;\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n}", "language": "C++", "metadata": {"date": 1563966531, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03583.html", "problem_id": "p03583", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03583/input.txt", "sample_output_relpath": "derived/input_output/data/p03583/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03583/C++/s689436211.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s689436211", "user_id": "u239316561"}, "prompt_components": {"gold_output": "1 2 2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i,k,n) for(int i = (k); i < n;i++)\n\nlong double calc (int N,int h,int n){\n\tlong double temp = n * h * N;\n\tlong double timp = 4*h*n - n*N - h*N;\n\treturn temp / timp;\n}\n\nint main(){\n\tint N;\n\tcin >> N;\n\tint h,n,w;\n\trep(i,1,3500){\n\t\trep(j,1,3500){\n\n\t\t\tlong double temp = calc(N,i,j);\n\t\t\tif(((temp - int(temp)) == 0) && (temp > 0)){\n\t\t\t\th = i;\n\t\t\t\tn = j;\n\t\t\t\tw = temp;\n\t\t\t\tcout << h << \" \" << n << \" \" << w << endl;\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nYou are given an integer N.\n\nFind a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.\n\nIf there are multiple solutions, any of them will be accepted.\n\nConstraints\n\nIt is guaranteed that, for the given integer N, there exists a solution such that h,n,w \\leq 3500.\n\nInputs\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutputs\n\nPrint a triple of positive integers h, n and w that satisfies the condition, in the following format:\n\nh n w\n\nSample Input 1\n\n2\n\nSample Output 1\n\n1 2 2\n\n4/2 = 1/1 + 1/2 + 1/2.\n\nSample Input 2\n\n3485\n\nSample Output 2\n\n872 1012974 1539173474040\n\nIt is allowed to use an integer exceeding 3500 in a solution.\n\nSample Input 3\n\n4664\n\nSample Output 3\n\n3498 3498 3498", "sample_input": "2\n"}, "reference_outputs": ["1 2 2\n"], "source_document_id": "p03583", "source_text": "Score : 300 points\n\nProblem Statement\n\nYou are given an integer N.\n\nFind a triple of positive integers h, n and w such that 4/N = 1/h + 1/n + 1/w.\n\nIf there are multiple solutions, any of them will be accepted.\n\nConstraints\n\nIt is guaranteed that, for the given integer N, there exists a solution such that h,n,w \\leq 3500.\n\nInputs\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutputs\n\nPrint a triple of positive integers h, n and w that satisfies the condition, in the following format:\n\nh n w\n\nSample Input 1\n\n2\n\nSample Output 1\n\n1 2 2\n\n4/2 = 1/1 + 1/2 + 1/2.\n\nSample Input 2\n\n3485\n\nSample Output 2\n\n872 1012974 1539173474040\n\nIt is allowed to use an integer exceeding 3500 in a solution.\n\nSample Input 3\n\n4664\n\nSample Output 3\n\n3498 3498 3498", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 496, "cpu_time_ms": 32, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s426300895", "group_id": "codeNet:p03585", "input_text": "#include <bits/stdc++.h>\n#define REP(i, a, n) for(ll i = ((ll) a); i < ((ll) n); i++)\nusing namespace std;\ntypedef long long ll;\n\nstruct line { double p, d; ll n; };\n\nll N, A[100000], B[100000], C[100000];\n\ntemplate<typename T> class BinaryIndexedTree {\n  vector<T> vec;\n  const ll n;\n\npublic:\n  BinaryIndexedTree(T _n) : vec(_n + 1), n(_n) {}\n\n  T query(ll x) {\n    T ret = 0;\n    for(ll i = x; i > 0; i -= i & (-i)) ret += vec[i];\n    return ret;\n  }\n\n  void update(ll x, T k) {\n    for(ll i = x; i <= n; i += i & (-i)) vec[i] += k;\n  }\n};\n\nbool ok(double x, ll k) {\n  line l[100000];\n  REP(i, 0, N) l[i] = (line) { (double) (C[i] - A[i] * x) / B[i], (double) -A[i] / B[i], 0 };\n\n  sort(l, l + N, [](const line &a, const line &b) { return a.d < b.d; });\n  REP(i, 0, N) l[i].n = i + 1;\n  sort(l, l + N, [](const line &a, const line &b) { return a.p < b.p; });\n\n  BinaryIndexedTree<ll> bit(100000);\n  ll cnt = 0;\n  REP(i, 0, N) {\n    cnt += i - bit.query(l[i].n);\n    bit.update(l[i].n, 1);\n  }\n\n  return N * (N - 1) / 2 - cnt < k;\n}\n\nint main(void) {\n  cin >> N;\n  REP(i, 0, N) cin >> A[i] >> B[i] >> C[i];\n\n  ll n = N * (N - 1) / 2;\n  ll k = n / 2 + (n % 2 ? 1 : 0);\n\n  double lx = -1e5, hx = 1e5;\n  REP(i, 0, 200) {\n    double mx = (lx + hx) / 2;\n    if(ok(mx, k)) lx = mx;\n    else hx = mx;\n  }\n\n  REP(i, 0, N) swap(A[i], B[i]);\n\n  double ly = -1e5, hy = 1e5;\n  REP(i, 0, 200) {\n    double my = (ly + hy) / 2;\n    if(ok(my, k)) ly = my;\n    else hy = my;\n  }\n\n  printf(\"%.15lf %.15lf\\n\", hx, hy);\n}\n", "language": "C++", "metadata": {"date": 1506839241, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03585.html", "problem_id": "p03585", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03585/input.txt", "sample_output_relpath": "derived/input_output/data/p03585/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03585/C++/s426300895.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s426300895", "user_id": "u981861542"}, "prompt_components": {"gold_output": "1.000000000000000 1.000000000000000\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define REP(i, a, n) for(ll i = ((ll) a); i < ((ll) n); i++)\nusing namespace std;\ntypedef long long ll;\n\nstruct line { double p, d; ll n; };\n\nll N, A[100000], B[100000], C[100000];\n\ntemplate<typename T> class BinaryIndexedTree {\n  vector<T> vec;\n  const ll n;\n\npublic:\n  BinaryIndexedTree(T _n) : vec(_n + 1), n(_n) {}\n\n  T query(ll x) {\n    T ret = 0;\n    for(ll i = x; i > 0; i -= i & (-i)) ret += vec[i];\n    return ret;\n  }\n\n  void update(ll x, T k) {\n    for(ll i = x; i <= n; i += i & (-i)) vec[i] += k;\n  }\n};\n\nbool ok(double x, ll k) {\n  line l[100000];\n  REP(i, 0, N) l[i] = (line) { (double) (C[i] - A[i] * x) / B[i], (double) -A[i] / B[i], 0 };\n\n  sort(l, l + N, [](const line &a, const line &b) { return a.d < b.d; });\n  REP(i, 0, N) l[i].n = i + 1;\n  sort(l, l + N, [](const line &a, const line &b) { return a.p < b.p; });\n\n  BinaryIndexedTree<ll> bit(100000);\n  ll cnt = 0;\n  REP(i, 0, N) {\n    cnt += i - bit.query(l[i].n);\n    bit.update(l[i].n, 1);\n  }\n\n  return N * (N - 1) / 2 - cnt < k;\n}\n\nint main(void) {\n  cin >> N;\n  REP(i, 0, N) cin >> A[i] >> B[i] >> C[i];\n\n  ll n = N * (N - 1) / 2;\n  ll k = n / 2 + (n % 2 ? 1 : 0);\n\n  double lx = -1e5, hx = 1e5;\n  REP(i, 0, 200) {\n    double mx = (lx + hx) / 2;\n    if(ok(mx, k)) lx = mx;\n    else hx = mx;\n  }\n\n  REP(i, 0, N) swap(A[i], B[i]);\n\n  double ly = -1e5, hy = 1e5;\n  REP(i, 0, 200) {\n    double my = (ly + hy) / 2;\n    if(ok(my, k)) ly = my;\n    else hy = my;\n  }\n\n  printf(\"%.15lf %.15lf\\n\", hx, hy);\n}\n", "problem_context": "Score : 800 points\n\nProblem Statement\n\nThere are N lines in the xy-plane. The i-th line is represented by A_ix+B_iy=C_i.\nAny two lines among the N+2 lines, the above N lines plus the x-axis and y-axis, cross each other at exactly one point.\n\nFor each pair 1 \\leq i < j \\leq N, there is a car at the cross point of the i-th and j-th lines.\nEven where three or more lines intersect at a point, a car is individually placed for each pair of lines.\nThat is, there will be k(k-1)/2 cars placed at the intersection of k lines.\n\nThose cars are already very old, and can only be moved parallel to the x-axis or y-axis.\n\nTakahashi will hold an exhibition of antique cars at a place on the xy-plane.\nIn order to avoid damaging the half-broken cars too much, he will select the place of the exhibition so that the total distance covered will be minimized when all the cars are moved to the place.\nIf such a place is not uniquely determined, among the places that satisfy the condition above, the place with the minimum x-coordinate will be selected.\nIf the place is still not uniquely determined, among the places that satisfy the two conditions above, the place with the minimum y-coordinate will be selected.\n\nFind the place of the exhibition that will be selected.\n\nConstraints\n\n2 \\leq N \\leq 4 × 10^4\n\n1 \\leq |A_i|,|B_i| \\leq 10^4(1 \\leq i \\leq N)\n\n0 \\leq |C_i| \\leq 10^4(1 \\leq i \\leq N)\n\nNo two given lines are parallel.\n\nAll input values are integers.\n\nInputs\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 B_1 C_1\n:\nA_N B_N C_N\n\nOutputs\n\nPrint the x-coordinate and y-coordinate of the place of the exhibition that will be selected, in this order, with a space in between. The output will be judged as correct when the absolute or relative error is at most 10^{-9}.\n\nSample Input 1\n\n3\n1 1 1\n2 -1 2\n-1 2 2\n\nSample Output 1\n\n1.000000000000000 1.000000000000000\n\nThere is a car at each place shown by a blue circle in the figure. The place to be selected is shown by a purple circle.\n\nSample Input 2\n\n4\n1 1 2\n1 -1 0\n3 -1 -2\n1 -3 4\n\nSample Output 2\n\n-1.000000000000000 -1.000000000000000\n\nSample Input 3\n\n7\n1 7 8\n-2 4 9\n3 -8 -5\n9 2 -14\n6 7 5\n-8 -9 3\n3 8 10\n\nSample Output 3\n\n-1.722222222222222 1.325000000000000", "sample_input": "3\n1 1 1\n2 -1 2\n-1 2 2\n"}, "reference_outputs": ["1.000000000000000 1.000000000000000\n"], "source_document_id": "p03585", "source_text": "Score : 800 points\n\nProblem Statement\n\nThere are N lines in the xy-plane. The i-th line is represented by A_ix+B_iy=C_i.\nAny two lines among the N+2 lines, the above N lines plus the x-axis and y-axis, cross each other at exactly one point.\n\nFor each pair 1 \\leq i < j \\leq N, there is a car at the cross point of the i-th and j-th lines.\nEven where three or more lines intersect at a point, a car is individually placed for each pair of lines.\nThat is, there will be k(k-1)/2 cars placed at the intersection of k lines.\n\nThose cars are already very old, and can only be moved parallel to the x-axis or y-axis.\n\nTakahashi will hold an exhibition of antique cars at a place on the xy-plane.\nIn order to avoid damaging the half-broken cars too much, he will select the place of the exhibition so that the total distance covered will be minimized when all the cars are moved to the place.\nIf such a place is not uniquely determined, among the places that satisfy the condition above, the place with the minimum x-coordinate will be selected.\nIf the place is still not uniquely determined, among the places that satisfy the two conditions above, the place with the minimum y-coordinate will be selected.\n\nFind the place of the exhibition that will be selected.\n\nConstraints\n\n2 \\leq N \\leq 4 × 10^4\n\n1 \\leq |A_i|,|B_i| \\leq 10^4(1 \\leq i \\leq N)\n\n0 \\leq |C_i| \\leq 10^4(1 \\leq i \\leq N)\n\nNo two given lines are parallel.\n\nAll input values are integers.\n\nInputs\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 B_1 C_1\n:\nA_N B_N C_N\n\nOutputs\n\nPrint the x-coordinate and y-coordinate of the place of the exhibition that will be selected, in this order, with a space in between. The output will be judged as correct when the absolute or relative error is at most 10^{-9}.\n\nSample Input 1\n\n3\n1 1 1\n2 -1 2\n-1 2 2\n\nSample Output 1\n\n1.000000000000000 1.000000000000000\n\nThere is a car at each place shown by a blue circle in the figure. The place to be selected is shown by a purple circle.\n\nSample Input 2\n\n4\n1 1 2\n1 -1 0\n3 -1 -2\n1 -3 4\n\nSample Output 2\n\n-1.000000000000000 -1.000000000000000\n\nSample Input 3\n\n7\n1 7 8\n-2 4 9\n3 -8 -5\n9 2 -14\n6 7 5\n-8 -9 3\n3 8 10\n\nSample Output 3\n\n-1.722222222222222 1.325000000000000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1503, "cpu_time_ms": 2787, "memory_kb": 4224}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s732683335", "group_id": "codeNet:p03587", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nint main(void){\n  int a=0,b;\n  char c;\n  string s;\n cin >> s;\n  for(int i = 0;i < s.size();i++){\n    if(s.at(i) == '1'){\n      a++;\n    }\n  }\n  cout << a;\n}", "language": "C++", "metadata": {"date": 1573235258, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03587.html", "problem_id": "p03587", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03587/input.txt", "sample_output_relpath": "derived/input_output/data/p03587/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03587/C++/s732683335.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s732683335", "user_id": "u259356079"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nint main(void){\n  int a=0,b;\n  char c;\n  string s;\n cin >> s;\n  for(int i = 0;i < s.size();i++){\n    if(s.at(i) == '1'){\n      a++;\n    }\n  }\n  cout << a;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nSnuke prepared 6 problems for a upcoming programming contest.\nFor each of those problems, Rng judged whether it can be used in the contest or not.\n\nYou are given a string S of length 6.\nIf the i-th character of s is 1, it means that the i-th problem prepared by Snuke is accepted to be used; 0 means that the problem is not accepted.\n\nHow many problems prepared by Snuke are accepted to be used in the contest?\n\nConstraints\n\nThe length of S is 6.\n\nS consists of 0 and 1.\n\nInputs\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutputs\n\nPrint the number of problems prepared by Snuke that are accepted to be used in the contest.\n\nSample Input 1\n\n111100\n\nSample Output 1\n\n4\n\nThe first, second, third and fourth problems are accepted, for a total of four.\n\nSample Input 2\n\n001001\n\nSample Output 2\n\n2\n\nSample Input 3\n\n000000\n\nSample Output 3\n\n0", "sample_input": "111100\n"}, "reference_outputs": ["4\n"], "source_document_id": "p03587", "source_text": "Score : 100 points\n\nProblem Statement\n\nSnuke prepared 6 problems for a upcoming programming contest.\nFor each of those problems, Rng judged whether it can be used in the contest or not.\n\nYou are given a string S of length 6.\nIf the i-th character of s is 1, it means that the i-th problem prepared by Snuke is accepted to be used; 0 means that the problem is not accepted.\n\nHow many problems prepared by Snuke are accepted to be used in the contest?\n\nConstraints\n\nThe length of S is 6.\n\nS consists of 0 and 1.\n\nInputs\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutputs\n\nPrint the number of problems prepared by Snuke that are accepted to be used in the contest.\n\nSample Input 1\n\n111100\n\nSample Output 1\n\n4\n\nThe first, second, third and fourth problems are accepted, for a total of four.\n\nSample Input 2\n\n001001\n\nSample Output 2\n\n2\n\nSample Input 3\n\n000000\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 201, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s153208577", "group_id": "codeNet:p03587", "input_text": "#include <stdlib.h>\n#include <iostream>\n#include <algorithm>\n#include <string>\n\nusing namespace std;\n\nint main(void){\n    string S;\n\n    for(int i=0;i<6;i++){\n        S[i] = '0';\n    }\n    \n    cin >> S;\n\n    int a = 0;\n    for(int i=0;i<6;i++){\n        if(S[i] == '1'){\n            a = a + 1;\n        }\n    }\n    cout << a << endl;\n    return 0;\n\n}", "language": "C++", "metadata": {"date": 1506866705, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03587.html", "problem_id": "p03587", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03587/input.txt", "sample_output_relpath": "derived/input_output/data/p03587/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03587/C++/s153208577.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s153208577", "user_id": "u249895018"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <stdlib.h>\n#include <iostream>\n#include <algorithm>\n#include <string>\n\nusing namespace std;\n\nint main(void){\n    string S;\n\n    for(int i=0;i<6;i++){\n        S[i] = '0';\n    }\n    \n    cin >> S;\n\n    int a = 0;\n    for(int i=0;i<6;i++){\n        if(S[i] == '1'){\n            a = a + 1;\n        }\n    }\n    cout << a << endl;\n    return 0;\n\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nSnuke prepared 6 problems for a upcoming programming contest.\nFor each of those problems, Rng judged whether it can be used in the contest or not.\n\nYou are given a string S of length 6.\nIf the i-th character of s is 1, it means that the i-th problem prepared by Snuke is accepted to be used; 0 means that the problem is not accepted.\n\nHow many problems prepared by Snuke are accepted to be used in the contest?\n\nConstraints\n\nThe length of S is 6.\n\nS consists of 0 and 1.\n\nInputs\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutputs\n\nPrint the number of problems prepared by Snuke that are accepted to be used in the contest.\n\nSample Input 1\n\n111100\n\nSample Output 1\n\n4\n\nThe first, second, third and fourth problems are accepted, for a total of four.\n\nSample Input 2\n\n001001\n\nSample Output 2\n\n2\n\nSample Input 3\n\n000000\n\nSample Output 3\n\n0", "sample_input": "111100\n"}, "reference_outputs": ["4\n"], "source_document_id": "p03587", "source_text": "Score : 100 points\n\nProblem Statement\n\nSnuke prepared 6 problems for a upcoming programming contest.\nFor each of those problems, Rng judged whether it can be used in the contest or not.\n\nYou are given a string S of length 6.\nIf the i-th character of s is 1, it means that the i-th problem prepared by Snuke is accepted to be used; 0 means that the problem is not accepted.\n\nHow many problems prepared by Snuke are accepted to be used in the contest?\n\nConstraints\n\nThe length of S is 6.\n\nS consists of 0 and 1.\n\nInputs\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutputs\n\nPrint the number of problems prepared by Snuke that are accepted to be used in the contest.\n\nSample Input 1\n\n111100\n\nSample Output 1\n\n4\n\nThe first, second, third and fourth problems are accepted, for a total of four.\n\nSample Input 2\n\n001001\n\nSample Output 2\n\n2\n\nSample Input 3\n\n000000\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 349, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s769017532", "group_id": "codeNet:p03592", "input_text": "#include <iostream>\nusing namespace std;\n\nint main()\n{\n  int n, m, k; cin >> n >> m >> k;\n  for (int i = 0; i < n; i++) {\n    for (int j = 0; j < m; j++) {\n      if (i*(m-j)+j*(n-i) == k) {\n        cout << \"Yes\" << endl;\n        return 0;\n      }\n    }\n  }\n\n  cout << \"No\" << endl;\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1506815493, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03592.html", "problem_id": "p03592", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03592/input.txt", "sample_output_relpath": "derived/input_output/data/p03592/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03592/C++/s769017532.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s769017532", "user_id": "u854191117"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <iostream>\nusing namespace std;\n\nint main()\n{\n  int n, m, k; cin >> n >> m >> k;\n  for (int i = 0; i < n; i++) {\n    for (int j = 0; j < m; j++) {\n      if (i*(m-j)+j*(n-i) == k) {\n        cout << \"Yes\" << endl;\n        return 0;\n      }\n    }\n  }\n\n  cout << \"No\" << endl;\n  return 0;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nWe have a grid with N rows and M columns of squares. Initially, all the squares are white.\n\nThere is a button attached to each row and each column.\nWhen a button attached to a row is pressed, the colors of all the squares in that row are inverted; that is, white squares become black and vice versa.\nWhen a button attached to a column is pressed, the colors of all the squares in that column are inverted.\n\nTakahashi can freely press the buttons any number of times. Determine whether he can have exactly K black squares in the grid.\n\nConstraints\n\n1 \\leq N,M \\leq 1000\n\n0 \\leq K \\leq NM\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M K\n\nOutput\n\nIf Takahashi can have exactly K black squares in the grid, print Yes; otherwise, print No.\n\nSample Input 1\n\n2 2 2\n\nSample Output 1\n\nYes\n\nPress the buttons in the order of the first row, the first column.\n\nSample Input 2\n\n2 2 1\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n3 5 8\n\nSample Output 3\n\nYes\n\nPress the buttons in the order of the first column, third column, second row, fifth column.\n\nSample Input 4\n\n7 9 20\n\nSample Output 4\n\nNo", "sample_input": "2 2 2\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p03592", "source_text": "Score : 200 points\n\nProblem Statement\n\nWe have a grid with N rows and M columns of squares. Initially, all the squares are white.\n\nThere is a button attached to each row and each column.\nWhen a button attached to a row is pressed, the colors of all the squares in that row are inverted; that is, white squares become black and vice versa.\nWhen a button attached to a column is pressed, the colors of all the squares in that column are inverted.\n\nTakahashi can freely press the buttons any number of times. Determine whether he can have exactly K black squares in the grid.\n\nConstraints\n\n1 \\leq N,M \\leq 1000\n\n0 \\leq K \\leq NM\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M K\n\nOutput\n\nIf Takahashi can have exactly K black squares in the grid, print Yes; otherwise, print No.\n\nSample Input 1\n\n2 2 2\n\nSample Output 1\n\nYes\n\nPress the buttons in the order of the first row, the first column.\n\nSample Input 2\n\n2 2 1\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n3 5 8\n\nSample Output 3\n\nYes\n\nPress the buttons in the order of the first column, third column, second row, fifth column.\n\nSample Input 4\n\n7 9 20\n\nSample Output 4\n\nNo", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 296, "cpu_time_ms": 2, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s873209997", "group_id": "codeNet:p03593", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nint main() {\n\tint h, w, flag = 0;\n\tcin >> h >> w;\n\tvector<int> arr(26, 0);\n\tchar c;\n\tfor(int i = 0; i < h * w; i++) {\n\t\tcin >> c;\n\t\tarr[c - 'a']++;\n\t}\n\t\n\tif((h % 2 == 0)&&(w % 2 == 0)) {\n\t\tfor(int i = 0; i < 26; i++) {\n\t\t\tif(arr[i] % 4 != 0) {\n\t\t\t\tflag = 1;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t} else if((h % 2 == 0)||(w % 2 == 0)){\n\t\tint odd, even, count;\n\t\tif(h % 2) {\n\t\t\todd = h;\n\t\t\teven = w;\n\t\t} else {\n\t\t\todd = w;\n\t\t\teven = h;\n\t\t}\n\t\tcount = even / 2;\n\t\tfor(int i = 0; i < 26; i++) {\n\t\t\tif(arr[i] % 4 != 0) {\n\t\t\t\tif((arr[i] % 2 == 0)&&(count)) {\n\t\t\t\t\tcount--;\n\t\t\t\t} else {\n\t\t\t\t\tflag = 1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t} else if(h == w) {\n\t\tint one = 1, count = h - 1;\n\t\tfor(int i = 0; i < 26; i++) {\n\t\t\tif(arr[i] % 4 != 0) {\n\t\t\t\tif(arr[i] % 2 == 1) {\n\t\t\t\t\tif(one == 0) {\n\t\t\t\t\t\tflag = 1;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t} else {\n\t\t\t\t\t\tone = 0;\n\t\t\t\t\t\tif((arr[i] - 1) % 4 != 0) {\n\t\t\t\t\t\t\tif(count != 0) {\n\t\t\t\t\t\t\t\tcount--;\n\t\t\t\t\t\t\t} else {\n\t\t\t\t\t\t\t\tflag = 1;\n\t\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t} else {\n\t\t\t\t\tif(count != 0) {\n\t\t\t\t\t\tcount--;\n\t\t\t\t\t} else {\n\t\t\t\t\t\tflag = 1;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t} else {\n\t\tint l, s, one = 1, count;\n\t\tl = max(h, w);\n\t\ts = min(h, w);\n\t\tcount = l / 2;\n\t\tfor(int i = 0; i < 26; i++) {\n\t\t\tif(arr[i] % 4 != 0) {\n\t\t\t\tif(arr[i] % 2 == 1) {\n\t\t\t\t\tif(one == 1) {\n\t\t\t\t\t\tif(((arr[i] - 1) % 4 != 0)&&(count != 0)) {\n\t\t\t\t\t\t\tcount--;\n\t\t\t\t\t\t} else if(((arr[i] - 1) % 4 != 0)&&(count == 0)) {\n\t\t\t\t\t\t\tflag = 1;\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t}\n\t\t\t\t\t\tone = 0;\n\t\t\t\t\t} else {\n\t\t\t\t\t\tflag = 1;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t} else if(arr[i] % 2 == 0) {\n\t\t\t\t\tif(count == 0) {\n\t\t\t\t\t\tflag = 1;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t} else {\n\t\t\t\t\t\tcount--;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tif(flag) {\n\t\tcout << \"No\" << endl;\n\t} else {\n\t\tcout << \"Yes\" << endl;\n\t}\n\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1506221547, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03593.html", "problem_id": "p03593", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03593/input.txt", "sample_output_relpath": "derived/input_output/data/p03593/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03593/C++/s873209997.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s873209997", "user_id": "u092665151"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nint main() {\n\tint h, w, flag = 0;\n\tcin >> h >> w;\n\tvector<int> arr(26, 0);\n\tchar c;\n\tfor(int i = 0; i < h * w; i++) {\n\t\tcin >> c;\n\t\tarr[c - 'a']++;\n\t}\n\t\n\tif((h % 2 == 0)&&(w % 2 == 0)) {\n\t\tfor(int i = 0; i < 26; i++) {\n\t\t\tif(arr[i] % 4 != 0) {\n\t\t\t\tflag = 1;\n\t\t\t\tbreak;\n\t\t\t}\n\t\t}\n\t} else if((h % 2 == 0)||(w % 2 == 0)){\n\t\tint odd, even, count;\n\t\tif(h % 2) {\n\t\t\todd = h;\n\t\t\teven = w;\n\t\t} else {\n\t\t\todd = w;\n\t\t\teven = h;\n\t\t}\n\t\tcount = even / 2;\n\t\tfor(int i = 0; i < 26; i++) {\n\t\t\tif(arr[i] % 4 != 0) {\n\t\t\t\tif((arr[i] % 2 == 0)&&(count)) {\n\t\t\t\t\tcount--;\n\t\t\t\t} else {\n\t\t\t\t\tflag = 1;\n\t\t\t\t\tbreak;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t} else if(h == w) {\n\t\tint one = 1, count = h - 1;\n\t\tfor(int i = 0; i < 26; i++) {\n\t\t\tif(arr[i] % 4 != 0) {\n\t\t\t\tif(arr[i] % 2 == 1) {\n\t\t\t\t\tif(one == 0) {\n\t\t\t\t\t\tflag = 1;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t} else {\n\t\t\t\t\t\tone = 0;\n\t\t\t\t\t\tif((arr[i] - 1) % 4 != 0) {\n\t\t\t\t\t\t\tif(count != 0) {\n\t\t\t\t\t\t\t\tcount--;\n\t\t\t\t\t\t\t} else {\n\t\t\t\t\t\t\t\tflag = 1;\n\t\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t\t}\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t} else {\n\t\t\t\t\tif(count != 0) {\n\t\t\t\t\t\tcount--;\n\t\t\t\t\t} else {\n\t\t\t\t\t\tflag = 1;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t} else {\n\t\tint l, s, one = 1, count;\n\t\tl = max(h, w);\n\t\ts = min(h, w);\n\t\tcount = l / 2;\n\t\tfor(int i = 0; i < 26; i++) {\n\t\t\tif(arr[i] % 4 != 0) {\n\t\t\t\tif(arr[i] % 2 == 1) {\n\t\t\t\t\tif(one == 1) {\n\t\t\t\t\t\tif(((arr[i] - 1) % 4 != 0)&&(count != 0)) {\n\t\t\t\t\t\t\tcount--;\n\t\t\t\t\t\t} else if(((arr[i] - 1) % 4 != 0)&&(count == 0)) {\n\t\t\t\t\t\t\tflag = 1;\n\t\t\t\t\t\t\tbreak;\n\t\t\t\t\t\t}\n\t\t\t\t\t\tone = 0;\n\t\t\t\t\t} else {\n\t\t\t\t\t\tflag = 1;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t} else if(arr[i] % 2 == 0) {\n\t\t\t\t\tif(count == 0) {\n\t\t\t\t\t\tflag = 1;\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t} else {\n\t\t\t\t\t\tcount--;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\tif(flag) {\n\t\tcout << \"No\" << endl;\n\t} else {\n\t\tcout << \"Yes\" << endl;\n\t}\n\n\treturn 0;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nWe have an H-by-W matrix.\nLet a_{ij} be the element at the i-th row from the top and j-th column from the left.\nIn this matrix, each a_{ij} is a lowercase English letter.\n\nSnuke is creating another H-by-W matrix, A', by freely rearranging the elements in A.\nHere, he wants to satisfy the following condition:\n\nEvery row and column in A' can be read as a palindrome.\n\nDetermine whether he can create a matrix satisfying the condition.\n\nNote\n\nA palindrome is a string that reads the same forward and backward.\nFor example, a, aa, abba and abcba are all palindromes, while ab, abab and abcda are not.\n\nConstraints\n\n1 ≤ H, W ≤ 100\n\na_{ij} is a lowercase English letter.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W\na_{11}a_{12}...a_{1W}\n:\na_{H1}a_{H2}...a_{HW}\n\nOutput\n\nIf Snuke can create a matrix satisfying the condition, print Yes; otherwise, print No.\n\nSample Input 1\n\n3 4\naabb\naabb\naacc\n\nSample Output 1\n\nYes\n\nFor example, the following matrix satisfies the condition.\n\nabba\nacca\nabba\n\nSample Input 2\n\n2 2\naa\nbb\n\nSample Output 2\n\nNo\n\nIt is not possible to create a matrix satisfying the condition, no matter how we rearrange the elements in A.\n\nSample Input 3\n\n5 1\nt\nw\ne\ne\nt\n\nSample Output 3\n\nYes\n\nFor example, the following matrix satisfies the condition.\n\nt\ne\nw\ne\nt\n\nSample Input 4\n\n2 5\nabxba\nabyba\n\nSample Output 4\n\nNo\n\nSample Input 5\n\n1 1\nz\n\nSample Output 5\n\nYes", "sample_input": "3 4\naabb\naabb\naacc\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p03593", "source_text": "Score : 400 points\n\nProblem Statement\n\nWe have an H-by-W matrix.\nLet a_{ij} be the element at the i-th row from the top and j-th column from the left.\nIn this matrix, each a_{ij} is a lowercase English letter.\n\nSnuke is creating another H-by-W matrix, A', by freely rearranging the elements in A.\nHere, he wants to satisfy the following condition:\n\nEvery row and column in A' can be read as a palindrome.\n\nDetermine whether he can create a matrix satisfying the condition.\n\nNote\n\nA palindrome is a string that reads the same forward and backward.\nFor example, a, aa, abba and abcba are all palindromes, while ab, abab and abcda are not.\n\nConstraints\n\n1 ≤ H, W ≤ 100\n\na_{ij} is a lowercase English letter.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W\na_{11}a_{12}...a_{1W}\n:\na_{H1}a_{H2}...a_{HW}\n\nOutput\n\nIf Snuke can create a matrix satisfying the condition, print Yes; otherwise, print No.\n\nSample Input 1\n\n3 4\naabb\naabb\naacc\n\nSample Output 1\n\nYes\n\nFor example, the following matrix satisfies the condition.\n\nabba\nacca\nabba\n\nSample Input 2\n\n2 2\naa\nbb\n\nSample Output 2\n\nNo\n\nIt is not possible to create a matrix satisfying the condition, no matter how we rearrange the elements in A.\n\nSample Input 3\n\n5 1\nt\nw\ne\ne\nt\n\nSample Output 3\n\nYes\n\nFor example, the following matrix satisfies the condition.\n\nt\ne\nw\ne\nt\n\nSample Input 4\n\n2 5\nabxba\nabyba\n\nSample Output 4\n\nNo\n\nSample Input 5\n\n1 1\nz\n\nSample Output 5\n\nYes", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1769, "cpu_time_ms": 2, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s330200898", "group_id": "codeNet:p03597", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n  int n, a;\n  cin >> n >> a;\n  cout << n * n - a << endl;\n}\n", "language": "C++", "metadata": {"date": 1582488300, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03597.html", "problem_id": "p03597", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03597/input.txt", "sample_output_relpath": "derived/input_output/data/p03597/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03597/C++/s330200898.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s330200898", "user_id": "u851113028"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n  int n, a;\n  cin >> n >> a;\n  cout << n * n - a << endl;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nWe have an N \\times N square grid.\n\nWe will paint each square in the grid either black or white.\n\nIf we paint exactly A squares white, how many squares will be painted black?\n\nConstraints\n\n1 \\leq N \\leq 100\n\n0 \\leq A \\leq N^2\n\nInputs\n\nInput is given from Standard Input in the following format:\n\nN\nA\n\nOutputs\n\nPrint the number of squares that will be painted black.\n\nSample Input 1\n\n3\n4\n\nSample Output 1\n\n5\n\nThere are nine squares in a 3 \\times 3 square grid.\nFour of them will be painted white, so the remaining five squares will be painted black.\n\nSample Input 2\n\n19\n100\n\nSample Output 2\n\n261\n\nSample Input 3\n\n10\n0\n\nSample Output 3\n\n100\n\nAs zero squares will be painted white, all the squares will be painted black.", "sample_input": "3\n4\n"}, "reference_outputs": ["5\n"], "source_document_id": "p03597", "source_text": "Score : 100 points\n\nProblem Statement\n\nWe have an N \\times N square grid.\n\nWe will paint each square in the grid either black or white.\n\nIf we paint exactly A squares white, how many squares will be painted black?\n\nConstraints\n\n1 \\leq N \\leq 100\n\n0 \\leq A \\leq N^2\n\nInputs\n\nInput is given from Standard Input in the following format:\n\nN\nA\n\nOutputs\n\nPrint the number of squares that will be painted black.\n\nSample Input 1\n\n3\n4\n\nSample Output 1\n\n5\n\nThere are nine squares in a 3 \\times 3 square grid.\nFour of them will be painted white, so the remaining five squares will be painted black.\n\nSample Input 2\n\n19\n100\n\nSample Output 2\n\n261\n\nSample Input 3\n\n10\n0\n\nSample Output 3\n\n100\n\nAs zero squares will be painted white, all the squares will be painted black.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 120, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s352607813", "group_id": "codeNet:p03597", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n  int N, A;\n  cin >> N >> A;\n  cout << N * N - A << endl;\n}\n", "language": "C++", "metadata": {"date": 1570246515, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03597.html", "problem_id": "p03597", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03597/input.txt", "sample_output_relpath": "derived/input_output/data/p03597/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03597/C++/s352607813.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s352607813", "user_id": "u841354647"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n  int N, A;\n  cin >> N >> A;\n  cout << N * N - A << endl;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nWe have an N \\times N square grid.\n\nWe will paint each square in the grid either black or white.\n\nIf we paint exactly A squares white, how many squares will be painted black?\n\nConstraints\n\n1 \\leq N \\leq 100\n\n0 \\leq A \\leq N^2\n\nInputs\n\nInput is given from Standard Input in the following format:\n\nN\nA\n\nOutputs\n\nPrint the number of squares that will be painted black.\n\nSample Input 1\n\n3\n4\n\nSample Output 1\n\n5\n\nThere are nine squares in a 3 \\times 3 square grid.\nFour of them will be painted white, so the remaining five squares will be painted black.\n\nSample Input 2\n\n19\n100\n\nSample Output 2\n\n261\n\nSample Input 3\n\n10\n0\n\nSample Output 3\n\n100\n\nAs zero squares will be painted white, all the squares will be painted black.", "sample_input": "3\n4\n"}, "reference_outputs": ["5\n"], "source_document_id": "p03597", "source_text": "Score : 100 points\n\nProblem Statement\n\nWe have an N \\times N square grid.\n\nWe will paint each square in the grid either black or white.\n\nIf we paint exactly A squares white, how many squares will be painted black?\n\nConstraints\n\n1 \\leq N \\leq 100\n\n0 \\leq A \\leq N^2\n\nInputs\n\nInput is given from Standard Input in the following format:\n\nN\nA\n\nOutputs\n\nPrint the number of squares that will be painted black.\n\nSample Input 1\n\n3\n4\n\nSample Output 1\n\n5\n\nThere are nine squares in a 3 \\times 3 square grid.\nFour of them will be painted white, so the remaining five squares will be painted black.\n\nSample Input 2\n\n19\n100\n\nSample Output 2\n\n261\n\nSample Input 3\n\n10\n0\n\nSample Output 3\n\n100\n\nAs zero squares will be painted white, all the squares will be painted black.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 120, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s259428195", "group_id": "codeNet:p03598", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n \nint main() {\n  int n,k,ans;\n  cin>>n>>k;\n  ans=0;\n  rep(i,n){\n  int x;\n  cin>>x;\n  if((k-x)*2>=x*2){\n  ans+=x*2;\n  }else{\n  ans+=(k-x)*2;\n  }\n  }\n  cout<<ans<<endl;\n}", "language": "C++", "metadata": {"date": 1586840520, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03598.html", "problem_id": "p03598", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03598/input.txt", "sample_output_relpath": "derived/input_output/data/p03598/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03598/C++/s259428195.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s259428195", "user_id": "u028554976"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n \nint main() {\n  int n,k,ans;\n  cin>>n>>k;\n  ans=0;\n  rep(i,n){\n  int x;\n  cin>>x;\n  if((k-x)*2>=x*2){\n  ans+=x*2;\n  }else{\n  ans+=(k-x)*2;\n  }\n  }\n  cout<<ans<<endl;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nThere are N balls in the xy-plane. The coordinates of the i-th of them is (x_i, i).\nThus, we have one ball on each of the N lines y = 1, y = 2, ..., y = N.\n\nIn order to collect these balls, Snuke prepared 2N robots, N of type A and N of type B.\nThen, he placed the i-th type-A robot at coordinates (0, i), and the i-th type-B robot at coordinates (K, i).\nThus, now we have one type-A robot and one type-B robot on each of the N lines y = 1, y = 2, ..., y = N.\n\nWhen activated, each type of robot will operate as follows.\n\nWhen a type-A robot is activated at coordinates (0, a), it will move to the position of the ball on the line y = a, collect the ball, move back to its original position (0, a) and deactivate itself. If there is no such ball, it will just deactivate itself without doing anything.\n\nWhen a type-B robot is activated at coordinates (K, b), it will move to the position of the ball on the line y = b, collect the ball, move back to its original position (K, b) and deactivate itself. If there is no such ball, it will just deactivate itself without doing anything.\n\nSnuke will activate some of the 2N robots to collect all of the balls. Find the minimum possible total distance covered by robots.\n\nConstraints\n\n1 \\leq N \\leq 100\n\n1 \\leq K \\leq 100\n\n0 < x_i < K\n\nAll input values are integers.\n\nInputs\n\nInput is given from Standard Input in the following format:\n\nN\nK\nx_1 x_2 ... x_N\n\nOutputs\n\nPrint the minimum possible total distance covered by robots.\n\nSample Input 1\n\n1\n10\n2\n\nSample Output 1\n\n4\n\nThere are just one ball, one type-A robot and one type-B robot.\n\nIf the type-A robot is used to collect the ball, the distance from the robot to the ball is 2, and the distance from the ball to the original position of the robot is also 2, for a total distance of 4.\n\nSimilarly, if the type-B robot is used, the total distance covered will be 16.\n\nThus, the total distance covered will be minimized when the type-A robot is used. The output should be 4.\n\nSample Input 2\n\n2\n9\n3 6\n\nSample Output 2\n\n12\n\nThe total distance covered will be minimized when the first ball is collected by the type-A robot, and the second ball by the type-B robot.\n\nSample Input 3\n\n5\n20\n11 12 9 17 12\n\nSample Output 3\n\n74", "sample_input": "1\n10\n2\n"}, "reference_outputs": ["4\n"], "source_document_id": "p03598", "source_text": "Score : 200 points\n\nProblem Statement\n\nThere are N balls in the xy-plane. The coordinates of the i-th of them is (x_i, i).\nThus, we have one ball on each of the N lines y = 1, y = 2, ..., y = N.\n\nIn order to collect these balls, Snuke prepared 2N robots, N of type A and N of type B.\nThen, he placed the i-th type-A robot at coordinates (0, i), and the i-th type-B robot at coordinates (K, i).\nThus, now we have one type-A robot and one type-B robot on each of the N lines y = 1, y = 2, ..., y = N.\n\nWhen activated, each type of robot will operate as follows.\n\nWhen a type-A robot is activated at coordinates (0, a), it will move to the position of the ball on the line y = a, collect the ball, move back to its original position (0, a) and deactivate itself. If there is no such ball, it will just deactivate itself without doing anything.\n\nWhen a type-B robot is activated at coordinates (K, b), it will move to the position of the ball on the line y = b, collect the ball, move back to its original position (K, b) and deactivate itself. If there is no such ball, it will just deactivate itself without doing anything.\n\nSnuke will activate some of the 2N robots to collect all of the balls. Find the minimum possible total distance covered by robots.\n\nConstraints\n\n1 \\leq N \\leq 100\n\n1 \\leq K \\leq 100\n\n0 < x_i < K\n\nAll input values are integers.\n\nInputs\n\nInput is given from Standard Input in the following format:\n\nN\nK\nx_1 x_2 ... x_N\n\nOutputs\n\nPrint the minimum possible total distance covered by robots.\n\nSample Input 1\n\n1\n10\n2\n\nSample Output 1\n\n4\n\nThere are just one ball, one type-A robot and one type-B robot.\n\nIf the type-A robot is used to collect the ball, the distance from the robot to the ball is 2, and the distance from the ball to the original position of the robot is also 2, for a total distance of 4.\n\nSimilarly, if the type-B robot is used, the total distance covered will be 16.\n\nThus, the total distance covered will be minimized when the type-A robot is used. The output should be 4.\n\nSample Input 2\n\n2\n9\n3 6\n\nSample Output 2\n\n12\n\nThe total distance covered will be minimized when the first ball is collected by the type-A robot, and the second ball by the type-B robot.\n\nSample Input 3\n\n5\n20\n11 12 9 17 12\n\nSample Output 3\n\n74", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 267, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s007264250", "group_id": "codeNet:p03599", "input_text": "#include <algorithm>\n#include <iostream>\n#include <numeric>\n#include <vector>\n#include <string>\n#include <bitset>\n#include <queue>\n#include <tuple>\n#include <cmath>\n#include <map>\n#include <cstring>\n\ntemplate<typename T> bool chmax( T &a, const T &b ) { if ( a <= b ) { a = b; return ( true ); } else { return ( false ); } }\ntemplate<typename T> bool chmin( T &a, const T &b ) { if ( a >= b ) { a = b; return ( true ); } else { return ( false ); } }\n\nusing namespace std;\n\nusing ll = long long;\nusing ull = unsigned long long;\n\nusing Pint = pair<int, int>;\nusing Pll  = pair<ll, ll>;\nusing Pull = pair<ull, ull>;\n\n#define eb emplace_back\n#define pb push_back\n#define mp make_pair\n#define mt make_tuple\n\n#define F first\n#define S second\n\n#define rep( i, n ) for ( int i = 0; i < (int)( n ); ++i )\n#define reps( i, n ) for ( int i = 1; i <= (int)( n ); ++i )\n#define rrep( i, n ) for ( int i = (int)( ( n ) - 1 ); i >= 0; --i )\n#define rreps( i, n ) for ( int i = (int)( ( n ) ); i > 0; --i )\n#define arep( i, v ) for ( auto &&i : ( v ) )\n\ntemplate<typename T> T gcd( const T a, const T b ) { return ( b ? gcd( b, a % b ) : a ); }\n\n#define ALL( c ) ( c ).begin(), ( c ).end()\n#define RALL( c ) ( c ).rbegin(), ( c ).rend()\n#define UNIQUE( c ) ( c ).erase( unique( ( c ).begin(), ( c ).end() ), ( c ).end() )\n\nconstexpr ll MOD = 1000000007LL;\n\n#define y0 y3487465\n#define y1 y8687969\n#define j0 j1347829\n#define j1 j234892\n#define next asdnext\n#define prev asdprev\n\ntemplate<typename T = ll> class UnionFind {\npublic:\n\tUnionFind( T n ) { par.resize( n ); siz.resize( n ); rep( i, n ) { par[i] = i; siz[i] = 1; } }\n\tT find( T x ) { if ( x == par[x] ) return ( x ); else return( par[x] = find( par[x] ) ); }\n\tvoid unite( T x, T y ) { T xx = find( x ); T yy = find( y ); if ( xx == yy ) return;\n\t\tif ( siz[xx] <= siz[yy] ) swap( xx, yy ); par[yy] = xx; siz[xx] += siz[yy]; }\nprivate:\n\tvector<T> par, siz;\n};\n\ntemplate<typename T = ll> class CompareMax {\npublic:\tT operator()( T a, T b ) { return ( max( a, b ) ); }\n};\ntemplate<typename T = ll> class CompareMin {\npublic:\tT operator()( T a, T b ) { return ( min( a, b ) ); }\n};\n\ntemplate<typename T = ll, typename F = CompareMax<T>, T I = 0> class SegTree {\npublic:\n\tSegTree( T n ) { N = n; v.resize( 4 * n ); rep( i, 4 * n ) v[i] = I; }\n\tvoid update( T i, T x ) { i += N - 1; v[i] = x; while ( i > 0 ) {\n\t\t\ti = ( i - 1 ) / 2; v[i] = func( v[i * 2 + 1], v[i * 2 + 2] ); } }\n\tT query( T a, T b, T k, T l, T r ) {\n\t\tif ( r <= a || b <= l ) return ( I );\n\t\tif ( a <= l && r <= b ) return ( v[k] );\n\t\telse { T vl = query( a, b, k * 2 + 1, l, ( l + r ) / 2 );\n\t\t\tT vr = query( a, b, k * 2 + 2, ( l + r ) / 2, r );\n\t\t\treturn ( func( vl, vr ) ); }\n\t}\nprivate:\n\tT N; F func; vector<T> v;\n};\n\ntemplate<typename T = ll> T solveLIS( const vector<T> &v ) {\n\tvector<T> dp( v.size(), numeric_limits<T>::max() );\n\trep( i, v.size() ) {\n\t\t*lower_bound( ALL( dp ), v[i] ) = v[i];\n\t}\n\treturn ( distance( dp.begin(), lower_bound( ALL( dp ), numeric_limits<T>::max() ) ) );\n}\n\ntemplate<typename T = ll> T power( T a, T b, T m = MOD ) {\n\tT res = 1;\n\twhile ( b > 0 ) { if ( b & 1 ) res = res * a % m;\n\t\ta = a * a % m; b >>= 1; }\n\treturn ( res );\n}\n\n/*\nconstexpr ll MAX = 500010;\nll fact[MAX];\nll inv[MAX];\nll inv_fact[MAX];\n\ntemplate<typename T> void initComb( T n, T m = MOD )\n{\n\tfact[0] = fact[1] = inv_fact[0] = inv_fact[1] = 1;\n\tinv[1] = 1;\n\tfor ( int i = 2; i < n; i++ ) {\n\t\tfact[i] = ( fact[i - 1] * i ) % m;\n\t\tinv[i] = m - inv[m % i] * ( m / i ) % m;\n\t\tinv_fact[i] = inv_fact[i - 1] * inv[i] % m;\n\t}\n}\n\ntemplate<typename T> T comb( T n, T r, T m = MOD )\n{\n\tif ( n < r ) return ( 0 );\n\tif ( n < 0 || r < 0 ) return ( 0 );\n\treturn ( fact[n] * ( inv_fact[r] * inv_fact[n - r] % m ) % m );\n}\n*/\n\nvoid replace( string &s, string t, string r ) {\n\tstring::size_type p = 0;\n\twhile ( ( p = s.find( t, p ) ) != string::npos ) {\n\t\ts.replace( p, t.length(), r );\n\t\tp += r.length();\n\t}\n}\n\n\nint main()\n{\n\tint a, b, c, d, e, f;\n\tcin >> a >> b >> c >> d >> e >> f;\n\n\tint w = 0, s = 0;\n\tdouble cons = 0.0;\n\treps( i, a )\n\t{\n\t\trep( j, b + 1 )\n\t\t{\n\t\t\tfor ( int k = 0; k <= e * ( i + j ); k += c )\n\t\t\t{\n\t\t\t\tfor ( int l = 0; l <= e * ( i + j ) - k; l += d )\n\t\t\t\t{\n\t\t\t\t\tif ( 100 * ( i + j ) + k + l > f )\n\t\t\t\t\t{\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t\telse\n\t\t\t\t\t{\n\t\t\t\t\t\tdouble t = (double)( k + l ) / ( 100 * ( i + j ) + k + l );\n\t\t\t\t\t\tif ( chmax( cons, t ) )\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tw = i + j;\n\t\t\t\t\t\t\ts = k + l;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tcout << ( w * 100 + s ) << \" \" << s << endl;\n\n\treturn ( 0 );\n}\n", "language": "C++", "metadata": {"date": 1564258025, "filename_ext": "cpp", "original_language": "C++14 (Clang 3.8.0)", "problem_description_relpath": "problem_descriptions/p03599.html", "problem_id": "p03599", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03599/input.txt", "sample_output_relpath": "derived/input_output/data/p03599/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03599/C++/s007264250.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s007264250", "user_id": "u408910484"}, "prompt_components": {"gold_output": "110 10\n", "input_to_evaluate": "#include <algorithm>\n#include <iostream>\n#include <numeric>\n#include <vector>\n#include <string>\n#include <bitset>\n#include <queue>\n#include <tuple>\n#include <cmath>\n#include <map>\n#include <cstring>\n\ntemplate<typename T> bool chmax( T &a, const T &b ) { if ( a <= b ) { a = b; return ( true ); } else { return ( false ); } }\ntemplate<typename T> bool chmin( T &a, const T &b ) { if ( a >= b ) { a = b; return ( true ); } else { return ( false ); } }\n\nusing namespace std;\n\nusing ll = long long;\nusing ull = unsigned long long;\n\nusing Pint = pair<int, int>;\nusing Pll  = pair<ll, ll>;\nusing Pull = pair<ull, ull>;\n\n#define eb emplace_back\n#define pb push_back\n#define mp make_pair\n#define mt make_tuple\n\n#define F first\n#define S second\n\n#define rep( i, n ) for ( int i = 0; i < (int)( n ); ++i )\n#define reps( i, n ) for ( int i = 1; i <= (int)( n ); ++i )\n#define rrep( i, n ) for ( int i = (int)( ( n ) - 1 ); i >= 0; --i )\n#define rreps( i, n ) for ( int i = (int)( ( n ) ); i > 0; --i )\n#define arep( i, v ) for ( auto &&i : ( v ) )\n\ntemplate<typename T> T gcd( const T a, const T b ) { return ( b ? gcd( b, a % b ) : a ); }\n\n#define ALL( c ) ( c ).begin(), ( c ).end()\n#define RALL( c ) ( c ).rbegin(), ( c ).rend()\n#define UNIQUE( c ) ( c ).erase( unique( ( c ).begin(), ( c ).end() ), ( c ).end() )\n\nconstexpr ll MOD = 1000000007LL;\n\n#define y0 y3487465\n#define y1 y8687969\n#define j0 j1347829\n#define j1 j234892\n#define next asdnext\n#define prev asdprev\n\ntemplate<typename T = ll> class UnionFind {\npublic:\n\tUnionFind( T n ) { par.resize( n ); siz.resize( n ); rep( i, n ) { par[i] = i; siz[i] = 1; } }\n\tT find( T x ) { if ( x == par[x] ) return ( x ); else return( par[x] = find( par[x] ) ); }\n\tvoid unite( T x, T y ) { T xx = find( x ); T yy = find( y ); if ( xx == yy ) return;\n\t\tif ( siz[xx] <= siz[yy] ) swap( xx, yy ); par[yy] = xx; siz[xx] += siz[yy]; }\nprivate:\n\tvector<T> par, siz;\n};\n\ntemplate<typename T = ll> class CompareMax {\npublic:\tT operator()( T a, T b ) { return ( max( a, b ) ); }\n};\ntemplate<typename T = ll> class CompareMin {\npublic:\tT operator()( T a, T b ) { return ( min( a, b ) ); }\n};\n\ntemplate<typename T = ll, typename F = CompareMax<T>, T I = 0> class SegTree {\npublic:\n\tSegTree( T n ) { N = n; v.resize( 4 * n ); rep( i, 4 * n ) v[i] = I; }\n\tvoid update( T i, T x ) { i += N - 1; v[i] = x; while ( i > 0 ) {\n\t\t\ti = ( i - 1 ) / 2; v[i] = func( v[i * 2 + 1], v[i * 2 + 2] ); } }\n\tT query( T a, T b, T k, T l, T r ) {\n\t\tif ( r <= a || b <= l ) return ( I );\n\t\tif ( a <= l && r <= b ) return ( v[k] );\n\t\telse { T vl = query( a, b, k * 2 + 1, l, ( l + r ) / 2 );\n\t\t\tT vr = query( a, b, k * 2 + 2, ( l + r ) / 2, r );\n\t\t\treturn ( func( vl, vr ) ); }\n\t}\nprivate:\n\tT N; F func; vector<T> v;\n};\n\ntemplate<typename T = ll> T solveLIS( const vector<T> &v ) {\n\tvector<T> dp( v.size(), numeric_limits<T>::max() );\n\trep( i, v.size() ) {\n\t\t*lower_bound( ALL( dp ), v[i] ) = v[i];\n\t}\n\treturn ( distance( dp.begin(), lower_bound( ALL( dp ), numeric_limits<T>::max() ) ) );\n}\n\ntemplate<typename T = ll> T power( T a, T b, T m = MOD ) {\n\tT res = 1;\n\twhile ( b > 0 ) { if ( b & 1 ) res = res * a % m;\n\t\ta = a * a % m; b >>= 1; }\n\treturn ( res );\n}\n\n/*\nconstexpr ll MAX = 500010;\nll fact[MAX];\nll inv[MAX];\nll inv_fact[MAX];\n\ntemplate<typename T> void initComb( T n, T m = MOD )\n{\n\tfact[0] = fact[1] = inv_fact[0] = inv_fact[1] = 1;\n\tinv[1] = 1;\n\tfor ( int i = 2; i < n; i++ ) {\n\t\tfact[i] = ( fact[i - 1] * i ) % m;\n\t\tinv[i] = m - inv[m % i] * ( m / i ) % m;\n\t\tinv_fact[i] = inv_fact[i - 1] * inv[i] % m;\n\t}\n}\n\ntemplate<typename T> T comb( T n, T r, T m = MOD )\n{\n\tif ( n < r ) return ( 0 );\n\tif ( n < 0 || r < 0 ) return ( 0 );\n\treturn ( fact[n] * ( inv_fact[r] * inv_fact[n - r] % m ) % m );\n}\n*/\n\nvoid replace( string &s, string t, string r ) {\n\tstring::size_type p = 0;\n\twhile ( ( p = s.find( t, p ) ) != string::npos ) {\n\t\ts.replace( p, t.length(), r );\n\t\tp += r.length();\n\t}\n}\n\n\nint main()\n{\n\tint a, b, c, d, e, f;\n\tcin >> a >> b >> c >> d >> e >> f;\n\n\tint w = 0, s = 0;\n\tdouble cons = 0.0;\n\treps( i, a )\n\t{\n\t\trep( j, b + 1 )\n\t\t{\n\t\t\tfor ( int k = 0; k <= e * ( i + j ); k += c )\n\t\t\t{\n\t\t\t\tfor ( int l = 0; l <= e * ( i + j ) - k; l += d )\n\t\t\t\t{\n\t\t\t\t\tif ( 100 * ( i + j ) + k + l > f )\n\t\t\t\t\t{\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t\telse\n\t\t\t\t\t{\n\t\t\t\t\t\tdouble t = (double)( k + l ) / ( 100 * ( i + j ) + k + l );\n\t\t\t\t\t\tif ( chmax( cons, t ) )\n\t\t\t\t\t\t{\n\t\t\t\t\t\t\tw = i + j;\n\t\t\t\t\t\t\ts = k + l;\n\t\t\t\t\t\t}\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tcout << ( w * 100 + s ) << \" \" << s << endl;\n\n\treturn ( 0 );\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nSnuke is making sugar water in a beaker.\nInitially, the beaker is empty. Snuke can perform the following four types of operations any number of times. He may choose not to perform some types of operations.\n\nOperation 1: Pour 100A grams of water into the beaker.\n\nOperation 2: Pour 100B grams of water into the beaker.\n\nOperation 3: Put C grams of sugar into the beaker.\n\nOperation 4: Put D grams of sugar into the beaker.\n\nIn our experimental environment, E grams of sugar can dissolve into 100 grams of water.\n\nSnuke will make sugar water with the highest possible density.\n\nThe beaker can contain at most F grams of substances (water and sugar combined), and there must not be any undissolved sugar in the beaker.\nFind the mass of the sugar water Snuke will make, and the mass of sugar dissolved in it.\nIf there is more than one candidate, any of them will be accepted.\n\nWe remind you that the sugar water that contains a grams of water and b grams of sugar is \\frac{100b}{a + b} percent.\nAlso, in this problem, pure water that does not contain any sugar is regarded as 0 percent density sugar water.\n\nConstraints\n\n1 \\leq A < B \\leq 30\n\n1 \\leq C < D \\leq 30\n\n1 \\leq E \\leq 100\n\n100A \\leq F \\leq 3 000\n\nA, B, C, D, E and F are all integers.\n\nInputs\n\nInput is given from Standard Input in the following format:\n\nA B C D E F\n\nOutputs\n\nPrint two integers separated by a space.\nThe first integer should be the mass of the desired sugar water, and the second should be the mass of the sugar dissolved in it.\n\nSample Input 1\n\n1 2 10 20 15 200\n\nSample Output 1\n\n110 10\n\nIn this environment, 15 grams of sugar can dissolve into 100 grams of water, and the beaker can contain at most 200 grams of substances.\n\nWe can make 110 grams of sugar water by performing Operation 1 once and Operation 3 once.\nIt is not possible to make sugar water with higher density.\nFor example, the following sequences of operations are infeasible:\n\nIf we perform Operation 1 once and Operation 4 once, there will be undissolved sugar in the beaker.\n\nIf we perform Operation 2 once and Operation 3 three times, the mass of substances in the beaker will exceed 200 grams.\n\nSample Input 2\n\n1 2 1 2 100 1000\n\nSample Output 2\n\n200 100\n\nThere are other acceptable outputs, such as:\n\n400 200\n\nHowever, the output below is not acceptable:\n\n300 150\n\nThis is because, in order to make 300 grams of sugar water containing 150 grams of sugar, we need to pour exactly 150 grams of water into the beaker, which is impossible.\n\nSample Input 3\n\n17 19 22 26 55 2802\n\nSample Output 3\n\n2634 934", "sample_input": "1 2 10 20 15 200\n"}, "reference_outputs": ["110 10\n"], "source_document_id": "p03599", "source_text": "Score : 300 points\n\nProblem Statement\n\nSnuke is making sugar water in a beaker.\nInitially, the beaker is empty. Snuke can perform the following four types of operations any number of times. He may choose not to perform some types of operations.\n\nOperation 1: Pour 100A grams of water into the beaker.\n\nOperation 2: Pour 100B grams of water into the beaker.\n\nOperation 3: Put C grams of sugar into the beaker.\n\nOperation 4: Put D grams of sugar into the beaker.\n\nIn our experimental environment, E grams of sugar can dissolve into 100 grams of water.\n\nSnuke will make sugar water with the highest possible density.\n\nThe beaker can contain at most F grams of substances (water and sugar combined), and there must not be any undissolved sugar in the beaker.\nFind the mass of the sugar water Snuke will make, and the mass of sugar dissolved in it.\nIf there is more than one candidate, any of them will be accepted.\n\nWe remind you that the sugar water that contains a grams of water and b grams of sugar is \\frac{100b}{a + b} percent.\nAlso, in this problem, pure water that does not contain any sugar is regarded as 0 percent density sugar water.\n\nConstraints\n\n1 \\leq A < B \\leq 30\n\n1 \\leq C < D \\leq 30\n\n1 \\leq E \\leq 100\n\n100A \\leq F \\leq 3 000\n\nA, B, C, D, E and F are all integers.\n\nInputs\n\nInput is given from Standard Input in the following format:\n\nA B C D E F\n\nOutputs\n\nPrint two integers separated by a space.\nThe first integer should be the mass of the desired sugar water, and the second should be the mass of the sugar dissolved in it.\n\nSample Input 1\n\n1 2 10 20 15 200\n\nSample Output 1\n\n110 10\n\nIn this environment, 15 grams of sugar can dissolve into 100 grams of water, and the beaker can contain at most 200 grams of substances.\n\nWe can make 110 grams of sugar water by performing Operation 1 once and Operation 3 once.\nIt is not possible to make sugar water with higher density.\nFor example, the following sequences of operations are infeasible:\n\nIf we perform Operation 1 once and Operation 4 once, there will be undissolved sugar in the beaker.\n\nIf we perform Operation 2 once and Operation 3 three times, the mass of substances in the beaker will exceed 200 grams.\n\nSample Input 2\n\n1 2 1 2 100 1000\n\nSample Output 2\n\n200 100\n\nThere are other acceptable outputs, such as:\n\n400 200\n\nHowever, the output below is not acceptable:\n\n300 150\n\nThis is because, in order to make 300 grams of sugar water containing 150 grams of sugar, we need to pour exactly 150 grams of water into the beaker, which is impossible.\n\nSample Input 3\n\n17 19 22 26 55 2802\n\nSample Output 3\n\n2634 934", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 4491, "cpu_time_ms": 12, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s341934157", "group_id": "codeNet:p03599", "input_text": "#include <iostream>\n#include <cmath>\n#include <string>\n#include <set>\n#include <vector>\n#include <map>\n#include <list>\n#include <stack>\n#include <queue>\nusing namespace std;\ntypedef long long ll;\n\nint main(void) {\n    set<double> swtr, ssgr;\n    int i, j, ans_wtr=0, ans_sgr=0;\n    double a, b, c, d, e, f, ans=0;\n    cin >> a >> b >> c >> d >> e >> f;\n    \n    for(i=0; i<=f/(100*a); i++) {\n        for(j=0; 100*a*i+100*b*j<=f; j++)\n            swtr.insert(100*a*i+100*b*j);\n    }\n    \n    for(i=0; i<=f/c; i++) {\n        for(j=0; c*i+d*j<=f; j++) {\n            ssgr.insert(c*i+d*j);\n        }\n    }\n    \n    vector<double>wtr = vector<double>(swtr.begin(), swtr.end());\n    vector<double>sgr = vector<double>(ssgr.begin(), ssgr.end());\n    \n    for(i=0; i<wtr.size(); i++) {\n        for(j=0; j<sgr.size(); j++) {\n            if(i==0 && j==0)\n                continue;\n            if(wtr[i]+sgr[j]<=f && e*wtr[i]>=100*sgr[j]) {\n                if(sgr[j]/(wtr[i]+sgr[j])>=ans) {\n                    ans=sgr[j]/(wtr[i]+sgr[j]);\n                    ans_wtr=wtr[i];\n                    ans_sgr=sgr[j];\n                }\n            }\n        }\n    }\n    cout << ans_wtr << \" \" << ans_sgr << endl;\n}\n", "language": "C++", "metadata": {"date": 1530591744, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03599.html", "problem_id": "p03599", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03599/input.txt", "sample_output_relpath": "derived/input_output/data/p03599/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03599/C++/s341934157.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s341934157", "user_id": "u768152935"}, "prompt_components": {"gold_output": "110 10\n", "input_to_evaluate": "#include <iostream>\n#include <cmath>\n#include <string>\n#include <set>\n#include <vector>\n#include <map>\n#include <list>\n#include <stack>\n#include <queue>\nusing namespace std;\ntypedef long long ll;\n\nint main(void) {\n    set<double> swtr, ssgr;\n    int i, j, ans_wtr=0, ans_sgr=0;\n    double a, b, c, d, e, f, ans=0;\n    cin >> a >> b >> c >> d >> e >> f;\n    \n    for(i=0; i<=f/(100*a); i++) {\n        for(j=0; 100*a*i+100*b*j<=f; j++)\n            swtr.insert(100*a*i+100*b*j);\n    }\n    \n    for(i=0; i<=f/c; i++) {\n        for(j=0; c*i+d*j<=f; j++) {\n            ssgr.insert(c*i+d*j);\n        }\n    }\n    \n    vector<double>wtr = vector<double>(swtr.begin(), swtr.end());\n    vector<double>sgr = vector<double>(ssgr.begin(), ssgr.end());\n    \n    for(i=0; i<wtr.size(); i++) {\n        for(j=0; j<sgr.size(); j++) {\n            if(i==0 && j==0)\n                continue;\n            if(wtr[i]+sgr[j]<=f && e*wtr[i]>=100*sgr[j]) {\n                if(sgr[j]/(wtr[i]+sgr[j])>=ans) {\n                    ans=sgr[j]/(wtr[i]+sgr[j]);\n                    ans_wtr=wtr[i];\n                    ans_sgr=sgr[j];\n                }\n            }\n        }\n    }\n    cout << ans_wtr << \" \" << ans_sgr << endl;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nSnuke is making sugar water in a beaker.\nInitially, the beaker is empty. Snuke can perform the following four types of operations any number of times. He may choose not to perform some types of operations.\n\nOperation 1: Pour 100A grams of water into the beaker.\n\nOperation 2: Pour 100B grams of water into the beaker.\n\nOperation 3: Put C grams of sugar into the beaker.\n\nOperation 4: Put D grams of sugar into the beaker.\n\nIn our experimental environment, E grams of sugar can dissolve into 100 grams of water.\n\nSnuke will make sugar water with the highest possible density.\n\nThe beaker can contain at most F grams of substances (water and sugar combined), and there must not be any undissolved sugar in the beaker.\nFind the mass of the sugar water Snuke will make, and the mass of sugar dissolved in it.\nIf there is more than one candidate, any of them will be accepted.\n\nWe remind you that the sugar water that contains a grams of water and b grams of sugar is \\frac{100b}{a + b} percent.\nAlso, in this problem, pure water that does not contain any sugar is regarded as 0 percent density sugar water.\n\nConstraints\n\n1 \\leq A < B \\leq 30\n\n1 \\leq C < D \\leq 30\n\n1 \\leq E \\leq 100\n\n100A \\leq F \\leq 3 000\n\nA, B, C, D, E and F are all integers.\n\nInputs\n\nInput is given from Standard Input in the following format:\n\nA B C D E F\n\nOutputs\n\nPrint two integers separated by a space.\nThe first integer should be the mass of the desired sugar water, and the second should be the mass of the sugar dissolved in it.\n\nSample Input 1\n\n1 2 10 20 15 200\n\nSample Output 1\n\n110 10\n\nIn this environment, 15 grams of sugar can dissolve into 100 grams of water, and the beaker can contain at most 200 grams of substances.\n\nWe can make 110 grams of sugar water by performing Operation 1 once and Operation 3 once.\nIt is not possible to make sugar water with higher density.\nFor example, the following sequences of operations are infeasible:\n\nIf we perform Operation 1 once and Operation 4 once, there will be undissolved sugar in the beaker.\n\nIf we perform Operation 2 once and Operation 3 three times, the mass of substances in the beaker will exceed 200 grams.\n\nSample Input 2\n\n1 2 1 2 100 1000\n\nSample Output 2\n\n200 100\n\nThere are other acceptable outputs, such as:\n\n400 200\n\nHowever, the output below is not acceptable:\n\n300 150\n\nThis is because, in order to make 300 grams of sugar water containing 150 grams of sugar, we need to pour exactly 150 grams of water into the beaker, which is impossible.\n\nSample Input 3\n\n17 19 22 26 55 2802\n\nSample Output 3\n\n2634 934", "sample_input": "1 2 10 20 15 200\n"}, "reference_outputs": ["110 10\n"], "source_document_id": "p03599", "source_text": "Score : 300 points\n\nProblem Statement\n\nSnuke is making sugar water in a beaker.\nInitially, the beaker is empty. Snuke can perform the following four types of operations any number of times. He may choose not to perform some types of operations.\n\nOperation 1: Pour 100A grams of water into the beaker.\n\nOperation 2: Pour 100B grams of water into the beaker.\n\nOperation 3: Put C grams of sugar into the beaker.\n\nOperation 4: Put D grams of sugar into the beaker.\n\nIn our experimental environment, E grams of sugar can dissolve into 100 grams of water.\n\nSnuke will make sugar water with the highest possible density.\n\nThe beaker can contain at most F grams of substances (water and sugar combined), and there must not be any undissolved sugar in the beaker.\nFind the mass of the sugar water Snuke will make, and the mass of sugar dissolved in it.\nIf there is more than one candidate, any of them will be accepted.\n\nWe remind you that the sugar water that contains a grams of water and b grams of sugar is \\frac{100b}{a + b} percent.\nAlso, in this problem, pure water that does not contain any sugar is regarded as 0 percent density sugar water.\n\nConstraints\n\n1 \\leq A < B \\leq 30\n\n1 \\leq C < D \\leq 30\n\n1 \\leq E \\leq 100\n\n100A \\leq F \\leq 3 000\n\nA, B, C, D, E and F are all integers.\n\nInputs\n\nInput is given from Standard Input in the following format:\n\nA B C D E F\n\nOutputs\n\nPrint two integers separated by a space.\nThe first integer should be the mass of the desired sugar water, and the second should be the mass of the sugar dissolved in it.\n\nSample Input 1\n\n1 2 10 20 15 200\n\nSample Output 1\n\n110 10\n\nIn this environment, 15 grams of sugar can dissolve into 100 grams of water, and the beaker can contain at most 200 grams of substances.\n\nWe can make 110 grams of sugar water by performing Operation 1 once and Operation 3 once.\nIt is not possible to make sugar water with higher density.\nFor example, the following sequences of operations are infeasible:\n\nIf we perform Operation 1 once and Operation 4 once, there will be undissolved sugar in the beaker.\n\nIf we perform Operation 2 once and Operation 3 three times, the mass of substances in the beaker will exceed 200 grams.\n\nSample Input 2\n\n1 2 1 2 100 1000\n\nSample Output 2\n\n200 100\n\nThere are other acceptable outputs, such as:\n\n400 200\n\nHowever, the output below is not acceptable:\n\n300 150\n\nThis is because, in order to make 300 grams of sugar water containing 150 grams of sugar, we need to pour exactly 150 grams of water into the beaker, which is impossible.\n\nSample Input 3\n\n17 19 22 26 55 2802\n\nSample Output 3\n\n2634 934", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1196, "cpu_time_ms": 13, "memory_kb": 384}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s354413412", "group_id": "codeNet:p03599", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n#define int long long\n\nsigned main() {\n    int a, b, c, d, e, f;\n    cin >> a >> b >> c >> d >> e >> f;\n\n    int ans = -1;\n    int sum = 0;\n    int t = 0;\n    for(int i=0; i<=600; ++i) {\n        for(int j=0; j<=600; ++j) {\n            if(i==0&&j==0) continue;\n            for(int k=0; k<=600; ++k) {\n                for(int l=0; l<=600; ++l) {\n                    int A = a*i, B = b*j, C = c*k, D = d*l;\n                    if((100*A+100*B+C+D)>f) {\n                        break;\n                    }\n                    if((double)(C+D)/(double)(100*(A+B))*1000>e*10) break;\n                    if(ans< 100*(C+D)/(100*A+100*B+C+D)) {\n                        //cout << A << \" \" << B << \" \" << C << \" \" << D << endl;\n                        ans = 100*(C+D)/(100*A+100*B+C+D);\n                        sum = 100*A+100*B+C+D;\n                        t = C+D;\n                    }\n                }\n            }\n        }\n    }\n    cout << sum << \" \" << t << endl;\n    return 0;\n}\n\n", "language": "C++", "metadata": {"date": 1505611805, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03599.html", "problem_id": "p03599", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03599/input.txt", "sample_output_relpath": "derived/input_output/data/p03599/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03599/C++/s354413412.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s354413412", "user_id": "u825445261"}, "prompt_components": {"gold_output": "110 10\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n#define int long long\n\nsigned main() {\n    int a, b, c, d, e, f;\n    cin >> a >> b >> c >> d >> e >> f;\n\n    int ans = -1;\n    int sum = 0;\n    int t = 0;\n    for(int i=0; i<=600; ++i) {\n        for(int j=0; j<=600; ++j) {\n            if(i==0&&j==0) continue;\n            for(int k=0; k<=600; ++k) {\n                for(int l=0; l<=600; ++l) {\n                    int A = a*i, B = b*j, C = c*k, D = d*l;\n                    if((100*A+100*B+C+D)>f) {\n                        break;\n                    }\n                    if((double)(C+D)/(double)(100*(A+B))*1000>e*10) break;\n                    if(ans< 100*(C+D)/(100*A+100*B+C+D)) {\n                        //cout << A << \" \" << B << \" \" << C << \" \" << D << endl;\n                        ans = 100*(C+D)/(100*A+100*B+C+D);\n                        sum = 100*A+100*B+C+D;\n                        t = C+D;\n                    }\n                }\n            }\n        }\n    }\n    cout << sum << \" \" << t << endl;\n    return 0;\n}\n\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nSnuke is making sugar water in a beaker.\nInitially, the beaker is empty. Snuke can perform the following four types of operations any number of times. He may choose not to perform some types of operations.\n\nOperation 1: Pour 100A grams of water into the beaker.\n\nOperation 2: Pour 100B grams of water into the beaker.\n\nOperation 3: Put C grams of sugar into the beaker.\n\nOperation 4: Put D grams of sugar into the beaker.\n\nIn our experimental environment, E grams of sugar can dissolve into 100 grams of water.\n\nSnuke will make sugar water with the highest possible density.\n\nThe beaker can contain at most F grams of substances (water and sugar combined), and there must not be any undissolved sugar in the beaker.\nFind the mass of the sugar water Snuke will make, and the mass of sugar dissolved in it.\nIf there is more than one candidate, any of them will be accepted.\n\nWe remind you that the sugar water that contains a grams of water and b grams of sugar is \\frac{100b}{a + b} percent.\nAlso, in this problem, pure water that does not contain any sugar is regarded as 0 percent density sugar water.\n\nConstraints\n\n1 \\leq A < B \\leq 30\n\n1 \\leq C < D \\leq 30\n\n1 \\leq E \\leq 100\n\n100A \\leq F \\leq 3 000\n\nA, B, C, D, E and F are all integers.\n\nInputs\n\nInput is given from Standard Input in the following format:\n\nA B C D E F\n\nOutputs\n\nPrint two integers separated by a space.\nThe first integer should be the mass of the desired sugar water, and the second should be the mass of the sugar dissolved in it.\n\nSample Input 1\n\n1 2 10 20 15 200\n\nSample Output 1\n\n110 10\n\nIn this environment, 15 grams of sugar can dissolve into 100 grams of water, and the beaker can contain at most 200 grams of substances.\n\nWe can make 110 grams of sugar water by performing Operation 1 once and Operation 3 once.\nIt is not possible to make sugar water with higher density.\nFor example, the following sequences of operations are infeasible:\n\nIf we perform Operation 1 once and Operation 4 once, there will be undissolved sugar in the beaker.\n\nIf we perform Operation 2 once and Operation 3 three times, the mass of substances in the beaker will exceed 200 grams.\n\nSample Input 2\n\n1 2 1 2 100 1000\n\nSample Output 2\n\n200 100\n\nThere are other acceptable outputs, such as:\n\n400 200\n\nHowever, the output below is not acceptable:\n\n300 150\n\nThis is because, in order to make 300 grams of sugar water containing 150 grams of sugar, we need to pour exactly 150 grams of water into the beaker, which is impossible.\n\nSample Input 3\n\n17 19 22 26 55 2802\n\nSample Output 3\n\n2634 934", "sample_input": "1 2 10 20 15 200\n"}, "reference_outputs": ["110 10\n"], "source_document_id": "p03599", "source_text": "Score : 300 points\n\nProblem Statement\n\nSnuke is making sugar water in a beaker.\nInitially, the beaker is empty. Snuke can perform the following four types of operations any number of times. He may choose not to perform some types of operations.\n\nOperation 1: Pour 100A grams of water into the beaker.\n\nOperation 2: Pour 100B grams of water into the beaker.\n\nOperation 3: Put C grams of sugar into the beaker.\n\nOperation 4: Put D grams of sugar into the beaker.\n\nIn our experimental environment, E grams of sugar can dissolve into 100 grams of water.\n\nSnuke will make sugar water with the highest possible density.\n\nThe beaker can contain at most F grams of substances (water and sugar combined), and there must not be any undissolved sugar in the beaker.\nFind the mass of the sugar water Snuke will make, and the mass of sugar dissolved in it.\nIf there is more than one candidate, any of them will be accepted.\n\nWe remind you that the sugar water that contains a grams of water and b grams of sugar is \\frac{100b}{a + b} percent.\nAlso, in this problem, pure water that does not contain any sugar is regarded as 0 percent density sugar water.\n\nConstraints\n\n1 \\leq A < B \\leq 30\n\n1 \\leq C < D \\leq 30\n\n1 \\leq E \\leq 100\n\n100A \\leq F \\leq 3 000\n\nA, B, C, D, E and F are all integers.\n\nInputs\n\nInput is given from Standard Input in the following format:\n\nA B C D E F\n\nOutputs\n\nPrint two integers separated by a space.\nThe first integer should be the mass of the desired sugar water, and the second should be the mass of the sugar dissolved in it.\n\nSample Input 1\n\n1 2 10 20 15 200\n\nSample Output 1\n\n110 10\n\nIn this environment, 15 grams of sugar can dissolve into 100 grams of water, and the beaker can contain at most 200 grams of substances.\n\nWe can make 110 grams of sugar water by performing Operation 1 once and Operation 3 once.\nIt is not possible to make sugar water with higher density.\nFor example, the following sequences of operations are infeasible:\n\nIf we perform Operation 1 once and Operation 4 once, there will be undissolved sugar in the beaker.\n\nIf we perform Operation 2 once and Operation 3 three times, the mass of substances in the beaker will exceed 200 grams.\n\nSample Input 2\n\n1 2 1 2 100 1000\n\nSample Output 2\n\n200 100\n\nThere are other acceptable outputs, such as:\n\n400 200\n\nHowever, the output below is not acceptable:\n\n300 150\n\nThis is because, in order to make 300 grams of sugar water containing 150 grams of sugar, we need to pour exactly 150 grams of water into the beaker, which is impossible.\n\nSample Input 3\n\n17 19 22 26 55 2802\n\nSample Output 3\n\n2634 934", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1027, "cpu_time_ms": 572, "memory_kb": 384}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s041089620", "group_id": "codeNet:p03600", "input_text": "#include <bits/stdc++.h>\nusing ll = long long;\nusing namespace std;\n#define rep(i,n) for(int i=0, i##_len=(int)(n); i<i##_len; i++)\n#define reps(i,n) for(int i=1 , i##_len=(int)(n);i<=i##_len;i++)\n#define rrep(i,n) for(int i=((int)(n)-1);i>=0;i--)\n#define rreps(i,n) for(int i=((int)(n));i>0;i--)\n#define all(x) (x).begin(), (x).end()\n#define F first\n#define S second\n#define mp make_pair\n#define pb push_back\n#define solve(a) ((a)?\"Yes\":\"No\")\ntypedef vector<long long> V;\ntypedef vector<V> VV;\ntypedef pair<long long , long long> P;\ntemplate<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1;} return 0;}\ntemplate<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1;} return 0;}\nconst long long INFLL = 1LL<<62;\nconst int INF = 1<<30;\nconst double PI=acos(-1);\n//ワーシャルフロイゼ法(隣接行列を受け取り、それぞれの最短を受け取る、size:10^2-)\nvector<vector<long long>> WarshallFloyd(vector<vector<long long>> &pathmatrix){\n    int index=pathmatrix.size();\n    vector<vector<long long >>res=pathmatrix;\n    for (int a = 0; a < index; a++){\n        for (int b = 0; b < index; b++){\n            for (int c = 0; c < index; c++){ \n                chmin(res[b][c], res[b][a] + res[a][c]);\n            }\n        }\n    }\n    return (res);\n}\nint main(){\n    int n;\n    ll ans=0LL;\n    ll stack=0LL;\n    cin >>n;\n    VV ppath(n,V(n));\n    VV upath(n, V(n,0LL));\n\n    rep(i,n){\n        rep(j,n){\n            cin>>ppath[i][j];\n            ans+=ppath[i][j];\n        }\n    }\n   // clog<<ans<<endl;\n        int index = ppath.size();\n        vector<vector<long long>> res = ppath;\n        for (int a = 0; a < index; a++)\n        {\n            for (int b = 0; b < index; b++)\n            {\n                for (int c = 0; c < index; c++)\n                {\n                    if(a!=b and a!=c and b!=c){\n                        if ((res[b][c] == res[b][a] + res[a][c])){\n                         \n                        //    clog << \"(\" << res[b][c] << \" \" << res[b][a] + res[a][c] << \")  \";\n                         //   clog<<b<<\" \"<<c<<\" ->thourg \"<<endl;\n                        }else if (res[b][c] > res[b][a] + res[a][c]){\n                            \n                            cout<<-1<<endl;\n                            return 0;\n                        }else if(upath[b][c]!=-1){\n                           \n                        //    clog << \"(\" << res[b][c] << \" \" << res[b][a] + res[a][c] << \")  \";\n                          //  clog << b << \" \" << c << \" ->strate \" << endl;\n                        }\n                        //chmin(res[b][c], res[b][a] + res[a][c]);\n                    }\n                   \n                }\n            }\n        }\n        \n\n    rep(i,n){\n        rep(j,n){\n            rep(k,n){\n                if(k!=i and k!=j){\n                    if(res[i][k] + res[k][j] == res[i][j]){\n                        ans-=res[i][j];\n                        break;\n                    }\n                }\n          \n            }\n         //   clog << upath[i][j] << \" \";\n        }\n       // clog<<endl;\n    }\n\n    cout<<ans/2<<endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1585538651, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03600.html", "problem_id": "p03600", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03600/input.txt", "sample_output_relpath": "derived/input_output/data/p03600/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03600/C++/s041089620.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s041089620", "user_id": "u179778090"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing ll = long long;\nusing namespace std;\n#define rep(i,n) for(int i=0, i##_len=(int)(n); i<i##_len; i++)\n#define reps(i,n) for(int i=1 , i##_len=(int)(n);i<=i##_len;i++)\n#define rrep(i,n) for(int i=((int)(n)-1);i>=0;i--)\n#define rreps(i,n) for(int i=((int)(n));i>0;i--)\n#define all(x) (x).begin(), (x).end()\n#define F first\n#define S second\n#define mp make_pair\n#define pb push_back\n#define solve(a) ((a)?\"Yes\":\"No\")\ntypedef vector<long long> V;\ntypedef vector<V> VV;\ntypedef pair<long long , long long> P;\ntemplate<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return 1;} return 0;}\ntemplate<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return 1;} return 0;}\nconst long long INFLL = 1LL<<62;\nconst int INF = 1<<30;\nconst double PI=acos(-1);\n//ワーシャルフロイゼ法(隣接行列を受け取り、それぞれの最短を受け取る、size:10^2-)\nvector<vector<long long>> WarshallFloyd(vector<vector<long long>> &pathmatrix){\n    int index=pathmatrix.size();\n    vector<vector<long long >>res=pathmatrix;\n    for (int a = 0; a < index; a++){\n        for (int b = 0; b < index; b++){\n            for (int c = 0; c < index; c++){ \n                chmin(res[b][c], res[b][a] + res[a][c]);\n            }\n        }\n    }\n    return (res);\n}\nint main(){\n    int n;\n    ll ans=0LL;\n    ll stack=0LL;\n    cin >>n;\n    VV ppath(n,V(n));\n    VV upath(n, V(n,0LL));\n\n    rep(i,n){\n        rep(j,n){\n            cin>>ppath[i][j];\n            ans+=ppath[i][j];\n        }\n    }\n   // clog<<ans<<endl;\n        int index = ppath.size();\n        vector<vector<long long>> res = ppath;\n        for (int a = 0; a < index; a++)\n        {\n            for (int b = 0; b < index; b++)\n            {\n                for (int c = 0; c < index; c++)\n                {\n                    if(a!=b and a!=c and b!=c){\n                        if ((res[b][c] == res[b][a] + res[a][c])){\n                         \n                        //    clog << \"(\" << res[b][c] << \" \" << res[b][a] + res[a][c] << \")  \";\n                         //   clog<<b<<\" \"<<c<<\" ->thourg \"<<endl;\n                        }else if (res[b][c] > res[b][a] + res[a][c]){\n                            \n                            cout<<-1<<endl;\n                            return 0;\n                        }else if(upath[b][c]!=-1){\n                           \n                        //    clog << \"(\" << res[b][c] << \" \" << res[b][a] + res[a][c] << \")  \";\n                          //  clog << b << \" \" << c << \" ->strate \" << endl;\n                        }\n                        //chmin(res[b][c], res[b][a] + res[a][c]);\n                    }\n                   \n                }\n            }\n        }\n        \n\n    rep(i,n){\n        rep(j,n){\n            rep(k,n){\n                if(k!=i and k!=j){\n                    if(res[i][k] + res[k][j] == res[i][j]){\n                        ans-=res[i][j];\n                        break;\n                    }\n                }\n          \n            }\n         //   clog << upath[i][j] << \" \";\n        }\n       // clog<<endl;\n    }\n\n    cout<<ans/2<<endl;\n    return 0;\n}", "problem_context": "Score : 500 points\n\nProblem Statement\n\nIn Takahashi Kingdom, which once existed, there are N cities, and some pairs of cities are connected bidirectionally by roads.\nThe following are known about the road network:\n\nPeople traveled between cities only through roads. It was possible to reach any city from any other city, via intermediate cities if necessary.\n\nDifferent roads may have had different lengths, but all the lengths were positive integers.\n\nSnuke the archeologist found a table with N rows and N columns, A, in the ruin of Takahashi Kingdom.\nHe thought that it represented the shortest distances between the cities along the roads in the kingdom.\n\nDetermine whether there exists a road network such that for each u and v, the integer A_{u, v} at the u-th row and v-th column of A is equal to the length of the shortest path from City u to City v.\nIf such a network exist, find the shortest possible total length of the roads.\n\nConstraints\n\n1 \\leq N \\leq 300\n\nIf i ≠ j, 1 \\leq A_{i, j} = A_{j, i} \\leq 10^9.\n\nA_{i, i} = 0\n\nInputs\n\nInput is given from Standard Input in the following format:\n\nN\nA_{1, 1} A_{1, 2} ... A_{1, N}\nA_{2, 1} A_{2, 2} ... A_{2, N}\n...\nA_{N, 1} A_{N, 2} ... A_{N, N}\n\nOutputs\n\nIf there exists no network that satisfies the condition, print -1.\nIf it exists, print the shortest possible total length of the roads.\n\nSample Input 1\n\n3\n0 1 3\n1 0 2\n3 2 0\n\nSample Output 1\n\n3\n\nThe network below satisfies the condition:\n\nCity 1 and City 2 is connected by a road of length 1.\n\nCity 2 and City 3 is connected by a road of length 2.\n\nCity 3 and City 1 is not connected by a road.\n\nSample Input 2\n\n3\n0 1 3\n1 0 1\n3 1 0\n\nSample Output 2\n\n-1\n\nAs there is a path of length 1 from City 1 to City 2 and City 2 to City 3, there is a path of length 2 from City 1 to City 3.\nHowever, according to the table, the shortest distance between City 1 and City 3 must be 3.\n\nThus, we conclude that there exists no network that satisfies the condition.\n\nSample Input 3\n\n5\n0 21 18 11 28\n21 0 13 10 26\n18 13 0 23 13\n11 10 23 0 17\n28 26 13 17 0\n\nSample Output 3\n\n82\n\nSample Input 4\n\n3\n0 1000000000 1000000000\n1000000000 0 1000000000\n1000000000 1000000000 0\n\nSample Output 4\n\n3000000000", "sample_input": "3\n0 1 3\n1 0 2\n3 2 0\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03600", "source_text": "Score : 500 points\n\nProblem Statement\n\nIn Takahashi Kingdom, which once existed, there are N cities, and some pairs of cities are connected bidirectionally by roads.\nThe following are known about the road network:\n\nPeople traveled between cities only through roads. It was possible to reach any city from any other city, via intermediate cities if necessary.\n\nDifferent roads may have had different lengths, but all the lengths were positive integers.\n\nSnuke the archeologist found a table with N rows and N columns, A, in the ruin of Takahashi Kingdom.\nHe thought that it represented the shortest distances between the cities along the roads in the kingdom.\n\nDetermine whether there exists a road network such that for each u and v, the integer A_{u, v} at the u-th row and v-th column of A is equal to the length of the shortest path from City u to City v.\nIf such a network exist, find the shortest possible total length of the roads.\n\nConstraints\n\n1 \\leq N \\leq 300\n\nIf i ≠ j, 1 \\leq A_{i, j} = A_{j, i} \\leq 10^9.\n\nA_{i, i} = 0\n\nInputs\n\nInput is given from Standard Input in the following format:\n\nN\nA_{1, 1} A_{1, 2} ... A_{1, N}\nA_{2, 1} A_{2, 2} ... A_{2, N}\n...\nA_{N, 1} A_{N, 2} ... A_{N, N}\n\nOutputs\n\nIf there exists no network that satisfies the condition, print -1.\nIf it exists, print the shortest possible total length of the roads.\n\nSample Input 1\n\n3\n0 1 3\n1 0 2\n3 2 0\n\nSample Output 1\n\n3\n\nThe network below satisfies the condition:\n\nCity 1 and City 2 is connected by a road of length 1.\n\nCity 2 and City 3 is connected by a road of length 2.\n\nCity 3 and City 1 is not connected by a road.\n\nSample Input 2\n\n3\n0 1 3\n1 0 1\n3 1 0\n\nSample Output 2\n\n-1\n\nAs there is a path of length 1 from City 1 to City 2 and City 2 to City 3, there is a path of length 2 from City 1 to City 3.\nHowever, according to the table, the shortest distance between City 1 and City 3 must be 3.\n\nThus, we conclude that there exists no network that satisfies the condition.\n\nSample Input 3\n\n5\n0 21 18 11 28\n21 0 13 10 26\n18 13 0 23 13\n11 10 23 0 17\n28 26 13 17 0\n\nSample Output 3\n\n82\n\nSample Input 4\n\n3\n0 1000000000 1000000000\n1000000000 0 1000000000\n1000000000 1000000000 0\n\nSample Output 4\n\n3000000000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 3138, "cpu_time_ms": 120, "memory_kb": 2432}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s171859774", "group_id": "codeNet:p03604", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef int sign;\ntypedef long long ll;\n#define For(i,a,b) for(register sign i=(sign)(a);i<=(sign)(b);++i)\n#define Fordown(i,a,b) for(register sign i=(sign)(a);i>=(sign)(b);--i)\nconst int N=2e5+5;\ntemplate<typename T>bool cmax(T &a,T b){return (a<b)?a=b,1:0;}\ntemplate<typename T>bool cmin(T &a,T b){return (a>b)?a=b,1:0;}\ntemplate<typename T>T read()\n{\n\tT ans=0,f=1;\n\tchar ch=getchar();\n\twhile(!isdigit(ch)&&ch!='-')ch=getchar();\n\tif(ch=='-')f=-1,ch=getchar();\n\twhile(isdigit(ch))ans=(ans<<3)+(ans<<1)+(ch-'0'),ch=getchar();\n\treturn ans*f;\n}\ntemplate<typename T>void write(T x,char y)\n{\n\tif(x==0)\n\t{\n\t\tputchar('0'),putchar(y);\n\t\treturn;\n\t}\n\tif(x<0)\n\t{\n\t\tputchar('-');\n\t\tx=-x;\n\t}\n\tstatic char wr[20];\n\tint top=0;\n\tfor(;x;x/=10)wr[++top]=x%10+'0';\n\twhile(top)putchar(wr[top--]);\n\tputchar(y);\n}\nvoid file()\n{\n#ifndef ONLINE_JUDGE\n\tfreopen(\"F.in\",\"r\",stdin);\n\tfreopen(\"F.out\",\"w\",stdout);\n#endif\n}\nint n,m;\nvector<int>E[N];\n#define pb push_back\nvoid input()\n{\n\tint x,y;\n\tn=read<int>();\n\tFor(i,1,n<<1)\n\t{\n\t\tx=read<int>(),y=read<int>()+n;\n\t\tE[x].pb(y),E[y].pb(x);\n\t}\n}\nconst int mo=1e9+7;\nint ans,inv[N];\nint vis[N],edge;\nint node[N],cnt;\nint c[N],top;\nint fa[N];\nint stk[N],tp;\nvoid dfs1(int u,int pre)\n{\n\t//cerr<<u<<endl;\n\tnode[++cnt]=u;stk[++tp]=u,vis[u]=1,stk[tp+1]=0;\n\t//cerr<<cnt<<endl;\n\tedge+=(int)E[u].size();\n\tfor(int v:E[u])if(v^pre)\n\t{\n\t\tif(!vis[v])dfs1(v,u);\n\t\telse if(!top)\n\t\t{\n\t\t\twhile(stk[tp+1]!=v)vis[c[++top]=stk[tp--]]=2;\n\t\t\tc[0]=v;\n\t\t}\n\t}\n\tif(!top)--tp;\n}\nvoid dfs2(int u,int pre)\n{\n\tfor(int v:E[u])if(v^pre&&vis[v]<2)\n\t{\n\t\tfa[v]=u;\n\t\tdfs2(v,u);\n\t}\n}\nvector<int>G[N];\nint d[N],sz[N];\nvoid dfs3(int u,int &res)\n{\n\tsz[u]=1;\n\tfor(int v:G[u])\n\t{\n\t\tdfs3(v,res);\n\t\tsz[u]+=sz[v];\n\t}\n\tres=1ll*res*inv[sz[u]]%mo;\n}\nint cal()\n{\n\tint res=1;\n\tFor(i,1,cnt)\n\t{\n\t\tres=1ll*res*i%mo;\n\t\td[node[i]]=0;\n\t\tG[node[i]].clear();\n\t}\n\tFor(i,1,cnt)\n\t{\n\t\tfor(int v:E[node[i]])if(v<fa[node[i]])\n\t\t{\n\t\t\tG[node[i]].pb(v);d[v]++;\n\t\t}\n\t}\n\tFor(i,1,cnt)if(!d[node[i]])dfs3(node[i],res);\n\treturn res;\n}\nvoid init(int st)\n{\n\tint res=0;\n\tcnt=top=tp=edge=0;\t\n\tdfs1(st,0);\t\n\tif(edge!=(cnt<<1)){puts(\"0\");exit(0);}\n\tFor(i,1,top)dfs2(c[i],0);\t\n\tFor(i,1,top)fa[c[i-1]]=c[i];\n\tres=cal();\n\tFor(i,1,top)fa[c[i]]=c[i-1];\n\tres=(res+cal())%mo;\n\tans=1ll*ans*res%mo;\n\tFor(i,1,cnt)ans=1ll*ans*inv[i]%mo;\n\t//cerr<<cnt<<endl;\n}\nvoid work()\n{\n\tans=1;\n\tinv[0]=inv[1]=1;\n\tFor(i,2,n<<1)ans=1ll*ans*i%mo,inv[i]=1ll*inv[mo%i]*(mo-mo/i)%mo;\n\tFor(i,1,n<<1)if(!vis[i])init(i);\n\twrite(ans,'\\n');\n}\nint main()\n{\n\n\tinput();\n\twork();\n\treturn 0;\n}\n\n", "language": "C++", "metadata": {"date": 1550716436, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03604.html", "problem_id": "p03604", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03604/input.txt", "sample_output_relpath": "derived/input_output/data/p03604/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03604/C++/s171859774.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s171859774", "user_id": "u263933075"}, "prompt_components": {"gold_output": "8\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef int sign;\ntypedef long long ll;\n#define For(i,a,b) for(register sign i=(sign)(a);i<=(sign)(b);++i)\n#define Fordown(i,a,b) for(register sign i=(sign)(a);i>=(sign)(b);--i)\nconst int N=2e5+5;\ntemplate<typename T>bool cmax(T &a,T b){return (a<b)?a=b,1:0;}\ntemplate<typename T>bool cmin(T &a,T b){return (a>b)?a=b,1:0;}\ntemplate<typename T>T read()\n{\n\tT ans=0,f=1;\n\tchar ch=getchar();\n\twhile(!isdigit(ch)&&ch!='-')ch=getchar();\n\tif(ch=='-')f=-1,ch=getchar();\n\twhile(isdigit(ch))ans=(ans<<3)+(ans<<1)+(ch-'0'),ch=getchar();\n\treturn ans*f;\n}\ntemplate<typename T>void write(T x,char y)\n{\n\tif(x==0)\n\t{\n\t\tputchar('0'),putchar(y);\n\t\treturn;\n\t}\n\tif(x<0)\n\t{\n\t\tputchar('-');\n\t\tx=-x;\n\t}\n\tstatic char wr[20];\n\tint top=0;\n\tfor(;x;x/=10)wr[++top]=x%10+'0';\n\twhile(top)putchar(wr[top--]);\n\tputchar(y);\n}\nvoid file()\n{\n#ifndef ONLINE_JUDGE\n\tfreopen(\"F.in\",\"r\",stdin);\n\tfreopen(\"F.out\",\"w\",stdout);\n#endif\n}\nint n,m;\nvector<int>E[N];\n#define pb push_back\nvoid input()\n{\n\tint x,y;\n\tn=read<int>();\n\tFor(i,1,n<<1)\n\t{\n\t\tx=read<int>(),y=read<int>()+n;\n\t\tE[x].pb(y),E[y].pb(x);\n\t}\n}\nconst int mo=1e9+7;\nint ans,inv[N];\nint vis[N],edge;\nint node[N],cnt;\nint c[N],top;\nint fa[N];\nint stk[N],tp;\nvoid dfs1(int u,int pre)\n{\n\t//cerr<<u<<endl;\n\tnode[++cnt]=u;stk[++tp]=u,vis[u]=1,stk[tp+1]=0;\n\t//cerr<<cnt<<endl;\n\tedge+=(int)E[u].size();\n\tfor(int v:E[u])if(v^pre)\n\t{\n\t\tif(!vis[v])dfs1(v,u);\n\t\telse if(!top)\n\t\t{\n\t\t\twhile(stk[tp+1]!=v)vis[c[++top]=stk[tp--]]=2;\n\t\t\tc[0]=v;\n\t\t}\n\t}\n\tif(!top)--tp;\n}\nvoid dfs2(int u,int pre)\n{\n\tfor(int v:E[u])if(v^pre&&vis[v]<2)\n\t{\n\t\tfa[v]=u;\n\t\tdfs2(v,u);\n\t}\n}\nvector<int>G[N];\nint d[N],sz[N];\nvoid dfs3(int u,int &res)\n{\n\tsz[u]=1;\n\tfor(int v:G[u])\n\t{\n\t\tdfs3(v,res);\n\t\tsz[u]+=sz[v];\n\t}\n\tres=1ll*res*inv[sz[u]]%mo;\n}\nint cal()\n{\n\tint res=1;\n\tFor(i,1,cnt)\n\t{\n\t\tres=1ll*res*i%mo;\n\t\td[node[i]]=0;\n\t\tG[node[i]].clear();\n\t}\n\tFor(i,1,cnt)\n\t{\n\t\tfor(int v:E[node[i]])if(v<fa[node[i]])\n\t\t{\n\t\t\tG[node[i]].pb(v);d[v]++;\n\t\t}\n\t}\n\tFor(i,1,cnt)if(!d[node[i]])dfs3(node[i],res);\n\treturn res;\n}\nvoid init(int st)\n{\n\tint res=0;\n\tcnt=top=tp=edge=0;\t\n\tdfs1(st,0);\t\n\tif(edge!=(cnt<<1)){puts(\"0\");exit(0);}\n\tFor(i,1,top)dfs2(c[i],0);\t\n\tFor(i,1,top)fa[c[i-1]]=c[i];\n\tres=cal();\n\tFor(i,1,top)fa[c[i]]=c[i-1];\n\tres=(res+cal())%mo;\n\tans=1ll*ans*res%mo;\n\tFor(i,1,cnt)ans=1ll*ans*inv[i]%mo;\n\t//cerr<<cnt<<endl;\n}\nvoid work()\n{\n\tans=1;\n\tinv[0]=inv[1]=1;\n\tFor(i,2,n<<1)ans=1ll*ans*i%mo,inv[i]=1ll*inv[mo%i]*(mo-mo/i)%mo;\n\tFor(i,1,n<<1)if(!vis[i])init(i);\n\twrite(ans,'\\n');\n}\nint main()\n{\n\n\tinput();\n\twork();\n\treturn 0;\n}\n\n", "problem_context": "Score : 1200 points\n\nProblem Statement\n\nThere are 2N balls in the xy-plane. The coordinates of the i-th of them is (x_i, y_i).\nHere, x_i and y_i are integers between 1 and N (inclusive) for all i, and no two balls occupy the same coordinates.\n\nIn order to collect these balls, Snuke prepared 2N robots, N of type A and N of type B.\nThen, he placed the type-A robots at coordinates (1, 0), (2, 0), ..., (N, 0), and the type-B robots at coordinates (0, 1), (0, 2), ..., (0, N), one at each position.\n\nWhen activated, each type of robot will operate as follows.\n\nWhen a type-A robot is activated at coordinates (a, 0), it will move to the position of the ball with the lowest y-coordinate among the balls on the line x = a, collect the ball and deactivate itself. If there is no such ball, it will just deactivate itself without doing anything.\n\nWhen a type-B robot is activated at coordinates (0, b), it will move to the position of the ball with the lowest x-coordinate among the balls on the line y = b, collect the ball and deactivate itself. If there is no such ball, it will just deactivate itself without doing anything.\n\nOnce deactivated, a robot cannot be activated again. Also, while a robot is operating, no new robot can be activated until the operating robot is deactivated.\n\nWhen Snuke was about to activate a robot, he noticed that he may fail to collect all the balls, depending on the order of activating the robots.\n\nAmong the (2N)! possible orders of activating the robots, find the number of the ones such that all the balls can be collected, modulo 1 000 000 007.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n1 \\leq x_i \\leq N\n\n1 \\leq y_i \\leq N\n\nIf i ≠ j, either x_i ≠ x_j or y_i ≠ y_j.\n\nInputs\n\nInput is given from Standard Input in the following format:\n\nN\nx_1 y_1\n...\nx_{2N} y_{2N}\n\nOutputs\n\nPrint the number of the orders of activating the robots such that all the balls can be collected, modulo 1 000 000 007.\n\nSample Input 1\n\n2\n1 1\n1 2\n2 1\n2 2\n\nSample Output 1\n\n8\n\nWe will refer to the robots placed at (1, 0) and (2, 0) as A1 and A2, respectively, and the robots placed at (0, 1) and (0, 2) as B1 and B2, respectively.\nThere are eight orders of activation that satisfy the condition, as follows:\n\nA1, B1, A2, B2\n\nA1, B1, B2, A2\n\nA1, B2, B1, A2\n\nA2, B1, A1, B2\n\nB1, A1, B2, A2\n\nB1, A1, A2, B2\n\nB1, A2, A1, B2\n\nB2, A1, B1, A2\n\nThus, the output should be 8.\n\nSample Input 2\n\n4\n3 2\n1 2\n4 1\n4 2\n2 2\n4 4\n2 1\n1 3\n\nSample Output 2\n\n7392\n\nSample Input 3\n\n4\n1 1\n2 2\n3 3\n4 4\n1 2\n2 1\n3 4\n4 3\n\nSample Output 3\n\n4480\n\nSample Input 4\n\n8\n6 2\n5 1\n6 8\n7 8\n6 5\n5 7\n4 3\n1 4\n7 6\n8 3\n2 8\n3 6\n3 2\n8 5\n1 5\n5 8\n\nSample Output 4\n\n82060779\n\nSample Input 5\n\n3\n1 1\n1 2\n1 3\n2 1\n2 2\n2 3\n\nSample Output 5\n\n0\n\nWhen there is no order of activation that satisfies the condition, the output should be 0.", "sample_input": "2\n1 1\n1 2\n2 1\n2 2\n"}, "reference_outputs": ["8\n"], "source_document_id": "p03604", "source_text": "Score : 1200 points\n\nProblem Statement\n\nThere are 2N balls in the xy-plane. The coordinates of the i-th of them is (x_i, y_i).\nHere, x_i and y_i are integers between 1 and N (inclusive) for all i, and no two balls occupy the same coordinates.\n\nIn order to collect these balls, Snuke prepared 2N robots, N of type A and N of type B.\nThen, he placed the type-A robots at coordinates (1, 0), (2, 0), ..., (N, 0), and the type-B robots at coordinates (0, 1), (0, 2), ..., (0, N), one at each position.\n\nWhen activated, each type of robot will operate as follows.\n\nWhen a type-A robot is activated at coordinates (a, 0), it will move to the position of the ball with the lowest y-coordinate among the balls on the line x = a, collect the ball and deactivate itself. If there is no such ball, it will just deactivate itself without doing anything.\n\nWhen a type-B robot is activated at coordinates (0, b), it will move to the position of the ball with the lowest x-coordinate among the balls on the line y = b, collect the ball and deactivate itself. If there is no such ball, it will just deactivate itself without doing anything.\n\nOnce deactivated, a robot cannot be activated again. Also, while a robot is operating, no new robot can be activated until the operating robot is deactivated.\n\nWhen Snuke was about to activate a robot, he noticed that he may fail to collect all the balls, depending on the order of activating the robots.\n\nAmong the (2N)! possible orders of activating the robots, find the number of the ones such that all the balls can be collected, modulo 1 000 000 007.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n1 \\leq x_i \\leq N\n\n1 \\leq y_i \\leq N\n\nIf i ≠ j, either x_i ≠ x_j or y_i ≠ y_j.\n\nInputs\n\nInput is given from Standard Input in the following format:\n\nN\nx_1 y_1\n...\nx_{2N} y_{2N}\n\nOutputs\n\nPrint the number of the orders of activating the robots such that all the balls can be collected, modulo 1 000 000 007.\n\nSample Input 1\n\n2\n1 1\n1 2\n2 1\n2 2\n\nSample Output 1\n\n8\n\nWe will refer to the robots placed at (1, 0) and (2, 0) as A1 and A2, respectively, and the robots placed at (0, 1) and (0, 2) as B1 and B2, respectively.\nThere are eight orders of activation that satisfy the condition, as follows:\n\nA1, B1, A2, B2\n\nA1, B1, B2, A2\n\nA1, B2, B1, A2\n\nA2, B1, A1, B2\n\nB1, A1, B2, A2\n\nB1, A1, A2, B2\n\nB1, A2, A1, B2\n\nB2, A1, B1, A2\n\nThus, the output should be 8.\n\nSample Input 2\n\n4\n3 2\n1 2\n4 1\n4 2\n2 2\n4 4\n2 1\n1 3\n\nSample Output 2\n\n7392\n\nSample Input 3\n\n4\n1 1\n2 2\n3 3\n4 4\n1 2\n2 1\n3 4\n4 3\n\nSample Output 3\n\n4480\n\nSample Input 4\n\n8\n6 2\n5 1\n6 8\n7 8\n6 5\n5 7\n4 3\n1 4\n7 6\n8 3\n2 8\n3 6\n3 2\n8 5\n1 5\n5 8\n\nSample Output 4\n\n82060779\n\nSample Input 5\n\n3\n1 1\n1 2\n1 3\n2 1\n2 2\n2 3\n\nSample Output 5\n\n0\n\nWhen there is no order of activation that satisfies the condition, the output should be 0.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2540, "cpu_time_ms": 114, "memory_kb": 27520}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s435544142", "group_id": "codeNet:p03604", "input_text": "#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <iostream>\n#include <vector>\n#include <string>\n#include <algorithm>\n#include <stack>\n#include <queue>\n#include <set>\n#include <map>\nusing namespace std;\n#define MOD 1000000007\n#define ADD(X,Y) ((X) = ((X) + (Y)%MOD) % MOD)\ntypedef long long i64; typedef vector<int> ivec; typedef vector<string> svec;\n\ni64 modpow(i64 a, int p = MOD - 2)\n{\n\tif (p == 0) return 1;\n\ti64 tmp = modpow(a, p / 2);\n\ttmp = tmp * tmp % MOD;\n\tif (p % 2 == 1) tmp = tmp * a % MOD;\n\treturn tmp;\n}\n\nint N, X[101010], Y[101010];\ni64 fact[202020], facti[202020];\n\nvector<int> ax[101010], ay[101010];\n\nint uf[202020];\n\nint root(int p)\n{\n\treturn uf[p] < 0 ? p : (uf[p] = root(uf[p]));\n}\nbool join(int p, int q)\n{\n\tp = root(p);\n\tq = root(q);\n\tif (p == q) return false;\n\tuf[p] += uf[q];\n\tuf[q] = p;\n\treturn true;\n}\n\nvector<int> grp[202020];\nint dir[202020]; // 0: down, 1: left\n\nset<int> sx[101010], sy[101010];\nvector<int> depends[202020];\nint depender[202020];\n\nvoid add_dependency(int p, int q)\n{\n\t// p depends on q\n\tdepends[p].push_back(q);\n\tdepender[q] = p;\n}\n\npair<int, i64> solve_dependency(int p)\n{\n\tint sz = 0;\n\ti64 pat = 1;\n\n\tfor (int q : depends[p]) {\n\t\t//printf(\"%d -> %d\\n\", p, q);\n\t\tauto sub = solve_dependency(q);\n\t\tpat = pat * sub.second % MOD;\n\t\tpat = pat * facti[sub.first] % MOD;\n\t\tsz += sub.first;\n\t}\n\tpat = pat * fact[sz] % MOD;\n\n\treturn{ sz + 1, pat };\n}\n\ni64 solve(int g)\n{\n\tset<int> xs, ys;\n\tfor (int c : grp[g]) {\n\t\txs.insert(X[c]);\n\t\tys.insert(Y[c]);\n\t}\n\tif (xs.size() + ys.size() != grp[g].size()) {\n\t\treturn 0;\n\t}\n\n\ti64 ret = 0;\n\tfor (int t = 0; t < 2; ++t) {\n\t\tfor (int c : grp[g]) {\n\t\t\tdepends[c].clear();\n\t\t\tdepender[c] = -1;\n\t\t\tdir[c] = -1;\n\t\t}\n\t\tfor (int x : xs) sx[x].clear();\n\t\tfor (int y : ys) sy[y].clear();\n\n\t\tfor (int c : grp[g]) {\n\t\t\tsx[X[c]].insert(c);\n\t\t\tsy[Y[c]].insert(c);\n\t\t}\n\t\tqueue<pair<int, int>> Q;\n\t\tfor (int x : xs) {\n\t\t\tif (sx[x].size() == 0) {\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\tif (sx[x].size() == 1) {\n\t\t\t\tQ.push({ 0, *sx[x].begin() });\n\t\t\t}\n\t\t}\n\t\tfor (int y : ys) {\n\t\t\tif (sy[y].size() == 0) {\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\tif (sy[y].size() == 1) {\n\t\t\t\tQ.push({ 1, *sy[y].begin() });\n\t\t\t}\n\t\t}\n\t\tint rem = grp[g].size();\n\n\t\twhile (rem > 0) {\n\t\t\tif (Q.empty()) {\n\t\t\t\tint tg = 0;\n\t\t\t\tfor (int x : xs) {\n\t\t\t\t\tif (sx[x].size() > 0) {\n\t\t\t\t\t\tQ.push({ t, *sx[x].begin() });\n\t\t\t\t\t\t//printf(\"force %d %d\\n\", *sx[x].begin(), t);\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tcontinue;\n\t\t\t}\n\n\t\t\tauto a = Q.front(); Q.pop();\n\t\t\t--rem;\n\n\t\t\tif (a.first == 0) {\n\t\t\t\tint p = a.second; // *sx[a.second].begin();\n\t\t\t\t//printf(\"decide %d %d\\n\", p, 0);\n\t\t\t\tdir[p] = 0;\n\t\t\t\tsx[X[p]].erase(p);\n\t\t\t\tsy[Y[p]].erase(p);\n\t\t\t\t//if (sy[Y[p]].size() == 0) return 0;\n\t\t\t\tif (sy[Y[p]].size() == 1) {\n\t\t\t\t\t//printf(\"%d\\n\", *sy[Y[p]].begin());\n\t\t\t\t\tQ.push({ 1, *sy[Y[p]].begin() });\n\t\t\t\t}\n\t\t\t} else {\n\t\t\t\tint p = a.second; // *sy[a.second].begin();\n\t\t\t\t//printf(\"decide %d %d\\n\", p, 1);\n\t\t\t\tdir[p] = 1;\n\t\t\t\tsx[X[p]].erase(p);\n\t\t\t\tsy[Y[p]].erase(p);\n\t\t\t\t//if (sx[X[p]].size() == 0) return 0;\n\t\t\t\tif (sx[X[p]].size() == 1) {\n\t\t\t\t\tQ.push({ 0, *sx[X[p]].begin() });\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tfor (int c : grp[g]) {\n\t\t\tint x = X[c], y = Y[c];\n\t\t//\tprintf(\"%d %d: %d\\n\", x, y, dir[c]);\n\t\t\tif (dir[c] == 0) {\n\t\t\t\tfor (int d : ax[x]) {\n\t\t\t\t\tif (Y[d] < y) {\n\t\t\t\t\t\tadd_dependency(c, d);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t} else if (dir[c] == 1) {\n\t\t\t\tfor (int d : ay[y]) {\n\t\t\t\t\tif (X[d] < x) {\n\t\t\t\t\t\tadd_dependency(c, d);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t} else {\n\t\t\t\tputs(\"><\");\n\t\t\t}\n\t\t}\n\n\t\ti64 pat = fact[grp[g].size()];\n\t\tfor (int c : grp[g]) {\n\t\t\tif (depender[c] == -1) {\n\t\t\t\tpair<int, i64> sz_pat = solve_dependency(c);\n\t\t\t\tpat = pat * facti[sz_pat.first] % MOD * sz_pat.second % MOD;\n\t\t\t}\n\t\t}\n\t\tADD(ret, pat);\n\t}\n\n\treturn ret;\n}\n\nint main()\n{\n\tscanf(\"%d\", &N);\n\tfor (int i = 0; i < 2 * N; ++i) {\n\t\tint x, y;\n\t\tscanf(\"%d%d\", &x, &y);\n\t\t--x; --y;\n\t\tX[i] = x;\n\t\tY[i] = y;\n\t\tax[x].push_back(i);\n\t\tay[y].push_back(i);\n\t}\n\tfact[0] = 1;\n\tfor (int i = 1; i <= 2 * N; ++i) fact[i] = fact[i - 1] * i % MOD;\n\tfor (int i = 0; i <= 2 * N; ++i) facti[i] = modpow(fact[i]);\n\n\tfor (int i = 0; i < 2 * N; ++i) uf[i] = -1;\n\tfor (int i = 0; i < N; ++i) {\n\t\tfor (int j = 1; j < ax[i].size(); ++j) {\n\t\t\tjoin(ax[i][j - 1], ax[i][j]);\n\t\t}\n\t\tfor (int j = 1; j < ay[i].size(); ++j) {\n\t\t\tjoin(ay[i][j - 1], ay[i][j]);\n\t\t}\n\t}\n\tfor (int i = 0; i < 2 * N; ++i) {\n\t\tgrp[root(i)].push_back(i);\n\t}\n\n\ti64 ret = fact[2 * N];\n\tfor (int i = 0; i < 2 * N; ++i) {\n\t\tif (grp[i].size() > 0) {\n\t\t\tret = ret * facti[grp[i].size()] % MOD * solve(i) % MOD;\n\t\t\tif (ret == 0) break;\n\t\t}\n\t}\n\n\n\tprintf(\"%lld\\n\", ret);\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1505615810, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03604.html", "problem_id": "p03604", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03604/input.txt", "sample_output_relpath": "derived/input_output/data/p03604/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03604/C++/s435544142.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s435544142", "user_id": "u967083551"}, "prompt_components": {"gold_output": "8\n", "input_to_evaluate": "#include <cstdio>\n#include <cstdlib>\n#include <cstring>\n#include <iostream>\n#include <vector>\n#include <string>\n#include <algorithm>\n#include <stack>\n#include <queue>\n#include <set>\n#include <map>\nusing namespace std;\n#define MOD 1000000007\n#define ADD(X,Y) ((X) = ((X) + (Y)%MOD) % MOD)\ntypedef long long i64; typedef vector<int> ivec; typedef vector<string> svec;\n\ni64 modpow(i64 a, int p = MOD - 2)\n{\n\tif (p == 0) return 1;\n\ti64 tmp = modpow(a, p / 2);\n\ttmp = tmp * tmp % MOD;\n\tif (p % 2 == 1) tmp = tmp * a % MOD;\n\treturn tmp;\n}\n\nint N, X[101010], Y[101010];\ni64 fact[202020], facti[202020];\n\nvector<int> ax[101010], ay[101010];\n\nint uf[202020];\n\nint root(int p)\n{\n\treturn uf[p] < 0 ? p : (uf[p] = root(uf[p]));\n}\nbool join(int p, int q)\n{\n\tp = root(p);\n\tq = root(q);\n\tif (p == q) return false;\n\tuf[p] += uf[q];\n\tuf[q] = p;\n\treturn true;\n}\n\nvector<int> grp[202020];\nint dir[202020]; // 0: down, 1: left\n\nset<int> sx[101010], sy[101010];\nvector<int> depends[202020];\nint depender[202020];\n\nvoid add_dependency(int p, int q)\n{\n\t// p depends on q\n\tdepends[p].push_back(q);\n\tdepender[q] = p;\n}\n\npair<int, i64> solve_dependency(int p)\n{\n\tint sz = 0;\n\ti64 pat = 1;\n\n\tfor (int q : depends[p]) {\n\t\t//printf(\"%d -> %d\\n\", p, q);\n\t\tauto sub = solve_dependency(q);\n\t\tpat = pat * sub.second % MOD;\n\t\tpat = pat * facti[sub.first] % MOD;\n\t\tsz += sub.first;\n\t}\n\tpat = pat * fact[sz] % MOD;\n\n\treturn{ sz + 1, pat };\n}\n\ni64 solve(int g)\n{\n\tset<int> xs, ys;\n\tfor (int c : grp[g]) {\n\t\txs.insert(X[c]);\n\t\tys.insert(Y[c]);\n\t}\n\tif (xs.size() + ys.size() != grp[g].size()) {\n\t\treturn 0;\n\t}\n\n\ti64 ret = 0;\n\tfor (int t = 0; t < 2; ++t) {\n\t\tfor (int c : grp[g]) {\n\t\t\tdepends[c].clear();\n\t\t\tdepender[c] = -1;\n\t\t\tdir[c] = -1;\n\t\t}\n\t\tfor (int x : xs) sx[x].clear();\n\t\tfor (int y : ys) sy[y].clear();\n\n\t\tfor (int c : grp[g]) {\n\t\t\tsx[X[c]].insert(c);\n\t\t\tsy[Y[c]].insert(c);\n\t\t}\n\t\tqueue<pair<int, int>> Q;\n\t\tfor (int x : xs) {\n\t\t\tif (sx[x].size() == 0) {\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\tif (sx[x].size() == 1) {\n\t\t\t\tQ.push({ 0, *sx[x].begin() });\n\t\t\t}\n\t\t}\n\t\tfor (int y : ys) {\n\t\t\tif (sy[y].size() == 0) {\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t\tif (sy[y].size() == 1) {\n\t\t\t\tQ.push({ 1, *sy[y].begin() });\n\t\t\t}\n\t\t}\n\t\tint rem = grp[g].size();\n\n\t\twhile (rem > 0) {\n\t\t\tif (Q.empty()) {\n\t\t\t\tint tg = 0;\n\t\t\t\tfor (int x : xs) {\n\t\t\t\t\tif (sx[x].size() > 0) {\n\t\t\t\t\t\tQ.push({ t, *sx[x].begin() });\n\t\t\t\t\t\t//printf(\"force %d %d\\n\", *sx[x].begin(), t);\n\t\t\t\t\t\tbreak;\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t\tcontinue;\n\t\t\t}\n\n\t\t\tauto a = Q.front(); Q.pop();\n\t\t\t--rem;\n\n\t\t\tif (a.first == 0) {\n\t\t\t\tint p = a.second; // *sx[a.second].begin();\n\t\t\t\t//printf(\"decide %d %d\\n\", p, 0);\n\t\t\t\tdir[p] = 0;\n\t\t\t\tsx[X[p]].erase(p);\n\t\t\t\tsy[Y[p]].erase(p);\n\t\t\t\t//if (sy[Y[p]].size() == 0) return 0;\n\t\t\t\tif (sy[Y[p]].size() == 1) {\n\t\t\t\t\t//printf(\"%d\\n\", *sy[Y[p]].begin());\n\t\t\t\t\tQ.push({ 1, *sy[Y[p]].begin() });\n\t\t\t\t}\n\t\t\t} else {\n\t\t\t\tint p = a.second; // *sy[a.second].begin();\n\t\t\t\t//printf(\"decide %d %d\\n\", p, 1);\n\t\t\t\tdir[p] = 1;\n\t\t\t\tsx[X[p]].erase(p);\n\t\t\t\tsy[Y[p]].erase(p);\n\t\t\t\t//if (sx[X[p]].size() == 0) return 0;\n\t\t\t\tif (sx[X[p]].size() == 1) {\n\t\t\t\t\tQ.push({ 0, *sx[X[p]].begin() });\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tfor (int c : grp[g]) {\n\t\t\tint x = X[c], y = Y[c];\n\t\t//\tprintf(\"%d %d: %d\\n\", x, y, dir[c]);\n\t\t\tif (dir[c] == 0) {\n\t\t\t\tfor (int d : ax[x]) {\n\t\t\t\t\tif (Y[d] < y) {\n\t\t\t\t\t\tadd_dependency(c, d);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t} else if (dir[c] == 1) {\n\t\t\t\tfor (int d : ay[y]) {\n\t\t\t\t\tif (X[d] < x) {\n\t\t\t\t\t\tadd_dependency(c, d);\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t} else {\n\t\t\t\tputs(\"><\");\n\t\t\t}\n\t\t}\n\n\t\ti64 pat = fact[grp[g].size()];\n\t\tfor (int c : grp[g]) {\n\t\t\tif (depender[c] == -1) {\n\t\t\t\tpair<int, i64> sz_pat = solve_dependency(c);\n\t\t\t\tpat = pat * facti[sz_pat.first] % MOD * sz_pat.second % MOD;\n\t\t\t}\n\t\t}\n\t\tADD(ret, pat);\n\t}\n\n\treturn ret;\n}\n\nint main()\n{\n\tscanf(\"%d\", &N);\n\tfor (int i = 0; i < 2 * N; ++i) {\n\t\tint x, y;\n\t\tscanf(\"%d%d\", &x, &y);\n\t\t--x; --y;\n\t\tX[i] = x;\n\t\tY[i] = y;\n\t\tax[x].push_back(i);\n\t\tay[y].push_back(i);\n\t}\n\tfact[0] = 1;\n\tfor (int i = 1; i <= 2 * N; ++i) fact[i] = fact[i - 1] * i % MOD;\n\tfor (int i = 0; i <= 2 * N; ++i) facti[i] = modpow(fact[i]);\n\n\tfor (int i = 0; i < 2 * N; ++i) uf[i] = -1;\n\tfor (int i = 0; i < N; ++i) {\n\t\tfor (int j = 1; j < ax[i].size(); ++j) {\n\t\t\tjoin(ax[i][j - 1], ax[i][j]);\n\t\t}\n\t\tfor (int j = 1; j < ay[i].size(); ++j) {\n\t\t\tjoin(ay[i][j - 1], ay[i][j]);\n\t\t}\n\t}\n\tfor (int i = 0; i < 2 * N; ++i) {\n\t\tgrp[root(i)].push_back(i);\n\t}\n\n\ti64 ret = fact[2 * N];\n\tfor (int i = 0; i < 2 * N; ++i) {\n\t\tif (grp[i].size() > 0) {\n\t\t\tret = ret * facti[grp[i].size()] % MOD * solve(i) % MOD;\n\t\t\tif (ret == 0) break;\n\t\t}\n\t}\n\n\n\tprintf(\"%lld\\n\", ret);\n\treturn 0;\n}\n", "problem_context": "Score : 1200 points\n\nProblem Statement\n\nThere are 2N balls in the xy-plane. The coordinates of the i-th of them is (x_i, y_i).\nHere, x_i and y_i are integers between 1 and N (inclusive) for all i, and no two balls occupy the same coordinates.\n\nIn order to collect these balls, Snuke prepared 2N robots, N of type A and N of type B.\nThen, he placed the type-A robots at coordinates (1, 0), (2, 0), ..., (N, 0), and the type-B robots at coordinates (0, 1), (0, 2), ..., (0, N), one at each position.\n\nWhen activated, each type of robot will operate as follows.\n\nWhen a type-A robot is activated at coordinates (a, 0), it will move to the position of the ball with the lowest y-coordinate among the balls on the line x = a, collect the ball and deactivate itself. If there is no such ball, it will just deactivate itself without doing anything.\n\nWhen a type-B robot is activated at coordinates (0, b), it will move to the position of the ball with the lowest x-coordinate among the balls on the line y = b, collect the ball and deactivate itself. If there is no such ball, it will just deactivate itself without doing anything.\n\nOnce deactivated, a robot cannot be activated again. Also, while a robot is operating, no new robot can be activated until the operating robot is deactivated.\n\nWhen Snuke was about to activate a robot, he noticed that he may fail to collect all the balls, depending on the order of activating the robots.\n\nAmong the (2N)! possible orders of activating the robots, find the number of the ones such that all the balls can be collected, modulo 1 000 000 007.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n1 \\leq x_i \\leq N\n\n1 \\leq y_i \\leq N\n\nIf i ≠ j, either x_i ≠ x_j or y_i ≠ y_j.\n\nInputs\n\nInput is given from Standard Input in the following format:\n\nN\nx_1 y_1\n...\nx_{2N} y_{2N}\n\nOutputs\n\nPrint the number of the orders of activating the robots such that all the balls can be collected, modulo 1 000 000 007.\n\nSample Input 1\n\n2\n1 1\n1 2\n2 1\n2 2\n\nSample Output 1\n\n8\n\nWe will refer to the robots placed at (1, 0) and (2, 0) as A1 and A2, respectively, and the robots placed at (0, 1) and (0, 2) as B1 and B2, respectively.\nThere are eight orders of activation that satisfy the condition, as follows:\n\nA1, B1, A2, B2\n\nA1, B1, B2, A2\n\nA1, B2, B1, A2\n\nA2, B1, A1, B2\n\nB1, A1, B2, A2\n\nB1, A1, A2, B2\n\nB1, A2, A1, B2\n\nB2, A1, B1, A2\n\nThus, the output should be 8.\n\nSample Input 2\n\n4\n3 2\n1 2\n4 1\n4 2\n2 2\n4 4\n2 1\n1 3\n\nSample Output 2\n\n7392\n\nSample Input 3\n\n4\n1 1\n2 2\n3 3\n4 4\n1 2\n2 1\n3 4\n4 3\n\nSample Output 3\n\n4480\n\nSample Input 4\n\n8\n6 2\n5 1\n6 8\n7 8\n6 5\n5 7\n4 3\n1 4\n7 6\n8 3\n2 8\n3 6\n3 2\n8 5\n1 5\n5 8\n\nSample Output 4\n\n82060779\n\nSample Input 5\n\n3\n1 1\n1 2\n1 3\n2 1\n2 2\n2 3\n\nSample Output 5\n\n0\n\nWhen there is no order of activation that satisfies the condition, the output should be 0.", "sample_input": "2\n1 1\n1 2\n2 1\n2 2\n"}, "reference_outputs": ["8\n"], "source_document_id": "p03604", "source_text": "Score : 1200 points\n\nProblem Statement\n\nThere are 2N balls in the xy-plane. The coordinates of the i-th of them is (x_i, y_i).\nHere, x_i and y_i are integers between 1 and N (inclusive) for all i, and no two balls occupy the same coordinates.\n\nIn order to collect these balls, Snuke prepared 2N robots, N of type A and N of type B.\nThen, he placed the type-A robots at coordinates (1, 0), (2, 0), ..., (N, 0), and the type-B robots at coordinates (0, 1), (0, 2), ..., (0, N), one at each position.\n\nWhen activated, each type of robot will operate as follows.\n\nWhen a type-A robot is activated at coordinates (a, 0), it will move to the position of the ball with the lowest y-coordinate among the balls on the line x = a, collect the ball and deactivate itself. If there is no such ball, it will just deactivate itself without doing anything.\n\nWhen a type-B robot is activated at coordinates (0, b), it will move to the position of the ball with the lowest x-coordinate among the balls on the line y = b, collect the ball and deactivate itself. If there is no such ball, it will just deactivate itself without doing anything.\n\nOnce deactivated, a robot cannot be activated again. Also, while a robot is operating, no new robot can be activated until the operating robot is deactivated.\n\nWhen Snuke was about to activate a robot, he noticed that he may fail to collect all the balls, depending on the order of activating the robots.\n\nAmong the (2N)! possible orders of activating the robots, find the number of the ones such that all the balls can be collected, modulo 1 000 000 007.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n1 \\leq x_i \\leq N\n\n1 \\leq y_i \\leq N\n\nIf i ≠ j, either x_i ≠ x_j or y_i ≠ y_j.\n\nInputs\n\nInput is given from Standard Input in the following format:\n\nN\nx_1 y_1\n...\nx_{2N} y_{2N}\n\nOutputs\n\nPrint the number of the orders of activating the robots such that all the balls can be collected, modulo 1 000 000 007.\n\nSample Input 1\n\n2\n1 1\n1 2\n2 1\n2 2\n\nSample Output 1\n\n8\n\nWe will refer to the robots placed at (1, 0) and (2, 0) as A1 and A2, respectively, and the robots placed at (0, 1) and (0, 2) as B1 and B2, respectively.\nThere are eight orders of activation that satisfy the condition, as follows:\n\nA1, B1, A2, B2\n\nA1, B1, B2, A2\n\nA1, B2, B1, A2\n\nA2, B1, A1, B2\n\nB1, A1, B2, A2\n\nB1, A1, A2, B2\n\nB1, A2, A1, B2\n\nB2, A1, B1, A2\n\nThus, the output should be 8.\n\nSample Input 2\n\n4\n3 2\n1 2\n4 1\n4 2\n2 2\n4 4\n2 1\n1 3\n\nSample Output 2\n\n7392\n\nSample Input 3\n\n4\n1 1\n2 2\n3 3\n4 4\n1 2\n2 1\n3 4\n4 3\n\nSample Output 3\n\n4480\n\nSample Input 4\n\n8\n6 2\n5 1\n6 8\n7 8\n6 5\n5 7\n4 3\n1 4\n7 6\n8 3\n2 8\n3 6\n3 2\n8 5\n1 5\n5 8\n\nSample Output 4\n\n82060779\n\nSample Input 5\n\n3\n1 1\n1 2\n1 3\n2 1\n2 2\n2 3\n\nSample Output 5\n\n0\n\nWhen there is no order of activation that satisfies the condition, the output should be 0.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 4550, "cpu_time_ms": 134, "memory_kb": 35584}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s003686061", "group_id": "codeNet:p03605", "input_text": "#include <iostream>\nusing namespace std;\n\nint main(){\n  int N, c, l, r;\n  int count = 0;\n  cin >> N;\n  for(int i = 0; i < N; ++i){\n    cin >> l >> r;\n    c = r - l + 1;\n    count += c;\n  }\n  \n  cout << count << endl;\n}", "language": "C++", "metadata": {"date": 1555002760, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03605.html", "problem_id": "p03605", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03605/input.txt", "sample_output_relpath": "derived/input_output/data/p03605/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03605/C++/s003686061.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s003686061", "user_id": "u954253447"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <iostream>\nusing namespace std;\n\nint main(){\n  int N, c, l, r;\n  int count = 0;\n  cin >> N;\n  for(int i = 0; i < N; ++i){\n    cin >> l >> r;\n    c = r - l + 1;\n    count += c;\n  }\n  \n  cout << count << endl;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nIt is September 9 in Japan now.\n\nYou are given a two-digit integer N. Answer the question: Is 9 contained in the decimal notation of N?\n\nConstraints\n\n10≤N≤99\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nIf 9 is contained in the decimal notation of N, print Yes; if not, print No.\n\nSample Input 1\n\n29\n\nSample Output 1\n\nYes\n\nThe one's digit of 29 is 9.\n\nSample Input 2\n\n72\n\nSample Output 2\n\nNo\n\n72 does not contain 9.\n\nSample Input 3\n\n91\n\nSample Output 3\n\nYes", "sample_input": "29\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p03605", "source_text": "Score : 100 points\n\nProblem Statement\n\nIt is September 9 in Japan now.\n\nYou are given a two-digit integer N. Answer the question: Is 9 contained in the decimal notation of N?\n\nConstraints\n\n10≤N≤99\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nIf 9 is contained in the decimal notation of N, print Yes; if not, print No.\n\nSample Input 1\n\n29\n\nSample Output 1\n\nYes\n\nThe one's digit of 29 is 9.\n\nSample Input 2\n\n72\n\nSample Output 2\n\nNo\n\n72 does not contain 9.\n\nSample Input 3\n\n91\n\nSample Output 3\n\nYes", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 218, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s627261816", "group_id": "codeNet:p03608", "input_text": "#include <cmath>\n#include <cstdio>\n#include <vector>\n#include <iostream>\n#include <algorithm>\n#include <queue>\n#include <string>\n#include <set>\n#include <map>\n#define REP(i,n) for(ll i = 0; i < (ll)n; i++)\n#define INF 1000000000000000\nusing namespace std;\ntypedef long long ll;\ntypedef double db;\ntypedef string str;\n\nstruct graph{\n  ll V;\n  vector<vector<ll> > d;\n  graph(ll n){\n    init(n);\n  }\n  void init(ll n){\n    V = n;\n    d.resize(V);\n    REP(i,V){\n      d[i].resize(V);\n    }\n    REP(i,V)REP(j,V) d[i][j] = (i==j)?0:INF;\n  }\n  void add_edge(ll from, ll to, ll cost){\n    d[from][to]=cost;\n  }\n  void warshall_floyd(){\n    REP(k,V)REP(i,V)REP(j,V){\n      d[i][j] = min(d[i][j],d[i][k]+d[k][j]);\n    }\n  }\n};\n\nint main(){\n  ll N,M,R;\n  cin >> N >> M >> R;\n  ll r[R];\n  REP(i,R){\n    cin >> r[i];\n    r[i]--;\n  }\n  graph g(N);\n  REP(i,M){\n    ll a,b,c;\n    cin >> a >> b >> c;\n    g.add_edge(a-1,b-1,c);\n    g.add_edge(b-1,a-1,c);\n  }\n  g.warshall_floyd();\n  ll perm[R];\n  REP(i,R){\n    perm[i] = i;\n  }\n  ll ans = INF;\n  do{\n    ll dist = 0;\n    REP(i,R-1) dist += g.d[r[perm[i]]][r[perm[i+1]]];\n    ans = min(ans,dist);\n  }while(next_permutation(perm,perm+R));\n  cout << ans << endl;\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1534350897, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03608.html", "problem_id": "p03608", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03608/input.txt", "sample_output_relpath": "derived/input_output/data/p03608/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03608/C++/s627261816.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s627261816", "user_id": "u780950519"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <cmath>\n#include <cstdio>\n#include <vector>\n#include <iostream>\n#include <algorithm>\n#include <queue>\n#include <string>\n#include <set>\n#include <map>\n#define REP(i,n) for(ll i = 0; i < (ll)n; i++)\n#define INF 1000000000000000\nusing namespace std;\ntypedef long long ll;\ntypedef double db;\ntypedef string str;\n\nstruct graph{\n  ll V;\n  vector<vector<ll> > d;\n  graph(ll n){\n    init(n);\n  }\n  void init(ll n){\n    V = n;\n    d.resize(V);\n    REP(i,V){\n      d[i].resize(V);\n    }\n    REP(i,V)REP(j,V) d[i][j] = (i==j)?0:INF;\n  }\n  void add_edge(ll from, ll to, ll cost){\n    d[from][to]=cost;\n  }\n  void warshall_floyd(){\n    REP(k,V)REP(i,V)REP(j,V){\n      d[i][j] = min(d[i][j],d[i][k]+d[k][j]);\n    }\n  }\n};\n\nint main(){\n  ll N,M,R;\n  cin >> N >> M >> R;\n  ll r[R];\n  REP(i,R){\n    cin >> r[i];\n    r[i]--;\n  }\n  graph g(N);\n  REP(i,M){\n    ll a,b,c;\n    cin >> a >> b >> c;\n    g.add_edge(a-1,b-1,c);\n    g.add_edge(b-1,a-1,c);\n  }\n  g.warshall_floyd();\n  ll perm[R];\n  REP(i,R){\n    perm[i] = i;\n  }\n  ll ans = INF;\n  do{\n    ll dist = 0;\n    REP(i,R-1) dist += g.d[r[perm[i]]][r[perm[i+1]]];\n    ans = min(ans,dist);\n  }while(next_permutation(perm,perm+R));\n  cout << ans << endl;\n  return 0;\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nThere are N towns in the State of Atcoder, connected by M bidirectional roads.\n\nThe i-th road connects Town A_i and B_i and has a length of C_i.\n\nJoisino is visiting R towns in the state, r_1,r_2,..,r_R (not necessarily in this order).\n\nShe will fly to the first town she visits, and fly back from the last town she visits, but for the rest of the trip she will have to travel by road.\n\nIf she visits the towns in the order that minimizes the distance traveled by road, what will that distance be?\n\nConstraints\n\n2≤N≤200\n\n1≤M≤N×(N-1)/2\n\n2≤R≤min(8,N) (min(8,N) is the smaller of 8 and N.)\n\nr_i≠r_j (i≠j)\n\n1≤A_i,B_i≤N, A_i≠B_i\n\n(A_i,B_i)≠(A_j,B_j),(A_i,B_i)≠(B_j,A_j) (i≠j)\n\n1≤C_i≤100000\n\nEvery town can be reached from every town by road.\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M R\nr_1 ... r_R\nA_1 B_1 C_1\n:\nA_M B_M C_M\n\nOutput\n\nPrint the distance traveled by road if Joisino visits the towns in the order that minimizes it.\n\nSample Input 1\n\n3 3 3\n1 2 3\n1 2 1\n2 3 1\n3 1 4\n\nSample Output 1\n\n2\n\nFor example, if she visits the towns in the order of 1, 2, 3, the distance traveled will be 2, which is the minimum possible.\n\nSample Input 2\n\n3 3 2\n1 3\n2 3 2\n1 3 6\n1 2 2\n\nSample Output 2\n\n4\n\nThe shortest distance between Towns 1 and 3 is 4. Thus, whether she visits Town 1 or 3 first, the distance traveled will be 4.\n\nSample Input 3\n\n4 6 3\n2 3 4\n1 2 4\n2 3 3\n4 3 1\n1 4 1\n4 2 2\n3 1 6\n\nSample Output 3\n\n3", "sample_input": "3 3 3\n1 2 3\n1 2 1\n2 3 1\n3 1 4\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03608", "source_text": "Score : 400 points\n\nProblem Statement\n\nThere are N towns in the State of Atcoder, connected by M bidirectional roads.\n\nThe i-th road connects Town A_i and B_i and has a length of C_i.\n\nJoisino is visiting R towns in the state, r_1,r_2,..,r_R (not necessarily in this order).\n\nShe will fly to the first town she visits, and fly back from the last town she visits, but for the rest of the trip she will have to travel by road.\n\nIf she visits the towns in the order that minimizes the distance traveled by road, what will that distance be?\n\nConstraints\n\n2≤N≤200\n\n1≤M≤N×(N-1)/2\n\n2≤R≤min(8,N) (min(8,N) is the smaller of 8 and N.)\n\nr_i≠r_j (i≠j)\n\n1≤A_i,B_i≤N, A_i≠B_i\n\n(A_i,B_i)≠(A_j,B_j),(A_i,B_i)≠(B_j,A_j) (i≠j)\n\n1≤C_i≤100000\n\nEvery town can be reached from every town by road.\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M R\nr_1 ... r_R\nA_1 B_1 C_1\n:\nA_M B_M C_M\n\nOutput\n\nPrint the distance traveled by road if Joisino visits the towns in the order that minimizes it.\n\nSample Input 1\n\n3 3 3\n1 2 3\n1 2 1\n2 3 1\n3 1 4\n\nSample Output 1\n\n2\n\nFor example, if she visits the towns in the order of 1, 2, 3, the distance traveled will be 2, which is the minimum possible.\n\nSample Input 2\n\n3 3 2\n1 3\n2 3 2\n1 3 6\n1 2 2\n\nSample Output 2\n\n4\n\nThe shortest distance between Towns 1 and 3 is 4. Thus, whether she visits Town 1 or 3 first, the distance traveled will be 4.\n\nSample Input 3\n\n4 6 3\n2 3 4\n1 2 4\n2 3 3\n4 3 1\n1 4 1\n4 2 2\n3 1 6\n\nSample Output 3\n\n3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1207, "cpu_time_ms": 25, "memory_kb": 512}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s761832163", "group_id": "codeNet:p03608", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n#define ll long long int\n#define rep(i,n) for( int i = 0; i < n; i++ )\n#define dump(x)  cerr << #x << \" = \" << (x) << endl;\n#define INF 2000000000\n#define mod 1000000007\n#define INF2 1000000000000000000\n\n\nint main(void)\n{\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n  int N, M, R;\n    cin >> N >> M >> R;\n    int r[R];\n \n    int A[M], B[M] ,C[N][N] = {};\n    for(int i = 0; i < N; i++)\n        for(int j = 0; j < N; j++)\n            if ( i != j) C[i][j] = 1000000;\n    for(int i = 0; i < R; i++) {\n        cin >> r[i];\n        r[i]--; // ここをdecrementするのを忘れていた。\n    }\n    for(int i = 0; i < M; i++) {\n        cin >> A[i] >> B[i];\n        A[i]--; B[i]--;\n        cin >> C[A[i]][B[i]];\n        C[B[i]][A[i]] = C[A[i]][B[i]];\n    }\n \n    int ans = 1000000000;\n \n    for(int k = 0; k < N; k++){\n        for(int i = 0; i < N; i++){\n            for(int j = 0; j < N; j++){\n                if(C[i][k] + C[k][j] < C[i][j] && C[i][k] && C[k][j] && C[i][j])\n                    C[i][j] = C[i][k] + C[k][j];\n            }\n        }\n    }\n    sort(r, r+R);\n    do{\n        int _ans = 0;\n        for(int i = 0; i < R - 1; i++)  \n            _ans += C[r[i]][r[i + 1]];\n\n        if(_ans < ans && _ans) \n            ans = _ans;\n    }while(next_permutation(r, r+R));\n \n    cout << ans << endl;\n \n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1513223788, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03608.html", "problem_id": "p03608", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03608/input.txt", "sample_output_relpath": "derived/input_output/data/p03608/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03608/C++/s761832163.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s761832163", "user_id": "u965730380"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n#define ll long long int\n#define rep(i,n) for( int i = 0; i < n; i++ )\n#define dump(x)  cerr << #x << \" = \" << (x) << endl;\n#define INF 2000000000\n#define mod 1000000007\n#define INF2 1000000000000000000\n\n\nint main(void)\n{\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n  int N, M, R;\n    cin >> N >> M >> R;\n    int r[R];\n \n    int A[M], B[M] ,C[N][N] = {};\n    for(int i = 0; i < N; i++)\n        for(int j = 0; j < N; j++)\n            if ( i != j) C[i][j] = 1000000;\n    for(int i = 0; i < R; i++) {\n        cin >> r[i];\n        r[i]--; // ここをdecrementするのを忘れていた。\n    }\n    for(int i = 0; i < M; i++) {\n        cin >> A[i] >> B[i];\n        A[i]--; B[i]--;\n        cin >> C[A[i]][B[i]];\n        C[B[i]][A[i]] = C[A[i]][B[i]];\n    }\n \n    int ans = 1000000000;\n \n    for(int k = 0; k < N; k++){\n        for(int i = 0; i < N; i++){\n            for(int j = 0; j < N; j++){\n                if(C[i][k] + C[k][j] < C[i][j] && C[i][k] && C[k][j] && C[i][j])\n                    C[i][j] = C[i][k] + C[k][j];\n            }\n        }\n    }\n    sort(r, r+R);\n    do{\n        int _ans = 0;\n        for(int i = 0; i < R - 1; i++)  \n            _ans += C[r[i]][r[i + 1]];\n\n        if(_ans < ans && _ans) \n            ans = _ans;\n    }while(next_permutation(r, r+R));\n \n    cout << ans << endl;\n \n    return 0;\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nThere are N towns in the State of Atcoder, connected by M bidirectional roads.\n\nThe i-th road connects Town A_i and B_i and has a length of C_i.\n\nJoisino is visiting R towns in the state, r_1,r_2,..,r_R (not necessarily in this order).\n\nShe will fly to the first town she visits, and fly back from the last town she visits, but for the rest of the trip she will have to travel by road.\n\nIf she visits the towns in the order that minimizes the distance traveled by road, what will that distance be?\n\nConstraints\n\n2≤N≤200\n\n1≤M≤N×(N-1)/2\n\n2≤R≤min(8,N) (min(8,N) is the smaller of 8 and N.)\n\nr_i≠r_j (i≠j)\n\n1≤A_i,B_i≤N, A_i≠B_i\n\n(A_i,B_i)≠(A_j,B_j),(A_i,B_i)≠(B_j,A_j) (i≠j)\n\n1≤C_i≤100000\n\nEvery town can be reached from every town by road.\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M R\nr_1 ... r_R\nA_1 B_1 C_1\n:\nA_M B_M C_M\n\nOutput\n\nPrint the distance traveled by road if Joisino visits the towns in the order that minimizes it.\n\nSample Input 1\n\n3 3 3\n1 2 3\n1 2 1\n2 3 1\n3 1 4\n\nSample Output 1\n\n2\n\nFor example, if she visits the towns in the order of 1, 2, 3, the distance traveled will be 2, which is the minimum possible.\n\nSample Input 2\n\n3 3 2\n1 3\n2 3 2\n1 3 6\n1 2 2\n\nSample Output 2\n\n4\n\nThe shortest distance between Towns 1 and 3 is 4. Thus, whether she visits Town 1 or 3 first, the distance traveled will be 4.\n\nSample Input 3\n\n4 6 3\n2 3 4\n1 2 4\n2 3 3\n4 3 1\n1 4 1\n4 2 2\n3 1 6\n\nSample Output 3\n\n3", "sample_input": "3 3 3\n1 2 3\n1 2 1\n2 3 1\n3 1 4\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03608", "source_text": "Score : 400 points\n\nProblem Statement\n\nThere are N towns in the State of Atcoder, connected by M bidirectional roads.\n\nThe i-th road connects Town A_i and B_i and has a length of C_i.\n\nJoisino is visiting R towns in the state, r_1,r_2,..,r_R (not necessarily in this order).\n\nShe will fly to the first town she visits, and fly back from the last town she visits, but for the rest of the trip she will have to travel by road.\n\nIf she visits the towns in the order that minimizes the distance traveled by road, what will that distance be?\n\nConstraints\n\n2≤N≤200\n\n1≤M≤N×(N-1)/2\n\n2≤R≤min(8,N) (min(8,N) is the smaller of 8 and N.)\n\nr_i≠r_j (i≠j)\n\n1≤A_i,B_i≤N, A_i≠B_i\n\n(A_i,B_i)≠(A_j,B_j),(A_i,B_i)≠(B_j,A_j) (i≠j)\n\n1≤C_i≤100000\n\nEvery town can be reached from every town by road.\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M R\nr_1 ... r_R\nA_1 B_1 C_1\n:\nA_M B_M C_M\n\nOutput\n\nPrint the distance traveled by road if Joisino visits the towns in the order that minimizes it.\n\nSample Input 1\n\n3 3 3\n1 2 3\n1 2 1\n2 3 1\n3 1 4\n\nSample Output 1\n\n2\n\nFor example, if she visits the towns in the order of 1, 2, 3, the distance traveled will be 2, which is the minimum possible.\n\nSample Input 2\n\n3 3 2\n1 3\n2 3 2\n1 3 6\n1 2 2\n\nSample Output 2\n\n4\n\nThe shortest distance between Towns 1 and 3 is 4. Thus, whether she visits Town 1 or 3 first, the distance traveled will be 4.\n\nSample Input 3\n\n4 6 3\n2 3 4\n1 2 4\n2 3 3\n4 3 1\n1 4 1\n4 2 2\n3 1 6\n\nSample Output 3\n\n3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1371, "cpu_time_ms": 24, "memory_kb": 640}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s143242879", "group_id": "codeNet:p03609", "input_text": "#include <iostream>\nusing namespace std;\n\nint main() {\n  int x, t;\n  \n  cin >> x >> t;\n  if (x - t > 0)\n    cout << x - t << endl;\n  else\n    cout << 0 << endl;\n}\n", "language": "C++", "metadata": {"date": 1524353574, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03609.html", "problem_id": "p03609", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03609/input.txt", "sample_output_relpath": "derived/input_output/data/p03609/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03609/C++/s143242879.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s143242879", "user_id": "u537459297"}, "prompt_components": {"gold_output": "83\n", "input_to_evaluate": "#include <iostream>\nusing namespace std;\n\nint main() {\n  int x, t;\n  \n  cin >> x >> t;\n  if (x - t > 0)\n    cout << x - t << endl;\n  else\n    cout << 0 << endl;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nWe have a sandglass that runs for X seconds. The sand drops from the upper bulb at a rate of 1 gram per second. That is, the upper bulb initially contains X grams of sand.\n\nHow many grams of sand will the upper bulb contains after t seconds?\n\nConstraints\n\n1≤X≤10^9\n\n1≤t≤10^9\n\nX and t are integers.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nX t\n\nOutput\n\nPrint the number of sand in the upper bulb after t second.\n\nSample Input 1\n\n100 17\n\nSample Output 1\n\n83\n\n17 out of the initial 100 grams of sand will be consumed, resulting in 83 grams.\n\nSample Input 2\n\n48 58\n\nSample Output 2\n\n0\n\nAll 48 grams of sand will be gone, resulting in 0 grams.\n\nSample Input 3\n\n1000000000 1000000000\n\nSample Output 3\n\n0", "sample_input": "100 17\n"}, "reference_outputs": ["83\n"], "source_document_id": "p03609", "source_text": "Score : 100 points\n\nProblem Statement\n\nWe have a sandglass that runs for X seconds. The sand drops from the upper bulb at a rate of 1 gram per second. That is, the upper bulb initially contains X grams of sand.\n\nHow many grams of sand will the upper bulb contains after t seconds?\n\nConstraints\n\n1≤X≤10^9\n\n1≤t≤10^9\n\nX and t are integers.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nX t\n\nOutput\n\nPrint the number of sand in the upper bulb after t second.\n\nSample Input 1\n\n100 17\n\nSample Output 1\n\n83\n\n17 out of the initial 100 grams of sand will be consumed, resulting in 83 grams.\n\nSample Input 2\n\n48 58\n\nSample Output 2\n\n0\n\nAll 48 grams of sand will be gone, resulting in 0 grams.\n\nSample Input 3\n\n1000000000 1000000000\n\nSample Output 3\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 163, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s625828577", "group_id": "codeNet:p03617", "input_text": "#include <iostream>\n#include <algorithm>\n#include <cmath>\n#define int long long\nusing namespace std;\n\nsigned main() {\n  int Q, H, S, D, N; cin >> Q >> H >> S >> D >> N;\n  int ans = (N/2) * min({8*Q, 4*H, 2*S, D}) + (N%2) * min({4*Q, 2*H, S});\n  std::cout << ans << std::endl;\n\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1562525037, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03617.html", "problem_id": "p03617", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03617/input.txt", "sample_output_relpath": "derived/input_output/data/p03617/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03617/C++/s625828577.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s625828577", "user_id": "u013803727"}, "prompt_components": {"gold_output": "150\n", "input_to_evaluate": "#include <iostream>\n#include <algorithm>\n#include <cmath>\n#define int long long\nusing namespace std;\n\nsigned main() {\n  int Q, H, S, D, N; cin >> Q >> H >> S >> D >> N;\n  int ans = (N/2) * min({8*Q, 4*H, 2*S, D}) + (N%2) * min({4*Q, 2*H, S});\n  std::cout << ans << std::endl;\n\n  return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nYou've come to your favorite store Infinitesco to buy some ice tea.\n\nThe store sells ice tea in bottles of different volumes at different costs.\nSpecifically, a 0.25-liter bottle costs Q yen, a 0.5-liter bottle costs H yen, a 1-liter bottle costs S yen, and a 2-liter bottle costs D yen.\nThe store has an infinite supply of bottles of each type.\n\nYou want to buy exactly N liters of ice tea. How many yen do you have to spend?\n\nConstraints\n\n1 \\leq Q, H, S, D \\leq 10^8\n\n1 \\leq N \\leq 10^9\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nQ H S D\nN\n\nOutput\n\nPrint the smallest number of yen you have to spend to buy exactly N liters of ice tea.\n\nSample Input 1\n\n20 30 70 90\n3\n\nSample Output 1\n\n150\n\nBuy one 2-liter bottle and two 0.5-liter bottles. You'll get 3 liters for 90 + 30 + 30 = 150 yen.\n\nSample Input 2\n\n10000 1000 100 10\n1\n\nSample Output 2\n\n100\n\nEven though a 2-liter bottle costs just 10 yen, you need only 1 liter.\nThus, you have to buy a 1-liter bottle for 100 yen.\n\nSample Input 3\n\n10 100 1000 10000\n1\n\nSample Output 3\n\n40\n\nNow it's better to buy four 0.25-liter bottles for 10 + 10 + 10 + 10 = 40 yen.\n\nSample Input 4\n\n12345678 87654321 12345678 87654321\n123456789\n\nSample Output 4\n\n1524157763907942", "sample_input": "20 30 70 90\n3\n"}, "reference_outputs": ["150\n"], "source_document_id": "p03617", "source_text": "Score : 300 points\n\nProblem Statement\n\nYou've come to your favorite store Infinitesco to buy some ice tea.\n\nThe store sells ice tea in bottles of different volumes at different costs.\nSpecifically, a 0.25-liter bottle costs Q yen, a 0.5-liter bottle costs H yen, a 1-liter bottle costs S yen, and a 2-liter bottle costs D yen.\nThe store has an infinite supply of bottles of each type.\n\nYou want to buy exactly N liters of ice tea. How many yen do you have to spend?\n\nConstraints\n\n1 \\leq Q, H, S, D \\leq 10^8\n\n1 \\leq N \\leq 10^9\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nQ H S D\nN\n\nOutput\n\nPrint the smallest number of yen you have to spend to buy exactly N liters of ice tea.\n\nSample Input 1\n\n20 30 70 90\n3\n\nSample Output 1\n\n150\n\nBuy one 2-liter bottle and two 0.5-liter bottles. You'll get 3 liters for 90 + 30 + 30 = 150 yen.\n\nSample Input 2\n\n10000 1000 100 10\n1\n\nSample Output 2\n\n100\n\nEven though a 2-liter bottle costs just 10 yen, you need only 1 liter.\nThus, you have to buy a 1-liter bottle for 100 yen.\n\nSample Input 3\n\n10 100 1000 10000\n1\n\nSample Output 3\n\n40\n\nNow it's better to buy four 0.25-liter bottles for 10 + 10 + 10 + 10 = 40 yen.\n\nSample Input 4\n\n12345678 87654321 12345678 87654321\n123456789\n\nSample Output 4\n\n1524157763907942", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 291, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s180806796", "group_id": "codeNet:p03617", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef vector<pair<unsigned long long int,unsigned long long int> > pi;\nint main()\n{ ios_base::sync_with_stdio(false);\n    cin.tie(NULL);\n     unsigned long long int n,x;pi a;int i;\n     for(i=0;i<4;i++)\n     { cin>>x;\n      a.push_back(make_pair(x,i));\n     }\n     cin>>n;\n     a[0].first*=4;\n     a[1].first*=2;\n     a[3].first/=2;\n     sort(a.begin(),a.end());\n     if(a[0].second==3)\n     cout<<(n/2)*((a[0].first)*2)+(n&1)*a[1].first;\n     else\n     cout<<n*(a[0].first);\n      \n  \n\treturn 0;\n\t\n}", "language": "C++", "metadata": {"date": 1504398244, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03617.html", "problem_id": "p03617", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03617/input.txt", "sample_output_relpath": "derived/input_output/data/p03617/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03617/C++/s180806796.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s180806796", "user_id": "u314435836"}, "prompt_components": {"gold_output": "150\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef vector<pair<unsigned long long int,unsigned long long int> > pi;\nint main()\n{ ios_base::sync_with_stdio(false);\n    cin.tie(NULL);\n     unsigned long long int n,x;pi a;int i;\n     for(i=0;i<4;i++)\n     { cin>>x;\n      a.push_back(make_pair(x,i));\n     }\n     cin>>n;\n     a[0].first*=4;\n     a[1].first*=2;\n     a[3].first/=2;\n     sort(a.begin(),a.end());\n     if(a[0].second==3)\n     cout<<(n/2)*((a[0].first)*2)+(n&1)*a[1].first;\n     else\n     cout<<n*(a[0].first);\n      \n  \n\treturn 0;\n\t\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nYou've come to your favorite store Infinitesco to buy some ice tea.\n\nThe store sells ice tea in bottles of different volumes at different costs.\nSpecifically, a 0.25-liter bottle costs Q yen, a 0.5-liter bottle costs H yen, a 1-liter bottle costs S yen, and a 2-liter bottle costs D yen.\nThe store has an infinite supply of bottles of each type.\n\nYou want to buy exactly N liters of ice tea. How many yen do you have to spend?\n\nConstraints\n\n1 \\leq Q, H, S, D \\leq 10^8\n\n1 \\leq N \\leq 10^9\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nQ H S D\nN\n\nOutput\n\nPrint the smallest number of yen you have to spend to buy exactly N liters of ice tea.\n\nSample Input 1\n\n20 30 70 90\n3\n\nSample Output 1\n\n150\n\nBuy one 2-liter bottle and two 0.5-liter bottles. You'll get 3 liters for 90 + 30 + 30 = 150 yen.\n\nSample Input 2\n\n10000 1000 100 10\n1\n\nSample Output 2\n\n100\n\nEven though a 2-liter bottle costs just 10 yen, you need only 1 liter.\nThus, you have to buy a 1-liter bottle for 100 yen.\n\nSample Input 3\n\n10 100 1000 10000\n1\n\nSample Output 3\n\n40\n\nNow it's better to buy four 0.25-liter bottles for 10 + 10 + 10 + 10 = 40 yen.\n\nSample Input 4\n\n12345678 87654321 12345678 87654321\n123456789\n\nSample Output 4\n\n1524157763907942", "sample_input": "20 30 70 90\n3\n"}, "reference_outputs": ["150\n"], "source_document_id": "p03617", "source_text": "Score : 300 points\n\nProblem Statement\n\nYou've come to your favorite store Infinitesco to buy some ice tea.\n\nThe store sells ice tea in bottles of different volumes at different costs.\nSpecifically, a 0.25-liter bottle costs Q yen, a 0.5-liter bottle costs H yen, a 1-liter bottle costs S yen, and a 2-liter bottle costs D yen.\nThe store has an infinite supply of bottles of each type.\n\nYou want to buy exactly N liters of ice tea. How many yen do you have to spend?\n\nConstraints\n\n1 \\leq Q, H, S, D \\leq 10^8\n\n1 \\leq N \\leq 10^9\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nQ H S D\nN\n\nOutput\n\nPrint the smallest number of yen you have to spend to buy exactly N liters of ice tea.\n\nSample Input 1\n\n20 30 70 90\n3\n\nSample Output 1\n\n150\n\nBuy one 2-liter bottle and two 0.5-liter bottles. You'll get 3 liters for 90 + 30 + 30 = 150 yen.\n\nSample Input 2\n\n10000 1000 100 10\n1\n\nSample Output 2\n\n100\n\nEven though a 2-liter bottle costs just 10 yen, you need only 1 liter.\nThus, you have to buy a 1-liter bottle for 100 yen.\n\nSample Input 3\n\n10 100 1000 10000\n1\n\nSample Output 3\n\n40\n\nNow it's better to buy four 0.25-liter bottles for 10 + 10 + 10 + 10 = 40 yen.\n\nSample Input 4\n\n12345678 87654321 12345678 87654321\n123456789\n\nSample Output 4\n\n1524157763907942", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 548, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s765985680", "group_id": "codeNet:p03617", "input_text": "#include<iostream>\n#include<string>\n#include<queue>\n#include<vector>\nusing namespace std;\nconst long long INF=20000000000000000LL;\ntypedef pair<long long,int> Pa;\nint main(){\n\tlong long Q,H,S,D,N,q,h,s,d=INF,ans;\n\tcin>>Q>>H>>S>>D>>N;\n\tq=Q*N*4;\n\th=H*N*2;\n\ts=S*N;\n\t\n\td=min(d,D*(N/2)+Q*4*(N%2));\n\td=min(d,D*(N/2)+H*2*(N%2));\n\td=min(d,D*(N/2)+S*(N%2));\n\tcout<<min(min(q,h),min(s,d))<<endl;\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1503796755, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03617.html", "problem_id": "p03617", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03617/input.txt", "sample_output_relpath": "derived/input_output/data/p03617/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03617/C++/s765985680.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s765985680", "user_id": "u770256251"}, "prompt_components": {"gold_output": "150\n", "input_to_evaluate": "#include<iostream>\n#include<string>\n#include<queue>\n#include<vector>\nusing namespace std;\nconst long long INF=20000000000000000LL;\ntypedef pair<long long,int> Pa;\nint main(){\n\tlong long Q,H,S,D,N,q,h,s,d=INF,ans;\n\tcin>>Q>>H>>S>>D>>N;\n\tq=Q*N*4;\n\th=H*N*2;\n\ts=S*N;\n\t\n\td=min(d,D*(N/2)+Q*4*(N%2));\n\td=min(d,D*(N/2)+H*2*(N%2));\n\td=min(d,D*(N/2)+S*(N%2));\n\tcout<<min(min(q,h),min(s,d))<<endl;\n\treturn 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nYou've come to your favorite store Infinitesco to buy some ice tea.\n\nThe store sells ice tea in bottles of different volumes at different costs.\nSpecifically, a 0.25-liter bottle costs Q yen, a 0.5-liter bottle costs H yen, a 1-liter bottle costs S yen, and a 2-liter bottle costs D yen.\nThe store has an infinite supply of bottles of each type.\n\nYou want to buy exactly N liters of ice tea. How many yen do you have to spend?\n\nConstraints\n\n1 \\leq Q, H, S, D \\leq 10^8\n\n1 \\leq N \\leq 10^9\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nQ H S D\nN\n\nOutput\n\nPrint the smallest number of yen you have to spend to buy exactly N liters of ice tea.\n\nSample Input 1\n\n20 30 70 90\n3\n\nSample Output 1\n\n150\n\nBuy one 2-liter bottle and two 0.5-liter bottles. You'll get 3 liters for 90 + 30 + 30 = 150 yen.\n\nSample Input 2\n\n10000 1000 100 10\n1\n\nSample Output 2\n\n100\n\nEven though a 2-liter bottle costs just 10 yen, you need only 1 liter.\nThus, you have to buy a 1-liter bottle for 100 yen.\n\nSample Input 3\n\n10 100 1000 10000\n1\n\nSample Output 3\n\n40\n\nNow it's better to buy four 0.25-liter bottles for 10 + 10 + 10 + 10 = 40 yen.\n\nSample Input 4\n\n12345678 87654321 12345678 87654321\n123456789\n\nSample Output 4\n\n1524157763907942", "sample_input": "20 30 70 90\n3\n"}, "reference_outputs": ["150\n"], "source_document_id": "p03617", "source_text": "Score : 300 points\n\nProblem Statement\n\nYou've come to your favorite store Infinitesco to buy some ice tea.\n\nThe store sells ice tea in bottles of different volumes at different costs.\nSpecifically, a 0.25-liter bottle costs Q yen, a 0.5-liter bottle costs H yen, a 1-liter bottle costs S yen, and a 2-liter bottle costs D yen.\nThe store has an infinite supply of bottles of each type.\n\nYou want to buy exactly N liters of ice tea. How many yen do you have to spend?\n\nConstraints\n\n1 \\leq Q, H, S, D \\leq 10^8\n\n1 \\leq N \\leq 10^9\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nQ H S D\nN\n\nOutput\n\nPrint the smallest number of yen you have to spend to buy exactly N liters of ice tea.\n\nSample Input 1\n\n20 30 70 90\n3\n\nSample Output 1\n\n150\n\nBuy one 2-liter bottle and two 0.5-liter bottles. You'll get 3 liters for 90 + 30 + 30 = 150 yen.\n\nSample Input 2\n\n10000 1000 100 10\n1\n\nSample Output 2\n\n100\n\nEven though a 2-liter bottle costs just 10 yen, you need only 1 liter.\nThus, you have to buy a 1-liter bottle for 100 yen.\n\nSample Input 3\n\n10 100 1000 10000\n1\n\nSample Output 3\n\n40\n\nNow it's better to buy four 0.25-liter bottles for 10 + 10 + 10 + 10 = 40 yen.\n\nSample Input 4\n\n12345678 87654321 12345678 87654321\n123456789\n\nSample Output 4\n\n1524157763907942", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 399, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s897279785", "group_id": "codeNet:p03618", "input_text": "#include <bits/stdc++.h>\n#define ll long long int\n#define ff first\n#define pb push_back\n#define ss second\n#define ff first\n#define mp make_pair\n\nusing namespace std;\n\nconst ll MOD = 1000000007LL;\n\nll fact[1000006];\nll ifact[1000006];\nll power2[1000006];\n\nll ar[1000056];\n\n\nll powr (ll a, ll  b)\n{\n    if (b == 0)\n        return 1;\n    long long int x = powr(a, b/2);\n    if (b % 2 == 0)\n        return (x*x)%MOD;\n    else\n        return (((x*x)%MOD)*a)%MOD;\n}\n \ninline ll inv(ll x) {\n  return powr(x, MOD - 2);\n}\n \ninline ll mulMod(ll a, ll b) {\n  return (a%MOD * b%MOD) % MOD;\n\n}\n \ninline void process() {\n  fact[0] = 1;\n  power2[0] = 1;\n  for(int i = 1; i < 1003; i++) {\n    fact[i] = mulMod(fact[i - 1], i);\n    power2[i] = mulMod(power2[i - 1], 2);\n  }\n  ifact[1002] = inv(fact[1002]);\n  for(int i = 1002 - 1; i >= 0; i--) {\n    ifact[i] = mulMod(ifact[i + 1], i + 1);\n  }\n}\n\ninline ll ncr(ll n, ll r) {\n  if(n < r) return 0;\n  return mulMod(fact[n], mulMod(ifact[r], ifact[(n - r)]));\n}\n\nll solve(ll n, ll k)\n{\n    ll C[k+1];\n    memset(C, 0, sizeof(C));\n \n    C[0] = 1; \n \n    for (ll i = 1; i <= n; i++)\n    {\n        for (ll j = min(i, k); j > 0; j--)\n            C[j] = C[j] + C[j-1];\n    }\n    return C[k];\n}\n\nvoid solve1(vector<ll> price, ll n, ll S[])\n{\n   \n   stack<ll> st;\n   st.push(0);\n \n   S[0] = 1;\n \n   for (ll i = 1; i < n; i++)\n   {\n\n      while (!st.empty() && price[st.top()] <= price[i])\n         st.pop();\n \n\n      S[i] = (st.empty())? (i + 1) : (i - st.top());\n \n      st.push(i);\n   }\n}\n\n\nmap<ll,ll> mark,has;\nmap<string,bool> hav;\n\nset<ll> st;\n\n\nint main() \n{\n    ll n,m,t,p,q,r,s,a,b,c,d,e,f,g,h,sum,res,flag,u,v,i,j,l,k,z,x,y,len,ans=0;\n    \n    string str,ptr,dtr;\n    \n    cin>>str;\n    ptr=str;\n    \n    len=str.length();\n    \n    for(i=0;i<len;i++)\n    {\n    \tfor(j=i+1;j<len;j++)\n    \t{\n    \t\treverse(ptr.begin()+i,ptr.begin()+j+1);\n    \t\thav[ptr]=1;\n    \t\tptr=str;\n\t\t}\n\t}\n\t\n\tcout<<hav.size();\n    \n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1503800132, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03618.html", "problem_id": "p03618", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03618/input.txt", "sample_output_relpath": "derived/input_output/data/p03618/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03618/C++/s897279785.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s897279785", "user_id": "u797697667"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define ll long long int\n#define ff first\n#define pb push_back\n#define ss second\n#define ff first\n#define mp make_pair\n\nusing namespace std;\n\nconst ll MOD = 1000000007LL;\n\nll fact[1000006];\nll ifact[1000006];\nll power2[1000006];\n\nll ar[1000056];\n\n\nll powr (ll a, ll  b)\n{\n    if (b == 0)\n        return 1;\n    long long int x = powr(a, b/2);\n    if (b % 2 == 0)\n        return (x*x)%MOD;\n    else\n        return (((x*x)%MOD)*a)%MOD;\n}\n \ninline ll inv(ll x) {\n  return powr(x, MOD - 2);\n}\n \ninline ll mulMod(ll a, ll b) {\n  return (a%MOD * b%MOD) % MOD;\n\n}\n \ninline void process() {\n  fact[0] = 1;\n  power2[0] = 1;\n  for(int i = 1; i < 1003; i++) {\n    fact[i] = mulMod(fact[i - 1], i);\n    power2[i] = mulMod(power2[i - 1], 2);\n  }\n  ifact[1002] = inv(fact[1002]);\n  for(int i = 1002 - 1; i >= 0; i--) {\n    ifact[i] = mulMod(ifact[i + 1], i + 1);\n  }\n}\n\ninline ll ncr(ll n, ll r) {\n  if(n < r) return 0;\n  return mulMod(fact[n], mulMod(ifact[r], ifact[(n - r)]));\n}\n\nll solve(ll n, ll k)\n{\n    ll C[k+1];\n    memset(C, 0, sizeof(C));\n \n    C[0] = 1; \n \n    for (ll i = 1; i <= n; i++)\n    {\n        for (ll j = min(i, k); j > 0; j--)\n            C[j] = C[j] + C[j-1];\n    }\n    return C[k];\n}\n\nvoid solve1(vector<ll> price, ll n, ll S[])\n{\n   \n   stack<ll> st;\n   st.push(0);\n \n   S[0] = 1;\n \n   for (ll i = 1; i < n; i++)\n   {\n\n      while (!st.empty() && price[st.top()] <= price[i])\n         st.pop();\n \n\n      S[i] = (st.empty())? (i + 1) : (i - st.top());\n \n      st.push(i);\n   }\n}\n\n\nmap<ll,ll> mark,has;\nmap<string,bool> hav;\n\nset<ll> st;\n\n\nint main() \n{\n    ll n,m,t,p,q,r,s,a,b,c,d,e,f,g,h,sum,res,flag,u,v,i,j,l,k,z,x,y,len,ans=0;\n    \n    string str,ptr,dtr;\n    \n    cin>>str;\n    ptr=str;\n    \n    len=str.length();\n    \n    for(i=0;i<len;i++)\n    {\n    \tfor(j=i+1;j<len;j++)\n    \t{\n    \t\treverse(ptr.begin()+i,ptr.begin()+j+1);\n    \t\thav[ptr]=1;\n    \t\tptr=str;\n\t\t}\n\t}\n\t\n\tcout<<hav.size();\n    \n    return 0;\n}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nYou have a string A = A_1 A_2 ... A_n consisting of lowercase English letters.\n\nYou can choose any two indices i and j such that 1 \\leq i \\leq j \\leq n and reverse substring A_i A_{i+1} ... A_j.\n\nYou can perform this operation at most once.\n\nHow many different strings can you obtain?\n\nConstraints\n\n1 \\leq |A| \\leq 200,000\n\nA consists of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA\n\nOutput\n\nPrint the number of different strings you can obtain by reversing any substring in A at most once.\n\nSample Input 1\n\naatt\n\nSample Output 1\n\n5\n\nYou can obtain aatt (don't do anything), atat (reverse A[2..3]), atta (reverse A[2..4]), ttaa (reverse A[1..4]) and taat (reverse A[1..3]).\n\nSample Input 2\n\nxxxxxxxxxx\n\nSample Output 2\n\n1\n\nWhatever substring you reverse, you'll always get xxxxxxxxxx.\n\nSample Input 3\n\nabracadabra\n\nSample Output 3\n\n44", "sample_input": "aatt\n"}, "reference_outputs": ["5\n"], "source_document_id": "p03618", "source_text": "Score : 500 points\n\nProblem Statement\n\nYou have a string A = A_1 A_2 ... A_n consisting of lowercase English letters.\n\nYou can choose any two indices i and j such that 1 \\leq i \\leq j \\leq n and reverse substring A_i A_{i+1} ... A_j.\n\nYou can perform this operation at most once.\n\nHow many different strings can you obtain?\n\nConstraints\n\n1 \\leq |A| \\leq 200,000\n\nA consists of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA\n\nOutput\n\nPrint the number of different strings you can obtain by reversing any substring in A at most once.\n\nSample Input 1\n\naatt\n\nSample Output 1\n\n5\n\nYou can obtain aatt (don't do anything), atat (reverse A[2..3]), atta (reverse A[2..4]), ttaa (reverse A[1..4]) and taat (reverse A[1..3]).\n\nSample Input 2\n\nxxxxxxxxxx\n\nSample Output 2\n\n1\n\nWhatever substring you reverse, you'll always get xxxxxxxxxx.\n\nSample Input 3\n\nabracadabra\n\nSample Output 3\n\n44", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1950, "cpu_time_ms": 3527, "memory_kb": 1722624}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s688967895", "group_id": "codeNet:p03621", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n\ntypedef long long lint;\ntypedef long double louble;\n\ntemplate<typename T1,typename T2> inline T1 max(T1 a,T2 b){return a<b?b:a;}\ntemplate<typename T1,typename T2> inline T1 min(T1 a,T2 b){return a<b?a:b;}\n\nconst char lf = '\\n';\n\nnamespace ae86\n{\n\tconst int bufl = 1 << 15;\n\n\tchar buf[bufl],*s=buf,*t=buf;\n\n\tinline int fetch()\n\t{\n\t\tif(s==t){t=(s=buf)+fread(buf,1,bufl,stdin);if(s==t)return EOF;}\n\t\treturn *s++;\n\t}\n\n\tinline int ty()\n\t{\n\t\tint a=0;int b=1,c=fetch();\n\t\twhile(!isdigit(c))b^=c=='-',c=fetch();\n\t\twhile(isdigit(c))a=a*10+c-48,c=fetch();\n\t\treturn b?a:-a;\n\t}\n\n\tinline int ts(char *s)\n\t{\n\t\tint a=0,c=fetch();\n\t\twhile(c<=32 && c!=EOF)c=fetch();\n\t\twhile(c>32 && c!=EOF)s[a++]=c,c=fetch();\n\t\ts[a]=0;\n\t\treturn a;\n\t}\n}\nusing ae86::ty;\nusing ae86::ts;\n\nconst int _ = 10007 , mo = 998244353;\n\ntemplate<typename T1,typename T2> inline T1 ad(T1 &a,T2 b){return a=a+b>=mo?a+b-mo:a+b;}\ntemplate<typename T1,typename T2> inline T1 dl(T1 &a,T2 b){return a=a>=b?a-b:a-b+mo;}\n\nlint powa(lint a,lint t)\n{\n\tlint b=1;a=(a+mo)%mo;\n\twhile(t){if(t&1)b=b*a%mo;a=a*a%mo,t>>=1;}\n\treturn b;\n}\n\ninline lint inva(lint a)\n{\n\treturn powa(a,mo-2);\n}\n\nlint jc[_],rjc[_];\n\nvoid fuck(int n=_-1)\n{\n\tjc[0]=jc[1]=rjc[0]=1;\n\tfor(int i=2;i<=n;i++)jc[i]=jc[i-1]*i%mo;\n\trjc[n]=inva(jc[n]);\n\tfor(int i=n-1;i>=1;i--)rjc[i]=rjc[i+1]*(1ll+i)%mo;\n}\n\nlint C(int n,int m)\n{\n\tif(n<m || n<0 || m<0)return 0;\n\treturn jc[n]*rjc[m]%mo*rjc[n-m]%mo;\n}\n\nint n;char sa[_],sb[_];\nint f[_][_]={0};\n\nint main()\n{\n\tios::sync_with_stdio(0),cout.tie(nullptr);\n\n\tfuck();\n\t\n\tn=ts(sa+1),ts(sb+1);\n\tint cnt1=0,cnt2=0;\n\tfor(int i=1;i<=n;i++)\n\t{\n\t\tif(sa[i]=='1' && sb[i]=='1')cnt1++;\n\t\tif(sa[i]=='1' && sb[i]=='0')cnt2++;\n\t}\n\n\tfor(int i=0;i<=cnt2;i++)f[0][i]=jc[i]*jc[i]%mo;\n\tfor(int i=1;i<=cnt1;i++)\n\t\tfor(int j=1;j<=cnt2;j++)\n\t\t\tf[i][j]=(1ll*f[i][j-1]*j%mo*j%mo+1ll*f[i-1][j]*i%mo*j%mo)%mo;\n\tlint ans=0;\n\tfor(int i=0;i<=cnt1;i++)\n\t\tad(ans,1ll*f[cnt1-i][cnt2]*jc[i]%mo*jc[i]%mo*C(cnt1,i)%mo*C(cnt1+cnt2,i)%mo);\n\tcout<<ans<<lf;\n\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1580512056, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03621.html", "problem_id": "p03621", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03621/input.txt", "sample_output_relpath": "derived/input_output/data/p03621/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03621/C++/s688967895.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s688967895", "user_id": "u816631826"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n\ntypedef long long lint;\ntypedef long double louble;\n\ntemplate<typename T1,typename T2> inline T1 max(T1 a,T2 b){return a<b?b:a;}\ntemplate<typename T1,typename T2> inline T1 min(T1 a,T2 b){return a<b?a:b;}\n\nconst char lf = '\\n';\n\nnamespace ae86\n{\n\tconst int bufl = 1 << 15;\n\n\tchar buf[bufl],*s=buf,*t=buf;\n\n\tinline int fetch()\n\t{\n\t\tif(s==t){t=(s=buf)+fread(buf,1,bufl,stdin);if(s==t)return EOF;}\n\t\treturn *s++;\n\t}\n\n\tinline int ty()\n\t{\n\t\tint a=0;int b=1,c=fetch();\n\t\twhile(!isdigit(c))b^=c=='-',c=fetch();\n\t\twhile(isdigit(c))a=a*10+c-48,c=fetch();\n\t\treturn b?a:-a;\n\t}\n\n\tinline int ts(char *s)\n\t{\n\t\tint a=0,c=fetch();\n\t\twhile(c<=32 && c!=EOF)c=fetch();\n\t\twhile(c>32 && c!=EOF)s[a++]=c,c=fetch();\n\t\ts[a]=0;\n\t\treturn a;\n\t}\n}\nusing ae86::ty;\nusing ae86::ts;\n\nconst int _ = 10007 , mo = 998244353;\n\ntemplate<typename T1,typename T2> inline T1 ad(T1 &a,T2 b){return a=a+b>=mo?a+b-mo:a+b;}\ntemplate<typename T1,typename T2> inline T1 dl(T1 &a,T2 b){return a=a>=b?a-b:a-b+mo;}\n\nlint powa(lint a,lint t)\n{\n\tlint b=1;a=(a+mo)%mo;\n\twhile(t){if(t&1)b=b*a%mo;a=a*a%mo,t>>=1;}\n\treturn b;\n}\n\ninline lint inva(lint a)\n{\n\treturn powa(a,mo-2);\n}\n\nlint jc[_],rjc[_];\n\nvoid fuck(int n=_-1)\n{\n\tjc[0]=jc[1]=rjc[0]=1;\n\tfor(int i=2;i<=n;i++)jc[i]=jc[i-1]*i%mo;\n\trjc[n]=inva(jc[n]);\n\tfor(int i=n-1;i>=1;i--)rjc[i]=rjc[i+1]*(1ll+i)%mo;\n}\n\nlint C(int n,int m)\n{\n\tif(n<m || n<0 || m<0)return 0;\n\treturn jc[n]*rjc[m]%mo*rjc[n-m]%mo;\n}\n\nint n;char sa[_],sb[_];\nint f[_][_]={0};\n\nint main()\n{\n\tios::sync_with_stdio(0),cout.tie(nullptr);\n\n\tfuck();\n\t\n\tn=ts(sa+1),ts(sb+1);\n\tint cnt1=0,cnt2=0;\n\tfor(int i=1;i<=n;i++)\n\t{\n\t\tif(sa[i]=='1' && sb[i]=='1')cnt1++;\n\t\tif(sa[i]=='1' && sb[i]=='0')cnt2++;\n\t}\n\n\tfor(int i=0;i<=cnt2;i++)f[0][i]=jc[i]*jc[i]%mo;\n\tfor(int i=1;i<=cnt1;i++)\n\t\tfor(int j=1;j<=cnt2;j++)\n\t\t\tf[i][j]=(1ll*f[i][j-1]*j%mo*j%mo+1ll*f[i-1][j]*i%mo*j%mo)%mo;\n\tlint ans=0;\n\tfor(int i=0;i<=cnt1;i++)\n\t\tad(ans,1ll*f[cnt1-i][cnt2]*jc[i]%mo*jc[i]%mo*C(cnt1,i)%mo*C(cnt1+cnt2,i)%mo);\n\tcout<<ans<<lf;\n\n\treturn 0;\n}\n", "problem_context": "Score : 1700 points\n\nProblem Statement\n\nYou have two strings A = A_1 A_2 ... A_n and B = B_1 B_2 ... B_n of the same length consisting of 0 and 1.\nThe number of 1's in A and B is equal.\n\nYou've decided to transform A using the following algorithm:\n\nLet a_1, a_2, ..., a_k be the indices of 1's in A.\n\nLet b_1, b_2, ..., b_k be the indices of 1's in B.\n\nReplace a and b with their random permutations, chosen independently and uniformly.\n\nFor each i from 1 to k, in order, swap A_{a_i} and A_{b_i}.\n\nLet P be the probability that strings A and B become equal after the procedure above.\n\nLet Z = P \\times (k!)^2. Clearly, Z is an integer.\n\nFind Z modulo 998244353.\n\nConstraints\n\n1 \\leq |A| = |B| \\leq 10,000\n\nA and B consist of 0 and 1.\n\nA and B contain the same number of 1's.\n\nA and B contain at least one 1.\n\nPartial Score\n\n1200 points will be awarded for passing the testset satisfying 1 \\leq |A| = |B| \\leq 500.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA\nB\n\nOutput\n\nPrint the value of Z modulo 998244353.\n\nSample Input 1\n\n1010\n1100\n\nSample Output 1\n\n3\n\nAfter the first two steps, a = [1, 3] and b = [1, 2]. There are 4 possible scenarios after shuffling a and b:\n\na = [1, 3], b = [1, 2]. Initially, A = 1010. After swap(A_1, A_1), A = 1010. After swap(A_3, A_2), A = 1100.\n\na = [1, 3], b = [2, 1]. Initially, A = 1010. After swap(A_1, A_2), A = 0110. After swap(A_3, A_1), A = 1100.\n\na = [3, 1], b = [1, 2]. Initially, A = 1010. After swap(A_3, A_1), A = 1010. After swap(A_1, A_2), A = 0110.\n\na = [3, 1], b = [2, 1]. Initially, A = 1010. After swap(A_3, A_2), A = 1100. After swap(A_1, A_1), A = 1100.\n\nOut of 4 scenarios, 3 of them result in A = B. Therefore, P = 3 / 4, and Z = 3.\n\nSample Input 2\n\n01001\n01001\n\nSample Output 2\n\n4\n\nNo swap ever changes A, so we'll always have A = B.\n\nSample Input 3\n\n101010\n010101\n\nSample Output 3\n\n36\n\nEvery possible sequence of three swaps puts the 1's in A into the right places.\n\nSample Input 4\n\n1101011011110\n0111101011101\n\nSample Output 4\n\n932171449", "sample_input": "1010\n1100\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03621", "source_text": "Score : 1700 points\n\nProblem Statement\n\nYou have two strings A = A_1 A_2 ... A_n and B = B_1 B_2 ... B_n of the same length consisting of 0 and 1.\nThe number of 1's in A and B is equal.\n\nYou've decided to transform A using the following algorithm:\n\nLet a_1, a_2, ..., a_k be the indices of 1's in A.\n\nLet b_1, b_2, ..., b_k be the indices of 1's in B.\n\nReplace a and b with their random permutations, chosen independently and uniformly.\n\nFor each i from 1 to k, in order, swap A_{a_i} and A_{b_i}.\n\nLet P be the probability that strings A and B become equal after the procedure above.\n\nLet Z = P \\times (k!)^2. Clearly, Z is an integer.\n\nFind Z modulo 998244353.\n\nConstraints\n\n1 \\leq |A| = |B| \\leq 10,000\n\nA and B consist of 0 and 1.\n\nA and B contain the same number of 1's.\n\nA and B contain at least one 1.\n\nPartial Score\n\n1200 points will be awarded for passing the testset satisfying 1 \\leq |A| = |B| \\leq 500.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA\nB\n\nOutput\n\nPrint the value of Z modulo 998244353.\n\nSample Input 1\n\n1010\n1100\n\nSample Output 1\n\n3\n\nAfter the first two steps, a = [1, 3] and b = [1, 2]. There are 4 possible scenarios after shuffling a and b:\n\na = [1, 3], b = [1, 2]. Initially, A = 1010. After swap(A_1, A_1), A = 1010. After swap(A_3, A_2), A = 1100.\n\na = [1, 3], b = [2, 1]. Initially, A = 1010. After swap(A_1, A_2), A = 0110. After swap(A_3, A_1), A = 1100.\n\na = [3, 1], b = [1, 2]. Initially, A = 1010. After swap(A_3, A_1), A = 1010. After swap(A_1, A_2), A = 0110.\n\na = [3, 1], b = [2, 1]. Initially, A = 1010. After swap(A_3, A_2), A = 1100. After swap(A_1, A_1), A = 1100.\n\nOut of 4 scenarios, 3 of them result in A = B. Therefore, P = 3 / 4, and Z = 3.\n\nSample Input 2\n\n01001\n01001\n\nSample Output 2\n\n4\n\nNo swap ever changes A, so we'll always have A = B.\n\nSample Input 3\n\n101010\n010101\n\nSample Output 3\n\n36\n\nEvery possible sequence of three swaps puts the 1's in A into the right places.\n\nSample Input 4\n\n1101011011110\n0111101011101\n\nSample Output 4\n\n932171449", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2026, "cpu_time_ms": 215, "memory_kb": 389760}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s241940945", "group_id": "codeNet:p03623", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\nint x ,a,b;\n  cin>>x >> a >>b;\n  if(abs(x-a)>abs(x-b)){\n\tcout << \"B\" << endl;\n  }\n  else{\n  \tcout << \"A\" << endl;\n  }\n}", "language": "C++", "metadata": {"date": 1581828708, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03623.html", "problem_id": "p03623", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03623/input.txt", "sample_output_relpath": "derived/input_output/data/p03623/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03623/C++/s241940945.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s241940945", "user_id": "u784072785"}, "prompt_components": {"gold_output": "B\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\nint x ,a,b;\n  cin>>x >> a >>b;\n  if(abs(x-a)>abs(x-b)){\n\tcout << \"B\" << endl;\n  }\n  else{\n  \tcout << \"A\" << endl;\n  }\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nSnuke lives at position x on a number line.\nOn this line, there are two stores A and B, respectively at position a and b, that offer food for delivery.\n\nSnuke decided to get food delivery from the closer of stores A and B.\nFind out which store is closer to Snuke's residence.\n\nHere, the distance between two points s and t on a number line is represented by |s-t|.\n\nConstraints\n\n1 \\leq x \\leq 1000\n\n1 \\leq a \\leq 1000\n\n1 \\leq b \\leq 1000\n\nx, a and b are pairwise distinct.\n\nThe distances between Snuke's residence and stores A and B are different.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nx a b\n\nOutput\n\nIf store A is closer, print A; if store B is closer, print B.\n\nSample Input 1\n\n5 2 7\n\nSample Output 1\n\nB\n\nThe distances between Snuke's residence and stores A and B are 3 and 2, respectively.\nSince store B is closer, print B.\n\nSample Input 2\n\n1 999 1000\n\nSample Output 2\n\nA", "sample_input": "5 2 7\n"}, "reference_outputs": ["B\n"], "source_document_id": "p03623", "source_text": "Score : 100 points\n\nProblem Statement\n\nSnuke lives at position x on a number line.\nOn this line, there are two stores A and B, respectively at position a and b, that offer food for delivery.\n\nSnuke decided to get food delivery from the closer of stores A and B.\nFind out which store is closer to Snuke's residence.\n\nHere, the distance between two points s and t on a number line is represented by |s-t|.\n\nConstraints\n\n1 \\leq x \\leq 1000\n\n1 \\leq a \\leq 1000\n\n1 \\leq b \\leq 1000\n\nx, a and b are pairwise distinct.\n\nThe distances between Snuke's residence and stores A and B are different.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nx a b\n\nOutput\n\nIf store A is closer, print A; if store B is closer, print B.\n\nSample Input 1\n\n5 2 7\n\nSample Output 1\n\nB\n\nThe distances between Snuke's residence and stores A and B are 3 and 2, respectively.\nSince store B is closer, print B.\n\nSample Input 2\n\n1 999 1000\n\nSample Output 2\n\nA", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 178, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s981756094", "group_id": "codeNet:p03625", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll=long long;\n\nint main(){\n    int N;cin>>N;\n    set<ll> a,b;\n    for(ll i=0,p;i<N;i++){\n        cin>>p;\n        if(a.count(p))b.insert(p);\n        a.insert(p);\n    }\n    if(b.size()<2)cout<<0<<endl;\n    else{\n        auto itr=b.end();\n        itr--;\n        ll ans=*itr;\n        itr--;\n        ans*=*itr;\n        cout<<ans<<endl;\n    }\n    return 0;\n}", "language": "C++", "metadata": {"date": 1568985100, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03625.html", "problem_id": "p03625", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03625/input.txt", "sample_output_relpath": "derived/input_output/data/p03625/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03625/C++/s981756094.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s981756094", "user_id": "u936602931"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nusing ll=long long;\n\nint main(){\n    int N;cin>>N;\n    set<ll> a,b;\n    for(ll i=0,p;i<N;i++){\n        cin>>p;\n        if(a.count(p))b.insert(p);\n        a.insert(p);\n    }\n    if(b.size()<2)cout<<0<<endl;\n    else{\n        auto itr=b.end();\n        itr--;\n        ll ans=*itr;\n        itr--;\n        ans*=*itr;\n        cout<<ans<<endl;\n    }\n    return 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nWe have N sticks with negligible thickness.\nThe length of the i-th stick is A_i.\n\nSnuke wants to select four different sticks from these sticks and form a rectangle (including a square), using the sticks as its sides.\nFind the maximum possible area of the rectangle.\n\nConstraints\n\n4 \\leq N \\leq 10^5\n\n1 \\leq A_i \\leq 10^9\n\nA_i is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the maximum possible area of the rectangle.\nIf no rectangle can be formed, print 0.\n\nSample Input 1\n\n6\n3 1 2 4 2 1\n\nSample Output 1\n\n2\n\n1 \\times 2 rectangle can be formed.\n\nSample Input 2\n\n4\n1 2 3 4\n\nSample Output 2\n\n0\n\nNo rectangle can be formed.\n\nSample Input 3\n\n10\n3 3 3 3 4 4 4 5 5 5\n\nSample Output 3\n\n20", "sample_input": "6\n3 1 2 4 2 1\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03625", "source_text": "Score : 300 points\n\nProblem Statement\n\nWe have N sticks with negligible thickness.\nThe length of the i-th stick is A_i.\n\nSnuke wants to select four different sticks from these sticks and form a rectangle (including a square), using the sticks as its sides.\nFind the maximum possible area of the rectangle.\n\nConstraints\n\n4 \\leq N \\leq 10^5\n\n1 \\leq A_i \\leq 10^9\n\nA_i is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the maximum possible area of the rectangle.\nIf no rectangle can be formed, print 0.\n\nSample Input 1\n\n6\n3 1 2 4 2 1\n\nSample Output 1\n\n2\n\n1 \\times 2 rectangle can be formed.\n\nSample Input 2\n\n4\n1 2 3 4\n\nSample Output 2\n\n0\n\nNo rectangle can be formed.\n\nSample Input 3\n\n10\n3 3 3 3 4 4 4 5 5 5\n\nSample Output 3\n\n20", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 403, "cpu_time_ms": 92, "memory_kb": 4992}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s197022615", "group_id": "codeNet:p03625", "input_text": "#include<stdio.h>\n#include<set>\n#include<vector>\n\n#define FOR(i,a,b) for(int i=(a);i<(b);++i)\n#define REP(i,n)   FOR(i,0,n)\n\nusing namespace std;\n\nint main(){\n  int n,a,m1=0,m2=0;\n  scanf(\"%d\",&n);\n  set<int> si;\n  set<int> array;\n  REP(i,n){\n    scanf(\"%d\",&a);\n    if(!si.insert(a).second) array.insert(a);\n  }\n  for(int b:array){\n    if(b > m1){\n      m2 = m1;\n      m1 = b;\n    }\n  }\n  printf(\"%ld\\n\",(long)m1*m2);\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1518422797, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03625.html", "problem_id": "p03625", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03625/input.txt", "sample_output_relpath": "derived/input_output/data/p03625/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03625/C++/s197022615.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s197022615", "user_id": "u736626080"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include<stdio.h>\n#include<set>\n#include<vector>\n\n#define FOR(i,a,b) for(int i=(a);i<(b);++i)\n#define REP(i,n)   FOR(i,0,n)\n\nusing namespace std;\n\nint main(){\n  int n,a,m1=0,m2=0;\n  scanf(\"%d\",&n);\n  set<int> si;\n  set<int> array;\n  REP(i,n){\n    scanf(\"%d\",&a);\n    if(!si.insert(a).second) array.insert(a);\n  }\n  for(int b:array){\n    if(b > m1){\n      m2 = m1;\n      m1 = b;\n    }\n  }\n  printf(\"%ld\\n\",(long)m1*m2);\n  return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nWe have N sticks with negligible thickness.\nThe length of the i-th stick is A_i.\n\nSnuke wants to select four different sticks from these sticks and form a rectangle (including a square), using the sticks as its sides.\nFind the maximum possible area of the rectangle.\n\nConstraints\n\n4 \\leq N \\leq 10^5\n\n1 \\leq A_i \\leq 10^9\n\nA_i is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the maximum possible area of the rectangle.\nIf no rectangle can be formed, print 0.\n\nSample Input 1\n\n6\n3 1 2 4 2 1\n\nSample Output 1\n\n2\n\n1 \\times 2 rectangle can be formed.\n\nSample Input 2\n\n4\n1 2 3 4\n\nSample Output 2\n\n0\n\nNo rectangle can be formed.\n\nSample Input 3\n\n10\n3 3 3 3 4 4 4 5 5 5\n\nSample Output 3\n\n20", "sample_input": "6\n3 1 2 4 2 1\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03625", "source_text": "Score : 300 points\n\nProblem Statement\n\nWe have N sticks with negligible thickness.\nThe length of the i-th stick is A_i.\n\nSnuke wants to select four different sticks from these sticks and form a rectangle (including a square), using the sticks as its sides.\nFind the maximum possible area of the rectangle.\n\nConstraints\n\n4 \\leq N \\leq 10^5\n\n1 \\leq A_i \\leq 10^9\n\nA_i is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the maximum possible area of the rectangle.\nIf no rectangle can be formed, print 0.\n\nSample Input 1\n\n6\n3 1 2 4 2 1\n\nSample Output 1\n\n2\n\n1 \\times 2 rectangle can be formed.\n\nSample Input 2\n\n4\n1 2 3 4\n\nSample Output 2\n\n0\n\nNo rectangle can be formed.\n\nSample Input 3\n\n10\n3 3 3 3 4 4 4 5 5 5\n\nSample Output 3\n\n20", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 433, "cpu_time_ms": 56, "memory_kb": 4864}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s026254776", "group_id": "codeNet:p03630", "input_text": "#include <iostream>\n#include <sstream>\n#include <algorithm>\n#include <cstdio>\n#include <cmath>\n#include <set>\n#include <map>\n#include <queue>\n#include <string>\n#include <cstring>\n#include <bitset>\n#include <functional>\n#include <random>\n#define REP(i,a,n) for(int i=a;i<=n;++i)\n#define PER(i,a,n) for(int i=n;i>=a;--i)\n#define hr putchar(10)\n#define pb push_back\n#define lc (o<<1)\n#define rc (lc|1)\n#define mid ((l+r)>>1)\n#define ls lc,l,mid\n#define rs rc,mid+1,r\n#define x first\n#define y second\n#define io std::ios::sync_with_stdio(false)\n#define endl '\\n'\n#define DB(a) ({REP(__i,1,n) cout<<a[__i]<<' ';hr;})\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> pii;\nconst int P = 1e9+7, INF = 0x3f3f3f3f;\nll gcd(ll a,ll b) {return b?gcd(b,a%b):a;}\nll qpow(ll a,ll n) {ll r=1%P;for (a%=P;n;a=a*a%P,n>>=1)if(n&1)r=r*a%P;return r;}\nll inv(ll x){return x<=1?1:inv(P%x)*(P-P/x)%P;}\ninline int rd() {int x=0;char p=getchar();while(p<'0'||p>'9')p=getchar();while(p>='0'&&p<='9')x=x*10+p-'0',p=getchar();return x;}\n//head\n\n\n\nconst int N = 2e3+10;\nint n, m, a[N][N], L[N][N], R[N][N], H[N][N];\nchar s[N][N];\n\nint main() {\n\tscanf(\"%d%d\", &n, &m);\n\tREP(i,1,n) scanf(\"%s\", s[i]+1);\n\tREP(i,1,n-1) REP(j,1,m-1) {\n\t\tint t = (s[i][j]=='#')^(s[i+1][j]=='#')^(s[i][j+1]=='#')^(s[i+1][j+1]=='#');\n\t\ta[i][j] = !t;\n\t}\n\tREP(i,1,n-1) {\n\t\tREP(j,1,m-1) if (a[i][j]) {\n\t\t\tif (a[i][j-1]) L[i][j] = L[i][j-1];\n\t\t\telse L[i][j] = j;\n\t\t}\n\t\tPER(j,1,m-1) if (a[i][j]) {\n\t\t\tif (a[i][j+1]) R[i][j] = R[i][j+1];\n\t\t\telse R[i][j] = j;\n\t\t}\n\t}\n\tint ans = max(n,m);\n\tREP(i,1,n-1) REP(j,1,m-1) if (a[i][j]) {\n\t\tH[i][j] = H[i-1][j]+1;\n\t\tif (H[i-1][j]) {\n\t\t\tL[i][j] = max(L[i][j],L[i-1][j]);\n\t\t\tR[i][j] = min(R[i][j],R[i-1][j]);\n\t\t}\n\t\tans = max(ans, (H[i][j]+1)*(R[i][j]-L[i][j]+2));\n\t}\n\tprintf(\"%d\\n\", ans);\n}\n\n\n\n\n\n\n\n", "language": "C++", "metadata": {"date": 1568390121, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03630.html", "problem_id": "p03630", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03630/input.txt", "sample_output_relpath": "derived/input_output/data/p03630/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03630/C++/s026254776.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s026254776", "user_id": "u018679195"}, "prompt_components": {"gold_output": "6\n", "input_to_evaluate": "#include <iostream>\n#include <sstream>\n#include <algorithm>\n#include <cstdio>\n#include <cmath>\n#include <set>\n#include <map>\n#include <queue>\n#include <string>\n#include <cstring>\n#include <bitset>\n#include <functional>\n#include <random>\n#define REP(i,a,n) for(int i=a;i<=n;++i)\n#define PER(i,a,n) for(int i=n;i>=a;--i)\n#define hr putchar(10)\n#define pb push_back\n#define lc (o<<1)\n#define rc (lc|1)\n#define mid ((l+r)>>1)\n#define ls lc,l,mid\n#define rs rc,mid+1,r\n#define x first\n#define y second\n#define io std::ios::sync_with_stdio(false)\n#define endl '\\n'\n#define DB(a) ({REP(__i,1,n) cout<<a[__i]<<' ';hr;})\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> pii;\nconst int P = 1e9+7, INF = 0x3f3f3f3f;\nll gcd(ll a,ll b) {return b?gcd(b,a%b):a;}\nll qpow(ll a,ll n) {ll r=1%P;for (a%=P;n;a=a*a%P,n>>=1)if(n&1)r=r*a%P;return r;}\nll inv(ll x){return x<=1?1:inv(P%x)*(P-P/x)%P;}\ninline int rd() {int x=0;char p=getchar();while(p<'0'||p>'9')p=getchar();while(p>='0'&&p<='9')x=x*10+p-'0',p=getchar();return x;}\n//head\n\n\n\nconst int N = 2e3+10;\nint n, m, a[N][N], L[N][N], R[N][N], H[N][N];\nchar s[N][N];\n\nint main() {\n\tscanf(\"%d%d\", &n, &m);\n\tREP(i,1,n) scanf(\"%s\", s[i]+1);\n\tREP(i,1,n-1) REP(j,1,m-1) {\n\t\tint t = (s[i][j]=='#')^(s[i+1][j]=='#')^(s[i][j+1]=='#')^(s[i+1][j+1]=='#');\n\t\ta[i][j] = !t;\n\t}\n\tREP(i,1,n-1) {\n\t\tREP(j,1,m-1) if (a[i][j]) {\n\t\t\tif (a[i][j-1]) L[i][j] = L[i][j-1];\n\t\t\telse L[i][j] = j;\n\t\t}\n\t\tPER(j,1,m-1) if (a[i][j]) {\n\t\t\tif (a[i][j+1]) R[i][j] = R[i][j+1];\n\t\t\telse R[i][j] = j;\n\t\t}\n\t}\n\tint ans = max(n,m);\n\tREP(i,1,n-1) REP(j,1,m-1) if (a[i][j]) {\n\t\tH[i][j] = H[i-1][j]+1;\n\t\tif (H[i-1][j]) {\n\t\t\tL[i][j] = max(L[i][j],L[i-1][j]);\n\t\t\tR[i][j] = min(R[i][j],R[i-1][j]);\n\t\t}\n\t\tans = max(ans, (H[i][j]+1)*(R[i][j]-L[i][j]+2));\n\t}\n\tprintf(\"%d\\n\", ans);\n}\n\n\n\n\n\n\n\n", "problem_context": "Score : 700 points\n\nProblem Statement\n\nWe have a board with an H \\times W grid.\nEach square in the grid is painted in black or white. The square at the i-th row from the top and j-th column from the left is black if the j-th character in S_i is #, and white if that character is ..\n\nSnuke can perform the following operation on the grid any number of times:\n\nSelect a row or column in the grid, and invert the color of all the squares in that row or column (that is, black squares become white and vice versa).\n\nThen, Snuke draws a rectangle along grid lines. Here, all the squares contained in the rectangle must be painted in black.\n\nFind the maximum possible area of Snuke's rectangle when the operation is performed optimally.\n\nConstraints\n\n2 \\leq H \\leq 2000\n\n2 \\leq W \\leq 2000\n\n|S_i| = W\n\nS_i consists of # and ..\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W\nS_1\nS_2\n:\nS_H\n\nOutput\n\nPrint the maximum possible area of Snuke's rectangle.\n\nSample Input 1\n\n3 3\n..#\n##.\n.#.\n\nSample Output 1\n\n6\n\nIf the first row from the top and the third column from the left are inverted, a 2 \\times 3 rectangle can be drawn, as shown below:\n\nSample Input 2\n\n4 4\n....\n....\n....\n....\n\nSample Output 2\n\n16\n\nSample Input 3\n\n10 8\n##...#.#\n##...#.#\n..###.#.\n#.##.#.#\n.#..#.#.\n..##.#.#\n##.#.#..\n...#.#..\n###.#.##\n###..###\n\nSample Output 3\n\n27", "sample_input": "3 3\n..#\n##.\n.#.\n"}, "reference_outputs": ["6\n"], "source_document_id": "p03630", "source_text": "Score : 700 points\n\nProblem Statement\n\nWe have a board with an H \\times W grid.\nEach square in the grid is painted in black or white. The square at the i-th row from the top and j-th column from the left is black if the j-th character in S_i is #, and white if that character is ..\n\nSnuke can perform the following operation on the grid any number of times:\n\nSelect a row or column in the grid, and invert the color of all the squares in that row or column (that is, black squares become white and vice versa).\n\nThen, Snuke draws a rectangle along grid lines. Here, all the squares contained in the rectangle must be painted in black.\n\nFind the maximum possible area of Snuke's rectangle when the operation is performed optimally.\n\nConstraints\n\n2 \\leq H \\leq 2000\n\n2 \\leq W \\leq 2000\n\n|S_i| = W\n\nS_i consists of # and ..\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W\nS_1\nS_2\n:\nS_H\n\nOutput\n\nPrint the maximum possible area of Snuke's rectangle.\n\nSample Input 1\n\n3 3\n..#\n##.\n.#.\n\nSample Output 1\n\n6\n\nIf the first row from the top and the third column from the left are inverted, a 2 \\times 3 rectangle can be drawn, as shown below:\n\nSample Input 2\n\n4 4\n....\n....\n....\n....\n\nSample Output 2\n\n16\n\nSample Input 3\n\n10 8\n##...#.#\n##...#.#\n..###.#.\n#.##.#.#\n.#..#.#.\n..##.#.#\n##.#.#..\n...#.#..\n###.#.##\n###..###\n\nSample Output 3\n\n27", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1790, "cpu_time_ms": 94, "memory_kb": 67200}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s639201596", "group_id": "codeNet:p03630", "input_text": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint const N = 2222;\n\nint ss[N][N], s[N][N];\n\nint d[N], st[N];\n\nint main() {\n  int n, m;\n  scanf(\"%d%d\", &n, &m);\n  for (int i = 0; i < n; i++) {\n    for (int j = 0; j < m; j++) {\n      int c = getchar();\n      while (c <= 32) c = getchar();\n      ss[i][j] = c;\n    }\n    for (int j = 0; j + 1 < m; j++) {\n      s[i][j] = ss[i][j] != ss[i][j + 1];\n    }\n  }\n  int ans = std::max(n, m);\n  for (int i = 0; i < n; i++) {\n    for (int j = 0; j + 1 < m; j++) {\n      if (i == 0) {\n        d[j] = 1;\n      } else if (s[i][j] == s[i - 1][j]) {\n        d[j]++;\n      } else {\n        d[j] = 1;\n      }\n    }\n    d[m - 1] = -1;\n    int cn = 0;\n    for (int j = 0; j < m; j++) {\n      while (cn > 0 && d[st[cn - 1]] > d[j]) { \n        int last = st[--cn];\n        ans = std::max(ans, (j - last + 1) * d[last]);\n      }\n      st[cn++] = j;\n    }\n  }\n  printf(\"%d\\n\", ans);\n}\n", "language": "C++", "metadata": {"date": 1503280863, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03630.html", "problem_id": "p03630", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03630/input.txt", "sample_output_relpath": "derived/input_output/data/p03630/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03630/C++/s639201596.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s639201596", "user_id": "u526715397"}, "prompt_components": {"gold_output": "6\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint const N = 2222;\n\nint ss[N][N], s[N][N];\n\nint d[N], st[N];\n\nint main() {\n  int n, m;\n  scanf(\"%d%d\", &n, &m);\n  for (int i = 0; i < n; i++) {\n    for (int j = 0; j < m; j++) {\n      int c = getchar();\n      while (c <= 32) c = getchar();\n      ss[i][j] = c;\n    }\n    for (int j = 0; j + 1 < m; j++) {\n      s[i][j] = ss[i][j] != ss[i][j + 1];\n    }\n  }\n  int ans = std::max(n, m);\n  for (int i = 0; i < n; i++) {\n    for (int j = 0; j + 1 < m; j++) {\n      if (i == 0) {\n        d[j] = 1;\n      } else if (s[i][j] == s[i - 1][j]) {\n        d[j]++;\n      } else {\n        d[j] = 1;\n      }\n    }\n    d[m - 1] = -1;\n    int cn = 0;\n    for (int j = 0; j < m; j++) {\n      while (cn > 0 && d[st[cn - 1]] > d[j]) { \n        int last = st[--cn];\n        ans = std::max(ans, (j - last + 1) * d[last]);\n      }\n      st[cn++] = j;\n    }\n  }\n  printf(\"%d\\n\", ans);\n}\n", "problem_context": "Score : 700 points\n\nProblem Statement\n\nWe have a board with an H \\times W grid.\nEach square in the grid is painted in black or white. The square at the i-th row from the top and j-th column from the left is black if the j-th character in S_i is #, and white if that character is ..\n\nSnuke can perform the following operation on the grid any number of times:\n\nSelect a row or column in the grid, and invert the color of all the squares in that row or column (that is, black squares become white and vice versa).\n\nThen, Snuke draws a rectangle along grid lines. Here, all the squares contained in the rectangle must be painted in black.\n\nFind the maximum possible area of Snuke's rectangle when the operation is performed optimally.\n\nConstraints\n\n2 \\leq H \\leq 2000\n\n2 \\leq W \\leq 2000\n\n|S_i| = W\n\nS_i consists of # and ..\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W\nS_1\nS_2\n:\nS_H\n\nOutput\n\nPrint the maximum possible area of Snuke's rectangle.\n\nSample Input 1\n\n3 3\n..#\n##.\n.#.\n\nSample Output 1\n\n6\n\nIf the first row from the top and the third column from the left are inverted, a 2 \\times 3 rectangle can be drawn, as shown below:\n\nSample Input 2\n\n4 4\n....\n....\n....\n....\n\nSample Output 2\n\n16\n\nSample Input 3\n\n10 8\n##...#.#\n##...#.#\n..###.#.\n#.##.#.#\n.#..#.#.\n..##.#.#\n##.#.#..\n...#.#..\n###.#.##\n###..###\n\nSample Output 3\n\n27", "sample_input": "3 3\n..#\n##.\n.#.\n"}, "reference_outputs": ["6\n"], "source_document_id": "p03630", "source_text": "Score : 700 points\n\nProblem Statement\n\nWe have a board with an H \\times W grid.\nEach square in the grid is painted in black or white. The square at the i-th row from the top and j-th column from the left is black if the j-th character in S_i is #, and white if that character is ..\n\nSnuke can perform the following operation on the grid any number of times:\n\nSelect a row or column in the grid, and invert the color of all the squares in that row or column (that is, black squares become white and vice versa).\n\nThen, Snuke draws a rectangle along grid lines. Here, all the squares contained in the rectangle must be painted in black.\n\nFind the maximum possible area of Snuke's rectangle when the operation is performed optimally.\n\nConstraints\n\n2 \\leq H \\leq 2000\n\n2 \\leq W \\leq 2000\n\n|S_i| = W\n\nS_i consists of # and ..\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W\nS_1\nS_2\n:\nS_H\n\nOutput\n\nPrint the maximum possible area of Snuke's rectangle.\n\nSample Input 1\n\n3 3\n..#\n##.\n.#.\n\nSample Output 1\n\n6\n\nIf the first row from the top and the third column from the left are inverted, a 2 \\times 3 rectangle can be drawn, as shown below:\n\nSample Input 2\n\n4 4\n....\n....\n....\n....\n\nSample Output 2\n\n16\n\nSample Input 3\n\n10 8\n##...#.#\n##...#.#\n..###.#.\n#.##.#.#\n.#..#.#.\n..##.#.#\n##.#.#..\n...#.#..\n###.#.##\n###..###\n\nSample Output 3\n\n27", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 911, "cpu_time_ms": 92, "memory_kb": 37120}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s872804653", "group_id": "codeNet:p03633", "input_text": "#include<bits/stdc++.h>\n#define rep(i, n) for(int i = 0; i < n; i++)\nusing ll = long long; \nusing namespace std;\n//最大公約数\nint GCD(ll a, ll b){\n  if(b==0){\n    return a;\n  }\n  GCD(b, a%b);\n}\n//最小公倍数\nint LCM(ll a, ll b){\n  ll g = GCD(a, b);\n  return a*b/g;\n}\n\nint main(){\n  int N;\n  cin >> N;\n  int ans = 1;\n  rep(i, N){\n    ll T;\n    cin >> T;\n    ans = LCM(ans, T);\n  }\n  cout << ans << endl;\n}\n\n", "language": "C++", "metadata": {"date": 1589508631, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03633.html", "problem_id": "p03633", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03633/input.txt", "sample_output_relpath": "derived/input_output/data/p03633/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03633/C++/s872804653.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s872804653", "user_id": "u126936481"}, "prompt_components": {"gold_output": "6\n", "input_to_evaluate": "#include<bits/stdc++.h>\n#define rep(i, n) for(int i = 0; i < n; i++)\nusing ll = long long; \nusing namespace std;\n//最大公約数\nint GCD(ll a, ll b){\n  if(b==0){\n    return a;\n  }\n  GCD(b, a%b);\n}\n//最小公倍数\nint LCM(ll a, ll b){\n  ll g = GCD(a, b);\n  return a*b/g;\n}\n\nint main(){\n  int N;\n  cin >> N;\n  int ans = 1;\n  rep(i, N){\n    ll T;\n    cin >> T;\n    ans = LCM(ans, T);\n  }\n  cout << ans << endl;\n}\n\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nWe have N clocks. The hand of the i-th clock (1≤i≤N) rotates through 360° in exactly T_i seconds.\n\nInitially, the hand of every clock stands still, pointing directly upward.\n\nNow, Dolphin starts all the clocks simultaneously.\n\nIn how many seconds will the hand of every clock point directly upward again?\n\nConstraints\n\n1≤N≤100\n\n1≤T_i≤10^{18}\n\nAll input values are integers.\n\nThe correct answer is at most 10^{18} seconds.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nT_1\n:\nT_N\n\nOutput\n\nPrint the number of seconds after which the hand of every clock point directly upward again.\n\nSample Input 1\n\n2\n2\n3\n\nSample Output 1\n\n6\n\nWe have two clocks. The time when the hand of each clock points upward is as follows:\n\nClock 1: 2, 4, 6, ... seconds after the beginning\n\nClock 2: 3, 6, 9, ... seconds after the beginning\n\nTherefore, it takes 6 seconds until the hands of both clocks point directly upward.\n\nSample Input 2\n\n5\n2\n5\n10\n1000000000000000000\n1000000000000000000\n\nSample Output 2\n\n1000000000000000000", "sample_input": "2\n2\n3\n"}, "reference_outputs": ["6\n"], "source_document_id": "p03633", "source_text": "Score : 300 points\n\nProblem Statement\n\nWe have N clocks. The hand of the i-th clock (1≤i≤N) rotates through 360° in exactly T_i seconds.\n\nInitially, the hand of every clock stands still, pointing directly upward.\n\nNow, Dolphin starts all the clocks simultaneously.\n\nIn how many seconds will the hand of every clock point directly upward again?\n\nConstraints\n\n1≤N≤100\n\n1≤T_i≤10^{18}\n\nAll input values are integers.\n\nThe correct answer is at most 10^{18} seconds.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nT_1\n:\nT_N\n\nOutput\n\nPrint the number of seconds after which the hand of every clock point directly upward again.\n\nSample Input 1\n\n2\n2\n3\n\nSample Output 1\n\n6\n\nWe have two clocks. The time when the hand of each clock points upward is as follows:\n\nClock 1: 2, 4, 6, ... seconds after the beginning\n\nClock 2: 3, 6, 9, ... seconds after the beginning\n\nTherefore, it takes 6 seconds until the hands of both clocks point directly upward.\n\nSample Input 2\n\n5\n2\n5\n10\n1000000000000000000\n1000000000000000000\n\nSample Output 2\n\n1000000000000000000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 415, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s243481818", "group_id": "codeNet:p03635", "input_text": "#include<iostream>\nusing namespace std;\nint main(){\n  int m;\n  int n;\n  cin>>m;\n  cin>>n;\n  cout<<(m-1)*(n-1);\n}", "language": "C++", "metadata": {"date": 1572399885, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03635.html", "problem_id": "p03635", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03635/input.txt", "sample_output_relpath": "derived/input_output/data/p03635/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03635/C++/s243481818.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s243481818", "user_id": "u300325058"}, "prompt_components": {"gold_output": "6\n", "input_to_evaluate": "#include<iostream>\nusing namespace std;\nint main(){\n  int m;\n  int n;\n  cin>>m;\n  cin>>n;\n  cout<<(m-1)*(n-1);\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nIn K-city, there are n streets running east-west, and m streets running north-south. Each street running east-west and each street running north-south cross each other. We will call the smallest area that is surrounded by four streets a block. How many blocks there are in K-city?\n\nConstraints\n\n2 ≤ n, m ≤ 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn m\n\nOutput\n\nPrint the number of blocks in K-city.\n\nSample Input 1\n\n3 4\n\nSample Output 1\n\n6\n\nThere are six blocks, as shown below:\n\nSample Input 2\n\n2 2\n\nSample Output 2\n\n1\n\nThere are one block, as shown below:", "sample_input": "3 4\n"}, "reference_outputs": ["6\n"], "source_document_id": "p03635", "source_text": "Score : 100 points\n\nProblem Statement\n\nIn K-city, there are n streets running east-west, and m streets running north-south. Each street running east-west and each street running north-south cross each other. We will call the smallest area that is surrounded by four streets a block. How many blocks there are in K-city?\n\nConstraints\n\n2 ≤ n, m ≤ 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn m\n\nOutput\n\nPrint the number of blocks in K-city.\n\nSample Input 1\n\n3 4\n\nSample Output 1\n\n6\n\nThere are six blocks, as shown below:\n\nSample Input 2\n\n2 2\n\nSample Output 2\n\n1\n\nThere are one block, as shown below:", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 112, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s998429125", "group_id": "codeNet:p03636", "input_text": "#include <iostream>\n#include <string>\n\nusing namespace std;\n\nint main () {\n    string s;\n    cin >> s;\n    cout << s[0] << s.size() - 2 << s[s.size() - 1];\n}", "language": "C++", "metadata": {"date": 1521784012, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03636.html", "problem_id": "p03636", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03636/input.txt", "sample_output_relpath": "derived/input_output/data/p03636/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03636/C++/s998429125.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s998429125", "user_id": "u896439542"}, "prompt_components": {"gold_output": "i18n\n", "input_to_evaluate": "#include <iostream>\n#include <string>\n\nusing namespace std;\n\nint main () {\n    string s;\n    cin >> s;\n    cout << s[0] << s.size() - 2 << s[s.size() - 1];\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nThe word internationalization is sometimes abbreviated to i18n.\nThis comes from the fact that there are 18 letters between the first i and the last n.\n\nYou are given a string s of length at least 3 consisting of lowercase English letters.\nAbbreviate s in the same way.\n\nConstraints\n\n3 ≤ |s| ≤ 100 (|s| denotes the length of s.)\n\ns consists of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\ns\n\nOutput\n\nPrint the abbreviation of s.\n\nSample Input 1\n\ninternationalization\n\nSample Output 1\n\ni18n\n\nSample Input 2\n\nsmiles\n\nSample Output 2\n\ns4s\n\nSample Input 3\n\nxyz\n\nSample Output 3\n\nx1z", "sample_input": "internationalization\n"}, "reference_outputs": ["i18n\n"], "source_document_id": "p03636", "source_text": "Score : 200 points\n\nProblem Statement\n\nThe word internationalization is sometimes abbreviated to i18n.\nThis comes from the fact that there are 18 letters between the first i and the last n.\n\nYou are given a string s of length at least 3 consisting of lowercase English letters.\nAbbreviate s in the same way.\n\nConstraints\n\n3 ≤ |s| ≤ 100 (|s| denotes the length of s.)\n\ns consists of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\ns\n\nOutput\n\nPrint the abbreviation of s.\n\nSample Input 1\n\ninternationalization\n\nSample Output 1\n\ni18n\n\nSample Input 2\n\nsmiles\n\nSample Output 2\n\ns4s\n\nSample Input 3\n\nxyz\n\nSample Output 3\n\nx1z", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 157, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s838380813", "group_id": "codeNet:p03637", "input_text": "#include <bits/stdc++.h>\n#define repd(i,a,b) for (int i=(a);i<(b);i++)\n#define rep(i,n) repd(i,0,n)\ntypedef long long ll;\nconst int MOD = 1000000007;\nconst int INF = 1010000000;\nconst double EPS = 1e-10;\nusing namespace std;\n\nint main() {\n  int n;cin>>n;int f = 0, t = 0, o = 0;\n  rep(i,n){\n    int aa;cin>>aa;\n    if(aa % 4 == 0){\n      f++;\n    }else if(aa % 2 == 0){\n      t++;\n    }else{\n      o++;\n    }\n  }\n  if(f >= o || (f>=o-1 && t == 0)){\n    cout << \"Yes\" << endl;\n  }else{\n    cout << \"No\" << endl;\n  }\n}\n\n", "language": "C++", "metadata": {"date": 1548657555, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03637.html", "problem_id": "p03637", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03637/input.txt", "sample_output_relpath": "derived/input_output/data/p03637/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03637/C++/s838380813.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s838380813", "user_id": "u317754719"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define repd(i,a,b) for (int i=(a);i<(b);i++)\n#define rep(i,n) repd(i,0,n)\ntypedef long long ll;\nconst int MOD = 1000000007;\nconst int INF = 1010000000;\nconst double EPS = 1e-10;\nusing namespace std;\n\nint main() {\n  int n;cin>>n;int f = 0, t = 0, o = 0;\n  rep(i,n){\n    int aa;cin>>aa;\n    if(aa % 4 == 0){\n      f++;\n    }else if(aa % 2 == 0){\n      t++;\n    }else{\n      o++;\n    }\n  }\n  if(f >= o || (f>=o-1 && t == 0)){\n    cout << \"Yes\" << endl;\n  }else{\n    cout << \"No\" << endl;\n  }\n}\n\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nWe have a sequence of length N, a = (a_1, a_2, ..., a_N).\nEach a_i is a positive integer.\n\nSnuke's objective is to permute the element in a so that the following condition is satisfied:\n\nFor each 1 ≤ i ≤ N - 1, the product of a_i and a_{i + 1} is a multiple of 4.\n\nDetermine whether Snuke can achieve his objective.\n\nConstraints\n\n2 ≤ N ≤ 10^5\n\na_i is an integer.\n\n1 ≤ a_i ≤ 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_N\n\nOutput\n\nIf Snuke can achieve his objective, print Yes; otherwise, print No.\n\nSample Input 1\n\n3\n1 10 100\n\nSample Output 1\n\nYes\n\nOne solution is (1, 100, 10).\n\nSample Input 2\n\n4\n1 2 3 4\n\nSample Output 2\n\nNo\n\nIt is impossible to permute a so that the condition is satisfied.\n\nSample Input 3\n\n3\n1 4 1\n\nSample Output 3\n\nYes\n\nThe condition is already satisfied initially.\n\nSample Input 4\n\n2\n1 1\n\nSample Output 4\n\nNo\n\nSample Input 5\n\n6\n2 7 1 8 2 8\n\nSample Output 5\n\nYes", "sample_input": "3\n1 10 100\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p03637", "source_text": "Score : 400 points\n\nProblem Statement\n\nWe have a sequence of length N, a = (a_1, a_2, ..., a_N).\nEach a_i is a positive integer.\n\nSnuke's objective is to permute the element in a so that the following condition is satisfied:\n\nFor each 1 ≤ i ≤ N - 1, the product of a_i and a_{i + 1} is a multiple of 4.\n\nDetermine whether Snuke can achieve his objective.\n\nConstraints\n\n2 ≤ N ≤ 10^5\n\na_i is an integer.\n\n1 ≤ a_i ≤ 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_N\n\nOutput\n\nIf Snuke can achieve his objective, print Yes; otherwise, print No.\n\nSample Input 1\n\n3\n1 10 100\n\nSample Output 1\n\nYes\n\nOne solution is (1, 100, 10).\n\nSample Input 2\n\n4\n1 2 3 4\n\nSample Output 2\n\nNo\n\nIt is impossible to permute a so that the condition is satisfied.\n\nSample Input 3\n\n3\n1 4 1\n\nSample Output 3\n\nYes\n\nThe condition is already satisfied initially.\n\nSample Input 4\n\n2\n1 1\n\nSample Output 4\n\nNo\n\nSample Input 5\n\n6\n2 7 1 8 2 8\n\nSample Output 5\n\nYes", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 518, "cpu_time_ms": 55, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s975521407", "group_id": "codeNet:p03640", "input_text": "\n#pragma GCC optimize(\"O3\") //コンパイラ最適化用\n\n#define _GLIBCXX_DEBUG //配列に[]でアクセス時のエラー表示\n#include <algorithm>   //sort,二分探索,など\n#include <bitset>      //固定長bit集合\n#include <cassert>     //assert(p)で，not pのときにエラー\n#include <chrono>      //実行時間計測\n#include <cmath>       //pow,logなど\n#include <complex>     //複素数\n#include <cstring>\n#include <deque>\n#include <functional> //sortのgreater\n#include <iomanip>    //setprecision(浮動小数点の出力の誤差)\n#include <iostream>   //入出力\n#include <iterator>   //集合演算(積集合,和集合,差集合など)\n#include <map>\n#include <numeric> //iota(整数列の生成),gcdとlcm,accumulate\n#include <queue>\n#include <set>\n#include <stack>\n#include <string>\n#include <unordered_map>\n#include <unordered_set>\n#include <utility> //pair\n#include <vector>  //可変長配列\nusing namespace std;\ntypedef long long ll;\ntypedef long double ld;\n\n#define ALL(x) x.begin(), x.end()\n#define SIZE(x) ll(x.size()) // sizeをsize_tからllに直しておく\nconst long long INF = 1e12;\nconst int MOD = 1e9 + 7;\n#define MAXR 100000 // 10^5:配列の最大のrange(素数列挙などで使用)\n//略記\n#define Umap unordered_map\n#define Uset unordered_set\n#define int long long\n#define LD long double\n#define P pair<int, int>\n#define PB push_back\n#define MP make_pair\n#define VI vector<int>\n#define VVI vector<vector<int>>\n#define REP(i, n) for (int i = 0; i < (int)(n); i++)\n#define REPD(i, n) for (int i = (int)(n)-1; i >= 0; i--)\n#define FOR(i, a, b) for (int i = a; i < (int)(b); i++)\n#define FORD(i, a, b) for (int i = (int)(b)-1; i >= (int)a; i--)\n\nconst unsigned int BIT_FLAG_0 = (1 << 0); // 0000 0000 0000 0001\nconst unsigned int BIT_FLAG_1 = (1 << 1); // 0000 0000 0000 0010\nconst unsigned int BIT_FLAG_2 = (1 << 2); // 0000 0000 0000 0100\nconst unsigned int BIT_FLAG_3 = (1 << 3); // 0000 0000 0000 1000\nconst unsigned int BIT_FLAG_4 = (1 << 4); // 0000 0000 0001 0000\nconst unsigned int BIT_FLAG_5 = (1 << 5); // 0000 0000 0010 0000\nconst unsigned int BIT_FLAG_6 = (1 << 6); // 0000 0000 0100 0000\nconst unsigned int BIT_FLAG_7 = (1 << 7); // 0000 0000 1000 0000\nconst int dx[4] = {0, 1, 0, -1}, dy[4] = {-1, 0, 1, 0};\nconst int Dx[8] = {0, 1, 1, 1, 0, -1, -1, -1},\n          Dy[8] = {-1, -1, 0, 1, 1, 1, 0, -1};\n\n// https://qiita.com/Lily0727K/items/06cb1d6da8a436369eed#c%E3%81%A7%E3%81%AE%E5%AE%9F%E8%A3%85\nvoid print() { cout << endl; }\n\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&... tail) {\n    cout << head;\n    if (sizeof...(tail) != 0)\n        cout << \" \";\n    print(forward<Tail>(tail)...);\n}\n\ntemplate <class T> void print(vector<T> &vec) {\n    for (auto &a : vec) {\n        cout << a;\n        if (&a != &vec.back())\n            cout << \" \";\n    }\n    cout << endl;\n}\n\ntemplate <class T> void print(vector<vector<T>> &df) {\n    for (auto &vec : df) {\n        print(vec);\n    }\n}\nlong long power(long long a, long long n) {\n    long long res = 1;\n    while (n > 0) {\n        if (n & 1)\n            res = res * a;\n        a *= a;\n        n >>= 1;\n    }\n    return res;\n}\nlong long comb(int n, int k) {\n    vector<vector<long long>> v(n + 1, vector<long long>(n + 1, 0));\n\n    for (int i = 0; i < v.size(); i++) {\n        v[i][0] = 1;\n        v[i][i] = 1;\n    }\n    for (int k = 1; k < v.size(); k++) {\n        for (int j = 1; j < k; j++) {\n            v[k][j] = (v[k - 1][j - 1] + v[k - 1][j]);\n        }\n    }\n    return v[n][k];\n}\nvoid add(long long &a, long long b) {\n    a += b;\n    if (a >= MOD)\n        a -= MOD;\n}\ntemplate <class T> inline bool chmin(T &a, T b) {\n    if (a > b) {\n        a = b;\n        return true;\n    }\n    return false;\n}\ntemplate <class T> inline bool chmax(T &a, T b) {\n    if (a < b) {\n        a = b;\n        return true;\n    }\n    return false;\n}\n\nint h, w, n, line = 0, cur = 0;\nVI A;\nVVI res;\nsigned main() {\n    cin >> h >> w >> n;\n    FOR(i, 1, n + 1) {\n        int times;\n        cin >> times;\n        REP(t, times) { A.PB(i); }\n    }\n    res.resize(h, vector<int>(w));\n\n    REP(i, h * w) {\n        if (line % 2 == 0) {\n            if (cur < w - 1) {\n                res[line][cur] = A[i];\n                cur++;\n            } else {\n                res[line][cur] = A[i];\n\n                line++;\n            }\n        }\n\n        else {\n            if (cur > 0) {\n                res[line][cur] = A[i];\n                cur--;\n            } else {\n                res[line][cur] = A[i];\n\n                line++;\n            }\n        }\n    }\n\n    REP(hi, h) {\n        REP(wi, w) {\n            cout << res[hi][wi] << \" \";\n            if (wi == w - 1) {\n                cout << endl;\n            }\n        }\n    }\n}\n", "language": "C++", "metadata": {"date": 1596802474, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03640.html", "problem_id": "p03640", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03640/input.txt", "sample_output_relpath": "derived/input_output/data/p03640/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03640/C++/s975521407.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s975521407", "user_id": "u992910889"}, "prompt_components": {"gold_output": "1 1\n2 3\n", "input_to_evaluate": "\n#pragma GCC optimize(\"O3\") //コンパイラ最適化用\n\n#define _GLIBCXX_DEBUG //配列に[]でアクセス時のエラー表示\n#include <algorithm>   //sort,二分探索,など\n#include <bitset>      //固定長bit集合\n#include <cassert>     //assert(p)で，not pのときにエラー\n#include <chrono>      //実行時間計測\n#include <cmath>       //pow,logなど\n#include <complex>     //複素数\n#include <cstring>\n#include <deque>\n#include <functional> //sortのgreater\n#include <iomanip>    //setprecision(浮動小数点の出力の誤差)\n#include <iostream>   //入出力\n#include <iterator>   //集合演算(積集合,和集合,差集合など)\n#include <map>\n#include <numeric> //iota(整数列の生成),gcdとlcm,accumulate\n#include <queue>\n#include <set>\n#include <stack>\n#include <string>\n#include <unordered_map>\n#include <unordered_set>\n#include <utility> //pair\n#include <vector>  //可変長配列\nusing namespace std;\ntypedef long long ll;\ntypedef long double ld;\n\n#define ALL(x) x.begin(), x.end()\n#define SIZE(x) ll(x.size()) // sizeをsize_tからllに直しておく\nconst long long INF = 1e12;\nconst int MOD = 1e9 + 7;\n#define MAXR 100000 // 10^5:配列の最大のrange(素数列挙などで使用)\n//略記\n#define Umap unordered_map\n#define Uset unordered_set\n#define int long long\n#define LD long double\n#define P pair<int, int>\n#define PB push_back\n#define MP make_pair\n#define VI vector<int>\n#define VVI vector<vector<int>>\n#define REP(i, n) for (int i = 0; i < (int)(n); i++)\n#define REPD(i, n) for (int i = (int)(n)-1; i >= 0; i--)\n#define FOR(i, a, b) for (int i = a; i < (int)(b); i++)\n#define FORD(i, a, b) for (int i = (int)(b)-1; i >= (int)a; i--)\n\nconst unsigned int BIT_FLAG_0 = (1 << 0); // 0000 0000 0000 0001\nconst unsigned int BIT_FLAG_1 = (1 << 1); // 0000 0000 0000 0010\nconst unsigned int BIT_FLAG_2 = (1 << 2); // 0000 0000 0000 0100\nconst unsigned int BIT_FLAG_3 = (1 << 3); // 0000 0000 0000 1000\nconst unsigned int BIT_FLAG_4 = (1 << 4); // 0000 0000 0001 0000\nconst unsigned int BIT_FLAG_5 = (1 << 5); // 0000 0000 0010 0000\nconst unsigned int BIT_FLAG_6 = (1 << 6); // 0000 0000 0100 0000\nconst unsigned int BIT_FLAG_7 = (1 << 7); // 0000 0000 1000 0000\nconst int dx[4] = {0, 1, 0, -1}, dy[4] = {-1, 0, 1, 0};\nconst int Dx[8] = {0, 1, 1, 1, 0, -1, -1, -1},\n          Dy[8] = {-1, -1, 0, 1, 1, 1, 0, -1};\n\n// https://qiita.com/Lily0727K/items/06cb1d6da8a436369eed#c%E3%81%A7%E3%81%AE%E5%AE%9F%E8%A3%85\nvoid print() { cout << endl; }\n\ntemplate <class Head, class... Tail> void print(Head &&head, Tail &&... tail) {\n    cout << head;\n    if (sizeof...(tail) != 0)\n        cout << \" \";\n    print(forward<Tail>(tail)...);\n}\n\ntemplate <class T> void print(vector<T> &vec) {\n    for (auto &a : vec) {\n        cout << a;\n        if (&a != &vec.back())\n            cout << \" \";\n    }\n    cout << endl;\n}\n\ntemplate <class T> void print(vector<vector<T>> &df) {\n    for (auto &vec : df) {\n        print(vec);\n    }\n}\nlong long power(long long a, long long n) {\n    long long res = 1;\n    while (n > 0) {\n        if (n & 1)\n            res = res * a;\n        a *= a;\n        n >>= 1;\n    }\n    return res;\n}\nlong long comb(int n, int k) {\n    vector<vector<long long>> v(n + 1, vector<long long>(n + 1, 0));\n\n    for (int i = 0; i < v.size(); i++) {\n        v[i][0] = 1;\n        v[i][i] = 1;\n    }\n    for (int k = 1; k < v.size(); k++) {\n        for (int j = 1; j < k; j++) {\n            v[k][j] = (v[k - 1][j - 1] + v[k - 1][j]);\n        }\n    }\n    return v[n][k];\n}\nvoid add(long long &a, long long b) {\n    a += b;\n    if (a >= MOD)\n        a -= MOD;\n}\ntemplate <class T> inline bool chmin(T &a, T b) {\n    if (a > b) {\n        a = b;\n        return true;\n    }\n    return false;\n}\ntemplate <class T> inline bool chmax(T &a, T b) {\n    if (a < b) {\n        a = b;\n        return true;\n    }\n    return false;\n}\n\nint h, w, n, line = 0, cur = 0;\nVI A;\nVVI res;\nsigned main() {\n    cin >> h >> w >> n;\n    FOR(i, 1, n + 1) {\n        int times;\n        cin >> times;\n        REP(t, times) { A.PB(i); }\n    }\n    res.resize(h, vector<int>(w));\n\n    REP(i, h * w) {\n        if (line % 2 == 0) {\n            if (cur < w - 1) {\n                res[line][cur] = A[i];\n                cur++;\n            } else {\n                res[line][cur] = A[i];\n\n                line++;\n            }\n        }\n\n        else {\n            if (cur > 0) {\n                res[line][cur] = A[i];\n                cur--;\n            } else {\n                res[line][cur] = A[i];\n\n                line++;\n            }\n        }\n    }\n\n    REP(hi, h) {\n        REP(wi, w) {\n            cout << res[hi][wi] << \" \";\n            if (wi == w - 1) {\n                cout << endl;\n            }\n        }\n    }\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nWe have a grid with H rows and W columns of squares.\nSnuke is painting these squares in colors 1, 2, ..., N.\nHere, the following conditions should be satisfied:\n\nFor each i (1 ≤ i ≤ N), there are exactly a_i squares painted in Color i. Here, a_1 + a_2 + ... + a_N = H W.\n\nFor each i (1 ≤ i ≤ N), the squares painted in Color i are 4-connected. That is, every square painted in Color i can be reached from every square painted in Color i by repeatedly traveling to a horizontally or vertically adjacent square painted in Color i.\n\nFind a way to paint the squares so that the conditions are satisfied.\nIt can be shown that a solution always exists.\n\nConstraints\n\n1 ≤ H, W ≤ 100\n\n1 ≤ N ≤ H W\n\na_i ≥ 1\n\na_1 + a_2 + ... + a_N = H W\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W\nN\na_1 a_2 ... a_N\n\nOutput\n\nPrint one way to paint the squares that satisfies the conditions.\nOutput in the following format:\n\nc_{1 1} ... c_{1 W}\n:\nc_{H 1} ... c_{H W}\n\nHere, c_{i j} is the color of the square at the i-th row from the top and j-th column from the left.\n\nSample Input 1\n\n2 2\n3\n2 1 1\n\nSample Output 1\n\n1 1\n2 3\n\nBelow is an example of an invalid solution:\n\n1 2\n3 1\n\nThis is because the squares painted in Color 1 are not 4-connected.\n\nSample Input 2\n\n3 5\n5\n1 2 3 4 5\n\nSample Output 2\n\n1 4 4 4 3\n2 5 4 5 3\n2 5 5 5 3\n\nSample Input 3\n\n1 1\n1\n1\n\nSample Output 3\n\n1", "sample_input": "2 2\n3\n2 1 1\n"}, "reference_outputs": ["1 1\n2 3\n"], "source_document_id": "p03640", "source_text": "Score : 400 points\n\nProblem Statement\n\nWe have a grid with H rows and W columns of squares.\nSnuke is painting these squares in colors 1, 2, ..., N.\nHere, the following conditions should be satisfied:\n\nFor each i (1 ≤ i ≤ N), there are exactly a_i squares painted in Color i. Here, a_1 + a_2 + ... + a_N = H W.\n\nFor each i (1 ≤ i ≤ N), the squares painted in Color i are 4-connected. That is, every square painted in Color i can be reached from every square painted in Color i by repeatedly traveling to a horizontally or vertically adjacent square painted in Color i.\n\nFind a way to paint the squares so that the conditions are satisfied.\nIt can be shown that a solution always exists.\n\nConstraints\n\n1 ≤ H, W ≤ 100\n\n1 ≤ N ≤ H W\n\na_i ≥ 1\n\na_1 + a_2 + ... + a_N = H W\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W\nN\na_1 a_2 ... a_N\n\nOutput\n\nPrint one way to paint the squares that satisfies the conditions.\nOutput in the following format:\n\nc_{1 1} ... c_{1 W}\n:\nc_{H 1} ... c_{H W}\n\nHere, c_{i j} is the color of the square at the i-th row from the top and j-th column from the left.\n\nSample Input 1\n\n2 2\n3\n2 1 1\n\nSample Output 1\n\n1 1\n2 3\n\nBelow is an example of an invalid solution:\n\n1 2\n3 1\n\nThis is because the squares painted in Color 1 are not 4-connected.\n\nSample Input 2\n\n3 5\n5\n1 2 3 4 5\n\nSample Output 2\n\n1 4 4 4 3\n2 5 4 5 3\n2 5 5 5 3\n\nSample Input 3\n\n1 1\n1\n1\n\nSample Output 3\n\n1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 4740, "cpu_time_ms": 14, "memory_kb": 3736}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s471031838", "group_id": "codeNet:p03640", "input_text": "#include <bits/stdc++.h>\n#include <climits>\n#include <sstream>\nusing namespace std;\n\nint main(){\n    int H,W;\n    cin >> H >> W;\n    int N;\n    cin >> N;\n    int A[H][W];\n    int a;\n    int from = 0;\n    int to = 0;\n    for(int i = 1; i <= N;i++){\n        from = to;\n        cin >> a;\n        to += a;\n        for(int j = from; j < to;j++){\n            \n            if((j/W)%2==0)A[j/W][j%W] = i;\n            else A[j/W][N-j%W - 1] = i;\n        }\n\n    }\n    \n    for(int i = 0; i < H;i++){\n        for(int j = 0; j < W;j++){\n            if(j == W-1)cout << A[i][j];\n            else cout << A[i][j] <<\" \";\n        }\n        cout << endl;\n    }\n}\n\n", "language": "C++", "metadata": {"date": 1590705499, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03640.html", "problem_id": "p03640", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03640/input.txt", "sample_output_relpath": "derived/input_output/data/p03640/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03640/C++/s471031838.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s471031838", "user_id": "u945452839"}, "prompt_components": {"gold_output": "1 1\n2 3\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#include <climits>\n#include <sstream>\nusing namespace std;\n\nint main(){\n    int H,W;\n    cin >> H >> W;\n    int N;\n    cin >> N;\n    int A[H][W];\n    int a;\n    int from = 0;\n    int to = 0;\n    for(int i = 1; i <= N;i++){\n        from = to;\n        cin >> a;\n        to += a;\n        for(int j = from; j < to;j++){\n            \n            if((j/W)%2==0)A[j/W][j%W] = i;\n            else A[j/W][N-j%W - 1] = i;\n        }\n\n    }\n    \n    for(int i = 0; i < H;i++){\n        for(int j = 0; j < W;j++){\n            if(j == W-1)cout << A[i][j];\n            else cout << A[i][j] <<\" \";\n        }\n        cout << endl;\n    }\n}\n\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nWe have a grid with H rows and W columns of squares.\nSnuke is painting these squares in colors 1, 2, ..., N.\nHere, the following conditions should be satisfied:\n\nFor each i (1 ≤ i ≤ N), there are exactly a_i squares painted in Color i. Here, a_1 + a_2 + ... + a_N = H W.\n\nFor each i (1 ≤ i ≤ N), the squares painted in Color i are 4-connected. That is, every square painted in Color i can be reached from every square painted in Color i by repeatedly traveling to a horizontally or vertically adjacent square painted in Color i.\n\nFind a way to paint the squares so that the conditions are satisfied.\nIt can be shown that a solution always exists.\n\nConstraints\n\n1 ≤ H, W ≤ 100\n\n1 ≤ N ≤ H W\n\na_i ≥ 1\n\na_1 + a_2 + ... + a_N = H W\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W\nN\na_1 a_2 ... a_N\n\nOutput\n\nPrint one way to paint the squares that satisfies the conditions.\nOutput in the following format:\n\nc_{1 1} ... c_{1 W}\n:\nc_{H 1} ... c_{H W}\n\nHere, c_{i j} is the color of the square at the i-th row from the top and j-th column from the left.\n\nSample Input 1\n\n2 2\n3\n2 1 1\n\nSample Output 1\n\n1 1\n2 3\n\nBelow is an example of an invalid solution:\n\n1 2\n3 1\n\nThis is because the squares painted in Color 1 are not 4-connected.\n\nSample Input 2\n\n3 5\n5\n1 2 3 4 5\n\nSample Output 2\n\n1 4 4 4 3\n2 5 4 5 3\n2 5 5 5 3\n\nSample Input 3\n\n1 1\n1\n1\n\nSample Output 3\n\n1", "sample_input": "2 2\n3\n2 1 1\n"}, "reference_outputs": ["1 1\n2 3\n"], "source_document_id": "p03640", "source_text": "Score : 400 points\n\nProblem Statement\n\nWe have a grid with H rows and W columns of squares.\nSnuke is painting these squares in colors 1, 2, ..., N.\nHere, the following conditions should be satisfied:\n\nFor each i (1 ≤ i ≤ N), there are exactly a_i squares painted in Color i. Here, a_1 + a_2 + ... + a_N = H W.\n\nFor each i (1 ≤ i ≤ N), the squares painted in Color i are 4-connected. That is, every square painted in Color i can be reached from every square painted in Color i by repeatedly traveling to a horizontally or vertically adjacent square painted in Color i.\n\nFind a way to paint the squares so that the conditions are satisfied.\nIt can be shown that a solution always exists.\n\nConstraints\n\n1 ≤ H, W ≤ 100\n\n1 ≤ N ≤ H W\n\na_i ≥ 1\n\na_1 + a_2 + ... + a_N = H W\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W\nN\na_1 a_2 ... a_N\n\nOutput\n\nPrint one way to paint the squares that satisfies the conditions.\nOutput in the following format:\n\nc_{1 1} ... c_{1 W}\n:\nc_{H 1} ... c_{H W}\n\nHere, c_{i j} is the color of the square at the i-th row from the top and j-th column from the left.\n\nSample Input 1\n\n2 2\n3\n2 1 1\n\nSample Output 1\n\n1 1\n2 3\n\nBelow is an example of an invalid solution:\n\n1 2\n3 1\n\nThis is because the squares painted in Color 1 are not 4-connected.\n\nSample Input 2\n\n3 5\n5\n1 2 3 4 5\n\nSample Output 2\n\n1 4 4 4 3\n2 5 4 5 3\n2 5 5 5 3\n\nSample Input 3\n\n1 1\n1\n1\n\nSample Output 3\n\n1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 647, "cpu_time_ms": 98, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s104745031", "group_id": "codeNet:p03643", "input_text": "#include<iostream>\n#include<cmath>\n\nusing namespace std;\n\nint main() {\nint N;\ncin >> N;\n\nint i = pow(2, static_cast<int>(log(N)));\n\ncout  << i << endl;\n\nreturn 0;\n}", "language": "C++", "metadata": {"date": 1502383061, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03643.html", "problem_id": "p03643", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03643/input.txt", "sample_output_relpath": "derived/input_output/data/p03643/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03643/C++/s104745031.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s104745031", "user_id": "u223575057"}, "prompt_components": {"gold_output": "ABC100\n", "input_to_evaluate": "#include<iostream>\n#include<cmath>\n\nusing namespace std;\n\nint main() {\nint N;\ncin >> N;\n\nint i = pow(2, static_cast<int>(log(N)));\n\ncout  << i << endl;\n\nreturn 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nThis contest, AtCoder Beginner Contest, is abbreviated as ABC.\n\nWhen we refer to a specific round of ABC, a three-digit number is appended after ABC. For example, ABC680 is the 680th round of ABC.\n\nWhat is the abbreviation for the N-th round of ABC? Write a program to output the answer.\n\nConstraints\n\n100 ≤ N ≤ 999\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the abbreviation for the N-th round of ABC.\n\nSample Input 1\n\n100\n\nSample Output 1\n\nABC100\n\nThe 100th round of ABC is ABC100.\n\nSample Input 2\n\n425\n\nSample Output 2\n\nABC425\n\nSample Input 3\n\n999\n\nSample Output 3\n\nABC999", "sample_input": "100\n"}, "reference_outputs": ["ABC100\n"], "source_document_id": "p03643", "source_text": "Score : 100 points\n\nProblem Statement\n\nThis contest, AtCoder Beginner Contest, is abbreviated as ABC.\n\nWhen we refer to a specific round of ABC, a three-digit number is appended after ABC. For example, ABC680 is the 680th round of ABC.\n\nWhat is the abbreviation for the N-th round of ABC? Write a program to output the answer.\n\nConstraints\n\n100 ≤ N ≤ 999\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the abbreviation for the N-th round of ABC.\n\nSample Input 1\n\n100\n\nSample Output 1\n\nABC100\n\nThe 100th round of ABC is ABC100.\n\nSample Input 2\n\n425\n\nSample Output 2\n\nABC425\n\nSample Input 3\n\n999\n\nSample Output 3\n\nABC999", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 164, "cpu_time_ms": 5, "memory_kb": 512}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s923588519", "group_id": "codeNet:p03644", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nint main() {\n  int two[7] = {1, 2, 4, 8, 16, 32, 64};\n  int N, res;\n  cin >> N;\n  for(int i = 0; i < 7; i++) {\n    if(two[i] <= N) res = two[i];\n  }\n  cout << res << endl;\n}", "language": "C++", "metadata": {"date": 1599168386, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03644.html", "problem_id": "p03644", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03644/input.txt", "sample_output_relpath": "derived/input_output/data/p03644/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03644/C++/s923588519.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s923588519", "user_id": "u222443391"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nint main() {\n  int two[7] = {1, 2, 4, 8, 16, 32, 64};\n  int N, res;\n  cin >> N;\n  for(int i = 0; i < 7; i++) {\n    if(two[i] <= N) res = two[i];\n  }\n  cout << res << endl;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nTakahashi loves numbers divisible by 2.\n\nYou are given a positive integer N. Among the integers between 1 and N (inclusive), find the one that can be divisible by 2 for the most number of times. The solution is always unique.\n\nHere, the number of times an integer can be divisible by 2, is how many times the integer can be divided by 2 without remainder.\n\nFor example,\n\n6 can be divided by 2 once: 6 -> 3.\n\n8 can be divided by 2 three times: 8 -> 4 -> 2 -> 1.\n\n3 can be divided by 2 zero times.\n\nConstraints\n\n1 ≤ N ≤ 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n7\n\nSample Output 1\n\n4\n\n4 can be divided by 2 twice, which is the most number of times among 1, 2, ..., 7.\n\nSample Input 2\n\n32\n\nSample Output 2\n\n32\n\nSample Input 3\n\n1\n\nSample Output 3\n\n1\n\nSample Input 4\n\n100\n\nSample Output 4\n\n64", "sample_input": "7\n"}, "reference_outputs": ["4\n"], "source_document_id": "p03644", "source_text": "Score : 200 points\n\nProblem Statement\n\nTakahashi loves numbers divisible by 2.\n\nYou are given a positive integer N. Among the integers between 1 and N (inclusive), find the one that can be divisible by 2 for the most number of times. The solution is always unique.\n\nHere, the number of times an integer can be divisible by 2, is how many times the integer can be divided by 2 without remainder.\n\nFor example,\n\n6 can be divided by 2 once: 6 -> 3.\n\n8 can be divided by 2 three times: 8 -> 4 -> 2 -> 1.\n\n3 can be divided by 2 zero times.\n\nConstraints\n\n1 ≤ N ≤ 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n7\n\nSample Output 1\n\n4\n\n4 can be divided by 2 twice, which is the most number of times among 1, 2, ..., 7.\n\nSample Input 2\n\n32\n\nSample Output 2\n\n32\n\nSample Input 3\n\n1\n\nSample Output 3\n\n1\n\nSample Input 4\n\n100\n\nSample Output 4\n\n64", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 218, "cpu_time_ms": 5, "memory_kb": 3548}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s819860065", "group_id": "codeNet:p03644", "input_text": "#include <bits/stdc++.h>\n\nusing namespace std;\n\ntypedef long long ll;\n\nconst int INF = 1e9;\nconst ll LLINF = 1e18;\nconst ll MOD = (ll)1e9 + 7;\n\nint main()\n{\n  int N; scanf(\"%d\", &N);\n  int ans = 1;\n  while (ans * 2 <= N) { ans *= 2; }\n  printf(\"%d\\n\", ans);\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1539315695, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03644.html", "problem_id": "p03644", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03644/input.txt", "sample_output_relpath": "derived/input_output/data/p03644/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03644/C++/s819860065.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s819860065", "user_id": "u105155351"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\nusing namespace std;\n\ntypedef long long ll;\n\nconst int INF = 1e9;\nconst ll LLINF = 1e18;\nconst ll MOD = (ll)1e9 + 7;\n\nint main()\n{\n  int N; scanf(\"%d\", &N);\n  int ans = 1;\n  while (ans * 2 <= N) { ans *= 2; }\n  printf(\"%d\\n\", ans);\n  return 0;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nTakahashi loves numbers divisible by 2.\n\nYou are given a positive integer N. Among the integers between 1 and N (inclusive), find the one that can be divisible by 2 for the most number of times. The solution is always unique.\n\nHere, the number of times an integer can be divisible by 2, is how many times the integer can be divided by 2 without remainder.\n\nFor example,\n\n6 can be divided by 2 once: 6 -> 3.\n\n8 can be divided by 2 three times: 8 -> 4 -> 2 -> 1.\n\n3 can be divided by 2 zero times.\n\nConstraints\n\n1 ≤ N ≤ 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n7\n\nSample Output 1\n\n4\n\n4 can be divided by 2 twice, which is the most number of times among 1, 2, ..., 7.\n\nSample Input 2\n\n32\n\nSample Output 2\n\n32\n\nSample Input 3\n\n1\n\nSample Output 3\n\n1\n\nSample Input 4\n\n100\n\nSample Output 4\n\n64", "sample_input": "7\n"}, "reference_outputs": ["4\n"], "source_document_id": "p03644", "source_text": "Score : 200 points\n\nProblem Statement\n\nTakahashi loves numbers divisible by 2.\n\nYou are given a positive integer N. Among the integers between 1 and N (inclusive), find the one that can be divisible by 2 for the most number of times. The solution is always unique.\n\nHere, the number of times an integer can be divisible by 2, is how many times the integer can be divided by 2 without remainder.\n\nFor example,\n\n6 can be divided by 2 once: 6 -> 3.\n\n8 can be divided by 2 three times: 8 -> 4 -> 2 -> 1.\n\n3 can be divided by 2 zero times.\n\nConstraints\n\n1 ≤ N ≤ 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n7\n\nSample Output 1\n\n4\n\n4 can be divided by 2 twice, which is the most number of times among 1, 2, ..., 7.\n\nSample Input 2\n\n32\n\nSample Output 2\n\n32\n\nSample Input 3\n\n1\n\nSample Output 3\n\n1\n\nSample Input 4\n\n100\n\nSample Output 4\n\n64", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 272, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s108731380", "group_id": "codeNet:p03646", "input_text": "#include <bits/stdc++.h>\ntypedef long long int lint;\n\n#define PI acos(-1)\n#define INF64 1LL << 60\n#define INF32 1 << 29\n#define all(a) (a).begin(), (a).end()\n#define INV ((long long int)1000000007)\n\nusing namespace std;\n\nvoid execute()\n{\n\tlint N;\n\tcin >> N;\n\tvector<lint> data(50, N / 50 + 49);\n\n\tfor (int i = 0; i < 50; i++)\n\t{\n\t\tif (i < N % 50)\n\t\t\tdata[i] += 1;\n\t\telse\n\t\t\tdata[i] -= N % 50;\n\t}\n\n\tcout << 50 << endl;\n\n\tfor (auto out : data)\n\t{\n\t\tcout << out << \" \";\n\t}\n\tcout << endl;\n\treturn;\n}\n\nint main()\n{\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\tstd::cout << std::fixed << std::setprecision(15);\n\texecute();\n\n\tint stop;\n\tcin >> stop;\n\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1582794384, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03646.html", "problem_id": "p03646", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03646/input.txt", "sample_output_relpath": "derived/input_output/data/p03646/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03646/C++/s108731380.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s108731380", "user_id": "u874525170"}, "prompt_components": {"gold_output": "4\n3 3 3 3\n", "input_to_evaluate": "#include <bits/stdc++.h>\ntypedef long long int lint;\n\n#define PI acos(-1)\n#define INF64 1LL << 60\n#define INF32 1 << 29\n#define all(a) (a).begin(), (a).end()\n#define INV ((long long int)1000000007)\n\nusing namespace std;\n\nvoid execute()\n{\n\tlint N;\n\tcin >> N;\n\tvector<lint> data(50, N / 50 + 49);\n\n\tfor (int i = 0; i < 50; i++)\n\t{\n\t\tif (i < N % 50)\n\t\t\tdata[i] += 1;\n\t\telse\n\t\t\tdata[i] -= N % 50;\n\t}\n\n\tcout << 50 << endl;\n\n\tfor (auto out : data)\n\t{\n\t\tcout << out << \" \";\n\t}\n\tcout << endl;\n\treturn;\n}\n\nint main()\n{\n\tcin.tie(0);\n\tios_base::sync_with_stdio(false);\n\tstd::cout << std::fixed << std::setprecision(15);\n\texecute();\n\n\tint stop;\n\tcin >> stop;\n\n\treturn 0;\n}", "problem_context": "Score : 600 points\n\nProblem Statement\n\nWe have a sequence of length N consisting of non-negative integers. Consider performing the following operation on this sequence until the largest element in this sequence becomes N-1 or smaller.\n\nDetermine the largest element in the sequence (if there is more than one, choose one). Decrease the value of this element by N, and increase each of the other elements by 1.\n\nIt can be proved that the largest element in the sequence becomes N-1 or smaller after a finite number of operations.\n\nYou are given an integer K. Find an integer sequence a_i such that the number of times we will perform the above operation is exactly K. It can be shown that there is always such a sequence under the constraints on input and output in this problem.\n\nConstraints\n\n0 ≤ K ≤ 50 \\times 10^{16}\n\nInput\n\nInput is given from Standard Input in the following format:\n\nK\n\nOutput\n\nPrint a solution in the following format:\n\nN\na_1 a_2 ... a_N\n\nHere, 2 ≤ N ≤ 50 and 0 ≤ a_i ≤ 10^{16} + 1000 must hold.\n\nSample Input 1\n\n0\n\nSample Output 1\n\n4\n3 3 3 3\n\nSample Input 2\n\n1\n\nSample Output 2\n\n3\n1 0 3\n\nSample Input 3\n\n2\n\nSample Output 3\n\n2\n2 2\n\nThe operation will be performed twice: [2, 2] -> [0, 3] -> [1, 1].\n\nSample Input 4\n\n3\n\nSample Output 4\n\n7\n27 0 0 0 0 0 0\n\nSample Input 5\n\n1234567894848\n\nSample Output 5\n\n10\n1000 193 256 777 0 1 1192 1234567891011 48 425", "sample_input": "0\n"}, "reference_outputs": ["4\n3 3 3 3\n"], "source_document_id": "p03646", "source_text": "Score : 600 points\n\nProblem Statement\n\nWe have a sequence of length N consisting of non-negative integers. Consider performing the following operation on this sequence until the largest element in this sequence becomes N-1 or smaller.\n\nDetermine the largest element in the sequence (if there is more than one, choose one). Decrease the value of this element by N, and increase each of the other elements by 1.\n\nIt can be proved that the largest element in the sequence becomes N-1 or smaller after a finite number of operations.\n\nYou are given an integer K. Find an integer sequence a_i such that the number of times we will perform the above operation is exactly K. It can be shown that there is always such a sequence under the constraints on input and output in this problem.\n\nConstraints\n\n0 ≤ K ≤ 50 \\times 10^{16}\n\nInput\n\nInput is given from Standard Input in the following format:\n\nK\n\nOutput\n\nPrint a solution in the following format:\n\nN\na_1 a_2 ... a_N\n\nHere, 2 ≤ N ≤ 50 and 0 ≤ a_i ≤ 10^{16} + 1000 must hold.\n\nSample Input 1\n\n0\n\nSample Output 1\n\n4\n3 3 3 3\n\nSample Input 2\n\n1\n\nSample Output 2\n\n3\n1 0 3\n\nSample Input 3\n\n2\n\nSample Output 3\n\n2\n2 2\n\nThe operation will be performed twice: [2, 2] -> [0, 3] -> [1, 1].\n\nSample Input 4\n\n3\n\nSample Output 4\n\n7\n27 0 0 0 0 0 0\n\nSample Input 5\n\n1234567894848\n\nSample Output 5\n\n10\n1000 193 256 777 0 1 1192 1234567891011 48 425", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 660, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s739408861", "group_id": "codeNet:p03646", "input_text": "#include<set>\n#include<map>\n#include<stack>\n#include<queue>\n#include<deque>\n#include<cstdio>\n#include<string>\n#include<vector>\n#include<math.h>\n#include<time.h>\n#include<utility>\n#include<cstdlib>\n#include<sstream>\n#include<cstring>\n#include<stdio.h>\n#include<iomanip>\n#include<iostream>\n#include<algorithm>\nusing namespace std;\nunsigned long k;\nint main(){\n\tcin>>k;\n    unsigned long k1=k-1;\n    for(unsigned long i=0;i<k;i++){\n    \tcout<<k1<<\" \";\n\t}\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1501381853, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03646.html", "problem_id": "p03646", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03646/input.txt", "sample_output_relpath": "derived/input_output/data/p03646/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03646/C++/s739408861.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s739408861", "user_id": "u904221771"}, "prompt_components": {"gold_output": "4\n3 3 3 3\n", "input_to_evaluate": "#include<set>\n#include<map>\n#include<stack>\n#include<queue>\n#include<deque>\n#include<cstdio>\n#include<string>\n#include<vector>\n#include<math.h>\n#include<time.h>\n#include<utility>\n#include<cstdlib>\n#include<sstream>\n#include<cstring>\n#include<stdio.h>\n#include<iomanip>\n#include<iostream>\n#include<algorithm>\nusing namespace std;\nunsigned long k;\nint main(){\n\tcin>>k;\n    unsigned long k1=k-1;\n    for(unsigned long i=0;i<k;i++){\n    \tcout<<k1<<\" \";\n\t}\n\treturn 0;\n}", "problem_context": "Score : 600 points\n\nProblem Statement\n\nWe have a sequence of length N consisting of non-negative integers. Consider performing the following operation on this sequence until the largest element in this sequence becomes N-1 or smaller.\n\nDetermine the largest element in the sequence (if there is more than one, choose one). Decrease the value of this element by N, and increase each of the other elements by 1.\n\nIt can be proved that the largest element in the sequence becomes N-1 or smaller after a finite number of operations.\n\nYou are given an integer K. Find an integer sequence a_i such that the number of times we will perform the above operation is exactly K. It can be shown that there is always such a sequence under the constraints on input and output in this problem.\n\nConstraints\n\n0 ≤ K ≤ 50 \\times 10^{16}\n\nInput\n\nInput is given from Standard Input in the following format:\n\nK\n\nOutput\n\nPrint a solution in the following format:\n\nN\na_1 a_2 ... a_N\n\nHere, 2 ≤ N ≤ 50 and 0 ≤ a_i ≤ 10^{16} + 1000 must hold.\n\nSample Input 1\n\n0\n\nSample Output 1\n\n4\n3 3 3 3\n\nSample Input 2\n\n1\n\nSample Output 2\n\n3\n1 0 3\n\nSample Input 3\n\n2\n\nSample Output 3\n\n2\n2 2\n\nThe operation will be performed twice: [2, 2] -> [0, 3] -> [1, 1].\n\nSample Input 4\n\n3\n\nSample Output 4\n\n7\n27 0 0 0 0 0 0\n\nSample Input 5\n\n1234567894848\n\nSample Output 5\n\n10\n1000 193 256 777 0 1 1192 1234567891011 48 425", "sample_input": "0\n"}, "reference_outputs": ["4\n3 3 3 3\n"], "source_document_id": "p03646", "source_text": "Score : 600 points\n\nProblem Statement\n\nWe have a sequence of length N consisting of non-negative integers. Consider performing the following operation on this sequence until the largest element in this sequence becomes N-1 or smaller.\n\nDetermine the largest element in the sequence (if there is more than one, choose one). Decrease the value of this element by N, and increase each of the other elements by 1.\n\nIt can be proved that the largest element in the sequence becomes N-1 or smaller after a finite number of operations.\n\nYou are given an integer K. Find an integer sequence a_i such that the number of times we will perform the above operation is exactly K. It can be shown that there is always such a sequence under the constraints on input and output in this problem.\n\nConstraints\n\n0 ≤ K ≤ 50 \\times 10^{16}\n\nInput\n\nInput is given from Standard Input in the following format:\n\nK\n\nOutput\n\nPrint a solution in the following format:\n\nN\na_1 a_2 ... a_N\n\nHere, 2 ≤ N ≤ 50 and 0 ≤ a_i ≤ 10^{16} + 1000 must hold.\n\nSample Input 1\n\n0\n\nSample Output 1\n\n4\n3 3 3 3\n\nSample Input 2\n\n1\n\nSample Output 2\n\n3\n1 0 3\n\nSample Input 3\n\n2\n\nSample Output 3\n\n2\n2 2\n\nThe operation will be performed twice: [2, 2] -> [0, 3] -> [1, 1].\n\nSample Input 4\n\n3\n\nSample Output 4\n\n7\n27 0 0 0 0 0 0\n\nSample Input 5\n\n1234567894848\n\nSample Output 5\n\n10\n1000 193 256 777 0 1 1192 1234567891011 48 425", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 464, "cpu_time_ms": 1207, "memory_kb": 131328}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s913235160", "group_id": "codeNet:p03648", "input_text": "#include <bits/stdc++.h>\n\nusing namespace std;\n#define X first\n#define Y second\ntypedef long long ll;\ntypedef pair<int, int> pii;\ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\n\n#define debug(x) cerr << #x << \" = \" << (x) << endl;\ntemplate<typename T>\nostream& operator<<(ostream& o, vector<T>& v) {\n    for (auto& x : v) o << x << ' ';\n    return o;\n}\n\nint main(){\n    std::ios_base::sync_with_stdio(false); cin.tie(0);\n    ll k; cin >> k;\n    ll p = k / 50, q = k % 50;\n    vector<ll> arr(50, 49 + p);\n    for (int i = 0; i < q; i++){\n        arr[i] += 1;\n    }\n    for (int i = q; i < 50; i++){\n        arr[i] -= q;\n    }\n    for (int i = 0; i < 50; i++)\n        cout << arr[i] <<  ' ';\n    cout << endl;\n}\n", "language": "C++", "metadata": {"date": 1501381347, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03648.html", "problem_id": "p03648", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03648/input.txt", "sample_output_relpath": "derived/input_output/data/p03648/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03648/C++/s913235160.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s913235160", "user_id": "u115464345"}, "prompt_components": {"gold_output": "4\n3 3 3 3\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\nusing namespace std;\n#define X first\n#define Y second\ntypedef long long ll;\ntypedef pair<int, int> pii;\ntypedef vector<int> vi;\ntypedef vector<vi> vvi;\n\n#define debug(x) cerr << #x << \" = \" << (x) << endl;\ntemplate<typename T>\nostream& operator<<(ostream& o, vector<T>& v) {\n    for (auto& x : v) o << x << ' ';\n    return o;\n}\n\nint main(){\n    std::ios_base::sync_with_stdio(false); cin.tie(0);\n    ll k; cin >> k;\n    ll p = k / 50, q = k % 50;\n    vector<ll> arr(50, 49 + p);\n    for (int i = 0; i < q; i++){\n        arr[i] += 1;\n    }\n    for (int i = q; i < 50; i++){\n        arr[i] -= q;\n    }\n    for (int i = 0; i < 50; i++)\n        cout << arr[i] <<  ' ';\n    cout << endl;\n}\n", "problem_context": "Score : 600 points\n\nProblem Statement\n\nWe have a sequence of length N consisting of non-negative integers. Consider performing the following operation on this sequence until the largest element in this sequence becomes N-1 or smaller.\n\nDetermine the largest element in the sequence (if there is more than one, choose one). Decrease the value of this element by N, and increase each of the other elements by 1.\n\nIt can be proved that the largest element in the sequence becomes N-1 or smaller after a finite number of operations.\n\nYou are given an integer K. Find an integer sequence a_i such that the number of times we will perform the above operation is exactly K. It can be shown that there is always such a sequence under the constraints on input and output in this problem.\n\nConstraints\n\n0 ≤ K ≤ 50 \\times 10^{16}\n\nInput\n\nInput is given from Standard Input in the following format:\n\nK\n\nOutput\n\nPrint a solution in the following format:\n\nN\na_1 a_2 ... a_N\n\nHere, 2 ≤ N ≤ 50 and 0 ≤ a_i ≤ 10^{16} + 1000 must hold.\n\nSample Input 1\n\n0\n\nSample Output 1\n\n4\n3 3 3 3\n\nSample Input 2\n\n1\n\nSample Output 2\n\n3\n1 0 3\n\nSample Input 3\n\n2\n\nSample Output 3\n\n2\n2 2\n\nThe operation will be performed twice: [2, 2] -> [0, 3] -> [1, 1].\n\nSample Input 4\n\n3\n\nSample Output 4\n\n7\n27 0 0 0 0 0 0\n\nSample Input 5\n\n1234567894848\n\nSample Output 5\n\n10\n1000 193 256 777 0 1 1192 1234567891011 48 425", "sample_input": "0\n"}, "reference_outputs": ["4\n3 3 3 3\n"], "source_document_id": "p03648", "source_text": "Score : 600 points\n\nProblem Statement\n\nWe have a sequence of length N consisting of non-negative integers. Consider performing the following operation on this sequence until the largest element in this sequence becomes N-1 or smaller.\n\nDetermine the largest element in the sequence (if there is more than one, choose one). Decrease the value of this element by N, and increase each of the other elements by 1.\n\nIt can be proved that the largest element in the sequence becomes N-1 or smaller after a finite number of operations.\n\nYou are given an integer K. Find an integer sequence a_i such that the number of times we will perform the above operation is exactly K. It can be shown that there is always such a sequence under the constraints on input and output in this problem.\n\nConstraints\n\n0 ≤ K ≤ 50 \\times 10^{16}\n\nInput\n\nInput is given from Standard Input in the following format:\n\nK\n\nOutput\n\nPrint a solution in the following format:\n\nN\na_1 a_2 ... a_N\n\nHere, 2 ≤ N ≤ 50 and 0 ≤ a_i ≤ 10^{16} + 1000 must hold.\n\nSample Input 1\n\n0\n\nSample Output 1\n\n4\n3 3 3 3\n\nSample Input 2\n\n1\n\nSample Output 2\n\n3\n1 0 3\n\nSample Input 3\n\n2\n\nSample Output 3\n\n2\n2 2\n\nThe operation will be performed twice: [2, 2] -> [0, 3] -> [1, 1].\n\nSample Input 4\n\n3\n\nSample Output 4\n\n7\n27 0 0 0 0 0 0\n\nSample Input 5\n\n1234567894848\n\nSample Output 5\n\n10\n1000 193 256 777 0 1 1192 1234567891011 48 425", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 711, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s861125711", "group_id": "codeNet:p03651", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (int64_t i = 0; i < (int64_t)(n); i++)\n\nint main(){\n    int n, k;\n    cin >> n >> k;\n    vector<int> a(n);\n    rep(i,n) cin >> a[i];\n    int amax = 0;\n    rep(i,n) amax = max(amax,a[i]);\n    int gcda = 0;\n    rep(i,n) gcda = __gcd(gcda,a[i]);\n    if(amax >= k && k%gcda == 0) cout << \"POSSIBLE\" << endl;\n    else cout << \"IMPOSSIBLE\" << endl;\n}", "language": "C++", "metadata": {"date": 1578257050, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03651.html", "problem_id": "p03651", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03651/input.txt", "sample_output_relpath": "derived/input_output/data/p03651/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03651/C++/s861125711.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s861125711", "user_id": "u366974105"}, "prompt_components": {"gold_output": "POSSIBLE\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n#define rep(i, n) for (int64_t i = 0; i < (int64_t)(n); i++)\n\nint main(){\n    int n, k;\n    cin >> n >> k;\n    vector<int> a(n);\n    rep(i,n) cin >> a[i];\n    int amax = 0;\n    rep(i,n) amax = max(amax,a[i]);\n    int gcda = 0;\n    rep(i,n) gcda = __gcd(gcda,a[i]);\n    if(amax >= k && k%gcda == 0) cout << \"POSSIBLE\" << endl;\n    else cout << \"IMPOSSIBLE\" << endl;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere is a box containing N balls. The i-th ball has the integer A_i written on it.\nSnuke can perform the following operation any number of times:\n\nTake out two balls from the box. Then, return them to the box along with a new ball, on which the absolute difference of the integers written on the two balls is written.\n\nDetermine whether it is possible for Snuke to reach the state where the box contains a ball on which the integer K is written.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq A_i \\leq 10^9\n\n1 \\leq K \\leq 10^9\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nA_1 A_2 ... A_N\n\nOutput\n\nIf it is possible for Snuke to reach the state where the box contains a ball on which the integer K is written, print POSSIBLE; if it is not possible, print IMPOSSIBLE.\n\nSample Input 1\n\n3 7\n9 3 4\n\nSample Output 1\n\nPOSSIBLE\n\nFirst, take out the two balls 9 and 4, and return them back along with a new ball, abs(9-4)=5.\nNext, take out 3 and 5, and return them back along with abs(3-5)=2.\nFinally, take out 9 and 2, and return them back along with abs(9-2)=7.\nNow we have 7 in the box, and the answer is therefore POSSIBLE.\n\nSample Input 2\n\n3 5\n6 9 3\n\nSample Output 2\n\nIMPOSSIBLE\n\nNo matter what we do, it is not possible to have 5 in the box. The answer is therefore IMPOSSIBLE.\n\nSample Input 3\n\n4 11\n11 3 7 15\n\nSample Output 3\n\nPOSSIBLE\n\nThe box already contains 11 before we do anything. The answer is therefore POSSIBLE.\n\nSample Input 4\n\n5 12\n10 2 8 6 4\n\nSample Output 4\n\nIMPOSSIBLE", "sample_input": "3 7\n9 3 4\n"}, "reference_outputs": ["POSSIBLE\n"], "source_document_id": "p03651", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere is a box containing N balls. The i-th ball has the integer A_i written on it.\nSnuke can perform the following operation any number of times:\n\nTake out two balls from the box. Then, return them to the box along with a new ball, on which the absolute difference of the integers written on the two balls is written.\n\nDetermine whether it is possible for Snuke to reach the state where the box contains a ball on which the integer K is written.\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq A_i \\leq 10^9\n\n1 \\leq K \\leq 10^9\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN K\nA_1 A_2 ... A_N\n\nOutput\n\nIf it is possible for Snuke to reach the state where the box contains a ball on which the integer K is written, print POSSIBLE; if it is not possible, print IMPOSSIBLE.\n\nSample Input 1\n\n3 7\n9 3 4\n\nSample Output 1\n\nPOSSIBLE\n\nFirst, take out the two balls 9 and 4, and return them back along with a new ball, abs(9-4)=5.\nNext, take out 3 and 5, and return them back along with abs(3-5)=2.\nFinally, take out 9 and 2, and return them back along with abs(9-2)=7.\nNow we have 7 in the box, and the answer is therefore POSSIBLE.\n\nSample Input 2\n\n3 5\n6 9 3\n\nSample Output 2\n\nIMPOSSIBLE\n\nNo matter what we do, it is not possible to have 5 in the box. The answer is therefore IMPOSSIBLE.\n\nSample Input 3\n\n4 11\n11 3 7 15\n\nSample Output 3\n\nPOSSIBLE\n\nThe box already contains 11 before we do anything. The answer is therefore POSSIBLE.\n\nSample Input 4\n\n5 12\n10 2 8 6 4\n\nSample Output 4\n\nIMPOSSIBLE", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 412, "cpu_time_ms": 41, "memory_kb": 640}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s583080345", "group_id": "codeNet:p03653", "input_text": "#include<bits/stdc++.h>\n//using namespace std;\n#pragma GCC target(\"avx\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n#define rep(i,j,n) for(ll i=(ll)(j);i<(ll)(n);i++)\n#define REP(i,j,n) for(ll i=(ll)(j);i<=(ll)(n);i++)\n#define per(i,j,n) for(ll i=(ll)(j);(ll)(n)<=i;i--)\n#define ll long long\n#define ALL(a) (a).begin(),(a).end()\n#define disup(A,key) distance(A.begin(),upper_bound(ALL(A),(ll)(key)))\n#define dislow(A,key) distance(A.begin(),lower_bound(ALL(A),(ll)(key)))\n#define pb emplace_back\n#define mp std::make_pair\n//\n#define endl \"\\n\"\n//using std::endl;\nusing std::cin;\nusing std::cout;\nusing std::vector;\nusing std::string;\nusing std::upper_bound;\nusing std::lower_bound;\nusing vi=vector<ll>;\nusing vii=vector<vi>;\nusing pii=std::pair<ll,ll>;\n//\nconstexpr ll MOD=1e9+7;\n//constexpr ll MOD=998244353; \n//constexpr ll MOD=10000000;\n//constexpr ll MOD=1e4;\nconstexpr ll MAX=3e6;\nconstexpr ll inf=(1ll<<60);\ntemplate<class T>\nclass prique :public std::priority_queue<T, std::vector<T>, std::greater<T>> {};\ntemplate<typename T>\nstruct Segment_tree{\n    ll N;\n    T mem;\n    vector<T> node;\n    Segment_tree(vector<T> &X,T m):mem(m){\n        ll sz=X.size();\n        N=1;\n        while(N<sz) N*=2;\n        node.resize(2*N-1,mem);\n        rep(i,0,sz) node[N-1+i]=X[i];\n        per(i,N-2,0){\n            node[i]=Compare(node[i*2+1],node[i*2+2]);\n        }\n    }\n    T Compare(T &A,T &B){\n        return std::max(A,B);\n    }\n    void update(ll X,T val){\n        X+=N-1;\n        node[X]=val;\n        while(X>0){\n            X=(X-1)/2;\n            node[X]=Compare(node[X*2+1],node[X*2+2]);\n        }\n    }\n    T Query(ll a,ll b,ll now,ll l,ll r){ //[a,b),[l,r)\n        if(r<0) r=N;\n        if(r<=a||b<=l) return mem;\n        if(a<=l&&r<=b) return node[now];\n        auto vl=Query(a,b,now*2+1,l,(l+r)/2),vr=Query(a,b,now*2+2,(l+r)/2,r);\n        return Compare(vl,vr);\n    }\n};\nstruct Tree{\n    int N;\n    vector<vector<int>> dp;\n    vector<int> dist;\n    Tree(vector<vector<int>> edge){\n        N=edge.size();\n        dp.resize(N);\n        dist.resize(N,-1);\n        for(int i=0;i<N;i++) dp[i].resize(30);\n        dist[0]=dp[0][0]=0;\n        std::queue<int> que;\n        que.push(0);\n        while(!que.empty()){\n            int now=que.front(); que.pop();\n            for(int i=0;i<edge[now].size();i++){\n                int next=edge[now][i];\n                if(dist[next]==-1){\n                    dist[next]=dist[now]+1;\n                    que.push(next);\n                    dp[next][0]=now;\n                }\n            }\n        }\n        for(int i=1;i<30;i++){\n            for(int j=0;j<N;j++) dp[j][i]=dp[dp[j][i-1]][i-1];\n        }\n    }\n    int LCA(int X,int Y){\n        if(dist[X]<dist[Y]) std::swap(X,Y);\n        {\n            int Z=dist[X]-dist[Y];\n            for(int i=0;i<30;i++){\n                if(Z&(1<<i)){\n                    X=dp[X][i];\n                }\n            }\n        }\n        if(X==Y) return X;\n        for(int i=29;i>=0;i--){\n            if(dp[X][i]!=dp[Y][i]){\n                X=dp[X][i];\n                Y=dp[Y][i];\n            }\n        }\n        return dp[X][0];\n    }\n};\nstruct Binary_indexed_tree{\n    int N;\n    vi bit;\n    Binary_indexed_tree(int n):N(n){\n        bit.resize(N+1,0);\n    }\n    void add(int x,ll a){\n        for(x;x<=N;x+=(x&-x)) bit[x]+=a;\n    }\n    ll sum(int x){\n        ll ret=0;\n        for(x;x>0;x-=(x&-x)) ret+=bit[x];\n        return ret;\n    }\n    ll lower_bound(ll X){\n        if(sum(N)<X) return -1;\n        ll ret=0,memo=1,sum=0;\n        while(memo*2<=N) memo*=2;\n        while(memo>0){\n            if(memo+ret<=N&&sum+bit[memo+ret]<X){\n                sum+=bit[memo+ret];\n                ret+=memo;\n            }\n            memo/=2;\n        }\n        return ret+1;\n    }\n};\nstruct Union_Find{\n    ll N;\n    vi par;\n    vi siz;\n    Union_Find(int n):N(n){\n        par.resize(N);\n        siz.resize(N,1);\n        rep(i,0,N) par[i]=i;\n    }\n    ll root(ll X){\n        if(par[X]==X) return X;\n        return par[X]=root(par[X]);\n    }\n    bool same(ll X,ll Y){\n        return root(X)==root(Y);\n    }\n    void unite(ll X,ll Y){\n        X=root(X);\n        Y=root(Y);\n        if(X==Y) return;\n        par[X]=Y;\n        siz[Y]+=siz[X];\n        siz[X]=0;\n    }\n    ll size(ll X){\n        return siz[root(X)];\n    }\n};\nlong long modpow(long long a, long long n, long long mod) {\n    long long res = 1;\n    while (n > 0) {\n        if (n & 1) res = res * a % mod;\n        a = a * a % mod;\n        n >>= 1;\n    }\n    return res;\n}\nvi fac,finv,inv;\nvoid COMinit() {\n    fac.resize(MAX);\n    finv.resize(MAX);\n    inv.resize(MAX);\n    fac[0] = fac[1] = 1;\n    finv[0] = finv[1] = 1;\n    inv[1] = 1;\n    for (int i = 2; i < MAX; i++){\n        fac[i] = fac[i - 1] * i % MOD;\n        inv[i] = MOD - inv[MOD%i] * (MOD / i) % MOD;\n        finv[i] = finv[i - 1] * inv[i] % MOD;\n    }\n}\nll COM(ll n,ll r){\n    if(n<r||n<0||r<0) return 0;\n    return fac[n]*finv[r]%MOD*finv[n-r]%MOD;\n}\nvoid comp(vi &A){\n    std::map<ll,ll> memo;\n    rep(i,0,A.size()) memo[A[i]]=0;\n    ll cnt=1;\n    for(auto &p:memo) p.second=cnt++;\n    rep(i,0,A.size()) A[i]=memo[A[i]];\n}\nint main(){\n    std::ios::sync_with_stdio(false);\n    std::cin.tie(nullptr);\n    vi A(3);\n    rep(i,0,3) cin>>A[i];\n    ll N=0;\n    rep(i,0,3) N+=A[i];\n    vii B(3,vi(N));\n    rep(i,0,N){\n        rep(j,0,3) cin>>B[j][i];\n    }\n    vi C={0,A[0],A[0]+A[1],N};\n    ll T=100;\n    while(T--){\n    vi D={0,1,2};\n    do{\n        rep(a,0,3){\n            rep(b,0,3){\n                ll i=D[a],j=D[b];\n                std::priority_queue<pii> que1,que2;\n                rep(k,0,N){\n                    if(C[i]<=k&&k<C[i+1]){\n                        que1.push(mp(B[j][k]-B[i][k],k));\n                    }\n                    if(C[j]<=k&&k<=C[j+1]){\n                        que2.push(mp(B[i][k]-B[j][k],k));\n                    }\n                }\n                while(1){\n                    auto p=que1.top(),q=que2.top();\n                    if(p.first+q.first<=0) break;\n                    que1.pop(),que2.pop();\n                    rep(k,0,3){\n                        std::swap(B[k][p.second],B[k][q.second]);\n                    }\n                    std::swap(p.first,q.first);\n                    p.first=-p.first;\n                    q.first=-q.first;\n                    que1.push(p);\n                    que2.push(q);\n                }\n            }\n        }\n    }while(next_permutation(ALL(D)));\n    }\n    ll ans=0;\n    rep(i,0,N){\n        rep(j,0,3){\n            if(C[j]<=i&&i<C[j+1]) ans+=B[j][i];\n        }\n    }\n    printf(\"%.lld\\n\",ans);\n}\n", "language": "C++", "metadata": {"date": 1596749516, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03653.html", "problem_id": "p03653", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03653/input.txt", "sample_output_relpath": "derived/input_output/data/p03653/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03653/C++/s583080345.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s583080345", "user_id": "u347057617"}, "prompt_components": {"gold_output": "18\n", "input_to_evaluate": "#include<bits/stdc++.h>\n//using namespace std;\n#pragma GCC target(\"avx\")\n#pragma GCC optimize(\"O3\")\n#pragma GCC optimize(\"unroll-loops\")\n#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n#define rep(i,j,n) for(ll i=(ll)(j);i<(ll)(n);i++)\n#define REP(i,j,n) for(ll i=(ll)(j);i<=(ll)(n);i++)\n#define per(i,j,n) for(ll i=(ll)(j);(ll)(n)<=i;i--)\n#define ll long long\n#define ALL(a) (a).begin(),(a).end()\n#define disup(A,key) distance(A.begin(),upper_bound(ALL(A),(ll)(key)))\n#define dislow(A,key) distance(A.begin(),lower_bound(ALL(A),(ll)(key)))\n#define pb emplace_back\n#define mp std::make_pair\n//\n#define endl \"\\n\"\n//using std::endl;\nusing std::cin;\nusing std::cout;\nusing std::vector;\nusing std::string;\nusing std::upper_bound;\nusing std::lower_bound;\nusing vi=vector<ll>;\nusing vii=vector<vi>;\nusing pii=std::pair<ll,ll>;\n//\nconstexpr ll MOD=1e9+7;\n//constexpr ll MOD=998244353; \n//constexpr ll MOD=10000000;\n//constexpr ll MOD=1e4;\nconstexpr ll MAX=3e6;\nconstexpr ll inf=(1ll<<60);\ntemplate<class T>\nclass prique :public std::priority_queue<T, std::vector<T>, std::greater<T>> {};\ntemplate<typename T>\nstruct Segment_tree{\n    ll N;\n    T mem;\n    vector<T> node;\n    Segment_tree(vector<T> &X,T m):mem(m){\n        ll sz=X.size();\n        N=1;\n        while(N<sz) N*=2;\n        node.resize(2*N-1,mem);\n        rep(i,0,sz) node[N-1+i]=X[i];\n        per(i,N-2,0){\n            node[i]=Compare(node[i*2+1],node[i*2+2]);\n        }\n    }\n    T Compare(T &A,T &B){\n        return std::max(A,B);\n    }\n    void update(ll X,T val){\n        X+=N-1;\n        node[X]=val;\n        while(X>0){\n            X=(X-1)/2;\n            node[X]=Compare(node[X*2+1],node[X*2+2]);\n        }\n    }\n    T Query(ll a,ll b,ll now,ll l,ll r){ //[a,b),[l,r)\n        if(r<0) r=N;\n        if(r<=a||b<=l) return mem;\n        if(a<=l&&r<=b) return node[now];\n        auto vl=Query(a,b,now*2+1,l,(l+r)/2),vr=Query(a,b,now*2+2,(l+r)/2,r);\n        return Compare(vl,vr);\n    }\n};\nstruct Tree{\n    int N;\n    vector<vector<int>> dp;\n    vector<int> dist;\n    Tree(vector<vector<int>> edge){\n        N=edge.size();\n        dp.resize(N);\n        dist.resize(N,-1);\n        for(int i=0;i<N;i++) dp[i].resize(30);\n        dist[0]=dp[0][0]=0;\n        std::queue<int> que;\n        que.push(0);\n        while(!que.empty()){\n            int now=que.front(); que.pop();\n            for(int i=0;i<edge[now].size();i++){\n                int next=edge[now][i];\n                if(dist[next]==-1){\n                    dist[next]=dist[now]+1;\n                    que.push(next);\n                    dp[next][0]=now;\n                }\n            }\n        }\n        for(int i=1;i<30;i++){\n            for(int j=0;j<N;j++) dp[j][i]=dp[dp[j][i-1]][i-1];\n        }\n    }\n    int LCA(int X,int Y){\n        if(dist[X]<dist[Y]) std::swap(X,Y);\n        {\n            int Z=dist[X]-dist[Y];\n            for(int i=0;i<30;i++){\n                if(Z&(1<<i)){\n                    X=dp[X][i];\n                }\n            }\n        }\n        if(X==Y) return X;\n        for(int i=29;i>=0;i--){\n            if(dp[X][i]!=dp[Y][i]){\n                X=dp[X][i];\n                Y=dp[Y][i];\n            }\n        }\n        return dp[X][0];\n    }\n};\nstruct Binary_indexed_tree{\n    int N;\n    vi bit;\n    Binary_indexed_tree(int n):N(n){\n        bit.resize(N+1,0);\n    }\n    void add(int x,ll a){\n        for(x;x<=N;x+=(x&-x)) bit[x]+=a;\n    }\n    ll sum(int x){\n        ll ret=0;\n        for(x;x>0;x-=(x&-x)) ret+=bit[x];\n        return ret;\n    }\n    ll lower_bound(ll X){\n        if(sum(N)<X) return -1;\n        ll ret=0,memo=1,sum=0;\n        while(memo*2<=N) memo*=2;\n        while(memo>0){\n            if(memo+ret<=N&&sum+bit[memo+ret]<X){\n                sum+=bit[memo+ret];\n                ret+=memo;\n            }\n            memo/=2;\n        }\n        return ret+1;\n    }\n};\nstruct Union_Find{\n    ll N;\n    vi par;\n    vi siz;\n    Union_Find(int n):N(n){\n        par.resize(N);\n        siz.resize(N,1);\n        rep(i,0,N) par[i]=i;\n    }\n    ll root(ll X){\n        if(par[X]==X) return X;\n        return par[X]=root(par[X]);\n    }\n    bool same(ll X,ll Y){\n        return root(X)==root(Y);\n    }\n    void unite(ll X,ll Y){\n        X=root(X);\n        Y=root(Y);\n        if(X==Y) return;\n        par[X]=Y;\n        siz[Y]+=siz[X];\n        siz[X]=0;\n    }\n    ll size(ll X){\n        return siz[root(X)];\n    }\n};\nlong long modpow(long long a, long long n, long long mod) {\n    long long res = 1;\n    while (n > 0) {\n        if (n & 1) res = res * a % mod;\n        a = a * a % mod;\n        n >>= 1;\n    }\n    return res;\n}\nvi fac,finv,inv;\nvoid COMinit() {\n    fac.resize(MAX);\n    finv.resize(MAX);\n    inv.resize(MAX);\n    fac[0] = fac[1] = 1;\n    finv[0] = finv[1] = 1;\n    inv[1] = 1;\n    for (int i = 2; i < MAX; i++){\n        fac[i] = fac[i - 1] * i % MOD;\n        inv[i] = MOD - inv[MOD%i] * (MOD / i) % MOD;\n        finv[i] = finv[i - 1] * inv[i] % MOD;\n    }\n}\nll COM(ll n,ll r){\n    if(n<r||n<0||r<0) return 0;\n    return fac[n]*finv[r]%MOD*finv[n-r]%MOD;\n}\nvoid comp(vi &A){\n    std::map<ll,ll> memo;\n    rep(i,0,A.size()) memo[A[i]]=0;\n    ll cnt=1;\n    for(auto &p:memo) p.second=cnt++;\n    rep(i,0,A.size()) A[i]=memo[A[i]];\n}\nint main(){\n    std::ios::sync_with_stdio(false);\n    std::cin.tie(nullptr);\n    vi A(3);\n    rep(i,0,3) cin>>A[i];\n    ll N=0;\n    rep(i,0,3) N+=A[i];\n    vii B(3,vi(N));\n    rep(i,0,N){\n        rep(j,0,3) cin>>B[j][i];\n    }\n    vi C={0,A[0],A[0]+A[1],N};\n    ll T=100;\n    while(T--){\n    vi D={0,1,2};\n    do{\n        rep(a,0,3){\n            rep(b,0,3){\n                ll i=D[a],j=D[b];\n                std::priority_queue<pii> que1,que2;\n                rep(k,0,N){\n                    if(C[i]<=k&&k<C[i+1]){\n                        que1.push(mp(B[j][k]-B[i][k],k));\n                    }\n                    if(C[j]<=k&&k<=C[j+1]){\n                        que2.push(mp(B[i][k]-B[j][k],k));\n                    }\n                }\n                while(1){\n                    auto p=que1.top(),q=que2.top();\n                    if(p.first+q.first<=0) break;\n                    que1.pop(),que2.pop();\n                    rep(k,0,3){\n                        std::swap(B[k][p.second],B[k][q.second]);\n                    }\n                    std::swap(p.first,q.first);\n                    p.first=-p.first;\n                    q.first=-q.first;\n                    que1.push(p);\n                    que2.push(q);\n                }\n            }\n        }\n    }while(next_permutation(ALL(D)));\n    }\n    ll ans=0;\n    rep(i,0,N){\n        rep(j,0,3){\n            if(C[j]<=i&&i<C[j+1]) ans+=B[j][i];\n        }\n    }\n    printf(\"%.lld\\n\",ans);\n}\n", "problem_context": "Score : 800 points\n\nProblem Statement\n\nThere are X+Y+Z people, conveniently numbered 1 through X+Y+Z.\nPerson i has A_i gold coins, B_i silver coins and C_i bronze coins.\n\nSnuke is thinking of getting gold coins from X of those people, silver coins from Y of the people and bronze coins from Z of the people.\nIt is not possible to get two or more different colors of coins from a single person.\nOn the other hand, a person will give all of his/her coins of the color specified by Snuke.\n\nSnuke would like to maximize the total number of coins of all colors he gets.\nFind the maximum possible number of coins.\n\nConstraints\n\n1 \\leq X\n\n1 \\leq Y\n\n1 \\leq Z\n\nX+Y+Z \\leq 10^5\n\n1 \\leq A_i \\leq 10^9\n\n1 \\leq B_i \\leq 10^9\n\n1 \\leq C_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX Y Z\nA_1 B_1 C_1\nA_2 B_2 C_2\n:\nA_{X+Y+Z} B_{X+Y+Z} C_{X+Y+Z}\n\nOutput\n\nPrint the maximum possible total number of coins of all colors he gets.\n\nSample Input 1\n\n1 2 1\n2 4 4\n3 2 1\n7 6 7\n5 2 3\n\nSample Output 1\n\n18\n\nGet silver coins from Person 1, silver coins from Person 2, bronze coins from Person 3 and gold coins from Person 4.\nIn this case, the total number of coins will be 4+2+7+5=18.\nIt is not possible to get 19 or more coins, and the answer is therefore 18.\n\nSample Input 2\n\n3 3 2\n16 17 1\n2 7 5\n2 16 12\n17 7 7\n13 2 10\n12 18 3\n16 15 19\n5 6 2\n\nSample Output 2\n\n110\n\nSample Input 3\n\n6 2 4\n33189 87907 277349742\n71616 46764 575306520\n8801 53151 327161251\n58589 4337 796697686\n66854 17565 289910583\n50598 35195 478112689\n13919 88414 103962455\n7953 69657 699253752\n44255 98144 468443709\n2332 42580 752437097\n39752 19060 845062869\n60126 74101 382963164\n\nSample Output 3\n\n3093929975", "sample_input": "1 2 1\n2 4 4\n3 2 1\n7 6 7\n5 2 3\n"}, "reference_outputs": ["18\n"], "source_document_id": "p03653", "source_text": "Score : 800 points\n\nProblem Statement\n\nThere are X+Y+Z people, conveniently numbered 1 through X+Y+Z.\nPerson i has A_i gold coins, B_i silver coins and C_i bronze coins.\n\nSnuke is thinking of getting gold coins from X of those people, silver coins from Y of the people and bronze coins from Z of the people.\nIt is not possible to get two or more different colors of coins from a single person.\nOn the other hand, a person will give all of his/her coins of the color specified by Snuke.\n\nSnuke would like to maximize the total number of coins of all colors he gets.\nFind the maximum possible number of coins.\n\nConstraints\n\n1 \\leq X\n\n1 \\leq Y\n\n1 \\leq Z\n\nX+Y+Z \\leq 10^5\n\n1 \\leq A_i \\leq 10^9\n\n1 \\leq B_i \\leq 10^9\n\n1 \\leq C_i \\leq 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX Y Z\nA_1 B_1 C_1\nA_2 B_2 C_2\n:\nA_{X+Y+Z} B_{X+Y+Z} C_{X+Y+Z}\n\nOutput\n\nPrint the maximum possible total number of coins of all colors he gets.\n\nSample Input 1\n\n1 2 1\n2 4 4\n3 2 1\n7 6 7\n5 2 3\n\nSample Output 1\n\n18\n\nGet silver coins from Person 1, silver coins from Person 2, bronze coins from Person 3 and gold coins from Person 4.\nIn this case, the total number of coins will be 4+2+7+5=18.\nIt is not possible to get 19 or more coins, and the answer is therefore 18.\n\nSample Input 2\n\n3 3 2\n16 17 1\n2 7 5\n2 16 12\n17 7 7\n13 2 10\n12 18 3\n16 15 19\n5 6 2\n\nSample Output 2\n\n110\n\nSample Input 3\n\n6 2 4\n33189 87907 277349742\n71616 46764 575306520\n8801 53151 327161251\n58589 4337 796697686\n66854 17565 289910583\n50598 35195 478112689\n13919 88414 103962455\n7953 69657 699253752\n44255 98144 468443709\n2332 42580 752437097\n39752 19060 845062869\n60126 74101 382963164\n\nSample Output 3\n\n3093929975", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 6654, "cpu_time_ms": 2205, "memory_kb": 10332}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s230314795", "group_id": "codeNet:p03657", "input_text": "#include <bits/stdc++.h>\n#define rep(i,n) for(int i = 0; i < (n); i++)\nusing namespace std;\nusing ll = long long;\n\nint main() {\n  \n  int a,b;\n  cin >> a >> b;\n  \n  if(a%3 == 0 || b%3 == 0 || (a+b) % 3 == 0) cout << \"Possible\" << endl;\n  else cout << \"Impossible\" << endl;\n  \n}\n", "language": "C++", "metadata": {"date": 1588128069, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03657.html", "problem_id": "p03657", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03657/input.txt", "sample_output_relpath": "derived/input_output/data/p03657/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03657/C++/s230314795.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s230314795", "user_id": "u717483569"}, "prompt_components": {"gold_output": "Possible\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define rep(i,n) for(int i = 0; i < (n); i++)\nusing namespace std;\nusing ll = long long;\n\nint main() {\n  \n  int a,b;\n  cin >> a >> b;\n  \n  if(a%3 == 0 || b%3 == 0 || (a+b) % 3 == 0) cout << \"Possible\" << endl;\n  else cout << \"Impossible\" << endl;\n  \n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nSnuke is giving cookies to his three goats.\n\nHe has two cookie tins. One contains A cookies, and the other contains B cookies. He can thus give A cookies, B cookies or A+B cookies to his goats (he cannot open the tins).\n\nYour task is to determine whether Snuke can give cookies to his three goats so that each of them can have the same number of cookies.\n\nConstraints\n\n1 \\leq A,B \\leq 100\n\nBoth A and B are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nIf it is possible to give cookies so that each of the three goats can have the same number of cookies, print Possible; otherwise, print Impossible.\n\nSample Input 1\n\n4 5\n\nSample Output 1\n\nPossible\n\nIf Snuke gives nine cookies, each of the three goats can have three cookies.\n\nSample Input 2\n\n1 1\n\nSample Output 2\n\nImpossible\n\nSince there are only two cookies, the three goats cannot have the same number of cookies no matter what Snuke gives to them.", "sample_input": "4 5\n"}, "reference_outputs": ["Possible\n"], "source_document_id": "p03657", "source_text": "Score : 100 points\n\nProblem Statement\n\nSnuke is giving cookies to his three goats.\n\nHe has two cookie tins. One contains A cookies, and the other contains B cookies. He can thus give A cookies, B cookies or A+B cookies to his goats (he cannot open the tins).\n\nYour task is to determine whether Snuke can give cookies to his three goats so that each of them can have the same number of cookies.\n\nConstraints\n\n1 \\leq A,B \\leq 100\n\nBoth A and B are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nIf it is possible to give cookies so that each of the three goats can have the same number of cookies, print Possible; otherwise, print Impossible.\n\nSample Input 1\n\n4 5\n\nSample Output 1\n\nPossible\n\nIf Snuke gives nine cookies, each of the three goats can have three cookies.\n\nSample Input 2\n\n1 1\n\nSample Output 2\n\nImpossible\n\nSince there are only two cookies, the three goats cannot have the same number of cookies no matter what Snuke gives to them.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 277, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s308521956", "group_id": "codeNet:p03659", "input_text": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <cmath>\n#include <functional>\n\nint main()\n{\n    long N;\n    std::cin >> N;\n    long a[200000]={};\n    for(long i=0; i<N; i++){\n        std::cin >> a[i];\n    }\n\n    long partial_sum[200000]={};\n    partial_sum[0]=a[0];\n    for(long i=1; i<N; i++){\n        partial_sum[i]=partial_sum[i-1]+a[i];\n    }\n\n    long result=partial_sum[N-1];\n    for(long i=0; i<N-1; i++){\n        if(abs(partial_sum[i]-(partial_sum[N-1]-partial_sum[i]))<result){\n            result=abs(partial_sum[i]-(partial_sum[N-1]-partial_sum[i]));\n        }else{\n            break;\n        }\n    }\n\n    std::cout << result << std::endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1565878037, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03659.html", "problem_id": "p03659", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03659/input.txt", "sample_output_relpath": "derived/input_output/data/p03659/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03659/C++/s308521956.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s308521956", "user_id": "u329731898"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <cmath>\n#include <functional>\n\nint main()\n{\n    long N;\n    std::cin >> N;\n    long a[200000]={};\n    for(long i=0; i<N; i++){\n        std::cin >> a[i];\n    }\n\n    long partial_sum[200000]={};\n    partial_sum[0]=a[0];\n    for(long i=1; i<N; i++){\n        partial_sum[i]=partial_sum[i-1]+a[i];\n    }\n\n    long result=partial_sum[N-1];\n    for(long i=0; i<N-1; i++){\n        if(abs(partial_sum[i]-(partial_sum[N-1]-partial_sum[i]))<result){\n            result=abs(partial_sum[i]-(partial_sum[N-1]-partial_sum[i]));\n        }else{\n            break;\n        }\n    }\n\n    std::cout << result << std::endl;\n    return 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nSnuke and Raccoon have a heap of N cards. The i-th card from the top has the integer a_i written on it.\n\nThey will share these cards.\nFirst, Snuke will take some number of cards from the top of the heap, then Raccoon will take all the remaining cards.\nHere, both Snuke and Raccoon have to take at least one card.\n\nLet the sum of the integers on Snuke's cards and Raccoon's cards be x and y, respectively.\nThey would like to minimize |x-y|.\nFind the minimum possible value of |x-y|.\n\nConstraints\n\n2 \\leq N \\leq 2 \\times 10^5\n\n-10^{9} \\leq a_i \\leq 10^{9}\n\na_i is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_{N}\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n6\n1 2 3 4 5 6\n\nSample Output 1\n\n1\n\nIf Snuke takes four cards from the top, and Raccoon takes the remaining two cards, x=10, y=11, and thus |x-y|=1. This is the minimum possible value.\n\nSample Input 2\n\n2\n10 -10\n\nSample Output 2\n\n20\n\nSnuke can only take one card from the top, and Raccoon can only take the remaining one card. In this case, x=10, y=-10, and thus |x-y|=20.", "sample_input": "6\n1 2 3 4 5 6\n"}, "reference_outputs": ["1\n"], "source_document_id": "p03659", "source_text": "Score : 300 points\n\nProblem Statement\n\nSnuke and Raccoon have a heap of N cards. The i-th card from the top has the integer a_i written on it.\n\nThey will share these cards.\nFirst, Snuke will take some number of cards from the top of the heap, then Raccoon will take all the remaining cards.\nHere, both Snuke and Raccoon have to take at least one card.\n\nLet the sum of the integers on Snuke's cards and Raccoon's cards be x and y, respectively.\nThey would like to minimize |x-y|.\nFind the minimum possible value of |x-y|.\n\nConstraints\n\n2 \\leq N \\leq 2 \\times 10^5\n\n-10^{9} \\leq a_i \\leq 10^{9}\n\na_i is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_{N}\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n6\n1 2 3 4 5 6\n\nSample Output 1\n\n1\n\nIf Snuke takes four cards from the top, and Raccoon takes the remaining two cards, x=10, y=11, and thus |x-y|=1. This is the minimum possible value.\n\nSample Input 2\n\n2\n10 -10\n\nSample Output 2\n\n20\n\nSnuke can only take one card from the top, and Raccoon can only take the remaining one card. In this case, x=10, y=-10, and thus |x-y|=20.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 685, "cpu_time_ms": 79, "memory_kb": 3328}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s300832933", "group_id": "codeNet:p03659", "input_text": "#include<cstdio>\n#include<map>\n#include<cstring>\n#include<cmath>\n#include<iostream>\n#include<algorithm>\n#include<queue>\nusing namespace std;\nlong long a[200005];\nlong long pre[200005];\nlong long last[200005];\nint main(){\n\tint n;\n\tscanf(\"%d\",&n);\n\tfor(int i = 1;i<=n;i++){\n\t\t\tscanf(\"%lld\",&a[i]);\n\t}\n\tlong long sumpre=0,sumlast=0;\n\tfor(int i = 1;i<n;i++){\n\t\tsumpre=sumpre+a[i];\n\t\tpre[i]=sumpre;\n//\t\tprintf(\"%lld++\\n\",pre[i]);\n\t}\n\tfor(int i = n,j=1;i>1,j<n;i--,j++){\n\t\tsumlast=sumlast+a[i];\n\t\tlast[j]=sumlast;\n//\t\tprintf(\"%lld+++\\n\",last[i]);\n\t}\n\tlong long d=(1ll<<60);\n\tfor(int i = 1;i<n;i++){\n//\t\tprintf(\"%lld\\n\",pre[i]-last[i+1]);\n\t\td=min(d,abs(pre[i]-last[n-i]));\n\t}\n\tprintf(\"%lld\\n\",d);\n}\n", "language": "C++", "metadata": {"date": 1500303351, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03659.html", "problem_id": "p03659", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03659/input.txt", "sample_output_relpath": "derived/input_output/data/p03659/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03659/C++/s300832933.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s300832933", "user_id": "u308494653"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include<cstdio>\n#include<map>\n#include<cstring>\n#include<cmath>\n#include<iostream>\n#include<algorithm>\n#include<queue>\nusing namespace std;\nlong long a[200005];\nlong long pre[200005];\nlong long last[200005];\nint main(){\n\tint n;\n\tscanf(\"%d\",&n);\n\tfor(int i = 1;i<=n;i++){\n\t\t\tscanf(\"%lld\",&a[i]);\n\t}\n\tlong long sumpre=0,sumlast=0;\n\tfor(int i = 1;i<n;i++){\n\t\tsumpre=sumpre+a[i];\n\t\tpre[i]=sumpre;\n//\t\tprintf(\"%lld++\\n\",pre[i]);\n\t}\n\tfor(int i = n,j=1;i>1,j<n;i--,j++){\n\t\tsumlast=sumlast+a[i];\n\t\tlast[j]=sumlast;\n//\t\tprintf(\"%lld+++\\n\",last[i]);\n\t}\n\tlong long d=(1ll<<60);\n\tfor(int i = 1;i<n;i++){\n//\t\tprintf(\"%lld\\n\",pre[i]-last[i+1]);\n\t\td=min(d,abs(pre[i]-last[n-i]));\n\t}\n\tprintf(\"%lld\\n\",d);\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nSnuke and Raccoon have a heap of N cards. The i-th card from the top has the integer a_i written on it.\n\nThey will share these cards.\nFirst, Snuke will take some number of cards from the top of the heap, then Raccoon will take all the remaining cards.\nHere, both Snuke and Raccoon have to take at least one card.\n\nLet the sum of the integers on Snuke's cards and Raccoon's cards be x and y, respectively.\nThey would like to minimize |x-y|.\nFind the minimum possible value of |x-y|.\n\nConstraints\n\n2 \\leq N \\leq 2 \\times 10^5\n\n-10^{9} \\leq a_i \\leq 10^{9}\n\na_i is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_{N}\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n6\n1 2 3 4 5 6\n\nSample Output 1\n\n1\n\nIf Snuke takes four cards from the top, and Raccoon takes the remaining two cards, x=10, y=11, and thus |x-y|=1. This is the minimum possible value.\n\nSample Input 2\n\n2\n10 -10\n\nSample Output 2\n\n20\n\nSnuke can only take one card from the top, and Raccoon can only take the remaining one card. In this case, x=10, y=-10, and thus |x-y|=20.", "sample_input": "6\n1 2 3 4 5 6\n"}, "reference_outputs": ["1\n"], "source_document_id": "p03659", "source_text": "Score : 300 points\n\nProblem Statement\n\nSnuke and Raccoon have a heap of N cards. The i-th card from the top has the integer a_i written on it.\n\nThey will share these cards.\nFirst, Snuke will take some number of cards from the top of the heap, then Raccoon will take all the remaining cards.\nHere, both Snuke and Raccoon have to take at least one card.\n\nLet the sum of the integers on Snuke's cards and Raccoon's cards be x and y, respectively.\nThey would like to minimize |x-y|.\nFind the minimum possible value of |x-y|.\n\nConstraints\n\n2 \\leq N \\leq 2 \\times 10^5\n\n-10^{9} \\leq a_i \\leq 10^{9}\n\na_i is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_{N}\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n6\n1 2 3 4 5 6\n\nSample Output 1\n\n1\n\nIf Snuke takes four cards from the top, and Raccoon takes the remaining two cards, x=10, y=11, and thus |x-y|=1. This is the minimum possible value.\n\nSample Input 2\n\n2\n10 -10\n\nSample Output 2\n\n20\n\nSnuke can only take one card from the top, and Raccoon can only take the remaining one card. In this case, x=10, y=-10, and thus |x-y|=20.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 692, "cpu_time_ms": 24, "memory_kb": 4992}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s667278197", "group_id": "codeNet:p03660", "input_text": "#include <iostream>\n#include <vector>\n#include <unordered_map>\n#include <unordered_set>\n#include <queue>\n#include <algorithm>\n\nusing namespace std;\n\nstruct PathData\n{\n    long long pos;\n    long long dist;\n    unordered_set<long long> set;\n};\n\nint main()\n{\n    unordered_map<long long, vector<long long>> checkMap;\n    unordered_map<long long, long long> fennecMap;\n    unordered_map<long long, long long> sunukeMap;\n\n    long long N;\n    cin >> N;\n\n    long a, b;\n    for (long long i = 0; i < N; i++)\n    {\n        cin >> a >> b;\n        a--;\n        b--;\n        checkMap[a].push_back(b);\n        checkMap[b].push_back(a);\n    }\n\n    queue<PathData> PQueue;\n    for (long long i = 0; i < checkMap[0].size(); i++)\n    {\n        if (checkMap[0][i] != N - 1)\n        {\n\n            PathData pd;\n            pd.pos = checkMap[0][i];\n            pd.dist = 1;\n            pd.set.emplace(0);\n            PQueue.push(pd);\n        }\n    }\n    fennecMap[0] = 0;\n\n    while (!PQueue.empty())\n    {\n        PathData pd = PQueue.front();\n        PQueue.pop();\n\n        fennecMap[pd.pos] = pd.dist;\n\n        for (long long i = 0; i < checkMap[pd.pos].size(); i++)\n        {\n            if (checkMap[pd.pos][i] != N - 1 && pd.set.find(checkMap[pd.pos][i]) == pd.set.end())\n            {\n                PathData pd_new;\n                pd_new.pos = checkMap[pd.pos][i];\n                pd_new.dist = pd.dist + 1;\n                pd_new.set.emplace(pd.pos);\n                PQueue.push(pd_new);\n            }\n        }\n    }\n\n    while (!PQueue.empty())\n    {\n        PQueue.pop();\n    }\n\n    for (long long i = 0; i < checkMap[N - 1].size(); i++)\n    {\n        if (checkMap[N - 1][i] != 0)\n        {\n\n            PathData pd;\n            pd.pos = checkMap[N - 1][i];\n            pd.dist = 1;\n            pd.set.emplace(N - 1);\n            PQueue.push(pd);\n        }\n    }\n    sunukeMap[N - 1] = 0;\n\n    long long fennec = 0;\n    while (!PQueue.empty())\n    {\n        PathData pd = PQueue.front();\n        PQueue.pop();\n\n        sunukeMap[pd.pos] = pd.dist;\n        if (pd.dist > fennecMap[pd.pos])\n        {\n            fennec++;\n        }\n\n        for (long long i = 0; i < checkMap[pd.pos].size(); i++)\n        {\n            if (checkMap[pd.pos][i] != 0 && pd.set.find(checkMap[pd.pos][i]) == pd.set.end())\n            {\n                PathData pd_new;\n                pd_new.pos = checkMap[pd.pos][i];\n                pd_new.dist = pd.dist + 1;\n                pd_new.set.emplace(pd.pos);\n                PQueue.push(pd_new);\n            }\n        }\n    }\n\n    if (N - fennec > 0)\n    {\n        cout << \"Fennec\" << endl;\n    }\n    else\n    {\n        cout << \"Snuke\" << endl;\n    }\n\n    return 0;\n}", "language": "C++", "metadata": {"date": 1508229036, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03660.html", "problem_id": "p03660", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03660/input.txt", "sample_output_relpath": "derived/input_output/data/p03660/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03660/C++/s667278197.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s667278197", "user_id": "u475968945"}, "prompt_components": {"gold_output": "Fennec\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\n#include <unordered_map>\n#include <unordered_set>\n#include <queue>\n#include <algorithm>\n\nusing namespace std;\n\nstruct PathData\n{\n    long long pos;\n    long long dist;\n    unordered_set<long long> set;\n};\n\nint main()\n{\n    unordered_map<long long, vector<long long>> checkMap;\n    unordered_map<long long, long long> fennecMap;\n    unordered_map<long long, long long> sunukeMap;\n\n    long long N;\n    cin >> N;\n\n    long a, b;\n    for (long long i = 0; i < N; i++)\n    {\n        cin >> a >> b;\n        a--;\n        b--;\n        checkMap[a].push_back(b);\n        checkMap[b].push_back(a);\n    }\n\n    queue<PathData> PQueue;\n    for (long long i = 0; i < checkMap[0].size(); i++)\n    {\n        if (checkMap[0][i] != N - 1)\n        {\n\n            PathData pd;\n            pd.pos = checkMap[0][i];\n            pd.dist = 1;\n            pd.set.emplace(0);\n            PQueue.push(pd);\n        }\n    }\n    fennecMap[0] = 0;\n\n    while (!PQueue.empty())\n    {\n        PathData pd = PQueue.front();\n        PQueue.pop();\n\n        fennecMap[pd.pos] = pd.dist;\n\n        for (long long i = 0; i < checkMap[pd.pos].size(); i++)\n        {\n            if (checkMap[pd.pos][i] != N - 1 && pd.set.find(checkMap[pd.pos][i]) == pd.set.end())\n            {\n                PathData pd_new;\n                pd_new.pos = checkMap[pd.pos][i];\n                pd_new.dist = pd.dist + 1;\n                pd_new.set.emplace(pd.pos);\n                PQueue.push(pd_new);\n            }\n        }\n    }\n\n    while (!PQueue.empty())\n    {\n        PQueue.pop();\n    }\n\n    for (long long i = 0; i < checkMap[N - 1].size(); i++)\n    {\n        if (checkMap[N - 1][i] != 0)\n        {\n\n            PathData pd;\n            pd.pos = checkMap[N - 1][i];\n            pd.dist = 1;\n            pd.set.emplace(N - 1);\n            PQueue.push(pd);\n        }\n    }\n    sunukeMap[N - 1] = 0;\n\n    long long fennec = 0;\n    while (!PQueue.empty())\n    {\n        PathData pd = PQueue.front();\n        PQueue.pop();\n\n        sunukeMap[pd.pos] = pd.dist;\n        if (pd.dist > fennecMap[pd.pos])\n        {\n            fennec++;\n        }\n\n        for (long long i = 0; i < checkMap[pd.pos].size(); i++)\n        {\n            if (checkMap[pd.pos][i] != 0 && pd.set.find(checkMap[pd.pos][i]) == pd.set.end())\n            {\n                PathData pd_new;\n                pd_new.pos = checkMap[pd.pos][i];\n                pd_new.dist = pd.dist + 1;\n                pd_new.set.emplace(pd.pos);\n                PQueue.push(pd_new);\n            }\n        }\n    }\n\n    if (N - fennec > 0)\n    {\n        cout << \"Fennec\" << endl;\n    }\n    else\n    {\n        cout << \"Snuke\" << endl;\n    }\n\n    return 0;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nFennec and Snuke are playing a board game.\n\nOn the board, there are N cells numbered 1 through N, and N-1 roads, each connecting two cells. Cell a_i is adjacent to Cell b_i through the i-th road. Every cell can be reached from every other cell by repeatedly traveling to an adjacent cell. In terms of graph theory, the graph formed by the cells and the roads is a tree.\n\nInitially, Cell 1 is painted black, and Cell N is painted white. The other cells are not yet colored.\nFennec (who goes first) and Snuke (who goes second) alternately paint an uncolored cell.\nMore specifically, each player performs the following action in her/his turn:\n\nFennec: selects an uncolored cell that is adjacent to a black cell, and paints it black.\n\nSnuke: selects an uncolored cell that is adjacent to a white cell, and paints it white.\n\nA player loses when she/he cannot paint a cell. Determine the winner of the game when Fennec and Snuke play optimally.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n1 \\leq a_i, b_i \\leq N\n\nThe given graph is a tree.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 b_1\n:\na_{N-1} b_{N-1}\n\nOutput\n\nIf Fennec wins, print Fennec; if Snuke wins, print Snuke.\n\nSample Input 1\n\n7\n3 6\n1 2\n3 1\n7 4\n5 7\n1 4\n\nSample Output 1\n\nFennec\n\nFor example, if Fennec first paints Cell 2 black, she will win regardless of Snuke's moves.\n\nSample Input 2\n\n4\n1 4\n4 2\n2 3\n\nSample Output 2\n\nSnuke", "sample_input": "7\n3 6\n1 2\n3 1\n7 4\n5 7\n1 4\n"}, "reference_outputs": ["Fennec\n"], "source_document_id": "p03660", "source_text": "Score : 400 points\n\nProblem Statement\n\nFennec and Snuke are playing a board game.\n\nOn the board, there are N cells numbered 1 through N, and N-1 roads, each connecting two cells. Cell a_i is adjacent to Cell b_i through the i-th road. Every cell can be reached from every other cell by repeatedly traveling to an adjacent cell. In terms of graph theory, the graph formed by the cells and the roads is a tree.\n\nInitially, Cell 1 is painted black, and Cell N is painted white. The other cells are not yet colored.\nFennec (who goes first) and Snuke (who goes second) alternately paint an uncolored cell.\nMore specifically, each player performs the following action in her/his turn:\n\nFennec: selects an uncolored cell that is adjacent to a black cell, and paints it black.\n\nSnuke: selects an uncolored cell that is adjacent to a white cell, and paints it white.\n\nA player loses when she/he cannot paint a cell. Determine the winner of the game when Fennec and Snuke play optimally.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n1 \\leq a_i, b_i \\leq N\n\nThe given graph is a tree.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 b_1\n:\na_{N-1} b_{N-1}\n\nOutput\n\nIf Fennec wins, print Fennec; if Snuke wins, print Snuke.\n\nSample Input 1\n\n7\n3 6\n1 2\n3 1\n7 4\n5 7\n1 4\n\nSample Output 1\n\nFennec\n\nFor example, if Fennec first paints Cell 2 black, she will win regardless of Snuke's moves.\n\nSample Input 2\n\n4\n1 4\n4 2\n2 3\n\nSample Output 2\n\nSnuke", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2689, "cpu_time_ms": 2106, "memory_kb": 20004}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s704377832", "group_id": "codeNet:p03662", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\ntypedef pair<int,int> ii;\ntypedef long long ll;\n\n#define SQR(x) ((x)*(x))\nvector<int>nodes[100010];\nint colour[100010];\nint pre[100010];\nvoid dfs(int x){\n    for(auto y:nodes[x]){\n        if(pre[y]!=0)continue;\n        pre[y]=x;\n        dfs(y);\n    }\n}\nvoid dfs2(int x){\n    for(auto y:nodes[x]){\n        if(colour[y]!=0)continue;\n        colour[y]=colour[x];\n        dfs2(y);\n    }\n}\n\nint main() {\n    //freopen(\"hi.txt\",\"r\",stdin);\n    int n;\n    scanf(\"%d\",&n);\n    int a,b;\n    for(int i=0;i<n-1;i++){\n        scanf(\"%d%d\",&a,&b);\n        nodes[a].push_back(b);\n        nodes[b].push_back(a);\n    }\n    pre[1]=-1;\n    dfs(1);\n    vector<int>v;\n    int cur=n;\n    while(cur!=-1){\n        v.push_back(cur);\n        cur=pre[cur];\n    }\n    for(int i=0;i<v.size()/2;i++){\n        colour[v[i]]=2;\n    }\n    for(int i=v.size()/2;i<v.size();i++){\n        colour[v[i]]=1;\n    }\n    for(auto i:v){\n        dfs2(i);\n    }\n    int counter=0;\n    for(int i=1;i<=n;i++){\n        counter+=colour[i]==1;\n    }\n    if(counter>n/2){\n        printf(\"Fennec\");\n    }\n    else{\n        printf(\"Snuke\");\n    }\n}\n", "language": "C++", "metadata": {"date": 1500262807, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03662.html", "problem_id": "p03662", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03662/input.txt", "sample_output_relpath": "derived/input_output/data/p03662/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03662/C++/s704377832.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s704377832", "user_id": "u138503292"}, "prompt_components": {"gold_output": "Fennec\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\ntypedef pair<int,int> ii;\ntypedef long long ll;\n\n#define SQR(x) ((x)*(x))\nvector<int>nodes[100010];\nint colour[100010];\nint pre[100010];\nvoid dfs(int x){\n    for(auto y:nodes[x]){\n        if(pre[y]!=0)continue;\n        pre[y]=x;\n        dfs(y);\n    }\n}\nvoid dfs2(int x){\n    for(auto y:nodes[x]){\n        if(colour[y]!=0)continue;\n        colour[y]=colour[x];\n        dfs2(y);\n    }\n}\n\nint main() {\n    //freopen(\"hi.txt\",\"r\",stdin);\n    int n;\n    scanf(\"%d\",&n);\n    int a,b;\n    for(int i=0;i<n-1;i++){\n        scanf(\"%d%d\",&a,&b);\n        nodes[a].push_back(b);\n        nodes[b].push_back(a);\n    }\n    pre[1]=-1;\n    dfs(1);\n    vector<int>v;\n    int cur=n;\n    while(cur!=-1){\n        v.push_back(cur);\n        cur=pre[cur];\n    }\n    for(int i=0;i<v.size()/2;i++){\n        colour[v[i]]=2;\n    }\n    for(int i=v.size()/2;i<v.size();i++){\n        colour[v[i]]=1;\n    }\n    for(auto i:v){\n        dfs2(i);\n    }\n    int counter=0;\n    for(int i=1;i<=n;i++){\n        counter+=colour[i]==1;\n    }\n    if(counter>n/2){\n        printf(\"Fennec\");\n    }\n    else{\n        printf(\"Snuke\");\n    }\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nFennec and Snuke are playing a board game.\n\nOn the board, there are N cells numbered 1 through N, and N-1 roads, each connecting two cells. Cell a_i is adjacent to Cell b_i through the i-th road. Every cell can be reached from every other cell by repeatedly traveling to an adjacent cell. In terms of graph theory, the graph formed by the cells and the roads is a tree.\n\nInitially, Cell 1 is painted black, and Cell N is painted white. The other cells are not yet colored.\nFennec (who goes first) and Snuke (who goes second) alternately paint an uncolored cell.\nMore specifically, each player performs the following action in her/his turn:\n\nFennec: selects an uncolored cell that is adjacent to a black cell, and paints it black.\n\nSnuke: selects an uncolored cell that is adjacent to a white cell, and paints it white.\n\nA player loses when she/he cannot paint a cell. Determine the winner of the game when Fennec and Snuke play optimally.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n1 \\leq a_i, b_i \\leq N\n\nThe given graph is a tree.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 b_1\n:\na_{N-1} b_{N-1}\n\nOutput\n\nIf Fennec wins, print Fennec; if Snuke wins, print Snuke.\n\nSample Input 1\n\n7\n3 6\n1 2\n3 1\n7 4\n5 7\n1 4\n\nSample Output 1\n\nFennec\n\nFor example, if Fennec first paints Cell 2 black, she will win regardless of Snuke's moves.\n\nSample Input 2\n\n4\n1 4\n4 2\n2 3\n\nSample Output 2\n\nSnuke", "sample_input": "7\n3 6\n1 2\n3 1\n7 4\n5 7\n1 4\n"}, "reference_outputs": ["Fennec\n"], "source_document_id": "p03662", "source_text": "Score : 400 points\n\nProblem Statement\n\nFennec and Snuke are playing a board game.\n\nOn the board, there are N cells numbered 1 through N, and N-1 roads, each connecting two cells. Cell a_i is adjacent to Cell b_i through the i-th road. Every cell can be reached from every other cell by repeatedly traveling to an adjacent cell. In terms of graph theory, the graph formed by the cells and the roads is a tree.\n\nInitially, Cell 1 is painted black, and Cell N is painted white. The other cells are not yet colored.\nFennec (who goes first) and Snuke (who goes second) alternately paint an uncolored cell.\nMore specifically, each player performs the following action in her/his turn:\n\nFennec: selects an uncolored cell that is adjacent to a black cell, and paints it black.\n\nSnuke: selects an uncolored cell that is adjacent to a white cell, and paints it white.\n\nA player loses when she/he cannot paint a cell. Determine the winner of the game when Fennec and Snuke play optimally.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n1 \\leq a_i, b_i \\leq N\n\nThe given graph is a tree.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 b_1\n:\na_{N-1} b_{N-1}\n\nOutput\n\nIf Fennec wins, print Fennec; if Snuke wins, print Snuke.\n\nSample Input 1\n\n7\n3 6\n1 2\n3 1\n7 4\n5 7\n1 4\n\nSample Output 1\n\nFennec\n\nFor example, if Fennec first paints Cell 2 black, she will win regardless of Snuke's moves.\n\nSample Input 2\n\n4\n1 4\n4 2\n2 3\n\nSample Output 2\n\nSnuke", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1142, "cpu_time_ms": 44, "memory_kb": 10104}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s882435006", "group_id": "codeNet:p03669", "input_text": "#include <bits/stdc++.h>\n\nusing namespace std;\n\ntypedef pair <int, int> pii;\n\nvector <int> LI[444], LO[444], RI[444], RO[444];\nvector <pii> V;\nbool chk[444];\nmultiset <int> SL, SR;\nint n, h;\n\nvoid dfs(int p, vector <int> *V)\n{\n\tchk[p] = 1;\n\tfor(int t: V[p]){\n\t\tif(!chk[t]) dfs(t, V);\n\t}\n}\n\nvoid die()\n{\n\tprintf(\"NO\\n\");\n\texit(0);\n}\n\nint main()\n{\n\tint i, j, a, b, c, d;\n\t\n\tscanf(\"%d%d\", &n, &h);\n\t\n\tfor(i=1;i<=n;i++){\n\t\tscanf(\"%d%d%d%d\", &a, &b, &c, &d);\n\t\t\n\t\tif(c == 0 && d == 0){\n\t\t\tif(a != h){\n\t\t\t\tLO[0].push_back(a);\n\t\t\t\tLI[a].push_back(0);\n\t\t\t}\n\t\t\tif(b != h){\n\t\t\t\tRO[0].push_back(b);\n\t\t\t\tRI[b].push_back(0);\n\t\t\t}\n\t\t}\n\t\telse if(c == 0){\n\t\t\tif(a != h){\n\t\t\t\tLO[d].push_back(a);\n\t\t\t\tLI[a].push_back(d);\n\t\t\t}\n\t\t}\n\t\telse if(d == 0){\n\t\t\tif(b != h){\n\t\t\t\tRO[c].push_back(b);\n\t\t\t\tRI[b].push_back(c);\n\t\t\t}\n\t\t}\n\t\telse V.push_back(pii(c, d));\n\t}\n\t\n\tdfs(0, LO);\n\t\n\tfor(i=1;i<h;i++){\n\t\tif((!LO[i].empty() || !LI[i].empty()) && !chk[i]) die();\n\t\tif(LI[i].size() >= LO[i].size()){\n\t\t\tfor(j=0;j<LI[i].size() - LO[i].size();j++) SL.insert(i);\n\t\t}\n\t\telse die();\n\t\tchk[i] = 0;\n\t}\n\t\n\tdfs(0, RO);\n\t\n\tfor(i=1;i<h;i++){\n\t\tif((!RO[i].empty() || !RI[i].empty()) && !chk[i]) die();\n\t\tif(RI[i].size() >= RO[i].size()){\n\t\t\tfor(j=0;j<RI[i].size() - RO[i].size();j++) SR.insert(i);\n\t\t}\n\t\telse die();\n\t\tchk[i] = 0;\n\t}\n\t\n\tfor(pii t: V){\n\t\tauto it = SL.find(t.second);\n\t\tif(it == SL.end()) die();\n\t\tSL.erase(it);\n\t\t\n\t\tit = SR.find(t.first);\n\t\tif(it == SR.end()) die();\n\t\tSR.erase(it);\n\t}\n\t\n\tif(SL.empty() || SR.empty()) die();\n\t\n\tprintf(\"YES\\n\");\n\t\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1532032966, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03669.html", "problem_id": "p03669", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03669/input.txt", "sample_output_relpath": "derived/input_output/data/p03669/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03669/C++/s882435006.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s882435006", "user_id": "u304382419"}, "prompt_components": {"gold_output": "YES\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\nusing namespace std;\n\ntypedef pair <int, int> pii;\n\nvector <int> LI[444], LO[444], RI[444], RO[444];\nvector <pii> V;\nbool chk[444];\nmultiset <int> SL, SR;\nint n, h;\n\nvoid dfs(int p, vector <int> *V)\n{\n\tchk[p] = 1;\n\tfor(int t: V[p]){\n\t\tif(!chk[t]) dfs(t, V);\n\t}\n}\n\nvoid die()\n{\n\tprintf(\"NO\\n\");\n\texit(0);\n}\n\nint main()\n{\n\tint i, j, a, b, c, d;\n\t\n\tscanf(\"%d%d\", &n, &h);\n\t\n\tfor(i=1;i<=n;i++){\n\t\tscanf(\"%d%d%d%d\", &a, &b, &c, &d);\n\t\t\n\t\tif(c == 0 && d == 0){\n\t\t\tif(a != h){\n\t\t\t\tLO[0].push_back(a);\n\t\t\t\tLI[a].push_back(0);\n\t\t\t}\n\t\t\tif(b != h){\n\t\t\t\tRO[0].push_back(b);\n\t\t\t\tRI[b].push_back(0);\n\t\t\t}\n\t\t}\n\t\telse if(c == 0){\n\t\t\tif(a != h){\n\t\t\t\tLO[d].push_back(a);\n\t\t\t\tLI[a].push_back(d);\n\t\t\t}\n\t\t}\n\t\telse if(d == 0){\n\t\t\tif(b != h){\n\t\t\t\tRO[c].push_back(b);\n\t\t\t\tRI[b].push_back(c);\n\t\t\t}\n\t\t}\n\t\telse V.push_back(pii(c, d));\n\t}\n\t\n\tdfs(0, LO);\n\t\n\tfor(i=1;i<h;i++){\n\t\tif((!LO[i].empty() || !LI[i].empty()) && !chk[i]) die();\n\t\tif(LI[i].size() >= LO[i].size()){\n\t\t\tfor(j=0;j<LI[i].size() - LO[i].size();j++) SL.insert(i);\n\t\t}\n\t\telse die();\n\t\tchk[i] = 0;\n\t}\n\t\n\tdfs(0, RO);\n\t\n\tfor(i=1;i<h;i++){\n\t\tif((!RO[i].empty() || !RI[i].empty()) && !chk[i]) die();\n\t\tif(RI[i].size() >= RO[i].size()){\n\t\t\tfor(j=0;j<RI[i].size() - RO[i].size();j++) SR.insert(i);\n\t\t}\n\t\telse die();\n\t\tchk[i] = 0;\n\t}\n\t\n\tfor(pii t: V){\n\t\tauto it = SL.find(t.second);\n\t\tif(it == SL.end()) die();\n\t\tSL.erase(it);\n\t\t\n\t\tit = SR.find(t.first);\n\t\tif(it == SR.end()) die();\n\t\tSR.erase(it);\n\t}\n\t\n\tif(SL.empty() || SR.empty()) die();\n\t\n\tprintf(\"YES\\n\");\n\t\n\treturn 0;\n}", "problem_context": "Score : 1200 points\n\nProblem Statement\n\nWe have N irregular jigsaw pieces. Each piece is composed of three rectangular parts of width 1 and various heights joined together. More specifically:\n\nThe i-th piece is a part of height H, with another part of height A_i joined to the left, and yet another part of height B_i joined to the right, as shown below. Here, the bottom sides of the left and right parts are respectively at C_i and D_i units length above the bottom side of the center part.\n\nSnuke is arranging these pieces on a square table of side 10^{100}. Here, the following conditions must be held:\n\nAll pieces must be put on the table.\n\nThe entire bottom side of the center part of each piece must touch the front side of the table.\n\nThe entire bottom side of the non-center parts of each piece must either touch the front side of the table, or touch the top side of a part of some other piece.\n\nThe pieces must not be rotated or flipped.\n\nDetermine whether such an arrangement is possible.\n\nConstraints\n\n1 \\leq N \\leq 100000\n\n1 \\leq H \\leq 200\n\n1 \\leq A_i \\leq H\n\n1 \\leq B_i \\leq H\n\n0 \\leq C_i \\leq H - A_i\n\n0 \\leq D_i \\leq H - B_i\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN H\nA_1 B_1 C_1 D_1\nA_2 B_2 C_2 D_2\n:\nA_N B_N C_N D_N\n\nOutput\n\nIf it is possible to arrange the pieces under the conditions, print YES; if it is impossible, print NO.\n\nSample Input 1\n\n3 4\n1 1 0 0\n2 2 0 1\n3 3 1 0\n\nSample Output 1\n\nYES\n\nThe figure below shows a possible arrangement.\n\nSample Input 2\n\n4 2\n1 1 0 1\n1 1 0 1\n1 1 0 1\n1 1 0 1\n\nSample Output 2\n\nNO\n\nSample Input 3\n\n10 4\n1 1 0 3\n2 3 2 0\n1 2 3 0\n2 1 0 0\n3 2 0 2\n1 1 3 0\n3 2 0 0\n1 3 2 0\n1 1 1 3\n2 3 0 0\n\nSample Output 3\n\nYES", "sample_input": "3 4\n1 1 0 0\n2 2 0 1\n3 3 1 0\n"}, "reference_outputs": ["YES\n"], "source_document_id": "p03669", "source_text": "Score : 1200 points\n\nProblem Statement\n\nWe have N irregular jigsaw pieces. Each piece is composed of three rectangular parts of width 1 and various heights joined together. More specifically:\n\nThe i-th piece is a part of height H, with another part of height A_i joined to the left, and yet another part of height B_i joined to the right, as shown below. Here, the bottom sides of the left and right parts are respectively at C_i and D_i units length above the bottom side of the center part.\n\nSnuke is arranging these pieces on a square table of side 10^{100}. Here, the following conditions must be held:\n\nAll pieces must be put on the table.\n\nThe entire bottom side of the center part of each piece must touch the front side of the table.\n\nThe entire bottom side of the non-center parts of each piece must either touch the front side of the table, or touch the top side of a part of some other piece.\n\nThe pieces must not be rotated or flipped.\n\nDetermine whether such an arrangement is possible.\n\nConstraints\n\n1 \\leq N \\leq 100000\n\n1 \\leq H \\leq 200\n\n1 \\leq A_i \\leq H\n\n1 \\leq B_i \\leq H\n\n0 \\leq C_i \\leq H - A_i\n\n0 \\leq D_i \\leq H - B_i\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN H\nA_1 B_1 C_1 D_1\nA_2 B_2 C_2 D_2\n:\nA_N B_N C_N D_N\n\nOutput\n\nIf it is possible to arrange the pieces under the conditions, print YES; if it is impossible, print NO.\n\nSample Input 1\n\n3 4\n1 1 0 0\n2 2 0 1\n3 3 1 0\n\nSample Output 1\n\nYES\n\nThe figure below shows a possible arrangement.\n\nSample Input 2\n\n4 2\n1 1 0 1\n1 1 0 1\n1 1 0 1\n1 1 0 1\n\nSample Output 2\n\nNO\n\nSample Input 3\n\n10 4\n1 1 0 3\n2 3 2 0\n1 2 3 0\n2 1 0 0\n3 2 0 2\n1 1 3 0\n3 2 0 0\n1 3 2 0\n1 1 1 3\n2 3 0 0\n\nSample Output 3\n\nYES", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1530, "cpu_time_ms": 51, "memory_kb": 6520}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s871382789", "group_id": "codeNet:p03673", "input_text": "#include <iostream> // cout, endl, cin\n#include <iomanip>\n#include <string>        // string, to_string, stoi\n#include <vector>        // vector\n#include <algorithm>     // min, max, swap, sort, reverse, lower_bound, upper_bound\n#include <utility>       // pair, make_pair\n#include <tuple>         // tuple, make_tuple\n#include <cstdint>       // int64_t, int*_t\n#include <cstdio>        // printf\n#include <map>           // map\n#include <queue>         // queue, priority_queue\n#include <set>           // set\n#include <stack>         // stack\n#include <deque>         // deque\n#include <unordered_map> // unordered_map\n#include <unordered_set> // unordered_set\n#include <bitset>        // bitset\n#include <cctype>        // isupper, islower, isdigit, toupper, tolower\n#include <math.h>\n#include <numeric>\nusing namespace std;\n#define _GLIBCXX_DEBUG\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define rep2(i, s, n) for (int i = (s); i < (int)(n); i++)\nconst int INF = 1001001001;\nconst int BG = 1000000007;\n\nint main()\n{\n    int n;\n    cin >> n;\n\n    vector<int> a(n);\n    rep(i, n) cin >> a[i];\n\n    vector<int> ans;\n    rep(i, n)\n    {\n        ans.push_back(a[i]);\n        reverse(ans.begin(), ans.end());\n    }\n    rep(i, n)\n    {\n        cout << ans[i];\n        if (i != n - 1)\n        {\n            cout << \" \";\n        }\n        else\n        {\n            cout << endl;\n        }\n    }\n}\n", "language": "C++", "metadata": {"date": 1580679745, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03673.html", "problem_id": "p03673", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03673/input.txt", "sample_output_relpath": "derived/input_output/data/p03673/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03673/C++/s871382789.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s871382789", "user_id": "u286623856"}, "prompt_components": {"gold_output": "4 2 1 3\n", "input_to_evaluate": "#include <iostream> // cout, endl, cin\n#include <iomanip>\n#include <string>        // string, to_string, stoi\n#include <vector>        // vector\n#include <algorithm>     // min, max, swap, sort, reverse, lower_bound, upper_bound\n#include <utility>       // pair, make_pair\n#include <tuple>         // tuple, make_tuple\n#include <cstdint>       // int64_t, int*_t\n#include <cstdio>        // printf\n#include <map>           // map\n#include <queue>         // queue, priority_queue\n#include <set>           // set\n#include <stack>         // stack\n#include <deque>         // deque\n#include <unordered_map> // unordered_map\n#include <unordered_set> // unordered_set\n#include <bitset>        // bitset\n#include <cctype>        // isupper, islower, isdigit, toupper, tolower\n#include <math.h>\n#include <numeric>\nusing namespace std;\n#define _GLIBCXX_DEBUG\n#define rep(i, n) for (int i = 0; i < (int)(n); i++)\n#define rep2(i, s, n) for (int i = (s); i < (int)(n); i++)\nconst int INF = 1001001001;\nconst int BG = 1000000007;\n\nint main()\n{\n    int n;\n    cin >> n;\n\n    vector<int> a(n);\n    rep(i, n) cin >> a[i];\n\n    vector<int> ans;\n    rep(i, n)\n    {\n        ans.push_back(a[i]);\n        reverse(ans.begin(), ans.end());\n    }\n    rep(i, n)\n    {\n        cout << ans[i];\n        if (i != n - 1)\n        {\n            cout << \" \";\n        }\n        else\n        {\n            cout << endl;\n        }\n    }\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nYou are given an integer sequence of length n, a_1, ..., a_n.\nLet us consider performing the following n operations on an empty sequence b.\n\nThe i-th operation is as follows:\n\nAppend a_i to the end of b.\n\nReverse the order of the elements in b.\n\nFind the sequence b obtained after these n operations.\n\nConstraints\n\n1 \\leq n \\leq 2\\times 10^5\n\n0 \\leq a_i \\leq 10^9\n\nn and a_i are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn\na_1 a_2 ... a_n\n\nOutput\n\nPrint n integers in a line with spaces in between.\nThe i-th integer should be b_i.\n\nSample Input 1\n\n4\n1 2 3 4\n\nSample Output 1\n\n4 2 1 3\n\nAfter step 1 of the first operation, b becomes: 1.\n\nAfter step 2 of the first operation, b becomes: 1.\n\nAfter step 1 of the second operation, b becomes: 1, 2.\n\nAfter step 2 of the second operation, b becomes: 2, 1.\n\nAfter step 1 of the third operation, b becomes: 2, 1, 3.\n\nAfter step 2 of the third operation, b becomes: 3, 1, 2.\n\nAfter step 1 of the fourth operation, b becomes: 3, 1, 2, 4.\n\nAfter step 2 of the fourth operation, b becomes: 4, 2, 1, 3.\n\nThus, the answer is 4 2 1 3.\n\nSample Input 2\n\n3\n1 2 3\n\nSample Output 2\n\n3 1 2\n\nAs shown above in Sample Output 1, b becomes 3, 1, 2 after step 2 of the third operation. Thus, the answer is 3 1 2.\n\nSample Input 3\n\n1\n1000000000\n\nSample Output 3\n\n1000000000\n\nSample Input 4\n\n6\n0 6 7 6 7 0\n\nSample Output 4\n\n0 6 6 0 7 7", "sample_input": "4\n1 2 3 4\n"}, "reference_outputs": ["4 2 1 3\n"], "source_document_id": "p03673", "source_text": "Score : 300 points\n\nProblem Statement\n\nYou are given an integer sequence of length n, a_1, ..., a_n.\nLet us consider performing the following n operations on an empty sequence b.\n\nThe i-th operation is as follows:\n\nAppend a_i to the end of b.\n\nReverse the order of the elements in b.\n\nFind the sequence b obtained after these n operations.\n\nConstraints\n\n1 \\leq n \\leq 2\\times 10^5\n\n0 \\leq a_i \\leq 10^9\n\nn and a_i are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn\na_1 a_2 ... a_n\n\nOutput\n\nPrint n integers in a line with spaces in between.\nThe i-th integer should be b_i.\n\nSample Input 1\n\n4\n1 2 3 4\n\nSample Output 1\n\n4 2 1 3\n\nAfter step 1 of the first operation, b becomes: 1.\n\nAfter step 2 of the first operation, b becomes: 1.\n\nAfter step 1 of the second operation, b becomes: 1, 2.\n\nAfter step 2 of the second operation, b becomes: 2, 1.\n\nAfter step 1 of the third operation, b becomes: 2, 1, 3.\n\nAfter step 2 of the third operation, b becomes: 3, 1, 2.\n\nAfter step 1 of the fourth operation, b becomes: 3, 1, 2, 4.\n\nAfter step 2 of the fourth operation, b becomes: 4, 2, 1, 3.\n\nThus, the answer is 4 2 1 3.\n\nSample Input 2\n\n3\n1 2 3\n\nSample Output 2\n\n3 1 2\n\nAs shown above in Sample Output 1, b becomes 3, 1, 2 after step 2 of the third operation. Thus, the answer is 3 1 2.\n\nSample Input 3\n\n1\n1000000000\n\nSample Output 3\n\n1000000000\n\nSample Input 4\n\n6\n0 6 7 6 7 0\n\nSample Output 4\n\n0 6 6 0 7 7", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1406, "cpu_time_ms": 2103, "memory_kb": 1660}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s868828768", "group_id": "codeNet:p03675", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n  int N, t;\n  cin >>N;\n  vector<int>A(N,0);\n  t=N/2;\n  for(int i=0; i<N; i++){\n    int a;\n    cin >>a;\n    if(N%2==0){\n      if(i%2==0) t+=i;\n      else t-=i;\n      A[t]=a;\n    }\n    else{\n      if(i%2==0) t-=i;\n      else t+=i;\n      A[t]=a;\n    }\n  }\n  for(int i=0; i<N; i++){\n    if(i!=N-1) cout <<A[i] <<\" \";\n    else cout <<A[i] <<endl;    \n  }\n}", "language": "C++", "metadata": {"date": 1578503478, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03675.html", "problem_id": "p03675", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03675/input.txt", "sample_output_relpath": "derived/input_output/data/p03675/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03675/C++/s868828768.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s868828768", "user_id": "u071282706"}, "prompt_components": {"gold_output": "4 2 1 3\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n  int N, t;\n  cin >>N;\n  vector<int>A(N,0);\n  t=N/2;\n  for(int i=0; i<N; i++){\n    int a;\n    cin >>a;\n    if(N%2==0){\n      if(i%2==0) t+=i;\n      else t-=i;\n      A[t]=a;\n    }\n    else{\n      if(i%2==0) t-=i;\n      else t+=i;\n      A[t]=a;\n    }\n  }\n  for(int i=0; i<N; i++){\n    if(i!=N-1) cout <<A[i] <<\" \";\n    else cout <<A[i] <<endl;    \n  }\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nYou are given an integer sequence of length n, a_1, ..., a_n.\nLet us consider performing the following n operations on an empty sequence b.\n\nThe i-th operation is as follows:\n\nAppend a_i to the end of b.\n\nReverse the order of the elements in b.\n\nFind the sequence b obtained after these n operations.\n\nConstraints\n\n1 \\leq n \\leq 2\\times 10^5\n\n0 \\leq a_i \\leq 10^9\n\nn and a_i are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn\na_1 a_2 ... a_n\n\nOutput\n\nPrint n integers in a line with spaces in between.\nThe i-th integer should be b_i.\n\nSample Input 1\n\n4\n1 2 3 4\n\nSample Output 1\n\n4 2 1 3\n\nAfter step 1 of the first operation, b becomes: 1.\n\nAfter step 2 of the first operation, b becomes: 1.\n\nAfter step 1 of the second operation, b becomes: 1, 2.\n\nAfter step 2 of the second operation, b becomes: 2, 1.\n\nAfter step 1 of the third operation, b becomes: 2, 1, 3.\n\nAfter step 2 of the third operation, b becomes: 3, 1, 2.\n\nAfter step 1 of the fourth operation, b becomes: 3, 1, 2, 4.\n\nAfter step 2 of the fourth operation, b becomes: 4, 2, 1, 3.\n\nThus, the answer is 4 2 1 3.\n\nSample Input 2\n\n3\n1 2 3\n\nSample Output 2\n\n3 1 2\n\nAs shown above in Sample Output 1, b becomes 3, 1, 2 after step 2 of the third operation. Thus, the answer is 3 1 2.\n\nSample Input 3\n\n1\n1000000000\n\nSample Output 3\n\n1000000000\n\nSample Input 4\n\n6\n0 6 7 6 7 0\n\nSample Output 4\n\n0 6 6 0 7 7", "sample_input": "4\n1 2 3 4\n"}, "reference_outputs": ["4 2 1 3\n"], "source_document_id": "p03675", "source_text": "Score : 300 points\n\nProblem Statement\n\nYou are given an integer sequence of length n, a_1, ..., a_n.\nLet us consider performing the following n operations on an empty sequence b.\n\nThe i-th operation is as follows:\n\nAppend a_i to the end of b.\n\nReverse the order of the elements in b.\n\nFind the sequence b obtained after these n operations.\n\nConstraints\n\n1 \\leq n \\leq 2\\times 10^5\n\n0 \\leq a_i \\leq 10^9\n\nn and a_i are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn\na_1 a_2 ... a_n\n\nOutput\n\nPrint n integers in a line with spaces in between.\nThe i-th integer should be b_i.\n\nSample Input 1\n\n4\n1 2 3 4\n\nSample Output 1\n\n4 2 1 3\n\nAfter step 1 of the first operation, b becomes: 1.\n\nAfter step 2 of the first operation, b becomes: 1.\n\nAfter step 1 of the second operation, b becomes: 1, 2.\n\nAfter step 2 of the second operation, b becomes: 2, 1.\n\nAfter step 1 of the third operation, b becomes: 2, 1, 3.\n\nAfter step 2 of the third operation, b becomes: 3, 1, 2.\n\nAfter step 1 of the fourth operation, b becomes: 3, 1, 2, 4.\n\nAfter step 2 of the fourth operation, b becomes: 4, 2, 1, 3.\n\nThus, the answer is 4 2 1 3.\n\nSample Input 2\n\n3\n1 2 3\n\nSample Output 2\n\n3 1 2\n\nAs shown above in Sample Output 1, b becomes 3, 1, 2 after step 2 of the third operation. Thus, the answer is 3 1 2.\n\nSample Input 3\n\n1\n1000000000\n\nSample Output 3\n\n1000000000\n\nSample Input 4\n\n6\n0 6 7 6 7 0\n\nSample Output 4\n\n0 6 6 0 7 7", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 409, "cpu_time_ms": 105, "memory_kb": 2944}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s377158777", "group_id": "codeNet:p03676", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n\n#define VA_NUM_ARGS(...) VA_NUM_ARGS_IMPL_((0,__VA_ARGS__, 6,5,4,3,2,1))\n#define VA_NUM_ARGS_IMPL_(tuple) VA_NUM_ARGS_IMPL tuple\n#define VA_NUM_ARGS_IMPL(_0,_1,_2,_3,_4,_5,_6,N,...) N\n#define macro_dispatcher(macro, ...) macro_dispatcher_(macro, VA_NUM_ARGS(__VA_ARGS__))\n#define macro_dispatcher_(macro, nargs) macro_dispatcher__(macro, nargs)\n#define macro_dispatcher__(macro, nargs) macro_dispatcher___(macro, nargs)\n#define macro_dispatcher___(macro, nargs) macro ## nargs\n#define Debug1(a)           cout<<#a<<\"=\"<<(a)<<\"\\n\"\n#define Debug2(a,b)         cout<<#a<<\"=\"<<(a)<<\", \"<<#b<<\"=\"<<(b)<<\"\\n\"\n#define Debug3(a,b,c)       cout<<#a<<\"=\"<<(a)<<\", \"<<#b<<\"=\"<<(b)<<\", \"<<#c<<\"=\"<<(c)<<\"\\n\"\n#define Debug4(a,b,c,d)     cout<<#a<<\"=\"<<(a)<<\", \"<<#b<<\"=\"<<(b)<<\", \"<<#c<<\"=\"<<(c)<<\", \"<<#d<<\"=\"<<(d)<<\"\\n\"\n#define Debug5(a,b,c,d,e)   cout<<#a<<\"=\"<<(a)<<\", \"<<#b<<\"=\"<<(b)<<\", \"<<#c<<\"=\"<<(c)<<\", \"<<#d<<\"=\"<<(d)<<\", \"<<#e<<\"=\"<<(e)<<\"\\n\"\n#define Debug6(a,b,c,d,e,f) cout<<#a<<\"=\"<<(a)<<\", \"<<#b<<\"=\"<<(b)<<\", \"<<#c<<\"=\"<<(c)<<\", \"<<#d<<\"=\"<<(d)<<\", \"<<#e<<\"=\"<<(e)<<\", \"<<#f<<\"=\"<<(f)<<\"\\n\"\n#define Debug(...) macro_dispatcher(Debug, __VA_ARGS__)(__VA_ARGS__)\n#define DA(a,n) cout<<#a<<\"=[\"; printarray(a,n); cout<<\"]\\n\"\n#define DAR(a,n,s) cout<<#a<<\"[\"<<s<<\"-\"<<n-1<<\"]=[\"; printarray(a,n,s); cout<<\"]\\n\"\n\n#define TT1 template<class T>\n#define TT1T2 template<class T1, class T2>\n#define TT1T2T3 template<class T1, class T2, class T3>\ntemplate<class T, size_t N> ostream& operator << (ostream& os, const array<T, N>& v);\nTT1T2 ostream& operator << (ostream& os, const pair<T1, T2>& p){ return os <<\"(\"<<p.first<<\", \"<< p.second<<\")\"; }\nTT1 ostream& operator << (ostream& os, const vector<T>& v){       bool f=1;os<<\"[\";for(auto& i : v) { if (!f)os << \", \";os<<i;f=0;}return os << \"]\"; }\ntemplate<class T, size_t N> ostream& operator << (ostream& os, const array<T, N>& v) {     bool f=1;os<<\"[\";for(auto& i : v) { if (!f)os << \", \";os<<i;f=0;}return os << \"]\"; }\nTT1T2 ostream& operator << (ostream& os, const set<T1, T2>&v){    bool f=1;os<<\"[\";for(auto& i : v) { if (!f)os << \", \";os<<i;f=0;}return os << \"]\"; }\nTT1T2 ostream& operator << (ostream& os, const multiset<T1,T2>&v){bool f=1;os<<\"[\";for(auto& i : v) { if (!f)os << \", \";os<<i;f=0;}return os << \"]\"; }\nTT1T2T3 ostream& operator << (ostream& os, const map<T1,T2,T3>& v){ bool f = 1; os << \"[\"; for (auto& ii : v) { if (!f)os << \", \"; os << \"(\" << ii.first << \" -> \" << ii.second << \") \"; f = 0; }return os << \"]\"; }\nTT1T2 ostream& operator << (ostream& os, const multimap<T1, T2>& v){ bool f = 1; os << \"[\"; for (auto& ii : v) { if (!f)os << \", \"; os << \"(\" << ii.first << \" -> \" << ii.second << \") \"; f = 0; }return os << \"]\"; }\nTT1T2 ostream& operator << (ostream& os, priority_queue<T1, T2> v) { bool f = 1; os << \"[\"; while (!v.empty()) { auto x = v.top(); v.pop(); if (!f) os << \", \"; f = 0; os << x; } return os << \"]\"; }\nTT1T2 void printarray(const T1& a, T2 sz, T2 beg = 0){ for (T2 i = beg; i<sz; i++) cout << a[i] << \" \"; cout << endl; }\n\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef pair<int, int> Pi;\ntypedef pair<ll, ll> Pll;\n\n#define Fi first\n#define Se second\n#define pb(x) push_back(x)\n#define sz(x) (int)x.size()\n#define rep(i, n) for(int i=0;i<n;i++)\n#define repp(i, n) for(int i=1;i<=n;i++)\n#define all(x) x.begin(), x.end()\n#define geti1(X) cin >> X\n#define geti2(X,Y) cin >> X >> Y\n#define geti3(X,Y,Z) cin >> X >> Y >> Z\n#define geti4(X,Y,Z,W) cin >> X >> Y >> Z >> W\n#define GET_MACRO(_1,_2,_3,_4,NAME,...) NAME\n#define geti(...) GET_MACRO(__VA_ARGS__, geti4, geti3, geti2, geti1) (__VA_ARGS__)\n\n#define INF 987654321\n\n#define endl '\\n'\nconst ll mod = 1e9+7;\nll fpow(ll a, ll b){\n\tll res = 1, t = a;\n\twhile( b ){\n\t\tif( b&1 ) res = (res*t)%mod;\n\t\tt = (t*t)%mod;\n\t\tb >>= 1;\n\t}\n\treturn res;\n}\nll inv(ll x){ return fpow(x,mod-2); }\nint p[100500];\nll fact[100500];\nll comb(ll n, ll m){\n\tif( m > n ) return 0LL;\n\tif( m == n || m == 0 ) return 1LL;\n\tll res = fact[n];\n\tres = (res * inv(fact[m]))%mod;\n\tres = (res * inv(fact[n-m]))%mod;\n\t//if( n == 0 ) Debug(m,res);\n\treturn res;\n}\nll ans[100500];\nint N;\nint main() {\n\tfact[0] = 1;\n\tfor(ll i=1;i<=100200;i++) fact[i] = (fact[i-1]*i)%mod;\n\n\tscanf(\"%d\",&N);\n\trepp(i,N+1) scanf(\"%d\",&p[i]);\n\tmap<int,vector<int>> mp;\n\trepp(i,N+1) mp[p[i]].pb(i);\n\tint i=0,j=0;\n\tfor(auto e : mp){\n\t\tif( sz(e.Se) >= 2 ){\n\t\t\ti = min(e.Se[0],e.Se[1]);\n\t\t\tj = max(e.Se[0],e.Se[1]);\n\t\t}\n\t}\n\n\tfor(ll i=1;i<=N;i++){\n\t\tans[i] = (ans[i] + comb(N,i))%mod;\n\t}\n\tll l = j-i;\n\tfor(ll m=1;m<=N;m++){\n\t\tll tmp = comb(N,m-1);\n\t\ttmp = (tmp - comb(N-l,m-1) + mod)%mod;\n\t\tans[m] = (ans[m] + tmp)%mod;\n\t}\n\n\n\tfor(ll i=1;i<=N;i++) printf(\"%lld\\n\",ans[i]);\n\tprintf(\"1\\n\");\n}", "language": "C++", "metadata": {"date": 1537693782, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03676.html", "problem_id": "p03676", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03676/input.txt", "sample_output_relpath": "derived/input_output/data/p03676/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03676/C++/s377158777.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s377158777", "user_id": "u903951856"}, "prompt_components": {"gold_output": "3\n5\n4\n1\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n\n#define VA_NUM_ARGS(...) VA_NUM_ARGS_IMPL_((0,__VA_ARGS__, 6,5,4,3,2,1))\n#define VA_NUM_ARGS_IMPL_(tuple) VA_NUM_ARGS_IMPL tuple\n#define VA_NUM_ARGS_IMPL(_0,_1,_2,_3,_4,_5,_6,N,...) N\n#define macro_dispatcher(macro, ...) macro_dispatcher_(macro, VA_NUM_ARGS(__VA_ARGS__))\n#define macro_dispatcher_(macro, nargs) macro_dispatcher__(macro, nargs)\n#define macro_dispatcher__(macro, nargs) macro_dispatcher___(macro, nargs)\n#define macro_dispatcher___(macro, nargs) macro ## nargs\n#define Debug1(a)           cout<<#a<<\"=\"<<(a)<<\"\\n\"\n#define Debug2(a,b)         cout<<#a<<\"=\"<<(a)<<\", \"<<#b<<\"=\"<<(b)<<\"\\n\"\n#define Debug3(a,b,c)       cout<<#a<<\"=\"<<(a)<<\", \"<<#b<<\"=\"<<(b)<<\", \"<<#c<<\"=\"<<(c)<<\"\\n\"\n#define Debug4(a,b,c,d)     cout<<#a<<\"=\"<<(a)<<\", \"<<#b<<\"=\"<<(b)<<\", \"<<#c<<\"=\"<<(c)<<\", \"<<#d<<\"=\"<<(d)<<\"\\n\"\n#define Debug5(a,b,c,d,e)   cout<<#a<<\"=\"<<(a)<<\", \"<<#b<<\"=\"<<(b)<<\", \"<<#c<<\"=\"<<(c)<<\", \"<<#d<<\"=\"<<(d)<<\", \"<<#e<<\"=\"<<(e)<<\"\\n\"\n#define Debug6(a,b,c,d,e,f) cout<<#a<<\"=\"<<(a)<<\", \"<<#b<<\"=\"<<(b)<<\", \"<<#c<<\"=\"<<(c)<<\", \"<<#d<<\"=\"<<(d)<<\", \"<<#e<<\"=\"<<(e)<<\", \"<<#f<<\"=\"<<(f)<<\"\\n\"\n#define Debug(...) macro_dispatcher(Debug, __VA_ARGS__)(__VA_ARGS__)\n#define DA(a,n) cout<<#a<<\"=[\"; printarray(a,n); cout<<\"]\\n\"\n#define DAR(a,n,s) cout<<#a<<\"[\"<<s<<\"-\"<<n-1<<\"]=[\"; printarray(a,n,s); cout<<\"]\\n\"\n\n#define TT1 template<class T>\n#define TT1T2 template<class T1, class T2>\n#define TT1T2T3 template<class T1, class T2, class T3>\ntemplate<class T, size_t N> ostream& operator << (ostream& os, const array<T, N>& v);\nTT1T2 ostream& operator << (ostream& os, const pair<T1, T2>& p){ return os <<\"(\"<<p.first<<\", \"<< p.second<<\")\"; }\nTT1 ostream& operator << (ostream& os, const vector<T>& v){       bool f=1;os<<\"[\";for(auto& i : v) { if (!f)os << \", \";os<<i;f=0;}return os << \"]\"; }\ntemplate<class T, size_t N> ostream& operator << (ostream& os, const array<T, N>& v) {     bool f=1;os<<\"[\";for(auto& i : v) { if (!f)os << \", \";os<<i;f=0;}return os << \"]\"; }\nTT1T2 ostream& operator << (ostream& os, const set<T1, T2>&v){    bool f=1;os<<\"[\";for(auto& i : v) { if (!f)os << \", \";os<<i;f=0;}return os << \"]\"; }\nTT1T2 ostream& operator << (ostream& os, const multiset<T1,T2>&v){bool f=1;os<<\"[\";for(auto& i : v) { if (!f)os << \", \";os<<i;f=0;}return os << \"]\"; }\nTT1T2T3 ostream& operator << (ostream& os, const map<T1,T2,T3>& v){ bool f = 1; os << \"[\"; for (auto& ii : v) { if (!f)os << \", \"; os << \"(\" << ii.first << \" -> \" << ii.second << \") \"; f = 0; }return os << \"]\"; }\nTT1T2 ostream& operator << (ostream& os, const multimap<T1, T2>& v){ bool f = 1; os << \"[\"; for (auto& ii : v) { if (!f)os << \", \"; os << \"(\" << ii.first << \" -> \" << ii.second << \") \"; f = 0; }return os << \"]\"; }\nTT1T2 ostream& operator << (ostream& os, priority_queue<T1, T2> v) { bool f = 1; os << \"[\"; while (!v.empty()) { auto x = v.top(); v.pop(); if (!f) os << \", \"; f = 0; os << x; } return os << \"]\"; }\nTT1T2 void printarray(const T1& a, T2 sz, T2 beg = 0){ for (T2 i = beg; i<sz; i++) cout << a[i] << \" \"; cout << endl; }\n\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef pair<int, int> Pi;\ntypedef pair<ll, ll> Pll;\n\n#define Fi first\n#define Se second\n#define pb(x) push_back(x)\n#define sz(x) (int)x.size()\n#define rep(i, n) for(int i=0;i<n;i++)\n#define repp(i, n) for(int i=1;i<=n;i++)\n#define all(x) x.begin(), x.end()\n#define geti1(X) cin >> X\n#define geti2(X,Y) cin >> X >> Y\n#define geti3(X,Y,Z) cin >> X >> Y >> Z\n#define geti4(X,Y,Z,W) cin >> X >> Y >> Z >> W\n#define GET_MACRO(_1,_2,_3,_4,NAME,...) NAME\n#define geti(...) GET_MACRO(__VA_ARGS__, geti4, geti3, geti2, geti1) (__VA_ARGS__)\n\n#define INF 987654321\n\n#define endl '\\n'\nconst ll mod = 1e9+7;\nll fpow(ll a, ll b){\n\tll res = 1, t = a;\n\twhile( b ){\n\t\tif( b&1 ) res = (res*t)%mod;\n\t\tt = (t*t)%mod;\n\t\tb >>= 1;\n\t}\n\treturn res;\n}\nll inv(ll x){ return fpow(x,mod-2); }\nint p[100500];\nll fact[100500];\nll comb(ll n, ll m){\n\tif( m > n ) return 0LL;\n\tif( m == n || m == 0 ) return 1LL;\n\tll res = fact[n];\n\tres = (res * inv(fact[m]))%mod;\n\tres = (res * inv(fact[n-m]))%mod;\n\t//if( n == 0 ) Debug(m,res);\n\treturn res;\n}\nll ans[100500];\nint N;\nint main() {\n\tfact[0] = 1;\n\tfor(ll i=1;i<=100200;i++) fact[i] = (fact[i-1]*i)%mod;\n\n\tscanf(\"%d\",&N);\n\trepp(i,N+1) scanf(\"%d\",&p[i]);\n\tmap<int,vector<int>> mp;\n\trepp(i,N+1) mp[p[i]].pb(i);\n\tint i=0,j=0;\n\tfor(auto e : mp){\n\t\tif( sz(e.Se) >= 2 ){\n\t\t\ti = min(e.Se[0],e.Se[1]);\n\t\t\tj = max(e.Se[0],e.Se[1]);\n\t\t}\n\t}\n\n\tfor(ll i=1;i<=N;i++){\n\t\tans[i] = (ans[i] + comb(N,i))%mod;\n\t}\n\tll l = j-i;\n\tfor(ll m=1;m<=N;m++){\n\t\tll tmp = comb(N,m-1);\n\t\ttmp = (tmp - comb(N-l,m-1) + mod)%mod;\n\t\tans[m] = (ans[m] + tmp)%mod;\n\t}\n\n\n\tfor(ll i=1;i<=N;i++) printf(\"%lld\\n\",ans[i]);\n\tprintf(\"1\\n\");\n}", "problem_context": "Score : 600 points\n\nProblem Statement\n\nYou are given an integer sequence of length n+1, a_1,a_2,...,a_{n+1}, which consists of the n integers 1,...,n.\nIt is known that each of the n integers 1,...,n appears at least once in this sequence.\n\nFor each integer k=1,...,n+1, find the number of the different subsequences (not necessarily contiguous) of the given sequence with length k, modulo 10^9+7.\n\nNotes\n\nIf the contents of two subsequences are the same, they are not separately counted even if they originate from different positions in the original sequence.\n\nA subsequence of a sequence a with length k is a sequence obtained by selecting k of the elements of a and arranging them without changing their relative order. For example, the sequences 1,3,5 and 1,2,3 are subsequences of 1,2,3,4,5, while 3,1,2 and 1,10,100 are not.\n\nConstraints\n\n1 \\leq n \\leq 10^5\n\n1 \\leq a_i \\leq n\n\nEach of the integers 1,...,n appears in the sequence.\n\nn and a_i are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn\na_1 a_2 ... a_{n+1}\n\nOutput\n\nPrint n+1 lines.\nThe k-th line should contain the number of the different subsequences of the given sequence with length k, modulo 10^9+7.\n\nSample Input 1\n\n3\n1 2 1 3\n\nSample Output 1\n\n3\n5\n4\n1\n\nThere are three subsequences with length 1: 1 and 2 and 3.\n\nThere are five subsequences with length 2: 1,1 and 1,2 and 1,3 and 2,1 and 2,3.\n\nThere are four subsequences with length 3: 1,1,3 and 1,2,1 and 1,2,3 and 2,1,3.\n\nThere is one subsequence with length 4: 1,2,1,3.\n\nSample Input 2\n\n1\n1 1\n\nSample Output 2\n\n1\n1\n\nThere is one subsequence with length 1: 1.\n\nThere is one subsequence with length 2: 1,1.\n\nSample Input 3\n\n32\n29 19 7 10 26 32 27 4 11 20 2 8 16 23 5 14 6 12 17 22 18 30 28 24 15 1 25 3 13 21 19 31 9\n\nSample Output 3\n\n32\n525\n5453\n40919\n237336\n1107568\n4272048\n13884156\n38567100\n92561040\n193536720\n354817320\n573166440\n818809200\n37158313\n166803103\n166803103\n37158313\n818809200\n573166440\n354817320\n193536720\n92561040\n38567100\n13884156\n4272048\n1107568\n237336\n40920\n5456\n528\n33\n1\n\nBe sure to print the numbers modulo 10^9+7.", "sample_input": "3\n1 2 1 3\n"}, "reference_outputs": ["3\n5\n4\n1\n"], "source_document_id": "p03676", "source_text": "Score : 600 points\n\nProblem Statement\n\nYou are given an integer sequence of length n+1, a_1,a_2,...,a_{n+1}, which consists of the n integers 1,...,n.\nIt is known that each of the n integers 1,...,n appears at least once in this sequence.\n\nFor each integer k=1,...,n+1, find the number of the different subsequences (not necessarily contiguous) of the given sequence with length k, modulo 10^9+7.\n\nNotes\n\nIf the contents of two subsequences are the same, they are not separately counted even if they originate from different positions in the original sequence.\n\nA subsequence of a sequence a with length k is a sequence obtained by selecting k of the elements of a and arranging them without changing their relative order. For example, the sequences 1,3,5 and 1,2,3 are subsequences of 1,2,3,4,5, while 3,1,2 and 1,10,100 are not.\n\nConstraints\n\n1 \\leq n \\leq 10^5\n\n1 \\leq a_i \\leq n\n\nEach of the integers 1,...,n appears in the sequence.\n\nn and a_i are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn\na_1 a_2 ... a_{n+1}\n\nOutput\n\nPrint n+1 lines.\nThe k-th line should contain the number of the different subsequences of the given sequence with length k, modulo 10^9+7.\n\nSample Input 1\n\n3\n1 2 1 3\n\nSample Output 1\n\n3\n5\n4\n1\n\nThere are three subsequences with length 1: 1 and 2 and 3.\n\nThere are five subsequences with length 2: 1,1 and 1,2 and 1,3 and 2,1 and 2,3.\n\nThere are four subsequences with length 3: 1,1,3 and 1,2,1 and 1,2,3 and 2,1,3.\n\nThere is one subsequence with length 4: 1,2,1,3.\n\nSample Input 2\n\n1\n1 1\n\nSample Output 2\n\n1\n1\n\nThere is one subsequence with length 1: 1.\n\nThere is one subsequence with length 2: 1,1.\n\nSample Input 3\n\n32\n29 19 7 10 26 32 27 4 11 20 2 8 16 23 5 14 6 12 17 22 18 30 28 24 15 1 25 3 13 21 19 31 9\n\nSample Output 3\n\n32\n525\n5453\n40919\n237336\n1107568\n4272048\n13884156\n38567100\n92561040\n193536720\n354817320\n573166440\n818809200\n37158313\n166803103\n166803103\n37158313\n818809200\n573166440\n354817320\n193536720\n92561040\n38567100\n13884156\n4272048\n1107568\n237336\n40920\n5456\n528\n33\n1\n\nBe sure to print the numbers modulo 10^9+7.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 4723, "cpu_time_ms": 162, "memory_kb": 14080}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s383344852", "group_id": "codeNet:p03679", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n    int x, a, b;\n    cin >> x >> a >> b;\n    if (a > b) {\n        cout << \"delicious\" << endl;\n    } else if (b - a <= x) {\n        cout << \"safe\" << endl;\n    } else {\n        cout << \"dangerous\" << endl;\n    }\n    return 0;\n}", "language": "C++", "metadata": {"date": 1583462016, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03679.html", "problem_id": "p03679", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03679/input.txt", "sample_output_relpath": "derived/input_output/data/p03679/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03679/C++/s383344852.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s383344852", "user_id": "u615258936"}, "prompt_components": {"gold_output": "safe\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main() {\n    int x, a, b;\n    cin >> x >> a >> b;\n    if (a > b) {\n        cout << \"delicious\" << endl;\n    } else if (b - a <= x) {\n        cout << \"safe\" << endl;\n    } else {\n        cout << \"dangerous\" << endl;\n    }\n    return 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nTakahashi has a strong stomach. He never gets a stomachache from eating something whose \"best-by\" date is at most X days earlier.\nHe gets a stomachache if the \"best-by\" date of the food is X+1 or more days earlier, though.\n\nOther than that, he finds the food delicious if he eats it not later than the \"best-by\" date. Otherwise, he does not find it delicious.\n\nTakahashi bought some food A days before the \"best-by\" date, and ate it B days after he bought it.\n\nWrite a program that outputs delicious if he found it delicious, safe if he did not found it delicious but did not get a stomachache either, and dangerous if he got a stomachache.\n\nConstraints\n\n1 ≤ X,A,B ≤ 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX A B\n\nOutput\n\nPrint delicious if Takahashi found the food delicious; print safe if he neither found it delicious nor got a stomachache; print dangerous if he got a stomachache.\n\nSample Input 1\n\n4 3 6\n\nSample Output 1\n\nsafe\n\nHe ate the food three days after the \"best-by\" date. It was not delicious or harmful for him.\n\nSample Input 2\n\n6 5 1\n\nSample Output 2\n\ndelicious\n\nHe ate the food by the \"best-by\" date. It was delicious for him.\n\nSample Input 3\n\n3 7 12\n\nSample Output 3\n\ndangerous\n\nHe ate the food five days after the \"best-by\" date. It was harmful for him.", "sample_input": "4 3 6\n"}, "reference_outputs": ["safe\n"], "source_document_id": "p03679", "source_text": "Score : 100 points\n\nProblem Statement\n\nTakahashi has a strong stomach. He never gets a stomachache from eating something whose \"best-by\" date is at most X days earlier.\nHe gets a stomachache if the \"best-by\" date of the food is X+1 or more days earlier, though.\n\nOther than that, he finds the food delicious if he eats it not later than the \"best-by\" date. Otherwise, he does not find it delicious.\n\nTakahashi bought some food A days before the \"best-by\" date, and ate it B days after he bought it.\n\nWrite a program that outputs delicious if he found it delicious, safe if he did not found it delicious but did not get a stomachache either, and dangerous if he got a stomachache.\n\nConstraints\n\n1 ≤ X,A,B ≤ 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX A B\n\nOutput\n\nPrint delicious if Takahashi found the food delicious; print safe if he neither found it delicious nor got a stomachache; print dangerous if he got a stomachache.\n\nSample Input 1\n\n4 3 6\n\nSample Output 1\n\nsafe\n\nHe ate the food three days after the \"best-by\" date. It was not delicious or harmful for him.\n\nSample Input 2\n\n6 5 1\n\nSample Output 2\n\ndelicious\n\nHe ate the food by the \"best-by\" date. It was delicious for him.\n\nSample Input 3\n\n3 7 12\n\nSample Output 3\n\ndangerous\n\nHe ate the food five days after the \"best-by\" date. It was harmful for him.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 287, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s228499565", "group_id": "codeNet:p03680", "input_text": "#include <iostream>\n#include <algorithm>\n\nusing namespace std;\ntypedef long long  ll;\n#define rep(i,s,n)for(ll i = s;i<n;i++)\n\nint main() {\n\tint N; cin >> N;\n\tint a[100001];\n\trep(i, 1, N + 1) {\n\t\tcin >> a[i];\n\t}\n\n\tint p = 1;\n\tint count = 0;\n\tbool isTwo = false;\n\trep(i, 1, N + 1) {\n\t\tcount++;\n\t\tint c = a[p];\n\t\tif (c == 2) {\n\t\t\tisTwo = true;\n\t\t\tbreak;\n\t\t}\n\t\tp = c;\n\t}\n\n\tcout << ((isTwo) ? count : -1) << endl;\n}", "language": "C++", "metadata": {"date": 1520112250, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03680.html", "problem_id": "p03680", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03680/input.txt", "sample_output_relpath": "derived/input_output/data/p03680/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03680/C++/s228499565.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s228499565", "user_id": "u147154640"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <iostream>\n#include <algorithm>\n\nusing namespace std;\ntypedef long long  ll;\n#define rep(i,s,n)for(ll i = s;i<n;i++)\n\nint main() {\n\tint N; cin >> N;\n\tint a[100001];\n\trep(i, 1, N + 1) {\n\t\tcin >> a[i];\n\t}\n\n\tint p = 1;\n\tint count = 0;\n\tbool isTwo = false;\n\trep(i, 1, N + 1) {\n\t\tcount++;\n\t\tint c = a[p];\n\t\tif (c == 2) {\n\t\t\tisTwo = true;\n\t\t\tbreak;\n\t\t}\n\t\tp = c;\n\t}\n\n\tcout << ((isTwo) ? count : -1) << endl;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nTakahashi wants to gain muscle, and decides to work out at AtCoder Gym.\n\nThe exercise machine at the gym has N buttons, and exactly one of the buttons is lighten up.\nThese buttons are numbered 1 through N.\nWhen Button i is lighten up and you press it, the light is turned off, and then Button a_i will be lighten up. It is possible that i=a_i.\nWhen Button i is not lighten up, nothing will happen by pressing it.\n\nInitially, Button 1 is lighten up. Takahashi wants to quit pressing buttons when Button 2 is lighten up.\n\nDetermine whether this is possible. If the answer is positive, find the minimum number of times he needs to press buttons.\n\nConstraints\n\n2 ≤ N ≤ 10^5\n\n1 ≤ a_i ≤ N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1\na_2\n:\na_N\n\nOutput\n\nPrint -1 if it is impossible to lighten up Button 2.\nOtherwise, print the minimum number of times we need to press buttons in order to lighten up Button 2.\n\nSample Input 1\n\n3\n3\n1\n2\n\nSample Output 1\n\n2\n\nPress Button 1, then Button 3.\n\nSample Input 2\n\n4\n3\n4\n1\n2\n\nSample Output 2\n\n-1\n\nPressing Button 1 lightens up Button 3, and vice versa, so Button 2 will never be lighten up.\n\nSample Input 3\n\n5\n3\n3\n4\n2\n4\n\nSample Output 3\n\n3", "sample_input": "3\n3\n1\n2\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03680", "source_text": "Score : 200 points\n\nProblem Statement\n\nTakahashi wants to gain muscle, and decides to work out at AtCoder Gym.\n\nThe exercise machine at the gym has N buttons, and exactly one of the buttons is lighten up.\nThese buttons are numbered 1 through N.\nWhen Button i is lighten up and you press it, the light is turned off, and then Button a_i will be lighten up. It is possible that i=a_i.\nWhen Button i is not lighten up, nothing will happen by pressing it.\n\nInitially, Button 1 is lighten up. Takahashi wants to quit pressing buttons when Button 2 is lighten up.\n\nDetermine whether this is possible. If the answer is positive, find the minimum number of times he needs to press buttons.\n\nConstraints\n\n2 ≤ N ≤ 10^5\n\n1 ≤ a_i ≤ N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1\na_2\n:\na_N\n\nOutput\n\nPrint -1 if it is impossible to lighten up Button 2.\nOtherwise, print the minimum number of times we need to press buttons in order to lighten up Button 2.\n\nSample Input 1\n\n3\n3\n1\n2\n\nSample Output 1\n\n2\n\nPress Button 1, then Button 3.\n\nSample Input 2\n\n4\n3\n4\n1\n2\n\nSample Output 2\n\n-1\n\nPressing Button 1 lightens up Button 3, and vice versa, so Button 2 will never be lighten up.\n\nSample Input 3\n\n5\n3\n3\n4\n2\n4\n\nSample Output 3\n\n3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 411, "cpu_time_ms": 39, "memory_kb": 640}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s877009569", "group_id": "codeNet:p03680", "input_text": "#include <iostream>\n#include <set>\nusing namespace std;\n\nint a[100010];\nset<int>s;\n\nint main () {\n\t\nint n;\ncin>>n;\nfor (int i=0; i<n; i++) {\n\tcin>>a[i];\n}\t\nint br=0;\nint t=1;\ns.insert(1);\nwhile (t!=2) {\n\tt=a[t-1];\n\tint ss=s.size();\n\ts.insert(t);\n\tif (ss==s.size()) {cout<<-1; return 0;}\n\tbr++;\n}\ncout<<br;\n\t\nreturn 0;\n}", "language": "C++", "metadata": {"date": 1498354076, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03680.html", "problem_id": "p03680", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03680/input.txt", "sample_output_relpath": "derived/input_output/data/p03680/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03680/C++/s877009569.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s877009569", "user_id": "u861532527"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <iostream>\n#include <set>\nusing namespace std;\n\nint a[100010];\nset<int>s;\n\nint main () {\n\t\nint n;\ncin>>n;\nfor (int i=0; i<n; i++) {\n\tcin>>a[i];\n}\t\nint br=0;\nint t=1;\ns.insert(1);\nwhile (t!=2) {\n\tt=a[t-1];\n\tint ss=s.size();\n\ts.insert(t);\n\tif (ss==s.size()) {cout<<-1; return 0;}\n\tbr++;\n}\ncout<<br;\n\t\nreturn 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nTakahashi wants to gain muscle, and decides to work out at AtCoder Gym.\n\nThe exercise machine at the gym has N buttons, and exactly one of the buttons is lighten up.\nThese buttons are numbered 1 through N.\nWhen Button i is lighten up and you press it, the light is turned off, and then Button a_i will be lighten up. It is possible that i=a_i.\nWhen Button i is not lighten up, nothing will happen by pressing it.\n\nInitially, Button 1 is lighten up. Takahashi wants to quit pressing buttons when Button 2 is lighten up.\n\nDetermine whether this is possible. If the answer is positive, find the minimum number of times he needs to press buttons.\n\nConstraints\n\n2 ≤ N ≤ 10^5\n\n1 ≤ a_i ≤ N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1\na_2\n:\na_N\n\nOutput\n\nPrint -1 if it is impossible to lighten up Button 2.\nOtherwise, print the minimum number of times we need to press buttons in order to lighten up Button 2.\n\nSample Input 1\n\n3\n3\n1\n2\n\nSample Output 1\n\n2\n\nPress Button 1, then Button 3.\n\nSample Input 2\n\n4\n3\n4\n1\n2\n\nSample Output 2\n\n-1\n\nPressing Button 1 lightens up Button 3, and vice versa, so Button 2 will never be lighten up.\n\nSample Input 3\n\n5\n3\n3\n4\n2\n4\n\nSample Output 3\n\n3", "sample_input": "3\n3\n1\n2\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03680", "source_text": "Score : 200 points\n\nProblem Statement\n\nTakahashi wants to gain muscle, and decides to work out at AtCoder Gym.\n\nThe exercise machine at the gym has N buttons, and exactly one of the buttons is lighten up.\nThese buttons are numbered 1 through N.\nWhen Button i is lighten up and you press it, the light is turned off, and then Button a_i will be lighten up. It is possible that i=a_i.\nWhen Button i is not lighten up, nothing will happen by pressing it.\n\nInitially, Button 1 is lighten up. Takahashi wants to quit pressing buttons when Button 2 is lighten up.\n\nDetermine whether this is possible. If the answer is positive, find the minimum number of times he needs to press buttons.\n\nConstraints\n\n2 ≤ N ≤ 10^5\n\n1 ≤ a_i ≤ N\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1\na_2\n:\na_N\n\nOutput\n\nPrint -1 if it is impossible to lighten up Button 2.\nOtherwise, print the minimum number of times we need to press buttons in order to lighten up Button 2.\n\nSample Input 1\n\n3\n3\n1\n2\n\nSample Output 1\n\n2\n\nPress Button 1, then Button 3.\n\nSample Input 2\n\n4\n3\n4\n1\n2\n\nSample Output 2\n\n-1\n\nPressing Button 1 lightens up Button 3, and vice versa, so Button 2 will never be lighten up.\n\nSample Input 3\n\n5\n3\n3\n4\n2\n4\n\nSample Output 3\n\n3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 319, "cpu_time_ms": 65, "memory_kb": 5376}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s687611068", "group_id": "codeNet:p03681", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n    long long ans,o=1,p=1,mod=1000000007;\n    int n,m;\n    scanf(\"%d %d\",&n,&m);\n    if (abs(n-m)>1) {\n        printf(\"0\\n\");\n    } else {\n        for (int i=1;i<=min(n,m);i++) {\n            o*=i;\n            p*=i;\n            o%=mod;\n            p%=mod;\n        }\n        if (abs(n-m)%2) {\n            o*=max(n,m);\n            o%=mod;\n            ans=(o*p)%mod;\n        } else {\n            ans=(o*p*2)%mod;\n        }\n    }\n    printf(\"%lld\\n\",ans);\n    return 0;\n}", "language": "C++", "metadata": {"date": 1541732972, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03681.html", "problem_id": "p03681", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03681/input.txt", "sample_output_relpath": "derived/input_output/data/p03681/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03681/C++/s687611068.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s687611068", "user_id": "u123756661"}, "prompt_components": {"gold_output": "8\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n    long long ans,o=1,p=1,mod=1000000007;\n    int n,m;\n    scanf(\"%d %d\",&n,&m);\n    if (abs(n-m)>1) {\n        printf(\"0\\n\");\n    } else {\n        for (int i=1;i<=min(n,m);i++) {\n            o*=i;\n            p*=i;\n            o%=mod;\n            p%=mod;\n        }\n        if (abs(n-m)%2) {\n            o*=max(n,m);\n            o%=mod;\n            ans=(o*p)%mod;\n        } else {\n            ans=(o*p*2)%mod;\n        }\n    }\n    printf(\"%lld\\n\",ans);\n    return 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nSnuke has N dogs and M monkeys. He wants them to line up in a row.\n\nAs a Japanese saying goes, these dogs and monkeys are on bad terms. (\"ken'en no naka\", literally \"the relationship of dogs and monkeys\", means a relationship of mutual hatred.) Snuke is trying to reconsile them, by arranging the animals so that there are neither two adjacent dogs nor two adjacent monkeys.\n\nHow many such arrangements there are? Find the count modulo 10^9+7 (since animals cannot understand numbers larger than that).\nHere, dogs and monkeys are both distinguishable. Also, two arrangements that result from reversing each other are distinguished.\n\nConstraints\n\n1 ≤ N,M ≤ 10^5\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\n\nOutput\n\nPrint the number of possible arrangements, modulo 10^9+7.\n\nSample Input 1\n\n2 2\n\nSample Output 1\n\n8\n\nWe will denote the dogs by A and B, and the monkeys by C and D. There are eight possible arrangements: ACBD, ADBC, BCAD, BDAC, CADB, CBDA, DACB and DBCA.\n\nSample Input 2\n\n3 2\n\nSample Output 2\n\n12\n\nSample Input 3\n\n1 8\n\nSample Output 3\n\n0\n\nSample Input 4\n\n100000 100000\n\nSample Output 4\n\n530123477", "sample_input": "2 2\n"}, "reference_outputs": ["8\n"], "source_document_id": "p03681", "source_text": "Score : 300 points\n\nProblem Statement\n\nSnuke has N dogs and M monkeys. He wants them to line up in a row.\n\nAs a Japanese saying goes, these dogs and monkeys are on bad terms. (\"ken'en no naka\", literally \"the relationship of dogs and monkeys\", means a relationship of mutual hatred.) Snuke is trying to reconsile them, by arranging the animals so that there are neither two adjacent dogs nor two adjacent monkeys.\n\nHow many such arrangements there are? Find the count modulo 10^9+7 (since animals cannot understand numbers larger than that).\nHere, dogs and monkeys are both distinguishable. Also, two arrangements that result from reversing each other are distinguished.\n\nConstraints\n\n1 ≤ N,M ≤ 10^5\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\n\nOutput\n\nPrint the number of possible arrangements, modulo 10^9+7.\n\nSample Input 1\n\n2 2\n\nSample Output 1\n\n8\n\nWe will denote the dogs by A and B, and the monkeys by C and D. There are eight possible arrangements: ACBD, ADBC, BCAD, BDAC, CADB, CBDA, DACB and DBCA.\n\nSample Input 2\n\n3 2\n\nSample Output 2\n\n12\n\nSample Input 3\n\n1 8\n\nSample Output 3\n\n0\n\nSample Input 4\n\n100000 100000\n\nSample Output 4\n\n530123477", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 524, "cpu_time_ms": 2, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s555330285", "group_id": "codeNet:p03687", "input_text": "#include <bits/stdc++.h>\n\n#define REP(i, x, n) for (int i = x; i < (int)(n); i++)\n#define rep(i, n) REP(i, 0, n)\n#define all(x) (x).begin(), (x).end()\n#define rall(x) (x).rbegin(), (x).rend()\n#define sz(x) (int)(x.size())\n#define popcount(x) __builtin_popcount(x)\n#define popcountll(x) __builtin_popcountll(x)\n#define uniq(x) x.erase(unique(x.begin(), x.end()), x.end())\n#define F first\n#define S second\n#define mp make_pair\n#define eb emplace_back\n#define pii pair<int, int>\n#define pll pair<ll, ll>\n\nusing namespace std;\n\ntypedef long long ll;\n\n/* --- INFやMODの値が適切か確認する --- */\n// const int INF = 1 << 30;\n// const ll INF = 1LL << 60;\n// const ll MOD = 1000000007;\n\nint main() {\n  string t;\n  cin >> t;\n\n  int ans = 100000;\n\n  rep(i, 26) {\n    char ch = 'a' + i;\n    string s = t;\n    do {\n      bool f = true;\n      rep(j, s.size()) if (s[j] != ch) f = false;\n      if (f) ans = min(ans, (int)(t.size() - s.size()));\n\n      string tmp = \"\";\n      rep(j, s.size() - 1) {\n        if (s[j] == ch || s[j + 1] == ch)\n          tmp += ch;\n        else\n          tmp += '-';\n      }\n      s = tmp;\n    } while (s.size());\n  }\n\n  cout << ans << endl;\n}\n", "language": "C++", "metadata": {"date": 1581044722, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03687.html", "problem_id": "p03687", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03687/input.txt", "sample_output_relpath": "derived/input_output/data/p03687/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03687/C++/s555330285.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s555330285", "user_id": "u267022560"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\n#define REP(i, x, n) for (int i = x; i < (int)(n); i++)\n#define rep(i, n) REP(i, 0, n)\n#define all(x) (x).begin(), (x).end()\n#define rall(x) (x).rbegin(), (x).rend()\n#define sz(x) (int)(x.size())\n#define popcount(x) __builtin_popcount(x)\n#define popcountll(x) __builtin_popcountll(x)\n#define uniq(x) x.erase(unique(x.begin(), x.end()), x.end())\n#define F first\n#define S second\n#define mp make_pair\n#define eb emplace_back\n#define pii pair<int, int>\n#define pll pair<ll, ll>\n\nusing namespace std;\n\ntypedef long long ll;\n\n/* --- INFやMODの値が適切か確認する --- */\n// const int INF = 1 << 30;\n// const ll INF = 1LL << 60;\n// const ll MOD = 1000000007;\n\nint main() {\n  string t;\n  cin >> t;\n\n  int ans = 100000;\n\n  rep(i, 26) {\n    char ch = 'a' + i;\n    string s = t;\n    do {\n      bool f = true;\n      rep(j, s.size()) if (s[j] != ch) f = false;\n      if (f) ans = min(ans, (int)(t.size() - s.size()));\n\n      string tmp = \"\";\n      rep(j, s.size() - 1) {\n        if (s[j] == ch || s[j + 1] == ch)\n          tmp += ch;\n        else\n          tmp += '-';\n      }\n      s = tmp;\n    } while (s.size());\n  }\n\n  cout << ans << endl;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nSnuke can change a string t of length N into a string t' of length N - 1 under the following rule:\n\nFor each i (1 ≤ i ≤ N - 1), the i-th character of t' must be either the i-th or (i + 1)-th character of t.\n\nThere is a string s consisting of lowercase English letters.\nSnuke's objective is to apply the above operation to s repeatedly so that all the characters in s are the same.\nFind the minimum necessary number of operations.\n\nConstraints\n\n1 ≤ |s| ≤ 100\n\ns consists of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\ns\n\nOutput\n\nPrint the minimum necessary number of operations to achieve the objective.\n\nSample Input 1\n\nserval\n\nSample Output 1\n\n3\n\nOne solution is: serval → srvvl → svvv → vvv.\n\nSample Input 2\n\njackal\n\nSample Output 2\n\n2\n\nOne solution is: jackal → aacaa → aaaa.\n\nSample Input 3\n\nzzz\n\nSample Output 3\n\n0\n\nAll the characters in s are the same from the beginning.\n\nSample Input 4\n\nwhbrjpjyhsrywlqjxdbrbaomnw\n\nSample Output 4\n\n8\n\nIn 8 operations, he can change s to rrrrrrrrrrrrrrrrrr.", "sample_input": "serval\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03687", "source_text": "Score : 300 points\n\nProblem Statement\n\nSnuke can change a string t of length N into a string t' of length N - 1 under the following rule:\n\nFor each i (1 ≤ i ≤ N - 1), the i-th character of t' must be either the i-th or (i + 1)-th character of t.\n\nThere is a string s consisting of lowercase English letters.\nSnuke's objective is to apply the above operation to s repeatedly so that all the characters in s are the same.\nFind the minimum necessary number of operations.\n\nConstraints\n\n1 ≤ |s| ≤ 100\n\ns consists of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\ns\n\nOutput\n\nPrint the minimum necessary number of operations to achieve the objective.\n\nSample Input 1\n\nserval\n\nSample Output 1\n\n3\n\nOne solution is: serval → srvvl → svvv → vvv.\n\nSample Input 2\n\njackal\n\nSample Output 2\n\n2\n\nOne solution is: jackal → aacaa → aaaa.\n\nSample Input 3\n\nzzz\n\nSample Output 3\n\n0\n\nAll the characters in s are the same from the beginning.\n\nSample Input 4\n\nwhbrjpjyhsrywlqjxdbrbaomnw\n\nSample Output 4\n\n8\n\nIn 8 operations, he can change s to rrrrrrrrrrrrrrrrrr.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1169, "cpu_time_ms": 3, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s781745273", "group_id": "codeNet:p03687", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n#define REP(i, n) for(int i = 0; i < n; i++)\n\nint main(){\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n\n    string s;\n    cin >> s;\n    map<char, int> mp;\n    REP(i, s.size()) mp[s[i]]++;\n\n    int ma = 0;\n    for(auto x : mp) ma = max(ma, x.second);\n\n    if(ma == s.size()){\n        cout << 0 << endl;\n        return 0;\n    }\n    if(ma == 1){\n        cout << max((int)(s.size() - 3), 1) << endl;\n        return 0;\n    }\n\n    vector<char> C;\n    for(auto x : mp){\n        if(x.second == ma){\n            C.push_back(x.first);\n        }\n    }\n\n    int mi = 100;\n    REP(i, C.size()){\n        string a = s, b = \"\";\n        while(true){\n            int cnt = 0;\n            REP(j, a.size() - 1){\n                if(a[j] == C[i] or a[j + 1] == C[i]){\n                    b += C[i];\n                    cnt++;\n                }else b += a[j];\n            }\n            set<char> st;\n            REP(j, a.size()) st.insert(a[j]);\n            if(st.size() == 1){\n                mi = min(mi, (int)(s.size() - a.size()));\n                break;\n            }\n            a = b;\n            b = \"\";\n        }\n    }\n    cout << mi << endl;\n\n    return 0;\n}", "language": "C++", "metadata": {"date": 1526081995, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03687.html", "problem_id": "p03687", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03687/input.txt", "sample_output_relpath": "derived/input_output/data/p03687/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03687/C++/s781745273.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s781745273", "user_id": "u136869985"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n#define REP(i, n) for(int i = 0; i < n; i++)\n\nint main(){\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n\n    string s;\n    cin >> s;\n    map<char, int> mp;\n    REP(i, s.size()) mp[s[i]]++;\n\n    int ma = 0;\n    for(auto x : mp) ma = max(ma, x.second);\n\n    if(ma == s.size()){\n        cout << 0 << endl;\n        return 0;\n    }\n    if(ma == 1){\n        cout << max((int)(s.size() - 3), 1) << endl;\n        return 0;\n    }\n\n    vector<char> C;\n    for(auto x : mp){\n        if(x.second == ma){\n            C.push_back(x.first);\n        }\n    }\n\n    int mi = 100;\n    REP(i, C.size()){\n        string a = s, b = \"\";\n        while(true){\n            int cnt = 0;\n            REP(j, a.size() - 1){\n                if(a[j] == C[i] or a[j + 1] == C[i]){\n                    b += C[i];\n                    cnt++;\n                }else b += a[j];\n            }\n            set<char> st;\n            REP(j, a.size()) st.insert(a[j]);\n            if(st.size() == 1){\n                mi = min(mi, (int)(s.size() - a.size()));\n                break;\n            }\n            a = b;\n            b = \"\";\n        }\n    }\n    cout << mi << endl;\n\n    return 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nSnuke can change a string t of length N into a string t' of length N - 1 under the following rule:\n\nFor each i (1 ≤ i ≤ N - 1), the i-th character of t' must be either the i-th or (i + 1)-th character of t.\n\nThere is a string s consisting of lowercase English letters.\nSnuke's objective is to apply the above operation to s repeatedly so that all the characters in s are the same.\nFind the minimum necessary number of operations.\n\nConstraints\n\n1 ≤ |s| ≤ 100\n\ns consists of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\ns\n\nOutput\n\nPrint the minimum necessary number of operations to achieve the objective.\n\nSample Input 1\n\nserval\n\nSample Output 1\n\n3\n\nOne solution is: serval → srvvl → svvv → vvv.\n\nSample Input 2\n\njackal\n\nSample Output 2\n\n2\n\nOne solution is: jackal → aacaa → aaaa.\n\nSample Input 3\n\nzzz\n\nSample Output 3\n\n0\n\nAll the characters in s are the same from the beginning.\n\nSample Input 4\n\nwhbrjpjyhsrywlqjxdbrbaomnw\n\nSample Output 4\n\n8\n\nIn 8 operations, he can change s to rrrrrrrrrrrrrrrrrr.", "sample_input": "serval\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03687", "source_text": "Score : 300 points\n\nProblem Statement\n\nSnuke can change a string t of length N into a string t' of length N - 1 under the following rule:\n\nFor each i (1 ≤ i ≤ N - 1), the i-th character of t' must be either the i-th or (i + 1)-th character of t.\n\nThere is a string s consisting of lowercase English letters.\nSnuke's objective is to apply the above operation to s repeatedly so that all the characters in s are the same.\nFind the minimum necessary number of operations.\n\nConstraints\n\n1 ≤ |s| ≤ 100\n\ns consists of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\ns\n\nOutput\n\nPrint the minimum necessary number of operations to achieve the objective.\n\nSample Input 1\n\nserval\n\nSample Output 1\n\n3\n\nOne solution is: serval → srvvl → svvv → vvv.\n\nSample Input 2\n\njackal\n\nSample Output 2\n\n2\n\nOne solution is: jackal → aacaa → aaaa.\n\nSample Input 3\n\nzzz\n\nSample Output 3\n\n0\n\nAll the characters in s are the same from the beginning.\n\nSample Input 4\n\nwhbrjpjyhsrywlqjxdbrbaomnw\n\nSample Output 4\n\n8\n\nIn 8 operations, he can change s to rrrrrrrrrrrrrrrrrr.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1195, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s526262749", "group_id": "codeNet:p03688", "input_text": "// In the name of God\n\n#include <iostream>\n#include <algorithm>\n#include <fstream>\n#include <vector>\n#include <deque>\n#include <assert.h>\n#include <queue>\n#include <stack>\n#include <set>\n#include <map>\n#include <stdio.h>\n#include <string.h>\n#include <utility>\n#include <math.h>\n#include <bitset>\n#include <iomanip>\n#include <complex>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (a), i##_end_ = (b); i < i##_end_; ++i)\n#define debug(...) fprintf(stderr, __VA_ARGS__)\n#define mp make_pair\n#define x first\n#define y second\n#define pb push_back\n#define SZ(x) (int((x).size()))\n#define ALL(x) (x).begin(), (x).end()\n\ntemplate<typename T> inline bool chkmin(T &a, const T &b) { return a > b ? a = b, 1 : 0; }\ntemplate<typename T> inline bool chkmax(T &a, const T &b) { return a < b ? a = b, 1 : 0; }\ntemplate<typename T> inline bool smin(T &a, const T &b)   { return a > b ? a = b : a;    }\ntemplate<typename T> inline bool smax(T &a, const T &b)   { return a < b ? a = b : a;    }\n\ntypedef long long LL;\n\nconst int N = (int) 1e6 + 6, mod = (int) 0;\nint a[N];\nint main() {\n\tint n;\n\tcin >> n;\n\tint mx = -1e9, mn = 1e9, cnt = 0;\n\tfor (int j = 0; j < n; ++j) {\n\t\tcin >> a[j];\n\t\tmx = max(mx, a[j]);\n\t\tmn = min(mn, a[j]);\n\t}\n\tif (mx - mn > 1) {\n\t\tcout << \"No\\n\";\n\t\treturn 0;\n\t}\n\tfor (int j = 0; j < n; ++j)\n\t\tcnt += (a[j] == mx);\n\tif (mx == mn) {\n\t\tif (mx == n - 1) {\n\t\t\tcout << \"Yes\\n\";\n\t\t\treturn 0;\n\t\t}\n\t\tif (mx <= n / 2) {\n\t\t\tcout << \"Yes\\n\";\n\t\t\treturn 0;\n\t\t}\n\t\tcout << \"No\\n\";\n\t\treturn 0;\n\t}\n\tint less = (n - cnt) + (cnt >= 1), most = (n - cnt) + (cnt / 2);\n\tfor (int j = 0; j < n; ++j) {\n\t\tif (a[j] + 1 < less) {\n\t\t\tcout << \"No\\n\";\n\t\t\treturn 0;\n\t\t}\n\t\tif (a[j] > most) {\n\t\t\tcout << \"No\\n\";\n\t\t\treturn 0;\n\t\t}\n\t}\n\tcout << \"Yes\\n\";\n}\n\n\n", "language": "C++", "metadata": {"date": 1497834591, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03688.html", "problem_id": "p03688", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03688/input.txt", "sample_output_relpath": "derived/input_output/data/p03688/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03688/C++/s526262749.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s526262749", "user_id": "u926591917"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "// In the name of God\n\n#include <iostream>\n#include <algorithm>\n#include <fstream>\n#include <vector>\n#include <deque>\n#include <assert.h>\n#include <queue>\n#include <stack>\n#include <set>\n#include <map>\n#include <stdio.h>\n#include <string.h>\n#include <utility>\n#include <math.h>\n#include <bitset>\n#include <iomanip>\n#include <complex>\n\nusing namespace std;\n\n#define rep(i, a, b) for (int i = (a), i##_end_ = (b); i < i##_end_; ++i)\n#define debug(...) fprintf(stderr, __VA_ARGS__)\n#define mp make_pair\n#define x first\n#define y second\n#define pb push_back\n#define SZ(x) (int((x).size()))\n#define ALL(x) (x).begin(), (x).end()\n\ntemplate<typename T> inline bool chkmin(T &a, const T &b) { return a > b ? a = b, 1 : 0; }\ntemplate<typename T> inline bool chkmax(T &a, const T &b) { return a < b ? a = b, 1 : 0; }\ntemplate<typename T> inline bool smin(T &a, const T &b)   { return a > b ? a = b : a;    }\ntemplate<typename T> inline bool smax(T &a, const T &b)   { return a < b ? a = b : a;    }\n\ntypedef long long LL;\n\nconst int N = (int) 1e6 + 6, mod = (int) 0;\nint a[N];\nint main() {\n\tint n;\n\tcin >> n;\n\tint mx = -1e9, mn = 1e9, cnt = 0;\n\tfor (int j = 0; j < n; ++j) {\n\t\tcin >> a[j];\n\t\tmx = max(mx, a[j]);\n\t\tmn = min(mn, a[j]);\n\t}\n\tif (mx - mn > 1) {\n\t\tcout << \"No\\n\";\n\t\treturn 0;\n\t}\n\tfor (int j = 0; j < n; ++j)\n\t\tcnt += (a[j] == mx);\n\tif (mx == mn) {\n\t\tif (mx == n - 1) {\n\t\t\tcout << \"Yes\\n\";\n\t\t\treturn 0;\n\t\t}\n\t\tif (mx <= n / 2) {\n\t\t\tcout << \"Yes\\n\";\n\t\t\treturn 0;\n\t\t}\n\t\tcout << \"No\\n\";\n\t\treturn 0;\n\t}\n\tint less = (n - cnt) + (cnt >= 1), most = (n - cnt) + (cnt / 2);\n\tfor (int j = 0; j < n; ++j) {\n\t\tif (a[j] + 1 < less) {\n\t\t\tcout << \"No\\n\";\n\t\t\treturn 0;\n\t\t}\n\t\tif (a[j] > most) {\n\t\t\tcout << \"No\\n\";\n\t\t\treturn 0;\n\t\t}\n\t}\n\tcout << \"Yes\\n\";\n}\n\n\n", "problem_context": "Score : 700 points\n\nProblem Statement\n\nThere are N cats.\nWe number them from 1 through N.\n\nEach of the cats wears a hat.\nCat i says: \"there are exactly a_i different colors among the N - 1 hats worn by the cats except me.\"\n\nDetermine whether there exists a sequence of colors of the hats that is consistent with the remarks of the cats.\n\nConstraints\n\n2 ≤ N ≤ 10^5\n\n1 ≤ a_i ≤ N-1\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_N\n\nOutput\n\nPrint Yes if there exists a sequence of colors of the hats that is consistent with the remarks of the cats; print No otherwise.\n\nSample Input 1\n\n3\n1 2 2\n\nSample Output 1\n\nYes\n\nFor example, if cat 1, 2 and 3 wears red, blue and blue hats, respectively, it is consistent with the remarks of the cats.\n\nSample Input 2\n\n3\n1 1 2\n\nSample Output 2\n\nNo\n\nFrom the remark of cat 1, we can see that cat 2 and 3 wear hats of the same color.\nAlso, from the remark of cat 2, we can see that cat 1 and 3 wear hats of the same color.\nTherefore, cat 1 and 2 wear hats of the same color, which contradicts the remark of cat 3.\n\nSample Input 3\n\n5\n4 3 4 3 4\n\nSample Output 3\n\nNo\n\nSample Input 4\n\n3\n2 2 2\n\nSample Output 4\n\nYes\n\nSample Input 5\n\n4\n2 2 2 2\n\nSample Output 5\n\nYes\n\nSample Input 6\n\n5\n3 3 3 3 3\n\nSample Output 6\n\nNo", "sample_input": "3\n1 2 2\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p03688", "source_text": "Score : 700 points\n\nProblem Statement\n\nThere are N cats.\nWe number them from 1 through N.\n\nEach of the cats wears a hat.\nCat i says: \"there are exactly a_i different colors among the N - 1 hats worn by the cats except me.\"\n\nDetermine whether there exists a sequence of colors of the hats that is consistent with the remarks of the cats.\n\nConstraints\n\n2 ≤ N ≤ 10^5\n\n1 ≤ a_i ≤ N-1\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_N\n\nOutput\n\nPrint Yes if there exists a sequence of colors of the hats that is consistent with the remarks of the cats; print No otherwise.\n\nSample Input 1\n\n3\n1 2 2\n\nSample Output 1\n\nYes\n\nFor example, if cat 1, 2 and 3 wears red, blue and blue hats, respectively, it is consistent with the remarks of the cats.\n\nSample Input 2\n\n3\n1 1 2\n\nSample Output 2\n\nNo\n\nFrom the remark of cat 1, we can see that cat 2 and 3 wear hats of the same color.\nAlso, from the remark of cat 2, we can see that cat 1 and 3 wear hats of the same color.\nTherefore, cat 1 and 2 wear hats of the same color, which contradicts the remark of cat 3.\n\nSample Input 3\n\n5\n4 3 4 3 4\n\nSample Output 3\n\nNo\n\nSample Input 4\n\n3\n2 2 2\n\nSample Output 4\n\nYes\n\nSample Input 5\n\n4\n2 2 2 2\n\nSample Output 5\n\nYes\n\nSample Input 6\n\n5\n3 3 3 3 3\n\nSample Output 6\n\nNo", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1738, "cpu_time_ms": 37, "memory_kb": 640}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s940195095", "group_id": "codeNet:p03689", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef vector<ll> vec;\ntypedef vector<vec> mat;\ntypedef pair<ll,ll> pll;\nconst ll mod=1e9+7;\n//const ll mod=998244353;\nconst ll inf=1LL<<62;\n\nint main() {\n  ll h,w,y,x;\n  cin >> h >> w >> y >> x;\n  if(h%y==0&&w%x==0) {\n    cout << \"No\" << endl;\n    return 0;\n  }\n  cout << \"Yes\" << endl;\n  if(w%x) {\n    vec s(w+1);\n    for(ll i=w;i>=0;i--) {\n      if(w-i<x) {\n        s[i]=1;\n      }\n      else {\n        s[i]=s[i+x]+1;\n      }\n    }\n    s[0]=0;\n    for(ll i=x;i<w;i+=y) {\n      s[i]=s[i-x]-1;\n    }\n    vec a(w);\n    for(ll i=0;i<w;i++) {\n      a[i]=s[i+1]-s[i];\n    }\n    for(ll i=0;i<h;i++) {\n      for(ll j=0;j<w;j++) {\n        if(j) cout << \" \";\n        cout << a[j];\n      }\n      cout << endl;\n    }\n  }\n  else {\n    vec s(h+1);\n    for(ll i=h;i>=0;i--) {\n      if(w-i<y) {\n        s[i]=1;\n      }\n      else {\n        s[i]=s[i+y]+1;\n      }\n    }\n    s[0]=0;\n    for(ll i=y;i<h;i+=y) {\n      s[i]=s[i-y]-1;\n    }\n    vec a(h);\n    for(ll i=0;i<h;i++) {\n      a[i]=s[i+1]-s[i];\n    }\n    for(ll i=0;i<h;i++) {\n      for(ll j=0;j<w;j++) {\n        if(j) cout << \" \";\n        cout << a[i];\n      }\n      cout << endl;\n    }\n  }\n}", "language": "C++", "metadata": {"date": 1592015626, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03689.html", "problem_id": "p03689", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03689/input.txt", "sample_output_relpath": "derived/input_output/data/p03689/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03689/C++/s940195095.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s940195095", "user_id": "u718758485"}, "prompt_components": {"gold_output": "Yes\n1 1 1\n1 -4 1\n1 1 1\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef vector<ll> vec;\ntypedef vector<vec> mat;\ntypedef pair<ll,ll> pll;\nconst ll mod=1e9+7;\n//const ll mod=998244353;\nconst ll inf=1LL<<62;\n\nint main() {\n  ll h,w,y,x;\n  cin >> h >> w >> y >> x;\n  if(h%y==0&&w%x==0) {\n    cout << \"No\" << endl;\n    return 0;\n  }\n  cout << \"Yes\" << endl;\n  if(w%x) {\n    vec s(w+1);\n    for(ll i=w;i>=0;i--) {\n      if(w-i<x) {\n        s[i]=1;\n      }\n      else {\n        s[i]=s[i+x]+1;\n      }\n    }\n    s[0]=0;\n    for(ll i=x;i<w;i+=y) {\n      s[i]=s[i-x]-1;\n    }\n    vec a(w);\n    for(ll i=0;i<w;i++) {\n      a[i]=s[i+1]-s[i];\n    }\n    for(ll i=0;i<h;i++) {\n      for(ll j=0;j<w;j++) {\n        if(j) cout << \" \";\n        cout << a[j];\n      }\n      cout << endl;\n    }\n  }\n  else {\n    vec s(h+1);\n    for(ll i=h;i>=0;i--) {\n      if(w-i<y) {\n        s[i]=1;\n      }\n      else {\n        s[i]=s[i+y]+1;\n      }\n    }\n    s[0]=0;\n    for(ll i=y;i<h;i+=y) {\n      s[i]=s[i-y]-1;\n    }\n    vec a(h);\n    for(ll i=0;i<h;i++) {\n      a[i]=s[i+1]-s[i];\n    }\n    for(ll i=0;i<h;i++) {\n      for(ll j=0;j<w;j++) {\n        if(j) cout << \" \";\n        cout << a[i];\n      }\n      cout << endl;\n    }\n  }\n}", "problem_context": "Score : 700 points\n\nProblem Statement\n\nYou are given four integers: H, W, h and w (1 ≤ h ≤ H, 1 ≤ w ≤ W).\nDetermine whether there exists a matrix such that all of the following conditions are held, and construct one such matrix if the answer is positive:\n\nThe matrix has H rows and W columns.\n\nEach element of the matrix is an integer between -10^9 and 10^9 (inclusive).\n\nThe sum of all the elements of the matrix is positive.\n\nThe sum of all the elements within every subrectangle with h rows and w columns in the matrix is negative.\n\nConstraints\n\n1 ≤ h ≤ H ≤ 500\n\n1 ≤ w ≤ W ≤ 500\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W h w\n\nOutput\n\nIf there does not exist a matrix that satisfies all of the conditions, print No.\n\nOtherwise, print Yes in the first line, and print a matrix in the subsequent lines in the following format:\n\na_{11} ... a_{1W}\n:\na_{H1} ... a_{HW}\n\nHere, a_{ij} represents the (i,\\ j) element of the matrix.\n\nSample Input 1\n\n3 3 2 2\n\nSample Output 1\n\nYes\n1 1 1\n1 -4 1\n1 1 1\n\nThe sum of all the elements of this matrix is 4, which is positive.\nAlso, in this matrix, there are four subrectangles with 2 rows and 2 columns as shown below. For each of them, the sum of all the elements inside is -1, which is negative.\n\nSample Input 2\n\n2 4 1 2\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n3 4 2 3\n\nSample Output 3\n\nYes\n2 -5 8 7\n3 -5 -4 -5\n2 1 -1 7", "sample_input": "3 3 2 2\n"}, "reference_outputs": ["Yes\n1 1 1\n1 -4 1\n1 1 1\n"], "source_document_id": "p03689", "source_text": "Score : 700 points\n\nProblem Statement\n\nYou are given four integers: H, W, h and w (1 ≤ h ≤ H, 1 ≤ w ≤ W).\nDetermine whether there exists a matrix such that all of the following conditions are held, and construct one such matrix if the answer is positive:\n\nThe matrix has H rows and W columns.\n\nEach element of the matrix is an integer between -10^9 and 10^9 (inclusive).\n\nThe sum of all the elements of the matrix is positive.\n\nThe sum of all the elements within every subrectangle with h rows and w columns in the matrix is negative.\n\nConstraints\n\n1 ≤ h ≤ H ≤ 500\n\n1 ≤ w ≤ W ≤ 500\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W h w\n\nOutput\n\nIf there does not exist a matrix that satisfies all of the conditions, print No.\n\nOtherwise, print Yes in the first line, and print a matrix in the subsequent lines in the following format:\n\na_{11} ... a_{1W}\n:\na_{H1} ... a_{HW}\n\nHere, a_{ij} represents the (i,\\ j) element of the matrix.\n\nSample Input 1\n\n3 3 2 2\n\nSample Output 1\n\nYes\n1 1 1\n1 -4 1\n1 1 1\n\nThe sum of all the elements of this matrix is 4, which is positive.\nAlso, in this matrix, there are four subrectangles with 2 rows and 2 columns as shown below. For each of them, the sum of all the elements inside is -1, which is negative.\n\nSample Input 2\n\n2 4 1 2\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n3 4 2 3\n\nSample Output 3\n\nYes\n2 -5 8 7\n3 -5 -4 -5\n2 1 -1 7", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1202, "cpu_time_ms": 30, "memory_kb": 1408}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s473178255", "group_id": "codeNet:p03689", "input_text": "#include <iostream>\nusing namespace std;\n\nint main(){\n  int n,m,x,y;\n  cin >> n >> m >> x >> y;\n  int a=(n/x)*(m/y);\n  int b=n*m-a;\n  if(n%x==0&&m%y==0){\n    cout << \"No\" << endl;\n  }\n  else{\n    cout << \"Yes\" << endl;\n    int c=1e9/b;\n    b*=c;\n    for(int i=1;i<=n;i++){\n      for(int j=1;j<=m;j++){\n        if(i%x==0&&j%y==0){\n          cout << -b;\n        }\n        else{\n          cout << (b-1)/(x*y-1);\n        }\n        cout << \" \";\n      }\n      cout << endl;\n    }\n  }\n}", "language": "C++", "metadata": {"date": 1552987735, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03689.html", "problem_id": "p03689", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03689/input.txt", "sample_output_relpath": "derived/input_output/data/p03689/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03689/C++/s473178255.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s473178255", "user_id": "u179970156"}, "prompt_components": {"gold_output": "Yes\n1 1 1\n1 -4 1\n1 1 1\n", "input_to_evaluate": "#include <iostream>\nusing namespace std;\n\nint main(){\n  int n,m,x,y;\n  cin >> n >> m >> x >> y;\n  int a=(n/x)*(m/y);\n  int b=n*m-a;\n  if(n%x==0&&m%y==0){\n    cout << \"No\" << endl;\n  }\n  else{\n    cout << \"Yes\" << endl;\n    int c=1e9/b;\n    b*=c;\n    for(int i=1;i<=n;i++){\n      for(int j=1;j<=m;j++){\n        if(i%x==0&&j%y==0){\n          cout << -b;\n        }\n        else{\n          cout << (b-1)/(x*y-1);\n        }\n        cout << \" \";\n      }\n      cout << endl;\n    }\n  }\n}", "problem_context": "Score : 700 points\n\nProblem Statement\n\nYou are given four integers: H, W, h and w (1 ≤ h ≤ H, 1 ≤ w ≤ W).\nDetermine whether there exists a matrix such that all of the following conditions are held, and construct one such matrix if the answer is positive:\n\nThe matrix has H rows and W columns.\n\nEach element of the matrix is an integer between -10^9 and 10^9 (inclusive).\n\nThe sum of all the elements of the matrix is positive.\n\nThe sum of all the elements within every subrectangle with h rows and w columns in the matrix is negative.\n\nConstraints\n\n1 ≤ h ≤ H ≤ 500\n\n1 ≤ w ≤ W ≤ 500\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W h w\n\nOutput\n\nIf there does not exist a matrix that satisfies all of the conditions, print No.\n\nOtherwise, print Yes in the first line, and print a matrix in the subsequent lines in the following format:\n\na_{11} ... a_{1W}\n:\na_{H1} ... a_{HW}\n\nHere, a_{ij} represents the (i,\\ j) element of the matrix.\n\nSample Input 1\n\n3 3 2 2\n\nSample Output 1\n\nYes\n1 1 1\n1 -4 1\n1 1 1\n\nThe sum of all the elements of this matrix is 4, which is positive.\nAlso, in this matrix, there are four subrectangles with 2 rows and 2 columns as shown below. For each of them, the sum of all the elements inside is -1, which is negative.\n\nSample Input 2\n\n2 4 1 2\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n3 4 2 3\n\nSample Output 3\n\nYes\n2 -5 8 7\n3 -5 -4 -5\n2 1 -1 7", "sample_input": "3 3 2 2\n"}, "reference_outputs": ["Yes\n1 1 1\n1 -4 1\n1 1 1\n"], "source_document_id": "p03689", "source_text": "Score : 700 points\n\nProblem Statement\n\nYou are given four integers: H, W, h and w (1 ≤ h ≤ H, 1 ≤ w ≤ W).\nDetermine whether there exists a matrix such that all of the following conditions are held, and construct one such matrix if the answer is positive:\n\nThe matrix has H rows and W columns.\n\nEach element of the matrix is an integer between -10^9 and 10^9 (inclusive).\n\nThe sum of all the elements of the matrix is positive.\n\nThe sum of all the elements within every subrectangle with h rows and w columns in the matrix is negative.\n\nConstraints\n\n1 ≤ h ≤ H ≤ 500\n\n1 ≤ w ≤ W ≤ 500\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W h w\n\nOutput\n\nIf there does not exist a matrix that satisfies all of the conditions, print No.\n\nOtherwise, print Yes in the first line, and print a matrix in the subsequent lines in the following format:\n\na_{11} ... a_{1W}\n:\na_{H1} ... a_{HW}\n\nHere, a_{ij} represents the (i,\\ j) element of the matrix.\n\nSample Input 1\n\n3 3 2 2\n\nSample Output 1\n\nYes\n1 1 1\n1 -4 1\n1 1 1\n\nThe sum of all the elements of this matrix is 4, which is positive.\nAlso, in this matrix, there are four subrectangles with 2 rows and 2 columns as shown below. For each of them, the sum of all the elements inside is -1, which is negative.\n\nSample Input 2\n\n2 4 1 2\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n3 4 2 3\n\nSample Output 3\n\nYes\n2 -5 8 7\n3 -5 -4 -5\n2 1 -1 7", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 479, "cpu_time_ms": 29, "memory_kb": 2944}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s082204625", "group_id": "codeNet:p03689", "input_text": "#include<cstdio>\nusing namespace std;\nconst int maxn = 1000000000;\nint main()\n{\n\tint a,b,c,d;\n\tscanf(\"%d%d%d%d\",&a,&b,&c,&d);\n\tif(a % c == 0 && b % d == 0)\n\t{\n\t\tprintf(\"No\\n\");\n\t}\n\telse\n\t{\n\t\tint nz = maxn / (c * d - 1);\n\t\tint nf = (c * d - 1) * nz + 1;\n\t\tprintf(\"Yes\\n\");\n\t\tfor(int i = 1;i <= a;++i)\n\t\t{\n\t\t\tfor(int j = 1;j <= b;++j)\n\t\t\t{\n\t\t\t\tif(i % c == 0 && j % d == 0)\n\t\t\t\t\tprintf(\"-%d \",nf);\n\t\t\t\telse\n\t\t\t\t\tprintf(\"%d \",nz);\n\t\t\t}\n\t\t\tputchar('\\n');\n\t\t}\n\t}\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1550276374, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03689.html", "problem_id": "p03689", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03689/input.txt", "sample_output_relpath": "derived/input_output/data/p03689/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03689/C++/s082204625.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s082204625", "user_id": "u089230684"}, "prompt_components": {"gold_output": "Yes\n1 1 1\n1 -4 1\n1 1 1\n", "input_to_evaluate": "#include<cstdio>\nusing namespace std;\nconst int maxn = 1000000000;\nint main()\n{\n\tint a,b,c,d;\n\tscanf(\"%d%d%d%d\",&a,&b,&c,&d);\n\tif(a % c == 0 && b % d == 0)\n\t{\n\t\tprintf(\"No\\n\");\n\t}\n\telse\n\t{\n\t\tint nz = maxn / (c * d - 1);\n\t\tint nf = (c * d - 1) * nz + 1;\n\t\tprintf(\"Yes\\n\");\n\t\tfor(int i = 1;i <= a;++i)\n\t\t{\n\t\t\tfor(int j = 1;j <= b;++j)\n\t\t\t{\n\t\t\t\tif(i % c == 0 && j % d == 0)\n\t\t\t\t\tprintf(\"-%d \",nf);\n\t\t\t\telse\n\t\t\t\t\tprintf(\"%d \",nz);\n\t\t\t}\n\t\t\tputchar('\\n');\n\t\t}\n\t}\n\treturn 0;\n}", "problem_context": "Score : 700 points\n\nProblem Statement\n\nYou are given four integers: H, W, h and w (1 ≤ h ≤ H, 1 ≤ w ≤ W).\nDetermine whether there exists a matrix such that all of the following conditions are held, and construct one such matrix if the answer is positive:\n\nThe matrix has H rows and W columns.\n\nEach element of the matrix is an integer between -10^9 and 10^9 (inclusive).\n\nThe sum of all the elements of the matrix is positive.\n\nThe sum of all the elements within every subrectangle with h rows and w columns in the matrix is negative.\n\nConstraints\n\n1 ≤ h ≤ H ≤ 500\n\n1 ≤ w ≤ W ≤ 500\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W h w\n\nOutput\n\nIf there does not exist a matrix that satisfies all of the conditions, print No.\n\nOtherwise, print Yes in the first line, and print a matrix in the subsequent lines in the following format:\n\na_{11} ... a_{1W}\n:\na_{H1} ... a_{HW}\n\nHere, a_{ij} represents the (i,\\ j) element of the matrix.\n\nSample Input 1\n\n3 3 2 2\n\nSample Output 1\n\nYes\n1 1 1\n1 -4 1\n1 1 1\n\nThe sum of all the elements of this matrix is 4, which is positive.\nAlso, in this matrix, there are four subrectangles with 2 rows and 2 columns as shown below. For each of them, the sum of all the elements inside is -1, which is negative.\n\nSample Input 2\n\n2 4 1 2\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n3 4 2 3\n\nSample Output 3\n\nYes\n2 -5 8 7\n3 -5 -4 -5\n2 1 -1 7", "sample_input": "3 3 2 2\n"}, "reference_outputs": ["Yes\n1 1 1\n1 -4 1\n1 1 1\n"], "source_document_id": "p03689", "source_text": "Score : 700 points\n\nProblem Statement\n\nYou are given four integers: H, W, h and w (1 ≤ h ≤ H, 1 ≤ w ≤ W).\nDetermine whether there exists a matrix such that all of the following conditions are held, and construct one such matrix if the answer is positive:\n\nThe matrix has H rows and W columns.\n\nEach element of the matrix is an integer between -10^9 and 10^9 (inclusive).\n\nThe sum of all the elements of the matrix is positive.\n\nThe sum of all the elements within every subrectangle with h rows and w columns in the matrix is negative.\n\nConstraints\n\n1 ≤ h ≤ H ≤ 500\n\n1 ≤ w ≤ W ≤ 500\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W h w\n\nOutput\n\nIf there does not exist a matrix that satisfies all of the conditions, print No.\n\nOtherwise, print Yes in the first line, and print a matrix in the subsequent lines in the following format:\n\na_{11} ... a_{1W}\n:\na_{H1} ... a_{HW}\n\nHere, a_{ij} represents the (i,\\ j) element of the matrix.\n\nSample Input 1\n\n3 3 2 2\n\nSample Output 1\n\nYes\n1 1 1\n1 -4 1\n1 1 1\n\nThe sum of all the elements of this matrix is 4, which is positive.\nAlso, in this matrix, there are four subrectangles with 2 rows and 2 columns as shown below. For each of them, the sum of all the elements inside is -1, which is negative.\n\nSample Input 2\n\n2 4 1 2\n\nSample Output 2\n\nNo\n\nSample Input 3\n\n3 4 2 3\n\nSample Output 3\n\nYes\n2 -5 8 7\n3 -5 -4 -5\n2 1 -1 7", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 469, "cpu_time_ms": 25, "memory_kb": 2944}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s701236875", "group_id": "codeNet:p03693", "input_text": "#include <bits/stdc++.h>\n#define rep(i, n) for (long long int i = 0; i < (n); ++i)\nusing namespace std;\ntypedef long long int ll;\ntemplate <class T>\n\ninline bool chmin(T &a, T b)\n{\n    if (a > b)\n    {\n        a = b;\n        return true;\n    }\n    return false;\n}\ntemplate <class T>\ninline bool chmax(T &a, T b)\n{\n    if (a < b)\n    {\n        a = b;\n        return true;\n    }\n    return false;\n}\nconst long long INF = 1LL << 60;\nint cnt = 0;\nint main()\n{\n    int r, g, b;\n    cin >> r >> g >> b;\n    int x = 100 * r + 10 * g + b;\n    if (x % 4 == 0)\n    {\n        cout << \"YES\" << endl;\n    }\n    else\n    {\n        cout << \"No\" << endl;\n    }\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1593568942, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03693.html", "problem_id": "p03693", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03693/input.txt", "sample_output_relpath": "derived/input_output/data/p03693/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03693/C++/s701236875.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s701236875", "user_id": "u693969714"}, "prompt_components": {"gold_output": "YES\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define rep(i, n) for (long long int i = 0; i < (n); ++i)\nusing namespace std;\ntypedef long long int ll;\ntemplate <class T>\n\ninline bool chmin(T &a, T b)\n{\n    if (a > b)\n    {\n        a = b;\n        return true;\n    }\n    return false;\n}\ntemplate <class T>\ninline bool chmax(T &a, T b)\n{\n    if (a < b)\n    {\n        a = b;\n        return true;\n    }\n    return false;\n}\nconst long long INF = 1LL << 60;\nint cnt = 0;\nint main()\n{\n    int r, g, b;\n    cin >> r >> g >> b;\n    int x = 100 * r + 10 * g + b;\n    if (x % 4 == 0)\n    {\n        cout << \"YES\" << endl;\n    }\n    else\n    {\n        cout << \"No\" << endl;\n    }\n    return 0;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nAtCoDeer has three cards, one red, one green and one blue.\n\nAn integer between 1 and 9 (inclusive) is written on each card: r on the red card, g on the green card and b on the blue card.\n\nWe will arrange the cards in the order red, green and blue from left to right, and read them as a three-digit integer.\n\nIs this integer a multiple of 4?\n\nConstraints\n\n1 ≤ r, g, b ≤ 9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nr g b\n\nOutput\n\nIf the three-digit integer is a multiple of 4, print YES (case-sensitive); otherwise, print NO.\n\nSample Input 1\n\n4 3 2\n\nSample Output 1\n\nYES\n\n432 is a multiple of 4, and thus YES should be printed.\n\nSample Input 2\n\n2 3 4\n\nSample Output 2\n\nNO\n\n234 is not a multiple of 4, and thus NO should be printed.", "sample_input": "4 3 2\n"}, "reference_outputs": ["YES\n"], "source_document_id": "p03693", "source_text": "Score : 100 points\n\nProblem Statement\n\nAtCoDeer has three cards, one red, one green and one blue.\n\nAn integer between 1 and 9 (inclusive) is written on each card: r on the red card, g on the green card and b on the blue card.\n\nWe will arrange the cards in the order red, green and blue from left to right, and read them as a three-digit integer.\n\nIs this integer a multiple of 4?\n\nConstraints\n\n1 ≤ r, g, b ≤ 9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nr g b\n\nOutput\n\nIf the three-digit integer is a multiple of 4, print YES (case-sensitive); otherwise, print NO.\n\nSample Input 1\n\n4 3 2\n\nSample Output 1\n\nYES\n\n432 is a multiple of 4, and thus YES should be printed.\n\nSample Input 2\n\n2 3 4\n\nSample Output 2\n\nNO\n\n234 is not a multiple of 4, and thus NO should be printed.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 661, "cpu_time_ms": 8, "memory_kb": 3600}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s091974882", "group_id": "codeNet:p03693", "input_text": "#include<iostream>\nusing namespace std;\nint main()\n{\n    int a,b,c;\n    cin>>a>>b>>c;\n      if(((a*100)+(b*10)+c)%2==0)\n      cout<<\"Yes\";\n      else  \n      cout<<\"No\";\n           }\n", "language": "C++", "metadata": {"date": 1507326510, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03693.html", "problem_id": "p03693", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03693/input.txt", "sample_output_relpath": "derived/input_output/data/p03693/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03693/C++/s091974882.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s091974882", "user_id": "u863370423"}, "prompt_components": {"gold_output": "YES\n", "input_to_evaluate": "#include<iostream>\nusing namespace std;\nint main()\n{\n    int a,b,c;\n    cin>>a>>b>>c;\n      if(((a*100)+(b*10)+c)%2==0)\n      cout<<\"Yes\";\n      else  \n      cout<<\"No\";\n           }\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nAtCoDeer has three cards, one red, one green and one blue.\n\nAn integer between 1 and 9 (inclusive) is written on each card: r on the red card, g on the green card and b on the blue card.\n\nWe will arrange the cards in the order red, green and blue from left to right, and read them as a three-digit integer.\n\nIs this integer a multiple of 4?\n\nConstraints\n\n1 ≤ r, g, b ≤ 9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nr g b\n\nOutput\n\nIf the three-digit integer is a multiple of 4, print YES (case-sensitive); otherwise, print NO.\n\nSample Input 1\n\n4 3 2\n\nSample Output 1\n\nYES\n\n432 is a multiple of 4, and thus YES should be printed.\n\nSample Input 2\n\n2 3 4\n\nSample Output 2\n\nNO\n\n234 is not a multiple of 4, and thus NO should be printed.", "sample_input": "4 3 2\n"}, "reference_outputs": ["YES\n"], "source_document_id": "p03693", "source_text": "Score : 100 points\n\nProblem Statement\n\nAtCoDeer has three cards, one red, one green and one blue.\n\nAn integer between 1 and 9 (inclusive) is written on each card: r on the red card, g on the green card and b on the blue card.\n\nWe will arrange the cards in the order red, green and blue from left to right, and read them as a three-digit integer.\n\nIs this integer a multiple of 4?\n\nConstraints\n\n1 ≤ r, g, b ≤ 9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nr g b\n\nOutput\n\nIf the three-digit integer is a multiple of 4, print YES (case-sensitive); otherwise, print NO.\n\nSample Input 1\n\n4 3 2\n\nSample Output 1\n\nYES\n\n432 is a multiple of 4, and thus YES should be printed.\n\nSample Input 2\n\n2 3 4\n\nSample Output 2\n\nNO\n\n234 is not a multiple of 4, and thus NO should be printed.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 183, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s081008544", "group_id": "codeNet:p03695", "input_text": "#include<iostream>\nusing namespace std;\nint i,n,m,a,c[20];\nint main()\n{\n\tfor(cin>>n;i++<n;cin>>a,c[a/400]++);\n\tfor(i=0;i<8;i++)m+=c[i]>0;\n\tcout<<(m?m:1)<<\" \"<<m+c[8]+c[9]+c[10]+c[11]+c[12];\n}\n", "language": "C++", "metadata": {"date": 1570779531, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03695.html", "problem_id": "p03695", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03695/input.txt", "sample_output_relpath": "derived/input_output/data/p03695/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03695/C++/s081008544.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s081008544", "user_id": "u885523920"}, "prompt_components": {"gold_output": "2 2\n", "input_to_evaluate": "#include<iostream>\nusing namespace std;\nint i,n,m,a,c[20];\nint main()\n{\n\tfor(cin>>n;i++<n;cin>>a,c[a/400]++);\n\tfor(i=0;i<8;i++)m+=c[i]>0;\n\tcout<<(m?m:1)<<\" \"<<m+c[8]+c[9]+c[10]+c[11]+c[12];\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nIn AtCoder, a person who has participated in a contest receives a color, which corresponds to the person's rating as follows:\n\nRating 1-399 : gray\n\nRating 400-799 : brown\n\nRating 800-1199 : green\n\nRating 1200-1599 : cyan\n\nRating 1600-1999 : blue\n\nRating 2000-2399 : yellow\n\nRating 2400-2799 : orange\n\nRating 2800-3199 : red\n\nOther than the above, a person whose rating is 3200 or higher can freely pick his/her color, which can be one of the eight colors above or not.\n\nCurrently, there are N users who have participated in a contest in AtCoder, and the i-th user has a rating of a_i.\n\nFind the minimum and maximum possible numbers of different colors of the users.\n\nConstraints\n\n1 ≤ N ≤ 100\n\n1 ≤ a_i ≤ 4800\n\na_i is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_N\n\nOutput\n\nPrint the minimum possible number of different colors of the users, and the maximum possible number of different colors, with a space in between.\n\nSample Input 1\n\n4\n2100 2500 2700 2700\n\nSample Output 1\n\n2 2\n\nThe user with rating 2100 is \"yellow\", and the others are \"orange\". There are two different colors.\n\nSample Input 2\n\n5\n1100 1900 2800 3200 3200\n\nSample Output 2\n\n3 5\n\nThe user with rating 1100 is \"green\", the user with rating 1900 is blue and the user with rating 2800 is \"red\".\n\nIf the fourth user picks \"red\", and the fifth user picks \"blue\", there are three different colors. This is one possible scenario for the minimum number of colors.\n\nIf the fourth user picks \"purple\", and the fifth user picks \"black\", there are five different colors. This is one possible scenario for the maximum number of colors.\n\nSample Input 3\n\n20\n800 810 820 830 840 850 860 870 880 890 900 910 920 930 940 950 960 970 980 990\n\nSample Output 3\n\n1 1\n\nAll the users are \"green\", and thus there is one color.", "sample_input": "4\n2100 2500 2700 2700\n"}, "reference_outputs": ["2 2\n"], "source_document_id": "p03695", "source_text": "Score : 300 points\n\nProblem Statement\n\nIn AtCoder, a person who has participated in a contest receives a color, which corresponds to the person's rating as follows:\n\nRating 1-399 : gray\n\nRating 400-799 : brown\n\nRating 800-1199 : green\n\nRating 1200-1599 : cyan\n\nRating 1600-1999 : blue\n\nRating 2000-2399 : yellow\n\nRating 2400-2799 : orange\n\nRating 2800-3199 : red\n\nOther than the above, a person whose rating is 3200 or higher can freely pick his/her color, which can be one of the eight colors above or not.\n\nCurrently, there are N users who have participated in a contest in AtCoder, and the i-th user has a rating of a_i.\n\nFind the minimum and maximum possible numbers of different colors of the users.\n\nConstraints\n\n1 ≤ N ≤ 100\n\n1 ≤ a_i ≤ 4800\n\na_i is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_N\n\nOutput\n\nPrint the minimum possible number of different colors of the users, and the maximum possible number of different colors, with a space in between.\n\nSample Input 1\n\n4\n2100 2500 2700 2700\n\nSample Output 1\n\n2 2\n\nThe user with rating 2100 is \"yellow\", and the others are \"orange\". There are two different colors.\n\nSample Input 2\n\n5\n1100 1900 2800 3200 3200\n\nSample Output 2\n\n3 5\n\nThe user with rating 1100 is \"green\", the user with rating 1900 is blue and the user with rating 2800 is \"red\".\n\nIf the fourth user picks \"red\", and the fifth user picks \"blue\", there are three different colors. This is one possible scenario for the minimum number of colors.\n\nIf the fourth user picks \"purple\", and the fifth user picks \"black\", there are five different colors. This is one possible scenario for the maximum number of colors.\n\nSample Input 3\n\n20\n800 810 820 830 840 850 860 870 880 890 900 910 920 930 940 950 960 970 980 990\n\nSample Output 3\n\n1 1\n\nAll the users are \"green\", and thus there is one color.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 192, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s240018815", "group_id": "codeNet:p03695", "input_text": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<string>\n#include<cmath>\n#include<map>\n#include<cstdio>\n#include<stack>\n#include<queue>\n#include<fstream>\n#include<cstdio>\n\nusing namespace std;\n#define ok1 printf(\"ok1\\n\");\n#define ok2 printf(\"ok2\\n\");\n#define M 1000000\n#define rep(i,n) for(int i=0;i<n;i++)\n#define REP(i,s,n) for(int i=(s);i<(n);i++)\n#define repr(i,n) for(int i=n-1;i>=0;i--)\n#define REPR(i,s,n) for(int i=(s);i>=(g);(i)--)\n#define all(a) (a).begin(),(a).end()\n#define reall(a) (a).rbegin(),(a).rend()\n#define pb push_back\n#define MIN(a,b) a=min((a),(b))\n#define MAX(a,b) a=max((a),(b))\n#define SIZE(v) (int)v.size()\n\n\ntypedef vector<int> vi;\ntypedef vector<string> vs;\ntypedef long long ll;\ntypedef vector<ll> vll;\n\n#ifdef TESTING\n#define DEBUG fprintf(stderr,\"====TESTING====\\n\")\n#define VALUE(x) cerr << \"The value of \" << #x << \" is \" << x << endl\n#define debug(...) fprintf(stderr, __VA_ARGS__)\n#else\n#define DEBUG \n#define VALUE(x)\n#define debug(...)\n#endif\n/*\ninline string IntToString(ll a) {\n\tchar x[100];\n\tsprintf_s(x, \"%lld\", a); string s = x;\n\treturn s;\n}\n\ninline ll StringToInt(string a) {\n\tchar x[100]; ll res;\n\tstrcpy_s(x, a.c_str()); sscanf_s(x, \"%lld\", &res);\n\treturn res;\n}\n*/\n\ninline string uppercase(string s) {\n\tint n = SIZE(s);\n\trep(i, n) if (s[i] >= 'a' && s[i] <= 'z') s[i] = s[i] - 'a' + 'A';\n\treturn s;\n}\n\ninline string lowercase(string s) {\n\tint n = SIZE(s);\n\trep(i, n) if (s[i] >= 'A' && s[i] <= 'Z') s[i] = s[i] - 'A' + 'a';\n\treturn s;\n}\n\n\nint main()\n{\n\tint n,ans = 0;\n\tcin >> n;\n\tvi v(n),a(8);\n\tint ex = 0;\n\tfor (int i = 0; i < n; i++) {\n\t\tcin >> v[i];\n\t\tif (v[i] >= 1 && v[i] < 400)\n\t\t\ta[0]++;\n\t\tif (v[i] >= 400 && v[i] < 800)\n\t\t\ta[1]++;\n\t\tif (v[i] >= 800 && v[i] < 1200)\n\t\t\ta[2]++;\n\t\tif (v[i] >= 1200 && v[i] < 1600)\n\t\t\ta[3]++;\n\t\tif (v[i] >= 1600 && v[i] < 2000)\n\t\t\ta[4]++;\n\t\tif (v[i] >= 2000 && v[i] < 2400)\n\t\t\ta[5]++;\n\t\tif (v[i] >= 2400 && v[i] < 2700)\n\t\t\ta[6]++;\n\t\tif (v[i] >= 2800 && v[i] < 3200)\n\t\t\ta[7]++;\n\t\tif (v[i] >= 3200)\n\t\t\tex++;\n\t}\n\trep(i, 8) {\n\t\tif (a[i] != 0)\n\t\t\tans++;\n\t\t//cout << a[i] << \" \";\n\t}\n\t//cout << endl;\n\t//cout << ex << endl;//(to debug)\n\tcout << ans << \" \" << ans + ex << endl;\n \treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1520483191, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03695.html", "problem_id": "p03695", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03695/input.txt", "sample_output_relpath": "derived/input_output/data/p03695/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03695/C++/s240018815.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s240018815", "user_id": "u373958718"}, "prompt_components": {"gold_output": "2 2\n", "input_to_evaluate": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<string>\n#include<cmath>\n#include<map>\n#include<cstdio>\n#include<stack>\n#include<queue>\n#include<fstream>\n#include<cstdio>\n\nusing namespace std;\n#define ok1 printf(\"ok1\\n\");\n#define ok2 printf(\"ok2\\n\");\n#define M 1000000\n#define rep(i,n) for(int i=0;i<n;i++)\n#define REP(i,s,n) for(int i=(s);i<(n);i++)\n#define repr(i,n) for(int i=n-1;i>=0;i--)\n#define REPR(i,s,n) for(int i=(s);i>=(g);(i)--)\n#define all(a) (a).begin(),(a).end()\n#define reall(a) (a).rbegin(),(a).rend()\n#define pb push_back\n#define MIN(a,b) a=min((a),(b))\n#define MAX(a,b) a=max((a),(b))\n#define SIZE(v) (int)v.size()\n\n\ntypedef vector<int> vi;\ntypedef vector<string> vs;\ntypedef long long ll;\ntypedef vector<ll> vll;\n\n#ifdef TESTING\n#define DEBUG fprintf(stderr,\"====TESTING====\\n\")\n#define VALUE(x) cerr << \"The value of \" << #x << \" is \" << x << endl\n#define debug(...) fprintf(stderr, __VA_ARGS__)\n#else\n#define DEBUG \n#define VALUE(x)\n#define debug(...)\n#endif\n/*\ninline string IntToString(ll a) {\n\tchar x[100];\n\tsprintf_s(x, \"%lld\", a); string s = x;\n\treturn s;\n}\n\ninline ll StringToInt(string a) {\n\tchar x[100]; ll res;\n\tstrcpy_s(x, a.c_str()); sscanf_s(x, \"%lld\", &res);\n\treturn res;\n}\n*/\n\ninline string uppercase(string s) {\n\tint n = SIZE(s);\n\trep(i, n) if (s[i] >= 'a' && s[i] <= 'z') s[i] = s[i] - 'a' + 'A';\n\treturn s;\n}\n\ninline string lowercase(string s) {\n\tint n = SIZE(s);\n\trep(i, n) if (s[i] >= 'A' && s[i] <= 'Z') s[i] = s[i] - 'A' + 'a';\n\treturn s;\n}\n\n\nint main()\n{\n\tint n,ans = 0;\n\tcin >> n;\n\tvi v(n),a(8);\n\tint ex = 0;\n\tfor (int i = 0; i < n; i++) {\n\t\tcin >> v[i];\n\t\tif (v[i] >= 1 && v[i] < 400)\n\t\t\ta[0]++;\n\t\tif (v[i] >= 400 && v[i] < 800)\n\t\t\ta[1]++;\n\t\tif (v[i] >= 800 && v[i] < 1200)\n\t\t\ta[2]++;\n\t\tif (v[i] >= 1200 && v[i] < 1600)\n\t\t\ta[3]++;\n\t\tif (v[i] >= 1600 && v[i] < 2000)\n\t\t\ta[4]++;\n\t\tif (v[i] >= 2000 && v[i] < 2400)\n\t\t\ta[5]++;\n\t\tif (v[i] >= 2400 && v[i] < 2700)\n\t\t\ta[6]++;\n\t\tif (v[i] >= 2800 && v[i] < 3200)\n\t\t\ta[7]++;\n\t\tif (v[i] >= 3200)\n\t\t\tex++;\n\t}\n\trep(i, 8) {\n\t\tif (a[i] != 0)\n\t\t\tans++;\n\t\t//cout << a[i] << \" \";\n\t}\n\t//cout << endl;\n\t//cout << ex << endl;//(to debug)\n\tcout << ans << \" \" << ans + ex << endl;\n \treturn 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nIn AtCoder, a person who has participated in a contest receives a color, which corresponds to the person's rating as follows:\n\nRating 1-399 : gray\n\nRating 400-799 : brown\n\nRating 800-1199 : green\n\nRating 1200-1599 : cyan\n\nRating 1600-1999 : blue\n\nRating 2000-2399 : yellow\n\nRating 2400-2799 : orange\n\nRating 2800-3199 : red\n\nOther than the above, a person whose rating is 3200 or higher can freely pick his/her color, which can be one of the eight colors above or not.\n\nCurrently, there are N users who have participated in a contest in AtCoder, and the i-th user has a rating of a_i.\n\nFind the minimum and maximum possible numbers of different colors of the users.\n\nConstraints\n\n1 ≤ N ≤ 100\n\n1 ≤ a_i ≤ 4800\n\na_i is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_N\n\nOutput\n\nPrint the minimum possible number of different colors of the users, and the maximum possible number of different colors, with a space in between.\n\nSample Input 1\n\n4\n2100 2500 2700 2700\n\nSample Output 1\n\n2 2\n\nThe user with rating 2100 is \"yellow\", and the others are \"orange\". There are two different colors.\n\nSample Input 2\n\n5\n1100 1900 2800 3200 3200\n\nSample Output 2\n\n3 5\n\nThe user with rating 1100 is \"green\", the user with rating 1900 is blue and the user with rating 2800 is \"red\".\n\nIf the fourth user picks \"red\", and the fifth user picks \"blue\", there are three different colors. This is one possible scenario for the minimum number of colors.\n\nIf the fourth user picks \"purple\", and the fifth user picks \"black\", there are five different colors. This is one possible scenario for the maximum number of colors.\n\nSample Input 3\n\n20\n800 810 820 830 840 850 860 870 880 890 900 910 920 930 940 950 960 970 980 990\n\nSample Output 3\n\n1 1\n\nAll the users are \"green\", and thus there is one color.", "sample_input": "4\n2100 2500 2700 2700\n"}, "reference_outputs": ["2 2\n"], "source_document_id": "p03695", "source_text": "Score : 300 points\n\nProblem Statement\n\nIn AtCoder, a person who has participated in a contest receives a color, which corresponds to the person's rating as follows:\n\nRating 1-399 : gray\n\nRating 400-799 : brown\n\nRating 800-1199 : green\n\nRating 1200-1599 : cyan\n\nRating 1600-1999 : blue\n\nRating 2000-2399 : yellow\n\nRating 2400-2799 : orange\n\nRating 2800-3199 : red\n\nOther than the above, a person whose rating is 3200 or higher can freely pick his/her color, which can be one of the eight colors above or not.\n\nCurrently, there are N users who have participated in a contest in AtCoder, and the i-th user has a rating of a_i.\n\nFind the minimum and maximum possible numbers of different colors of the users.\n\nConstraints\n\n1 ≤ N ≤ 100\n\n1 ≤ a_i ≤ 4800\n\na_i is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_N\n\nOutput\n\nPrint the minimum possible number of different colors of the users, and the maximum possible number of different colors, with a space in between.\n\nSample Input 1\n\n4\n2100 2500 2700 2700\n\nSample Output 1\n\n2 2\n\nThe user with rating 2100 is \"yellow\", and the others are \"orange\". There are two different colors.\n\nSample Input 2\n\n5\n1100 1900 2800 3200 3200\n\nSample Output 2\n\n3 5\n\nThe user with rating 1100 is \"green\", the user with rating 1900 is blue and the user with rating 2800 is \"red\".\n\nIf the fourth user picks \"red\", and the fifth user picks \"blue\", there are three different colors. This is one possible scenario for the minimum number of colors.\n\nIf the fourth user picks \"purple\", and the fifth user picks \"black\", there are five different colors. This is one possible scenario for the maximum number of colors.\n\nSample Input 3\n\n20\n800 810 820 830 840 850 860 870 880 890 900 910 920 930 940 950 960 970 980 990\n\nSample Output 3\n\n1 1\n\nAll the users are \"green\", and thus there is one color.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2184, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s975774519", "group_id": "codeNet:p03695", "input_text": "#include <iostream>\n#include <vector>\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef vector<ll> vi;\ntypedef vector<vi> vvi;\n\nint main(int argc, char ** argv) {\n\tll n;\n\tcin >> n;\n\tvi a(n,0);\n\tvector<bool> col(8, false);\n\tll num_pros = 0;\n\tfor(ll i=0; i<n; i++) {\n\t\tcin >> a[i];\n\t\tif(a[i] < 3200) col[a[i]/400] = true;\n\t\telse num_pros++;\n\t}\n\tll min_cols = 0;\n\tfor(ll i=0; i<8; i++) if(col[i]) min_cols++;\n\tif(min_cols == 0) cout << 1 << \" \" << num_pros << endl;\n\telse cout << min_cols << \" \" << min_cols+num_pros << endl;\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1497159029, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03695.html", "problem_id": "p03695", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03695/input.txt", "sample_output_relpath": "derived/input_output/data/p03695/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03695/C++/s975774519.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s975774519", "user_id": "u563175612"}, "prompt_components": {"gold_output": "2 2\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef vector<ll> vi;\ntypedef vector<vi> vvi;\n\nint main(int argc, char ** argv) {\n\tll n;\n\tcin >> n;\n\tvi a(n,0);\n\tvector<bool> col(8, false);\n\tll num_pros = 0;\n\tfor(ll i=0; i<n; i++) {\n\t\tcin >> a[i];\n\t\tif(a[i] < 3200) col[a[i]/400] = true;\n\t\telse num_pros++;\n\t}\n\tll min_cols = 0;\n\tfor(ll i=0; i<8; i++) if(col[i]) min_cols++;\n\tif(min_cols == 0) cout << 1 << \" \" << num_pros << endl;\n\telse cout << min_cols << \" \" << min_cols+num_pros << endl;\n\treturn 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nIn AtCoder, a person who has participated in a contest receives a color, which corresponds to the person's rating as follows:\n\nRating 1-399 : gray\n\nRating 400-799 : brown\n\nRating 800-1199 : green\n\nRating 1200-1599 : cyan\n\nRating 1600-1999 : blue\n\nRating 2000-2399 : yellow\n\nRating 2400-2799 : orange\n\nRating 2800-3199 : red\n\nOther than the above, a person whose rating is 3200 or higher can freely pick his/her color, which can be one of the eight colors above or not.\n\nCurrently, there are N users who have participated in a contest in AtCoder, and the i-th user has a rating of a_i.\n\nFind the minimum and maximum possible numbers of different colors of the users.\n\nConstraints\n\n1 ≤ N ≤ 100\n\n1 ≤ a_i ≤ 4800\n\na_i is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_N\n\nOutput\n\nPrint the minimum possible number of different colors of the users, and the maximum possible number of different colors, with a space in between.\n\nSample Input 1\n\n4\n2100 2500 2700 2700\n\nSample Output 1\n\n2 2\n\nThe user with rating 2100 is \"yellow\", and the others are \"orange\". There are two different colors.\n\nSample Input 2\n\n5\n1100 1900 2800 3200 3200\n\nSample Output 2\n\n3 5\n\nThe user with rating 1100 is \"green\", the user with rating 1900 is blue and the user with rating 2800 is \"red\".\n\nIf the fourth user picks \"red\", and the fifth user picks \"blue\", there are three different colors. This is one possible scenario for the minimum number of colors.\n\nIf the fourth user picks \"purple\", and the fifth user picks \"black\", there are five different colors. This is one possible scenario for the maximum number of colors.\n\nSample Input 3\n\n20\n800 810 820 830 840 850 860 870 880 890 900 910 920 930 940 950 960 970 980 990\n\nSample Output 3\n\n1 1\n\nAll the users are \"green\", and thus there is one color.", "sample_input": "4\n2100 2500 2700 2700\n"}, "reference_outputs": ["2 2\n"], "source_document_id": "p03695", "source_text": "Score : 300 points\n\nProblem Statement\n\nIn AtCoder, a person who has participated in a contest receives a color, which corresponds to the person's rating as follows:\n\nRating 1-399 : gray\n\nRating 400-799 : brown\n\nRating 800-1199 : green\n\nRating 1200-1599 : cyan\n\nRating 1600-1999 : blue\n\nRating 2000-2399 : yellow\n\nRating 2400-2799 : orange\n\nRating 2800-3199 : red\n\nOther than the above, a person whose rating is 3200 or higher can freely pick his/her color, which can be one of the eight colors above or not.\n\nCurrently, there are N users who have participated in a contest in AtCoder, and the i-th user has a rating of a_i.\n\nFind the minimum and maximum possible numbers of different colors of the users.\n\nConstraints\n\n1 ≤ N ≤ 100\n\n1 ≤ a_i ≤ 4800\n\na_i is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_N\n\nOutput\n\nPrint the minimum possible number of different colors of the users, and the maximum possible number of different colors, with a space in between.\n\nSample Input 1\n\n4\n2100 2500 2700 2700\n\nSample Output 1\n\n2 2\n\nThe user with rating 2100 is \"yellow\", and the others are \"orange\". There are two different colors.\n\nSample Input 2\n\n5\n1100 1900 2800 3200 3200\n\nSample Output 2\n\n3 5\n\nThe user with rating 1100 is \"green\", the user with rating 1900 is blue and the user with rating 2800 is \"red\".\n\nIf the fourth user picks \"red\", and the fifth user picks \"blue\", there are three different colors. This is one possible scenario for the minimum number of colors.\n\nIf the fourth user picks \"purple\", and the fifth user picks \"black\", there are five different colors. This is one possible scenario for the maximum number of colors.\n\nSample Input 3\n\n20\n800 810 820 830 840 850 860 870 880 890 900 910 920 930 940 950 960 970 980 990\n\nSample Output 3\n\n1 1\n\nAll the users are \"green\", and thus there is one color.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 539, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s955173330", "group_id": "codeNet:p03697", "input_text": "#include <bits/stdc++.h>\n#define rep(i, a, n) for(int i = a; i < n; i++)\n#define repb(i, a, b) for(int i = a; i >= b; i--)\n#define all(a) a.begin(), a.end()\n#define int long long\n#define chmax(x, y) x = max(x, y)\n#define chmin(x, y) x = min(x, y)\nusing namespace std;\ntypedef pair<int, int> P;\nconst int mod = 1000000007;\n\nsigned main(){\n    int a, b;\n    cin >> a >> b;\n    if(a + b >= 10) cout << \"error\" << endl;\n    else cout << a + b << endl;\n}", "language": "C++", "metadata": {"date": 1502566809, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03697.html", "problem_id": "p03697", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03697/input.txt", "sample_output_relpath": "derived/input_output/data/p03697/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03697/C++/s955173330.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s955173330", "user_id": "u984730891"}, "prompt_components": {"gold_output": "9\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define rep(i, a, n) for(int i = a; i < n; i++)\n#define repb(i, a, b) for(int i = a; i >= b; i--)\n#define all(a) a.begin(), a.end()\n#define int long long\n#define chmax(x, y) x = max(x, y)\n#define chmin(x, y) x = min(x, y)\nusing namespace std;\ntypedef pair<int, int> P;\nconst int mod = 1000000007;\n\nsigned main(){\n    int a, b;\n    cin >> a >> b;\n    if(a + b >= 10) cout << \"error\" << endl;\n    else cout << a + b << endl;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nYou are given two integers A and B as the input. Output the value of A + B.\n\nHowever, if A + B is 10 or greater, output error instead.\n\nConstraints\n\nA and B are integers.\n\n1 ≤ A, B ≤ 9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nIf A + B is 10 or greater, print the string error (case-sensitive); otherwise, print the value of A + B.\n\nSample Input 1\n\n6 3\n\nSample Output 1\n\n9\n\nSample Input 2\n\n6 4\n\nSample Output 2\n\nerror", "sample_input": "6 3\n"}, "reference_outputs": ["9\n"], "source_document_id": "p03697", "source_text": "Score : 100 points\n\nProblem Statement\n\nYou are given two integers A and B as the input. Output the value of A + B.\n\nHowever, if A + B is 10 or greater, output error instead.\n\nConstraints\n\nA and B are integers.\n\n1 ≤ A, B ≤ 9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B\n\nOutput\n\nIf A + B is 10 or greater, print the string error (case-sensitive); otherwise, print the value of A + B.\n\nSample Input 1\n\n6 3\n\nSample Output 1\n\n9\n\nSample Input 2\n\n6 4\n\nSample Output 2\n\nerror", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 449, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s060481527", "group_id": "codeNet:p03698", "input_text": "#include <iostream>\n#include <string>\n#include <algorithm>\n#include <vector>\n\nusing namespace std;\n\nint main(void) {\n\n\tstring s;\n\tint a[26] = { 0 }, co = 0;\n\n\tcin >> s;\n\n\tfor (int i = 0; i < s.size(); i++) {\n\t\tif (a[(int)s[i] - 'a'] != 0) {\n\t\t\tco = 1;\n\t\t\tbreak;\n\t\t}\n\t\ta[(int)s[i] - 'a']++;\n\t}\t\n\n\tif (co == 0) cout << \"yes\" << endl;\n\telse cout << \"no\" << endl;\n\n\treturn 0;\n\n}", "language": "C++", "metadata": {"date": 1504837420, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03698.html", "problem_id": "p03698", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03698/input.txt", "sample_output_relpath": "derived/input_output/data/p03698/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03698/C++/s060481527.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s060481527", "user_id": "u599422759"}, "prompt_components": {"gold_output": "yes\n", "input_to_evaluate": "#include <iostream>\n#include <string>\n#include <algorithm>\n#include <vector>\n\nusing namespace std;\n\nint main(void) {\n\n\tstring s;\n\tint a[26] = { 0 }, co = 0;\n\n\tcin >> s;\n\n\tfor (int i = 0; i < s.size(); i++) {\n\t\tif (a[(int)s[i] - 'a'] != 0) {\n\t\t\tco = 1;\n\t\t\tbreak;\n\t\t}\n\t\ta[(int)s[i] - 'a']++;\n\t}\t\n\n\tif (co == 0) cout << \"yes\" << endl;\n\telse cout << \"no\" << endl;\n\n\treturn 0;\n\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nYou are given a string S consisting of lowercase English letters. Determine whether all the characters in S are different.\n\nConstraints\n\n2 ≤ |S| ≤ 26, where |S| denotes the length of S.\n\nS consists of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nIf all the characters in S are different, print yes (case-sensitive); otherwise, print no.\n\nSample Input 1\n\nuncopyrightable\n\nSample Output 1\n\nyes\n\nSample Input 2\n\ndifferent\n\nSample Output 2\n\nno\n\nSample Input 3\n\nno\n\nSample Output 3\n\nyes", "sample_input": "uncopyrightable\n"}, "reference_outputs": ["yes\n"], "source_document_id": "p03698", "source_text": "Score : 200 points\n\nProblem Statement\n\nYou are given a string S consisting of lowercase English letters. Determine whether all the characters in S are different.\n\nConstraints\n\n2 ≤ |S| ≤ 26, where |S| denotes the length of S.\n\nS consists of lowercase English letters.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nS\n\nOutput\n\nIf all the characters in S are different, print yes (case-sensitive); otherwise, print no.\n\nSample Input 1\n\nuncopyrightable\n\nSample Output 1\n\nyes\n\nSample Input 2\n\ndifferent\n\nSample Output 2\n\nno\n\nSample Input 3\n\nno\n\nSample Output 3\n\nyes", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 374, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s708498054", "group_id": "codeNet:p03699", "input_text": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include <string>\nusing namespace std;\nint main()\n{\n    int n,S,ans=0,hyouka;\n\tvector<int> s;\n    cin >> n;\n    for(int i=0;i<n;i++)\n\t{\n\t\tcin>>S;\n\t\ts.push_back(S);\n\t\tans+=s[i];\n\t}\n\tsort(s.begin(),s.end());\n\tfor(int i=0;i<n;i++)\n\t{\n\t\tif(ans%10==0&&s[i]%10!=0)\n\t\t\tans-=s[i];\n\t\telse\n\t\t{\n\t\t\tcout<<ans;\n\t\t\treturn 0;\n\t\t}\n\t}\n\tcout<<\"0\";\n    return 0;\n}", "language": "C++", "metadata": {"date": 1509945217, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03699.html", "problem_id": "p03699", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03699/input.txt", "sample_output_relpath": "derived/input_output/data/p03699/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03699/C++/s708498054.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s708498054", "user_id": "u373958718"}, "prompt_components": {"gold_output": "25\n", "input_to_evaluate": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include <string>\nusing namespace std;\nint main()\n{\n    int n,S,ans=0,hyouka;\n\tvector<int> s;\n    cin >> n;\n    for(int i=0;i<n;i++)\n\t{\n\t\tcin>>S;\n\t\ts.push_back(S);\n\t\tans+=s[i];\n\t}\n\tsort(s.begin(),s.end());\n\tfor(int i=0;i<n;i++)\n\t{\n\t\tif(ans%10==0&&s[i]%10!=0)\n\t\t\tans-=s[i];\n\t\telse\n\t\t{\n\t\t\tcout<<ans;\n\t\t\treturn 0;\n\t\t}\n\t}\n\tcout<<\"0\";\n    return 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nYou are taking a computer-based examination. The examination consists of N questions, and the score allocated to the i-th question is s_i. Your answer to each question will be judged as either \"correct\" or \"incorrect\", and your grade will be the sum of the points allocated to questions that are answered correctly. When you finish answering the questions, your answers will be immediately judged and your grade will be displayed... if everything goes well.\n\nHowever, the examination system is actually flawed, and if your grade is a multiple of 10, the system displays 0 as your grade. Otherwise, your grade is displayed correctly. In this situation, what is the maximum value that can be displayed as your grade?\n\nConstraints\n\nAll input values are integers.\n\n1 ≤ N ≤ 100\n\n1 ≤ s_i ≤ 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\ns_1\ns_2\n:\ns_N\n\nOutput\n\nPrint the maximum value that can be displayed as your grade.\n\nSample Input 1\n\n3\n5\n10\n15\n\nSample Output 1\n\n25\n\nYour grade will be 25 if the 10-point and 15-point questions are answered correctly and the 5-point question is not, and this grade will be displayed correctly. Your grade will become 30 if the 5-point question is also answered correctly, but this grade will be incorrectly displayed as 0.\n\nSample Input 2\n\n3\n10\n10\n15\n\nSample Output 2\n\n35\n\nYour grade will be 35 if all the questions are answered correctly, and this grade will be displayed correctly.\n\nSample Input 3\n\n3\n10\n20\n30\n\nSample Output 3\n\n0\n\nRegardless of whether each question is answered correctly or not, your grade will be a multiple of 10 and displayed as 0.", "sample_input": "3\n5\n10\n15\n"}, "reference_outputs": ["25\n"], "source_document_id": "p03699", "source_text": "Score : 300 points\n\nProblem Statement\n\nYou are taking a computer-based examination. The examination consists of N questions, and the score allocated to the i-th question is s_i. Your answer to each question will be judged as either \"correct\" or \"incorrect\", and your grade will be the sum of the points allocated to questions that are answered correctly. When you finish answering the questions, your answers will be immediately judged and your grade will be displayed... if everything goes well.\n\nHowever, the examination system is actually flawed, and if your grade is a multiple of 10, the system displays 0 as your grade. Otherwise, your grade is displayed correctly. In this situation, what is the maximum value that can be displayed as your grade?\n\nConstraints\n\nAll input values are integers.\n\n1 ≤ N ≤ 100\n\n1 ≤ s_i ≤ 100\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\ns_1\ns_2\n:\ns_N\n\nOutput\n\nPrint the maximum value that can be displayed as your grade.\n\nSample Input 1\n\n3\n5\n10\n15\n\nSample Output 1\n\n25\n\nYour grade will be 25 if the 10-point and 15-point questions are answered correctly and the 5-point question is not, and this grade will be displayed correctly. Your grade will become 30 if the 5-point question is also answered correctly, but this grade will be incorrectly displayed as 0.\n\nSample Input 2\n\n3\n10\n10\n15\n\nSample Output 2\n\n35\n\nYour grade will be 35 if all the questions are answered correctly, and this grade will be displayed correctly.\n\nSample Input 3\n\n3\n10\n20\n30\n\nSample Output 3\n\n0\n\nRegardless of whether each question is answered correctly or not, your grade will be a multiple of 10 and displayed as 0.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 401, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s003295820", "group_id": "codeNet:p03702", "input_text": "#include <algorithm>\n#include <cstdio>\n#include <iostream>\n#include <cfloat>\n#include <climits>\n#include <cstdlib>\n#include <cstring>\n#include <cmath>\n#include <queue>\n#include <sstream>\n#include <stack>\n#include <time.h>\n#include <vector>\n#include <complex>\n#include <map>\n#include <set>\n#include <iomanip>\n#include <math.h>\n#include <stdlib.h>\n#include  <list>\n#include  <utility>\n#include  <memory>\n#include  <cstring>\n#include  <fstream>\n#include  <numeric>\nusing namespace std;\nlong long monst[100003];\nint main(){\n  long long n,a,b,ans=0;\n  cin>>n>>a>>b;\n  for (long long i=0;i<n;i++)\n    cin>>monst[i];\n  sort (monst,monst+n);\n  while (monst[n-1]>0){\n    ans++;\n  \tmonst[n-1]-=a;\n  \tfor (long long i=n-2;i>=0;i--) monst[i]-=b;\n  \tsort (monst,monst+n);\n  }\n  cout<<ans;\n  return 0;\n}", "language": "C++", "metadata": {"date": 1528334403, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03702.html", "problem_id": "p03702", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03702/input.txt", "sample_output_relpath": "derived/input_output/data/p03702/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03702/C++/s003295820.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s003295820", "user_id": "u937608388"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <algorithm>\n#include <cstdio>\n#include <iostream>\n#include <cfloat>\n#include <climits>\n#include <cstdlib>\n#include <cstring>\n#include <cmath>\n#include <queue>\n#include <sstream>\n#include <stack>\n#include <time.h>\n#include <vector>\n#include <complex>\n#include <map>\n#include <set>\n#include <iomanip>\n#include <math.h>\n#include <stdlib.h>\n#include  <list>\n#include  <utility>\n#include  <memory>\n#include  <cstring>\n#include  <fstream>\n#include  <numeric>\nusing namespace std;\nlong long monst[100003];\nint main(){\n  long long n,a,b,ans=0;\n  cin>>n>>a>>b;\n  for (long long i=0;i<n;i++)\n    cin>>monst[i];\n  sort (monst,monst+n);\n  while (monst[n-1]>0){\n    ans++;\n  \tmonst[n-1]-=a;\n  \tfor (long long i=n-2;i>=0;i--) monst[i]-=b;\n  \tsort (monst,monst+n);\n  }\n  cout<<ans;\n  return 0;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nYou are going out for a walk, when you suddenly encounter N monsters. Each monster has a parameter called health, and the health of the i-th monster is h_i at the moment of encounter. A monster will vanish immediately when its health drops to 0 or below.\n\nFortunately, you are a skilled magician, capable of causing explosions that damage monsters. In one explosion, you can damage monsters as follows:\n\nSelect an alive monster, and cause an explosion centered at that monster. The health of the monster at the center of the explosion will decrease by A, and the health of each of the other monsters will decrease by B. Here, A and B are predetermined parameters, and A > B holds.\n\nAt least how many explosions do you need to cause in order to vanish all the monsters?\n\nConstraints\n\nAll input values are integers.\n\n1 ≤ N ≤ 10^5\n\n1 ≤ B < A ≤ 10^9\n\n1 ≤ h_i ≤ 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN A B\nh_1\nh_2\n:\nh_N\n\nOutput\n\nPrint the minimum number of explosions that needs to be caused in order to vanish all the monsters.\n\nSample Input 1\n\n4 5 3\n8\n7\n4\n2\n\nSample Output 1\n\n2\n\nYou can vanish all the monsters in two explosion, as follows:\n\nFirst, cause an explosion centered at the monster with 8 health. The healths of the four monsters become 3, 4, 1 and -1, respectively, and the last monster vanishes.\n\nSecond, cause an explosion centered at the monster with 4 health remaining. The healths of the three remaining monsters become 0, -1 and -2, respectively, and all the monsters are now vanished.\n\nSample Input 2\n\n2 10 4\n20\n20\n\nSample Output 2\n\n4\n\nYou need to cause two explosions centered at each monster, for a total of four.\n\nSample Input 3\n\n5 2 1\n900000000\n900000000\n1000000000\n1000000000\n1000000000\n\nSample Output 3\n\n800000000", "sample_input": "4 5 3\n8\n7\n4\n2\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03702", "source_text": "Score : 400 points\n\nProblem Statement\n\nYou are going out for a walk, when you suddenly encounter N monsters. Each monster has a parameter called health, and the health of the i-th monster is h_i at the moment of encounter. A monster will vanish immediately when its health drops to 0 or below.\n\nFortunately, you are a skilled magician, capable of causing explosions that damage monsters. In one explosion, you can damage monsters as follows:\n\nSelect an alive monster, and cause an explosion centered at that monster. The health of the monster at the center of the explosion will decrease by A, and the health of each of the other monsters will decrease by B. Here, A and B are predetermined parameters, and A > B holds.\n\nAt least how many explosions do you need to cause in order to vanish all the monsters?\n\nConstraints\n\nAll input values are integers.\n\n1 ≤ N ≤ 10^5\n\n1 ≤ B < A ≤ 10^9\n\n1 ≤ h_i ≤ 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN A B\nh_1\nh_2\n:\nh_N\n\nOutput\n\nPrint the minimum number of explosions that needs to be caused in order to vanish all the monsters.\n\nSample Input 1\n\n4 5 3\n8\n7\n4\n2\n\nSample Output 1\n\n2\n\nYou can vanish all the monsters in two explosion, as follows:\n\nFirst, cause an explosion centered at the monster with 8 health. The healths of the four monsters become 3, 4, 1 and -1, respectively, and the last monster vanishes.\n\nSecond, cause an explosion centered at the monster with 4 health remaining. The healths of the three remaining monsters become 0, -1 and -2, respectively, and all the monsters are now vanished.\n\nSample Input 2\n\n2 10 4\n20\n20\n\nSample Output 2\n\n4\n\nYou need to cause two explosions centered at each monster, for a total of four.\n\nSample Input 3\n\n5 2 1\n900000000\n900000000\n1000000000\n1000000000\n1000000000\n\nSample Output 3\n\n800000000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 789, "cpu_time_ms": 2103, "memory_kb": 1024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s534629462", "group_id": "codeNet:p03704", "input_text": "#include<cstdio>\n#include<algorithm>\nlong long pow10[15];\nlong long mapL[1000005]; int sizeL = -1;\nlong long mapR[1000005]; int sizeR = -1;\n//org: a[n],a[n-1]...a[2],a[1]\n//rev: a[1],a[2]...a[n-1],a[n]\n//dfs on rev, a[n]!=0\n//end of left is (n+1)/2\n\nvoid dfsL(int p,int n,long long sum){\n    int mid = (n+1)/2;\n    if(p==mid+1) mapL[++sizeL] = sum;\n    else{\n        for(long long i = 0; i <= 9; i++){\n            long long add = i*pow10[n-p], minus = i*pow10[p-1];\n            dfsL(p+1,n,sum+add-minus);\n        }\n    }\n}\n\nvoid dfsR(int p,int n,long long sum){\n    if(p==n+1) mapR[++sizeR] = sum;\n    else{\n        int start = 0;\n        if(p==n) start = 1;\n        for(long long i = start; i <= 9; i++){\n            long long add = i*pow10[n-p], minus = i*pow10[p-1];\n            dfsR(p+1,n,sum+add-minus);\n        }\n    }\n}\n\nint getFirst(long long u,long long map[],int size){\n    int L = 1, R = size;\n    int res = -1;\n    while(L<=R){\n        int M = (L+R)/2;\n        if(map[M]>=u){\n            res = M;\n            R = M-1;\n        }\n        else L = M+1;\n    }\n    return res;\n}\n\nint getLast(long long u,long long map[],int size){\n    int L = 1, R = size;\n    int res = -1;\n    while(L<=R){\n        int M = (L+R)/2;\n        if(map[M]<=u){\n            res = M;\n            L = M+1;\n        }\n        else R = M-1;\n    }\n    return res;\n}\n\nint main(){\n    pow10[0] = 1;\n    for(int i = 1; i <= 13; i++) pow10[i] = pow10[i-1]*10ll;\n    long long d;\n    scanf(\"%lld\",&d);\n    long long ans = 0;\n    for(int i = 1; i <= 10; i++){\n        sizeL = sizeR = 0;\n        int mid = (i+1)/2;\n        dfsL(1,i,0);\n        dfsR(mid+1,i,0);\n        std::sort(mapL+1,mapL+1+sizeL);\n        std::sort(mapR+1,mapR+1+sizeR);\n        for(int j = 1; j <= sizeL; j++){\n            long long u = mapL[j];\n            long long need = d-u;\n            int lower = getFirst(need,mapR,sizeR), upper = getLast(need,mapR,sizeR);\n            if(lower!=-1 && upper!=-1 && mapR[lower]==need && mapR[upper]==need) ans += (long long)(upper-lower+1);\n        }\n    }\n    printf(\"%lld\\n\",ans);\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1600802632, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03704.html", "problem_id": "p03704", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03704/input.txt", "sample_output_relpath": "derived/input_output/data/p03704/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03704/C++/s534629462.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s534629462", "user_id": "u602509796"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include<cstdio>\n#include<algorithm>\nlong long pow10[15];\nlong long mapL[1000005]; int sizeL = -1;\nlong long mapR[1000005]; int sizeR = -1;\n//org: a[n],a[n-1]...a[2],a[1]\n//rev: a[1],a[2]...a[n-1],a[n]\n//dfs on rev, a[n]!=0\n//end of left is (n+1)/2\n\nvoid dfsL(int p,int n,long long sum){\n    int mid = (n+1)/2;\n    if(p==mid+1) mapL[++sizeL] = sum;\n    else{\n        for(long long i = 0; i <= 9; i++){\n            long long add = i*pow10[n-p], minus = i*pow10[p-1];\n            dfsL(p+1,n,sum+add-minus);\n        }\n    }\n}\n\nvoid dfsR(int p,int n,long long sum){\n    if(p==n+1) mapR[++sizeR] = sum;\n    else{\n        int start = 0;\n        if(p==n) start = 1;\n        for(long long i = start; i <= 9; i++){\n            long long add = i*pow10[n-p], minus = i*pow10[p-1];\n            dfsR(p+1,n,sum+add-minus);\n        }\n    }\n}\n\nint getFirst(long long u,long long map[],int size){\n    int L = 1, R = size;\n    int res = -1;\n    while(L<=R){\n        int M = (L+R)/2;\n        if(map[M]>=u){\n            res = M;\n            R = M-1;\n        }\n        else L = M+1;\n    }\n    return res;\n}\n\nint getLast(long long u,long long map[],int size){\n    int L = 1, R = size;\n    int res = -1;\n    while(L<=R){\n        int M = (L+R)/2;\n        if(map[M]<=u){\n            res = M;\n            L = M+1;\n        }\n        else R = M-1;\n    }\n    return res;\n}\n\nint main(){\n    pow10[0] = 1;\n    for(int i = 1; i <= 13; i++) pow10[i] = pow10[i-1]*10ll;\n    long long d;\n    scanf(\"%lld\",&d);\n    long long ans = 0;\n    for(int i = 1; i <= 10; i++){\n        sizeL = sizeR = 0;\n        int mid = (i+1)/2;\n        dfsL(1,i,0);\n        dfsR(mid+1,i,0);\n        std::sort(mapL+1,mapL+1+sizeL);\n        std::sort(mapR+1,mapR+1+sizeR);\n        for(int j = 1; j <= sizeL; j++){\n            long long u = mapL[j];\n            long long need = d-u;\n            int lower = getFirst(need,mapR,sizeR), upper = getLast(need,mapR,sizeR);\n            if(lower!=-1 && upper!=-1 && mapR[lower]==need && mapR[upper]==need) ans += (long long)(upper-lower+1);\n        }\n    }\n    printf(\"%lld\\n\",ans);\n    return 0;\n}\n", "problem_context": "Score : 800 points\n\nProblem Statement\n\nFor a positive integer n, we denote the integer obtained by reversing the decimal notation of n (without leading zeroes) by rev(n). For example, rev(123) = 321 and rev(4000) = 4.\n\nYou are given a positive integer D. How many positive integers N satisfy rev(N) = N + D?\n\nConstraints\n\nD is an integer.\n\n1 ≤ D < 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nD\n\nOutput\n\nPrint the number of the positive integers N such that rev(N) = N + D.\n\nSample Input 1\n\n63\n\nSample Output 1\n\n2\n\nThere are two positive integers N such that rev(N) = N + 63: N = 18 and 29.\n\nSample Input 2\n\n75\n\nSample Output 2\n\n0\n\nThere are no positive integers N such that rev(N) = N + 75.\n\nSample Input 3\n\n864197532\n\nSample Output 3\n\n1920", "sample_input": "63\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03704", "source_text": "Score : 800 points\n\nProblem Statement\n\nFor a positive integer n, we denote the integer obtained by reversing the decimal notation of n (without leading zeroes) by rev(n). For example, rev(123) = 321 and rev(4000) = 4.\n\nYou are given a positive integer D. How many positive integers N satisfy rev(N) = N + D?\n\nConstraints\n\nD is an integer.\n\n1 ≤ D < 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nD\n\nOutput\n\nPrint the number of the positive integers N such that rev(N) = N + D.\n\nSample Input 1\n\n63\n\nSample Output 1\n\n2\n\nThere are two positive integers N such that rev(N) = N + 63: N = 18 and 29.\n\nSample Input 2\n\n75\n\nSample Output 2\n\n0\n\nThere are no positive integers N such that rev(N) = N + 75.\n\nSample Input 3\n\n864197532\n\nSample Output 3\n\n1920", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2081, "cpu_time_ms": 43, "memory_kb": 3228}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s231115942", "group_id": "codeNet:p03704", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define FOR(i,l,r) for(int i = (int) (l);i < (int) (r);i++)\ntemplate<typename T> bool chmax(T& a,const T& b){ return a < b ? (a = b,true) : false; }\ntemplate<typename T> bool chmin(T& a,const T& b){ return b < a ? (a = b,true) : false; }\ntypedef long long ll;\n\nint N;\nll D;\nll powTable [15];\nll dp [20] [2];\n\nint digit_count(ll x)\n{\n\tint res = 0;\n\tdo{\n\t\tres++;\n\t}while(x /= 10);\n\treturn res;\n}\n\nll dfs(int n,vector<int>& v)\n{\n\tll res = 0;\n\tif(n == N / 2){\n\t\tll sum = 0;\n\t\tFOR(i,0,n){\n\t\t\tsum += v [i] * (powTable [N - 1 - i] - powTable [i]);\n\t\t}\n\t\tif(sum == D){\n\t\t\tmemset(dp,0,sizeof(dp));\n\t\t\tint M = N / 2;\n\t\t\tdp [0] [1] = 1;\n\t\t\tFOR(i,0,M) FOR(j,0,2){\n\t\t\t\tFOR(k,0,10){\n\t\t\t\t\tif(k + v [i] >= 0 && k + v [i] <= 9){\n\t\t\t\t\t\tif(j == 1 && k == 0) continue;\n\t\t\t\t\t\tdp [i + 1] [0] += dp [i] [j];\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(N % 2){\n\t\t\t\tdp [M] [0] *= 10;\n\t\t\t}\n\t\t\tres = dp [M] [0];\n\t\t\treturn res;\n\t\t}\n\t\treturn 0;\n\t}\n\tFOR(i,-9,10){\n\t\tv.push_back(i);\n\t\tres += dfs(n + 1,v);\n\t\tv.pop_back();\n\t}\n\treturn res;\n}\n\nint main()\n{\n\tscanf(\"%lld\",&D);\n\n\tN = digit_count(D);\n\tpowTable [0] = 1;\n\tfor(int i = 1;i < 15;i++){\n\t\tpowTable [i] = powTable [i - 1] * 10;\n\t}\n\tvector<int> v;\n\tll ans = dfs(0,v);\n\n\tprintf(\"%lld\\n\",ans);\n\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1496543284, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03704.html", "problem_id": "p03704", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03704/input.txt", "sample_output_relpath": "derived/input_output/data/p03704/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03704/C++/s231115942.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s231115942", "user_id": "u657011188"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define FOR(i,l,r) for(int i = (int) (l);i < (int) (r);i++)\ntemplate<typename T> bool chmax(T& a,const T& b){ return a < b ? (a = b,true) : false; }\ntemplate<typename T> bool chmin(T& a,const T& b){ return b < a ? (a = b,true) : false; }\ntypedef long long ll;\n\nint N;\nll D;\nll powTable [15];\nll dp [20] [2];\n\nint digit_count(ll x)\n{\n\tint res = 0;\n\tdo{\n\t\tres++;\n\t}while(x /= 10);\n\treturn res;\n}\n\nll dfs(int n,vector<int>& v)\n{\n\tll res = 0;\n\tif(n == N / 2){\n\t\tll sum = 0;\n\t\tFOR(i,0,n){\n\t\t\tsum += v [i] * (powTable [N - 1 - i] - powTable [i]);\n\t\t}\n\t\tif(sum == D){\n\t\t\tmemset(dp,0,sizeof(dp));\n\t\t\tint M = N / 2;\n\t\t\tdp [0] [1] = 1;\n\t\t\tFOR(i,0,M) FOR(j,0,2){\n\t\t\t\tFOR(k,0,10){\n\t\t\t\t\tif(k + v [i] >= 0 && k + v [i] <= 9){\n\t\t\t\t\t\tif(j == 1 && k == 0) continue;\n\t\t\t\t\t\tdp [i + 1] [0] += dp [i] [j];\n\t\t\t\t\t}\n\t\t\t\t}\n\t\t\t}\n\t\t\tif(N % 2){\n\t\t\t\tdp [M] [0] *= 10;\n\t\t\t}\n\t\t\tres = dp [M] [0];\n\t\t\treturn res;\n\t\t}\n\t\treturn 0;\n\t}\n\tFOR(i,-9,10){\n\t\tv.push_back(i);\n\t\tres += dfs(n + 1,v);\n\t\tv.pop_back();\n\t}\n\treturn res;\n}\n\nint main()\n{\n\tscanf(\"%lld\",&D);\n\n\tN = digit_count(D);\n\tpowTable [0] = 1;\n\tfor(int i = 1;i < 15;i++){\n\t\tpowTable [i] = powTable [i - 1] * 10;\n\t}\n\tvector<int> v;\n\tll ans = dfs(0,v);\n\n\tprintf(\"%lld\\n\",ans);\n\n\treturn 0;\n}\n", "problem_context": "Score : 800 points\n\nProblem Statement\n\nFor a positive integer n, we denote the integer obtained by reversing the decimal notation of n (without leading zeroes) by rev(n). For example, rev(123) = 321 and rev(4000) = 4.\n\nYou are given a positive integer D. How many positive integers N satisfy rev(N) = N + D?\n\nConstraints\n\nD is an integer.\n\n1 ≤ D < 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nD\n\nOutput\n\nPrint the number of the positive integers N such that rev(N) = N + D.\n\nSample Input 1\n\n63\n\nSample Output 1\n\n2\n\nThere are two positive integers N such that rev(N) = N + 63: N = 18 and 29.\n\nSample Input 2\n\n75\n\nSample Output 2\n\n0\n\nThere are no positive integers N such that rev(N) = N + 75.\n\nSample Input 3\n\n864197532\n\nSample Output 3\n\n1920", "sample_input": "63\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03704", "source_text": "Score : 800 points\n\nProblem Statement\n\nFor a positive integer n, we denote the integer obtained by reversing the decimal notation of n (without leading zeroes) by rev(n). For example, rev(123) = 321 and rev(4000) = 4.\n\nYou are given a positive integer D. How many positive integers N satisfy rev(N) = N + D?\n\nConstraints\n\nD is an integer.\n\n1 ≤ D < 10^9\n\nInput\n\nInput is given from Standard Input in the following format:\n\nD\n\nOutput\n\nPrint the number of the positive integers N such that rev(N) = N + D.\n\nSample Input 1\n\n63\n\nSample Output 1\n\n2\n\nThere are two positive integers N such that rev(N) = N + 63: N = 18 and 29.\n\nSample Input 2\n\n75\n\nSample Output 2\n\n0\n\nThere are no positive integers N such that rev(N) = N + 75.\n\nSample Input 3\n\n864197532\n\nSample Output 3\n\n1920", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1255, "cpu_time_ms": 3, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s236983461", "group_id": "codeNet:p03709", "input_text": "#include<bits/stdc++.h>\n#define pb push_back\n#define mp make_pair\n#define fi first\n#define se second\nusing namespace std;\nconst int N=2e5+10;\nconst int inf=1e9;\nconst int mod=1e9+7;\ntypedef pair<int,int> pii;\nint gi() {\n    int x=0,o=1;char ch=getchar();\n    while((ch<'0'||ch>'9')&&ch!='-') ch=getchar();\n    if(ch=='-') o=-1,ch=getchar();\n    while(ch>='0'&&ch<='9') x=x*10+ch-'0',ch=getchar();\n    return x*o;\n}\nint n,st[N],pre[N],suf[N],top=0,f[N],sum[N];\npii a[N];\nvector<int> v[N];\nint main() {\n    cin>>n;\n    for(int i=1;i<=n;i++) a[i].fi=gi(),a[i].se=gi(),st[++top]=a[i].se;\n    sort(st+1,st+top+1);\n    for(int i=1;i<=n;i++) a[i].se=lower_bound(st+1,st+top+1,a[i].se)-st;\n    sort(a+1,a+n+1);\n    for(int i=1;i<=n;i++) pre[i]=max(pre[i-1],a[i].se);\n    suf[n+1]=inf;\n    for(int i=n;i;i--) suf[i]=min(suf[i+1],a[i].se);\n    for(int i=1;i<=n;i++) v[pre[i]].pb(suf[i]);\n    f[0]=sum[0]=1;\n    for(int i=1;i<=n;i++) {\n        sum[i]=sum[i-1];\n        for(int j:v[i]) {\n            f[i]=(f[i]+sum[i])%mod;\n            if(j>=2) f[i]=(f[i]-sum[j-2]+mod)%mod;\n            sum[i]=(sum[i-1]+f[i])%mod;\n        }\n    }\n    printf(\"%d\\n\",f[n]);\n    return 0;\n}\n//orzgzy\n//鸡贼明年进队超稳\n", "language": "C++", "metadata": {"date": 1536681943, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03709.html", "problem_id": "p03709", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03709/input.txt", "sample_output_relpath": "derived/input_output/data/p03709/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03709/C++/s236983461.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s236983461", "user_id": "u030892114"}, "prompt_components": {"gold_output": "6\n", "input_to_evaluate": "#include<bits/stdc++.h>\n#define pb push_back\n#define mp make_pair\n#define fi first\n#define se second\nusing namespace std;\nconst int N=2e5+10;\nconst int inf=1e9;\nconst int mod=1e9+7;\ntypedef pair<int,int> pii;\nint gi() {\n    int x=0,o=1;char ch=getchar();\n    while((ch<'0'||ch>'9')&&ch!='-') ch=getchar();\n    if(ch=='-') o=-1,ch=getchar();\n    while(ch>='0'&&ch<='9') x=x*10+ch-'0',ch=getchar();\n    return x*o;\n}\nint n,st[N],pre[N],suf[N],top=0,f[N],sum[N];\npii a[N];\nvector<int> v[N];\nint main() {\n    cin>>n;\n    for(int i=1;i<=n;i++) a[i].fi=gi(),a[i].se=gi(),st[++top]=a[i].se;\n    sort(st+1,st+top+1);\n    for(int i=1;i<=n;i++) a[i].se=lower_bound(st+1,st+top+1,a[i].se)-st;\n    sort(a+1,a+n+1);\n    for(int i=1;i<=n;i++) pre[i]=max(pre[i-1],a[i].se);\n    suf[n+1]=inf;\n    for(int i=n;i;i--) suf[i]=min(suf[i+1],a[i].se);\n    for(int i=1;i<=n;i++) v[pre[i]].pb(suf[i]);\n    f[0]=sum[0]=1;\n    for(int i=1;i<=n;i++) {\n        sum[i]=sum[i-1];\n        for(int j:v[i]) {\n            f[i]=(f[i]+sum[i])%mod;\n            if(j>=2) f[i]=(f[i]-sum[j-2]+mod)%mod;\n            sum[i]=(sum[i-1]+f[i])%mod;\n        }\n    }\n    printf(\"%d\\n\",f[n]);\n    return 0;\n}\n//orzgzy\n//鸡贼明年进队超稳\n", "problem_context": "Score : 1200 points\n\nProblem Statement\n\nTakahashi is an expert of Clone Jutsu, a secret art that creates copies of his body.\n\nOn a number line, there are N copies of Takahashi, numbered 1 through N.\nThe i-th copy is located at position X_i and starts walking with velocity V_i in the positive direction at time 0.\n\nKenus is a master of Transformation Jutsu, and not only can he change into a person other than himself, but he can also transform another person into someone else.\n\nKenus can select some of the copies of Takahashi at time 0, and transform them into copies of Aoki, another Ninja.\nThe walking velocity of a copy does not change when it transforms.\nFrom then on, whenever a copy of Takahashi and a copy of Aoki are at the same coordinate, that copy of Takahashi transforms into a copy of Aoki.\n\nAmong the 2^N ways to transform some copies of Takahashi into copies of Aoki at time 0, in how many ways will all the copies of Takahashi become copies of Aoki after a sufficiently long time?\nFind the count modulo 10^9+7.\n\nConstraints\n\n1 ≤ N ≤ 200000\n\n1 ≤ X_i,V_i ≤ 10^9(1 ≤ i ≤ N)\n\nX_i and V_i are integers.\n\nAll X_i are distinct.\n\nAll V_i are distinct.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nX_1 V_1\n:\nX_N V_N\n\nOutput\n\nPrint the number of the ways that cause all the copies of Takahashi to turn into copies of Aoki after a sufficiently long time, modulo 10^9+7.\n\nSample Input 1\n\n3\n2 5\n6 1\n3 7\n\nSample Output 1\n\n6\n\nAll copies of Takahashi will turn into copies of Aoki after a sufficiently long time if Kenus transforms one of the following sets of copies of Takahashi into copies of Aoki: (2), (3), (1,2), (1,3), (2,3) and (1,2,3).\n\nSample Input 2\n\n4\n3 7\n2 9\n8 16\n10 8\n\nSample Output 2\n\n9", "sample_input": "3\n2 5\n6 1\n3 7\n"}, "reference_outputs": ["6\n"], "source_document_id": "p03709", "source_text": "Score : 1200 points\n\nProblem Statement\n\nTakahashi is an expert of Clone Jutsu, a secret art that creates copies of his body.\n\nOn a number line, there are N copies of Takahashi, numbered 1 through N.\nThe i-th copy is located at position X_i and starts walking with velocity V_i in the positive direction at time 0.\n\nKenus is a master of Transformation Jutsu, and not only can he change into a person other than himself, but he can also transform another person into someone else.\n\nKenus can select some of the copies of Takahashi at time 0, and transform them into copies of Aoki, another Ninja.\nThe walking velocity of a copy does not change when it transforms.\nFrom then on, whenever a copy of Takahashi and a copy of Aoki are at the same coordinate, that copy of Takahashi transforms into a copy of Aoki.\n\nAmong the 2^N ways to transform some copies of Takahashi into copies of Aoki at time 0, in how many ways will all the copies of Takahashi become copies of Aoki after a sufficiently long time?\nFind the count modulo 10^9+7.\n\nConstraints\n\n1 ≤ N ≤ 200000\n\n1 ≤ X_i,V_i ≤ 10^9(1 ≤ i ≤ N)\n\nX_i and V_i are integers.\n\nAll X_i are distinct.\n\nAll V_i are distinct.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nX_1 V_1\n:\nX_N V_N\n\nOutput\n\nPrint the number of the ways that cause all the copies of Takahashi to turn into copies of Aoki after a sufficiently long time, modulo 10^9+7.\n\nSample Input 1\n\n3\n2 5\n6 1\n3 7\n\nSample Output 1\n\n6\n\nAll copies of Takahashi will turn into copies of Aoki after a sufficiently long time if Kenus transforms one of the following sets of copies of Takahashi into copies of Aoki: (2), (3), (1,2), (1,3), (2,3) and (1,2,3).\n\nSample Input 2\n\n4\n3 7\n2 9\n8 16\n10 8\n\nSample Output 2\n\n9", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1196, "cpu_time_ms": 100, "memory_kb": 16640}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s352644951", "group_id": "codeNet:p03711", "input_text": "#include <iostream>\n#include <vector>\n\nusing namespace std;\n\nint main()\n{\n  int par[] = {-1, 1, 2, 1, 4, 1, 4, 1, 1, 4, 1, 4, 1};\n  int x, y;\n  cin >> x >> y;\n\n  if (par[x] == par[y]) cout << \"Yes\" << endl;\n  else cout << \"No\" << endl;\n\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1555620267, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03711.html", "problem_id": "p03711", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03711/input.txt", "sample_output_relpath": "derived/input_output/data/p03711/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03711/C++/s352644951.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s352644951", "user_id": "u973997867"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\n\nusing namespace std;\n\nint main()\n{\n  int par[] = {-1, 1, 2, 1, 4, 1, 4, 1, 1, 4, 1, 4, 1};\n  int x, y;\n  cin >> x >> y;\n\n  if (par[x] == par[y]) cout << \"Yes\" << endl;\n  else cout << \"No\" << endl;\n\n  return 0;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nBased on some criterion, Snuke divided the integers from 1 through 12 into three groups as shown in the figure below.\nGiven two integers x and y (1 ≤ x < y ≤ 12), determine whether they belong to the same group.\n\nConstraints\n\nx and y are integers.\n\n1 ≤ x < y ≤ 12\n\nInput\n\nInput is given from Standard Input in the following format:\n\nx y\n\nOutput\n\nIf x and y belong to the same group, print Yes; otherwise, print No.\n\nSample Input 1\n\n1 3\n\nSample Output 1\n\nYes\n\nSample Input 2\n\n2 4\n\nSample Output 2\n\nNo", "sample_input": "1 3\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p03711", "source_text": "Score : 100 points\n\nProblem Statement\n\nBased on some criterion, Snuke divided the integers from 1 through 12 into three groups as shown in the figure below.\nGiven two integers x and y (1 ≤ x < y ≤ 12), determine whether they belong to the same group.\n\nConstraints\n\nx and y are integers.\n\n1 ≤ x < y ≤ 12\n\nInput\n\nInput is given from Standard Input in the following format:\n\nx y\n\nOutput\n\nIf x and y belong to the same group, print Yes; otherwise, print No.\n\nSample Input 1\n\n1 3\n\nSample Output 1\n\nYes\n\nSample Input 2\n\n2 4\n\nSample Output 2\n\nNo", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 251, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s187333640", "group_id": "codeNet:p03720", "input_text": "#include  <iostream>\n#include  <cstdlib>\n\n\nint main(void)\n{\n\tint N, M;\n\n\tstd::cin >> N >> M;\n\n\tint a[M], b[M];\n\tint ans[N] = {0};\n\n\tfor(int i = 0; i < M; i++){\n\t\tstd::cin >> a[i] >> b[i];\n\t\tans[a[i]-1]++;\n\t\tans[b[i]-1]++;\n\t}\n\n\tfor(int i = 0; i < N; i++)\n\t\tstd::cout << ans[i] << std::endl;\n\n\treturn EXIT_SUCCESS;\n}\n", "language": "C++", "metadata": {"date": 1590630144, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03720.html", "problem_id": "p03720", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03720/input.txt", "sample_output_relpath": "derived/input_output/data/p03720/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03720/C++/s187333640.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s187333640", "user_id": "u169867439"}, "prompt_components": {"gold_output": "2\n2\n1\n1\n", "input_to_evaluate": "#include  <iostream>\n#include  <cstdlib>\n\n\nint main(void)\n{\n\tint N, M;\n\n\tstd::cin >> N >> M;\n\n\tint a[M], b[M];\n\tint ans[N] = {0};\n\n\tfor(int i = 0; i < M; i++){\n\t\tstd::cin >> a[i] >> b[i];\n\t\tans[a[i]-1]++;\n\t\tans[b[i]-1]++;\n\t}\n\n\tfor(int i = 0; i < N; i++)\n\t\tstd::cout << ans[i] << std::endl;\n\n\treturn EXIT_SUCCESS;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nThere are N cities and M roads.\nThe i-th road (1≤i≤M) connects two cities a_i and b_i (1≤a_i,b_i≤N) bidirectionally.\nThere may be more than one road that connects the same pair of two cities.\nFor each city, how many roads are connected to the city?\n\nConstraints\n\n2≤N,M≤50\n\n1≤a_i,b_i≤N\n\na_i ≠ b_i\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\na_1 b_1\n:\na_M b_M\n\nOutput\n\nPrint the answer in N lines.\nIn the i-th line (1≤i≤N), print the number of roads connected to city i.\n\nSample Input 1\n\n4 3\n1 2\n2 3\n1 4\n\nSample Output 1\n\n2\n2\n1\n1\n\nCity 1 is connected to the 1-st and 3-rd roads.\n\nCity 2 is connected to the 1-st and 2-nd roads.\n\nCity 3 is connected to the 2-nd road.\n\nCity 4 is connected to the 3-rd road.\n\nSample Input 2\n\n2 5\n1 2\n2 1\n1 2\n2 1\n1 2\n\nSample Output 2\n\n5\n5\n\nSample Input 3\n\n8 8\n1 2\n3 4\n1 5\n2 8\n3 7\n5 2\n4 1\n6 8\n\nSample Output 3\n\n3\n3\n2\n2\n2\n1\n1\n2", "sample_input": "4 3\n1 2\n2 3\n1 4\n"}, "reference_outputs": ["2\n2\n1\n1\n"], "source_document_id": "p03720", "source_text": "Score : 200 points\n\nProblem Statement\n\nThere are N cities and M roads.\nThe i-th road (1≤i≤M) connects two cities a_i and b_i (1≤a_i,b_i≤N) bidirectionally.\nThere may be more than one road that connects the same pair of two cities.\nFor each city, how many roads are connected to the city?\n\nConstraints\n\n2≤N,M≤50\n\n1≤a_i,b_i≤N\n\na_i ≠ b_i\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\na_1 b_1\n:\na_M b_M\n\nOutput\n\nPrint the answer in N lines.\nIn the i-th line (1≤i≤N), print the number of roads connected to city i.\n\nSample Input 1\n\n4 3\n1 2\n2 3\n1 4\n\nSample Output 1\n\n2\n2\n1\n1\n\nCity 1 is connected to the 1-st and 3-rd roads.\n\nCity 2 is connected to the 1-st and 2-nd roads.\n\nCity 3 is connected to the 2-nd road.\n\nCity 4 is connected to the 3-rd road.\n\nSample Input 2\n\n2 5\n1 2\n2 1\n1 2\n2 1\n1 2\n\nSample Output 2\n\n5\n5\n\nSample Input 3\n\n8 8\n1 2\n3 4\n1 5\n2 8\n3 7\n5 2\n4 1\n6 8\n\nSample Output 3\n\n3\n3\n2\n2\n2\n1\n1\n2", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 315, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s217542391", "group_id": "codeNet:p03720", "input_text": "#include <iostream>\n\nusing namespace std;\n\nint main(int argc, char const *argv[]) {\n  int n, m;\n  cin >> n >> m;\n  int a[m], b[m], ans[50]={0};\n  for (size_t i = 0; i < m; i++) {\n    cin >> a[i] >> b[i];\n    ans[a[i]-1]++;\n    ans[b[i]-1]++;\n  }\n  for (size_t i = 0; i < n; i++) cout << ans[i] << endl;;\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1533324940, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03720.html", "problem_id": "p03720", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03720/input.txt", "sample_output_relpath": "derived/input_output/data/p03720/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03720/C++/s217542391.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s217542391", "user_id": "u391752022"}, "prompt_components": {"gold_output": "2\n2\n1\n1\n", "input_to_evaluate": "#include <iostream>\n\nusing namespace std;\n\nint main(int argc, char const *argv[]) {\n  int n, m;\n  cin >> n >> m;\n  int a[m], b[m], ans[50]={0};\n  for (size_t i = 0; i < m; i++) {\n    cin >> a[i] >> b[i];\n    ans[a[i]-1]++;\n    ans[b[i]-1]++;\n  }\n  for (size_t i = 0; i < n; i++) cout << ans[i] << endl;;\n  return 0;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nThere are N cities and M roads.\nThe i-th road (1≤i≤M) connects two cities a_i and b_i (1≤a_i,b_i≤N) bidirectionally.\nThere may be more than one road that connects the same pair of two cities.\nFor each city, how many roads are connected to the city?\n\nConstraints\n\n2≤N,M≤50\n\n1≤a_i,b_i≤N\n\na_i ≠ b_i\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\na_1 b_1\n:\na_M b_M\n\nOutput\n\nPrint the answer in N lines.\nIn the i-th line (1≤i≤N), print the number of roads connected to city i.\n\nSample Input 1\n\n4 3\n1 2\n2 3\n1 4\n\nSample Output 1\n\n2\n2\n1\n1\n\nCity 1 is connected to the 1-st and 3-rd roads.\n\nCity 2 is connected to the 1-st and 2-nd roads.\n\nCity 3 is connected to the 2-nd road.\n\nCity 4 is connected to the 3-rd road.\n\nSample Input 2\n\n2 5\n1 2\n2 1\n1 2\n2 1\n1 2\n\nSample Output 2\n\n5\n5\n\nSample Input 3\n\n8 8\n1 2\n3 4\n1 5\n2 8\n3 7\n5 2\n4 1\n6 8\n\nSample Output 3\n\n3\n3\n2\n2\n2\n1\n1\n2", "sample_input": "4 3\n1 2\n2 3\n1 4\n"}, "reference_outputs": ["2\n2\n1\n1\n"], "source_document_id": "p03720", "source_text": "Score : 200 points\n\nProblem Statement\n\nThere are N cities and M roads.\nThe i-th road (1≤i≤M) connects two cities a_i and b_i (1≤a_i,b_i≤N) bidirectionally.\nThere may be more than one road that connects the same pair of two cities.\nFor each city, how many roads are connected to the city?\n\nConstraints\n\n2≤N,M≤50\n\n1≤a_i,b_i≤N\n\na_i ≠ b_i\n\nAll input values are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\na_1 b_1\n:\na_M b_M\n\nOutput\n\nPrint the answer in N lines.\nIn the i-th line (1≤i≤N), print the number of roads connected to city i.\n\nSample Input 1\n\n4 3\n1 2\n2 3\n1 4\n\nSample Output 1\n\n2\n2\n1\n1\n\nCity 1 is connected to the 1-st and 3-rd roads.\n\nCity 2 is connected to the 1-st and 2-nd roads.\n\nCity 3 is connected to the 2-nd road.\n\nCity 4 is connected to the 3-rd road.\n\nSample Input 2\n\n2 5\n1 2\n2 1\n1 2\n2 1\n1 2\n\nSample Output 2\n\n5\n5\n\nSample Input 3\n\n8 8\n1 2\n3 4\n1 5\n2 8\n3 7\n5 2\n4 1\n6 8\n\nSample Output 3\n\n3\n3\n2\n2\n2\n1\n1\n2", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 318, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s521038668", "group_id": "codeNet:p03722", "input_text": "#include <bits/stdc++.h>\n#define rep(i, n) for (int i = 0; i < (n); ++i)\nusing namespace std;\ntypedef long long ll;\n\nconst ll INF = 1e15;\n\nstruct edge {\n  int u, v, cost;\n};\n\nll dist[1010];\n\nint main() {\n  int N, M;\n  cin >> N >> M;\n  vector<edge> edges(M);\n  for (auto &e : edges) {\n    cin >> e.u >> e.v >> e.cost;\n    e.u--, e.v--;\n    e.cost = -e.cost;\n  }\n\n  vector<ll> dist(N, INF);\n  dist[0] = 0;\n  for (int i = 0; i < 2 * N; i++) {\n    for (auto e : edges) {\n      if (dist[e.u] == INF) continue;\n      if (dist[e.u] + e.cost < dist[e.v]) {\n        dist[e.v] = dist[e.u] + e.cost;\n        if (i >= N - 1) dist[e.v] = -INF;\n      }\n    }\n  }\n  if (dist[N - 1] == -INF)\n    cout << \"inf\" << endl;\n  else\n    cout << -dist[N - 1] << endl;\n}", "language": "C++", "metadata": {"date": 1593283044, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03722.html", "problem_id": "p03722", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03722/input.txt", "sample_output_relpath": "derived/input_output/data/p03722/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03722/C++/s521038668.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s521038668", "user_id": "u810388173"}, "prompt_components": {"gold_output": "7\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define rep(i, n) for (int i = 0; i < (n); ++i)\nusing namespace std;\ntypedef long long ll;\n\nconst ll INF = 1e15;\n\nstruct edge {\n  int u, v, cost;\n};\n\nll dist[1010];\n\nint main() {\n  int N, M;\n  cin >> N >> M;\n  vector<edge> edges(M);\n  for (auto &e : edges) {\n    cin >> e.u >> e.v >> e.cost;\n    e.u--, e.v--;\n    e.cost = -e.cost;\n  }\n\n  vector<ll> dist(N, INF);\n  dist[0] = 0;\n  for (int i = 0; i < 2 * N; i++) {\n    for (auto e : edges) {\n      if (dist[e.u] == INF) continue;\n      if (dist[e.u] + e.cost < dist[e.v]) {\n        dist[e.v] = dist[e.u] + e.cost;\n        if (i >= N - 1) dist[e.v] = -INF;\n      }\n    }\n  }\n  if (dist[N - 1] == -INF)\n    cout << \"inf\" << endl;\n  else\n    cout << -dist[N - 1] << endl;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nThere is a directed graph with N vertices and M edges.\nThe i-th edge (1≤i≤M) points from vertex a_i to vertex b_i, and has a weight c_i.\nWe will play the following single-player game using this graph and a piece.\n\nInitially, the piece is placed at vertex 1, and the score of the player is set to 0.\nThe player can move the piece as follows:\n\nWhen the piece is placed at vertex a_i, move the piece along the i-th edge to vertex b_i. After this move, the score of the player is increased by c_i.\n\nThe player can end the game only when the piece is placed at vertex N.\nThe given graph guarantees that it is possible to traverse from vertex 1 to vertex N.\n\nWhen the player acts optimally to maximize the score at the end of the game, what will the score be?\nIf it is possible to increase the score indefinitely, print inf.\n\nConstraints\n\n2≤N≤1000\n\n1≤M≤min(N(N-1),2000)\n\n1≤a_i,b_i≤N (1≤i≤M)\n\na_i≠b_i (1≤i≤M)\n\na_i≠a_j or b_i≠b_j (1≤i<j≤M)\n\n-10^9≤c_i≤10^9 (1≤i≤M)\n\nc_i is an integer.\n\nIn the given graph, there exists a path from vertex 1 to vertex N.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\na_1 b_1 c_1\na_2 b_2 c_2\n:\na_M b_M c_M\n\nOutput\n\nPrint the maximum possible score at the end of the game, if it is finite. If it is possible to increase the score indefinitely, print inf.\n\nSample Input 1\n\n3 3\n1 2 4\n2 3 3\n1 3 5\n\nSample Output 1\n\n7\n\nThere are two ways to move the piece to vertex N=3:\n\nvertex 1 → vertex 2 → vertex 3 : score 4+3=7\n\nvertex 1 → vertex 3 : score 5\n\nThus, the maximum possible score at the end of the game is 7.\n\nSample Input 2\n\n2 2\n1 2 1\n2 1 1\n\nSample Output 2\n\ninf\n\nIt is possible to increase the score indefinitely by alternating between vertex 1 and 2.\n\nSample Input 3\n\n6 5\n1 2 -1000000000\n2 3 -1000000000\n3 4 -1000000000\n4 5 -1000000000\n5 6 -1000000000\n\nSample Output 3\n\n-5000000000", "sample_input": "3 3\n1 2 4\n2 3 3\n1 3 5\n"}, "reference_outputs": ["7\n"], "source_document_id": "p03722", "source_text": "Score : 400 points\n\nProblem Statement\n\nThere is a directed graph with N vertices and M edges.\nThe i-th edge (1≤i≤M) points from vertex a_i to vertex b_i, and has a weight c_i.\nWe will play the following single-player game using this graph and a piece.\n\nInitially, the piece is placed at vertex 1, and the score of the player is set to 0.\nThe player can move the piece as follows:\n\nWhen the piece is placed at vertex a_i, move the piece along the i-th edge to vertex b_i. After this move, the score of the player is increased by c_i.\n\nThe player can end the game only when the piece is placed at vertex N.\nThe given graph guarantees that it is possible to traverse from vertex 1 to vertex N.\n\nWhen the player acts optimally to maximize the score at the end of the game, what will the score be?\nIf it is possible to increase the score indefinitely, print inf.\n\nConstraints\n\n2≤N≤1000\n\n1≤M≤min(N(N-1),2000)\n\n1≤a_i,b_i≤N (1≤i≤M)\n\na_i≠b_i (1≤i≤M)\n\na_i≠a_j or b_i≠b_j (1≤i<j≤M)\n\n-10^9≤c_i≤10^9 (1≤i≤M)\n\nc_i is an integer.\n\nIn the given graph, there exists a path from vertex 1 to vertex N.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\na_1 b_1 c_1\na_2 b_2 c_2\n:\na_M b_M c_M\n\nOutput\n\nPrint the maximum possible score at the end of the game, if it is finite. If it is possible to increase the score indefinitely, print inf.\n\nSample Input 1\n\n3 3\n1 2 4\n2 3 3\n1 3 5\n\nSample Output 1\n\n7\n\nThere are two ways to move the piece to vertex N=3:\n\nvertex 1 → vertex 2 → vertex 3 : score 4+3=7\n\nvertex 1 → vertex 3 : score 5\n\nThus, the maximum possible score at the end of the game is 7.\n\nSample Input 2\n\n2 2\n1 2 1\n2 1 1\n\nSample Output 2\n\ninf\n\nIt is possible to increase the score indefinitely by alternating between vertex 1 and 2.\n\nSample Input 3\n\n6 5\n1 2 -1000000000\n2 3 -1000000000\n3 4 -1000000000\n4 5 -1000000000\n5 6 -1000000000\n\nSample Output 3\n\n-5000000000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 745, "cpu_time_ms": 17, "memory_kb": 3656}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s073701525", "group_id": "codeNet:p03722", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n    int n,m;\n    cin >> n >> m;\n    vector<int>a(m);\n    vector<int>b(m);\n    vector<int>c(m);\n    for(int i=0;i<m;i++){\n        cin >> a[i] >> b[i] >> c[i];\n    }\n    vector<long>score(n+1,-999999999999);\n    bool chk = true;\n    int count = 0;\n    score[1] = 0;\n    while(chk){\n        chk = false;\n        count++;\n\n        for(int i=0;i<m;i++){\n            if(score[a[i]]+c[i] > score[b[i]]){\n                score[b[i]] = score[a[i]] + c[i];\n                chk = true;\n            }\n        }\n\n\n        if(count > 2*m)break;\n    }\n    if(!chk)cout<<score[n]<<endl;\n    else cout<<\"inf\"<<endl;\n}", "language": "C++", "metadata": {"date": 1589594681, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03722.html", "problem_id": "p03722", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03722/input.txt", "sample_output_relpath": "derived/input_output/data/p03722/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03722/C++/s073701525.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s073701525", "user_id": "u523698212"}, "prompt_components": {"gold_output": "7\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nint main(){\n    int n,m;\n    cin >> n >> m;\n    vector<int>a(m);\n    vector<int>b(m);\n    vector<int>c(m);\n    for(int i=0;i<m;i++){\n        cin >> a[i] >> b[i] >> c[i];\n    }\n    vector<long>score(n+1,-999999999999);\n    bool chk = true;\n    int count = 0;\n    score[1] = 0;\n    while(chk){\n        chk = false;\n        count++;\n\n        for(int i=0;i<m;i++){\n            if(score[a[i]]+c[i] > score[b[i]]){\n                score[b[i]] = score[a[i]] + c[i];\n                chk = true;\n            }\n        }\n\n\n        if(count > 2*m)break;\n    }\n    if(!chk)cout<<score[n]<<endl;\n    else cout<<\"inf\"<<endl;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nThere is a directed graph with N vertices and M edges.\nThe i-th edge (1≤i≤M) points from vertex a_i to vertex b_i, and has a weight c_i.\nWe will play the following single-player game using this graph and a piece.\n\nInitially, the piece is placed at vertex 1, and the score of the player is set to 0.\nThe player can move the piece as follows:\n\nWhen the piece is placed at vertex a_i, move the piece along the i-th edge to vertex b_i. After this move, the score of the player is increased by c_i.\n\nThe player can end the game only when the piece is placed at vertex N.\nThe given graph guarantees that it is possible to traverse from vertex 1 to vertex N.\n\nWhen the player acts optimally to maximize the score at the end of the game, what will the score be?\nIf it is possible to increase the score indefinitely, print inf.\n\nConstraints\n\n2≤N≤1000\n\n1≤M≤min(N(N-1),2000)\n\n1≤a_i,b_i≤N (1≤i≤M)\n\na_i≠b_i (1≤i≤M)\n\na_i≠a_j or b_i≠b_j (1≤i<j≤M)\n\n-10^9≤c_i≤10^9 (1≤i≤M)\n\nc_i is an integer.\n\nIn the given graph, there exists a path from vertex 1 to vertex N.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\na_1 b_1 c_1\na_2 b_2 c_2\n:\na_M b_M c_M\n\nOutput\n\nPrint the maximum possible score at the end of the game, if it is finite. If it is possible to increase the score indefinitely, print inf.\n\nSample Input 1\n\n3 3\n1 2 4\n2 3 3\n1 3 5\n\nSample Output 1\n\n7\n\nThere are two ways to move the piece to vertex N=3:\n\nvertex 1 → vertex 2 → vertex 3 : score 4+3=7\n\nvertex 1 → vertex 3 : score 5\n\nThus, the maximum possible score at the end of the game is 7.\n\nSample Input 2\n\n2 2\n1 2 1\n2 1 1\n\nSample Output 2\n\ninf\n\nIt is possible to increase the score indefinitely by alternating between vertex 1 and 2.\n\nSample Input 3\n\n6 5\n1 2 -1000000000\n2 3 -1000000000\n3 4 -1000000000\n4 5 -1000000000\n5 6 -1000000000\n\nSample Output 3\n\n-5000000000", "sample_input": "3 3\n1 2 4\n2 3 3\n1 3 5\n"}, "reference_outputs": ["7\n"], "source_document_id": "p03722", "source_text": "Score : 400 points\n\nProblem Statement\n\nThere is a directed graph with N vertices and M edges.\nThe i-th edge (1≤i≤M) points from vertex a_i to vertex b_i, and has a weight c_i.\nWe will play the following single-player game using this graph and a piece.\n\nInitially, the piece is placed at vertex 1, and the score of the player is set to 0.\nThe player can move the piece as follows:\n\nWhen the piece is placed at vertex a_i, move the piece along the i-th edge to vertex b_i. After this move, the score of the player is increased by c_i.\n\nThe player can end the game only when the piece is placed at vertex N.\nThe given graph guarantees that it is possible to traverse from vertex 1 to vertex N.\n\nWhen the player acts optimally to maximize the score at the end of the game, what will the score be?\nIf it is possible to increase the score indefinitely, print inf.\n\nConstraints\n\n2≤N≤1000\n\n1≤M≤min(N(N-1),2000)\n\n1≤a_i,b_i≤N (1≤i≤M)\n\na_i≠b_i (1≤i≤M)\n\na_i≠a_j or b_i≠b_j (1≤i<j≤M)\n\n-10^9≤c_i≤10^9 (1≤i≤M)\n\nc_i is an integer.\n\nIn the given graph, there exists a path from vertex 1 to vertex N.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\na_1 b_1 c_1\na_2 b_2 c_2\n:\na_M b_M c_M\n\nOutput\n\nPrint the maximum possible score at the end of the game, if it is finite. If it is possible to increase the score indefinitely, print inf.\n\nSample Input 1\n\n3 3\n1 2 4\n2 3 3\n1 3 5\n\nSample Output 1\n\n7\n\nThere are two ways to move the piece to vertex N=3:\n\nvertex 1 → vertex 2 → vertex 3 : score 4+3=7\n\nvertex 1 → vertex 3 : score 5\n\nThus, the maximum possible score at the end of the game is 7.\n\nSample Input 2\n\n2 2\n1 2 1\n2 1 1\n\nSample Output 2\n\ninf\n\nIt is possible to increase the score indefinitely by alternating between vertex 1 and 2.\n\nSample Input 3\n\n6 5\n1 2 -1000000000\n2 3 -1000000000\n3 4 -1000000000\n4 5 -1000000000\n5 6 -1000000000\n\nSample Output 3\n\n-5000000000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 657, "cpu_time_ms": 18, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s349813610", "group_id": "codeNet:p03722", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nstruct edge {int from, to, cost; };\n\nint main() {\n  int n, m;\n  cin>>n>>m;\n\n  edge es[m];\n  for (int i=0; i<m; i++) {\n    int a, b, c;\n    cin>>a>>b>>c;\n    --a;\n    --b;\n    edge e = {a, b, -c};\n    es[i] = e;\n  }\n  long long d[n];\n  for (int i=0; i<n; i++) d[i] = LLONG_MAX;\n\n  d[0] = 0;\n  for (int i=0; i<n; i++) {\n    for (auto e: es) {\n      if (d[e.from] != LLONG_MAX && d[e.to] > d[e.from] + e.cost) {\n        d[e.to] = d[e.from] + e.cost;\n        if (i == n - 1) {\n          cout<<\"inf\"<<endl;\n          return 0;\n        }\n      }\n    }\n  }\n  cout<<-d[n-1]<<endl;\n\n}", "language": "C++", "metadata": {"date": 1561692884, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03722.html", "problem_id": "p03722", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03722/input.txt", "sample_output_relpath": "derived/input_output/data/p03722/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03722/C++/s349813610.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s349813610", "user_id": "u313766957"}, "prompt_components": {"gold_output": "7\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nstruct edge {int from, to, cost; };\n\nint main() {\n  int n, m;\n  cin>>n>>m;\n\n  edge es[m];\n  for (int i=0; i<m; i++) {\n    int a, b, c;\n    cin>>a>>b>>c;\n    --a;\n    --b;\n    edge e = {a, b, -c};\n    es[i] = e;\n  }\n  long long d[n];\n  for (int i=0; i<n; i++) d[i] = LLONG_MAX;\n\n  d[0] = 0;\n  for (int i=0; i<n; i++) {\n    for (auto e: es) {\n      if (d[e.from] != LLONG_MAX && d[e.to] > d[e.from] + e.cost) {\n        d[e.to] = d[e.from] + e.cost;\n        if (i == n - 1) {\n          cout<<\"inf\"<<endl;\n          return 0;\n        }\n      }\n    }\n  }\n  cout<<-d[n-1]<<endl;\n\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nThere is a directed graph with N vertices and M edges.\nThe i-th edge (1≤i≤M) points from vertex a_i to vertex b_i, and has a weight c_i.\nWe will play the following single-player game using this graph and a piece.\n\nInitially, the piece is placed at vertex 1, and the score of the player is set to 0.\nThe player can move the piece as follows:\n\nWhen the piece is placed at vertex a_i, move the piece along the i-th edge to vertex b_i. After this move, the score of the player is increased by c_i.\n\nThe player can end the game only when the piece is placed at vertex N.\nThe given graph guarantees that it is possible to traverse from vertex 1 to vertex N.\n\nWhen the player acts optimally to maximize the score at the end of the game, what will the score be?\nIf it is possible to increase the score indefinitely, print inf.\n\nConstraints\n\n2≤N≤1000\n\n1≤M≤min(N(N-1),2000)\n\n1≤a_i,b_i≤N (1≤i≤M)\n\na_i≠b_i (1≤i≤M)\n\na_i≠a_j or b_i≠b_j (1≤i<j≤M)\n\n-10^9≤c_i≤10^9 (1≤i≤M)\n\nc_i is an integer.\n\nIn the given graph, there exists a path from vertex 1 to vertex N.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\na_1 b_1 c_1\na_2 b_2 c_2\n:\na_M b_M c_M\n\nOutput\n\nPrint the maximum possible score at the end of the game, if it is finite. If it is possible to increase the score indefinitely, print inf.\n\nSample Input 1\n\n3 3\n1 2 4\n2 3 3\n1 3 5\n\nSample Output 1\n\n7\n\nThere are two ways to move the piece to vertex N=3:\n\nvertex 1 → vertex 2 → vertex 3 : score 4+3=7\n\nvertex 1 → vertex 3 : score 5\n\nThus, the maximum possible score at the end of the game is 7.\n\nSample Input 2\n\n2 2\n1 2 1\n2 1 1\n\nSample Output 2\n\ninf\n\nIt is possible to increase the score indefinitely by alternating between vertex 1 and 2.\n\nSample Input 3\n\n6 5\n1 2 -1000000000\n2 3 -1000000000\n3 4 -1000000000\n4 5 -1000000000\n5 6 -1000000000\n\nSample Output 3\n\n-5000000000", "sample_input": "3 3\n1 2 4\n2 3 3\n1 3 5\n"}, "reference_outputs": ["7\n"], "source_document_id": "p03722", "source_text": "Score : 400 points\n\nProblem Statement\n\nThere is a directed graph with N vertices and M edges.\nThe i-th edge (1≤i≤M) points from vertex a_i to vertex b_i, and has a weight c_i.\nWe will play the following single-player game using this graph and a piece.\n\nInitially, the piece is placed at vertex 1, and the score of the player is set to 0.\nThe player can move the piece as follows:\n\nWhen the piece is placed at vertex a_i, move the piece along the i-th edge to vertex b_i. After this move, the score of the player is increased by c_i.\n\nThe player can end the game only when the piece is placed at vertex N.\nThe given graph guarantees that it is possible to traverse from vertex 1 to vertex N.\n\nWhen the player acts optimally to maximize the score at the end of the game, what will the score be?\nIf it is possible to increase the score indefinitely, print inf.\n\nConstraints\n\n2≤N≤1000\n\n1≤M≤min(N(N-1),2000)\n\n1≤a_i,b_i≤N (1≤i≤M)\n\na_i≠b_i (1≤i≤M)\n\na_i≠a_j or b_i≠b_j (1≤i<j≤M)\n\n-10^9≤c_i≤10^9 (1≤i≤M)\n\nc_i is an integer.\n\nIn the given graph, there exists a path from vertex 1 to vertex N.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\na_1 b_1 c_1\na_2 b_2 c_2\n:\na_M b_M c_M\n\nOutput\n\nPrint the maximum possible score at the end of the game, if it is finite. If it is possible to increase the score indefinitely, print inf.\n\nSample Input 1\n\n3 3\n1 2 4\n2 3 3\n1 3 5\n\nSample Output 1\n\n7\n\nThere are two ways to move the piece to vertex N=3:\n\nvertex 1 → vertex 2 → vertex 3 : score 4+3=7\n\nvertex 1 → vertex 3 : score 5\n\nThus, the maximum possible score at the end of the game is 7.\n\nSample Input 2\n\n2 2\n1 2 1\n2 1 1\n\nSample Output 2\n\ninf\n\nIt is possible to increase the score indefinitely by alternating between vertex 1 and 2.\n\nSample Input 3\n\n6 5\n1 2 -1000000000\n2 3 -1000000000\n3 4 -1000000000\n4 5 -1000000000\n5 6 -1000000000\n\nSample Output 3\n\n-5000000000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 621, "cpu_time_ms": 8, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s319967427", "group_id": "codeNet:p03722", "input_text": "#include<bits/stdc++.h>\n#include<iostream>\n#include<cmath>\n#include<vector>\n#include<string>\n#include<queue>\n#include<set>\n#include<map>\n#include<algorithm>\n#include<functional>\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef pair<int,int> pii;\ntypedef pair<ll, ll> pll;\ntypedef pair<ull, ull> pullull;\ntypedef pair<ll, int> plli;\ntypedef pair<int, pii> pipii;\ntypedef vector<vector<int> > mati;\ntypedef vector<vector<double> > matd;\ntypedef vector<ll> vll;\ntypedef vector<vector<ll>> vvll;\ntypedef vector<vector<vector<ll>>> vvvll;\ntypedef vector<bool> vb;\ntypedef vector<vector<bool>> vvb;\ntypedef vector<vector<vector<bool>>> vvvb;\n\n#define FOR(i,x,y) for(ll i=(ll)x; i<(ll)y; ++i)\n#define REP(i,y) FOR(i, 0, y)\n\ntemplate <typename T>\nvoid vec_print(vector<T> VEC){\n  REP(i, VEC.size()){\n    cout << VEC[i] << \" \";\n  }\n  cout << \"\\n\";\n};\n\ntemplate <typename T>\nvoid mat_print(vector<vector<T> > MAT){\n  REP(i, MAT.size()){\n    REP(j, MAT[i].size()){\n      cout << MAT[i][j] << \" \";\n    }\n    cout << \"\\n\";\n  }\n};\n\ntemplate <typename CLASS1, typename CLASS2>\nclass HOGE{\n  public:\n    CLASS1 key;\n    CLASS2 value;\n    HOGE(void){\n      return;\n    };\n    HOGE(CLASS1 key, CLASS2 value){\n      this->key = key;\n      this->value = value;\n    };\n    ~HOGE(void){\n      return;\n    };\n\n    void print(void){\n      cout << \"key : \" << key << \", value : \" << value << \"\\n\";\n      return;\n    };\n    \n    bool operator==(const HOGE &obj){\n      return (this->value == obj.value);\n    };\n    bool operator<(const HOGE &obj){\n      return (this->value < obj.value);\n    };\n    bool operator>(const HOGE &obj){\n      return (this->value > obj.value);\n    };\n};\n\nconstexpr int INF = (1<<30);\nconstexpr ll INFLL = 1LL<<62;\nconstexpr long double EPS = 1e-12;\nconstexpr ll MOD = (ll)((1E+9)+7);\n\nconstexpr ll MAX = 1LL<<55;\n\nvector<vector<pair<ll, ll>>> edge;\nvll dp;\nvb path_flag;\n\nvoid search(const ll pos, const ll tmp_cost){\n  if(tmp_cost < dp[pos]) return;\n  if(path_flag[pos]){\n    if(dp[pos] < tmp_cost){\n      dp[dp.size()-1] = MAX;\n    }\n    return;\n  }\n  path_flag[pos] = true;\n  dp[pos] = max(tmp_cost, dp[pos]);\n  for(auto tmp_pair : edge[pos]){\n    search(tmp_pair.first, tmp_cost+tmp_pair.second);\n  }\n  path_flag[pos] = false;\n  return;\n}\n\nint main(){\n  cin.tie(0); // cut the cin and cout (default, std::flush is performed after std::cin)\n  ios::sync_with_stdio(false); // cut the iostream and stdio (DON'T endl; BUT \"\\n\";)\n\n  ll N, M;\n  cin >> N >> M;\n  edge.resize(N);\n  REP(i, M){\n    ll a, b, c;\n    cin >> a >> b >> c;\n    a--;\n    b--;\n    pair<ll, ll> tmp(b, c);\n    edge[a].push_back(tmp);\n  }\n\n  dp.resize(N, -MAX);\n  path_flag.resize(N, false);\n\n  search(0, 0);\n\n  if(dp[N-1]==-MAX || dp[N-1]==MAX){\n    cout << \"inf\\n\";\n  }else{\n    cout << dp[N-1] << \"\\n\";\n  }\n\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1549417748, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03722.html", "problem_id": "p03722", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03722/input.txt", "sample_output_relpath": "derived/input_output/data/p03722/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03722/C++/s319967427.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s319967427", "user_id": "u355335354"}, "prompt_components": {"gold_output": "7\n", "input_to_evaluate": "#include<bits/stdc++.h>\n#include<iostream>\n#include<cmath>\n#include<vector>\n#include<string>\n#include<queue>\n#include<set>\n#include<map>\n#include<algorithm>\n#include<functional>\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef pair<int,int> pii;\ntypedef pair<ll, ll> pll;\ntypedef pair<ull, ull> pullull;\ntypedef pair<ll, int> plli;\ntypedef pair<int, pii> pipii;\ntypedef vector<vector<int> > mati;\ntypedef vector<vector<double> > matd;\ntypedef vector<ll> vll;\ntypedef vector<vector<ll>> vvll;\ntypedef vector<vector<vector<ll>>> vvvll;\ntypedef vector<bool> vb;\ntypedef vector<vector<bool>> vvb;\ntypedef vector<vector<vector<bool>>> vvvb;\n\n#define FOR(i,x,y) for(ll i=(ll)x; i<(ll)y; ++i)\n#define REP(i,y) FOR(i, 0, y)\n\ntemplate <typename T>\nvoid vec_print(vector<T> VEC){\n  REP(i, VEC.size()){\n    cout << VEC[i] << \" \";\n  }\n  cout << \"\\n\";\n};\n\ntemplate <typename T>\nvoid mat_print(vector<vector<T> > MAT){\n  REP(i, MAT.size()){\n    REP(j, MAT[i].size()){\n      cout << MAT[i][j] << \" \";\n    }\n    cout << \"\\n\";\n  }\n};\n\ntemplate <typename CLASS1, typename CLASS2>\nclass HOGE{\n  public:\n    CLASS1 key;\n    CLASS2 value;\n    HOGE(void){\n      return;\n    };\n    HOGE(CLASS1 key, CLASS2 value){\n      this->key = key;\n      this->value = value;\n    };\n    ~HOGE(void){\n      return;\n    };\n\n    void print(void){\n      cout << \"key : \" << key << \", value : \" << value << \"\\n\";\n      return;\n    };\n    \n    bool operator==(const HOGE &obj){\n      return (this->value == obj.value);\n    };\n    bool operator<(const HOGE &obj){\n      return (this->value < obj.value);\n    };\n    bool operator>(const HOGE &obj){\n      return (this->value > obj.value);\n    };\n};\n\nconstexpr int INF = (1<<30);\nconstexpr ll INFLL = 1LL<<62;\nconstexpr long double EPS = 1e-12;\nconstexpr ll MOD = (ll)((1E+9)+7);\n\nconstexpr ll MAX = 1LL<<55;\n\nvector<vector<pair<ll, ll>>> edge;\nvll dp;\nvb path_flag;\n\nvoid search(const ll pos, const ll tmp_cost){\n  if(tmp_cost < dp[pos]) return;\n  if(path_flag[pos]){\n    if(dp[pos] < tmp_cost){\n      dp[dp.size()-1] = MAX;\n    }\n    return;\n  }\n  path_flag[pos] = true;\n  dp[pos] = max(tmp_cost, dp[pos]);\n  for(auto tmp_pair : edge[pos]){\n    search(tmp_pair.first, tmp_cost+tmp_pair.second);\n  }\n  path_flag[pos] = false;\n  return;\n}\n\nint main(){\n  cin.tie(0); // cut the cin and cout (default, std::flush is performed after std::cin)\n  ios::sync_with_stdio(false); // cut the iostream and stdio (DON'T endl; BUT \"\\n\";)\n\n  ll N, M;\n  cin >> N >> M;\n  edge.resize(N);\n  REP(i, M){\n    ll a, b, c;\n    cin >> a >> b >> c;\n    a--;\n    b--;\n    pair<ll, ll> tmp(b, c);\n    edge[a].push_back(tmp);\n  }\n\n  dp.resize(N, -MAX);\n  path_flag.resize(N, false);\n\n  search(0, 0);\n\n  if(dp[N-1]==-MAX || dp[N-1]==MAX){\n    cout << \"inf\\n\";\n  }else{\n    cout << dp[N-1] << \"\\n\";\n  }\n\n  return 0;\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nThere is a directed graph with N vertices and M edges.\nThe i-th edge (1≤i≤M) points from vertex a_i to vertex b_i, and has a weight c_i.\nWe will play the following single-player game using this graph and a piece.\n\nInitially, the piece is placed at vertex 1, and the score of the player is set to 0.\nThe player can move the piece as follows:\n\nWhen the piece is placed at vertex a_i, move the piece along the i-th edge to vertex b_i. After this move, the score of the player is increased by c_i.\n\nThe player can end the game only when the piece is placed at vertex N.\nThe given graph guarantees that it is possible to traverse from vertex 1 to vertex N.\n\nWhen the player acts optimally to maximize the score at the end of the game, what will the score be?\nIf it is possible to increase the score indefinitely, print inf.\n\nConstraints\n\n2≤N≤1000\n\n1≤M≤min(N(N-1),2000)\n\n1≤a_i,b_i≤N (1≤i≤M)\n\na_i≠b_i (1≤i≤M)\n\na_i≠a_j or b_i≠b_j (1≤i<j≤M)\n\n-10^9≤c_i≤10^9 (1≤i≤M)\n\nc_i is an integer.\n\nIn the given graph, there exists a path from vertex 1 to vertex N.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\na_1 b_1 c_1\na_2 b_2 c_2\n:\na_M b_M c_M\n\nOutput\n\nPrint the maximum possible score at the end of the game, if it is finite. If it is possible to increase the score indefinitely, print inf.\n\nSample Input 1\n\n3 3\n1 2 4\n2 3 3\n1 3 5\n\nSample Output 1\n\n7\n\nThere are two ways to move the piece to vertex N=3:\n\nvertex 1 → vertex 2 → vertex 3 : score 4+3=7\n\nvertex 1 → vertex 3 : score 5\n\nThus, the maximum possible score at the end of the game is 7.\n\nSample Input 2\n\n2 2\n1 2 1\n2 1 1\n\nSample Output 2\n\ninf\n\nIt is possible to increase the score indefinitely by alternating between vertex 1 and 2.\n\nSample Input 3\n\n6 5\n1 2 -1000000000\n2 3 -1000000000\n3 4 -1000000000\n4 5 -1000000000\n5 6 -1000000000\n\nSample Output 3\n\n-5000000000", "sample_input": "3 3\n1 2 4\n2 3 3\n1 3 5\n"}, "reference_outputs": ["7\n"], "source_document_id": "p03722", "source_text": "Score : 400 points\n\nProblem Statement\n\nThere is a directed graph with N vertices and M edges.\nThe i-th edge (1≤i≤M) points from vertex a_i to vertex b_i, and has a weight c_i.\nWe will play the following single-player game using this graph and a piece.\n\nInitially, the piece is placed at vertex 1, and the score of the player is set to 0.\nThe player can move the piece as follows:\n\nWhen the piece is placed at vertex a_i, move the piece along the i-th edge to vertex b_i. After this move, the score of the player is increased by c_i.\n\nThe player can end the game only when the piece is placed at vertex N.\nThe given graph guarantees that it is possible to traverse from vertex 1 to vertex N.\n\nWhen the player acts optimally to maximize the score at the end of the game, what will the score be?\nIf it is possible to increase the score indefinitely, print inf.\n\nConstraints\n\n2≤N≤1000\n\n1≤M≤min(N(N-1),2000)\n\n1≤a_i,b_i≤N (1≤i≤M)\n\na_i≠b_i (1≤i≤M)\n\na_i≠a_j or b_i≠b_j (1≤i<j≤M)\n\n-10^9≤c_i≤10^9 (1≤i≤M)\n\nc_i is an integer.\n\nIn the given graph, there exists a path from vertex 1 to vertex N.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN M\na_1 b_1 c_1\na_2 b_2 c_2\n:\na_M b_M c_M\n\nOutput\n\nPrint the maximum possible score at the end of the game, if it is finite. If it is possible to increase the score indefinitely, print inf.\n\nSample Input 1\n\n3 3\n1 2 4\n2 3 3\n1 3 5\n\nSample Output 1\n\n7\n\nThere are two ways to move the piece to vertex N=3:\n\nvertex 1 → vertex 2 → vertex 3 : score 4+3=7\n\nvertex 1 → vertex 3 : score 5\n\nThus, the maximum possible score at the end of the game is 7.\n\nSample Input 2\n\n2 2\n1 2 1\n2 1 1\n\nSample Output 2\n\ninf\n\nIt is possible to increase the score indefinitely by alternating between vertex 1 and 2.\n\nSample Input 3\n\n6 5\n1 2 -1000000000\n2 3 -1000000000\n3 4 -1000000000\n4 5 -1000000000\n5 6 -1000000000\n\nSample Output 3\n\n-5000000000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2831, "cpu_time_ms": 2103, "memory_kb": 384}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s397826439", "group_id": "codeNet:p03725", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef pair<ll, ll> P;\ntypedef pair<P, ll> PPI;\n\n#define fi first\n#define se second\n#define repl(i,a,b) for(ll i=(ll)(a);i<(ll)(b);i++)\n#define rep(i,n) repl(i,0,n)\n#define each(itr,v) for(auto itr:v)\n#define pb push_back\n#define all(x) (x).begin(),(x).end()\n#define dbg(x) cout<<#x\"=\"<<x<<endl\n#define mmax(x,y) (x>y?x:y)\n#define mmin(x,y) (x<y?x:y)\n#define maxch(x,y) x=mmax(x,y)\n#define minch(x,y) x=mmin(x,y)\n#define uni(x) x.erase(unique(all(x)),x.end())\n#define exist(x,y) (find(all(x),y)!=x.end())\n#define bcnt __builtin_popcount\n\n#define INF INT_MAX/3\n\nint h,w,k;\nchar a[810][810];\nint dd[]={1,0,-1,0,1};\nint si,sj;\nint dist[810][810],dist2[810][810];\n\nbool valid(int i,int j){\n  return i>=0&&i<h&&j>=0&&j<w;\n}\n\nint manh(int i,int j){\n  return abs(i-si)+abs(j-sj);\n}\n\nint main(){\n\tcin.sync_with_stdio(false);\n  cin>>h>>w>>k;\n  rep(i,h){\n    cin>>a[i];\n    rep(j,w)if(a[i][j]=='S'){\n      si=i; sj=j;\n      a[i][j]='.';\n    }\n  }\n  rep(i,h)rep(j,w)dist[i][j]=INF;\n  queue<PPI> que;\n  que.push(PPI(P(si,sj),0));\n  while(que.size()){\n    PPI np=que.front(); que.pop();\n    int ni=np.fi.fi, nj=np.fi.se;\n    if(dist[ni][nj]!=INF)continue;\n    dist[ni][nj]=np.se;\n    rep(d,4){\n      int pi=ni+dd[d],pj=nj+dd[d+1];\n      if(valid(pi,pj)&&a[pi][pj]!='#')que.push(PPI(P(pi,pj),np.se+1));\n    }\n  }\n  int mind=INF;\n  rep(i,h){\n    minch(mind,min(dist[i][0],manh(i,0)+k));\n    minch(mind,min(dist[i][w-1],manh(i,w-1)+k));\n  }\n  rep(i,w){\n    minch(mind,min(dist[0][i],manh(0,i)));\n    minch(mind,min(dist[h-1][i],manh(h-1,i)));\n  }\n  //dbg(mind);\n  cout<<ceil((double)mind/k)<<endl;\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1494126361, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03725.html", "problem_id": "p03725", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03725/input.txt", "sample_output_relpath": "derived/input_output/data/p03725/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03725/C++/s397826439.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s397826439", "user_id": "u762921614"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\ntypedef long long ll;\ntypedef unsigned long long ull;\ntypedef pair<ll, ll> P;\ntypedef pair<P, ll> PPI;\n\n#define fi first\n#define se second\n#define repl(i,a,b) for(ll i=(ll)(a);i<(ll)(b);i++)\n#define rep(i,n) repl(i,0,n)\n#define each(itr,v) for(auto itr:v)\n#define pb push_back\n#define all(x) (x).begin(),(x).end()\n#define dbg(x) cout<<#x\"=\"<<x<<endl\n#define mmax(x,y) (x>y?x:y)\n#define mmin(x,y) (x<y?x:y)\n#define maxch(x,y) x=mmax(x,y)\n#define minch(x,y) x=mmin(x,y)\n#define uni(x) x.erase(unique(all(x)),x.end())\n#define exist(x,y) (find(all(x),y)!=x.end())\n#define bcnt __builtin_popcount\n\n#define INF INT_MAX/3\n\nint h,w,k;\nchar a[810][810];\nint dd[]={1,0,-1,0,1};\nint si,sj;\nint dist[810][810],dist2[810][810];\n\nbool valid(int i,int j){\n  return i>=0&&i<h&&j>=0&&j<w;\n}\n\nint manh(int i,int j){\n  return abs(i-si)+abs(j-sj);\n}\n\nint main(){\n\tcin.sync_with_stdio(false);\n  cin>>h>>w>>k;\n  rep(i,h){\n    cin>>a[i];\n    rep(j,w)if(a[i][j]=='S'){\n      si=i; sj=j;\n      a[i][j]='.';\n    }\n  }\n  rep(i,h)rep(j,w)dist[i][j]=INF;\n  queue<PPI> que;\n  que.push(PPI(P(si,sj),0));\n  while(que.size()){\n    PPI np=que.front(); que.pop();\n    int ni=np.fi.fi, nj=np.fi.se;\n    if(dist[ni][nj]!=INF)continue;\n    dist[ni][nj]=np.se;\n    rep(d,4){\n      int pi=ni+dd[d],pj=nj+dd[d+1];\n      if(valid(pi,pj)&&a[pi][pj]!='#')que.push(PPI(P(pi,pj),np.se+1));\n    }\n  }\n  int mind=INF;\n  rep(i,h){\n    minch(mind,min(dist[i][0],manh(i,0)+k));\n    minch(mind,min(dist[i][w-1],manh(i,w-1)+k));\n  }\n  rep(i,w){\n    minch(mind,min(dist[0][i],manh(0,i)));\n    minch(mind,min(dist[h-1][i],manh(h-1,i)));\n  }\n  //dbg(mind);\n  cout<<ceil((double)mind/k)<<endl;\n\treturn 0;\n}\n", "problem_context": "Score : 700 points\n\nProblem Statement\n\nTakahashi is locked within a building.\n\nThis building consists of H×W rooms, arranged in H rows and W columns.\nWe will denote the room at the i-th row and j-th column as (i,j). The state of this room is represented by a character A_{i,j}. If A_{i,j}= #, the room is locked and cannot be entered; if A_{i,j}= ., the room is not locked and can be freely entered.\nTakahashi is currently at the room where A_{i,j}= S, which can also be freely entered.\n\nEach room in the 1-st row, 1-st column, H-th row or W-th column, has an exit.\nEach of the other rooms (i,j) is connected to four rooms: (i-1,j), (i+1,j), (i,j-1) and (i,j+1).\n\nTakahashi will use his magic to get out of the building. In one cast, he can do the following:\n\nMove to an adjacent room at most K times, possibly zero. Here, locked rooms cannot be entered.\n\nThen, select and unlock at most K locked rooms, possibly zero. Those rooms will remain unlocked from then on.\n\nHis objective is to reach a room with an exit. Find the minimum necessary number of casts to do so.\n\nIt is guaranteed that Takahashi is initially at a room without an exit.\n\nConstraints\n\n3 ≤ H ≤ 800\n\n3 ≤ W ≤ 800\n\n1 ≤ K ≤ H×W\n\nEach A_{i,j} is # , . or S.\n\nThere uniquely exists (i,j) such that A_{i,j}= S, and it satisfies 2 ≤ i ≤ H-1 and 2 ≤ j ≤ W-1.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W K\nA_{1,1}A_{1,2}...A_{1,W}\n:\nA_{H,1}A_{H,2}...A_{H,W}\n\nOutput\n\nPrint the minimum necessary number of casts.\n\nSample Input 1\n\n3 3 3\n#.#\n#S.\n###\n\nSample Output 1\n\n1\n\nTakahashi can move to room (1,2) in one cast.\n\nSample Input 2\n\n3 3 3\n###\n#S#\n###\n\nSample Output 2\n\n2\n\nTakahashi cannot move in the first cast, but can unlock room (1,2).\nThen, he can move to room (1,2) in the next cast, achieving the objective in two casts.\n\nSample Input 3\n\n7 7 2\n#######\n#######\n##...##\n###S###\n##.#.##\n###.###\n#######\n\nSample Output 3\n\n2", "sample_input": "3 3 3\n#.#\n#S.\n###\n"}, "reference_outputs": ["1\n"], "source_document_id": "p03725", "source_text": "Score : 700 points\n\nProblem Statement\n\nTakahashi is locked within a building.\n\nThis building consists of H×W rooms, arranged in H rows and W columns.\nWe will denote the room at the i-th row and j-th column as (i,j). The state of this room is represented by a character A_{i,j}. If A_{i,j}= #, the room is locked and cannot be entered; if A_{i,j}= ., the room is not locked and can be freely entered.\nTakahashi is currently at the room where A_{i,j}= S, which can also be freely entered.\n\nEach room in the 1-st row, 1-st column, H-th row or W-th column, has an exit.\nEach of the other rooms (i,j) is connected to four rooms: (i-1,j), (i+1,j), (i,j-1) and (i,j+1).\n\nTakahashi will use his magic to get out of the building. In one cast, he can do the following:\n\nMove to an adjacent room at most K times, possibly zero. Here, locked rooms cannot be entered.\n\nThen, select and unlock at most K locked rooms, possibly zero. Those rooms will remain unlocked from then on.\n\nHis objective is to reach a room with an exit. Find the minimum necessary number of casts to do so.\n\nIt is guaranteed that Takahashi is initially at a room without an exit.\n\nConstraints\n\n3 ≤ H ≤ 800\n\n3 ≤ W ≤ 800\n\n1 ≤ K ≤ H×W\n\nEach A_{i,j} is # , . or S.\n\nThere uniquely exists (i,j) such that A_{i,j}= S, and it satisfies 2 ≤ i ≤ H-1 and 2 ≤ j ≤ W-1.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nH W K\nA_{1,1}A_{1,2}...A_{1,W}\n:\nA_{H,1}A_{H,2}...A_{H,W}\n\nOutput\n\nPrint the minimum necessary number of casts.\n\nSample Input 1\n\n3 3 3\n#.#\n#S.\n###\n\nSample Output 1\n\n1\n\nTakahashi can move to room (1,2) in one cast.\n\nSample Input 2\n\n3 3 3\n###\n#S#\n###\n\nSample Output 2\n\n2\n\nTakahashi cannot move in the first cast, but can unlock room (1,2).\nThen, he can move to room (1,2) in the next cast, achieving the objective in two casts.\n\nSample Input 3\n\n7 7 2\n#######\n#######\n##...##\n###S###\n##.#.##\n###.###\n#######\n\nSample Output 3\n\n2", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1697, "cpu_time_ms": 34, "memory_kb": 4096}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s358600950", "group_id": "codeNet:p03729", "input_text": "#include <iostream>\n#include <string>\n\nusing namespace std;\n\nint main() {\n  ios::sync_with_stdio(false);\n  cin.tie(0);\n\n  string a, b, c;\n  cin >> a >> b >> c;\n  if (a.back() == b[0] && b.back() == c[0])\n    cout << \"YES\" << endl;\n  else\n    cout << \"NO\" << endl;\n\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1532356167, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03729.html", "problem_id": "p03729", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03729/input.txt", "sample_output_relpath": "derived/input_output/data/p03729/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03729/C++/s358600950.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s358600950", "user_id": "u150861392"}, "prompt_components": {"gold_output": "YES\n", "input_to_evaluate": "#include <iostream>\n#include <string>\n\nusing namespace std;\n\nint main() {\n  ios::sync_with_stdio(false);\n  cin.tie(0);\n\n  string a, b, c;\n  cin >> a >> b >> c;\n  if (a.back() == b[0] && b.back() == c[0])\n    cout << \"YES\" << endl;\n  else\n    cout << \"NO\" << endl;\n\n  return 0;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nYou are given three strings A, B and C. Check whether they form a word chain.\n\nMore formally, determine whether both of the following are true:\n\nThe last character in A and the initial character in B are the same.\n\nThe last character in B and the initial character in C are the same.\n\nIf both are true, print YES. Otherwise, print NO.\n\nConstraints\n\nA, B and C are all composed of lowercase English letters (a - z).\n\n1 ≤ |A|, |B|, |C| ≤ 10, where |A|, |B| and |C| are the lengths of A, B and C, respectively.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B C\n\nOutput\n\nPrint YES or NO.\n\nSample Input 1\n\nrng gorilla apple\n\nSample Output 1\n\nYES\n\nThey form a word chain.\n\nSample Input 2\n\nyakiniku unagi sushi\n\nSample Output 2\n\nNO\n\nA and B form a word chain, but B and C do not.\n\nSample Input 3\n\na a a\n\nSample Output 3\n\nYES\n\nSample Input 4\n\naaaaaaaaab aaaaaaaaaa aaaaaaaaab\n\nSample Output 4\n\nNO", "sample_input": "rng gorilla apple\n"}, "reference_outputs": ["YES\n"], "source_document_id": "p03729", "source_text": "Score : 100 points\n\nProblem Statement\n\nYou are given three strings A, B and C. Check whether they form a word chain.\n\nMore formally, determine whether both of the following are true:\n\nThe last character in A and the initial character in B are the same.\n\nThe last character in B and the initial character in C are the same.\n\nIf both are true, print YES. Otherwise, print NO.\n\nConstraints\n\nA, B and C are all composed of lowercase English letters (a - z).\n\n1 ≤ |A|, |B|, |C| ≤ 10, where |A|, |B| and |C| are the lengths of A, B and C, respectively.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B C\n\nOutput\n\nPrint YES or NO.\n\nSample Input 1\n\nrng gorilla apple\n\nSample Output 1\n\nYES\n\nThey form a word chain.\n\nSample Input 2\n\nyakiniku unagi sushi\n\nSample Output 2\n\nNO\n\nA and B form a word chain, but B and C do not.\n\nSample Input 3\n\na a a\n\nSample Output 3\n\nYES\n\nSample Input 4\n\naaaaaaaaab aaaaaaaaaa aaaaaaaaab\n\nSample Output 4\n\nNO", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 279, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s340641123", "group_id": "codeNet:p03730", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint64_t gcd(int64_t a, int64_t m);\nint main(void) {\n    int64_t A, B, C;\n    int64_t d;\n\n    cin >> A >> B >> C;\n    \n    // Ax mod B = C\n    d = gcd(A,B);\n    if( d == 1) {\n        cout << \"YES\\n\";\n    } else {\n        if(C % d) {\n            cout << \"NO\\n\";\n        } else {\n            cout << \"YES\\n\";\n        }\n    }\n\n    return 0;\n}\nint64_t gcd(int64_t a, int64_t m) {\n    int64_t tmp;\n    int64_t r;\n\n    if(a < m) {\n        tmp = a;\n        a = m;\n        m = tmp;\n    }\n\n    r = a % m;\n    while(r!=0) {\n        a = m;\n        m = r;\n        r = a % m;\n    }\n\n    return m;\n}\n", "language": "C++", "metadata": {"date": 1588649865, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03730.html", "problem_id": "p03730", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03730/input.txt", "sample_output_relpath": "derived/input_output/data/p03730/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03730/C++/s340641123.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s340641123", "user_id": "u346040900"}, "prompt_components": {"gold_output": "YES\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint64_t gcd(int64_t a, int64_t m);\nint main(void) {\n    int64_t A, B, C;\n    int64_t d;\n\n    cin >> A >> B >> C;\n    \n    // Ax mod B = C\n    d = gcd(A,B);\n    if( d == 1) {\n        cout << \"YES\\n\";\n    } else {\n        if(C % d) {\n            cout << \"NO\\n\";\n        } else {\n            cout << \"YES\\n\";\n        }\n    }\n\n    return 0;\n}\nint64_t gcd(int64_t a, int64_t m) {\n    int64_t tmp;\n    int64_t r;\n\n    if(a < m) {\n        tmp = a;\n        a = m;\n        m = tmp;\n    }\n\n    r = a % m;\n    while(r!=0) {\n        a = m;\n        m = r;\n        r = a % m;\n    }\n\n    return m;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nWe ask you to select some number of positive integers, and calculate the sum of them.\n\nIt is allowed to select as many integers as you like, and as large integers as you wish.\nYou have to follow these, however: each selected integer needs to be a multiple of A, and you need to select at least one integer.\n\nYour objective is to make the sum congruent to C modulo B.\nDetermine whether this is possible.\n\nIf the objective is achievable, print YES. Otherwise, print NO.\n\nConstraints\n\n1 ≤ A ≤ 100\n\n1 ≤ B ≤ 100\n\n0 ≤ C < B\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B C\n\nOutput\n\nPrint YES or NO.\n\nSample Input 1\n\n7 5 1\n\nSample Output 1\n\nYES\n\nFor example, if you select 7 and 14, the sum 21 is congruent to 1 modulo 5.\n\nSample Input 2\n\n2 2 1\n\nSample Output 2\n\nNO\n\nThe sum of even numbers, no matter how many, is never odd.\n\nSample Input 3\n\n1 100 97\n\nSample Output 3\n\nYES\n\nYou can select 97, since you may select multiples of 1, that is, all integers.\n\nSample Input 4\n\n40 98 58\n\nSample Output 4\n\nYES\n\nSample Input 5\n\n77 42 36\n\nSample Output 5\n\nNO", "sample_input": "7 5 1\n"}, "reference_outputs": ["YES\n"], "source_document_id": "p03730", "source_text": "Score : 200 points\n\nProblem Statement\n\nWe ask you to select some number of positive integers, and calculate the sum of them.\n\nIt is allowed to select as many integers as you like, and as large integers as you wish.\nYou have to follow these, however: each selected integer needs to be a multiple of A, and you need to select at least one integer.\n\nYour objective is to make the sum congruent to C modulo B.\nDetermine whether this is possible.\n\nIf the objective is achievable, print YES. Otherwise, print NO.\n\nConstraints\n\n1 ≤ A ≤ 100\n\n1 ≤ B ≤ 100\n\n0 ≤ C < B\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B C\n\nOutput\n\nPrint YES or NO.\n\nSample Input 1\n\n7 5 1\n\nSample Output 1\n\nYES\n\nFor example, if you select 7 and 14, the sum 21 is congruent to 1 modulo 5.\n\nSample Input 2\n\n2 2 1\n\nSample Output 2\n\nNO\n\nThe sum of even numbers, no matter how many, is never odd.\n\nSample Input 3\n\n1 100 97\n\nSample Output 3\n\nYES\n\nYou can select 97, since you may select multiples of 1, that is, all integers.\n\nSample Input 4\n\n40 98 58\n\nSample Output 4\n\nYES\n\nSample Input 5\n\n77 42 36\n\nSample Output 5\n\nNO", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 632, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s804061391", "group_id": "codeNet:p03730", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n\tint A,B,C;\n  \tcin >> A >> B >> C;\n  \tbool ans = false;\n  \tfor(int i =1;i <B;i++){\n    \tif(i*A%B == C)ans = true;\n    }\n  \tif(ans)cout << \"YES\" << endl;\n  \telse cout << \"NO\" <<endl;\n}", "language": "C++", "metadata": {"date": 1585512325, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03730.html", "problem_id": "p03730", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03730/input.txt", "sample_output_relpath": "derived/input_output/data/p03730/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03730/C++/s804061391.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s804061391", "user_id": "u816145694"}, "prompt_components": {"gold_output": "YES\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n\tint A,B,C;\n  \tcin >> A >> B >> C;\n  \tbool ans = false;\n  \tfor(int i =1;i <B;i++){\n    \tif(i*A%B == C)ans = true;\n    }\n  \tif(ans)cout << \"YES\" << endl;\n  \telse cout << \"NO\" <<endl;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nWe ask you to select some number of positive integers, and calculate the sum of them.\n\nIt is allowed to select as many integers as you like, and as large integers as you wish.\nYou have to follow these, however: each selected integer needs to be a multiple of A, and you need to select at least one integer.\n\nYour objective is to make the sum congruent to C modulo B.\nDetermine whether this is possible.\n\nIf the objective is achievable, print YES. Otherwise, print NO.\n\nConstraints\n\n1 ≤ A ≤ 100\n\n1 ≤ B ≤ 100\n\n0 ≤ C < B\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B C\n\nOutput\n\nPrint YES or NO.\n\nSample Input 1\n\n7 5 1\n\nSample Output 1\n\nYES\n\nFor example, if you select 7 and 14, the sum 21 is congruent to 1 modulo 5.\n\nSample Input 2\n\n2 2 1\n\nSample Output 2\n\nNO\n\nThe sum of even numbers, no matter how many, is never odd.\n\nSample Input 3\n\n1 100 97\n\nSample Output 3\n\nYES\n\nYou can select 97, since you may select multiples of 1, that is, all integers.\n\nSample Input 4\n\n40 98 58\n\nSample Output 4\n\nYES\n\nSample Input 5\n\n77 42 36\n\nSample Output 5\n\nNO", "sample_input": "7 5 1\n"}, "reference_outputs": ["YES\n"], "source_document_id": "p03730", "source_text": "Score : 200 points\n\nProblem Statement\n\nWe ask you to select some number of positive integers, and calculate the sum of them.\n\nIt is allowed to select as many integers as you like, and as large integers as you wish.\nYou have to follow these, however: each selected integer needs to be a multiple of A, and you need to select at least one integer.\n\nYour objective is to make the sum congruent to C modulo B.\nDetermine whether this is possible.\n\nIf the objective is achievable, print YES. Otherwise, print NO.\n\nConstraints\n\n1 ≤ A ≤ 100\n\n1 ≤ B ≤ 100\n\n0 ≤ C < B\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA B C\n\nOutput\n\nPrint YES or NO.\n\nSample Input 1\n\n7 5 1\n\nSample Output 1\n\nYES\n\nFor example, if you select 7 and 14, the sum 21 is congruent to 1 modulo 5.\n\nSample Input 2\n\n2 2 1\n\nSample Output 2\n\nNO\n\nThe sum of even numbers, no matter how many, is never odd.\n\nSample Input 3\n\n1 100 97\n\nSample Output 3\n\nYES\n\nYou can select 97, since you may select multiples of 1, that is, all integers.\n\nSample Input 4\n\n40 98 58\n\nSample Output 4\n\nYES\n\nSample Input 5\n\n77 42 36\n\nSample Output 5\n\nNO", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 241, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s433279558", "group_id": "codeNet:p03733", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nconst int max_n=200005;\nint n,T,t[max_n];\nint main(){\n    scanf(\"%d%d\",&n,&T);\n    for(int i=1;i<=n;i++)scanf(\"%d\",t+i);\n    int ans=t[n]+T;\n    for(int i=2;i<=n;i++){\n        ans-=max(0,t[i]-(t[i-1]+T));\n    }\n    printf(\"%d\\n\",ans);\n    return 0;\n}", "language": "C++", "metadata": {"date": 1584825976, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03733.html", "problem_id": "p03733", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03733/input.txt", "sample_output_relpath": "derived/input_output/data/p03733/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03733/C++/s433279558.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s433279558", "user_id": "u019233781"}, "prompt_components": {"gold_output": "7\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nconst int max_n=200005;\nint n,T,t[max_n];\nint main(){\n    scanf(\"%d%d\",&n,&T);\n    for(int i=1;i<=n;i++)scanf(\"%d\",t+i);\n    int ans=t[n]+T;\n    for(int i=2;i<=n;i++){\n        ans-=max(0,t[i]-(t[i-1]+T));\n    }\n    printf(\"%d\\n\",ans);\n    return 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nIn a public bath, there is a shower which emits water for T seconds when the switch is pushed.\n\nIf the switch is pushed when the shower is already emitting water, from that moment it will be emitting water for T seconds.\nNote that it does not mean that the shower emits water for T additional seconds.\n\nN people will push the switch while passing by the shower.\nThe i-th person will push the switch t_i seconds after the first person pushes it.\n\nHow long will the shower emit water in total?\n\nConstraints\n\n1 ≤ N ≤ 200,000\n\n1 ≤ T ≤ 10^9\n\n0 = t_1 < t_2 < t_3 < , ..., < t_{N-1} < t_N ≤ 10^9\n\nT and each t_i are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN T\nt_1 t_2 ... t_N\n\nOutput\n\nAssume that the shower will emit water for a total of X seconds. Print X.\n\nSample Input 1\n\n2 4\n0 3\n\nSample Output 1\n\n7\n\nThree seconds after the first person pushes the water, the switch is pushed again and the shower emits water for four more seconds, for a total of seven seconds.\n\nSample Input 2\n\n2 4\n0 5\n\nSample Output 2\n\n8\n\nOne second after the shower stops emission of water triggered by the first person, the switch is pushed again.\n\nSample Input 3\n\n4 1000000000\n0 1000 1000000 1000000000\n\nSample Output 3\n\n2000000000\n\nSample Input 4\n\n1 1\n0\n\nSample Output 4\n\n1\n\nSample Input 5\n\n9 10\n0 3 5 7 100 110 200 300 311\n\nSample Output 5\n\n67", "sample_input": "2 4\n0 3\n"}, "reference_outputs": ["7\n"], "source_document_id": "p03733", "source_text": "Score : 300 points\n\nProblem Statement\n\nIn a public bath, there is a shower which emits water for T seconds when the switch is pushed.\n\nIf the switch is pushed when the shower is already emitting water, from that moment it will be emitting water for T seconds.\nNote that it does not mean that the shower emits water for T additional seconds.\n\nN people will push the switch while passing by the shower.\nThe i-th person will push the switch t_i seconds after the first person pushes it.\n\nHow long will the shower emit water in total?\n\nConstraints\n\n1 ≤ N ≤ 200,000\n\n1 ≤ T ≤ 10^9\n\n0 = t_1 < t_2 < t_3 < , ..., < t_{N-1} < t_N ≤ 10^9\n\nT and each t_i are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN T\nt_1 t_2 ... t_N\n\nOutput\n\nAssume that the shower will emit water for a total of X seconds. Print X.\n\nSample Input 1\n\n2 4\n0 3\n\nSample Output 1\n\n7\n\nThree seconds after the first person pushes the water, the switch is pushed again and the shower emits water for four more seconds, for a total of seven seconds.\n\nSample Input 2\n\n2 4\n0 5\n\nSample Output 2\n\n8\n\nOne second after the shower stops emission of water triggered by the first person, the switch is pushed again.\n\nSample Input 3\n\n4 1000000000\n0 1000 1000000 1000000000\n\nSample Output 3\n\n2000000000\n\nSample Input 4\n\n1 1\n0\n\nSample Output 4\n\n1\n\nSample Input 5\n\n9 10\n0 3 5 7 100 110 200 300 311\n\nSample Output 5\n\n67", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 317, "cpu_time_ms": 24, "memory_kb": 1024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s114145310", "group_id": "codeNet:p03738", "input_text": "#define _CRT_SECURE_NO_WARNINGS\n#include<bits/stdc++.h>\nusing namespace std;\n#ifndef FAST_IO\n #define IOS ios_base::sync_with_stdio(false);cin.tie(nullptr);\n#endif\n\n#define int long long\n#define FILE_IO freopen(\"input.txt\",\"r\",stdin)/#define int long long\n#define f first\n#define s second\n#define endl '\\n'\n#define all(c) c.begin(),c.end()\n#define bp __builtin_popcount\n#define debug(x) cerr << #x << \" = \" << x << endl;\n\nconst int MOD = 1e9 + 7;\nconst int INF = 1000000000;\n\nmt19937 rng(chrono::steady_clock::now().time_since_epoch().count());\ntemplate <typename T>void print(T t){for(auto &it : t)cout<<it<<\" \";}\ninline int powerexp(int a, int b, int m = MOD){ int res = 1;while(b){if(b&1)res = res * a % m;a = a * a % m,b >>= 1;}return res % m;}\ninline int modinv(int a){ return powerexp(a,MOD-2,MOD);}\ninline int lcm(int a, int b){ int g = __gcd(a,b);return a/g*b;}\ninline int add(int x, int y){ x += y; if (x >= MOD) x -=  MOD; return x;}\ninline int mul(int x, int y){ return (x * 1ll * y) % MOD;}\ninline int sub(int x, int y){ x -= y; if (x<0) x += MOD; return x ;}\n\n//-------------------< start here >-------------------------// \n\nvoid solve(){\n    string a, b;\n    cin >> a >> b;\n    if (a == b) cout << \"EQUAL\" << endl;\n    else if (a < b) cout << \"LESS\" << endl;\n    else cout << \"GREATER\" << endl;\n}\n\n//-----------------------------\n//comment from here for TOPCODER \nint32_t main(){\n   IOS;\n   solve();\n   //find();\n   #ifdef LOCAL_DEFINE\n   cerr << \"time elapsed \" << (double)clock()/CLOCKS_PER_SEC << endl;\n   #endif\n}\n", "language": "C++", "metadata": {"date": 1564896296, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03738.html", "problem_id": "p03738", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03738/input.txt", "sample_output_relpath": "derived/input_output/data/p03738/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03738/C++/s114145310.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s114145310", "user_id": "u572138437"}, "prompt_components": {"gold_output": "GREATER\n", "input_to_evaluate": "#define _CRT_SECURE_NO_WARNINGS\n#include<bits/stdc++.h>\nusing namespace std;\n#ifndef FAST_IO\n #define IOS ios_base::sync_with_stdio(false);cin.tie(nullptr);\n#endif\n\n#define int long long\n#define FILE_IO freopen(\"input.txt\",\"r\",stdin)/#define int long long\n#define f first\n#define s second\n#define endl '\\n'\n#define all(c) c.begin(),c.end()\n#define bp __builtin_popcount\n#define debug(x) cerr << #x << \" = \" << x << endl;\n\nconst int MOD = 1e9 + 7;\nconst int INF = 1000000000;\n\nmt19937 rng(chrono::steady_clock::now().time_since_epoch().count());\ntemplate <typename T>void print(T t){for(auto &it : t)cout<<it<<\" \";}\ninline int powerexp(int a, int b, int m = MOD){ int res = 1;while(b){if(b&1)res = res * a % m;a = a * a % m,b >>= 1;}return res % m;}\ninline int modinv(int a){ return powerexp(a,MOD-2,MOD);}\ninline int lcm(int a, int b){ int g = __gcd(a,b);return a/g*b;}\ninline int add(int x, int y){ x += y; if (x >= MOD) x -=  MOD; return x;}\ninline int mul(int x, int y){ return (x * 1ll * y) % MOD;}\ninline int sub(int x, int y){ x -= y; if (x<0) x += MOD; return x ;}\n\n//-------------------< start here >-------------------------// \n\nvoid solve(){\n    string a, b;\n    cin >> a >> b;\n    if (a == b) cout << \"EQUAL\" << endl;\n    else if (a < b) cout << \"LESS\" << endl;\n    else cout << \"GREATER\" << endl;\n}\n\n//-----------------------------\n//comment from here for TOPCODER \nint32_t main(){\n   IOS;\n   solve();\n   //find();\n   #ifdef LOCAL_DEFINE\n   cerr << \"time elapsed \" << (double)clock()/CLOCKS_PER_SEC << endl;\n   #endif\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nYou are given two positive integers A and B. Compare the magnitudes of these numbers.\n\nConstraints\n\n1 ≤ A, B ≤ 10^{100}\n\nNeither A nor B begins with a 0.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA\nB\n\nOutput\n\nPrint GREATER if A>B, LESS if A<B and EQUAL if A=B.\n\nSample Input 1\n\n36\n24\n\nSample Output 1\n\nGREATER\n\nSince 36>24, print GREATER.\n\nSample Input 2\n\n850\n3777\n\nSample Output 2\n\nLESS\n\nSample Input 3\n\n9720246\n22516266\n\nSample Output 3\n\nLESS\n\nSample Input 4\n\n123456789012345678901234567890\n234567890123456789012345678901\n\nSample Output 4\n\nLESS", "sample_input": "36\n24\n"}, "reference_outputs": ["GREATER\n"], "source_document_id": "p03738", "source_text": "Score : 200 points\n\nProblem Statement\n\nYou are given two positive integers A and B. Compare the magnitudes of these numbers.\n\nConstraints\n\n1 ≤ A, B ≤ 10^{100}\n\nNeither A nor B begins with a 0.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nA\nB\n\nOutput\n\nPrint GREATER if A>B, LESS if A<B and EQUAL if A=B.\n\nSample Input 1\n\n36\n24\n\nSample Output 1\n\nGREATER\n\nSince 36>24, print GREATER.\n\nSample Input 2\n\n850\n3777\n\nSample Output 2\n\nLESS\n\nSample Input 3\n\n9720246\n22516266\n\nSample Output 3\n\nLESS\n\nSample Input 4\n\n123456789012345678901234567890\n234567890123456789012345678901\n\nSample Output 4\n\nLESS", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1532, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s751438648", "group_id": "codeNet:p03739", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nint n, option;\nll ch[2];\n\nint main() {\n    cin.sync_with_stdio(0); cin.tie(0);\n    cin >> n;\n    vector<ll> a(n);\n    for (auto& i : a) cin >> i;\n    \n    for (int i = 0; i < n; ++i) {\n        if (a[i] >= 0)\n            ch[i % 2] += a[i] + 1;\n    }\n    \n    // Which is going to be negative\n    option = (ch[0] >= ch[1]);\n    ll cur = 0, ans = 0;\n    for (int i = 0; i < n; ++i) {\n        cur += a[i];\n        if (i % 2 == option && cur >= 0) {\n            ans += cur + 1;\n            cur = -1;\n        } else if (i % 2 != option && cur <= 0) {\n            ans += -1ll * (cur - 1);\n            cur = 1;\n        }\n    }\n    cout << ans;\n}\n", "language": "C++", "metadata": {"date": 1592994652, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03739.html", "problem_id": "p03739", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03739/input.txt", "sample_output_relpath": "derived/input_output/data/p03739/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03739/C++/s751438648.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s751438648", "user_id": "u736647947"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nusing ll = long long;\n\nint n, option;\nll ch[2];\n\nint main() {\n    cin.sync_with_stdio(0); cin.tie(0);\n    cin >> n;\n    vector<ll> a(n);\n    for (auto& i : a) cin >> i;\n    \n    for (int i = 0; i < n; ++i) {\n        if (a[i] >= 0)\n            ch[i % 2] += a[i] + 1;\n    }\n    \n    // Which is going to be negative\n    option = (ch[0] >= ch[1]);\n    ll cur = 0, ans = 0;\n    for (int i = 0; i < n; ++i) {\n        cur += a[i];\n        if (i % 2 == option && cur >= 0) {\n            ans += cur + 1;\n            cur = -1;\n        } else if (i % 2 != option && cur <= 0) {\n            ans += -1ll * (cur - 1);\n            cur = 1;\n        }\n    }\n    cout << ans;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nYou are given an integer sequence of length N. The i-th term in the sequence is a_i.\nIn one operation, you can select a term and either increment or decrement it by one.\n\nAt least how many operations are necessary to satisfy the following conditions?\n\nFor every i (1≤i≤n), the sum of the terms from the 1-st through i-th term is not zero.\n\nFor every i (1≤i≤n-1), the sign of the sum of the terms from the 1-st through i-th term, is different from the sign of the sum of the terms from the 1-st through (i+1)-th term.\n\nConstraints\n\n2 ≤ n ≤ 10^5\n\n|a_i| ≤ 10^9\n\nEach a_i is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn\na_1 a_2 ... a_n\n\nOutput\n\nPrint the minimum necessary count of operations.\n\nSample Input 1\n\n4\n1 -3 1 0\n\nSample Output 1\n\n4\n\nFor example, the given sequence can be transformed into 1, -2, 2, -2 by four operations. The sums of the first one, two, three and four terms are 1, -1, 1 and -1, respectively, which satisfy the conditions.\n\nSample Input 2\n\n5\n3 -6 4 -5 7\n\nSample Output 2\n\n0\n\nThe given sequence already satisfies the conditions.\n\nSample Input 3\n\n6\n-1 4 3 2 -5 4\n\nSample Output 3\n\n8", "sample_input": "4\n1 -3 1 0\n"}, "reference_outputs": ["4\n"], "source_document_id": "p03739", "source_text": "Score : 300 points\n\nProblem Statement\n\nYou are given an integer sequence of length N. The i-th term in the sequence is a_i.\nIn one operation, you can select a term and either increment or decrement it by one.\n\nAt least how many operations are necessary to satisfy the following conditions?\n\nFor every i (1≤i≤n), the sum of the terms from the 1-st through i-th term is not zero.\n\nFor every i (1≤i≤n-1), the sign of the sum of the terms from the 1-st through i-th term, is different from the sign of the sum of the terms from the 1-st through (i+1)-th term.\n\nConstraints\n\n2 ≤ n ≤ 10^5\n\n|a_i| ≤ 10^9\n\nEach a_i is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn\na_1 a_2 ... a_n\n\nOutput\n\nPrint the minimum necessary count of operations.\n\nSample Input 1\n\n4\n1 -3 1 0\n\nSample Output 1\n\n4\n\nFor example, the given sequence can be transformed into 1, -2, 2, -2 by four operations. The sums of the first one, two, three and four terms are 1, -1, 1 and -1, respectively, which satisfy the conditions.\n\nSample Input 2\n\n5\n3 -6 4 -5 7\n\nSample Output 2\n\n0\n\nThe given sequence already satisfies the conditions.\n\nSample Input 3\n\n6\n-1 4 3 2 -5 4\n\nSample Output 3\n\n8", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 707, "cpu_time_ms": 24, "memory_kb": 3988}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s465225513", "group_id": "codeNet:p03740", "input_text": "#include <iostream>\n#include <string>\n#include <vector>\n#include <list>\n#include <map>\n#include <queue>\n#include <stack>\n#include <algorithm>\n#include <fstream>\n#include <sstream>\n#include <iomanip>\n\nusing namespace std;\n\nlong long MOD = 1000000007;\n\nint main(){\n    long long X, Y;\n    cin >> X >> Y;\n    if(abs(X-Y)<=1){\n        cout << \"Brown\" << endl;\n    }else{\n        cout << \"Alice\" << endl;\n    }\n}", "language": "C++", "metadata": {"date": 1581892116, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03740.html", "problem_id": "p03740", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03740/input.txt", "sample_output_relpath": "derived/input_output/data/p03740/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03740/C++/s465225513.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s465225513", "user_id": "u658993896"}, "prompt_components": {"gold_output": "Brown\n", "input_to_evaluate": "#include <iostream>\n#include <string>\n#include <vector>\n#include <list>\n#include <map>\n#include <queue>\n#include <stack>\n#include <algorithm>\n#include <fstream>\n#include <sstream>\n#include <iomanip>\n\nusing namespace std;\n\nlong long MOD = 1000000007;\n\nint main(){\n    long long X, Y;\n    cin >> X >> Y;\n    if(abs(X-Y)<=1){\n        cout << \"Brown\" << endl;\n    }else{\n        cout << \"Alice\" << endl;\n    }\n}", "problem_context": "Score : 500 points\n\nProblem Statement\n\nAlice and Brown loves games. Today, they will play the following game.\n\nIn this game, there are two piles initially consisting of X and Y stones, respectively.\nAlice and Bob alternately perform the following operation, starting from Alice:\n\nTake 2i stones from one of the piles. Then, throw away i of them, and put the remaining i in the other pile. Here, the integer i (1≤i) can be freely chosen as long as there is a sufficient number of stones in the pile.\n\nThe player who becomes unable to perform the operation, loses the game.\n\nGiven X and Y, determine the winner of the game, assuming that both players play optimally.\n\nConstraints\n\n0 ≤ X, Y ≤ 10^{18}\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX Y\n\nOutput\n\nPrint the winner: either Alice or Brown.\n\nSample Input 1\n\n2 1\n\nSample Output 1\n\nBrown\n\nAlice can do nothing but taking two stones from the pile containing two stones. As a result, the piles consist of zero and two stones, respectively. Then, Brown will take the two stones, and the piles will consist of one and zero stones, respectively. Alice will be unable to perform the operation anymore, which means Brown's victory.\n\nSample Input 2\n\n5 0\n\nSample Output 2\n\nAlice\n\nSample Input 3\n\n0 0\n\nSample Output 3\n\nBrown\n\nSample Input 4\n\n4 8\n\nSample Output 4\n\nAlice", "sample_input": "2 1\n"}, "reference_outputs": ["Brown\n"], "source_document_id": "p03740", "source_text": "Score : 500 points\n\nProblem Statement\n\nAlice and Brown loves games. Today, they will play the following game.\n\nIn this game, there are two piles initially consisting of X and Y stones, respectively.\nAlice and Bob alternately perform the following operation, starting from Alice:\n\nTake 2i stones from one of the piles. Then, throw away i of them, and put the remaining i in the other pile. Here, the integer i (1≤i) can be freely chosen as long as there is a sufficient number of stones in the pile.\n\nThe player who becomes unable to perform the operation, loses the game.\n\nGiven X and Y, determine the winner of the game, assuming that both players play optimally.\n\nConstraints\n\n0 ≤ X, Y ≤ 10^{18}\n\nInput\n\nInput is given from Standard Input in the following format:\n\nX Y\n\nOutput\n\nPrint the winner: either Alice or Brown.\n\nSample Input 1\n\n2 1\n\nSample Output 1\n\nBrown\n\nAlice can do nothing but taking two stones from the pile containing two stones. As a result, the piles consist of zero and two stones, respectively. Then, Brown will take the two stones, and the piles will consist of one and zero stones, respectively. Alice will be unable to perform the operation anymore, which means Brown's victory.\n\nSample Input 2\n\n5 0\n\nSample Output 2\n\nAlice\n\nSample Input 3\n\n0 0\n\nSample Output 3\n\nBrown\n\nSample Input 4\n\n4 8\n\nSample Output 4\n\nAlice", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 407, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s827540794", "group_id": "codeNet:p03741", "input_text": "#include <bits/stdc++.h>\n\nusing namespace std;\n#define FOR(i, a, b) for (int i = (a), _##i = (b); i < _##i; ++i)\n#define REP(i, a) for (int i = 0, _##i = (a); i < _##i; ++i)\n#define pb push_back\ntypedef long long LL;\n\nint n;\nLL a[100004];\n\nLL solve(LL sum){\n\t\n\tLL res = 0;\t\n\tFOR(i,2,n){\t\n\t\tif(sum < 0){\n\t\t\tif( sum + a[i] > 0){\t\t\t\n\t\t\t\tsum += a[i];\n\t\t\t\tcontinue;\t\t\n\t\t\t}\t\t\n\t\t\tres+= 1 - (sum + a[i]);\n\t\t\tsum = 1;\n\t\t}else{\n\t\t\tif( sum + a[i] < 0) {\t\t\t\n\t\t\t\tsum += a[i];\n\t\t\t\tcontinue;\t\t\n\t\t\t}\n\t\t\tres+= (sum + a[i]) + 1;\n\t\t\tsum = -1;\n\t\t}\n\t}\t\n\treturn res;\n}\n\nint main(){\n//\tfreopen(\"test.in\",\"r\",stdin);\n\tcin>> n;\n\tREP(i,n){\n\t\tcin >> a[i];\n\t}\n\tLL sum = a[0] + a[1];\n\tif(sum){\n\t\tif( sum > 0){\n\t\t\tLL res = min( solve(-1) + sum + 1, solve(sum) );\n\t\t\tcout << min( solve(1) + sum - 1, res ) << endl;\n\t\t}else{\n\t\t\tLL res = min( solve(1)  - sum + 1, solve(sum) );\n\t\t\tcout << min( solve(-1)  - sum - 1, res ) << endl;\n\t\t}\n\t}else{\n\t\tcout << min( solve(1), solve(-1) ) + 1 << endl;\n\t}\t\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1496160577, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03741.html", "problem_id": "p03741", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03741/input.txt", "sample_output_relpath": "derived/input_output/data/p03741/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03741/C++/s827540794.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s827540794", "user_id": "u301598979"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\nusing namespace std;\n#define FOR(i, a, b) for (int i = (a), _##i = (b); i < _##i; ++i)\n#define REP(i, a) for (int i = 0, _##i = (a); i < _##i; ++i)\n#define pb push_back\ntypedef long long LL;\n\nint n;\nLL a[100004];\n\nLL solve(LL sum){\n\t\n\tLL res = 0;\t\n\tFOR(i,2,n){\t\n\t\tif(sum < 0){\n\t\t\tif( sum + a[i] > 0){\t\t\t\n\t\t\t\tsum += a[i];\n\t\t\t\tcontinue;\t\t\n\t\t\t}\t\t\n\t\t\tres+= 1 - (sum + a[i]);\n\t\t\tsum = 1;\n\t\t}else{\n\t\t\tif( sum + a[i] < 0) {\t\t\t\n\t\t\t\tsum += a[i];\n\t\t\t\tcontinue;\t\t\n\t\t\t}\n\t\t\tres+= (sum + a[i]) + 1;\n\t\t\tsum = -1;\n\t\t}\n\t}\t\n\treturn res;\n}\n\nint main(){\n//\tfreopen(\"test.in\",\"r\",stdin);\n\tcin>> n;\n\tREP(i,n){\n\t\tcin >> a[i];\n\t}\n\tLL sum = a[0] + a[1];\n\tif(sum){\n\t\tif( sum > 0){\n\t\t\tLL res = min( solve(-1) + sum + 1, solve(sum) );\n\t\t\tcout << min( solve(1) + sum - 1, res ) << endl;\n\t\t}else{\n\t\t\tLL res = min( solve(1)  - sum + 1, solve(sum) );\n\t\t\tcout << min( solve(-1)  - sum - 1, res ) << endl;\n\t\t}\n\t}else{\n\t\tcout << min( solve(1), solve(-1) ) + 1 << endl;\n\t}\t\n\treturn 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nYou are given an integer sequence of length N. The i-th term in the sequence is a_i.\nIn one operation, you can select a term and either increment or decrement it by one.\n\nAt least how many operations are necessary to satisfy the following conditions?\n\nFor every i (1≤i≤n), the sum of the terms from the 1-st through i-th term is not zero.\n\nFor every i (1≤i≤n-1), the sign of the sum of the terms from the 1-st through i-th term, is different from the sign of the sum of the terms from the 1-st through (i+1)-th term.\n\nConstraints\n\n2 ≤ n ≤ 10^5\n\n|a_i| ≤ 10^9\n\nEach a_i is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn\na_1 a_2 ... a_n\n\nOutput\n\nPrint the minimum necessary count of operations.\n\nSample Input 1\n\n4\n1 -3 1 0\n\nSample Output 1\n\n4\n\nFor example, the given sequence can be transformed into 1, -2, 2, -2 by four operations. The sums of the first one, two, three and four terms are 1, -1, 1 and -1, respectively, which satisfy the conditions.\n\nSample Input 2\n\n5\n3 -6 4 -5 7\n\nSample Output 2\n\n0\n\nThe given sequence already satisfies the conditions.\n\nSample Input 3\n\n6\n-1 4 3 2 -5 4\n\nSample Output 3\n\n8", "sample_input": "4\n1 -3 1 0\n"}, "reference_outputs": ["4\n"], "source_document_id": "p03741", "source_text": "Score : 300 points\n\nProblem Statement\n\nYou are given an integer sequence of length N. The i-th term in the sequence is a_i.\nIn one operation, you can select a term and either increment or decrement it by one.\n\nAt least how many operations are necessary to satisfy the following conditions?\n\nFor every i (1≤i≤n), the sum of the terms from the 1-st through i-th term is not zero.\n\nFor every i (1≤i≤n-1), the sign of the sum of the terms from the 1-st through i-th term, is different from the sign of the sum of the terms from the 1-st through (i+1)-th term.\n\nConstraints\n\n2 ≤ n ≤ 10^5\n\n|a_i| ≤ 10^9\n\nEach a_i is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn\na_1 a_2 ... a_n\n\nOutput\n\nPrint the minimum necessary count of operations.\n\nSample Input 1\n\n4\n1 -3 1 0\n\nSample Output 1\n\n4\n\nFor example, the given sequence can be transformed into 1, -2, 2, -2 by four operations. The sums of the first one, two, three and four terms are 1, -1, 1 and -1, respectively, which satisfy the conditions.\n\nSample Input 2\n\n5\n3 -6 4 -5 7\n\nSample Output 2\n\n0\n\nThe given sequence already satisfies the conditions.\n\nSample Input 3\n\n6\n-1 4 3 2 -5 4\n\nSample Output 3\n\n8", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 976, "cpu_time_ms": 45, "memory_kb": 1024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s587480253", "group_id": "codeNet:p03745", "input_text": "#include <stdio.h>\n#include <cstdlib>\n\nvoid scanData(int *array, int size) {\n    for (int i = 0; i < size; ++i) {\n        char buffer[100001];\n        char *remain;\n        scanf(\"%s\", &buffer[0]);\n        array[i] = (int)atol(buffer);\n    }\n}\n\nvoid print_array(int *array, int size) {\n    if (size == 0) return;\n    printf(\"%d \", array[0]);\n    print_array(array + 1, size - 1);\n}\n\nint count(const int *array, int size) {\n    enum Arranged {\n        None = -1,\n        Ascending,\n        Descending\n    };\n\n    int splitNum = 0;\n    Arranged arranged = array[0] < array[1] ? Ascending : Descending;\n    Arranged prevState = arranged;\n    for (int i = 1; i < size - 1; ++i) {\n        if ((arranged == Ascending && array[i] > array[i + 1]) || (arranged == Descending && array[i] < array[i + 1])) {\n            splitNum++;\n            i++;\n            arranged = array[i] < array[i + 1] ? Ascending : Descending;\n        }\n    }\n\n    return splitNum + 1;\n}\n\nint main() {\n    int *array;\n    int array_len;\n\n    scanf(\"%d\", &array_len);\n    if (array_len == 1) {\n        printf(\"0\");\n        return 0;\n    }\n    array = (int*)malloc(sizeof(int) * (size_t)array_len);\n\n    scanData(array, array_len);\n    printf(\"%d\", count(array, array_len));\n\n    free(array);\n\n    return 0;\n}", "language": "C++", "metadata": {"date": 1545980202, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03745.html", "problem_id": "p03745", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03745/input.txt", "sample_output_relpath": "derived/input_output/data/p03745/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03745/C++/s587480253.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s587480253", "user_id": "u513475309"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <stdio.h>\n#include <cstdlib>\n\nvoid scanData(int *array, int size) {\n    for (int i = 0; i < size; ++i) {\n        char buffer[100001];\n        char *remain;\n        scanf(\"%s\", &buffer[0]);\n        array[i] = (int)atol(buffer);\n    }\n}\n\nvoid print_array(int *array, int size) {\n    if (size == 0) return;\n    printf(\"%d \", array[0]);\n    print_array(array + 1, size - 1);\n}\n\nint count(const int *array, int size) {\n    enum Arranged {\n        None = -1,\n        Ascending,\n        Descending\n    };\n\n    int splitNum = 0;\n    Arranged arranged = array[0] < array[1] ? Ascending : Descending;\n    Arranged prevState = arranged;\n    for (int i = 1; i < size - 1; ++i) {\n        if ((arranged == Ascending && array[i] > array[i + 1]) || (arranged == Descending && array[i] < array[i + 1])) {\n            splitNum++;\n            i++;\n            arranged = array[i] < array[i + 1] ? Ascending : Descending;\n        }\n    }\n\n    return splitNum + 1;\n}\n\nint main() {\n    int *array;\n    int array_len;\n\n    scanf(\"%d\", &array_len);\n    if (array_len == 1) {\n        printf(\"0\");\n        return 0;\n    }\n    array = (int*)malloc(sizeof(int) * (size_t)array_len);\n\n    scanData(array, array_len);\n    printf(\"%d\", count(array, array_len));\n\n    free(array);\n\n    return 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nYou are given an array A of length N.\nYour task is to divide it into several contiguous subarrays.\nHere, all subarrays obtained must be sorted in either non-decreasing or non-increasing order.\nAt least how many subarrays do you need to divide A into?\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq A_i \\leq 10^9\n\nEach A_i is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the minimum possible number of subarrays after division of A.\n\nSample Input 1\n\n6\n1 2 3 2 2 1\n\nSample Output 1\n\n2\n\nOne optimal solution is to divide the array into [1,2,3] and [2,2,1].\n\nSample Input 2\n\n9\n1 2 1 2 1 2 1 2 1\n\nSample Output 2\n\n5\n\nSample Input 3\n\n7\n1 2 3 2 1 999999999 1000000000\n\nSample Output 3\n\n3", "sample_input": "6\n1 2 3 2 2 1\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03745", "source_text": "Score : 300 points\n\nProblem Statement\n\nYou are given an array A of length N.\nYour task is to divide it into several contiguous subarrays.\nHere, all subarrays obtained must be sorted in either non-decreasing or non-increasing order.\nAt least how many subarrays do you need to divide A into?\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq A_i \\leq 10^9\n\nEach A_i is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the minimum possible number of subarrays after division of A.\n\nSample Input 1\n\n6\n1 2 3 2 2 1\n\nSample Output 1\n\n2\n\nOne optimal solution is to divide the array into [1,2,3] and [2,2,1].\n\nSample Input 2\n\n9\n1 2 1 2 1 2 1 2 1\n\nSample Output 2\n\n5\n\nSample Input 3\n\n7\n1 2 3 2 1 999999999 1000000000\n\nSample Output 3\n\n3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1274, "cpu_time_ms": 12, "memory_kb": 512}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s715295426", "group_id": "codeNet:p03745", "input_text": "#include<cstdio>\nlong long a[100000];\nint main()\n{\n\tint t,sum1=0,i;\n\tscanf(\"%d\",&t);\n\tfor(i=0;i<t;i++){\n\t\tscanf(\"%lld\",&a[i]);\n\t}\n\tfor(i=1;i<t;i++){\n\t\tif(a[i]>a[i-1])\n\t\t\tif(a[i]>a[i+1])\n\t\t\t\tsum1++;\n\t}\n\tprintf(\"%d\\n\",sum1+1);\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1496004578, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03745.html", "problem_id": "p03745", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03745/input.txt", "sample_output_relpath": "derived/input_output/data/p03745/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03745/C++/s715295426.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s715295426", "user_id": "u089230684"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include<cstdio>\nlong long a[100000];\nint main()\n{\n\tint t,sum1=0,i;\n\tscanf(\"%d\",&t);\n\tfor(i=0;i<t;i++){\n\t\tscanf(\"%lld\",&a[i]);\n\t}\n\tfor(i=1;i<t;i++){\n\t\tif(a[i]>a[i-1])\n\t\t\tif(a[i]>a[i+1])\n\t\t\t\tsum1++;\n\t}\n\tprintf(\"%d\\n\",sum1+1);\n\treturn 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nYou are given an array A of length N.\nYour task is to divide it into several contiguous subarrays.\nHere, all subarrays obtained must be sorted in either non-decreasing or non-increasing order.\nAt least how many subarrays do you need to divide A into?\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq A_i \\leq 10^9\n\nEach A_i is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the minimum possible number of subarrays after division of A.\n\nSample Input 1\n\n6\n1 2 3 2 2 1\n\nSample Output 1\n\n2\n\nOne optimal solution is to divide the array into [1,2,3] and [2,2,1].\n\nSample Input 2\n\n9\n1 2 1 2 1 2 1 2 1\n\nSample Output 2\n\n5\n\nSample Input 3\n\n7\n1 2 3 2 1 999999999 1000000000\n\nSample Output 3\n\n3", "sample_input": "6\n1 2 3 2 2 1\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03745", "source_text": "Score : 300 points\n\nProblem Statement\n\nYou are given an array A of length N.\nYour task is to divide it into several contiguous subarrays.\nHere, all subarrays obtained must be sorted in either non-decreasing or non-increasing order.\nAt least how many subarrays do you need to divide A into?\n\nConstraints\n\n1 \\leq N \\leq 10^5\n\n1 \\leq A_i \\leq 10^9\n\nEach A_i is an integer.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the minimum possible number of subarrays after division of A.\n\nSample Input 1\n\n6\n1 2 3 2 2 1\n\nSample Output 1\n\n2\n\nOne optimal solution is to divide the array into [1,2,3] and [2,2,1].\n\nSample Input 2\n\n9\n1 2 1 2 1 2 1 2 1\n\nSample Output 2\n\n5\n\nSample Input 3\n\n7\n1 2 3 2 1 999999999 1000000000\n\nSample Output 3\n\n3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 237, "cpu_time_ms": 12, "memory_kb": 896}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s711762738", "group_id": "codeNet:p03764", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nconst int N = 100000 + 5, P = 1e9 + 7; \nint n, m, x[N], y[N];\nint main() {\n    scanf(\"%d%d\", &n, &m);\n    ll ans = 0, psum = 0;\n    for (int i = 1; i <= n; ++i) {\n        scanf (\"%d\", &x[i]);\n        ans += 1ll * (i - 1) * x[i] - psum;\n        ans %= P;\n        psum += x[i];\n    }\n    ll ans1 = 0;\n    psum = 0;\n    for (int i = 1; i <= m; ++i) {\n        scanf (\"%d\", &y[i]);\n        ans1 += 1ll * (i - 1) * y[i] - psum;\n        ans1 %= P;\n        psum += y[i];\n    }\n    cout << (ll)ans1 * ans % P << '\\n';\n    return 0; \n}", "language": "C++", "metadata": {"date": 1599312875, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03764.html", "problem_id": "p03764", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03764/input.txt", "sample_output_relpath": "derived/input_output/data/p03764/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03764/C++/s711762738.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s711762738", "user_id": "u011129112"}, "prompt_components": {"gold_output": "60\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nconst int N = 100000 + 5, P = 1e9 + 7; \nint n, m, x[N], y[N];\nint main() {\n    scanf(\"%d%d\", &n, &m);\n    ll ans = 0, psum = 0;\n    for (int i = 1; i <= n; ++i) {\n        scanf (\"%d\", &x[i]);\n        ans += 1ll * (i - 1) * x[i] - psum;\n        ans %= P;\n        psum += x[i];\n    }\n    ll ans1 = 0;\n    psum = 0;\n    for (int i = 1; i <= m; ++i) {\n        scanf (\"%d\", &y[i]);\n        ans1 += 1ll * (i - 1) * y[i] - psum;\n        ans1 %= P;\n        psum += y[i];\n    }\n    cout << (ll)ans1 * ans % P << '\\n';\n    return 0; \n}", "problem_context": "Score : 500 points\n\nProblem Statement\n\nOn a two-dimensional plane, there are m lines drawn parallel to the x axis, and n lines drawn parallel to the y axis.\nAmong the lines parallel to the x axis, the i-th from the bottom is represented by y = y_i.\nSimilarly, among the lines parallel to the y axis, the i-th from the left is represented by x = x_i.\n\nFor every rectangle that is formed by these lines, find its area, and print the total area modulo 10^9+7.\n\nThat is, for every quadruple (i,j,k,l) satisfying 1\\leq i < j\\leq n and 1\\leq k < l\\leq m, find the area of the rectangle formed by the lines x=x_i, x=x_j, y=y_k and y=y_l, and print the sum of these areas modulo 10^9+7.\n\nConstraints\n\n2 \\leq n,m \\leq 10^5\n\n-10^9 \\leq x_1 < ... < x_n \\leq 10^9\n\n-10^9 \\leq y_1 < ... < y_m \\leq 10^9\n\nx_i and y_i are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn m\nx_1 x_2 ... x_n\ny_1 y_2 ... y_m\n\nOutput\n\nPrint the total area of the rectangles, modulo 10^9+7.\n\nSample Input 1\n\n3 3\n1 3 4\n1 3 6\n\nSample Output 1\n\n60\n\nThe following figure illustrates this input:\n\nThe total area of the nine rectangles A, B, ..., I shown in the following figure, is 60.\n\nSample Input 2\n\n6 5\n-790013317 -192321079 95834122 418379342 586260100 802780784\n-253230108 193944314 363756450 712662868 735867677\n\nSample Output 2\n\n835067060", "sample_input": "3 3\n1 3 4\n1 3 6\n"}, "reference_outputs": ["60\n"], "source_document_id": "p03764", "source_text": "Score : 500 points\n\nProblem Statement\n\nOn a two-dimensional plane, there are m lines drawn parallel to the x axis, and n lines drawn parallel to the y axis.\nAmong the lines parallel to the x axis, the i-th from the bottom is represented by y = y_i.\nSimilarly, among the lines parallel to the y axis, the i-th from the left is represented by x = x_i.\n\nFor every rectangle that is formed by these lines, find its area, and print the total area modulo 10^9+7.\n\nThat is, for every quadruple (i,j,k,l) satisfying 1\\leq i < j\\leq n and 1\\leq k < l\\leq m, find the area of the rectangle formed by the lines x=x_i, x=x_j, y=y_k and y=y_l, and print the sum of these areas modulo 10^9+7.\n\nConstraints\n\n2 \\leq n,m \\leq 10^5\n\n-10^9 \\leq x_1 < ... < x_n \\leq 10^9\n\n-10^9 \\leq y_1 < ... < y_m \\leq 10^9\n\nx_i and y_i are integers.\n\nInput\n\nInput is given from Standard Input in the following format:\n\nn m\nx_1 x_2 ... x_n\ny_1 y_2 ... y_m\n\nOutput\n\nPrint the total area of the rectangles, modulo 10^9+7.\n\nSample Input 1\n\n3 3\n1 3 4\n1 3 6\n\nSample Output 1\n\n60\n\nThe following figure illustrates this input:\n\nThe total area of the nine rectangles A, B, ..., I shown in the following figure, is 60.\n\nSample Input 2\n\n6 5\n-790013317 -192321079 95834122 418379342 586260100 802780784\n-253230108 193944314 363756450 712662868 735867677\n\nSample Output 2\n\n835067060", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 593, "cpu_time_ms": 37, "memory_kb": 4416}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s711735022", "group_id": "codeNet:p03774", "input_text": "#include <bits/stdc++.h>\n#define rep(i,a,b) for(int i=int(a);i<int(b);++i)\n#define SIZE 200005\n#define INF 1000000005LL\n#define MOD 1000000007\nusing namespace std;\ntypedef long long int ll;\ntypedef pair <int,int> P;\nint main(){\n    ll n,m;\n    cin >> n>>m;\n    vector<pair<ll,ll>> student(n);\n    vector<pair<ll,ll>> check(m);\n    rep(i,0,n){\n        cin >> student[i].first;\n        cin >> student[i].second;\n    }\n    rep(i,0,m){\n        cin>>check[i].first;\n        cin>>check[i].second;\n    }\n    vector<int> ans(n);\n    //cout<<check[0].first<<endl;\n    rep(i,0,n){\n        ll k = 1000000000;\n        rep(j,0,m){\n            ll now = abs(student[i].first-check[j].first)+abs(student[i].second-check[j].second);\n            if(now<k){\n                k = now;\n                ans[i]=j;\n                \n            }\n        }\n    }\n    rep(i,0,n){\n        cout<<ans[i]+1<<endl;\n    }\n  return 0;\n}", "language": "C++", "metadata": {"date": 1593403324, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03774.html", "problem_id": "p03774", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03774/input.txt", "sample_output_relpath": "derived/input_output/data/p03774/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03774/C++/s711735022.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s711735022", "user_id": "u169190252"}, "prompt_components": {"gold_output": "2\n1\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define rep(i,a,b) for(int i=int(a);i<int(b);++i)\n#define SIZE 200005\n#define INF 1000000005LL\n#define MOD 1000000007\nusing namespace std;\ntypedef long long int ll;\ntypedef pair <int,int> P;\nint main(){\n    ll n,m;\n    cin >> n>>m;\n    vector<pair<ll,ll>> student(n);\n    vector<pair<ll,ll>> check(m);\n    rep(i,0,n){\n        cin >> student[i].first;\n        cin >> student[i].second;\n    }\n    rep(i,0,m){\n        cin>>check[i].first;\n        cin>>check[i].second;\n    }\n    vector<int> ans(n);\n    //cout<<check[0].first<<endl;\n    rep(i,0,n){\n        ll k = 1000000000;\n        rep(j,0,m){\n            ll now = abs(student[i].first-check[j].first)+abs(student[i].second-check[j].second);\n            if(now<k){\n                k = now;\n                ans[i]=j;\n                \n            }\n        }\n    }\n    rep(i,0,n){\n        cout<<ans[i]+1<<endl;\n    }\n  return 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nThere are N students and M checkpoints on the xy-plane.\n\nThe coordinates of the i-th student (1 \\leq i \\leq N) is (a_i,b_i), and the coordinates of the checkpoint numbered j (1 \\leq j \\leq M) is (c_j,d_j).\n\nWhen the teacher gives a signal, each student has to go to the nearest checkpoint measured in Manhattan distance.\n\nThe Manhattan distance between two points (x_1,y_1) and (x_2,y_2) is |x_1-x_2|+|y_1-y_2|.\n\nHere, |x| denotes the absolute value of x.\n\nIf there are multiple nearest checkpoints for a student, he/she will select the checkpoint with the smallest index.\n\nWhich checkpoint will each student go to?\n\nConstraints\n\n1 \\leq N,M \\leq 50\n\n-10^8 \\leq a_i,b_i,c_j,d_j \\leq 10^8\n\nAll input values are integers.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN M\na_1 b_1\n:\na_N b_N\nc_1 d_1\n:\nc_M d_M\n\nOutput\n\nPrint N lines.\n\nThe i-th line (1 \\leq i \\leq N) should contain the index of the checkpoint for the i-th student to go.\n\nSample Input 1\n\n2 2\n2 0\n0 0\n-1 0\n1 0\n\nSample Output 1\n\n2\n1\n\nThe Manhattan distance between the first student and each checkpoint is:\n\nFor checkpoint 1: |2-(-1)|+|0-0|=3\n\nFor checkpoint 2: |2-1|+|0-0|=1\n\nThe nearest checkpoint is checkpoint 2. Thus, the first line in the output should contain 2.\n\nThe Manhattan distance between the second student and each checkpoint is:\n\nFor checkpoint 1: |0-(-1)|+|0-0|=1\n\nFor checkpoint 2: |0-1|+|0-0|=1\n\nWhen there are multiple nearest checkpoints, the student will go to the checkpoint with the smallest index. Thus, the second line in the output should contain 1.\n\nSample Input 2\n\n3 4\n10 10\n-10 -10\n3 3\n1 2\n2 3\n3 5\n3 5\n\nSample Output 2\n\n3\n1\n2\n\nThere can be multiple checkpoints at the same coordinates.\n\nSample Input 3\n\n5 5\n-100000000 -100000000\n-100000000 100000000\n100000000 -100000000\n100000000 100000000\n0 0\n0 0\n100000000 100000000\n100000000 -100000000\n-100000000 100000000\n-100000000 -100000000\n\nSample Output 3\n\n5\n4\n3\n2\n1", "sample_input": "2 2\n2 0\n0 0\n-1 0\n1 0\n"}, "reference_outputs": ["2\n1\n"], "source_document_id": "p03774", "source_text": "Score : 200 points\n\nProblem Statement\n\nThere are N students and M checkpoints on the xy-plane.\n\nThe coordinates of the i-th student (1 \\leq i \\leq N) is (a_i,b_i), and the coordinates of the checkpoint numbered j (1 \\leq j \\leq M) is (c_j,d_j).\n\nWhen the teacher gives a signal, each student has to go to the nearest checkpoint measured in Manhattan distance.\n\nThe Manhattan distance between two points (x_1,y_1) and (x_2,y_2) is |x_1-x_2|+|y_1-y_2|.\n\nHere, |x| denotes the absolute value of x.\n\nIf there are multiple nearest checkpoints for a student, he/she will select the checkpoint with the smallest index.\n\nWhich checkpoint will each student go to?\n\nConstraints\n\n1 \\leq N,M \\leq 50\n\n-10^8 \\leq a_i,b_i,c_j,d_j \\leq 10^8\n\nAll input values are integers.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN M\na_1 b_1\n:\na_N b_N\nc_1 d_1\n:\nc_M d_M\n\nOutput\n\nPrint N lines.\n\nThe i-th line (1 \\leq i \\leq N) should contain the index of the checkpoint for the i-th student to go.\n\nSample Input 1\n\n2 2\n2 0\n0 0\n-1 0\n1 0\n\nSample Output 1\n\n2\n1\n\nThe Manhattan distance between the first student and each checkpoint is:\n\nFor checkpoint 1: |2-(-1)|+|0-0|=3\n\nFor checkpoint 2: |2-1|+|0-0|=1\n\nThe nearest checkpoint is checkpoint 2. Thus, the first line in the output should contain 2.\n\nThe Manhattan distance between the second student and each checkpoint is:\n\nFor checkpoint 1: |0-(-1)|+|0-0|=1\n\nFor checkpoint 2: |0-1|+|0-0|=1\n\nWhen there are multiple nearest checkpoints, the student will go to the checkpoint with the smallest index. Thus, the second line in the output should contain 1.\n\nSample Input 2\n\n3 4\n10 10\n-10 -10\n3 3\n1 2\n2 3\n3 5\n3 5\n\nSample Output 2\n\n3\n1\n2\n\nThere can be multiple checkpoints at the same coordinates.\n\nSample Input 3\n\n5 5\n-100000000 -100000000\n-100000000 100000000\n100000000 -100000000\n100000000 100000000\n0 0\n0 0\n100000000 100000000\n100000000 -100000000\n-100000000 100000000\n-100000000 -100000000\n\nSample Output 3\n\n5\n4\n3\n2\n1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 902, "cpu_time_ms": 7, "memory_kb": 3636}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s672631157", "group_id": "codeNet:p03774", "input_text": "#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <set>\n#include <stack>\n#include <deque>\n#include <cmath>\n#include <map>\nusing ll = long long;\nusing namespace std;\n\nint main() {\n  int n, m;\n  cin >> n >> m;\n  int a[n], b[n], c[m], d[m];\n  for (int i = 0; i < n; i++) cin >> a[i] >> b[i];\n  for (int i = 0; i < m; i++) cin >> c[i] >> d[i];\n\n  for (int i = 0; i < n; i++) {\n    int ans = 1;\n    ll mind = 1<<15;\n    for (int j = 0; j < m; j++) {\n      int dist = abs(a[i] - c[j]) + abs(b[i] - d[j]);\n      if (dist < mind) {\n        ans = j+1;\n        mind = dist;\n      }\n    }\n    cout << ans << endl;\n  }\n}\n", "language": "C++", "metadata": {"date": 1534814431, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03774.html", "problem_id": "p03774", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03774/input.txt", "sample_output_relpath": "derived/input_output/data/p03774/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03774/C++/s672631157.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s672631157", "user_id": "u318785595"}, "prompt_components": {"gold_output": "2\n1\n", "input_to_evaluate": "#include <iostream>\n#include <string>\n#include <vector>\n#include <algorithm>\n#include <set>\n#include <stack>\n#include <deque>\n#include <cmath>\n#include <map>\nusing ll = long long;\nusing namespace std;\n\nint main() {\n  int n, m;\n  cin >> n >> m;\n  int a[n], b[n], c[m], d[m];\n  for (int i = 0; i < n; i++) cin >> a[i] >> b[i];\n  for (int i = 0; i < m; i++) cin >> c[i] >> d[i];\n\n  for (int i = 0; i < n; i++) {\n    int ans = 1;\n    ll mind = 1<<15;\n    for (int j = 0; j < m; j++) {\n      int dist = abs(a[i] - c[j]) + abs(b[i] - d[j]);\n      if (dist < mind) {\n        ans = j+1;\n        mind = dist;\n      }\n    }\n    cout << ans << endl;\n  }\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nThere are N students and M checkpoints on the xy-plane.\n\nThe coordinates of the i-th student (1 \\leq i \\leq N) is (a_i,b_i), and the coordinates of the checkpoint numbered j (1 \\leq j \\leq M) is (c_j,d_j).\n\nWhen the teacher gives a signal, each student has to go to the nearest checkpoint measured in Manhattan distance.\n\nThe Manhattan distance between two points (x_1,y_1) and (x_2,y_2) is |x_1-x_2|+|y_1-y_2|.\n\nHere, |x| denotes the absolute value of x.\n\nIf there are multiple nearest checkpoints for a student, he/she will select the checkpoint with the smallest index.\n\nWhich checkpoint will each student go to?\n\nConstraints\n\n1 \\leq N,M \\leq 50\n\n-10^8 \\leq a_i,b_i,c_j,d_j \\leq 10^8\n\nAll input values are integers.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN M\na_1 b_1\n:\na_N b_N\nc_1 d_1\n:\nc_M d_M\n\nOutput\n\nPrint N lines.\n\nThe i-th line (1 \\leq i \\leq N) should contain the index of the checkpoint for the i-th student to go.\n\nSample Input 1\n\n2 2\n2 0\n0 0\n-1 0\n1 0\n\nSample Output 1\n\n2\n1\n\nThe Manhattan distance between the first student and each checkpoint is:\n\nFor checkpoint 1: |2-(-1)|+|0-0|=3\n\nFor checkpoint 2: |2-1|+|0-0|=1\n\nThe nearest checkpoint is checkpoint 2. Thus, the first line in the output should contain 2.\n\nThe Manhattan distance between the second student and each checkpoint is:\n\nFor checkpoint 1: |0-(-1)|+|0-0|=1\n\nFor checkpoint 2: |0-1|+|0-0|=1\n\nWhen there are multiple nearest checkpoints, the student will go to the checkpoint with the smallest index. Thus, the second line in the output should contain 1.\n\nSample Input 2\n\n3 4\n10 10\n-10 -10\n3 3\n1 2\n2 3\n3 5\n3 5\n\nSample Output 2\n\n3\n1\n2\n\nThere can be multiple checkpoints at the same coordinates.\n\nSample Input 3\n\n5 5\n-100000000 -100000000\n-100000000 100000000\n100000000 -100000000\n100000000 100000000\n0 0\n0 0\n100000000 100000000\n100000000 -100000000\n-100000000 100000000\n-100000000 -100000000\n\nSample Output 3\n\n5\n4\n3\n2\n1", "sample_input": "2 2\n2 0\n0 0\n-1 0\n1 0\n"}, "reference_outputs": ["2\n1\n"], "source_document_id": "p03774", "source_text": "Score : 200 points\n\nProblem Statement\n\nThere are N students and M checkpoints on the xy-plane.\n\nThe coordinates of the i-th student (1 \\leq i \\leq N) is (a_i,b_i), and the coordinates of the checkpoint numbered j (1 \\leq j \\leq M) is (c_j,d_j).\n\nWhen the teacher gives a signal, each student has to go to the nearest checkpoint measured in Manhattan distance.\n\nThe Manhattan distance between two points (x_1,y_1) and (x_2,y_2) is |x_1-x_2|+|y_1-y_2|.\n\nHere, |x| denotes the absolute value of x.\n\nIf there are multiple nearest checkpoints for a student, he/she will select the checkpoint with the smallest index.\n\nWhich checkpoint will each student go to?\n\nConstraints\n\n1 \\leq N,M \\leq 50\n\n-10^8 \\leq a_i,b_i,c_j,d_j \\leq 10^8\n\nAll input values are integers.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN M\na_1 b_1\n:\na_N b_N\nc_1 d_1\n:\nc_M d_M\n\nOutput\n\nPrint N lines.\n\nThe i-th line (1 \\leq i \\leq N) should contain the index of the checkpoint for the i-th student to go.\n\nSample Input 1\n\n2 2\n2 0\n0 0\n-1 0\n1 0\n\nSample Output 1\n\n2\n1\n\nThe Manhattan distance between the first student and each checkpoint is:\n\nFor checkpoint 1: |2-(-1)|+|0-0|=3\n\nFor checkpoint 2: |2-1|+|0-0|=1\n\nThe nearest checkpoint is checkpoint 2. Thus, the first line in the output should contain 2.\n\nThe Manhattan distance between the second student and each checkpoint is:\n\nFor checkpoint 1: |0-(-1)|+|0-0|=1\n\nFor checkpoint 2: |0-1|+|0-0|=1\n\nWhen there are multiple nearest checkpoints, the student will go to the checkpoint with the smallest index. Thus, the second line in the output should contain 1.\n\nSample Input 2\n\n3 4\n10 10\n-10 -10\n3 3\n1 2\n2 3\n3 5\n3 5\n\nSample Output 2\n\n3\n1\n2\n\nThere can be multiple checkpoints at the same coordinates.\n\nSample Input 3\n\n5 5\n-100000000 -100000000\n-100000000 100000000\n100000000 -100000000\n100000000 100000000\n0 0\n0 0\n100000000 100000000\n100000000 -100000000\n-100000000 100000000\n-100000000 -100000000\n\nSample Output 3\n\n5\n4\n3\n2\n1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 645, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s691015116", "group_id": "codeNet:p03777", "input_text": "#include \"bits/stdc++.h\"\nusing namespace std;\ntypedef long long ll;\n#define INF (1<<30)\n#define INFLL (1ll<<60)\ntypedef pair<ll, int> P;\n#define MOD (1000000007ll)\n#define l_ength size\n\nll sq(ll x){\n\treturn x*x;\n}\n\nvoid mul_mod(ll& a, ll b){\n\ta *= b;\n\ta %= MOD;\n}\n\nbool isvowel(char c){\n\tint i;\n\tstring v=\"aeiou\";\n\tfor(i = (v.size()-1); i>=0; --i){\n\t\tif(c == v[i]){\n\t\t\treturn true;\n\t\t}\n\t}\n\treturn false;\n}\n\nint main(void){\n\tchar a,b;\n\tcin >> a >> b;\n\tcout << ((a==b)?\"H\":\"D\") << endl;\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1519380519, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03777.html", "problem_id": "p03777", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03777/input.txt", "sample_output_relpath": "derived/input_output/data/p03777/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03777/C++/s691015116.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s691015116", "user_id": "u548624367"}, "prompt_components": {"gold_output": "H\n", "input_to_evaluate": "#include \"bits/stdc++.h\"\nusing namespace std;\ntypedef long long ll;\n#define INF (1<<30)\n#define INFLL (1ll<<60)\ntypedef pair<ll, int> P;\n#define MOD (1000000007ll)\n#define l_ength size\n\nll sq(ll x){\n\treturn x*x;\n}\n\nvoid mul_mod(ll& a, ll b){\n\ta *= b;\n\ta %= MOD;\n}\n\nbool isvowel(char c){\n\tint i;\n\tstring v=\"aeiou\";\n\tfor(i = (v.size()-1); i>=0; --i){\n\t\tif(c == v[i]){\n\t\t\treturn true;\n\t\t}\n\t}\n\treturn false;\n}\n\nint main(void){\n\tchar a,b;\n\tcin >> a >> b;\n\tcout << ((a==b)?\"H\":\"D\") << endl;\n\treturn 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nTwo deer, AtCoDeer and TopCoDeer, are playing a game called Honest or Dishonest.\nIn this game, an honest player always tells the truth, and an dishonest player always tell lies.\nYou are given two characters a and b as the input. Each of them is either H or D, and carries the following information:\n\nIf a=H, AtCoDeer is honest; if a=D, AtCoDeer is dishonest.\nIf b=H, AtCoDeer is saying that TopCoDeer is honest; if b=D, AtCoDeer is saying that TopCoDeer is dishonest.\n\nGiven this information, determine whether TopCoDeer is honest.\n\nConstraints\n\na=H or a=D.\n\nb=H or b=D.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\na b\n\nOutput\n\nIf TopCoDeer is honest, print H. If he is dishonest, print D.\n\nSample Input 1\n\nH H\n\nSample Output 1\n\nH\n\nIn this input, AtCoDeer is honest. Hence, as he says, TopCoDeer is honest.\n\nSample Input 2\n\nD H\n\nSample Output 2\n\nD\n\nIn this input, AtCoDeer is dishonest. Hence, contrary to what he says, TopCoDeer is dishonest.\n\nSample Input 3\n\nD D\n\nSample Output 3\n\nH", "sample_input": "H H\n"}, "reference_outputs": ["H\n"], "source_document_id": "p03777", "source_text": "Score : 100 points\n\nProblem Statement\n\nTwo deer, AtCoDeer and TopCoDeer, are playing a game called Honest or Dishonest.\nIn this game, an honest player always tells the truth, and an dishonest player always tell lies.\nYou are given two characters a and b as the input. Each of them is either H or D, and carries the following information:\n\nIf a=H, AtCoDeer is honest; if a=D, AtCoDeer is dishonest.\nIf b=H, AtCoDeer is saying that TopCoDeer is honest; if b=D, AtCoDeer is saying that TopCoDeer is dishonest.\n\nGiven this information, determine whether TopCoDeer is honest.\n\nConstraints\n\na=H or a=D.\n\nb=H or b=D.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\na b\n\nOutput\n\nIf TopCoDeer is honest, print H. If he is dishonest, print D.\n\nSample Input 1\n\nH H\n\nSample Output 1\n\nH\n\nIn this input, AtCoDeer is honest. Hence, as he says, TopCoDeer is honest.\n\nSample Input 2\n\nD H\n\nSample Output 2\n\nD\n\nIn this input, AtCoDeer is dishonest. Hence, contrary to what he says, TopCoDeer is dishonest.\n\nSample Input 3\n\nD D\n\nSample Output 3\n\nH", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 497, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s310368801", "group_id": "codeNet:p03778", "input_text": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define endl \"\\n\"\n#define pb(s) push_back(s)\n#define mp(a,b) make_pair(a,b)\n#define f first\n#define se second\n#define ALL(v) v.begin(), v.end()\n#define ALLA(arr, sz) arr, arr + sz\n#define SORT(v) sort(ALL(v))\n#define REVERSE(v) reverse(ALL(v))\n#define SORTA(arr, sz) sort(ALLA(arr, sz))\n#define REVERSEA(arr, sz) reverse(ALLA(arr, sz))\n#define PI 3.14159265358979323846264338327950L\n#define MOD 1000000007\n\ntypedef long long ll;\n\nvoid solve(){\n    int W,a,b;\n    cin>>W>>a>>b;\n    int firstL=a;\n    int firstR=a+W;\n    int secondL=b;\n    int secondR=b+W;\n    if(firstL>secondR){\n        cout<<firstL-secondR<<endl;\n    }\n    else if(firstR<secondL){\n        cout<<secondL-firstR<<endl;\n    }\n    else cout<<0<<endl;\n}\n\nint main()\n{\n    ios_base::sync_with_stdio(false);\n    cin.tie(0);\n    //int t;\n    //cin>>t;\n    //while(t--)\n        solve();\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1590916800, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03778.html", "problem_id": "p03778", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03778/input.txt", "sample_output_relpath": "derived/input_output/data/p03778/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03778/C++/s310368801.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s310368801", "user_id": "u051484887"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define endl \"\\n\"\n#define pb(s) push_back(s)\n#define mp(a,b) make_pair(a,b)\n#define f first\n#define se second\n#define ALL(v) v.begin(), v.end()\n#define ALLA(arr, sz) arr, arr + sz\n#define SORT(v) sort(ALL(v))\n#define REVERSE(v) reverse(ALL(v))\n#define SORTA(arr, sz) sort(ALLA(arr, sz))\n#define REVERSEA(arr, sz) reverse(ALLA(arr, sz))\n#define PI 3.14159265358979323846264338327950L\n#define MOD 1000000007\n\ntypedef long long ll;\n\nvoid solve(){\n    int W,a,b;\n    cin>>W>>a>>b;\n    int firstL=a;\n    int firstR=a+W;\n    int secondL=b;\n    int secondR=b+W;\n    if(firstL>secondR){\n        cout<<firstL-secondR<<endl;\n    }\n    else if(firstR<secondL){\n        cout<<secondL-firstR<<endl;\n    }\n    else cout<<0<<endl;\n}\n\nint main()\n{\n    ios_base::sync_with_stdio(false);\n    cin.tie(0);\n    //int t;\n    //cin>>t;\n    //while(t--)\n        solve();\n    return 0;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nAtCoDeer the deer found two rectangles lying on the table, each with height 1 and width W.\nIf we consider the surface of the desk as a two-dimensional plane, the first rectangle covers the vertical range of [0,1] and the horizontal range of [a,a+W], and the second rectangle covers the vertical range of [1,2] and the horizontal range of [b,b+W], as shown in the following figure:\n\nAtCoDeer will move the second rectangle horizontally so that it connects with the first rectangle.\nFind the minimum distance it needs to be moved.\n\nConstraints\n\nAll input values are integers.\n\n1≤W≤10^5\n\n1≤a,b≤10^5\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nW a b\n\nOutput\n\nPrint the minimum distance the second rectangle needs to be moved.\n\nSample Input 1\n\n3 2 6\n\nSample Output 1\n\n1\n\nThis input corresponds to the figure in the statement. In this case, the second rectangle should be moved to the left by a distance of 1.\n\nSample Input 2\n\n3 1 3\n\nSample Output 2\n\n0\n\nThe rectangles are already connected, and thus no move is needed.\n\nSample Input 3\n\n5 10 1\n\nSample Output 3\n\n4", "sample_input": "3 2 6\n"}, "reference_outputs": ["1\n"], "source_document_id": "p03778", "source_text": "Score : 200 points\n\nProblem Statement\n\nAtCoDeer the deer found two rectangles lying on the table, each with height 1 and width W.\nIf we consider the surface of the desk as a two-dimensional plane, the first rectangle covers the vertical range of [0,1] and the horizontal range of [a,a+W], and the second rectangle covers the vertical range of [1,2] and the horizontal range of [b,b+W], as shown in the following figure:\n\nAtCoDeer will move the second rectangle horizontally so that it connects with the first rectangle.\nFind the minimum distance it needs to be moved.\n\nConstraints\n\nAll input values are integers.\n\n1≤W≤10^5\n\n1≤a,b≤10^5\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nW a b\n\nOutput\n\nPrint the minimum distance the second rectangle needs to be moved.\n\nSample Input 1\n\n3 2 6\n\nSample Output 1\n\n1\n\nThis input corresponds to the figure in the statement. In this case, the second rectangle should be moved to the left by a distance of 1.\n\nSample Input 2\n\n3 1 3\n\nSample Output 2\n\n0\n\nThe rectangles are already connected, and thus no move is needed.\n\nSample Input 3\n\n5 10 1\n\nSample Output 3\n\n4", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 911, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s679921709", "group_id": "codeNet:p03780", "input_text": "#include <iostream>\n#include <string>\n#include <utility>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <vector>\n#include <cmath>\n#include <cstdlib>\n#include <queue>\n#include <stack>\n#include <iomanip>\n\n\nusing namespace std;\n\n#define REP(i, n) for(ll i = 0;i < n;i++)\n#define REPR(i, n) for(ll i = n;i >= 0;i--)\n#define FOR(i, m, n) for(ll i = m;i < n;i++)\n#define FORR(i, m, n) for(int i = m;i >= n;i--)\n#define REPO(i, n) for(ll i = 1;i <= n;i++)\n#define ll long long\n#define INF (ll)1 << 60\n#define MINF (-1 * INF)\n#define ALL(n) n.begin(),n.end()\n#define MOD (ll)1000000007\n#define P pair<ll, ll>\n\n\nll n, k, s[5100], ans;\nll dat[1100010];\nvoid add(ll x, ll a) {\n\tx++;\n\tfor (ll i = x; i <= 5100; i += i & -i) dat[i] += a;\n}\n\nll sum(ll x) {\n\tif (x < 0)return 0;\n\tx++;\n\tll res = 0;\n\tfor (int i = x; i > 0; i -= i & -i) res += dat[i];\n\treturn res;\n}\n\n\nbool dp[5100][5100]; //上限5001\nint main() {\n\tcin >> n >> k;\n\tREP(i, n)cin >> s[i];\n\tdp[0][0] = 1;\n\tadd(0, 1);\n\tREP(i, n) {\n\t\tREP(j, k + 1) {\n\t\t\tif (dp[i][j]) {\n\t\t\t\tdp[i + 1][j] = true;\n\t\t\t\tdp[i + 1][min((ll)5001, j + s[i])] = true;\n\t\t\t}\n\t\t}\n\t}\n\tREPR(i, n - 1) {\n\t\tbool ok = true;\n\t\tREP(j, k) {\n\t\t\tif (dp[i][j]) {\n\t\t\t\tif (sum(max(0ll, k - 1 - j)) - sum(k - s[i] - 1 - j) > 0) {\n\t\t\t\t\tok = false;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif (ok)ans++;\n\t\tREPR(j, 5001) {\n\t\t\tif (sum(j) - sum(j - 1) > 0)add(min((ll)5001, j + s[i]), 1);\n\t\t}\n\t}\n\tcout << ans << endl;\n}\n", "language": "C++", "metadata": {"date": 1570703756, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03780.html", "problem_id": "p03780", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03780/input.txt", "sample_output_relpath": "derived/input_output/data/p03780/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03780/C++/s679921709.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s679921709", "user_id": "u196497077"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <iostream>\n#include <string>\n#include <utility>\n#include <algorithm>\n#include <map>\n#include <set>\n#include <vector>\n#include <cmath>\n#include <cstdlib>\n#include <queue>\n#include <stack>\n#include <iomanip>\n\n\nusing namespace std;\n\n#define REP(i, n) for(ll i = 0;i < n;i++)\n#define REPR(i, n) for(ll i = n;i >= 0;i--)\n#define FOR(i, m, n) for(ll i = m;i < n;i++)\n#define FORR(i, m, n) for(int i = m;i >= n;i--)\n#define REPO(i, n) for(ll i = 1;i <= n;i++)\n#define ll long long\n#define INF (ll)1 << 60\n#define MINF (-1 * INF)\n#define ALL(n) n.begin(),n.end()\n#define MOD (ll)1000000007\n#define P pair<ll, ll>\n\n\nll n, k, s[5100], ans;\nll dat[1100010];\nvoid add(ll x, ll a) {\n\tx++;\n\tfor (ll i = x; i <= 5100; i += i & -i) dat[i] += a;\n}\n\nll sum(ll x) {\n\tif (x < 0)return 0;\n\tx++;\n\tll res = 0;\n\tfor (int i = x; i > 0; i -= i & -i) res += dat[i];\n\treturn res;\n}\n\n\nbool dp[5100][5100]; //上限5001\nint main() {\n\tcin >> n >> k;\n\tREP(i, n)cin >> s[i];\n\tdp[0][0] = 1;\n\tadd(0, 1);\n\tREP(i, n) {\n\t\tREP(j, k + 1) {\n\t\t\tif (dp[i][j]) {\n\t\t\t\tdp[i + 1][j] = true;\n\t\t\t\tdp[i + 1][min((ll)5001, j + s[i])] = true;\n\t\t\t}\n\t\t}\n\t}\n\tREPR(i, n - 1) {\n\t\tbool ok = true;\n\t\tREP(j, k) {\n\t\t\tif (dp[i][j]) {\n\t\t\t\tif (sum(max(0ll, k - 1 - j)) - sum(k - s[i] - 1 - j) > 0) {\n\t\t\t\t\tok = false;\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t\tif (ok)ans++;\n\t\tREPR(j, 5001) {\n\t\t\tif (sum(j) - sum(j - 1) > 0)add(min((ll)5001, j + s[i]), 1);\n\t\t}\n\t}\n\tcout << ans << endl;\n}\n", "problem_context": "Score : 600 points\n\nProblem Statement\n\nAtCoDeer the deer has N cards with positive integers written on them. The number on the i-th card (1≤i≤N) is a_i.\nBecause he loves big numbers, he calls a subset of the cards good when the sum of the numbers written on the cards in the subset, is K or greater.\n\nThen, for each card i, he judges whether it is unnecessary or not, as follows:\n\nIf, for any good subset of the cards containing card i, the set that can be obtained by eliminating card i from the subset is also good, card i is unnecessary.\n\nOtherwise, card i is NOT unnecessary.\n\nFind the number of the unnecessary cards. Here, he judges each card independently, and he does not throw away cards that turn out to be unnecessary.\n\nConstraints\n\nAll input values are integers.\n\n1≤N≤5000\n\n1≤K≤5000\n\n1≤a_i≤10^9 (1≤i≤N)\n\nPartial Score\n\n300 points will be awarded for passing the test set satisfying N,K≤400.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN K\na_1 a_2 ... a_N\n\nOutput\n\nPrint the number of the unnecessary cards.\n\nSample Input 1\n\n3 6\n1 4 3\n\nSample Output 1\n\n1\n\nThere are two good sets: {2,3} and {1,2,3}.\n\nCard 1 is only contained in {1,2,3}, and this set without card 1, {2,3}, is also good. Thus, card 1 is unnecessary.\n\nFor card 2, a good set {2,3} without card 2, {3}, is not good. Thus, card 2 is NOT unnecessary.\n\nNeither is card 3 for a similar reason, hence the answer is 1.\n\nSample Input 2\n\n5 400\n3 1 4 1 5\n\nSample Output 2\n\n5\n\nIn this case, there is no good set. Therefore, all the cards are unnecessary.\n\nSample Input 3\n\n6 20\n10 4 3 10 25 2\n\nSample Output 3\n\n3", "sample_input": "3 6\n1 4 3\n"}, "reference_outputs": ["1\n"], "source_document_id": "p03780", "source_text": "Score : 600 points\n\nProblem Statement\n\nAtCoDeer the deer has N cards with positive integers written on them. The number on the i-th card (1≤i≤N) is a_i.\nBecause he loves big numbers, he calls a subset of the cards good when the sum of the numbers written on the cards in the subset, is K or greater.\n\nThen, for each card i, he judges whether it is unnecessary or not, as follows:\n\nIf, for any good subset of the cards containing card i, the set that can be obtained by eliminating card i from the subset is also good, card i is unnecessary.\n\nOtherwise, card i is NOT unnecessary.\n\nFind the number of the unnecessary cards. Here, he judges each card independently, and he does not throw away cards that turn out to be unnecessary.\n\nConstraints\n\nAll input values are integers.\n\n1≤N≤5000\n\n1≤K≤5000\n\n1≤a_i≤10^9 (1≤i≤N)\n\nPartial Score\n\n300 points will be awarded for passing the test set satisfying N,K≤400.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN K\na_1 a_2 ... a_N\n\nOutput\n\nPrint the number of the unnecessary cards.\n\nSample Input 1\n\n3 6\n1 4 3\n\nSample Output 1\n\n1\n\nThere are two good sets: {2,3} and {1,2,3}.\n\nCard 1 is only contained in {1,2,3}, and this set without card 1, {2,3}, is also good. Thus, card 1 is unnecessary.\n\nFor card 2, a good set {2,3} without card 2, {3}, is not good. Thus, card 2 is NOT unnecessary.\n\nNeither is card 3 for a similar reason, hence the answer is 1.\n\nSample Input 2\n\n5 400\n3 1 4 1 5\n\nSample Output 2\n\n5\n\nIn this case, there is no good set. Therefore, all the cards are unnecessary.\n\nSample Input 3\n\n6 20\n10 4 3 10 25 2\n\nSample Output 3\n\n3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1406, "cpu_time_ms": 849, "memory_kb": 26880}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s079736270", "group_id": "codeNet:p03786", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> Pii;\ntypedef pair<ll,ll> Pll;\n#define rep(i,n) for (ll i=0;i<n;++i)\n#define rep2(i,a,b) for (ll i=a;i<b;++i)\nconst ll MOD=1000000007;\nstring alp=\"abcdefghijklmnopqrstuvwxyz\";\n\nll N;\nvector<ll> A(100000),B(100000);\n\nbool can(int n){\n    auto itr=upper_bound(A.begin(),A.begin()+N,2*B[n]);\n    itr--;\n    if (itr-A.begin()==N-1){\n        return true;\n    }\n    else if (itr-A.begin()==n){\n        return false;\n    }\n    else {\n        return can(itr-A.begin());\n    }\n}\n\nint main(){\n    cin >> N;\n    rep(i,N){\n        cin >> A[i];\n    }\n    sort(A.begin(),A.begin()+N);\n    B[0]=A[0];\n    rep(i,N-1){\n        B[i+1]=B[i]+A[i+1];\n    }\n    ll lb=-1,ub=N;\n    while(ub-lb>1){\n        ll mid=(ub+lb)/2;\n        if (can(mid)){\n            ub=mid;\n        }\n        else {\n            lb=mid;\n        }\n    }\n    cout << N-ub << endl;\n}", "language": "C++", "metadata": {"date": 1569884132, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03786.html", "problem_id": "p03786", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03786/input.txt", "sample_output_relpath": "derived/input_output/data/p03786/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03786/C++/s079736270.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s079736270", "user_id": "u275786410"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> Pii;\ntypedef pair<ll,ll> Pll;\n#define rep(i,n) for (ll i=0;i<n;++i)\n#define rep2(i,a,b) for (ll i=a;i<b;++i)\nconst ll MOD=1000000007;\nstring alp=\"abcdefghijklmnopqrstuvwxyz\";\n\nll N;\nvector<ll> A(100000),B(100000);\n\nbool can(int n){\n    auto itr=upper_bound(A.begin(),A.begin()+N,2*B[n]);\n    itr--;\n    if (itr-A.begin()==N-1){\n        return true;\n    }\n    else if (itr-A.begin()==n){\n        return false;\n    }\n    else {\n        return can(itr-A.begin());\n    }\n}\n\nint main(){\n    cin >> N;\n    rep(i,N){\n        cin >> A[i];\n    }\n    sort(A.begin(),A.begin()+N);\n    B[0]=A[0];\n    rep(i,N-1){\n        B[i+1]=B[i]+A[i+1];\n    }\n    ll lb=-1,ub=N;\n    while(ub-lb>1){\n        ll mid=(ub+lb)/2;\n        if (can(mid)){\n            ub=mid;\n        }\n        else {\n            lb=mid;\n        }\n    }\n    cout << N-ub << endl;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nSnuke found N strange creatures.\nEach creature has a fixed color and size. The color and size of the i-th creature are represented by i and A_i, respectively.\n\nEvery creature can absorb another creature whose size is at most twice the size of itself.\nWhen a creature of size A and color B absorbs another creature of size C and color D (C \\leq 2 \\times A), they will merge into one creature of size A+C and color B.\nHere, depending on the sizes of two creatures, it is possible that both of them can absorb the other.\n\nSnuke has been watching these creatures merge over and over and ultimately become one creature.\nFind the number of the possible colors of this creature.\n\nConstraints\n\n2 \\leq N \\leq 100000\n\n1 \\leq A_i \\leq 10^9\n\nA_i is an integer.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1 A_2 … A_N\n\nOutput\n\nPrint the number of the possible colors of the last remaining creature after the N creatures repeatedly merge and ultimately become one creature.\n\nSample Input 1\n\n3\n3 1 4\n\nSample Output 1\n\n2\n\nThe possible colors of the last remaining creature are colors 1 and 3.\nFor example, when the creature of color 3 absorbs the creature of color 2, then the creature of color 1 absorbs the creature of color 3, the color of the last remaining creature will be color 1.\n\nSample Input 2\n\n5\n1 1 1 1 1\n\nSample Output 2\n\n5\n\nThere may be multiple creatures of the same size.\n\nSample Input 3\n\n6\n40 1 30 2 7 20\n\nSample Output 3\n\n4", "sample_input": "3\n3 1 4\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03786", "source_text": "Score : 400 points\n\nProblem Statement\n\nSnuke found N strange creatures.\nEach creature has a fixed color and size. The color and size of the i-th creature are represented by i and A_i, respectively.\n\nEvery creature can absorb another creature whose size is at most twice the size of itself.\nWhen a creature of size A and color B absorbs another creature of size C and color D (C \\leq 2 \\times A), they will merge into one creature of size A+C and color B.\nHere, depending on the sizes of two creatures, it is possible that both of them can absorb the other.\n\nSnuke has been watching these creatures merge over and over and ultimately become one creature.\nFind the number of the possible colors of this creature.\n\nConstraints\n\n2 \\leq N \\leq 100000\n\n1 \\leq A_i \\leq 10^9\n\nA_i is an integer.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1 A_2 … A_N\n\nOutput\n\nPrint the number of the possible colors of the last remaining creature after the N creatures repeatedly merge and ultimately become one creature.\n\nSample Input 1\n\n3\n3 1 4\n\nSample Output 1\n\n2\n\nThe possible colors of the last remaining creature are colors 1 and 3.\nFor example, when the creature of color 3 absorbs the creature of color 2, then the creature of color 1 absorbs the creature of color 3, the color of the last remaining creature will be color 1.\n\nSample Input 2\n\n5\n1 1 1 1 1\n\nSample Output 2\n\n5\n\nThere may be multiple creatures of the same size.\n\nSample Input 3\n\n6\n40 1 30 2 7 20\n\nSample Output 3\n\n4", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 921, "cpu_time_ms": 48, "memory_kb": 1920}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s777533285", "group_id": "codeNet:p03791", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define pb         push_back\n\ntypedef long long ll;\nconst ll INF = 1000000000000000000ll;\nconst ll MOD = 1000000007ll;\nconst double EPS = 1e-8;\n\nint main(void) {\n\t//ios_base::sync_with_stdio(false);\n\t//cin.tie(0);\n\t\n\tll n;\n\tcin >> n;\n\n\tvector<ll> x;\n\tfor(int i=0; i<n; i++){\n\t\tll t;\n\t\tcin >> t;\n\t\tx.pb(t);\n\t}\n\n\n\t/*\n\tfor(int i=0; i<n; i++){\n\t\tprintf(\"%d \", x[i]);\n\t}\n\tputs(\"\");\n\t*/\n\n\tll ans = 1;\n\n\tint sn = n;\n\tfor(int k=0; k<sn; k++){\n\t\tmap<ll, int> use;\n\t\tif(x[0] > 1) x[0] = 1;\n\t\tuse[x[0]] = 1;\n\t\tfor(int i=1; i<n; i++){\n\t\t\tif(x[i-1] + 2 < x[i]){\n\t\t\t\tx[i] = x[i-1] + 2;\n\t\t\t}\n\t\t\t//printf(\"%d \", x[i]);\n\t\t\tuse[x[i]] = 1;\n\t\t}\n\n\t\tll cnt = 0;\n\t\tfor(int i=2; i<n; i++){\n\t\t\tfor(int j=0; j<i; j++){\n\t\t\t\tif(use.find(x[j]-1) != use.end()){\n\t\t\t\t\tcnt++;\n\t\t\t\t\tbreak;\n\t\t\t\t}else{\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tvector<ll> next;\n\t\tfor(int i=1; i<n;i ++){\n\t\t\tnext.pb(x[i]);\n\t\t}\n\t\tx = next;\n\t\tans *= (n-cnt);\n\t\tans %= MOD;\n\t\tn--;\n\t}\n\n\n\t//printf(\"cnt:%d\\n\", cnt);\n\t/*\n\tll ans = n - cnt;\n\tfor(int i=1; i<=n-1; i++){\n\t\tans *= i;\n\t\tans %= MOD;\n\t}\n\t*/\n\n\tcout << ans << endl;\n\t\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1488081296, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03791.html", "problem_id": "p03791", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03791/input.txt", "sample_output_relpath": "derived/input_output/data/p03791/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03791/C++/s777533285.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s777533285", "user_id": "u753982487"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define pb         push_back\n\ntypedef long long ll;\nconst ll INF = 1000000000000000000ll;\nconst ll MOD = 1000000007ll;\nconst double EPS = 1e-8;\n\nint main(void) {\n\t//ios_base::sync_with_stdio(false);\n\t//cin.tie(0);\n\t\n\tll n;\n\tcin >> n;\n\n\tvector<ll> x;\n\tfor(int i=0; i<n; i++){\n\t\tll t;\n\t\tcin >> t;\n\t\tx.pb(t);\n\t}\n\n\n\t/*\n\tfor(int i=0; i<n; i++){\n\t\tprintf(\"%d \", x[i]);\n\t}\n\tputs(\"\");\n\t*/\n\n\tll ans = 1;\n\n\tint sn = n;\n\tfor(int k=0; k<sn; k++){\n\t\tmap<ll, int> use;\n\t\tif(x[0] > 1) x[0] = 1;\n\t\tuse[x[0]] = 1;\n\t\tfor(int i=1; i<n; i++){\n\t\t\tif(x[i-1] + 2 < x[i]){\n\t\t\t\tx[i] = x[i-1] + 2;\n\t\t\t}\n\t\t\t//printf(\"%d \", x[i]);\n\t\t\tuse[x[i]] = 1;\n\t\t}\n\n\t\tll cnt = 0;\n\t\tfor(int i=2; i<n; i++){\n\t\t\tfor(int j=0; j<i; j++){\n\t\t\t\tif(use.find(x[j]-1) != use.end()){\n\t\t\t\t\tcnt++;\n\t\t\t\t\tbreak;\n\t\t\t\t}else{\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\n\t\tvector<ll> next;\n\t\tfor(int i=1; i<n;i ++){\n\t\t\tnext.pb(x[i]);\n\t\t}\n\t\tx = next;\n\t\tans *= (n-cnt);\n\t\tans %= MOD;\n\t\tn--;\n\t}\n\n\n\t//printf(\"cnt:%d\\n\", cnt);\n\t/*\n\tll ans = n - cnt;\n\tfor(int i=1; i<=n-1; i++){\n\t\tans *= i;\n\t\tans %= MOD;\n\t}\n\t*/\n\n\tcout << ans << endl;\n\t\n\treturn 0;\n}\n", "problem_context": "Score : 900 points\n\nProblem Statement\n\nYou are developing frog-shaped robots, and decided to race them against each other.\n\nFirst, you placed N robots onto a number line.\nThese robots are numbered 1 through N.\nThe current coordinate of robot i is x_i.\nHere, all x_i are integers, and 0 < x_1 < x_2 < ... < x_N.\n\nYou will repeatedly perform the following operation:\n\nSelect a robot on the number line. Let the coordinate of the robot be x. Select the destination coordinate, either x-1 or x-2, that is not occupied by another robot. The robot now jumps to the selected coordinate.\n\nWhen the coordinate of a robot becomes 0 or less, the robot is considered finished and will be removed from the number line immediately.\nYou will repeat the operation until all the robots finish the race.\n\nDepending on your choice in the operation, the N robots can finish the race in different orders.\nIn how many different orders can the N robots finish the race?\nFind the answer modulo 10^9+7.\n\nConstraints\n\n2 ≤ N ≤ 10^5\n\nx_i is an integer.\n\n0 < x_1 < x_2 < ... < x_N ≤ 10^9\n\nPartial Score\n\nIn a test set worth 500 points, N ≤ 8.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nx_1 x_2 ... x_N\n\nOutput\n\nPrint the number of the different orders in which the N robots can finish the race, modulo 10^9+7.\n\nSample Input 1\n\n3\n1 2 3\n\nSample Output 1\n\n4\n\nThere are four different orders in which the three robots can finish the race:\n\n(Robot 1 → Robot 2 → Robot 3)\n\n(Robot 1 → Robot 3 → Robot 2)\n\n(Robot 2 → Robot 1 → Robot 3)\n\n(Robot 2 → Robot 3 → Robot 1)\n\nSample Input 2\n\n3\n2 3 4\n\nSample Output 2\n\n6\n\nThere are six different orders in which the three robots can finish the race:\n\n(Robot 1 → Robot 2 → Robot 3)\n\n(Robot 1 → Robot 3 → Robot 2)\n\n(Robot 2 → Robot 1 → Robot 3)\n\n(Robot 2 → Robot 3 → Robot 1)\n\n(Robot 3 → Robot 1 → Robot 2)\n\n(Robot 3 → Robot 2 → Robot 1)\n\nFor example, the order (Robot 3 → Robot 2 → Robot 1) can be achieved as shown in the figure below:\n\nSample Input 3\n\n8\n1 2 3 5 7 11 13 17\n\nSample Output 3\n\n10080\n\nSample Input 4\n\n13\n4 6 8 9 10 12 14 15 16 18 20 21 22\n\nSample Output 4\n\n311014372\n\nRemember to print the answer modulo 10^9+7.\nThis case is not included in the test set for the partial score.", "sample_input": "3\n1 2 3\n"}, "reference_outputs": ["4\n"], "source_document_id": "p03791", "source_text": "Score : 900 points\n\nProblem Statement\n\nYou are developing frog-shaped robots, and decided to race them against each other.\n\nFirst, you placed N robots onto a number line.\nThese robots are numbered 1 through N.\nThe current coordinate of robot i is x_i.\nHere, all x_i are integers, and 0 < x_1 < x_2 < ... < x_N.\n\nYou will repeatedly perform the following operation:\n\nSelect a robot on the number line. Let the coordinate of the robot be x. Select the destination coordinate, either x-1 or x-2, that is not occupied by another robot. The robot now jumps to the selected coordinate.\n\nWhen the coordinate of a robot becomes 0 or less, the robot is considered finished and will be removed from the number line immediately.\nYou will repeat the operation until all the robots finish the race.\n\nDepending on your choice in the operation, the N robots can finish the race in different orders.\nIn how many different orders can the N robots finish the race?\nFind the answer modulo 10^9+7.\n\nConstraints\n\n2 ≤ N ≤ 10^5\n\nx_i is an integer.\n\n0 < x_1 < x_2 < ... < x_N ≤ 10^9\n\nPartial Score\n\nIn a test set worth 500 points, N ≤ 8.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nx_1 x_2 ... x_N\n\nOutput\n\nPrint the number of the different orders in which the N robots can finish the race, modulo 10^9+7.\n\nSample Input 1\n\n3\n1 2 3\n\nSample Output 1\n\n4\n\nThere are four different orders in which the three robots can finish the race:\n\n(Robot 1 → Robot 2 → Robot 3)\n\n(Robot 1 → Robot 3 → Robot 2)\n\n(Robot 2 → Robot 1 → Robot 3)\n\n(Robot 2 → Robot 3 → Robot 1)\n\nSample Input 2\n\n3\n2 3 4\n\nSample Output 2\n\n6\n\nThere are six different orders in which the three robots can finish the race:\n\n(Robot 1 → Robot 2 → Robot 3)\n\n(Robot 1 → Robot 3 → Robot 2)\n\n(Robot 2 → Robot 1 → Robot 3)\n\n(Robot 2 → Robot 3 → Robot 1)\n\n(Robot 3 → Robot 1 → Robot 2)\n\n(Robot 3 → Robot 2 → Robot 1)\n\nFor example, the order (Robot 3 → Robot 2 → Robot 1) can be achieved as shown in the figure below:\n\nSample Input 3\n\n8\n1 2 3 5 7 11 13 17\n\nSample Output 3\n\n10080\n\nSample Input 4\n\n13\n4 6 8 9 10 12 14 15 16 18 20 21 22\n\nSample Output 4\n\n311014372\n\nRemember to print the answer modulo 10^9+7.\nThis case is not included in the test set for the partial score.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1103, "cpu_time_ms": 2104, "memory_kb": 9304}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s189444438", "group_id": "codeNet:p03791", "input_text": "#include<iostream>\n#include<cstdio>\n#include<algorithm>\n#define P 1000000007\n#define ll long long\nusing namespace std;\nll n,a[100005];\nint main()\n{\n\tscanf(\"%lld\",&n);\n\tfor (ll i=1;i<=n;i++)\n\t\tscanf(\"%lld\",&a[i]);\n\tsort(a+1,a+n+1);\n\tll Ans=1,sum=0;\n\tfor (ll i=1;i<=n;i++)\n\t{\n\t//\tcout<<Ans<<' '<<sum<<endl;\n\t\tif (sum*2+1>a[i]+1)\n\t\t\tAns=Ans*sum%P;\n\t\telse\n\t\tif (sum*2+1==a[i]+1) Ans=Ans*(sum+1)%P;\n\t\telse sum++;\n\t//cout<<Ans<<' '<<sum<<endl;\n\t}\n\twhile(sum) Ans=Ans*(sum--)%P;\n\tprintf(\"%lld\\n\",Ans);\n}", "language": "C++", "metadata": {"date": 1488076065, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03791.html", "problem_id": "p03791", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03791/input.txt", "sample_output_relpath": "derived/input_output/data/p03791/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03791/C++/s189444438.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s189444438", "user_id": "u908136050"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include<iostream>\n#include<cstdio>\n#include<algorithm>\n#define P 1000000007\n#define ll long long\nusing namespace std;\nll n,a[100005];\nint main()\n{\n\tscanf(\"%lld\",&n);\n\tfor (ll i=1;i<=n;i++)\n\t\tscanf(\"%lld\",&a[i]);\n\tsort(a+1,a+n+1);\n\tll Ans=1,sum=0;\n\tfor (ll i=1;i<=n;i++)\n\t{\n\t//\tcout<<Ans<<' '<<sum<<endl;\n\t\tif (sum*2+1>a[i]+1)\n\t\t\tAns=Ans*sum%P;\n\t\telse\n\t\tif (sum*2+1==a[i]+1) Ans=Ans*(sum+1)%P;\n\t\telse sum++;\n\t//cout<<Ans<<' '<<sum<<endl;\n\t}\n\twhile(sum) Ans=Ans*(sum--)%P;\n\tprintf(\"%lld\\n\",Ans);\n}", "problem_context": "Score : 900 points\n\nProblem Statement\n\nYou are developing frog-shaped robots, and decided to race them against each other.\n\nFirst, you placed N robots onto a number line.\nThese robots are numbered 1 through N.\nThe current coordinate of robot i is x_i.\nHere, all x_i are integers, and 0 < x_1 < x_2 < ... < x_N.\n\nYou will repeatedly perform the following operation:\n\nSelect a robot on the number line. Let the coordinate of the robot be x. Select the destination coordinate, either x-1 or x-2, that is not occupied by another robot. The robot now jumps to the selected coordinate.\n\nWhen the coordinate of a robot becomes 0 or less, the robot is considered finished and will be removed from the number line immediately.\nYou will repeat the operation until all the robots finish the race.\n\nDepending on your choice in the operation, the N robots can finish the race in different orders.\nIn how many different orders can the N robots finish the race?\nFind the answer modulo 10^9+7.\n\nConstraints\n\n2 ≤ N ≤ 10^5\n\nx_i is an integer.\n\n0 < x_1 < x_2 < ... < x_N ≤ 10^9\n\nPartial Score\n\nIn a test set worth 500 points, N ≤ 8.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nx_1 x_2 ... x_N\n\nOutput\n\nPrint the number of the different orders in which the N robots can finish the race, modulo 10^9+7.\n\nSample Input 1\n\n3\n1 2 3\n\nSample Output 1\n\n4\n\nThere are four different orders in which the three robots can finish the race:\n\n(Robot 1 → Robot 2 → Robot 3)\n\n(Robot 1 → Robot 3 → Robot 2)\n\n(Robot 2 → Robot 1 → Robot 3)\n\n(Robot 2 → Robot 3 → Robot 1)\n\nSample Input 2\n\n3\n2 3 4\n\nSample Output 2\n\n6\n\nThere are six different orders in which the three robots can finish the race:\n\n(Robot 1 → Robot 2 → Robot 3)\n\n(Robot 1 → Robot 3 → Robot 2)\n\n(Robot 2 → Robot 1 → Robot 3)\n\n(Robot 2 → Robot 3 → Robot 1)\n\n(Robot 3 → Robot 1 → Robot 2)\n\n(Robot 3 → Robot 2 → Robot 1)\n\nFor example, the order (Robot 3 → Robot 2 → Robot 1) can be achieved as shown in the figure below:\n\nSample Input 3\n\n8\n1 2 3 5 7 11 13 17\n\nSample Output 3\n\n10080\n\nSample Input 4\n\n13\n4 6 8 9 10 12 14 15 16 18 20 21 22\n\nSample Output 4\n\n311014372\n\nRemember to print the answer modulo 10^9+7.\nThis case is not included in the test set for the partial score.", "sample_input": "3\n1 2 3\n"}, "reference_outputs": ["4\n"], "source_document_id": "p03791", "source_text": "Score : 900 points\n\nProblem Statement\n\nYou are developing frog-shaped robots, and decided to race them against each other.\n\nFirst, you placed N robots onto a number line.\nThese robots are numbered 1 through N.\nThe current coordinate of robot i is x_i.\nHere, all x_i are integers, and 0 < x_1 < x_2 < ... < x_N.\n\nYou will repeatedly perform the following operation:\n\nSelect a robot on the number line. Let the coordinate of the robot be x. Select the destination coordinate, either x-1 or x-2, that is not occupied by another robot. The robot now jumps to the selected coordinate.\n\nWhen the coordinate of a robot becomes 0 or less, the robot is considered finished and will be removed from the number line immediately.\nYou will repeat the operation until all the robots finish the race.\n\nDepending on your choice in the operation, the N robots can finish the race in different orders.\nIn how many different orders can the N robots finish the race?\nFind the answer modulo 10^9+7.\n\nConstraints\n\n2 ≤ N ≤ 10^5\n\nx_i is an integer.\n\n0 < x_1 < x_2 < ... < x_N ≤ 10^9\n\nPartial Score\n\nIn a test set worth 500 points, N ≤ 8.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nx_1 x_2 ... x_N\n\nOutput\n\nPrint the number of the different orders in which the N robots can finish the race, modulo 10^9+7.\n\nSample Input 1\n\n3\n1 2 3\n\nSample Output 1\n\n4\n\nThere are four different orders in which the three robots can finish the race:\n\n(Robot 1 → Robot 2 → Robot 3)\n\n(Robot 1 → Robot 3 → Robot 2)\n\n(Robot 2 → Robot 1 → Robot 3)\n\n(Robot 2 → Robot 3 → Robot 1)\n\nSample Input 2\n\n3\n2 3 4\n\nSample Output 2\n\n6\n\nThere are six different orders in which the three robots can finish the race:\n\n(Robot 1 → Robot 2 → Robot 3)\n\n(Robot 1 → Robot 3 → Robot 2)\n\n(Robot 2 → Robot 1 → Robot 3)\n\n(Robot 2 → Robot 3 → Robot 1)\n\n(Robot 3 → Robot 1 → Robot 2)\n\n(Robot 3 → Robot 2 → Robot 1)\n\nFor example, the order (Robot 3 → Robot 2 → Robot 1) can be achieved as shown in the figure below:\n\nSample Input 3\n\n8\n1 2 3 5 7 11 13 17\n\nSample Output 3\n\n10080\n\nSample Input 4\n\n13\n4 6 8 9 10 12 14 15 16 18 20 21 22\n\nSample Output 4\n\n311014372\n\nRemember to print the answer modulo 10^9+7.\nThis case is not included in the test set for the partial score.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 496, "cpu_time_ms": 14, "memory_kb": 1024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s213712321", "group_id": "codeNet:p03792", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nchar mas[510][510];\n\nint main(){\n    int n;\n    cin >> n;\n\n    for(int i = 0;i < n;i++){\n        cin >> mas[i];\n    }\n\n    int last = 0;\n    for(int j = 0;j < n;j++){\n        int cnt = 0;\n        for(int i = 0;i < n;i++){\n            cnt += mas[i][j] == '.' ? 1 : 0;\n        }\n        if(cnt != 0) last++;\n    }\n\n    int ans = INT_MAX;\n    for(int i = 0;i < n;i++){\n        int cnt = 0;\n        for(int j = 0;j < n;j++){\n            if(mas[i][j] == '.'){\n                cnt++;\n            }\n        }\n        if(cnt != n){\n            if(mas[i][i] == '.'){\n                cnt++;\n            }\n            ans = min(ans, cnt);\n        }\n    }\n\n    if(ans == INT_MAX){\n        cout << -1 << endl;\n    }else{\n        cout << ans + last << endl;\n    }\n\n    return 0;\n}\n\n\n", "language": "C++", "metadata": {"date": 1564958656, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03792.html", "problem_id": "p03792", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03792/input.txt", "sample_output_relpath": "derived/input_output/data/p03792/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03792/C++/s213712321.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s213712321", "user_id": "u221119670"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nchar mas[510][510];\n\nint main(){\n    int n;\n    cin >> n;\n\n    for(int i = 0;i < n;i++){\n        cin >> mas[i];\n    }\n\n    int last = 0;\n    for(int j = 0;j < n;j++){\n        int cnt = 0;\n        for(int i = 0;i < n;i++){\n            cnt += mas[i][j] == '.' ? 1 : 0;\n        }\n        if(cnt != 0) last++;\n    }\n\n    int ans = INT_MAX;\n    for(int i = 0;i < n;i++){\n        int cnt = 0;\n        for(int j = 0;j < n;j++){\n            if(mas[i][j] == '.'){\n                cnt++;\n            }\n        }\n        if(cnt != n){\n            if(mas[i][i] == '.'){\n                cnt++;\n            }\n            ans = min(ans, cnt);\n        }\n    }\n\n    if(ans == INT_MAX){\n        cout << -1 << endl;\n    }else{\n        cout << ans + last << endl;\n    }\n\n    return 0;\n}\n\n\n", "problem_context": "Score : 1300 points\n\nProblem Statement\n\nThere is a square-shaped grid with N vertical rows and N horizontal columns.\nWe will denote the square at the i-th row from the top and the j-th column from the left as (i,\\ j).\n\nInitially, each square is either white or black.\nThe initial color of the grid is given to you as characters a_{ij}, arranged in a square shape.\nIf the square (i,\\ j) is white, a_{ij} is .. If it is black, a_{ij} is #.\n\nYou are developing a robot that repaints the grid.\nIt can repeatedly perform the following operation:\n\nSelect two integers i, j (1 ≤ i,\\ j ≤ N). Memorize the colors of the squares (i,\\ 1), (i,\\ 2), ..., (i,\\ N) as c_1, c_2, ..., c_N, respectively. Then, repaint the squares (1,\\ j), (2,\\ j), ..., (N,\\ j) with the colors c_1, c_2, ..., c_N, respectively.\n\nYour objective is to turn all the squares black.\nDetermine whether it is possible, and find the minimum necessary number of operations to achieve it if the answer is positive.\n\nConstraints\n\n2 ≤ N ≤ 500\n\na_{ij} is either . or #.\n\nPartial Score\n\nIn a test set worth 300 points, N ≤ 3.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\na_{11}...a_{1N}\n:\na_{N1}...a_{NN}\n\nOutput\n\nIf it is possible to turn all the squares black, print the minimum necessary number of operations to achieve the objective.\nIf it is impossible, print -1 instead.\n\nSample Input 1\n\n2\n#.\n.#\n\nSample Output 1\n\n3\n\nFor example, perform the operation as follows:\n\nSelect i = 1, j = 2.\n\nSelect i = 1, j = 1.\n\nSelect i = 1, j = 2.\n\nThe transition of the colors of the squares is shown in the figure below:\n\nSample Input 2\n\n2\n..\n..\n\nSample Output 2\n\n-1\n\nSample Input 3\n\n2\n##\n##\n\nSample Output 3\n\n0\n\nSample Input 4\n\n3\n.#.\n###\n.#.\n\nSample Output 4\n\n2\n\nSample Input 5\n\n3\n...\n.#.\n...\n\nSample Output 5\n\n5", "sample_input": "2\n#.\n.#\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03792", "source_text": "Score : 1300 points\n\nProblem Statement\n\nThere is a square-shaped grid with N vertical rows and N horizontal columns.\nWe will denote the square at the i-th row from the top and the j-th column from the left as (i,\\ j).\n\nInitially, each square is either white or black.\nThe initial color of the grid is given to you as characters a_{ij}, arranged in a square shape.\nIf the square (i,\\ j) is white, a_{ij} is .. If it is black, a_{ij} is #.\n\nYou are developing a robot that repaints the grid.\nIt can repeatedly perform the following operation:\n\nSelect two integers i, j (1 ≤ i,\\ j ≤ N). Memorize the colors of the squares (i,\\ 1), (i,\\ 2), ..., (i,\\ N) as c_1, c_2, ..., c_N, respectively. Then, repaint the squares (1,\\ j), (2,\\ j), ..., (N,\\ j) with the colors c_1, c_2, ..., c_N, respectively.\n\nYour objective is to turn all the squares black.\nDetermine whether it is possible, and find the minimum necessary number of operations to achieve it if the answer is positive.\n\nConstraints\n\n2 ≤ N ≤ 500\n\na_{ij} is either . or #.\n\nPartial Score\n\nIn a test set worth 300 points, N ≤ 3.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\na_{11}...a_{1N}\n:\na_{N1}...a_{NN}\n\nOutput\n\nIf it is possible to turn all the squares black, print the minimum necessary number of operations to achieve the objective.\nIf it is impossible, print -1 instead.\n\nSample Input 1\n\n2\n#.\n.#\n\nSample Output 1\n\n3\n\nFor example, perform the operation as follows:\n\nSelect i = 1, j = 2.\n\nSelect i = 1, j = 1.\n\nSelect i = 1, j = 2.\n\nThe transition of the colors of the squares is shown in the figure below:\n\nSample Input 2\n\n2\n..\n..\n\nSample Output 2\n\n-1\n\nSample Input 3\n\n2\n##\n##\n\nSample Output 3\n\n0\n\nSample Input 4\n\n3\n.#.\n###\n.#.\n\nSample Output 4\n\n2\n\nSample Input 5\n\n3\n...\n.#.\n...\n\nSample Output 5\n\n5", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 816, "cpu_time_ms": 9, "memory_kb": 512}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s369999618", "group_id": "codeNet:p03792", "input_text": "#include <iostream>\n#include <string>\n#include <vector>\nusing namespace std;\n \nint n;\nstring s[3];\nint dp[512];\n \nint encode(vector<string> ss) {\n\tint ret = 0;\n\tfor (int i = 0; i < n; i++) {\n\t\tfor (int j = 0; j < n; j++) {\n\t\t\tint type = (ss[i][j] == '.' ? 1 : 0);\n\t\t\tret += (type << (i * n + j));\n\t\t}\n\t}\n\treturn ret;\n}\n \nvoid print(vector<string> ss) {\n\tfor (int i = 0; i < 3; i++) {\n\t\tcout << ss[i] << endl;\n\t}\n\tcout << endl;\n}\n \nint INF = 11451419;\n \nint dfs(vector<string> ss) {\n\t//print(ss);\n\tint state = encode(ss);\n\tif (state == 0) return 0;\t\t\t\t//完成\n\tif (dp[state] == -1) return INF;\t\t//探索中\n\tif (dp[state] >= 0) return dp[state];\t//答えが分かっている\n\t\n\tdp[state] = -1;\n\tint i, j, k;\n\tint ret = INF;\n\t\n\tfor (i = 0; i < n; i++) {\n\t\tfor (j = 0; j < n; j++) {\n\t\t\tvector<string> ns = ss;\n\t\t\tfor (k = 0; k < n; k++) {\n\t\t\t\tns[k][j] = ss[i][k];\n\t\t\t}\n\t\t\tret = min(ret, dfs(ns) + 1);\n\t\t}\n\t}\n\tdp[state] = ret;\n\treturn ret;\n}\n \nint main() {\n\tcin >> n;\n\tfor (int i = 0; i < n; i++) cin >> s[i];\n\t\n\tvector<string> ss;\n\tfor (int i = 0; i < n; i++) ss.push_back(s[i]);\n\tfor (int i = 0; i < 512; i++) dp[i] = -2;\n\t\n\tint res = dfs(ss);\n\tif (res < INF) cout << res - 1 << endl;\n\telse { cout << -1 << endl; }\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1488156499, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03792.html", "problem_id": "p03792", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03792/input.txt", "sample_output_relpath": "derived/input_output/data/p03792/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03792/C++/s369999618.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s369999618", "user_id": "u610441939"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <iostream>\n#include <string>\n#include <vector>\nusing namespace std;\n \nint n;\nstring s[3];\nint dp[512];\n \nint encode(vector<string> ss) {\n\tint ret = 0;\n\tfor (int i = 0; i < n; i++) {\n\t\tfor (int j = 0; j < n; j++) {\n\t\t\tint type = (ss[i][j] == '.' ? 1 : 0);\n\t\t\tret += (type << (i * n + j));\n\t\t}\n\t}\n\treturn ret;\n}\n \nvoid print(vector<string> ss) {\n\tfor (int i = 0; i < 3; i++) {\n\t\tcout << ss[i] << endl;\n\t}\n\tcout << endl;\n}\n \nint INF = 11451419;\n \nint dfs(vector<string> ss) {\n\t//print(ss);\n\tint state = encode(ss);\n\tif (state == 0) return 0;\t\t\t\t//完成\n\tif (dp[state] == -1) return INF;\t\t//探索中\n\tif (dp[state] >= 0) return dp[state];\t//答えが分かっている\n\t\n\tdp[state] = -1;\n\tint i, j, k;\n\tint ret = INF;\n\t\n\tfor (i = 0; i < n; i++) {\n\t\tfor (j = 0; j < n; j++) {\n\t\t\tvector<string> ns = ss;\n\t\t\tfor (k = 0; k < n; k++) {\n\t\t\t\tns[k][j] = ss[i][k];\n\t\t\t}\n\t\t\tret = min(ret, dfs(ns) + 1);\n\t\t}\n\t}\n\tdp[state] = ret;\n\treturn ret;\n}\n \nint main() {\n\tcin >> n;\n\tfor (int i = 0; i < n; i++) cin >> s[i];\n\t\n\tvector<string> ss;\n\tfor (int i = 0; i < n; i++) ss.push_back(s[i]);\n\tfor (int i = 0; i < 512; i++) dp[i] = -2;\n\t\n\tint res = dfs(ss);\n\tif (res < INF) cout << res - 1 << endl;\n\telse { cout << -1 << endl; }\n\treturn 0;\n}", "problem_context": "Score : 1300 points\n\nProblem Statement\n\nThere is a square-shaped grid with N vertical rows and N horizontal columns.\nWe will denote the square at the i-th row from the top and the j-th column from the left as (i,\\ j).\n\nInitially, each square is either white or black.\nThe initial color of the grid is given to you as characters a_{ij}, arranged in a square shape.\nIf the square (i,\\ j) is white, a_{ij} is .. If it is black, a_{ij} is #.\n\nYou are developing a robot that repaints the grid.\nIt can repeatedly perform the following operation:\n\nSelect two integers i, j (1 ≤ i,\\ j ≤ N). Memorize the colors of the squares (i,\\ 1), (i,\\ 2), ..., (i,\\ N) as c_1, c_2, ..., c_N, respectively. Then, repaint the squares (1,\\ j), (2,\\ j), ..., (N,\\ j) with the colors c_1, c_2, ..., c_N, respectively.\n\nYour objective is to turn all the squares black.\nDetermine whether it is possible, and find the minimum necessary number of operations to achieve it if the answer is positive.\n\nConstraints\n\n2 ≤ N ≤ 500\n\na_{ij} is either . or #.\n\nPartial Score\n\nIn a test set worth 300 points, N ≤ 3.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\na_{11}...a_{1N}\n:\na_{N1}...a_{NN}\n\nOutput\n\nIf it is possible to turn all the squares black, print the minimum necessary number of operations to achieve the objective.\nIf it is impossible, print -1 instead.\n\nSample Input 1\n\n2\n#.\n.#\n\nSample Output 1\n\n3\n\nFor example, perform the operation as follows:\n\nSelect i = 1, j = 2.\n\nSelect i = 1, j = 1.\n\nSelect i = 1, j = 2.\n\nThe transition of the colors of the squares is shown in the figure below:\n\nSample Input 2\n\n2\n..\n..\n\nSample Output 2\n\n-1\n\nSample Input 3\n\n2\n##\n##\n\nSample Output 3\n\n0\n\nSample Input 4\n\n3\n.#.\n###\n.#.\n\nSample Output 4\n\n2\n\nSample Input 5\n\n3\n...\n.#.\n...\n\nSample Output 5\n\n5", "sample_input": "2\n#.\n.#\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03792", "source_text": "Score : 1300 points\n\nProblem Statement\n\nThere is a square-shaped grid with N vertical rows and N horizontal columns.\nWe will denote the square at the i-th row from the top and the j-th column from the left as (i,\\ j).\n\nInitially, each square is either white or black.\nThe initial color of the grid is given to you as characters a_{ij}, arranged in a square shape.\nIf the square (i,\\ j) is white, a_{ij} is .. If it is black, a_{ij} is #.\n\nYou are developing a robot that repaints the grid.\nIt can repeatedly perform the following operation:\n\nSelect two integers i, j (1 ≤ i,\\ j ≤ N). Memorize the colors of the squares (i,\\ 1), (i,\\ 2), ..., (i,\\ N) as c_1, c_2, ..., c_N, respectively. Then, repaint the squares (1,\\ j), (2,\\ j), ..., (N,\\ j) with the colors c_1, c_2, ..., c_N, respectively.\n\nYour objective is to turn all the squares black.\nDetermine whether it is possible, and find the minimum necessary number of operations to achieve it if the answer is positive.\n\nConstraints\n\n2 ≤ N ≤ 500\n\na_{ij} is either . or #.\n\nPartial Score\n\nIn a test set worth 300 points, N ≤ 3.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\na_{11}...a_{1N}\n:\na_{N1}...a_{NN}\n\nOutput\n\nIf it is possible to turn all the squares black, print the minimum necessary number of operations to achieve the objective.\nIf it is impossible, print -1 instead.\n\nSample Input 1\n\n2\n#.\n.#\n\nSample Output 1\n\n3\n\nFor example, perform the operation as follows:\n\nSelect i = 1, j = 2.\n\nSelect i = 1, j = 1.\n\nSelect i = 1, j = 2.\n\nThe transition of the colors of the squares is shown in the figure below:\n\nSample Input 2\n\n2\n..\n..\n\nSample Output 2\n\n-1\n\nSample Input 3\n\n2\n##\n##\n\nSample Output 3\n\n0\n\nSample Input 4\n\n3\n.#.\n###\n.#.\n\nSample Output 4\n\n2\n\nSample Input 5\n\n3\n...\n.#.\n...\n\nSample Output 5\n\n5", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1227, "cpu_time_ms": 98, "memory_kb": 384}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s333090710", "group_id": "codeNet:p03795", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nint n,total;\nint main () {\ncin >> n;\ntotal = n*800 - n/15*200;\ncout << total << endl;\n\n}\n", "language": "C++", "metadata": {"date": 1570282749, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03795.html", "problem_id": "p03795", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03795/input.txt", "sample_output_relpath": "derived/input_output/data/p03795/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03795/C++/s333090710.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s333090710", "user_id": "u353919145"}, "prompt_components": {"gold_output": "15800\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nint n,total;\nint main () {\ncin >> n;\ntotal = n*800 - n/15*200;\ncout << total << endl;\n\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nSnuke has a favorite restaurant.\n\nThe price of any meal served at the restaurant is 800 yen (the currency of Japan), and each time a customer orders 15 meals, the restaurant pays 200 yen back to the customer.\n\nSo far, Snuke has ordered N meals at the restaurant.\nLet the amount of money Snuke has paid to the restaurant be x yen, and let the amount of money the restaurant has paid back to Snuke be y yen.\nFind x-y.\n\nConstraints\n\n1 ≤ N ≤ 100\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n20\n\nSample Output 1\n\n15800\n\nSo far, Snuke has paid 16000 yen, and the restaurant has paid back 200 yen. Thus, the answer is 15800.\n\nSample Input 2\n\n60\n\nSample Output 2\n\n47200\n\nSnuke has paid 48000 yen for 60 meals, and the restaurant has paid back 800 yen.", "sample_input": "20\n"}, "reference_outputs": ["15800\n"], "source_document_id": "p03795", "source_text": "Score : 100 points\n\nProblem Statement\n\nSnuke has a favorite restaurant.\n\nThe price of any meal served at the restaurant is 800 yen (the currency of Japan), and each time a customer orders 15 meals, the restaurant pays 200 yen back to the customer.\n\nSo far, Snuke has ordered N meals at the restaurant.\nLet the amount of money Snuke has paid to the restaurant be x yen, and let the amount of money the restaurant has paid back to Snuke be y yen.\nFind x-y.\n\nConstraints\n\n1 ≤ N ≤ 100\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n20\n\nSample Output 1\n\n15800\n\nSo far, Snuke has paid 16000 yen, and the restaurant has paid back 200 yen. Thus, the answer is 15800.\n\nSample Input 2\n\n60\n\nSample Output 2\n\n47200\n\nSnuke has paid 48000 yen for 60 meals, and the restaurant has paid back 800 yen.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 135, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s515374687", "group_id": "codeNet:p03796", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> P;\n#define rep(i,N) for(ll (i)=0;(i)<(N);(i)++)\nconst int mod = 1000000007;\n\nint main(){\n  ll n;\n  cin >> n;\n  ll ans = 1;\n  for(int i = 1; i <= n; ++i){\n    ans *= i;\n    ans %= mod;\n  }\n  cout << ans << endl;\n}", "language": "C++", "metadata": {"date": 1582360766, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03796.html", "problem_id": "p03796", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03796/input.txt", "sample_output_relpath": "derived/input_output/data/p03796/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03796/C++/s515374687.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s515374687", "user_id": "u239409893"}, "prompt_components": {"gold_output": "6\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> P;\n#define rep(i,N) for(ll (i)=0;(i)<(N);(i)++)\nconst int mod = 1000000007;\n\nint main(){\n  ll n;\n  cin >> n;\n  ll ans = 1;\n  for(int i = 1; i <= n; ++i){\n    ans *= i;\n    ans %= mod;\n  }\n  cout << ans << endl;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nSnuke loves working out. He is now exercising N times.\n\nBefore he starts exercising, his power is 1. After he exercises for the i-th time, his power gets multiplied by i.\n\nFind Snuke's power after he exercises N times. Since the answer can be extremely large, print the answer modulo 10^{9}+7.\n\nConstraints\n\n1 ≤ N ≤ 10^{5}\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the answer modulo 10^{9}+7.\n\nSample Input 1\n\n3\n\nSample Output 1\n\n6\n\nAfter Snuke exercises for the first time, his power gets multiplied by 1 and becomes 1.\n\nAfter Snuke exercises for the second time, his power gets multiplied by 2 and becomes 2.\n\nAfter Snuke exercises for the third time, his power gets multiplied by 3 and becomes 6.\n\nSample Input 2\n\n10\n\nSample Output 2\n\n3628800\n\nSample Input 3\n\n100000\n\nSample Output 3\n\n457992974\n\nPrint the answer modulo 10^{9}+7.", "sample_input": "3\n"}, "reference_outputs": ["6\n"], "source_document_id": "p03796", "source_text": "Score : 200 points\n\nProblem Statement\n\nSnuke loves working out. He is now exercising N times.\n\nBefore he starts exercising, his power is 1. After he exercises for the i-th time, his power gets multiplied by i.\n\nFind Snuke's power after he exercises N times. Since the answer can be extremely large, print the answer modulo 10^{9}+7.\n\nConstraints\n\n1 ≤ N ≤ 10^{5}\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the answer modulo 10^{9}+7.\n\nSample Input 1\n\n3\n\nSample Output 1\n\n6\n\nAfter Snuke exercises for the first time, his power gets multiplied by 1 and becomes 1.\n\nAfter Snuke exercises for the second time, his power gets multiplied by 2 and becomes 2.\n\nAfter Snuke exercises for the third time, his power gets multiplied by 3 and becomes 6.\n\nSample Input 2\n\n10\n\nSample Output 2\n\n3628800\n\nSample Input 3\n\n100000\n\nSample Output 3\n\n457992974\n\nPrint the answer modulo 10^{9}+7.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 301, "cpu_time_ms": 2, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s455315177", "group_id": "codeNet:p03797", "input_text": "#include<bits/stdc++.h>\n#define fast ios::sync_with_stdio(false), cin.tie(0);\n#define ll long long\n#define pb push_back\n#define mp make_pair\n#define ff first\n#define ss second\n#define endl '\\n'\n\nconst int M = 1e9+7;\n\nusing namespace std;\n\nmain()\n{\n    fast;\n    ll n,m;\n    cin>>n>>m;\n    if (n==m/2)\n        cout<<n<<endl;\n    else if (n<m/2)\n    {\n        m-=2*n;\n        cout<<n+m/4<<endl;\n    }\n    else\n        cout<<m/2<<endl;\n}", "language": "C++", "metadata": {"date": 1586946017, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03797.html", "problem_id": "p03797", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03797/input.txt", "sample_output_relpath": "derived/input_output/data/p03797/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03797/C++/s455315177.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s455315177", "user_id": "u041940198"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include<bits/stdc++.h>\n#define fast ios::sync_with_stdio(false), cin.tie(0);\n#define ll long long\n#define pb push_back\n#define mp make_pair\n#define ff first\n#define ss second\n#define endl '\\n'\n\nconst int M = 1e9+7;\n\nusing namespace std;\n\nmain()\n{\n    fast;\n    ll n,m;\n    cin>>n>>m;\n    if (n==m/2)\n        cout<<n<<endl;\n    else if (n<m/2)\n    {\n        m-=2*n;\n        cout<<n+m/4<<endl;\n    }\n    else\n        cout<<m/2<<endl;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nSnuke loves puzzles.\n\nToday, he is working on a puzzle using S- and c-shaped pieces.\nIn this puzzle, you can combine two c-shaped pieces into one S-shaped piece, as shown in the figure below:\n\nSnuke decided to create as many Scc groups as possible by putting together one S-shaped piece and two c-shaped pieces.\n\nFind the maximum number of Scc groups that can be created when Snuke has N S-shaped pieces and M c-shaped pieces.\n\nConstraints\n\n1 ≤ N,M ≤ 10^{12}\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN M\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n1 6\n\nSample Output 1\n\n2\n\nTwo Scc groups can be created as follows:\n\nCombine two c-shaped pieces into one S-shaped piece\n\nCreate two Scc groups, each from one S-shaped piece and two c-shaped pieces\n\nSample Input 2\n\n12345 678901\n\nSample Output 2\n\n175897", "sample_input": "1 6\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03797", "source_text": "Score : 300 points\n\nProblem Statement\n\nSnuke loves puzzles.\n\nToday, he is working on a puzzle using S- and c-shaped pieces.\nIn this puzzle, you can combine two c-shaped pieces into one S-shaped piece, as shown in the figure below:\n\nSnuke decided to create as many Scc groups as possible by putting together one S-shaped piece and two c-shaped pieces.\n\nFind the maximum number of Scc groups that can be created when Snuke has N S-shaped pieces and M c-shaped pieces.\n\nConstraints\n\n1 ≤ N,M ≤ 10^{12}\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN M\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n1 6\n\nSample Output 1\n\n2\n\nTwo Scc groups can be created as follows:\n\nCombine two c-shaped pieces into one S-shaped piece\n\nCreate two Scc groups, each from one S-shaped piece and two c-shaped pieces\n\nSample Input 2\n\n12345 678901\n\nSample Output 2\n\n175897", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 434, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s895564350", "group_id": "codeNet:p03797", "input_text": "#include <iostream>\n#include <vector>\n#include <string>\n#include <algorithm>\n#include <cmath>\n#include <queue>\n#include <climits>\n#include <set>\n#include <map>\n#include <stack>\n#include <iomanip>\n#include <tuple>\n#define ll long long\nusing namespace std;\nll factorial(ll n){\n    if(n==0){\n        return 1;\n    }\n    else{\n        return n*factorial(n-1);\n    }\n}\n\ndouble dist(pair<double,double> a,pair<double,double> b){\n\treturn sqrt(pow((a.first - b.first) ,2) + pow((a.second - b.second),2));\n}\n//繰り返し自乗法\ndouble ism(double aa,ll p){\n    double ap=aa;\n    double ans=1;\n    while(p>0){\n        //cout<<\"p=\"<<p<<\",ap=\"<<ap<<endl;\n        if(p&1){//奇数が真\n            ans*=ap;\n        }\n        p/=2;\n        ap=ap*ap;\n    }\n    return ans;\n\n}\n//繰り返し自乗法(アマリトリバージョン)\nll ismm(ll aa,ll p,ll m){\n    ll ap=aa;\n    ll ans=1;\n    while(p>0){\n        //cout<<\"p=\"<<p<<\",ap=\"<<ap<<endl;\n        if(p&1){//奇数が真\n            ans=(ans*ap)%m;    \n        }\n        p/=2;              \n        ap=(ap*ap)%m;\n    }\n    return ans;\n\n}\n\nstruct all_init\n{\n    all_init()\n    {\n        cout << fixed << setprecision(9);\n    }\n} All_init;\n\n\nint main()\n{\n    ll n,m,ans=0;\n    cin>>n>>m;\n    ans=min(n,m/2);\n    m-=ans*2;\n    ans+=m/4;\n    cout<<ans<<endl;\n\n    \n}\n", "language": "C++", "metadata": {"date": 1581879262, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03797.html", "problem_id": "p03797", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03797/input.txt", "sample_output_relpath": "derived/input_output/data/p03797/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03797/C++/s895564350.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s895564350", "user_id": "u553461888"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\n#include <string>\n#include <algorithm>\n#include <cmath>\n#include <queue>\n#include <climits>\n#include <set>\n#include <map>\n#include <stack>\n#include <iomanip>\n#include <tuple>\n#define ll long long\nusing namespace std;\nll factorial(ll n){\n    if(n==0){\n        return 1;\n    }\n    else{\n        return n*factorial(n-1);\n    }\n}\n\ndouble dist(pair<double,double> a,pair<double,double> b){\n\treturn sqrt(pow((a.first - b.first) ,2) + pow((a.second - b.second),2));\n}\n//繰り返し自乗法\ndouble ism(double aa,ll p){\n    double ap=aa;\n    double ans=1;\n    while(p>0){\n        //cout<<\"p=\"<<p<<\",ap=\"<<ap<<endl;\n        if(p&1){//奇数が真\n            ans*=ap;\n        }\n        p/=2;\n        ap=ap*ap;\n    }\n    return ans;\n\n}\n//繰り返し自乗法(アマリトリバージョン)\nll ismm(ll aa,ll p,ll m){\n    ll ap=aa;\n    ll ans=1;\n    while(p>0){\n        //cout<<\"p=\"<<p<<\",ap=\"<<ap<<endl;\n        if(p&1){//奇数が真\n            ans=(ans*ap)%m;    \n        }\n        p/=2;              \n        ap=(ap*ap)%m;\n    }\n    return ans;\n\n}\n\nstruct all_init\n{\n    all_init()\n    {\n        cout << fixed << setprecision(9);\n    }\n} All_init;\n\n\nint main()\n{\n    ll n,m,ans=0;\n    cin>>n>>m;\n    ans=min(n,m/2);\n    m-=ans*2;\n    ans+=m/4;\n    cout<<ans<<endl;\n\n    \n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nSnuke loves puzzles.\n\nToday, he is working on a puzzle using S- and c-shaped pieces.\nIn this puzzle, you can combine two c-shaped pieces into one S-shaped piece, as shown in the figure below:\n\nSnuke decided to create as many Scc groups as possible by putting together one S-shaped piece and two c-shaped pieces.\n\nFind the maximum number of Scc groups that can be created when Snuke has N S-shaped pieces and M c-shaped pieces.\n\nConstraints\n\n1 ≤ N,M ≤ 10^{12}\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN M\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n1 6\n\nSample Output 1\n\n2\n\nTwo Scc groups can be created as follows:\n\nCombine two c-shaped pieces into one S-shaped piece\n\nCreate two Scc groups, each from one S-shaped piece and two c-shaped pieces\n\nSample Input 2\n\n12345 678901\n\nSample Output 2\n\n175897", "sample_input": "1 6\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03797", "source_text": "Score : 300 points\n\nProblem Statement\n\nSnuke loves puzzles.\n\nToday, he is working on a puzzle using S- and c-shaped pieces.\nIn this puzzle, you can combine two c-shaped pieces into one S-shaped piece, as shown in the figure below:\n\nSnuke decided to create as many Scc groups as possible by putting together one S-shaped piece and two c-shaped pieces.\n\nFind the maximum number of Scc groups that can be created when Snuke has N S-shaped pieces and M c-shaped pieces.\n\nConstraints\n\n1 ≤ N,M ≤ 10^{12}\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN M\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n1 6\n\nSample Output 1\n\n2\n\nTwo Scc groups can be created as follows:\n\nCombine two c-shaped pieces into one S-shaped piece\n\nCreate two Scc groups, each from one S-shaped piece and two c-shaped pieces\n\nSample Input 2\n\n12345 678901\n\nSample Output 2\n\n175897", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1307, "cpu_time_ms": 2, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s739641705", "group_id": "codeNet:p03799", "input_text": "#include <bits/stdc++.h>\n#define ls (o << 1)\n#define rs (o << 1 | 1)\n#define mid ((L + R + 1) >> 1)\nusing namespace std;\nconst int MAXN = 200050;\nconst int mod = 998244353;\ntypedef long long LL;\nint main() {\n#ifdef TEST\n\tfreopen(\"input.txt\", \"r\", stdin);\n#endif\n\tLL a, b;\n\tcin >> a >> b;\n\tLL L = 0, R = a + b;\n\twhile (L < R) {\n\t\tif (b >= mid + mid && a + (b - mid - mid) / 2 >= mid) {\n\t\t\tL = mid;\n\t\t} else {\n\t\t\tR = mid - 1;\n\t\t}\n\t}\n\tcout << L << endl;\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1575166143, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03799.html", "problem_id": "p03799", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03799/input.txt", "sample_output_relpath": "derived/input_output/data/p03799/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03799/C++/s739641705.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s739641705", "user_id": "u944802555"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define ls (o << 1)\n#define rs (o << 1 | 1)\n#define mid ((L + R + 1) >> 1)\nusing namespace std;\nconst int MAXN = 200050;\nconst int mod = 998244353;\ntypedef long long LL;\nint main() {\n#ifdef TEST\n\tfreopen(\"input.txt\", \"r\", stdin);\n#endif\n\tLL a, b;\n\tcin >> a >> b;\n\tLL L = 0, R = a + b;\n\twhile (L < R) {\n\t\tif (b >= mid + mid && a + (b - mid - mid) / 2 >= mid) {\n\t\t\tL = mid;\n\t\t} else {\n\t\t\tR = mid - 1;\n\t\t}\n\t}\n\tcout << L << endl;\n\treturn 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nSnuke loves puzzles.\n\nToday, he is working on a puzzle using S- and c-shaped pieces.\nIn this puzzle, you can combine two c-shaped pieces into one S-shaped piece, as shown in the figure below:\n\nSnuke decided to create as many Scc groups as possible by putting together one S-shaped piece and two c-shaped pieces.\n\nFind the maximum number of Scc groups that can be created when Snuke has N S-shaped pieces and M c-shaped pieces.\n\nConstraints\n\n1 ≤ N,M ≤ 10^{12}\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN M\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n1 6\n\nSample Output 1\n\n2\n\nTwo Scc groups can be created as follows:\n\nCombine two c-shaped pieces into one S-shaped piece\n\nCreate two Scc groups, each from one S-shaped piece and two c-shaped pieces\n\nSample Input 2\n\n12345 678901\n\nSample Output 2\n\n175897", "sample_input": "1 6\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03799", "source_text": "Score : 300 points\n\nProblem Statement\n\nSnuke loves puzzles.\n\nToday, he is working on a puzzle using S- and c-shaped pieces.\nIn this puzzle, you can combine two c-shaped pieces into one S-shaped piece, as shown in the figure below:\n\nSnuke decided to create as many Scc groups as possible by putting together one S-shaped piece and two c-shaped pieces.\n\nFind the maximum number of Scc groups that can be created when Snuke has N S-shaped pieces and M c-shaped pieces.\n\nConstraints\n\n1 ≤ N,M ≤ 10^{12}\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN M\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n1 6\n\nSample Output 1\n\n2\n\nTwo Scc groups can be created as follows:\n\nCombine two c-shaped pieces into one S-shaped piece\n\nCreate two Scc groups, each from one S-shaped piece and two c-shaped pieces\n\nSample Input 2\n\n12345 678901\n\nSample Output 2\n\n175897", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 463, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s052602738", "group_id": "codeNet:p03804", "input_text": "#include<bits//stdc++.h>\nusing namespace std;\n#define rep(i,n) for(int i = 0; i < n;i++)\nint main() {\n\tint n, m;cin >> n >> m;\n\tchar a[50][50],b[50][50];bool h = false;\n\trep(i, n) rep(j,n) cin >> a[i][j];\n\trep(j, m) rep(i,m) cin >> b[j][i];\n\tfor (int i = 0; i < n;i++) {\n\t\tfor (int j = 0;j < n;j++) {\n\t\t\tif (i + m - 1 >= n || j + m - 1>= n) continue;\n\t\t\tbool ch = true;\n\t\t\trep(k, m) {\n\t\t\t\trep(l, m) {\n\t\t\t\t\tif (a[i + k][l + j] != b[k][l]) ch = false;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (ch) h = true;\n\t\t}\n\t}\n\tif (h) cout << \"Yes\" << endl;\n\telse cout << \"No\" << endl;\n}", "language": "C++", "metadata": {"date": 1585009875, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03804.html", "problem_id": "p03804", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03804/input.txt", "sample_output_relpath": "derived/input_output/data/p03804/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03804/C++/s052602738.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s052602738", "user_id": "u670898337"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include<bits//stdc++.h>\nusing namespace std;\n#define rep(i,n) for(int i = 0; i < n;i++)\nint main() {\n\tint n, m;cin >> n >> m;\n\tchar a[50][50],b[50][50];bool h = false;\n\trep(i, n) rep(j,n) cin >> a[i][j];\n\trep(j, m) rep(i,m) cin >> b[j][i];\n\tfor (int i = 0; i < n;i++) {\n\t\tfor (int j = 0;j < n;j++) {\n\t\t\tif (i + m - 1 >= n || j + m - 1>= n) continue;\n\t\t\tbool ch = true;\n\t\t\trep(k, m) {\n\t\t\t\trep(l, m) {\n\t\t\t\t\tif (a[i + k][l + j] != b[k][l]) ch = false;\n\t\t\t\t}\n\t\t\t}\n\t\t\tif (ch) h = true;\n\t\t}\n\t}\n\tif (h) cout << \"Yes\" << endl;\n\telse cout << \"No\" << endl;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nYou are given an image A composed of N rows and N columns of pixels, and a template image B composed of M rows and M columns of pixels.\n\nA pixel is the smallest element of an image, and in this problem it is a square of size 1×1.\n\nAlso, the given images are binary images, and the color of each pixel is either white or black.\n\nIn the input, every pixel is represented by a character: . corresponds to a white pixel, and # corresponds to a black pixel.\n\nThe image A is given as N strings A_1,...,A_N.\n\nThe j-th character in the string A_i corresponds to the pixel at the i-th row and j-th column of the image A (1≦i,j≦N).\n\nSimilarly, the template image B is given as M strings B_1,...,B_M.\n\nThe j-th character in the string B_i corresponds to the pixel at the i-th row and j-th column of the template image B (1≦i,j≦M).\n\nDetermine whether the template image B is contained in the image A when only parallel shifts can be applied to the images.\n\nConstraints\n\n1≦M≦N≦50\n\nA_i is a string of length N consisting of # and ..\n\nB_i is a string of length M consisting of # and ..\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN M\nA_1\nA_2\n:\nA_N\nB_1\nB_2\n:\nB_M\n\nOutput\n\nPrint Yes if the template image B is contained in the image A. Print No otherwise.\n\nSample Input 1\n\n3 2\n#.#\n.#.\n#.#\n#.\n.#\n\nSample Output 1\n\nYes\n\nThe template image B is identical to the upper-left 2 × 2 subimage and the lower-right 2 × 2 subimage of A. Thus, the output should be Yes.\n\nSample Input 2\n\n4 1\n....\n....\n....\n....\n#\n\nSample Output 2\n\nNo\n\nThe template image B, composed of a black pixel, is not contained in the image A composed of white pixels.", "sample_input": "3 2\n#.#\n.#.\n#.#\n#.\n.#\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p03804", "source_text": "Score : 200 points\n\nProblem Statement\n\nYou are given an image A composed of N rows and N columns of pixels, and a template image B composed of M rows and M columns of pixels.\n\nA pixel is the smallest element of an image, and in this problem it is a square of size 1×1.\n\nAlso, the given images are binary images, and the color of each pixel is either white or black.\n\nIn the input, every pixel is represented by a character: . corresponds to a white pixel, and # corresponds to a black pixel.\n\nThe image A is given as N strings A_1,...,A_N.\n\nThe j-th character in the string A_i corresponds to the pixel at the i-th row and j-th column of the image A (1≦i,j≦N).\n\nSimilarly, the template image B is given as M strings B_1,...,B_M.\n\nThe j-th character in the string B_i corresponds to the pixel at the i-th row and j-th column of the template image B (1≦i,j≦M).\n\nDetermine whether the template image B is contained in the image A when only parallel shifts can be applied to the images.\n\nConstraints\n\n1≦M≦N≦50\n\nA_i is a string of length N consisting of # and ..\n\nB_i is a string of length M consisting of # and ..\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN M\nA_1\nA_2\n:\nA_N\nB_1\nB_2\n:\nB_M\n\nOutput\n\nPrint Yes if the template image B is contained in the image A. Print No otherwise.\n\nSample Input 1\n\n3 2\n#.#\n.#.\n#.#\n#.\n.#\n\nSample Output 1\n\nYes\n\nThe template image B is identical to the upper-left 2 × 2 subimage and the lower-right 2 × 2 subimage of A. Thus, the output should be Yes.\n\nSample Input 2\n\n4 1\n....\n....\n....\n....\n#\n\nSample Output 2\n\nNo\n\nThe template image B, composed of a black pixel, is not contained in the image A composed of white pixels.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 549, "cpu_time_ms": 2, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s409779583", "group_id": "codeNet:p03804", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nchar x[55][55];\nchar y[55][55];\nint main(){\n\tint n,m,w,count=0;\n\tcin>>n>>m;\n\tfor(int i=0;i<n;i++){\n\t\tfor(int j=0;j<n;j++){\n\t\t\tcin>>x[i][j];\n\t\t}\n\t}\n\t\tfor(int i=0;i<m;i++){\n\t\tfor(int j=0;j<m;j++){\n\t\t\tcin>>y[i][j];\n\t\t}\n\t}\n\tfor(int i=0;i<m-n;i++){\n\tfor(int j=0;j<m-n;j++){\n\tfor(int k=0;k<n;k++){\n\tfor(int l=0;l<n;l++){\n\t\t\tif(y[i+k][l+j]==x[i+k][l+j]){\n\t\t\t\tcount++;\n\t\t\t}\n\t\t}\n\t}\n\n\tw=m*m;\n\tif(count==w)\n\treturn cout<<\"Yes\" ,0;\n\n\t\t}\n\t}\n\n\treturn cout<<\"No\" ,0;\n}/**\n\n3 2\n#.#\n.#.\n#.#\n#.\n.#\n*/", "language": "C++", "metadata": {"date": 1563588174, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03804.html", "problem_id": "p03804", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03804/input.txt", "sample_output_relpath": "derived/input_output/data/p03804/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03804/C++/s409779583.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s409779583", "user_id": "u089230684"}, "prompt_components": {"gold_output": "Yes\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nchar x[55][55];\nchar y[55][55];\nint main(){\n\tint n,m,w,count=0;\n\tcin>>n>>m;\n\tfor(int i=0;i<n;i++){\n\t\tfor(int j=0;j<n;j++){\n\t\t\tcin>>x[i][j];\n\t\t}\n\t}\n\t\tfor(int i=0;i<m;i++){\n\t\tfor(int j=0;j<m;j++){\n\t\t\tcin>>y[i][j];\n\t\t}\n\t}\n\tfor(int i=0;i<m-n;i++){\n\tfor(int j=0;j<m-n;j++){\n\tfor(int k=0;k<n;k++){\n\tfor(int l=0;l<n;l++){\n\t\t\tif(y[i+k][l+j]==x[i+k][l+j]){\n\t\t\t\tcount++;\n\t\t\t}\n\t\t}\n\t}\n\n\tw=m*m;\n\tif(count==w)\n\treturn cout<<\"Yes\" ,0;\n\n\t\t}\n\t}\n\n\treturn cout<<\"No\" ,0;\n}/**\n\n3 2\n#.#\n.#.\n#.#\n#.\n.#\n*/", "problem_context": "Score : 200 points\n\nProblem Statement\n\nYou are given an image A composed of N rows and N columns of pixels, and a template image B composed of M rows and M columns of pixels.\n\nA pixel is the smallest element of an image, and in this problem it is a square of size 1×1.\n\nAlso, the given images are binary images, and the color of each pixel is either white or black.\n\nIn the input, every pixel is represented by a character: . corresponds to a white pixel, and # corresponds to a black pixel.\n\nThe image A is given as N strings A_1,...,A_N.\n\nThe j-th character in the string A_i corresponds to the pixel at the i-th row and j-th column of the image A (1≦i,j≦N).\n\nSimilarly, the template image B is given as M strings B_1,...,B_M.\n\nThe j-th character in the string B_i corresponds to the pixel at the i-th row and j-th column of the template image B (1≦i,j≦M).\n\nDetermine whether the template image B is contained in the image A when only parallel shifts can be applied to the images.\n\nConstraints\n\n1≦M≦N≦50\n\nA_i is a string of length N consisting of # and ..\n\nB_i is a string of length M consisting of # and ..\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN M\nA_1\nA_2\n:\nA_N\nB_1\nB_2\n:\nB_M\n\nOutput\n\nPrint Yes if the template image B is contained in the image A. Print No otherwise.\n\nSample Input 1\n\n3 2\n#.#\n.#.\n#.#\n#.\n.#\n\nSample Output 1\n\nYes\n\nThe template image B is identical to the upper-left 2 × 2 subimage and the lower-right 2 × 2 subimage of A. Thus, the output should be Yes.\n\nSample Input 2\n\n4 1\n....\n....\n....\n....\n#\n\nSample Output 2\n\nNo\n\nThe template image B, composed of a black pixel, is not contained in the image A composed of white pixels.", "sample_input": "3 2\n#.#\n.#.\n#.#\n#.\n.#\n"}, "reference_outputs": ["Yes\n"], "source_document_id": "p03804", "source_text": "Score : 200 points\n\nProblem Statement\n\nYou are given an image A composed of N rows and N columns of pixels, and a template image B composed of M rows and M columns of pixels.\n\nA pixel is the smallest element of an image, and in this problem it is a square of size 1×1.\n\nAlso, the given images are binary images, and the color of each pixel is either white or black.\n\nIn the input, every pixel is represented by a character: . corresponds to a white pixel, and # corresponds to a black pixel.\n\nThe image A is given as N strings A_1,...,A_N.\n\nThe j-th character in the string A_i corresponds to the pixel at the i-th row and j-th column of the image A (1≦i,j≦N).\n\nSimilarly, the template image B is given as M strings B_1,...,B_M.\n\nThe j-th character in the string B_i corresponds to the pixel at the i-th row and j-th column of the template image B (1≦i,j≦M).\n\nDetermine whether the template image B is contained in the image A when only parallel shifts can be applied to the images.\n\nConstraints\n\n1≦M≦N≦50\n\nA_i is a string of length N consisting of # and ..\n\nB_i is a string of length M consisting of # and ..\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN M\nA_1\nA_2\n:\nA_N\nB_1\nB_2\n:\nB_M\n\nOutput\n\nPrint Yes if the template image B is contained in the image A. Print No otherwise.\n\nSample Input 1\n\n3 2\n#.#\n.#.\n#.#\n#.\n.#\n\nSample Output 1\n\nYes\n\nThe template image B is identical to the upper-left 2 × 2 subimage and the lower-right 2 × 2 subimage of A. Thus, the output should be Yes.\n\nSample Input 2\n\n4 1\n....\n....\n....\n....\n#\n\nSample Output 2\n\nNo\n\nThe template image B, composed of a black pixel, is not contained in the image A composed of white pixels.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 527, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s583739720", "group_id": "codeNet:p03805", "input_text": "#include <stdio.h>\n\nint num[8], n, ans = 0;\nbool r[8][8], flg[8];\n\nvoid saiki(int a) {\n  int i;\n  if(a == n) {\n    bool b = true;\n    for(i = 1; i < n; ++i) if(!r[num[i - 1]][num[i]]) b = false;\n    if(b) ++ans;\n    return;\n  }\n  for(i = 1; i < n; ++i) if(flg[i]) {\n    num[a] = i, flg[i] = false;\n    saiki(a + 1);\n    flg[i] = true;\n  }\n}\n\nint main(void) {\n  int i, m, j, x, y;\n  scanf(\"%d%d\", &n, &m);\n  for(i = 0; i < n; ++i) for(j = 0; j < n; ++j) r[i][j] = false;\n  for(i = 0; i < n; ++i) flg[i] = true;\n  for(i = 0; i < m; ++i) {\n    scanf(\"%d%d\", &x, &y);\n    x--, y--;\n    r[x][y] = r[y][x] = true;\n  }\n  num[0] = 0;\n  saiki(1);\n  printf(\"%d\", ans);\n  return 0;\n}", "language": "C++", "metadata": {"date": 1533315849, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03805.html", "problem_id": "p03805", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03805/input.txt", "sample_output_relpath": "derived/input_output/data/p03805/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03805/C++/s583739720.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s583739720", "user_id": "u440920318"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <stdio.h>\n\nint num[8], n, ans = 0;\nbool r[8][8], flg[8];\n\nvoid saiki(int a) {\n  int i;\n  if(a == n) {\n    bool b = true;\n    for(i = 1; i < n; ++i) if(!r[num[i - 1]][num[i]]) b = false;\n    if(b) ++ans;\n    return;\n  }\n  for(i = 1; i < n; ++i) if(flg[i]) {\n    num[a] = i, flg[i] = false;\n    saiki(a + 1);\n    flg[i] = true;\n  }\n}\n\nint main(void) {\n  int i, m, j, x, y;\n  scanf(\"%d%d\", &n, &m);\n  for(i = 0; i < n; ++i) for(j = 0; j < n; ++j) r[i][j] = false;\n  for(i = 0; i < n; ++i) flg[i] = true;\n  for(i = 0; i < m; ++i) {\n    scanf(\"%d%d\", &x, &y);\n    x--, y--;\n    r[x][y] = r[y][x] = true;\n  }\n  num[0] = 0;\n  saiki(1);\n  printf(\"%d\", ans);\n  return 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nYou are given an undirected unweighted graph with N vertices and M edges that contains neither self-loops nor double edges.\n\nHere, a self-loop is an edge where a_i = b_i (1≤i≤M), and double edges are two edges where (a_i,b_i)=(a_j,b_j) or (a_i,b_i)=(b_j,a_j) (1≤i<j≤M).\n\nHow many different paths start from vertex 1 and visit all the vertices exactly once?\n\nHere, the endpoints of a path are considered visited.\n\nFor example, let us assume that the following undirected graph shown in Figure 1 is given.\n\nFigure 1: an example of an undirected graph\n\nThe following path shown in Figure 2 satisfies the condition.\n\nFigure 2: an example of a path that satisfies the condition\n\nHowever, the following path shown in Figure 3 does not satisfy the condition, because it does not visit all the vertices.\n\nFigure 3: an example of a path that does not satisfy the condition\n\nNeither the following path shown in Figure 4, because it does not start from vertex 1.\n\nFigure 4: another example of a path that does not satisfy the condition\n\nConstraints\n\n2≦N≦8\n\n0≦M≦N(N-1)/2\n\n1≦a_i<b_i≦N\n\nThe given graph contains neither self-loops nor double edges.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN M\na_1 b_1\na_2 b_2\n:\na_M b_M\n\nOutput\n\nPrint the number of the different paths that start from vertex 1 and visit all the vertices exactly once.\n\nSample Input 1\n\n3 3\n1 2\n1 3\n2 3\n\nSample Output 1\n\n2\n\nThe given graph is shown in the following figure:\n\nThe following two paths satisfy the condition:\n\nSample Input 2\n\n7 7\n1 3\n2 7\n3 4\n4 5\n4 6\n5 6\n6 7\n\nSample Output 2\n\n1\n\nThis test case is the same as the one described in the problem statement.", "sample_input": "3 3\n1 2\n1 3\n2 3\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03805", "source_text": "Score : 300 points\n\nProblem Statement\n\nYou are given an undirected unweighted graph with N vertices and M edges that contains neither self-loops nor double edges.\n\nHere, a self-loop is an edge where a_i = b_i (1≤i≤M), and double edges are two edges where (a_i,b_i)=(a_j,b_j) or (a_i,b_i)=(b_j,a_j) (1≤i<j≤M).\n\nHow many different paths start from vertex 1 and visit all the vertices exactly once?\n\nHere, the endpoints of a path are considered visited.\n\nFor example, let us assume that the following undirected graph shown in Figure 1 is given.\n\nFigure 1: an example of an undirected graph\n\nThe following path shown in Figure 2 satisfies the condition.\n\nFigure 2: an example of a path that satisfies the condition\n\nHowever, the following path shown in Figure 3 does not satisfy the condition, because it does not visit all the vertices.\n\nFigure 3: an example of a path that does not satisfy the condition\n\nNeither the following path shown in Figure 4, because it does not start from vertex 1.\n\nFigure 4: another example of a path that does not satisfy the condition\n\nConstraints\n\n2≦N≦8\n\n0≦M≦N(N-1)/2\n\n1≦a_i<b_i≦N\n\nThe given graph contains neither self-loops nor double edges.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN M\na_1 b_1\na_2 b_2\n:\na_M b_M\n\nOutput\n\nPrint the number of the different paths that start from vertex 1 and visit all the vertices exactly once.\n\nSample Input 1\n\n3 3\n1 2\n1 3\n2 3\n\nSample Output 1\n\n2\n\nThe given graph is shown in the following figure:\n\nThe following two paths satisfy the condition:\n\nSample Input 2\n\n7 7\n1 3\n2 7\n3 4\n4 5\n4 6\n5 6\n6 7\n\nSample Output 2\n\n1\n\nThis test case is the same as the one described in the problem statement.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 672, "cpu_time_ms": 1, "memory_kb": 128}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s147670489", "group_id": "codeNet:p03807", "input_text": "#include <sstream>\n#include <string>\n#include <vector>\n#include <map>\n#include <algorithm>\n#include <iostream>\n#include <utility>\n#include <set>\n#include <cctype>\n#include <queue>\n#include <stack>\n#include <cstdio>\n#include <cstdlib>\n#include <cmath>\n#define all(v) (v).begin(),(v).end()\n#define rep(i,n) for(int i=0;i<(n);i++)\n#define reps(i,f,n) for(int i=(f);i<(n);i++)\n#define each(it,v) for(__typeof((v).begin()) it=(v).begin();it!=(v).end();it++)\n#define MAX(a,b) (a>b?a:b)\nusing namespace std;\n\nint main(){\n  int N, num;\n  cin >> N;\n  int cnt =0;\n  rep(i, N){\n    cin >> num;\n    if(num%2==1) cnt++;\n  }\n  if(cnt%2==0) cout << \"YES\" << endl;\n  else  cout << \"NO\" << endl;\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1486262436, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03807.html", "problem_id": "p03807", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03807/input.txt", "sample_output_relpath": "derived/input_output/data/p03807/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03807/C++/s147670489.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s147670489", "user_id": "u777258731"}, "prompt_components": {"gold_output": "YES\n", "input_to_evaluate": "#include <sstream>\n#include <string>\n#include <vector>\n#include <map>\n#include <algorithm>\n#include <iostream>\n#include <utility>\n#include <set>\n#include <cctype>\n#include <queue>\n#include <stack>\n#include <cstdio>\n#include <cstdlib>\n#include <cmath>\n#define all(v) (v).begin(),(v).end()\n#define rep(i,n) for(int i=0;i<(n);i++)\n#define reps(i,f,n) for(int i=(f);i<(n);i++)\n#define each(it,v) for(__typeof((v).begin()) it=(v).begin();it!=(v).end();it++)\n#define MAX(a,b) (a>b?a:b)\nusing namespace std;\n\nint main(){\n  int N, num;\n  cin >> N;\n  int cnt =0;\n  rep(i, N){\n    cin >> num;\n    if(num%2==1) cnt++;\n  }\n  if(cnt%2==0) cout << \"YES\" << endl;\n  else  cout << \"NO\" << endl;\n  return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N integers written on a blackboard. The i-th integer is A_i.\n\nTakahashi will repeatedly perform the following operation on these numbers:\n\nSelect a pair of integers, A_i and A_j, that have the same parity (that is, both are even or both are odd) and erase them.\n\nThen, write a new integer on the blackboard that is equal to the sum of those integers, A_i+A_j.\n\nDetermine whether it is possible to have only one integer on the blackboard.\n\nConstraints\n\n2 ≦ N ≦ 10^5\n\n1 ≦ A_i ≦ 10^9\n\nA_i is an integer.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1 A_2 … A_N\n\nOutput\n\nIf it is possible to have only one integer on the blackboard, print YES. Otherwise, print NO.\n\nSample Input 1\n\n3\n1 2 3\n\nSample Output 1\n\nYES\n\nIt is possible to have only one integer on the blackboard, as follows:\n\nErase 1 and 3 from the blackboard, then write 4. Now, there are two integers on the blackboard: 2 and 4.\n\nErase 2 and 4 from the blackboard, then write 6. Now, there is only one integer on the blackboard: 6.\n\nSample Input 2\n\n5\n1 2 3 4 5\n\nSample Output 2\n\nNO", "sample_input": "3\n1 2 3\n"}, "reference_outputs": ["YES\n"], "source_document_id": "p03807", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N integers written on a blackboard. The i-th integer is A_i.\n\nTakahashi will repeatedly perform the following operation on these numbers:\n\nSelect a pair of integers, A_i and A_j, that have the same parity (that is, both are even or both are odd) and erase them.\n\nThen, write a new integer on the blackboard that is equal to the sum of those integers, A_i+A_j.\n\nDetermine whether it is possible to have only one integer on the blackboard.\n\nConstraints\n\n2 ≦ N ≦ 10^5\n\n1 ≦ A_i ≦ 10^9\n\nA_i is an integer.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1 A_2 … A_N\n\nOutput\n\nIf it is possible to have only one integer on the blackboard, print YES. Otherwise, print NO.\n\nSample Input 1\n\n3\n1 2 3\n\nSample Output 1\n\nYES\n\nIt is possible to have only one integer on the blackboard, as follows:\n\nErase 1 and 3 from the blackboard, then write 4. Now, there are two integers on the blackboard: 2 and 4.\n\nErase 2 and 4 from the blackboard, then write 6. Now, there is only one integer on the blackboard: 6.\n\nSample Input 2\n\n5\n1 2 3 4 5\n\nSample Output 2\n\nNO", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 693, "cpu_time_ms": 51, "memory_kb": 384}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s042068345", "group_id": "codeNet:p03807", "input_text": "#include<bits/stdc++.h>\n\nusing namespace std;\n\n#define pb push_back\n#define mp make_pair\n#define F first\n#define S second\n\n#define fo(i, n) for(int i = 1; i <= n; ++i)\n#define rep(i, a, b) for(int (i) = (a); (i) < (b); ++(i))\n\ntypedef long long ll;\ntypedef pair <int, int> pii;\ntypedef pair <ll, ll> pll;\n\nconst int N = 200200;\nconst int mod = 1e9 + 7;\nconst ll INF = 1e18;\nint n,cnt;\n\nint main()\n{\n\tios::sync_with_stdio(0); cin.tie(0);\n\t\tcin>>n;\n\t\tfo(i,n)\n\t\t{\n\t\t\tint x;\n\t\t\tcin>>x;\n\t\t\tif(x%2==1)\n\t\t\t\t++cnt;\n\t\t}\n\t\tif(cnt&1)\n\t\tcout<<\"NO\";\n\t\telse cout<<\"YES\";\n\treturn 0;\t\n}", "language": "C++", "metadata": {"date": 1486260213, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03807.html", "problem_id": "p03807", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03807/input.txt", "sample_output_relpath": "derived/input_output/data/p03807/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03807/C++/s042068345.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s042068345", "user_id": "u473040387"}, "prompt_components": {"gold_output": "YES\n", "input_to_evaluate": "#include<bits/stdc++.h>\n\nusing namespace std;\n\n#define pb push_back\n#define mp make_pair\n#define F first\n#define S second\n\n#define fo(i, n) for(int i = 1; i <= n; ++i)\n#define rep(i, a, b) for(int (i) = (a); (i) < (b); ++(i))\n\ntypedef long long ll;\ntypedef pair <int, int> pii;\ntypedef pair <ll, ll> pll;\n\nconst int N = 200200;\nconst int mod = 1e9 + 7;\nconst ll INF = 1e18;\nint n,cnt;\n\nint main()\n{\n\tios::sync_with_stdio(0); cin.tie(0);\n\t\tcin>>n;\n\t\tfo(i,n)\n\t\t{\n\t\t\tint x;\n\t\t\tcin>>x;\n\t\t\tif(x%2==1)\n\t\t\t\t++cnt;\n\t\t}\n\t\tif(cnt&1)\n\t\tcout<<\"NO\";\n\t\telse cout<<\"YES\";\n\treturn 0;\t\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N integers written on a blackboard. The i-th integer is A_i.\n\nTakahashi will repeatedly perform the following operation on these numbers:\n\nSelect a pair of integers, A_i and A_j, that have the same parity (that is, both are even or both are odd) and erase them.\n\nThen, write a new integer on the blackboard that is equal to the sum of those integers, A_i+A_j.\n\nDetermine whether it is possible to have only one integer on the blackboard.\n\nConstraints\n\n2 ≦ N ≦ 10^5\n\n1 ≦ A_i ≦ 10^9\n\nA_i is an integer.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1 A_2 … A_N\n\nOutput\n\nIf it is possible to have only one integer on the blackboard, print YES. Otherwise, print NO.\n\nSample Input 1\n\n3\n1 2 3\n\nSample Output 1\n\nYES\n\nIt is possible to have only one integer on the blackboard, as follows:\n\nErase 1 and 3 from the blackboard, then write 4. Now, there are two integers on the blackboard: 2 and 4.\n\nErase 2 and 4 from the blackboard, then write 6. Now, there is only one integer on the blackboard: 6.\n\nSample Input 2\n\n5\n1 2 3 4 5\n\nSample Output 2\n\nNO", "sample_input": "3\n1 2 3\n"}, "reference_outputs": ["YES\n"], "source_document_id": "p03807", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N integers written on a blackboard. The i-th integer is A_i.\n\nTakahashi will repeatedly perform the following operation on these numbers:\n\nSelect a pair of integers, A_i and A_j, that have the same parity (that is, both are even or both are odd) and erase them.\n\nThen, write a new integer on the blackboard that is equal to the sum of those integers, A_i+A_j.\n\nDetermine whether it is possible to have only one integer on the blackboard.\n\nConstraints\n\n2 ≦ N ≦ 10^5\n\n1 ≦ A_i ≦ 10^9\n\nA_i is an integer.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1 A_2 … A_N\n\nOutput\n\nIf it is possible to have only one integer on the blackboard, print YES. Otherwise, print NO.\n\nSample Input 1\n\n3\n1 2 3\n\nSample Output 1\n\nYES\n\nIt is possible to have only one integer on the blackboard, as follows:\n\nErase 1 and 3 from the blackboard, then write 4. Now, there are two integers on the blackboard: 2 and 4.\n\nErase 2 and 4 from the blackboard, then write 6. Now, there is only one integer on the blackboard: 6.\n\nSample Input 2\n\n5\n1 2 3 4 5\n\nSample Output 2\n\nNO", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 570, "cpu_time_ms": 13, "memory_kb": 384}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s541842926", "group_id": "codeNet:p03808", "input_text": "#include<iostream>\n#define abs(a) a>0?a:-a\nusing namespace std;\nint a[100005];\nint b[100005];\n\nint main(){\n\tint n,m=0;\n\tint i,j,k;\n\tbool miss=false;\n\tcin>>n;\n\tfor(i=0;i<n;i++){\n\t\tcin>>a[i];\n\t}\n\tfor(i=0;i<n;i++){\n\t\tif(i==n-1){\n\t\t\tb[n-1]=a[n-1]-a[0];\n\t\t}else{\n\t\t\tb[i]=a[i]-a[i+1];\n\t\t}\n\t\tif(b[i]<0){\n\t\t\tj=(-b[i])/n+1;\n\t\t\tb[i]+=j*n;\n\t\t}\n\t}\n\tk=b[0]%n;\n\tfor(i=0;i<n;i++){\n\t\tif(b[i]%n!=k){\n\t\t\tmiss=true;\n\t\t\tbreak;\n\t\t}\n\t}\n\tif(miss){\n\t\tcout<<\"NO\"<<endl;\n\t}else{\n\t\tcout<<\"YES\"<<endl;\n\t}\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1487020718, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03808.html", "problem_id": "p03808", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03808/input.txt", "sample_output_relpath": "derived/input_output/data/p03808/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03808/C++/s541842926.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s541842926", "user_id": "u464804957"}, "prompt_components": {"gold_output": "YES\n", "input_to_evaluate": "#include<iostream>\n#define abs(a) a>0?a:-a\nusing namespace std;\nint a[100005];\nint b[100005];\n\nint main(){\n\tint n,m=0;\n\tint i,j,k;\n\tbool miss=false;\n\tcin>>n;\n\tfor(i=0;i<n;i++){\n\t\tcin>>a[i];\n\t}\n\tfor(i=0;i<n;i++){\n\t\tif(i==n-1){\n\t\t\tb[n-1]=a[n-1]-a[0];\n\t\t}else{\n\t\t\tb[i]=a[i]-a[i+1];\n\t\t}\n\t\tif(b[i]<0){\n\t\t\tj=(-b[i])/n+1;\n\t\t\tb[i]+=j*n;\n\t\t}\n\t}\n\tk=b[0]%n;\n\tfor(i=0;i<n;i++){\n\t\tif(b[i]%n!=k){\n\t\t\tmiss=true;\n\t\t\tbreak;\n\t\t}\n\t}\n\tif(miss){\n\t\tcout<<\"NO\"<<endl;\n\t}else{\n\t\tcout<<\"YES\"<<endl;\n\t}\n\treturn 0;\n}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nThere are N boxes arranged in a circle. The i-th box contains A_i stones.\n\nDetermine whether it is possible to remove all the stones from the boxes by repeatedly performing the following operation:\n\nSelect one box. Let the box be the i-th box. Then, for each j from 1 through N, remove exactly j stones from the (i+j)-th box. Here, the (N+k)-th box is identified with the k-th box.\n\nNote that the operation cannot be performed if there is a box that does not contain enough number of stones to be removed.\n\nConstraints\n\n1 ≦ N ≦ 10^5\n\n1 ≦ A_i ≦ 10^9\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1 A_2 … A_N\n\nOutput\n\nIf it is possible to remove all the stones from the boxes, print YES. Otherwise, print NO.\n\nSample Input 1\n\n5\n4 5 1 2 3\n\nSample Output 1\n\nYES\n\nAll the stones can be removed in one operation by selecting the second box.\n\nSample Input 2\n\n5\n6 9 12 10 8\n\nSample Output 2\n\nYES\n\nSample Input 3\n\n4\n1 2 3 1\n\nSample Output 3\n\nNO", "sample_input": "5\n4 5 1 2 3\n"}, "reference_outputs": ["YES\n"], "source_document_id": "p03808", "source_text": "Score : 500 points\n\nProblem Statement\n\nThere are N boxes arranged in a circle. The i-th box contains A_i stones.\n\nDetermine whether it is possible to remove all the stones from the boxes by repeatedly performing the following operation:\n\nSelect one box. Let the box be the i-th box. Then, for each j from 1 through N, remove exactly j stones from the (i+j)-th box. Here, the (N+k)-th box is identified with the k-th box.\n\nNote that the operation cannot be performed if there is a box that does not contain enough number of stones to be removed.\n\nConstraints\n\n1 ≦ N ≦ 10^5\n\n1 ≦ A_i ≦ 10^9\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1 A_2 … A_N\n\nOutput\n\nIf it is possible to remove all the stones from the boxes, print YES. Otherwise, print NO.\n\nSample Input 1\n\n5\n4 5 1 2 3\n\nSample Output 1\n\nYES\n\nAll the stones can be removed in one operation by selecting the second box.\n\nSample Input 2\n\n5\n6 9 12 10 8\n\nSample Output 2\n\nYES\n\nSample Input 3\n\n4\n1 2 3 1\n\nSample Output 3\n\nNO", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 490, "cpu_time_ms": 49, "memory_kb": 1024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s694941027", "group_id": "codeNet:p03808", "input_text": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define INF 1001000100010001000\n#define MOD 1000000007\n#define EPS 1e-10\n#define int long long\n#define rep(i, N) for (int i = 0; i < N; i++)\n#define Rep(i, N) for (int i = 1; i < N; i++)\n#define For(i, a, b) for (int i = (a); i < (b); i++)\n#define pb push_back\n#define mp make_pair\n#define i_i pair<int, int>\n#define vi vector<int>\n#define vvi vector<vi >\n#define vb vector<bool>\n#define vvb vector<vb >\n#define vp vector< i_i >\n#define all(a) (a).begin(), (a).end()\n#define Int(x) int x; scanf(\"%lld\", &x);\n\n//int dxy[5] = {0, 1, 0, -1, 0};\n// assign\n\nsigned main()\n{\n    Int(n);\n    int sum = 0;\n    vi data(n, 0);\n    rep(i, n) {\n        cin >> data[i];\n        sum += data[i];\n    }\n\n    int k = sum / (n * (n + 1) / 2);\n    if (k * (n * (n + 1) / 2) != sum) {\n        cout << \"NO\" << endl;\n        return 0;\n    }\n\n    vi dist(n, 0);\n\n    rep(i, n-1) {\n        dist[i] = data[i+1] - data[i] - k;\n    }\n    dist[n-1] = data[0] - data[n-1] - k;\n\n    rep(i, n) {\n        if (dist[i] <= 0 && (-dist[i]) % n) {\n            cout << \"NO\" << endl;\n            return 0;\n        }\n    }\n    cout << \"YES\" << endl;\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1486269447, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03808.html", "problem_id": "p03808", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03808/input.txt", "sample_output_relpath": "derived/input_output/data/p03808/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03808/C++/s694941027.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s694941027", "user_id": "u572468811"}, "prompt_components": {"gold_output": "YES\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define INF 1001000100010001000\n#define MOD 1000000007\n#define EPS 1e-10\n#define int long long\n#define rep(i, N) for (int i = 0; i < N; i++)\n#define Rep(i, N) for (int i = 1; i < N; i++)\n#define For(i, a, b) for (int i = (a); i < (b); i++)\n#define pb push_back\n#define mp make_pair\n#define i_i pair<int, int>\n#define vi vector<int>\n#define vvi vector<vi >\n#define vb vector<bool>\n#define vvb vector<vb >\n#define vp vector< i_i >\n#define all(a) (a).begin(), (a).end()\n#define Int(x) int x; scanf(\"%lld\", &x);\n\n//int dxy[5] = {0, 1, 0, -1, 0};\n// assign\n\nsigned main()\n{\n    Int(n);\n    int sum = 0;\n    vi data(n, 0);\n    rep(i, n) {\n        cin >> data[i];\n        sum += data[i];\n    }\n\n    int k = sum / (n * (n + 1) / 2);\n    if (k * (n * (n + 1) / 2) != sum) {\n        cout << \"NO\" << endl;\n        return 0;\n    }\n\n    vi dist(n, 0);\n\n    rep(i, n-1) {\n        dist[i] = data[i+1] - data[i] - k;\n    }\n    dist[n-1] = data[0] - data[n-1] - k;\n\n    rep(i, n) {\n        if (dist[i] <= 0 && (-dist[i]) % n) {\n            cout << \"NO\" << endl;\n            return 0;\n        }\n    }\n    cout << \"YES\" << endl;\n    return 0;\n}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nThere are N boxes arranged in a circle. The i-th box contains A_i stones.\n\nDetermine whether it is possible to remove all the stones from the boxes by repeatedly performing the following operation:\n\nSelect one box. Let the box be the i-th box. Then, for each j from 1 through N, remove exactly j stones from the (i+j)-th box. Here, the (N+k)-th box is identified with the k-th box.\n\nNote that the operation cannot be performed if there is a box that does not contain enough number of stones to be removed.\n\nConstraints\n\n1 ≦ N ≦ 10^5\n\n1 ≦ A_i ≦ 10^9\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1 A_2 … A_N\n\nOutput\n\nIf it is possible to remove all the stones from the boxes, print YES. Otherwise, print NO.\n\nSample Input 1\n\n5\n4 5 1 2 3\n\nSample Output 1\n\nYES\n\nAll the stones can be removed in one operation by selecting the second box.\n\nSample Input 2\n\n5\n6 9 12 10 8\n\nSample Output 2\n\nYES\n\nSample Input 3\n\n4\n1 2 3 1\n\nSample Output 3\n\nNO", "sample_input": "5\n4 5 1 2 3\n"}, "reference_outputs": ["YES\n"], "source_document_id": "p03808", "source_text": "Score : 500 points\n\nProblem Statement\n\nThere are N boxes arranged in a circle. The i-th box contains A_i stones.\n\nDetermine whether it is possible to remove all the stones from the boxes by repeatedly performing the following operation:\n\nSelect one box. Let the box be the i-th box. Then, for each j from 1 through N, remove exactly j stones from the (i+j)-th box. Here, the (N+k)-th box is identified with the k-th box.\n\nNote that the operation cannot be performed if there is a box that does not contain enough number of stones to be removed.\n\nConstraints\n\n1 ≦ N ≦ 10^5\n\n1 ≦ A_i ≦ 10^9\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1 A_2 … A_N\n\nOutput\n\nIf it is possible to remove all the stones from the boxes, print YES. Otherwise, print NO.\n\nSample Input 1\n\n5\n4 5 1 2 3\n\nSample Output 1\n\nYES\n\nAll the stones can be removed in one operation by selecting the second box.\n\nSample Input 2\n\n5\n6 9 12 10 8\n\nSample Output 2\n\nYES\n\nSample Input 3\n\n4\n1 2 3 1\n\nSample Output 3\n\nNO", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1174, "cpu_time_ms": 52, "memory_kb": 1792}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s603069162", "group_id": "codeNet:p03809", "input_text": "#include <iostream>\n#include <cstdio>\n#include <algorithm>\n#include <vector>\n#include <cstring>\n\nusing namespace std;\n\n#define x first\n#define y second\n#define mp make_pair\n#define pb push_back\n\n#define no {printf(\"NO\\n\"); return 0;}\n\ntypedef long long ll;\n\nconst ll MOD = 1e9+7;\n\nint a[100005];\n\nvector <int> v[100005];\n\nint br[100005];\n\nvoid dfs(int x, int par) {\n\tint uk = 2*a[x];\n\tfor (int i=0 ; i<v[x].size() ; i++) {\n\t\tif (v[x][i] == par) continue;\n\t\tdfs(v[x][i], x);\n\t\tuk -= br[v[x][i]];\n\t}\n\tbr[x] = uk;\n\tif (v[x].size() == 1) br[x]/=2;\n}\n\nint main() {\n\tint n;\n\tscanf(\"%d\", &n);\n\tfor (int i=1 ; i<=n ; i++) {\n\t\tscanf(\"%d\", a+i);\n\t}\n\tfor (int i=0 ; i<n-1 ; i++) {\n\t\tint x,y;\n\t\tscanf(\"%d%d\", &x, &y);\n\t\tv[x].pb(y);\n\t\tv[y].pb(x);\n\t}\n\tdfs(1, 0);\n\t//for (int i=1 ; i<=n ; i++) cout <<br[i]<<\" \";\n\tif (br[1]) no;\n\tfor (int i=2 ; i<=n ; i++) {\n\t\tif (br[i] > a[i]) no;\n\t}\n\tprintf(\"YES\\n\");\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1575434085, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03809.html", "problem_id": "p03809", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03809/input.txt", "sample_output_relpath": "derived/input_output/data/p03809/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03809/C++/s603069162.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s603069162", "user_id": "u828669332"}, "prompt_components": {"gold_output": "YES\n", "input_to_evaluate": "#include <iostream>\n#include <cstdio>\n#include <algorithm>\n#include <vector>\n#include <cstring>\n\nusing namespace std;\n\n#define x first\n#define y second\n#define mp make_pair\n#define pb push_back\n\n#define no {printf(\"NO\\n\"); return 0;}\n\ntypedef long long ll;\n\nconst ll MOD = 1e9+7;\n\nint a[100005];\n\nvector <int> v[100005];\n\nint br[100005];\n\nvoid dfs(int x, int par) {\n\tint uk = 2*a[x];\n\tfor (int i=0 ; i<v[x].size() ; i++) {\n\t\tif (v[x][i] == par) continue;\n\t\tdfs(v[x][i], x);\n\t\tuk -= br[v[x][i]];\n\t}\n\tbr[x] = uk;\n\tif (v[x].size() == 1) br[x]/=2;\n}\n\nint main() {\n\tint n;\n\tscanf(\"%d\", &n);\n\tfor (int i=1 ; i<=n ; i++) {\n\t\tscanf(\"%d\", a+i);\n\t}\n\tfor (int i=0 ; i<n-1 ; i++) {\n\t\tint x,y;\n\t\tscanf(\"%d%d\", &x, &y);\n\t\tv[x].pb(y);\n\t\tv[y].pb(x);\n\t}\n\tdfs(1, 0);\n\t//for (int i=1 ; i<=n ; i++) cout <<br[i]<<\" \";\n\tif (br[1]) no;\n\tfor (int i=2 ; i<=n ; i++) {\n\t\tif (br[i] > a[i]) no;\n\t}\n\tprintf(\"YES\\n\");\n\treturn 0;\n}", "problem_context": "Score : 700 points\n\nProblem Statement\n\nThere is a tree with N vertices, numbered 1 through N.\nThe i-th of the N-1 edges connects vertices a_i and b_i.\n\nCurrently, there are A_i stones placed on vertex i.\nDetermine whether it is possible to remove all the stones from the vertices by repeatedly performing the following operation:\n\nSelect a pair of different leaves. Then, remove exactly one stone from every vertex on the path between those two vertices.\nHere, a leaf is a vertex of the tree whose degree is 1, and the selected leaves themselves are also considered as vertices on the path connecting them.\n\nNote that the operation cannot be performed if there is a vertex with no stone on the path.\n\nConstraints\n\n2 ≦ N ≦ 10^5\n\n1 ≦ a_i,b_i ≦ N\n\n0 ≦ A_i ≦ 10^9\n\nThe given graph is a tree.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1 A_2 … A_N\na_1 b_1\n:\na_{N-1} b_{N-1}\n\nOutput\n\nIf it is possible to remove all the stones from the vertices, print YES. Otherwise, print NO.\n\nSample Input 1\n\n5\n1 2 1 1 2\n2 4\n5 2\n3 2\n1 3\n\nSample Output 1\n\nYES\n\nAll the stones can be removed, as follows:\n\nSelect vertices 4 and 5. Then, there is one stone remaining on each vertex except 4.\n\nSelect vertices 1 and 5. Then, there is no stone on any vertex.\n\nSample Input 2\n\n3\n1 2 1\n1 2\n2 3\n\nSample Output 2\n\nNO\n\nSample Input 3\n\n6\n3 2 2 2 2 2\n1 2\n2 3\n1 4\n1 5\n4 6\n\nSample Output 3\n\nYES", "sample_input": "5\n1 2 1 1 2\n2 4\n5 2\n3 2\n1 3\n"}, "reference_outputs": ["YES\n"], "source_document_id": "p03809", "source_text": "Score : 700 points\n\nProblem Statement\n\nThere is a tree with N vertices, numbered 1 through N.\nThe i-th of the N-1 edges connects vertices a_i and b_i.\n\nCurrently, there are A_i stones placed on vertex i.\nDetermine whether it is possible to remove all the stones from the vertices by repeatedly performing the following operation:\n\nSelect a pair of different leaves. Then, remove exactly one stone from every vertex on the path between those two vertices.\nHere, a leaf is a vertex of the tree whose degree is 1, and the selected leaves themselves are also considered as vertices on the path connecting them.\n\nNote that the operation cannot be performed if there is a vertex with no stone on the path.\n\nConstraints\n\n2 ≦ N ≦ 10^5\n\n1 ≦ a_i,b_i ≦ N\n\n0 ≦ A_i ≦ 10^9\n\nThe given graph is a tree.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1 A_2 … A_N\na_1 b_1\n:\na_{N-1} b_{N-1}\n\nOutput\n\nIf it is possible to remove all the stones from the vertices, print YES. Otherwise, print NO.\n\nSample Input 1\n\n5\n1 2 1 1 2\n2 4\n5 2\n3 2\n1 3\n\nSample Output 1\n\nYES\n\nAll the stones can be removed, as follows:\n\nSelect vertices 4 and 5. Then, there is one stone remaining on each vertex except 4.\n\nSelect vertices 1 and 5. Then, there is no stone on any vertex.\n\nSample Input 2\n\n3\n1 2 1\n1 2\n2 3\n\nSample Output 2\n\nNO\n\nSample Input 3\n\n6\n3 2 2 2 2 2\n1 2\n2 3\n1 4\n1 5\n4 6\n\nSample Output 3\n\nYES", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 901, "cpu_time_ms": 51, "memory_kb": 13184}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s543123094", "group_id": "codeNet:p03809", "input_text": "#include <iostream>\n#include <sstream>\n#include <vector>\n#include <cmath>\n#include <ctime>\n#include <cassert>\n#include <iomanip>\n#include <cstdio>\n#include <float.h>\n#include <queue>\n#include <set>\n#include <map>\n#include <fstream>\n#include <cstdlib>\n#include <string>\n#include <cstring>\n#include <algorithm>\n#include <numeric>\n#include <stack>\n#include <functional>\n       \nusing namespace std;\n       \n#define endl '\\n'\n#define MOD 1000000007\n#define INF 1ll<<30\n \n// #define MAX 100010\n \n#define eps 1e-11\n#define bit_max 1ll<<32\n#define _USE_MATH_DEFINES\n\nint a[1234567];\nvector<int> g[1234567];\nbool poss;  \n\nint dfs(int u,int v)\n{\n    int sum = 0;\n    int cnt = 0;\n    int mx = 0;\n    for(int i=0;i<g[u].size();i++)\n    {\n        int zolo = g[u][i];\n        if(zolo==v)\n            continue;\n        cnt++;\n        int temp = dfs(zolo,u);\n        sum+=temp;\n        mx = max(mx,temp);\n    }\n    if(cnt == 0)\n        return a[u];\n    if(a[u]>sum||a[u]<mx||(2*a[u])<sum)\n    {\n        poss = true;\n        return 0;\n    }\n    return 2*a[u]-sum;\n}\n\nint main()\n{\n    ios_base::sync_with_stdio(false);\n    cin.tie(NULL);\n    cout.tie(NULL);\n    // #ifndef ONLINE_JUDGE\n        // freopen(\"input.txt\",\"r\",stdin);\n        // freopen(\"output.txt\",\"w\",stdout);\n    // #endif\n    long long int n;\n    cin>>n;\n    for(int i=0;i<n;i++)\n    {\n        cin>>a[i];\n    }\n    if(n==2)\n    {\n        if(a[0]==a[1])\n            cout<<\"YES\";\n        else\n            cout<<\"NO\";\n        cout<<endl;\n        return 0;\n    }\n    for(int i=0;i<n-1;i++)\n    {\n        int x,y;\n        cin>>x>>y;\n        x--;y--;\n        g[x].push_back(y);\n        g[y].push_back(x);\n    }\n    poss = false;\n    int temp=1;\n    for(int i=0;i<n;i++)\n    {\n        if(g[i].size()>1)\n        {\n            temp = dfs(i,-1);\n            break;\n        }\n    }\n    if(temp==0&&!poss)\n        cout<<\"YES\";\n    else\n        cout<<\"NO\";\n    cout<<endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1486508773, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03809.html", "problem_id": "p03809", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03809/input.txt", "sample_output_relpath": "derived/input_output/data/p03809/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03809/C++/s543123094.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s543123094", "user_id": "u566864240"}, "prompt_components": {"gold_output": "YES\n", "input_to_evaluate": "#include <iostream>\n#include <sstream>\n#include <vector>\n#include <cmath>\n#include <ctime>\n#include <cassert>\n#include <iomanip>\n#include <cstdio>\n#include <float.h>\n#include <queue>\n#include <set>\n#include <map>\n#include <fstream>\n#include <cstdlib>\n#include <string>\n#include <cstring>\n#include <algorithm>\n#include <numeric>\n#include <stack>\n#include <functional>\n       \nusing namespace std;\n       \n#define endl '\\n'\n#define MOD 1000000007\n#define INF 1ll<<30\n \n// #define MAX 100010\n \n#define eps 1e-11\n#define bit_max 1ll<<32\n#define _USE_MATH_DEFINES\n\nint a[1234567];\nvector<int> g[1234567];\nbool poss;  \n\nint dfs(int u,int v)\n{\n    int sum = 0;\n    int cnt = 0;\n    int mx = 0;\n    for(int i=0;i<g[u].size();i++)\n    {\n        int zolo = g[u][i];\n        if(zolo==v)\n            continue;\n        cnt++;\n        int temp = dfs(zolo,u);\n        sum+=temp;\n        mx = max(mx,temp);\n    }\n    if(cnt == 0)\n        return a[u];\n    if(a[u]>sum||a[u]<mx||(2*a[u])<sum)\n    {\n        poss = true;\n        return 0;\n    }\n    return 2*a[u]-sum;\n}\n\nint main()\n{\n    ios_base::sync_with_stdio(false);\n    cin.tie(NULL);\n    cout.tie(NULL);\n    // #ifndef ONLINE_JUDGE\n        // freopen(\"input.txt\",\"r\",stdin);\n        // freopen(\"output.txt\",\"w\",stdout);\n    // #endif\n    long long int n;\n    cin>>n;\n    for(int i=0;i<n;i++)\n    {\n        cin>>a[i];\n    }\n    if(n==2)\n    {\n        if(a[0]==a[1])\n            cout<<\"YES\";\n        else\n            cout<<\"NO\";\n        cout<<endl;\n        return 0;\n    }\n    for(int i=0;i<n-1;i++)\n    {\n        int x,y;\n        cin>>x>>y;\n        x--;y--;\n        g[x].push_back(y);\n        g[y].push_back(x);\n    }\n    poss = false;\n    int temp=1;\n    for(int i=0;i<n;i++)\n    {\n        if(g[i].size()>1)\n        {\n            temp = dfs(i,-1);\n            break;\n        }\n    }\n    if(temp==0&&!poss)\n        cout<<\"YES\";\n    else\n        cout<<\"NO\";\n    cout<<endl;\n    return 0;\n}", "problem_context": "Score : 700 points\n\nProblem Statement\n\nThere is a tree with N vertices, numbered 1 through N.\nThe i-th of the N-1 edges connects vertices a_i and b_i.\n\nCurrently, there are A_i stones placed on vertex i.\nDetermine whether it is possible to remove all the stones from the vertices by repeatedly performing the following operation:\n\nSelect a pair of different leaves. Then, remove exactly one stone from every vertex on the path between those two vertices.\nHere, a leaf is a vertex of the tree whose degree is 1, and the selected leaves themselves are also considered as vertices on the path connecting them.\n\nNote that the operation cannot be performed if there is a vertex with no stone on the path.\n\nConstraints\n\n2 ≦ N ≦ 10^5\n\n1 ≦ a_i,b_i ≦ N\n\n0 ≦ A_i ≦ 10^9\n\nThe given graph is a tree.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1 A_2 … A_N\na_1 b_1\n:\na_{N-1} b_{N-1}\n\nOutput\n\nIf it is possible to remove all the stones from the vertices, print YES. Otherwise, print NO.\n\nSample Input 1\n\n5\n1 2 1 1 2\n2 4\n5 2\n3 2\n1 3\n\nSample Output 1\n\nYES\n\nAll the stones can be removed, as follows:\n\nSelect vertices 4 and 5. Then, there is one stone remaining on each vertex except 4.\n\nSelect vertices 1 and 5. Then, there is no stone on any vertex.\n\nSample Input 2\n\n3\n1 2 1\n1 2\n2 3\n\nSample Output 2\n\nNO\n\nSample Input 3\n\n6\n3 2 2 2 2 2\n1 2\n2 3\n1 4\n1 5\n4 6\n\nSample Output 3\n\nYES", "sample_input": "5\n1 2 1 1 2\n2 4\n5 2\n3 2\n1 3\n"}, "reference_outputs": ["YES\n"], "source_document_id": "p03809", "source_text": "Score : 700 points\n\nProblem Statement\n\nThere is a tree with N vertices, numbered 1 through N.\nThe i-th of the N-1 edges connects vertices a_i and b_i.\n\nCurrently, there are A_i stones placed on vertex i.\nDetermine whether it is possible to remove all the stones from the vertices by repeatedly performing the following operation:\n\nSelect a pair of different leaves. Then, remove exactly one stone from every vertex on the path between those two vertices.\nHere, a leaf is a vertex of the tree whose degree is 1, and the selected leaves themselves are also considered as vertices on the path connecting them.\n\nNote that the operation cannot be performed if there is a vertex with no stone on the path.\n\nConstraints\n\n2 ≦ N ≦ 10^5\n\n1 ≦ a_i,b_i ≦ N\n\n0 ≦ A_i ≦ 10^9\n\nThe given graph is a tree.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1 A_2 … A_N\na_1 b_1\n:\na_{N-1} b_{N-1}\n\nOutput\n\nIf it is possible to remove all the stones from the vertices, print YES. Otherwise, print NO.\n\nSample Input 1\n\n5\n1 2 1 1 2\n2 4\n5 2\n3 2\n1 3\n\nSample Output 1\n\nYES\n\nAll the stones can be removed, as follows:\n\nSelect vertices 4 and 5. Then, there is one stone remaining on each vertex except 4.\n\nSelect vertices 1 and 5. Then, there is no stone on any vertex.\n\nSample Input 2\n\n3\n1 2 1\n1 2\n2 3\n\nSample Output 2\n\nNO\n\nSample Input 3\n\n6\n3 2 2 2 2 2\n1 2\n2 3\n1 4\n1 5\n4 6\n\nSample Output 3\n\nYES", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1925, "cpu_time_ms": 86, "memory_kb": 39424}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s083494942", "group_id": "codeNet:p03809", "input_text": "#include <iostream>\n#include <vector>\n#include <cstdio>\n#include <sstream>\n#include <map>\n#include <string>\n#include <algorithm>\n#include <queue>\n#include <cmath>\n#include <functional>\n#include <set>\n#include <ctime>\n#include <random>\n#include <chrono>\n#include <cassert>\n#include <tuple>\n#include <utility>\nusing namespace std;\n\nnamespace {\n  using Integer = long long; //__int128;\n  template<class T, class S> istream& operator >> (istream& is, pair<T,S>& p){return is >> p.first >> p.second;}\n  template<class T> istream& operator >> (istream& is, vector<T>& vec){for(T& val: vec) is >> val; return is;}\n  template<class T> istream& operator ,  (istream& is, T& val){ return is >> val;}\n  template<class T, class S> ostream& operator << (ostream& os, const pair<T,S>& p){return os << p.first << \" \" << p.second;}\n  template<class T> ostream& operator << (ostream& os, const vector<T>& vec){for(size_t i=0; i<vec.size(); i++) os << vec[i] << (i==vec.size()-1?\"\":\" \"); return os;}\n  template<class T> ostream& operator ,  (ostream& os, const T& val){ return os << \" \" << val;}\n\n  template<class H> void print(const H& head){ cout << head; }\n  template<class H, class ... T> void print(const H& head, const T& ... tail){ cout << head << \" \"; print(tail...); }\n  template<class ... T> void println(const T& ... values){ print(values...); cout << endl; }\n\n  template<class H> void eprint(const H& head){ cerr << head; }\n  template<class H, class ... T> void eprint(const H& head, const T& ... tail){ cerr << head << \" \"; eprint(tail...); }\n  template<class ... T> void eprintln(const T& ... values){ eprint(values...); cerr << endl; }\n\n  class range{ Integer start_, end_, step_; public: struct range_iterator{ Integer val, step_; range_iterator(Integer v, Integer step) : val(v), step_(step) {} Integer operator * (){return val;} void operator ++ (){val += step_;} bool operator != (range_iterator& x){return step_ > 0 ? val < x.val : val > x.val;} }; range(Integer len) : start_(0), end_(len), step_(1) {} range(Integer start, Integer end) : start_(start), end_(end), step_(1) {} range(Integer start, Integer end, Integer step) : start_(start), end_(end), step_(step) {} range_iterator begin(){ return range_iterator(start_, step_); } range_iterator   end(){ return range_iterator(  end_, step_); } };\n\n  inline string operator \"\" _s (const char* str, size_t size){ return move(string(str)); }\n  constexpr Integer my_pow(Integer x, Integer k, Integer z=1){return k==0 ? z : k==1 ? z*x : (k&1) ? my_pow(x*x,k>>1,z*x) : my_pow(x*x,k>>1,z);}\n  constexpr Integer my_pow_mod(Integer x, Integer k, Integer M, Integer z=1){return k==0 ? z%M : k==1 ? z*x%M : (k&1) ? my_pow_mod(x*x%M,k>>1,M,z*x%M) : my_pow_mod(x*x%M,k>>1,M,z);}\n  constexpr unsigned long long operator \"\" _ten (unsigned long long value){ return my_pow(10,value); }\n\n  inline int k_bit(Integer x, int k){return (x>>k)&1;} //0-indexed\n\n  mt19937 mt(chrono::duration_cast<chrono::nanoseconds>(chrono::steady_clock::now().time_since_epoch()).count());\n\n  template<class T> string join(const vector<T>& v, const string& sep){ stringstream ss; for(size_t i=0; i<v.size(); i++){ if(i>0) ss << sep; ss << v[i]; } return ss.str(); }\n\n  inline string operator * (string s, int k){ string ret; while(k){ if(k&1) ret += s; s += s; k >>= 1; } return ret; }\n}\nconstexpr long long mod = 9_ten + 7;\n\nlong long dfs(vector<vector<int>>& G, vector<long long>& a, int pos, int last){\n  if(G[pos].size() == 1) return a[pos];\n\n  long long mx  = 0;\n  long long sum = 0;\n  for(int nx : G[pos]){\n    if(nx == last) continue;\n    long long tmp = dfs(G, a, nx, pos);\n    if(tmp == -1) return -1;\n    mx = max(tmp, mx);\n    sum += tmp;\n  }\n\n  long long p = sum - a[pos];\n  long long max_p;\n  if(sum/2 >= mx){\n    max_p = sum/2;\n  }else{\n    max_p = sum - mx;\n  }\n  if(max_p < p){\n    return -1;\n  }\n  long long d = sum - 2*p;\n  if(d < 0 || p < 0){\n    return -1;\n  }\n  if( d + p == a[pos] ){\n    return d;\n  }else{\n    return -1;\n  }\n\n}\n\nint main(){\n  int n;\n  cin >> n;\n  vector<long long> a(n);\n  cin >> a;\n  vector<vector<int>> G(n);\n  for(auto i : range(n-1) ){\n    int u,v;\n    cin >> u,v;\n    u--; v--;\n    G[u].push_back(v);\n    G[v].push_back(u);\n  }\n\n  if(n == 2){\n    println(a[0] == a[1] ? \"YES\" : \"NO\");\n    return 0;\n  }\n\n  int root = -1;\n  for(int i=0; i<n; i++){\n    if(G[i].size() >= 2){\n      root = i;\n      break;\n    }\n  }\n\n  auto res = dfs(G, a, root, -1);\n\n  if(res == 0){\n    println(\"YES\");\n  }else{\n    println(\"NO\");\n  }\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1486274886, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03809.html", "problem_id": "p03809", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03809/input.txt", "sample_output_relpath": "derived/input_output/data/p03809/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03809/C++/s083494942.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s083494942", "user_id": "u075551644"}, "prompt_components": {"gold_output": "YES\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\n#include <cstdio>\n#include <sstream>\n#include <map>\n#include <string>\n#include <algorithm>\n#include <queue>\n#include <cmath>\n#include <functional>\n#include <set>\n#include <ctime>\n#include <random>\n#include <chrono>\n#include <cassert>\n#include <tuple>\n#include <utility>\nusing namespace std;\n\nnamespace {\n  using Integer = long long; //__int128;\n  template<class T, class S> istream& operator >> (istream& is, pair<T,S>& p){return is >> p.first >> p.second;}\n  template<class T> istream& operator >> (istream& is, vector<T>& vec){for(T& val: vec) is >> val; return is;}\n  template<class T> istream& operator ,  (istream& is, T& val){ return is >> val;}\n  template<class T, class S> ostream& operator << (ostream& os, const pair<T,S>& p){return os << p.first << \" \" << p.second;}\n  template<class T> ostream& operator << (ostream& os, const vector<T>& vec){for(size_t i=0; i<vec.size(); i++) os << vec[i] << (i==vec.size()-1?\"\":\" \"); return os;}\n  template<class T> ostream& operator ,  (ostream& os, const T& val){ return os << \" \" << val;}\n\n  template<class H> void print(const H& head){ cout << head; }\n  template<class H, class ... T> void print(const H& head, const T& ... tail){ cout << head << \" \"; print(tail...); }\n  template<class ... T> void println(const T& ... values){ print(values...); cout << endl; }\n\n  template<class H> void eprint(const H& head){ cerr << head; }\n  template<class H, class ... T> void eprint(const H& head, const T& ... tail){ cerr << head << \" \"; eprint(tail...); }\n  template<class ... T> void eprintln(const T& ... values){ eprint(values...); cerr << endl; }\n\n  class range{ Integer start_, end_, step_; public: struct range_iterator{ Integer val, step_; range_iterator(Integer v, Integer step) : val(v), step_(step) {} Integer operator * (){return val;} void operator ++ (){val += step_;} bool operator != (range_iterator& x){return step_ > 0 ? val < x.val : val > x.val;} }; range(Integer len) : start_(0), end_(len), step_(1) {} range(Integer start, Integer end) : start_(start), end_(end), step_(1) {} range(Integer start, Integer end, Integer step) : start_(start), end_(end), step_(step) {} range_iterator begin(){ return range_iterator(start_, step_); } range_iterator   end(){ return range_iterator(  end_, step_); } };\n\n  inline string operator \"\" _s (const char* str, size_t size){ return move(string(str)); }\n  constexpr Integer my_pow(Integer x, Integer k, Integer z=1){return k==0 ? z : k==1 ? z*x : (k&1) ? my_pow(x*x,k>>1,z*x) : my_pow(x*x,k>>1,z);}\n  constexpr Integer my_pow_mod(Integer x, Integer k, Integer M, Integer z=1){return k==0 ? z%M : k==1 ? z*x%M : (k&1) ? my_pow_mod(x*x%M,k>>1,M,z*x%M) : my_pow_mod(x*x%M,k>>1,M,z);}\n  constexpr unsigned long long operator \"\" _ten (unsigned long long value){ return my_pow(10,value); }\n\n  inline int k_bit(Integer x, int k){return (x>>k)&1;} //0-indexed\n\n  mt19937 mt(chrono::duration_cast<chrono::nanoseconds>(chrono::steady_clock::now().time_since_epoch()).count());\n\n  template<class T> string join(const vector<T>& v, const string& sep){ stringstream ss; for(size_t i=0; i<v.size(); i++){ if(i>0) ss << sep; ss << v[i]; } return ss.str(); }\n\n  inline string operator * (string s, int k){ string ret; while(k){ if(k&1) ret += s; s += s; k >>= 1; } return ret; }\n}\nconstexpr long long mod = 9_ten + 7;\n\nlong long dfs(vector<vector<int>>& G, vector<long long>& a, int pos, int last){\n  if(G[pos].size() == 1) return a[pos];\n\n  long long mx  = 0;\n  long long sum = 0;\n  for(int nx : G[pos]){\n    if(nx == last) continue;\n    long long tmp = dfs(G, a, nx, pos);\n    if(tmp == -1) return -1;\n    mx = max(tmp, mx);\n    sum += tmp;\n  }\n\n  long long p = sum - a[pos];\n  long long max_p;\n  if(sum/2 >= mx){\n    max_p = sum/2;\n  }else{\n    max_p = sum - mx;\n  }\n  if(max_p < p){\n    return -1;\n  }\n  long long d = sum - 2*p;\n  if(d < 0 || p < 0){\n    return -1;\n  }\n  if( d + p == a[pos] ){\n    return d;\n  }else{\n    return -1;\n  }\n\n}\n\nint main(){\n  int n;\n  cin >> n;\n  vector<long long> a(n);\n  cin >> a;\n  vector<vector<int>> G(n);\n  for(auto i : range(n-1) ){\n    int u,v;\n    cin >> u,v;\n    u--; v--;\n    G[u].push_back(v);\n    G[v].push_back(u);\n  }\n\n  if(n == 2){\n    println(a[0] == a[1] ? \"YES\" : \"NO\");\n    return 0;\n  }\n\n  int root = -1;\n  for(int i=0; i<n; i++){\n    if(G[i].size() >= 2){\n      root = i;\n      break;\n    }\n  }\n\n  auto res = dfs(G, a, root, -1);\n\n  if(res == 0){\n    println(\"YES\");\n  }else{\n    println(\"NO\");\n  }\n  return 0;\n}\n", "problem_context": "Score : 700 points\n\nProblem Statement\n\nThere is a tree with N vertices, numbered 1 through N.\nThe i-th of the N-1 edges connects vertices a_i and b_i.\n\nCurrently, there are A_i stones placed on vertex i.\nDetermine whether it is possible to remove all the stones from the vertices by repeatedly performing the following operation:\n\nSelect a pair of different leaves. Then, remove exactly one stone from every vertex on the path between those two vertices.\nHere, a leaf is a vertex of the tree whose degree is 1, and the selected leaves themselves are also considered as vertices on the path connecting them.\n\nNote that the operation cannot be performed if there is a vertex with no stone on the path.\n\nConstraints\n\n2 ≦ N ≦ 10^5\n\n1 ≦ a_i,b_i ≦ N\n\n0 ≦ A_i ≦ 10^9\n\nThe given graph is a tree.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1 A_2 … A_N\na_1 b_1\n:\na_{N-1} b_{N-1}\n\nOutput\n\nIf it is possible to remove all the stones from the vertices, print YES. Otherwise, print NO.\n\nSample Input 1\n\n5\n1 2 1 1 2\n2 4\n5 2\n3 2\n1 3\n\nSample Output 1\n\nYES\n\nAll the stones can be removed, as follows:\n\nSelect vertices 4 and 5. Then, there is one stone remaining on each vertex except 4.\n\nSelect vertices 1 and 5. Then, there is no stone on any vertex.\n\nSample Input 2\n\n3\n1 2 1\n1 2\n2 3\n\nSample Output 2\n\nNO\n\nSample Input 3\n\n6\n3 2 2 2 2 2\n1 2\n2 3\n1 4\n1 5\n4 6\n\nSample Output 3\n\nYES", "sample_input": "5\n1 2 1 1 2\n2 4\n5 2\n3 2\n1 3\n"}, "reference_outputs": ["YES\n"], "source_document_id": "p03809", "source_text": "Score : 700 points\n\nProblem Statement\n\nThere is a tree with N vertices, numbered 1 through N.\nThe i-th of the N-1 edges connects vertices a_i and b_i.\n\nCurrently, there are A_i stones placed on vertex i.\nDetermine whether it is possible to remove all the stones from the vertices by repeatedly performing the following operation:\n\nSelect a pair of different leaves. Then, remove exactly one stone from every vertex on the path between those two vertices.\nHere, a leaf is a vertex of the tree whose degree is 1, and the selected leaves themselves are also considered as vertices on the path connecting them.\n\nNote that the operation cannot be performed if there is a vertex with no stone on the path.\n\nConstraints\n\n2 ≦ N ≦ 10^5\n\n1 ≦ a_i,b_i ≦ N\n\n0 ≦ A_i ≦ 10^9\n\nThe given graph is a tree.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1 A_2 … A_N\na_1 b_1\n:\na_{N-1} b_{N-1}\n\nOutput\n\nIf it is possible to remove all the stones from the vertices, print YES. Otherwise, print NO.\n\nSample Input 1\n\n5\n1 2 1 1 2\n2 4\n5 2\n3 2\n1 3\n\nSample Output 1\n\nYES\n\nAll the stones can be removed, as follows:\n\nSelect vertices 4 and 5. Then, there is one stone remaining on each vertex except 4.\n\nSelect vertices 1 and 5. Then, there is no stone on any vertex.\n\nSample Input 2\n\n3\n1 2 1\n1 2\n2 3\n\nSample Output 2\n\nNO\n\nSample Input 3\n\n6\n3 2 2 2 2 2\n1 2\n2 3\n1 4\n1 5\n4 6\n\nSample Output 3\n\nYES", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 4492, "cpu_time_ms": 131, "memory_kb": 14464}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s665878074", "group_id": "codeNet:p03810", "input_text": "#include<cstdio>\n#define N 110000\ninline char gc(){\n\tstatic char now[1<<16],*T,*S;\n\tif (T==S){T=(S=now)+fread(now,1,1<<16,stdin);if (T==S) return EOF;}\n\treturn *S++;\n} \ninline int read(){\n\tint x=0;char ch=gc();\n\twhile (ch<'0'||ch>'9') ch=gc();\n\twhile (ch<='9'&&ch>='0'){x=x*10+ch-'0';ch=gc();}\n\treturn x;\n}\ninline int gcd(int x,int y){\n\tif (y==0) return x;return gcd(y,x%y);\n}\nint cur,n,a[N],mod,g1[N],g2[N];long long sum;\nvoid printans(){\n\tif (!cur) printf(\"Second\");else printf(\"First\");\n}\nint main(){\n\t//freopen(\"d.in\",\"r\",stdin);\n\tn=read();\n\tfor (int i=1;i<=n;++i) a[i]=read(),(mod+=a[i]%2)%=2;\n\tif (n%2&&!mod) {printf(\"First\");return 0;}\n\tif (!n%2) {if (mod) printf(\"First\");else printf(\"Second\");return 0;}\n\twhile (1){sum=0;\n\t\tfor (int i=1;i<=n;++i) g1[i]=gcd(a[i],g1[i-1]);\n\t\tfor (int i=n;i>=1;--i) g2[i]=gcd(a[i],g2[i+1]);\n\t\tfor (int i=1;i<=n;++i) sum+=a[i];int g;\n\t\tfor (int i=1;i<=n;++i){\n\t\t\tif (a[i]==1) {printans();return 0;}\n\t\t\tg=gcd(g1[i-1],gcd(a[i]-1,g2[i+1]));\n\t\t\tif (((sum-1)/g)%2) break;\n\t\t}\n\t\tif (g==1) {printans();return 0;}\n\t\tfor (int i=1;i<=n;++i) a[i]/=g;\n\t\tcur^=1;\n\t}\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1509209237, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03810.html", "problem_id": "p03810", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03810/input.txt", "sample_output_relpath": "derived/input_output/data/p03810/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03810/C++/s665878074.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s665878074", "user_id": "u018679195"}, "prompt_components": {"gold_output": "First\n", "input_to_evaluate": "#include<cstdio>\n#define N 110000\ninline char gc(){\n\tstatic char now[1<<16],*T,*S;\n\tif (T==S){T=(S=now)+fread(now,1,1<<16,stdin);if (T==S) return EOF;}\n\treturn *S++;\n} \ninline int read(){\n\tint x=0;char ch=gc();\n\twhile (ch<'0'||ch>'9') ch=gc();\n\twhile (ch<='9'&&ch>='0'){x=x*10+ch-'0';ch=gc();}\n\treturn x;\n}\ninline int gcd(int x,int y){\n\tif (y==0) return x;return gcd(y,x%y);\n}\nint cur,n,a[N],mod,g1[N],g2[N];long long sum;\nvoid printans(){\n\tif (!cur) printf(\"Second\");else printf(\"First\");\n}\nint main(){\n\t//freopen(\"d.in\",\"r\",stdin);\n\tn=read();\n\tfor (int i=1;i<=n;++i) a[i]=read(),(mod+=a[i]%2)%=2;\n\tif (n%2&&!mod) {printf(\"First\");return 0;}\n\tif (!n%2) {if (mod) printf(\"First\");else printf(\"Second\");return 0;}\n\twhile (1){sum=0;\n\t\tfor (int i=1;i<=n;++i) g1[i]=gcd(a[i],g1[i-1]);\n\t\tfor (int i=n;i>=1;--i) g2[i]=gcd(a[i],g2[i+1]);\n\t\tfor (int i=1;i<=n;++i) sum+=a[i];int g;\n\t\tfor (int i=1;i<=n;++i){\n\t\t\tif (a[i]==1) {printans();return 0;}\n\t\t\tg=gcd(g1[i-1],gcd(a[i]-1,g2[i+1]));\n\t\t\tif (((sum-1)/g)%2) break;\n\t\t}\n\t\tif (g==1) {printans();return 0;}\n\t\tfor (int i=1;i<=n;++i) a[i]/=g;\n\t\tcur^=1;\n\t}\n\treturn 0;\n}", "problem_context": "Score : 1000 points\n\nProblem Statement\n\nThere are N integers written on a blackboard. The i-th integer is A_i, and the greatest common divisor of these integers is 1.\n\nTakahashi and Aoki will play a game using these integers. In this game, starting from Takahashi the two player alternately perform the following operation:\n\nSelect one integer on the blackboard that is not less than 2, and subtract 1 from the integer.\n\nThen, divide all the integers on the black board by g, where g is the greatest common divisor of the integers written on the blackboard.\n\nThe player who is left with only 1s on the blackboard and thus cannot perform the operation, loses the game.\nAssuming that both players play optimally, determine the winner of the game.\n\nConstraints\n\n1 ≦ N ≦ 10^5\n\n1 ≦ A_i ≦ 10^9\n\nThe greatest common divisor of the integers from A_1 through A_N is 1.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1 A_2 … A_N\n\nOutput\n\nIf Takahashi will win, print First. If Aoki will win, print Second.\n\nSample Input 1\n\n3\n3 6 7\n\nSample Output 1\n\nFirst\n\nTakahashi, the first player, can win as follows:\n\nTakahashi subtracts 1 from 7. Then, the integers become: (1,2,2).\n\nAoki subtracts 1 from 2. Then, the integers become: (1,1,2).\n\nTakahashi subtracts 1 from 2. Then, the integers become: (1,1,1).\n\nSample Input 2\n\n4\n1 2 4 8\n\nSample Output 2\n\nFirst\n\nSample Input 3\n\n5\n7 8 8 8 8\n\nSample Output 3\n\nSecond", "sample_input": "3\n3 6 7\n"}, "reference_outputs": ["First\n"], "source_document_id": "p03810", "source_text": "Score : 1000 points\n\nProblem Statement\n\nThere are N integers written on a blackboard. The i-th integer is A_i, and the greatest common divisor of these integers is 1.\n\nTakahashi and Aoki will play a game using these integers. In this game, starting from Takahashi the two player alternately perform the following operation:\n\nSelect one integer on the blackboard that is not less than 2, and subtract 1 from the integer.\n\nThen, divide all the integers on the black board by g, where g is the greatest common divisor of the integers written on the blackboard.\n\nThe player who is left with only 1s on the blackboard and thus cannot perform the operation, loses the game.\nAssuming that both players play optimally, determine the winner of the game.\n\nConstraints\n\n1 ≦ N ≦ 10^5\n\n1 ≦ A_i ≦ 10^9\n\nThe greatest common divisor of the integers from A_1 through A_N is 1.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1 A_2 … A_N\n\nOutput\n\nIf Takahashi will win, print First. If Aoki will win, print Second.\n\nSample Input 1\n\n3\n3 6 7\n\nSample Output 1\n\nFirst\n\nTakahashi, the first player, can win as follows:\n\nTakahashi subtracts 1 from 7. Then, the integers become: (1,2,2).\n\nAoki subtracts 1 from 2. Then, the integers become: (1,1,2).\n\nTakahashi subtracts 1 from 2. Then, the integers become: (1,1,1).\n\nSample Input 2\n\n4\n1 2 4 8\n\nSample Output 2\n\nFirst\n\nSample Input 3\n\n5\n7 8 8 8 8\n\nSample Output 3\n\nSecond", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1104, "cpu_time_ms": 45, "memory_kb": 1408}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s122845782", "group_id": "codeNet:p03815", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nlong long x;\n\nint main() {\n\tios_base::sync_with_stdio(false);\n\tcin.tie(0);\n\tcout.tie(0);\n\n\tcin >> x;\n\n\tlong long lo = 1, mid, hi = 1e15;\n\twhile (lo <= hi) {\n\t\tmid = (lo+hi) / 2;\n\t\tlong long R = (mid / 2 + (mid&1)) * 6 + (mid / 2) * 5;\n\t\tlong long L = R - ((mid&1) ? 6 : 5) + 1;\n\t\tif (L <= x && x <= R) {\n\t\t\tcout << mid << '\\n';\n\t\t\treturn 0;\n\t\t}\n\t\telse if (R <= x) {\n\t\t\tlo = mid+1;\n\t\t}\n\t\telse {\n\t\t\thi = mid-1;\n\t\t}\n\t}\n\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1585588890, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03815.html", "problem_id": "p03815", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03815/input.txt", "sample_output_relpath": "derived/input_output/data/p03815/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03815/C++/s122845782.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s122845782", "user_id": "u514760660"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nlong long x;\n\nint main() {\n\tios_base::sync_with_stdio(false);\n\tcin.tie(0);\n\tcout.tie(0);\n\n\tcin >> x;\n\n\tlong long lo = 1, mid, hi = 1e15;\n\twhile (lo <= hi) {\n\t\tmid = (lo+hi) / 2;\n\t\tlong long R = (mid / 2 + (mid&1)) * 6 + (mid / 2) * 5;\n\t\tlong long L = R - ((mid&1) ? 6 : 5) + 1;\n\t\tif (L <= x && x <= R) {\n\t\t\tcout << mid << '\\n';\n\t\t\treturn 0;\n\t\t}\n\t\telse if (R <= x) {\n\t\t\tlo = mid+1;\n\t\t}\n\t\telse {\n\t\t\thi = mid-1;\n\t\t}\n\t}\n\n\treturn 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nSnuke has decided to play with a six-sided die. Each of its six sides shows an integer 1 through 6, and two numbers on opposite sides always add up to 7.\n\nSnuke will first put the die on the table with an arbitrary side facing upward, then repeatedly perform the following operation:\n\nOperation: Rotate the die 90° toward one of the following directions: left, right, front (the die will come closer) and back (the die will go farther). Then, obtain y points where y is the number written in the side facing upward.\n\nFor example, let us consider the situation where the side showing 1 faces upward, the near side shows 5 and the right side shows 4, as illustrated in the figure.\nIf the die is rotated toward the right as shown in the figure, the side showing 3 will face upward.\nBesides, the side showing 4 will face upward if the die is rotated toward the left, the side showing 2 will face upward if the die is rotated toward the front, and the side showing 5 will face upward if the die is rotated toward the back.\n\nFind the minimum number of operation Snuke needs to perform in order to score at least x points in total.\n\nConstraints\n\n1 ≦ x ≦ 10^{15}\n\nx is an integer.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nx\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n7\n\nSample Output 1\n\n2\n\nSample Input 2\n\n149696127901\n\nSample Output 2\n\n27217477801", "sample_input": "7\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03815", "source_text": "Score : 300 points\n\nProblem Statement\n\nSnuke has decided to play with a six-sided die. Each of its six sides shows an integer 1 through 6, and two numbers on opposite sides always add up to 7.\n\nSnuke will first put the die on the table with an arbitrary side facing upward, then repeatedly perform the following operation:\n\nOperation: Rotate the die 90° toward one of the following directions: left, right, front (the die will come closer) and back (the die will go farther). Then, obtain y points where y is the number written in the side facing upward.\n\nFor example, let us consider the situation where the side showing 1 faces upward, the near side shows 5 and the right side shows 4, as illustrated in the figure.\nIf the die is rotated toward the right as shown in the figure, the side showing 3 will face upward.\nBesides, the side showing 4 will face upward if the die is rotated toward the left, the side showing 2 will face upward if the die is rotated toward the front, and the side showing 5 will face upward if the die is rotated toward the back.\n\nFind the minimum number of operation Snuke needs to perform in order to score at least x points in total.\n\nConstraints\n\n1 ≦ x ≦ 10^{15}\n\nx is an integer.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nx\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n7\n\nSample Output 1\n\n2\n\nSample Input 2\n\n149696127901\n\nSample Output 2\n\n27217477801", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 476, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s885244208", "group_id": "codeNet:p03818", "input_text": "#include<bits/stdc++.h>\n#define F first\n#define S second\n#define MP make_pair\n#define pb push_back\n#define endl '\\n'\n\nusing namespace std;\n\ntypedef long long LL;\ntypedef pair< int, int > P;\ntypedef pair< LL, LL > LP;\ntypedef pair< int, P > iP;\ntypedef pair< P, P > PP;\n\nstatic const int INF = INT_MAX;\nstatic const LL LINF = LLONG_MAX;\nstatic const int MIN = INT_MIN;\nstatic const LL LMIN = LLONG_MIN;\nstatic const int MOD = 1000000007;\nstatic const int SIZE = 100005;\n\nint dx[] = {0, -1, 1, 0};\nint dy[] = {-1, 0, 0, 1};\n\nint main() {\n    ios::sync_with_stdio(false);\n    cin.tie(0);\n    \n    int n;\n    cin >> n;\n    int cnt[SIZE] = {};\n    for( int i = 0; i < n; ++i ) {\n        int a;\n        cin >> a;\n        ++cnt[a];\n\n    }\n\n    int res = 0;\n    for( int i = 1; i < SIZE; ++i ) {\n        res += max( 0, cnt[i] - 1 );\n\n    }\n\n    if( res % 2 ) ++res;\n    cout << n - res << endl;\n\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1563669770, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03818.html", "problem_id": "p03818", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03818/input.txt", "sample_output_relpath": "derived/input_output/data/p03818/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03818/C++/s885244208.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s885244208", "user_id": "u254187258"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include<bits/stdc++.h>\n#define F first\n#define S second\n#define MP make_pair\n#define pb push_back\n#define endl '\\n'\n\nusing namespace std;\n\ntypedef long long LL;\ntypedef pair< int, int > P;\ntypedef pair< LL, LL > LP;\ntypedef pair< int, P > iP;\ntypedef pair< P, P > PP;\n\nstatic const int INF = INT_MAX;\nstatic const LL LINF = LLONG_MAX;\nstatic const int MIN = INT_MIN;\nstatic const LL LMIN = LLONG_MIN;\nstatic const int MOD = 1000000007;\nstatic const int SIZE = 100005;\n\nint dx[] = {0, -1, 1, 0};\nint dy[] = {-1, 0, 0, 1};\n\nint main() {\n    ios::sync_with_stdio(false);\n    cin.tie(0);\n    \n    int n;\n    cin >> n;\n    int cnt[SIZE] = {};\n    for( int i = 0; i < n; ++i ) {\n        int a;\n        cin >> a;\n        ++cnt[a];\n\n    }\n\n    int res = 0;\n    for( int i = 1; i < SIZE; ++i ) {\n        res += max( 0, cnt[i] - 1 );\n\n    }\n\n    if( res % 2 ) ++res;\n    cout << n - res << endl;\n\n    return 0;\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nSnuke has decided to play a game using cards.\nHe has a deck consisting of N cards. On the i-th card from the top, an integer A_i is written.\n\nHe will perform the operation described below zero or more times, so that the values written on the remaining cards will be pairwise distinct. Find the maximum possible number of remaining cards. Here, N is odd, which guarantees that at least one card can be kept.\n\nOperation: Take out three arbitrary cards from the deck. Among those three cards, eat two: one with the largest value, and another with the smallest value. Then, return the remaining one card to the deck.\n\nConstraints\n\n3 ≦ N ≦ 10^{5}\n\nN is odd.\n\n1 ≦ A_i ≦ 10^{5}\n\nA_i is an integer.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1 A_2 A_3 ... A_{N}\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n5\n1 2 1 3 7\n\nSample Output 1\n\n3\n\nOne optimal solution is to perform the operation once, taking out two cards with 1 and one card with 2. One card with 1 and another with 2 will be eaten, and the remaining card with 1 will be returned to deck. Then, the values written on the remaining cards in the deck will be pairwise distinct: 1, 3 and 7.\n\nSample Input 2\n\n15\n1 3 5 2 1 3 2 8 8 6 2 6 11 1 1\n\nSample Output 2\n\n7", "sample_input": "5\n1 2 1 3 7\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03818", "source_text": "Score : 400 points\n\nProblem Statement\n\nSnuke has decided to play a game using cards.\nHe has a deck consisting of N cards. On the i-th card from the top, an integer A_i is written.\n\nHe will perform the operation described below zero or more times, so that the values written on the remaining cards will be pairwise distinct. Find the maximum possible number of remaining cards. Here, N is odd, which guarantees that at least one card can be kept.\n\nOperation: Take out three arbitrary cards from the deck. Among those three cards, eat two: one with the largest value, and another with the smallest value. Then, return the remaining one card to the deck.\n\nConstraints\n\n3 ≦ N ≦ 10^{5}\n\nN is odd.\n\n1 ≦ A_i ≦ 10^{5}\n\nA_i is an integer.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1 A_2 A_3 ... A_{N}\n\nOutput\n\nPrint the answer.\n\nSample Input 1\n\n5\n1 2 1 3 7\n\nSample Output 1\n\n3\n\nOne optimal solution is to perform the operation once, taking out two cards with 1 and one card with 2. One card with 1 and another with 2 will be eaten, and the remaining card with 1 will be returned to deck. Then, the values written on the remaining cards in the deck will be pairwise distinct: 1, 3 and 7.\n\nSample Input 2\n\n15\n1 3 5 2 1 3 2 8 8 6 2 6 11 1 1\n\nSample Output 2\n\n7", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 904, "cpu_time_ms": 9, "memory_kb": 1276}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s005356230", "group_id": "codeNet:p03821", "input_text": "// AGC009_A\n#include <iostream>\n#include <cstdio>\n#include <string>\n#include <vector>\n#include <iterator>  // std::back_inserter()\n#include <tuple>  // std::tuple std::get\n#include <set>\n#include <map>\n#include <unordered_map>\n#include <unordered_set>\n#include <stack>\n#include <queue>\n#include <algorithm>  // std::copy()\n#include <functional>  // std::greater<T>()\n#include <utility>  // std::swap()\n#include <numeric>  // accumulate(ALL(vec), 0)  0 は初期値\n#include <bitset>  // static_cast<std::bitset<8>>\n#include <sstream>  // std::stringstream\n#include <cmath>\n#include <climits>  // INT_MIN\n#include <cctype>  // std::isdigit()\n#include <iomanip>  // std::setprecision()\nusing namespace std;\n\n#define ALL(obj) (obj).begin(), (obj).end()\n#define REP(i, n) for (ll i=0; i < n; i++)  // 0 ~ n-1\n#define REPN(i, n) for (ll i=1; i <= n; i++)  // 1 ~ n\n#define MIN(vec) min_element(ALL((vec)))  // イテレータのため、値を取り出すときは * を先頭につける\n#define MAX(vec) max_element(ALL((vec)))\n#define IDX(vec, element_iter) distance((vec).begin(), element_iter)\n#define SUM(vec) accumulate(ALL((vec)), 0LL)  // 0 は初期値\n#define COPY(vec1, vec2) copy(ALL(vec1), back_inserter(vec2))  // vec1をvec2にコピーする vec2は空にしておく必要あり\n#define zero_pad(num) setfill('0') << std::right << setw(num)\n#define space_pad(num) setfill(' ') << std::right << setw(num)\n\ntypedef long long ll;\n\nconst ll MOD7 = 1000000007;  // 1 000 000 007\nconst ll MOD9 = 1000000009;  // 1 000 000 009\n\nint main() {\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n\n    // input\n    ll N;\n    cin >> N;\n    vector<ll> A(N), B(N), diff(N);\n    REP(i, N) {\n        cin >> A[i] >> B[i];\n        if (A[i] <= B[i]) {\n            diff[i] = B[i] - A[i];\n        } else {\n            diff[i] = B[i] - A[i]%B[i];\n        }\n    }\n    \n    // calculation\n    // 何回押さないといけないか\n    reverse(diff.begin(), diff.end());\n    ll res = diff[0], now;\n    for (ll i = 1; i < N; ++i) {\n        now = A[i] + res;\n        if (now <= B[i]) {\n            res += B[i] - A[i];\n        } else {\n            res += B[i] - now%B[i];\n        }\n    }\n    \n    cout << res << \"\\n\";\n    \n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1550379681, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03821.html", "problem_id": "p03821", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03821/input.txt", "sample_output_relpath": "derived/input_output/data/p03821/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03821/C++/s005356230.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s005356230", "user_id": "u870998297"}, "prompt_components": {"gold_output": "7\n", "input_to_evaluate": "// AGC009_A\n#include <iostream>\n#include <cstdio>\n#include <string>\n#include <vector>\n#include <iterator>  // std::back_inserter()\n#include <tuple>  // std::tuple std::get\n#include <set>\n#include <map>\n#include <unordered_map>\n#include <unordered_set>\n#include <stack>\n#include <queue>\n#include <algorithm>  // std::copy()\n#include <functional>  // std::greater<T>()\n#include <utility>  // std::swap()\n#include <numeric>  // accumulate(ALL(vec), 0)  0 は初期値\n#include <bitset>  // static_cast<std::bitset<8>>\n#include <sstream>  // std::stringstream\n#include <cmath>\n#include <climits>  // INT_MIN\n#include <cctype>  // std::isdigit()\n#include <iomanip>  // std::setprecision()\nusing namespace std;\n\n#define ALL(obj) (obj).begin(), (obj).end()\n#define REP(i, n) for (ll i=0; i < n; i++)  // 0 ~ n-1\n#define REPN(i, n) for (ll i=1; i <= n; i++)  // 1 ~ n\n#define MIN(vec) min_element(ALL((vec)))  // イテレータのため、値を取り出すときは * を先頭につける\n#define MAX(vec) max_element(ALL((vec)))\n#define IDX(vec, element_iter) distance((vec).begin(), element_iter)\n#define SUM(vec) accumulate(ALL((vec)), 0LL)  // 0 は初期値\n#define COPY(vec1, vec2) copy(ALL(vec1), back_inserter(vec2))  // vec1をvec2にコピーする vec2は空にしておく必要あり\n#define zero_pad(num) setfill('0') << std::right << setw(num)\n#define space_pad(num) setfill(' ') << std::right << setw(num)\n\ntypedef long long ll;\n\nconst ll MOD7 = 1000000007;  // 1 000 000 007\nconst ll MOD9 = 1000000009;  // 1 000 000 009\n\nint main() {\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n\n    // input\n    ll N;\n    cin >> N;\n    vector<ll> A(N), B(N), diff(N);\n    REP(i, N) {\n        cin >> A[i] >> B[i];\n        if (A[i] <= B[i]) {\n            diff[i] = B[i] - A[i];\n        } else {\n            diff[i] = B[i] - A[i]%B[i];\n        }\n    }\n    \n    // calculation\n    // 何回押さないといけないか\n    reverse(diff.begin(), diff.end());\n    ll res = diff[0], now;\n    for (ll i = 1; i < N; ++i) {\n        now = A[i] + res;\n        if (now <= B[i]) {\n            res += B[i] - A[i];\n        } else {\n            res += B[i] - now%B[i];\n        }\n    }\n    \n    cout << res << \"\\n\";\n    \n    return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are an integer sequence A_1,...,A_N consisting of N terms, and N buttons.\nWhen the i-th (1 ≦ i ≦ N) button is pressed, the values of the i terms from the first through the i-th are all incremented by 1.\n\nThere is also another integer sequence B_1,...,B_N. Takahashi will push the buttons some number of times so that for every i, A_i will be a multiple of B_i.\n\nFind the minimum number of times Takahashi will press the buttons.\n\nConstraints\n\nAll input values are integers.\n\n1 ≦ N ≦ 10^5\n\n0 ≦ A_i ≦ 10^9(1 ≦ i ≦ N)\n\n1 ≦ B_i ≦ 10^9(1 ≦ i ≦ N)\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1 B_1\n:\nA_N B_N\n\nOutput\n\nPrint an integer representing the minimum number of times Takahashi will press the buttons.\n\nSample Input 1\n\n3\n3 5\n2 7\n9 4\n\nSample Output 1\n\n7\n\nPress the first button twice, the second button twice and the third button three times.\n\nSample Input 2\n\n7\n3 1\n4 1\n5 9\n2 6\n5 3\n5 8\n9 7\n\nSample Output 2\n\n22", "sample_input": "3\n3 5\n2 7\n9 4\n"}, "reference_outputs": ["7\n"], "source_document_id": "p03821", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are an integer sequence A_1,...,A_N consisting of N terms, and N buttons.\nWhen the i-th (1 ≦ i ≦ N) button is pressed, the values of the i terms from the first through the i-th are all incremented by 1.\n\nThere is also another integer sequence B_1,...,B_N. Takahashi will push the buttons some number of times so that for every i, A_i will be a multiple of B_i.\n\nFind the minimum number of times Takahashi will press the buttons.\n\nConstraints\n\nAll input values are integers.\n\n1 ≦ N ≦ 10^5\n\n0 ≦ A_i ≦ 10^9(1 ≦ i ≦ N)\n\n1 ≦ B_i ≦ 10^9(1 ≦ i ≦ N)\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1 B_1\n:\nA_N B_N\n\nOutput\n\nPrint an integer representing the minimum number of times Takahashi will press the buttons.\n\nSample Input 1\n\n3\n3 5\n2 7\n9 4\n\nSample Output 1\n\n7\n\nPress the first button twice, the second button twice and the third button three times.\n\nSample Input 2\n\n7\n3 1\n4 1\n5 9\n2 6\n5 3\n5 8\n9 7\n\nSample Output 2\n\n22", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2223, "cpu_time_ms": 29, "memory_kb": 2560}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s727217117", "group_id": "codeNet:p03826", "input_text": "/*\nID: y1197771\nPROG: test\nLANG: C++\n*/\n#include<bits/stdc++.h>\n#define pb push_back\n#define FOR(i, n) for (int i = 0; i < (int)n; ++i)\n#define dbg(x) cout << #x << \" at line \" << __LINE__ << \" is: \" << x << endl\ntypedef long long ll;\nusing namespace std;\ntypedef pair<int, int> pii;\nconst int maxn = 1e3 + 10;\nvoid solve() {\n    int x, y, a, b;\n    cin >> x >> y >> a >> b;\n    cout << max(x * y, a * b) << endl;\n}\nint main() {\n    //freopen(\"test.in\", \"r\", stdin);\n    //freopen(\"test.out\", \"w\", stdout);\n    ios::sync_with_stdio(0);\n    cin.tie(0); cout.tie(0);\n    solve();\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1484532095, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03826.html", "problem_id": "p03826", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03826/input.txt", "sample_output_relpath": "derived/input_output/data/p03826/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03826/C++/s727217117.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s727217117", "user_id": "u154228546"}, "prompt_components": {"gold_output": "15\n", "input_to_evaluate": "/*\nID: y1197771\nPROG: test\nLANG: C++\n*/\n#include<bits/stdc++.h>\n#define pb push_back\n#define FOR(i, n) for (int i = 0; i < (int)n; ++i)\n#define dbg(x) cout << #x << \" at line \" << __LINE__ << \" is: \" << x << endl\ntypedef long long ll;\nusing namespace std;\ntypedef pair<int, int> pii;\nconst int maxn = 1e3 + 10;\nvoid solve() {\n    int x, y, a, b;\n    cin >> x >> y >> a >> b;\n    cout << max(x * y, a * b) << endl;\n}\nint main() {\n    //freopen(\"test.in\", \"r\", stdin);\n    //freopen(\"test.out\", \"w\", stdout);\n    ios::sync_with_stdio(0);\n    cin.tie(0); cout.tie(0);\n    solve();\n    return 0;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nThere are two rectangles.\nThe lengths of the vertical sides of the first rectangle are A, and the lengths of the horizontal sides of the first rectangle are B.\nThe lengths of the vertical sides of the second rectangle are C, and the lengths of the horizontal sides of the second rectangle are D.\n\nPrint the area of the rectangle with the larger area.\nIf the two rectangles have equal areas, print that area.\n\nConstraints\n\nAll input values are integers.\n\n1≤A≤10^4\n\n1≤B≤10^4\n\n1≤C≤10^4\n\n1≤D≤10^4\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nA B C D\n\nOutput\n\nPrint the area of the rectangle with the larger area.\nIf the two rectangles have equal areas, print that area.\n\nSample Input 1\n\n3 5 2 7\n\nSample Output 1\n\n15\n\nThe first rectangle has an area of 3×5=15, and the second rectangle has an area of 2×7=14.\nThus, the output should be 15, the larger area.\n\nSample Input 2\n\n100 600 200 300\n\nSample Output 2\n\n60000", "sample_input": "3 5 2 7\n"}, "reference_outputs": ["15\n"], "source_document_id": "p03826", "source_text": "Score : 100 points\n\nProblem Statement\n\nThere are two rectangles.\nThe lengths of the vertical sides of the first rectangle are A, and the lengths of the horizontal sides of the first rectangle are B.\nThe lengths of the vertical sides of the second rectangle are C, and the lengths of the horizontal sides of the second rectangle are D.\n\nPrint the area of the rectangle with the larger area.\nIf the two rectangles have equal areas, print that area.\n\nConstraints\n\nAll input values are integers.\n\n1≤A≤10^4\n\n1≤B≤10^4\n\n1≤C≤10^4\n\n1≤D≤10^4\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nA B C D\n\nOutput\n\nPrint the area of the rectangle with the larger area.\nIf the two rectangles have equal areas, print that area.\n\nSample Input 1\n\n3 5 2 7\n\nSample Output 1\n\n15\n\nThe first rectangle has an area of 3×5=15, and the second rectangle has an area of 2×7=14.\nThus, the output should be 15, the larger area.\n\nSample Input 2\n\n100 600 200 300\n\nSample Output 2\n\n60000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 594, "cpu_time_ms": 116, "memory_kb": 764}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s209021484", "group_id": "codeNet:p03827", "input_text": "#include <iostream>\n#include <vector>\n#include <set>\n#include <map>\n#include <unordered_map>\n#include <unordered_set>\n#include <algorithm>\n#include <iomanip>\n#include <numeric>\n#include <queue>\n#include <cmath>\nusing namespace std;\n\nint main() {  \n    int n;\n    cin >> n;\n    string s;\n    cin >> s;\n    int res = 0;\n    int c = 0;\n    for (auto ss : s) {\n        if (ss == 'I') {\n            c++; \n        } else {\n            c--;\n        }\n        res = max(res, c);\n    }\n    cout << res << endl;\n}\n\n\n", "language": "C++", "metadata": {"date": 1598620509, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03827.html", "problem_id": "p03827", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03827/input.txt", "sample_output_relpath": "derived/input_output/data/p03827/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03827/C++/s209021484.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s209021484", "user_id": "u495704746"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\n#include <set>\n#include <map>\n#include <unordered_map>\n#include <unordered_set>\n#include <algorithm>\n#include <iomanip>\n#include <numeric>\n#include <queue>\n#include <cmath>\nusing namespace std;\n\nint main() {  \n    int n;\n    cin >> n;\n    string s;\n    cin >> s;\n    int res = 0;\n    int c = 0;\n    for (auto ss : s) {\n        if (ss == 'I') {\n            c++; \n        } else {\n            c--;\n        }\n        res = max(res, c);\n    }\n    cout << res << endl;\n}\n\n\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nYou have an integer variable x.\nInitially, x=0.\n\nSome person gave you a string S of length N, and using the string you performed the following operation N times.\nIn the i-th operation, you incremented the value of x by 1 if S_i=I, and decremented the value of x by 1 if S_i=D.\n\nFind the maximum value taken by x during the operations (including before the first operation, and after the last operation).\n\nConstraints\n\n1≤N≤100\n\n|S|=N\n\nNo characters except I and D occur in S.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nS\n\nOutput\n\nPrint the maximum value taken by x during the operations.\n\nSample Input 1\n\n5\nIIDID\n\nSample Output 1\n\n2\n\nAfter each operation, the value of x becomes 1, 2, 1, 2 and 1, respectively. Thus, the output should be 2, the maximum value.\n\nSample Input 2\n\n7\nDDIDDII\n\nSample Output 2\n\n0\n\nThe initial value x=0 is the maximum value taken by x, thus the output should be 0.", "sample_input": "5\nIIDID\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03827", "source_text": "Score : 200 points\n\nProblem Statement\n\nYou have an integer variable x.\nInitially, x=0.\n\nSome person gave you a string S of length N, and using the string you performed the following operation N times.\nIn the i-th operation, you incremented the value of x by 1 if S_i=I, and decremented the value of x by 1 if S_i=D.\n\nFind the maximum value taken by x during the operations (including before the first operation, and after the last operation).\n\nConstraints\n\n1≤N≤100\n\n|S|=N\n\nNo characters except I and D occur in S.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nS\n\nOutput\n\nPrint the maximum value taken by x during the operations.\n\nSample Input 1\n\n5\nIIDID\n\nSample Output 1\n\n2\n\nAfter each operation, the value of x becomes 1, 2, 1, 2 and 1, respectively. Thus, the output should be 2, the maximum value.\n\nSample Input 2\n\n7\nDDIDDII\n\nSample Output 2\n\n0\n\nThe initial value x=0 is the maximum value taken by x, thus the output should be 0.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 506, "cpu_time_ms": 8, "memory_kb": 3624}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s330494227", "group_id": "codeNet:p03829", "input_text": "#include <bits/stdc++.h>\n#define rep(i,n) for (int i = (0); i < (n); ++i)\n#define rrep(i,n) for(int i = 1; i <= (n); ++i)\n#define drep(i,n) for(int i = (n)-1; i >= 0; --i)\n#define srep(i,s,t) for (int i = s; i < t; ++i)\n#define rng(x) (x).begin(),(x).end()\n#define rrng(x) (x).rbegin(),(x).rend()\n#define limit(x,l,r) max(l,min(x,r))\n#define lims(x,l,r) (x = max(l,min(x,r)))\n#define isin(x,l,r) ((l) <= (x) && (x) < (r))\n#define show(x) cout << #x << \" = \" << (x) << endl\n#define show2(x,y) cout << #x << \" = \" << (x) << \", \" << #y << \" = \" << (y) << endl\n#define show3(x,y,z) cout << #x << \" = \" << (x) << \", \" << #y << \" = \" << (y) <<  \", \" << #z << \" = \" << (z) << endl\n#define showv(v) rep(i,v.size()) printf(\"%d%c\", v[i], i==v.size()-1?'\\n':' ')\n#define showv2(v) rep(j,v.size()) showv(v[j])\n#define showt(t,n) rep(i,n) printf(\"%d%c\", t[i], i==n-1?'\\n':' ')\n#define showt2(t,r,c) rep(j,r) showt(t[j],c)\n#define showvp(p) rep(i,p.size()) printf(\"%d %d\\n\", p[i].first, p[i].second);\n#define printv(v) rep(i,v.size()) printf(\"%d\\n\", v[i])\n#define printt(t,n) rep(i,n) printf(\"%d\\n\", t[i])\n#define incl(v,x) find(rng(v),x)!=v.end()\n#define incls(s,c) s.find(c)!=string::npos\n#define fi first\n#define se second\n#define pb push_back\n#define eb emplace_back\n#define sz(x) (int)(x).size()\n#define pcnt __builtin_popcountll\n#define bit(n,k) ((n>>k)&1) // nのk bit目\n#define bn(x) ((1<<x)-1)\n#define dup(x,y) (((x)+(y)-1)/(y))\n#define newline puts(\"\")\n#define uni(x) x.erase(unique(rng(x)),x.end())\n#define SP << \" \" <<\n#define v(T) vector<T>\n#define vv(T) v(v(T))\nusing namespace std;\nusing ll = long long;\nusing vi = vector<int>;\nusing vvi = vector<vi>;\nusing vl = vector<ll>;\nusing vs = vector<string>;\nusing P = pair<int, int>;\nusing T = tuple<int, int, int>;\nusing vp = vector<P>;\nusing vt = vector<T>;\nconst int mod = 1000000007;\nconst double EPS = 1e-9;\nconst int INF = (1<<30)-1;\n//const ll INF = (1LL<<62)-1;\n#define dame { puts(\"No\"); return 0;}\n#define yn {puts(\"Yes\");}else{puts(\"No\");}\n//inline int in() { int x; scanf(\"%d\",&x); return x;}\ntemplate<class T = int> inline T in() { T x; cin >> x; return (x);}\ntemplate<typename T>inline ll suma(const v(T)& a) { ll res(0); for (auto&& x : a) res += x; return res;}\ntemplate<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return true; } return false; }\ntemplate<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return true; } return false; }\n\nint main () {\n  ll n, a, b;\n  cin >> n >> a >> b;\n  vl x(n);\n  rep(i,n) cin >> x[i];\n  \n  ll ans = 0;\n  rep(i,n-1) {\n    ans += min(a*(x[i+1]-x[i]),b);\n  }\n  cout << ans << endl;\n  return 0;\n}", "language": "C++", "metadata": {"date": 1582960095, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03829.html", "problem_id": "p03829", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03829/input.txt", "sample_output_relpath": "derived/input_output/data/p03829/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03829/C++/s330494227.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s330494227", "user_id": "u850516963"}, "prompt_components": {"gold_output": "11\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define rep(i,n) for (int i = (0); i < (n); ++i)\n#define rrep(i,n) for(int i = 1; i <= (n); ++i)\n#define drep(i,n) for(int i = (n)-1; i >= 0; --i)\n#define srep(i,s,t) for (int i = s; i < t; ++i)\n#define rng(x) (x).begin(),(x).end()\n#define rrng(x) (x).rbegin(),(x).rend()\n#define limit(x,l,r) max(l,min(x,r))\n#define lims(x,l,r) (x = max(l,min(x,r)))\n#define isin(x,l,r) ((l) <= (x) && (x) < (r))\n#define show(x) cout << #x << \" = \" << (x) << endl\n#define show2(x,y) cout << #x << \" = \" << (x) << \", \" << #y << \" = \" << (y) << endl\n#define show3(x,y,z) cout << #x << \" = \" << (x) << \", \" << #y << \" = \" << (y) <<  \", \" << #z << \" = \" << (z) << endl\n#define showv(v) rep(i,v.size()) printf(\"%d%c\", v[i], i==v.size()-1?'\\n':' ')\n#define showv2(v) rep(j,v.size()) showv(v[j])\n#define showt(t,n) rep(i,n) printf(\"%d%c\", t[i], i==n-1?'\\n':' ')\n#define showt2(t,r,c) rep(j,r) showt(t[j],c)\n#define showvp(p) rep(i,p.size()) printf(\"%d %d\\n\", p[i].first, p[i].second);\n#define printv(v) rep(i,v.size()) printf(\"%d\\n\", v[i])\n#define printt(t,n) rep(i,n) printf(\"%d\\n\", t[i])\n#define incl(v,x) find(rng(v),x)!=v.end()\n#define incls(s,c) s.find(c)!=string::npos\n#define fi first\n#define se second\n#define pb push_back\n#define eb emplace_back\n#define sz(x) (int)(x).size()\n#define pcnt __builtin_popcountll\n#define bit(n,k) ((n>>k)&1) // nのk bit目\n#define bn(x) ((1<<x)-1)\n#define dup(x,y) (((x)+(y)-1)/(y))\n#define newline puts(\"\")\n#define uni(x) x.erase(unique(rng(x)),x.end())\n#define SP << \" \" <<\n#define v(T) vector<T>\n#define vv(T) v(v(T))\nusing namespace std;\nusing ll = long long;\nusing vi = vector<int>;\nusing vvi = vector<vi>;\nusing vl = vector<ll>;\nusing vs = vector<string>;\nusing P = pair<int, int>;\nusing T = tuple<int, int, int>;\nusing vp = vector<P>;\nusing vt = vector<T>;\nconst int mod = 1000000007;\nconst double EPS = 1e-9;\nconst int INF = (1<<30)-1;\n//const ll INF = (1LL<<62)-1;\n#define dame { puts(\"No\"); return 0;}\n#define yn {puts(\"Yes\");}else{puts(\"No\");}\n//inline int in() { int x; scanf(\"%d\",&x); return x;}\ntemplate<class T = int> inline T in() { T x; cin >> x; return (x);}\ntemplate<typename T>inline ll suma(const v(T)& a) { ll res(0); for (auto&& x : a) res += x; return res;}\ntemplate<class T> inline bool chmax(T& a, T b) { if (a < b) { a = b; return true; } return false; }\ntemplate<class T> inline bool chmin(T& a, T b) { if (a > b) { a = b; return true; } return false; }\n\nint main () {\n  ll n, a, b;\n  cin >> n >> a >> b;\n  vl x(n);\n  rep(i,n) cin >> x[i];\n  \n  ll ans = 0;\n  rep(i,n-1) {\n    ans += min(a*(x[i+1]-x[i]),b);\n  }\n  cout << ans << endl;\n  return 0;\n}", "problem_context": "Score : 500 points\n\nProblem Statement\n\nThere are N towns on a line running east-west.\nThe towns are numbered 1 through N, in order from west to east.\nEach point on the line has a one-dimensional coordinate, and a point that is farther east has a greater coordinate value.\nThe coordinate of town i is X_i.\n\nYou are now at town 1, and you want to visit all the other towns.\nYou have two ways to travel:\n\nWalk on the line.\nYour fatigue level increases by A each time you travel a distance of 1, regardless of direction.\n\nTeleport to any location of your choice.\nYour fatigue level increases by B, regardless of the distance covered.\n\nFind the minimum possible total increase of your fatigue level when you visit all the towns in these two ways.\n\nConstraints\n\nAll input values are integers.\n\n2≤N≤10^5\n\n1≤X_i≤10^9\n\nFor all i(1≤i≤N-1), X_i<X_{i+1}.\n\n1≤A≤10^9\n\n1≤B≤10^9\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN A B\nX_1 X_2 ... X_N\n\nOutput\n\nPrint the minimum possible total increase of your fatigue level when you visit all the towns.\n\nSample Input 1\n\n4 2 5\n1 2 5 7\n\nSample Output 1\n\n11\n\nFrom town 1, walk a distance of 1 to town 2, then teleport to town 3, then walk a distance of 2 to town 4.\nThe total increase of your fatigue level in this case is 2×1+5+2×2=11, which is the minimum possible value.\n\nSample Input 2\n\n7 1 100\n40 43 45 105 108 115 124\n\nSample Output 2\n\n84\n\nFrom town 1, walk all the way to town 7.\nThe total increase of your fatigue level in this case is 84, which is the minimum possible value.\n\nSample Input 3\n\n7 1 2\n24 35 40 68 72 99 103\n\nSample Output 3\n\n12\n\nVisit all the towns in any order by teleporting six times.\nThe total increase of your fatigue level in this case is 12, which is the minimum possible value.", "sample_input": "4 2 5\n1 2 5 7\n"}, "reference_outputs": ["11\n"], "source_document_id": "p03829", "source_text": "Score : 500 points\n\nProblem Statement\n\nThere are N towns on a line running east-west.\nThe towns are numbered 1 through N, in order from west to east.\nEach point on the line has a one-dimensional coordinate, and a point that is farther east has a greater coordinate value.\nThe coordinate of town i is X_i.\n\nYou are now at town 1, and you want to visit all the other towns.\nYou have two ways to travel:\n\nWalk on the line.\nYour fatigue level increases by A each time you travel a distance of 1, regardless of direction.\n\nTeleport to any location of your choice.\nYour fatigue level increases by B, regardless of the distance covered.\n\nFind the minimum possible total increase of your fatigue level when you visit all the towns in these two ways.\n\nConstraints\n\nAll input values are integers.\n\n2≤N≤10^5\n\n1≤X_i≤10^9\n\nFor all i(1≤i≤N-1), X_i<X_{i+1}.\n\n1≤A≤10^9\n\n1≤B≤10^9\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN A B\nX_1 X_2 ... X_N\n\nOutput\n\nPrint the minimum possible total increase of your fatigue level when you visit all the towns.\n\nSample Input 1\n\n4 2 5\n1 2 5 7\n\nSample Output 1\n\n11\n\nFrom town 1, walk a distance of 1 to town 2, then teleport to town 3, then walk a distance of 2 to town 4.\nThe total increase of your fatigue level in this case is 2×1+5+2×2=11, which is the minimum possible value.\n\nSample Input 2\n\n7 1 100\n40 43 45 105 108 115 124\n\nSample Output 2\n\n84\n\nFrom town 1, walk all the way to town 7.\nThe total increase of your fatigue level in this case is 84, which is the minimum possible value.\n\nSample Input 3\n\n7 1 2\n24 35 40 68 72 99 103\n\nSample Output 3\n\n12\n\nVisit all the towns in any order by teleporting six times.\nThe total increase of your fatigue level in this case is 12, which is the minimum possible value.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2617, "cpu_time_ms": 41, "memory_kb": 1024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s141712588", "group_id": "codeNet:p03836", "input_text": "#include <cstdio>\n#include <iostream>\n#include <iomanip>\n#include <string>\n#include <queue>\n#include <stack>\n#include <vector>\n#include <set>\n#include <map>\n#include <algorithm>\n#include <utility>\n#include <cmath>\n\n#define ll long long int\n#define pb push_back\n#define mk make_pair\n#define pq priority_queue\n\nusing namespace std;\ntypedef pair<int, int> P;\ntypedef pair<ll, int> Pl;\ntypedef pair<ll, ll> Pll;\nconst int inf = 1e9;\nconst ll linf = 1LL << 50;\n\nint main(int argc, char const* argv[])\n{\n  int sx, sy, tx, ty;\n  cin >> sx >> sy >> tx >> ty;\n  cout << \"D\";\n  for(int i = 0; i < tx - sx + 1; i++)cout << \"R\";\n  for(int i = 0; i < ty - sy + 1; i++)cout << \"U\";\n  cout << \"L\";\n  for(int i = 0; i < ty - sy; i++)cout << \"D\";\n  for(int i = 0; i < tx - sx; i++)cout << \"L\";\n  for(int i = 0; i < ty - sy; i++)cout << \"U\";\n  for(int i = 0; i < tx - sx; i++)cout << \"R\";\n  cout << \"U\";\n  for(int i = 0; i < tx - sx + 1; i++)cout << \"L\";\n  for(int i = 0; i < ty - sy + 1; i++)cout << \"D\";\n  cout << \"R\" << endl;\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1538786095, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03836.html", "problem_id": "p03836", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03836/input.txt", "sample_output_relpath": "derived/input_output/data/p03836/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03836/C++/s141712588.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s141712588", "user_id": "u424110125"}, "prompt_components": {"gold_output": "UURDDLLUUURRDRDDDLLU\n", "input_to_evaluate": "#include <cstdio>\n#include <iostream>\n#include <iomanip>\n#include <string>\n#include <queue>\n#include <stack>\n#include <vector>\n#include <set>\n#include <map>\n#include <algorithm>\n#include <utility>\n#include <cmath>\n\n#define ll long long int\n#define pb push_back\n#define mk make_pair\n#define pq priority_queue\n\nusing namespace std;\ntypedef pair<int, int> P;\ntypedef pair<ll, int> Pl;\ntypedef pair<ll, ll> Pll;\nconst int inf = 1e9;\nconst ll linf = 1LL << 50;\n\nint main(int argc, char const* argv[])\n{\n  int sx, sy, tx, ty;\n  cin >> sx >> sy >> tx >> ty;\n  cout << \"D\";\n  for(int i = 0; i < tx - sx + 1; i++)cout << \"R\";\n  for(int i = 0; i < ty - sy + 1; i++)cout << \"U\";\n  cout << \"L\";\n  for(int i = 0; i < ty - sy; i++)cout << \"D\";\n  for(int i = 0; i < tx - sx; i++)cout << \"L\";\n  for(int i = 0; i < ty - sy; i++)cout << \"U\";\n  for(int i = 0; i < tx - sx; i++)cout << \"R\";\n  cout << \"U\";\n  for(int i = 0; i < tx - sx + 1; i++)cout << \"L\";\n  for(int i = 0; i < ty - sy + 1; i++)cout << \"D\";\n  cout << \"R\" << endl;\n\treturn 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nDolphin resides in two-dimensional Cartesian plane, with the positive x-axis pointing right and the positive y-axis pointing up.\n\nCurrently, he is located at the point (sx,sy). In each second, he can move up, down, left or right by a distance of 1.\n\nHere, both the x- and y-coordinates before and after each movement must be integers.\n\nHe will first visit the point (tx,ty) where sx < tx and sy < ty, then go back to the point (sx,sy), then visit the point (tx,ty) again, and lastly go back to the point (sx,sy).\n\nHere, during the whole travel, he is not allowed to pass through the same point more than once, except the points (sx,sy) and (tx,ty).\n\nUnder this condition, find a shortest path for him.\n\nConstraints\n\n-1000 ≤ sx < tx ≤ 1000\n\n-1000 ≤ sy < ty ≤ 1000\n\nsx,sy,tx and ty are integers.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nsx sy tx ty\n\nOutput\n\nPrint a string S that represents a shortest path for Dolphin.\n\nThe i-th character in S should correspond to his i-th movement.\n\nThe directions of the movements should be indicated by the following characters:\n\nU: Up\n\nD: Down\n\nL: Left\n\nR: Right\n\nIf there exist multiple shortest paths under the condition, print any of them.\n\nSample Input 1\n\n0 0 1 2\n\nSample Output 1\n\nUURDDLLUUURRDRDDDLLU\n\nOne possible shortest path is:\n\nGoing from (sx,sy) to (tx,ty) for the first time: (0,0) → (0,1) → (0,2) → (1,2)\n\nGoing from (tx,ty) to (sx,sy) for the first time: (1,2) → (1,1) → (1,0) → (0,0)\n\nGoing from (sx,sy) to (tx,ty) for the second time: (0,0) → (-1,0) → (-1,1) → (-1,2) → (-1,3) → (0,3) → (1,3) → (1,2)\n\nGoing from (tx,ty) to (sx,sy) for the second time: (1,2) → (2,2) → (2,1) → (2,0) → (2,-1) → (1,-1) → (0,-1) → (0,0)\n\nSample Input 2\n\n-2 -2 1 1\n\nSample Output 2\n\nUURRURRDDDLLDLLULUUURRURRDDDLLDL", "sample_input": "0 0 1 2\n"}, "reference_outputs": ["UURDDLLUUURRDRDDDLLU\n"], "source_document_id": "p03836", "source_text": "Score : 300 points\n\nProblem Statement\n\nDolphin resides in two-dimensional Cartesian plane, with the positive x-axis pointing right and the positive y-axis pointing up.\n\nCurrently, he is located at the point (sx,sy). In each second, he can move up, down, left or right by a distance of 1.\n\nHere, both the x- and y-coordinates before and after each movement must be integers.\n\nHe will first visit the point (tx,ty) where sx < tx and sy < ty, then go back to the point (sx,sy), then visit the point (tx,ty) again, and lastly go back to the point (sx,sy).\n\nHere, during the whole travel, he is not allowed to pass through the same point more than once, except the points (sx,sy) and (tx,ty).\n\nUnder this condition, find a shortest path for him.\n\nConstraints\n\n-1000 ≤ sx < tx ≤ 1000\n\n-1000 ≤ sy < ty ≤ 1000\n\nsx,sy,tx and ty are integers.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nsx sy tx ty\n\nOutput\n\nPrint a string S that represents a shortest path for Dolphin.\n\nThe i-th character in S should correspond to his i-th movement.\n\nThe directions of the movements should be indicated by the following characters:\n\nU: Up\n\nD: Down\n\nL: Left\n\nR: Right\n\nIf there exist multiple shortest paths under the condition, print any of them.\n\nSample Input 1\n\n0 0 1 2\n\nSample Output 1\n\nUURDDLLUUURRDRDDDLLU\n\nOne possible shortest path is:\n\nGoing from (sx,sy) to (tx,ty) for the first time: (0,0) → (0,1) → (0,2) → (1,2)\n\nGoing from (tx,ty) to (sx,sy) for the first time: (1,2) → (1,1) → (1,0) → (0,0)\n\nGoing from (sx,sy) to (tx,ty) for the second time: (0,0) → (-1,0) → (-1,1) → (-1,2) → (-1,3) → (0,3) → (1,3) → (1,2)\n\nGoing from (tx,ty) to (sx,sy) for the second time: (1,2) → (2,2) → (2,1) → (2,0) → (2,-1) → (1,-1) → (0,-1) → (0,0)\n\nSample Input 2\n\n-2 -2 1 1\n\nSample Output 2\n\nUURRURRDDDLLDLLULUUURRURRDDDLLDL", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1024, "cpu_time_ms": 2, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s108398933", "group_id": "codeNet:p03836", "input_text": "#include<iostream>\nusing namespace std;\n\nint main() {\n    int sx, sy, tx, ty;\n    cin >> sx >> sy >> tx >> ty;\n    for (int i = 0; i < ty - sy; i++) {\n        cout << 'U';\n    }\n    for (int i = 0; i < tx - sx; i++) {\n        cout << 'R';\n    }\n    for (int i = 0; i < ty - sy; i++) {\n        cout << 'D';\n    }\n    for (int i = 0; i < tx - sx + 1; i++) {\n        cout << 'L';\n    }\n    for (int i = 0; i < ty - sy + 1; i++) {\n        cout << 'U';\n    }\n    for (int i = 0; i < tx - sx + 1; i++) {\n        cout << 'R';\n    }\n    cout << \"DR\";\n    for (int i = 0; i < ty - sy + 1; i++) {\n        cout << 'D';\n    }\n    for (int i = 0; i < tx -sx + 1; i++) {\n        cout << 'L';\n    }\n    cout << 'U' << endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1530293798, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03836.html", "problem_id": "p03836", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03836/input.txt", "sample_output_relpath": "derived/input_output/data/p03836/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03836/C++/s108398933.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s108398933", "user_id": "u134519179"}, "prompt_components": {"gold_output": "UURDDLLUUURRDRDDDLLU\n", "input_to_evaluate": "#include<iostream>\nusing namespace std;\n\nint main() {\n    int sx, sy, tx, ty;\n    cin >> sx >> sy >> tx >> ty;\n    for (int i = 0; i < ty - sy; i++) {\n        cout << 'U';\n    }\n    for (int i = 0; i < tx - sx; i++) {\n        cout << 'R';\n    }\n    for (int i = 0; i < ty - sy; i++) {\n        cout << 'D';\n    }\n    for (int i = 0; i < tx - sx + 1; i++) {\n        cout << 'L';\n    }\n    for (int i = 0; i < ty - sy + 1; i++) {\n        cout << 'U';\n    }\n    for (int i = 0; i < tx - sx + 1; i++) {\n        cout << 'R';\n    }\n    cout << \"DR\";\n    for (int i = 0; i < ty - sy + 1; i++) {\n        cout << 'D';\n    }\n    for (int i = 0; i < tx -sx + 1; i++) {\n        cout << 'L';\n    }\n    cout << 'U' << endl;\n    return 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nDolphin resides in two-dimensional Cartesian plane, with the positive x-axis pointing right and the positive y-axis pointing up.\n\nCurrently, he is located at the point (sx,sy). In each second, he can move up, down, left or right by a distance of 1.\n\nHere, both the x- and y-coordinates before and after each movement must be integers.\n\nHe will first visit the point (tx,ty) where sx < tx and sy < ty, then go back to the point (sx,sy), then visit the point (tx,ty) again, and lastly go back to the point (sx,sy).\n\nHere, during the whole travel, he is not allowed to pass through the same point more than once, except the points (sx,sy) and (tx,ty).\n\nUnder this condition, find a shortest path for him.\n\nConstraints\n\n-1000 ≤ sx < tx ≤ 1000\n\n-1000 ≤ sy < ty ≤ 1000\n\nsx,sy,tx and ty are integers.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nsx sy tx ty\n\nOutput\n\nPrint a string S that represents a shortest path for Dolphin.\n\nThe i-th character in S should correspond to his i-th movement.\n\nThe directions of the movements should be indicated by the following characters:\n\nU: Up\n\nD: Down\n\nL: Left\n\nR: Right\n\nIf there exist multiple shortest paths under the condition, print any of them.\n\nSample Input 1\n\n0 0 1 2\n\nSample Output 1\n\nUURDDLLUUURRDRDDDLLU\n\nOne possible shortest path is:\n\nGoing from (sx,sy) to (tx,ty) for the first time: (0,0) → (0,1) → (0,2) → (1,2)\n\nGoing from (tx,ty) to (sx,sy) for the first time: (1,2) → (1,1) → (1,0) → (0,0)\n\nGoing from (sx,sy) to (tx,ty) for the second time: (0,0) → (-1,0) → (-1,1) → (-1,2) → (-1,3) → (0,3) → (1,3) → (1,2)\n\nGoing from (tx,ty) to (sx,sy) for the second time: (1,2) → (2,2) → (2,1) → (2,0) → (2,-1) → (1,-1) → (0,-1) → (0,0)\n\nSample Input 2\n\n-2 -2 1 1\n\nSample Output 2\n\nUURRURRDDDLLDLLULUUURRURRDDDLLDL", "sample_input": "0 0 1 2\n"}, "reference_outputs": ["UURDDLLUUURRDRDDDLLU\n"], "source_document_id": "p03836", "source_text": "Score : 300 points\n\nProblem Statement\n\nDolphin resides in two-dimensional Cartesian plane, with the positive x-axis pointing right and the positive y-axis pointing up.\n\nCurrently, he is located at the point (sx,sy). In each second, he can move up, down, left or right by a distance of 1.\n\nHere, both the x- and y-coordinates before and after each movement must be integers.\n\nHe will first visit the point (tx,ty) where sx < tx and sy < ty, then go back to the point (sx,sy), then visit the point (tx,ty) again, and lastly go back to the point (sx,sy).\n\nHere, during the whole travel, he is not allowed to pass through the same point more than once, except the points (sx,sy) and (tx,ty).\n\nUnder this condition, find a shortest path for him.\n\nConstraints\n\n-1000 ≤ sx < tx ≤ 1000\n\n-1000 ≤ sy < ty ≤ 1000\n\nsx,sy,tx and ty are integers.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nsx sy tx ty\n\nOutput\n\nPrint a string S that represents a shortest path for Dolphin.\n\nThe i-th character in S should correspond to his i-th movement.\n\nThe directions of the movements should be indicated by the following characters:\n\nU: Up\n\nD: Down\n\nL: Left\n\nR: Right\n\nIf there exist multiple shortest paths under the condition, print any of them.\n\nSample Input 1\n\n0 0 1 2\n\nSample Output 1\n\nUURDDLLUUURRDRDDDLLU\n\nOne possible shortest path is:\n\nGoing from (sx,sy) to (tx,ty) for the first time: (0,0) → (0,1) → (0,2) → (1,2)\n\nGoing from (tx,ty) to (sx,sy) for the first time: (1,2) → (1,1) → (1,0) → (0,0)\n\nGoing from (sx,sy) to (tx,ty) for the second time: (0,0) → (-1,0) → (-1,1) → (-1,2) → (-1,3) → (0,3) → (1,3) → (1,2)\n\nGoing from (tx,ty) to (sx,sy) for the second time: (1,2) → (2,2) → (2,1) → (2,0) → (2,-1) → (1,-1) → (0,-1) → (0,0)\n\nSample Input 2\n\n-2 -2 1 1\n\nSample Output 2\n\nUURRURRDDDLLDLLULUUURRURRDDDLLDL", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 724, "cpu_time_ms": 2, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s473576890", "group_id": "codeNet:p03836", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define REP(i,n) for(int i=0;i<(int)(n);i++)\n#define ALL(x) (x).begin(), (x).end()\n\ntypedef long long ll;\ntypedef long double ld;\n\nconst int INF = 1e9;\nconst ld EPS = 1e-8;\n\nint main(){\n  int sx, sy, tx, ty;\n  cin >> sx >> sy >> tx >> ty;\n\n  string res;\n\n  REP(i,ty - sy) res += \"U\";\n  REP(i,tx - sx) res += \"R\";\n\n  REP(i,ty - sy) res += \"D\";\n  REP(i,tx - sx) res += \"L\";\n\n  res += \"L\";\n  REP(i,ty - sy + 1) res += \"U\";\n  REP(i,tx - sx + 1) res += \"R\";\n  res += \"D\";\n\n  res += \"R\";\n  REP(i,ty - sy + 1) res += \"D\";\n  REP(i,tx - sx + 1) res += \"L\";\n  res += \"U\";\n\n  cout << res << endl;\n  return 0;\n}\n\n", "language": "C++", "metadata": {"date": 1483911629, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03836.html", "problem_id": "p03836", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03836/input.txt", "sample_output_relpath": "derived/input_output/data/p03836/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03836/C++/s473576890.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s473576890", "user_id": "u886956383"}, "prompt_components": {"gold_output": "UURDDLLUUURRDRDDDLLU\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define REP(i,n) for(int i=0;i<(int)(n);i++)\n#define ALL(x) (x).begin(), (x).end()\n\ntypedef long long ll;\ntypedef long double ld;\n\nconst int INF = 1e9;\nconst ld EPS = 1e-8;\n\nint main(){\n  int sx, sy, tx, ty;\n  cin >> sx >> sy >> tx >> ty;\n\n  string res;\n\n  REP(i,ty - sy) res += \"U\";\n  REP(i,tx - sx) res += \"R\";\n\n  REP(i,ty - sy) res += \"D\";\n  REP(i,tx - sx) res += \"L\";\n\n  res += \"L\";\n  REP(i,ty - sy + 1) res += \"U\";\n  REP(i,tx - sx + 1) res += \"R\";\n  res += \"D\";\n\n  res += \"R\";\n  REP(i,ty - sy + 1) res += \"D\";\n  REP(i,tx - sx + 1) res += \"L\";\n  res += \"U\";\n\n  cout << res << endl;\n  return 0;\n}\n\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nDolphin resides in two-dimensional Cartesian plane, with the positive x-axis pointing right and the positive y-axis pointing up.\n\nCurrently, he is located at the point (sx,sy). In each second, he can move up, down, left or right by a distance of 1.\n\nHere, both the x- and y-coordinates before and after each movement must be integers.\n\nHe will first visit the point (tx,ty) where sx < tx and sy < ty, then go back to the point (sx,sy), then visit the point (tx,ty) again, and lastly go back to the point (sx,sy).\n\nHere, during the whole travel, he is not allowed to pass through the same point more than once, except the points (sx,sy) and (tx,ty).\n\nUnder this condition, find a shortest path for him.\n\nConstraints\n\n-1000 ≤ sx < tx ≤ 1000\n\n-1000 ≤ sy < ty ≤ 1000\n\nsx,sy,tx and ty are integers.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nsx sy tx ty\n\nOutput\n\nPrint a string S that represents a shortest path for Dolphin.\n\nThe i-th character in S should correspond to his i-th movement.\n\nThe directions of the movements should be indicated by the following characters:\n\nU: Up\n\nD: Down\n\nL: Left\n\nR: Right\n\nIf there exist multiple shortest paths under the condition, print any of them.\n\nSample Input 1\n\n0 0 1 2\n\nSample Output 1\n\nUURDDLLUUURRDRDDDLLU\n\nOne possible shortest path is:\n\nGoing from (sx,sy) to (tx,ty) for the first time: (0,0) → (0,1) → (0,2) → (1,2)\n\nGoing from (tx,ty) to (sx,sy) for the first time: (1,2) → (1,1) → (1,0) → (0,0)\n\nGoing from (sx,sy) to (tx,ty) for the second time: (0,0) → (-1,0) → (-1,1) → (-1,2) → (-1,3) → (0,3) → (1,3) → (1,2)\n\nGoing from (tx,ty) to (sx,sy) for the second time: (1,2) → (2,2) → (2,1) → (2,0) → (2,-1) → (1,-1) → (0,-1) → (0,0)\n\nSample Input 2\n\n-2 -2 1 1\n\nSample Output 2\n\nUURRURRDDDLLDLLULUUURRURRDDDLLDL", "sample_input": "0 0 1 2\n"}, "reference_outputs": ["UURDDLLUUURRDRDDDLLU\n"], "source_document_id": "p03836", "source_text": "Score : 300 points\n\nProblem Statement\n\nDolphin resides in two-dimensional Cartesian plane, with the positive x-axis pointing right and the positive y-axis pointing up.\n\nCurrently, he is located at the point (sx,sy). In each second, he can move up, down, left or right by a distance of 1.\n\nHere, both the x- and y-coordinates before and after each movement must be integers.\n\nHe will first visit the point (tx,ty) where sx < tx and sy < ty, then go back to the point (sx,sy), then visit the point (tx,ty) again, and lastly go back to the point (sx,sy).\n\nHere, during the whole travel, he is not allowed to pass through the same point more than once, except the points (sx,sy) and (tx,ty).\n\nUnder this condition, find a shortest path for him.\n\nConstraints\n\n-1000 ≤ sx < tx ≤ 1000\n\n-1000 ≤ sy < ty ≤ 1000\n\nsx,sy,tx and ty are integers.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nsx sy tx ty\n\nOutput\n\nPrint a string S that represents a shortest path for Dolphin.\n\nThe i-th character in S should correspond to his i-th movement.\n\nThe directions of the movements should be indicated by the following characters:\n\nU: Up\n\nD: Down\n\nL: Left\n\nR: Right\n\nIf there exist multiple shortest paths under the condition, print any of them.\n\nSample Input 1\n\n0 0 1 2\n\nSample Output 1\n\nUURDDLLUUURRDRDDDLLU\n\nOne possible shortest path is:\n\nGoing from (sx,sy) to (tx,ty) for the first time: (0,0) → (0,1) → (0,2) → (1,2)\n\nGoing from (tx,ty) to (sx,sy) for the first time: (1,2) → (1,1) → (1,0) → (0,0)\n\nGoing from (sx,sy) to (tx,ty) for the second time: (0,0) → (-1,0) → (-1,1) → (-1,2) → (-1,3) → (0,3) → (1,3) → (1,2)\n\nGoing from (tx,ty) to (sx,sy) for the second time: (1,2) → (2,2) → (2,1) → (2,0) → (2,-1) → (1,-1) → (0,-1) → (0,0)\n\nSample Input 2\n\n-2 -2 1 1\n\nSample Output 2\n\nUURRURRDDDLLDLLULUUURRURRDDDLLDL", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 648, "cpu_time_ms": 3, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s938184948", "group_id": "codeNet:p03837", "input_text": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define MAX 110\n#define MAX_E 1010\n#define INF 10000000\n\n\nint e[MAX][MAX];\nint d[MAX][MAX];\nint n;\n\nvoid warshall_floyd() {\n  for (int k = 0; k < n; k++) {\n    for (int i = 0; i < n; i++) {\n      for (int j = 0; j < n; j++) {\n        if (d[i][j] > d[i][k] + d[k][j]) {\n          d[i][j] = d[i][k] + d[k][j];\n        }\n      }\n    }\n  }\n}\n\nbool contains(int i, int j) {\n  for (int s = 0; s < n; s++) {\n    if (s == j) continue;\n    if (d[s][i] + e[i][j] == d[s][j]) return true;\n  }\n  return false;\n}\n\nint main() {\n  for (int i = 0; i < MAX; i++) {\n    for (int j = 0; j < MAX; j++) {\n      if (i == j) d[i][j] = 0;\n      else d[i][j] = INF;\n    }\n  }\n  int m;\n  cin >> n >> m;\n  for (int i = 0; i < n; i++) {\n    for (int j = 0; j < n; j++) {\n      if (i == j) e[i][j] = 0;\n      else e[i][j] = INF;\n    }\n  }\n  for (int i = 0; i < m; i++) {\n    int a, b, c;\n    cin >> a >> b >> c;\n    e[a - 1][b - 1] = c;\n    e[b - 1][a - 1] = c;\n    d[a - 1][b - 1] = c;\n    d[b - 1][a - 1] = c;\n  }\n  warshall_floyd();\n  int ans = 0;\n  for (int i = 0; i < n; i++) {\n    for (int j = i; j < n; j++) {\n      if (e[i][j] != INF && e[i][j] > d[i][j]) ans++;\n    }\n  }\n  cout << ans << endl;\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1520138903, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03837.html", "problem_id": "p03837", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03837/input.txt", "sample_output_relpath": "derived/input_output/data/p03837/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03837/C++/s938184948.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s938184948", "user_id": "u184659204"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <iostream>\n#include <algorithm>\nusing namespace std;\n#define MAX 110\n#define MAX_E 1010\n#define INF 10000000\n\n\nint e[MAX][MAX];\nint d[MAX][MAX];\nint n;\n\nvoid warshall_floyd() {\n  for (int k = 0; k < n; k++) {\n    for (int i = 0; i < n; i++) {\n      for (int j = 0; j < n; j++) {\n        if (d[i][j] > d[i][k] + d[k][j]) {\n          d[i][j] = d[i][k] + d[k][j];\n        }\n      }\n    }\n  }\n}\n\nbool contains(int i, int j) {\n  for (int s = 0; s < n; s++) {\n    if (s == j) continue;\n    if (d[s][i] + e[i][j] == d[s][j]) return true;\n  }\n  return false;\n}\n\nint main() {\n  for (int i = 0; i < MAX; i++) {\n    for (int j = 0; j < MAX; j++) {\n      if (i == j) d[i][j] = 0;\n      else d[i][j] = INF;\n    }\n  }\n  int m;\n  cin >> n >> m;\n  for (int i = 0; i < n; i++) {\n    for (int j = 0; j < n; j++) {\n      if (i == j) e[i][j] = 0;\n      else e[i][j] = INF;\n    }\n  }\n  for (int i = 0; i < m; i++) {\n    int a, b, c;\n    cin >> a >> b >> c;\n    e[a - 1][b - 1] = c;\n    e[b - 1][a - 1] = c;\n    d[a - 1][b - 1] = c;\n    d[b - 1][a - 1] = c;\n  }\n  warshall_floyd();\n  int ans = 0;\n  for (int i = 0; i < n; i++) {\n    for (int j = i; j < n; j++) {\n      if (e[i][j] != INF && e[i][j] > d[i][j]) ans++;\n    }\n  }\n  cout << ans << endl;\n  return 0;\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nYou are given an undirected connected weighted graph with N vertices and M edges that contains neither self-loops nor double edges.\n\nThe i-th (1≤i≤M) edge connects vertex a_i and vertex b_i with a distance of c_i.\n\nHere, a self-loop is an edge where a_i = b_i (1≤i≤M), and double edges are two edges where (a_i,b_i)=(a_j,b_j) or (a_i,b_i)=(b_j,a_j) (1≤i<j≤M).\n\nA connected graph is a graph where there is a path between every pair of different vertices.\n\nFind the number of the edges that are not contained in any shortest path between any pair of different vertices.\n\nConstraints\n\n2≤N≤100\n\nN-1≤M≤min(N(N-1)/2,1000)\n\n1≤a_i,b_i≤N\n\n1≤c_i≤1000\n\nc_i is an integer.\n\nThe given graph contains neither self-loops nor double edges.\n\nThe given graph is connected.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN M\na_1 b_1 c_1\na_2 b_2 c_2\n:\na_M b_M c_M\n\nOutput\n\nPrint the number of the edges in the graph that are not contained in any shortest path between any pair of different vertices.\n\nSample Input 1\n\n3 3\n1 2 1\n1 3 1\n2 3 3\n\nSample Output 1\n\n1\n\nIn the given graph, the shortest paths between all pairs of different vertices are as follows:\n\nThe shortest path from vertex 1 to vertex 2 is: vertex 1 → vertex 2, with the length of 1.\n\nThe shortest path from vertex 1 to vertex 3 is: vertex 1 → vertex 3, with the length of 1.\n\nThe shortest path from vertex 2 to vertex 1 is: vertex 2 → vertex 1, with the length of 1.\n\nThe shortest path from vertex 2 to vertex 3 is: vertex 2 → vertex 1 → vertex 3, with the length of 2.\n\nThe shortest path from vertex 3 to vertex 1 is: vertex 3 → vertex 1, with the length of 1.\n\nThe shortest path from vertex 3 to vertex 2 is: vertex 3 → vertex 1 → vertex 2, with the length of 2.\n\nThus, the only edge that is not contained in any shortest path, is the edge of length 3 connecting vertex 2 and vertex 3, hence the output should be 1.\n\nSample Input 2\n\n3 2\n1 2 1\n2 3 1\n\nSample Output 2\n\n0\n\nEvery edge is contained in some shortest path between some pair of different vertices.", "sample_input": "3 3\n1 2 1\n1 3 1\n2 3 3\n"}, "reference_outputs": ["1\n"], "source_document_id": "p03837", "source_text": "Score : 400 points\n\nProblem Statement\n\nYou are given an undirected connected weighted graph with N vertices and M edges that contains neither self-loops nor double edges.\n\nThe i-th (1≤i≤M) edge connects vertex a_i and vertex b_i with a distance of c_i.\n\nHere, a self-loop is an edge where a_i = b_i (1≤i≤M), and double edges are two edges where (a_i,b_i)=(a_j,b_j) or (a_i,b_i)=(b_j,a_j) (1≤i<j≤M).\n\nA connected graph is a graph where there is a path between every pair of different vertices.\n\nFind the number of the edges that are not contained in any shortest path between any pair of different vertices.\n\nConstraints\n\n2≤N≤100\n\nN-1≤M≤min(N(N-1)/2,1000)\n\n1≤a_i,b_i≤N\n\n1≤c_i≤1000\n\nc_i is an integer.\n\nThe given graph contains neither self-loops nor double edges.\n\nThe given graph is connected.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN M\na_1 b_1 c_1\na_2 b_2 c_2\n:\na_M b_M c_M\n\nOutput\n\nPrint the number of the edges in the graph that are not contained in any shortest path between any pair of different vertices.\n\nSample Input 1\n\n3 3\n1 2 1\n1 3 1\n2 3 3\n\nSample Output 1\n\n1\n\nIn the given graph, the shortest paths between all pairs of different vertices are as follows:\n\nThe shortest path from vertex 1 to vertex 2 is: vertex 1 → vertex 2, with the length of 1.\n\nThe shortest path from vertex 1 to vertex 3 is: vertex 1 → vertex 3, with the length of 1.\n\nThe shortest path from vertex 2 to vertex 1 is: vertex 2 → vertex 1, with the length of 1.\n\nThe shortest path from vertex 2 to vertex 3 is: vertex 2 → vertex 1 → vertex 3, with the length of 2.\n\nThe shortest path from vertex 3 to vertex 1 is: vertex 3 → vertex 1, with the length of 1.\n\nThe shortest path from vertex 3 to vertex 2 is: vertex 3 → vertex 1 → vertex 2, with the length of 2.\n\nThus, the only edge that is not contained in any shortest path, is the edge of length 3 connecting vertex 2 and vertex 3, hence the output should be 1.\n\nSample Input 2\n\n3 2\n1 2 1\n2 3 1\n\nSample Output 2\n\n0\n\nEvery edge is contained in some shortest path between some pair of different vertices.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1251, "cpu_time_ms": 3, "memory_kb": 384}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s849713824", "group_id": "codeNet:p03839", "input_text": "#include <iostream>\n#include <string>\n#include <algorithm>\n#include <vector>\n#include <math.h>\n#include <iomanip>\n#include <cmath>\n#include <queue>\n#include <stack>\n#include <cstdlib>\n#include <map>\nusing namespace std;\n#define int long long\n#define rep(i,n) for(int i=0;i<n;i++)\n#define pie 3.141592653589793238462643383279\n#define mod 1000000007\n#define inf 10000000000000007\n#define all(vec) vec.begin(),vec.end()\n#define ggr getchar(); getchar();return 0;\nint gcd(int x, int y) {\n\tif (y == 0)return x;\n\treturn gcd(y, x % y);\n}\nint lcm(int x, int y) {\n\treturn x / gcd(x, y) * y;\n}\nbool prime(int x) {\n\tfor (int i = 2; i <= sqrt(x); i++) {\n\t\tif (x % i == 0)return false;\n\t}\n\treturn true;\n}\n\nint n, k, a[100010];\nint ta, mu, rin, ans;\n\nsigned main() {\n\tcin >> n >> k;\n\trep(i, n) {\n\t\tcin >> a[i];\n\t\tif (a[i] > 0)ta += a[i];\n\t}\n\trep(i, n) {\n\t\tif (i <= k - 1) {\n\t\t\tif (a[i] > 0)mu += a[i];\n\t\t\trin += a[i];\n\t\t}\n\t\telse {\n\t\t\tif (a[i - (k - 1)] > 0)mu -= a[i - (k - 1)];\n\t\t\trin -= a[i - (k - 1)];\n\t\t\tif (a[i] > 0)mu += a[i];\n\t\t\trin += a[i];\n\t\t}\n\t\tif (i > k - 2)ans = max({ ans,ta + rin - mu,ta - mu });;\n\t}\n\tcout << ans << endl;\n}", "language": "C++", "metadata": {"date": 1554764732, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03839.html", "problem_id": "p03839", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03839/input.txt", "sample_output_relpath": "derived/input_output/data/p03839/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03839/C++/s849713824.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s849713824", "user_id": "u277153875"}, "prompt_components": {"gold_output": "10\n", "input_to_evaluate": "#include <iostream>\n#include <string>\n#include <algorithm>\n#include <vector>\n#include <math.h>\n#include <iomanip>\n#include <cmath>\n#include <queue>\n#include <stack>\n#include <cstdlib>\n#include <map>\nusing namespace std;\n#define int long long\n#define rep(i,n) for(int i=0;i<n;i++)\n#define pie 3.141592653589793238462643383279\n#define mod 1000000007\n#define inf 10000000000000007\n#define all(vec) vec.begin(),vec.end()\n#define ggr getchar(); getchar();return 0;\nint gcd(int x, int y) {\n\tif (y == 0)return x;\n\treturn gcd(y, x % y);\n}\nint lcm(int x, int y) {\n\treturn x / gcd(x, y) * y;\n}\nbool prime(int x) {\n\tfor (int i = 2; i <= sqrt(x); i++) {\n\t\tif (x % i == 0)return false;\n\t}\n\treturn true;\n}\n\nint n, k, a[100010];\nint ta, mu, rin, ans;\n\nsigned main() {\n\tcin >> n >> k;\n\trep(i, n) {\n\t\tcin >> a[i];\n\t\tif (a[i] > 0)ta += a[i];\n\t}\n\trep(i, n) {\n\t\tif (i <= k - 1) {\n\t\t\tif (a[i] > 0)mu += a[i];\n\t\t\trin += a[i];\n\t\t}\n\t\telse {\n\t\t\tif (a[i - (k - 1)] > 0)mu -= a[i - (k - 1)];\n\t\t\trin -= a[i - (k - 1)];\n\t\t\tif (a[i] > 0)mu += a[i];\n\t\t\trin += a[i];\n\t\t}\n\t\tif (i > k - 2)ans = max({ ans,ta + rin - mu,ta - mu });;\n\t}\n\tcout << ans << endl;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nThere are N squares aligned in a row.\nThe i-th square from the left contains an integer a_i.\n\nInitially, all the squares are white.\nSnuke will perform the following operation some number of times:\n\nSelect K consecutive squares. Then, paint all of them white, or paint all of them black. Here, the colors of the squares are overwritten.\n\nAfter Snuke finishes performing the operation, the score will be calculated as the sum of the integers contained in the black squares.\nFind the maximum possible score.\n\nConstraints\n\n1≤N≤10^5\n\n1≤K≤N\n\na_i is an integer.\n\n|a_i|≤10^9\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN K\na_1 a_2 ... a_N\n\nOutput\n\nPrint the maximum possible score.\n\nSample Input 1\n\n5 3\n-10 10 -10 10 -10\n\nSample Output 1\n\n10\n\nPaint the following squares black: the second, third and fourth squares from the left.\n\nSample Input 2\n\n4 2\n10 -10 -10 10\n\nSample Output 2\n\n20\n\nOne possible way to obtain the maximum score is as follows:\n\nPaint the following squares black: the first and second squares from the left.\n\nPaint the following squares black: the third and fourth squares from the left.\n\nPaint the following squares white: the second and third squares from the left.\n\nSample Input 3\n\n1 1\n-10\n\nSample Output 3\n\n0\n\nSample Input 4\n\n10 5\n5 -4 -5 -8 -4 7 2 -4 0 7\n\nSample Output 4\n\n17", "sample_input": "5 3\n-10 10 -10 10 -10\n"}, "reference_outputs": ["10\n"], "source_document_id": "p03839", "source_text": "Score : 400 points\n\nProblem Statement\n\nThere are N squares aligned in a row.\nThe i-th square from the left contains an integer a_i.\n\nInitially, all the squares are white.\nSnuke will perform the following operation some number of times:\n\nSelect K consecutive squares. Then, paint all of them white, or paint all of them black. Here, the colors of the squares are overwritten.\n\nAfter Snuke finishes performing the operation, the score will be calculated as the sum of the integers contained in the black squares.\nFind the maximum possible score.\n\nConstraints\n\n1≤N≤10^5\n\n1≤K≤N\n\na_i is an integer.\n\n|a_i|≤10^9\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN K\na_1 a_2 ... a_N\n\nOutput\n\nPrint the maximum possible score.\n\nSample Input 1\n\n5 3\n-10 10 -10 10 -10\n\nSample Output 1\n\n10\n\nPaint the following squares black: the second, third and fourth squares from the left.\n\nSample Input 2\n\n4 2\n10 -10 -10 10\n\nSample Output 2\n\n20\n\nOne possible way to obtain the maximum score is as follows:\n\nPaint the following squares black: the first and second squares from the left.\n\nPaint the following squares black: the third and fourth squares from the left.\n\nPaint the following squares white: the second and third squares from the left.\n\nSample Input 3\n\n1 1\n-10\n\nSample Output 3\n\n0\n\nSample Input 4\n\n10 5\n5 -4 -5 -8 -4 7 2 -4 0 7\n\nSample Output 4\n\n17", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1124, "cpu_time_ms": 47, "memory_kb": 1024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s903462866", "group_id": "codeNet:p03840", "input_text": "#include <bits/stdc++.h>\n//typedef\n//-------------------------#include <bits/stdc++.h>\n \nconst double pi = 3.141592653589793238462643383279;\n \n \nusing namespace std;\n \n//conversion\n//------------------------------------------\ninline int toInt(string s) { int v; istringstream sin(s); sin >> v; return v; }\ntemplate<class T> inline string toString(T x) { ostringstream sout; sout << x; return sout.str(); }\ninline int readInt() { int x; scanf(\"%d\", &x); return x; }\n \n//typedef\n//------------------------------------------\ntypedef vector<int> VI;\ntypedef vector<VI> VVI;\ntypedef vector<string> VS;\ntypedef pair<int, int> PII;\ntypedef pair<long long, long long> PLL;\ntypedef pair<int, PII> TIII;\ntypedef long long LL;\ntypedef unsigned long long ULL;\ntypedef vector<LL> VLL;\ntypedef vector<VLL> VVLL;\n \n \n//container util\n \n//------------------------------------------\n#define ALL(a)  (a).begin(),(a).end()\n#define RALL(a) (a).rbegin(), (a).rend()\n#define PB push_back\n#define MP make_pair\n#define SZ(a) int((a).size())\n#define SQ(a) ((a)*(a))\n#define EACH(i,c) for(typeof((c).begin()) i=(c).begin(); i!=(c).end(); ++i)\n#define EXIST(s,e) ((s).find(e)!=(s).end())\n#define SORT(c) sort((c).begin(),(c).end())\n \n \n//repetition\n//------------------------------------------\n#define FOR(i,s,n) for(int i=s;i<(int)n;++i)\n#define REP(i,n) FOR(i,0,n)\n#define MOD 1000000007\n \n#define rep(i, a, b) for(int i = a; i < (b); ++i)\n#define trav(a, x) for(auto& a : x)\n#define all(x) x.begin(), x.end()\n#define sz(x) (int)(x).size()\n \ntypedef long long ll;\ntypedef pair<int, int> pii;\ntypedef vector<int> vi;\nconst double EPS = 1E-8;\n \n#define chmin(x,y) x=min(x,y)\n#define chmax(x,y) x=max(x,y)\n \nclass UnionFind {\npublic:\n    vector <int> par; \n    vector <int> siz; \n\n    UnionFind(int sz_): par(sz_), siz(sz_, 1) {\n        for (ll i = 0; i < sz_; ++i) par[i] = i;\n    }\n    void init(int sz_) {\n        par.resize(sz_);\n        siz.assign(sz_, 1LL);\n        for (ll i = 0; i < sz_; ++i) par[i] = i;\n    }\n \n    int root(int x) { \n        while (par[x] != x) {\n            x = par[x] = par[par[x]];\n        }\n        return x;\n    }\n \n    bool merge(int x, int y) {\n        x = root(x);\n        y = root(y);\n        if (x == y) return false;\n        if (siz[x] < siz[y]) swap(x, y);\n        siz[x] += siz[y];\n        par[y] = x;\n        return true;\n    }\n \n    bool issame(int x, int y) { \n        return root(x) == root(y);\n    }\n \n    int size(int x) { \n        return siz[root(x)];\n    }\n};\n \n \nll modPow(ll x, ll n, ll mod = MOD){\n    ll res = 1;\n    while(n){\n        if(n&1) res = (res * x)%mod;\n \n        res %= mod;\n        x = x * x %mod;\n        n >>= 1;\n    }\n    return res;\n}\n \n#define SIEVE_SIZE 5000000+10\nbool sieve[SIEVE_SIZE];\nvoid makeSieve(){\n    for(int i=0; i<SIEVE_SIZE; ++i) sieve[i] = true;\n    sieve[0] = sieve[1] = false;\n    for(int i=2; i*i<SIEVE_SIZE; ++i) if(sieve[i]) for(int j=2; i*j<SIEVE_SIZE; ++j) sieve[i*j] = false;\n}\n \nbool isprime(ll n){\n    if(n == 0 || n == 1) return false;\n    for(ll i=2; i*i<=n; ++i) if(n%i==0) return false;\n    return true;\n}\n \nconst int MAX = 2000010;\nlong long fac[MAX], finv[MAX], inv[MAX];\n \n// テーブルを作る前処理\nvoid COMinit() {\n    fac[0] = fac[1] = 1;\n    finv[0] = finv[1] = 1;\n    inv[1] = 1;\n    for (int i = 2; i < MAX; i++){\n        fac[i] = fac[i - 1] * i % MOD;\n        inv[i] = MOD - inv[MOD%i] * (MOD / i) % MOD;\n        finv[i] = finv[i - 1] * inv[i] % MOD;\n    }\n}\n \n// 二項係数計算\nlong long COM(int n, int k){\n    if (n < k) return 0;\n    if (n < 0 || k < 0) return 0;\n    return fac[n] * (finv[k] * finv[n - k] % MOD) % MOD;\n}\n \nlong long extGCD(long long a, long long b, long long &x, long long &y) {\n    if (b == 0) {\n        x = 1;\n        y = 0;\n        return a;\n    }\n    long long d = extGCD(b, a%b, y, x);\n    y -= a/b * x;\n    return d;\n}\n// 負の数にも対応した mod (a = -11 とかでも OK) \ninline long long mod(long long a, long long m) {\n    return (a % m + m) % m;\n}\n \n// 逆元計算 (ここでは a と m が互いに素であることが必要)\nlong long modinv(long long a, long long m) {\n    long long x, y;\n    extGCD(a, m, x, y);\n    return mod(x, m); // 気持ち的には x % m だが、x が負かもしれないので\n}\nll GCD(ll a, ll b){\n    \n    if(b == 0) return a;\n    return GCD(b, a%b);\n}\n\ntypedef vector<ll> vec;\ntypedef vector<vec> mat;\n\nmat mul(mat &A, mat &B) {\n    mat C(A.size(), vec((int)B[0].size()));\n    for(int i=0; i<A.size(); ++i){\n        for(int k=0; k<B.size(); ++k){\n            for(int j=0; j<B[0].size(); ++j){\n                C[i][j] = (C[i][j] + A[i][k] * B[k][j] %MOD) % MOD;\n            }\n        }\n    }\n    return C;\n}\nmat matPow(mat A, ll n) {\n    mat B(A.size(), vec((int)A.size()));\n \n    for(int i=0; i<A.size(); ++i){\n        B[i][i] = 1;\n    }\n \n    while(n > 0) {\n        if(n & 1) B = mul(B, A);\n        A = mul(A, A);\n        n >>= 1;\n    }\n    return B;\n}\n\nint main() {\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n    cout << fixed << setprecision(15);\n\n\n    ll ai,ao,at,aj,al,as,az;cin>>ai>>ao>>at>>aj>>al>>as>>az;\n\n    ll ans = 0;\n\n    for(ll i=0; i<=min({ai, aj, al}); i++){\n        ans = max(ans, ao+i*3 + (ai-i)/2*2 + (aj-i)/2*2 + (al-i)/2*2);\n    }\n    cout << ans << endl;\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1584712005, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03840.html", "problem_id": "p03840", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03840/input.txt", "sample_output_relpath": "derived/input_output/data/p03840/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03840/C++/s903462866.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s903462866", "user_id": "u181719868"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <bits/stdc++.h>\n//typedef\n//-------------------------#include <bits/stdc++.h>\n \nconst double pi = 3.141592653589793238462643383279;\n \n \nusing namespace std;\n \n//conversion\n//------------------------------------------\ninline int toInt(string s) { int v; istringstream sin(s); sin >> v; return v; }\ntemplate<class T> inline string toString(T x) { ostringstream sout; sout << x; return sout.str(); }\ninline int readInt() { int x; scanf(\"%d\", &x); return x; }\n \n//typedef\n//------------------------------------------\ntypedef vector<int> VI;\ntypedef vector<VI> VVI;\ntypedef vector<string> VS;\ntypedef pair<int, int> PII;\ntypedef pair<long long, long long> PLL;\ntypedef pair<int, PII> TIII;\ntypedef long long LL;\ntypedef unsigned long long ULL;\ntypedef vector<LL> VLL;\ntypedef vector<VLL> VVLL;\n \n \n//container util\n \n//------------------------------------------\n#define ALL(a)  (a).begin(),(a).end()\n#define RALL(a) (a).rbegin(), (a).rend()\n#define PB push_back\n#define MP make_pair\n#define SZ(a) int((a).size())\n#define SQ(a) ((a)*(a))\n#define EACH(i,c) for(typeof((c).begin()) i=(c).begin(); i!=(c).end(); ++i)\n#define EXIST(s,e) ((s).find(e)!=(s).end())\n#define SORT(c) sort((c).begin(),(c).end())\n \n \n//repetition\n//------------------------------------------\n#define FOR(i,s,n) for(int i=s;i<(int)n;++i)\n#define REP(i,n) FOR(i,0,n)\n#define MOD 1000000007\n \n#define rep(i, a, b) for(int i = a; i < (b); ++i)\n#define trav(a, x) for(auto& a : x)\n#define all(x) x.begin(), x.end()\n#define sz(x) (int)(x).size()\n \ntypedef long long ll;\ntypedef pair<int, int> pii;\ntypedef vector<int> vi;\nconst double EPS = 1E-8;\n \n#define chmin(x,y) x=min(x,y)\n#define chmax(x,y) x=max(x,y)\n \nclass UnionFind {\npublic:\n    vector <int> par; \n    vector <int> siz; \n\n    UnionFind(int sz_): par(sz_), siz(sz_, 1) {\n        for (ll i = 0; i < sz_; ++i) par[i] = i;\n    }\n    void init(int sz_) {\n        par.resize(sz_);\n        siz.assign(sz_, 1LL);\n        for (ll i = 0; i < sz_; ++i) par[i] = i;\n    }\n \n    int root(int x) { \n        while (par[x] != x) {\n            x = par[x] = par[par[x]];\n        }\n        return x;\n    }\n \n    bool merge(int x, int y) {\n        x = root(x);\n        y = root(y);\n        if (x == y) return false;\n        if (siz[x] < siz[y]) swap(x, y);\n        siz[x] += siz[y];\n        par[y] = x;\n        return true;\n    }\n \n    bool issame(int x, int y) { \n        return root(x) == root(y);\n    }\n \n    int size(int x) { \n        return siz[root(x)];\n    }\n};\n \n \nll modPow(ll x, ll n, ll mod = MOD){\n    ll res = 1;\n    while(n){\n        if(n&1) res = (res * x)%mod;\n \n        res %= mod;\n        x = x * x %mod;\n        n >>= 1;\n    }\n    return res;\n}\n \n#define SIEVE_SIZE 5000000+10\nbool sieve[SIEVE_SIZE];\nvoid makeSieve(){\n    for(int i=0; i<SIEVE_SIZE; ++i) sieve[i] = true;\n    sieve[0] = sieve[1] = false;\n    for(int i=2; i*i<SIEVE_SIZE; ++i) if(sieve[i]) for(int j=2; i*j<SIEVE_SIZE; ++j) sieve[i*j] = false;\n}\n \nbool isprime(ll n){\n    if(n == 0 || n == 1) return false;\n    for(ll i=2; i*i<=n; ++i) if(n%i==0) return false;\n    return true;\n}\n \nconst int MAX = 2000010;\nlong long fac[MAX], finv[MAX], inv[MAX];\n \n// テーブルを作る前処理\nvoid COMinit() {\n    fac[0] = fac[1] = 1;\n    finv[0] = finv[1] = 1;\n    inv[1] = 1;\n    for (int i = 2; i < MAX; i++){\n        fac[i] = fac[i - 1] * i % MOD;\n        inv[i] = MOD - inv[MOD%i] * (MOD / i) % MOD;\n        finv[i] = finv[i - 1] * inv[i] % MOD;\n    }\n}\n \n// 二項係数計算\nlong long COM(int n, int k){\n    if (n < k) return 0;\n    if (n < 0 || k < 0) return 0;\n    return fac[n] * (finv[k] * finv[n - k] % MOD) % MOD;\n}\n \nlong long extGCD(long long a, long long b, long long &x, long long &y) {\n    if (b == 0) {\n        x = 1;\n        y = 0;\n        return a;\n    }\n    long long d = extGCD(b, a%b, y, x);\n    y -= a/b * x;\n    return d;\n}\n// 負の数にも対応した mod (a = -11 とかでも OK) \ninline long long mod(long long a, long long m) {\n    return (a % m + m) % m;\n}\n \n// 逆元計算 (ここでは a と m が互いに素であることが必要)\nlong long modinv(long long a, long long m) {\n    long long x, y;\n    extGCD(a, m, x, y);\n    return mod(x, m); // 気持ち的には x % m だが、x が負かもしれないので\n}\nll GCD(ll a, ll b){\n    \n    if(b == 0) return a;\n    return GCD(b, a%b);\n}\n\ntypedef vector<ll> vec;\ntypedef vector<vec> mat;\n\nmat mul(mat &A, mat &B) {\n    mat C(A.size(), vec((int)B[0].size()));\n    for(int i=0; i<A.size(); ++i){\n        for(int k=0; k<B.size(); ++k){\n            for(int j=0; j<B[0].size(); ++j){\n                C[i][j] = (C[i][j] + A[i][k] * B[k][j] %MOD) % MOD;\n            }\n        }\n    }\n    return C;\n}\nmat matPow(mat A, ll n) {\n    mat B(A.size(), vec((int)A.size()));\n \n    for(int i=0; i<A.size(); ++i){\n        B[i][i] = 1;\n    }\n \n    while(n > 0) {\n        if(n & 1) B = mul(B, A);\n        A = mul(A, A);\n        n >>= 1;\n    }\n    return B;\n}\n\nint main() {\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n    cout << fixed << setprecision(15);\n\n\n    ll ai,ao,at,aj,al,as,az;cin>>ai>>ao>>at>>aj>>al>>as>>az;\n\n    ll ans = 0;\n\n    for(ll i=0; i<=min({ai, aj, al}); i++){\n        ans = max(ans, ao+i*3 + (ai-i)/2*2 + (aj-i)/2*2 + (al-i)/2*2);\n    }\n    cout << ans << endl;\n    return 0;\n}\n", "problem_context": "Score : 600 points\n\nProblem Statement\n\nA tetromino is a figure formed by joining four squares edge to edge.\nWe will refer to the following seven kinds of tetromino as I-, O-, T-, J-, L-, S- and Z-tetrominos, respectively:\n\nSnuke has many tetrominos. The number of I-, O-, T-, J-, L-, S- and Z-tetrominos in his possession are a_I, a_O, a_T, a_J, a_L, a_S and a_Z, respectively.\nSnuke will join K of his tetrominos to form a rectangle that is two squares tall and 2K squares wide.\nHere, the following rules must be followed:\n\nWhen placing each tetromino, rotation is allowed, but reflection is not.\n\nEach square in the rectangle must be covered by exactly one tetromino.\n\nNo part of each tetromino may be outside the rectangle.\n\nSnuke wants to form as large a rectangle as possible.\nFind the maximum possible value of K.\n\nConstraints\n\n0≤a_I,a_O,a_T,a_J,a_L,a_S,a_Z≤10^9\n\na_I+a_O+a_T+a_J+a_L+a_S+a_Z≥1\n\nInput\n\nThe input is given from Standard Input in the following format:\n\na_I a_O a_T a_J a_L a_S a_Z\n\nOutput\n\nPrint the maximum possible value of K. If no rectangle can be formed, print 0.\n\nSample Input 1\n\n2 1 1 0 0 0 0\n\nSample Output 1\n\n3\n\nOne possible way to form the largest rectangle is shown in the following figure:\n\nSample Input 2\n\n0 0 10 0 0 0 0\n\nSample Output 2\n\n0\n\nNo rectangle can be formed.", "sample_input": "2 1 1 0 0 0 0\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03840", "source_text": "Score : 600 points\n\nProblem Statement\n\nA tetromino is a figure formed by joining four squares edge to edge.\nWe will refer to the following seven kinds of tetromino as I-, O-, T-, J-, L-, S- and Z-tetrominos, respectively:\n\nSnuke has many tetrominos. The number of I-, O-, T-, J-, L-, S- and Z-tetrominos in his possession are a_I, a_O, a_T, a_J, a_L, a_S and a_Z, respectively.\nSnuke will join K of his tetrominos to form a rectangle that is two squares tall and 2K squares wide.\nHere, the following rules must be followed:\n\nWhen placing each tetromino, rotation is allowed, but reflection is not.\n\nEach square in the rectangle must be covered by exactly one tetromino.\n\nNo part of each tetromino may be outside the rectangle.\n\nSnuke wants to form as large a rectangle as possible.\nFind the maximum possible value of K.\n\nConstraints\n\n0≤a_I,a_O,a_T,a_J,a_L,a_S,a_Z≤10^9\n\na_I+a_O+a_T+a_J+a_L+a_S+a_Z≥1\n\nInput\n\nThe input is given from Standard Input in the following format:\n\na_I a_O a_T a_J a_L a_S a_Z\n\nOutput\n\nPrint the maximum possible value of K. If no rectangle can be formed, print 0.\n\nSample Input 1\n\n2 1 1 0 0 0 0\n\nSample Output 1\n\n3\n\nOne possible way to form the largest rectangle is shown in the following figure:\n\nSample Input 2\n\n0 0 10 0 0 0 0\n\nSample Output 2\n\n0\n\nNo rectangle can be formed.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 5266, "cpu_time_ms": 2103, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s228299533", "group_id": "codeNet:p03842", "input_text": "#include<stdio.h>\n#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define f(i, x, n) for(int i = x; i < (int)n; ++i)\n\nint an = 1, cy[100001], md = 1e9 + 7, dp[100001][2];\npair<int, int> y[100001], ln[100001];\nbool vis[100001];\n\nvoid no(){\n\tprintf(\"0\\n\");\n\texit(0);\n}\n\nint V;\nbool go(int v, int m = 0, int d = 0){\n\tif (vis[v]){\n\t\tif (v == V) { ln[m].first = d; return true; }\n\t\treturn false;\n\t}\n\tvis[v] = true;\n\tif (!y[v].first) { ln[m].second = d; return false; }\n\tbool k = go(y[v].first, y[v].second ? v : m, d + 1);\n\tif (y[v].second)ln[m].first = d, k |= go(y[v].second, v, d + 1);\n\treturn k;\n}\n\ninline void ad(int s, int l){\n\tdp[0][0] = 1;\n\tint z = (s & 1 && s != 1) + 1;\n\tf(i, 1, l + 1){\n\t\tdp[i][0] = ((ll)dp[i - 1][0] * z + (ll)dp[i - 1][1] * s) % md;\n\t\tdp[i][1] = ((ll)dp[i - 1][1] * z + dp[i - 1][0]) % md;\n\t}\n\tan = (ll)an * dp[l][0] % md;\n}\n\nint main(){\n\tint n;\n\tscanf(\"%d\", &n);\n\tf(i, 1, n + 1){\n\t\tint t;\n\t\tscanf(\"%d\", &t);\n\t\tif (y[t].first){\n\t\t\tif (y[t].second)no();\n\t\t\ty[t].second = i;\n\t\t}\n\t\telse y[t].first = i;\n\t}\n\tf(i, 1, n + 1)if (y[i].second){\n\t\tV = i;\n\t\tif (!vis[i] && !go(i))no();\n\t\tif (!ln[i].second)no();\n\t\tif (ln[i].first > ln[i].second) { if ((an <<= 1) >= md)an -= md; }\n\t\telse if (ln[i].first < ln[i].second)no();\n\t}\n\tf(i, 1, n + 1)if (!vis[i]){\n\t\tV = i;\n\t\tif (go(i, i))++cy[ln[i].first];\n\t}\n\tf(i, 1, n + 1)if (cy[i])ad(i, cy[i]);\n\tprintf(\"%d\\n\", an);\n}\n", "language": "C++", "metadata": {"date": 1482922063, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03842.html", "problem_id": "p03842", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03842/input.txt", "sample_output_relpath": "derived/input_output/data/p03842/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03842/C++/s228299533.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s228299533", "user_id": "u647100698"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include<stdio.h>\n#include<bits/stdc++.h>\nusing namespace std;\n#define ll long long\n#define f(i, x, n) for(int i = x; i < (int)n; ++i)\n\nint an = 1, cy[100001], md = 1e9 + 7, dp[100001][2];\npair<int, int> y[100001], ln[100001];\nbool vis[100001];\n\nvoid no(){\n\tprintf(\"0\\n\");\n\texit(0);\n}\n\nint V;\nbool go(int v, int m = 0, int d = 0){\n\tif (vis[v]){\n\t\tif (v == V) { ln[m].first = d; return true; }\n\t\treturn false;\n\t}\n\tvis[v] = true;\n\tif (!y[v].first) { ln[m].second = d; return false; }\n\tbool k = go(y[v].first, y[v].second ? v : m, d + 1);\n\tif (y[v].second)ln[m].first = d, k |= go(y[v].second, v, d + 1);\n\treturn k;\n}\n\ninline void ad(int s, int l){\n\tdp[0][0] = 1;\n\tint z = (s & 1 && s != 1) + 1;\n\tf(i, 1, l + 1){\n\t\tdp[i][0] = ((ll)dp[i - 1][0] * z + (ll)dp[i - 1][1] * s) % md;\n\t\tdp[i][1] = ((ll)dp[i - 1][1] * z + dp[i - 1][0]) % md;\n\t}\n\tan = (ll)an * dp[l][0] % md;\n}\n\nint main(){\n\tint n;\n\tscanf(\"%d\", &n);\n\tf(i, 1, n + 1){\n\t\tint t;\n\t\tscanf(\"%d\", &t);\n\t\tif (y[t].first){\n\t\t\tif (y[t].second)no();\n\t\t\ty[t].second = i;\n\t\t}\n\t\telse y[t].first = i;\n\t}\n\tf(i, 1, n + 1)if (y[i].second){\n\t\tV = i;\n\t\tif (!vis[i] && !go(i))no();\n\t\tif (!ln[i].second)no();\n\t\tif (ln[i].first > ln[i].second) { if ((an <<= 1) >= md)an -= md; }\n\t\telse if (ln[i].first < ln[i].second)no();\n\t}\n\tf(i, 1, n + 1)if (!vis[i]){\n\t\tV = i;\n\t\tif (go(i, i))++cy[ln[i].first];\n\t}\n\tf(i, 1, n + 1)if (cy[i])ad(i, cy[i]);\n\tprintf(\"%d\\n\", an);\n}\n", "problem_context": "Score : 1400 points\n\nProblem Statement\n\nYou are given an integer sequence a of length N.\nHow many permutations p of the integers 1 through N satisfy the following condition?\n\nFor each 1 ≤ i ≤ N, at least one of the following holds: p_i = a_i and p_{p_i} = a_i.\n\nFind the count modulo 10^9 + 7.\n\nConstraints\n\n1 ≤ N ≤ 10^5\n\na_i is an integer.\n\n1 ≤ a_i ≤ N\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_N\n\nOutput\n\nPrint the number of the permutations p that satisfy the condition, modulo 10^9 + 7.\n\nSample Input 1\n\n3\n1 2 3\n\nSample Output 1\n\n4\n\nThe following four permutations satisfy the condition:\n\n(1, 2, 3)\n\n(1, 3, 2)\n\n(3, 2, 1)\n\n(2, 1, 3)\n\nFor example, (1, 3, 2) satisfies the condition because p_1 = 1, p_{p_2} = 2 and p_{p_3} = 3.\n\nSample Input 2\n\n2\n1 1\n\nSample Output 2\n\n1\n\nThe following one permutation satisfies the condition:\n\n(2, 1)\n\nSample Input 3\n\n3\n2 1 1\n\nSample Output 3\n\n2\n\nThe following two permutations satisfy the condition:\n\n(2, 3, 1)\n\n(3, 1, 2)\n\nSample Input 4\n\n3\n1 1 1\n\nSample Output 4\n\n0\n\nSample Input 5\n\n13\n2 1 4 3 6 7 5 9 10 8 8 9 11\n\nSample Output 5\n\n6", "sample_input": "3\n1 2 3\n"}, "reference_outputs": ["4\n"], "source_document_id": "p03842", "source_text": "Score : 1400 points\n\nProblem Statement\n\nYou are given an integer sequence a of length N.\nHow many permutations p of the integers 1 through N satisfy the following condition?\n\nFor each 1 ≤ i ≤ N, at least one of the following holds: p_i = a_i and p_{p_i} = a_i.\n\nFind the count modulo 10^9 + 7.\n\nConstraints\n\n1 ≤ N ≤ 10^5\n\na_i is an integer.\n\n1 ≤ a_i ≤ N\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_N\n\nOutput\n\nPrint the number of the permutations p that satisfy the condition, modulo 10^9 + 7.\n\nSample Input 1\n\n3\n1 2 3\n\nSample Output 1\n\n4\n\nThe following four permutations satisfy the condition:\n\n(1, 2, 3)\n\n(1, 3, 2)\n\n(3, 2, 1)\n\n(2, 1, 3)\n\nFor example, (1, 3, 2) satisfies the condition because p_1 = 1, p_{p_2} = 2 and p_{p_3} = 3.\n\nSample Input 2\n\n2\n1 1\n\nSample Output 2\n\n1\n\nThe following one permutation satisfies the condition:\n\n(2, 1)\n\nSample Input 3\n\n3\n2 1 1\n\nSample Output 3\n\n2\n\nThe following two permutations satisfy the condition:\n\n(2, 3, 1)\n\n(3, 1, 2)\n\nSample Input 4\n\n3\n1 1 1\n\nSample Output 4\n\n0\n\nSample Input 5\n\n13\n2 1 4 3 6 7 5 9 10 8 8 9 11\n\nSample Output 5\n\n6", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1396, "cpu_time_ms": 22, "memory_kb": 5760}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s128057507", "group_id": "codeNet:p03843", "input_text": "#include <iostream>\n#include <vector>\n#include <utility>\n#include <map>\n#include <set>\n#include <string>\n#include <algorithm>\n#define llint long long\n#define inf 1000000000\n\nusing namespace std;\ntypedef pair<llint, llint> P;\n\nllint n;\nvector<llint> G[200005];\nvector<llint> dp[200005], dp2[200005];\nllint pid[200005];\nvector<P> E;\nstring s;\n\nmap<P, llint> Ginv;\nvector<llint> lmin[200005], rmin[200005];\n\nvoid dfs(int v, int p)\n{\n\tpid[v] = -1;\n\tfor(int i = 0; i < G[v].size(); i++){\n\t\tint u = G[v][i];\n\t\tif(u == p){\n\t\t\tpid[v] = i;\n\t\t\tcontinue;\n\t\t}\n\t\tdfs(u, v);\n\t\t\n\t\tllint mx = 0, mn = inf;\n\t\tfor(int j = 0; j < G[u].size(); j++){\n\t\t\tif(G[u][j] == v) continue;\n\t\t\tmx = max(mx, dp[u][j]);\n\t\t\tmn = min(mn, dp2[u][j]);\n\t\t}\n\t\tdp[v][i] = mx + 1;\n\t\tif(s[u] == '1') mn = 0;\n\t\tif(s[v] == '1') mn = -1;\n\t\tdp2[v][i] = mn + 1;\n\t}\n}\n\nllint lmx[200005], rmx[200005];\nllint lmn[200005], rmn[200005];\nvoid dfs2(int v, int p)\n{\n\tfor(int i = 0; i < G[v].size(); i++){\n\t\tlmx[i] = dp[v][i];\n\t\tif(i > 0) lmx[i] = max(lmx[i], lmx[i-1]);\n\t\tlmn[i] = dp2[v][i];\n\t\tif(i > 0) lmn[i] = min(lmn[i], lmn[i-1]);\n\t}\n\tfor(int i = (int)G[v].size()-1; i >= 0; i--){\n\t\trmx[i] = dp[v][i];\n\t\tif(i < (int)G[v].size()-1) rmx[i] = max(rmx[i], rmx[i+1]);\n\t\trmn[i] = dp2[v][i];\n\t\tif(i < (int)G[v].size()-1) rmn[i] = min(rmn[i], rmn[i+1]);\n\t}\n\tfor(int i = 0; i < G[v].size(); i++){\n\t\tint u = G[v][i];\n\t\tif(u == p) continue;\n\t\tllint mx = 0;\n\t\tif(i > 0) mx = max(mx, lmx[i-1]);\n\t\tif(i < (int)G[v].size()-1) mx = max(mx, rmx[i+1]);\n\t\tdp[u][pid[u]] = mx+1;\n\t\t\n\t\tllint mn = inf;\n\t\tif(i > 0) mn = min(mn, lmn[i-1]);\n\t\tif(i < (int)G[v].size()-1) mn = min(mn, rmn[i+1]);\n\t\tif(s[v] == '1') mn = 0;\n\t\tif(s[u] == '1') mn = -1;\n\t\tdp2[u][pid[u]] = mn+1;\n\t}\n\tfor(int i = 0; i < G[v].size(); i++){\n\t\tif(G[v][i] == p) continue;\n\t\tdfs2(G[v][i], v);\n\t}\n}\n\nint main(void)\n{\n\tios::sync_with_stdio(0);\n\tcin.tie(0);\n\t\n\tcin >> n;\n\tllint u, v;\n\tfor(int i = 1; i <= n-1; i++){\n\t\tcin >> u >> v;\n\t\tG[u].push_back(v);\n\t\tG[v].push_back(u);\n\t\tE.push_back(make_pair(u, v));\n\t}\n\tcin >> s;\n\ts = \"#\" + s;\n\t\n\tfor(int i = 1; i <= n; i++) dp[i].resize(G[i].size()), dp2[i].resize(G[i].size());\n\tdfs(1, -1);\n\tdfs2(1, -1);\n\t\n\t/*for(int i = 1; i <= n; i++){\n\t\tfor(int j = 0; j < dp[i].size(); j++){\n\t\t\tcout << i << G[i][j] << \" \" << dp2[i][j] << endl;\n\t\t}\n\t}*/\n\t\n\tllint ans = 0;\n\tfor(int i = 1; i <= n; i++){\n\t\t//cout << i << \" \" << ans << endl;\n\t\tif(s[i] == '1'){\n\t\t\tans++;\n\t\t\tvector<llint> vec;\n\t\t\tif(G[i].size() <= 1) continue;\n\t\t\tfor(int j = 0; j < G[i].size(); j++) vec.push_back(dp[i][j]);\n\t\t\tsort(vec.rbegin(), vec.rend());\n\t\t\tans += min(vec[0], vec[1]);\n\t\t}\n\t\telse{\n\t\t\tvector<P> vec, vec2;\n\t\t\tif(G[i].size() <= 1) continue;\n\t\t\tfor(int j = 0; j < G[i].size(); j++){\n\t\t\t\tllint dep = dp[i][j], dep2 = dp2[i][j], x = 1;\n\t\t\t\tif(dep >= dep2) x = 0;\n\t\t\t\tvec.push_back(make_pair(dep, x));\n\t\t\t}\n\t\t\tsort(vec.begin(), vec.end());\n\t\t\t\n\t\t\tbool flag = false;\n\t\t\tfor(int j = 0; j < vec.size(); j++){\n\t\t\t\tif(vec[j].second == 0) flag = true;\n\t\t\t\tif(flag) vec2.push_back(vec[j]);\n\t\t\t}\n\t\t\tif(vec2.size() <= 1) continue;\n\t\t\t\n\t\t\tif(vec2.size() >= 3){\n\t\t\t\tllint mx2 = vec2[vec2.size()-2].first;\n\t\t\t\tans += max(0LL, mx2 - vec2.front().first + 1);\n\t\t\t}\n\t\t\t/*set<llint> S;\n\t\t\tif(vec[1].first < mn2 && vec[1].second == 1) S.insert(vec[1].first);\n\t\t\tif(vec[0].first < mn2 && vec[0].second == 1) S.insert(vec[0].first);\n\t\t\tans += S.size();*/\n\t\t}\n\t\t//cout << i << \" \" << ans << endl;\n\t}\n\t\n\tfor(int i = 1; i <= n; i++){\n\t\tlmin[i].resize(G[i].size()), rmin[i].resize(G[i].size());\n\t\tfor(int j = 0; j < G[i].size(); j++){\n\t\t\tGinv[make_pair(i, G[i][j])] = j;\n\t\t\tlmin[i][j] = dp2[i][j];\n\t\t\tif(j > 0) lmin[i][j] = min(lmin[i][j], lmin[i][j-1]);\n\t\t}\n\t\tfor(int j = (int)G[i].size()-1; j >= 0; j--){\n\t\t\trmin[i][j] = dp2[i][j];\n\t\t\tif(j < (int)G[i].size()-1) rmin[i][j] = min(rmin[i][j], rmin[i][j+1]);\n\t\t}\n\t}\n\t\n\tfor(int i = 0; i < E.size(); i++){\n\t\tllint u = E[i].first, v = E[i].second;\n\t\tllint umx = dp[v][Ginv[make_pair(v, u)]]-1, vmx = dp[u][Ginv[make_pair(u, v)]]-1;\n\t\tllint d = min(umx, vmx);\n\t\t\n\t\tllint umx2 = inf, vmx2 = inf;\n\t\tif(s[u] == '1') umx2 = 0; if(s[v] == '1') vmx2 = 0;\n\t\tllint upos = Ginv[make_pair(u, v)], vpos = Ginv[make_pair(v, u)];\n\t\tif(upos > 0) umx2 = min(umx2, lmin[u][upos-1]);\n\t\tif(upos < (int)G[u].size()-1) umx2 = min(umx2, rmin[u][upos+1]);\n\t\tif(vpos > 0) vmx2 = min(vmx2, lmin[v][vpos-1]);\n\t\tif(vpos < (int)G[v].size()-1) vmx2 = min(vmx2, rmin[v][vpos+1]);\n\t\t\n\t\t//bool flag = (umx == d && umx >= umx2) || (vmx == d && vmx >= vmx2);\n\t\t//cout << u << \" \" << v << \" \" << umx2 << \" \" << vmx2 << \" \" << flag << endl;\n\t\t\n\t\tif((umx == d && umx >= umx2) || (vmx == d && vmx >= vmx2)) ans++;\n\t\t//cout << u << \" \" << v << \" \" << flag << endl;\n\t}\n\t\n\tcout << ans << endl;\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1563515668, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03843.html", "problem_id": "p03843", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03843/input.txt", "sample_output_relpath": "derived/input_output/data/p03843/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03843/C++/s128057507.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s128057507", "user_id": "u319282133"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\n#include <utility>\n#include <map>\n#include <set>\n#include <string>\n#include <algorithm>\n#define llint long long\n#define inf 1000000000\n\nusing namespace std;\ntypedef pair<llint, llint> P;\n\nllint n;\nvector<llint> G[200005];\nvector<llint> dp[200005], dp2[200005];\nllint pid[200005];\nvector<P> E;\nstring s;\n\nmap<P, llint> Ginv;\nvector<llint> lmin[200005], rmin[200005];\n\nvoid dfs(int v, int p)\n{\n\tpid[v] = -1;\n\tfor(int i = 0; i < G[v].size(); i++){\n\t\tint u = G[v][i];\n\t\tif(u == p){\n\t\t\tpid[v] = i;\n\t\t\tcontinue;\n\t\t}\n\t\tdfs(u, v);\n\t\t\n\t\tllint mx = 0, mn = inf;\n\t\tfor(int j = 0; j < G[u].size(); j++){\n\t\t\tif(G[u][j] == v) continue;\n\t\t\tmx = max(mx, dp[u][j]);\n\t\t\tmn = min(mn, dp2[u][j]);\n\t\t}\n\t\tdp[v][i] = mx + 1;\n\t\tif(s[u] == '1') mn = 0;\n\t\tif(s[v] == '1') mn = -1;\n\t\tdp2[v][i] = mn + 1;\n\t}\n}\n\nllint lmx[200005], rmx[200005];\nllint lmn[200005], rmn[200005];\nvoid dfs2(int v, int p)\n{\n\tfor(int i = 0; i < G[v].size(); i++){\n\t\tlmx[i] = dp[v][i];\n\t\tif(i > 0) lmx[i] = max(lmx[i], lmx[i-1]);\n\t\tlmn[i] = dp2[v][i];\n\t\tif(i > 0) lmn[i] = min(lmn[i], lmn[i-1]);\n\t}\n\tfor(int i = (int)G[v].size()-1; i >= 0; i--){\n\t\trmx[i] = dp[v][i];\n\t\tif(i < (int)G[v].size()-1) rmx[i] = max(rmx[i], rmx[i+1]);\n\t\trmn[i] = dp2[v][i];\n\t\tif(i < (int)G[v].size()-1) rmn[i] = min(rmn[i], rmn[i+1]);\n\t}\n\tfor(int i = 0; i < G[v].size(); i++){\n\t\tint u = G[v][i];\n\t\tif(u == p) continue;\n\t\tllint mx = 0;\n\t\tif(i > 0) mx = max(mx, lmx[i-1]);\n\t\tif(i < (int)G[v].size()-1) mx = max(mx, rmx[i+1]);\n\t\tdp[u][pid[u]] = mx+1;\n\t\t\n\t\tllint mn = inf;\n\t\tif(i > 0) mn = min(mn, lmn[i-1]);\n\t\tif(i < (int)G[v].size()-1) mn = min(mn, rmn[i+1]);\n\t\tif(s[v] == '1') mn = 0;\n\t\tif(s[u] == '1') mn = -1;\n\t\tdp2[u][pid[u]] = mn+1;\n\t}\n\tfor(int i = 0; i < G[v].size(); i++){\n\t\tif(G[v][i] == p) continue;\n\t\tdfs2(G[v][i], v);\n\t}\n}\n\nint main(void)\n{\n\tios::sync_with_stdio(0);\n\tcin.tie(0);\n\t\n\tcin >> n;\n\tllint u, v;\n\tfor(int i = 1; i <= n-1; i++){\n\t\tcin >> u >> v;\n\t\tG[u].push_back(v);\n\t\tG[v].push_back(u);\n\t\tE.push_back(make_pair(u, v));\n\t}\n\tcin >> s;\n\ts = \"#\" + s;\n\t\n\tfor(int i = 1; i <= n; i++) dp[i].resize(G[i].size()), dp2[i].resize(G[i].size());\n\tdfs(1, -1);\n\tdfs2(1, -1);\n\t\n\t/*for(int i = 1; i <= n; i++){\n\t\tfor(int j = 0; j < dp[i].size(); j++){\n\t\t\tcout << i << G[i][j] << \" \" << dp2[i][j] << endl;\n\t\t}\n\t}*/\n\t\n\tllint ans = 0;\n\tfor(int i = 1; i <= n; i++){\n\t\t//cout << i << \" \" << ans << endl;\n\t\tif(s[i] == '1'){\n\t\t\tans++;\n\t\t\tvector<llint> vec;\n\t\t\tif(G[i].size() <= 1) continue;\n\t\t\tfor(int j = 0; j < G[i].size(); j++) vec.push_back(dp[i][j]);\n\t\t\tsort(vec.rbegin(), vec.rend());\n\t\t\tans += min(vec[0], vec[1]);\n\t\t}\n\t\telse{\n\t\t\tvector<P> vec, vec2;\n\t\t\tif(G[i].size() <= 1) continue;\n\t\t\tfor(int j = 0; j < G[i].size(); j++){\n\t\t\t\tllint dep = dp[i][j], dep2 = dp2[i][j], x = 1;\n\t\t\t\tif(dep >= dep2) x = 0;\n\t\t\t\tvec.push_back(make_pair(dep, x));\n\t\t\t}\n\t\t\tsort(vec.begin(), vec.end());\n\t\t\t\n\t\t\tbool flag = false;\n\t\t\tfor(int j = 0; j < vec.size(); j++){\n\t\t\t\tif(vec[j].second == 0) flag = true;\n\t\t\t\tif(flag) vec2.push_back(vec[j]);\n\t\t\t}\n\t\t\tif(vec2.size() <= 1) continue;\n\t\t\t\n\t\t\tif(vec2.size() >= 3){\n\t\t\t\tllint mx2 = vec2[vec2.size()-2].first;\n\t\t\t\tans += max(0LL, mx2 - vec2.front().first + 1);\n\t\t\t}\n\t\t\t/*set<llint> S;\n\t\t\tif(vec[1].first < mn2 && vec[1].second == 1) S.insert(vec[1].first);\n\t\t\tif(vec[0].first < mn2 && vec[0].second == 1) S.insert(vec[0].first);\n\t\t\tans += S.size();*/\n\t\t}\n\t\t//cout << i << \" \" << ans << endl;\n\t}\n\t\n\tfor(int i = 1; i <= n; i++){\n\t\tlmin[i].resize(G[i].size()), rmin[i].resize(G[i].size());\n\t\tfor(int j = 0; j < G[i].size(); j++){\n\t\t\tGinv[make_pair(i, G[i][j])] = j;\n\t\t\tlmin[i][j] = dp2[i][j];\n\t\t\tif(j > 0) lmin[i][j] = min(lmin[i][j], lmin[i][j-1]);\n\t\t}\n\t\tfor(int j = (int)G[i].size()-1; j >= 0; j--){\n\t\t\trmin[i][j] = dp2[i][j];\n\t\t\tif(j < (int)G[i].size()-1) rmin[i][j] = min(rmin[i][j], rmin[i][j+1]);\n\t\t}\n\t}\n\t\n\tfor(int i = 0; i < E.size(); i++){\n\t\tllint u = E[i].first, v = E[i].second;\n\t\tllint umx = dp[v][Ginv[make_pair(v, u)]]-1, vmx = dp[u][Ginv[make_pair(u, v)]]-1;\n\t\tllint d = min(umx, vmx);\n\t\t\n\t\tllint umx2 = inf, vmx2 = inf;\n\t\tif(s[u] == '1') umx2 = 0; if(s[v] == '1') vmx2 = 0;\n\t\tllint upos = Ginv[make_pair(u, v)], vpos = Ginv[make_pair(v, u)];\n\t\tif(upos > 0) umx2 = min(umx2, lmin[u][upos-1]);\n\t\tif(upos < (int)G[u].size()-1) umx2 = min(umx2, rmin[u][upos+1]);\n\t\tif(vpos > 0) vmx2 = min(vmx2, lmin[v][vpos-1]);\n\t\tif(vpos < (int)G[v].size()-1) vmx2 = min(vmx2, rmin[v][vpos+1]);\n\t\t\n\t\t//bool flag = (umx == d && umx >= umx2) || (vmx == d && vmx >= vmx2);\n\t\t//cout << u << \" \" << v << \" \" << umx2 << \" \" << vmx2 << \" \" << flag << endl;\n\t\t\n\t\tif((umx == d && umx >= umx2) || (vmx == d && vmx >= vmx2)) ans++;\n\t\t//cout << u << \" \" << v << \" \" << flag << endl;\n\t}\n\t\n\tcout << ans << endl;\n\treturn 0;\n}", "problem_context": "Score : 1900 points\n\nProblem Statement\n\nThere is a tree with N vertices.\nThe vertices are numbered 1 through N.\nFor each 1 ≤ i ≤ N - 1, the i-th edge connects vertices a_i and b_i.\nThe lengths of all the edges are 1.\n\nSnuke likes some of the vertices.\nThe information on his favorite vertices are given to you as a string s of length N.\nFor each 1 ≤ i ≤ N, s_i is 1 if Snuke likes vertex i, and 0 if he does not like vertex i.\n\nInitially, all the vertices are white.\nSnuke will perform the following operation exactly once:\n\nSelect a vertex v that he likes, and a non-negative integer d. Then, paint all the vertices black whose distances from v are at most d.\n\nFind the number of the possible combinations of colors of the vertices after the operation.\n\nConstraints\n\n2 ≤ N ≤ 2×10^5\n\n1 ≤ a_i, b_i ≤ N\n\nThe given graph is a tree.\n\n|s| = N\n\ns consists of 0 and 1.\n\ns contains at least one occurrence of 1.\n\nPartial Score\n\nIn the test set worth 1300 points, s consists only of 1.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\na_1 b_1\na_2 b_2\n:\na_{N - 1} b_{N - 1}\ns\n\nOutput\n\nPrint the number of the possible combinations of colors of the vertices after the operation.\n\nSample Input 1\n\n4\n1 2\n1 3\n1 4\n1100\n\nSample Output 1\n\n4\n\nThe following four combinations of colors of the vertices are possible:\n\nSample Input 2\n\n5\n1 2\n1 3\n1 4\n4 5\n11111\n\nSample Output 2\n\n11\n\nThis case satisfies the additional constraint for the partial score.\n\nSample Input 3\n\n6\n1 2\n1 3\n1 4\n2 5\n2 6\n100011\n\nSample Output 3\n\n8", "sample_input": "4\n1 2\n1 3\n1 4\n1100\n"}, "reference_outputs": ["4\n"], "source_document_id": "p03843", "source_text": "Score : 1900 points\n\nProblem Statement\n\nThere is a tree with N vertices.\nThe vertices are numbered 1 through N.\nFor each 1 ≤ i ≤ N - 1, the i-th edge connects vertices a_i and b_i.\nThe lengths of all the edges are 1.\n\nSnuke likes some of the vertices.\nThe information on his favorite vertices are given to you as a string s of length N.\nFor each 1 ≤ i ≤ N, s_i is 1 if Snuke likes vertex i, and 0 if he does not like vertex i.\n\nInitially, all the vertices are white.\nSnuke will perform the following operation exactly once:\n\nSelect a vertex v that he likes, and a non-negative integer d. Then, paint all the vertices black whose distances from v are at most d.\n\nFind the number of the possible combinations of colors of the vertices after the operation.\n\nConstraints\n\n2 ≤ N ≤ 2×10^5\n\n1 ≤ a_i, b_i ≤ N\n\nThe given graph is a tree.\n\n|s| = N\n\ns consists of 0 and 1.\n\ns contains at least one occurrence of 1.\n\nPartial Score\n\nIn the test set worth 1300 points, s consists only of 1.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\na_1 b_1\na_2 b_2\n:\na_{N - 1} b_{N - 1}\ns\n\nOutput\n\nPrint the number of the possible combinations of colors of the vertices after the operation.\n\nSample Input 1\n\n4\n1 2\n1 3\n1 4\n1100\n\nSample Output 1\n\n4\n\nThe following four combinations of colors of the vertices are possible:\n\nSample Input 2\n\n5\n1 2\n1 3\n1 4\n4 5\n11111\n\nSample Output 2\n\n11\n\nThis case satisfies the additional constraint for the partial score.\n\nSample Input 3\n\n6\n1 2\n1 3\n1 4\n2 5\n2 6\n100011\n\nSample Output 3\n\n8", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 4690, "cpu_time_ms": 759, "memory_kb": 105708}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s675326431", "group_id": "codeNet:p03844", "input_text": "\n#include<bits/stdc++.h>\n#include <ext/pb_ds/assoc_container.hpp>\n#include <ext/pb_ds/tree_policy.hpp>\n#define F first\n#define S second\n#define pi acos(-1)\nusing ll = long long;\nusing namespace std;\nusing namespace __gnu_pbds;\nusing vl = vector<ll>;\nusing pll =  pair<ll,ll>;\nconst ll mod = 1000000007;\nconst ll infi = 1000000000000000;\nconst ll md = 998244353;\ntypedef tree<int,null_type,less<int>,rb_tree_tag,tree_order_statistics_node_update>ordered_set;\n\nint counter = 0;\n\n\nvoid solve(){\n\tint a,b;\n\tchar ch;\n\tcin>>a>>ch>>b;\n\tif(ch == '-')\n\t\tcout<<a-b;\n\telse\n\t\tcout<< a+b;\n}\n\n\n\nint main()\n{\n  \n    ios_base::sync_with_stdio(false);\n    cin.tie(NULL);\n    cout.tie(NULL);\n  //  int n; cin>>n; for (counter = 0; counter < n; ++counter)\n    solve();\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1585460246, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03844.html", "problem_id": "p03844", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03844/input.txt", "sample_output_relpath": "derived/input_output/data/p03844/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03844/C++/s675326431.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s675326431", "user_id": "u353919145"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "\n#include<bits/stdc++.h>\n#include <ext/pb_ds/assoc_container.hpp>\n#include <ext/pb_ds/tree_policy.hpp>\n#define F first\n#define S second\n#define pi acos(-1)\nusing ll = long long;\nusing namespace std;\nusing namespace __gnu_pbds;\nusing vl = vector<ll>;\nusing pll =  pair<ll,ll>;\nconst ll mod = 1000000007;\nconst ll infi = 1000000000000000;\nconst ll md = 998244353;\ntypedef tree<int,null_type,less<int>,rb_tree_tag,tree_order_statistics_node_update>ordered_set;\n\nint counter = 0;\n\n\nvoid solve(){\n\tint a,b;\n\tchar ch;\n\tcin>>a>>ch>>b;\n\tif(ch == '-')\n\t\tcout<<a-b;\n\telse\n\t\tcout<< a+b;\n}\n\n\n\nint main()\n{\n  \n    ios_base::sync_with_stdio(false);\n    cin.tie(NULL);\n    cout.tie(NULL);\n  //  int n; cin>>n; for (counter = 0; counter < n; ++counter)\n    solve();\n    return 0;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nJoisino wants to evaluate the formula \"A op B\".\nHere, A and B are integers, and the binary operator op is either + or -.\nYour task is to evaluate the formula instead of her.\n\nConstraints\n\n1≦A,B≦10^9\n\nop is either + or -.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nA op B\n\nOutput\n\nEvaluate the formula and print the result.\n\nSample Input 1\n\n1 + 2\n\nSample Output 1\n\n3\n\nSince 1 + 2 = 3, the output should be 3.\n\nSample Input 2\n\n5 - 7\n\nSample Output 2\n\n-2", "sample_input": "1 + 2\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03844", "source_text": "Score : 100 points\n\nProblem Statement\n\nJoisino wants to evaluate the formula \"A op B\".\nHere, A and B are integers, and the binary operator op is either + or -.\nYour task is to evaluate the formula instead of her.\n\nConstraints\n\n1≦A,B≦10^9\n\nop is either + or -.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nA op B\n\nOutput\n\nEvaluate the formula and print the result.\n\nSample Input 1\n\n1 + 2\n\nSample Output 1\n\n3\n\nSince 1 + 2 = 3, the output should be 3.\n\nSample Input 2\n\n5 - 7\n\nSample Output 2\n\n-2", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 766, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s506863400", "group_id": "codeNet:p03844", "input_text": "#include <iostream>\nusing namespace std;\n\nint main () {\n    int a, b;\n    char c;\n    cin >> a >> c >> b;\n    if(c == '+') {\n        cout << a+b << endl;\n    } else if(c == '-') {\n        cout << a-b << endl;\n    }\n}\n", "language": "C++", "metadata": {"date": 1529961416, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03844.html", "problem_id": "p03844", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03844/input.txt", "sample_output_relpath": "derived/input_output/data/p03844/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03844/C++/s506863400.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s506863400", "user_id": "u610408057"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <iostream>\nusing namespace std;\n\nint main () {\n    int a, b;\n    char c;\n    cin >> a >> c >> b;\n    if(c == '+') {\n        cout << a+b << endl;\n    } else if(c == '-') {\n        cout << a-b << endl;\n    }\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nJoisino wants to evaluate the formula \"A op B\".\nHere, A and B are integers, and the binary operator op is either + or -.\nYour task is to evaluate the formula instead of her.\n\nConstraints\n\n1≦A,B≦10^9\n\nop is either + or -.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nA op B\n\nOutput\n\nEvaluate the formula and print the result.\n\nSample Input 1\n\n1 + 2\n\nSample Output 1\n\n3\n\nSince 1 + 2 = 3, the output should be 3.\n\nSample Input 2\n\n5 - 7\n\nSample Output 2\n\n-2", "sample_input": "1 + 2\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03844", "source_text": "Score : 100 points\n\nProblem Statement\n\nJoisino wants to evaluate the formula \"A op B\".\nHere, A and B are integers, and the binary operator op is either + or -.\nYour task is to evaluate the formula instead of her.\n\nConstraints\n\n1≦A,B≦10^9\n\nop is either + or -.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nA op B\n\nOutput\n\nEvaluate the formula and print the result.\n\nSample Input 1\n\n1 + 2\n\nSample Output 1\n\n3\n\nSince 1 + 2 = 3, the output should be 3.\n\nSample Input 2\n\n5 - 7\n\nSample Output 2\n\n-2", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 217, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s326244144", "group_id": "codeNet:p03844", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  long long A,B,ans;\n  char o;\n  cin>>A>>o>>B;\n  if(o=='+'){\n    ans=A+B;\n    cout<<ans<<endl;\n  }\n  else if(o=='-'){\n    ans=A-B;\n    cout<<ans<<endl;\n  }\n  return 0;\n}\n\n", "language": "C++", "metadata": {"date": 1494593947, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03844.html", "problem_id": "p03844", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03844/input.txt", "sample_output_relpath": "derived/input_output/data/p03844/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03844/C++/s326244144.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s326244144", "user_id": "u386294884"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  long long A,B,ans;\n  char o;\n  cin>>A>>o>>B;\n  if(o=='+'){\n    ans=A+B;\n    cout<<ans<<endl;\n  }\n  else if(o=='-'){\n    ans=A-B;\n    cout<<ans<<endl;\n  }\n  return 0;\n}\n\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nJoisino wants to evaluate the formula \"A op B\".\nHere, A and B are integers, and the binary operator op is either + or -.\nYour task is to evaluate the formula instead of her.\n\nConstraints\n\n1≦A,B≦10^9\n\nop is either + or -.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nA op B\n\nOutput\n\nEvaluate the formula and print the result.\n\nSample Input 1\n\n1 + 2\n\nSample Output 1\n\n3\n\nSince 1 + 2 = 3, the output should be 3.\n\nSample Input 2\n\n5 - 7\n\nSample Output 2\n\n-2", "sample_input": "1 + 2\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03844", "source_text": "Score : 100 points\n\nProblem Statement\n\nJoisino wants to evaluate the formula \"A op B\".\nHere, A and B are integers, and the binary operator op is either + or -.\nYour task is to evaluate the formula instead of her.\n\nConstraints\n\n1≦A,B≦10^9\n\nop is either + or -.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nA op B\n\nOutput\n\nEvaluate the formula and print the result.\n\nSample Input 1\n\n1 + 2\n\nSample Output 1\n\n3\n\nSince 1 + 2 = 3, the output should be 3.\n\nSample Input 2\n\n5 - 7\n\nSample Output 2\n\n-2", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 229, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s660104297", "group_id": "codeNet:p03846", "input_text": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <string>\n#include<cstdio>\n#include<cstring>\n#include<queue>\n#include<stack>\n#include<cmath>\nusing namespace std;\ntypedef long long ll;\ntypedef unsigned long long LL;\ntypedef pair<int,int> P;\ntypedef pair<double,double> P_f;\n#define rep(i, n) for (int i = 0; i < (int)n; i++)\n#define reprev(i, n) for (int i = (int)n - 1; i >= 0; i--)\n#define bitrep(bit,n) for(int bit=0; bit<=(1<<n);bit++)\n#define MAX 100100\n#define MAX_N 200100\n#define MAX_T 2001001\n#define SENTINEL 20010010010\n#define NIL -1\nstatic const int INF = 1 << 29;\nconst ll INFTY = 1LL<<50;\nconst int MOD=1e9+7;\nint n;\nint a[MAX];\nint main(){\n    cin>>n;rep(i,n)cin>>a[i];\n    sort(a,a+n);\n    if(n%2==0){int m=n/2;\n    rep(i,m){\n        if(a[2*i]!=a[2*i+1] || a[2*i]!=2*i+1){\n            cout<<0<<endl;return 0;\n        }\n    }\n    LL ans = (m%MOD)*(m%MOD);\n    cout<<ans<<endl;\n    }\n    else {\n        int m=n/2;\n        for(int i=1;i<m;i++){\n            if(a[0]!=0 ||a[2*i-1]!=a[2*i] ||a[2*i]!=2*i){\n                cout<<0<<endl;return 0;\n            }\n        }\n        LL ans=(m%MOD)*(m%MOD);\n        cout<<ans<<endl;\n    }\n    return 0;\n\n}", "language": "C++", "metadata": {"date": 1584220436, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03846.html", "problem_id": "p03846", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03846/input.txt", "sample_output_relpath": "derived/input_output/data/p03846/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03846/C++/s660104297.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s660104297", "user_id": "u000212387"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <string>\n#include<cstdio>\n#include<cstring>\n#include<queue>\n#include<stack>\n#include<cmath>\nusing namespace std;\ntypedef long long ll;\ntypedef unsigned long long LL;\ntypedef pair<int,int> P;\ntypedef pair<double,double> P_f;\n#define rep(i, n) for (int i = 0; i < (int)n; i++)\n#define reprev(i, n) for (int i = (int)n - 1; i >= 0; i--)\n#define bitrep(bit,n) for(int bit=0; bit<=(1<<n);bit++)\n#define MAX 100100\n#define MAX_N 200100\n#define MAX_T 2001001\n#define SENTINEL 20010010010\n#define NIL -1\nstatic const int INF = 1 << 29;\nconst ll INFTY = 1LL<<50;\nconst int MOD=1e9+7;\nint n;\nint a[MAX];\nint main(){\n    cin>>n;rep(i,n)cin>>a[i];\n    sort(a,a+n);\n    if(n%2==0){int m=n/2;\n    rep(i,m){\n        if(a[2*i]!=a[2*i+1] || a[2*i]!=2*i+1){\n            cout<<0<<endl;return 0;\n        }\n    }\n    LL ans = (m%MOD)*(m%MOD);\n    cout<<ans<<endl;\n    }\n    else {\n        int m=n/2;\n        for(int i=1;i<m;i++){\n            if(a[0]!=0 ||a[2*i-1]!=a[2*i] ||a[2*i]!=2*i){\n                cout<<0<<endl;return 0;\n            }\n        }\n        LL ans=(m%MOD)*(m%MOD);\n        cout<<ans<<endl;\n    }\n    return 0;\n\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N people, conveniently numbered 1 through N.\nThey were standing in a row yesterday, but now they are unsure of the order in which they were standing.\nHowever, each person remembered the following fact: the absolute difference of the number of the people who were standing to the left of that person, and the number of the people who were standing to the right of that person.\nAccording to their reports, the difference above for person i is A_i.\n\nBased on these reports, find the number of the possible orders in which they were standing.\nSince it can be extremely large, print the answer modulo 10^9+7.\nNote that the reports may be incorrect and thus there may be no consistent order.\nIn such a case, print 0.\n\nConstraints\n\n1≦N≦10^5\n\n0≦A_i≦N-1\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the number of the possible orders in which they were standing, modulo 10^9+7.\n\nSample Input 1\n\n5\n2 4 4 0 2\n\nSample Output 1\n\n4\n\nThere are four possible orders, as follows:\n\n2,1,4,5,3\n\n2,5,4,1,3\n\n3,1,4,5,2\n\n3,5,4,1,2\n\nSample Input 2\n\n7\n6 4 0 2 4 0 2\n\nSample Output 2\n\n0\n\nAny order would be inconsistent with the reports, thus the answer is 0.\n\nSample Input 3\n\n8\n7 5 1 1 7 3 5 3\n\nSample Output 3\n\n16", "sample_input": "5\n2 4 4 0 2\n"}, "reference_outputs": ["4\n"], "source_document_id": "p03846", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N people, conveniently numbered 1 through N.\nThey were standing in a row yesterday, but now they are unsure of the order in which they were standing.\nHowever, each person remembered the following fact: the absolute difference of the number of the people who were standing to the left of that person, and the number of the people who were standing to the right of that person.\nAccording to their reports, the difference above for person i is A_i.\n\nBased on these reports, find the number of the possible orders in which they were standing.\nSince it can be extremely large, print the answer modulo 10^9+7.\nNote that the reports may be incorrect and thus there may be no consistent order.\nIn such a case, print 0.\n\nConstraints\n\n1≦N≦10^5\n\n0≦A_i≦N-1\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the number of the possible orders in which they were standing, modulo 10^9+7.\n\nSample Input 1\n\n5\n2 4 4 0 2\n\nSample Output 1\n\n4\n\nThere are four possible orders, as follows:\n\n2,1,4,5,3\n\n2,5,4,1,3\n\n3,1,4,5,2\n\n3,5,4,1,2\n\nSample Input 2\n\n7\n6 4 0 2 4 0 2\n\nSample Output 2\n\n0\n\nAny order would be inconsistent with the reports, thus the answer is 0.\n\nSample Input 3\n\n8\n7 5 1 1 7 3 5 3\n\nSample Output 3\n\n16", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1178, "cpu_time_ms": 42, "memory_kb": 640}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s985872040", "group_id": "codeNet:p03846", "input_text": "#include <bits/stdc++.h>\ntypedef unsigned long long ull;\ntypedef long long ll;\n#define __TRUE \"YES\"\n#define __FALSE \"NO\"\n#define MAX 100001\nusing namespace std;\n\nint main() {\n  ll N,ans=0;\n  cin >> N;\n  vector<ll> a(N),odd(N/2+1,0);\n  for(int i=0;i<N;i++) {\n    cin >> a[i];\n  }\n  sort(a.begin(),a.end());\n  ll num=0;\n  for(int i=0;i<N-1;i++) {\n    if(N%2!=0) i++;\n    if(a[i]==a[i+1]) num++;\n  }\n  if(N/2==num) {\n    ans=pow(2,N/2);\n  }else{\n    ans=0;\n  }\n  cout << ans << endl;\n}", "language": "C++", "metadata": {"date": 1548467467, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03846.html", "problem_id": "p03846", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03846/input.txt", "sample_output_relpath": "derived/input_output/data/p03846/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03846/C++/s985872040.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s985872040", "user_id": "u003019316"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <bits/stdc++.h>\ntypedef unsigned long long ull;\ntypedef long long ll;\n#define __TRUE \"YES\"\n#define __FALSE \"NO\"\n#define MAX 100001\nusing namespace std;\n\nint main() {\n  ll N,ans=0;\n  cin >> N;\n  vector<ll> a(N),odd(N/2+1,0);\n  for(int i=0;i<N;i++) {\n    cin >> a[i];\n  }\n  sort(a.begin(),a.end());\n  ll num=0;\n  for(int i=0;i<N-1;i++) {\n    if(N%2!=0) i++;\n    if(a[i]==a[i+1]) num++;\n  }\n  if(N/2==num) {\n    ans=pow(2,N/2);\n  }else{\n    ans=0;\n  }\n  cout << ans << endl;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N people, conveniently numbered 1 through N.\nThey were standing in a row yesterday, but now they are unsure of the order in which they were standing.\nHowever, each person remembered the following fact: the absolute difference of the number of the people who were standing to the left of that person, and the number of the people who were standing to the right of that person.\nAccording to their reports, the difference above for person i is A_i.\n\nBased on these reports, find the number of the possible orders in which they were standing.\nSince it can be extremely large, print the answer modulo 10^9+7.\nNote that the reports may be incorrect and thus there may be no consistent order.\nIn such a case, print 0.\n\nConstraints\n\n1≦N≦10^5\n\n0≦A_i≦N-1\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the number of the possible orders in which they were standing, modulo 10^9+7.\n\nSample Input 1\n\n5\n2 4 4 0 2\n\nSample Output 1\n\n4\n\nThere are four possible orders, as follows:\n\n2,1,4,5,3\n\n2,5,4,1,3\n\n3,1,4,5,2\n\n3,5,4,1,2\n\nSample Input 2\n\n7\n6 4 0 2 4 0 2\n\nSample Output 2\n\n0\n\nAny order would be inconsistent with the reports, thus the answer is 0.\n\nSample Input 3\n\n8\n7 5 1 1 7 3 5 3\n\nSample Output 3\n\n16", "sample_input": "5\n2 4 4 0 2\n"}, "reference_outputs": ["4\n"], "source_document_id": "p03846", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N people, conveniently numbered 1 through N.\nThey were standing in a row yesterday, but now they are unsure of the order in which they were standing.\nHowever, each person remembered the following fact: the absolute difference of the number of the people who were standing to the left of that person, and the number of the people who were standing to the right of that person.\nAccording to their reports, the difference above for person i is A_i.\n\nBased on these reports, find the number of the possible orders in which they were standing.\nSince it can be extremely large, print the answer modulo 10^9+7.\nNote that the reports may be incorrect and thus there may be no consistent order.\nIn such a case, print 0.\n\nConstraints\n\n1≦N≦10^5\n\n0≦A_i≦N-1\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the number of the possible orders in which they were standing, modulo 10^9+7.\n\nSample Input 1\n\n5\n2 4 4 0 2\n\nSample Output 1\n\n4\n\nThere are four possible orders, as follows:\n\n2,1,4,5,3\n\n2,5,4,1,3\n\n3,1,4,5,2\n\n3,5,4,1,2\n\nSample Input 2\n\n7\n6 4 0 2 4 0 2\n\nSample Output 2\n\n0\n\nAny order would be inconsistent with the reports, thus the answer is 0.\n\nSample Input 3\n\n8\n7 5 1 1 7 3 5 3\n\nSample Output 3\n\n16", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 482, "cpu_time_ms": 35, "memory_kb": 1408}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s253712455", "group_id": "codeNet:p03848", "input_text": "#include<iostream>\n#include<iomanip>\n#include<math.h>\n#include<vector>\n#include<algorithm>\n#include<set>\n#include<map>\n#include<queue>\n#include<stack>\n#include<string>\n#include<time.h>\n#define INF 1000000000ll\n#define MOD 1000000007ll\n#define EPS 1e-10\n#define REP(i,m) for(long long i=0; i<m; ++i)\n#define FOR(i,n,m) for(long long i=n; i<m; ++i)\n#define DUMP(n,a) for(long long dump=0; dump<n; ++dump) { cout<<a[dump]; if(dump!=n-1) cout<<\" \"; else cout<<endl; }\n#define ALL(v) v.begin(),v.end()\n#define pb push_back\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll, ll> P;\ntypedef long double ld;\n\nint main() {\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tll n;\n\tcin>>n;\n\tvector<ll> b(n,0);\n\tREP(i,n) {\n\t\tll a;\n\t\tcin>>a;\n\t\tb[a]++;\n\t}\n\tfor(ll i=n-1; i>=0; i-=2) {\n\t\tif(i==0) {\n\t\t\tif(b[i]!=1) {\n\t\t\t\tcout<<0<<endl;\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t\telse if(b[i]!=2) {\n\t\t\tcout<<0<<endl;\n\t\t\treturn 0;\n\t\t}\n\t}\n\tll ret=1;\n\tREP(i,n/2) {\n\t\tret*=2;\n\t\tret%=MOD;\n\t}\n\tcout<<ret<<endl;\n}\n", "language": "C++", "metadata": {"date": 1508719865, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03848.html", "problem_id": "p03848", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03848/input.txt", "sample_output_relpath": "derived/input_output/data/p03848/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03848/C++/s253712455.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s253712455", "user_id": "u607034173"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include<iostream>\n#include<iomanip>\n#include<math.h>\n#include<vector>\n#include<algorithm>\n#include<set>\n#include<map>\n#include<queue>\n#include<stack>\n#include<string>\n#include<time.h>\n#define INF 1000000000ll\n#define MOD 1000000007ll\n#define EPS 1e-10\n#define REP(i,m) for(long long i=0; i<m; ++i)\n#define FOR(i,n,m) for(long long i=n; i<m; ++i)\n#define DUMP(n,a) for(long long dump=0; dump<n; ++dump) { cout<<a[dump]; if(dump!=n-1) cout<<\" \"; else cout<<endl; }\n#define ALL(v) v.begin(),v.end()\n#define pb push_back\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll, ll> P;\ntypedef long double ld;\n\nint main() {\n\tcin.tie(0);\n\tios::sync_with_stdio(false);\n\tll n;\n\tcin>>n;\n\tvector<ll> b(n,0);\n\tREP(i,n) {\n\t\tll a;\n\t\tcin>>a;\n\t\tb[a]++;\n\t}\n\tfor(ll i=n-1; i>=0; i-=2) {\n\t\tif(i==0) {\n\t\t\tif(b[i]!=1) {\n\t\t\t\tcout<<0<<endl;\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t\telse if(b[i]!=2) {\n\t\t\tcout<<0<<endl;\n\t\t\treturn 0;\n\t\t}\n\t}\n\tll ret=1;\n\tREP(i,n/2) {\n\t\tret*=2;\n\t\tret%=MOD;\n\t}\n\tcout<<ret<<endl;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThere are N people, conveniently numbered 1 through N.\nThey were standing in a row yesterday, but now they are unsure of the order in which they were standing.\nHowever, each person remembered the following fact: the absolute difference of the number of the people who were standing to the left of that person, and the number of the people who were standing to the right of that person.\nAccording to their reports, the difference above for person i is A_i.\n\nBased on these reports, find the number of the possible orders in which they were standing.\nSince it can be extremely large, print the answer modulo 10^9+7.\nNote that the reports may be incorrect and thus there may be no consistent order.\nIn such a case, print 0.\n\nConstraints\n\n1≦N≦10^5\n\n0≦A_i≦N-1\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the number of the possible orders in which they were standing, modulo 10^9+7.\n\nSample Input 1\n\n5\n2 4 4 0 2\n\nSample Output 1\n\n4\n\nThere are four possible orders, as follows:\n\n2,1,4,5,3\n\n2,5,4,1,3\n\n3,1,4,5,2\n\n3,5,4,1,2\n\nSample Input 2\n\n7\n6 4 0 2 4 0 2\n\nSample Output 2\n\n0\n\nAny order would be inconsistent with the reports, thus the answer is 0.\n\nSample Input 3\n\n8\n7 5 1 1 7 3 5 3\n\nSample Output 3\n\n16", "sample_input": "5\n2 4 4 0 2\n"}, "reference_outputs": ["4\n"], "source_document_id": "p03848", "source_text": "Score : 300 points\n\nProblem Statement\n\nThere are N people, conveniently numbered 1 through N.\nThey were standing in a row yesterday, but now they are unsure of the order in which they were standing.\nHowever, each person remembered the following fact: the absolute difference of the number of the people who were standing to the left of that person, and the number of the people who were standing to the right of that person.\nAccording to their reports, the difference above for person i is A_i.\n\nBased on these reports, find the number of the possible orders in which they were standing.\nSince it can be extremely large, print the answer modulo 10^9+7.\nNote that the reports may be incorrect and thus there may be no consistent order.\nIn such a case, print 0.\n\nConstraints\n\n1≦N≦10^5\n\n0≦A_i≦N-1\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the number of the possible orders in which they were standing, modulo 10^9+7.\n\nSample Input 1\n\n5\n2 4 4 0 2\n\nSample Output 1\n\n4\n\nThere are four possible orders, as follows:\n\n2,1,4,5,3\n\n2,5,4,1,3\n\n3,1,4,5,2\n\n3,5,4,1,2\n\nSample Input 2\n\n7\n6 4 0 2 4 0 2\n\nSample Output 2\n\n0\n\nAny order would be inconsistent with the reports, thus the answer is 0.\n\nSample Input 3\n\n8\n7 5 1 1 7 3 5 3\n\nSample Output 3\n\n16", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 975, "cpu_time_ms": 9, "memory_kb": 1024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s028239552", "group_id": "codeNet:p03851", "input_text": "#include\"bits/stdc++.h\"\n\n\n#define PB push_back\n#define PF push_front\n#define LB lower_bound\n#define UB upper_bound\n#define fr(x) freopen(x,\"r\",stdin)\n#define fw(x) freopen(x,\"w\",stdout)\n#define iout(x) printf(\"%d\\n\",x)\n#define lout(x) printf(\"%lld\\n\",x)\n#define REP(x,l,u) for(int x = (l);x<=(u);x++)\n#define RREP(x,l,u) for(int x = (l);x>=(u);x--)\n#define mst(x,a) memset(x,a,sizeof(x))\n#define PII pair<int,int>\n#define PLL pair<ll,ll>\n#define MP make_pair\n#define se second\n#define fi first\n#define dbg(x) cout<<#x<<\" = \"<<(x)<<endl;\n#define sz(x) ((int)x.size())\n#define cl(x) x.clear()\n\ntypedef  long long ll;\ntypedef unsigned long long ull;\ntypedef double db;\ntypedef long double ld;\nusing namespace std;\n\nconst int maxn = 300010;\nconst int mod = 1e9+7;\nconst int MAX = 1000000010;\nconst double eps = 1e-6;\nconst double PI = acos(-1);\n\ntemplate<typename T> inline void read(T &x){\nx=0;T f=1;char ch;do{ch=getchar();if(ch=='-')f=-1;}while(ch<'0'||ch>'9');do x=x*10+ch-'0',ch=getchar();while(ch<='9'&&ch>='0');x*=f;\n}\n\ntemplate<typename A,typename B> inline void read(A&x,B&y){read(x);read(y);}\ntemplate<typename A,typename B,typename C> inline void read(A&x,B&y,C&z){read(x);read(y);read(z);}\ntemplate<typename A,typename B,typename C,typename D> inline void read(A&x,B&y,C&z,D&w){read(x);read(y);read(z);read(w);}\ntemplate<typename A,typename B> inline A fexp(A x,B p){A ans=1;for(;p;p>>=1,x=1LL*x*x%mod)if(p&1)ans=1LL*ans*x%mod;return ans;}\ntemplate<typename A,typename B> inline A fexp(A x,B p,A mo){A ans=1;for(;p;p>>=1,x=1LL*x*x%mo)if(p&1)ans=1LL*ans*x%mo;return ans;}\n\nint n,q;\n\nint t[maxn];\n\nint Q[maxn],top;\n\nll sm[maxn],f[maxn],y[maxn],pre[maxn],suf[maxn],tmp[maxn],Ans[maxn];\n\nvoid DP(){\n\tREP(i,1,n)sm[i]=sm[i-1]+t[i];\n\tQ[top=1]=0;\n\tREP(i,1,n){\n\t\tf[i]=f[i-1];\n\t\twhile(top>1&&(y[Q[top]]-y[Q[top-1]])<=2ll*i*(Q[top]-Q[top-1]))top--;\n\t\tf[i]=max(f[i],f[Q[top]]+1ll*(i-Q[top])*(i-Q[top]+1)/2+sm[Q[top]]-sm[i]);\n\t\ty[i]=f[i]*2+1ll*i*i-i+sm[i]*2;\n\t\twhile(top>1&&(y[Q[top]]-y[Q[top-1]])*(i-Q[top])<=(y[i]-y[Q[top]])*(Q[top]-Q[top-1]))top--;\n\t\tQ[++top]=i;\n\t}\n}\n\nvoid solve(int l,int r){\n//\tcout<<l<<' '<<r<<endl;\n\tif(l==r){\n\t\tAns[l]=max(Ans[l],pre[l-1]+suf[l+1]+1-t[l]);\n\t\treturn;\n\t}\n\tint M=l+r>>1;\n\ttop=0;\n\tREP(i,l-1,M-1){\n\t\ty[i]=pre[i]*2+1ll*i*i-i+sm[i]*2;\n\t\twhile(top>1&&(y[Q[top]]-y[Q[top-1]])*(i-Q[top])<=(y[i]-y[Q[top]])*(Q[top]-Q[top-1]))top--;\n\t\tQ[++top]=i;\n\t}\n\tREP(i,M,r){\n\t\twhile(top>1&&(y[Q[top]]-y[Q[top-1]])<=2ll*i*(Q[top]-Q[top-1]))top--;\n\t\ttmp[i]=pre[Q[top]]+suf[i+1]+1ll*(i-Q[top])*(i-Q[top]+1)/2+sm[Q[top]]-sm[i];\n\t}\n\tRREP(i,r-1,M)tmp[i]=max(tmp[i],tmp[i+1]);\n//\tREP(i,M+1,r)cout<<tmp[i]<<' ';cout<<endl;\n\tREP(i,M,r)Ans[i]=max(Ans[i],tmp[i]);\n\tsolve(l,M);solve(M+1,r);\n\t\n}\n\nvoid Work(){\n\tread(q);\n\twhile(q--){\n\t\tint p,x;read(p,x);\n\t\tll ans=max(pre[p-1]+suf[p+1],Ans[p]-x+t[p]);\n\t\tprintf(\"%lld\\n\",ans);\n\t}\n}\n\nvoid Init(){\n\tread(n);\n\tREP(i,1,n)read(t[i]);\n\tDP();REP(i,1,n)pre[i]=f[i];\n\treverse(t+1,t+n+1);\n\tDP();REP(i,1,n)suf[i]=f[i];\n\treverse(t+1,t+n+1);reverse(suf+1,suf+n+1);\n\t\n//\tREP(i,1,n)cout<<pre[i]<<' ';cout<<endl;\n//\tREP(i,1,n)cout<<suf[i]<<' ';cout<<endl;\n\t\n\tREP(i,1,n)Ans[i]=-t[i],sm[i]=sm[i-1]+t[i];\t\n\tsolve(1,n);\n\treverse(t+1,t+n+1);REP(i,1,n)sm[i]=sm[i-1]+t[i];\n\treverse(pre+1,pre+n+1);reverse(suf+1,suf+n+1);reverse(Ans+1,Ans+n+1);REP(i,1,n)swap(pre[i],suf[i]);\n\tsolve(1,n);\n\treverse(t+1,t+n+1);REP(i,1,n)sm[i]=sm[i-1]+t[i];\n\treverse(pre+1,pre+n+1);reverse(suf+1,suf+n+1);reverse(Ans+1,Ans+n+1);REP(i,1,n)swap(pre[i],suf[i]);\n}\n\nint main(){\n\tInit();\n\tWork();\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1513226705, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03851.html", "problem_id": "p03851", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03851/input.txt", "sample_output_relpath": "derived/input_output/data/p03851/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03851/C++/s028239552.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s028239552", "user_id": "u824191773"}, "prompt_components": {"gold_output": "9\n2\n", "input_to_evaluate": "#include\"bits/stdc++.h\"\n\n\n#define PB push_back\n#define PF push_front\n#define LB lower_bound\n#define UB upper_bound\n#define fr(x) freopen(x,\"r\",stdin)\n#define fw(x) freopen(x,\"w\",stdout)\n#define iout(x) printf(\"%d\\n\",x)\n#define lout(x) printf(\"%lld\\n\",x)\n#define REP(x,l,u) for(int x = (l);x<=(u);x++)\n#define RREP(x,l,u) for(int x = (l);x>=(u);x--)\n#define mst(x,a) memset(x,a,sizeof(x))\n#define PII pair<int,int>\n#define PLL pair<ll,ll>\n#define MP make_pair\n#define se second\n#define fi first\n#define dbg(x) cout<<#x<<\" = \"<<(x)<<endl;\n#define sz(x) ((int)x.size())\n#define cl(x) x.clear()\n\ntypedef  long long ll;\ntypedef unsigned long long ull;\ntypedef double db;\ntypedef long double ld;\nusing namespace std;\n\nconst int maxn = 300010;\nconst int mod = 1e9+7;\nconst int MAX = 1000000010;\nconst double eps = 1e-6;\nconst double PI = acos(-1);\n\ntemplate<typename T> inline void read(T &x){\nx=0;T f=1;char ch;do{ch=getchar();if(ch=='-')f=-1;}while(ch<'0'||ch>'9');do x=x*10+ch-'0',ch=getchar();while(ch<='9'&&ch>='0');x*=f;\n}\n\ntemplate<typename A,typename B> inline void read(A&x,B&y){read(x);read(y);}\ntemplate<typename A,typename B,typename C> inline void read(A&x,B&y,C&z){read(x);read(y);read(z);}\ntemplate<typename A,typename B,typename C,typename D> inline void read(A&x,B&y,C&z,D&w){read(x);read(y);read(z);read(w);}\ntemplate<typename A,typename B> inline A fexp(A x,B p){A ans=1;for(;p;p>>=1,x=1LL*x*x%mod)if(p&1)ans=1LL*ans*x%mod;return ans;}\ntemplate<typename A,typename B> inline A fexp(A x,B p,A mo){A ans=1;for(;p;p>>=1,x=1LL*x*x%mo)if(p&1)ans=1LL*ans*x%mo;return ans;}\n\nint n,q;\n\nint t[maxn];\n\nint Q[maxn],top;\n\nll sm[maxn],f[maxn],y[maxn],pre[maxn],suf[maxn],tmp[maxn],Ans[maxn];\n\nvoid DP(){\n\tREP(i,1,n)sm[i]=sm[i-1]+t[i];\n\tQ[top=1]=0;\n\tREP(i,1,n){\n\t\tf[i]=f[i-1];\n\t\twhile(top>1&&(y[Q[top]]-y[Q[top-1]])<=2ll*i*(Q[top]-Q[top-1]))top--;\n\t\tf[i]=max(f[i],f[Q[top]]+1ll*(i-Q[top])*(i-Q[top]+1)/2+sm[Q[top]]-sm[i]);\n\t\ty[i]=f[i]*2+1ll*i*i-i+sm[i]*2;\n\t\twhile(top>1&&(y[Q[top]]-y[Q[top-1]])*(i-Q[top])<=(y[i]-y[Q[top]])*(Q[top]-Q[top-1]))top--;\n\t\tQ[++top]=i;\n\t}\n}\n\nvoid solve(int l,int r){\n//\tcout<<l<<' '<<r<<endl;\n\tif(l==r){\n\t\tAns[l]=max(Ans[l],pre[l-1]+suf[l+1]+1-t[l]);\n\t\treturn;\n\t}\n\tint M=l+r>>1;\n\ttop=0;\n\tREP(i,l-1,M-1){\n\t\ty[i]=pre[i]*2+1ll*i*i-i+sm[i]*2;\n\t\twhile(top>1&&(y[Q[top]]-y[Q[top-1]])*(i-Q[top])<=(y[i]-y[Q[top]])*(Q[top]-Q[top-1]))top--;\n\t\tQ[++top]=i;\n\t}\n\tREP(i,M,r){\n\t\twhile(top>1&&(y[Q[top]]-y[Q[top-1]])<=2ll*i*(Q[top]-Q[top-1]))top--;\n\t\ttmp[i]=pre[Q[top]]+suf[i+1]+1ll*(i-Q[top])*(i-Q[top]+1)/2+sm[Q[top]]-sm[i];\n\t}\n\tRREP(i,r-1,M)tmp[i]=max(tmp[i],tmp[i+1]);\n//\tREP(i,M+1,r)cout<<tmp[i]<<' ';cout<<endl;\n\tREP(i,M,r)Ans[i]=max(Ans[i],tmp[i]);\n\tsolve(l,M);solve(M+1,r);\n\t\n}\n\nvoid Work(){\n\tread(q);\n\twhile(q--){\n\t\tint p,x;read(p,x);\n\t\tll ans=max(pre[p-1]+suf[p+1],Ans[p]-x+t[p]);\n\t\tprintf(\"%lld\\n\",ans);\n\t}\n}\n\nvoid Init(){\n\tread(n);\n\tREP(i,1,n)read(t[i]);\n\tDP();REP(i,1,n)pre[i]=f[i];\n\treverse(t+1,t+n+1);\n\tDP();REP(i,1,n)suf[i]=f[i];\n\treverse(t+1,t+n+1);reverse(suf+1,suf+n+1);\n\t\n//\tREP(i,1,n)cout<<pre[i]<<' ';cout<<endl;\n//\tREP(i,1,n)cout<<suf[i]<<' ';cout<<endl;\n\t\n\tREP(i,1,n)Ans[i]=-t[i],sm[i]=sm[i-1]+t[i];\t\n\tsolve(1,n);\n\treverse(t+1,t+n+1);REP(i,1,n)sm[i]=sm[i-1]+t[i];\n\treverse(pre+1,pre+n+1);reverse(suf+1,suf+n+1);reverse(Ans+1,Ans+n+1);REP(i,1,n)swap(pre[i],suf[i]);\n\tsolve(1,n);\n\treverse(t+1,t+n+1);REP(i,1,n)sm[i]=sm[i-1]+t[i];\n\treverse(pre+1,pre+n+1);reverse(suf+1,suf+n+1);reverse(Ans+1,Ans+n+1);REP(i,1,n)swap(pre[i],suf[i]);\n}\n\nint main(){\n\tInit();\n\tWork();\n\treturn 0;\n}\n", "problem_context": "Score : 1400 points\n\nProblem Statement\n\nJoisino is about to compete in the final round of a certain programming competition.\nIn this contest, there are N problems, numbered 1 through N.\nJoisino knows that it takes her T_i seconds to solve problem i(1≦i≦N).\n\nIn this contest, a contestant will first select some number of problems to solve.\nThen, the contestant will solve the selected problems.\nAfter that, the score of the contestant will be calculated as follows:\n\n(The score) = (The number of the pairs of integers L and R (1≦L≦R≦N) such that for every i satisfying L≦i≦R, problem i is solved) - (The total number of seconds it takes for the contestant to solve the selected problems)\n\nNote that a contestant is allowed to choose to solve zero problems, in which case the score will be 0.\n\nAlso, there are M kinds of drinks offered to the contestants, numbered 1 through M.\nIf Joisino takes drink i(1≦i≦M), her brain will be stimulated and the time it takes for her to solve problem P_i will become X_i seconds.\nHere, X_i may be greater than the length of time originally required to solve problem P_i.\nTaking drink i does not affect the time required to solve the other problems.\n\nA contestant is allowed to take exactly one of the drinks before the start of the contest.\nFor each drink, Joisino wants to know the maximum score that can be obtained in the contest if she takes that drink.\nYour task is to write a program to calculate it instead of her.\n\nConstraints\n\nAll input values are integers.\n\n1≦N≦3*10^5\n\n1≦T_i≦10^9\n\n(The sum of T_i) ≦10^{12}\n\n1≦M≦3*10^5\n\n1≦P_i≦N\n\n1≦X_i≦10^9\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nT_1 T_2 ... T_N\nM\nP_1 X_1\nP_2 X_2\n:\nP_M X_M\n\nOutput\n\nFor each drink, print the maximum score that can be obtained if Joisino takes that drink, in order, one per line.\n\nSample Input 1\n\n5\n1 1 4 1 1\n2\n3 2\n3 10\n\nSample Output 1\n\n9\n2\n\nIf she takes drink 1, the maximum score can be obtained by solving all the problems.\n\nIf she takes drink 2, the maximum score can be obtained by solving the problems 1,2,4 and 5.\n\nSample Input 2\n\n12\n1 2 1 3 4 1 2 1 12 3 12 12\n10\n9 3\n11 1\n5 35\n6 15\n12 1\n1 9\n4 3\n10 2\n5 1\n7 6\n\nSample Output 2\n\n34\n35\n5\n11\n35\n17\n25\n26\n28\n21", "sample_input": "5\n1 1 4 1 1\n2\n3 2\n3 10\n"}, "reference_outputs": ["9\n2\n"], "source_document_id": "p03851", "source_text": "Score : 1400 points\n\nProblem Statement\n\nJoisino is about to compete in the final round of a certain programming competition.\nIn this contest, there are N problems, numbered 1 through N.\nJoisino knows that it takes her T_i seconds to solve problem i(1≦i≦N).\n\nIn this contest, a contestant will first select some number of problems to solve.\nThen, the contestant will solve the selected problems.\nAfter that, the score of the contestant will be calculated as follows:\n\n(The score) = (The number of the pairs of integers L and R (1≦L≦R≦N) such that for every i satisfying L≦i≦R, problem i is solved) - (The total number of seconds it takes for the contestant to solve the selected problems)\n\nNote that a contestant is allowed to choose to solve zero problems, in which case the score will be 0.\n\nAlso, there are M kinds of drinks offered to the contestants, numbered 1 through M.\nIf Joisino takes drink i(1≦i≦M), her brain will be stimulated and the time it takes for her to solve problem P_i will become X_i seconds.\nHere, X_i may be greater than the length of time originally required to solve problem P_i.\nTaking drink i does not affect the time required to solve the other problems.\n\nA contestant is allowed to take exactly one of the drinks before the start of the contest.\nFor each drink, Joisino wants to know the maximum score that can be obtained in the contest if she takes that drink.\nYour task is to write a program to calculate it instead of her.\n\nConstraints\n\nAll input values are integers.\n\n1≦N≦3*10^5\n\n1≦T_i≦10^9\n\n(The sum of T_i) ≦10^{12}\n\n1≦M≦3*10^5\n\n1≦P_i≦N\n\n1≦X_i≦10^9\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nT_1 T_2 ... T_N\nM\nP_1 X_1\nP_2 X_2\n:\nP_M X_M\n\nOutput\n\nFor each drink, print the maximum score that can be obtained if Joisino takes that drink, in order, one per line.\n\nSample Input 1\n\n5\n1 1 4 1 1\n2\n3 2\n3 10\n\nSample Output 1\n\n9\n2\n\nIf she takes drink 1, the maximum score can be obtained by solving all the problems.\n\nIf she takes drink 2, the maximum score can be obtained by solving the problems 1,2,4 and 5.\n\nSample Input 2\n\n12\n1 2 1 3 4 1 2 1 12 3 12 12\n10\n9 3\n11 1\n5 35\n6 15\n12 1\n1 9\n4 3\n10 2\n5 1\n7 6\n\nSample Output 2\n\n34\n35\n5\n11\n35\n17\n25\n26\n28\n21", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 3508, "cpu_time_ms": 261, "memory_kb": 21376}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s024020224", "group_id": "codeNet:p03852", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nnamespace FAST_IO\n{\n\ttemplate<typename T> void read(T &a)\n\t{\n\t\ta=0;\n\t\tint f=1;\n\t\tchar c=getchar();\n\t\twhile(!isdigit(c))\n\t\t{\n\t\t\tif(c=='-')\n\t\t\t{\n\t\t\t\tf=-1;\n\t\t\t}\n\t\t\tc=getchar();\n\t\t}\n\t\twhile(isdigit(c))\n\t\t{\n\t\t\ta=a*10+c-'0';\n\t\t\tc=getchar();\n\t\t}\n\t\ta=a*f;\n\t}\n\ttemplate <typename T> void write(T a)\n\t{\n\t\tif(a<0)\n\t\t{\n\t\t\ta=-a;\n\t\t\tputchar('-');\n\t\t}\n\t\tif(a>9)\n\t\t{\n\t\t\twrite(a/10);\n\t\t}\n\t\tputchar(a%10+'0');\n\t}\n\ttemplate <typename T> void writeln(T a)\n\t{\n\t\twrite(a);\n\t\tputs(\"\");\n\t}\n}\nint main()\n{\n\tchar a;\n\tcin>>a;\n\tif(a=='a'||a=='e'||a=='i'||a=='o'||a=='u')\n\t{\n\t\tcout<<\"vowel\";\n\t}\n\telse\n\t{\n\t\tcout<<\"consonant\";\n\t}\n}\n", "language": "C++", "metadata": {"date": 1586138517, "filename_ext": "cpp", "original_language": "C++ (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03852.html", "problem_id": "p03852", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03852/input.txt", "sample_output_relpath": "derived/input_output/data/p03852/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03852/C++/s024020224.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s024020224", "user_id": "u207310767"}, "prompt_components": {"gold_output": "vowel\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nnamespace FAST_IO\n{\n\ttemplate<typename T> void read(T &a)\n\t{\n\t\ta=0;\n\t\tint f=1;\n\t\tchar c=getchar();\n\t\twhile(!isdigit(c))\n\t\t{\n\t\t\tif(c=='-')\n\t\t\t{\n\t\t\t\tf=-1;\n\t\t\t}\n\t\t\tc=getchar();\n\t\t}\n\t\twhile(isdigit(c))\n\t\t{\n\t\t\ta=a*10+c-'0';\n\t\t\tc=getchar();\n\t\t}\n\t\ta=a*f;\n\t}\n\ttemplate <typename T> void write(T a)\n\t{\n\t\tif(a<0)\n\t\t{\n\t\t\ta=-a;\n\t\t\tputchar('-');\n\t\t}\n\t\tif(a>9)\n\t\t{\n\t\t\twrite(a/10);\n\t\t}\n\t\tputchar(a%10+'0');\n\t}\n\ttemplate <typename T> void writeln(T a)\n\t{\n\t\twrite(a);\n\t\tputs(\"\");\n\t}\n}\nint main()\n{\n\tchar a;\n\tcin>>a;\n\tif(a=='a'||a=='e'||a=='i'||a=='o'||a=='u')\n\t{\n\t\tcout<<\"vowel\";\n\t}\n\telse\n\t{\n\t\tcout<<\"consonant\";\n\t}\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nGiven a lowercase English letter c, determine whether it is a vowel. Here, there are five vowels in the English alphabet: a, e, i, o and u.\n\nConstraints\n\nc is a lowercase English letter.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nc\n\nOutput\n\nIf c is a vowel, print vowel. Otherwise, print consonant.\n\nSample Input 1\n\na\n\nSample Output 1\n\nvowel\n\nSince a is a vowel, print vowel.\n\nSample Input 2\n\nz\n\nSample Output 2\n\nconsonant\n\nSample Input 3\n\ns\n\nSample Output 3\n\nconsonant", "sample_input": "a\n"}, "reference_outputs": ["vowel\n"], "source_document_id": "p03852", "source_text": "Score : 100 points\n\nProblem Statement\n\nGiven a lowercase English letter c, determine whether it is a vowel. Here, there are five vowels in the English alphabet: a, e, i, o and u.\n\nConstraints\n\nc is a lowercase English letter.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nc\n\nOutput\n\nIf c is a vowel, print vowel. Otherwise, print consonant.\n\nSample Input 1\n\na\n\nSample Output 1\n\nvowel\n\nSince a is a vowel, print vowel.\n\nSample Input 2\n\nz\n\nSample Output 2\n\nconsonant\n\nSample Input 3\n\ns\n\nSample Output 3\n\nconsonant", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 646, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s160450735", "group_id": "codeNet:p03855", "input_text": "#pragma GCC optimize (\"O3\")\n\n#include <iostream>\n#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#include <math.h>\n#include <queue>\nusing namespace std;\n\nusing QWORD = unsigned long long;\nusing SQWORD = long long;\nusing DWORD = unsigned int;\nusing SDWORD = int;\nusing WORD = unsigned short;\nusing SWORD = short;\nusing BYTE = unsigned char;\nusing SBYTE = char;\nusing DOUBLE = double;\nusing FLOAT = float;\n\n#define MIN_SDWORD (-2147483648)\n#define MAX_SDWORD (2147483647)\n#define MIN_SBYTE (-128)\n#define MAX_SBYTE (127)\n\n#define MAX_QWORD (0xFFFFFFFFFFFFFFFF)\n#define MAX_DWORD (0xFFFFFFFF)\n#define MAX_WORD  (0xFFFF)\n#define MAX_BYTE  (0xFF)\n\n\n#define ArrayLength(a)  (sizeof(a) / sizeof(a[0]))\n\nstatic inline QWORD MAX(QWORD a, QWORD b) { return a > b ? a : b; }\nstatic inline DWORD MAX(DWORD a, DWORD b) { return a > b ? a : b; }\nstatic inline SDWORD MAX(SDWORD a, SDWORD b) { return a > b ? a : b; }\nstatic inline QWORD MIN(QWORD a, QWORD b) { return a < b ? a : b; }\nstatic inline DWORD MIN(DWORD a, DWORD b) { return a < b ? a : b; }\nstatic inline SDWORD MIN(SDWORD a, SDWORD b) { return a < b ? a : b; }\n\n#define BYTE_BITS   (8)\n#define WORD_BITS   (16)\n#define DWORD_BITS  (32)\n#define QWORD_BITS  (64)\n\nusing M_BOOL = bool;\n#define M_TRUE (true)\n#define M_FALSE (false)\n#define DIVISOR (1000000007)\n\nstatic inline void inputString(char *pcStr)\n{\n    char *pcCur = pcStr;\n    for (;;) {\n        char c = getchar();\n        if (('\\n' == c) || (EOF == c)) {\n            break;\n        }\n        *pcCur = c;\n        pcCur++;\n    }\n    *pcCur = '\\0';\n}\n\nstatic inline SDWORD inputSDWORD(void)\n{\n    SDWORD lNumber = 0;\n    M_BOOL bRead = M_FALSE;\n    for (;;) {\n        char c = getchar();\n        if (('0' <= c) && (c <= '9')) {\n            lNumber *= 10;\n            lNumber += (c - '0');\n            bRead = M_TRUE;\n        } else {\n            if (bRead) {\n                return lNumber;\n            }\n        }\n    }\n}\n\ntypedef struct {\n    DWORD   *pdwPar;\n    DWORD   *pdwRank;\n    DWORD   *pdwCnt;\n    DWORD   dwSize;\n} ST_UNION_FIND;\n\nstatic void initUnionFind(\n    ST_UNION_FIND *pstUf, \n    DWORD *pdwPar, \n    DWORD *pdwRank,\n    DWORD *pdwCnt,\n    DWORD dwSize)\n{\n    pstUf->dwSize = dwSize;\n    pstUf->pdwPar = pdwPar;\n    pstUf->pdwRank = pdwRank;\n    pstUf->pdwCnt = pdwCnt;\n\n    for (DWORD dwIdx = 0; dwIdx < dwSize; dwIdx++) {\n        *(pstUf->pdwPar + dwIdx)  = dwIdx;\n        *(pstUf->pdwRank + dwIdx) = 0;\n        *(pstUf->pdwCnt + dwIdx)  = 1;\n    }\n}\n\nstatic DWORD ufGetParent(const ST_UNION_FIND *pstUf, DWORD dwIdx)\n{\n    return *(pstUf->pdwPar + dwIdx);\n}\n\nstatic DWORD ufGetRank(const ST_UNION_FIND *pstUf, DWORD dwIdx)\n{\n    return *(pstUf->pdwRank + dwIdx);\n}\n\nstatic void ufSetParent(ST_UNION_FIND *pstUf, DWORD dwIdx, DWORD dwParent)\n{\n    *(pstUf->pdwPar + dwIdx) = dwParent; \n    if (ufGetRank(pstUf, dwIdx) == ufGetRank(pstUf, dwParent)) {\n        (*(pstUf->pdwRank + dwParent))++;\n    }\n}\n\nstatic DWORD ufGetRoot(ST_UNION_FIND *pstUf, DWORD dwIdx)\n{\n    if (ufGetParent(pstUf, dwIdx) == dwIdx) {\n        return dwIdx;\n    } else {\n        DWORD dwParent = ufGetParent(pstUf, dwIdx);\n        DWORD dwRoot = ufGetRoot(pstUf, dwParent);\n        ufSetParent(pstUf, dwIdx, dwParent);\n        return dwRoot;\n    }\n}\n\nstatic void ufUnite(ST_UNION_FIND *pstUf, DWORD dwX, DWORD dwY)\n{\n    DWORD dwRootX = ufGetRoot(pstUf, dwX);\n    DWORD dwRootY = ufGetRoot(pstUf, dwY);\n\n    if (dwRootX == dwRootY) {\n        return;\n    }\n\n    if (ufGetRank(pstUf, dwRootX) < ufGetRank(pstUf, dwRootY)) {\n        ufSetParent(pstUf, dwRootX, dwRootY);\n        (*(pstUf->pdwCnt + dwRootY)) += (*(pstUf->pdwCnt + dwRootX));\n    } else {\n        ufSetParent(pstUf, dwRootY, dwRootX);\n        (*(pstUf->pdwCnt + dwRootX)) += (*(pstUf->pdwCnt + dwRootY));\n    }\n}\n\nstatic M_BOOL ufIsSame(ST_UNION_FIND *pstUf, DWORD dwX, DWORD dwY)\n{\n    return (ufGetRoot(pstUf, dwX)  == ufGetRoot(pstUf,dwY));\n}\n\n\n\n#define MAX_CITY_NUM         (100000)\n#define CITY_INFO_ARY_SIZE   (100000 + 1)\n\nint main()\n{\n    DWORD dwInput_N;\n    DWORD dwInput_K;\n    DWORD dwInput_L;\n\n    static DWORD adwRoad_Parents[CITY_INFO_ARY_SIZE];\n    static DWORD adwRoad_Rank[CITY_INFO_ARY_SIZE];\n    static DWORD adwRoad_Cnt[CITY_INFO_ARY_SIZE];\n    static DWORD adwRail_Parents[CITY_INFO_ARY_SIZE];\n    static DWORD adwRail_Rank[CITY_INFO_ARY_SIZE];\n    static DWORD adwRail_Cnt[CITY_INFO_ARY_SIZE];\n\n    ST_UNION_FIND stUfRoad;\n    ST_UNION_FIND stUfRail;\n\n    initUnionFind(&stUfRoad, adwRoad_Parents, adwRoad_Rank, adwRoad_Cnt, ArrayLength(adwRoad_Parents));\n    initUnionFind(&stUfRail, adwRail_Parents, adwRail_Rank, adwRail_Cnt, ArrayLength(adwRail_Parents));\n\n    dwInput_N = inputSDWORD();\n    dwInput_K = inputSDWORD();\n    dwInput_L = inputSDWORD();\n\n    for (DWORD dwIdx = 0; dwIdx < dwInput_K; dwIdx++) {\n        DWORD dwInput_p = inputSDWORD();\n        DWORD dwInput_q = inputSDWORD(); \n        ufUnite(&stUfRoad, dwInput_p, dwInput_q);\n    }\n    for (DWORD dwIdx = 0; dwIdx < dwInput_L; dwIdx++) {\n        DWORD dwInput_r = inputSDWORD();\n        DWORD dwInput_s = inputSDWORD(); \n        if (ufIsSame(&stUfRoad, dwInput_r, dwInput_s)) {\n            ufUnite(&stUfRail, dwInput_r, dwInput_s);\n        } \n    }\n    for (DWORD dwIdxJ = 1; dwIdxJ <= dwInput_N; dwIdxJ++) {\n        printf(\"%d\", *(stUfRail.pdwCnt + ufGetRoot(&stUfRail, dwIdxJ)));\n        if (dwIdxJ != dwInput_N) {\n            printf(\" \");\n        }\n    }\n    printf(\"\\n\");\n}\n", "language": "C++", "metadata": {"date": 1546290331, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03855.html", "problem_id": "p03855", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03855/input.txt", "sample_output_relpath": "derived/input_output/data/p03855/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03855/C++/s160450735.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s160450735", "user_id": "u487476769"}, "prompt_components": {"gold_output": "1 2 2 1\n", "input_to_evaluate": "#pragma GCC optimize (\"O3\")\n\n#include <iostream>\n#include <stdio.h>\n#include <stdlib.h>\n#include <string.h>\n#include <math.h>\n#include <queue>\nusing namespace std;\n\nusing QWORD = unsigned long long;\nusing SQWORD = long long;\nusing DWORD = unsigned int;\nusing SDWORD = int;\nusing WORD = unsigned short;\nusing SWORD = short;\nusing BYTE = unsigned char;\nusing SBYTE = char;\nusing DOUBLE = double;\nusing FLOAT = float;\n\n#define MIN_SDWORD (-2147483648)\n#define MAX_SDWORD (2147483647)\n#define MIN_SBYTE (-128)\n#define MAX_SBYTE (127)\n\n#define MAX_QWORD (0xFFFFFFFFFFFFFFFF)\n#define MAX_DWORD (0xFFFFFFFF)\n#define MAX_WORD  (0xFFFF)\n#define MAX_BYTE  (0xFF)\n\n\n#define ArrayLength(a)  (sizeof(a) / sizeof(a[0]))\n\nstatic inline QWORD MAX(QWORD a, QWORD b) { return a > b ? a : b; }\nstatic inline DWORD MAX(DWORD a, DWORD b) { return a > b ? a : b; }\nstatic inline SDWORD MAX(SDWORD a, SDWORD b) { return a > b ? a : b; }\nstatic inline QWORD MIN(QWORD a, QWORD b) { return a < b ? a : b; }\nstatic inline DWORD MIN(DWORD a, DWORD b) { return a < b ? a : b; }\nstatic inline SDWORD MIN(SDWORD a, SDWORD b) { return a < b ? a : b; }\n\n#define BYTE_BITS   (8)\n#define WORD_BITS   (16)\n#define DWORD_BITS  (32)\n#define QWORD_BITS  (64)\n\nusing M_BOOL = bool;\n#define M_TRUE (true)\n#define M_FALSE (false)\n#define DIVISOR (1000000007)\n\nstatic inline void inputString(char *pcStr)\n{\n    char *pcCur = pcStr;\n    for (;;) {\n        char c = getchar();\n        if (('\\n' == c) || (EOF == c)) {\n            break;\n        }\n        *pcCur = c;\n        pcCur++;\n    }\n    *pcCur = '\\0';\n}\n\nstatic inline SDWORD inputSDWORD(void)\n{\n    SDWORD lNumber = 0;\n    M_BOOL bRead = M_FALSE;\n    for (;;) {\n        char c = getchar();\n        if (('0' <= c) && (c <= '9')) {\n            lNumber *= 10;\n            lNumber += (c - '0');\n            bRead = M_TRUE;\n        } else {\n            if (bRead) {\n                return lNumber;\n            }\n        }\n    }\n}\n\ntypedef struct {\n    DWORD   *pdwPar;\n    DWORD   *pdwRank;\n    DWORD   *pdwCnt;\n    DWORD   dwSize;\n} ST_UNION_FIND;\n\nstatic void initUnionFind(\n    ST_UNION_FIND *pstUf, \n    DWORD *pdwPar, \n    DWORD *pdwRank,\n    DWORD *pdwCnt,\n    DWORD dwSize)\n{\n    pstUf->dwSize = dwSize;\n    pstUf->pdwPar = pdwPar;\n    pstUf->pdwRank = pdwRank;\n    pstUf->pdwCnt = pdwCnt;\n\n    for (DWORD dwIdx = 0; dwIdx < dwSize; dwIdx++) {\n        *(pstUf->pdwPar + dwIdx)  = dwIdx;\n        *(pstUf->pdwRank + dwIdx) = 0;\n        *(pstUf->pdwCnt + dwIdx)  = 1;\n    }\n}\n\nstatic DWORD ufGetParent(const ST_UNION_FIND *pstUf, DWORD dwIdx)\n{\n    return *(pstUf->pdwPar + dwIdx);\n}\n\nstatic DWORD ufGetRank(const ST_UNION_FIND *pstUf, DWORD dwIdx)\n{\n    return *(pstUf->pdwRank + dwIdx);\n}\n\nstatic void ufSetParent(ST_UNION_FIND *pstUf, DWORD dwIdx, DWORD dwParent)\n{\n    *(pstUf->pdwPar + dwIdx) = dwParent; \n    if (ufGetRank(pstUf, dwIdx) == ufGetRank(pstUf, dwParent)) {\n        (*(pstUf->pdwRank + dwParent))++;\n    }\n}\n\nstatic DWORD ufGetRoot(ST_UNION_FIND *pstUf, DWORD dwIdx)\n{\n    if (ufGetParent(pstUf, dwIdx) == dwIdx) {\n        return dwIdx;\n    } else {\n        DWORD dwParent = ufGetParent(pstUf, dwIdx);\n        DWORD dwRoot = ufGetRoot(pstUf, dwParent);\n        ufSetParent(pstUf, dwIdx, dwParent);\n        return dwRoot;\n    }\n}\n\nstatic void ufUnite(ST_UNION_FIND *pstUf, DWORD dwX, DWORD dwY)\n{\n    DWORD dwRootX = ufGetRoot(pstUf, dwX);\n    DWORD dwRootY = ufGetRoot(pstUf, dwY);\n\n    if (dwRootX == dwRootY) {\n        return;\n    }\n\n    if (ufGetRank(pstUf, dwRootX) < ufGetRank(pstUf, dwRootY)) {\n        ufSetParent(pstUf, dwRootX, dwRootY);\n        (*(pstUf->pdwCnt + dwRootY)) += (*(pstUf->pdwCnt + dwRootX));\n    } else {\n        ufSetParent(pstUf, dwRootY, dwRootX);\n        (*(pstUf->pdwCnt + dwRootX)) += (*(pstUf->pdwCnt + dwRootY));\n    }\n}\n\nstatic M_BOOL ufIsSame(ST_UNION_FIND *pstUf, DWORD dwX, DWORD dwY)\n{\n    return (ufGetRoot(pstUf, dwX)  == ufGetRoot(pstUf,dwY));\n}\n\n\n\n#define MAX_CITY_NUM         (100000)\n#define CITY_INFO_ARY_SIZE   (100000 + 1)\n\nint main()\n{\n    DWORD dwInput_N;\n    DWORD dwInput_K;\n    DWORD dwInput_L;\n\n    static DWORD adwRoad_Parents[CITY_INFO_ARY_SIZE];\n    static DWORD adwRoad_Rank[CITY_INFO_ARY_SIZE];\n    static DWORD adwRoad_Cnt[CITY_INFO_ARY_SIZE];\n    static DWORD adwRail_Parents[CITY_INFO_ARY_SIZE];\n    static DWORD adwRail_Rank[CITY_INFO_ARY_SIZE];\n    static DWORD adwRail_Cnt[CITY_INFO_ARY_SIZE];\n\n    ST_UNION_FIND stUfRoad;\n    ST_UNION_FIND stUfRail;\n\n    initUnionFind(&stUfRoad, adwRoad_Parents, adwRoad_Rank, adwRoad_Cnt, ArrayLength(adwRoad_Parents));\n    initUnionFind(&stUfRail, adwRail_Parents, adwRail_Rank, adwRail_Cnt, ArrayLength(adwRail_Parents));\n\n    dwInput_N = inputSDWORD();\n    dwInput_K = inputSDWORD();\n    dwInput_L = inputSDWORD();\n\n    for (DWORD dwIdx = 0; dwIdx < dwInput_K; dwIdx++) {\n        DWORD dwInput_p = inputSDWORD();\n        DWORD dwInput_q = inputSDWORD(); \n        ufUnite(&stUfRoad, dwInput_p, dwInput_q);\n    }\n    for (DWORD dwIdx = 0; dwIdx < dwInput_L; dwIdx++) {\n        DWORD dwInput_r = inputSDWORD();\n        DWORD dwInput_s = inputSDWORD(); \n        if (ufIsSame(&stUfRoad, dwInput_r, dwInput_s)) {\n            ufUnite(&stUfRail, dwInput_r, dwInput_s);\n        } \n    }\n    for (DWORD dwIdxJ = 1; dwIdxJ <= dwInput_N; dwIdxJ++) {\n        printf(\"%d\", *(stUfRail.pdwCnt + ufGetRoot(&stUfRail, dwIdxJ)));\n        if (dwIdxJ != dwInput_N) {\n            printf(\" \");\n        }\n    }\n    printf(\"\\n\");\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nThere are N cities. There are also K roads and L railways, extending between the cities.\nThe i-th road bidirectionally connects the p_i-th and q_i-th cities, and the i-th railway bidirectionally connects the r_i-th and s_i-th cities.\nNo two roads connect the same pair of cities. Similarly, no two railways connect the same pair of cities.\n\nWe will say city A and B are connected by roads if city B is reachable from city A by traversing some number of roads. Here, any city is considered to be connected to itself by roads.\nWe will also define connectivity by railways similarly.\n\nFor each city, find the number of the cities connected to that city by both roads and railways.\n\nConstraints\n\n2 ≦ N ≦ 2*10^5\n\n1 ≦ K, L≦ 10^5\n\n1 ≦ p_i, q_i, r_i, s_i ≦ N\n\np_i < q_i\n\nr_i < s_i\n\nWhen i ≠ j, (p_i, q_i) ≠ (p_j, q_j)\n\nWhen i ≠ j, (r_i, s_i) ≠ (r_j, s_j)\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN K L\np_1 q_1\n:\np_K q_K\nr_1 s_1\n:\nr_L s_L\n\nOutput\n\nPrint N integers. The i-th of them should represent the number of the cities connected to the i-th city by both roads and railways.\n\nSample Input 1\n\n4 3 1\n1 2\n2 3\n3 4\n2 3\n\nSample Output 1\n\n1 2 2 1\n\nAll the four cities are connected to each other by roads.\n\nBy railways, only the second and third cities are connected. Thus, the answers for the cities are 1, 2, 2 and 1, respectively.\n\nSample Input 2\n\n4 2 2\n1 2\n2 3\n1 4\n2 3\n\nSample Output 2\n\n1 2 2 1\n\nSample Input 3\n\n7 4 4\n1 2\n2 3\n2 5\n6 7\n3 5\n4 5\n3 4\n6 7\n\nSample Output 3\n\n1 1 2 1 2 2 2", "sample_input": "4 3 1\n1 2\n2 3\n3 4\n2 3\n"}, "reference_outputs": ["1 2 2 1\n"], "source_document_id": "p03855", "source_text": "Score : 400 points\n\nProblem Statement\n\nThere are N cities. There are also K roads and L railways, extending between the cities.\nThe i-th road bidirectionally connects the p_i-th and q_i-th cities, and the i-th railway bidirectionally connects the r_i-th and s_i-th cities.\nNo two roads connect the same pair of cities. Similarly, no two railways connect the same pair of cities.\n\nWe will say city A and B are connected by roads if city B is reachable from city A by traversing some number of roads. Here, any city is considered to be connected to itself by roads.\nWe will also define connectivity by railways similarly.\n\nFor each city, find the number of the cities connected to that city by both roads and railways.\n\nConstraints\n\n2 ≦ N ≦ 2*10^5\n\n1 ≦ K, L≦ 10^5\n\n1 ≦ p_i, q_i, r_i, s_i ≦ N\n\np_i < q_i\n\nr_i < s_i\n\nWhen i ≠ j, (p_i, q_i) ≠ (p_j, q_j)\n\nWhen i ≠ j, (r_i, s_i) ≠ (r_j, s_j)\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN K L\np_1 q_1\n:\np_K q_K\nr_1 s_1\n:\nr_L s_L\n\nOutput\n\nPrint N integers. The i-th of them should represent the number of the cities connected to the i-th city by both roads and railways.\n\nSample Input 1\n\n4 3 1\n1 2\n2 3\n3 4\n2 3\n\nSample Output 1\n\n1 2 2 1\n\nAll the four cities are connected to each other by roads.\n\nBy railways, only the second and third cities are connected. Thus, the answers for the cities are 1, 2, 2 and 1, respectively.\n\nSample Input 2\n\n4 2 2\n1 2\n2 3\n1 4\n2 3\n\nSample Output 2\n\n1 2 2 1\n\nSample Input 3\n\n7 4 4\n1 2\n2 3\n2 5\n6 7\n3 5\n4 5\n3 4\n6 7\n\nSample Output 3\n\n1 1 2 1 2 2 2", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 5441, "cpu_time_ms": 102, "memory_kb": 3200}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s410615703", "group_id": "codeNet:p03857", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nint vis1[200005],vis2[200005];\nvector<int>g[200005],e[200005];\nmap<pair<int,int>,int>mp;\nvoid dfs1(int x,int xx)\n{\n\tvis1[x]=xx;\n\tfor(int i=0;i<g[x].size();i++)if(!vis1[g[x][i]])dfs1(g[x][i],xx);\n}\nvoid dfs2(int x,int xx)\n{\n\tvis2[x]=xx;\n\tfor(int i=0;i<e[x].size();i++)if(!vis2[e[x][i]])dfs2(e[x][i],xx);\n}\nint main()\n{\n\tint n,m,k;\n\tscanf(\"%d%d%d\",&n,&m,&k);\n\tfor(int i=1;i<=m;i++)\n\t{\n\t\tint u,v;\n\t\tscanf(\"%d%d\",&u,&v);\n\t\tg[u].push_back(v);\n\t\tg[v].push_back(u);\n\t}\n\tfor(int i=1;i<=k;i++)\n\t{\n\t\tint u,v;\n\t\tscanf(\"%d%d\",&u,&v);\n\t\te[u].push_back(v);\n\t\te[v].push_back(u);\n\t}\n\tint cnt=1;\n\tmemset(vis1,0,sizeof(vis1));\n\tmemset(vis2,0,sizeof(vis2));\n\tfor(int i=1;i<=n;i++)if(!vis1[i])dfs1(i,cnt++);\n\tfor(int i=1;i<=n;i++)if(!vis2[i])dfs2(i,cnt++);\n\tfor(int i=1;i<=n;i++)mp[make_pair(vis1[i],vis2[i])]++;\n\tfor(int i=1;i<=n;i++)printf(\"%d \",mp[make_pair(vis1[i],vis2[i])]);\n\tputs(\"\");\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1500598375, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03857.html", "problem_id": "p03857", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03857/input.txt", "sample_output_relpath": "derived/input_output/data/p03857/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03857/C++/s410615703.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s410615703", "user_id": "u140621697"}, "prompt_components": {"gold_output": "1 2 2 1\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nint vis1[200005],vis2[200005];\nvector<int>g[200005],e[200005];\nmap<pair<int,int>,int>mp;\nvoid dfs1(int x,int xx)\n{\n\tvis1[x]=xx;\n\tfor(int i=0;i<g[x].size();i++)if(!vis1[g[x][i]])dfs1(g[x][i],xx);\n}\nvoid dfs2(int x,int xx)\n{\n\tvis2[x]=xx;\n\tfor(int i=0;i<e[x].size();i++)if(!vis2[e[x][i]])dfs2(e[x][i],xx);\n}\nint main()\n{\n\tint n,m,k;\n\tscanf(\"%d%d%d\",&n,&m,&k);\n\tfor(int i=1;i<=m;i++)\n\t{\n\t\tint u,v;\n\t\tscanf(\"%d%d\",&u,&v);\n\t\tg[u].push_back(v);\n\t\tg[v].push_back(u);\n\t}\n\tfor(int i=1;i<=k;i++)\n\t{\n\t\tint u,v;\n\t\tscanf(\"%d%d\",&u,&v);\n\t\te[u].push_back(v);\n\t\te[v].push_back(u);\n\t}\n\tint cnt=1;\n\tmemset(vis1,0,sizeof(vis1));\n\tmemset(vis2,0,sizeof(vis2));\n\tfor(int i=1;i<=n;i++)if(!vis1[i])dfs1(i,cnt++);\n\tfor(int i=1;i<=n;i++)if(!vis2[i])dfs2(i,cnt++);\n\tfor(int i=1;i<=n;i++)mp[make_pair(vis1[i],vis2[i])]++;\n\tfor(int i=1;i<=n;i++)printf(\"%d \",mp[make_pair(vis1[i],vis2[i])]);\n\tputs(\"\");\n\treturn 0;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nThere are N cities. There are also K roads and L railways, extending between the cities.\nThe i-th road bidirectionally connects the p_i-th and q_i-th cities, and the i-th railway bidirectionally connects the r_i-th and s_i-th cities.\nNo two roads connect the same pair of cities. Similarly, no two railways connect the same pair of cities.\n\nWe will say city A and B are connected by roads if city B is reachable from city A by traversing some number of roads. Here, any city is considered to be connected to itself by roads.\nWe will also define connectivity by railways similarly.\n\nFor each city, find the number of the cities connected to that city by both roads and railways.\n\nConstraints\n\n2 ≦ N ≦ 2*10^5\n\n1 ≦ K, L≦ 10^5\n\n1 ≦ p_i, q_i, r_i, s_i ≦ N\n\np_i < q_i\n\nr_i < s_i\n\nWhen i ≠ j, (p_i, q_i) ≠ (p_j, q_j)\n\nWhen i ≠ j, (r_i, s_i) ≠ (r_j, s_j)\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN K L\np_1 q_1\n:\np_K q_K\nr_1 s_1\n:\nr_L s_L\n\nOutput\n\nPrint N integers. The i-th of them should represent the number of the cities connected to the i-th city by both roads and railways.\n\nSample Input 1\n\n4 3 1\n1 2\n2 3\n3 4\n2 3\n\nSample Output 1\n\n1 2 2 1\n\nAll the four cities are connected to each other by roads.\n\nBy railways, only the second and third cities are connected. Thus, the answers for the cities are 1, 2, 2 and 1, respectively.\n\nSample Input 2\n\n4 2 2\n1 2\n2 3\n1 4\n2 3\n\nSample Output 2\n\n1 2 2 1\n\nSample Input 3\n\n7 4 4\n1 2\n2 3\n2 5\n6 7\n3 5\n4 5\n3 4\n6 7\n\nSample Output 3\n\n1 1 2 1 2 2 2", "sample_input": "4 3 1\n1 2\n2 3\n3 4\n2 3\n"}, "reference_outputs": ["1 2 2 1\n"], "source_document_id": "p03857", "source_text": "Score : 400 points\n\nProblem Statement\n\nThere are N cities. There are also K roads and L railways, extending between the cities.\nThe i-th road bidirectionally connects the p_i-th and q_i-th cities, and the i-th railway bidirectionally connects the r_i-th and s_i-th cities.\nNo two roads connect the same pair of cities. Similarly, no two railways connect the same pair of cities.\n\nWe will say city A and B are connected by roads if city B is reachable from city A by traversing some number of roads. Here, any city is considered to be connected to itself by roads.\nWe will also define connectivity by railways similarly.\n\nFor each city, find the number of the cities connected to that city by both roads and railways.\n\nConstraints\n\n2 ≦ N ≦ 2*10^5\n\n1 ≦ K, L≦ 10^5\n\n1 ≦ p_i, q_i, r_i, s_i ≦ N\n\np_i < q_i\n\nr_i < s_i\n\nWhen i ≠ j, (p_i, q_i) ≠ (p_j, q_j)\n\nWhen i ≠ j, (r_i, s_i) ≠ (r_j, s_j)\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN K L\np_1 q_1\n:\np_K q_K\nr_1 s_1\n:\nr_L s_L\n\nOutput\n\nPrint N integers. The i-th of them should represent the number of the cities connected to the i-th city by both roads and railways.\n\nSample Input 1\n\n4 3 1\n1 2\n2 3\n3 4\n2 3\n\nSample Output 1\n\n1 2 2 1\n\nAll the four cities are connected to each other by roads.\n\nBy railways, only the second and third cities are connected. Thus, the answers for the cities are 1, 2, 2 and 1, respectively.\n\nSample Input 2\n\n4 2 2\n1 2\n2 3\n1 4\n2 3\n\nSample Output 2\n\n1 2 2 1\n\nSample Input 3\n\n7 4 4\n1 2\n2 3\n2 5\n6 7\n3 5\n4 5\n3 4\n6 7\n\nSample Output 3\n\n1 1 2 1 2 2 2", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 929, "cpu_time_ms": 167, "memory_kb": 27904}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s477014435", "group_id": "codeNet:p03861", "input_text": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <string>\n#include <deque>\n#include <list>\n#include <map>\n#include <queue>\n#include <set>\n#include <stack>\n#include <cstring>\n#include <iomanip>\n\n#define rep(i,n) for(int i=0;i<(n);i++)\n#define reps(i,n) for(int i=1;i<=(n);i++)\nconst int INF = 0x3f3f3f3f;\nconst long long LINF = 0x3f3f3f3f3f3f3f3fLL;\nusing namespace std;\n\nint main(){\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n\n    int a,b,x,i;\n    cin>>a>>b>>x;\n    \n    int sum=0;\n    for(i=a;i<=b;i++){\n\tif(i%x==0){\n\t    break;\n\t}\n    }\n\n    for(i=i;i<=b;i+=x){\n\tsum++;\n    }\n    cout<<sum<<'\\n';\n\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1576865034, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03861.html", "problem_id": "p03861", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03861/input.txt", "sample_output_relpath": "derived/input_output/data/p03861/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03861/C++/s477014435.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s477014435", "user_id": "u623468376"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\n#include <algorithm>\n#include <string>\n#include <deque>\n#include <list>\n#include <map>\n#include <queue>\n#include <set>\n#include <stack>\n#include <cstring>\n#include <iomanip>\n\n#define rep(i,n) for(int i=0;i<(n);i++)\n#define reps(i,n) for(int i=1;i<=(n);i++)\nconst int INF = 0x3f3f3f3f;\nconst long long LINF = 0x3f3f3f3f3f3f3f3fLL;\nusing namespace std;\n\nint main(){\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n\n    int a,b,x,i;\n    cin>>a>>b>>x;\n    \n    int sum=0;\n    for(i=a;i<=b;i++){\n\tif(i%x==0){\n\t    break;\n\t}\n    }\n\n    for(i=i;i<=b;i+=x){\n\tsum++;\n    }\n    cout<<sum<<'\\n';\n\n    return 0;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nYou are given nonnegative integers a and b (a ≤ b), and a positive integer x.\nAmong the integers between a and b, inclusive, how many are divisible by x?\n\nConstraints\n\n0 ≤ a ≤ b ≤ 10^{18}\n\n1 ≤ x ≤ 10^{18}\n\nInput\n\nThe input is given from Standard Input in the following format:\n\na b x\n\nOutput\n\nPrint the number of the integers between a and b, inclusive, that are divisible by x.\n\nSample Input 1\n\n4 8 2\n\nSample Output 1\n\n3\n\nThere are three integers between 4 and 8, inclusive, that are divisible by 2: 4, 6 and 8.\n\nSample Input 2\n\n0 5 1\n\nSample Output 2\n\n6\n\nThere are six integers between 0 and 5, inclusive, that are divisible by 1: 0, 1, 2, 3, 4 and 5.\n\nSample Input 3\n\n9 9 2\n\nSample Output 3\n\n0\n\nThere are no integer between 9 and 9, inclusive, that is divisible by 2.\n\nSample Input 4\n\n1 1000000000000000000 3\n\nSample Output 4\n\n333333333333333333\n\nWatch out for integer overflows.", "sample_input": "4 8 2\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03861", "source_text": "Score : 200 points\n\nProblem Statement\n\nYou are given nonnegative integers a and b (a ≤ b), and a positive integer x.\nAmong the integers between a and b, inclusive, how many are divisible by x?\n\nConstraints\n\n0 ≤ a ≤ b ≤ 10^{18}\n\n1 ≤ x ≤ 10^{18}\n\nInput\n\nThe input is given from Standard Input in the following format:\n\na b x\n\nOutput\n\nPrint the number of the integers between a and b, inclusive, that are divisible by x.\n\nSample Input 1\n\n4 8 2\n\nSample Output 1\n\n3\n\nThere are three integers between 4 and 8, inclusive, that are divisible by 2: 4, 6 and 8.\n\nSample Input 2\n\n0 5 1\n\nSample Output 2\n\n6\n\nThere are six integers between 0 and 5, inclusive, that are divisible by 1: 0, 1, 2, 3, 4 and 5.\n\nSample Input 3\n\n9 9 2\n\nSample Output 3\n\n0\n\nThere are no integer between 9 and 9, inclusive, that is divisible by 2.\n\nSample Input 4\n\n1 1000000000000000000 3\n\nSample Output 4\n\n333333333333333333\n\nWatch out for integer overflows.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 641, "cpu_time_ms": 97, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s927824400", "group_id": "codeNet:p03861", "input_text": "#include <bits/stdc++.h>\n#include <sys/time.h>\nusing namespace std;\n\n#define rep(i,n) for(long long i = 0; i < (long long)(n); i++)\n#define repi(i,a,b) for(long long i = (long long)(a); i < (long long)(b); i++)\n#define pb push_back\n#define all(x) (x).begin(), (x).end()\n#define fi first\n#define se second\n#define mt make_tuple\n#define mp make_pair\ntemplate<class T1, class T2> bool chmin(T1 &a, T2 b) { return b < a && (a = b, true); }\ntemplate<class T1, class T2> bool chmax(T1 &a, T2 b) { return a < b && (a = b, true); }\n\nusing ll = long long; using vll = vector<ll>; using vvll = vector<vll>; using P = pair<ll, ll>;\nusing ld = long double;  using vld = vector<ld>; \nusing vi = vector<int>; using vvi = vector<vi>; vll conv(vi& v) { vll r(v.size()); rep(i, v.size()) r[i] = v[i]; return r; }\n\ninline void input(int &v){ v=0;char c=0;int p=1; while(c<'0' || c>'9'){if(c=='-')p=-1;c=getchar();} while(c>='0' && c<='9'){v=(v<<3)+(v<<1)+c-'0';c=getchar();} v*=p; } // これを使うならば、tieとかを消して！！\ntemplate <typename T, typename U> ostream &operator<<(ostream &o, const pair<T, U> &v) {  o << \"(\" << v.first << \", \" << v.second << \")\"; return o; }\ntemplate<size_t...> struct seq{}; template<size_t N, size_t... Is> struct gen_seq : gen_seq<N-1, N-1, Is...>{}; template<size_t... Is> struct gen_seq<0, Is...> : seq<Is...>{};\ntemplate<class Ch, class Tr, class Tuple, size_t... Is>\nvoid print_tuple(basic_ostream<Ch,Tr>& os, Tuple const& t, seq<Is...>){ using s = int[]; (void)s{0, (void(os << (Is == 0? \"\" : \", \") << get<Is>(t)), 0)...}; }\ntemplate<class Ch, class Tr, class... Args> \nauto operator<<(basic_ostream<Ch, Tr>& os, tuple<Args...> const& t) -> basic_ostream<Ch, Tr>& { os << \"(\"; print_tuple(os, t, gen_seq<sizeof...(Args)>()); return os << \")\"; }\nostream &operator<<(ostream &o, const vvll &v) { rep(i, v.size()) { rep(j, v[i].size()) o << v[i][j] << \" \"; o << endl; } return o; }\ntemplate <typename T> ostream &operator<<(ostream &o, const vector<T> &v) { o << '['; rep(i, v.size()) o << v[i] << (i != v.size()-1 ? \", \" : \"\"); o << \"]\";  return o; }\ntemplate <typename T> ostream &operator<<(ostream &o, const deque<T> &v) { o << '['; rep(i, v.size()) o << v[i] << (i != v.size()-1 ? \", \" : \"\"); o << \"]\";  return o; }\ntemplate <typename T>  ostream &operator<<(ostream &o, const set<T> &m) { o << '['; for (auto it = m.begin(); it != m.end(); it++) o << *it << (next(it) != m.end() ? \", \" : \"\"); o << \"]\";  return o; }\ntemplate <typename T>  ostream &operator<<(ostream &o, const unordered_set<T> &m) { o << '['; for (auto it = m.begin(); it != m.end(); it++) o << *it << (next(it) != m.end() ? \", \" : \"\"); o << \"]\";  return o; }\ntemplate <typename T, typename U>  ostream &operator<<(ostream &o, const map<T, U> &m) { o << '['; for (auto it = m.begin(); it != m.end(); it++) o << *it << (next(it) != m.end() ? \", \" : \"\"); o << \"]\";  return o; }\ntemplate <typename T, typename U, typename V>  ostream &operator<<(ostream &o, const unordered_map<T, U, V> &m) { o << '['; for (auto it = m.begin(); it != m.end(); it++) o << *it; o << \"]\";  return o; }\nvector<int> range(const int x, const int y) { vector<int> v(y - x + 1); iota(v.begin(), v.end(), x); return v; }\ntemplate <typename T> istream& operator>>(istream& i, vector<T>& o) { rep(j, o.size()) i >> o[j]; return i;}\ntemplate <typename T, typename S, typename U> ostream &operator<<(ostream &o, const priority_queue<T, S, U> &v) { auto tmp = v; while (tmp.size()) { auto x = tmp.top(); tmp.pop(); o << x << \" \";} return o; }\ntemplate <typename T> ostream &operator<<(ostream &o, const queue<T> &v) { auto tmp = v; while (tmp.size()) { auto x = tmp.front(); tmp.pop(); o << x << \" \";} return o; }\ntemplate <typename T> ostream &operator<<(ostream &o, const stack<T> &v) { auto tmp = v; while (tmp.size()) { auto x = tmp.top(); tmp.pop(); o << x << \" \";} return o; }\ntemplate <typename T> unordered_map<T, ll> counter(vector<T> vec){unordered_map<T, ll> ret; for (auto&& x : vec) ret[x]++; return ret;};\nstring substr(string s, P x) {return s.substr(x.fi, x.se - x.fi); }\nvoid vizGraph(vvll& g, int mode = 0, string filename = \"out.png\") { ofstream ofs(\"./out.dot\"); ofs << \"digraph graph_name {\" << endl; set<P> memo; rep(i, g.size())  rep(j, g[i].size()) { if (mode && (memo.count(P(i, g[i][j])) || memo.count(P(g[i][j], i)))) continue; memo.insert(P(i, g[i][j])); ofs << \"    \" << i << \" -> \" << g[i][j] << (mode ? \" [arrowhead = none]\" : \"\")<< endl;  } ofs << \"}\" << endl; ofs.close(); system(((string)\"dot -T png out.dot >\" + filename).c_str()); }\nsize_t random_seed; namespace std { using argument_type = P; template<> struct hash<argument_type> { size_t operator()(argument_type const& x) const { size_t seed = random_seed; seed ^= hash<ll>{}(x.fi); seed ^= (hash<ll>{}(x.se) << 1); return seed; } }; }; // hash for various class\nstruct timeval start; double sec() { struct timeval tv; gettimeofday(&tv, NULL); return (tv.tv_sec - start.tv_sec) + (tv.tv_usec - start.tv_usec) * 1e-6; }\nstruct init_{init_(){ ios::sync_with_stdio(false); cin.tie(0); gettimeofday(&start, NULL); struct timeval myTime; struct tm *time_st; gettimeofday(&myTime, NULL); time_st = localtime(&myTime.tv_sec); srand(myTime.tv_usec); random_seed = RAND_MAX / 2 + rand() / 2; }} init__;\n#define ldout fixed << setprecision(40) \n\n#define EPS (double)1e-14\n#define INF (ll)1e18\n#define mo  (ll)(1e9+7)\n\nint main(void) {\n    ll a,b,x;cin>>a>>b>>x;\n    cout<<(b+1+x-1)/x-(a+x-1)/x<<endl;;\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1515290208, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03861.html", "problem_id": "p03861", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03861/input.txt", "sample_output_relpath": "derived/input_output/data/p03861/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03861/C++/s927824400.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s927824400", "user_id": "u061916079"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#include <sys/time.h>\nusing namespace std;\n\n#define rep(i,n) for(long long i = 0; i < (long long)(n); i++)\n#define repi(i,a,b) for(long long i = (long long)(a); i < (long long)(b); i++)\n#define pb push_back\n#define all(x) (x).begin(), (x).end()\n#define fi first\n#define se second\n#define mt make_tuple\n#define mp make_pair\ntemplate<class T1, class T2> bool chmin(T1 &a, T2 b) { return b < a && (a = b, true); }\ntemplate<class T1, class T2> bool chmax(T1 &a, T2 b) { return a < b && (a = b, true); }\n\nusing ll = long long; using vll = vector<ll>; using vvll = vector<vll>; using P = pair<ll, ll>;\nusing ld = long double;  using vld = vector<ld>; \nusing vi = vector<int>; using vvi = vector<vi>; vll conv(vi& v) { vll r(v.size()); rep(i, v.size()) r[i] = v[i]; return r; }\n\ninline void input(int &v){ v=0;char c=0;int p=1; while(c<'0' || c>'9'){if(c=='-')p=-1;c=getchar();} while(c>='0' && c<='9'){v=(v<<3)+(v<<1)+c-'0';c=getchar();} v*=p; } // これを使うならば、tieとかを消して！！\ntemplate <typename T, typename U> ostream &operator<<(ostream &o, const pair<T, U> &v) {  o << \"(\" << v.first << \", \" << v.second << \")\"; return o; }\ntemplate<size_t...> struct seq{}; template<size_t N, size_t... Is> struct gen_seq : gen_seq<N-1, N-1, Is...>{}; template<size_t... Is> struct gen_seq<0, Is...> : seq<Is...>{};\ntemplate<class Ch, class Tr, class Tuple, size_t... Is>\nvoid print_tuple(basic_ostream<Ch,Tr>& os, Tuple const& t, seq<Is...>){ using s = int[]; (void)s{0, (void(os << (Is == 0? \"\" : \", \") << get<Is>(t)), 0)...}; }\ntemplate<class Ch, class Tr, class... Args> \nauto operator<<(basic_ostream<Ch, Tr>& os, tuple<Args...> const& t) -> basic_ostream<Ch, Tr>& { os << \"(\"; print_tuple(os, t, gen_seq<sizeof...(Args)>()); return os << \")\"; }\nostream &operator<<(ostream &o, const vvll &v) { rep(i, v.size()) { rep(j, v[i].size()) o << v[i][j] << \" \"; o << endl; } return o; }\ntemplate <typename T> ostream &operator<<(ostream &o, const vector<T> &v) { o << '['; rep(i, v.size()) o << v[i] << (i != v.size()-1 ? \", \" : \"\"); o << \"]\";  return o; }\ntemplate <typename T> ostream &operator<<(ostream &o, const deque<T> &v) { o << '['; rep(i, v.size()) o << v[i] << (i != v.size()-1 ? \", \" : \"\"); o << \"]\";  return o; }\ntemplate <typename T>  ostream &operator<<(ostream &o, const set<T> &m) { o << '['; for (auto it = m.begin(); it != m.end(); it++) o << *it << (next(it) != m.end() ? \", \" : \"\"); o << \"]\";  return o; }\ntemplate <typename T>  ostream &operator<<(ostream &o, const unordered_set<T> &m) { o << '['; for (auto it = m.begin(); it != m.end(); it++) o << *it << (next(it) != m.end() ? \", \" : \"\"); o << \"]\";  return o; }\ntemplate <typename T, typename U>  ostream &operator<<(ostream &o, const map<T, U> &m) { o << '['; for (auto it = m.begin(); it != m.end(); it++) o << *it << (next(it) != m.end() ? \", \" : \"\"); o << \"]\";  return o; }\ntemplate <typename T, typename U, typename V>  ostream &operator<<(ostream &o, const unordered_map<T, U, V> &m) { o << '['; for (auto it = m.begin(); it != m.end(); it++) o << *it; o << \"]\";  return o; }\nvector<int> range(const int x, const int y) { vector<int> v(y - x + 1); iota(v.begin(), v.end(), x); return v; }\ntemplate <typename T> istream& operator>>(istream& i, vector<T>& o) { rep(j, o.size()) i >> o[j]; return i;}\ntemplate <typename T, typename S, typename U> ostream &operator<<(ostream &o, const priority_queue<T, S, U> &v) { auto tmp = v; while (tmp.size()) { auto x = tmp.top(); tmp.pop(); o << x << \" \";} return o; }\ntemplate <typename T> ostream &operator<<(ostream &o, const queue<T> &v) { auto tmp = v; while (tmp.size()) { auto x = tmp.front(); tmp.pop(); o << x << \" \";} return o; }\ntemplate <typename T> ostream &operator<<(ostream &o, const stack<T> &v) { auto tmp = v; while (tmp.size()) { auto x = tmp.top(); tmp.pop(); o << x << \" \";} return o; }\ntemplate <typename T> unordered_map<T, ll> counter(vector<T> vec){unordered_map<T, ll> ret; for (auto&& x : vec) ret[x]++; return ret;};\nstring substr(string s, P x) {return s.substr(x.fi, x.se - x.fi); }\nvoid vizGraph(vvll& g, int mode = 0, string filename = \"out.png\") { ofstream ofs(\"./out.dot\"); ofs << \"digraph graph_name {\" << endl; set<P> memo; rep(i, g.size())  rep(j, g[i].size()) { if (mode && (memo.count(P(i, g[i][j])) || memo.count(P(g[i][j], i)))) continue; memo.insert(P(i, g[i][j])); ofs << \"    \" << i << \" -> \" << g[i][j] << (mode ? \" [arrowhead = none]\" : \"\")<< endl;  } ofs << \"}\" << endl; ofs.close(); system(((string)\"dot -T png out.dot >\" + filename).c_str()); }\nsize_t random_seed; namespace std { using argument_type = P; template<> struct hash<argument_type> { size_t operator()(argument_type const& x) const { size_t seed = random_seed; seed ^= hash<ll>{}(x.fi); seed ^= (hash<ll>{}(x.se) << 1); return seed; } }; }; // hash for various class\nstruct timeval start; double sec() { struct timeval tv; gettimeofday(&tv, NULL); return (tv.tv_sec - start.tv_sec) + (tv.tv_usec - start.tv_usec) * 1e-6; }\nstruct init_{init_(){ ios::sync_with_stdio(false); cin.tie(0); gettimeofday(&start, NULL); struct timeval myTime; struct tm *time_st; gettimeofday(&myTime, NULL); time_st = localtime(&myTime.tv_sec); srand(myTime.tv_usec); random_seed = RAND_MAX / 2 + rand() / 2; }} init__;\n#define ldout fixed << setprecision(40) \n\n#define EPS (double)1e-14\n#define INF (ll)1e18\n#define mo  (ll)(1e9+7)\n\nint main(void) {\n    ll a,b,x;cin>>a>>b>>x;\n    cout<<(b+1+x-1)/x-(a+x-1)/x<<endl;;\n    return 0;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nYou are given nonnegative integers a and b (a ≤ b), and a positive integer x.\nAmong the integers between a and b, inclusive, how many are divisible by x?\n\nConstraints\n\n0 ≤ a ≤ b ≤ 10^{18}\n\n1 ≤ x ≤ 10^{18}\n\nInput\n\nThe input is given from Standard Input in the following format:\n\na b x\n\nOutput\n\nPrint the number of the integers between a and b, inclusive, that are divisible by x.\n\nSample Input 1\n\n4 8 2\n\nSample Output 1\n\n3\n\nThere are three integers between 4 and 8, inclusive, that are divisible by 2: 4, 6 and 8.\n\nSample Input 2\n\n0 5 1\n\nSample Output 2\n\n6\n\nThere are six integers between 0 and 5, inclusive, that are divisible by 1: 0, 1, 2, 3, 4 and 5.\n\nSample Input 3\n\n9 9 2\n\nSample Output 3\n\n0\n\nThere are no integer between 9 and 9, inclusive, that is divisible by 2.\n\nSample Input 4\n\n1 1000000000000000000 3\n\nSample Output 4\n\n333333333333333333\n\nWatch out for integer overflows.", "sample_input": "4 8 2\n"}, "reference_outputs": ["3\n"], "source_document_id": "p03861", "source_text": "Score : 200 points\n\nProblem Statement\n\nYou are given nonnegative integers a and b (a ≤ b), and a positive integer x.\nAmong the integers between a and b, inclusive, how many are divisible by x?\n\nConstraints\n\n0 ≤ a ≤ b ≤ 10^{18}\n\n1 ≤ x ≤ 10^{18}\n\nInput\n\nThe input is given from Standard Input in the following format:\n\na b x\n\nOutput\n\nPrint the number of the integers between a and b, inclusive, that are divisible by x.\n\nSample Input 1\n\n4 8 2\n\nSample Output 1\n\n3\n\nThere are three integers between 4 and 8, inclusive, that are divisible by 2: 4, 6 and 8.\n\nSample Input 2\n\n0 5 1\n\nSample Output 2\n\n6\n\nThere are six integers between 0 and 5, inclusive, that are divisible by 1: 0, 1, 2, 3, 4 and 5.\n\nSample Input 3\n\n9 9 2\n\nSample Output 3\n\n0\n\nThere are no integer between 9 and 9, inclusive, that is divisible by 2.\n\nSample Input 4\n\n1 1000000000000000000 3\n\nSample Output 4\n\n333333333333333333\n\nWatch out for integer overflows.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 5474, "cpu_time_ms": 2, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s355424715", "group_id": "codeNet:p03863", "input_text": "#include <iostream>\n#include <cstring>\nusing namespace std;\nint main(){\n  string s;\n  cin>>s;\n  if(s[0]==s[s.length()-1]){\n    if(s.length()%2==0)\n      cout<<\"First\"<<endl;\n    else cout<<\"Second\"<<endl;\n  }\n  else {\n    if(s.length()%2==0)\n      cout<<\"Second\"<<endl;\n    else cout<<\"First\"<<endl;\n  }\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1484431690, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03863.html", "problem_id": "p03863", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03863/input.txt", "sample_output_relpath": "derived/input_output/data/p03863/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03863/C++/s355424715.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s355424715", "user_id": "u089230684"}, "prompt_components": {"gold_output": "Second\n", "input_to_evaluate": "#include <iostream>\n#include <cstring>\nusing namespace std;\nint main(){\n  string s;\n  cin>>s;\n  if(s[0]==s[s.length()-1]){\n    if(s.length()%2==0)\n      cout<<\"First\"<<endl;\n    else cout<<\"Second\"<<endl;\n  }\n  else {\n    if(s.length()%2==0)\n      cout<<\"Second\"<<endl;\n    else cout<<\"First\"<<endl;\n  }\n  return 0;\n}\n", "problem_context": "Score : 500 points\n\nProblem Statement\n\nThere is a string s of length 3 or greater.\nNo two neighboring characters in s are equal.\n\nTakahashi and Aoki will play a game against each other.\nThe two players alternately performs the following operation, Takahashi going first:\n\nRemove one of the characters in s, excluding both ends. However, a character cannot be removed if removal of the character would result in two neighboring equal characters in s.\n\nThe player who becomes unable to perform the operation, loses the game. Determine which player will win when the two play optimally.\n\nConstraints\n\n3 ≤ |s| ≤ 10^5\n\ns consists of lowercase English letters.\n\nNo two neighboring characters in s are equal.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\ns\n\nOutput\n\nIf Takahashi will win, print First. If Aoki will win, print Second.\n\nSample Input 1\n\naba\n\nSample Output 1\n\nSecond\n\nTakahashi, who goes first, cannot perform the operation, since removal of the b, which is the only character not at either ends of s, would result in s becoming aa, with two as neighboring.\n\nSample Input 2\n\nabc\n\nSample Output 2\n\nFirst\n\nWhen Takahashi removes b from s, it becomes ac.\nThen, Aoki cannot perform the operation, since there is no character in s, excluding both ends.\n\nSample Input 3\n\nabcab\n\nSample Output 3\n\nFirst", "sample_input": "aba\n"}, "reference_outputs": ["Second\n"], "source_document_id": "p03863", "source_text": "Score : 500 points\n\nProblem Statement\n\nThere is a string s of length 3 or greater.\nNo two neighboring characters in s are equal.\n\nTakahashi and Aoki will play a game against each other.\nThe two players alternately performs the following operation, Takahashi going first:\n\nRemove one of the characters in s, excluding both ends. However, a character cannot be removed if removal of the character would result in two neighboring equal characters in s.\n\nThe player who becomes unable to perform the operation, loses the game. Determine which player will win when the two play optimally.\n\nConstraints\n\n3 ≤ |s| ≤ 10^5\n\ns consists of lowercase English letters.\n\nNo two neighboring characters in s are equal.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\ns\n\nOutput\n\nIf Takahashi will win, print First. If Aoki will win, print Second.\n\nSample Input 1\n\naba\n\nSample Output 1\n\nSecond\n\nTakahashi, who goes first, cannot perform the operation, since removal of the b, which is the only character not at either ends of s, would result in s becoming aa, with two as neighboring.\n\nSample Input 2\n\nabc\n\nSample Output 2\n\nFirst\n\nWhen Takahashi removes b from s, it becomes ac.\nThen, Aoki cannot perform the operation, since there is no character in s, excluding both ends.\n\nSample Input 3\n\nabcab\n\nSample Output 3\n\nFirst", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 318, "cpu_time_ms": 116, "memory_kb": 764}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s797373988", "group_id": "codeNet:p03866", "input_text": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define pb push_back\n#define mp make_pair\n#define mt make_tuple\n#define fi first\n#define se second\n#define all(a) (a).begin(),(a).end()\n#define endl \"\\n\"\n#define rep(i, a, b) for (auto (i) = (a); (i) < (b); (i)++)\n#define rrep(i, a, b) for (auto (i) = (a); (i) > (b); (i)--)\n\n#define aim_cpo do{ios::sync_with_stdio(false);\\\ncin.tie(nullptr);cout.precision(12);cout<<fixed;}while(0)\n\n#define LOCAL_INPUT do{FILE *stream1;\\\nstream1=freopen(\"/Users/aim_cpo/CLionProjects/competitive/in.txt\",\"r\",stdin);\\\nif(stream1==nullptr)return 0;}while(0)\n#define LOCAL_OUTPUT do{FILE *stream2;\\\nstream2 = freopen(\"out.txt\", \"w\", stdout);\\\nif (stream2 == nullptr) return 0;}while(0)\n\n#ifdef LOCAL_DEFINE\n#define show(x) cerr << #x << \" = \" << (x) << endl\n#define dump(x) cerr << #x << \" = \" << (x) << \" (line \" << __LINE__ << \")\" << endl\n#define showV(v, n) do{\\\nfor(int _i_t_e_=0; _i_t_e_<(n);_i_t_e_++)\\\ncerr<<\"(\"<<_i_t_e_<<\" = \"<<(v)[_i_t_e_]<<\") \";\\\ncerr<<endl;}while(0)\n#define showA(a, n) do{\\\nfor(int _i_t_e_=0;_i_t_e_<(n);_i_t_e_++)\\\ncerr<<\"(\"<<_i_t_e_<<\" = \"<<(a)[_i_t_e_]<<\") \";\\\ncerr<<endl;}while(0)\n#define showA2(a, n, m) do{\\\nfor(int _i_t_e_=0;_i_t_e_<(n);_i_t_e_++){\\\nfor(int _i_t_e_2=0;_i_t_e_2<(m);_i_t_e_2++){\\\ncerr<<\"(\"<<_i_t_e_<<\", \"<<_i_t_e_2<<\" = \"<<(a)[_i_t_e_][_i_t_e_2]<<\") \";\\\n}cerr<<endl;}cerr<<endl;}while(0)\n#else\n#define show(x)\n#define dump(x)\n#define showV(v, n)\n#define showA(a, n)\n#define showA2(a, n, m)\n#endif\n\ntypedef long long ll;\ntypedef unsigned long long ull;\n\nconstexpr const int INT_INF=0x3f3f3f3f; //1061109567\nconstexpr const ll LL_INF=0x3f3f3f3f3f3f3f3f; //4557430888798830399\n\ntemplate <typename T> bool chmin(T &a, T b){return a>b?(a=b,true):false;}\ntemplate <typename T> bool chmax(T &a, T b){return a<b?(a=b,true):false;}\ntemplate <typename T> void ln(T i, T n){cout<<(i==n-1?\"\\n\":\" \");}\ntemplate <typename T, typename S>\nostream &operator<<(ostream &out,const pair<T, S> &pair1){\n  out<<'('<<pair1.fi<<\", \"<<pair1.se<<')';return out;}\ntemplate <typename T>\nostream &operator<<(ostream &out,const vector<T> &vector1){\n  out<<'[';for(unsigned int i=0;i<vector1.size();i++){\n    out<<vector1[i];if(i==vector1.size()-1)out<<\"]\";else out<<\", \";\n  }return out;\n}\n\n// INT\n#define GCD(a, b) __gcd(a, b)\ntemplate <typename T> T LCM(T a, T b) {return a / GCD(a, b) * b;}\ntemplate <typename T> T EXTGCD(T a, T b, T& x, T& y) {\n  T d = a;\n  if (b != 0) {d=EXTGCD(b,a%b,y,x);y-=(a/b)*x;}\n  else x=1,y=0;\n  return d;\n}\ntemplate <typename T> bool is_prime(T a) {\n  for(int i=2;i*i<=a;i++)if(a%i==0)return 1;\n  return 0;\n}\ntemplate <typename T, typename S> T Pow(T a, S b) {\n  T res = 1, now = a;\n  while(b){if(b&1)res*=now;b>>=1;now*=now;}return res;\n}\n\n// MOD\nll MOD = 1000000000L + 7L;\n#define add(a, b) ((a % MOD) + (b % MOD)) % MOD\n#define mul(a, b) ((a % MOD) * (b % MOD)) % MOD\n#define sub(a, b) ((a % MOD) + MOD - (b % MOD)) % MOD\ntemplate <typename T, typename S> T ModPow(T a, S b) {\n  T res = 1, now = a;\n  while(b){if(b&1)res=mul(res,now);b>>=1;now=mul(now,now);}return res;\n}\ntemplate <typename T> T mod_inverse(T a, T mod, bool prime){ // if mod is prime, \"prime\" is true.\n  if(prime)return ModPow(a, mod - 2);\n  else{T x,y;EXTGCD(a,mod,x,y);return (mod+x%mod)%mod;}\n}\n#define divide(a, b) ((a % MOD) * (mod_inverse(b, MOD, true))) % MOD\n\n//LLの数値をつかう時は最後にLをつける癖をつけよう\n//\n//  ┏┓┏┓　┓　┏┓\n//  ┏┛┃┃　┃　┗┫\n//  ┗┛┗┛　┻　┗┛\n//\n//   謹┃賀┃新┃年┃\n//   ━┛━┛━┛━┛\n//WWWWWWWWWWWWWWWWWWWWWW\n\nvector < pair < pair <int, int>, int> > v;\nvector < pair <int, double> > g[1011];\ndouble d[1011];\n\nint main() {\n  aim_cpo; // インタラクティブのときは消すように.\n#ifdef LOCAL_DEFINE\n  LOCAL_INPUT; // インタラクティブのときは消すように.\n//  LOCAL_OUTPUT; // ファイルに出力したいときのみ\n  show(MOD);\n#endif\n  // テキトー考察\n  //\n  // いろんな行き方がありそうだから、ダイクストラかな...(でもどうやって辺を貼れば良いんだろう)\n  // 例え��、ある座標からある座標に行くときに、その途中で関係ない場所のバリアを通ってしまうようなときは辺のコストをどんな値にすれば\n  // 良いのだろう...\n  // でも、よく考えたらそんな経路が最短になるわけないよね.\n  // 途中で、どこかのバリアをかすってしまうなら、そのバリアの中心に向かって移動して、そこからまた目的の場所に行くほうが\n  // 絶対に短くなるはず\n  // じゃあ、どうせその経路は使われないんだから、厳密なコストを求める必要はなくて、それよりもう少し長いコストでも良さそう.\n  // じゃあ、シンプルに座標同士の距離をコストにすれば丁度いい感じに求められそう.\n  // 個人的に、辺のコストを求める部分がこの問題の本質だなって思った.\n  // ある座標からある座標への経路の中に、絶対使われない経路が存在することに気づくことが大切.\n  int sx, sy; cin >> sx >> sy;\n  int gx, gy; cin >> gx >> gy;\n  v.push_back(mp(mp(sx, sy), 0));\n  v.push_back(mp(mp(gx, gy), 0));\n  int n; cin >> n;\n  rep(i, 0, n) {\n    int x, y, r; cin >> x >> y >> r;\n    v.push_back(mp(mp(x, y), r));\n  }\n  rep(i, 0, (int)v.size()) {\n    rep(j, 0, (int)v.size()) {\n      if (i == j) continue;\n      double cost = sqrt(Pow((double)v[i].fi.fi - v[j].fi.fi, 2) + Pow((double)v[i].fi.se - v[j].fi.se, 2));\n      if (cost - v[i].se - v[j].se < 0) cost = 0.;\n      else cost -= v[i].se + v[j].se;\n      g[i].emplace_back(j, cost);\n    }\n  }\n  priority_queue<pair<double, int> > q;\n  fill(d, d + n + 2, 1e17);\n  d[0] = 0.;\n  q.push(mp(0., 0));\n  while (!q.empty()) {\n    int now = q.top().se;\n    double cost = -q.top().fi; q.pop();\n    if (d[now] < cost) continue;\n    rep(i, 0, (int)g[now].size()) {\n      if (d[g[now][i].fi] > d[now] + g[now][i].se) {\n        d[g[now][i].fi] = d[now] + g[now][i].se;\n        q.push(mp(-d[g[now][i].fi], g[now][i].fi));\n      }\n    }\n  }\n  cout << d[1] << endl;\n#ifdef  LOCAL_DEFINE\n  cerr << \"Time elapsed: \" << 1.0 * clock() / CLOCKS_PER_SEC << \"s.\" << endl;\n#endif\n  return 0;\n}", "language": "C++", "metadata": {"date": 1548999106, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03866.html", "problem_id": "p03866", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03866/input.txt", "sample_output_relpath": "derived/input_output/data/p03866/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03866/C++/s797373988.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s797373988", "user_id": "u660656117"}, "prompt_components": {"gold_output": "3.6568542495\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define pb push_back\n#define mp make_pair\n#define mt make_tuple\n#define fi first\n#define se second\n#define all(a) (a).begin(),(a).end()\n#define endl \"\\n\"\n#define rep(i, a, b) for (auto (i) = (a); (i) < (b); (i)++)\n#define rrep(i, a, b) for (auto (i) = (a); (i) > (b); (i)--)\n\n#define aim_cpo do{ios::sync_with_stdio(false);\\\ncin.tie(nullptr);cout.precision(12);cout<<fixed;}while(0)\n\n#define LOCAL_INPUT do{FILE *stream1;\\\nstream1=freopen(\"/Users/aim_cpo/CLionProjects/competitive/in.txt\",\"r\",stdin);\\\nif(stream1==nullptr)return 0;}while(0)\n#define LOCAL_OUTPUT do{FILE *stream2;\\\nstream2 = freopen(\"out.txt\", \"w\", stdout);\\\nif (stream2 == nullptr) return 0;}while(0)\n\n#ifdef LOCAL_DEFINE\n#define show(x) cerr << #x << \" = \" << (x) << endl\n#define dump(x) cerr << #x << \" = \" << (x) << \" (line \" << __LINE__ << \")\" << endl\n#define showV(v, n) do{\\\nfor(int _i_t_e_=0; _i_t_e_<(n);_i_t_e_++)\\\ncerr<<\"(\"<<_i_t_e_<<\" = \"<<(v)[_i_t_e_]<<\") \";\\\ncerr<<endl;}while(0)\n#define showA(a, n) do{\\\nfor(int _i_t_e_=0;_i_t_e_<(n);_i_t_e_++)\\\ncerr<<\"(\"<<_i_t_e_<<\" = \"<<(a)[_i_t_e_]<<\") \";\\\ncerr<<endl;}while(0)\n#define showA2(a, n, m) do{\\\nfor(int _i_t_e_=0;_i_t_e_<(n);_i_t_e_++){\\\nfor(int _i_t_e_2=0;_i_t_e_2<(m);_i_t_e_2++){\\\ncerr<<\"(\"<<_i_t_e_<<\", \"<<_i_t_e_2<<\" = \"<<(a)[_i_t_e_][_i_t_e_2]<<\") \";\\\n}cerr<<endl;}cerr<<endl;}while(0)\n#else\n#define show(x)\n#define dump(x)\n#define showV(v, n)\n#define showA(a, n)\n#define showA2(a, n, m)\n#endif\n\ntypedef long long ll;\ntypedef unsigned long long ull;\n\nconstexpr const int INT_INF=0x3f3f3f3f; //1061109567\nconstexpr const ll LL_INF=0x3f3f3f3f3f3f3f3f; //4557430888798830399\n\ntemplate <typename T> bool chmin(T &a, T b){return a>b?(a=b,true):false;}\ntemplate <typename T> bool chmax(T &a, T b){return a<b?(a=b,true):false;}\ntemplate <typename T> void ln(T i, T n){cout<<(i==n-1?\"\\n\":\" \");}\ntemplate <typename T, typename S>\nostream &operator<<(ostream &out,const pair<T, S> &pair1){\n  out<<'('<<pair1.fi<<\", \"<<pair1.se<<')';return out;}\ntemplate <typename T>\nostream &operator<<(ostream &out,const vector<T> &vector1){\n  out<<'[';for(unsigned int i=0;i<vector1.size();i++){\n    out<<vector1[i];if(i==vector1.size()-1)out<<\"]\";else out<<\", \";\n  }return out;\n}\n\n// INT\n#define GCD(a, b) __gcd(a, b)\ntemplate <typename T> T LCM(T a, T b) {return a / GCD(a, b) * b;}\ntemplate <typename T> T EXTGCD(T a, T b, T& x, T& y) {\n  T d = a;\n  if (b != 0) {d=EXTGCD(b,a%b,y,x);y-=(a/b)*x;}\n  else x=1,y=0;\n  return d;\n}\ntemplate <typename T> bool is_prime(T a) {\n  for(int i=2;i*i<=a;i++)if(a%i==0)return 1;\n  return 0;\n}\ntemplate <typename T, typename S> T Pow(T a, S b) {\n  T res = 1, now = a;\n  while(b){if(b&1)res*=now;b>>=1;now*=now;}return res;\n}\n\n// MOD\nll MOD = 1000000000L + 7L;\n#define add(a, b) ((a % MOD) + (b % MOD)) % MOD\n#define mul(a, b) ((a % MOD) * (b % MOD)) % MOD\n#define sub(a, b) ((a % MOD) + MOD - (b % MOD)) % MOD\ntemplate <typename T, typename S> T ModPow(T a, S b) {\n  T res = 1, now = a;\n  while(b){if(b&1)res=mul(res,now);b>>=1;now=mul(now,now);}return res;\n}\ntemplate <typename T> T mod_inverse(T a, T mod, bool prime){ // if mod is prime, \"prime\" is true.\n  if(prime)return ModPow(a, mod - 2);\n  else{T x,y;EXTGCD(a,mod,x,y);return (mod+x%mod)%mod;}\n}\n#define divide(a, b) ((a % MOD) * (mod_inverse(b, MOD, true))) % MOD\n\n//LLの数値をつかう時は最後にLをつける癖をつけよう\n//\n//  ┏┓┏┓　┓　┏┓\n//  ┏┛┃┃　┃　┗┫\n//  ┗┛┗┛　┻　┗┛\n//\n//   謹┃賀┃新┃年┃\n//   ━┛━┛━┛━┛\n//WWWWWWWWWWWWWWWWWWWWWW\n\nvector < pair < pair <int, int>, int> > v;\nvector < pair <int, double> > g[1011];\ndouble d[1011];\n\nint main() {\n  aim_cpo; // インタラクティブのときは消すように.\n#ifdef LOCAL_DEFINE\n  LOCAL_INPUT; // インタラクティブのときは消すように.\n//  LOCAL_OUTPUT; // ファイルに出力したいときのみ\n  show(MOD);\n#endif\n  // テキトー考察\n  //\n  // いろんな行き方がありそうだから、ダイクストラかな...(でもどうやって辺を貼れば良いんだろう)\n  // 例えば、ある座標からある座標に行くときに、その途中で関係ない場所のバリアを通ってしまうようなときは辺のコストをどんな値にすれば\n  // 良いのだろう...\n  // でも、よく考えたらそんな経路が最短になるわけないよね.\n  // 途中で、どこかのバリアをかすってしまうなら、そのバリアの中心に向かって移動して、そこからまた目的の場所に行くほうが\n  // 絶対に短くなるはず\n  // じゃあ、どうせその経路は使われないんだから、厳密なコストを求める必要はなくて、それよりもう少し長いコストでも良さそう.\n  // じゃあ、シンプルに座標同士の距離をコストにすれば丁度いい感じに求められそう.\n  // 個人的に、辺のコストを求める部分がこの問題の本質だなって思った.\n  // ある座標からある座標への経路の中に、絶対使われない経路が存在することに気づくことが大切.\n  int sx, sy; cin >> sx >> sy;\n  int gx, gy; cin >> gx >> gy;\n  v.push_back(mp(mp(sx, sy), 0));\n  v.push_back(mp(mp(gx, gy), 0));\n  int n; cin >> n;\n  rep(i, 0, n) {\n    int x, y, r; cin >> x >> y >> r;\n    v.push_back(mp(mp(x, y), r));\n  }\n  rep(i, 0, (int)v.size()) {\n    rep(j, 0, (int)v.size()) {\n      if (i == j) continue;\n      double cost = sqrt(Pow((double)v[i].fi.fi - v[j].fi.fi, 2) + Pow((double)v[i].fi.se - v[j].fi.se, 2));\n      if (cost - v[i].se - v[j].se < 0) cost = 0.;\n      else cost -= v[i].se + v[j].se;\n      g[i].emplace_back(j, cost);\n    }\n  }\n  priority_queue<pair<double, int> > q;\n  fill(d, d + n + 2, 1e17);\n  d[0] = 0.;\n  q.push(mp(0., 0));\n  while (!q.empty()) {\n    int now = q.top().se;\n    double cost = -q.top().fi; q.pop();\n    if (d[now] < cost) continue;\n    rep(i, 0, (int)g[now].size()) {\n      if (d[g[now][i].fi] > d[now] + g[now][i].se) {\n        d[g[now][i].fi] = d[now] + g[now][i].se;\n        q.push(mp(-d[g[now][i].fi], g[now][i].fi));\n      }\n    }\n  }\n  cout << d[1] << endl;\n#ifdef  LOCAL_DEFINE\n  cerr << \"Time elapsed: \" << 1.0 * clock() / CLOCKS_PER_SEC << \"s.\" << endl;\n#endif\n  return 0;\n}", "problem_context": "Score : 600 points\n\nProblem Statement\n\nOn the xy-plane, Snuke is going to travel from the point (x_s, y_s) to the point (x_t, y_t).\nHe can move in arbitrary directions with speed 1.\nHere, we will consider him as a point without size.\n\nThere are N circular barriers deployed on the plane.\nThe center and the radius of the i-th barrier are (x_i, y_i) and r_i, respectively.\nThe barriers may overlap or contain each other.\n\nA point on the plane is exposed to cosmic rays if the point is not within any of the barriers.\n\nSnuke wants to avoid exposure to cosmic rays as much as possible during the travel.\nFind the minimum possible duration of time he is exposed to cosmic rays during the travel.\n\nConstraints\n\nAll input values are integers.\n\n-10^9 ≤ x_s, y_s, x_t, y_t ≤ 10^9\n\n(x_s, y_s) ≠ (x_t, y_t)\n\n1≤N≤1,000\n\n-10^9 ≤ x_i, y_i ≤ 10^9\n\n1 ≤ r_i ≤ 10^9\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nx_s y_s x_t y_t\nN\nx_1 y_1 r_1\nx_2 y_2 r_2\n:\nx_N y_N r_N\n\nOutput\n\nPrint the minimum possible duration of time Snuke is exposed to cosmic rays during the travel.\nThe output is considered correct if the absolute or relative error is at most 10^{-9}.\n\nSample Input 1\n\n-2 -2 2 2\n1\n0 0 1\n\nSample Output 1\n\n3.6568542495\n\nAn optimal route is as follows:\n\nSample Input 2\n\n-2 0 2 0\n2\n-1 0 2\n1 0 2\n\nSample Output 2\n\n0.0000000000\n\nAn optimal route is as follows:\n\nSample Input 3\n\n4 -2 -2 4\n3\n0 0 2\n4 0 1\n0 4 1\n\nSample Output 3\n\n4.0000000000\n\nAn optimal route is as follows:", "sample_input": "-2 -2 2 2\n1\n0 0 1\n"}, "reference_outputs": ["3.6568542495\n"], "source_document_id": "p03866", "source_text": "Score : 600 points\n\nProblem Statement\n\nOn the xy-plane, Snuke is going to travel from the point (x_s, y_s) to the point (x_t, y_t).\nHe can move in arbitrary directions with speed 1.\nHere, we will consider him as a point without size.\n\nThere are N circular barriers deployed on the plane.\nThe center and the radius of the i-th barrier are (x_i, y_i) and r_i, respectively.\nThe barriers may overlap or contain each other.\n\nA point on the plane is exposed to cosmic rays if the point is not within any of the barriers.\n\nSnuke wants to avoid exposure to cosmic rays as much as possible during the travel.\nFind the minimum possible duration of time he is exposed to cosmic rays during the travel.\n\nConstraints\n\nAll input values are integers.\n\n-10^9 ≤ x_s, y_s, x_t, y_t ≤ 10^9\n\n(x_s, y_s) ≠ (x_t, y_t)\n\n1≤N≤1,000\n\n-10^9 ≤ x_i, y_i ≤ 10^9\n\n1 ≤ r_i ≤ 10^9\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nx_s y_s x_t y_t\nN\nx_1 y_1 r_1\nx_2 y_2 r_2\n:\nx_N y_N r_N\n\nOutput\n\nPrint the minimum possible duration of time Snuke is exposed to cosmic rays during the travel.\nThe output is considered correct if the absolute or relative error is at most 10^{-9}.\n\nSample Input 1\n\n-2 -2 2 2\n1\n0 0 1\n\nSample Output 1\n\n3.6568542495\n\nAn optimal route is as follows:\n\nSample Input 2\n\n-2 0 2 0\n2\n-1 0 2\n1 0 2\n\nSample Output 2\n\n0.0000000000\n\nAn optimal route is as follows:\n\nSample Input 3\n\n4 -2 -2 4\n3\n0 0 2\n4 0 1\n0 4 1\n\nSample Output 3\n\n4.0000000000\n\nAn optimal route is as follows:", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 6299, "cpu_time_ms": 113, "memory_kb": 22512}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s782972046", "group_id": "codeNet:p03878", "input_text": "#include <iostream>\n#include <vector>\n#include <algorithm>\n\nusing namespace std;\n\ntypedef struct {\n  int type;\n  int x;\n} S;\n\nint64_t MOD = 1000000007;\n\nint main() {\n  int N;\n  cin >> N;\n\n  vector<S> v;\n\n  for (int i = 0; i < N; i++) {\n    int a;\n    cin >> a;\n    v.push_back({ 0, a });\n  }\n\n  for (int i = 0; i < N; i++) {\n    int b;\n    cin >> b;\n    v.push_back({ 1, b });\n  }\n\n  sort(v.begin(), v.end(), [](S a, S b) { return a.x < b.x; });\n\n  int cnt0 = 0;\n  int cnt1 = 0;\n  int64_t ans = 1;\n  for (auto i: v) {\n    if (i.type == 0) {\n      if (cnt1 == 0) {\n        cnt0 += 1;\n      } else {\n        ans = ans * cnt1 % MOD;\n        cnt1 -= 1;\n      }\n    } else {\n      if (cnt0 == 0) {\n        cnt1 += 1;\n      } else {\n        ans = ans * cnt0 % MOD;\n        cnt0 -= 1;\n      }\n    }\n  }\n\n  cout << ans << endl;\n}", "language": "C++", "metadata": {"date": 1557838499, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03878.html", "problem_id": "p03878", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03878/input.txt", "sample_output_relpath": "derived/input_output/data/p03878/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03878/C++/s782972046.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s782972046", "user_id": "u845152373"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\n#include <algorithm>\n\nusing namespace std;\n\ntypedef struct {\n  int type;\n  int x;\n} S;\n\nint64_t MOD = 1000000007;\n\nint main() {\n  int N;\n  cin >> N;\n\n  vector<S> v;\n\n  for (int i = 0; i < N; i++) {\n    int a;\n    cin >> a;\n    v.push_back({ 0, a });\n  }\n\n  for (int i = 0; i < N; i++) {\n    int b;\n    cin >> b;\n    v.push_back({ 1, b });\n  }\n\n  sort(v.begin(), v.end(), [](S a, S b) { return a.x < b.x; });\n\n  int cnt0 = 0;\n  int cnt1 = 0;\n  int64_t ans = 1;\n  for (auto i: v) {\n    if (i.type == 0) {\n      if (cnt1 == 0) {\n        cnt0 += 1;\n      } else {\n        ans = ans * cnt1 % MOD;\n        cnt1 -= 1;\n      }\n    } else {\n      if (cnt0 == 0) {\n        cnt1 += 1;\n      } else {\n        ans = ans * cnt0 % MOD;\n        cnt0 -= 1;\n      }\n    }\n  }\n\n  cout << ans << endl;\n}", "problem_context": "Score : 500 points\n\nProblem Statement\n\n#nck {\nwidth: 30px;\nheight: auto;\n}\n\nThere are N computers and N sockets in a one-dimensional world.\nThe coordinate of the i-th computer is a_i, and the coordinate of the i-th socket is b_i.\nIt is guaranteed that these 2N coordinates are pairwise distinct.\n\nSnuke wants to connect each computer to a socket using a cable.\nEach socket can be connected to only one computer.\n\nIn how many ways can he minimize the total length of the cables?\nCompute the answer modulo 10^9+7.\n\nConstraints\n\n1 ≤ N ≤ 10^5\n\n0 ≤ a_i, b_i ≤ 10^9\n\nThe coordinates are integers.\n\nThe coordinates are pairwise distinct.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\na_1\n:\na_N\nb_1\n:\nb_N\n\nOutput\n\nPrint the number of ways to minimize the total length of the cables, modulo 10^9+7.\n\nSample Input 1\n\n2\n0\n10\n20\n30\n\nSample Output 1\n\n2\n\nThere are two optimal connections: 0-20, 10-30 and 0-30, 10-20.\nIn both connections the total length of the cables is 40.\n\nSample Input 2\n\n3\n3\n10\n8\n7\n12\n5\n\nSample Output 2\n\n1", "sample_input": "2\n0\n10\n20\n30\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03878", "source_text": "Score : 500 points\n\nProblem Statement\n\n#nck {\nwidth: 30px;\nheight: auto;\n}\n\nThere are N computers and N sockets in a one-dimensional world.\nThe coordinate of the i-th computer is a_i, and the coordinate of the i-th socket is b_i.\nIt is guaranteed that these 2N coordinates are pairwise distinct.\n\nSnuke wants to connect each computer to a socket using a cable.\nEach socket can be connected to only one computer.\n\nIn how many ways can he minimize the total length of the cables?\nCompute the answer modulo 10^9+7.\n\nConstraints\n\n1 ≤ N ≤ 10^5\n\n0 ≤ a_i, b_i ≤ 10^9\n\nThe coordinates are integers.\n\nThe coordinates are pairwise distinct.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\na_1\n:\na_N\nb_1\n:\nb_N\n\nOutput\n\nPrint the number of ways to minimize the total length of the cables, modulo 10^9+7.\n\nSample Input 1\n\n2\n0\n10\n20\n30\n\nSample Output 1\n\n2\n\nThere are two optimal connections: 0-20, 10-30 and 0-30, 10-20.\nIn both connections the total length of the cables is 40.\n\nSample Input 2\n\n3\n3\n10\n8\n7\n12\n5\n\nSample Output 2\n\n1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 821, "cpu_time_ms": 97, "memory_kb": 2420}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s618570253", "group_id": "codeNet:p03891", "input_text": "#include <iostream>\n#include <algorithm>\n#include <iomanip>\n#include <vector>\n#include <queue>\n#include <set>\n#include <map>\n\nusing namespace std;\ntypedef long long ll;\n\nint main(){\n    ios::sync_with_stdio(false);\n    cin.tie(0);\n    cout << setprecision(10) << fixed;\n    int a, b, c; cin >> a >> b >> c;\n    cout << a << ' ' << b << ' ' << 3*c-(a+b) << endl;\n    cout << 4*c-2*a-b << ' ' << c << ' ' << 2*a+b-2*c << endl;\n    cout << a+b-c << ' ' << 2*c-b << ' ' << 2*c-a << endl;\n}", "language": "C++", "metadata": {"date": 1594868340, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03891.html", "problem_id": "p03891", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03891/input.txt", "sample_output_relpath": "derived/input_output/data/p03891/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03891/C++/s618570253.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s618570253", "user_id": "u346875991"}, "prompt_components": {"gold_output": "8 3 4\n1 5 9\n6 7 2\n", "input_to_evaluate": "#include <iostream>\n#include <algorithm>\n#include <iomanip>\n#include <vector>\n#include <queue>\n#include <set>\n#include <map>\n\nusing namespace std;\ntypedef long long ll;\n\nint main(){\n    ios::sync_with_stdio(false);\n    cin.tie(0);\n    cout << setprecision(10) << fixed;\n    int a, b, c; cin >> a >> b >> c;\n    cout << a << ' ' << b << ' ' << 3*c-(a+b) << endl;\n    cout << 4*c-2*a-b << ' ' << c << ' ' << 2*a+b-2*c << endl;\n    cout << a+b-c << ' ' << 2*c-b << ' ' << 2*c-a << endl;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nA 3×3 grid with a integer written in each square, is called a magic square if and only if the integers in each row, the integers in each column, and the integers in each diagonal (from the top left corner to the bottom right corner, and from the top right corner to the bottom left corner), all add up to the same sum.\n\nYou are given the integers written in the following three squares in a magic square:\n\nThe integer A at the upper row and left column\n\nThe integer B at the upper row and middle column\n\nThe integer C at the middle row and middle column\n\nDetermine the integers written in the remaining squares in the magic square.\n\nIt can be shown that there exists a unique magic square consistent with the given information.\n\nConstraints\n\n0 \\leq A, B, C \\leq 100\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nA\nB\nC\n\nOutput\n\nOutput the integers written in the magic square, in the following format:\n\nX_{1,1} X_{1,2} X_{1,3}\nX_{2,1} X_{2,2} X_{2,3}\nX_{3,1} X_{3,2} X_{3,3}\n\nwhere X_{i,j} is the integer written in the square at the i-th row and j-th column.\n\nSample Input 1\n\n8\n3\n5\n\nSample Output 1\n\n8 3 4\n1 5 9\n6 7 2\n\nSample Input 2\n\n1\n1\n1\n\nSample Output 2\n\n1 1 1\n1 1 1\n1 1 1", "sample_input": "8\n3\n5\n"}, "reference_outputs": ["8 3 4\n1 5 9\n6 7 2\n"], "source_document_id": "p03891", "source_text": "Score : 100 points\n\nProblem Statement\n\nA 3×3 grid with a integer written in each square, is called a magic square if and only if the integers in each row, the integers in each column, and the integers in each diagonal (from the top left corner to the bottom right corner, and from the top right corner to the bottom left corner), all add up to the same sum.\n\nYou are given the integers written in the following three squares in a magic square:\n\nThe integer A at the upper row and left column\n\nThe integer B at the upper row and middle column\n\nThe integer C at the middle row and middle column\n\nDetermine the integers written in the remaining squares in the magic square.\n\nIt can be shown that there exists a unique magic square consistent with the given information.\n\nConstraints\n\n0 \\leq A, B, C \\leq 100\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nA\nB\nC\n\nOutput\n\nOutput the integers written in the magic square, in the following format:\n\nX_{1,1} X_{1,2} X_{1,3}\nX_{2,1} X_{2,2} X_{2,3}\nX_{3,1} X_{3,2} X_{3,3}\n\nwhere X_{i,j} is the integer written in the square at the i-th row and j-th column.\n\nSample Input 1\n\n8\n3\n5\n\nSample Output 1\n\n8 3 4\n1 5 9\n6 7 2\n\nSample Input 2\n\n1\n1\n1\n\nSample Output 2\n\n1 1 1\n1 1 1\n1 1 1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 485, "cpu_time_ms": 6, "memory_kb": 3660}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s597568367", "group_id": "codeNet:p03891", "input_text": "#include <cstdio>\nusing namespace std;\nint k[15];\nint main()\n{\n    int a, b, c;\n    scanf(\"%d%d%d\", &a, &b, &c);\n    int sum = c * 3;\n    k[1] = a;\n    k[2] = b;\n    k[3] = sum - k[1] - k[2];\n    k[5] = c;\n    k[8] = sum - k[2] - k[5];\n    k[9] = sum - k[1] - k[5];\n    k[6] = sum - k[3] - k[9];\n    k[4] = sum - k[5] - k[6];\n    k[7] = sum - k[8] - k[9];\n    for( int i = 1; i <= 9; i++)\n    {\n        printf(\"%d \", k[i]);\n        if( i % 3 == 0) puts(\" \");\n    }\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1585869886, "filename_ext": "cpp", "original_language": "C++ (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03891.html", "problem_id": "p03891", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03891/input.txt", "sample_output_relpath": "derived/input_output/data/p03891/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03891/C++/s597568367.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s597568367", "user_id": "u426964396"}, "prompt_components": {"gold_output": "8 3 4\n1 5 9\n6 7 2\n", "input_to_evaluate": "#include <cstdio>\nusing namespace std;\nint k[15];\nint main()\n{\n    int a, b, c;\n    scanf(\"%d%d%d\", &a, &b, &c);\n    int sum = c * 3;\n    k[1] = a;\n    k[2] = b;\n    k[3] = sum - k[1] - k[2];\n    k[5] = c;\n    k[8] = sum - k[2] - k[5];\n    k[9] = sum - k[1] - k[5];\n    k[6] = sum - k[3] - k[9];\n    k[4] = sum - k[5] - k[6];\n    k[7] = sum - k[8] - k[9];\n    for( int i = 1; i <= 9; i++)\n    {\n        printf(\"%d \", k[i]);\n        if( i % 3 == 0) puts(\" \");\n    }\n    return 0;\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nA 3×3 grid with a integer written in each square, is called a magic square if and only if the integers in each row, the integers in each column, and the integers in each diagonal (from the top left corner to the bottom right corner, and from the top right corner to the bottom left corner), all add up to the same sum.\n\nYou are given the integers written in the following three squares in a magic square:\n\nThe integer A at the upper row and left column\n\nThe integer B at the upper row and middle column\n\nThe integer C at the middle row and middle column\n\nDetermine the integers written in the remaining squares in the magic square.\n\nIt can be shown that there exists a unique magic square consistent with the given information.\n\nConstraints\n\n0 \\leq A, B, C \\leq 100\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nA\nB\nC\n\nOutput\n\nOutput the integers written in the magic square, in the following format:\n\nX_{1,1} X_{1,2} X_{1,3}\nX_{2,1} X_{2,2} X_{2,3}\nX_{3,1} X_{3,2} X_{3,3}\n\nwhere X_{i,j} is the integer written in the square at the i-th row and j-th column.\n\nSample Input 1\n\n8\n3\n5\n\nSample Output 1\n\n8 3 4\n1 5 9\n6 7 2\n\nSample Input 2\n\n1\n1\n1\n\nSample Output 2\n\n1 1 1\n1 1 1\n1 1 1", "sample_input": "8\n3\n5\n"}, "reference_outputs": ["8 3 4\n1 5 9\n6 7 2\n"], "source_document_id": "p03891", "source_text": "Score : 100 points\n\nProblem Statement\n\nA 3×3 grid with a integer written in each square, is called a magic square if and only if the integers in each row, the integers in each column, and the integers in each diagonal (from the top left corner to the bottom right corner, and from the top right corner to the bottom left corner), all add up to the same sum.\n\nYou are given the integers written in the following three squares in a magic square:\n\nThe integer A at the upper row and left column\n\nThe integer B at the upper row and middle column\n\nThe integer C at the middle row and middle column\n\nDetermine the integers written in the remaining squares in the magic square.\n\nIt can be shown that there exists a unique magic square consistent with the given information.\n\nConstraints\n\n0 \\leq A, B, C \\leq 100\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nA\nB\nC\n\nOutput\n\nOutput the integers written in the magic square, in the following format:\n\nX_{1,1} X_{1,2} X_{1,3}\nX_{2,1} X_{2,2} X_{2,3}\nX_{3,1} X_{3,2} X_{3,3}\n\nwhere X_{i,j} is the integer written in the square at the i-th row and j-th column.\n\nSample Input 1\n\n8\n3\n5\n\nSample Output 1\n\n8 3 4\n1 5 9\n6 7 2\n\nSample Input 2\n\n1\n1\n1\n\nSample Output 2\n\n1 1 1\n1 1 1\n1 1 1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 481, "cpu_time_ms": 2, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s492858584", "group_id": "codeNet:p03891", "input_text": "#include<bits/stdc++.h>\n#define range(i,a,b) for(int i = (a); i < (b); i++)\n#define rep(i,b) for(int i = 0; i < (b); i++)\n#define all(a) (a).begin(), (a).end()\n#define show(x)  cerr << #x << \" = \" << (x) << endl;\n//const int INF = 1e8;\nusing namespace std;\n\nint main(){\n\tint a[9];\n\tcin >> a[0] >> a[1] >> a[4];\n\trange(i,max(a[0] + a[1], a[1] + a[4]),101){\n\t\ta[2] = i - a[0] - a[1];\n\t\ta[7] = i - a[1] - a[4];\n\t\tfor(int j = 0; j <= i - a[0]; j++){\n\t\t\ta[3] = j;\n\t\t\ta[6] = i - a[0] - j;\n\n\t\t\ta[5] = i - a[3] - a[4];\n\t\t\ta[8] = i - a[6] - a[7];\n\t\t\t\n\t\t\tif(a[2] + a[5] + a[8] == i &&\n\t\t\t\t\ta[0] + a[4] + a[8] == i &&\n\t\t\t\t\ta[2] + a[4] + a[6] == i){\n\t\t\t\trep(x,3){\n\t\t\t\t\trep(y,3){\n\t\t\t\t\t\tif(y) cout << ' ';\n\t\t\t\t\t\tcout << a[x * 3 + y];\n\t\t\t\t\t}\n\t\t\t\t\tcout << endl;\n\t\t\t\t}\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n\tassert(false);\n}\n", "language": "C++", "metadata": {"date": 1512857012, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03891.html", "problem_id": "p03891", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03891/input.txt", "sample_output_relpath": "derived/input_output/data/p03891/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03891/C++/s492858584.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s492858584", "user_id": "u750424669"}, "prompt_components": {"gold_output": "8 3 4\n1 5 9\n6 7 2\n", "input_to_evaluate": "#include<bits/stdc++.h>\n#define range(i,a,b) for(int i = (a); i < (b); i++)\n#define rep(i,b) for(int i = 0; i < (b); i++)\n#define all(a) (a).begin(), (a).end()\n#define show(x)  cerr << #x << \" = \" << (x) << endl;\n//const int INF = 1e8;\nusing namespace std;\n\nint main(){\n\tint a[9];\n\tcin >> a[0] >> a[1] >> a[4];\n\trange(i,max(a[0] + a[1], a[1] + a[4]),101){\n\t\ta[2] = i - a[0] - a[1];\n\t\ta[7] = i - a[1] - a[4];\n\t\tfor(int j = 0; j <= i - a[0]; j++){\n\t\t\ta[3] = j;\n\t\t\ta[6] = i - a[0] - j;\n\n\t\t\ta[5] = i - a[3] - a[4];\n\t\t\ta[8] = i - a[6] - a[7];\n\t\t\t\n\t\t\tif(a[2] + a[5] + a[8] == i &&\n\t\t\t\t\ta[0] + a[4] + a[8] == i &&\n\t\t\t\t\ta[2] + a[4] + a[6] == i){\n\t\t\t\trep(x,3){\n\t\t\t\t\trep(y,3){\n\t\t\t\t\t\tif(y) cout << ' ';\n\t\t\t\t\t\tcout << a[x * 3 + y];\n\t\t\t\t\t}\n\t\t\t\t\tcout << endl;\n\t\t\t\t}\n\t\t\t\treturn 0;\n\t\t\t}\n\t\t}\n\t}\n\tassert(false);\n}\n", "problem_context": "Score : 100 points\n\nProblem Statement\n\nA 3×3 grid with a integer written in each square, is called a magic square if and only if the integers in each row, the integers in each column, and the integers in each diagonal (from the top left corner to the bottom right corner, and from the top right corner to the bottom left corner), all add up to the same sum.\n\nYou are given the integers written in the following three squares in a magic square:\n\nThe integer A at the upper row and left column\n\nThe integer B at the upper row and middle column\n\nThe integer C at the middle row and middle column\n\nDetermine the integers written in the remaining squares in the magic square.\n\nIt can be shown that there exists a unique magic square consistent with the given information.\n\nConstraints\n\n0 \\leq A, B, C \\leq 100\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nA\nB\nC\n\nOutput\n\nOutput the integers written in the magic square, in the following format:\n\nX_{1,1} X_{1,2} X_{1,3}\nX_{2,1} X_{2,2} X_{2,3}\nX_{3,1} X_{3,2} X_{3,3}\n\nwhere X_{i,j} is the integer written in the square at the i-th row and j-th column.\n\nSample Input 1\n\n8\n3\n5\n\nSample Output 1\n\n8 3 4\n1 5 9\n6 7 2\n\nSample Input 2\n\n1\n1\n1\n\nSample Output 2\n\n1 1 1\n1 1 1\n1 1 1", "sample_input": "8\n3\n5\n"}, "reference_outputs": ["8 3 4\n1 5 9\n6 7 2\n"], "source_document_id": "p03891", "source_text": "Score : 100 points\n\nProblem Statement\n\nA 3×3 grid with a integer written in each square, is called a magic square if and only if the integers in each row, the integers in each column, and the integers in each diagonal (from the top left corner to the bottom right corner, and from the top right corner to the bottom left corner), all add up to the same sum.\n\nYou are given the integers written in the following three squares in a magic square:\n\nThe integer A at the upper row and left column\n\nThe integer B at the upper row and middle column\n\nThe integer C at the middle row and middle column\n\nDetermine the integers written in the remaining squares in the magic square.\n\nIt can be shown that there exists a unique magic square consistent with the given information.\n\nConstraints\n\n0 \\leq A, B, C \\leq 100\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nA\nB\nC\n\nOutput\n\nOutput the integers written in the magic square, in the following format:\n\nX_{1,1} X_{1,2} X_{1,3}\nX_{2,1} X_{2,2} X_{2,3}\nX_{3,1} X_{3,2} X_{3,3}\n\nwhere X_{i,j} is the integer written in the square at the i-th row and j-th column.\n\nSample Input 1\n\n8\n3\n5\n\nSample Output 1\n\n8 3 4\n1 5 9\n6 7 2\n\nSample Input 2\n\n1\n1\n1\n\nSample Output 2\n\n1 1 1\n1 1 1\n1 1 1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 796, "cpu_time_ms": 100, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s185952287", "group_id": "codeNet:p03910", "input_text": "#include <algorithm>\n#include <bitset>\n#include <cassert>\n#include <chrono>\n#include <cmath>\n#include <cstdio>\n#include <cstring>\n#include <iomanip>\n#include <iostream>\n#include <map>\n#include <queue>\n#include <random>\n#include <set>\n#include <stack>\n#include <string>\n#include <vector>\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair<int, int> pii;\n\nvoid solve() {\n  int n;\n  cin >> n;\n  set<int> s;\n  int tot = 0;\n  for(int i = 1; tot < n; i++) {\n    s.insert(i);\n    tot += i;\n  }\n  s.erase(tot-n);\n  for(int out: s) cout << out << \"\\n\";\n}\n\nint main() {\n  ios_base::sync_with_stdio(false);\n  cin.tie(NULL); cout.tie(NULL);\n  /*\n  int t;\n  cin >> t;\n  for(int i = 1; i <= t; i++) {\n    cout << \"Case #\" << i << \": \";\n    solve();\n  }\n  */\n  solve();\n}\n", "language": "C++", "metadata": {"date": 1558291596, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03910.html", "problem_id": "p03910", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03910/input.txt", "sample_output_relpath": "derived/input_output/data/p03910/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03910/C++/s185952287.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s185952287", "user_id": "u109256064"}, "prompt_components": {"gold_output": "1\n3\n", "input_to_evaluate": "#include <algorithm>\n#include <bitset>\n#include <cassert>\n#include <chrono>\n#include <cmath>\n#include <cstdio>\n#include <cstring>\n#include <iomanip>\n#include <iostream>\n#include <map>\n#include <queue>\n#include <random>\n#include <set>\n#include <stack>\n#include <string>\n#include <vector>\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair<int, int> pii;\n\nvoid solve() {\n  int n;\n  cin >> n;\n  set<int> s;\n  int tot = 0;\n  for(int i = 1; tot < n; i++) {\n    s.insert(i);\n    tot += i;\n  }\n  s.erase(tot-n);\n  for(int out: s) cout << out << \"\\n\";\n}\n\nint main() {\n  ios_base::sync_with_stdio(false);\n  cin.tie(NULL); cout.tie(NULL);\n  /*\n  int t;\n  cin >> t;\n  for(int i = 1; i <= t; i++) {\n    cout << \"Case #\" << i << \": \";\n    solve();\n  }\n  */\n  solve();\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nThe problem set at CODE FESTIVAL 20XX Finals consists of N problems.\n\nThe score allocated to the i-th (1≦i≦N) problem is i points.\n\nTakahashi, a contestant, is trying to score exactly N points. For that, he is deciding which problems to solve.\n\nAs problems with higher scores are harder, he wants to minimize the highest score of a problem among the ones solved by him.\n\nDetermine the set of problems that should be solved.\n\nConstraints\n\n1≦N≦10^7\n\nPartial Score\n\n200 points will be awarded for passing the test set satisfying 1≦N≦1000.\n\nAdditional 100 points will be awarded for passing the test set without additional constraints.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\n\nOutput\n\nAmong the sets of problems with the total score of N, find a set in which the highest score of a problem is minimum, then print the indices of the problems in the set in any order, one per line.\n\nIf there exists more than one such set, any of them will be accepted.\n\nSample Input 1\n\n4\n\nSample Output 1\n\n1\n3\n\nSolving only the 4-th problem will also result in the total score of 4 points, but solving the 1-st and 3-rd problems will lower the highest score of a solved problem.\n\nSample Input 2\n\n7\n\nSample Output 2\n\n1\n2\n4\n\nThe set \\{3,4\\} will also be accepted.\n\nSample Input 3\n\n1\n\nSample Output 3\n\n1", "sample_input": "4\n"}, "reference_outputs": ["1\n3\n"], "source_document_id": "p03910", "source_text": "Score : 300 points\n\nProblem Statement\n\nThe problem set at CODE FESTIVAL 20XX Finals consists of N problems.\n\nThe score allocated to the i-th (1≦i≦N) problem is i points.\n\nTakahashi, a contestant, is trying to score exactly N points. For that, he is deciding which problems to solve.\n\nAs problems with higher scores are harder, he wants to minimize the highest score of a problem among the ones solved by him.\n\nDetermine the set of problems that should be solved.\n\nConstraints\n\n1≦N≦10^7\n\nPartial Score\n\n200 points will be awarded for passing the test set satisfying 1≦N≦1000.\n\nAdditional 100 points will be awarded for passing the test set without additional constraints.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\n\nOutput\n\nAmong the sets of problems with the total score of N, find a set in which the highest score of a problem is minimum, then print the indices of the problems in the set in any order, one per line.\n\nIf there exists more than one such set, any of them will be accepted.\n\nSample Input 1\n\n4\n\nSample Output 1\n\n1\n3\n\nSolving only the 4-th problem will also result in the total score of 4 points, but solving the 1-st and 3-rd problems will lower the highest score of a solved problem.\n\nSample Input 2\n\n7\n\nSample Output 2\n\n1\n2\n4\n\nThe set \\{3,4\\} will also be accepted.\n\nSample Input 3\n\n1\n\nSample Output 3\n\n1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 764, "cpu_time_ms": 2, "memory_kb": 512}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s619002110", "group_id": "codeNet:p03911", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nstruct UnionFind {\n\tconst int V;\n\t// par[x] := xのroot\n\tvector<int> par;\n\t// sz[x] := xを含む集合のサイズ\n\tvector<int> sz;\n\tUnionFind(const int V) :\n\t\tV(V),\n\t\tpar(vector<int>(V)),\n\t\tsz(vector<int>(V, 1))\n\t\t{\n\t\t\tfor(int i = 0; i < V; ++i) par[i] = i;\n\t\t}\n\tbool unite(int x, int y) {\n\t\tx = root(x), y = root(y);\n\t\tif(same(x, y)) return false;\n\t\tif(y < x) swap(x, y);\n\t\tpar[y] = x;\n\t\tsz[x] += sz[y];\n\t\treturn true;\n\t}\n\tint root(int x) {\n\t\tif(par[x] == x) return x;\n\t\treturn (par[x] = root(par[x]));\n\t}\n\tbool same(int x, int y) {\n\t\treturn (root(x) == root(y));\n\t}\n\tint size(int x) {\n\t\treturn sz[root(x)];\n\t}\n};\n\nint main() {\n\tint n, m; cin >> n >> m;\n\tvector<int> l[n];\n\tfor(int i = 0; i < n; ++i) {\n\t\tint k; cin >> k;\n\t\twhile(k--) {\n\t\t\tint ll; cin >> ll;\n\t\t\t--ll;\n\t\t\tl[i].push_back(ll);\n\t\t}\n\t}\n\tUnionFind uf(m);\n\tfor(int i = 0; i < n; ++i) {\n\t\tfor(int j = 1; j < (int)l[i].size(); ++j) {\n\t\t\tuf.unite(l[i][j - 1], l[i][j]);\n\t\t}\n\t}\n\tset<int> ans;\n\tfor(int i = 0; i < n; ++i) {\n\t\tans.insert(uf.root(l[i].front()));\n\t}\n\tif(ans.size() == 1) {\n\t\tcout << \"YES\" << '\\n';\n\t} else {\n\t\tcout << \"NO\" << '\\n';\t\n\t}\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1571335251, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03911.html", "problem_id": "p03911", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03911/input.txt", "sample_output_relpath": "derived/input_output/data/p03911/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03911/C++/s619002110.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s619002110", "user_id": "u588300896"}, "prompt_components": {"gold_output": "YES\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nstruct UnionFind {\n\tconst int V;\n\t// par[x] := xのroot\n\tvector<int> par;\n\t// sz[x] := xを含む集合のサイズ\n\tvector<int> sz;\n\tUnionFind(const int V) :\n\t\tV(V),\n\t\tpar(vector<int>(V)),\n\t\tsz(vector<int>(V, 1))\n\t\t{\n\t\t\tfor(int i = 0; i < V; ++i) par[i] = i;\n\t\t}\n\tbool unite(int x, int y) {\n\t\tx = root(x), y = root(y);\n\t\tif(same(x, y)) return false;\n\t\tif(y < x) swap(x, y);\n\t\tpar[y] = x;\n\t\tsz[x] += sz[y];\n\t\treturn true;\n\t}\n\tint root(int x) {\n\t\tif(par[x] == x) return x;\n\t\treturn (par[x] = root(par[x]));\n\t}\n\tbool same(int x, int y) {\n\t\treturn (root(x) == root(y));\n\t}\n\tint size(int x) {\n\t\treturn sz[root(x)];\n\t}\n};\n\nint main() {\n\tint n, m; cin >> n >> m;\n\tvector<int> l[n];\n\tfor(int i = 0; i < n; ++i) {\n\t\tint k; cin >> k;\n\t\twhile(k--) {\n\t\t\tint ll; cin >> ll;\n\t\t\t--ll;\n\t\t\tl[i].push_back(ll);\n\t\t}\n\t}\n\tUnionFind uf(m);\n\tfor(int i = 0; i < n; ++i) {\n\t\tfor(int j = 1; j < (int)l[i].size(); ++j) {\n\t\t\tuf.unite(l[i][j - 1], l[i][j]);\n\t\t}\n\t}\n\tset<int> ans;\n\tfor(int i = 0; i < n; ++i) {\n\t\tans.insert(uf.root(l[i].front()));\n\t}\n\tif(ans.size() == 1) {\n\t\tcout << \"YES\" << '\\n';\n\t} else {\n\t\tcout << \"NO\" << '\\n';\t\n\t}\n\treturn 0;\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nOn a planet far, far away, M languages are spoken. They are conveniently numbered 1 through M.\n\nFor CODE FESTIVAL 20XX held on this planet, N participants gathered from all over the planet.\n\nThe i-th (1≦i≦N) participant can speak K_i languages numbered L_{i,1}, L_{i,2}, ..., L_{i,{}K_i}.\n\nTwo participants A and B can communicate with each other if and only if one of the following conditions is satisfied:\n\nThere exists a language that both A and B can speak.\n\nThere exists a participant X that both A and B can communicate with.\n\nDetermine whether all N participants can communicate with all other participants.\n\nConstraints\n\n2≦N≦10^5\n\n1≦M≦10^5\n\n1≦K_i≦M\n\n(The sum of all K_i)≦10^5\n\n1≦L_{i,j}≦M\n\nL_{i,1}, L_{i,2}, ..., L_{i,{}K_i} are pairwise distinct.\n\nPartial Score\n\n200 points will be awarded for passing the test set satisfying the following: N≦1000, M≦1000 and (The sum of all K_i)≦1000.\n\nAdditional 200 points will be awarded for passing the test set without additional constraints.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN M\nK_1 L_{1,1} L_{1,2} ... L_{1,{}K_1}\nK_2 L_{2,1} L_{2,2} ... L_{2,{}K_2}\n:\nK_N L_{N,1} L_{N,2} ... L_{N,{}K_N}\n\nOutput\n\nIf all N participants can communicate with all other participants, print YES. Otherwise, print NO.\n\nSample Input 1\n\n4 6\n3 1 2 3\n2 4 2\n2 4 6\n1 6\n\nSample Output 1\n\nYES\n\nAny two participants can communicate with each other, as follows:\n\nParticipants 1 and 2: both can speak language 2.\n\nParticipants 2 and 3: both can speak language 4.\n\nParticipants 1 and 3: both can communicate with participant 2.\n\nParticipants 3 and 4: both can speak language 6.\n\nParticipants 2 and 4: both can communicate with participant 3.\n\nParticipants 1 and 4: both can communicate with participant 2.\n\nNote that there can be languages spoken by no participant.\n\nSample Input 2\n\n4 4\n2 1 2\n2 1 2\n1 3\n2 4 3\n\nSample Output 2\n\nNO\n\nFor example, participants 1 and 3 cannot communicate with each other.", "sample_input": "4 6\n3 1 2 3\n2 4 2\n2 4 6\n1 6\n"}, "reference_outputs": ["YES\n"], "source_document_id": "p03911", "source_text": "Score : 400 points\n\nProblem Statement\n\nOn a planet far, far away, M languages are spoken. They are conveniently numbered 1 through M.\n\nFor CODE FESTIVAL 20XX held on this planet, N participants gathered from all over the planet.\n\nThe i-th (1≦i≦N) participant can speak K_i languages numbered L_{i,1}, L_{i,2}, ..., L_{i,{}K_i}.\n\nTwo participants A and B can communicate with each other if and only if one of the following conditions is satisfied:\n\nThere exists a language that both A and B can speak.\n\nThere exists a participant X that both A and B can communicate with.\n\nDetermine whether all N participants can communicate with all other participants.\n\nConstraints\n\n2≦N≦10^5\n\n1≦M≦10^5\n\n1≦K_i≦M\n\n(The sum of all K_i)≦10^5\n\n1≦L_{i,j}≦M\n\nL_{i,1}, L_{i,2}, ..., L_{i,{}K_i} are pairwise distinct.\n\nPartial Score\n\n200 points will be awarded for passing the test set satisfying the following: N≦1000, M≦1000 and (The sum of all K_i)≦1000.\n\nAdditional 200 points will be awarded for passing the test set without additional constraints.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN M\nK_1 L_{1,1} L_{1,2} ... L_{1,{}K_1}\nK_2 L_{2,1} L_{2,2} ... L_{2,{}K_2}\n:\nK_N L_{N,1} L_{N,2} ... L_{N,{}K_N}\n\nOutput\n\nIf all N participants can communicate with all other participants, print YES. Otherwise, print NO.\n\nSample Input 1\n\n4 6\n3 1 2 3\n2 4 2\n2 4 6\n1 6\n\nSample Output 1\n\nYES\n\nAny two participants can communicate with each other, as follows:\n\nParticipants 1 and 2: both can speak language 2.\n\nParticipants 2 and 3: both can speak language 4.\n\nParticipants 1 and 3: both can communicate with participant 2.\n\nParticipants 3 and 4: both can speak language 6.\n\nParticipants 2 and 4: both can communicate with participant 3.\n\nParticipants 1 and 4: both can communicate with participant 2.\n\nNote that there can be languages spoken by no participant.\n\nSample Input 2\n\n4 4\n2 1 2\n2 1 2\n1 3\n2 4 3\n\nSample Output 2\n\nNO\n\nFor example, participants 1 and 3 cannot communicate with each other.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1168, "cpu_time_ms": 53, "memory_kb": 6528}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s292153153", "group_id": "codeNet:p03913", "input_text": "#include <vector>\n#include <queue>\n#include <unordered_map>\n#include <tuple>\n#include <cstdio>\nusing namespace std;\n\nnamespace std{\n\ttemplate<typename T>\n\tinline void hash_combine(size_t& seed, T const& v){\n\t\tseed ^= hash<T>()(v) + 0x9e3779b9 + (seed<<6) + (seed>>2);\n\t}\n\ttemplate<typename A,typename B>\n\tclass hash<pair<A,B>>{\n\t\tpublic:\n\t\tsize_t operator()(pair<A,B> const &p) const{\n\t\t\tsize_t seed=0;\n\t\t\thash_combine(seed,p.first);\n\t\t\thash_combine(seed,p.second);\n\t\t\treturn seed;\n\t\t}\n\t};\n}\n \nint main(){\n\tlong long N,A,R;\n\tscanf(\"%lld%lld\",&N,&A);R=N;\n\tif(N>1000000)return 1;\n \n\tunordered_map<pair<long long,long long>,long long>m; //m<n,speed>=time\n\tm[{0,1}]=0;\n\tqueue<tuple<long long,long long,long long> >q;\n\tq.push(make_tuple(0,1,0));\n\tfor(;!q.empty();){\n\t\tauto cur=q.front();q.pop();\n\t\tlong long n=get<0>(cur);\n\t\tlong long speed=get<1>(cur);\n\t\tlong long time=get<2>(cur);\n\t\tif(time>=R)continue;\n \n\t\tvector<tuple<int,int,int>> nxt={\n\t\t\tmake_tuple(0,n,time+A),\n\t\t\tmake_tuple(n+speed,speed,time+1)\n\t\t};\n\t\tfor(auto &e:nxt){\n\t\t\tlong long nxtn=get<0>(e);\n\t\t\tlong long nxtspeed=get<1>(e);\n\t\t\tlong long nxttime=get<2>(e);\n\t\t\tif(nxtn>=N){\n\t\t\t\tR=min(R,nxttime);\n\t\t\t}else if(m.find({nxtn,nxtspeed})==m.end()||m[{nxtn,nxtspeed}]>nxttime){\n\t\t\t\tm[{nxtn,nxtspeed}]=nxttime;\n\t\t\t\tq.push(e);\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%lld\\n\",R);\n}", "language": "C++", "metadata": {"date": 1480190485, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03913.html", "problem_id": "p03913", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03913/input.txt", "sample_output_relpath": "derived/input_output/data/p03913/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03913/C++/s292153153.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s292153153", "user_id": "u805593120"}, "prompt_components": {"gold_output": "7\n", "input_to_evaluate": "#include <vector>\n#include <queue>\n#include <unordered_map>\n#include <tuple>\n#include <cstdio>\nusing namespace std;\n\nnamespace std{\n\ttemplate<typename T>\n\tinline void hash_combine(size_t& seed, T const& v){\n\t\tseed ^= hash<T>()(v) + 0x9e3779b9 + (seed<<6) + (seed>>2);\n\t}\n\ttemplate<typename A,typename B>\n\tclass hash<pair<A,B>>{\n\t\tpublic:\n\t\tsize_t operator()(pair<A,B> const &p) const{\n\t\t\tsize_t seed=0;\n\t\t\thash_combine(seed,p.first);\n\t\t\thash_combine(seed,p.second);\n\t\t\treturn seed;\n\t\t}\n\t};\n}\n \nint main(){\n\tlong long N,A,R;\n\tscanf(\"%lld%lld\",&N,&A);R=N;\n\tif(N>1000000)return 1;\n \n\tunordered_map<pair<long long,long long>,long long>m; //m<n,speed>=time\n\tm[{0,1}]=0;\n\tqueue<tuple<long long,long long,long long> >q;\n\tq.push(make_tuple(0,1,0));\n\tfor(;!q.empty();){\n\t\tauto cur=q.front();q.pop();\n\t\tlong long n=get<0>(cur);\n\t\tlong long speed=get<1>(cur);\n\t\tlong long time=get<2>(cur);\n\t\tif(time>=R)continue;\n \n\t\tvector<tuple<int,int,int>> nxt={\n\t\t\tmake_tuple(0,n,time+A),\n\t\t\tmake_tuple(n+speed,speed,time+1)\n\t\t};\n\t\tfor(auto &e:nxt){\n\t\t\tlong long nxtn=get<0>(e);\n\t\t\tlong long nxtspeed=get<1>(e);\n\t\t\tlong long nxttime=get<2>(e);\n\t\t\tif(nxtn>=N){\n\t\t\t\tR=min(R,nxttime);\n\t\t\t}else if(m.find({nxtn,nxtspeed})==m.end()||m[{nxtn,nxtspeed}]>nxttime){\n\t\t\t\tm[{nxtn,nxtspeed}]=nxttime;\n\t\t\t\tq.push(e);\n\t\t\t}\n\t\t}\n\t}\n\tprintf(\"%lld\\n\",R);\n}", "problem_context": "Score : 1000 points\n\nProblem Statement\n\nRng is baking cookies.\n\nInitially, he can bake one cookie per second.\n\nHe can also eat the cookies baked by himself.\nWhen there are x cookies not yet eaten, he can choose to eat all those cookies. After he finishes eating those cookies, the number of cookies he can bake per second becomes x. Note that a cookie always needs to be baked for 1 second, that is, he cannot bake a cookie in 1/x seconds when x > 1.\nWhen he choose to eat the cookies, he must eat all of them; he cannot choose to eat only part of them.\nIt takes him A seconds to eat the cookies regardless of how many, during which no cookies can be baked.\n\nHe wants to give N cookies to Grandma.\nFind the shortest time needed to produce at least N cookies not yet eaten.\n\nConstraints\n\n1≦N≦10^{12}\n\n0≦A≦10^{12}\n\nA is an integer.\n\nPartial Score\n\n500 points will be awarded for passing the test set satisfying N≦10^6 and A≦10^6.\n\nAdditional 500 points will be awarded for passing the test set without additional constraints.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN A\n\nOutput\n\nPrint the shortest time needed to produce at least N cookies not yet eaten.\n\nSample Input 1\n\n8 1\n\nSample Output 1\n\n7\n\nIt is possible to produce 8 cookies in 7 seconds, as follows:\n\nAfter 1 second: 1 cookie is done.\n\nAfter 2 seconds: 1 more cookie is done, totaling 2. Now, Rng starts eating those 2 cookies.\n\nAfter 3 seconds: He finishes eating the cookies, and he can now bake 2 cookies per second.\n\nAfter 4 seconds: 2 cookies are done.\n\nAfter 5 seconds: 2 more cookies are done, totaling 4.\n\nAfter 6 seconds: 2 more cookies are done, totaling 6.\n\nAfter 7 seconds: 2 more cookies are done, totaling 8.\n\nSample Input 2\n\n1000000000000 1000000000000\n\nSample Output 2\n\n1000000000000", "sample_input": "8 1\n"}, "reference_outputs": ["7\n"], "source_document_id": "p03913", "source_text": "Score : 1000 points\n\nProblem Statement\n\nRng is baking cookies.\n\nInitially, he can bake one cookie per second.\n\nHe can also eat the cookies baked by himself.\nWhen there are x cookies not yet eaten, he can choose to eat all those cookies. After he finishes eating those cookies, the number of cookies he can bake per second becomes x. Note that a cookie always needs to be baked for 1 second, that is, he cannot bake a cookie in 1/x seconds when x > 1.\nWhen he choose to eat the cookies, he must eat all of them; he cannot choose to eat only part of them.\nIt takes him A seconds to eat the cookies regardless of how many, during which no cookies can be baked.\n\nHe wants to give N cookies to Grandma.\nFind the shortest time needed to produce at least N cookies not yet eaten.\n\nConstraints\n\n1≦N≦10^{12}\n\n0≦A≦10^{12}\n\nA is an integer.\n\nPartial Score\n\n500 points will be awarded for passing the test set satisfying N≦10^6 and A≦10^6.\n\nAdditional 500 points will be awarded for passing the test set without additional constraints.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN A\n\nOutput\n\nPrint the shortest time needed to produce at least N cookies not yet eaten.\n\nSample Input 1\n\n8 1\n\nSample Output 1\n\n7\n\nIt is possible to produce 8 cookies in 7 seconds, as follows:\n\nAfter 1 second: 1 cookie is done.\n\nAfter 2 seconds: 1 more cookie is done, totaling 2. Now, Rng starts eating those 2 cookies.\n\nAfter 3 seconds: He finishes eating the cookies, and he can now bake 2 cookies per second.\n\nAfter 4 seconds: 2 cookies are done.\n\nAfter 5 seconds: 2 more cookies are done, totaling 4.\n\nAfter 6 seconds: 2 more cookies are done, totaling 6.\n\nAfter 7 seconds: 2 more cookies are done, totaling 8.\n\nSample Input 2\n\n1000000000000 1000000000000\n\nSample Output 2\n\n1000000000000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1315, "cpu_time_ms": 2114, "memory_kb": 227672}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s540260009", "group_id": "codeNet:p03913", "input_text": "#include <algorithm>\n#include <cassert>\n#include <cctype>\n#include <cstdlib>\n#include <cmath>\n#include <cstdio>\n#include <functional>\n#include <iostream>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <string>\n#include <unordered_map>\n#include <unordered_set>\n#include <vector>\n#include <utility>\n\n#define reps(i,f,n) for(int i=f; i<int(n); ++i)\n#define rep(i,n) reps(i,0,n)\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef vector<ll> vi;\ntypedef vector<vi> vvi;\ntypedef pair<int, int> pii;\n\nconst ll INF = 1001001001001001ll;\n\nsigned main()\n{\n    ll n, a;\n    cin >> n >> a;\n    \n    if(a <= 1000000){\n        vi dp(1000000 * 45);\n        rep(t, dp.size()) dp[t] = t;\n        \n        int mae = 1;\n        \n        rep(t, dp.size()){\n            reps(s, mae, t){\n                ll tmp = dp[s] * (t-s-a);\n                if(tmp > dp[t]){\n                    mae = s;\n                    dp[t] = tmp;\n                }\n            }\n            \n            if(dp[t] >= n){\n                cout << t << endl;\n                return 0;\n            }\n            if(t==100) break;\n        }\n    }\n    else{\n        vi dp(2000000, INF);\n        dp[1] = 0;\n        \n        reps(i, 1, dp.size()){\n            for(int j=i*2; j<dp.size(); j+=i){\n                dp[j] = min(dp[j], dp[i] + (i/j) + a);\n            }\n        }\n        \n        ll ans = INF;\n        reps(i, 1, dp.size()){\n            ans = min(ans, dp[i] + (n+i-1)/i);\n        }\n        \n        cout << ans << endl;\n    }\n}\n", "language": "C++", "metadata": {"date": 1480189378, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03913.html", "problem_id": "p03913", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03913/input.txt", "sample_output_relpath": "derived/input_output/data/p03913/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03913/C++/s540260009.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s540260009", "user_id": "u389832297"}, "prompt_components": {"gold_output": "7\n", "input_to_evaluate": "#include <algorithm>\n#include <cassert>\n#include <cctype>\n#include <cstdlib>\n#include <cmath>\n#include <cstdio>\n#include <functional>\n#include <iostream>\n#include <map>\n#include <numeric>\n#include <queue>\n#include <set>\n#include <sstream>\n#include <string>\n#include <unordered_map>\n#include <unordered_set>\n#include <vector>\n#include <utility>\n\n#define reps(i,f,n) for(int i=f; i<int(n); ++i)\n#define rep(i,n) reps(i,0,n)\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef vector<ll> vi;\ntypedef vector<vi> vvi;\ntypedef pair<int, int> pii;\n\nconst ll INF = 1001001001001001ll;\n\nsigned main()\n{\n    ll n, a;\n    cin >> n >> a;\n    \n    if(a <= 1000000){\n        vi dp(1000000 * 45);\n        rep(t, dp.size()) dp[t] = t;\n        \n        int mae = 1;\n        \n        rep(t, dp.size()){\n            reps(s, mae, t){\n                ll tmp = dp[s] * (t-s-a);\n                if(tmp > dp[t]){\n                    mae = s;\n                    dp[t] = tmp;\n                }\n            }\n            \n            if(dp[t] >= n){\n                cout << t << endl;\n                return 0;\n            }\n            if(t==100) break;\n        }\n    }\n    else{\n        vi dp(2000000, INF);\n        dp[1] = 0;\n        \n        reps(i, 1, dp.size()){\n            for(int j=i*2; j<dp.size(); j+=i){\n                dp[j] = min(dp[j], dp[i] + (i/j) + a);\n            }\n        }\n        \n        ll ans = INF;\n        reps(i, 1, dp.size()){\n            ans = min(ans, dp[i] + (n+i-1)/i);\n        }\n        \n        cout << ans << endl;\n    }\n}\n", "problem_context": "Score : 1000 points\n\nProblem Statement\n\nRng is baking cookies.\n\nInitially, he can bake one cookie per second.\n\nHe can also eat the cookies baked by himself.\nWhen there are x cookies not yet eaten, he can choose to eat all those cookies. After he finishes eating those cookies, the number of cookies he can bake per second becomes x. Note that a cookie always needs to be baked for 1 second, that is, he cannot bake a cookie in 1/x seconds when x > 1.\nWhen he choose to eat the cookies, he must eat all of them; he cannot choose to eat only part of them.\nIt takes him A seconds to eat the cookies regardless of how many, during which no cookies can be baked.\n\nHe wants to give N cookies to Grandma.\nFind the shortest time needed to produce at least N cookies not yet eaten.\n\nConstraints\n\n1≦N≦10^{12}\n\n0≦A≦10^{12}\n\nA is an integer.\n\nPartial Score\n\n500 points will be awarded for passing the test set satisfying N≦10^6 and A≦10^6.\n\nAdditional 500 points will be awarded for passing the test set without additional constraints.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN A\n\nOutput\n\nPrint the shortest time needed to produce at least N cookies not yet eaten.\n\nSample Input 1\n\n8 1\n\nSample Output 1\n\n7\n\nIt is possible to produce 8 cookies in 7 seconds, as follows:\n\nAfter 1 second: 1 cookie is done.\n\nAfter 2 seconds: 1 more cookie is done, totaling 2. Now, Rng starts eating those 2 cookies.\n\nAfter 3 seconds: He finishes eating the cookies, and he can now bake 2 cookies per second.\n\nAfter 4 seconds: 2 cookies are done.\n\nAfter 5 seconds: 2 more cookies are done, totaling 4.\n\nAfter 6 seconds: 2 more cookies are done, totaling 6.\n\nAfter 7 seconds: 2 more cookies are done, totaling 8.\n\nSample Input 2\n\n1000000000000 1000000000000\n\nSample Output 2\n\n1000000000000", "sample_input": "8 1\n"}, "reference_outputs": ["7\n"], "source_document_id": "p03913", "source_text": "Score : 1000 points\n\nProblem Statement\n\nRng is baking cookies.\n\nInitially, he can bake one cookie per second.\n\nHe can also eat the cookies baked by himself.\nWhen there are x cookies not yet eaten, he can choose to eat all those cookies. After he finishes eating those cookies, the number of cookies he can bake per second becomes x. Note that a cookie always needs to be baked for 1 second, that is, he cannot bake a cookie in 1/x seconds when x > 1.\nWhen he choose to eat the cookies, he must eat all of them; he cannot choose to eat only part of them.\nIt takes him A seconds to eat the cookies regardless of how many, during which no cookies can be baked.\n\nHe wants to give N cookies to Grandma.\nFind the shortest time needed to produce at least N cookies not yet eaten.\n\nConstraints\n\n1≦N≦10^{12}\n\n0≦A≦10^{12}\n\nA is an integer.\n\nPartial Score\n\n500 points will be awarded for passing the test set satisfying N≦10^6 and A≦10^6.\n\nAdditional 500 points will be awarded for passing the test set without additional constraints.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN A\n\nOutput\n\nPrint the shortest time needed to produce at least N cookies not yet eaten.\n\nSample Input 1\n\n8 1\n\nSample Output 1\n\n7\n\nIt is possible to produce 8 cookies in 7 seconds, as follows:\n\nAfter 1 second: 1 cookie is done.\n\nAfter 2 seconds: 1 more cookie is done, totaling 2. Now, Rng starts eating those 2 cookies.\n\nAfter 3 seconds: He finishes eating the cookies, and he can now bake 2 cookies per second.\n\nAfter 4 seconds: 2 cookies are done.\n\nAfter 5 seconds: 2 more cookies are done, totaling 4.\n\nAfter 6 seconds: 2 more cookies are done, totaling 6.\n\nAfter 7 seconds: 2 more cookies are done, totaling 8.\n\nSample Input 2\n\n1000000000000 1000000000000\n\nSample Output 2\n\n1000000000000", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1535, "cpu_time_ms": 432, "memory_kb": 351872}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s977700574", "group_id": "codeNet:p03929", "input_text": "#include <iostream>\n\nusing namespace std;\n\nint main() {\n    int n, k;\n    cin >> n >> k;\n\n    long long ans = 0LL;\n    for (int i = 1; i <= n - 3 + 1; ++i) {\n        for (int j = 1; j <= 5; ++j) {\n            if ((8 * i + 9 * j + 9) % 11 == k) ans++;\n        }\n    }\n\n    cout << ans << endl;\n}\n", "language": "C++", "metadata": {"date": 1527715057, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03929.html", "problem_id": "p03929", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03929/input.txt", "sample_output_relpath": "derived/input_output/data/p03929/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03929/C++/s977700574.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s977700574", "user_id": "u830419090"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <iostream>\n\nusing namespace std;\n\nint main() {\n    int n, k;\n    cin >> n >> k;\n\n    long long ans = 0LL;\n    for (int i = 1; i <= n - 3 + 1; ++i) {\n        for (int j = 1; j <= 5; ++j) {\n            if ((8 * i + 9 * j + 9) % 11 == k) ans++;\n        }\n    }\n\n    cout << ans << endl;\n}\n", "problem_context": "Max Score: $250$ Points\n\nProblem Statement\n\nSnuke has a very long calendar. It has a grid with $n$ rows and $7$ columns. One day, he noticed that calendar has a following regularity.\n\nThe cell at the $i$-th row and $j$-th column contains the integer $7i+j-7$.\n\nA good sub-grid is a $3 \\times 3$ sub-grid and the sum of integers in this sub-grid mod $11$ is $k$.\n\nHow many good sub-grid are there? Write a program and help him.\n\nInput\n\nThe input is given from standard input in the following format.\n\n$n \\quad k$\n\nOutput\n\nPrint the number of good sub-grid. If there are no solution exists, print 0.\n\nConstraints\n\n$1 \\le n \\le 10^9$\n\n$0 \\le k \\le 10$\n\nSubtasks\n\nSubtask 1 [ $150$ points ]\n\nThe testcase in the subtask satisfies $1 \\le n \\le 100$.\n\nSubtask 2 [ $100$ points ]\n\nThere are no additional constraints.\n\nSample Input 1\n\n7 7\n\nSample Output 1\n\n2\n\nIn this case, the calendar likes this matrix.\n\nSun.\n\nMon.\n\nTue.\n\nWed.\n\nThu.\n\nFri.\n\nSat.\n\nWeek 1\n\n1\n\n2\n\n3\n\n4\n\n5\n\n6\n\n7\n\nWeek 2\n\n8\n\n9\n\n10\n\n11\n\n12\n\n13\n\n14\n\nWeek 3\n\n15\n\n16\n\n17\n\n18\n\n19\n\n20\n\n21\n\nWeek 4\n\n22\n\n23\n\n24\n\n25\n\n26\n\n27\n\n28\n\nWeek 5\n\n29\n\n30\n\n31\n\n32\n\n33\n\n34\n\n35\n\nWeek 6\n\n36\n\n37\n\n38\n\n39\n\n40\n\n41\n\n42\n\nWeek 7\n\n43\n\n44\n\n45\n\n46\n\n47\n\n48\n\n49\n\nThe cell at $i$-th row and $j$-th column is denoted $(i, j)$.\n\nIf upper-left is $(1, 5)$, the sum of integers is $5+6+7+12+13+14+19+20+21=117$.\n\nIf upper-left is $(3, 2)$, the sum of integers is $16+17+18+23+24+25+30+31+32=216$.\n\nTherefore, there are 2 good sub-grids.\n\nSample Input 2\n\n6 0\n\nSample Output 2\n\n2\n\nIf upper-left is $(1, 3)$ or $(4, 4)$, it is a good sub-grid.\n\nSample Input 3\n\n18 10", "sample_input": "7 7\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03929", "source_text": "Max Score: $250$ Points\n\nProblem Statement\n\nSnuke has a very long calendar. It has a grid with $n$ rows and $7$ columns. One day, he noticed that calendar has a following regularity.\n\nThe cell at the $i$-th row and $j$-th column contains the integer $7i+j-7$.\n\nA good sub-grid is a $3 \\times 3$ sub-grid and the sum of integers in this sub-grid mod $11$ is $k$.\n\nHow many good sub-grid are there? Write a program and help him.\n\nInput\n\nThe input is given from standard input in the following format.\n\n$n \\quad k$\n\nOutput\n\nPrint the number of good sub-grid. If there are no solution exists, print 0.\n\nConstraints\n\n$1 \\le n \\le 10^9$\n\n$0 \\le k \\le 10$\n\nSubtasks\n\nSubtask 1 [ $150$ points ]\n\nThe testcase in the subtask satisfies $1 \\le n \\le 100$.\n\nSubtask 2 [ $100$ points ]\n\nThere are no additional constraints.\n\nSample Input 1\n\n7 7\n\nSample Output 1\n\n2\n\nIn this case, the calendar likes this matrix.\n\nSun.\n\nMon.\n\nTue.\n\nWed.\n\nThu.\n\nFri.\n\nSat.\n\nWeek 1\n\n1\n\n2\n\n3\n\n4\n\n5\n\n6\n\n7\n\nWeek 2\n\n8\n\n9\n\n10\n\n11\n\n12\n\n13\n\n14\n\nWeek 3\n\n15\n\n16\n\n17\n\n18\n\n19\n\n20\n\n21\n\nWeek 4\n\n22\n\n23\n\n24\n\n25\n\n26\n\n27\n\n28\n\nWeek 5\n\n29\n\n30\n\n31\n\n32\n\n33\n\n34\n\n35\n\nWeek 6\n\n36\n\n37\n\n38\n\n39\n\n40\n\n41\n\n42\n\nWeek 7\n\n43\n\n44\n\n45\n\n46\n\n47\n\n48\n\n49\n\nThe cell at $i$-th row and $j$-th column is denoted $(i, j)$.\n\nIf upper-left is $(1, 5)$, the sum of integers is $5+6+7+12+13+14+19+20+21=117$.\n\nIf upper-left is $(3, 2)$, the sum of integers is $16+17+18+23+24+25+30+31+32=216$.\n\nTherefore, there are 2 good sub-grids.\n\nSample Input 2\n\n6 0\n\nSample Output 2\n\n2\n\nIf upper-left is $(1, 3)$ or $(4, 4)$, it is a good sub-grid.\n\nSample Input 3\n\n18 10", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 295, "cpu_time_ms": 1055, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s266816747", "group_id": "codeNet:p03942", "input_text": "#include \"bits/stdc++.h\"\nusing namespace std;\n\nstatic const int INF = 0x3f3f3f3f;\n\nint main() {\n        int n;\n        scanf(\"%d\", &n);\n        string s, t;\n        cin >> s >> t;\n        if (s == t) return !puts(\"0\");\n        if (s[0] != t[0]) return !puts(\"-1\");\n        vector<int> a, b;\n        b.push_back(0);\n        a.push_back(0);\n        set<int> check;\n        for (int i = 1; i < n; i ++) if (t[i] != t[i - 1]) b.push_back(i);\n        for (int i = 1; i < b.size(); i ++) {\n                int p = b[i];\n                while (p > 0 && s[p] != t[b[i]]) p --;\n                if (p == 0) return !puts(\"-1\");\n                if (check.count(p)) return !puts(\"-1\");\n                check.insert(p);\n                a.push_back(p);\n        }\n        int lb = -1, ub = INF;\n        while (ub - lb > 1) {\n                int s = (lb + ub) / 2;\n                bool ok = true;\n                for (int i = 0; i < b.size(); i ++) {\n                        if (i + s < a.size()) ok &= a[i + s] - s >= b[i];\n                }\n                if (ok) ub = s;\n                else lb = s;\n        }\n        printf(\"%d\\n\", ub + 1);\n        return 0;\n}\n", "language": "C++", "metadata": {"date": 1509643892, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03942.html", "problem_id": "p03942", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03942/input.txt", "sample_output_relpath": "derived/input_output/data/p03942/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03942/C++/s266816747.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s266816747", "user_id": "u987564901"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include \"bits/stdc++.h\"\nusing namespace std;\n\nstatic const int INF = 0x3f3f3f3f;\n\nint main() {\n        int n;\n        scanf(\"%d\", &n);\n        string s, t;\n        cin >> s >> t;\n        if (s == t) return !puts(\"0\");\n        if (s[0] != t[0]) return !puts(\"-1\");\n        vector<int> a, b;\n        b.push_back(0);\n        a.push_back(0);\n        set<int> check;\n        for (int i = 1; i < n; i ++) if (t[i] != t[i - 1]) b.push_back(i);\n        for (int i = 1; i < b.size(); i ++) {\n                int p = b[i];\n                while (p > 0 && s[p] != t[b[i]]) p --;\n                if (p == 0) return !puts(\"-1\");\n                if (check.count(p)) return !puts(\"-1\");\n                check.insert(p);\n                a.push_back(p);\n        }\n        int lb = -1, ub = INF;\n        while (ub - lb > 1) {\n                int s = (lb + ub) / 2;\n                bool ok = true;\n                for (int i = 0; i < b.size(); i ++) {\n                        if (i + s < a.size()) ok &= a[i + s] - s >= b[i];\n                }\n                if (ok) ub = s;\n                else lb = s;\n        }\n        printf(\"%d\\n\", ub + 1);\n        return 0;\n}\n", "problem_context": "Score : 1500 points\n\nProblem Statement\n\n#nck {\nwidth: 30px;\nheight: auto;\n}\n\nShik's job is very boring. At day 0, his boss gives him a string S_0 of length N which consists of only lowercase English letters. In the i-th day after day 0, Shik's job is to copy the string S_{i-1} to a string S_i. We denote the j-th letter of S_i as S_i[j].\n\nShik is inexperienced in this job. In each day, when he is copying letters one by one from the first letter to the last letter, he would make mistakes. That is, he sometimes accidentally writes down the same letter that he wrote previously instead of the correct one. More specifically, S_i[j] is equal to either S_{i-1}[j] or S_{i}[j-1]. (Note that S_i[1] always equals to S_{i-1}[1].)\n\nYou are given the string S_0 and another string T.\nPlease determine the smallest integer i such that S_i could be equal to T. If no such i exists, please print -1.\n\nConstraints\n\n1 \\leq N \\leq 1,000,000\n\nThe lengths of S_0 and T are both N.\n\nBoth S_0 and T consist of lowercase English letters.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nS_0\nT\n\nOutput\n\nPrint the smallest integer i such that S_i could be equal to T. If no such i exists, print -1 instead.\n\nSample Input 1\n\n5\nabcde\naaacc\n\nSample Output 1\n\n2\n\nS_0 = abcde, S_1 = aaccc and S_2 = aaacc is a possible sequence such that S_2 = T.\n\nSample Input 2\n\n5\nabcde\nabcde\n\nSample Output 2\n\n0\n\nSample Input 3\n\n4\nacaa\naaca\n\nSample Output 3\n\n2\n\nSample Input 4\n\n5\nabcde\nbbbbb\n\nSample Output 4\n\n-1", "sample_input": "5\nabcde\naaacc\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03942", "source_text": "Score : 1500 points\n\nProblem Statement\n\n#nck {\nwidth: 30px;\nheight: auto;\n}\n\nShik's job is very boring. At day 0, his boss gives him a string S_0 of length N which consists of only lowercase English letters. In the i-th day after day 0, Shik's job is to copy the string S_{i-1} to a string S_i. We denote the j-th letter of S_i as S_i[j].\n\nShik is inexperienced in this job. In each day, when he is copying letters one by one from the first letter to the last letter, he would make mistakes. That is, he sometimes accidentally writes down the same letter that he wrote previously instead of the correct one. More specifically, S_i[j] is equal to either S_{i-1}[j] or S_{i}[j-1]. (Note that S_i[1] always equals to S_{i-1}[1].)\n\nYou are given the string S_0 and another string T.\nPlease determine the smallest integer i such that S_i could be equal to T. If no such i exists, please print -1.\n\nConstraints\n\n1 \\leq N \\leq 1,000,000\n\nThe lengths of S_0 and T are both N.\n\nBoth S_0 and T consist of lowercase English letters.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nS_0\nT\n\nOutput\n\nPrint the smallest integer i such that S_i could be equal to T. If no such i exists, print -1 instead.\n\nSample Input 1\n\n5\nabcde\naaacc\n\nSample Output 1\n\n2\n\nS_0 = abcde, S_1 = aaccc and S_2 = aaacc is a possible sequence such that S_2 = T.\n\nSample Input 2\n\n5\nabcde\nabcde\n\nSample Output 2\n\n0\n\nSample Input 3\n\n4\nacaa\naaca\n\nSample Output 3\n\n2\n\nSample Input 4\n\n5\nabcde\nbbbbb\n\nSample Output 4\n\n-1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1149, "cpu_time_ms": 619, "memory_kb": 56956}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s987789911", "group_id": "codeNet:p03944", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n    int v_x, v_y, p;\n    cin>>v_x>>v_y>>p;\n    int x[p], y[p], c[p], xf = 0, xl = v_x, yf = 0, yl = v_y, ans;\n\n    for(int i = 0; i < p; i++)\n    {\n        cin>>x[i]>>y[i]>>c[i];\n\n        if(c[i] == 1)\n            xf = max(x[i], xf);\n\n        else if(c[i] == 2)\n            xl = min(x[i], xl);\n\n        else if(c[i] == 3)\n            yf = max(y[i], yf);\n\n        else if(c[i] == 4)\n            yl = min(y[i], yl);\n    }\n    ans = (xl - xf) * (yl - yf);\n    if(ans < 0)\n        ans = 0;\n    cout<<ans<<endl;\n\n}\n", "language": "C++", "metadata": {"date": 1581761337, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03944.html", "problem_id": "p03944", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03944/input.txt", "sample_output_relpath": "derived/input_output/data/p03944/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03944/C++/s987789911.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s987789911", "user_id": "u353919145"}, "prompt_components": {"gold_output": "9\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n    int v_x, v_y, p;\n    cin>>v_x>>v_y>>p;\n    int x[p], y[p], c[p], xf = 0, xl = v_x, yf = 0, yl = v_y, ans;\n\n    for(int i = 0; i < p; i++)\n    {\n        cin>>x[i]>>y[i]>>c[i];\n\n        if(c[i] == 1)\n            xf = max(x[i], xf);\n\n        else if(c[i] == 2)\n            xl = min(x[i], xl);\n\n        else if(c[i] == 3)\n            yf = max(y[i], yf);\n\n        else if(c[i] == 4)\n            yl = min(y[i], yl);\n    }\n    ans = (xl - xf) * (yl - yf);\n    if(ans < 0)\n        ans = 0;\n    cout<<ans<<endl;\n\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nThere is a rectangle in the xy-plane, with its lower left corner at (0, 0) and its upper right corner at (W, H). Each of its sides is parallel to the x-axis or y-axis. Initially, the whole region within the rectangle is painted white.\n\nSnuke plotted N points into the rectangle. The coordinate of the i-th (1 ≦ i ≦ N) point was (x_i, y_i).\n\nThen, he created an integer sequence a of length N, and for each 1 ≦ i ≦ N, he painted some region within the rectangle black, as follows:\n\nIf a_i = 1, he painted the region satisfying x < x_i within the rectangle.\n\nIf a_i = 2, he painted the region satisfying x > x_i within the rectangle.\n\nIf a_i = 3, he painted the region satisfying y < y_i within the rectangle.\n\nIf a_i = 4, he painted the region satisfying y > y_i within the rectangle.\n\nFind the area of the white region within the rectangle after he finished painting.\n\nConstraints\n\n1 ≦ W, H ≦ 100\n\n1 ≦ N ≦ 100\n\n0 ≦ x_i ≦ W (1 ≦ i ≦ N)\n\n0 ≦ y_i ≦ H (1 ≦ i ≦ N)\n\nW, H (21:32, added), x_i and y_i are integers.\n\na_i (1 ≦ i ≦ N) is 1, 2, 3 or 4.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nW H N\nx_1 y_1 a_1\nx_2 y_2 a_2\n:\nx_N y_N a_N\n\nOutput\n\nPrint the area of the white region within the rectangle after Snuke finished painting.\n\nSample Input 1\n\n5 4 2\n2 1 1\n3 3 4\n\nSample Output 1\n\n9\n\nThe figure below shows the rectangle before Snuke starts painting.\n\nFirst, as (x_1, y_1) = (2, 1) and a_1 = 1, he paints the region satisfying x < 2 within the rectangle:\n\nThen, as (x_2, y_2) = (3, 3) and a_2 = 4, he paints the region satisfying y > 3 within the rectangle:\n\nNow, the area of the white region within the rectangle is 9.\n\nSample Input 2\n\n5 4 3\n2 1 1\n3 3 4\n1 4 2\n\nSample Output 2\n\n0\n\nIt is possible that the whole region within the rectangle is painted black.\n\nSample Input 3\n\n10 10 5\n1 6 1\n4 1 3\n6 9 4\n9 4 2\n3 1 3\n\nSample Output 3\n\n64", "sample_input": "5 4 2\n2 1 1\n3 3 4\n"}, "reference_outputs": ["9\n"], "source_document_id": "p03944", "source_text": "Score : 200 points\n\nProblem Statement\n\nThere is a rectangle in the xy-plane, with its lower left corner at (0, 0) and its upper right corner at (W, H). Each of its sides is parallel to the x-axis or y-axis. Initially, the whole region within the rectangle is painted white.\n\nSnuke plotted N points into the rectangle. The coordinate of the i-th (1 ≦ i ≦ N) point was (x_i, y_i).\n\nThen, he created an integer sequence a of length N, and for each 1 ≦ i ≦ N, he painted some region within the rectangle black, as follows:\n\nIf a_i = 1, he painted the region satisfying x < x_i within the rectangle.\n\nIf a_i = 2, he painted the region satisfying x > x_i within the rectangle.\n\nIf a_i = 3, he painted the region satisfying y < y_i within the rectangle.\n\nIf a_i = 4, he painted the region satisfying y > y_i within the rectangle.\n\nFind the area of the white region within the rectangle after he finished painting.\n\nConstraints\n\n1 ≦ W, H ≦ 100\n\n1 ≦ N ≦ 100\n\n0 ≦ x_i ≦ W (1 ≦ i ≦ N)\n\n0 ≦ y_i ≦ H (1 ≦ i ≦ N)\n\nW, H (21:32, added), x_i and y_i are integers.\n\na_i (1 ≦ i ≦ N) is 1, 2, 3 or 4.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nW H N\nx_1 y_1 a_1\nx_2 y_2 a_2\n:\nx_N y_N a_N\n\nOutput\n\nPrint the area of the white region within the rectangle after Snuke finished painting.\n\nSample Input 1\n\n5 4 2\n2 1 1\n3 3 4\n\nSample Output 1\n\n9\n\nThe figure below shows the rectangle before Snuke starts painting.\n\nFirst, as (x_1, y_1) = (2, 1) and a_1 = 1, he paints the region satisfying x < 2 within the rectangle:\n\nThen, as (x_2, y_2) = (3, 3) and a_2 = 4, he paints the region satisfying y > 3 within the rectangle:\n\nNow, the area of the white region within the rectangle is 9.\n\nSample Input 2\n\n5 4 3\n2 1 1\n3 3 4\n1 4 2\n\nSample Output 2\n\n0\n\nIt is possible that the whole region within the rectangle is painted black.\n\nSample Input 3\n\n10 10 5\n1 6 1\n4 1 3\n6 9 4\n9 4 2\n3 1 3\n\nSample Output 3\n\n64", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 569, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s051277339", "group_id": "codeNet:p03946", "input_text": "#include <iostream>\nusing namespace std;\n\nint main(){\n\tint n, t, count = 0, diff = 0;\n\tcin >> n >> t;\n\tint a[n];\n\tfor(int i = 0; i < n; i++) cin >> a[i];\n\tfor(int i = 0; i < n; i++) for(int j = i + 1; j < n; j++){\n\t\tif(a[j] - a[i] > diff){\n\t\t\tdiff = a[j] - a[i];\n\t\t\tcount = 1;\n\t\t}else if(a[j] - a[i] == diff) count++;\n\t}\n\tcout << count << endl;\n}", "language": "C++", "metadata": {"date": 1478488452, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03946.html", "problem_id": "p03946", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03946/input.txt", "sample_output_relpath": "derived/input_output/data/p03946/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03946/C++/s051277339.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s051277339", "user_id": "u017167684"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <iostream>\nusing namespace std;\n\nint main(){\n\tint n, t, count = 0, diff = 0;\n\tcin >> n >> t;\n\tint a[n];\n\tfor(int i = 0; i < n; i++) cin >> a[i];\n\tfor(int i = 0; i < n; i++) for(int j = i + 1; j < n; j++){\n\t\tif(a[j] - a[i] > diff){\n\t\t\tdiff = a[j] - a[i];\n\t\t\tcount = 1;\n\t\t}else if(a[j] - a[i] == diff) count++;\n\t}\n\tcout << count << endl;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nThere are N towns located in a line, conveniently numbered 1 through N. Takahashi the merchant is going on a travel from town 1 to town N, buying and selling apples.\n\nTakahashi will begin the travel at town 1, with no apple in his possession. The actions that can be performed during the travel are as follows:\n\nMove: When at town i (i < N), move to town i + 1.\n\nMerchandise: Buy or sell an arbitrary number of apples at the current town. Here, it is assumed that one apple can always be bought and sold for A_i yen (the currency of Japan) at town i (1 ≦ i ≦ N), where A_i are distinct integers. Also, you can assume that he has an infinite supply of money.\n\nFor some reason, there is a constraint on merchandising apple during the travel: the sum of the number of apples bought and the number of apples sold during the whole travel, must be at most T. (Note that a single apple can be counted in both.)\n\nDuring the travel, Takahashi will perform actions so that the profit of the travel is maximized. Here, the profit of the travel is the amount of money that is gained by selling apples, minus the amount of money that is spent on buying apples. Note that we are not interested in apples in his possession at the end of the travel.\n\nAoki, a business rival of Takahashi, wants to trouble Takahashi by manipulating the market price of apples. Prior to the beginning of Takahashi's travel, Aoki can change A_i into another arbitrary non-negative integer A_i' for any town i, any number of times. The cost of performing this operation is |A_i - A_i'|. After performing this operation, different towns may have equal values of A_i.\n\nAoki's objective is to decrease Takahashi's expected profit by at least 1 yen. Find the minimum total cost to achieve it. You may assume that Takahashi's expected profit is initially at least 1 yen.\n\nConstraints\n\n1 ≦ N ≦ 10^5\n\n1 ≦ A_i ≦ 10^9 (1 ≦ i ≦ N)\n\nA_i are distinct.\n\n2 ≦ T ≦ 10^9\n\nIn the initial state, Takahashi's expected profit is at least 1 yen.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN T\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the minimum total cost to decrease Takahashi's expected profit by at least 1 yen.\n\nSample Input 1\n\n3 2\n100 50 200\n\nSample Output 1\n\n1\n\nIn the initial state, Takahashi can achieve the maximum profit of 150 yen as follows:\n\nMove from town 1 to town 2.\n\nBuy one apple for 50 yen at town 2.\n\nMove from town 2 to town 3.\n\nSell one apple for 200 yen at town 3.\n\nIf, for example, Aoki changes the price of an apple at town 2 from 50 yen to 51 yen, Takahashi will not be able to achieve the profit of 150 yen. The cost of performing this operation is 1, thus the answer is 1.\n\nThere are other ways to decrease Takahashi's expected profit, such as changing the price of an apple at town 3 from 200 yen to 199 yen.\n\nSample Input 2\n\n5 8\n50 30 40 10 20\n\nSample Output 2\n\n2\n\nSample Input 3\n\n10 100\n7 10 4 5 9 3 6 8 2 1\n\nSample Output 3\n\n2", "sample_input": "3 2\n100 50 200\n"}, "reference_outputs": ["1\n"], "source_document_id": "p03946", "source_text": "Score : 400 points\n\nProblem Statement\n\nThere are N towns located in a line, conveniently numbered 1 through N. Takahashi the merchant is going on a travel from town 1 to town N, buying and selling apples.\n\nTakahashi will begin the travel at town 1, with no apple in his possession. The actions that can be performed during the travel are as follows:\n\nMove: When at town i (i < N), move to town i + 1.\n\nMerchandise: Buy or sell an arbitrary number of apples at the current town. Here, it is assumed that one apple can always be bought and sold for A_i yen (the currency of Japan) at town i (1 ≦ i ≦ N), where A_i are distinct integers. Also, you can assume that he has an infinite supply of money.\n\nFor some reason, there is a constraint on merchandising apple during the travel: the sum of the number of apples bought and the number of apples sold during the whole travel, must be at most T. (Note that a single apple can be counted in both.)\n\nDuring the travel, Takahashi will perform actions so that the profit of the travel is maximized. Here, the profit of the travel is the amount of money that is gained by selling apples, minus the amount of money that is spent on buying apples. Note that we are not interested in apples in his possession at the end of the travel.\n\nAoki, a business rival of Takahashi, wants to trouble Takahashi by manipulating the market price of apples. Prior to the beginning of Takahashi's travel, Aoki can change A_i into another arbitrary non-negative integer A_i' for any town i, any number of times. The cost of performing this operation is |A_i - A_i'|. After performing this operation, different towns may have equal values of A_i.\n\nAoki's objective is to decrease Takahashi's expected profit by at least 1 yen. Find the minimum total cost to achieve it. You may assume that Takahashi's expected profit is initially at least 1 yen.\n\nConstraints\n\n1 ≦ N ≦ 10^5\n\n1 ≦ A_i ≦ 10^9 (1 ≦ i ≦ N)\n\nA_i are distinct.\n\n2 ≦ T ≦ 10^9\n\nIn the initial state, Takahashi's expected profit is at least 1 yen.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN T\nA_1 A_2 ... A_N\n\nOutput\n\nPrint the minimum total cost to decrease Takahashi's expected profit by at least 1 yen.\n\nSample Input 1\n\n3 2\n100 50 200\n\nSample Output 1\n\n1\n\nIn the initial state, Takahashi can achieve the maximum profit of 150 yen as follows:\n\nMove from town 1 to town 2.\n\nBuy one apple for 50 yen at town 2.\n\nMove from town 2 to town 3.\n\nSell one apple for 200 yen at town 3.\n\nIf, for example, Aoki changes the price of an apple at town 2 from 50 yen to 51 yen, Takahashi will not be able to achieve the profit of 150 yen. The cost of performing this operation is 1, thus the answer is 1.\n\nThere are other ways to decrease Takahashi's expected profit, such as changing the price of an apple at town 3 from 200 yen to 199 yen.\n\nSample Input 2\n\n5 8\n50 30 40 10 20\n\nSample Output 2\n\n2\n\nSample Input 3\n\n10 100\n7 10 4 5 9 3 6 8 2 1\n\nSample Output 3\n\n2", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 346, "cpu_time_ms": 2102, "memory_kb": 640}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s025296999", "group_id": "codeNet:p03947", "input_text": "#include <bits/stdc++.h>\n#define MOD 1000000007LL\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> P;\n\nstring str;\n\nint main(void){\n\tcin >> str;\n\tint cnt=0;\n\tfor(int i=1;i<str.size();i++){\n\t\tif(str[i]!=str[i-1])cnt++;\n\t}\n\tprintf(\"%d\\n\",cnt);\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1518051767, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03947.html", "problem_id": "p03947", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03947/input.txt", "sample_output_relpath": "derived/input_output/data/p03947/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03947/C++/s025296999.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s025296999", "user_id": "u854869949"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define MOD 1000000007LL\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> P;\n\nstring str;\n\nint main(void){\n\tcin >> str;\n\tint cnt=0;\n\tfor(int i=1;i<str.size();i++){\n\t\tif(str[i]!=str[i-1])cnt++;\n\t}\n\tprintf(\"%d\\n\",cnt);\n\treturn 0;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nTwo foxes Jiro and Saburo are playing a game called 1D Reversi. This game is played on a board, using black and white stones. On the board, stones are placed in a row, and each player places a new stone to either end of the row. Similarly to the original game of Reversi, when a white stone is placed, all black stones between the new white stone and another white stone, turn into white stones, and vice versa.\n\nIn the middle of a game, something came up and Saburo has to leave the game. The state of the board at this point is described by a string S. There are |S| (the length of S) stones on the board, and each character in S represents the color of the i-th (1 ≦ i ≦ |S|) stone from the left. If the i-th character in S is B, it means that the color of the corresponding stone on the board is black. Similarly, if the i-th character in S is W, it means that the color of the corresponding stone is white.\n\nJiro wants all stones on the board to be of the same color. For this purpose, he will place new stones on the board according to the rules. Find the minimum number of new stones that he needs to place.\n\nConstraints\n\n1 ≦ |S| ≦ 10^5\n\nEach character in S is B or W.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the minimum number of new stones that Jiro needs to place for his purpose.\n\nSample Input 1\n\nBBBWW\n\nSample Output 1\n\n1\n\nBy placing a new black stone to the right end of the row of stones, all white stones will become black. Also, by placing a new white stone to the left end of the row of stones, all black stones will become white.\n\nIn either way, Jiro's purpose can be achieved by placing one stone.\n\nSample Input 2\n\nWWWWWW\n\nSample Output 2\n\n0\n\nIf all stones are already of the same color, no new stone is necessary.\n\nSample Input 3\n\nWBWBWBWBWB\n\nSample Output 3\n\n9", "sample_input": "BBBWW\n"}, "reference_outputs": ["1\n"], "source_document_id": "p03947", "source_text": "Score : 300 points\n\nProblem Statement\n\nTwo foxes Jiro and Saburo are playing a game called 1D Reversi. This game is played on a board, using black and white stones. On the board, stones are placed in a row, and each player places a new stone to either end of the row. Similarly to the original game of Reversi, when a white stone is placed, all black stones between the new white stone and another white stone, turn into white stones, and vice versa.\n\nIn the middle of a game, something came up and Saburo has to leave the game. The state of the board at this point is described by a string S. There are |S| (the length of S) stones on the board, and each character in S represents the color of the i-th (1 ≦ i ≦ |S|) stone from the left. If the i-th character in S is B, it means that the color of the corresponding stone on the board is black. Similarly, if the i-th character in S is W, it means that the color of the corresponding stone is white.\n\nJiro wants all stones on the board to be of the same color. For this purpose, he will place new stones on the board according to the rules. Find the minimum number of new stones that he needs to place.\n\nConstraints\n\n1 ≦ |S| ≦ 10^5\n\nEach character in S is B or W.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nS\n\nOutput\n\nPrint the minimum number of new stones that Jiro needs to place for his purpose.\n\nSample Input 1\n\nBBBWW\n\nSample Output 1\n\n1\n\nBy placing a new black stone to the right end of the row of stones, all white stones will become black. Also, by placing a new white stone to the left end of the row of stones, all black stones will become white.\n\nIn either way, Jiro's purpose can be achieved by placing one stone.\n\nSample Input 2\n\nWWWWWW\n\nSample Output 2\n\n0\n\nIf all stones are already of the same color, no new stone is necessary.\n\nSample Input 3\n\nWBWBWBWBWB\n\nSample Output 3\n\n9", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 270, "cpu_time_ms": 4, "memory_kb": 512}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s350175247", "group_id": "codeNet:p03951", "input_text": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<math.h>\n#include<queue>\n#include<stack>\n#include<string>\n\nusing namespace std;\nconst int INF = 1<<30;\ntypedef long long int ll;\n\nint main(){\n\tint n;cin>>n;\n\tstring s, t;cin>>s>>t;\n\tint ans=int(s.size()+t.size());\n\tfor(int i=0;i<n;i++){\n\t\tstring tmp = s.substr(i, n-i);\n\t\tbool match=true;\n\t\tfor(int j=0;j<n-i;j++){\n\t\t\tif(t[j]!=tmp[j]){match=false;break;}\n\t\t}\n\t\tif(match){ans=int(t.size())+i;break;}\n\t}\n\tcout<<ans<<endl;\n}\n", "language": "C++", "metadata": {"date": 1559245386, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03951.html", "problem_id": "p03951", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03951/input.txt", "sample_output_relpath": "derived/input_output/data/p03951/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03951/C++/s350175247.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s350175247", "user_id": "u630664279"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<math.h>\n#include<queue>\n#include<stack>\n#include<string>\n\nusing namespace std;\nconst int INF = 1<<30;\ntypedef long long int ll;\n\nint main(){\n\tint n;cin>>n;\n\tstring s, t;cin>>s>>t;\n\tint ans=int(s.size()+t.size());\n\tfor(int i=0;i<n;i++){\n\t\tstring tmp = s.substr(i, n-i);\n\t\tbool match=true;\n\t\tfor(int j=0;j<n-i;j++){\n\t\t\tif(t[j]!=tmp[j]){match=false;break;}\n\t\t}\n\t\tif(match){ans=int(t.size())+i;break;}\n\t}\n\tcout<<ans<<endl;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nSnuke is interested in strings that satisfy the following conditions:\n\nThe length of the string is at least N.\n\nThe first N characters equal to the string s.\n\nThe last N characters equal to the string t.\n\nFind the length of the shortest string that satisfies the conditions.\n\nConstraints\n\n1≤N≤100\n\nThe lengths of s and t are both N.\n\ns and t consist of lowercase English letters.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\ns\nt\n\nOutput\n\nPrint the length of the shortest string that satisfies the conditions.\n\nSample Input 1\n\n3\nabc\ncde\n\nSample Output 1\n\n5\n\nThe shortest string is abcde.\n\nSample Input 2\n\n1\na\nz\n\nSample Output 2\n\n2\n\nThe shortest string is az.\n\nSample Input 3\n\n4\nexpr\nexpr\n\nSample Output 3\n\n4\n\nThe shortest string is expr.", "sample_input": "3\nabc\ncde\n"}, "reference_outputs": ["5\n"], "source_document_id": "p03951", "source_text": "Score : 200 points\n\nProblem Statement\n\nSnuke is interested in strings that satisfy the following conditions:\n\nThe length of the string is at least N.\n\nThe first N characters equal to the string s.\n\nThe last N characters equal to the string t.\n\nFind the length of the shortest string that satisfies the conditions.\n\nConstraints\n\n1≤N≤100\n\nThe lengths of s and t are both N.\n\ns and t consist of lowercase English letters.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\ns\nt\n\nOutput\n\nPrint the length of the shortest string that satisfies the conditions.\n\nSample Input 1\n\n3\nabc\ncde\n\nSample Output 1\n\n5\n\nThe shortest string is abcde.\n\nSample Input 2\n\n1\na\nz\n\nSample Output 2\n\n2\n\nThe shortest string is az.\n\nSample Input 3\n\n4\nexpr\nexpr\n\nSample Output 3\n\n4\n\nThe shortest string is expr.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 486, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s096265409", "group_id": "codeNet:p03952", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll,ll> P;\n#define rep(i,n) for(int i=0;i<(int)n;i++)\nconst ll INF = (1LL<<31)-1;\n\n\nint main(){\n    int N, x; cin >> N >> x;\n    vector<int> X(2*N-1,INF);\n\n    if(x==1 || x==2*N-1){ cout << \"No\" << endl;}\n    else {\n        X[N-2] = x-1; X[N-1] = x; X[N] = x+1;\n        set<int> num;\n        for(int i=1;i<=2*N-1;i++){\n            if(abs(x-i)>1) num.insert(i);\n        }\n        rep(i,2*N-1){\n            int xi = *num.begin();\n            if(X[i]==INF){\n                X[i] = xi;\n                num.erase(xi);\n            }\n        }\n        cout << \"Yes\" << endl;\n        rep(i,2*N-1) cout << X[i] << endl;\n    }\n\n}", "language": "C++", "metadata": {"date": 1598130411, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03952.html", "problem_id": "p03952", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03952/input.txt", "sample_output_relpath": "derived/input_output/data/p03952/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03952/C++/s096265409.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s096265409", "user_id": "u123896133"}, "prompt_components": {"gold_output": "Yes\n1\n6\n3\n7\n4\n5\n2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll,ll> P;\n#define rep(i,n) for(int i=0;i<(int)n;i++)\nconst ll INF = (1LL<<31)-1;\n\n\nint main(){\n    int N, x; cin >> N >> x;\n    vector<int> X(2*N-1,INF);\n\n    if(x==1 || x==2*N-1){ cout << \"No\" << endl;}\n    else {\n        X[N-2] = x-1; X[N-1] = x; X[N] = x+1;\n        set<int> num;\n        for(int i=1;i<=2*N-1;i++){\n            if(abs(x-i)>1) num.insert(i);\n        }\n        rep(i,2*N-1){\n            int xi = *num.begin();\n            if(X[i]==INF){\n                X[i] = xi;\n                num.erase(xi);\n            }\n        }\n        cout << \"Yes\" << endl;\n        rep(i,2*N-1) cout << X[i] << endl;\n    }\n\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nWe have a pyramid with N steps, built with blocks.\nThe steps are numbered 1 through N from top to bottom.\nFor each 1≤i≤N, step i consists of 2i-1 blocks aligned horizontally.\nThe pyramid is built so that the blocks at the centers of the steps are aligned vertically.\n\nA pyramid with N=4 steps\n\nSnuke wrote a permutation of (1, 2, ..., 2N-1) into the blocks of step N.\nThen, he wrote integers into all remaining blocks, under the following rule:\n\nThe integer written into a block b must be equal to the median of the three integers written into the three blocks directly under b, or to the lower left or lower right of b.\n\nWriting integers into the blocks\n\nAfterwards, he erased all integers written into the blocks.\nNow, he only remembers that the integer written into the block of step 1 was x.\n\nConstruct a permutation of (1, 2, ..., 2N-1) that could have been written into the blocks of step N, or declare that Snuke's memory is incorrect and such a permutation does not exist.\n\nConstraints\n\n2≤N≤10^5\n\n1≤x≤2N-1\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN x\n\nOutput\n\nIf no permutation of (1, 2, ..., 2N-1) could have been written into the blocks of step N, print No.\n\nOtherwise, print Yes in the first line, then print 2N-1 lines in addition.\n\nThe i-th of these 2N-1 lines should contain the i-th element of a possible permutation.\n\nSample Input 1\n\n4 4\n\nSample Output 1\n\nYes\n1\n6\n3\n7\n4\n5\n2\n\nThis case corresponds to the figure in the problem statement.\n\nSample Input 2\n\n2 1\n\nSample Output 2\n\nNo\n\nNo matter what permutation was written into the blocks of step N, the integer written into the block of step 1 would be 2.", "sample_input": "4 4\n"}, "reference_outputs": ["Yes\n1\n6\n3\n7\n4\n5\n2\n"], "source_document_id": "p03952", "source_text": "Score : 400 points\n\nProblem Statement\n\nWe have a pyramid with N steps, built with blocks.\nThe steps are numbered 1 through N from top to bottom.\nFor each 1≤i≤N, step i consists of 2i-1 blocks aligned horizontally.\nThe pyramid is built so that the blocks at the centers of the steps are aligned vertically.\n\nA pyramid with N=4 steps\n\nSnuke wrote a permutation of (1, 2, ..., 2N-1) into the blocks of step N.\nThen, he wrote integers into all remaining blocks, under the following rule:\n\nThe integer written into a block b must be equal to the median of the three integers written into the three blocks directly under b, or to the lower left or lower right of b.\n\nWriting integers into the blocks\n\nAfterwards, he erased all integers written into the blocks.\nNow, he only remembers that the integer written into the block of step 1 was x.\n\nConstruct a permutation of (1, 2, ..., 2N-1) that could have been written into the blocks of step N, or declare that Snuke's memory is incorrect and such a permutation does not exist.\n\nConstraints\n\n2≤N≤10^5\n\n1≤x≤2N-1\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN x\n\nOutput\n\nIf no permutation of (1, 2, ..., 2N-1) could have been written into the blocks of step N, print No.\n\nOtherwise, print Yes in the first line, then print 2N-1 lines in addition.\n\nThe i-th of these 2N-1 lines should contain the i-th element of a possible permutation.\n\nSample Input 1\n\n4 4\n\nSample Output 1\n\nYes\n1\n6\n3\n7\n4\n5\n2\n\nThis case corresponds to the figure in the problem statement.\n\nSample Input 2\n\n2 1\n\nSample Output 2\n\nNo\n\nNo matter what permutation was written into the blocks of step N, the integer written into the block of step 1 would be 2.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 699, "cpu_time_ms": 351, "memory_kb": 13164}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s450335197", "group_id": "codeNet:p03952", "input_text": "\n#include<algorithm>\n#include<iostream>\n#include<vector>\n#include<string>\n#include<cstring>\n#include<utility>\n#include<queue>\nusing namespace std;\n#define REP(i, a,b) for(i=a;i<b;i++) \n#define REP1(i,b,a) for(i=b-1;i>=a;i--)\n#define output(x) cout<<x<<endl;\n#define pb(x) push_back(x);\ntypedef long long int ll;\nconst int MAX = 510000;\nconst int MOD = 1000000007;\n\nlong long fac[MAX], finv[MAX], inv[MAX];\n\n// テーブルを作る前処理\nvoid COMinit() {\n\tfac[0] = fac[1] = 1;\n\tfinv[0] = finv[1] = 1;\n\tinv[1] = 1;\n\tfor (int i = 2; i < MAX; i++) {\n\t\tfac[i] = fac[i - 1] * i % MOD;\n\t\tinv[i] = MOD - inv[MOD%i] * (MOD / i) % MOD;\n\t\tfinv[i] = finv[i - 1] * inv[i] % MOD;\n\t}\n}\n\n// 二項係数計算\nlong long COM(int n, int k) {\n\tif (n < k) return 0;\n\tif (n < 0 || k < 0) return 0;\n\treturn fac[n] * (finv[k] * finv[n - k] % MOD) % MOD;\n}\n\n\n\nint main()\n{\n\tll  i, j, k, l, m, sum, flag, N, x, y, M, K, H, W, A, B;\n\tcin >> N>>x;\n\tflag = 0;\n\tvector<ll>a(N*2-1);\n\tvector<ll>b;\n\tREP(i, 1, 2 * N ) {\n\t\tb.pb(i);\n\t}\n\tif (N == 2) {\n\t\tif (x == 2) {\n\t\t\toutput(\"Yes\");\n\t\t\toutput(1);\n\t\t\toutput(2);\n\t\t\toutput(3);\n\t\t\treturn 0;\n\t\t}\n\t\toutput(\"No\");\n\t\treturn 0;\n\t}\n\tif (x >= 2 && x <=2*N - 2) {\n\t\tflag = 1;\n\t\tif (x < 2*N - 2) {\n\t\t\ta[N - 1] = x;\n\t\t\ta[N] = 1;\n\t\t\ta[N - 2] = x + 2;\n\t\t\ta[N + 1] = x + 1;\n\t\t\tb.erase(b.begin());\n\t\t\tb.erase(b.begin() + x - 2);\n\t\t\tb.erase(b.begin() + x - 2);\n\t\t\tb.erase(b.begin() + x - 2);\n\t\t\tREP(i, 0, N - 2) {\n\t\t\t\ta[i] = b[i];\n\t\t\t}\n\t\t\tREP(i, N + 2, 2 * N - 1) {\n\t\t\t\ta[i] = b[i- 4];\n\t\t\t}\n\t\t\toutput(\"Yes\");\n\t\t\tREP(i, 0, 2 * N - 1) {\n\t\t\t\toutput(a[i]);\n\t\t\t}\n\t\t\treturn 0;\n\t\t}\n\t\ta[N - 1] = x;\n\t\ta[N] = x+1;\n\t\ta[N - 2] = x - 2;\n\t\ta[N + 1] = x - 1;\n\t\tb.erase(b.begin() + x - 3);\n\t\tb.erase(b.begin() + x - 3);\n\t\tb.erase(b.begin() + x - 3);\n\t\tb.erase(b.begin() + x - 3);\n\t\tREP(i, 0, N - 2) {\n\t\t\ta[i] = b[i];\n\t\t}\n\t\tREP(i, N + 2, 2 * N - 1) {\n\t\t\ta[i] = b[i - 4];\n\t\t}\n\t\toutput(\"Yes\");\n\t\tREP(i, 0, 2 * N - 1) {\n\t\t\toutput(a[i]);\n\t\t}\n\t\treturn 0;\n\n\n\t}\n\toutput(\"No\");\n\treturn 0;\n\t\n}\n\n\n\n\n\n\n\n\n\n\n\n", "language": "C++", "metadata": {"date": 1538843207, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03952.html", "problem_id": "p03952", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03952/input.txt", "sample_output_relpath": "derived/input_output/data/p03952/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03952/C++/s450335197.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s450335197", "user_id": "u213156132"}, "prompt_components": {"gold_output": "Yes\n1\n6\n3\n7\n4\n5\n2\n", "input_to_evaluate": "\n#include<algorithm>\n#include<iostream>\n#include<vector>\n#include<string>\n#include<cstring>\n#include<utility>\n#include<queue>\nusing namespace std;\n#define REP(i, a,b) for(i=a;i<b;i++) \n#define REP1(i,b,a) for(i=b-1;i>=a;i--)\n#define output(x) cout<<x<<endl;\n#define pb(x) push_back(x);\ntypedef long long int ll;\nconst int MAX = 510000;\nconst int MOD = 1000000007;\n\nlong long fac[MAX], finv[MAX], inv[MAX];\n\n// テーブルを作る前処理\nvoid COMinit() {\n\tfac[0] = fac[1] = 1;\n\tfinv[0] = finv[1] = 1;\n\tinv[1] = 1;\n\tfor (int i = 2; i < MAX; i++) {\n\t\tfac[i] = fac[i - 1] * i % MOD;\n\t\tinv[i] = MOD - inv[MOD%i] * (MOD / i) % MOD;\n\t\tfinv[i] = finv[i - 1] * inv[i] % MOD;\n\t}\n}\n\n// 二項係数計算\nlong long COM(int n, int k) {\n\tif (n < k) return 0;\n\tif (n < 0 || k < 0) return 0;\n\treturn fac[n] * (finv[k] * finv[n - k] % MOD) % MOD;\n}\n\n\n\nint main()\n{\n\tll  i, j, k, l, m, sum, flag, N, x, y, M, K, H, W, A, B;\n\tcin >> N>>x;\n\tflag = 0;\n\tvector<ll>a(N*2-1);\n\tvector<ll>b;\n\tREP(i, 1, 2 * N ) {\n\t\tb.pb(i);\n\t}\n\tif (N == 2) {\n\t\tif (x == 2) {\n\t\t\toutput(\"Yes\");\n\t\t\toutput(1);\n\t\t\toutput(2);\n\t\t\toutput(3);\n\t\t\treturn 0;\n\t\t}\n\t\toutput(\"No\");\n\t\treturn 0;\n\t}\n\tif (x >= 2 && x <=2*N - 2) {\n\t\tflag = 1;\n\t\tif (x < 2*N - 2) {\n\t\t\ta[N - 1] = x;\n\t\t\ta[N] = 1;\n\t\t\ta[N - 2] = x + 2;\n\t\t\ta[N + 1] = x + 1;\n\t\t\tb.erase(b.begin());\n\t\t\tb.erase(b.begin() + x - 2);\n\t\t\tb.erase(b.begin() + x - 2);\n\t\t\tb.erase(b.begin() + x - 2);\n\t\t\tREP(i, 0, N - 2) {\n\t\t\t\ta[i] = b[i];\n\t\t\t}\n\t\t\tREP(i, N + 2, 2 * N - 1) {\n\t\t\t\ta[i] = b[i- 4];\n\t\t\t}\n\t\t\toutput(\"Yes\");\n\t\t\tREP(i, 0, 2 * N - 1) {\n\t\t\t\toutput(a[i]);\n\t\t\t}\n\t\t\treturn 0;\n\t\t}\n\t\ta[N - 1] = x;\n\t\ta[N] = x+1;\n\t\ta[N - 2] = x - 2;\n\t\ta[N + 1] = x - 1;\n\t\tb.erase(b.begin() + x - 3);\n\t\tb.erase(b.begin() + x - 3);\n\t\tb.erase(b.begin() + x - 3);\n\t\tb.erase(b.begin() + x - 3);\n\t\tREP(i, 0, N - 2) {\n\t\t\ta[i] = b[i];\n\t\t}\n\t\tREP(i, N + 2, 2 * N - 1) {\n\t\t\ta[i] = b[i - 4];\n\t\t}\n\t\toutput(\"Yes\");\n\t\tREP(i, 0, 2 * N - 1) {\n\t\t\toutput(a[i]);\n\t\t}\n\t\treturn 0;\n\n\n\t}\n\toutput(\"No\");\n\treturn 0;\n\t\n}\n\n\n\n\n\n\n\n\n\n\n\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nWe have a pyramid with N steps, built with blocks.\nThe steps are numbered 1 through N from top to bottom.\nFor each 1≤i≤N, step i consists of 2i-1 blocks aligned horizontally.\nThe pyramid is built so that the blocks at the centers of the steps are aligned vertically.\n\nA pyramid with N=4 steps\n\nSnuke wrote a permutation of (1, 2, ..., 2N-1) into the blocks of step N.\nThen, he wrote integers into all remaining blocks, under the following rule:\n\nThe integer written into a block b must be equal to the median of the three integers written into the three blocks directly under b, or to the lower left or lower right of b.\n\nWriting integers into the blocks\n\nAfterwards, he erased all integers written into the blocks.\nNow, he only remembers that the integer written into the block of step 1 was x.\n\nConstruct a permutation of (1, 2, ..., 2N-1) that could have been written into the blocks of step N, or declare that Snuke's memory is incorrect and such a permutation does not exist.\n\nConstraints\n\n2≤N≤10^5\n\n1≤x≤2N-1\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN x\n\nOutput\n\nIf no permutation of (1, 2, ..., 2N-1) could have been written into the blocks of step N, print No.\n\nOtherwise, print Yes in the first line, then print 2N-1 lines in addition.\n\nThe i-th of these 2N-1 lines should contain the i-th element of a possible permutation.\n\nSample Input 1\n\n4 4\n\nSample Output 1\n\nYes\n1\n6\n3\n7\n4\n5\n2\n\nThis case corresponds to the figure in the problem statement.\n\nSample Input 2\n\n2 1\n\nSample Output 2\n\nNo\n\nNo matter what permutation was written into the blocks of step N, the integer written into the block of step 1 would be 2.", "sample_input": "4 4\n"}, "reference_outputs": ["Yes\n1\n6\n3\n7\n4\n5\n2\n"], "source_document_id": "p03952", "source_text": "Score : 400 points\n\nProblem Statement\n\nWe have a pyramid with N steps, built with blocks.\nThe steps are numbered 1 through N from top to bottom.\nFor each 1≤i≤N, step i consists of 2i-1 blocks aligned horizontally.\nThe pyramid is built so that the blocks at the centers of the steps are aligned vertically.\n\nA pyramid with N=4 steps\n\nSnuke wrote a permutation of (1, 2, ..., 2N-1) into the blocks of step N.\nThen, he wrote integers into all remaining blocks, under the following rule:\n\nThe integer written into a block b must be equal to the median of the three integers written into the three blocks directly under b, or to the lower left or lower right of b.\n\nWriting integers into the blocks\n\nAfterwards, he erased all integers written into the blocks.\nNow, he only remembers that the integer written into the block of step 1 was x.\n\nConstruct a permutation of (1, 2, ..., 2N-1) that could have been written into the blocks of step N, or declare that Snuke's memory is incorrect and such a permutation does not exist.\n\nConstraints\n\n2≤N≤10^5\n\n1≤x≤2N-1\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN x\n\nOutput\n\nIf no permutation of (1, 2, ..., 2N-1) could have been written into the blocks of step N, print No.\n\nOtherwise, print Yes in the first line, then print 2N-1 lines in addition.\n\nThe i-th of these 2N-1 lines should contain the i-th element of a possible permutation.\n\nSample Input 1\n\n4 4\n\nSample Output 1\n\nYes\n1\n6\n3\n7\n4\n5\n2\n\nThis case corresponds to the figure in the problem statement.\n\nSample Input 2\n\n2 1\n\nSample Output 2\n\nNo\n\nNo matter what permutation was written into the blocks of step N, the integer written into the block of step 1 would be 2.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1984, "cpu_time_ms": 329, "memory_kb": 4720}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s126922850", "group_id": "codeNet:p03960", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n#define int long long\n#define ii pair <int, int>\n#define app push_back\n#define all(a) a.begin(), a.end()\n#define bp __builtin_popcountll\n#define ll long long\n#define mp make_pair\n#define f first\n#define s second\n#define Time (double)clock()/CLOCKS_PER_SEC\n#define debug(x) std::cout << #x << \": \" << x << '\\n';\n\nconst int N = 307, INF = 1e18;\nint n, m;\nstring a[N];\n\nint p[2 * N][N];\nint dp[N][N];\n\nsigned main() {\n    #ifdef HOME\n    freopen(\"input.txt\", \"r\", stdin);\n    #else\n    #define endl '\\n'\n    ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);\n    cout.setf(ios::fixed); cout.precision(20); \n    #endif\n    cin >> n >> m;\n    for (int i = 0; i < n; ++i)\n        cin >> a[i];\n\n    function <int(string, string)> solve = [&](string s, string t) {\n\n        for (int i = 0; i <= n; ++i) for (int j = 0; j <= n; ++j) dp[i][j] = INF;\n\n        for (int sh = -n; sh <= n; ++sh) {\n            for (int i = 0; i < n; ++i) {\n                p[sh + n][i + 1] = p[sh + n][i] + (0 <= i + sh && i + sh < n && s[i] == t[i + sh]);\n            }   \n        }   \n\n        dp[0][0] = 0;\n        for (int i = 0; i <= n; ++i) {\n            for (int j = 0; j <= n; ++j) {\n                int add = p[i - j + n][n - i];\n                if (i < n) {\n                    dp[i + 1][j] = min(dp[i + 1][j], dp[i][j] + add);\n                }\n                if (j < n) {\n                    dp[i][j + 1] = min(dp[i][j + 1], dp[i][j] + add);\n                }\n            }   \n        }   \n        return dp[n][n];\n        \n    };  \n\n    int ans = 0;            \n    for (int j = 0; j < m - 1; ++j) {\n        string s, t;\n        for (int i = 0; i < n; ++i) {\n            s += a[i][j];\n            t += a[i][j + 1];\n        }   \n        ans += solve(s, t);\n    }   \n    cout << ans << endl;\n}\n", "language": "C++", "metadata": {"date": 1600322744, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p03960.html", "problem_id": "p03960", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03960/input.txt", "sample_output_relpath": "derived/input_output/data/p03960/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03960/C++/s126922850.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s126922850", "user_id": "u655490856"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n#define int long long\n#define ii pair <int, int>\n#define app push_back\n#define all(a) a.begin(), a.end()\n#define bp __builtin_popcountll\n#define ll long long\n#define mp make_pair\n#define f first\n#define s second\n#define Time (double)clock()/CLOCKS_PER_SEC\n#define debug(x) std::cout << #x << \": \" << x << '\\n';\n\nconst int N = 307, INF = 1e18;\nint n, m;\nstring a[N];\n\nint p[2 * N][N];\nint dp[N][N];\n\nsigned main() {\n    #ifdef HOME\n    freopen(\"input.txt\", \"r\", stdin);\n    #else\n    #define endl '\\n'\n    ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);\n    cout.setf(ios::fixed); cout.precision(20); \n    #endif\n    cin >> n >> m;\n    for (int i = 0; i < n; ++i)\n        cin >> a[i];\n\n    function <int(string, string)> solve = [&](string s, string t) {\n\n        for (int i = 0; i <= n; ++i) for (int j = 0; j <= n; ++j) dp[i][j] = INF;\n\n        for (int sh = -n; sh <= n; ++sh) {\n            for (int i = 0; i < n; ++i) {\n                p[sh + n][i + 1] = p[sh + n][i] + (0 <= i + sh && i + sh < n && s[i] == t[i + sh]);\n            }   \n        }   \n\n        dp[0][0] = 0;\n        for (int i = 0; i <= n; ++i) {\n            for (int j = 0; j <= n; ++j) {\n                int add = p[i - j + n][n - i];\n                if (i < n) {\n                    dp[i + 1][j] = min(dp[i + 1][j], dp[i][j] + add);\n                }\n                if (j < n) {\n                    dp[i][j + 1] = min(dp[i][j + 1], dp[i][j] + add);\n                }\n            }   \n        }   \n        return dp[n][n];\n        \n    };  \n\n    int ans = 0;            \n    for (int j = 0; j < m - 1; ++j) {\n        string s, t;\n        for (int i = 0; i < n; ++i) {\n            s += a[i][j];\n            t += a[i][j + 1];\n        }   \n        ans += solve(s, t);\n    }   \n    cout << ans << endl;\n}\n", "problem_context": "Score : 800 points\n\nProblem Statement\n\nMr. Takahashi has in his room an art object with H rows and W columns, made up of H \\times W blocks.\nEach block has a color represented by a lowercase English letter (a-z).\nThe color of the block at the i-th row and j-th column is c_{i,j}.\n\nMr. Takahashi would like to dismantle the object, finding it a bit kitschy for his tastes.\nThe dismantling is processed by repeating the following operation:\n\nChoose one of the W columns and push down that column one row.\nThe block at the bottom of that column disappears.\n\nEach time the operation is performed, a cost is incurred.\nSince blocks of the same color have a property to draw each other together, the cost of the operation is the number of the pairs of blocks (p, q) such that:\n\nThe block p is in the selected column.\n\nThe two blocks p and q are horizontally adjacent (before pushing down the column).\n\nThe two blocks p and q have the same color.\n\nMr. Takahashi dismantles the object by repeating the operation H \\times W times to get rid of all the blocks.\nCompute the minimum total cost to dismantle the object.\n\nConstraints\n\n1 ≤ H ≤ 300\n\n2 ≤ W ≤ 300\n\nAll characters c_{i,j} are lowercase English letters (a-z).\n\nPartial Score\n\nIn test cases worth 300 points, W = 3.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nH W\nc_{1,1}c_{1,2}..c_{1,W}\nc_{2,1}c_{2,2}..c_{2,W}\n:\nc_{H,1}c_{H,2}..c_{H,W}\n\nOutput\n\nPrint the minimum total cost to dismantle the object.\n\nSample Input 1\n\n2 3\nrrr\nbrg\n\nSample Output 1\n\n2\n\nFor example, the total cost of 2 can be achieved by performing the operation as follows and this is the minimum value.\n\nSample Input 2\n\n6 3\nxya\nxya\nayz\nayz\nxaz\nxaz\n\nSample Output 2\n\n0\n\nThe total cost of 0 can be achieved by first pushing down all blocks of the middle column, then all of the left column, and all of the right column.\n\nSample Input 3\n\n4 2\nay\nxa\nxy\nay\n\nSample Output 3\n\n0\n\nThe total cost of 0 can be achieved by the following operations:\n\npushing down the right column one row;\n\npushing down the left column one row;\n\npushing down all of the right column;\n\nand pushing down all of the left column.\n\nSample Input 4\n\n5 5\naaaaa\nabbba\nababa\nabbba\naaaaa\n\nSample Output 4\n\n24\n\nSample Input 5\n\n7 10\nxxxxxxxxxx\nccccxxffff\ncxxcxxfxxx\ncxxxxxffff\ncxxcxxfxxx\nccccxxfxxx\nxxxxxxxxxx\n\nSample Output 5\n\n130", "sample_input": "2 3\nrrr\nbrg\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03960", "source_text": "Score : 800 points\n\nProblem Statement\n\nMr. Takahashi has in his room an art object with H rows and W columns, made up of H \\times W blocks.\nEach block has a color represented by a lowercase English letter (a-z).\nThe color of the block at the i-th row and j-th column is c_{i,j}.\n\nMr. Takahashi would like to dismantle the object, finding it a bit kitschy for his tastes.\nThe dismantling is processed by repeating the following operation:\n\nChoose one of the W columns and push down that column one row.\nThe block at the bottom of that column disappears.\n\nEach time the operation is performed, a cost is incurred.\nSince blocks of the same color have a property to draw each other together, the cost of the operation is the number of the pairs of blocks (p, q) such that:\n\nThe block p is in the selected column.\n\nThe two blocks p and q are horizontally adjacent (before pushing down the column).\n\nThe two blocks p and q have the same color.\n\nMr. Takahashi dismantles the object by repeating the operation H \\times W times to get rid of all the blocks.\nCompute the minimum total cost to dismantle the object.\n\nConstraints\n\n1 ≤ H ≤ 300\n\n2 ≤ W ��� 300\n\nAll characters c_{i,j} are lowercase English letters (a-z).\n\nPartial Score\n\nIn test cases worth 300 points, W = 3.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nH W\nc_{1,1}c_{1,2}..c_{1,W}\nc_{2,1}c_{2,2}..c_{2,W}\n:\nc_{H,1}c_{H,2}..c_{H,W}\n\nOutput\n\nPrint the minimum total cost to dismantle the object.\n\nSample Input 1\n\n2 3\nrrr\nbrg\n\nSample Output 1\n\n2\n\nFor example, the total cost of 2 can be achieved by performing the operation as follows and this is the minimum value.\n\nSample Input 2\n\n6 3\nxya\nxya\nayz\nayz\nxaz\nxaz\n\nSample Output 2\n\n0\n\nThe total cost of 0 can be achieved by first pushing down all blocks of the middle column, then all of the left column, and all of the right column.\n\nSample Input 3\n\n4 2\nay\nxa\nxy\nay\n\nSample Output 3\n\n0\n\nThe total cost of 0 can be achieved by the following operations:\n\npushing down the right column one row;\n\npushing down the left column one row;\n\npushing down all of the right column;\n\nand pushing down all of the left column.\n\nSample Input 4\n\n5 5\naaaaa\nabbba\nababa\nabbba\naaaaa\n\nSample Output 4\n\n24\n\nSample Input 5\n\n7 10\nxxxxxxxxxx\nccccxxffff\ncxxcxxfxxx\ncxxxxxffff\ncxxcxxfxxx\nccccxxfxxx\nxxxxxxxxxx\n\nSample Output 5\n\n130", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1824, "cpu_time_ms": 156, "memory_kb": 5924}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s127339571", "group_id": "codeNet:p03963", "input_text": "/* BISMILLAHIR RAHMANIR RAHIM */\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n\nint main() \n{\n\tios_base :: sync_with_stdio(0);  \n\tll n, k;\n\tcin >> n >> k;\n\tll res = 1;\n\tfor(ll i = 1; i < n; i++, k--) {\n\t\tres *= k;\n\t}\n\tcout << res << \"\\n\";\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1557592785, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03963.html", "problem_id": "p03963", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03963/input.txt", "sample_output_relpath": "derived/input_output/data/p03963/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03963/C++/s127339571.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s127339571", "user_id": "u421022275"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "/* BISMILLAHIR RAHMANIR RAHIM */\n#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\n\nint main() \n{\n\tios_base :: sync_with_stdio(0);  \n\tll n, k;\n\tcin >> n >> k;\n\tll res = 1;\n\tfor(ll i = 1; i < n; i++, k--) {\n\t\tres *= k;\n\t}\n\tcout << res << \"\\n\";\n\treturn 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nThere are N balls placed in a row.\nAtCoDeer the deer is painting each of these in one of the K colors of his paint cans.\nFor aesthetic reasons, any two adjacent balls must be painted in different colors.\n\nFind the number of the possible ways to paint the balls.\n\nConstraints\n\n1≦N≦1000\n\n2≦K≦1000\n\nThe correct answer is at most 2^{31}-1.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the number of the possible ways to paint the balls.\n\nSample Input 1\n\n2 2\n\nSample Output 1\n\n2\n\nWe will denote the colors by 0 and 1. There are two possible ways: we can either paint the left ball in color 0 and the right ball in color 1, or paint the left in color 1 and the right in color 0.\n\nSample Input 2\n\n1 10\n\nSample Output 2\n\n10\n\nSince there is only one ball, we can use any of the ten colors to paint it. Thus, the answer is ten.", "sample_input": "2 2\n"}, "reference_outputs": ["2\n"], "source_document_id": "p03963", "source_text": "Score : 200 points\n\nProblem Statement\n\nThere are N balls placed in a row.\nAtCoDeer the deer is painting each of these in one of the K colors of his paint cans.\nFor aesthetic reasons, any two adjacent balls must be painted in different colors.\n\nFind the number of the possible ways to paint the balls.\n\nConstraints\n\n1≦N≦1000\n\n2≦K≦1000\n\nThe correct answer is at most 2^{31}-1.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN K\n\nOutput\n\nPrint the number of the possible ways to paint the balls.\n\nSample Input 1\n\n2 2\n\nSample Output 1\n\n2\n\nWe will denote the colors by 0 and 1. There are two possible ways: we can either paint the left ball in color 0 and the right ball in color 1, or paint the left in color 1 and the right in color 0.\n\nSample Input 2\n\n1 10\n\nSample Output 2\n\n10\n\nSince there is only one ball, we can use any of the ten colors to paint it. Thus, the answer is ten.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 273, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s260220776", "group_id": "codeNet:p03964", "input_text": "#define _CRT_SECURE_NO_WARNINGS\n#pragma comment(linker, \"/STACK:256000000\")\n#define _USE_MATH_DEFINES\n#include<iostream>\n#include<vector>\n#include<string>\n#include<stack>\n#include<algorithm>\n#include<cmath>\n#include<set>\n#include<queue>\n#include<sstream>\n#include<utility>\n#include<map>\n#include<ctime>\n#include<cstdio>\n#include<cassert>\n#include<functional>\n#include<unordered_map>\n#include<deque>\n#include<cmath>\n\n\n\n\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef long double ld;\ntypedef unsigned int uint;\ntypedef unsigned long long ull;\ntypedef pair<ll, ll> pll;\ntypedef pair<int, int> pii;\ntypedef pair<char, char> pcc;\ntypedef pair<double, double> pdd;\n\n#define show(x) cerr << x\n#define debug(x) show(#x << \": \" << (x) << endl)\n\nconst long double PI = 3.14159265358979323846;\nconst long double eps = 1e-5;\nconst ll INF = numeric_limits<int>::max();\nconst ll LINF = numeric_limits<ll>::max();\n//const ll mod = 1000 * 1000 * 1000 + 7;\n\n\n\n\nvoid solve() {\n    int n;\n    cin >> n;\n    int x, y;\n    x = 1, y = 1;\n    int a, b;\n    for (int i = 0; i < n; ++i) {\n        cin >> a >> b;\n        int q = max((x + a - 1) / a, (y + b - 1) / b);\n        x = a * q, y = b * q;\n    }\n    cout << x + y << endl;\n\n}\n\n\n//#define LOCAL\n\nint main() {\n    ios_base::sync_with_stdio(0);cin.tie(nullptr);cout.tie(nullptr);\n#ifdef LOCAL\n    freopen(\"input.txt\", \"r\", stdin);\n    freopen(\"output.txt\", \"w\", stdout);\n#endif\n    solve();\n\n\n\n#ifdef LOCAL\n    cerr << \"Time elapsed: \" << 1.0 * clock() / CLOCKS_PER_SEC << \" s.\\n\";\n#endif\t\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1577601295, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03964.html", "problem_id": "p03964", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03964/input.txt", "sample_output_relpath": "derived/input_output/data/p03964/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03964/C++/s260220776.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s260220776", "user_id": "u644276233"}, "prompt_components": {"gold_output": "10\n", "input_to_evaluate": "#define _CRT_SECURE_NO_WARNINGS\n#pragma comment(linker, \"/STACK:256000000\")\n#define _USE_MATH_DEFINES\n#include<iostream>\n#include<vector>\n#include<string>\n#include<stack>\n#include<algorithm>\n#include<cmath>\n#include<set>\n#include<queue>\n#include<sstream>\n#include<utility>\n#include<map>\n#include<ctime>\n#include<cstdio>\n#include<cassert>\n#include<functional>\n#include<unordered_map>\n#include<deque>\n#include<cmath>\n\n\n\n\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef long double ld;\ntypedef unsigned int uint;\ntypedef unsigned long long ull;\ntypedef pair<ll, ll> pll;\ntypedef pair<int, int> pii;\ntypedef pair<char, char> pcc;\ntypedef pair<double, double> pdd;\n\n#define show(x) cerr << x\n#define debug(x) show(#x << \": \" << (x) << endl)\n\nconst long double PI = 3.14159265358979323846;\nconst long double eps = 1e-5;\nconst ll INF = numeric_limits<int>::max();\nconst ll LINF = numeric_limits<ll>::max();\n//const ll mod = 1000 * 1000 * 1000 + 7;\n\n\n\n\nvoid solve() {\n    int n;\n    cin >> n;\n    int x, y;\n    x = 1, y = 1;\n    int a, b;\n    for (int i = 0; i < n; ++i) {\n        cin >> a >> b;\n        int q = max((x + a - 1) / a, (y + b - 1) / b);\n        x = a * q, y = b * q;\n    }\n    cout << x + y << endl;\n\n}\n\n\n//#define LOCAL\n\nint main() {\n    ios_base::sync_with_stdio(0);cin.tie(nullptr);cout.tie(nullptr);\n#ifdef LOCAL\n    freopen(\"input.txt\", \"r\", stdin);\n    freopen(\"output.txt\", \"w\", stdout);\n#endif\n    solve();\n\n\n\n#ifdef LOCAL\n    cerr << \"Time elapsed: \" << 1.0 * clock() / CLOCKS_PER_SEC << \" s.\\n\";\n#endif\t\n    return 0;\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nAtCoDeer the deer is seeing a quick report of election results on TV.\nTwo candidates are standing for the election: Takahashi and Aoki.\nThe report shows the ratio of the current numbers of votes the two candidates have obtained, but not the actual numbers of votes.\nAtCoDeer has checked the report N times, and when he checked it for the i-th (1≦i≦N) time, the ratio was T_i:A_i.\nIt is known that each candidate had at least one vote when he checked the report for the first time.\n\nFind the minimum possible total number of votes obtained by the two candidates when he checked the report for the N-th time.\nIt can be assumed that the number of votes obtained by each candidate never decreases.\n\nConstraints\n\n1≦N≦1000\n\n1≦T_i,A_i≦1000 (1≦i≦N)\n\nT_i and A_i (1≦i≦N) are coprime.\n\nIt is guaranteed that the correct answer is at most 10^{18}.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nT_1 A_1\nT_2 A_2\n:\nT_N A_N\n\nOutput\n\nPrint the minimum possible total number of votes obtained by Takahashi and Aoki when AtCoDeer checked the report for the N-th time.\n\nSample Input 1\n\n3\n2 3\n1 1\n3 2\n\nSample Output 1\n\n10\n\nWhen the numbers of votes obtained by the two candidates change as 2,3 → 3,3 → 6,4, the total number of votes at the end is 10, which is the minimum possible number.\n\nSample Input 2\n\n4\n1 1\n1 1\n1 5\n1 100\n\nSample Output 2\n\n101\n\nIt is possible that neither candidate obtained a vote between the moment when he checked the report, and the moment when he checked it for the next time.\n\nSample Input 3\n\n5\n3 10\n48 17\n31 199\n231 23\n3 2\n\nSample Output 3\n\n6930", "sample_input": "3\n2 3\n1 1\n3 2\n"}, "reference_outputs": ["10\n"], "source_document_id": "p03964", "source_text": "Score : 300 points\n\nProblem Statement\n\nAtCoDeer the deer is seeing a quick report of election results on TV.\nTwo candidates are standing for the election: Takahashi and Aoki.\nThe report shows the ratio of the current numbers of votes the two candidates have obtained, but not the actual numbers of votes.\nAtCoDeer has checked the report N times, and when he checked it for the i-th (1≦i≦N) time, the ratio was T_i:A_i.\nIt is known that each candidate had at least one vote when he checked the report for the first time.\n\nFind the minimum possible total number of votes obtained by the two candidates when he checked the report for the N-th time.\nIt can be assumed that the number of votes obtained by each candidate never decreases.\n\nConstraints\n\n1≦N≦1000\n\n1≦T_i,A_i≦1000 (1≦i≦N)\n\nT_i and A_i (1≦i≦N) are coprime.\n\nIt is guaranteed that the correct answer is at most 10^{18}.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nT_1 A_1\nT_2 A_2\n:\nT_N A_N\n\nOutput\n\nPrint the minimum possible total number of votes obtained by Takahashi and Aoki when AtCoDeer checked the report for the N-th time.\n\nSample Input 1\n\n3\n2 3\n1 1\n3 2\n\nSample Output 1\n\n10\n\nWhen the numbers of votes obtained by the two candidates change as 2,3 → 3,3 → 6,4, the total number of votes at the end is 10, which is the minimum possible number.\n\nSample Input 2\n\n4\n1 1\n1 1\n1 5\n1 100\n\nSample Output 2\n\n101\n\nIt is possible that neither candidate obtained a vote between the moment when he checked the report, and the moment when he checked it for the next time.\n\nSample Input 3\n\n5\n3 10\n48 17\n31 199\n231 23\n3 2\n\nSample Output 3\n\n6930", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1541, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s490414555", "group_id": "codeNet:p03974", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\ntemplate<typename T, typename VAL_TYPE>\nstruct trie{\n\ttypedef function<int(T)> To_Int;\n\tint SIGMA;\n\tTo_Int to_int;\n\n\tstruct node{\n\t\tvector<VAL_TYPE> val;\n\t\tint cnt;\n\t\tvector<node *> nexts;\n\t};\n\n\tnode *root;\n\n\ttrie(int SIGMA, To_Int to_int) : SIGMA(SIGMA), to_int(to_int), root(NULL) {}\n\n\tint ret_cnt(node *nd){\n\t\tif(nd == NULL) return 0;\n\t\telse return nd->cnt;\n\t}\n\n\tvector<VAL_TYPE> ret_val(node *nd){\n\t\tif(nd == NULL) return vector<VAL_TYPE>(0);\n\t\telse return nd->val;\n\t}\n\n\t//ndにSの[l,r)を追加したノードを返す\n\tnode *add(node *nd, string &S, int l, int r, VAL_TYPE v){\n\t\tnode *ans;\n\t\tif(nd == NULL){\n\t\t\tans = new node;\n\t\t\tans->val.assign(0, v);\n\t\t\tans->cnt = 0;\n\t\t\tans->nexts.assign(SIGMA, NULL);\n\t\t}\n\t\telse{\n\t\t\tans = nd;\n\t\t}\n\t\tans->cnt++;\n\t\tif(l == r){\n\t\t\tans->val.push_back(v);\n\t\t}\n\t\telse{\n\t\t\tans->nexts[to_int(S[l])] = add(ans->nexts[to_int(S[l])], S, l + 1, r, v);\n\t\t}\n\t\treturn ans;\n\t}\n\n\t//(S,v)を追加する\n\tvoid add(string &S, VAL_TYPE v){\n\t\troot = add(root, S, 0, S.size(), v);\n\t}\n\n\t//ndからSの[l,r)を辿ったノードを返す(無いときはNULL)\n\tnode *search(node *nd, string &S, int l, int r){\n\t\tif(nd == NULL){\n\t\t\treturn NULL;\n\t\t}\n\t\telse if(l == r){\n\t\t\treturn nd;\n\t\t}\n\t\telse{\n\t\t\treturn search(nd->nexts[to_int(S[l])], S, l + 1, r);\n\t\t}\n\t}\n\n\t//Sをprefixに含む文字列の個数\n\tint prefix_count(string &S){\n\t\treturn ret_cnt(search(root, S, 0, S.size()));\n\t}\n\n\t//Sの値\n\tvector<VAL_TYPE> value(string &S){\n\t\treturn ret_val(search(root, S, 0, S.size()));\n\t}\n\n\tvoid junp_check(node *nd, string &S, vector<int> &junp, int l, int r){\n\t\tif(l < r && nd != NULL && nd->nexts[to_int(S[l])] != NULL){\n\t\t\tif(nd->cnt == nd->nexts[to_int(S[l])]->cnt){\n\t\t\t\tjunp[l] = 1;\n\t\t\t}\n\t\t\tjunp_check(nd->nexts[to_int(S[l])], S, junp, l + 1, r);\n\t\t}\n\t}\n\n\tvoid junp_check(string &S, vector<int> &junp){\n\t\tjunp_check(root, S, junp, 0, S.size());\n\t}\n\n\tnode *compression(node *nd){\n\t\tif(nd == NULL || ret_cnt(nd) == 0){\n\t\t\treturn NULL;\n\t\t}\n\t\tfor(int i = 0; i < SIGMA; i++){\n\t\t\tnode *ndi = nd->nexts[i];\n\t\t\tif(nd->cnt == ret_cnt(ndi)){\n\t\t\t\treturn compression(ndi);\n\t\t\t}\n\t\t\tnd->nexts[i] = compression(ndi);\n\t\t}\n\t\treturn nd;\n\t}\n\n\tvoid compression(){\n\t\troot = compression(root);\n\t}\n\n\tint solve(node *nd, string &S, int l, int r, string &p){\n\t\tif(l == r || nd == NULL){\n\t\t\treturn 0;\n\t\t}\n\t\telse{\n\t\t\tint ans = ret_val(nd).size();\n\t\t\tfor(int i = 0; i < SIGMA; i++){\n\t\t\t\tif(p[i] == S[l]){\n\t\t\t\t\treturn ans + solve(nd->nexts[to_int(p[i])], S, l + 1, r, p);\n\t\t\t\t}\n\t\t\t\telse{\n\t\t\t\t\tans += ret_cnt(nd->nexts[to_int(p[i])]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tint solve(string &S, string &p){\n\t\treturn solve(root, S, 0, S.size(), p);\n\t}\n};\n\nint char_to_int(char c){\n\treturn (int)(c - 'a');\n}\n\nint main(){\n\tint N, Q, i, j;\n\tscanf(\"%d\", &N);\n\tvector<string> S(N);\n\tfor(i = 0; i < N; i++){\n\t\tcin >> S[i];\n\t}\n\ttrie<char, int> t(26, char_to_int);\n\tfor(i = 0; i < N; i++){\n\t\tt.add(S[i], i);\n\t}\n\tvector<vector<int>> junp(N);\n\tvector<string> Scomp(N, \"\");\n\tfor(i = 0; i < N; i++){\n\t\tjunp[i] = vector<int>(S[i].size(), 0);\n\t\tt.junp_check(S[i], junp[i]);\n\t\tfor(j = 0; j < S[i].size(); j++){\n\t\t\tif(junp[i][j] == 0){\n\t\t\t\tScomp[i].push_back(S[i][j]);\n\t\t\t}\n\t\t}\n\t}\n\tt.compression();\n/*\tprintf(\"compression!\\n\");\n\tfor(i = 0; i < N; i++){\n\t\tcout << Scomp[i] << endl;\n\t}\n\twhile(1){\n\t\tint ins;\n\t\tstring T;\n\t\tscanf(\"%d\", &ins);\n\t\tcin >> T;\n\t\tif(ins == 0){\n\t\t\tprintf(\"%d\\n\", t.prefix_count(T));\n\t\t}\n\t\telse{\n\t\t\tvector<int> ids = t.value(T);\n\t\t\tfor(i = 0; i < ids.size(); i++){\n\t\t\t\tprintf(\"%d \", ids[i]);\n\t\t\t}\n\t\t\tprintf(\"\\n\");\n\t\t}\n\t}\n*/\tscanf(\"%d\", &Q);\n\tfor(i = 0; i < Q; i++){\n\t\tint k;\n\t\tstring p;\n\t\tscanf(\"%d\", &k);\n\t\tcin >> p;\n\t\tprintf(\"%d\\n\", t.solve(Scomp[k - 1], p) + 1);\n\t}\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1564153796, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03974.html", "problem_id": "p03974", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03974/input.txt", "sample_output_relpath": "derived/input_output/data/p03974/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03974/C++/s490414555.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Time Limit Exceeded", "submission_id": "s490414555", "user_id": "u208608367"}, "prompt_components": {"gold_output": "1\n2\n5\n4\n2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\ntemplate<typename T, typename VAL_TYPE>\nstruct trie{\n\ttypedef function<int(T)> To_Int;\n\tint SIGMA;\n\tTo_Int to_int;\n\n\tstruct node{\n\t\tvector<VAL_TYPE> val;\n\t\tint cnt;\n\t\tvector<node *> nexts;\n\t};\n\n\tnode *root;\n\n\ttrie(int SIGMA, To_Int to_int) : SIGMA(SIGMA), to_int(to_int), root(NULL) {}\n\n\tint ret_cnt(node *nd){\n\t\tif(nd == NULL) return 0;\n\t\telse return nd->cnt;\n\t}\n\n\tvector<VAL_TYPE> ret_val(node *nd){\n\t\tif(nd == NULL) return vector<VAL_TYPE>(0);\n\t\telse return nd->val;\n\t}\n\n\t//ndにSの[l,r)を追加したノードを返す\n\tnode *add(node *nd, string &S, int l, int r, VAL_TYPE v){\n\t\tnode *ans;\n\t\tif(nd == NULL){\n\t\t\tans = new node;\n\t\t\tans->val.assign(0, v);\n\t\t\tans->cnt = 0;\n\t\t\tans->nexts.assign(SIGMA, NULL);\n\t\t}\n\t\telse{\n\t\t\tans = nd;\n\t\t}\n\t\tans->cnt++;\n\t\tif(l == r){\n\t\t\tans->val.push_back(v);\n\t\t}\n\t\telse{\n\t\t\tans->nexts[to_int(S[l])] = add(ans->nexts[to_int(S[l])], S, l + 1, r, v);\n\t\t}\n\t\treturn ans;\n\t}\n\n\t//(S,v)を追加する\n\tvoid add(string &S, VAL_TYPE v){\n\t\troot = add(root, S, 0, S.size(), v);\n\t}\n\n\t//ndからSの[l,r)を辿ったノードを返す(無いときはNULL)\n\tnode *search(node *nd, string &S, int l, int r){\n\t\tif(nd == NULL){\n\t\t\treturn NULL;\n\t\t}\n\t\telse if(l == r){\n\t\t\treturn nd;\n\t\t}\n\t\telse{\n\t\t\treturn search(nd->nexts[to_int(S[l])], S, l + 1, r);\n\t\t}\n\t}\n\n\t//Sをprefixに含む文字列の個数\n\tint prefix_count(string &S){\n\t\treturn ret_cnt(search(root, S, 0, S.size()));\n\t}\n\n\t//Sの値\n\tvector<VAL_TYPE> value(string &S){\n\t\treturn ret_val(search(root, S, 0, S.size()));\n\t}\n\n\tvoid junp_check(node *nd, string &S, vector<int> &junp, int l, int r){\n\t\tif(l < r && nd != NULL && nd->nexts[to_int(S[l])] != NULL){\n\t\t\tif(nd->cnt == nd->nexts[to_int(S[l])]->cnt){\n\t\t\t\tjunp[l] = 1;\n\t\t\t}\n\t\t\tjunp_check(nd->nexts[to_int(S[l])], S, junp, l + 1, r);\n\t\t}\n\t}\n\n\tvoid junp_check(string &S, vector<int> &junp){\n\t\tjunp_check(root, S, junp, 0, S.size());\n\t}\n\n\tnode *compression(node *nd){\n\t\tif(nd == NULL || ret_cnt(nd) == 0){\n\t\t\treturn NULL;\n\t\t}\n\t\tfor(int i = 0; i < SIGMA; i++){\n\t\t\tnode *ndi = nd->nexts[i];\n\t\t\tif(nd->cnt == ret_cnt(ndi)){\n\t\t\t\treturn compression(ndi);\n\t\t\t}\n\t\t\tnd->nexts[i] = compression(ndi);\n\t\t}\n\t\treturn nd;\n\t}\n\n\tvoid compression(){\n\t\troot = compression(root);\n\t}\n\n\tint solve(node *nd, string &S, int l, int r, string &p){\n\t\tif(l == r || nd == NULL){\n\t\t\treturn 0;\n\t\t}\n\t\telse{\n\t\t\tint ans = ret_val(nd).size();\n\t\t\tfor(int i = 0; i < SIGMA; i++){\n\t\t\t\tif(p[i] == S[l]){\n\t\t\t\t\treturn ans + solve(nd->nexts[to_int(p[i])], S, l + 1, r, p);\n\t\t\t\t}\n\t\t\t\telse{\n\t\t\t\t\tans += ret_cnt(nd->nexts[to_int(p[i])]);\n\t\t\t\t}\n\t\t\t}\n\t\t}\n\t}\n\n\tint solve(string &S, string &p){\n\t\treturn solve(root, S, 0, S.size(), p);\n\t}\n};\n\nint char_to_int(char c){\n\treturn (int)(c - 'a');\n}\n\nint main(){\n\tint N, Q, i, j;\n\tscanf(\"%d\", &N);\n\tvector<string> S(N);\n\tfor(i = 0; i < N; i++){\n\t\tcin >> S[i];\n\t}\n\ttrie<char, int> t(26, char_to_int);\n\tfor(i = 0; i < N; i++){\n\t\tt.add(S[i], i);\n\t}\n\tvector<vector<int>> junp(N);\n\tvector<string> Scomp(N, \"\");\n\tfor(i = 0; i < N; i++){\n\t\tjunp[i] = vector<int>(S[i].size(), 0);\n\t\tt.junp_check(S[i], junp[i]);\n\t\tfor(j = 0; j < S[i].size(); j++){\n\t\t\tif(junp[i][j] == 0){\n\t\t\t\tScomp[i].push_back(S[i][j]);\n\t\t\t}\n\t\t}\n\t}\n\tt.compression();\n/*\tprintf(\"compression!\\n\");\n\tfor(i = 0; i < N; i++){\n\t\tcout << Scomp[i] << endl;\n\t}\n\twhile(1){\n\t\tint ins;\n\t\tstring T;\n\t\tscanf(\"%d\", &ins);\n\t\tcin >> T;\n\t\tif(ins == 0){\n\t\t\tprintf(\"%d\\n\", t.prefix_count(T));\n\t\t}\n\t\telse{\n\t\t\tvector<int> ids = t.value(T);\n\t\t\tfor(i = 0; i < ids.size(); i++){\n\t\t\t\tprintf(\"%d \", ids[i]);\n\t\t\t}\n\t\t\tprintf(\"\\n\");\n\t\t}\n\t}\n*/\tscanf(\"%d\", &Q);\n\tfor(i = 0; i < Q; i++){\n\t\tint k;\n\t\tstring p;\n\t\tscanf(\"%d\", &k);\n\t\tcin >> p;\n\t\tprintf(\"%d\\n\", t.solve(Scomp[k - 1], p) + 1);\n\t}\n\treturn 0;\n}", "problem_context": "Score : 1100 points\n\nProblem Statement\n\nThere are N strings of lowercase alphabet only. The i-th string is S_i. Every string is unique.\n\nProvide answers for the Q queries below. The i-th query has the following format:\n\nQuery: An integer k_i and a string p_{i,1}p_{i,2}...p_{i,26} that results from permuting {a,b,...,z} are given. Output the sequence of the string S_{k_i} among the N strings in lexicographical order when the literal sequence is p_{i,1}<p_{i,2}<...<p_{i,26}.\n\nConstraints\n\n1 ≦ N,Q ≦ 100000\n\n1 ≦ |S_i| (1 ≦ i ≦ N)\n\nS_i (1 ≦ i ≦ N) is a string of lowercase alphabet.\n\nThe sum of |S_i| is no more than 400000.\n\nEvery S_i is unique.\n\n1 ≦ k_i ≦ N (1 ≦ i ≦ Q)\n\nFor all 1 ≦ i ≦ Q, p_{i,1}p_{i,2}...p_{i,26} is a permutation of abcd...z.\n\nInput\n\nInputs are provided from standard inputs in the following form.\n\nN\nS_1\n:\nS_N\nQ\nk_1 p_{1,1}p_{1,2}...p_{1,26}\n:\nk_Q p_{Q,1}p_{Q,2}...p_{Q,26}\n\nOutput\n\nOutput Q lines.\n\nOn line i, for the i-th query, output an integer indicating the sequence of the string S_{k_i} among the N strings in lexicographical order.\n\nSample Input 1\n\n5\naa\nabbaa\nabbba\naaab\naaaaaba\n5\n1 abcdefghijklmnopqrstuvwxyz\n2 bacdefghijklmnopqrstuvwxyz\n3 abcdefghijklmnopqrstuvwxyz\n4 bacdefghijklmnopqrstuvwxyz\n5 abcdefghijklmnopqrstuvwxyz\n\nSample Output 1\n\n1\n2\n5\n4\n2\n\nWhen the literal sequence is a < b, sorting the input strings in lexicographical order yields aa, aaaaaba, aaab, abbaa, abbba. The answers to queries 1, 3, and 5 are thus 1, 5, and 2, respectively.\n\nWhen the literal sequence is b < a, sorting the input strings in lexicographical order yields abbba, abbaa, aa, aaab, aaaaaba. The answers to queries 2 and 4 are thus 2 and 4, respectively.\n\nSample Input 2\n\n8\nabrakatabra\nabadaba\nabracadabra\natcoder\ngrand\ncontest\nababa\na\n6\n3 abcdefghijklmnopqrstuvwxyz\n6 qwertyuiopasdfghjklzxcvbnm\n8 poiuytrewqlkjhgfdsamnbvcxz\n2 qazwsxedcrfvtgbyhnujmikolp\n1 plokmijnuhbygvtfcrdxeszwaq\n4 mnbvcxzasdfghjklpoiuytrewq\n\nSample Output 2\n\n4\n8\n2\n3\n4\n7", "sample_input": "5\naa\nabbaa\nabbba\naaab\naaaaaba\n5\n1 abcdefghijklmnopqrstuvwxyz\n2 bacdefghijklmnopqrstuvwxyz\n3 abcdefghijklmnopqrstuvwxyz\n4 bacdefghijklmnopqrstuvwxyz\n5 abcdefghijklmnopqrstuvwxyz\n"}, "reference_outputs": ["1\n2\n5\n4\n2\n"], "source_document_id": "p03974", "source_text": "Score : 1100 points\n\nProblem Statement\n\nThere are N strings of lowercase alphabet only. The i-th string is S_i. Every string is unique.\n\nProvide answers for the Q queries below. The i-th query has the following format:\n\nQuery: An integer k_i and a string p_{i,1}p_{i,2}...p_{i,26} that results from permuting {a,b,...,z} are given. Output the sequence of the string S_{k_i} among the N strings in lexicographical order when the literal sequence is p_{i,1}<p_{i,2}<...<p_{i,26}.\n\nConstraints\n\n1 ≦ N,Q ≦ 100000\n\n1 ≦ |S_i| (1 ≦ i ≦ N)\n\nS_i (1 ≦ i ≦ N) is a string of lowercase alphabet.\n\nThe sum of |S_i| is no more than 400000.\n\nEvery S_i is unique.\n\n1 ≦ k_i ≦ N (1 ≦ i ≦ Q)\n\nFor all 1 ≦ i ≦ Q, p_{i,1}p_{i,2}...p_{i,26} is a permutation of abcd...z.\n\nInput\n\nInputs are provided from standard inputs in the following form.\n\nN\nS_1\n:\nS_N\nQ\nk_1 p_{1,1}p_{1,2}...p_{1,26}\n:\nk_Q p_{Q,1}p_{Q,2}...p_{Q,26}\n\nOutput\n\nOutput Q lines.\n\nOn line i, for the i-th query, output an integer indicating the sequence of the string S_{k_i} among the N strings in lexicographical order.\n\nSample Input 1\n\n5\naa\nabbaa\nabbba\naaab\naaaaaba\n5\n1 abcdefghijklmnopqrstuvwxyz\n2 bacdefghijklmnopqrstuvwxyz\n3 abcdefghijklmnopqrstuvwxyz\n4 bacdefghijklmnopqrstuvwxyz\n5 abcdefghijklmnopqrstuvwxyz\n\nSample Output 1\n\n1\n2\n5\n4\n2\n\nWhen the literal sequence is a < b, sorting the input strings in lexicographical order yields aa, aaaaaba, aaab, abbaa, abbba. The answers to queries 1, 3, and 5 are thus 1, 5, and 2, respectively.\n\nWhen the literal sequence is b < a, sorting the input strings in lexicographical order yields abbba, abbaa, aa, aaab, aaaaaba. The answers to queries 2 and 4 are thus 2 and 4, respectively.\n\nSample Input 2\n\n8\nabrakatabra\nabadaba\nabracadabra\natcoder\ngrand\ncontest\nababa\na\n6\n3 abcdefghijklmnopqrstuvwxyz\n6 qwertyuiopasdfghjklzxcvbnm\n8 poiuytrewqlkjhgfdsamnbvcxz\n2 qazwsxedcrfvtgbyhnujmikolp\n1 plokmijnuhbygvtfcrdxeszwaq\n4 mnbvcxzasdfghjklpoiuytrewq\n\nSample Output 2\n\n4\n8\n2\n3\n4\n7", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 3697, "cpu_time_ms": 6079, "memory_kb": 131076}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s724877734", "group_id": "codeNet:p03986", "input_text": "#include <bits/stdc++.h>\ntypedef long long ll;\nusing namespace std;\n \nint main(){\n\t\tstring x;\n\t\tcin >> x;\n\t\tint s = 0;\n\t\tint ans = x.size();\n \n\t\tfor(int i=0;i<x.size();i++) {\n\t\t\t\tif(x[i]=='S') s++;\n\t\t\t\tif(x[i]=='T') {\n\t\t\t\t\t\tif(s>0){\n\t\t\t\t\t\t\t\tans -= 2;\n\t\t\t\t\t\t\t\ts--;\n\t\t\t\t\t\t}\n\t\t\t\t}\n\t\t}\n \n\t\tcout << ans << endl;\n}", "language": "C++", "metadata": {"date": 1559582517, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03986.html", "problem_id": "p03986", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03986/input.txt", "sample_output_relpath": "derived/input_output/data/p03986/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03986/C++/s724877734.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s724877734", "user_id": "u407416173"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <bits/stdc++.h>\ntypedef long long ll;\nusing namespace std;\n \nint main(){\n\t\tstring x;\n\t\tcin >> x;\n\t\tint s = 0;\n\t\tint ans = x.size();\n \n\t\tfor(int i=0;i<x.size();i++) {\n\t\t\t\tif(x[i]=='S') s++;\n\t\t\t\tif(x[i]=='T') {\n\t\t\t\t\t\tif(s>0){\n\t\t\t\t\t\t\t\tans -= 2;\n\t\t\t\t\t\t\t\ts--;\n\t\t\t\t\t\t}\n\t\t\t\t}\n\t\t}\n \n\t\tcout << ans << endl;\n}", "problem_context": "Score : 300 points\n\nProblem Statement\n\nWe have a string X, which has an even number of characters. Half the characters are S, and the other half are T.\n\nTakahashi, who hates the string ST, will perform the following operation 10^{10000} times:\n\nAmong the occurrences of ST in X as (contiguous) substrings, remove the leftmost one. If there is no occurrence, do nothing.\n\nFind the eventual length of X.\n\nConstraints\n\n2 ≦ |X| ≦ 200,000\n\nThe length of X is even.\n\nHalf the characters in X are S, and the other half are T.\n\nPartial Scores\n\nIn test cases worth 200 points, |X| ≦ 200.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint the eventual length of X.\n\nSample Input 1\n\nTSTTSS\n\nSample Output 1\n\n4\n\nIn the 1-st operation, the 2-nd and 3-rd characters of TSTTSS are removed.\nX becomes TTSS, and since it does not contain ST anymore, nothing is done in the remaining 10^{10000}-1 operations.\nThus, the answer is 4.\n\nSample Input 2\n\nSSTTST\n\nSample Output 2\n\n0\n\nX will eventually become an empty string: SSTTST ⇒ STST ⇒ ST ⇒ ``.\n\nSample Input 3\n\nTSSTTTSS\n\nSample Output 3\n\n4\n\nX will become: TSSTTTSS ⇒ TSTTSS ⇒ TTSS.", "sample_input": "TSTTSS\n"}, "reference_outputs": ["4\n"], "source_document_id": "p03986", "source_text": "Score : 300 points\n\nProblem Statement\n\nWe have a string X, which has an even number of characters. Half the characters are S, and the other half are T.\n\nTakahashi, who hates the string ST, will perform the following operation 10^{10000} times:\n\nAmong the occurrences of ST in X as (contiguous) substrings, remove the leftmost one. If there is no occurrence, do nothing.\n\nFind the eventual length of X.\n\nConstraints\n\n2 ≦ |X| ≦ 200,000\n\nThe length of X is even.\n\nHalf the characters in X are S, and the other half are T.\n\nPartial Scores\n\nIn test cases worth 200 points, |X| ≦ 200.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint the eventual length of X.\n\nSample Input 1\n\nTSTTSS\n\nSample Output 1\n\n4\n\nIn the 1-st operation, the 2-nd and 3-rd characters of TSTTSS are removed.\nX becomes TTSS, and since it does not contain ST anymore, nothing is done in the remaining 10^{10000}-1 operations.\nThus, the answer is 4.\n\nSample Input 2\n\nSSTTST\n\nSample Output 2\n\n0\n\nX will eventually become an empty string: SSTTST ⇒ STST ⇒ ST ⇒ ``.\n\nSample Input 3\n\nTSSTTTSS\n\nSample Output 3\n\n4\n\nX will become: TSSTTTSS ⇒ TSTTSS ⇒ TTSS.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 308, "cpu_time_ms": 8, "memory_kb": 640}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s383243557", "group_id": "codeNet:p03986", "input_text": "#include <cstdio>\n#include <cstring>\nusing namespace std;\n\nconst int N = 200500;\nchar st[N];\n\nchar buf[N];\n\nint main() {\n    scanf(\"%s\", buf);\n    int len = strlen(buf);\n    int pt = 0;\n    for (int i = 0; i < len; i++) {\n        char c = buf[i];\n        if (pt != 0 && st[pt - 1] == 'S' && c == 'T')\n            --pt;\n        else\n            st[pt++] = c;\n    }\n    printf(\"%d\\n\", pt);\n}\n", "language": "C++", "metadata": {"date": 1475370123, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03986.html", "problem_id": "p03986", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03986/input.txt", "sample_output_relpath": "derived/input_output/data/p03986/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03986/C++/s383243557.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s383243557", "user_id": "u510005981"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <cstdio>\n#include <cstring>\nusing namespace std;\n\nconst int N = 200500;\nchar st[N];\n\nchar buf[N];\n\nint main() {\n    scanf(\"%s\", buf);\n    int len = strlen(buf);\n    int pt = 0;\n    for (int i = 0; i < len; i++) {\n        char c = buf[i];\n        if (pt != 0 && st[pt - 1] == 'S' && c == 'T')\n            --pt;\n        else\n            st[pt++] = c;\n    }\n    printf(\"%d\\n\", pt);\n}\n", "problem_context": "Score : 300 points\n\nProblem Statement\n\nWe have a string X, which has an even number of characters. Half the characters are S, and the other half are T.\n\nTakahashi, who hates the string ST, will perform the following operation 10^{10000} times:\n\nAmong the occurrences of ST in X as (contiguous) substrings, remove the leftmost one. If there is no occurrence, do nothing.\n\nFind the eventual length of X.\n\nConstraints\n\n2 ≦ |X| ≦ 200,000\n\nThe length of X is even.\n\nHalf the characters in X are S, and the other half are T.\n\nPartial Scores\n\nIn test cases worth 200 points, |X| ≦ 200.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint the eventual length of X.\n\nSample Input 1\n\nTSTTSS\n\nSample Output 1\n\n4\n\nIn the 1-st operation, the 2-nd and 3-rd characters of TSTTSS are removed.\nX becomes TTSS, and since it does not contain ST anymore, nothing is done in the remaining 10^{10000}-1 operations.\nThus, the answer is 4.\n\nSample Input 2\n\nSSTTST\n\nSample Output 2\n\n0\n\nX will eventually become an empty string: SSTTST ⇒ STST ⇒ ST ⇒ ``.\n\nSample Input 3\n\nTSSTTTSS\n\nSample Output 3\n\n4\n\nX will become: TSSTTTSS ⇒ TSTTSS ⇒ TTSS.", "sample_input": "TSTTSS\n"}, "reference_outputs": ["4\n"], "source_document_id": "p03986", "source_text": "Score : 300 points\n\nProblem Statement\n\nWe have a string X, which has an even number of characters. Half the characters are S, and the other half are T.\n\nTakahashi, who hates the string ST, will perform the following operation 10^{10000} times:\n\nAmong the occurrences of ST in X as (contiguous) substrings, remove the leftmost one. If there is no occurrence, do nothing.\n\nFind the eventual length of X.\n\nConstraints\n\n2 ≦ |X| ≦ 200,000\n\nThe length of X is even.\n\nHalf the characters in X are S, and the other half are T.\n\nPartial Scores\n\nIn test cases worth 200 points, |X| ≦ 200.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nX\n\nOutput\n\nPrint the eventual length of X.\n\nSample Input 1\n\nTSTTSS\n\nSample Output 1\n\n4\n\nIn the 1-st operation, the 2-nd and 3-rd characters of TSTTSS are removed.\nX becomes TTSS, and since it does not contain ST anymore, nothing is done in the remaining 10^{10000}-1 operations.\nThus, the answer is 4.\n\nSample Input 2\n\nSSTTST\n\nSample Output 2\n\n0\n\nX will eventually become an empty string: SSTTST ⇒ STST ⇒ ST ⇒ ``.\n\nSample Input 3\n\nTSSTTTSS\n\nSample Output 3\n\n4\n\nX will become: TSSTTTSS ⇒ TSTTSS ⇒ TTSS.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 390, "cpu_time_ms": 3, "memory_kb": 512}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s171446224", "group_id": "codeNet:p03987", "input_text": "/*\n * src.cpp\n *\n *  Created on: 2016/10/01\n *      Author: joi\n */\n\n#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define FOR(i,a,b) for(int i=(a);i<(b);i++)\n#define REP(i,a) FOR(i,0,a)\n\nconst int MAX_N=2e5;\n\ntypedef long long ll;\nint N;\nint A[MAX_N];\nll dp[MAX_N];\n\nint main(){\n\tscanf(\"%d\",&N);\n\tREP(i,N){\n\t\tscanf(\"%d\",&A[i]);\n\t}\n\tll res=A[0];\n\tint mi=A[0];\n\tdp[0]=A[0];\n\tFOR(i,1,N){\n\t\tll d=0;\n\t\tres+=A[i];\n\t\td=A[i];\n\t\tif (A[i]<mi){\n\t\t\tmi=A[i];\n\t\t\tres+=mi*i;\n\t\t\td+=mi*i;\n\t\t}else{\n\t\t\tint j=i-1;\n\t\t\twhile (A[j]>A[i]){\n\t\t\t\tres+=A[i];\n\t\t\t\td+=A[i];\n\t\t\t\tj--;\n\t\t\t}\n\t\t\tres+=dp[j];\n\t\t\td+=dp[j];\n\t\t}\n\t\tdp[i]=d;\n\t}\n\tprintf(\"%lld\\n\",res);\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1475370885, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03987.html", "problem_id": "p03987", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03987/input.txt", "sample_output_relpath": "derived/input_output/data/p03987/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03987/C++/s171446224.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s171446224", "user_id": "u533920479"}, "prompt_components": {"gold_output": "9\n", "input_to_evaluate": "/*\n * src.cpp\n *\n *  Created on: 2016/10/01\n *      Author: joi\n */\n\n#include <bits/stdc++.h>\n\nusing namespace std;\n\n#define FOR(i,a,b) for(int i=(a);i<(b);i++)\n#define REP(i,a) FOR(i,0,a)\n\nconst int MAX_N=2e5;\n\ntypedef long long ll;\nint N;\nint A[MAX_N];\nll dp[MAX_N];\n\nint main(){\n\tscanf(\"%d\",&N);\n\tREP(i,N){\n\t\tscanf(\"%d\",&A[i]);\n\t}\n\tll res=A[0];\n\tint mi=A[0];\n\tdp[0]=A[0];\n\tFOR(i,1,N){\n\t\tll d=0;\n\t\tres+=A[i];\n\t\td=A[i];\n\t\tif (A[i]<mi){\n\t\t\tmi=A[i];\n\t\t\tres+=mi*i;\n\t\t\td+=mi*i;\n\t\t}else{\n\t\t\tint j=i-1;\n\t\t\twhile (A[j]>A[i]){\n\t\t\t\tres+=A[i];\n\t\t\t\td+=A[i];\n\t\t\t\tj--;\n\t\t\t}\n\t\t\tres+=dp[j];\n\t\t\td+=dp[j];\n\t\t}\n\t\tdp[i]=d;\n\t}\n\tprintf(\"%lld\\n\",res);\n\treturn 0;\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nOne day, Snuke was given a permutation of length N, a_1, a_2, ..., a_N, from his friend.\n\nFind the following:\n\nConstraints\n\n1 ≦ N ≦ 200,000\n\n(a_1, a_2, ..., a_N) is a permutation of (1, 2, ..., N).\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_N\n\nOutput\n\nPrint the answer.\n\nNote that the answer may not fit into a 32-bit integer.\n\nSample Input 1\n\n3\n2 1 3\n\nSample Output 1\n\n9\n\nSample Input 2\n\n4\n1 3 2 4\n\nSample Output 2\n\n19\n\nSample Input 3\n\n8\n5 4 8 1 2 6 7 3\n\nSample Output 3\n\n85", "sample_input": "3\n2 1 3\n"}, "reference_outputs": ["9\n"], "source_document_id": "p03987", "source_text": "Score : 400 points\n\nProblem Statement\n\nOne day, Snuke was given a permutation of length N, a_1, a_2, ..., a_N, from his friend.\n\nFind the following:\n\nConstraints\n\n1 ≦ N ≦ 200,000\n\n(a_1, a_2, ..., a_N) is a permutation of (1, 2, ..., N).\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_N\n\nOutput\n\nPrint the answer.\n\nNote that the answer may not fit into a 32-bit integer.\n\nSample Input 1\n\n3\n2 1 3\n\nSample Output 1\n\n9\n\nSample Input 2\n\n4\n1 3 2 4\n\nSample Output 2\n\n19\n\nSample Input 3\n\n8\n5 4 8 1 2 6 7 3\n\nSample Output 3\n\n85", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 644, "cpu_time_ms": 2102, "memory_kb": 2688}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s469567004", "group_id": "codeNet:p03988", "input_text": "#include<bits/stdc++.h>\n#define N (1001)\nusing namespace std;\nint n,a[N],Keg[N],maxn;\nint main()\n{\n\tscanf(\"%d\",&n);\n\tfor (int i=1; i<=n; ++i)\n\t{\n\t\tscanf(\"%d\",&a[i]);\n\t\tKeg[a[i]]++; maxn=max(maxn,a[i]);\n\t}\n//\tfor (int i=(maxn+1)/2; i<=maxn; ++i)\n//\t{\n//\t\tif (maxn%2==0 && i==(maxn+1)/2) Keg[i]-=1;\n//\t\telse Keg[i]-=2;\n//\t\tif (Keg[i]<0){puts(\"Impossible\"); return 0;}\n//\t}\n//\tfor (int i=1; i<=maxn/2; ++i)\n//\t\tif (Keg[i]) {puts(\"Impossible\"); return 0;}\n\tputs(\"Impossible\"); return 0;\n}", "language": "C++", "metadata": {"date": 1534892020, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03988.html", "problem_id": "p03988", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03988/input.txt", "sample_output_relpath": "derived/input_output/data/p03988/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03988/C++/s469567004.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s469567004", "user_id": "u736934109"}, "prompt_components": {"gold_output": "Possible\n", "input_to_evaluate": "#include<bits/stdc++.h>\n#define N (1001)\nusing namespace std;\nint n,a[N],Keg[N],maxn;\nint main()\n{\n\tscanf(\"%d\",&n);\n\tfor (int i=1; i<=n; ++i)\n\t{\n\t\tscanf(\"%d\",&a[i]);\n\t\tKeg[a[i]]++; maxn=max(maxn,a[i]);\n\t}\n//\tfor (int i=(maxn+1)/2; i<=maxn; ++i)\n//\t{\n//\t\tif (maxn%2==0 && i==(maxn+1)/2) Keg[i]-=1;\n//\t\telse Keg[i]-=2;\n//\t\tif (Keg[i]<0){puts(\"Impossible\"); return 0;}\n//\t}\n//\tfor (int i=1; i<=maxn/2; ++i)\n//\t\tif (Keg[i]) {puts(\"Impossible\"); return 0;}\n\tputs(\"Impossible\"); return 0;\n}", "problem_context": "Score : 700 points\n\nProblem Statement\n\nAoki loves numerical sequences and trees.\n\nOne day, Takahashi gave him an integer sequence of length N, a_1, a_2, ..., a_N, which made him want to construct a tree.\n\nAoki wants to construct a tree with N vertices numbered 1 through N, such that for each i = 1,2,...,N, the distance between vertex i and the farthest vertex from it is a_i, assuming that the length of each edge is 1.\n\nDetermine whether such a tree exists.\n\nConstraints\n\n2 ≦ N ≦ 100\n\n1 ≦ a_i ≦ N-1\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_N\n\nOutput\n\nIf there exists a tree that satisfies the condition, print Possible. Otherwise, print Impossible.\n\nSample Input 1\n\n5\n3 2 2 3 3\n\nSample Output 1\n\nPossible\n\nThe diagram above shows an example of a tree that satisfies the conditions. The red arrows show paths from each vertex to the farthest vertex from it.\n\nSample Input 2\n\n3\n1 1 2\n\nSample Output 2\n\nImpossible\n\nSample Input 3\n\n10\n1 2 2 2 2 2 2 2 2 2\n\nSample Output 3\n\nPossible\n\nSample Input 4\n\n10\n1 1 2 2 2 2 2 2 2 2\n\nSample Output 4\n\nImpossible\n\nSample Input 5\n\n6\n1 1 1 1 1 5\n\nSample Output 5\n\nImpossible\n\nSample Input 6\n\n5\n4 3 2 3 4\n\nSample Output 6\n\nPossible", "sample_input": "5\n3 2 2 3 3\n"}, "reference_outputs": ["Possible\n"], "source_document_id": "p03988", "source_text": "Score : 700 points\n\nProblem Statement\n\nAoki loves numerical sequences and trees.\n\nOne day, Takahashi gave him an integer sequence of length N, a_1, a_2, ..., a_N, which made him want to construct a tree.\n\nAoki wants to construct a tree with N vertices numbered 1 through N, such that for each i = 1,2,...,N, the distance between vertex i and the farthest vertex from it is a_i, assuming that the length of each edge is 1.\n\nDetermine whether such a tree exists.\n\nConstraints\n\n2 ≦ N ≦ 100\n\n1 ≦ a_i ≦ N-1\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_N\n\nOutput\n\nIf there exists a tree that satisfies the condition, print Possible. Otherwise, print Impossible.\n\nSample Input 1\n\n5\n3 2 2 3 3\n\nSample Output 1\n\nPossible\n\nThe diagram above shows an example of a tree that satisfies the conditions. The red arrows show paths from each vertex to the farthest vertex from it.\n\nSample Input 2\n\n3\n1 1 2\n\nSample Output 2\n\nImpossible\n\nSample Input 3\n\n10\n1 2 2 2 2 2 2 2 2 2\n\nSample Output 3\n\nPossible\n\nSample Input 4\n\n10\n1 1 2 2 2 2 2 2 2 2\n\nSample Output 4\n\nImpossible\n\nSample Input 5\n\n6\n1 1 1 1 1 5\n\nSample Output 5\n\nImpossible\n\nSample Input 6\n\n5\n4 3 2 3 4\n\nSample Output 6\n\nPossible", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 484, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s493005057", "group_id": "codeNet:p03994", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  string s;cin >> s;\n  int k; cin >> k;\n  for(int i=0; i<s.size()-1; i++){\n    //cout << k << endl;\n    if(((int)s.at(i) - 96)==1||k==0){\n      continue;\n    }else if((27-((int)s.at(i) - 96))<=k){\n      \n      //cout << (int)s.at(i) << endl;\n      k -= 27-((int)s.at(i)-96);\n      s.at(i) = 'a';\n    }\n  }\n  //cout << k << endl;\n  k = k%26;\n  if(k!=0){\n    if(122<s.at(s.size()-1)+k){\n      s.at(s.size()-1) = (char)96+(s.at(s.size()-1)+k-122);\n    }else{\n      s.at(s.size()-1) = (char)s.at(s.size()-1)+k;\n    }\n  }\n  cout << s << endl;\n}\n      ", "language": "C++", "metadata": {"date": 1580791145, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03994.html", "problem_id": "p03994", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03994/input.txt", "sample_output_relpath": "derived/input_output/data/p03994/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03994/C++/s493005057.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s493005057", "user_id": "u091552241"}, "prompt_components": {"gold_output": "aya\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main(){\n  string s;cin >> s;\n  int k; cin >> k;\n  for(int i=0; i<s.size()-1; i++){\n    //cout << k << endl;\n    if(((int)s.at(i) - 96)==1||k==0){\n      continue;\n    }else if((27-((int)s.at(i) - 96))<=k){\n      \n      //cout << (int)s.at(i) << endl;\n      k -= 27-((int)s.at(i)-96);\n      s.at(i) = 'a';\n    }\n  }\n  //cout << k << endl;\n  k = k%26;\n  if(k!=0){\n    if(122<s.at(s.size()-1)+k){\n      s.at(s.size()-1) = (char)96+(s.at(s.size()-1)+k-122);\n    }else{\n      s.at(s.size()-1) = (char)s.at(s.size()-1)+k;\n    }\n  }\n  cout << s << endl;\n}\n      ", "problem_context": "Score : 400 points\n\nProblem Statement\n\nMr. Takahashi has a string s consisting of lowercase English letters.\nHe repeats the following operation on s exactly K times.\n\nChoose an arbitrary letter on s and change that letter to the next alphabet. Note that the next letter of z is a.\n\nFor example, if you perform an operation for the second letter on aaz, aaz becomes abz.\nIf you then perform an operation for the third letter on abz, abz becomes aba.\n\nMr. Takahashi wants to have the lexicographically smallest string after performing exactly K operations on s.\nFind the such string.\n\nConstraints\n\n1≤|s|≤10^5\n\nAll letters in s are lowercase English letters.\n\n1≤K≤10^9\n\nInput\n\nThe input is given from Standard Input in the following format:\n\ns\nK\n\nOutput\n\nPrint the lexicographically smallest string after performing exactly K operations on s.\n\nSample Input 1\n\nxyz\n4\n\nSample Output 1\n\naya\n\nFor example, you can perform the following operations: xyz, yyz, zyz, ayz, aya.\n\nSample Input 2\n\na\n25\n\nSample Output 2\n\nz\n\nYou have to perform exactly K operations.\n\nSample Input 3\n\ncodefestival\n100\n\nSample Output 3\n\naaaafeaaivap", "sample_input": "xyz\n4\n"}, "reference_outputs": ["aya\n"], "source_document_id": "p03994", "source_text": "Score : 400 points\n\nProblem Statement\n\nMr. Takahashi has a string s consisting of lowercase English letters.\nHe repeats the following operation on s exactly K times.\n\nChoose an arbitrary letter on s and change that letter to the next alphabet. Note that the next letter of z is a.\n\nFor example, if you perform an operation for the second letter on aaz, aaz becomes abz.\nIf you then perform an operation for the third letter on abz, abz becomes aba.\n\nMr. Takahashi wants to have the lexicographically smallest string after performing exactly K operations on s.\nFind the such string.\n\nConstraints\n\n1≤|s|≤10^5\n\nAll letters in s are lowercase English letters.\n\n1≤K≤10^9\n\nInput\n\nThe input is given from Standard Input in the following format:\n\ns\nK\n\nOutput\n\nPrint the lexicographically smallest string after performing exactly K operations on s.\n\nSample Input 1\n\nxyz\n4\n\nSample Output 1\n\naya\n\nFor example, you can perform the following operations: xyz, yyz, zyz, ayz, aya.\n\nSample Input 2\n\na\n25\n\nSample Output 2\n\nz\n\nYou have to perform exactly K operations.\n\nSample Input 3\n\ncodefestival\n100\n\nSample Output 3\n\naaaafeaaivap", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 605, "cpu_time_ms": 5, "memory_kb": 512}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s527948901", "group_id": "codeNet:p03994", "input_text": "#include <bits/stdc++.h>\n#define ll long long\nusing namespace std;\n\nint main(){\n  string s;\n  ll n;\n  cin>>s>>n;\n  ll len = s.size();\n  for(ll i=0;i<len-1;i++){\n    if(s[i]=='a')continue;\n    if('z'-s[i]+1<=n) {n=n-('z'-s[i]+1);s[i]='a';}\n    //cout<<n<<endl;\n  }\n  if(n>0) s[len-1] = 'a'+((s[len-1]-'a')+n)%26;\n  cout<<s<<endl;\n  return 0;\n}\n", "language": "C++", "metadata": {"date": 1474772881, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03994.html", "problem_id": "p03994", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03994/input.txt", "sample_output_relpath": "derived/input_output/data/p03994/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03994/C++/s527948901.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s527948901", "user_id": "u176841462"}, "prompt_components": {"gold_output": "aya\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#define ll long long\nusing namespace std;\n\nint main(){\n  string s;\n  ll n;\n  cin>>s>>n;\n  ll len = s.size();\n  for(ll i=0;i<len-1;i++){\n    if(s[i]=='a')continue;\n    if('z'-s[i]+1<=n) {n=n-('z'-s[i]+1);s[i]='a';}\n    //cout<<n<<endl;\n  }\n  if(n>0) s[len-1] = 'a'+((s[len-1]-'a')+n)%26;\n  cout<<s<<endl;\n  return 0;\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nMr. Takahashi has a string s consisting of lowercase English letters.\nHe repeats the following operation on s exactly K times.\n\nChoose an arbitrary letter on s and change that letter to the next alphabet. Note that the next letter of z is a.\n\nFor example, if you perform an operation for the second letter on aaz, aaz becomes abz.\nIf you then perform an operation for the third letter on abz, abz becomes aba.\n\nMr. Takahashi wants to have the lexicographically smallest string after performing exactly K operations on s.\nFind the such string.\n\nConstraints\n\n1≤|s|≤10^5\n\nAll letters in s are lowercase English letters.\n\n1≤K≤10^9\n\nInput\n\nThe input is given from Standard Input in the following format:\n\ns\nK\n\nOutput\n\nPrint the lexicographically smallest string after performing exactly K operations on s.\n\nSample Input 1\n\nxyz\n4\n\nSample Output 1\n\naya\n\nFor example, you can perform the following operations: xyz, yyz, zyz, ayz, aya.\n\nSample Input 2\n\na\n25\n\nSample Output 2\n\nz\n\nYou have to perform exactly K operations.\n\nSample Input 3\n\ncodefestival\n100\n\nSample Output 3\n\naaaafeaaivap", "sample_input": "xyz\n4\n"}, "reference_outputs": ["aya\n"], "source_document_id": "p03994", "source_text": "Score : 400 points\n\nProblem Statement\n\nMr. Takahashi has a string s consisting of lowercase English letters.\nHe repeats the following operation on s exactly K times.\n\nChoose an arbitrary letter on s and change that letter to the next alphabet. Note that the next letter of z is a.\n\nFor example, if you perform an operation for the second letter on aaz, aaz becomes abz.\nIf you then perform an operation for the third letter on abz, abz becomes aba.\n\nMr. Takahashi wants to have the lexicographically smallest string after performing exactly K operations on s.\nFind the such string.\n\nConstraints\n\n1≤|s|≤10^5\n\nAll letters in s are lowercase English letters.\n\n1≤K≤10^9\n\nInput\n\nThe input is given from Standard Input in the following format:\n\ns\nK\n\nOutput\n\nPrint the lexicographically smallest string after performing exactly K operations on s.\n\nSample Input 1\n\nxyz\n4\n\nSample Output 1\n\naya\n\nFor example, you can perform the following operations: xyz, yyz, zyz, ayz, aya.\n\nSample Input 2\n\na\n25\n\nSample Output 2\n\nz\n\nYou have to perform exactly K operations.\n\nSample Input 3\n\ncodefestival\n100\n\nSample Output 3\n\naaaafeaaivap", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 343, "cpu_time_ms": 6, "memory_kb": 640}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s675602968", "group_id": "codeNet:p03997", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n    int a,b,h;\n    cin>>a>>b>>h;\n    cout<<(a+b)*h/2<<endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1562977144, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03997.html", "problem_id": "p03997", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03997/input.txt", "sample_output_relpath": "derived/input_output/data/p03997/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03997/C++/s675602968.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s675602968", "user_id": "u930561195"}, "prompt_components": {"gold_output": "7\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(){\n    int a,b,h;\n    cin>>a>>b>>h;\n    cout<<(a+b)*h/2<<endl;\n    return 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nYou are given a trapezoid. The lengths of its upper base, lower base, and height are a, b, and h, respectively.\n\nAn example of a trapezoid\n\nFind the area of this trapezoid.\n\nConstraints\n\n1≦a≦100\n\n1≦b≦100\n\n1≦h≦100\n\nAll input values are integers.\n\nh is even.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\na\nb\nh\n\nOutput\n\nPrint the area of the given trapezoid. It is guaranteed that the area is an integer.\n\nSample Input 1\n\n3\n4\n2\n\nSample Output 1\n\n7\n\nWhen the lengths of the upper base, lower base, and height are 3, 4, and 2, respectively, the area of the trapezoid is (3+4)×2/2 = 7.\n\nSample Input 2\n\n4\n4\n4\n\nSample Output 2\n\n16\n\nIn this case, a parallelogram is given, which is also a trapezoid.", "sample_input": "3\n4\n2\n"}, "reference_outputs": ["7\n"], "source_document_id": "p03997", "source_text": "Score : 100 points\n\nProblem Statement\n\nYou are given a trapezoid. The lengths of its upper base, lower base, and height are a, b, and h, respectively.\n\nAn example of a trapezoid\n\nFind the area of this trapezoid.\n\nConstraints\n\n1≦a≦100\n\n1≦b≦100\n\n1≦h≦100\n\nAll input values are integers.\n\nh is even.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\na\nb\nh\n\nOutput\n\nPrint the area of the given trapezoid. It is guaranteed that the area is an integer.\n\nSample Input 1\n\n3\n4\n2\n\nSample Output 1\n\n7\n\nWhen the lengths of the upper base, lower base, and height are 3, 4, and 2, respectively, the area of the trapezoid is (3+4)×2/2 = 7.\n\nSample Input 2\n\n4\n4\n4\n\nSample Output 2\n\n16\n\nIn this case, a parallelogram is given, which is also a trapezoid.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 133, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s581541186", "group_id": "codeNet:p03997", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main( void ) {\n\n    int a, b, h;\n    cin >> a >> b >> h;\n    \n    cout << (a + b) * h / 2;\n    \n    return 0;\n}", "language": "C++", "metadata": {"date": 1493689138, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p03997.html", "problem_id": "p03997", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p03997/input.txt", "sample_output_relpath": "derived/input_output/data/p03997/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p03997/C++/s581541186.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s581541186", "user_id": "u741323508"}, "prompt_components": {"gold_output": "7\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main( void ) {\n\n    int a, b, h;\n    cin >> a >> b >> h;\n    \n    cout << (a + b) * h / 2;\n    \n    return 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nYou are given a trapezoid. The lengths of its upper base, lower base, and height are a, b, and h, respectively.\n\nAn example of a trapezoid\n\nFind the area of this trapezoid.\n\nConstraints\n\n1≦a≦100\n\n1≦b≦100\n\n1≦h≦100\n\nAll input values are integers.\n\nh is even.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\na\nb\nh\n\nOutput\n\nPrint the area of the given trapezoid. It is guaranteed that the area is an integer.\n\nSample Input 1\n\n3\n4\n2\n\nSample Output 1\n\n7\n\nWhen the lengths of the upper base, lower base, and height are 3, 4, and 2, respectively, the area of the trapezoid is (3+4)×2/2 = 7.\n\nSample Input 2\n\n4\n4\n4\n\nSample Output 2\n\n16\n\nIn this case, a parallelogram is given, which is also a trapezoid.", "sample_input": "3\n4\n2\n"}, "reference_outputs": ["7\n"], "source_document_id": "p03997", "source_text": "Score : 100 points\n\nProblem Statement\n\nYou are given a trapezoid. The lengths of its upper base, lower base, and height are a, b, and h, respectively.\n\nAn example of a trapezoid\n\nFind the area of this trapezoid.\n\nConstraints\n\n1≦a≦100\n\n1≦b≦100\n\n1≦h≦100\n\nAll input values are integers.\n\nh is even.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\na\nb\nh\n\nOutput\n\nPrint the area of the given trapezoid. It is guaranteed that the area is an integer.\n\nSample Input 1\n\n3\n4\n2\n\nSample Output 1\n\n7\n\nWhen the lengths of the upper base, lower base, and height are 3, 4, and 2, respectively, the area of the trapezoid is (3+4)×2/2 = 7.\n\nSample Input 2\n\n4\n4\n4\n\nSample Output 2\n\n16\n\nIn this case, a parallelogram is given, which is also a trapezoid.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 162, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s065669664", "group_id": "codeNet:p04003", "input_text": "#include <bits/stdc++.h>\n\nusing namespace std;\n\ntypedef pair<int, int> P;\ntypedef vector< vector<P> > graph;\n\nconst int INF = 10000000;\nconst int NONE = -1;\n\nstruct Node {\n    int at;\n    int cost; \n    int prev;\n    Node(int at, int cost, int prev) : at(at), cost(cost), prev(prev) {}\n    bool operator>(const Node &s) const {\n        return cost > s.cost;\n    }\n};\n\nint main() {\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n    int n, m;\n    scanf(\"%d %d\", &n, &m);\n    graph e(n);\n    for (int i = 0; i < m; i++) {\n        int p, q, c;\n        scanf(\"%d %d %d\", &p, &q, &c);\n        p--;\n        q--;\n        e[p].emplace_back(q, c);\n        e[q].emplace_back(p, c);\n    }\n    set<P> memo;\n    vector<int> minc(n, INF);\n    priority_queue<Node, vector<Node>, greater<Node> > pq;\n    pq.push(Node(0, 0, NONE));\n    //P g(n - 1, NONE);\n    while (!pq.empty()) {\n        Node x = pq.top();\n        pq.pop();\n        P key(x.at, x.prev);\n        if (memo.find(key) != memo.end()) continue;\n        if (x.cost > minc[x.at]) continue;\n        if (x.at == n - 1) {\n            cout << x.cost << \"\\n\";\n            return 0;\n        }\n        memo.insert(key);\n        minc[x.at] = x.cost;\n        for (auto i = e[x.at].begin(), f = e[x.at].end(); i != f; ++i) {            \n            if (memo.find(*i) != memo.end()) continue;\n            int to = i->first;\n            int c = (*i).second;\n            int cost = x.cost + (x.prev != c);\n            if (cost < minc[to]) pq.push(Node(to, cost, c));\n        }\n    }\n    cout << \"-1\\n\";\n    return 0;\n}", "language": "C++", "metadata": {"date": 1473656059, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p04003.html", "problem_id": "p04003", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p04003/input.txt", "sample_output_relpath": "derived/input_output/data/p04003/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p04003/C++/s065669664.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s065669664", "user_id": "u553623615"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\nusing namespace std;\n\ntypedef pair<int, int> P;\ntypedef vector< vector<P> > graph;\n\nconst int INF = 10000000;\nconst int NONE = -1;\n\nstruct Node {\n    int at;\n    int cost; \n    int prev;\n    Node(int at, int cost, int prev) : at(at), cost(cost), prev(prev) {}\n    bool operator>(const Node &s) const {\n        return cost > s.cost;\n    }\n};\n\nint main() {\n    cin.tie(0);\n    ios::sync_with_stdio(false);\n    int n, m;\n    scanf(\"%d %d\", &n, &m);\n    graph e(n);\n    for (int i = 0; i < m; i++) {\n        int p, q, c;\n        scanf(\"%d %d %d\", &p, &q, &c);\n        p--;\n        q--;\n        e[p].emplace_back(q, c);\n        e[q].emplace_back(p, c);\n    }\n    set<P> memo;\n    vector<int> minc(n, INF);\n    priority_queue<Node, vector<Node>, greater<Node> > pq;\n    pq.push(Node(0, 0, NONE));\n    //P g(n - 1, NONE);\n    while (!pq.empty()) {\n        Node x = pq.top();\n        pq.pop();\n        P key(x.at, x.prev);\n        if (memo.find(key) != memo.end()) continue;\n        if (x.cost > minc[x.at]) continue;\n        if (x.at == n - 1) {\n            cout << x.cost << \"\\n\";\n            return 0;\n        }\n        memo.insert(key);\n        minc[x.at] = x.cost;\n        for (auto i = e[x.at].begin(), f = e[x.at].end(); i != f; ++i) {            \n            if (memo.find(*i) != memo.end()) continue;\n            int to = i->first;\n            int c = (*i).second;\n            int cost = x.cost + (x.prev != c);\n            if (cost < minc[to]) pq.push(Node(to, cost, c));\n        }\n    }\n    cout << \"-1\\n\";\n    return 0;\n}", "problem_context": "Score : 600 points\n\nProblem Statement\n\nSnuke's town has a subway system, consisting of N stations and M railway lines. The stations are numbered 1 through N. Each line is operated by a company. Each company has an identification number.\n\nThe i-th ( 1 \\leq i \\leq M ) line connects station p_i and q_i bidirectionally. There is no intermediate station. This line is operated by company c_i.\n\nYou can change trains at a station where multiple lines are available.\n\nThe fare system used in this subway system is a bit strange. When a passenger only uses lines that are operated by the same company, the fare is 1 yen (the currency of Japan). Whenever a passenger changes to a line that is operated by a different company from the current line, the passenger is charged an additional fare of 1 yen. In a case where a passenger who changed from some company A's line to another company's line changes to company A's line again, the additional fare is incurred again.\n\nSnuke is now at station 1 and wants to travel to station N by subway. Find the minimum required fare.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n0 \\leq M \\leq 2×10^5\n\n1 \\leq p_i \\leq N (1 \\leq i \\leq M)\n\n1 \\leq q_i \\leq N (1 \\leq i \\leq M)\n\n1 \\leq c_i \\leq 10^6 (1 \\leq i \\leq M)\n\np_i \\neq q_i (1 \\leq i \\leq M)\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN M\np_1 q_1 c_1\n:\np_M q_M c_M\n\nOutput\n\nPrint the minimum required fare. If it is impossible to get to station N by subway, print -1 instead.\n\nSample Input 1\n\n3 3\n1 2 1\n2 3 1\n3 1 2\n\nSample Output 1\n\n1\n\nUse company 1's lines: 1 → 2 → 3. The fare is 1 yen.\n\nSample Input 2\n\n8 11\n1 3 1\n1 4 2\n2 3 1\n2 5 1\n3 4 3\n3 6 3\n3 7 3\n4 8 4\n5 6 1\n6 7 5\n7 8 5\n\nSample Output 2\n\n2\n\nFirst, use company 1's lines: 1 → 3 → 2 → 5 → 6. Then, use company 5's lines: 6 → 7 → 8. The fare is 2 yen.\n\nSample Input 3\n\n2 0\n\nSample Output 3\n\n-1", "sample_input": "3 3\n1 2 1\n2 3 1\n3 1 2\n"}, "reference_outputs": ["1\n"], "source_document_id": "p04003", "source_text": "Score : 600 points\n\nProblem Statement\n\nSnuke's town has a subway system, consisting of N stations and M railway lines. The stations are numbered 1 through N. Each line is operated by a company. Each company has an identification number.\n\nThe i-th ( 1 \\leq i \\leq M ) line connects station p_i and q_i bidirectionally. There is no intermediate station. This line is operated by company c_i.\n\nYou can change trains at a station where multiple lines are available.\n\nThe fare system used in this subway system is a bit strange. When a passenger only uses lines that are operated by the same company, the fare is 1 yen (the currency of Japan). Whenever a passenger changes to a line that is operated by a different company from the current line, the passenger is charged an additional fare of 1 yen. In a case where a passenger who changed from some company A's line to another company's line changes to company A's line again, the additional fare is incurred again.\n\nSnuke is now at station 1 and wants to travel to station N by subway. Find the minimum required fare.\n\nConstraints\n\n2 \\leq N \\leq 10^5\n\n0 \\leq M \\leq 2×10^5\n\n1 \\leq p_i \\leq N (1 \\leq i \\leq M)\n\n1 \\leq q_i \\leq N (1 \\leq i \\leq M)\n\n1 \\leq c_i \\leq 10^6 (1 \\leq i \\leq M)\n\np_i \\neq q_i (1 \\leq i \\leq M)\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN M\np_1 q_1 c_1\n:\np_M q_M c_M\n\nOutput\n\nPrint the minimum required fare. If it is impossible to get to station N by subway, print -1 instead.\n\nSample Input 1\n\n3 3\n1 2 1\n2 3 1\n3 1 2\n\nSample Output 1\n\n1\n\nUse company 1's lines: 1 → 2 → 3. The fare is 1 yen.\n\nSample Input 2\n\n8 11\n1 3 1\n1 4 2\n2 3 1\n2 5 1\n3 4 3\n3 6 3\n3 7 3\n4 8 4\n5 6 1\n6 7 5\n7 8 5\n\nSample Output 2\n\n2\n\nFirst, use company 1's lines: 1 → 3 → 2 → 5 → 6. Then, use company 5's lines: 6 → 7 → 8. The fare is 2 yen.\n\nSample Input 3\n\n2 0\n\nSample Output 3\n\n-1", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1551, "cpu_time_ms": 3169, "memory_kb": 201016}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s495864508", "group_id": "codeNet:p04005", "input_text": "/*input\n5 3 5\n*/\n#include <bits/stdc++.h>\n#pragma GCC optimize(\"unroll-loops,no-stack-protector\")\n#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> pii;\ntypedef pair<ll,ll> pll;\ntypedef pair<double,double> pdd;\n#define IOS ios_base::sync_with_stdio(0); cin.tie(0)\n#define ALL(a) a.begin(),a.end()\n#define SZ(a) ((int)a.size())\n#define F first\n#define S second\n#define REP(i,n) for(int i=0;i<((int)n);i++)\n#define pb push_back\n#define MP(a,b) make_pair(a,b)\n#define SORT_UNIQUE(c) (sort(c.begin(),c.end()), c.resize(distance(c.begin(),unique(c.begin(),c.end()))))\n#define GET_POS(c,x) (lower_bound(c.begin(),c.end(),x)-c.begin())\ntemplate<typename T1,typename T2>\nostream& operator<<(ostream& out,pair<T1,T2> P){\n\tout<<'('<<P.F<<','<<P.S<<')';\n\treturn out;\n}\n\n//}}}\nconst ll maxn=300005;\nconst ll maxlg=__lg(maxn)+2;\nconst ll INF64=8000000000000000000LL;\nconst int INF=0x3f3f3f3f;\nconst ll MOD=ll(1e9+7);\nconst double PI=acos(-1);\n//const ll p=880301;\n//const ll P=31;\n\nll mypow(ll a,ll b){\n\tll res=1LL;\n\twhile(b){\n\t\tif(b&1) res=res*a%MOD;\n\t\ta=a*a%MOD;\n\t\t\n\t\tb>>=1;\n\t}\n\treturn res;\n}\nset<char> st;\nint main()\n{\n\tIOS;\n\tll a,b,c;\n\tcin>>a>>b>>c;\n\tif(a%2&&b%2&&c%2){\n\t\tcout<<min({a*b,a*c,b*c});\n\t}\n\telse cout<<0;\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1553349266, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p04005.html", "problem_id": "p04005", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p04005/input.txt", "sample_output_relpath": "derived/input_output/data/p04005/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p04005/C++/s495864508.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s495864508", "user_id": "u010467501"}, "prompt_components": {"gold_output": "9\n", "input_to_evaluate": "/*input\n5 3 5\n*/\n#include <bits/stdc++.h>\n#pragma GCC optimize(\"unroll-loops,no-stack-protector\")\n#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\nusing namespace std;\ntypedef long long ll;\ntypedef pair<int,int> pii;\ntypedef pair<ll,ll> pll;\ntypedef pair<double,double> pdd;\n#define IOS ios_base::sync_with_stdio(0); cin.tie(0)\n#define ALL(a) a.begin(),a.end()\n#define SZ(a) ((int)a.size())\n#define F first\n#define S second\n#define REP(i,n) for(int i=0;i<((int)n);i++)\n#define pb push_back\n#define MP(a,b) make_pair(a,b)\n#define SORT_UNIQUE(c) (sort(c.begin(),c.end()), c.resize(distance(c.begin(),unique(c.begin(),c.end()))))\n#define GET_POS(c,x) (lower_bound(c.begin(),c.end(),x)-c.begin())\ntemplate<typename T1,typename T2>\nostream& operator<<(ostream& out,pair<T1,T2> P){\n\tout<<'('<<P.F<<','<<P.S<<')';\n\treturn out;\n}\n\n//}}}\nconst ll maxn=300005;\nconst ll maxlg=__lg(maxn)+2;\nconst ll INF64=8000000000000000000LL;\nconst int INF=0x3f3f3f3f;\nconst ll MOD=ll(1e9+7);\nconst double PI=acos(-1);\n//const ll p=880301;\n//const ll P=31;\n\nll mypow(ll a,ll b){\n\tll res=1LL;\n\twhile(b){\n\t\tif(b&1) res=res*a%MOD;\n\t\ta=a*a%MOD;\n\t\t\n\t\tb>>=1;\n\t}\n\treturn res;\n}\nset<char> st;\nint main()\n{\n\tIOS;\n\tll a,b,c;\n\tcin>>a>>b>>c;\n\tif(a%2&&b%2&&c%2){\n\t\tcout<<min({a*b,a*c,b*c});\n\t}\n\telse cout<<0;\n\treturn 0;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nWe have a rectangular parallelepiped of size A×B×C, built with blocks of size 1×1×1. Snuke will paint each of the A×B×C blocks either red or blue, so that:\n\nThere is at least one red block and at least one blue block.\n\nThe union of all red blocks forms a rectangular parallelepiped.\n\nThe union of all blue blocks forms a rectangular parallelepiped.\n\nSnuke wants to minimize the difference between the number of red blocks and the number of blue blocks. Find the minimum possible difference.\n\nConstraints\n\n2≤A,B,C≤10^9\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nA B C\n\nOutput\n\nPrint the minimum possible difference between the number of red blocks and the number of blue blocks.\n\nSample Input 1\n\n3 3 3\n\nSample Output 1\n\n9\n\nFor example, Snuke can paint the blocks as shown in the diagram below.\nThere are 9 red blocks and 18 blue blocks, thus the difference is 9.\n\nSample Input 2\n\n2 2 4\n\nSample Output 2\n\n0\n\nFor example, Snuke can paint the blocks as shown in the diagram below.\nThere are 8 red blocks and 8 blue blocks, thus the difference is 0.\n\nSample Input 3\n\n5 3 5\n\nSample Output 3\n\n15\n\nFor example, Snuke can paint the blocks as shown in the diagram below.\nThere are 45 red blocks and 30 blue blocks, thus the difference is 9.", "sample_input": "3 3 3\n"}, "reference_outputs": ["9\n"], "source_document_id": "p04005", "source_text": "Score : 200 points\n\nProblem Statement\n\nWe have a rectangular parallelepiped of size A×B×C, built with blocks of size 1×1×1. Snuke will paint each of the A×B×C blocks either red or blue, so that:\n\nThere is at least one red block and at least one blue block.\n\nThe union of all red blocks forms a rectangular parallelepiped.\n\nThe union of all blue blocks forms a rectangular parallelepiped.\n\nSnuke wants to minimize the difference between the number of red blocks and the number of blue blocks. Find the minimum possible difference.\n\nConstraints\n\n2≤A,B,C≤10^9\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nA B C\n\nOutput\n\nPrint the minimum possible difference between the number of red blocks and the number of blue blocks.\n\nSample Input 1\n\n3 3 3\n\nSample Output 1\n\n9\n\nFor example, Snuke can paint the blocks as shown in the diagram below.\nThere are 9 red blocks and 18 blue blocks, thus the difference is 9.\n\nSample Input 2\n\n2 2 4\n\nSample Output 2\n\n0\n\nFor example, Snuke can paint the blocks as shown in the diagram below.\nThere are 8 red blocks and 8 blue blocks, thus the difference is 0.\n\nSample Input 3\n\n5 3 5\n\nSample Output 3\n\n15\n\nFor example, Snuke can paint the blocks as shown in the diagram below.\nThere are 45 red blocks and 30 blue blocks, thus the difference is 9.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1313, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s414112585", "group_id": "codeNet:p04006", "input_text": "#include <bits/stdc++.h>\ntypedef long long ll;\nconst int INF = 1e9,MOD = 1e9+7,ohara = 1e6;\nconst ll LINF = 1e18;\nusing namespace std;\n\n#define rep(i,n) for(ll (i)=0;(i)<(int)(n);(i)++)\n#define rrep(i,a,b) for(ll i=(a);i<(b);i++)\n#define rrrep(i,a,b) for(ll i=(a);i>=(b);i--)\n#define all(v) (v).begin(), (v).end()\n#define pb(q) push_back(q)\n#define Size(n) (n).size()\n#define Cout(x) cout<<(x)<<endl\n\nll n,cnt=0,ans=LINF,a[ohara],b,c,d,cmp,cmpp,m,h,w,x,y,sum=0,pos,hozon[2000+10][2000+10];\nint dy[]={1,0,-1,0};\nint dx[]={0,1,0,-1};\n//int dy[]={-1,0,1,-1,1,-1,0,1};\n//int dx[]={-1,-1,-1,0,0,1,1,1};\nstring alph(\"abcdefghijklmnopqrstuvwxyz\"),s;\nbool fl;\nstruct edge{int to,cost;};\n\n//-------------------------↓↓↓↓↓↓------------------------\n\nint main(void){\n       cin.tie(0);\n    ios::sync_with_stdio(false);\n      \n    cin>>n>>x;\n    rep(i,n)cin>>a[i],a[i+n]=a[i];\n    rrep(i,n,2*n){\n        cnt=0;\n        rrrep(j,i,i-n+1){\n            if(cnt!=0)hozon[i-n][cnt]=min(hozon[i-n][cnt-1],a[j]);\n            else hozon[i-n][cnt]=a[j];\n            cnt++;\n        }\n    }\n    rep(mahou,n+1){\n        cnt=mahou*x;\n        rrep(i,n,2*n){\n            cnt+=hozon[i-n][mahou];\n        }\n         ans=min(ans,cnt);\n    }\n    Cout(ans);\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1541644464, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p04006.html", "problem_id": "p04006", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p04006/input.txt", "sample_output_relpath": "derived/input_output/data/p04006/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p04006/C++/s414112585.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s414112585", "user_id": "u876335718"}, "prompt_components": {"gold_output": "12\n", "input_to_evaluate": "#include <bits/stdc++.h>\ntypedef long long ll;\nconst int INF = 1e9,MOD = 1e9+7,ohara = 1e6;\nconst ll LINF = 1e18;\nusing namespace std;\n\n#define rep(i,n) for(ll (i)=0;(i)<(int)(n);(i)++)\n#define rrep(i,a,b) for(ll i=(a);i<(b);i++)\n#define rrrep(i,a,b) for(ll i=(a);i>=(b);i--)\n#define all(v) (v).begin(), (v).end()\n#define pb(q) push_back(q)\n#define Size(n) (n).size()\n#define Cout(x) cout<<(x)<<endl\n\nll n,cnt=0,ans=LINF,a[ohara],b,c,d,cmp,cmpp,m,h,w,x,y,sum=0,pos,hozon[2000+10][2000+10];\nint dy[]={1,0,-1,0};\nint dx[]={0,1,0,-1};\n//int dy[]={-1,0,1,-1,1,-1,0,1};\n//int dx[]={-1,-1,-1,0,0,1,1,1};\nstring alph(\"abcdefghijklmnopqrstuvwxyz\"),s;\nbool fl;\nstruct edge{int to,cost;};\n\n//-------------------------↓↓↓↓↓↓------------------------\n\nint main(void){\n       cin.tie(0);\n    ios::sync_with_stdio(false);\n      \n    cin>>n>>x;\n    rep(i,n)cin>>a[i],a[i+n]=a[i];\n    rrep(i,n,2*n){\n        cnt=0;\n        rrrep(j,i,i-n+1){\n            if(cnt!=0)hozon[i-n][cnt]=min(hozon[i-n][cnt-1],a[j]);\n            else hozon[i-n][cnt]=a[j];\n            cnt++;\n        }\n    }\n    rep(mahou,n+1){\n        cnt=mahou*x;\n        rrep(i,n,2*n){\n            cnt+=hozon[i-n][mahou];\n        }\n         ans=min(ans,cnt);\n    }\n    Cout(ans);\n    return 0;\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nSnuke lives in another world, where slimes are real creatures and kept by some people.\nSlimes come in N colors. Those colors are conveniently numbered 1 through N.\nSnuke currently has no slime. His objective is to have slimes of all the colors together.\n\nSnuke can perform the following two actions:\n\nSelect a color i (1≤i≤N), such that he does not currently have a slime in color i, and catch a slime in color i. This action takes him a_i seconds.\n\nCast a spell, which changes the color of all the slimes that he currently has. The color of a slime in color i (1≤i≤N-1) will become color i+1, and the color of a slime in color N will become color 1. This action takes him x seconds.\n\nFind the minimum time that Snuke needs to have slimes in all N colors.\n\nConstraints\n\n2≤N≤2,000\n\na_i are integers.\n\n1≤a_i≤10^9\n\nx is an integer.\n\n1≤x≤10^9\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN x\na_1 a_2 ... a_N\n\nOutput\n\nFind the minimum time that Snuke needs to have slimes in all N colors.\n\nSample Input 1\n\n2 10\n1 100\n\nSample Output 1\n\n12\n\nSnuke can act as follows:\n\nCatch a slime in color 1. This takes 1 second.\n\nCast the spell. The color of the slime changes: 1 → 2. This takes 10 seconds.\n\nCatch a slime in color 1. This takes 1 second.\n\nSample Input 2\n\n3 10\n100 1 100\n\nSample Output 2\n\n23\n\nSnuke can act as follows:\n\nCatch a slime in color 2. This takes 1 second.\n\nCast the spell. The color of the slime changes: 2 → 3. This takes 10 seconds.\n\nCatch a slime in color 2. This takes 1 second.\n\nCast the soell. The color of each slime changes: 3 → 1, 2 → 3. This takes 10 seconds.\n\nCatch a slime in color 2. This takes 1 second.\n\nSample Input 3\n\n4 10\n1 2 3 4\n\nSample Output 3\n\n10\n\nSnuke can act as follows:\n\nCatch a slime in color 1. This takes 1 second.\n\nCatch a slime in color 2. This takes 2 seconds.\n\nCatch a slime in color 3. This takes 3 seconds.\n\nCatch a slime in color 4. This takes 4 seconds.", "sample_input": "2 10\n1 100\n"}, "reference_outputs": ["12\n"], "source_document_id": "p04006", "source_text": "Score : 400 points\n\nProblem Statement\n\nSnuke lives in another world, where slimes are real creatures and kept by some people.\nSlimes come in N colors. Those colors are conveniently numbered 1 through N.\nSnuke currently has no slime. His objective is to have slimes of all the colors together.\n\nSnuke can perform the following two actions:\n\nSelect a color i (1≤i≤N), such that he does not currently have a slime in color i, and catch a slime in color i. This action takes him a_i seconds.\n\nCast a spell, which changes the color of all the slimes that he currently has. The color of a slime in color i (1≤i≤N-1) will become color i+1, and the color of a slime in color N will become color 1. This action takes him x seconds.\n\nFind the minimum time that Snuke needs to have slimes in all N colors.\n\nConstraints\n\n2≤N≤2,000\n\na_i are integers.\n\n1≤a_i≤10^9\n\nx is an integer.\n\n1≤x≤10^9\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN x\na_1 a_2 ... a_N\n\nOutput\n\nFind the minimum time that Snuke needs to have slimes in all N colors.\n\nSample Input 1\n\n2 10\n1 100\n\nSample Output 1\n\n12\n\nSnuke can act as follows:\n\nCatch a slime in color 1. This takes 1 second.\n\nCast the spell. The color of the slime changes: 1 → 2. This takes 10 seconds.\n\nCatch a slime in color 1. This takes 1 second.\n\nSample Input 2\n\n3 10\n100 1 100\n\nSample Output 2\n\n23\n\nSnuke can act as follows:\n\nCatch a slime in color 2. This takes 1 second.\n\nCast the spell. The color of the slime changes: 2 → 3. This takes 10 seconds.\n\nCatch a slime in color 2. This takes 1 second.\n\nCast the soell. The color of each slime changes: 3 → 1, 2 → 3. This takes 10 seconds.\n\nCatch a slime in color 2. This takes 1 second.\n\nSample Input 3\n\n4 10\n1 2 3 4\n\nSample Output 3\n\n10\n\nSnuke can act as follows:\n\nCatch a slime in color 1. This takes 1 second.\n\nCatch a slime in color 2. This takes 2 seconds.\n\nCatch a slime in color 3. This takes 3 seconds.\n\nCatch a slime in color 4. This takes 4 seconds.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1251, "cpu_time_ms": 28, "memory_kb": 33024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s101232679", "group_id": "codeNet:p04006", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n  long long n, x;\n  long long count = 0;\n  cin >> n >> x;\n\n  vector<long long> v(n, 0);\n\n  for (int i = 0; i < n; i++)\n  {\n    cin >> v[i];\n  }\n\n  sort(v.begin(),v.end());\n\n  for (int i = 0; i < n; i++)\n  {\n    if (v[0] + x < v[i])\n    {\n      count += v[0] + x;\n    }\n    else \n      count += v[i];\n  }\n\n  cout << count << endl;\n\n\n}\n", "language": "C++", "metadata": {"date": 1529970900, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p04006.html", "problem_id": "p04006", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p04006/input.txt", "sample_output_relpath": "derived/input_output/data/p04006/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p04006/C++/s101232679.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s101232679", "user_id": "u471368568"}, "prompt_components": {"gold_output": "12\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint main()\n{\n  long long n, x;\n  long long count = 0;\n  cin >> n >> x;\n\n  vector<long long> v(n, 0);\n\n  for (int i = 0; i < n; i++)\n  {\n    cin >> v[i];\n  }\n\n  sort(v.begin(),v.end());\n\n  for (int i = 0; i < n; i++)\n  {\n    if (v[0] + x < v[i])\n    {\n      count += v[0] + x;\n    }\n    else \n      count += v[i];\n  }\n\n  cout << count << endl;\n\n\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nSnuke lives in another world, where slimes are real creatures and kept by some people.\nSlimes come in N colors. Those colors are conveniently numbered 1 through N.\nSnuke currently has no slime. His objective is to have slimes of all the colors together.\n\nSnuke can perform the following two actions:\n\nSelect a color i (1≤i≤N), such that he does not currently have a slime in color i, and catch a slime in color i. This action takes him a_i seconds.\n\nCast a spell, which changes the color of all the slimes that he currently has. The color of a slime in color i (1≤i≤N-1) will become color i+1, and the color of a slime in color N will become color 1. This action takes him x seconds.\n\nFind the minimum time that Snuke needs to have slimes in all N colors.\n\nConstraints\n\n2≤N≤2,000\n\na_i are integers.\n\n1≤a_i≤10^9\n\nx is an integer.\n\n1≤x≤10^9\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN x\na_1 a_2 ... a_N\n\nOutput\n\nFind the minimum time that Snuke needs to have slimes in all N colors.\n\nSample Input 1\n\n2 10\n1 100\n\nSample Output 1\n\n12\n\nSnuke can act as follows:\n\nCatch a slime in color 1. This takes 1 second.\n\nCast the spell. The color of the slime changes: 1 → 2. This takes 10 seconds.\n\nCatch a slime in color 1. This takes 1 second.\n\nSample Input 2\n\n3 10\n100 1 100\n\nSample Output 2\n\n23\n\nSnuke can act as follows:\n\nCatch a slime in color 2. This takes 1 second.\n\nCast the spell. The color of the slime changes: 2 → 3. This takes 10 seconds.\n\nCatch a slime in color 2. This takes 1 second.\n\nCast the soell. The color of each slime changes: 3 → 1, 2 → 3. This takes 10 seconds.\n\nCatch a slime in color 2. This takes 1 second.\n\nSample Input 3\n\n4 10\n1 2 3 4\n\nSample Output 3\n\n10\n\nSnuke can act as follows:\n\nCatch a slime in color 1. This takes 1 second.\n\nCatch a slime in color 2. This takes 2 seconds.\n\nCatch a slime in color 3. This takes 3 seconds.\n\nCatch a slime in color 4. This takes 4 seconds.", "sample_input": "2 10\n1 100\n"}, "reference_outputs": ["12\n"], "source_document_id": "p04006", "source_text": "Score : 400 points\n\nProblem Statement\n\nSnuke lives in another world, where slimes are real creatures and kept by some people.\nSlimes come in N colors. Those colors are conveniently numbered 1 through N.\nSnuke currently has no slime. His objective is to have slimes of all the colors together.\n\nSnuke can perform the following two actions:\n\nSelect a color i (1≤i≤N), such that he does not currently have a slime in color i, and catch a slime in color i. This action takes him a_i seconds.\n\nCast a spell, which changes the color of all the slimes that he currently has. The color of a slime in color i (1≤i≤N-1) will become color i+1, and the color of a slime in color N will become color 1. This action takes him x seconds.\n\nFind the minimum time that Snuke needs to have slimes in all N colors.\n\nConstraints\n\n2≤N≤2,000\n\na_i are integers.\n\n1≤a_i≤10^9\n\nx is an integer.\n\n1≤x≤10^9\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN x\na_1 a_2 ... a_N\n\nOutput\n\nFind the minimum time that Snuke needs to have slimes in all N colors.\n\nSample Input 1\n\n2 10\n1 100\n\nSample Output 1\n\n12\n\nSnuke can act as follows:\n\nCatch a slime in color 1. This takes 1 second.\n\nCast the spell. The color of the slime changes: 1 → 2. This takes 10 seconds.\n\nCatch a slime in color 1. This takes 1 second.\n\nSample Input 2\n\n3 10\n100 1 100\n\nSample Output 2\n\n23\n\nSnuke can act as follows:\n\nCatch a slime in color 2. This takes 1 second.\n\nCast the spell. The color of the slime changes: 2 → 3. This takes 10 seconds.\n\nCatch a slime in color 2. This takes 1 second.\n\nCast the soell. The color of each slime changes: 3 → 1, 2 → 3. This takes 10 seconds.\n\nCatch a slime in color 2. This takes 1 second.\n\nSample Input 3\n\n4 10\n1 2 3 4\n\nSample Output 3\n\n10\n\nSnuke can act as follows:\n\nCatch a slime in color 1. This takes 1 second.\n\nCatch a slime in color 2. This takes 2 seconds.\n\nCatch a slime in color 3. This takes 3 seconds.\n\nCatch a slime in color 4. This takes 4 seconds.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 394, "cpu_time_ms": 2, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s643455170", "group_id": "codeNet:p04007", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nint h,w,col;\nchar mp[600][600],a[600][600],b[600][600];\nint main()\n{\n\tscanf(\"%d%d\",&h,&w);\n\tfor(int i=1;i<=h;i++)\n\t\tscanf(\"%s\",mp[i]+1);\n\tmemset(a,'.',sizeof(a));\n\tmemset(b,'.',sizeof(b));\n\tcol=0;\n\tfor(int i=1;i<=h;i++)\n\t{\n\t\tcol=1-col;\n\t\tif(col)\n\t\t{\n\t\t\tfor(int j=1;j<=w;j++)\n\t\t\t{\n\t\t\t\ta[i][j]='#';\n\t\t\t\tif(mp[i][j]=='#') b[i][j]='#';\n\t\t\t}\n\t\t}\n\t\telse\n\t\t{\n\t\t\tfor(int j=1;j<=w;j++)\n\t\t\t{\n\t\t\t\tb[i][j]='#';\n\t\t\t\tif(mp[i][j]=='#') a[i][j]='#';\n\t\t\t}\n\t\t}\n\t}\n\tfor(int i=1;i<=h;i++)\n\t{\n\t\tfor(int j=1;j<=w;j++)\n\t\t\tprintf(\"%c\",a[i][j]);\n\t\tputs(\"\");\n\t}\n\tputs(\"\");\n\tfor(int i=1;i<=h;i++)\n\t{\n\t\tfor(int j=1;j<=w;j++)\n\t\t\tprintf(\"%c\",b[i][j]);\n\t\tputs(\"\");\n\t}\n}", "language": "C++", "metadata": {"date": 1538251591, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p04007.html", "problem_id": "p04007", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p04007/input.txt", "sample_output_relpath": "derived/input_output/data/p04007/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p04007/C++/s643455170.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s643455170", "user_id": "u873278439"}, "prompt_components": {"gold_output": ".....\n#####\n#....\n#####\n.....\n\n.###.\n.#.#.\n.#.#.\n.#.#.\n.....\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nint h,w,col;\nchar mp[600][600],a[600][600],b[600][600];\nint main()\n{\n\tscanf(\"%d%d\",&h,&w);\n\tfor(int i=1;i<=h;i++)\n\t\tscanf(\"%s\",mp[i]+1);\n\tmemset(a,'.',sizeof(a));\n\tmemset(b,'.',sizeof(b));\n\tcol=0;\n\tfor(int i=1;i<=h;i++)\n\t{\n\t\tcol=1-col;\n\t\tif(col)\n\t\t{\n\t\t\tfor(int j=1;j<=w;j++)\n\t\t\t{\n\t\t\t\ta[i][j]='#';\n\t\t\t\tif(mp[i][j]=='#') b[i][j]='#';\n\t\t\t}\n\t\t}\n\t\telse\n\t\t{\n\t\t\tfor(int j=1;j<=w;j++)\n\t\t\t{\n\t\t\t\tb[i][j]='#';\n\t\t\t\tif(mp[i][j]=='#') a[i][j]='#';\n\t\t\t}\n\t\t}\n\t}\n\tfor(int i=1;i<=h;i++)\n\t{\n\t\tfor(int j=1;j<=w;j++)\n\t\t\tprintf(\"%c\",a[i][j]);\n\t\tputs(\"\");\n\t}\n\tputs(\"\");\n\tfor(int i=1;i<=h;i++)\n\t{\n\t\tfor(int j=1;j<=w;j++)\n\t\t\tprintf(\"%c\",b[i][j]);\n\t\tputs(\"\");\n\t}\n}", "problem_context": "Score : 700 points\n\nProblem Statement\n\nSnuke and Ciel went to a strange stationery store. Each of them got a transparent graph paper with H rows and W columns.\n\nSnuke painted some of the cells red in his paper. Here, the cells painted red were 4-connected, that is, it was possible to traverse from any red cell to any other red cell, by moving to vertically or horizontally adjacent red cells only.\n\nCiel painted some of the cells blue in her paper. Here, the cells painted blue were 4-connected.\n\nAfterwards, they precisely overlaid the two sheets in the same direction. Then, the intersection of the red cells and the blue cells appeared purple.\n\nYou are given a matrix of letters a_{ij} (1≤i≤H, 1≤j≤W) that describes the positions of the purple cells. If the cell at the i-th row and j-th column is purple, then a_{ij} is #, otherwise a_{ij} is .. Here, it is guaranteed that no outermost cell is purple. That is, if i=1, H or j = 1, W, then a_{ij} is ..\n\nFind a pair of the set of the positions of the red cells and the blue cells that is consistent with the situation described. It can be shown that a solution always exists.\n\nConstraints\n\n3≤H,W≤500\n\na_{ij} is # or ..\n\nIf i=1,H or j=1,W, then a_{ij} is ..\n\nAt least one of a_{ij} is #.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nH W\na_{11}...a_{1W}\n:\na_{H1}...a_{HW}\n\nOutput\n\nPrint a pair of the set of the positions of the red cells and the blue cells that is consistent with the situation, as follows:\n\nThe first H lines should describe the positions of the red cells.\n\nThe following 1 line should be empty.\n\nThe following H lines should describe the positions of the blue cells.\n\nThe description of the positions of the red or blue cells should follow the format of the description of the positions of the purple cells.\n\nSample Input 1\n\n5 5\n.....\n.#.#.\n.....\n.#.#.\n.....\n\nSample Output 1\n\n.....\n#####\n#....\n#####\n.....\n\n.###.\n.#.#.\n.#.#.\n.#.#.\n.....\n\nOne possible pair of the set of the positions of the red cells and the blue cells is as follows:\n\nSample Input 2\n\n7 13\n.............\n.###.###.###.\n.#.#.#...#...\n.###.#...#...\n.#.#.#.#.#...\n.#.#.###.###.\n.............\n\nSample Output 2\n\n.............\n.###########.\n.###.###.###.\n.###.###.###.\n.###.###.###.\n.###.###.###.\n.............\n\n.............\n.###.###.###.\n.#.#.#...#...\n.###.#...#...\n.#.#.#.#.#...\n.#.#########.\n.............\n\nOne possible pair of the set of the positions of the red cells and the blue cells is as follows:", "sample_input": "5 5\n.....\n.#.#.\n.....\n.#.#.\n.....\n"}, "reference_outputs": [".....\n#####\n#....\n#####\n.....\n\n.###.\n.#.#.\n.#.#.\n.#.#.\n.....\n"], "source_document_id": "p04007", "source_text": "Score : 700 points\n\nProblem Statement\n\nSnuke and Ciel went to a strange stationery store. Each of them got a transparent graph paper with H rows and W columns.\n\nSnuke painted some of the cells red in his paper. Here, the cells painted red were 4-connected, that is, it was possible to traverse from any red cell to any other red cell, by moving to vertically or horizontally adjacent red cells only.\n\nCiel painted some of the cells blue in her paper. Here, the cells painted blue were 4-connected.\n\nAfterwards, they precisely overlaid the two sheets in the same direction. Then, the intersection of the red cells and the blue cells appeared purple.\n\nYou are given a matrix of letters a_{ij} (1≤i≤H, 1≤j≤W) that describes the positions of the purple cells. If the cell at the i-th row and j-th column is purple, then a_{ij} is #, otherwise a_{ij} is .. Here, it is guaranteed that no outermost cell is purple. That is, if i=1, H or j = 1, W, then a_{ij} is ..\n\nFind a pair of the set of the positions of the red cells and the blue cells that is consistent with the situation described. It can be shown that a solution always exists.\n\nConstraints\n\n3≤H,W≤500\n\na_{ij} is # or ..\n\nIf i=1,H or j=1,W, then a_{ij} is ..\n\nAt least one of a_{ij} is #.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nH W\na_{11}...a_{1W}\n:\na_{H1}...a_{HW}\n\nOutput\n\nPrint a pair of the set of the positions of the red cells and the blue cells that is consistent with the situation, as follows:\n\nThe first H lines should describe the positions of the red cells.\n\nThe following 1 line should be empty.\n\nThe following H lines should describe the positions of the blue cells.\n\nThe description of the positions of the red or blue cells should follow the format of the description of the positions of the purple cells.\n\nSample Input 1\n\n5 5\n.....\n.#.#.\n.....\n.#.#.\n.....\n\nSample Output 1\n\n.....\n#####\n#....\n#####\n.....\n\n.###.\n.#.#.\n.#.#.\n.#.#.\n.....\n\nOne possible pair of the set of the positions of the red cells and the blue cells is as follows:\n\nSample Input 2\n\n7 13\n.............\n.###.###.###.\n.#.#.#...#...\n.###.#...#...\n.#.#.#.#.#...\n.#.#.###.###.\n.............\n\nSample Output 2\n\n.............\n.###########.\n.###.###.###.\n.###.###.###.\n.###.###.###.\n.###.###.###.\n.............\n\n.............\n.###.###.###.\n.#.#.#...#...\n.###.#...#...\n.#.#.#.#.#...\n.#.#########.\n.............\n\nOne possible pair of the set of the positions of the red cells and the blue cells is as follows:", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 683, "cpu_time_ms": 8, "memory_kb": 1792}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s299148252", "group_id": "codeNet:p04013", "input_text": "#include <iostream> \n#include <math.h> \nusing namespace std; \n\ntypedef long long ll;  \n\nll SumSubsets(int * set, int n, int k) \n{ \n    unsigned int pow_set_size = pow(2, n); \n    int counter, j; \n\n    ll result = 0;\n\n    for(counter = 0; counter < pow_set_size; counter++) \n    { \n        ll temp_result = 0, temp_cnt = 0;\n\n        for(j = 0; j < n; j++) \n        { \n            if(counter & (1 << j)) {\n                temp_cnt++;\n                temp_result += set[j];\n\n                cout << \"in here ..\" << endl;\n                \n            }\n        } \n\n        if  (temp_cnt > 0 && temp_result > 0 && ((float)temp_result / (float)temp_cnt) == (float)k ){\n\n            cout << temp_result << \" \" << temp_cnt << endl;\n\n            result++;\n        }\n        cout << endl; cout << endl;\n    } \n\n    return result;\n} \n\nint main() \n{  \n    int n, k;\n    cin >> n >> k;\n\n    int set[n]; \n    for (int i = 0; i < n; i++) cin >> set[i];\n\n    ll result = SumSubsets(set, n, k); \n    cout << result << endl;\n\n    return 0; \n} ", "language": "C++", "metadata": {"date": 1565992582, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p04013.html", "problem_id": "p04013", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p04013/input.txt", "sample_output_relpath": "derived/input_output/data/p04013/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p04013/C++/s299148252.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s299148252", "user_id": "u682828614"}, "prompt_components": {"gold_output": "5\n", "input_to_evaluate": "#include <iostream> \n#include <math.h> \nusing namespace std; \n\ntypedef long long ll;  \n\nll SumSubsets(int * set, int n, int k) \n{ \n    unsigned int pow_set_size = pow(2, n); \n    int counter, j; \n\n    ll result = 0;\n\n    for(counter = 0; counter < pow_set_size; counter++) \n    { \n        ll temp_result = 0, temp_cnt = 0;\n\n        for(j = 0; j < n; j++) \n        { \n            if(counter & (1 << j)) {\n                temp_cnt++;\n                temp_result += set[j];\n\n                cout << \"in here ..\" << endl;\n                \n            }\n        } \n\n        if  (temp_cnt > 0 && temp_result > 0 && ((float)temp_result / (float)temp_cnt) == (float)k ){\n\n            cout << temp_result << \" \" << temp_cnt << endl;\n\n            result++;\n        }\n        cout << endl; cout << endl;\n    } \n\n    return result;\n} \n\nint main() \n{  \n    int n, k;\n    cin >> n >> k;\n\n    int set[n]; \n    for (int i = 0; i < n; i++) cin >> set[i];\n\n    ll result = SumSubsets(set, n, k); \n    cout << result << endl;\n\n    return 0; \n} ", "problem_context": "Score : 300 points\n\nProblem Statement\n\nTak has N cards. On the i-th (1 \\leq i \\leq N) card is written an integer x_i.\nHe is selecting one or more cards from these N cards, so that the average of the integers written on the selected cards is exactly A.\nIn how many ways can he make his selection?\n\nConstraints\n\n1 \\leq N \\leq 50\n\n1 \\leq A \\leq 50\n\n1 \\leq x_i \\leq 50\n\nN,\\,A,\\,x_i are integers.\n\nPartial Score\n\n200 points will be awarded for passing the test set satisfying 1 \\leq N \\leq 16.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN A\nx_1 x_2 ... x_N\n\nOutput\n\nPrint the number of ways to select cards such that the average of the written integers is exactly A.\n\nSample Input 1\n\n4 8\n7 9 8 9\n\nSample Output 1\n\n5\n\nThe following are the 5 ways to select cards such that the average is 8:\n\nSelect the 3-rd card.\n\nSelect the 1-st and 2-nd cards.\n\nSelect the 1-st and 4-th cards.\n\nSelect the 1-st, 2-nd and 3-rd cards.\n\nSelect the 1-st, 3-rd and 4-th cards.\n\nSample Input 2\n\n3 8\n6 6 9\n\nSample Output 2\n\n0\n\nSample Input 3\n\n8 5\n3 6 2 8 7 6 5 9\n\nSample Output 3\n\n19\n\nSample Input 4\n\n33 3\n3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3\n\nSample Output 4\n\n8589934591\n\nThe answer may not fit into a 32-bit integer.", "sample_input": "4 8\n7 9 8 9\n"}, "reference_outputs": ["5\n"], "source_document_id": "p04013", "source_text": "Score : 300 points\n\nProblem Statement\n\nTak has N cards. On the i-th (1 \\leq i \\leq N) card is written an integer x_i.\nHe is selecting one or more cards from these N cards, so that the average of the integers written on the selected cards is exactly A.\nIn how many ways can he make his selection?\n\nConstraints\n\n1 \\leq N \\leq 50\n\n1 \\leq A \\leq 50\n\n1 \\leq x_i \\leq 50\n\nN,\\,A,\\,x_i are integers.\n\nPartial Score\n\n200 points will be awarded for passing the test set satisfying 1 \\leq N \\leq 16.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN A\nx_1 x_2 ... x_N\n\nOutput\n\nPrint the number of ways to select cards such that the average of the written integers is exactly A.\n\nSample Input 1\n\n4 8\n7 9 8 9\n\nSample Output 1\n\n5\n\nThe following are the 5 ways to select cards such that the average is 8:\n\nSelect the 3-rd card.\n\nSelect the 1-st and 2-nd cards.\n\nSelect the 1-st and 4-th cards.\n\nSelect the 1-st, 2-nd and 3-rd cards.\n\nSelect the 1-st, 3-rd and 4-th cards.\n\nSample Input 2\n\n3 8\n6 6 9\n\nSample Output 2\n\n0\n\nSample Input 3\n\n8 5\n3 6 2 8 7 6 5 9\n\nSample Output 3\n\n19\n\nSample Input 4\n\n33 3\n3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3 3\n\nSample Output 4\n\n8589934591\n\nThe answer may not fit into a 32-bit integer.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1025, "cpu_time_ms": 1120, "memory_kb": 6400}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s902998255", "group_id": "codeNet:p04020", "input_text": "#include <iostream> // cout, endl, cin\n#include <string> // string, to_string, stoi\n#include <vector> // vector\n#include <algorithm> // min, max, swap, sort, reverse, lower_bound, upper_bound\n#include <utility> // pair, make_pair\n#include <tuple> // tuple, make_tuple\n#include <cstdint> // int64_t, int*_t\n#include <cstdio> // printf\n#include <map> // map\n#include <queue> // queue, priority_queue\n#include <set> // set\n#include <stack> // stack\n#include <deque> // deque\n#include <unordered_map> // unordered_map\n#include <unordered_set> // unordered_set\n#include <bitset> // bitset\n#include <cctype> // isupper, islower, isdigit, toupper, tolower\n#include <cmath> // sqrt\n#define _GLIBCXX_DEBUG // check []\n#define DIVISOR 1000000007\n\nusing namespace std;\ntypedef pair<int,int> pii;\ntypedef pair<int64_t, int64_t> pII;\n\ntemplate<typename T>\nvoid cins(vector<T>& arr) { for(T& e: arr) cin >> e; }\n\n#ifdef DEBUG\n#define debug(fmt, ...) \\\n    printf(\"[debug: %s] \" fmt, __func__, __VA_ARGS__)\n#define ps(arr) \\\n    debug(\"size %ld: \", arr.size()); \\\n    for(auto e: arr) cout << e << \" \"; \\\n    cout << endl;\n#else\n#define debug(fmt, ...)\n#define ps(arr)\n#endif\n\n\nint main(void) {\n    int num;\n    cin >> num;\n    vector<int> arr(num);\n    cins(arr);\n\n    stack<int> stack;\n    int64_t ans = 0;\n    stack.push(arr[0]);\n    // make even as many as possible\n    for(int i = 1; i < num; i++) {\n        int cur = arr[i];\n        int prev = stack.top(); stack.pop();\n        if(prev%2 && cur != 0) {\n            ans++;\n            prev--;\n            cur--;\n        }\n        stack.push(prev); stack.push(cur);\n    }\n\n    while(!stack.empty()) {\n        int val = stack.top(); stack.pop();\n        debug(\"%d\\n\", val);\n        ans += (val/2);\n    }\n\n    cout << ans << endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1594414320, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p04020.html", "problem_id": "p04020", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p04020/input.txt", "sample_output_relpath": "derived/input_output/data/p04020/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p04020/C++/s902998255.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s902998255", "user_id": "u866370648"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <iostream> // cout, endl, cin\n#include <string> // string, to_string, stoi\n#include <vector> // vector\n#include <algorithm> // min, max, swap, sort, reverse, lower_bound, upper_bound\n#include <utility> // pair, make_pair\n#include <tuple> // tuple, make_tuple\n#include <cstdint> // int64_t, int*_t\n#include <cstdio> // printf\n#include <map> // map\n#include <queue> // queue, priority_queue\n#include <set> // set\n#include <stack> // stack\n#include <deque> // deque\n#include <unordered_map> // unordered_map\n#include <unordered_set> // unordered_set\n#include <bitset> // bitset\n#include <cctype> // isupper, islower, isdigit, toupper, tolower\n#include <cmath> // sqrt\n#define _GLIBCXX_DEBUG // check []\n#define DIVISOR 1000000007\n\nusing namespace std;\ntypedef pair<int,int> pii;\ntypedef pair<int64_t, int64_t> pII;\n\ntemplate<typename T>\nvoid cins(vector<T>& arr) { for(T& e: arr) cin >> e; }\n\n#ifdef DEBUG\n#define debug(fmt, ...) \\\n    printf(\"[debug: %s] \" fmt, __func__, __VA_ARGS__)\n#define ps(arr) \\\n    debug(\"size %ld: \", arr.size()); \\\n    for(auto e: arr) cout << e << \" \"; \\\n    cout << endl;\n#else\n#define debug(fmt, ...)\n#define ps(arr)\n#endif\n\n\nint main(void) {\n    int num;\n    cin >> num;\n    vector<int> arr(num);\n    cins(arr);\n\n    stack<int> stack;\n    int64_t ans = 0;\n    stack.push(arr[0]);\n    // make even as many as possible\n    for(int i = 1; i < num; i++) {\n        int cur = arr[i];\n        int prev = stack.top(); stack.pop();\n        if(prev%2 && cur != 0) {\n            ans++;\n            prev--;\n            cur--;\n        }\n        stack.push(prev); stack.push(cur);\n    }\n\n    while(!stack.empty()) {\n        int val = stack.top(); stack.pop();\n        debug(\"%d\\n\", val);\n        ans += (val/2);\n    }\n\n    cout << ans << endl;\n    return 0;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nSnuke has a large collection of cards. Each card has an integer between 1 and N, inclusive, written on it.\nHe has A_i cards with an integer i.\n\nTwo cards can form a pair if the absolute value of the difference of the integers written on them is at most 1.\n\nSnuke wants to create the maximum number of pairs from his cards, on the condition that no card should be used in multiple pairs. Find the maximum number of pairs that he can create.\n\nConstraints\n\n1 ≦ N ≦ 10^5\n\n0 ≦ A_i ≦ 10^9 (1 ≦ i ≦ N)\n\nAll input values are integers.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1\n:\nA_N\n\nOutput\n\nPrint the maximum number of pairs that Snuke can create.\n\nSample Input 1\n\n4\n4\n0\n3\n2\n\nSample Output 1\n\n4\n\nFor example, Snuke can create the following four pairs: (1,1),(1,1),(3,4),(3,4).\n\nSample Input 2\n\n8\n2\n0\n1\n6\n0\n8\n2\n1\n\nSample Output 2\n\n9", "sample_input": "4\n4\n0\n3\n2\n"}, "reference_outputs": ["4\n"], "source_document_id": "p04020", "source_text": "Score : 400 points\n\nProblem Statement\n\nSnuke has a large collection of cards. Each card has an integer between 1 and N, inclusive, written on it.\nHe has A_i cards with an integer i.\n\nTwo cards can form a pair if the absolute value of the difference of the integers written on them is at most 1.\n\nSnuke wants to create the maximum number of pairs from his cards, on the condition that no card should be used in multiple pairs. Find the maximum number of pairs that he can create.\n\nConstraints\n\n1 ≦ N ≦ 10^5\n\n0 ≦ A_i ≦ 10^9 (1 ≦ i ≦ N)\n\nAll input values are integers.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1\n:\nA_N\n\nOutput\n\nPrint the maximum number of pairs that Snuke can create.\n\nSample Input 1\n\n4\n4\n0\n3\n2\n\nSample Output 1\n\n4\n\nFor example, Snuke can create the following four pairs: (1,1),(1,1),(3,4),(3,4).\n\nSample Input 2\n\n8\n2\n0\n1\n6\n0\n8\n2\n1\n\nSample Output 2\n\n9", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1783, "cpu_time_ms": 47, "memory_kb": 4008}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s124273736", "group_id": "codeNet:p04020", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define d(x) cerr << #x \":\" << x << endl;\n#define dd(x, y) cerr << \"(\" #x \",\" #y \"):(\" << x << \",\" << y << \")\" << endl\n#define rep(i, n) for (int i = (int)(0); i < (int)(n); i++)\n#define repp(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define all(v) v.begin(), v.end()\n#define dump(v)                  \\\n    cerr << #v \":[ \";            \\\n    for (auto macro_vi : v) {    \\\n        cerr << macro_vi << \" \"; \\\n    }                            \\\n    cerr << \"]\" << endl;\n#define ddump(v)                           \\\n    cerr << #v \":\" << endl;                \\\n    for (auto macro_row : v) {             \\\n        cerr << \"[\";                       \\\n        for (auto macro__vi : macro_row) { \\\n            cerr << macro__vi << \" \";      \\\n        }                                  \\\n        cerr << \"]\" << endl;               \\\n    }\nusing lint       = long long;\nconst int INF    = 1e9;\nconst lint LINF  = 1e18;\nconst lint MOD   = 1e9 + 7;\nconst double EPS = 1e-10;\n\nint main() {\n    int N;\n    cin >> N;\n    vector<lint> A(N, 0);\n    lint ans = 0;\n    rep(i, N) {\n        cin >> A[i];\n        ans += A[i] / 2;\n        A[i] = A[i] % 2;\n    }\n    dump(A);\n    for (int i = 0; i < N - 1; i++) {\n        int gen = min(A[i], A[i + 1]);\n        ans += gen;\n        A[i] -= gen;\n        A[i + 1] -= gen;\n    }\n    cout << ans << endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1583873086, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p04020.html", "problem_id": "p04020", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p04020/input.txt", "sample_output_relpath": "derived/input_output/data/p04020/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p04020/C++/s124273736.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s124273736", "user_id": "u784072785"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\n#define d(x) cerr << #x \":\" << x << endl;\n#define dd(x, y) cerr << \"(\" #x \",\" #y \"):(\" << x << \",\" << y << \")\" << endl\n#define rep(i, n) for (int i = (int)(0); i < (int)(n); i++)\n#define repp(i, a, b) for (int i = (int)(a); i < (int)(b); i++)\n#define all(v) v.begin(), v.end()\n#define dump(v)                  \\\n    cerr << #v \":[ \";            \\\n    for (auto macro_vi : v) {    \\\n        cerr << macro_vi << \" \"; \\\n    }                            \\\n    cerr << \"]\" << endl;\n#define ddump(v)                           \\\n    cerr << #v \":\" << endl;                \\\n    for (auto macro_row : v) {             \\\n        cerr << \"[\";                       \\\n        for (auto macro__vi : macro_row) { \\\n            cerr << macro__vi << \" \";      \\\n        }                                  \\\n        cerr << \"]\" << endl;               \\\n    }\nusing lint       = long long;\nconst int INF    = 1e9;\nconst lint LINF  = 1e18;\nconst lint MOD   = 1e9 + 7;\nconst double EPS = 1e-10;\n\nint main() {\n    int N;\n    cin >> N;\n    vector<lint> A(N, 0);\n    lint ans = 0;\n    rep(i, N) {\n        cin >> A[i];\n        ans += A[i] / 2;\n        A[i] = A[i] % 2;\n    }\n    dump(A);\n    for (int i = 0; i < N - 1; i++) {\n        int gen = min(A[i], A[i + 1]);\n        ans += gen;\n        A[i] -= gen;\n        A[i + 1] -= gen;\n    }\n    cout << ans << endl;\n    return 0;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nSnuke has a large collection of cards. Each card has an integer between 1 and N, inclusive, written on it.\nHe has A_i cards with an integer i.\n\nTwo cards can form a pair if the absolute value of the difference of the integers written on them is at most 1.\n\nSnuke wants to create the maximum number of pairs from his cards, on the condition that no card should be used in multiple pairs. Find the maximum number of pairs that he can create.\n\nConstraints\n\n1 ≦ N ≦ 10^5\n\n0 ≦ A_i ≦ 10^9 (1 ≦ i ≦ N)\n\nAll input values are integers.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1\n:\nA_N\n\nOutput\n\nPrint the maximum number of pairs that Snuke can create.\n\nSample Input 1\n\n4\n4\n0\n3\n2\n\nSample Output 1\n\n4\n\nFor example, Snuke can create the following four pairs: (1,1),(1,1),(3,4),(3,4).\n\nSample Input 2\n\n8\n2\n0\n1\n6\n0\n8\n2\n1\n\nSample Output 2\n\n9", "sample_input": "4\n4\n0\n3\n2\n"}, "reference_outputs": ["4\n"], "source_document_id": "p04020", "source_text": "Score : 400 points\n\nProblem Statement\n\nSnuke has a large collection of cards. Each card has an integer between 1 and N, inclusive, written on it.\nHe has A_i cards with an integer i.\n\nTwo cards can form a pair if the absolute value of the difference of the integers written on them is at most 1.\n\nSnuke wants to create the maximum number of pairs from his cards, on the condition that no card should be used in multiple pairs. Find the maximum number of pairs that he can create.\n\nConstraints\n\n1 ≦ N ≦ 10^5\n\n0 ≦ A_i ≦ 10^9 (1 ≦ i ≦ N)\n\nAll input values are integers.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1\n:\nA_N\n\nOutput\n\nPrint the maximum number of pairs that Snuke can create.\n\nSample Input 1\n\n4\n4\n0\n3\n2\n\nSample Output 1\n\n4\n\nFor example, Snuke can create the following four pairs: (1,1),(1,1),(3,4),(3,4).\n\nSample Input 2\n\n8\n2\n0\n1\n6\n0\n8\n2\n1\n\nSample Output 2\n\n9", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1401, "cpu_time_ms": 128, "memory_kb": 1024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s983949815", "group_id": "codeNet:p04020", "input_text": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<string>\n#include<map>\n#define _USE_MATH_DEFINES\n#include<math.h>\n#include<queue>\n#include<deque>\n#include<stack>\n#include<cstdio>\n#include<utility>\n#include<set>\n#include<list>\n#include<cmath>\n#include<stdio.h>\n#include<string.h>\n#include<iomanip>\n#include<cstdio>\n#include<cstdlib>\n#include<cstring>\nusing namespace std;\n#define FOR(i, a, b) for (ll i = (a); i <= (b); i++)\n#define REP(i, n) FOR(i, 0, n - 1)\n#define NREP(i, n) FOR(i, 1, n)\nusing ll = long long;\nusing pii = pair<int, int>;\nusing piii = pair<pii, pii>;\nconst ll dx[4] = { 0,1,0,-1 };\nconst ll dy[4] = { -1, 0, 1,0 };\nconst int INF = 1e9 + 7;\nint gcd(int x, int y) {\n\tif (x < y)swap(x, y);\n\tif (y == 0)return x;\n\treturn gcd(y, x%y);\n}\nvoid mul(ll a, ll b) {\n\ta = a * b % INF;\n}\ndouble mysqrt(double x) {\n\tdouble l = 0, r = x;\n\tfor (int i = 0; i < 64; ++i) {\n\t\tdouble m = (l + r) / 2.0;\n\t\tif (m*m < x)l = m;\n\t\telse r = m;\n\t}\n\treturn l;\n}\n///////////////////////////////////////\n\nint main() {\n\tint N; cin >> N;\n\tint a[100100];\n\tREP(i, N)cin >> a[i];\n\tll ans = 0;\n\tfor (int i = 0; i < N-1; ++i) {\n\t\tif (a[i + 1] > a[i]) {\n\t\t\tans += a[i];\n\t\t\ta[i + 1] -= a[i];\n\t\t}\n\t\telse {\n\t\t\tans += a[i + 1];\n\t\t\ta[i] -= a[i + 1];\n\t\t\ta[i + 1] = 0;\n\t\t\tans += a[i] / 2;\n\t\t}\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1571522635, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p04020.html", "problem_id": "p04020", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p04020/input.txt", "sample_output_relpath": "derived/input_output/data/p04020/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p04020/C++/s983949815.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s983949815", "user_id": "u406158207"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include<iostream>\n#include<vector>\n#include<algorithm>\n#include<string>\n#include<map>\n#define _USE_MATH_DEFINES\n#include<math.h>\n#include<queue>\n#include<deque>\n#include<stack>\n#include<cstdio>\n#include<utility>\n#include<set>\n#include<list>\n#include<cmath>\n#include<stdio.h>\n#include<string.h>\n#include<iomanip>\n#include<cstdio>\n#include<cstdlib>\n#include<cstring>\nusing namespace std;\n#define FOR(i, a, b) for (ll i = (a); i <= (b); i++)\n#define REP(i, n) FOR(i, 0, n - 1)\n#define NREP(i, n) FOR(i, 1, n)\nusing ll = long long;\nusing pii = pair<int, int>;\nusing piii = pair<pii, pii>;\nconst ll dx[4] = { 0,1,0,-1 };\nconst ll dy[4] = { -1, 0, 1,0 };\nconst int INF = 1e9 + 7;\nint gcd(int x, int y) {\n\tif (x < y)swap(x, y);\n\tif (y == 0)return x;\n\treturn gcd(y, x%y);\n}\nvoid mul(ll a, ll b) {\n\ta = a * b % INF;\n}\ndouble mysqrt(double x) {\n\tdouble l = 0, r = x;\n\tfor (int i = 0; i < 64; ++i) {\n\t\tdouble m = (l + r) / 2.0;\n\t\tif (m*m < x)l = m;\n\t\telse r = m;\n\t}\n\treturn l;\n}\n///////////////////////////////////////\n\nint main() {\n\tint N; cin >> N;\n\tint a[100100];\n\tREP(i, N)cin >> a[i];\n\tll ans = 0;\n\tfor (int i = 0; i < N-1; ++i) {\n\t\tif (a[i + 1] > a[i]) {\n\t\t\tans += a[i];\n\t\t\ta[i + 1] -= a[i];\n\t\t}\n\t\telse {\n\t\t\tans += a[i + 1];\n\t\t\ta[i] -= a[i + 1];\n\t\t\ta[i + 1] = 0;\n\t\t\tans += a[i] / 2;\n\t\t}\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nSnuke has a large collection of cards. Each card has an integer between 1 and N, inclusive, written on it.\nHe has A_i cards with an integer i.\n\nTwo cards can form a pair if the absolute value of the difference of the integers written on them is at most 1.\n\nSnuke wants to create the maximum number of pairs from his cards, on the condition that no card should be used in multiple pairs. Find the maximum number of pairs that he can create.\n\nConstraints\n\n1 ≦ N ≦ 10^5\n\n0 ≦ A_i ≦ 10^9 (1 ≦ i ≦ N)\n\nAll input values are integers.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1\n:\nA_N\n\nOutput\n\nPrint the maximum number of pairs that Snuke can create.\n\nSample Input 1\n\n4\n4\n0\n3\n2\n\nSample Output 1\n\n4\n\nFor example, Snuke can create the following four pairs: (1,1),(1,1),(3,4),(3,4).\n\nSample Input 2\n\n8\n2\n0\n1\n6\n0\n8\n2\n1\n\nSample Output 2\n\n9", "sample_input": "4\n4\n0\n3\n2\n"}, "reference_outputs": ["4\n"], "source_document_id": "p04020", "source_text": "Score : 400 points\n\nProblem Statement\n\nSnuke has a large collection of cards. Each card has an integer between 1 and N, inclusive, written on it.\nHe has A_i cards with an integer i.\n\nTwo cards can form a pair if the absolute value of the difference of the integers written on them is at most 1.\n\nSnuke wants to create the maximum number of pairs from his cards, on the condition that no card should be used in multiple pairs. Find the maximum number of pairs that he can create.\n\nConstraints\n\n1 ≦ N ≦ 10^5\n\n0 ≦ A_i ≦ 10^9 (1 ≦ i ≦ N)\n\nAll input values are integers.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1\n:\nA_N\n\nOutput\n\nPrint the maximum number of pairs that Snuke can create.\n\nSample Input 1\n\n4\n4\n0\n3\n2\n\nSample Output 1\n\n4\n\nFor example, Snuke can create the following four pairs: (1,1),(1,1),(3,4),(3,4).\n\nSample Input 2\n\n8\n2\n0\n1\n6\n0\n8\n2\n1\n\nSample Output 2\n\n9", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1320, "cpu_time_ms": 59, "memory_kb": 640}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s260830727", "group_id": "codeNet:p04020", "input_text": "#include <algorithm>\n#include <iterator>\n#include <vector>\n#include <iomanip>\n#include <iostream>\n#include <stack>\n#include <queue>\n#include <list>\n#include <utility>\n \n#include <string>\n#include <cstring>\n \n#include <cstdio>\n#include <cassert>\n \n// M_PI for pi\n#define _USE_MATH_DEFINES\n#include <cmath>\n \nusing namespace std;\n \nstatic const int MAX = 100005;\n\nint v[MAX];\nint n;\n \nint main(int argc, char* argv[]) {\n\n    cin >> n;\n\n    for (int i = 0; i < n; ++i) {\n        cin >> v[i];\n    }\n\n    int S = 0;\n    int s = 0;\n\n    for (int i = 0; i < n; ++i) {\n        s = v[i] / 2;\n        S += s;\n\n        v[i] = v[i] / 2;\n    }\n\n    for (int i = 1; i < n; ++i) {\n        if (v[i] == 1 && v[i-1] == 1) {\n            S += 1;\n            v[i] = 0;\n            v[i-1] = 0;\n        }\n    }\n\n    cout << S << endl;\n\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1473512552, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p04020.html", "problem_id": "p04020", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p04020/input.txt", "sample_output_relpath": "derived/input_output/data/p04020/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p04020/C++/s260830727.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s260830727", "user_id": "u591168730"}, "prompt_components": {"gold_output": "4\n", "input_to_evaluate": "#include <algorithm>\n#include <iterator>\n#include <vector>\n#include <iomanip>\n#include <iostream>\n#include <stack>\n#include <queue>\n#include <list>\n#include <utility>\n \n#include <string>\n#include <cstring>\n \n#include <cstdio>\n#include <cassert>\n \n// M_PI for pi\n#define _USE_MATH_DEFINES\n#include <cmath>\n \nusing namespace std;\n \nstatic const int MAX = 100005;\n\nint v[MAX];\nint n;\n \nint main(int argc, char* argv[]) {\n\n    cin >> n;\n\n    for (int i = 0; i < n; ++i) {\n        cin >> v[i];\n    }\n\n    int S = 0;\n    int s = 0;\n\n    for (int i = 0; i < n; ++i) {\n        s = v[i] / 2;\n        S += s;\n\n        v[i] = v[i] / 2;\n    }\n\n    for (int i = 1; i < n; ++i) {\n        if (v[i] == 1 && v[i-1] == 1) {\n            S += 1;\n            v[i] = 0;\n            v[i-1] = 0;\n        }\n    }\n\n    cout << S << endl;\n\n    return 0;\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nSnuke has a large collection of cards. Each card has an integer between 1 and N, inclusive, written on it.\nHe has A_i cards with an integer i.\n\nTwo cards can form a pair if the absolute value of the difference of the integers written on them is at most 1.\n\nSnuke wants to create the maximum number of pairs from his cards, on the condition that no card should be used in multiple pairs. Find the maximum number of pairs that he can create.\n\nConstraints\n\n1 ≦ N ≦ 10^5\n\n0 ≦ A_i ≦ 10^9 (1 ≦ i ≦ N)\n\nAll input values are integers.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1\n:\nA_N\n\nOutput\n\nPrint the maximum number of pairs that Snuke can create.\n\nSample Input 1\n\n4\n4\n0\n3\n2\n\nSample Output 1\n\n4\n\nFor example, Snuke can create the following four pairs: (1,1),(1,1),(3,4),(3,4).\n\nSample Input 2\n\n8\n2\n0\n1\n6\n0\n8\n2\n1\n\nSample Output 2\n\n9", "sample_input": "4\n4\n0\n3\n2\n"}, "reference_outputs": ["4\n"], "source_document_id": "p04020", "source_text": "Score : 400 points\n\nProblem Statement\n\nSnuke has a large collection of cards. Each card has an integer between 1 and N, inclusive, written on it.\nHe has A_i cards with an integer i.\n\nTwo cards can form a pair if the absolute value of the difference of the integers written on them is at most 1.\n\nSnuke wants to create the maximum number of pairs from his cards, on the condition that no card should be used in multiple pairs. Find the maximum number of pairs that he can create.\n\nConstraints\n\n1 ≦ N ≦ 10^5\n\n0 ≦ A_i ≦ 10^9 (1 ≦ i ≦ N)\n\nAll input values are integers.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1\n:\nA_N\n\nOutput\n\nPrint the maximum number of pairs that Snuke can create.\n\nSample Input 1\n\n4\n4\n0\n3\n2\n\nSample Output 1\n\n4\n\nFor example, Snuke can create the following four pairs: (1,1),(1,1),(3,4),(3,4).\n\nSample Input 2\n\n8\n2\n0\n1\n6\n0\n8\n2\n1\n\nSample Output 2\n\n9", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 829, "cpu_time_ms": 87, "memory_kb": 640}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s376178107", "group_id": "codeNet:p04021", "input_text": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint N;\nvector<pair<int, int>> A;\nint x[101010];\n\nint main() {\n  cin >> N;\n  A.assign(N + 1, pair<int, int>());\n  int a;\n  A[0] = make_pair(0, 0);\n  for (int i = 1; i <= N; i++) {\n    cin >> a;\n    A[i] = make_pair(a, i);\n  }\n  sort(A.begin(), A.end());\n\n  int res = 0;\n  for (int i = 2; i <= N; i += 2) {\n    if (A[i].second % 2) res++;\n  }\n\n  cout << res << endl;\n\n  return 0;\n}", "language": "C++", "metadata": {"date": 1570503889, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p04021.html", "problem_id": "p04021", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p04021/input.txt", "sample_output_relpath": "derived/input_output/data/p04021/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p04021/C++/s376178107.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s376178107", "user_id": "u764228018"}, "prompt_components": {"gold_output": "1\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\nusing namespace std;\n\nint N;\nvector<pair<int, int>> A;\nint x[101010];\n\nint main() {\n  cin >> N;\n  A.assign(N + 1, pair<int, int>());\n  int a;\n  A[0] = make_pair(0, 0);\n  for (int i = 1; i <= N; i++) {\n    cin >> a;\n    A[i] = make_pair(a, i);\n  }\n  sort(A.begin(), A.end());\n\n  int res = 0;\n  for (int i = 2; i <= N; i += 2) {\n    if (A[i].second % 2) res++;\n  }\n\n  cout << res << endl;\n\n  return 0;\n}", "problem_context": "Score : 600 points\n\nProblem Statement\n\nSnuke got an integer sequence of length N from his mother, as a birthday present. The i-th (1 ≦ i ≦ N) element of the sequence is a_i. The elements are pairwise distinct.\nHe is sorting this sequence in increasing order.\nWith supernatural power, he can perform the following two operations on the sequence in any order:\n\nOperation 1: choose 2 consecutive elements, then reverse the order of those elements.\n\nOperation 2: choose 3 consecutive elements, then reverse the order of those elements.\n\nSnuke likes Operation 2, but not Operation 1. Find the minimum number of Operation 1 that he has to perform in order to sort the sequence in increasing order.\n\nConstraints\n\n1 ≦ N ≦ 10^5\n\n0 ≦ A_i ≦ 10^9\n\nIf i ≠ j, then A_i ≠ A_j.\n\nAll input values are integers.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1\n:\nA_N\n\nOutput\n\nPrint the minimum number of times Operation 1 that Snuke has to perform.\n\nSample Input 1\n\n4\n2\n4\n3\n1\n\nSample Output 1\n\n1\n\nThe given sequence can be sorted as follows:\n\nFirst, reverse the order of the last three elements. The sequence is now: 2,1,3,4.\n\nThen, reverse the order of the first two elements. The sequence is now: 1,2,3,4.\n\nIn this sequence of operations, Operation 1 is performed once. It is not possible to sort the sequence with less number of Operation 1, thus the answer is 1.\n\nSample Input 2\n\n5\n10\n8\n5\n3\n2\n\nSample Output 2\n\n0", "sample_input": "4\n2\n4\n3\n1\n"}, "reference_outputs": ["1\n"], "source_document_id": "p04021", "source_text": "Score : 600 points\n\nProblem Statement\n\nSnuke got an integer sequence of length N from his mother, as a birthday present. The i-th (1 ≦ i ≦ N) element of the sequence is a_i. The elements are pairwise distinct.\nHe is sorting this sequence in increasing order.\nWith supernatural power, he can perform the following two operations on the sequence in any order:\n\nOperation 1: choose 2 consecutive elements, then reverse the order of those elements.\n\nOperation 2: choose 3 consecutive elements, then reverse the order of those elements.\n\nSnuke likes Operation 2, but not Operation 1. Find the minimum number of Operation 1 that he has to perform in order to sort the sequence in increasing order.\n\nConstraints\n\n1 ≦ N ≦ 10^5\n\n0 ≦ A_i ≦ 10^9\n\nIf i ≠ j, then A_i ≠ A_j.\n\nAll input values are integers.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nA_1\n:\nA_N\n\nOutput\n\nPrint the minimum number of times Operation 1 that Snuke has to perform.\n\nSample Input 1\n\n4\n2\n4\n3\n1\n\nSample Output 1\n\n1\n\nThe given sequence can be sorted as follows:\n\nFirst, reverse the order of the last three elements. The sequence is now: 2,1,3,4.\n\nThen, reverse the order of the first two elements. The sequence is now: 1,2,3,4.\n\nIn this sequence of operations, Operation 1 is performed once. It is not possible to sort the sequence with less number of Operation 1, thus the answer is 1.\n\nSample Input 2\n\n5\n10\n8\n5\n3\n2\n\nSample Output 2\n\n0", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 427, "cpu_time_ms": 60, "memory_kb": 1024}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s967654590", "group_id": "codeNet:p04024", "input_text": "//khodaya khodet komak kon\n#include <bits/stdc++.h>\n\n#define F first\n#define S second\n#define pb push_back\n#define all(x) x.begin(), x.end()\n#pragma GCC optimize(\"Ofast,no-stack-protector,unroll-loops,fast-math\")\n#define int long long\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair<int, int> pii;\ntypedef vector<int> vi;\n\nconst int N = 20000000 + 10;\nconst ll MOD = 1000000000 + 7;\nconst ll INF = 1000000010;\nconst ll LOG = 25;\n\nint n, m, a[1010][1010], ans[N];\nll k;\n\nint mul(int a, int b){\n\treturn a * 1ll * b % MOD;\n}\n\nint add(int a, int b){\n\ta += b;\n\tif (a >= MOD) a -= MOD;\n\treturn a;\n}\n\nint minu(int a, int b){\n\ta -= b;\n\tif (a < 0) a += MOD;\n\treturn a;\n}\n\nint POW(int a, int b){\n\tint res = 1;\n\twhile (b){\n\t\tif (b & 1) res = mul(res, a);\n\t\tb >>= 1;\n\t\ta = mul(a, a);\n\t}\n\treturn res;\n}\n\nint inv(int a){\n\treturn POW(a, MOD - 2);\n}\n\nint32_t main(){\n\tios::sync_with_stdio(0); cin.tie(0); cout.tie(0);\n\tcin >> n >> m >> k;\n\tif (k >= 20000000) assert(0);\n\tans[0] = 1;\n\tbool R = 0, C = 0;\n\tfor (int i = 1; i <= n; i++){\n\t\tfor (int j = 1; j <= m; j++){\n\t\t\tchar c;\n\t\t\tcin >> c;\n\t\t\ta[i][j] = (c == '#');\n\t\t}\n\t}\n\tfor (int i = 1; i <= n; i++) if (a[i][1] == a[i][m] && a[i][1] == 1) R = 1;\n\tfor (int j = 1; j <= m; j++) if (a[1][j] == a[n][j] && a[1][j] == 1) C = 1;\n\tif (R & C) return cout << 1, 0;\n\tif (!(R | C)){\n\t\tint cnt = 0;\n\t\tfor (int i = 1; i <= n; i++) for (int j = 1; j <= m; j++) cnt += a[i][j];\n\t\tcout << POW(cnt, k);\n\t\treturn 0;\n\t}\n\tans[1] = 1;\n\tint moj = 0, kol = 0, cnt = 0;\n\tif (R){\n\t\tfor (int i = 1; i <= n; i++) if (a[i][1] == a[i][m] && a[i][1] == 1) cnt++;\n\t\tfor (int i = 1; i <= n; i++) for (int j = 1; j < m; j++) if (a[i][j] == 1 && a[i][j + 1] == 1) moj++;\n\t\tfor (int i = 1; i <= n; i++) for (int j = 1; j <= m; j++) kol += a[i][j]; \n\t}else{\n\t\tfor (int j = 1; j <= m; j++) if (a[1][j] == a[n][j] && a[1][j] == 1) cnt++;\n\t\tfor (int i = 1; i < n; i++) for (int j = 1; j <= m; j++) if (a[i][j] == a[i + 1][j] && a[i][j] == 1) moj++;\n\t\tfor (int i = 1; i <= n; i++) for (int j = 1; j <= m; j++) kol += a[i][j];\n\t}\n//\tcout << POW(4, 2) << '\\n';\n\tif (k == 1 || k == 0) return cout << 1, 0;\n\tif (k == 2) return cout << kol - moj, 0;\n\tans[2] = kol - moj;\n\tfor (int i = 3; i <= k; i++){\n\t\tans[i] = ans[i - 1] * 1ll * kol % MOD;\n\t\tans[i] -= POW(cnt, i - 2) * 1ll * moj % MOD;\n\t\tans[i] %= MOD;\n\t\tans[i] += MOD;\n\t\tans[i] %= MOD;\n\t}\n//\tint ans2 = kol - moj;\n//\tint x = cnt * moj;\n//\tint A = minu(POW(kol, k - 2), 1);\n//\tA = mul(A, inv(kol - 1));\n//\tans2 = mul(ans2, POW(kol, k - 2));\n//\tans2 = minu(ans2, mul(x, A));\n//\tcout << ans2;\n\tcout << ans[k];\n\n\n\n\n\n\n\n\treturn 0;\n}\n", "language": "C++", "metadata": {"date": 1595731355, "filename_ext": "cpp", "original_language": "C++ (GCC 9.2.1)", "problem_description_relpath": "problem_descriptions/p04024.html", "problem_id": "p04024", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p04024/input.txt", "sample_output_relpath": "derived/input_output/data/p04024/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p04024/C++/s967654590.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s967654590", "user_id": "u349705898"}, "prompt_components": {"gold_output": "20\n", "input_to_evaluate": "//khodaya khodet komak kon\n#include <bits/stdc++.h>\n\n#define F first\n#define S second\n#define pb push_back\n#define all(x) x.begin(), x.end()\n#pragma GCC optimize(\"Ofast,no-stack-protector,unroll-loops,fast-math\")\n#define int long long\n\nusing namespace std;\n\ntypedef long long ll;\ntypedef pair<int, int> pii;\ntypedef vector<int> vi;\n\nconst int N = 20000000 + 10;\nconst ll MOD = 1000000000 + 7;\nconst ll INF = 1000000010;\nconst ll LOG = 25;\n\nint n, m, a[1010][1010], ans[N];\nll k;\n\nint mul(int a, int b){\n\treturn a * 1ll * b % MOD;\n}\n\nint add(int a, int b){\n\ta += b;\n\tif (a >= MOD) a -= MOD;\n\treturn a;\n}\n\nint minu(int a, int b){\n\ta -= b;\n\tif (a < 0) a += MOD;\n\treturn a;\n}\n\nint POW(int a, int b){\n\tint res = 1;\n\twhile (b){\n\t\tif (b & 1) res = mul(res, a);\n\t\tb >>= 1;\n\t\ta = mul(a, a);\n\t}\n\treturn res;\n}\n\nint inv(int a){\n\treturn POW(a, MOD - 2);\n}\n\nint32_t main(){\n\tios::sync_with_stdio(0); cin.tie(0); cout.tie(0);\n\tcin >> n >> m >> k;\n\tif (k >= 20000000) assert(0);\n\tans[0] = 1;\n\tbool R = 0, C = 0;\n\tfor (int i = 1; i <= n; i++){\n\t\tfor (int j = 1; j <= m; j++){\n\t\t\tchar c;\n\t\t\tcin >> c;\n\t\t\ta[i][j] = (c == '#');\n\t\t}\n\t}\n\tfor (int i = 1; i <= n; i++) if (a[i][1] == a[i][m] && a[i][1] == 1) R = 1;\n\tfor (int j = 1; j <= m; j++) if (a[1][j] == a[n][j] && a[1][j] == 1) C = 1;\n\tif (R & C) return cout << 1, 0;\n\tif (!(R | C)){\n\t\tint cnt = 0;\n\t\tfor (int i = 1; i <= n; i++) for (int j = 1; j <= m; j++) cnt += a[i][j];\n\t\tcout << POW(cnt, k);\n\t\treturn 0;\n\t}\n\tans[1] = 1;\n\tint moj = 0, kol = 0, cnt = 0;\n\tif (R){\n\t\tfor (int i = 1; i <= n; i++) if (a[i][1] == a[i][m] && a[i][1] == 1) cnt++;\n\t\tfor (int i = 1; i <= n; i++) for (int j = 1; j < m; j++) if (a[i][j] == 1 && a[i][j + 1] == 1) moj++;\n\t\tfor (int i = 1; i <= n; i++) for (int j = 1; j <= m; j++) kol += a[i][j]; \n\t}else{\n\t\tfor (int j = 1; j <= m; j++) if (a[1][j] == a[n][j] && a[1][j] == 1) cnt++;\n\t\tfor (int i = 1; i < n; i++) for (int j = 1; j <= m; j++) if (a[i][j] == a[i + 1][j] && a[i][j] == 1) moj++;\n\t\tfor (int i = 1; i <= n; i++) for (int j = 1; j <= m; j++) kol += a[i][j];\n\t}\n//\tcout << POW(4, 2) << '\\n';\n\tif (k == 1 || k == 0) return cout << 1, 0;\n\tif (k == 2) return cout << kol - moj, 0;\n\tans[2] = kol - moj;\n\tfor (int i = 3; i <= k; i++){\n\t\tans[i] = ans[i - 1] * 1ll * kol % MOD;\n\t\tans[i] -= POW(cnt, i - 2) * 1ll * moj % MOD;\n\t\tans[i] %= MOD;\n\t\tans[i] += MOD;\n\t\tans[i] %= MOD;\n\t}\n//\tint ans2 = kol - moj;\n//\tint x = cnt * moj;\n//\tint A = minu(POW(kol, k - 2), 1);\n//\tA = mul(A, inv(kol - 1));\n//\tans2 = mul(ans2, POW(kol, k - 2));\n//\tans2 = minu(ans2, mul(x, A));\n//\tcout << ans2;\n\tcout << ans[k];\n\n\n\n\n\n\n\n\treturn 0;\n}\n", "problem_context": "Score : 1700 points\n\nProblem Statement\n\nSnuke got a grid from his mother, as a birthday present. The grid has H rows and W columns. Each cell is painted black or white. All black cells are 4-connected, that is, it is possible to traverse from any black cell to any other black cell by just visiting black cells, where it is only allowed to move horizontally or vertically.\n\nThe color of the cell at the i-th row and j-th column (1 ≦ i ≦ H, 1 ≦ j ≦ W) is represented by a character s_{ij}. If s_{ij} is #, the cell is painted black. If s_{ij} is ., the cell is painted white. At least one cell is painted black.\n\nWe will define fractals as follows.\nThe fractal of level 0 is a 1 × 1 grid with a black cell.\nThe fractal of level k+1 is obtained by arranging smaller grids in H rows and W columns, following the pattern of the Snuke's grid.\nAt a position that corresponds to a black cell in the Snuke's grid, a copy of the fractal of level k is placed.\nAt a position that corresponds to a white cell in the Snuke's grid, a grid whose cells are all white, with the same dimensions as the fractal of level k, is placed.\n\nYou are given the description of the Snuke's grid, and an integer K. Find the number of connected components of black cells in the fractal of level K, modulo 10^9+7.\n\nConstraints\n\n1 ≦ H,W ≦ 1000\n\n0 ≦ K ≦ 10^{18}\n\nEach s_{ij} is either # or ..\n\nAll black cells in the given grid are 4-connected.\n\nThere is at least one black cell in the given grid.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nH W K\ns_{11} .. s_{1W}\n:\ns_{H1} .. s_{HW}\n\nOutput\n\nPrint the number of connected components of black cells in the fractal of level K, modulo 10^9+7.\n\nSample Input 1\n\n3 3 3\n.#.\n###\n#.#\n\nSample Output 1\n\n20\n\nThe fractal of level K=3 in this case is shown below. There are 20 connected components of black cells.\n\n.............#.............\n............###............\n............#.#............\n..........#..#..#..........\n.........#########.........\n.........#.##.##.#.........\n..........#.....#..........\n.........###...###.........\n.........#.#...#.#.........\n....#........#........#....\n...###......###......###...\n...#.#......#.#......#.#...\n.#..#..#..#..#..#..#..#..#.\n###########################\n#.##.##.##.##.##.##.##.##.#\n.#.....#..#.....#..#.....#.\n###...######...######...###\n#.#...#.##.#...#.##.#...#.#\n....#.................#....\n...###...............###...\n...#.#...............#.#...\n.#..#..#...........#..#..#.\n#########.........#########\n#.##.##.#.........#.##.##.#\n.#.....#...........#.....#.\n###...###.........###...###\n#.#...#.#.........#.#...#.#\n\nSample Input 2\n\n3 3 3\n###\n#.#\n###\n\nSample Output 2\n\n1\n\nSample Input 3\n\n11 15 1000000000000000000\n.....#.........\n....###........\n....####.......\n...######......\n...#######.....\n..##.###.##....\n..##########...\n.###.....####..\n.####...######.\n###############\n#.##..##..##..#\n\nSample Output 3\n\n301811921", "sample_input": "3 3 3\n.#.\n###\n#.#\n"}, "reference_outputs": ["20\n"], "source_document_id": "p04024", "source_text": "Score : 1700 points\n\nProblem Statement\n\nSnuke got a grid from his mother, as a birthday present. The grid has H rows and W columns. Each cell is painted black or white. All black cells are 4-connected, that is, it is possible to traverse from any black cell to any other black cell by just visiting black cells, where it is only allowed to move horizontally or vertically.\n\nThe color of the cell at the i-th row and j-th column (1 ≦ i ≦ H, 1 ≦ j ≦ W) is represented by a character s_{ij}. If s_{ij} is #, the cell is painted black. If s_{ij} is ., the cell is painted white. At least one cell is painted black.\n\nWe will define fractals as follows.\nThe fractal of level 0 is a 1 × 1 grid with a black cell.\nThe fractal of level k+1 is obtained by arranging smaller grids in H rows and W columns, following the pattern of the Snuke's grid.\nAt a position that corresponds to a black cell in the Snuke's grid, a copy of the fractal of level k is placed.\nAt a position that corresponds to a white cell in the Snuke's grid, a grid whose cells are all white, with the same dimensions as the fractal of level k, is placed.\n\nYou are given the description of the Snuke's grid, and an integer K. Find the number of connected components of black cells in the fractal of level K, modulo 10^9+7.\n\nConstraints\n\n1 ≦ H,W ≦ 1000\n\n0 ≦ K ≦ 10^{18}\n\nEach s_{ij} is either # or ..\n\nAll black cells in the given grid are 4-connected.\n\nThere is at least one black cell in the given grid.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nH W K\ns_{11} .. s_{1W}\n:\ns_{H1} .. s_{HW}\n\nOutput\n\nPrint the number of connected components of black cells in the fractal of level K, modulo 10^9+7.\n\nSample Input 1\n\n3 3 3\n.#.\n###\n#.#\n\nSample Output 1\n\n20\n\nThe fractal of level K=3 in this case is shown below. There are 20 connected components of black cells.\n\n.............#.............\n............###............\n............#.#............\n..........#..#..#..........\n.........#########.........\n.........#.##.##.#.........\n..........#.....#..........\n.........###...###.........\n.........#.#...#.#.........\n....#........#........#....\n...###......###......###...\n...#.#......#.#......#.#...\n.#..#..#..#..#..#..#..#..#.\n###########################\n#.##.##.##.##.##.##.##.##.#\n.#.....#..#.....#..#.....#.\n###...######...######...###\n#.#...#.##.#...#.##.#...#.#\n....#.................#....\n...###...............###...\n...#.#...............#.#...\n.#..#..#...........#..#..#.\n#########.........#########\n#.##.##.#.........#.##.##.#\n.#.....#...........#.....#.\n###...###.........###...###\n#.#...#.#.........#.#...#.#\n\nSample Input 2\n\n3 3 3\n###\n#.#\n###\n\nSample Output 2\n\n1\n\nSample Input 3\n\n11 15 1000000000000000000\n.....#.........\n....###........\n....####.......\n...######......\n...#######.....\n..##.###.##....\n..##########...\n.###.....####..\n.####...######.\n###############\n#.##..##..##..#\n\nSample Output 3\n\n301811921", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2584, "cpu_time_ms": 509, "memory_kb": 45720}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s806584510", "group_id": "codeNet:p04025", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nconst int N = 110;\nint a[N];\nint n,Max,Min;\n\nint Find(int Max,int Min)\n{\n\tint MinMoney=INT_MAX,NowMoney=0;\n\tfor(int i=Min;i<=Max;i++)\n\t{\n\t\tNowMoney=0;\n\t\tfor(int j=1;j<=n;j++)\n\t\t\tNowMoney+=((a[j]-i)*(a[j]-i));\n\t\tMinMoney=min(NowMoney,MinMoney);\n\t}\n\treturn MinMoney;\n}\nint main()\n{\n\tMax=INT_MIN;\n\tMin=INT_MAX;\n\tcin>>n;\n\tfor(int i=1;i<=n;i++)\n\t{\n\t\tcin>>a[i];\n\t\tMax=max(Max,a[i]);\n\t\tMin=min(Min,a[i]);\n\t}\n\tint money=Find(Max,Min);\n\tcout<<money<<\"\\n\";\n}", "language": "C++", "metadata": {"date": 1558293943, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p04025.html", "problem_id": "p04025", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p04025/input.txt", "sample_output_relpath": "derived/input_output/data/p04025/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p04025/C++/s806584510.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s806584510", "user_id": "u247366051"}, "prompt_components": {"gold_output": "8\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nconst int N = 110;\nint a[N];\nint n,Max,Min;\n\nint Find(int Max,int Min)\n{\n\tint MinMoney=INT_MAX,NowMoney=0;\n\tfor(int i=Min;i<=Max;i++)\n\t{\n\t\tNowMoney=0;\n\t\tfor(int j=1;j<=n;j++)\n\t\t\tNowMoney+=((a[j]-i)*(a[j]-i));\n\t\tMinMoney=min(NowMoney,MinMoney);\n\t}\n\treturn MinMoney;\n}\nint main()\n{\n\tMax=INT_MIN;\n\tMin=INT_MAX;\n\tcin>>n;\n\tfor(int i=1;i<=n;i++)\n\t{\n\t\tcin>>a[i];\n\t\tMax=max(Max,a[i]);\n\t\tMin=min(Min,a[i]);\n\t}\n\tint money=Find(Max,Min);\n\tcout<<money<<\"\\n\";\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nEvi has N integers a_1,a_2,..,a_N. His objective is to have N equal integers by transforming some of them.\n\nHe may transform each integer at most once. Transforming an integer x into another integer y costs him (x-y)^2 dollars. Even if a_i=a_j (i≠j), he has to pay the cost separately for transforming each of them (See Sample 2).\n\nFind the minimum total cost to achieve his objective.\n\nConstraints\n\n1≦N≦100\n\n-100≦a_i≦100\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_N\n\nOutput\n\nPrint the minimum total cost to achieve Evi's objective.\n\nSample Input 1\n\n2\n4 8\n\nSample Output 1\n\n8\n\nTransforming the both into 6s will cost (4-6)^2+(8-6)^2=8 dollars, which is the minimum.\n\nSample Input 2\n\n3\n1 1 3\n\nSample Output 2\n\n3\n\nTransforming the all into 2s will cost (1-2)^2+(1-2)^2+(3-2)^2=3 dollars. Note that Evi has to pay (1-2)^2 dollar separately for transforming each of the two 1s.\n\nSample Input 3\n\n3\n4 2 5\n\nSample Output 3\n\n5\n\nLeaving the 4 as it is and transforming the 2 and the 5 into 4s will achieve the total cost of (2-4)^2+(5-4)^2=5 dollars, which is the minimum.\n\nSample Input 4\n\n4\n-100 -100 -100 -100\n\nSample Output 4\n\n0\n\nWithout transforming anything, Evi's objective is already achieved. Thus, the necessary cost is 0.", "sample_input": "2\n4 8\n"}, "reference_outputs": ["8\n"], "source_document_id": "p04025", "source_text": "Score : 200 points\n\nProblem Statement\n\nEvi has N integers a_1,a_2,..,a_N. His objective is to have N equal integers by transforming some of them.\n\nHe may transform each integer at most once. Transforming an integer x into another integer y costs him (x-y)^2 dollars. Even if a_i=a_j (i≠j), he has to pay the cost separately for transforming each of them (See Sample 2).\n\nFind the minimum total cost to achieve his objective.\n\nConstraints\n\n1≦N≦100\n\n-100≦a_i≦100\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_N\n\nOutput\n\nPrint the minimum total cost to achieve Evi's objective.\n\nSample Input 1\n\n2\n4 8\n\nSample Output 1\n\n8\n\nTransforming the both into 6s will cost (4-6)^2+(8-6)^2=8 dollars, which is the minimum.\n\nSample Input 2\n\n3\n1 1 3\n\nSample Output 2\n\n3\n\nTransforming the all into 2s will cost (1-2)^2+(1-2)^2+(3-2)^2=3 dollars. Note that Evi has to pay (1-2)^2 dollar separately for transforming each of the two 1s.\n\nSample Input 3\n\n3\n4 2 5\n\nSample Output 3\n\n5\n\nLeaving the 4 as it is and transforming the 2 and the 5 into 4s will achieve the total cost of (2-4)^2+(5-4)^2=5 dollars, which is the minimum.\n\nSample Input 4\n\n4\n-100 -100 -100 -100\n\nSample Output 4\n\n0\n\nWithout transforming anything, Evi's objective is already achieved. Thus, the necessary cost is 0.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 494, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s695878017", "group_id": "codeNet:p04026", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n#define arep(i,x,n) for(int i=int(x);i<(int)(n);i++)\n#define rep(i,n) for(long long i = 0;i < n;++i)\n#define pi 3.141592653589793\n#define eps 0.00000001\n#define INF 1e9+7  \nusing ll = long long; \nusing P=pair<int,int>;\nusing lP=pair<ll,ll>;\nusing fP=pair<double,double>;\nll const mod=998244353;\nconst ll MAX=300000;\nusing vi=vector<int>;\nusing vc=vector<char>;\nusing vs=vector<string>;\nusing vvi =vector<vector<int>>;\nusing vvc=vector<vector<char>>;\nusing vvp =vector<vector<P>>;\n\n\nint main(){\n    string s;\n    cin>>s;\n    int n=s.size();\n    rep(i,n-1){\n        if(i+2<n&&s[i]==s[i+2]){\n            cout<<i+1<<\" \"<<i+3<<endl;\n            return 0;\n        }\n        if(s[i]==s[i+1]){\n            cout<<i+1<<\" \"<<i+2<<endl;\n            return 0;\n        }\n    }\n    cout<<-1<<\" \"<<-1<<endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1590112463, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p04026.html", "problem_id": "p04026", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p04026/input.txt", "sample_output_relpath": "derived/input_output/data/p04026/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p04026/C++/s695878017.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s695878017", "user_id": "u395287054"}, "prompt_components": {"gold_output": "2 5\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n#define arep(i,x,n) for(int i=int(x);i<(int)(n);i++)\n#define rep(i,n) for(long long i = 0;i < n;++i)\n#define pi 3.141592653589793\n#define eps 0.00000001\n#define INF 1e9+7  \nusing ll = long long; \nusing P=pair<int,int>;\nusing lP=pair<ll,ll>;\nusing fP=pair<double,double>;\nll const mod=998244353;\nconst ll MAX=300000;\nusing vi=vector<int>;\nusing vc=vector<char>;\nusing vs=vector<string>;\nusing vvi =vector<vector<int>>;\nusing vvc=vector<vector<char>>;\nusing vvp =vector<vector<P>>;\n\n\nint main(){\n    string s;\n    cin>>s;\n    int n=s.size();\n    rep(i,n-1){\n        if(i+2<n&&s[i]==s[i+2]){\n            cout<<i+1<<\" \"<<i+3<<endl;\n            return 0;\n        }\n        if(s[i]==s[i+1]){\n            cout<<i+1<<\" \"<<i+2<<endl;\n            return 0;\n        }\n    }\n    cout<<-1<<\" \"<<-1<<endl;\n    return 0;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nGiven a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both voodoo and melee are unbalanced, while neither noon nor a is.\n\nYou are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.\n\nConstraints\n\n2 ≦ |s| ≦ 10^5\n\ns consists of lowercase letters.\n\nPartial Score\n\n200 points will be awarded for passing the test set satisfying 2 ≦ N ≦ 100.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\ns\n\nOutput\n\nIf there exists no unbalanced substring of s, print -1 -1.\n\nIf there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print a b. If there exists more than one such substring, any of them will be accepted.\n\nSample Input 1\n\nneeded\n\nSample Output 1\n\n2 5\n\nThe string s_2 s_3 s_4 s_5 = eede is unbalanced. There are also other unbalanced substrings. For example, the output 2 6 will also be accepted.\n\nSample Input 2\n\natcoder\n\nSample Output 2\n\n-1 -1\n\nThe string atcoder contains no unbalanced substring.", "sample_input": "needed\n"}, "reference_outputs": ["2 5\n"], "source_document_id": "p04026", "source_text": "Score : 400 points\n\nProblem Statement\n\nGiven a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both voodoo and melee are unbalanced, while neither noon nor a is.\n\nYou are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.\n\nConstraints\n\n2 ≦ |s| ≦ 10^5\n\ns consists of lowercase letters.\n\nPartial Score\n\n200 points will be awarded for passing the test set satisfying 2 ≦ N ≦ 100.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\ns\n\nOutput\n\nIf there exists no unbalanced substring of s, print -1 -1.\n\nIf there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print a b. If there exists more than one such substring, any of them will be accepted.\n\nSample Input 1\n\nneeded\n\nSample Output 1\n\n2 5\n\nThe string s_2 s_3 s_4 s_5 = eede is unbalanced. There are also other unbalanced substrings. For example, the output 2 6 will also be accepted.\n\nSample Input 2\n\natcoder\n\nSample Output 2\n\n-1 -1\n\nThe string atcoder contains no unbalanced substring.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 852, "cpu_time_ms": 4, "memory_kb": 512}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s265303209", "group_id": "codeNet:p04026", "input_text": "#include<cstdio>\n#include<cstring>\nconst int N=100000;\n\nchar s[N+5];\nint P[256],len;\nbool f;\n\nbool Pan(int k,int d)\n{\n\treturn k>(d>>1);\n}\n\nbool Find(int d)\n{\n\tmemset(P,0,sizeof(P));\n\tfor(int i=1;i<=d;i++)\n\t\tif(Pan(++P[s[i]],d))\n\t\t{\n\t\t\tprintf(\"1 %d\\n\",d);\n\t\t\tf=1; return true;\n\t\t}\n\t\n\tfor(int i=d+1;i<=len;i++)\n\t{\n\t\tP[s[i-d]]--;\n\t\tif(Pan(++P[s[i]],d))\n\t\t{\n\t\t\tprintf(\"%d %d\\n\",i,i+d-1);\n\t\t\tf=1; return true;\n\t\t}\n\t}\n\treturn false;\n}\n\nint main()\n{\n\tscanf(\"%s\",s+1);\n\tlen=strlen(s+1);\n\t\n\tint depth=3;\n\twhile(depth<=len&&!Find(depth)) depth++;\n\t\n\tif(!f) puts(\"-1 -1\");\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1531515077, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p04026.html", "problem_id": "p04026", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p04026/input.txt", "sample_output_relpath": "derived/input_output/data/p04026/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p04026/C++/s265303209.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s265303209", "user_id": "u816631826"}, "prompt_components": {"gold_output": "2 5\n", "input_to_evaluate": "#include<cstdio>\n#include<cstring>\nconst int N=100000;\n\nchar s[N+5];\nint P[256],len;\nbool f;\n\nbool Pan(int k,int d)\n{\n\treturn k>(d>>1);\n}\n\nbool Find(int d)\n{\n\tmemset(P,0,sizeof(P));\n\tfor(int i=1;i<=d;i++)\n\t\tif(Pan(++P[s[i]],d))\n\t\t{\n\t\t\tprintf(\"1 %d\\n\",d);\n\t\t\tf=1; return true;\n\t\t}\n\t\n\tfor(int i=d+1;i<=len;i++)\n\t{\n\t\tP[s[i-d]]--;\n\t\tif(Pan(++P[s[i]],d))\n\t\t{\n\t\t\tprintf(\"%d %d\\n\",i,i+d-1);\n\t\t\tf=1; return true;\n\t\t}\n\t}\n\treturn false;\n}\n\nint main()\n{\n\tscanf(\"%s\",s+1);\n\tlen=strlen(s+1);\n\t\n\tint depth=3;\n\twhile(depth<=len&&!Find(depth)) depth++;\n\t\n\tif(!f) puts(\"-1 -1\");\n\treturn 0;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nGiven a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both voodoo and melee are unbalanced, while neither noon nor a is.\n\nYou are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.\n\nConstraints\n\n2 ≦ |s| ≦ 10^5\n\ns consists of lowercase letters.\n\nPartial Score\n\n200 points will be awarded for passing the test set satisfying 2 ≦ N ≦ 100.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\ns\n\nOutput\n\nIf there exists no unbalanced substring of s, print -1 -1.\n\nIf there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print a b. If there exists more than one such substring, any of them will be accepted.\n\nSample Input 1\n\nneeded\n\nSample Output 1\n\n2 5\n\nThe string s_2 s_3 s_4 s_5 = eede is unbalanced. There are also other unbalanced substrings. For example, the output 2 6 will also be accepted.\n\nSample Input 2\n\natcoder\n\nSample Output 2\n\n-1 -1\n\nThe string atcoder contains no unbalanced substring.", "sample_input": "needed\n"}, "reference_outputs": ["2 5\n"], "source_document_id": "p04026", "source_text": "Score : 400 points\n\nProblem Statement\n\nGiven a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both voodoo and melee are unbalanced, while neither noon nor a is.\n\nYou are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.\n\nConstraints\n\n2 ≦ |s| ≦ 10^5\n\ns consists of lowercase letters.\n\nPartial Score\n\n200 points will be awarded for passing the test set satisfying 2 ≦ N ≦ 100.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\ns\n\nOutput\n\nIf there exists no unbalanced substring of s, print -1 -1.\n\nIf there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print a b. If there exists more than one such substring, any of them will be accepted.\n\nSample Input 1\n\nneeded\n\nSample Output 1\n\n2 5\n\nThe string s_2 s_3 s_4 s_5 = eede is unbalanced. There are also other unbalanced substrings. For example, the output 2 6 will also be accepted.\n\nSample Input 2\n\natcoder\n\nSample Output 2\n\n-1 -1\n\nThe string atcoder contains no unbalanced substring.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 574, "cpu_time_ms": 2103, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s485598741", "group_id": "codeNet:p04026", "input_text": "#include <iostream>\n#include <vector>\n#include <string>\n#include <map>\n#include <set>\n#include <cmath>\n#include <algorithm>\n  \n#define INF 2000000010\n#define mod7 1000000007\n#define YJ 1145141919\n#define INF_INT_MAX 2147483647\n#define INF_LL_MAX 9223372036854775807\n#define INF_LL 9223372036854775\n#define EPS 1e-10\n#define Pi acos(-1)\n#define LL long long\n#define ULL unsigned long long\n#define LD long double \n \nusing namespace std;\n\n#define MAX_S\n\nstring S;\n\nint main(){\n\n  cin >> S;\n  for(int i = 0; i < (int)S.length()-1; i++){\n    if(S[i] == S[i+1]){\n      cout << i+1 << \" \" << i+2 << endl;\n      return 0;\n    }\n  }\n\n  for(int i = 0; i < (int)S.length()-2; i++){\n    if(S[i] == S[i+2]){\n      cout << i+1 << \" \" << i+3 << endl;\n      return 0;\n    }\n  }\n\n  cout << -1 << \" \" << -1 << endl;\n\n  return 0;\n\n}\n", "language": "C++", "metadata": {"date": 1471136908, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p04026.html", "problem_id": "p04026", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p04026/input.txt", "sample_output_relpath": "derived/input_output/data/p04026/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p04026/C++/s485598741.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s485598741", "user_id": "u246275061"}, "prompt_components": {"gold_output": "2 5\n", "input_to_evaluate": "#include <iostream>\n#include <vector>\n#include <string>\n#include <map>\n#include <set>\n#include <cmath>\n#include <algorithm>\n  \n#define INF 2000000010\n#define mod7 1000000007\n#define YJ 1145141919\n#define INF_INT_MAX 2147483647\n#define INF_LL_MAX 9223372036854775807\n#define INF_LL 9223372036854775\n#define EPS 1e-10\n#define Pi acos(-1)\n#define LL long long\n#define ULL unsigned long long\n#define LD long double \n \nusing namespace std;\n\n#define MAX_S\n\nstring S;\n\nint main(){\n\n  cin >> S;\n  for(int i = 0; i < (int)S.length()-1; i++){\n    if(S[i] == S[i+1]){\n      cout << i+1 << \" \" << i+2 << endl;\n      return 0;\n    }\n  }\n\n  for(int i = 0; i < (int)S.length()-2; i++){\n    if(S[i] == S[i+2]){\n      cout << i+1 << \" \" << i+3 << endl;\n      return 0;\n    }\n  }\n\n  cout << -1 << \" \" << -1 << endl;\n\n  return 0;\n\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nGiven a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both voodoo and melee are unbalanced, while neither noon nor a is.\n\nYou are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.\n\nConstraints\n\n2 ≦ |s| ≦ 10^5\n\ns consists of lowercase letters.\n\nPartial Score\n\n200 points will be awarded for passing the test set satisfying 2 ≦ N ≦ 100.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\ns\n\nOutput\n\nIf there exists no unbalanced substring of s, print -1 -1.\n\nIf there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print a b. If there exists more than one such substring, any of them will be accepted.\n\nSample Input 1\n\nneeded\n\nSample Output 1\n\n2 5\n\nThe string s_2 s_3 s_4 s_5 = eede is unbalanced. There are also other unbalanced substrings. For example, the output 2 6 will also be accepted.\n\nSample Input 2\n\natcoder\n\nSample Output 2\n\n-1 -1\n\nThe string atcoder contains no unbalanced substring.", "sample_input": "needed\n"}, "reference_outputs": ["2 5\n"], "source_document_id": "p04026", "source_text": "Score : 400 points\n\nProblem Statement\n\nGiven a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both voodoo and melee are unbalanced, while neither noon nor a is.\n\nYou are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.\n\nConstraints\n\n2 ≦ |s| ≦ 10^5\n\ns consists of lowercase letters.\n\nPartial Score\n\n200 points will be awarded for passing the test set satisfying 2 ≦ N ≦ 100.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\ns\n\nOutput\n\nIf there exists no unbalanced substring of s, print -1 -1.\n\nIf there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print a b. If there exists more than one such substring, any of them will be accepted.\n\nSample Input 1\n\nneeded\n\nSample Output 1\n\n2 5\n\nThe string s_2 s_3 s_4 s_5 = eede is unbalanced. There are also other unbalanced substrings. For example, the output 2 6 will also be accepted.\n\nSample Input 2\n\natcoder\n\nSample Output 2\n\n-1 -1\n\nThe string atcoder contains no unbalanced substring.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 814, "cpu_time_ms": 10, "memory_kb": 512}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s714939287", "group_id": "codeNet:p04029", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(void){\n  int n; cin >> n;\n  cout << n*(n+1)/2 << endl;\n  return 0;\n}", "language": "C++", "metadata": {"date": 1512943850, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p04029.html", "problem_id": "p04029", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p04029/input.txt", "sample_output_relpath": "derived/input_output/data/p04029/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p04029/C++/s714939287.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s714939287", "user_id": "u212904724"}, "prompt_components": {"gold_output": "6\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\n\nint main(void){\n  int n; cin >> n;\n  cout << n*(n+1)/2 << endl;\n  return 0;\n}", "problem_context": "Score : 100 points\n\nProblem Statement\n\nThere are N children in AtCoder Kindergarten. Mr. Evi will arrange the children in a line, then give 1 candy to the first child in the line, 2 candies to the second child, ..., N candies to the N-th child. How many candies will be necessary in total?\n\nConstraints\n\n1≦N≦100\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the necessary number of candies in total.\n\nSample Input 1\n\n3\n\nSample Output 1\n\n6\n\nThe answer is 1+2+3=6.\n\nSample Input 2\n\n10\n\nSample Output 2\n\n55\n\nThe sum of the integers from 1 to 10 is 55.\n\nSample Input 3\n\n1\n\nSample Output 3\n\n1\n\nOnly one child. The answer is 1 in this case.", "sample_input": "3\n"}, "reference_outputs": ["6\n"], "source_document_id": "p04029", "source_text": "Score : 100 points\n\nProblem Statement\n\nThere are N children in AtCoder Kindergarten. Mr. Evi will arrange the children in a line, then give 1 candy to the first child in the line, 2 candies to the second child, ..., N candies to the N-th child. How many candies will be necessary in total?\n\nConstraints\n\n1≦N≦100\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\n\nOutput\n\nPrint the necessary number of candies in total.\n\nSample Input 1\n\n3\n\nSample Output 1\n\n6\n\nThe answer is 1+2+3=6.\n\nSample Input 2\n\n10\n\nSample Output 2\n\n55\n\nThe sum of the integers from 1 to 10 is 55.\n\nSample Input 3\n\n1\n\nSample Output 3\n\n1\n\nOnly one child. The answer is 1 in this case.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 123, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s886265832", "group_id": "codeNet:p04030", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n  string s;\n  cin>>s;\n  vector<char>ans(s.size());\n  int j=-1;\n  for(int i=0;i<s.size();i++)\n  {\n      if(s[i]=='B')\n      {\n        if(j==-1)\n          continue;\n        else\n          j--;\n      }\n      else\n      {\n        ans[j+1]=s[i];\n        j++;\n      }\n  }\n  for(int i=0;i<=j;i++)\n  {\n    cout<<ans[i];\n  }\n  \n  return 0;\n}", "language": "C++", "metadata": {"date": 1570395549, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p04030.html", "problem_id": "p04030", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p04030/input.txt", "sample_output_relpath": "derived/input_output/data/p04030/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p04030/C++/s886265832.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s886265832", "user_id": "u847764000"}, "prompt_components": {"gold_output": "00\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n  string s;\n  cin>>s;\n  vector<char>ans(s.size());\n  int j=-1;\n  for(int i=0;i<s.size();i++)\n  {\n      if(s[i]=='B')\n      {\n        if(j==-1)\n          continue;\n        else\n          j--;\n      }\n      else\n      {\n        ans[j+1]=s[i];\n        j++;\n      }\n  }\n  for(int i=0;i<=j;i++)\n  {\n    cout<<ans[i];\n  }\n  \n  return 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nSig has built his own keyboard. Designed for ultimate simplicity, this keyboard only has 3 keys on it: the 0 key, the 1 key and the backspace key.\n\nTo begin with, he is using a plain text editor with this keyboard. This editor always displays one string (possibly empty). Just after the editor is launched, this string is empty. When each key on the keyboard is pressed, the following changes occur to the string:\n\nThe 0 key: a letter 0 will be inserted to the right of the string.\n\nThe 1 key: a letter 1 will be inserted to the right of the string.\n\nThe backspace key: if the string is empty, nothing happens. Otherwise, the rightmost letter of the string is deleted.\n\nSig has launched the editor, and pressed these keys several times. You are given a string s, which is a record of his keystrokes in order. In this string, the letter 0 stands for the 0 key, the letter 1 stands for the 1 key and the letter B stands for the backspace key. What string is displayed in the editor now?\n\nConstraints\n\n1 ≦ |s| ≦ 10 (|s| denotes the length of s)\n\ns consists of the letters 0, 1 and B.\n\nThe correct answer is not an empty string.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\ns\n\nOutput\n\nPrint the string displayed in the editor in the end.\n\nSample Input 1\n\n01B0\n\nSample Output 1\n\n00\n\nEach time the key is pressed, the string in the editor will change as follows: 0, 01, 0, 00.\n\nSample Input 2\n\n0BB1\n\nSample Output 2\n\n1\n\nEach time the key is pressed, the string in the editor will change as follows: 0, (empty), (empty), 1.", "sample_input": "01B0\n"}, "reference_outputs": ["00\n"], "source_document_id": "p04030", "source_text": "Score : 200 points\n\nProblem Statement\n\nSig has built his own keyboard. Designed for ultimate simplicity, this keyboard only has 3 keys on it: the 0 key, the 1 key and the backspace key.\n\nTo begin with, he is using a plain text editor with this keyboard. This editor always displays one string (possibly empty). Just after the editor is launched, this string is empty. When each key on the keyboard is pressed, the following changes occur to the string:\n\nThe 0 key: a letter 0 will be inserted to the right of the string.\n\nThe 1 key: a letter 1 will be inserted to the right of the string.\n\nThe backspace key: if the string is empty, nothing happens. Otherwise, the rightmost letter of the string is deleted.\n\nSig has launched the editor, and pressed these keys several times. You are given a string s, which is a record of his keystrokes in order. In this string, the letter 0 stands for the 0 key, the letter 1 stands for the 1 key and the letter B stands for the backspace key. What string is displayed in the editor now?\n\nConstraints\n\n1 ≦ |s| ≦ 10 (|s| denotes the length of s)\n\ns consists of the letters 0, 1 and B.\n\nThe correct answer is not an empty string.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\ns\n\nOutput\n\nPrint the string displayed in the editor in the end.\n\nSample Input 1\n\n01B0\n\nSample Output 1\n\n00\n\nEach time the key is pressed, the string in the editor will change as follows: 0, 01, 0, 00.\n\nSample Input 2\n\n0BB1\n\nSample Output 2\n\n1\n\nEach time the key is pressed, the string in the editor will change as follows: 0, (empty), (empty), 1.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 390, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s335415153", "group_id": "codeNet:p04030", "input_text": "\n#include <string>\n#include <iostream>\nusing namespace std;\n\nint main()\n{\n\tstring s;\n\tstring buf;\n\tcin >> s;\n\tfor (char c : s)\n\t{\n\t\tif (c == 'B')\n\t\t{\n\t\t\tif (!buf.empty())buf.pop_back();\n\t\t}\n\t\telse\n\t\t{\n\t\t\tbuf.push_back(c);\n\t\t}\n\t}\n\tcout << buf << endl;\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1485228393, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p04030.html", "problem_id": "p04030", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p04030/input.txt", "sample_output_relpath": "derived/input_output/data/p04030/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p04030/C++/s335415153.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s335415153", "user_id": "u558671021"}, "prompt_components": {"gold_output": "00\n", "input_to_evaluate": "\n#include <string>\n#include <iostream>\nusing namespace std;\n\nint main()\n{\n\tstring s;\n\tstring buf;\n\tcin >> s;\n\tfor (char c : s)\n\t{\n\t\tif (c == 'B')\n\t\t{\n\t\t\tif (!buf.empty())buf.pop_back();\n\t\t}\n\t\telse\n\t\t{\n\t\t\tbuf.push_back(c);\n\t\t}\n\t}\n\tcout << buf << endl;\n\treturn 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nSig has built his own keyboard. Designed for ultimate simplicity, this keyboard only has 3 keys on it: the 0 key, the 1 key and the backspace key.\n\nTo begin with, he is using a plain text editor with this keyboard. This editor always displays one string (possibly empty). Just after the editor is launched, this string is empty. When each key on the keyboard is pressed, the following changes occur to the string:\n\nThe 0 key: a letter 0 will be inserted to the right of the string.\n\nThe 1 key: a letter 1 will be inserted to the right of the string.\n\nThe backspace key: if the string is empty, nothing happens. Otherwise, the rightmost letter of the string is deleted.\n\nSig has launched the editor, and pressed these keys several times. You are given a string s, which is a record of his keystrokes in order. In this string, the letter 0 stands for the 0 key, the letter 1 stands for the 1 key and the letter B stands for the backspace key. What string is displayed in the editor now?\n\nConstraints\n\n1 ≦ |s| ≦ 10 (|s| denotes the length of s)\n\ns consists of the letters 0, 1 and B.\n\nThe correct answer is not an empty string.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\ns\n\nOutput\n\nPrint the string displayed in the editor in the end.\n\nSample Input 1\n\n01B0\n\nSample Output 1\n\n00\n\nEach time the key is pressed, the string in the editor will change as follows: 0, 01, 0, 00.\n\nSample Input 2\n\n0BB1\n\nSample Output 2\n\n1\n\nEach time the key is pressed, the string in the editor will change as follows: 0, (empty), (empty), 1.", "sample_input": "01B0\n"}, "reference_outputs": ["00\n"], "source_document_id": "p04030", "source_text": "Score : 200 points\n\nProblem Statement\n\nSig has built his own keyboard. Designed for ultimate simplicity, this keyboard only has 3 keys on it: the 0 key, the 1 key and the backspace key.\n\nTo begin with, he is using a plain text editor with this keyboard. This editor always displays one string (possibly empty). Just after the editor is launched, this string is empty. When each key on the keyboard is pressed, the following changes occur to the string:\n\nThe 0 key: a letter 0 will be inserted to the right of the string.\n\nThe 1 key: a letter 1 will be inserted to the right of the string.\n\nThe backspace key: if the string is empty, nothing happens. Otherwise, the rightmost letter of the string is deleted.\n\nSig has launched the editor, and pressed these keys several times. You are given a string s, which is a record of his keystrokes in order. In this string, the letter 0 stands for the 0 key, the letter 1 stands for the 1 key and the letter B stands for the backspace key. What string is displayed in the editor now?\n\nConstraints\n\n1 ≦ |s| ≦ 10 (|s| denotes the length of s)\n\ns consists of the letters 0, 1 and B.\n\nThe correct answer is not an empty string.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\ns\n\nOutput\n\nPrint the string displayed in the editor in the end.\n\nSample Input 1\n\n01B0\n\nSample Output 1\n\n00\n\nEach time the key is pressed, the string in the editor will change as follows: 0, 01, 0, 00.\n\nSample Input 2\n\n0BB1\n\nSample Output 2\n\n1\n\nEach time the key is pressed, the string in the editor will change as follows: 0, (empty), (empty), 1.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 263, "cpu_time_ms": 3, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s962944158", "group_id": "codeNet:p04031", "input_text": "#include <iostream>\n#include <algorithm>\n#include <cmath>\nusing namespace std;\n\nint main()\n{\n    int n,i,j,p=0;\n    int x[105];\n    int y[1005];\n    long long sum;\n    int minone=99999;\n    int maxone=0;\n    cin>>n;\n    for(i=0;i<n;i++)\n    {\n        cin>>x[i];\n        minone=min(minone,x[i]);\n        maxone=max(maxone,x[i]);\n    }\n    for(i=minone;i<=maxone;i++)\n    {\n        sum=0;\n        for(j=0;j<n;j++)\n        {\n            sum += pow(( x[j]-i),2 );\n        }\n        y[p++]=sum;\n    }\n    sort(y,y+p);\n    cout<<y[0]<<endl;\n    return 0;\n}", "language": "C++", "metadata": {"date": 1528592321, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p04031.html", "problem_id": "p04031", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p04031/input.txt", "sample_output_relpath": "derived/input_output/data/p04031/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p04031/C++/s962944158.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s962944158", "user_id": "u955002772"}, "prompt_components": {"gold_output": "8\n", "input_to_evaluate": "#include <iostream>\n#include <algorithm>\n#include <cmath>\nusing namespace std;\n\nint main()\n{\n    int n,i,j,p=0;\n    int x[105];\n    int y[1005];\n    long long sum;\n    int minone=99999;\n    int maxone=0;\n    cin>>n;\n    for(i=0;i<n;i++)\n    {\n        cin>>x[i];\n        minone=min(minone,x[i]);\n        maxone=max(maxone,x[i]);\n    }\n    for(i=minone;i<=maxone;i++)\n    {\n        sum=0;\n        for(j=0;j<n;j++)\n        {\n            sum += pow(( x[j]-i),2 );\n        }\n        y[p++]=sum;\n    }\n    sort(y,y+p);\n    cout<<y[0]<<endl;\n    return 0;\n}", "problem_context": "Score : 200 points\n\nProblem Statement\n\nEvi has N integers a_1,a_2,..,a_N. His objective is to have N equal integers by transforming some of them.\n\nHe may transform each integer at most once. Transforming an integer x into another integer y costs him (x-y)^2 dollars. Even if a_i=a_j (i≠j), he has to pay the cost separately for transforming each of them (See Sample 2).\n\nFind the minimum total cost to achieve his objective.\n\nConstraints\n\n1≦N≦100\n\n-100≦a_i≦100\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_N\n\nOutput\n\nPrint the minimum total cost to achieve Evi's objective.\n\nSample Input 1\n\n2\n4 8\n\nSample Output 1\n\n8\n\nTransforming the both into 6s will cost (4-6)^2+(8-6)^2=8 dollars, which is the minimum.\n\nSample Input 2\n\n3\n1 1 3\n\nSample Output 2\n\n3\n\nTransforming the all into 2s will cost (1-2)^2+(1-2)^2+(3-2)^2=3 dollars. Note that Evi has to pay (1-2)^2 dollar separately for transforming each of the two 1s.\n\nSample Input 3\n\n3\n4 2 5\n\nSample Output 3\n\n5\n\nLeaving the 4 as it is and transforming the 2 and the 5 into 4s will achieve the total cost of (2-4)^2+(5-4)^2=5 dollars, which is the minimum.\n\nSample Input 4\n\n4\n-100 -100 -100 -100\n\nSample Output 4\n\n0\n\nWithout transforming anything, Evi's objective is already achieved. Thus, the necessary cost is 0.", "sample_input": "2\n4 8\n"}, "reference_outputs": ["8\n"], "source_document_id": "p04031", "source_text": "Score : 200 points\n\nProblem Statement\n\nEvi has N integers a_1,a_2,..,a_N. His objective is to have N equal integers by transforming some of them.\n\nHe may transform each integer at most once. Transforming an integer x into another integer y costs him (x-y)^2 dollars. Even if a_i=a_j (i≠j), he has to pay the cost separately for transforming each of them (See Sample 2).\n\nFind the minimum total cost to achieve his objective.\n\nConstraints\n\n1≦N≦100\n\n-100≦a_i≦100\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\na_1 a_2 ... a_N\n\nOutput\n\nPrint the minimum total cost to achieve Evi's objective.\n\nSample Input 1\n\n2\n4 8\n\nSample Output 1\n\n8\n\nTransforming the both into 6s will cost (4-6)^2+(8-6)^2=8 dollars, which is the minimum.\n\nSample Input 2\n\n3\n1 1 3\n\nSample Output 2\n\n3\n\nTransforming the all into 2s will cost (1-2)^2+(1-2)^2+(3-2)^2=3 dollars. Note that Evi has to pay (1-2)^2 dollar separately for transforming each of the two 1s.\n\nSample Input 3\n\n3\n4 2 5\n\nSample Output 3\n\n5\n\nLeaving the 4 as it is and transforming the 2 and the 5 into 4s will achieve the total cost of (2-4)^2+(5-4)^2=5 dollars, which is the minimum.\n\nSample Input 4\n\n4\n-100 -100 -100 -100\n\nSample Output 4\n\n0\n\nWithout transforming anything, Evi's objective is already achieved. Thus, the necessary cost is 0.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 550, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s424027936", "group_id": "codeNet:p04032", "input_text": "#include<stdio.h>\n#include<string.h>\nint main(){\nint a;\nchar b[10005];\nscanf(\"%s\",b);\na=strlen(b);\nfor(int i=0;i<a-2;i++){\nif(b[i]==b[i+1]){\nprintf(\"%d %d\",i+1,i+2);\nreturn 0;\n}\nif(b[i]==b[i+2]){\nprintf(\"%d %d\",i+1,i+3);\nreturn 0;\n}\n}\nif(b[a-2]==b[a-1]){\nprintf(\"%d %d\",a-1,a);\nreturn 0;\n}\n\nprintf(\"%d  %d\",-1,-1);\nreturn 0;\n}", "language": "C++", "metadata": {"date": 1475712965, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p04032.html", "problem_id": "p04032", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p04032/input.txt", "sample_output_relpath": "derived/input_output/data/p04032/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p04032/C++/s424027936.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s424027936", "user_id": "u478808605"}, "prompt_components": {"gold_output": "2 5\n", "input_to_evaluate": "#include<stdio.h>\n#include<string.h>\nint main(){\nint a;\nchar b[10005];\nscanf(\"%s\",b);\na=strlen(b);\nfor(int i=0;i<a-2;i++){\nif(b[i]==b[i+1]){\nprintf(\"%d %d\",i+1,i+2);\nreturn 0;\n}\nif(b[i]==b[i+2]){\nprintf(\"%d %d\",i+1,i+3);\nreturn 0;\n}\n}\nif(b[a-2]==b[a-1]){\nprintf(\"%d %d\",a-1,a);\nreturn 0;\n}\n\nprintf(\"%d  %d\",-1,-1);\nreturn 0;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nGiven a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both voodoo and melee are unbalanced, while neither noon nor a is.\n\nYou are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.\n\nConstraints\n\n2 ≦ |s| ≦ 10^5\n\ns consists of lowercase letters.\n\nPartial Score\n\n200 points will be awarded for passing the test set satisfying 2 ≦ N ≦ 100.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\ns\n\nOutput\n\nIf there exists no unbalanced substring of s, print -1 -1.\n\nIf there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print a b. If there exists more than one such substring, any of them will be accepted.\n\nSample Input 1\n\nneeded\n\nSample Output 1\n\n2 5\n\nThe string s_2 s_3 s_4 s_5 = eede is unbalanced. There are also other unbalanced substrings. For example, the output 2 6 will also be accepted.\n\nSample Input 2\n\natcoder\n\nSample Output 2\n\n-1 -1\n\nThe string atcoder contains no unbalanced substring.", "sample_input": "needed\n"}, "reference_outputs": ["2 5\n"], "source_document_id": "p04032", "source_text": "Score : 400 points\n\nProblem Statement\n\nGiven a string t, we will call it unbalanced if and only if the length of t is at least 2, and more than half of the letters in t are the same. For example, both voodoo and melee are unbalanced, while neither noon nor a is.\n\nYou are given a string s consisting of lowercase letters. Determine if there exists a (contiguous) substring of s that is unbalanced. If the answer is positive, show a position where such a substring occurs in s.\n\nConstraints\n\n2 ≦ |s| ≦ 10^5\n\ns consists of lowercase letters.\n\nPartial Score\n\n200 points will be awarded for passing the test set satisfying 2 ≦ N ≦ 100.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\ns\n\nOutput\n\nIf there exists no unbalanced substring of s, print -1 -1.\n\nIf there exists an unbalanced substring of s, let one such substring be s_a s_{a+1} ... s_{b} (1 ≦ a < b ≦ |s|), and print a b. If there exists more than one such substring, any of them will be accepted.\n\nSample Input 1\n\nneeded\n\nSample Output 1\n\n2 5\n\nThe string s_2 s_3 s_4 s_5 = eede is unbalanced. There are also other unbalanced substrings. For example, the output 2 6 will also be accepted.\n\nSample Input 2\n\natcoder\n\nSample Output 2\n\n-1 -1\n\nThe string atcoder contains no unbalanced substring.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 326, "cpu_time_ms": 118, "memory_kb": 128}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s692707004", "group_id": "codeNet:p04033", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\n\nint a, b;\n\nint main() {\n    scanf(\"%d%d\", &a, &b);\n    if(a <= 0 && b >= 0) printf(\"Zero\\n\");\n    else if(a < 0 && b < 0) {\n        if(b - a + 1 % 2 == 0) printf(\"Positive\\n\");\n        else printf(\"Negative\\n\");\n    } else printf(\"Positive\\n\");\n}", "language": "C++", "metadata": {"date": 1592081777, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p04033.html", "problem_id": "p04033", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p04033/input.txt", "sample_output_relpath": "derived/input_output/data/p04033/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p04033/C++/s692707004.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s692707004", "user_id": "u863370423"}, "prompt_components": {"gold_output": "Positive\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\n\nint a, b;\n\nint main() {\n    scanf(\"%d%d\", &a, &b);\n    if(a <= 0 && b >= 0) printf(\"Zero\\n\");\n    else if(a < 0 && b < 0) {\n        if(b - a + 1 % 2 == 0) printf(\"Positive\\n\");\n        else printf(\"Negative\\n\");\n    } else printf(\"Positive\\n\");\n}", "problem_context": "Problem Statement\n\nYou are given two integers a and b (a≤b). Determine if the product of the integers a, a+1, …, b is positive, negative or zero.\n\nConstraints\n\na and b are integers.\n\n-10^9≤a≤b≤10^9\n\nPartial Score\n\nIn test cases worth 100 points, -10≤a≤b≤10.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\na b\n\nOutput\n\nIf the product is positive, print Positive. If it is negative, print Negative. If it is zero, print Zero.\n\nSample Input 1\n\n1 3\n\nSample Output 1\n\nPositive\n\n1×2×3=6 is positive.\n\nSample Input 2\n\n-3 -1\n\nSample Output 2\n\nNegative\n\n(-3)×(-2)×(-1)=-6 is negative.\n\nSample Input 3\n\n-1 1\n\nSample Output 3\n\nZero\n\n(-1)×0×1=0.", "sample_input": "1 3\n"}, "reference_outputs": ["Positive\n"], "source_document_id": "p04033", "source_text": "Problem Statement\n\nYou are given two integers a and b (a≤b). Determine if the product of the integers a, a+1, …, b is positive, negative or zero.\n\nConstraints\n\na and b are integers.\n\n-10^9≤a≤b≤10^9\n\nPartial Score\n\nIn test cases worth 100 points, -10≤a≤b≤10.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\na b\n\nOutput\n\nIf the product is positive, print Positive. If it is negative, print Negative. If it is zero, print Zero.\n\nSample Input 1\n\n1 3\n\nSample Output 1\n\nPositive\n\n1×2×3=6 is positive.\n\nSample Input 2\n\n-3 -1\n\nSample Output 2\n\nNegative\n\n(-3)×(-2)×(-1)=-6 is negative.\n\nSample Input 3\n\n-1 1\n\nSample Output 3\n\nZero\n\n(-1)×0×1=0.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 293, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s763128228", "group_id": "codeNet:p04033", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n  int a,b;\n  cin>>a>>b;\n  if(a>0 && b>0)\n    cout<<\"Positive\"<<endl;\n  else\n    if(a<0 && b<0)\n    {\n      if(b==a)\n        cout<<\"Positive\"<<endl;\n      else\n      if(b-a%2==0)\n        cout<<\"Negative\"<<endl;\n      else\n        cout<<\"Positive\"<<endl;\n    }\n  else\n    cout<<\"Zero\"<<endl;\n  \n  \n  return 0;\n}", "language": "C++", "metadata": {"date": 1583375330, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p04033.html", "problem_id": "p04033", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p04033/input.txt", "sample_output_relpath": "derived/input_output/data/p04033/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p04033/C++/s763128228.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s763128228", "user_id": "u537266526"}, "prompt_components": {"gold_output": "Positive\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\nint main()\n{\n  int a,b;\n  cin>>a>>b;\n  if(a>0 && b>0)\n    cout<<\"Positive\"<<endl;\n  else\n    if(a<0 && b<0)\n    {\n      if(b==a)\n        cout<<\"Positive\"<<endl;\n      else\n      if(b-a%2==0)\n        cout<<\"Negative\"<<endl;\n      else\n        cout<<\"Positive\"<<endl;\n    }\n  else\n    cout<<\"Zero\"<<endl;\n  \n  \n  return 0;\n}", "problem_context": "Problem Statement\n\nYou are given two integers a and b (a≤b). Determine if the product of the integers a, a+1, …, b is positive, negative or zero.\n\nConstraints\n\na and b are integers.\n\n-10^9≤a≤b≤10^9\n\nPartial Score\n\nIn test cases worth 100 points, -10≤a≤b≤10.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\na b\n\nOutput\n\nIf the product is positive, print Positive. If it is negative, print Negative. If it is zero, print Zero.\n\nSample Input 1\n\n1 3\n\nSample Output 1\n\nPositive\n\n1×2×3=6 is positive.\n\nSample Input 2\n\n-3 -1\n\nSample Output 2\n\nNegative\n\n(-3)×(-2)×(-1)=-6 is negative.\n\nSample Input 3\n\n-1 1\n\nSample Output 3\n\nZero\n\n(-1)×0×1=0.", "sample_input": "1 3\n"}, "reference_outputs": ["Positive\n"], "source_document_id": "p04033", "source_text": "Problem Statement\n\nYou are given two integers a and b (a≤b). Determine if the product of the integers a, a+1, …, b is positive, negative or zero.\n\nConstraints\n\na and b are integers.\n\n-10^9≤a≤b≤10^9\n\nPartial Score\n\nIn test cases worth 100 points, -10≤a≤b���10.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\na b\n\nOutput\n\nIf the product is positive, print Positive. If it is negative, print Negative. If it is zero, print Zero.\n\nSample Input 1\n\n1 3\n\nSample Output 1\n\nPositive\n\n1×2×3=6 is positive.\n\nSample Input 2\n\n-3 -1\n\nSample Output 2\n\nNegative\n\n(-3)×(-2)×(-1)=-6 is negative.\n\nSample Input 3\n\n-1 1\n\nSample Output 3\n\nZero\n\n(-1)×0×1=0.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 367, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s593356064", "group_id": "codeNet:p04033", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll, ll> pii;\n#define FOR(i, j, k, in) for (ll i=j ; i<k ; i+=in)\n#define REP(i, j) FOR(i, 0, j, 1)\n#define ALL(_a) _a.begin(),_a.end()\n#define mp make_pair\n#define eb emplace_back\n#define X first\n#define Y second\n\nconst ll MOD=1000000007;\nconst ll INF=0x3f3f3f3f3f3f3f3f;\nconst ll MAXN=1e5+5;\nconst ll MAXLG=__lg(MAXN)+2;\n\nstruct QUERY {\n    ll x,y,z;\n};\n\nstruct SOLVER {\n    vector<ll> qid;\n    ll L,R;\n};\n\nll n,m,q,ans[MAXN];\nvector<pii> edge;\nvector<QUERY> Q;\nll djs[MAXN],sz[MAXN];\n\nvoid init() {\n    REP (i,MAXN) {\n        djs[i] = i;\n        sz[i] = 1;\n    }\n}\n\nll fnd(ll x) {\n    return djs[x] == x ? x : djs[x] = fnd(djs[x]);\n}\n\nvoid uni(ll x,ll y) {\n    if (sz[x=fnd(x)] < sz[y=fnd(y)]) swap(x,y);\n    djs[y] = x;\n    sz[x] += sz[y];\n}\n\n/********** Good Luck :) **********/\nint main()\n{\n    ios_base::sync_with_stdio(0);\n    cin.tie(0);\n\n    cin >> n >> m;\n\n    edge.eb(-1,-1);\n    REP (i,m) {\n        ll u,v;\n        cin >> u >> v;\n        edge.eb(u,v);\n    }\n\n    cin >> q;\n    REP (i,q) {\n        ll x,y,z;\n        cin >> x >> y >> z;\n        Q.push_back({x,y,z});\n    }\n\n    vector<ll> qid;\n    REP (i,q) {\n        qid.eb(i);\n    }\n\n    queue<SOLVER> BFS;\n    BFS.push({qid,0,m+1});\n\n    \n    ll state = INF;\n    while (BFS.size()) {\n        SOLVER cur = BFS.front();BFS.pop();\n        if (cur.L == cur.R - 1) {\n            for (auto v:cur.qid) {\n                ans[v] = cur.L;\n            }\n            continue;\n        }\n\n        ll mid = (cur.L + cur.R) / 2;\n        if (mid - 1 < state) {\n            init();\n            state = 0;\n        }\n\n        while (state < mid - 1) {\n            state++;\n            if (fnd(edge[state].X) != fnd(edge[state].Y)) {\n                uni(edge[state].X,edge[state].Y);\n            }\n        }\n\n        vector<ll> lV,rV;\n        for (auto v:cur.qid) {\n            ll siz = (fnd(Q[v].x) == fnd(Q[v].y) ? sz[fnd(Q[v].x)]:sz[fnd(Q[v].x)] + sz[fnd(Q[v].y)]);\n            if (siz >= Q[v].z) {\n                lV.eb(v);\n            } else {\n                rV.eb(v);\n            }\n        }\n\n        BFS.push({lV,cur.L,mid});\n        BFS.push({rV,mid,cur.R});\n    }\n\n    REP (i,q) {\n        cout << ans[i] << endl;\n    }\n    \n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1544076064, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p04033.html", "problem_id": "p04033", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p04033/input.txt", "sample_output_relpath": "derived/input_output/data/p04033/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p04033/C++/s593356064.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Runtime Error", "submission_id": "s593356064", "user_id": "u825429292"}, "prompt_components": {"gold_output": "Positive\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\ntypedef pair<ll, ll> pii;\n#define FOR(i, j, k, in) for (ll i=j ; i<k ; i+=in)\n#define REP(i, j) FOR(i, 0, j, 1)\n#define ALL(_a) _a.begin(),_a.end()\n#define mp make_pair\n#define eb emplace_back\n#define X first\n#define Y second\n\nconst ll MOD=1000000007;\nconst ll INF=0x3f3f3f3f3f3f3f3f;\nconst ll MAXN=1e5+5;\nconst ll MAXLG=__lg(MAXN)+2;\n\nstruct QUERY {\n    ll x,y,z;\n};\n\nstruct SOLVER {\n    vector<ll> qid;\n    ll L,R;\n};\n\nll n,m,q,ans[MAXN];\nvector<pii> edge;\nvector<QUERY> Q;\nll djs[MAXN],sz[MAXN];\n\nvoid init() {\n    REP (i,MAXN) {\n        djs[i] = i;\n        sz[i] = 1;\n    }\n}\n\nll fnd(ll x) {\n    return djs[x] == x ? x : djs[x] = fnd(djs[x]);\n}\n\nvoid uni(ll x,ll y) {\n    if (sz[x=fnd(x)] < sz[y=fnd(y)]) swap(x,y);\n    djs[y] = x;\n    sz[x] += sz[y];\n}\n\n/********** Good Luck :) **********/\nint main()\n{\n    ios_base::sync_with_stdio(0);\n    cin.tie(0);\n\n    cin >> n >> m;\n\n    edge.eb(-1,-1);\n    REP (i,m) {\n        ll u,v;\n        cin >> u >> v;\n        edge.eb(u,v);\n    }\n\n    cin >> q;\n    REP (i,q) {\n        ll x,y,z;\n        cin >> x >> y >> z;\n        Q.push_back({x,y,z});\n    }\n\n    vector<ll> qid;\n    REP (i,q) {\n        qid.eb(i);\n    }\n\n    queue<SOLVER> BFS;\n    BFS.push({qid,0,m+1});\n\n    \n    ll state = INF;\n    while (BFS.size()) {\n        SOLVER cur = BFS.front();BFS.pop();\n        if (cur.L == cur.R - 1) {\n            for (auto v:cur.qid) {\n                ans[v] = cur.L;\n            }\n            continue;\n        }\n\n        ll mid = (cur.L + cur.R) / 2;\n        if (mid - 1 < state) {\n            init();\n            state = 0;\n        }\n\n        while (state < mid - 1) {\n            state++;\n            if (fnd(edge[state].X) != fnd(edge[state].Y)) {\n                uni(edge[state].X,edge[state].Y);\n            }\n        }\n\n        vector<ll> lV,rV;\n        for (auto v:cur.qid) {\n            ll siz = (fnd(Q[v].x) == fnd(Q[v].y) ? sz[fnd(Q[v].x)]:sz[fnd(Q[v].x)] + sz[fnd(Q[v].y)]);\n            if (siz >= Q[v].z) {\n                lV.eb(v);\n            } else {\n                rV.eb(v);\n            }\n        }\n\n        BFS.push({lV,cur.L,mid});\n        BFS.push({rV,mid,cur.R});\n    }\n\n    REP (i,q) {\n        cout << ans[i] << endl;\n    }\n    \n    return 0;\n}\n", "problem_context": "Problem Statement\n\nYou are given two integers a and b (a≤b). Determine if the product of the integers a, a+1, …, b is positive, negative or zero.\n\nConstraints\n\na and b are integers.\n\n-10^9≤a≤b≤10^9\n\nPartial Score\n\nIn test cases worth 100 points, -10≤a≤b≤10.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\na b\n\nOutput\n\nIf the product is positive, print Positive. If it is negative, print Negative. If it is zero, print Zero.\n\nSample Input 1\n\n1 3\n\nSample Output 1\n\nPositive\n\n1×2×3=6 is positive.\n\nSample Input 2\n\n-3 -1\n\nSample Output 2\n\nNegative\n\n(-3)×(-2)×(-1)=-6 is negative.\n\nSample Input 3\n\n-1 1\n\nSample Output 3\n\nZero\n\n(-1)×0×1=0.", "sample_input": "1 3\n"}, "reference_outputs": ["Positive\n"], "source_document_id": "p04033", "source_text": "Problem Statement\n\nYou are given two integers a and b (a≤b). Determine if the product of the integers a, a+1, …, b is positive, negative or zero.\n\nConstraints\n\na and b are integers.\n\n-10^9≤a≤b≤10^9\n\nPartial Score\n\nIn test cases worth 100 points, -10≤a≤b≤10.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\na b\n\nOutput\n\nIf the product is positive, print Positive. If it is negative, print Negative. If it is zero, print Zero.\n\nSample Input 1\n\n1 3\n\nSample Output 1\n\nPositive\n\n1×2×3=6 is positive.\n\nSample Input 2\n\n-3 -1\n\nSample Output 2\n\nNegative\n\n(-3)×(-2)×(-1)=-6 is negative.\n\nSample Input 3\n\n-1 1\n\nSample Output 3\n\nZero\n\n(-1)×0×1=0.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2274, "cpu_time_ms": 2109, "memory_kb": 1942348}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s385014217", "group_id": "codeNet:p04033", "input_text": "#include \"bits/stdc++.h\"\nusing namespace std;\n\nint main(){\n\tint a, b;\n\tcin>>a>>b;\n\tif(a <= 0 and b >= 0)\tcout<<\"Zero\\n\";\n\telse{\n\t\tif(a > 0)\tcout<<\"Positive\\n\";\n\t\telse{\n\t\t\tint diff = (b - a) + 1;\n\t\t\tif((diff % 2) == 0)\tcout<<\"Positive\\n\";\n\t\t\telse cout<<\"Negative\\n\";\n\t\t}\n\t}\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1470119132, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p04033.html", "problem_id": "p04033", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p04033/input.txt", "sample_output_relpath": "derived/input_output/data/p04033/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p04033/C++/s385014217.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s385014217", "user_id": "u146547555"}, "prompt_components": {"gold_output": "Positive\n", "input_to_evaluate": "#include \"bits/stdc++.h\"\nusing namespace std;\n\nint main(){\n\tint a, b;\n\tcin>>a>>b;\n\tif(a <= 0 and b >= 0)\tcout<<\"Zero\\n\";\n\telse{\n\t\tif(a > 0)\tcout<<\"Positive\\n\";\n\t\telse{\n\t\t\tint diff = (b - a) + 1;\n\t\t\tif((diff % 2) == 0)\tcout<<\"Positive\\n\";\n\t\t\telse cout<<\"Negative\\n\";\n\t\t}\n\t}\n\treturn 0;\n}", "problem_context": "Problem Statement\n\nYou are given two integers a and b (a≤b). Determine if the product of the integers a, a+1, …, b is positive, negative or zero.\n\nConstraints\n\na and b are integers.\n\n-10^9≤a≤b≤10^9\n\nPartial Score\n\nIn test cases worth 100 points, -10≤a≤b≤10.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\na b\n\nOutput\n\nIf the product is positive, print Positive. If it is negative, print Negative. If it is zero, print Zero.\n\nSample Input 1\n\n1 3\n\nSample Output 1\n\nPositive\n\n1×2×3=6 is positive.\n\nSample Input 2\n\n-3 -1\n\nSample Output 2\n\nNegative\n\n(-3)×(-2)×(-1)=-6 is negative.\n\nSample Input 3\n\n-1 1\n\nSample Output 3\n\nZero\n\n(-1)×0×1=0.", "sample_input": "1 3\n"}, "reference_outputs": ["Positive\n"], "source_document_id": "p04033", "source_text": "Problem Statement\n\nYou are given two integers a and b (a≤b). Determine if the product of the integers a, a+1, …, b is positive, negative or zero.\n\nConstraints\n\na and b are integers.\n\n-10^9≤a≤b≤10^9\n\nPartial Score\n\nIn test cases worth 100 points, -10≤a≤b≤10.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\na b\n\nOutput\n\nIf the product is positive, print Positive. If it is negative, print Negative. If it is zero, print Zero.\n\nSample Input 1\n\n1 3\n\nSample Output 1\n\nPositive\n\n1×2×3=6 is positive.\n\nSample Input 2\n\n-3 -1\n\nSample Output 2\n\nNegative\n\n(-3)×(-2)×(-1)=-6 is negative.\n\nSample Input 3\n\n-1 1\n\nSample Output 3\n\nZero\n\n(-1)×0×1=0.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 285, "cpu_time_ms": 8, "memory_kb": 384}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s848766609", "group_id": "codeNet:p04034", "input_text": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n  int n,m;cin>>n>>m;\n  int ball[n+1];\n  for(int i=0;i<n;i++) ball[i]=1;\n  bool red[n+1];\n  for(int i=0;i<n+1;i++) red[i]=false;\n  red[0]=true;\n  for(int i=0;i<m;i++){\n      int x,y;cin>>x>>y;\n      x--;y--;\n      ball[x]--;ball[y]++;\n      if(red[x]){\n          red[y]=true;\n      }\n      if(ball[x]==0) red[x]=false;\n  }\n  int res=0;\n  for(int i=0;i<n;i++) if(red[i]) res++;\n  cout<<res<<endl;\n}\n", "language": "C++", "metadata": {"date": 1491711458, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p04034.html", "problem_id": "p04034", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p04034/input.txt", "sample_output_relpath": "derived/input_output/data/p04034/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p04034/C++/s848766609.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s848766609", "user_id": "u968834127"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\nusing namespace std;\nint main(){\n  int n,m;cin>>n>>m;\n  int ball[n+1];\n  for(int i=0;i<n;i++) ball[i]=1;\n  bool red[n+1];\n  for(int i=0;i<n+1;i++) red[i]=false;\n  red[0]=true;\n  for(int i=0;i<m;i++){\n      int x,y;cin>>x>>y;\n      x--;y--;\n      ball[x]--;ball[y]++;\n      if(red[x]){\n          red[y]=true;\n      }\n      if(ball[x]==0) red[x]=false;\n  }\n  int res=0;\n  for(int i=0;i<n;i++) if(red[i]) res++;\n  cout<<res<<endl;\n}\n", "problem_context": "Problem Statement\n\nWe have N boxes, numbered 1 through N. At first, box 1 contains one red ball, and each of the other boxes contains one white ball.\n\nSnuke will perform the following M operations, one by one. In the i-th operation, he randomly picks one ball from box x_i, then he puts it into box y_i.\n\nFind the number of boxes that may contain the red ball after all operations are performed.\n\nConstraints\n\n2≤N≤10^5\n\n1≤M≤10^5\n\n1≤x_i,y_i≤N\n\nx_i≠y_i\n\nJust before the i-th operation is performed, box x_i contains at least 1 ball.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN M\nx_1 y_1\n:\nx_M y_M\n\nOutput\n\nPrint the number of boxes that may contain the red ball after all operations are performed.\n\nSample Input 1\n\n3 2\n1 2\n2 3\n\nSample Output 1\n\n2\n\nJust after the first operation, box 1 is empty, box 2 contains one red ball and one white ball, and box 3 contains one white ball.\n\nNow, consider the second operation. If Snuke picks the red ball from box 2, the red ball will go into box 3. If he picks the white ball instead, the red ball will stay in box 2.\nThus, the number of boxes that may contain the red ball after all operations, is 2.\n\nSample Input 2\n\n3 3\n1 2\n2 3\n2 3\n\nSample Output 2\n\n1\n\nAll balls will go into box 3.\n\nSample Input 3\n\n4 4\n1 2\n2 3\n4 1\n3 4\n\nSample Output 3\n\n3", "sample_input": "3 2\n1 2\n2 3\n"}, "reference_outputs": ["2\n"], "source_document_id": "p04034", "source_text": "Problem Statement\n\nWe have N boxes, numbered 1 through N. At first, box 1 contains one red ball, and each of the other boxes contains one white ball.\n\nSnuke will perform the following M operations, one by one. In the i-th operation, he randomly picks one ball from box x_i, then he puts it into box y_i.\n\nFind the number of boxes that may contain the red ball after all operations are performed.\n\nConstraints\n\n2≤N≤10^5\n\n1≤M≤10^5\n\n1≤x_i,y_i≤N\n\nx_i≠y_i\n\nJust before the i-th operation is performed, box x_i contains at least 1 ball.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN M\nx_1 y_1\n:\nx_M y_M\n\nOutput\n\nPrint the number of boxes that may contain the red ball after all operations are performed.\n\nSample Input 1\n\n3 2\n1 2\n2 3\n\nSample Output 1\n\n2\n\nJust after the first operation, box 1 is empty, box 2 contains one red ball and one white ball, and box 3 contains one white ball.\n\nNow, consider the second operation. If Snuke picks the red ball from box 2, the red ball will go into box 3. If he picks the white ball instead, the red ball will stay in box 2.\nThus, the number of boxes that may contain the red ball after all operations, is 2.\n\nSample Input 2\n\n3 3\n1 2\n2 3\n2 3\n\nSample Output 2\n\n1\n\nAll balls will go into box 3.\n\nSample Input 3\n\n4 4\n1 2\n2 3\n4 1\n3 4\n\nSample Output 3\n\n3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 455, "cpu_time_ms": 70, "memory_kb": 768}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s586645482", "group_id": "codeNet:p04034", "input_text": "//DPするけど、遷移を節約する. DPするとO(N^2)なんて思ったのが間違いだったorz\n\n#include <iostream>\nusing namespace std;\n\nint n, m;\nint x[100000], y[100000];\nbool dp[100000];\t//dp[i] = 箱iに赤いキャンディーがある状態(0, 1)\nint cnt[100000];\t//cnt[i] = 箱iにある飴の総数\n\nint main() {\n\tint i;\n\t\n\tcin >> n >> m;\n\tfor (i = 0; i < m; i++) { cin >> x[i] >> y[i]; x[i]--; y[i]--; }\n\t\n\tfor (i = 0; i < n; i++) { dp[i] = false; cnt[i] = 1; }\n\tdp[0] = true;\n\t\n\tfor (i = 0; i < m; i++) {\n\t\tif (!dp[x[i]]) { }\n\t\telse if (cnt[x[i]] == 1) { dp[x[i]] = false; dp[y[i]] = true; }\n\t\telse { dp[x[i]] = true; dp[y[i]] = true; }\n\t\tcnt[x[i]]--;\n\t\tcnt[y[i]]++;\n\t}\n\t\n\tint ans = 0;\n\tfor (i = 0; i < n; i++) {\n\t\tif (dp[i]) {\n\t\t\tans++;\n\t\t}\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1470018594, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p04034.html", "problem_id": "p04034", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p04034/input.txt", "sample_output_relpath": "derived/input_output/data/p04034/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p04034/C++/s586645482.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s586645482", "user_id": "u610441939"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "//DPするけど、遷移を節約する. DPするとO(N^2)なんて思ったのが間違いだったorz\n\n#include <iostream>\nusing namespace std;\n\nint n, m;\nint x[100000], y[100000];\nbool dp[100000];\t//dp[i] = 箱iに赤いキャンディーがある状態(0, 1)\nint cnt[100000];\t//cnt[i] = 箱iにある飴の総数\n\nint main() {\n\tint i;\n\t\n\tcin >> n >> m;\n\tfor (i = 0; i < m; i++) { cin >> x[i] >> y[i]; x[i]--; y[i]--; }\n\t\n\tfor (i = 0; i < n; i++) { dp[i] = false; cnt[i] = 1; }\n\tdp[0] = true;\n\t\n\tfor (i = 0; i < m; i++) {\n\t\tif (!dp[x[i]]) { }\n\t\telse if (cnt[x[i]] == 1) { dp[x[i]] = false; dp[y[i]] = true; }\n\t\telse { dp[x[i]] = true; dp[y[i]] = true; }\n\t\tcnt[x[i]]--;\n\t\tcnt[y[i]]++;\n\t}\n\t\n\tint ans = 0;\n\tfor (i = 0; i < n; i++) {\n\t\tif (dp[i]) {\n\t\t\tans++;\n\t\t}\n\t}\n\tcout << ans << endl;\n\treturn 0;\n}", "problem_context": "Problem Statement\n\nWe have N boxes, numbered 1 through N. At first, box 1 contains one red ball, and each of the other boxes contains one white ball.\n\nSnuke will perform the following M operations, one by one. In the i-th operation, he randomly picks one ball from box x_i, then he puts it into box y_i.\n\nFind the number of boxes that may contain the red ball after all operations are performed.\n\nConstraints\n\n2≤N≤10^5\n\n1≤M≤10^5\n\n1≤x_i,y_i≤N\n\nx_i≠y_i\n\nJust before the i-th operation is performed, box x_i contains at least 1 ball.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN M\nx_1 y_1\n:\nx_M y_M\n\nOutput\n\nPrint the number of boxes that may contain the red ball after all operations are performed.\n\nSample Input 1\n\n3 2\n1 2\n2 3\n\nSample Output 1\n\n2\n\nJust after the first operation, box 1 is empty, box 2 contains one red ball and one white ball, and box 3 contains one white ball.\n\nNow, consider the second operation. If Snuke picks the red ball from box 2, the red ball will go into box 3. If he picks the white ball instead, the red ball will stay in box 2.\nThus, the number of boxes that may contain the red ball after all operations, is 2.\n\nSample Input 2\n\n3 3\n1 2\n2 3\n2 3\n\nSample Output 2\n\n1\n\nAll balls will go into box 3.\n\nSample Input 3\n\n4 4\n1 2\n2 3\n4 1\n3 4\n\nSample Output 3\n\n3", "sample_input": "3 2\n1 2\n2 3\n"}, "reference_outputs": ["2\n"], "source_document_id": "p04034", "source_text": "Problem Statement\n\nWe have N boxes, numbered 1 through N. At first, box 1 contains one red ball, and each of the other boxes contains one white ball.\n\nSnuke will perform the following M operations, one by one. In the i-th operation, he randomly picks one ball from box x_i, then he puts it into box y_i.\n\nFind the number of boxes that may contain the red ball after all operations are performed.\n\nConstraints\n\n2≤N≤10^5\n\n1≤M≤10^5\n\n1≤x_i,y_i≤N\n\nx_i≠y_i\n\nJust before the i-th operation is performed, box x_i contains at least 1 ball.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN M\nx_1 y_1\n:\nx_M y_M\n\nOutput\n\nPrint the number of boxes that may contain the red ball after all operations are performed.\n\nSample Input 1\n\n3 2\n1 2\n2 3\n\nSample Output 1\n\n2\n\nJust after the first operation, box 1 is empty, box 2 contains one red ball and one white ball, and box 3 contains one white ball.\n\nNow, consider the second operation. If Snuke picks the red ball from box 2, the red ball will go into box 3. If he picks the white ball instead, the red ball will stay in box 2.\nThus, the number of boxes that may contain the red ball after all operations, is 2.\n\nSample Input 2\n\n3 3\n1 2\n2 3\n2 3\n\nSample Output 2\n\n1\n\nAll balls will go into box 3.\n\nSample Input 3\n\n4 4\n1 2\n2 3\n4 1\n3 4\n\nSample Output 3\n\n3", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 800, "cpu_time_ms": 119, "memory_kb": 1536}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s756557497", "group_id": "codeNet:p04040", "input_text": "#include <bits/stdc++.h>\n#include <ext/rope>\n#include <ext/pb_ds/assoc_container.hpp>\n#include <ext/pb_ds/tree_policy.hpp>\n#pragma GCC optimize(\"Ofast\")\n//#pragma GCC optimize(\"unroll-loops\")\n//#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n#define ll long long\n//#define int long long\n#define pb push_back\n#define x first\n#define ld long double\n#define y second\n#define mk(a,b) make_pair(a,b)\n#define rr return 0\n#define sqr(a) ((a)*(a))\n#define all(a) a.begin(),a.end()\n\nusing namespace std;\nusing namespace __gnu_cxx;\nusing namespace __gnu_pbds;\ntemplate<class value, class cmp = less<value> >\nusing ordered_set = tree<value, null_type, cmp, rb_tree_tag, tree_order_statistics_node_update>;\ntemplate<class value, class cmp = less_equal<value> >\nusing ordered_multiset = tree<value, null_type, cmp, rb_tree_tag, tree_order_statistics_node_update>;\ntemplate<class key, class value, class cmp = less<key> >\nusing ordered_map = tree<key, value, cmp, rb_tree_tag, tree_order_statistics_node_update>;\n\n/// find_by_order()\n/// order_of_key()\nmt19937 rng(chrono::steady_clock::now().time_since_epoch().count());\ninline int randll(int l = INT_MIN, int r = INT_MAX) {\n    return uniform_int_distribution<int>(l, r)(rng);\n}\nconst int MOD = 1e9 + 7;\ninline int mul (int a, int b) {\n    return ((ll)a * b) % MOD;\n}\ninline void add (int &a, int x) {\n    a += x;\n    if (a < 0) a += MOD;\n    if (a >= MOD) a -= MOD;\n}\ninline int binpow (int a, int n) {\n    int ans = 1;\n    while (n) {\n        if (n & 1) {\n            ans = mul(ans, a);\n        }\n        a = mul(a, a);\n        n >>= 1;\n    }\n    return ans;\n}\ninline int inv (int x) {\n    return binpow(x, MOD - 2);\n}\nconst int N = 2e5 + 11;\nint f[N] = {}, fi[N] = {};\ninline int C (int n, int k) {\n    return mul(f[n], mul(fi[k], fi[n - k]));\n}\ninline int cnt_way (int n, int m) {\n    return C(n + m - 2, n - 1);\n}\nmain()\n{\n    ios::sync_with_stdio(0);\n    ios_base::sync_with_stdio(0);\n    cin.tie(0);\n    cout.tie(0);\n    f[0] = 1;\n    for (int i = 1; i < N; i++) f[i] = mul(f[i - 1], i);\n    fi[N - 1] = inv(f[N - 1]);\n    for (int i = N - 2; i >= 0; i--) {\n        fi[i] = mul(fi[i + 1], i + 1);\n    }\n    int n, m, a, b, ans = 0;\n    cin >> n >> m >> a >> b;\n    for (int i = 0; i < n - a; i++) {\n        add(ans, mul(cnt_way(i + 1, b), cnt_way(n - i, m - b)));\n    }\n    cout << ans << '\\n';\n}\n", "language": "C++", "metadata": {"date": 1578178387, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p04040.html", "problem_id": "p04040", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p04040/input.txt", "sample_output_relpath": "derived/input_output/data/p04040/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p04040/C++/s756557497.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s756557497", "user_id": "u423778821"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include <bits/stdc++.h>\n#include <ext/rope>\n#include <ext/pb_ds/assoc_container.hpp>\n#include <ext/pb_ds/tree_policy.hpp>\n#pragma GCC optimize(\"Ofast\")\n//#pragma GCC optimize(\"unroll-loops\")\n//#pragma GCC target(\"sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native\")\n#define ll long long\n//#define int long long\n#define pb push_back\n#define x first\n#define ld long double\n#define y second\n#define mk(a,b) make_pair(a,b)\n#define rr return 0\n#define sqr(a) ((a)*(a))\n#define all(a) a.begin(),a.end()\n\nusing namespace std;\nusing namespace __gnu_cxx;\nusing namespace __gnu_pbds;\ntemplate<class value, class cmp = less<value> >\nusing ordered_set = tree<value, null_type, cmp, rb_tree_tag, tree_order_statistics_node_update>;\ntemplate<class value, class cmp = less_equal<value> >\nusing ordered_multiset = tree<value, null_type, cmp, rb_tree_tag, tree_order_statistics_node_update>;\ntemplate<class key, class value, class cmp = less<key> >\nusing ordered_map = tree<key, value, cmp, rb_tree_tag, tree_order_statistics_node_update>;\n\n/// find_by_order()\n/// order_of_key()\nmt19937 rng(chrono::steady_clock::now().time_since_epoch().count());\ninline int randll(int l = INT_MIN, int r = INT_MAX) {\n    return uniform_int_distribution<int>(l, r)(rng);\n}\nconst int MOD = 1e9 + 7;\ninline int mul (int a, int b) {\n    return ((ll)a * b) % MOD;\n}\ninline void add (int &a, int x) {\n    a += x;\n    if (a < 0) a += MOD;\n    if (a >= MOD) a -= MOD;\n}\ninline int binpow (int a, int n) {\n    int ans = 1;\n    while (n) {\n        if (n & 1) {\n            ans = mul(ans, a);\n        }\n        a = mul(a, a);\n        n >>= 1;\n    }\n    return ans;\n}\ninline int inv (int x) {\n    return binpow(x, MOD - 2);\n}\nconst int N = 2e5 + 11;\nint f[N] = {}, fi[N] = {};\ninline int C (int n, int k) {\n    return mul(f[n], mul(fi[k], fi[n - k]));\n}\ninline int cnt_way (int n, int m) {\n    return C(n + m - 2, n - 1);\n}\nmain()\n{\n    ios::sync_with_stdio(0);\n    ios_base::sync_with_stdio(0);\n    cin.tie(0);\n    cout.tie(0);\n    f[0] = 1;\n    for (int i = 1; i < N; i++) f[i] = mul(f[i - 1], i);\n    fi[N - 1] = inv(f[N - 1]);\n    for (int i = N - 2; i >= 0; i--) {\n        fi[i] = mul(fi[i + 1], i + 1);\n    }\n    int n, m, a, b, ans = 0;\n    cin >> n >> m >> a >> b;\n    for (int i = 0; i < n - a; i++) {\n        add(ans, mul(cnt_way(i + 1, b), cnt_way(n - i, m - b)));\n    }\n    cout << ans << '\\n';\n}\n", "problem_context": "Score : 400 points\n\nProblem Statement\n\nWe have a large square grid with H rows and W columns.\nIroha is now standing in the top-left cell.\nShe will repeat going right or down to the adjacent cell, until she reaches the bottom-right cell.\n\nHowever, she cannot enter the cells in the intersection of the bottom A rows and the leftmost B columns. (That is, there are A×B forbidden cells.) There is no restriction on entering the other cells.\n\nFind the number of ways she can travel to the bottom-right cell.\n\nSince this number can be extremely large, print the number modulo 10^9+7.\n\nConstraints\n\n1 ≦ H, W ≦ 100,000\n\n1 ≦ A < H\n\n1 ≦ B < W\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nH W A B\n\nOutput\n\nPrint the number of ways she can travel to the bottom-right cell, modulo 10^9+7.\n\nSample Input 1\n\n2 3 1 1\n\nSample Output 1\n\n2\n\nWe have a 2×3 grid, but entering the bottom-left cell is forbidden. The number of ways to travel is two: \"Right, Right, Down\" and \"Right, Down, Right\".\n\nSample Input 2\n\n10 7 3 4\n\nSample Output 2\n\n3570\n\nThere are 12 forbidden cells.\n\nSample Input 3\n\n100000 100000 99999 99999\n\nSample Output 3\n\n1\n\nSample Input 4\n\n100000 100000 44444 55555\n\nSample Output 4\n\n738162020", "sample_input": "2 3 1 1\n"}, "reference_outputs": ["2\n"], "source_document_id": "p04040", "source_text": "Score : 400 points\n\nProblem Statement\n\nWe have a large square grid with H rows and W columns.\nIroha is now standing in the top-left cell.\nShe will repeat going right or down to the adjacent cell, until she reaches the bottom-right cell.\n\nHowever, she cannot enter the cells in the intersection of the bottom A rows and the leftmost B columns. (That is, there are A×B forbidden cells.) There is no restriction on entering the other cells.\n\nFind the number of ways she can travel to the bottom-right cell.\n\nSince this number can be extremely large, print the number modulo 10^9+7.\n\nConstraints\n\n1 ≦ H, W ≦ 100,000\n\n1 ≦ A < H\n\n1 ≦ B < W\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nH W A B\n\nOutput\n\nPrint the number of ways she can travel to the bottom-right cell, modulo 10^9+7.\n\nSample Input 1\n\n2 3 1 1\n\nSample Output 1\n\n2\n\nWe have a 2×3 grid, but entering the bottom-left cell is forbidden. The number of ways to travel is two: \"Right, Right, Down\" and \"Right, Down, Right\".\n\nSample Input 2\n\n10 7 3 4\n\nSample Output 2\n\n3570\n\nThere are 12 forbidden cells.\n\nSample Input 3\n\n100000 100000 99999 99999\n\nSample Output 3\n\n1\n\nSample Input 4\n\n100000 100000 44444 55555\n\nSample Output 4\n\n738162020", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 2372, "cpu_time_ms": 5, "memory_kb": 1792}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s580970189", "group_id": "codeNet:p04040", "input_text": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nconst int N=2e5+10,p=1e9+7;\nint inc(int x,int y){x+=y;return x>=p?x-p:x;}\nint mul(int x,int y){return (ll)x*y%p;}\nint power(int x,int y){\n\tint ans=1;\n\tfor (;y;y>>=1,x=mul(x,x))\n\t\tif (y&1) ans=mul(ans,x);\n\treturn ans;\n}\nint n,m,a,b,fac[N],ifac[N];\nint C(int n,int m){\n\treturn mul(fac[n],mul(ifac[m],ifac[n-m]));\n}\nint main()\n{\n\tcin>>n>>m>>a>>b;\n\tfac[0]=1;\n\tfor (int i=1;i<N;i++) fac[i]=mul(fac[i-1],i);\n\tifac[N-1]=power(fac[N-1],p-2);\n\tfor (int i=N-1;i;i--) ifac[i-1]=mul(ifac[i],i);\n\tint ans=0;\n\tfor (int i=b+1;i<=m;i++) ans=inc(ans,mul(C(n-a+i-2,n-a-1),C(a-1+m-i,a-1)));\n\tcout<<ans<<endl;\n\treturn 0;\n}", "language": "C++", "metadata": {"date": 1507584136, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p04040.html", "problem_id": "p04040", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p04040/input.txt", "sample_output_relpath": "derived/input_output/data/p04040/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p04040/C++/s580970189.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s580970189", "user_id": "u719378199"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "#include<bits/stdc++.h>\nusing namespace std;\ntypedef long long ll;\nconst int N=2e5+10,p=1e9+7;\nint inc(int x,int y){x+=y;return x>=p?x-p:x;}\nint mul(int x,int y){return (ll)x*y%p;}\nint power(int x,int y){\n\tint ans=1;\n\tfor (;y;y>>=1,x=mul(x,x))\n\t\tif (y&1) ans=mul(ans,x);\n\treturn ans;\n}\nint n,m,a,b,fac[N],ifac[N];\nint C(int n,int m){\n\treturn mul(fac[n],mul(ifac[m],ifac[n-m]));\n}\nint main()\n{\n\tcin>>n>>m>>a>>b;\n\tfac[0]=1;\n\tfor (int i=1;i<N;i++) fac[i]=mul(fac[i-1],i);\n\tifac[N-1]=power(fac[N-1],p-2);\n\tfor (int i=N-1;i;i--) ifac[i-1]=mul(ifac[i],i);\n\tint ans=0;\n\tfor (int i=b+1;i<=m;i++) ans=inc(ans,mul(C(n-a+i-2,n-a-1),C(a-1+m-i,a-1)));\n\tcout<<ans<<endl;\n\treturn 0;\n}", "problem_context": "Score : 400 points\n\nProblem Statement\n\nWe have a large square grid with H rows and W columns.\nIroha is now standing in the top-left cell.\nShe will repeat going right or down to the adjacent cell, until she reaches the bottom-right cell.\n\nHowever, she cannot enter the cells in the intersection of the bottom A rows and the leftmost B columns. (That is, there are A×B forbidden cells.) There is no restriction on entering the other cells.\n\nFind the number of ways she can travel to the bottom-right cell.\n\nSince this number can be extremely large, print the number modulo 10^9+7.\n\nConstraints\n\n1 ≦ H, W ≦ 100,000\n\n1 ≦ A < H\n\n1 ≦ B < W\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nH W A B\n\nOutput\n\nPrint the number of ways she can travel to the bottom-right cell, modulo 10^9+7.\n\nSample Input 1\n\n2 3 1 1\n\nSample Output 1\n\n2\n\nWe have a 2×3 grid, but entering the bottom-left cell is forbidden. The number of ways to travel is two: \"Right, Right, Down\" and \"Right, Down, Right\".\n\nSample Input 2\n\n10 7 3 4\n\nSample Output 2\n\n3570\n\nThere are 12 forbidden cells.\n\nSample Input 3\n\n100000 100000 99999 99999\n\nSample Output 3\n\n1\n\nSample Input 4\n\n100000 100000 44444 55555\n\nSample Output 4\n\n738162020", "sample_input": "2 3 1 1\n"}, "reference_outputs": ["2\n"], "source_document_id": "p04040", "source_text": "Score : 400 points\n\nProblem Statement\n\nWe have a large square grid with H rows and W columns.\nIroha is now standing in the top-left cell.\nShe will repeat going right or down to the adjacent cell, until she reaches the bottom-right cell.\n\nHowever, she cannot enter the cells in the intersection of the bottom A rows and the leftmost B columns. (That is, there are A×B forbidden cells.) There is no restriction on entering the other cells.\n\nFind the number of ways she can travel to the bottom-right cell.\n\nSince this number can be extremely large, print the number modulo 10^9+7.\n\nConstraints\n\n1 ≦ H, W ≦ 100,000\n\n1 ≦ A < H\n\n1 ≦ B < W\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nH W A B\n\nOutput\n\nPrint the number of ways she can travel to the bottom-right cell, modulo 10^9+7.\n\nSample Input 1\n\n2 3 1 1\n\nSample Output 1\n\n2\n\nWe have a 2×3 grid, but entering the bottom-left cell is forbidden. The number of ways to travel is two: \"Right, Right, Down\" and \"Right, Down, Right\".\n\nSample Input 2\n\n10 7 3 4\n\nSample Output 2\n\n3570\n\nThere are 12 forbidden cells.\n\nSample Input 3\n\n100000 100000 99999 99999\n\nSample Output 3\n\n1\n\nSample Input 4\n\n100000 100000 44444 55555\n\nSample Output 4\n\n738162020", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 669, "cpu_time_ms": 5, "memory_kb": 1792}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s449702754", "group_id": "codeNet:p04047", "input_text": "#include<cstdio>\n#include<algorithm>\n#include<iostream>\n#include<queue>\n#include<set>\n#define rep(i,s,t) for(register int i=s;i<=t;++i)\n#define _rep(i,s,t) for(register int i=s;i>=t;--i)\n#define Rep(i,s,t) for(register int i=s;i<t;++i)\n#define go(x) for(register int e=las[x];e;e=nxt[e])\n#define re register\n#define fi first\n#define se second\n#define mp make_pair\n#define pb push_back\n#define pii pair<int,int>\n#define gi(x) read(x)\n#define gii(x,y) read(x),read(y)\n#define giii(x,y,z) read(x),read(y),read(z)\n#define ms(f,x) memset(f,x,sizeof f)\n#define open(x) freopen(#x\".in\",\"r\",stdin),freopen(#x\".out\",\"w\",stdout)\nnamespace IO{\n    #define gc getchar()\n    #define pc(x) putchar(x)\n    template<typename T>inline void read(T &x){\n        x=0;int f=1;char ch=gc;while(ch>'9'||ch<'0'){if(ch=='-')f=-1;ch=gc;}\n        while(ch>='0'&&ch<='9')x=(x<<3)+(x<<1)+ch-'0',ch=gc;x*=f;return;\n    }\n    template<typename T>inline void write(T x=0){\n        T wr[51];wr[0]=0;if(x<0)pc('-'),x=-x;if(!x)pc(48);\n        while(x)wr[++wr[0]]=x%10,x/=10;while(wr[0])pc(48+wr[wr[0]--]);\n\t\tputchar('\\n');\n\t\treturn;\n    }\n}\nusing IO::read;\nusing IO::write;\nusing namespace std;\n#define gi(x) read(x)\nint a[233333];\nlong long sum;\nint n;\nint main(){\n    gi(n);\n    rep(i,1,n+n)\n        gi(a[i]);\n    sort(a+1,a+n+n+1);\n    for(int i=1;i<=n+n;i+=2)\n        sum+=a[i];\n    cout<<sum<<endl;\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1543195756, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p04047.html", "problem_id": "p04047", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p04047/input.txt", "sample_output_relpath": "derived/input_output/data/p04047/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p04047/C++/s449702754.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s449702754", "user_id": "u816631826"}, "prompt_components": {"gold_output": "3\n", "input_to_evaluate": "#include<cstdio>\n#include<algorithm>\n#include<iostream>\n#include<queue>\n#include<set>\n#define rep(i,s,t) for(register int i=s;i<=t;++i)\n#define _rep(i,s,t) for(register int i=s;i>=t;--i)\n#define Rep(i,s,t) for(register int i=s;i<t;++i)\n#define go(x) for(register int e=las[x];e;e=nxt[e])\n#define re register\n#define fi first\n#define se second\n#define mp make_pair\n#define pb push_back\n#define pii pair<int,int>\n#define gi(x) read(x)\n#define gii(x,y) read(x),read(y)\n#define giii(x,y,z) read(x),read(y),read(z)\n#define ms(f,x) memset(f,x,sizeof f)\n#define open(x) freopen(#x\".in\",\"r\",stdin),freopen(#x\".out\",\"w\",stdout)\nnamespace IO{\n    #define gc getchar()\n    #define pc(x) putchar(x)\n    template<typename T>inline void read(T &x){\n        x=0;int f=1;char ch=gc;while(ch>'9'||ch<'0'){if(ch=='-')f=-1;ch=gc;}\n        while(ch>='0'&&ch<='9')x=(x<<3)+(x<<1)+ch-'0',ch=gc;x*=f;return;\n    }\n    template<typename T>inline void write(T x=0){\n        T wr[51];wr[0]=0;if(x<0)pc('-'),x=-x;if(!x)pc(48);\n        while(x)wr[++wr[0]]=x%10,x/=10;while(wr[0])pc(48+wr[wr[0]--]);\n\t\tputchar('\\n');\n\t\treturn;\n    }\n}\nusing IO::read;\nusing IO::write;\nusing namespace std;\n#define gi(x) read(x)\nint a[233333];\nlong long sum;\nint n;\nint main(){\n    gi(n);\n    rep(i,1,n+n)\n        gi(a[i]);\n    sort(a+1,a+n+n+1);\n    for(int i=1;i<=n+n;i+=2)\n        sum+=a[i];\n    cout<<sum<<endl;\n    return 0;\n}\n", "problem_context": "Score : 200 points\n\nProblem Statement\n\nSnuke is having a barbeque party.\n\nAt the party, he will make N servings of Skewer Meal.\n\nExample of a serving of Skewer Meal\n\nHe has a stock of 2N skewers, all of which will be used in Skewer Meal. The length of the i-th skewer is L_i.\nAlso, he has an infinite supply of ingredients.\n\nTo make a serving of Skewer Meal, he picks 2 skewers and threads ingredients onto those skewers.\nLet the length of the shorter skewer be x, then the serving can hold the maximum of x ingredients.\n\nWhat is the maximum total number of ingredients that his N servings of Skewer Meal can hold, if he uses the skewers optimally?\n\nConstraints\n\n1≦N≦100\n\n1≦L_i≦100\n\nFor each i, L_i is an integer.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nL_1 L_2 ... L_{2N}\n\nOutput\n\nPrint the maximum total number of ingredients that Snuke's N servings of Skewer Meal can hold.\n\nSample Input 1\n\n2\n1 3 1 2\n\nSample Output 1\n\n3\n\nIf he makes a serving using the first and third skewers, and another using the second and fourth skewers, each serving will hold 1 and 2 ingredients, for the total of 3.\n\nSample Input 2\n\n5\n100 1 2 3 14 15 58 58 58 29\n\nSample Output 2\n\n135", "sample_input": "2\n1 3 1 2\n"}, "reference_outputs": ["3\n"], "source_document_id": "p04047", "source_text": "Score : 200 points\n\nProblem Statement\n\nSnuke is having a barbeque party.\n\nAt the party, he will make N servings of Skewer Meal.\n\nExample of a serving of Skewer Meal\n\nHe has a stock of 2N skewers, all of which will be used in Skewer Meal. The length of the i-th skewer is L_i.\nAlso, he has an infinite supply of ingredients.\n\nTo make a serving of Skewer Meal, he picks 2 skewers and threads ingredients onto those skewers.\nLet the length of the shorter skewer be x, then the serving can hold the maximum of x ingredients.\n\nWhat is the maximum total number of ingredients that his N servings of Skewer Meal can hold, if he uses the skewers optimally?\n\nConstraints\n\n1≦N≦100\n\n1≦L_i≦100\n\nFor each i, L_i is an integer.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN\nL_1 L_2 ... L_{2N}\n\nOutput\n\nPrint the maximum total number of ingredients that Snuke's N servings of Skewer Meal can hold.\n\nSample Input 1\n\n2\n1 3 1 2\n\nSample Output 1\n\n3\n\nIf he makes a serving using the first and third skewers, and another using the second and fourth skewers, each serving will hold 1 and 2 ingredients, for the total of 3.\n\nSample Input 2\n\n5\n100 1 2 3 14 15 58 58 58 29\n\nSample Output 2\n\n135", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1385, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s282391560", "group_id": "codeNet:p04049", "input_text": "// luogu-judger-enable-o2\n#include <iostream>\n#include <cstdio>\n#include <cstring>\n#include <algorithm>\n#define ez(i,x) for(int i = h[x]; i; i = e[i].next)\nusing namespace std;\nconst int N = 2005;\nint h[N], dis[N], vis[N];\nint fa[N];\nint n, cnt, k;\nint ans;\nstruct edge{\n\tint from,to, next;\n}e[N<<1];\n\nvoid add(int u, int v) {\n\te[++cnt] = (edge){u, v, h[u]}; h[u] = cnt;\n\te[++cnt] = (edge){v, u, h[v]}; h[v] = cnt;\n}\n\nvoid dfs(int x){\n\tez(i,x) {\n\t\tint v = e[i].to;\n\t\tif (dis[v]) continue;\n\t\tdis[v] = dis[x] + 1;\n\t\tdfs(v);\n\t}\n}\nint main() {\n\tscanf(\"%d %d\", &n, &k);\n\tfor (int i = 1; i < n; i++) {\n\t\tint u, v;\n\t\tscanf(\"%d %d\", &u, &v);\n\t\tadd(u, v);\n\t}\n\tans = 0x7fffffff;\n\tif (k & 1){\n\t\tfor (int i = 1; i <= n; i += 2) {\n\t\t\tint u = e[i].from, v = e[i].to;\n\t\t\tmemset(dis, 0, sizeof(dis));\n\t\t\tdis[v] = 1; dis[u] = 1;\n\t\t\tdfs(v); dfs(u);\n\t\t\tcnt = 0;\n\t\t\tfor (int i = 1; i <= n; i++) if (dis[i] > (k + 1) / 2) ++cnt;\n\t\t\tans = min(ans, cnt);\n\t\t}\n\t}\n\telse {\n\t\tfor (int i = 1; i <= n; i++) {\n\t\t\tmemset(dis, 0, sizeof(dis));\n\t\t\tdis[i] = 1;\n\t\t\tdfs(i);\n\t\t\tcnt = 0;\n\t\t\tfor (int i = 1; i <= n; i++) if (dis[i] > k / 2 + 1) ++cnt ;\n\t\t\tans = min(ans, cnt);\n\t\t}\n\n\t}\n\tcout << ans << endl;\n\n\n}\n", "language": "C++", "metadata": {"date": 1567992426, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p04049.html", "problem_id": "p04049", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p04049/input.txt", "sample_output_relpath": "derived/input_output/data/p04049/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p04049/C++/s282391560.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Accepted", "submission_id": "s282391560", "user_id": "u247366051"}, "prompt_components": {"gold_output": "2\n", "input_to_evaluate": "// luogu-judger-enable-o2\n#include <iostream>\n#include <cstdio>\n#include <cstring>\n#include <algorithm>\n#define ez(i,x) for(int i = h[x]; i; i = e[i].next)\nusing namespace std;\nconst int N = 2005;\nint h[N], dis[N], vis[N];\nint fa[N];\nint n, cnt, k;\nint ans;\nstruct edge{\n\tint from,to, next;\n}e[N<<1];\n\nvoid add(int u, int v) {\n\te[++cnt] = (edge){u, v, h[u]}; h[u] = cnt;\n\te[++cnt] = (edge){v, u, h[v]}; h[v] = cnt;\n}\n\nvoid dfs(int x){\n\tez(i,x) {\n\t\tint v = e[i].to;\n\t\tif (dis[v]) continue;\n\t\tdis[v] = dis[x] + 1;\n\t\tdfs(v);\n\t}\n}\nint main() {\n\tscanf(\"%d %d\", &n, &k);\n\tfor (int i = 1; i < n; i++) {\n\t\tint u, v;\n\t\tscanf(\"%d %d\", &u, &v);\n\t\tadd(u, v);\n\t}\n\tans = 0x7fffffff;\n\tif (k & 1){\n\t\tfor (int i = 1; i <= n; i += 2) {\n\t\t\tint u = e[i].from, v = e[i].to;\n\t\t\tmemset(dis, 0, sizeof(dis));\n\t\t\tdis[v] = 1; dis[u] = 1;\n\t\t\tdfs(v); dfs(u);\n\t\t\tcnt = 0;\n\t\t\tfor (int i = 1; i <= n; i++) if (dis[i] > (k + 1) / 2) ++cnt;\n\t\t\tans = min(ans, cnt);\n\t\t}\n\t}\n\telse {\n\t\tfor (int i = 1; i <= n; i++) {\n\t\t\tmemset(dis, 0, sizeof(dis));\n\t\t\tdis[i] = 1;\n\t\t\tdfs(i);\n\t\t\tcnt = 0;\n\t\t\tfor (int i = 1; i <= n; i++) if (dis[i] > k / 2 + 1) ++cnt ;\n\t\t\tans = min(ans, cnt);\n\t\t}\n\n\t}\n\tcout << ans << endl;\n\n\n}\n", "problem_context": "Score : 600 points\n\nProblem Statement\n\nGiven an undirected tree, let the distance between vertices u and v be the\nnumber of edges on the simple path from u to v.\nThe diameter of a tree is the maximum among the distances between any two vertices.\nWe will call a tree good if and only if its diameter is at most K.\n\nYou are given an undirected tree with N vertices numbered 1 through N.\nFor each i (1≦i≦N-1), there is an edge connecting vertices A_i and B_i.\n\nYou want to remove zero or more vertices from the tree, so that the resulting tree is good.\nWhen a vertex is removed, all incident edges will also be removed.\nThe resulting graph must be connected.\n\nFind the minimum number of vertices that you need to remove in order to produce a good tree.\n\nConstraints\n\n2≦N≦2000\n\n1≦K≦N-1\n\n1≦A_i≦N, 1≦B_i≦N\n\nThe graph defined by A_i and B_i is a tree.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN K\nA_1 B_1\nA_2 B_2\n:\nA_{N-1} B_{N-1}\n\nOutput\n\nPrint the minimum number of vertices that you need to remove in order to produce a good tree.\n\nSample Input 1\n\n6 2\n1 2\n3 2\n4 2\n1 6\n5 6\n\nSample Output 1\n\n2\n\nThe tree is shown below. Removing vertices 5 and 6 will result in a good tree with the diameter of 2.\n\nSample Input 2\n\n6 5\n1 2\n3 2\n4 2\n1 6\n5 6\n\nSample Output 2\n\n0\n\nSince the given tree is already good, you do not need to remove any vertex.", "sample_input": "6 2\n1 2\n3 2\n4 2\n1 6\n5 6\n"}, "reference_outputs": ["2\n"], "source_document_id": "p04049", "source_text": "Score : 600 points\n\nProblem Statement\n\nGiven an undirected tree, let the distance between vertices u and v be the\nnumber of edges on the simple path from u to v.\nThe diameter of a tree is the maximum among the distances between any two vertices.\nWe will call a tree good if and only if its diameter is at most K.\n\nYou are given an undirected tree with N vertices numbered 1 through N.\nFor each i (1≦i≦N-1), there is an edge connecting vertices A_i and B_i.\n\nYou want to remove zero or more vertices from the tree, so that the resulting tree is good.\nWhen a vertex is removed, all incident edges will also be removed.\nThe resulting graph must be connected.\n\nFind the minimum number of vertices that you need to remove in order to produce a good tree.\n\nConstraints\n\n2≦N≦2000\n\n1≦K≦N-1\n\n1≦A_i≦N, 1≦B_i≦N\n\nThe graph defined by A_i and B_i is a tree.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN K\nA_1 B_1\nA_2 B_2\n:\nA_{N-1} B_{N-1}\n\nOutput\n\nPrint the minimum number of vertices that you need to remove in order to produce a good tree.\n\nSample Input 1\n\n6 2\n1 2\n3 2\n4 2\n1 6\n5 6\n\nSample Output 1\n\n2\n\nThe tree is shown below. Removing vertices 5 and 6 will result in a good tree with the diameter of 2.\n\nSample Input 2\n\n6 5\n1 2\n3 2\n4 2\n1 6\n5 6\n\nSample Output 2\n\n0\n\nSince the given tree is already good, you do not need to remove any vertex.", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 1172, "cpu_time_ms": 65, "memory_kb": 384}, "variant": "high_resource"}
+{"dataset": "codeNet", "domain": "code_generation", "example_id": "codeNet:C++:s417436415", "group_id": "codeNet:p04050", "input_text": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n//#define FILE_IO\n\nint main()\n{\n    #ifdef FILE_IO\n    freopen(\"1.in\", \"r\", stdin);\n    freopen(\"1.out\", \"w\", stdout);\n    #endif\n\n    int N, M;\n    int v[100005];\n    scanf(\"%d%d\", &N, &M);\n    int cnt = 0;\n    for(int i = 1; i <= M; i++)\n    {\n        scanf(\"%d\", &v[i]);\n        cnt += (v[i] & 1);\n    }\n    if(cnt > 1)\n    {\n        printf(\"Impossible\\n\");\n        return 0;\n    }\n\n    for(int i = 1; i <= M; i++)\n        printf(\"%d \", v[i]);\n    printf(\"\\n\");\n\n    vector <int> r;\n    r.push_back(v[1] - 1);\n    for(int i = 2; i < M; i++)\n        r.push_back(v[i]);\n    r.push_back(v[M] + 1);\n\n    if(M == 1)\n    {\n        r.pop_back();\n        r.push_back(1);\n    }\n    if(r[0] == 0)\n        r.erase(r.begin());\n\n    printf(\"%d\\n\", (int)r.size());\n    for(auto x: r)\n        printf(\"%d \", x);\n\n\n    return 0;\n}\n", "language": "C++", "metadata": {"date": 1491270637, "filename_ext": "cpp", "original_language": "C++14 (GCC 5.4.1)", "problem_description_relpath": "problem_descriptions/p04050.html", "problem_id": "p04050", "resource_group": "high_resource", "sample_input_relpath": "derived/input_output/data/p04050/input.txt", "sample_output_relpath": "derived/input_output/data/p04050/output.txt", "source_dataset": "Project CodeNet", "source_relpath": "data/p04050/C++/s417436415.cpp", "split_policy": "Global OOD problem IDs are disjoint from train, validation, and in-distribution test problem IDs.", "status": "Wrong Answer", "submission_id": "s417436415", "user_id": "u533606242"}, "prompt_components": {"gold_output": "1 2\n1\n3\n", "input_to_evaluate": "#include <bits/stdc++.h>\n\nusing namespace std;\n\n//#define FILE_IO\n\nint main()\n{\n    #ifdef FILE_IO\n    freopen(\"1.in\", \"r\", stdin);\n    freopen(\"1.out\", \"w\", stdout);\n    #endif\n\n    int N, M;\n    int v[100005];\n    scanf(\"%d%d\", &N, &M);\n    int cnt = 0;\n    for(int i = 1; i <= M; i++)\n    {\n        scanf(\"%d\", &v[i]);\n        cnt += (v[i] & 1);\n    }\n    if(cnt > 1)\n    {\n        printf(\"Impossible\\n\");\n        return 0;\n    }\n\n    for(int i = 1; i <= M; i++)\n        printf(\"%d \", v[i]);\n    printf(\"\\n\");\n\n    vector <int> r;\n    r.push_back(v[1] - 1);\n    for(int i = 2; i < M; i++)\n        r.push_back(v[i]);\n    r.push_back(v[M] + 1);\n\n    if(M == 1)\n    {\n        r.pop_back();\n        r.push_back(1);\n    }\n    if(r[0] == 0)\n        r.erase(r.begin());\n\n    printf(\"%d\\n\", (int)r.size());\n    for(auto x: r)\n        printf(\"%d \", x);\n\n\n    return 0;\n}\n", "problem_context": "Score : 1000 points\n\nProblem Statement\n\nSnuke got a present from his mother on his birthday.\nThe present was a pair of two sequences a and b, consisting of positive integers.\nThey satisfied all of the following properties:\n\nThe sum of all elements of a is N.\n\nThe sum of all elements of b is N.\n\nAny string of length N that satisfies the following two conditions (1) and (2) will also satisfy the condition (3).\n\n(1) Any of the following forms a palindrome: the first a_1 letters, the following a_2 letters, the following a_3 letters and so on.\n\n(2) Any of the following forms a palindrome: the first b_1 letters, the following b_2 letters, the following b_3 letters and so on.\n\n(3) All N letters are the same.\n\nHe was happy, until one day he lost both of the sequences.\nNow, he only remembers that the sequence a was a permutation of another sequence A of length M.\n\nTo bring him happiness again, his mother has decided to give him another pair of sequences a and b that satisfies his favorite properties and is consistent with his memory.\n\nConstraints\n\n1≦N≦10^5\n\n1≦M≦100\n\n1≦A_i≦10^5\n\nThe sum of all A_i equals N.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN M\nA_1 A_2 ... A_M\n\nOutput\n\nIf there exists a pair of sequences a and b that satisfies the properties and is consistent with Snuke's memory, print three lines. The first line must contain the sequence a, the second line must contain the length of the sequence b, and the third line must contain the sequence b.\n\nIf such a pair does not exist (because Snuke's memory is wrong or some other reason), print a single line containing the word Impossible (case-sensitive).\n\nSample Input 1\n\n3 2\n2 1\n\nSample Output 1\n\n1 2\n1\n3\n\nSample Input 2\n\n6 1\n6\n\nSample Output 2\n\n6\n3\n1 2 3\n\nSample Input 3\n\n55 10\n1 2 3 4 5 6 7 8 9 10\n\nSample Output 3\n\nImpossible", "sample_input": "3 2\n2 1\n"}, "reference_outputs": ["1 2\n1\n3\n"], "source_document_id": "p04050", "source_text": "Score : 1000 points\n\nProblem Statement\n\nSnuke got a present from his mother on his birthday.\nThe present was a pair of two sequences a and b, consisting of positive integers.\nThey satisfied all of the following properties:\n\nThe sum of all elements of a is N.\n\nThe sum of all elements of b is N.\n\nAny string of length N that satisfies the following two conditions (1) and (2) will also satisfy the condition (3).\n\n(1) Any of the following forms a palindrome: the first a_1 letters, the following a_2 letters, the following a_3 letters and so on.\n\n(2) Any of the following forms a palindrome: the first b_1 letters, the following b_2 letters, the following b_3 letters and so on.\n\n(3) All N letters are the same.\n\nHe was happy, until one day he lost both of the sequences.\nNow, he only remembers that the sequence a was a permutation of another sequence A of length M.\n\nTo bring him happiness again, his mother has decided to give him another pair of sequences a and b that satisfies his favorite properties and is consistent with his memory.\n\nConstraints\n\n1≦N≦10^5\n\n1≦M≦100\n\n1≦A_i≦10^5\n\nThe sum of all A_i equals N.\n\nInput\n\nThe input is given from Standard Input in the following format:\n\nN M\nA_1 A_2 ... A_M\n\nOutput\n\nIf there exists a pair of sequences a and b that satisfies the properties and is consistent with Snuke's memory, print three lines. The first line must contain the sequence a, the second line must contain the length of the sequence b, and the third line must contain the sequence b.\n\nIf such a pair does not exist (because Snuke's memory is wrong or some other reason), print a single line containing the word Impossible (case-sensitive).\n\nSample Input 1\n\n3 2\n2 1\n\nSample Output 1\n\n1 2\n1\n3\n\nSample Input 2\n\n6 1\n6\n\nSample Output 2\n\n6\n3\n1 2 3\n\nSample Input 3\n\n55 10\n1 2 3 4 5 6 7 8 9 10\n\nSample Output 3\n\nImpossible", "split": "test_in_distribution", "target_descriptions": {"code_size_bytes": "Submitted source-code file size, in bytes.", "cpu_time_ms": "Execution CPU time reported by official Project CodeNet metadata, in milliseconds.", "memory_kb": "Peak memory usage reported by official Project CodeNet metadata, in kilobytes."}, "targets": {"code_size_bytes": 865, "cpu_time_ms": 1, "memory_kb": 256}, "variant": "high_resource"}