diff --git a/ChemEquation/ChemEquation.jsonl b/ChemEquation/ChemEquation.jsonl new file mode 100644 index 0000000000000000000000000000000000000000..2639b8e25cf6c395313acbf1948c263ce1679e02 --- /dev/null +++ b/ChemEquation/ChemEquation.jsonl @@ -0,0 +1,1000 @@ +{"index": 0, "question": "请你朗读以下化学公式符号:$c\\left(Fe^{2+}\\right)$", "audio_path": "audio/chemistry_1f13e798-e3f3-47b4-9825-8460c6f3c990.wav", "formula": "$c\\left(Fe^{2+}\\right)$", "answer": "亚铁离子的浓度", "subset": "ChemEquation", "task_type": "tts"} +{"index": 1, "question": "请你朗读以下化学公式符号:$${{C}_{x}}{{H}_{y}}$$", "audio_path": "audio/chemistry_4f0cd99a-12aa-408d-98e5-baec9762c3f4.wav", "formula": "$${{C}_{x}}{{H}_{y}}$$", "answer": "一个由x个碳原子和y个氢原子构成的分子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 2, "question": "请你朗读以下化学公式符号:$$20{ mg}/100{ mL}\\leqslant$$", "audio_path": "audio/chemistry_750d1357-63bc-4a54-a71c-e0cb87d0f08e.wav", "formula": "$$20{ mg}/100{ mL}\\leqslant$$", "answer": "二十毫克每一百毫升小于等于", "subset": "ChemEquation", "task_type": "tts"} +{"index": 3, "question": "请你朗读以下化学公式符号:$\\left(O^{2−}_{2}\\right)$", "audio_path": "audio/chemistry_2d74b7a7-3c49-4a11-b966-be038136fc70.wav", "formula": "$\\left(O^{2−}_{2}\\right)$", "answer": "过氧根离子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 4, "question": "请你朗读以下化学公式符号:$Q_{3}< Q_{2}=Q_{1}=Q$", "audio_path": "audio/chemistry_5ab5a92b-54b8-4a1e-936e-314b49fea9d0.wav", "formula": "$Q_{3}< Q_{2}=Q_{1}=Q$", "answer": "Q三小于Q二等于Q一等于Q", "subset": "ChemEquation", "task_type": "tts"} +{"index": 5, "question": "请你朗读以下化学公式符号:$\\left(H_{2}O_{2}\\right)$", "audio_path": "audio/chemistry_97b33801-b977-47ec-be12-9d2fb9a6cd1d.wav", "formula": "$\\left(H_{2}O_{2}\\right)$", "answer": "过氧化氢", "subset": "ChemEquation", "task_type": "tts"} +{"index": 6, "question": "请你朗读以下化学公式符号:$${{{C}}_7}{{{H}}_{14}}{{{O}}_3}{{{N}}_2}$$", "audio_path": "audio/chemistry_6d17ca3d-94e8-43bf-bd71-385ac271dfc6.wav", "formula": "$${{{C}}_7}{{{H}}_{14}}{{{O}}_3}{{{N}}_2}$$", "answer": "一个由七个碳原子、十四个氢原子、三个氧原子和两个氮原子构成的分子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 7, "question": "请你朗读以下化学公式符号:$$4.4 g {C}{{O}}_2$$", "audio_path": "audio/chemistry_61297cce-6586-4cad-9531-4695d63141bb.wav", "formula": "$$4.4 g {C}{{O}}_2$$", "answer": "四点四克二氧化碳", "subset": "ChemEquation", "task_type": "tts"} +{"index": 8, "question": "请你朗读以下化学公式符号:$C_{10}N_{5}P_{3}H_{18}O_{3}$", "audio_path": "audio/chemistry_945e2195-f672-474a-b80e-5c8e593d8dca.wav", "formula": "$C_{10}N_{5}P_{3}H_{18}O_{3}$", "answer": "一个由十个碳原子、五个氮原子、三个磷原子、十八个氢原子和三个氧原子构成的分子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 9, "question": "请你朗读以下化学公式符号:$Al(OH)_{3}(s)\\xlongequal{△}\\frac{1}{2}Al_{2}O_{3}(s)+\\frac{2}{3}H_{2}O(g)$", "audio_path": "audio/chemistry_0a5a0b04-af00-41c7-a6b8-96667a2d1169.wav", "formula": "$Al(OH)_{3}(s)\\xlongequal{△}\\frac{1}{2}Al_{2}O_{3}(s)+\\frac{2}{3}H_{2}O(g)$", "answer": "一摩尔的固态氢氧化铝在加热的条件下分解生成二分之一摩尔的固态氧化铝和三分之二摩尔的气态水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 10, "question": "请你朗读以下化学公式符号:$Ni\\left(OH\\right)_{2}$", "audio_path": "audio/chemistry_286a637b-f494-4f44-af06-7f59f8302cfd.wav", "formula": "$Ni\\left(OH\\right)_{2}$", "answer": "氢氧化镍", "subset": "ChemEquation", "task_type": "tts"} +{"index": 11, "question": "请你朗读以下化学公式符号:$\\left(C_{6}H_{5}CH_{3}\\right)$", "audio_path": "audio/chemistry_2126a083-fa59-4acb-8f3b-ca4d8a5f65f3.wav", "formula": "$\\left(C_{6}H_{5}CH_{3}\\right)$", "answer": "甲苯", "subset": "ChemEquation", "task_type": "tts"} +{"index": 12, "question": "请你朗读以下化学公式符号:$$12+1\\times 2+16=30$$", "audio_path": "audio/chemistry_1bef0430-dd6e-4479-bbbe-c7a3baa7f7ef.wav", "formula": "$$12+1\\times 2+16=30$$", "answer": "十二加一乘二加十六等于三十", "subset": "ChemEquation", "task_type": "tts"} +{"index": 13, "question": "请你朗读以下化学公式符号:$${{{N}}_2}{{{H}}_4}$$", "audio_path": "audio/chemistry_d3b9bf41-a3e8-46b5-86ba-29932f866173.wav", "formula": "$${{{N}}_2}{{{H}}_4}$$", "answer": "肼", "subset": "ChemEquation", "task_type": "tts"} +{"index": 14, "question": "请你朗读以下化学公式符号:$$\\rm (12\\times15):(1\\times22):(16\\times5)=90:11:40$$", "audio_path": "audio/chemistry_1c496d98-7b45-444c-bdbb-e2ad259935af.wav", "formula": "$$\\rm (12\\times15):(1\\times22):(16\\times5)=90:11:40$$", "answer": "十二乘十五的积比一乘二十二的积比十六乘五的积等于九十比十一比四十", "subset": "ChemEquation", "task_type": "tts"} +{"index": 15, "question": "请你朗读以下化学公式符号:$7 \\times 6.02 \\times 10^{23}$", "audio_path": "audio/chemistry_4803eb40-a636-4aca-9f06-f65beea7d6d0.wav", "formula": "$7 \\times 6.02 \\times 10^{23}$", "answer": "七乘六点零二乘十的二十三次方", "subset": "ChemEquation", "task_type": "tts"} +{"index": 16, "question": "请你朗读以下化学公式符号:$$Cu_{2}(OH)_{2}CO_{3}$$", "audio_path": "audio/chemistry_d399e5b1-9972-4dde-9b90-2f0099afb7a8.wav", "formula": "$$Cu_{2}(OH)_{2}CO_{3}$$", "answer": "碱式碳酸铜", "subset": "ChemEquation", "task_type": "tts"} +{"index": 17, "question": "请你朗读以下化学公式符号:$\\frac{1mol}{0.1mol}$", "audio_path": "audio/chemistry_1b88d5ee-c673-4433-90cf-eabb62d27103.wav", "formula": "$\\frac{1mol}{0.1mol}$", "answer": "零点一摩尔分之一摩尔", "subset": "ChemEquation", "task_type": "tts"} +{"index": 18, "question": "请你朗读以下化学公式符号:$N_{2}H_{4}(g)+O_{2}(g)=N_{2}(g)+2H_{2}O(g)$", "audio_path": "audio/chemistry_4bf831ef-9960-4a31-8ad4-dc6caa9fa08e.wav", "formula": "$N_{2}H_{4}(g)+O_{2}(g)=N_{2}(g)+2H_{2}O(g)$", "answer": "一摩尔的气态肼和一摩尔的气态氧气反应生成一摩尔的气态氮气和两摩尔的气态水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 19, "question": "请你朗读以下化学公式符号:$$2{HI}({g})\\rightleftharpoons {{{H}}_{2}}({g})+{{{I}}_{2}}({g})$$", "audio_path": "audio/chemistry_31bc8202-fc32-454a-952b-f266d2fd774d.wav", "formula": "$$2{HI}({g})\\rightleftharpoons {{{H}}_{2}}({g})+{{{I}}_{2}}({g})$$", "answer": "二摩尔的气态碘化氢反应生成一摩尔的气态氢气和一摩尔的气态碘", "subset": "ChemEquation", "task_type": "tts"} +{"index": 20, "question": "请你朗读以下化学公式符号:$2\\upsilon\\left(O_{2}\\right)$", "audio_path": "audio/chemistry_833325ca-fd38-49f5-b22b-12f2c20d34e2.wav", "formula": "$2\\upsilon\\left(O_{2}\\right)$", "answer": "二倍的氧气的反应速率", "subset": "ChemEquation", "task_type": "tts"} +{"index": 21, "question": "请你朗读以下化学公式符号:$$CO_{2} \\left(mol\\right)$$", "audio_path": "audio/chemistry_6d250eb2-3f15-4caa-bc6b-e3bd2e208f6b.wav", "formula": "$$CO_{2} \\left(mol\\right)$$", "answer": "二氧化碳 摩尔", "subset": "ChemEquation", "task_type": "tts"} +{"index": 22, "question": "请你朗读以下化学公式符号:$Cl_2+2NaOH═NaClO+NaCl+H_2O$", "audio_path": "audio/chemistry_1678e7ab-c676-4661-8c52-f8e7cca84ad0.wav", "formula": "$Cl_2+2NaOH═NaClO+NaCl+H_2O$", "answer": "氯气和氢氧化钠反应生成次氯酸钠、氯化钠和水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 23, "question": "请你朗读以下化学公式符号:$Cu+HCl Cu+AgNO_{3}$", "audio_path": "audio/chemistry_457c1f9e-db36-4461-a387-c1113b934200.wav", "formula": "$Cu+HCl Cu+AgNO_{3}$", "answer": "铜加盐酸 铜加硝酸银", "subset": "ChemEquation", "task_type": "tts"} +{"index": 24, "question": "请你朗读以下化学公式符号:$0.2mol/LNa_{2}CO_{3}$", "audio_path": "audio/chemistry_12e2002e-4213-4cc1-abbf-01b5c3c37c48.wav", "formula": "$0.2mol/LNa_{2}CO_{3}$", "answer": "零点二摩尔每升的碳酸钠", "subset": "ChemEquation", "task_type": "tts"} +{"index": 25, "question": "请你朗读以下化学公式符号:$2H_{2}O_{2}=2H_{2}O+O_{2}↑$", "audio_path": "audio/chemistry_42afd28c-f607-4384-9f29-e06a72a33470.wav", "formula": "$2H_{2}O_{2}=2H_{2}O+O_{2}↑$", "answer": "过氧化氢分解生成水和氧气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 26, "question": "请你朗读以下化学公式符号:$Cu_{2}(OH)_{2}CO_{3}$", "audio_path": "audio/chemistry_ff241f03-bd61-49d4-9af9-4f8a5972659a.wav", "formula": "$Cu_{2}(OH)_{2}CO_{3}$", "answer": "碱式碳酸铜", "subset": "ChemEquation", "task_type": "tts"} +{"index": 27, "question": "请你朗读以下化学公式符号:$F$ $ 1s^{2}2s^{2}2p^{5}$", "audio_path": "audio/chemistry_dda6da85-2661-421f-b7cb-e8e460346fc2.wav", "formula": "$F$ $ 1s^{2}2s^{2}2p^{5}$", "answer": "氟 一s 轨道填充 两个电子,二s 轨道填充 两 个电子,二p 轨道填充 五个电子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 28, "question": "请你朗读以下化学公式符号:$3CO(g)+Fe_{2}O_{3}(s)\\xlongequal{\\text{高温}} 3CO_{2}(g)+2Fe(s)$", "audio_path": "audio/chemistry_4c93ffd3-9a3b-4bdf-9008-47c40b95f1b5.wav", "formula": "$3CO(g)+Fe_{2}O_{3}(s)\\xlongequal{\\text{高温}} 3CO_{2}(g)+2Fe(s)$", "answer": "三摩尔气态一氧化碳和一摩尔固态氧化铁在高温条件下,反应生成三摩尔气态二氧化碳和两摩尔固态铁", "subset": "ChemEquation", "task_type": "tts"} +{"index": 29, "question": "请你朗读以下化学公式符号:$$\\frac{22.4g}{56g/mol}$$", "audio_path": "audio/chemistry_091fc1a5-fc0f-4dc6-8c1f-a4f8b27e4741.wav", "formula": "$$\\frac{22.4g}{56g/mol}$$", "answer": "五十六克每摩尔分之二十二点四克", "subset": "ChemEquation", "task_type": "tts"} +{"index": 30, "question": "请你朗读以下化学公式符号:$19\\times 6.02\\times {{10}^{23}}$", "audio_path": "audio/chemistry_2b6485b9-119f-404b-b547-030a24b23256.wav", "formula": "$19\\times 6.02\\times {{10}^{23}}$", "answer": "十九乘六点零二乘十的二十三次方", "subset": "ChemEquation", "task_type": "tts"} +{"index": 31, "question": "请你朗读以下化学公式符号:$4.0mol/\\left(L⋅s\\right)$", "audio_path": "audio/chemistry_dd73c8d9-f680-49fb-921a-923dc9f8fa0e.wav", "formula": "$4.0mol/\\left(L⋅s\\right)$", "answer": "四点零摩尔每升秒", "subset": "ChemEquation", "task_type": "tts"} +{"index": 32, "question": "请你朗读以下化学公式符号:$$Fe+CuSO_{4}═Cu+Fe SO_{4}$$", "audio_path": "audio/chemistry_ce43d860-4fd5-4250-a14d-cc4311cafdcf.wav", "formula": "$$Fe+CuSO_{4}═Cu+Fe SO_{4}$$", "answer": "铁和硫酸铜反应生成铜和硫酸亚铁", "subset": "ChemEquation", "task_type": "tts"} +{"index": 33, "question": "请你朗读以下化学公式符号:$4CO(g)+Fe_{3}O_{4}(s)\\xlongequal{\\text{高温}} 4CO_{2}(g)+3Fe(s)$", "audio_path": "audio/chemistry_66f8566f-5b43-4fbf-b840-0d1524e156ec.wav", "formula": "$4CO(g)+Fe_{3}O_{4}(s)\\xlongequal{\\text{高温}} 4CO_{2}(g)+3Fe(s)$", "answer": "四摩尔气态一氧化碳和一摩尔固态四氧化三铁在高温条件下,反应生成四摩尔气态二氧化碳和三摩尔固态铁", "subset": "ChemEquation", "task_type": "tts"} +{"index": 34, "question": "请你朗读以下化学公式符号:$\\rm FeCl_3+3NaOH\\ce{\\xlongequal{}}Fe(OH)_3\\downarrow \\rm +3NaCl$", "audio_path": "audio/chemistry_0e298be2-86d0-4996-bd36-fb3e0ece7116.wav", "formula": "$\\rm FeCl_3+3NaOH\\ce{\\xlongequal{}}Fe(OH)_3\\downarrow \\rm +3NaCl$", "answer": "氯化铁和氢氧化钠反应生成氢氧化铁沉淀和氯化钠", "subset": "ChemEquation", "task_type": "tts"} +{"index": 35, "question": "请你朗读以下化学公式符号:$\\stackrel{{AgNO}_{3}}{\\rightarrow }\\ \\stackrel{Ca(OH)_2}{\\rightarrow }$", "audio_path": "audio/chemistry_25917c73-da81-4463-b960-430bdc0e52b3.wav", "formula": "$\\stackrel{{AgNO}_{3}}{\\rightarrow }\\ \\stackrel{Ca(OH)_2}{\\rightarrow }$", "answer": "在硝酸银的条件下反应 在氢氧化钙的条件下反应", "subset": "ChemEquation", "task_type": "tts"} +{"index": 36, "question": "请你朗读以下化学公式符号:$c\\left(OH^{-}\\right)$", "audio_path": "audio/chemistry_78686cab-0ac5-4723-96c4-41112c4c3256.wav", "formula": "$c\\left(OH^{-}\\right)$", "answer": "氢氧根离子的浓度", "subset": "ChemEquation", "task_type": "tts"} +{"index": 37, "question": "请你朗读以下化学公式符号:$1.8\\mathrm{g}\\div \\frac{12}{40+12+16\\times 3}\\times 100\\mathrm{\\% }=15\\mathrm{g}$", "audio_path": "audio/chemistry_ff10b3fa-1903-4315-9026-d621e210dca8.wav", "formula": "$1.8\\mathrm{g}\\div \\frac{12}{40+12+16\\times 3}\\times 100\\mathrm{\\% }=15\\mathrm{g}$", "answer": "一点八克除以四十加十二加十六乘三的积的和分之十二,再乘百分之百等于十五克", "subset": "ChemEquation", "task_type": "tts"} +{"index": 38, "question": "请你朗读以下化学公式符号:$$\\frac{34}{60}=\\frac{x}{6{ t}}$$", "audio_path": "audio/chemistry_fb2c7fcc-9a2d-46f3-b67e-222699ddc564.wav", "formula": "$$\\frac{34}{60}=\\frac{x}{6{ t}}$$", "answer": "六十分之三十四等于六t分之x", "subset": "ChemEquation", "task_type": "tts"} +{"index": 39, "question": "请你朗读以下化学公式符号:$\\frac{4.6g}{23g/mol}$", "audio_path": "audio/chemistry_c69f54ea-1acd-49f7-bbbe-781e69a0189d.wav", "formula": "$\\frac{4.6g}{23g/mol}$", "answer": "二十三克每摩尔分之四点六克", "subset": "ChemEquation", "task_type": "tts"} +{"index": 40, "question": "请你朗读以下化学公式符号:$(12\\times37):(1\\times38):(14\\times2):(16\\times6)=222:19:14:48$", "audio_path": "audio/chemistry_93394907-7c0e-4a65-82ed-7f0143be18ea.wav", "formula": "$(12\\times37):(1\\times38):(14\\times2):(16\\times6)=222:19:14:48$", "answer": "十二乘三十七的积比一乘三十八的积比十四乘二的积比十六乘六的积等于二百二十二比十九比十四比四十八", "subset": "ChemEquation", "task_type": "tts"} +{"index": 41, "question": "请你朗读以下化学公式符号:$$Fe\\left(NO_{3}\\right)_{3}$$", "audio_path": "audio/chemistry_6f5460f2-9703-400e-bfe1-73c4249c0910.wav", "formula": "$$Fe\\left(NO_{3}\\right)_{3}$$", "answer": "硝酸铁", "subset": "ChemEquation", "task_type": "tts"} +{"index": 42, "question": "请你朗读以下化学公式符号:$v(N_{2})=0.002 \\, \\text{mol} \\cdot L^{-1} \\cdot s^{-1}$", "audio_path": "audio/chemistry_6d033356-f9ae-4ba3-8c69-18f6f3e6bb84.wav", "formula": "$v(N_{2})=0.002 \\, \\text{mol} \\cdot L^{-1} \\cdot s^{-1}$", "answer": "氮气的反应速率等于零点零零二摩尔每升每秒", "subset": "ChemEquation", "task_type": "tts"} +{"index": 43, "question": "请你朗读以下化学公式符号:$C_{10}H_{14}N_{2}$", "audio_path": "audio/chemistry_c3cbaf31-cf71-40bf-b9af-c08ecda62f3e.wav", "formula": "$C_{10}H_{14}N_{2}$", "answer": "一个由十个碳原子、十四个氢原子和两个氮原子构成的分子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 44, "question": "请你朗读以下化学公式符号:$$\\left(MgF_{2}\\right)$$", "audio_path": "audio/chemistry_25cb597f-efae-4a59-9fa2-5ee1fe310943.wav", "formula": "$$\\left(MgF_{2}\\right)$$", "answer": "氟化镁", "subset": "ChemEquation", "task_type": "tts"} +{"index": 45, "question": "请你朗读以下化学公式符号:$1.5Q_{1}−0.5Q_{2}+0.5Q_{3}$", "audio_path": "audio/chemistry_47b66926-b2c1-4181-9b6c-b191575caeb7.wav", "formula": "$1.5Q_{1}−0.5Q_{2}+0.5Q_{3}$", "answer": "一点五Q一减零点五Q二加零点五Q三", "subset": "ChemEquation", "task_type": "tts"} +{"index": 46, "question": "请你朗读以下化学公式符号:$3\\times6.02\\times10^{23}$", "audio_path": "audio/chemistry_bc83330e-409b-48f4-bf2c-1066295a2a3a.wav", "formula": "$3\\times6.02\\times10^{23}$", "answer": "三乘六点零二乘十的二十三次方", "subset": "ChemEquation", "task_type": "tts"} +{"index": 47, "question": "请你朗读以下化学公式符号:$$CH_{4}$$$$ C_{10}H_{22}$$", "audio_path": "audio/chemistry_55ececf0-3161-4368-9281-9e8379f485f6.wav", "formula": "$$CH_{4}$$$$ C_{10}H_{22}$$", "answer": "甲烷 癸烷", "subset": "ChemEquation", "task_type": "tts"} +{"index": 48, "question": "请你朗读以下化学公式符号:$Cl_{2}O+H_{2}O=2HClO$", "audio_path": "audio/chemistry_1839231e-f227-431f-b827-7b167d845d70.wav", "formula": "$Cl_{2}O+H_{2}O=2HClO$", "answer": "一氧化二氯和水反应生成次氯酸", "subset": "ChemEquation", "task_type": "tts"} +{"index": 49, "question": "请你朗读以下化学公式符号:$0.1mol⋅L^{−1}H_{2}A$", "audio_path": "audio/chemistry_769813d8-c427-47ec-9c2a-ddbd9db30780.wav", "formula": "$0.1mol⋅L^{−1}H_{2}A$", "answer": "零点一摩尔每升A化氢", "subset": "ChemEquation", "task_type": "tts"} +{"index": 50, "question": "请你朗读以下化学公式符号:$2 \\times C_{25}H_{51}COOH$", "audio_path": "audio/chemistry_d6bc7d12-bff3-4c02-a028-f17191d42854.wav", "formula": "$2 \\times C_{25}H_{51}COOH$", "answer": "二倍的二十六烷酸", "subset": "ChemEquation", "task_type": "tts"} +{"index": 51, "question": "请你朗读以下化学公式符号:$0.1mol⋅L^{-1}CH_{3}COOH$", "audio_path": "audio/chemistry_927c9d29-b731-4006-8b58-a9698c4442b4.wav", "formula": "$0.1mol⋅L^{-1}CH_{3}COOH$", "answer": "零点一摩尔每升醋酸", "subset": "ChemEquation", "task_type": "tts"} +{"index": 52, "question": "请你朗读以下化学公式符号:$△H=−242kJ⋅mol^{−1}$", "audio_path": "audio/chemistry_99e29b5b-61eb-47f9-9066-bfa8f958ca78.wav", "formula": "$△H=−242kJ⋅mol^{−1}$", "answer": "delta H 等于负二百四十二千焦每摩尔", "subset": "ChemEquation", "task_type": "tts"} +{"index": 53, "question": "请你朗读以下化学公式符号:$$3K_{2}S+8HNO_{3}$$", "audio_path": "audio/chemistry_624e6a9d-902e-43a8-9ad4-93dc8e631918.wav", "formula": "$$3K_{2}S+8HNO_{3}$$", "answer": "三个硫化钾加八个硝酸", "subset": "ChemEquation", "task_type": "tts"} +{"index": 54, "question": "请你朗读以下化学公式符号:$\\frac{5}{6}v\\left(O_{2}\\right)=v\\left(H_{2}O\\right)$", "audio_path": "audio/chemistry_a6164c77-f7c2-47b6-80aa-71edd77a311f.wav", "formula": "$\\frac{5}{6}v\\left(O_{2}\\right)=v\\left(H_{2}O\\right)$", "answer": "六分之五倍的氧气的反应速率等于水的反应速率", "subset": "ChemEquation", "task_type": "tts"} +{"index": 55, "question": "请你朗读以下化学公式符号:$0.1\\,\\mathrm{mol} \\,\\mathrm{HgO} + 0.1\\,\\mathrm{mol} \\,\\mathrm{Hg}$", "audio_path": "audio/chemistry_81d2c996-cebc-4253-900e-b0dbb994dd78.wav", "formula": "$0.1\\,\\mathrm{mol} \\,\\mathrm{HgO} + 0.1\\,\\mathrm{mol} \\,\\mathrm{Hg}$", "answer": "零点一摩尔氧化汞加零点一摩尔汞", "subset": "ChemEquation", "task_type": "tts"} +{"index": 56, "question": "请你朗读以下化学公式符号:$$4.94\\times10^{−3} \\mathrm{mol/L}$$", "audio_path": "audio/chemistry_ab7049e8-fbbf-424e-9e4c-daca7b963669.wav", "formula": "$$4.94\\times10^{−3} \\mathrm{mol/L}$$", "answer": "四点九四乘十的负三次方摩尔每升", "subset": "ChemEquation", "task_type": "tts"} +{"index": 57, "question": "请你朗读以下化学公式符号:$\\left(Si_{3}N_{4}\\right)$", "audio_path": "audio/chemistry_206a57a6-166f-4797-abaf-b7c598a7ca68.wav", "formula": "$\\left(Si_{3}N_{4}\\right)$", "answer": "氮化硅", "subset": "ChemEquation", "task_type": "tts"} +{"index": 58, "question": "请你朗读以下化学公式符号:$1.204\\times10^{24}$", "audio_path": "audio/chemistry_9ee94bf6-5c79-4014-9341-7a2806ab62cb.wav", "formula": "$1.204\\times10^{24}$", "answer": "一点二零四乘十的二十四次方", "subset": "ChemEquation", "task_type": "tts"} +{"index": 59, "question": "请你朗读以下化学公式符号:$$Al_{2}\\left(SO_{4}\\right)_{3}$$", "audio_path": "audio/chemistry_5e6ddab6-66ae-4496-b742-4e1f978cee2f.wav", "formula": "$$Al_{2}\\left(SO_{4}\\right)_{3}$$", "answer": "硫酸铝", "subset": "ChemEquation", "task_type": "tts"} +{"index": 60, "question": "请你朗读以下化学公式符号:$CO^{2−}_{3}+2CH_{3}COOH═CO_{2}\\uparrow+H_{2}O+2CH_{3}COO^{−}$", "audio_path": "audio/chemistry_9f5fb31a-e556-4a85-af92-ffd9060a2961.wav", "formula": "$CO^{2−}_{3}+2CH_{3}COOH═CO_{2}\\uparrow+H_{2}O+2CH_{3}COO^{−}$", "answer": "碳酸根离子和醋酸反应生成二氧化碳、水和醋酸根离子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 61, "question": "请你朗读以下化学公式符号:$(C_{6}H_{10}O_{5})_{n}$", "audio_path": "audio/chemistry_26a2871d-6684-4cbc-bc0d-a48ac8047d05.wav", "formula": "$(C_{6}H_{10}O_{5})_{n}$", "answer": "多糖", "subset": "ChemEquation", "task_type": "tts"} +{"index": 62, "question": "请你朗读以下化学公式符号:$Fe+2H^{+}=H_{2}\\uparrow+Fe^{2+}$", "audio_path": "audio/chemistry_78965733-9cd3-41e6-a043-44f149714a99.wav", "formula": "$Fe+2H^{+}=H_{2}\\uparrow+Fe^{2+}$", "answer": "铁和氢离子反应生成氢气和亚铁离子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 63, "question": "请你朗读以下化学公式符号:$Mg\\left(NO_{3}\\right)_{2}$", "audio_path": "audio/chemistry_8b5943f8-f8b3-404d-a428-604ddb81b6f5.wav", "formula": "$Mg\\left(NO_{3}\\right)_{2}$", "answer": "硝酸镁", "subset": "ChemEquation", "task_type": "tts"} +{"index": 64, "question": "请你朗读以下化学公式符号:$2{{{s}}^2}2{{{p}}^1}$", "audio_path": "audio/chemistry_fdf932cf-5c64-4b72-a31b-c19b00af85a3.wav", "formula": "$2{{{s}}^2}2{{{p}}^1}$", "answer": "二s轨道上填充两个电子,二p轨道上填充一个电子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 65, "question": "请你朗读以下化学公式符号:$1L 1mol\\cdot L^{-1}K_{2}CO_{3}$", "audio_path": "audio/chemistry_03efa2c1-79c4-4e88-8f8a-deabc6c992c9.wav", "formula": "$1L 1mol\\cdot L^{-1}K_{2}CO_{3}$", "answer": "一升一摩尔每升的碳酸钾溶液", "subset": "ChemEquation", "task_type": "tts"} +{"index": 66, "question": "请你朗读以下化学公式符号:$Fe_{2}O_{3}•H_{2}O$", "audio_path": "audio/chemistry_d1d3090b-18de-491d-87ff-0e05dc3292ac.wav", "formula": "$Fe_{2}O_{3}•H_{2}O$", "answer": "一水合氧化铁", "subset": "ChemEquation", "task_type": "tts"} +{"index": 67, "question": "请你朗读以下化学公式符号:$2HSCN+K_{2}CO_{3}=2KSCN+CO_{2}\\uparrow+H_{2}O$", "audio_path": "audio/chemistry_b8aee3d1-be9e-4506-972e-c2deddaecb6a.wav", "formula": "$2HSCN+K_{2}CO_{3}=2KSCN+CO_{2}\\uparrow+H_{2}O$", "answer": "硫氰酸和碳酸钾反应生成硫氰酸钾、二氧化碳气体和水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 68, "question": "请你朗读以下化学公式符号:$\\frac{124g}{124g/mol}$", "audio_path": "audio/chemistry_19ecfca9-f463-4aa1-8562-f8575db6a9f7.wav", "formula": "$\\frac{124g}{124g/mol}$", "answer": "一百二十四克每摩尔分之一百二十四克", "subset": "ChemEquation", "task_type": "tts"} +{"index": 69, "question": "请你朗读以下化学公式符号:$\\frac{1}{2}Ba(OH)_{2}(aq)$", "audio_path": "audio/chemistry_d37c36f3-3ea7-425b-a478-ddb30a3e92c0.wav", "formula": "$\\frac{1}{2}Ba(OH)_{2}(aq)$", "answer": "二分之一摩尔氢氧化钡溶液", "subset": "ChemEquation", "task_type": "tts"} +{"index": 70, "question": "请你朗读以下化学公式符号:${{{C}}_{8}}{{{H}}_{8}}$", "audio_path": "audio/chemistry_1aec0eda-5937-4e0a-a421-2e401a067cc1.wav", "formula": "${{{C}}_{8}}{{{H}}_{8}}$", "answer": "苯乙烯", "subset": "ChemEquation", "task_type": "tts"} +{"index": 71, "question": "请你朗读以下化学公式符号:$CO^{2−}_{3}+2H^{+}═CO_{2}\\uparrow+H_{2}O$", "audio_path": "audio/chemistry_e40ded84-e2fd-46dd-9612-092ebb254550.wav", "formula": "$CO^{2−}_{3}+2H^{+}═CO_{2}\\uparrow+H_{2}O$", "answer": "碳酸根离子和氢离子反应生成二氧化碳和水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 72, "question": "请你朗读以下化学公式符号:$O_{2}$", "audio_path": "audio/chemistry_3509f765-9623-4e1d-9fae-effdd7f8aaa9.wav", "formula": "$O_{2}$", "answer": "氧气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 73, "question": "请你朗读以下化学公式符号:$CaCO_{3}+2H^{+}=Ca^{2+}+CO_{2}\\uparrow+H_{2}O$", "audio_path": "audio/chemistry_a7413cc8-b504-4c1b-89ae-0d9e1e96d645.wav", "formula": "$CaCO_{3}+2H^{+}=Ca^{2+}+CO_{2}\\uparrow+H_{2}O$", "answer": "碳酸钙和氢离子反应生成钙离子、二氧化碳和水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 74, "question": "请你朗读以下化学公式符号:$CaCO_{3}+2H^{+}═Ca^{2+}+CO_{2}\\uparrow+H_{2}O$", "audio_path": "audio/chemistry_f08bafa3-4e98-41fa-9e78-9ef29f4180ca.wav", "formula": "$CaCO_{3}+2H^{+}═Ca^{2+}+CO_{2}\\uparrow+H_{2}O$", "answer": "碳酸钙和氢离子反应生成钙离子、二氧化碳气体和水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 75, "question": "请你朗读以下化学公式符号:$HClO_{4}>H_{2}SO_{4}>H_{4}SiO_{4}>H_{2}CO_{3}$", "audio_path": "audio/chemistry_304700a9-c587-4807-8ee6-b9bd2ff461b5.wav", "formula": "$HClO_{4}>H_{2}SO_{4}>H_{4}SiO_{4}>H_{2}CO_{3}$", "answer": "高氯酸强于硫酸强于原硅酸强于碳酸", "subset": "ChemEquation", "task_type": "tts"} +{"index": 76, "question": "请你朗读以下化学公式符号:$N_{2}H_{4}(g)+\\frac{1}{2}N_{2}O_{4}(g)═\\frac{3}{2}N_{2}(g)+2H_{2}O(g)$", "audio_path": "audio/chemistry_3f252540-9eda-4708-8e93-b1e2ff9e21d0.wav", "formula": "$N_{2}H_{4}(g)+\\frac{1}{2}N_{2}O_{4}(g)═\\frac{3}{2}N_{2}(g)+2H_{2}O(g)$", "answer": "一摩尔的气态联氨和二分之一摩尔的气态四氧化二氮反应生成二分之三摩尔的气态氮气和两摩尔的气态水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 77, "question": "请你朗读以下化学公式符号:$$\\left(TiO_{2}\\right)$$", "audio_path": "audio/chemistry_55fc13fd-1c8e-48b4-91ae-2fa146ae839f.wav", "formula": "$$\\left(TiO_{2}\\right)$$", "answer": "二氧化钛", "subset": "ChemEquation", "task_type": "tts"} +{"index": 78, "question": "请你朗读以下化学公式符号:$$aM^{2+}+bO_{2}+4H^{+}═cM^{3+}+dH_{2}O$$", "audio_path": "audio/chemistry_f52a4dbf-05f7-413f-87e6-12c2db1602c3.wav", "formula": "$$aM^{2+}+bO_{2}+4H^{+}═cM^{3+}+dH_{2}O$$", "answer": "二价M离子和氧气和氢离子反应生成三价M离子和水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 79, "question": "请你朗读以下化学公式符号:$Al_{2}O_{3}+2OH^{−}═2AlO^{−}_{2}+H_{2}O$", "audio_path": "audio/chemistry_fa5414e8-628e-4a39-b60e-b13d3c9580bf.wav", "formula": "$Al_{2}O_{3}+2OH^{−}═2AlO^{−}_{2}+H_{2}O$", "answer": "氧化铝和氢氧根离子反应生成偏铝酸根离子和水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 80, "question": "请你朗读以下化学公式符号:$0.01mol⋅L^{−1}⋅min^{−1}$", "audio_path": "audio/chemistry_531b1305-8265-4225-974d-aaa1860e19ba.wav", "formula": "$0.01mol⋅L^{−1}⋅min^{−1}$", "answer": "零点零一摩尔每升每分钟", "subset": "ChemEquation", "task_type": "tts"} +{"index": 81, "question": "请你朗读以下化学公式符号:$$\\mathrm{Fe}_2\\mathrm{O}_3$$", "audio_path": "audio/chemistry_6b658e2c-0726-4bf2-88c7-51c4a2443908.wav", "formula": "$$\\mathrm{Fe}_2\\mathrm{O}_3$$", "answer": "氧化铁", "subset": "ChemEquation", "task_type": "tts"} +{"index": 82, "question": "请你朗读以下化学公式符号:$$2HCl+FeO=FeCl_{2}+H_{2}O$$", "audio_path": "audio/chemistry_649821f7-9bfd-45b5-89d8-87d1d929a100.wav", "formula": "$$2HCl+FeO=FeCl_{2}+H_{2}O$$", "answer": "盐酸和氧化亚铁反应生成氯化亚铁和水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 83, "question": "请你朗读以下化学公式符号:$2C_{2}H_{5}SH+9O_{2}=4CO_{2}+2X+6H_{2}O$", "audio_path": "audio/chemistry_4a6f55aa-8d1e-457d-a368-e1ee3dae2637.wav", "formula": "$2C_{2}H_{5}SH+9O_{2}=4CO_{2}+2X+6H_{2}O$", "answer": "乙硫醇和氧气反应生成二氧化碳、X和水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 84, "question": "请你朗读以下化学公式符号:$△H=−571.6kJ⋅mol^{−1}$", "audio_path": "audio/chemistry_73a9c545-424d-44dc-9af2-2f307423426b.wav", "formula": "$△H=−571.6kJ⋅mol^{−1}$", "answer": "delta H等于负五百七十一点六千焦每摩尔", "subset": "ChemEquation", "task_type": "tts"} +{"index": 85, "question": "请你朗读以下化学公式符号:$CO_{2}\\left(g\\right)+H_{2}\\left(g\\right)$", "audio_path": "audio/chemistry_d477be58-cbfc-403e-8164-3b64461cdcd9.wav", "formula": "$CO_{2}\\left(g\\right)+H_{2}\\left(g\\right)$", "answer": "一摩尔的气态二氧化碳和一摩尔的气态氢气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 86, "question": "请你朗读以下化学公式符号:$4H_{2}O_{2}+PbS=PbSO_{4}+4H_{2}O$", "audio_path": "audio/chemistry_e0a982c6-6673-40c1-8f5b-3f5b69522d22.wav", "formula": "$4H_{2}O_{2}+PbS=PbSO_{4}+4H_{2}O$", "answer": "过氧化氢和硫化铅反应生成硫酸铅和水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 87, "question": "请你朗读以下化学公式符号:$$\\prescript{90}{39}{\\text{Y}}$$", "audio_path": "audio/chemistry_bf1ddcba-38bb-454b-8c87-0148e8ce5d4b.wav", "formula": "$$\\prescript{90}{39}{\\text{Y}}$$", "answer": "钇 九十", "subset": "ChemEquation", "task_type": "tts"} +{"index": 88, "question": "请你朗读以下化学公式符号:$\\overset{MnO_2}{\\rightarrow}$", "audio_path": "audio/chemistry_43971827-a8f0-44ce-a922-b05318bc11dd.wav", "formula": "$\\overset{MnO_2}{\\rightarrow}$", "answer": "在二氧化锰催化的条件下", "subset": "ChemEquation", "task_type": "tts"} +{"index": 89, "question": "请你朗读以下化学公式符号:$△H_{2}=+78.3kJ⋅mol^{−1}$", "audio_path": "audio/chemistry_f3fcf1ee-98bc-412b-bb4b-95e4030b2d6a.wav", "formula": "$△H_{2}=+78.3kJ⋅mol^{−1}$", "answer": "Delta H二等于正七十八点三千焦耳每摩尔", "subset": "ChemEquation", "task_type": "tts"} +{"index": 90, "question": "请你朗读以下化学公式符号:$12:(1\\times 2):16=6:1:8$", "audio_path": "audio/chemistry_8888729a-eaef-4ba3-afda-34173cb80df9.wav", "formula": "$12:(1\\times 2):16=6:1:8$", "answer": "十二比一乘二的积比十六等于六比一比八", "subset": "ChemEquation", "task_type": "tts"} +{"index": 91, "question": "请你朗读以下化学公式符号:$$c\\left(Ag^{+}\\right),v\\left(Cr^{3+}\\right)$$", "audio_path": "audio/chemistry_6eb16866-801b-4346-a533-31ad6dc721b6.wav", "formula": "$$c\\left(Ag^{+}\\right),v\\left(Cr^{3+}\\right)$$", "answer": "银离子的浓度,三价铬离子的反应速率", "subset": "ChemEquation", "task_type": "tts"} +{"index": 92, "question": "请你朗读以下化学公式符号:$\\frac{17.1g}{171g/mol}$", "audio_path": "audio/chemistry_b6574090-3d36-430f-badb-cb0dd8f5a67f.wav", "formula": "$\\frac{17.1g}{171g/mol}$", "answer": "一百七十一克每摩尔分之十七点一克", "subset": "ChemEquation", "task_type": "tts"} +{"index": 93, "question": "请你朗读以下化学公式符号:$amol NH_{4}HSO_{4}$", "audio_path": "audio/chemistry_3d1cdf7f-6bdd-4e6b-ae3b-544e4443682b.wav", "formula": "$amol NH_{4}HSO_{4}$", "answer": "a摩尔硫酸氢铵", "subset": "ChemEquation", "task_type": "tts"} +{"index": 94, "question": "请你朗读以下化学公式符号:${Cl}_2 + {H_2}O \\rightleftharpoons {HCl} + {HClO}$", "audio_path": "audio/chemistry_f365af81-1ef5-4f3e-b942-22c172e05588.wav", "formula": "${Cl}_2 + {H_2}O \\rightleftharpoons {HCl} + {HClO}$", "answer": "氯气和水反应生成盐酸和次氯酸", "subset": "ChemEquation", "task_type": "tts"} +{"index": 95, "question": "请你朗读以下化学公式符号:$CaCO_{3}+2H^+═Ca^{2+}+H_{2}O+CO_{2}\\uparrow$", "audio_path": "audio/chemistry_3329ff67-63fd-44f7-bf0e-188d7ef52c60.wav", "formula": "$CaCO_{3}+2H^+═Ca^{2+}+H_{2}O+CO_{2}\\uparrow$", "answer": "碳酸钙与氢离子反应生成钙离子、水和二氧化碳", "subset": "ChemEquation", "task_type": "tts"} +{"index": 96, "question": "请你朗读以下化学公式符号:$PbO_{2}+4H^{+}+SO^{2−}_{4}$", "audio_path": "audio/chemistry_531953cc-b74d-4cc5-9ea5-6b44f6f77013.wav", "formula": "$PbO_{2}+4H^{+}+SO^{2−}_{4}$", "answer": "二氧化铅,氢离子和硫酸根离子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 97, "question": "请你朗读以下化学公式符号:$c\\left(Cr^{3+}\\right)$", "audio_path": "audio/chemistry_9c5a3eb3-c0ba-4ec9-8b4e-658754cc1617.wav", "formula": "$c\\left(Cr^{3+}\\right)$", "answer": "三价铬离子的浓度", "subset": "ChemEquation", "task_type": "tts"} +{"index": 98, "question": "请你朗读以下化学公式符号:$c\\left(H^{+}\\right)>c\\left(OH^{-}\\right)$", "audio_path": "audio/chemistry_7dc04707-048d-4c60-b91d-f80d070bb7bc.wav", "formula": "$c\\left(H^{+}\\right)>c\\left(OH^{-}\\right)$", "answer": "氢离子浓度大于氢氧根离子浓度", "subset": "ChemEquation", "task_type": "tts"} +{"index": 99, "question": "请你朗读以下化学公式符号:$$\\frac{\\frac{0.9mol}{0.5L}}{30s}$$", "audio_path": "audio/chemistry_355da38f-fd5d-4127-b09a-a6e71f148a94.wav", "formula": "$$\\frac{\\frac{0.9mol}{0.5L}}{30s}$$", "answer": "三十秒 分之 零点五升分之零点九摩尔", "subset": "ChemEquation", "task_type": "tts"} +{"index": 100, "question": "请你朗读以下化学公式符号:$c\\left(H^{+}\\right)+c\\left(NH^{+}_{4}\\right)=2c\\left(OH^{−}\\right)$", "audio_path": "audio/chemistry_b24cde2c-e12e-400b-943f-512667cc11b7.wav", "formula": "$c\\left(H^{+}\\right)+c\\left(NH^{+}_{4}\\right)=2c\\left(OH^{−}\\right)$", "answer": "氢离子的浓度加铵根离子的浓度等于两倍氢氧根离子的浓度", "subset": "ChemEquation", "task_type": "tts"} +{"index": 101, "question": "请你朗读以下化学公式符号:$NO_{2}+Ag$", "audio_path": "audio/chemistry_0a005df6-fb54-4614-93ca-c4f74a45a92c.wav", "formula": "$NO_{2}+Ag$", "answer": "二氧化氮加银", "subset": "ChemEquation", "task_type": "tts"} +{"index": 102, "question": "请你朗读以下化学公式符号:$4.4\\ {g}\\times \\frac{12}{44}=1.2\\ {g}$", "audio_path": "audio/chemistry_d5a56d06-6ac3-4a52-9c29-0b8c55d1264e.wav", "formula": "$4.4\\ {g}\\times \\frac{12}{44}=1.2\\ {g}$", "answer": "四点四克乘四十四分之十二等于一点二克", "subset": "ChemEquation", "task_type": "tts"} +{"index": 103, "question": "请你朗读以下化学公式符号:$$Zn$$、$$Cu$$", "audio_path": "audio/chemistry_d5d36351-7edc-4dcc-9666-d21fb6a9a45e.wav", "formula": "$$Zn$$、$$Cu$$", "answer": "锌、铜", "subset": "ChemEquation", "task_type": "tts"} +{"index": 104, "question": "请你朗读以下化学公式符号:$$\\left[KAl\\left(SO_{4}\\right)_{2}⋅12H_{2}O\\right]$$", "audio_path": "audio/chemistry_e886eb51-23de-409a-a619-7ea925d43700.wav", "formula": "$$\\left[KAl\\left(SO_{4}\\right)_{2}⋅12H_{2}O\\right]$$", "answer": "十二水合硫酸铝钾", "subset": "ChemEquation", "task_type": "tts"} +{"index": 105, "question": "请你朗读以下化学公式符号:$c\\left(H^{+}\\right)$", "audio_path": "audio/chemistry_3243901d-7b80-4d2e-8377-61bcdbc7af5d.wav", "formula": "$c\\left(H^{+}\\right)$", "answer": "氢离子的浓度", "subset": "ChemEquation", "task_type": "tts"} +{"index": 106, "question": "请你朗读以下化学公式符号:$Fe_{2}O_{3}+3CO$", "audio_path": "audio/chemistry_45301f99-42c5-4651-8a90-4a646ebc6b48.wav", "formula": "$Fe_{2}O_{3}+3CO$", "answer": "氧化铁加一氧化碳", "subset": "ChemEquation", "task_type": "tts"} +{"index": 107, "question": "请你朗读以下化学公式符号:$2Fe+6H^{+}=2Fe^{3+}+3H_{2}\\uparrow$", "audio_path": "audio/chemistry_ad4188ad-cbc1-407d-b952-c3f2e00c48ea.wav", "formula": "$2Fe+6H^{+}=2Fe^{3+}+3H_{2}\\uparrow$", "answer": "铁和氢离子反应生成铁离子和氢气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 108, "question": "请你朗读以下化学公式符号:$Zn\\left(s\\right)+2HCl\\left(aq\\right)═ZnCl_{2}\\left(aq\\right)+H_{2}\\left(g\\right)$", "audio_path": "audio/chemistry_847d5381-5695-4cba-bf49-c0284a2b801c.wav", "formula": "$Zn\\left(s\\right)+2HCl\\left(aq\\right)═ZnCl_{2}\\left(aq\\right)+H_{2}\\left(g\\right)$", "answer": "一摩尔的固态锌和两摩尔的盐酸溶液反应生成一摩尔的氯化锌溶液和一摩尔的气态氢气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 109, "question": "请你朗读以下化学公式符号:$H^{+}+OH^{-}=H_{2}O$", "audio_path": "audio/chemistry_1ff9cb12-033c-4a13-bb44-13414eaa4b59.wav", "formula": "$H^{+}+OH^{-}=H_{2}O$", "answer": "氢离子和氢氧根离子反应生成水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 110, "question": "请你朗读以下化学公式符号:$NaHCO_{3}=Na^{+}+HCO^{−}_{3}$", "audio_path": "audio/chemistry_4eb1d136-7b07-4355-bebf-1c28699c366c.wav", "formula": "$NaHCO_{3}=Na^{+}+HCO^{−}_{3}$", "answer": "碳酸氢钠电离生成钠离子和碳酸氢根离子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 111, "question": "请你朗读以下化学公式符号:$2mol ⋅L^{-1}AgNO_{3}$", "audio_path": "audio/chemistry_736106fc-1f7e-4cca-b48a-e8f8ba5b51ac.wav", "formula": "$2mol ⋅L^{-1}AgNO_{3}$", "answer": "两摩尔每升硝酸银", "subset": "ChemEquation", "task_type": "tts"} +{"index": 112, "question": "请你朗读以下化学公式符号:$\\left(2\\right)Br_{2} +2Fe^{2+}=2Br^{-}+2Fe^{3+}$", "audio_path": "audio/chemistry_89a025a2-3841-4c63-a6f5-6b6cf346156c.wav", "formula": "$\\left(2\\right)Br_{2} +2Fe^{2+}=2Br^{-}+2Fe^{3+}$", "answer": "二 溴分子和亚铁离子反应生成溴离子和铁离子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 113, "question": "请你朗读以下化学公式符号:$0.2mol HgO+0.1mol O_{2}$", "audio_path": "audio/chemistry_3c6ae271-dac3-4b39-a1d9-3a94584c9425.wav", "formula": "$0.2mol HgO+0.1mol O_{2}$", "answer": "零点二摩尔氧化汞加零点一摩尔氧气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 114, "question": "请你朗读以下化学公式符号:$2H_{2}O_{2}=2H_{2}O+O_{2}\\uparrow$", "audio_path": "audio/chemistry_e67d8e1c-ff2e-4655-a86c-85b7755a1c6e.wav", "formula": "$2H_{2}O_{2}=2H_{2}O+O_{2}\\uparrow$", "answer": "过氧化氢分解生成水和氧气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 115, "question": "请你朗读以下化学公式符号:$\\rm Ca(OH)_2+CO_2=CaCO_3+H_2O$", "audio_path": "audio/chemistry_fbebaac4-c6c0-490a-8219-ee0ed1ce4046.wav", "formula": "$\\rm Ca(OH)_2+CO_2=CaCO_3+H_2O$", "answer": "氢氧化钙和二氧化碳反应生成碳酸钙和水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 116, "question": "请你朗读以下化学公式符号:$0.2mol/LH_{2}SO_{4}$", "audio_path": "audio/chemistry_b187007c-28d4-4494-a179-383f6cffe41a.wav", "formula": "$0.2mol/LH_{2}SO_{4}$", "answer": "零点二摩尔每升硫酸", "subset": "ChemEquation", "task_type": "tts"} +{"index": 117, "question": "请你朗读以下化学公式符号:$\\frac{c\\left(HCO^{−}_{3}\\right)⋅c\\left(OH^{−}\\right)}{c\\left(CO^{2−}_{3}\\right)}$", "audio_path": "audio/chemistry_dc1ffbd4-db4d-444d-bfbe-6be56b3b994e.wav", "formula": "$\\frac{c\\left(HCO^{−}_{3}\\right)⋅c\\left(OH^{−}\\right)}{c\\left(CO^{2−}_{3}\\right)}$", "answer": "碳酸根离子的浓度分之碳酸氢根离子的浓度乘氢氧根离子的浓度", "subset": "ChemEquation", "task_type": "tts"} +{"index": 118, "question": "请你朗读以下化学公式符号:${{{H}}_3}{P}{{{O}}_4}$", "audio_path": "audio/chemistry_7cfedf04-56f6-46a6-a1c4-b7b604123ee3.wav", "formula": "${{{H}}_3}{P}{{{O}}_4}$", "answer": "磷酸", "subset": "ChemEquation", "task_type": "tts"} +{"index": 119, "question": "请你朗读以下化学公式符号:$c\\left(Ag^{+}\\right)=c\\left(Cl^{−}\\right)$", "audio_path": "audio/chemistry_632dd09f-1638-4932-8847-c51cf9287e27.wav", "formula": "$c\\left(Ag^{+}\\right)=c\\left(Cl^{−}\\right)$", "answer": "银离子的浓度等于氯离子的浓度", "subset": "ChemEquation", "task_type": "tts"} +{"index": 120, "question": "请你朗读以下化学公式符号:$$\\overset{+4}{\\mathop{{Mn}{{{O}}_{2}}}}\\to \\overset{+2}{\\mathop{{MnC}{{{l}}_{2}}}}$$", "audio_path": "audio/chemistry_eab23a1f-6d6c-4498-8914-7d32023bb815.wav", "formula": "$$\\overset{+4}{\\mathop{{Mn}{{{O}}_{2}}}}\\to \\overset{+2}{\\mathop{{MnC}{{{l}}_{2}}}}$$", "answer": "二氧化锰中锰元素的化合价是正四价 箭头 氯化锰中锰元素的化合价是正二价", "subset": "ChemEquation", "task_type": "tts"} +{"index": 121, "question": "请你朗读以下化学公式符号:${4NO+3}{{{O}}_{{2}}}{+2}{{{H}}_{{2}}}{O}=\\!=\\!={4HN}{{{O}}_{{3}}}$", "audio_path": "audio/chemistry_970abd79-3d95-445f-8070-85052a0303ac.wav", "formula": "${4NO+3}{{{O}}_{{2}}}{+2}{{{H}}_{{2}}}{O}=\\!=\\!={4HN}{{{O}}_{{3}}}$", "answer": "一氧化氮和氧气和水反应生成硝酸", "subset": "ChemEquation", "task_type": "tts"} +{"index": 122, "question": "请你朗读以下化学公式符号:$Na_{2}SiO_{3}+2H^{+}=H_{2}SiO_{3}\\downarrow+2Na^{+}$", "audio_path": "audio/chemistry_8795740b-fe5b-4bde-8d13-0b8ce3e6ed9b.wav", "formula": "$Na_{2}SiO_{3}+2H^{+}=H_{2}SiO_{3}\\downarrow+2Na^{+}$", "answer": "硅酸钠和氢离子反应生成硅酸沉淀和钠离子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 123, "question": "请你朗读以下化学公式符号:$$C_{27}H_{37}N_{3}O_{7}S$$", "audio_path": "audio/chemistry_967f15a3-6975-4680-b10c-4ce172c5257e.wav", "formula": "$$C_{27}H_{37}N_{3}O_{7}S$$", "answer": "一个由二十七个碳原子、三十七个氢原子、三个氮原子、七个氧原子和一个硫原子构成的分子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 124, "question": "请你朗读以下化学公式符号:$$0.8mol/\\left(L⋅s\\right)$$", "audio_path": "audio/chemistry_c151c8dd-af2a-4535-a596-1c10962decbb.wav", "formula": "$$0.8mol/\\left(L⋅s\\right)$$", "answer": "零点八摩尔每升秒", "subset": "ChemEquation", "task_type": "tts"} +{"index": 125, "question": "请你朗读以下化学公式符号:$$Cl_{2}+H_{2}O⇌H^{+}+Cl^{−}+HClO$$", "audio_path": "audio/chemistry_d4e7da7a-8348-4b59-919a-928ea5d5d151.wav", "formula": "$$Cl_{2}+H_{2}O⇌H^{+}+Cl^{−}+HClO$$", "answer": "氯气和水反应生成氢离子、氯离子和次氯酸", "subset": "ChemEquation", "task_type": "tts"} +{"index": 126, "question": "请你朗读以下化学公式符号:${{{C}}_6}{{{H}}_7}{N}$", "audio_path": "audio/chemistry_2ffd4824-5618-401c-9280-67affb3deec9.wav", "formula": "${{{C}}_6}{{{H}}_7}{N}$", "answer": "苯胺", "subset": "ChemEquation", "task_type": "tts"} +{"index": 127, "question": "请你朗读以下化学公式符号:$W+2H^{+}═W^{2+}+H_{2}\\uparrow$", "audio_path": "audio/chemistry_1318f45d-16c9-4c56-83f5-3db6eb0992f6.wav", "formula": "$W+2H^{+}═W^{2+}+H_{2}\\uparrow$", "answer": "W和氢离子反应生成W离子和氢气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 128, "question": "请你朗读以下化学公式符号:$2H_{2}+4OH^{−}-4e^{−}=4H_{2}O$", "audio_path": "audio/chemistry_d67d8173-f4fa-47d8-a10d-bbf64ed69126.wav", "formula": "$2H_{2}+4OH^{−}-4e^{−}=4H_{2}O$", "answer": "两个氢气分子和四个氢氧根离子失去四个电子生成四个水分子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 129, "question": "请你朗读以下化学公式符号:$\\frac{17.4g}{87g/mol}$", "audio_path": "audio/chemistry_396a69d0-fb08-4a0a-83f2-be5687f33cf8.wav", "formula": "$\\frac{17.4g}{87g/mol}$", "answer": "八十七克每摩尔分之十七点四克", "subset": "ChemEquation", "task_type": "tts"} +{"index": 130, "question": "请你朗读以下化学公式符号:$\\frac{c(N{{H}_{4}}^{+})}{c(N{H}_{3}•{H}_{2}O)}$", "audio_path": "audio/chemistry_4ab22480-b34d-4b45-86f2-bab7e7854e2e.wav", "formula": "$\\frac{c(N{{H}_{4}}^{+})}{c(N{H}_{3}•{H}_{2}O)}$", "answer": "一水合氨的浓度分之铵根离子的浓度", "subset": "ChemEquation", "task_type": "tts"} +{"index": 131, "question": "请你朗读以下化学公式符号:$Na_{2}S_{4}O_{6}+2NaI$", "audio_path": "audio/chemistry_33c3259b-1839-44b1-b9e2-aff2fc338981.wav", "formula": "$Na_{2}S_{4}O_{6}+2NaI$", "answer": "四硫代硫酸钠和碘化钠", "subset": "ChemEquation", "task_type": "tts"} +{"index": 132, "question": "请你朗读以下化学公式符号:$$2SO_{2}\\left(g\\right)+O_{2}\\left(g\\right)⇌2SO_{3}\\left(g\\right)$$", "audio_path": "audio/chemistry_319be8dd-1633-49ff-8f94-1f20577bb801.wav", "formula": "$$2SO_{2}\\left(g\\right)+O_{2}\\left(g\\right)⇌2SO_{3}\\left(g\\right)$$", "answer": "两摩尔的气态二氧化硫和一摩尔的气态氧气反应生成两摩尔的气态三氧化硫", "subset": "ChemEquation", "task_type": "tts"} +{"index": 133, "question": "请你朗读以下化学公式符号:$\\left[\\left(NH_{4}\\right)_{2}SO_{4}\\right]$", "audio_path": "audio/chemistry_21165530-361f-447c-87d8-6ceb35d1c2d5.wav", "formula": "$\\left[\\left(NH_{4}\\right)_{2}SO_{4}\\right]$", "answer": "硫酸铵", "subset": "ChemEquation", "task_type": "tts"} +{"index": 134, "question": "请你朗读以下化学公式符号:$2n(\\mathrm{NaOH})=3n(\\mathrm{HCl})=3n(\\mathrm{NH}_4\\mathrm{Cl})$", "audio_path": "audio/chemistry_41f25e8f-5bc7-4322-803e-db15babf6631.wav", "formula": "$2n(\\mathrm{NaOH})=3n(\\mathrm{HCl})=3n(\\mathrm{NH}_4\\mathrm{Cl})$", "answer": "两倍的氢氧化钠的物质的量等于三倍的盐酸的物质的量等于三倍的氯化铵的物质的量", "subset": "ChemEquation", "task_type": "tts"} +{"index": 135, "question": "请你朗读以下化学公式符号:$a{X}+b{Q}=c{Y}+d{Z}$", "audio_path": "audio/chemistry_333f89a5-e7f0-45b3-8366-92e24c59b771.wav", "formula": "$a{X}+b{Q}=c{Y}+d{Z}$", "answer": "X和Q反应生成Y和Z", "subset": "ChemEquation", "task_type": "tts"} +{"index": 136, "question": "请你朗读以下化学公式符号:$7.5\\times10^{7} J/m^{3}$", "audio_path": "audio/chemistry_fc833d96-18c8-4b10-ac93-5048d22b004d.wav", "formula": "$7.5\\times10^{7} J/m^{3}$", "answer": "七点五乘十的七次方焦耳每立方米", "subset": "ChemEquation", "task_type": "tts"} +{"index": 137, "question": "请你朗读以下化学公式符号:$$2I^{−}+2H^{+}+H_{2}O_{2}═I_{2}+2H_{2}O$$", "audio_path": "audio/chemistry_22119163-50b5-4de7-9dce-c4b704cdf858.wav", "formula": "$$2I^{−}+2H^{+}+H_{2}O_{2}═I_{2}+2H_{2}O$$", "answer": "碘离子、氢离子和过氧化氢反应生成碘单质和水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 138, "question": "请你朗读以下化学公式符号:$\\left(ρ=1.84g/cm^3\\right)$", "audio_path": "audio/chemistry_27099177-6e2f-4d12-a63c-c3a5633138d0.wav", "formula": "$\\left(ρ=1.84g/cm^3\\right)$", "answer": "rho等于一点八四克每立方厘米", "subset": "ChemEquation", "task_type": "tts"} +{"index": 139, "question": "请你朗读以下化学公式符号:$2v\\left(H_{2}\\right)=3v\\left(NH_{3}\\right)$", "audio_path": "audio/chemistry_85e1244f-dd9f-4690-912c-472207d1b7a2.wav", "formula": "$2v\\left(H_{2}\\right)=3v\\left(NH_{3}\\right)$", "answer": "二倍氢气的反应速率等于三倍氨气的反应速率", "subset": "ChemEquation", "task_type": "tts"} +{"index": 140, "question": "请你朗读以下化学公式符号:$P^{3-}$", "audio_path": "audio/chemistry_a6f6bfff-a7fc-4e45-a071-841ee3c91c3b.wav", "formula": "$P^{3-}$", "answer": "磷离子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 141, "question": "请你朗读以下化学公式符号:$c\\left(H^{+}\\right)=1×10^{−7}mol⋅L^{−1}$", "audio_path": "audio/chemistry_2064770c-707d-45da-a141-07a948195882.wav", "formula": "$c\\left(H^{+}\\right)=1×10^{−7}mol⋅L^{−1}$", "answer": "氢离子的浓度等于一乘十的负七次方摩尔每升", "subset": "ChemEquation", "task_type": "tts"} +{"index": 142, "question": "请你朗读以下化学公式符号:$${{{K}}_2}{C}{{{O}}_3}+{2HCl}= {2KCl} +{{{H}}_2}{O}+CO_2\\uparrow$$", "audio_path": "audio/chemistry_665ec5d5-60c6-4d19-ab43-d2001b7785b8.wav", "formula": "$${{{K}}_2}{C}{{{O}}_3}+{2HCl}= {2KCl} +{{{H}}_2}{O}+CO_2\\uparrow$$", "answer": "碳酸钾和盐酸反应生成氯化钾、水和二氧化碳", "subset": "ChemEquation", "task_type": "tts"} +{"index": 143, "question": "请你朗读以下化学公式符号:$KCN+CO_{2}+H_{2}O=HCN+KHCO_{3}$", "audio_path": "audio/chemistry_339a60f9-5547-4dcf-89a6-efeac31434ad.wav", "formula": "$KCN+CO_{2}+H_{2}O=HCN+KHCO_{3}$", "answer": "氰化钾、二氧化碳和水反应生成氰化氢和碳酸氢钾", "subset": "ChemEquation", "task_type": "tts"} +{"index": 144, "question": "请你朗读以下化学公式符号:$2Na + 2HCl = 2NaCl + H_2↑$", "audio_path": "audio/chemistry_a6fca2f0-f701-49ad-b6e7-ed0081bee8c2.wav", "formula": "$2Na + 2HCl = 2NaCl + H_2↑$", "answer": "钠和盐酸反应生成氯化钠和氢气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 145, "question": "请你朗读以下化学公式符号:$Cl_{2}+H_{2}O\\rightleftharpoons HCl+HClO$", "audio_path": "audio/chemistry_74d0337c-b981-46ca-8410-a4ce56a807e1.wav", "formula": "$Cl_{2}+H_{2}O\\rightleftharpoons HCl+HClO$", "answer": "氯气和水反应生成盐酸和次氯酸", "subset": "ChemEquation", "task_type": "tts"} +{"index": 146, "question": "请你朗读以下化学公式符号:$Cu(OH)_{2} \\xrightarrow{+NaCl}$", "audio_path": "audio/chemistry_f3bb7fd3-33d7-4a45-9c8a-7b74f888b451.wav", "formula": "$Cu(OH)_{2} \\xrightarrow{+NaCl}$", "answer": "氢氧化铜和氯化钠反应", "subset": "ChemEquation", "task_type": "tts"} +{"index": 147, "question": "请你朗读以下化学公式符号:$S_{2}O^{2−}_{3}+6H^{+}$", "audio_path": "audio/chemistry_890bc7e6-e785-468d-ba2f-2f48b8d74bd9.wav", "formula": "$S_{2}O^{2−}_{3}+6H^{+}$", "answer": "一个硫代硫酸根离子加六个氢离子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 148, "question": "请你朗读以下化学公式符号:$\\frac{2.3g}{23g/mol}$", "audio_path": "audio/chemistry_653b5adc-8946-4c6e-aa4c-0d0c8989ffc8.wav", "formula": "$\\frac{2.3g}{23g/mol}$", "answer": "二十三克每摩尔分之二点三克", "subset": "ChemEquation", "task_type": "tts"} +{"index": 149, "question": "请你朗读以下化学公式符号:$${Mg}{{{F}}_{{2}}}$$", "audio_path": "audio/chemistry_1b9a59a2-d3a3-4a99-8950-1a7c2fb6c875.wav", "formula": "$${Mg}{{{F}}_{{2}}}$$", "answer": "氟化镁", "subset": "ChemEquation", "task_type": "tts"} +{"index": 150, "question": "请你朗读以下化学公式符号:$Al^{3+}+3H_{2}O ⇌ Al\\left(OH\\right)_{3}+3H^{+}$", "audio_path": "audio/chemistry_4e02b77d-9ed2-41b7-8357-ee74ee64c35c.wav", "formula": "$Al^{3+}+3H_{2}O ⇌ Al\\left(OH\\right)_{3}+3H^{+}$", "answer": "铝离子和水反应生成氢氧化铝和氢离子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 151, "question": "请你朗读以下化学公式符号:$C_{17}H_{20}O_{6}N_{4}$", "audio_path": "audio/chemistry_cd880b07-94af-4619-9a7b-b3e1f3982bd6.wav", "formula": "$C_{17}H_{20}O_{6}N_{4}$", "answer": "一个由十七个碳原子、二十个氢原子、六个氧原子和四个氮原子构成的分子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 152, "question": "请你朗读以下化学公式符号:$2N_{2}H_{4}(g)+N_{2}O_{4}(g)═3N_{2}(g)+4H_{2}O(g)$", "audio_path": "audio/chemistry_e5e826ef-79c5-4c77-8c40-355a2c8b604c.wav", "formula": "$2N_{2}H_{4}(g)+N_{2}O_{4}(g)═3N_{2}(g)+4H_{2}O(g)$", "answer": "两摩尔气态肼和一摩尔气态四氧化二氮反应生成三摩尔气态氮气和四摩尔气态水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 153, "question": "请你朗读以下化学公式符号:$△H_{1} C_{2}H_{5}OH$", "audio_path": "audio/chemistry_fb4c6e19-8c60-44f4-b892-415eeb669ffc.wav", "formula": "$△H_{1} C_{2}H_{5}OH$", "answer": "delta H一 乙醇", "subset": "ChemEquation", "task_type": "tts"} +{"index": 154, "question": "请你朗读以下化学公式符号:$25gCuSO_{4}\\cdot 5H_{2}O$", "audio_path": "audio/chemistry_45094d00-416d-4584-85a3-d46f6ab570c2.wav", "formula": "$25gCuSO_{4}\\cdot 5H_{2}O$", "answer": "二十五克五水硫酸铜", "subset": "ChemEquation", "task_type": "tts"} +{"index": 155, "question": "请你朗读以下化学公式符号:$1\\times10^{-7}N_{A}$", "audio_path": "audio/chemistry_734b5555-cc15-477e-9588-2040298447a9.wav", "formula": "$1\\times10^{-7}N_{A}$", "answer": "一乘十的负七次方乘NA", "subset": "ChemEquation", "task_type": "tts"} +{"index": 156, "question": "请你朗读以下化学公式符号:$\\frac{106}{44}=\\frac{10.6~{g}}{x}$", "audio_path": "audio/chemistry_0cfd52c1-ff58-4ee0-b604-43d4964e837f.wav", "formula": "$\\frac{106}{44}=\\frac{10.6~{g}}{x}$", "answer": "四十四分之一百零六等于x分之十点六克", "subset": "ChemEquation", "task_type": "tts"} +{"index": 157, "question": "请你朗读以下化学公式符号:$CaCO_{3}+2H^{+}=Ca^{2+}+H_{2}O+CO_{2}\\uparrow$", "audio_path": "audio/chemistry_fcbfbd88-ad87-473d-922a-c71f0fc837c5.wav", "formula": "$CaCO_{3}+2H^{+}=Ca^{2+}+H_{2}O+CO_{2}\\uparrow$", "answer": "碳酸钙和氢离子反应生成钙离子,水和二氧化碳", "subset": "ChemEquation", "task_type": "tts"} +{"index": 158, "question": "请你朗读以下化学公式符号:$KOH═K^{+}+{OH}^{−}$", "audio_path": "audio/chemistry_be7fb2f0-28e1-4418-83f9-16ffc7982435.wav", "formula": "$KOH═K^{+}+{OH}^{−}$", "answer": "氢氧化钾电离生成钾离子和氢氧根离子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 159, "question": "请你朗读以下化学公式符号:$4{\\mathrm{A}\\mathrm{l}}_{2}{\\mathrm{O}}_{3}+$", "audio_path": "audio/chemistry_ea784825-bdab-4c58-a9ad-f37eb2ada623.wav", "formula": "$4{\\mathrm{A}\\mathrm{l}}_{2}{\\mathrm{O}}_{3}+$", "answer": "四个氧化铝分子加", "subset": "ChemEquation", "task_type": "tts"} +{"index": 160, "question": "请你朗读以下化学公式符号:$Ca^{2+}+OH^{−}+HCO^{−}_{3}=CaCO_{3}\\downarrow+H_{2}O$", "audio_path": "audio/chemistry_cba9c339-c75b-4d6b-9344-b9489b9d8ee8.wav", "formula": "$Ca^{2+}+OH^{−}+HCO^{−}_{3}=CaCO_{3}\\downarrow+H_{2}O$", "answer": "钙离子、氢氧根离子和碳酸氢根离子反应生成碳酸钙沉淀和水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 161, "question": "请你朗读以下化学公式符号:$$\\prescript{89}{39}{\\text{Y}}$$", "audio_path": "audio/chemistry_f5ac37e8-d78f-450f-80f1-448d3e6f671a.wav", "formula": "$$\\prescript{89}{39}{\\text{Y}}$$", "answer": "钇 八十九", "subset": "ChemEquation", "task_type": "tts"} +{"index": 162, "question": "请你朗读以下化学公式符号:$\\left(mol/L\\right)$", "audio_path": "audio/chemistry_5424979c-f8cd-4e06-bcec-b56a327a522f.wav", "formula": "$\\left(mol/L\\right)$", "answer": "摩尔每升", "subset": "ChemEquation", "task_type": "tts"} +{"index": 163, "question": "请你朗读以下化学公式符号:$\\overset{+3}{\\mathop{{Fe}}}\\,{C}{{{l}}_3}$", "audio_path": "audio/chemistry_29b70da3-4aab-4689-9e84-982233a86f20.wav", "formula": "$\\overset{+3}{\\mathop{{Fe}}}\\,{C}{{{l}}_3}$", "answer": "氯化铁 铁元素的化合价是正三价", "subset": "ChemEquation", "task_type": "tts"} +{"index": 164, "question": "请你朗读以下化学公式符号:$${{{K}}_{{2}}}{C}{{{O}}_{{3}}},{CaC}{{{l}}_{{2}}}$$", "audio_path": "audio/chemistry_f787714f-1e28-46ea-8938-bfa00fc8a20c.wav", "formula": "$${{{K}}_{{2}}}{C}{{{O}}_{{3}}},{CaC}{{{l}}_{{2}}}$$", "answer": "碳酸钾,氯化钙", "subset": "ChemEquation", "task_type": "tts"} +{"index": 165, "question": "请你朗读以下化学公式符号:$2A(g) + 2B(g) \\rightleftharpoons C(g) + 3D(g)$", "audio_path": "audio/chemistry_a84efaad-3e7f-4a01-91ab-00201686a7cf.wav", "formula": "$2A(g) + 2B(g) \\rightleftharpoons C(g) + 3D(g)$", "answer": "两摩尔气态A和两摩尔气态B反应生成一摩尔气态C和三摩尔气态D", "subset": "ChemEquation", "task_type": "tts"} +{"index": 166, "question": "请你朗读以下化学公式符号:$$\\left(H_{2}O_{2}\\right)$$", "audio_path": "audio/chemistry_bbaa1250-a838-4663-aee7-86179ee1c9f0.wav", "formula": "$$\\left(H_{2}O_{2}\\right)$$", "answer": "过氧化氢", "subset": "ChemEquation", "task_type": "tts"} +{"index": 167, "question": "请你朗读以下化学公式符号:$$\\left(1\\right)PM2.5$$", "audio_path": "audio/chemistry_b1866f70-dba3-4a26-a03f-c8cce53fd4f3.wav", "formula": "$$\\left(1\\right)PM2.5$$", "answer": "一 PM二点五", "subset": "ChemEquation", "task_type": "tts"} +{"index": 168, "question": "请你朗读以下化学公式符号:$({{{C}}_2}{{{H}}_5}{OH})$", "audio_path": "audio/chemistry_a8a77221-b69e-41ea-ad3d-a60709c399de.wav", "formula": "$({{{C}}_2}{{{H}}_5}{OH})$", "answer": "乙醇", "subset": "ChemEquation", "task_type": "tts"} +{"index": 169, "question": "请你朗读以下化学公式符号:$\\left(Lewis\\right)$", "audio_path": "audio/chemistry_6811aa97-09f3-4aed-badf-f13f22bd778b.wav", "formula": "$\\left(Lewis\\right)$", "answer": "路易斯", "subset": "ChemEquation", "task_type": "tts"} +{"index": 170, "question": "请你朗读以下化学公式符号:$MgCO_{3}+MgO+CO_{2}$", "audio_path": "audio/chemistry_d94c3e6f-6618-4fd4-b7c8-2b4eea977e45.wav", "formula": "$MgCO_{3}+MgO+CO_{2}$", "answer": "碳酸镁加氧化镁加二氧化碳", "subset": "ChemEquation", "task_type": "tts"} +{"index": 171, "question": "请你朗读以下化学公式符号:$$Fe\\left(Cu\\right),$$", "audio_path": "audio/chemistry_0078b940-d0ac-47ea-820f-20553caeeb76.wav", "formula": "$$Fe\\left(Cu\\right),$$", "answer": "铁(铜)", "subset": "ChemEquation", "task_type": "tts"} +{"index": 172, "question": "请你朗读以下化学公式符号:$\\frac{V}{V_{m}} N_{A}$", "audio_path": "audio/chemistry_fe92ab18-28a5-499a-8bd6-eb69c9b2e79d.wav", "formula": "$\\frac{V}{V_{m}} N_{A}$", "answer": "摩尔体积分之体积乘阿伏加德罗常数", "subset": "ChemEquation", "task_type": "tts"} +{"index": 173, "question": "请你朗读以下化学公式符号:$O(g) \\Delta H=+44.0\\,\\mathrm{kJ}\\cdot\\mathrm{mol}^{-1}$", "audio_path": "audio/chemistry_c133e046-7a0b-4332-a981-0e93befba10e.wav", "formula": "$O(g) \\Delta H=+44.0\\,\\mathrm{kJ}\\cdot\\mathrm{mol}^{-1}$", "answer": "一摩尔的气态氧气 delth H等于正四十四点零千焦每摩尔", "subset": "ChemEquation", "task_type": "tts"} +{"index": 174, "question": "请你朗读以下化学公式符号:$△H_{1}=△H_{2}<△H_{3}$", "audio_path": "audio/chemistry_7d8764c4-ff92-4c8d-8774-50595ac89460.wav", "formula": "$△H_{1}=△H_{2}<△H_{3}$", "answer": "delta H 一等于delta H 二小于delta H 三", "subset": "ChemEquation", "task_type": "tts"} +{"index": 175, "question": "请你朗读以下化学公式符号:$1.0\\times10^{−7}mol⋅L^{−1}$", "audio_path": "audio/chemistry_30934043-7c76-4d13-b7dc-7048f1f41c53.wav", "formula": "$1.0\\times10^{−7}mol⋅L^{−1}$", "answer": "一点零乘十的负七次方摩尔每升", "subset": "ChemEquation", "task_type": "tts"} +{"index": 176, "question": "请你朗读以下化学公式符号:$W = \\frac{17V}{17V+22400}$", "audio_path": "audio/chemistry_e6c83d87-d5cc-42f8-9e0e-61454d63914d.wav", "formula": "$W = \\frac{17V}{17V+22400}$", "answer": "W等于十七乘V的积加两万两千四百的和分之十七乘V", "subset": "ChemEquation", "task_type": "tts"} +{"index": 177, "question": "请你朗读以下化学公式符号:$2A (g) +B(g) =2C(g)$", "audio_path": "audio/chemistry_44fa661e-2f6f-4abd-ac75-b4a0e7380e60.wav", "formula": "$2A (g) +B(g) =2C(g)$", "answer": "两摩尔的气态A和一摩尔的气态B反应生成两摩尔的气态C", "subset": "ChemEquation", "task_type": "tts"} +{"index": 178, "question": "请你朗读以下化学公式符号:$c\\left(CO_{2}\\right)=c\\left(CO\\right)$", "audio_path": "audio/chemistry_33be68c1-dbf5-4312-8a0d-913e27249fef.wav", "formula": "$c\\left(CO_{2}\\right)=c\\left(CO\\right)$", "answer": "二氧化碳的浓度等于一氧化碳的浓度", "subset": "ChemEquation", "task_type": "tts"} +{"index": 179, "question": "请你朗读以下化学公式符号:$$N_{2}\\left(g\\right)$$", "audio_path": "audio/chemistry_e52542e5-32d3-4972-82a9-954f9915a6ac.wav", "formula": "$$N_{2}\\left(g\\right)$$", "answer": "一摩尔的气态氮气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 180, "question": "请你朗读以下化学公式符号:$4P+5O_{2}\\xlongequal{点燃} 2P_{2}O_5$", "audio_path": "audio/chemistry_ea999126-78e1-4736-9a9e-e119f4b31f67.wav", "formula": "$4P+5O_{2}\\xlongequal{点燃} 2P_{2}O_5$", "answer": "磷和氧气在点燃的条件下反应生成五氧化二磷", "subset": "ChemEquation", "task_type": "tts"} +{"index": 181, "question": "请你朗读以下化学公式符号:$$CaCO_{3}$$、$$NaCl$$", "audio_path": "audio/chemistry_edcffa66-899c-4309-94bf-dcf0817ffbba.wav", "formula": "$$CaCO_{3}$$、$$NaCl$$", "answer": "碳酸钙、氯化钠", "subset": "ChemEquation", "task_type": "tts"} +{"index": 182, "question": "请你朗读以下化学公式符号:$\\xrightarrow[1100℃]{H_{2}}$", "audio_path": "audio/chemistry_9c75a9e1-6091-44fa-912c-e5a0c3484882.wav", "formula": "$\\xrightarrow[1100℃]{H_{2}}$", "answer": "在氢气和一千一百摄氏度条件下反应", "subset": "ChemEquation", "task_type": "tts"} +{"index": 183, "question": "请你朗读以下化学公式符号:$$1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{5}4s^{2}$$", "audio_path": "audio/chemistry_2cdde74b-6029-41c6-aebb-1b7aa28a2542.wav", "formula": "$$1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{5}4s^{2}$$", "answer": "一s 轨道填充 两 个电子,二s 轨道填充 两 个电子,二p 轨道填充 六 个电子,三s 轨道填充 两 个电子,三p 轨道填充 六 个电子,三d 轨道填充五 个电子,四S 轨道填充 两 个电子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 184, "question": "请你朗读以下化学公式符号:$50mL 0.5mol/L KNO_{3}$", "audio_path": "audio/chemistry_83a3c1ab-03dc-4fc2-999c-7b7186926e8d.wav", "formula": "$50mL 0.5mol/L KNO_{3}$", "answer": "五十毫升零点五摩尔每升硝酸钾", "subset": "ChemEquation", "task_type": "tts"} +{"index": 185, "question": "请你朗读以下化学公式符号:$\\left(NH_{3}\\right)$", "audio_path": "audio/chemistry_b5a8ca8f-03c1-4e92-8ebf-4853aad1ecc7.wav", "formula": "$\\left(NH_{3}\\right)$", "answer": "氨气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 186, "question": "请你朗读以下化学公式符号:$Cu+2Ag^{+}=Cu^{2+}+2Ag$", "audio_path": "audio/chemistry_be17df51-d840-4992-bdc2-7e7fc5f92645.wav", "formula": "$Cu+2Ag^{+}=Cu^{2+}+2Ag$", "answer": "铜和银离子反应生成铜离子和银", "subset": "ChemEquation", "task_type": "tts"} +{"index": 187, "question": "请你朗读以下化学公式符号:$$2NaCl+H_{2}SO_{4}$$", "audio_path": "audio/chemistry_f55ecaa7-7453-43d1-8775-939a2a780037.wav", "formula": "$$2NaCl+H_{2}SO_{4}$$", "answer": "两个氯化钠加一个硫酸", "subset": "ChemEquation", "task_type": "tts"} +{"index": 188, "question": "请你朗读以下化学公式符号:$$mX\\left(g\\right)⇌nY\\left(g\\right)$$", "audio_path": "audio/chemistry_33358729-b6fc-4849-9689-e2e65e575610.wav", "formula": "$$mX\\left(g\\right)⇌nY\\left(g\\right)$$", "answer": "m摩尔气态X分解生成n摩尔气态Y", "subset": "ChemEquation", "task_type": "tts"} +{"index": 189, "question": "请你朗读以下化学公式符号:$$\\left(1\\right)2Fe^{3+}+2I^{−}=2Fe^{2+}+I_{2}$$", "audio_path": "audio/chemistry_611189f0-6b7e-42c1-acb2-281682039c9c.wav", "formula": "$$\\left(1\\right)2Fe^{3+}+2I^{−}=2Fe^{2+}+I_{2}$$", "answer": "一 铁离子和碘离子反应生成亚铁离子和碘", "subset": "ChemEquation", "task_type": "tts"} +{"index": 190, "question": "请你朗读以下化学公式符号:$$ (NH_{4})_{2}SO_{4} $$", "audio_path": "audio/chemistry_e19eaadb-d8e8-45e0-bd57-413962382689.wav", "formula": "$$ (NH_{4})_{2}SO_{4} $$", "answer": "硫酸铵", "subset": "ChemEquation", "task_type": "tts"} +{"index": 191, "question": "请你朗读以下化学公式符号:$2KMnO_{4}+16HCl=2KCl+2MnCl_{2}+5Cl_{2}\\uparrow+8H_{2}O$", "audio_path": "audio/chemistry_5379066e-6c85-4907-a8a4-d420db9b7ddc.wav", "formula": "$2KMnO_{4}+16HCl=2KCl+2MnCl_{2}+5Cl_{2}\\uparrow+8H_{2}O$", "answer": "高锰酸钾和盐酸反应生成氯化钾、氯化锰、氯气和水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 192, "question": "请你朗读以下化学公式符号:$0.1mol/LCH_{3}COOH$", "audio_path": "audio/chemistry_c3f0f5a2-bff6-413d-a2d7-580bff33a8b9.wav", "formula": "$0.1mol/LCH_{3}COOH$", "answer": "零点一摩尔每升乙酸", "subset": "ChemEquation", "task_type": "tts"} +{"index": 193, "question": "请你朗读以下化学公式符号:$HXO_{4}>HYO_{4}>HZO_{4}$", "audio_path": "audio/chemistry_ffab6f45-b046-4efd-9edd-3751b29a316f.wav", "formula": "$HXO_{4}>HYO_{4}>HZO_{4}$", "answer": "高X酸大于高Y酸大于高Z酸", "subset": "ChemEquation", "task_type": "tts"} +{"index": 194, "question": "请你朗读以下化学公式符号:$$⑴H_{2}(g) + 0.5O_{2}(g) =H_{2}O(g)$$", "audio_path": "audio/chemistry_ea6619d0-2325-487a-a8fb-e97e0b7c0f96.wav", "formula": "$$⑴H_{2}(g) + 0.5O_{2}(g) =H_{2}O(g)$$", "answer": "一 一摩尔的气态氢气体和零点五摩尔的气态氧气反应生成一摩尔的气态水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 195, "question": "请你朗读以下化学公式符号:$△H=+2\\times283.0kJ/mol$", "audio_path": "audio/chemistry_c10be224-3583-4085-bb23-1b2fb4be3ca0.wav", "formula": "$△H=+2\\times283.0kJ/mol$", "answer": "delta H等于正二乘二百八十三点零千焦每摩尔", "subset": "ChemEquation", "task_type": "tts"} +{"index": 196, "question": "请你朗读以下化学公式符号:$\\left(C_{15}H_{22}O_{2}\\right)$", "audio_path": "audio/chemistry_4244ddf3-a5bf-4439-b2a0-fb82656c87ff.wav", "formula": "$\\left(C_{15}H_{22}O_{2}\\right)$", "answer": "一个由十五个碳原子、二十二个氢原子和两个氧原子构成的分子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 197, "question": "请你朗读以下化学公式符号:${1 mol Cl}{{{O}}_2}$", "audio_path": "audio/chemistry_46292208-ab29-467d-ac5c-e88f6fc49b9b.wav", "formula": "${1 mol Cl}{{{O}}_2}$", "answer": "一摩尔二氧化氯", "subset": "ChemEquation", "task_type": "tts"} +{"index": 198, "question": "请你朗读以下化学公式符号:$$C_{20}H_{14}O_{4}$$", "audio_path": "audio/chemistry_430b6143-12e2-49a0-9fc0-85d07f0544b1.wav", "formula": "$$C_{20}H_{14}O_{4}$$", "answer": "酚酞", "subset": "ChemEquation", "task_type": "tts"} +{"index": 199, "question": "请你朗读以下化学公式符号:$\\frac{0.9 {\\rm mol}}{0.2 {\\rm L}}=4.5 \\rm mol/L$", "audio_path": "audio/chemistry_c259d151-540c-4b44-980c-0c17414166e4.wav", "formula": "$\\frac{0.9 {\\rm mol}}{0.2 {\\rm L}}=4.5 \\rm mol/L$", "answer": "零点二升分之零点九摩尔等于四点五摩尔每升", "subset": "ChemEquation", "task_type": "tts"} +{"index": 200, "question": "请你朗读以下化学公式符号:$NaCl \\left(Na_{2}CO_{3}\\right)$", "audio_path": "audio/chemistry_567f32f2-b599-49f0-a71f-9e8d8ded4fc2.wav", "formula": "$NaCl \\left(Na_{2}CO_{3}\\right)$", "answer": "氯化钠(碳酸钠)", "subset": "ChemEquation", "task_type": "tts"} +{"index": 201, "question": "请你朗读以下化学公式符号:$Na_{2}S_{2}O_{3}+2HCl=2NaCl+S\\downarrow+SO_{2}\\uparrow+H_{2}O$", "audio_path": "audio/chemistry_520557f2-c78c-4bfb-9d8d-0b9c2ac01f8b.wav", "formula": "$Na_{2}S_{2}O_{3}+2HCl=2NaCl+S\\downarrow+SO_{2}\\uparrow+H_{2}O$", "answer": "硫代硫酸钠和盐酸反应生成氯化钠、硫单质、二氧化硫气体和水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 202, "question": "请你朗读以下化学公式符号:$$Cu+4H^{+}+2NO^{−}_{3}═Cu^{2+}+2NO_{2}\\uparrow+2H_{2}O$$", "audio_path": "audio/chemistry_e71873d7-c490-4121-8ed9-6f4cb494273f.wav", "formula": "$$Cu+4H^{+}+2NO^{−}_{3}═Cu^{2+}+2NO_{2}\\uparrow+2H_{2}O$$", "answer": "铜、氢离子和硝酸根离子反应生成铜离子、二氧化氮和水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 203, "question": "请你朗读以下化学公式符号:$Fe\\left(Fe_{2}O_{3}\\right)$", "audio_path": "audio/chemistry_19b8e4d7-ea1f-4b90-aca7-627ccb9d1e82.wav", "formula": "$Fe\\left(Fe_{2}O_{3}\\right)$", "answer": "铁(氧化铁)", "subset": "ChemEquation", "task_type": "tts"} +{"index": 204, "question": "请你朗读以下化学公式符号:$6Fe^{3+}+16Cl^{−}+5I_{2}$", "audio_path": "audio/chemistry_849cf93d-24f8-40ba-9062-858c84665c5e.wav", "formula": "$6Fe^{3+}+16Cl^{−}+5I_{2}$", "answer": "六个铁离子加十六个氯离子加五个碘分子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 205, "question": "请你朗读以下化学公式符号:$1s^{2}2s^{2}2p^{2}$", "audio_path": "audio/chemistry_d718b356-d71a-4fde-81b2-5786f2571ed5.wav", "formula": "$1s^{2}2s^{2}2p^{2}$", "answer": "一s轨道填充两个电子,二s轨道填充两个电子,二p轨道填充两个电子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 206, "question": "请你朗读以下化学公式符号:$$C_{14}H_{12}O_{3}$", "audio_path": "audio/chemistry_0719a5f9-f3c3-45e5-b8e2-0ef846c229b5.wav", "formula": "$$C_{14}H_{12}O_{3}$", "answer": "一个由十四个碳原子、十二个氢原子和三个氧原子构成的分子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 207, "question": "请你朗读以下化学公式符号:$\\mathrm{Cu}(\\mathrm{NO_3})_2$", "audio_path": "audio/chemistry_f2729a99-e7b9-4ff0-85a3-ac57c02c85ae.wav", "formula": "$\\mathrm{Cu}(\\mathrm{NO_3})_2$", "answer": "硝酸铜", "subset": "ChemEquation", "task_type": "tts"} +{"index": 208, "question": "请你朗读以下化学公式符号:$Mg+2H_{2}O=Mg\\left(OH\\right)_{2}+H_{2}\\uparrow$", "audio_path": "audio/chemistry_3fb2f149-2029-462d-a1f8-2f3c26e00ef6.wav", "formula": "$Mg+2H_{2}O=Mg\\left(OH\\right)_{2}+H_{2}\\uparrow$", "answer": "镁和水反应生成氢氧化镁和氢气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 209, "question": "请你朗读以下化学公式符号:$${Fe}+{CuS}{{{O}}_4}={FeS}{{{O}}_4}+{Cu}$$", "audio_path": "audio/chemistry_306a2c83-816b-45dc-b579-f2196ae60e55.wav", "formula": "$${Fe}+{CuS}{{{O}}_4}={FeS}{{{O}}_4}+{Cu}$$", "answer": "铁和硫酸铜反应生成硫酸亚铁和铜", "subset": "ChemEquation", "task_type": "tts"} +{"index": 210, "question": "请你朗读以下化学公式符号:$$\\mathrm{Ca(OH)_2 + Na_2CO_3 = CaCO_3 \\downarrow + 2NaOH}$$", "audio_path": "audio/chemistry_acb6ec88-7678-4f2f-87de-953d28026414.wav", "formula": "$$\\mathrm{Ca(OH)_2 + Na_2CO_3 = CaCO_3 \\downarrow + 2NaOH}$$", "answer": "氢氧化钙和碳酸钠反应生成碳酸钙沉淀和氢氧化钠", "subset": "ChemEquation", "task_type": "tts"} +{"index": 211, "question": "请你朗读以下化学公式符号:$2Na_{2}O_{2}+2H_{2}O═4Na^{+}+4OH^{−}+O_{2}\\uparrow$", "audio_path": "audio/chemistry_be3f25ba-6a57-4eea-8548-96e031fbbab2.wav", "formula": "$2Na_{2}O_{2}+2H_{2}O═4Na^{+}+4OH^{−}+O_{2}\\uparrow$", "answer": "过氧化钠和水反应生成钠离子、氢氧根离子和氧气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 212, "question": "请你朗读以下化学公式符号:$$\\xrightarrow{H_{2}SO_{4}}$$", "audio_path": "audio/chemistry_dbba42e7-67e2-4009-97d0-6a0bcf45ec19.wav", "formula": "$$\\xrightarrow{H_{2}SO_{4}}$$", "answer": "在硫酸的条件下反应", "subset": "ChemEquation", "task_type": "tts"} +{"index": 213, "question": "请你朗读以下化学公式符号:$Zn+H_{2}SO_{4}= ZnSO_{4}+H_{2}\\uparrow$", "audio_path": "audio/chemistry_5ce2de7b-30b6-4e48-ad4e-27d9941767fa.wav", "formula": "$Zn+H_{2}SO_{4}= ZnSO_{4}+H_{2}\\uparrow$", "answer": "锌和硫酸反应生成硫酸锌和氢气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 214, "question": "请你朗读以下化学公式符号:$2CH_{3}OH\\left(l\\right)+3O_{2}\\left(g\\right)$", "audio_path": "audio/chemistry_78ed6e7d-8a78-426c-b29d-221ce4b08b68.wav", "formula": "$2CH_{3}OH\\left(l\\right)+3O_{2}\\left(g\\right)$", "answer": "两摩尔液态甲醇加三摩尔气态氧气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 215, "question": "请你朗读以下化学公式符号:$HCOOCH_{3}(g)+2H_{2}(g)$", "audio_path": "audio/chemistry_65e95305-672a-46c6-84ae-dd1adcece627.wav", "formula": "$HCOOCH_{3}(g)+2H_{2}(g)$", "answer": "一摩尔气态甲酸甲酯加两摩尔气态氢气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 216, "question": "请你朗读以下化学公式符号:$2H_{2}(g)+O_{2}(g)$", "audio_path": "audio/chemistry_413264b7-0686-4fc3-a655-e6075cc8e40e.wav", "formula": "$2H_{2}(g)+O_{2}(g)$", "answer": "两摩尔的气态氢气和一摩尔的气态氧气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 217, "question": "请你朗读以下化学公式符号:$$F_{2}< Cl_{2}< Br_{2}< I_{2}$$", "audio_path": "audio/chemistry_c95cf0df-7c77-4d14-ad6c-561d736a76a7.wav", "formula": "$$F_{2}< Cl_{2}< Br_{2}< I_{2}$$", "answer": "氟气小于氯气小于溴单质小于碘单质", "subset": "ChemEquation", "task_type": "tts"} +{"index": 218, "question": "请你朗读以下化学公式符号:$\\left(C_{2}H_{5}OH\\right),$", "audio_path": "audio/chemistry_6e701e2f-c9b4-4c73-ac6e-2dfb9f82c843.wav", "formula": "$\\left(C_{2}H_{5}OH\\right),$", "answer": "乙醇", "subset": "ChemEquation", "task_type": "tts"} +{"index": 219, "question": "请你朗读以下化学公式符号:$HClO_{3} > H_{2}SO_{4}$", "audio_path": "audio/chemistry_3979eada-c188-4ac9-b778-586395abc830.wav", "formula": "$HClO_{3} > H_{2}SO_{4}$", "answer": "氯酸大于硫酸", "subset": "ChemEquation", "task_type": "tts"} +{"index": 220, "question": "请你朗读以下化学公式符号:$mol/L$ $1.0$ $0.50$", "audio_path": "audio/chemistry_40aa8ab1-c74e-4a30-a16c-25a5ba24e534.wav", "formula": "$mol/L$ $1.0$ $0.50$", "answer": "摩尔每升 一点零 零点五零", "subset": "ChemEquation", "task_type": "tts"} +{"index": 221, "question": "请你朗读以下化学公式符号:$1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{5}$", "audio_path": "audio/chemistry_a09b7fa7-f8a4-411f-8afb-44c573ed03e2.wav", "formula": "$1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{5}$", "answer": "一s 轨道填充两个电子,二s 轨道填充两个电子,二p 轨道填充 六个电子,三s 轨道填充 两个电子,三p 轨道填充六个电子,三d 轨道填充 五个电子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 222, "question": "请你朗读以下化学公式符号:$Al^{3+} + 3NH_{3} \\cdot H_{2}O = Al(OH)_{3} \\downarrow + 3NH_{4}^{+}$", "audio_path": "audio/chemistry_2ad02801-b09c-4d5b-9dcd-cbd57917a381.wav", "formula": "$Al^{3+} + 3NH_{3} \\cdot H_{2}O = Al(OH)_{3} \\downarrow + 3NH_{4}^{+}$", "answer": "铝离子和一水合氨反应生成氢氧化铝沉淀和铵根离子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 223, "question": "请你朗读以下化学公式符号:$$(NH_{4})_{2}SO_{4}$$", "audio_path": "audio/chemistry_3710d12c-39e6-4df4-b8a6-6ecc703cc869.wav", "formula": "$$(NH_{4})_{2}SO_{4}$$", "answer": "硫酸铵", "subset": "ChemEquation", "task_type": "tts"} +{"index": 224, "question": "请你朗读以下化学公式符号:$Fe_{2}O_{3}+3NaNO_{3}+4NaOH═2Na_{2}FeO_{4}+3NaNO_{2}+2X$", "audio_path": "audio/chemistry_0df2dbb6-5511-45cd-a919-757d930ce222.wav", "formula": "$Fe_{2}O_{3}+3NaNO_{3}+4NaOH═2Na_{2}FeO_{4}+3NaNO_{2}+2X$", "answer": "氧化铁,硝酸钠和氢氧化钠反应生成高铁酸钠,亚硝酸钠和X", "subset": "ChemEquation", "task_type": "tts"} +{"index": 225, "question": "请你朗读以下化学公式符号:$Al{^{3+}}+3NH_{3}•H_{2}O═Al(OH)_{3}\\downarrow+3NH_{4} {^{+}}$", "audio_path": "audio/chemistry_b259f907-79e3-4bc4-bd32-0fdafd382c40.wav", "formula": "$Al{^{3+}}+3NH_{3}•H_{2}O═Al(OH)_{3}\\downarrow+3NH_{4} {^{+}}$", "answer": "铝离子和一水合氨反应生成氢氧化铝沉淀和铵根离子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 226, "question": "请你朗读以下化学公式符号:$\\left(K_{2}CO_{3}\\right)$", "audio_path": "audio/chemistry_1aa8cc57-4e40-40a7-a3bd-e59fe7d599ed.wav", "formula": "$\\left(K_{2}CO_{3}\\right)$", "answer": "碳酸钾", "subset": "ChemEquation", "task_type": "tts"} +{"index": 227, "question": "请你朗读以下化学公式符号:${Ca}{{({HC}{{O}_3})}_2}$", "audio_path": "audio/chemistry_fe133c87-5718-404b-b5ee-141a355cd604.wav", "formula": "${Ca}{{({HC}{{O}_3})}_2}$", "answer": "碳酸氢钙", "subset": "ChemEquation", "task_type": "tts"} +{"index": 228, "question": "请你朗读以下化学公式符号:$\\frac{39}{158}\\times 100\\%=24.7\\%$", "audio_path": "audio/chemistry_5f7faa71-ef3c-4736-b2ae-ca78aa451927.wav", "formula": "$\\frac{39}{158}\\times 100\\%=24.7\\%$", "answer": "一百五十八分之三十九乘百分之百等于百分之二十四点七", "subset": "ChemEquation", "task_type": "tts"} +{"index": 229, "question": "请你朗读以下化学公式符号:$\\left(Na_{2}SiO_{3}\\right)$", "audio_path": "audio/chemistry_9c5f7d9d-95fc-46cd-a398-9ce9e7fc4b79.wav", "formula": "$\\left(Na_{2}SiO_{3}\\right)$", "answer": "硅酸钠", "subset": "ChemEquation", "task_type": "tts"} +{"index": 230, "question": "请你朗读以下化学公式符号:$$\\frac{49g}{98g/mol}$$", "audio_path": "audio/chemistry_da628405-c3cc-4665-8ca6-f82c68bfe131.wav", "formula": "$$\\frac{49g}{98g/mol}$$", "answer": "九十八克每摩尔分之四十九克", "subset": "ChemEquation", "task_type": "tts"} +{"index": 231, "question": "请你朗读以下化学公式符号:$CO_2+H_2O\\rightleftharpoons {H_{2}CO_{3}}$", "audio_path": "audio/chemistry_c43ef3f3-a189-4009-8520-0d76d53ea5ec.wav", "formula": "$CO_2+H_2O\\rightleftharpoons {H_{2}CO_{3}}$", "answer": "二氧化碳和水反应生成碳酸", "subset": "ChemEquation", "task_type": "tts"} +{"index": 232, "question": "请你朗读以下化学公式符号:$OH^{−}+HCO^{−}_{3}═CO^{2−}_{3}+H_{2}O$", "audio_path": "audio/chemistry_4d30f010-c1c2-4b25-a34d-505bb98fe284.wav", "formula": "$OH^{−}+HCO^{−}_{3}═CO^{2−}_{3}+H_{2}O$", "answer": "氢氧根离子和碳酸氢根离子反应生成碳酸根离子和水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 233, "question": "请你朗读以下化学公式符号:$PH_{3}>H_{2}S>HCl>HF$", "audio_path": "audio/chemistry_d626070a-a8ae-4002-9f18-6b4de10af385.wav", "formula": "$PH_{3}>H_{2}S>HCl>HF$", "answer": "磷化氢大于硫化氢大于氯化氢大于氟化氢", "subset": "ChemEquation", "task_type": "tts"} +{"index": 234, "question": "请你朗读以下化学公式符号:$C_{2}H_{5}O_{6}Na_{2}Br_{3}Hg$", "audio_path": "audio/chemistry_50193239-1d91-45bd-804a-175300bd102d.wav", "formula": "$C_{2}H_{5}O_{6}Na_{2}Br_{3}Hg$", "answer": "一个由两个碳原子、五个氢原子、六个氧原子、两个钠原子、三个溴原子和一个汞原子构成的分子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 235, "question": "请你朗读以下化学公式符号:$${A}{{{g}}}_{2}{O}$$", "audio_path": "audio/chemistry_c0da192c-ea30-4811-ae58-7189083d99c3.wav", "formula": "$${A}{{{g}}}_{2}{O}$$", "answer": "氧化银", "subset": "ChemEquation", "task_type": "tts"} +{"index": 236, "question": "请你朗读以下化学公式符号:${{H}_2}{C}{{O}_3}$", "audio_path": "audio/chemistry_d91fb3ab-1efc-4152-a8f7-86ed5b7e3783.wav", "formula": "${{H}_2}{C}{{O}_3}$", "answer": "碳酸", "subset": "ChemEquation", "task_type": "tts"} +{"index": 237, "question": "请你朗读以下化学公式符号:$2HCO^{−}_{3}+Ba^{2+}+2H^{+}+SO^{2−}_{4}═BaSO_{4}\\downarrow+2H_{2}O+2CO_{2}\\uparrow$", "audio_path": "audio/chemistry_571bfcf0-1eff-49f5-899c-a77a817a94f4.wav", "formula": "$2HCO^{−}_{3}+Ba^{2+}+2H^{+}+SO^{2−}_{4}═BaSO_{4}\\downarrow+2H_{2}O+2CO_{2}\\uparrow$", "answer": "碳酸氢根离子、钡离子、氢离子和硫酸根离子反应生成硫酸钡沉淀、水和二氧化碳气体", "subset": "ChemEquation", "task_type": "tts"} +{"index": 238, "question": "请你朗读以下化学公式符号:$CaO(s)+H_{2}O(l)$", "audio_path": "audio/chemistry_dd0a4e3e-b4d4-4bac-86b9-ee902d08faf4.wav", "formula": "$CaO(s)+H_{2}O(l)$", "answer": "一摩尔固态氧化钙加一摩尔液态水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 239, "question": "请你朗读以下化学公式符号:$$=1\\times \\frac4{1\\times12+4\\times1+1\\times16}\\times100 \\%=12.5 \\%$$", "audio_path": "audio/chemistry_8777baed-b35c-4929-bc9a-c4f1161d79ab.wav", "formula": "$$=1\\times \\frac4{1\\times12+4\\times1+1\\times16}\\times100 \\%=12.5 \\%$$", "answer": "等于一乘一乘十二加四乘一加一乘十六分之四,再乘百分之百等于百分之十二点五", "subset": "ChemEquation", "task_type": "tts"} +{"index": 240, "question": "请你朗读以下化学公式符号:$$H_{2}+O_{2}→H_{2}O$$", "audio_path": "audio/chemistry_8aa145be-824e-4e5d-87fe-cda36688f36d.wav", "formula": "$$H_{2}+O_{2}→H_{2}O$$", "answer": "氢气和氧气反应生成水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 241, "question": "请你朗读以下化学公式符号:$NO_{2}+SO⇌NO+SO_{3}$", "audio_path": "audio/chemistry_7d9c4030-969d-44e0-aa9a-81f74869177c.wav", "formula": "$NO_{2}+SO⇌NO+SO_{3}$", "answer": "二氧化氮和二氧化硫反应生成一氧化氮和三氧化硫", "subset": "ChemEquation", "task_type": "tts"} +{"index": 242, "question": "请你朗读以下化学公式符号:$$\\left(C_{15}H_{10}O_{2}\\right)$$", "audio_path": "audio/chemistry_9e32ac46-c44d-4b37-bc80-39207283649c.wav", "formula": "$$\\left(C_{15}H_{10}O_{2}\\right)$$", "answer": "一个由十五个碳原子、十个氢原子和两个氧原子构成的分子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 243, "question": "请你朗读以下化学公式符号:$c\\left(N_{2}\\right):c\\left(H_{2}\\right):c\\left(NH_{3}\\right)=1:3:2$", "audio_path": "audio/chemistry_5218aaf5-0814-44e1-8c39-2e698d3565c9.wav", "formula": "$c\\left(N_{2}\\right):c\\left(H_{2}\\right):c\\left(NH_{3}\\right)=1:3:2$", "answer": "氮气的浓度比氢气的浓度比氨气的浓度等于一比三比二", "subset": "ChemEquation", "task_type": "tts"} +{"index": 244, "question": "请你朗读以下化学公式符号:$2S^{2−}+2Br^{−}+3Cl_{2}=2S\\downarrow+Br_{2}+6Cl^{−}$", "audio_path": "audio/chemistry_e9efbb91-bed2-4e19-875d-bd56fffb7c8e.wav", "formula": "$2S^{2−}+2Br^{−}+3Cl_{2}=2S\\downarrow+Br_{2}+6Cl^{−}$", "answer": "硫离子、溴离子和氯气反应生成硫单质、溴单质和氯离子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 245, "question": "请你朗读以下化学公式符号:${BiC}{{{l}}_{5}}={BiC}{{{l}}_{3}}+{C}{{{l}}_{2}}$", "audio_path": "audio/chemistry_88864a55-10be-4b7c-b346-84d03a3b7c11.wav", "formula": "${BiC}{{{l}}_{5}}={BiC}{{{l}}_{3}}+{C}{{{l}}_{2}}$", "answer": "五氯化铋分解生成三氯化铋和氯气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 246, "question": "请你朗读以下化学公式符号:$3.986\\times10^{−26}kg$", "audio_path": "audio/chemistry_0ac4dd9c-c4fa-4a94-9b4f-c3ed762ceb98.wav", "formula": "$3.986\\times10^{−26}kg$", "answer": "三点九八六乘十的负二十六次方千克", "subset": "ChemEquation", "task_type": "tts"} +{"index": 247, "question": "请你朗读以下化学公式符号:$Cu(OH)_{2}+2HCl=CuCl_{2}+2H_{2}O$", "audio_path": "audio/chemistry_3c080f2e-b7ca-4917-b749-a9a6ea6f8ee9.wav", "formula": "$Cu(OH)_{2}+2HCl=CuCl_{2}+2H_{2}O$", "answer": "氢氧化铜和盐酸反应生成氯化铜和水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 248, "question": "请你朗读以下化学公式符号:$$\\left(IUPAC\\right)2012$$", "audio_path": "audio/chemistry_c6b83c16-9ca8-4b82-98f6-bcf66df67a59.wav", "formula": "$$\\left(IUPAC\\right)2012$$", "answer": "IUPAC二零一二", "subset": "ChemEquation", "task_type": "tts"} +{"index": 249, "question": "请你朗读以下化学公式符号:$Ca(HCO_{3})_{2}\\xlongequal{\\text{△}}CaCO_{3}\\downarrow+H_{2}O+CO_{2}\\uparrow$", "audio_path": "audio/chemistry_5b28e64b-a2aa-4574-9cd4-4580f7d76811.wav", "formula": "$Ca(HCO_{3})_{2}\\xlongequal{\\text{△}}CaCO_{3}\\downarrow+H_{2}O+CO_{2}\\uparrow$", "answer": "碳酸氢钙在加热的条件下反应生成碳酸钙沉淀、水和二氧化碳气体", "subset": "ChemEquation", "task_type": "tts"} +{"index": 250, "question": "请你朗读以下化学公式符号:$2Na_{2}CO_{3}+O_{2},$", "audio_path": "audio/chemistry_8189f3ab-b27f-4284-b58c-dd21e7a3cd00.wav", "formula": "$2Na_{2}CO_{3}+O_{2},$", "answer": "两个碳酸钠加一个氧气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 251, "question": "请你朗读以下化学公式符号:$Mg(OH)_{2}>Al(OH)_{3}$", "audio_path": "audio/chemistry_457ecbb5-dc5f-4c52-932f-778b5f4a38cf.wav", "formula": "$Mg(OH)_{2}>Al(OH)_{3}$", "answer": "氢氧化镁大于氢氧化铝", "subset": "ChemEquation", "task_type": "tts"} +{"index": 252, "question": "请你朗读以下化学公式符号:$$2NO+O_{2}⇌2NO_{2}$$", "audio_path": "audio/chemistry_ba223ff4-229f-4d8f-9f2d-34e5c5f25460.wav", "formula": "$$2NO+O_{2}⇌2NO_{2}$$", "answer": "一氧化氮和氧气反应生成二氧化氮", "subset": "ChemEquation", "task_type": "tts"} +{"index": 253, "question": "请你朗读以下化学公式符号:$2NF_{3}\\left(\\mathrm{g}\\right)$", "audio_path": "audio/chemistry_20c7231d-6956-49c9-9959-7f388ff7451d.wav", "formula": "$2NF_{3}\\left(\\mathrm{g}\\right)$", "answer": "两摩尔的气态三氟化氮", "subset": "ChemEquation", "task_type": "tts"} +{"index": 254, "question": "请你朗读以下化学公式符号:$$Fe(OH)_{3}$$", "audio_path": "audio/chemistry_86e55c70-4159-4021-904e-d77974218e87.wav", "formula": "$$Fe(OH)_{3}$$", "answer": "氢氧化铁", "subset": "ChemEquation", "task_type": "tts"} +{"index": 255, "question": "请你朗读以下化学公式符号:$1 {g}+8.775~ {g}=9.775 {g}$", "audio_path": "audio/chemistry_1afadd7f-80ce-4336-8f48-73351acf6f2c.wav", "formula": "$1 {g}+8.775~ {g}=9.775 {g}$", "answer": "一克加八点七七五克等于九点七七五克", "subset": "ChemEquation", "task_type": "tts"} +{"index": 256, "question": "请你朗读以下化学公式符号:$2CuH+2HCl═2CuCl+2H_{2}\\uparrow$", "audio_path": "audio/chemistry_22817159-e2f8-433a-8049-e71388afc010.wav", "formula": "$2CuH+2HCl═2CuCl+2H_{2}\\uparrow$", "answer": "氢化铜和盐酸反应生成氯化亚铜和氢气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 257, "question": "请你朗读以下化学公式符号:$\\frac {{2.22~{g}}}{{22.2~{g}}}\\times 100\\% =10\\%$", "audio_path": "audio/chemistry_499f550f-ef2b-40a3-856d-517c5c235071.wav", "formula": "$\\frac {{2.22~{g}}}{{22.2~{g}}}\\times 100\\% =10\\%$", "answer": "二十二点二克分之二点二二克乘百分之百等于百分之十", "subset": "ChemEquation", "task_type": "tts"} +{"index": 258, "question": "请你朗读以下化学公式符号:${{C}_{15}}{{H}_{22}}{{O}_{5}}$", "audio_path": "audio/chemistry_6e47211e-0cab-4d8e-b3a8-f7ec14dac0ae.wav", "formula": "${{C}_{15}}{{H}_{22}}{{O}_{5}}$", "answer": "一个由十五个碳原子、二十二个氢原子和五个氧原子构成的分子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 259, "question": "请你朗读以下化学公式符号:$\\left(ClO^{-}\\right)$", "audio_path": "audio/chemistry_8f3142a0-37e5-4715-aece-0d1d576bb06d.wav", "formula": "$\\left(ClO^{-}\\right)$", "answer": "次氯酸根离子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 260, "question": "请你朗读以下化学公式符号:$\\mathrm{Fe} + 2\\mathrm{HCl} = \\mathrm{FeCl}_2 + \\mathrm{H}_2\\uparrow$", "audio_path": "audio/chemistry_6367e18a-a7be-4c02-9336-25d91e233b34.wav", "formula": "$\\mathrm{Fe} + 2\\mathrm{HCl} = \\mathrm{FeCl}_2 + \\mathrm{H}_2\\uparrow$", "answer": "铁和盐酸反应生成氯化亚铁和氢气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 261, "question": "请你朗读以下化学公式符号:$CH_{4}(g) + 2O_{2}(g)$", "audio_path": "audio/chemistry_65610837-25d3-422d-9a2d-78bdb8e078b3.wav", "formula": "$CH_{4}(g) + 2O_{2}(g)$", "answer": "一摩尔的气态甲烷加二摩尔的气态氧气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 262, "question": "请你朗读以下化学公式符号:$H_{2}O(l)═H_{2}O(g)$", "audio_path": "audio/chemistry_1d0ba45c-a872-44f0-8cb2-2612a36b51f8.wav", "formula": "$H_{2}O(l)═H_{2}O(g)$", "answer": "一摩尔的液态水转化为一摩尔的气态水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 263, "question": "请你朗读以下化学公式符号:$H_{2}\\left(g\\right)+I_{2}\\left(g\\right)=2HI\\left(g\\right)$", "audio_path": "audio/chemistry_7e3ceeb3-9aec-46aa-b41e-a7ab8cdbeb4e.wav", "formula": "$H_{2}\\left(g\\right)+I_{2}\\left(g\\right)=2HI\\left(g\\right)$", "answer": "一摩尔的气态氢气和一摩尔的气态碘反应生成两摩尔的气态碘化氢", "subset": "ChemEquation", "task_type": "tts"} +{"index": 264, "question": "请你朗读以下化学公式符号:$CH_{3} CH_{3}N_{2}O$", "audio_path": "audio/chemistry_1d190a14-4522-4ff7-9d6f-f7a652509598.wav", "formula": "$CH_{3} CH_{3}N_{2}O$", "answer": "一个由两个碳原子、六个氢原子、两个氮原子和一个氧原子构成的分子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 265, "question": "请你朗读以下化学公式符号:$$\\frac{4g}{40g/mol}$$", "audio_path": "audio/chemistry_455b31ff-1c1b-4d74-9442-a8081c4910f8.wav", "formula": "$$\\frac{4g}{40g/mol}$$", "answer": "四十克每摩尔分之四克", "subset": "ChemEquation", "task_type": "tts"} +{"index": 266, "question": "请你朗读以下化学公式符号:$\\widetilde{{{\\nu }_{{e}}}}$", "audio_path": "audio/chemistry_d6d34df9-2f32-4d1e-8e42-f90ee8f2c0e6.wav", "formula": "$\\widetilde{{{\\nu }_{{e}}}}$", "answer": "反电子中微子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 267, "question": "请你朗读以下化学公式符号:${1}.0{1}\\times {1}{{{0}}^{5}}{Pa}$", "audio_path": "audio/chemistry_2b56b1ac-de27-468a-9b9b-50d3e223cf96.wav", "formula": "${1}.0{1}\\times {1}{{{0}}^{5}}{Pa}$", "answer": "一点零一乘十的五次方帕", "subset": "ChemEquation", "task_type": "tts"} +{"index": 268, "question": "请你朗读以下化学公式符号:$c\\left(H^{+}\\right)>c\\left(OH^{-}\\right)$", "audio_path": "audio/chemistry_3602dd58-1b4f-4578-802b-b2872db68bbe.wav", "formula": "$c\\left(H^{+}\\right)>c\\left(OH^{-}\\right)$", "answer": "氢离子的浓度大于氢氧根离子的浓度", "subset": "ChemEquation", "task_type": "tts"} +{"index": 269, "question": "请你朗读以下化学公式符号:$C_{8}H_{18}\\left( l \\right)$", "audio_path": "audio/chemistry_0b78fed2-6421-415a-ba10-b15ce2492a44.wav", "formula": "$C_{8}H_{18}\\left( l \\right)$", "answer": "液态辛烷", "subset": "ChemEquation", "task_type": "tts"} +{"index": 270, "question": "请你朗读以下化学公式符号:$Ba^{2+}+SO^{2−}_{4}=BaSO_{4}\\downarrow$", "audio_path": "audio/chemistry_d105f931-59d6-4c9c-8f23-1ba294001de4.wav", "formula": "$Ba^{2+}+SO^{2−}_{4}=BaSO_{4}\\downarrow$", "answer": "钡离子和硫酸根离子反应生成硫酸钡沉淀", "subset": "ChemEquation", "task_type": "tts"} +{"index": 271, "question": "请你朗读以下化学公式符号:$\\left(CuCl_{2}\\right)$", "audio_path": "audio/chemistry_fbdefd8c-31b6-457c-9909-505152d4b577.wav", "formula": "$\\left(CuCl_{2}\\right)$", "answer": "氯化铜", "subset": "ChemEquation", "task_type": "tts"} +{"index": 272, "question": "请你朗读以下化学公式符号:$$Si(s)+3HCl(g)=SiHCl_{3}(g)+H_{2}(g)$$", "audio_path": "audio/chemistry_6e29546b-0e45-456a-b66f-a35f16836b6d.wav", "formula": "$$Si(s)+3HCl(g)=SiHCl_{3}(g)+H_{2}(g)$$", "answer": "一摩尔的固态硅和三摩尔的气态氯化氢反应生成一摩尔的气态三氯硅烷和一摩尔的气态氢气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 273, "question": "请你朗读以下化学公式符号:$\\frac{46.33}{35.5}$", "audio_path": "audio/chemistry_0b6c3a3b-fda5-4da2-aced-372749a55ef0.wav", "formula": "$\\frac{46.33}{35.5}$", "answer": "三十五点五分之四十六点三三", "subset": "ChemEquation", "task_type": "tts"} +{"index": 274, "question": "请你朗读以下化学公式符号:$6.0mol/\\left(L⋅s\\right)$", "audio_path": "audio/chemistry_770d3489-c9a9-431f-a7a6-c5b427c144bf.wav", "formula": "$6.0mol/\\left(L⋅s\\right)$", "answer": "六点零摩尔每升秒", "subset": "ChemEquation", "task_type": "tts"} +{"index": 275, "question": "请你朗读以下化学公式符号:$$H_{2}\\left(g\\right)$$", "audio_path": "audio/chemistry_8204380d-6077-4e2c-a969-c4c991e56d4c.wav", "formula": "$$H_{2}\\left(g\\right)$$", "answer": "一摩尔的气态氢气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 276, "question": "请你朗读以下化学公式符号:$C_{17}H_{19}N_{3}O$", "audio_path": "audio/chemistry_4e80d378-37f8-4e3a-9b3f-6700d5ce269c.wav", "formula": "$C_{17}H_{19}N_{3}O$", "answer": "一个由十七个碳原子、十九个氢原子、三个氮原子和一个氧原子构成的分子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 277, "question": "请你朗读以下化学公式符号:$\\mathrm{2NO + O_2\\xlongequal{}2NO_2}$", "audio_path": "audio/chemistry_6161c674-626d-45c6-99fc-463dd09fbe19.wav", "formula": "$\\mathrm{2NO + O_2\\xlongequal{}2NO_2}$", "answer": "一氧化氮和氧气反应生成二氧化氮", "subset": "ChemEquation", "task_type": "tts"} +{"index": 278, "question": "请你朗读以下化学公式符号:$CO_{2}\\left(HCl\\right)$", "audio_path": "audio/chemistry_711578be-93d9-4143-9c5e-016376acd5c8.wav", "formula": "$CO_{2}\\left(HCl\\right)$", "answer": "二氧化碳 盐酸", "subset": "ChemEquation", "task_type": "tts"} +{"index": 279, "question": "请你朗读以下化学公式符号:$CaCO_{3}\\left(s\\right)⇌Ca^{2+}\\left(aq\\right)+CO^{2−}_{3}\\left(aq\\right)$", "audio_path": "audio/chemistry_c1dba978-5a9a-401d-b1cb-d81679dae947.wav", "formula": "$CaCO_{3}\\left(s\\right)⇌Ca^{2+}\\left(aq\\right)+CO^{2−}_{3}\\left(aq\\right)$", "answer": "一摩尔固态碳酸钙在水溶液中溶解生成一摩尔钙离子和一摩尔碳酸根离子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 280, "question": "请你朗读以下化学公式符号:$c\\left(H^{+}\\right)=0.02mol⋅L^{−1}c\\left(Mg^{2+}\\right) =0.01mol⋅L^{−1}$", "audio_path": "audio/chemistry_0f1c7a10-2d93-4b4e-9b0a-b68da7dafe93.wav", "formula": "$c\\left(H^{+}\\right)=0.02mol⋅L^{−1}c\\left(Mg^{2+}\\right) =0.01mol⋅L^{−1}$", "answer": "氢离子的浓度等于零点零二摩尔每升,镁离子的浓度等于零点零一摩尔每升", "subset": "ChemEquation", "task_type": "tts"} +{"index": 281, "question": "请你朗读以下化学公式符号:${F}{{{e}}_3}{{{O}}_4}$", "audio_path": "audio/chemistry_e44326d1-5abf-49b7-ab4a-6d26162384ef.wav", "formula": "${F}{{{e}}_3}{{{O}}_4}$", "answer": "四氧化三铁", "subset": "ChemEquation", "task_type": "tts"} +{"index": 282, "question": "请你朗读以下化学公式符号:$C\\left(s\\right)+H_{2}O\\left(g\\right)=CO\\left(g\\right)+H_{2}\\left(g\\right)$", "audio_path": "audio/chemistry_5083e9ff-362e-4598-adc3-448982e410b0.wav", "formula": "$C\\left(s\\right)+H_{2}O\\left(g\\right)=CO\\left(g\\right)+H_{2}\\left(g\\right)$", "answer": "一摩尔的固态碳和一摩尔的气态水反应生成一摩尔的气态一氧化碳和一摩尔的气态氢气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 283, "question": "请你朗读以下化学公式符号:$$r_{a}>r_{e}>r_{b}>r_{d}$$", "audio_path": "audio/chemistry_90ce8c05-183b-4fa5-8399-6f4d23a6a380.wav", "formula": "$$r_{a}>r_{e}>r_{b}>r_{d}$$", "answer": "a的半径大于e的半径大于b的半径大于d的半径", "subset": "ChemEquation", "task_type": "tts"} +{"index": 284, "question": "请你朗读以下化学公式符号:$\\frac{16\\times 3}{40+32+16\\times 3}\\times 100\\%=40\\%$", "audio_path": "audio/chemistry_fe04adc1-78f8-4a9d-9ed0-311a4dc4fe78.wav", "formula": "$\\frac{16\\times 3}{40+32+16\\times 3}\\times 100\\%=40\\%$", "answer": "四十加三十二加十六乘三的和 分之十六乘三 乘百分之百等于百分之四十", "subset": "ChemEquation", "task_type": "tts"} +{"index": 285, "question": "请你朗读以下化学公式符号:$2A(g)+B(g)⇌x C(g)+2D(s)$", "audio_path": "audio/chemistry_f4cd1469-008e-4244-b9c3-1324962cd7c4.wav", "formula": "$2A(g)+B(g)⇌x C(g)+2D(s)$", "answer": "二摩尔气态A和一摩尔气态B反应生成x摩尔气态C和二摩尔固态D", "subset": "ChemEquation", "task_type": "tts"} +{"index": 286, "question": "请你朗读以下化学公式符号:$$2Al+3H_{2}SO_{4}=Al_{2}(SO_{4})_{3}+3H_{2}\\uparrow$$", "audio_path": "audio/chemistry_24fce5cd-128e-4484-b870-575cbbf6eb4d.wav", "formula": "$$2Al+3H_{2}SO_{4}=Al_{2}(SO_{4})_{3}+3H_{2}\\uparrow$$", "answer": "铝和硫酸反应生成硫酸铝和氢气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 287, "question": "请你朗读以下化学公式符号:$\\frac{12.6~{g}}{13.6~{g}}\\times 100\\%\\approx 92.6\\%$", "audio_path": "audio/chemistry_f89be336-fd91-4d03-8309-8b14b2311c51.wav", "formula": "$\\frac{12.6~{g}}{13.6~{g}}\\times 100\\%\\approx 92.6\\%$", "answer": "十三点六克分之十二点六克乘百分之百约等于百分之九十二点六", "subset": "ChemEquation", "task_type": "tts"} +{"index": 288, "question": "请你朗读以下化学公式符号:$0.1mol ⋅L^{−1}NaClO$", "audio_path": "audio/chemistry_d1223b91-89f5-4547-803b-9bcae4af7b55.wav", "formula": "$0.1mol ⋅L^{−1}NaClO$", "answer": "零点一摩尔每升的次氯酸钠", "subset": "ChemEquation", "task_type": "tts"} +{"index": 289, "question": "请你朗读以下化学公式符号:$\\frac{18g}{20g/mol}$", "audio_path": "audio/chemistry_f6e26a67-c814-4a7f-a6b9-e8f3e7308a5b.wav", "formula": "$\\frac{18g}{20g/mol}$", "answer": "二十克每摩尔分之十八克", "subset": "ChemEquation", "task_type": "tts"} +{"index": 290, "question": "请你朗读以下化学公式符号:$c\\left(Mg^{2+}\\right)$", "audio_path": "audio/chemistry_230bebb1-d0cb-4665-8d3c-c0bee5509837.wav", "formula": "$c\\left(Mg^{2+}\\right)$", "answer": "镁离子的浓度", "subset": "ChemEquation", "task_type": "tts"} +{"index": 291, "question": "请你朗读以下化学公式符号:$I_{2}O_{5}+5CO═I_{2}+5CO_{2}$", "audio_path": "audio/chemistry_998d1625-2eb1-497f-93df-eafc4fb376e7.wav", "formula": "$I_{2}O_{5}+5CO═I_{2}+5CO_{2}$", "answer": "五氧化二碘和一氧化碳反应生成碘和二氧化碳", "subset": "ChemEquation", "task_type": "tts"} +{"index": 292, "question": "请你朗读以下化学公式符号:$BaCl_{2}、 H_{2}SO_{4}、KNO_{3}$", "audio_path": "audio/chemistry_51c79955-d1f5-4ba5-a0bf-5970955b4438.wav", "formula": "$BaCl_{2}、 H_{2}SO_{4}、KNO_{3}$", "answer": "氯化钡、硫酸、硝酸钾", "subset": "ChemEquation", "task_type": "tts"} +{"index": 293, "question": "请你朗读以下化学公式符号:$ZnSO_{4}(CuSO_{4})$", "audio_path": "audio/chemistry_b30805f0-72b8-43bf-bd63-0eb244711bd8.wav", "formula": "$ZnSO_{4}(CuSO_{4})$", "answer": "硫酸锌(硫酸铜)", "subset": "ChemEquation", "task_type": "tts"} +{"index": 294, "question": "请你朗读以下化学公式符号:$\\left(NO_{2}\\right)$", "audio_path": "audio/chemistry_83a3cdce-db47-45e9-8829-5269e4494143.wav", "formula": "$\\left(NO_{2}\\right)$", "answer": "二氧化氮", "subset": "ChemEquation", "task_type": "tts"} +{"index": 295, "question": "请你朗读以下化学公式符号:$Cu+Ag^{+}=Cu^{2+}+Ag$", "audio_path": "audio/chemistry_1b2eb940-08c2-45bc-8b4d-fa6eb065a260.wav", "formula": "$Cu+Ag^{+}=Cu^{2+}+Ag$", "answer": "铜和银离子反应生成铜离子和银单质", "subset": "ChemEquation", "task_type": "tts"} +{"index": 296, "question": "请你朗读以下化学公式符号:$n(\\mathrm{HCl}) = 4 mol$", "audio_path": "audio/chemistry_49923871-fd12-4681-aa9f-38f4464b2b61.wav", "formula": "$n(\\mathrm{HCl}) = 4 mol$", "answer": "氯化氢的物质的量等于四摩尔", "subset": "ChemEquation", "task_type": "tts"} +{"index": 297, "question": "请你朗读以下化学公式符号:$△H_{2}>△H_{3}>△H_{1}$", "audio_path": "audio/chemistry_9c498afd-ef8f-4a6f-a77c-06ae788c23cb.wav", "formula": "$△H_{2}>△H_{3}>△H_{1}$", "answer": "delta H二大于delta H三大于delta H一", "subset": "ChemEquation", "task_type": "tts"} +{"index": 298, "question": "请你朗读以下化学公式符号:${\\rm N_2}$", "audio_path": "audio/chemistry_98967fea-ba88-42c1-9908-eedf74c456b6.wav", "formula": "${\\rm N_2}$", "answer": "氮气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 299, "question": "请你朗读以下化学公式符号:$C_{3}N_{3}O_{3}Cl_{3}$", "audio_path": "audio/chemistry_b69fbf9e-8579-4c76-bb73-52a55d231871.wav", "formula": "$C_{3}N_{3}O_{3}Cl_{3}$", "answer": "一个由三个碳原子、三个氮原子、三个氧原子和三个氯原子构成的分子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 300, "question": "请你朗读以下化学公式符号:$C_{5}H_{12} > C_{2}H_{6}$", "audio_path": "audio/chemistry_8e3ab084-5154-4254-ab73-083d2448904e.wav", "formula": "$C_{5}H_{12} > C_{2}H_{6}$", "answer": "戊烷大于乙烷", "subset": "ChemEquation", "task_type": "tts"} +{"index": 301, "question": "请你朗读以下化学公式符号:$c_{1}V_{1}>c_{2}V_{2}$", "audio_path": "audio/chemistry_56434e03-4f8c-4b7d-a2bd-63077ea0783d.wav", "formula": "$c_{1}V_{1}>c_{2}V_{2}$", "answer": "浓度一乘体积一大于浓度二乘体积二", "subset": "ChemEquation", "task_type": "tts"} +{"index": 302, "question": "请你朗读以下化学公式符号:$1.0molB\\left( g \\right)$", "audio_path": "audio/chemistry_03a8d4a4-9c1d-43e7-9d82-2af32da6d2aa.wav", "formula": "$1.0molB\\left( g \\right)$", "answer": "一点零摩尔气态硼", "subset": "ChemEquation", "task_type": "tts"} +{"index": 303, "question": "请你朗读以下化学公式符号:$\\frac{c(OH^{−})}{c(NH_{3}•H_{2}O)}$", "audio_path": "audio/chemistry_ee2917d0-8225-4ce9-a343-df557b4d1f08.wav", "formula": "$\\frac{c(OH^{−})}{c(NH_{3}•H_{2}O)}$", "answer": "一水合氨的浓度分之氢氧根离子的浓度", "subset": "ChemEquation", "task_type": "tts"} +{"index": 304, "question": "请你朗读以下化学公式符号:$C\\left(s\\right)+O_{2}\\left(g\\right)═CO_{2}\\left(g\\right)$", "audio_path": "audio/chemistry_6bb1406d-7399-4b69-bf52-a59266310169.wav", "formula": "$C\\left(s\\right)+O_{2}\\left(g\\right)═CO_{2}\\left(g\\right)$", "answer": "一摩尔的固态碳和一摩尔的气态氧气反应生成一摩尔的气态二氧化碳", "subset": "ChemEquation", "task_type": "tts"} +{"index": 305, "question": "请你朗读以下化学公式符号:$Al_{2}O_{3}⋅2SiO_{2}⋅2H_{2}O$", "audio_path": "audio/chemistry_ebe41b01-2a08-4f94-97b6-0dae55ad6627.wav", "formula": "$Al_{2}O_{3}⋅2SiO_{2}⋅2H_{2}O$", "answer": "二水合硅酸铝", "subset": "ChemEquation", "task_type": "tts"} +{"index": 306, "question": "请你朗读以下化学公式符号:$H_{3}PO_{4}>H_{2}SO_{4}>HClO_{4}$", "audio_path": "audio/chemistry_246fa0f3-248d-4db4-b4fb-437309618be9.wav", "formula": "$H_{3}PO_{4}>H_{2}SO_{4}>HClO_{4}$", "answer": "磷酸大于硫酸大于高氯酸", "subset": "ChemEquation", "task_type": "tts"} +{"index": 307, "question": "请你朗读以下化学公式符号:$$Ca\\left(OH\\right)_{2}$$", "audio_path": "audio/chemistry_ebe8baa0-504f-41d6-a055-57f00c437a1e.wav", "formula": "$$Ca\\left(OH\\right)_{2}$$", "answer": "氢氧化钙", "subset": "ChemEquation", "task_type": "tts"} +{"index": 308, "question": "请你朗读以下化学公式符号:$4X\\left(g\\right)+5Y\\left(g\\right)=nZ\\left(g\\right)+6W\\left(g\\right)$", "audio_path": "audio/chemistry_f4524cb6-6818-4f09-9a1b-6b3a3f821341.wav", "formula": "$4X\\left(g\\right)+5Y\\left(g\\right)=nZ\\left(g\\right)+6W\\left(g\\right)$", "answer": "四摩尔气态X和五摩尔气态Y反应生成n摩尔气态Z和六摩尔气态W", "subset": "ChemEquation", "task_type": "tts"} +{"index": 309, "question": "请你朗读以下化学公式符号:$$CH_{3}COOH+NH_{3}═CH_{3}COONH_{4}$$", "audio_path": "audio/chemistry_f67372ba-66fe-4f50-84c4-42c43f0d039f.wav", "formula": "$$CH_{3}COOH+NH_{3}═CH_{3}COONH_{4}$$", "answer": "乙酸和氨反应生成乙酸铵", "subset": "ChemEquation", "task_type": "tts"} +{"index": 310, "question": "请你朗读以下化学公式符号:$CCl_{4}>CHCl_{3}>H_{2}O$", "audio_path": "audio/chemistry_42476815-5774-49b1-b004-86f182d5ef90.wav", "formula": "$CCl_{4}>CHCl_{3}>H_{2}O$", "answer": "四氯化碳大于三氯甲烷大于水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 311, "question": "请你朗读以下化学公式符号:$c\\left(Ag^{+}\\right),v\\left(Cr^{3+}\\right)$", "audio_path": "audio/chemistry_0c687c72-7adb-4bc5-93a6-6da192574620.wav", "formula": "$c\\left(Ag^{+}\\right),v\\left(Cr^{3+}\\right)$", "answer": "银离子的浓度,三价铬离子的反应速率", "subset": "ChemEquation", "task_type": "tts"} +{"index": 312, "question": "请你朗读以下化学公式符号:$\\left(2\\right)Cl^{−}$", "audio_path": "audio/chemistry_4e6a9aa9-f926-44e8-a745-f697dd4edcd3.wav", "formula": "$\\left(2\\right)Cl^{−}$", "answer": "二 氯离子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 313, "question": "请你朗读以下化学公式符号:$$\\left(mg/L\\right)$$", "audio_path": "audio/chemistry_06d21188-5def-48bd-9e4d-01e6cc9db68a.wav", "formula": "$$\\left(mg/L\\right)$$", "answer": "毫克每升", "subset": "ChemEquation", "task_type": "tts"} +{"index": 314, "question": "请你朗读以下化学公式符号:$\\left(TiCl_{4}\\right)$", "audio_path": "audio/chemistry_8fa5286d-afa0-48df-b6e0-73d09d26b61e.wav", "formula": "$\\left(TiCl_{4}\\right)$", "answer": "四氯化钛", "subset": "ChemEquation", "task_type": "tts"} +{"index": 315, "question": "请你朗读以下化学公式符号:$2CO_{2}\\left(g\\right)△H=−566.0kJ⋅mol^{−1}$", "audio_path": "audio/chemistry_a8f6addf-dace-4cfd-b858-ecd8d09e6224.wav", "formula": "$2CO_{2}\\left(g\\right)△H=−566.0kJ⋅mol^{−1}$", "answer": "两摩尔气态二氧化碳 delta H等于负五百六十六点零千焦每摩尔", "subset": "ChemEquation", "task_type": "tts"} +{"index": 316, "question": "请你朗读以下化学公式符号:$\\left(\\mathrm{CH_4}\\right)$", "audio_path": "audio/chemistry_aa4b20b8-d691-4c6f-86ec-706196dc8027.wav", "formula": "$\\left(\\mathrm{CH_4}\\right)$", "answer": "甲烷", "subset": "ChemEquation", "task_type": "tts"} +{"index": 317, "question": "请你朗读以下化学公式符号:$c\\left(H^{+}\\right)=1.0\\times10^{-12}\\,\\mathrm{mol\\cdot L^{-1}}$", "audio_path": "audio/chemistry_379cae73-5c40-4207-bdd0-00f47af1e604.wav", "formula": "$c\\left(H^{+}\\right)=1.0\\times10^{-12}\\,\\mathrm{mol\\cdot L^{-1}}$", "answer": "氢离子的浓度等于一点零乘十的负十二次方摩尔每升", "subset": "ChemEquation", "task_type": "tts"} +{"index": 318, "question": "请你朗读以下化学公式符号:$Fe_{2}O_{3}(s)+3CO(g)=2Fe(s)+3CO_{2}(g)$", "audio_path": "audio/chemistry_098a94e7-d193-4649-8695-b7f40b4f67d4.wav", "formula": "$Fe_{2}O_{3}(s)+3CO(g)=2Fe(s)+3CO_{2}(g)$", "answer": "一摩尔的固态氧化铁和三摩尔的气态一氧化碳反应生成两摩尔的固态铁和三摩尔的气态二氧化碳", "subset": "ChemEquation", "task_type": "tts"} +{"index": 319, "question": "请你朗读以下化学公式符号:$NaHSO_{4}═Na^{+}+HSO^{−}_{4}$", "audio_path": "audio/chemistry_1f37ec75-7f70-457a-995b-5379f41f70ff.wav", "formula": "$NaHSO_{4}═Na^{+}+HSO^{−}_{4}$", "answer": "硫酸氢钠电离生成钠离子和硫酸氢根离子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 320, "question": "请你朗读以下化学公式符号:$c\\left(H^{+}\\right)=c\\left(SO^{2−}_{4}\\right)+c\\left(OH^{−}\\right)$", "audio_path": "audio/chemistry_a545941e-e26d-4415-ba86-0784b658f9ce.wav", "formula": "$c\\left(H^{+}\\right)=c\\left(SO^{2−}_{4}\\right)+c\\left(OH^{−}\\right)$", "answer": "氢离子的浓度等于硫酸根离子的浓度加氢氧根离子的浓度", "subset": "ChemEquation", "task_type": "tts"} +{"index": 321, "question": "请你朗读以下化学公式符号:$$\\ce{AgNO3 + NaCl=AgCl↓ + NaNO3}$$", "audio_path": "audio/chemistry_d0cabd30-8ba5-4079-9fa1-d43ddac64c34.wav", "formula": "$$\\ce{AgNO3 + NaCl=AgCl↓ + NaNO3}$$", "answer": "硝酸银和氯化钠反应生成氯化银沉淀和硝酸钠", "subset": "ChemEquation", "task_type": "tts"} +{"index": 322, "question": "请你朗读以下化学公式符号:$(C_{6}H_{10}O_{5})_{n}$", "audio_path": "audio/chemistry_02bafbf0-c697-44e9-9cb6-159968680462.wav", "formula": "$(C_{6}H_{10}O_{5})_{n}$", "answer": "多糖", "subset": "ChemEquation", "task_type": "tts"} +{"index": 323, "question": "请你朗读以下化学公式符号:${{{H}}_2}{{{O}}_2}$", "audio_path": "audio/chemistry_159ce6fe-17a0-469c-a8e8-fcab9bfe03ea.wav", "formula": "${{{H}}_2}{{{O}}_2}$", "answer": "过氧化氢", "subset": "ChemEquation", "task_type": "tts"} +{"index": 324, "question": "请你朗读以下化学公式符号:$$3CO+Fe_{2}O_{3}\\xlongequal{\\text{高温}}2Fe+3CO_{2}\\uparrow$$", "audio_path": "audio/chemistry_7d4740dc-a205-40e4-8acb-4cd634b3f14a.wav", "formula": "$$3CO+Fe_{2}O_{3}\\xlongequal{\\text{高温}}2Fe+3CO_{2}\\uparrow$$", "answer": "一氧化碳和氧化铁在高温条件下反应生成铁和二氧化碳气体", "subset": "ChemEquation", "task_type": "tts"} +{"index": 325, "question": "请你朗读以下化学公式符号:$S_{2}O^{2−}_{3}+2H^{+}=S\\downarrow+SO_{2}\\uparrow+H_{2}O$", "audio_path": "audio/chemistry_fab2a07e-b747-4c89-9825-cdcb8cf67f74.wav", "formula": "$S_{2}O^{2−}_{3}+2H^{+}=S\\downarrow+SO_{2}\\uparrow+H_{2}O$", "answer": "硫代硫酸根离子和氢离子反应生成硫沉淀,二氧化硫和水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 326, "question": "请你朗读以下化学公式符号:$4\\times 463{kJ}=1{ }852{ kJ}$", "audio_path": "audio/chemistry_0b482e05-96b8-4ffe-b566-c05e70813c5b.wav", "formula": "$4\\times 463{kJ}=1{ }852{ kJ}$", "answer": "四乘四百六十三千焦等于一千八百五十二千焦", "subset": "ChemEquation", "task_type": "tts"} +{"index": 327, "question": "请你朗读以下化学公式符号:$Fe^{3+}+Cu=Fe^{2+}+Cu^{2+}$", "audio_path": "audio/chemistry_87defc25-9c7c-4815-86e7-b2dabb07950a.wav", "formula": "$Fe^{3+}+Cu=Fe^{2+}+Cu^{2+}$", "answer": "铁离子和铜反应生成亚铁离子和铜离子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 328, "question": "请你朗读以下化学公式符号:$2H_{2}O═2H_{2}+O_{2}$", "audio_path": "audio/chemistry_37c82ec3-9fd9-40da-958f-7d3271e06b9b.wav", "formula": "$2H_{2}O═2H_{2}+O_{2}$", "answer": "水分解生成氢气和氧气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 329, "question": "请你朗读以下化学公式符号:$N_{2}+3H_{2}⇌2NH_{3},$", "audio_path": "audio/chemistry_b74a49dd-d194-49a7-a165-30a377e06da8.wav", "formula": "$N_{2}+3H_{2}⇌2NH_{3},$", "answer": "氮气和氢气反应生成氨气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 330, "question": "请你朗读以下化学公式符号:$Al(OH)_{3}+3HCl═AlCl_{3}+3H_{2}O$", "audio_path": "audio/chemistry_13ba4cfa-a2e5-4491-8c35-5f25196ed9b1.wav", "formula": "$Al(OH)_{3}+3HCl═AlCl_{3}+3H_{2}O$", "answer": "氢氧化铝和盐酸反应生成氯化铝和水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 331, "question": "请你朗读以下化学公式符号:$C_{12}H_{22}O_{14}Ca$", "audio_path": "audio/chemistry_c12431d9-3b9a-42b0-8e07-1dc8ad81f3b0.wav", "formula": "$C_{12}H_{22}O_{14}Ca$", "answer": "一个由十二个碳原子、二十二个氢原子、十四个氧原子和一个钙原子构成的分子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 332, "question": "请你朗读以下化学公式符号:$CH_{3}CH=CHCH=CH-COOH$", "audio_path": "audio/chemistry_14b9919c-6ebc-4697-893e-c570a9398f7f.wav", "formula": "$CH_{3}CH=CHCH=CH-COOH$", "answer": "二 四 己二烯酸", "subset": "ChemEquation", "task_type": "tts"} +{"index": 333, "question": "请你朗读以下化学公式符号:$\\left[Cu\\left(NH_{3}\\right)_{4}\\right]Cl_{2}$", "audio_path": "audio/chemistry_c1a04e66-fa2a-4f30-aad6-a03dbb29059c.wav", "formula": "$\\left[Cu\\left(NH_{3}\\right)_{4}\\right]Cl_{2}$", "answer": "氯化四氨合铜", "subset": "ChemEquation", "task_type": "tts"} +{"index": 334, "question": "请你朗读以下化学公式符号:$△H_{1}<△H_{2}<△H_{3}$", "audio_path": "audio/chemistry_dbdf3652-ec55-45fe-8e59-ed4f93929be0.wav", "formula": "$△H_{1}<△H_{2}<△H_{3}$", "answer": "delta H一小于delta H二,小于delta H三", "subset": "ChemEquation", "task_type": "tts"} +{"index": 335, "question": "请你朗读以下化学公式符号:$Ba\\left(OH\\right)_{2}⋅8H_{2}O$", "audio_path": "audio/chemistry_0fdc7e24-20aa-439d-a16a-180d45ee4438.wav", "formula": "$Ba\\left(OH\\right)_{2}⋅8H_{2}O$", "answer": "八水合氢氧化钡", "subset": "ChemEquation", "task_type": "tts"} +{"index": 336, "question": "请你朗读以下化学公式符号:$$\\left(mol⋅L^{−1} \\right)$$", "audio_path": "audio/chemistry_09b2b7df-4044-4d77-a325-aba39018ce12.wav", "formula": "$$\\left(mol⋅L^{−1} \\right)$$", "answer": "摩尔每升", "subset": "ChemEquation", "task_type": "tts"} +{"index": 337, "question": "请你朗读以下化学公式符号:$\\frac{52.36\\%}{40}$", "audio_path": "audio/chemistry_da620e94-db42-434f-b8f4-77051d94fb73.wav", "formula": "$\\frac{52.36\\%}{40}$", "answer": "四十分之百分之五十二点三六", "subset": "ChemEquation", "task_type": "tts"} +{"index": 338, "question": "请你朗读以下化学公式符号:$HCl、Ca(OH)_{2}、 K_{2}SO_{4}、 CaCl_{2}$", "audio_path": "audio/chemistry_7aa3b5e0-3aa1-4fa9-a9dd-ef6dd593ab3b.wav", "formula": "$HCl、Ca(OH)_{2}、 K_{2}SO_{4}、 CaCl_{2}$", "answer": "氯化氢、氢氧化钙、硫酸钾、氯化钙", "subset": "ChemEquation", "task_type": "tts"} +{"index": 339, "question": "请你朗读以下化学公式符号:$$mA\\left(g\\right)+nB\\left(g\\right)$$", "audio_path": "audio/chemistry_17695067-42ab-4f48-91c0-83decd826761.wav", "formula": "$$mA\\left(g\\right)+nB\\left(g\\right)$$", "answer": "m摩尔气态A加n摩尔气态B", "subset": "ChemEquation", "task_type": "tts"} +{"index": 340, "question": "请你朗读以下化学公式符号:$$aA\\left(g\\right)+bB\\left(g\\right)$$", "audio_path": "audio/chemistry_d664a0aa-4ca4-422b-9253-66b2c33cd93f.wav", "formula": "$$aA\\left(g\\right)+bB\\left(g\\right)$$", "answer": "a摩尔的气态A和b摩尔的气态B", "subset": "ChemEquation", "task_type": "tts"} +{"index": 341, "question": "请你朗读以下化学公式符号:$$Fe_{2}O_{3}\\cdot 3H_{2}O$$", "audio_path": "audio/chemistry_b69ce467-4a8b-4b41-8600-44cccddefddd.wav", "formula": "$$Fe_{2}O_{3}\\cdot 3H_{2}O$$", "answer": "三水合氧化铁", "subset": "ChemEquation", "task_type": "tts"} +{"index": 342, "question": "请你朗读以下化学公式符号:$2Na_{2}S_{2}O_{3}+I_{2}$", "audio_path": "audio/chemistry_9b728b56-8d9b-446a-aa1d-9c234d9983c7.wav", "formula": "$2Na_{2}S_{2}O_{3}+I_{2}$", "answer": "硫代硫酸钠和碘", "subset": "ChemEquation", "task_type": "tts"} +{"index": 343, "question": "请你朗读以下化学公式符号:$,1.01\\times10^{5}Pa,64gSO_{2}$", "audio_path": "audio/chemistry_64c2add2-730a-4713-8e6d-5d8bba0a6141.wav", "formula": "$,1.01\\times10^{5}Pa,64gSO_{2}$", "answer": "一点零一乘十的五次方帕斯卡,六十四克二氧化硫", "subset": "ChemEquation", "task_type": "tts"} +{"index": 344, "question": "请你朗读以下化学公式符号:$\\frac{c(X)•c^{2}(Y)}{c^{2}(Z)•c^{2}(W)}$", "audio_path": "audio/chemistry_2659838d-e8a5-4443-a8c3-95b1a86a061c.wav", "formula": "$\\frac{c(X)•c^{2}(Y)}{c^{2}(Z)•c^{2}(W)}$", "answer": "Z的浓度的平方乘W的浓度的平方的积分之X的浓度乘Y的浓度的平方的积", "subset": "ChemEquation", "task_type": "tts"} +{"index": 345, "question": "请你朗读以下化学公式符号:$$CH_{3}COONH_{4} = CH_{3}COO^{-}+NH_{4}^{+}$$", "audio_path": "audio/chemistry_f13ec763-a3e0-4b32-81f0-5ade917fa0e5.wav", "formula": "$$CH_{3}COONH_{4} = CH_{3}COO^{-}+NH_{4}^{+}$$", "answer": "醋酸铵电离生成醋酸根离子和铵根离子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 346, "question": "请你朗读以下化学公式符号:$$\\rm [KAl(SO_4)_2\\cdot 12H_2O]$$", "audio_path": "audio/chemistry_eca2e232-1b99-4cf6-aadf-e83867f67093.wav", "formula": "$$\\rm [KAl(SO_4)_2\\cdot 12H_2O]$$", "answer": "十二水合硫酸铝钾", "subset": "ChemEquation", "task_type": "tts"} +{"index": 347, "question": "请你朗读以下化学公式符号:$NaCl \\rightarrow NaNO_{3}$", "audio_path": "audio/chemistry_8736f9fa-2541-42bd-8781-cb39c1b83eb9.wav", "formula": "$NaCl \\rightarrow NaNO_{3}$", "answer": "氯化钠箭头硝酸钠", "subset": "ChemEquation", "task_type": "tts"} +{"index": 348, "question": "请你朗读以下化学公式符号:$$NaClO_{3}+6HCl=NaCl+3Cl_{2}+3H_{2}O$$", "audio_path": "audio/chemistry_a7e2e0fb-a679-411d-b3e9-08df57d2a99f.wav", "formula": "$$NaClO_{3}+6HCl=NaCl+3Cl_{2}+3H_{2}O$$", "answer": "氯酸钠与盐酸反应生成氯化钠、氯气和水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 349, "question": "请你朗读以下化学公式符号:$NaOH(aq)+CH_{3}COOH(aq)=CH_{3}COONa(aq)+H_{2}O(l)$", "audio_path": "audio/chemistry_4a0cd7fc-52ff-4238-b7b9-d9ce856314ed.wav", "formula": "$NaOH(aq)+CH_{3}COOH(aq)=CH_{3}COONa(aq)+H_{2}O(l)$", "answer": "一摩尔的氢氧化钠溶液和一摩尔的乙酸溶液反应生成一摩尔的乙酸钠溶液和一摩尔的液态水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 350, "question": "请你朗读以下化学公式符号:$Cr_2O_5$", "audio_path": "audio/chemistry_b7a384b7-f202-4a77-9612-61356ee131e5.wav", "formula": "$Cr_2O_5$", "answer": "五氧化二铬", "subset": "ChemEquation", "task_type": "tts"} +{"index": 351, "question": "请你朗读以下化学公式符号:$CaO→Ca\\left(OH\\right)_{2}$", "audio_path": "audio/chemistry_7fdcdb3d-e9c2-4e98-9d91-0c4eb632e894.wav", "formula": "$CaO→Ca\\left(OH\\right)_{2}$", "answer": "氧化钙箭头氢氧化钙", "subset": "ChemEquation", "task_type": "tts"} +{"index": 352, "question": "请你朗读以下化学公式符号:$CO_{2}\\left(HCl\\right):$", "audio_path": "audio/chemistry_e0c58826-3775-480f-8a15-b9cf1f8ef4ce.wav", "formula": "$CO_{2}\\left(HCl\\right):$", "answer": "二氧化碳(氯化氢)", "subset": "ChemEquation", "task_type": "tts"} +{"index": 353, "question": "请你朗读以下化学公式符号:$$2KMnO_{4}+16HCl=2KCl+2MnCl_{2}+5Cl_{2}\\uparrow+8H_{2}O$$", "audio_path": "audio/chemistry_82bd3cc3-ff90-4bb2-93ae-19d9edd81faa.wav", "formula": "$$2KMnO_{4}+16HCl=2KCl+2MnCl_{2}+5Cl_{2}\\uparrow+8H_{2}O$$", "answer": "高锰酸钾和盐酸反应生成氯化钾、氯化锰、氯气和水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 354, "question": "请你朗读以下化学公式符号:$Cl_{2}>BrO^{−}_{3}>ClO^{−}_{3}>HIO_{3}$", "audio_path": "audio/chemistry_182f0149-1766-4eef-853c-7c782a960018.wav", "formula": "$Cl_{2}>BrO^{−}_{3}>ClO^{−}_{3}>HIO_{3}$", "answer": "氯气大于溴酸根离子大于氯酸根离子大于碘酸", "subset": "ChemEquation", "task_type": "tts"} +{"index": 355, "question": "请你朗读以下化学公式符号:$Ba^{2+}+2OH^{−}+2H^{+}+SO^{2−}_{4}═BaSO_{4}\\downarrow+2H_{2}O$", "audio_path": "audio/chemistry_cf5bc95c-ce4c-42da-a4a4-635000671d57.wav", "formula": "$Ba^{2+}+2OH^{−}+2H^{+}+SO^{2−}_{4}═BaSO_{4}\\downarrow+2H_{2}O$", "answer": "钡离子和氢氧根离子、氢离子、硫酸根离子反应生成硫酸钡和水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 356, "question": "请你朗读以下化学公式符号:$NO$ $CO$ $CO_{2}$ $O_{2}$ $SO_{2}$", "audio_path": "audio/chemistry_c782fd12-bc6a-4b3b-8002-c8d3d9dd5ad1.wav", "formula": "$NO$ $CO$ $CO_{2}$ $O_{2}$ $SO_{2}$", "answer": "一氧化氮 一氧化碳 二氧化碳 氧气 二氧化硫", "subset": "ChemEquation", "task_type": "tts"} +{"index": 357, "question": "请你朗读以下化学公式符号:$1molH_{2}\\left(g\\right)$", "audio_path": "audio/chemistry_ecf45419-67eb-4318-986a-134dcfb888b7.wav", "formula": "$1molH_{2}\\left(g\\right)$", "answer": "一摩尔气态氢气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 358, "question": "请你朗读以下化学公式符号:$2Fe{^{2+}}+2H{^{+}}+H_{2}O_{2}=2Fe{^{3+}}+2H_{2}O$", "audio_path": "audio/chemistry_7922d633-ac8a-41c4-a979-1cd07854e018.wav", "formula": "$2Fe{^{2+}}+2H{^{+}}+H_{2}O_{2}=2Fe{^{3+}}+2H_{2}O$", "answer": "亚铁离子、氢离子和过氧化氢反应生成铁离子和水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 359, "question": "请你朗读以下化学公式符号:$$2CO + O_{2}\\xlongequal{} 2CO_{2}$$", "audio_path": "audio/chemistry_1a9550e7-ebe6-4f7b-93ba-d852cdaa57a4.wav", "formula": "$$2CO + O_{2}\\xlongequal{} 2CO_{2}$$", "answer": "一氧化碳和氧气反应生成二氧化碳", "subset": "ChemEquation", "task_type": "tts"} +{"index": 360, "question": "请你朗读以下化学公式符号:$CO_{2}+H_{2}O+2NaClO$", "audio_path": "audio/chemistry_b50c7832-6095-41f6-ab3f-2237810eb5e5.wav", "formula": "$CO_{2}+H_{2}O+2NaClO$", "answer": "二氧化碳加水加两个次氯酸钠", "subset": "ChemEquation", "task_type": "tts"} +{"index": 361, "question": "请你朗读以下化学公式符号:$Na_{2}CO_{3}>NaHCO_{3}$", "audio_path": "audio/chemistry_b14e153c-397f-4da4-af8b-0bbc39d0cc0b.wav", "formula": "$Na_{2}CO_{3}>NaHCO_{3}$", "answer": "碳酸钠大于碳酸氢钠", "subset": "ChemEquation", "task_type": "tts"} +{"index": 362, "question": "请你朗读以下化学公式符号:$\\frac{9.775~{g}}{116.5~{g}}\\times 100\\%\\approx 8.4\\%$", "audio_path": "audio/chemistry_d9020148-38f4-448b-892e-02dfee4cd0f4.wav", "formula": "$\\frac{9.775~{g}}{116.5~{g}}\\times 100\\%\\approx 8.4\\%$", "answer": "一百一十六点五克分之九点七七五克乘百分之百约等于百分之八点四", "subset": "ChemEquation", "task_type": "tts"} +{"index": 363, "question": "请你朗读以下化学公式符号:${CO}{{({N}{{{H}}_2})}_2}$", "audio_path": "audio/chemistry_9aff46a1-3adc-4f2d-86b4-207138ba87dc.wav", "formula": "${CO}{{({N}{{{H}}_2})}_2}$", "answer": "尿素", "subset": "ChemEquation", "task_type": "tts"} +{"index": 364, "question": "请你朗读以下化学公式符号:$Na_{2}CO_{3}+Ca$(OH)$_{2}═CaCO_{3}\\downarrow+2NaOH$", "audio_path": "audio/chemistry_59007a52-573b-46b7-9b34-b4b5d862fe38.wav", "formula": "$Na_{2}CO_{3}+Ca$(OH)$_{2}═CaCO_{3}\\downarrow+2NaOH$", "answer": "碳酸钠和氢氧化钙反应生成碳酸钙沉淀和氢氧化钠 。", "subset": "ChemEquation", "task_type": "tts"} +{"index": 365, "question": "请你朗读以下化学公式符号:$$N_{2}(g)+3H_{2}(g)⇌2NH_{3}(g)$$", "audio_path": "audio/chemistry_c531cb87-e087-41b4-92f4-1e28b8e3b3e8.wav", "formula": "$$N_{2}(g)+3H_{2}(g)⇌2NH_{3}(g)$$", "answer": "一摩尔的气态氮气和三摩尔的气态氢气反应生成两摩尔的气态氨气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 366, "question": "请你朗读以下化学公式符号:$C_{6}H_{5}OH+CO^{2−}_{3}\\rightarrow C_{6}H_{5}O^{−}+HCO_3^-$", "audio_path": "audio/chemistry_f236be9c-609c-42fd-a580-ced968035cd8.wav", "formula": "$C_{6}H_{5}OH+CO^{2−}_{3}\\rightarrow C_{6}H_{5}O^{−}+HCO_3^-$", "answer": "苯酚和碳酸根离子反应生成苯酚根离子和碳酸氢根离子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 367, "question": "请你朗读以下化学公式符号:$$NH_{3}+H_{2}O+CO_{2}=NH_{4}HCO_{3}$$", "audio_path": "audio/chemistry_e7d47c6c-0d32-4ca0-99ee-5f2dc492a93a.wav", "formula": "$$NH_{3}+H_{2}O+CO_{2}=NH_{4}HCO_{3}$$", "answer": "氨气、水和二氧化碳反应生成碳酸氢铵", "subset": "ChemEquation", "task_type": "tts"} +{"index": 368, "question": "请你朗读以下化学公式符号:$Fe+2HCl=FeCl_{2}+H_{2}\\uparrow$", "audio_path": "audio/chemistry_f99dba00-3ea8-4dca-b05a-f595514c5b10.wav", "formula": "$Fe+2HCl=FeCl_{2}+H_{2}\\uparrow$", "answer": "铁和盐酸反应生成氯化亚铁和氢气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 369, "question": "请你朗读以下化学公式符号:$Fe_{3}O_{4}(s)+CO(g)=3FeO(s)+CO_{2}(g)$", "audio_path": "audio/chemistry_84c1233f-c3a1-4050-94af-a260d186e55b.wav", "formula": "$Fe_{3}O_{4}(s)+CO(g)=3FeO(s)+CO_{2}(g)$", "answer": "一摩尔的固态四氧化三铁和一摩尔的气态一氧化碳反应生成三摩尔的固态氧化亚铁和一摩尔的气态二氧化碳", "subset": "ChemEquation", "task_type": "tts"} +{"index": 370, "question": "请你朗读以下化学公式符号:$CH_{3}CH_{2}COCH_{3}$", "audio_path": "audio/chemistry_bd11777d-d93a-4b56-adf3-ac121cd8feb9.wav", "formula": "$CH_{3}CH_{2}COCH_{3}$", "answer": "二 丁酮", "subset": "ChemEquation", "task_type": "tts"} +{"index": 371, "question": "请你朗读以下化学公式符号:$c\\left(H^{+}\\right)=1\\times10^{-12}mol/L$", "audio_path": "audio/chemistry_74796101-38b2-4d69-8d0a-cb90ca2e641d.wav", "formula": "$c\\left(H^{+}\\right)=1\\times10^{-12}mol/L$", "answer": "氢离子的浓度等于一乘十的负十二次方摩尔每升", "subset": "ChemEquation", "task_type": "tts"} +{"index": 372, "question": "请你朗读以下化学公式符号:$CO^{2−}_{3}+H^{+}\\rightarrow HCO^{−}_{3}$", "audio_path": "audio/chemistry_78333cce-55ef-4b23-9b17-cd89e75262b2.wav", "formula": "$CO^{2−}_{3}+H^{+}\\rightarrow HCO^{−}_{3}$", "answer": "碳酸根离子和氢离子反应生成碳酸氢根离子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 373, "question": "请你朗读以下化学公式符号:$CO_{2}+3H_{2}=X+H_{2}O$", "audio_path": "audio/chemistry_f4891b56-e3b3-425f-bfdb-198df8a1008e.wav", "formula": "$CO_{2}+3H_{2}=X+H_{2}O$", "answer": "二氧化碳和氢气反应生成X和水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 374, "question": "请你朗读以下化学公式符号:$$\\left(O_{3}\\right)$$", "audio_path": "audio/chemistry_de4eabff-8c22-45cb-9475-dff7dcf1e5d6.wav", "formula": "$$\\left(O_{3}\\right)$$", "answer": "臭氧", "subset": "ChemEquation", "task_type": "tts"} +{"index": 375, "question": "请你朗读以下化学公式符号:$$2NO\\left(g\\right)+O_{2}\\left(g\\right)⇌2NO_{2}\\left(g\\right)$$", "audio_path": "audio/chemistry_0b6121cf-9159-468b-b0a6-d6a4be94a4f5.wav", "formula": "$$2NO\\left(g\\right)+O_{2}\\left(g\\right)⇌2NO_{2}\\left(g\\right)$$", "answer": "两摩尔的气态一氧化氮和一摩尔的气态氧气反应生成两摩尔的气态二氧化氮", "subset": "ChemEquation", "task_type": "tts"} +{"index": 376, "question": "请你朗读以下化学公式符号:$2v({N}{{{H}}_3})=v({C}{{{O}}_2})$", "audio_path": "audio/chemistry_fab1e59f-b9a6-45f5-99ff-f292e916f975.wav", "formula": "$2v({N}{{{H}}_3})=v({C}{{{O}}_2})$", "answer": "两倍的氨气的反应速率等于二氧化碳的反应速率", "subset": "ChemEquation", "task_type": "tts"} +{"index": 377, "question": "请你朗读以下化学公式符号:$$\\ce{Na_{2}CO_{3} + 2CH_{3}COOH -> 2CH_{3}COONa + H_{2}O + CO_{2}\\uparrow}$$", "audio_path": "audio/chemistry_a0c5843f-bd2d-448f-a6c2-f2eac002e214.wav", "formula": "$$\\ce{Na_{2}CO_{3} + 2CH_{3}COOH -> 2CH_{3}COONa + H_{2}O + CO_{2}\\uparrow}$$", "answer": "碳酸钠和醋酸反应生成醋酸钠、水和二氧化碳气体", "subset": "ChemEquation", "task_type": "tts"} +{"index": 378, "question": "请你朗读以下化学公式符号:$2A(g)+3B(g)⇌xC(g)+yD(g)$", "audio_path": "audio/chemistry_e5e3a55e-0ecd-453b-a910-82bd723aafdf.wav", "formula": "$2A(g)+3B(g)⇌xC(g)+yD(g)$", "answer": "两摩尔的气态A和三摩尔的气态B反应生成x摩尔的气态C和y摩尔的气态D", "subset": "ChemEquation", "task_type": "tts"} +{"index": 379, "question": "请你朗读以下化学公式符号:$$(12\\times 16):(14\\times 3)=32:7$$", "audio_path": "audio/chemistry_912b3adb-1770-478f-bd86-cedd1129d260.wav", "formula": "$$(12\\times 16):(14\\times 3)=32:7$$", "answer": "十二乘十六的积比十四乘三的积等于三十二比七", "subset": "ChemEquation", "task_type": "tts"} +{"index": 380, "question": "请你朗读以下化学公式符号:$$2KMnO_{4}+16HCl=2KCl+2MnCl_{2}+5Cl_{2}\\uparrow+8H_{2}O $$", "audio_path": "audio/chemistry_ac555ed2-c28f-41ce-b9ac-a9fd255bedad.wav", "formula": "$$2KMnO_{4}+16HCl=2KCl+2MnCl_{2}+5Cl_{2}\\uparrow+8H_{2}O $$", "answer": "高锰酸钾和盐酸反应生成氯化钾、氯化锰、氯气和水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 381, "question": "请你朗读以下化学公式符号:$Al\\left(OH\\right)_{3}$", "audio_path": "audio/chemistry_a3c5b46a-8f40-4f2d-8d0f-580025275d77.wav", "formula": "$Al\\left(OH\\right)_{3}$", "answer": "氢氧化铝", "subset": "ChemEquation", "task_type": "tts"} +{"index": 382, "question": "请你朗读以下化学公式符号:$250mL 0.2 0mol⋅L^{−1}$", "audio_path": "audio/chemistry_043c9dd5-3c80-4ade-90a0-a612756f3707.wav", "formula": "$250mL 0.2 0mol⋅L^{−1}$", "answer": "二百五十毫升零点二零摩尔每升", "subset": "ChemEquation", "task_type": "tts"} +{"index": 383, "question": "请你朗读以下化学公式符号:$\\frac{c\\left(CH_{3}COOH\\right)}{c\\left(H^{+}\\right)⋅c\\left(CH_{3}COO^{−}\\right)}$", "audio_path": "audio/chemistry_645c9057-d7b4-48a5-9db9-21d8ea3cc863.wav", "formula": "$\\frac{c\\left(CH_{3}COOH\\right)}{c\\left(H^{+}\\right)⋅c\\left(CH_{3}COO^{−}\\right)}$", "answer": "氢离子的浓度乘醋酸根离子的浓度的积分之醋酸的浓度", "subset": "ChemEquation", "task_type": "tts"} +{"index": 384, "question": "请你朗读以下化学公式符号:${{{C}}_{16}}{{{H}}_{10}}{{{N}}_2}{{{O}}_2}$", "audio_path": "audio/chemistry_e34ffddd-512d-42ef-a150-14a0ffaba689.wav", "formula": "${{{C}}_{16}}{{{H}}_{10}}{{{N}}_2}{{{O}}_2}$", "answer": "一个由十六个碳原子、十个氢原子、两个氮原子和两个氧原子构成的分子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 385, "question": "请你朗读以下化学公式符号:$$CaO + H_{2}O = Ca(OH)_{2}$$", "audio_path": "audio/chemistry_a3d5b04c-5254-4db6-b6ea-6c44afadab7d.wav", "formula": "$$CaO + H_{2}O = Ca(OH)_{2}$$", "answer": "氧化钙和水反应生成氢氧化钙", "subset": "ChemEquation", "task_type": "tts"} +{"index": 386, "question": "请你朗读以下化学公式符号:$P(s) + \\frac{5}{4} O_{2} (g)\\xlongequal{点燃} \\frac{1}{2} P_{2}O_5 (s)$", "audio_path": "audio/chemistry_bb32292d-3609-4c95-ba22-37c0e5e498a9.wav", "formula": "$P(s) + \\frac{5}{4} O_{2} (g)\\xlongequal{点燃} \\frac{1}{2} P_{2}O_5 (s)$", "answer": "一摩尔固态的磷和四分之五摩尔的气态氧气在点燃的条件下反应生成二分之一摩尔的固态五氧化二磷", "subset": "ChemEquation", "task_type": "tts"} +{"index": 387, "question": "请你朗读以下化学公式符号:$V\\left[H2O\\left(g\\right)\\right]=1$", "audio_path": "audio/chemistry_fb058b51-01b9-40b1-866d-d99150ad2cc5.wav", "formula": "$V\\left[H2O\\left(g\\right)\\right]=1$", "answer": "气态水的体积等于一", "subset": "ChemEquation", "task_type": "tts"} +{"index": 388, "question": "请你朗读以下化学公式符号:$Cu_{2}\\left(OH\\right)_{2}CO_{3}$", "audio_path": "audio/chemistry_38c3d0cd-0f35-400e-a48b-a60118405c9c.wav", "formula": "$Cu_{2}\\left(OH\\right)_{2}CO_{3}$", "answer": "碱式碳酸铜", "subset": "ChemEquation", "task_type": "tts"} +{"index": 389, "question": "请你朗读以下化学公式符号:$\\frac{1}{2}H_{2}SO_{4}(aq)$", "audio_path": "audio/chemistry_31aa66d7-2390-4afb-9292-aa89960210d1.wav", "formula": "$\\frac{1}{2}H_{2}SO_{4}(aq)$", "answer": "二分之一摩尔硫酸溶液", "subset": "ChemEquation", "task_type": "tts"} +{"index": 390, "question": "请你朗读以下化学公式符号:$c\\left(H^{+}\\right)=10^{−14}mol⋅L^{−1}$", "audio_path": "audio/chemistry_98da5bfa-162c-42ad-9b8f-383ed999d348.wav", "formula": "$c\\left(H^{+}\\right)=10^{−14}mol⋅L^{−1}$", "answer": "氢离子的浓度等于十的负十四次方摩尔每升", "subset": "ChemEquation", "task_type": "tts"} +{"index": 391, "question": "请你朗读以下化学公式符号:$[\\frac{A}{(50+A+B)}]\\times100\\%$", "audio_path": "audio/chemistry_bf1a1605-3f26-4ecd-92ad-a06e57540631.wav", "formula": "$[\\frac{A}{(50+A+B)}]\\times100\\%$", "answer": "五十加A加B的和分之A乘百分之百", "subset": "ChemEquation", "task_type": "tts"} +{"index": 392, "question": "请你朗读以下化学公式符号:$$A_{2}\\left(g\\right)+3B_{2}\\left(g\\right)⇌2C\\left(g\\right)$$", "audio_path": "audio/chemistry_5a0a97a2-2c63-4a1f-bc25-5b1a150e51cb.wav", "formula": "$$A_{2}\\left(g\\right)+3B_{2}\\left(g\\right)⇌2C\\left(g\\right)$$", "answer": "一摩尔的气态A单质和三摩尔的气态B单质反应生成两摩尔的气态C", "subset": "ChemEquation", "task_type": "tts"} +{"index": 393, "question": "请你朗读以下化学公式符号:$$2Na_{2}O_{2}+2CO_{2}$$", "audio_path": "audio/chemistry_0ccc0153-d4aa-44fd-8a04-860562f0f7f5.wav", "formula": "$$2Na_{2}O_{2}+2CO_{2}$$", "answer": "两个过氧化钠分子加两个二氧化碳分子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 394, "question": "请你朗读以下化学公式符号:$1{.8 g}\\times \\frac{2}{18}=0{.2 g}$", "audio_path": "audio/chemistry_e9abd473-40b5-4c14-80f9-28c29f64bda0.wav", "formula": "$1{.8 g}\\times \\frac{2}{18}=0{.2 g}$", "answer": "一点八克乘十八分之二等于零点二克", "subset": "ChemEquation", "task_type": "tts"} +{"index": 395, "question": "请你朗读以下化学公式符号:$200ml0.15mol⋅L^{-1}$", "audio_path": "audio/chemistry_2778b3a0-9b1f-4843-998c-80d68b2104b6.wav", "formula": "$200ml0.15mol⋅L^{-1}$", "answer": "二百毫升零点一五摩尔每升", "subset": "ChemEquation", "task_type": "tts"} +{"index": 396, "question": "请你朗读以下化学公式符号:$H^{+}\\left(aq\\right)+OH^{−}\\left(aq\\right)═H_{2}O\\left(l\\right)$", "audio_path": "audio/chemistry_f2d52653-0844-4865-9a0f-df14ea8f3af9.wav", "formula": "$H^{+}\\left(aq\\right)+OH^{−}\\left(aq\\right)═H_{2}O\\left(l\\right)$", "answer": "溶液中的一摩尔氢离子和溶液中的一摩尔氢氧根离子反应生成一摩尔液态水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 397, "question": "请你朗读以下化学公式符号:$v\\left(C\\right):v\\left(B\\right)=1:2$", "audio_path": "audio/chemistry_db817880-69f3-4559-ab7f-d8d93bc2f5a5.wav", "formula": "$v\\left(C\\right):v\\left(B\\right)=1:2$", "answer": "C的反应速率比上B的反应速率等于一比二", "subset": "ChemEquation", "task_type": "tts"} +{"index": 398, "question": "请你朗读以下化学公式符号:$$\\rm NH_3+HCl\\ce{\\xlongequal{}}NH_4Cl$$", "audio_path": "audio/chemistry_3450676e-6b04-4af1-921d-cb112d8d4994.wav", "formula": "$$\\rm NH_3+HCl\\ce{\\xlongequal{}}NH_4Cl$$", "answer": "氨气和氯化氢反应生成氯化铵", "subset": "ChemEquation", "task_type": "tts"} +{"index": 399, "question": "请你朗读以下化学公式符号:$\\left(NH_{4}\\right)_{2}SO_{4}$", "audio_path": "audio/chemistry_f9474520-94fb-4458-b6ab-be27591e9d8d.wav", "formula": "$\\left(NH_{4}\\right)_{2}SO_{4}$", "answer": "硫酸铵", "subset": "ChemEquation", "task_type": "tts"} +{"index": 400, "question": "请你朗读以下化学公式符号:${{{C}}_{2}}{{{H}}_{6}}$", "audio_path": "audio/chemistry_969d3937-b031-428a-9953-c3781cfc89a9.wav", "formula": "${{{C}}_{2}}{{{H}}_{6}}$", "answer": "乙烷", "subset": "ChemEquation", "task_type": "tts"} +{"index": 401, "question": "请你朗读以下化学公式符号:$$1molCH_{2}=CH−CH =CH−CH =CH_{2}$$", "audio_path": "audio/chemistry_cdc13dfa-c32c-4554-b0c7-5c215e95acd4.wav", "formula": "$$1molCH_{2}=CH−CH =CH−CH =CH_{2}$$", "answer": "一摩尔的 一 三 五己三烯", "subset": "ChemEquation", "task_type": "tts"} +{"index": 402, "question": "请你朗读以下化学公式符号:$5NH_{4}NO_{3}═4N_{2}\\uparrow+2HNO_{3}+9H_{2}O$", "audio_path": "audio/chemistry_ce250737-f59c-432a-a8ad-31446e9d56cb.wav", "formula": "$5NH_{4}NO_{3}═4N_{2}\\uparrow+2HNO_{3}+9H_{2}O$", "answer": "硝酸铵分解生成氮气和硝酸和水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 403, "question": "请你朗读以下化学公式符号:$${{{C}}_2}{{{H}}_5}{OH}$$", "audio_path": "audio/chemistry_f7e2d36f-2dba-4615-b216-606afac5dfa2.wav", "formula": "$${{{C}}_2}{{{H}}_5}{OH}$$", "answer": "乙醇", "subset": "ChemEquation", "task_type": "tts"} +{"index": 404, "question": "请你朗读以下化学公式符号:$C_{6}H_{12}O_{6}+6O_{2}$", "audio_path": "audio/chemistry_1ea1873b-71fd-4a2f-92a3-7e2e6c72ed05.wav", "formula": "$C_{6}H_{12}O_{6}+6O_{2}$", "answer": "一个葡萄糖分子加六个氧气分子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 405, "question": "请你朗读以下化学公式符号:$$2H_{2}S+O_{2}\\xlongequal{点燃}2H_{2}O+S\\downarrow$$", "audio_path": "audio/chemistry_e5bc26a8-b073-4673-839e-d959ac9bf4e9.wav", "formula": "$$2H_{2}S+O_{2}\\xlongequal{点燃}2H_{2}O+S\\downarrow$$", "answer": "硫化氢和氧气在点燃的条件下反应生成水和硫", "subset": "ChemEquation", "task_type": "tts"} +{"index": 406, "question": "请你朗读以下化学公式符号:$3Na+Fe^{3+}=3Na^{+}+Fe$", "audio_path": "audio/chemistry_d79caaaf-a60c-43f1-bd3d-4b76a86c8b3e.wav", "formula": "$3Na+Fe^{3+}=3Na^{+}+Fe$", "answer": "钠和铁离子反应生成钠离子和铁", "subset": "ChemEquation", "task_type": "tts"} +{"index": 407, "question": "请你朗读以下化学公式符号:$△H=2\\times\\left(−57.3\\right)kJ/mol$", "audio_path": "audio/chemistry_3df3e467-dcf4-4b08-8346-83b1f436e3ef.wav", "formula": "$△H=2\\times\\left(−57.3\\right)kJ/mol$", "answer": "delta H等于二乘负五十七点三千焦每摩尔", "subset": "ChemEquation", "task_type": "tts"} +{"index": 408, "question": "请你朗读以下化学公式符号:$HA^{-} \\rightleftharpoons H^{+} + A^{2-}$", "audio_path": "audio/chemistry_e952b356-78cf-4e19-8886-daa7a747d25e.wav", "formula": "$HA^{-} \\rightleftharpoons H^{+} + A^{2-}$", "answer": "氢A离子电离生成氢离子和A离子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 409, "question": "请你朗读以下化学公式符号:${{{C}}_{{9}}}{{{H}}_{{8}}}{{{O}}_{{2}}}$", "audio_path": "audio/chemistry_4dcf7b95-4c53-4923-b2f7-1fac8ed9bc5a.wav", "formula": "${{{C}}_{{9}}}{{{H}}_{{8}}}{{{O}}_{{2}}}$", "answer": "肉桂酸", "subset": "ChemEquation", "task_type": "tts"} +{"index": 410, "question": "请你朗读以下化学公式符号:$15{g}+9{g}+Y=3{0g}$", "audio_path": "audio/chemistry_43c23fd0-9e9a-4eae-bc00-51c3d80ce9cc.wav", "formula": "$15{g}+9{g}+Y=3{0g}$", "answer": "十五克加九克加Y等于三十克", "subset": "ChemEquation", "task_type": "tts"} +{"index": 411, "question": "请你朗读以下化学公式符号:$c(NH_{4}^{+}) = 0.5\\,\\mathrm{mol/L}$", "audio_path": "audio/chemistry_76e8cace-2535-422d-ad95-400bee9de662.wav", "formula": "$c(NH_{4}^{+}) = 0.5\\,\\mathrm{mol/L}$", "answer": "铵根离子的浓度等于零点五摩尔每升", "subset": "ChemEquation", "task_type": "tts"} +{"index": 412, "question": "请你朗读以下化学公式符号:$\\left(3\\right)104.4g$", "audio_path": "audio/chemistry_ef310c4e-0248-4e3e-98a5-8b68ab4aab7b.wav", "formula": "$\\left(3\\right)104.4g$", "answer": "三 一百零四点四克", "subset": "ChemEquation", "task_type": "tts"} +{"index": 413, "question": "请你朗读以下化学公式符号:$\\left(ZrO_{2}\\right)$", "audio_path": "audio/chemistry_b9fa0201-011a-4dd1-b1fd-4b56699e6781.wav", "formula": "$\\left(ZrO_{2}\\right)$", "answer": "氧化锆", "subset": "ChemEquation", "task_type": "tts"} +{"index": 414, "question": "请你朗读以下化学公式符号:$NaHSO_{4}, NH_{4}Cl$", "audio_path": "audio/chemistry_6f7c5dbb-cafd-4e0e-a9c9-03d8ae10159b.wav", "formula": "$NaHSO_{4}, NH_{4}Cl$", "answer": "硫酸氢钠 氯化铵", "subset": "ChemEquation", "task_type": "tts"} +{"index": 415, "question": "请你朗读以下化学公式符号:$H_{2}O \\left(mol\\right)$", "audio_path": "audio/chemistry_98f3caa7-1fcf-49a1-a1d3-fc9cdeefc097.wav", "formula": "$H_{2}O \\left(mol\\right)$", "answer": "水 摩尔", "subset": "ChemEquation", "task_type": "tts"} +{"index": 416, "question": "请你朗读以下化学公式符号:$$CO\\left(g\\right)+H_{2}O\\left(g\\right)⇌CO_{2}\\left(g\\right)+H_{2}\\left(g\\right)$$", "audio_path": "audio/chemistry_e2c8388d-4f93-4ed8-a3aa-9ace0a9919d3.wav", "formula": "$$CO\\left(g\\right)+H_{2}O\\left(g\\right)⇌CO_{2}\\left(g\\right)+H_{2}\\left(g\\right)$$", "answer": "一摩尔的气态一氧化碳和一摩尔的气态水反应生成一摩尔的气态二氧化碳和一摩尔的气态氢气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 417, "question": "请你朗读以下化学公式符号:$CaO + H_{2}O = Ca(OH)_{2}$", "audio_path": "audio/chemistry_66789f43-221a-4703-bb3f-b0a5909f58bf.wav", "formula": "$CaO + H_{2}O = Ca(OH)_{2}$", "answer": "氧化钙和水反应生成氢氧化钙", "subset": "ChemEquation", "task_type": "tts"} +{"index": 418, "question": "请你朗读以下化学公式符号:$0.1mol/\\left(L⋅min\\right)$", "audio_path": "audio/chemistry_6f4b959c-c8b1-426c-9cd8-3ed9ea4d02ad.wav", "formula": "$0.1mol/\\left(L⋅min\\right)$", "answer": "零点一摩尔每升每分钟", "subset": "ChemEquation", "task_type": "tts"} +{"index": 419, "question": "请你朗读以下化学公式符号:$HCHO+2 Cu\\left(OH\\right)_{2}+NaOH=HCOONa +Cu_{2}O\\downarrow+3H_{2}O$", "audio_path": "audio/chemistry_b91a971e-c88f-446f-94f4-2dd161fb974c.wav", "formula": "$HCHO+2 Cu\\left(OH\\right)_{2}+NaOH=HCOONa +Cu_{2}O\\downarrow+3H_{2}O$", "answer": "甲醛、氢氧化铜和氢氧化钠反应生成甲酸钠、氧化亚铜和水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 420, "question": "请你朗读以下化学公式符号:$$\\left(N_{2}H_{4}\\right)$$", "audio_path": "audio/chemistry_35ca9f80-23f3-4a3b-9950-ec6f2f2d90be.wav", "formula": "$$\\left(N_{2}H_{4}\\right)$$", "answer": "肼", "subset": "ChemEquation", "task_type": "tts"} +{"index": 421, "question": "请你朗读以下化学公式符号:${NaN}{{{O}}_{{3}}}$", "audio_path": "audio/chemistry_8ea0e4b6-41be-43a6-a9c6-e917e5b05a30.wav", "formula": "${NaN}{{{O}}_{{3}}}$", "answer": "硝酸钠", "subset": "ChemEquation", "task_type": "tts"} +{"index": 422, "question": "请你朗读以下化学公式符号:$Fe_{2}O_{3}+3H_{2}SO_{4}═Fe_2(SO_{4})_3+3H_{2}O$", "audio_path": "audio/chemistry_ffc4577c-41c0-476b-b722-e9b5f7730942.wav", "formula": "$Fe_{2}O_{3}+3H_{2}SO_{4}═Fe_2(SO_{4})_3+3H_{2}O$", "answer": "氧化铁和硫酸反应生成硫酸铁和水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 423, "question": "请你朗读以下化学公式符号:$\\left(3\\right)CO_{2}$", "audio_path": "audio/chemistry_679344b8-a5bd-4f1c-9155-c56315ace5ef.wav", "formula": "$\\left(3\\right)CO_{2}$", "answer": "三 二氧化碳", "subset": "ChemEquation", "task_type": "tts"} +{"index": 424, "question": "请你朗读以下化学公式符号:$8NH_{3}+3Cl_{2}=6NH_{4}Cl+N_{2}$", "audio_path": "audio/chemistry_e60443c9-5e5e-42bf-8288-af5c0dd9afea.wav", "formula": "$8NH_{3}+3Cl_{2}=6NH_{4}Cl+N_{2}$", "answer": "氨气和氯气反应生成氯化铵和氮气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 425, "question": "请你朗读以下化学公式符号:$CH_{3}OH(g) + CO(g)$", "audio_path": "audio/chemistry_7f35e386-558e-41f7-8d92-081bf235da46.wav", "formula": "$CH_{3}OH(g) + CO(g)$", "answer": "一摩尔气态甲醇加一摩尔气态一氧化碳", "subset": "ChemEquation", "task_type": "tts"} +{"index": 426, "question": "请你朗读以下化学公式符号:$2Na_{2}O_{2}+2SO_{3}=2Na_{2}SO_{4}+O_{2}$", "audio_path": "audio/chemistry_dfac786e-366d-4616-933c-5389dd674992.wav", "formula": "$2Na_{2}O_{2}+2SO_{3}=2Na_{2}SO_{4}+O_{2}$", "answer": "过氧化钠和三氧化硫反应生成硫酸钠和氧气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 427, "question": "请你朗读以下化学公式符号:$$\\left(H_{2}SO_{4}\\right)$$", "audio_path": "audio/chemistry_bc5d1ea5-2957-4d34-95e2-a84f045f0629.wav", "formula": "$$\\left(H_{2}SO_{4}\\right)$$", "answer": "硫酸", "subset": "ChemEquation", "task_type": "tts"} +{"index": 428, "question": "请你朗读以下化学公式符号:$Cu(OH)_{2}+H_{2}SO_{4}=CuSO_{4}+2H_{2}O$", "audio_path": "audio/chemistry_48d3eadb-2853-469b-b704-80d36fcd9e9c.wav", "formula": "$Cu(OH)_{2}+H_{2}SO_{4}=CuSO_{4}+2H_{2}O$", "answer": "氢氧化铜和硫酸反应生成硫酸铜和水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 429, "question": "请你朗读以下化学公式符号:$v_{1}mol/\\left(L⋅s\\right);0.2mol/L Na_{2}S_{2}O_{3}$", "audio_path": "audio/chemistry_e18dde59-f353-455d-9752-f2cee4d182fd.wav", "formula": "$v_{1}mol/\\left(L⋅s\\right);0.2mol/L Na_{2}S_{2}O_{3}$", "answer": "v一摩尔每升每秒;零点二摩尔每升的硫代硫酸钠", "subset": "ChemEquation", "task_type": "tts"} +{"index": 430, "question": "请你朗读以下化学公式符号:$\\frac{c\\left(NH^{+}_{4}\\right)}{c\\left(NH_{3}⋅H_{2}O\\right)}$", "audio_path": "audio/chemistry_faf7c9f2-4098-4fb7-8ffc-5f06779f6f9d.wav", "formula": "$\\frac{c\\left(NH^{+}_{4}\\right)}{c\\left(NH_{3}⋅H_{2}O\\right)}$", "answer": "一水合氨的浓度分之铵根离子的浓度", "subset": "ChemEquation", "task_type": "tts"} +{"index": 431, "question": "请你朗读以下化学公式符号:$H_{3}ZO_{4} > H_{2}YO_{4} > HXO_{4}$", "audio_path": "audio/chemistry_1de36fef-0b9e-4b22-ba79-fa6c874ceaba.wav", "formula": "$H_{3}ZO_{4} > H_{2}YO_{4} > HXO_{4}$", "answer": "Z酸大于Y酸大于高X酸", "subset": "ChemEquation", "task_type": "tts"} +{"index": 432, "question": "请你朗读以下化学公式符号:$1 mol⋅L^{−1}CaCl_{2}$", "audio_path": "audio/chemistry_61ae086f-957f-4cd7-a14f-077ec17145a7.wav", "formula": "$1 mol⋅L^{−1}CaCl_{2}$", "answer": "一摩尔每升氯化钙", "subset": "ChemEquation", "task_type": "tts"} +{"index": 433, "question": "请你朗读以下化学公式符号:$({C}{{{H}}_{3}}{C}{{{H}}_{2}}{OH})$", "audio_path": "audio/chemistry_3c0cac89-8f21-4c0c-bdea-cb7284afdb99.wav", "formula": "$({C}{{{H}}_{3}}{C}{{{H}}_{2}}{OH})$", "answer": "乙醇", "subset": "ChemEquation", "task_type": "tts"} +{"index": 434, "question": "请你朗读以下化学公式符号:$K_{sp} \\left(BaCO_{3} \\right)=5.1\\times10^{−9}$", "audio_path": "audio/chemistry_11f6696e-bbbd-4825-bd5b-337546003747.wav", "formula": "$K_{sp} \\left(BaCO_{3} \\right)=5.1\\times10^{−9}$", "answer": "碳酸钡的K sp等于五点一乘十的负九次方", "subset": "ChemEquation", "task_type": "tts"} +{"index": 435, "question": "请你朗读以下化学公式符号:$NH_{4}^{+}+2H_{2}O⇌NH_{3}\\cdot H_{2}O+H_{3}O^{+}$", "audio_path": "audio/chemistry_31b4a49b-fb77-44e5-8c16-fd914614a756.wav", "formula": "$NH_{4}^{+}+2H_{2}O⇌NH_{3}\\cdot H_{2}O+H_{3}O^{+}$", "answer": "铵根离子和水反应生成一水合氨和水合氢离子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 436, "question": "请你朗读以下化学公式符号:$$2X+15O_{2}═12CO_{2}+6H_{2}O$$", "audio_path": "audio/chemistry_7ce2971d-2631-4532-b7ef-21b34f1fb215.wav", "formula": "$$2X+15O_{2}═12CO_{2}+6H_{2}O$$", "answer": "X和氧气反应生成二氧化碳和水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 437, "question": "请你朗读以下化学公式符号:$Cu+2HCl=CuCl_{2}+H_{2}\\uparrow$", "audio_path": "audio/chemistry_19176ff6-3ef8-4df0-a0f0-f3424a51d28f.wav", "formula": "$Cu+2HCl=CuCl_{2}+H_{2}\\uparrow$", "answer": "铜和盐酸反应生成氯化铜和氢气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 438, "question": "请你朗读以下化学公式符号:$CaCl_{2},Ca\\left(ClO\\right)_{2},CaCO_{3}$", "audio_path": "audio/chemistry_147591e7-88ad-47ea-acaf-961a7dc02ce9.wav", "formula": "$CaCl_{2},Ca\\left(ClO\\right)_{2},CaCO_{3}$", "answer": "氯化钙,次氯酸钙,碳酸钙", "subset": "ChemEquation", "task_type": "tts"} +{"index": 439, "question": "请你朗读以下化学公式符号:${NaClO}+2{HCl}={NaCl}+{Cl}_{2}\\uparrow +{H}_{2}{O}$", "audio_path": "audio/chemistry_43ca3c2e-af29-44e4-9cc6-9208b53a11d0.wav", "formula": "${NaClO}+2{HCl}={NaCl}+{Cl}_{2}\\uparrow +{H}_{2}{O}$", "answer": "次氯酸钠和盐酸反应生成氯化钠、氯气和水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 440, "question": "请你朗读以下化学公式符号:$c\\left(H^{+}\\right)\\cdot c\\left(OH^{−}\\right)=1×10^{−14}mol^{2}⋅L^{−2}$", "audio_path": "audio/chemistry_75508c45-0aa9-49f5-8357-f29625a51ad2.wav", "formula": "$c\\left(H^{+}\\right)\\cdot c\\left(OH^{−}\\right)=1×10^{−14}mol^{2}⋅L^{−2}$", "answer": "氢离子浓度乘氢氧根离子浓度等于一乘十的负十四次方摩尔二次方每升二次方", "subset": "ChemEquation", "task_type": "tts"} +{"index": 441, "question": "请你朗读以下化学公式符号:$Na_{2}SO_{4}$ $FeCl_{3}$", "audio_path": "audio/chemistry_2fcbc70c-5b31-4098-9575-5276ff5b1626.wav", "formula": "$Na_{2}SO_{4}$ $FeCl_{3}$", "answer": "硫酸钠 氯化铁", "subset": "ChemEquation", "task_type": "tts"} +{"index": 442, "question": "请你朗读以下化学公式符号:$$ H_{2}+2NiO\\left(OH\\right)⇌2Ni\\left(OH\\right)_{2}$$", "audio_path": "audio/chemistry_4514f96b-0d7d-4d99-a80e-fb42679c74af.wav", "formula": "$$ H_{2}+2NiO\\left(OH\\right)⇌2Ni\\left(OH\\right)_{2}$$", "answer": "氢气和氢氧化氧镍反应生成氢氧化镍", "subset": "ChemEquation", "task_type": "tts"} +{"index": 443, "question": "请你朗读以下化学公式符号:$H_{2}S+Fe^{3+}═Fe^{2+}+S\\downarrow+2H^{+}$", "audio_path": "audio/chemistry_3835451d-5696-4838-8b13-2b7493aac4c3.wav", "formula": "$H_{2}S+Fe^{3+}═Fe^{2+}+S\\downarrow+2H^{+}$", "answer": "硫化氢和铁离子反应生成亚铁离子、硫单质和氢离子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 444, "question": "请你朗读以下化学公式符号:$$Cu^{2+}$$ $$ Fe^{2+}$$ $$ NO^{−}_{3}$$ $$ Cl^{−}$$", "audio_path": "audio/chemistry_11e2ddf8-c725-44b6-9753-6781922d57fe.wav", "formula": "$$Cu^{2+}$$ $$ Fe^{2+}$$ $$ NO^{−}_{3}$$ $$ Cl^{−}$$", "answer": "铜离子 亚铁离子 硝酸根离子 氯离子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 445, "question": "请你朗读以下化学公式符号:$2C(s)+2O_{2}(g)=2CO_{2} (g)$", "audio_path": "audio/chemistry_2d036008-57b9-4db5-9f16-925deaa75068.wav", "formula": "$2C(s)+2O_{2}(g)=2CO_{2} (g)$", "answer": "两摩尔的固态碳和两摩尔的气态氧气反应生成两摩尔的气态二氧化碳", "subset": "ChemEquation", "task_type": "tts"} +{"index": 446, "question": "请你朗读以下化学公式符号:$△H=−285.84kJ⋅mol^{−1}$", "audio_path": "audio/chemistry_cd84f288-bfc4-4e2a-9dbc-f38ad6c8c396.wav", "formula": "$△H=−285.84kJ⋅mol^{−1}$", "answer": "delta H 等于 负二百八十五点八四 千焦每摩尔", "subset": "ChemEquation", "task_type": "tts"} +{"index": 447, "question": "请你朗读以下化学公式符号:$NaOH\\left(Na_{2}CO_{3}\\right)$", "audio_path": "audio/chemistry_847bf31c-3659-4849-8def-c80cd57f7e6e.wav", "formula": "$NaOH\\left(Na_{2}CO_{3}\\right)$", "answer": "氢氧化钠碳酸钠", "subset": "ChemEquation", "task_type": "tts"} +{"index": 448, "question": "请你朗读以下化学公式符号:$O^{2−}1s^{2}2s^{2}2p^{6}$", "audio_path": "audio/chemistry_9b72e4ef-385e-4752-b0af-f771139c78ca.wav", "formula": "$O^{2−}1s^{2}2s^{2}2p^{6}$", "answer": "氧离子一s轨道填充两个电子,二s轨道填充两个电子,二p轨道填充六个电子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 449, "question": "请你朗读以下化学公式符号:$ClO^{-}+CO_{2}+H_{2}O=HClO+HCO_3^-$", "audio_path": "audio/chemistry_ddc7bf7c-87d4-4305-8792-7dee2a292ac0.wav", "formula": "$ClO^{-}+CO_{2}+H_{2}O=HClO+HCO_3^-$", "answer": "次氯酸根离子、二氧化碳和水反应生成次氯酸和碳酸氢根离子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 450, "question": "请你朗读以下化学公式符号:$c(OH^{−})=0.3mol/L$", "audio_path": "audio/chemistry_b0be74a3-70f7-4109-a82e-ba4535664e1d.wav", "formula": "$c(OH^{−})=0.3mol/L$", "answer": "氢氧根离子的浓度等于零点三摩尔每升", "subset": "ChemEquation", "task_type": "tts"} +{"index": 451, "question": "请你朗读以下化学公式符号:$CO\\left(g\\right)+\\frac{1}{2}O_{2}\\left(g\\right)=CO_{2}\\left(g\\right)$", "audio_path": "audio/chemistry_1ef4b596-b9e8-4ad5-9469-7d7b4e2d1e5a.wav", "formula": "$CO\\left(g\\right)+\\frac{1}{2}O_{2}\\left(g\\right)=CO_{2}\\left(g\\right)$", "answer": "一摩尔的气态一氧化碳和二分之一摩尔的气态氧气反应生成一摩尔的气态二氧化碳", "subset": "ChemEquation", "task_type": "tts"} +{"index": 452, "question": "请你朗读以下化学公式符号:$S(g)+O_{2}(g)=SO_{2}(g)$", "audio_path": "audio/chemistry_7cf8f17f-06ed-4efc-815d-c7b208647890.wav", "formula": "$S(g)+O_{2}(g)=SO_{2}(g)$", "answer": "一摩尔的气态硫和一摩尔的气态氧气反应生成一摩尔的气态二氧化硫", "subset": "ChemEquation", "task_type": "tts"} +{"index": 453, "question": "请你朗读以下化学公式符号:$S(s)+3F_{2}(g)=SF_{6}(g)$", "audio_path": "audio/chemistry_a3786e46-4261-4285-afbd-32148c7f2171.wav", "formula": "$S(s)+3F_{2}(g)=SF_{6}(g)$", "answer": "一摩尔的固态硫和三摩尔的气态氟气反应生成一摩尔的气态六氟化硫", "subset": "ChemEquation", "task_type": "tts"} +{"index": 454, "question": "请你朗读以下化学公式符号:$\\left(2\\right)Na_{2}S$", "audio_path": "audio/chemistry_061aac37-53bb-40a2-a8b0-2c434115747f.wav", "formula": "$\\left(2\\right)Na_{2}S$", "answer": "二 硫化钠", "subset": "ChemEquation", "task_type": "tts"} +{"index": 455, "question": "请你朗读以下化学公式符号:$Mg+2HCl═MgCl_{2}+H_{2}\\uparrow$", "audio_path": "audio/chemistry_16284519-fe0a-454b-a5a1-73751c25762b.wav", "formula": "$Mg+2HCl═MgCl_{2}+H_{2}\\uparrow$", "answer": "镁和盐酸反应生成氯化镁和氢气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 456, "question": "请你朗读以下化学公式符号:$$\\left(1\\right)Na_{2}CO_{3}\\left(Na_{2}O_{2}\\right)$$", "audio_path": "audio/chemistry_324a338f-9ca4-4abb-b6e8-174d27f56ba5.wav", "formula": "$$\\left(1\\right)Na_{2}CO_{3}\\left(Na_{2}O_{2}\\right)$$", "answer": "一 碳酸钠(过氧化钠)", "subset": "ChemEquation", "task_type": "tts"} +{"index": 457, "question": "请你朗读以下化学公式符号:$X_{3}Y_{2}(ZWR_{4})_{3}T_{2}$", "audio_path": "audio/chemistry_e461bc58-b4f1-48b1-b68d-7f32dca45771.wav", "formula": "$X_{3}Y_{2}(ZWR_{4})_{3}T_{2}$", "answer": "一个由三个X原子、两个Y原子、三个Z原子、三个W原子、十二个R原子、两个T原子构成的分子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 458, "question": "请你朗读以下化学公式符号:$HCO^{−}_{3}+OH^{−}═CO_{3}^{2-}+H_{2}O$", "audio_path": "audio/chemistry_c5f0fc59-91ea-48cd-b639-26a255036a68.wav", "formula": "$HCO^{−}_{3}+OH^{−}═CO_{3}^{2-}+H_{2}O$", "answer": "碳酸氢根离子和氢氧根离子反应生成碳酸根离子和水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 459, "question": "请你朗读以下化学公式符号:$$Cu\\left(OH\\right)_{2}$$", "audio_path": "audio/chemistry_25626bfb-b7fa-46ff-893f-f36d1cc33ae4.wav", "formula": "$$Cu\\left(OH\\right)_{2}$$", "answer": "氢氧化铜", "subset": "ChemEquation", "task_type": "tts"} +{"index": 460, "question": "请你朗读以下化学公式符号:$0.5molNa_{2}SO_{4}$", "audio_path": "audio/chemistry_97648fad-95f7-4d5b-8e2c-2fa897a3349f.wav", "formula": "$0.5molNa_{2}SO_{4}$", "answer": "零点五摩尔硫酸钠", "subset": "ChemEquation", "task_type": "tts"} +{"index": 461, "question": "请你朗读以下化学公式符号:$C_{19}H_{26}O_{3}$", "audio_path": "audio/chemistry_a795895e-046b-4bae-a999-39aea254579c.wav", "formula": "$C_{19}H_{26}O_{3}$", "answer": "一个由十九个碳原子、二十六个氢原子和三个氧原子构成的分子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 462, "question": "请你朗读以下化学公式符号:$$\\frac{△{c}_{(A)}}{△t}$$", "audio_path": "audio/chemistry_90326ee3-1dbe-4abf-ad0e-e2e4743ee9a8.wav", "formula": "$$\\frac{△{c}_{(A)}}{△t}$$", "answer": "时间变化量分之A的浓度变化量", "subset": "ChemEquation", "task_type": "tts"} +{"index": 463, "question": "请你朗读以下化学公式符号:$$Fe+2H^{+}═Fe^{2+}+H_{2}\\uparrow$$", "audio_path": "audio/chemistry_5fe30ff7-ca7d-4729-8bb8-f88609d24c94.wav", "formula": "$$Fe+2H^{+}═Fe^{2+}+H_{2}\\uparrow$$", "answer": "铁和氢离子反应生成亚铁离子和氢气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 464, "question": "请你朗读以下化学公式符号:$NaOH+HCl═NaCl+H_{2}O$", "audio_path": "audio/chemistry_f927d3af-5093-4874-9ff5-18e3a2cd354e.wav", "formula": "$NaOH+HCl═NaCl+H_{2}O$", "answer": "氢氧化钠和盐酸反应生成氯化钠和水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 465, "question": "请你朗读以下化学公式符号:$0.1mol/L K_{2}CO_{3}$", "audio_path": "audio/chemistry_337daec3-0308-4a09-9924-8fc149ff389f.wav", "formula": "$0.1mol/L K_{2}CO_{3}$", "answer": "零点一摩尔每升的碳酸钾", "subset": "ChemEquation", "task_type": "tts"} +{"index": 466, "question": "请你朗读以下化学公式符号:$Ba\\left(HCO_{3}\\right)_{2}$", "audio_path": "audio/chemistry_684c91e1-45cc-4992-a1ef-9e75ca0631c7.wav", "formula": "$Ba\\left(HCO_{3}\\right)_{2}$", "answer": "碳酸氢钡", "subset": "ChemEquation", "task_type": "tts"} +{"index": 467, "question": "请你朗读以下化学公式符号:$0.50molBa\\left(OH\\right)_{2}$", "audio_path": "audio/chemistry_f6fff53f-7c4a-40f2-a331-c00d8bcd2242.wav", "formula": "$0.50molBa\\left(OH\\right)_{2}$", "answer": "零点五零摩尔氢氧化钡", "subset": "ChemEquation", "task_type": "tts"} +{"index": 468, "question": "请你朗读以下化学公式符号:$4P+5O_{2}\\xlongequal{点燃} 2P_{2}O_5$", "audio_path": "audio/chemistry_a62a545e-d707-48a3-9098-c7090d742602.wav", "formula": "$4P+5O_{2}\\xlongequal{点燃} 2P_{2}O_5$", "answer": "磷和氧气在点燃的条件下反应生成五氧化二磷", "subset": "ChemEquation", "task_type": "tts"} +{"index": 469, "question": "请你朗读以下化学公式符号:$$\\frac{c(NO)•c(S{O}_{3})}{c(N{O}_{2})•c(S{O}_{2})}$$", "audio_path": "audio/chemistry_ecaf7beb-65b0-41fd-ab34-f0595c754fa8.wav", "formula": "$$\\frac{c(NO)•c(S{O}_{3})}{c(N{O}_{2})•c(S{O}_{2})}$$", "answer": "二氧化氮的浓度乘二氧化硫的浓度的积分之一氧化氮的浓度乘三氧化硫的浓度的积", "subset": "ChemEquation", "task_type": "tts"} +{"index": 470, "question": "请你朗读以下化学公式符号:$$\\left(Na_{2}O_{2}\\right)$$", "audio_path": "audio/chemistry_07b02478-3fb7-4861-90c8-d7ce8be0ba33.wav", "formula": "$$\\left(Na_{2}O_{2}\\right)$$", "answer": "过氧化钠", "subset": "ChemEquation", "task_type": "tts"} +{"index": 471, "question": "请你朗读以下化学公式符号:$$3Fe+2O_{2}═Fe_{3}O_{4}$$", "audio_path": "audio/chemistry_25b2639d-e8e8-4381-aafb-6a1e2eb023ff.wav", "formula": "$$3Fe+2O_{2}═Fe_{3}O_{4}$$", "answer": "铁和氧气反应生成四氧化三铁", "subset": "ChemEquation", "task_type": "tts"} +{"index": 472, "question": "请你朗读以下化学公式符号:$$Na^{+} 、K^{+} 、OH^{-} 、Cl^{-}$$", "audio_path": "audio/chemistry_38a39bec-81a4-4e28-bb4d-229b4fccecdb.wav", "formula": "$$Na^{+} 、K^{+} 、OH^{-} 、Cl^{-}$$", "answer": "钠离子、钾离子、氢氧根离子、氯离子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 473, "question": "请你朗读以下化学公式符号:$\\frac{n\\left(H_{2}\\right)}{n\\left(CO_{2}\\right)}$", "audio_path": "audio/chemistry_bbd21c27-3f9c-4c6f-903f-d936aa848631.wav", "formula": "$\\frac{n\\left(H_{2}\\right)}{n\\left(CO_{2}\\right)}$", "answer": "二氧化碳的物质的量分之氢气的物质的量", "subset": "ChemEquation", "task_type": "tts"} +{"index": 474, "question": "请你朗读以下化学公式符号:$$C_{12}H_{18}OCl_{2}N_{2}$$", "audio_path": "audio/chemistry_54c7c2f9-f982-4633-8a05-5993b8740dae.wav", "formula": "$$C_{12}H_{18}OCl_{2}N_{2}$$", "answer": "一个由十二个碳原子、十八个氢原子、一个氧原子、两个氯原子和两个氮原子构成的分子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 475, "question": "请你朗读以下化学公式符号:$+3{\\mathrm{F}\\mathrm{e}}_{3}{\\mathrm{O}}_{4}$", "audio_path": "audio/chemistry_19791a69-6a02-457c-8a01-afce3e12a624.wav", "formula": "$+3{\\mathrm{F}\\mathrm{e}}_{3}{\\mathrm{O}}_{4}$", "answer": "加三个四氧化三铁分子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 476, "question": "请你朗读以下化学公式符号:$$\\left(1\\right)Na_{2}CO_{3}$$", "audio_path": "audio/chemistry_c6a3c09d-4e3f-4780-bcbd-54c5b3018036.wav", "formula": "$$\\left(1\\right)Na_{2}CO_{3}$$", "answer": "一 碳酸钠", "subset": "ChemEquation", "task_type": "tts"} +{"index": 477, "question": "请你朗读以下化学公式符号:$\\left(2\\right)10.0g$", "audio_path": "audio/chemistry_9445bff7-34aa-40f0-9726-e157a086ccdb.wav", "formula": "$\\left(2\\right)10.0g$", "answer": "二 十点零克", "subset": "ChemEquation", "task_type": "tts"} +{"index": 478, "question": "请你朗读以下化学公式符号:$3Fe+2NO^{−}_{3}+8H^{+}═3Fe^{2+}+2NO\\uparrow+4H_{2}O$", "audio_path": "audio/chemistry_2adb8f59-0c83-4076-83a7-8db2aa5fc120.wav", "formula": "$3Fe+2NO^{−}_{3}+8H^{+}═3Fe^{2+}+2NO\\uparrow+4H_{2}O$", "answer": "铁、硝酸根离子和氢离子反应生成亚铁离子、一氧化氮气体和水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 479, "question": "请你朗读以下化学公式符号:$2FeO^{2−}_{4}+10H^{+}+6e^{−}=Fe_{2}O_{3}+5H_{2}O$", "audio_path": "audio/chemistry_b7b74b3e-c3e7-420b-9c34-8c46401afde8.wav", "formula": "$2FeO^{2−}_{4}+10H^{+}+6e^{−}=Fe_{2}O_{3}+5H_{2}O$", "answer": "两个高铁酸根离子和十个氢离子得到六个电子生成氧化铁和五个水分子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 480, "question": "请你朗读以下化学公式符号:$HNO_{3}KOHNaNO_{3}$", "audio_path": "audio/chemistry_0004eaf5-d928-4e91-a162-b6ec19af4b3b.wav", "formula": "$HNO_{3}KOHNaNO_{3}$", "answer": "硝酸、氢氧化钾、硝酸钠", "subset": "ChemEquation", "task_type": "tts"} +{"index": 481, "question": "请你朗读以下化学公式符号:$CaO+H_{2}O=Ca(OH)_{2}$", "audio_path": "audio/chemistry_c4f66a60-c07c-4a24-95b4-f9e37bd4b5c8.wav", "formula": "$CaO+H_{2}O=Ca(OH)_{2}$", "answer": "氧化钙和水反应生成氢氧化钙", "subset": "ChemEquation", "task_type": "tts"} +{"index": 482, "question": "请你朗读以下化学公式符号:$\\left[Cu_{2}\\left(OH\\right)_{2}CO_{3}\\right]:$", "audio_path": "audio/chemistry_de987c40-5c75-46b6-bf23-5d0cf0794a02.wav", "formula": "$\\left[Cu_{2}\\left(OH\\right)_{2}CO_{3}\\right]:$", "answer": "碱式碳酸铜", "subset": "ChemEquation", "task_type": "tts"} +{"index": 483, "question": "请你朗读以下化学公式符号:$Ca\\left(ClO\\right)_{2}$", "audio_path": "audio/chemistry_05b1a2b6-37c5-4136-b93f-24681dfb217d.wav", "formula": "$Ca\\left(ClO\\right)_{2}$", "answer": "次氯酸钙", "subset": "ChemEquation", "task_type": "tts"} +{"index": 484, "question": "请你朗读以下化学公式符号:$$\\left(C_{3}O_{3}N_{3}Cl_{3}\\right),$$", "audio_path": "audio/chemistry_fd6bca36-3b04-4d91-b18f-73ec0e206b52.wav", "formula": "$$\\left(C_{3}O_{3}N_{3}Cl_{3}\\right),$$", "answer": "一个由三个碳原子、三个氧原子、三个氮原子和三个氯原子构成的分子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 485, "question": "请你朗读以下化学公式符号:$KIO_{3}+5KI+3H_{2}SO_{4}═3I_{2}+3K_{2}SO_{4}+3H_{2}O$", "audio_path": "audio/chemistry_10cf2279-6560-4ea9-875e-5116f34cc0cf.wav", "formula": "$KIO_{3}+5KI+3H_{2}SO_{4}═3I_{2}+3K_{2}SO_{4}+3H_{2}O$", "answer": "碘酸钾,碘化钾和硫酸反应生成碘单质、硫酸钾和水", "subset": "ChemEquation", "task_type": "tts"} +{"index": 486, "question": "请你朗读以下化学公式符号:$Ag^{+}+NH_{3} \\cdot H_{2}O \\xlongequal{} AgOH\\downarrow+NH_{4}^{+}$", "audio_path": "audio/chemistry_61d3b1f2-ff21-4d92-a4d5-42025cb9420e.wav", "formula": "$Ag^{+}+NH_{3} \\cdot H_{2}O \\xlongequal{} AgOH\\downarrow+NH_{4}^{+}$", "answer": "银离子和一水合氨反应生成氢氧化银沉淀和铵根离子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 487, "question": "请你朗读以下化学公式符号:$$1.993\\times10^{-26}\\,\\mathrm{kg}$$", "audio_path": "audio/chemistry_35af2057-90d6-4c47-b820-f31d203ce00e.wav", "formula": "$$1.993\\times10^{-26}\\,\\mathrm{kg}$$", "answer": "一点九九三乘十的负二十六次方千克", "subset": "ChemEquation", "task_type": "tts"} +{"index": 488, "question": "请你朗读以下化学公式符号:$Fe+CrCl_{2}═Cr+FeCl_{2}$", "audio_path": "audio/chemistry_0ff19552-6efa-496c-869e-1fb888fdfe79.wav", "formula": "$Fe+CrCl_{2}═Cr+FeCl_{2}$", "answer": "铁和氯化铬反应生成铬和氯化亚铁", "subset": "ChemEquation", "task_type": "tts"} +{"index": 489, "question": "请你朗读以下化学公式符号:$$CO+PdCl_{2}+H_{2}O═2HCl+Pd+X$$", "audio_path": "audio/chemistry_a309e140-bcf0-4b81-9062-2047113015bb.wav", "formula": "$$CO+PdCl_{2}+H_{2}O═2HCl+Pd+X$$", "answer": "一氧化碳、氯化钯和水反应生成盐酸、钯单质和X", "subset": "ChemEquation", "task_type": "tts"} +{"index": 490, "question": "请你朗读以下化学公式符号:$Zn+2OH^{−}−2e=Zn\\left(OH\\right)_{2} ,Ag_{2}O+H_{2}O+2e^{−}=2Ag+2OH^{−}$", "audio_path": "audio/chemistry_5cd49ec5-e328-41db-a4a4-aa13919d5080.wav", "formula": "$Zn+2OH^{−}−2e=Zn\\left(OH\\right)_{2} ,Ag_{2}O+H_{2}O+2e^{−}=2Ag+2OH^{−}$", "answer": "锌和两个氢氧根离子失去两个电子反应生成氢氧化锌;氧化银和一个水分子得到两个电子反应生成两个银和两个氢氧根离子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 491, "question": "请你朗读以下化学公式符号:$NaHCO_{3}+NH_{4}Cl$", "audio_path": "audio/chemistry_97f2369e-ef9a-4d5d-841a-c0cfbea28c32.wav", "formula": "$NaHCO_{3}+NH_{4}Cl$", "answer": "一个碳酸氢钠加一个氯化铵", "subset": "ChemEquation", "task_type": "tts"} +{"index": 492, "question": "请你朗读以下化学公式符号:$N_{2}\\left(g\\right)+3H_{2} \\left(g\\right)⇌2NH_{3}\\left(g\\right)$", "audio_path": "audio/chemistry_f23c6d99-0f87-4c2d-80e5-bdb35cd2ef72.wav", "formula": "$N_{2}\\left(g\\right)+3H_{2} \\left(g\\right)⇌2NH_{3}\\left(g\\right)$", "answer": "一摩尔的气态氮气和三摩尔的气态氢气反应生成两摩尔的气态氨气", "subset": "ChemEquation", "task_type": "tts"} +{"index": 493, "question": "请你朗读以下化学公式符号:$$\\left(NaNO_{2}\\right)$$", "audio_path": "audio/chemistry_7eef0129-d3c5-47db-a9ce-cd48ef71eb55.wav", "formula": "$$\\left(NaNO_{2}\\right)$$", "answer": "亚硝酸钠", "subset": "ChemEquation", "task_type": "tts"} +{"index": 494, "question": "请你朗读以下化学公式符号:$$\\left(CH_{4}⋅nH_{2}O\\right)$$", "audio_path": "audio/chemistry_69c7712e-1389-46f3-91b3-ef02ed23cc17.wav", "formula": "$$\\left(CH_{4}⋅nH_{2}O\\right)$$", "answer": "甲烷水合物", "subset": "ChemEquation", "task_type": "tts"} +{"index": 495, "question": "请你朗读以下化学公式符号:$$C_{15}H_{22}O_{5}$$", "audio_path": "audio/chemistry_88761d94-cb05-4105-a5db-a34576a9d418.wav", "formula": "$$C_{15}H_{22}O_{5}$$", "answer": "一个由十五个碳原子、二十二个氢原子和五个氧原子构成的分子", "subset": "ChemEquation", "task_type": "tts"} +{"index": 496, "question": "请你朗读以下化学公式符号:$H_{2} \\left(mol\\right)$", "audio_path": "audio/chemistry_28eb1465-eef3-4f66-b7be-a637f67b4965.wav", "formula": "$H_{2} \\left(mol\\right)$", "answer": "氢气 摩尔", "subset": "ChemEquation", "task_type": "tts"} +{"index": 497, "question": "请你朗读以下化学公式符号:${{{H}}_{2}}{{{O}}_{2}}$", "audio_path": "audio/chemistry_962f9d3e-0462-490c-a005-481641d4afd3.wav", "formula": "${{{H}}_{2}}{{{O}}_{2}}$", "answer": "过氧化氢", "subset": "ChemEquation", "task_type": "tts"} +{"index": 498, "question": "请你朗读以下化学公式符号:${2Na+2}{{{H}}_{{2}}}{O}=\\!=\\!={{{H}}_{2}}\\uparrow {+2NaOH}$", "audio_path": "audio/chemistry_19ab625b-5e09-40a5-b536-e32a5ea47fa6.wav", "formula": "${2Na+2}{{{H}}_{{2}}}{O}=\\!=\\!={{{H}}_{2}}\\uparrow {+2NaOH}$", "answer": "钠和水反应生成氢气和氢氧化钠", "subset": "ChemEquation", "task_type": "tts"} +{"index": 499, "question": "请你朗读以下化学公式符号:$0.1mol⋅L^{−1}CH_{3}COOH$", "audio_path": "audio/chemistry_20e7f491-977e-4a7a-a8be-15c2b348e815.wav", "formula": "$0.1mol⋅L^{−1}CH_{3}COOH$", "answer": "零点一摩尔每升乙酸", "subset": "ChemEquation", "task_type": "tts"} +{"index": 500, "question": "Please read the following chemistry formula symbols: $\\frac{c\\left(H^{+}\\right)}{c\\left(OH^{-}\\right)}=1\\times10^{-12}$", "audio_path": "audio/chemistry_c05d5740-cb77-4ef7-8983-e350aa798db5.wav", "formula": "$\\frac{c\\left(H^{+}\\right)}{c\\left(OH^{-}\\right)}=1\\times10^{-12}$", "answer": "The concentration of hydrogen ion divided by the concentration of hydroxide ion equals one times ten to the power of negative twelve.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 501, "question": "Please read the following chemistry formula symbols: $$Na_{2}CO_{3}+2HCl \\xlongequal{} 2NaCl+H_{2}O+CO_{2}\\uparrow$$", "audio_path": "audio/chemistry_ebd1cbbb-4d21-4618-9687-c93334b27826.wav", "formula": "$$Na_{2}CO_{3}+2HCl \\xlongequal{} 2NaCl+H_{2}O+CO_{2}\\uparrow$$", "answer": "Sodium carbonate plus two molecules of hydrogen chloride produce two molecules of sodium chloride, one molecule of water, and one molecule of carbon dioxide gas", "subset": "ChemEquation", "task_type": "tts"} +{"index": 502, "question": "Please read the following chemistry formula symbols: $$2X+15O_{2}═12CO_{2}+6H_{2}O$$", "audio_path": "audio/chemistry_aa0cfc07-487b-4c96-866a-842fb94f0e93.wav", "formula": "$$2X+15O_{2}═12CO_{2}+6H_{2}O$$", "answer": "Two molecules of X plus fifteen molecules of oxygen produce twelve molecules of carbon dioxide plus six molecules of water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 503, "question": "Please read the following chemistry formula symbols: $2Fe+6HCl=2FeCl_{2}+3H_{2}\\uparrow$", "audio_path": "audio/chemistry_01726727-4200-4087-ba95-908ce94aca6d.wav", "formula": "$2Fe+6HCl=2FeCl_{2}+3H_{2}\\uparrow$", "answer": "Two atoms of iron plus six molecules of hydrochloric acid produce two molecules of iron(III) chloride plus three molecules of hydrogen.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 504, "question": "Please read the following chemistry formula symbols: ${ }^{1}_{1}H { }^{2}_{1}H { }^{3}_{1}H$", "audio_path": "audio/chemistry_d93646d1-0a22-404f-a386-adc715adf204.wav", "formula": "${ }^{1}_{1}H { }^{2}_{1}H { }^{3}_{1}H$", "answer": "hydrogen one, hydrogen two, and hydrogen three", "subset": "ChemEquation", "task_type": "tts"} +{"index": 505, "question": "Please read the following chemistry formula symbols: $3NO_{2}+H_{2}O=2HNO_{3}+NO$", "audio_path": "audio/chemistry_fe2dda28-77dc-4b72-8787-df2bfb25d554.wav", "formula": "$3NO_{2}+H_{2}O=2HNO_{3}+NO$", "answer": "Three molecules of nitrogen dioxide plus one molecule of water produce two molecules of nitric acid plus one molecule of nitric oxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 506, "question": "Please read the following chemistry formula symbols: $2.0mol⋅L^{−1}Ca\\left(OH\\right)_{2}$", "audio_path": "audio/chemistry_f3bff2aa-de8a-4e9b-819e-a9154a28bf29.wav", "formula": "$2.0mol⋅L^{−1}Ca\\left(OH\\right)_{2}$", "answer": "Two point zero moles per liter of calcium hydroxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 507, "question": "Please read the following chemistry formula symbols: $$CO_{2}\\left(CO\\right)$$", "audio_path": "audio/chemistry_e05d8ae3-4cd3-4e8e-8980-7d7229293681.wav", "formula": "$$CO_{2}\\left(CO\\right)$$", "answer": "dicarbon trioxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 508, "question": "Please read the following chemistry formula symbols: $\\left(2\\right)\\left(6\\right)$", "audio_path": "audio/chemistry_45d750fb-a431-416d-bffe-f0e86033dc72.wav", "formula": "$\\left(2\\right)\\left(6\\right)$", "answer": "left parenthesis two right parenthesis left parenthesis six right parenthesis", "subset": "ChemEquation", "task_type": "tts"} +{"index": 509, "question": "Please read the following chemistry formula symbols: $OH ^{−^{ }}+H^{+}═H_{2}O$", "audio_path": "audio/chemistry_17bf644d-92ef-4e8e-9c00-0be934d1677c.wav", "formula": "$OH ^{−^{ }}+H^{+}═H_{2}O$", "answer": "Hydroxide one minus ion plus hydrogen one plus ion produces one molecule of water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 510, "question": "Please read the following chemistry formula symbols: $$A_{2}(g)+B_{2}(g)═2AB(g)$$", "audio_path": "audio/chemistry_5c2507db-322b-48af-ab25-de67729ab295.wav", "formula": "$$A_{2}(g)+B_{2}(g)═2AB(g)$$", "answer": "One molecule of A two gas plus one molecule of B two gas produce two molecules of AB gas.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 511, "question": "Please read the following chemistry formula symbols: $Mg^{2+}+2OH^{−}═Mg \\left(OH\\right)_{2}\\downarrow$", "audio_path": "audio/chemistry_80bbd1bf-39c8-409b-a608-8d88c61b3dcc.wav", "formula": "$Mg^{2+}+2OH^{−}═Mg \\left(OH\\right)_{2}\\downarrow$", "answer": "The magnesium two plus ion plus two hydroxide ions produce solid magnesium hydroxide.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 512, "question": "Please read the following chemistry formula symbols: $2CO_{2}\\left(g\\right)=2CO\\left(g\\right)+O_{2}\\left(g\\right)$", "audio_path": "audio/chemistry_49846df4-3b2e-4494-9a09-57ef473bcf1d.wav", "formula": "$2CO_{2}\\left(g\\right)=2CO\\left(g\\right)+O_{2}\\left(g\\right)$", "answer": "Two molecules of carbon dioxide gas produce two molecules of carbon monoxide gas plus one molecule of oxygen gas", "subset": "ChemEquation", "task_type": "tts"} +{"index": 513, "question": "Please read the following chemistry formula symbols: ${{K}_2}{Mn}{{O}_4}$", "audio_path": "audio/chemistry_fd7b1ef9-5a41-4058-bba8-d899b898f4a9.wav", "formula": "${{K}_2}{Mn}{{O}_4}$", "answer": "potassium manganate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 514, "question": "Please read the following chemistry formula symbols: $$HXO_{4}>H_{2}YO_{4}>H_{3}ZO_{4}$$", "audio_path": "audio/chemistry_c59072a8-e44d-46f4-9cf3-93f9d7abf12f.wav", "formula": "$$HXO_{4}>H_{2}YO_{4}>H_{3}ZO_{4}$$", "answer": "Hydrogen X O four is greater than hydrogen two Y O four is greater than hydrogen three Z O four", "subset": "ChemEquation", "task_type": "tts"} +{"index": 515, "question": "Please read the following chemistry formula symbols: $2{NaOH}+{C}{{{l}}_{2}}=\\!=\\!={NaCl}+{NaClO}+{{{H}}_{2}}{O}$", "audio_path": "audio/chemistry_83befa51-7b61-45a6-9518-348df7dd78eb.wav", "formula": "$2{NaOH}+{C}{{{l}}_{2}}=\\!=\\!={NaCl}+{NaClO}+{{{H}}_{2}}{O}$", "answer": "Two molecules of sodium hydroxide plus one molecule of chlorine gas produce one molecule of sodium chloride, one molecule of sodium hypochlorite, and one molecule of water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 516, "question": "Please read the following chemistry formula symbols: $c(OH^{−})=0.3mol/L$", "audio_path": "audio/chemistry_b0e62bbf-905c-4c8b-987a-31f0a37bc6cb.wav", "formula": "$c(OH^{−})=0.3mol/L$", "answer": "The concentration of hydroxide minus ion equals zero point three moles per liter.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 517, "question": "Please read the following chemistry formula symbols: $NaHSO_{4}, NH_{4}Cl$", "audio_path": "audio/chemistry_d2f57bb4-76eb-48ba-82f7-5780d9de5857.wav", "formula": "$NaHSO_{4}, NH_{4}Cl$", "answer": "One molecule of sodium hydrogen sulfate and one molecule of ammonium chloride", "subset": "ChemEquation", "task_type": "tts"} +{"index": 518, "question": "Please read the following chemistry formula symbols: $$SO_{3}+H_{2}O= H_{2}SO_{4}$$", "audio_path": "audio/chemistry_560d10ab-3135-473d-b296-188dd5301ce6.wav", "formula": "$$SO_{3}+H_{2}O= H_{2}SO_{4}$$", "answer": "One molecule of sulfur trioxide plus one molecule of water produces one molecule of sulfuric acid", "subset": "ChemEquation", "task_type": "tts"} +{"index": 519, "question": "Please read the following chemistry formula symbols: $NaHSO_{4}═Na^{+}+H^{+}+SO^{2−}_{4}$", "audio_path": "audio/chemistry_25e433c4-490d-4fd5-93d8-94e85753bfc1.wav", "formula": "$NaHSO_{4}═Na^{+}+H^{+}+SO^{2−}_{4}$", "answer": "Sodium bisulfate produces sodium ion plus hydrogen ion plus sulfate two minus ion", "subset": "ChemEquation", "task_type": "tts"} +{"index": 520, "question": "Please read the following chemistry formula symbols: $CO\\left(g\\right)+H_{2}O\\left(g\\right)⇌H_{2}\\left(g\\right)+CO_{2}\\left(g\\right)$", "audio_path": "audio/chemistry_420da4f8-b9f1-47c4-be3d-de58134cfdd8.wav", "formula": "$CO\\left(g\\right)+H_{2}O\\left(g\\right)⇌H_{2}\\left(g\\right)+CO_{2}\\left(g\\right)$", "answer": "Carbon monoxide gas plus water vapor reversibly produces hydrogen gas and carbon dioxide gas.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 521, "question": "Please read the following chemistry formula symbols: $\\frac{58.5}{44}=\\frac{y}{6.6~{g}}$", "audio_path": "audio/chemistry_c5b97b1e-af82-4e0f-b6ec-dcf20f441b75.wav", "formula": "$\\frac{58.5}{44}=\\frac{y}{6.6~{g}}$", "answer": "Fifty-eight point five divided by forty-four yields y divided by six point six grams", "subset": "ChemEquation", "task_type": "tts"} +{"index": 522, "question": "Please read the following chemistry formula symbols: $1.0molB\\left( g \\right)$", "audio_path": "audio/chemistry_cd050db5-860c-4463-b203-ec085bddf1e5.wav", "formula": "$1.0molB\\left( g \\right)$", "answer": "one point zero moles of boron gas", "subset": "ChemEquation", "task_type": "tts"} +{"index": 523, "question": "Please read the following chemistry formula symbols: $Cl_{2}(g)$", "audio_path": "audio/chemistry_2360a12d-25b6-43a4-81dd-e8b4a21ec5b5.wav", "formula": "$Cl_{2}(g)$", "answer": "one molecule of chlorine gas", "subset": "ChemEquation", "task_type": "tts"} +{"index": 524, "question": "Please read the following chemistry formula symbols: $$F_{2}>Cl_{2}>Br_{2}>I_{2}$$", "audio_path": "audio/chemistry_a253b660-37bf-41f9-a364-480c57b43d2c.wav", "formula": "$$F_{2}>Cl_{2}>Br_{2}>I_{2}$$", "answer": "One molecule of fluorine produces one molecule of chlorine, which produces one molecule of bromine, which produces one molecule of iodine", "subset": "ChemEquation", "task_type": "tts"} +{"index": 525, "question": "Please read the following chemistry formula symbols: $\\frac{c(N{{H}_{4}}^{+})}{c(N{H}_{3}•{H}_{2}O)}$", "audio_path": "audio/chemistry_4e1b2545-8441-4414-ad71-3085ed39f862.wav", "formula": "$\\frac{c(N{{H}_{4}}^{+})}{c(N{H}_{3}•{H}_{2}O)}$", "answer": "The concentration of ammonium ion plus one divided by the concentration of ammonium hydroxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 526, "question": "Please read the following chemistry formula symbols: $n(\\mathrm{Fe}) = 2\\,\\mathrm{mol} + 3\\,\\mathrm{mol} + 4\\,\\mathrm{mol} = 9\\,\\mathrm{mol}$", "audio_path": "audio/chemistry_f4a184d0-f999-4ad8-a34f-1e87b8d915e1.wav", "formula": "$n(\\mathrm{Fe}) = 2\\,\\mathrm{mol} + 3\\,\\mathrm{mol} + 4\\,\\mathrm{mol} = 9\\,\\mathrm{mol}$", "answer": "The amount of iron equals two moles plus three moles plus four moles, which equals nine moles.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 527, "question": "Please read the following chemistry formula symbols: $$C_{10}H_{14}N_{2}$$", "audio_path": "audio/chemistry_88a5bc27-001f-4e60-a36f-bb7d2c239d42.wav", "formula": "$$C_{10}H_{14}N_{2}$$", "answer": "nicotine", "subset": "ChemEquation", "task_type": "tts"} +{"index": 528, "question": "Please read the following chemistry formula symbols: $$aA\\left(g\\right)+bB\\left(g\\right)$$", "audio_path": "audio/chemistry_bbadcc3a-ce06-49b1-9b62-97084ec65793.wav", "formula": "$$aA\\left(g\\right)+bB\\left(g\\right)$$", "answer": "a atoms of A gas plus b atoms of B gas", "subset": "ChemEquation", "task_type": "tts"} +{"index": 529, "question": "Please read the following chemistry formula symbols: $\\left(mol/L\\right)0.30.150.3$", "audio_path": "audio/chemistry_e779411c-bbf0-4b8e-b0d9-1bfd024ac790.wav", "formula": "$\\left(mol/L\\right)0.30.150.3$", "answer": "zero point three, zero point one five, zero point three moles per liter", "subset": "ChemEquation", "task_type": "tts"} +{"index": 530, "question": "Please read the following chemistry formula symbols: $$\\left(1\\right)Cl_{2}+SO_{2}+2H_{2}O$$", "audio_path": "audio/chemistry_842d323a-a87f-42b1-80a0-0a8a98df48d6.wav", "formula": "$$\\left(1\\right)Cl_{2}+SO_{2}+2H_{2}O$$", "answer": "One molecule of chlorine plus sulfur dioxide plus two molecules of water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 531, "question": "Please read the following chemistry formula symbols: $Ca(OH)_{2}+2NH_{4}Cl=CaCl_{2}+2NH_{3}\\uparrow+2H_{2}O$", "audio_path": "audio/chemistry_343aecbf-0841-49cf-a680-33c94227e3f5.wav", "formula": "$Ca(OH)_{2}+2NH_{4}Cl=CaCl_{2}+2NH_{3}\\uparrow+2H_{2}O$", "answer": "Calcium hydroxide plus two molecules of ammonium chloride produce calcium chloride plus two molecules of ammonia gas plus two molecules of water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 532, "question": "Please read the following chemistry formula symbols: $2HSCN+K_{2}CO_{3}=2KSCN+CO_{2}\\uparrow+H_{2}O$", "audio_path": "audio/chemistry_96f28677-ea5d-4f3f-afd0-91389d64dfce.wav", "formula": "$2HSCN+K_{2}CO_{3}=2KSCN+CO_{2}\\uparrow+H_{2}O$", "answer": "Two molecules of hydrogen thiocyanate plus one molecule of potassium carbonate produce two molecules of potassium thiocyanate plus one molecule of carbon dioxide gas plus one molecule of water.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 533, "question": "Please read the following chemistry formula symbols: $Fe+H_{2}SO_{4}=FeSO_{4}+H_{2}\\uparrow$", "audio_path": "audio/chemistry_4180bc82-bccf-47a4-bd77-ce06ed579ff0.wav", "formula": "$Fe+H_{2}SO_{4}=FeSO_{4}+H_{2}\\uparrow$", "answer": "Iron plus sulfuric acid produces iron(II) sulfate plus hydrogen gas", "subset": "ChemEquation", "task_type": "tts"} +{"index": 534, "question": "Please read the following chemistry formula symbols: $8Cu+4FeO+2Fe_{2}O_{3}+16SO_{2}$", "audio_path": "audio/chemistry_ffef6b0f-9c26-490a-be21-2f5d6a57ff38.wav", "formula": "$8Cu+4FeO+2Fe_{2}O_{3}+16SO_{2}$", "answer": "Eight atoms of copper plus four molecules of iron(II) oxide plus two molecules of iron(III) oxide plus sixteen molecules of sulfur dioxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 535, "question": "Please read the following chemistry formula symbols: $\\rightarrow CH_{3}OH+HCOONa$", "audio_path": "audio/chemistry_13cf4b6b-5c05-417b-9967-22dac1fd6402.wav", "formula": "$\\rightarrow CH_{3}OH+HCOONa$", "answer": "produces one molecule of methanol plus one molecule of sodium formate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 536, "question": "Please read the following chemistry formula symbols: $△H=−57.3kJ⋅mol^{−1}$", "audio_path": "audio/chemistry_0c33b0f5-782f-4228-9a89-a99ce144adf8.wav", "formula": "$△H=−57.3kJ⋅mol^{−1}$", "answer": "Delta H produces negative fifty-seven point three kilojoules per mole", "subset": "ChemEquation", "task_type": "tts"} +{"index": 537, "question": "Please read the following chemistry formula symbols: $V\\left(CH_{3}COOH\\right) < V\\left(NaOH\\right)$", "audio_path": "audio/chemistry_9e8adf9b-a0e7-4cae-bb91-ae8cb1cf87c1.wav", "formula": "$V\\left(CH_{3}COOH\\right) < V\\left(NaOH\\right)$", "answer": "The volume of acetic acid is less than the volume of sodium hydroxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 538, "question": "Please read the following chemistry formula symbols: $117~{g}\\times 20\\%=23.4~{g}$", "audio_path": "audio/chemistry_5e22559b-0efd-4577-b558-7d559a15824f.wav", "formula": "$117~{g}\\times 20\\%=23.4~{g}$", "answer": "One hundred seventeen grams times twenty percent equals twenty-three point four grams", "subset": "ChemEquation", "task_type": "tts"} +{"index": 539, "question": "Please read the following chemistry formula symbols: $NaClO$ $ Na_{2}SO_{3}$ $ Na_{2}CO_{3} $ $CaCO_{3}$", "audio_path": "audio/chemistry_24e70efa-6a0b-43fc-ae3b-b3a4417eaf3e.wav", "formula": "$NaClO$ $ Na_{2}SO_{3}$ $ Na_{2}CO_{3} $ $CaCO_{3}$", "answer": "sodium hypochlorite, sodium sulfite, sodium carbonate, and calcium carbonate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 540, "question": "Please read the following chemistry formula symbols: $\\frac{c(H^{+})•c(NH_{3}•H_{2}O)}{c(NH_{4}^{+})}$", "audio_path": "audio/chemistry_0e7f11c6-3c41-4fec-925b-b5ff15b98c61.wav", "formula": "$\\frac{c(H^{+})•c(NH_{3}•H_{2}O)}{c(NH_{4}^{+})}$", "answer": "The ratio of the product of the concentration of hydrogen ion and the concentration of ammonia monohydrate to the concentration of ammonium ion", "subset": "ChemEquation", "task_type": "tts"} +{"index": 541, "question": "Please read the following chemistry formula symbols: $Cl_{2}+H_{2}O\\rightleftharpoons HCl+HClO$", "audio_path": "audio/chemistry_71359bbd-254f-442f-a9fe-714b18bf47c1.wav", "formula": "$Cl_{2}+H_{2}O\\rightleftharpoons HCl+HClO$", "answer": "One molecule of chlorine plus one molecule of water reversibly produces one molecule of hydrogen chloride plus one molecule of hypochlorous acid", "subset": "ChemEquation", "task_type": "tts"} +{"index": 542, "question": "Please read the following chemistry formula symbols: $\\left(4\\right)GaF_{3}$", "audio_path": "audio/chemistry_6e60ad67-6ecd-42af-8022-fe72324eb862.wav", "formula": "$\\left(4\\right)GaF_{3}$", "answer": "four molecules of gallium fluoride", "subset": "ChemEquation", "task_type": "tts"} +{"index": 543, "question": "Please read the following chemistry formula symbols: $\\left(a+b\\right)g B$", "audio_path": "audio/chemistry_58f8b05d-0b39-456d-8508-73b769b08632.wav", "formula": "$\\left(a+b\\right)g B$", "answer": "open parenthesis a plus b close parenthesis multiplied by g multiplied by B", "subset": "ChemEquation", "task_type": "tts"} +{"index": 544, "question": "Please read the following chemistry formula symbols: $$2Na+O_{2}═Na_{2}O_{2}$$", "audio_path": "audio/chemistry_07e362c7-31fc-4290-9914-b6de1523de1e.wav", "formula": "$$2Na+O_{2}═Na_{2}O_{2}$$", "answer": "Two atoms of sodium plus one molecule of oxygen produce one molecule of sodium peroxide.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 545, "question": "Please read the following chemistry formula symbols: $$H_{2}O<H_{2}S<HBr<HCl$$", "audio_path": "audio/chemistry_6dd32005-b41f-43a4-ae4b-bb2a3732d2b4.wav", "formula": "$$H_{2}O<H_{2}S<HBr<HCl$$", "answer": "Water is less than hydrogen sulfide is less than hydrogen bromide is less than hydrogen chloride", "subset": "ChemEquation", "task_type": "tts"} +{"index": 546, "question": "Please read the following chemistry formula symbols: $K=\\frac{K_{sp}\\left(FeS\\right)}{K_{sp}\\left(PbS\\right)}$", "audio_path": "audio/chemistry_82a2ce88-2aaa-4deb-93da-345ff7436c05.wav", "formula": "$K=\\frac{K_{sp}\\left(FeS\\right)}{K_{sp}\\left(PbS\\right)}$", "answer": "K equals the solubility product constant of iron(II) sulfide divided by the solubility product constant of lead(II) sulfide.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 547, "question": "Please read the following chemistry formula symbols: $1.1mol/LNH_{3}⋅H_{2}O$", "audio_path": "audio/chemistry_222015e4-78d3-4665-9b02-488a06ddc4b8.wav", "formula": "$1.1mol/LNH_{3}⋅H_{2}O$", "answer": "1.1 moles per liter of ammonia monohydrate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 548, "question": "Please read the following chemistry formula symbols: $NaCl$ $NaOH$ $NaNO_{3}$", "audio_path": "audio/chemistry_14c65d7c-bf71-4a6e-a6ca-87378f939865.wav", "formula": "$NaCl$ $NaOH$ $NaNO_{3}$", "answer": "sodium chloride sodium hydroxide sodium nitrate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 549, "question": "Please read the following chemistry formula symbols: $\\frac{5.6L}{22.4L/mol}$", "audio_path": "audio/chemistry_b25712e7-b16e-46fb-8df3-2c312396fd08.wav", "formula": "$\\frac{5.6L}{22.4L/mol}$", "answer": "five point six liters divided by twenty-two point four liters per mole", "subset": "ChemEquation", "task_type": "tts"} +{"index": 550, "question": "Please read the following chemistry formula symbols: $CaO+2HCl=CaCl_{2}+H_{2}O$", "audio_path": "audio/chemistry_96ee9223-6ac7-4eef-ab11-49fbd15f8c5a.wav", "formula": "$CaO+2HCl=CaCl_{2}+H_{2}O$", "answer": "one molecule of calcium oxide plus two molecules of hydrogen chloride produce one molecule of calcium chloride plus one molecule of water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 551, "question": "Please read the following chemistry formula symbols: $Mn^{2+}$", "audio_path": "audio/chemistry_dbffd7d7-beba-42ac-a55f-a8dfdddd8cbc.wav", "formula": "$Mn^{2+}$", "answer": "two atoms of manganese", "subset": "ChemEquation", "task_type": "tts"} +{"index": 552, "question": "Please read the following chemistry formula symbols: $2CO_{2}\\left(g\\right)+4H_{2}O\\left(l\\right)△H=−1451.6kJ⋅mol^{−1}$", "audio_path": "audio/chemistry_0592226f-0458-4de9-b257-91e11ee85f93.wav", "formula": "$2CO_{2}\\left(g\\right)+4H_{2}O\\left(l\\right)△H=−1451.6kJ⋅mol^{−1}$", "answer": "Two molecules of carbon dioxide gas plus four molecules of liquid water. Delta H equals negative one thousand four hundred fifty-one point six kilojoules per mole.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 553, "question": "Please read the following chemistry formula symbols: $H_{2}C_{2}O_{4}+MnO^{−}_{4}+H^{+}→CO_{2}↑+Mn^{2+} +H_{2}O$", "audio_path": "audio/chemistry_4e7ef94b-e2fc-44fd-8891-2b25a96e971e.wav", "formula": "$H_{2}C_{2}O_{4}+MnO^{−}_{4}+H^{+}→CO_{2}↑+Mn^{2+} +H_{2}O$", "answer": "One molecule of oxalic acid plus one permanganate ion plus one hydrogen ion produce one molecule of carbon dioxide gas plus one manganese two plus ion plus one molecule of water.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 554, "question": "Please read the following chemistry formula symbols: $HNO_{3}$ $KNO_{3}$ $K_{2}SO_{4}$", "audio_path": "audio/chemistry_be1dcd7a-0391-4017-9359-4bfadcf574c0.wav", "formula": "$HNO_{3}$ $KNO_{3}$ $K_{2}SO_{4}$", "answer": "nitric acid plus potassium nitrate plus potassium sulfate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 555, "question": "Please read the following chemistry formula symbols: $$C_{38}H_{42}N_{2}O_{6}$$", "audio_path": "audio/chemistry_d930620d-c4cc-49c4-8dd1-cb7309aabb75.wav", "formula": "$$C_{38}H_{42}N_{2}O_{6}$$", "answer": "thirty-eight carbon atoms, forty-two hydrogen atoms, two nitrogen atoms, and six oxygen atoms", "subset": "ChemEquation", "task_type": "tts"} +{"index": 556, "question": "Please read the following chemistry formula symbols: $\\frac{c\\left(H^{+}\\right)}{c\\left(CH_{3}COOH\\right)}$", "audio_path": "audio/chemistry_fc169eb3-a435-4a5a-9d3a-cafa2e39b7a0.wav", "formula": "$\\frac{c\\left(H^{+}\\right)}{c\\left(CH_{3}COOH\\right)}$", "answer": "The ratio of the concentration of hydrogen plus ion to the concentration of acetic acid", "subset": "ChemEquation", "task_type": "tts"} +{"index": 557, "question": "Please read the following chemistry formula symbols: $NaOH > Mg(OH)_{2} > Al(OH)_{3}$", "audio_path": "audio/chemistry_b650e9b4-0ba4-4e1c-b445-8dc10471b0aa.wav", "formula": "$NaOH > Mg(OH)_{2} > Al(OH)_{3}$", "answer": "Sodium hydroxide greater than magnesium hydroxide greater than aluminum hydroxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 558, "question": "Please read the following chemistry formula symbols: $\\rm Fe_2O_3+3H_2SO_4=Fe_2(SO_4)_3+3H_2O$", "audio_path": "audio/chemistry_158171eb-b59e-4e56-9b9e-e2354c10e9b6.wav", "formula": "$\\rm Fe_2O_3+3H_2SO_4=Fe_2(SO_4)_3+3H_2O$", "answer": "Iron(III) oxide plus three molecules of sulfuric acid produce iron(III) sulfate plus three molecules of water.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 559, "question": "Please read the following chemistry formula symbols: $V({{{O}}_{2}})=\\frac{5}{4}V({NO})=\\frac{5}{4}\\times 44.8{mL}=56{mL}$", "audio_path": "audio/chemistry_f485cfed-7bf2-45e4-a285-d6e9a50e43dc.wav", "formula": "$V({{{O}}_{2}})=\\frac{5}{4}V({NO})=\\frac{5}{4}\\times 44.8{mL}=56{mL}$", "answer": "The volume of oxygen equals five fourths times the volume of nitrogen monoxide, which equals five fourths multiplied by forty-four point eight milliliters, resulting in fifty-six milliliters.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 560, "question": "Please read the following chemistry formula symbols: $$\\left(NaNO_{2}\\right)$$", "audio_path": "audio/chemistry_387e09ff-4190-4d15-87ab-dadd451a2912.wav", "formula": "$$\\left(NaNO_{2}\\right)$$", "answer": "sodium nitrite", "subset": "ChemEquation", "task_type": "tts"} +{"index": 561, "question": "Please read the following chemistry formula symbols: $$C\\left(s\\right)+CO_{2}\\left(g\\right)⇌2CO\\left(g\\right)$$", "audio_path": "audio/chemistry_89fe04e2-1b2e-47d3-82a0-b1c9de94b70a.wav", "formula": "$$C\\left(s\\right)+CO_{2}\\left(g\\right)⇌2CO\\left(g\\right)$$", "answer": "Solid carbon plus carbon dioxide gas reversibly produces two molecules of carbon monoxide gas", "subset": "ChemEquation", "task_type": "tts"} +{"index": 562, "question": "Please read the following chemistry formula symbols: $\\rm FeCl_3+3NaOH\\ce{\\xlongequal{}}Fe(OH)_3\\downarrow \\rm +3NaCl$", "audio_path": "audio/chemistry_7b32eb48-2c74-40a8-ad6d-16061f99b90f.wav", "formula": "$\\rm FeCl_3+3NaOH\\ce{\\xlongequal{}}Fe(OH)_3\\downarrow \\rm +3NaCl$", "answer": "One molecule of iron(III) chloride plus three molecules of sodium hydroxide produce one molecule of iron(III) hydroxide solid plus three molecules of sodium chloride", "subset": "ChemEquation", "task_type": "tts"} +{"index": 563, "question": "Please read the following chemistry formula symbols: $c\\left(H^{+}\\right)=0.02mol⋅L^{−1}c\\left(Mg^{2+}\\right) =0.01mol⋅L^{−1}$", "audio_path": "audio/chemistry_d68a9b66-80d2-447e-9f4a-aa709bb48590.wav", "formula": "$c\\left(H^{+}\\right)=0.02mol⋅L^{−1}c\\left(Mg^{2+}\\right) =0.01mol⋅L^{−1}$", "answer": "Concentration of hydrogen ion equals zero point zero two moles per liter and concentration of magnesium two plus ion equals zero point zero one moles per liter", "subset": "ChemEquation", "task_type": "tts"} +{"index": 564, "question": "Please read the following chemistry formula symbols: $\\rm CuO+\\rm H_2\\rm SO_4=\\!=\\rm CuSO_4+\\rm H_2\\rm O$", "audio_path": "audio/chemistry_66873e4c-bee7-4bad-ae47-741c57e7bb9b.wav", "formula": "$\\rm CuO+\\rm H_2\\rm SO_4=\\!=\\rm CuSO_4+\\rm H_2\\rm O$", "answer": "One molecule of copper(II) oxide plus one molecule of sulfuric acid produces one molecule of copper(II) sulfate plus one molecule of water.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 565, "question": "Please read the following chemistry formula symbols: $Cu+2AgNO_3=Cu(NO_3)_{2}+2Ag$", "audio_path": "audio/chemistry_7e5680e3-02b1-4a39-9c09-0db8ba46abb7.wav", "formula": "$Cu+2AgNO_3=Cu(NO_3)_{2}+2Ag$", "answer": "Copper plus two molecules of silver chloride produce copper(II) chloride plus two molecules of silver.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 566, "question": "Please read the following chemistry formula symbols: $△H=−241.8kJ/mol^{-1}$", "audio_path": "audio/chemistry_39c05f99-193a-499a-864b-2a6022e41f36.wav", "formula": "$△H=−241.8kJ/mol^{-1}$", "answer": "delta H equals negative two hundred forty-one point eight kilojoules times mole", "subset": "ChemEquation", "task_type": "tts"} +{"index": 567, "question": "Please read the following chemistry formula symbols: $$Fe+CuSO_{4}═Cu+Fe SO_{4}$$", "audio_path": "audio/chemistry_91f17747-49ca-4c59-8ab3-314066d1c331.wav", "formula": "$$Fe+CuSO_{4}═Cu+Fe SO_{4}$$", "answer": "One molecule of iron plus one molecule of copper(II) sulfate produces one molecule of copper plus one molecule of iron(II) sulfate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 568, "question": "Please read the following chemistry formula symbols: $CH_{4}+H_{2}O$ $ CH_{4}+H_{2}O$", "audio_path": "audio/chemistry_a3a8f803-b41b-42eb-aafa-c753dfbac54f.wav", "formula": "$CH_{4}+H_{2}O$ $ CH_{4}+H_{2}O$", "answer": "methane plus water methane plus water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 569, "question": "Please read the following chemistry formula symbols: $$\\left(SO_{2}\\right)$$", "audio_path": "audio/chemistry_118c904e-9437-4ffc-9243-058a7b19c6ab.wav", "formula": "$$\\left(SO_{2}\\right)$$", "answer": "sulfur dioxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 570, "question": "Please read the following chemistry formula symbols: $\\left(Na_{2}CO_{3}\\right)$", "audio_path": "audio/chemistry_5d55678e-e730-43d0-b7aa-2218009a1474.wav", "formula": "$\\left(Na_{2}CO_{3}\\right)$", "answer": "sodium carbonate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 571, "question": "Please read the following chemistry formula symbols: ${R}+2{{{N}}_2}{{{O}}_4}=3{{{N}}_2}↑+4{{{H}}_2}{O}+{2C}{{{O}}_2}↑$", "audio_path": "audio/chemistry_308b67b7-eeb0-468b-9cb2-9fab0ba813af.wav", "formula": "${R}+2{{{N}}_2}{{{O}}_4}=3{{{N}}_2}↑+4{{{H}}_2}{O}+{2C}{{{O}}_2}↑$", "answer": "R plus two molecules of dinitrogen tetroxide produce three molecules of nitrogen plus four molecules of water plus two molecules of carbon dioxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 572, "question": "Please read the following chemistry formula symbols: $Ba^{2+}+2OH^{−}+2H^{+}+SO^{2−}_{4}═BaSO_{4}\\downarrow+2H_{2}O$", "audio_path": "audio/chemistry_8f8500f9-95c7-4264-ace6-8ccdd2217efc.wav", "formula": "$Ba^{2+}+2OH^{−}+2H^{+}+SO^{2−}_{4}═BaSO_{4}\\downarrow+2H_{2}O$", "answer": "Barium two plus ion plus hydroxide ion plus hydrogen ion plus sulfate two minus ion produces solid barium sulfate plus water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 573, "question": "Please read the following chemistry formula symbols: $\\left(Na_{2}SiO_{3}\\right)$", "audio_path": "audio/chemistry_e55218b8-6ec7-462b-8610-b0610cfd0dd7.wav", "formula": "$\\left(Na_{2}SiO_{3}\\right)$", "answer": "sodium silicate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 574, "question": "Please read the following chemistry formula symbols: $$\\left[C_{7}H_{10}O_{5}\\right]$$", "audio_path": "audio/chemistry_dd066499-c0d7-4330-9cb0-fe7aecd6bbda.wav", "formula": "$$\\left[C_{7}H_{10}O_{5}\\right]$$", "answer": "One molecule of carbon seven H ten O five", "subset": "ChemEquation", "task_type": "tts"} +{"index": 575, "question": "Please read the following chemistry formula symbols: $N_{2}\\left(g\\right)+3H_{2} \\left(g\\right)⇌2NH_{3}\\left(g\\right)$", "audio_path": "audio/chemistry_0b72c6a6-ec4a-4611-b8ab-06af862ba848.wav", "formula": "$N_{2}\\left(g\\right)+3H_{2} \\left(g\\right)⇌2NH_{3}\\left(g\\right)$", "answer": "One molecule of nitrogen gas plus three molecules of hydrogen gas reversibly produce two molecules of ammonia gas", "subset": "ChemEquation", "task_type": "tts"} +{"index": 576, "question": "Please read the following chemistry formula symbols: $200\\,\\mathrm{mL}\\ 4\\,\\mathrm{mol/L}\\ \\mathrm{NaOH}$", "audio_path": "audio/chemistry_914af8f0-a9b6-4b3b-961e-cd0bbcaf1503.wav", "formula": "$200\\,\\mathrm{mL}\\ 4\\,\\mathrm{mol/L}\\ \\mathrm{NaOH}$", "answer": "two hundred milliliters of four moles per liter sodium hydroxide solution", "subset": "ChemEquation", "task_type": "tts"} +{"index": 577, "question": "Please read the following chemistry formula symbols: $NaCl \\left(Na_{2}CO_{3}\\right)$", "audio_path": "audio/chemistry_ca80486f-bea2-443c-8d12-8be749d7c49c.wav", "formula": "$NaCl \\left(Na_{2}CO_{3}\\right)$", "answer": "sodium chloride sodium carbonate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 578, "question": "Please read the following chemistry formula symbols: $$\\left[M_{r}\\left(A\\right)>M_{r}\\left(B\\right)\\right]$$", "audio_path": "audio/chemistry_59179b9e-9ee8-450b-9a46-3cc1dc5ec702.wav", "formula": "$$\\left[M_{r}\\left(A\\right)>M_{r}\\left(B\\right)\\right]$$", "answer": "The relative molar mass of A is greater than the relative molar mass of B.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 579, "question": "Please read the following chemistry formula symbols: $c\\left(A^{−}\\right)$", "audio_path": "audio/chemistry_d659d90b-ad94-45a7-bf46-c94535bae8ec.wav", "formula": "$c\\left(A^{−}\\right)$", "answer": "c of A minus ion", "subset": "ChemEquation", "task_type": "tts"} +{"index": 580, "question": "Please read the following chemistry formula symbols: $Fe\\left(NO_{3}\\right)_{3}$", "audio_path": "audio/chemistry_a8eb97f5-afb7-4947-b30f-abe13c95e96d.wav", "formula": "$Fe\\left(NO_{3}\\right)_{3}$", "answer": "iron three nitrate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 581, "question": "Please read the following chemistry formula symbols: $$\\ce{5HClO_{2} = 4ClO_{2}\\uparrow + H^{+} + Cl^{-} + 2H_{2}O}$$", "audio_path": "audio/chemistry_20738074-2eb8-4f2a-b3d2-963c96ed4572.wav", "formula": "$$\\ce{5HClO_{2} = 4ClO_{2}\\uparrow + H^{+} + Cl^{-} + 2H_{2}O}$$", "answer": "Five molecules of chlorous acid produce four molecules of chlorine dioxide gas plus one hydrogen ion plus one chloride ion plus two molecules of water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 582, "question": "Please read the following chemistry formula symbols: $2H_{2}O_{2}\\xlongequal[]{MnO_2}2H_{2}O+O_{2}\\uparrow$", "audio_path": "audio/chemistry_89dfcd30-ff97-498a-aaaa-9c6e7f78d622.wav", "formula": "$2H_{2}O_{2}\\xlongequal[]{MnO_2}2H_{2}O+O_{2}\\uparrow$", "answer": "Two molecules of hydrogen peroxide produce two molecules of water plus one molecule of oxygen gas.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 583, "question": "Please read the following chemistry formula symbols: $$\\frac{4g}{40g/mol}$$", "audio_path": "audio/chemistry_cb49456e-9932-4c96-b097-cec639ca0933.wav", "formula": "$$\\frac{4g}{40g/mol}$$", "answer": "four grams divided by forty grams per mole", "subset": "ChemEquation", "task_type": "tts"} +{"index": 584, "question": "Please read the following chemistry formula symbols: $$C_{3}O_{3}N_{3}Cl_{3}$$", "audio_path": "audio/chemistry_929b382d-aa14-4f1a-a5d8-67e8c070d925.wav", "formula": "$$C_{3}O_{3}N_{3}Cl_{3}$$", "answer": "tricarbon trioxygen trinitrogen trichlorine", "subset": "ChemEquation", "task_type": "tts"} +{"index": 585, "question": "Please read the following chemistry formula symbols: $2NF_{3}\\left(\\mathrm{g}\\right)$", "audio_path": "audio/chemistry_1677d8f8-814c-48a6-b8d9-b342f0e16a12.wav", "formula": "$2NF_{3}\\left(\\mathrm{g}\\right)$", "answer": "Two molecules of nitrogen trifluoride gas", "subset": "ChemEquation", "task_type": "tts"} +{"index": 586, "question": "Please read the following chemistry formula symbols: $\\frac{702.1kJ}{726.5kJ}$", "audio_path": "audio/chemistry_72483f47-0f12-4b9b-95d5-8dee1e5000cb.wav", "formula": "$\\frac{702.1kJ}{726.5kJ}$", "answer": "Seven hundred two point one kilojoules divided by seven hundred twenty-six point five kilojoules", "subset": "ChemEquation", "task_type": "tts"} +{"index": 587, "question": "Please read the following chemistry formula symbols: $2NaCl+2CO_{2}+N_{2},$", "audio_path": "audio/chemistry_0adc2c2c-d1ac-4ccc-adae-0ce9262fa96b.wav", "formula": "$2NaCl+2CO_{2}+N_{2},$", "answer": "Two molecules of sodium chloride plus two molecules of carbon dioxide plus one molecule of nitrogen", "subset": "ChemEquation", "task_type": "tts"} +{"index": 588, "question": "Please read the following chemistry formula symbols: $NaCl AgNO_{3} HNO_{3}$", "audio_path": "audio/chemistry_283ff488-1c94-4f47-a3bd-b0754df5c09e.wav", "formula": "$NaCl AgNO_{3} HNO_{3}$", "answer": "sodium chloride, silver nitrate, nitric acid", "subset": "ChemEquation", "task_type": "tts"} +{"index": 589, "question": "Please read the following chemistry formula symbols: $$\\ce{CO_{2} + 2NaOH = Na_{2}CO_{3} + H_{2}O}$$", "audio_path": "audio/chemistry_f9d10617-76bd-4bb8-9986-d7567459dcd3.wav", "formula": "$$\\ce{CO_{2} + 2NaOH = Na_{2}CO_{3} + H_{2}O}$$", "answer": "Carbon monoxide plus sodium hydroxide produces sodium carbonate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 590, "question": "Please read the following chemistry formula symbols: $$\\left(N_{2}H_{4}\\right)$$", "audio_path": "audio/chemistry_f65fef48-9b02-413b-91c2-3f7067176475.wav", "formula": "$$\\left(N_{2}H_{4}\\right)$$", "answer": "hydrazine", "subset": "ChemEquation", "task_type": "tts"} +{"index": 591, "question": "Please read the following chemistry formula symbols: $$C_{15}H_{22}O_{5}$$", "audio_path": "audio/chemistry_9bbed6d0-e3f6-4ea6-96dc-3f2364479bfd.wav", "formula": "$$C_{15}H_{22}O_{5}$$", "answer": "One molecule containing fifteen carbon atoms, twenty-two hydrogen atoms, and five oxygen atoms.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 592, "question": "Please read the following chemistry formula symbols: $$c\\left(H^{+}\\right)$$", "audio_path": "audio/chemistry_198ffff7-79a1-4e96-a4a6-f7c48f7dfad1.wav", "formula": "$$c\\left(H^{+}\\right)$$", "answer": "concentration of hydrogen ions", "subset": "ChemEquation", "task_type": "tts"} +{"index": 593, "question": "Please read the following chemistry formula symbols: $SO_{2}:Ca^{2+}+3ClO^{−}+H_{2}O+SO_{2}=CaSO_{3}\\downarrow+{Cl}^-+2HClO$", "audio_path": "audio/chemistry_b2558da0-4bd7-4bc2-8d32-d128b55cadad.wav", "formula": "$SO_{2}:Ca^{2+}+3ClO^{−}+H_{2}O+SO_{2}=CaSO_{3}\\downarrow+{Cl}^-+2HClO$", "answer": "Calcium ion plus two hypochlorite ions plus water plus sulfur dioxide produce solid calcium sulfite plus two molecules of hypochlorous acid", "subset": "ChemEquation", "task_type": "tts"} +{"index": 594, "question": "Please read the following chemistry formula symbols: $${3N}{{{O}}_2}+{{{H}}_2} {O=2HN}{{{O}}_3}{+NO}$$", "audio_path": "audio/chemistry_046ccb80-cab5-4d11-9771-aa7abc5f21b7.wav", "formula": "$${3N}{{{O}}_2}+{{{H}}_2} {O=2HN}{{{O}}_3}{+NO}$$", "answer": "Three molecules of nitrogen dioxide plus one molecule of water produce two molecules of nitric acid and one molecule of nitrogen monoxide.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 595, "question": "Please read the following chemistry formula symbols: $\\frac{c\\left(NH^{+}_{4}\\right)}{c\\left(NH_{3}⋅H_{2}O\\right)}$", "audio_path": "audio/chemistry_23919bca-68c7-423f-be39-19fff5005a5e.wav", "formula": "$\\frac{c\\left(NH^{+}_{4}\\right)}{c\\left(NH_{3}⋅H_{2}O\\right)}$", "answer": "The ratio of the concentration of ammonium one plus ion to the concentration of ammonia monohydrate.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 596, "question": "Please read the following chemistry formula symbols: $Na_{2}SO_{4}$ $FeCl_{3}$", "audio_path": "audio/chemistry_22deaa3f-2199-495e-9e27-e96102b1c286.wav", "formula": "$Na_{2}SO_{4}$ $FeCl_{3}$", "answer": "sodium sulfate and iron(III) chloride", "subset": "ChemEquation", "task_type": "tts"} +{"index": 597, "question": "Please read the following chemistry formula symbols: $MgO+2H^{+}═Mg^{2+}+H_{2}O$", "audio_path": "audio/chemistry_3df681f0-3f6b-4652-a553-842b3c29507c.wav", "formula": "$MgO+2H^{+}═Mg^{2+}+H_{2}O$", "answer": "Magnesium oxide plus two hydrogen ions produce magnesium two plus ion plus water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 598, "question": "Please read the following chemistry formula symbols: $$[{CO}{{({N}{{{H}}_{2}})}_{2}}]$$", "audio_path": "audio/chemistry_fefb6edf-1aa6-4e7a-a028-c07871b39a6c.wav", "formula": "$$[{CO}{{({N}{{{H}}_{2}})}_{2}}]$$", "answer": "urea", "subset": "ChemEquation", "task_type": "tts"} +{"index": 599, "question": "Please read the following chemistry formula symbols: $H_{2}SO_{4} \\cdot SO_{3}$", "audio_path": "audio/chemistry_591fe4c7-312f-4eff-93ed-342384bb7ca8.wav", "formula": "$H_{2}SO_{4} \\cdot SO_{3}$", "answer": "One molecule of sulfuric acid combined with one molecule of sulfur trioxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 600, "question": "Please read the following chemistry formula symbols: $H_{3}AsO_{4} > KBrO_{3}$", "audio_path": "audio/chemistry_c12ba574-47f3-4e69-89c8-53d2c7697fdc.wav", "formula": "$H_{3}AsO_{4} > KBrO_{3}$", "answer": "One molecule of arsenic acid produces one molecule of potassium bromate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 601, "question": "Please read the following chemistry formula symbols: $\\left(2FeCl_{3}+Cu=2FeCl_{2}+CuCl_{2}\\right)$", "audio_path": "audio/chemistry_228d6cf5-a3bb-48f4-9867-2752f90d5386.wav", "formula": "$\\left(2FeCl_{3}+Cu=2FeCl_{2}+CuCl_{2}\\right)$", "answer": "Two molecules of iron(III) chloride plus copper produce two molecules of iron(II) chloride plus copper(II) chloride", "subset": "ChemEquation", "task_type": "tts"} +{"index": 602, "question": "Please read the following chemistry formula symbols: $2CuS+3O_{2}═2CuO+2SO_{2}$", "audio_path": "audio/chemistry_7b7ec9d9-d1e9-41a2-afaa-fbca3ebacc76.wav", "formula": "$2CuS+3O_{2}═2CuO+2SO_{2}$", "answer": "Two molecules of copper sulfide plus three molecules of oxygen produce two molecules of copper oxide plus two molecules of sulfur dioxide.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 603, "question": "Please read the following chemistry formula symbols: $100~{g}\\times 5\\%=5~{g}$", "audio_path": "audio/chemistry_8c7a509b-f11c-4635-b6f4-f1ff7104997e.wav", "formula": "$100~{g}\\times 5\\%=5~{g}$", "answer": "One hundred grams multiplied by five percent equals five grams", "subset": "ChemEquation", "task_type": "tts"} +{"index": 604, "question": "Please read the following chemistry formula symbols: $2NH^{+}_{4}+2e^{-}=2NH_{3}+H_{2}$", "audio_path": "audio/chemistry_938de88d-8bc8-4776-841f-d3a500bac712.wav", "formula": "$2NH^{+}_{4}+2e^{-}=2NH_{3}+H_{2}$", "answer": "Two ammonium one plus ions plus two electrons produce two molecules of ammonia plus one molecule of hydrogen.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 605, "question": "Please read the following chemistry formula symbols: $$\\left(C_{15}H_{10}O_{2}\\right)$$", "audio_path": "audio/chemistry_4c7978ba-f630-4491-b564-775bb01cbddf.wav", "formula": "$$\\left(C_{15}H_{10}O_{2}\\right)$$", "answer": "open parenthesis C fifteen H ten O two close parenthesis", "subset": "ChemEquation", "task_type": "tts"} +{"index": 606, "question": "Please read the following chemistry formula symbols: $c\\left(H^{+}\\right)+c\\left(H_{2}Y\\right)=c\\left(OH^{−}\\right)+c\\left(Y^{2−}\\right)$", "audio_path": "audio/chemistry_6d9cc5a0-20af-408e-a62c-e7dfc7071c00.wav", "formula": "$c\\left(H^{+}\\right)+c\\left(H_{2}Y\\right)=c\\left(OH^{−}\\right)+c\\left(Y^{2−}\\right)$", "answer": "The concentration of hydrogen ion plus the concentration of H two Y produces the concentration of hydroxide ion plus the concentration of Y two minus ion", "subset": "ChemEquation", "task_type": "tts"} +{"index": 607, "question": "Please read the following chemistry formula symbols: $50~{g}\\times 25\\%=(50~{g}+x)\\times 5\\%$", "audio_path": "audio/chemistry_844d8cc0-23fd-4cab-9c9e-255e1f91f831.wav", "formula": "$50~{g}\\times 25\\%=(50~{g}+x)\\times 5\\%$", "answer": "Fifty grams multiplied by twenty-five percent equals the quantity fifty grams plus x multiplied by five percent.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 608, "question": "Please read the following chemistry formula symbols: $\\frac{V}{V_{m}} N_{A}$", "audio_path": "audio/chemistry_e0ca1603-e242-42c4-80fe-2595e236389a.wav", "formula": "$\\frac{V}{V_{m}} N_{A}$", "answer": "Volume divided by molar volume multiplied by Avogadro's constant", "subset": "ChemEquation", "task_type": "tts"} +{"index": 609, "question": "Please read the following chemistry formula symbols: $H_{2}(g)+I_{2}(g)\\rightleftharpoons 2HI(g)$", "audio_path": "audio/chemistry_b300184d-058a-41c5-9dd0-a793b6a8115e.wav", "formula": "$H_{2}(g)+I_{2}(g)\\rightleftharpoons 2HI(g)$", "answer": "One molecule of hydrogen gas plus one molecule of iodine gas reversibly produce two molecules of hydrogen iodide.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 610, "question": "Please read the following chemistry formula symbols: $\\rm Ca(OH)_2+CO_2=CaCO_3+H_2O$", "audio_path": "audio/chemistry_fae067f8-dabf-41fa-a318-31625d46a995.wav", "formula": "$\\rm Ca(OH)_2+CO_2=CaCO_3+H_2O$", "answer": "One molecule of calcium hydroxide plus one molecule of carbon dioxide produces one molecule of calcium carbonate plus one molecule of water.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 611, "question": "Please read the following chemistry formula symbols: $Mg(NO_3)_2 = Mg^{2+} + ()$", "audio_path": "audio/chemistry_8e4ef6e3-8700-4532-8584-21ac840050f1.wav", "formula": "$Mg(NO_3)_2 = Mg^{2+} + ()$", "answer": "Two nitrate ions produce magnesium two plus ion plus empty parentheses", "subset": "ChemEquation", "task_type": "tts"} +{"index": 612, "question": "Please read the following chemistry formula symbols: $NaCO_{3}+CaCl_{2}=2NaCl+CaCO_{3}\\downarrow$", "audio_path": "audio/chemistry_b84a2476-eab3-426c-b78c-66336541c7c1.wav", "formula": "$NaCO_{3}+CaCl_{2}=2NaCl+CaCO_{3}\\downarrow$", "answer": "One molecule of sodium carbonate plus one molecule of calcium chloride produces two molecules of sodium chloride plus one molecule of calcium carbonate solid", "subset": "ChemEquation", "task_type": "tts"} +{"index": 613, "question": "Please read the following chemistry formula symbols: $△H_{1} C_{2}H_{5}OH$", "audio_path": "audio/chemistry_c1e887ce-9a37-49e0-816b-f28b949da4f5.wav", "formula": "$△H_{1} C_{2}H_{5}OH$", "answer": "delta H one ethanol", "subset": "ChemEquation", "task_type": "tts"} +{"index": 614, "question": "Please read the following chemistry formula symbols: $c(H^{+}) < \\sqrt{K_W}$", "audio_path": "audio/chemistry_c167f840-c61e-4c44-ac79-0ed867ecc276.wav", "formula": "$c(H^{+}) < \\sqrt{K_W}$", "answer": "The concentration of hydrogen ions is less than the square root of K sub W", "subset": "ChemEquation", "task_type": "tts"} +{"index": 615, "question": "Please read the following chemistry formula symbols: $Fe+2H^{+}═Fe^{2+}+H_{2}\\uparrow$", "audio_path": "audio/chemistry_a13d27fa-932e-41bf-a069-596d270e6058.wav", "formula": "$Fe+2H^{+}═Fe^{2+}+H_{2}\\uparrow$", "answer": "Two atoms of iron plus six hydrogen ions produce two iron three plus ions plus three molecules of hydrogen gas", "subset": "ChemEquation", "task_type": "tts"} +{"index": 616, "question": "Please read the following chemistry formula symbols: $$4Li+2SOCl_{2}=4LiCl+S+SO_{2}$$", "audio_path": "audio/chemistry_eeafd6d8-d127-413d-a172-8d634954057b.wav", "formula": "$$4Li+2SOCl_{2}=4LiCl+S+SO_{2}$$", "answer": "Four atoms of lithium plus two molecules of thionyl chloride produce four molecules of lithium chloride plus one atom of sulfur plus one molecule of sulfur dioxide.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 617, "question": "Please read the following chemistry formula symbols: $\\stackrel{{AgNO}_{3}}{\\rightarrow }\\ \\stackrel{Ca(OH)_2}{\\rightarrow }$", "audio_path": "audio/chemistry_e3089706-6e65-44bc-ae30-15e224bd1bef.wav", "formula": "$\\stackrel{{AgNO}_{3}}{\\rightarrow }\\ \\stackrel{Ca(OH)_2}{\\rightarrow }$", "answer": "The reaction sequence involves silver nitrate followed by calcium hydroxide.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 618, "question": "Please read the following chemistry formula symbols: $HCO^{-}_{3}+Ca^{2+}+OH^{-}\\rightarrow CaCO_{3}\\downarrow+H_{2}O$", "audio_path": "audio/chemistry_3344cb4d-08d5-4a0e-a949-92ae081bda28.wav", "formula": "$HCO^{-}_{3}+Ca^{2+}+OH^{-}\\rightarrow CaCO_{3}\\downarrow+H_{2}O$", "answer": "Bicarbonate one minus ion plus calcium two plus ion plus hydroxide one minus ion produce calcium carbonate solid plus water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 619, "question": "Please read the following chemistry formula symbols: $2H_{2}\\left(g\\right)+O_{2}\\left(g\\right)\\xlongequal{} 2H_{2}O\\left(l\\right) \\Delta H=-571.6\\text{ kJ}$", "audio_path": "audio/chemistry_5e2b0a05-c905-4467-93f4-aa317302e39e.wav", "formula": "$2H_{2}\\left(g\\right)+O_{2}\\left(g\\right)\\xlongequal{} 2H_{2}O\\left(l\\right) \\Delta H=-571.6\\text{ kJ}$", "answer": "Two molecules of hydrogen gas plus one molecule of oxygen gas produce two molecules of liquid water plus 571.6 kilojoules", "subset": "ChemEquation", "task_type": "tts"} +{"index": 620, "question": "Please read the following chemistry formula symbols: $\\left(CH_{3}COOH\\right)$", "audio_path": "audio/chemistry_ceea443f-5443-4288-b765-2d06cbfc9870.wav", "formula": "$\\left(CH_{3}COOH\\right)$", "answer": "acetic acid", "subset": "ChemEquation", "task_type": "tts"} +{"index": 621, "question": "Please read the following chemistry formula symbols: $CH_{3}CH=CH−COOH$", "audio_path": "audio/chemistry_d01d67fd-0fec-430e-828b-aa5086885a54.wav", "formula": "$CH_{3}CH=CH−COOH$", "answer": "pent-2-enoic acid", "subset": "ChemEquation", "task_type": "tts"} +{"index": 622, "question": "Please read the following chemistry formula symbols: $Ca(OH)_{2}+2H^{+}═2H_{2}O+Ca^{2+}$", "audio_path": "audio/chemistry_9743c05a-93b9-4e58-8c5d-f12517f1d313.wav", "formula": "$Ca(OH)_{2}+2H^{+}═2H_{2}O+Ca^{2+}$", "answer": "Calcium hydroxide plus two hydrogen ions produce two molecules of water and a calcium two plus ion.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 623, "question": "Please read the following chemistry formula symbols: $mol,M(Fe)=56 g\\cdot mol^{-1}$", "audio_path": "audio/chemistry_72e12a57-4437-4ec5-aeba-b6af983fec96.wav", "formula": "$mol,M(Fe)=56 g\\cdot mol^{-1}$", "answer": "Mole, mass of iron equals fifty-six grams times mole", "subset": "ChemEquation", "task_type": "tts"} +{"index": 624, "question": "Please read the following chemistry formula symbols: $\\left(I_{2}+2Na_{2}S_{2}O_{3}=2NaI+Na_{2}S_{4}O_{6}\\right)$", "audio_path": "audio/chemistry_9a53802a-c4d8-460c-b1ac-409f2e3461f6.wav", "formula": "$\\left(I_{2}+2Na_{2}S_{2}O_{3}=2NaI+Na_{2}S_{4}O_{6}\\right)$", "answer": "One molecule of iodine plus two molecules of sodium thiosulfate produce two molecules of sodium iodide plus one molecule of sodium tetrathionate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 625, "question": "Please read the following chemistry formula symbols: $6HCl+Fe_{2}O_{3}═2FeCl_{3}+3H_{2}O$", "audio_path": "audio/chemistry_878fdf5e-5518-446f-86d8-22f4c1921d76.wav", "formula": "$6HCl+Fe_{2}O_{3}═2FeCl_{3}+3H_{2}O$", "answer": "Six molecules of hydrochloric acid plus one molecule of iron(III) oxide produce two molecules of iron(III) chloride plus three molecules of water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 626, "question": "Please read the following chemistry formula symbols: $\\frac{0.01mol}{0.05L}$", "audio_path": "audio/chemistry_fa39c384-0212-4320-8e9d-7553b6f68c1c.wav", "formula": "$\\frac{0.01mol}{0.05L}$", "answer": "zero point zero one moles divided by zero point zero five liters", "subset": "ChemEquation", "task_type": "tts"} +{"index": 627, "question": "Please read the following chemistry formula symbols: $\\overset{+3}{\\mathop{{Fe}}}\\,{C}{{{l}}_3}$", "audio_path": "audio/chemistry_a22ddc53-5665-47d1-816c-918815fb711d.wav", "formula": "$\\overset{+3}{\\mathop{{Fe}}}\\,{C}{{{l}}_3}$", "answer": "iron(III) chloride", "subset": "ChemEquation", "task_type": "tts"} +{"index": 628, "question": "Please read the following chemistry formula symbols: $CO_{2}+3H_{2}=X+H_{2}O$", "audio_path": "audio/chemistry_9c9a7b73-e2ed-430c-b80c-3fa005a90f29.wav", "formula": "$CO_{2}+3H_{2}=X+H_{2}O$", "answer": "Carbon dioxide plus three molecules of hydrogen produce X plus water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 629, "question": "Please read the following chemistry formula symbols: $$Pb_{3}(OH)_{2}(CO_{3})_{2}$$", "audio_path": "audio/chemistry_0598ec57-95f8-4400-9edc-2f13087efe40.wav", "formula": "$$Pb_{3}(OH)_{2}(CO_{3})_{2}$$", "answer": "one molecule of lead(II) hydroxide carbonate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 630, "question": "Please read the following chemistry formula symbols: $Na_{2}SO_{4}+H_{2}O$", "audio_path": "audio/chemistry_ced2a2d6-7f0c-4a1e-8c2e-94b0429a52d1.wav", "formula": "$Na_{2}SO_{4}+H_{2}O$", "answer": "One molecule of sodium sulfate plus one molecule of water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 631, "question": "Please read the following chemistry formula symbols: $CO^{2−}_{3}+2CH_{3}COOH═CO_{2}\\uparrow+H_{2}O+2CH_{3}COO^{−}$", "audio_path": "audio/chemistry_527852f0-5bd5-41a5-8afa-79b8aa0ee7de.wav", "formula": "$CO^{2−}_{3}+2CH_{3}COOH═CO_{2}\\uparrow+H_{2}O+2CH_{3}COO^{−}$", "answer": "Carbonate two minus ion plus two molecules of acetic acid reversibly produce carbon dioxide gas, water, and two acetate one minus ions", "subset": "ChemEquation", "task_type": "tts"} +{"index": 632, "question": "Please read the following chemistry formula symbols: $$Ca_{2}Mg_{x}Si_{8}O_{22}(OH)_{2}$$", "audio_path": "audio/chemistry_64930bf8-8408-4d0a-af58-30243e4c7f9e.wav", "formula": "$$Ca_{2}Mg_{x}Si_{8}O_{22}(OH)_{2}$$", "answer": "calcium two magnesium x silicon eight oxygen twenty-two hydroxide two", "subset": "ChemEquation", "task_type": "tts"} +{"index": 633, "question": "Please read the following chemistry formula symbols: $0.075mol⋅L^{-1}$", "audio_path": "audio/chemistry_e5a4d690-f4c8-4752-980e-94ec21fceefa.wav", "formula": "$0.075mol⋅L^{-1}$", "answer": "zero point zero seven five moles per liter", "subset": "ChemEquation", "task_type": "tts"} +{"index": 634, "question": "Please read the following chemistry formula symbols: ${{{C}}_6}{{{H}}_{12}}{{{O}}_6}$", "audio_path": "audio/chemistry_2e1d25e7-19b1-490c-b569-55b379409ce7.wav", "formula": "${{{C}}_6}{{{H}}_{12}}{{{O}}_6}$", "answer": "one molecule of glucose", "subset": "ChemEquation", "task_type": "tts"} +{"index": 635, "question": "Please read the following chemistry formula symbols: $C_{17}H_{18}FN_{3}O_{3}$", "audio_path": "audio/chemistry_b8fb1b1c-896d-4815-8fa3-603af287e840.wav", "formula": "$C_{17}H_{18}FN_{3}O_{3}$", "answer": "fluoxetine", "subset": "ChemEquation", "task_type": "tts"} +{"index": 636, "question": "Please read the following chemistry formula symbols: $$H_{2}\\left(g\\right)+Cl_{2}\\left(g\\right)$$", "audio_path": "audio/chemistry_2578770a-4d6a-4998-9e28-46a7dcba4ad3.wav", "formula": "$$H_{2}\\left(g\\right)+Cl_{2}\\left(g\\right)$$", "answer": "One molecule of hydrogen gas plus one molecule of chlorine gas", "subset": "ChemEquation", "task_type": "tts"} +{"index": 637, "question": "Please read the following chemistry formula symbols: $\\left\\{\\begin{matrix}x+y=0.1\\\\ 3x+y=0.1\\times 2\\end{matrix}\\right.$", "audio_path": "audio/chemistry_53d908ec-6aa9-4091-b451-589103c8d376.wav", "formula": "$\\left\\{\\begin{matrix}x+y=0.1\\\\ 3x+y=0.1\\times 2\\end{matrix}\\right.$", "answer": "A system of equations: the first equation is x plus y produces zero point one, and the second equation is three x plus y produces zero point one times two.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 638, "question": "Please read the following chemistry formula symbols: $\\rm 2NaHCO_3 \\xlongequal{△} Na_2CO_3 + CO_2\\uparrow + H_2O$", "audio_path": "audio/chemistry_147a7f65-442b-431f-86a5-aa6befa81290.wav", "formula": "$\\rm 2NaHCO_3 \\xlongequal{△} Na_2CO_3 + CO_2\\uparrow + H_2O$", "answer": "Two molecules of sodium bicarbonate, when heated, produce sodium carbonate, carbon dioxide gas, and water.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 639, "question": "Please read the following chemistry formula symbols: $\\left(t_{2}\\right)$", "audio_path": "audio/chemistry_e8c23f7c-d358-46a9-81dc-5dbe442b5ff5.wav", "formula": "$\\left(t_{2}\\right)$", "answer": "tee two", "subset": "ChemEquation", "task_type": "tts"} +{"index": 640, "question": "Please read the following chemistry formula symbols: $2A (l) + B(l)=2C(l)$", "audio_path": "audio/chemistry_0fdaa1d1-cbe3-4d06-8c35-26db0b65da3b.wav", "formula": "$2A (l) + B(l)=2C(l)$", "answer": "Two molecules of A liquid plus one molecule of B liquid produce two molecules of C liquid.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 641, "question": "Please read the following chemistry formula symbols: $HCl+AgNO_{3}═AgCl\\downarrow+HNO_{3}$", "audio_path": "audio/chemistry_3b08a3c5-0c39-4e11-b9ff-04df427a5705.wav", "formula": "$HCl+AgNO_{3}═AgCl\\downarrow+HNO_{3}$", "answer": "One molecule of hydrochloric acid plus one molecule of silver nitrate produces one molecule of silver chloride solid plus one molecule of nitric acid.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 642, "question": "Please read the following chemistry formula symbols: $Li_{2}NH+H_{2}=LiNH_{2}+LiH$", "audio_path": "audio/chemistry_923ec469-0054-4b56-9ca6-19bc0c333f47.wav", "formula": "$Li_{2}NH+H_{2}=LiNH_{2}+LiH$", "answer": "One molecule of lithium imide plus one molecule of hydrogen produces one molecule of lithium amide plus one molecule of lithium hydride.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 643, "question": "Please read the following chemistry formula symbols: $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{5}$", "audio_path": "audio/chemistry_cde6cf24-6eef-44e0-a892-c99cde749d39.wav", "formula": "$1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{5}$", "answer": "one s two, two s two, two p six, three s two, three p six, three d five", "subset": "ChemEquation", "task_type": "tts"} +{"index": 644, "question": "Please read the following chemistry formula symbols: $\\frac{r(Na)}{r(Mg)}$", "audio_path": "audio/chemistry_ad69c31f-0864-400d-9840-f69404d316f9.wav", "formula": "$\\frac{r(Na)}{r(Mg)}$", "answer": "The ratio of the radius of sodium to the radius of magnesium", "subset": "ChemEquation", "task_type": "tts"} +{"index": 645, "question": "Please read the following chemistry formula symbols: $\\frac{18g}{20g/mol}$", "audio_path": "audio/chemistry_e8f6330c-b3ef-4b29-b19a-338c3b5f5cc3.wav", "formula": "$\\frac{18g}{20g/mol}$", "answer": "eighteen grams divided by twenty grams per mole", "subset": "ChemEquation", "task_type": "tts"} +{"index": 646, "question": "Please read the following chemistry formula symbols: $\\Delta S=+635.5\\,J/(mol\\cdot K)$", "audio_path": "audio/chemistry_f19a05a1-807e-4f9f-902f-bc27eabcb09a.wav", "formula": "$\\Delta S=+635.5\\,J/(mol\\cdot K)$", "answer": "Delta S equals positive six hundred thirty-five point five joules per mole dot kelvin", "subset": "ChemEquation", "task_type": "tts"} +{"index": 647, "question": "Please read the following chemistry formula symbols: $2C_{2}H_{5}SH+9O_{2}=4CO_{2}+2X+6H_{2}O$", "audio_path": "audio/chemistry_ed664b85-bbda-4fc2-9124-2b1b240fe10e.wav", "formula": "$2C_{2}H_{5}SH+9O_{2}=4CO_{2}+2X+6H_{2}O$", "answer": "Two molecules of ethanethiol plus nine molecules of oxygen gas produce four molecules of carbon dioxide plus two molecules of X plus six molecules of water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 648, "question": "Please read the following chemistry formula symbols: $NaCl 、Na_{2}CO_{3} 、Ca(OH)_{2}$", "audio_path": "audio/chemistry_65401321-ed8a-47c8-9549-c548c2b211b9.wav", "formula": "$NaCl 、Na_{2}CO_{3} 、Ca(OH)_{2}$", "answer": "sodium chloride sodium carbonate calcium hydroxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 649, "question": "Please read the following chemistry formula symbols: $\\frac{4}{5}v\\left(NH_{3}\\right)=v\\left(O_{2}\\right)$", "audio_path": "audio/chemistry_e7368b56-733a-4765-aafb-fd7f12a2d226.wav", "formula": "$\\frac{4}{5}v\\left(NH_{3}\\right)=v\\left(O_{2}\\right)$", "answer": "Four-fifths multiplied by nu of ammonia equals nu of oxygen.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 650, "question": "Please read the following chemistry formula symbols: $$CO_{2}+H_{2}O+NaClO$$", "audio_path": "audio/chemistry_57badeab-d0d3-4cf7-ae0f-157ba981353d.wav", "formula": "$$CO_{2}+H_{2}O+NaClO$$", "answer": "One molecule of carbon dioxide plus one molecule of water plus one molecule of sodium hypochlorite", "subset": "ChemEquation", "task_type": "tts"} +{"index": 651, "question": "Please read the following chemistry formula symbols: $$Cu_{2}O+2H^{+}=Cu^{2+}+Cu+H_{2}O$$", "audio_path": "audio/chemistry_941db784-1c41-474f-ab8e-74e2da2741df.wav", "formula": "$$Cu_{2}O+2H^{+}=Cu^{2+}+Cu+H_{2}O$$", "answer": "Copper(I) oxide plus two hydrogen ions produce copper two plus ion, copper, and water.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 652, "question": "Please read the following chemistry formula symbols: $$ H_2CO_3=CO_2\\uparrow +H_2O$$", "audio_path": "audio/chemistry_93ccacfb-e9a4-4601-a1e6-6c786d2d8b8f.wav", "formula": "$$ H_2CO_3=CO_2\\uparrow +H_2O$$", "answer": "One molecule of carbonic acid produces one molecule of carbon dioxide gas plus one molecule of water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 653, "question": "Please read the following chemistry formula symbols: $SO_{2}(g)$", "audio_path": "audio/chemistry_c55aca95-bb3e-41b9-b7d5-83b3ceb7ea36.wav", "formula": "$SO_{2}(g)$", "answer": "one molecule of sulfur dioxide gas", "subset": "ChemEquation", "task_type": "tts"} +{"index": 654, "question": "Please read the following chemistry formula symbols: $$\\overset{+4}{\\mathop{{Mn}{{{O}}_{2}}}}\\to \\overset{+2}{\\mathop{{MnC}{{{l}}_{2}}}}$$", "audio_path": "audio/chemistry_a2ff22b8-98ca-4231-b595-c2d062e80a22.wav", "formula": "$$\\overset{+4}{\\mathop{{Mn}{{{O}}_{2}}}}\\to \\overset{+2}{\\mathop{{MnC}{{{l}}_{2}}}}$$", "answer": "Manganese(IV) oxide produces manganese(II) chloride", "subset": "ChemEquation", "task_type": "tts"} +{"index": 655, "question": "Please read the following chemistry formula symbols: $v\\left(O_{2}\\right)=3mol/\\left(L⋅min\\right)$", "audio_path": "audio/chemistry_2d522dae-5565-452e-b8f9-e2ddc671feed.wav", "formula": "$v\\left(O_{2}\\right)=3mol/\\left(L⋅min\\right)$", "answer": "The rate of oxygen equals three moles per liter per minute.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 656, "question": "Please read the following chemistry formula symbols: $12\\times 2+1\\times 6+16=46$", "audio_path": "audio/chemistry_16d831e3-6163-4d6e-af6a-3fc745d0ee7b.wav", "formula": "$12\\times 2+1\\times 6+16=46$", "answer": "Twelve multiplied by two plus one multiplied by six plus sixteen equals forty-six", "subset": "ChemEquation", "task_type": "tts"} +{"index": 657, "question": "Please read the following chemistry formula symbols: $0.12mol⋅L^{−1}⋅s^{−1}$", "audio_path": "audio/chemistry_54daac22-502f-4810-95fd-6156480a6aaf.wav", "formula": "$0.12mol⋅L^{−1}⋅s^{−1}$", "answer": "zero point one two moles per liter per second", "subset": "ChemEquation", "task_type": "tts"} +{"index": 658, "question": "Please read the following chemistry formula symbols: $$ NaOH$$", "audio_path": "audio/chemistry_bcbb9256-9fd3-4216-9f12-28cd6d24a3f1.wav", "formula": "$$ NaOH$$", "answer": "sodium dihydroxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 659, "question": "Please read the following chemistry formula symbols: $2Q_{2}=Q_{1}<92.4\\,\\text{kJ}$", "audio_path": "audio/chemistry_32df4229-f5de-4920-bc78-7d0ba3494c95.wav", "formula": "$2Q_{2}=Q_{1}<92.4\\,\\text{kJ}$", "answer": "Two molecules of Q two produce Q one plus less than 92.4 kilojoules.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 660, "question": "Please read the following chemistry formula symbols: $CH_{4} (g) +4F_{2} (g) =CF_{4}(g) +4HF(g)$", "audio_path": "audio/chemistry_d93a325d-13b6-4ba4-b02d-b824d3710f95.wav", "formula": "$CH_{4} (g) +4F_{2} (g) =CF_{4}(g) +4HF(g)$", "answer": "Methane gas plus four molecules of fluorine gas produce carbon tetrafluoride gas plus four molecules of hydrogen fluoride gas", "subset": "ChemEquation", "task_type": "tts"} +{"index": 661, "question": "Please read the following chemistry formula symbols: $\\stackrel{△}{\\rightarrow }Na_{2}SO_{4}+SO_{2}\\uparrow+H_{2}O$", "audio_path": "audio/chemistry_6d72f3bd-e9f3-4fca-bb9b-bd79fb41d59f.wav", "formula": "$\\stackrel{△}{\\rightarrow }Na_{2}SO_{4}+SO_{2}\\uparrow+H_{2}O$", "answer": "Under delta conditions, one molecule of sodium sulfate plus one molecule of sulfur dioxide gas plus one molecule of water are produced.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 662, "question": "Please read the following chemistry formula symbols: $\\frac{0.6mol×1}{2}$", "audio_path": "audio/chemistry_184ae0c9-5098-42ff-b8b5-228f2b056139.wav", "formula": "$\\frac{0.6mol×1}{2}$", "answer": "zero point six moles multiplied by one divided by two", "subset": "ChemEquation", "task_type": "tts"} +{"index": 663, "question": "Please read the following chemistry formula symbols: $C_{3}H_{5}N_{3}O_{9}$", "audio_path": "audio/chemistry_06b72f64-a08a-46af-9866-7d5ff1d2b61f.wav", "formula": "$C_{3}H_{5}N_{3}O_{9}$", "answer": "one molecule of nitroglycerin", "subset": "ChemEquation", "task_type": "tts"} +{"index": 664, "question": "Please read the following chemistry formula symbols: $$c\\left(H^{+}\\right)⋅c\\left(OH^{−}\\right)$$", "audio_path": "audio/chemistry_704c2c58-3bbe-49a8-8b5b-41bcbab2bd93.wav", "formula": "$$c\\left(H^{+}\\right)⋅c\\left(OH^{−}\\right)$$", "answer": "The concentration of hydrogen ion times the concentration of hydroxide ion.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 665, "question": "Please read the following chemistry formula symbols: $$\\rm [KAl(SO_4)_2\\cdot 12H_2O]$$", "audio_path": "audio/chemistry_121b111d-5bc2-44ed-83ff-a341158f2df7.wav", "formula": "$$\\rm [KAl(SO_4)_2\\cdot 12H_2O]$$", "answer": "potassium aluminum sulfate dodecahydrate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 666, "question": "Please read the following chemistry formula symbols: $H_{2}S(g) \\rightleftharpoons H_{2}(g) + S(s)$", "audio_path": "audio/chemistry_a1bd8f4a-9c62-497e-ae3e-371f9105ffc0.wav", "formula": "$H_{2}S(g) \\rightleftharpoons H_{2}(g) + S(s)$", "answer": "One molecule of hydrogen sulfide gas reversibly produces one molecule of hydrogen plus solid sulfur.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 667, "question": "Please read the following chemistry formula symbols: $$mA\\left(g\\right)+nB\\left(g\\right)$$", "audio_path": "audio/chemistry_84f24731-6f80-4138-b978-fee33a454f0e.wav", "formula": "$$mA\\left(g\\right)+nB\\left(g\\right)$$", "answer": "m molecules of A gas plus n molecules of B gas", "subset": "ChemEquation", "task_type": "tts"} +{"index": 668, "question": "Please read the following chemistry formula symbols: $1s^{2}2s^{2}2p^{5}$", "audio_path": "audio/chemistry_5fde384a-1cd0-48cb-94c7-cf018f1b41ec.wav", "formula": "$1s^{2}2s^{2}2p^{5}$", "answer": "one s two two s two two p five", "subset": "ChemEquation", "task_type": "tts"} +{"index": 669, "question": "Please read the following chemistry formula symbols: $K_{a2}=6.4\\times10^{-5}$", "audio_path": "audio/chemistry_89ff0aba-a157-4a61-8054-c3e54fceab74.wav", "formula": "$K_{a2}=6.4\\times10^{-5}$", "answer": "K a two equals 6.4 times ten to the negative five", "subset": "ChemEquation", "task_type": "tts"} +{"index": 670, "question": "Please read the following chemistry formula symbols: $2Fe^{3+}+2I^{−}= 2Fe^{2+}+I_{2}$", "audio_path": "audio/chemistry_d2ee299c-34da-400a-aa9c-347bbe06ac60.wav", "formula": "$2Fe^{3+}+2I^{−}= 2Fe^{2+}+I_{2}$", "answer": "Two iron three plus ions plus two iodide ions produce two iron two plus ions plus one molecule of iodine", "subset": "ChemEquation", "task_type": "tts"} +{"index": 671, "question": "Please read the following chemistry formula symbols: $[\\frac{A}{(50+A+B)}]\\times100\\%$", "audio_path": "audio/chemistry_a3ae8cc9-6293-45a8-b65c-b0d6aedfaadf.wav", "formula": "$[\\frac{A}{(50+A+B)}]\\times100\\%$", "answer": "The quantity A divided by the quantity fifty plus A plus B, times one hundred percent", "subset": "ChemEquation", "task_type": "tts"} +{"index": 672, "question": "Please read the following chemistry formula symbols: $Cu+HCl Cu+AgNO_{3}$", "audio_path": "audio/chemistry_d48debf4-a166-49d6-913f-50e8cf7b6734.wav", "formula": "$Cu+HCl Cu+AgNO_{3}$", "answer": "copper plus hydrogen chloride plus copper plus silver nitrate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 673, "question": "Please read the following chemistry formula symbols: $$\\left(TiO_{2}\\right)$$", "audio_path": "audio/chemistry_0f448d29-3675-4d20-bf1a-08a12e718ec0.wav", "formula": "$$\\left(TiO_{2}\\right)$$", "answer": "titanium dioxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 674, "question": "Please read the following chemistry formula symbols: $△H_{3}=−285.8kJ⋅mol^{−1}$", "audio_path": "audio/chemistry_aa3f1754-f265-4ba1-bc04-cb8f2932dbc9.wav", "formula": "$△H_{3}=−285.8kJ⋅mol^{−1}$", "answer": "Delta H three equals negative two hundred eighty-five point eight kilojoules per mole.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 675, "question": "Please read the following chemistry formula symbols: $X_{3}Y_{2}(ZWR_{4})_{3}T_{2}$", "audio_path": "audio/chemistry_d7dcf3ea-16ea-4d9c-8f39-f53bd195bcde.wav", "formula": "$X_{3}Y_{2}(ZWR_{4})_{3}T_{2}$", "answer": "X three Y two open parenthesis Z W R four close parenthesis three T two", "subset": "ChemEquation", "task_type": "tts"} +{"index": 676, "question": "Please read the following chemistry formula symbols: $75mL 1mol/L MgCl_{2}$", "audio_path": "audio/chemistry_91360764-e873-4714-883d-cc5743e2a09c.wav", "formula": "$75mL 1mol/L MgCl_{2}$", "answer": "Seventy-five milliliters of one molar magnesium chloride solution", "subset": "ChemEquation", "task_type": "tts"} +{"index": 677, "question": "Please read the following chemistry formula symbols: $CuO+H_{2}SO_{4}=CuSO_{4}+H_{2}O$", "audio_path": "audio/chemistry_7f287ce4-a99b-4881-b68d-1bcec1d434fc.wav", "formula": "$CuO+H_{2}SO_{4}=CuSO_{4}+H_{2}O$", "answer": "One molecule of copper(II) oxide plus one molecule of sulfuric acid produces one molecule of copper(II) sulfate plus one molecule of water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 678, "question": "Please read the following chemistry formula symbols: $c(NH_4^+) > c({NH}_3 \\cdot {H}_2{O})$", "audio_path": "audio/chemistry_c0dbf536-bae6-49d2-adfe-677adcab85b1.wav", "formula": "$c(NH_4^+) > c({NH}_3 \\cdot {H}_2{O})$", "answer": "The concentration of ammonium ion is greater than the concentration of ammonia monohydrate.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 679, "question": "Please read the following chemistry formula symbols: $C\\left(HCl\\right)$", "audio_path": "audio/chemistry_04492102-a88a-480d-a393-b2b7dedab4e8.wav", "formula": "$C\\left(HCl\\right)$", "answer": "carbon hydrogen chloride", "subset": "ChemEquation", "task_type": "tts"} +{"index": 680, "question": "Please read the following chemistry formula symbols: $BaCl_{2}+Na_{2}CO_{3}═BaCO_{3}\\downarrow+2NaCl$", "audio_path": "audio/chemistry_cf7e0f56-38ae-4bf0-b846-a51fbdc46db8.wav", "formula": "$BaCl_{2}+Na_{2}CO_{3}═BaCO_{3}\\downarrow+2NaCl$", "answer": "One molecule of barium chloride plus one molecule of sodium carbonate produces solid barium carbonate plus one molecule of sodium chloride", "subset": "ChemEquation", "task_type": "tts"} +{"index": 681, "question": "Please read the following chemistry formula symbols: ${C}{{{r}}_2}{{{O}}_3}$", "audio_path": "audio/chemistry_b283836d-5843-4d99-b16e-de580d16e943.wav", "formula": "${C}{{{r}}_2}{{{O}}_3}$", "answer": "chromium(III) oxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 682, "question": "Please read the following chemistry formula symbols: $\\frac{c(H^{+})}{K_w}$", "audio_path": "audio/chemistry_b2fcc587-e538-45ca-91b9-2560ec51d7c1.wav", "formula": "$\\frac{c(H^{+})}{K_w}$", "answer": "The concentration of hydrogen ion plus one divided by K sub w", "subset": "ChemEquation", "task_type": "tts"} +{"index": 683, "question": "Please read the following chemistry formula symbols: $\\left(C_{6}H_{12}O_{6}\\right)$", "audio_path": "audio/chemistry_0f5592ea-5fdc-414c-af3b-13cc9113342f.wav", "formula": "$\\left(C_{6}H_{12}O_{6}\\right)$", "answer": "glucose", "subset": "ChemEquation", "task_type": "tts"} +{"index": 684, "question": "Please read the following chemistry formula symbols: $Fe^{3+}>Cl_{2}>I_{2}$", "audio_path": "audio/chemistry_1b42e92d-db42-4d4c-941a-9e6990373e67.wav", "formula": "$Fe^{3+}>Cl_{2}>I_{2}$", "answer": "Iron three plus ion produces one molecule of chlorine, which produces one molecule of iodine.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 685, "question": "Please read the following chemistry formula symbols: $${0}{.5mol }{{{N}}_{{2}}}$$", "audio_path": "audio/chemistry_e554de3e-117e-4c00-b4bc-84a6f1a9c99f.wav", "formula": "$${0}{.5mol }{{{N}}_{{2}}}$$", "answer": "zero point five moles of nitrogen", "subset": "ChemEquation", "task_type": "tts"} +{"index": 686, "question": "Please read the following chemistry formula symbols: $A\\left(s\\right)+B\\left(g\\right)=C\\left(s\\right)+D\\left(s\\right)$", "audio_path": "audio/chemistry_8353a451-030a-411c-9562-d9295308ce42.wav", "formula": "$A\\left(s\\right)+B\\left(g\\right)=C\\left(s\\right)+D\\left(s\\right)$", "answer": "One molecule of solid A plus one molecule of gaseous B produces one molecule of solid C plus one molecule of solid D.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 687, "question": "Please read the following chemistry formula symbols: $C_{6}H_{12}O_{6}+6O_{2}$", "audio_path": "audio/chemistry_a4bf597b-69b6-492a-b18c-939dfb29c82e.wav", "formula": "$C_{6}H_{12}O_{6}+6O_{2}$", "answer": "glucose plus six molecules of oxygen", "subset": "ChemEquation", "task_type": "tts"} +{"index": 688, "question": "Please read the following chemistry formula symbols: $Al_{2}O_{3}+2OH^{−}═2AlO^{−}_{2}+H_{2}O$", "audio_path": "audio/chemistry_b61f81a5-c5d4-4f4d-a152-fb29c1c50418.wav", "formula": "$Al_{2}O_{3}+2OH^{−}═2AlO^{−}_{2}+H_{2}O$", "answer": "Aluminum oxide plus two hydroxide ions produce two aluminate ions plus water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 689, "question": "Please read the following chemistry formula symbols: $Na_{2}CO_{3}\\cdot 10H_{2}O$", "audio_path": "audio/chemistry_ee256778-27c7-4abd-bc81-5cd4be823f29.wav", "formula": "$Na_{2}CO_{3}\\cdot 10H_{2}O$", "answer": "sodium carbonate decahydrate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 690, "question": "Please read the following chemistry formula symbols: $K_{sp}\\left(FeS\\right)$", "audio_path": "audio/chemistry_091e1a16-17c4-4e63-bd63-415ac3318cfe.wav", "formula": "$K_{sp}\\left(FeS\\right)$", "answer": "K subscript s p of iron(II) sulfide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 691, "question": "Please read the following chemistry formula symbols: $2L 0.3mol/L FeSO_{4}$", "audio_path": "audio/chemistry_66e4650c-0515-4048-b6e1-b64bf123f321.wav", "formula": "$2L 0.3mol/L FeSO_{4}$", "answer": "Two liters of a 0.3 molar solution of iron(II) sulfate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 692, "question": "Please read the following chemistry formula symbols: $c\\left(OH^{-}\\right)=\\sqrt{K_{W}}$", "audio_path": "audio/chemistry_9525061e-5e3a-4dd7-be50-bcbccd263fe3.wav", "formula": "$c\\left(OH^{-}\\right)=\\sqrt{K_{W}}$", "answer": "The concentration of hydroxide ion equals the square root of K subscript w", "subset": "ChemEquation", "task_type": "tts"} +{"index": 693, "question": "Please read the following chemistry formula symbols: $$O_{2}+PtF_{6}═O_{2}[PtF_{6}]$$", "audio_path": "audio/chemistry_a4c52726-8b54-4b49-ac4b-61e9986e3be8.wav", "formula": "$$O_{2}+PtF_{6}═O_{2}[PtF_{6}]$$", "answer": "One molecule of oxygen plus one molecule of platinum hexafluoride produces one molecule of oxygen platinum hexafluoride", "subset": "ChemEquation", "task_type": "tts"} +{"index": 694, "question": "Please read the following chemistry formula symbols: $$\\ce{4C_{3}H_{5}N_{3}O_{9} -> 12CO_{2}\\uparrow + 10H_{2}O\\uparrow + 6N_{2}\\uparrow + O_{2}\\uparrow}$$", "audio_path": "audio/chemistry_5f77b1dc-a85f-4542-a6a7-cae8fc253fe4.wav", "formula": "$$\\ce{4C_{3}H_{5}N_{3}O_{9} -> 12CO_{2}\\uparrow + 10H_{2}O\\uparrow + 6N_{2}\\uparrow + O_{2}\\uparrow}$$", "answer": "Four molecules of nitroglycerin produce twelve molecules of carbon dioxide gas plus ten molecules of water vapor plus six molecules of X gas plus one molecule of oxygen gas.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 695, "question": "Please read the following chemistry formula symbols: $\\left(O_{2}\\right)$", "audio_path": "audio/chemistry_80e66590-c983-4d96-921c-a48cddb3788d.wav", "formula": "$\\left(O_{2}\\right)$", "answer": "one molecule of oxygen", "subset": "ChemEquation", "task_type": "tts"} +{"index": 696, "question": "Please read the following chemistry formula symbols: $1 mol⋅L^{−1}CaCl_{2}$", "audio_path": "audio/chemistry_45a49ce4-3169-4a4a-8536-f6ebddfe29c9.wav", "formula": "$1 mol⋅L^{−1}CaCl_{2}$", "answer": "one mole per liter of calcium chloride", "subset": "ChemEquation", "task_type": "tts"} +{"index": 697, "question": "Please read the following chemistry formula symbols: $H_{2}O_{2} \\rightarrow H_{2}O + O_{2}$", "audio_path": "audio/chemistry_648028f3-c897-4712-b98c-1671ee733c89.wav", "formula": "$H_{2}O_{2} \\rightarrow H_{2}O + O_{2}$", "answer": "One molecule of hydrogen peroxide produces one molecule of water plus one molecule of oxygen", "subset": "ChemEquation", "task_type": "tts"} +{"index": 698, "question": "Please read the following chemistry formula symbols: $=\\frac{1}{2}\\mathrm{BaSO}_{4}(s)+\\mathrm{H}_{2}\\mathrm{O}(l)$", "audio_path": "audio/chemistry_4fce4855-402a-4760-b168-01ae97439a84.wav", "formula": "$=\\frac{1}{2}\\mathrm{BaSO}_{4}(s)+\\mathrm{H}_{2}\\mathrm{O}(l)$", "answer": "Yields one half molecule of solid barium sulfate plus one molecule of water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 699, "question": "Please read the following chemistry formula symbols: $CO_{2}+Ca(OH)_{2}═CaCO_{3}\\downarrow+H_{2}O$", "audio_path": "audio/chemistry_67a3bbf3-c2c0-48b3-b220-60360d2a8816.wav", "formula": "$CO_{2}+Ca(OH)_{2}═CaCO_{3}\\downarrow+H_{2}O$", "answer": "One molecule of carbon dioxide plus one molecule of calcium hydroxide produces one molecule of calcium carbonate solid plus one molecule of water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 700, "question": "Please read the following chemistry formula symbols: $Ca(HCO_{3})_{2}\\xlongequal{\\text{△}}CaCO_{3}\\downarrow+H_{2}O+CO_{2}\\uparrow$", "audio_path": "audio/chemistry_8ac2b850-e3e9-4d8f-9ae7-0047de5383df.wav", "formula": "$Ca(HCO_{3})_{2}\\xlongequal{\\text{△}}CaCO_{3}\\downarrow+H_{2}O+CO_{2}\\uparrow$", "answer": "One molecule of calcium bicarbonate produces calcium carbonate solid plus water plus carbon dioxide gas.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 701, "question": "Please read the following chemistry formula symbols: $K=\\frac{c\\left(CoCl^{2−}_{4}\\right)}{c\\left(Co^{2+}\\right)⋅c^{4}\\left(Cl^{−}\\right)}$", "audio_path": "audio/chemistry_64cd2027-da84-433c-a764-aa0672470174.wav", "formula": "$K=\\frac{c\\left(CoCl^{2−}_{4}\\right)}{c\\left(Co^{2+}\\right)⋅c^{4}\\left(Cl^{−}\\right)}$", "answer": "K equals the concentration of the tetrachlorocobaltate(II) ion divided by the product of the concentration of the cobalt two plus ion multiplied by the chloride ion concentration raised to the fourth power.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 702, "question": "Please read the following chemistry formula symbols: $CO^{2−}_{3}+C_{6}H_{5}OH→C_{6}H_{5}O^{−}+HCO^{−}_{3}$", "audio_path": "audio/chemistry_4de27b95-88d7-43af-9c4a-434c5617ead9.wav", "formula": "$CO^{2−}_{3}+C_{6}H_{5}OH→C_{6}H_{5}O^{−}+HCO^{−}_{3}$", "answer": "Carbonate two minus ion plus phenol produces phenoxide one minus ion plus bicarbonate one minus ion", "subset": "ChemEquation", "task_type": "tts"} +{"index": 703, "question": "Please read the following chemistry formula symbols: $Cu+2HCl=CuCl_{2}+H_{2}\\uparrow$", "audio_path": "audio/chemistry_450399fb-8633-481a-af90-1e8d767d90db.wav", "formula": "$Cu+2HCl=CuCl_{2}+H_{2}\\uparrow$", "answer": "One atom of copper plus two molecules of hydrochloric acid produce one molecule of copper(II) chloride plus one molecule of hydrogen gas.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 704, "question": "Please read the following chemistry formula symbols: $25gCuSO_{4}\\cdot 5H_{2}O$", "audio_path": "audio/chemistry_7c79075e-760d-423d-9628-6f7327dc6814.wav", "formula": "$25gCuSO_{4}\\cdot 5H_{2}O$", "answer": "25 grams of copper(II) sulfate pentahydrate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 705, "question": "Please read the following chemistry formula symbols: $\\frac{0.4mol/L}{2min}$", "audio_path": "audio/chemistry_ba7b6263-c5ad-4c0a-9d5c-1d8045b63a2c.wav", "formula": "$\\frac{0.4mol/L}{2min}$", "answer": "zero point four moles per liter divided by two minutes", "subset": "ChemEquation", "task_type": "tts"} +{"index": 706, "question": "Please read the following chemistry formula symbols: $C_{13}H_{16}ONCl_{2}$", "audio_path": "audio/chemistry_2822b998-55b1-427c-aa46-c19f1b26a893.wav", "formula": "$C_{13}H_{16}ONCl_{2}$", "answer": "carbon thirteen hydrogen sixteen oxygen one nitrogen one chlorine two", "subset": "ChemEquation", "task_type": "tts"} +{"index": 707, "question": "Please read the following chemistry formula symbols: $$Fe\\left(NO_{3}\\right)_{3}$$", "audio_path": "audio/chemistry_25d8f637-9a58-4c17-bd4f-e729da3594e3.wav", "formula": "$$Fe\\left(NO_{3}\\right)_{3}$$", "answer": "iron(III) nitrate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 708, "question": "Please read the following chemistry formula symbols: $2NaOH+H_{2}SO_{4}$", "audio_path": "audio/chemistry_221b5b97-01ec-435b-8b3d-3e25bbce1370.wav", "formula": "$2NaOH+H_{2}SO_{4}$", "answer": "Two molecules of sodium hydroxide plus one molecule of sulfuric acid", "subset": "ChemEquation", "task_type": "tts"} +{"index": 709, "question": "Please read the following chemistry formula symbols: $CH_{3}CH_{2}=CH-COOCH_{3}$", "audio_path": "audio/chemistry_c47334b5-824e-474f-aec7-7bd19aa27ddf.wav", "formula": "$CH_{3}CH_{2}=CH-COOCH_{3}$", "answer": "methyl acrylate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 710, "question": "Please read the following chemistry formula symbols: $c\\left(CO\\right):c\\left(CO_{2}\\right)=3:2$", "audio_path": "audio/chemistry_b06708da-f174-4fff-b332-2d024aed30dd.wav", "formula": "$c\\left(CO\\right):c\\left(CO_{2}\\right)=3:2$", "answer": "The concentration ratio of carbon monoxide to carbon dioxide is three to two.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 711, "question": "Please read the following chemistry formula symbols: $$3X\\left(g\\right)+Y\\left(g\\right)⇌2Z\\left(g\\right)+2Q\\left(s\\right)$$", "audio_path": "audio/chemistry_942429f4-fdad-4d8c-9189-6c7e3656f888.wav", "formula": "$$3X\\left(g\\right)+Y\\left(g\\right)⇌2Z\\left(g\\right)+2Q\\left(s\\right)$$", "answer": "Three molecules of X gas plus one molecule of Y gas reversibly produce two molecules of Z gas plus two molecules of Q solid", "subset": "ChemEquation", "task_type": "tts"} +{"index": 712, "question": "Please read the following chemistry formula symbols: $CH_{3}OH(l)+H_{2}O(l)$", "audio_path": "audio/chemistry_7f1a1b1d-5b0d-4738-8c81-221de5e14acb.wav", "formula": "$CH_{3}OH(l)+H_{2}O(l)$", "answer": "one molecule of methanol liquid plus one molecule of water liquid", "subset": "ChemEquation", "task_type": "tts"} +{"index": 713, "question": "Please read the following chemistry formula symbols: $11.2L CH_{3}CH_{2}OH$", "audio_path": "audio/chemistry_8cb6647e-bb59-4352-810c-27ab5df708c7.wav", "formula": "$11.2L CH_{3}CH_{2}OH$", "answer": "11.2 liters of ethanol", "subset": "ChemEquation", "task_type": "tts"} +{"index": 714, "question": "Please read the following chemistry formula symbols: $\\left(HNO_{3}\\right)$", "audio_path": "audio/chemistry_9dea0d84-28ae-4083-a386-10e945c4ef14.wav", "formula": "$\\left(HNO_{3}\\right)$", "answer": "nitric acid", "subset": "ChemEquation", "task_type": "tts"} +{"index": 715, "question": "Please read the following chemistry formula symbols: $\\left(Na_{2}FeO_{4}\\right)$", "audio_path": "audio/chemistry_2ba4496f-9e23-4b9c-a069-b5910020b559.wav", "formula": "$\\left(Na_{2}FeO_{4}\\right)$", "answer": "sodium ferrate(VI)", "subset": "ChemEquation", "task_type": "tts"} +{"index": 716, "question": "Please read the following chemistry formula symbols: $BrO^{−}_{3}>Cl_{2}>ClO^{−}_{3}>HIO_{3}$", "audio_path": "audio/chemistry_e6d70144-8110-4c21-b45a-ab50594bd6e9.wav", "formula": "$BrO^{−}_{3}>Cl_{2}>ClO^{−}_{3}>HIO_{3}$", "answer": "bromate one minus ion greater than one molecule of chlorine greater than chlorate one minus ion greater than iodic acid", "subset": "ChemEquation", "task_type": "tts"} +{"index": 717, "question": "Please read the following chemistry formula symbols: $1.0 L Ba\\left(OH\\right)_{2}$", "audio_path": "audio/chemistry_f51c3c40-8e97-4e8b-9121-1d558c39c28a.wav", "formula": "$1.0 L Ba\\left(OH\\right)_{2}$", "answer": "one point zero liters of barium hydroxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 718, "question": "Please read the following chemistry formula symbols: ${C}_7{H}_{14}{O}_2$", "audio_path": "audio/chemistry_875d8408-57cc-4764-9d20-aaaa8a5da169.wav", "formula": "${C}_7{H}_{14}{O}_2$", "answer": "one molecule of carbon seven hydrogen fourteen oxygen two", "subset": "ChemEquation", "task_type": "tts"} +{"index": 719, "question": "Please read the following chemistry formula symbols: $2Na_{2}S_{2}O_{3}+I_{2}$", "audio_path": "audio/chemistry_57865f02-d07d-4c58-9787-f334c00993aa.wav", "formula": "$2Na_{2}S_{2}O_{3}+I_{2}$", "answer": "Two molecules of sodium thiosulfate plus one molecule of iodine", "subset": "ChemEquation", "task_type": "tts"} +{"index": 720, "question": "Please read the following chemistry formula symbols: $$Ca\\left(OH\\right)_{2}$$", "audio_path": "audio/chemistry_551df10a-3df7-49d9-9edb-80f92eef380c.wav", "formula": "$$Ca\\left(OH\\right)_{2}$$", "answer": "calcium hydroxide one minus ion", "subset": "ChemEquation", "task_type": "tts"} +{"index": 721, "question": "Please read the following chemistry formula symbols: $△H_{1}=+87.7kJ/mol$", "audio_path": "audio/chemistry_efbe87fe-1aff-4b89-9419-69038d4421f5.wav", "formula": "$△H_{1}=+87.7kJ/mol$", "answer": "delta H subscript one equals positive eighty-seven point seven kilojoules per mole", "subset": "ChemEquation", "task_type": "tts"} +{"index": 722, "question": "Please read the following chemistry formula symbols: $Q_{3}< Q_{2}=Q_{1}=Q$", "audio_path": "audio/chemistry_f1fdf1e8-df96-4c8a-b55f-3f7a073075a3.wav", "formula": "$Q_{3}< Q_{2}=Q_{1}=Q$", "answer": "Q subscript three is less than Q subscript two equals Q subscript one equals Q", "subset": "ChemEquation", "task_type": "tts"} +{"index": 723, "question": "Please read the following chemistry formula symbols: $2Fe(s)+3CO_{2}(g)$", "audio_path": "audio/chemistry_19c45842-308d-4b46-8e80-08a145f608b8.wav", "formula": "$2Fe(s)+3CO_{2}(g)$", "answer": "Yields two atoms of solid iron plus three molecules of gaseous carbon dioxide.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 724, "question": "Please read the following chemistry formula symbols: $NaNO_{3} $", "audio_path": "audio/chemistry_9c0034e1-584d-4101-9321-614a337b53fa.wav", "formula": "$NaNO_{3} $", "answer": "Sodium nitrate plus barium chloride produce barium", "subset": "ChemEquation", "task_type": "tts"} +{"index": 725, "question": "Please read the following chemistry formula symbols: $PbSO_{4}−2e^{−}+2H_{2}O$", "audio_path": "audio/chemistry_2ca0850b-7919-4457-bd24-cbcd12e0c8f2.wav", "formula": "$PbSO_{4}−2e^{−}+2H_{2}O$", "answer": "Lead(II) sulfate minus two electrons plus two molecules of water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 726, "question": "Please read the following chemistry formula symbols: $\\frac{c\\left(CO^{2−}_{3}\\right)}{c\\left(HCO^{−}_{3}\\right)}$", "audio_path": "audio/chemistry_ac45ae98-7d66-4891-844b-80264285881a.wav", "formula": "$\\frac{c\\left(CO^{2−}_{3}\\right)}{c\\left(HCO^{−}_{3}\\right)}$", "answer": "The ratio of the concentration of carbonate two minus ion to the concentration of bicarbonate one minus ion", "subset": "ChemEquation", "task_type": "tts"} +{"index": 727, "question": "Please read the following chemistry formula symbols: $0.125mol⋅L^{-1}⋅s^{-1}$", "audio_path": "audio/chemistry_11fdfa96-77a1-44de-af71-2b3bd299a41f.wav", "formula": "$0.125mol⋅L^{-1}⋅s^{-1}$", "answer": "zero point one two five moles per liter per second", "subset": "ChemEquation", "task_type": "tts"} +{"index": 728, "question": "Please read the following chemistry formula symbols: $K_{sp}\\left(BaSO_{4}\\right)< K_{sp}\\left(BaCO_{3}\\right)$", "audio_path": "audio/chemistry_d5595462-b390-4ba1-b96b-0b465e051daa.wav", "formula": "$K_{sp}\\left(BaSO_{4}\\right)< K_{sp}\\left(BaCO_{3}\\right)$", "answer": "The solubility product constant of barium sulfate is less than the solubility product constant of barium carbonate.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 729, "question": "Please read the following chemistry formula symbols: $3\\times6.02\\times10^{23}$", "audio_path": "audio/chemistry_d1b6023d-eed1-4ca3-9a5e-5d9bfe282e9a.wav", "formula": "$3\\times6.02\\times10^{23}$", "answer": "three times six point zero two times ten to the power of twenty-three", "subset": "ChemEquation", "task_type": "tts"} +{"index": 730, "question": "Please read the following chemistry formula symbols: ${Y}+2{ZN}{{{O}}_3}={Y}{{({N}{{{O}}_3})}_2}+2{Z}$", "audio_path": "audio/chemistry_59f820de-3330-4f65-9a21-38b315663130.wav", "formula": "${Y}+2{ZN}{{{O}}_3}={Y}{{({N}{{{O}}_3})}_2}+2{Z}$", "answer": "Yttrium plus two molecules of zinc O three produce yttrium nitrate plus two molecules of zinc", "subset": "ChemEquation", "task_type": "tts"} +{"index": 731, "question": "Please read the following chemistry formula symbols: ${{\\rm{H}}_2}\\rm{O}$", "audio_path": "audio/chemistry_99d95920-3429-4c26-bc57-bf8c2217e90a.wav", "formula": "${{\\rm{H}}_2}\\rm{O}$", "answer": "water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 732, "question": "Please read the following chemistry formula symbols: $$Fe_{2}O_{3}\\cdot 3H_{2}O$$", "audio_path": "audio/chemistry_4ae42dcf-2113-4848-b2d6-3b706e7be295.wav", "formula": "$$Fe_{2}O_{3}\\cdot 3H_{2}O$$", "answer": "iron(III) oxide trihydrate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 733, "question": "Please read the following chemistry formula symbols: $HXO_{4} > H_{2}YO_{4} > H_{3}ZO_{4}$", "audio_path": "audio/chemistry_6d5b3103-c559-4ed7-98ab-c651e47d88ac.wav", "formula": "$HXO_{4} > H_{2}YO_{4} > H_{3}ZO_{4}$", "answer": "Hydrogen X O four is greater than hydrogen two Y O four is greater than hydrogen three Z O four", "subset": "ChemEquation", "task_type": "tts"} +{"index": 734, "question": "Please read the following chemistry formula symbols: $xMgCO_{3}$、$yMg(OH)_{2}$", "audio_path": "audio/chemistry_9c6bae9a-0939-4361-b868-51a1ed203bc6.wav", "formula": "$xMgCO_{3}$、$yMg(OH)_{2}$", "answer": "x molecules of magnesium carbonate combined with y molecules of magnesium hydroxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 735, "question": "Please read the following chemistry formula symbols: $(C_{7}H_{14}O_{2})$", "audio_path": "audio/chemistry_34bc2bab-3f4c-4557-85ae-27750a7704f2.wav", "formula": "$(C_{7}H_{14}O_{2})$", "answer": "heptanoic acid", "subset": "ChemEquation", "task_type": "tts"} +{"index": 736, "question": "Please read the following chemistry formula symbols: $$ c\\left(S_{2}O^{2−}_{8}\\right)$$ $$mol⋅L^{−1}$$", "audio_path": "audio/chemistry_4fa2ac3b-f34e-46ba-9f32-7dffcaec64f6.wav", "formula": "$$ c\\left(S_{2}O^{2−}_{8}\\right)$$ $$mol⋅L^{−1}$$", "answer": "The concentration of peroxydisulfate two minus ion in moles per liter.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 737, "question": "Please read the following chemistry formula symbols: $$3Fe+2O_{2}═Fe_{3}O_{4}$$", "audio_path": "audio/chemistry_61126433-dc00-4beb-8e96-7b4b7f912f5a.wav", "formula": "$$3Fe+2O_{2}═Fe_{3}O_{4}$$", "answer": "Three atoms of iron plus two molecules of oxygen produce iron two plus comma three plus oxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 738, "question": "Please read the following chemistry formula symbols: $\\left(C_{8}H_{10}N_{4}O_{2}\\right)$", "audio_path": "audio/chemistry_01458a66-4ba5-42ec-a623-be62d4c4472e.wav", "formula": "$\\left(C_{8}H_{10}N_{4}O_{2}\\right)$", "answer": "caffeine", "subset": "ChemEquation", "task_type": "tts"} +{"index": 739, "question": "Please read the following chemistry formula symbols: $NaHCO_{3}+NaOH═Na_{2}CO_{3}+H_{2}O$", "audio_path": "audio/chemistry_9a80945f-ef9c-4f64-8564-1c3e948eb91d.wav", "formula": "$NaHCO_{3}+NaOH═Na_{2}CO_{3}+H_{2}O$", "answer": "One molecule of sodium bicarbonate plus one molecule of sodium hydroxide produces one molecule of sodium carbonate plus one molecule of water.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 740, "question": "Please read the following chemistry formula symbols: $△H=−QkJ ⋅mol^{−1}\\left(Q>0\\right)$", "audio_path": "audio/chemistry_e46cb762-68b5-439a-a860-b22d8eb8ebc4.wav", "formula": "$△H=−QkJ ⋅mol^{−1}\\left(Q>0\\right)$", "answer": "Delta H equals negative Q kilojoules per mole, where Q is greater than zero.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 741, "question": "Please read the following chemistry formula symbols: $5.3152\\times10^{-25}\\,\\mathrm{kg}$", "audio_path": "audio/chemistry_aa8e44cc-fc52-41d7-bd11-dd40f9eac547.wav", "formula": "$5.3152\\times10^{-25}\\,\\mathrm{kg}$", "answer": "five point three one five two times ten to the negative twenty-fifth kilograms", "subset": "ChemEquation", "task_type": "tts"} +{"index": 742, "question": "Please read the following chemistry formula symbols: $CaCO_{3}+2HCl=CaCl_{2}+H_{2}O+CO_{2}\\uparrow$", "audio_path": "audio/chemistry_5cf80a57-f861-4bc1-a023-803e303af9e1.wav", "formula": "$CaCO_{3}+2HCl=CaCl_{2}+H_{2}O+CO_{2}\\uparrow$", "answer": "Calcium carbonate plus two molecules of hydrochloric acid produce calcium chloride, water, and carbon dioxide gas.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 743, "question": "Please read the following chemistry formula symbols: $H_{2}S+Fe^{3+}═Fe^{2+}+S\\downarrow+2H^{+}$", "audio_path": "audio/chemistry_68abf38b-f808-40a0-bde5-24319a8671fa.wav", "formula": "$H_{2}S+Fe^{3+}═Fe^{2+}+S\\downarrow+2H^{+}$", "answer": "One molecule of hydrogen sulfide plus one iron three plus ion produce one iron two plus ion plus one molecule of solid sulfur plus two hydrogen ions.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 744, "question": "Please read the following chemistry formula symbols: $0.1mol ⋅L^{−1} H_{2}SO_{4}$", "audio_path": "audio/chemistry_a0c3be10-c7db-435d-b33d-4617d0beeacc.wav", "formula": "$0.1mol ⋅L^{−1} H_{2}SO_{4}$", "answer": "zero point one mole per liter sulfuric acid", "subset": "ChemEquation", "task_type": "tts"} +{"index": 745, "question": "Please read the following chemistry formula symbols: $KSCN$", "audio_path": "audio/chemistry_5669043b-77b0-4ddc-946b-918db24875b0.wav", "formula": "$KSCN$", "answer": "produces in the presence of potassium thiocyanate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 746, "question": "Please read the following chemistry formula symbols: $H_{2}O_{2}+Cl_{2}=2HCl+O_{2}$", "audio_path": "audio/chemistry_a393ef32-783c-49b9-bacc-0bbf2d3d4f7f.wav", "formula": "$H_{2}O_{2}+Cl_{2}=2HCl+O_{2}$", "answer": "One molecule of hydrogen peroxide plus one molecule of chlorine gas produce two molecules of hydrogen chloride plus one molecule of oxygen gas", "subset": "ChemEquation", "task_type": "tts"} +{"index": 747, "question": "Please read the following chemistry formula symbols: $MgCO_{3}+2H^{+}\\xlongequal{}Mg^{2+}+CO_{2}\\uparrow+H_{2}O$", "audio_path": "audio/chemistry_b2ca5185-e8b5-485e-be53-09315dba0e58.wav", "formula": "$MgCO_{3}+2H^{+}\\xlongequal{}Mg^{2+}+CO_{2}\\uparrow+H_{2}O$", "answer": "Magnesium carbonate plus two hydrogen ions produce magnesium two plus ion, carbon dioxide gas, and water.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 748, "question": "Please read the following chemistry formula symbols: $Fe+2H{^{+}}=H_{2}\\uparrow+Fe{^{2+}}$", "audio_path": "audio/chemistry_2db2b25c-9d9a-49fe-b7c0-d4dbb96def77.wav", "formula": "$Fe+2H{^{+}}=H_{2}\\uparrow+Fe{^{2+}}$", "answer": "Two atoms of iron plus six hydrogen ions produce three molecules of hydrogen gas plus two iron(III) ions.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 749, "question": "Please read the following chemistry formula symbols: $c\\left(Cr^{3+}\\right)$ $mol⋅L^{−1}$", "audio_path": "audio/chemistry_8b96563a-2b1d-4412-bdba-9db569531206.wav", "formula": "$c\\left(Cr^{3+}\\right)$ $mol⋅L^{−1}$", "answer": "concentration of chromium three plus ions divided by moles per liter", "subset": "ChemEquation", "task_type": "tts"} +{"index": 750, "question": "Please read the following chemistry formula symbols: $Na^{+} 1s^{2}2s^{2}2p^{6}$", "audio_path": "audio/chemistry_488181cc-513f-409c-bdde-d9248e8d8164.wav", "formula": "$Na^{+} 1s^{2}2s^{2}2p^{6}$", "answer": "sodium ion one s two two s two two p six", "subset": "ChemEquation", "task_type": "tts"} +{"index": 751, "question": "Please read the following chemistry formula symbols: $NaHCO_{3}>Na_{2}CO_{3}$", "audio_path": "audio/chemistry_42d87a5b-6526-478e-8c17-495319750b6e.wav", "formula": "$NaHCO_{3}>Na_{2}CO_{3}$", "answer": "One molecule of sodium bicarbonate produces one molecule of sodium carbonate.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 752, "question": "Please read the following chemistry formula symbols: $1s^{2}2s^{2}2p^{6}$", "audio_path": "audio/chemistry_ad35d734-0dab-48ad-8aa8-61d41a87032a.wav", "formula": "$1s^{2}2s^{2}2p^{6}$", "answer": "one s two two s two two p six", "subset": "ChemEquation", "task_type": "tts"} +{"index": 753, "question": "Please read the following chemistry formula symbols: $2Mn^{2+}+5O_{2}↑+8H_{2}O$", "audio_path": "audio/chemistry_5eafb9b7-fb4b-4665-b3bb-b325c3fb4355.wav", "formula": "$2Mn^{2+}+5O_{2}↑+8H_{2}O$", "answer": "Two manganese two plus ions plus five molecules of oxygen gas plus eight molecules of water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 754, "question": "Please read the following chemistry formula symbols: $$\\prescript{89}{39}{\\text{Y}}$$", "audio_path": "audio/chemistry_2e360a7f-8d61-455d-b9f8-afae9625a874.wav", "formula": "$$\\prescript{89}{39}{\\text{Y}}$$", "answer": "yttrium hyphen eighty-nine", "subset": "ChemEquation", "task_type": "tts"} +{"index": 755, "question": "Please read the following chemistry formula symbols: $⑶H_{2}(g) + 0.5O_{2}(g) =H_{2}O(l)$", "audio_path": "audio/chemistry_1e855ad4-d813-4b70-ab14-5f40cc825362.wav", "formula": "$⑶H_{2}(g) + 0.5O_{2}(g) =H_{2}O(l)$", "answer": "Three molecules of hydrogen gas plus half a molecule of oxygen gas yield one molecule of water liquid", "subset": "ChemEquation", "task_type": "tts"} +{"index": 756, "question": "Please read the following chemistry formula symbols: $CuCO_{3}+2NaOH=Cu(OH)_{2}\\downarrow+Na_{2}CO_{3}$", "audio_path": "audio/chemistry_3d48c3e1-9e4c-46e9-99eb-95db7f100634.wav", "formula": "$CuCO_{3}+2NaOH=Cu(OH)_{2}\\downarrow+Na_{2}CO_{3}$", "answer": "Copper(II) carbonate plus two molecules of sodium hydroxide produces copper(II) hydroxide solid plus sodium carbonate.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 757, "question": "Please read the following chemistry formula symbols: $\\frac{1000Vd}{2240+VM}$", "audio_path": "audio/chemistry_58b5e6f3-d820-4fab-a5db-bfdbe243ac6b.wav", "formula": "$\\frac{1000Vd}{2240+VM}$", "answer": "One thousand V d divided by two thousand two hundred forty plus V M", "subset": "ChemEquation", "task_type": "tts"} +{"index": 758, "question": "Please read the following chemistry formula symbols: $CaO_{2}⋅8H_{2}O+H_{2}SO_{4}$", "audio_path": "audio/chemistry_147dcf78-414a-42aa-b507-792d0d45cbc3.wav", "formula": "$CaO_{2}⋅8H_{2}O+H_{2}SO_{4}$", "answer": "Calcium peroxide octahydrate plus sulfuric acid", "subset": "ChemEquation", "task_type": "tts"} +{"index": 759, "question": "Please read the following chemistry formula symbols: $3H_{2}O_{2}+2NaCrO_{2}+2NaOH=2Na_{2}CrO_{4}+4H_{2}O$", "audio_path": "audio/chemistry_42f8d1b7-0261-4761-a9d0-f599c9439834.wav", "formula": "$3H_{2}O_{2}+2NaCrO_{2}+2NaOH=2Na_{2}CrO_{4}+4H_{2}O$", "answer": "Three molecules of hydrogen peroxide plus two molecules of sodium chromite plus two molecules of sodium hydroxide produce two molecules of sodium chromate plus four molecules of water.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 760, "question": "Please read the following chemistry formula symbols: $CH_{3}CH_{2}CH_{2}CHO$", "audio_path": "audio/chemistry_06502145-8088-4d1c-aaf8-326341603cb3.wav", "formula": "$CH_{3}CH_{2}CH_{2}CHO$", "answer": "butanal", "subset": "ChemEquation", "task_type": "tts"} +{"index": 761, "question": "Please read the following chemistry formula symbols: $BrO^{−}_{3}>ClO^{−}_{3}>Cl_{2}>HIO_{3}$", "audio_path": "audio/chemistry_0d1c49db-b00c-41c2-9dab-8a25409337fa.wav", "formula": "$BrO^{−}_{3}>ClO^{−}_{3}>Cl_{2}>HIO_{3}$", "answer": "Bromate one minus ion greater than chlorate one minus ion greater than one molecule of chlorine greater than iodic acid", "subset": "ChemEquation", "task_type": "tts"} +{"index": 762, "question": "Please read the following chemistry formula symbols: $C_{3}H_{8}+5O_{2}$", "audio_path": "audio/chemistry_81830de8-c797-4618-90a3-735158ba11ec.wav", "formula": "$C_{3}H_{8}+5O_{2}$", "answer": "One molecule of propane plus five molecules of oxygen produce", "subset": "ChemEquation", "task_type": "tts"} +{"index": 763, "question": "Please read the following chemistry formula symbols: $Ca^{2+}+ClO^{−}+SO_{2}+H_{2}O$", "audio_path": "audio/chemistry_e8844bf8-a161-41a2-955a-756ac01b0799.wav", "formula": "$Ca^{2+}+ClO^{−}+SO_{2}+H_{2}O$", "answer": "One calcium two plus ion plus one hypochlorite one minus ion plus one molecule of sulfur dioxide plus one molecule of water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 764, "question": "Please read the following chemistry formula symbols: $1.8\\mathrm{g}\\div \\frac{12}{40+12+16\\times 3}\\times 100\\mathrm{\\% }=15\\mathrm{g}$", "audio_path": "audio/chemistry_9e5a7e27-2e58-4dd0-b469-746077dab9e6.wav", "formula": "$1.8\\mathrm{g}\\div \\frac{12}{40+12+16\\times 3}\\times 100\\mathrm{\\% }=15\\mathrm{g}$", "answer": "One point eight grams divided by the quantity twelve divided by the sum of forty plus twelve plus sixteen multiplied by three, all multiplied by one hundred percent equals fifteen grams", "subset": "ChemEquation", "task_type": "tts"} +{"index": 765, "question": "Please read the following chemistry formula symbols: $$ A\\left(g\\right)+3B\\left(g\\right)⇌2C\\left(g\\right)$$", "audio_path": "audio/chemistry_f15e856a-4deb-4307-9068-92268c85abdb.wav", "formula": "$$ A\\left(g\\right)+3B\\left(g\\right)⇌2C\\left(g\\right)$$", "answer": "One molecule of A gas plus three molecules of B gas reversibly produce two molecules of C gas.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 766, "question": "Please read the following chemistry formula symbols: $2KOH + MgCl_{2} = Mg(OH)_{2} \\downarrow + 2KCl$", "audio_path": "audio/chemistry_9928d2dd-6440-4377-8b7b-6d12d363a591.wav", "formula": "$2KOH + MgCl_{2} = Mg(OH)_{2} \\downarrow + 2KCl$", "answer": "Two molecules of potassium hydroxide plus one molecule of magnesium chloride produce one molecule of magnesium hydroxide solid plus two molecules of potassium chloride", "subset": "ChemEquation", "task_type": "tts"} +{"index": 767, "question": "Please read the following chemistry formula symbols: $2KMnO_{4}+5H_{2}O_{2}+3H_{2}SO_{4}═K_{2}SO_{4}+2MnSO_{4}+5O_{2}\\uparrow+8H_{2}O$", "audio_path": "audio/chemistry_32fb4856-fa8d-4182-8a8a-14493b85672a.wav", "formula": "$2KMnO_{4}+5H_{2}O_{2}+3H_{2}SO_{4}═K_{2}SO_{4}+2MnSO_{4}+5O_{2}\\uparrow+8H_{2}O$", "answer": "Two molecules of potassium permanganate plus five molecules of hydrogen peroxide plus three molecules of sulfuric acid produce one molecule of potassium sulfate plus two molecules of manganese(II) sulfate plus five molecules of oxygen gas plus eight molecules of water.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 768, "question": "Please read the following chemistry formula symbols: $0.05\\times6.02\\times10^{23}$", "audio_path": "audio/chemistry_3951168f-e751-458b-a431-05e8b25646c9.wav", "formula": "$0.05\\times6.02\\times10^{23}$", "answer": "zero point zero five times six point zero two times ten to the twenty-third power", "subset": "ChemEquation", "task_type": "tts"} +{"index": 769, "question": "Please read the following chemistry formula symbols: $S+O_{2}\\uparrow═SO_{2}$", "audio_path": "audio/chemistry_0f79371b-a717-49c7-8a80-0a71c7b183f7.wav", "formula": "$S+O_{2}\\uparrow═SO_{2}$", "answer": "One molecule of sulfur plus one molecule of oxygen gas produces one molecule of sulfur dioxide.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 770, "question": "Please read the following chemistry formula symbols: $CH_{4}⋅nH_{2}O=CH_{4}+nH_{2}O,$", "audio_path": "audio/chemistry_4dd37d36-7d65-499a-bbc1-4f128a2ca025.wav", "formula": "$CH_{4}⋅nH_{2}O=CH_{4}+nH_{2}O,$", "answer": "One molecule of methane hydrate produces one molecule of methane plus n molecules of water.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 771, "question": "Please read the following chemistry formula symbols: $2.5~{g}\\times 80\\% =2~{g}$", "audio_path": "audio/chemistry_30085ec3-5e32-4a3d-b0f2-425bdb6b0cfa.wav", "formula": "$2.5~{g}\\times 80\\% =2~{g}$", "answer": "Two point five grams multiplied by eighty percent equals two grams", "subset": "ChemEquation", "task_type": "tts"} +{"index": 772, "question": "Please read the following chemistry formula symbols: $$\\left(TiO_{2}\\right)$$", "audio_path": "audio/chemistry_c5e39abd-6bd9-4eaf-b0fd-e155e3734e5b.wav", "formula": "$$\\left(TiO_{2}\\right)$$", "answer": "titanium dioxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 773, "question": "Please read the following chemistry formula symbols: $$Ba(OH)_{2}·8H_{2}O$$", "audio_path": "audio/chemistry_36578bd4-63c9-44e6-a1ec-a1af92ef3957.wav", "formula": "$$Ba(OH)_{2}·8H_{2}O$$", "answer": "barium hydroxide octahydrate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 774, "question": "Please read the following chemistry formula symbols: $c\\left(H^{+}\\right)=c\\left(CH_{3}COO^{−}\\right)$", "audio_path": "audio/chemistry_e892a3e6-9365-4207-9aa3-089713292367.wav", "formula": "$c\\left(H^{+}\\right)=c\\left(CH_{3}COO^{−}\\right)$", "answer": "The concentration of hydrogen ion equals the concentration of acetate one minus ion.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 775, "question": "Please read the following chemistry formula symbols: $$Al_{2}\\left(SO_{4}\\right)_{3}$$", "audio_path": "audio/chemistry_522fa955-af52-47b3-8592-30d4abb1d1a7.wav", "formula": "$$Al_{2}\\left(SO_{4}\\right)_{3}$$", "answer": "aluminum sulfate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 776, "question": "Please read the following chemistry formula symbols: $$CuO+H_{2} \\xlongequal{\\triangle}Cu+H_{2}O$$", "audio_path": "audio/chemistry_e0fcfe17-8bec-42db-a65a-f29a45949fcb.wav", "formula": "$$CuO+H_{2} \\xlongequal{\\triangle}Cu+H_{2}O$$", "answer": "One molecule of copper(II) oxide plus one molecule of hydrogen, when heated, produces one atom of copper plus one molecule of water.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 777, "question": "Please read the following chemistry formula symbols: $2FeO^{2−}_{4}+10H^{+}+6e^{−}=Fe_{2}O_{3}+5H_{2}O$", "audio_path": "audio/chemistry_5f829fdf-99a9-4144-8f54-5593444aa159.wav", "formula": "$2FeO^{2−}_{4}+10H^{+}+6e^{−}=Fe_{2}O_{3}+5H_{2}O$", "answer": "Two ferrate two minus ions plus ten hydrogen ions plus six electrons produce one iron(III) oxide plus five molecules of water.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 778, "question": "Please read the following chemistry formula symbols: $CH_{3}COOH⇌CH_{3}COO^{−}+H^{+}$", "audio_path": "audio/chemistry_8630d0e8-be33-4839-8260-aaf6f4ae2f32.wav", "formula": "$CH_{3}COOH⇌CH_{3}COO^{−}+H^{+}$", "answer": "Acetic acid reversibly produces acetate one minus ion plus hydrogen ion", "subset": "ChemEquation", "task_type": "tts"} +{"index": 779, "question": "Please read the following chemistry formula symbols: $$HCl>H_{2}S>H_{2}O$$", "audio_path": "audio/chemistry_3cfd973d-5cc2-4921-aa39-771ebea9e319.wav", "formula": "$$HCl>H_{2}S>H_{2}O$$", "answer": "Hydrochloric acid greater than hydrogen sulfide greater than water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 780, "question": "Please read the following chemistry formula symbols: $$\\left(CH_{2}O\\right)$$", "audio_path": "audio/chemistry_511dd0bf-0ee2-433b-9b37-9b1c8cc40fba.wav", "formula": "$$\\left(CH_{2}O\\right)$$", "answer": "formaldehyde", "subset": "ChemEquation", "task_type": "tts"} +{"index": 781, "question": "Please read the following chemistry formula symbols: $(16\\times 3):32=3:2$", "audio_path": "audio/chemistry_354cb033-ac7c-4346-a670-0ba07c4dfc6e.wav", "formula": "$(16\\times 3):32=3:2$", "answer": "This is a mathematical ratio expression, not a chemical formula. It represents the simplification of the ratio (16 multiplied by 3) to 32, which reduces to 3:2.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 782, "question": "Please read the following chemistry formula symbols: $\\rm 5~ mL \\rm NaOH$", "audio_path": "audio/chemistry_190053e4-9860-4b85-91f6-0ca3437b4dbf.wav", "formula": "$\\rm 5~ mL \\rm NaOH$", "answer": "five milliliters of sodium hydroxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 783, "question": "Please read the following chemistry formula symbols: $CH_{3}CH_{2}CH_{2}CH_{2}CH_{3}$", "audio_path": "audio/chemistry_8791e6fc-8d1f-4686-87d2-99276e84a359.wav", "formula": "$CH_{3}CH_{2}CH_{2}CH_{2}CH_{3}$", "answer": "pentane", "subset": "ChemEquation", "task_type": "tts"} +{"index": 784, "question": "Please read the following chemistry formula symbols: $$\\left(N_{2}O_{4}\\right)$$", "audio_path": "audio/chemistry_cb7dd105-4325-46ed-be4c-5cd78ece601a.wav", "formula": "$$\\left(N_{2}O_{4}\\right)$$", "answer": "dinitrogen tetroxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 785, "question": "Please read the following chemistry formula symbols: $0.1\\,\\mathrm{mol} \\,\\mathrm{AlO_2^-}$", "audio_path": "audio/chemistry_539a7625-f2ce-4668-8a18-9f05c0384117.wav", "formula": "$0.1\\,\\mathrm{mol} \\,\\mathrm{AlO_2^-}$", "answer": "zero point one mole of aluminate one minus ion", "subset": "ChemEquation", "task_type": "tts"} +{"index": 786, "question": "Please read the following chemistry formula symbols: $\\frac{0.896L}{22.4L/mol}$", "audio_path": "audio/chemistry_c4a6e803-5973-4379-ab20-365e6a22f4d8.wav", "formula": "$\\frac{0.896L}{22.4L/mol}$", "answer": "zero point eight nine six liters divided by twenty-two point four liters per mole", "subset": "ChemEquation", "task_type": "tts"} +{"index": 787, "question": "Please read the following chemistry formula symbols: $HXO_{4}>HYO_{4}>HZO_{4}$", "audio_path": "audio/chemistry_b95a1219-f88b-4414-9892-ff5b698a3443.wav", "formula": "$HXO_{4}>HYO_{4}>HZO_{4}$", "answer": "Hydrogen X O four is greater than hydrogen Y O four is greater than hydrogen Z O four", "subset": "ChemEquation", "task_type": "tts"} +{"index": 788, "question": "Please read the following chemistry formula symbols: $$Fe_{2}O_{3}+3Na_{2}O_{2}=2Na_{2}FeO_{4}+Na_{2}O$$", "audio_path": "audio/chemistry_167fd2e5-e4ee-4a3f-ba0a-a8307989c704.wav", "formula": "$$Fe_{2}O_{3}+3Na_{2}O_{2}=2Na_{2}FeO_{4}+Na_{2}O$$", "answer": "Iron(III) oxide plus three molecules of sodium peroxide produce two molecules of sodium ferrate(VI) plus one molecule of sodium oxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 789, "question": "Please read the following chemistry formula symbols: $2CaO_{2}+2H_{2}O=2Ca\\left(OH\\right)_{2}+O_{2}↑.$", "audio_path": "audio/chemistry_da718352-2a12-4fe7-a72f-78ad5e38d2cd.wav", "formula": "$2CaO_{2}+2H_{2}O=2Ca\\left(OH\\right)_{2}+O_{2}↑.$", "answer": "Two molecules of calcium peroxide plus two molecules of water produce two molecules of calcium hydroxide plus one molecule of oxygen gas.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 790, "question": "Please read the following chemistry formula symbols: ${N}{{{a}}_2}{C}{{{O}}_3}$", "audio_path": "audio/chemistry_fbc7948a-134b-4d2b-932c-f72bea71a3f2.wav", "formula": "${N}{{{a}}_2}{C}{{{O}}_3}$", "answer": "sodium carbonate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 791, "question": "Please read the following chemistry formula symbols: $\\left(BrF_{2}\\right)_{2}SnF_{6}$", "audio_path": "audio/chemistry_d7b842ce-e7c1-4ad1-89b9-bd3566f53f38.wav", "formula": "$\\left(BrF_{2}\\right)_{2}SnF_{6}$", "answer": "bis(bromine difluoride) hexafluorostannate(IV)", "subset": "ChemEquation", "task_type": "tts"} +{"index": 792, "question": "Please read the following chemistry formula symbols: $2Na_{2}O_{2}+2CO_{2}═2Na_{2}CO_{3}+O_{2}$", "audio_path": "audio/chemistry_bbf58f16-8fdd-498d-baf9-1ccc22bb7d5d.wav", "formula": "$2Na_{2}O_{2}+2CO_{2}═2Na_{2}CO_{3}+O_{2}$", "answer": "Two molecules of sodium peroxide plus two molecules of carbon dioxide produce two molecules of sodium carbonate plus one molecule of oxygen.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 793, "question": "Please read the following chemistry formula symbols: $2C(s) + O_{2} (g) = 2CO(g) \\Delta H_{2}$", "audio_path": "audio/chemistry_1a7cd83f-dd88-4021-b098-9485183e2a45.wav", "formula": "$2C(s) + O_{2} (g) = 2CO(g) \\Delta H_{2}$", "answer": "Two atoms of carbon solid plus one molecule of oxygen gas produce two molecules of carbon monoxide gas delta H two", "subset": "ChemEquation", "task_type": "tts"} +{"index": 794, "question": "Please read the following chemistry formula symbols: ${Cl}_2 + {H_2}O \\rightleftharpoons {HCl} + {HClO}$", "audio_path": "audio/chemistry_f85252d9-eba2-48aa-91be-30d3ae9335e3.wav", "formula": "${Cl}_2 + {H_2}O \\rightleftharpoons {HCl} + {HClO}$", "answer": "One molecule of chlorine plus one molecule of water reversibly produces one molecule of hydrogen chloride plus one molecule of hypochlorous acid", "subset": "ChemEquation", "task_type": "tts"} +{"index": 795, "question": "Please read the following chemistry formula symbols: $3Na+Fe^{3+}=3Na^{+}+Fe$", "audio_path": "audio/chemistry_1251b5bc-29e4-4184-93ed-3fa65e4a8896.wav", "formula": "$3Na+Fe^{3+}=3Na^{+}+Fe$", "answer": "Three atoms of sodium plus one iron three plus ion produce three sodium one plus ions plus one atom of iron", "subset": "ChemEquation", "task_type": "tts"} +{"index": 796, "question": "Please read the following chemistry formula symbols: $NH_{4}NO_{3}$ $ B.K_{2}SO_{4} $ $C.\\left(NH_{4}\\right)_{2}HPO_{4}.$", "audio_path": "audio/chemistry_bf1b938e-65d3-415d-9925-e048e740d856.wav", "formula": "$NH_{4}NO_{3}$ $ B.K_{2}SO_{4} $ $C.\\left(NH_{4}\\right)_{2}HPO_{4}.$", "answer": "Ammonium nitrate, B. potassium sulfate, C. ammonium hydrogen phosphate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 797, "question": "Please read the following chemistry formula symbols: $Mg(OH)_{2}>Al(OH)_{3}$", "audio_path": "audio/chemistry_82a1b1f4-52b7-4880-a42f-48dd39efe5cb.wav", "formula": "$Mg(OH)_{2}>Al(OH)_{3}$", "answer": "Magnesium hydroxide greater than aluminum hydroxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 798, "question": "Please read the following chemistry formula symbols: $Sb_{2}O_{3}+2H_{2}O_{2}=X+2H_{2}O$", "audio_path": "audio/chemistry_df8e7877-771e-4a23-bf04-658fdddb83e0.wav", "formula": "$Sb_{2}O_{3}+2H_{2}O_{2}=X+2H_{2}O$", "answer": "One molecule of antimony(III) oxide plus two molecules of hydrogen peroxide produce X plus two molecules of water.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 799, "question": "Please read the following chemistry formula symbols: ${A}{{{l}}_2}{{{O}}_3}$", "audio_path": "audio/chemistry_22f095b3-a343-4e84-a9ef-a94220ee0115.wav", "formula": "${A}{{{l}}_2}{{{O}}_3}$", "answer": "aluminum oxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 800, "question": "Please read the following chemistry formula symbols: ${N}{{{a}}_2}{S}{{{O}}_4} +{BaC}{{{l}}_2}= {BaS}{{{O}}_4}\\downarrow + 2\\rm NaCl$", "audio_path": "audio/chemistry_b9d67887-5972-4490-a2a6-340b94ab2272.wav", "formula": "${N}{{{a}}_2}{S}{{{O}}_4} +{BaC}{{{l}}_2}= {BaS}{{{O}}_4}\\downarrow + 2\\rm NaCl$", "answer": "One molecule of sodium sulfate plus one molecule of barium chloride produces solid barium sulfate plus two molecules of sodium chloride.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 801, "question": "Please read the following chemistry formula symbols: $K_{sp} \\left(BaCO_{3} \\right)>K_{sp} \\left(BaSO_{4} \\right)$", "audio_path": "audio/chemistry_58cb769c-2cfd-4d25-9a5d-44aef5ace090.wav", "formula": "$K_{sp} \\left(BaCO_{3} \\right)>K_{sp} \\left(BaSO_{4} \\right)$", "answer": "The solubility product constant of barium carbonate is greater than the solubility product constant of barium sulfate.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 802, "question": "Please read the following chemistry formula symbols: $K_{2}SO_{4}$ $BaCl_{2}$ $NaNO_{3}$", "audio_path": "audio/chemistry_14cd5202-8849-4028-9a0d-410ae4bafc7c.wav", "formula": "$K_{2}SO_{4}$ $BaCl_{2}$ $NaNO_{3}$", "answer": "One molecule of potassium sulfate, one molecule of barium chloride, one molecule of sodium nitrate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 803, "question": "Please read the following chemistry formula symbols: $$Mg(OH)_{2}(s)\\xlongequal{△}MgO(s)+H_{2}O(g)$$", "audio_path": "audio/chemistry_d6b2a5a2-4486-4bb6-b303-5492ea232e02.wav", "formula": "$$Mg(OH)_{2}(s)\\xlongequal{△}MgO(s)+H_{2}O(g)$$", "answer": "One molecule of solid magnesium hydroxide produces one molecule of solid magnesium oxide plus one molecule of water vapor", "subset": "ChemEquation", "task_type": "tts"} +{"index": 804, "question": "Please read the following chemistry formula symbols: $△H=−99kJ⋅mol^{−1}.$", "audio_path": "audio/chemistry_aa80ec51-e4ed-4814-90c9-35d040741b4c.wav", "formula": "$△H=−99kJ⋅mol^{−1}.$", "answer": "delta H equals negative ninety-nine kilojoules per mole", "subset": "ChemEquation", "task_type": "tts"} +{"index": 805, "question": "Please read the following chemistry formula symbols: $$2FeCl_{3}+Cu=2FeCl_{2}+CuCl_{2}$$", "audio_path": "audio/chemistry_d7c8f0f1-5c1f-4a59-bf79-df1897e9049e.wav", "formula": "$$2FeCl_{3}+Cu=2FeCl_{2}+CuCl_{2}$$", "answer": "Two molecules of iron(III) chloride plus copper produce two molecules of iron(II) chloride plus copper(II) chloride.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 806, "question": "Please read the following chemistry formula symbols: $0.3mol⋅L^{−1}⋅S^{−1}$", "audio_path": "audio/chemistry_ecde3210-9571-4ba7-a97a-fb2666e86f77.wav", "formula": "$0.3mol⋅L^{−1}⋅S^{−1}$", "answer": "zero point three moles per liter per second", "subset": "ChemEquation", "task_type": "tts"} +{"index": 807, "question": "Please read the following chemistry formula symbols: $\\left(×10^{6}J/Kg\\right)$", "audio_path": "audio/chemistry_b907309b-c095-4cb8-b104-7d44cce701cc.wav", "formula": "$\\left(×10^{6}J/Kg\\right)$", "answer": "times ten to the sixth power joules per kilogram", "subset": "ChemEquation", "task_type": "tts"} +{"index": 808, "question": "Please read the following chemistry formula symbols: $△H_{1}=+178.32\\,\\text{kJ}⋅\\text{mol}^{-1}$", "audio_path": "audio/chemistry_eb74e497-bec7-4005-8e50-a5995f665672.wav", "formula": "$△H_{1}=+178.32\\,\\text{kJ}⋅\\text{mol}^{-1}$", "answer": "delta H one produces positive 178.32 kilojoules per mole", "subset": "ChemEquation", "task_type": "tts"} +{"index": 809, "question": "Please read the following chemistry formula symbols: $$CuO+CO \\stackrel{△}{\\rightarrow }Cu+CO_{2}$$", "audio_path": "audio/chemistry_132e6a33-cbcd-4861-b5fe-c76b2e0abf72.wav", "formula": "$$CuO+CO \\stackrel{△}{\\rightarrow }Cu+CO_{2}$$", "answer": "One molecule of copper(II) oxide plus one molecule of carbon monoxide yields one molecule of copper plus one molecule of carbon dioxide with delta.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 810, "question": "Please read the following chemistry formula symbols: $K_{sp}=2.8\\times10^{−9}$", "audio_path": "audio/chemistry_dbe7254a-3717-4366-9c33-d8fb7f5c0fa7.wav", "formula": "$K_{sp}=2.8\\times10^{−9}$", "answer": "K s p equals two point eight times ten to the negative ninth power", "subset": "ChemEquation", "task_type": "tts"} +{"index": 811, "question": "Please read the following chemistry formula symbols: $$2HCl+FeO=FeCl_{2}+H_{2}O$$", "audio_path": "audio/chemistry_0d623592-edf3-4f84-b74d-34ee277d599f.wav", "formula": "$$2HCl+FeO=FeCl_{2}+H_{2}O$$", "answer": "Two molecules of hydrogen chloride plus iron(II) oxide produce iron(II) chloride plus water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 812, "question": "Please read the following chemistry formula symbols: $KCN+CO_{2}+H_{2}O=HCN+KHCO_{3}$", "audio_path": "audio/chemistry_90e1f2fd-5259-40e4-bacf-4c7fb0306c63.wav", "formula": "$KCN+CO_{2}+H_{2}O=HCN+KHCO_{3}$", "answer": "One molecule of potassium cyanide plus one molecule of carbon dioxide plus one molecule of water produces one molecule of hydrogen cyanide plus one molecule of potassium hydrogen carbonate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 813, "question": "Please read the following chemistry formula symbols: $$\\frac{\\frac{0.2mol}{2L}}{2min}$$", "audio_path": "audio/chemistry_ae1f457b-0d44-414c-99dd-8e762c598dfb.wav", "formula": "$$\\frac{\\frac{0.2mol}{2L}}{2min}$$", "answer": "Zero point two moles divided by two liters divided by two minutes.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 814, "question": "Please read the following chemistry formula symbols: $2OH^{−}+Cl_{2}\\uparrow+H_{2}\\uparrow$", "audio_path": "audio/chemistry_4dac652b-70e4-4e65-8bc7-641c3c5021e3.wav", "formula": "$2OH^{−}+Cl_{2}\\uparrow+H_{2}\\uparrow$", "answer": "Two hydroxide one minus ions plus one molecule of chlorine gas plus one molecule of hydrogen gas", "subset": "ChemEquation", "task_type": "tts"} +{"index": 815, "question": "Please read the following chemistry formula symbols: $$Cu\\left(OH\\right)_{2}$$", "audio_path": "audio/chemistry_09b36818-99c8-4639-ae10-d63e93ff2be1.wav", "formula": "$$Cu\\left(OH\\right)_{2}$$", "answer": "copper(II) hydroxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 816, "question": "Please read the following chemistry formula symbols: $\\left[Zn\\left(NH_{3}\\right)_{4}\\right]^{2+}$", "audio_path": "audio/chemistry_4538f621-9b76-400f-9c01-1b9a9c942c6d.wav", "formula": "$\\left[Zn\\left(NH_{3}\\right)_{4}\\right]^{2+}$", "answer": "tetraamminezinc(II)", "subset": "ChemEquation", "task_type": "tts"} +{"index": 817, "question": "Please read the following chemistry formula symbols: $\\frac{a}{\\left( a+2b \\right)}$", "audio_path": "audio/chemistry_8e96cfde-c99e-46f4-abb1-eee89c19986b.wav", "formula": "$\\frac{a}{\\left( a+2b \\right)}$", "answer": "a divided by the quantity a plus two b", "subset": "ChemEquation", "task_type": "tts"} +{"index": 818, "question": "Please read the following chemistry formula symbols: $2{{{s}}^2}2{{{p}}^1}$", "audio_path": "audio/chemistry_94780fac-6f82-4552-9832-adf6b6b46561.wav", "formula": "$2{{{s}}^2}2{{{p}}^1}$", "answer": "two s squared, two p one", "subset": "ChemEquation", "task_type": "tts"} +{"index": 819, "question": "Please read the following chemistry formula symbols: $0.5$ $ mol C_{3}H_{8}$", "audio_path": "audio/chemistry_b9a105bd-bff2-482f-ad70-6d869fdab0e1.wav", "formula": "$0.5$ $ mol C_{3}H_{8}$", "answer": "Half a mole of propane", "subset": "ChemEquation", "task_type": "tts"} +{"index": 820, "question": "Please read the following chemistry formula symbols: $c\\left(NH^{+}_{4}\\right)$", "audio_path": "audio/chemistry_5fb000d4-e5d6-4eac-b47a-608e0044ab08.wav", "formula": "$c\\left(NH^{+}_{4}\\right)$", "answer": "concentration of ammonium ion", "subset": "ChemEquation", "task_type": "tts"} +{"index": 821, "question": "Please read the following chemistry formula symbols: $$\\frac{n}{V}=\\frac{\\frac{m}{M}}{V}$", "audio_path": "audio/chemistry_8487e8df-d8ec-4e28-a179-0962315aceaa.wav", "formula": "$$\\frac{n}{V}=\\frac{\\frac{m}{M}}{V}$", "answer": "Amount of substance divided by volume equals mass divided by molar mass divided by volume.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 822, "question": "Please read the following chemistry formula symbols: $0.1\\mathrm{mol/L}\\ CH_{3}COOH$", "audio_path": "audio/chemistry_a3f86409-e51d-43fd-bb97-ffc93df422ca.wav", "formula": "$0.1\\mathrm{mol/L}\\ CH_{3}COOH$", "answer": "zero point zero moles per liter multiplied by acetic acid", "subset": "ChemEquation", "task_type": "tts"} +{"index": 823, "question": "Please read the following chemistry formula symbols: ${Fe}+{{{H}}_{{2}}}{S}{{{O}}_{{4}}}={FeS}{{{O}}_{{4}}}+{{{H}}_{{2}}}\\uparrow$", "audio_path": "audio/chemistry_5b245d90-7546-4433-9ef4-a46c424a627b.wav", "formula": "${Fe}+{{{H}}_{{2}}}{S}{{{O}}_{{4}}}={FeS}{{{O}}_{{4}}}+{{{H}}_{{2}}}\\uparrow$", "answer": "Iron plus one molecule of sulfuric acid produces one molecule of iron(II) sulfate plus one molecule of hydrogen gas", "subset": "ChemEquation", "task_type": "tts"} +{"index": 824, "question": "Please read the following chemistry formula symbols: $c\\left(CO_{3}^{2−}\\right)< c\\left(HCO_{3}^{-}\\right)$", "audio_path": "audio/chemistry_2477fdd8-855c-4f92-8edc-2b8b075d84f9.wav", "formula": "$c\\left(CO_{3}^{2−}\\right)< c\\left(HCO_{3}^{-}\\right)$", "answer": "The concentration of carbonate two minus ion is less than the concentration of bicarbonate one minus ion.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 825, "question": "Please read the following chemistry formula symbols: $0.1 mol Na_{2}O_{2}$", "audio_path": "audio/chemistry_5c75aed9-b249-4c4f-b0c3-b1691620f5c6.wav", "formula": "$0.1 mol Na_{2}O_{2}$", "answer": "zero point one moles of sodium peroxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 826, "question": "Please read the following chemistry formula symbols: $Cu^{2+}+2NH_{3}⋅H_{2}O=Cu\\left(OH\\right)_{2}\\downarrow+2NH^{+}_{4}$", "audio_path": "audio/chemistry_f33a0f1f-09c5-4fe7-9ab6-6d157f434bb6.wav", "formula": "$Cu^{2+}+2NH_{3}⋅H_{2}O=Cu\\left(OH\\right)_{2}\\downarrow+2NH^{+}_{4}$", "answer": "copper two plus ion plus two molecules of ammonia monohydrate produce solid copper(II) hydroxide plus two ammonium ions", "subset": "ChemEquation", "task_type": "tts"} +{"index": 827, "question": "Please read the following chemistry formula symbols: $2X_{2}+Y_{2}=2X_{2}Y$", "audio_path": "audio/chemistry_fe103915-3ad3-4d5f-a3a4-6472fbbebada.wav", "formula": "$2X_{2}+Y_{2}=2X_{2}Y$", "answer": "Two molecules of X two plus one molecule of Y two produce two molecules of X two Y", "subset": "ChemEquation", "task_type": "tts"} +{"index": 828, "question": "Please read the following chemistry formula symbols: ${{{C}}_{{9}}}{{{H}}_{{8}}}{{{O}}_{{2}}}$", "audio_path": "audio/chemistry_7adbf1eb-3d77-4d75-bbb2-d60c5e13c15e.wav", "formula": "${{{C}}_{{9}}}{{{H}}_{{8}}}{{{O}}_{{2}}}$", "answer": "nine carbon atoms, eight hydrogen atoms, and two oxygen atoms", "subset": "ChemEquation", "task_type": "tts"} +{"index": 829, "question": "Please read the following chemistry formula symbols: $\\dfrac{162.5}{\\mathrm{x}}=\\dfrac{107}{10.7\\mathrm{g}}$", "audio_path": "audio/chemistry_87468dee-1dc7-427c-985b-fbad44e2db48.wav", "formula": "$\\dfrac{162.5}{\\mathrm{x}}=\\dfrac{107}{10.7\\mathrm{g}}$", "answer": "One hundred sixty-two point five divided by x equals one hundred seven divided by ten point seven grams", "subset": "ChemEquation", "task_type": "tts"} +{"index": 830, "question": "Please read the following chemistry formula symbols: $0.2mol/LNa_{2}CO_{3}$", "audio_path": "audio/chemistry_f03bb864-3a6e-4825-a9bc-d2cb95280d89.wav", "formula": "$0.2mol/LNa_{2}CO_{3}$", "answer": "zero point two moles per liter sodium carbonate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 831, "question": "Please read the following chemistry formula symbols: $2mol ⋅L^{-1}AgNO_{3}$", "audio_path": "audio/chemistry_cfad4754-4a76-4691-8ef8-087be25952cd.wav", "formula": "$2mol ⋅L^{-1}AgNO_{3}$", "answer": "two moles per liter silver nitrate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 832, "question": "Please read the following chemistry formula symbols: $H_{2}\\left(g\\right)+S\\left(s\\right)\\xlongequal{\\triangle }H_{2}S\\left(g\\right)$", "audio_path": "audio/chemistry_ed5230c5-795c-43bf-bd7c-f6fe0344ad6d.wav", "formula": "$H_{2}\\left(g\\right)+S\\left(s\\right)\\xlongequal{\\triangle }H_{2}S\\left(g\\right)$", "answer": "Two molecules of hydrogen gas plus one molecule of solid sulfur produce two molecules of hydrogen sulfide gas", "subset": "ChemEquation", "task_type": "tts"} +{"index": 833, "question": "Please read the following chemistry formula symbols: $$\\frac{1.6g}{64g/mol}$$", "audio_path": "audio/chemistry_85c3d07d-8f4c-40c3-90c8-275cb065281a.wav", "formula": "$$\\frac{1.6g}{64g/mol}$$", "answer": "1.6 grams divided by 64 grams per mole", "subset": "ChemEquation", "task_type": "tts"} +{"index": 834, "question": "Please read the following chemistry formula symbols: ${{{N}}_2}{{{O}}_4}$", "audio_path": "audio/chemistry_9658755a-a8a4-4943-9972-7cb3e9dd4ed3.wav", "formula": "${{{N}}_2}{{{O}}_4}$", "answer": "one molecule of dinitrogen tetroxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 835, "question": "Please read the following chemistry formula symbols: $C_{3}N_{3}O_{3}Cl_{3}$", "audio_path": "audio/chemistry_96f02c33-18d8-4e17-806e-ad52d075e255.wav", "formula": "$C_{3}N_{3}O_{3}Cl_{3}$", "answer": "trichloroisocyanuric acid", "subset": "ChemEquation", "task_type": "tts"} +{"index": 836, "question": "Please read the following chemistry formula symbols: $0.50molNa_{2}SO_{4}$", "audio_path": "audio/chemistry_b858cca3-b5e5-4a3a-b233-3f1ca4f2ccac.wav", "formula": "$0.50molNa_{2}SO_{4}$", "answer": "zero point five zero moles of sodium sulfate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 837, "question": "Please read the following chemistry formula symbols: $(C_{6}H_{10}O_{5})_{n}$", "audio_path": "audio/chemistry_0bd2461e-7d2f-4146-9b60-7e7e4d9781f5.wav", "formula": "$(C_{6}H_{10}O_{5})_{n}$", "answer": "cellulose", "subset": "ChemEquation", "task_type": "tts"} +{"index": 838, "question": "Please read the following chemistry formula symbols: $Fe_{2}O_{3}+6H^{+}═2Fe^{3+}+3H_{2}O$", "audio_path": "audio/chemistry_bab379d6-5a26-4941-b573-c4c289c60a1a.wav", "formula": "$Fe_{2}O_{3}+6H^{+}═2Fe^{3+}+3H_{2}O$", "answer": "One molecule of iron(III) oxide plus six hydrogen ions produces two iron three plus ions plus three molecules of water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 839, "question": "Please read the following chemistry formula symbols: $2CO_{2}(g)=2CO(g)+O_{2}(g)$", "audio_path": "audio/chemistry_83e2f910-1c88-466a-892d-0b748d3028c7.wav", "formula": "$2CO_{2}(g)=2CO(g)+O_{2}(g)$", "answer": "Two molecules of carbon dioxide gas produce two molecules of carbon monoxide gas plus one molecule of oxygen gas.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 840, "question": "Please read the following chemistry formula symbols: $1.204\\times10^{23}$", "audio_path": "audio/chemistry_341b00c0-3261-4451-915e-7648de9ab31e.wav", "formula": "$1.204\\times10^{23}$", "answer": "one point two zero four times ten to the power of twenty-three", "subset": "ChemEquation", "task_type": "tts"} +{"index": 841, "question": "Please read the following chemistry formula symbols: $\\left[Vc−\\frac{9a+b}{3}\\right]mol$", "audio_path": "audio/chemistry_c54b0e33-3fb6-40d1-ac7d-52938401feb4.wav", "formula": "$\\left[Vc−\\frac{9a+b}{3}\\right]mol$", "answer": "Left bracket V c minus nine a plus b over three right bracket moles", "subset": "ChemEquation", "task_type": "tts"} +{"index": 842, "question": "Please read the following chemistry formula symbols: $\\stackrel{△}{\\rightarrow }Na_{2}SO_{4}+2HCl\\uparrow$", "audio_path": "audio/chemistry_63580d20-ee5f-4ef3-8f70-b19876900cd2.wav", "formula": "$\\stackrel{△}{\\rightarrow }Na_{2}SO_{4}+2HCl\\uparrow$", "answer": "Delta produces sodium sulfate plus two molecules of hydrogen chloride gas", "subset": "ChemEquation", "task_type": "tts"} +{"index": 843, "question": "Please read the following chemistry formula symbols: $═H_{2}O\\left( l \\right)$", "audio_path": "audio/chemistry_7fbfc70b-9f52-4a90-8db7-4bdf201569cd.wav", "formula": "$═H_{2}O\\left( l \\right)$", "answer": "One molecule of liquid water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 844, "question": "Please read the following chemistry formula symbols: $Ksp(BaCO_{3})< Ksp(BaSO_{4})$", "audio_path": "audio/chemistry_7d93908f-a010-420c-a8bb-3bc9b6788a48.wav", "formula": "$Ksp(BaCO_{3})< Ksp(BaSO_{4})$", "answer": "The solubility product of barium carbonate is less than the solubility product of barium sulfate.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 845, "question": "Please read the following chemistry formula symbols: $CO\\left(g\\right)+2H_{2}\\left(g\\right)$", "audio_path": "audio/chemistry_c0ebf8d7-6236-422c-99ee-855eb85d34e2.wav", "formula": "$CO\\left(g\\right)+2H_{2}\\left(g\\right)$", "answer": "Carbon monoxide gas plus two molecules of hydrogen gas", "subset": "ChemEquation", "task_type": "tts"} +{"index": 846, "question": "Please read the following chemistry formula symbols: $50mL1mol/LFeCl_{3}$", "audio_path": "audio/chemistry_159aaaba-8f4e-4684-a253-cfeae351392a.wav", "formula": "$50mL1mol/LFeCl_{3}$", "answer": "fifty milliliters of one mole per liter iron(III) chloride solution", "subset": "ChemEquation", "task_type": "tts"} +{"index": 847, "question": "Please read the following chemistry formula symbols: $${N}{{{a}}_2}{S}{{{O}}_4}$$", "audio_path": "audio/chemistry_1a5192b5-3bc4-4e41-8744-2b13d4e9b06b.wav", "formula": "$${N}{{{a}}_2}{S}{{{O}}_4}$$", "answer": "sodium sulfate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 848, "question": "Please read the following chemistry formula symbols: $H_{2}\\left(g\\right)+Cl_{2}\\left(g\\right)═2HCl\\left(g\\right)$", "audio_path": "audio/chemistry_e024568d-eb20-4524-817d-9ca99ef0b2b9.wav", "formula": "$H_{2}\\left(g\\right)+Cl_{2}\\left(g\\right)═2HCl\\left(g\\right)$", "answer": "One molecule of hydrogen gas plus one molecule of chlorine gas produces two molecules of hydrogen chloride gas", "subset": "ChemEquation", "task_type": "tts"} +{"index": 849, "question": "Please read the following chemistry formula symbols: ${{{K}}_2}{S}{{{O}}_4}$", "audio_path": "audio/chemistry_4db6695f-ad63-46ab-a325-364e8b80dd98.wav", "formula": "${{{K}}_2}{S}{{{O}}_4}$", "answer": "potassium sulfate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 850, "question": "Please read the following chemistry formula symbols: $△H=2\\times283.0\\,\\text{kJ/mol}$", "audio_path": "audio/chemistry_fe235957-a15b-4247-aa9f-986202e5a08d.wav", "formula": "$△H=2\\times283.0\\,\\text{kJ/mol}$", "answer": "Delta H yields two times two hundred eighty-three point zero kilojoules per mole", "subset": "ChemEquation", "task_type": "tts"} +{"index": 851, "question": "Please read the following chemistry formula symbols: ${{H}_2}{C}{{O}_3}$", "audio_path": "audio/chemistry_31be6432-ab65-4274-8b6d-1f269b653a7c.wav", "formula": "${{H}_2}{C}{{O}_3}$", "answer": "carbonic acid", "subset": "ChemEquation", "task_type": "tts"} +{"index": 852, "question": "Please read the following chemistry formula symbols: $K^{+} 、Na^{+} 、Cl^{−} 、NO^{−}_{3}$", "audio_path": "audio/chemistry_ea72b24b-2961-4cd4-a452-710c3a25242a.wav", "formula": "$K^{+} 、Na^{+} 、Cl^{−} 、NO^{−}_{3}$", "answer": "Potassium ion plus sodium ion plus chloride ion plus nitrate ion", "subset": "ChemEquation", "task_type": "tts"} +{"index": 853, "question": "Please read the following chemistry formula symbols: $c\\left(S_{2}O^{2−}_{8}\\right),v\\left(Cr^{3+}\\right)$", "audio_path": "audio/chemistry_ca80e6de-3234-4655-99d7-210c34eda3f3.wav", "formula": "$c\\left(S_{2}O^{2−}_{8}\\right),v\\left(Cr^{3+}\\right)$", "answer": "c of peroxydisulfate two minus ion comma v of chromium three plus ion", "subset": "ChemEquation", "task_type": "tts"} +{"index": 854, "question": "Please read the following chemistry formula symbols: $CaCO_{3}\\left(s\\right)⇌Ca^{2+}\\left(aq\\right)+CO^{2−}_{3}\\left(aq\\right)$", "audio_path": "audio/chemistry_1958a94f-30d5-419e-8519-5140240580ba.wav", "formula": "$CaCO_{3}\\left(s\\right)⇌Ca^{2+}\\left(aq\\right)+CO^{2−}_{3}\\left(aq\\right)$", "answer": "Calcium carbonate solid is in equilibrium with one calcium two plus ion aqueous solution plus one carbonate two minus ion aqueous solution.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 855, "question": "Please read the following chemistry formula symbols: $$CH_{3}COOCH_{2}CH_{3}$$", "audio_path": "audio/chemistry_2386ef8a-f5ec-42fd-9fda-5b65a57c8049.wav", "formula": "$$CH_{3}COOCH_{2}CH_{3}$$", "answer": "ethyl acetate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 856, "question": "Please read the following chemistry formula symbols: $$2CO+4H_{2}=X+H_{2}O$$", "audio_path": "audio/chemistry_65f7c73a-9b82-4a29-9ad7-7f68e3c1682a.wav", "formula": "$$2CO+4H_{2}=X+H_{2}O$$", "answer": "Two molecules of carbon monoxide plus four molecules of hydrogen produce X plus one molecule of water.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 857, "question": "Please read the following chemistry formula symbols: $(ZnCl_{2})$", "audio_path": "audio/chemistry_ec722ad5-247e-4558-bc7b-debd39383507.wav", "formula": "$(ZnCl_{2})$", "answer": "zinc chloride", "subset": "ChemEquation", "task_type": "tts"} +{"index": 858, "question": "Please read the following chemistry formula symbols: $HCl$ $Na_{2}CO_{3}$ $BaCl_{2}$ $Na_{2}SO_{4}$", "audio_path": "audio/chemistry_79649fd1-822f-4b78-b41a-92103ae5b3f3.wav", "formula": "$HCl$ $Na_{2}CO_{3}$ $BaCl_{2}$ $Na_{2}SO_{4}$", "answer": "hydrogen chloride sodium carbonate barium chloride sodium sulfate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 859, "question": "Please read the following chemistry formula symbols: $c\\left(Fe^{3+}\\right)=0.1 mol⋅L^{−1}$", "audio_path": "audio/chemistry_15d80428-5d8e-4363-b815-92a75bf10421.wav", "formula": "$c\\left(Fe^{3+}\\right)=0.1 mol⋅L^{−1}$", "answer": "The concentration of the iron three plus ion equals zero point one moles per liter.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 860, "question": "Please read the following chemistry formula symbols: $$Y_{2}X_{3}< YZ_{3}$$", "audio_path": "audio/chemistry_3dfff417-9e30-49dc-9561-9c3fd0d07bc3.wav", "formula": "$$Y_{2}X_{3}< YZ_{3}$$", "answer": "Y two X three is less than Y Z three", "subset": "ChemEquation", "task_type": "tts"} +{"index": 861, "question": "Please read the following chemistry formula symbols: $$HNO_{3}$$", "audio_path": "audio/chemistry_c909aba9-4561-4329-89d4-1f23f946e0e3.wav", "formula": "$$HNO_{3}$$", "answer": "Four molecules of nitric acid produce lead(IV) oxide plus two atoms of lead", "subset": "ChemEquation", "task_type": "tts"} +{"index": 862, "question": "Please read the following chemistry formula symbols: $0.1mol⋅L^{-1}CH_{3}COOH$", "audio_path": "audio/chemistry_b9d85165-c7c5-4bf2-82a1-293bc373596e.wav", "formula": "$0.1mol⋅L^{-1}CH_{3}COOH$", "answer": "zero point one molar acetic acid", "subset": "ChemEquation", "task_type": "tts"} +{"index": 863, "question": "Please read the following chemistry formula symbols: $Al(OH)_{3}+3HCl═AlCl_{3}+3H_{2}O$", "audio_path": "audio/chemistry_688ed688-6cae-472a-96d6-9ae9c899d6a7.wav", "formula": "$Al(OH)_{3}+3HCl═AlCl_{3}+3H_{2}O$", "answer": "One molecule of aluminum hydroxide plus three molecules of hydrogen chloride yield one molecule of aluminum chloride plus three molecules of water.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 864, "question": "Please read the following chemistry formula symbols: $3S^{2−}+2Br^{−}+4Cl_{2}═3S\\downarrow+Br_{2}+8Cl^{−}$", "audio_path": "audio/chemistry_a17f8ea2-a34f-4919-9bdc-83a5e7a1e2cd.wav", "formula": "$3S^{2−}+2Br^{−}+4Cl_{2}═3S\\downarrow+Br_{2}+8Cl^{−}$", "answer": "Three sulfide two minus ions plus two bromide ions plus four molecules of chlorine produce three atoms of solid sulfur plus one molecule of bromine plus eight chloride ions.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 865, "question": "Please read the following chemistry formula symbols: $H_{3}PO_{4}>H_{2}SO_{4}>HClO_{4}$", "audio_path": "audio/chemistry_57dbca72-e286-49b1-b533-d138d92fae9c.wav", "formula": "$H_{3}PO_{4}>H_{2}SO_{4}>HClO_{4}$", "answer": "Phosphoric acid greater than sulfuric acid greater than perchloric acid", "subset": "ChemEquation", "task_type": "tts"} +{"index": 866, "question": "Please read the following chemistry formula symbols: $c\\left(H^{+}\\right)=10^{−14}mol⋅L^{−1}$", "audio_path": "audio/chemistry_1f9bb1a1-bafb-4e54-891d-bb3085aa425d.wav", "formula": "$c\\left(H^{+}\\right)=10^{−14}mol⋅L^{−1}$", "answer": "The concentration of hydrogen ion equals ten to the negative fourteenth moles per liter.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 867, "question": "Please read the following chemistry formula symbols: $rac{3a{N}_{A}}{14}$", "audio_path": "audio/chemistry_d126f58f-801d-453c-94bd-b314f5be4c44.wav", "formula": "$rac{3a{N}_{A}}{14}$", "answer": "Three times a times N subscript A over fourteen", "subset": "ChemEquation", "task_type": "tts"} +{"index": 868, "question": "Please read the following chemistry formula symbols: $$C_{15}H_{22}O_{5}$$", "audio_path": "audio/chemistry_3079ee98-cef2-4458-959a-58f7c71ca7ca.wav", "formula": "$$C_{15}H_{22}O_{5}$$", "answer": "A molecule containing fifteen carbon atoms, twenty-two hydrogen atoms, and five oxygen atoms", "subset": "ChemEquation", "task_type": "tts"} +{"index": 869, "question": "Please read the following chemistry formula symbols: $\\frac{c\\left(H^{+}\\right)}{c\\left(OH^{−}\\right)}=10^{4}$", "audio_path": "audio/chemistry_71e98f25-fa64-400d-94dd-c0f188104d20.wav", "formula": "$\\frac{c\\left(H^{+}\\right)}{c\\left(OH^{−}\\right)}=10^{4}$", "answer": "The concentration of hydrogen ions divided by the concentration of hydroxide ions equals ten to the power of four.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 870, "question": "Please read the following chemistry formula symbols: $c\\left(H^{+}\\right)=1\\times10^{-12}mol/L$", "audio_path": "audio/chemistry_5e2965f6-a9fe-4feb-9d54-83ea721d4025.wav", "formula": "$c\\left(H^{+}\\right)=1\\times10^{-12}mol/L$", "answer": "The concentration of hydrogen plus ion equals one times ten to the power of negative twelve moles per liter.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 871, "question": "Please read the following chemistry formula symbols: $${N}{{{H}}_4}{N}{{{O}}_3}$$", "audio_path": "audio/chemistry_ffccfaad-14d9-4e8d-95ce-119c59d64638.wav", "formula": "$${N}{{{H}}_4}{N}{{{O}}_3}$$", "answer": "ammonium nitrate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 872, "question": "Please read the following chemistry formula symbols: $$Cu_{2}(OH)_{2}CO_{3}$$", "audio_path": "audio/chemistry_e1bfbe75-fe7d-4dab-8f17-00754245b086.wav", "formula": "$$Cu_{2}(OH)_{2}CO_{3}$$", "answer": "copper(II) hydroxide carbonate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 873, "question": "Please read the following chemistry formula symbols: $n({NaNO}_3)=n({NaOH})=0.2{L} \\times4 {mol}/{L}=0.8{mol}$", "audio_path": "audio/chemistry_ad96258d-4478-4ab1-8ff2-bcb5d35bc880.wav", "formula": "$n({NaNO}_3)=n({NaOH})=0.2{L} \\times4 {mol}/{L}=0.8{mol}$", "answer": "Moles of sodium nitrate equals moles of sodium hydroxide equals zero point two liters multiplied by four moles per liter equals zero point eight moles", "subset": "ChemEquation", "task_type": "tts"} +{"index": 874, "question": "Please read the following chemistry formula symbols: $Al^{3+}+4Na+2H_{2}O=AlO^{−}_{2}+4Na^{+}+2H_{2}\\uparrow$", "audio_path": "audio/chemistry_4960c3f3-f7b6-4e5b-9454-da94c06edccb.wav", "formula": "$Al^{3+}+4Na+2H_{2}O=AlO^{−}_{2}+4Na^{+}+2H_{2}\\uparrow$", "answer": "Aluminum ion plus four sodium atoms plus two molecules of water produce aluminate one minus ion plus four sodium ions plus two molecules of hydrogen gas.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 875, "question": "Please read the following chemistry formula symbols: $CaO→Ca\\left(OH\\right)_{2}$", "audio_path": "audio/chemistry_2b214d33-53b3-4fab-aed4-da539a6b546d.wav", "formula": "$CaO→Ca\\left(OH\\right)_{2}$", "answer": "One molecule of calcium oxide produces one molecule of calcium hydroxide.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 876, "question": "Please read the following chemistry formula symbols: $Ti^{4+}+\\left(X+2\\right)H_{2}O ⇌TiO_{2}⋅H_{2}O+4H^{+}$", "audio_path": "audio/chemistry_d9a79bc8-12b7-4c21-a55c-42c4ff93b47a.wav", "formula": "$Ti^{4+}+\\left(X+2\\right)H_{2}O ⇌TiO_{2}⋅H_{2}O+4H^{+}$", "answer": "titanium four plus ion plus X plus two molecules of water reversibly produces titanium dioxide monohydrate plus four hydrogen ions", "subset": "ChemEquation", "task_type": "tts"} +{"index": 877, "question": "Please read the following chemistry formula symbols: $2FeCl_{3}+3 H_{2}O$", "audio_path": "audio/chemistry_1a7d65b2-b6d1-4425-9648-c7993da06089.wav", "formula": "$2FeCl_{3}+3 H_{2}O$", "answer": "Two molecules of iron(III) chloride plus three molecules of water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 878, "question": "Please read the following chemistry formula symbols: $I_{2}O_{5}+5CO═I_{2}+5CO_{2}$", "audio_path": "audio/chemistry_5c62ecd0-9bdd-43df-98f0-019d1cde2308.wav", "formula": "$I_{2}O_{5}+5CO═I_{2}+5CO_{2}$", "answer": "One molecule of iodine pentoxide plus five molecules of carbon monoxide produce one molecule of iodine gas and five molecules of carbon dioxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 879, "question": "Please read the following chemistry formula symbols: $3I_{2}+6KOH=5KI+KIO_{3}+3H_{2}O$", "audio_path": "audio/chemistry_1bee1e38-28fc-43c7-90e1-5d161d5e217c.wav", "formula": "$3I_{2}+6KOH=5KI+KIO_{3}+3H_{2}O$", "answer": "Three molecules of iodine plus six molecules of potassium hydroxide produce five molecules of potassium iodide plus one molecule of potassium iodate plus three molecules of water.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 880, "question": "Please read the following chemistry formula symbols: $\\frac{c(C{H}_{3}COOH)}{{c}^{2}({H}^{+})}$", "audio_path": "audio/chemistry_2e8f216a-ae8a-4132-bb07-4f84ec1016c0.wav", "formula": "$\\frac{c(C{H}_{3}COOH)}{{c}^{2}({H}^{+})}$", "answer": "The concentration of acetic acid divided by c squared times the concentration of hydrogen ions", "subset": "ChemEquation", "task_type": "tts"} +{"index": 881, "question": "Please read the following chemistry formula symbols: $\\frac{Ar(N)}{Mr[CO{(N{H}_{2})}_{2}]}\\times100\\%$", "audio_path": "audio/chemistry_8509cbff-00c8-4b5b-a7de-6030dc3c8a5e.wav", "formula": "$\\frac{Ar(N)}{Mr[CO{(N{H}_{2})}_{2}]}\\times100\\%$", "answer": "The atomic mass of nitrogen divided by the molecular mass of urea multiplied by 100 percent", "subset": "ChemEquation", "task_type": "tts"} +{"index": 882, "question": "Please read the following chemistry formula symbols: $H_{2}SO_{4} HCl Mg\\left(OH\\right)_{2} MgCl_{2}$", "audio_path": "audio/chemistry_f2c87291-91f9-4c93-a156-e57620a1144e.wav", "formula": "$H_{2}SO_{4} HCl Mg\\left(OH\\right)_{2} MgCl_{2}$", "answer": "sulfuric acid, hydrogen chloride, magnesium hydroxide, magnesium chloride", "subset": "ChemEquation", "task_type": "tts"} +{"index": 883, "question": "Please read the following chemistry formula symbols: $Ca\\left(ClO\\right)_2$", "audio_path": "audio/chemistry_1dbf86df-3445-4457-90a6-af061ea3d5f5.wav", "formula": "$Ca\\left(ClO\\right)_2$", "answer": "calcium hypochlorite", "subset": "ChemEquation", "task_type": "tts"} +{"index": 884, "question": "Please read the following chemistry formula symbols: $${CaO+}{{{H}}_{{2}}}{O}=Ca(OH)_{{2}}$$", "audio_path": "audio/chemistry_00922af6-e771-46a8-ad10-76a1b3b45562.wav", "formula": "$${CaO+}{{{H}}_{{2}}}{O}=Ca(OH)_{{2}}$$", "answer": "One molecule of calcium oxide plus one molecule of water produces one molecule of calcium hydroxide.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 885, "question": "Please read the following chemistry formula symbols: $\\frac{2.33g}{233g/mol}$", "audio_path": "audio/chemistry_19c26a87-245e-4cb9-8260-19a02748ff53.wav", "formula": "$\\frac{2.33g}{233g/mol}$", "answer": "two point three three grams divided by two hundred thirty-three grams per mole", "subset": "ChemEquation", "task_type": "tts"} +{"index": 886, "question": "Please read the following chemistry formula symbols: $Fe^{3+}+Cu═Fe^{2+}+Cu^{2+}$", "audio_path": "audio/chemistry_86f4d7a7-8c70-42b0-a791-8ba55487d7c0.wav", "formula": "$Fe^{3+}+Cu═Fe^{2+}+Cu^{2+}$", "answer": "Iron three plus ion plus copper produce iron two plus ion plus copper two plus ion.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 887, "question": "Please read the following chemistry formula symbols: $$Ca\\left(OH\\right)_{2}$$", "audio_path": "audio/chemistry_3a5f90f7-afb4-4a80-bfa0-1bbd2dd3ad85.wav", "formula": "$$Ca\\left(OH\\right)_{2}$$", "answer": "calcium hydroxide ion, one minus ion", "subset": "ChemEquation", "task_type": "tts"} +{"index": 888, "question": "Please read the following chemistry formula symbols: $HCl$ $H_{2}SO_{4}$ $HNO_{3}$", "audio_path": "audio/chemistry_72179e16-11a7-40b2-815b-c46210893a8c.wav", "formula": "$HCl$ $H_{2}SO_{4}$ $HNO_{3}$", "answer": "hydrogen chloride, sulfuric acid, and nitric acid", "subset": "ChemEquation", "task_type": "tts"} +{"index": 889, "question": "Please read the following chemistry formula symbols: $Al^{3+}+3OH^{−}═Al\\left(OH\\right)_{3}\\downarrow$", "audio_path": "audio/chemistry_bb434fa0-b741-47df-bf88-bcfb757441d0.wav", "formula": "$Al^{3+}+3OH^{−}═Al\\left(OH\\right)_{3}\\downarrow$", "answer": "One aluminum three plus ion plus three hydroxide one minus ions produce one molecule of solid aluminum hydroxide.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 890, "question": "Please read the following chemistry formula symbols: $${Mg}{{{F}}_{{2}}}$$", "audio_path": "audio/chemistry_05ce025c-1f1a-45fd-b4c0-cc8ff9533f44.wav", "formula": "$${Mg}{{{F}}_{{2}}}$$", "answer": "magnesium fluoride", "subset": "ChemEquation", "task_type": "tts"} +{"index": 891, "question": "Please read the following chemistry formula symbols: $$\\mathrm{Fe}_2\\mathrm{O}_3$$", "audio_path": "audio/chemistry_f1dd6231-4c71-4cc5-9507-a862a92c5350.wav", "formula": "$$\\mathrm{Fe}_2\\mathrm{O}_3$$", "answer": "iron three oxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 892, "question": "Please read the following chemistry formula symbols: $H_{2}(g)+\\frac{1}{2}O_{2}(g)$", "audio_path": "audio/chemistry_a2637eba-f8f1-41d4-86c4-9a21caba9d8c.wav", "formula": "$H_{2}(g)+\\frac{1}{2}O_{2}(g)$", "answer": "delta H one: one molecule of hydrogen gas plus half a molecule of oxygen", "subset": "ChemEquation", "task_type": "tts"} +{"index": 893, "question": "Please read the following chemistry formula symbols: $4.0mol/\\left(L⋅s\\right)$", "audio_path": "audio/chemistry_ba8316ab-3a6f-46ef-a41a-1c604b7a84d8.wav", "formula": "$4.0mol/\\left(L⋅s\\right)$", "answer": "four point zero moles per liter per second", "subset": "ChemEquation", "task_type": "tts"} +{"index": 894, "question": "Please read the following chemistry formula symbols: $\\frac{2.3g}{23g/mol}$", "audio_path": "audio/chemistry_f2b0689b-2ff0-417c-abdd-58c4962c2ed6.wav", "formula": "$\\frac{2.3g}{23g/mol}$", "answer": "2.3 grams divided by 23 grams per mole", "subset": "ChemEquation", "task_type": "tts"} +{"index": 895, "question": "Please read the following chemistry formula symbols: $$4.94\\times10^{−3} \\mathrm{mol/L}$$", "audio_path": "audio/chemistry_a94a15ce-18e7-4f53-a4d0-c4179e7c4e6d.wav", "formula": "$$4.94\\times10^{−3} \\mathrm{mol/L}$$", "answer": "four point nine four times ten to the negative three moles per liter", "subset": "ChemEquation", "task_type": "tts"} +{"index": 896, "question": "Please read the following chemistry formula symbols: $Al^{3+} + 3NH_{3} \\cdot H_{2}O = Al\\left(OH\\right)_{3} \\downarrow + 3NH_{4}^{+}$", "audio_path": "audio/chemistry_a64d1e7b-39f7-4f91-81cb-bd033435a262.wav", "formula": "$Al^{3+} + 3NH_{3} \\cdot H_{2}O = Al\\left(OH\\right)_{3} \\downarrow + 3NH_{4}^{+}$", "answer": "Aluminum three plus ion plus three molecules of ammonia and one molecule of water produce solid aluminum hydroxide plus three ammonium ions.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 897, "question": "Please read the following chemistry formula symbols: $$0.1mol⋅L^{−1} Na_{2}S_{2}O_{3}$$", "audio_path": "audio/chemistry_85ab7041-23d9-4747-8556-f983d890973d.wav", "formula": "$$0.1mol⋅L^{−1} Na_{2}S_{2}O_{3}$$", "answer": "zero point one moles per liter of sodium thiosulfate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 898, "question": "Please read the following chemistry formula symbols: $$\\left(C_{6}H_{8}O_{2}\\right)$$", "audio_path": "audio/chemistry_08bbf68f-c3aa-4c72-ab0f-21dff2cd902a.wav", "formula": "$$\\left(C_{6}H_{8}O_{2}\\right)$$", "answer": "carbon six hydrogen eight oxygen two", "subset": "ChemEquation", "task_type": "tts"} +{"index": 899, "question": "Please read the following chemistry formula symbols: $Ca\\left(OH\\right)_{2}$", "audio_path": "audio/chemistry_08aeb30d-b359-4095-8771-7b0ac8385028.wav", "formula": "$Ca\\left(OH\\right)_{2}$", "answer": "one molecule of calcium hydroxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 900, "question": "Please read the following chemistry formula symbols: $GeH_{4}>SiH_{4}>CH_{4}$", "audio_path": "audio/chemistry_460c3881-8a59-4fcf-b0b8-c61443e4446f.wav", "formula": "$GeH_{4}>SiH_{4}>CH_{4}$", "answer": "germane greater than silane greater than methane", "subset": "ChemEquation", "task_type": "tts"} +{"index": 901, "question": "Please read the following chemistry formula symbols: $AlCl_{3}═Al^{3+}+3Cl^{−}$", "audio_path": "audio/chemistry_e2293f23-6baf-49a8-997d-84b1a15b11f4.wav", "formula": "$AlCl_{3}═Al^{3+}+3Cl^{−}$", "answer": "One unit of aluminum chloride produces one aluminum three plus ion plus one chloride three minus ion.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 902, "question": "Please read the following chemistry formula symbols: $$\\left(C_{15}H_{22}O_{5}\\right)$$", "audio_path": "audio/chemistry_e6addeae-b1cf-492f-8230-73de150a27db.wav", "formula": "$$\\left(C_{15}H_{22}O_{5}\\right)$$", "answer": "carbon fifteen hydrogen twenty-two oxygen five", "subset": "ChemEquation", "task_type": "tts"} +{"index": 903, "question": "Please read the following chemistry formula symbols: $4NaI+O_{2}+2H_{2}SO_{4}=2Na_{2}SO_{4}+2I_{2}+2H_{2}O$", "audio_path": "audio/chemistry_17b68fe2-cb18-43fe-a816-0922e64ab8a1.wav", "formula": "$4NaI+O_{2}+2H_{2}SO_{4}=2Na_{2}SO_{4}+2I_{2}+2H_{2}O$", "answer": "Four molecules of sodium iodide plus one molecule of oxygen plus two molecules of sulfuric acid produce two molecules of sodium sulfate plus two molecules of iodine plus two molecules of water.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 904, "question": "Please read the following chemistry formula symbols: $1 mol Al_{2}(SO_{4})_{3}$", "audio_path": "audio/chemistry_5531da03-4020-42fb-b368-efc22a932a83.wav", "formula": "$1 mol Al_{2}(SO_{4})_{3}$", "answer": "One mole of aluminum sulfate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 905, "question": "Please read the following chemistry formula symbols: $CaCO_{3}+2H^{+}═Ca^{2+}+H_{2}O+CO_{2}$", "audio_path": "audio/chemistry_dfeabebe-bea6-40e6-90a0-4d0a213d785c.wav", "formula": "$CaCO_{3}+2H^{+}═Ca^{2+}+H_{2}O+CO_{2}$", "answer": "Calcium carbonate plus two hydrogen ions are in equilibrium with calcium two plus ion plus carbonic acid", "subset": "ChemEquation", "task_type": "tts"} +{"index": 906, "question": "Please read the following chemistry formula symbols: $C_{3}H_{7}OH, CH_{3}OH$", "audio_path": "audio/chemistry_8f8a3398-de54-4d94-b671-2d39fc3218cc.wav", "formula": "$C_{3}H_{7}OH, CH_{3}OH$", "answer": "propanol and methanol", "subset": "ChemEquation", "task_type": "tts"} +{"index": 907, "question": "Please read the following chemistry formula symbols: $W_{2} > Z_{2} > X_{2} > Y_{2}$", "audio_path": "audio/chemistry_1f82843d-f22c-495f-b8b9-f48e2380a150.wav", "formula": "$W_{2} > Z_{2} > X_{2} > Y_{2}$", "answer": "One molecule of tungsten greater than one molecule of Z greater than one molecule of X greater than one molecule of Y", "subset": "ChemEquation", "task_type": "tts"} +{"index": 908, "question": "Please read the following chemistry formula symbols: $Ba^{2+}+2OH^{−}+2H^{+}+SO^{2−}_{4}=BaSO_{4}\\downarrow+2H_{2}O$", "audio_path": "audio/chemistry_14e45bc9-e366-4d22-b461-1efaa5d8699c.wav", "formula": "$Ba^{2+}+2OH^{−}+2H^{+}+SO^{2−}_{4}=BaSO_{4}\\downarrow+2H_{2}O$", "answer": "One barium two plus ion plus one hydroxide ion plus one hydrogen ion plus one sulfate two minus ion produces solid barium sulfate plus one molecule of water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 909, "question": "Please read the following chemistry formula symbols: $NaCl$ $Mg(NO_{3})_{2}$", "audio_path": "audio/chemistry_da304183-2dc8-4a74-abc0-176db8df0eb7.wav", "formula": "$NaCl$ $Mg(NO_{3})_{2}$", "answer": "One molecule of sodium chloride and one molecule of magnesium nitrate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 910, "question": "Please read the following chemistry formula symbols: $$NaOH>Mg\\left(OH\\right)_{2}$$", "audio_path": "audio/chemistry_763c84a6-b086-4e5a-bac4-77b6a16073d2.wav", "formula": "$$NaOH>Mg\\left(OH\\right)_{2}$$", "answer": "Sodium hydroxide produces magnesium hydroxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 911, "question": "Please read the following chemistry formula symbols: $CaCl_{2}(CaCO_{3})$", "audio_path": "audio/chemistry_03a52af5-a3ee-43d3-a43e-636cc564e82e.wav", "formula": "$CaCl_{2}(CaCO_{3})$", "answer": "calcium chloride calcium carbonate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 912, "question": "Please read the following chemistry formula symbols: $C_{16}H_{12}N_{2}O$", "audio_path": "audio/chemistry_c843f516-1511-4f2c-8f92-680bc5bf95fe.wav", "formula": "$C_{16}H_{12}N_{2}O$", "answer": "C sixteen H twelve N two O", "subset": "ChemEquation", "task_type": "tts"} +{"index": 913, "question": "Please read the following chemistry formula symbols: $H_{2}SO_{4}═2H^{+}+SO^{2−}_{4}$", "audio_path": "audio/chemistry_aa91fec5-8a3d-49f1-ac3b-faeb7ee9d5be.wav", "formula": "$H_{2}SO_{4}═2H^{+}+SO^{2−}_{4}$", "answer": "Sulfuric acid reversibly produces two hydrogen ions and one sulfate two minus ion", "subset": "ChemEquation", "task_type": "tts"} +{"index": 914, "question": "Please read the following chemistry formula symbols: $v\\left(C\\right)=0.6 mol/\\left(L⋅s\\right)$", "audio_path": "audio/chemistry_0602add3-046a-4e8f-b6ce-be655bd22b01.wav", "formula": "$v\\left(C\\right)=0.6 mol/\\left(L⋅s\\right)$", "answer": "v of carbon equals zero point six mole per liter per second", "subset": "ChemEquation", "task_type": "tts"} +{"index": 915, "question": "Please read the following chemistry formula symbols: $HCO^{−}_{3}+OH^{−}═CO_{3}^{2-}+H_{2}O$", "audio_path": "audio/chemistry_c41e3a42-4746-4635-aedc-0e80af786b97.wav", "formula": "$HCO^{−}_{3}+OH^{−}═CO_{3}^{2-}+H_{2}O$", "answer": "One bicarbonate one minus ion plus one hydroxide one minus ion produces one molecule of carbon dioxide gas plus one molecule of water.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 916, "question": "Please read the following chemistry formula symbols: $$2FeCl_{3}+2HI=2FeCl_{2}+I_{2}+2HCl$$", "audio_path": "audio/chemistry_8f68420d-3116-4b06-8cf8-76795d6d7efd.wav", "formula": "$$2FeCl_{3}+2HI=2FeCl_{2}+I_{2}+2HCl$$", "answer": "Two molecules of iron(III) chloride plus two molecules of hydrogen iodide produce two molecules of iron(II) chloride plus one molecule of iodine plus two molecules of hydrogen chloride", "subset": "ChemEquation", "task_type": "tts"} +{"index": 917, "question": "Please read the following chemistry formula symbols: $Na_{2}CO_{3}\\cdot 10H_{2}O$", "audio_path": "audio/chemistry_abc814a7-49c1-44d9-abad-720c47114bdf.wav", "formula": "$Na_{2}CO_{3}\\cdot 10H_{2}O$", "answer": "sodium carbonate decahydrate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 918, "question": "Please read the following chemistry formula symbols: $SO_{4}^{2-} + Ba^{2+} \\rightarrow BaSO_{4} \\downarrow$", "audio_path": "audio/chemistry_c94b55dd-9d9c-4375-bd76-b372689d9ca2.wav", "formula": "$SO_{4}^{2-} + Ba^{2+} \\rightarrow BaSO_{4} \\downarrow$", "answer": "One sulfate two minus ion plus one barium two plus ion produces solid barium sulfate.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 919, "question": "Please read the following chemistry formula symbols: $KCl$、$K_{2}CO_{3}$", "audio_path": "audio/chemistry_0bb13d79-1f35-49d5-befc-023cad9d052a.wav", "formula": "$KCl$、$K_{2}CO_{3}$", "answer": "potassium chloride plus potassium carbonate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 920, "question": "Please read the following chemistry formula symbols: $K_{sp}[Cu(OH)_{2}]>K_{sp}[Mg(OH)_{2}]$", "audio_path": "audio/chemistry_1a48f32a-51da-450b-8cc0-4d82d476236e.wav", "formula": "$K_{sp}[Cu(OH)_{2}]>K_{sp}[Mg(OH)_{2}]$", "answer": "The solubility product constant of copper(II) hydroxide is greater than the solubility product constant of magnesium hydroxide.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 921, "question": "Please read the following chemistry formula symbols: $0.50molBa\\left(OH\\right)_{2}$", "audio_path": "audio/chemistry_a77821ac-9bb6-489b-8c66-430bdc9d251f.wav", "formula": "$0.50molBa\\left(OH\\right)_{2}$", "answer": "zero point five zero moles of barium hydroxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 922, "question": "Please read the following chemistry formula symbols: $Cu_{2}(OH)_{2}CO_{3}$", "audio_path": "audio/chemistry_c8fa9ce4-669c-4723-aaac-8187701abea1.wav", "formula": "$Cu_{2}(OH)_{2}CO_{3}$", "answer": "copper two plus hydroxide carbonate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 923, "question": "Please read the following chemistry formula symbols: $Cu^{2+}>H^{+}>Fe^{3+}>Na^{+}$", "audio_path": "audio/chemistry_b05b1b73-9447-438b-989e-da88091ec6c2.wav", "formula": "$Cu^{2+}>H^{+}>Fe^{3+}>Na^{+}$", "answer": "Copper two plus ion is greater than hydrogen ion, which is greater than iron three plus ion, which is greater than sodium ion.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 924, "question": "Please read the following chemistry formula symbols: $H^{+}+SO^{2−}_{4}+Ba^{2+}+OH^{−}$", "audio_path": "audio/chemistry_3fdc95fd-3ab1-4299-9c3a-7de6d7c2e513.wav", "formula": "$H^{+}+SO^{2−}_{4}+Ba^{2+}+OH^{−}$", "answer": "hydrogen ion plus sulfate two minus ion plus barium ion plus hydroxide one minus ion", "subset": "ChemEquation", "task_type": "tts"} +{"index": 925, "question": "Please read the following chemistry formula symbols: $H_{2}O$ $HNO_{3}$ $NaOH$ $KNO_{3}$", "audio_path": "audio/chemistry_6fdcc432-d043-42c0-9651-b6bcafefbf40.wav", "formula": "$H_{2}O$ $HNO_{3}$ $NaOH$ $KNO_{3}$", "answer": "water nitric acid sodium hydroxide potassium nitrate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 926, "question": "Please read the following chemistry formula symbols: $$(NH_{4})_{2}SO_{4}$$", "audio_path": "audio/chemistry_4403ed12-1b1e-403d-ac96-93edf24a9f55.wav", "formula": "$$(NH_{4})_{2}SO_{4}$$", "answer": "ammonium sulfate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 927, "question": "Please read the following chemistry formula symbols: $106a\\times \\left(\\frac{46}{106}\\times 100\\%\\right)=46a$", "audio_path": "audio/chemistry_bcfd4e67-24a4-4ea3-8b7a-7ec0fe4b62ec.wav", "formula": "$106a\\times \\left(\\frac{46}{106}\\times 100\\%\\right)=46a$", "answer": "One hundred six a times the quantity forty-six divided by one hundred six multiplied by one hundred percent equals forty-six a", "subset": "ChemEquation", "task_type": "tts"} +{"index": 928, "question": "Please read the following chemistry formula symbols: $1molO_{2}(g)$", "audio_path": "audio/chemistry_f81975bb-715e-4231-a796-f43b9b3d5b4d.wav", "formula": "$1molO_{2}(g)$", "answer": "one molecule of oxygen gas", "subset": "ChemEquation", "task_type": "tts"} +{"index": 929, "question": "Please read the following chemistry formula symbols: $\\frac{36\\ {g}}{36\\ {g}+100\\ {g}}\\times 100\\%\\approx 26.5\\%>16\\%$", "audio_path": "audio/chemistry_a2aa70b8-ab59-4f22-b027-01c061f439d0.wav", "formula": "$\\frac{36\\ {g}}{36\\ {g}+100\\ {g}}\\times 100\\%\\approx 26.5\\%>16\\%$", "answer": "Thirty-six grams divided by the sum of thirty-six grams plus one hundred grams, multiplied by one hundred percent, is approximately twenty-six point five percent, which is greater than sixteen percent.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 930, "question": "Please read the following chemistry formula symbols: $CH_{3}CH_{2} CH_{2} CH_{3}$", "audio_path": "audio/chemistry_a167b265-3be9-4538-bea3-9ac233cf6c7d.wav", "formula": "$CH_{3}CH_{2} CH_{2} CH_{3}$", "answer": "butane", "subset": "ChemEquation", "task_type": "tts"} +{"index": 931, "question": "Please read the following chemistry formula symbols: $Na_{2}CO_{3}+Ca$(OH)$_{2}═CaCO_{3}\\downarrow+2NaOH$", "audio_path": "audio/chemistry_d0260ee7-4bca-43a5-b270-9bc02d80796e.wav", "formula": "$Na_{2}CO_{3}+Ca$(OH)$_{2}═CaCO_{3}\\downarrow+2NaOH$", "answer": "Sodium carbonate plus calcium hydroxide produces calcium carbonate plus two molecules of sodium hydroxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 932, "question": "Please read the following chemistry formula symbols: $c\\left(Ba^{2+} \\right)=1.0\\times10^{−5} \\text{mol/L}$", "audio_path": "audio/chemistry_467918a8-7830-4e99-adaa-4a3b40cf31d0.wav", "formula": "$c\\left(Ba^{2+} \\right)=1.0\\times10^{−5} \\text{mol/L}$", "answer": "The concentration of barium two plus ion equals one point zero times ten to the negative fifth moles per liter.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 933, "question": "Please read the following chemistry formula symbols: $$2H_{2}O(g) =2H_{2}(g)+O_{2}(g)$$", "audio_path": "audio/chemistry_dc12d5f7-d8db-4117-86aa-d0c66adf38fa.wav", "formula": "$$2H_{2}O(g) =2H_{2}(g)+O_{2}(g)$$", "answer": "Two molecules of water vapor produce two molecules of hydrogen gas plus one molecule of oxygen gas.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 934, "question": "Please read the following chemistry formula symbols: $Ag^{+}+NH_{3} \\cdot H_{2}O \\xlongequal{} AgOH\\downarrow+NH_{4}^{+}$", "audio_path": "audio/chemistry_3aa322cb-64fb-458c-a1f1-6f5ec079587f.wav", "formula": "$Ag^{+}+NH_{3} \\cdot H_{2}O \\xlongequal{} AgOH\\downarrow+NH_{4}^{+}$", "answer": "Silver one plus ion plus one molecule of ammonia monohydrate produces solid silver hydroxide plus ammonium ion", "subset": "ChemEquation", "task_type": "tts"} +{"index": 935, "question": "Please read the following chemistry formula symbols: $$V_{1}mL c_{1} mol/L$", "audio_path": "audio/chemistry_3eb02894-9a77-4f85-9ee2-a77e69f1084e.wav", "formula": "$$V_{1}mL c_{1} mol/L$", "answer": "V one milliliters c one moles per liter", "subset": "ChemEquation", "task_type": "tts"} +{"index": 936, "question": "Please read the following chemistry formula symbols: ${CaO+}{{{H}}_{{2}}}{O}=\\!=\\!={Ca}{{({OH})}_{{2}}}$", "audio_path": "audio/chemistry_adf79b9e-7f40-4593-a850-82de67e3705d.wav", "formula": "${CaO+}{{{H}}_{{2}}}{O}=\\!=\\!={Ca}{{({OH})}_{{2}}}$", "answer": "One molecule of calcium oxide plus one molecule of water produces one molecule of calcium hydroxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 937, "question": "Please read the following chemistry formula symbols: $CO_{2}\\left(g\\right)+3H_{2}\\left(g\\right)$", "audio_path": "audio/chemistry_946ccb48-73c0-4473-bee8-2259594c3300.wav", "formula": "$CO_{2}\\left(g\\right)+3H_{2}\\left(g\\right)$", "answer": "Carbon dioxide gas plus three molecules of hydrogen gas", "subset": "ChemEquation", "task_type": "tts"} +{"index": 938, "question": "Please read the following chemistry formula symbols: $NaHSO_{4}═Na^{+}+HSO^{−}_{4}$", "audio_path": "audio/chemistry_a8079375-5404-4e20-8de6-b29144ea0a49.wav", "formula": "$NaHSO_{4}═Na^{+}+HSO^{−}_{4}$", "answer": "One molecule of sodium hydrogen sulfate produces one sodium ion plus one hydrogen sulfate one minus ion", "subset": "ChemEquation", "task_type": "tts"} +{"index": 939, "question": "Please read the following chemistry formula symbols: $Ca\\left(H_{2}PO_{4}\\right)_{2}$", "audio_path": "audio/chemistry_3d46e072-c88a-46dc-83eb-9c1cb4984a25.wav", "formula": "$Ca\\left(H_{2}PO_{4}\\right)_{2}$", "answer": "calcium dihydrogen phosphate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 940, "question": "Please read the following chemistry formula symbols: $HCOOCH_{3}(g)+2H_{2}(g)$", "audio_path": "audio/chemistry_13695da8-0a9c-4995-a3ac-b53c9a8cc58f.wav", "formula": "$HCOOCH_{3}(g)+2H_{2}(g)$", "answer": "is in equilibrium with methyl formate gas plus two molecules of hydrogen gas", "subset": "ChemEquation", "task_type": "tts"} +{"index": 941, "question": "Please read the following chemistry formula symbols: $2KOH+H_{2}SO_{4}=K_{2}SO_{4}+2H_{2}O$", "audio_path": "audio/chemistry_cc9337be-0450-4852-9935-5c9e18c5ec81.wav", "formula": "$2KOH+H_{2}SO_{4}=K_{2}SO_{4}+2H_{2}O$", "answer": "Two molecules of potassium hydroxide plus one molecule of sulfuric acid produce one molecule of potassium sulfate plus two molecules of water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 942, "question": "Please read the following chemistry formula symbols: $$\\left(C_{3}H_{6}O_{3}\\right).$$", "audio_path": "audio/chemistry_8ef613a2-94fc-4bb8-bd33-e8e6f044e78f.wav", "formula": "$$\\left(C_{3}H_{6}O_{3}\\right).$$", "answer": "lactic acid", "subset": "ChemEquation", "task_type": "tts"} +{"index": 943, "question": "Please read the following chemistry formula symbols: $$\\left(C_{7}H_{14}O_{2}\\right)$$", "audio_path": "audio/chemistry_c503de68-2e0c-466a-9ac9-55d565e8b570.wav", "formula": "$$\\left(C_{7}H_{14}O_{2}\\right)$$", "answer": "heptanoic acid", "subset": "ChemEquation", "task_type": "tts"} +{"index": 944, "question": "Please read the following chemistry formula symbols: $CO\\left(g\\right) +H_{2}O\\left(g\\right)⇌CO_{2}\\left(g\\right)+H_{2}\\left(g\\right)$", "audio_path": "audio/chemistry_2c3cbd91-33ec-4212-b4c7-cb74fc5678d1.wav", "formula": "$CO\\left(g\\right) +H_{2}O\\left(g\\right)⇌CO_{2}\\left(g\\right)+H_{2}\\left(g\\right)$", "answer": "One molecule of carbon monoxide gas plus one molecule of water gas reversibly produces one molecule of carbon dioxide gas plus one molecule of hydrogen gas", "subset": "ChemEquation", "task_type": "tts"} +{"index": 945, "question": "Please read the following chemistry formula symbols: $22.4 L$ $ CH_{3}CH_{2}OH$", "audio_path": "audio/chemistry_7494c8f5-379b-4c93-99ad-71beceaa9d10.wav", "formula": "$22.4 L$ $ CH_{3}CH_{2}OH$", "answer": "Twenty-two point four liters of ethanol", "subset": "ChemEquation", "task_type": "tts"} +{"index": 946, "question": "Please read the following chemistry formula symbols: ${{{H}}_{2}}{{{O}}_{2}}$", "audio_path": "audio/chemistry_a21d45b4-c1ea-41e1-aa3d-d327200125eb.wav", "formula": "${{{H}}_{2}}{{{O}}_{2}}$", "answer": "hydrogen peroxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 947, "question": "Please read the following chemistry formula symbols: $OH^{-}+H^{+}═H_{2}O$", "audio_path": "audio/chemistry_4876900f-f22a-40bd-8c03-689c86ecda0d.wav", "formula": "$OH^{-}+H^{+}═H_{2}O$", "answer": "Hydroxide one minus ion plus hydrogen one plus ion produce one molecule of water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 948, "question": "Please read the following chemistry formula symbols: $Cu\\left(NO_{3}\\right)_{2}$", "audio_path": "audio/chemistry_a59bebc9-3428-4d7e-8190-7c252b5b5217.wav", "formula": "$Cu\\left(NO_{3}\\right)_{2}$", "answer": "copper(II) nitrate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 949, "question": "Please read the following chemistry formula symbols: $3c\\left(CO_{2}\\right)⋅c\\left(H_{2}\\right)=5c\\left(CO\\right)⋅c\\left(H_{2}O\\right)$", "audio_path": "audio/chemistry_56f16f10-1870-4bdf-8fdd-35b6067a740c.wav", "formula": "$3c\\left(CO_{2}\\right)⋅c\\left(H_{2}\\right)=5c\\left(CO\\right)⋅c\\left(H_{2}O\\right)$", "answer": "Three times the concentration of carbon dioxide multiplied by the concentration of hydrogen gas produces five times the concentration of carbon monoxide multiplied by the concentration of water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 950, "question": "Please read the following chemistry formula symbols: $$({12}\\times{2}):({1}\\times{4}):({16}\\times{2})={6}:{1}:{8}$$", "audio_path": "audio/chemistry_20e84098-413e-453b-86ee-98d8b521a85a.wav", "formula": "$$({12}\\times{2}):({1}\\times{4}):({16}\\times{2})={6}:{1}:{8}$$", "answer": "Left parenthesis twelve multiplied by two right parenthesis left parenthesis one multiplied by four right parenthesis left parenthesis sixteen multiplied by two right parenthesis equals six to one to eight", "subset": "ChemEquation", "task_type": "tts"} +{"index": 951, "question": "Please read the following chemistry formula symbols: $ClO_2 + CaCl_2 + 2H_2O$", "audio_path": "audio/chemistry_b4133215-7269-4497-9438-497d38c6bfd6.wav", "formula": "$ClO_2 + CaCl_2 + 2H_2O$", "answer": "Chlorine dioxide plus calcium chloride plus two molecules of water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 952, "question": "Please read the following chemistry formula symbols: $$\\left(1\\right)6.5g$$", "audio_path": "audio/chemistry_746235fb-2aa0-4ca9-abe5-003b7390e488.wav", "formula": "$$\\left(1\\right)6.5g$$", "answer": "Open parenthesis one close parenthesis six point five grams", "subset": "ChemEquation", "task_type": "tts"} +{"index": 953, "question": "Please read the following chemistry formula symbols: $CO_{2}+OH^{−}=HCO^{−}_{3}$", "audio_path": "audio/chemistry_8a7a9ab8-61b2-4917-bef6-f271172dd862.wav", "formula": "$CO_{2}+OH^{−}=HCO^{−}_{3}$", "answer": "One molecule of carbon dioxide plus one hydroxide one minus ion produces one bicarbonate one minus ion plus one molecule of water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 954, "question": "Please read the following chemistry formula symbols: $CaO + H_{2}O = Ca(OH)_{2}$", "audio_path": "audio/chemistry_456c408f-4a60-4891-9852-93ea6aadd69b.wav", "formula": "$CaO + H_{2}O = Ca(OH)_{2}$", "answer": "Calcium oxide plus water produces calcium hydroxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 955, "question": "Please read the following chemistry formula symbols: $S(g)+O_{2}(g)=SO_{2}(g)$", "audio_path": "audio/chemistry_7d67e339-0eb7-4a5d-8db9-abfbeb5aaa91.wav", "formula": "$S(g)+O_{2}(g)=SO_{2}(g)$", "answer": "One molecule of sulfur gas plus one molecule of oxygen gas produce one molecule of sulfur dioxide gas.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 956, "question": "Please read the following chemistry formula symbols: $HCO^{−}_{3}⇌H^{+}+CO_{3}^{2-}$", "audio_path": "audio/chemistry_49d529ea-aefe-4da4-bdaf-1ecdc4caaec6.wav", "formula": "$HCO^{−}_{3}⇌H^{+}+CO_{3}^{2-}$", "answer": "One bicarbonate one minus ion reversibly produces hydroxide one minus ion plus one molecule of carbon dioxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 957, "question": "Please read the following chemistry formula symbols: $C\\left(s\\right)+O_{2}\\left(g\\right)═CO_{2}\\left(g\\right)$", "audio_path": "audio/chemistry_d8474809-9b1f-4e26-80a0-d28fdce0e520.wav", "formula": "$C\\left(s\\right)+O_{2}\\left(g\\right)═CO_{2}\\left(g\\right)$", "answer": "One molecule of carbon solid plus one molecule of oxygen gas produces one molecule of carbon dioxide gas.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 958, "question": "Please read the following chemistry formula symbols: $v\\left(KMnO_{4}\\right)=5×10^{−4}mol⋅L^{−1}⋅s^{−1}$", "audio_path": "audio/chemistry_ae36b24b-7530-4502-a0d8-ddf71fa9d190.wav", "formula": "$v\\left(KMnO_{4}\\right)=5×10^{−4}mol⋅L^{−1}⋅s^{−1}$", "answer": "The reaction rate of potassium permanganate produces five times ten to the negative fourth power moles per liter per second.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 959, "question": "Please read the following chemistry formula symbols: $4P+5O_{2}═2P_{2}O_{5}$", "audio_path": "audio/chemistry_33736e83-cdb9-4593-b2ec-56784144cb9f.wav", "formula": "$4P+5O_{2}═2P_{2}O_{5}$", "answer": "One molecule of phosphorus plus one molecule of oxygen produces one molecule of diphosphorus pentoxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 960, "question": "Please read the following chemistry formula symbols: $Na_{2}O•3FeO•Fe_{2}O_{3}•8SiO_{2}•H_{2}O$", "audio_path": "audio/chemistry_c456ee75-574c-496a-ad9c-e59dba72ae2e.wav", "formula": "$Na_{2}O•3FeO•Fe_{2}O_{3}•8SiO_{2}•H_{2}O$", "answer": "sodium oxide dot three molecules of iron(II) oxide dot iron(III) oxide dot eight molecules of silicon dioxide dot water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 961, "question": "Please read the following chemistry formula symbols: $${S}{O}_3 + 2{NaOH} = {N}{a}_2{S}{O}_4 + {H}_2{O}$$", "audio_path": "audio/chemistry_9953c5c7-ee90-4fcc-81f7-9942d9a042cb.wav", "formula": "$${S}{O}_3 + 2{NaOH} = {N}{a}_2{S}{O}_4 + {H}_2{O}$$", "answer": "One molecule of sulfur trioxide plus two molecules of sodium hydroxide produce one molecule of sodium sulfate and one molecule of water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 962, "question": "Please read the following chemistry formula symbols: $Na_{2}SiO_{3}+2H^{+}=H_{2}SiO_{3}\\downarrow+2Na^{+}$", "audio_path": "audio/chemistry_8ff52012-c1b7-45b7-a9a4-450869583bba.wav", "formula": "$Na_{2}SiO_{3}+2H^{+}=H_{2}SiO_{3}\\downarrow+2Na^{+}$", "answer": "Sodium silicate plus two hydrogen ions produce silicic acid solid plus two sodium ions.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 963, "question": "Please read the following chemistry formula symbols: $$\\frac{m}{M} N_{A}$$", "audio_path": "audio/chemistry_a5435c29-01ea-4fcd-b4f5-5e2b691f651a.wav", "formula": "$$\\frac{m}{M} N_{A}$$", "answer": "mass divided by molar mass multiplied by N subscript A", "subset": "ChemEquation", "task_type": "tts"} +{"index": 964, "question": "Please read the following chemistry formula symbols: $O_{2}$", "audio_path": "audio/chemistry_0a737104-0695-4eb7-8968-90007a3b53e7.wav", "formula": "$O_{2}$", "answer": "plus one molecule of oxygen produces", "subset": "ChemEquation", "task_type": "tts"} +{"index": 965, "question": "Please read the following chemistry formula symbols: $\\frac{\\frac{1mol}{2L}}{2s}$", "audio_path": "audio/chemistry_6d1af6e7-9d00-4d3f-89b9-ae73b18c1439.wav", "formula": "$\\frac{\\frac{1mol}{2L}}{2s}$", "answer": "one mole divided by two liters divided by two seconds", "subset": "ChemEquation", "task_type": "tts"} +{"index": 966, "question": "Please read the following chemistry formula symbols: $\\Delta H = -1160\\ \\mathrm{kJ} \\cdot \\mathrm{mol}^{-1}$", "audio_path": "audio/chemistry_17517f83-a562-4094-bd1a-0c48f8f4dc3a.wav", "formula": "$\\Delta H = -1160\\ \\mathrm{kJ} \\cdot \\mathrm{mol}^{-1}$", "answer": "Delta H equals negative 1160 kilojoules per mole", "subset": "ChemEquation", "task_type": "tts"} +{"index": 967, "question": "Please read the following chemistry formula symbols: $$3H_{2}+N_{2}⇌2NH_{3}$$", "audio_path": "audio/chemistry_18060ab5-75c1-4581-abc8-15e5efffa5a0.wav", "formula": "$$3H_{2}+N_{2}⇌2NH_{3}$$", "answer": "Three molecules of hydrogen plus one molecule of nitrogen reversibly produce two molecules of ammonia.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 968, "question": "Please read the following chemistry formula symbols: $H_{2}O\\left(g\\right)$", "audio_path": "audio/chemistry_7f3ec4f4-4fbd-4084-9664-0167e34bd632.wav", "formula": "$H_{2}O\\left(g\\right)$", "answer": "water gas", "subset": "ChemEquation", "task_type": "tts"} +{"index": 969, "question": "Please read the following chemistry formula symbols: $Na_{2}CO_{3}$", "audio_path": "audio/chemistry_2ce141d1-0f6b-4d79-bbb2-c49d2ab64c4b.wav", "formula": "$Na_{2}CO_{3}$", "answer": "sodium carbonate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 970, "question": "Please read the following chemistry formula symbols: $\\left(kJ⋅mol^{-1}\\right)$", "audio_path": "audio/chemistry_a9796370-d7b2-4c3c-af21-7ee7014f0821.wav", "formula": "$\\left(kJ⋅mol^{-1}\\right)$", "answer": "kilojoules per mole", "subset": "ChemEquation", "task_type": "tts"} +{"index": 971, "question": "Please read the following chemistry formula symbols: $2Na_{2}O_{2}+2H_{2}O=4NaOH+O_{2}$", "audio_path": "audio/chemistry_abfafc62-e0c8-4742-9ca8-779e96156a6f.wav", "formula": "$2Na_{2}O_{2}+2H_{2}O=4NaOH+O_{2}$", "answer": "Two molecules of sodium peroxide plus two molecules of water produce four molecules of sodium hydroxide plus one molecule of oxygen.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 972, "question": "Please read the following chemistry formula symbols: $c\\left(H^{+}\\right)−c\\left(OH^{−}\\right)=c\\left(A^{−}\\right)−c\\left(B^{+}\\right)$", "audio_path": "audio/chemistry_5f5820ba-9388-4451-93cb-f097b8548a43.wav", "formula": "$c\\left(H^{+}\\right)−c\\left(OH^{−}\\right)=c\\left(A^{−}\\right)−c\\left(B^{+}\\right)$", "answer": "The concentration of hydrogen ion minus the concentration of hydroxide ion equals the concentration of A minus ion minus the concentration of B plus ion.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 973, "question": "Please read the following chemistry formula symbols: $\\left(C_{6}H_{6}\\right)$", "audio_path": "audio/chemistry_3ac65e43-7add-4dc7-a77b-35c4f74086d3.wav", "formula": "$\\left(C_{6}H_{6}\\right)$", "answer": "one molecule of benzene", "subset": "ChemEquation", "task_type": "tts"} +{"index": 974, "question": "Please read the following chemistry formula symbols: $Fe+4H^{+}+NO^{−}_{3}=Fe^{3+}+NO\\uparrow+2H_{2}O$", "audio_path": "audio/chemistry_e1e738d0-c774-41a9-9802-5fb8d61d8fa7.wav", "formula": "$Fe+4H^{+}+NO^{−}_{3}=Fe^{3+}+NO\\uparrow+2H_{2}O$", "answer": "Iron plus four hydrogen ions plus nitrate ion produce iron three plus ion plus nitric oxide gas plus two molecules of water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 975, "question": "Please read the following chemistry formula symbols: $Cl_{2}:2 Fe^{2+}+Cl_{2}=2 Fe^{3+}+2Cl^{−}$", "audio_path": "audio/chemistry_714b8222-cde0-4abd-8d39-f9180b189b84.wav", "formula": "$Cl_{2}:2 Fe^{2+}+Cl_{2}=2 Fe^{3+}+2Cl^{−}$", "answer": "Two iron two plus ions plus one molecule of chlorine produce two iron three plus ions plus two chloride ions", "subset": "ChemEquation", "task_type": "tts"} +{"index": 976, "question": "Please read the following chemistry formula symbols: $CaO+H_{2}O═Ca(OH)_{2}$", "audio_path": "audio/chemistry_52471a4b-6dbc-4ae0-b6dc-d20b2d28eaf7.wav", "formula": "$CaO+H_{2}O═Ca(OH)_{2}$", "answer": "One molecule of calcium oxide plus one molecule of water produces one molecule of calcium hydroxide", "subset": "ChemEquation", "task_type": "tts"} +{"index": 977, "question": "Please read the following chemistry formula symbols: $K_{sp}\\left[Zn\\left(OH\\right)_{2}\\right]=1.0\\times10^{-18}$", "audio_path": "audio/chemistry_af2a8fdf-fa75-4527-97b4-b2ace1e490fe.wav", "formula": "$K_{sp}\\left[Zn\\left(OH\\right)_{2}\\right]=1.0\\times10^{-18}$", "answer": "K subscript s p for zinc hydroxide equals one point zero times ten to the negative eighteenth", "subset": "ChemEquation", "task_type": "tts"} +{"index": 978, "question": "Please read the following chemistry formula symbols: $2Mg(s)+O_2(g)=2MgO(s)\\ \\Delta H<0$", "audio_path": "audio/chemistry_8cf67a68-a0f3-4539-ab7d-44b9aae783b8.wav", "formula": "$2Mg(s)+O_2(g)=2MgO(s)\\ \\Delta H<0$", "answer": "Two atoms of solid magnesium plus one molecule of oxygen gas produce two molecules of magnesium oxide, with delta H less than zero", "subset": "ChemEquation", "task_type": "tts"} +{"index": 979, "question": "Please read the following chemistry formula symbols: $\\mathrm{2NO + O_2\\xlongequal{}2NO_2}$", "audio_path": "audio/chemistry_eee155c5-48f9-4b31-bb7c-3016c687a7ba.wav", "formula": "$\\mathrm{2NO + O_2\\xlongequal{}2NO_2}$", "answer": "Two molecules of nitric oxide plus one molecule of oxygen produce two molecules of nitrogen dioxide.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 980, "question": "Please read the following chemistry formula symbols: $$Fe+2H{^{+}}\\xlongequal{} Fe{^{2+}}+H_{2}\\uparrow$$", "audio_path": "audio/chemistry_7227c139-fa3d-40be-a1d8-d6ab6a1b5266.wav", "formula": "$$Fe+2H{^{+}}\\xlongequal{} Fe{^{2+}}+H_{2}\\uparrow$$", "answer": "Two atoms of iron plus six hydrogen ions produce two iron three plus ions plus three molecules of hydrogen.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 981, "question": "Please read the following chemistry formula symbols: $c\\left(OH^{-}\\right)$", "audio_path": "audio/chemistry_d8ccaaae-babf-4f32-b975-82589f446bbe.wav", "formula": "$c\\left(OH^{-}\\right)$", "answer": "c hydroxide ion", "subset": "ChemEquation", "task_type": "tts"} +{"index": 982, "question": "Please read the following chemistry formula symbols: $v\\left(SO_{2}\\right)=0.3mol/\\left(L⋅s\\right)$", "audio_path": "audio/chemistry_5f9464bc-912f-4e01-ab36-536e8662740e.wav", "formula": "$v\\left(SO_{2}\\right)=0.3mol/\\left(L⋅s\\right)$", "answer": "The rate of sulfur dioxide equals zero point three moles per liter per second.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 983, "question": "Please read the following chemistry formula symbols: $$N\\left(NO_{2}\\right)_{3}$$", "audio_path": "audio/chemistry_8dcb76e4-9da2-4c1d-8a89-b75899e8f9b5.wav", "formula": "$$N\\left(NO_{2}\\right)_{3}$$", "answer": "nitrogen trinitrite", "subset": "ChemEquation", "task_type": "tts"} +{"index": 984, "question": "Please read the following chemistry formula symbols: $v\\left(D\\right)=0.25mol⋅L^{-1}⋅s^{-1}$", "audio_path": "audio/chemistry_61e64668-b2d2-4d48-8c25-4d6c8468095d.wav", "formula": "$v\\left(D\\right)=0.25mol⋅L^{-1}⋅s^{-1}$", "answer": "v of D equals zero point two five moles per liter per second", "subset": "ChemEquation", "task_type": "tts"} +{"index": 985, "question": "Please read the following chemistry formula symbols: $$\\left(C_{3}O_{3}N_{3}Cl_{3}\\right),$$", "audio_path": "audio/chemistry_96173428-51dd-43f3-8bcf-52177f0debee.wav", "formula": "$$\\left(C_{3}O_{3}N_{3}Cl_{3}\\right),$$", "answer": "cyanuric chloride", "subset": "ChemEquation", "task_type": "tts"} +{"index": 986, "question": "Please read the following chemistry formula symbols: $CH_{4}+2O_{2}═CO_{2}+2H_{2}O$", "audio_path": "audio/chemistry_8d202f11-9ec7-446f-9fec-29a9af2a4ee5.wav", "formula": "$CH_{4}+2O_{2}═CO_{2}+2H_{2}O$", "answer": "One molecule of methane plus two molecules of oxygen produce one molecule of carbon dioxide plus two molecules of water", "subset": "ChemEquation", "task_type": "tts"} +{"index": 987, "question": "Please read the following chemistry formula symbols: $${Na}_{2}{{{CO}}_{{3}}}$$", "audio_path": "audio/chemistry_d7c4669e-5d4f-4e34-a628-c9e2c2202fc3.wav", "formula": "$${Na}_{2}{{{CO}}_{{3}}}$$", "answer": "sodium carbonate", "subset": "ChemEquation", "task_type": "tts"} +{"index": 988, "question": "Please read the following chemistry formula symbols: $$2SO_{2}+O_{2} ⇌2SO_{3}$$", "audio_path": "audio/chemistry_66ccbc2c-dfea-4cb2-8646-b921f8ecc07d.wav", "formula": "$$2SO_{2}+O_{2} ⇌2SO_{3}$$", "answer": "Two molecules of sulfur dioxide plus one molecule of oxygen reversibly produce two molecules of sulfur trioxide.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 989, "question": "Please read the following chemistry formula symbols: $$Na_{2}O+H_{2}O═2Na^{+}+2OH^{−}$$", "audio_path": "audio/chemistry_9df1f36c-e930-4984-82cb-d648d651e552.wav", "formula": "$$Na_{2}O+H_{2}O═2Na^{+}+2OH^{−}$$", "answer": "Sodium oxide plus water produces two sodium ions plus two hydroxide ions.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 990, "question": "Please read the following chemistry formula symbols: $(2 \\times 2):32:(2 \\times 18) = 1:8:9$", "audio_path": "audio/chemistry_32843dd3-1317-4a1e-bcec-57d14fac2539.wav", "formula": "$(2 \\times 2):32:(2 \\times 18) = 1:8:9$", "answer": "Two times two to thirty-two to two times eighteen equals one to eight to nine.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 991, "question": "Please read the following chemistry formula symbols: $8{.4g}\\div (\\frac{1\\times 42}{414}\\times 100 \\% )=82{.8g}$", "audio_path": "audio/chemistry_f6d8e6cf-3da9-46ee-8455-ddc715acdca4.wav", "formula": "$8{.4g}\\div (\\frac{1\\times 42}{414}\\times 100 \\% )=82{.8g}$", "answer": "Eight point four grams divided by the quantity one multiplied by forty-two divided by four hundred fourteen times one hundred percent equals eighty-two point eight grams", "subset": "ChemEquation", "task_type": "tts"} +{"index": 992, "question": "Please read the following chemistry formula symbols: $2Fe^{3+}+Cu═2Fe^{2+}+Cu^{2+}$", "audio_path": "audio/chemistry_ab6edfc1-24b2-4dac-b6ac-245e496f3946.wav", "formula": "$2Fe^{3+}+Cu═2Fe^{2+}+Cu^{2+}$", "answer": "Two iron three plus ions plus one copper atom produce two iron two plus ions plus one copper two plus ion", "subset": "ChemEquation", "task_type": "tts"} +{"index": 993, "question": "Please read the following chemistry formula symbols: $(12\\times 2):({1}\\times 8):(14\\times 2){=6:2:7}$", "audio_path": "audio/chemistry_f94cf54e-e63e-4eaf-8460-8431c8dce131.wav", "formula": "$(12\\times 2):({1}\\times 8):(14\\times 2){=6:2:7}$", "answer": "Twelve times two to one times eight to fourteen times two yields six to two to seven.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 994, "question": "Please read the following chemistry formula symbols: $X_{2}+2Y_{2}═2XY_{2}$", "audio_path": "audio/chemistry_d1df588e-7456-4e95-934d-63d1c74a1ece.wav", "formula": "$X_{2}+2Y_{2}═2XY_{2}$", "answer": "One molecule of X two plus two molecules of Y two produce two molecules of X Y two.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 995, "question": "Please read the following chemistry formula symbols: $H_{2}\\left(g\\right)+I_{2}\\left(g\\right)=2HI\\left(g\\right)$", "audio_path": "audio/chemistry_6f52f5ee-b387-4c7e-80d4-70578f4dc76a.wav", "formula": "$H_{2}\\left(g\\right)+I_{2}\\left(g\\right)=2HI\\left(g\\right)$", "answer": "One molecule of hydrogen gas plus one molecule of iodine gas produces one molecule of hydrogen iodide gas.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 996, "question": "Please read the following chemistry formula symbols: $△H=−890kJ⋅mol^{−1}$", "audio_path": "audio/chemistry_01418943-92e6-46ff-b2e2-eb4482d061b7.wav", "formula": "$△H=−890kJ⋅mol^{−1}$", "answer": "delta H equals negative 890 kilojoules per mole", "subset": "ChemEquation", "task_type": "tts"} +{"index": 997, "question": "Please read the following chemistry formula symbols: $$\\left[Co\\left(NH_{3}\\right)_{4} Cl_{2}\\right]Cl$$", "audio_path": "audio/chemistry_bb5677fd-b4ba-4edf-8fe9-952116cdcfdb.wav", "formula": "$$\\left[Co\\left(NH_{3}\\right)_{4} Cl_{2}\\right]Cl$$", "answer": "tetraamminedichlorocobalt(III) chloride", "subset": "ChemEquation", "task_type": "tts"} +{"index": 998, "question": "Please read the following chemistry formula symbols: $CuO+H_{2}SO_{4}═CuSO_{4}+H_{2}O$", "audio_path": "audio/chemistry_502f6e11-f7c8-4291-ae8a-46b32c646399.wav", "formula": "$CuO+H_{2}SO_{4}═CuSO_{4}+H_{2}O$", "answer": "One molecule of copper(II) oxide plus one molecule of sulfuric acid produces one molecule of copper(II) sulfate plus one molecule of water.", "subset": "ChemEquation", "task_type": "tts"} +{"index": 999, "question": "Please read the following chemistry formula symbols: $$SiH_{4} < PH_{3} < H_{2}O$$", "audio_path": "audio/chemistry_eced3076-91db-42d2-8b2b-679c56922df6.wav", "formula": "$$SiH_{4} < PH_{3} < H_{2}O$$", "answer": "One molecule of silane less than one molecule of phosphine less than one molecule of water", "subset": "ChemEquation", "task_type": "tts"} diff --git 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diff --git a/ChemEquation/audio/chemistry_ffccfaad-14d9-4e8d-95ce-119c59d64638.wav b/ChemEquation/audio/chemistry_ffccfaad-14d9-4e8d-95ce-119c59d64638.wav new file mode 100644 index 0000000000000000000000000000000000000000..abd03102f2a3b4aeabf934fc34650e0f0604cc75 --- /dev/null +++ b/ChemEquation/audio/chemistry_ffccfaad-14d9-4e8d-95ce-119c59d64638.wav @@ -0,0 +1,3 @@ +version https://git-lfs.github.com/spec/v1 +oid sha256:23e569e1c9e8d07b1c58ce2de297957282d6c8f2971eb8faccd9d1455c85fe0c +size 111438 diff --git a/ChemEquation/audio/chemistry_ffef6b0f-9c26-490a-be21-2f5d6a57ff38.wav b/ChemEquation/audio/chemistry_ffef6b0f-9c26-490a-be21-2f5d6a57ff38.wav new file mode 100644 index 0000000000000000000000000000000000000000..33750becbe33a6ddd6647377d26dd7363a0ea44e --- /dev/null +++ b/ChemEquation/audio/chemistry_ffef6b0f-9c26-490a-be21-2f5d6a57ff38.wav @@ -0,0 +1,3 @@ +version https://git-lfs.github.com/spec/v1 +oid sha256:aaf70d4d34baac6eb9ebf434531a4fe119d8c6c853781220b17a0180d985d860 +size 587598 diff --git a/MixMath/MixMath.jsonl b/MixMath/MixMath.jsonl new file mode 100644 index 0000000000000000000000000000000000000000..bf4d03ea8863241a7fb5a4ff798abc0e612bf59a --- /dev/null +++ b/MixMath/MixMath.jsonl @@ -0,0 +1,2000 @@ +{"index": 0, "question": "Please read the following math formula symbols: $e^k\\leqe^{k+2}$", "audio_path": "audio/row_02047995_1755840188937845.wav", "formula": "$e^k\\leqe^{k+2}$", "answer": "e raised to the power of k is less than or equal to e raised to the power of k plus 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 1, "question": "Please read the following math formula symbols: $C_1=\\frac{-A_1A_3+A_4}{A_4}$", "audio_path": "audio/row_01121719_1755723410700064.wav", "formula": "$C_1=\\frac{-A_1A_3+A_4}{A_4}$", "answer": "C sub 1 equals negative A sub 1 times A sub 3 plus A sub 4 all divided by A sub 4.", "subset": "mixmath", "task_type": "tts"} +{"index": 2, "question": "请你朗读以下数学公式符号:$=4\\times 3.5+4\\times 2\\times 2+3.5\\times 2\\times 2$", "audio_path": "audio/math_ba50cc4b-6c92-45a9-ba0b-b278b33f48b2.wav", "formula": "$=4\\times 3.5+4\\times 2\\times 2+3.5\\times 2\\times 2$", "answer": "等于四乘三点五加四乘二乘二加三点五乘二乘二", "subset": "mixmath", "task_type": "tts"} +{"index": 3, "question": "请你朗读以下数学公式符号:$$ \\left\\{\\begin{array}{c}x+y=600\\\\ 1700x+1300y=940000\\end{array}\\right.$$", "audio_path": "audio/math_b4e9fc0c-a202-4241-82bc-5ddf49f95ed5.wav", "formula": "$$ \\left\\{\\begin{array}{c}x+y=600\\\\ 1700x+1300y=940000\\end{array}\\right.$$", "answer": "x加y的等于六百,一千七百x加一千三百y等于九十四万", "subset": "mixmath", "task_type": "tts"} +{"index": 4, "question": "请你朗读以下数学公式符号:$$\\frac{3}{4}×\\frac{8}{13}+\\frac{5}{13}×\\frac{3}{4}$$", "audio_path": "audio/math_a8cb2a11-f586-48ee-990f-d6c1f5e8080e.wav", "formula": "$$\\frac{3}{4}×\\frac{8}{13}+\\frac{5}{13}×\\frac{3}{4}$$", "answer": "四分之三乘十三分之八加十三分之五乘四分之三", "subset": "mixmath", "task_type": "tts"} +{"index": 5, "question": "请你朗读以下数学公式符号:$={{a}^{2}}({{a}^{2}}+7a)+{{b}^{2}}({{b}^{2}}+7b)$", "audio_path": "audio/math_640a2827-ebbe-4df3-a26c-bf0083869eaf.wav", "formula": "$={{a}^{2}}({{a}^{2}}+7a)+{{b}^{2}}({{b}^{2}}+7b)$", "answer": "等于a的平方乘a平方与七a的和,再加上b的平方乘b平方与七b的和", "subset": "mixmath", "task_type": "tts"} +{"index": 6, "question": "请你朗读以下数学公式符号:$=\\frac{9}{10}\\times \\frac{5}{2}\\times \\frac{5}{2}$", "audio_path": "audio/math_fa1ebdd6-cf46-48bd-bb91-13a3201ccc43.wav", "formula": "$=\\frac{9}{10}\\times \\frac{5}{2}\\times \\frac{5}{2}$", "answer": "等于十分之九乘二分之五乘二分之五", "subset": "mixmath", "task_type": "tts"} +{"index": 7, "question": "请你朗读以下数学公式符号:$\\frac{x+y}{x}=\\frac{x+\\dfrac{2}{3}x}{x}=\\frac{5}{3}$", "audio_path": "audio/math_b34eba96-4e0e-49ab-a7fb-f44b257727ad.wav", "formula": "$\\frac{x+y}{x}=\\frac{x+\\dfrac{2}{3}x}{x}=\\frac{5}{3}$", "answer": "x 分之 x 加 y 的和 等于 x 分之 x 加三分之二 x 的和 等于 三分之五", "subset": "mixmath", "task_type": "tts"} +{"index": 8, "question": "请你朗读以下数学公式符号:$\\begin{eqnarray}&&35.14\\div 3.5\\div 0.2\\\\ &=&35.14\\div \\left( 3.5\\times 0.2 \\right)\\\\ &=&35.14\\div 0.7\\\\ &=&50.2\\end{eqnarray}$", "audio_path": "audio/math_a32f7011-b149-41e5-a486-9fb7c44ddf6a.wav", "formula": "$\\begin{eqnarray}&&35.14\\div 3.5\\div 0.2\\\\ &=&35.14\\div \\left( 3.5\\times 0.2 \\right)\\\\ &=&35.14\\div 0.7\\\\ &=&50.2\\end{eqnarray}$", "answer": "三十五点一四除以三点五除以零点二等于三十五点一四除以三点五乘零点二的积等于三十五点一四除以零点七等于五十点二。", "subset": "mixmath", "task_type": "tts"} +{"index": 9, "question": "Please read the following math formula symbols: $\\dim(\\pi_1\\cap\\pi_2)=d_0\\ge2d-D$", "audio_path": "audio/row_01857376_1755816137564810.wav", "formula": "$\\dim(\\pi_1\\cap\\pi_2)=d_0\\ge2d-D$", "answer": "Dimension of the intersection of pi sub 1 and pi sub 2 equals d sub 0 greater than or equal to 2d minus D.", "subset": "mixmath", "task_type": "tts"} +{"index": 10, "question": "请你朗读以下数学公式符号:$=5+\\frac{1}{1\\times 3}+\\frac{1}{3\\times 5}+\\frac{1}{5\\times 7}+\\frac{1}{7\\times 9}+\\frac{1}{9\\times 11}$", "audio_path": "audio/math_9730de62-b6c8-4cbc-9f56-6f5d7916a2e7.wav", "formula": "$=5+\\frac{1}{1\\times 3}+\\frac{1}{3\\times 5}+\\frac{1}{5\\times 7}+\\frac{1}{7\\times 9}+\\frac{1}{9\\times 11}$", "answer": "等于五加一乘三的积分之一加三乘五的积分之一加五乘七的积分之一加七乘九的积分之一加九乘十一的积分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 11, "question": "请你朗读以下数学公式符号:${{14}^{2}}\\equiv 196\\equiv 6(\\bmod 10),{{14}^{14}}\\equiv {{\\left( {{14}^{2}} \\right)}^{7}}\\equiv {{6}^{7}}\\equiv 6(\\bmod 10)$", "audio_path": "audio/math_eb6b3986-edce-44f6-9d96-bd170176b16c.wav", "formula": "${{14}^{2}}\\equiv 196\\equiv 6(\\bmod 10),{{14}^{14}}\\equiv {{\\left( {{14}^{2}} \\right)}^{7}}\\equiv {{6}^{7}}\\equiv 6(\\bmod 10)$", "answer": "十四的平方同余于一百九十六同余于六模十,十四的十四次方同余于十四的平方的七次方同余于六的七次方同余于六模十", "subset": "mixmath", "task_type": "tts"} +{"index": 12, "question": "请你朗读以下数学公式符号:$\\left\\{\\begin{array}{c}5x+6y=10\\\\ 4x+y=5y+x\\end{array}\\right.$", "audio_path": "audio/math_95c31624-cb3a-4663-bb14-6725b9d96131.wav", "formula": "$\\left\\{\\begin{array}{c}5x+6y=10\\\\ 4x+y=5y+x\\end{array}\\right.$", "answer": "五x加六y等于十,四x加y等于五y加x", "subset": "mixmath", "task_type": "tts"} +{"index": 13, "question": "请你朗读以下数学公式符号:$\\left( 100+60 \\right)\\times x=\\left( 90+60 \\right)\\times \\left( x+2 \\right)$", "audio_path": "audio/math_a38567f6-6baa-4569-ba99-1c88e1ee754a.wav", "formula": "$\\left( 100+60 \\right)\\times x=\\left( 90+60 \\right)\\times \\left( x+2 \\right)$", "answer": "一百加六十的和乘x等于九十加六十的和乘x加二的和", "subset": "mixmath", "task_type": "tts"} +{"index": 14, "question": "请你朗读以下数学公式符号:$1004.8\\times 3\\div \\left( 6\\times 6\\times 3.14 \\right)=\\frac{80}{3}$", "audio_path": "audio/math_dddf5c24-e2c7-4807-a9b7-a4965b9760d0.wav", "formula": "$1004.8\\times 3\\div \\left( 6\\times 6\\times 3.14 \\right)=\\frac{80}{3}$", "answer": "一千零四点八乘三除以六乘六乘三点一四的积等于三分之八十", "subset": "mixmath", "task_type": "tts"} +{"index": 15, "question": "请你朗读以下数学公式符号:$\\frac{8}{9}=\\frac{8\\times 7}{9\\times 7}=\\frac{56}{63}$", "audio_path": "audio/math_9eab1c7e-a960-4bc7-9217-eadd9099a7ca.wav", "formula": "$\\frac{8}{9}=\\frac{8\\times 7}{9\\times 7}=\\frac{56}{63}$", "answer": "九分之八等于九乘七的积分之八乘七的积等于六十三分之五十六", "subset": "mixmath", "task_type": "tts"} +{"index": 16, "question": "请你朗读以下数学公式符号:$=\\frac{6}{7}\\div \\left[ \\frac{1}{14}\\times \\frac{2}{5} \\right]$", "audio_path": "audio/math_f985055c-dad1-4b95-9d84-963a1c4c2fa0.wav", "formula": "$=\\frac{6}{7}\\div \\left[ \\frac{1}{14}\\times \\frac{2}{5} \\right]$", "answer": "等于七分之六除以十四分之一乘五分之二的积", "subset": "mixmath", "task_type": "tts"} +{"index": 17, "question": "Please read the following math formula symbols: ${f_{T'}}_*\\mathcalO_{X_{T'}}(mL_{T'})$", "audio_path": "audio/row_01011533_1755709685096645.wav", "formula": "${f_{T'}}_*\\mathcalO_{X_{T'}}(mL_{T'})$", "answer": "f sub T prime, sub asterisk O sub X sub T prime, open parenthesis, m L sub T prime, close parenthesis", "subset": "mixmath", "task_type": "tts"} +{"index": 18, "question": "Please read the following math formula symbols: $\\|\\hat{\\eta}-\\eta^\\ast\\|_2\\leq\\tilde{\\delta}$", "audio_path": "audio/row_00225049_1755612386997215.wav", "formula": "$\\|\\hat{\\eta}-\\eta^\\ast\\|_2\\leq\\tilde{\\delta}$", "answer": "The norm of the difference between eta hat and eta asterisk, with subscript 2, is less than or equal to tilde delta.", "subset": "mixmath", "task_type": "tts"} +{"index": 19, "question": "Please read the following math formula symbols: $\\mathrm{tr}\\big[V(L^\\diamond_N)\\big]$", "audio_path": "audio/row_00341731_1755626564972004.wav", "formula": "$\\mathrm{tr}\\big[V(L^\\diamond_N)\\big]$", "answer": "The trace of the composition of the linear operator V with the diamond power of the operator L subscripted by N.", "subset": "mixmath", "task_type": "tts"} +{"index": 20, "question": "Please read the following math formula symbols: $m=8^{t_1-1}4^{t_2}$", "audio_path": "audio/row_00379836_1755631228535529.wav", "formula": "$m=8^{t_1-1}4^{t_2}$", "answer": "m equals 8 to the power of t sub 1 minus 1 times 4 to the power of t sub 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 21, "question": "请你朗读以下数学公式符号:$$\\frac{3}{4}+\\frac{1}{6}=\\frac{9}{12}+\\frac{2}{12}=\\frac{11}{12}$$", "audio_path": "audio/math_703e3fdf-b301-4dc9-8add-8eeb356f5c0e.wav", "formula": "$$\\frac{3}{4}+\\frac{1}{6}=\\frac{9}{12}+\\frac{2}{12}=\\frac{11}{12}$$", "answer": "四分之三加六分之一等于十二分之九加十二分之二等于十二分之十一", "subset": "mixmath", "task_type": "tts"} +{"index": 22, "question": "请你朗读以下数学公式符号:$\\left\\{\\begin{array}{c}x=1\\\\y=6\\end{array}\\right.$", "audio_path": "audio/math_3ffbe2b0-d34f-4d15-bc43-6866f6180e84.wav", "formula": "$\\left\\{\\begin{array}{c}x=1\\\\y=6\\end{array}\\right.$", "answer": "x等于一和y等于六", "subset": "mixmath", "task_type": "tts"} +{"index": 23, "question": "Please read the following math formula symbols: $|V(H_{vv_j,2})\\capV(H_{vw,1})|=0$", "audio_path": "audio/row_00787244_1755681621125249.wav", "formula": "$|V(H_{vv_j,2})\\capV(H_{vw,1})|=0$", "answer": "Absolute value of V of H sub vv sub j comma 2 intersect V of H sub v w comma 1 equals zero.", "subset": "mixmath", "task_type": "tts"} +{"index": 24, "question": "请你朗读以下数学公式符号:$\\left\\{ \\begin{array}{l} & a+b=4 \\\\ & ab=2 \\end{array} \\right.$", "audio_path": "audio/math_cbbbca3b-0ca5-4585-b972-3aed82443ed1.wav", "formula": "$\\left\\{ \\begin{array}{l} & a+b=4 \\\\ & ab=2 \\end{array} \\right.$", "answer": "a加b等于四和a乘b等于二", "subset": "mixmath", "task_type": "tts"} +{"index": 25, "question": "请你朗读以下数学公式符号:$(2){{10}^{n}}\\equiv {{4}^{n}}\\equiv {{4}^{1}}\\equiv 4\\left( mod6 \\right)$", "audio_path": "audio/math_21331375-89c2-4905-b91e-43405c17447a.wav", "formula": "$(2){{10}^{n}}\\equiv {{4}^{n}}\\equiv {{4}^{1}}\\equiv 4\\left( mod6 \\right)$", "answer": "二 十的n次方同余于四的n次方同余于四的一次方同余于四模六", "subset": "mixmath", "task_type": "tts"} +{"index": 26, "question": "请你朗读以下数学公式符号:$\\left\\{ \\begin{matrix} x=3 \\\\ y=4 \\end{matrix} \\right.$", "audio_path": "audio/math_7c820a21-3993-4e0e-8b82-11c0a0786f94.wav", "formula": "$\\left\\{ \\begin{matrix} x=3 \\\\ y=4 \\end{matrix} \\right.$", "answer": "x等于三,y等于四", "subset": "mixmath", "task_type": "tts"} +{"index": 27, "question": "Please read the following math formula symbols: $\\overline{\\mu}=\\sqrt{4\\pi}e^{-\\gamma_{E}/2}\\mu$", "audio_path": "audio/row_01264133_1755741303134712.wav", "formula": "$\\overline{\\mu}=\\sqrt{4\\pi}e^{-\\gamma_{E}/2}\\mu$", "answer": "mu bar equals square root of 4 pi times e to the power of negative gamma E divided by 2 times mu.", "subset": "mixmath", "task_type": "tts"} +{"index": 28, "question": "请你朗读以下数学公式符号:$36\\div \\left( 1+\\frac{1}{2} \\right)=36\\div \\frac{3}{2}=24$", "audio_path": "audio/math_338e803d-717b-4a8e-81f4-93a70c2c494e.wav", "formula": "$36\\div \\left( 1+\\frac{1}{2} \\right)=36\\div \\frac{3}{2}=24$", "answer": "三十六除以一加二分之一的和等于三十六除以二分之三等于二十四", "subset": "mixmath", "task_type": "tts"} +{"index": 29, "question": "请你朗读以下数学公式符号:$$\\frac{4}{11}+\\frac{8}{13}+\\frac{7}{11}+\\frac{3}{13}$$", "audio_path": "audio/math_18a0af06-d687-4296-a5f7-91f54a120f53.wav", "formula": "$$\\frac{4}{11}+\\frac{8}{13}+\\frac{7}{11}+\\frac{3}{13}$$", "answer": "十一分之四加十三分之八加十一分之七加十三分之三", "subset": "mixmath", "task_type": "tts"} +{"index": 30, "question": "请你朗读以下数学公式符号:$$\\left( \\frac{8}{2009}+\\frac{8}{2011} \\right)\\div \\left( \\frac{4}{2009}+\\frac{4}{2011} \\right)$$", "audio_path": "audio/math_4146b6d4-7801-44a5-b1aa-37c788a77d78.wav", "formula": "$$\\left( \\frac{8}{2009}+\\frac{8}{2011} \\right)\\div \\left( \\frac{4}{2009}+\\frac{4}{2011} \\right)$$", "answer": "二千零九分之八加二千零一十一分之八的和除以二千零九分之四加二千零一十一分之四的和", "subset": "mixmath", "task_type": "tts"} +{"index": 31, "question": "Please read the following math formula symbols: $S\\coloneqq\\{i_1,\\dots,i_m\\}\\subseteq[n]$", "audio_path": "audio/row_01475671_1755767892914560.wav", "formula": "$S\\coloneqq\\{i_1,\\dots,i_m\\}\\subseteq[n]$", "answer": "S is a subset of the set containing i sub 1, dot dot dot, i sub m, which is a subset of the interval from n.", "subset": "mixmath", "task_type": "tts"} +{"index": 32, "question": "请你朗读以下数学公式符号:$4500\\times 16\\times 5+7500\\times 6\\times 10=810000$", "audio_path": "audio/math_b0547635-6cb3-4e10-ac79-50867eff3623.wav", "formula": "$4500\\times 16\\times 5+7500\\times 6\\times 10=810000$", "answer": "四千五百乘十六乘五加七千五百乘六乘十等于八十一万", "subset": "mixmath", "task_type": "tts"} +{"index": 33, "question": "Please read the following math formula symbols: $\\alpha_1=r_1-r_2,\\alpha_2=r_2-r_3$", "audio_path": "audio/row_01482660_1755768763066817.wav", "formula": "$\\alpha_1=r_1-r_2,\\alpha_2=r_2-r_3$", "answer": "Alpha sub 1 equals r sub 1 minus r sub 2, alpha sub 2 equals r sub 2 minus r sub 3.", "subset": "mixmath", "task_type": "tts"} +{"index": 34, "question": "Please read the following math formula symbols: $\\cD_{\\text{val}}=\\{(\\Bx_n,y_n)\\}|_{n=1}^N$", "audio_path": "audio/row_01314314_1755747545288992.wav", "formula": "$\\cD_{\\text{val}}=\\{(\\Bx_n,y_n)\\}|_{n=1}^N$", "answer": "c D val equals the set of all tuples B x sub n comma y sub n, such that n equals 1 to N.", "subset": "mixmath", "task_type": "tts"} +{"index": 35, "question": "Please read the following math formula symbols: $-1+a\\lex\\le1-a$", "audio_path": "audio/row_00340013_1755626367156607.wav", "formula": "$-1+a\\lex\\le1-a$", "answer": "Negative one plus a is less than or equal to x, which is less than or equal to one minus a.", "subset": "mixmath", "task_type": "tts"} +{"index": 36, "question": "Please read the following math formula symbols: $\\bar{\\clV}(\\beta_{n,h})\\subseteq\\clV(\\beta_{n,h})$", "audio_path": "audio/row_01175659_1755730197417056.wav", "formula": "$\\bar{\\clV}(\\beta_{n,h})\\subseteq\\clV(\\beta_{n,h})$", "answer": "Bar L V of beta sub n comma h is a subset of L V of beta sub n comma h.", "subset": "mixmath", "task_type": "tts"} +{"index": 37, "question": "Please read the following math formula symbols: $tw_2+uv_1w_3-v_1w_1w_2-v_3w_2w_3$", "audio_path": "audio/row_01651990_1755790182240369.wav", "formula": "$tw_2+uv_1w_3-v_1w_1w_2-v_3w_2w_3$", "answer": "tw 2 plus u v 1 w 3 minus v 1 w 1 w 2 minus v 3 w 2 w 3", "subset": "mixmath", "task_type": "tts"} +{"index": 38, "question": "Please read the following math formula symbols: $\\epsilon+\\mathcal{O}(1/\\sqrt{\\min_{i\\in[K]}N_i})$", "audio_path": "audio/row_01778653_1755806178625172.wav", "formula": "$\\epsilon+\\mathcal{O}(1/\\sqrt{\\min_{i\\in[K]}N_i})$", "answer": "Epsilon plus big O of one over the square root of the minimum over i in the set of K of N sub i.", "subset": "mixmath", "task_type": "tts"} +{"index": 39, "question": "请你朗读以下数学公式符号:$$ {1}^{{3}}{=}{1}^{{2}}{,}{1}^{{3}}{+}{2}^{{3}}{=}{3}^{{2}}{,}{1}^{{3}}{+}{2}^{{3}}{+}{3}^{{3}}{=}{6}^{{2}}{,}{1}^{{3}}{+}{2}^{{3}}{+}{3}^{{3}}{+}{4}^{{3}}{=1}{0}^{{2}}{,{\\ldots}{\\ldots}{\\ldots}}$$", "audio_path": "audio/math_2bf4d167-b6c0-4e42-8ceb-81d9eb33ced9.wav", "formula": "$$ {1}^{{3}}{=}{1}^{{2}}{,}{1}^{{3}}{+}{2}^{{3}}{=}{3}^{{2}}{,}{1}^{{3}}{+}{2}^{{3}}{+}{3}^{{3}}{=}{6}^{{2}}{,}{1}^{{3}}{+}{2}^{{3}}{+}{3}^{{3}}{+}{4}^{{3}}{=1}{0}^{{2}}{,{\\ldots}{\\ldots}{\\ldots}}$$", "answer": "一的立方等于一的平方,一的立方加二的立方等于三的平方,一的立方加二的立方加三的立方等于六的平方,一的立方加二的立方加三的立方加四的立方等于十的平方,依此类推", "subset": "mixmath", "task_type": "tts"} +{"index": 40, "question": "Please read the following math formula symbols: $\\lbrace\\lbraceBCA\\rbrace,\\lbraceED\\rbrace,\\lbraceFG\\rbrace\\rbrace$", "audio_path": "audio/row_01121156_1755723338460376.wav", "formula": "$\\lbrace\\lbraceBCA\\rbrace,\\lbraceED\\rbrace,\\lbraceFG\\rbrace\\rbrace$", "answer": "Brace, left brace, B A, right brace, comma, left brace, E, right brace, comma, left brace, F, right brace, right brace.", "subset": "mixmath", "task_type": "tts"} +{"index": 41, "question": "Please read the following math formula symbols: $S_i=u_{i\\psi},u_{i\\psi+1},\\dots,u_{i\\psi+\\psi-1}$", "audio_path": "audio/row_01036795_1755712819999491.wav", "formula": "$S_i=u_{i\\psi},u_{i\\psi+1},\\dots,u_{i\\psi+\\psi-1}$", "answer": "S sub i equals u sub i psi, u sub i psi plus 1, dot dot dot, u sub i psi plus psi minus 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 42, "question": "Please read the following math formula symbols: $x\\mapsto\\int_{\\R^{p}}\\psi(x,y)dK(x,\\cdot)(y)$", "audio_path": "audio/row_00714708_1755672522916181.wav", "formula": "$x\\mapsto\\int_{\\R^{p}}\\psi(x,y)dK(x,\\cdot)(y)$", "answer": "x maps to the integral over R to the power of p of psi of x, y, d K of x, dot of y.", "subset": "mixmath", "task_type": "tts"} +{"index": 43, "question": "请你朗读以下数学公式符号:$$15.4\\times 99+15.4=15.4\\times \\left( 99{+}1 \\right)$$", "audio_path": "audio/math_b0bf843f-90d8-4b03-b292-d3b744447990.wav", "formula": "$$15.4\\times 99+15.4=15.4\\times \\left( 99{+}1 \\right)$$", "answer": "十五点四乘九十九加上十五点四等于十五点四乘九十九加一的和", "subset": "mixmath", "task_type": "tts"} +{"index": 44, "question": "Please read the following math formula symbols: $\\aPdown_1=\\aPdown_1(\\delta),\\aPup_1=\\aPup_1(\\delta)$", "audio_path": "audio/row_00633352_1755662458462164.wav", "formula": "$\\aPdown_1=\\aPdown_1(\\delta),\\aPup_1=\\aPup_1(\\delta)$", "answer": "The product of a P up 1 and a P up 1 equals the product of a P up 1 and a delta.", "subset": "mixmath", "task_type": "tts"} +{"index": 45, "question": "请你朗读以下数学公式符号:$$\\begin{cases}{{a}_{1}}x+{{b}_{1}}y={{c}_{1}} \\\\ {{a}_{2}}x+{{b}_{2}}y={{c}_{2}} \\\\ \\end{cases}$$", "audio_path": "audio/math_76522fe1-50ec-4810-9d9e-b252e96e48ae.wav", "formula": "$$\\begin{cases}{{a}_{1}}x+{{b}_{1}}y={{c}_{1}} \\\\ {{a}_{2}}x+{{b}_{2}}y={{c}_{2}} \\\\ \\end{cases}$$", "answer": "a 一 x 加 b 一 y等于 c 一,a 二 x 加 b 二 y 等于 c 二。", "subset": "mixmath", "task_type": "tts"} +{"index": 46, "question": "Please read the following math formula symbols: $(QB^{(1)},\\ldots,QB^{(p)})$", "audio_path": "audio/row_01976632_1755831178258751.wav", "formula": "$(QB^{(1)},\\ldots,QB^{(p)})$", "answer": "Open parenthesis, Q B raised to the power of 1, comma, ellipsis, Q B raised to the power of p, close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 47, "question": "Please read the following math formula symbols: $|\\sum_{j\\inS^+}\\langles_j\\rangle\\mathbf{F}_j|$", "audio_path": "audio/row_01404263_1755758865063497.wav", "formula": "$|\\sum_{j\\inS^+}\\langles_j\\rangle\\mathbf{F}_j|$", "answer": "Absolute value of the sum over j in S plus of the inner product of s sub j and F sub j.", "subset": "mixmath", "task_type": "tts"} +{"index": 48, "question": "请你朗读以下数学公式符号:$\\frac{4}{3} \\pi {{r}^{2}}h\\div \\frac{2}{3} \\pi {{r}^{2}}h=2:1$", "audio_path": "audio/math_d064f6c9-30b3-48d5-b4ff-6c32c3fa1ff0.wav", "formula": "$\\frac{4}{3} \\pi {{r}^{2}}h\\div \\frac{2}{3} \\pi {{r}^{2}}h=2:1$", "answer": "三分之四 pi乘 r的平方 h 除以 三分之二 pi 乘r的平方 h 等于 二比一", "subset": "mixmath", "task_type": "tts"} +{"index": 49, "question": "请你朗读以下数学公式符号:${{x}^{4}}+{{x}^{2}}+a={{x}^{4}}+(b+m){{x}^{3}}+(c+bm+n){{x}^{2}}+(mc+bn)x+nc$", "audio_path": "audio/math_035780c2-ad47-46fa-b84a-7a74a8480076.wav", "formula": "${{x}^{4}}+{{x}^{2}}+a={{x}^{4}}+(b+m){{x}^{3}}+(c+bm+n){{x}^{2}}+(mc+bn)x+nc$", "answer": "x的四次方加x的平方加a等于x的四次方加上 b加m的和乘x的三次方加上 c加b m加n的和乘x的平方加上 m c加b n的和乘x加n c", "subset": "mixmath", "task_type": "tts"} +{"index": 50, "question": "请你朗读以下数学公式符号:$$102 \\times 45 = (100 + 2) \\times 45 = 100 \\times 45 + 2\\times 45 = 4500 + 90 = 4590$$", "audio_path": "audio/math_a1ce705b-1639-4bdf-96a0-c06e5d4e34a9.wav", "formula": "$$102 \\times 45 = (100 + 2) \\times 45 = 100 \\times 45 + 2\\times 45 = 4500 + 90 = 4590$$", "answer": "一百零二乘四十五等于一百加二的和乘四十五等于一百乘四十五加二乘四十五等于四千五百加九十等于四千五百九十", "subset": "mixmath", "task_type": "tts"} +{"index": 51, "question": "Please read the following math formula symbols: $\\zeta(z)=\\frac{\\eta_{\\tau_1}}{\\tau_1}z+\\varphi_1(z)$", "audio_path": "audio/row_01587791_1755782079838521.wav", "formula": "$\\zeta(z)=\\frac{\\eta_{\\tau_1}}{\\tau_1}z+\\varphi_1(z)$", "answer": "zeta of z equals eta sub tau sub 1 divided by tau sub 1 z plus phi sub 1 of z.", "subset": "mixmath", "task_type": "tts"} +{"index": 52, "question": "Please read the following math formula symbols: $\\mathop{\\max}_{a_j^{'}}Q_j()$", "audio_path": "audio/row_00221032_1755611893939884.wav", "formula": "$\\mathop{\\max}_{a_j^{'}}Q_j()$", "answer": "The maximum of Q sub j, with respect to a prime sub j, where Q sub j is a function of empty parentheses.", "subset": "mixmath", "task_type": "tts"} +{"index": 53, "question": "请你朗读以下数学公式符号:$$40\\times 30\\times 10=12000\\left( {c}{{{m}}^{3}} \\right)$$", "audio_path": "audio/math_f9384937-6faf-49af-9174-9e55f9aeca3e.wav", "formula": "$$40\\times 30\\times 10=12000\\left( {c}{{{m}}^{3}} \\right)$$", "answer": "四十乘三十乘十等于一万二千立方厘米", "subset": "mixmath", "task_type": "tts"} +{"index": 54, "question": "请你朗读以下数学公式符号:$3 \\div \\frac{a}{b}=3 \\times \\frac{7}{2}= \\frac{21}{2}$", "audio_path": "audio/math_0d7e8860-4348-4a3c-9f29-90d8a46a035b.wav", "formula": "$3 \\div \\frac{a}{b}=3 \\times \\frac{7}{2}= \\frac{21}{2}$", "answer": "三除以b分之a等于三乘二分之七等于二分之二十一", "subset": "mixmath", "task_type": "tts"} +{"index": 55, "question": "Please read the following math formula symbols: $\\rmM_{halo}=\\frac{v_{rot}^{3}}{10GH(\\it{z})}$", "audio_path": "audio/row_01966066_1755829869908196.wav", "formula": "$\\rmM_{halo}=\\frac{v_{rot}^{3}}{10GH(\\it{z})}$", "answer": "The M subscript o is equal to the fraction v subscript rot cubed divided by 10 times G times M subscript z.", "subset": "mixmath", "task_type": "tts"} +{"index": 56, "question": "Please read the following math formula symbols: $$|x|^{\\gamma}v_{xx}+v_{yy}=0\\quad\\text{in}B_1$$", "audio_path": "audio/row_00924687_1755698859472170.wav", "formula": "$$|x|^{\\gamma}v_{xx}+v_{yy}=0\\quad\\text{in}B_1$$", "answer": "Absolute value of x raised to the power of gamma times v sub x plus v sub y y equals zero, belonging to B sub one.", "subset": "mixmath", "task_type": "tts"} +{"index": 57, "question": "请你朗读以下数学公式符号:${{9}^{x}}\\cdot {{27}^{y}}={{3}^{2x}}\\cdot {{3}^{3y}}={{3}^{2x+3y}}$", "audio_path": "audio/math_04619ab4-fef1-4a6c-815a-63bc5d59dde2.wav", "formula": "${{9}^{x}}\\cdot {{27}^{y}}={{3}^{2x}}\\cdot {{3}^{3y}}={{3}^{2x+3y}}$", "answer": "九的x次方乘二十七的y次方等于三的二x次方乘三的三y次方等于三的二x加三y次方", "subset": "mixmath", "task_type": "tts"} +{"index": 58, "question": "请你朗读以下数学公式符号:$S=\\left(49\\times 52\\times 55+1\\times 4\\times2\\right)\\div 9=15572$", "audio_path": "audio/math_393260da-84ed-4e85-be92-8efe219c9547.wav", "formula": "$S=\\left(49\\times 52\\times 55+1\\times 4\\times2\\right)\\div 9=15572$", "answer": "S等于 四十九乘五十二乘五十五 加 一乘四乘二 的和,除以九等于一万五千五百七十二", "subset": "mixmath", "task_type": "tts"} +{"index": 59, "question": "请你朗读以下数学公式符号:$3\\div 7=0.\\overset{\\cdot }{\\mathop{4}}\\,2857\\overset{\\cdot }{\\mathop{1}}\\,$", "audio_path": "audio/math_29d46583-5c96-44cc-b7bc-6218c9d764d1.wav", "formula": "$3\\div 7=0.\\overset{\\cdot }{\\mathop{4}}\\,2857\\overset{\\cdot }{\\mathop{1}}\\,$", "answer": "三除以七等于零点四二八五七一 四二八五七一循环", "subset": "mixmath", "task_type": "tts"} +{"index": 60, "question": "Please read the following math formula symbols: $T^{p2}[S^3\\backslashK]$", "audio_path": "audio/row_01355539_1755752732496914.wav", "formula": "$T^{p2}[S^3\\backslashK]$", "answer": "T raised to the power of p 2, open square bracket, S raised to the power of 3 backslash K, close square bracket.", "subset": "mixmath", "task_type": "tts"} +{"index": 61, "question": "Please read the following math formula symbols: $|\\tilde{\\psi}_i|^2=O(N^{-1})$", "audio_path": "audio/row_02010733_1755835503739343.wav", "formula": "$|\\tilde{\\psi}_i|^2=O(N^{-1})$", "answer": "The absolute value of the tilde psi sub i squared equals big O of N to the power of negative one.", "subset": "mixmath", "task_type": "tts"} +{"index": 62, "question": "请你朗读以下数学公式符号:$\\frac{2}{3}\\times \\frac{3}{5}\\times \\frac{1}{2}=\\frac{1}{5}$", "audio_path": "audio/math_b350fd2e-a8ea-46c6-9112-a7f4d4106b2f.wav", "formula": "$\\frac{2}{3}\\times \\frac{3}{5}\\times \\frac{1}{2}=\\frac{1}{5}$", "answer": "三分之二乘五分之三乘二分之一等于五分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 63, "question": "Please read the following math formula symbols: $q_n:=f_n|_{(0,\\infty)^n}$", "audio_path": "audio/row_00156931_1755604079864691.wav", "formula": "$q_n:=f_n|_{(0,\\infty)^n}$", "answer": "q sub n is defined as f sub n restricted to the interval from 0 to infinity raised to the power of n.", "subset": "mixmath", "task_type": "tts"} +{"index": 64, "question": "请你朗读以下数学公式符号:$$\\frac{30}{\\pi \\times {{15}^{2}}}:\\frac{40}{\\pi \\times {{20}^{2}}}=\\frac{4}{3}>1$$", "audio_path": "audio/math_386d1285-f4a4-4e26-ad1f-f88a7cd35a9b.wav", "formula": "$$\\frac{30}{\\pi \\times {{15}^{2}}}:\\frac{40}{\\pi \\times {{20}^{2}}}=\\frac{4}{3}>1$$", "answer": "pi乘十五的平方的积分之三十 比pi乘二十的平方的积分之四十 等于三分之四 大于一", "subset": "mixmath", "task_type": "tts"} +{"index": 65, "question": "Please read the following math formula symbols: $\\left\\lvertf(z)\\right\\rvert\\leC\\left\\lvertg(z)\\right\\rvert$", "audio_path": "audio/row_01567771_1755779534442555.wav", "formula": "$\\left\\lvertf(z)\\right\\rvert\\leC\\left\\lvertg(z)\\right\\rvert$", "answer": "The absolute value of f of z is less than or equal to C times the absolute value of g of z.", "subset": "mixmath", "task_type": "tts"} +{"index": 66, "question": "Please read the following math formula symbols: $$\\Omega^*(M)=\\bigoplus_{k\\geq0}\\Omega^{k}(M)$$", "audio_path": "audio/row_00854504_1755690056480983.wav", "formula": "$$\\Omega^*(M)=\\bigoplus_{k\\geq0}\\Omega^{k}(M)$$", "answer": "Omega raised to the star, M, equals the direct sum over k greater than or equal to zero of Omega raised to the k, M.", "subset": "mixmath", "task_type": "tts"} +{"index": 67, "question": "请你朗读以下数学公式符号:$\\frac78\\times\\left(\\frac35\\times\\frac59\\right)=\\left(\\frac78\\times\\frac35\\right)\\times\\frac59$", "audio_path": "audio/math_d48cc0d7-8c1c-40a0-bb8d-7dbf723d32aa.wav", "formula": "$\\frac78\\times\\left(\\frac35\\times\\frac59\\right)=\\left(\\frac78\\times\\frac35\\right)\\times\\frac59$", "answer": "八分之七乘 五分之三乘九分之五的积等于八分之七乘五分之三的积乘九分之五", "subset": "mixmath", "task_type": "tts"} +{"index": 68, "question": "Please read the following math formula symbols: $\\pi(f_d,g_d)_{i,j}(d=0,1,\\ldots,D)$", "audio_path": "audio/row_00775005_1755680064896901.wav", "formula": "$\\pi(f_d,g_d)_{i,j}(d=0,1,\\ldots,D)$", "answer": "Pi of f sub d, g sub d, sub i, j, open parenthesis, d equals 0, 1, ellipsis, D, close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 69, "question": "请你朗读以下数学公式符号:$192\\div 2\\times 0.5+192\\div 2\\times 0.5\\times 80\\%=86.4$", "audio_path": "audio/math_65d1b4c2-b27a-4d7d-8b6b-7bfce271d0ac.wav", "formula": "$192\\div 2\\times 0.5+192\\div 2\\times 0.5\\times 80\\%=86.4$", "answer": "一百九十二除以二乘零点五加一百九十二除以二乘零点五乘百分之八十等于八十六点四", "subset": "mixmath", "task_type": "tts"} +{"index": 70, "question": "Please read the following math formula symbols: $\\frac{a_y}{a}=[\\lna]^{(0,1)}$", "audio_path": "audio/row_01231313_1755737193822173.wav", "formula": "$\\frac{a_y}{a}=[\\lna]^{(0,1)}$", "answer": "The fraction a sub y divided by a is equal to the natural logarithm of a raised to the power of 0 comma 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 71, "question": "请你朗读以下数学公式符号:$$(2+1)\\left( {{2}^{2}}+1 \\right)\\left( {{2}^{4}}+1 \\right)\\left( {{2}^{8}}+1 \\right)=$$", "audio_path": "audio/math_61a69261-c353-4e15-9786-069313276f32.wav", "formula": "$$(2+1)\\left( {{2}^{2}}+1 \\right)\\left( {{2}^{4}}+1 \\right)\\left( {{2}^{8}}+1 \\right)=$$", "answer": "二加一的和乘二的平方加一的和乘二的四次方加一的和乘二的八次方加一的和等于", "subset": "mixmath", "task_type": "tts"} +{"index": 72, "question": "请你朗读以下数学公式符号:$\\frac{1}{5}:\\frac{1}{4}=\\frac{40}{\\left( 50 \\right)}=$", "audio_path": "audio/math_5c06fe46-8a01-407c-955b-9c802d4374eb.wav", "formula": "$\\frac{1}{5}:\\frac{1}{4}=\\frac{40}{\\left( 50 \\right)}=$", "answer": "五分之一比四分之一等于五十分之四十等于", "subset": "mixmath", "task_type": "tts"} +{"index": 73, "question": "Please read the following math formula symbols: $f=a_1x_1+\\cdots+a_dx_d\\inR^{\\pm}$", "audio_path": "audio/row_01156906_1755727844789041.wav", "formula": "$f=a_1x_1+\\cdots+a_dx_d\\inR^{\\pm}$", "answer": "f equals a sub 1 x sub 1 plus dot dot dot plus a sub d x sub d in R to the plus or minus.", "subset": "mixmath", "task_type": "tts"} +{"index": 74, "question": "请你朗读以下数学公式符号:$2\\left( a+b \\right)=2\\left( 5\\sqrt{3}+\\sqrt{3} \\right)=10\\sqrt{3}+2\\sqrt{3}=12\\sqrt{3}$", "audio_path": "audio/math_5c2d90f4-ff15-45e6-b619-ef101f735e72.wav", "formula": "$2\\left( a+b \\right)=2\\left( 5\\sqrt{3}+\\sqrt{3} \\right)=10\\sqrt{3}+2\\sqrt{3}=12\\sqrt{3}$", "answer": "二乘 a加b的和 等于二乘 五倍的根号三加根号三的和 等于十倍的根号三加二倍的根号三等于十二倍的根号三", "subset": "mixmath", "task_type": "tts"} +{"index": 75, "question": "请你朗读以下数学公式符号:$$\\begin{eqnarray}&&21.9+9.8+8.9\\\\ &=&31.7+8.9\\\\ &=&40.6\\end{eqnarray}$$", "audio_path": "audio/math_9963a258-6251-4d2c-9a94-c5d78411a655.wav", "formula": "$$\\begin{eqnarray}&&21.9+9.8+8.9\\\\ &=&31.7+8.9\\\\ &=&40.6\\end{eqnarray}$$", "answer": "二十一点九加九点八加八点九等于三十一点七加八点九等于四十点六", "subset": "mixmath", "task_type": "tts"} +{"index": 76, "question": "请你朗读以下数学公式符号:$$ \\left\\{\\begin{array}{c}5x+6y=16\\\\ 4x+y=5y+x\\end{array}\\right.$$", "audio_path": "audio/math_a7d8eaf5-c818-4f72-9697-08e615b8fb19.wav", "formula": "$$ \\left\\{\\begin{array}{c}5x+6y=16\\\\ 4x+y=5y+x\\end{array}\\right.$$", "answer": "五x加六y等于十六和四x加y等于五y加x", "subset": "mixmath", "task_type": "tts"} +{"index": 77, "question": "请你朗读以下数学公式符号:$\\left[ \\frac{1}{3}\\pi \\times {{\\left( 3r \\right)}^{2}}\\times h \\right]\\div \\left[ \\pi \\times {{\\left( 4r \\right)}^{2}}\\times h \\right]$", "audio_path": "audio/math_11171eba-b2d1-4f08-9c9c-0bd7a04daaf8.wav", "formula": "$\\left[ \\frac{1}{3}\\pi \\times {{\\left( 3r \\right)}^{2}}\\times h \\right]\\div \\left[ \\pi \\times {{\\left( 4r \\right)}^{2}}\\times h \\right]$", "answer": "三分之一pi乘三r的平方乘h 的积,除以 pi乘四r的平方乘h 的积", "subset": "mixmath", "task_type": "tts"} +{"index": 78, "question": "请你朗读以下数学公式符号:$2B=\\frac{3333332}{6666665}\\times 2=\\frac{6666664}{6666665}$", "audio_path": "audio/math_61322237-770c-4df7-9834-0bdf034df2ac.wav", "formula": "$2B=\\frac{3333332}{6666665}\\times 2=\\frac{6666664}{6666665}$", "answer": "二B等于六百六十六万六千六百六十五分之三百三十三万三千三百三十二,再乘二,等于六百六十六万六千六百六十五分之六百六十六万六千六百六十四", "subset": "mixmath", "task_type": "tts"} +{"index": 79, "question": "请你朗读以下数学公式符号:$\\frac{1}{2}+\\frac{1}{4}+\\frac{1}{8}+\\frac{1}{16}+\\frac{1}{32}=$", "audio_path": "audio/math_b021cbcc-c35d-46fe-af80-157b6ec551a4.wav", "formula": "$\\frac{1}{2}+\\frac{1}{4}+\\frac{1}{8}+\\frac{1}{16}+\\frac{1}{32}=$", "answer": "二分之一加四分之一加八分之一加十六分之一加三十二分之一等于", "subset": "mixmath", "task_type": "tts"} +{"index": 80, "question": "Please read the following math formula symbols: $A=\\sum_{k\\in[m]}y_kA_k$", "audio_path": "audio/row_00271633_1755618052503771.wav", "formula": "$A=\\sum_{k\\in[m]}y_kA_k$", "answer": "A equals the sum over k in the set from 1 to m of y sub k times A sub k.", "subset": "mixmath", "task_type": "tts"} +{"index": 81, "question": "Please read the following math formula symbols: $\\mathbf{v}_{DD}(k+Kl)=Z_v[k,l]$", "audio_path": "audio/row_00813016_1755684848192484.wav", "formula": "$\\mathbf{v}_{DD}(k+Kl)=Z_v[k,l]$", "answer": "The vector v sub D S of k plus K times l equals Z sub v open square bracket k comma l close square bracket.", "subset": "mixmath", "task_type": "tts"} +{"index": 82, "question": "请你朗读以下数学公式符号:$$\\dfrac{2}{3}\\times\\dfrac{7}{8}\\times\\dfrac{3}{2}=\\dfrac{2}{3}\\times\\dfrac{3}{2}\\times\\dfrac{7}{8}=1\\times\\dfrac{7}{8}=\\dfrac{7}{8}$$", "audio_path": "audio/math_5edaa1ed-32ae-445d-a0a9-c163e9bd8464.wav", "formula": "$$\\dfrac{2}{3}\\times\\dfrac{7}{8}\\times\\dfrac{3}{2}=\\dfrac{2}{3}\\times\\dfrac{3}{2}\\times\\dfrac{7}{8}=1\\times\\dfrac{7}{8}=\\dfrac{7}{8}$$", "answer": "三分之二乘八分之七乘二分之三等于三分之二乘二分之三乘八分之七等于一乘八分之七等于八分之七", "subset": "mixmath", "task_type": "tts"} +{"index": 83, "question": "请你朗读以下数学公式符号:$72\\div 4\\times \\frac{5}{9}=18\\times \\frac{5}{9}=10$", "audio_path": "audio/math_8b9a6f56-9033-4597-ac6c-5221b3c2f591.wav", "formula": "$72\\div 4\\times \\frac{5}{9}=18\\times \\frac{5}{9}=10$", "answer": "七十二除以四乘九分之五等于十八乘九分之五等于十", "subset": "mixmath", "task_type": "tts"} +{"index": 84, "question": "请你朗读以下数学公式符号:$\\sqrt{4{{y}^{2}}+12xy+9{{x}^{2}}}=\\sqrt{{{(2y+3x)}^{2}}}$", "audio_path": "audio/math_d49a167b-27f4-44fd-a43c-381a08fab075.wav", "formula": "$\\sqrt{4{{y}^{2}}+12xy+9{{x}^{2}}}=\\sqrt{{{(2y+3x)}^{2}}}$", "answer": "根号下 四 y平方加十二 x y 加九 x平方 等于 根号下 二y 加 三 x和 的平方", "subset": "mixmath", "task_type": "tts"} +{"index": 85, "question": "Please read the following math formula symbols: $X(G_n,\\alpha_n)/X(G_n/N_n,\\tilde\\alpha_n)$", "audio_path": "audio/row_01551661_1755777477995670.wav", "formula": "$X(G_n,\\alpha_n)/X(G_n/N_n,\\tilde\\alpha_n)$", "answer": "X of G sub n, alpha sub n divided by X of G sub n divided by N, tilde alpha sub n.", "subset": "mixmath", "task_type": "tts"} +{"index": 86, "question": "Please read the following math formula symbols: $\\R_+\\coloneqq\\{x\\in\\R:x\\geq0\\}$", "audio_path": "audio/row_00065542_1755593054026961.wav", "formula": "$\\R_+\\coloneqq\\{x\\in\\R:x\\geq0\\}$", "answer": "R plus is defined as the set of all x in R such that x is greater than or equal to zero.", "subset": "mixmath", "task_type": "tts"} +{"index": 87, "question": "请你朗读以下数学公式符号:$\\left\\{ \\begin{matrix} 5000x+100y=18000 \\\\ 10x+y=84 \\\\\\end{matrix} \\right.$", "audio_path": "audio/math_8d078479-f2d8-4a7a-97ef-255172e18ef6.wav", "formula": "$\\left\\{ \\begin{matrix} 5000x+100y=18000 \\\\ 10x+y=84 \\\\\\end{matrix} \\right.$", "answer": "五千x加一百y等于一万八千,十x加y等于八十四", "subset": "mixmath", "task_type": "tts"} +{"index": 88, "question": "请你朗读以下数学公式符号:$$\\frac{3}{5}\\times \\frac{1}{4}+ \\frac{9}{5}\\div 4=$$", "audio_path": "audio/math_d0e498b0-9411-4fc0-9386-f8891be89dd9.wav", "formula": "$$\\frac{3}{5}\\times \\frac{1}{4}+ \\frac{9}{5}\\div 4=$$", "answer": "五分之三乘四分之一加五分之九除以四等于", "subset": "mixmath", "task_type": "tts"} +{"index": 89, "question": "请你朗读以下数学公式符号:$\\frac{6}{7}=\\frac{6\\times 9}{7\\times 9}=\\frac{54}{63}$", "audio_path": "audio/math_a650f3a0-28b9-426d-bc1b-803d9c054ba2.wav", "formula": "$\\frac{6}{7}=\\frac{6\\times 9}{7\\times 9}=\\frac{54}{63}$", "answer": "七分之六等于七乘九的积分之六乘九的积等于六十三分之五十四", "subset": "mixmath", "task_type": "tts"} +{"index": 90, "question": "Please read the following math formula symbols: $|A^m\\capV(\\overline{K})|^\\ell$", "audio_path": "audio/row_01486639_1755769264179443.wav", "formula": "$|A^m\\capV(\\overline{K})|^\\ell$", "answer": "Absolute value of A to the power of m intersect V of K bar, all raised to the power of ell.", "subset": "mixmath", "task_type": "tts"} +{"index": 91, "question": "请你朗读以下数学公式符号:$1101{{}_{2}}\\times 101{{}_{2}}={{\\left( 1000001 \\right)}_{2}}$", "audio_path": "audio/math_db997ba3-c33a-4af3-b9d2-eccbff2b289d.wav", "formula": "$1101{{}_{2}}\\times 101{{}_{2}}={{\\left( 1000001 \\right)}_{2}}$", "answer": "二进制 一一零一 乘 二进制 一零一等于 二进制 一零零零零零一", "subset": "mixmath", "task_type": "tts"} +{"index": 92, "question": "Please read the following math formula symbols: $K=-\\dot{\\nu}(t_1)/\\nu(t_1)^n$", "audio_path": "audio/row_01070022_1755716974388128.wav", "formula": "$K=-\\dot{\\nu}(t_1)/\\nu(t_1)^n$", "answer": "K equals negative the derivative of nu with respect to t sub 1 divided by nu times t sub 1 raised to the power of n.", "subset": "mixmath", "task_type": "tts"} +{"index": 93, "question": "请你朗读以下数学公式符号:$\\left( 1+\\frac{1}{9} \\right)=\\frac{10}{9}\\left( {{{m}}^{3}} \\right)$", "audio_path": "audio/math_4d696bb1-acc3-41ad-9a15-beebf250fc8c.wav", "formula": "$\\left( 1+\\frac{1}{9} \\right)=\\frac{10}{9}\\left( {{{m}}^{3}} \\right)$", "answer": "一与九分之一的和等于九分之十立方米", "subset": "mixmath", "task_type": "tts"} +{"index": 94, "question": "Please read the following math formula symbols: $F(t_1,t_2)\\simK\\delta(t_1-t_2)$", "audio_path": "audio/row_00713750_1755672417663824.wav", "formula": "$F(t_1,t_2)\\simK\\delta(t_1-t_2)$", "answer": "F of t sub 1, t sub 2 is approximately equal to K delta of t sub 1 minus t sub 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 95, "question": "Please read the following math formula symbols: $\\tau(H)/|V(H)|\\in(0,1)$", "audio_path": "audio/row_01054530_1755715052719946.wav", "formula": "$\\tau(H)/|V(H)|\\in(0,1)$", "answer": "Tau of H divided by the absolute value of V of H, belongs to the open interval from 0 to 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 96, "question": "Please read the following math formula symbols: $Re_{b}l/(2L_{3})=\\rho_{f}u_{b}l/\\mu_{f}=600$", "audio_path": "audio/row_00933509_1755699943408640.wav", "formula": "$Re_{b}l/(2L_{3})=\\rho_{f}u_{b}l/\\mu_{f}=600$", "answer": "Re sub b l divided by 2 L sub 3 equals rho sub f u sub b l divided by mu sub f equals 600", "subset": "mixmath", "task_type": "tts"} +{"index": 97, "question": "请你朗读以下数学公式符号:$$=\\frac{79}{8}\\div \\left( \\frac{79}{8}+\\frac{2014\\times 2015+1}{2015+{{2014}^{2}}} \\right)$$", "audio_path": "audio/math_634e5d3d-b7bd-4c98-b8f4-e7155582f242.wav", "formula": "$$=\\frac{79}{8}\\div \\left( \\frac{79}{8}+\\frac{2014\\times 2015+1}{2015+{{2014}^{2}}} \\right)$$", "answer": "等于八分之七十九除以 括号八分之七十九 加上两千零一十五加两千零一十四的平方的和分之两千零一十四乘两千零一十五加一 的和括号", "subset": "mixmath", "task_type": "tts"} +{"index": 98, "question": "请你朗读以下数学公式符号:$\\left[ 45,60 \\right]=5\\times {{3}^{2}}\\times {{2}^{2}}=180$", "audio_path": "audio/math_e0304dc3-ce49-4328-8f5d-02329603e9fe.wav", "formula": "$\\left[ 45,60 \\right]=5\\times {{3}^{2}}\\times {{2}^{2}}=180$", "answer": "中括号四十五,六十中括号等于五乘三的平方乘二的平方等于一百八十", "subset": "mixmath", "task_type": "tts"} +{"index": 99, "question": "Please read the following math formula symbols: $F=e^{-iEr},G=ie^{-iEr}$", "audio_path": "audio/row_01699819_1755796200092087.wav", "formula": "$F=e^{-iEr},G=ie^{-iEr}$", "answer": "F equals e to the power of negative i E, G equals i e to the power of negative i E.", "subset": "mixmath", "task_type": "tts"} +{"index": 100, "question": "Please read the following math formula symbols: $(t,s)\\rightarrowe^{i(nt+ms)}$", "audio_path": "audio/row_00385528_1755631913824978.wav", "formula": "$(t,s)\\rightarrowe^{i(nt+ms)}$", "answer": "The function of t and s maps to the exponential of i times the quantity of n times t plus m times s.", "subset": "mixmath", "task_type": "tts"} +{"index": 101, "question": "Please read the following math formula symbols: $s_j\\simc_2|j|^{2/N}$", "audio_path": "audio/row_01676926_1755793312733447.wav", "formula": "$s_j\\simc_2|j|^{2/N}$", "answer": "s sub j is approximately c sub 2 times the absolute value of j raised to the power of 2 divided by N.", "subset": "mixmath", "task_type": "tts"} +{"index": 102, "question": "Please read the following math formula symbols: $\\kappa_1=\\frac{R_0\\sqrt{R_0^2-r_U^2}}{\\ellL}$", "audio_path": "audio/row_01436556_1755762945952492.wav", "formula": "$\\kappa_1=\\frac{R_0\\sqrt{R_0^2-r_U^2}}{\\ellL}$", "answer": "Kappa sub 1 equals R sub 0 square root of R sub 0 squared minus r sub U squared divided by ell L.", "subset": "mixmath", "task_type": "tts"} +{"index": 103, "question": "Please read the following math formula symbols: $\\ones{\\strl{x}^1}\\in[n/12,n/6]$", "audio_path": "audio/row_00560443_1755653346593718.wav", "formula": "$\\ones{\\strl{x}^1}\\in[n/12,n/6]$", "answer": "For all x to the power of 1, belonging to the interval from n divided by 12, to n divided by 6.", "subset": "mixmath", "task_type": "tts"} +{"index": 104, "question": "Please read the following math formula symbols: $t_{\\rmsoft}T\\sim1/\\alpha_s\\log\\alpha_s^{-1}$", "audio_path": "audio/row_01223408_1755736193922863.wav", "formula": "$t_{\\rmsoft}T\\sim1/\\alpha_s\\log\\alpha_s^{-1}$", "answer": "t sub soft T is approximately equal to one divided by alpha sub s log alpha sub s to the power of negative one.", "subset": "mixmath", "task_type": "tts"} +{"index": 105, "question": "请你朗读以下数学公式符号:$$=(2.5\\times 0.4)\\times (0.2\\times 5)\\times (0.8\\times 1.25)$$", "audio_path": "audio/math_97a330a7-f298-48fa-a692-0c0d366d5731.wav", "formula": "$$=(2.5\\times 0.4)\\times (0.2\\times 5)\\times (0.8\\times 1.25)$$", "answer": "等于 二点五乘零点四的积 乘 零点二乘五的积 乘 零点八乘一点二五的积", "subset": "mixmath", "task_type": "tts"} +{"index": 106, "question": "Please read the following math formula symbols: $V=(x_V,y_V,z_V)\\in\\mathcal{Z}(g)$", "audio_path": "audio/row_00931022_1755699638152588.wav", "formula": "$V=(x_V,y_V,z_V)\\in\\mathcal{Z}(g)$", "answer": "V equals open parenthesis x sub V, y sub V, z sub V close parenthesis belongs to script Z of g.", "subset": "mixmath", "task_type": "tts"} +{"index": 107, "question": "Please read the following math formula symbols: $\\card(A+A)\\leq2^{d}(2-\\epsilon)\\cardA$", "audio_path": "audio/row_00856503_1755690309510349.wav", "formula": "$\\card(A+A)\\leq2^{d}(2-\\epsilon)\\cardA$", "answer": "Card of A plus A is less than or equal to 2 to the power of d times 2 minus epsilon times cardinality of A.", "subset": "mixmath", "task_type": "tts"} +{"index": 108, "question": "Please read the following math formula symbols: $y\\in\\varepsilonR_z(\\mathbb\\Z+\\frac12)^d$", "audio_path": "audio/row_00661855_1755665983075784.wav", "formula": "$y\\in\\varepsilonR_z(\\mathbb\\Z+\\frac12)^d$", "answer": "y belongs to the set of epsilon R sub z, open parenthesis, Z plus twelve, close parenthesis, raised to the power of d.", "subset": "mixmath", "task_type": "tts"} +{"index": 109, "question": "请你朗读以下数学公式符号:$\\overline{ab}=7\\left( a+b \\right)\\Rightarrow 10a+b=7a+7b$", "audio_path": "audio/math_6c949e2a-7ad1-4236-a0cb-774a0c2cc1eb.wav", "formula": "$\\overline{ab}=7\\left( a+b \\right)\\Rightarrow 10a+b=7a+7b$", "answer": "两位数ab等于七乘a加b的和推出十a加b等于七a加七b", "subset": "mixmath", "task_type": "tts"} +{"index": 110, "question": "Please read the following math formula symbols: $E\\coloneqq\\{x\\in\\mathbb{R}\\colong(x)=h(x)\\}$", "audio_path": "audio/row_01563384_1755778975321086.wav", "formula": "$E\\coloneqq\\{x\\in\\mathbb{R}\\colong(x)=h(x)\\}$", "answer": "E is defined as the set of x in the real numbers such that g of x equals h of x.", "subset": "mixmath", "task_type": "tts"} +{"index": 111, "question": "Please read the following math formula symbols: $\\mathcal{V}(x+y)\\leq\\mathcal{V}(x)+\\mathcal{V}(y)$", "audio_path": "audio/row_00936391_1755700308389491.wav", "formula": "$\\mathcal{V}(x+y)\\leq\\mathcal{V}(x)+\\mathcal{V}(y)$", "answer": "Mathcal V of x plus y is less than or equal to Mathcal V of x plus Mathcal V of y.", "subset": "mixmath", "task_type": "tts"} +{"index": 112, "question": "请你朗读以下数学公式符号:$\\frac{1}{6}<{}\\frac{7}{18}<{}\\frac{4}{9}<{}\\frac{1}{2}<{}\\frac{2}{3}$", "audio_path": "audio/math_e00a3bbc-14aa-4a96-b2ff-8294ab23849f.wav", "formula": "$\\frac{1}{6}<{}\\frac{7}{18}<{}\\frac{4}{9}<{}\\frac{1}{2}<{}\\frac{2}{3}$", "answer": "六分之一小于十八分之七小于九分之四小于二分之一小于三分之二", "subset": "mixmath", "task_type": "tts"} +{"index": 113, "question": "请你朗读以下数学公式符号:$85+85\\times 1\\%\\times 28=85\\times (1+1\\%\\times 28)=108.8$", "audio_path": "audio/math_d237e63e-1a67-4c8e-a4b4-1be8bc41bdcd.wav", "formula": "$85+85\\times 1\\%\\times 28=85\\times (1+1\\%\\times 28)=108.8$", "answer": "八十五加八十五乘百分之一乘二十八等于八十五乘一加百分之一乘二十八的积的和等于一百零八点八", "subset": "mixmath", "task_type": "tts"} +{"index": 114, "question": "Please read the following math formula symbols: $\\sum_{j'\\in\\cN_i}x_{i,j'}\\leb_i$", "audio_path": "audio/row_01635505_1755788098391924.wav", "formula": "$\\sum_{j'\\in\\cN_i}x_{i,j'}\\leb_i$", "answer": "Sum over j prime in the set of cN sub i, x sub i, j prime, is less than or equal to b sub i.", "subset": "mixmath", "task_type": "tts"} +{"index": 115, "question": "Please read the following math formula symbols: $\\mu_1(\\omega)\\geq\\mu_2(\\omega)\\geq...>0$", "audio_path": "audio/row_00526696_1755649215379927.wav", "formula": "$\\mu_1(\\omega)\\geq\\mu_2(\\omega)\\geq...>0$", "answer": "Mu sub 1 of omega is greater than or equal to mu sub 2 of omega is greater than or equal to ellipsis, greater than 0.", "subset": "mixmath", "task_type": "tts"} +{"index": 116, "question": "请你朗读以下数学公式符号:$=\\left( 3.92+6.08 \\right)+\\left( 2.37+7.63 \\right)$", "audio_path": "audio/math_a8b5a330-1311-4dda-9e80-4a2178fb4014.wav", "formula": "$=\\left( 3.92+6.08 \\right)+\\left( 2.37+7.63 \\right)$", "answer": "等于三点九二加六点零八的和加二点三七加七点六三的和", "subset": "mixmath", "task_type": "tts"} +{"index": 117, "question": "Please read the following math formula symbols: $x+\\frac{l^2+a_1l+n}{\\pi_P^{2k}}$", "audio_path": "audio/row_00464953_1755641651336120.wav", "formula": "$x+\\frac{l^2+a_1l+n}{\\pi_P^{2k}}$", "answer": "x plus the quantity l squared plus a sub 1 l plus n all over the quantity pi sub P raised to the power of 2k.", "subset": "mixmath", "task_type": "tts"} +{"index": 118, "question": "Please read the following math formula symbols: $U_m\\inT_k(e_1,U^M)$", "audio_path": "audio/row_01170993_1755729616964940.wav", "formula": "$U_m\\inT_k(e_1,U^M)$", "answer": "U sub m belongs to T sub k open parenthesis e sub 1 comma U to the power of M close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 119, "question": "Please read the following math formula symbols: $1\\!\\leq\\!k\\!\\leq\\!|Y|$", "audio_path": "audio/row_00238678_1755614027643758.wav", "formula": "$1\\!\\leq\\!k\\!\\leq\\!|Y|$", "answer": "One factorial is less than or equal to k factorial, which is less than or equal to the absolute value of Y.", "subset": "mixmath", "task_type": "tts"} +{"index": 120, "question": "请你朗读以下数学公式符号:${(100001)}_{2} \\div {(11)}_{2} = {(1011)}_{2}$", "audio_path": "audio/math_9b2a9b7b-b8ab-4352-8637-0709240f619b.wav", "formula": "${(100001)}_{2} \\div {(11)}_{2} = {(1011)}_{2}$", "answer": "二进制的一零零零零一除以二进制的一一等于二进制的一零一一", "subset": "mixmath", "task_type": "tts"} +{"index": 121, "question": "Please read the following math formula symbols: $\\rho=1-\\frac{1-c^2}{m(1+\\bar{\\tau}/m)}$", "audio_path": "audio/row_01047358_1755714162623986.wav", "formula": "$\\rho=1-\\frac{1-c^2}{m(1+\\bar{\\tau}/m)}$", "answer": "rho equals one minus the fraction one minus c squared over m times the quantity one plus tau bar over m.", "subset": "mixmath", "task_type": "tts"} +{"index": 122, "question": "Please read the following math formula symbols: $\\mathbf{a}_{ij}=(\\mathbf{r}_i+\\mathbf{r}_j)/2$", "audio_path": "audio/row_00779096_1755680580809182.wav", "formula": "$\\mathbf{a}_{ij}=(\\mathbf{r}_i+\\mathbf{r}_j)/2$", "answer": "Math bold a sub i j equals open parenthesis math bold r sub i plus math bold r sub j close parenthesis divided by 2", "subset": "mixmath", "task_type": "tts"} +{"index": 123, "question": "Please read the following math formula symbols: $\\frac{\\partialF^{k+1}}{\\partialG_j^k}$", "audio_path": "audio/row_01267939_1755741756270641.wav", "formula": "$\\frac{\\partialF^{k+1}}{\\partialG_j^k}$", "answer": "Fraction, partial F to the power of k plus 1, divided by partial G sub j to the power of k.", "subset": "mixmath", "task_type": "tts"} +{"index": 124, "question": "请你朗读以下数学公式符号:$\\left\\{ \\begin{array}{*{35}{l}} a=3 \\\\ b=5 \\\\ \\end{array} \\right.$", "audio_path": "audio/math_4a514c55-d588-43c4-ae4a-7aa39a7d9c8d.wav", "formula": "$\\left\\{ \\begin{array}{*{35}{l}} a=3 \\\\ b=5 \\\\ \\end{array} \\right.$", "answer": "a等于三,b等于五", "subset": "mixmath", "task_type": "tts"} +{"index": 125, "question": "请你朗读以下数学公式符号:$\\left( \\dfrac{23}{16}\\times \\dfrac{8}{23} \\right)\\times \\left( \\dfrac{15}{13}+\\dfrac{1}{2} \\right)$", "audio_path": "audio/math_bf3530c1-8840-423a-af8e-75ff23c001e1.wav", "formula": "$\\left( \\dfrac{23}{16}\\times \\dfrac{8}{23} \\right)\\times \\left( \\dfrac{15}{13}+\\dfrac{1}{2} \\right)$", "answer": "十六分之二十三乘二十三分之八的积,乘十三分之十五加二分之一的和", "subset": "mixmath", "task_type": "tts"} +{"index": 126, "question": "请你朗读以下数学公式符号:$\\frac{1}{2}\\div \\frac{5}{6}=\\frac{1}{2}\\times \\frac{6}{5}=\\frac{3}{5}$", "audio_path": "audio/math_fd9aaf93-b59e-4780-be05-b300adf37401.wav", "formula": "$\\frac{1}{2}\\div \\frac{5}{6}=\\frac{1}{2}\\times \\frac{6}{5}=\\frac{3}{5}$", "answer": "二分之一除以六分之五等于二分之一乘五分之六等于五分之三", "subset": "mixmath", "task_type": "tts"} +{"index": 127, "question": "Please read the following math formula symbols: $f\\in\\mathcal{S}(\\Omega_D)\\cap\\ker(\\partial/\\partialx_t^c)$", "audio_path": "audio/row_01057309_1755715411340501.wav", "formula": "$f\\in\\mathcal{S}(\\Omega_D)\\cap\\ker(\\partial/\\partialx_t^c)$", "answer": "f belongs to the set S of the Omega D intersection kernel of the partial derivative with respect to x sub t sub c.", "subset": "mixmath", "task_type": "tts"} +{"index": 128, "question": "Please read the following math formula symbols: $\\{\\KH_\\beta^\\lambda\\}_{\\lambda\\in\\R}$", "audio_path": "audio/row_01691379_1755795146336410.wav", "formula": "$\\{\\KH_\\beta^\\lambda\\}_{\\lambda\\in\\R}$", "answer": "Open brace, K H, subscript beta to the power of lambda, close brace, subscript lambda in the set of real numbers.", "subset": "mixmath", "task_type": "tts"} +{"index": 129, "question": "Please read the following math formula symbols: $\\mathcal{A}\\in\\Alg(\\Shv_?(\\pt)\\hphMod)$", "audio_path": "audio/row_00978612_1755705559383218.wav", "formula": "$\\mathcal{A}\\in\\Alg(\\Shv_?(\\pt)\\hphMod)$", "answer": "Mathcal A belongs to the set of alpha g, S h v sub question mark open parenthesis p t close parenthesis, h p h Mod.", "subset": "mixmath", "task_type": "tts"} +{"index": 130, "question": "请你朗读以下数学公式符号:$$(1+0.234+0.345+0.456)\\times (0.234+0.345+0.456+0.567)$$", "audio_path": "audio/math_d2279f45-ee23-4591-884e-3685a0470e69.wav", "formula": "$$(1+0.234+0.345+0.456)\\times (0.234+0.345+0.456+0.567)$$", "answer": "一加零点二三四加零点三四五加零点四五六的和乘零点二三四加零点三四五加零点四五六加零点五六七的和", "subset": "mixmath", "task_type": "tts"} +{"index": 131, "question": "Please read the following math formula symbols: $u_1\\cdotv_k=u_1\\cdotv_j+O(C_0\\theta)$", "audio_path": "audio/row_01119147_1755723093568982.wav", "formula": "$u_1\\cdotv_k=u_1\\cdotv_j+O(C_0\\theta)$", "answer": "u sub 1 times v sub k equals u sub 1 times v sub j plus capital O open parenthesis C sub 0 theta close parenthesis", "subset": "mixmath", "task_type": "tts"} +{"index": 132, "question": "Please read the following math formula symbols: $\\cD_i=(f_i,\\rho,J),i=0,1,2$", "audio_path": "audio/row_01279813_1755743271910846.wav", "formula": "$\\cD_i=(f_i,\\rho,J),i=0,1,2$", "answer": "c D sub i equals open parenthesis f sub i comma rho comma J close parenthesis, i equals 0, 1, 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 133, "question": "Please read the following math formula symbols: $\\lambda_{\\max}(n^{-1}_k\\bX^T_S\\bX_S)$", "audio_path": "audio/row_01803271_1755809305452342.wav", "formula": "$\\lambda_{\\max}(n^{-1}_k\\bX^T_S\\bX_S)$", "answer": "Lambda sub max of n to the power of negative one times k times b times X transpose times S times X sub S.", "subset": "mixmath", "task_type": "tts"} +{"index": 134, "question": "Please read the following math formula symbols: $x=(x_1,\\dotsc,x_n)\\in\\Sph{p}{n-1}$", "audio_path": "audio/row_02057684_1755841441324049.wav", "formula": "$x=(x_1,\\dotsc,x_n)\\in\\Sph{p}{n-1}$", "answer": "x equals open parenthesis x sub 1, dot dot dot, x sub n close parenthesis belongs to Sph p n minus 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 135, "question": "Please read the following math formula symbols: $\\bq_{ni}=\\bq_{ni}^0+\\bq_{ni}^+$", "audio_path": "audio/row_02064119_1755842284595834.wav", "formula": "$\\bq_{ni}=\\bq_{ni}^0+\\bq_{ni}^+$", "answer": "Bold q sub n i equals bold q sub n i superscript 0 plus bold q sub n i superscript plus", "subset": "mixmath", "task_type": "tts"} +{"index": 136, "question": "Please read the following math formula symbols: $M_0/tM_0\\congt^{N+1}M_0$", "audio_path": "audio/row_01059402_1755715663744619.wav", "formula": "$M_0/tM_0\\congt^{N+1}M_0$", "answer": "M sub 0 divided by t M sub 0 is isomorphic to t raised to the power of N plus 1 times M sub 0.", "subset": "mixmath", "task_type": "tts"} +{"index": 137, "question": "请你朗读以下数学公式符号:$$ \\left\\{\\begin{array}{c}120k+b=100\\\\ 130k+b=95\\end{array}\\right.$$", "audio_path": "audio/math_cfe158e8-d623-4cf1-9108-0be69ef12b6c.wav", "formula": "$$ \\left\\{\\begin{array}{c}120k+b=100\\\\ 130k+b=95\\end{array}\\right.$$", "answer": "一百二十k加b等于一百,一百三十k加b等于九十五", "subset": "mixmath", "task_type": "tts"} +{"index": 138, "question": "Please read the following math formula symbols: $e^{i\\sqrt{\\kappa}dW_{p_a}\\Pop_a}$", "audio_path": "audio/row_00637559_1755662969539069.wav", "formula": "$e^{i\\sqrt{\\kappa}dW_{p_a}\\Pop_a}$", "answer": "e to the power of i times the square root of kappa times d W sub p sub a times P op sub a", "subset": "mixmath", "task_type": "tts"} +{"index": 139, "question": "Please read the following math formula symbols: $(0,0,z^*)\\in\\bR^{c+s+l}$", "audio_path": "audio/row_01550759_1755777358604164.wav", "formula": "$(0,0,z^*)\\in\\bR^{c+s+l}$", "answer": "Open parenthesis, zero, comma, z star, close parenthesis, belongs to, b, R, raised to the power of, c plus s plus l.", "subset": "mixmath", "task_type": "tts"} +{"index": 140, "question": "Please read the following math formula symbols: $\\D(pq)\\subset\\E(pq)$", "audio_path": "audio/row_00267286_1755617531620730.wav", "formula": "$\\D(pq)\\subset\\E(pq)$", "answer": "D of the set consisting of p times q is a subset of E of the set consisting of p times q.", "subset": "mixmath", "task_type": "tts"} +{"index": 141, "question": "请你朗读以下数学公式符号:$$\\left( \\dfrac{\\dfrac{7}{4}+\\dfrac{1}{6}}{\\dfrac{4}{3}}\\div 2\\dfrac{7}{8} \\right)\\times \\left( \\dfrac{1}{\\dfrac{13}{15}}+\\dfrac{1}{2} \\right)$$", "audio_path": "audio/math_56a49c55-903e-4dd9-ab3d-a99cfba2dd86.wav", "formula": "$$\\left( \\dfrac{\\dfrac{7}{4}+\\dfrac{1}{6}}{\\dfrac{4}{3}}\\div 2\\dfrac{7}{8} \\right)\\times \\left( \\dfrac{1}{\\dfrac{13}{15}}+\\dfrac{1}{2} \\right)$$", "answer": "三分之四 分之 四分之七加六分之一的和 除以二又八分之七的商 乘 十五分之十三 分之一 加二分之一 的和", "subset": "mixmath", "task_type": "tts"} +{"index": 142, "question": "请你朗读以下数学公式符号:${{\\left( 63 \\right)}_{7}}=3+6\\times 7={{(45)}_{10}}={{\\left( 140 \\right)}_{5}}$", "audio_path": "audio/math_91aa839a-2e02-4bce-8d58-7185880dcf1d.wav", "formula": "${{\\left( 63 \\right)}_{7}}=3+6\\times 7={{(45)}_{10}}={{\\left( 140 \\right)}_{5}}$", "answer": "七进制六三等于三加六乘七等于十进制四十五等于五进制一四零", "subset": "mixmath", "task_type": "tts"} +{"index": 143, "question": "请你朗读以下数学公式符号:$\\left\\{\\begin{array}{c}ax+by=5\\\\bx+ay=2\\end{array}\\right.$", "audio_path": "audio/math_91ac5ba5-1a92-4a0f-986d-f53e8e5d563a.wav", "formula": "$\\left\\{\\begin{array}{c}ax+by=5\\\\bx+ay=2\\end{array}\\right.$", "answer": "ax加by等于五,bx加ay等于二", "subset": "mixmath", "task_type": "tts"} +{"index": 144, "question": "Please read the following math formula symbols: $0\\leqS_{n1}\\leqS_{n2}\\leq\\ldots$", "audio_path": "audio/row_01706674_1755797065743595.wav", "formula": "$0\\leqS_{n1}\\leqS_{n2}\\leq\\ldots$", "answer": "Zero less than or equal to S sub n1 less than or equal to S sub n2 less than or equal to ellipsis.", "subset": "mixmath", "task_type": "tts"} +{"index": 145, "question": "请你朗读以下数学公式符号:${{x}^{2}}+ax+\\left( m+1 \\right)\\left( m+2 \\right)=0$", "audio_path": "audio/math_79c447cd-a1ec-4ec2-a639-1c40247d94aa.wav", "formula": "${{x}^{2}}+ax+\\left( m+1 \\right)\\left( m+2 \\right)=0$", "answer": "x的平方加a 乘x加m加一的和乘m加二的和等于零", "subset": "mixmath", "task_type": "tts"} +{"index": 146, "question": "Please read the following math formula symbols: $V_A=\\sum_{v\\inA}\\nabla\\cdot_ve_p/(2\\piN_{\\text{void}})$", "audio_path": "audio/row_01800820_1755808988212865.wav", "formula": "$V_A=\\sum_{v\\inA}\\nabla\\cdot_ve_p/(2\\piN_{\\text{void}})$", "answer": "V sub A equals the sum over v in A of nabla dot sub v e sub p divided by 2 pi N sub void.", "subset": "mixmath", "task_type": "tts"} +{"index": 147, "question": "Please read the following math formula symbols: $1+x_2\\ge1+x_1\\ge1$", "audio_path": "audio/row_01964985_1755829736242157.wav", "formula": "$1+x_2\\ge1+x_1\\ge1$", "answer": "One plus x sub 2 greater than or equal to one plus x sub 1 greater than or equal to one.", "subset": "mixmath", "task_type": "tts"} +{"index": 148, "question": "请你朗读以下数学公式符号:$=\\frac{2}{11}\\times \\frac{3}{5}+\\frac{9}{11}\\times \\frac{3}{5}$", "audio_path": "audio/math_e29e51db-7f56-488e-893d-6a4196c5cba9.wav", "formula": "$=\\frac{2}{11}\\times \\frac{3}{5}+\\frac{9}{11}\\times \\frac{3}{5}$", "answer": "等于十一分之二乘五分之三加上十一分之九乘五分之三", "subset": "mixmath", "task_type": "tts"} +{"index": 149, "question": "请你朗读以下数学公式符号:$$0.25=\\frac{()}{4}=\\frac{5}{()}=\\frac{()}{16}=10\\div ()$$", "audio_path": "audio/math_39221989-7ba7-4c4f-a795-7b614a92b489.wav", "formula": "$$0.25=\\frac{()}{4}=\\frac{5}{()}=\\frac{()}{16}=10\\div ()$$", "answer": "零点二五等于四分之多少等于多少分之五等于十六分之多少等于十除以多少", "subset": "mixmath", "task_type": "tts"} +{"index": 150, "question": "请你朗读以下数学公式符号:$28\\times 21+28\\times 79=28\\times \\left( 21+79 \\right)$", "audio_path": "audio/math_77e61de0-8984-4caa-9991-01ff6405198e.wav", "formula": "$28\\times 21+28\\times 79=28\\times \\left( 21+79 \\right)$", "answer": "二十八乘二十一加二十八乘七十九等于二十八乘二十一加七十九的和", "subset": "mixmath", "task_type": "tts"} +{"index": 151, "question": "Please read the following math formula symbols: $S^k=S^{k-1}\\cupS_{[m]}$", "audio_path": "audio/row_01171346_1755729652507435.wav", "formula": "$S^k=S^{k-1}\\cupS_{[m]}$", "answer": "S raised to the power of k equals S raised to the power of k minus 1 union S subscript m.", "subset": "mixmath", "task_type": "tts"} +{"index": 152, "question": "Please read the following math formula symbols: $\\ket{\\xx}^{\\bx{1}},\\cdots,\\ket\\xx^{\\bx{r}}$", "audio_path": "audio/row_01448618_1755764457948260.wav", "formula": "$\\ket{\\xx}^{\\bx{1}},\\cdots,\\ket\\xx^{\\bx{r}}$", "answer": "Ket x raised to the power of b x 1, dot dot dot, ket x raised to the power of b x r.", "subset": "mixmath", "task_type": "tts"} +{"index": 153, "question": "Please read the following math formula symbols: ${\\nu_p(F_n)=\\nu_\\gerp(\\gamma^n-1)}$", "audio_path": "audio/row_02029798_1755837908132588.wav", "formula": "${\\nu_p(F_n)=\\nu_\\gerp(\\gamma^n-1)}$", "answer": "Nu sub p of F sub n equals nu sub r p of gamma to the power of n minus 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 154, "question": "Please read the following math formula symbols: $$\\bar\\sigma_2(\\Sigma,\\nu)\\leq\\frac{4\\pi}{M_0}$$", "audio_path": "audio/row_01729567_1755799972941755.wav", "formula": "$$\\bar\\sigma_2(\\Sigma,\\nu)\\leq\\frac{4\\pi}{M_0}$$", "answer": "The bar sigma sub 2 of Sigma, nu is less than or equal to 4 pi divided by M sub 0.", "subset": "mixmath", "task_type": "tts"} +{"index": 155, "question": "Please read the following math formula symbols: $q_1(x,y)=i^{\\pm(x^2+y^2)}$", "audio_path": "audio/row_01071062_1755717111426243.wav", "formula": "$q_1(x,y)=i^{\\pm(x^2+y^2)}$", "answer": "q sub 1 of x, y equals i to the power of plus or minus open parenthesis x squared plus y squared close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 156, "question": "Please read the following math formula symbols: $\\CC^\\gamma[\\mfg,\\mfg]$", "audio_path": "audio/row_00643531_1755663708346743.wav", "formula": "$\\CC^\\gamma[\\mfg,\\mfg]$", "answer": "C C raised to the power of gamma, the commutator of m times f times g and m times f times g.", "subset": "mixmath", "task_type": "tts"} +{"index": 157, "question": "Please read the following math formula symbols: $-\\sum_{i\\in[{\\calX}^{L}]}G_{i}\\logG_{i}$", "audio_path": "audio/row_01353143_1755752418590041.wav", "formula": "$-\\sum_{i\\in[{\\calX}^{L}]}G_{i}\\logG_{i}$", "answer": "Minus, the sum over i in the set X to the power of L, of G sub i, log G sub i.", "subset": "mixmath", "task_type": "tts"} +{"index": 158, "question": "Please read the following math formula symbols: $\\|u^{(n)}\\|_{H^s}=1$", "audio_path": "audio/row_00295678_1755620976696688.wav", "formula": "$\\|u^{(n)}\\|_{H^s}=1$", "answer": "Norm of the derivative of u with respect to n, in the H to the power of s space, equals 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 159, "question": "请你朗读以下数学公式符号:$\\frac{\\left( a+b \\right)\\left( a+c \\right)\\left( b+c \\right)}{abc}=\\frac{2c\\cdot 2b\\cdot 2a}{abc}=8$", "audio_path": "audio/math_831acce0-4365-4c57-bacf-0f40fe26f792.wav", "formula": "$\\frac{\\left( a+b \\right)\\left( a+c \\right)\\left( b+c \\right)}{abc}=\\frac{2c\\cdot 2b\\cdot 2a}{abc}=8$", "answer": "abc分之a加b的和乘a加c的和乘b加c的和的积 等于 abc分之二c乘二b乘二a的积等于八", "subset": "mixmath", "task_type": "tts"} +{"index": 160, "question": "Please read the following math formula symbols: $\\Ueps(t,0)=0_k\\in\\R^k$", "audio_path": "audio/row_01868979_1755817613383640.wav", "formula": "$\\Ueps(t,0)=0_k\\in\\R^k$", "answer": "The U e p s of t comma 0 equals 0 sub k belongs to R to the power of k.", "subset": "mixmath", "task_type": "tts"} +{"index": 161, "question": "Please read the following math formula symbols: $\\mu_i=m_i/\\sqrt{\\gamma_i}(i=2,\\cdots,n)$", "audio_path": "audio/row_00982158_1755706008642491.wav", "formula": "$\\mu_i=m_i/\\sqrt{\\gamma_i}(i=2,\\cdots,n)$", "answer": "mu i equals m i divided by the square root of gamma i, where i is equal to 2, dot dot dot, n.", "subset": "mixmath", "task_type": "tts"} +{"index": 162, "question": "Please read the following math formula symbols: $[W^{1,\\infty}(\\Omega)]^d$", "audio_path": "audio/row_00227526_1755612687823677.wav", "formula": "$[W^{1,\\infty}(\\Omega)]^d$", "answer": "The quantity W raised to the power of one to infinity, defined on the domain Omega, all raised to the power of d.", "subset": "mixmath", "task_type": "tts"} +{"index": 163, "question": "请你朗读以下数学公式符号:$\\frac{5}{14}\\div \\left[ \\frac{5}{26}\\times \\left( \\frac{3}{7}+\\frac{1}{2} \\right) \\right]$", "audio_path": "audio/math_ed0c61d5-1966-499e-9ca4-de5fdb688fdb.wav", "formula": "$\\frac{5}{14}\\div \\left[ \\frac{5}{26}\\times \\left( \\frac{3}{7}+\\frac{1}{2} \\right) \\right]$", "answer": "十四分之五除以二十六分之五乘七分之三加二分之一的和的积", "subset": "mixmath", "task_type": "tts"} +{"index": 164, "question": "Please read the following math formula symbols: $m\\equiv\\Omega_{\\tau_m,n}\\bmod{(p^f-1)}$", "audio_path": "audio/row_00394010_1755632962806796.wav", "formula": "$m\\equiv\\Omega_{\\tau_m,n}\\bmod{(p^f-1)}$", "answer": "m is congruent to the residue of Omega sub tau m comma n modulo the quantity p to the power of f minus 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 165, "question": "请你朗读以下数学公式符号:$\\dfrac{2}{7}\\div 3=\\dfrac{2}{7}\\times \\dfrac{1}{3}=\\dfrac{2}{21}$", "audio_path": "audio/math_af85825b-de59-4e3f-a6fe-0ec128d0d408.wav", "formula": "$\\dfrac{2}{7}\\div 3=\\dfrac{2}{7}\\times \\dfrac{1}{3}=\\dfrac{2}{21}$", "answer": "七分之二除以三等于七分之二 乘 三分之一 等于二十一分之二", "subset": "mixmath", "task_type": "tts"} +{"index": 166, "question": "请你朗读以下数学公式符号:$2\\times 2\\times 3\\times 5\\times 7\\times 11=3\\times 2\\times 2\\times 7\\times 5\\times 11$", "audio_path": "audio/math_cb190c6a-f4b4-4e57-9a9e-e30fb91e094a.wav", "formula": "$2\\times 2\\times 3\\times 5\\times 7\\times 11=3\\times 2\\times 2\\times 7\\times 5\\times 11$", "answer": "二乘二乘三乘五乘七乘十一等于三乘二乘二乘七乘五乘十一", "subset": "mixmath", "task_type": "tts"} +{"index": 167, "question": "Please read the following math formula symbols: $g\\inB_{F^\\beta}(0,\\ep_{\\operatorname*{surj}})$", "audio_path": "audio/row_00035265_1755589370417848.wav", "formula": "$g\\inB_{F^\\beta}(0,\\ep_{\\operatorname*{surj}})$", "answer": "g belongs to the set B sub F to the power of beta, open interval from 0 to epsilon sub surj.", "subset": "mixmath", "task_type": "tts"} +{"index": 168, "question": "请你朗读以下数学公式符号:$$=15\\times \\left( \\frac{4}{7}+\\frac{3}{7} \\right)+\\frac{5}{8}\\times (7+9)$$", "audio_path": "audio/math_bf58a8af-eaf1-40bc-b015-e7b144655295.wav", "formula": "$$=15\\times \\left( \\frac{4}{7}+\\frac{3}{7} \\right)+\\frac{5}{8}\\times (7+9)$$", "answer": "等于十五乘七分之四加七分之三的和,加八分之五乘七加九的和", "subset": "mixmath", "task_type": "tts"} +{"index": 169, "question": "请你朗读以下数学公式符号:$\\begin{eqnarray}\\frac{1.2}{2.5}&=&\\frac{x}{3}\\\\ 1.2x&=&2.5\\times 3\\\\ 1.2x\\div 1.2&=&2.5\\times 3\\div 1.2\\\\ x&=&6.25\\end{eqnarray}$", "audio_path": "audio/math_603b1bc1-6351-4d8e-9433-505ea95b5612.wav", "formula": "$\\begin{eqnarray}\\frac{1.2}{2.5}&=&\\frac{x}{3}\\\\ 1.2x&=&2.5\\times 3\\\\ 1.2x\\div 1.2&=&2.5\\times 3\\div 1.2\\\\ x&=&6.25\\end{eqnarray}$", "answer": "二点五分之一点二等于三分之x \n一点二x等于二点五乘三\n一点二x除以一点二等于二点五乘三除以一点二\n x等于六点二五", "subset": "mixmath", "task_type": "tts"} +{"index": 170, "question": "Please read the following math formula symbols: $V^0\\in\\textnormal{BUC}(\\R^n)$", "audio_path": "audio/row_01805467_1755809585725361.wav", "formula": "$V^0\\in\\textnormal{BUC}(\\R^n)$", "answer": "V raised to the power of 0 belongs to the set of BUC of R raised to the power of n.", "subset": "mixmath", "task_type": "tts"} +{"index": 171, "question": "Please read the following math formula symbols: $a'=P(P+4a)/8$", "audio_path": "audio/row_01720126_1755798773548271.wav", "formula": "$a'=P(P+4a)/8$", "answer": "The derivative of a with respect to time is equal to the product of P and the sum of P and 4a divided by 8.", "subset": "mixmath", "task_type": "tts"} +{"index": 172, "question": "请你朗读以下数学公式符号:$50.2\\times 0.24=5.02\\times 10\\times 2.4\\div 10=12.048$", "audio_path": "audio/math_371c4867-4107-4291-abfe-b5a7218de4de.wav", "formula": "$50.2\\times 0.24=5.02\\times 10\\times 2.4\\div 10=12.048$", "answer": "五十点二乘零点二四等于五点零二乘十乘二点四除以十等于十二点零四八", "subset": "mixmath", "task_type": "tts"} +{"index": 173, "question": "Please read the following math formula symbols: ${B(p_1,h^\\eta),\\dots,B(p_l,h^\\eta)}$", "audio_path": "audio/row_01730027_1755800021771214.wav", "formula": "${B(p_1,h^\\eta),\\dots,B(p_l,h^\\eta)}$", "answer": "B of p sub 1, h to the power of eta, dot dot dot, B of p sub l, h to the power of eta.", "subset": "mixmath", "task_type": "tts"} +{"index": 174, "question": "请你朗读以下数学公式符号:$\\frac{3}{8}\\times \\frac{1}{4}=\\frac{3}{32}\\left( {{{m}}^{2}} \\right)$", "audio_path": "audio/math_a86e6d4e-b631-4256-8e31-c6c53610104a.wav", "formula": "$\\frac{3}{8}\\times \\frac{1}{4}=\\frac{3}{32}\\left( {{{m}}^{2}} \\right)$", "answer": "八分之三乘四分之一等于三十二分之三平方米", "subset": "mixmath", "task_type": "tts"} +{"index": 175, "question": "Please read the following math formula symbols: $\\alpha=(\\alpha_0,\\alpha_1,\\alpha_2,\\dots,\\alpha_n)$", "audio_path": "audio/row_01513830_1755772676974549.wav", "formula": "$\\alpha=(\\alpha_0,\\alpha_1,\\alpha_2,\\dots,\\alpha_n)$", "answer": "Alpha equals open parenthesis alpha sub zero, alpha sub one, alpha sub two, dot dot dot, alpha sub n close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 176, "question": "请你朗读以下数学公式符号:$4 \\times \\frac{8}{{13}} = \\frac{{32}}{{13}} = 2\\frac{6}{{13}}$", "audio_path": "audio/math_6c530ff4-56a8-4edc-8d9f-caf76831e87b.wav", "formula": "$4 \\times \\frac{8}{{13}} = \\frac{{32}}{{13}} = 2\\frac{6}{{13}}$", "answer": "四乘十三分之八等于十三分之三十二等于二又十三分之六", "subset": "mixmath", "task_type": "tts"} +{"index": 177, "question": "Please read the following math formula symbols: $N^{-1}\\sum_{i\\in\\D}\\hatm(X_i)\\hath(X_i)$", "audio_path": "audio/row_00888748_1755694359220673.wav", "formula": "$N^{-1}\\sum_{i\\in\\D}\\hatm(X_i)\\hath(X_i)$", "answer": "N to the power of negative one, sum over i in D, hat m of X sub i, hat h of X sub i.", "subset": "mixmath", "task_type": "tts"} +{"index": 178, "question": "请你朗读以下数学公式符号:$\\therefore {{S}_{\\vartriangle ABC}}=\\frac{1}{2}\\times 3\\times 4=6$", "audio_path": "audio/math_353101a0-7862-4008-a24d-4bc9bc91fc07.wav", "formula": "$\\therefore {{S}_{\\vartriangle ABC}}=\\frac{1}{2}\\times 3\\times 4=6$", "answer": "所以,S 三角形ABC等于二分之一乘三乘四等于六", "subset": "mixmath", "task_type": "tts"} +{"index": 179, "question": "请你朗读以下数学公式符号:$$=(2\\times 4\\times 6\\times 8\\times 10\\times 12\\times 14\\times 16)\\div (2\\times 10\\times 6\\times 8\\times 4\\times 14)$$", "audio_path": "audio/math_581196be-75b0-4a8b-b783-ae80e51ce0ee.wav", "formula": "$$=(2\\times 4\\times 6\\times 8\\times 10\\times 12\\times 14\\times 16)\\div (2\\times 10\\times 6\\times 8\\times 4\\times 14)$$", "answer": "等于二乘四乘六乘八乘十乘十二乘十四乘十六的积除以二乘十乘六乘八乘四乘十四的积", "subset": "mixmath", "task_type": "tts"} +{"index": 180, "question": "请你朗读以下数学公式符号:$\\left\\{\\begin{array}{c}x=1\\\\ y=2\\end{array}\\right.$", "audio_path": "audio/math_4bfe7221-53a0-4bec-9b89-4c6b39553d0d.wav", "formula": "$\\left\\{\\begin{array}{c}x=1\\\\ y=2\\end{array}\\right.$", "answer": "x等于一,y等于二", "subset": "mixmath", "task_type": "tts"} +{"index": 181, "question": "Please read the following math formula symbols: $\\nu^\\rho_t,\\nu^{\\rho\\prime}_t\\in\\P(\\Y)$", "audio_path": "audio/row_00801521_1755683397327958.wav", "formula": "$\\nu^\\rho_t,\\nu^{\\rho\\prime}_t\\in\\P(\\Y)$", "answer": "Nu to the power of rho sub t, nu to the power of rho prime sub t belongs to the probability of Y.", "subset": "mixmath", "task_type": "tts"} +{"index": 182, "question": "请你朗读以下数学公式符号:$$\\left\\{\\begin{array}{l}x+y=10\\\\ 49x+37y=422\\end{array}\\right.$$", "audio_path": "audio/math_ad81b324-eedd-4945-8b3c-cf7477d3c96b.wav", "formula": "$$\\left\\{\\begin{array}{l}x+y=10\\\\ 49x+37y=422\\end{array}\\right.$$", "answer": "x加y等于十,四十九x加三十七y等于四百二十二", "subset": "mixmath", "task_type": "tts"} +{"index": 183, "question": "Please read the following math formula symbols: $O(n^{\\lfloord/2\\rfloor+1}\\log^{d}n)$", "audio_path": "audio/row_00124837_1755600191832130.wav", "formula": "$O(n^{\\lfloord/2\\rfloor+1}\\log^{d}n)$", "answer": "O of n to the floor of d divided by 2 plus 1, times log to the power of d of n.", "subset": "mixmath", "task_type": "tts"} +{"index": 184, "question": "Please read the following math formula symbols: $\\left(1,8^{7k}-1,8^{7k}\\right)$", "audio_path": "audio/row_00063050_1755592755343768.wav", "formula": "$\\left(1,8^{7k}-1,8^{7k}\\right)$", "answer": "One point eight raised to the power of seven k, minus one point eight raised to the power of seven k.", "subset": "mixmath", "task_type": "tts"} +{"index": 185, "question": "Please read the following math formula symbols: ${\\bmc}^{\\prime}={\\bmc}+(q/2){\\bmz}_{m+n-k+\\alpha}$", "audio_path": "audio/row_00056305_1755591920914511.wav", "formula": "${\\bmc}^{\\prime}={\\bmc}+(q/2){\\bmz}_{m+n-k+\\alpha}$", "answer": "c prime equals c plus open parenthesis q divided by 2 close parenthesis z sub m plus n minus k plus alpha", "subset": "mixmath", "task_type": "tts"} +{"index": 186, "question": "Please read the following math formula symbols: $\\text{Der}(\\ms{C},\\ms{I}_0^p/\\ms{I}_0^{p+1}))$", "audio_path": "audio/row_01797812_1755808607385243.wav", "formula": "$\\text{Der}(\\ms{C},\\ms{I}_0^p/\\ms{I}_0^{p+1}))$", "answer": "Der of ms C, ms I zero to the power of p divided by ms I zero to the power of p plus 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 187, "question": "请你朗读以下数学公式符号:$1\\times \\frac{1}{2}\\times \\frac{1}{4}=\\frac{1}{8}$", "audio_path": "audio/math_bcb1ddef-fb97-4bbb-93ab-f5ae9811440f.wav", "formula": "$1\\times \\frac{1}{2}\\times \\frac{1}{4}=\\frac{1}{8}$", "answer": "一乘二分之一乘四分之一等于八分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 188, "question": "请你朗读以下数学公式符号:$=\\frac{2n}{{{n}^{2}}+4n}\\times \\frac{n+4}{n}=\\frac{2}{n+4}\\times \\frac{n+4}{n}=\\frac{2}{n}=$", "audio_path": "audio/math_957dd4f7-03c3-4b78-a39a-2e2c024d0a44.wav", "formula": "$=\\frac{2n}{{{n}^{2}}+4n}\\times \\frac{n+4}{n}=\\frac{2}{n+4}\\times \\frac{n+4}{n}=\\frac{2}{n}=$", "answer": "等于n平方加四n的和分之二n 乘n分之n加四的和等于n加四的和分之二乘n分之n加四的和等于n分之二等于", "subset": "mixmath", "task_type": "tts"} +{"index": 189, "question": "Please read the following math formula symbols: $$U_{i,j}=U_{j,i}=\\max\\{U_{k}:k=i,\\cdots,j-1\\}.$$", "audio_path": "audio/row_00074543_1755594122670217.wav", "formula": "$$U_{i,j}=U_{j,i}=\\max\\{U_{k}:k=i,\\cdots,j-1\\}.$$", "answer": "U sub i, j equals U sub j, i equals the maximum of U sub k, where k equals i, dot dot dot, j minus 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 190, "question": "Please read the following math formula symbols: $p_{\\rmocc}(m_{\\rmBH}|M_v,z,\\vect{\\theta})$", "audio_path": "audio/row_01980531_1755831674133345.wav", "formula": "$p_{\\rmocc}(m_{\\rmBH}|M_v,z,\\vect{\\theta})$", "answer": "P sub occ, open parenthesis, m sub BH, vertical bar, M sub v, comma, z, comma, vector t theta, close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 191, "question": "请你朗读以下数学公式符号:$$\\frac{1}{1\\times 2}+\\frac{1}{2\\times 3}+\\frac{1}{3\\times 4}$$", "audio_path": "audio/math_88ef770d-cf94-408e-9251-62b5a395f6c8.wav", "formula": "$$\\frac{1}{1\\times 2}+\\frac{1}{2\\times 3}+\\frac{1}{3\\times 4}$$", "answer": "一乘二的积分之一加二乘三的积分之一加三乘四的积分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 192, "question": "请你朗读以下数学公式符号:$48\\times \\frac{11}{5+11}=48\\times \\frac{11}{16}=33$", "audio_path": "audio/math_4d335d39-5794-4e8f-8ebb-017655662d90.wav", "formula": "$48\\times \\frac{11}{5+11}=48\\times \\frac{11}{16}=33$", "answer": "四十八乘五加十一的和分之十一等于四十八乘十六分之十一等于三十三", "subset": "mixmath", "task_type": "tts"} +{"index": 193, "question": "请你朗读以下数学公式符号:$$\\begin{cases}33x+17y=83(1) \\\\ 17x+33y=67(2) \\\\ \\end{cases}$$", "audio_path": "audio/math_7042c6ab-7293-42d3-97c7-f490fdce573a.wav", "formula": "$$\\begin{cases}33x+17y=83(1) \\\\ 17x+33y=67(2) \\\\ \\end{cases}$$", "answer": "三十三x加十七y等于八十三,一式;十七x加三十三y等于六十七,二式。", "subset": "mixmath", "task_type": "tts"} +{"index": 194, "question": "请你朗读以下数学公式符号:$36\\times 101=36\\times (100+1)=36\\times 100+36\\times 1$", "audio_path": "audio/math_48a98a19-f085-432f-8e73-2fe7364c715b.wav", "formula": "$36\\times 101=36\\times (100+1)=36\\times 100+36\\times 1$", "answer": "三十六乘一百零一等于三十六乘一百加一的和等于三十六乘一百加三十六乘一", "subset": "mixmath", "task_type": "tts"} +{"index": 195, "question": "请你朗读以下数学公式符号:$$\\begin{eqnarray}&&\\frac{4}{5}\\div \\left( \\frac{3}{5}+\\frac{1}{2} \\right)\\\\ &=&\\frac{4}{5}\\div \\left( \\frac{6}{10}+\\frac{5}{10} \\right)\\\\ &=&\\frac{4}{5}\\times \\frac{10}{11}\\\\ &=&\\frac{8}{11}.\\end{eqnarray}$$", "audio_path": "audio/math_75bb94b3-80c9-4273-9a32-ab71ec158c93.wav", "formula": "$$\\begin{eqnarray}&&\\frac{4}{5}\\div \\left( \\frac{3}{5}+\\frac{1}{2} \\right)\\\\ &=&\\frac{4}{5}\\div \\left( \\frac{6}{10}+\\frac{5}{10} \\right)\\\\ &=&\\frac{4}{5}\\times \\frac{10}{11}\\\\ &=&\\frac{8}{11}.\\end{eqnarray}$$", "answer": "五分之四除以五分之三加二分之一的和,等于五分之四除以十分之六加十分之五的和,等于五分之四乘十一分之十,等于十一分之八。", "subset": "mixmath", "task_type": "tts"} +{"index": 196, "question": "Please read the following math formula symbols: $\\Phi_0,\\ldots,\\Phi_n\\in\\{\\mathbf\\k[x_0,\\ldots,x_n]$", "audio_path": "audio/row_00524880_1755648990931979.wav", "formula": "$\\Phi_0,\\ldots,\\Phi_n\\in\\{\\mathbf\\k[x_0,\\ldots,x_n]$", "answer": "Phi sub zero, dot dot dot, Phi sub n belongs to the set of k over x sub zero, dot dot dot, x sub n.", "subset": "mixmath", "task_type": "tts"} +{"index": 197, "question": "请你朗读以下数学公式符号:$$\\begin{eqnarray}1.6:x&=&0.125:0.5\\\\ 0.125x&=&0.5\\times 1.6\\\\ 0.125x&=&0.8\\\\ x&=&0.8\\div 0.125\\\\ x&=&6.4\\end{eqnarray}$$", "audio_path": "audio/math_835aa2ad-20b5-4c54-be7c-19dfa21ce8cc.wav", "formula": "$$\\begin{eqnarray}1.6:x&=&0.125:0.5\\\\ 0.125x&=&0.5\\times 1.6\\\\ 0.125x&=&0.8\\\\ x&=&0.8\\div 0.125\\\\ x&=&6.4\\end{eqnarray}$$", "answer": "一点六比x等于零点一二五比零点五;零点一二五x等于零点五乘一点六;零点一二五x等于零点八;x等于零点八除以零点一二五;x等于六点四", "subset": "mixmath", "task_type": "tts"} +{"index": 198, "question": "Please read the following math formula symbols: $(x,y)\\cdotB=xBy^{-1}$", "audio_path": "audio/row_02041555_1755839379681682.wav", "formula": "$(x,y)\\cdotB=xBy^{-1}$", "answer": "Open parenthesis x comma y close parenthesis dot product B equals x times B times y to the power of negative one.", "subset": "mixmath", "task_type": "tts"} +{"index": 199, "question": "Please read the following math formula symbols: $g_{b}\\in\\Fix_{G}(Tb)\\cap\\Fix_G(\\mathcal{T})$", "audio_path": "audio/row_01148210_1755726759493269.wav", "formula": "$g_{b}\\in\\Fix_{G}(Tb)\\cap\\Fix_G(\\mathcal{T})$", "answer": "g sub b belongs to the set of Fix sub G of T sub b intersect Fix sub G of T.", "subset": "mixmath", "task_type": "tts"} +{"index": 200, "question": "Please read the following math formula symbols: $c_r(\\mathcal{V})\\in\\Ch^r(X_\\kb)$", "audio_path": "audio/row_00359233_1755628705163849.wav", "formula": "$c_r(\\mathcal{V})\\in\\Ch^r(X_\\kb)$", "answer": "c sub r of the set V belongs to the rth chain group of the space X sub k sub b.", "subset": "mixmath", "task_type": "tts"} +{"index": 201, "question": "Please read the following math formula symbols: $d:=d^q_{\\ns^{\\infty,C}}$", "audio_path": "audio/row_00260476_1755616686107198.wav", "formula": "$d:=d^q_{\\ns^{\\infty,C}}$", "answer": "d is defined as d raised to the power of q sub n s raised to the power of infinity comma C.", "subset": "mixmath", "task_type": "tts"} +{"index": 202, "question": "Please read the following math formula symbols: $\\{a_i(t)\\}_{i=1}^k\\cup\\{a_i(t+h)\\}$", "audio_path": "audio/row_00784214_1755681231721019.wav", "formula": "$\\{a_i(t)\\}_{i=1}^k\\cup\\{a_i(t+h)\\}$", "answer": "Curly brace, a sub i of t, curly brace, sub i equals 1, caret, k union, curly brace, a sub i of t plus h.", "subset": "mixmath", "task_type": "tts"} +{"index": 203, "question": "Please read the following math formula symbols: $T=\\{y\\inG:o(y)\\in\\{2,4,6\\}\\}$", "audio_path": "audio/row_00516543_1755647963345390.wav", "formula": "$T=\\{y\\inG:o(y)\\in\\{2,4,6\\}\\}$", "answer": "T equals the set of y in G such that o of y is in the set 2 to 4, 6.", "subset": "mixmath", "task_type": "tts"} +{"index": 204, "question": "请你朗读以下数学公式符号:$\\left\\{\\begin{array}{c}{x}{=}7\\\\ {y}{=}5\\end{array}\\right.$", "audio_path": "audio/math_87ddacc0-727b-4003-8c70-e6575fa99c7c.wav", "formula": "$\\left\\{\\begin{array}{c}{x}{=}7\\\\ {y}{=}5\\end{array}\\right.$", "answer": "x等于七,y等于五", "subset": "mixmath", "task_type": "tts"} +{"index": 205, "question": "请你朗读以下数学公式符号:$\\overline{ab999}=\\overline{ab}\\times 1000+999=989\\times \\overline{ab}+989+11\\overline{ab}+10$", "audio_path": "audio/math_275a0a5d-85bf-4361-9347-91c3406453fc.wav", "formula": "$\\overline{ab999}=\\overline{ab}\\times 1000+999=989\\times \\overline{ab}+989+11\\overline{ab}+10$", "answer": "五位数a b九九九等于两位数a b乘一千加九百九十九等于九百八十九乘两位数a b加九百八十九加十一乘两位数a b加十", "subset": "mixmath", "task_type": "tts"} +{"index": 206, "question": "请你朗读以下数学公式符号:$\\frac{7}{20}=\\frac{7\\times 3}{20\\times 3}=\\frac{21}{60}$", "audio_path": "audio/math_db8da4da-4ed8-4576-a9e3-cefa25dc4591.wav", "formula": "$\\frac{7}{20}=\\frac{7\\times 3}{20\\times 3}=\\frac{21}{60}$", "answer": "二十分之七等于二十乘三的积分之七乘三等于六十分之二十一", "subset": "mixmath", "task_type": "tts"} +{"index": 207, "question": "Please read the following math formula symbols: $A=\\cinfty(\\R^{\\mathbb{N}})=\\colim_{n\\in\\N}\\cinfty(\\R^n)$", "audio_path": "audio/row_00920775_1755698357792151.wav", "formula": "$A=\\cinfty(\\R^{\\mathbb{N}})=\\colim_{n\\in\\N}\\cinfty(\\R^n)$", "answer": "A equals infinity of R to the power of N, equals colim over n in N, infinity of R to the power of n.", "subset": "mixmath", "task_type": "tts"} +{"index": 208, "question": "请你朗读以下数学公式符号:${{\\left( 11202 \\right)}_{4}}={{\\left( 433\\right)}_{9}}$", "audio_path": "audio/math_15890914-ccb2-4b2c-b182-41145add77e3.wav", "formula": "${{\\left( 11202 \\right)}_{4}}={{\\left( 433\\right)}_{9}}$", "answer": "四进制一一二零二等于九进制四三三", "subset": "mixmath", "task_type": "tts"} +{"index": 209, "question": "Please read the following math formula symbols: $Q:=(q^{1}+p_{2})/\\sqrt{2}$", "audio_path": "audio/row_00844536_1755688821754962.wav", "formula": "$Q:=(q^{1}+p_{2})/\\sqrt{2}$", "answer": "Q equals open parenthesis q to the power of 1 plus p sub 2 close parenthesis divided by square root of 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 210, "question": "请你朗读以下数学公式符号:$\\frac{7}{9} < \\frac{7+4}{9+5}=\\frac{11}{14} < \\frac{4}{5}$", "audio_path": "audio/math_8cc65fc5-2cff-4338-a94f-880538e7c9ef.wav", "formula": "$\\frac{7}{9} < \\frac{7+4}{9+5}=\\frac{11}{14} < \\frac{4}{5}$", "answer": "九分之七小于九加五的和分之七加四的和等于十四分之十一小于五分之四", "subset": "mixmath", "task_type": "tts"} +{"index": 211, "question": "Please read the following math formula symbols: $n_B=b\\sum_i\\left(n_{\\psi_i}-n_{\\bar{\\psi}_i}\\right)$", "audio_path": "audio/row_00480101_1755643500565192.wav", "formula": "$n_B=b\\sum_i\\left(n_{\\psi_i}-n_{\\bar{\\psi}_i}\\right)$", "answer": "n sub B equals b times the sum over i of the quantity n sub psi i minus n sub psi bar i.", "subset": "mixmath", "task_type": "tts"} +{"index": 212, "question": "Please read the following math formula symbols: $\\tilde\\{\\mathsf\\{D^6=\\nbs_\\{\\mathsf\\{s^6$", "audio_path": "audio/row_01751480_1755802769989133.wav", "formula": "$\\tilde\\{\\mathsf\\{D^6=\\nbs_\\{\\mathsf\\{s^6$", "answer": "The tilde of D to the power of 6 equals n times b times s sub s to the power of 6.", "subset": "mixmath", "task_type": "tts"} +{"index": 213, "question": "请你朗读以下数学公式符号:$0.4\\times 2\\times 3.14\\times 1.5+0.4\\times 0.4\\times 3.14\\times 2=4.7728(m^{2})$", "audio_path": "audio/math_84151876-5f4c-4930-bdf9-6e4522bd1129.wav", "formula": "$0.4\\times 2\\times 3.14\\times 1.5+0.4\\times 0.4\\times 3.14\\times 2=4.7728(m^{2})$", "answer": "零点四乘二乘三点一四乘一点五加零点四乘零点四乘三点一四乘二等于四点七七二八平方米", "subset": "mixmath", "task_type": "tts"} +{"index": 214, "question": "Please read the following math formula symbols: $y(z)\\simx(z)y(z)^2=u(z)=z\\to0$", "audio_path": "audio/row_00464545_1755641598693761.wav", "formula": "$y(z)\\simx(z)y(z)^2=u(z)=z\\to0$", "answer": "y of z, approximately equal to x of z, times y of z squared, equals u of z, equals z approaching zero.", "subset": "mixmath", "task_type": "tts"} +{"index": 215, "question": "请你朗读以下数学公式符号:$\\frac{7}{13}+\\frac{5}{14}-\\frac{7}{13}+\\frac{5}{14}$", "audio_path": "audio/math_d9fb9fa2-8c03-42d1-9c49-d91620320237.wav", "formula": "$\\frac{7}{13}+\\frac{5}{14}-\\frac{7}{13}+\\frac{5}{14}$", "answer": "十三分之七加十四分之五减十三分之七加十四分之五", "subset": "mixmath", "task_type": "tts"} +{"index": 216, "question": "请你朗读以下数学公式符号:$404\\times 25=(400+4)\\times 25=400\\times 25+4\\times 25=10000+100=10100$", "audio_path": "audio/math_4f1b2ec8-1965-404b-ba27-67da6bcc9f89.wav", "formula": "$404\\times 25=(400+4)\\times 25=400\\times 25+4\\times 25=10000+100=10100$", "answer": "四百零四乘二十五等于四百加四的和乘二十五等于四百乘二十五加四乘二十五的积等于一万加一百等于一万零一百", "subset": "mixmath", "task_type": "tts"} +{"index": 217, "question": "Please read the following math formula symbols: $B(x_0,r)\\subset\\mathbb\\{R^N$", "audio_path": "audio/row_00376063_1755630768439115.wav", "formula": "$B(x_0,r)\\subset\\mathbb\\{R^N$", "answer": "B open parenthesis x sub 0 comma r close parenthesis is a subset of the set of real numbers to the power of capital N.", "subset": "mixmath", "task_type": "tts"} +{"index": 218, "question": "Please read the following math formula symbols: $\\cT(h^i)=(\\cC^{c})^{\\cap}$", "audio_path": "audio/row_00266524_1755617430894585.wav", "formula": "$\\cT(h^i)=(\\cC^{c})^{\\cap}$", "answer": "The transformation of h to the power of i is equal to the intersection of the complement of c raised to the power of c.", "subset": "mixmath", "task_type": "tts"} +{"index": 219, "question": "Please read the following math formula symbols: $\\varepsilon_1\\in(0,1),\\kappa\\in\\NN^+$", "audio_path": "audio/row_01938930_1755826444216789.wav", "formula": "$\\varepsilon_1\\in(0,1),\\kappa\\in\\NN^+$", "answer": "Epsilon sub 1 belongs to the open interval from 0 to 1, kappa belongs to the set of natural numbers plus.", "subset": "mixmath", "task_type": "tts"} +{"index": 220, "question": "请你朗读以下数学公式符号:$32+\\overline{4B}+\\overline{A5}+76+89+9=251+\\overline{AB}=99\\times 3$", "audio_path": "audio/math_fa8ff55c-b623-4964-bd51-181c05491305.wav", "formula": "$32+\\overline{4B}+\\overline{A5}+76+89+9=251+\\overline{AB}=99\\times 3$", "answer": "三十二加两位数 四B 加 两位数A五加 七十六 加八十九加 九,等于二百五十一加 两位数AB ,等于九十九乘三", "subset": "mixmath", "task_type": "tts"} +{"index": 221, "question": "Please read the following math formula symbols: $\\sigma_{h}\\langle\\gamma\\rangle\\gtrsim\\gamma_{\\rmsyn}\\sim10^9$", "audio_path": "audio/row_01020142_1755710764188122.wav", "formula": "$\\sigma_{h}\\langle\\gamma\\rangle\\gtrsim\\gamma_{\\rmsyn}\\sim10^9$", "answer": "Sigma sub h, angle bracket gamma, greater than or equal to gamma sub syn, approximately equal to 10 to the power of 9.", "subset": "mixmath", "task_type": "tts"} +{"index": 222, "question": "请你朗读以下数学公式符号:$\\left\\{ \\begin{array}{*{35}{l}} 2x=3 \\\\ 3y=4 \\end{array} \\right.$", "audio_path": "audio/math_0522e40f-658f-4b22-8add-47d3428a6014.wav", "formula": "$\\left\\{ \\begin{array}{*{35}{l}} 2x=3 \\\\ 3y=4 \\end{array} \\right.$", "answer": "二x等于三,三y等于四", "subset": "mixmath", "task_type": "tts"} +{"index": 223, "question": "Please read the following math formula symbols: $0\\leqk_1,k_2\\leqq_{n+1}+1$", "audio_path": "audio/row_01258039_1755740534282747.wav", "formula": "$0\\leqk_1,k_2\\leqq_{n+1}+1$", "answer": "Zero less than or equal to k sub 1, k sub 2 less than or equal to q sub n plus 1 plus one.", "subset": "mixmath", "task_type": "tts"} +{"index": 224, "question": "Please read the following math formula symbols: $$\\|P_\\mu(f)\\|_1\\leq\\mu(\\Gamma)\\|f\\|_1.$$", "audio_path": "audio/row_01376056_1755755307912820.wav", "formula": "$$\\|P_\\mu(f)\\|_1\\leq\\mu(\\Gamma)\\|f\\|_1.$$", "answer": "The norm of P sub mu of f, sub 1, is less than or equal to mu of Gamma, times the norm of f sub 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 225, "question": "Please read the following math formula symbols: $\\overlineu=v^TC^{-1}$", "audio_path": "audio/row_01229676_1755736991056523.wav", "formula": "$\\overlineu=v^TC^{-1}$", "answer": "The vector u equals the product of velocity raised to the power of temperature and the inverse of the speed of light.", "subset": "mixmath", "task_type": "tts"} +{"index": 226, "question": "Please read the following math formula symbols: $\\sigma_h^2\\leq\\frac{M(N+1)}{M-1}m_h^2$", "audio_path": "audio/row_01786601_1755807195749488.wav", "formula": "$\\sigma_h^2\\leq\\frac{M(N+1)}{M-1}m_h^2$", "answer": "sigma sub h squared is less than or equal to M times N plus 1 divided by M minus 1 times m sub h squared.", "subset": "mixmath", "task_type": "tts"} +{"index": 227, "question": "Please read the following math formula symbols: $h^0(\\Ii_A(1,2))=2$", "audio_path": "audio/row_00195874_1755608824301876.wav", "formula": "$h^0(\\Ii_A(1,2))=2$", "answer": "h to the power of 0, the image of the set A under the function I sub A of 1, 2, equals 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 228, "question": "Please read the following math formula symbols: $\\lvertcM+dN\\rvert\\ggM^{-(d-1)}$", "audio_path": "audio/row_01703867_1755796707509585.wav", "formula": "$\\lvertcM+dN\\rvert\\ggM^{-(d-1)}$", "answer": "Absolute value of c times M plus d times N, much greater than M to the power of negative d minus 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 229, "question": "Please read the following math formula symbols: $E^n=(\\NN)^{\\ZZ_n^2}$", "audio_path": "audio/row_01651007_1755790054402406.wav", "formula": "$E^n=(\\NN)^{\\ZZ_n^2}$", "answer": "E to the power of n equals open parenthesis N times N close parenthesis to the power of Z times Z sub n squared.", "subset": "mixmath", "task_type": "tts"} +{"index": 230, "question": "Please read the following math formula symbols: $\\tau\\in\\{n_2,n_4,\\dots,n_{2k},n_{2k+1}\\}$", "audio_path": "audio/row_01267490_1755741699256356.wav", "formula": "$\\tau\\in\\{n_2,n_4,\\dots,n_{2k},n_{2k+1}\\}$", "answer": "Tau belongs to the set of n sub 2, n sub 4, dot dot dot, n sub 2k, n sub 2k plus 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 231, "question": "请你朗读以下数学公式符号:$$1\\times 5+2\\times 4+3\\times 3+4\\times 2+5\\times 1=35$$", "audio_path": "audio/math_d070a535-0ebf-4785-9aa8-bb8aad36d95f.wav", "formula": "$$1\\times 5+2\\times 4+3\\times 3+4\\times 2+5\\times 1=35$$", "answer": "一乘五加二乘四加三乘三加四乘二加五乘一等于三十五", "subset": "mixmath", "task_type": "tts"} +{"index": 232, "question": "请你朗读以下数学公式符号:$$ \\frac{2\\times 2022+1}{2\\times 2022}=\\frac{4045}{4044}$$", "audio_path": "audio/math_964482f6-d9cd-457f-9f8a-f791b0376493.wav", "formula": "$$ \\frac{2\\times 2022+1}{2\\times 2022}=\\frac{4045}{4044}$$", "answer": "二乘两千零二十二的积分之二乘二千零二十二加一等于四千零四十四分之四千零四十五", "subset": "mixmath", "task_type": "tts"} +{"index": 233, "question": "Please read the following math formula symbols: $\\bx=(x_{1},\\dots,x_{n})\\in\\cK$", "audio_path": "audio/row_01354851_1755752647466274.wav", "formula": "$\\bx=(x_{1},\\dots,x_{n})\\in\\cK$", "answer": "b times x equals open parenthesis x sub 1, dot dot dot, x sub n close parenthesis, belongs to c times K.", "subset": "mixmath", "task_type": "tts"} +{"index": 234, "question": "请你朗读以下数学公式符号:$=\\left( 4\\times 1111111 \\right)\\times \\left( 9\\times 11111111 \\right)$", "audio_path": "audio/math_70942b23-04f9-4a82-80b9-1328d9a8d9fb.wav", "formula": "$=\\left( 4\\times 1111111 \\right)\\times \\left( 9\\times 11111111 \\right)$", "answer": "等于四乘一百一十一万一千一百一十一的积乘九乘一千一百一十一万一千一百一十一的积", "subset": "mixmath", "task_type": "tts"} +{"index": 235, "question": "Please read the following math formula symbols: $(x^i_c,y_c=\\pi,z^i_c)$", "audio_path": "audio/row_01196131_1755732778079017.wav", "formula": "$(x^i_c,y_c=\\pi,z^i_c)$", "answer": "x raised to the power of i sub c, y sub c equals pi, z raised to the power of i sub c.", "subset": "mixmath", "task_type": "tts"} +{"index": 236, "question": "请你朗读以下数学公式符号:$\\begin{eqnarray}&&5.6+4.4\\times 4.4\\\\ &=&5.6+19.36 \\\\ &=&24.96\\end{eqnarray}$", "audio_path": "audio/math_099389e5-b5cd-4b11-afb0-a1ce1ac32647.wav", "formula": "$\\begin{eqnarray}&&5.6+4.4\\times 4.4\\\\ &=&5.6+19.36 \\\\ &=&24.96\\end{eqnarray}$", "answer": "五点六加四点四乘四点四等于五点六加十九点三六等于二十四点九六", "subset": "mixmath", "task_type": "tts"} +{"index": 237, "question": "请你朗读以下数学公式符号:$\\left[ 400\\div 5 \\right]+\\left[ 400\\div 25 \\right]+\\left[ 400\\div 125 \\right]=80+16+3=99$", "audio_path": "audio/math_b1d9ca6c-00b8-40e6-a349-3fabfa6cb097.wav", "formula": "$\\left[ 400\\div 5 \\right]+\\left[ 400\\div 25 \\right]+\\left[ 400\\div 125 \\right]=80+16+3=99$", "answer": "四百除以五的商加四百除以二十五的商加四百除以一百二十五的商等于八十加十六加三等于九十九", "subset": "mixmath", "task_type": "tts"} +{"index": 238, "question": "Please read the following math formula symbols: $\\Bar{t}_2=(m\\kappa_3+t_3)\\kappa_2\\kappa_1\\kappa_0$", "audio_path": "audio/row_01437998_1755763127447360.wav", "formula": "$\\Bar{t}_2=(m\\kappa_3+t_3)\\kappa_2\\kappa_1\\kappa_0$", "answer": "Bar t sub 2 equals open parenthesis m kappa sub 3 plus t sub 3 close parenthesis kappa sub 2 kappa sub 1 kappa sub 0", "subset": "mixmath", "task_type": "tts"} +{"index": 239, "question": "请你朗读以下数学公式符号:${{\\left( 10111 \\right)}_{2}}={{\\left( 23 \\right)}_{10}}$", "audio_path": "audio/math_b25501c7-aea9-4dfb-8663-95f344a986e0.wav", "formula": "${{\\left( 10111 \\right)}_{2}}={{\\left( 23 \\right)}_{10}}$", "answer": "二进制的一零一一一等于十进制的二十三", "subset": "mixmath", "task_type": "tts"} +{"index": 240, "question": "请你朗读以下数学公式符号:${{x}_{1}}\\cdot {{x}_{2}}=\\frac{1}{4}{{k}^{2}}+1>0$", "audio_path": "audio/math_29a28ab6-7259-438f-80cb-69097da8fb61.wav", "formula": "${{x}_{1}}\\cdot {{x}_{2}}=\\frac{1}{4}{{k}^{2}}+1>0$", "answer": "x一乘x二等于四分之一k的平方加一大于零", "subset": "mixmath", "task_type": "tts"} +{"index": 241, "question": "请你朗读以下数学公式符号:$299\\times 101>99\\times 299>298\\times 99>96\\times 298$", "audio_path": "audio/math_a1aa3674-caf4-42f6-b929-e864d6501ced.wav", "formula": "$299\\times 101>99\\times 299>298\\times 99>96\\times 298$", "answer": "二百九十九乘一百零一大于九十九乘二百九十九大于二百九十八乘九十九大于九十六乘二百九十八", "subset": "mixmath", "task_type": "tts"} +{"index": 242, "question": "Please read the following math formula symbols: $-1.46^{+0.019}_{+0.011}$", "audio_path": "audio/row_00508615_1755646994537836.wav", "formula": "$-1.46^{+0.019}_{+0.011}$", "answer": "Minus one point four six raised to the power of plus zero point zero one nine plus zero point zero one one.", "subset": "mixmath", "task_type": "tts"} +{"index": 243, "question": "请你朗读以下数学公式符号:$${{\\left( 101101 \\right)}_{2}}={{\\left( 45 \\right)}_{10}}$$", "audio_path": "audio/math_7324c5ca-a025-4d30-9820-2b66198662bf.wav", "formula": "$${{\\left( 101101 \\right)}_{2}}={{\\left( 45 \\right)}_{10}}$$", "answer": "二进制 一零一一零一等于十进制 四十五", "subset": "mixmath", "task_type": "tts"} +{"index": 244, "question": "请你朗读以下数学公式符号:$1.2x\\times 90+1.2\\times 0.8x\\times 10=100x+35200$", "audio_path": "audio/math_c0edd8b8-4b07-4af7-9abe-908bc49ecabc.wav", "formula": "$1.2x\\times 90+1.2\\times 0.8x\\times 10=100x+35200$", "answer": "一点二x乘九十加一点二乘零点八x乘十等于一百x加三万五千二百", "subset": "mixmath", "task_type": "tts"} +{"index": 245, "question": "Please read the following math formula symbols: $\\rho=\\sum_{k}p_k|\\alpha_k\\rangle\\langle\\alpha_k|$", "audio_path": "audio/row_01609169_1755784771050969.wav", "formula": "$\\rho=\\sum_{k}p_k|\\alpha_k\\rangle\\langle\\alpha_k|$", "answer": "Rho equals the sum over k of p sub k, multiplied by the ket alpha sub k, multiplied by the bra alpha sub k.", "subset": "mixmath", "task_type": "tts"} +{"index": 246, "question": "请你朗读以下数学公式符号:$\\frac{6}{7}\\times \\frac{8}{13}+ \\frac{8}{13}\\div 14$", "audio_path": "audio/math_20bf80ee-2c10-423e-bd90-6230be2f6e7b.wav", "formula": "$\\frac{6}{7}\\times \\frac{8}{13}+ \\frac{8}{13}\\div 14$", "answer": "七分之六乘十三分之八加十三分之八除以十四", "subset": "mixmath", "task_type": "tts"} +{"index": 247, "question": "请你朗读以下数学公式符号:$ {\\mathrm{x}}^{2}+\\mathrm{m}\\mathrm{x}+\\mathrm{n}=0$", "audio_path": "audio/math_5b05e8f4-c119-4c47-99f6-e60d30edd95a.wav", "formula": "$ {\\mathrm{x}}^{2}+\\mathrm{m}\\mathrm{x}+\\mathrm{n}=0$", "answer": "x的平方加m乘x加n等于零", "subset": "mixmath", "task_type": "tts"} +{"index": 248, "question": "Please read the following math formula symbols: $N_t\\sim\\mathcal{N}(\\mu=\\mu_b,\\sigmash^2=\\mu_b)$", "audio_path": "audio/row_01635420_1755788090051528.wav", "formula": "$N_t\\sim\\mathcal{N}(\\mu=\\mu_b,\\sigmash^2=\\mu_b)$", "answer": "N sub t is distributed as normal with mean mu equals mu sub b and variance sigma times sh squared equals mu sub b.", "subset": "mixmath", "task_type": "tts"} +{"index": 249, "question": "请你朗读以下数学公式符号:$\\frac{5\\%\\times 80+8\\%\\times 20}{80+20}\\times 100\\%=5.6\\%$", "audio_path": "audio/math_b776afc9-699a-4762-b29f-3ed4506eef71.wav", "formula": "$\\frac{5\\%\\times 80+8\\%\\times 20}{80+20}\\times 100\\%=5.6\\%$", "answer": "八十加二十的和分之百分之五乘八十与百分之八乘二十的和乘百分之百等于百分之五点六", "subset": "mixmath", "task_type": "tts"} +{"index": 250, "question": "Please read the following math formula symbols: $\\frac{||\\rho^{\\Gamma_A}||_1-1}{2}$", "audio_path": "audio/row_01715026_1755798126796106.wav", "formula": "$\\frac{||\\rho^{\\Gamma_A}||_1-1}{2}$", "answer": "Fraction, absolute value of rho to the power of Gamma sub A, absolute value sub 1 minus 1, divided by 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 251, "question": "请你朗读以下数学公式符号:$\\left\\{ \\begin{array}{*{35}{l}} x=\\dfrac{7}{3} \\\\ y=\\dfrac{2}{3} \\\\ \\end{array} \\right.$", "audio_path": "audio/math_b79c62cd-cee0-405b-9233-ed2520a8e6cb.wav", "formula": "$\\left\\{ \\begin{array}{*{35}{l}} x=\\dfrac{7}{3} \\\\ y=\\dfrac{2}{3} \\\\ \\end{array} \\right.$", "answer": "x等于三分之七,y等于三分之二", "subset": "mixmath", "task_type": "tts"} +{"index": 252, "question": "Please read the following math formula symbols: $g^i\\in\\partialf(x^i)$", "audio_path": "audio/row_01714483_1755798057771474.wav", "formula": "$g^i\\in\\partialf(x^i)$", "answer": "g raised to the power of i belongs to the boundary of f of x raised to the power of i.", "subset": "mixmath", "task_type": "tts"} +{"index": 253, "question": "Please read the following math formula symbols: $\\{Z'u:\\|u\\|_q=1,\\:u\\in\\mathbb{R}^d\\}$", "audio_path": "audio/row_01579211_1755780973739988.wav", "formula": "$\\{Z'u:\\|u\\|_q=1,\\:u\\in\\mathbb{R}^d\\}$", "answer": "Set Z prime u, norm of u subscript q equals 1, u in the set of real numbers raised to the power of d.", "subset": "mixmath", "task_type": "tts"} +{"index": 254, "question": "Please read the following math formula symbols: $N_i(N_i-1)(N_i-2)\\Omega_{ij}^3$", "audio_path": "audio/row_00063577_1755592822527684.wav", "formula": "$N_i(N_i-1)(N_i-2)\\Omega_{ij}^3$", "answer": "N sub i times N sub i minus 1 times N sub i minus 2 times omega sub i j cubed.", "subset": "mixmath", "task_type": "tts"} +{"index": 255, "question": "Please read the following math formula symbols: $P(T_\\ball<\\infty|\\,|x|=r)=r^{-(d-\\alpha)}$", "audio_path": "audio/row_01948680_1755827684628366.wav", "formula": "$P(T_\\ball<\\infty|\\,|x|=r)=r^{-(d-\\alpha)}$", "answer": "P of T given the absolute value of x equals r equals r to the power of negative d minus alpha.", "subset": "mixmath", "task_type": "tts"} +{"index": 256, "question": "Please read the following math formula symbols: $\\p_{F1}=-\\p_{F2}=-\\p_{F3}=\\p_{F4}$", "audio_path": "audio/row_01288909_1755744407132415.wav", "formula": "$\\p_{F1}=-\\p_{F2}=-\\p_{F3}=\\p_{F4}$", "answer": "p sub F 1 equals negative p sub F 2 equals negative p sub F 3 equals p sub F 4", "subset": "mixmath", "task_type": "tts"} +{"index": 257, "question": "请你朗读以下数学公式符号:$$\\left( \\frac{4}{5}+\\frac{2}{15} \\right)\\times \\frac{5}{16}=\\frac{4}{5}+\\frac{2}{15}\\times \\frac{5}{16}$$", "audio_path": "audio/math_b5fae075-618b-47a9-b2d5-e05f9d03d6fb.wav", "formula": "$$\\left( \\frac{4}{5}+\\frac{2}{15} \\right)\\times \\frac{5}{16}=\\frac{4}{5}+\\frac{2}{15}\\times \\frac{5}{16}$$", "answer": "五分之四加十五分之二的和乘十六分之五等于五分之四加十五分之二乘十六分之五", "subset": "mixmath", "task_type": "tts"} +{"index": 258, "question": "Please read the following math formula symbols: $1\\leq_1,q_2\\le\\infty$", "audio_path": "audio/row_00023461_1755587955359379.wav", "formula": "$1\\leq_1,q_2\\le\\infty$", "answer": "One is less than or equal to q sub 1, comma q sub 2, which are both less than or equal to infinity.", "subset": "mixmath", "task_type": "tts"} +{"index": 259, "question": "Please read the following math formula symbols: $\\Pf_{1\\lei2m+1 \\\\ & x>m+2 \\\\ \\end{align} \\right.$$", "audio_path": "audio/math_2008a3f5-a7c2-4e88-8f8c-86052611a2b7.wav", "formula": "$$\\left\\{ \\begin{align} & x>2m+1 \\\\ & x>m+2 \\\\ \\end{align} \\right.$$", "answer": "x大于二m加一,x大于m加二", "subset": "mixmath", "task_type": "tts"} +{"index": 343, "question": "请你朗读以下数学公式符号:$$3\\div 8=\\frac {3}{8}=0.375=9\\div 24=\\frac {36}{96}$$", "audio_path": "audio/math_f14ca209-737c-4017-b0dc-a0b67e2943c2.wav", "formula": "$$3\\div 8=\\frac {3}{8}=0.375=9\\div 24=\\frac {36}{96}$$", "answer": "三除以八等于八分之三等于零点三七五等于九除以二十四等于九十六分之三十六", "subset": "mixmath", "task_type": "tts"} +{"index": 344, "question": "Please read the following math formula symbols: $\\smash{\\pi_0\\,\\widetilde{\\Homeo}^+(T^d)}\\ra\\SL_d(\\bfZ)$", "audio_path": "audio/row_01023443_1755711172748459.wav", "formula": "$\\smash{\\pi_0\\,\\widetilde{\\Homeo}^+(T^d)}\\ra\\SL_d(\\bfZ)$", "answer": "Pi sub zero tilde Home plus T to the power of d, ra, S L sub d open parenthesis Z close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 345, "question": "Please read the following math formula symbols: $AVDHLA(K,N_1,...,N_i,...,N_K,\\lambda_1,\\lambda_2)$", "audio_path": "audio/row_00637952_1755663021148116.wav", "formula": "$AVDHLA(K,N_1,...,N_i,...,N_K,\\lambda_1,\\lambda_2)$", "answer": "AVRA of K, N sub 1, dot dot dot, N sub i, dot dot dot, N sub K, lambda sub 1, lambda sub 2", "subset": "mixmath", "task_type": "tts"} +{"index": 346, "question": "请你朗读以下数学公式符号:$$5\\frac{5}{8}\\times \\frac{2}{3}\\div 2\\frac{1}{2}$$", "audio_path": "audio/math_4fb92e21-580d-4c56-9294-847e51c05aa6.wav", "formula": "$$5\\frac{5}{8}\\times \\frac{2}{3}\\div 2\\frac{1}{2}$$", "answer": "五又八分之五乘三分之二除以二又二分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 347, "question": "Please read the following math formula symbols: $\\max_{x\\in\\mathbb{R}}\\frac{\\ALGW(\\I,x)}{\\OPTW(\\I)}$", "audio_path": "audio/row_00211188_1755610713087826.wav", "formula": "$\\max_{x\\in\\mathbb{R}}\\frac{\\ALGW(\\I,x)}{\\OPTW(\\I)}$", "answer": "Maximize over x in the set of real numbers, the fraction of ALGW of I and x divided by OPTW of I.", "subset": "mixmath", "task_type": "tts"} +{"index": 348, "question": "请你朗读以下数学公式符号:$\\frac{3}{5}\\times 26+\\frac{3}{5}\\times 31+\\frac{3}{5}\\times 43$", "audio_path": "audio/math_00e314b8-0a24-488e-b8fa-f0f7eb76d405.wav", "formula": "$\\frac{3}{5}\\times 26+\\frac{3}{5}\\times 31+\\frac{3}{5}\\times 43$", "answer": "五分之三乘二十六加五分之三乘三十一加五分之三乘四十三", "subset": "mixmath", "task_type": "tts"} +{"index": 349, "question": "Please read the following math formula symbols: $\\miu^1:=\\miu^++\\miu^{\\dagger,-}$", "audio_path": "audio/row_01417357_1755760509442519.wav", "formula": "$\\miu^1:=\\miu^++\\miu^{\\dagger,-}$", "answer": "M u to the power of 1 is equal to M u to the power of plus plus M u dagger, minus.", "subset": "mixmath", "task_type": "tts"} +{"index": 350, "question": "Please read the following math formula symbols: $\\rH(\\bm\\{p)=-\\sum_{i=1}^Np_i\\logp_i$", "audio_path": "audio/row_01314305_1755747544537017.wav", "formula": "$\\rH(\\bm\\{p)=-\\sum_{i=1}^Np_i\\logp_i$", "answer": "The H of p is equal to negative summation from i equals 1 to N of p sub i times the logarithm of p sub i.", "subset": "mixmath", "task_type": "tts"} +{"index": 351, "question": "Please read the following math formula symbols: $M_{\\rmv}>10^{11}h^{-1}{\\rmM}_\\odot$", "audio_path": "audio/row_01890166_1755820279876019.wav", "formula": "$M_{\\rmv}>10^{11}h^{-1}{\\rmM}_\\odot$", "answer": "M sub v is greater than 10 to the power of 11 h to the power of negative 1 M sub solar mass.", "subset": "mixmath", "task_type": "tts"} +{"index": 352, "question": "请你朗读以下数学公式符号:$\\frac{{{2}^{2}}+{{3}^{2}}}{2\\times 3}=\\frac{13}{6}=2\\frac{1}{6}$", "audio_path": "audio/math_0f12cb35-53ba-4ddb-a182-de1fe401e05c.wav", "formula": "$\\frac{{{2}^{2}}+{{3}^{2}}}{2\\times 3}=\\frac{13}{6}=2\\frac{1}{6}$", "answer": "二乘三的积分之二的平方加三的平方的和等于六分之十三等于二又六分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 353, "question": "请你朗读以下数学公式符号:$\\frac{2}{5}\\div 8=\\frac{2}{5}\\times \\frac{1}{8}=\\frac{1}{20}$", "audio_path": "audio/math_140c340c-2c7c-4dcc-8d90-313d0a1b4c0a.wav", "formula": "$\\frac{2}{5}\\div 8=\\frac{2}{5}\\times \\frac{1}{8}=\\frac{1}{20}$", "answer": "五分之二除以八等于五分之二乘八分之一等于二十分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 354, "question": "请你朗读以下数学公式符号:$=8\\left( \\frac{1}{2009}+\\frac{1}{2011} \\right)\\div 4\\left( \\frac{1}{2009}+\\frac{1}{2011} \\right)$", "audio_path": "audio/math_f5289493-ded4-47e6-a637-92a9318170a7.wav", "formula": "$=8\\left( \\frac{1}{2009}+\\frac{1}{2011} \\right)\\div 4\\left( \\frac{1}{2009}+\\frac{1}{2011} \\right)$", "answer": "等于八倍的两千零九分之一加两千零一十一分之一除以四倍的两千零九分之一加两千零一十一分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 355, "question": "请你朗读以下数学公式符号:$\\left\\{ \\begin{aligned} & a=1 \\\\ & b=0 \\end{aligned} \\right.$", "audio_path": "audio/math_2c9a11c6-de33-4f45-a864-7bc588b0c1af.wav", "formula": "$\\left\\{ \\begin{aligned} & a=1 \\\\ & b=0 \\end{aligned} \\right.$", "answer": "a等于一,b等于零", "subset": "mixmath", "task_type": "tts"} +{"index": 356, "question": "请你朗读以下数学公式符号:$$\\begin{eqnarray}&=&\\left( \\frac{5}{7}+\\frac{2}{7} \\right)+\\left( \\frac{3}{8}+\\frac{5}{8} \\right)\\end{eqnarray}$$", "audio_path": "audio/math_ef1ef9b1-0d53-42b1-ad23-3b5dd2cb760f.wav", "formula": "$$\\begin{eqnarray}&=&\\left( \\frac{5}{7}+\\frac{2}{7} \\right)+\\left( \\frac{3}{8}+\\frac{5}{8} \\right)\\end{eqnarray}$$", "answer": "等于七分之五加七分之二的和加八分之三加八分之五的和", "subset": "mixmath", "task_type": "tts"} +{"index": 357, "question": "请你朗读以下数学公式符号:$=\\frac{{x}_{1}+{x}_{2}}{{x}_{1}{x}_{2}}=\\frac{4}{3}$", "audio_path": "audio/math_b939a468-f5ed-43e9-9d79-40d54cc221de.wav", "formula": "$=\\frac{{x}_{1}+{x}_{2}}{{x}_{1}{x}_{2}}=\\frac{4}{3}$", "answer": "等于x 一乘x 二的积分之x 一加x 二的和等于三分之四", "subset": "mixmath", "task_type": "tts"} +{"index": 358, "question": "Please read the following math formula symbols: ${\\calD}^{[1]}_2\\backslash{\\calD}^{[1]}_1$", "audio_path": "audio/row_02025937_1755837422578197.wav", "formula": "${\\calD}^{[1]}_2\\backslash{\\calD}^{[1]}_1$", "answer": "cal D raised to the power of one, subscript 2, backslash cal D raised to the power of one, subscript 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 359, "question": "请你朗读以下数学公式符号:$120\\times \\left( \\frac{1}{5}+\\frac{5}{24} \\right)=49$", "audio_path": "audio/math_1c806e6a-769a-4285-9d83-d8ef53e52f2e.wav", "formula": "$120\\times \\left( \\frac{1}{5}+\\frac{5}{24} \\right)=49$", "answer": "一百二十乘五分之一加二十四分之五的和等于四十九", "subset": "mixmath", "task_type": "tts"} +{"index": 360, "question": "请你朗读以下数学公式符号:$$\\begin{eqnarray}10:8&=&x:10\\\\ 8x&=&100\\\\ x&=&12.5\\end{eqnarray}$$", "audio_path": "audio/math_e8649d55-1376-4fbe-9c90-70c178aeadda.wav", "formula": "$$\\begin{eqnarray}10:8&=&x:10\\\\ 8x&=&100\\\\ x&=&12.5\\end{eqnarray}$$", "answer": "十比八等于x比十;八x等于一百;x等于十二点五", "subset": "mixmath", "task_type": "tts"} +{"index": 361, "question": "Please read the following math formula symbols: $X_\\ell\\cupX_\\ell'\\cupY^\\ell\\cupZ^\\ell$", "audio_path": "audio/row_01494618_1755770280277563.wav", "formula": "$X_\\ell\\cupX_\\ell'\\cupY^\\ell\\cupZ^\\ell$", "answer": "X sub L union X sub L prime union Y to the power of L union Z to the power of L.", "subset": "mixmath", "task_type": "tts"} +{"index": 362, "question": "Please read the following math formula symbols: $\\NN_j:=\\{n_i^j\\}_{i\\inP_j}$", "audio_path": "audio/row_00933937_1755699999712003.wav", "formula": "$\\NN_j:=\\{n_i^j\\}_{i\\inP_j}$", "answer": "N sub j is defined as the set of n sub i to the power of j, where i belongs to P sub j.", "subset": "mixmath", "task_type": "tts"} +{"index": 363, "question": "请你朗读以下数学公式符号:$\\begin{eqnarray}4x+20&=&2\\left( x+20 \\right)\\\\ 4x+20&=&2x+40\\\\ 2x&=&20\\\\ x&=&10\\end{eqnarray}$", "audio_path": "audio/math_f901d78a-85da-49cd-be27-d52e5e06a7a5.wav", "formula": "$\\begin{eqnarray}4x+20&=&2\\left( x+20 \\right)\\\\ 4x+20&=&2x+40\\\\ 2x&=&20\\\\ x&=&10\\end{eqnarray}$", "answer": "四x加二十等于二乘x加二十的和\n四x加二十等于二x加四十\n二x等于二十\nx等于十", "subset": "mixmath", "task_type": "tts"} +{"index": 364, "question": "请你朗读以下数学公式符号:$\\left(\\dfrac{1}{3}\\right)^2+\\dfrac{1}{\\left(\\dfrac{1}{3}\\right)^2}=9+\\dfrac{1}{9}=\\dfrac{82}{9}$", "audio_path": "audio/math_a4e8d398-b8aa-48a6-961a-c41d38c22a3e.wav", "formula": "$\\left(\\dfrac{1}{3}\\right)^2+\\dfrac{1}{\\left(\\dfrac{1}{3}\\right)^2}=9+\\dfrac{1}{9}=\\dfrac{82}{9}$", "answer": "三分之一的平方加三分之一的平方分之一等于九加九分之一等于九分之八十二", "subset": "mixmath", "task_type": "tts"} +{"index": 365, "question": "Please read the following math formula symbols: $\\rbr*{1-\\frac{\\mu\\gamma\\alpha}{2}}\\w_t=\\w_{t-1}$", "audio_path": "audio/row_01874098_1755818266532211.wav", "formula": "$\\rbr*{1-\\frac{\\mu\\gamma\\alpha}{2}}\\w_t=\\w_{t-1}$", "answer": "r b r times one minus the fraction mu gamma alpha over two times w sub t equals w sub t minus one.", "subset": "mixmath", "task_type": "tts"} +{"index": 366, "question": "Please read the following math formula symbols: $\\homs(F,\\ccfi(G_1))=\\homs(F,\\ccfitwist(G_1))$", "audio_path": "audio/row_01682715_1755794054958177.wav", "formula": "$\\homs(F,\\ccfi(G_1))=\\homs(F,\\ccfitwist(G_1))$", "answer": "hom s of F, cosine fi of G sub 1, equals hom s of F, cotangent w of G sub 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 367, "question": "Please read the following math formula symbols: $\\phi':=z\\cdot\\phi=(z\\cdot\\varphi(z)dz^3,z\\cdot\\theta)$", "audio_path": "audio/row_01846745_1755814786101194.wav", "formula": "$\\phi':=z\\cdot\\phi=(z\\cdot\\varphi(z)dz^3,z\\cdot\\theta)$", "answer": "Phi prime equals z times phi equals open parenthesis z times varphi of z d z cubed, z times theta close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 368, "question": "Please read the following math formula symbols: $\\{(j_{t},\\Contextjkt):t\\in[T]\\}$", "audio_path": "audio/row_00566186_1755654056926216.wav", "formula": "$\\{(j_{t},\\Contextjkt):t\\in[T]\\}$", "answer": "Open brace, open parenthesis, j sub t, comma, Congruent to j k t, close parenthesis, colon, t belongs to the set of T.", "subset": "mixmath", "task_type": "tts"} +{"index": 369, "question": "请你朗读以下数学公式符号:$=\\sum\\limits_{{{t}_{1}}=1}^{9}{\\sum\\limits_{{{t}_{2}}=0}^{9}{\\sum\\limits_{{{t}_{3}}=0}^{9}{\\sum\\limits_{{{t}_{4}}=0}^{9}{{{x}^{{{t}_{1}}+{{t}_{2}}+{{t}_{3}}+{{t}_{4}}}}}}}}$", "audio_path": "audio/math_7a83b600-ba40-46bc-a4fb-1a5911afbefe.wav", "formula": "$=\\sum\\limits_{{{t}_{1}}=1}^{9}{\\sum\\limits_{{{t}_{2}}=0}^{9}{\\sum\\limits_{{{t}_{3}}=0}^{9}{\\sum\\limits_{{{t}_{4}}=0}^{9}{{{x}^{{{t}_{1}}+{{t}_{2}}+{{t}_{3}}+{{t}_{4}}}}}}}}$", "answer": "对于t 一从一到九,t 二从零到九,t 三从零到九, t 四从零到九,关于x 的 t 一加 t 二加 t 三加 t 四 次方 求和", "subset": "mixmath", "task_type": "tts"} +{"index": 370, "question": "Please read the following math formula symbols: $A_1=|1-\\DeltatA_1^{'}|+\\DeltatA_{1}^{``},$", "audio_path": "audio/row_00810004_1755684484963788.wav", "formula": "$A_1=|1-\\DeltatA_1^{'}|+\\DeltatA_{1}^{``},$", "answer": "A sub 1 equals the absolute value of 1 minus delta t times A sub 1 prime, plus delta t times A sub 1 tilde.", "subset": "mixmath", "task_type": "tts"} +{"index": 371, "question": "Please read the following math formula symbols: $|H_p|=|H_{tt}+H_{vt}|$", "audio_path": "audio/row_01659362_1755791109109485.wav", "formula": "$|H_p|=|H_{tt}+H_{vt}|$", "answer": "The absolute value of H sub p equals the absolute value of H sub t t plus H sub v t.", "subset": "mixmath", "task_type": "tts"} +{"index": 372, "question": "Please read the following math formula symbols: $\\hat{X}^\\mu=x^\\mu-\\hat{z}^\\mu$", "audio_path": "audio/row_01479330_1755768350822270.wav", "formula": "$\\hat{X}^\\mu=x^\\mu-\\hat{z}^\\mu$", "answer": "Hat X to the power of mu equals x to the power of mu minus hat z to the power of mu.", "subset": "mixmath", "task_type": "tts"} +{"index": 373, "question": "Please read the following math formula symbols: $A=\\{\\xtpf,p_1,p_2,$", "audio_path": "audio/row_00444754_1755639154909184.wav", "formula": "$A=\\{\\xtpf,p_1,p_2,$", "answer": "A equals open curly brace x sub t p f comma p sub 1 comma p sub 2 comma close curly brace.", "subset": "mixmath", "task_type": "tts"} +{"index": 374, "question": "Please read the following math formula symbols: $(g^S_{u_{33}},g^P_{u_{33}})$", "audio_path": "audio/row_01408948_1755759446007226.wav", "formula": "$(g^S_{u_{33}},g^P_{u_{33}})$", "answer": "Open parenthesis, g to the power of S sub u sub 33, comma, g to the power of P sub u sub 33, close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 375, "question": "请你朗读以下数学公式符号:$\\frac{{{x}^{2}}}{{{x}^{4}}+{{x}^{2}}+1}=\\frac{1}{{{x}^{2}}+1+\\frac{1}{{{x}^{2}}}}=\\frac{1}{8}$", "audio_path": "audio/math_4e57baac-ab68-421b-80fa-4467f20c2d38.wav", "formula": "$\\frac{{{x}^{2}}}{{{x}^{4}}+{{x}^{2}}+1}=\\frac{1}{{{x}^{2}}+1+\\frac{1}{{{x}^{2}}}}=\\frac{1}{8}$", "answer": "x四次方加x平方加一的和分之x平方等于x平方加一加x平方分之一的和分之一等于八分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 376, "question": "请你朗读以下数学公式符号:$\\frac{\\sqrt{6}+\\sqrt{8}}{2}=\\frac{\\sqrt{6}}{2}+\\sqrt{2}\\ne \\sqrt{3}+2$", "audio_path": "audio/math_0bb26bf0-13af-449c-b5c8-15f91a6cfbd7.wav", "formula": "$\\frac{\\sqrt{6}+\\sqrt{8}}{2}=\\frac{\\sqrt{6}}{2}+\\sqrt{2}\\ne \\sqrt{3}+2$", "answer": "二分之根号六加根号八的和等于二分之根号六加根号二不等于根号三加二", "subset": "mixmath", "task_type": "tts"} +{"index": 377, "question": "请你朗读以下数学公式符号:$0.8\\times \\left( 7.2+x \\right)\\div 0.8=7.92\\div 0.8$", "audio_path": "audio/math_bfd59c76-1ba6-4efc-9b16-db901fd5ff81.wav", "formula": "$0.8\\times \\left( 7.2+x \\right)\\div 0.8=7.92\\div 0.8$", "answer": "零点八乘七点二加x的和除以零点八等于七点九二除以零点八", "subset": "mixmath", "task_type": "tts"} +{"index": 378, "question": "请你朗读以下数学公式符号:$\\begin{cases}k\\equiv 5 & \\left( \\bmod 7 \\right) \\\\ k\\equiv 9 & \\left( \\bmod 11 \\right) \\\\ k\\equiv 12 & \\left( \\bmod 13 \\right) \\end{cases}$", "audio_path": "audio/math_b853bc85-c9f6-429e-9ed4-678cb87be97f.wav", "formula": "$\\begin{cases}k\\equiv 5 & \\left( \\bmod 7 \\right) \\\\ k\\equiv 9 & \\left( \\bmod 11 \\right) \\\\ k\\equiv 12 & \\left( \\bmod 13 \\right) \\end{cases}$", "answer": "k同余于五模七,k同余于九模十一,k同余于十二模十三", "subset": "mixmath", "task_type": "tts"} +{"index": 379, "question": "Please read the following math formula symbols: $g_0\\big(\\y0,\\hat\\gamma_1(\\y0)\\big)$", "audio_path": "audio/row_00168075_1755605450380082.wav", "formula": "$g_0\\big(\\y0,\\hat\\gamma_1(\\y0)\\big)$", "answer": "g sub 0 open parenthesis y sub 0 comma gamma hat sub 1 open parenthesis y sub 0 close parenthesis close parenthesis", "subset": "mixmath", "task_type": "tts"} +{"index": 380, "question": "请你朗读以下数学公式符号:$\\frac{x+24}{1.2y}=\\frac{0.5x}{y}+\\frac{0.5x}{1+y}$", "audio_path": "audio/math_4882d64b-1c3d-4cb9-9d95-86b75d2308ab.wav", "formula": "$\\frac{x+24}{1.2y}=\\frac{0.5x}{y}+\\frac{0.5x}{1+y}$", "answer": "一点二 y 分之 x 加二十四的和 等于 y 分之零点五 x 加上 一加y 的和分之零点五 x", "subset": "mixmath", "task_type": "tts"} +{"index": 381, "question": "请你朗读以下数学公式符号:$$=\\sqrt{{{x}^{3}}y\\cdot \\frac{5}{{{x}^{2}}y}}=\\sqrt{5x}$$", "audio_path": "audio/math_3b6e838a-f699-4316-9d67-c1143ebdef81.wav", "formula": "$$=\\sqrt{{{x}^{3}}y\\cdot \\frac{5}{{{x}^{2}}y}}=\\sqrt{5x}$$", "answer": "等于根号下x的三次方y乘x的平方y分之五的积等于根号下五x", "subset": "mixmath", "task_type": "tts"} +{"index": 382, "question": "请你朗读以下数学公式符号:$AB=\\sqrt{\\left(m+m\\right)^{2}+\\left(m^{2}+m^{2}\\right)^{2}}=2\\sqrt{m^{2}+m^{4}}$", "audio_path": "audio/math_30e48a85-b203-44b9-be2c-5b014877570d.wav", "formula": "$AB=\\sqrt{\\left(m+m\\right)^{2}+\\left(m^{2}+m^{2}\\right)^{2}}=2\\sqrt{m^{2}+m^{4}}$", "answer": "AB等于根号下m加m的和的平方加上m平方加m平方的和的平方等于二倍的根号下m平方加m的四次方", "subset": "mixmath", "task_type": "tts"} +{"index": 383, "question": "请你朗读以下数学公式符号:$$\\left( \\frac{4}{7}+\\frac{2}{9} \\right)\\times 7\\times 9$$", "audio_path": "audio/math_edb5c3de-6ccd-40cf-8fcf-e1858c116d0a.wav", "formula": "$$\\left( \\frac{4}{7}+\\frac{2}{9} \\right)\\times 7\\times 9$$", "answer": "七分之四与九分之二的和乘七乘九", "subset": "mixmath", "task_type": "tts"} +{"index": 384, "question": "请你朗读以下数学公式符号:$=\\frac{2}{3}\\times \\left[ \\frac{1}{4}\\times \\frac{4}{5} \\right]$", "audio_path": "audio/math_e91eb591-4c9e-4077-bfd1-66351a362f90.wav", "formula": "$=\\frac{2}{3}\\times \\left[ \\frac{1}{4}\\times \\frac{4}{5} \\right]$", "answer": "等于三分之二乘括号四分之一乘五分之四括号", "subset": "mixmath", "task_type": "tts"} +{"index": 385, "question": "Please read the following math formula symbols: $u'\\inQ[1,|G^\\prec_\\dashv(p(\\alpha,|\\alpha|-k))|]$", "audio_path": "audio/row_00633821_1755662504449239.wav", "formula": "$u'\\inQ[1,|G^\\prec_\\dashv(p(\\alpha,|\\alpha|-k))|]$", "answer": "u prime belongs to Q of 1, absolute value of G subscript dash v of p of alpha, absolute value of alpha minus k.", "subset": "mixmath", "task_type": "tts"} +{"index": 386, "question": "Please read the following math formula symbols: $q_k^2x\\end{array}\\right.$", "audio_path": "audio/math_34d1b633-ada5-4256-a8e5-beaec12d1502.wav", "formula": "$\\left\\{\\begin{array}{c}2(x+3)\\leqslant 4x+7\\\\ \\frac{x+2}{2}>x\\end{array}\\right.$", "answer": "二倍的x加三小于等于四x加七,二分之x加二的和大于x", "subset": "mixmath", "task_type": "tts"} +{"index": 462, "question": "请你朗读以下数学公式符号:$m\\div 25 < \\left( m\\times 5 \\right)\\div \\left( 35\\div 5 \\right)$", "audio_path": "audio/math_06673c8f-79d9-48c6-b4e2-97b9a67258c1.wav", "formula": "$m\\div 25 < \\left( m\\times 5 \\right)\\div \\left( 35\\div 5 \\right)$", "answer": "m除以二十五小于m乘五的积除以三十五除以五的商", "subset": "mixmath", "task_type": "tts"} +{"index": 463, "question": "请你朗读以下数学公式符号:$\\begin{cases}3a+2b=1 \\\\ 7a+5b=3 \\\\ a+b=1 \\end{cases}$", "audio_path": "audio/math_bf1d2734-fef6-4be2-9d06-a00e4792a09e.wav", "formula": "$\\begin{cases}3a+2b=1 \\\\ 7a+5b=3 \\\\ a+b=1 \\end{cases}$", "answer": "三a加二b等于一,七a加五b等于三,a加b等于一。", "subset": "mixmath", "task_type": "tts"} +{"index": 464, "question": "请你朗读以下数学公式符号:$$\\left\\{ \\begin{align} & 5x+3y=k+2 \\\\ & 3x+2y=k \\\\ \\end{align} \\right.$$", "audio_path": "audio/math_e16729e7-3df7-4aa5-a933-fc93c3e2e590.wav", "formula": "$$\\left\\{ \\begin{align} & 5x+3y=k+2 \\\\ & 3x+2y=k \\\\ \\end{align} \\right.$$", "answer": "五x加三y等于k加二;三x加二y等于k", "subset": "mixmath", "task_type": "tts"} +{"index": 465, "question": "请你朗读以下数学公式符号:$\\frac{1}{9}\\left\\{ \\frac{x+2}{105}+\\frac{4}{35}+\\frac{6}{7}+8 \\right\\}=1$", "audio_path": "audio/math_3c7fb53d-2d7d-4d8a-b920-01da41dc1fe2.wav", "formula": "$\\frac{1}{9}\\left\\{ \\frac{x+2}{105}+\\frac{4}{35}+\\frac{6}{7}+8 \\right\\}=1$", "answer": "九分之一 乘 一百零五分之 x加二的和 与 三十五分之四 与 七分之六 与 八的和 等于一", "subset": "mixmath", "task_type": "tts"} +{"index": 466, "question": "Please read the following math formula symbols: $\\psi'(x;d)\\leq\\psi(x+d)-\\psi(x).$", "audio_path": "audio/row_00678800_1755668068181150.wav", "formula": "$\\psi'(x;d)\\leq\\psi(x+d)-\\psi(x).$", "answer": "Psi prime of x, semicolon d, is less than or equal to psi of x plus d, minus psi of x.", "subset": "mixmath", "task_type": "tts"} +{"index": 467, "question": "请你朗读以下数学公式符号:$$=7.8\\times \\left( 24+71+5 \\right)=7.8\\times 100=780$$", "audio_path": "audio/math_cb458fcd-75f4-4539-8b7e-069c80f78e9d.wav", "formula": "$$=7.8\\times \\left( 24+71+5 \\right)=7.8\\times 100=780$$", "answer": "等于七点八乘二十四加七十一加五的和,等于七点八乘一百,等于七百八十", "subset": "mixmath", "task_type": "tts"} +{"index": 468, "question": "Please read the following math formula symbols: $\\rho_E\\coloneqq\\sum_{x}P(X=x)\\rho_E^x$", "audio_path": "audio/row_00598260_1755658054048874.wav", "formula": "$\\rho_E\\coloneqq\\sum_{x}P(X=x)\\rho_E^x$", "answer": "Rho sub E is defined as the sum over x of P of X equals x times Rho sub E to the power of x.", "subset": "mixmath", "task_type": "tts"} +{"index": 469, "question": "请你朗读以下数学公式符号:$\\therefore\\begin{cases}{{x}_{1}}+1=m \\\\ {{x}_{1}}\\cdot 1=2m \\end{cases}$", "audio_path": "audio/math_b8fa63ba-17e0-4065-a103-1aa7c5e0d8ab.wav", "formula": "$\\therefore\\begin{cases}{{x}_{1}}+1=m \\\\ {{x}_{1}}\\cdot 1=2m \\end{cases}$", "answer": "所以,x一加一等于m,x一乘一等于二m。", "subset": "mixmath", "task_type": "tts"} +{"index": 470, "question": "Please read the following math formula symbols: $$G^2-1,\\H^2-1,\\X^2,\\GX+XG,\\HX+XH,\\GH-HG\\,.$$", "audio_path": "audio/row_01612373_1755785182540297.wav", "formula": "$$G^2-1,\\H^2-1,\\X^2,\\GX+XG,\\HX+XH,\\GH-HG\\,.$$", "answer": "G squared minus one, H squared minus one, X squared, G X plus X G, H X plus X H, G minus HG.", "subset": "mixmath", "task_type": "tts"} +{"index": 471, "question": "请你朗读以下数学公式符号:$\\frac{1}{10} \\times 8+\\frac{1}{30}\\times 2=\\frac{13}{15}$", "audio_path": "audio/math_f7938a23-c23e-4c80-8082-49279bbfe4b2.wav", "formula": "$\\frac{1}{10} \\times 8+\\frac{1}{30}\\times 2=\\frac{13}{15}$", "answer": "十分之一乘八加三十分之一乘二等于十五分之十三", "subset": "mixmath", "task_type": "tts"} +{"index": 472, "question": "请你朗读以下数学公式符号:$\\left[1−\\left(\\frac{1}{2}−\\frac{1}{4}\\right)\\right]÷\\frac{2}{3}$", "audio_path": "audio/math_24435136-b4ce-4084-8c91-5e927e5d5780.wav", "formula": "$\\left[1−\\left(\\frac{1}{2}−\\frac{1}{4}\\right)\\right]÷\\frac{2}{3}$", "answer": "一减去 二分之一减四分之一的差 的差再除以三分之二", "subset": "mixmath", "task_type": "tts"} +{"index": 473, "question": "Please read the following math formula symbols: $U^{\\mathcalR}(W)\\in\\mathcalR^r(\\mathrm{Th}(X;W))$", "audio_path": "audio/row_01668787_1755792304942652.wav", "formula": "$U^{\\mathcalR}(W)\\in\\mathcalR^r(\\mathrm{Th}(X;W))$", "answer": "U raised to the power of R of W belongs to R to the power of r of Th of X semicolon W.", "subset": "mixmath", "task_type": "tts"} +{"index": 474, "question": "请你朗读以下数学公式符号:$1\\times 2\\times 3\\times 4\\times 5\\times 6\\times 7\\times 8\\times 9\\times 0$", "audio_path": "audio/math_14ba59f1-16aa-4eb2-8dfe-ae68182e464c.wav", "formula": "$1\\times 2\\times 3\\times 4\\times 5\\times 6\\times 7\\times 8\\times 9\\times 0$", "answer": "一乘二乘三乘四乘五乘六乘七乘八乘九乘零", "subset": "mixmath", "task_type": "tts"} +{"index": 475, "question": "请你朗读以下数学公式符号:$AB=\\sqrt{A{{C}^{2}}+B{{C}^{2}}}=\\sqrt{{{\\left( 5k \\right)}^{2}}+{{\\left( 12k \\right)}^{2}}}=13k$", "audio_path": "audio/math_74cc49b2-72a7-439f-9691-72a8a39d2ed6.wav", "formula": "$AB=\\sqrt{A{{C}^{2}}+B{{C}^{2}}}=\\sqrt{{{\\left( 5k \\right)}^{2}}+{{\\left( 12k \\right)}^{2}}}=13k$", "answer": "AB等于根号下AC的平方加BC平方,等于根号下五乘k的积的平方加十二乘k的积的平方,等于十三k", "subset": "mixmath", "task_type": "tts"} +{"index": 476, "question": "请你朗读以下数学公式符号:$$=(471\\times 1001001001)\\div (157\\times 1001001001)$$", "audio_path": "audio/math_d88ac5dd-dd3b-4fd5-afdd-a6b2846a5a2e.wav", "formula": "$$=(471\\times 1001001001)\\div (157\\times 1001001001)$$", "answer": "等于四百七十一乘十亿零一百万一千零一的积除以一百五十七乘十亿零一百万一千零一的积", "subset": "mixmath", "task_type": "tts"} +{"index": 477, "question": "Please read the following math formula symbols: $\\omega(U\\cupV)=\\omega(U)+\\omega(V)-\\omega(U\\capV)$", "audio_path": "audio/row_00132596_1755601135998617.wav", "formula": "$\\omega(U\\cupV)=\\omega(U)+\\omega(V)-\\omega(U\\capV)$", "answer": "Omega of the union of U and V equals omega of U plus omega of V minus omega of the intersection of U and V.", "subset": "mixmath", "task_type": "tts"} +{"index": 478, "question": "请你朗读以下数学公式符号:$28\\%=(0.28)=\\frac{28}{100}=\\left( \\frac{7}{25} \\right)$", "audio_path": "audio/math_39f3f3b7-93c1-4f3a-b857-bb9ece5cc1d5.wav", "formula": "$28\\%=(0.28)=\\frac{28}{100}=\\left( \\frac{7}{25} \\right)$", "answer": "百分之二十八等于零点二八等于一百分之二十八等于二十五分之七", "subset": "mixmath", "task_type": "tts"} +{"index": 479, "question": "请你朗读以下数学公式符号:$$\\frac{1}{a}+\\frac{1}{b}+\\frac{1}{c}+\\frac{1}{d}=1$$", "audio_path": "audio/math_d9e0962f-8566-4141-a6f3-5bd3e069ffdf.wav", "formula": "$$\\frac{1}{a}+\\frac{1}{b}+\\frac{1}{c}+\\frac{1}{d}=1$$", "answer": "a分之一加b分之一加c分之一加d分之一等于一", "subset": "mixmath", "task_type": "tts"} +{"index": 480, "question": "请你朗读以下数学公式符号:$=1\\times \\frac{1}{4}+5\\times 1\\times 1+10\\times 1\\times \\frac{1}{4}$", "audio_path": "audio/math_c54aa36b-802f-414d-a77b-6d6939b0a357.wav", "formula": "$=1\\times \\frac{1}{4}+5\\times 1\\times 1+10\\times 1\\times \\frac{1}{4}$", "answer": "等于一乘四分之一加五乘一乘一加十乘一乘四分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 481, "question": "请你朗读以下数学公式符号:${{(167)}_{9}}=1\\times {{9}^{2}}+6\\times 9+7=142=2\\times {{8}^{2}}+1\\times 8+6={{(216)}_{8}}$", "audio_path": "audio/math_fb12a373-e87c-4aaf-a8c1-626299a1cef7.wav", "formula": "${{(167)}_{9}}=1\\times {{9}^{2}}+6\\times 9+7=142=2\\times {{8}^{2}}+1\\times 8+6={{(216)}_{8}}$", "answer": "一六七的九进制等于 一乘九的平方加六乘九加七,等于一百四十二,等于二乘八的平方加一乘八加六,等于二一六的八进制", "subset": "mixmath", "task_type": "tts"} +{"index": 482, "question": "Please read the following math formula symbols: $-\\DeltaM\\frac{\\hat{p}^2}{2\\bar{m}_0}\\lambda_j(t)/2$", "audio_path": "audio/row_01650100_1755789935440858.wav", "formula": "$-\\DeltaM\\frac{\\hat{p}^2}{2\\bar{m}_0}\\lambda_j(t)/2$", "answer": "Delta M, open fraction, hat p squared, close fraction, divided by, 2 bar m sub 0, lambda sub j of t, divided by 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 483, "question": "Please read the following math formula symbols: $|MN|_p\\le|M|_p|N|_p$", "audio_path": "audio/row_00661452_1755665927463975.wav", "formula": "$|MN|_p\\le|M|_p|N|_p$", "answer": "Absolute value of M N, subscript p, is less than or equal to absolute value of M, subscript p, N, subscript p.", "subset": "mixmath", "task_type": "tts"} +{"index": 484, "question": "Please read the following math formula symbols: $\\card{B_{t+1}}\\le\\card{B_t}/2$", "audio_path": "audio/row_00593902_1755657514540436.wav", "formula": "$\\card{B_{t+1}}\\le\\card{B_t}/2$", "answer": "The cardinality of B sub t plus one is less than or equal to the cardinality of B sub t divided by 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 485, "question": "Please read the following math formula symbols: $\\rho_{a}(|\\bz|)=\\rho_{a,0}(|\\bz|)$", "audio_path": "audio/row_00123439_1755600030610124.wav", "formula": "$\\rho_{a}(|\\bz|)=\\rho_{a,0}(|\\bz|)$", "answer": "rho sub a of the absolute value of z equals rho sub a comma zero of the absolute value of z.", "subset": "mixmath", "task_type": "tts"} +{"index": 486, "question": "Please read the following math formula symbols: $(L_{i,x_k},L_{i,x_{k-1}},\\ldots,L_{i,x_0})$", "audio_path": "audio/row_00679654_1755668179125944.wav", "formula": "$(L_{i,x_k},L_{i,x_{k-1}},\\ldots,L_{i,x_0})$", "answer": "L sub i, x sub k, L sub i, x sub k minus 1, ellipsis, L sub i, x sub 0.", "subset": "mixmath", "task_type": "tts"} +{"index": 487, "question": "请你朗读以下数学公式符号:$\\left\\{ \\begin{align} & x=\\frac{16}{3} \\\\ & y=4 \\\\ \\end{align} \\right.$", "audio_path": "audio/math_dcf08856-57f0-437c-b665-f539396b811f.wav", "formula": "$\\left\\{ \\begin{align} & x=\\frac{16}{3} \\\\ & y=4 \\\\ \\end{align} \\right.$", "answer": "x等于三分之十六 和 y等于四", "subset": "mixmath", "task_type": "tts"} +{"index": 488, "question": "请你朗读以下数学公式符号:$\\frac{1}{8}=\\frac{1+4}{8\\times (1+4)}=\\frac{1}{40}+\\frac{1}{10}$", "audio_path": "audio/math_4ec3130e-16ac-4e70-8769-80110f799498.wav", "formula": "$\\frac{1}{8}=\\frac{1+4}{8\\times (1+4)}=\\frac{1}{40}+\\frac{1}{10}$", "answer": "八分之一等于八乘一加四的和的积分之一加四的和等于四十分之一加十分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 489, "question": "请你朗读以下数学公式符号:$\\frac{7}{15}x\\div \\frac{7}{15}=70\\div \\frac{7}{15}$", "audio_path": "audio/math_c7bb1ab1-16dc-4a83-9ed2-b3c8a154bdc5.wav", "formula": "$\\frac{7}{15}x\\div \\frac{7}{15}=70\\div \\frac{7}{15}$", "answer": "十五分之七x除以十五分之七等于七十除以十五分之七", "subset": "mixmath", "task_type": "tts"} +{"index": 490, "question": "请你朗读以下数学公式符号:$\\frac{{{19}^{2}}+{{20}^{2}}}{19\\times 20}=\\frac{761}{380}=2\\frac{1}{380}$", "audio_path": "audio/math_7364d4bf-267a-47af-a249-a528bef00be3.wav", "formula": "$\\frac{{{19}^{2}}+{{20}^{2}}}{19\\times 20}=\\frac{761}{380}=2\\frac{1}{380}$", "answer": "十九乘二十的积分之十九的平方与二十的平方的和等于三百八十分之七百六十一等于二又三百八十分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 491, "question": "请你朗读以下数学公式符号:$1\\times 2\\times 1\\times 4\\times 2\\times 1\\times 3\\times 2=96$", "audio_path": "audio/math_535dbf89-f75b-4752-a024-c8a445c94f21.wav", "formula": "$1\\times 2\\times 1\\times 4\\times 2\\times 1\\times 3\\times 2=96$", "answer": "一乘二乘一乘四乘二乘一乘三乘二等于九十六", "subset": "mixmath", "task_type": "tts"} +{"index": 492, "question": "请你朗读以下数学公式符号:$$\\because \\left( \\sqrt{a+b} \\right)\\left( \\sqrt{a+b} \\right)=a+b$$", "audio_path": "audio/math_7a37f4ad-f4c5-48cf-8b50-626cda134b59.wav", "formula": "$$\\because \\left( \\sqrt{a+b} \\right)\\left( \\sqrt{a+b} \\right)=a+b$$", "answer": "因为根号下a加b乘根号下a加b等于a加b", "subset": "mixmath", "task_type": "tts"} +{"index": 493, "question": "请你朗读以下数学公式符号:$a=\\left(1+3+3^{2}+3^{3}+3^{4}+3^{5}\\right)(1+5)(1+7)\\left(1+17+17^{2}\\right)$", "audio_path": "audio/math_4a32bfe7-5d84-4505-9232-6c516b6d3b22.wav", "formula": "$a=\\left(1+3+3^{2}+3^{3}+3^{4}+3^{5}\\right)(1+5)(1+7)\\left(1+17+17^{2}\\right)$", "answer": "a等于一加三加三的平方加三的立方加三的四次方加三的五次方的和乘一加五的和乘一加七的和乘一加十七加十七的平方的和", "subset": "mixmath", "task_type": "tts"} +{"index": 494, "question": "Please read the following math formula symbols: $\\lambda_c=m\\kappa_1+in\\omega_1~(m=0,1,2,\\ldots$", "audio_path": "audio/row_00592520_1755657347647359.wav", "formula": "$\\lambda_c=m\\kappa_1+in\\omega_1~(m=0,1,2,\\ldots$", "answer": "Lambda sub c equals m kappa sub 1 plus i n omega sub 1, where m equals 0, 1, 2, ellipsis.", "subset": "mixmath", "task_type": "tts"} +{"index": 495, "question": "请你朗读以下数学公式符号:$$\\sqrt{3}\\times \\sqrt{\\frac{1}{3}}=\\sqrt{3\\times \\frac{1}{3}}=\\sqrt{1}=1$$", "audio_path": "audio/math_98c4a3c3-e12d-4e9f-b520-f5ea4fccbc81.wav", "formula": "$$\\sqrt{3}\\times \\sqrt{\\frac{1}{3}}=\\sqrt{3\\times \\frac{1}{3}}=\\sqrt{1}=1$$", "answer": "根号三乘根号下三分之一等于根号下三乘三分之一的积等于根号一等于一", "subset": "mixmath", "task_type": "tts"} +{"index": 496, "question": "请你朗读以下数学公式符号:$=\\frac{3}{4}\\times \\frac{71}{25}\\times \\frac{5}{18}\\times \\frac{2}{3}\\times \\frac{50}{71}\\times \\frac{9}{5}+10\\times \\frac{81}{20}=\\frac{1}{2}+\\frac{81}{2}=41$", "audio_path": "audio/math_ea75e945-b6d8-431e-8429-f0be40ed5df0.wav", "formula": "$=\\frac{3}{4}\\times \\frac{71}{25}\\times \\frac{5}{18}\\times \\frac{2}{3}\\times \\frac{50}{71}\\times \\frac{9}{5}+10\\times \\frac{81}{20}=\\frac{1}{2}+\\frac{81}{2}=41$", "answer": "等于四分之三乘二十五分之七十一乘十八分之五乘三分之二乘七十一分之五十乘五分之九加十乘二十分之八十一等于二分之一加二分之八十一等于四十一", "subset": "mixmath", "task_type": "tts"} +{"index": 497, "question": "请你朗读以下数学公式符号:$=2\\sqrt{\\frac{4+2\\sqrt{3}}{2}}=\\sqrt{6}+\\sqrt{2}$", "audio_path": "audio/math_1b59c748-e1a9-40ed-acfd-f9f48c6569cf.wav", "formula": "$=2\\sqrt{\\frac{4+2\\sqrt{3}}{2}}=\\sqrt{6}+\\sqrt{2}$", "answer": "等于二乘根号下二分之四加二倍根号三的和,等于根号六加根号二", "subset": "mixmath", "task_type": "tts"} +{"index": 498, "question": "请你朗读以下数学公式符号:$18\\times3+18\\times2=18\\times \\left( {3+2} \\right)=90$", "audio_path": "audio/math_93f1ed47-99a9-4ba7-b983-8e2698aa6cbe.wav", "formula": "$18\\times3+18\\times2=18\\times \\left( {3+2} \\right)=90$", "answer": "十八乘三加十八乘二等于十八乘三加二的和等于九十", "subset": "mixmath", "task_type": "tts"} +{"index": 499, "question": "请你朗读以下数学公式符号:$= \\frac{13}{14} \\div \\left[ \\frac{6}{7} \\times \\frac{1}{2} \\right]$", "audio_path": "audio/math_567c4e6f-eef2-4fcb-a5b7-18894aa10d00.wav", "formula": "$= \\frac{13}{14} \\div \\left[ \\frac{6}{7} \\times \\frac{1}{2} \\right]$", "answer": "等于 十四分之十三 除以 七分之六乘二分之一的积", "subset": "mixmath", "task_type": "tts"} +{"index": 500, "question": "请你朗读以下数学公式符号:$$40=2\\times 2\\times 2\\times 5=1\\times 1\\times 40=1\\times 2\\times 20=1\\times 4\\times 10=1\\times 5\\times 8=2\\times 2\\times 10=2\\times 4\\times 5$$", "audio_path": "audio/math_9ec1f6e7-cfc6-4ded-912a-9ac6cc019c42.wav", "formula": "$$40=2\\times 2\\times 2\\times 5=1\\times 1\\times 40=1\\times 2\\times 20=1\\times 4\\times 10=1\\times 5\\times 8=2\\times 2\\times 10=2\\times 4\\times 5$$", "answer": "四十等于二乘二乘二乘五等于一乘一乘四十等于一乘二乘二十等于一乘四乘十等于一乘五乘八等于二乘二乘十等于二乘四乘五", "subset": "mixmath", "task_type": "tts"} +{"index": 501, "question": "Please read the following math formula symbols: $\\nu^{(\\pi)}=\\nu^{(\\pm\\pi/3)}=1$", "audio_path": "audio/row_00175517_1755606345389765.wav", "formula": "$\\nu^{(\\pi)}=\\nu^{(\\pm\\pi/3)}=1$", "answer": "Nu raised to the power of pi equals nu raised to the power of plus or minus pi over 3 equals 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 502, "question": "Please read the following math formula symbols: $\\dot{a}_A\\equiv\\partial_Ua_A$", "audio_path": "audio/row_01580078_1755781089599652.wav", "formula": "$\\dot{a}_A\\equiv\\partial_Ua_A$", "answer": "The derivative of a sub A with respect to time is equal to the partial derivative of A sub A with respect to time.", "subset": "mixmath", "task_type": "tts"} +{"index": 503, "question": "请你朗读以下数学公式符号:$$\\left( \\frac{1}{60}+\\frac{1}{75} \\right)\\times 4$$", "audio_path": "audio/math_4a9dee56-4cea-411a-8596-b6c661ba2cd1.wav", "formula": "$$\\left( \\frac{1}{60}+\\frac{1}{75} \\right)\\times 4$$", "answer": "六十分之一加七十五分之一的和乘四", "subset": "mixmath", "task_type": "tts"} +{"index": 504, "question": "请你朗读以下数学公式符号:$(1\\div25)\\times(27\\div17)\\div(27\\div25)\\times(17\\times19)=1\\div25\\times27\\div17\\div27\\times25\\times17\\times19=1\\times19=19$", "audio_path": "audio/math_abc66504-b6c8-4b16-a450-e6712f63e70a.wav", "formula": "$(1\\div25)\\times(27\\div17)\\div(27\\div25)\\times(17\\times19)=1\\div25\\times27\\div17\\div27\\times25\\times17\\times19=1\\times19=19$", "answer": "一除以二十五的商乘二十七除以十七的商,再除以二十七除以二十五的商,再乘十七乘十九的积,等于一除以二十五乘二十七除以十七除以二十七,再乘二十五乘十七乘十九,等于一乘十九等于十九", "subset": "mixmath", "task_type": "tts"} +{"index": 505, "question": "请你朗读以下数学公式符号:$3\\times 3\\times 3\\div \\left( 1\\times 1\\times 1 \\right)$", "audio_path": "audio/math_560d759a-78dc-411a-b5c2-eda5f1597ebd.wav", "formula": "$3\\times 3\\times 3\\div \\left( 1\\times 1\\times 1 \\right)$", "answer": "三乘三乘三除以 一乘一乘一的积", "subset": "mixmath", "task_type": "tts"} +{"index": 506, "question": "请你朗读以下数学公式符号:$\\frac{1}{15}\\div \\left( 1+\\frac{1}{5} \\right)=\\frac{1}{18}$", "audio_path": "audio/math_d8a9e0d6-f6d0-4ce3-a248-388b27dbd81b.wav", "formula": "$\\frac{1}{15}\\div \\left( 1+\\frac{1}{5} \\right)=\\frac{1}{18}$", "answer": "十五分之一除以一加五分之一的和等于十八分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 507, "question": "Please read the following math formula symbols: ${|B|}^2\\leq|A||\\mathcal{L}|$", "audio_path": "audio/row_01720587_1755798835069201.wav", "formula": "${|B|}^2\\leq|A||\\mathcal{L}|$", "answer": "The absolute value of B squared is less than or equal to the absolute value of A times the absolute value of L.", "subset": "mixmath", "task_type": "tts"} +{"index": 508, "question": "请你朗读以下数学公式符号:$=14\\times 17+14\\times 2\\times 19+14\\times 3\\times 15$", "audio_path": "audio/math_1d5aba31-7db3-4fbd-be29-9a7e168e6e11.wav", "formula": "$=14\\times 17+14\\times 2\\times 19+14\\times 3\\times 15$", "answer": "等于十四乘十七加十四乘二乘十九加十四乘三乘十五", "subset": "mixmath", "task_type": "tts"} +{"index": 509, "question": "Please read the following math formula symbols: $\\mcM\\models\\num{n_0}+\\num{n_1}=\\num{n_2}$", "audio_path": "audio/row_01235184_1755737680906969.wav", "formula": "$\\mcM\\models\\num{n_0}+\\num{n_1}=\\num{n_2}$", "answer": "m c M models nu m n sub 0 plus nu m n sub 1 equals nu m n sub 2", "subset": "mixmath", "task_type": "tts"} +{"index": 510, "question": "请你朗读以下数学公式符号:$\\frac{2}{5}x\\div \\frac{2}{5}=\\frac{1}{5}\\div \\frac{2}{5}$", "audio_path": "audio/math_0dad5d5f-a00a-4a03-9fcd-90701d1c076b.wav", "formula": "$\\frac{2}{5}x\\div \\frac{2}{5}=\\frac{1}{5}\\div \\frac{2}{5}$", "answer": "五分之二x除以五分之二等于五分之一除以五分之二", "subset": "mixmath", "task_type": "tts"} +{"index": 511, "question": "Please read the following math formula symbols: $\\sigma_\\beta:C_\\beta\\to\\Und_{\\Sigma_\\beta}\\tr_\\beta^\\Sigma\\bbX$", "audio_path": "audio/row_00791379_1755682148881975.wav", "formula": "$\\sigma_\\beta:C_\\beta\\to\\Und_{\\Sigma_\\beta}\\tr_\\beta^\\Sigma\\bbX$", "answer": "sigma sub beta, colon, C sub beta to Und sub Sigma sub beta, tr sub beta to the power of Sigma, b X", "subset": "mixmath", "task_type": "tts"} +{"index": 512, "question": "Please read the following math formula symbols: $h_1=\\int{\\rmd}x\\\\psi^\\dagger(W\\sigma_y)\\psi$", "audio_path": "audio/row_00461090_1755641168425863.wav", "formula": "$h_1=\\int{\\rmd}x\\\\psi^\\dagger(W\\sigma_y)\\psi$", "answer": "h sub 1 equals the integral of d x times psi dagger times open parenthesis W sigma y close parenthesis times psi.", "subset": "mixmath", "task_type": "tts"} +{"index": 513, "question": "请你朗读以下数学公式符号:$\\left( 110\\div 2 \\right)\\times \\left( 80\\div 2 \\right)=2200$", "audio_path": "audio/math_f4bbcdca-a7d5-4549-be81-1b1c49151d04.wav", "formula": "$\\left( 110\\div 2 \\right)\\times \\left( 80\\div 2 \\right)=2200$", "answer": "一百一十除以二的商乘八十除以二的商等于两千二百", "subset": "mixmath", "task_type": "tts"} +{"index": 514, "question": "请你朗读以下数学公式符号:$x=\\pm \\sqrt{\\frac{3+2\\sqrt{2}}{2}}=\\pm \\left( \\frac{2+\\sqrt{2}}{2} \\right)$", "audio_path": "audio/math_32ce6eab-8e6b-4191-91e8-cd37fe5c2ecb.wav", "formula": "$x=\\pm \\sqrt{\\frac{3+2\\sqrt{2}}{2}}=\\pm \\left( \\frac{2+\\sqrt{2}}{2} \\right)$", "answer": "x等于正负根号下二分之三加二倍的根号二等于正负二分之二加根号二", "subset": "mixmath", "task_type": "tts"} +{"index": 515, "question": "请你朗读以下数学公式符号:$\\dfrac{1}{6}+\\dfrac{2}{9}=\\dfrac{3}{18}+\\dfrac{4}{18}=\\dfrac{7}{18}<{}\\dfrac{12}{18}=\\dfrac{2}{3}$", "audio_path": "audio/math_a2670727-f594-4fac-af1e-a1f42aaa0bf0.wav", "formula": "$\\dfrac{1}{6}+\\dfrac{2}{9}=\\dfrac{3}{18}+\\dfrac{4}{18}=\\dfrac{7}{18}<{}\\dfrac{12}{18}=\\dfrac{2}{3}$", "answer": "六分之一加九分之二等于十八分之三加十八分之四等于十八分之七小于十八分之十二等于三分之二", "subset": "mixmath", "task_type": "tts"} +{"index": 516, "question": "请你朗读以下数学公式符号:$\\overline{ababab}=\\overline{ab}\\times 10101=\\overline{ab}\\times 3\\times 7\\times 13\\times 37$", "audio_path": "audio/math_1de3b09c-48a1-48b5-9d0f-e6a461fafa0e.wav", "formula": "$\\overline{ababab}=\\overline{ab}\\times 10101=\\overline{ab}\\times 3\\times 7\\times 13\\times 37$", "answer": "六位数ababab等于两位数ab乘一万零一百零一等于两位数ab乘三乘七乘十三乘三十七", "subset": "mixmath", "task_type": "tts"} +{"index": 517, "question": "Please read the following math formula symbols: $P_{n_1,n_2,n_3}=P_{n_3,n_2,n_1}$", "audio_path": "audio/row_02039203_1755839073303437.wav", "formula": "$P_{n_1,n_2,n_3}=P_{n_3,n_2,n_1}$", "answer": "P sub n sub 1, n sub 2, n sub 3 equals P sub n sub 3, n sub 2, n sub 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 518, "question": "Please read the following math formula symbols: $\\Umat^{-\\hermconj}\\amat\\Umat^{-1}$", "audio_path": "audio/row_01356708_1755752873468455.wav", "formula": "$\\Umat^{-\\hermconj}\\amat\\Umat^{-1}$", "answer": "The u times a times t to the power of negative semicolon m times c times a times t to the power of negative one.", "subset": "mixmath", "task_type": "tts"} +{"index": 519, "question": "Please read the following math formula symbols: $M(\\RL{0}{\\alpha}f)\\le\\frac{n-\\alpha}{n}\\ntwo{f}+1$", "audio_path": "audio/row_00323027_1755624297143055.wav", "formula": "$M(\\RL{0}{\\alpha}f)\\le\\frac{n-\\alpha}{n}\\ntwo{f}+1$", "answer": "M times the quantity zero alpha f is less than or equal to the fraction n minus alpha over n times f plus one.", "subset": "mixmath", "task_type": "tts"} +{"index": 520, "question": "请你朗读以下数学公式符号:$3.27\\times \\frac{3}{7}+3.27\\div \\frac{7}{4}=3.27$", "audio_path": "audio/math_afeb9beb-351e-47fa-854b-bb79787acacb.wav", "formula": "$3.27\\times \\frac{3}{7}+3.27\\div \\frac{7}{4}=3.27$", "answer": "三点二七乘七分之三加上三点二七除以四分之七等于三点二七", "subset": "mixmath", "task_type": "tts"} +{"index": 521, "question": "请你朗读以下数学公式符号:$$\\frac{1}{2}+\\frac{1}{6}+\\frac{1}{12}+\\frac{1}{20}+\\frac{1}{30}+\\frac{1}{42}$$", "audio_path": "audio/math_8f1646f7-276d-4bc1-ab6e-da663a2de5cd.wav", "formula": "$$\\frac{1}{2}+\\frac{1}{6}+\\frac{1}{12}+\\frac{1}{20}+\\frac{1}{30}+\\frac{1}{42}$$", "answer": "二分之一加六分之一加十二分之一加二十分之一加三十分之一加四十二分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 522, "question": "Please read the following math formula symbols: $\\omega_4(t)=[-\\cos{2t}~1~\\sin{5t}]^T$", "audio_path": "audio/row_00890902_1755694637866341.wav", "formula": "$\\omega_4(t)=[-\\cos{2t}~1~\\sin{5t}]^T$", "answer": "Omega sub 4 of t equals negative cosine 2t times 1 times sine 5t, all raised to the power of T.", "subset": "mixmath", "task_type": "tts"} +{"index": 523, "question": "请你朗读以下数学公式符号:$$30\\times 7\\div 5.5=\\frac{420}{11}=38\\frac{2}{11}$$", "audio_path": "audio/math_e836ef07-c09f-4bb3-a7b5-493fe62e8819.wav", "formula": "$$30\\times 7\\div 5.5=\\frac{420}{11}=38\\frac{2}{11}$$", "answer": "三十乘七除以五点五等于十一分之四百二十等于三十八又十一分之二", "subset": "mixmath", "task_type": "tts"} +{"index": 524, "question": "Please read the following math formula symbols: $r_1+2r_2+\\cdots+nr_n=2n-2$", "audio_path": "audio/row_01293664_1755744985935922.wav", "formula": "$r_1+2r_2+\\cdots+nr_n=2n-2$", "answer": "r sub 1 plus 2 r sub 2 plus dot dot dot plus n r sub n equals 2 n minus 2", "subset": "mixmath", "task_type": "tts"} +{"index": 525, "question": "Please read the following math formula symbols: $R_2=\\agb^{-s-1}\\dy_y$", "audio_path": "audio/row_02087634_1755845253180146.wav", "formula": "$R_2=\\agb^{-s-1}\\dy_y$", "answer": "R sub 2 equals a times g times b to the power of negative s minus 1, d times y sub y.", "subset": "mixmath", "task_type": "tts"} +{"index": 526, "question": "Please read the following math formula symbols: $\\eta(t)>0\\Longrightarrow\\left\\\\\\|\\bar\\{x^2-\\bar\\{x^1\\right\\\\\\|=7$", "audio_path": "audio/row_01920115_1755824077815822.wav", "formula": "$\\eta(t)>0\\Longrightarrow\\left\\\\\\|\\bar\\{x^2-\\bar\\{x^1\\right\\\\\\|=7$", "answer": "Eta of t is greater than zero, implies the norm of the norm of x squared minus x bar, which is equal to seven.", "subset": "mixmath", "task_type": "tts"} +{"index": 527, "question": "Please read the following math formula symbols: $u^0\\in\\dot{H}^s_{\\mathcal{M}}$", "audio_path": "audio/row_01321193_1755748403119999.wav", "formula": "$u^0\\in\\dot{H}^s_{\\mathcal{M}}$", "answer": "u raised to the power of 0 belongs to the set of H raised to the power of s sub M.", "subset": "mixmath", "task_type": "tts"} +{"index": 528, "question": "Please read the following math formula symbols: $(x,t)\\mapstoxf_C(t\\mathbf{a}_x)$", "audio_path": "audio/row_01183446_1755731185384325.wav", "formula": "$(x,t)\\mapstoxf_C(t\\mathbf{a}_x)$", "answer": "Open parenthesis x, comma t, close parenthesis maps to x, f sub C open parenthesis t, bold a sub x, close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 529, "question": "请你朗读以下数学公式符号:$\\begin{cases}100x+150y=1500 \\\\ 120x+160y=1720 \\end{cases}$", "audio_path": "audio/math_eb3ca718-b57a-45f7-8eb1-f5180a254942.wav", "formula": "$\\begin{cases}100x+150y=1500 \\\\ 120x+160y=1720 \\end{cases}$", "answer": "一百x加一百五十y等于一千五百和一百二十x加一百六十y等于一千七百二十", "subset": "mixmath", "task_type": "tts"} +{"index": 530, "question": "Please read the following math formula symbols: $\\vert\\vertX\\vert\\vert_1\\geq\\tr\\(XY\\)/\\vert\\vertY\\vert\\vert$", "audio_path": "audio/row_02036120_1755838697766829.wav", "formula": "$\\vert\\vertX\\vert\\vert_1\\geq\\tr\\(XY\\)/\\vert\\vertY\\vert\\vert$", "answer": "Absolute value of X, subscript 1, greater than or equal to the trace of XY divided by absolute value of Y.", "subset": "mixmath", "task_type": "tts"} +{"index": 531, "question": "Please read the following math formula symbols: $\\sum_{i=1}^N\\whG_{ii}=N\\md$", "audio_path": "audio/row_00985026_1755706364503853.wav", "formula": "$\\sum_{i=1}^N\\whG_{ii}=N\\md$", "answer": "The sum from i equals 1 to N of the whine of G sub i i equals N times m times d.", "subset": "mixmath", "task_type": "tts"} +{"index": 532, "question": "请你朗读以下数学公式符号:$$\\left\\{\\begin{array}{c}x=1\\\\y=2\\end{array}\\right.$", "audio_path": "audio/math_6ca121a1-836a-4168-994d-29ffb238b28e.wav", "formula": "$$\\left\\{\\begin{array}{c}x=1\\\\y=2\\end{array}\\right.$", "answer": "x等于一,y等于二", "subset": "mixmath", "task_type": "tts"} +{"index": 533, "question": "Please read the following math formula symbols: $[2^{-k},2^{-k}+2^{-m}]$", "audio_path": "audio/row_01910516_1755822868236470.wav", "formula": "$[2^{-k},2^{-k}+2^{-m}]$", "answer": "The quantity 2 to the power of negative k, comma, 2 to the power of negative k plus 2 to the power of negative m.", "subset": "mixmath", "task_type": "tts"} +{"index": 534, "question": "请你朗读以下数学公式符号:$\\therefore 0 < \\alpha +\\beta +\\gamma < \\frac{3\\pi }{4}\\therefore \\alpha +\\beta +\\gamma =\\frac{\\pi }{4}$", "audio_path": "audio/math_f71a0d20-23e8-49b1-999b-87a7c7e86a05.wav", "formula": "$\\therefore 0 < \\alpha +\\beta +\\gamma < \\frac{3\\pi }{4}\\therefore \\alpha +\\beta +\\gamma =\\frac{\\pi }{4}$", "answer": "所以 alpha加beta加gamma大于零小于四分之三pi 所以 alpha加beta加gamma等于四分之pi", "subset": "mixmath", "task_type": "tts"} +{"index": 535, "question": "请你朗读以下数学公式符号:$S=\\frac{150 \\pi \\times {24}^{2}}{360}=240 \\pi{c}{m}^{2}$", "audio_path": "audio/math_f539538b-4e02-4dd7-87d5-4c3e96edbfec.wav", "formula": "$S=\\frac{150 \\pi \\times {24}^{2}}{360}=240 \\pi{c}{m}^{2}$", "answer": "S等于三百六十分之一百五十pi乘二十四的平方,等于二百四十pi平方厘米", "subset": "mixmath", "task_type": "tts"} +{"index": 536, "question": "Please read the following math formula symbols: $\\lambda\\inH^C(\\rho,\\sigma)=\\int_CH(\\rho,\\sigma)$", "audio_path": "audio/row_00634473_1755662598092583.wav", "formula": "$\\lambda\\inH^C(\\rho,\\sigma)=\\int_CH(\\rho,\\sigma)$", "answer": "Lambda belongs to H raised to the power of C of rho, sigma equals the integral over C of H of rho, sigma.", "subset": "mixmath", "task_type": "tts"} +{"index": 537, "question": "Please read the following math formula symbols: $\\mathbb{S}_2(s,s_0)\\subsetneq\\mathbb{S}_1(s,s_0)$", "audio_path": "audio/row_01499532_1755770891391932.wav", "formula": "$\\mathbb{S}_2(s,s_0)\\subsetneq\\mathbb{S}_1(s,s_0)$", "answer": "The set S sub 2 of s, s sub 0 is a proper subset of the set S sub 1 of s, s sub 0.", "subset": "mixmath", "task_type": "tts"} +{"index": 538, "question": "Please read the following math formula symbols: $\\Psi\\in\\Ww^{1,p}(E,\\RR^m)$", "audio_path": "audio/row_00967748_1755704219372683.wav", "formula": "$\\Psi\\in\\Ww^{1,p}(E,\\RR^m)$", "answer": "Psi belongs to W w raised to the power of 1, p, in parentheses E, comma R R raised to the power of m.", "subset": "mixmath", "task_type": "tts"} +{"index": 539, "question": "请你朗读以下数学公式符号:$\\frac{3\\pm \\sqrt{9+44}}{2}=\\frac{3\\pm \\sqrt{53}}{2}$", "audio_path": "audio/math_0b72f510-7e5d-4e69-b386-a885fc809e31.wav", "formula": "$\\frac{3\\pm \\sqrt{9+44}}{2}=\\frac{3\\pm \\sqrt{53}}{2}$", "answer": "二分之 三加减根号下九加四十四的和等于二分之 三加减根号五十三", "subset": "mixmath", "task_type": "tts"} +{"index": 540, "question": "Please read the following math formula symbols: $\\max_{j\\in[d]}(a_j^2+b_j^2)$", "audio_path": "audio/row_01122311_1755723494263525.wav", "formula": "$\\max_{j\\in[d]}(a_j^2+b_j^2)$", "answer": "Maximize over j in the set of integers from 1 to d, of the quantity a sub j squared plus b sub j squared.", "subset": "mixmath", "task_type": "tts"} +{"index": 541, "question": "请你朗读以下数学公式符号:$\\begin{eqnarray}&&\\frac{1}{8}{t}:450{kg}\\\\ &=&\\frac{1}{8}\\times 1000{kg}:450{kg}\\\\ &=&125{kg}:450{kg}\\\\ &=&125:450\\\\ &=&25:90\\\\ &=&5:18.\\end{eqnarray}$", "audio_path": "audio/math_b77a0baf-e94b-4b5c-8ed1-a5c46d8d26b8.wav", "formula": "$\\begin{eqnarray}&&\\frac{1}{8}{t}:450{kg}\\\\ &=&\\frac{1}{8}\\times 1000{kg}:450{kg}\\\\ &=&125{kg}:450{kg}\\\\ &=&125:450\\\\ &=&25:90\\\\ &=&5:18.\\end{eqnarray}$", "answer": "八分之一t比四百五十千克等于八分之一乘一千千克比四百五十千克等于一百二十五千克比四百五十千克等于一百二十五比四百五十等于二十五比九十等于五比十八。", "subset": "mixmath", "task_type": "tts"} +{"index": 542, "question": "Please read the following math formula symbols: $\\omega_{\\phi}(p)\\subset\\omega_{\\{\\Phi^t\\}}(p),$", "audio_path": "audio/row_01820241_1755811455745656.wav", "formula": "$\\omega_{\\phi}(p)\\subset\\omega_{\\{\\Phi^t\\}}(p),$", "answer": "Omega sub phi of p is a subset of omega sub open curly brace Phi superscript t close curly brace of p.", "subset": "mixmath", "task_type": "tts"} +{"index": 543, "question": "请你朗读以下数学公式符号:$$\\frac{{{x}^{2}}+2x+3}{x+1}=\\frac{{{(x+1)}^{2}}+2}{x+1}=x+1+\\frac{2}{x+1}$$", "audio_path": "audio/math_24a91499-fe73-4eb6-96d0-170f5cde15ce.wav", "formula": "$$\\frac{{{x}^{2}}+2x+3}{x+1}=\\frac{{{(x+1)}^{2}}+2}{x+1}=x+1+\\frac{2}{x+1}$$", "answer": "x加一的和分之x的平方加二x加三的和等于x加一的和分之x加一的和的平方加二的和等于x加一的和加x加一的和分之二", "subset": "mixmath", "task_type": "tts"} +{"index": 544, "question": "请你朗读以下数学公式符号:$\\frac{1}{2}\\times \\frac{1}{3}\\div \\frac{1}{3}\\times \\frac{1}{2}=$", "audio_path": "audio/math_83a45f0c-f356-4590-b5ab-db45166199c3.wav", "formula": "$\\frac{1}{2}\\times \\frac{1}{3}\\div \\frac{1}{3}\\times \\frac{1}{2}=$", "answer": "二分之一乘三分之一除以三分之一乘二分之一等于", "subset": "mixmath", "task_type": "tts"} +{"index": 545, "question": "请你朗读以下数学公式符号:$\\min \\left\\{ \\sin 30^\\circ ,\\cos 60^\\circ ,\\tan 45^\\circ \\right\\}=\\frac{1}{2}$", "audio_path": "audio/math_9cb29fdd-e468-4264-8d7e-f464ee86b2d5.wav", "formula": "$\\min \\left\\{ \\sin 30^\\circ ,\\cos 60^\\circ ,\\tan 45^\\circ \\right\\}=\\frac{1}{2}$", "answer": "sine 三十度,cosine 六十度,tangent 四十五度的最小值等于二分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 546, "question": "Please read the following math formula symbols: $(\\vec{a}_i\\cdot\\nabla)^jf_i$", "audio_path": "audio/row_00439526_1755638516150013.wav", "formula": "$(\\vec{a}_i\\cdot\\nabla)^jf_i$", "answer": "The vector a sub i dot product with the nabla operator, all raised to the power of j, acting on the function f sub i.", "subset": "mixmath", "task_type": "tts"} +{"index": 547, "question": "Please read the following math formula symbols: $\\beta_{2}=\\frac{N}{2}\\sqrt{\\frac{d(1-\\theta^2)}{r}}$", "audio_path": "audio/row_00292706_1755620614967803.wav", "formula": "$\\beta_{2}=\\frac{N}{2}\\sqrt{\\frac{d(1-\\theta^2)}{r}}$", "answer": "Beta sub 2 equals N over 2 times the square root of d times the quantity 1 minus theta squared all over r.", "subset": "mixmath", "task_type": "tts"} +{"index": 548, "question": "请你朗读以下数学公式符号:$5568=12\\times 464=16\\times 348=24\\times 232=32\\times 174=48\\times 116=58\\times 96=64\\times 87$", "audio_path": "audio/math_387e3f48-c813-48a8-bbbd-a5382597f287.wav", "formula": "$5568=12\\times 464=16\\times 348=24\\times 232=32\\times 174=48\\times 116=58\\times 96=64\\times 87$", "answer": "五千五百六十八等于十二乘四百六十四等于十六乘三百四十八等于二十四乘二百三十二等于三十二乘一百七十四等于四十八乘一百一十六等于五十八乘九十六等于六十四乘八十七", "subset": "mixmath", "task_type": "tts"} +{"index": 549, "question": "请你朗读以下数学公式符号:$${{\\left( 1 \\right)}_{8}}={{\\left( 001 \\right)}_{2}}:{{\\left( 2 \\right)}_{8}}={{\\left( 010 \\right)}_{2}}:{{\\left( 5 \\right)}_{8}}={{\\left( 101 \\right)}_{2}}$$", "audio_path": "audio/math_03113594-ab4a-4d9e-846e-d22d4d98ea08.wav", "formula": "$${{\\left( 1 \\right)}_{8}}={{\\left( 001 \\right)}_{2}}:{{\\left( 2 \\right)}_{8}}={{\\left( 010 \\right)}_{2}}:{{\\left( 5 \\right)}_{8}}={{\\left( 101 \\right)}_{2}}$$", "answer": "八进制的一等于二进制的零零一比八进制的二等于二进制的零一零比八进制的五等于二进制的一零一", "subset": "mixmath", "task_type": "tts"} +{"index": 550, "question": "Please read the following math formula symbols: $2\\leqk\\leq|A_i|$", "audio_path": "audio/row_01720497_1755798824933358.wav", "formula": "$2\\leqk\\leq|A_i|$", "answer": "Two is less than or equal to k, which is less than or equal to the absolute value of A sub i.", "subset": "mixmath", "task_type": "tts"} +{"index": 551, "question": "请你朗读以下数学公式符号:$=\\frac{1.25}{0.75}+\\frac{1.5}{4.5}=\\frac{5}{3}+\\frac{1}{3}=2$", "audio_path": "audio/math_8e07bf9c-8a2b-4520-b99c-5f1df49d8cfb.wav", "formula": "$=\\frac{1.25}{0.75}+\\frac{1.5}{4.5}=\\frac{5}{3}+\\frac{1}{3}=2$", "answer": "等于 零点七五分之一点二五 加 四点五分之一点五 等于 三分之五 加 三分之一 等于 二", "subset": "mixmath", "task_type": "tts"} +{"index": 552, "question": "Please read the following math formula symbols: $\\hat{X}_{i}:=\\mathbb{E}[X_{i}|Y_0^{i}]$", "audio_path": "audio/row_00948431_1755701807695663.wav", "formula": "$\\hat{X}_{i}:=\\mathbb{E}[X_{i}|Y_0^{i}]$", "answer": "X hat sub i is defined as the expectation of X sub i given Y sub 0 to the power of i.", "subset": "mixmath", "task_type": "tts"} +{"index": 553, "question": "请你朗读以下数学公式符号:$$\\frac{1}{10}\\times \\left( \\frac{1}{10}+\\frac{2}{10}+\\frac{3}{10}+\\frac{4}{10} \\right)=$$", "audio_path": "audio/math_bb6b6678-ef3e-4ef2-a1cf-2dcbb4a1eeca.wav", "formula": "$$\\frac{1}{10}\\times \\left( \\frac{1}{10}+\\frac{2}{10}+\\frac{3}{10}+\\frac{4}{10} \\right)=$$", "answer": "十分之一乘十分之一加十分之二加十分之三加十分之四的和等于", "subset": "mixmath", "task_type": "tts"} +{"index": 554, "question": "Please read the following math formula symbols: $t^2F(t,x+t\\widehat{v})\\sim\\mathbb{F}[f_\\infty](v)$", "audio_path": "audio/row_02062412_1755842057593450.wav", "formula": "$t^2F(t,x+t\\widehat{v})\\sim\\mathbb{F}[f_\\infty](v)$", "answer": "t squared F of t, x plus t hat v, is approximately equal to the set of F infinity of v.", "subset": "mixmath", "task_type": "tts"} +{"index": 555, "question": "Please read the following math formula symbols: $z_{-\\nkkc},z_{-\\nkkc}'\\in\\mathcalZ_{-\\nkkc}$", "audio_path": "audio/row_00745426_1755676371070186.wav", "formula": "$z_{-\\nkkc},z_{-\\nkkc}'\\in\\mathcalZ_{-\\nkkc}$", "answer": "z sub negative n c c, z sub negative n c c prime belongs to Z sub negative n c c.", "subset": "mixmath", "task_type": "tts"} +{"index": 556, "question": "请你朗读以下数学公式符号:$\\left\\{\\begin{array}{c}x=0.1\\\\ y=0.5\\end{array}\\right.$", "audio_path": "audio/math_b9426159-2069-4d50-9010-aa271e9aa104.wav", "formula": "$\\left\\{\\begin{array}{c}x=0.1\\\\ y=0.5\\end{array}\\right.$", "answer": "x等于零点一和y等于零点五", "subset": "mixmath", "task_type": "tts"} +{"index": 557, "question": "Please read the following math formula symbols: $D_n=\\{t_k^n\\}_{k\\geq0}\\m$", "audio_path": "audio/row_01963830_1755829591878054.wav", "formula": "$D_n=\\{t_k^n\\}_{k\\geq0}\\m$", "answer": "D sub n equals the set of t sub k to the power of n, for k greater than or equal to 0, times m.", "subset": "mixmath", "task_type": "tts"} +{"index": 558, "question": "Please read the following math formula symbols: $D^*(2007)^0\\to\\bar{K}^{*0}$", "audio_path": "audio/row_01897643_1755821236133862.wav", "formula": "$D^*(2007)^0\\to\\bar{K}^{*0}$", "answer": "D star of 2007 raised to the power of 0, maps to bar K raised to the power of star 0.", "subset": "mixmath", "task_type": "tts"} +{"index": 559, "question": "请你朗读以下数学公式符号:$$\\frac{5}{14}+\\frac{3}{4}+\\frac{9}{14}+\\frac{1}{4}$$", "audio_path": "audio/math_09bda3a8-5265-4727-bff6-2403988a6b0b.wav", "formula": "$$\\frac{5}{14}+\\frac{3}{4}+\\frac{9}{14}+\\frac{1}{4}$$", "answer": "十四分之五加四分之三加十四分之九加四分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 560, "question": "Please read the following math formula symbols: $\\ker(\\phi)=(\\beta_1)_\\R(\\tau)^{\\gp}$", "audio_path": "audio/row_00989461_1755706922535032.wav", "formula": "$\\ker(\\phi)=(\\beta_1)_\\R(\\tau)^{\\gp}$", "answer": "Kernel of phi equals open parenthesis beta sub 1 close parenthesis sub R of tau raised to the power of gp.", "subset": "mixmath", "task_type": "tts"} +{"index": 561, "question": "请你朗读以下数学公式符号:$$\\sqrt{5\\frac{5}{24}}=\\sqrt{5{+}\\frac{5}{24}}{=}\\sqrt{\\frac{125}{24}}{=}\\sqrt{\\frac{{{5}^{2}}\\times 5}{24}}{=}5\\sqrt{\\frac{5}{24}}$$", "audio_path": "audio/math_02518a94-265f-40e6-b719-4970b7c49f4b.wav", "formula": "$$\\sqrt{5\\frac{5}{24}}=\\sqrt{5{+}\\frac{5}{24}}{=}\\sqrt{\\frac{125}{24}}{=}\\sqrt{\\frac{{{5}^{2}}\\times 5}{24}}{=}5\\sqrt{\\frac{5}{24}}$$", "answer": "根号下五又二十四分之五等于根号下五加二十四分之五的和等于根号下二十四分之一百二十五等于根号下二十四分之五的平方乘五的积等于五倍的根号下二十四分之五", "subset": "mixmath", "task_type": "tts"} +{"index": 562, "question": "请你朗读以下数学公式符号:${{x}_{1}}+{{x}_{2}}+{{x}_{3}}+{{x}_{4}}+{{x}_{5}}=45$", "audio_path": "audio/math_4c1f59aa-eff4-4326-a4ab-ebd1f279268c.wav", "formula": "${{x}_{1}}+{{x}_{2}}+{{x}_{3}}+{{x}_{4}}+{{x}_{5}}=45$", "answer": "x一加x二加x三加x四加x五的和等于四十五", "subset": "mixmath", "task_type": "tts"} +{"index": 563, "question": "Please read the following math formula symbols: $\\phi_i(p)(x_2)=\\phi(p)(x_2)=x_2$", "audio_path": "audio/row_02014282_1755835941539681.wav", "formula": "$\\phi_i(p)(x_2)=\\phi(p)(x_2)=x_2$", "answer": "Phi sub i of p times x sub 2 equals phi of p times x sub 2 equals x sub 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 564, "question": "Please read the following math formula symbols: $(x^2+y^2)/(r^2+a^2)+z^2/r^2=1$", "audio_path": "audio/row_01265923_1755741509857382.wav", "formula": "$(x^2+y^2)/(r^2+a^2)+z^2/r^2=1$", "answer": "x squared plus y squared divided by r squared plus a squared plus z squared divided by r squared equals 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 565, "question": "请你朗读以下数学公式符号:$$\\frac{5+\\dfrac{5}{11}+\\dfrac{4}{12}+\\dfrac{3}{13}+\\dfrac{2}{14}+\\dfrac{1}{15}}{\\dfrac{17}{11}+\\dfrac{17}{12}+\\dfrac{17}{13}+\\dfrac{17}{14}+\\dfrac{17}{15}}$$", "audio_path": "audio/math_66bb6acf-587d-44f3-9081-3c5a262ae7de.wav", "formula": "$$\\frac{5+\\dfrac{5}{11}+\\dfrac{4}{12}+\\dfrac{3}{13}+\\dfrac{2}{14}+\\dfrac{1}{15}}{\\dfrac{17}{11}+\\dfrac{17}{12}+\\dfrac{17}{13}+\\dfrac{17}{14}+\\dfrac{17}{15}}$$", "answer": "十一分之十七加十二分之十七加十三分之十七加十四分之十七加十五分之十七的和分之五加十一分之五加十二分之四加十三分之三加十四分之二加十五分之一的和", "subset": "mixmath", "task_type": "tts"} +{"index": 566, "question": "请你朗读以下数学公式符号:$${{\\left( 345 \\right)}_{6}}=3\\\\times 36+4\\\\times 6+5={{\\\\left( 137 \\\\right)}_{10}}$$", "audio_path": "audio/math_02c8463f-9e8f-44fe-b051-2f3fa71e81a2.wav", "formula": "$${{\\left( 345 \\right)}_{6}}=3\\\\times 36+4\\\\times 6+5={{\\\\left( 137 \\\\right)}_{10}}$$", "answer": "六进制的三四五等于三乘三十六加四乘六加五等于十进制的一百三十七", "subset": "mixmath", "task_type": "tts"} +{"index": 567, "question": "请你朗读以下数学公式符号:$(1+2)\\times (1+3+{{3}^{2}}+{{3}^{3}})\\times (1+37)=4560$", "audio_path": "audio/math_1f818a3b-83f2-4420-80b8-3309875cb9fb.wav", "formula": "$(1+2)\\times (1+3+{{3}^{2}}+{{3}^{3}})\\times (1+37)=4560$", "answer": "一加二的和 乘 一加三加三的平方加三的立方的和 乘 一加三十七的和 等于四千五百六十", "subset": "mixmath", "task_type": "tts"} +{"index": 568, "question": "Please read the following math formula symbols: $a_{1,f(1)}a_{2,f(2)}\\cdotsa_{n,f(n)}$", "audio_path": "audio/row_00264203_1755617151581432.wav", "formula": "$a_{1,f(1)}a_{2,f(2)}\\cdotsa_{n,f(n)}$", "answer": "a sub 1, f of 1, times a sub 2, f of 2, dot dot dot, times a sub n, f of n.", "subset": "mixmath", "task_type": "tts"} +{"index": 569, "question": "Please read the following math formula symbols: $\\sum_{1\\leqi\\leqk}w_i\\in\\Nbb^k$", "audio_path": "audio/row_00361498_1755628987145314.wav", "formula": "$\\sum_{1\\leqi\\leqk}w_i\\in\\Nbb^k$", "answer": "The sum from i equals 1 to k of w sub i belongs to the set of natural numbers to the power of k.", "subset": "mixmath", "task_type": "tts"} +{"index": 570, "question": "Please read the following math formula symbols: $\\exp(-t\\sigma(-\\Delta_\\vartheta))\\subset\\sigma(S_\\vartheta(t))$", "audio_path": "audio/row_01388768_1755756926595613.wav", "formula": "$\\exp(-t\\sigma(-\\Delta_\\vartheta))\\subset\\sigma(S_\\vartheta(t))$", "answer": "Exponential of negative t times sigma of negative Delta sub theta is a subset of sigma of S sub theta of t.", "subset": "mixmath", "task_type": "tts"} +{"index": 571, "question": "Please read the following math formula symbols: $\\normmattxt{M}_2\\leq\\normmattxt{A^{-1}}_2^{-1}/2$", "audio_path": "audio/row_00661024_1755665882237207.wav", "formula": "$\\normmattxt{M}_2\\leq\\normmattxt{A^{-1}}_2^{-1}/2$", "answer": "The norm of M sub 2 is less than or equal to the norm of A inverse sub 2 inverse divided by 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 572, "question": "Please read the following math formula symbols: $p_\\perp=-T_\\vartheta^{~\\vartheta}=-T_\\phi^{~\\phi}$", "audio_path": "audio/row_00479517_1755643429622341.wav", "formula": "$p_\\perp=-T_\\vartheta^{~\\vartheta}=-T_\\phi^{~\\phi}$", "answer": "p perpendicular equals negative T theta raised to the power of theta equals negative T phi raised to the power of phi.", "subset": "mixmath", "task_type": "tts"} +{"index": 573, "question": "请你朗读以下数学公式符号:$$\\left( 0.\\dot{5}\\times 0.\\dot{6}+0.\\dot{7}\\times 0.\\dot{8} \\right)\\div 0.\\dot{9}$$", "audio_path": "audio/math_cacaaa21-02de-418e-bcbf-e740420ac3e5.wav", "formula": "$$\\left( 0.\\dot{5}\\times 0.\\dot{6}+0.\\dot{7}\\times 0.\\dot{8} \\right)\\div 0.\\dot{9}$$", "answer": "零点五 五循环乘零点六 六循环加零点七 七循环乘零点八 八循环,再除以零点九 九循环", "subset": "mixmath", "task_type": "tts"} +{"index": 574, "question": "请你朗读以下数学公式符号:$$(300\\times 6+312\\times 6+288\\times 6)\\div (6+6+6)=300$$", "audio_path": "audio/math_1fbcf761-cd85-4fd8-b0e7-3f548becac10.wav", "formula": "$$(300\\times 6+312\\times 6+288\\times 6)\\div (6+6+6)=300$$", "answer": "三百乘六加三百一十二乘六加二百八十八乘六的和除以六加六加六的和等于三百", "subset": "mixmath", "task_type": "tts"} +{"index": 575, "question": "请你朗读以下数学公式符号:$={{x}_{1}}^{2}+2{{x}_{1}}{{x}_{2}}+{{x}_{2}}^{2}+{{x}_{1}}{{x}_{2}}$", "audio_path": "audio/math_22f8eb21-20a1-40db-b94a-6d388b261a8b.wav", "formula": "$={{x}_{1}}^{2}+2{{x}_{1}}{{x}_{2}}+{{x}_{2}}^{2}+{{x}_{1}}{{x}_{2}}$", "answer": "等于x一的平方加二x一x二加x二的平方加x一x二", "subset": "mixmath", "task_type": "tts"} +{"index": 576, "question": "Please read the following math formula symbols: $M_2=\\langle[[j,H],H]j\\rangle$", "audio_path": "audio/row_01247369_1755739205359709.wav", "formula": "$M_2=\\langle[[j,H],H]j\\rangle$", "answer": "M sub 2 equals the inner product of the commutator of the commutator of j and H with H with j.", "subset": "mixmath", "task_type": "tts"} +{"index": 577, "question": "Please read the following math formula symbols: $W^{1,1}_{loc}(\\mathbb{R}^n,\\mathbb{R}^n)$", "audio_path": "audio/row_01867723_1755817448318664.wav", "formula": "$W^{1,1}_{loc}(\\mathbb{R}^n,\\mathbb{R}^n)$", "answer": "W superscript 1,1 subscript loc, open parenthesis, R to the power of n, comma, R to the power of n, close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 578, "question": "请你朗读以下数学公式符号:$1\\frac{1}{4}:1\\frac{1}{3}:1\\frac{1}{2}=\\frac{5}{4}:\\frac{4}{3}:\\frac{3}{2}=15:16:18$", "audio_path": "audio/math_ada0765c-a384-400d-9dc3-f254cec5d8ae.wav", "formula": "$1\\frac{1}{4}:1\\frac{1}{3}:1\\frac{1}{2}=\\frac{5}{4}:\\frac{4}{3}:\\frac{3}{2}=15:16:18$", "answer": "一又四分之一比一又三分之一比一又二分之一等于四分之五比三分之四比二分之三等于十五比十六比十八", "subset": "mixmath", "task_type": "tts"} +{"index": 579, "question": "请你朗读以下数学公式符号:$\\frac{1980+1982+1984+1986+1988+1990}{1985+1986+1987+1988+1989+1990}$", "audio_path": "audio/math_382006b0-fa46-4b70-8d62-4293e0da7283.wav", "formula": "$\\frac{1980+1982+1984+1986+1988+1990}{1985+1986+1987+1988+1989+1990}$", "answer": "一千九百八十五加一千九百八十六加一千九百八十七加一千九百八十八加一千九百八十九加一千九百九十的和分之一千九百八十加一千九百八十二加一千九百八十四加一千九百八十六加一千九百八十八加一千九百九十的和", "subset": "mixmath", "task_type": "tts"} +{"index": 580, "question": "请你朗读以下数学公式符号:$x=512 \\times 513 k+83=27\\times 256 \\times 38 k+38 \\times 2+7=38 \\times\\left(27 \\times 256 k+2\\right)+7$", "audio_path": "audio/math_75e18dce-b179-4831-8dba-c58639720c8d.wav", "formula": "$x=512 \\times 513 k+83=27\\times 256 \\times 38 k+38 \\times 2+7=38 \\times\\left(27 \\times 256 k+2\\right)+7$", "answer": "x等于五百一十二乘 五百一十三k 加八十三 等于二十七乘 二百五十六乘 三十八k加三十八乘 二加七等于三十八与 二十七乘 二百五十六k加二的乘积 加七", "subset": "mixmath", "task_type": "tts"} +{"index": 581, "question": "请你朗读以下数学公式符号:$M\\left\\{ 2,1+x,2x \\right\\}=\\min \\left\\{ 2,1+x,2x \\right\\}$", "audio_path": "audio/math_6581d1a8-b2c2-45a8-8b0e-4fd9931d851d.wav", "formula": "$M\\left\\{ 2,1+x,2x \\right\\}=\\min \\left\\{ 2,1+x,2x \\right\\}$", "answer": "运算M 集合二、一加x、二x,等于二、一加x、二x的最小值", "subset": "mixmath", "task_type": "tts"} +{"index": 582, "question": "Please read the following math formula symbols: $d(u_n,u)\\leqC_1|Q_n|^2$", "audio_path": "audio/row_00161427_1755604622814411.wav", "formula": "$d(u_n,u)\\leqC_1|Q_n|^2$", "answer": "d of u sub n, u is less than or equal to C sub 1, absolute value of Q sub n squared.", "subset": "mixmath", "task_type": "tts"} +{"index": 583, "question": "请你朗读以下数学公式符号:$=\\frac{35}{64}\\div \\left( \\frac{1}{8}+\\frac{6}{8} \\right)$", "audio_path": "audio/math_dac1112a-18b7-4f76-b723-28eed24ef697.wav", "formula": "$=\\frac{35}{64}\\div \\left( \\frac{1}{8}+\\frac{6}{8} \\right)$", "answer": "等于六十四分之三十五除以八分之一加八分之六的和", "subset": "mixmath", "task_type": "tts"} +{"index": 584, "question": "请你朗读以下数学公式符号:$$\\left( \\frac{1}{2}+\\frac{1}{3}+\\frac{1}{4}+\\frac{1}{5}+\\frac{1}{6} \\right)\\times \\left( \\frac{1}{3}+\\frac{1}{4}+\\frac{1}{5}+\\frac{1}{6}+\\frac{1}{7} \\right)$$", "audio_path": "audio/math_6cf6f802-0b82-407e-ad66-736ec969d440.wav", "formula": "$$\\left( \\frac{1}{2}+\\frac{1}{3}+\\frac{1}{4}+\\frac{1}{5}+\\frac{1}{6} \\right)\\times \\left( \\frac{1}{3}+\\frac{1}{4}+\\frac{1}{5}+\\frac{1}{6}+\\frac{1}{7} \\right)$$", "answer": "二分之一加三分之一加四分之一加五分之一加六分之一的和 乘 三分之一加四分之一加五分之一加六分之一加七分之一的和", "subset": "mixmath", "task_type": "tts"} +{"index": 585, "question": "Please read the following math formula symbols: $\\omega_2(t)=O(\\omega_{M^{q,2}}(t))$", "audio_path": "audio/row_00470419_1755642309645825.wav", "formula": "$\\omega_2(t)=O(\\omega_{M^{q,2}}(t))$", "answer": "omega sub 2 of t equals big O of omega sub M to the power of q comma 2 of t.", "subset": "mixmath", "task_type": "tts"} +{"index": 586, "question": "Please read the following math formula symbols: $\\mathbf{d}=(1/a_2,\\dots,1/a_{k-1})$", "audio_path": "audio/row_00978144_1755705497330220.wav", "formula": "$\\mathbf{d}=(1/a_2,\\dots,1/a_{k-1})$", "answer": "Math bold d equals open parenthesis one over a sub 2, ellipsis, one over a sub k minus one close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 587, "question": "Please read the following math formula symbols: $\\vert\\Cond_{Z^2}(v_s,i_1,i_2)\\vert=2$", "audio_path": "audio/row_01568707_1755779644853498.wav", "formula": "$\\vert\\Cond_{Z^2}(v_s,i_1,i_2)\\vert=2$", "answer": "Absolute value of Cond sub Z squared open parenthesis v sub s comma i sub 1 comma i sub 2 close parenthesis equals 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 588, "question": "Please read the following math formula symbols: $\\MC(V,I\\sqcupY_1\\sqcup\\dots\\sqcupY_k)=\\{C\\}$", "audio_path": "audio/row_00588682_1755656853802598.wav", "formula": "$\\MC(V,I\\sqcupY_1\\sqcup\\dots\\sqcupY_k)=\\{C\\}$", "answer": "MC of V, I union Y sub 1 union dot dot dot union Y sub k equals curly brace C curly brace", "subset": "mixmath", "task_type": "tts"} +{"index": 589, "question": "请你朗读以下数学公式符号:${{10}^{{{10}^{n}}}}\\equiv {{10}^{4}}\\equiv 4\\left( \\bmod 7 \\right)$", "audio_path": "audio/math_7c6fdcf5-1053-4a99-925c-db71cdc96026.wav", "formula": "${{10}^{{{10}^{n}}}}\\equiv {{10}^{4}}\\equiv 4\\left( \\bmod 7 \\right)$", "answer": "十的十的n次方次方同余于十的四次方同余于四模七", "subset": "mixmath", "task_type": "tts"} +{"index": 590, "question": "Please read the following math formula symbols: $\\wt{c_i}\\leq\\wtc\\leq\\deltta\\theta_k$", "audio_path": "audio/row_01549654_1755777215155633.wav", "formula": "$\\wt{c_i}\\leq\\wtc\\leq\\deltta\\theta_k$", "answer": "wt c sub i is less than or equal to wt c is less than or equal to delta theta sub k.", "subset": "mixmath", "task_type": "tts"} +{"index": 591, "question": "请你朗读以下数学公式符号:$\\begin{cases}\\dfrac{1}{x}+y=3 \\\\ \\dfrac{1}{y}+2x=4 \\end{cases}$", "audio_path": "audio/math_4fb92a51-3630-4356-94d4-8f0d46003625.wav", "formula": "$\\begin{cases}\\dfrac{1}{x}+y=3 \\\\ \\dfrac{1}{y}+2x=4 \\end{cases}$", "answer": "x分之一加y等于三,y分之一加二x等于四", "subset": "mixmath", "task_type": "tts"} +{"index": 592, "question": "Please read the following math formula symbols: $$p\\astq(g)=\\sum_{{g_1\\cdotg_2}=g}p(g_1)q(g_2)$$", "audio_path": "audio/row_01960024_1755829124494465.wav", "formula": "$$p\\astq(g)=\\sum_{{g_1\\cdotg_2}=g}p(g_1)q(g_2)$$", "answer": "p star q of g equals the sum over g1 times g2 equals g of p of g1 times q of g2.", "subset": "mixmath", "task_type": "tts"} +{"index": 593, "question": "Please read the following math formula symbols: $T_{i}=(2T_{\\perpi}+T_{\\paralleli})/3$", "audio_path": "audio/row_01166133_1755729000227323.wav", "formula": "$T_{i}=(2T_{\\perpi}+T_{\\paralleli})/3$", "answer": "T sub i equals open parenthesis 2 T sub perpendicular i plus T sub parallel i close parenthesis divided by 3.", "subset": "mixmath", "task_type": "tts"} +{"index": 594, "question": "请你朗读以下数学公式符号:$\\left\\{ \\begin{array}{*{35}{l}} a=5 \\\\ b=4 \\end{array} \\right.$", "audio_path": "audio/math_ecc957e2-b500-414a-aa80-96024a8460f9.wav", "formula": "$\\left\\{ \\begin{array}{*{35}{l}} a=5 \\\\ b=4 \\end{array} \\right.$", "answer": "a等于五,b等于四", "subset": "mixmath", "task_type": "tts"} +{"index": 595, "question": "Please read the following math formula symbols: $r_{0}=2.07^{+0.23}_{-0.24}\\rm\\,h^{-1}\\,cMpc$", "audio_path": "audio/row_00570531_1755654604217227.wav", "formula": "$r_{0}=2.07^{+0.23}_{-0.24}\\rm\\,h^{-1}\\,cMpc$", "answer": "r sub zero equals 2.07 to the power of positive 0.23 sub negative 0.24, h to the power of negative 1, CMV.", "subset": "mixmath", "task_type": "tts"} +{"index": 596, "question": "请你朗读以下数学公式符号:$(6+8+12+18+21+16)\\div (2+1)=27\\left( {kg} \\right)$", "audio_path": "audio/math_da98573f-1042-49aa-bee1-837d039c11be.wav", "formula": "$(6+8+12+18+21+16)\\div (2+1)=27\\left( {kg} \\right)$", "answer": "六加八加十二加十八加二十一加十六的和除以二加一的和等于二十七千克", "subset": "mixmath", "task_type": "tts"} +{"index": 597, "question": "请你朗读以下数学公式符号:$\\begin{cases} x=\\dfrac{1 }{2 } \\\\ y=\\dfrac{1 }{2 } \\end{cases}$", "audio_path": "audio/math_826d3b79-f786-4700-8b68-7e320b79f130.wav", "formula": "$\\begin{cases} x=\\dfrac{1 }{2 } \\\\ y=\\dfrac{1 }{2 } \\end{cases}$", "answer": "x等于二分之一,y等于二分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 598, "question": "Please read the following math formula symbols: $\\Psi^{(t-1)}\\in\\mathbb{R}^{D_{out}}$", "audio_path": "audio/row_01138240_1755725503805819.wav", "formula": "$\\Psi^{(t-1)}\\in\\mathbb{R}^{D_{out}}$", "answer": "Psi to the power of t minus 1 belongs to the set of real numbers raised to the power of D sub out.", "subset": "mixmath", "task_type": "tts"} +{"index": 599, "question": "请你朗读以下数学公式符号:$=\\left( {{x}^{2}}+5x+5 \\right)\\left( 9x+7 \\right)$", "audio_path": "audio/math_8d12c26f-6f04-4040-ab30-6c047a18f88a.wav", "formula": "$=\\left( {{x}^{2}}+5x+5 \\right)\\left( 9x+7 \\right)$", "answer": "等于x的平方加五x加五的和乘九x加七的和", "subset": "mixmath", "task_type": "tts"} +{"index": 600, "question": "Please read the following math formula symbols: $\\boldsymbol{s}=[w_1,w_2,...,w_n]$", "audio_path": "audio/row_01950627_1755827922535456.wav", "formula": "$\\boldsymbol{s}=[w_1,w_2,...,w_n]$", "answer": "Bold s equals open square bracket, w sub 1, comma, w sub 2, comma, ellipsis, comma, w sub n, close square bracket.", "subset": "mixmath", "task_type": "tts"} +{"index": 601, "question": "请你朗读以下数学公式符号:$\\begin{cases}k=\\dfrac{1}{5} \\\\ b=9 \\\\ \\end{cases}$", "audio_path": "audio/math_01113538-4a92-47a0-8d8e-0707e0154ad3.wav", "formula": "$\\begin{cases}k=\\dfrac{1}{5} \\\\ b=9 \\\\ \\end{cases}$", "answer": "k等于五分之一,b等于九", "subset": "mixmath", "task_type": "tts"} +{"index": 602, "question": "Please read the following math formula symbols: $Y_t^j-Y_{t+1}^j\\geqm$", "audio_path": "audio/row_00560617_1755653365152111.wav", "formula": "$Y_t^j-Y_{t+1}^j\\geqm$", "answer": "Y sub t to the power of j minus Y sub t plus 1 to the power of j is greater than or equal to m.", "subset": "mixmath", "task_type": "tts"} +{"index": 603, "question": "Please read the following math formula symbols: $j_1\\leq\\dots\\leqj_{w+1}$", "audio_path": "audio/row_00358149_1755628573349528.wav", "formula": "$j_1\\leq\\dots\\leqj_{w+1}$", "answer": "j sub 1 is less than or equal to dot dot dot is less than or equal to j sub w plus 1", "subset": "mixmath", "task_type": "tts"} +{"index": 604, "question": "Please read the following math formula symbols: $\\pmb{\\Theta}=\\{\\pmb{\\Theta}[n]\\}_{\\foralln}$", "audio_path": "audio/row_01679416_1755793636099643.wav", "formula": "$\\pmb{\\Theta}=\\{\\pmb{\\Theta}[n]\\}_{\\foralln}$", "answer": "Plus or minus b times capital Theta equals the set of plus or minus b times capital Theta, subscript n, for all n.", "subset": "mixmath", "task_type": "tts"} +{"index": 605, "question": "Please read the following math formula symbols: $$K_{\\XX}+\\BB+\\MM=\\pi^*(K_X+B+M).$$", "audio_path": "audio/row_01913698_1755823265739396.wav", "formula": "$$K_{\\XX}+\\BB+\\MM=\\pi^*(K_X+B+M).$$", "answer": "K sub X X plus B B plus M equals pi star open parenthesis K sub X plus B plus M close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 606, "question": "Please read the following math formula symbols: $\\rR(\\Trh)=\\rp(\\Trh)=3\\,M_P^2\\,\\Hrh^2$", "audio_path": "audio/row_01915776_1755823524978269.wav", "formula": "$\\rR(\\Trh)=\\rp(\\Trh)=3\\,M_P^2\\,\\Hrh^2$", "answer": "Rho times R of Tr h equals Rho of Tr h equals 3 times M sub P squared times H rho squared.", "subset": "mixmath", "task_type": "tts"} +{"index": 607, "question": "Please read the following math formula symbols: $\\int_0^1f_N(T^nx)gdx=0$", "audio_path": "audio/row_01409435_1755759507074374.wav", "formula": "$\\int_0^1f_N(T^nx)gdx=0$", "answer": "Integral from 0 to 1 of f sub N times T to the power of n times x times g times d times x equals 0.", "subset": "mixmath", "task_type": "tts"} +{"index": 608, "question": "Please read the following math formula symbols: $|1-\\F[\\Theta](\\xi)|\\leC|\\xi|^2$", "audio_path": "audio/row_00565470_1755653969491845.wav", "formula": "$|1-\\F[\\Theta](\\xi)|\\leC|\\xi|^2$", "answer": "Absolute value of one minus F of theta of xi is less than or equal to C times the absolute value of xi squared.", "subset": "mixmath", "task_type": "tts"} +{"index": 609, "question": "Please read the following math formula symbols: $$g_i(s)=\\alpha_i(1-s)_++\\beta_i.$$", "audio_path": "audio/row_00661947_1755665992736791.wav", "formula": "$$g_i(s)=\\alpha_i(1-s)_++\\beta_i.$$", "answer": "g sub i of s equals alpha sub i times open parenthesis 1 minus s close parenthesis sub plus beta sub i.", "subset": "mixmath", "task_type": "tts"} +{"index": 610, "question": "Please read the following math formula symbols: $|f(x)-\\langlew^*,\\psi(x)\\rangle|\\leqM.$", "audio_path": "audio/row_01740704_1755801385770041.wav", "formula": "$|f(x)-\\langlew^*,\\psi(x)\\rangle|\\leqM.$", "answer": "Absolute value of f of x minus the inner product of w star and psi of x, less than or equal to M.", "subset": "mixmath", "task_type": "tts"} +{"index": 611, "question": "请你朗读以下数学公式符号:$\\frac{14}{15}-\\left( \\frac{2}{13}-\\frac{1}{15} \\right)$", "audio_path": "audio/math_267dd9b5-bd50-454b-94c8-63288a9db5b5.wav", "formula": "$\\frac{14}{15}-\\left( \\frac{2}{13}-\\frac{1}{15} \\right)$", "answer": "十五分之十四减十三分之二减十五分之一的差", "subset": "mixmath", "task_type": "tts"} +{"index": 612, "question": "请你朗读以下数学公式符号:${{r}_{1}}={{r}_{2}}={{r}_{3}}={{r}_{4}}=\\frac{1}{6}$", "audio_path": "audio/math_48ea17b2-f391-4546-b6fd-1572729fa6ce.wav", "formula": "${{r}_{1}}={{r}_{2}}={{r}_{3}}={{r}_{4}}=\\frac{1}{6}$", "answer": "r一等于r二等于r三等于r四等于六分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 613, "question": "Please read the following math formula symbols: $\\mathcal\\{S^1(\\T_{h})^3$", "audio_path": "audio/row_01555280_1755777934538028.wav", "formula": "$\\mathcal\\{S^1(\\T_{h})^3$", "answer": "script S raised to the power of 1, open parenthesis, T sub h, close parenthesis, raised to the power of 3.", "subset": "mixmath", "task_type": "tts"} +{"index": 614, "question": "Please read the following math formula symbols: $$\\frac{1}{\\log\\logt}\\ll\\zeta(1+it)\\ll\\log\\logt.$$", "audio_path": "audio/row_01245974_1755739027112192.wav", "formula": "$$\\frac{1}{\\log\\logt}\\ll\\zeta(1+it)\\ll\\log\\logt.$$", "answer": "Fraction one divided by log log t is much less than zeta of one plus is much less than log log t.", "subset": "mixmath", "task_type": "tts"} +{"index": 615, "question": "Please read the following math formula symbols: $H_I\\lesssim\\SI{2.5e14}{\\giga\\electronvolt}$", "audio_path": "audio/row_00229646_1755612936798770.wav", "formula": "$H_I\\lesssim\\SI{2.5e14}{\\giga\\electronvolt}$", "answer": "H sub I is less than or approximately equal to 2.5 times 10 to the power of 14 giga electron volts.", "subset": "mixmath", "task_type": "tts"} +{"index": 616, "question": "Please read the following math formula symbols: $\\epsilon=\\eta_1\\sqrt{\\frac{\\log(n(2s+\\widetildes))}{n}}$", "audio_path": "audio/row_01789559_1755807571563861.wav", "formula": "$\\epsilon=\\eta_1\\sqrt{\\frac{\\log(n(2s+\\widetildes))}{n}}$", "answer": "Epsilon equals eta sub 1 square root of the fraction log of n times 2s plus tilde s divided by n.", "subset": "mixmath", "task_type": "tts"} +{"index": 617, "question": "请你朗读以下数学公式符号:$$2\\times 3\\times 2\\times 2\\times 5\\times 2\\times 3\\times 7\\times 2\\times 5\\times 2\\times 7$$", "audio_path": "audio/math_464f7395-8ec5-4c27-af85-ba99ca93459e.wav", "formula": "$$2\\times 3\\times 2\\times 2\\times 5\\times 2\\times 3\\times 7\\times 2\\times 5\\times 2\\times 7$$", "answer": "二乘三乘二乘二乘五乘二乘三乘七乘二乘五乘二乘七", "subset": "mixmath", "task_type": "tts"} +{"index": 618, "question": "Please read the following math formula symbols: $M_j\\in\\dLOfdb{0}{0}$", "audio_path": "audio/row_00239515_1755614126408007.wav", "formula": "$M_j\\in\\dLOfdb{0}{0}$", "answer": "M sub j belongs to the set of differential operators with respect to the variable t, ranging from 0 to 0.", "subset": "mixmath", "task_type": "tts"} +{"index": 619, "question": "请你朗读以下数学公式符号:$=\\frac{3}{5}\\times \\left( 26+31+43 \\right)=\\frac{3}{5}\\times 100=60$", "audio_path": "audio/math_e406cc37-effb-45c4-a3e2-24b027c84992.wav", "formula": "$=\\frac{3}{5}\\times \\left( 26+31+43 \\right)=\\frac{3}{5}\\times 100=60$", "answer": "等于五分之三乘二十六加三十一加四十三的和,等于五分之三乘一百,等于六十", "subset": "mixmath", "task_type": "tts"} +{"index": 620, "question": "Please read the following math formula symbols: $p_{xy}\\,p_{yz}\\lep_{xz}\\,p_{yy}$", "audio_path": "audio/row_00002363_1755585397932006.wav", "formula": "$p_{xy}\\,p_{yz}\\lep_{xz}\\,p_{yy}$", "answer": "p sub x y, p sub y z, less than or equal to p sub x z, p sub y y.", "subset": "mixmath", "task_type": "tts"} +{"index": 621, "question": "请你朗读以下数学公式符号:$$\\sqrt{4} \\times \\sqrt{4} \\times \\sqrt{4}\\times \\sqrt{4}= 2 \\times 2 \\times 2 \\times 2=16$$", "audio_path": "audio/math_5bee3cb2-3118-4ceb-a3b6-0744659b8090.wav", "formula": "$$\\sqrt{4} \\times \\sqrt{4} \\times \\sqrt{4}\\times \\sqrt{4}= 2 \\times 2 \\times 2 \\times 2=16$$", "answer": "根号四乘根号四乘根号四乘根号四等于二乘二乘二乘二等于十六", "subset": "mixmath", "task_type": "tts"} +{"index": 622, "question": "请你朗读以下数学公式符号:$=(27000\\times 8)\\div (125\\times 8)=216000\\div 1000=216$", "audio_path": "audio/math_a803c3a7-489e-4441-aec2-41c1c5e56787.wav", "formula": "$=(27000\\times 8)\\div (125\\times 8)=216000\\div 1000=216$", "answer": "等于两万七千乘八的积除以一百二十五乘八的积等于二十一万六千除以一千等于二百一十六", "subset": "mixmath", "task_type": "tts"} +{"index": 623, "question": "请你朗读以下数学公式符号:$x☆\\left(\\frac{5}{8}☆\\frac{1}{4}\\right)= \\frac{27}{20}$", "audio_path": "audio/math_2b462ea9-b83a-409a-8e8f-0a7d730e2a86.wav", "formula": "$x☆\\left(\\frac{5}{8}☆\\frac{1}{4}\\right)= \\frac{27}{20}$", "answer": "x五角星括号八分之五 五角星 四分之一 括号等于二十分之二十七", "subset": "mixmath", "task_type": "tts"} +{"index": 624, "question": "请你朗读以下数学公式符号:$=\\dfrac{1979\\times 1980+1979\\times 1978}{\\dfrac{1}{2}( 1979\\times 1980+1979\\times 1978 )}$", "audio_path": "audio/math_a2e730d1-3a99-41a8-9ab4-81a1c2012367.wav", "formula": "$=\\dfrac{1979\\times 1980+1979\\times 1978}{\\dfrac{1}{2}( 1979\\times 1980+1979\\times 1978 )}$", "answer": "等于二分之一乘括号一千九百七十九乘一千九百八十加一千九百七十九乘一千九百七十八括号的积 分之 一千九百七十九乘一千九百八十 加一千九百七十九乘一千九百七十八 的和", "subset": "mixmath", "task_type": "tts"} +{"index": 625, "question": "请你朗读以下数学公式符号:$6\\times5\\times5\\times5\\times5\\times5\\times 5=93750$", "audio_path": "audio/math_bb448728-e187-48f6-a4e8-1fcb1acd4979.wav", "formula": "$6\\times5\\times5\\times5\\times5\\times5\\times 5=93750$", "answer": "六乘五乘五乘五乘五乘五乘五等于九万三千七百五十。", "subset": "mixmath", "task_type": "tts"} +{"index": 626, "question": "请你朗读以下数学公式符号:$$\\frac{12}{13}, \\frac{14}{15}, \\frac{21}{23}, \\frac{84}{89}$$", "audio_path": "audio/math_89e5b3e0-78a5-4b00-90c7-dc4487bf280d.wav", "formula": "$$\\frac{12}{13}, \\frac{14}{15}, \\frac{21}{23}, \\frac{84}{89}$$", "answer": "十三分之十二,十五分之十四,二十三分之二十一,八十九分之八十四", "subset": "mixmath", "task_type": "tts"} +{"index": 627, "question": "请你朗读以下数学公式符号:$=\\frac{5}{14}\\div \\left[ \\frac{5}{26}\\times \\left( \\frac{6}{14}+\\frac{7}{14} \\right) \\right]$", "audio_path": "audio/math_44a93207-2b46-4bc6-9866-418afc9de363.wav", "formula": "$=\\frac{5}{14}\\div \\left[ \\frac{5}{26}\\times \\left( \\frac{6}{14}+\\frac{7}{14} \\right) \\right]$", "answer": "等于 十四分之五 除以 二十六分之五 乘 十四分之六加十四分之七的和的积", "subset": "mixmath", "task_type": "tts"} +{"index": 628, "question": "请你朗读以下数学公式符号:$=\\left(3 \\div \\frac{3}{4}\\right):\\left(\\frac{3}{4}\\div \\frac{3}{4}\\right)$", "audio_path": "audio/math_2270b5b6-82c9-4e4a-ae01-f7f0d36af0a9.wav", "formula": "$=\\left(3 \\div \\frac{3}{4}\\right):\\left(\\frac{3}{4}\\div \\frac{3}{4}\\right)$", "answer": "等于三除以四分之三的商比四分之三除以四分之三的商", "subset": "mixmath", "task_type": "tts"} +{"index": 629, "question": "请你朗读以下数学公式符号:$(1+20\\%)x\\times 90+(1+20\\%)\\times 0.8x\\times 10=100x+35200$", "audio_path": "audio/math_e4af99fd-2390-4a86-9b7d-930a61108e3a.wav", "formula": "$(1+20\\%)x\\times 90+(1+20\\%)\\times 0.8x\\times 10=100x+35200$", "answer": "一加百分之二十的和乘x乘九十加一加百分之二十的和乘零点八x乘十等于一百x加三万五千二百", "subset": "mixmath", "task_type": "tts"} +{"index": 630, "question": "Please read the following math formula symbols: $\\frac{1-\\sqrt{4p-3}}{2p}=0.35$", "audio_path": "audio/row_00624139_1755661334608107.wav", "formula": "$\\frac{1-\\sqrt{4p-3}}{2p}=0.35$", "answer": "The fraction one minus the square root of four p minus three divided by two p equals zero point three five.", "subset": "mixmath", "task_type": "tts"} +{"index": 631, "question": "请你朗读以下数学公式符号:$$\\frac{3}{8}\\times \\frac{2}{3}=\\frac{2}{8}=\\frac{1}{4}\\left( m \\right)$$", "audio_path": "audio/math_a8e2bb82-a3c6-45a6-8694-6ec22109611f.wav", "formula": "$$\\frac{3}{8}\\times \\frac{2}{3}=\\frac{2}{8}=\\frac{1}{4}\\left( m \\right)$$", "answer": "八分之三乘三分之二等于八分之二等于四分之一米", "subset": "mixmath", "task_type": "tts"} +{"index": 632, "question": "请你朗读以下数学公式符号:$\\frac{1}{8}=\\frac{1+1}{8\\times (1+1)}=\\frac{1}{16}+\\frac{1}{16}$", "audio_path": "audio/math_21055664-3eb2-4976-80a7-2948b1e42838.wav", "formula": "$\\frac{1}{8}=\\frac{1+1}{8\\times (1+1)}=\\frac{1}{16}+\\frac{1}{16}$", "answer": "八分之一等于八乘一加一的和分之一加一的和等于十六分之一加十六分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 633, "question": "请你朗读以下数学公式符号:$$3.14\\times {{2}^{2}}\\times 1.5\\times \\frac{1}{3}\\div 3.14=4\\times 0.5=2$$", "audio_path": "audio/math_5073449c-a336-4525-a48d-387144d79c72.wav", "formula": "$$3.14\\times {{2}^{2}}\\times 1.5\\times \\frac{1}{3}\\div 3.14=4\\times 0.5=2$$", "answer": "三点一四乘二的平方乘一点五乘三分之一除以三点一四等于四乘零点五等于二", "subset": "mixmath", "task_type": "tts"} +{"index": 634, "question": "请你朗读以下数学公式符号:$$1.2\\div 2+1.2\\div 3+1.2\\div 4+1.2\\div 5+1.2\\div 6$$", "audio_path": "audio/math_f83de322-7eed-4dd1-be57-362c81e33c13.wav", "formula": "$$1.2\\div 2+1.2\\div 3+1.2\\div 4+1.2\\div 5+1.2\\div 6$$", "answer": "一点二除以二加一点二除以三加一点二除以四加一点二除以五加一点二除以六", "subset": "mixmath", "task_type": "tts"} +{"index": 635, "question": "请你朗读以下数学公式符号:$$0.125\\times \\frac{3}{4}+\\frac{1}{8}\\times 8.25+12.5\\%=$$", "audio_path": "audio/math_48e8a0bc-9fc2-4674-a9ef-380a6d92cea5.wav", "formula": "$$0.125\\times \\frac{3}{4}+\\frac{1}{8}\\times 8.25+12.5\\%=$$", "answer": "零点一二五乘四分之三加八分之一乘八点二五加百分之十二点五等于", "subset": "mixmath", "task_type": "tts"} +{"index": 636, "question": "请你朗读以下数学公式符号:$\\frac{5}{7}=0.\\overset{\\centerdot }{\\mathop{7}}\\,1428\\overset{\\centerdot }{\\mathop{5}}\\,$", "audio_path": "audio/math_bd2ee3b9-695e-4e4a-88d3-7a21d0c534a5.wav", "formula": "$\\frac{5}{7}=0.\\overset{\\centerdot }{\\mathop{7}}\\,1428\\overset{\\centerdot }{\\mathop{5}}\\,$", "answer": "七分之五等于零点七一四二八五 七一四二八五循环", "subset": "mixmath", "task_type": "tts"} +{"index": 637, "question": "请你朗读以下数学公式符号:$=\\frac{1}{7}\\times 7\\times \\left( 34\\times \\frac{2}{17} \\right)$", "audio_path": "audio/math_1421d3c8-00d1-4c2a-9dbf-cf9b52b497d1.wav", "formula": "$=\\frac{1}{7}\\times 7\\times \\left( 34\\times \\frac{2}{17} \\right)$", "answer": "等于七分之一乘七乘三十四乘十七分之二的积", "subset": "mixmath", "task_type": "tts"} +{"index": 638, "question": "请你朗读以下数学公式符号:$\\frac{1}{2\\times 4}+\\frac{1}{4\\times 6}+\\ldots +\\frac{1}{2012\\times 2014}+\\frac{1}{2014\\times 2016}$", "audio_path": "audio/math_d5d07913-343b-4a30-835b-1a61e8c6ab68.wav", "formula": "$\\frac{1}{2\\times 4}+\\frac{1}{4\\times 6}+\\ldots +\\frac{1}{2012\\times 2014}+\\frac{1}{2014\\times 2016}$", "answer": "二乘四的积分之一加四乘六的积分之一加省略号加二千零一十二乘二千零一十四的积分之一加二千零一十四乘二千零一十六的积分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 639, "question": "Please read the following math formula symbols: $x\\in\\Hom_{\\mbbZ}(\\mbbZ,\\mbbZ)\\simeq\\mbbZ^\\vee$", "audio_path": "audio/row_01420413_1755760902469333.wav", "formula": "$x\\in\\Hom_{\\mbbZ}(\\mbbZ,\\mbbZ)\\simeq\\mbbZ^\\vee$", "answer": "x belongs to the set of integers from the pair of integers modulo Z, to the pair of integers modulo Z.", "subset": "mixmath", "task_type": "tts"} +{"index": 640, "question": "请你朗读以下数学公式符号:$\\frac{35}{64}\\div \\left( \\frac{1}{8}+\\frac{3}{4} \\right)$", "audio_path": "audio/math_735e480f-a6df-4a80-8236-87f4d5fb827b.wav", "formula": "$\\frac{35}{64}\\div \\left( \\frac{1}{8}+\\frac{3}{4} \\right)$", "answer": "六十四分之三十五除以八分之一加四分之三的和", "subset": "mixmath", "task_type": "tts"} +{"index": 641, "question": "请你朗读以下数学公式符号:${{(11111)}_{2}}={{2}^{4}}+{{2}^{3}}+{{2}^{2}}+{{2}^{1}}+{{2}^{0}}={{(31)}_{10}}$", "audio_path": "audio/math_b4163d75-b9f9-4db9-be1e-67391158bfd1.wav", "formula": "${{(11111)}_{2}}={{2}^{4}}+{{2}^{3}}+{{2}^{2}}+{{2}^{1}}+{{2}^{0}}={{(31)}_{10}}$", "answer": "二进制一 一 一 一 一等于二的四次方加二的三次方加二的平方加二的一次方加二的零次方等于十进制三十一", "subset": "mixmath", "task_type": "tts"} +{"index": 642, "question": "请你朗读以下数学公式符号:$\\frac{12345678987654321}{999999999\\times 999999999}=$", "audio_path": "audio/math_ac73183f-7ac9-487c-9b0f-4404f259372d.wav", "formula": "$\\frac{12345678987654321}{999999999\\times 999999999}=$", "answer": "九亿九千九百九十九万九千九百九十九乘九亿九千九百九十九万九千九百九十九的积分之一亿两千三百四十五万六千七百八十九亿八千七百六十五万四千三百二十一等于", "subset": "mixmath", "task_type": "tts"} +{"index": 643, "question": "请你朗读以下数学公式符号:$$\\overline{x}=\\frac{{x}_{1}+{x}_{2}+…+{x}_{n}}{n}$$", "audio_path": "audio/math_4c4d032c-e228-43db-9cda-8d568dd7754b.wav", "formula": "$$\\overline{x}=\\frac{{x}_{1}+{x}_{2}+…+{x}_{n}}{n}$$", "answer": "x拔 等于n分之x一加x二加 一直加到 加xn的和", "subset": "mixmath", "task_type": "tts"} +{"index": 644, "question": "Please read the following math formula symbols: $\\sin\\xi=2J^D/J^E$", "audio_path": "audio/row_01866802_1755817331999811.wav", "formula": "$\\sin\\xi=2J^D/J^E$", "answer": "The sine of xi equals 2 times J raised to the power of D divided by J raised to the power of E.", "subset": "mixmath", "task_type": "tts"} +{"index": 645, "question": "请你朗读以下数学公式符号:$0.258\\times 448+0.417\\times 258+1.35\\times 25.8$", "audio_path": "audio/math_7ac82ab3-a42e-4928-9c97-f653269fd4cc.wav", "formula": "$0.258\\times 448+0.417\\times 258+1.35\\times 25.8$", "answer": "零点二五八乘四百四十八加零点四一七乘二百五十八加一点三五乘二十五点八", "subset": "mixmath", "task_type": "tts"} +{"index": 646, "question": "请你朗读以下数学公式符号:$\\begin{cases}m+1\\ne 0 \\\\ {{m}^{2}}=1 \\end{cases}$", "audio_path": "audio/math_a1db1911-0131-435e-9708-ada24cdbe3b6.wav", "formula": "$\\begin{cases}m+1\\ne 0 \\\\ {{m}^{2}}=1 \\end{cases}$", "answer": "m加一不等于零,m的平方等于一", "subset": "mixmath", "task_type": "tts"} +{"index": 647, "question": "请你朗读以下数学公式符号:$\\sqrt{\\frac{2}{3}}=\\sqrt{\\frac{6}{9}}=\\frac{\\sqrt{6}}{3}$", "audio_path": "audio/math_6576eb9d-f48c-489c-a707-456514b3b8a3.wav", "formula": "$\\sqrt{\\frac{2}{3}}=\\sqrt{\\frac{6}{9}}=\\frac{\\sqrt{6}}{3}$", "answer": "根号三分之二等于根号九分之六等于三分之根号六", "subset": "mixmath", "task_type": "tts"} +{"index": 648, "question": "请你朗读以下数学公式符号:$$3.14\\times {{\\left( 0.5\\div 2 \\right)}^{2}}\\times 800=157\\left( {{{m}}^{2}} \\right)$$", "audio_path": "audio/math_f8aef59a-4bfa-48d0-9beb-fbfc97490a7e.wav", "formula": "$$3.14\\times {{\\left( 0.5\\div 2 \\right)}^{2}}\\times 800=157\\left( {{{m}}^{2}} \\right)$$", "answer": "三点一四乘零点五除以二的商的平方乘八百等于一百五十七平方米", "subset": "mixmath", "task_type": "tts"} +{"index": 649, "question": "请你朗读以下数学公式符号:$$1+3\\frac{1}{6}+5\\frac{1}{12}+7\\frac{1}{20}+9\\frac{1}{30}+11\\frac{1}{42}+13\\frac{1}{56}+15\\frac{1}{72}+17\\frac{1}{90}$$", "audio_path": "audio/math_50a96d6b-13db-4e54-bfd2-c4ccbf15a7c6.wav", "formula": "$$1+3\\frac{1}{6}+5\\frac{1}{12}+7\\frac{1}{20}+9\\frac{1}{30}+11\\frac{1}{42}+13\\frac{1}{56}+15\\frac{1}{72}+17\\frac{1}{90}$$", "answer": "一加三又六分之一,加五又十二分之一,加七又二十分之一,加九又三十分之一,加十一又四十二分之一,加十三又五十六分之一,加十五又七十二分之一,加十七又九十分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 650, "question": "请你朗读以下数学公式符号:$\\left(\\dfrac{1}{2}\\right)^2+\\dfrac{1}{\\left(\\dfrac{1}{2}\\right)^2}=4+\\dfrac{1}{4}=\\dfrac{17}{4}$", "audio_path": "audio/math_8a4845e0-0916-4ced-9978-35778c61fccd.wav", "formula": "$\\left(\\dfrac{1}{2}\\right)^2+\\dfrac{1}{\\left(\\dfrac{1}{2}\\right)^2}=4+\\dfrac{1}{4}=\\dfrac{17}{4}$", "answer": "二分之一的平方加二分之一的平方分之一等于四加四分之一等于四分之十七", "subset": "mixmath", "task_type": "tts"} +{"index": 651, "question": "请你朗读以下数学公式符号:$${{\\left( {{a}^{2}} \\right)}^{3}}\\cdot {{\\left( {{a}^{2}} \\right)}^{4}}\\div {{\\left( {{a}^{2}} \\right)}^{5}}$$", "audio_path": "audio/math_2087383b-6d82-4b8c-9c9d-47af8c1fbbf5.wav", "formula": "$${{\\left( {{a}^{2}} \\right)}^{3}}\\cdot {{\\left( {{a}^{2}} \\right)}^{4}}\\div {{\\left( {{a}^{2}} \\right)}^{5}}$$", "answer": "a的平方的三次方乘a的平方的四次方除以a的平方的五次方", "subset": "mixmath", "task_type": "tts"} +{"index": 652, "question": "请你朗读以下数学公式符号:$\\sqrt{\\frac{1}{7}}+\\sqrt{28}{=}\\frac{\\sqrt{7}}{7}{+2}\\sqrt{7}{=}\\frac{15}{7}\\sqrt{7}$", "audio_path": "audio/math_84328a8b-6934-45df-94cb-fa92745ade52.wav", "formula": "$\\sqrt{\\frac{1}{7}}+\\sqrt{28}{=}\\frac{\\sqrt{7}}{7}{+2}\\sqrt{7}{=}\\frac{15}{7}\\sqrt{7}$", "answer": "根号下七分之一 加 根号二十八 等于 七分之根号七 加 二倍的根号七 等于 七分之十五倍的根号七", "subset": "mixmath", "task_type": "tts"} +{"index": 653, "question": "Please read the following math formula symbols: $f\\neqR_{i+1}(a_i,a_{i+1})$", "audio_path": "audio/row_01996437_1755833695965121.wav", "formula": "$f\\neqR_{i+1}(a_i,a_{i+1})$", "answer": "f not equal to R sub i plus 1 open parenthesis a sub i comma a sub i plus 1 close parenthesis", "subset": "mixmath", "task_type": "tts"} +{"index": 654, "question": "Please read the following math formula symbols: $\\sum_{k=1}^N||B_k-A_k||^2_\\infty$", "audio_path": "audio/row_00123646_1755600052306419.wav", "formula": "$\\sum_{k=1}^N||B_k-A_k||^2_\\infty$", "answer": "Sum from k equals 1 to N of the absolute value of the difference between B sub k and A sub k, squared, infinity norm.", "subset": "mixmath", "task_type": "tts"} +{"index": 655, "question": "请你朗读以下数学公式符号:$79\\times \\frac{65}{77}=(77+2)\\times \\frac{65}{77}=77\\times \\frac{65}{77}+2\\times \\frac{65}{77}=65+1\\frac{53}{77}=66\\frac{53}{77}$", "audio_path": "audio/math_607467ce-1445-4ca2-bf5a-21514598eba4.wav", "formula": "$79\\times \\frac{65}{77}=(77+2)\\times \\frac{65}{77}=77\\times \\frac{65}{77}+2\\times \\frac{65}{77}=65+1\\frac{53}{77}=66\\frac{53}{77}$", "answer": "七十九乘七十七分之六十五等于七十七加二的和乘七十七分之六十五等于七十七乘七十七分之六十五加二乘七十七分之六十五等于六十五加一又七十七分之五十三等于六十六又七十七分之五十三", "subset": "mixmath", "task_type": "tts"} +{"index": 656, "question": "Please read the following math formula symbols: $i\\in\\N,(s_i,m_i,s_{i+1})\\in\\Delta$", "audio_path": "audio/row_00984474_1755706293203337.wav", "formula": "$i\\in\\N,(s_i,m_i,s_{i+1})\\in\\Delta$", "answer": "i belongs to the set of natural numbers, such that s sub i, m sub i, s sub i plus one, belongs to the set Delta.", "subset": "mixmath", "task_type": "tts"} +{"index": 657, "question": "Please read the following math formula symbols: $U_i^\\alpha=U_i^{\\alpha-1}\\capH_2$", "audio_path": "audio/row_01881169_1755819155693643.wav", "formula": "$U_i^\\alpha=U_i^{\\alpha-1}\\capH_2$", "answer": "U sub i to the power of alpha equals U sub i to the power of alpha minus 1 intersection H sub 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 658, "question": "请你朗读以下数学公式符号:$\\left\\{ 0,3\\frac{3}{4},0.01,\\frac{3}{7},2013 \\right\\}$", "audio_path": "audio/math_48100691-4aab-46de-9665-df39695ea62f.wav", "formula": "$\\left\\{ 0,3\\frac{3}{4},0.01,\\frac{3}{7},2013 \\right\\}$", "answer": "由零,三又四分之三,零点零一,七分之三,二千零一十三组成的集合", "subset": "mixmath", "task_type": "tts"} +{"index": 659, "question": "请你朗读以下数学公式符号:$4+118+46+82=\\left( 54+46 \\right)+\\left( 118+82 \\right)=100+200=300$", "audio_path": "audio/math_8ae9cb83-a857-4881-a0ba-d1ef640afaf2.wav", "formula": "$4+118+46+82=\\left( 54+46 \\right)+\\left( 118+82 \\right)=100+200=300$", "answer": "四加一百一十八加四十六加八十二等于五十四加四十六的和加一百一十八加八十二的和等于一百加二百等于三百", "subset": "mixmath", "task_type": "tts"} +{"index": 660, "question": "请你朗读以下数学公式符号:$\\begin{eqnarray}&&2.1\\times 0.3+2.1\\div 0.7\\\\ &=&0.63+3\\\\ &=&3.63.\\end{eqnarray}$", "audio_path": "audio/math_60c7a8e7-a642-4c3d-96c0-e63898b2b3b1.wav", "formula": "$\\begin{eqnarray}&&2.1\\times 0.3+2.1\\div 0.7\\\\ &=&0.63+3\\\\ &=&3.63.\\end{eqnarray}$", "answer": "二点一乘零点三加二点一除以零点七,等于零点六三加三,等于三点六三。", "subset": "mixmath", "task_type": "tts"} +{"index": 661, "question": "请你朗读以下数学公式符号:$$a\\times \\frac{2}{3}=b\\times 0.75=c\\times \\frac{3}{2}=1$$", "audio_path": "audio/math_79f39fcf-c553-40fb-8d3d-c5fcd7e13b54.wav", "formula": "$$a\\times \\frac{2}{3}=b\\times 0.75=c\\times \\frac{3}{2}=1$$", "answer": "a乘三分之二等于b乘零点七五等于c乘二分之三等于一", "subset": "mixmath", "task_type": "tts"} +{"index": 662, "question": "Please read the following math formula symbols: $F_0\\subseteq\\dots\\subseteqF_l=[n]$", "audio_path": "audio/row_00941268_1755700927116663.wav", "formula": "$F_0\\subseteq\\dots\\subseteqF_l=[n]$", "answer": "F sub 0 is a subset of dot dot dot is a subset of F sub l equals open bracket n close bracket.", "subset": "mixmath", "task_type": "tts"} +{"index": 663, "question": "请你朗读以下数学公式符号:$= (1998+2)+(199.8+0.2)+(19.98+0.02)+(1.998+0.002)$", "audio_path": "audio/math_def5ce02-5b51-4db5-a52c-cb68c3061f84.wav", "formula": "$= (1998+2)+(199.8+0.2)+(19.98+0.02)+(1.998+0.002)$", "answer": "等于一千九百九十八加二的和,加一百九十九点八加零点二的和,加十九点九八加零点零二的和,加一点九九八加零点零零二的和", "subset": "mixmath", "task_type": "tts"} +{"index": 664, "question": "请你朗读以下数学公式符号:$=49\\times \\frac{13}{4}+30\\times \\frac{13}{4}+\\frac{13}{4}$", "audio_path": "audio/math_b0da90d1-8002-4a8e-b601-9915887b9ba7.wav", "formula": "$=49\\times \\frac{13}{4}+30\\times \\frac{13}{4}+\\frac{13}{4}$", "answer": "等于四十九乘 四分之十三加三十乘 四分之十三加四分之十三", "subset": "mixmath", "task_type": "tts"} +{"index": 665, "question": "请你朗读以下数学公式符号:${{5}^{4}}\\times {{7}^{6}}\\times {{5}^{6}}\\times {{7}^{4}}={{35}^{4}}\\times {{35}^{6}}={{35}^{10}}$", "audio_path": "audio/math_b58f3d33-03e3-462d-b760-596d9fc7b2f9.wav", "formula": "${{5}^{4}}\\times {{7}^{6}}\\times {{5}^{6}}\\times {{7}^{4}}={{35}^{4}}\\times {{35}^{6}}={{35}^{10}}$", "answer": "五的四次方乘七的六次方乘五的六次方乘七的四次方等于三十五的四次方乘三十五的六次方等于三十五的十次方", "subset": "mixmath", "task_type": "tts"} +{"index": 666, "question": "Please read the following math formula symbols: $1\\leqi\\leq|L_t|$", "audio_path": "audio/row_00311043_1755622853377076.wav", "formula": "$1\\leqi\\leq|L_t|$", "answer": "One is less than or equal to i, which is less than or equal to the absolute value of L sub t.", "subset": "mixmath", "task_type": "tts"} +{"index": 667, "question": "请你朗读以下数学公式符号:$\\cot \\frac{A}{2}+\\cot \\frac{B}{2}+\\cot \\frac{C}{2}=\\frac{{{\\left( a+b+c \\right)}^{2}}}{4S}$", "audio_path": "audio/math_6a7fc53b-9e38-49ce-b24c-0487884d7ef9.wav", "formula": "$\\cot \\frac{A}{2}+\\cot \\frac{B}{2}+\\cot \\frac{C}{2}=\\frac{{{\\left( a+b+c \\right)}^{2}}}{4S}$", "answer": "cotangent 二分之A 加 cotangent 二分之B 加 cotangent 二分之C 等于 四S分之a加b加c的和的平方", "subset": "mixmath", "task_type": "tts"} +{"index": 668, "question": "请你朗读以下数学公式符号:$32{d}{{m}^{2}}=32\\times 100{c}{{m}^{2}}=3200{c}{{m}^{2}}$", "audio_path": "audio/math_aecadb41-4949-495d-b441-164990dcb4bd.wav", "formula": "$32{d}{{m}^{2}}=32\\times 100{c}{{m}^{2}}=3200{c}{{m}^{2}}$", "answer": "三十二平方分米等于三十二乘一百平方厘米等于三千二百平方厘米", "subset": "mixmath", "task_type": "tts"} +{"index": 669, "question": "Please read the following math formula symbols: $X=\\{\\mathbf{x}_i\\in\\mathbb{R}^3:i=1,2,...,n\\}$", "audio_path": "audio/row_01163317_1755728650337173.wav", "formula": "$X=\\{\\mathbf{x}_i\\in\\mathbb{R}^3:i=1,2,...,n\\}$", "answer": "X equals the set of x sub i in the real numbers cubed such that i equals 1, 2, dot dot dot, n.", "subset": "mixmath", "task_type": "tts"} +{"index": 670, "question": "Please read the following math formula symbols: $\\rho_{{\\rmc}0}h^{-2}=10.54\\,{\\rmGeV}\\,{\\rmm}^{-3}$", "audio_path": "audio/row_01983373_1755832027498922.wav", "formula": "$\\rho_{{\\rmc}0}h^{-2}=10.54\\,{\\rmGeV}\\,{\\rmm}^{-3}$", "answer": "Rho sub c zero, h to the power of negative two, equals 10.54 gigaelectron volts, meters to the power of negative three.", "subset": "mixmath", "task_type": "tts"} +{"index": 671, "question": "请你朗读以下数学公式符号:$a^{2m+n}=({a^{m}})^{2}\\times a^{n}=3^{2}\\times 5=9\\times 5=45$", "audio_path": "audio/math_08ce6ec2-b3e6-4f4f-a920-8d92e15021a7.wav", "formula": "$a^{2m+n}=({a^{m}})^{2}\\times a^{n}=3^{2}\\times 5=9\\times 5=45$", "answer": "a 的二 m 加 n 次方等于a 的 m 次方的平方乘 a 的 n 次方等于三的平方乘五等于九乘五等于四十五", "subset": "mixmath", "task_type": "tts"} +{"index": 672, "question": "Please read the following math formula symbols: $\\mathcal{P}_a\\to\\mathbb{R}^{\\dim\\mathcal{P}_a}$", "audio_path": "audio/row_00207507_1755610254732743.wav", "formula": "$\\mathcal{P}_a\\to\\mathbb{R}^{\\dim\\mathcal{P}_a}$", "answer": "P sub a maps to the set of real numbers raised to the power of the dimension of P sub a.", "subset": "mixmath", "task_type": "tts"} +{"index": 673, "question": "Please read the following math formula symbols: $\\mathbf{s}_\\tau:\\R^p\\to\\R^p$", "audio_path": "audio/row_01000382_1755708279070545.wav", "formula": "$\\mathbf{s}_\\tau:\\R^p\\to\\R^p$", "answer": "Math bold s sub tau, colon, capital R raised to the power of p, arrow, capital R raised to the power of p.", "subset": "mixmath", "task_type": "tts"} +{"index": 674, "question": "Please read the following math formula symbols: $\\p\\left[Z\\geqk+1\\vertZs_1\\circf_2(x)$", "audio_path": "audio/row_01961244_1755829272753435.wav", "formula": "$s_1\\circf_2(x_1)>s_1\\circf_2(x)$", "answer": "s sub 1 circle f sub 2 of x sub 1 greater than s sub 1 circle f sub 2 of x", "subset": "mixmath", "task_type": "tts"} +{"index": 712, "question": "请你朗读以下数学公式符号:$\\frac{7}{11}\\times \\frac{8}{25}+\\frac{3}{11}\\times \\frac{7}{25}$", "audio_path": "audio/math_1a278989-4695-4120-81cd-f9559f67309a.wav", "formula": "$\\frac{7}{11}\\times \\frac{8}{25}+\\frac{3}{11}\\times \\frac{7}{25}$", "answer": "十一分之七乘二十五分之八加十一分之三乘二十五分之七", "subset": "mixmath", "task_type": "tts"} +{"index": 713, "question": "Please read the following math formula symbols: $A_{i\\rightarrowj}=\\overline{\\big(A_{i\\rightarrowj}\\big)^*}$", "audio_path": "audio/row_02005415_1755834826104837.wav", "formula": "$A_{i\\rightarrowj}=\\overline{\\big(A_{i\\rightarrowj}\\big)^*}$", "answer": "A sub i to j equals the complex conjugate of A sub i to j, raised to the power of star.", "subset": "mixmath", "task_type": "tts"} +{"index": 714, "question": "请你朗读以下数学公式符号:$\\begin{eqnarray}&&600\\div25\\\\ &=&600\\div25\\div4\\times4\\\\ &=&(600\\times4)\\div(25\\times4)\\\\ &=&2400\\div100\\\\ &=&24\\end{eqnarray}$", "audio_path": "audio/math_bcf32fa2-0038-432d-9c0c-293c72369df5.wav", "formula": "$\\begin{eqnarray}&&600\\div25\\\\ &=&600\\div25\\div4\\times4\\\\ &=&(600\\times4)\\div(25\\times4)\\\\ &=&2400\\div100\\\\ &=&24\\end{eqnarray}$", "answer": "六百除以二十五等于六百除以二十五除以四乘四等于六百乘四的积除以二十五乘四的积等于两千四百除以一百等于二十四", "subset": "mixmath", "task_type": "tts"} +{"index": 715, "question": "Please read the following math formula symbols: $f\\in(I^{[pq]}:I)\\setminusI^{[pq]}$", "audio_path": "audio/row_01855131_1755815851059295.wav", "formula": "$f\\in(I^{[pq]}:I)\\setminusI^{[pq]}$", "answer": "f belongs to the set of I raised to the power of p q, colon I set minus I raised to the power of p q.", "subset": "mixmath", "task_type": "tts"} +{"index": 716, "question": "请你朗读以下数学公式符号:$=\\left( \\frac{32}{9}+\\frac{5}{6} \\right)\\times \\frac{9}{2}$", "audio_path": "audio/math_83efa88e-f078-4812-ab23-fd2c49f95a5a.wav", "formula": "$=\\left( \\frac{32}{9}+\\frac{5}{6} \\right)\\times \\frac{9}{2}$", "answer": "等于九分之三十二与六分之五的和乘二分之九", "subset": "mixmath", "task_type": "tts"} +{"index": 717, "question": "Please read the following math formula symbols: $r_d=|\\{n\\in\\N:\\text{depth}(n)=d\\}|$", "audio_path": "audio/row_00586963_1755656655276947.wav", "formula": "$r_d=|\\{n\\in\\N:\\text{depth}(n)=d\\}|$", "answer": "r sub d equals the cardinality of the set of n in the set of natural numbers such that the depth of n equals d.", "subset": "mixmath", "task_type": "tts"} +{"index": 718, "question": "请你朗读以下数学公式符号:$$\\left( \\frac{5}{5+3}+\\frac{7}{7+9} \\right):\\left( \\frac{3}{5+3}+\\frac{9}{7+9} \\right)=\\frac{17}{16}:\\frac{15}{16}=17:15$$", "audio_path": "audio/math_9c63be40-08b5-4b23-929b-113a1a914172.wav", "formula": "$$\\left( \\frac{5}{5+3}+\\frac{7}{7+9} \\right):\\left( \\frac{3}{5+3}+\\frac{9}{7+9} \\right)=\\frac{17}{16}:\\frac{15}{16}=17:15$$", "answer": "五加三的和分之五与七加九的和分之七的和比五加三的和分之三与七加九的和分之九的和等于十六分之十七比十六分之十五等于十七比十五", "subset": "mixmath", "task_type": "tts"} +{"index": 719, "question": "请你朗读以下数学公式符号:$\\begin{eqnarray}\n&=&\\frac{8}{9}\\times \\frac{3}{4}\\div \\frac{3}{16}\\\\\n&=&\\frac{8}{9}\\times \\frac{3}{4}\\times \\frac{16}{3}\\\\\n&=&\\frac{32}{9}.\\end{eqnarray}$", "audio_path": "audio/math_29dc51cd-345c-4cc6-8014-2bc4a68f5177.wav", "formula": "$\\begin{eqnarray}\n&=&\\frac{8}{9}\\times \\frac{3}{4}\\div \\frac{3}{16}\\\\\n&=&\\frac{8}{9}\\times \\frac{3}{4}\\times \\frac{16}{3}\\\\\n&=&\\frac{32}{9}.\\end{eqnarray}$", "answer": "等于九分之八乘四分之三除十六分之三,等于九分之八乘四分之三乘三分之十六,等于九分之三十二", "subset": "mixmath", "task_type": "tts"} +{"index": 720, "question": "请你朗读以下数学公式符号:$\\frac{{1}}{{(}x{+1)}^{{2}}} = \\frac{x}{x{+1}} \\cdot \\frac{x{+2}}{x{+1}}$", "audio_path": "audio/math_b1e86a81-b0f6-47a5-bbbb-2aa3a2bee2b8.wav", "formula": "$\\frac{{1}}{{(}x{+1)}^{{2}}} = \\frac{x}{x{+1}} \\cdot \\frac{x{+2}}{x{+1}}$", "answer": "x加一的和的平方分之一等于x加一的和分之x乘x加一的和分之x加二的和", "subset": "mixmath", "task_type": "tts"} +{"index": 721, "question": "请你朗读以下数学公式符号:$$\\begin{eqnarray}4x+16x&=&80\\\\ 20x&=&80\\\\ x&=&4.\\end{eqnarray}$$", "audio_path": "audio/math_84c4493a-1856-406a-a85a-efd0153723bf.wav", "formula": "$$\\begin{eqnarray}4x+16x&=&80\\\\ 20x&=&80\\\\ x&=&4.\\end{eqnarray}$$", "answer": "四x加十六x等于八十。二十x等于八十。x等于四。", "subset": "mixmath", "task_type": "tts"} +{"index": 722, "question": "Please read the following math formula symbols: $|B|\\gg\\frac{\\sqrt{q}}{3\\logq}$", "audio_path": "audio/row_01636882_1755788271092489.wav", "formula": "$|B|\\gg\\frac{\\sqrt{q}}{3\\logq}$", "answer": "Absolute value of B is much greater than the square root of q divided by 3 times the logarithm of q.", "subset": "mixmath", "task_type": "tts"} +{"index": 723, "question": "请你朗读以下数学公式符号:$$(84+85+86+87+88+89+90)\\div 7=87\\times 7\\div 7=87$$", "audio_path": "audio/math_6ff15550-9f63-44a8-af0a-417e6c7fa2e4.wav", "formula": "$$(84+85+86+87+88+89+90)\\div 7=87\\times 7\\div 7=87$$", "answer": "八十四加八十五加八十六加八十七加八十八加八十九加九十的和除以七等于八十七乘七除以七等于八十七", "subset": "mixmath", "task_type": "tts"} +{"index": 724, "question": "请你朗读以下数学公式符号:$5568=2\\times 2\\times 2\\times 2\\times 2\\times 2\\times 3\\times 29$", "audio_path": "audio/math_8d842f96-d210-4eca-b956-c3caace1391f.wav", "formula": "$5568=2\\times 2\\times 2\\times 2\\times 2\\times 2\\times 3\\times 29$", "answer": "五千五百六十八等于二乘二乘二乘二乘二乘二乘三乘二十九", "subset": "mixmath", "task_type": "tts"} +{"index": 725, "question": "Please read the following math formula symbols: $[\\mu_1+\\gamma/2,\\mu_1-\\gamma]\\cap\\Gamma(S)=\\{\\mu_1\\}$", "audio_path": "audio/row_00327475_1755624838420119.wav", "formula": "$[\\mu_1+\\gamma/2,\\mu_1-\\gamma]\\cap\\Gamma(S)=\\{\\mu_1\\}$", "answer": "The interval from mu 1 plus gamma divided by 2 to mu 1 minus gamma intersection Gamma of S is equal to mu 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 726, "question": "请你朗读以下数学公式符号:$\\left\\{ \\begin{matrix}a=3 \\\\ b=5 \\\\\\end{matrix} \\right.$", "audio_path": "audio/math_049417c3-ac88-4812-8400-4e3306283b35.wav", "formula": "$\\left\\{ \\begin{matrix}a=3 \\\\ b=5 \\\\\\end{matrix} \\right.$", "answer": "a等于三,b等于五", "subset": "mixmath", "task_type": "tts"} +{"index": 727, "question": "Please read the following math formula symbols: $g_{s\\eta}=g_0+s\\dotg_{\\eta}+\\frakq(s\\eta,s\\eta)$", "audio_path": "audio/row_00250115_1755615419000253.wav", "formula": "$g_{s\\eta}=g_0+s\\dotg_{\\eta}+\\frakq(s\\eta,s\\eta)$", "answer": "g sub s eta equals g sub 0 plus s dot g sub eta plus q open parenthesis s eta comma s eta close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 728, "question": "Please read the following math formula symbols: $\\tildeX'=\\frac{1}{N_1}\\sum_{T_{i}=1}X_i'$", "audio_path": "audio/row_00591281_1755657187488176.wav", "formula": "$\\tildeX'=\\frac{1}{N_1}\\sum_{T_{i}=1}X_i'$", "answer": "The tilde X prime equals one over N sub 1 times the sum over T sub i equals 1 of X sub i prime.", "subset": "mixmath", "task_type": "tts"} +{"index": 729, "question": "请你朗读以下数学公式符号:$$=\\frac{1\\times 3+1}{1\\times 3}+\\frac{3\\times 5+1}{3\\times 5}+\\frac{5\\times 7+1}{5\\times 7}+\\frac{7\\times 9+1}{7\\times 9}+\\frac{9\\times 11+1}{9\\times 11}$$", "audio_path": "audio/math_4ff82759-f0ee-49bf-99a8-c0fb7cd55dd1.wav", "formula": "$$=\\frac{1\\times 3+1}{1\\times 3}+\\frac{3\\times 5+1}{3\\times 5}+\\frac{5\\times 7+1}{5\\times 7}+\\frac{7\\times 9+1}{7\\times 9}+\\frac{9\\times 11+1}{9\\times 11}$$", "answer": "等于一乘三的积分之一乘三加一,加三乘五的积分之三乘五加一,加五乘七的积分之五乘七加一,加七乘九的积分之七乘九加一,加九乘十一的积分之九乘十一加一", "subset": "mixmath", "task_type": "tts"} +{"index": 730, "question": "Please read the following math formula symbols: $\\lambda(u_j(A_j)-u_i(A_i))=\\varepsilon$", "audio_path": "audio/row_00697817_1755670433071754.wav", "formula": "$\\lambda(u_j(A_j)-u_i(A_i))=\\varepsilon$", "answer": "Lambda times the difference between u sub j of A sub j and u sub i of A sub i equals epsilon.", "subset": "mixmath", "task_type": "tts"} +{"index": 731, "question": "Please read the following math formula symbols: $y:=-\\ln{\\frac{\\delta}{\\arms(\\arms-1)}}>1$", "audio_path": "audio/row_02039316_1755839094430427.wav", "formula": "$y:=-\\ln{\\frac{\\delta}{\\arms(\\arms-1)}}>1$", "answer": "y is equal to negative natural logarithm of the fraction delta divided by the arms of negative one, greater than one.", "subset": "mixmath", "task_type": "tts"} +{"index": 732, "question": "Please read the following math formula symbols: $r_1(w)\\ler\\ler_2(w)$", "audio_path": "audio/row_00549234_1755651969979251.wav", "formula": "$r_1(w)\\ler\\ler_2(w)$", "answer": "r sub 1 of w is less than or equal to r, which is less than or equal to r sub 2 of w.", "subset": "mixmath", "task_type": "tts"} +{"index": 733, "question": "Please read the following math formula symbols: $\\hat{\\boldw}^{(i)}\\in\\{\\pm1\\}^n$", "audio_path": "audio/row_01947147_1755827488622991.wav", "formula": "$\\hat{\\boldw}^{(i)}\\in\\{\\pm1\\}^n$", "answer": "The hat bold w raised to the power of i belongs to the set of plus or minus 1 raised to the power of n.", "subset": "mixmath", "task_type": "tts"} +{"index": 734, "question": "Please read the following math formula symbols: $[-1+\\frac{2i^*-2}{2^L},-1+\\frac{2i^*}{2^L}]$", "audio_path": "audio/row_00658903_1755665620132734.wav", "formula": "$[-1+\\frac{2i^*-2}{2^L},-1+\\frac{2i^*}{2^L}]$", "answer": "Negative one plus two i star minus two divided by two L, negative one plus two i star divided by two L.", "subset": "mixmath", "task_type": "tts"} +{"index": 735, "question": "请你朗读以下数学公式符号:$n\\Theta 3=n\\times \\left(n+1\\right)\\times \\left(n+2\\right)=24$", "audio_path": "audio/math_539cc456-ff34-465b-bcff-cc861df0a352.wav", "formula": "$n\\Theta 3=n\\times \\left(n+1\\right)\\times \\left(n+2\\right)=24$", "answer": "n theta 三 等于n乘n加一的和,再乘n加二的和等于二十四", "subset": "mixmath", "task_type": "tts"} +{"index": 736, "question": "Please read the following math formula symbols: $\\mathbf{\\Phi}_{\\varepsilon}:\\R^N\\to\\R^N$", "audio_path": "audio/row_00909023_1755696900126320.wav", "formula": "$\\mathbf{\\Phi}_{\\varepsilon}:\\R^N\\to\\R^N$", "answer": "Math bold Phi subscript epsilon, colon, R raised to the power of N, arrow, R raised to the power of N.", "subset": "mixmath", "task_type": "tts"} +{"index": 737, "question": "Please read the following math formula symbols: $m=O(\\s{M}p+\\sqrt{\\s{M}p\\log\\s{N}\\delta^{-1}})$", "audio_path": "audio/row_00281045_1755619203783284.wav", "formula": "$m=O(\\s{M}p+\\sqrt{\\s{M}p\\log\\s{N}\\delta^{-1}})$", "answer": "m equals big O of M p plus the square root of M p log N delta to the power of negative one.", "subset": "mixmath", "task_type": "tts"} +{"index": 738, "question": "请你朗读以下数学公式符号:$6\\frac{1}{5}=6\\frac{1}{5}\\times 100\\%=\\frac{31}{5}\\times 100\\%=620\\%$", "audio_path": "audio/math_e0447dcd-6289-4595-9c38-93a02c9c257b.wav", "formula": "$6\\frac{1}{5}=6\\frac{1}{5}\\times 100\\%=\\frac{31}{5}\\times 100\\%=620\\%$", "answer": "六又五分之一等于六又五分之一乘百分之百等于五分之三十一乘百分之百等于百分之六百二十", "subset": "mixmath", "task_type": "tts"} +{"index": 739, "question": "Please read the following math formula symbols: $[\\hat{H}_g,\\hat{Q}^5]\\neq0$", "audio_path": "audio/row_01625946_1755786890364460.wav", "formula": "$[\\hat{H}_g,\\hat{Q}^5]\\neq0$", "answer": "Open square bracket, hat H sub g, comma, hat Q raised to the power of 5, close square bracket, not equal to 0.", "subset": "mixmath", "task_type": "tts"} +{"index": 740, "question": "请你朗读以下数学公式符号:$\\frac{\\left( a+b \\right)\\left( a+c \\right)\\left( b+c \\right)}{abc}=$", "audio_path": "audio/math_419bf94e-786c-436f-a83a-6a7df064f5f0.wav", "formula": "$\\frac{\\left( a+b \\right)\\left( a+c \\right)\\left( b+c \\right)}{abc}=$", "answer": "a b c 分之 a加b的和乘a加c的和乘b加c的和 等于", "subset": "mixmath", "task_type": "tts"} +{"index": 741, "question": "Please read the following math formula symbols: $E(P_n)=\\{v_iv_{i+1}\\,|\\,1\\leqi\\leqn\\}$", "audio_path": "audio/row_00106770_1755598007522929.wav", "formula": "$E(P_n)=\\{v_iv_{i+1}\\,|\\,1\\leqi\\leqn\\}$", "answer": "E of P sub n equals the sum of v sub i times v sub i plus 1, for all i from 1 to n.", "subset": "mixmath", "task_type": "tts"} +{"index": 742, "question": "请你朗读以下数学公式符号:$58\\times 19+42\\times 20+58\\times 27+42\\times 26=4600$", "audio_path": "audio/math_e331e9bc-f75e-4740-b747-094808c349a1.wav", "formula": "$58\\times 19+42\\times 20+58\\times 27+42\\times 26=4600$", "answer": "五十八乘十九加四十二乘二十加五十八乘二十七加四十二乘二十六等于四千六百", "subset": "mixmath", "task_type": "tts"} +{"index": 743, "question": "请你朗读以下数学公式符号:$$\\left( 400+800\\times 4 \\right)\\div \\left( 24+26 \\right)=72$$", "audio_path": "audio/math_20d6cfb1-2dc1-47c3-9ce8-b5f4f8494d3e.wav", "formula": "$$\\left( 400+800\\times 4 \\right)\\div \\left( 24+26 \\right)=72$$", "answer": "四百加八百乘四 的和,除以二十四加二十六的和等于七十二", "subset": "mixmath", "task_type": "tts"} +{"index": 744, "question": "Please read the following math formula symbols: ${\\ddH_t^{(N)}=\\sum_jE_j^{(N)}\\,\\ddB^j_t}$", "audio_path": "audio/row_00646827_1755664127422750.wav", "formula": "${\\ddH_t^{(N)}=\\sum_jE_j^{(N)}\\,\\ddB^j_t}$", "answer": "d H sub t superscript N equals the sum over j of E sub j superscript N, d B superscript j sub t.", "subset": "mixmath", "task_type": "tts"} +{"index": 745, "question": "Please read the following math formula symbols: $Y=[y_1,y_2,\\ldots,y_{200}]^{\\top}$", "audio_path": "audio/row_00515651_1755647859134750.wav", "formula": "$Y=[y_1,y_2,\\ldots,y_{200}]^{\\top}$", "answer": "Y equals open square bracket y sub 1, comma y sub 2, comma ellipsis, comma y sub 200 close square bracket transpose.", "subset": "mixmath", "task_type": "tts"} +{"index": 746, "question": "请你朗读以下数学公式符号:$1\\times \\left( 1+\\frac{2}{5} \\right)=\\frac{7}{5}$", "audio_path": "audio/math_acbb739e-57cf-48f4-b86e-108e844bbb6b.wav", "formula": "$1\\times \\left( 1+\\frac{2}{5} \\right)=\\frac{7}{5}$", "answer": "一乘一加五分之二的和等于五分之七", "subset": "mixmath", "task_type": "tts"} +{"index": 747, "question": "Please read the following math formula symbols: $\\mathbf{a}_j=(a_j^x,a_j^y,a_j^z)$", "audio_path": "audio/row_00226663_1755612582751474.wav", "formula": "$\\mathbf{a}_j=(a_j^x,a_j^y,a_j^z)$", "answer": "a sub j equals open parenthesis a sub j superscript x, a sub j superscript y, a sub j superscript z close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 748, "question": "请你朗读以下数学公式符号:$12=1\\times 12=2\\times 6=3\\times 4=2\\times 2\\times 3$", "audio_path": "audio/math_dc8572dc-9941-4300-b456-88ef76c52f76.wav", "formula": "$12=1\\times 12=2\\times 6=3\\times 4=2\\times 2\\times 3$", "answer": "十二等于一乘十二等于二乘六等于三乘四等于二乘二乘三", "subset": "mixmath", "task_type": "tts"} +{"index": 749, "question": "请你朗读以下数学公式符号:$={{({{x}^{2}}+12)}^{2}}+15x({{x}^{2}}+12)+14{{x}^{2}}$", "audio_path": "audio/math_cc357482-3da8-48ee-bbd3-7d3dde191057.wav", "formula": "$={{({{x}^{2}}+12)}^{2}}+15x({{x}^{2}}+12)+14{{x}^{2}}$", "answer": "等于x的平方加十二的和的平方加十五x乘x的平方加十二的和加十四乘x的平方", "subset": "mixmath", "task_type": "tts"} +{"index": 750, "question": "请你朗读以下数学公式符号:$x=3+2\\sin 60^\\circ =3+2\\times \\frac{\\sqrt{3}}{2}=3+\\sqrt{3}$", "audio_path": "audio/math_75b03214-704c-400a-9273-fe3fe6790d3f.wav", "formula": "$x=3+2\\sin 60^\\circ =3+2\\times \\frac{\\sqrt{3}}{2}=3+\\sqrt{3}$", "answer": "x等于三加二乘 sine 六十度 等于三加二乘 二分之根号三 等于三加根号三", "subset": "mixmath", "task_type": "tts"} +{"index": 751, "question": "请你朗读以下数学公式符号:$3\\div \\frac{1}{2}\\div \\frac{1}{5}=3\\times 2\\times 5=30$", "audio_path": "audio/math_359678fb-2c1a-44d0-836f-74181195d922.wav", "formula": "$3\\div \\frac{1}{2}\\div \\frac{1}{5}=3\\times 2\\times 5=30$", "answer": "三除以二分之一除以五分之一等于三乘二乘五等于三十", "subset": "mixmath", "task_type": "tts"} +{"index": 752, "question": "请你朗读以下数学公式符号:$A_{6}^{6}=6!=6\\times 5\\times 4\\times 3\\times 2\\times 1=720$", "audio_path": "audio/math_030ee944-61f4-44ef-b9f6-e13fa526200b.wav", "formula": "$A_{6}^{6}=6!=6\\times 5\\times 4\\times 3\\times 2\\times 1=720$", "answer": "A六六等于六的阶乘等于六乘五乘四乘三乘二乘一等于七百二十", "subset": "mixmath", "task_type": "tts"} +{"index": 753, "question": "请你朗读以下数学公式符号:$$\\left\\{\\begin{array}{c}3x+y=1+a\\\\x+3y=3\\end{array}\\right .$$", "audio_path": "audio/math_b5d3ba41-bf9c-42a0-9ffd-976053a0a2d6.wav", "formula": "$$\\left\\{\\begin{array}{c}3x+y=1+a\\\\x+3y=3\\end{array}\\right .$$", "answer": "方程组:三x加y等于一加a;x加三y等于三。", "subset": "mixmath", "task_type": "tts"} +{"index": 754, "question": "Please read the following math formula symbols: $\\mathcal{P}(x)=[w(x)]\\in\\Omega_{\\check{M}}$", "audio_path": "audio/row_00719014_1755673078066969.wav", "formula": "$\\mathcal{P}(x)=[w(x)]\\in\\Omega_{\\check{M}}$", "answer": "Math calligraphic P of x equals open square bracket w of x close square bracket belongs to Omega sub check M.", "subset": "mixmath", "task_type": "tts"} +{"index": 755, "question": "请你朗读以下数学公式符号:$\\dfrac{8{{x}^{2}}}{{{x}^{2}}+2x+1}\\div \\dfrac{6x}{x+1}$", "audio_path": "audio/math_b54db75c-7260-4f10-a2e2-c7ded0ca0b3d.wav", "formula": "$\\dfrac{8{{x}^{2}}}{{{x}^{2}}+2x+1}\\div \\dfrac{6x}{x+1}$", "answer": "x平方 加 二x 加 一的和 分之 八 x平方 ,再除以x加一的和分之六x", "subset": "mixmath", "task_type": "tts"} +{"index": 756, "question": "请你朗读以下数学公式符号:$40\\times 30\\times 10+20\\times 20\\times h=40\\times 30\\times h$", "audio_path": "audio/math_ce15967a-1061-41cb-b6bf-eea799a02b8b.wav", "formula": "$40\\times 30\\times 10+20\\times 20\\times h=40\\times 30\\times h$", "answer": "四十乘三十乘十加二十乘二十乘h等于四十乘三十乘h", "subset": "mixmath", "task_type": "tts"} +{"index": 757, "question": "Please read the following math formula symbols: $T\\in\\mathrm{Rep}_{\\O_E}^{\\mathrm{cris}}(G_K)$", "audio_path": "audio/row_01242536_1755738595084133.wav", "formula": "$T\\in\\mathrm{Rep}_{\\O_E}^{\\mathrm{cris}}(G_K)$", "answer": "T belongs to the set of real numbers, subscript O sub E, superscript crit, open parenthesis G sub K, close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 758, "question": "请你朗读以下数学公式符号:$2*\\left( 3*4 \\right)=2*\\frac{3+4}{3\\times 4}=2*\\frac{7}{12}=\\left( 2+\\frac{7}{12} \\right)\\div \\left( 2\\times \\frac{7}{12} \\right)=\\frac{31}{12}\\div \\frac{7}{6}=\\frac{31}{2}\\times \\frac{1}{7}=\\frac{31}{14}$", "audio_path": "audio/math_d3bf5301-9049-4efc-b5c8-16401046e40c.wav", "formula": "$2*\\left( 3*4 \\right)=2*\\frac{3+4}{3\\times 4}=2*\\frac{7}{12}=\\left( 2+\\frac{7}{12} \\right)\\div \\left( 2\\times \\frac{7}{12} \\right)=\\frac{31}{12}\\div \\frac{7}{6}=\\frac{31}{2}\\times \\frac{1}{7}=\\frac{31}{14}$", "answer": "二 星号 括号 三 星号 四 括号 等于 二 星号 三乘四的积分之三加四的和 等于二 星号 十二分之七等于 二加十二分之七的和除以二乘十二分之七的积 等于十二分之三十一除以 六分之七 等于二分之三十一乘 七分之一 等于十四分之三十一", "subset": "mixmath", "task_type": "tts"} +{"index": 759, "question": "请你朗读以下数学公式符号:$\\frac{11}{15}=\\frac{11\\times 2}{15\\times 2}=\\frac{22}{30}$", "audio_path": "audio/math_f31aecb8-b870-4dd3-99e9-2f078a063020.wav", "formula": "$\\frac{11}{15}=\\frac{11\\times 2}{15\\times 2}=\\frac{22}{30}$", "answer": "十五分之十一等于十五乘二分之十一乘二等于三十分之二十二", "subset": "mixmath", "task_type": "tts"} +{"index": 760, "question": "请你朗读以下数学公式符号:$11.\\dot{1}\\times 6+1.\\dot{1}\\dot{1}\\times 6+1.1\\dot{1}\\times 6=\\left( \\frac{100}{9}+\\frac{10}{9}+\\frac{10}{9} \\right)\\times 6=80$", "audio_path": "audio/math_2c2f0a83-8413-445c-bd0b-bcce1d655f5d.wav", "formula": "$11.\\dot{1}\\times 6+1.\\dot{1}\\dot{1}\\times 6+1.1\\dot{1}\\times 6=\\left( \\frac{100}{9}+\\frac{10}{9}+\\frac{10}{9} \\right)\\times 6=80$", "answer": "十一点一 一循环 乘六 加 一点一一 一一循环 乘 六 加 一点一一 一循环 乘 六 等于 九分之一百加九分之十加九分之十的和 乘 六 等于 八十", "subset": "mixmath", "task_type": "tts"} +{"index": 761, "question": "请你朗读以下数学公式符号:$$84\\div 7+85\\div 7+86\\div 7+87\\div 7+88\\div 7+89\\div 7+90\\div 7$$", "audio_path": "audio/math_623fea98-ca13-42d5-aa16-843357fbee52.wav", "formula": "$$84\\div 7+85\\div 7+86\\div 7+87\\div 7+88\\div 7+89\\div 7+90\\div 7$$", "answer": "八十四除以七加八十五除以七加八十六除以七加八十七除以七加八十八除以七加八十九除以七加九十除以七", "subset": "mixmath", "task_type": "tts"} +{"index": 762, "question": "Please read the following math formula symbols: $\\hsmid=\\ell^{2}(\\Z\\setminus\\set{0})$", "audio_path": "audio/row_00186460_1755607672852341.wav", "formula": "$\\hsmid=\\ell^{2}(\\Z\\setminus\\set{0})$", "answer": "h sub m i d equals ell squared, open parenthesis, Z set minus set open brace 0 close brace, close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 763, "question": "请你朗读以下数学公式符号:$x\\div \\frac{4}{7}\\times \\frac{4}{7}=\\frac{1}{14}\\times \\frac{4}{7}$", "audio_path": "audio/math_10936fd4-9767-4a11-a7ca-d8b90efec67d.wav", "formula": "$x\\div \\frac{4}{7}\\times \\frac{4}{7}=\\frac{1}{14}\\times \\frac{4}{7}$", "answer": "x 除以 七分之四 乘 七分之四 等于 十四分之一 乘 七分之四", "subset": "mixmath", "task_type": "tts"} +{"index": 764, "question": "请你朗读以下数学公式符号:$$0.75=\\frac{75}{100}=\\frac{3}{4}=\\frac{12}{16}=\\frac{6}{8}$$", "audio_path": "audio/math_67ddb3eb-8e14-485f-b85f-54869cc84fe3.wav", "formula": "$$0.75=\\frac{75}{100}=\\frac{3}{4}=\\frac{12}{16}=\\frac{6}{8}$$", "answer": "零点七五等于一百分之七十五等于四分之三等于十六分之十二等于八分之六", "subset": "mixmath", "task_type": "tts"} +{"index": 765, "question": "请你朗读以下数学公式符号:$$=\\frac{1}{27}{{a}^{9}}{{b}^{6}}\\div \\frac{9}{16}{{a}^{2}}{{b}^{4}}=\\frac{16}{243}{{a}^{7}}{{b}^{2}}$$", "audio_path": "audio/math_a7828c35-abf2-4989-a734-f3dc55e20ca9.wav", "formula": "$$=\\frac{1}{27}{{a}^{9}}{{b}^{6}}\\div \\frac{9}{16}{{a}^{2}}{{b}^{4}}=\\frac{16}{243}{{a}^{7}}{{b}^{2}}$$", "answer": "等于二十七分之一a的九次方b的六次方除以十六分之九a的平方b的四次方等于二百四十三分之十六a的七次方b的平方", "subset": "mixmath", "task_type": "tts"} +{"index": 766, "question": "Please read the following math formula symbols: $\\Phi:=\\{(Y_n,\\xi_n)\\}_{n\\in\\n_0}$", "audio_path": "audio/row_00772798_1755679781817709.wav", "formula": "$\\Phi:=\\{(Y_n,\\xi_n)\\}_{n\\in\\n_0}$", "answer": "Phi is equal to the set of tuples Y sub n comma xi sub n, where n belongs to the set of n sub 0.", "subset": "mixmath", "task_type": "tts"} +{"index": 767, "question": "Please read the following math formula symbols: $\\mathbf{1\\leq\\tilde{\\delta}_0\\leqk_B}$", "audio_path": "audio/row_00510879_1755647262345959.wav", "formula": "$\\mathbf{1\\leq\\tilde{\\delta}_0\\leqk_B}$", "answer": "Math bold one is less than or equal to tilde delta sub zero, which is less than or equal to k sub B.", "subset": "mixmath", "task_type": "tts"} +{"index": 768, "question": "请你朗读以下数学公式符号:$={{a}^{m}}\\cdot {{\\left( {{a}^{n}} \\right)}^{2}}$", "audio_path": "audio/math_10d445dc-67cd-4838-98c8-51017bed9c44.wav", "formula": "$={{a}^{m}}\\cdot {{\\left( {{a}^{n}} \\right)}^{2}}$", "answer": "等于 a 的 m 次方乘a 的 n 次方的平方", "subset": "mixmath", "task_type": "tts"} +{"index": 769, "question": "Please read the following math formula symbols: $p^{NF}=1-2p^{PF}-p^{BF}$", "audio_path": "audio/row_00637576_1755662971388506.wav", "formula": "$p^{NF}=1-2p^{PF}-p^{BF}$", "answer": "p to the power of N F equals one minus two p to the power of P F minus p to the power of B F.", "subset": "mixmath", "task_type": "tts"} +{"index": 770, "question": "Please read the following math formula symbols: $T_p=\\{T_1,T_2,T_2,3T_2,T\\}$", "audio_path": "audio/row_01280132_1755743315424056.wav", "formula": "$T_p=\\{T_1,T_2,T_2,3T_2,T\\}$", "answer": "T sub p equals the set containing T sub 1, T sub 2, T sub 2, 3 T sub 2, and T.", "subset": "mixmath", "task_type": "tts"} +{"index": 771, "question": "请你朗读以下数学公式符号:$$=\\frac{2}{3}+\\frac{3}{5}+\\frac{5}{7}+\\frac{1}{3}+\\frac{1}{5}+\\frac{1}{5}+\\frac{1}{7}+\\frac{1}{7}+\\frac{1}{10}+\\frac{9}{10}=4$$", "audio_path": "audio/math_249ef282-845a-48fa-9b1d-cf99f704c26e.wav", "formula": "$$=\\frac{2}{3}+\\frac{3}{5}+\\frac{5}{7}+\\frac{1}{3}+\\frac{1}{5}+\\frac{1}{5}+\\frac{1}{7}+\\frac{1}{7}+\\frac{1}{10}+\\frac{9}{10}=4$$", "answer": "等于三分之二加五分之三加七分之五加三分之一加五分之一加五分之一加七分之一加七分之一加十分之一加十分之九等于四", "subset": "mixmath", "task_type": "tts"} +{"index": 772, "question": "Please read the following math formula symbols: $R_1,S_1\\in\\bdS^{0}_\\delta(\\mathcalD)$", "audio_path": "audio/row_01103103_1755721108402152.wav", "formula": "$R_1,S_1\\in\\bdS^{0}_\\delta(\\mathcalD)$", "answer": "R sub 1, S sub 1 belongs to the set of bounded S to the power of 0 sub delta of D.", "subset": "mixmath", "task_type": "tts"} +{"index": 773, "question": "Please read the following math formula symbols: $d_1,d_3,d_2\\in\\mathbb{N}\\cup\\lbrace0\\rbrace$", "audio_path": "audio/row_01394162_1755757609988691.wav", "formula": "$d_1,d_3,d_2\\in\\mathbb{N}\\cup\\lbrace0\\rbrace$", "answer": "d sub 1, d sub 3, d sub 2 belong to the set of natural numbers union with the set containing 0.", "subset": "mixmath", "task_type": "tts"} +{"index": 774, "question": "请你朗读以下数学公式符号:$=2019\\times \\frac{2020}{2019\\times 2020+2019}+\\frac{1}{2021}$", "audio_path": "audio/math_8527221b-5497-4114-bd6e-826d648b48a6.wav", "formula": "$=2019\\times \\frac{2020}{2019\\times 2020+2019}+\\frac{1}{2021}$", "answer": "等于二千零一十九 乘 二千零一十九乘二千零二十加二千零一十九的和 分之 二千零二十,再加二千零二十一分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 775, "question": "Please read the following math formula symbols: $|S_i|=|\\Omega_{d_i}|-1$", "audio_path": "audio/row_01407885_1755759310005621.wav", "formula": "$|S_i|=|\\Omega_{d_i}|-1$", "answer": "The absolute value of S sub i is equal to the absolute value of Omega sub d sub i minus 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 776, "question": "Please read the following math formula symbols: $|V_i|\\leq\\frac{\\v(G)}{k}+1$", "audio_path": "audio/row_02007465_1755835088275438.wav", "formula": "$|V_i|\\leq\\frac{\\v(G)}{k}+1$", "answer": "Absolute value of V sub i is less than or equal to the fraction v of G divided by k plus 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 777, "question": "Please read the following math formula symbols: $P_i(y)=\\min\\{P_1(y),\\dots,P_n(y)\\}.$", "audio_path": "audio/row_01613842_1755785373220658.wav", "formula": "$P_i(y)=\\min\\{P_1(y),\\dots,P_n(y)\\}.$", "answer": "P sub i of y equals the minimum of P sub 1 of y, dot dot dot, P sub n of y.", "subset": "mixmath", "task_type": "tts"} +{"index": 778, "question": "请你朗读以下数学公式符号:$\\therefore \\frac{1}{{{a}^{2}}}+\\frac{1}{{{b}^{2}}}=\\frac{1}{{{h}^{2}}}$", "audio_path": "audio/math_8674124d-42fc-4e99-81b5-c10f9a00b69f.wav", "formula": "$\\therefore \\frac{1}{{{a}^{2}}}+\\frac{1}{{{b}^{2}}}=\\frac{1}{{{h}^{2}}}$", "answer": "所以,a的平方分之一加b的平方分之一等于h的平方分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 779, "question": "请你朗读以下数学公式符号:$\\sqrt{6\\frac{6}{35}}=\\sqrt{{6+}\\frac{6}{35}}{=}\\sqrt{\\frac{216}{35}}{=}\\sqrt{\\frac{{{6}^{2}}\\times 6}{35}}{=}6\\sqrt{\\frac{6}{35}}$", "audio_path": "audio/math_9cfa747d-709e-4f83-acfb-99ae5308903d.wav", "formula": "$\\sqrt{6\\frac{6}{35}}=\\sqrt{{6+}\\frac{6}{35}}{=}\\sqrt{\\frac{216}{35}}{=}\\sqrt{\\frac{{{6}^{2}}\\times 6}{35}}{=}6\\sqrt{\\frac{6}{35}}$", "answer": "根号下六又三十五分之六 等于根号下六加三十五分之六的和 等于根号下三十五分之二百一十六 等于根号下三十五 分之 六的平方乘六的积 等于六倍的根号下三十五分之六", "subset": "mixmath", "task_type": "tts"} +{"index": 780, "question": "请你朗读以下数学公式符号:$$\\left( a\\times b \\right)\\times c=a\\times \\left( b\\times c \\right)$$", "audio_path": "audio/math_a98a20fd-5202-4892-b759-f430e79d8225.wav", "formula": "$$\\left( a\\times b \\right)\\times c=a\\times \\left( b\\times c \\right)$$", "answer": "a乘b的积乘c等于a乘b乘c的积", "subset": "mixmath", "task_type": "tts"} +{"index": 781, "question": "Please read the following math formula symbols: $k_0e_0^2/(k_BT/a)\\sim10$", "audio_path": "audio/row_01331452_1755749698603449.wav", "formula": "$k_0e_0^2/(k_BT/a)\\sim10$", "answer": "k sub zero e sub zero squared divided by k sub B T divided by a is approximately equal to 10.", "subset": "mixmath", "task_type": "tts"} +{"index": 782, "question": "请你朗读以下数学公式符号:$=\\left( 11+19 \\right)+\\left( 12+18 \\right)+\\left( 13+17 \\right)+\\left( 14+16 \\right)+15$", "audio_path": "audio/math_9caa3287-43aa-4c84-90ea-21ccaf82c8ab.wav", "formula": "$=\\left( 11+19 \\right)+\\left( 12+18 \\right)+\\left( 13+17 \\right)+\\left( 14+16 \\right)+15$", "answer": "等于十一加十九的和加十二加十八的和加十三加十七的和加十四加十六的和加十五", "subset": "mixmath", "task_type": "tts"} +{"index": 783, "question": "Please read the following math formula symbols: $C^0(\\overline{B(x_0,r)})$", "audio_path": "audio/row_00376101_1755630772828164.wav", "formula": "$C^0(\\overline{B(x_0,r)})$", "answer": "C raised to the power of 0, the closure of the set B with center x sub 0 and radius r.", "subset": "mixmath", "task_type": "tts"} +{"index": 784, "question": "请你朗读以下数学公式符号:$\\left({{x}^{2}}+4x+6\\right)\\left({{x}^{2}}+8x+6\\right)$", "audio_path": "audio/math_5e0eb12e-cdd1-4d51-bdd7-cef22ce1460e.wav", "formula": "$\\left({{x}^{2}}+4x+6\\right)\\left({{x}^{2}}+8x+6\\right)$", "answer": "x平方加四x加六的和乘x平方加八x加六的和", "subset": "mixmath", "task_type": "tts"} +{"index": 785, "question": "Please read the following math formula symbols: $\\frac12\\ell(J)\\leq\\ell(I)\\leq2\\ell(J)$", "audio_path": "audio/row_01232967_1755737410893711.wav", "formula": "$\\frac12\\ell(J)\\leq\\ell(I)\\leq2\\ell(J)$", "answer": "Fraction 12 times L of J is less than or equal to L of I is less than or equal to 2 times L of J.", "subset": "mixmath", "task_type": "tts"} +{"index": 786, "question": "Please read the following math formula symbols: $h_t(\\gamma)=\\Vert\\gamma-\\delta_t\\Vert_2^2-\\diam(\\Delta)^2$", "audio_path": "audio/row_01252896_1755739885411130.wav", "formula": "$h_t(\\gamma)=\\Vert\\gamma-\\delta_t\\Vert_2^2-\\diam(\\Delta)^2$", "answer": "h sub t of gamma equals the norm of gamma minus delta sub t times the norm of 2 squared minus the dim of Delta squared.", "subset": "mixmath", "task_type": "tts"} +{"index": 787, "question": "Please read the following math formula symbols: $\\sigma_\\ess(C)\\subset\\sigma^0_\\ess(C)\\subset\\sigma(C)$", "audio_path": "audio/row_01914925_1755823430483240.wav", "formula": "$\\sigma_\\ess(C)\\subset\\sigma^0_\\ess(C)\\subset\\sigma(C)$", "answer": "Sigma sub s of C is a subset of sigma to the power of 0 sub s of C is a subset of sigma of C.", "subset": "mixmath", "task_type": "tts"} +{"index": 788, "question": "请你朗读以下数学公式符号:$\\frac{1}{4}=\\frac{1\\times 4}{4\\times 4}=\\frac{4}{16}$", "audio_path": "audio/math_5b91c70e-bf47-476f-b497-f9926c4a5870.wav", "formula": "$\\frac{1}{4}=\\frac{1\\times 4}{4\\times 4}=\\frac{4}{16}$", "answer": "四分之一等于四乘四分之一乘四等于十六分之四", "subset": "mixmath", "task_type": "tts"} +{"index": 789, "question": "Please read the following math formula symbols: $\\mathbb{S}^{n-1}\\subseteq\\mathbb{R}^{n}$", "audio_path": "audio/row_01216742_1755735364906516.wav", "formula": "$\\mathbb{S}^{n-1}\\subseteq\\mathbb{R}^{n}$", "answer": "The set of S to the power of n minus one is a subset of the set of R to the power of n.", "subset": "mixmath", "task_type": "tts"} +{"index": 790, "question": "Please read the following math formula symbols: $\\rho(R_d)=\\dot{M}_{\\rmout}/(4\\piR_d^2v_w)$", "audio_path": "audio/row_01061944_1755715978866113.wav", "formula": "$\\rho(R_d)=\\dot{M}_{\\rmout}/(4\\piR_d^2v_w)$", "answer": "Rho of R sub d equals M dot sub out divided by 4 pi R sub d squared v sub w.", "subset": "mixmath", "task_type": "tts"} +{"index": 791, "question": "请你朗读以下数学公式符号:$=\\left( \\sum\\limits_{{{t}_{1}}=1}^{9}{{{x}^{{{t}_{1}}}}} \\right)\\left( \\sum\\limits_{{{t}_{2}}=0}^{9}{{{x}^{{{t}_{2}}}}} \\right)\\left( \\sum\\limits_{{{t}_{3}}=0}^{9}{{{x}^{{{t}_{3}}}}} \\right)\\left( \\sum\\limits_{{{t}_{4}}=0}^{9}{{{x}^{{{t}_{4}}}}} \\right)$", "audio_path": "audio/math_d81f4bc0-aac4-434d-a4a5-2edabaf24036.wav", "formula": "$=\\left( \\sum\\limits_{{{t}_{1}}=1}^{9}{{{x}^{{{t}_{1}}}}} \\right)\\left( \\sum\\limits_{{{t}_{2}}=0}^{9}{{{x}^{{{t}_{2}}}}} \\right)\\left( \\sum\\limits_{{{t}_{3}}=0}^{9}{{{x}^{{{t}_{3}}}}} \\right)\\left( \\sum\\limits_{{{t}_{4}}=0}^{9}{{{x}^{{{t}_{4}}}}} \\right)$", "answer": "等于t 一从一到九对x的t一次方的和,乘从t二从零到九对x的t二次方的和,乘从t三从零到九对x的t三次方的和,乘从t四从零到九对x的t四次方的和", "subset": "mixmath", "task_type": "tts"} +{"index": 792, "question": "Please read the following math formula symbols: $P(\\a)\\colon\\cA^d\\to\\cA^m$", "audio_path": "audio/row_01514421_1755772754628496.wav", "formula": "$P(\\a)\\colon\\cA^d\\to\\cA^m$", "answer": "P of a, colon c times A to the power of d, arrow c times A to the power of m.", "subset": "mixmath", "task_type": "tts"} +{"index": 793, "question": "请你朗读以下数学公式符号:$=\\dfrac{8{{x}^{2}}}{{{x}^{2}}+2x+1}\\cdot \\dfrac{x+1}{6x}$", "audio_path": "audio/math_1ea7467c-255a-4038-9cb8-a86e7a811884.wav", "formula": "$=\\dfrac{8{{x}^{2}}}{{{x}^{2}}+2x+1}\\cdot \\dfrac{x+1}{6x}$", "answer": "x平方 加 二x 加 一的和 分之 八 x平方 ,再乘六x分之x加一的和", "subset": "mixmath", "task_type": "tts"} +{"index": 794, "question": "Please read the following math formula symbols: $\\mathbf{T}^{\\Phi^{\\mathrm{hom}}(s,\\cdot)}$", "audio_path": "audio/row_01821338_1755811593544731.wav", "formula": "$\\mathbf{T}^{\\Phi^{\\mathrm{hom}}(s,\\cdot)}$", "answer": "Math bold T raised to the power of Phi raised to the power of hom, open parenthesis s, comma dot, close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 795, "question": "请你朗读以下数学公式符号:$${{a}^{2}}\\times 6\\times {{\\left( \\frac{6}{a} \\right)}^{3}}={{6}^{2}}\\times 6\\times 2$$", "audio_path": "audio/math_7ccdf336-c42c-4e48-aa77-7019fbb281e5.wav", "formula": "$${{a}^{2}}\\times 6\\times {{\\left( \\frac{6}{a} \\right)}^{3}}={{6}^{2}}\\times 6\\times 2$$", "answer": "a的平方乘六乘a分之六的立方等于六的平方乘六乘二", "subset": "mixmath", "task_type": "tts"} +{"index": 796, "question": "Please read the following math formula symbols: $a_{so}(K_n)\\geq|V_1|$", "audio_path": "audio/row_02049778_1755840422251358.wav", "formula": "$a_{so}(K_n)\\geq|V_1|$", "answer": "a sub c o, open parenthesis, K sub n, close parenthesis, greater than or equal to, absolute value of, V sub 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 797, "question": "请你朗读以下数学公式符号:$$\\frac{5}{6}\\div \\frac{3}{2}\\times \\frac{3}{4}=\\frac{5}{6}\\times \\frac{2}{3}\\times \\frac{3}{4}=\\frac{5}{12}$$", "audio_path": "audio/math_62b3551a-e71b-42e1-baf1-042dcab249de.wav", "formula": "$$\\frac{5}{6}\\div \\frac{3}{2}\\times \\frac{3}{4}=\\frac{5}{6}\\times \\frac{2}{3}\\times \\frac{3}{4}=\\frac{5}{12}$$", "answer": "六分之五除以二分之三乘四分之三等于六分之五乘三分之二乘四分之三等于十二分之五", "subset": "mixmath", "task_type": "tts"} +{"index": 798, "question": "请你朗读以下数学公式符号:$2\\left( x+5 \\right)\\geqslant 3\\left( x+3 \\right)$", "audio_path": "audio/math_bd5d3d1a-1288-4f00-8598-6b0fc331112b.wav", "formula": "$2\\left( x+5 \\right)\\geqslant 3\\left( x+3 \\right)$", "answer": "二乘x加五的和大于等于三乘x加三的和", "subset": "mixmath", "task_type": "tts"} +{"index": 799, "question": "Please read the following math formula symbols: $o_p(1/\\sqrt{n})+\\min\\qty{r\\norm{\\mu-\\bestmu}_2,r^2})$", "audio_path": "audio/row_01943654_1755827045442571.wav", "formula": "$o_p(1/\\sqrt{n})+\\min\\qty{r\\norm{\\mu-\\bestmu}_2,r^2})$", "answer": "o sub p of 1 over square root of n plus minimum r norm mu minus max m u sub 2, r squared", "subset": "mixmath", "task_type": "tts"} +{"index": 800, "question": "Please read the following math formula symbols: $g_{a\\gamma\\gamma}^{\\rmfid}=10^{-10}\\,{\\rmGeV}^{-1}$", "audio_path": "audio/row_00781164_1755680842694861.wav", "formula": "$g_{a\\gamma\\gamma}^{\\rmfid}=10^{-10}\\,{\\rmGeV}^{-1}$", "answer": "g sub a gamma gamma superscript fid equals 10 to the power of negative 10 GeV to the power of negative 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 801, "question": "请你朗读以下数学公式符号:$\\left( \\sqrt{a} \\right)^{2} + \\left( \\sqrt{b} \\right)^{2} = m$", "audio_path": "audio/math_1488af9b-d602-487a-a20d-94fdcb8cd2f7.wav", "formula": "$\\left( \\sqrt{a} \\right)^{2} + \\left( \\sqrt{b} \\right)^{2} = m$", "answer": "根号a的平方加根号b的平方等于m", "subset": "mixmath", "task_type": "tts"} +{"index": 802, "question": "Please read the following math formula symbols: $K^\\circ\\subset\\cO(X)^\\circ$", "audio_path": "audio/row_02076720_1755843886000857.wav", "formula": "$K^\\circ\\subset\\cO(X)^\\circ$", "answer": "K raised to the power of degree is a subset of big O of X raised to the power of degree.", "subset": "mixmath", "task_type": "tts"} +{"index": 803, "question": "Please read the following math formula symbols: $0r\\ge4\\barc\\epsilon$", "audio_path": "audio/row_00661620_1755665956318526.wav", "formula": "$R/\\sqrtd>r\\ge4\\barc\\epsilon$", "answer": "R divided by the square root of d, greater than r, greater than or equal to 4 times the bar c times epsilon.", "subset": "mixmath", "task_type": "tts"} +{"index": 840, "question": "Please read the following math formula symbols: $\\dim(Y)\\le\\dim(\\gtX_s)\\led$", "audio_path": "audio/row_00369756_1755629987715876.wav", "formula": "$\\dim(Y)\\le\\dim(\\gtX_s)\\led$", "answer": "Dimension of Y is less than or equal to dimension of X sub s, which is less than or equal to d.", "subset": "mixmath", "task_type": "tts"} +{"index": 841, "question": "请你朗读以下数学公式符号:$4\\div 7=0.\\overset{.}{\\mathop{5}}7142\\overset{.}{\\mathop{8}}$", "audio_path": "audio/math_2bcbe9b3-1e44-4b6a-8c09-0b556dd4b870.wav", "formula": "$4\\div 7=0.\\overset{.}{\\mathop{5}}7142\\overset{.}{\\mathop{8}}$", "answer": "四除以七等于零点五七一四二八 五七一四二八循环", "subset": "mixmath", "task_type": "tts"} +{"index": 842, "question": "Please read the following math formula symbols: $$y_0\\in(\\int_{E_m}\\nablag(x)dx)^{\\perp},$$", "audio_path": "audio/row_00890159_1755694537061782.wav", "formula": "$$y_0\\in(\\int_{E_m}\\nablag(x)dx)^{\\perp},$$", "answer": "y sub 0 belongs to the integral over E sub m of the gradient of g of x, d x, raised to the power of perpendicular.", "subset": "mixmath", "task_type": "tts"} +{"index": 843, "question": "请你朗读以下数学公式符号:$\\left\\{ \\begin{matrix} x=y+1 \\\\ 10x+y=10y+x+9 \\\\\\end{matrix} \\right.$", "audio_path": "audio/math_e107d394-8aec-486e-b5fb-0e3d7e4ccdf6.wav", "formula": "$\\left\\{ \\begin{matrix} x=y+1 \\\\ 10x+y=10y+x+9 \\\\\\end{matrix} \\right.$", "answer": "x等于y加一;十x加y等于十y加x加九", "subset": "mixmath", "task_type": "tts"} +{"index": 844, "question": "请你朗读以下数学公式符号:$$\\left[ \\frac{x}{2} \\right]+\\left[ \\frac{x}{3} \\right]+\\left[ \\frac{x}{6} \\right]=x$$", "audio_path": "audio/math_a05e61d6-16e5-4470-8d44-82fd1e81d3de.wav", "formula": "$$\\left[ \\frac{x}{2} \\right]+\\left[ \\frac{x}{3} \\right]+\\left[ \\frac{x}{6} \\right]=x$$", "answer": "二分之x的整数部分加三分之x的整数部分加六分之x的整数部分等于x", "subset": "mixmath", "task_type": "tts"} +{"index": 845, "question": "Please read the following math formula symbols: $f(\\xi_2-\\chi_{c',t'})>f(\\xi_2)$", "audio_path": "audio/row_00009458_1755586251463675.wav", "formula": "$f(\\xi_2-\\chi_{c',t'})>f(\\xi_2)$", "answer": "f of the quantity xi sub 2 minus chi sub c prime, t prime is greater than f of the quantity xi sub 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 846, "question": "Please read the following math formula symbols: $\\dist^{\\gamma(f,v)}(f,v)\\leq\\ell$", "audio_path": "audio/row_01855740_1755815930192387.wav", "formula": "$\\dist^{\\gamma(f,v)}(f,v)\\leq\\ell$", "answer": "Dist to the power of gamma of f comma v, open parenthesis f comma v, close parenthesis, less than or equal to ell.", "subset": "mixmath", "task_type": "tts"} +{"index": 847, "question": "Please read the following math formula symbols: $|(A\\capB)(x)|=k_1+k_2$", "audio_path": "audio/row_01860224_1755816492283812.wav", "formula": "$|(A\\capB)(x)|=k_1+k_2$", "answer": "Absolute value of the intersection of A and B, with respect to x, is equal to k sub 1 plus k sub 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 848, "question": "请你朗读以下数学公式符号:$1764=4\\times 3\\times 3\\times 7\\times 7=2\\times 6\\times 3\\times 7\\times 7=2\\times 2\\times 9\\times 7\\times 7=1\\times 6\\times 6\\times 7\\times 7=1\\times 4\\times 9\\times 7\\times$", "audio_path": "audio/math_b9f1c489-37a0-4663-9721-62efa78dd48d.wav", "formula": "$1764=4\\times 3\\times 3\\times 7\\times 7=2\\times 6\\times 3\\times 7\\times 7=2\\times 2\\times 9\\times 7\\times 7=1\\times 6\\times 6\\times 7\\times 7=1\\times 4\\times 9\\times 7\\times$", "answer": "一千七百六十四等于四乘三乘三乘七乘七等于二乘六乘三乘七乘七等于二乘二乘九乘七乘七等于一乘六乘六乘七乘七等于一乘四乘九乘七乘", "subset": "mixmath", "task_type": "tts"} +{"index": 849, "question": "请你朗读以下数学公式符号:$\\frac{5}{8}m^3=\\frac{5}{8}\\times 1000\\,dm^3=625\\,dm^3$", "audio_path": "audio/math_9749b333-e641-4d15-bae6-4609529928f9.wav", "formula": "$\\frac{5}{8}m^3=\\frac{5}{8}\\times 1000\\,dm^3=625\\,dm^3$", "answer": "八分之五立方米等于八分之五乘一千立方分米等于六百二十五立方分米", "subset": "mixmath", "task_type": "tts"} +{"index": 850, "question": "请你朗读以下数学公式符号:$\\begin{matrix}&4&9&7\\\\ +&2&8&7\\\\ \\hline &7&8&4\\end{matrix}$", "audio_path": "audio/math_8c7d2484-5de4-42fe-96ea-6848bed59ab3.wav", "formula": "$\\begin{matrix}&4&9&7\\\\ +&2&8&7\\\\ \\hline &7&8&4\\end{matrix}$", "answer": "四百九十七加二百八十七等于七百八十四", "subset": "mixmath", "task_type": "tts"} +{"index": 851, "question": "Please read the following math formula symbols: $N_S(w)=\\{u_1,u_3\\},\\{u_2,u_4\\}$", "audio_path": "audio/row_00837529_1755687937264878.wav", "formula": "$N_S(w)=\\{u_1,u_3\\},\\{u_2,u_4\\}$", "answer": "N sub S of w equals the set containing u sub 1, u sub 3, and the set containing u sub 2, and u sub 4.", "subset": "mixmath", "task_type": "tts"} +{"index": 852, "question": "Please read the following math formula symbols: $p^{2}=(m_{1}+m_{2})^{2}$", "audio_path": "audio/row_01051406_1755714672342586.wav", "formula": "$p^{2}=(m_{1}+m_{2})^{2}$", "answer": "p raised to the power of 2 equals open parenthesis, m sub 1 plus m sub 2, close parenthesis raised to the power of 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 853, "question": "请你朗读以下数学公式符号:$2{{r}_{1}}+2{{r}_{2}}+2{{r}_{3}}+3{{r}_{4}}=2{{r}_{1}}+2{{r}_{2}}+2{{r}_{3}}+3{{r}_{5}}$", "audio_path": "audio/math_457f2c34-615f-4209-9580-32d7b3cb6aeb.wav", "formula": "$2{{r}_{1}}+2{{r}_{2}}+2{{r}_{3}}+3{{r}_{4}}=2{{r}_{1}}+2{{r}_{2}}+2{{r}_{3}}+3{{r}_{5}}$", "answer": "二r一加二r二加二r三加三r四等于二r一加二r二加二r三加三r五", "subset": "mixmath", "task_type": "tts"} +{"index": 854, "question": "请你朗读以下数学公式符号:$\\begin{cases}2{{a}_{1}}x+3{{b}_{1}}y={{c}_{1}} \\\\ 2{{a}_{2}}x+3{{b}_{2}}y={{c}_{2}} \\\\ \\end{cases}$", "audio_path": "audio/math_8b315a71-404a-4a6e-8584-0b8677cf7445.wav", "formula": "$\\begin{cases}2{{a}_{1}}x+3{{b}_{1}}y={{c}_{1}} \\\\ 2{{a}_{2}}x+3{{b}_{2}}y={{c}_{2}} \\\\ \\end{cases}$", "answer": "二a一x加三b一y等于c一,二a二x加三b二y等于c二", "subset": "mixmath", "task_type": "tts"} +{"index": 855, "question": "请你朗读以下数学公式符号:$\\frac{3}{8}\\times 10\\times \\frac{7}{8}=\\frac{105}{32}$", "audio_path": "audio/math_cd5fc6ee-fe71-4aaa-a1ea-44ec5bcf40f6.wav", "formula": "$\\frac{3}{8}\\times 10\\times \\frac{7}{8}=\\frac{105}{32}$", "answer": "八分之三乘十乘八分之七等于三十二分之一百零五", "subset": "mixmath", "task_type": "tts"} +{"index": 856, "question": "请你朗读以下数学公式符号:$$=\\frac{2\\times 3\\times 5+{{4}^{3}}\\times \\left( 2\\times 3\\times 5 \\right)+{{5}^{3}}\\times \\left( 2\\times 3\\times 5 \\right)}{3\\times 5\\times 7+{{4}^{3}}\\times \\left( 3\\times 5\\times 7 \\right)+{{5}^{3}}\\times \\left( 3\\times 5\\times 7 \\right)}$$", "audio_path": "audio/math_077b03f2-95b5-45d4-a5b8-5a29b8e5f9b7.wav", "formula": "$$=\\frac{2\\times 3\\times 5+{{4}^{3}}\\times \\left( 2\\times 3\\times 5 \\right)+{{5}^{3}}\\times \\left( 2\\times 3\\times 5 \\right)}{3\\times 5\\times 7+{{4}^{3}}\\times \\left( 3\\times 5\\times 7 \\right)+{{5}^{3}}\\times \\left( 3\\times 5\\times 7 \\right)}$$", "answer": "等于三乘五乘七 加四的立方乘 三乘五乘七的积 加五的立方乘 三乘五乘七的积 分之 二乘三乘五 加四的立方乘 二乘三乘五的积 加五的立方乘 二乘三乘五的积", "subset": "mixmath", "task_type": "tts"} +{"index": 857, "question": "请你朗读以下数学公式符号:$$=(1+2+3+4+5+6+7+8+9)\\times 1.111=45\\times 1.111=49.995$$", "audio_path": "audio/math_6e829f51-60f7-47a7-b708-9e19e8eb12be.wav", "formula": "$$=(1+2+3+4+5+6+7+8+9)\\times 1.111=45\\times 1.111=49.995$$", "answer": "等于一加二加三加四加五加六加七加八加九的和乘一点一一一,等于四十五乘一点一一一,等于四十九点九九五", "subset": "mixmath", "task_type": "tts"} +{"index": 858, "question": "请你朗读以下数学公式符号:$S=5\\times 5\\sqrt{3}\\times \\frac{1}{2}=\\frac{25\\sqrt{3}}{2}{c}{{{m}}^{2}}$", "audio_path": "audio/math_1074459b-2c3e-46cb-a9be-acea553d87ec.wav", "formula": "$S=5\\times 5\\sqrt{3}\\times \\frac{1}{2}=\\frac{25\\sqrt{3}}{2}{c}{{{m}}^{2}}$", "answer": "S等于五乘五倍的根号三乘二分之一,等于二分之二十五倍的根号三平方厘米", "subset": "mixmath", "task_type": "tts"} +{"index": 859, "question": "Please read the following math formula symbols: $\\cP(\\aao,\\gamma^0,t)\\in\\overline{\\K}^2$", "audio_path": "audio/row_00198948_1755609204815346.wav", "formula": "$\\cP(\\aao,\\gamma^0,t)\\in\\overline{\\K}^2$", "answer": "The probability of the event A, gamma raised to the power of 0, at time t, belongs to the closure of K squared.", "subset": "mixmath", "task_type": "tts"} +{"index": 860, "question": "Please read the following math formula symbols: $e_{i}^{'}=(e_{i}\\setminus\\{u\\})\\bigcup\\{v\\}$", "audio_path": "audio/row_01676633_1755793271586071.wav", "formula": "$e_{i}^{'}=(e_{i}\\setminus\\{u\\})\\bigcup\\{v\\}$", "answer": "e sub i prime equals open parenthesis e sub i set minus open brace u close brace close parenthesis union v", "subset": "mixmath", "task_type": "tts"} +{"index": 861, "question": "Please read the following math formula symbols: ${\\bfX}\\sim\\mu\\in\\mathcal{P}_{ac}(\\mathbb{R}^p)$", "audio_path": "audio/row_01000202_1755708258495153.wav", "formula": "${\\bfX}\\sim\\mu\\in\\mathcal{P}_{ac}(\\mathbb{R}^p)$", "answer": "The set X is distributed as mu belongs to the set P sub a c of the real numbers raised to the power of p.", "subset": "mixmath", "task_type": "tts"} +{"index": 862, "question": "Please read the following math formula symbols: $\\frac{4M_3}{3S_0}>\\frac{4}{S_0}$", "audio_path": "audio/row_01801812_1755809117309358.wav", "formula": "$\\frac{4M_3}{3S_0}>\\frac{4}{S_0}$", "answer": "Four times M sub three divided by three times S sub zero is greater than four divided by S sub zero.", "subset": "mixmath", "task_type": "tts"} +{"index": 863, "question": "请你朗读以下数学公式符号:$30\\div ({{1}^{2}} \\pi +{{2}^{2}} \\pi )=\\frac{6}{ \\pi }$", "audio_path": "audio/math_e89941f2-bde7-4bd2-a87e-35c9cc62a6e1.wav", "formula": "$30\\div ({{1}^{2}} \\pi +{{2}^{2}} \\pi )=\\frac{6}{ \\pi }$", "answer": "三十除以一的平方pi与二的平方pi的和等于pi分之六", "subset": "mixmath", "task_type": "tts"} +{"index": 864, "question": "请你朗读以下数学公式符号:$$50\\times 50\\times 2+50\\times 80\\times 4=21000{c}{{{m}}^{2}}$$", "audio_path": "audio/math_ab30b6ed-09bf-4729-8c09-73970e376cb0.wav", "formula": "$$50\\times 50\\times 2+50\\times 80\\times 4=21000{c}{{{m}}^{2}}$$", "answer": "五十乘五十乘二加五十乘八十乘四等于二万一千平方厘米", "subset": "mixmath", "task_type": "tts"} +{"index": 865, "question": "Please read the following math formula symbols: $|x_2|=\\sqrt{c(1-\\delta\\lambda_i)}$", "audio_path": "audio/row_01964864_1755829722090047.wav", "formula": "$|x_2|=\\sqrt{c(1-\\delta\\lambda_i)}$", "answer": "Absolute value of x sub 2 equals square root of c times open parenthesis 1 minus delta lambda sub i close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 866, "question": "Please read the following math formula symbols: $(T_4^M-T_3^S)/2$", "audio_path": "audio/row_01570701_1755779898753917.wav", "formula": "$(T_4^M-T_3^S)/2$", "answer": "T sub 4 raised to the power of M minus T sub 3 raised to the power of S divided by 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 867, "question": "请你朗读以下数学公式符号:$${{\\left( 6\\\\div 2 \\\\right)}^{2}}\\\\times 3.14\\\\times 2\\\\times \\\\frac{1}{3}=18.84$$", "audio_path": "audio/math_c90db055-fb33-407d-bec1-ec92ca811982.wav", "formula": "$${{\\left( 6\\\\div 2 \\\\right)}^{2}}\\\\times 3.14\\\\times 2\\\\times \\\\frac{1}{3}=18.84$$", "answer": "六除以二的商的平方乘三点一四乘二乘三分之一等于十八点八四", "subset": "mixmath", "task_type": "tts"} +{"index": 868, "question": "请你朗读以下数学公式符号:$\\frac{5}{12}=\\frac{5\\times 5}{12\\times 5}=\\frac{25}{60}$", "audio_path": "audio/math_ca1e63e3-614a-4109-a05c-df10e4dc718d.wav", "formula": "$\\frac{5}{12}=\\frac{5\\times 5}{12\\times 5}=\\frac{25}{60}$", "answer": "十二分之五等于十二乘五的积分之五乘五等于六十分之二十五", "subset": "mixmath", "task_type": "tts"} +{"index": 869, "question": "请你朗读以下数学公式符号:$$f\\left( \\sqrt{5} \\right)=\\frac{\\sqrt{5}}{\\sqrt{5}+2}$$", "audio_path": "audio/math_9373320d-092d-4c60-9349-2e8756b08da7.wav", "formula": "$$f\\left( \\sqrt{5} \\right)=\\frac{\\sqrt{5}}{\\sqrt{5}+2}$$", "answer": "f 根号五 等于 根号五加二的和分之根号五", "subset": "mixmath", "task_type": "tts"} +{"index": 870, "question": "请你朗读以下数学公式符号:$\\frac{10\\times 9}{2\\times 1}\\times \\frac{8\\times 7\\times 6}{3\\times 2\\times 1}=2520$", "audio_path": "audio/math_fa3e7cb4-985c-4f70-aec9-4af807766b60.wav", "formula": "$\\frac{10\\times 9}{2\\times 1}\\times \\frac{8\\times 7\\times 6}{3\\times 2\\times 1}=2520$", "answer": "二乘一的积分之十乘九的积乘三乘二乘一的积分之八乘七乘六的积等于两千五百二十", "subset": "mixmath", "task_type": "tts"} +{"index": 871, "question": "Please read the following math formula symbols: $F(g,\\deltag)=|\\langle\\psi(g)|\\psi(g+\\deltag)\\rangle|$", "audio_path": "audio/row_00828547_1755686786210558.wav", "formula": "$F(g,\\deltag)=|\\langle\\psi(g)|\\psi(g+\\deltag)\\rangle|$", "answer": "F of g, delta g equals the absolute value of the inner product of psi of g and psi of g plus delta g.", "subset": "mixmath", "task_type": "tts"} +{"index": 872, "question": "请你朗读以下数学公式符号:$\\left( 5+10 \\right)\\times \\left( 15+1 \\right)=240$", "audio_path": "audio/math_8bc4613e-97f0-466f-936d-8594bc7a5a26.wav", "formula": "$\\left( 5+10 \\right)\\times \\left( 15+1 \\right)=240$", "answer": "五加十的和乘十五加一的和等于二百四十", "subset": "mixmath", "task_type": "tts"} +{"index": 873, "question": "Please read the following math formula symbols: $K_{\\sigma}:H_p(\\r{d})\\toH_p(\\r{d})$", "audio_path": "audio/row_00602641_1755658603282045.wav", "formula": "$K_{\\sigma}:H_p(\\r{d})\\toH_p(\\r{d})$", "answer": "K sub sigma, H sub p open parenthesis r d close parenthesis arrow H sub p open parenthesis r d close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 874, "question": "Please read the following math formula symbols: $Y_i\\sim\\mathcal{N}(0,{\\Theta^{*}}_i^{-1})$", "audio_path": "audio/row_00569173_1755654437405553.wav", "formula": "$Y_i\\sim\\mathcal{N}(0,{\\Theta^{*}}_i^{-1})$", "answer": "Y sub i is distributed as normal with mean 0 and variance Theta star sub i to the power of negative 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 875, "question": "请你朗读以下数学公式符号:${{2}^{6}}+{{2}^{5}}+{{2}^{4}}+{{2}^{3}}+{{2}^{2}}+2+1$", "audio_path": "audio/math_2fc03593-0fd9-4c79-a6fb-2370e569086d.wav", "formula": "${{2}^{6}}+{{2}^{5}}+{{2}^{4}}+{{2}^{3}}+{{2}^{2}}+2+1$", "answer": "二的六次方加二的五次方加二的四次方加二的立方加二的平方加二加一", "subset": "mixmath", "task_type": "tts"} +{"index": 876, "question": "Please read the following math formula symbols: $n^{-1}\\ip{\\bs}{\\bs'}\\in[0,\\nu_1]\\cup[\\nu_2,1]$", "audio_path": "audio/row_00633059_1755662418343367.wav", "formula": "$n^{-1}\\ip{\\bs}{\\bs'}\\in[0,\\nu_1]\\cup[\\nu_2,1]$", "answer": "n inverse times p times b times s prime belongs to the interval from 0 to nu 1 union the interval from nu 2 to 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 877, "question": "请你朗读以下数学公式符号:$$=\\left( \\frac{3}{11}+\\frac{8}{11} \\right)\\times \\frac{1}{6}$$", "audio_path": "audio/math_b4af985d-693f-4e73-8a54-8b5acef3f2e9.wav", "formula": "$$=\\left( \\frac{3}{11}+\\frac{8}{11} \\right)\\times \\frac{1}{6}$$", "answer": "等于十一分之三加十一分之八的和 乘 六分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 878, "question": "Please read the following math formula symbols: $Q(\\tau):=\\E_{Q(z)}[\\mathbb{I}[\\tau=\\tau(z)]]$", "audio_path": "audio/row_01331759_1755749737794552.wav", "formula": "$Q(\\tau):=\\E_{Q(z)}[\\mathbb{I}[\\tau=\\tau(z)]]$", "answer": "Q of tau is defined as the expectation of Q of z, in the set of I of tau equals tau of z.", "subset": "mixmath", "task_type": "tts"} +{"index": 879, "question": "Please read the following math formula symbols: $2\\sigma(f_\\mathrm\\{NL^\\Delta)\\sim\\num{e4}$", "audio_path": "audio/row_01884809_1755819627914066.wav", "formula": "$2\\sigma(f_\\mathrm\\{NL^\\Delta)\\sim\\num{e4}$", "answer": "Two times sigma of f sub N T delta is approximately nu times m times e to the power of four.", "subset": "mixmath", "task_type": "tts"} +{"index": 880, "question": "请你朗读以下数学公式符号:$\\left( \\frac{5}{12}+\\frac{5}{32} \\right)\\times \\frac{8}{25}$", "audio_path": "audio/math_6396fc03-b441-43b2-95af-aba183cecdbd.wav", "formula": "$\\left( \\frac{5}{12}+\\frac{5}{32} \\right)\\times \\frac{8}{25}$", "answer": "十二分之五加三十二分之五的和乘二十五分之八", "subset": "mixmath", "task_type": "tts"} +{"index": 881, "question": "Please read the following math formula symbols: $u^{(t)}_{ij}:=1/v^{(t)}_{ij}$", "audio_path": "audio/row_00601865_1755658500168451.wav", "formula": "$u^{(t)}_{ij}:=1/v^{(t)}_{ij}$", "answer": "u raised to the power of t, subscript i j, equals one divided by v raised to the power of t, subscript i j.", "subset": "mixmath", "task_type": "tts"} +{"index": 882, "question": "请你朗读以下数学公式符号:$\\begin{cases}m+n=0 \\\\ mn+b=1 \\\\ c+mb=0 \\\\ mc=a \\end{cases}$", "audio_path": "audio/math_e55ab1bc-a436-4380-96ff-b9900c88e08f.wav", "formula": "$\\begin{cases}m+n=0 \\\\ mn+b=1 \\\\ c+mb=0 \\\\ mc=a \\end{cases}$", "answer": "m加n等于零,mn加b的和等于一,c加mb等于零,mc等于a。", "subset": "mixmath", "task_type": "tts"} +{"index": 883, "question": "请你朗读以下数学公式符号:$\\frac{9}{10}\\div \\left( \\frac{1}{60}+\\frac{1}{75} \\right)$", "audio_path": "audio/math_6522ed90-a0ce-423d-b4c6-17e05275e721.wav", "formula": "$\\frac{9}{10}\\div \\left( \\frac{1}{60}+\\frac{1}{75} \\right)$", "answer": "十分之九除以 六十分之一加七十五分之一的和", "subset": "mixmath", "task_type": "tts"} +{"index": 884, "question": "Please read the following math formula symbols: $z^{n_m}_{m}\\leqz^{n_t}_{t}$", "audio_path": "audio/row_01315922_1755747745402527.wav", "formula": "$z^{n_m}_{m}\\leqz^{n_t}_{t}$", "answer": "z to the power of n sub m sub m is less than or equal to z to the power of n sub t sub t.", "subset": "mixmath", "task_type": "tts"} +{"index": 885, "question": "Please read the following math formula symbols: $\\tilde{L}_+Pf=(L_+-\\mu)Pf=-\\muPf$", "audio_path": "audio/row_01452337_1755764937791959.wav", "formula": "$\\tilde{L}_+Pf=(L_+-\\mu)Pf=-\\muPf$", "answer": "tilde L plus P f equals open parenthesis L sub plus minus mu close parenthesis P f equals minus mu P f", "subset": "mixmath", "task_type": "tts"} +{"index": 886, "question": "Please read the following math formula symbols: $\\{x\\inW:\\operatorname{dist}(x,p_2)\\geqr\\}$", "audio_path": "audio/row_00799981_1755683201372006.wav", "formula": "$\\{x\\inW:\\operatorname{dist}(x,p_2)\\geqr\\}$", "answer": "Open brace, x in W, colon, dist of x, comma, p sub 2, greater than or equal to r, close brace.", "subset": "mixmath", "task_type": "tts"} +{"index": 887, "question": "Please read the following math formula symbols: $a_t\\sim\\pi(a_t\\,|\\,o_{\\leqt},a_{0.5\\}|>round(0.8*k)$", "audio_path": "audio/row_02054913_1755841072131631.wav", "formula": "$|\\{a\\inK_i:logits_a>0.5\\}|>round(0.8*k)$", "answer": "Absolute value of the set of a in K sub i such that the logarithm of a is greater than 0.5, greater than 0.8 times k.", "subset": "mixmath", "task_type": "tts"} +{"index": 892, "question": "Please read the following math formula symbols: $C^n(G,A):=\\ker(\\deri^n)$", "audio_path": "audio/row_00724221_1755673727335170.wav", "formula": "$C^n(G,A):=\\ker(\\deri^n)$", "answer": "C to the power of n of G, A is defined as the kernel of i to the power of n.", "subset": "mixmath", "task_type": "tts"} +{"index": 893, "question": "请你朗读以下数学公式符号:$$\\dfrac{2}{3}\\times\\dfrac{7}{8}\\times\\dfrac{3}{2}=$$", "audio_path": "audio/math_4a45068c-08af-4064-80f3-f503f1c01e23.wav", "formula": "$$\\dfrac{2}{3}\\times\\dfrac{7}{8}\\times\\dfrac{3}{2}=$$", "answer": "三分之二乘八分之七乘二分之三等于", "subset": "mixmath", "task_type": "tts"} +{"index": 894, "question": "请你朗读以下数学公式符号:$=\\frac{7}{11}\\times \\frac{8}{25}+\\frac{7}{11}\\times \\frac{3}{25}$", "audio_path": "audio/math_1c1bb581-aff8-48dc-bd99-a09a4ea77951.wav", "formula": "$=\\frac{7}{11}\\times \\frac{8}{25}+\\frac{7}{11}\\times \\frac{3}{25}$", "answer": "等于十一分之七乘二十五分之八加十一分之七乘二十五分之三", "subset": "mixmath", "task_type": "tts"} +{"index": 895, "question": "请你朗读以下数学公式符号:$\\left\\{ \\begin{array}{*{35}{l}} a=8 \\\\ b=2 \\\\\\end{array} \\right.$", "audio_path": "audio/math_79339df2-2bcd-4cdc-8b03-b7f96cb39a0a.wav", "formula": "$\\left\\{ \\begin{array}{*{35}{l}} a=8 \\\\ b=2 \\\\\\end{array} \\right.$", "answer": "a等于八,b等于二", "subset": "mixmath", "task_type": "tts"} +{"index": 896, "question": "请你朗读以下数学公式符号:$0.\\overset{\\centerdot }{\\mathop{3}}\\overset{\\centerdot }{\\mathop{6}}+0.\\overset{\\centerdot }{\\mathop{2}}9\\overset{\\centerdot }{\\mathop{6}}$", "audio_path": "audio/math_5a7db12c-f7df-4143-a028-0e0a677d609b.wav", "formula": "$0.\\overset{\\centerdot }{\\mathop{3}}\\overset{\\centerdot }{\\mathop{6}}+0.\\overset{\\centerdot }{\\mathop{2}}9\\overset{\\centerdot }{\\mathop{6}}$", "answer": "零点三六 三六循环加零点二九六 二九六循环", "subset": "mixmath", "task_type": "tts"} +{"index": 897, "question": "请你朗读以下数学公式符号:$\\dfrac{3}{4}=\\dfrac{3\\times6}{4\\times6}=\\dfrac{18}{24}$", "audio_path": "audio/math_46082b10-1a51-4793-be44-793b8f433d5d.wav", "formula": "$\\dfrac{3}{4}=\\dfrac{3\\times6}{4\\times6}=\\dfrac{18}{24}$", "answer": "四分之三等于四乘六的积分之三乘六的积等于二十四分之十八", "subset": "mixmath", "task_type": "tts"} +{"index": 898, "question": "请你朗读以下数学公式符号:$$2\\dfrac{1}{20} + 3\\dfrac{1}{30} + 4\\dfrac{1}{42} + 5\\dfrac{1}{56}$$", "audio_path": "audio/math_2209fb42-0770-4c12-8f81-576b4a7fc272.wav", "formula": "$$2\\dfrac{1}{20} + 3\\dfrac{1}{30} + 4\\dfrac{1}{42} + 5\\dfrac{1}{56}$$", "answer": "二又二十分之一加三又三十分之一加四又四十二分之一加五又五十六分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 899, "question": "请你朗读以下数学公式符号:$=1\\times \\frac{1}{4}+5\\times 4\\times 1+10\\times 1\\times \\frac{1}{4}$", "audio_path": "audio/math_044a6ba6-97d2-48a8-a372-5c8e2edcb6c7.wav", "formula": "$=1\\times \\frac{1}{4}+5\\times 4\\times 1+10\\times 1\\times \\frac{1}{4}$", "answer": "等于一乘四分之一加五乘四乘一加十乘一乘四分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 900, "question": "Please read the following math formula symbols: $\\{\\delta_k=0,1\\}_{k=0,n_q-1}$", "audio_path": "audio/row_00743554_1755676134097849.wav", "formula": "$\\{\\delta_k=0,1\\}_{k=0,n_q-1}$", "answer": "Curly brace, delta sub k equals zero comma one, end curly brace, sub k equals zero, comma, n sub q minus one.", "subset": "mixmath", "task_type": "tts"} +{"index": 901, "question": "Please read the following math formula symbols: ${\\boldsymbolx}^{(t)}\\in\\mathbb{R}^{S}$", "audio_path": "audio/row_01382013_1755756058758959.wav", "formula": "${\\boldsymbolx}^{(t)}\\in\\mathbb{R}^{S}$", "answer": "Bold x raised to the power of t belongs to the set of real numbers raised to the power of S.", "subset": "mixmath", "task_type": "tts"} +{"index": 902, "question": "请你朗读以下数学公式符号:$=\\left( \\frac{5}{9}\\times \\frac{6}{9}+\\frac{7}{9}\\times \\frac{8}{9} \\right)\\div 1$", "audio_path": "audio/math_9e277fc5-efeb-442f-a5f7-dde2378a2700.wav", "formula": "$=\\left( \\frac{5}{9}\\times \\frac{6}{9}+\\frac{7}{9}\\times \\frac{8}{9} \\right)\\div 1$", "answer": "等于九分之五乘九分之六与九分之七乘九分之八的和除以一", "subset": "mixmath", "task_type": "tts"} +{"index": 903, "question": "Please read the following math formula symbols: $\\lim_{k\\rightarrow\\infty}\\dimfM{F_k}=\\dimM{X}$", "audio_path": "audio/row_01287299_1755744207963773.wav", "formula": "$\\lim_{k\\rightarrow\\infty}\\dimfM{F_k}=\\dimM{X}$", "answer": "Limit as k approaches infinity of the dimension of f times M times F sub k equals the dimension of M times X.", "subset": "mixmath", "task_type": "tts"} +{"index": 904, "question": "Please read the following math formula symbols: $\\partial_\\muS_E=\\intd^2x\\,f(x_1,x_2)$", "audio_path": "audio/row_00924370_1755698816556944.wav", "formula": "$\\partial_\\muS_E=\\intd^2x\\,f(x_1,x_2)$", "answer": "Partial derivative with respect to mu of S E equals the integral of d squared x, f of x 1, x 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 905, "question": "请你朗读以下数学公式符号:$=3333\\times \\left( 3\\times 2222 \\right)+3333\\times 3334$", "audio_path": "audio/math_fc3c8a79-60a8-40d0-9cd5-ca7708406667.wav", "formula": "$=3333\\times \\left( 3\\times 2222 \\right)+3333\\times 3334$", "answer": "等于三千三百三十三乘三乘二千二百二十二的积,加上三千三百三十三乘三千三百三十四", "subset": "mixmath", "task_type": "tts"} +{"index": 906, "question": "Please read the following math formula symbols: $\\vvev{I_1^{n_1}I_2^{n_2}\\dots}$", "audio_path": "audio/row_02010931_1755835523715973.wav", "formula": "$\\vvev{I_1^{n_1}I_2^{n_2}\\dots}$", "answer": "v or I sub 1 to the power of n sub 1, I sub 2 to the power of n sub 2, dot dot dot", "subset": "mixmath", "task_type": "tts"} +{"index": 907, "question": "请你朗读以下数学公式符号:$\\frac{9}{11}\\times \\frac{7}{15}\\times \\frac{11}{3}=3\\times \\frac{7}{15}=\\frac{7}{5}$", "audio_path": "audio/math_672735c9-7131-404b-9c6b-398c7c7a33b4.wav", "formula": "$\\frac{9}{11}\\times \\frac{7}{15}\\times \\frac{11}{3}=3\\times \\frac{7}{15}=\\frac{7}{5}$", "answer": "十一分之九乘十五分之七乘三分之十一等于三乘十五分之七等于五分之七", "subset": "mixmath", "task_type": "tts"} +{"index": 908, "question": "请你朗读以下数学公式符号:$\\dfrac{3^{6}+3\\times2+3^{2}\\times2+3^{3}}{6}=130$", "audio_path": "audio/math_196123fb-b6df-4ece-8d81-585e4ea93558.wav", "formula": "$\\dfrac{3^{6}+3\\times2+3^{2}\\times2+3^{3}}{6}=130$", "answer": "六分之三的六次方加三乘二加三的平方乘二加三的立方的和等于一百三十", "subset": "mixmath", "task_type": "tts"} +{"index": 909, "question": "请你朗读以下数学公式符号:$68d\\frac{14}{17}\\leqslant n\\leqslant 70\\dfrac{14}{17}$", "audio_path": "audio/math_46c2c408-3d1f-4aaa-87e7-565c80f177a9.wav", "formula": "$68d\\frac{14}{17}\\leqslant n\\leqslant 70\\dfrac{14}{17}$", "answer": "n大于等于六十八d又十七分之十四 且小于等于七十又十七分之十四", "subset": "mixmath", "task_type": "tts"} +{"index": 910, "question": "请你朗读以下数学公式符号:$\\begin{eqnarray}14:56&=&x:113\\\\ 56x&=&14\\times 113\\\\ 56x\\div 56&=&14\\times 113\\div 56\\\\ x&=&28.25.\\end{eqnarray}$", "audio_path": "audio/math_cdde09a3-15d9-4799-a2c8-65719a026947.wav", "formula": "$\\begin{eqnarray}14:56&=&x:113\\\\ 56x&=&14\\times 113\\\\ 56x\\div 56&=&14\\times 113\\div 56\\\\ x&=&28.25.\\end{eqnarray}$", "answer": "十四比五十六等于x比一百一十三;五十六x等于十四乘一百一十三;五十六x除以五十六等于十四乘一百一十三除以五十六;x等于二十八点二五。", "subset": "mixmath", "task_type": "tts"} +{"index": 911, "question": "请你朗读以下数学公式符号:$\\frac{9}{10}=\\frac{9\\times 3}{10\\times 3}=\\frac{27}{30}$", "audio_path": "audio/math_61482802-3436-4d93-b09f-1299aa8cd884.wav", "formula": "$\\frac{9}{10}=\\frac{9\\times 3}{10\\times 3}=\\frac{27}{30}$", "answer": "十分之九等于十乘三的积分之九乘三的积等于三十分之二十七", "subset": "mixmath", "task_type": "tts"} +{"index": 912, "question": "Please read the following math formula symbols: $r_k=enc_r([h_t;h_{G(t)}])$", "audio_path": "audio/row_01782755_1755806707664234.wav", "formula": "$r_k=enc_r([h_t;h_{G(t)}])$", "answer": "r sub k equals c r open bracket h sub t semicolon h sub G open bracket t close bracket close bracket", "subset": "mixmath", "task_type": "tts"} +{"index": 913, "question": "请你朗读以下数学公式符号:$$\\log _2\\left(\\log _8 x\\right)=\\log _8\\left(\\log _2 x\\right)$$", "audio_path": "audio/math_35b373cd-53df-4a4a-af56-641134d7410b.wav", "formula": "$$\\log _2\\left(\\log _8 x\\right)=\\log _8\\left(\\log _2 x\\right)$$", "answer": "以二为底 以八为底 x 的对数的对数 等于 以八为底以二为底 x 的对数的对数", "subset": "mixmath", "task_type": "tts"} +{"index": 914, "question": "请你朗读以下数学公式符号:$\\frac{1234321}{4444\\times 4444}=\\frac{1}{4\\times 4}=\\frac{1}{16}$", "audio_path": "audio/math_6925228a-8753-4f1b-93ac-b2027553cb25.wav", "formula": "$\\frac{1234321}{4444\\times 4444}=\\frac{1}{4\\times 4}=\\frac{1}{16}$", "answer": "四千四百四十四乘四千四百四十四的积分之一百二十三万四千三百二十一等于四乘四的积分之一等于十六分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 915, "question": "请你朗读以下数学公式符号:$3.14\\times {{2}^{2}}=3.14\\times 4=12.56({{m}^{2}})$", "audio_path": "audio/math_96c03489-37f5-4282-a62c-5dbf4141fecd.wav", "formula": "$3.14\\times {{2}^{2}}=3.14\\times 4=12.56({{m}^{2}})$", "answer": "三点一四乘二的平方等于三点一四乘四等于十二点五六平方米", "subset": "mixmath", "task_type": "tts"} +{"index": 916, "question": "请你朗读以下数学公式符号:$${{\\left( x+\\frac{1}{x} \\right)}^{2}}=2\\left( x+\\frac{1}{x} \\right)$$", "audio_path": "audio/math_3ddc50f0-9561-475d-ba9c-3e12aa227adc.wav", "formula": "$${{\\left( x+\\frac{1}{x} \\right)}^{2}}=2\\left( x+\\frac{1}{x} \\right)$$", "answer": "x加x分之一的和的平方等于二倍的x加x分之一的和", "subset": "mixmath", "task_type": "tts"} +{"index": 917, "question": "Please read the following math formula symbols: ${\\mathfrak{R}}_n(\\mathcal{H})\\leC_\\mathcal{H}/\\sqrt{n}$", "audio_path": "audio/row_00751113_1755677090097057.wav", "formula": "${\\mathfrak{R}}_n(\\mathcal{H})\\leC_\\mathcal{H}/\\sqrt{n}$", "answer": "R sub n of H is less than or equal to C sub H divided by the square root of n.", "subset": "mixmath", "task_type": "tts"} +{"index": 918, "question": "请你朗读以下数学公式符号:$\\left( 140+x \\right)\\times \\frac{4}{3}=140+\\left( 46\\frac{2}{3}+\\frac{4}{3}x \\right)$", "audio_path": "audio/math_9b5a20dc-14da-4228-aa03-f2e510bbeea4.wav", "formula": "$\\left( 140+x \\right)\\times \\frac{4}{3}=140+\\left( 46\\frac{2}{3}+\\frac{4}{3}x \\right)$", "answer": "一百四十加x的和乘三分之四 等于一百四十加上 四十六又三分之二加三分之四x的和", "subset": "mixmath", "task_type": "tts"} +{"index": 919, "question": "Please read the following math formula symbols: $Q\\preceqQ'\\preceqQ^{\\rmref}$", "audio_path": "audio/row_00049345_1755591092393759.wav", "formula": "$Q\\preceqQ'\\preceqQ^{\\rmref}$", "answer": "Q is less than or equal to Q prime, which is less than or equal to Q raised to the reference power.", "subset": "mixmath", "task_type": "tts"} +{"index": 920, "question": "Please read the following math formula symbols: $p_{8r}^s=i{N_r\\overR_-}{x_r^8\\over\\Delta\\tau_*}$", "audio_path": "audio/row_02085164_1755844932307706.wav", "formula": "$p_{8r}^s=i{N_r\\overR_-}{x_r^8\\over\\Delta\\tau_*}$", "answer": "p sub 8 r superscript s equals i N sub r overline R sub negative x sub r superscript 8 overline Delta tau star.", "subset": "mixmath", "task_type": "tts"} +{"index": 921, "question": "Please read the following math formula symbols: $\\phi=X_1+X_2\\in\\{\\vmathbb\\S[X_1,X_2]$", "audio_path": "audio/row_00513452_1755647579000515.wav", "formula": "$\\phi=X_1+X_2\\in\\{\\vmathbb\\S[X_1,X_2]$", "answer": "Phi equals X sub 1 plus X sub 2 belongs to the set of maps from S of X sub 1 comma X sub 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 922, "question": "请你朗读以下数学公式符号:$=(\\frac{9}{7}+\\frac{5}{7})+(\\frac{1}{8}+\\frac{3}{8})$", "audio_path": "audio/math_4e417a22-dcec-4bb2-8717-d9455d89320a.wav", "formula": "$=(\\frac{9}{7}+\\frac{5}{7})+(\\frac{1}{8}+\\frac{3}{8})$", "answer": "等于七分之九加七分之五的和加八分之一加八分之三的和", "subset": "mixmath", "task_type": "tts"} +{"index": 923, "question": "Please read the following math formula symbols: $f(x_1\\dots,x_n)\\in\\F_q[x_1,\\dots,x_n]$", "audio_path": "audio/row_01426225_1755761642124553.wav", "formula": "$f(x_1\\dots,x_n)\\in\\F_q[x_1,\\dots,x_n]$", "answer": "f of x sub 1 through x sub n belongs to the set of F sub q of x sub 1 through x sub n.", "subset": "mixmath", "task_type": "tts"} +{"index": 924, "question": "Please read the following math formula symbols: $P_2':=(\\rho_1)_*P_1'$", "audio_path": "audio/row_00371039_1755630137183474.wav", "formula": "$P_2':=(\\rho_1)_*P_1'$", "answer": "P sub 2 prime is defined as the product of the star of rho sub 1 and P sub 1 prime.", "subset": "mixmath", "task_type": "tts"} +{"index": 925, "question": "Please read the following math formula symbols: $$\\mathrm{sub\\;to\\;\\;}h_j(x)\\leq0\\,\\;j=1,2,...n$$", "audio_path": "audio/row_00790104_1755681994598241.wav", "formula": "$$\\mathrm{sub\\;to\\;\\;}h_j(x)\\leq0\\,\\;j=1,2,...n$$", "answer": "Subset h sub j of x is less than or equal to 0, j equals 1, 2, dot dot dot, n.", "subset": "mixmath", "task_type": "tts"} +{"index": 926, "question": "Please read the following math formula symbols: $P^0_\\perp=K_\\perp\\rho_c^{1+1/n_\\perp}$", "audio_path": "audio/row_00709480_1755671886720638.wav", "formula": "$P^0_\\perp=K_\\perp\\rho_c^{1+1/n_\\perp}$", "answer": "P to the power of 0 perpendicular equals K perpendicular rho c to the power of 1 plus 1 over n perpendicular.", "subset": "mixmath", "task_type": "tts"} +{"index": 927, "question": "Please read the following math formula symbols: $Y_2=\\overline{\\pi}^{k}p^{-(2k+s-4)}$", "audio_path": "audio/row_01689296_1755794886550917.wav", "formula": "$Y_2=\\overline{\\pi}^{k}p^{-(2k+s-4)}$", "answer": "Y sub 2 equals the conjugate of pi to the power of k times p to the power of negative 2k plus s minus 4.", "subset": "mixmath", "task_type": "tts"} +{"index": 928, "question": "Please read the following math formula symbols: $Z(a^\\mI,a^\\mIp)$", "audio_path": "audio/row_00766658_1755679028142249.wav", "formula": "$Z(a^\\mI,a^\\mIp)$", "answer": "Z, open parenthesis, a to the power of m times I, comma, a to the power of m times I times p, close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 929, "question": "Please read the following math formula symbols: ${p}^{\\ast}_{1}\\leq{p}^{\\ast}$", "audio_path": "audio/row_00590508_1755657094479813.wav", "formula": "${p}^{\\ast}_{1}\\leq{p}^{\\ast}$", "answer": "p raised to the power of asterisk sub 1 is less than or equal to p raised to the power of asterisk.", "subset": "mixmath", "task_type": "tts"} +{"index": 930, "question": "请你朗读以下数学公式符号:$128+120+112+104+96+88+80+72+64+56+48=88\\times 11=968$", "audio_path": "audio/math_6eb36f44-5343-4f6b-9f2a-4a06c061cf1d.wav", "formula": "$128+120+112+104+96+88+80+72+64+56+48=88\\times 11=968$", "answer": "一百二十八加一百二十加一百一十二加一百零四加九十六加八十八加八十加七十二加六十四加五十六加四十八等于八十八乘十一等于九百六十八", "subset": "mixmath", "task_type": "tts"} +{"index": 931, "question": "Please read the following math formula symbols: $\\gamma_\\star\\eqdef\\min\\Spec{\\partial^2\\tilde{\\Phi}(\\thv)}$", "audio_path": "audio/row_00660839_1755665852311478.wav", "formula": "$\\gamma_\\star\\eqdef\\min\\Spec{\\partial^2\\tilde{\\Phi}(\\thv)}$", "answer": "Gamma star is defined as the minimum of the minimum of the second partial derivative of tilde Phi with respect to t.", "subset": "mixmath", "task_type": "tts"} +{"index": 932, "question": "请你朗读以下数学公式符号:$(2+1)\\left( {{2}^{2}}+1 \\right)\\left( {{2}^{4}}+1 \\right)\\left( {{2}^{8}}+1 \\right)$", "audio_path": "audio/math_0827f7c7-bbdb-4f74-ade7-cc79aea7be27.wav", "formula": "$(2+1)\\left( {{2}^{2}}+1 \\right)\\left( {{2}^{4}}+1 \\right)\\left( {{2}^{8}}+1 \\right)$", "answer": "二加一的和乘二的平方加一的和乘二的四次方加一的和乘二的八次方加一的和", "subset": "mixmath", "task_type": "tts"} +{"index": 933, "question": "请你朗读以下数学公式符号:$1\\times \\left( 1+\\frac{1}{2} \\right)=\\frac{3}{2}$", "audio_path": "audio/math_37ba95be-4548-4322-82d9-3cc81e47fea7.wav", "formula": "$1\\times \\left( 1+\\frac{1}{2} \\right)=\\frac{3}{2}$", "answer": "一乘一加二分之一的和等于二分之三", "subset": "mixmath", "task_type": "tts"} +{"index": 934, "question": "Please read the following math formula symbols: $p_{A_1,A_2}=c_{A_1,A_2}u_{A_1,A_2}$", "audio_path": "audio/row_00792895_1755682335572056.wav", "formula": "$p_{A_1,A_2}=c_{A_1,A_2}u_{A_1,A_2}$", "answer": "p sub A sub 1, A sub 2 equals c sub A sub 1, A sub 2 u sub A sub 1, A sub 2", "subset": "mixmath", "task_type": "tts"} +{"index": 935, "question": "Please read the following math formula symbols: $p\\len-1,0\\leg\\lep-1$", "audio_path": "audio/row_00970026_1755704489405415.wav", "formula": "$p\\len-1,0\\leg\\lep-1$", "answer": "p less than or equal to n minus 1, 0 less than or equal to g less than or equal to p minus 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 936, "question": "Please read the following math formula symbols: $-1+c^{2}_{19}-c^{4}_{19}+c^{6}_{19}$", "audio_path": "audio/row_01506688_1755771796552711.wav", "formula": "$-1+c^{2}_{19}-c^{4}_{19}+c^{6}_{19}$", "answer": "Minus one plus c squared sub 19 minus c to the power of 4 sub 19 plus c to the power of 6 sub 19.", "subset": "mixmath", "task_type": "tts"} +{"index": 937, "question": "请你朗读以下数学公式符号:$71{{{m}}^{2}}=71\\times 100{d}{{{m}}^{2}}=71\\times 10000{c}{{{m}}^{2}}$", "audio_path": "audio/math_9f0189e3-5ee8-4350-aa1e-61eb65a14d15.wav", "formula": "$71{{{m}}^{2}}=71\\times 100{d}{{{m}}^{2}}=71\\times 10000{c}{{{m}}^{2}}$", "answer": "七十一平方米等于七十一乘一百平方分米等于七十一乘一万平方厘米", "subset": "mixmath", "task_type": "tts"} +{"index": 938, "question": "请你朗读以下数学公式符号:$\\left\\{\\begin{array}{c}x+y=10\\\\ 37x+49y=422\\end{array}\\right.$", "audio_path": "audio/math_d8782a90-ccc7-4a55-ad51-cd6f1ab909db.wav", "formula": "$\\left\\{\\begin{array}{c}x+y=10\\\\ 37x+49y=422\\end{array}\\right.$", "answer": "x加y等于十,三十七x加四十九y等于四百二十二", "subset": "mixmath", "task_type": "tts"} +{"index": 939, "question": "Please read the following math formula symbols: $A\\backslashB:=\\{x\\;|\\:x\\inA,x\\notinB\\}$", "audio_path": "audio/row_01330784_1755749614837088.wav", "formula": "$A\\backslashB:=\\{x\\;|\\:x\\inA,x\\notinB\\}$", "answer": "A backslash B is defined as the set of x such that x is in A and x is not in B.", "subset": "mixmath", "task_type": "tts"} +{"index": 940, "question": "请你朗读以下数学公式符号:$=\\frac{2013}{2018}\\times 2018+\\frac{2013}{2018}\\times 1$", "audio_path": "audio/math_a12cef46-4784-461d-9260-8306d26db2e5.wav", "formula": "$=\\frac{2013}{2018}\\times 2018+\\frac{2013}{2018}\\times 1$", "answer": "等于两千零一十八分之两千零一十三乘两千零一十八加两千零一十八分之两千零一十三乘一", "subset": "mixmath", "task_type": "tts"} +{"index": 941, "question": "Please read the following math formula symbols: $l\\ge(p+1)d-n>0$", "audio_path": "audio/row_00429734_1755637305277852.wav", "formula": "$l\\ge(p+1)d-n>0$", "answer": "l is greater than or equal to the quantity p plus 1, multiplied by d minus n, which is greater than 0.", "subset": "mixmath", "task_type": "tts"} +{"index": 942, "question": "请你朗读以下数学公式符号:$\\frac{7}{9}=\\frac{91}{117}>\\frac{90}{117}=\\frac{10}{13}$", "audio_path": "audio/math_a2ae9e76-c6ee-48c2-9373-ba2dd0974f01.wav", "formula": "$\\frac{7}{9}=\\frac{91}{117}>\\frac{90}{117}=\\frac{10}{13}$", "answer": "九分之七等于一百一十七分之九十一大于一百一十七分之九十等于十三分之十", "subset": "mixmath", "task_type": "tts"} +{"index": 943, "question": "Please read the following math formula symbols: $H^0(\\mathcal{L}_\\tau(\\varphi_1\\varphi_0^{-1}))$", "audio_path": "audio/row_01261538_1755740973643584.wav", "formula": "$H^0(\\mathcal{L}_\\tau(\\varphi_1\\varphi_0^{-1}))$", "answer": "H raised to the power of 0, L sub tau, open parenthesis, phi sub 1 phi sub 0 inverse, close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 944, "question": "请你朗读以下数学公式符号:$${{x}^{2}}+\\frac{1}{{{x}^{2}}}+2=2\\left( x+\\frac{1}{x} \\right)$$", "audio_path": "audio/math_69e8f162-a601-463f-bacd-e723b694f571.wav", "formula": "$${{x}^{2}}+\\frac{1}{{{x}^{2}}}+2=2\\left( x+\\frac{1}{x} \\right)$$", "answer": "x的平方加x平方分之一加二等于二乘x加x分之一的和", "subset": "mixmath", "task_type": "tts"} +{"index": 945, "question": "Please read the following math formula symbols: $f_{r,K}:=K\\eins_{B_{m_1}}+\\eins_{\\{g>0\\}\\capB_r}$", "audio_path": "audio/row_01850952_1755815330651560.wav", "formula": "$f_{r,K}:=K\\eins_{B_{m_1}}+\\eins_{\\{g>0\\}\\capB_r}$", "answer": "f sub r comma K equals K intersection B sub m sub 1 plus element g greater than 0 intersection B sub r", "subset": "mixmath", "task_type": "tts"} +{"index": 946, "question": "请你朗读以下数学公式符号:$$ g\\left(x\\right)=\\frac{f\\left(x\\right)}{{x}^{5}} $$", "audio_path": "audio/math_197d7f2e-76b2-44b3-8bb8-dcb9d39ecf69.wav", "formula": "$$ g\\left(x\\right)=\\frac{f\\left(x\\right)}{{x}^{5}} $$", "answer": "g x等于x的五次方分之f x", "subset": "mixmath", "task_type": "tts"} +{"index": 947, "question": "Please read the following math formula symbols: $\\gamma_{i}=\\#\\{\\mu_{j}:\\,\\mu_{j}\\gei\\}$", "audio_path": "audio/row_00014010_1755586802035699.wav", "formula": "$\\gamma_{i}=\\#\\{\\mu_{j}:\\,\\mu_{j}\\gei\\}$", "answer": "Gamma sub i equals the set of mu sub j such that mu sub j is greater than or equal to i.", "subset": "mixmath", "task_type": "tts"} +{"index": 948, "question": "请你朗读以下数学公式符号:$f\\left(\\frac{1}{x}\\right)=\\frac{1}{1+\\dfrac{1}{x}}=\\frac{x}{1+x}$", "audio_path": "audio/math_ed2433df-9075-4f35-95ec-cad29171a4b0.wav", "formula": "$f\\left(\\frac{1}{x}\\right)=\\frac{1}{1+\\dfrac{1}{x}}=\\frac{x}{1+x}$", "answer": "f x分之一等于一加x分之一的和分之一等于一加x的和分之x", "subset": "mixmath", "task_type": "tts"} +{"index": 949, "question": "请你朗读以下数学公式符号:$$\\frac{3}{11}\\times \\frac{2}{5}+\\frac{9}{11}\\times \\frac{3}{5}$$", "audio_path": "audio/math_da5b3829-8873-4694-a9cb-4901ba564c27.wav", "formula": "$$\\frac{3}{11}\\times \\frac{2}{5}+\\frac{9}{11}\\times \\frac{3}{5}$$", "answer": "十一分之三乘五分之二加十一分之九乘五分之三", "subset": "mixmath", "task_type": "tts"} +{"index": 950, "question": "Please read the following math formula symbols: $0.880113\\leq\\frac{r_0}{R}\\leq0.938387$", "audio_path": "audio/row_00263227_1755617032883474.wav", "formula": "$0.880113\\leq\\frac{r_0}{R}\\leq0.938387$", "answer": "0.880113 is less than or equal to the ratio of r sub 0 to capital R, which is less than or equal to 0.938387.", "subset": "mixmath", "task_type": "tts"} +{"index": 951, "question": "Please read the following math formula symbols: $F_d(\\tPois^{\\pi_{[-n,\\infty]}(\\mu),n}(T))$", "audio_path": "audio/row_02041398_1755839361035042.wav", "formula": "$F_d(\\tPois^{\\pi_{[-n,\\infty]}(\\mu),n}(T))$", "answer": "F sub d of Pi sub open square bracket negative n comma infinity close square bracket of mu comma n of T", "subset": "mixmath", "task_type": "tts"} +{"index": 952, "question": "请你朗读以下数学公式符号:$$\\frac{1}{3}\\times 360\\times 7.5\\div \\left( 3\\times 3 \\right)=900\\div 9=100$$", "audio_path": "audio/math_ad04085c-2291-451f-b202-2a03138ee278.wav", "formula": "$$\\frac{1}{3}\\times 360\\times 7.5\\div \\left( 3\\times 3 \\right)=900\\div 9=100$$", "answer": "三分之一乘三百六十乘七点五除以三乘三的积等于九百除以九等于一百", "subset": "mixmath", "task_type": "tts"} +{"index": 953, "question": "Please read the following math formula symbols: $A'=P+Q(I-W)^{-1}R$", "audio_path": "audio/row_00325206_1755624568235982.wav", "formula": "$A'=P+Q(I-W)^{-1}R$", "answer": "A prime equals P plus Q times the inverse of the quantity I minus W, all raised to the power of negative one, times R.", "subset": "mixmath", "task_type": "tts"} +{"index": 954, "question": "请你朗读以下数学公式符号:$90\\%\\times \\left( 500\\times 20+40x \\right)=36x+9000$", "audio_path": "audio/math_2409fea4-06a2-4077-ad90-a1bf21fe1e4c.wav", "formula": "$90\\%\\times \\left( 500\\times 20+40x \\right)=36x+9000$", "answer": "百分之九十 乘 括号 五百乘二十加上四十x 括号 等于三十六x加九千", "subset": "mixmath", "task_type": "tts"} +{"index": 955, "question": "Please read the following math formula symbols: $\\mathcalG(\\mathcalH):=\\mathcalG^{[0,1]}(\\mathcalH)$", "audio_path": "audio/row_00889490_1755694454721555.wav", "formula": "$\\mathcalG(\\mathcalH):=\\mathcalG^{[0,1]}(\\mathcalH)$", "answer": "Mathcal G of Mathcal H is defined as Mathcal G superscript open bracket 0 comma 1 close bracket of Mathcal H.", "subset": "mixmath", "task_type": "tts"} +{"index": 956, "question": "Please read the following math formula symbols: $\\zeta\\inU_{C_0}\\capU_{C_{\\pm}}$", "audio_path": "audio/row_00057805_1755592107979605.wav", "formula": "$\\zeta\\inU_{C_0}\\capU_{C_{\\pm}}$", "answer": "Zeta belongs to the intersection of the sets U sub C sub 0 and U sub C sub plus or minus.", "subset": "mixmath", "task_type": "tts"} +{"index": 957, "question": "请你朗读以下数学公式符号:$\\begin{eqnarray}\\frac{4}{5}x&=&\\frac{8}{15}\\\\ x&=&\\frac{8}{15}\\times \\frac{5}{4}\\\\ x&=&\\frac{2}{3}.\\end{eqnarray}$", "audio_path": "audio/math_8b6a5b51-36b0-4338-92cd-3f4882169dfb.wav", "formula": "$\\begin{eqnarray}\\frac{4}{5}x&=&\\frac{8}{15}\\\\ x&=&\\frac{8}{15}\\times \\frac{5}{4}\\\\ x&=&\\frac{2}{3}.\\end{eqnarray}$", "answer": "五分之四x等于十五分之八。x等于十五分之八乘 四分之五。x等于三分之二。", "subset": "mixmath", "task_type": "tts"} +{"index": 958, "question": "请你朗读以下数学公式符号:$C: \\frac{x^2}{a^2} + \\frac{y^2}{b^2} = 1 (a > b > 0)$", "audio_path": "audio/math_1a95f6cb-b308-412c-a1f4-5edbd8364b5e.wav", "formula": "$C: \\frac{x^2}{a^2} + \\frac{y^2}{b^2} = 1 (a > b > 0)$", "answer": "C:a平方分之x平方加b平方分之y平方等于一,a大于b大于零", "subset": "mixmath", "task_type": "tts"} +{"index": 959, "question": "Please read the following math formula symbols: $[d_i,d^\\dag_j]=\\delta_{ij}(n_i-n_{i+1})$", "audio_path": "audio/row_01927548_1755825000348779.wav", "formula": "$[d_i,d^\\dag_j]=\\delta_{ij}(n_i-n_{i+1})$", "answer": "d sub i, d dagger sub j, equals delta sub i j, open parenthesis, n sub i minus n sub i plus 1, close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 960, "question": "请你朗读以下数学公式符号:$25\\times125\\times16=25\\times125\\times2\\times8=(25\\times2)\\times (125\\times8)=50\\times1000=50000$", "audio_path": "audio/math_498e53b7-a2a2-4806-83cd-99fdcf7a0066.wav", "formula": "$25\\times125\\times16=25\\times125\\times2\\times8=(25\\times2)\\times (125\\times8)=50\\times1000=50000$", "answer": "二十五乘一百二十五乘十六等于二十五乘一百二十五乘二乘八等于二十五乘二的积乘一百二十五乘八的积等于五十乘一千等于五万", "subset": "mixmath", "task_type": "tts"} +{"index": 961, "question": "请你朗读以下数学公式符号:$\\underbrace{5\\times {5}\\times {5}\\times ...\\times {5}}_{b}$", "audio_path": "audio/math_7b627682-865d-4bc0-9a0f-17c3dbbfa73a.wav", "formula": "$\\underbrace{5\\times {5}\\times {5}\\times ...\\times {5}}_{b}$", "answer": "b个五相乘", "subset": "mixmath", "task_type": "tts"} +{"index": 962, "question": "请你朗读以下数学公式符号:$\\frac{2}{13}\\div \\frac{7}{5}+\\frac{7}{13}\\times \\frac{5}{7}$", "audio_path": "audio/math_939f1200-655b-45d5-959d-1a1b5b94006f.wav", "formula": "$\\frac{2}{13}\\div \\frac{7}{5}+\\frac{7}{13}\\times \\frac{5}{7}$", "answer": "十三分之二除以七分之五,加上十三分之七乘七分之五", "subset": "mixmath", "task_type": "tts"} +{"index": 963, "question": "请你朗读以下数学公式符号:${{\\left( 1+\\frac{a+b}{2} \\right)}^{2}}=1+a+b+{{\\left( \\frac{a+b}{2} \\right)}^{2}}$", "audio_path": "audio/math_6fc80158-1b62-4562-8588-a4b4d9f08cf0.wav", "formula": "${{\\left( 1+\\frac{a+b}{2} \\right)}^{2}}=1+a+b+{{\\left( \\frac{a+b}{2} \\right)}^{2}}$", "answer": "一加 二分之a加b 的完全平方, 等于一加a加b加 二分之 a加b 整体的平方", "subset": "mixmath", "task_type": "tts"} +{"index": 964, "question": "Please read the following math formula symbols: $S^n=e^{inB}=e^{i\\alphan}I$", "audio_path": "audio/row_01462689_1755766238208838.wav", "formula": "$S^n=e^{inB}=e^{i\\alphan}I$", "answer": "S to the power of n equals e to the power of in B equals e to the power of i alpha n times I.", "subset": "mixmath", "task_type": "tts"} +{"index": 965, "question": "Please read the following math formula symbols: $S^{\\Lambda/((n-k)^{s-1})}$", "audio_path": "audio/row_01293963_1755745026791494.wav", "formula": "$S^{\\Lambda/((n-k)^{s-1})}$", "answer": "S raised to the power of Lambda divided by the quantity n minus k raised to the power of s minus 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 966, "question": "Please read the following math formula symbols: $(x_2,y_2)\\in\\Fix(B_1)$", "audio_path": "audio/row_01214097_1755735051741644.wav", "formula": "$(x_2,y_2)\\in\\Fix(B_1)$", "answer": "Open parenthesis, x sub 2, comma, y sub 2, close parenthesis, belongs to the set of Fix of B sub 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 967, "question": "Please read the following math formula symbols: $\\ho{k}\\subset\\Shv_{\\Nis}(\\Sm_k)$", "audio_path": "audio/row_01160555_1755728305224119.wav", "formula": "$\\ho{k}\\subset\\Shv_{\\Nis}(\\Sm_k)$", "answer": "H o k is a subset of S h v sub N s open parenthesis S m sub k close parenthesis", "subset": "mixmath", "task_type": "tts"} +{"index": 968, "question": "请你朗读以下数学公式符号:$\\left( \\frac{5}{6}\\times 10.68+8.52\\times \\frac{5}{6} \\right)+1\\frac{3}{5}$", "audio_path": "audio/math_cef61633-1332-4649-90a2-44b43bd26706.wav", "formula": "$\\left( \\frac{5}{6}\\times 10.68+8.52\\times \\frac{5}{6} \\right)+1\\frac{3}{5}$", "answer": "六分之五乘十点六八加八点五二乘六分之五的和,加上一又五分之三", "subset": "mixmath", "task_type": "tts"} +{"index": 969, "question": "Please read the following math formula symbols: $\\set{S^{0}_{n}|n=0,1,\\cdots,N-1}$", "audio_path": "audio/row_00985896_1755706479062168.wav", "formula": "$\\set{S^{0}_{n}|n=0,1,\\cdots,N-1}$", "answer": "Set S to the power of zero, sub n, such that n equals zero, one, dot dot dot, N minus one.", "subset": "mixmath", "task_type": "tts"} +{"index": 970, "question": "Please read the following math formula symbols: $R_{\\cdotj}(k)=\\sum_{i=1}^{n_j}R_{i,j}$", "audio_path": "audio/row_01167499_1755729175268639.wav", "formula": "$R_{\\cdotj}(k)=\\sum_{i=1}^{n_j}R_{i,j}$", "answer": "R sub dot j open parenthesis k close parenthesis equals the sum from i equals 1 to n sub j R sub i comma j.", "subset": "mixmath", "task_type": "tts"} +{"index": 971, "question": "Please read the following math formula symbols: $H^k(X[-k]^\\bullet)\\congX$", "audio_path": "audio/row_01260825_1755740883352093.wav", "formula": "$H^k(X[-k]^\\bullet)\\congX$", "answer": "H to the power of k, open parenthesis, X sub negative k, close parenthesis, to the power of bullet, is isomorphic to X.", "subset": "mixmath", "task_type": "tts"} +{"index": 972, "question": "请你朗读以下数学公式符号:$\\begin{eqnarray}\\frac{3}{5}x&=&\\frac{6}{7}:\\frac{2}{3}\\\\ \\frac{6}{7}x&=&\\frac{2}{3}\\times \\frac{3}{5}\\\\ \\frac{6}{7}x\\div \\frac{6}{7}&=&\\frac{2}{3}\\times \\frac{3}{5}\\div \\frac{6}{7}\\\\ x&=&\\frac{7}{15}.\\end{eqnarray}$", "audio_path": "audio/math_711a8877-93b2-4c59-9f1a-dc6996589ef0.wav", "formula": "$\\begin{eqnarray}\\frac{3}{5}x&=&\\frac{6}{7}:\\frac{2}{3}\\\\ \\frac{6}{7}x&=&\\frac{2}{3}\\times \\frac{3}{5}\\\\ \\frac{6}{7}x\\div \\frac{6}{7}&=&\\frac{2}{3}\\times \\frac{3}{5}\\div \\frac{6}{7}\\\\ x&=&\\frac{7}{15}.\\end{eqnarray}$", "answer": "五分之三x等于七分之六比三分之二,七分之六x等于三分之二乘五分之三,七分之六x除以七分之六等于三分之二乘五分之三除以七分之六,x等于十五分之七。", "subset": "mixmath", "task_type": "tts"} +{"index": 973, "question": "请你朗读以下数学公式符号:$29.5\\leqslant \\frac{1}{4}\\left( \\frac{49}{10}x+3 \\right)<39.5$", "audio_path": "audio/math_8e2b7998-f11e-4b3a-baa8-f8c252033ec2.wav", "formula": "$29.5\\leqslant \\frac{1}{4}\\left( \\frac{49}{10}x+3 \\right)<39.5$", "answer": "四分之一倍的十分之四十九x加三的和大于等于二十九点五小于三十九点五", "subset": "mixmath", "task_type": "tts"} +{"index": 974, "question": "Please read the following math formula symbols: $E_i^{(n)}=E_i^n/[n]!$", "audio_path": "audio/row_00749096_1755676837097499.wav", "formula": "$E_i^{(n)}=E_i^n/[n]!$", "answer": "E sub i to the power of n equals E sub i to the power of n divided by factorial of n.", "subset": "mixmath", "task_type": "tts"} +{"index": 975, "question": "请你朗读以下数学公式符号:$=11\\times 13+11\\times 2\\times 8+11\\times 3\\times 7$", "audio_path": "audio/math_bf413329-16f3-4815-8dec-a3ed6886c873.wav", "formula": "$=11\\times 13+11\\times 2\\times 8+11\\times 3\\times 7$", "answer": "等于十一乘十三加十一乘二乘八加十一乘三乘七", "subset": "mixmath", "task_type": "tts"} +{"index": 976, "question": "请你朗读以下数学公式符号:$$=\\frac{5}{6}\\times \\frac{8}{9}\\times \\frac{3}{10}$$", "audio_path": "audio/math_9fd9c6fd-7764-48ab-afb1-fd9ff81c3866.wav", "formula": "$$=\\frac{5}{6}\\times \\frac{8}{9}\\times \\frac{3}{10}$$", "answer": "等于六分之五乘九分之八乘十分之三", "subset": "mixmath", "task_type": "tts"} +{"index": 977, "question": "Please read the following math formula symbols: $\\{(B_j)_{v_j,i}\\}_{i\\inT_1}$", "audio_path": "audio/row_01824219_1755811954005456.wav", "formula": "$\\{(B_j)_{v_j,i}\\}_{i\\inT_1}$", "answer": "Open brace, open parenthesis, B sub j, close parenthesis, sub v comma i, close brace, sub i in T sub 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 978, "question": "请你朗读以下数学公式符号:$\\pi {{r}^{2}}= \\pi \\times 0.5\\times 0.5=0.25 \\pi =0.785$", "audio_path": "audio/math_6ba11a70-10e2-4b2a-b01e-4549a3965907.wav", "formula": "$\\pi {{r}^{2}}= \\pi \\times 0.5\\times 0.5=0.25 \\pi =0.785$", "answer": "pi 乘r平方 等于 pi乘零点五乘零点五 等于 零点二五 pi 等于 零点七八五", "subset": "mixmath", "task_type": "tts"} +{"index": 979, "question": "Please read the following math formula symbols: $\\boldsymbol{e_2}=(-\\sqrt{3}a/2,-a/2)$", "audio_path": "audio/row_01044127_1755713765432210.wav", "formula": "$\\boldsymbol{e_2}=(-\\sqrt{3}a/2,-a/2)$", "answer": "The bold symbol e sub 2 is equal to negative square root of 3 times a divided by 2, negative a divided by 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 980, "question": "Please read the following math formula symbols: $\\kappa_\\sigma(T,K_T+B_T+M_T)=0$", "audio_path": "audio/row_00371090_1755630142756846.wav", "formula": "$\\kappa_\\sigma(T,K_T+B_T+M_T)=0$", "answer": "Kappa sub sigma, open parenthesis, T, comma, K sub T plus B sub T plus M sub T, close parenthesis, equals zero.", "subset": "mixmath", "task_type": "tts"} +{"index": 981, "question": "请你朗读以下数学公式符号:$$\\frac{2}{11}+\\frac{2}{12}+\\frac{2}{13}+\\frac{2}{14}+\\frac{2}{15}+\\frac{2}{16}+\\frac{2}{17}+\\frac{2}{18}+\\frac{2}{19}+\\frac{2}{20}$$", "audio_path": "audio/math_54e6d2d1-1258-47f0-b332-7798b788c778.wav", "formula": "$$\\frac{2}{11}+\\frac{2}{12}+\\frac{2}{13}+\\frac{2}{14}+\\frac{2}{15}+\\frac{2}{16}+\\frac{2}{17}+\\frac{2}{18}+\\frac{2}{19}+\\frac{2}{20}$$", "answer": "十一分之二加十二分之二加十三分之二加十四分之二加十五分之二加十六分之二加十七分之二加十八分之二加十九分之二加二十分之二", "subset": "mixmath", "task_type": "tts"} +{"index": 982, "question": "请你朗读以下数学公式符号:$\\frac{8}{17} < \\frac{14}{23} < \\frac{26}{35} < \\frac{50}{59} < \\frac{52}{61}$", "audio_path": "audio/math_60b6303b-6c61-47df-88c4-c5348b0cef16.wav", "formula": "$\\frac{8}{17} < \\frac{14}{23} < \\frac{26}{35} < \\frac{50}{59} < \\frac{52}{61}$", "answer": "十七分之八小于二十三分之十四小于三十五分之二十六小于五十九分之五十小于六十一分之五十二", "subset": "mixmath", "task_type": "tts"} +{"index": 983, "question": "请你朗读以下数学公式符号:$=\\frac{1}{8}\\times \\frac{3}{4}+\\frac{1}{8}\\times 8\\frac{1}{4}+\\frac{1}{8}\\times 1=\\frac{1}{8}\\times \\left( \\frac{3}{4}+8\\frac{1}{4}+1 \\right)=\\frac{1}{8}\\times 10=\\frac{5}{4}=1.25$", "audio_path": "audio/math_8f5627a6-2125-4ff6-b7c9-ed4b22b4b685.wav", "formula": "$=\\frac{1}{8}\\times \\frac{3}{4}+\\frac{1}{8}\\times 8\\frac{1}{4}+\\frac{1}{8}\\times 1=\\frac{1}{8}\\times \\left( \\frac{3}{4}+8\\frac{1}{4}+1 \\right)=\\frac{1}{8}\\times 10=\\frac{5}{4}=1.25$", "answer": "等于八分之一乘四分之三加八分之一乘八又四分之一加八分之一乘一等于八分之一乘四分之三加八又四分之一加一的和等于八分之一乘十等于四分之五等于一点二五", "subset": "mixmath", "task_type": "tts"} +{"index": 984, "question": "请你朗读以下数学公式符号:$\\left( x+1 \\right)\\left( x+2 \\right)={{x}^{2}}+3x+2$", "audio_path": "audio/math_b92dbbe2-a046-4bd8-bb40-4a53efdbf2e6.wav", "formula": "$\\left( x+1 \\right)\\left( x+2 \\right)={{x}^{2}}+3x+2$", "answer": "x加一的和与x加二的和的积等于x的平方加三x加二", "subset": "mixmath", "task_type": "tts"} +{"index": 985, "question": "Please read the following math formula symbols: $\\hat\\epsilon_i\\defeqY_i-\\phi(X_i,W_i)^T\\hat\\beta$", "audio_path": "audio/row_01725925_1755799504694423.wav", "formula": "$\\hat\\epsilon_i\\defeqY_i-\\phi(X_i,W_i)^T\\hat\\beta$", "answer": "hat epsilon sub i is defined as Y sub i minus phi of X sub i, W sub i, transpose hat beta.", "subset": "mixmath", "task_type": "tts"} +{"index": 986, "question": "Please read the following math formula symbols: $\\bv\\defeq\\frac1T\\sum_{t=0}^{T-1}v_t$", "audio_path": "audio/row_00155344_1755603891113739.wav", "formula": "$\\bv\\defeq\\frac1T\\sum_{t=0}^{T-1}v_t$", "answer": "b v is defined as one over T times the sum from t equals 0 to T minus 1 of v sub t.", "subset": "mixmath", "task_type": "tts"} +{"index": 987, "question": "请你朗读以下数学公式符号:$=\\sqrt{\\frac{5}{3}\\times \\frac{3}{7}\\times \\frac{7}{5}}$", "audio_path": "audio/math_1e471017-005b-488e-a91c-4e034e568fd6.wav", "formula": "$=\\sqrt{\\frac{5}{3}\\times \\frac{3}{7}\\times \\frac{7}{5}}$", "answer": "等于根号下三分之五乘七分之三乘五分之七", "subset": "mixmath", "task_type": "tts"} +{"index": 988, "question": "请你朗读以下数学公式符号:$260\\times \\frac{a}{b}$", "audio_path": "audio/math_7d000db0-9f1f-4fe9-92d5-bdf2a108670e.wav", "formula": "$260\\times \\frac{a}{b}$", "answer": "二百六十乘b分之a", "subset": "mixmath", "task_type": "tts"} +{"index": 989, "question": "Please read the following math formula symbols: $$l_t=l_{t-1}+b_{t-1}+\\alpha\\varepsilon_t,$$", "audio_path": "audio/row_00366213_1755629560446990.wav", "formula": "$$l_t=l_{t-1}+b_{t-1}+\\alpha\\varepsilon_t,$$", "answer": "l sub t equals l sub t minus 1 plus b sub t minus 1 plus alpha times epsilon sub t.", "subset": "mixmath", "task_type": "tts"} +{"index": 990, "question": "Please read the following math formula symbols: $|h_{i+1}|\\leq|h_i|/2$", "audio_path": "audio/row_00622608_1755661147287830.wav", "formula": "$|h_{i+1}|\\leq|h_i|/2$", "answer": "Absolute value of h sub i plus one is less than or equal to absolute value of h sub i divided by 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 991, "question": "Please read the following math formula symbols: $$\\limsup_{n\\to\\infty}\\frac{\\phi^*(n)}{n}=\\log(C)>0.$$", "audio_path": "audio/row_00509486_1755647104664632.wav", "formula": "$$\\limsup_{n\\to\\infty}\\frac{\\phi^*(n)}{n}=\\log(C)>0.$$", "answer": "Limit as n approaches infinity of the fraction phi star of n divided by n equals log of C, greater than 0.", "subset": "mixmath", "task_type": "tts"} +{"index": 992, "question": "Please read the following math formula symbols: $\\tau_j\\inC^\\infty_0(B_{4r_j}(p_j),[0,1])$", "audio_path": "audio/row_01443905_1755763866473612.wav", "formula": "$\\tau_j\\inC^\\infty_0(B_{4r_j}(p_j),[0,1])$", "answer": "Tau sub j belongs to C infinity sub 0 of B sub 4 r sub j of p sub j, open bracket 0, 1 close bracket.", "subset": "mixmath", "task_type": "tts"} +{"index": 993, "question": "请你朗读以下数学公式符号:$\\dfrac{5}{12}\\div 10=\\dfrac{5}{12}\\times \\dfrac{1}{10}=\\dfrac{1\\times 1}{12\\times 2}=\\dfrac{1}{24}$", "audio_path": "audio/math_8a591264-cc55-4d0e-a8d4-7b0087a3b287.wav", "formula": "$\\dfrac{5}{12}\\div 10=\\dfrac{5}{12}\\times \\dfrac{1}{10}=\\dfrac{1\\times 1}{12\\times 2}=\\dfrac{1}{24}$", "answer": "十二分之五除以十,等于十二分之五乘十分之一,等于十二乘二的积分之一乘一,等于二十四分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 994, "question": "请你朗读以下数学公式符号:$\\begin{cases}x+y=50 \\\\ 14x \\times 2=20y \\\\ \\end{cases}$", "audio_path": "audio/math_34753aef-6a0d-4381-9a2d-78157291a44a.wav", "formula": "$\\begin{cases}x+y=50 \\\\ 14x \\times 2=20y \\\\ \\end{cases}$", "answer": "x加y等于五十,十四x乘二等于二十y。", "subset": "mixmath", "task_type": "tts"} +{"index": 995, "question": "Please read the following math formula symbols: $\\|\\x-\\y\\|_N=\\|f(\\x)-f(\\y)\\|_N$", "audio_path": "audio/row_01472828_1755767517308273.wav", "formula": "$\\|\\x-\\y\\|_N=\\|f(\\x)-f(\\y)\\|_N$", "answer": "The norm of x minus y sub N equals the norm of f of x minus f of y sub N.", "subset": "mixmath", "task_type": "tts"} +{"index": 996, "question": "请你朗读以下数学公式符号:$\\frac{13}{11}=\\frac{104}{88}>\\frac{99}{88}=\\frac{9}{8}$", "audio_path": "audio/math_7ec169a0-d073-49ea-9e23-00f9e6e5cc3c.wav", "formula": "$\\frac{13}{11}=\\frac{104}{88}>\\frac{99}{88}=\\frac{9}{8}$", "answer": "十一分之十三等于八十八分之一百零四大于八十八分之九十九等于八分之九", "subset": "mixmath", "task_type": "tts"} +{"index": 997, "question": "请你朗读以下数学公式符号:$\\frac{1}{11}\\times \\left( 1+\\frac{1}{10} \\right)=\\frac{1}{10}$", "audio_path": "audio/math_5fa8106d-1851-4636-9d33-a4c092b659af.wav", "formula": "$\\frac{1}{11}\\times \\left( 1+\\frac{1}{10} \\right)=\\frac{1}{10}$", "answer": "十一分之一乘一加十分之一的和等于十分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 998, "question": "Please read the following math formula symbols: $V_D^{-1,-1}(k_i,n_i)$", "audio_path": "audio/row_01886797_1755819874403351.wav", "formula": "$V_D^{-1,-1}(k_i,n_i)$", "answer": "V sub D to the power of negative one, negative one, open parenthesis k sub i, comma n sub i, close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 999, "question": "Please read the following math formula symbols: $0\\leq\\alpha(t)+\\beta(t)\\leq1$", "audio_path": "audio/row_00404139_1755634208718032.wav", "formula": "$0\\leq\\alpha(t)+\\beta(t)\\leq1$", "answer": "Zero is less than or equal to alpha of t plus beta of t, which is less than or equal to one.", "subset": "mixmath", "task_type": "tts"} +{"index": 1000, "question": "请你朗读以下数学公式符号:$\\left\\{ \\begin{align} & x=6 \\\\ & y=0.4 \\end{align} \\right.$", "audio_path": "audio/math_3dfed970-34c3-4024-beaa-1b4bd76419b0.wav", "formula": "$\\left\\{ \\begin{align} & x=6 \\\\ & y=0.4 \\end{align} \\right.$", "answer": "x等于六,y等于零点四", "subset": "mixmath", "task_type": "tts"} +{"index": 1001, "question": "请你朗读以下数学公式符号:$\\left\\{\\begin{array}{c}5x+6y=16\\\\ 5x=6y\\end{array}\\right.$", "audio_path": "audio/math_e58cc13a-6b87-4ec4-8ae4-40d13c7e07be.wav", "formula": "$\\left\\{\\begin{array}{c}5x+6y=16\\\\ 5x=6y\\end{array}\\right.$", "answer": "五x加六y等于十六,五x等于六y", "subset": "mixmath", "task_type": "tts"} +{"index": 1002, "question": "请你朗读以下数学公式符号:$66\\frac{2}{11}\\times \\frac{400}{7}=3781\\frac{9}{11}$", "audio_path": "audio/math_f52ca2de-8b98-44d2-8772-76117ab7c3ae.wav", "formula": "$66\\frac{2}{11}\\times \\frac{400}{7}=3781\\frac{9}{11}$", "answer": "六十六又十一分之二乘七分之四百等于三千七百八十一又十一分之九", "subset": "mixmath", "task_type": "tts"} +{"index": 1003, "question": "请你朗读以下数学公式符号:${{10}^{{{10}^{n}}}}\\equiv {{10}^{4}}\\equiv {3^{4}}\\equiv 3\\left( mod13 \\right)$", "audio_path": "audio/math_fe0fb4e5-dd54-4474-97c9-f9ace6d83e8b.wav", "formula": "${{10}^{{{10}^{n}}}}\\equiv {{10}^{4}}\\equiv {3^{4}}\\equiv 3\\left( mod13 \\right)$", "answer": "十的十的n次方次方同余于十的四次方同余于三的四次方同余于三模十三", "subset": "mixmath", "task_type": "tts"} +{"index": 1004, "question": "请你朗读以下数学公式符号:$$\\frac{30÷(\\frac{1}{2}+\\frac{1}{3}+\\frac{1}{5})}{\\frac{161}{374}÷\\frac{598}{297}×\\frac{260}{31}}$$", "audio_path": "audio/math_3fdaffa1-ab67-4e0f-a54f-66e12181e4a0.wav", "formula": "$$\\frac{30÷(\\frac{1}{2}+\\frac{1}{3}+\\frac{1}{5})}{\\frac{161}{374}÷\\frac{598}{297}×\\frac{260}{31}}$$", "answer": "三十除以二分之一加三分之一加五分之一的和,整体除以 三百七十四分之一百六十一除以二百九十七分之五百九十八 乘三十一分之二百六十的结果", "subset": "mixmath", "task_type": "tts"} +{"index": 1005, "question": "请你朗读以下数学公式符号:$$5\\frac{5}{8}\\times \\frac{2}{3}\\div 2\\frac{1}{2}=$$", "audio_path": "audio/math_1c3952cd-130c-4a89-8837-92b1c050a0b1.wav", "formula": "$$5\\frac{5}{8}\\times \\frac{2}{3}\\div 2\\frac{1}{2}=$$", "answer": "五又八分之五乘三分之二除以二又二分之一等于", "subset": "mixmath", "task_type": "tts"} +{"index": 1006, "question": "请你朗读以下数学公式符号:$$\\frac{2\\times 2}{1\\times 3}+\\frac{4\\times 4}{3\\times 5}+\\frac{6\\times 6}{5\\times 7}+\\frac{8\\times 8}{7\\times 9}+\\frac{10\\times 10}{9\\times 11}=$$", "audio_path": "audio/math_193e6380-afd6-4fc9-abcd-89ef586b64a2.wav", "formula": "$$\\frac{2\\times 2}{1\\times 3}+\\frac{4\\times 4}{3\\times 5}+\\frac{6\\times 6}{5\\times 7}+\\frac{8\\times 8}{7\\times 9}+\\frac{10\\times 10}{9\\times 11}=$$", "answer": "一乘三的积分之二乘二的积加三乘五的积分之四乘四的积加五乘七的积分之六乘六的积加七乘九的积分之八乘八的积加九乘十一的积分之十乘十的积等于", "subset": "mixmath", "task_type": "tts"} +{"index": 1007, "question": "Please read the following math formula symbols: $\\Ybt_k^\\top\\Ubt_k\\Sigmabt_k\\Vbt_k^\\top\\Ybt_k=\\zerob$", "audio_path": "audio/row_01896436_1755821073612008.wav", "formula": "$\\Ybt_k^\\top\\Ubt_k\\Sigmabt_k\\Vbt_k^\\top\\Ybt_k=\\zerob$", "answer": "Y b t sub k top U b t sub k Sigma b t sub k top Y b t sub k equals zero b", "subset": "mixmath", "task_type": "tts"} +{"index": 1008, "question": "Please read the following math formula symbols: $S_w=\\{t\\midt\\landx\\inS\\}\\cup(S\\cap\\IP(\\Sigma_{w}))$", "audio_path": "audio/row_00541345_1755650995073863.wav", "formula": "$S_w=\\{t\\midt\\landx\\inS\\}\\cup(S\\cap\\IP(\\Sigma_{w}))$", "answer": "S sub w equals the set of t such that t and x is in S union S intersection IP of Sigma sub w.", "subset": "mixmath", "task_type": "tts"} +{"index": 1009, "question": "Please read the following math formula symbols: $Z^{TST}_{2}\\equiv\\left\\{1,TST\\right\\}$", "audio_path": "audio/row_01532151_1755775013075710.wav", "formula": "$Z^{TST}_{2}\\equiv\\left\\{1,TST\\right\\}$", "answer": "Z raised to the power of T S sub 2 is equivalent to the set containing 1 and T S S.", "subset": "mixmath", "task_type": "tts"} +{"index": 1010, "question": "请你朗读以下数学公式符号:$a\\left( x+y \\right)\\leqslant 1+{{x}^{2}}+xy+{{y}^{2}}$", "audio_path": "audio/math_1bcc5f91-bbd1-4eff-9544-d0316a4b829f.wav", "formula": "$a\\left( x+y \\right)\\leqslant 1+{{x}^{2}}+xy+{{y}^{2}}$", "answer": "a倍的x加y小于等于一加x的平方加x乘 y加y的平方", "subset": "mixmath", "task_type": "tts"} +{"index": 1011, "question": "请你朗读以下数学公式符号:$\\frac{1}{{{x}_{1}}}+\\frac{1}{{{x}_{2}}}=\\frac{{{x}_{1}}+{{x}_{2}}}{{{x}_{1}}{{x}_{2}}}$", "audio_path": "audio/math_daf9c463-6f2d-4a6b-8e55-edccfc3cb610.wav", "formula": "$\\frac{1}{{{x}_{1}}}+\\frac{1}{{{x}_{2}}}=\\frac{{{x}_{1}}+{{x}_{2}}}{{{x}_{1}}{{x}_{2}}}$", "answer": "x一 分之一 加x二 分之一等于x一x二 分之x一加x二的和", "subset": "mixmath", "task_type": "tts"} +{"index": 1012, "question": "Please read the following math formula symbols: $E_G^{(i)}\\in\\mathbb{R}^d$", "audio_path": "audio/row_00663006_1755666125302662.wav", "formula": "$E_G^{(i)}\\in\\mathbb{R}^d$", "answer": "E sub G raised to the power of i belongs to the set of real numbers raised to the power of d.", "subset": "mixmath", "task_type": "tts"} +{"index": 1013, "question": "请你朗读以下数学公式符号:$$965+225+775+3035=\\left( 965+3035 \\right)+\\left( 225+775 \\right)=5000$$", "audio_path": "audio/math_fffde528-f3a3-4e9f-8507-aa4e09736eaa.wav", "formula": "$$965+225+775+3035=\\left( 965+3035 \\right)+\\left( 225+775 \\right)=5000$$", "answer": "九百六十五加二百二十五加七百七十五加三千零三十五等于九百六十五加三千零三十五的和加二百二十五加七百七十五的和等于五千", "subset": "mixmath", "task_type": "tts"} +{"index": 1014, "question": "请你朗读以下数学公式符号:$0.3\\overset{.}{\\mathop{0}}\\overset{.}{\\mathop{2}}$", "audio_path": "audio/math_2e5ef806-5382-40a6-93f4-ef10c0c5845e.wav", "formula": "$0.3\\overset{.}{\\mathop{0}}\\overset{.}{\\mathop{2}}$", "answer": "零点三零二 零二循环", "subset": "mixmath", "task_type": "tts"} +{"index": 1015, "question": "Please read the following math formula symbols: $\\Gamma_{xy}X^k=(X+y-x)^k.$", "audio_path": "audio/row_01385839_1755756549230676.wav", "formula": "$\\Gamma_{xy}X^k=(X+y-x)^k.$", "answer": "Gamma sub x y times X to the power of k equals open parenthesis X plus y minus x close parenthesis to the power of k.", "subset": "mixmath", "task_type": "tts"} +{"index": 1016, "question": "请你朗读以下数学公式符号:$\\begin{cases}\\dfrac{54}{7}\\leqslant x\\leqslant \\dfrac{104}{7} \\\\ \\dfrac{55}{9}\\leqslant y\\leqslant \\dfrac{105}{9} \\end{cases}$", "audio_path": "audio/math_0d6021e8-a5c6-4dc7-af50-c98f55e15f60.wav", "formula": "$\\begin{cases}\\dfrac{54}{7}\\leqslant x\\leqslant \\dfrac{104}{7} \\\\ \\dfrac{55}{9}\\leqslant y\\leqslant \\dfrac{105}{9} \\end{cases}$", "answer": "x大于等于七分之五十四小于等于七分之一百零四;y大于等于九分之五十五小于等于九分之一百零五", "subset": "mixmath", "task_type": "tts"} +{"index": 1017, "question": "Please read the following math formula symbols: $K_\\mathrm{mct}[F_\\mathrm{mct}]>K_\\mathrm{mct}[F]$", "audio_path": "audio/row_01321691_1755748467797742.wav", "formula": "$K_\\mathrm{mct}[F_\\mathrm{mct}]>K_\\mathrm{mct}[F]$", "answer": "K sub m c t of F sub m c t is greater than K sub m c t of F.", "subset": "mixmath", "task_type": "tts"} +{"index": 1018, "question": "Please read the following math formula symbols: $\\{z^{(n)}\\}_{1\\leqn\\leqN}$", "audio_path": "audio/row_00542605_1755651142126292.wav", "formula": "$\\{z^{(n)}\\}_{1\\leqn\\leqN}$", "answer": "Curly brace, z to the power of n, end curly brace, subscript 1 less than or equal to n less than or equal to capital N.", "subset": "mixmath", "task_type": "tts"} +{"index": 1019, "question": "Please read the following math formula symbols: $\\widehat{k}\\leqk\\leq\\min(m,n)$", "audio_path": "audio/row_00531378_1755649778649081.wav", "formula": "$\\widehat{k}\\leqk\\leq\\min(m,n)$", "answer": "The hat of k is less than or equal to k is less than or equal to the minimum of m and n.", "subset": "mixmath", "task_type": "tts"} +{"index": 1020, "question": "请你朗读以下数学公式符号:$\\left\\{\\begin{array}{l}x=3\\\\y=6\\end{array}\\right.$", "audio_path": "audio/math_cc237025-49cd-4e59-8004-b5328959d73f.wav", "formula": "$\\left\\{\\begin{array}{l}x=3\\\\y=6\\end{array}\\right.$", "answer": "x等于三 和 y等于六", "subset": "mixmath", "task_type": "tts"} +{"index": 1021, "question": "请你朗读以下数学公式符号:$27\\left( =\\frac{1}{2}\\left( 44+10 \\right) \\right)$", "audio_path": "audio/math_5ecf62e8-9e34-4df1-9c32-fdbfefce78eb.wav", "formula": "$27\\left( =\\frac{1}{2}\\left( 44+10 \\right) \\right)$", "answer": "二十七等于二分之一乘四十四加十的和", "subset": "mixmath", "task_type": "tts"} +{"index": 1022, "question": "请你朗读以下数学公式符号:$3.14\\times {{2}^{2}}\\times 2+12.56\\times 8=125.6$", "audio_path": "audio/math_4457615c-fa7c-4c5c-929d-b7f49b5b83d2.wav", "formula": "$3.14\\times {{2}^{2}}\\times 2+12.56\\times 8=125.6$", "answer": "三点一四乘二的平方乘二,加上十二点五六乘八等于一百二十五点六", "subset": "mixmath", "task_type": "tts"} +{"index": 1023, "question": "Please read the following math formula symbols: $L_{\\bbA^1}\\bbZ(j)^\\sub{mot}|_{\\Sm_{\\bbF}}$", "audio_path": "audio/row_01612978_1755785259953654.wav", "formula": "$L_{\\bbA^1}\\bbZ(j)^\\sub{mot}|_{\\Sm_{\\bbF}}$", "answer": "L sub B A superscript 1, B B Z open parenthesis j close parenthesis superscript subset mot vertical bar sub S m sub F", "subset": "mixmath", "task_type": "tts"} +{"index": 1024, "question": "Please read the following math formula symbols: $\\left\\{\\varphi^k(w)\\midk=0,1,\\dots\\right\\}$", "audio_path": "audio/row_00767007_1755679073372008.wav", "formula": "$\\left\\{\\varphi^k(w)\\midk=0,1,\\dots\\right\\}$", "answer": "Left brace, phi to the power of k of w, such that k equals 0, 1, dot dot dot, right brace.", "subset": "mixmath", "task_type": "tts"} +{"index": 1025, "question": "Please read the following math formula symbols: $8p^16f^45g^1$", "audio_path": "audio/row_00076729_1755594387472488.wav", "formula": "$8p^16f^45g^1$", "answer": "8p raised to the power of 1, 6f raised to the power of 4, 5g raised to the power of 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 1026, "question": "请你朗读以下数学公式符号:$\\frac{8}{9}\\div \\frac{1}{63}=\\frac{8}{9}\\times 63=56$", "audio_path": "audio/math_67edbf07-e3a8-4eee-b655-c2c01b5e57ee.wav", "formula": "$\\frac{8}{9}\\div \\frac{1}{63}=\\frac{8}{9}\\times 63=56$", "answer": "九分之八除以六十三分之一等于九分之八乘六十三等于五十六", "subset": "mixmath", "task_type": "tts"} +{"index": 1027, "question": "请你朗读以下数学公式符号:$\\left( x+a \\right)\\left( x+6 \\right)={{x}^{2}}+8x+12$", "audio_path": "audio/math_cfc87164-a85c-4dfb-bf19-33c3e677276c.wav", "formula": "$\\left( x+a \\right)\\left( x+6 \\right)={{x}^{2}}+8x+12$", "answer": "x加a的和乘x加六的和等于x的平方加八x加十二", "subset": "mixmath", "task_type": "tts"} +{"index": 1028, "question": "请你朗读以下数学公式符号:$\\left\\{\\begin{array}{l}m=6\\\\ n=12\\end{array}\\right.$", "audio_path": "audio/math_eaa9789c-6312-4e53-a78a-e49739746444.wav", "formula": "$\\left\\{\\begin{array}{l}m=6\\\\ n=12\\end{array}\\right.$", "answer": "m等于六,n等于十二", "subset": "mixmath", "task_type": "tts"} +{"index": 1029, "question": "请你朗读以下数学公式符号:$\\dfrac{1}{5}\\times\\left( 1+\\dfrac{3}{10}\\right)=\\dfrac{13}{50}$", "audio_path": "audio/math_51ba7ccb-a9de-40db-8b71-a36e69967cd9.wav", "formula": "$\\dfrac{1}{5}\\times\\left( 1+\\dfrac{3}{10}\\right)=\\dfrac{13}{50}$", "answer": "五分之一乘一加十分之三的和等于五十分之十三", "subset": "mixmath", "task_type": "tts"} +{"index": 1030, "question": "Please read the following math formula symbols: $z_1^2+z_2^2=re^{\\sqrt{-1}\\theta}$", "audio_path": "audio/row_02090326_1755845583117725.wav", "formula": "$z_1^2+z_2^2=re^{\\sqrt{-1}\\theta}$", "answer": "z sub 1 squared plus z sub 2 squared equals r times e to the power of the negative one times theta.", "subset": "mixmath", "task_type": "tts"} +{"index": 1031, "question": "Please read the following math formula symbols: $e(t)\\conc\\langlei\\rangle\\subseteqe(t\\conc\\langlei\\rangle)$", "audio_path": "audio/row_00539033_1755650704052497.wav", "formula": "$e(t)\\conc\\langlei\\rangle\\subseteqe(t\\conc\\langlei\\rangle)$", "answer": "e of t is congruent to the angle bracket i, which is a subset of e of t is congruent to the angle bracket i.", "subset": "mixmath", "task_type": "tts"} +{"index": 1032, "question": "Please read the following math formula symbols: $P^\\sfe:=\\bmP^*(x^{\\sfe})$", "audio_path": "audio/row_00261190_1755616782596271.wav", "formula": "$P^\\sfe:=\\bmP^*(x^{\\sfe})$", "answer": "P to the power of epsilon is defined as the matrix P star evaluated at x to the power of epsilon.", "subset": "mixmath", "task_type": "tts"} +{"index": 1033, "question": "Please read the following math formula symbols: $[\\widehat{e}_{1}(z)dz]_{\\mathrm{Hodge}}=0$", "audio_path": "audio/row_01723270_1755799179702010.wav", "formula": "$[\\widehat{e}_{1}(z)dz]_{\\mathrm{Hodge}}=0$", "answer": "Open square bracket, hat e sub 1 open parenthesis z close parenthesis d z close square bracket sub Hodge equals 0.", "subset": "mixmath", "task_type": "tts"} +{"index": 1034, "question": "Please read the following math formula symbols: $R_{mn}=\\partial_k\\arg\\xi_{nm}+a_m-a_n$", "audio_path": "audio/row_00801825_1755683439901501.wav", "formula": "$R_{mn}=\\partial_k\\arg\\xi_{nm}+a_m-a_n$", "answer": "R sub m n equals the partial derivative with respect to k of xi sub n m plus a sub m minus a sub n.", "subset": "mixmath", "task_type": "tts"} +{"index": 1035, "question": "请你朗读以下数学公式符号:$\\left( 84\\times 25 \\right)\\times 8=84\\times \\left( 25\\times 8 \\right)$", "audio_path": "audio/math_b3c625bc-5fb6-497b-9e4c-63f9be237635.wav", "formula": "$\\left( 84\\times 25 \\right)\\times 8=84\\times \\left( 25\\times 8 \\right)$", "answer": "八十四乘二十五的积乘八等于八十四乘二十五乘八的积", "subset": "mixmath", "task_type": "tts"} +{"index": 1036, "question": "Please read the following math formula symbols: $\\frac{e^{0}}{e^{0}+e^{0.14}}$", "audio_path": "audio/row_01411494_1755759761480996.wav", "formula": "$\\frac{e^{0}}{e^{0}+e^{0.14}}$", "answer": "Fraction e to the power of 0, divided by e to the power of 0 plus e to the power of 0.14.", "subset": "mixmath", "task_type": "tts"} +{"index": 1037, "question": "Please read the following math formula symbols: $W^{(1)}\\cupW^{(2)}\\cupW^{(3)}$", "audio_path": "audio/row_01449755_1755764597059849.wav", "formula": "$W^{(1)}\\cupW^{(2)}\\cupW^{(3)}$", "answer": "W raised to the power of 1, union W raised to the power of 2, union W raised to the power of 3.", "subset": "mixmath", "task_type": "tts"} +{"index": 1038, "question": "请你朗读以下数学公式符号:$$ \\left\\{\\begin{array}{c}2x=3y\\\\ 4x+7y=34800\\end{array}\\right.$$", "audio_path": "audio/math_05753395-76c8-4491-92d1-94455266c230.wav", "formula": "$$ \\left\\{\\begin{array}{c}2x=3y\\\\ 4x+7y=34800\\end{array}\\right.$$", "answer": "二x等于三y,四x加七y等于三万四千八百", "subset": "mixmath", "task_type": "tts"} +{"index": 1039, "question": "Please read the following math formula symbols: $F=\\{x\\in\\mathbb{R}\\midf(x)\\neq0\\}$", "audio_path": "audio/row_00385355_1755631897164017.wav", "formula": "$F=\\{x\\in\\mathbb{R}\\midf(x)\\neq0\\}$", "answer": "F is the set of all x in the real numbers such that f of x is not equal to zero.", "subset": "mixmath", "task_type": "tts"} +{"index": 1040, "question": "Please read the following math formula symbols: $\\zeta(n,l_{\\check\\nu}(z))\\leqO_z(\\epsilon_n)$", "audio_path": "audio/row_01208168_1755734294586167.wav", "formula": "$\\zeta(n,l_{\\check\\nu}(z))\\leqO_z(\\epsilon_n)$", "answer": "Zeta of n, l sub cosine nu of z, is less than or equal to O sub z of epsilon sub n.", "subset": "mixmath", "task_type": "tts"} +{"index": 1041, "question": "请你朗读以下数学公式符号:$92\\times 49+108\\times 51+92\\times 51+49\\times 108$", "audio_path": "audio/math_67790686-4b22-47b1-85b5-4454aed86c36.wav", "formula": "$92\\times 49+108\\times 51+92\\times 51+49\\times 108$", "answer": "九十二乘四十九加一百零八乘五十一加九十二乘五十一加四十九乘一百零八", "subset": "mixmath", "task_type": "tts"} +{"index": 1042, "question": "请你朗读以下数学公式符号:$24\\times \\left( \\frac{3}{8}\\div 6+\\frac{5}{12} \\right)$", "audio_path": "audio/math_fd5c8fc3-8083-47b7-83ca-eadc486a051c.wav", "formula": "$24\\times \\left( \\frac{3}{8}\\div 6+\\frac{5}{12} \\right)$", "answer": "二十四乘括号八分之三除以六加十二分之五括号", "subset": "mixmath", "task_type": "tts"} +{"index": 1043, "question": "Please read the following math formula symbols: $,+(x_{1},\\ldots,x_{n})=\\sum_{1}^{n}x_{i}$", "audio_path": "audio/row_00832606_1755687302704594.wav", "formula": "$,+(x_{1},\\ldots,x_{n})=\\sum_{1}^{n}x_{i}$", "answer": "comma plus open parenthesis x sub 1 comma ellipsis comma x sub n close parenthesis equals sigma sub 1 caret n x sub i", "subset": "mixmath", "task_type": "tts"} +{"index": 1044, "question": "Please read the following math formula symbols: $v(G_{r+1})<2^{-b(r+1)}n$", "audio_path": "audio/row_01083972_1755718731036149.wav", "formula": "$v(G_{r+1})<2^{-b(r+1)}n$", "answer": "v of G sub r plus 1 is less than 2 to the power of negative b times r plus 1 times n.", "subset": "mixmath", "task_type": "tts"} +{"index": 1045, "question": "请你朗读以下数学公式符号:$\\left( 1+2\\times 3+4\\times 5+6 \\right)\\times 7+8\\times 9=303$", "audio_path": "audio/math_88c522e7-0772-42d8-9f4d-de3ce53267c5.wav", "formula": "$\\left( 1+2\\times 3+4\\times 5+6 \\right)\\times 7+8\\times 9=303$", "answer": "一加二乘三加四乘五加六的和乘七加八乘九等于三百零三", "subset": "mixmath", "task_type": "tts"} +{"index": 1046, "question": "Please read the following math formula symbols: $f_2(n_1,n_2)=n_1n_2$", "audio_path": "audio/row_01240476_1755738331640371.wav", "formula": "$f_2(n_1,n_2)=n_1n_2$", "answer": "f sub 2 open parenthesis n sub 1 comma n sub 2 close parenthesis equals n sub 1 n sub 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 1047, "question": "Please read the following math formula symbols: $T_n\\geq\\chi_{p+1}^2[1-\\phi]$", "audio_path": "audio/row_01360759_1755753393090226.wav", "formula": "$T_n\\geq\\chi_{p+1}^2[1-\\phi]$", "answer": "T sub n is greater than or equal to chi sub p plus 1 squared times the quantity 1 minus phi.", "subset": "mixmath", "task_type": "tts"} +{"index": 1048, "question": "Please read the following math formula symbols: $\\Q_{\\mu_0}(\\tau_\\g>t)=\\e^{-t}.$", "audio_path": "audio/row_01905253_1755822186270630.wav", "formula": "$\\Q_{\\mu_0}(\\tau_\\g>t)=\\e^{-t}.$", "answer": "Q sub mu sub 0 open parenthesis tau sub g greater than t close parenthesis equals e to the power of negative t.", "subset": "mixmath", "task_type": "tts"} +{"index": 1049, "question": "请你朗读以下数学公式符号:$\\frac{9}{5}=\\frac{5+4}{5}=1+\\frac{4}{5}=1\\frac{4}{5}$", "audio_path": "audio/math_14faedb1-3648-4361-be8f-5299213f4367.wav", "formula": "$\\frac{9}{5}=\\frac{5+4}{5}=1+\\frac{4}{5}=1\\frac{4}{5}$", "answer": "五分之九等于五分之五加四的和等于一加五分之四等于一又五分之四", "subset": "mixmath", "task_type": "tts"} +{"index": 1050, "question": "Please read the following math formula symbols: $$\\Cov(r_i,r_j)=\\E[\\beta_i]^T\\V[f]\\E[\\beta_j]$$", "audio_path": "audio/row_01490110_1755769714478263.wav", "formula": "$$\\Cov(r_i,r_j)=\\E[\\beta_i]^T\\V[f]\\E[\\beta_j]$$", "answer": "Covariance of r sub i comma r sub j equals expectation of beta sub i transpose V sub f expectation of beta sub j.", "subset": "mixmath", "task_type": "tts"} +{"index": 1051, "question": "请你朗读以下数学公式符号:$$5\\div 4=1.25=20\\times \\frac{1}{16}=\\frac{80}{64}=125\\%$$", "audio_path": "audio/math_8de5c7a8-566a-4182-9b1a-2a180a237bfe.wav", "formula": "$$5\\div 4=1.25=20\\times \\frac{1}{16}=\\frac{80}{64}=125\\%$$", "answer": "五除以四等于一点二五等于二十乘十六分之一等于六十四分之八十等于百分之一百二十五", "subset": "mixmath", "task_type": "tts"} +{"index": 1052, "question": "Please read the following math formula symbols: $\\smash{t_{\\mu_0}^{\\mu_t}(x)=m_t+(x-m_0)}$", "audio_path": "audio/row_00459837_1755641018517233.wav", "formula": "$\\smash{t_{\\mu_0}^{\\mu_t}(x)=m_t+(x-m_0)}$", "answer": "t sub mu zero superscript mu t of x equals m t plus open parenthesis x minus m zero close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 1053, "question": "请你朗读以下数学公式符号:$=92\\times \\left( 49+51 \\right)+108\\times \\left( 51+49 \\right)$", "audio_path": "audio/math_823202ee-698b-482e-9bef-7e4b386d0b5d.wav", "formula": "$=92\\times \\left( 49+51 \\right)+108\\times \\left( 51+49 \\right)$", "answer": "等于九十二乘四十九加五十一的和加一百零八乘五十一加四十九的和", "subset": "mixmath", "task_type": "tts"} +{"index": 1054, "question": "请你朗读以下数学公式符号:$$\\begin{eqnarray}&&0.125\\times 408\\\\ &=&0.125\\times \\left( 400+8 \\right)\\\\ &=&0.125\\times 400+0.125\\times 8\\\\ &=&50+1\\\\ &=&51.\\end{eqnarray}$$", "audio_path": "audio/math_e2946150-645b-402d-b15d-b2b4e78ce745.wav", "formula": "$$\\begin{eqnarray}&&0.125\\times 408\\\\ &=&0.125\\times \\left( 400+8 \\right)\\\\ &=&0.125\\times 400+0.125\\times 8\\\\ &=&50+1\\\\ &=&51.\\end{eqnarray}$$", "answer": "零点一二五乘四百零八等于零点一二五乘四百加八的和等于零点一二五乘四百加零点一二五乘八等于五十加一等于五十一", "subset": "mixmath", "task_type": "tts"} +{"index": 1055, "question": "Please read the following math formula symbols: $({\\hat\\pi}^1,\\ldots,{\\hat\\pi}^k)$", "audio_path": "audio/row_00876930_1755692892976573.wav", "formula": "$({\\hat\\pi}^1,\\ldots,{\\hat\\pi}^k)$", "answer": "Open parenthesis, hat pi raised to the power of 1, comma, ellipsis, hat pi raised to the power of k, close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 1056, "question": "Please read the following math formula symbols: $\\{p_r:1\\leqr\\leqk\\}$", "audio_path": "audio/row_01673692_1755792914440637.wav", "formula": "$\\{p_r:1\\leqr\\leqk\\}$", "answer": "Open brace, p sub r, colon, 1 less than or equal to r less than or equal to k, close brace.", "subset": "mixmath", "task_type": "tts"} +{"index": 1057, "question": "请你朗读以下数学公式符号:$50\\left( 1+x \\right)+20{{\\left( 1+x \\right)}^{2}}=72$", "audio_path": "audio/math_54941839-cf90-4c95-a765-3a9843656abc.wav", "formula": "$50\\left( 1+x \\right)+20{{\\left( 1+x \\right)}^{2}}=72$", "answer": "五十乘一加x的和加上二十乘一加x的和的平方等于七十二", "subset": "mixmath", "task_type": "tts"} +{"index": 1058, "question": "请你朗读以下数学公式符号:$$119\\div 1000=\\frac{119}{1000}\\left( {L} \\right)$$", "audio_path": "audio/math_bc16f550-e198-4c5c-9e0e-721faf4bd46b.wav", "formula": "$$119\\div 1000=\\frac{119}{1000}\\left( {L} \\right)$$", "answer": "一百一十九除以一千等于一千分之一百一十九升", "subset": "mixmath", "task_type": "tts"} +{"index": 1059, "question": "请你朗读以下数学公式符号:$\\left\\{ \\begin{matrix} x=y+1 \\\\ 10x+y=y+x+9 \\end{matrix} \\right.$", "audio_path": "audio/math_5bbc7b65-352d-41fe-8310-ceddfcdabbee.wav", "formula": "$\\left\\{ \\begin{matrix} x=y+1 \\\\ 10x+y=y+x+9 \\end{matrix} \\right.$", "answer": "x等于y加一和十x加y等于y加x加九", "subset": "mixmath", "task_type": "tts"} +{"index": 1060, "question": "Please read the following math formula symbols: $$H(X)=-\\sum_{x\\inA}p_x\\log_2p_x.$$", "audio_path": "audio/row_01210855_1755734638141461.wav", "formula": "$$H(X)=-\\sum_{x\\inA}p_x\\log_2p_x.$$", "answer": "H of X equals negative summation over x in A of p sub x logarithm base 2 of p sub x.", "subset": "mixmath", "task_type": "tts"} +{"index": 1061, "question": "Please read the following math formula symbols: $\\langlef(\\chi)\\rangle=\\sum_{k=1}^Np_kf(\\chi_k)$", "audio_path": "audio/row_01977725_1755831316808879.wav", "formula": "$\\langlef(\\chi)\\rangle=\\sum_{k=1}^Np_kf(\\chi_k)$", "answer": "Angle bracket f of chi equals the sum from k equals 1 to N of p sub k times f of chi sub k.", "subset": "mixmath", "task_type": "tts"} +{"index": 1062, "question": "Please read the following math formula symbols: $e(G_{f(S)})\\leq(1-\\gamma)e(\\Gamma)$", "audio_path": "audio/row_00888677_1755694350673492.wav", "formula": "$e(G_{f(S)})\\leq(1-\\gamma)e(\\Gamma)$", "answer": "e of G sub f of S is less than or equal to open parenthesis 1 minus gamma close parenthesis e of Gamma.", "subset": "mixmath", "task_type": "tts"} +{"index": 1063, "question": "请你朗读以下数学公式符号:$=\\frac{11}{4}\\times \\frac{5}{11}\\times \\frac{8}{3}$", "audio_path": "audio/math_ca14aef4-6f4b-4342-aff8-cbba6f7a3660.wav", "formula": "$=\\frac{11}{4}\\times \\frac{5}{11}\\times \\frac{8}{3}$", "answer": "等于四分之十一乘十一分之五乘三分之八", "subset": "mixmath", "task_type": "tts"} +{"index": 1064, "question": "请你朗读以下数学公式符号:$$\\begin{matrix}242\\div (80+30)=2.2 \\\\ 2.2\\times 30=66 \\end{matrix}$$", "audio_path": "audio/math_c6c1a4e5-5657-4109-896c-7b045cac6281.wav", "formula": "$$\\begin{matrix}242\\div (80+30)=2.2 \\\\ 2.2\\times 30=66 \\end{matrix}$$", "answer": "二百四十二除以八十加三十的和等于二点二,二点二乘三十等于六十六", "subset": "mixmath", "task_type": "tts"} +{"index": 1065, "question": "Please read the following math formula symbols: $\\Pm^j\\coloneqq\\pi(\\thetab)^j$", "audio_path": "audio/row_01013791_1755709974840638.wav", "formula": "$\\Pm^j\\coloneqq\\pi(\\thetab)^j$", "answer": "P m raised to the power of j is defined as pi of theta b raised to the power of j.", "subset": "mixmath", "task_type": "tts"} +{"index": 1066, "question": "请你朗读以下数学公式符号:$\\left\\{ \\begin{align} & x=3 \\\\ & y=4 \\end{align} \\right.$", "audio_path": "audio/math_34258960-d501-4dc3-bc4f-8fa73b4bb0f9.wav", "formula": "$\\left\\{ \\begin{align} & x=3 \\\\ & y=4 \\end{align} \\right.$", "answer": "x等于三,y等于四", "subset": "mixmath", "task_type": "tts"} +{"index": 1067, "question": "请你朗读以下数学公式符号:$5050+5051+\\ldots +5150=\\left( 5050+5150 \\right)\\times 101\\div 2=515100$", "audio_path": "audio/math_a3c591f0-e3b1-4bd8-9236-0d77147b4ea1.wav", "formula": "$5050+5051+\\ldots +5150=\\left( 5050+5150 \\right)\\times 101\\div 2=515100$", "answer": "五千零五十加五千零五十一加一直加到加五千一百五十等于五千零五十加五千一百五十的和乘一百零一除以二等于五十一万五千一百", "subset": "mixmath", "task_type": "tts"} +{"index": 1068, "question": "请你朗读以下数学公式符号:$\\frac{1}{8}=\\frac{9}{72}=\\frac{1}{72}+\\frac{1}{9}$", "audio_path": "audio/math_e49e9312-6bb8-4a4d-852c-7553df48e4cb.wav", "formula": "$\\frac{1}{8}=\\frac{9}{72}=\\frac{1}{72}+\\frac{1}{9}$", "answer": "八分之一等于七十二分之九等于七十二分之一加九分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 1069, "question": "Please read the following math formula symbols: $(\\mu^j)_{1\\leqj\\leqr}$", "audio_path": "audio/row_01299572_1755745715870003.wav", "formula": "$(\\mu^j)_{1\\leqj\\leqr}$", "answer": "mu raised to the power of j, sub 1 less than or equal to j less than or equal to r.", "subset": "mixmath", "task_type": "tts"} +{"index": 1070, "question": "Please read the following math formula symbols: $\\|\\rho-\\rho_0\\|_{\\Uc,2}\\leq\\ve(D_0)$", "audio_path": "audio/row_00095998_1755596721056582.wav", "formula": "$\\|\\rho-\\rho_0\\|_{\\Uc,2}\\leq\\ve(D_0)$", "answer": "Norm of the difference between rho and rho sub 0, subscript Uc comma 2, is less than or equal to epsilon times D sub 0.", "subset": "mixmath", "task_type": "tts"} +{"index": 1071, "question": "请你朗读以下数学公式符号:$$\\begin{eqnarray} &=&4.2\\times 0.01\\\\ &=&0.042.\\end{eqnarray}$$", "audio_path": "audio/math_9d38fdd2-9c10-4ec7-b162-8f3ac64d21ac.wav", "formula": "$$\\begin{eqnarray} &=&4.2\\times 0.01\\\\ &=&0.042.\\end{eqnarray}$$", "answer": "等于四点二乘零点零一等于零点零四二。", "subset": "mixmath", "task_type": "tts"} +{"index": 1072, "question": "请你朗读以下数学公式符号:${{x}_{1}}^{2}+{{x}_{1}}+{{x}_{2}}^{2}+{{x}_{2}}={{x}_{1}}{{x}_{2}}+{{x}_{1}}+{{x}_{2}}+1$", "audio_path": "audio/math_2ed55e21-0cb2-456f-8975-5f87503d01eb.wav", "formula": "${{x}_{1}}^{2}+{{x}_{1}}+{{x}_{2}}^{2}+{{x}_{2}}={{x}_{1}}{{x}_{2}}+{{x}_{1}}+{{x}_{2}}+1$", "answer": "x 一的平方加x 一加x 二的平方加x 二等于x 一乘 x 二加x 一加x 二加一", "subset": "mixmath", "task_type": "tts"} +{"index": 1073, "question": "Please read the following math formula symbols: $\\int|f|^pd\\gamma<\\infty$", "audio_path": "audio/row_01127259_1755724113996170.wav", "formula": "$\\int|f|^pd\\gamma<\\infty$", "answer": "Integral of the absolute value of f raised to the power of p, with respect to gamma, is less than infinity.", "subset": "mixmath", "task_type": "tts"} +{"index": 1074, "question": "Please read the following math formula symbols: $v(r)=v_\\infty(1-R_\\ast/r)^\\beta$", "audio_path": "audio/row_00481606_1755643679022788.wav", "formula": "$v(r)=v_\\infty(1-R_\\ast/r)^\\beta$", "answer": "v of r equals v infinity times the quantity one minus R asterisk over r raised to the power of beta.", "subset": "mixmath", "task_type": "tts"} +{"index": 1075, "question": "请你朗读以下数学公式符号:$\\left\\{\\begin{array}{c} x=1\\\\ y=1 \\end{array}\\right.$", "audio_path": "audio/math_3392cfbf-1759-4478-be23-45dafb49109e.wav", "formula": "$\\left\\{\\begin{array}{c} x=1\\\\ y=1 \\end{array}\\right.$", "answer": "x等于一和y等于一", "subset": "mixmath", "task_type": "tts"} +{"index": 1076, "question": "请你朗读以下数学公式符号:$25\\left[1+\\left( 1+x\\right)+{{\\left( 1+x\\right)}^{2}} \\right]=82.75$", "audio_path": "audio/math_36c672ce-554f-471f-b2f0-557ceb0a8f23.wav", "formula": "$25\\left[1+\\left( 1+x\\right)+{{\\left( 1+x\\right)}^{2}} \\right]=82.75$", "answer": "二十五乘 中括号 一加 一加x的和 加一加x的和的平方 中括号等于八十二点七五", "subset": "mixmath", "task_type": "tts"} +{"index": 1077, "question": "请你朗读以下数学公式符号:${{\\left( x+y \\right)}^{3}}{{\\left( 2x+2y \\right)}^{3}}{{\\left( 3x+3y \\right)}^{3}}$", "audio_path": "audio/math_9f332311-ad02-4c36-84fe-85f9cbe03761.wav", "formula": "${{\\left( x+y \\right)}^{3}}{{\\left( 2x+2y \\right)}^{3}}{{\\left( 3x+3y \\right)}^{3}}$", "answer": "x加y的和的立方乘二x加二y的和的立方乘三x加三y的和的立方", "subset": "mixmath", "task_type": "tts"} +{"index": 1078, "question": "Please read the following math formula symbols: $\\mathrm{Cov}(\\|Z\\|_2,\\|Z\\|_{\\logt})\\geq0$", "audio_path": "audio/row_01579160_1755780967971486.wav", "formula": "$\\mathrm{Cov}(\\|Z\\|_2,\\|Z\\|_{\\logt})\\geq0$", "answer": "Covariance of the norm of Z sub 2 and the norm of Z sub log t is greater than or equal to zero.", "subset": "mixmath", "task_type": "tts"} +{"index": 1079, "question": "Please read the following math formula symbols: $\\mathcal{B}^\\alpha_n(\\scrd{f}{nlm1},\\cdot)$", "audio_path": "audio/row_01497527_1755770640526435.wav", "formula": "$\\mathcal{B}^\\alpha_n(\\scrd{f}{nlm1},\\cdot)$", "answer": "Mathcal B to the power of alpha sub n, open parenthesis, scrd f, n l m 1, comma, dot, close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 1080, "question": "Please read the following math formula symbols: $\\vertK(x\\verty)-K'(x\\verty)\\vert\\le\\kappa$", "audio_path": "audio/row_00272917_1755618213196624.wav", "formula": "$\\vertK(x\\verty)-K'(x\\verty)\\vert\\le\\kappa$", "answer": "Absolute value of K of x given y minus K prime of x given y is less than or equal to kappa.", "subset": "mixmath", "task_type": "tts"} +{"index": 1081, "question": "请你朗读以下数学公式符号:$$\\begin{eqnarray}8※(X※2)&=&50\\\\ 8※(3X+2\\times2)&=&50\\\\ 3\\times8+2(3X+2\\times2)&=&50\\\\ 24+6X+8&=&50\\\\ 6X&=&18\\\\ X&=&3\\end{eqnarray}$$", "audio_path": "audio/math_f59cd0a4-0031-451b-bb65-8186a93479cc.wav", "formula": "$$\\begin{eqnarray}8※(X※2)&=&50\\\\ 8※(3X+2\\times2)&=&50\\\\ 3\\times8+2(3X+2\\times2)&=&50\\\\ 24+6X+8&=&50\\\\ 6X&=&18\\\\ X&=&3\\end{eqnarray}$$", "answer": "八星号 括号 X 星号二 括号 等于五十, 八星号 括号 三X加二乘二 括号 等于五十,三乘八加二倍的 三X加二乘二 等于五十,二十四加六X加八等于五十,六X等于十八,X等于三。", "subset": "mixmath", "task_type": "tts"} +{"index": 1082, "question": "请你朗读以下数学公式符号:$$ \\left\\{\\begin{array}{c}\\Delta \\geqslant 0\\\\ k\\ne 0\\end{array}\\right.$$", "audio_path": "audio/math_1e0f6790-1879-40fd-afd3-76bbafdc67f0.wav", "formula": "$$ \\left\\{\\begin{array}{c}\\Delta \\geqslant 0\\\\ k\\ne 0\\end{array}\\right.$$", "answer": "delta大于等于零和k不等于零", "subset": "mixmath", "task_type": "tts"} +{"index": 1083, "question": "Please read the following math formula symbols: $\\lvert\\pi(\\mathbb{Z}_k)\\rvert=l$", "audio_path": "audio/row_00422799_1755636456226783.wav", "formula": "$\\lvert\\pi(\\mathbb{Z}_k)\\rvert=l$", "answer": "The absolute value of the cardinality of the set of integers modulo k, denoted as pi of Z sub k, is equal to l.", "subset": "mixmath", "task_type": "tts"} +{"index": 1084, "question": "Please read the following math formula symbols: $U=\\exp\\left[\\frac{2\\pii}{f}\\vec{\\pi}\\cdot\\vec{T}\\right]$", "audio_path": "audio/row_01161796_1755728464364983.wav", "formula": "$U=\\exp\\left[\\frac{2\\pii}{f}\\vec{\\pi}\\cdot\\vec{T}\\right]$", "answer": "U equals e to the power of open square bracket, 2 pi i over f, pi dot T, close square bracket.", "subset": "mixmath", "task_type": "tts"} +{"index": 1085, "question": "Please read the following math formula symbols: $\\mathcal{H}_t(E)=\\{h_y:y\\inE\\}$", "audio_path": "audio/row_01367268_1755754204300284.wav", "formula": "$\\mathcal{H}_t(E)=\\{h_y:y\\inE\\}$", "answer": "The set H sub t of E is equal to the set of h sub y, where y belongs to E.", "subset": "mixmath", "task_type": "tts"} +{"index": 1086, "question": "请你朗读以下数学公式符号:$\\begin{cases}35\\dfrac{7}{17}\\geqslant \\dfrac{n}{2} \\\\ 35\\dfrac{7}{17}\\leqslant \\dfrac{n+2}{2} \\end{cases}$", "audio_path": "audio/math_94372391-a63e-4f1a-9b14-9bd525cac6ff.wav", "formula": "$\\begin{cases}35\\dfrac{7}{17}\\geqslant \\dfrac{n}{2} \\\\ 35\\dfrac{7}{17}\\leqslant \\dfrac{n+2}{2} \\end{cases}$", "answer": "三十五又十七分之七大于等于二分之n,三十五又十七分之七小于等于二分之n加二的和", "subset": "mixmath", "task_type": "tts"} +{"index": 1087, "question": "请你朗读以下数学公式符号:$(6\\times 9+6\\times 9+6\\times 6)\\times 2=(54+54+36)\\times 2=288$", "audio_path": "audio/math_805a9511-3e4a-4415-bc57-e1408a7240fd.wav", "formula": "$(6\\times 9+6\\times 9+6\\times 6)\\times 2=(54+54+36)\\times 2=288$", "answer": "六乘九加六乘九加六乘六的和乘二等于五十四加五十四加三十六的和乘二等于二百八十八", "subset": "mixmath", "task_type": "tts"} +{"index": 1088, "question": "请你朗读以下数学公式符号:$\\left\\{ \\begin{aligned} & 5x+3y = k+2 \\\\ & 3x+2y = k \\end{aligned} \\right.$", "audio_path": "audio/math_7a84cde7-dc6d-41d5-8d33-004985d944b3.wav", "formula": "$\\left\\{ \\begin{aligned} & 5x+3y = k+2 \\\\ & 3x+2y = k \\end{aligned} \\right.$", "answer": "五x加三y等于k加二和三x加二y等于k", "subset": "mixmath", "task_type": "tts"} +{"index": 1089, "question": "Please read the following math formula symbols: $\\boldsymbol{x}^{(l-1)}\\in\\mathbb{R}^{(n_{l-1})}$", "audio_path": "audio/row_01687688_1755794682647174.wav", "formula": "$\\boldsymbol{x}^{(l-1)}\\in\\mathbb{R}^{(n_{l-1})}$", "answer": "X raised to the power of l minus 1 belongs to the set of real numbers raised to the power of n sub l minus 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 1090, "question": "请你朗读以下数学公式符号:$=\\left( \\frac{3}{4}+\\frac{1}{4} \\right)+\\left( \\frac{5}{14}+\\frac{9}{14} \\right)$", "audio_path": "audio/math_691db139-968a-4169-a9a6-d1d2e20724f6.wav", "formula": "$=\\left( \\frac{3}{4}+\\frac{1}{4} \\right)+\\left( \\frac{5}{14}+\\frac{9}{14} \\right)$", "answer": "等于四分之三加四分之一的和加十四分之五加十四分之九的和", "subset": "mixmath", "task_type": "tts"} +{"index": 1091, "question": "Please read the following math formula symbols: $(C_0:=C,C_1,C_2,\\dots,C_{\\ell-1},C_{\\ell}:=C')$", "audio_path": "audio/row_00588628_1755656847586278.wav", "formula": "$(C_0:=C,C_1,C_2,\\dots,C_{\\ell-1},C_{\\ell}:=C')$", "answer": "C sub 0 equals C, C sub 1, C sub 2, dot dot dot, C sub ell minus 1, C sub ell equals C prime.", "subset": "mixmath", "task_type": "tts"} +{"index": 1092, "question": "Please read the following math formula symbols: $p\\notdiv2n(1+pu)^{-3}=h'(u)/p$", "audio_path": "audio/row_00630041_1755662048012249.wav", "formula": "$p\\notdiv2n(1+pu)^{-3}=h'(u)/p$", "answer": "p not divided by 2n times 1 plus p raised to the power of negative 3 equals h prime of u divided by p.", "subset": "mixmath", "task_type": "tts"} +{"index": 1093, "question": "Please read the following math formula symbols: $V,V^1,V^2,\\ldots,V^x$", "audio_path": "audio/row_01246831_1755739140492901.wav", "formula": "$V,V^1,V^2,\\ldots,V^x$", "answer": "V, V raised to the power of 1, V raised to the power of 2, dot dot dot, V raised to the power of x.", "subset": "mixmath", "task_type": "tts"} +{"index": 1094, "question": "请你朗读以下数学公式符号:$$=\\frac{3}{10}\\times \\frac{5}{7}\\times \\frac{10}{21}=\\frac{5}{49}$$", "audio_path": "audio/math_3ef0150f-fc11-4107-8eb2-d148868f8519.wav", "formula": "$$=\\frac{3}{10}\\times \\frac{5}{7}\\times \\frac{10}{21}=\\frac{5}{49}$$", "answer": "等于十分之三乘七分之五乘二十一分之十等于四十九分之五", "subset": "mixmath", "task_type": "tts"} +{"index": 1095, "question": "Please read the following math formula symbols: $\\varepsilon^{(I)}:=(\\varepsilon_v^{(I)})_{v\\inV}$", "audio_path": "audio/row_01875876_1755818483124056.wav", "formula": "$\\varepsilon^{(I)}:=(\\varepsilon_v^{(I)})_{v\\inV}$", "answer": "Epsilon raised to the power of I is equal to epsilon subscript v raised to the power of I, all divided by v in V.", "subset": "mixmath", "task_type": "tts"} +{"index": 1096, "question": "请你朗读以下数学公式符号:$\\frac{5}{12}\\div 0.6=\\frac{5}{12}\\div \\frac{3}{5}=\\frac{5}{12}\\times \\frac{5}{3}$", "audio_path": "audio/math_99ff38db-6250-4054-882b-8a1dca988b01.wav", "formula": "$\\frac{5}{12}\\div 0.6=\\frac{5}{12}\\div \\frac{3}{5}=\\frac{5}{12}\\times \\frac{5}{3}$", "answer": "十二分之五除以零点六等于十二分之五除以五分之三等于十二分之五乘三分之五", "subset": "mixmath", "task_type": "tts"} +{"index": 1097, "question": "Please read the following math formula symbols: $0.024\\leqA_{\\rm1549}\\leq0.43$", "audio_path": "audio/row_01019884_1755710727088758.wav", "formula": "$0.024\\leqA_{\\rm1549}\\leq0.43$", "answer": "Zero point zero two four less than or equal to A sub 1549 less than or equal to zero point four three.", "subset": "mixmath", "task_type": "tts"} +{"index": 1098, "question": "Please read the following math formula symbols: $H_0:\\Delta_i\\simN(0,\\sigma)\\foralli\\inD_{r_1}$", "audio_path": "audio/row_01236195_1755737810466379.wav", "formula": "$H_0:\\Delta_i\\simN(0,\\sigma)\\foralli\\inD_{r_1}$", "answer": "H sub 0, Delta sub i is distributed as normal with mean 0 and variance sigma, for all i in D sub r sub 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 1099, "question": "Please read the following math formula symbols: $B=(\\mathbf{b}_1,\\ldots,\\mathbf{b}_{n_{l-1}+1})$", "audio_path": "audio/row_00278006_1755618828620238.wav", "formula": "$B=(\\mathbf{b}_1,\\ldots,\\mathbf{b}_{n_{l-1}+1})$", "answer": "B equals open parenthesis, bold b sub 1, ellipsis, bold b sub n sub l minus 1 plus 1, close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 1100, "question": "请你朗读以下数学公式符号:$$\\frac{7}{999}\\times 35+\\frac{7}{999}\\times 26+\\frac{7}{999}\\times 50=$$", "audio_path": "audio/math_7b473422-12b8-456e-b899-205fc748d991.wav", "formula": "$$\\frac{7}{999}\\times 35+\\frac{7}{999}\\times 26+\\frac{7}{999}\\times 50=$$", "answer": "九百九十九分之七乘三十五加九百九十九分之七乘二十六加九百九十九分之七乘五十等于", "subset": "mixmath", "task_type": "tts"} +{"index": 1101, "question": "Please read the following math formula symbols: $I(\\nu,t)=\\delta^3I(\\nu',t')\\sim8\\Gamma^3I(\\nu',t')$", "audio_path": "audio/row_00386898_1755632088463214.wav", "formula": "$I(\\nu,t)=\\delta^3I(\\nu',t')\\sim8\\Gamma^3I(\\nu',t')$", "answer": "I of nu, t equals delta cubed I of nu prime, t prime, approximately eight gamma cubed I of nu prime, t prime.", "subset": "mixmath", "task_type": "tts"} +{"index": 1102, "question": "请你朗读以下数学公式符号:$=1.23\\times 56+1.23\\times 33+1.23\\times 11=1.23\\times (56+33+11)=123$", "audio_path": "audio/math_0f352b9b-cc5e-4fa2-ad74-8ca463f428b7.wav", "formula": "$=1.23\\times 56+1.23\\times 33+1.23\\times 11=1.23\\times (56+33+11)=123$", "answer": "等于一点二三乘五十六加一点二三乘三十三加一点二三乘十一等于一点二三乘五十六加三十三加十一的和等于一百二十三", "subset": "mixmath", "task_type": "tts"} +{"index": 1103, "question": "请你朗读以下数学公式符号:$\\frac{1}{8}=\\frac{1+8}{8\\times (1+8)}=\\frac{1}{72}+\\frac{1}{9}$", "audio_path": "audio/math_a4b8f127-f37d-4aca-9857-4b0f5ff960c7.wav", "formula": "$\\frac{1}{8}=\\frac{1+8}{8\\times (1+8)}=\\frac{1}{72}+\\frac{1}{9}$", "answer": "八分之一等于八乘一加八的和分之一加八的和等于七十二分之一加九分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 1104, "question": "Please read the following math formula symbols: $\\lambda^{(1)}_k=[2/\\pi(2k-1)]^2$", "audio_path": "audio/row_00757257_1755677844084518.wav", "formula": "$\\lambda^{(1)}_k=[2/\\pi(2k-1)]^2$", "answer": "Lambda to the power of one, sub k, equals the quantity two over pi times the quantity two k minus one, squared.", "subset": "mixmath", "task_type": "tts"} +{"index": 1105, "question": "Please read the following math formula symbols: $\\nor{\\rho^r-1}_{C^\\alpha}\\lesssimr^\\alpha$", "audio_path": "audio/row_01075757_1755717703700307.wav", "formula": "$\\nor{\\rho^r-1}_{C^\\alpha}\\lesssimr^\\alpha$", "answer": "Nor rho to the power of r minus one, subscript C alpha, less than or approximately equal to r to the power of alpha.", "subset": "mixmath", "task_type": "tts"} +{"index": 1106, "question": "Please read the following math formula symbols: $I_{j,i}(z)\\inB_j(0,\\lambda'''r_\\ell)$", "audio_path": "audio/row_01227134_1755736668367766.wav", "formula": "$I_{j,i}(z)\\inB_j(0,\\lambda'''r_\\ell)$", "answer": "I sub j, i of z belongs to B sub j open parenthesis 0, lambda double prime r sub ell close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 1107, "question": "Please read the following math formula symbols: $\\norm{u}_{H_0^1(\\Omega)}\\leqC_u$", "audio_path": "audio/row_00399596_1755633645762826.wav", "formula": "$\\norm{u}_{H_0^1(\\Omega)}\\leqC_u$", "answer": "the norm of u in the H zero one space of Omega is less than or equal to C sub u.", "subset": "mixmath", "task_type": "tts"} +{"index": 1108, "question": "Please read the following math formula symbols: $D\\cdotv_y,D\\cdotv_{y}+1,\\ldots,D\\cdotv_{y}+D-1$", "audio_path": "audio/row_01922077_1755824322402559.wav", "formula": "$D\\cdotv_y,D\\cdotv_{y}+1,\\ldots,D\\cdotv_{y}+D-1$", "answer": "D times v sub y, D times v sub y plus 1, dot dot dot, D times v sub y plus D minus 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 1109, "question": "Please read the following math formula symbols: $v_A\\!=\\,\\mid\\!\\!B_r\\!\\!\\mid\\!\\!/\\sqrt{\\rho\\mu_0}$", "audio_path": "audio/row_00108872_1755598264894467.wav", "formula": "$v_A\\!=\\,\\mid\\!\\!B_r\\!\\!\\mid\\!\\!/\\sqrt{\\rho\\mu_0}$", "answer": "v sub A factorial equals absolute value of B sub r factorial divided by the square root of rho mu zero.", "subset": "mixmath", "task_type": "tts"} +{"index": 1110, "question": "Please read the following math formula symbols: $|\\cT_3(L^S)|\\sim\\mathbf{a}$", "audio_path": "audio/row_01472377_1755767460773156.wav", "formula": "$|\\cT_3(L^S)|\\sim\\mathbf{a}$", "answer": "Absolute value of c times T sub 3 times L to the power of S is approximately equal to bold a.", "subset": "mixmath", "task_type": "tts"} +{"index": 1111, "question": "请你朗读以下数学公式符号:$\\left( x+y \\right)\\ne \\left( x \\right)+\\left( y \\right)$", "audio_path": "audio/math_c14e2abc-d228-457b-be89-36585e387ce4.wav", "formula": "$\\left( x+y \\right)\\ne \\left( x \\right)+\\left( y \\right)$", "answer": "x加y的和不等于x加y", "subset": "mixmath", "task_type": "tts"} +{"index": 1112, "question": "Please read the following math formula symbols: $\\wfratperp{j}=\\colrad\\gamrot^{-1}\\cos\\Theta_j^{(0)}$", "audio_path": "audio/row_01373063_1755754920986755.wav", "formula": "$\\wfratperp{j}=\\colrad\\gamrot^{-1}\\cos\\Theta_j^{(0)}$", "answer": "W fperp j equals colrad gamma rot to the power of negative one cosine Theta j to the power of zero.", "subset": "mixmath", "task_type": "tts"} +{"index": 1113, "question": "Please read the following math formula symbols: $in(\\ref{def-NN-loss-3})%toobtainanestimate$", "audio_path": "audio/row_00942127_1755701043923658.wav", "formula": "$in(\\ref{def-NN-loss-3})%toobtainanestimate$", "answer": "In the context of the law, the equation in parentheses, f minus n o s minus 3, percent, to an estimate.", "subset": "mixmath", "task_type": "tts"} +{"index": 1114, "question": "请你朗读以下数学公式符号:$$\\frac{\\left( 0.125+\\dfrac{3}{5} \\right)\\times \\dfrac{33}{87}}{12.1\\times \\dfrac{1}{11}}$$", "audio_path": "audio/math_45b68561-40d4-4aa1-b80d-7b2388c15f2e.wav", "formula": "$$\\frac{\\left( 0.125+\\dfrac{3}{5} \\right)\\times \\dfrac{33}{87}}{12.1\\times \\dfrac{1}{11}}$$", "answer": "十二点一乘十一分之一的积分之零点一二五加五分之三的和乘八十七分之三十三", "subset": "mixmath", "task_type": "tts"} +{"index": 1115, "question": "Please read the following math formula symbols: $\\uu(\\kappa)=\\P_{<\\kappa}\\oplus(\\dotS_i:i<\\kappa)$", "audio_path": "audio/row_00817899_1755685453763805.wav", "formula": "$\\uu(\\kappa)=\\P_{<\\kappa}\\oplus(\\dotS_i:i<\\kappa)$", "answer": "u of kappa equals P sub less than kappa direct sum of dot S sub i colon i less than kappa", "subset": "mixmath", "task_type": "tts"} +{"index": 1116, "question": "Please read the following math formula symbols: $\\log{(\\rm{M_{BH}}/\\rm{M_\\odot})}=9.3^{+0.5}_{-0.8}$", "audio_path": "audio/row_01707828_1755797210105578.wav", "formula": "$\\log{(\\rm{M_{BH}}/\\rm{M_\\odot})}=9.3^{+0.5}_{-0.8}$", "answer": "Log of the ratio of M sub BH to M sub solar equals 9.3 raised to the power of plus 0.5, sub minus 0.8.", "subset": "mixmath", "task_type": "tts"} +{"index": 1117, "question": "Please read the following math formula symbols: $k(j')\\getsk(j')-1$", "audio_path": "audio/row_00143064_1755602406775110.wav", "formula": "$k(j')\\getsk(j')-1$", "answer": "k times the derivative of j prime is assigned the value of k times the derivative of j prime minus one.", "subset": "mixmath", "task_type": "tts"} +{"index": 1118, "question": "请你朗读以下数学公式符号:$$\\left( 80+4 \\right)\\times 125=80\\times 125+4\\times 125$$", "audio_path": "audio/math_81de88d3-f69a-401a-bf7a-a0750f68fac6.wav", "formula": "$$\\left( 80+4 \\right)\\times 125=80\\times 125+4\\times 125$$", "answer": "八十加四的和乘一百二十五等于八十乘一百二十五加四乘一百二十五", "subset": "mixmath", "task_type": "tts"} +{"index": 1119, "question": "Please read the following math formula symbols: $t_{\\rmcool}^{(s)}/t_{\\rmff}\\proptoV_{\\rmesc}^{4.4}$", "audio_path": "audio/row_00330532_1755625207684934.wav", "formula": "$t_{\\rmcool}^{(s)}/t_{\\rmff}\\proptoV_{\\rmesc}^{4.4}$", "answer": "t sub cool, raised to the power of s, divided by t sub ff, is proportional to V sub esc raised to the power of 4.4.", "subset": "mixmath", "task_type": "tts"} +{"index": 1120, "question": "请你朗读以下数学公式符号:$$29\\times 12+29\\times 13+29\\times 25+29\\times 10$$", "audio_path": "audio/math_ee61cc6c-13bb-4303-a8ea-6dcc2b7865ce.wav", "formula": "$$29\\times 12+29\\times 13+29\\times 25+29\\times 10$$", "answer": "二十九乘十二加二十九乘十三加二十九乘二十五加二十九乘十", "subset": "mixmath", "task_type": "tts"} +{"index": 1121, "question": "请你朗读以下数学公式符号:$$\\dfrac{7}{8}\\div 6=\\dfrac{7}{8}\\times \\dfrac{1}{6}=\\dfrac{7}{48}$$", "audio_path": "audio/math_151f663a-63f6-4cc8-b05b-eba15cb6742f.wav", "formula": "$$\\dfrac{7}{8}\\div 6=\\dfrac{7}{8}\\times \\dfrac{1}{6}=\\dfrac{7}{48}$$", "answer": "八分之七除以六等于八分之七乘六分之一等于四十八分之七", "subset": "mixmath", "task_type": "tts"} +{"index": 1122, "question": "请你朗读以下数学公式符号:$\\sqrt{2.4}=\\sqrt{\\frac{24}{10}}=\\frac{2\\sqrt{15}}{5}$", "audio_path": "audio/math_41c011fb-4e20-408f-b2cf-7f0c466e5d55.wav", "formula": "$\\sqrt{2.4}=\\sqrt{\\frac{24}{10}}=\\frac{2\\sqrt{15}}{5}$", "answer": "根号二点四等于根号下十分之二十四等于五分之二倍的根号十五", "subset": "mixmath", "task_type": "tts"} +{"index": 1123, "question": "请你朗读以下数学公式符号:$\\frac{\\sqrt{5}}{\\sqrt{3}}\\times \\frac{\\sqrt{3}}{\\sqrt{7}}\\times \\frac{\\sqrt{7}}{\\sqrt{5}}=\\sqrt{\\frac{5}{7}}\\times \\sqrt{\\frac{7}{5}}=1$", "audio_path": "audio/math_bd75fb72-039d-4822-a6bf-867ddc6dfbc6.wav", "formula": "$\\frac{\\sqrt{5}}{\\sqrt{3}}\\times \\frac{\\sqrt{3}}{\\sqrt{7}}\\times \\frac{\\sqrt{7}}{\\sqrt{5}}=\\sqrt{\\frac{5}{7}}\\times \\sqrt{\\frac{7}{5}}=1$", "answer": "根号三分之根号五 乘 根号七分之根号三 乘 根号五分之根号七 等于 根号下七分之五 乘 根号下五分之七 等于 一", "subset": "mixmath", "task_type": "tts"} +{"index": 1124, "question": "请你朗读以下数学公式符号:$\\left( 6\\times 2+6\\times 4+4\\times 2 \\right)\\times 2=88$", "audio_path": "audio/math_132507da-dc63-409d-ae38-a937b7926b61.wav", "formula": "$\\left( 6\\times 2+6\\times 4+4\\times 2 \\right)\\times 2=88$", "answer": "六乘二加六乘四加四乘二的和乘二等于八十八", "subset": "mixmath", "task_type": "tts"} +{"index": 1125, "question": "Please read the following math formula symbols: $\\propto(Y^{n,n+1}+Y^{n+1,n})$", "audio_path": "audio/row_00650338_1755664550573622.wav", "formula": "$\\propto(Y^{n,n+1}+Y^{n+1,n})$", "answer": "Proportional to the quantity Y to the power of n, n plus one plus Y to the power of n plus one, n.", "subset": "mixmath", "task_type": "tts"} +{"index": 1126, "question": "Please read the following math formula symbols: $L_{pop,\\infty}=\\frac{p_a}{2(1-L_{pop})}$", "audio_path": "audio/row_01778750_1755806199252526.wav", "formula": "$L_{pop,\\infty}=\\frac{p_a}{2(1-L_{pop})}$", "answer": "L sub p comma infinity equals the fraction p sub a divided by 2 times the quantity 1 minus L sub p.", "subset": "mixmath", "task_type": "tts"} +{"index": 1127, "question": "请你朗读以下数学公式符号:${{x}^{10}}+{{y}^{10}}\\geqslant \\frac{1}{2}\\left( {{x}^{8}}+{{y}^{8}} \\right)\\left( {{x}^{2}}+{{y}^{2}} \\right)=\\frac{1}{2}\\left( {{x}^{8}}+{{y}^{8}} \\right)$", "audio_path": "audio/math_dbe80eda-b4ed-4e64-b186-630fdbec7c87.wav", "formula": "${{x}^{10}}+{{y}^{10}}\\geqslant \\frac{1}{2}\\left( {{x}^{8}}+{{y}^{8}} \\right)\\left( {{x}^{2}}+{{y}^{2}} \\right)=\\frac{1}{2}\\left( {{x}^{8}}+{{y}^{8}} \\right)$", "answer": "x的十次方加y的十次方大于等于二分之一乘x的八次方加y的八次方的和乘x的平方加y的平方的和,等于二分之一乘x的八次方加y的八次方的和", "subset": "mixmath", "task_type": "tts"} +{"index": 1128, "question": "Please read the following math formula symbols: $T_C(K(a,b)):[0,\\infty)\\to\\Vect_K$", "audio_path": "audio/row_00260329_1755616668890516.wav", "formula": "$T_C(K(a,b)):[0,\\infty)\\to\\Vect_K$", "answer": "T sub C of K of a, b is a function that maps the interval from 0 to infinity to the vector space over K.", "subset": "mixmath", "task_type": "tts"} +{"index": 1129, "question": "请你朗读以下数学公式符号:$$L=\\frac{n \\pi R}{180}=\\frac{30 \\pi \\cdot 5}{180}=\\frac{5 \\pi }{6}$$", "audio_path": "audio/math_66c22f13-983e-4a26-883f-9e1bcec27713.wav", "formula": "$$L=\\frac{n \\pi R}{180}=\\frac{30 \\pi \\cdot 5}{180}=\\frac{5 \\pi }{6}$$", "answer": "L等于一百八十分之n pi R等于一百八十分之三十pi乘五等于六分之五pi", "subset": "mixmath", "task_type": "tts"} +{"index": 1130, "question": "Please read the following math formula symbols: $Y_{e^t}=(\\mathcal{L}_\\ThetaX)_{e^t}$", "audio_path": "audio/row_00071023_1755593702783513.wav", "formula": "$Y_{e^t}=(\\mathcal{L}_\\ThetaX)_{e^t}$", "answer": "Y sub e to the power of t equals the Laplace transform of X with respect to Theta, evaluated at e to the power of t.", "subset": "mixmath", "task_type": "tts"} +{"index": 1131, "question": "请你朗读以下数学公式符号:$=\\dfrac{8{{x}^{2}}\\cdot \\left( x+1 \\right)}{\\left( {{x}^{2}}+2x+1 \\right)\\cdot 6x}$", "audio_path": "audio/math_bdd3b777-0e9c-456b-97f6-5b4d39fab174.wav", "formula": "$=\\dfrac{8{{x}^{2}}\\cdot \\left( x+1 \\right)}{\\left( {{x}^{2}}+2x+1 \\right)\\cdot 6x}$", "answer": "等于x平方加二x加一的和乘六x的积分之八x平方乘x加一的和", "subset": "mixmath", "task_type": "tts"} +{"index": 1132, "question": "Please read the following math formula symbols: $\\theta_0\\in\\{\\pm0.5,\\pm1,\\pm1.5,\\pm2\\}$", "audio_path": "audio/row_00836270_1755687772015906.wav", "formula": "$\\theta_0\\in\\{\\pm0.5,\\pm1,\\pm1.5,\\pm2\\}$", "answer": "Theta sub zero belongs to the set of plus or minus 0.5, plus or minus 1, plus or minus 1.5, plus or minus 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 1133, "question": "请你朗读以下数学公式符号:$\\left\\{ \\begin{align} & 2x=k+2 \\\\ & x=k \\\\ \\end{align} \\right.$", "audio_path": "audio/math_93c0f7ac-0dbe-496e-b197-58e139b88ccb.wav", "formula": "$\\left\\{ \\begin{align} & 2x=k+2 \\\\ & x=k \\\\ \\end{align} \\right.$", "answer": "二x等于k加二,x等于k", "subset": "mixmath", "task_type": "tts"} +{"index": 1134, "question": "请你朗读以下数学公式符号:$\\left( 6\\times 3 \\right):\\left( 6\\times 2 \\right):\\left( 3\\times 2 \\right)=18:12:6=3:2:1$", "audio_path": "audio/math_5c3ffa02-e4da-4d31-b408-8c3175c1119b.wav", "formula": "$\\left( 6\\times 3 \\right):\\left( 6\\times 2 \\right):\\left( 3\\times 2 \\right)=18:12:6=3:2:1$", "answer": "六乘三的积比六乘二的积比三乘二的积等于十八比十二比六等于三比二比一", "subset": "mixmath", "task_type": "tts"} +{"index": 1135, "question": "Please read the following math formula symbols: $\\beta^\\intercalx-\\bar{\\beta}\\le0$", "audio_path": "audio/row_01740565_1755801368641741.wav", "formula": "$\\beta^\\intercalx-\\bar{\\beta}\\le0$", "answer": "Beta raised to the power of beta, greater than or equal to x minus beta bar, less than or equal to zero.", "subset": "mixmath", "task_type": "tts"} +{"index": 1136, "question": "请你朗读以下数学公式符号:$$\\frac{1}{2}+\\frac{1}{3(1+A)}=\\frac{2}{3}\\Rightarrow A=1$$", "audio_path": "audio/math_529ea455-e2f9-4930-9bc8-178d60846e81.wav", "formula": "$$\\frac{1}{2}+\\frac{1}{3(1+A)}=\\frac{2}{3}\\Rightarrow A=1$$", "answer": "二分之一加三乘一加A的和的积分之一等于三分之二,推出A等于一", "subset": "mixmath", "task_type": "tts"} +{"index": 1137, "question": "Please read the following math formula symbols: $\\log(a+b)\\leq2\\max\\{\\loga,\\logb\\}$", "audio_path": "audio/row_01041414_1755713426128616.wav", "formula": "$\\log(a+b)\\leq2\\max\\{\\loga,\\logb\\}$", "answer": "Log of the quantity a plus b is less than or equal to 2 times the maximum of log a and log b.", "subset": "mixmath", "task_type": "tts"} +{"index": 1138, "question": "Please read the following math formula symbols: $\\frac{|A_k|}{|F_k|}\\leq1$", "audio_path": "audio/row_00618233_1755660598153770.wav", "formula": "$\\frac{|A_k|}{|F_k|}\\leq1$", "answer": "The absolute value of A sub k divided by the absolute value of F sub k is less than or equal to 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 1139, "question": "请你朗读以下数学公式符号:$\\begin{eqnarray}&&(20+4)\\times25\\\\ &=&20\\times25+4\\times25\\\\ &=&500+100\\\\ &=&600\\end{eqnarray}$", "audio_path": "audio/math_0bde8125-0f64-4169-b8bb-8326a69f161d.wav", "formula": "$\\begin{eqnarray}&&(20+4)\\times25\\\\ &=&20\\times25+4\\times25\\\\ &=&500+100\\\\ &=&600\\end{eqnarray}$", "answer": "二十加四的和乘二十五等于二十乘二十五加四乘二十五等于五百加一百等于六百", "subset": "mixmath", "task_type": "tts"} +{"index": 1140, "question": "Please read the following math formula symbols: ${x}_T=\\left[c_T^d,c_T^p\\right]$", "audio_path": "audio/row_01318231_1755748022228264.wav", "formula": "${x}_T=\\left[c_T^d,c_T^p\\right]$", "answer": "x sub T equals open bracket c sub T to the power of d, comma c sub T to the power of p close bracket.", "subset": "mixmath", "task_type": "tts"} +{"index": 1141, "question": "请你朗读以下数学公式符号:$\\frac{3}{4}{+}\\frac{1}{6}{+}\\frac{5}{12}=\\frac{4}{3}$", "audio_path": "audio/math_716b3f30-9486-42f5-bedc-beb8fb8e4d39.wav", "formula": "$\\frac{3}{4}{+}\\frac{1}{6}{+}\\frac{5}{12}=\\frac{4}{3}$", "answer": "四分之三加六分之一加十二分之五等于三分之四", "subset": "mixmath", "task_type": "tts"} +{"index": 1142, "question": "Please read the following math formula symbols: $Z=Z^\\lambda\\partial_{x^\\lambda}\\in\\mathbb{K}$", "audio_path": "audio/row_02062563_1755842074272903.wav", "formula": "$Z=Z^\\lambda\\partial_{x^\\lambda}\\in\\mathbb{K}$", "answer": "Z equals Z to the power of lambda times the partial derivative with respect to x lambda of the set of K.", "subset": "mixmath", "task_type": "tts"} +{"index": 1143, "question": "Please read the following math formula symbols: $\\{W_i^Q,W_i^K,W_i^V\\}$", "audio_path": "audio/row_00900246_1755695811172085.wav", "formula": "$\\{W_i^Q,W_i^K,W_i^V\\}$", "answer": "Open brace, W sub i superscript Q, comma, W sub i superscript K, comma, W sub i superscript V, close brace.", "subset": "mixmath", "task_type": "tts"} +{"index": 1144, "question": "Please read the following math formula symbols: $d^W_f=-eF_3(m_Z^2)$", "audio_path": "audio/row_00529635_1755649568399942.wav", "formula": "$d^W_f=-eF_3(m_Z^2)$", "answer": "d to the power of W sub f equals negative e F sub 3 open parenthesis m sub Z squared close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 1145, "question": "请你朗读以下数学公式符号:$10(1+20\\%)+5(1+40\\%)x=(10+5x)\\left( 1+\\frac{1}{3} \\right)$", "audio_path": "audio/math_5aaec1b7-5a10-4668-8812-81dbb342af29.wav", "formula": "$10(1+20\\%)+5(1+40\\%)x=(10+5x)\\left( 1+\\frac{1}{3} \\right)$", "answer": "十乘一加百分之二十的和 加 五乘一加百分之四十的和乘x 等于 十加五x的和乘一加三分之一的和", "subset": "mixmath", "task_type": "tts"} +{"index": 1146, "question": "请你朗读以下数学公式符号:$$\\left\\{\\begin{array}{c}4x+5y=24\\\\ 6x+7y=31\\end{array}\\right .$$", "audio_path": "audio/math_c5bd7256-0475-481b-bd60-995749879208.wav", "formula": "$$\\left\\{\\begin{array}{c}4x+5y=24\\\\ 6x+7y=31\\end{array}\\right .$$", "answer": "四x加五y等于二十四和六x加七y等于三十一", "subset": "mixmath", "task_type": "tts"} +{"index": 1147, "question": "Please read the following math formula symbols: $\\left(\\bigcup_{i=1}^{k-1}h_i\\right)\\caph_k=e$", "audio_path": "audio/row_01538358_1755775786912599.wav", "formula": "$\\left(\\bigcup_{i=1}^{k-1}h_i\\right)\\caph_k=e$", "answer": "Left parenthesis, the union from i equals 1 to k minus 1, h sub i, right parenthesis, intersection h sub k equals e.", "subset": "mixmath", "task_type": "tts"} +{"index": 1148, "question": "请你朗读以下数学公式符号:$$\\frac{1}{4}\\div \\left( \\frac{3}{2}+\\frac{1}{2} \\right)$$", "audio_path": "audio/math_97401cc2-2ed3-4731-838a-cf7b0a208ef8.wav", "formula": "$$\\frac{1}{4}\\div \\left( \\frac{3}{2}+\\frac{1}{2} \\right)$$", "answer": "四分之一除以二分之三加二分之一的和", "subset": "mixmath", "task_type": "tts"} +{"index": 1149, "question": "Please read the following math formula symbols: $F:[0,1]\\to\\mathbb{R}_{>0}$", "audio_path": "audio/row_00604519_1755658832869861.wav", "formula": "$F:[0,1]\\to\\mathbb{R}_{>0}$", "answer": "F, colon, open square bracket, 0, comma, 1, close square bracket, arrow, R with a greater than or equal to 0.", "subset": "mixmath", "task_type": "tts"} +{"index": 1150, "question": "请你朗读以下数学公式符号:$\\therefore {2}^{a+2b}={2}^{a}\\cdot {2}^{2b}={2}^{a}\\cdot {4}^{b}=3\\times 5=15$", "audio_path": "audio/math_a07f86f5-e80d-42e9-bfca-b0b02d9cee70.wav", "formula": "$\\therefore {2}^{a+2b}={2}^{a}\\cdot {2}^{2b}={2}^{a}\\cdot {4}^{b}=3\\times 5=15$", "answer": "所以,二的a加二b次方等于二的a次方乘二的二b次方等于二的a次方乘四的b次方等于三乘五等于十五", "subset": "mixmath", "task_type": "tts"} +{"index": 1151, "question": "Please read the following math formula symbols: $P_4+2P_4+5P_3+10P_3$", "audio_path": "audio/row_01274564_1755742618549353.wav", "formula": "$P_4+2P_4+5P_3+10P_3$", "answer": "P sub 4 plus 2 times P sub 4 plus 5 times P sub 3 plus 10 times P sub 3.", "subset": "mixmath", "task_type": "tts"} +{"index": 1152, "question": "请你朗读以下数学公式符号:$\\frac{5}{7}\\times \\left( 1\\div \\frac{10}{21} \\right)$", "audio_path": "audio/math_18dbf6e4-684a-4dbc-9095-083aa382a56b.wav", "formula": "$\\frac{5}{7}\\times \\left( 1\\div \\frac{10}{21} \\right)$", "answer": "七分之五乘一除以二十一分之十的商", "subset": "mixmath", "task_type": "tts"} +{"index": 1153, "question": "请你朗读以下数学公式符号:$$0.6=\\frac{6}{10}=\\frac{3}{5}=\\frac{15}{25}=\\frac{21}{35}=21:35$$", "audio_path": "audio/math_43efeaf2-f2ac-49ec-88df-0756b9ace481.wav", "formula": "$$0.6=\\frac{6}{10}=\\frac{3}{5}=\\frac{15}{25}=\\frac{21}{35}=21:35$$", "answer": "零点六等于十分之六等于五分之三等于二十五分之十五等于三十五分之二十一等于二十一比三十五", "subset": "mixmath", "task_type": "tts"} +{"index": 1154, "question": "请你朗读以下数学公式符号:$\\frac{1}{2}+\\frac{1}{4}+\\frac{1}{8}+\\frac{1}{16}+\\frac{1}{32}+\\frac{1}{64}=$", "audio_path": "audio/math_e433c64d-66c9-40b4-974d-1c25d3df8eea.wav", "formula": "$\\frac{1}{2}+\\frac{1}{4}+\\frac{1}{8}+\\frac{1}{16}+\\frac{1}{32}+\\frac{1}{64}=$", "answer": "二分之一加四分之一加八分之一加十六分之一加三十二分之一加六十四分之一等于", "subset": "mixmath", "task_type": "tts"} +{"index": 1155, "question": "请你朗读以下数学公式符号:$=\\left[ 8\\times \\left( \\frac{2}{5}+\\frac{3}{7}+\\frac{4}{9}+\\frac{5}{11} \\right) \\right]\\div \\left( \\frac{2}{5}+\\frac{3}{7}+\\frac{4}{9}+\\frac{5}{11} \\right)$", "audio_path": "audio/math_c4bb11ac-d630-4147-8e09-0af2af898341.wav", "formula": "$=\\left[ 8\\times \\left( \\frac{2}{5}+\\frac{3}{7}+\\frac{4}{9}+\\frac{5}{11} \\right) \\right]\\div \\left( \\frac{2}{5}+\\frac{3}{7}+\\frac{4}{9}+\\frac{5}{11} \\right)$", "answer": "等于八乘五分之二加七分之三加九分之四加十一分之五的和除以五分之二加七分之三加九分之四加十一分之五的和", "subset": "mixmath", "task_type": "tts"} +{"index": 1156, "question": "请你朗读以下数学公式符号:$=\\left( 60+\\frac{5}{3} \\right)\\div \\frac{5}{3}+\\left( 70+\\frac{7}{4} \\right)\\div \\frac{7}{4}+\\left( 90+\\frac{9}{5} \\right)\\div \\frac{9}{5}$", "audio_path": "audio/math_fba32dd3-ca78-4eca-89b5-b9c0c14dea53.wav", "formula": "$=\\left( 60+\\frac{5}{3} \\right)\\div \\frac{5}{3}+\\left( 70+\\frac{7}{4} \\right)\\div \\frac{7}{4}+\\left( 90+\\frac{9}{5} \\right)\\div \\frac{9}{5}$", "answer": "等于六十加三分之五的和除以三分之五,加七十加四分之七的和除以四分之七,加九十加五分之九的和除以五分之九", "subset": "mixmath", "task_type": "tts"} +{"index": 1157, "question": "请你朗读以下数学公式符号:$\\frac{5}{12}=\\frac{5\\times 2}{12\\times 2}=\\frac{10}{24}$", "audio_path": "audio/math_31b618f0-bf1b-4228-85e3-c12f4db345d8.wav", "formula": "$\\frac{5}{12}=\\frac{5\\times 2}{12\\times 2}=\\frac{10}{24}$", "answer": "十二分之五等于十二乘二的积 分之 五乘二的积 等于二十四分之十", "subset": "mixmath", "task_type": "tts"} +{"index": 1158, "question": "Please read the following math formula symbols: $$|\\lambda_2|\\le\\sqrt{d_1d_2}\\alpha.$$", "audio_path": "audio/row_01011175_1755709636076884.wav", "formula": "$$|\\lambda_2|\\le\\sqrt{d_1d_2}\\alpha.$$", "answer": "Absolute value of lambda sub 2 is less than or equal to the square root of d sub 1 times d sub 2 times alpha.", "subset": "mixmath", "task_type": "tts"} +{"index": 1159, "question": "Please read the following math formula symbols: $F_{X|\\barX}(T,x_{\\ell'+1},h_{m+1})$", "audio_path": "audio/row_02014108_1755835913131929.wav", "formula": "$F_{X|\\barX}(T,x_{\\ell'+1},h_{m+1})$", "answer": "F sub X bar X open parenthesis T, x sub ell prime plus 1, h sub m plus 1 close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 1160, "question": "Please read the following math formula symbols: $D=[\\lambdas^*(1-s^*)]^2/2=0.0002$", "audio_path": "audio/row_00698688_1755670540492646.wav", "formula": "$D=[\\lambdas^*(1-s^*)]^2/2=0.0002$", "answer": "D equals the quantity lambda times s star times the quantity 1 minus s star all squared divided by 2 equals 0.0002.", "subset": "mixmath", "task_type": "tts"} +{"index": 1161, "question": "请你朗读以下数学公式符号:${{a}^{b}}={{\\left( \\frac{1}{2} \\right)}^{3}}=\\frac{1}{8}$", "audio_path": "audio/math_77e1ac0b-7df0-4407-861a-70f7fe8b4beb.wav", "formula": "${{a}^{b}}={{\\left( \\frac{1}{2} \\right)}^{3}}=\\frac{1}{8}$", "answer": "a 的 b 次方等于二分之一的立方等于八分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 1162, "question": "Please read the following math formula symbols: $\\mu[u]=-\\mu[\\tilde{u}]=(1/\\sqrt2)\\HH^1\\restr\\Sigma$", "audio_path": "audio/row_01683894_1755794202760658.wav", "formula": "$\\mu[u]=-\\mu[\\tilde{u}]=(1/\\sqrt2)\\HH^1\\restr\\Sigma$", "answer": "mu of u equals negative mu of tilde u equals one over square root of two times HH to the power of one times Sigma.", "subset": "mixmath", "task_type": "tts"} +{"index": 1163, "question": "Please read the following math formula symbols: $\\bfv\\inW_0^{1,\\infty}(\\Omega)^d$", "audio_path": "audio/row_00622003_1755661061111802.wav", "formula": "$\\bfv\\inW_0^{1,\\infty}(\\Omega)^d$", "answer": "Bold v belongs to W sub 0 to the power of 1, infinity, open parenthesis Omega close parenthesis, to the power of d.", "subset": "mixmath", "task_type": "tts"} +{"index": 1164, "question": "请你朗读以下数学公式符号:$\\left\\{ \\begin{matrix} a=5 \\\\ b=4 \\\\ \\end{matrix} \\right.$", "audio_path": "audio/math_473ec777-9d62-4d73-9dd5-025e131d7235.wav", "formula": "$\\left\\{ \\begin{matrix} a=5 \\\\ b=4 \\\\ \\end{matrix} \\right.$", "answer": "a等于五,b等于四", "subset": "mixmath", "task_type": "tts"} +{"index": 1165, "question": "请你朗读以下数学公式符号:$\\left\\{ \\begin{array}{l} {3x+4y=38} \\\\ {4x+2y=44} \\end{array}\\right.$", "audio_path": "audio/math_485cda70-4c0c-41b5-9302-dddeee3bdd22.wav", "formula": "$\\left\\{ \\begin{array}{l} {3x+4y=38} \\\\ {4x+2y=44} \\end{array}\\right.$", "answer": "三x加四y等于三十八,四x加二y等于四十四", "subset": "mixmath", "task_type": "tts"} +{"index": 1166, "question": "请你朗读以下数学公式符号:$$90\\times \\frac{3}{10}+92\\times \\frac{3}{10}+86\\times \\frac{4}{10}=27+27.6+34.4=89$$", "audio_path": "audio/math_ffa06b5f-028c-42af-93ba-04d272b17c66.wav", "formula": "$$90\\times \\frac{3}{10}+92\\times \\frac{3}{10}+86\\times \\frac{4}{10}=27+27.6+34.4=89$$", "answer": "九十乘十分之三加九十二乘十分之三加八十六乘十分之四等于二十七加二十七点六加三十四点四等于八十九", "subset": "mixmath", "task_type": "tts"} +{"index": 1167, "question": "Please read the following math formula symbols: $\\Sigma_{K+1+i,K+1+i}=\\langle\\hat{p}_i^2\\rangle$", "audio_path": "audio/row_00826270_1755686497143583.wav", "formula": "$\\Sigma_{K+1+i,K+1+i}=\\langle\\hat{p}_i^2\\rangle$", "answer": "Sigma sub K plus 1 plus i, K plus 1 plus i equals the angle bracket p hat sub i squared angle bracket.", "subset": "mixmath", "task_type": "tts"} +{"index": 1168, "question": "Please read the following math formula symbols: $\\Tilde{\\phi_1},\\Tilde{\\phi_2}\\inC^{2,1}(M)$", "audio_path": "audio/row_01871263_1755817906739808.wav", "formula": "$\\Tilde{\\phi_1},\\Tilde{\\phi_2}\\inC^{2,1}(M)$", "answer": "The tilde phi sub 1, the tilde phi sub 2, belongs to the set of complex numbers raised to the power of 2,1 of M.", "subset": "mixmath", "task_type": "tts"} +{"index": 1169, "question": "请你朗读以下数学公式符号:$$\\frac{3}{2\\times 5}+\\frac{3}{5\\times 8}+\\frac{3}{8\\times 11}+\\frac{3}{11\\times 14}+\\frac{3}{14\\times 17}+\\frac{3}{17\\times 20}$$", "audio_path": "audio/math_7a585056-7295-4906-ba24-5021a8844e02.wav", "formula": "$$\\frac{3}{2\\times 5}+\\frac{3}{5\\times 8}+\\frac{3}{8\\times 11}+\\frac{3}{11\\times 14}+\\frac{3}{14\\times 17}+\\frac{3}{17\\times 20}$$", "answer": "二乘五的积分之三 加五乘八的积分之三 加八乘十一的积 分之三 加十一乘十四的积 分之三 加十四乘十七的积分之三 加十七乘二十的积分之三", "subset": "mixmath", "task_type": "tts"} +{"index": 1170, "question": "Please read the following math formula symbols: $5^4)^3=244140625$", "audio_path": "audio/row_01027497_1755711675230272.wav", "formula": "$5^4)^3=244140625$", "answer": "Five to the power of four, raised to the power of three, equals two point four four one six two five.", "subset": "mixmath", "task_type": "tts"} +{"index": 1171, "question": "请你朗读以下数学公式符号:$\\left\\{ \\begin{matrix}a=6 \\\\ b=3 \\\\\\end{matrix} \\right.$", "audio_path": "audio/math_146270ce-0722-42fb-923c-67c5f25f6017.wav", "formula": "$\\left\\{ \\begin{matrix}a=6 \\\\ b=3 \\\\\\end{matrix} \\right.$", "answer": "a等于六,b等于三", "subset": "mixmath", "task_type": "tts"} +{"index": 1172, "question": "Please read the following math formula symbols: $\\mathcalC_\\Delta^{(2)}\\leq\\algL^{\\Z_p^2}$", "audio_path": "audio/row_01660663_1755791279232196.wav", "formula": "$\\mathcalC_\\Delta^{(2)}\\leq\\algL^{\\Z_p^2}$", "answer": "C sub Delta to the power of 2 is less than or equal to alpha g L to the power of Z sub p squared.", "subset": "mixmath", "task_type": "tts"} +{"index": 1173, "question": "请你朗读以下数学公式符号:$AB + C = (a+2b) \\times 3b + ab = 3ab + 6b^2 + ab = 4ab + 6b^2$", "audio_path": "audio/math_7ee96299-3a47-4763-8d2c-576dc421bc2f.wav", "formula": "$AB + C = (a+2b) \\times 3b + ab = 3ab + 6b^2 + ab = 4ab + 6b^2$", "answer": "AB 加 C 等于 a 加二b的和乘三b 加 a乘b 等于 三乘a乘b 加六乘b的平方 加a乘b 等于 四乘a乘b 加六乘b的平方", "subset": "mixmath", "task_type": "tts"} +{"index": 1174, "question": "Please read the following math formula symbols: $\\ket{\\psi(0)}=\\f{1}{\\sqrt{2}}(\\ket{0}+\\ket{1})$", "audio_path": "audio/row_00374783_1755630603713829.wav", "formula": "$\\ket{\\psi(0)}=\\f{1}{\\sqrt{2}}(\\ket{0}+\\ket{1})$", "answer": "The ket psi of 0 is equal to one over the square root of 2, multiplied by the sum of ket 0 and ket 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 1175, "question": "请你朗读以下数学公式符号:$8000\\times 2\\times 3.75\\%=16000\\times 3.75\\%=600$", "audio_path": "audio/math_f98db56e-a757-4246-ada9-933b6d653a4f.wav", "formula": "$8000\\times 2\\times 3.75\\%=16000\\times 3.75\\%=600$", "answer": "八千乘二乘百分之三点七五等于一万六千乘百分之三点七五等于六百", "subset": "mixmath", "task_type": "tts"} +{"index": 1176, "question": "Please read the following math formula symbols: $D_{i_{1}}'90{}^\\circ$", "audio_path": "audio/math_bdf5e93d-d84a-4ff5-afe3-839d6dd3dfbb.wav", "formula": "$\\angle A=6\\times \\frac{180}{11}{}^\\circ >90{}^\\circ$", "answer": "角A等于六乘十一分之一百八十度,大于九十度", "subset": "mixmath", "task_type": "tts"} +{"index": 1207, "question": "请你朗读以下数学公式符号:$\\sqrt{5\\pm 2\\sqrt{6}}=\\sqrt{{{\\left( \\sqrt{3} \\right)}^{2}}\\pm 2\\sqrt{3}\\times \\sqrt{2}+{{\\left( \\sqrt{2} \\right)}^{2}}}$", "audio_path": "audio/math_1123e6fd-fdef-452f-b096-e4baac76633a.wav", "formula": "$\\sqrt{5\\pm 2\\sqrt{6}}=\\sqrt{{{\\left( \\sqrt{3} \\right)}^{2}}\\pm 2\\sqrt{3}\\times \\sqrt{2}+{{\\left( \\sqrt{2} \\right)}^{2}}}$", "answer": "根号下五加减二倍的根号六等于根号下根号三的平方加减二倍的根号三乘根号二加根号二的平方", "subset": "mixmath", "task_type": "tts"} +{"index": 1208, "question": "请你朗读以下数学公式符号:$125\\times 25\\times 8=125\\times 8\\times 25=1000\\times 25=25000$", "audio_path": "audio/math_7c82de6a-40ed-4a5c-a7d0-0fb431f1c27b.wav", "formula": "$125\\times 25\\times 8=125\\times 8\\times 25=1000\\times 25=25000$", "answer": "一百二十五乘二十五乘八等于一百二十五乘八乘二十五等于一千乘二十五等于两万五千", "subset": "mixmath", "task_type": "tts"} +{"index": 1209, "question": "Please read the following math formula symbols: $v\\in\\mathrm{D}_2(D_\\mathfrak{t},\\mathbb{R}^n_+,\\Lambda)$", "audio_path": "audio/row_00703086_1755671107382730.wav", "formula": "$v\\in\\mathrm{D}_2(D_\\mathfrak{t},\\mathbb{R}^n_+,\\Lambda)$", "answer": "v belongs to the set of D sub 2, where D sub t, R to the power of n plus, Lambda.", "subset": "mixmath", "task_type": "tts"} +{"index": 1210, "question": "请你朗读以下数学公式符号:$\\left( 3\\times 5+3\\times 5+3\\times 3\\right)\\times 2=78$", "audio_path": "audio/math_c2840bda-d0ce-4d0f-9e6a-fb45ad76652e.wav", "formula": "$\\left( 3\\times 5+3\\times 5+3\\times 3\\right)\\times 2=78$", "answer": "三乘五加三乘五加三乘三的和乘二等于七十八", "subset": "mixmath", "task_type": "tts"} +{"index": 1211, "question": "Please read the following math formula symbols: $Y=|\\mcO_{\\bbP^1}(-1)\\oplus\\mcO_{\\bbP^1}(-1)|$", "audio_path": "audio/row_01662269_1755791476301257.wav", "formula": "$Y=|\\mcO_{\\bbP^1}(-1)\\oplus\\mcO_{\\bbP^1}(-1)|$", "answer": "Y equals the absolute value of m c O sub b P one negative one direct sum m c O sub b P one negative one.", "subset": "mixmath", "task_type": "tts"} +{"index": 1212, "question": "请你朗读以下数学公式符号:$\\begin{cases} a\\ne 1,7 \\\\ c\\ne 1,7 \\end{cases}\\Rightarrow a,c$", "audio_path": "audio/math_6f439768-6a29-4875-9eee-7790aad0123d.wav", "formula": "$\\begin{cases} a\\ne 1,7 \\\\ c\\ne 1,7 \\end{cases}\\Rightarrow a,c$", "answer": "a不等于一,七,c不等于一,七,推出a,c", "subset": "mixmath", "task_type": "tts"} +{"index": 1213, "question": "Please read the following math formula symbols: $2^{N_{\\code}h(N_{\\ph}^{\\U{U}}/N_{\\code})}$", "audio_path": "audio/row_00400740_1755633787233613.wav", "formula": "$2^{N_{\\code}h(N_{\\ph}^{\\U{U}}/N_{\\code})}$", "answer": "Two to the power of N sub code times h of N sub phi to the power of U sub U divided by N sub code.", "subset": "mixmath", "task_type": "tts"} +{"index": 1214, "question": "Please read the following math formula symbols: $|\\vec{E}|\\propto1/\\sqrt{\\omega_rV_{\\rm{PPC}}}$", "audio_path": "audio/row_01915417_1755823489277874.wav", "formula": "$|\\vec{E}|\\propto1/\\sqrt{\\omega_rV_{\\rm{PPC}}}$", "answer": "Absolute value of vector E is proportional to one divided by the square root of omega sub r times V sub PPC.", "subset": "mixmath", "task_type": "tts"} +{"index": 1215, "question": "请你朗读以下数学公式符号:$2A=\\frac{1111110}{2222221}\\times 2=\\frac{2222220}{2222221}$", "audio_path": "audio/math_0660866c-9d57-4b16-9cce-e5e772a12e5b.wav", "formula": "$2A=\\frac{1111110}{2222221}\\times 2=\\frac{2222220}{2222221}$", "answer": "二 A 等于 二百二十二万两千二百二十一分之一百一十一万一千一百一十乘二 等于 二百二十二万两千二百二十一分之二百二十二万两千二百二十", "subset": "mixmath", "task_type": "tts"} +{"index": 1216, "question": "请你朗读以下数学公式符号:$\\left\\{\\begin{array}{c}x=12\\\\ y=18\\end{array}\\right.$", "audio_path": "audio/math_05b811f3-4627-4ecf-9b9c-c9940a3240b7.wav", "formula": "$\\left\\{\\begin{array}{c}x=12\\\\ y=18\\end{array}\\right.$", "answer": "x等于十二,y等于十八", "subset": "mixmath", "task_type": "tts"} +{"index": 1217, "question": "请你朗读以下数学公式符号:$\\left\\{\\begin{array}{c}x=150\\\\ y=50\\end{array}\\right.$", "audio_path": "audio/math_3cfd5df6-84f2-4286-97ed-7285334e54b4.wav", "formula": "$\\left\\{\\begin{array}{c}x=150\\\\ y=50\\end{array}\\right.$", "answer": "x 等于 一百五十和y 等于 五十", "subset": "mixmath", "task_type": "tts"} +{"index": 1218, "question": "Please read the following math formula symbols: $g\\colon[0,1]^m\\to\\ensuremath\\{\\mathbb\\{R$", "audio_path": "audio/row_00201677_1755609534688465.wav", "formula": "$g\\colon[0,1]^m\\to\\ensuremath\\{\\mathbb\\{R$", "answer": "g maps the closed interval from 0 to 1 raised to the power of m to the set of real numbers.", "subset": "mixmath", "task_type": "tts"} +{"index": 1219, "question": "Please read the following math formula symbols: $\\{\\mathcal{I}^{B}_{c_B|y}\\}_{c_B\\in\\{0,1\\}}$", "audio_path": "audio/row_02085862_1755845017527905.wav", "formula": "$\\{\\mathcal{I}^{B}_{c_B|y}\\}_{c_B\\in\\{0,1\\}}$", "answer": "The set of I superscript B subscript c sub B given y, subscript c sub B in the set containing 0 and 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 1220, "question": "请你朗读以下数学公式符号:$$=\\sum\\limits_{k=1}^{20}{\\left( \\dfrac{2k+1}{{{k}^{2}}{{\\left( k+1 \\right)}^{2}}} \\right)}$$", "audio_path": "audio/math_1324faba-30dc-41f5-84fc-64366f0f0cb4.wav", "formula": "$$=\\sum\\limits_{k=1}^{20}{\\left( \\dfrac{2k+1}{{{k}^{2}}{{\\left( k+1 \\right)}^{2}}} \\right)}$$", "answer": "等于从k等于一到二十,对k平方乘k加一的和的平方 分之 二k加一 求和", "subset": "mixmath", "task_type": "tts"} +{"index": 1221, "question": "Please read the following math formula symbols: $\\bsgamma=(\\gamma_{\\fraku})_{\\fraku\\subseteq\\{1:s\\}}$", "audio_path": "audio/row_00139841_1755602022019121.wav", "formula": "$\\bsgamma=(\\gamma_{\\fraku})_{\\fraku\\subseteq\\{1:s\\}}$", "answer": "Gamma equals open parenthesis gamma sub u close parenthesis sub u subset equal to open brace one colon s close brace.", "subset": "mixmath", "task_type": "tts"} +{"index": 1222, "question": "请你朗读以下数学公式符号:$\\left( 6\\times 4+6\\times 2+4\\times 2 \\right)\\times 2=88$", "audio_path": "audio/math_10713168-d7d9-4652-b647-c8c57c8dfaca.wav", "formula": "$\\left( 6\\times 4+6\\times 2+4\\times 2 \\right)\\times 2=88$", "answer": "六乘四加六乘二加四乘二的和乘二等于八十八", "subset": "mixmath", "task_type": "tts"} +{"index": 1223, "question": "Please read the following math formula symbols: $0.65\\lesssim\\ecc\\lesssim0.85$", "audio_path": "audio/row_00740322_1755675715816261.wav", "formula": "$0.65\\lesssim\\ecc\\lesssim0.85$", "answer": "zero point six five less than or equal to e c c less than or equal to zero point eight five.", "subset": "mixmath", "task_type": "tts"} +{"index": 1224, "question": "Please read the following math formula symbols: $T_{1/2}^{(1)\\dagger}\\bar{D}S_{1/2i}^{(0)}$", "audio_path": "audio/row_00136538_1755601618618868.wav", "formula": "$T_{1/2}^{(1)\\dagger}\\bar{D}S_{1/2i}^{(0)}$", "answer": "T half to the power of one dagger times the conjugate of D times S half i to the power of zero.", "subset": "mixmath", "task_type": "tts"} +{"index": 1225, "question": "Please read the following math formula symbols: ${\\rmPSH}(X,\\omega)\\subsetL^q(\\omega^n)$", "audio_path": "audio/row_00773555_1755679878185744.wav", "formula": "${\\rmPSH}(X,\\omega)\\subsetL^q(\\omega^n)$", "answer": "PSH of X, omega, is a subset of L to the power of q of omega to the power of n.", "subset": "mixmath", "task_type": "tts"} +{"index": 1226, "question": "请你朗读以下数学公式符号:$=\\frac{1}{9}\\times 45+\\frac{4}{15} \\times 45+\\frac{3}{25}\\times45$", "audio_path": "audio/math_47305c95-102e-438a-9f10-4e8bb22bbcaa.wav", "formula": "$=\\frac{1}{9}\\times 45+\\frac{4}{15} \\times 45+\\frac{3}{25}\\times45$", "answer": "等于九分之一乘四十五加十五分之四乘四十五加二十五分之三乘四十五", "subset": "mixmath", "task_type": "tts"} +{"index": 1227, "question": "Please read the following math formula symbols: $O((\\sqrt[9]{720})^n)\\approxO(2.077^n)$", "audio_path": "audio/row_01816919_1755811029614028.wav", "formula": "$O((\\sqrt[9]{720})^n)\\approxO(2.077^n)$", "answer": "O of the square root of 9 times 720 raised to the power of n is approximately O of 2.077 raised to the power of n.", "subset": "mixmath", "task_type": "tts"} +{"index": 1228, "question": "请你朗读以下数学公式符号:$$\\begin{eqnarray}\n&=&5.4\\times 20\\\\\n&=&108.\n\\end{eqnarray}$$", "audio_path": "audio/math_963b244a-f797-42e8-8e29-05c6829b3d81.wav", "formula": "$$\\begin{eqnarray}\n&=&5.4\\times 20\\\\\n&=&108.\n\\end{eqnarray}$$", "answer": "等于五点四乘二十,等于一百零八。", "subset": "mixmath", "task_type": "tts"} +{"index": 1229, "question": "Please read the following math formula symbols: $a_k=\\eta\\frac{C_k^3L_k^3}{T_k^2}$", "audio_path": "audio/row_01848673_1755815036175288.wav", "formula": "$a_k=\\eta\\frac{C_k^3L_k^3}{T_k^2}$", "answer": "a sub k equals eta times C sub k cubed times L sub k cubed divided by T sub k squared.", "subset": "mixmath", "task_type": "tts"} +{"index": 1230, "question": "Please read the following math formula symbols: $R_{\\mu\\nu}-Rg_{\\mu\\nu}/2=\\{M_\\text\\{PlT_{\\mu\\nu}\\,$", "audio_path": "audio/row_00075095_1755594191181805.wav", "formula": "$R_{\\mu\\nu}-Rg_{\\mu\\nu}/2=\\{M_\\text\\{PlT_{\\mu\\nu}\\,$", "answer": "R sub mu nu minus R g sub mu nu divided by 2 equals M sub Pl T sub mu nu.", "subset": "mixmath", "task_type": "tts"} +{"index": 1231, "question": "请你朗读以下数学公式符号:$${{(125)}_{8}}=1\\times {{8}^{2}}+2\\times 8+5=64+16+5={{(85)}_{10}}={{(1010101)}_{2}}$$", "audio_path": "audio/math_daf53c06-e6fd-4ea3-99ab-ec5f9d5af387.wav", "formula": "$${{(125)}_{8}}=1\\times {{8}^{2}}+2\\times 8+5=64+16+5={{(85)}_{10}}={{(1010101)}_{2}}$$", "answer": "八进制 一二五 等于一乘 八的平方加二乘八 加五等于六十四加十六加五等于十进制 八十五 等于二进制 一零一零一零一", "subset": "mixmath", "task_type": "tts"} +{"index": 1232, "question": "Please read the following math formula symbols: $f_n(t_1),\\ldots,f_n(t_m)$", "audio_path": "audio/row_01828401_1755812485258681.wav", "formula": "$f_n(t_1),\\ldots,f_n(t_m)$", "answer": "f sub n open parenthesis t sub 1 close parenthesis, ellipsis, f sub n open parenthesis t sub m close parenthesis", "subset": "mixmath", "task_type": "tts"} +{"index": 1233, "question": "Please read the following math formula symbols: $\\rvg_i,\\rvh_i\\in\\mathbb{R}^{n-1}$", "audio_path": "audio/row_00045010_1755590563058289.wav", "formula": "$\\rvg_i,\\rvh_i\\in\\mathbb{R}^{n-1}$", "answer": "g sub i, h sub i, belong to the set of real numbers raised to the power of n minus 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 1234, "question": "请你朗读以下数学公式符号:$\\begin{eqnarray}&&36\\times 111+888\\times 8\\\\ &=&36\\times 111+111\\times 8\\times 8\\\\ &=&36\\times 111+111\\times 64\\\\ &=&111\\times \\left( 36+64 \\right)\\\\ &=&111\\times 100\\\\ &=&11100\\end{eqnarray}$", "audio_path": "audio/math_9331e9fc-512c-4734-ae37-760d681ebafd.wav", "formula": "$\\begin{eqnarray}&&36\\times 111+888\\times 8\\\\ &=&36\\times 111+111\\times 8\\times 8\\\\ &=&36\\times 111+111\\times 64\\\\ &=&111\\times \\left( 36+64 \\right)\\\\ &=&111\\times 100\\\\ &=&11100\\end{eqnarray}$", "answer": "三十六乘一百一十一加八百八十八乘八等于三十六乘一百一十一加一百一十一乘八乘八等于三十六乘一百一十一加一百一十一乘六十四等于一百一十一乘三十六加六十四的和等于一百一十一乘一百等于一万一千一百", "subset": "mixmath", "task_type": "tts"} +{"index": 1235, "question": "Please read the following math formula symbols: $|\\mathcal{E}|\\geq9q^{d/2}$", "audio_path": "audio/row_00515734_1755647866913637.wav", "formula": "$|\\mathcal{E}|\\geq9q^{d/2}$", "answer": "Absolute value of E is greater than or equal to 9 times q to the power of d divided by 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 1236, "question": "Please read the following math formula symbols: $\\sqrt{\\half\\rhoc|\\boldvc-\\boldvn|^2/E}\\approx1$", "audio_path": "audio/row_01167111_1755729125143181.wav", "formula": "$\\sqrt{\\half\\rhoc|\\boldvc-\\boldvn|^2/E}\\approx1$", "answer": "Square root of half rho c times the absolute value of v c minus v n squared divided by E is approximately equal to 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 1237, "question": "请你朗读以下数学公式符号:$\\frac{4}{5}\\times \\frac{5}{16}+\\frac{2}{15}\\times \\frac{5}{16}$", "audio_path": "audio/math_80e4f5d8-7352-4286-bdc8-4cbdb3f777e6.wav", "formula": "$\\frac{4}{5}\\times \\frac{5}{16}+\\frac{2}{15}\\times \\frac{5}{16}$", "answer": "五分之四乘十六分之五加十五分之二乘十六分之五", "subset": "mixmath", "task_type": "tts"} +{"index": 1238, "question": "Please read the following math formula symbols: $T_i(z)\\ciC_i(z)\\mid\\{Z_i,S_i,X_i\\}$", "audio_path": "audio/row_00304057_1755621994059940.wav", "formula": "$T_i(z)\\ciC_i(z)\\mid\\{Z_i,S_i,X_i\\}$", "answer": "T sub i of z is independent of C sub i of z given Z sub i, S sub i, X sub i.", "subset": "mixmath", "task_type": "tts"} +{"index": 1239, "question": "Please read the following math formula symbols: $f_{(z,k)}\\in\\CI(\\paM;F|_{\\paM})$", "audio_path": "audio/row_00678464_1755668030974394.wav", "formula": "$f_{(z,k)}\\in\\CI(\\paM;F|_{\\paM})$", "answer": "f sub z comma k belongs to CI open parenthesis P M semicolon F vertical bar sub P M close parenthesis", "subset": "mixmath", "task_type": "tts"} +{"index": 1240, "question": "Please read the following math formula symbols: $s_1=t_1,s_2=t_2,\\ldots,s_m=t_m$", "audio_path": "audio/row_00018339_1755587331490506.wav", "formula": "$s_1=t_1,s_2=t_2,\\ldots,s_m=t_m$", "answer": "s sub 1 equals t sub 1, s sub 2 equals t sub 2, dot dot dot, s sub m equals t sub m.", "subset": "mixmath", "task_type": "tts"} +{"index": 1241, "question": "Please read the following math formula symbols: $\\wt{D}_{p,p}(\\delta)\\lsm_{p,\\vep}\\delta^{-\\vep}$", "audio_path": "audio/row_00737276_1755675334859470.wav", "formula": "$\\wt{D}_{p,p}(\\delta)\\lsm_{p,\\vep}\\delta^{-\\vep}$", "answer": "wt D sub p comma p open parenthesis delta close parenthesis lsm sub p comma vep delta to the power of negative vep", "subset": "mixmath", "task_type": "tts"} +{"index": 1242, "question": "请你朗读以下数学公式符号:$$3.2\\times 0.125=0.4\\times \\left( 8\\times 0.125 \\right)$$", "audio_path": "audio/math_5924989b-6ce7-45f2-98d3-cd90533ac65f.wav", "formula": "$$3.2\\times 0.125=0.4\\times \\left( 8\\times 0.125 \\right)$$", "answer": "三点二乘零点一二五等于零点四乘八与零点一二五的积", "subset": "mixmath", "task_type": "tts"} +{"index": 1243, "question": "Please read the following math formula symbols: $P\\left(y_{i}\\right)=1=\\frac{1}{1+e^{-a_{i}^{T}x^0}}$", "audio_path": "audio/row_00148420_1755603046199799.wav", "formula": "$P\\left(y_{i}\\right)=1=\\frac{1}{1+e^{-a_{i}^{T}x^0}}$", "answer": "P of y sub i equals 1 equals one divided by one plus e to the power of negative a sub i transpose x superscript 0.", "subset": "mixmath", "task_type": "tts"} +{"index": 1244, "question": "Please read the following math formula symbols: $\\phi^{iq}(s)\\preceq\\phi^{iq}(y)=y$", "audio_path": "audio/row_01233549_1755737480439855.wav", "formula": "$\\phi^{iq}(s)\\preceq\\phi^{iq}(y)=y$", "answer": "Phi to the power of i q of s is a precececece phi to the power of i q of y equals y.", "subset": "mixmath", "task_type": "tts"} +{"index": 1245, "question": "请你朗读以下数学公式符号:$\\frac{3}{4}, \\frac{2}{6}, \\frac{3}{6}, \\frac{2}{10}, \\frac{4}{12}, \\frac{5}{15}, \\frac{3}{21}, \\frac{30}{60}, \\frac{45}{60}$", "audio_path": "audio/math_3d966f28-d4dc-431b-87eb-cd491fb37dc3.wav", "formula": "$\\frac{3}{4}, \\frac{2}{6}, \\frac{3}{6}, \\frac{2}{10}, \\frac{4}{12}, \\frac{5}{15}, \\frac{3}{21}, \\frac{30}{60}, \\frac{45}{60}$", "answer": "四分之三,六分之二,六分之三,十分之二,十二分之四,十五分之五,二十一分之三,六十分之三十,六十分之四十五", "subset": "mixmath", "task_type": "tts"} +{"index": 1246, "question": "Please read the following math formula symbols: $h_i=\\tilde{\\tau}^ih\\tilde{\\tau}^{-i}\\in\\cH$", "audio_path": "audio/row_01468816_1755767007319017.wav", "formula": "$h_i=\\tilde{\\tau}^ih\\tilde{\\tau}^{-i}\\in\\cH$", "answer": "h sub i equals tau tilde to the power of i h tau tilde to the power of negative i in c H", "subset": "mixmath", "task_type": "tts"} +{"index": 1247, "question": "Please read the following math formula symbols: $\\sum_{\\omega\\in\\{0,1\\}^k}\\tildef_\\omega\\circ\\pi_\\omega$", "audio_path": "audio/row_00744581_1755676268327424.wav", "formula": "$\\sum_{\\omega\\in\\{0,1\\}^k}\\tildef_\\omega\\circ\\pi_\\omega$", "answer": "Sum over omega in the set of 0, 1 to the power of k, tilde f sub omega circle pi sub omega.", "subset": "mixmath", "task_type": "tts"} +{"index": 1248, "question": "请你朗读以下数学公式符号:$= \\left( \\frac{7}{13} - \\frac{7}{13} \\right) + \\left( \\frac{5}{14} + \\frac{5}{14} \\right)$", "audio_path": "audio/math_9284c87f-e546-4549-a86e-fd14fae4a8c1.wav", "formula": "$= \\left( \\frac{7}{13} - \\frac{7}{13} \\right) + \\left( \\frac{5}{14} + \\frac{5}{14} \\right)$", "answer": "等于十三分之七减十三分之七的差加十四分之五加十四分之五的和", "subset": "mixmath", "task_type": "tts"} +{"index": 1249, "question": "请你朗读以下数学公式符号:${{5}^{4}}\\times {{7}^{6}}\\times {{5}^{6}}\\times {{7}^{4}}={{5}^{10}}\\times {{7}^{10}}={{35}^{10}}$", "audio_path": "audio/math_f5aa9b81-1d5b-464e-bdc3-c86ae3135fe9.wav", "formula": "${{5}^{4}}\\times {{7}^{6}}\\times {{5}^{6}}\\times {{7}^{4}}={{5}^{10}}\\times {{7}^{10}}={{35}^{10}}$", "answer": "五的四次方乘七的六次方乘五的六次方乘七的四次方等于五的十次方乘七的十次方等于三十五的十次方", "subset": "mixmath", "task_type": "tts"} +{"index": 1250, "question": "Please read the following math formula symbols: $\\boldsymbol{u}\\inC_t(W^{1,q}_x\\capL^{p'}_x)$", "audio_path": "audio/row_01436651_1755762955501540.wav", "formula": "$\\boldsymbol{u}\\inC_t(W^{1,q}_x\\capL^{p'}_x)$", "answer": "Bold u belongs to C sub t of W superscript 1, q subscript x intersection L superscript p prime subscript x.", "subset": "mixmath", "task_type": "tts"} +{"index": 1251, "question": "Please read the following math formula symbols: $\\rho\\leqw(C^{\\rho})/2$", "audio_path": "audio/row_01953848_1755828346329345.wav", "formula": "$\\rho\\leqw(C^{\\rho})/2$", "answer": "Rho is less than or equal to w times the quantity C raised to the power of rho, divided by 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 1252, "question": "请你朗读以下数学公式符号:$$ \\frac{5}{9}+ \\frac{11}{8}+ \\frac{5}{8}+ \\frac{4}{9}$$", "audio_path": "audio/math_c851925c-f235-4202-ab2d-3036aa75f25d.wav", "formula": "$$ \\frac{5}{9}+ \\frac{11}{8}+ \\frac{5}{8}+ \\frac{4}{9}$$", "answer": "九分之五加八分之十一加八分之五加九分之四", "subset": "mixmath", "task_type": "tts"} +{"index": 1253, "question": "请你朗读以下数学公式符号:$$\\frac{12345678987654321}{999999999\\times 999999999}=\\frac{1}{9\\times 9}=\\frac{1}{81}$$", "audio_path": "audio/math_e7ce67dc-510c-459f-9bdd-62896df178b1.wav", "formula": "$$\\frac{12345678987654321}{999999999\\times 999999999}=\\frac{1}{9\\times 9}=\\frac{1}{81}$$", "answer": "九亿九千九百九十九万九千九百九十九乘九亿九千九百九十九万九千九百九十九的积分之一万二千三百四十五万亿,六千七百八十九亿,八千七百六十五万,四千三百二十一等于九乘九的积分之一等于八十一分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 1254, "question": "Please read the following math formula symbols: $a\\in\\mathcalC^{\\infty}_c(T^*\\mathbbT^d)$", "audio_path": "audio/row_00895624_1755695231237310.wav", "formula": "$a\\in\\mathcalC^{\\infty}_c(T^*\\mathbbT^d)$", "answer": "a belongs to the set of infinity sub c, open parenthesis, T star, T to the power of d, close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 1255, "question": "请你朗读以下数学公式符号:$\\frac{5}{9}\\times 47\\%+47\\%\\times \\frac{4}{9}=47\\%$", "audio_path": "audio/math_be9dbecd-ff81-4e74-9752-a137e676279c.wav", "formula": "$\\frac{5}{9}\\times 47\\%+47\\%\\times \\frac{4}{9}=47\\%$", "answer": "九分之五乘百分之四十七加百分之四十七乘九分之四等于百分之四十七", "subset": "mixmath", "task_type": "tts"} +{"index": 1256, "question": "请你朗读以下数学公式符号:$$=\\left(1+3+5+7\\right)+\\left(\\frac{1}{2 \\times 4}+ \\frac{1}{3 \\times 5}+ \\frac{1}{4 \\times 6}+ \\frac{1}{5 \\times 7}\\right)$$", "audio_path": "audio/math_6883f559-30a1-4673-99ff-674fd175aaf1.wav", "formula": "$$=\\left(1+3+5+7\\right)+\\left(\\frac{1}{2 \\times 4}+ \\frac{1}{3 \\times 5}+ \\frac{1}{4 \\times 6}+ \\frac{1}{5 \\times 7}\\right)$$", "answer": "等于一加三加五加七的和 加二乘四的积分之一加三乘五的积分之一加四乘六的积分之一加五乘七的积分之一的和", "subset": "mixmath", "task_type": "tts"} +{"index": 1257, "question": "Please read the following math formula symbols: $\\bm{g}_{\\bm{k}}=(\\sink_y,-\\sink_x,0)$", "audio_path": "audio/row_01447299_1755764287605970.wav", "formula": "$\\bm{g}_{\\bm{k}}=(\\sink_y,-\\sink_x,0)$", "answer": "Bold g sub bold k equals open parenthesis sine k sub y comma negative sine k sub x comma zero close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 1258, "question": "Please read the following math formula symbols: $X^t_a=(y_a^t)^{-1}\\cdotX_a$", "audio_path": "audio/row_01634596_1755787979317526.wav", "formula": "$X^t_a=(y_a^t)^{-1}\\cdotX_a$", "answer": "X sub a equals the inverse of y sub a raised to the power of t, multiplied by X sub a.", "subset": "mixmath", "task_type": "tts"} +{"index": 1259, "question": "Please read the following math formula symbols: $=\\frac{1}{R^3}\\partial_z\\Omega^2R^4$", "audio_path": "audio/row_01027356_1755711661467783.wav", "formula": "$=\\frac{1}{R^3}\\partial_z\\Omega^2R^4$", "answer": "Equals one over R cubed times the partial derivative with respect to z of Omega squared times R to the power of four.", "subset": "mixmath", "task_type": "tts"} +{"index": 1260, "question": "Please read the following math formula symbols: $x+\\ell_2e_v\\in\\partialB_\\rho(z_0)\\setminus\\Gamma$", "audio_path": "audio/row_01342612_1755751090928209.wav", "formula": "$x+\\ell_2e_v\\in\\partialB_\\rho(z_0)\\setminus\\Gamma$", "answer": "x plus ell sub 2 e sub v belongs to the boundary of B sub rho of z sub 0, set minus Gamma.", "subset": "mixmath", "task_type": "tts"} +{"index": 1261, "question": "Please read the following math formula symbols: $\\ysf^{(i)}=[\\ysf_1,\\dots,\\ysf_i]$", "audio_path": "audio/row_00888712_1755694354480754.wav", "formula": "$\\ysf^{(i)}=[\\ysf_1,\\dots,\\ysf_i]$", "answer": "y s f raised to the power of i equals the commutator of y s f sub 1 through y s f sub i.", "subset": "mixmath", "task_type": "tts"} +{"index": 1262, "question": "Please read the following math formula symbols: $\\Delta^n\\varphi\\inL^\\infty(\\ZZ_n^2,e(l))$", "audio_path": "audio/row_01651098_1755790064535503.wav", "formula": "$\\Delta^n\\varphi\\inL^\\infty(\\ZZ_n^2,e(l))$", "answer": "Delta to the power of n times phi belongs to L infinity of Z Z sub n squared, e of l.", "subset": "mixmath", "task_type": "tts"} +{"index": 1263, "question": "请你朗读以下数学公式符号:$8736\\div 42=8736\\div \\left( 21\\times 2 \\right)=8736\\div 21\\div 2$", "audio_path": "audio/math_e3a1bf70-e3da-4be7-9fc8-e631f4a511a6.wav", "formula": "$8736\\div 42=8736\\div \\left( 21\\times 2 \\right)=8736\\div 21\\div 2$", "answer": "八千七百三十六除以四十二等于八千七百三十六除以二十一乘二的积等于八千七百三十六除以二十一再除以二", "subset": "mixmath", "task_type": "tts"} +{"index": 1264, "question": "请你朗读以下数学公式符号:$=\\frac{1}{3}\\times 99\\times 100\\times 101=333300$", "audio_path": "audio/math_e9910923-06d7-4444-af38-c27482d6bfe8.wav", "formula": "$=\\frac{1}{3}\\times 99\\times 100\\times 101=333300$", "answer": "等于三分之一乘九十九乘一百乘一百零一,等于三十三万三千三百", "subset": "mixmath", "task_type": "tts"} +{"index": 1265, "question": "请你朗读以下数学公式符号:${{\\left( \\alpha +\\beta \\right)}^{2}}={{\\alpha }^{2}}+{{\\beta }^{2}}+2\\alpha \\beta =3+2\\alpha \\beta ={{2}^{2}}$", "audio_path": "audio/math_5f15983b-82e3-43db-97e4-68b347df8a63.wav", "formula": "${{\\left( \\alpha +\\beta \\right)}^{2}}={{\\alpha }^{2}}+{{\\beta }^{2}}+2\\alpha \\beta =3+2\\alpha \\beta ={{2}^{2}}$", "answer": "alpha加beta的和的平方等于alpha的平方加beta的平方加二alpha beta等于三加二alpha beta等于二的平方", "subset": "mixmath", "task_type": "tts"} +{"index": 1266, "question": "请你朗读以下数学公式符号:$\\frac{1}{a}+\\frac{1}{a+1}=1 \\Rightarrow a=\\frac{1 \\pm \\sqrt{5}}{2}$", "audio_path": "audio/math_5d818b6e-1d5e-4d1c-ade7-ece4ed549db7.wav", "formula": "$\\frac{1}{a}+\\frac{1}{a+1}=1 \\Rightarrow a=\\frac{1 \\pm \\sqrt{5}}{2}$", "answer": "a分之一加a加一的和分之一等于一,推导出a等于二分之一加减根号五", "subset": "mixmath", "task_type": "tts"} +{"index": 1267, "question": "请你朗读以下数学公式符号:$$\\because \\tan 10^\\circ +\\tan 50^\\circ +\\sqrt{3}\\tan 10^\\circ \\tan 50^\\circ$$", "audio_path": "audio/math_828abadc-d2e1-4857-851b-2a3fbdbaebcf.wav", "formula": "$$\\because \\tan 10^\\circ +\\tan 50^\\circ +\\sqrt{3}\\tan 10^\\circ \\tan 50^\\circ$$", "answer": "因为 tangent 十度 加 tangent 五十度 加 根号三倍的 tangent 十度 乘 tangent 五十度", "subset": "mixmath", "task_type": "tts"} +{"index": 1268, "question": "Please read the following math formula symbols: $\\Delta\\leqc_{d,3}n^{-1/d}$", "audio_path": "audio/row_00460171_1755641054092705.wav", "formula": "$\\Delta\\leqc_{d,3}n^{-1/d}$", "answer": "Delta is less than or equal to c sub d comma 3 times n to the power of negative 1 over d.", "subset": "mixmath", "task_type": "tts"} +{"index": 1269, "question": "请你朗读以下数学公式符号:${{x}^{2}}+\\left( a+6 \\right)x+6a={{x}^{2}}+8x+12$", "audio_path": "audio/math_1e2f09c7-2ae7-4676-8acb-d9fa6422f2c5.wav", "formula": "${{x}^{2}}+\\left( a+6 \\right)x+6a={{x}^{2}}+8x+12$", "answer": "x的平方,加a加六的和乘x,加六a等于x的平方加八x加十二", "subset": "mixmath", "task_type": "tts"} +{"index": 1270, "question": "Please read the following math formula symbols: $0<|J\\capI_{i_1}\\capI_{i_2}|<\\varepsilon$", "audio_path": "audio/row_00434125_1755637856179845.wav", "formula": "$0<|J\\capI_{i_1}\\capI_{i_2}|<\\varepsilon$", "answer": "0 is less than the absolute value of the intersection of J, I sub i 1, and I sub i 2, which is less than epsilon.", "subset": "mixmath", "task_type": "tts"} +{"index": 1271, "question": "请你朗读以下数学公式符号:$\\frac{1.2\\times 3.6\\times 10.8+2\\times 6\\times 18+7\\times 21\\times 63}{1.2\\times 2.4\\times 4.8+2\\times 4\\times 8+7\\times 14\\times 28}$", "audio_path": "audio/math_41fe32a6-1ec7-4145-9883-b03a1b21a620.wav", "formula": "$\\frac{1.2\\times 3.6\\times 10.8+2\\times 6\\times 18+7\\times 21\\times 63}{1.2\\times 2.4\\times 4.8+2\\times 4\\times 8+7\\times 14\\times 28}$", "answer": "一点二乘三点六乘十点八加二乘六乘十八加七乘二十一乘六十三,整体除以一点二乘二点四乘四点八加二乘四乘八加七乘十四乘二十八的和", "subset": "mixmath", "task_type": "tts"} +{"index": 1272, "question": "Please read the following math formula symbols: $\\PiUX\\circ\\hatX\\circ\\hatU_{\\ibar}^{g_i,g_j}=\\PiUX$", "audio_path": "audio/row_01484230_1755768956313578.wav", "formula": "$\\PiUX\\circ\\hatX\\circ\\hatU_{\\ibar}^{g_i,g_j}=\\PiUX$", "answer": "Pi U X circle hat X circle hat U i bar superscript g i comma g j equals Pi U X.", "subset": "mixmath", "task_type": "tts"} +{"index": 1273, "question": "请你朗读以下数学公式符号:$\\left\\{ \\begin{array}{*{35}{l}} x=2 \\\\ y=1 \\\\\\end{array} \\right.$", "audio_path": "audio/math_a5ede6ae-c25b-4896-8bf0-5671a65b450d.wav", "formula": "$\\left\\{ \\begin{array}{*{35}{l}} x=2 \\\\ y=1 \\\\\\end{array} \\right.$", "answer": "x等于二,y等于一", "subset": "mixmath", "task_type": "tts"} +{"index": 1274, "question": "请你朗读以下数学公式符号:$S=\\frac{1}{2}\\cdot AB\\cdot OC=\\frac{1}{2}\\times 2\\sqrt{m^{2}+m^{4}}\\times \\sqrt{\\frac{1}{m^{2}}+\\frac{1}{m^{4}}}=\\sqrt{\\left(m+\\frac{1}{m}\\right)^{2}}=m+\\frac{1}{m}$", "audio_path": "audio/math_7caad927-da79-40c8-b748-6c935da9c109.wav", "formula": "$S=\\frac{1}{2}\\cdot AB\\cdot OC=\\frac{1}{2}\\times 2\\sqrt{m^{2}+m^{4}}\\times \\sqrt{\\frac{1}{m^{2}}+\\frac{1}{m^{4}}}=\\sqrt{\\left(m+\\frac{1}{m}\\right)^{2}}=m+\\frac{1}{m}$", "answer": "S等于二分之一乘 AB乘 OC等于二分之一乘 二倍的根号下m的平方加m的四次方的和乘 根号下m的平方分之一加m的四次方分之一的和 等于根号下 m加m分之一的和的平方 等于m加m分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 1275, "question": "请你朗读以下数学公式符号:$\\left\\{\\begin{array}{c}x=21\\\\ y=150.\\end{array}\\right.$", "audio_path": "audio/math_28536210-d7b4-42d7-965f-a6087bf627c8.wav", "formula": "$\\left\\{\\begin{array}{c}x=21\\\\ y=150.\\end{array}\\right.$", "answer": "x等于二十一和y等于一百五十", "subset": "mixmath", "task_type": "tts"} +{"index": 1276, "question": "请你朗读以下数学公式符号:$$\\left\\{ \\begin{align} & 40x+100y=280 \\\\ & 30x+200y=260 \\end{align} \\right.$$", "audio_path": "audio/math_c168de65-1f5c-4abe-8341-79a6e042e1ee.wav", "formula": "$$\\left\\{ \\begin{align} & 40x+100y=280 \\\\ & 30x+200y=260 \\end{align} \\right.$$", "answer": "四十x加一百y等于二百八十,三十x加二百y等于二百六十", "subset": "mixmath", "task_type": "tts"} +{"index": 1277, "question": "Please read the following math formula symbols: $\\opt=\\sum_{i=2}^nw(v_{i-1},v_{i})$", "audio_path": "audio/row_00876134_1755692796856569.wav", "formula": "$\\opt=\\sum_{i=2}^nw(v_{i-1},v_{i})$", "answer": "opt equals the sum from i equals 2 to n of w of v sub i minus 1, v sub i.", "subset": "mixmath", "task_type": "tts"} +{"index": 1278, "question": "请你朗读以下数学公式符号:$=\\dfrac{4x\\cdot \\left( x+1 \\right)}{3{{\\left( x+1 \\right)}^{2}}}$", "audio_path": "audio/math_c376bb23-f7fd-4524-b84d-3e96b8b1fe25.wav", "formula": "$=\\dfrac{4x\\cdot \\left( x+1 \\right)}{3{{\\left( x+1 \\right)}^{2}}}$", "answer": "等于三乘x加一的完全平方的积 分之 四x乘x加一和 的积", "subset": "mixmath", "task_type": "tts"} +{"index": 1279, "question": "请你朗读以下数学公式符号:${{x}^{2}}+\\frac{1}{2}mx+81={{x}^{2}}\\pm 2\\times 9x+{{9}^{2}}$", "audio_path": "audio/math_81f11e67-1b8c-445f-8ad5-e979a8c245c4.wav", "formula": "${{x}^{2}}+\\frac{1}{2}mx+81={{x}^{2}}\\pm 2\\times 9x+{{9}^{2}}$", "answer": "x的平方加二分之一m乘 x加八十一等于x的平方加减二乘九x加九的平方", "subset": "mixmath", "task_type": "tts"} +{"index": 1280, "question": "Please read the following math formula symbols: $\\calH(x,y)\\eqdef\\set{h\\in\\calH\\text{suchthat}h(x)=y}$", "audio_path": "audio/row_01429590_1755762062639252.wav", "formula": "$\\calH(x,y)\\eqdef\\set{h\\in\\calH\\text{suchthat}h(x)=y}$", "answer": "Cal H of x, y is defined as f set containing h in Cal H such that h of x equals y.", "subset": "mixmath", "task_type": "tts"} +{"index": 1281, "question": "Please read the following math formula symbols: $h:B\\to(R_{B/A}^\\ext/(t^{-1}))_0$", "audio_path": "audio/row_00792057_1755682227837501.wav", "formula": "$h:B\\to(R_{B/A}^\\ext/(t^{-1}))_0$", "answer": "h, B, to, R sub B over A, raised to the power of ext, divided by, t to the power of negative one, sub zero.", "subset": "mixmath", "task_type": "tts"} +{"index": 1282, "question": "请你朗读以下数学公式符号:$1m^{2}=100dm^{2}=10000cm^{2}$", "audio_path": "audio/math_b02bb2d9-e68d-4ff5-9757-7fe830c70bc7.wav", "formula": "$1m^{2}=100dm^{2}=10000cm^{2}$", "answer": "一平方米等于一百平方分米等于一万平方厘米", "subset": "mixmath", "task_type": "tts"} +{"index": 1283, "question": "Please read the following math formula symbols: $|\\overline{\\overline{Y}}_{S}|\\leqE[X|\\mathcal{F}_{S}]$", "audio_path": "audio/row_01705271_1755796888834436.wav", "formula": "$|\\overline{\\overline{Y}}_{S}|\\leqE[X|\\mathcal{F}_{S}]$", "answer": "Absolute value of the overline Y sub S is less than or equal to E of X given F sub S.", "subset": "mixmath", "task_type": "tts"} +{"index": 1284, "question": "请你朗读以下数学公式符号:$1\\frac{1}{11}\\div 5\\frac{1}{7}=\\frac{12}{11} \\times \\frac{7}{36}=\\frac{7}{33}$", "audio_path": "audio/math_97f9915b-aa94-4002-bd6b-678d816de529.wav", "formula": "$1\\frac{1}{11}\\div 5\\frac{1}{7}=\\frac{12}{11} \\times \\frac{7}{36}=\\frac{7}{33}$", "answer": "一又十一分之一除以五又七分之一等于十一分之十二乘三十六分之七等于三十三分之七", "subset": "mixmath", "task_type": "tts"} +{"index": 1285, "question": "Please read the following math formula symbols: $(v_n)_{n}\\subsetX_R$", "audio_path": "audio/row_00486214_1755644236155925.wav", "formula": "$(v_n)_{n}\\subsetX_R$", "answer": "The sequence v sub n, where n belongs to the set of natural numbers, is a subset of X sub R.", "subset": "mixmath", "task_type": "tts"} +{"index": 1286, "question": "Please read the following math formula symbols: $\\log(M_h/[h^{-1}M_\\odot])=11.09^{+0.10}_{-0.09}$", "audio_path": "audio/row_00170294_1755605716773977.wav", "formula": "$\\log(M_h/[h^{-1}M_\\odot])=11.09^{+0.10}_{-0.09}$", "answer": "Logarithm of M sub h divided by h to the power of negative 1 times M sub solar equals 11.09 plus 0.10 minus 0.09.", "subset": "mixmath", "task_type": "tts"} +{"index": 1287, "question": "请你朗读以下数学公式符号:${{x}^{4}}+{{y}^{4}}\\geqslant \\frac{1}{2}\\cdot \\left( {{x}^{2}}+{{y}^{2}} \\right)=\\frac{1}{2}$", "audio_path": "audio/math_37d62758-7e90-40cd-b08f-39d591686767.wav", "formula": "${{x}^{4}}+{{y}^{4}}\\geqslant \\frac{1}{2}\\cdot \\left( {{x}^{2}}+{{y}^{2}} \\right)=\\frac{1}{2}$", "answer": "x的四次方加y的四次方的和大于等于二分之一乘x平方加y平方的和等于二分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 1288, "question": "Please read the following math formula symbols: $v_n^\\pm=\\lim_{\\varepsilon\\to0+}v(x,t_n\\pm\\varepsilon)$", "audio_path": "audio/row_00550140_1755652077930562.wav", "formula": "$v_n^\\pm=\\lim_{\\varepsilon\\to0+}v(x,t_n\\pm\\varepsilon)$", "answer": "v sub n plus or minus equals the limit as epsilon approaches zero plus of v of x, t sub n plus or minus epsilon.", "subset": "mixmath", "task_type": "tts"} +{"index": 1289, "question": "请你朗读以下数学公式符号:$={{x}^{2}}+2xy+xz+2yx+4{{y}^{2}}+2yz+xz+2yz+{{z}^{2}}$", "audio_path": "audio/math_92c5c7d6-009e-4e6e-b4b3-73ab7c833286.wav", "formula": "$={{x}^{2}}+2xy+xz+2yx+4{{y}^{2}}+2yz+xz+2yz+{{z}^{2}}$", "answer": "等于x的平方加二x y加x z加二y x加四y的平方加二y z加x z加二y z加z的平方", "subset": "mixmath", "task_type": "tts"} +{"index": 1290, "question": "Please read the following math formula symbols: $F_J^M=i^M_{F^M}(g)(p)$", "audio_path": "audio/row_01272446_1755742344127708.wav", "formula": "$F_J^M=i^M_{F^M}(g)(p)$", "answer": "F sub J to the power of M equals i to the power of M sub F to the power of M of g of p.", "subset": "mixmath", "task_type": "tts"} +{"index": 1291, "question": "请你朗读以下数学公式符号:$$0.0\\overset{.}{\\mathop{8}}=\\frac{8}{90}=\\frac{4}{45}$$", "audio_path": "audio/math_3c7ab64a-4976-4ca5-aa95-f4fbc79b6ec6.wav", "formula": "$$0.0\\overset{.}{\\mathop{8}}=\\frac{8}{90}=\\frac{4}{45}$$", "answer": "零点零八 八循环 等于 九十分之八 等于四十五分之四", "subset": "mixmath", "task_type": "tts"} +{"index": 1292, "question": "请你朗读以下数学公式符号:$\\left( x+5 \\right)\\times \\frac{1}{20}+\\frac{1}{30}x=1$", "audio_path": "audio/math_1c4ea7bd-eab0-49e3-be5a-276f8947cf7f.wav", "formula": "$\\left( x+5 \\right)\\times \\frac{1}{20}+\\frac{1}{30}x=1$", "answer": "x加五的和 乘二十分之一 加三十分之一 x 等于一", "subset": "mixmath", "task_type": "tts"} +{"index": 1293, "question": "Please read the following math formula symbols: $I^{\\infty}_U\\coloneqqB^{\\infty}\\capI_U$", "audio_path": "audio/row_01638858_1755788510487987.wav", "formula": "$I^{\\infty}_U\\coloneqqB^{\\infty}\\capI_U$", "answer": "I to the power of infinity, sub U, is defined as B to the power of infinity intersect I sub U.", "subset": "mixmath", "task_type": "tts"} +{"index": 1294, "question": "Please read the following math formula symbols: $E_b^S=E_g^{\\mathrm{QP}}-\\Omega^S$", "audio_path": "audio/row_00797027_1755682840776584.wav", "formula": "$E_b^S=E_g^{\\mathrm{QP}}-\\Omega^S$", "answer": "E sub b to the power of S equals E sub g to the power of QP minus Omega to the power of S.", "subset": "mixmath", "task_type": "tts"} +{"index": 1295, "question": "Please read the following math formula symbols: $\\ID^d_{r,k}\\to\\Delta^r_s\\subseteqS_k$", "audio_path": "audio/row_01755344_1755803256274391.wav", "formula": "$\\ID^d_{r,k}\\to\\Delta^r_s\\subseteqS_k$", "answer": "ID raised to the power of d sub r, k, goes to Delta raised to the power of r sub s, subset S sub k.", "subset": "mixmath", "task_type": "tts"} +{"index": 1296, "question": "请你朗读以下数学公式符号:$\\frac{16}{15}\\div 2\\frac{2}{3}=\\frac{16}{15} \\times \\frac{3}{8}=\\frac{2}{5}$", "audio_path": "audio/math_00892f3d-8e7f-4f07-97db-8970b7411864.wav", "formula": "$\\frac{16}{15}\\div 2\\frac{2}{3}=\\frac{16}{15} \\times \\frac{3}{8}=\\frac{2}{5}$", "answer": "十五分之十六除以二又三分之二等于十五分之十六乘八分之三等于五分之二", "subset": "mixmath", "task_type": "tts"} +{"index": 1297, "question": "请你朗读以下数学公式符号:$\\frac{3}{7}=0.\\overset{\\centerdot }{\\mathop{4}}\\,2857\\overset{\\centerdot }{\\mathop{1}}\\,$", "audio_path": "audio/math_09aef338-3f8a-43cb-b278-7a666e08f604.wav", "formula": "$\\frac{3}{7}=0.\\overset{\\centerdot }{\\mathop{4}}\\,2857\\overset{\\centerdot }{\\mathop{1}}\\,$", "answer": "七分之三等于零点四二八五七一 四二八五七一循环", "subset": "mixmath", "task_type": "tts"} +{"index": 1298, "question": "请你朗读以下数学公式符号:$\\begin{cases}x=8\\\\ y=7\\end{cases}$", "audio_path": "audio/math_684ddc94-6b5f-4cd8-8e84-ea6d3216d683.wav", "formula": "$\\begin{cases}x=8\\\\ y=7\\end{cases}$", "answer": "x等于八和y等于七", "subset": "mixmath", "task_type": "tts"} +{"index": 1299, "question": "Please read the following math formula symbols: $e_1'\\inN(e_1)\\capV(Z)$", "audio_path": "audio/row_00013049_1755586688894211.wav", "formula": "$e_1'\\inN(e_1)\\capV(Z)$", "answer": "e sub 1 prime belongs to the intersection of the set of N of e sub 1 and the set of V of Z.", "subset": "mixmath", "task_type": "tts"} +{"index": 1300, "question": "请你朗读以下数学公式符号:$a^2+\\frac{1}{a^2}=\\left(\\frac{1}{m}\\right)^2+\\dfrac{1}{\\left(\\dfrac{1}{m}\\right)^2}=m^2+\\frac{1}{m^2}$", "audio_path": "audio/math_9e53f5c8-6a43-434a-8710-a3e402da5f4c.wav", "formula": "$a^2+\\frac{1}{a^2}=\\left(\\frac{1}{m}\\right)^2+\\dfrac{1}{\\left(\\dfrac{1}{m}\\right)^2}=m^2+\\frac{1}{m^2}$", "answer": "a的平方加a平方分之一等于m分之一的平方加m分之一的平方分之一等于m的平方加m平方分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 1301, "question": "Please read the following math formula symbols: $1\\llt_2-t_1\\ll\\log(\\zeta^{-1})$", "audio_path": "audio/row_00306942_1755622355760447.wav", "formula": "$1\\llt_2-t_1\\ll\\log(\\zeta^{-1})$", "answer": "One is much less than t sub 2 minus t sub 1, which is much less than the logarithm of the reciprocal of zeta.", "subset": "mixmath", "task_type": "tts"} +{"index": 1302, "question": "Please read the following math formula symbols: $\\{t+|x|\\leq2\\tau,\\,t\\geq\\tau\\}$", "audio_path": "audio/row_02062734_1755842093953142.wav", "formula": "$\\{t+|x|\\leq2\\tau,\\,t\\geq\\tau\\}$", "answer": "Open brace, t plus absolute value of x less than or equal to 2 tau, comma, t greater than or equal to tau, close brace.", "subset": "mixmath", "task_type": "tts"} +{"index": 1303, "question": "请你朗读以下数学公式符号:$\\begin{cases}x+y=7 \\\\ 10x+y+45=10y+x \\end{cases}$", "audio_path": "audio/math_2191fd2e-892e-44eb-a6b4-bd1e6394ab8d.wav", "formula": "$\\begin{cases}x+y=7 \\\\ 10x+y+45=10y+x \\end{cases}$", "answer": "x加y的和等于七,十x加y加四十五等于十y加x。", "subset": "mixmath", "task_type": "tts"} +{"index": 1304, "question": "请你朗读以下数学公式符号:$$\\left( \\frac{7}{25}+\\frac{7}{15} \\right)\\times 75=\\frac{7}{25}\\times 75+\\frac{7}{15}\\times 75=21+35=56$$", "audio_path": "audio/math_5e203240-28d1-4a38-b224-123f4f2a567c.wav", "formula": "$$\\left( \\frac{7}{25}+\\frac{7}{15} \\right)\\times 75=\\frac{7}{25}\\times 75+\\frac{7}{15}\\times 75=21+35=56$$", "answer": "二十五分之七加十五分之七的和乘七十五等于二十五分之七乘七十五加十五分之七乘七十五等于二十一加三十五等于五十六", "subset": "mixmath", "task_type": "tts"} +{"index": 1305, "question": "Please read the following math formula symbols: $0\\leqt\\leq\\frac{2}{C(\\alpha_0)}$", "audio_path": "audio/row_01328232_1755749291693159.wav", "formula": "$0\\leqt\\leq\\frac{2}{C(\\alpha_0)}$", "answer": "Zero is less than or equal to t, which is less than or equal to two divided by C of alpha sub zero.", "subset": "mixmath", "task_type": "tts"} +{"index": 1306, "question": "请你朗读以下数学公式符号:$\\frac{{{x}_{1}}+{{x}_{2}}}{{{x}_{1}}{{x}_{2}}}=3$", "audio_path": "audio/math_940e9c9d-24e6-49a0-912a-d0bd948b0bfc.wav", "formula": "$\\frac{{{x}_{1}}+{{x}_{2}}}{{{x}_{1}}{{x}_{2}}}=3$", "answer": "x一加x二的和除以x一乘x二的积等于三", "subset": "mixmath", "task_type": "tts"} +{"index": 1307, "question": "请你朗读以下数学公式符号:$\\frac{3}{4}+2\\frac{9}{17}+\\frac{1}{4}+3\\frac{8}{17}$", "audio_path": "audio/math_2b77f488-cac4-4bbc-9145-566903462ba2.wav", "formula": "$\\frac{3}{4}+2\\frac{9}{17}+\\frac{1}{4}+3\\frac{8}{17}$", "answer": "四分之三加二又十七分之九加四分之一加三又十七分之八", "subset": "mixmath", "task_type": "tts"} +{"index": 1308, "question": "请你朗读以下数学公式符号:$$=12.34+98.76+\\left( 67.89+43.21 \\right)=111.1+111.1=222.2$$", "audio_path": "audio/math_fe6eebbf-ede5-480a-9e96-114005a3e64d.wav", "formula": "$$=12.34+98.76+\\left( 67.89+43.21 \\right)=111.1+111.1=222.2$$", "answer": "等于十二点三四加九十八点七六加六十七点八九加四十三点二一的和等于一百一十一点一加一百一十一点一等于二百二十二点二", "subset": "mixmath", "task_type": "tts"} +{"index": 1309, "question": "请你朗读以下数学公式符号:${{a}^{m}}\\cdot {{b}^{m}}={{\\left( ab \\right)}^{m}}$", "audio_path": "audio/math_d6b46a7d-0cc2-4126-bef7-48e19584d6eb.wav", "formula": "${{a}^{m}}\\cdot {{b}^{m}}={{\\left( ab \\right)}^{m}}$", "answer": "a的m次方乘b的m次方等于ab的m次方", "subset": "mixmath", "task_type": "tts"} +{"index": 1310, "question": "Please read the following math formula symbols: $%[x_{j'},p_{j}]=i\\delta_{j'j}$", "audio_path": "audio/row_01063259_1755716131426416.wav", "formula": "$%[x_{j'},p_{j}]=i\\delta_{j'j}$", "answer": "Tensor product with the commutator of x sub j prime and p sub j equals i times the Kronecker delta of j prime j.", "subset": "mixmath", "task_type": "tts"} +{"index": 1311, "question": "Please read the following math formula symbols: $\\psi_{12}^{\\pm}(0)=\\gamma_1\\pmi\\gamma_2$", "audio_path": "audio/row_00250784_1755615495652673.wav", "formula": "$\\psi_{12}^{\\pm}(0)=\\gamma_1\\pmi\\gamma_2$", "answer": "Psi sub 12 superscript plus or minus open parenthesis 0 close parenthesis equals gamma 1 plus or minus i gamma 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 1312, "question": "请你朗读以下数学公式符号:$$\\left\\{ \\begin{array}{*{35}{l}} mx+2y=6 \\\\ 2x+ny=8 \\end{array} \\right.$$", "audio_path": "audio/math_6e912ff7-e263-426f-aab2-4da0f78a6cf5.wav", "formula": "$$\\left\\{ \\begin{array}{*{35}{l}} mx+2y=6 \\\\ 2x+ny=8 \\end{array} \\right.$$", "answer": "m 乘x加二y等于六,二x加n 乘y等于八", "subset": "mixmath", "task_type": "tts"} +{"index": 1313, "question": "请你朗读以下数学公式符号:$\\therefore 2\\left( A\\cdot {{10}^{k}}+x \\right)=x\\cdot 10+A$", "audio_path": "audio/math_5f714882-e8f3-4bcf-a19f-b7c807fbe0f6.wav", "formula": "$\\therefore 2\\left( A\\cdot {{10}^{k}}+x \\right)=x\\cdot 10+A$", "answer": "所以,二倍的A乘十的k次方加x等于x乘十加A", "subset": "mixmath", "task_type": "tts"} +{"index": 1314, "question": "Please read the following math formula symbols: $\\E^{-8\\cpi^2/(bg^2)}$", "audio_path": "audio/row_00912737_1755697358218163.wav", "formula": "$\\E^{-8\\cpi^2/(bg^2)}$", "answer": "E to the power of negative 8 times c times i squared divided by open parenthesis b times g squared close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 1315, "question": "请你朗读以下数学公式符号:$\\frac{13}{11}>\\frac{9}{8}>\\frac{7}{9}>\\frac{10}{13}$", "audio_path": "audio/math_b4c4f349-f9ee-4750-85d8-b20cc38ce4dc.wav", "formula": "$\\frac{13}{11}>\\frac{9}{8}>\\frac{7}{9}>\\frac{10}{13}$", "answer": "十一分之十三大于八分之九大于九分之七大于十三分之十", "subset": "mixmath", "task_type": "tts"} +{"index": 1316, "question": "请你朗读以下数学公式符号:$\\frac{1}{5}+\\frac{2}{5}+\\frac{3}{5}+\\frac{4}{5}=2$", "audio_path": "audio/math_a9892a28-356a-4b0d-b001-e636c3c1c0e0.wav", "formula": "$\\frac{1}{5}+\\frac{2}{5}+\\frac{3}{5}+\\frac{4}{5}=2$", "answer": "五分之一加五分之二加五分之三加五分之四等于二", "subset": "mixmath", "task_type": "tts"} +{"index": 1317, "question": "Please read the following math formula symbols: $0\\le\\lambda_{j,n}\\le\\kappa^2<1$", "audio_path": "audio/row_01542277_1755776274855991.wav", "formula": "$0\\le\\lambda_{j,n}\\le\\kappa^2<1$", "answer": "Zero less than or equal to lambda sub j comma n less than or equal to kappa squared less than one.", "subset": "mixmath", "task_type": "tts"} +{"index": 1318, "question": "Please read the following math formula symbols: $\\cU_{Q_i}\\subseteq\\cN^{(1-\\eta')}_{Q_i}$", "audio_path": "audio/row_01075696_1755717685623839.wav", "formula": "$\\cU_{Q_i}\\subseteq\\cN^{(1-\\eta')}_{Q_i}$", "answer": "c U sub Q sub i is a subset of c N to the power of one minus eta prime sub Q sub i", "subset": "mixmath", "task_type": "tts"} +{"index": 1319, "question": "Please read the following math formula symbols: $\\tau\\in\\{\\tau:|t-\\tau|<\\dmax+1\\}$", "audio_path": "audio/row_01051043_1755714621542042.wav", "formula": "$\\tau\\in\\{\\tau:|t-\\tau|<\\dmax+1\\}$", "answer": "Tau belongs to the set of tau such that the absolute value of t minus tau is less than d max plus 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 1320, "question": "请你朗读以下数学公式符号:$\\overline{AB}=1000\\left( B+2 \\right)+B=1001B+2000=2017k$", "audio_path": "audio/math_23956d7f-01e5-4dda-b68a-f493fcd290a2.wav", "formula": "$\\overline{AB}=1000\\left( B+2 \\right)+B=1001B+2000=2017k$", "answer": "两位数AB等于一千乘B加二的和加B等于一千零一B加两千等于两千零一十七k", "subset": "mixmath", "task_type": "tts"} +{"index": 1321, "question": "Please read the following math formula symbols: $s\\inV(X_i),t\\inV(X_j),i\\neqj$", "audio_path": "audio/row_01885551_1755819718883899.wav", "formula": "$s\\inV(X_i),t\\inV(X_j),i\\neqj$", "answer": "s belongs to V of X sub i, t belongs to V of X sub j, i not equal to j.", "subset": "mixmath", "task_type": "tts"} +{"index": 1322, "question": "Please read the following math formula symbols: $M_{\\huaH_2}=6R^2N^4$", "audio_path": "audio/row_01323098_1755748650183819.wav", "formula": "$M_{\\huaH_2}=6R^2N^4$", "answer": "The value of M sub h u a H sub 2 equals 6 times R squared times N to the power of 4.", "subset": "mixmath", "task_type": "tts"} +{"index": 1323, "question": "Please read the following math formula symbols: $n+1=\\big|\\hAle\\big|+\\big|\\hAbet\\big|+\\big|\\hAge\\big|$", "audio_path": "audio/row_00125244_1755600245228238.wav", "formula": "$n+1=\\big|\\hAle\\big|+\\big|\\hAbet\\big|+\\big|\\hAge\\big|$", "answer": "n plus 1 equals the absolute value of h Ale plus the absolute value of h Abet plus the absolute value of h Age.", "subset": "mixmath", "task_type": "tts"} +{"index": 1324, "question": "Please read the following math formula symbols: $||\\vec{x}_i||{=}\\sqrt{\\vec{x}_i^\\mathsf{T}\\vec{x}_i}$", "audio_path": "audio/row_00511124_1755647296818221.wav", "formula": "$||\\vec{x}_i||{=}\\sqrt{\\vec{x}_i^\\mathsf{T}\\vec{x}_i}$", "answer": "Absolute value of vector x sub i equals square root of vector x sub i transpose times vector x sub i.", "subset": "mixmath", "task_type": "tts"} +{"index": 1325, "question": "Please read the following math formula symbols: $(f_1,\\dots,f_N)R_m^{-1}$", "audio_path": "audio/row_00896485_1755695332287044.wav", "formula": "$(f_1,\\dots,f_N)R_m^{-1}$", "answer": "Open parenthesis, f sub 1, comma, ellipsis, f sub N, close parenthesis, R sub m to the power of negative 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 1326, "question": "Please read the following math formula symbols: $(n-1,n+1,2n-1,2n+1,...)$", "audio_path": "audio/row_01934463_1755825882070828.wav", "formula": "$(n-1,n+1,2n-1,2n+1,...)$", "answer": "Open parenthesis, n minus 1, comma, n plus 1, comma, 2n minus 1, comma, 2n plus 1, comma, ellipsis, close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 1327, "question": "Please read the following math formula symbols: $y\\equivk\\left(\\eta-\\eta_{\\rmkin}/2+1/H\\right)$", "audio_path": "audio/row_00983016_1755706113985892.wav", "formula": "$y\\equivk\\left(\\eta-\\eta_{\\rmkin}/2+1/H\\right)$", "answer": "y is equivalent to k times the quantity eta minus eta sub kin divided by 2 plus 1 divided by H.", "subset": "mixmath", "task_type": "tts"} +{"index": 1328, "question": "请你朗读以下数学公式符号:$\\frac{3}{2}x\\div \\frac{3}{2}=\\frac{5}{2}\\div \\frac{3}{2}$", "audio_path": "audio/math_4d74967a-0541-4bad-9b7e-613ccb9d6557.wav", "formula": "$\\frac{3}{2}x\\div \\frac{3}{2}=\\frac{5}{2}\\div \\frac{3}{2}$", "answer": "二分之三x除以二分之三等于二分之五除以二分之三", "subset": "mixmath", "task_type": "tts"} +{"index": 1329, "question": "请你朗读以下数学公式符号:$\\left\\{\\begin{array}{c}5x+6y=16\\\\ 4x+y=5y+x\\end{array}\\right.$", "audio_path": "audio/math_9f569463-30ca-42fa-9893-2eb0f3d3a05c.wav", "formula": "$\\left\\{\\begin{array}{c}5x+6y=16\\\\ 4x+y=5y+x\\end{array}\\right.$", "answer": "五x加六y等于十六,四x加y等于五y加x", "subset": "mixmath", "task_type": "tts"} +{"index": 1330, "question": "Please read the following math formula symbols: $\\lbrace\\bx_i\\in\\bbR^d\\rbrace_{i=1}^n$", "audio_path": "audio/row_00620900_1755660926338688.wav", "formula": "$\\lbrace\\bx_i\\in\\bbR^d\\rbrace_{i=1}^n$", "answer": "The set of x sub i in the set of R to the power of d, with i equals 1 to n.", "subset": "mixmath", "task_type": "tts"} +{"index": 1331, "question": "请你朗读以下数学公式符号:$\\frac{3}{5}=\\frac{3\\times 6}{5\\times 6}=\\frac{18}{30}$", "audio_path": "audio/math_6f856b98-4147-4adf-9412-d2eaa59b4557.wav", "formula": "$\\frac{3}{5}=\\frac{3\\times 6}{5\\times 6}=\\frac{18}{30}$", "answer": "五分之三等于五乘六的积分之三乘六的积等于三十分之十八", "subset": "mixmath", "task_type": "tts"} +{"index": 1332, "question": "请你朗读以下数学公式符号:$37\\times 43+37\\times 56+37=37\\times (43+56+1)=37\\times 100=3700$", "audio_path": "audio/math_71f8f3b2-a85d-4efb-ad35-8b01185cc623.wav", "formula": "$37\\times 43+37\\times 56+37=37\\times (43+56+1)=37\\times 100=3700$", "answer": "三十七乘四十三加上三十七乘五十六加上三十七等于三十七乘四十三加五十六加一的和等于三十七乘一百等于三千七百", "subset": "mixmath", "task_type": "tts"} +{"index": 1333, "question": "Please read the following math formula symbols: $$\\lim_{m\\to\\infty}p(m,T,u_1)\\leq2S'\\epsilon$$", "audio_path": "audio/row_00311383_1755622898993098.wav", "formula": "$$\\lim_{m\\to\\infty}p(m,T,u_1)\\leq2S'\\epsilon$$", "answer": "Limit as m approaches infinity of p of m, T, u sub 1 is less than or equal to 2S prime epsilon.", "subset": "mixmath", "task_type": "tts"} +{"index": 1334, "question": "请你朗读以下数学公式符号:$\\frac{12321}{333\\times 333}=\\frac{1}{3\\times 3}=\\frac{1}{9}$", "audio_path": "audio/math_a7522ff7-f345-495b-93b1-c29ccfe63b9b.wav", "formula": "$\\frac{12321}{333\\times 333}=\\frac{1}{3\\times 3}=\\frac{1}{9}$", "answer": "三百三十三乘三百三十三的积 分之一万两千三百二十一 等于三乘三的积 分之一 等于九分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 1335, "question": "Please read the following math formula symbols: $\\hat{V}_h^k(s)\\geqV_h^*(s)$", "audio_path": "audio/row_00506080_1755646673175952.wav", "formula": "$\\hat{V}_h^k(s)\\geqV_h^*(s)$", "answer": "V hat sub h superscript k of s is greater than or equal to V sub h superscript star of s.", "subset": "mixmath", "task_type": "tts"} +{"index": 1336, "question": "请你朗读以下数学公式符号:$\\begin{cases} x+y=36 \\\\ 2 \\times 25x =40y \\end{cases}$", "audio_path": "audio/math_e22b7ed1-85bc-4fb1-a3fe-04f86ba18bb3.wav", "formula": "$\\begin{cases} x+y=36 \\\\ 2 \\times 25x =40y \\end{cases}$", "answer": "x加y等于三十六,二乘二十五x等于四十y", "subset": "mixmath", "task_type": "tts"} +{"index": 1337, "question": "请你朗读以下数学公式符号:$\\frac{1}{2}+\\left( \\frac{1}{6}+\\frac{1}{3} \\right)x=1$", "audio_path": "audio/math_dacfee3b-26d5-434e-a38d-13d567c2f71b.wav", "formula": "$\\frac{1}{2}+\\left( \\frac{1}{6}+\\frac{1}{3} \\right)x=1$", "answer": "二分之一加括号六分之一加三分之一括号乘x等于一", "subset": "mixmath", "task_type": "tts"} +{"index": 1338, "question": "Please read the following math formula symbols: $X\\in\\textnormal\\{Fun(\\R(Q,V),\\mathcal{C})$", "audio_path": "audio/row_00166878_1755605296191084.wav", "formula": "$X\\in\\textnormal\\{Fun(\\R(Q,V),\\mathcal{C})$", "answer": "X belongs to the set of functions from the set of real numbers Q and the set of vectors V to the set C.", "subset": "mixmath", "task_type": "tts"} +{"index": 1339, "question": "请你朗读以下数学公式符号:$$17+16+15+14+13+12+11+10=\\left( 17+10 \\right)\\times 8\\div 2=108$$", "audio_path": "audio/math_4f0be8e0-8d0e-44b8-9165-9c940127ee08.wav", "formula": "$$17+16+15+14+13+12+11+10=\\left( 17+10 \\right)\\times 8\\div 2=108$$", "answer": "十七加十六加十五加十四加十三加十二加十一加十等于十七加十的和乘八除以二等于一百零八", "subset": "mixmath", "task_type": "tts"} +{"index": 1340, "question": "请你朗读以下数学公式符号:$={{\\left( {10}^{m} \\right)}^{2}}\\cdot {{\\left( {10}^{n} \\right)}^{3}}$", "audio_path": "audio/math_8d3dbb91-e797-4435-9b06-8065193cac3f.wav", "formula": "$={{\\left( {10}^{m} \\right)}^{2}}\\cdot {{\\left( {10}^{n} \\right)}^{3}}$", "answer": "等于十的m次方的平方乘十的n次方的立方", "subset": "mixmath", "task_type": "tts"} +{"index": 1341, "question": "请你朗读以下数学公式符号:$ = \\frac{7}{11} \\times \\left( \\frac{8}{25}+\\frac{3}{25} \\right) $", "audio_path": "audio/math_1ebaf688-c788-4677-ad67-e94465889b26.wav", "formula": "$ = \\frac{7}{11} \\times \\left( \\frac{8}{25}+\\frac{3}{25} \\right) $", "answer": "等于十一分之七乘二十五分之八加二十五分之三的和", "subset": "mixmath", "task_type": "tts"} +{"index": 1342, "question": "Please read the following math formula symbols: $|x(t)|\\geq\\Omega(e^{-\\frac{\\mu}{2}t})$", "audio_path": "audio/row_01550810_1755777365336343.wav", "formula": "$|x(t)|\\geq\\Omega(e^{-\\frac{\\mu}{2}t})$", "answer": "Absolute value of x of t is greater than or equal to Omega of e to the power of negative mu divided by 2 times t.", "subset": "mixmath", "task_type": "tts"} +{"index": 1343, "question": "Please read the following math formula symbols: $0.772\\le\\tilde{\\mu}_P\\le0.801$", "audio_path": "audio/row_00893783_1755694988028259.wav", "formula": "$0.772\\le\\tilde{\\mu}_P\\le0.801$", "answer": "Zero point seven seven two is less than or equal to tilde mu sub P which is less than or equal to zero point eight one.", "subset": "mixmath", "task_type": "tts"} +{"index": 1344, "question": "Please read the following math formula symbols: $\\eta=48N\\eps^2\\sqrt{\\frac{\\log(10)}{M}}$", "audio_path": "audio/row_00519145_1755648276028646.wav", "formula": "$\\eta=48N\\eps^2\\sqrt{\\frac{\\log(10)}{M}}$", "answer": "Eta equals 48 N times the exponential of 2 times the square root of the logarithm of 10 divided by M.", "subset": "mixmath", "task_type": "tts"} +{"index": 1345, "question": "请你朗读以下数学公式符号:${{S}^{\\prime }}= \\pi {{r}^{2}}= \\pi {{\\left( \\frac{1}{2}R \\right)}^{2}}=\\frac{1}{4} \\pi {{R}^{2}}$", "audio_path": "audio/math_e2855368-8648-43c9-8c5b-599b8e41bf32.wav", "formula": "${{S}^{\\prime }}= \\pi {{r}^{2}}= \\pi {{\\left( \\frac{1}{2}R \\right)}^{2}}=\\frac{1}{4} \\pi {{R}^{2}}$", "answer": "S撇 等于 pi 乘 r的平方 等于 pi乘 二分之一R的平方 等于 四分之一 乘pi乘R的平方", "subset": "mixmath", "task_type": "tts"} +{"index": 1346, "question": "Please read the following math formula symbols: $s_{\\Lambda}^{\\mu_a,\\mu_b}-s_{\\mathcal{O}}^{P_a,P_b}=0$", "audio_path": "audio/row_01938534_1755826400245458.wav", "formula": "$s_{\\Lambda}^{\\mu_a,\\mu_b}-s_{\\mathcal{O}}^{P_a,P_b}=0$", "answer": "s sub lambda superscript mu a comma mu b minus s sub O superscript P sub a comma P sub b equals zero", "subset": "mixmath", "task_type": "tts"} +{"index": 1347, "question": "请你朗读以下数学公式符号:$\\frac{{{x}^{2}}(a{{x}^{5}}+b{{x}^{3}}+cx)}{{{x}^{4}}+d{{x}^{2}}}$", "audio_path": "audio/math_2c4ac462-edd3-42e1-be40-c438ca9f7250.wav", "formula": "$\\frac{{{x}^{2}}(a{{x}^{5}}+b{{x}^{3}}+cx)}{{{x}^{4}}+d{{x}^{2}}}$", "answer": "x的四次方加d乘 x平方分之x的平方乘a 乘x的五次方加b 乘x的三次方加c 乘x的和", "subset": "mixmath", "task_type": "tts"} +{"index": 1348, "question": "Please read the following math formula symbols: $\\HT_j(\\BC'(\\varrho))=-\\fw(\\lambda_j)$", "audio_path": "audio/row_01455754_1755765362656699.wav", "formula": "$\\HT_j(\\BC'(\\varrho))=-\\fw(\\lambda_j)$", "answer": "The HT sub j of the derivative of BC with respect to rho equals negative f times w of lambda sub j.", "subset": "mixmath", "task_type": "tts"} +{"index": 1349, "question": "请你朗读以下数学公式符号:$$\\frac{5}{4}>\\frac{7}{6}>\\frac{9}{8}>\\frac{13}{12}>\\frac{4}{5}>\\frac{3}{4}$$", "audio_path": "audio/math_2a12187e-e6b3-4d28-afd6-704d11148a52.wav", "formula": "$$\\frac{5}{4}>\\frac{7}{6}>\\frac{9}{8}>\\frac{13}{12}>\\frac{4}{5}>\\frac{3}{4}$$", "answer": "四分之五大于六分之七大于八分之九大于十二分之十三大于五分之四大于四分之三", "subset": "mixmath", "task_type": "tts"} +{"index": 1350, "question": "请你朗读以下数学公式符号:$\\sqrt{2+\\frac{2}{3}}=\\sqrt{\\frac{8}{3}}=\\sqrt{\\frac{{2}^{2}\\times 2}{3}}=2\\sqrt{\\frac{2}{3}},\\sqrt{3+\\frac{3}{8}}=3\\sqrt{\\frac{3}{8}}$", "audio_path": "audio/math_8662ed8d-bdca-4db0-a20e-39237e644761.wav", "formula": "$\\sqrt{2+\\frac{2}{3}}=\\sqrt{\\frac{8}{3}}=\\sqrt{\\frac{{2}^{2}\\times 2}{3}}=2\\sqrt{\\frac{2}{3}},\\sqrt{3+\\frac{3}{8}}=3\\sqrt{\\frac{3}{8}}$", "answer": "根号下二加三分之二等于根号下三分之八等于根号下三分之二的平方乘二等于二倍的根号下三分之二,根号下三加八分之三等于三倍的根号下八分之三", "subset": "mixmath", "task_type": "tts"} +{"index": 1351, "question": "Please read the following math formula symbols: $$P^r:\\mathbb{R}^k\\to\\mathbb{R}^{k-r}$$", "audio_path": "audio/row_01315241_1755747655139742.wav", "formula": "$$P^r:\\mathbb{R}^k\\to\\mathbb{R}^{k-r}$$", "answer": "P to the power of r, colon, R to the power of k, arrow, R to the power of k minus r.", "subset": "mixmath", "task_type": "tts"} +{"index": 1352, "question": "Please read the following math formula symbols: $A_5=\\frac{r_5kr_3}{r_1}$", "audio_path": "audio/row_01121702_1755723408935602.wav", "formula": "$A_5=\\frac{r_5kr_3}{r_1}$", "answer": "A sub 5 equals the fraction with numerator r sub 5 times k times r sub 3 and denominator r sub 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 1353, "question": "请你朗读以下数学公式符号:$25\\times 13\\times 4=\\left( 25\\times 4 \\right)\\times 13$", "audio_path": "audio/math_79e6130a-ca67-40ef-9fcf-a5a8c3b83efc.wav", "formula": "$25\\times 13\\times 4=\\left( 25\\times 4 \\right)\\times 13$", "answer": "二十五乘十三乘四等于二十五乘四的积乘十三", "subset": "mixmath", "task_type": "tts"} +{"index": 1354, "question": "请你朗读以下数学公式符号:$$\\left( \\frac{4}{5}+\\frac{2}{15} \\right)\\times \\frac{5}{16}$$", "audio_path": "audio/math_d80d5737-a690-43ce-82d6-636f1bcb4422.wav", "formula": "$$\\left( \\frac{4}{5}+\\frac{2}{15} \\right)\\times \\frac{5}{16}$$", "answer": "五分之四与十五分之二的和乘十六分之五", "subset": "mixmath", "task_type": "tts"} +{"index": 1355, "question": "Please read the following math formula symbols: $u\\inX^{s_{0},b_{0}}(T)$", "audio_path": "audio/row_00432323_1755637635754419.wav", "formula": "$u\\inX^{s_{0},b_{0}}(T)$", "answer": "u belongs to the set X raised to the power of s sub 0, b sub 0, and it is a function of T.", "subset": "mixmath", "task_type": "tts"} +{"index": 1356, "question": "请你朗读以下数学公式符号:$25 \\% \\times \\frac{8}{9}+\\frac{3}{4}\\div \\frac{9}{8}$", "audio_path": "audio/math_cb13e35c-a099-403e-9812-99949bd9553a.wav", "formula": "$25 \\% \\times \\frac{8}{9}+\\frac{3}{4}\\div \\frac{9}{8}$", "answer": "百分之二十五乘九分之八加四分之三除以八分之九", "subset": "mixmath", "task_type": "tts"} +{"index": 1357, "question": "Please read the following math formula symbols: $H_0(x)=\\sum_{s=0}^\\inftyP_sx^s$", "audio_path": "audio/row_01508902_1755772079980786.wav", "formula": "$H_0(x)=\\sum_{s=0}^\\inftyP_sx^s$", "answer": "H sub zero of x equals the summation from s equals zero to infinity of P sub s times x to the power of s.", "subset": "mixmath", "task_type": "tts"} +{"index": 1358, "question": "Please read the following math formula symbols: $\\Om=Q^n:=(0,1)^n$", "audio_path": "audio/row_01683749_1755794186643267.wav", "formula": "$\\Om=Q^n:=(0,1)^n$", "answer": "O times m equals Q to the power of n, which is equal to the quantity 0 comma 1 raised to the power of n.", "subset": "mixmath", "task_type": "tts"} +{"index": 1359, "question": "请你朗读以下数学公式符号:$h=25.12\\div \\frac{1}{3}\\div (3.14\\times {{2}^{2}})$", "audio_path": "audio/math_7f22406d-4232-4322-ae46-391681af64ed.wav", "formula": "$h=25.12\\div \\frac{1}{3}\\div (3.14\\times {{2}^{2}})$", "answer": "h等于二十五点一二除以三分之一,再除以三点一四乘二的平方的积", "subset": "mixmath", "task_type": "tts"} +{"index": 1360, "question": "Please read the following math formula symbols: $\\bV=(\\bI+\\bJ+\\bK+\\bL)/\\sqrt{2}$", "audio_path": "audio/row_01099613_1755720672196976.wav", "formula": "$\\bV=(\\bI+\\bJ+\\bK+\\bL)/\\sqrt{2}$", "answer": "Lambda V equals open parenthesis, b I plus b J plus b K plus b L, close parenthesis, divided by square root of 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 1361, "question": "请你朗读以下数学公式符号:$\\begin{cases}x+1\\geqslant 0 \\\\ x\\ne 0 \\end{cases}$", "audio_path": "audio/math_8c08d436-f043-47e3-865c-2f837c170bec.wav", "formula": "$\\begin{cases}x+1\\geqslant 0 \\\\ x\\ne 0 \\end{cases}$", "answer": "x加一大于等于零和x不等于零", "subset": "mixmath", "task_type": "tts"} +{"index": 1362, "question": "Please read the following math formula symbols: $\\overline{P_kP_{k+1}}\\capS=\\{P_k,P_{k+1}\\}$", "audio_path": "audio/row_02078843_1755844147195613.wav", "formula": "$\\overline{P_kP_{k+1}}\\capS=\\{P_k,P_{k+1}\\}$", "answer": "P sub k P sub k plus 1 intersection S equals the set containing P sub k and P sub k plus 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 1363, "question": "Please read the following math formula symbols: $\\|\\cdot\\|_{Q(S')}=\\|\\cdot\\|_{Q(T(S'))}$", "audio_path": "audio/row_01228115_1755736796326193.wav", "formula": "$\\|\\cdot\\|_{Q(S')}=\\|\\cdot\\|_{Q(T(S'))}$", "answer": "Norm of the dot product, subscript Q of S prime, equals norm of the dot product, subscript Q of T of S prime.", "subset": "mixmath", "task_type": "tts"} +{"index": 1364, "question": "Please read the following math formula symbols: $g(\\bm\\{Q)-g(\\bm\\{X^0)\\leq\\delta_1$", "audio_path": "audio/row_01997440_1755833825254484.wav", "formula": "$g(\\bm\\{Q)-g(\\bm\\{X^0)\\leq\\delta_1$", "answer": "g of boldface Q minus g of boldface X to the power of 0 is less than or equal to delta sub 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 1365, "question": "请你朗读以下数学公式符号:$$\\begin{eqnarray}&&2.36\\times 0.25\\times 40\\\\ &=&2.36\\times \\left( 0.25\\times 40 \\right) \\\\ &=&2.36\\times 10 \\\\ &=&23.6\\end{eqnarray}$$", "audio_path": "audio/math_d5841d2f-bd34-4ee9-b5ed-59a7fb0bbe96.wav", "formula": "$$\\begin{eqnarray}&&2.36\\times 0.25\\times 40\\\\ &=&2.36\\times \\left( 0.25\\times 40 \\right) \\\\ &=&2.36\\times 10 \\\\ &=&23.6\\end{eqnarray}$$", "answer": "二点三六乘零点二五乘四十等于二点三六乘零点二五乘四十的积等于二点三六乘十等于二十三点六", "subset": "mixmath", "task_type": "tts"} +{"index": 1366, "question": "请你朗读以下数学公式符号:$$9\\frac{5}{6}+99\\frac{5}{6}+999\\frac{5}{6}+9999\\frac{5}{6}+99999\\frac{5}{6}+\\frac{1}{6}\\times 5$$", "audio_path": "audio/math_fadb9a51-d8e5-4272-a3ba-e1c35072a6fa.wav", "formula": "$$9\\frac{5}{6}+99\\frac{5}{6}+999\\frac{5}{6}+9999\\frac{5}{6}+99999\\frac{5}{6}+\\frac{1}{6}\\times 5$$", "answer": "九又六分之五加九十九又六分之五加九百九十九又六分之五加九千九百九十九又六分之五加九万九千九百九十九又六分之五加六分之一乘五", "subset": "mixmath", "task_type": "tts"} +{"index": 1367, "question": "Please read the following math formula symbols: $\\tilde\\mu_\\delta(f):=(\\mu_\\delta'(f)+\\mu_\\delta''(f))/2$", "audio_path": "audio/row_00108011_1755598156149569.wav", "formula": "$\\tilde\\mu_\\delta(f):=(\\mu_\\delta'(f)+\\mu_\\delta''(f))/2$", "answer": "The tilde mu delta of f, defined as the sum of mu delta prime of f and mu delta double prime of f, divided by two.", "subset": "mixmath", "task_type": "tts"} +{"index": 1368, "question": "Please read the following math formula symbols: $\\gamma_{i-1}(v)\\neq\\gamma_{i-1}(x_i)=2$", "audio_path": "audio/row_00141477_1755602215922384.wav", "formula": "$\\gamma_{i-1}(v)\\neq\\gamma_{i-1}(x_i)=2$", "answer": "Gamma sub i minus 1 of v is not equal to gamma sub i minus 1 of x sub i equals 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 1369, "question": "Please read the following math formula symbols: $\\xi\\colon\\cloQ_\\conv\\to\\omega(\\cloQ_\\conv)$", "audio_path": "audio/row_00205954_1755610062659062.wav", "formula": "$\\xi\\colon\\cloQ_\\conv\\to\\omega(\\cloQ_\\conv)$", "answer": "Xi maps the closure of Q sub convex to the closure of the image of Q sub convex under the function omega.", "subset": "mixmath", "task_type": "tts"} +{"index": 1370, "question": "请你朗读以下数学公式符号:$\\dfrac{1}{2}\\div\\left( \\dfrac{1}{50}+\\dfrac{1}{75}\\right)=15$", "audio_path": "audio/math_d4778209-a376-43ef-bfeb-319ec979acb1.wav", "formula": "$\\dfrac{1}{2}\\div\\left( \\dfrac{1}{50}+\\dfrac{1}{75}\\right)=15$", "answer": "二分之一除以五十分之一加七十五分之一的和等于十五", "subset": "mixmath", "task_type": "tts"} +{"index": 1371, "question": "请你朗读以下数学公式符号:$\\min \\left( {{A}_{i}}\\cap {{A}_{j}} \\right)=1 < \\max {{A}_{i}}$", "audio_path": "audio/math_943794b5-9c7b-4fd6-839b-84d7e1c75c89.wav", "formula": "$\\min \\left( {{A}_{i}}\\cap {{A}_{j}} \\right)=1 < \\max {{A}_{i}}$", "answer": "A i交A j的最小值等于一,小于A i的最大值", "subset": "mixmath", "task_type": "tts"} +{"index": 1372, "question": "Please read the following math formula symbols: $b_n=b_0+\\frac{m\\pin}{4W(2m\\pin/\\nu_T)}$", "audio_path": "audio/row_01167199_1755729133318458.wav", "formula": "$b_n=b_0+\\frac{m\\pin}{4W(2m\\pin/\\nu_T)}$", "answer": "b sub n equals b sub 0 plus m pi n divided by 4 W times 2 m pi n divided by nu sub T.", "subset": "mixmath", "task_type": "tts"} +{"index": 1373, "question": "请你朗读以下数学公式符号:$30000{c}{{{m}}^{2}}=30000\\div 10000{{{cm}}^{2}}=3{{{m}}^{2}}$", "audio_path": "audio/math_9c1b0196-18f4-4b5e-a1c0-e3714bc1adc5.wav", "formula": "$30000{c}{{{m}}^{2}}=30000\\div 10000{{{cm}}^{2}}=3{{{m}}^{2}}$", "answer": "三万平方厘米等于三万除以一万平方厘米等于三平方米", "subset": "mixmath", "task_type": "tts"} +{"index": 1374, "question": "请你朗读以下数学公式符号:$b={{2}^{3}}\\times {{3}^{2}}\\times 5\\times 7\\times 11$", "audio_path": "audio/math_add15385-3a05-48a4-989b-a61bd646a095.wav", "formula": "$b={{2}^{3}}\\times {{3}^{2}}\\times 5\\times 7\\times 11$", "answer": "b等于二的三次方乘三的平方乘五乘七乘十一", "subset": "mixmath", "task_type": "tts"} +{"index": 1375, "question": "Please read the following math formula symbols: $E_{ij}\\inE\\iffX_i\\in\\mathbf{PA}_j$", "audio_path": "audio/row_01175123_1755730129837323.wav", "formula": "$E_{ij}\\inE\\iffX_i\\in\\mathbf{PA}_j$", "answer": "E sub i j belongs to E if and only if X sub i belongs to the set of P sub j.", "subset": "mixmath", "task_type": "tts"} +{"index": 1376, "question": "Please read the following math formula symbols: $\\vecx=(x_{11},x_{12},x_{21},x_{22})$", "audio_path": "audio/row_01257133_1755740419890554.wav", "formula": "$\\vecx=(x_{11},x_{12},x_{21},x_{22})$", "answer": "Vector x equals open parenthesis x sub 11 comma x sub 12 comma x sub 21 comma x sub 22 close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 1377, "question": "Please read the following math formula symbols: $K_{\\bar{v}}:=\\cQ_{\\bar{v}}\\capG(F^+_{\\bar{v}})$", "audio_path": "audio/row_00426692_1755636934761939.wav", "formula": "$K_{\\bar{v}}:=\\cQ_{\\bar{v}}\\capG(F^+_{\\bar{v}})$", "answer": "K sub v bar is defined as the intersection of Q sub v bar and the set G of the positive F sub v bar.", "subset": "mixmath", "task_type": "tts"} +{"index": 1378, "question": "Please read the following math formula symbols: $|K_{\\eta\\beta\\beta',\\eta_1\\beta_1\\alpha_1}|0\\}$", "audio_path": "audio/row_01641905_1755788896162886.wav", "formula": "$x_n=(\\frac1n,y_n)\\in\\partial\\{u>0\\}$", "answer": "x sub n equals the fraction one over n, comma y sub n, in the boundary of the set u greater than zero.", "subset": "mixmath", "task_type": "tts"} +{"index": 1470, "question": "请你朗读以下数学公式符号:$=\\frac{5}{6}\\times \\left( 10.68+8.52 \\right)+1\\frac{3}{5}$", "audio_path": "audio/math_278c0856-69e1-49d5-a3b3-a18a8e513195.wav", "formula": "$=\\frac{5}{6}\\times \\left( 10.68+8.52 \\right)+1\\frac{3}{5}$", "answer": "等于六分之五乘 十点六八与八点五二的和,再加一又五分之三", "subset": "mixmath", "task_type": "tts"} +{"index": 1471, "question": "请你朗读以下数学公式符号:$$(0.1\\dot{5}+0.2\\dot{1}\\dot{8})\\times 0.\\dot{3}\\times \\frac{11}{111}=$$", "audio_path": "audio/math_1f2ad847-031d-491b-ad93-de647b8858dc.wav", "formula": "$$(0.1\\dot{5}+0.2\\dot{1}\\dot{8})\\times 0.\\dot{3}\\times \\frac{11}{111}=$$", "answer": "零点一五 五循环 加 零点二一八 一八循环的和 乘 零点三 三循环 乘 一百一十一分之十一等于", "subset": "mixmath", "task_type": "tts"} +{"index": 1472, "question": "Please read the following math formula symbols: $\\dima(X\\cap(W+y))\\leq\\dimh(X\\cap(V+x))$", "audio_path": "audio/row_01029124_1755711894217562.wav", "formula": "$\\dima(X\\cap(W+y))\\leq\\dimh(X\\cap(V+x))$", "answer": "Dimension of a of X intersection W plus y is less than or equal to dimension of h of X intersection V plus x.", "subset": "mixmath", "task_type": "tts"} +{"index": 1473, "question": "请你朗读以下数学公式符号:$\\frac{\\sqrt{6}+\\sqrt{8}}{2}=\\sqrt{3}+\\sqrt{4}=\\sqrt{3}+2$", "audio_path": "audio/math_5c866da8-2d80-423d-af4e-02bd21fcb015.wav", "formula": "$\\frac{\\sqrt{6}+\\sqrt{8}}{2}=\\sqrt{3}+\\sqrt{4}=\\sqrt{3}+2$", "answer": "二分之根号六加根号八的和等于根号三加根号四等于根号三加二", "subset": "mixmath", "task_type": "tts"} +{"index": 1474, "question": "请你朗读以下数学公式符号:$${{x}^{2}}+2x+3=\\left( {{x}^{2}}+2x+1 \\right)+2={{\\left( x+1 \\right)}^{2}}+2$$", "audio_path": "audio/math_78df912b-5463-406b-be2f-1d92fbfd2064.wav", "formula": "$${{x}^{2}}+2x+3=\\left( {{x}^{2}}+2x+1 \\right)+2={{\\left( x+1 \\right)}^{2}}+2$$", "answer": "x的平方加二x加三等于x的平方加二x加一的和加二等于x加一的和的平方加二", "subset": "mixmath", "task_type": "tts"} +{"index": 1475, "question": "请你朗读以下数学公式符号:${{\\left( {{a}^{2}} \\right)}^{3}}={{a}^{6}}\\neq {{a}^{5}}$", "audio_path": "audio/math_05588bf3-fc0d-4662-94ab-951317414635.wav", "formula": "${{\\left( {{a}^{2}} \\right)}^{3}}={{a}^{6}}\\neq {{a}^{5}}$", "answer": "a 的平方的立方等于 a 的六次方,不等于 a 的五次方", "subset": "mixmath", "task_type": "tts"} +{"index": 1476, "question": "请你朗读以下数学公式符号:$${{1}^{2}}+{{2}^{2}}+{{3}^{2}}+\\ldots +{{249}^{2}}+{{250}^{2}}$$", "audio_path": "audio/math_b72bcc5a-c249-4faf-bd60-edfce38385fb.wav", "formula": "$${{1}^{2}}+{{2}^{2}}+{{3}^{2}}+\\ldots +{{249}^{2}}+{{250}^{2}}$$", "answer": "一的平方加二的平方加三的平方加 一直加到 加二百四十九的平方加二百五十的平方", "subset": "mixmath", "task_type": "tts"} +{"index": 1477, "question": "请你朗读以下数学公式符号:$=\\frac{5}{8}\\times 31+\\frac{5}{8}\\times 9=\\frac{5}{8}\\times \\left( 31+9 \\right)=25$", "audio_path": "audio/math_5c9c4c97-0ffa-4455-9a9e-b1d1a57e1939.wav", "formula": "$=\\frac{5}{8}\\times 31+\\frac{5}{8}\\times 9=\\frac{5}{8}\\times \\left( 31+9 \\right)=25$", "answer": "等于八分之五乘三十一加八分之五乘九等于八分之五乘三十一加九的和等于二十五", "subset": "mixmath", "task_type": "tts"} +{"index": 1478, "question": "请你朗读以下数学公式符号:$$\\begin{eqnarray}&&0.36\\times0.5+0.64\\div0.5\\\\ &=&0.18+1.28\\\\ &=&1.46\\end{eqnarray}$$", "audio_path": "audio/math_c5e0122e-088f-47df-8a87-92bec6281b46.wav", "formula": "$$\\begin{eqnarray}&&0.36\\times0.5+0.64\\div0.5\\\\ &=&0.18+1.28\\\\ &=&1.46\\end{eqnarray}$$", "answer": "零点三六乘零点五加零点六四除以零点五,等于零点一八加一点二八,等于一点四六。", "subset": "mixmath", "task_type": "tts"} +{"index": 1479, "question": "请你朗读以下数学公式符号:$$\\left\\{\\begin{array}{c}x=4\\\\y=3\\end{array}\\right.$$", "audio_path": "audio/math_eb7449a0-013f-4ec1-adad-2282477967cc.wav", "formula": "$$\\left\\{\\begin{array}{c}x=4\\\\y=3\\end{array}\\right.$$", "answer": "x等于四,y等于三", "subset": "mixmath", "task_type": "tts"} +{"index": 1480, "question": "请你朗读以下数学公式符号:$=2\\times 4\\times 2\\times 8\\times 5\\times 125\\times 25$", "audio_path": "audio/math_b80c0d2e-88a3-4cb2-b73f-f5173db9e580.wav", "formula": "$=2\\times 4\\times 2\\times 8\\times 5\\times 125\\times 25$", "answer": "等于二乘四乘二乘八乘五乘一百二十五乘二十五", "subset": "mixmath", "task_type": "tts"} +{"index": 1481, "question": "Please read the following math formula symbols: $A=\\{j_1,\\dots,j_m\\}\\subseteq\\{1,\\dots,n\\}$", "audio_path": "audio/row_01421339_1755761033571274.wav", "formula": "$A=\\{j_1,\\dots,j_m\\}\\subseteq\\{1,\\dots,n\\}$", "answer": "A equals the set of j sub 1, dot dot dot, j sub m, which is a subset of the set containing 1 through n.", "subset": "mixmath", "task_type": "tts"} +{"index": 1482, "question": "请你朗读以下数学公式符号:$\\begin{cases}x+\\dfrac{x}{2}=12 \\\\ y+\\dfrac{x}{2}=9 \\end{cases}$", "audio_path": "audio/math_8d1d1302-867a-4d6d-aa1a-c5944058f540.wav", "formula": "$\\begin{cases}x+\\dfrac{x}{2}=12 \\\\ y+\\dfrac{x}{2}=9 \\end{cases}$", "answer": "x加二分之x等于十二,y加二分之x等于九", "subset": "mixmath", "task_type": "tts"} +{"index": 1483, "question": "Please read the following math formula symbols: $|Q'_{N+1}|=|\\Sigma|^{N+1}$", "audio_path": "audio/row_01491578_1755769898092975.wav", "formula": "$|Q'_{N+1}|=|\\Sigma|^{N+1}$", "answer": "Absolute value of Q sub N plus one equals absolute value of Sigma raised to the power of N plus one.", "subset": "mixmath", "task_type": "tts"} +{"index": 1484, "question": "请你朗读以下数学公式符号:$\\frac{10\\times 9}{2\\times 1}\\times \\frac{8\\times 7\\times 6}{3\\times 2\\times 1}\\times \\left( 3\\times 2\\times 1 \\right)=15120$", "audio_path": "audio/math_76adb2a3-4c2b-4b2c-ba57-46d9c260792a.wav", "formula": "$\\frac{10\\times 9}{2\\times 1}\\times \\frac{8\\times 7\\times 6}{3\\times 2\\times 1}\\times \\left( 3\\times 2\\times 1 \\right)=15120$", "answer": "二乘一的积分之十乘九 乘三乘二乘一的积分之八乘七乘六 乘三乘二乘一的积等于一万五千一百二十", "subset": "mixmath", "task_type": "tts"} +{"index": 1485, "question": "Please read the following math formula symbols: $\\Phi(t,\\alpha)\\inL_1^{\\infty}[0,T]$", "audio_path": "audio/row_00997441_1755707923800890.wav", "formula": "$\\Phi(t,\\alpha)\\inL_1^{\\infty}[0,T]$", "answer": "Phi of t, alpha, belongs to L sub 1 to the power of infinity, open square bracket 0, comma T, close square bracket.", "subset": "mixmath", "task_type": "tts"} +{"index": 1486, "question": "Please read the following math formula symbols: $\\norm{\\mu_I^X-\\mu_I^Y}_{\\infty}$", "audio_path": "audio/row_01028239_1755711776662014.wav", "formula": "$\\norm{\\mu_I^X-\\mu_I^Y}_{\\infty}$", "answer": "The norm of the difference between mu sub I to the power of X and mu sub I to the power of Y, sub infinity.", "subset": "mixmath", "task_type": "tts"} +{"index": 1487, "question": "请你朗读以下数学公式符号:${{m}^{2}}={{\\left( 10n+6 \\right)}^{2}}=\\left( {{n}^{2}}+n \\right)100+\\left( 2n+3 \\right)10+6$", "audio_path": "audio/math_2a89b727-ea3b-4df0-b4a9-d148e95d9fac.wav", "formula": "${{m}^{2}}={{\\left( 10n+6 \\right)}^{2}}=\\left( {{n}^{2}}+n \\right)100+\\left( 2n+3 \\right)10+6$", "answer": "m的平方等于十n加六的和的平方等于 n的平方加n的和 乘 一百加二n加三的和 乘十加六", "subset": "mixmath", "task_type": "tts"} +{"index": 1488, "question": "请你朗读以下数学公式符号:$\\begin{cases}x+y=422\\\\ 49x+37y=10\\end{cases}$", "audio_path": "audio/math_396ffc2e-e62c-4040-9ca3-26020858530f.wav", "formula": "$\\begin{cases}x+y=422\\\\ 49x+37y=10\\end{cases}$", "answer": "x加y等于四百二十二和四十九x加三十七y等于十", "subset": "mixmath", "task_type": "tts"} +{"index": 1489, "question": "Please read the following math formula symbols: $V_r=\\{v_{5i+r}:i=0,1,\\ldots,t-1\\}$", "audio_path": "audio/row_00715970_1755672692608890.wav", "formula": "$V_r=\\{v_{5i+r}:i=0,1,\\ldots,t-1\\}$", "answer": "V sub r equals the set of v sub 5i plus r, where i is equal to 0, 1, dot dot dot, t minus 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 1490, "question": "请你朗读以下数学公式符号:$\\begin{eqnarray}&&14\\times 50\\\\ &=&7\\times 2\\times 50\\\\ &=&7\\times \\left( 2\\times 50 \\right)\\\\ &=&7\\times 100\\\\ &=&700\\end{eqnarray}$", "audio_path": "audio/math_86a0d714-320b-42a9-9728-4fb790a09421.wav", "formula": "$\\begin{eqnarray}&&14\\times 50\\\\ &=&7\\times 2\\times 50\\\\ &=&7\\times \\left( 2\\times 50 \\right)\\\\ &=&7\\times 100\\\\ &=&700\\end{eqnarray}$", "answer": "十四乘五十等于七乘二乘五十等于七 乘 二乘五十的积 等于七乘一百等于七百", "subset": "mixmath", "task_type": "tts"} +{"index": 1491, "question": "请你朗读以下数学公式符号:$\\frac{1}{1\\times 2}+\\frac{1}{2\\times 3}+\\frac{1}{3\\times 4}+\\frac{1}{4\\times 5}=\\frac{3}{4}+\\frac{1}{20}=\\frac{4}{5}$", "audio_path": "audio/math_039cf71e-1b82-4e71-aaf8-b9ec878834e0.wav", "formula": "$\\frac{1}{1\\times 2}+\\frac{1}{2\\times 3}+\\frac{1}{3\\times 4}+\\frac{1}{4\\times 5}=\\frac{3}{4}+\\frac{1}{20}=\\frac{4}{5}$", "answer": "一乘二的积分之一加二乘三的积分之一加三乘四的积分之一加四乘五的积分之一等于四分之三加二十分之一等于五分之四", "subset": "mixmath", "task_type": "tts"} +{"index": 1492, "question": "Please read the following math formula symbols: $\\mathcal{U}(-4sT^{-2},4sT^{-2})$", "audio_path": "audio/row_00181286_1755607049244289.wav", "formula": "$\\mathcal{U}(-4sT^{-2},4sT^{-2})$", "answer": "U of negative 4 s T to the power of negative 2, comma 4 s T to the power of negative 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 1493, "question": "请你朗读以下数学公式符号:$T\\left( 1,0 \\right)=\\frac{a\\times 1+b\\times 0}{1+2\\times 0}=a$", "audio_path": "audio/math_bcd74e59-caf5-41b6-be31-ab2016c80346.wav", "formula": "$T\\left( 1,0 \\right)=\\frac{a\\times 1+b\\times 0}{1+2\\times 0}=a$", "answer": "T括号一,零括号等于一加 二乘零的和分之a乘一的积加b乘零的积的和等于a", "subset": "mixmath", "task_type": "tts"} +{"index": 1494, "question": "Please read the following math formula symbols: $P_{\\max}(y)-P_{\\max,(a_i)}(y)\\neq0$", "audio_path": "audio/row_01613938_1755785384860657.wav", "formula": "$P_{\\max}(y)-P_{\\max,(a_i)}(y)\\neq0$", "answer": "P sub max of y minus P sub max, open parenthesis, a sub i, close parenthesis, of y, not equal to zero.", "subset": "mixmath", "task_type": "tts"} +{"index": 1495, "question": "Please read the following math formula symbols: $m_{1\\itf}\\approx10^8\\sqrt{\\barr_i\\barm_{1i}}M_\\odot$", "audio_path": "audio/row_00729624_1755674400866560.wav", "formula": "$m_{1\\itf}\\approx10^8\\sqrt{\\barr_i\\barm_{1i}}M_\\odot$", "answer": "m sub 1 f is approximately 10 to the power of 8 square root of r bar sub i m sub 1 i M sub sun", "subset": "mixmath", "task_type": "tts"} +{"index": 1496, "question": "请你朗读以下数学公式符号:$\\frac{9}{11}\\times \\frac{7}{15}\\times \\frac{11}{3}$", "audio_path": "audio/math_9333b220-eeaf-44da-b1c0-cb537095a349.wav", "formula": "$\\frac{9}{11}\\times \\frac{7}{15}\\times \\frac{11}{3}$", "answer": "十一分之九乘十五分之七乘三分之十一", "subset": "mixmath", "task_type": "tts"} +{"index": 1497, "question": "请你朗读以下数学公式符号:$2+3+4+\\ldots +100=\\left( 2+100 \\right)\\times 99\\div 2=5049$", "audio_path": "audio/math_9dff85d7-ac1a-402a-a84d-23f4e605b791.wav", "formula": "$2+3+4+\\ldots +100=\\left( 2+100 \\right)\\times 99\\div 2=5049$", "answer": "二加三加四加 一直加到一百的和等于二加一百的和乘九十九的积的二分之一等于五千零四十九", "subset": "mixmath", "task_type": "tts"} +{"index": 1498, "question": "Please read the following math formula symbols: $D_{n}\\prod_{i=0}^{n}(x_{i}y_{i})\\in\\Z$", "audio_path": "audio/row_00947565_1755701701242184.wav", "formula": "$D_{n}\\prod_{i=0}^{n}(x_{i}y_{i})\\in\\Z$", "answer": "D sub n, product from i equals 0 to n, of x sub i times y sub i, belongs to Z.", "subset": "mixmath", "task_type": "tts"} +{"index": 1499, "question": "Please read the following math formula symbols: $\\min\\{r_1(y^*),r_2(y^*)\\}\\geq0.6503$", "audio_path": "audio/row_00594857_1755657636112730.wav", "formula": "$\\min\\{r_1(y^*),r_2(y^*)\\}\\geq0.6503$", "answer": "The minimum of r sub 1 times y star, and r sub 2 times y star, is greater than or equal to 0.6503.", "subset": "mixmath", "task_type": "tts"} +{"index": 1500, "question": "请你朗读以下数学公式符号:${{(1011)}_{2}}=1\\times {{2}^{3}}+0\\times {{2}^{2}}+1\\times {{2}^{1}}+1\\times {{2}^{0}}$", "audio_path": "audio/math_293c9134-22ab-4d75-b648-f1397aca2842.wav", "formula": "${{(1011)}_{2}}=1\\times {{2}^{3}}+0\\times {{2}^{2}}+1\\times {{2}^{1}}+1\\times {{2}^{0}}$", "answer": "二进制的一零一一等于一乘二的立方加零乘二的平方加一乘二的一次方加一乘二的零次方", "subset": "mixmath", "task_type": "tts"} +{"index": 1501, "question": "请你朗读以下数学公式符号:$\\left\\{ \\begin{array}{*{35}{l}} x=2+4k \\\\ y=1+3k \\end{array} \\right.$", "audio_path": "audio/math_04cd6fa6-2202-4d7b-8d58-62449b466889.wav", "formula": "$\\left\\{ \\begin{array}{*{35}{l}} x=2+4k \\\\ y=1+3k \\end{array} \\right.$", "answer": "x等于二加四k和y等于一加三k", "subset": "mixmath", "task_type": "tts"} +{"index": 1502, "question": "请你朗读以下数学公式符号:$2.5\\times\\dfrac{3}{7}\\times0.4\\times2\\dfrac{1}{3}$", "audio_path": "audio/math_8fb592d9-c560-4f6a-a9de-cdd1d8da0f4f.wav", "formula": "$2.5\\times\\dfrac{3}{7}\\times0.4\\times2\\dfrac{1}{3}$", "answer": "二点五乘七分之三乘零点四乘二又三分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 1503, "question": "请你朗读以下数学公式符号:$\\frac{13}{16}\\div \\frac{13}{8}=\\frac{13}{16}\\times \\frac{8}{13}=\\frac{1}{2}$", "audio_path": "audio/math_e2210304-8723-4f56-98d0-5b8c3025508f.wav", "formula": "$\\frac{13}{16}\\div \\frac{13}{8}=\\frac{13}{16}\\times \\frac{8}{13}=\\frac{1}{2}$", "answer": "十六分之十三除以八分之十三等于十六分之十三乘十三分之八等于二分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 1504, "question": "Please read the following math formula symbols: $u_0(x,y)=A\\,[\\,\\sech(q-x)+\\sech(q+x)\\,]$", "audio_path": "audio/row_01624812_1755786746962253.wav", "formula": "$u_0(x,y)=A\\,[\\,\\sech(q-x)+\\sech(q+x)\\,]$", "answer": "u sub 0 of x, y equals A times the quantity secant h of q minus x plus secant h of q plus x", "subset": "mixmath", "task_type": "tts"} +{"index": 1505, "question": "Please read the following math formula symbols: $\\Hom_{A[G_n]}(V,\\Ind_{N_n}^{G_n}\\psi_A)$", "audio_path": "audio/row_02051907_1755840692959347.wav", "formula": "$\\Hom_{A[G_n]}(V,\\Ind_{N_n}^{G_n}\\psi_A)$", "answer": "Hom sub A, G sub n, open parenthesis, V, comma, Ind sub N sub n, superscript G sub n, psi sub A, close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 1506, "question": "Please read the following math formula symbols: $F\\astg(x)=\\int_{\\SS}F(x\\cdoty)\\,g(y)d\\omega(y)$", "audio_path": "audio/row_01276875_1755742898390441.wav", "formula": "$F\\astg(x)=\\int_{\\SS}F(x\\cdoty)\\,g(y)d\\omega(y)$", "answer": "F star g of x equals the integral over S of F of x times y, g of y, d omega of y.", "subset": "mixmath", "task_type": "tts"} +{"index": 1507, "question": "请你朗读以下数学公式符号:${C}_{4}^{1}\\times {C}_{4}^{2}\\times {A}_{3}^{2}=144$", "audio_path": "audio/math_ea74ce93-f14a-49dc-94e2-19ac39a49e28.wav", "formula": "${C}_{4}^{1}\\times {C}_{4}^{2}\\times {A}_{3}^{2}=144$", "answer": "C四一乘C四二乘A三二等于一百四十四", "subset": "mixmath", "task_type": "tts"} +{"index": 1508, "question": "请你朗读以下数学公式符号:$$(1300+65)\\div 13=1300\\div 13+65\\div 13=100+5=105$$", "audio_path": "audio/math_e1047659-0d68-4ea6-863e-8fc7dc310bdb.wav", "formula": "$$(1300+65)\\div 13=1300\\div 13+65\\div 13=100+5=105$$", "answer": "一千三百加六十五的和除以十三等于一千三百除以十三加六十五除以十三等于一百加五等于一百零五", "subset": "mixmath", "task_type": "tts"} +{"index": 1509, "question": "Please read the following math formula symbols: $\\left(|H|^2_j\\right)^{\\order{\\alpha_s}}$", "audio_path": "audio/row_00747123_1755676592072905.wav", "formula": "$\\left(|H|^2_j\\right)^{\\order{\\alpha_s}}$", "answer": "Left parenthesis, absolute value of H squared sub j, right parenthesis, raised to the power of top of alpha sub s.", "subset": "mixmath", "task_type": "tts"} +{"index": 1510, "question": "请你朗读以下数学公式符号:$\\begin{cases}x+y=50 \\\\ 14x \\times 2=20y \\end{cases}$", "audio_path": "audio/math_e4a45df5-e26b-42e5-89cc-b82b8069093a.wav", "formula": "$\\begin{cases}x+y=50 \\\\ 14x \\times 2=20y \\end{cases}$", "answer": "x加y等于五十,十四x乘二等于二十y", "subset": "mixmath", "task_type": "tts"} +{"index": 1511, "question": "Please read the following math formula symbols: $=M^{(4f)}_{UI}(\\Theta_i,\\Phi_i))$", "audio_path": "audio/row_01413231_1755759984578000.wav", "formula": "$=M^{(4f)}_{UI}(\\Theta_i,\\Phi_i))$", "answer": "equals M to the power of four f, subscript U U, open parenthesis, Theta sub i, comma, Phi sub i, close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 1512, "question": "请你朗读以下数学公式符号:$$n!\\times \\left( n+1 \\right)=\\left( n+1 \\right)!$$", "audio_path": "audio/math_17a30a72-4a3d-471c-a250-97a47c5a594a.wav", "formula": "$$n!\\times \\left( n+1 \\right)=\\left( n+1 \\right)!$$", "answer": "n的阶乘 乘 n加一的和等于n加一的和的阶乘", "subset": "mixmath", "task_type": "tts"} +{"index": 1513, "question": "Please read the following math formula symbols: $\\gamma:=(\\deltaqq^{-1})g^{-1}$", "audio_path": "audio/row_00169688_1755605647097537.wav", "formula": "$\\gamma:=(\\deltaqq^{-1})g^{-1}$", "answer": "Gamma is defined as the product of delta q times q to the power of negative one, all multiplied by the inverse of g.", "subset": "mixmath", "task_type": "tts"} +{"index": 1514, "question": "请你朗读以下数学公式符号:$$\\left\\{\\begin{array}{c}x>m\\\\x>3\\end{array}\\right.$$", "audio_path": "audio/math_7fb9f9e3-3ef0-4f0b-874c-c120104458b3.wav", "formula": "$$\\left\\{\\begin{array}{c}x>m\\\\x>3\\end{array}\\right.$$", "answer": "x大于m,x大于三", "subset": "mixmath", "task_type": "tts"} +{"index": 1515, "question": "Please read the following math formula symbols: $\\ball:=\\left\\{y\\inS\\,\\vert\\,\\|y\\|_\\infty\\leq1\\right\\}$", "audio_path": "audio/row_01534519_1755775313347566.wav", "formula": "$\\ball:=\\left\\{y\\inS\\,\\vert\\,\\|y\\|_\\infty\\leq1\\right\\}$", "answer": "Mathcal is defined as the set of y in S such that the norm of y is sub infinity less than or equal to 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 1516, "question": "Please read the following math formula symbols: $\\cp'_1\\subseteq\\cp_1,\\cdots,\\cp'_n\\subseteq\\cp_n$", "audio_path": "audio/row_02092612_1755845883907370.wav", "formula": "$\\cp'_1\\subseteq\\cp_1,\\cdots,\\cp'_n\\subseteq\\cp_n$", "answer": "c p prime 1 is a subset of c p 1, dot dot dot, c p prime n is a subset of c p sub n.", "subset": "mixmath", "task_type": "tts"} +{"index": 1517, "question": "请你朗读以下数学公式符号:$\\cos B=\\frac{BC}{AB}=\\frac{5k}{13k}=\\frac{5}{13}$", "audio_path": "audio/math_aeb8eb4e-b850-4c05-8585-950deaf10843.wav", "formula": "$\\cos B=\\frac{BC}{AB}=\\frac{5k}{13k}=\\frac{5}{13}$", "answer": "cosine B等于A B分之B C等于十三k分之五k等于十三分之五", "subset": "mixmath", "task_type": "tts"} +{"index": 1518, "question": "请你朗读以下数学公式符号:$$67\\times 22+67\\times 77+67=67\\times \\left( 22+77+1 \\right)=67\\times 100=6700$$", "audio_path": "audio/math_60140bdc-f68f-4624-8ef0-977c9f34c7aa.wav", "formula": "$$67\\times 22+67\\times 77+67=67\\times \\left( 22+77+1 \\right)=67\\times 100=6700$$", "answer": "六十七乘二十二加六十七乘七十七加六十七等于六十七乘 二十二加七十七加一的和 等于六十七乘一百等于六千七百", "subset": "mixmath", "task_type": "tts"} +{"index": 1519, "question": "Please read the following math formula symbols: $\\frac{2}{1+e^{\\lvertY-Y^m_{B}\\rvert}}$", "audio_path": "audio/row_01370043_1755754538716005.wav", "formula": "$\\frac{2}{1+e^{\\lvertY-Y^m_{B}\\rvert}}$", "answer": "Fraction two over one plus e to the absolute value of Y minus Y to the power of m sub B.", "subset": "mixmath", "task_type": "tts"} +{"index": 1520, "question": "Please read the following math formula symbols: $Dy=y''+a_1(x,t)y'+a_2(x,t)=0$", "audio_path": "audio/row_00347411_1755627270058153.wav", "formula": "$Dy=y''+a_1(x,t)y'+a_2(x,t)=0$", "answer": "Dy equals y double prime plus a sub 1 of x, t times y prime plus a sub 2 of x, t equals 0.", "subset": "mixmath", "task_type": "tts"} +{"index": 1521, "question": "Please read the following math formula symbols: $u(t,\\{\\tspb\\raisebox\\{2pt;B)-u(t,0;B)\\deqB$", "audio_path": "audio/row_01691408_1755795150183281.wav", "formula": "$u(t,\\{\\tspb\\raisebox\\{2pt;B)-u(t,0;B)\\deqB$", "answer": "u of t, spb open box 2pt semicolon B close minus u of t comma 0 semicolon B is defined as B.", "subset": "mixmath", "task_type": "tts"} +{"index": 1522, "question": "Please read the following math formula symbols: $qE(t)\\dotz(t)\\rightarrow-q\\dotE(t)z(t)$", "audio_path": "audio/row_00579559_1755655719044980.wav", "formula": "$qE(t)\\dotz(t)\\rightarrow-q\\dotE(t)z(t)$", "answer": "q E of t times the derivative of z of t, goes to negative q times the derivative of E of t times z of t.", "subset": "mixmath", "task_type": "tts"} +{"index": 1523, "question": "Please read the following math formula symbols: $N\\ll(\\delta/M)^{-O(d)^{O(1)}}$", "audio_path": "audio/row_01270210_1755742033155779.wav", "formula": "$N\\ll(\\delta/M)^{-O(d)^{O(1)}}$", "answer": "N much less than delta over M to the power of negative O of d to the power of O of 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 1524, "question": "请你朗读以下数学公式符号:$$\\begin{eqnarray}&&\\frac{1}{8}\\times \\left[ \\frac{1}{2}\\div \\left( \\frac{3}{5}\\times \\frac{10}{9} \\right) \\right]\\\\ &=&\\frac{1}{8}\\times \\left( \\frac{1}{2}\\div \\frac{2}{3} \\right)\\\\ &=&\\frac{1}{8}\\times \\frac{3}{4}\\\\ &=&\\frac{3}{32}.\\end{eqnarray}$$", "audio_path": "audio/math_9618fef9-cfa6-4186-bfc4-8ce44aac3dc7.wav", "formula": "$$\\begin{eqnarray}&&\\frac{1}{8}\\times \\left[ \\frac{1}{2}\\div \\left( \\frac{3}{5}\\times \\frac{10}{9} \\right) \\right]\\\\ &=&\\frac{1}{8}\\times \\left( \\frac{1}{2}\\div \\frac{2}{3} \\right)\\\\ &=&\\frac{1}{8}\\times \\frac{3}{4}\\\\ &=&\\frac{3}{32}.\\end{eqnarray}$$", "answer": "八分之一乘二分之一除以五分之三乘九分之十的积的商等于八分之一乘二分之一除以三分之二的商等于八分之一乘四分之三等于三十二分之三", "subset": "mixmath", "task_type": "tts"} +{"index": 1525, "question": "请你朗读以下数学公式符号:$=({{x}^{4}}+{{x}^{3}}+{{x}^{2}})+(3{{x}^{2}}+3x+3)={{x}^{2}}({{x}^{2}}+x+1)+3({{x}^{2}}+x+1)=({{x}^{2}}+3)({{x}^{2}}+x+1)$", "audio_path": "audio/math_76e5ca37-0a27-4084-af85-62de4c55d065.wav", "formula": "$=({{x}^{4}}+{{x}^{3}}+{{x}^{2}})+(3{{x}^{2}}+3x+3)={{x}^{2}}({{x}^{2}}+x+1)+3({{x}^{2}}+x+1)=({{x}^{2}}+3)({{x}^{2}}+x+1)$", "answer": "等于x的四次方加x的三次方加x的平方的和 加 三乘x的平方加三x加三的和 等于 x的平方乘 x的平方加x加一的和 加三乘 x的平方加x加一的和 等于 x的平方加三的和乘 x的平方加x加一的和", "subset": "mixmath", "task_type": "tts"} +{"index": 1526, "question": "Please read the following math formula symbols: $A^{\\pi^{\\tiny{opt}}}(a,s)<0$", "audio_path": "audio/row_00096309_1755596763358131.wav", "formula": "$A^{\\pi^{\\tiny{opt}}}(a,s)<0$", "answer": "A to the power of pi to the power of opt, open parenthesis a comma s close parenthesis, is less than zero.", "subset": "mixmath", "task_type": "tts"} +{"index": 1527, "question": "请你朗读以下数学公式符号:$$7.8\\times \\left[ \\left( 0.6+8.9 \\right)\\div 0.25 \\right]$$", "audio_path": "audio/math_cfb50b71-abc5-4e5c-81c9-6f2b5fb981c3.wav", "formula": "$$7.8\\times \\left[ \\left( 0.6+8.9 \\right)\\div 0.25 \\right]$$", "answer": "七点八乘 零点六加八点九的和除以零点二五的商", "subset": "mixmath", "task_type": "tts"} +{"index": 1528, "question": "Please read the following math formula symbols: $D^i(S)\\subset\\horint^i_t$", "audio_path": "audio/row_01353821_1755752516808750.wav", "formula": "$D^i(S)\\subset\\horint^i_t$", "answer": "D raised to the power of i, open parenthesis S, close parenthesis, is a subset of the dual of i subscript t.", "subset": "mixmath", "task_type": "tts"} +{"index": 1529, "question": "请你朗读以下数学公式符号:$=\\frac{5}{14}\\div \\left[ \\frac{5}{26}\\times \\frac{13}{14} \\right]$", "audio_path": "audio/math_8d3e248a-2824-40d2-88f2-d5d2af67b0fc.wav", "formula": "$=\\frac{5}{14}\\div \\left[ \\frac{5}{26}\\times \\frac{13}{14} \\right]$", "answer": "等于十四分之五除以二十六分之五乘十四分之十三的积", "subset": "mixmath", "task_type": "tts"} +{"index": 1530, "question": "请你朗读以下数学公式符号:$\\frac{3}{11}\\div 6+\\frac{8}{11}\\times \\frac{1}{6}$", "audio_path": "audio/math_71b7157a-e5c3-4768-8efb-65f01914e93b.wav", "formula": "$\\frac{3}{11}\\div 6+\\frac{8}{11}\\times \\frac{1}{6}$", "answer": "十一分之三除以六加十一分之八乘六分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 1531, "question": "Please read the following math formula symbols: $(N_{X_3}(z_1)\\capN_{X_3}(z_2))=\\emptyset$", "audio_path": "audio/row_01896745_1755821119260591.wav", "formula": "$(N_{X_3}(z_1)\\capN_{X_3}(z_2))=\\emptyset$", "answer": "N sub X sub 3 of z sub 1 intersection N sub X sub 3 of z sub 2 equals empty set.", "subset": "mixmath", "task_type": "tts"} +{"index": 1532, "question": "Please read the following math formula symbols: $\\Vert\\p-f(\\p)\\Vert\\leq\\frac{L_fL_G}{\\gamma}$", "audio_path": "audio/row_01127034_1755724091990293.wav", "formula": "$\\Vert\\p-f(\\p)\\Vert\\leq\\frac{L_fL_G}{\\gamma}$", "answer": "Double vertical bar p minus f of p double vertical bar is less than or equal to L sub f L sub G divided by gamma.", "subset": "mixmath", "task_type": "tts"} +{"index": 1533, "question": "Please read the following math formula symbols: $\\left\\Vert\\hat{U}-U\\right\\Vert=O_p(n^{-\\Delta})$", "audio_path": "audio/row_00044946_1755590555977601.wav", "formula": "$\\left\\Vert\\hat{U}-U\\right\\Vert=O_p(n^{-\\Delta})$", "answer": "The norm of the difference between the estimated U and U is equal to big O sub p of n to the power of negative delta.", "subset": "mixmath", "task_type": "tts"} +{"index": 1534, "question": "请你朗读以下数学公式符号:$\\frac{24}{32}=\\frac{(\\begin{matrix} { } \\end{matrix})}{4}$", "audio_path": "audio/math_2660f1ed-b927-4f03-bb2c-a6f8ddf263f3.wav", "formula": "$\\frac{24}{32}=\\frac{(\\begin{matrix} { } \\end{matrix})}{4}$", "answer": "三十二分之二十四等于四分之多少", "subset": "mixmath", "task_type": "tts"} +{"index": 1535, "question": "请你朗读以下数学公式符号:${{S}_{124}}+{{S}_{234}}+{{S}_{341}}={{S}_{125}}+{{S}_{235}}+{{S}_{351}}$", "audio_path": "audio/math_006183ea-bc2d-448c-a69b-d66c4db728aa.wav", "formula": "${{S}_{124}}+{{S}_{234}}+{{S}_{341}}={{S}_{125}}+{{S}_{235}}+{{S}_{351}}$", "answer": "S 一百二十四加S 二百三十四加S 三百四十一等于S一百二十五加S 二百三十五加S 三百五十一", "subset": "mixmath", "task_type": "tts"} +{"index": 1536, "question": "请你朗读以下数学公式符号:$$\\frac{7}{999}\\times 35+\\frac{7}{999}\\times 26+\\frac{7}{999}\\times 50=\\frac{7}{999}\\times (35+26+50)=\\frac{7}{9}$$", "audio_path": "audio/math_98f6f9ae-65d5-4a3d-9cd3-d48f45c1e099.wav", "formula": "$$\\frac{7}{999}\\times 35+\\frac{7}{999}\\times 26+\\frac{7}{999}\\times 50=\\frac{7}{999}\\times (35+26+50)=\\frac{7}{9}$$", "answer": "九百九十九分之七乘三十五加九百九十九分之七乘二十六加九百九十九分之七乘五十等于九百九十九分之七乘三十五加二十六加五十的和等于九分之七", "subset": "mixmath", "task_type": "tts"} +{"index": 1537, "question": "请你朗读以下数学公式符号:${{x}_{2}}\\left( {{x}_{1}}\\leqslant {{x}_{2}} \\right)$", "audio_path": "audio/math_825c779d-ec11-4cdf-ad61-8f63708a8742.wav", "formula": "${{x}_{2}}\\left( {{x}_{1}}\\leqslant {{x}_{2}} \\right)$", "answer": "x二,x一小于等于x二", "subset": "mixmath", "task_type": "tts"} +{"index": 1538, "question": "Please read the following math formula symbols: $\\sigma(a+m\\varepsilon_1+n\\varepsilon_2)=a+(m+n)\\varepsilon$", "audio_path": "audio/row_00226259_1755612530261166.wav", "formula": "$\\sigma(a+m\\varepsilon_1+n\\varepsilon_2)=a+(m+n)\\varepsilon$", "answer": "Sigma of a plus m epsilon one plus n epsilon two equals a plus the quantity m plus n times epsilon.", "subset": "mixmath", "task_type": "tts"} +{"index": 1539, "question": "请你朗读以下数学公式符号:$$\\frac{2}{3}+\\frac{3}{5}+\\frac{5}{7}+\\frac{8}{15}+\\frac{12}{35}+\\frac{17}{70}+\\frac{9}{10}=$$", "audio_path": "audio/math_9efcf814-029d-48a9-8d6b-92aad9b3ff65.wav", "formula": "$$\\frac{2}{3}+\\frac{3}{5}+\\frac{5}{7}+\\frac{8}{15}+\\frac{12}{35}+\\frac{17}{70}+\\frac{9}{10}=$$", "answer": "三分之二加上五分之三加上七分之五加上十五分之八加上三十五分之十二加上七十分之十七加上十分之九等于", "subset": "mixmath", "task_type": "tts"} +{"index": 1540, "question": "Please read the following math formula symbols: $[t_0t_1^{-1}\\cdotst_q^{-1}]$", "audio_path": "audio/row_00235673_1755613662277024.wav", "formula": "$[t_0t_1^{-1}\\cdotst_q^{-1}]$", "answer": "t sub 0 times t sub 1 to the power of negative 1 dot dot dot t sub q to the power of negative 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 1541, "question": "Please read the following math formula symbols: $a_1=a_2=b=c_1=c_2=r_s$", "audio_path": "audio/row_01233379_1755737451892661.wav", "formula": "$a_1=a_2=b=c_1=c_2=r_s$", "answer": "a sub 1 equals a sub 2 equals b equals c sub 1 equals c sub 2 equals r sub s", "subset": "mixmath", "task_type": "tts"} +{"index": 1542, "question": "Please read the following math formula symbols: $\\vert\\deltax_{i}|=\\vertx_{i}|\\mathcal{O}(\\varepsilon_{w})$", "audio_path": "audio/row_00712352_1755672242497819.wav", "formula": "$\\vert\\deltax_{i}|=\\vertx_{i}|\\mathcal{O}(\\varepsilon_{w})$", "answer": "Absolute value of delta x sub i equals absolute value of x sub i times capital O of epsilon sub w.", "subset": "mixmath", "task_type": "tts"} +{"index": 1543, "question": "Please read the following math formula symbols: $G=\\frac{R^4}{150\\ln\\frac{4K}{\\delta}}$", "audio_path": "audio/row_01856805_1755816063820250.wav", "formula": "$G=\\frac{R^4}{150\\ln\\frac{4K}{\\delta}}$", "answer": "G equals R to the power of 4 divided by 150 times the natural logarithm of 4 times K divided by delta.", "subset": "mixmath", "task_type": "tts"} +{"index": 1544, "question": "请你朗读以下数学公式符号:${{\\left( x+y \\right)}^{2}}={{x}^{2}}{+}2xy+{{y}^{2}}$", "audio_path": "audio/math_fdccc6ce-e965-4206-b822-0a3d1e7a5ad2.wav", "formula": "${{\\left( x+y \\right)}^{2}}={{x}^{2}}{+}2xy+{{y}^{2}}$", "answer": "x加y的和的平方等于x的平方加二x y加y的平方", "subset": "mixmath", "task_type": "tts"} +{"index": 1545, "question": "Please read the following math formula symbols: $h-\\sum_{T\\inC_4\\cupC'}|I(T)|>2$", "audio_path": "audio/row_01776586_1755805926363891.wav", "formula": "$h-\\sum_{T\\inC_4\\cupC'}|I(T)|>2$", "answer": "h minus the summation over T in C sub 4 union C prime of the absolute value of I of T is greater than 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 1546, "question": "请你朗读以下数学公式符号:$$2\\vec{a}+\\frac{1}{3}\\left( \\vec{a}+\\vec{b} \\right)=$$", "audio_path": "audio/math_202f72a8-eb22-40bf-89eb-ee9eca3da9e5.wav", "formula": "$$2\\vec{a}+\\frac{1}{3}\\left( \\vec{a}+\\vec{b} \\right)=$$", "answer": "二倍的向量a加三分之一乘向量a与向量b的和等于", "subset": "mixmath", "task_type": "tts"} +{"index": 1547, "question": "Please read the following math formula symbols: $(1+\\log{y})^4\\geq\\log{y}$", "audio_path": "audio/row_01480934_1755768552790431.wav", "formula": "$(1+\\log{y})^4\\geq\\log{y}$", "answer": "Open parenthesis, one plus log y, close parenthesis, raised to the power of four, greater than or equal to log y.", "subset": "mixmath", "task_type": "tts"} +{"index": 1548, "question": "请你朗读以下数学公式符号:$=(\\frac{16}{7}+\\frac{28}{9}+\\frac{24}{11}+\\frac{48}{13})\\div (\\frac{4}{7}+\\frac{7}{9}+\\frac{6}{11}+\\frac{12}{13})=4$", "audio_path": "audio/math_998f6eb1-88b9-48e1-80f4-7c86795e3e9d.wav", "formula": "$=(\\frac{16}{7}+\\frac{28}{9}+\\frac{24}{11}+\\frac{48}{13})\\div (\\frac{4}{7}+\\frac{7}{9}+\\frac{6}{11}+\\frac{12}{13})=4$", "answer": "等于七分之十六加九分之二十八加十一分之二十四加十三分之四十八的和除以七分之四加九分之七加十一分之六加十三分之十二的和等于四", "subset": "mixmath", "task_type": "tts"} +{"index": 1549, "question": "请你朗读以下数学公式符号:$\\Rightarrow \\begin{cases}m= \\pm 1 \\\\ m\\ne 1 \\end{cases}$", "audio_path": "audio/math_48aa5778-1ba1-4734-91d5-8f2a7f94ed4b.wav", "formula": "$\\Rightarrow \\begin{cases}m= \\pm 1 \\\\ m\\ne 1 \\end{cases}$", "answer": "推出m等于正负一,且m不等于一", "subset": "mixmath", "task_type": "tts"} +{"index": 1550, "question": "请你朗读以下数学公式符号:${{\\left( {{a}^{2}} \\right)}^{3}}={{a}^{2\\times 3}}={{a}^{6}}$", "audio_path": "audio/math_c1a5857c-159b-4934-8a1f-0048a8db4545.wav", "formula": "${{\\left( {{a}^{2}} \\right)}^{3}}={{a}^{2\\times 3}}={{a}^{6}}$", "answer": "a的平方的三次方等于a的二乘三次方等于a的六次方", "subset": "mixmath", "task_type": "tts"} +{"index": 1551, "question": "Please read the following math formula symbols: $10B_{\\wh{Q_j}}\\capE_R^1\\neq\\emptyset$", "audio_path": "audio/row_01232607_1755737361617506.wav", "formula": "$10B_{\\wh{Q_j}}\\capE_R^1\\neq\\emptyset$", "answer": "Ten times B sub the quotient of Q sub j intersect E sub R superscript one is not equal to empty set.", "subset": "mixmath", "task_type": "tts"} +{"index": 1552, "question": "请你朗读以下数学公式符号:$\\begin{eqnarray} 34:x&=&0.25:8\\\\ 0.25x&=&34\\times 8\\\\ 0.25x\\div 0.25&=&34\\times 8\\div 0.25\\\\ x&=&1088.\\end{eqnarray}$", "audio_path": "audio/math_b81df929-cf86-406f-8fbc-59f530258cc6.wav", "formula": "$\\begin{eqnarray} 34:x&=&0.25:8\\\\ 0.25x&=&34\\times 8\\\\ 0.25x\\div 0.25&=&34\\times 8\\div 0.25\\\\ x&=&1088.\\end{eqnarray}$", "answer": "三十四比x等于零点二五比八。零点二五x等于三十四乘八。零点二五x除以零点二五等于三十四乘八除以零点二五。x等于一千零八十八。", "subset": "mixmath", "task_type": "tts"} +{"index": 1553, "question": "Please read the following math formula symbols: $[j\\sqrt{2\\gamma_e}~j\\sqrt{2\\gamma_e}]$", "audio_path": "audio/row_02001042_1755834275804706.wav", "formula": "$[j\\sqrt{2\\gamma_e}~j\\sqrt{2\\gamma_e}]$", "answer": "Open bracket, j, square root of 2 gamma e, space, tilde, space, j, square root of 2 gamma e, close bracket.", "subset": "mixmath", "task_type": "tts"} +{"index": 1554, "question": "Please read the following math formula symbols: $\\ex{n|\\hat{S}_q^-|\\Psi}$", "audio_path": "audio/row_01095718_1755720185700022.wav", "formula": "$\\ex{n|\\hat{S}_q^-|\\Psi}$", "answer": "Exponential of n times the absolute value of S hat sub q to the power of negative absolute value of Psi.", "subset": "mixmath", "task_type": "tts"} +{"index": 1555, "question": "Please read the following math formula symbols: $P_{S_1\\cupS_{\\star}}\\leqP_{S_2\\cupS_{\\star}}$", "audio_path": "audio/row_01674538_1755793031912371.wav", "formula": "$P_{S_1\\cupS_{\\star}}\\leqP_{S_2\\cupS_{\\star}}$", "answer": "P sub S sub 1 union S sub star is less than or equal to P sub S sub 2 union S sub star.", "subset": "mixmath", "task_type": "tts"} +{"index": 1556, "question": "请你朗读以下数学公式符号:$\\begin{cases}1013=77b+r \\\\ r<{}b \\end{cases}\\Rightarrow \\begin{cases}b=13 \\\\ r=12 \\end{cases}$", "audio_path": "audio/math_b67d1b63-3976-40f2-b28b-ff2fbcc7c30c.wav", "formula": "$\\begin{cases}1013=77b+r \\\\ r<{}b \\end{cases}\\Rightarrow \\begin{cases}b=13 \\\\ r=12 \\end{cases}$", "answer": "一千零一十三等于七十七b加r,r小于b 推出 b等于十三,r等于十二", "subset": "mixmath", "task_type": "tts"} +{"index": 1557, "question": "Please read the following math formula symbols: $q=3e^{-\\frac{x_1^2+x_2^2}{10}}$", "audio_path": "audio/row_01180787_1755730844852129.wav", "formula": "$q=3e^{-\\frac{x_1^2+x_2^2}{10}}$", "answer": "q equals 3 times e to the power of negative the quantity x sub 1 squared plus x sub 2 squared divided by 10.", "subset": "mixmath", "task_type": "tts"} +{"index": 1558, "question": "请你朗读以下数学公式符号:$2\\times 2\\times 6=24\\left( {d} {m}^{2} \\right)$", "audio_path": "audio/math_cdd7220a-eb1f-438c-9af0-f5dcab61c676.wav", "formula": "$2\\times 2\\times 6=24\\left( {d} {m}^{2} \\right)$", "answer": "二乘二乘六等于二十四平方分米", "subset": "mixmath", "task_type": "tts"} +{"index": 1559, "question": "Please read the following math formula symbols: $\\vec{b}^{p,-n}\\inE_0^p$", "audio_path": "audio/row_00887521_1755694208857817.wav", "formula": "$\\vec{b}^{p,-n}\\inE_0^p$", "answer": "Vector b raised to the power of p, negative n, belongs to the set E sub 0 raised to the power of p.", "subset": "mixmath", "task_type": "tts"} +{"index": 1560, "question": "请你朗读以下数学公式符号:$$=\\left( \\frac{104}{99}+\\frac{104}{33}+\\frac{104}{11} \\right)\\div \\left( \\frac{100}{99}+\\frac{100}{33}+\\frac{100}{11} \\right)=\\frac{104}{100}=\\frac{26}{25}$$", "audio_path": "audio/math_f632f777-5a66-4ec6-b5f2-455523ae58d8.wav", "formula": "$$=\\left( \\frac{104}{99}+\\frac{104}{33}+\\frac{104}{11} \\right)\\div \\left( \\frac{100}{99}+\\frac{100}{33}+\\frac{100}{11} \\right)=\\frac{104}{100}=\\frac{26}{25}$$", "answer": "等于九十九分之一百零四加三十三分之一百零四加十一分之一百零四的和除以九十九分之一百加三十三分之一百加十一分之一百的和等于一百分之一百零四等于二十五分之二十六", "subset": "mixmath", "task_type": "tts"} +{"index": 1561, "question": "Please read the following math formula symbols: $\\#\\mathcal{P}_{r,m}(k)\\leq(C_2)^{k}$", "audio_path": "audio/row_00114591_1755598945441090.wav", "formula": "$\\#\\mathcal{P}_{r,m}(k)\\leq(C_2)^{k}$", "answer": "Probability of event P sub r comma m of k is less than or equal to C sub 2 raised to the power of k.", "subset": "mixmath", "task_type": "tts"} +{"index": 1562, "question": "请你朗读以下数学公式符号:$$({{367}^{367}}+{{762}^{762}})\\times {{123}^{123}}$$", "audio_path": "audio/math_72bc0501-dd18-41dd-9dab-35af5b93c383.wav", "formula": "$$({{367}^{367}}+{{762}^{762}})\\times {{123}^{123}}$$", "answer": "三百六十七的三百六十七次方加七百六十二的七百六十二次方的和乘一百二十三的一百二十三次方", "subset": "mixmath", "task_type": "tts"} +{"index": 1563, "question": "Please read the following math formula symbols: $h(y_2)-h(x_2)=-h(y_1)+h(x_1)$", "audio_path": "audio/row_01376101_1755755313577222.wav", "formula": "$h(y_2)-h(x_2)=-h(y_1)+h(x_1)$", "answer": "h of y sub 2 minus h of x sub 2 equals negative h of y sub 1 plus h of x sub 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 1564, "question": "请你朗读以下数学公式符号:$$=\\left( \\frac{1}{8}+\\frac{3}{5} \\right)\\times \\frac{33}{87}\\times \\frac{10}{11}$$", "audio_path": "audio/math_3e4ea0bb-9861-4fba-963a-34fbf4267827.wav", "formula": "$$=\\left( \\frac{1}{8}+\\frac{3}{5} \\right)\\times \\frac{33}{87}\\times \\frac{10}{11}$$", "answer": "等于八分之一与五分之三的和乘八十七分之三十三乘十一分之十", "subset": "mixmath", "task_type": "tts"} +{"index": 1565, "question": "Please read the following math formula symbols: $|C\\cap\\mathfrak{nb}_G(i_0)|=1$", "audio_path": "audio/row_00243710_1755614634403256.wav", "formula": "$|C\\cap\\mathfrak{nb}_G(i_0)|=1$", "answer": "The cardinality of the intersection between set C and the neighborhood of vertex i sub 0 in graph G is equal to 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 1566, "question": "Please read the following math formula symbols: $|S_{km}|^{2}=|V_{k}|^{2}|I_{km}|^{2}$", "audio_path": "audio/row_02026750_1755837530047697.wav", "formula": "$|S_{km}|^{2}=|V_{k}|^{2}|I_{km}|^{2}$", "answer": "Absolute value of S sub k squared equals absolute value of V sub k squared times absolute value of I sub k squared.", "subset": "mixmath", "task_type": "tts"} +{"index": 1567, "question": "Please read the following math formula symbols: $\\Gamma^{\\mu}:=f^{\\mu}\\circ\\Gamma\\circ(f^{\\mu})^{-1}$", "audio_path": "audio/row_01818879_1755811278297789.wav", "formula": "$\\Gamma^{\\mu}:=f^{\\mu}\\circ\\Gamma\\circ(f^{\\mu})^{-1}$", "answer": "Gamma to the power mu is equal to f to the power mu circle Gamma circle f to the power mu inverse.", "subset": "mixmath", "task_type": "tts"} +{"index": 1568, "question": "Please read the following math formula symbols: $|\\logh_{\\ell_0}|/(nh_{\\ell_0}^d)\\to0$", "audio_path": "audio/row_01423396_1755761299444871.wav", "formula": "$|\\logh_{\\ell_0}|/(nh_{\\ell_0}^d)\\to0$", "answer": "Absolute value of log h sub ell sub 0 divided by n h sub ell sub 0 to the power of d goes to zero.", "subset": "mixmath", "task_type": "tts"} +{"index": 1569, "question": "Please read the following math formula symbols: $\\mathcal{C}:=\\bigcup_{i=1}^{16\\ln\\nn}\\mathcal{C}_i$", "audio_path": "audio/row_00979707_1755705695866679.wav", "formula": "$\\mathcal{C}:=\\bigcup_{i=1}^{16\\ln\\nn}\\mathcal{C}_i$", "answer": "Mathcal C is defined as the union from i equals 1 to 16 of the natural logarithm of n times Mathcal C sub i.", "subset": "mixmath", "task_type": "tts"} +{"index": 1570, "question": "请你朗读以下数学公式符号:$\\left( 12\\times 10+10\\times 10+12\\times 10 \\right)\\times 2=680$", "audio_path": "audio/math_5d7bd81c-a075-4905-863b-65ad02280044.wav", "formula": "$\\left( 12\\times 10+10\\times 10+12\\times 10 \\right)\\times 2=680$", "answer": "十二乘十加十乘十加十二乘十的和乘二等于六百八十", "subset": "mixmath", "task_type": "tts"} +{"index": 1571, "question": "请你朗读以下数学公式符号:${1}^{{3}}{+}{2}^{{3}}{+}{3}^{{3}}{=}\\left({1+2+3}\\right)^{{2}}{=}{6}^{{2}}$", "audio_path": "audio/math_a4d981f7-e5f8-493b-a834-9e6e3c807299.wav", "formula": "${1}^{{3}}{+}{2}^{{3}}{+}{3}^{{3}}{=}\\left({1+2+3}\\right)^{{2}}{=}{6}^{{2}}$", "answer": "一的立方加二的立方加三的立方等于一加二加三的和的平方等于六的平方", "subset": "mixmath", "task_type": "tts"} +{"index": 1572, "question": "Please read the following math formula symbols: $0.0<(H-K_{s})<2.0\\\\rmmag$", "audio_path": "audio/row_00593541_1755657475969996.wav", "formula": "$0.0<(H-K_{s})<2.0\\\\rmmag$", "answer": "Zero point zero is less than the quantity H minus K sub s, which is less than two point zero mag.", "subset": "mixmath", "task_type": "tts"} +{"index": 1573, "question": "Please read the following math formula symbols: $15B^i\\cap15B^j\\neq\\emptyset$", "audio_path": "audio/row_01227078_1755736660840896.wav", "formula": "$15B^i\\cap15B^j\\neq\\emptyset$", "answer": "15 B raised to the power of i intersect 15 B raised to the power of j is not equal to empty set.", "subset": "mixmath", "task_type": "tts"} +{"index": 1574, "question": "Please read the following math formula symbols: $g_xA_{\\Theta_x}\\capg_zA_{\\Theta_z}\\neq\\emptyset$", "audio_path": "audio/row_01094549_1755720031468417.wav", "formula": "$g_xA_{\\Theta_x}\\capg_zA_{\\Theta_z}\\neq\\emptyset$", "answer": "g sub x A sub Theta sub x intersection g sub z A sub Theta sub z is not equal to empty set.", "subset": "mixmath", "task_type": "tts"} +{"index": 1575, "question": "请你朗读以下数学公式符号:$\\begin{eqnarray} \\left( 57+x \\right)\\times 8&=&960\\\\ x&=&63\\end{eqnarray}$", "audio_path": "audio/math_d6c8efb2-6d6e-4526-bc30-123046b1061c.wav", "formula": "$\\begin{eqnarray} \\left( 57+x \\right)\\times 8&=&960\\\\ x&=&63\\end{eqnarray}$", "answer": "五十七加x的和乘八等于九百六十 x等于六十三", "subset": "mixmath", "task_type": "tts"} +{"index": 1576, "question": "请你朗读以下数学公式符号:$$\\begin{eqnarray}&&30+169+70\\\\ &=&30+70+169\\\\ &=&100+169\\\\ &=&269.\\end{eqnarray}$$", "audio_path": "audio/math_970d2336-56ac-475d-96d9-6095eabac0bd.wav", "formula": "$$\\begin{eqnarray}&&30+169+70\\\\ &=&30+70+169\\\\ &=&100+169\\\\ &=&269.\\end{eqnarray}$$", "answer": "三十加一百六十九加七十等于三十加七十加一百六十九等于一百加一百六十九等于二百六十九", "subset": "mixmath", "task_type": "tts"} +{"index": 1577, "question": "请你朗读以下数学公式符号:$(100+115+135+140+ 180+197+203+230+x+y) = 157 \\times 10 = 1570$", "audio_path": "audio/math_ce530675-41bd-45e6-bdc1-d106d347fcd4.wav", "formula": "$(100+115+135+140+ 180+197+203+230+x+y) = 157 \\times 10 = 1570$", "answer": "一百加一百一十五加一百三十五加一百四十加一百八十加一百九十七加二百零三加二百三十加x加y的和等于一百五十七乘十等于一千五百七十", "subset": "mixmath", "task_type": "tts"} +{"index": 1578, "question": "Please read the following math formula symbols: $j=E(G(t_k-0))\\setminusE(G(t_k+0))$", "audio_path": "audio/row_00721244_1755673359470520.wav", "formula": "$j=E(G(t_k-0))\\setminusE(G(t_k+0))$", "answer": "j equals E of G of t sub k minus zero, set minus E of G of t sub k plus zero.", "subset": "mixmath", "task_type": "tts"} +{"index": 1579, "question": "Please read the following math formula symbols: $\\phi(D,[x+l+1,x+l+k-k'])$", "audio_path": "audio/row_01508209_1755771988372972.wav", "formula": "$\\phi(D,[x+l+1,x+l+k-k'])$", "answer": "Phi of D, open square bracket, x plus l plus 1, comma, x plus l plus k minus k prime, close square bracket.", "subset": "mixmath", "task_type": "tts"} +{"index": 1580, "question": "请你朗读以下数学公式符号:$\\begin{cases}x+y=20 \\\\ 8x+5x\\geqslant 148 \\\\ y\\geqslant 2. \\end{cases}$", "audio_path": "audio/math_3b701f2b-6e08-4b83-806b-f99cdd65f2d6.wav", "formula": "$\\begin{cases}x+y=20 \\\\ 8x+5x\\geqslant 148 \\\\ y\\geqslant 2. \\end{cases}$", "answer": "x加y等于二十,八x加五x大于等于一百四十八,y大于等于二。", "subset": "mixmath", "task_type": "tts"} +{"index": 1581, "question": "请你朗读以下数学公式符号:$\\left\\{ \\begin{matrix}a=8 \\\\ b=4 \\\\\\end{matrix} \\right.$", "audio_path": "audio/math_f478e578-76a8-405a-b7bc-29dffefeaf8f.wav", "formula": "$\\left\\{ \\begin{matrix}a=8 \\\\ b=4 \\\\\\end{matrix} \\right.$", "answer": "a等于八,b等于四", "subset": "mixmath", "task_type": "tts"} +{"index": 1582, "question": "Please read the following math formula symbols: $\\varphi(x)=\\sqrt{\\rho(x)}e^{i\\phi(x)}$", "audio_path": "audio/row_00340252_1755626390793470.wav", "formula": "$\\varphi(x)=\\sqrt{\\rho(x)}e^{i\\phi(x)}$", "answer": "Phi of x equals the square root of rho of x times e to the power of i times phi of x.", "subset": "mixmath", "task_type": "tts"} +{"index": 1583, "question": "Please read the following math formula symbols: $\\barf(z,r)=(f_r(z),r+\\frac{l}{k})$", "audio_path": "audio/row_02054501_1755841016701016.wav", "formula": "$\\barf(z,r)=(f_r(z),r+\\frac{l}{k})$", "answer": "Bar f of z, r equals open parenthesis f sub r of z, r plus l divided by k close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 1584, "question": "请你朗读以下数学公式符号:$\\frac{1}{4}=\\frac{1\\times 10}{4\\times 10}=\\frac{10}{40}=10\\div 40$", "audio_path": "audio/math_dd3cdfb8-f46f-4ff5-9350-36a235bbef4c.wav", "formula": "$\\frac{1}{4}=\\frac{1\\times 10}{4\\times 10}=\\frac{10}{40}=10\\div 40$", "answer": "四分之一等于四乘十的积分之一乘十的积等于四十分之十等于十除以四十", "subset": "mixmath", "task_type": "tts"} +{"index": 1585, "question": "Please read the following math formula symbols: $\\log_{2}\\frac{1}{p(y\\vertx,b)}-E_{b}^{x}$", "audio_path": "audio/row_00272924_1755618213375364.wav", "formula": "$\\log_{2}\\frac{1}{p(y\\vertx,b)}-E_{b}^{x}$", "answer": "Log base 2 of the fraction one divided by p of y given x, b, minus E of b raised to the power of x.", "subset": "mixmath", "task_type": "tts"} +{"index": 1586, "question": "Please read the following math formula symbols: $\\frac{|\\{\\cal\\A'|}{|\\{\\cal\\O'|}\\leq8$", "audio_path": "audio/row_00780545_1755680763783260.wav", "formula": "$\\frac{|\\{\\cal\\A'|}{|\\{\\cal\\O'|}\\leq8$", "answer": "The absolute value of the set A prime divided by the absolute value of the set O prime is less than or equal to 8.", "subset": "mixmath", "task_type": "tts"} +{"index": 1587, "question": "请你朗读以下数学公式符号:$ab{{\\left( a+b \\right)}^{2}}+{{\\left( a+b \\right)}^{2}}+1$", "audio_path": "audio/math_5bf39800-6929-4dd1-9856-be1238a30663.wav", "formula": "$ab{{\\left( a+b \\right)}^{2}}+{{\\left( a+b \\right)}^{2}}+1$", "answer": "ab乘a加b的和的平方,加a加b的和的平方加一", "subset": "mixmath", "task_type": "tts"} +{"index": 1588, "question": "请你朗读以下数学公式符号:$20\\times \\left( 1+\\frac{5}{7} \\right)=\\frac{240}{7}$", "audio_path": "audio/math_777f6b9e-81df-4049-bee3-f4c5b4fb58ae.wav", "formula": "$20\\times \\left( 1+\\frac{5}{7} \\right)=\\frac{240}{7}$", "answer": "二十乘一加七分之五的和等于七分之二百四十", "subset": "mixmath", "task_type": "tts"} +{"index": 1589, "question": "请你朗读以下数学公式符号:$=\\left( 2\\times 3\\times 1111111 \\right)\\times \\left( 2\\times 3\\times 11111111 \\right)$", "audio_path": "audio/math_4880d4f7-a1ba-4fe9-95d6-205110979170.wav", "formula": "$=\\left( 2\\times 3\\times 1111111 \\right)\\times \\left( 2\\times 3\\times 11111111 \\right)$", "answer": "等于二乘三乘一百一十一万一千一百一十一的积乘二乘三乘一千一百一十一万一千一百一十一的积", "subset": "mixmath", "task_type": "tts"} +{"index": 1590, "question": "Please read the following math formula symbols: $\\sup_{s\\in\\left[a,t\\right]}\\|V_s\\|(K)<\\infty$", "audio_path": "audio/row_01902341_1755821814996080.wav", "formula": "$\\sup_{s\\in\\left[a,t\\right]}\\|V_s\\|(K)<\\infty$", "answer": "Supremum over s in the interval from a to t of the norm of V sub s of K is less than infinity.", "subset": "mixmath", "task_type": "tts"} +{"index": 1591, "question": "Please read the following math formula symbols: $$\\frac{\\partialh_{k,A,\\rho}}{\\partialx^{*}}=0.$$", "audio_path": "audio/row_00911648_1755697226558005.wav", "formula": "$$\\frac{\\partialh_{k,A,\\rho}}{\\partialx^{*}}=0.$$", "answer": "Fraction, partial derivative of h sub k comma A comma rho with respect to partial derivative of x star equals 0.", "subset": "mixmath", "task_type": "tts"} +{"index": 1592, "question": "Please read the following math formula symbols: $\\bigoplus_{y\\in\\Irr(\\cX)}\\mathcal{X}(xs\\toy)$", "audio_path": "audio/row_00733844_1755674924879115.wav", "formula": "$\\bigoplus_{y\\in\\Irr(\\cX)}\\mathcal{X}(xs\\toy)$", "answer": "Big O plus, subscript y in the interval from c times X to y, of X of x s arrow y.", "subset": "mixmath", "task_type": "tts"} +{"index": 1593, "question": "请你朗读以下数学公式符号:$$\\left\\{\\begin{array}{c}2x+y=5\\\\x+2y=4\\end{array}\\right.$$", "audio_path": "audio/math_41e27ab8-f1f2-4e3d-a8fc-cf5b6d611d27.wav", "formula": "$$\\left\\{\\begin{array}{c}2x+y=5\\\\x+2y=4\\end{array}\\right.$$", "answer": "二x加y等于五,x加二y等于四", "subset": "mixmath", "task_type": "tts"} +{"index": 1594, "question": "请你朗读以下数学公式符号:$V={{3}^{2}}\\times 3.14\\times 2\\div 3=18.84({d}{{{m}}^{3}})$", "audio_path": "audio/math_74d68668-eb38-4b2f-a7a3-0b27015ad88a.wav", "formula": "$V={{3}^{2}}\\times 3.14\\times 2\\div 3=18.84({d}{{{m}}^{3}})$", "answer": "V等于三的平方乘三点一四乘二除以三等于十八点八四立方分米", "subset": "mixmath", "task_type": "tts"} +{"index": 1595, "question": "Please read the following math formula symbols: $p(k;\\lambda)=e^{-\\lambda}\\tfrac{\\lambda^{k}}{k!}$", "audio_path": "audio/row_01081007_1755718354251001.wav", "formula": "$p(k;\\lambda)=e^{-\\lambda}\\tfrac{\\lambda^{k}}{k!}$", "answer": "p of k, lambda equals e to the power of negative lambda, divided by k factorial times lambda to the power of k.", "subset": "mixmath", "task_type": "tts"} +{"index": 1596, "question": "Please read the following math formula symbols: $f_1/k+\\cdots+f_1/k+f_2+\\cdots+f_n$", "audio_path": "audio/row_00564589_1755653857850690.wav", "formula": "$f_1/k+\\cdots+f_1/k+f_2+\\cdots+f_n$", "answer": "f one over k plus dot dot dot plus f one over k plus f two plus dot dot dot plus f n", "subset": "mixmath", "task_type": "tts"} +{"index": 1597, "question": "请你朗读以下数学公式符号:$$\\frac{3}{8}=\\frac{3\\times 3}{8\\times 3}=\\frac{9}{24}$$", "audio_path": "audio/math_29cdbb84-6018-4c2a-b54b-1a09e0925264.wav", "formula": "$$\\frac{3}{8}=\\frac{3\\times 3}{8\\times 3}=\\frac{9}{24}$$", "answer": "八分之三等于八乘三的积分之三乘三的积等于二十四分之九", "subset": "mixmath", "task_type": "tts"} +{"index": 1598, "question": "请你朗读以下数学公式符号:$12.13^\\circ =12^\\circ {{7.8}^{\\prime }}=12^\\circ {{7}^{\\prime }}{48}^{\\prime\\prime }$", "audio_path": "audio/math_303bf713-c270-4e44-8855-35440179c79a.wav", "formula": "$12.13^\\circ =12^\\circ {{7.8}^{\\prime }}=12^\\circ {{7}^{\\prime }}{48}^{\\prime\\prime }$", "answer": "十二点一三度等于十二度七点八分等于十二度七分四十八秒", "subset": "mixmath", "task_type": "tts"} +{"index": 1599, "question": "Please read the following math formula symbols: $$a_t=1+\\sint,\\quad\\lambda_t=e^t,\\quadt\\ge0.$$", "audio_path": "audio/row_00710150_1755671976341683.wav", "formula": "$$a_t=1+\\sint,\\quad\\lambda_t=e^t,\\quadt\\ge0.$$", "answer": "a sub t equals 1 plus sine t, lambda sub t equals e to the power of t, t greater than or equal to 0.", "subset": "mixmath", "task_type": "tts"} +{"index": 1600, "question": "Please read the following math formula symbols: $$\\rank\\MW(\\pi)=10-2-\\sum_{p\\in\\Sigma}(m_p-1).$$", "audio_path": "audio/row_01759594_1755803781816380.wav", "formula": "$$\\rank\\MW(\\pi)=10-2-\\sum_{p\\in\\Sigma}(m_p-1).$$", "answer": "Rank of W times M of pi equals 10 minus 2 minus the sum over p in Sigma of m sub p minus 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 1601, "question": "请你朗读以下数学公式符号:${\\left( a {b}^{2} \\right)}^{3}={a}^{3}{b}^{6}$", "audio_path": "audio/math_9e187f9e-8a25-47e1-a44c-fc01200dc907.wav", "formula": "${\\left( a {b}^{2} \\right)}^{3}={a}^{3}{b}^{6}$", "answer": "a乘b平方,整体的三次方等于a的三次方b的六次方", "subset": "mixmath", "task_type": "tts"} +{"index": 1602, "question": "请你朗读以下数学公式符号:$=\\dfrac{1978\\times 1979+1979\\times 1980}{( 1+1979 )\\times 1979\\div 2+( 1978+1 )\\times 1978\\div 2}$", "audio_path": "audio/math_9eed1f82-bf62-40d8-a344-63bf693c208c.wav", "formula": "$=\\dfrac{1978\\times 1979+1979\\times 1980}{( 1+1979 )\\times 1979\\div 2+( 1978+1 )\\times 1978\\div 2}$", "answer": "等于 一加一千九百七十九的和乘一千九百七十九除以二加一千九百七十八加一的和 乘一千九百七十八除以二 分之 一千九百七十八乘一千九百七十九加一千九百七十九乘一千九百八十", "subset": "mixmath", "task_type": "tts"} +{"index": 1603, "question": "Please read the following math formula symbols: $\\sigma_1(a+b\\sqrt{d})=a+b\\sqrt{d}$", "audio_path": "audio/row_01324153_1755748781724638.wav", "formula": "$\\sigma_1(a+b\\sqrt{d})=a+b\\sqrt{d}$", "answer": "Sigma sub 1, open parenthesis, a plus b square root of d, close parenthesis, equals a plus b square root of d.", "subset": "mixmath", "task_type": "tts"} +{"index": 1604, "question": "Please read the following math formula symbols: $$\\chi_c^{\\mathbbA^1}:K_0(\\var(k))\\toGW(k)\\,,$$", "audio_path": "audio/row_01330520_1755749576619551.wav", "formula": "$$\\chi_c^{\\mathbbA^1}:K_0(\\var(k))\\toGW(k)\\,,$$", "answer": "Chi sub c to the power of A one, colon, K sub zero of var of k, arrow, G sub k, comma.", "subset": "mixmath", "task_type": "tts"} +{"index": 1605, "question": "请你朗读以下数学公式符号:$540\\times \\frac{a}{b}$", "audio_path": "audio/math_b94bb8b1-d5a6-45c8-9910-23810cd156d8.wav", "formula": "$540\\times \\frac{a}{b}$", "answer": "五百四十乘b分之a", "subset": "mixmath", "task_type": "tts"} +{"index": 1606, "question": "Please read the following math formula symbols: $S_1^k\\subsetB_{\\beta}(0,R),$", "audio_path": "audio/row_00831507_1755687160850316.wav", "formula": "$S_1^k\\subsetB_{\\beta}(0,R),$", "answer": "S sub 1 to the power of k is a subset of B sub beta, open parenthesis 0, comma R, close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 1607, "question": "Please read the following math formula symbols: $|N(A)|\\ge|N(C_2^{-}(A))|$", "audio_path": "audio/row_02055418_1755841135610733.wav", "formula": "$|N(A)|\\ge|N(C_2^{-}(A))|$", "answer": "Absolute value of N of A is greater than or equal to absolute value of N of C sub 2 minus of A.", "subset": "mixmath", "task_type": "tts"} +{"index": 1608, "question": "请你朗读以下数学公式符号:${{\\left( 215 \\right)}_{6}}+{{\\left( 224 \\right)}_{6}}=$", "audio_path": "audio/math_26d40c2f-34a3-44c7-a77e-45d8e38cf04f.wav", "formula": "${{\\left( 215 \\right)}_{6}}+{{\\left( 224 \\right)}_{6}}=$", "answer": "六进制的二一五加六进制的二二四等于", "subset": "mixmath", "task_type": "tts"} +{"index": 1609, "question": "请你朗读以下数学公式符号:$\\left\\{\\begin{array}{c}3x=2y\\\\ 4x+7y=34800\\end{array}\\right.$", "audio_path": "audio/math_22f5877e-cd71-4459-b75f-c8fb141e8c76.wav", "formula": "$\\left\\{\\begin{array}{c}3x=2y\\\\ 4x+7y=34800\\end{array}\\right.$", "answer": "三x等于二y,四x加七y等于三万四千八百", "subset": "mixmath", "task_type": "tts"} +{"index": 1610, "question": "请你朗读以下数学公式符号:$$\\begin{cases}\\angle A=60{}^\\circ \\\\ \\angle C=2\\angle B \\\\ \\angle A+\\angle B+\\angle C=180{}^\\circ \\\\ \\end{cases}$$", "audio_path": "audio/math_b0c772f9-4be5-4c08-a1f3-5e70583249a7.wav", "formula": "$$\\begin{cases}\\angle A=60{}^\\circ \\\\ \\angle C=2\\angle B \\\\ \\angle A+\\angle B+\\angle C=180{}^\\circ \\\\ \\end{cases}$$", "answer": "角A等于六十度,角C等于二倍的角B,角A加角B加角C等于一百八十度", "subset": "mixmath", "task_type": "tts"} +{"index": 1611, "question": "Please read the following math formula symbols: $\\{\\rho_{j,j}(Y):j\\geq0\\}$", "audio_path": "audio/row_00557943_1755653030614158.wav", "formula": "$\\{\\rho_{j,j}(Y):j\\geq0\\}$", "answer": "Open brace, rho sub j comma j open parenthesis Y close parenthesis colon j greater than or equal to 0, close brace.", "subset": "mixmath", "task_type": "tts"} +{"index": 1612, "question": "Please read the following math formula symbols: $\\{S_i(C')\\midC'\\in\\mathcal{C}\\}$", "audio_path": "audio/row_00996995_1755707868784459.wav", "formula": "$\\{S_i(C')\\midC'\\in\\mathcal{C}\\}$", "answer": "Open brace, S sub i open parenthesis C prime close parenthesis, such that C prime belongs to script C, close brace.", "subset": "mixmath", "task_type": "tts"} +{"index": 1613, "question": "Please read the following math formula symbols: $\\mathbb{E}[Y_{ij}^2]\\leqp/4$", "audio_path": "audio/row_00192151_1755608370685961.wav", "formula": "$\\mathbb{E}[Y_{ij}^2]\\leqp/4$", "answer": "The expected value of the square of Y sub i j is less than or equal to p divided by 4.", "subset": "mixmath", "task_type": "tts"} +{"index": 1614, "question": "请你朗读以下数学公式符号:$$\\sqrt{\\frac{1}{2}}\\times \\sqrt{6}+\\sqrt{9}\\div \\sqrt{3}$$", "audio_path": "audio/math_8b297107-f266-42eb-b4af-9d71e7b3d4d6.wav", "formula": "$$\\sqrt{\\frac{1}{2}}\\times \\sqrt{6}+\\sqrt{9}\\div \\sqrt{3}$$", "answer": "根号下二分之一乘根号六加根号九除以根号三", "subset": "mixmath", "task_type": "tts"} +{"index": 1615, "question": "Please read the following math formula symbols: $B^{-s+\\frac\\beta2}_{2,1}(\\Omega)\\subsetB^t_{2,1}(\\Omega)$", "audio_path": "audio/row_01136724_1755725313369929.wav", "formula": "$B^{-s+\\frac\\beta2}_{2,1}(\\Omega)\\subsetB^t_{2,1}(\\Omega)$", "answer": "B to the power of negative s plus beta over 2, 1, Omega, subset B to the power of t 2, 1, Omega.", "subset": "mixmath", "task_type": "tts"} +{"index": 1616, "question": "Please read the following math formula symbols: $z\\in\\cap_{i=0}^\\inftyU^\\Psi(\\lambda_i)$", "audio_path": "audio/row_00657393_1755665427478377.wav", "formula": "$z\\in\\cap_{i=0}^\\inftyU^\\Psi(\\lambda_i)$", "answer": "z belongs to the intersection from i equals 0 to infinity of U raised to the power of Psi lambda sub i.", "subset": "mixmath", "task_type": "tts"} +{"index": 1617, "question": "请你朗读以下数学公式符号:$\\frac{5}{11}+\\frac{6}{11}=\\frac{5+6}{11}=\\frac{11}{11}=1$", "audio_path": "audio/math_9e92b232-36ee-44b8-a252-5cfd4b3add10.wav", "formula": "$\\frac{5}{11}+\\frac{6}{11}=\\frac{5+6}{11}=\\frac{11}{11}=1$", "answer": "十一分之五加十一分之六等于十一分之五加六的和等于十一分之十一等于一", "subset": "mixmath", "task_type": "tts"} +{"index": 1618, "question": "Please read the following math formula symbols: $X^{u-e_{\\alpha}-e_j}\\subseteqX^{u-e_{\\alpha}}$", "audio_path": "audio/row_00762508_1755678511236453.wav", "formula": "$X^{u-e_{\\alpha}-e_j}\\subseteqX^{u-e_{\\alpha}}$", "answer": "X to the power of u minus e sub alpha minus e sub j belongs to X to the power of u minus e sub alpha.", "subset": "mixmath", "task_type": "tts"} +{"index": 1619, "question": "请你朗读以下数学公式符号:$\\frac{1}{4}=\\frac{1\\times 5}{4\\times 5}=\\frac{5}{20}$", "audio_path": "audio/math_7369789f-a4df-48db-855c-e3e39cfa0ca2.wav", "formula": "$\\frac{1}{4}=\\frac{1\\times 5}{4\\times 5}=\\frac{5}{20}$", "answer": "四分之一等于四乘五的积分之一乘五的积等于二十分之五", "subset": "mixmath", "task_type": "tts"} +{"index": 1620, "question": "请你朗读以下数学公式符号:$\\begin{cases}5\\equiv k\\left( \\bmod 7 \\right) \\\\ 3\\equiv 4k\\left( \\bmod 11 \\right) \\\\ 11\\equiv 2k\\left( \\bmod 13 \\right) \\end{cases}$", "audio_path": "audio/math_83e29f75-8ba8-4334-81f5-d0a985ca021e.wav", "formula": "$\\begin{cases}5\\equiv k\\left( \\bmod 7 \\right) \\\\ 3\\equiv 4k\\left( \\bmod 11 \\right) \\\\ 11\\equiv 2k\\left( \\bmod 13 \\right) \\end{cases}$", "answer": "五同余于k模七和三同余于四k模十一和十一同余于二k模十三", "subset": "mixmath", "task_type": "tts"} +{"index": 1621, "question": "请你朗读以下数学公式符号:$$\\begin{eqnarray}&&15\\times 2\\\\ &=&3\\times 5\\times 2\\\\ &=&3\\times \\left( 5\\times 2 \\right)\\\\ &=&3\\times 10\\\\ &=&30\\end{eqnarray}$$", "audio_path": "audio/math_9d0b9a06-6ace-49c7-b556-b421a73437eb.wav", "formula": "$$\\begin{eqnarray}&&15\\times 2\\\\ &=&3\\times 5\\times 2\\\\ &=&3\\times \\left( 5\\times 2 \\right)\\\\ &=&3\\times 10\\\\ &=&30\\end{eqnarray}$$", "answer": "十五乘二等于三乘五乘二等于三乘五乘二的积等于三乘十等于三十", "subset": "mixmath", "task_type": "tts"} +{"index": 1622, "question": "Please read the following math formula symbols: $\\{(U_i,\\varphi_i)\\}_{i=0}^n$", "audio_path": "audio/row_02057426_1755841413086988.wav", "formula": "$\\{(U_i,\\varphi_i)\\}_{i=0}^n$", "answer": "Open brace, open parenthesis, U sub i, comma, phi sub i, close parenthesis, close brace, sub i equals zero, to n.", "subset": "mixmath", "task_type": "tts"} +{"index": 1623, "question": "Please read the following math formula symbols: $\\E[h(A,Y^{(1)})\\midR_Y=1,A,{\\bfZ}]=0$", "audio_path": "audio/row_01193498_1755732452599743.wav", "formula": "$\\E[h(A,Y^{(1)})\\midR_Y=1,A,{\\bfZ}]=0$", "answer": "Expectation of h of A, Y to the power of 1, given R sub Y equals 1, A, Z equals 0.", "subset": "mixmath", "task_type": "tts"} +{"index": 1624, "question": "请你朗读以下数学公式符号:$\\frac{1}{2}\\cdot 5x\\cdot a=\\frac{1}{2}\\cdot 6x\\cdot b=\\frac{1}{2}\\cdot 7x\\cdot c$", "audio_path": "audio/math_dec61999-7752-462b-931a-284fdaf43a6d.wav", "formula": "$\\frac{1}{2}\\cdot 5x\\cdot a=\\frac{1}{2}\\cdot 6x\\cdot b=\\frac{1}{2}\\cdot 7x\\cdot c$", "answer": "二分之一乘五x乘a等于二分之一乘六x乘b等于二分之一乘七x乘c", "subset": "mixmath", "task_type": "tts"} +{"index": 1625, "question": "Please read the following math formula symbols: $g(t_*)=\\min_{t\\in[t_1,t_1+\\beta]}g(t)$", "audio_path": "audio/row_01722590_1755799095558962.wav", "formula": "$g(t_*)=\\min_{t\\in[t_1,t_1+\\beta]}g(t)$", "answer": "g of t star equals the minimum over t in the interval from t sub 1 to t sub 1 plus beta of g of t.", "subset": "mixmath", "task_type": "tts"} +{"index": 1626, "question": "请你朗读以下数学公式符号:$=\\left( 200\\div 50 \\right):\\left( 750\\div 50 \\right)$", "audio_path": "audio/math_00a777d3-e1c3-4686-be19-be44e219cdc7.wav", "formula": "$=\\left( 200\\div 50 \\right):\\left( 750\\div 50 \\right)$", "answer": "等于二百除以五十的商比七百五十除以五十的商", "subset": "mixmath", "task_type": "tts"} +{"index": 1627, "question": "Please read the following math formula symbols: $p(x)\\propto\\prod_{F\\in\\mathcal{F}}\\psi_F(x_F)$", "audio_path": "audio/row_01188575_1755731833381529.wav", "formula": "$p(x)\\propto\\prod_{F\\in\\mathcal{F}}\\psi_F(x_F)$", "answer": "p of x is proportional to the product over F in the set F of psi sub F of x sub F.", "subset": "mixmath", "task_type": "tts"} +{"index": 1628, "question": "Please read the following math formula symbols: $R^{-1}Q^{n_{l+1}}_{s_ls_{l+1}}$", "audio_path": "audio/row_00153097_1755603612572284.wav", "formula": "$R^{-1}Q^{n_{l+1}}_{s_ls_{l+1}}$", "answer": "R to the power of negative one, Q to the power of n sub l plus one, sub s sub l s sub l plus one.", "subset": "mixmath", "task_type": "tts"} +{"index": 1629, "question": "请你朗读以下数学公式符号:$\\left( 3k+4k \\right):\\left( 2k+4k \\right):\\left( 2k+3k \\right)=7:6:5$", "audio_path": "audio/math_39bd2f2b-9cd0-420e-8e92-5a6e34f3a3d0.wav", "formula": "$\\left( 3k+4k \\right):\\left( 2k+4k \\right):\\left( 2k+3k \\right)=7:6:5$", "answer": "三k加四k的和比二k加四k的和比二k加三k的和等于七比六比五", "subset": "mixmath", "task_type": "tts"} +{"index": 1630, "question": "Please read the following math formula symbols: $A\\notin\\Cc^{*}(d+2)$", "audio_path": "audio/row_00195829_1755608818647790.wav", "formula": "$A\\notin\\Cc^{*}(d+2)$", "answer": "A is not an element of the set of complex numbers raised to the power of the star of the quantity d plus 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 1631, "question": "Please read the following math formula symbols: $$\\mathcalL=1-K=({{J_3}/{J_2}})^{1/2}.$$", "audio_path": "audio/row_00995633_1755707693110706.wav", "formula": "$$\\mathcalL=1-K=({{J_3}/{J_2}})^{1/2}.$$", "answer": "the set L equals one minus K equals the square root of the fraction J sub 3 divided by J sub 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 1632, "question": "Please read the following math formula symbols: $\\phi(t)=\\Pi_{i=1}^{d}\\delta(x_{i}(t)-x_{i})$", "audio_path": "audio/row_01757341_1755803506640319.wav", "formula": "$\\phi(t)=\\Pi_{i=1}^{d}\\delta(x_{i}(t)-x_{i})$", "answer": "Phi of t equals the product from i equals 1 to d of delta of x sub i of t minus x sub i.", "subset": "mixmath", "task_type": "tts"} +{"index": 1633, "question": "请你朗读以下数学公式符号:$\\left\\{ \\begin{matrix}x=4 \\\\ y=1 \\end{matrix} \\right.$", "audio_path": "audio/math_6e667316-3add-43cc-84a6-a5cc1c3f7f6f.wav", "formula": "$\\left\\{ \\begin{matrix}x=4 \\\\ y=1 \\end{matrix} \\right.$", "answer": "x等于四和y等于一", "subset": "mixmath", "task_type": "tts"} +{"index": 1634, "question": "请你朗读以下数学公式符号:$\\left\\{ \\begin{array}{*{35}{l}} \\frac{x}{10}=\\frac{y}{5}=\\frac{z}{7} \\\\ 3x+2z=44 \\end{array} \\right.$", "audio_path": "audio/math_6eabd0ad-ee8a-4fe3-845a-f75d67b21091.wav", "formula": "$\\left\\{ \\begin{array}{*{35}{l}} \\frac{x}{10}=\\frac{y}{5}=\\frac{z}{7} \\\\ 3x+2z=44 \\end{array} \\right.$", "answer": "十分之x等于五分之y等于七分之z,三x与二z等于四十四", "subset": "mixmath", "task_type": "tts"} +{"index": 1635, "question": "请你朗读以下数学公式符号:$$\\frac{1}{9}\\left\\{ \\frac{1}{7}\\left[ \\frac{1}{5}\\left( \\frac{x+2}{3}+4 \\right)+6 \\right]+8 \\right\\}=1$$", "audio_path": "audio/math_f466fc30-f94b-49ef-8344-566fd172c2d9.wav", "formula": "$$\\frac{1}{9}\\left\\{ \\frac{1}{7}\\left[ \\frac{1}{5}\\left( \\frac{x+2}{3}+4 \\right)+6 \\right]+8 \\right\\}=1$$", "answer": "九分之一乘 七分之一与 五分之一乘 三分之x加二的和加四的和 加六的和的乘积 加八的和等于一", "subset": "mixmath", "task_type": "tts"} +{"index": 1636, "question": "请你朗读以下数学公式符号:$f(x)+f\\left(\\frac{1}{x}\\right)=\\frac{1}{x+1}+\\frac{x}{1+x}=1$", "audio_path": "audio/math_971490f8-2c21-47dc-8794-2f9b75df1bf9.wav", "formula": "$f(x)+f\\left(\\frac{1}{x}\\right)=\\frac{1}{x+1}+\\frac{x}{1+x}=1$", "answer": "f x 加 f x分之一等于x加一的和分之一加一加x的和分之x等于一", "subset": "mixmath", "task_type": "tts"} +{"index": 1637, "question": "Please read the following math formula symbols: $S:=I(G_{r-1}-B(G_{r-1}))$", "audio_path": "audio/row_01996254_1755833666380781.wav", "formula": "$S:=I(G_{r-1}-B(G_{r-1}))$", "answer": "S is equal to I times the quantity G sub r minus 1 minus B times the quantity G sub r minus 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 1638, "question": "Please read the following math formula symbols: $36\\klog{v_\\alpha}2^{\\dcrit+2}=72\\klog{v_\\alpha}2^{\\dcrit+1}$", "audio_path": "audio/row_01922196_1755824333647643.wav", "formula": "$36\\klog{v_\\alpha}2^{\\dcrit+2}=72\\klog{v_\\alpha}2^{\\dcrit+1}$", "answer": "36 log v alpha 2 to the power of dcrit plus 2 equals 72 log v alpha 2 to the power of dcrit plus 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 1639, "question": "请你朗读以下数学公式符号:$\\frac{1}{8}=\\frac{1+2}{8\\times (1+2)}=\\frac{1}{24}+\\frac{1}{12}$", "audio_path": "audio/math_d3648cb0-8363-470a-8c47-aef6aa78f267.wav", "formula": "$\\frac{1}{8}=\\frac{1+2}{8\\times (1+2)}=\\frac{1}{24}+\\frac{1}{12}$", "answer": "八分之一等于 八乘 一加二的和的积 分之 一加二的和 等于二十四分之一加十二分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 1640, "question": "请你朗读以下数学公式符号:$\\left\\{\\begin{array}{c}3x+y=b\\\\ kx+y=1\\end{array}\\right.$", "audio_path": "audio/math_033a6636-fb8c-46b9-a820-70684206ee76.wav", "formula": "$\\left\\{\\begin{array}{c}3x+y=b\\\\ kx+y=1\\end{array}\\right.$", "answer": "三x加y等于b,k x加y等于一", "subset": "mixmath", "task_type": "tts"} +{"index": 1641, "question": "Please read the following math formula symbols: $\\Pi=\\{\\pi|\\int\\pi(x,x')dx'=\\mu(x)$", "audio_path": "audio/row_01915477_1755823494908639.wav", "formula": "$\\Pi=\\{\\pi|\\int\\pi(x,x')dx'=\\mu(x)$", "answer": "Pi equals the set of pi such that the integral of pi of x, x prime, with respect to x prime, equals mu of x.", "subset": "mixmath", "task_type": "tts"} +{"index": 1642, "question": "Please read the following math formula symbols: $D^Y_1,\\dots,D_N^Y$", "audio_path": "audio/row_00631983_1755662282945459.wav", "formula": "$D^Y_1,\\dots,D_N^Y$", "answer": "D raised to the power of Y sub 1, dot dot dot, D sub N raised to the power of Y.", "subset": "mixmath", "task_type": "tts"} +{"index": 1643, "question": "Please read the following math formula symbols: $u\\in\\mc{V}\\cap\\wtU=\\pi^{-1}(0)\\cap\\wtU$", "audio_path": "audio/row_00795135_1755682610424250.wav", "formula": "$u\\in\\mc{V}\\cap\\wtU=\\pi^{-1}(0)\\cap\\wtU$", "answer": "u belongs to the set of m c V and w t U equals pi inverse of 0 intersection w t U.", "subset": "mixmath", "task_type": "tts"} +{"index": 1644, "question": "请你朗读以下数学公式符号:$\\therefore \\begin{cases}A+B=2 \\\\ 2A+B=1 \\end{cases}$", "audio_path": "audio/math_ce1e1fb1-059e-4afd-9b81-dbacb73a2a3c.wav", "formula": "$\\therefore \\begin{cases}A+B=2 \\\\ 2A+B=1 \\end{cases}$", "answer": "所以,A加B的和等于二 和 二A加B的和等于一", "subset": "mixmath", "task_type": "tts"} +{"index": 1645, "question": "Please read the following math formula symbols: $u=[w^1,...,w^I]$", "audio_path": "audio/row_00527280_1755649284724630.wav", "formula": "$u=[w^1,...,w^I]$", "answer": "u equals open square bracket w to the power of 1, ellipsis, w to the power of I close square bracket.", "subset": "mixmath", "task_type": "tts"} +{"index": 1646, "question": "请你朗读以下数学公式符号:$60=1\\times 60=2\\times 30=3\\times 20=4\\times 15=5\\times 12=6\\times 10$", "audio_path": "audio/math_75300a7f-2cda-4ffd-9930-0a428c39f6a8.wav", "formula": "$60=1\\times 60=2\\times 30=3\\times 20=4\\times 15=5\\times 12=6\\times 10$", "answer": "六十等于一乘六十等于二乘三十等于三乘二十等于四乘十五等于五乘十二等于六乘十", "subset": "mixmath", "task_type": "tts"} +{"index": 1647, "question": "请你朗读以下数学公式符号:$$\\left( 2\\frac{2}{7}+3\\frac{1}{9}+2\\frac{2}{11}+3\\frac{9}{13} \\right)\\div \\left( \\frac{4}{7}+\\frac{7}{9}+\\frac{6}{11}+\\frac{12}{13} \\right)=$$", "audio_path": "audio/math_66fec7d0-59b7-4ef2-9747-0dbff2bace9d.wav", "formula": "$$\\left( 2\\frac{2}{7}+3\\frac{1}{9}+2\\frac{2}{11}+3\\frac{9}{13} \\right)\\div \\left( \\frac{4}{7}+\\frac{7}{9}+\\frac{6}{11}+\\frac{12}{13} \\right)=$$", "answer": "二又七分之二加三又九分之一加二又十一分之二加三又十三分之九的和除以七分之四加九分之七加十一分之六加十三分之十二的和等于", "subset": "mixmath", "task_type": "tts"} +{"index": 1648, "question": "Please read the following math formula symbols: $q(H_{2,Q})=\\paren*{2^B-1}\\delta$", "audio_path": "audio/row_00538060_1755650588572322.wav", "formula": "$q(H_{2,Q})=\\paren*{2^B-1}\\delta$", "answer": "q open parenthesis H subscript 2 comma Q close parenthesis equals delta times 2 to the power of B minus 1 delta", "subset": "mixmath", "task_type": "tts"} +{"index": 1649, "question": "Please read the following math formula symbols: $\\abs{\\frac{b}{a}+A}\\leq\\frac{CR}{Q}$", "audio_path": "audio/row_00197378_1755609012056500.wav", "formula": "$\\abs{\\frac{b}{a}+A}\\leq\\frac{CR}{Q}$", "answer": "The absolute value of the fraction b over a plus A is less than or equal to the fraction CR over Q.", "subset": "mixmath", "task_type": "tts"} +{"index": 1650, "question": "请你朗读以下数学公式符号:$\\begin{cases}m < \\dfrac{5}{4} \\\\ m>1 \\end{cases}$", "audio_path": "audio/math_b6f546e1-c0d2-4fa7-bcc6-19925edb1184.wav", "formula": "$\\begin{cases}m < \\dfrac{5}{4} \\\\ m>1 \\end{cases}$", "answer": "m 小于 四分之五 ,m 大于 一", "subset": "mixmath", "task_type": "tts"} +{"index": 1651, "question": "请你朗读以下数学公式符号:$$3\\times 3,3\\times 5,3\\times 7,5\\times 5,3\\times 9,3\\times 11,5\\times 7,3\\times 13,\\ldots$$", "audio_path": "audio/math_47d0ccea-bb8f-47c0-ac03-e5f0a61f353d.wav", "formula": "$$3\\times 3,3\\times 5,3\\times 7,5\\times 5,3\\times 9,3\\times 11,5\\times 7,3\\times 13,\\ldots$$", "answer": "三乘三,三乘五,三乘七,五乘五,三乘九,三乘十一,五乘七,三乘十三", "subset": "mixmath", "task_type": "tts"} +{"index": 1652, "question": "请你朗读以下数学公式符号:$$1.2\\overset{\\centerdot }{\\mathop{8}}\\,\\overset{\\centerdot }{\\mathop{1}}$$", "audio_path": "audio/math_99b14f5d-d96a-4c46-8eb3-6ed3511548ab.wav", "formula": "$$1.2\\overset{\\centerdot }{\\mathop{8}}\\,\\overset{\\centerdot }{\\mathop{1}}$$", "answer": "一点二八一 八一循环", "subset": "mixmath", "task_type": "tts"} +{"index": 1653, "question": "Please read the following math formula symbols: $a_0+a_1-a_2\\equiv3+a_2$", "audio_path": "audio/row_01123499_1755723641927835.wav", "formula": "$a_0+a_1-a_2\\equiv3+a_2$", "answer": "The quantity a sub 0 plus a sub 1 minus a sub 2 is equivalent to 3 plus a sub 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 1654, "question": "Please read the following math formula symbols: $\\hat{\\bY}=(\\hat{y}_1,\\hat{y}_2,\\cdots\\hat{y}_n)$", "audio_path": "audio/row_00374018_1755630516667619.wav", "formula": "$\\hat{\\bY}=(\\hat{y}_1,\\hat{y}_2,\\cdots\\hat{y}_n)$", "answer": "The hat Y equals open parenthesis, hat y sub 1, comma, hat y sub 2, comma, ellipsis, hat y sub n, close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 1655, "question": "Please read the following math formula symbols: $a(y):=y/\\int_{y_0}^y\\mu(g>t)\\,\\mathrm{d}t$", "audio_path": "audio/row_00853633_1755689953998647.wav", "formula": "$a(y):=y/\\int_{y_0}^y\\mu(g>t)\\,\\mathrm{d}t$", "answer": "a of y is defined as y divided by the integral from y sub 0 to y of mu of g greater than t, dt.", "subset": "mixmath", "task_type": "tts"} +{"index": 1656, "question": "Please read the following math formula symbols: $\\|A\\{\\bf\\x\\|_2\\leq\\|A\\|\\|\\{\\bf\\x\\|_2$", "audio_path": "audio/row_01531051_1755774878540317.wav", "formula": "$\\|A\\{\\bf\\x\\|_2\\leq\\|A\\|\\|\\{\\bf\\x\\|_2$", "answer": "Norm of A, bold x, subscript 2, is less than or equal to norm of A, norm of bold x, subscript 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 1657, "question": "请你朗读以下数学公式符号:$$6\\times 5+\\left( 6\\times 3+5\\times 3 \\right)\\times 2=96\\left( {d}{{{m}}^{2}} \\right)$$", "audio_path": "audio/math_11e9a0a9-9ada-4fe7-b422-dee312efe616.wav", "formula": "$$6\\times 5+\\left( 6\\times 3+5\\times 3 \\right)\\times 2=96\\left( {d}{{{m}}^{2}} \\right)$$", "answer": "六乘五加六乘三加五乘三的和乘二等于九十六平方分米", "subset": "mixmath", "task_type": "tts"} +{"index": 1658, "question": "请你朗读以下数学公式符号:$$\\left\\{ \\begin{matrix} 6y=x+20 \\\\ 4y=x+4 \\end{matrix} \\right.$$", "audio_path": "audio/math_0a248bd8-ab4d-4213-9697-95a00a1cf272.wav", "formula": "$$\\left\\{ \\begin{matrix} 6y=x+20 \\\\ 4y=x+4 \\end{matrix} \\right.$$", "answer": "六 y 等于 x 加二十,四 y 等于 x 加四", "subset": "mixmath", "task_type": "tts"} +{"index": 1659, "question": "Please read the following math formula symbols: $\\Gr^{(m)}\\geq\\Gr^{(m_0)}$", "audio_path": "audio/row_01831271_1755812838181608.wav", "formula": "$\\Gr^{(m)}\\geq\\Gr^{(m_0)}$", "answer": "Gr raised to the power of m is greater than or equal to Gr raised to the power of m sub 0.", "subset": "mixmath", "task_type": "tts"} +{"index": 1660, "question": "Please read the following math formula symbols: $x_{B^Q},x_{B^P}\\in3B_R$", "audio_path": "audio/row_01233207_1755737434392579.wav", "formula": "$x_{B^Q},x_{B^P}\\in3B_R$", "answer": "x sub B to the power of Q, x sub B to the power of P belongs to 3B sub R.", "subset": "mixmath", "task_type": "tts"} +{"index": 1661, "question": "Please read the following math formula symbols: $e_{G}(V(H'),S)<\\lceil\\frac{r}{r-2}\\rceil=2$", "audio_path": "audio/row_01903838_1755822005055582.wav", "formula": "$e_{G}(V(H'),S)<\\lceil\\frac{r}{r-2}\\rceil=2$", "answer": "e sub G of V of H prime, S, is less than the ceiling of r divided by r minus 2, equals 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 1662, "question": "请你朗读以下数学公式符号:$=\\sqrt{{{\\left( \\sqrt{a}\\pm \\sqrt{b} \\right)}^{2}}} =\\sqrt{a}\\pm \\sqrt{b}$", "audio_path": "audio/math_a3ecc290-2295-4808-8329-2e5b18797414.wav", "formula": "$=\\sqrt{{{\\left( \\sqrt{a}\\pm \\sqrt{b} \\right)}^{2}}} =\\sqrt{a}\\pm \\sqrt{b}$", "answer": "等于根号下根号a加减根号b的完全平方等于根号a加减根号b", "subset": "mixmath", "task_type": "tts"} +{"index": 1663, "question": "Please read the following math formula symbols: $\\mathbb{S}^{2n-1}_\\varepsilon\\subset\\C^n$", "audio_path": "audio/row_01088837_1755719329690327.wav", "formula": "$\\mathbb{S}^{2n-1}_\\varepsilon\\subset\\C^n$", "answer": "The set of all n minus 1 epsilon, subset of the set of complex numbers raised to the power of n.", "subset": "mixmath", "task_type": "tts"} +{"index": 1664, "question": "请你朗读以下数学公式符号:$25\\% \\times \\frac{8}{9}+\\frac{3}{4}\\times \\frac{8}{9}$", "audio_path": "audio/math_33ee436d-9f99-4fe7-97d3-a7a42b882b78.wav", "formula": "$25\\% \\times \\frac{8}{9}+\\frac{3}{4}\\times \\frac{8}{9}$", "answer": "百分之二十五乘九分之八加四分之三乘九分之八", "subset": "mixmath", "task_type": "tts"} +{"index": 1665, "question": "Please read the following math formula symbols: $\\lVertx\\rVert_2=\\left(\\sum_{j=1}^dx_j^2\\right)^{1/2}$", "audio_path": "audio/row_01347876_1755751764867205.wav", "formula": "$\\lVertx\\rVert_2=\\left(\\sum_{j=1}^dx_j^2\\right)^{1/2}$", "answer": "The norm of x is equal to the square root of the sum from j equals 1 to dx sub j squared.", "subset": "mixmath", "task_type": "tts"} +{"index": 1666, "question": "请你朗读以下数学公式符号:$A+B\\times C\\times D\\times (B+C)=1+2\\times 3\\times 67\\times (2+3)=2011$", "audio_path": "audio/math_925b6e93-bd03-4036-ada4-7e9757a63579.wav", "formula": "$A+B\\times C\\times D\\times (B+C)=1+2\\times 3\\times 67\\times (2+3)=2011$", "answer": "A 加上 B乘C乘D 乘 B 加 C 的和 等于 一加二乘三乘六十七乘二加三的和 等于 两千零一十一", "subset": "mixmath", "task_type": "tts"} +{"index": 1667, "question": "请你朗读以下数学公式符号:$\\left( \\frac{7}{8}+\\frac{13}{16} \\right)\\times \\frac{16}{13}$", "audio_path": "audio/math_a4ebac79-58e5-4032-8fc9-6d48631fb986.wav", "formula": "$\\left( \\frac{7}{8}+\\frac{13}{16} \\right)\\times \\frac{16}{13}$", "answer": "八分之七加十六分之十三的和乘十三分之十六", "subset": "mixmath", "task_type": "tts"} +{"index": 1668, "question": "Please read the following math formula symbols: $\\vert\\eta_2(0)-\\eta_2(\\tau_H)\\vert\\approx0.009117525$", "audio_path": "audio/row_00460549_1755641101322632.wav", "formula": "$\\vert\\eta_2(0)-\\eta_2(\\tau_H)\\vert\\approx0.009117525$", "answer": "The absolute value of eta sub 2 of 0 minus eta sub 2 of tau sub H is approximately equal to 0.009117525.", "subset": "mixmath", "task_type": "tts"} +{"index": 1669, "question": "请你朗读以下数学公式符号:$\\left\\{\\begin{array}{c}x=2\\\\y=6\\end{array}\\right.$", "audio_path": "audio/math_8f21fb64-75cb-40d2-9722-7989d7076c1d.wav", "formula": "$\\left\\{\\begin{array}{c}x=2\\\\y=6\\end{array}\\right.$", "answer": "x等于二和y等于六", "subset": "mixmath", "task_type": "tts"} +{"index": 1670, "question": "请你朗读以下数学公式符号:$=\\left( 10+1 \\right)+\\left( 100+4 \\right)+\\left( 1000+12\\right)$", "audio_path": "audio/math_99f96d88-f825-41cf-9f6d-e6fd3a377000.wav", "formula": "$=\\left( 10+1 \\right)+\\left( 100+4 \\right)+\\left( 1000+12\\right)$", "answer": "等于十加一的和加一百加四的和加一千加十二的和", "subset": "mixmath", "task_type": "tts"} +{"index": 1671, "question": "Please read the following math formula symbols: $a_1g_{134}+g_{245}+g_{345};$", "audio_path": "audio/row_01003574_1755708686886740.wav", "formula": "$f_{134}+f_{245}+f_{345}>g_{134}+g_{245}+g_{345};$", "answer": "f sub 134 plus f sub 245 plus f sub 345 is greater than g sub 134 plus g sub 245 plus g sub 345.", "subset": "mixmath", "task_type": "tts"} +{"index": 1687, "question": "请你朗读以下数学公式符号:$\\frac{5}{18}\\times \\left( 1+\\frac{3}{10} \\right)=\\frac{13}{36}$", "audio_path": "audio/math_b99af18c-0d14-4730-aedd-5b3358777018.wav", "formula": "$\\frac{5}{18}\\times \\left( 1+\\frac{3}{10} \\right)=\\frac{13}{36}$", "answer": "十八分之五乘一加十分之三的和等于三十六分之十三", "subset": "mixmath", "task_type": "tts"} +{"index": 1688, "question": "请你朗读以下数学公式符号:$1\\times 1\\times 1+2\\times 2\\times 2+3\\times 3\\times 3+4\\times 4\\times 4+5\\times 5\\times 5+6\\times 6\\times 6=$", "audio_path": "audio/math_6d1b71cb-69bc-4094-be55-1aa05b421e21.wav", "formula": "$1\\times 1\\times 1+2\\times 2\\times 2+3\\times 3\\times 3+4\\times 4\\times 4+5\\times 5\\times 5+6\\times 6\\times 6=$", "answer": "一乘一乘一加二乘二乘二加三乘三乘三加四乘四乘四加五乘五乘五加六乘六乘六等于", "subset": "mixmath", "task_type": "tts"} +{"index": 1689, "question": "Please read the following math formula symbols: $I_p(q)=q\\log\\frac{q}{p}+(1-q)\\log\\frac{1-q}{1-p}$", "audio_path": "audio/row_02087871_1755845278590625.wav", "formula": "$I_p(q)=q\\log\\frac{q}{p}+(1-q)\\log\\frac{1-q}{1-p}$", "answer": "I sub p of q equals q log of q over p plus 1 minus q log of 1 minus q over 1 minus p.", "subset": "mixmath", "task_type": "tts"} +{"index": 1690, "question": "请你朗读以下数学公式符号:$\\pi r\\times r\\times r=3.14\\times {{4}^{2}}\\times4=200.96{c}{{{m}}^{3}}$", "audio_path": "audio/math_7f8031ea-30ff-46d3-b2af-22a1343fec8f.wav", "formula": "$\\pi r\\times r\\times r=3.14\\times {{4}^{2}}\\times4=200.96{c}{{{m}}^{3}}$", "answer": "pi r 乘 r 乘 r 等于 三点一四乘四的平方乘四 等于 二百点九六立方厘米", "subset": "mixmath", "task_type": "tts"} +{"index": 1691, "question": "请你朗读以下数学公式符号:$\\frac{5}{12}{x}\\div \\frac{5}{12}=5\\div \\frac{5}{12}$", "audio_path": "audio/math_f1c63701-b945-4115-860c-2242657fb896.wav", "formula": "$\\frac{5}{12}{x}\\div \\frac{5}{12}=5\\div \\frac{5}{12}$", "answer": "十二分之五x除以十二分之五等于五除以十二分之五", "subset": "mixmath", "task_type": "tts"} +{"index": 1692, "question": "Please read the following math formula symbols: $p_n\\in\\mathbb{R}^{}[x_1,\\dots,x_d]$", "audio_path": "audio/row_00280051_1755619074150438.wav", "formula": "$p_n\\in\\mathbb{R}^{}[x_1,\\dots,x_d]$", "answer": "p sub n belongs to the set of real numbers raised to the empty power, with variables x sub 1 through x sub d.", "subset": "mixmath", "task_type": "tts"} +{"index": 1693, "question": "Please read the following math formula symbols: $|L\\cap\\Sigma^m|\\lep(m)$", "audio_path": "audio/row_00412367_1755635195651336.wav", "formula": "$|L\\cap\\Sigma^m|\\lep(m)$", "answer": "The cardinality of the intersection of set L and the set of strings of length m is less than or equal to p of m.", "subset": "mixmath", "task_type": "tts"} +{"index": 1694, "question": "Please read the following math formula symbols: $g_D(S)=|S|+2\\operatorname{rk}_{{M}}(S^+)-2|S^{+}|$", "audio_path": "audio/row_00966642_1755704076376647.wav", "formula": "$g_D(S)=|S|+2\\operatorname{rk}_{{M}}(S^+)-2|S^{+}|$", "answer": "g sub D of S equals absolute value of S plus 2 rk sub M of S plus minus 2 absolute value of S plus", "subset": "mixmath", "task_type": "tts"} +{"index": 1695, "question": "请你朗读以下数学公式符号:${{9}^{x}}\\cdot {{27}^{y}}={{3}^{2x}}\\cdot {{3}^{3y}}$", "audio_path": "audio/math_27ab9025-fafb-493c-b1e5-cc41798742c2.wav", "formula": "${{9}^{x}}\\cdot {{27}^{y}}={{3}^{2x}}\\cdot {{3}^{3y}}$", "answer": "九的x次方 乘 二十七的y次方等于三的二x次方 乘 三的三y次方", "subset": "mixmath", "task_type": "tts"} +{"index": 1696, "question": "请你朗读以下数学公式符号:$78+\\overline{6B}+\\overline{A5}+34+29+1=207+\\overline{AB}=99\\times 3$", "audio_path": "audio/math_a47c0cb2-d7a0-49b4-aae2-6d63d5380bb6.wav", "formula": "$78+\\overline{6B}+\\overline{A5}+34+29+1=207+\\overline{AB}=99\\times 3$", "answer": "七十八加两位数六B加两位数A五加三十四加二十九加一等于二百零七加两位数A B等于九十九乘三", "subset": "mixmath", "task_type": "tts"} +{"index": 1697, "question": "Please read the following math formula symbols: $0\\neqw\\in\\R^{n+2}$", "audio_path": "audio/row_00124032_1755600099456188.wav", "formula": "$0\\neqw\\in\\R^{n+2}$", "answer": "0 is not equal to w, where w belongs to the set of real numbers raised to the power of n plus 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 1698, "question": "Please read the following math formula symbols: $\\left(\\int_{X_k}u_k\\om_k^n\\right)_k$", "audio_path": "audio/row_00898870_1755695630577652.wav", "formula": "$\\left(\\int_{X_k}u_k\\om_k^n\\right)_k$", "answer": "Left parenthesis, integral over X sub k, u sub k, om sub k to the power of n, right parenthesis, sub k.", "subset": "mixmath", "task_type": "tts"} +{"index": 1699, "question": "Please read the following math formula symbols: $$w_{n+2}=y_{n+2}+1=p-r_1-l_2-1$$", "audio_path": "audio/row_00386316_1755632017627634.wav", "formula": "$$w_{n+2}=y_{n+2}+1=p-r_1-l_2-1$$", "answer": "w sub n plus 2 equals y sub n plus 2 plus 1 equals p minus r sub 1 minus l sub 2 minus 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 1700, "question": "请你朗读以下数学公式符号:$\\frac{5}{21}\\times 0+\\frac{10}{21}=\\frac{10}{21}$", "audio_path": "audio/math_308c5bbd-a2d6-443f-a0bf-92b3550b9d68.wav", "formula": "$\\frac{5}{21}\\times 0+\\frac{10}{21}=\\frac{10}{21}$", "answer": "二十一分之五乘零加二十一分之十等于二十一分之十", "subset": "mixmath", "task_type": "tts"} +{"index": 1701, "question": "请你朗读以下数学公式符号:$$=2020\\times 10\\times 67+2020\\times 124+505\\times 4\\times 200+2020\\times 2\\times 3$$", "audio_path": "audio/math_9c401313-4b12-45ff-b336-485c4dd39db9.wav", "formula": "$$=2020\\times 10\\times 67+2020\\times 124+505\\times 4\\times 200+2020\\times 2\\times 3$$", "answer": "等于二千零二十乘十乘六十七加二千零二十乘一百二十四加五百零五乘四乘二百加二千零十乘二乘三", "subset": "mixmath", "task_type": "tts"} +{"index": 1702, "question": "请你朗读以下数学公式符号:$$\\frac{1}{4}\\times \\frac{2}{11}+\\frac{1}{3}\\times \\frac{3}{11}+\\frac{5}{12}\\times \\frac{4}{11}=\\frac{19}{66}$$", "audio_path": "audio/math_356ec4ed-f6ae-44c3-b12a-efddb2304010.wav", "formula": "$$\\frac{1}{4}\\times \\frac{2}{11}+\\frac{1}{3}\\times \\frac{3}{11}+\\frac{5}{12}\\times \\frac{4}{11}=\\frac{19}{66}$$", "answer": "四分之一乘十一分之二加三分之一乘十一分之三加十二分之五乘十一分之四等于六十六分之十九", "subset": "mixmath", "task_type": "tts"} +{"index": 1703, "question": "请你朗读以下数学公式符号:$\\begin{cases}m\\ne 0 \\\\ \\Delta =2+4m\\geqslant 0 \\\\ \\end{cases}$", "audio_path": "audio/math_695c97b1-5610-49ea-b8a5-a9400b1be515.wav", "formula": "$\\begin{cases}m\\ne 0 \\\\ \\Delta =2+4m\\geqslant 0 \\\\ \\end{cases}$", "answer": "m 不等于零 和 Delta 等于二加四m 大于等于零", "subset": "mixmath", "task_type": "tts"} +{"index": 1704, "question": "请你朗读以下数学公式符号:$$\\overline{abcabc}=\\overline{abc}\\times 1001=\\overline{abc}\\times 7\\times 11\\times 13$$", "audio_path": "audio/math_e2ac33e3-1f97-4711-8225-0d0fe879f7a4.wav", "formula": "$$\\overline{abcabc}=\\overline{abc}\\times 1001=\\overline{abc}\\times 7\\times 11\\times 13$$", "answer": "六位数abcabc等于三位数abc乘一千零一,等于三位数abc乘七乘十一乘十三。", "subset": "mixmath", "task_type": "tts"} +{"index": 1705, "question": "请你朗读以下数学公式符号:$$\\left\\{ \\begin{matrix}x+3>2 \\\\ \\frac{1}{x}+2\\leqslant 5 \\\\ \\end{matrix} \\right.$$", "audio_path": "audio/math_3dc00183-b62e-4f23-8e1c-8bdd7fa1ff98.wav", "formula": "$$\\left\\{ \\begin{matrix}x+3>2 \\\\ \\frac{1}{x}+2\\leqslant 5 \\\\ \\end{matrix} \\right.$$", "answer": "x加三大于二;x分之一加二小于等于五", "subset": "mixmath", "task_type": "tts"} +{"index": 1706, "question": "Please read the following math formula symbols: $p^*_i\\leq\\ucb_{b2}=\\ucb'_i$", "audio_path": "audio/row_02092723_1755845897082625.wav", "formula": "$p^*_i\\leq\\ucb_{b2}=\\ucb'_i$", "answer": "p star i less than or equal to u c b sub b 2 equals u c b prime sub i.", "subset": "mixmath", "task_type": "tts"} +{"index": 1707, "question": "Please read the following math formula symbols: $\\mathbf{M}=\\{\\mathbf{M}_i\\}_{i=1,...,n}$", "audio_path": "audio/row_01298333_1755745551450020.wav", "formula": "$\\mathbf{M}=\\{\\mathbf{M}_i\\}_{i=1,...,n}$", "answer": "Math bold M equals open curly brace math bold M sub i close curly brace sub i equals 1 comma dot dot dot comma n", "subset": "mixmath", "task_type": "tts"} +{"index": 1708, "question": "请你朗读以下数学公式符号:$3\\div \\frac{1}{3}\\div \\frac{3}{4}\\div 4=3\\times 3\\times \\frac{4}{3}\\times \\frac{1}{4}=3$", "audio_path": "audio/math_38423f05-2ebf-4ef4-82b5-b987ffdb147b.wav", "formula": "$3\\div \\frac{1}{3}\\div \\frac{3}{4}\\div 4=3\\times 3\\times \\frac{4}{3}\\times \\frac{1}{4}=3$", "answer": "三除以三分之一除以四分之三除以四等于三乘三乘三分之四乘四分之一等于三", "subset": "mixmath", "task_type": "tts"} +{"index": 1709, "question": "Please read the following math formula symbols: $$0\\leq\\widetildeA\\sim_{\\Q,Z}h^*C-\\varepsilonH'$$", "audio_path": "audio/row_00371106_1755630144497839.wav", "formula": "$$0\\leq\\widetildeA\\sim_{\\Q,Z}h^*C-\\varepsilonH'$$", "answer": "0 is less than or equal to tilde A similar to Q comma Z, h star C minus epsilon H prime.", "subset": "mixmath", "task_type": "tts"} +{"index": 1710, "question": "请你朗读以下数学公式符号:$$90\\times44\\div11\\div9=(90\\div9)\\times(44\\div11)=10\\times4=40$$", "audio_path": "audio/math_7d967f58-964d-4f63-8d24-fbe2850663b3.wav", "formula": "$$90\\times44\\div11\\div9=(90\\div9)\\times(44\\div11)=10\\times4=40$$", "answer": "九十乘四十四除以十一除以九等于九十除以九的商乘四十四除以十一的商等于十乘四等于四十", "subset": "mixmath", "task_type": "tts"} +{"index": 1711, "question": "请你朗读以下数学公式符号:${{4}^{x}}\\cdot {{32}^{y}}={{({{2}^{2}})}^{x}}\\cdot {{({{2}^{5}})}^{y}}={{2}^{2x}}\\cdot {{2}^{5y}}={{2}^{2x+5y}}$", "audio_path": "audio/math_17ec270a-863e-4e06-a24e-c437609d4b78.wav", "formula": "${{4}^{x}}\\cdot {{32}^{y}}={{({{2}^{2}})}^{x}}\\cdot {{({{2}^{5}})}^{y}}={{2}^{2x}}\\cdot {{2}^{5y}}={{2}^{2x+5y}}$", "answer": "四的x次方乘三十二的y次方等于二的平方的x次方乘二的五次方的y次方等于二的二x次方乘二的五y次方等于二的二x加五y的和次方", "subset": "mixmath", "task_type": "tts"} +{"index": 1712, "question": "Please read the following math formula symbols: $$\\isom(\\matH^3)\\to\\isom(\\matH^3)\\,,\\qquadg\\mapstog\\cdotr_i$$", "audio_path": "audio/row_01687865_1755794702351992.wav", "formula": "$$\\isom(\\matH^3)\\to\\isom(\\matH^3)\\,,\\qquadg\\mapstog\\cdotr_i$$", "answer": "Empty set of matrices of size 3 maps to em of dimension 3, comma, g maps to g times r sub i.", "subset": "mixmath", "task_type": "tts"} +{"index": 1713, "question": "Please read the following math formula symbols: $p_0,p_n\\in\\mathbfP_{U_\\xi}\\cap\\mathbfP_{U_\\zeta}$", "audio_path": "audio/row_01098092_1755720489897895.wav", "formula": "$p_0,p_n\\in\\mathbfP_{U_\\xi}\\cap\\mathbfP_{U_\\zeta}$", "answer": "p sub 0, p sub n, belongs to the set of P sub U sub xi intersect P sub U sub zeta.", "subset": "mixmath", "task_type": "tts"} +{"index": 1714, "question": "请你朗读以下数学公式符号:$\\dfrac{3}{4}=\\dfrac{3\\times4}{4\\times4}=\\dfrac{12}{16}$", "audio_path": "audio/math_75a4767f-c48d-4dcd-a758-88840b10494b.wav", "formula": "$\\dfrac{3}{4}=\\dfrac{3\\times4}{4\\times4}=\\dfrac{12}{16}$", "answer": "四分之三等于四乘四的积 分之三乘四的积 等于十六分之十二", "subset": "mixmath", "task_type": "tts"} +{"index": 1715, "question": "Please read the following math formula symbols: $\\bmf:\\mathcalX\\mapsto\\mathcalV(\\mathcalX)\\subseteq\\R^n$", "audio_path": "audio/row_00168540_1755605505603755.wav", "formula": "$\\bmf:\\mathcalX\\mapsto\\mathcalV(\\mathcalX)\\subseteq\\R^n$", "answer": "f maps the set X to the set V of X, which is a subset of R to the power of n.", "subset": "mixmath", "task_type": "tts"} +{"index": 1716, "question": "Please read the following math formula symbols: $$Y_i=f\\left(X_i\\right)+g_Y\\left(D_i\\right)+\\varepsilon_{Yi}$$", "audio_path": "audio/row_00771447_1755679608437862.wav", "formula": "$$Y_i=f\\left(X_i\\right)+g_Y\\left(D_i\\right)+\\varepsilon_{Yi}$$", "answer": "Y sub i equals f of X sub i plus g sub Y of D sub i plus epsilon sub Y.", "subset": "mixmath", "task_type": "tts"} +{"index": 1717, "question": "请你朗读以下数学公式符号:$=\\left( \\frac{5}{8}+\\frac{3}{8} \\right)+\\left( \\frac{7}{10}+\\frac{3}{10} \\right)$", "audio_path": "audio/math_092ffb4f-13e7-45bf-9046-bb587e728c1c.wav", "formula": "$=\\left( \\frac{5}{8}+\\frac{3}{8} \\right)+\\left( \\frac{7}{10}+\\frac{3}{10} \\right)$", "answer": "等于八分之五加八分之三的和加十分之七加十分之三的和", "subset": "mixmath", "task_type": "tts"} +{"index": 1718, "question": "Please read the following math formula symbols: $|S_2|\\geq2^{13}\\ln^2n$", "audio_path": "audio/row_01661555_1755791387421185.wav", "formula": "$|S_2|\\geq2^{13}\\ln^2n$", "answer": "Absolute value of S sub 2 is greater than or equal to 2 to the power of 13 times the natural logarithm squared of n.", "subset": "mixmath", "task_type": "tts"} +{"index": 1719, "question": "Please read the following math formula symbols: $\\mathcal{O}(1)\\leq\\ell\\leq\\mathcal{O}(100)$", "audio_path": "audio/row_00337006_1755626001847584.wav", "formula": "$\\mathcal{O}(1)\\leq\\ell\\leq\\mathcal{O}(100)$", "answer": "Big O of 1 is less than or equal to ell, which is less than or equal to Big O of 100.", "subset": "mixmath", "task_type": "tts"} +{"index": 1720, "question": "Please read the following math formula symbols: $\\mathbf{B}=[\\mathbf{B}_1,\\cdots,\\mathbf{B}_M]$", "audio_path": "audio/row_01944021_1755827085690412.wav", "formula": "$\\mathbf{B}=[\\mathbf{B}_1,\\cdots,\\mathbf{B}_M]$", "answer": "Math bold B equals open square bracket math bold B sub 1 comma ellipsis comma math bold B sub M close square bracket.", "subset": "mixmath", "task_type": "tts"} +{"index": 1721, "question": "Please read the following math formula symbols: $R(t):0\\leqslantR(t)\\leqslant1$", "audio_path": "audio/row_00156431_1755604020814191.wav", "formula": "$R(t):0\\leqslantR(t)\\leqslant1$", "answer": "R of t, colon, zero is less than or equal to R of t, which is less than or equal to one.", "subset": "mixmath", "task_type": "tts"} +{"index": 1722, "question": "请你朗读以下数学公式符号:$\\left\\{ \\begin{matrix}a=2 \\\\ b=1 \\end{matrix} \\right.$", "audio_path": "audio/math_887c7a7f-bdd6-4036-87b2-764c9571b4df.wav", "formula": "$\\left\\{ \\begin{matrix}a=2 \\\\ b=1 \\end{matrix} \\right.$", "answer": "a等于二,b等于一", "subset": "mixmath", "task_type": "tts"} +{"index": 1723, "question": "Please read the following math formula symbols: $w_{ij}=r^{cls}_{ij}\\cdotr^{obj}_{ij}$", "audio_path": "audio/row_00868507_1755691841502028.wav", "formula": "$w_{ij}=r^{cls}_{ij}\\cdotr^{obj}_{ij}$", "answer": "W subscript i j equals r superscript c l s subscript i j times r superscript o b j subscript i j.", "subset": "mixmath", "task_type": "tts"} +{"index": 1724, "question": "请你朗读以下数学公式符号:$\\boxed{0} \\ \\boxed{2} \\ \\boxed{3} \\ \\boxed{5} \\ \\boxed{7}$", "audio_path": "audio/math_d172a770-1333-43ec-a942-21b8774a90e4.wav", "formula": "$\\boxed{0} \\ \\boxed{2} \\ \\boxed{3} \\ \\boxed{5} \\ \\boxed{7}$", "answer": "零 二 三 五 七", "subset": "mixmath", "task_type": "tts"} +{"index": 1725, "question": "请你朗读以下数学公式符号:$\\begin{eqnarray}&&125\\times88\\\\ &=&125\\times (8\\times11)\\\\ &=&(125\\times8)\\times11\\\\ &=&1000\\times11\\\\ &=&11000\\end{eqnarray}$", "audio_path": "audio/math_1672b711-0898-4f18-a6f8-59bdcd98b14c.wav", "formula": "$\\begin{eqnarray}&&125\\times88\\\\ &=&125\\times (8\\times11)\\\\ &=&(125\\times8)\\times11\\\\ &=&1000\\times11\\\\ &=&11000\\end{eqnarray}$", "answer": "一百二十五乘八十八等于一百二十五乘八乘十一的积,等于一百二十五乘八的积乘十一,等于一千乘十一,等于一万一千。", "subset": "mixmath", "task_type": "tts"} +{"index": 1726, "question": "请你朗读以下数学公式符号:$$\\left[ \\frac{x}{2} \\right]+\\left[ \\frac{x}{3} \\right]+\\left[ \\frac{x}{6} \\right]\\leqslant \\frac{x}{2}+\\frac{x}{3}+\\frac{x}{6}=x$$", "audio_path": "audio/math_1ab48c16-9fb1-4b99-8bda-1daff2d5dfc7.wav", "formula": "$$\\left[ \\frac{x}{2} \\right]+\\left[ \\frac{x}{3} \\right]+\\left[ \\frac{x}{6} \\right]\\leqslant \\frac{x}{2}+\\frac{x}{3}+\\frac{x}{6}=x$$", "answer": "二分之x的整数部分 加 三分之x的整数部分 加 六分之x的整数部分 小于等于 二分之x 加 三分之x 加 六分之x 等于 x", "subset": "mixmath", "task_type": "tts"} +{"index": 1727, "question": "Please read the following math formula symbols: $u=\\|\\frac{\\by_t-\\bx_{i_t}}{h}\\|^2\\bigr/2$", "audio_path": "audio/row_01042354_1755713536200781.wav", "formula": "$u=\\|\\frac{\\by_t-\\bx_{i_t}}{h}\\|^2\\bigr/2$", "answer": "u equals the norm of the fraction with numerator b times x sub i sub t, and denominator h, squared, divided by 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 1728, "question": "请你朗读以下数学公式符号:$$ \\frac{{\\mathrm{c}\\mathrm{o}\\mathrm{s}}^{2}{30}^{0}+{\\mathrm{c}\\mathrm{o}\\mathrm{s}}^{2}{60}^{0}}{\\mathrm{t}\\mathrm{a}\\mathrm{n}{60}^{0}\\times \\mathrm{t}\\mathrm{a}\\mathrm{n}{30}^{0}}+\\mathrm{s}\\mathrm{i}\\mathrm{n}{45}^{0}$$", "audio_path": "audio/math_27d0aa92-b874-4831-856a-b358f1617236.wav", "formula": "$$ \\frac{{\\mathrm{c}\\mathrm{o}\\mathrm{s}}^{2}{30}^{0}+{\\mathrm{c}\\mathrm{o}\\mathrm{s}}^{2}{60}^{0}}{\\mathrm{t}\\mathrm{a}\\mathrm{n}{60}^{0}\\times \\mathrm{t}\\mathrm{a}\\mathrm{n}{30}^{0}}+\\mathrm{s}\\mathrm{i}\\mathrm{n}{45}^{0}$$", "answer": "tangent 六十度 乘 tangent 三十度 的积分之 cosine 三十度的平方 加 cosine 六十度的平方的和,再加sine 四十五度", "subset": "mixmath", "task_type": "tts"} +{"index": 1729, "question": "请你朗读以下数学公式符号:$\\therefore {{a}^{2}}+2ab+{{b}^{2}} < {{c}^{2}}+2ch+{{h}^{2}}$", "audio_path": "audio/math_6ea510f8-6978-4ff9-a80e-3c47c1dd5ba7.wav", "formula": "$\\therefore {{a}^{2}}+2ab+{{b}^{2}} < {{c}^{2}}+2ch+{{h}^{2}}$", "answer": "所以,a的平方加二a b加b的平方小于c的平方加二c h加h的平方", "subset": "mixmath", "task_type": "tts"} +{"index": 1730, "question": "请你朗读以下数学公式符号:${{S}_{{}}}=4\\times 3+4\\times 2+3\\times 2\\times 2\\times 3=156$", "audio_path": "audio/math_2c154e65-9829-46d3-a279-8e3e14d2ce69.wav", "formula": "${{S}_{{}}}=4\\times 3+4\\times 2+3\\times 2\\times 2\\times 3=156$", "answer": "S等于四乘三加四乘二加三乘二乘二乘三等于一百五十六", "subset": "mixmath", "task_type": "tts"} +{"index": 1731, "question": "请你朗读以下数学公式符号:$\\frac{1}{2\\times 3\\times 4\\times 5}=\\frac{1}{120}$", "audio_path": "audio/math_18a937af-feda-4ad7-882b-a862428a15c5.wav", "formula": "$\\frac{1}{2\\times 3\\times 4\\times 5}=\\frac{1}{120}$", "answer": "二乘三乘四乘五的积分之一等于一百二十分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 1732, "question": "请你朗读以下数学公式符号:$\\left( x+a \\right)\\left( x+b \\right)=\\left( x+2 \\right)\\left( x+5 \\right)$", "audio_path": "audio/math_bfe9800e-3da0-44c3-ad1d-471debf744d8.wav", "formula": "$\\left( x+a \\right)\\left( x+b \\right)=\\left( x+2 \\right)\\left( x+5 \\right)$", "answer": "x加a的和乘x加b的和等于x加二的和乘x加五的和", "subset": "mixmath", "task_type": "tts"} +{"index": 1733, "question": "Please read the following math formula symbols: $\\displaystyle\\frac{(-1)^j(j+1)!}{a_{j-1}}$", "audio_path": "audio/row_00552734_1755652395273731.wav", "formula": "$\\displaystyle\\frac{(-1)^j(j+1)!}{a_{j-1}}$", "answer": "Fraction, negative one raised to the power of j times j plus one factorial, divided by a sub j minus one.", "subset": "mixmath", "task_type": "tts"} +{"index": 1734, "question": "Please read the following math formula symbols: $x^i(\\lambda):=x^i\\circc(\\lambda)$", "audio_path": "audio/row_01512083_1755772462560622.wav", "formula": "$x^i(\\lambda):=x^i\\circc(\\lambda)$", "answer": "x raised to the power of i, parentheses lambda, equals x raised to the power of i, circle c, parentheses lambda.", "subset": "mixmath", "task_type": "tts"} +{"index": 1735, "question": "请你朗读以下数学公式符号:$\\frac{1}{84}\\times 6+\\frac{1}{55}\\times 5=\\frac{25}{154}$", "audio_path": "audio/math_58ebed8d-b41d-4af1-9a16-b9ab2c979b55.wav", "formula": "$\\frac{1}{84}\\times 6+\\frac{1}{55}\\times 5=\\frac{25}{154}$", "answer": "八十四分之一乘六加五十五分之一乘五等于一百五十四分之二十五", "subset": "mixmath", "task_type": "tts"} +{"index": 1736, "question": "请你朗读以下数学公式符号:$\\begin{eqnarray} x:20&=&133.5:15\\\\ 15x&=&133.5\\times20\\\\ 15x&=&2670\\\\ 15x\\div15&=&2670\\div15\\\\ x&=&178\\end{eqnarray}$", "audio_path": "audio/math_24882663-5583-46df-aa8b-2d11073d0606.wav", "formula": "$\\begin{eqnarray} x:20&=&133.5:15\\\\ 15x&=&133.5\\times20\\\\ 15x&=&2670\\\\ 15x\\div15&=&2670\\div15\\\\ x&=&178\\end{eqnarray}$", "answer": "x 比 二十 等于 一百三十三点五 比 十五;十五x 等于 一百三十三点五 乘 二十;十五x 等于 两千六百七十;十五x 除以 十五 等于 两千六百七十 除以 十五;x 等于 一百七十八", "subset": "mixmath", "task_type": "tts"} +{"index": 1737, "question": "请你朗读以下数学公式符号:$$6\\times6\\times6\\times6\\times6\\times6\\times6=279936$$", "audio_path": "audio/math_b7e4fd3e-954b-4647-ba72-62685987c1d0.wav", "formula": "$$6\\times6\\times6\\times6\\times6\\times6\\times6=279936$$", "answer": "六乘六乘六乘六乘六乘六乘六等于二十七万九千九百三十六", "subset": "mixmath", "task_type": "tts"} +{"index": 1738, "question": "Please read the following math formula symbols: $\\red(\\mathbf{a})=(a_{i_1},a_{i_2},\\dots,a_{i_k})$", "audio_path": "audio/row_01445072_1755764008113028.wav", "formula": "$\\red(\\mathbf{a})=(a_{i_1},a_{i_2},\\dots,a_{i_k})$", "answer": "red of a equals open parenthesis a sub i sub 1, a sub i sub 2, dot dot dot, a sub i sub k close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 1739, "question": "Please read the following math formula symbols: $\\sqrt{n\\alpha_n}F_0(\\tilde{\\psi}_{[K_n]})=o(1)$", "audio_path": "audio/row_00323460_1755624350513280.wav", "formula": "$\\sqrt{n\\alpha_n}F_0(\\tilde{\\psi}_{[K_n]})=o(1)$", "answer": "Square root of n times alpha sub n, times F sub 0 of psi tilde sub K sub n, equals little o of 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 1740, "question": "Please read the following math formula symbols: $\\tilde{\\mathbf{Q}}_i^l\\in\\mathbb{R}^d$", "audio_path": "audio/row_00870364_1755692056065853.wav", "formula": "$\\tilde{\\mathbf{Q}}_i^l\\in\\mathbb{R}^d$", "answer": "The tilde of the bold Q, subscript i, superscript l, belongs to the set of real numbers raised to the power of d.", "subset": "mixmath", "task_type": "tts"} +{"index": 1741, "question": "Please read the following math formula symbols: $|\\xi-\\sqrt{3}|\\gtrsim2^{-100}$", "audio_path": "audio/row_00576795_1755655376432242.wav", "formula": "$|\\xi-\\sqrt{3}|\\gtrsim2^{-100}$", "answer": "Absolute value of xi minus square root of 3, greater than or approximately equal to 2 to the power of negative 100.", "subset": "mixmath", "task_type": "tts"} +{"index": 1742, "question": "Please read the following math formula symbols: $Y=[y_1,y_2,...y_n]$", "audio_path": "audio/row_01747839_1755802314691588.wav", "formula": "$Y=[y_1,y_2,...y_n]$", "answer": "Y equals open square bracket, y sub 1, comma, y sub 2, comma, dot dot dot, y sub n, close square bracket.", "subset": "mixmath", "task_type": "tts"} +{"index": 1743, "question": "请你朗读以下数学公式符号:$\\frac{4}{7}=0.\\overset{\\centerdot }{\\mathop{5}}\\,7142\\overset{\\centerdot }{\\mathop{8}}\\,$", "audio_path": "audio/math_25e68ac7-c8da-4dfd-a210-45af690c2445.wav", "formula": "$\\frac{4}{7}=0.\\overset{\\centerdot }{\\mathop{5}}\\,7142\\overset{\\centerdot }{\\mathop{8}}\\,$", "answer": "七分之四等于零点五七一四二八 五七一四二八循环", "subset": "mixmath", "task_type": "tts"} +{"index": 1744, "question": "Please read the following math formula symbols: $f(t)=\\alpha_s(\\Phi(q_1)+t\\vw)$", "audio_path": "audio/row_01506777_1755771806982408.wav", "formula": "$f(t)=\\alpha_s(\\Phi(q_1)+t\\vw)$", "answer": "f of t equals alpha sub s open parenthesis Phi of q sub 1 plus t times v times w close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 1745, "question": "请你朗读以下数学公式符号:$\\frac{4}{5}=\\frac{4\\times 4}{5\\times 4}=\\frac{16}{20}$", "audio_path": "audio/math_5da1ecef-89b8-4015-b7bf-ad472204898b.wav", "formula": "$\\frac{4}{5}=\\frac{4\\times 4}{5\\times 4}=\\frac{16}{20}$", "answer": "五分之四等于五乘四的积 分之四乘四的积 等于二十分之十六", "subset": "mixmath", "task_type": "tts"} +{"index": 1746, "question": "Please read the following math formula symbols: $\\lambda_{n}B_{n}/\\mathcal{D}'(G_{n},G_{*,n})\\to0$", "audio_path": "audio/row_00479721_1755643450053130.wav", "formula": "$\\lambda_{n}B_{n}/\\mathcal{D}'(G_{n},G_{*,n})\\to0$", "answer": "Lambda sub n B sub n divided by D prime of G sub n, G sub asterisk comma n tends to zero.", "subset": "mixmath", "task_type": "tts"} +{"index": 1747, "question": "Please read the following math formula symbols: $|\\xi_3|\\lesssim2^{-\\ell-10}$", "audio_path": "audio/row_00576647_1755655357084032.wav", "formula": "$|\\xi_3|\\lesssim2^{-\\ell-10}$", "answer": "Absolute value of xi sub 3 is less than or approximately equal to 2 to the power of negative ell minus 10.", "subset": "mixmath", "task_type": "tts"} +{"index": 1748, "question": "请你朗读以下数学公式符号:$\\begin{eqnarray}\\frac{3}{4}:x&=&3:12\\\\ 3x&=&\\frac{3}{4}\\times 12\\\\ 3x\\div 3&=&\\frac{3}{4}\\times 12\\div 3\\\\ x&=&3\\end{eqnarray}$", "audio_path": "audio/math_ebfebef2-baf0-490e-8f43-9855c3e2efbc.wav", "formula": "$\\begin{eqnarray}\\frac{3}{4}:x&=&3:12\\\\ 3x&=&\\frac{3}{4}\\times 12\\\\ 3x\\div 3&=&\\frac{3}{4}\\times 12\\div 3\\\\ x&=&3\\end{eqnarray}$", "answer": "四分之三比x等于三比十二,三x等于四分之三乘十二,三x除以三等于四分之三乘十二除以三,x等于三", "subset": "mixmath", "task_type": "tts"} +{"index": 1749, "question": "请你朗读以下数学公式符号:$\\left\\{ \\begin{array}{l} {x=10} \\\\ {y=2} \\end{array}\\right.$", "audio_path": "audio/math_d0000f59-4b29-44ae-a665-bc4f207ba0c5.wav", "formula": "$\\left\\{ \\begin{array}{l} {x=10} \\\\ {y=2} \\end{array}\\right.$", "answer": "x等于十和y等于二", "subset": "mixmath", "task_type": "tts"} +{"index": 1750, "question": "请你朗读以下数学公式符号:$\\frac{5}{6}+\\frac{1}{3}+\\frac{1}{6}=\\frac{5}{6}+\\frac{1}{6}+\\frac{1}{3}=1+\\frac{1}{3}=1\\frac{1}{3}$", "audio_path": "audio/math_180eec55-53eb-4cee-99a2-151aa9134500.wav", "formula": "$\\frac{5}{6}+\\frac{1}{3}+\\frac{1}{6}=\\frac{5}{6}+\\frac{1}{6}+\\frac{1}{3}=1+\\frac{1}{3}=1\\frac{1}{3}$", "answer": "六分之五加三分之一加六分之一等于六分之五加六分之一加三分之一等于一加三分之一等于一又三分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 1751, "question": "请你朗读以下数学公式符号:$\\begin{equation}5.4\\times \\left( 12.3+7.7 \\right)\\end{equation}$", "audio_path": "audio/math_8b46c572-971c-4da2-9cd1-04501714cd20.wav", "formula": "$\\begin{equation}5.4\\times \\left( 12.3+7.7 \\right)\\end{equation}$", "answer": "五点四乘 十二点三加七点七的和", "subset": "mixmath", "task_type": "tts"} +{"index": 1752, "question": "Please read the following math formula symbols: $\\varphi:\\mathbb{R}^n\\to\\Rex$", "audio_path": "audio/row_00143859_1755602494164338.wav", "formula": "$\\varphi:\\mathbb{R}^n\\to\\Rex$", "answer": "Phi, colon, the set of real numbers raised to the power of n, maps to the set of extended real numbers.", "subset": "mixmath", "task_type": "tts"} +{"index": 1753, "question": "请你朗读以下数学公式符号:$=\\frac{4}{7}\\times \\left( 23\\frac{12}{13}+\\frac{1}{13}+4 \\right)$", "audio_path": "audio/math_e755dfe7-9bb4-4e96-b269-e349ce3a01b2.wav", "formula": "$=\\frac{4}{7}\\times \\left( 23\\frac{12}{13}+\\frac{1}{13}+4 \\right)$", "answer": "等于七分之四乘二十三又十三分之十二加十三分之一加四的和", "subset": "mixmath", "task_type": "tts"} +{"index": 1754, "question": "Please read the following math formula symbols: $\\kappa_n:=\\sum_{i=1}^n\\hat\\kappa_i(t)\\phi_i(x)$", "audio_path": "audio/row_01523495_1755773915986314.wav", "formula": "$\\kappa_n:=\\sum_{i=1}^n\\hat\\kappa_i(t)\\phi_i(x)$", "answer": "Kappa sub n equals the sum from i equals 1 to n of kappa sub i of t times phi sub i of x.", "subset": "mixmath", "task_type": "tts"} +{"index": 1755, "question": "Please read the following math formula symbols: $\\bar\\xx=\\frac{1}{n}\\sum_i\\xx_i$", "audio_path": "audio/row_00648384_1755664318111449.wav", "formula": "$\\bar\\xx=\\frac{1}{n}\\sum_i\\xx_i$", "answer": "The average of x is equal to one over n times the sum of x sub i where i goes back to x.", "subset": "mixmath", "task_type": "tts"} +{"index": 1756, "question": "Please read the following math formula symbols: $M=\\dfrac{r_h^4}{\\ell^2}+\\dfrac{Q^2}{r_h^2}$", "audio_path": "audio/row_00015904_1755587030724378.wav", "formula": "$M=\\dfrac{r_h^4}{\\ell^2}+\\dfrac{Q^2}{r_h^2}$", "answer": "M equals r sub h to the power of 4 over ell squared plus Q squared over r sub h squared.", "subset": "mixmath", "task_type": "tts"} +{"index": 1757, "question": "Please read the following math formula symbols: $a_{n+1}=a_n-\\phi(a_n)/\\phi'(a_n)$", "audio_path": "audio/row_01994549_1755833449061465.wav", "formula": "$a_{n+1}=a_n-\\phi(a_n)/\\phi'(a_n)$", "answer": "a sub n plus one equals a sub n minus phi of a sub n divided by phi prime of a sub n", "subset": "mixmath", "task_type": "tts"} +{"index": 1758, "question": "Please read the following math formula symbols: $\\delta^{(4)}\\left(\\sum\\limits_{i=1}^Np_i\\right)$", "audio_path": "audio/row_01527365_1755774403205901.wav", "formula": "$\\delta^{(4)}\\left(\\sum\\limits_{i=1}^Np_i\\right)$", "answer": "Delta to the power of four, open parenthesis, the sum from i equals one to N of p sub i, close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 1759, "question": "请你朗读以下数学公式符号:$\\left\\{ \\begin{array}{*{35}{l}} x=\\dfrac{3}{2} \\\\ y=\\dfrac{4}{3} \\\\\\end{array} \\right.$", "audio_path": "audio/math_1b9a50c2-6f0f-46ee-825b-5b5cba6bfe0e.wav", "formula": "$\\left\\{ \\begin{array}{*{35}{l}} x=\\dfrac{3}{2} \\\\ y=\\dfrac{4}{3} \\\\\\end{array} \\right.$", "answer": "x等于二分之三,y等于三分之四", "subset": "mixmath", "task_type": "tts"} +{"index": 1760, "question": "Please read the following math formula symbols: $\\mathcal{T}(s_{t-1}|s_{t-2},\\bm{a}_{t-2})$", "audio_path": "audio/row_01859609_1755816418376561.wav", "formula": "$\\mathcal{T}(s_{t-1}|s_{t-2},\\bm{a}_{t-2})$", "answer": "Mathcal T, open parenthesis, s sub t minus 1, vertical bar, s sub t minus 2, comma, a sub t minus 2, close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 1761, "question": "请你朗读以下数学公式符号:$$\\frac{\\left(~ ~ ~ ~ ~ ~ \\right)}{30}=\\frac{2}{3}=\\frac{18}{\\left(~ ~ ~ ~ ~ ~ \\right)}=6\\div \\left(~ ~ ~ ~ ~ ~ \\right)$$", "audio_path": "audio/math_247b72cc-7c19-4f01-91ee-aa529ea1be3e.wav", "formula": "$$\\frac{\\left(~ ~ ~ ~ ~ ~ \\right)}{30}=\\frac{2}{3}=\\frac{18}{\\left(~ ~ ~ ~ ~ ~ \\right)}=6\\div \\left(~ ~ ~ ~ ~ ~ \\right)$$", "answer": "三十分之多少等于三分之二等于多少分之十八等于六除以多少", "subset": "mixmath", "task_type": "tts"} +{"index": 1762, "question": "请你朗读以下数学公式符号:$={{\\left( x+y \\right)}^{3}}\\cdot {{\\left[ 2\\left( x+y \\right) \\right]}^{3}}\\cdot {{\\left[ 3\\left( x+y \\right) \\right]}^{3}}$", "audio_path": "audio/math_2ad44b68-c254-44e0-9375-2681addf1aed.wav", "formula": "$={{\\left( x+y \\right)}^{3}}\\cdot {{\\left[ 2\\left( x+y \\right) \\right]}^{3}}\\cdot {{\\left[ 3\\left( x+y \\right) \\right]}^{3}}$", "answer": "等于x加y的和的立方 乘二乘x加y的和的积的立方 乘三乘x加y的和的积的立方", "subset": "mixmath", "task_type": "tts"} +{"index": 1763, "question": "请你朗读以下数学公式符号:$X = \\frac{5}{7}\\times \\left( \\frac{2}{13}+\\frac{7}{13} \\right)$", "audio_path": "audio/math_dbc9ba16-37e3-4dc3-8c82-88ac1b480eff.wav", "formula": "$X = \\frac{5}{7}\\times \\left( \\frac{2}{13}+\\frac{7}{13} \\right)$", "answer": "X等于七分之五乘十三分之二加十三分之七的和", "subset": "mixmath", "task_type": "tts"} +{"index": 1764, "question": "Please read the following math formula symbols: $r>q>-\\lambda^{[x,z]}_{0}$", "audio_path": "audio/row_01516941_1755773084165576.wav", "formula": "$r>q>-\\lambda^{[x,z]}_{0}$", "answer": "r greater than q greater than negative lambda raised to the power of the commutator of x and z sub 0.", "subset": "mixmath", "task_type": "tts"} +{"index": 1765, "question": "请你朗读以下数学公式符号:$$1\\frac{1}{3}\\ \\times\\frac{2}{3}=\\frac{4}{3}\\ \\times \\frac{2}{3}=\\frac{8}{9}$$", "audio_path": "audio/math_53eebc23-76a3-4dbc-8554-5510e010ad97.wav", "formula": "$$1\\frac{1}{3}\\ \\times\\frac{2}{3}=\\frac{4}{3}\\ \\times \\frac{2}{3}=\\frac{8}{9}$$", "answer": "一又三分之二乘三分之二等于三分之四乘三分之二等于九分之八", "subset": "mixmath", "task_type": "tts"} +{"index": 1766, "question": "请你朗读以下数学公式符号:$2\\times 2\\times 2\\times 2\\times 2\\times 2\\times 2=128$", "audio_path": "audio/math_f35eb5ac-fa80-4b4a-aac1-9f4b08cd0e8a.wav", "formula": "$2\\times 2\\times 2\\times 2\\times 2\\times 2\\times 2=128$", "answer": "二乘二乘二乘二乘二乘二乘二等于一百二十八", "subset": "mixmath", "task_type": "tts"} +{"index": 1767, "question": "Please read the following math formula symbols: $\\gamma\\geq|Y|\\geq|Y-S|$", "audio_path": "audio/row_01053602_1755714938420668.wav", "formula": "$\\gamma\\geq|Y|\\geq|Y-S|$", "answer": "gamma greater than or equal to absolute value of Y greater than or equal to absolute value of Y minus S.", "subset": "mixmath", "task_type": "tts"} +{"index": 1768, "question": "请你朗读以下数学公式符号:$[A,B,C]={{2}^{4}}\\times {{3}^{3}}\\times {{5}^{3}}$", "audio_path": "audio/math_a82da8f6-4114-4add-870f-5cae7a88809c.wav", "formula": "$[A,B,C]={{2}^{4}}\\times {{3}^{3}}\\times {{5}^{3}}$", "answer": "中括号A、B、C中括号等于二的四次方乘三的立方乘五的立方", "subset": "mixmath", "task_type": "tts"} +{"index": 1769, "question": "Please read the following math formula symbols: $\\sigma_\\mathrm{R}=8\\pi^3\\dcpolarizability^2/(3\\epsilon_0^2\\lambda^4)$", "audio_path": "audio/row_00507143_1755646806743782.wav", "formula": "$\\sigma_\\mathrm{R}=8\\pi^3\\dcpolarizability^2/(3\\epsilon_0^2\\lambda^4)$", "answer": "Sigma sub R equals 8 pi cubed times d c i zability divided by 3 epsilon sub 0 squared lambda to the power of 4.", "subset": "mixmath", "task_type": "tts"} +{"index": 1770, "question": "Please read the following math formula symbols: $\\|\\proj_{\\bU_{k-1}^{\\AO}}^\\perp\\bu_k^{\\AO}\\|$", "audio_path": "audio/row_01585495_1755781770533771.wav", "formula": "$\\|\\proj_{\\bU_{k-1}^{\\AO}}^\\perp\\bu_k^{\\AO}\\|$", "answer": "Norm of proj sub b times U sub k minus 1 superscript A times A, perpendicular to beta sub k superscript A times O.", "subset": "mixmath", "task_type": "tts"} +{"index": 1771, "question": "请你朗读以下数学公式符号:$$\\begin{cases}33x+17y=83 \\\\ 17x+33y=67 \\\\ \\end{cases}$$", "audio_path": "audio/math_04946373-8bf0-4841-9f88-9837ea7ade55.wav", "formula": "$$\\begin{cases}33x+17y=83 \\\\ 17x+33y=67 \\\\ \\end{cases}$$", "answer": "三十三x加十七y等于八十三,十七x加三十三y等于六十七。", "subset": "mixmath", "task_type": "tts"} +{"index": 1772, "question": "Please read the following math formula symbols: $v(s)=\\innorm{\\pi_s,Q(s,\\cdot)}_{\\A},\\quad\\foralls\\in\\St$", "audio_path": "audio/row_00555078_1755652693506179.wav", "formula": "$v(s)=\\innorm{\\pi_s,Q(s,\\cdot)}_{\\A},\\quad\\foralls\\in\\St$", "answer": "v of s equals the inner product of pi sub s, Q of s, dot, sub A, for all s in S.", "subset": "mixmath", "task_type": "tts"} +{"index": 1773, "question": "请你朗读以下数学公式符号:$720\\times \\frac{1}{2}\\times \\frac{1}{3+2+1}=6{c}{{{m}}^{2}}$", "audio_path": "audio/math_56048c49-705f-4f0c-a628-2da64176d466.wav", "formula": "$720\\times \\frac{1}{2}\\times \\frac{1}{3+2+1}=6{c}{{{m}}^{2}}$", "answer": "七百二十乘二分之一乘三加二加一的和分之一等于六平方厘米", "subset": "mixmath", "task_type": "tts"} +{"index": 1774, "question": "Please read the following math formula symbols: $\\{e^{-t\\mathcal\\{A}\\}_{t\\geq0}$", "audio_path": "audio/row_01997244_1755833793056696.wav", "formula": "$\\{e^{-t\\mathcal\\{A}\\}_{t\\geq0}$", "answer": "Open brace, e to the power of negative t times script A, close brace, subscript t greater than or equal to zero.", "subset": "mixmath", "task_type": "tts"} +{"index": 1775, "question": "请你朗读以下数学公式符号:$\\begin{cases} 3x+2\\left( x+1 \\right)>0 \\\\ 2x+5a>4x+3a \\end{cases}$", "audio_path": "audio/math_483ca65c-0f37-4917-b41c-70e7fcd05594.wav", "formula": "$\\begin{cases} 3x+2\\left( x+1 \\right)>0 \\\\ 2x+5a>4x+3a \\end{cases}$", "answer": "三x加二乘x加一的和大于零 和 二x加五a大于四x加三a", "subset": "mixmath", "task_type": "tts"} +{"index": 1776, "question": "请你朗读以下数学公式符号:$\\frac{{{3}^{2}}+{{4}^{2}}}{3\\times 4}=\\frac{25}{12}=2\\frac{1}{12}$", "audio_path": "audio/math_4bdeb873-8ba2-42c2-a756-23087c09011e.wav", "formula": "$\\frac{{{3}^{2}}+{{4}^{2}}}{3\\times 4}=\\frac{25}{12}=2\\frac{1}{12}$", "answer": "三乘四的积分之三的平方与四的平方的和等于十二分之二十五等于二又十二分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 1777, "question": "请你朗读以下数学公式符号:$\\mathrm{\\angle }\\mathrm{A}=\\mathrm{\\angle }\\mathrm{D}$", "audio_path": "audio/math_648caa49-155b-4aff-b2e5-a7983dd32782.wav", "formula": "$\\mathrm{\\angle }\\mathrm{A}=\\mathrm{\\angle }\\mathrm{D}$", "answer": "角A等于角D", "subset": "mixmath", "task_type": "tts"} +{"index": 1778, "question": "Please read the following math formula symbols: $u_0\\in\\dot{H}^1\\cap\\dot{H}^s$", "audio_path": "audio/row_01451480_1755764818493935.wav", "formula": "$u_0\\in\\dot{H}^1\\cap\\dot{H}^s$", "answer": "u sub 0 belongs to the complement of H raised to the power of 1 intersect the complement of H raised to the power of s.", "subset": "mixmath", "task_type": "tts"} +{"index": 1779, "question": "Please read the following math formula symbols: $I\\subseteq[m]=\\{1,2,\\ldots,m\\}$", "audio_path": "audio/row_00662059_1755666015703503.wav", "formula": "$I\\subseteq[m]=\\{1,2,\\ldots,m\\}$", "answer": "I is a subset of the set containing elements m, which is equal to the set containing 1, 2, dot dot dot, m.", "subset": "mixmath", "task_type": "tts"} +{"index": 1780, "question": "Please read the following math formula symbols: $E_0\\subsetS^{d-1}\\subset\\R^d$", "audio_path": "audio/row_01370655_1755754628277463.wav", "formula": "$E_0\\subsetS^{d-1}\\subset\\R^d$", "answer": "E sub 0 is a subset of S to the power of d minus 1 is a subset of R to the power of d.", "subset": "mixmath", "task_type": "tts"} +{"index": 1781, "question": "Please read the following math formula symbols: $\\Re(Z'_0(E_{i+1}))>\\Re(Z'_0(E_{i}))$", "audio_path": "audio/row_01198420_1755733067564041.wav", "formula": "$\\Re(Z'_0(E_{i+1}))>\\Re(Z'_0(E_{i}))$", "answer": "Re of Z prime sub 0 of E sub i plus 1 is greater than Re of Z prime sub 0 of E sub i.", "subset": "mixmath", "task_type": "tts"} +{"index": 1782, "question": "Please read the following math formula symbols: $a(n)=\\int_XT^nf\\cdotg~d\\mu$", "audio_path": "audio/row_00675453_1755667656022803.wav", "formula": "$a(n)=\\int_XT^nf\\cdotg~d\\mu$", "answer": "a of n equals the integral over X of T to the power of n times f times g, d mu", "subset": "mixmath", "task_type": "tts"} +{"index": 1783, "question": "Please read the following math formula symbols: $U=\\exp(-iG_Nm\\ell\\sigma_z/2v^2d^2)$", "audio_path": "audio/row_00336879_1755625978894950.wav", "formula": "$U=\\exp(-iG_Nm\\ell\\sigma_z/2v^2d^2)$", "answer": "U equals e to the power of negative i g sub n m ell sigma sub z divided by 2 v squared d squared.", "subset": "mixmath", "task_type": "tts"} +{"index": 1784, "question": "Please read the following math formula symbols: $(|Y|+\\min(|X|,|Y|))t$", "audio_path": "audio/row_00179721_1755606868536641.wav", "formula": "$(|Y|+\\min(|X|,|Y|))t$", "answer": "The absolute value of Y plus the minimum of the absolute value of X and the absolute value of Y, all multiplied by t.", "subset": "mixmath", "task_type": "tts"} +{"index": 1785, "question": "Please read the following math formula symbols: $\\la^T_i-\\mu^T_i\\leq1$", "audio_path": "audio/row_01283939_1755743787663092.wav", "formula": "$\\la^T_i-\\mu^T_i\\leq1$", "answer": "Less than or equal to T sub i minus mu raised to the power of T sub i less than or equal to 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 1786, "question": "Please read the following math formula symbols: $\\bm\\Omega_{0}=\\bmT_{0}'\\bmD_{0}^{-1}\\bmT_{0}$", "audio_path": "audio/row_01489950_1755769695149265.wav", "formula": "$\\bm\\Omega_{0}=\\bmT_{0}'\\bmD_{0}^{-1}\\bmT_{0}$", "answer": "Bold Omega sub zero equals bold T sub zero prime times bold D sub zero inverse times bold T sub zero.", "subset": "mixmath", "task_type": "tts"} +{"index": 1787, "question": "请你朗读以下数学公式符号:$\\begin{eqnarray}x+4x+2&=&62\\\\ 5x&=&60\\\\ x&=&12\\end{eqnarray}$", "audio_path": "audio/math_0b7f4541-d37c-4069-9842-7ada95cf1717.wav", "formula": "$\\begin{eqnarray}x+4x+2&=&62\\\\ 5x&=&60\\\\ x&=&12\\end{eqnarray}$", "answer": "x加四x加二的和等于六十二\n五x等于六十\nx等于十二", "subset": "mixmath", "task_type": "tts"} +{"index": 1788, "question": "Please read the following math formula symbols: ${\\hat\\sigma}_z^i\\equiv\\hatn_{i,1}-\\hatn_{i,2}$", "audio_path": "audio/row_01966100_1755829883918634.wav", "formula": "${\\hat\\sigma}_z^i\\equiv\\hatn_{i,1}-\\hatn_{i,2}$", "answer": "The hat sigma sub z raised to the power of i is equivalent to the hat n sub i,1 minus the hat n sub i,2.", "subset": "mixmath", "task_type": "tts"} +{"index": 1789, "question": "Please read the following math formula symbols: $(F_2/F_1)^2-4F_3/F_1$", "audio_path": "audio/row_00415754_1755635615812767.wav", "formula": "$(F_2/F_1)^2-4F_3/F_1$", "answer": "Open parenthesis, F sub 2 divided by F sub 1, close parenthesis, squared, minus 4 times F sub 3 divided by F sub 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 1790, "question": "Please read the following math formula symbols: $p_1(q_{i-1},\\alpha_i,q_i)=\\alpha_i'$", "audio_path": "audio/row_01992848_1755833241598692.wav", "formula": "$p_1(q_{i-1},\\alpha_i,q_i)=\\alpha_i'$", "answer": "p sub 1 open parenthesis q sub i minus 1, alpha sub i, q sub i close parenthesis equals alpha sub i prime.", "subset": "mixmath", "task_type": "tts"} +{"index": 1791, "question": "Please read the following math formula symbols: $a_1\\lambda^*_{i_1}+\\dots+a_n\\lambda^*_{i_n}=0$", "audio_path": "audio/row_00847625_1755689207248859.wav", "formula": "$a_1\\lambda^*_{i_1}+\\dots+a_n\\lambda^*_{i_n}=0$", "answer": "a sub 1 lambda star sub i sub 1 plus dot dot dot plus a sub n lambda star sub i sub n equals 0", "subset": "mixmath", "task_type": "tts"} +{"index": 1792, "question": "Please read the following math formula symbols: $|\\alpha_n|\\le\\tau(n)^{B_0}$", "audio_path": "audio/row_01616802_1755785742942208.wav", "formula": "$|\\alpha_n|\\le\\tau(n)^{B_0}$", "answer": "Absolute value of alpha sub n is less than or equal to tau of n raised to the power of B sub 0.", "subset": "mixmath", "task_type": "tts"} +{"index": 1793, "question": "Please read the following math formula symbols: $Z_n(X,Y)\\subseteqC_n(X,Y)$", "audio_path": "audio/row_01248511_1755739343657897.wav", "formula": "$Z_n(X,Y)\\subseteqC_n(X,Y)$", "answer": "Z sub n open parenthesis X, Y close parenthesis is a subset of C sub n open parenthesis X, Y close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 1794, "question": "请你朗读以下数学公式符号:$={{\\left( {{x}_{1}}+{{x}_{2}} \\right)}^{2}}+{{x}_{1}}{{x}_{2}}$", "audio_path": "audio/math_91d0ec1c-2257-42c8-9fe1-015a74452319.wav", "formula": "$={{\\left( {{x}_{1}}+{{x}_{2}} \\right)}^{2}}+{{x}_{1}}{{x}_{2}}$", "answer": "等于x一加x二的完全平方,再加x一x二", "subset": "mixmath", "task_type": "tts"} +{"index": 1795, "question": "Please read the following math formula symbols: $E_Q(f(\\omega^1,\\dots,\\omega^k,-))$", "audio_path": "audio/row_00201741_1755609552775040.wav", "formula": "$E_Q(f(\\omega^1,\\dots,\\omega^k,-))$", "answer": "E Q of f of omega to the power of 1, dot dot dot, omega to the power of k, comma minus", "subset": "mixmath", "task_type": "tts"} +{"index": 1796, "question": "Please read the following math formula symbols: $P(h^c)\\leP(h^c)$", "audio_path": "audio/row_01211273_1755734692029609.wav", "formula": "$P(h^c)\\leP(h^c)$", "answer": "P of h to the power of c is less than or equal to P of h to the power of c.", "subset": "mixmath", "task_type": "tts"} +{"index": 1797, "question": "Please read the following math formula symbols: $\\Omega(\\kappa)\\df\\OmegaE_D\\cap\\mathcal{H}(\\kappa)$", "audio_path": "audio/row_00499515_1755645870690048.wav", "formula": "$\\Omega(\\kappa)\\df\\OmegaE_D\\cap\\mathcal{H}(\\kappa)$", "answer": "Omega of kappa is defined as the intersection of Omega times E sub D and the set of all H of kappa.", "subset": "mixmath", "task_type": "tts"} +{"index": 1798, "question": "请你朗读以下数学公式符号:$\\begin{cases}a=2 \\\\ b=3 \\\\ c=9 \\\\ d=18 \\\\ \\end{cases}$", "audio_path": "audio/math_3bff7cd8-b955-431b-a218-c637278ed3b4.wav", "formula": "$\\begin{cases}a=2 \\\\ b=3 \\\\ c=9 \\\\ d=18 \\\\ \\end{cases}$", "answer": "a等于二;b等于三;c等于九;d等于十八", "subset": "mixmath", "task_type": "tts"} +{"index": 1799, "question": "Please read the following math formula symbols: $\\|p\\|_{L_1}=\\int|p(w)|dw$", "audio_path": "audio/row_00530668_1755649697606526.wav", "formula": "$\\|p\\|_{L_1}=\\int|p(w)|dw$", "answer": "The norm of p sub L1 is equal to the integral of the absolute value of p of w with respect to w.", "subset": "mixmath", "task_type": "tts"} +{"index": 1800, "question": "请你朗读以下数学公式符号:$\\begin{cases}\\dfrac{x}{40}+\\dfrac{y}{60}=6 \\\\ \\dfrac{x}{60}+\\dfrac{y}{40}=6.5 \\end{cases}$", "audio_path": "audio/math_66373d54-e3cd-4f10-a209-c1976dbd20cf.wav", "formula": "$\\begin{cases}\\dfrac{x}{40}+\\dfrac{y}{60}=6 \\\\ \\dfrac{x}{60}+\\dfrac{y}{40}=6.5 \\end{cases}$", "answer": "四十分之x加六十分之y等于六,六十分之x加四十分之y等于六点五", "subset": "mixmath", "task_type": "tts"} +{"index": 1801, "question": "Please read the following math formula symbols: $\\bra{q_k}L\\ket{p_l}=\\bra{p_k}L\\ket{q_l}=0$", "audio_path": "audio/row_01231020_1755737161130491.wav", "formula": "$\\bra{q_k}L\\ket{p_l}=\\bra{p_k}L\\ket{q_l}=0$", "answer": "The bra q sub k L ket p sub l equals the bra p sub k L ket q sub l equals zero.", "subset": "mixmath", "task_type": "tts"} +{"index": 1802, "question": "Please read the following math formula symbols: $X=\\Speck[x,y,z]/(x(x-1)+yz)$", "audio_path": "audio/row_01586600_1755781919139610.wav", "formula": "$X=\\Speck[x,y,z]/(x(x-1)+yz)$", "answer": "X equals the cosecant of x, y, z divided by the quantity x times the quantity x minus 1 plus y times z.", "subset": "mixmath", "task_type": "tts"} +{"index": 1803, "question": "Please read the following math formula symbols: $\\alpha_S^n\\,\\text{ln}^{m}(m_V^2/q_T^2)$", "audio_path": "audio/row_00583837_1755656267149373.wav", "formula": "$\\alpha_S^n\\,\\text{ln}^{m}(m_V^2/q_T^2)$", "answer": "Alpha sub S to the power of n times the natural logarithm of m sub V squared divided by q sub T squared.", "subset": "mixmath", "task_type": "tts"} +{"index": 1804, "question": "请你朗读以下数学公式符号:$N=2^{3} \\cdot 3^{5} \\cdot 5 \\cdot 7 \\cdot 17^{2}$", "audio_path": "audio/math_dbed807e-fb8e-4687-8e73-7159f9b4ef2f.wav", "formula": "$N=2^{3} \\cdot 3^{5} \\cdot 5 \\cdot 7 \\cdot 17^{2}$", "answer": "N等于二的立方乘三的五次方乘五乘七乘十七的平方", "subset": "mixmath", "task_type": "tts"} +{"index": 1805, "question": "Please read the following math formula symbols: $V(p)\\subseteq\\{\\vmathbb\\H^{n+1}$", "audio_path": "audio/row_01692607_1755795297466013.wav", "formula": "$V(p)\\subseteq\\{\\vmathbb\\H^{n+1}$", "answer": "V of p is a subset of the set containing the boldface letter H to the power of n plus 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 1806, "question": "请你朗读以下数学公式符号:$\\begin{cases}a=2 & \\\\ b=4 & \\\\ c=5 & \\\\ d=20 & \\\\ \\end{cases}$", "audio_path": "audio/math_fd278daa-b540-4a96-b5ed-ef84c0d1ffc9.wav", "formula": "$\\begin{cases}a=2 & \\\\ b=4 & \\\\ c=5 & \\\\ d=20 & \\\\ \\end{cases}$", "answer": "a等于二,b等于四,c等于五,d等于二十", "subset": "mixmath", "task_type": "tts"} +{"index": 1807, "question": "Please read the following math formula symbols: $J_2:=\\overline{J(E+N)_0+I_0(E)}$", "audio_path": "audio/row_00208851_1755610418715685.wav", "formula": "$J_2:=\\overline{J(E+N)_0+I_0(E)}$", "answer": "J sub 2 is defined as the overline of J times the quantity E plus N, subscript 0, plus I subscript 0 times E.", "subset": "mixmath", "task_type": "tts"} +{"index": 1808, "question": "请你朗读以下数学公式符号:$$\\begin{cases}2{{a}_{1}}x+3{{b}_{1}}y={{c}_{1}} \\\\ 2{{a}_{2}}x+3{{b}_{2}}y={{c}_{2}} \\\\ \\end{cases}$$", "audio_path": "audio/math_314f7c05-b6dd-47d4-b216-900529dc83ef.wav", "formula": "$$\\begin{cases}2{{a}_{1}}x+3{{b}_{1}}y={{c}_{1}} \\\\ 2{{a}_{2}}x+3{{b}_{2}}y={{c}_{2}} \\\\ \\end{cases}$$", "answer": "二a一乘x加三b一乘y等于c一 和 二a二乘x加三b二乘y等于c二", "subset": "mixmath", "task_type": "tts"} +{"index": 1809, "question": "请你朗读以下数学公式符号:$\\frac{1}{2}+\\frac{2}{4}+\\frac{1}{3}+\\frac{6}{9}+\\frac{1}{4}+\\frac{9}{12}=\\left( \\frac{1}{2}+\\frac{2}{4} \\right)+\\left( \\frac{1}{3}+\\frac{6}{9} \\right)+\\left( \\frac{1}{4}+\\frac{9}{12} \\right)=1+1+1=3$", "audio_path": "audio/math_8cd79c79-0431-4069-8f69-63a903403a0e.wav", "formula": "$\\frac{1}{2}+\\frac{2}{4}+\\frac{1}{3}+\\frac{6}{9}+\\frac{1}{4}+\\frac{9}{12}=\\left( \\frac{1}{2}+\\frac{2}{4} \\right)+\\left( \\frac{1}{3}+\\frac{6}{9} \\right)+\\left( \\frac{1}{4}+\\frac{9}{12} \\right)=1+1+1=3$", "answer": "二分之一加四分之二加三分之一加九分之六加四分之一加十二分之九等于 二分之一加四分之二的和 加 三分之一加九分之六的和 加 四分之一加十二分之九的和 等于一加一加一等于三", "subset": "mixmath", "task_type": "tts"} +{"index": 1810, "question": "请你朗读以下数学公式符号:${{x}^{8}}+{{y}^{8}}\\geqslant \\frac{1}{2}\\left( {{x}^{6}}+{{y}^{6}} \\right)$", "audio_path": "audio/math_7e5f5d04-5a18-4d32-ad44-c3d0ea890fd7.wav", "formula": "${{x}^{8}}+{{y}^{8}}\\geqslant \\frac{1}{2}\\left( {{x}^{6}}+{{y}^{6}} \\right)$", "answer": "x的八次方加y的八次方 大于等于 二分之一乘 x的六次方加y的六次方的和", "subset": "mixmath", "task_type": "tts"} +{"index": 1811, "question": "请你朗读以下数学公式符号:$${{3}^{m+n}}={{3}^{m}}\\cdot {{3}^{n}}=5\\\\times 7 =35$$", "audio_path": "audio/math_79bd3050-6f69-43ba-8b2d-a304ca24ae0a.wav", "formula": "$${{3}^{m+n}}={{3}^{m}}\\cdot {{3}^{n}}=5\\\\times 7 =35$$", "answer": "三的m加n次方等于三的m次方乘三的n次方等于五乘七等于三十五", "subset": "mixmath", "task_type": "tts"} +{"index": 1812, "question": "Please read the following math formula symbols: $y\\inB(x,c''N^{-1/d})\\cap\\spt\\nu$", "audio_path": "audio/row_01621780_1755786373953129.wav", "formula": "$y\\inB(x,c''N^{-1/d})\\cap\\spt\\nu$", "answer": "y belongs to the set B of x, c prime prime N to the power of negative one over d, intersected with nu.", "subset": "mixmath", "task_type": "tts"} +{"index": 1813, "question": "请你朗读以下数学公式符号:$\\frac{{{a}^{2}}}{{{b}^{2}}}=\\frac{bc}{{{b}^{2}}}=\\frac{16}{9}$", "audio_path": "audio/math_8c5a8b33-2129-4e06-af82-b18ba67611a5.wav", "formula": "$\\frac{{{a}^{2}}}{{{b}^{2}}}=\\frac{bc}{{{b}^{2}}}=\\frac{16}{9}$", "answer": "b平方分之a平方等于b平方分之b乘c等于九分之十六", "subset": "mixmath", "task_type": "tts"} +{"index": 1814, "question": "Please read the following math formula symbols: $w\\inH^1(\\R^3\\setminus\\Gamma)$", "audio_path": "audio/row_01773197_1755805503584611.wav", "formula": "$w\\inH^1(\\R^3\\setminus\\Gamma)$", "answer": "w belongs to H raised to the power of 1, open parenthesis, R raised to the power of 3, minus Gamma, close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 1815, "question": "请你朗读以下数学公式符号:$=36\\times \\frac{1}{6}\\times 33\\times 34\\times 67$", "audio_path": "audio/math_3fe3ddc1-3098-4c3d-b851-9fb7732dbdf1.wav", "formula": "$=36\\times \\frac{1}{6}\\times 33\\times 34\\times 67$", "answer": "等于三十六乘六分之一乘三十三乘三十四乘六十七", "subset": "mixmath", "task_type": "tts"} +{"index": 1816, "question": "Please read the following math formula symbols: $\\Delta^n_{\\theta_*}{=}\\O_{P_{0}^n}({1})$", "audio_path": "audio/row_00128634_1755600655586897.wav", "formula": "$\\Delta^n_{\\theta_*}{=}\\O_{P_{0}^n}({1})$", "answer": "Delta to the power of n, subscript theta star, equals big O of P to the power of n, subscript zero, of one.", "subset": "mixmath", "task_type": "tts"} +{"index": 1817, "question": "请你朗读以下数学公式符号:$$\\begin{eqnarray}&&36\\times 111+111\\times 4\\\\ &=&(36+4)\\times 111\\\\ &=&40\\times 111\\\\ &=&4440\\end{eqnarray}$$", "audio_path": "audio/math_13722a2c-672a-4367-993e-3778ef9d2e51.wav", "formula": "$$\\begin{eqnarray}&&36\\times 111+111\\times 4\\\\ &=&(36+4)\\times 111\\\\ &=&40\\times 111\\\\ &=&4440\\end{eqnarray}$$", "answer": "三十六乘一百一十一加一百一十一乘四等于三十六加四的和乘一百一十一等于四十乘一百一十一等于四千四百四十", "subset": "mixmath", "task_type": "tts"} +{"index": 1818, "question": "Please read the following math formula symbols: $$c_i(V):=V^*(c_i)\\inH^{2i}(X;\\mathbbZ).$$", "audio_path": "audio/row_00176652_1755606491651486.wav", "formula": "$$c_i(V):=V^*(c_i)\\inH^{2i}(X;\\mathbbZ).$$", "answer": "c sub i of V is defined as V star of c sub i belonging to H to the power 2i of X semicolon capital Z.", "subset": "mixmath", "task_type": "tts"} +{"index": 1819, "question": "Please read the following math formula symbols: $L_{\\bC}:\\Val_{n-k}^\\infty\\to\\Val_k^\\infty$", "audio_path": "audio/row_02068692_1755842865591924.wav", "formula": "$L_{\\bC}:\\Val_{n-k}^\\infty\\to\\Val_k^\\infty$", "answer": "L sub b C, V sub n minus k to the power of infinity, to V sub k to the power of infinity.", "subset": "mixmath", "task_type": "tts"} +{"index": 1820, "question": "请你朗读以下数学公式符号:$\\therefore \\left\\{ \\begin{array}{l} & a=3 \\\\ & b=1 \\end{array} \\right.$", "audio_path": "audio/math_3f3164d2-676b-45bb-a496-e4c4b890e559.wav", "formula": "$\\therefore \\left\\{ \\begin{array}{l} & a=3 \\\\ & b=1 \\end{array} \\right.$", "answer": "所以a等于三 和 b等于一", "subset": "mixmath", "task_type": "tts"} +{"index": 1821, "question": "Please read the following math formula symbols: $j\\inJ'=\\{j\\inJ\\midH_{R_j}=H_R\\}$", "audio_path": "audio/row_00932424_1755699812578419.wav", "formula": "$j\\inJ'=\\{j\\inJ\\midH_{R_j}=H_R\\}$", "answer": "j belongs to J prime equals the set of j belongs to J such that H sub R sub j equals H sub R.", "subset": "mixmath", "task_type": "tts"} +{"index": 1822, "question": "请你朗读以下数学公式符号:$\\left( x+7 \\right)\\left( x+b \\right)={{x}^{2}}+12x+35$", "audio_path": "audio/math_791ca93e-23d4-4f03-96a4-8b39871b5dbf.wav", "formula": "$\\left( x+7 \\right)\\left( x+b \\right)={{x}^{2}}+12x+35$", "answer": "x加七的和乘 x加b的和 等于x的平方加十二x加三十五", "subset": "mixmath", "task_type": "tts"} +{"index": 1823, "question": "请你朗读以下数学公式符号:$${{(4\\times 5)}^{3}}=(4\\times 5)\\times (4\\times 5)\\times (4\\times 5)=4\\times 4\\times 4\\times 5\\times 5\\times 5={{4}^{3}}\\times {{5}^{3}}$$", "audio_path": "audio/math_8a8e42ee-35d1-48c3-be43-eba6351e4004.wav", "formula": "$${{(4\\times 5)}^{3}}=(4\\times 5)\\times (4\\times 5)\\times (4\\times 5)=4\\times 4\\times 4\\times 5\\times 5\\times 5={{4}^{3}}\\times {{5}^{3}}$$", "answer": "四乘五的积的三次方等于四乘五的积乘四乘五的积乘四乘五的积等于四乘四乘四乘五乘五乘五等于四的三次方乘五的三次方", "subset": "mixmath", "task_type": "tts"} +{"index": 1824, "question": "Please read the following math formula symbols: $y_i(\\theta)=1/\\sqrt{NK}\\sum_{k=1}^Ks_kV_{i-k}$", "audio_path": "audio/row_01750201_1755802611718897.wav", "formula": "$y_i(\\theta)=1/\\sqrt{NK}\\sum_{k=1}^Ks_kV_{i-k}$", "answer": "y sub i of theta equals one over square root of K times s sub k times V sub i minus k.", "subset": "mixmath", "task_type": "tts"} +{"index": 1825, "question": "请你朗读以下数学公式符号:$\\frac{4}{25}=4\\div 25=(0.16)=\\frac{16}{100}=(16\\%)$", "audio_path": "audio/math_00c36d37-281e-493f-aa37-9e9536664d3f.wav", "formula": "$\\frac{4}{25}=4\\div 25=(0.16)=\\frac{16}{100}=(16\\%)$", "answer": "二十五分之四等于四除以二十五等于零点一六等于一百分之十六等于百分之十六", "subset": "mixmath", "task_type": "tts"} +{"index": 1826, "question": "Please read the following math formula symbols: $p_2>1-m/[N-(k-1)m]$", "audio_path": "audio/row_01802679_1755809216845267.wav", "formula": "$p_2>1-m/[N-(k-1)m]$", "answer": "p sub 2 is greater than 1 minus m divided by the quantity N minus the quantity k minus 1 times m.", "subset": "mixmath", "task_type": "tts"} +{"index": 1827, "question": "Please read the following math formula symbols: $\\partialp_t({\\bmX})/\\partialt=L_{\\bmX}p_t({\\bmX})$", "audio_path": "audio/row_00592454_1755657339686551.wav", "formula": "$\\partialp_t({\\bmX})/\\partialt=L_{\\bmX}p_t({\\bmX})$", "answer": "Partial derivative of p sub t of X divided by partial derivative of t equals L sub X times p sub t of X.", "subset": "mixmath", "task_type": "tts"} +{"index": 1828, "question": "请你朗读以下数学公式符号:$${{a}^{2}}\\geqslant 4\\left( m+1 \\right)\\left( m+2 \\right)$$", "audio_path": "audio/math_fdec7674-2c0b-4706-95c1-fc1b5d90c2de.wav", "formula": "$${{a}^{2}}\\geqslant 4\\left( m+1 \\right)\\left( m+2 \\right)$$", "answer": "a的平方大于等于四乘m加一的和乘m加二的和", "subset": "mixmath", "task_type": "tts"} +{"index": 1829, "question": "请你朗读以下数学公式符号:$2\\frac{3}{4}\\times \\frac{5}{11}\\div \\frac{3}{8}=$", "audio_path": "audio/math_795ef572-7214-40c3-abc3-4202a9402f0d.wav", "formula": "$2\\frac{3}{4}\\times \\frac{5}{11}\\div \\frac{3}{8}=$", "answer": "二又四分之三乘十一分之五除以八分之三等于", "subset": "mixmath", "task_type": "tts"} +{"index": 1830, "question": "Please read the following math formula symbols: $c(v_r)=\\gamma(x_{j_{r,1}})=\\gamma(x_{j_{r,t}})$", "audio_path": "audio/row_00357727_1755628519395898.wav", "formula": "$c(v_r)=\\gamma(x_{j_{r,1}})=\\gamma(x_{j_{r,t}})$", "answer": "c of v sub r equals gamma of x sub j sub r comma 1 equals gamma of x sub j sub r comma t", "subset": "mixmath", "task_type": "tts"} +{"index": 1831, "question": "请你朗读以下数学公式符号:$360\\div 8\\div 3\\times (8\\div 2)\\times (3+5)=15\\times 4\\times 8=480$", "audio_path": "audio/math_42b71b76-eacb-46b5-98e1-64b455a52d89.wav", "formula": "$360\\div 8\\div 3\\times (8\\div 2)\\times (3+5)=15\\times 4\\times 8=480$", "answer": "三百六十除以八除以三乘八除以二的商乘三加五的和等于十五乘四乘八等于四百八十", "subset": "mixmath", "task_type": "tts"} +{"index": 1832, "question": "Please read the following math formula symbols: $\\p_0^{-1}\\xi(\\e_+)\\inB_{\\epsilon_1}^\\circ$", "audio_path": "audio/row_00102225_1755597456820836.wav", "formula": "$\\p_0^{-1}\\xi(\\e_+)\\inB_{\\epsilon_1}^\\circ$", "answer": "p sub 0 to the power of negative 1 times xi of e plus in B sub epsilon 1 to the power of circle.", "subset": "mixmath", "task_type": "tts"} +{"index": 1833, "question": "请你朗读以下数学公式符号:$$\\sqrt{{{x}^{3}}y}\\div \\sqrt{\\frac{{{x}^{2}}y}{5}}$$", "audio_path": "audio/math_c2d70ab8-c485-4557-845c-2e42d0a64930.wav", "formula": "$$\\sqrt{{{x}^{3}}y}\\div \\sqrt{\\frac{{{x}^{2}}y}{5}}$$", "answer": "根号下x的立方乘y的积除以根号下五分之x的平方乘y", "subset": "mixmath", "task_type": "tts"} +{"index": 1834, "question": "Please read the following math formula symbols: $\\mathbb{E}[d_1(X,\\hatX_1)]\\leqD_1$", "audio_path": "audio/row_00311630_1755622925779152.wav", "formula": "$\\mathbb{E}[d_1(X,\\hatX_1)]\\leqD_1$", "answer": "Expectation of d sub 1 of X and X hat sub 1 is less than or equal to D sub 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 1835, "question": "Please read the following math formula symbols: $q(\\theta)^2(1-\\Gamma^{n})(1-\\Gamma^{u})$", "audio_path": "audio/row_01566692_1755779390946328.wav", "formula": "$q(\\theta)^2(1-\\Gamma^{n})(1-\\Gamma^{u})$", "answer": "q of theta squared times one minus Gamma to the power of n times one minus Gamma to the power of u.", "subset": "mixmath", "task_type": "tts"} +{"index": 1836, "question": "请你朗读以下数学公式符号:$\\frac{5}{6}\\div \\left( \\frac{13}{15}+\\frac{1}{3} \\right)$", "audio_path": "audio/math_e4c507b1-a743-4901-9a15-4830810453b6.wav", "formula": "$\\frac{5}{6}\\div \\left( \\frac{13}{15}+\\frac{1}{3} \\right)$", "answer": "六分之五除以十五分之十三加三分之一的和", "subset": "mixmath", "task_type": "tts"} +{"index": 1837, "question": "请你朗读以下数学公式符号:$5\\times 5\\times (5\\times 4\\times 3\\times 2\\times 1)=3000$", "audio_path": "audio/math_fa3b71d5-f172-4eed-b871-793abdaf5a7b.wav", "formula": "$5\\times 5\\times (5\\times 4\\times 3\\times 2\\times 1)=3000$", "answer": "五乘五 再乘五乘四乘三乘二乘一的积等于三千", "subset": "mixmath", "task_type": "tts"} +{"index": 1838, "question": "Please read the following math formula symbols: $k_\\#=|\\{v\\inV\\,|\\,w_v\\not=\\w_v\\}|$", "audio_path": "audio/row_01076319_1755717775285698.wav", "formula": "$k_\\#=|\\{v\\inV\\,|\\,w_v\\not=\\w_v\\}|$", "answer": "k sub hashtag equals the cardinality of the set of v in V such that w sub v not equal to w sub v.", "subset": "mixmath", "task_type": "tts"} +{"index": 1839, "question": "Please read the following math formula symbols: $(\\{\\bf\\s^k)\\subset\\mathbb{B}_2(1)$", "audio_path": "audio/row_00005667_1755585807222198.wav", "formula": "$(\\{\\bf\\s^k)\\subset\\mathbb{B}_2(1)$", "answer": "The set s raised to the power of k is a subset of the set B sub 2 with radius 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 1840, "question": "请你朗读以下数学公式符号:$$(2+1)\\left( {{2}^{2}}+1 \\right)\\left( {{2}^{4}}+1 \\right)\\left( {{2}^{8}}+1 \\right)$$", "audio_path": "audio/math_e69e8f1a-a5c4-4503-8f02-82e85fa61402.wav", "formula": "$$(2+1)\\left( {{2}^{2}}+1 \\right)\\left( {{2}^{4}}+1 \\right)\\left( {{2}^{8}}+1 \\right)$$", "answer": "二加一的和乘二的平方加一的和乘二的四次方加一的和乘二的八次方加一的和", "subset": "mixmath", "task_type": "tts"} +{"index": 1841, "question": "Please read the following math formula symbols: $\\|U^{-1}x\\|_2\\leq\\cN(Ax)$", "audio_path": "audio/row_01068910_1755716838239122.wav", "formula": "$\\|U^{-1}x\\|_2\\leq\\cN(Ax)$", "answer": "The norm of U inverse times x, subscript 2, is less than or equal to c times N of A times x.", "subset": "mixmath", "task_type": "tts"} +{"index": 1842, "question": "请你朗读以下数学公式符号:${{b}^{2}}\\cdot {{b}^{3}}={{b}^{2{+}3}}{=}{{b}^{5}}$", "audio_path": "audio/math_1316a0d9-4ad4-404e-9063-e0c698421c6c.wav", "formula": "${{b}^{2}}\\cdot {{b}^{3}}={{b}^{2{+}3}}{=}{{b}^{5}}$", "answer": "b 的平方乘 b 的立方等于 b 的二加三次方等于 b 的五次方", "subset": "mixmath", "task_type": "tts"} +{"index": 1843, "question": "请你朗读以下数学公式符号:$$\\frac{1}{8}\\times \\left[ \\frac{1}{2}\\div \\left( \\frac{3}{5}\\times \\frac{10}{9} \\right) \\right]$$", "audio_path": "audio/math_df015736-9896-4cd7-a89e-44fc8826cbc3.wav", "formula": "$$\\frac{1}{8}\\times \\left[ \\frac{1}{2}\\div \\left( \\frac{3}{5}\\times \\frac{10}{9} \\right) \\right]$$", "answer": "八分之一乘二分之一除以五分之三乘九分之十的积的商", "subset": "mixmath", "task_type": "tts"} +{"index": 1844, "question": "Please read the following math formula symbols: $g'(c^\\circ)(1-p(c^\\circ))=p'(c^\\circ)(1-g(c^\\circ))$", "audio_path": "audio/row_01908301_1755822593523963.wav", "formula": "$g'(c^\\circ)(1-p(c^\\circ))=p'(c^\\circ)(1-g(c^\\circ))$", "answer": "g prime of c circle times one minus p of c circle equals p prime of c circle times one minus g of c circle.", "subset": "mixmath", "task_type": "tts"} +{"index": 1845, "question": "Please read the following math formula symbols: $k(x,y_1,y_2)/k(f_4,d_2,d_3)[h_3]$", "audio_path": "audio/row_02071431_1755843217390987.wav", "formula": "$k(x,y_1,y_2)/k(f_4,d_2,d_3)[h_3]$", "answer": "k of x, y sub 1, y sub 2, divided by k of f sub 4, d sub 2, d sub 3, times h sub 3.", "subset": "mixmath", "task_type": "tts"} +{"index": 1846, "question": "请你朗读以下数学公式符号:$=31\\times 5\\times 4\\times 3\\times 2\\times 1=3720$", "audio_path": "audio/math_68b0c5f5-7496-479d-92c5-3b9719911a2f.wav", "formula": "$=31\\times 5\\times 4\\times 3\\times 2\\times 1=3720$", "answer": "等于三十一乘五乘四乘三乘二乘一等于三千七百二十", "subset": "mixmath", "task_type": "tts"} +{"index": 1847, "question": "Please read the following math formula symbols: $\\Gamma_{Z}(h)=(\\Gamma_{Z,ij}(h))_{i,j=1,2}$", "audio_path": "audio/row_00022848_1755587882799770.wav", "formula": "$\\Gamma_{Z}(h)=(\\Gamma_{Z,ij}(h))_{i,j=1,2}$", "answer": "Gamma sub Z of h equals open parenthesis Gamma sub Z comma i j of h close parenthesis sub i comma j equals 1 comma 2.", "subset": "mixmath", "task_type": "tts"} +{"index": 1848, "question": "Please read the following math formula symbols: $a_{i}=(a_{i,0},\\ldots,a_{i,m-1})$", "audio_path": "audio/row_00977674_1755705436015196.wav", "formula": "$a_{i}=(a_{i,0},\\ldots,a_{i,m-1})$", "answer": "a sub i equals open parenthesis a sub i comma zero close parenthesis ellipsis comma a sub i comma m minus one", "subset": "mixmath", "task_type": "tts"} +{"index": 1849, "question": "请你朗读以下数学公式符号:$$a+\\overline{b3}+\\overline{1c26}+\\overline{d341}=1837\\times 4$$", "audio_path": "audio/math_cb607049-9198-4aa4-a03c-06624b642e0b.wav", "formula": "$$a+\\overline{b3}+\\overline{1c26}+\\overline{d341}=1837\\times 4$$", "answer": "a加两位数b三加四位数一c二六加四位数d三四一等于一千八百三十七乘四", "subset": "mixmath", "task_type": "tts"} +{"index": 1850, "question": "请你朗读以下数学公式符号:$=\\frac{3}{5}\\times \\left( \\frac{2}{11}+\\frac{9}{11} \\right)$", "audio_path": "audio/math_2155160f-d8dc-49d3-b6af-dfc333f2c049.wav", "formula": "$=\\frac{3}{5}\\times \\left( \\frac{2}{11}+\\frac{9}{11} \\right)$", "answer": "等于五分之三乘十一分之二加十一分之九的和", "subset": "mixmath", "task_type": "tts"} +{"index": 1851, "question": "请你朗读以下数学公式符号:$=\\sqrt{{{\\left( \\sqrt{3}+\\sqrt{2} \\right)}^{2}}}=\\sqrt{3}\\pm \\sqrt{2}$", "audio_path": "audio/math_0680cd8b-749d-4fa0-a52f-aefdb84b8d8b.wav", "formula": "$=\\sqrt{{{\\left( \\sqrt{3}+\\sqrt{2} \\right)}^{2}}}=\\sqrt{3}\\pm \\sqrt{2}$", "answer": "等于根号下根号三加根号二的和的平方等于根号三加减根号二", "subset": "mixmath", "task_type": "tts"} +{"index": 1852, "question": "Please read the following math formula symbols: $0\\leqt_1|\\yll|^{\\mathrm{mid}}$", "audio_path": "audio/row_00480577_1755643558308158.wav", "formula": "$|\\yll|>|\\yll|^{\\mathrm{mid}}$", "answer": "The absolute value of y double ell is greater than the absolute value of y double ell to the power of mid.", "subset": "mixmath", "task_type": "tts"} +{"index": 1899, "question": "请你朗读以下数学公式符号:$$9009=7\\times \\left( 3\\times 3 \\right)\\times 11\\times 13$$", "audio_path": "audio/math_0877d4b8-dd1f-466c-923c-ad046baa9e67.wav", "formula": "$$9009=7\\times \\left( 3\\times 3 \\right)\\times 11\\times 13$$", "answer": "九千零九等于七乘 三乘三的积 乘十一乘十三", "subset": "mixmath", "task_type": "tts"} +{"index": 1900, "question": "Please read the following math formula symbols: $A':=A^{k|G|+1}$", "audio_path": "audio/row_01616092_1755785653257666.wav", "formula": "$A':=A^{k|G|+1}$", "answer": "The derivative of A with respect to time is equal to A to the power of k times the absolute value of G plus 1.", "subset": "mixmath", "task_type": "tts"} +{"index": 1901, "question": "Please read the following math formula symbols: $\\min_{i}d_{i}^{*}\\geq\\frac{\\logn}{\\log\\logn}$", "audio_path": "audio/row_00167868_1755605418425850.wav", "formula": "$\\min_{i}d_{i}^{*}\\geq\\frac{\\logn}{\\log\\logn}$", "answer": "Minimize i, d sub i star, greater than or equal to the logarithm of n divided by the logarithm of the logarithm of n.", "subset": "mixmath", "task_type": "tts"} +{"index": 1902, "question": "Please read the following math formula symbols: $\\partial_h\\beta_h(h^*=64,\\infty)<0$", "audio_path": "audio/row_00186787_1755607706464522.wav", "formula": "$\\partial_h\\beta_h(h^*=64,\\infty)<0$", "answer": "Partial derivative with respect to h of beta sub h, evaluated at h equals 64 and infinity, is less than zero.", "subset": "mixmath", "task_type": "tts"} +{"index": 1903, "question": "Please read the following math formula symbols: $z_{-n}^{(k)}(t)=z_{-n}[f^{(k)}](t)$", "audio_path": "audio/row_00093695_1755596433419005.wav", "formula": "$z_{-n}^{(k)}(t)=z_{-n}[f^{(k)}](t)$", "answer": "z sub negative n superscript k of t equals z sub negative n of the function f superscript k of t.", "subset": "mixmath", "task_type": "tts"} +{"index": 1904, "question": "Please read the following math formula symbols: $\\alpha_{q}(I)\\geq\\vnum(I^{[q]})-\\vnum_{\\frakp}(I)$", "audio_path": "audio/row_01855124_1755815851093262.wav", "formula": "$\\alpha_{q}(I)\\geq\\vnum(I^{[q]})-\\vnum_{\\frakp}(I)$", "answer": "Alpha sub q of I is greater than or equal to vnum of I raised to the power of q minus vnum sub frakp of I.", "subset": "mixmath", "task_type": "tts"} +{"index": 1905, "question": "Please read the following math formula symbols: $$\\{y_{a,U}\\}_{\\max\\supp\\,a\\leq\\maxU}$$", "audio_path": "audio/row_01932558_1755825636680981.wav", "formula": "$$\\{y_{a,U}\\}_{\\max\\supp\\,a\\leq\\maxU}$$", "answer": "Open brace, y sub a comma U, close brace, subscript max superscript p, a less than or equal to max U.", "subset": "mixmath", "task_type": "tts"} +{"index": 1906, "question": "Please read the following math formula symbols: $\\mathcal{O}((\\max_k\\sigma_k+2/\\log(2))\\sqrt{T\\log(T)})$", "audio_path": "audio/row_01253003_1755739897042193.wav", "formula": "$\\mathcal{O}((\\max_k\\sigma_k+2/\\log(2))\\sqrt{T\\log(T)})$", "answer": "Math call O of open parenthesis, max k sigma k plus 2 log 2, close parenthesis, square root of T log T.", "subset": "mixmath", "task_type": "tts"} +{"index": 1907, "question": "请你朗读以下数学公式符号:$$3.14\\times 3\\times 2\\div 4=9.42\\times 2\\div 4=18.84\\div 4=4.71$$", "audio_path": "audio/math_d5065044-0037-4655-bb0c-c241163304d3.wav", "formula": "$$3.14\\times 3\\times 2\\div 4=9.42\\times 2\\div 4=18.84\\div 4=4.71$$", "answer": "三点一四乘三乘二除以四等于九点四二乘二除以四等于十八点八四除以四等于四点七一", "subset": "mixmath", "task_type": "tts"} +{"index": 1908, "question": "Please read the following math formula symbols: $\\sigma_{t}^2=\\max_{a\\in\\cA}\\E[(\\varepsilon_t(a))^2]$", "audio_path": "audio/row_00653496_1755664943339420.wav", "formula": "$\\sigma_{t}^2=\\max_{a\\in\\cA}\\E[(\\varepsilon_t(a))^2]$", "answer": "Sigma sub t squared equals the maximum over a in the set A of E of the quantity epsilon sub t of a squared.", "subset": "mixmath", "task_type": "tts"} +{"index": 1909, "question": "请你朗读以下数学公式符号:$\\begin{eqnarray}&&\\left( \\frac{5}{12}+\\frac{5}{32} \\right)\\times \\frac{8}{25}\\\\ &=&\\frac{5}{12}\\times \\frac{8}{25}+\\frac{5}{32}\\times \\frac{8}{25}\\\\ &=&\\frac{2}{15}+\\frac{1}{20}\\\\ &=&\\frac{8}{60}+\\frac{3}{60}\\\\ &=&\\frac{11}{60}.\\end{eqnarray}$", "audio_path": "audio/math_600765f4-4ec3-4b46-9be4-025b39503725.wav", "formula": "$\\begin{eqnarray}&&\\left( \\frac{5}{12}+\\frac{5}{32} \\right)\\times \\frac{8}{25}\\\\ &=&\\frac{5}{12}\\times \\frac{8}{25}+\\frac{5}{32}\\times \\frac{8}{25}\\\\ &=&\\frac{2}{15}+\\frac{1}{20}\\\\ &=&\\frac{8}{60}+\\frac{3}{60}\\\\ &=&\\frac{11}{60}.\\end{eqnarray}$", "answer": "十二分之五加三十二分之五的和 乘二十五分之八等于十二分之五乘二十五分之八加三十二分之五乘二十五分之八等于十五分之二加二十分之一等于六十分之八加六十分之三等于六十分之十一。", "subset": "mixmath", "task_type": "tts"} +{"index": 1910, "question": "请你朗读以下数学公式符号:$9S=1+\\frac{1}{100}+\\frac{1}{1000}+\\frac{2}{10000}+\\frac{3}{100000}+\\cdots$", "audio_path": "audio/math_d53e9930-accf-4bf5-8651-8ec3c5809f2d.wav", "formula": "$9S=1+\\frac{1}{100}+\\frac{1}{1000}+\\frac{2}{10000}+\\frac{3}{100000}+\\cdots$", "answer": "九 S 等于 一加一百分之一加一千分之一加一万分之二加十万分之三加依此类推", "subset": "mixmath", "task_type": "tts"} +{"index": 1911, "question": "Please read the following math formula symbols: $[\\lcb_{i+1},\\ucb_{i+1}]$", "audio_path": "audio/row_02092441_1755845851817381.wav", "formula": "$[\\lcb_{i+1},\\ucb_{i+1}]$", "answer": "Open square bracket, l c b sub i plus 1, comma, u c b sub i plus 1, close square bracket.", "subset": "mixmath", "task_type": "tts"} +{"index": 1912, "question": "请你朗读以下数学公式符号:$=\\frac{1}{1\\times 2}+\\frac{1}{2\\times 3}+\\frac{1}{3\\times 4}+\\frac{1}{4\\times 5}+\\frac{1}{5\\times 6}+\\frac{1}{6\\times 7}$", "audio_path": "audio/math_722a2f41-50c9-4061-a756-2ed74ca948c6.wav", "formula": "$=\\frac{1}{1\\times 2}+\\frac{1}{2\\times 3}+\\frac{1}{3\\times 4}+\\frac{1}{4\\times 5}+\\frac{1}{5\\times 6}+\\frac{1}{6\\times 7}$", "answer": "等于一乘二的积 分之一 加二乘三的积 分之一 加三乘四的积 分之一 加四乘五的积分之一 加五乘六的积 分之一 加六乘七的积分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 1913, "question": "请你朗读以下数学公式符号:$\\frac{7}{6}x\\times \\frac{6}{7}=42\\times \\frac{6}{7}$", "audio_path": "audio/math_c36be618-d3bd-4be3-ae45-97a91a17f7a8.wav", "formula": "$\\frac{7}{6}x\\times \\frac{6}{7}=42\\times \\frac{6}{7}$", "answer": "六分之七x乘七分之六等于四十二乘七分之六", "subset": "mixmath", "task_type": "tts"} +{"index": 1914, "question": "请你朗读以下数学公式符号:$$\\frac{1}{7}=0.\\overset{\\centerdot }{\\mathop{1}}\\,4285\\overset{\\centerdot }{\\mathop{7}}$$", "audio_path": "audio/math_dbb7b32e-55d2-48f7-ae3d-1b9312bdcf65.wav", "formula": "$$\\frac{1}{7}=0.\\overset{\\centerdot }{\\mathop{1}}\\,4285\\overset{\\centerdot }{\\mathop{7}}$$", "answer": "七分之一等于零点一四二八五七 一四二八五七循环", "subset": "mixmath", "task_type": "tts"} +{"index": 1915, "question": "请你朗读以下数学公式符号:$$\\frac{1}{3}+\\frac{1}{4}+\\frac{1}{5}+\\frac{1}{6}=\\frac{19}{20}$$", "audio_path": "audio/math_901dbb83-18f2-4328-8049-8d24817809e4.wav", "formula": "$$\\frac{1}{3}+\\frac{1}{4}+\\frac{1}{5}+\\frac{1}{6}=\\frac{19}{20}$$", "answer": "三分之一加四分之一加五分之一加六分之一等于二十分之十九", "subset": "mixmath", "task_type": "tts"} +{"index": 1916, "question": "请你朗读以下数学公式符号:$\\left( 320\\times 144\\times 96 \\right)\\div \\left( 16\\times 16\\times 16 \\right)=1080$", "audio_path": "audio/math_113040c1-ec57-4520-b425-7fc42f71801c.wav", "formula": "$\\left( 320\\times 144\\times 96 \\right)\\div \\left( 16\\times 16\\times 16 \\right)=1080$", "answer": "三百二十乘一百四十四乘九十六的积除以十六乘十六乘十六的积等于一千零八十", "subset": "mixmath", "task_type": "tts"} +{"index": 1917, "question": "请你朗读以下数学公式符号:$\\frac{1}{a\\left( 1+b \\right)}+\\frac{1}{b\\left( 1+c \\right)}+\\frac{1}{c\\left( 1+a \\right)}\\geqslant \\frac{27}{4}$", "audio_path": "audio/math_de1bcbc1-472b-430a-89e9-fc283d6de909.wav", "formula": "$\\frac{1}{a\\left( 1+b \\right)}+\\frac{1}{b\\left( 1+c \\right)}+\\frac{1}{c\\left( 1+a \\right)}\\geqslant \\frac{27}{4}$", "answer": "a乘一加b的和分之一 加b乘一加c的和 分之一 加c乘一加a的和分之一大于等于四分之二十七", "subset": "mixmath", "task_type": "tts"} +{"index": 1918, "question": "请你朗读以下数学公式符号:$ = \\left( 1 + 19 \\right) \\times 19 \\div 2 = 190$", "audio_path": "audio/math_42f201e4-a9b9-419e-ad86-b5e8763e6cb3.wav", "formula": "$ = \\left( 1 + 19 \\right) \\times 19 \\div 2 = 190$", "answer": "等于 一加十九的和乘十九除以二 等于 一百九十", "subset": "mixmath", "task_type": "tts"} +{"index": 1919, "question": "Please read the following math formula symbols: $\\frac{n(n+3)}{2}-1>n^2-n$", "audio_path": "audio/row_01220261_1755735799852195.wav", "formula": "$\\frac{n(n+3)}{2}-1>n^2-n$", "answer": "The fraction n times the quantity n plus 3 divided by 2 minus 1 is greater than n squared minus n.", "subset": "mixmath", "task_type": "tts"} +{"index": 1920, "question": "请你朗读以下数学公式符号:$=25\\times \\left( 40+4 \\right)=25\\times 40+25\\times 4=1000+100=1100$", "audio_path": "audio/math_e80d778e-06b1-4548-bc4f-62b274595d79.wav", "formula": "$=25\\times \\left( 40+4 \\right)=25\\times 40+25\\times 4=1000+100=1100$", "answer": "等于二十五乘四十加四的和等于二十五乘四十加二十五乘四等于一千加一百等于一千一百", "subset": "mixmath", "task_type": "tts"} +{"index": 1921, "question": "Please read the following math formula symbols: $\\tilde\\sigma=1/r\\alpha=\\sqrt{\\logn}/c$", "audio_path": "audio/row_00634250_1755662562341565.wav", "formula": "$\\tilde\\sigma=1/r\\alpha=\\sqrt{\\logn}/c$", "answer": "The tilde sigma equals one divided by r times alpha equals the square root of the logarithm of n divided by c.", "subset": "mixmath", "task_type": "tts"} +{"index": 1922, "question": "请你朗读以下数学公式符号:$$\\overline{ab}+\\overline{ba}=10a+b+10b+a=11a+11b=11(a+b)$$", "audio_path": "audio/math_32671c48-e0ce-464e-a882-6e8ece7fae2c.wav", "formula": "$$\\overline{ab}+\\overline{ba}=10a+b+10b+a=11a+11b=11(a+b)$$", "answer": "两位数ab加两位数ba等于十乘a加b加十乘b加a等于十一乘a加十一乘b等于十一乘a加b的和", "subset": "mixmath", "task_type": "tts"} +{"index": 1923, "question": "请你朗读以下数学公式符号:$$(2\\times 4\\times 6\\times 8\\times 10\\times 12\\times 14\\times 16)\\div (20\\times 48\\times 56)$$", "audio_path": "audio/math_c849895e-a901-46f7-84c0-8d8967a5fe9a.wav", "formula": "$$(2\\times 4\\times 6\\times 8\\times 10\\times 12\\times 14\\times 16)\\div (20\\times 48\\times 56)$$", "answer": "二乘四乘六乘八乘十乘十二乘十四乘十六的积除以二十乘四十八乘五十六的积", "subset": "mixmath", "task_type": "tts"} +{"index": 1924, "question": "Please read the following math formula symbols: $$|C_n^{(1)}(x)|>\\frac{c_x}{n^{}}$$", "audio_path": "audio/row_01403887_1755758813412373.wav", "formula": "$$|C_n^{(1)}(x)|>\\frac{c_x}{n^{}}$$", "answer": "Absolute value of C sub n superscript 1 open parenthesis x close parenthesis is greater than c sub x divided by n.", "subset": "mixmath", "task_type": "tts"} +{"index": 1925, "question": "请你朗读以下数学公式符号:$5 \\times\\left(\\frac{1}{9}+ \\frac{1}{15}\\right)= \\frac{8}{9}$", "audio_path": "audio/math_1eec6a5a-dd16-4928-8f95-ce68663fccff.wav", "formula": "$5 \\times\\left(\\frac{1}{9}+ \\frac{1}{15}\\right)= \\frac{8}{9}$", "answer": "五乘九分之一加十五分之一的和等于九分之八", "subset": "mixmath", "task_type": "tts"} +{"index": 1926, "question": "Please read the following math formula symbols: $|E(G_n)|/|V(G_n)|^2\\rightarrow0$", "audio_path": "audio/row_01089444_1755719406150823.wav", "formula": "$|E(G_n)|/|V(G_n)|^2\\rightarrow0$", "answer": "Absolute value of E of G sub n divided by absolute value of V of G sub n squared tends to zero.", "subset": "mixmath", "task_type": "tts"} +{"index": 1927, "question": "Please read the following math formula symbols: $y\\in\\mcf_f^{s/u}(x)\\subset\\Lambda$", "audio_path": "audio/row_01914221_1755823334627415.wav", "formula": "$y\\in\\mcf_f^{s/u}(x)\\subset\\Lambda$", "answer": "y belongs to the set of m c f f s slash u of x, which is a subset of Lambda", "subset": "mixmath", "task_type": "tts"} +{"index": 1928, "question": "请你朗读以下数学公式符号:$160\\times \\frac{1}{2}\\times 10\\times 10+160\\times 10\\times 15=8000+24000=32000$", "audio_path": "audio/math_9366b1af-86c1-4c5f-9eec-2cc8b4192cfe.wav", "formula": "$160\\times \\frac{1}{2}\\times 10\\times 10+160\\times 10\\times 15=8000+24000=32000$", "answer": "一百六十乘二分之一乘十乘十加一百六十乘十乘十五等于八千加二万四千等于三万二千", "subset": "mixmath", "task_type": "tts"} +{"index": 1929, "question": "请你朗读以下数学公式符号:$\\left( mx+n \\right)\\left( x+2 \\right)=2{{x}^{2}}+x+a$", "audio_path": "audio/math_9b05f734-4f66-47a2-987b-b00487036075.wav", "formula": "$\\left( mx+n \\right)\\left( x+2 \\right)=2{{x}^{2}}+x+a$", "answer": "m乘x加n的和乘x加二的和等于二乘x的平方加x加a", "subset": "mixmath", "task_type": "tts"} +{"index": 1930, "question": "请你朗读以下数学公式符号:$$C_{8}^{4}=\\frac{8\\times 7\\times 6\\times 5}{4\\times 3\\times 2\\times 1}=70$$", "audio_path": "audio/math_3c2bea63-8229-45b7-a0b9-c1a84bb996ed.wav", "formula": "$$C_{8}^{4}=\\frac{8\\times 7\\times 6\\times 5}{4\\times 3\\times 2\\times 1}=70$$", "answer": "C八四 等于四乘三乘二乘一的积分之八乘七乘六乘五的积等于七十", "subset": "mixmath", "task_type": "tts"} +{"index": 1931, "question": "Please read the following math formula symbols: $\\OH:\\mathcal{T}^{2r}\\to\\real^p$", "audio_path": "audio/row_00313578_1755623163633252.wav", "formula": "$\\OH:\\mathcal{T}^{2r}\\to\\real^p$", "answer": "O H maps from the space of T raised to the power of 2r to the real numbers raised to the power of p.", "subset": "mixmath", "task_type": "tts"} +{"index": 1932, "question": "Please read the following math formula symbols: $K^{I\\bar{J}}K_{M\\bar{J}}=\\delta^I_M$", "audio_path": "audio/row_00586025_1755656534851212.wav", "formula": "$K^{I\\bar{J}}K_{M\\bar{J}}=\\delta^I_M$", "answer": "K raised to the power of I bar J, K sub M bar J, equals delta raised to the power of I sub M.", "subset": "mixmath", "task_type": "tts"} +{"index": 1933, "question": "请你朗读以下数学公式符号:$\\frac{1}{8}=\\frac{3}{24}=\\frac{1}{24}+\\frac{1}{12}$", "audio_path": "audio/math_d1532c84-8a17-4e1b-aead-1a42c151b27f.wav", "formula": "$\\frac{1}{8}=\\frac{3}{24}=\\frac{1}{24}+\\frac{1}{12}$", "answer": "八分之一等于二十四分之三等于二十四分之一加十二分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 1934, "question": "请你朗读以下数学公式符号:$\\sqrt{3+\\frac{3}{8}}=\\sqrt{\\frac{27}{8}}=\\sqrt{\\frac{{3}^{2}\\times 3}{8}}=3\\sqrt{\\frac{3}{8}}$", "audio_path": "audio/math_23bcdf2a-6545-4fac-bb4f-65ff4ba8d1ad.wav", "formula": "$\\sqrt{3+\\frac{3}{8}}=\\sqrt{\\frac{27}{8}}=\\sqrt{\\frac{{3}^{2}\\times 3}{8}}=3\\sqrt{\\frac{3}{8}}$", "answer": "根号下三加八分之三的和等于根号下八分之二十七等于根号下八分之三的平方乘三的积等于三倍的根号下八分之三", "subset": "mixmath", "task_type": "tts"} +{"index": 1935, "question": "请你朗读以下数学公式符号:$\\frac{7}{8}\\times \\frac{16}{13}+\\frac{13}{16}\\times \\frac{16}{13}$", "audio_path": "audio/math_cd6651fb-aeac-4176-b85e-3d7f458b73c7.wav", "formula": "$\\frac{7}{8}\\times \\frac{16}{13}+\\frac{13}{16}\\times \\frac{16}{13}$", "answer": "八分之七乘十三分之十六加十六分之十三乘十三分之十六", "subset": "mixmath", "task_type": "tts"} +{"index": 1936, "question": "Please read the following math formula symbols: $\\tan\\theta_k=\\tilde{\\Delta}_k/(h-\\tilde{t}_k)$", "audio_path": "audio/row_00536821_1755650442369423.wav", "formula": "$\\tan\\theta_k=\\tilde{\\Delta}_k/(h-\\tilde{t}_k)$", "answer": "Tangent theta sub k equals tilde delta sub k divided by open parenthesis h minus tilde t sub k close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 1937, "question": "Please read the following math formula symbols: $$x_1x_1'=x_2+1=x_3x_3'$$", "audio_path": "audio/row_01998389_1755833947433314.wav", "formula": "$$x_1x_1'=x_2+1=x_3x_3'$$", "answer": "x sub 1, x sub 1 prime equals x sub 2 plus 1 equals x sub 3, x sub 3 prime", "subset": "mixmath", "task_type": "tts"} +{"index": 1938, "question": "请你朗读以下数学公式符号:$\\frac{1}{{{a}^{2}}}+\\frac{1}{{{b}^{2}}}=\\frac{1}{{{h}^{2}}}$", "audio_path": "audio/math_797a7d20-1ebc-49e3-8cec-efada1835d9d.wav", "formula": "$\\frac{1}{{{a}^{2}}}+\\frac{1}{{{b}^{2}}}=\\frac{1}{{{h}^{2}}}$", "answer": "a平方分之一加b平方分之一等于h平方分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 1939, "question": "Please read the following math formula symbols: $\\{\\hat{\\phi}_{\\bsi}|\\bsi\\inI_{\\cX}\\}$", "audio_path": "audio/row_01187504_1755731703320692.wav", "formula": "$\\{\\hat{\\phi}_{\\bsi}|\\bsi\\inI_{\\cX}\\}$", "answer": "Open brace, hat, phi, subscript, b s i, vertical bar, b s i, belongs to, capital I, subscript, c, X, close brace.", "subset": "mixmath", "task_type": "tts"} +{"index": 1940, "question": "请你朗读以下数学公式符号:$\\therefore x=\\pm \\sqrt{\\frac{81}{4}}=\\pm \\frac{9}{2}$", "audio_path": "audio/math_521cf577-45cc-4e21-a0f2-d63c870a24e1.wav", "formula": "$\\therefore x=\\pm \\sqrt{\\frac{81}{4}}=\\pm \\frac{9}{2}$", "answer": "所以x等于正负根号下四分之八十一等于正负二分之九", "subset": "mixmath", "task_type": "tts"} +{"index": 1941, "question": "请你朗读以下数学公式符号:$\\frac{5}{4}x\\div \\frac{5}{4}=\\frac{1}{8}\\div \\frac{5}{4}$", "audio_path": "audio/math_fdc9741d-9e9a-4b12-ae3c-5315ceed6502.wav", "formula": "$\\frac{5}{4}x\\div \\frac{5}{4}=\\frac{1}{8}\\div \\frac{5}{4}$", "answer": "四分之五x除以四分之五等于八分之一除以四分之五", "subset": "mixmath", "task_type": "tts"} +{"index": 1942, "question": "Please read the following math formula symbols: $\\Psi^\\tau(u(t_n),\\varphi^\\tau(u(t_n)))$", "audio_path": "audio/row_00528668_1755649453645333.wav", "formula": "$\\Psi^\\tau(u(t_n),\\varphi^\\tau(u(t_n)))$", "answer": "Psi to the power of tau of u of t sub n, comma, phi to the power of tau of u of t sub n.", "subset": "mixmath", "task_type": "tts"} +{"index": 1943, "question": "Please read the following math formula symbols: $f\\in\\cC^{l+p-1}(\\R^n)$", "audio_path": "audio/row_01375591_1755755243861342.wav", "formula": "$f\\in\\cC^{l+p-1}(\\R^n)$", "answer": "f belongs to c times C to the power of l plus p minus 1, times R to the power of n.", "subset": "mixmath", "task_type": "tts"} +{"index": 1944, "question": "Please read the following math formula symbols: $\\Delta_{sc}(r)=\\Delta_{sc}e^{iq\\cdotr}$", "audio_path": "audio/row_00552430_1755652355794470.wav", "formula": "$\\Delta_{sc}(r)=\\Delta_{sc}e^{iq\\cdotr}$", "answer": "Delta sub s c of r equals Delta sub s c times e to the power of i q dot r.", "subset": "mixmath", "task_type": "tts"} +{"index": 1945, "question": "请你朗读以下数学公式符号:$$\\frac{20}{25}=0.8=\\frac{4}{5}=16\\div 20=\\frac{24}{30}$$", "audio_path": "audio/math_e887b508-e023-4e62-a6a5-41e429ebc471.wav", "formula": "$$\\frac{20}{25}=0.8=\\frac{4}{5}=16\\div 20=\\frac{24}{30}$$", "answer": "二十五分之二十等于零点八等于五分之四等于十六除以二十等于三十分之二十四", "subset": "mixmath", "task_type": "tts"} +{"index": 1946, "question": "请你朗读以下数学公式符号:$$\\begin{cases} x>4 \\\\ x < \\frac{24}{5} \\end{cases}$$", "audio_path": "audio/math_71675710-a9d6-45a2-b253-62761f8122b1.wav", "formula": "$$\\begin{cases} x>4 \\\\ x < \\frac{24}{5} \\end{cases}$$", "answer": "x 大于四,x 小于五分之二十四", "subset": "mixmath", "task_type": "tts"} +{"index": 1947, "question": "请你朗读以下数学公式符号:${{x}^{2}}\\mp \\sqrt{\\frac{1}{2}\\left( 3+t \\right)}x+\\frac{1}{2}\\left( 1+t \\right)=0$", "audio_path": "audio/math_36df0e5b-de6a-4801-972d-e3a688e55153.wav", "formula": "${{x}^{2}}\\mp \\sqrt{\\frac{1}{2}\\left( 3+t \\right)}x+\\frac{1}{2}\\left( 1+t \\right)=0$", "answer": "x的平方 减加根号下二分之一乘三加t的和 乘x 加二分之一乘一加t的和等于零", "subset": "mixmath", "task_type": "tts"} +{"index": 1948, "question": "请你朗读以下数学公式符号:$={{5}^{\\frac{1}{2}}}\\times {{\\left( \\frac{2}{5} \\right)}^{\\frac{1}{2}}}\\div {{2}^{\\frac{1}{3}}}$", "audio_path": "audio/math_221ebd96-cd45-4df6-b05b-db752ce2ce6d.wav", "formula": "$={{5}^{\\frac{1}{2}}}\\times {{\\left( \\frac{2}{5} \\right)}^{\\frac{1}{2}}}\\div {{2}^{\\frac{1}{3}}}$", "answer": "等于五的二分之一次方乘五分之二的二分之一次方除以二的三分之一次方", "subset": "mixmath", "task_type": "tts"} +{"index": 1949, "question": "请你朗读以下数学公式符号:$\\text{Expression} =\\left( 186+14 \\right)+\\left( 245+55 \\right)+\\left( 217+83 \\right)$", "audio_path": "audio/math_a235d15b-33a1-4bec-8919-3548fd963b23.wav", "formula": "$\\text{Expression} =\\left( 186+14 \\right)+\\left( 245+55 \\right)+\\left( 217+83 \\right)$", "answer": "Expression 等于一百八十六加十四的和加二百四十五加五十五的和加二百一十七加八十三的和", "subset": "mixmath", "task_type": "tts"} +{"index": 1950, "question": "请你朗读以下数学公式符号:$\\frac{P \\% }{1+P \\% }\\times 100 \\% =\\frac{P}{100+P} \\%$", "audio_path": "audio/math_05fe7024-5a9b-4a35-8dba-d82e8dc61cfc.wav", "formula": "$\\frac{P \\% }{1+P \\% }\\times 100 \\% =\\frac{P}{100+P} \\%$", "answer": "一加百分之P的和 分之 百分之P 乘 百分之百 等于百分之 一百加 P 的和 分之 P", "subset": "mixmath", "task_type": "tts"} +{"index": 1951, "question": "Please read the following math formula symbols: $\\sim0.1~{\\rms}~(B_{\\rms}/10^{15}~{\\rmGauss})^{-1}$", "audio_path": "audio/row_01950934_1755827963183820.wav", "formula": "$\\sim0.1~{\\rms}~(B_{\\rms}/10^{15}~{\\rmGauss})^{-1}$", "answer": "0.1 grams per cubic centimeter times the quantity B sub s divided by 10 to the power of 15 grams per second.", "subset": "mixmath", "task_type": "tts"} +{"index": 1952, "question": "Please read the following math formula symbols: $K^{(0)},\\ldots,K^{(k_1+k_2)}$", "audio_path": "audio/row_02070989_1755843157986400.wav", "formula": "$K^{(0)},\\ldots,K^{(k_1+k_2)}$", "answer": "K raised to the power of zero, ellipsis, K raised to the power of k sub one plus k sub two.", "subset": "mixmath", "task_type": "tts"} +{"index": 1953, "question": "Please read the following math formula symbols: $\\chi_H\\inC_s\\bigr(\\R,\\mathcal{B}(E^\\star,E)\\bigr)$", "audio_path": "audio/row_01055332_1755715159873621.wav", "formula": "$\\chi_H\\inC_s\\bigr(\\R,\\mathcal{B}(E^\\star,E)\\bigr)$", "answer": "Chi sub H belongs to C sub s open parenthesis R, B open parenthesis E star, E close parenthesis close parenthesis.", "subset": "mixmath", "task_type": "tts"} +{"index": 1954, "question": "请你朗读以下数学公式符号:$4\\times\\dfrac{1}{2},2\\times\\dfrac{2}{2}=2,2\\times\\dfrac{3}{2},3\\times\\dfrac{4}{2},6\\times\\dfrac{5}{2},15\\times\\dfrac{6}{2}$", "audio_path": "audio/math_7ab7dd88-92ba-47d8-9e1a-99a09bc47a71.wav", "formula": "$4\\times\\dfrac{1}{2},2\\times\\dfrac{2}{2}=2,2\\times\\dfrac{3}{2},3\\times\\dfrac{4}{2},6\\times\\dfrac{5}{2},15\\times\\dfrac{6}{2}$", "answer": "四乘二分之一,二乘二分之二等于二,二乘二分之三,三乘二分之四,六乘二分之五,十五乘二分之六", "subset": "mixmath", "task_type": "tts"} +{"index": 1955, "question": "请你朗读以下数学公式符号:${{\\left({{19}^{5}}\\right)}^{4}}\\times 19=1{{9}^{20+1}}={{19}^{21}}$", "audio_path": "audio/math_33aa9ee1-10a4-47b9-a47b-5bf3c5b9ad47.wav", "formula": "${{\\left({{19}^{5}}\\right)}^{4}}\\times 19=1{{9}^{20+1}}={{19}^{21}}$", "answer": "十九的五次方的四次方乘十九等于十九的二十加一次方等于十九的二十一次方", "subset": "mixmath", "task_type": "tts"} +{"index": 1956, "question": "Please read the following math formula symbols: $a_N=\\frac{GM}{r^2}$", "audio_path": "audio/row_01534092_1755775257528284.wav", "formula": "$a_N=\\frac{GM}{r^2}$", "answer": "The acceleration a sub N is equal to the product of G times M divided by the square of the radius r.", "subset": "mixmath", "task_type": "tts"} +{"index": 1957, "question": "Please read the following math formula symbols: $\\lambda^{c[P]}\\neq\\lambda^{*[P]}_{\\lambda_\\Delta}$", "audio_path": "audio/row_01356882_1755752901937453.wav", "formula": "$\\lambda^{c[P]}\\neq\\lambda^{*[P]}_{\\lambda_\\Delta}$", "answer": "Lambda raised to the power of c, P, is not equal to lambda raised to the power of star, P, sub lambda Delta.", "subset": "mixmath", "task_type": "tts"} +{"index": 1958, "question": "Please read the following math formula symbols: $\\partial_iG:=\\partialG/\\partialx_i.$", "audio_path": "audio/row_00639327_1755663186585732.wav", "formula": "$\\partial_iG:=\\partialG/\\partialx_i.$", "answer": "Partial derivative with respect to i of G is defined as partial derivative of G with respect to x sub i.", "subset": "mixmath", "task_type": "tts"} +{"index": 1959, "question": "Please read the following math formula symbols: $a=1-2^{\\alpha/2}\\sin\\left(\\alpha\\pi/4\\right)$", "audio_path": "audio/row_00901231_1755695935672242.wav", "formula": "$a=1-2^{\\alpha/2}\\sin\\left(\\alpha\\pi/4\\right)$", "answer": "a equals one minus two to the power of alpha divided by two times sine of alpha times pi divided by four.", "subset": "mixmath", "task_type": "tts"} +{"index": 1960, "question": "请你朗读以下数学公式符号:$${{1}^{2}}+{{2}^{2}}+{{3}^{2}}+\\ldots +{{2004}^{2}}+{{2005}^{2}}$$", "audio_path": "audio/math_ed0f20f2-037c-48ca-9653-20551bec2444.wav", "formula": "$${{1}^{2}}+{{2}^{2}}+{{3}^{2}}+\\ldots +{{2004}^{2}}+{{2005}^{2}}$$", "answer": "一的平方加二的平方加三的平方,一直加到两千零四的平方加两千零五的平方", "subset": "mixmath", "task_type": "tts"} +{"index": 1961, "question": "请你朗读以下数学公式符号:$$\\left( 135\\div 5 \\right)\\times \\left( 75\\div 5 \\right)$$", "audio_path": "audio/math_812bfe6e-7000-4b40-b651-569693f0bc5f.wav", "formula": "$$\\left( 135\\div 5 \\right)\\times \\left( 75\\div 5 \\right)$$", "answer": "一百三十五除以五的商乘七十五除以五的商", "subset": "mixmath", "task_type": "tts"} +{"index": 1962, "question": "请你朗读以下数学公式符号:$0.9\\times 34.5+11.1\\times 1.8+54.3\\div 1\\dfrac{1}{9}$", "audio_path": "audio/math_2a9aa210-93de-4632-943e-0a6a85e4e064.wav", "formula": "$0.9\\times 34.5+11.1\\times 1.8+54.3\\div 1\\dfrac{1}{9}$", "answer": "零点九乘三十四点五加十一点一乘一点八加五十四点三除以一又九分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 1963, "question": "Please read the following math formula symbols: $0.690^{+0.055}_{-0.055}$", "audio_path": "audio/row_01382484_1755756120388727.wav", "formula": "$0.690^{+0.055}_{-0.055}$", "answer": "zero point six nine nine raised to the power of plus zero point zero five five subscript minus zero point zero five.", "subset": "mixmath", "task_type": "tts"} +{"index": 1964, "question": "请你朗读以下数学公式符号:$$\\frac{1}{9}\\left\\{ \\frac{1}{7}\\left[ \\frac{x+2}{15}+\\frac{4}{5}+6 \\right]+8 \\right\\}=1$$", "audio_path": "audio/math_7f4657fe-1f7f-4b79-8f9c-95c8a9ee46e4.wav", "formula": "$$\\frac{1}{9}\\left\\{ \\frac{1}{7}\\left[ \\frac{x+2}{15}+\\frac{4}{5}+6 \\right]+8 \\right\\}=1$$", "answer": "九分之一乘 七分之一乘 十五分之x 加二的和 与 五分之四与六的和的积加八的和等于一", "subset": "mixmath", "task_type": "tts"} +{"index": 1965, "question": "请你朗读以下数学公式符号:$$155\\div 3\\times 18=155\\times 18\\div 3=155\\times \\left( 18\\div 3 \\right)=155\\times 6=930$$", "audio_path": "audio/math_efc22085-c81c-4533-abc8-02006c56c037.wav", "formula": "$$155\\div 3\\times 18=155\\times 18\\div 3=155\\times \\left( 18\\div 3 \\right)=155\\times 6=930$$", "answer": "一百五十五除以三乘以十八等于一百五十五乘以十八除以三等于一百五十五乘以十八除以三的商等于一百五十五乘以六等于九百三十", "subset": "mixmath", "task_type": "tts"} +{"index": 1966, "question": "Please read the following math formula symbols: $\\tau^{-O(\\frac{1}{K})}\\ll_\\epsilonx^\\epsilon$", "audio_path": "audio/row_01014204_1755710018811379.wav", "formula": "$\\tau^{-O(\\frac{1}{K})}\\ll_\\epsilonx^\\epsilon$", "answer": "Tau to the power of negative O of one over K, much less than epsilon x to the power of epsilon.", "subset": "mixmath", "task_type": "tts"} +{"index": 1967, "question": "请你朗读以下数学公式符号:$=\\frac{6}{25}\\times \\frac{1}{9}+\\frac{6}{25}\\times \\frac{8}{9}$", "audio_path": "audio/math_cf092c7e-0c63-48a9-8431-f7c45644c7dd.wav", "formula": "$=\\frac{6}{25}\\times \\frac{1}{9}+\\frac{6}{25}\\times \\frac{8}{9}$", "answer": "等于二十五分之六乘九分之一,加二十五分之六乘九分之八", "subset": "mixmath", "task_type": "tts"} +{"index": 1968, "question": "Please read the following math formula symbols: $\\mathcal{I}_2\\subset\\{1,\\dots,g+n+k\\}^2$", "audio_path": "audio/row_01979861_1755831583653918.wav", "formula": "$\\mathcal{I}_2\\subset\\{1,\\dots,g+n+k\\}^2$", "answer": "The set I sub 2 is a subset of the set containing 1, dot dot dot, g plus n plus k, squared.", "subset": "mixmath", "task_type": "tts"} +{"index": 1969, "question": "Please read the following math formula symbols: $\\text{exp}(\\norm{x_i-x_j}^2)/2\\sigma^2$", "audio_path": "audio/row_01967564_1755830060923105.wav", "formula": "$\\text{exp}(\\norm{x_i-x_j}^2)/2\\sigma^2$", "answer": "The exponential of the square of the norm of x sub i minus x sub j divided by 2 times sigma squared.", "subset": "mixmath", "task_type": "tts"} +{"index": 1970, "question": "Please read the following math formula symbols: $\\sqrt{C_{11}C_{33}}-C_{13}-2C_{44}=0$", "audio_path": "audio/row_00859475_1755690691681096.wav", "formula": "$\\sqrt{C_{11}C_{33}}-C_{13}-2C_{44}=0$", "answer": "The square root of C sub 11 times C sub 33 minus C sub 13 minus 2 times C sub 44 equals 0.", "subset": "mixmath", "task_type": "tts"} +{"index": 1971, "question": "请你朗读以下数学公式符号:$=\\left( \\frac{16}{5}+\\frac{24}{7}+\\frac{32}{9}+\\frac{40}{11} \\right)\\div \\left( \\frac{2}{5}+\\frac{3}{7}+\\frac{4}{9}+\\frac{5}{11} \\right)$", "audio_path": "audio/math_7a682bea-3c8c-495d-b90b-aca52df6a2c0.wav", "formula": "$=\\left( \\frac{16}{5}+\\frac{24}{7}+\\frac{32}{9}+\\frac{40}{11} \\right)\\div \\left( \\frac{2}{5}+\\frac{3}{7}+\\frac{4}{9}+\\frac{5}{11} \\right)$", "answer": "等于五分之十六加七分之二十四加九分之三十二加十一分之四十的和除以五分之二加七分之三加九分之四加十一分之五的和", "subset": "mixmath", "task_type": "tts"} +{"index": 1972, "question": "Please read the following math formula symbols: $t^-_{\\lambda_n}(\\overline{w}_{\\lambda_n})\\tot$", "audio_path": "audio/row_01650434_1755789983061787.wav", "formula": "$t^-_{\\lambda_n}(\\overline{w}_{\\lambda_n})\\tot$", "answer": "t to the power of negative lambda sub n, open parenthesis, w bar sub lambda sub n, close parenthesis, goes to t.", "subset": "mixmath", "task_type": "tts"} +{"index": 1973, "question": "Please read the following math formula symbols: $e^*(\\calG^I_{Z^{\\sharp}})$", "audio_path": "audio/row_00682942_1755668577048081.wav", "formula": "$e^*(\\calG^I_{Z^{\\sharp}})$", "answer": "e raised to the power of the quantity G raised to the power of I sub Z raised to the sharp power.", "subset": "mixmath", "task_type": "tts"} +{"index": 1974, "question": "Please read the following math formula symbols: $\\sum_kE_k(t)|0\\rangle_s\\langle0|_sE^\\dag_k(t)$", "audio_path": "audio/row_01302363_1755746061943007.wav", "formula": "$\\sum_kE_k(t)|0\\rangle_s\\langle0|_sE^\\dag_k(t)$", "answer": "Sum over k, E sub k of t, ket 0, sub s, bra 0, sub s, E dagger sub k of t.", "subset": "mixmath", "task_type": "tts"} +{"index": 1975, "question": "请你朗读以下数学公式符号:$$\\frac{3}{4\\times 7}+\\frac{3}{7\\times 10}+\\frac{3}{10\\times 13}+\\frac{3}{13\\times 16}$$", "audio_path": "audio/math_0803f1f4-8996-4e64-8671-5e24fdb8b7b2.wav", "formula": "$$\\frac{3}{4\\times 7}+\\frac{3}{7\\times 10}+\\frac{3}{10\\times 13}+\\frac{3}{13\\times 16}$$", "answer": "四乘七的积分之三加七乘十的积分之三加十乘十三的积分之三加十三乘十六的积分之三", "subset": "mixmath", "task_type": "tts"} +{"index": 1976, "question": "请你朗读以下数学公式符号:$\\left[ \\frac{x}{2} \\right]+\\left[ \\frac{x}{3} \\right]+\\left[ \\frac{x}{6} \\right]=x$", "audio_path": "audio/math_6e76b712-f3d0-4b83-a243-01264ade9fa9.wav", "formula": "$\\left[ \\frac{x}{2} \\right]+\\left[ \\frac{x}{3} \\right]+\\left[ \\frac{x}{6} \\right]=x$", "answer": "二分之x向下取整的结果 加 三分之x向下取整的结果 加 六分之x向下取整的结果 等于x", "subset": "mixmath", "task_type": "tts"} +{"index": 1977, "question": "请你朗读以下数学公式符号:$${{\\left( 232 \\right)}_{6}}+{{\\left( 313 \\right)}_{6}} = 0$$", "audio_path": "audio/math_2a432c6f-bbb3-40a0-89fb-bbde5c4e81ae.wav", "formula": "$${{\\left( 232 \\right)}_{6}}+{{\\left( 313 \\right)}_{6}} = 0$$", "answer": "六进制的二三二加六进制的三一三等于零", "subset": "mixmath", "task_type": "tts"} +{"index": 1978, "question": "Please read the following math formula symbols: $g_{(0)ij}=\\Omega(x)^2\\delta_{ij}$", "audio_path": "audio/row_02009706_1755835377943436.wav", "formula": "$g_{(0)ij}=\\Omega(x)^2\\delta_{ij}$", "answer": "g sub open parenthesis 0 close parenthesis i j equals Omega open parenthesis x close parenthesis squared delta sub i j.", "subset": "mixmath", "task_type": "tts"} +{"index": 1979, "question": "Please read the following math formula symbols: $H(t)=\\text{Erf}\\left(\\sqrt{rt}\\right)/\\sqrt{r}$", "audio_path": "audio/row_01853348_1755815621448907.wav", "formula": "$H(t)=\\text{Erf}\\left(\\sqrt{rt}\\right)/\\sqrt{r}$", "answer": "H of t equals the error function of the square root of r times t divided by the square root of r.", "subset": "mixmath", "task_type": "tts"} +{"index": 1980, "question": "请你朗读以下数学公式符号:$\\dfrac{3}{8}\\div 15=\\dfrac{3}{8}\\times \\dfrac{1}{15}=\\dfrac{1\\times 1}{8\\times 5}=\\dfrac{1}{40}$", "audio_path": "audio/math_f1f7663c-c1d1-45ba-abd4-5e169c4bb56d.wav", "formula": "$\\dfrac{3}{8}\\div 15=\\dfrac{3}{8}\\times \\dfrac{1}{15}=\\dfrac{1\\times 1}{8\\times 5}=\\dfrac{1}{40}$", "answer": "八分之三除以十五等于八分之三乘十五分之一等于八乘五的积分之一乘一的积等于四十分之一", "subset": "mixmath", "task_type": "tts"} +{"index": 1981, "question": "Please read the following math formula symbols: $\\cA:=\\Zp\\{\\{X_1,\\cdots,X_d\\}\\}$", "audio_path": "audio/row_00020134_1755587551513146.wav", "formula": "$\\cA:=\\Zp\\{\\{X_1,\\cdots,X_d\\}\\}$", "answer": "The set A is defined as the set of integers modulo p, where X1, X2, ..., Xd are elements of the set.", "subset": "mixmath", "task_type": "tts"} +{"index": 1982, "question": "Please read the following math formula symbols: $d(\\varepsilon)=\\sum_{n=0}^2d_n\\varepsilon^n$", "audio_path": "audio/row_00113440_1755598811434445.wav", "formula": "$d(\\varepsilon)=\\sum_{n=0}^2d_n\\varepsilon^n$", "answer": "d epsilon equals the sum from n equals 0 to 2 of d sub n epsilon to the power of n.", "subset": "mixmath", "task_type": "tts"} +{"index": 1983, "question": "Please read the following math formula symbols: $H^1(\\Omega)\\hookrightarrowL^{2r}(\\Omega)$", "audio_path": "audio/row_01788287_1755807405075961.wav", "formula": "$H^1(\\Omega)\\hookrightarrowL^{2r}(\\Omega)$", "answer": "H raised to the power of 1, in parentheses Omega, hookrightarrow L raised to the power of 2r, in parentheses Omega.", "subset": "mixmath", "task_type": "tts"} +{"index": 1984, "question": "请你朗读以下数学公式符号:$a\\times \\frac{3}{2}=b\\div 0.4=c\\times \\frac{3}{4}=d\\div 80\\%$", "audio_path": "audio/math_04bdd6cb-3334-481a-9b35-2514ed67e5a9.wav", "formula": "$a\\times \\frac{3}{2}=b\\div 0.4=c\\times \\frac{3}{4}=d\\div 80\\%$", "answer": "a乘二分之三等于b除以零点四等于c乘四分之三等于d除以百分之八十", "subset": "mixmath", "task_type": "tts"} +{"index": 1985, "question": "请你朗读以下数学公式符号:$=47+\\dfrac{2}{6\\times 8}+\\frac{2}{8\\times 10}+\\ldots \\ldots +\\dfrac{2}{98\\times 100}$", "audio_path": "audio/math_941dc062-37a9-474d-aeae-f86e0369b30e.wav", "formula": "$=47+\\dfrac{2}{6\\times 8}+\\frac{2}{8\\times 10}+\\ldots \\ldots +\\dfrac{2}{98\\times 100}$", "answer": "等于四十七加六乘八的积分之二加八乘十的积分之二加 一直加到 加九十八乘一百的积分之二", "subset": "mixmath", "task_type": "tts"} +{"index": 1986, "question": "Please read the following math formula symbols: $h_1,\\ldots,h_{K}\\inT_p\\mathbb{H}^D$", "audio_path": "audio/row_00116297_1755599168915560.wav", "formula": "$h_1,\\ldots,h_{K}\\inT_p\\mathbb{H}^D$", "answer": "h sub 1, ellipsis, h sub K belongs to the tangent space at p of the hyperbolic space raised to the power of D.", "subset": "mixmath", "task_type": "tts"} +{"index": 1987, "question": "请你朗读以下数学公式符号:$=0.\\dot{9}+0.\\dot{9}+0.\\dot{9}+0.\\dot{9}+0.\\dot{9}\\approx1+1+1+1+1=5$", "audio_path": "audio/math_65b39623-f285-47f2-9ec3-fb9489c688ef.wav", "formula": "$=0.\\dot{9}+0.\\dot{9}+0.\\dot{9}+0.\\dot{9}+0.\\dot{9}\\approx1+1+1+1+1=5$", "answer": "等于零点九 九循环加零点九 九循环加零点九 九循环加零点九 九循环加零点九 九循环约等于一加一加一加一加一等于五", "subset": "mixmath", "task_type": "tts"} +{"index": 1988, "question": "Please read the following math formula symbols: $\\cU\\to\\mathbb{B}_k(\\cA_{\\gamma}^d;\\cA^m)$", "audio_path": "audio/row_01515003_1755772834525204.wav", "formula": "$\\cU\\to\\mathbb{B}_k(\\cA_{\\gamma}^d;\\cA^m)$", "answer": "c U to the set of B sub k, c A sub gamma to the power of d, semicolon c A to the power of m.", "subset": "mixmath", "task_type": "tts"} +{"index": 1989, "question": "请你朗读以下数学公式符号:$$96=1\\times96=2\\times48=3\\times32=4\\times24=6\\times16=8\\times12$$", "audio_path": "audio/math_0b376b4d-a2dc-44c5-90f7-13048befbe29.wav", "formula": "$$96=1\\times96=2\\times48=3\\times32=4\\times24=6\\times16=8\\times12$$", "answer": "九十六等于一乘九十六等于二乘四十八等于三乘三十二等于四乘二十四等于六乘十六等于八乘十二", "subset": "mixmath", "task_type": "tts"} +{"index": 1990, "question": "请你朗读以下数学公式符号:$=60\\frac{5}{3}\\div \\frac{5}{3}+70\\frac{7}{4}\\div \\frac{7}{4}+90\\frac{9}{5}\\div \\frac{9}{5}$", "audio_path": "audio/math_0e22eebd-6ec0-4746-a6d2-14dee26cf290.wav", "formula": "$=60\\frac{5}{3}\\div \\frac{5}{3}+70\\frac{7}{4}\\div \\frac{7}{4}+90\\frac{9}{5}\\div \\frac{9}{5}$", "answer": "等于六十又五分之三除以三分之五加上七十又四分之七除以四分之七加上九十又五分之九除以五分之九", "subset": "mixmath", "task_type": "tts"} +{"index": 1991, "question": "请你朗读以下数学公式符号:$${{2}^{3}}=3+5,{{3}^{3}}=7+9+11,{{4}^{3}}=13+15+17+19$$", "audio_path": "audio/math_ec99e4d1-06d9-41e7-b0af-c986f0086c1b.wav", "formula": "$${{2}^{3}}=3+5,{{3}^{3}}=7+9+11,{{4}^{3}}=13+15+17+19$$", "answer": "二的立方等于三加五的和,三的立方等于七加九加十一,四的立方等于十三加十五加十七加十九", "subset": "mixmath", "task_type": "tts"} +{"index": 1992, "question": "Please read the following math formula symbols: $\\frac{n^+}{N}(1-a)\\left(1-q(\\tau)\\right)$", "audio_path": "audio/row_01946391_1755827383682563.wav", "formula": "$\\frac{n^+}{N}(1-a)\\left(1-q(\\tau)\\right)$", "answer": "Fraction N plus divided by N, multiplied by the quantity one minus a, multiplied by the quantity one minus q of tau.", "subset": "mixmath", "task_type": "tts"} +{"index": 1993, "question": "Please read the following math formula symbols: $\\Z_p=\\varprojlim\\mathbb\\{Z/p^n\\mathbb\\{Z$", "audio_path": "audio/row_01648629_1755789736001834.wav", "formula": "$\\Z_p=\\varprojlim\\mathbb\\{Z/p^n\\mathbb\\{Z$", "answer": "Z sub p equals the inverse limit of the set of integers modulo p to the power of n, and Z.", "subset": "mixmath", "task_type": "tts"} +{"index": 1994, "question": "Please read the following math formula symbols: $x_e=\\sum_{P\\in\\calP:e\\inP}x_{P}$", "audio_path": "audio/row_01735796_1755800754563590.wav", "formula": "$x_e=\\sum_{P\\in\\calP:e\\inP}x_{P}$", "answer": "x subscript e equals the sum over P in the set P such that e is in P of x subscript P.", "subset": "mixmath", "task_type": "tts"} +{"index": 1995, "question": "请你朗读以下数学公式符号:$$\\begin{cases}x+y=5 \\\\ y+z=6 \\\\ x+z=7 \\\\ \\end{cases}$$", "audio_path": "audio/math_79fb8e11-4260-497a-80b5-9b4706bc0648.wav", "formula": "$$\\begin{cases}x+y=5 \\\\ y+z=6 \\\\ x+z=7 \\\\ \\end{cases}$$", "answer": "x加y等于五和y加z等于六和x加z等于七", "subset": "mixmath", "task_type": "tts"} +{"index": 1996, "question": "Please read the following math formula symbols: $\\|l\\|_{e}=(l_1^2+\\cdots+l_n^2)^{\\frac{1}{2}}$", "audio_path": "audio/row_00164915_1755605049183004.wav", "formula": "$\\|l\\|_{e}=(l_1^2+\\cdots+l_n^2)^{\\frac{1}{2}}$", "answer": "Norm of l, subscript e, equals the square root of the sum of the squares of l sub 1, dot dot dot, l sub n.", "subset": "mixmath", "task_type": "tts"} +{"index": 1997, "question": "请你朗读以下数学公式符号:$=(2\\times 5)\\times (4\\times 25)\\times (8\\times 125)\\times (16\\times 25)$", "audio_path": "audio/math_3c22501f-0630-43fa-8042-0e217b3fdea9.wav", "formula": "$=(2\\times 5)\\times (4\\times 25)\\times (8\\times 125)\\times (16\\times 25)$", "answer": "等于二乘五的积乘四乘二十五的积乘八乘一百二十五的积乘十六乘二十五的积", "subset": "mixmath", "task_type": "tts"} +{"index": 1998, "question": "Please read the following math formula symbols: $\\log_{10}n_0=-2.6^{+1.2}_{-1.1}$", "audio_path": "audio/row_01684303_1755794259601214.wav", "formula": "$\\log_{10}n_0=-2.6^{+1.2}_{-1.1}$", "answer": "The logarithm base 10 of n sub 0 equals negative 2.6 raised to the power of plus 1.2 sub negative 1.1.", "subset": "mixmath", "task_type": "tts"} +{"index": 1999, "question": "请你朗读以下数学公式符号:${{x}^{4}}+{{x}^{2}}+a={{x}^{4}}+(m+n){{x}^{2}}+mn$", "audio_path": "audio/math_20f90e14-6d77-4164-9800-3c1e9362ad1f.wav", "formula": "${{x}^{4}}+{{x}^{2}}+a={{x}^{4}}+(m+n){{x}^{2}}+mn$", "answer": "x的四次方加x的平方加a等于x的四次方加m加n的和乘x的平方加mn", "subset": "mixmath", "task_type": "tts"} diff --git a/MixMath/audio/math_006183ea-bc2d-448c-a69b-d66c4db728aa.wav b/MixMath/audio/math_006183ea-bc2d-448c-a69b-d66c4db728aa.wav new file mode 100644 index 0000000000000000000000000000000000000000..629ff357ed2a9f64e8fa49810f47c8ece6b4e7ec --- /dev/null +++ b/MixMath/audio/math_006183ea-bc2d-448c-a69b-d66c4db728aa.wav @@ -0,0 +1,3 @@ +version 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a/Physics700/Physics700.jsonl b/Physics700/Physics700.jsonl new file mode 100644 index 0000000000000000000000000000000000000000..6edbec61f83089555aa19d9706e194cb593b8b58 --- /dev/null +++ b/Physics700/Physics700.jsonl @@ -0,0 +1,710 @@ +{"index": 0, "question": "Please read the following physics formula symbols: $$1.0\\times 10^{3}kg/m^{3}$$", "audio_path": "audio/physics_eb3d1fa7-016d-4b61-a14f-c5891f8cc144.wav", "formula": "$$1.0\\times 10^{3}kg/m^{3}$$", "answer": "one point zero times l zero cubed kilograms over meters cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 1, "question": "Please read the following physics formula symbols: $$v=\\frac{ε}{h}$$", "audio_path": "audio/physics_c9e5f99d-4cbf-4af8-9c85-0287d1a12b8c.wav", "formula": "$$v=\\frac{ε}{h}$$", "answer": "v equals epsilon over Planck's constant h", "subset": "Physics700", "task_type": "tts"} +{"index": 2, "question": "请你朗读以下物理公式符号:$\\frac{\\sin θ_{1}}{\\sin θ_{2}}$", "audio_path": "audio/physics_6631f2ee-7c04-468e-bbf0-9c5099378ab9.wav", "formula": "$\\frac{\\sin θ_{1}}{\\sin θ_{2}}$", "answer": "sine theta 二 分之 sine theta 一", "subset": "Physics700", "task_type": "tts"} +{"index": 3, "question": "请你朗读以下物理公式符号:$0.8×10^{3} kg/m^{3}$", "audio_path": "audio/physics_b4757b54-ee99-4603-8d66-1cf69fa2751a.wav", "formula": "$0.8×10^{3} kg/m^{3}$", "answer": "零点八乘十的三次方千克每立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 4, "question": "Please read the following physics formula symbols: $$\\upsilon=\\frac{s}{t}$$", "audio_path": "audio/physics_00a33106-d681-4dd9-8a9b-12af27de2a05.wav", "formula": "$$\\upsilon=\\frac{s}{t}$$", "answer": "upsilon equals s over t", "subset": "Physics700", "task_type": "tts"} +{"index": 5, "question": "Please read the following physics formula symbols: $W_{1}:W_{2}=1:3$", "audio_path": "audio/physics_9e818faa-0aed-44a7-baa2-88961d628c6f.wav", "formula": "$W_{1}:W_{2}=1:3$", "answer": "The ratio of W one to W two equals one to three", "subset": "Physics700", "task_type": "tts"} +{"index": 6, "question": "请你朗读以下物理公式符号:$$7.3×10^{26}g=$$", "audio_path": "audio/physics_9a6b71d2-080f-417e-8b33-bafcd27b36f9.wav", "formula": "$$7.3×10^{26}g=$$", "answer": "七点三乘十的二十六次方克等于", "subset": "Physics700", "task_type": "tts"} +{"index": 7, "question": "Please read the following physics formula symbols: $x=−\\upsilon t−\\frac{1}{2}at^{2}$", "audio_path": "audio/physics_c3f4df62-e383-4a22-b6dc-ecb9c3bdda70.wav", "formula": "$x=−\\upsilon t−\\frac{1}{2}at^{2}$", "answer": "x equals negative upsilon times t minus one over two times a times t squared", "subset": "Physics700", "task_type": "tts"} +{"index": 8, "question": "请你朗读以下物理公式符号:$-\\frac{3}{16}E_{1}$", "audio_path": "audio/physics_8f7a3415-6c2a-4bca-bc3b-6dcc65e29a9f.wav", "formula": "$-\\frac{3}{16}E_{1}$", "answer": "负的十六分之三乘E一", "subset": "Physics700", "task_type": "tts"} +{"index": 9, "question": "请你朗读以下物理公式符号:$$v=\\frac{S}{t}$$", "audio_path": "audio/physics_5c4d9dba-befe-439d-9fef-df956f42de0b.wav", "formula": "$$v=\\frac{S}{t}$$", "answer": "v 等于 t 分之 S", "subset": "Physics700", "task_type": "tts"} +{"index": 10, "question": "请你朗读以下物理公式符号:$\\frac{p}{p_{0}}$", "audio_path": "audio/physics_c1be2cfe-cdeb-4a60-ac1f-8376b6bcc5ba.wav", "formula": "$\\frac{p}{p_{0}}$", "answer": "p 零分之 p", "subset": "Physics700", "task_type": "tts"} +{"index": 11, "question": "Please read the following physics formula symbols: $$1.4 \\times 10^{8} \\mathrm{J/kg}$$", "audio_path": "audio/physics_d3278039-93f0-47d0-92da-d72f2ca35e38.wav", "formula": "$$1.4 \\times 10^{8} \\mathrm{J/kg}$$", "answer": "1.4 times 10 to the power of 8 joules over kilograms", "subset": "Physics700", "task_type": "tts"} +{"index": 12, "question": "Please read the following physics formula symbols: $$I=\\frac{P}{U}$$", "audio_path": "audio/physics_ac800d14-b188-42bc-afae-be8010560872.wav", "formula": "$$I=\\frac{P}{U}$$", "answer": "I equals P over U", "subset": "Physics700", "task_type": "tts"} +{"index": 13, "question": "Please read the following physics formula symbols: $\\frac{\\frac{Gh}{η}−Gh}{s}$", "audio_path": "audio/physics_d8c95b5a-bca1-48c1-8e85-f67f4711a0a8.wav", "formula": "$\\frac{\\frac{Gh}{η}−Gh}{s}$", "answer": "the difference between G h over eta and G h, over s", "subset": "Physics700", "task_type": "tts"} +{"index": 14, "question": "请你朗读以下物理公式符号:$$F=\\frac{1}{n}G$$", "audio_path": "audio/physics_a27581fa-3e18-4ff9-948b-8e07d05f63ba.wav", "formula": "$$F=\\frac{1}{n}G$$", "answer": "F等于n分之一乘G", "subset": "Physics700", "task_type": "tts"} +{"index": 15, "question": "Please read the following physics formula symbols: $$F_{1}l_{1}=F_{2}l_{2}$$", "audio_path": "audio/physics_6b37692c-aa6c-4c8e-8697-8c903eda8927.wav", "formula": "$$F_{1}l_{1}=F_{2}l_{2}$$", "answer": "F one times l one equals F two times l two", "subset": "Physics700", "task_type": "tts"} +{"index": 16, "question": "请你朗读以下物理公式符号:$$0.8\\times 10^{3} \\mathrm{Kg/m^{3}}$$", "audio_path": "audio/physics_39c8df6a-a923-4735-b634-4808855dcfad.wav", "formula": "$$0.8\\times 10^{3} \\mathrm{Kg/m^{3}}$$", "answer": "零点八乘十的三次方千克每立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 17, "question": "请你朗读以下物理公式符号:$= 2.5 \\times 10^{-5} \\, \\text{dm}$", "audio_path": "audio/physics_ae53f192-9933-4040-8127-0927be6667cf.wav", "formula": "$= 2.5 \\times 10^{-5} \\, \\text{dm}$", "answer": "等于二点五乘十的负五次方分米", "subset": "Physics700", "task_type": "tts"} +{"index": 18, "question": "请你朗读以下物理公式符号:$^{235}_{92}\\mathrm{U} + ^{1}_{0}n \\rightarrow ^{141}_{56}\\mathrm{Ba} + ^{92}_{36}\\mathrm{Kr} + 3^{1}_{0}n$", "audio_path": "audio/physics_654f79c3-1f52-4848-9a07-444110ef8d86.wav", "formula": "$^{235}_{92}\\mathrm{U} + ^{1}_{0}n \\rightarrow ^{141}_{56}\\mathrm{Ba} + ^{92}_{36}\\mathrm{Kr} + 3^{1}_{0}n$", "answer": "铀-二百三十五 加一个中子,生成钡-一百四十一加氪-九十二加三个中子", "subset": "Physics700", "task_type": "tts"} +{"index": 19, "question": "请你朗读以下物理公式符号:$$8.7×10^{7}J/m^{3}$$", "audio_path": "audio/physics_bd042fcf-a968-411f-a750-46db1380e9c5.wav", "formula": "$$8.7×10^{7}J/m^{3}$$", "answer": "八点七乘十的七次方焦耳每立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 20, "question": "Please read the following physics formula symbols: $U=\\frac{P}{I}$", "audio_path": "audio/physics_4fc044b9-ea82-4627-8aff-b10716478197.wav", "formula": "$U=\\frac{P}{I}$", "answer": "U equals P over I", "subset": "Physics700", "task_type": "tts"} +{"index": 21, "question": "请你朗读以下物理公式符号:$$1.0\\times 10^{3}kg/m^{3}$$", "audio_path": "audio/physics_1d618dbc-34f1-4ce4-9fe5-a1b398abd75a.wav", "formula": "$$1.0\\times 10^{3}kg/m^{3}$$", "answer": "一点零乘十的三次方千克每立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 22, "question": "Please read the following physics formula symbols: $= 0.46 \\times 10^{3} \\, \\mathrm{J/(kg \\cdot \\degree C)}$", "audio_path": "audio/physics_1c2baff9-2410-4474-a89e-c2ae5252fb90.wav", "formula": "$= 0.46 \\times 10^{3} \\, \\mathrm{J/(kg \\cdot \\degree C)}$", "answer": "equals 0.46 times 10 cubed joules per kilogram degree Celsius", "subset": "Physics700", "task_type": "tts"} +{"index": 23, "question": "请你朗读以下物理公式符号:$\\frac{v_{0}}{g}$", "audio_path": "audio/physics_7865a233-3907-4c17-8147-5c88b16d5e6e.wav", "formula": "$\\frac{v_{0}}{g}$", "answer": "g 分之 v 零", "subset": "Physics700", "task_type": "tts"} +{"index": 24, "question": "请你朗读以下物理公式符号:$\\frac{H}{4\\left(T_{2}−T_{1}\\right)^{2}}$", "audio_path": "audio/physics_008c79ad-2c11-4523-8e01-3fba15365604.wav", "formula": "$\\frac{H}{4\\left(T_{2}−T_{1}\\right)^{2}}$", "answer": "四乘T二减T一的差的平方 分之H", "subset": "Physics700", "task_type": "tts"} +{"index": 25, "question": "Please read the following physics formula symbols: $t=\\frac{1}{120}$", "audio_path": "audio/physics_b20a3669-6372-46e6-bab5-fdf6f34711fe.wav", "formula": "$t=\\frac{1}{120}$", "answer": "t equals one over one hundred twenty", "subset": "Physics700", "task_type": "tts"} +{"index": 26, "question": "Please read the following physics formula symbols: $v=40\\,\\mathrm{m/s},\\ C.a=80\\,\\mathrm{m/s}$", "audio_path": "audio/physics_aac33d81-77c7-414d-bb7f-172d49f775e5.wav", "formula": "$v=40\\,\\mathrm{m/s},\\ C.a=80\\,\\mathrm{m/s}$", "answer": "v equals 40 meters per second, C times a equals 80 meters per second", "subset": "Physics700", "task_type": "tts"} +{"index": 27, "question": "Please read the following physics formula symbols: $$m=\\frac{Q}{q}$$", "audio_path": "audio/physics_92fc9729-f7b7-4244-b7db-618113b11ad9.wav", "formula": "$$m=\\frac{Q}{q}$$", "answer": "m equals Q over q", "subset": "Physics700", "task_type": "tts"} +{"index": 28, "question": "请你朗读以下物理公式符号:$\\frac{1.2×10^{−2}}{0.1^{2}}$", "audio_path": "audio/physics_6fa6c7f4-2df5-44c8-922b-e8f4fa69c865.wav", "formula": "$\\frac{1.2×10^{−2}}{0.1^{2}}$", "answer": "零点一的平方分之一点二乘十的负二次方", "subset": "Physics700", "task_type": "tts"} +{"index": 29, "question": "请你朗读以下物理公式符号:$$\\frac{a^{3}}{T^{2}}$$", "audio_path": "audio/physics_fe48f73b-c47d-40d5-a818-a526c82e90d5.wav", "formula": "$$\\frac{a^{3}}{T^{2}}$$", "answer": "T的平方分之a的立方", "subset": "Physics700", "task_type": "tts"} +{"index": 30, "question": "Please read the following physics formula symbols: $$P=\\frac{U^{2}}{R}$$", "audio_path": "audio/physics_531a4352-7531-4007-be37-09b582f8302d.wav", "formula": "$$P=\\frac{U^{2}}{R}$$", "answer": "P equals U squared over R", "subset": "Physics700", "task_type": "tts"} +{"index": 31, "question": "请你朗读以下物理公式符号:$$\\frac{R^{3}}{T^{2}}$$", "audio_path": "audio/physics_7a9da727-1729-42b7-bf77-337162a587ea.wav", "formula": "$$\\frac{R^{3}}{T^{2}}$$", "answer": "T的平方分之R的立方", "subset": "Physics700", "task_type": "tts"} +{"index": 32, "question": "请你朗读以下物理公式符号:$$λ=\\frac{c}{f}$$", "audio_path": "audio/physics_650123f5-ca19-497e-9ca2-a2d7f7f8c29a.wav", "formula": "$$λ=\\frac{c}{f}$$", "answer": "lambda等于f分之c", "subset": "Physics700", "task_type": "tts"} +{"index": 33, "question": "Please read the following physics formula symbols: $$\\frac{d}{2}mm$$", "audio_path": "audio/physics_0c02c8fd-6449-49c9-9a82-76b499d616ac.wav", "formula": "$$\\frac{d}{2}mm$$", "answer": "d over two times m m", "subset": "Physics700", "task_type": "tts"} +{"index": 34, "question": "请你朗读以下物理公式符号:$$1.26×10^{4} J$$", "audio_path": "audio/physics_c5aab513-db6f-4314-bbf0-873ef0f231b2.wav", "formula": "$$1.26×10^{4} J$$", "answer": "一点二六乘十的四次方焦耳", "subset": "Physics700", "task_type": "tts"} +{"index": 35, "question": "Please read the following physics formula symbols: $$P=\\frac{F}{s \\frac{G}{s}}=\\frac{\\rho s h g}{s}=\\rho gh$$", "audio_path": "audio/physics_223b70f6-8613-490e-a74a-97be2f9930db.wav", "formula": "$$P=\\frac{F}{s \\frac{G}{s}}=\\frac{\\rho s h g}{s}=\\rho gh$$", "answer": "P equals F over s times G over s, equalsrotimes s times h times g over s, equalsrotimes g times h", "subset": "Physics700", "task_type": "tts"} +{"index": 36, "question": "Please read the following physics formula symbols: $$I=\\frac{Q}{t}$$", "audio_path": "audio/physics_d7a7468f-5897-4641-9773-a1f8a3a33a79.wav", "formula": "$$I=\\frac{Q}{t}$$", "answer": "I equals Q over t", "subset": "Physics700", "task_type": "tts"} +{"index": 37, "question": "请你朗读以下物理公式符号:$E=5×10^{5}V/m$", "audio_path": "audio/physics_b07fbfe1-a629-4659-9660-f7ebdafb5c8b.wav", "formula": "$E=5×10^{5}V/m$", "answer": "E等于五乘十的五次方伏特每米", "subset": "Physics700", "task_type": "tts"} +{"index": 38, "question": "Please read the following physics formula symbols: $$4.6×10^{7}J/kg$$", "audio_path": "audio/physics_718ab73b-5bc6-4f04-b984-a9825ff37494.wav", "formula": "$$4.6×10^{7}J/kg$$", "answer": "4.6 times 10 to the power of 7 J over kg", "subset": "Physics700", "task_type": "tts"} +{"index": 39, "question": "Please read the following physics formula symbols: $\\frac{p_{0}}{p}$", "audio_path": "audio/physics_e1ec6dbc-3250-4a64-a5d7-76cbab513915.wav", "formula": "$\\frac{p_{0}}{p}$", "answer": "p naught over p", "subset": "Physics700", "task_type": "tts"} +{"index": 40, "question": "Please read the following physics formula symbols: $0.7×10^{3}kg/m^{3}$", "audio_path": "audio/physics_2b495ecc-8b4a-4a4f-b5f4-a80a59f14bca.wav", "formula": "$0.7×10^{3}kg/m^{3}$", "answer": "zero point seven times ten cubed kilograms over meter cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 41, "question": "请你朗读以下物理公式符号:$h=\\frac{1}{2}gt^{2}$", "audio_path": "audio/physics_16750c5e-940b-49b6-b6a1-4834b1367c88.wav", "formula": "$h=\\frac{1}{2}gt^{2}$", "answer": "h等于二分之一乘g乘t的平方", "subset": "Physics700", "task_type": "tts"} +{"index": 42, "question": "请你朗读以下物理公式符号:$$P =\\frac{F}{S}$$", "audio_path": "audio/physics_58a00abb-7319-4a3b-b5f1-2061a26506d2.wav", "formula": "$$P =\\frac{F}{S}$$", "answer": "P 等于 S 分之 F", "subset": "Physics700", "task_type": "tts"} +{"index": 43, "question": "Please read the following physics formula symbols: $$p=\\frac{w}{t}$$", "audio_path": "audio/physics_0739c097-9095-46ec-ae01-7bbe1f3d5292.wav", "formula": "$$p=\\frac{w}{t}$$", "answer": "p equals w over t", "subset": "Physics700", "task_type": "tts"} +{"index": 44, "question": "请你朗读以下物理公式符号:$$a=\\frac{∆v}{∆t}$$", "audio_path": "audio/physics_bd0e6a55-ffa3-4ec0-bc54-9abd580d55ad.wav", "formula": "$$a=\\frac{∆v}{∆t}$$", "answer": "a 等于 delta t分之 delta v", "subset": "Physics700", "task_type": "tts"} +{"index": 45, "question": "请你朗读以下物理公式符号:$v=40\\,\\mathrm{m/s},\\ C.a=80\\,\\mathrm{m/s}$", "audio_path": "audio/physics_6fb901bf-a7ef-4d8f-88f0-baf072e51718.wav", "formula": "$v=40\\,\\mathrm{m/s},\\ C.a=80\\,\\mathrm{m/s}$", "answer": "v等于四十米每秒,C,a等于八十米每秒", "subset": "Physics700", "task_type": "tts"} +{"index": 46, "question": "请你朗读以下物理公式符号:$$\\frac{50}{273}$$", "audio_path": "audio/physics_3da4acae-ed94-4516-a33c-13cf6631fa98.wav", "formula": "$$\\frac{50}{273}$$", "answer": "二百七十三分之五十", "subset": "Physics700", "task_type": "tts"} +{"index": 47, "question": "Please read the following physics formula symbols: $$p=\\frac{F}{S}$$", "audio_path": "audio/physics_a909a100-42c1-41d8-91c4-fb73670a2bd0.wav", "formula": "$$p=\\frac{F}{S}$$", "answer": "p equals F over S", "subset": "Physics700", "task_type": "tts"} +{"index": 48, "question": "请你朗读以下物理公式符号:$$\\frac{a^{3}}{T^{2}}=k$$", "audio_path": "audio/physics_789fcd95-9672-4797-bbaf-4dc9a3a83bca.wav", "formula": "$$\\frac{a^{3}}{T^{2}}=k$$", "answer": "T的平方分之a的立方等于k", "subset": "Physics700", "task_type": "tts"} +{"index": 49, "question": "请你朗读以下物理公式符号:$\\frac{p_{0}}{p}$", "audio_path": "audio/physics_de6928ad-ccc4-423a-a76b-ef3108bb8bdf.wav", "formula": "$\\frac{p_{0}}{p}$", "answer": "p 分之 p 零", "subset": "Physics700", "task_type": "tts"} +{"index": 50, "question": "请你朗读以下物理公式符号:$\\frac{v0+v1}{2}$", "audio_path": "audio/physics_34de878d-ea1c-4e14-8ab8-f5ea42809b86.wav", "formula": "$\\frac{v0+v1}{2}$", "answer": "二分之v 零加v 一的和", "subset": "Physics700", "task_type": "tts"} +{"index": 51, "question": "请你朗读以下物理公式符号:$P_{max}={\\frac{E}{4r}}^{2}$", "audio_path": "audio/physics_80a41ce2-7a30-4beb-af7f-25eba3acff2a.wav", "formula": "$P_{max}={\\frac{E}{4r}}^{2}$", "answer": "P 最大等于四乘r的积分之E平方", "subset": "Physics700", "task_type": "tts"} +{"index": 52, "question": "Please read the following physics formula symbols: $\\frac{hc}{λPΔt}$", "audio_path": "audio/physics_80187e6b-3aca-40f7-8590-e0d447383f5f.wav", "formula": "$\\frac{hc}{λPΔt}$", "answer": "Planck's constant h times speed of light c over lambda times P times delta t", "subset": "Physics700", "task_type": "tts"} +{"index": 53, "question": "Please read the following physics formula symbols: $$Δt=\\frac{Q}{Cm}$$", "audio_path": "audio/physics_7d4d5ff1-7139-44fa-a3e1-dac1ab2d69f0.wav", "formula": "$$Δt=\\frac{Q}{Cm}$$", "answer": "delta t equals Q over C times m", "subset": "Physics700", "task_type": "tts"} +{"index": 54, "question": "请你朗读以下物理公式符号:$\\frac{v_{2}-v_{1}}{t}$", "audio_path": "audio/physics_3867ee37-000c-4678-a240-3daa6673e002.wav", "formula": "$\\frac{v_{2}-v_{1}}{t}$", "answer": "t 分之 v 二减 v 一的差", "subset": "Physics700", "task_type": "tts"} +{"index": 55, "question": "请你朗读以下物理公式符号:$10^{−18} m^{3}$", "audio_path": "audio/physics_80cc058f-2b12-4ce1-a466-7b13bb363975.wav", "formula": "$10^{−18} m^{3}$", "answer": "十的负十八次方立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 56, "question": "请你朗读以下物理公式符号:$$t=\\frac{4}{3}s$$", "audio_path": "audio/physics_50c74613-e16c-46ce-897a-ad7b3e1652e9.wav", "formula": "$$t=\\frac{4}{3}s$$", "answer": "t等于三分之四秒", "subset": "Physics700", "task_type": "tts"} +{"index": 57, "question": "Please read the following physics formula symbols: $$\\frac{2πr}{T}$$", "audio_path": "audio/physics_c5278a7d-4736-4465-9705-010dfc161a5d.wav", "formula": "$$\\frac{2πr}{T}$$", "answer": "two pi r over T", "subset": "Physics700", "task_type": "tts"} +{"index": 58, "question": "请你朗读以下物理公式符号:$P=\\frac{F}{S}=\\frac{G}{S}=\\frac{mg}{S}=\\frac{ρVg}{S}=\\frac{ρShg}{S}=ρgh$", "audio_path": "audio/physics_c46b6257-a2f3-4d45-9d85-3dad311646c8.wav", "formula": "$P=\\frac{F}{S}=\\frac{G}{S}=\\frac{mg}{S}=\\frac{ρVg}{S}=\\frac{ρShg}{S}=ρgh$", "answer": "P 等于 S 分之 F 等于 S 分之 G 等于 S 分之 m乘g 等于S 分之 rho乘V乘 g 等于 S 分之 rho乘S乘 h乘 g 等于 rho乘g乘 h", "subset": "Physics700", "task_type": "tts"} +{"index": 59, "question": "Please read the following physics formula symbols: $$p=FV_{m}=fV_{m}$$", "audio_path": "audio/physics_6bc22c70-d71e-4ac5-861c-fdb850067688.wav", "formula": "$$p=FV_{m}=fV_{m}$$", "answer": "p equals F times V m equals f times V m", "subset": "Physics700", "task_type": "tts"} +{"index": 60, "question": "Please read the following physics formula symbols: $U_{1}^{'}:U_{2}^{'}$", "audio_path": "audio/physics_35b35c4c-0ad8-4379-b4bd-8649847c6050.wav", "formula": "$U_{1}^{'}:U_{2}^{'}$", "answer": "U one prime to U two prime", "subset": "Physics700", "task_type": "tts"} +{"index": 61, "question": "Please read the following physics formula symbols: $$v=\\frac{S}{t}$$", "audio_path": "audio/physics_2f308971-d355-44a7-927a-d33d50f4f80e.wav", "formula": "$$v=\\frac{S}{t}$$", "answer": "v equals S over t", "subset": "Physics700", "task_type": "tts"} +{"index": 62, "question": "Please read the following physics formula symbols: $$\\frac{c\\Delta t}{h\\lambda P}$$", "audio_path": "audio/physics_fa19a030-6ddd-47c3-ad77-964d1ec8dbdd.wav", "formula": "$$\\frac{c\\Delta t}{h\\lambda P}$$", "answer": "speed of light c times delta t over Planck's constant h times lambda times P", "subset": "Physics700", "task_type": "tts"} +{"index": 63, "question": "请你朗读以下物理公式符号:$$\\frac{Δv}{Δt}$$", "audio_path": "audio/physics_da60deb5-d956-4940-9579-8f636d8031af.wav", "formula": "$$\\frac{Δv}{Δt}$$", "answer": "delta t分之delta v", "subset": "Physics700", "task_type": "tts"} +{"index": 64, "question": "Please read the following physics formula symbols: $$0.92\\times 10^{3}kg/m^{3}$$", "audio_path": "audio/physics_561c79ec-b4f3-45ae-95ba-d8b3b4acf4c3.wav", "formula": "$$0.92\\times 10^{3}kg/m^{3}$$", "answer": "zero point nine two times ten cubed kilograms per cubic meter", "subset": "Physics700", "task_type": "tts"} +{"index": 65, "question": "请你朗读以下物理公式符号:$t=\\frac{1}{120}$", "audio_path": "audio/physics_ff2cd154-169f-41ce-af06-fcc89a33c42e.wav", "formula": "$t=\\frac{1}{120}$", "answer": "t 等于 一百二十分之一", "subset": "Physics700", "task_type": "tts"} +{"index": 66, "question": "请你朗读以下物理公式符号:$$I=\\frac{Q}{t}$$", "audio_path": "audio/physics_db89d5b6-f5f2-4106-9848-d87a4d195357.wav", "formula": "$$I=\\frac{Q}{t}$$", "answer": "i等于t分之q", "subset": "Physics700", "task_type": "tts"} +{"index": 67, "question": "请你朗读以下物理公式符号:$$3.84 \\times 10^{5}~\\mathrm{km}$$", "audio_path": "audio/physics_c568c3bd-d105-4d1d-a296-44b1e4c5b6cf.wav", "formula": "$$3.84 \\times 10^{5}~\\mathrm{km}$$", "answer": "三点八四乘十的五次方千米", "subset": "Physics700", "task_type": "tts"} +{"index": 68, "question": "Please read the following physics formula symbols: $$\\frac{Kq}{r^{2}}$$", "audio_path": "audio/physics_29279b04-027b-40ff-bc70-968bd2e0c100.wav", "formula": "$$\\frac{Kq}{r^{2}}$$", "answer": "K q over r squared", "subset": "Physics700", "task_type": "tts"} +{"index": 69, "question": "Please read the following physics formula symbols: $$3.0 \\times 10^{8} m/s$$", "audio_path": "audio/physics_b459a90b-ea49-4e95-a4af-b6c09ac50dcb.wav", "formula": "$$3.0 \\times 10^{8} m/s$$", "answer": "3.0 times 10 to the power of 8 meters per second", "subset": "Physics700", "task_type": "tts"} +{"index": 70, "question": "Please read the following physics formula symbols: $4.2×10^{3}J/\\left(kg⋅℃\\right)$", "audio_path": "audio/physics_f84e7775-7e70-4d40-bbc4-1500a0c114be.wav", "formula": "$4.2×10^{3}J/\\left(kg⋅℃\\right)$", "answer": "4.2 times 10 cubed joules over kilogram times degrees Celsius", "subset": "Physics700", "task_type": "tts"} +{"index": 71, "question": "Please read the following physics formula symbols: $$Q=W=Pt=\\frac{U^{2}}{R}t$$", "audio_path": "audio/physics_a7857c05-017a-4c79-aa7f-5133d00f4177.wav", "formula": "$$Q=W=Pt=\\frac{U^{2}}{R}t$$", "answer": "Q equals W equals P times t equals U squared over R times t", "subset": "Physics700", "task_type": "tts"} +{"index": 72, "question": "Please read the following physics formula symbols: $10^{−18} m^{3}$", "audio_path": "audio/physics_7bb84ed2-7c27-464b-b8ef-533ce80356f5.wav", "formula": "$10^{−18} m^{3}$", "answer": "10 to the power of negative 18 times m cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 73, "question": "Please read the following physics formula symbols: $$R_{1}:R_{2}=3:4$$", "audio_path": "audio/physics_42d23068-6bc3-4340-929a-5cdff80961df.wav", "formula": "$$R_{1}:R_{2}=3:4$$", "answer": "R one to R two equals three to four", "subset": "Physics700", "task_type": "tts"} +{"index": 74, "question": "Please read the following physics formula symbols: $$3.645×10^{10}$$", "audio_path": "audio/physics_1c7bd55a-a52e-47f5-a730-ac701bd0d45e.wav", "formula": "$$3.645×10^{10}$$", "answer": "three point six four five times ten to the power of ten", "subset": "Physics700", "task_type": "tts"} +{"index": 75, "question": "请你朗读以下物理公式符号:$\\frac{r^{3}}{k}$", "audio_path": "audio/physics_6e164ae0-55be-4487-9d41-8c08eb3c385b.wav", "formula": "$\\frac{r^{3}}{k}$", "answer": "k 分之 r 的立方", "subset": "Physics700", "task_type": "tts"} +{"index": 76, "question": "Please read the following physics formula symbols: $m\\left(\\frac{2π}{T}\\right)^{2}r$", "audio_path": "audio/physics_67d323b1-c954-47ba-bd74-b107bbcae700.wav", "formula": "$m\\left(\\frac{2π}{T}\\right)^{2}r$", "answer": "m times the square of the quantity two pi over tee times r", "subset": "Physics700", "task_type": "tts"} +{"index": 77, "question": "请你朗读以下物理公式符号:$v=\\frac{2πR}{T}$", "audio_path": "audio/physics_a4df3b60-dba6-4a88-802b-4551e4c54306.wav", "formula": "$v=\\frac{2πR}{T}$", "answer": "v 等于 T 分之二乘 pi 乘 R", "subset": "Physics700", "task_type": "tts"} +{"index": 78, "question": "请你朗读以下物理公式符号:$\\frac{1}{10}m^{3}$", "audio_path": "audio/physics_ca9ac401-5800-4de6-b160-789c9bf81fa3.wav", "formula": "$\\frac{1}{10}m^{3}$", "answer": "十分之一立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 79, "question": "Please read the following physics formula symbols: $\\frac{υ^{2}}{r}$", "audio_path": "audio/physics_6dda1235-da16-4f2b-9fea-08207765d940.wav", "formula": "$\\frac{υ^{2}}{r}$", "answer": "upsilon squared over r", "subset": "Physics700", "task_type": "tts"} +{"index": 80, "question": "请你朗读以下物理公式符号:$\\left(2\\right)$", "audio_path": "audio/physics_af677dfb-d788-4cf6-8905-06dec692c60e.wav", "formula": "$\\left(2\\right)$", "answer": "二", "subset": "Physics700", "task_type": "tts"} +{"index": 81, "question": "Please read the following physics formula symbols: $1.03×10^{3}kg/m^{3}$", "audio_path": "audio/physics_b8c55c28-6a10-4152-a87a-1516a840f4d6.wav", "formula": "$1.03×10^{3}kg/m^{3}$", "answer": "1.03 times 10 to the power of 3 kilograms over meters cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 82, "question": "Please read the following physics formula symbols: $x=−υt+\\frac{1}{2}at^{2}$", "audio_path": "audio/physics_acd99d36-9dd4-44a0-9dc9-72eb08a57312.wav", "formula": "$x=−υt+\\frac{1}{2}at^{2}$", "answer": "x equals negative upsilon t plus one half times a times t squared", "subset": "Physics700", "task_type": "tts"} +{"index": 83, "question": "Please read the following physics formula symbols: $IU=I^{2}R=U^{2}/R$", "audio_path": "audio/physics_60ed0aef-a699-4a32-b022-249669eae155.wav", "formula": "$IU=I^{2}R=U^{2}/R$", "answer": "I times U equals I squared times R equals U squared over R", "subset": "Physics700", "task_type": "tts"} +{"index": 84, "question": "请你朗读以下物理公式符号:$$1.0×10^{3}kg/m^{3}$$", "audio_path": "audio/physics_bcfe6ba6-4417-4132-afae-ad412ed0b9dc.wav", "formula": "$$1.0×10^{3}kg/m^{3}$$", "answer": "一点零乘十的三次方千克每立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 85, "question": "Please read the following physics formula symbols: $\\frac{\\left(M+m\\right)υ_{2}}{mυ_{1}}$", "audio_path": "audio/physics_c699f82d-19f1-4376-af32-bc5f64f7db3b.wav", "formula": "$\\frac{\\left(M+m\\right)υ_{2}}{mυ_{1}}$", "answer": "the sum of capital M and lowercase m times nu two over lowercase m times nu one", "subset": "Physics700", "task_type": "tts"} +{"index": 86, "question": "Please read the following physics formula symbols: $$p=\\frac{m}{V}$$", "audio_path": "audio/physics_45e261d1-7cb1-4dea-b7d7-25341c357446.wav", "formula": "$$p=\\frac{m}{V}$$", "answer": "p equals m over V", "subset": "Physics700", "task_type": "tts"} +{"index": 87, "question": "请你朗读以下物理公式符号:$\\frac{8v_{0}}{g}$", "audio_path": "audio/physics_4fe390c9-9b04-4b24-9244-becbe18dd079.wav", "formula": "$\\frac{8v_{0}}{g}$", "answer": "g 分之八乘v零", "subset": "Physics700", "task_type": "tts"} +{"index": 88, "question": "Please read the following physics formula symbols: $Q=\\frac{U^{2}}{R}t$", "audio_path": "audio/physics_03859732-3a8b-4db4-9f55-ff50efed6f73.wav", "formula": "$Q=\\frac{U^{2}}{R}t$", "answer": "Q equals U squared over R times t", "subset": "Physics700", "task_type": "tts"} +{"index": 89, "question": "Please read the following physics formula symbols: $1km/h=\\frac{1000m}{3600s}=\\frac{1}{3.6}m/s$", "audio_path": "audio/physics_0efe3182-7ca2-43f4-baad-78bd9401c0ef.wav", "formula": "$1km/h=\\frac{1000m}{3600s}=\\frac{1}{3.6}m/s$", "answer": "one kilometer per hour equals one thousand meters over three thousand six hundred seconds equals one over three point six meters per second", "subset": "Physics700", "task_type": "tts"} +{"index": 90, "question": "请你朗读以下物理公式符号:$2.5×10^{3}J/\\left(kg·℃\\right)$", "audio_path": "audio/physics_16539ca0-bbf3-4b90-885d-79712637c91b.wav", "formula": "$2.5×10^{3}J/\\left(kg·℃\\right)$", "answer": "二点五乘十的三次方焦耳每千克摄氏度", "subset": "Physics700", "task_type": "tts"} +{"index": 91, "question": "请你朗读以下物理公式符号:$$C=\\frac{Q}{U}$$", "audio_path": "audio/physics_9940b068-6735-468c-9dee-a03024ce42df.wav", "formula": "$$C=\\frac{Q}{U}$$", "answer": "C 等于 U 分之 Q", "subset": "Physics700", "task_type": "tts"} +{"index": 92, "question": "请你朗读以下物理公式符号:$$t=\\frac{W}{P}$$", "audio_path": "audio/physics_5726beee-7fdb-42c6-9eab-9ed731f43456.wav", "formula": "$$t=\\frac{W}{P}$$", "answer": "t 等于 P 分之 W", "subset": "Physics700", "task_type": "tts"} +{"index": 93, "question": "请你朗读以下物理公式符号:$$x=\\upsilon t+\\frac{1}{2}at^{2}$$", "audio_path": "audio/physics_402f91d0-1e73-4695-b283-7821c1088b5b.wav", "formula": "$$x=\\upsilon t+\\frac{1}{2}at^{2}$$", "answer": "x等于upsilon乘t加二分之一乘a乘t的平方", "subset": "Physics700", "task_type": "tts"} +{"index": 94, "question": "Please read the following physics formula symbols: $\\frac{gR^{2}}{G}$", "audio_path": "audio/physics_988cdd04-ba2e-417a-b021-7b39ef499666.wav", "formula": "$\\frac{gR^{2}}{G}$", "answer": "g times R squared over gravitational constant G", "subset": "Physics700", "task_type": "tts"} +{"index": 95, "question": "请你朗读以下物理公式符号:$1.2\\times10^{3} kg/m^{3}$", "audio_path": "audio/physics_12abda2e-c8f5-4fb2-8e5b-95c09cfc6e2e.wav", "formula": "$1.2\\times10^{3} kg/m^{3}$", "answer": "一点二乘十的三次方千克每立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 96, "question": "请你朗读以下物理公式符号:$x=−υt+\\frac{1}{2}at^{2}$", "audio_path": "audio/physics_cb924c7f-e4b2-447c-ab70-092eccdb72dc.wav", "formula": "$x=−υt+\\frac{1}{2}at^{2}$", "answer": "x等于负的upsilon乘t加二分之一乘a乘t的平方", "subset": "Physics700", "task_type": "tts"} +{"index": 97, "question": "Please read the following physics formula symbols: $\\frac{ρShg}{S}$", "audio_path": "audio/physics_c7a2551a-81df-4285-98cd-6f5269099e2f.wav", "formula": "$\\frac{ρShg}{S}$", "answer": "rho S h g over S", "subset": "Physics700", "task_type": "tts"} +{"index": 98, "question": "请你朗读以下物理公式符号:$$1.5×10^{3}m^{3}$$", "audio_path": "audio/physics_c8ef2963-5d86-4881-a98c-e6f7f68416f4.wav", "formula": "$$1.5×10^{3}m^{3}$$", "answer": "一点五乘十的三次方立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 99, "question": "请你朗读以下物理公式符号:$$\\frac{△υ}{△t}$$", "audio_path": "audio/physics_e3215785-5920-41d4-b545-b15acff5bbc9.wav", "formula": "$$\\frac{△υ}{△t}$$", "answer": "delta t 分之 delta v", "subset": "Physics700", "task_type": "tts"} +{"index": 100, "question": "Please read the following physics formula symbols: $$1.2×10^{3}kg/m^{3}$$", "audio_path": "audio/physics_d6635205-bffb-4739-b0c5-b402a9d280a2.wav", "formula": "$$1.2×10^{3}kg/m^{3}$$", "answer": "one point two times ten cubed kilograms over meters cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 101, "question": "Please read the following physics formula symbols: $$4.6×10^{7}J/kg$$", "audio_path": "audio/physics_59cb02ff-cbc8-4395-a205-18281e0d07d9.wav", "formula": "$$4.6×10^{7}J/kg$$", "answer": "four point six times ten to the power of seven joules over kilograms", "subset": "Physics700", "task_type": "tts"} +{"index": 102, "question": "请你朗读以下物理公式符号:$$\\frac{4kg}{5dm^{3}}$$", "audio_path": "audio/physics_6012ef88-c4d6-413d-92f8-cdecfcd37973.wav", "formula": "$$\\frac{4kg}{5dm^{3}}$$", "answer": "五立方分米分之四千克", "subset": "Physics700", "task_type": "tts"} +{"index": 103, "question": "Please read the following physics formula symbols: $\\frac{1}{1000}$", "audio_path": "audio/physics_e672b0f3-70eb-41cb-84b3-11e98944ca32.wav", "formula": "$\\frac{1}{1000}$", "answer": "one over one thousand", "subset": "Physics700", "task_type": "tts"} +{"index": 104, "question": "Please read the following physics formula symbols: $$1.1\\times 10^{3}kg/m^{3}$$", "audio_path": "audio/physics_2f5793f1-5080-47e3-946d-c44fe59f8693.wav", "formula": "$$1.1\\times 10^{3}kg/m^{3}$$", "answer": "one point one times ten cubed kilogram over meter cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 105, "question": "Please read the following physics formula symbols: $\\frac{8v_{0}}{g}$", "audio_path": "audio/physics_289ddba5-98da-41e5-a5f0-f97ceb161ebd.wav", "formula": "$\\frac{8v_{0}}{g}$", "answer": "eight v naught over g", "subset": "Physics700", "task_type": "tts"} +{"index": 106, "question": "请你朗读以下物理公式符号:$$t=\\frac{Q}{UI}$$", "audio_path": "audio/physics_2119c2b5-b376-4b56-b8bb-5458f37f4142.wav", "formula": "$$t=\\frac{Q}{UI}$$", "answer": "t等于U乘I的积分之Q", "subset": "Physics700", "task_type": "tts"} +{"index": 107, "question": "Please read the following physics formula symbols: $$x=5+2t^{3}\\left( m \\right)$$", "audio_path": "audio/physics_05530325-1dad-4441-9e1c-a4e3507d0fe4.wav", "formula": "$$x=5+2t^{3}\\left( m \\right)$$", "answer": "x equals five plus two t cubed times m", "subset": "Physics700", "task_type": "tts"} +{"index": 108, "question": "Please read the following physics formula symbols: $\\left(2\\right)$", "audio_path": "audio/physics_ddf9e629-5309-426e-8c95-c5696b994465.wav", "formula": "$\\left(2\\right)$", "answer": "two", "subset": "Physics700", "task_type": "tts"} +{"index": 109, "question": "请你朗读以下物理公式符号:$1.03×10^{3}kg/m^{3}$", "audio_path": "audio/physics_8c19f2d8-2a27-40e4-97a9-f276eed1654e.wav", "formula": "$1.03×10^{3}kg/m^{3}$", "answer": "一点零三乘十的三次方千克每立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 110, "question": "请你朗读以下物理公式符号:$\\frac{m\\upsilon_{2}}{M\\upsilon_{1}}$", "audio_path": "audio/physics_db57e771-01e8-4f00-b997-44df9f4f163f.wav", "formula": "$\\frac{m\\upsilon_{2}}{M\\upsilon_{1}}$", "answer": "M乘upsilon一的积分之m乘upsilon二", "subset": "Physics700", "task_type": "tts"} +{"index": 111, "question": "请你朗读以下物理公式符号:$$h_{1}、h_{2}、h_{3}$$", "audio_path": "audio/physics_a9fbd927-68a0-445b-8979-8db6f94bfc20.wav", "formula": "$$h_{1}、h_{2}、h_{3}$$", "answer": "h 一、h 二、h 三", "subset": "Physics700", "task_type": "tts"} +{"index": 112, "question": "请你朗读以下物理公式符号:$\\frac{π^{2}\\left(4R+ct\\right)^{3}}{2GT^{2}}$", "audio_path": "audio/physics_948507f5-67bb-4531-8698-8dc6a56a3834.wav", "formula": "$\\frac{π^{2}\\left(4R+ct\\right)^{3}}{2GT^{2}}$", "answer": "二乘G乘T的平方的积分之pi的平方乘四乘R加c乘t的和的立方", "subset": "Physics700", "task_type": "tts"} +{"index": 113, "question": "请你朗读以下物理公式符号:$\\frac{50}{323}$", "audio_path": "audio/physics_3309cdd3-7e12-4321-99e1-fa88f1af161a.wav", "formula": "$\\frac{50}{323}$", "answer": "三百二十三分之五十", "subset": "Physics700", "task_type": "tts"} +{"index": 114, "question": "请你朗读以下物理公式符号:$$10^{-2} m^{3}$$", "audio_path": "audio/physics_814fb57a-92d9-4c3b-bb19-4fa5730db9c4.wav", "formula": "$$10^{-2} m^{3}$$", "answer": "十的负二次方立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 115, "question": "请你朗读以下物理公式符号:$W=\\frac{U^{2}}{R}t$", "audio_path": "audio/physics_420ead43-2ab3-49d6-9f75-f2c69039fd79.wav", "formula": "$W=\\frac{U^{2}}{R}t$", "answer": "W 等于 R 分之 U 平方乘 t", "subset": "Physics700", "task_type": "tts"} +{"index": 116, "question": "请你朗读以下物理公式符号:$$\\frac{p_{1}V_{1}}{T_{1}}=\\frac{p_{2}V_{2}}{T_{2}}$$", "audio_path": "audio/physics_af756f22-d534-47f3-8bbd-eb05c5798dfe.wav", "formula": "$$\\frac{p_{1}V_{1}}{T_{1}}=\\frac{p_{2}V_{2}}{T_{2}}$$", "answer": "T 一分之p 一乘V 一等于T 二分之p 二乘V 二", "subset": "Physics700", "task_type": "tts"} +{"index": 117, "question": "请你朗读以下物理公式符号:$1.0×10^{3}kg/m^{3}$", "audio_path": "audio/physics_6310aa11-c401-47cc-be77-10c7586efd03.wav", "formula": "$1.0×10^{3}kg/m^{3}$", "answer": "一点零乘十的三次方千克每立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 118, "question": "请你朗读以下物理公式符号:$\\frac{2v_{0}}{g}$", "audio_path": "audio/physics_3a5b07fe-3d65-4501-a514-b7bc89f65ff2.wav", "formula": "$\\frac{2v_{0}}{g}$", "answer": "g 分之二乘 v 零", "subset": "Physics700", "task_type": "tts"} +{"index": 119, "question": "Please read the following physics formula symbols: $\\left(\\frac{md^{2}h^{2}}{n^{2}e^{3}}\\right)^{\\frac{1}{3}}$", "audio_path": "audio/physics_89e75a57-5882-4ad5-80be-3a537c62976c.wav", "formula": "$\\left(\\frac{md^{2}h^{2}}{n^{2}e^{3}}\\right)^{\\frac{1}{3}}$", "answer": "the quantity m times d squared times Planck's constant h squared over n squared times e cubed to the power of one third", "subset": "Physics700", "task_type": "tts"} +{"index": 120, "question": "Please read the following physics formula symbols: $$a=\\frac{Δv}{Δt}$$", "audio_path": "audio/physics_2bd4c30c-96a7-4eb8-a4b7-2f87768bf3b5.wav", "formula": "$$a=\\frac{Δv}{Δt}$$", "answer": "a equals delta v over delta t", "subset": "Physics700", "task_type": "tts"} +{"index": 121, "question": "Please read the following physics formula symbols: $0.8\\times 10^{3} \\, \\text{kg}/\\text{m}^{3}$", "audio_path": "audio/physics_90d754e3-a623-4f56-9c46-eb41472d8fad.wav", "formula": "$0.8\\times 10^{3} \\, \\text{kg}/\\text{m}^{3}$", "answer": "zero point eight times ten cubed kilograms per meter cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 122, "question": "Please read the following physics formula symbols: $$V=\\frac{m}{ρ}$", "audio_path": "audio/physics_efe38aa2-2fdc-4276-9e9e-c27a9b3f8f7e.wav", "formula": "$$V=\\frac{m}{ρ}$", "answer": "V equals m over rho", "subset": "Physics700", "task_type": "tts"} +{"index": 123, "question": "Please read the following physics formula symbols: $$8.7×10^{7}J/m^{3}$$", "audio_path": "audio/physics_e9c7db9b-c3a2-4117-a7cf-998367fe0e53.wav", "formula": "$$8.7×10^{7}J/m^{3}$$", "answer": "eight point seven times ten to the power of seven joules over meters cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 124, "question": "请你朗读以下物理公式符号:$$mgh=mv^{2}/2$$", "audio_path": "audio/physics_6bf9e1f0-c967-4d9f-8fed-6b08e5c4b3b3.wav", "formula": "$$mgh=mv^{2}/2$$", "answer": "m乘g乘h等于二分之m乘v的平方", "subset": "Physics700", "task_type": "tts"} +{"index": 125, "question": "请你朗读以下物理公式符号:$$\\overline{v}=\\frac{s}{t}$$", "audio_path": "audio/physics_67eb98f2-48f0-4d7f-8388-9ebb93f95363.wav", "formula": "$$\\overline{v}=\\frac{s}{t}$$", "answer": "v平均等于t分之s", "subset": "Physics700", "task_type": "tts"} +{"index": 126, "question": "请你朗读以下物理公式符号:$$h=\\frac{1}{2}gt^{2}$$", "audio_path": "audio/physics_b24fc61d-b337-4946-9cde-7a70c0e6578a.wav", "formula": "$$h=\\frac{1}{2}gt^{2}$$", "answer": "h等于二分之一乘g乘t的平方", "subset": "Physics700", "task_type": "tts"} +{"index": 127, "question": "请你朗读以下物理公式符号:$$p=FV_{m}=fV_{m}$$", "audio_path": "audio/physics_b4700d8b-38f4-43ca-b577-c78ad888d487.wav", "formula": "$$p=FV_{m}=fV_{m}$$", "answer": "p 等于 F 乘V m 等于 f 乘 V m", "subset": "Physics700", "task_type": "tts"} +{"index": 128, "question": "请你朗读以下物理公式符号:$$△t=\\frac{Q}{cm}$$", "audio_path": "audio/physics_95a84f44-e74d-4ee5-9d3d-b499774609ec.wav", "formula": "$$△t=\\frac{Q}{cm}$$", "answer": "delta t 等于c乘m的积分之Q", "subset": "Physics700", "task_type": "tts"} +{"index": 129, "question": "Please read the following physics formula symbols: $$\\frac{Gh}{η^{s}}+G$$", "audio_path": "audio/physics_d307d326-3c4e-4920-af24-d5c5b807793f.wav", "formula": "$$\\frac{Gh}{η^{s}}+G$$", "answer": "Gravitational constant G times Planck's constant h over eta to the power of s plus gravitational constant G", "subset": "Physics700", "task_type": "tts"} +{"index": 130, "question": "请你朗读以下物理公式符号:$η=\\frac{Gh}{\\left(F−f\\right)L}$", "audio_path": "audio/physics_17ba33fe-efa2-479e-a2ba-91b0f5b7a570.wav", "formula": "$η=\\frac{Gh}{\\left(F−f\\right)L}$", "answer": "eta等于F减f的差乘L的积分之G乘h", "subset": "Physics700", "task_type": "tts"} +{"index": 131, "question": "Please read the following physics formula symbols: $$t=\\frac{Q}{UI}$$", "audio_path": "audio/physics_e4cf29f3-28e4-4c3e-8c6f-459540225121.wav", "formula": "$$t=\\frac{Q}{UI}$$", "answer": "t equals Q over U times I", "subset": "Physics700", "task_type": "tts"} +{"index": 132, "question": "请你朗读以下物理公式符号:$W_{1}:W_{2}=1:3$", "audio_path": "audio/physics_9b9857bd-89ed-4e23-831b-099c8a315846.wav", "formula": "$W_{1}:W_{2}=1:3$", "answer": "W 一比W 二等于一比三", "subset": "Physics700", "task_type": "tts"} +{"index": 133, "question": "Please read the following physics formula symbols: $\\frac{1.2×10^{−2}}{0.1^{2}}$", "audio_path": "audio/physics_5e51c3fc-3233-4cb0-94f9-c81bee7283ae.wav", "formula": "$\\frac{1.2×10^{−2}}{0.1^{2}}$", "answer": "1.2 times 10 to the power of negative 2 over 0.1 squared", "subset": "Physics700", "task_type": "tts"} +{"index": 134, "question": "Please read the following physics formula symbols: $$λ=\\frac{c}{f}$$", "audio_path": "audio/physics_7e33c57c-f879-45d1-8e78-d6daed89c682.wav", "formula": "$$λ=\\frac{c}{f}$$", "answer": "lambda equals speed of light c over f", "subset": "Physics700", "task_type": "tts"} +{"index": 135, "question": "请你朗读以下物理公式符号:$$F=G\\frac{m_{1}m_{2}}{R^{2}}$$", "audio_path": "audio/physics_7e99c14b-a8b4-46d6-b51f-08d5ef3cc977.wav", "formula": "$$F=G\\frac{m_{1}m_{2}}{R^{2}}$$", "answer": "F等于G乘R的平方分之m一乘m二", "subset": "Physics700", "task_type": "tts"} +{"index": 136, "question": "请你朗读以下物理公式符号:$\\frac{E_{1}}{n^{2}}$", "audio_path": "audio/physics_3983ab4d-d496-430a-9b4c-390321dc10d3.wav", "formula": "$\\frac{E_{1}}{n^{2}}$", "answer": "n 的平方分之 E 一", "subset": "Physics700", "task_type": "tts"} +{"index": 137, "question": "Please read the following physics formula symbols: $4.2×10^{3}J/\\left(kg·℃\\right)$", "audio_path": "audio/physics_32ebe782-0b57-4c77-a6c8-5d9e7fd050ae.wav", "formula": "$4.2×10^{3}J/\\left(kg·℃\\right)$", "answer": "4.2 times 10 cubed joules over kilograms times degrees Celsius", "subset": "Physics700", "task_type": "tts"} +{"index": 138, "question": "Please read the following physics formula symbols: $c=3×10^{8}m/s$", "audio_path": "audio/physics_23ace2ee-df89-47ec-b8b4-c1bd1cefb1b0.wav", "formula": "$c=3×10^{8}m/s$", "answer": "speed of light c equals three times ten to the power of eight times m over s", "subset": "Physics700", "task_type": "tts"} +{"index": 139, "question": "Please read the following physics formula symbols: $$\\frac{△υ}{△t}$$", "audio_path": "audio/physics_b561cfa2-2f11-4680-b0a4-ef7d4a219dc4.wav", "formula": "$$\\frac{△υ}{△t}$$", "answer": "delta upsilon over delta t", "subset": "Physics700", "task_type": "tts"} +{"index": 140, "question": "Please read the following physics formula symbols: $\\frac{8H}{\\left(T_{2}−T_{1}\\right)^{2}}$", "audio_path": "audio/physics_0046a11d-3666-4886-8872-1a0fcdd545df.wav", "formula": "$\\frac{8H}{\\left(T_{2}−T_{1}\\right)^{2}}$", "answer": "eight H over the square of the difference between T two and T one", "subset": "Physics700", "task_type": "tts"} +{"index": 141, "question": "请你朗读以下物理公式符号:$$0.8×10^{3}kg/m^{3}$$", "audio_path": "audio/physics_fad4df67-e228-4125-9396-174c79a5c0b8.wav", "formula": "$$0.8×10^{3}kg/m^{3}$$", "answer": "零点八乘十的三次方千克每立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 142, "question": "请你朗读以下物理公式符号:$0.8\\times 10^{3} \\, \\text{kg}/\\text{m}^{3}$", "audio_path": "audio/physics_45bd966e-bda0-4867-b3b3-de6dbeb2adf6.wav", "formula": "$0.8\\times 10^{3} \\, \\text{kg}/\\text{m}^{3}$", "answer": "零点八乘十的三次方千克每立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 143, "question": "请你朗读以下物理公式符号:$$\\frac{1}{3.6}$$", "audio_path": "audio/physics_1a1d0b00-7538-4be3-a4a6-c2299b055266.wav", "formula": "$$\\frac{1}{3.6}$$", "answer": "三点六分之一", "subset": "Physics700", "task_type": "tts"} +{"index": 144, "question": "Please read the following physics formula symbols: $$1.5×10^{3}m^{3}$$", "audio_path": "audio/physics_30e52c31-99c0-4ef8-a298-e23bca11e607.wav", "formula": "$$1.5×10^{3}m^{3}$$", "answer": "1.5 times 10 cubed times m cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 145, "question": "Please read the following physics formula symbols: $η=\\frac{Gh}{fL}$", "audio_path": "audio/physics_31f3c6d5-807d-48a6-8d5d-639e26e7d8e8.wav", "formula": "$η=\\frac{Gh}{fL}$", "answer": "eta equals gravitational constant G times Planck's constant h over f times L", "subset": "Physics700", "task_type": "tts"} +{"index": 146, "question": "请你朗读以下物理公式符号:$$Q=\\frac{U^{2}}{R}t$$", "audio_path": "audio/physics_e5e0dd69-068e-494b-b9b4-b00e57f1d18e.wav", "formula": "$$Q=\\frac{U^{2}}{R}t$$", "answer": "Q等于R分之U平方乘t", "subset": "Physics700", "task_type": "tts"} +{"index": 147, "question": "请你朗读以下物理公式符号:$\\frac{1}{2}mυ_{n}^{2}$", "audio_path": "audio/physics_5e22a74e-0c84-474f-96e7-12130e0ee79f.wav", "formula": "$\\frac{1}{2}mυ_{n}^{2}$", "answer": "二分之一乘m乘upsilon n的平方", "subset": "Physics700", "task_type": "tts"} +{"index": 148, "question": "Please read the following physics formula symbols: $$\\frac{1}{1837}$$", "audio_path": "audio/physics_0a5174d3-3d7e-4b6a-9501-fbfe58ec0f22.wav", "formula": "$$\\frac{1}{1837}$$", "answer": "one over one thousand eight hundred thirty-seven", "subset": "Physics700", "task_type": "tts"} +{"index": 149, "question": "Please read the following physics formula symbols: $\\frac{U^{2}}{R}$", "audio_path": "audio/physics_d2e75d2f-6dbc-486a-929e-961d2735710d.wav", "formula": "$\\frac{U^{2}}{R}$", "answer": "U squared over R", "subset": "Physics700", "task_type": "tts"} +{"index": 150, "question": "请你朗读以下物理公式符号:$$R_{1}:R_{2}=3:1$$", "audio_path": "audio/physics_92b9d5a6-0428-43e7-b6dd-4746a72f6629.wav", "formula": "$$R_{1}:R_{2}=3:1$$", "answer": "R 一比 R 二等于三比一", "subset": "Physics700", "task_type": "tts"} +{"index": 151, "question": "请你朗读以下物理公式符号:$$\\frac{v_{0}+v_{1}}{2}$$", "audio_path": "audio/physics_0109b5b4-b3f5-45f6-8f92-a88ab84126b2.wav", "formula": "$$\\frac{v_{0}+v_{1}}{2}$$", "answer": "二分之v 零加v 一的和", "subset": "Physics700", "task_type": "tts"} +{"index": 152, "question": "Please read the following physics formula symbols: $$\\frac{π^{2}\\left(8R+ct\\right)^{3}}{2GT^{2}}$$", "audio_path": "audio/physics_e678b7aa-4822-4eaf-8ac3-5eed63efe04b.wav", "formula": "$$\\frac{π^{2}\\left(8R+ct\\right)^{3}}{2GT^{2}}$$", "answer": "pi squared times the cube of the sum of 8 R and c t over 2 times gravitational constant G times T squared", "subset": "Physics700", "task_type": "tts"} +{"index": 153, "question": "Please read the following physics formula symbols: $\\frac{8H}{T_{2}^{2}−T_{1}^{2}}$", "audio_path": "audio/physics_1717c27c-f094-4880-bcbc-f0be509464cb.wav", "formula": "$\\frac{8H}{T_{2}^{2}−T_{1}^{2}}$", "answer": "eight H over the difference between T two squared and T one squared", "subset": "Physics700", "task_type": "tts"} +{"index": 154, "question": "请你朗读以下物理公式符号:$$P=\\frac{F}{S}$$", "audio_path": "audio/physics_70c9b76a-455d-471b-b850-6390379b6cae.wav", "formula": "$$P=\\frac{F}{S}$$", "answer": "P等于S分之F", "subset": "Physics700", "task_type": "tts"} +{"index": 155, "question": "Please read the following physics formula symbols: $h=\\frac{v_{0}^{2}}{2g}$", "audio_path": "audio/physics_f9092c80-2306-4105-8606-5c8cfda07efe.wav", "formula": "$h=\\frac{v_{0}^{2}}{2g}$", "answer": "h equals v naught squared over two g", "subset": "Physics700", "task_type": "tts"} +{"index": 156, "question": "Please read the following physics formula symbols: $$0.8×10^{3}kg/m^{3}$$", "audio_path": "audio/physics_40266f2c-4b15-4541-ab35-d33da35d90df.wav", "formula": "$$0.8×10^{3}kg/m^{3}$$", "answer": "zero point eight times ten cubed kilograms per cubic meter", "subset": "Physics700", "task_type": "tts"} +{"index": 157, "question": "Please read the following physics formula symbols: $$x=\\upsilon t+\\frac{1}{2}at^{2}$$", "audio_path": "audio/physics_1106283a-a860-4f57-af6d-da6171108242.wav", "formula": "$$x=\\upsilon t+\\frac{1}{2}at^{2}$$", "answer": "x equals upsilon t plus one over two times a times t squared", "subset": "Physics700", "task_type": "tts"} +{"index": 158, "question": "请你朗读以下物理公式符号:$U_{1}^{'}:U_{2}^{'}$", "audio_path": "audio/physics_1e88eb91-8544-4ba5-9a40-f0ac6ca4b973.wav", "formula": "$U_{1}^{'}:U_{2}^{'}$", "answer": "U 一撇 比 U 二撇", "subset": "Physics700", "task_type": "tts"} +{"index": 159, "question": "请你朗读以下物理公式符号:$cm\\left(t−t_{0}\\right)$", "audio_path": "audio/physics_1329bffe-a2aa-49b9-9644-d93c387eb693.wav", "formula": "$cm\\left(t−t_{0}\\right)$", "answer": "c 乘 m 乘 t 减 t 零的差", "subset": "Physics700", "task_type": "tts"} +{"index": 160, "question": "请你朗读以下物理公式符号:$\\frac{d^{2}h^{2}}{2men^{2}}$", "audio_path": "audio/physics_c653031d-47ce-44ee-8612-ae7ccff83367.wav", "formula": "$\\frac{d^{2}h^{2}}{2men^{2}}$", "answer": "d平方乘h平方的积除以二乘m乘e乘n平方的积", "subset": "Physics700", "task_type": "tts"} +{"index": 161, "question": "Please read the following physics formula symbols: $E_{0}=4.5×10^{6}J$", "audio_path": "audio/physics_837a65b3-7621-4ab1-b41d-dddbe29e6321.wav", "formula": "$E_{0}=4.5×10^{6}J$", "answer": "E naught equals 4.5 times 10 to the power of 6 J", "subset": "Physics700", "task_type": "tts"} +{"index": 162, "question": "Please read the following physics formula symbols: $$1.75×10^{3} kg/m^{3}$$", "audio_path": "audio/physics_0e7d0c35-d7b1-433e-b431-8ec9fef3d575.wav", "formula": "$$1.75×10^{3} kg/m^{3}$$", "answer": "one point seven five times ten cubed kg over m cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 163, "question": "请你朗读以下物理公式符号:$$\\frac{kQ}{r^{2}}$$", "audio_path": "audio/physics_bd2f9804-8de8-46bb-8ea2-bb7d27d6d15a.wav", "formula": "$$\\frac{kQ}{r^{2}}$$", "answer": "r的平方分之k乘Q", "subset": "Physics700", "task_type": "tts"} +{"index": 164, "question": "Please read the following physics formula symbols: $$P=\\frac{F}{S}$$", "audio_path": "audio/physics_30390640-cb14-4e73-8f28-752d5b1916f0.wav", "formula": "$$P=\\frac{F}{S}$$", "answer": "P equals F over S", "subset": "Physics700", "task_type": "tts"} +{"index": 165, "question": "请你朗读以下物理公式符号:$η=\\frac{Gh}{FL}$", "audio_path": "audio/physics_a588378e-e12c-42bd-93e4-ff968ee0c276.wav", "formula": "$η=\\frac{Gh}{FL}$", "answer": "eta等于F乘L的积分之G乘h", "subset": "Physics700", "task_type": "tts"} +{"index": 166, "question": "请你朗读以下物理公式符号:$\\frac{θ_{1}}{θ_{2}}$", "audio_path": "audio/physics_4d8ac30a-4931-4210-a895-7efc20281c32.wav", "formula": "$\\frac{θ_{1}}{θ_{2}}$", "answer": "theta 二分之 theta 一", "subset": "Physics700", "task_type": "tts"} +{"index": 167, "question": "Please read the following physics formula symbols: $$1.1×10^{3} kg/m^{3}$$", "audio_path": "audio/physics_f2b75dc9-2013-49d2-b935-7e784f317a29.wav", "formula": "$$1.1×10^{3} kg/m^{3}$$", "answer": "one point one times ten to the power of three kilograms over meters cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 168, "question": "请你朗读以下物理公式符号:$$\\times \\frac{1}{100}$$", "audio_path": "audio/physics_033f8f8b-bac3-43e3-929f-3ae56023fb79.wav", "formula": "$$\\times \\frac{1}{100}$$", "answer": "乘一百分之一", "subset": "Physics700", "task_type": "tts"} +{"index": 169, "question": "请你朗读以下物理公式符号:$$E=h \\gamma=h\\frac{c}{\\lambda}$$", "audio_path": "audio/physics_693277d0-9cf0-402a-aba5-681011a7d009.wav", "formula": "$$E=h \\gamma=h\\frac{c}{\\lambda}$$", "answer": "E等于h乘gamma等于h乘lambda分之c", "subset": "Physics700", "task_type": "tts"} +{"index": 170, "question": "Please read the following physics formula symbols: $$10^{−2} m^{2}$$", "audio_path": "audio/physics_c9706927-38f3-45d9-96de-9aaf046334ce.wav", "formula": "$$10^{−2} m^{2}$$", "answer": "10 to the power of negative 2 m squared", "subset": "Physics700", "task_type": "tts"} +{"index": 171, "question": "请你朗读以下物理公式符号:$$η=\\frac{Gh}{Fnh}$$", "audio_path": "audio/physics_850e0a31-864b-4cbf-8e2a-ed73d5a38f60.wav", "formula": "$$η=\\frac{Gh}{Fnh}$$", "answer": "eta等于G乘h的积除以F乘n乘h的积", "subset": "Physics700", "task_type": "tts"} +{"index": 172, "question": "Please read the following physics formula symbols: $$=2.5\\mu m\\times 10^{-6}m$$", "audio_path": "audio/physics_63569f27-c04f-47c4-be07-b42e55cb1b2a.wav", "formula": "$$=2.5\\mu m\\times 10^{-6}m$$", "answer": "equals two point five mu m times ten to the power of negative six m", "subset": "Physics700", "task_type": "tts"} +{"index": 173, "question": "请你朗读以下物理公式符号:$\\frac{v_{1}−v_{2}}{t}$", "audio_path": "audio/physics_ac784b69-931d-4d5d-91b9-7c632aac2717.wav", "formula": "$\\frac{v_{1}−v_{2}}{t}$", "answer": "t 分之 v 一减 v 二的差", "subset": "Physics700", "task_type": "tts"} +{"index": 174, "question": "请你朗读以下物理公式符号:$\\frac{Q_{1}Q_{2}}{r^{2}}$", "audio_path": "audio/physics_011a8e76-4744-41d4-8f8b-fddc16b17ec8.wav", "formula": "$\\frac{Q_{1}Q_{2}}{r^{2}}$", "answer": "r的平方分之Q一乘Q二", "subset": "Physics700", "task_type": "tts"} +{"index": 175, "question": "请你朗读以下物理公式符号:$$10^{14} m^{2}$$", "audio_path": "audio/physics_3cb6e438-2297-44a7-aa9b-00e295c1570c.wav", "formula": "$$10^{14} m^{2}$$", "answer": "十的十四次方平方米", "subset": "Physics700", "task_type": "tts"} +{"index": 176, "question": "请你朗读以下物理公式符号:$7.5\\times10^{12}m^{3}$", "audio_path": "audio/physics_4db6ab2d-f47c-4960-88b6-8609acd44cfc.wav", "formula": "$7.5\\times10^{12}m^{3}$", "answer": "七点五乘十的十二次方立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 177, "question": "请你朗读以下物理公式符号:$$1km=10^{3}m=10^{4}dm=10^{5}cm=10^{6}mm=10^{9}μm=10^{12}nm$$", "audio_path": "audio/physics_c67b52ae-2366-4a6a-8c19-6d5c31d12408.wav", "formula": "$$1km=10^{3}m=10^{4}dm=10^{5}cm=10^{6}mm=10^{9}μm=10^{12}nm$$", "answer": "一千米等于十的三次方米等于十的四次方分米等于十的五次方厘米等于十的六次方毫米等于十的九次方微米等于十的十二次方纳米", "subset": "Physics700", "task_type": "tts"} +{"index": 178, "question": "Please read the following physics formula symbols: $\\left(g+\\frac{v^{2}}{R}\\right)$", "audio_path": "audio/physics_48bc415e-e7ff-44f5-8222-872ef716238e.wav", "formula": "$\\left(g+\\frac{v^{2}}{R}\\right)$", "answer": "the sum of g and v squared over R", "subset": "Physics700", "task_type": "tts"} +{"index": 179, "question": "Please read the following physics formula symbols: $m=\\frac{Q}{c\\left(t_{2}−t_{1}\\right)}$", "audio_path": "audio/physics_3f3749f5-09b3-4526-950e-7486d9c12567.wav", "formula": "$m=\\frac{Q}{c\\left(t_{2}−t_{1}\\right)}$", "answer": "m equals Q over c times the difference between t two and t one", "subset": "Physics700", "task_type": "tts"} +{"index": 180, "question": "Please read the following physics formula symbols: $$\\times \\frac{1}{100}$$", "audio_path": "audio/physics_8c684884-a3c9-440f-b9bf-762d42defcc4.wav", "formula": "$$\\times \\frac{1}{100}$$", "answer": "times one over one hundred", "subset": "Physics700", "task_type": "tts"} +{"index": 181, "question": "请你朗读以下物理公式符号:$$4×10^{−2}m^{3}$$", "audio_path": "audio/physics_7bb0f149-7edc-4044-b15f-95ec038787cc.wav", "formula": "$$4×10^{−2}m^{3}$$", "answer": "四乘十的负二次方立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 182, "question": "Please read the following physics formula symbols: $$Q=\\frac{U^{2}}{R}t$$", "audio_path": "audio/physics_cf2070f7-79cd-40b6-b865-944632db1a53.wav", "formula": "$$Q=\\frac{U^{2}}{R}t$$", "answer": "Q equals U squared over R times t", "subset": "Physics700", "task_type": "tts"} +{"index": 183, "question": "请你朗读以下物理公式符号:$\\frac{373}{323}$", "audio_path": "audio/physics_d58ea82e-8ecb-4613-9ca9-b320af9fb29d.wav", "formula": "$\\frac{373}{323}$", "answer": "三百二十三分之三百七十三", "subset": "Physics700", "task_type": "tts"} +{"index": 184, "question": "Please read the following physics formula symbols: $$ρ=\\frac{m}{V}$$", "audio_path": "audio/physics_9be2b947-08bf-4d84-a88f-366554ac4cd6.wav", "formula": "$$ρ=\\frac{m}{V}$$", "answer": "rho equals m over V", "subset": "Physics700", "task_type": "tts"} +{"index": 185, "question": "Please read the following physics formula symbols: $$ρ =\\frac{m}{V}$$", "audio_path": "audio/physics_f3a33549-7828-452a-919f-c7277e3182f6.wav", "formula": "$$ρ =\\frac{m}{V}$$", "answer": "rho equals m over V", "subset": "Physics700", "task_type": "tts"} +{"index": 186, "question": "Please read the following physics formula symbols: $$\\frac{100}{105}$$", "audio_path": "audio/physics_c70daeae-700a-46da-9c72-19f2add7acac.wav", "formula": "$$\\frac{100}{105}$$", "answer": "one hundred over one hundred five", "subset": "Physics700", "task_type": "tts"} +{"index": 187, "question": "请你朗读以下物理公式符号:$1km/h=\\frac{1000m}{3600s}=\\frac{1}{3.6}m/s$", "audio_path": "audio/physics_9cf8140f-40e9-4e03-a87f-78a5f47487b8.wav", "formula": "$1km/h=\\frac{1000m}{3600s}=\\frac{1}{3.6}m/s$", "answer": "一千米每小时等于三千六百秒分之一千米,等于三点六分之一米每秒", "subset": "Physics700", "task_type": "tts"} +{"index": 188, "question": "Please read the following physics formula symbols: $$1g/cm^{3}=10^{3}kg/m^{3}$$", "audio_path": "audio/physics_208c64fd-270e-47da-904a-e5b038864289.wav", "formula": "$$1g/cm^{3}=10^{3}kg/m^{3}$$", "answer": "1 gram per cubic centimeter equals 10 to the power of 3 kilograms per cubic meter", "subset": "Physics700", "task_type": "tts"} +{"index": 189, "question": "请你朗读以下物理公式符号:$υ^{2}−υ_{0}^{2}$", "audio_path": "audio/physics_b0e0c336-ddc1-4941-bb63-abbf953cb1d2.wav", "formula": "$υ^{2}−υ_{0}^{2}$", "answer": "v的平方减v零的平方", "subset": "Physics700", "task_type": "tts"} +{"index": 190, "question": "Please read the following physics formula symbols: $$P=\\frac{F}{S}$$", "audio_path": "audio/physics_35141af9-5250-48f2-b71e-3668415541d9.wav", "formula": "$$P=\\frac{F}{S}$$", "answer": "P equals F over S", "subset": "Physics700", "task_type": "tts"} +{"index": 191, "question": "Please read the following physics formula symbols: $$d=\\frac{1}{10}L$$", "audio_path": "audio/physics_7df25537-6352-4daa-8ccd-a8f3dc025854.wav", "formula": "$$d=\\frac{1}{10}L$$", "answer": "d equals one over ten times L", "subset": "Physics700", "task_type": "tts"} +{"index": 192, "question": "Please read the following physics formula symbols: $$a=\\frac{∆v}{∆t}$$", "audio_path": "audio/physics_57bfc551-20f1-47e8-8962-b9ba9b5e3376.wav", "formula": "$$a=\\frac{∆v}{∆t}$$", "answer": "a equals delta v over delta t", "subset": "Physics700", "task_type": "tts"} +{"index": 193, "question": "Please read the following physics formula symbols: $$\\frac{U^{2}}{P}$$", "audio_path": "audio/physics_83ec9968-f12c-40c8-ba81-db39d0760413.wav", "formula": "$$\\frac{U^{2}}{P}$$", "answer": "U squared over P", "subset": "Physics700", "task_type": "tts"} +{"index": 194, "question": "Please read the following physics formula symbols: $4.6\\times10^{7}J/kg$", "audio_path": "audio/physics_b8e76d6c-de47-4a4c-8625-9c1324825a01.wav", "formula": "$4.6\\times10^{7}J/kg$", "answer": "4.6 times ten to the power of seven joules per kilogram", "subset": "Physics700", "task_type": "tts"} +{"index": 195, "question": "请你朗读以下物理公式符号:$h=\\frac{v_{0}^{2}}{2g}$", "audio_path": "audio/physics_dc4cbb3c-357c-48d2-8fae-71befbc5834b.wav", "formula": "$h=\\frac{v_{0}^{2}}{2g}$", "answer": "h等于二乘g的积分之v零的平方", "subset": "Physics700", "task_type": "tts"} +{"index": 196, "question": "请你朗读以下物理公式符号:$\\frac{v_{1}−v_{0}}{2}$", "audio_path": "audio/physics_1a247b65-38e3-4a55-b5c4-743d12325b6d.wav", "formula": "$\\frac{v_{1}−v_{0}}{2}$", "answer": "二分之v 一减v 零的差", "subset": "Physics700", "task_type": "tts"} +{"index": 197, "question": "Please read the following physics formula symbols: $\\frac{W_{AB}}{q}$", "audio_path": "audio/physics_401969ad-72b5-4f3f-a508-9b19afb29f37.wav", "formula": "$\\frac{W_{AB}}{q}$", "answer": "W A B over q", "subset": "Physics700", "task_type": "tts"} +{"index": 198, "question": "Please read the following physics formula symbols: $$0.9×10^{3}kg/m^{3}$$", "audio_path": "audio/physics_651b6a28-dea3-4bcc-b281-4f09dcb30818.wav", "formula": "$$0.9×10^{3}kg/m^{3}$$", "answer": "zero point nine times ten cubed k g over m cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 199, "question": "Please read the following physics formula symbols: $$\\upsilon\\left(m \\cdot s^{-1}\\right)$$", "audio_path": "audio/physics_f13f6f31-b712-4314-b71f-6feb242beeef.wav", "formula": "$$\\upsilon\\left(m \\cdot s^{-1}\\right)$$", "answer": "upsilon over m times s to the power of negative one", "subset": "Physics700", "task_type": "tts"} +{"index": 200, "question": "Please read the following physics formula symbols: $$\\left\\{\\begin{array}{l}x+2y=k, \\\\ 2x+y=1\\end{array}\\right.$$", "audio_path": "audio/physics_576a1129-50c7-4c3e-a09a-a270898216c3.wav", "formula": "$$\\left\\{\\begin{array}{l}x+2y=k, \\\\ 2x+y=1\\end{array}\\right.$$", "answer": "a system of equations where x plus two y equals k and two x plus y equals one", "subset": "Physics700", "task_type": "tts"} +{"index": 201, "question": "Please read the following physics formula symbols: $\\frac{Q}{r^{2}}$", "audio_path": "audio/physics_f67f4660-ed7f-42ab-9d02-bd8a2503c7c2.wav", "formula": "$\\frac{Q}{r^{2}}$", "answer": "Q over r squared", "subset": "Physics700", "task_type": "tts"} +{"index": 202, "question": "Please read the following physics formula symbols: $\\frac{k}{T^{2}}$", "audio_path": "audio/physics_6824a752-858a-46d2-b034-55e705e0dee5.wav", "formula": "$\\frac{k}{T^{2}}$", "answer": "k over T squared", "subset": "Physics700", "task_type": "tts"} +{"index": 203, "question": "Please read the following physics formula symbols: $$P=P_{1}+P_{2}+P_{3}+\\cdots$$", "audio_path": "audio/physics_37e32781-99ee-4f49-b49c-1e5c8bbfb69a.wav", "formula": "$$P=P_{1}+P_{2}+P_{3}+\\cdots$$", "answer": "P equals P one plus P two plus P three and so on", "subset": "Physics700", "task_type": "tts"} +{"index": 204, "question": "请你朗读以下物理公式符号:$0.8×10^{3}kg/m^{3}$", "audio_path": "audio/physics_5cf67d71-d47d-4f8e-a2cf-23487a3ed525.wav", "formula": "$0.8×10^{3}kg/m^{3}$", "answer": "零点八乘十的三次方千克每立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 205, "question": "请你朗读以下物理公式符号:$E_{p1}< E_{p2}$", "audio_path": "audio/physics_077c3f98-77f2-4d18-8799-63a968e8806a.wav", "formula": "$E_{p1}< E_{p2}$", "answer": "E p 一小于 E p 二", "subset": "Physics700", "task_type": "tts"} +{"index": 206, "question": "Please read the following physics formula symbols: $q=4.6×10^{7}J/kg$", "audio_path": "audio/physics_38b06ebf-83d7-463b-b21c-4f4f31df10be.wav", "formula": "$q=4.6×10^{7}J/kg$", "answer": "q equals 4.6 times 10 to the power of 7 joules over kilograms", "subset": "Physics700", "task_type": "tts"} +{"index": 207, "question": "Please read the following physics formula symbols: $$I=\\frac{U}{R}$$", "audio_path": "audio/physics_eaed292c-5c9f-4b59-b76d-e66fbd8d1676.wav", "formula": "$$I=\\frac{U}{R}$$", "answer": "I equals U over R", "subset": "Physics700", "task_type": "tts"} +{"index": 208, "question": "请你朗读以下物理公式符号:$\\frac{1}{1000}$", "audio_path": "audio/physics_0513ba6f-7e69-4eca-ae92-30c85cc9d20f.wav", "formula": "$\\frac{1}{1000}$", "answer": "一千分之一", "subset": "Physics700", "task_type": "tts"} +{"index": 209, "question": "请你朗读以下物理公式符号:$$Q=W=\\frac{U^{2}}{R}t$$", "audio_path": "audio/physics_8dfd4692-b268-4c08-ac20-ef2bad0ba246.wav", "formula": "$$Q=W=\\frac{U^{2}}{R}t$$", "answer": "Q 等于 W 等于 R 分之 U平方乘 t", "subset": "Physics700", "task_type": "tts"} +{"index": 210, "question": "Please read the following physics formula symbols: $$F=\\frac{P}{v}$$", "audio_path": "audio/physics_1856f1ac-c5e8-4c5c-91b9-f373ea882941.wav", "formula": "$$F=\\frac{P}{v}$$", "answer": "F equals P over v", "subset": "Physics700", "task_type": "tts"} +{"index": 211, "question": "请你朗读以下物理公式符号:$$\\frac{U_{1}}{U_{2}}=\\frac{R_{1}}{R_{2}}$$", "audio_path": "audio/physics_fb4abae5-a8a5-4b7f-9e2b-e3c8eae2eb84.wav", "formula": "$$\\frac{U_{1}}{U_{2}}=\\frac{R_{1}}{R_{2}}$$", "answer": "U 二分之 U 一等于 R 二分之 R 一", "subset": "Physics700", "task_type": "tts"} +{"index": 212, "question": "请你朗读以下物理公式符号:$$\\frac{1}{1837}$$", "audio_path": "audio/physics_e681a2a2-e247-4fd3-9b4c-b8421b37749d.wav", "formula": "$$\\frac{1}{1837}$$", "answer": "一千八百三十七分之一", "subset": "Physics700", "task_type": "tts"} +{"index": 213, "question": "Please read the following physics formula symbols: $\\frac{373}{323}$", "audio_path": "audio/physics_03f0063b-9c92-4f5a-a5de-ec5afba37611.wav", "formula": "$\\frac{373}{323}$", "answer": "three hundred seventy-three over three hundred twenty-three", "subset": "Physics700", "task_type": "tts"} +{"index": 214, "question": "Please read the following physics formula symbols: $2.5×10^{3}J/\\left(kg·℃\\right)$", "audio_path": "audio/physics_678168f3-15de-4a20-844d-5c010e30abd0.wav", "formula": "$2.5×10^{3}J/\\left(kg·℃\\right)$", "answer": "two point five times ten to the power of three joules over kilogram times degree Celsius", "subset": "Physics700", "task_type": "tts"} +{"index": 215, "question": "Please read the following physics formula symbols: $t_{1}:t_{2}=3:4$", "audio_path": "audio/physics_8aa91b8f-e0a1-44ff-9c30-95cfea2e1e0b.wav", "formula": "$t_{1}:t_{2}=3:4$", "answer": "t one to t two equals three to four", "subset": "Physics700", "task_type": "tts"} +{"index": 216, "question": "Please read the following physics formula symbols: $1.2\\times10^{3} kg/m^{3}$", "audio_path": "audio/physics_e20b0184-2bfa-45fd-b3e0-b1f3263fd599.wav", "formula": "$1.2\\times10^{3} kg/m^{3}$", "answer": "1.2 times 10 cubed kg over m cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 217, "question": "请你朗读以下物理公式符号:$\\frac{49N}{80\\%}$", "audio_path": "audio/physics_4646b888-0e16-4fa2-890b-e617319a2a98.wav", "formula": "$\\frac{49N}{80\\%}$", "answer": "百分之八十分之四十九牛", "subset": "Physics700", "task_type": "tts"} +{"index": 218, "question": "请你朗读以下物理公式符号:$\\frac{4π^{2}mr}{T^{2}}$", "audio_path": "audio/physics_f6fcce85-d654-4d58-bf7d-b9df6662a02b.wav", "formula": "$\\frac{4π^{2}mr}{T^{2}}$", "answer": "T的平方分之四乘pi平方乘m乘r", "subset": "Physics700", "task_type": "tts"} +{"index": 219, "question": "Please read the following physics formula symbols: $$\\frac{υ^{2}}{r}$$", "audio_path": "audio/physics_cf89afbd-f62c-47d2-990b-91496f7a4a4d.wav", "formula": "$$\\frac{υ^{2}}{r}$$", "answer": "upsilon squared over r", "subset": "Physics700", "task_type": "tts"} +{"index": 220, "question": "请你朗读以下物理公式符号:$$F_{1}l_{1}=F_{2}l_{2}$$", "audio_path": "audio/physics_0f3f3eee-981e-4b70-83a4-dd8ef78b2e1c.wav", "formula": "$$F_{1}l_{1}=F_{2}l_{2}$$", "answer": "F 一 乘l 一等于F 二乘 l 二", "subset": "Physics700", "task_type": "tts"} +{"index": 221, "question": "Please read the following physics formula symbols: $$y=\\frac{1}{2}gt^{2}$$", "audio_path": "audio/physics_a56d1113-7f92-4119-af61-ee5dc0d0ec55.wav", "formula": "$$y=\\frac{1}{2}gt^{2}$$", "answer": "y equals one over two times g times t squared", "subset": "Physics700", "task_type": "tts"} +{"index": 222, "question": "请你朗读以下物理公式符号:$$\\frac{△Φ}{△t}$$", "audio_path": "audio/physics_2dd59134-f6ed-4b08-8502-ad3d994a75ea.wav", "formula": "$$\\frac{△Φ}{△t}$$", "answer": "delta t 分之delta phi", "subset": "Physics700", "task_type": "tts"} +{"index": 223, "question": "请你朗读以下物理公式符号:$\\frac{v_{2}−v_{1}}{t}$", "audio_path": "audio/physics_e4fdc38b-ab57-40da-afd3-ca5e65f8e58f.wav", "formula": "$\\frac{v_{2}−v_{1}}{t}$", "answer": "t 分之 v 二减 v 一的差", "subset": "Physics700", "task_type": "tts"} +{"index": 224, "question": "请你朗读以下物理公式符号:$$\\frac{1}{100}$$", "audio_path": "audio/physics_72216b84-5159-45b1-b180-c127dc27d126.wav", "formula": "$$\\frac{1}{100}$$", "answer": "一百分之一", "subset": "Physics700", "task_type": "tts"} +{"index": 225, "question": "Please read the following physics formula symbols: $$h_{1}、h_{2}、h_{3}$$", "audio_path": "audio/physics_3b2b75ad-0ff9-4af9-a63d-f138387fd048.wav", "formula": "$$h_{1}、h_{2}、h_{3}$$", "answer": "h one, h two, h three", "subset": "Physics700", "task_type": "tts"} +{"index": 226, "question": "请你朗读以下物理公式符号:$\\frac{3gt^{2}}{8}$", "audio_path": "audio/physics_3ddfa451-c078-466f-ac34-5b970d26b0dc.wav", "formula": "$\\frac{3gt^{2}}{8}$", "answer": "八分之三乘g乘t的平方", "subset": "Physics700", "task_type": "tts"} +{"index": 227, "question": "Please read the following physics formula symbols: $$1kw·h=3.6×10^{6}J$$", "audio_path": "audio/physics_81b02eff-05fd-40be-94ce-b167711c2f05.wav", "formula": "$$1kw·h=3.6×10^{6}J$$", "answer": "1 times k times w times h equals 3.6 times 10 to the power of 6 times J", "subset": "Physics700", "task_type": "tts"} +{"index": 228, "question": "Please read the following physics formula symbols: $$0.8×10^{3}kg/m^{3}$$", "audio_path": "audio/physics_fee134f4-8921-4e1c-8d86-cf22a5cb5bb4.wav", "formula": "$$0.8×10^{3}kg/m^{3}$$", "answer": "zero point eight times ten cubed kilograms over meters cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 229, "question": "请你朗读以下物理公式符号:$1.16 \\times 10^{3} \\,\\mathrm{kg/m^{3}}$", "audio_path": "audio/physics_fcea5816-188f-460b-bade-03314dd5b8d1.wav", "formula": "$1.16 \\times 10^{3} \\,\\mathrm{kg/m^{3}}$", "answer": "一点一六乘十的三次方千克每立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 230, "question": "Please read the following physics formula symbols: $\\frac{v_{1}−v_{0}}{t}$", "audio_path": "audio/physics_81e29da8-6c33-447f-a107-d0b44d26cdf0.wav", "formula": "$\\frac{v_{1}−v_{0}}{t}$", "answer": "the difference between v one and v naught over t", "subset": "Physics700", "task_type": "tts"} +{"index": 231, "question": "请你朗读以下物理公式符号:$$10^{3}kg/m^{3}$$", "audio_path": "audio/physics_fb6ba662-446f-4dcc-bd4f-4c475cc9ab4b.wav", "formula": "$$10^{3}kg/m^{3}$$", "answer": "十的三次方千克每立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 232, "question": "Please read the following physics formula symbols: $$\\frac{∆v}{∆t}$$", "audio_path": "audio/physics_7623e6ef-e5ce-4b5c-876b-98fa1c2a11f1.wav", "formula": "$$\\frac{∆v}{∆t}$$", "answer": "delta v over delta t", "subset": "Physics700", "task_type": "tts"} +{"index": 233, "question": "请你朗读以下物理公式符号:$\\frac{3}{4}E_{1}$", "audio_path": "audio/physics_3247a080-ed6c-4193-a36b-1c3dd5b65aac.wav", "formula": "$\\frac{3}{4}E_{1}$", "answer": "四分之三乘E一", "subset": "Physics700", "task_type": "tts"} +{"index": 234, "question": "Please read the following physics formula symbols: $\\frac{U^{2}}{P}$", "audio_path": "audio/physics_63e9576f-f131-4bde-9961-93dd5512b3b5.wav", "formula": "$\\frac{U^{2}}{P}$", "answer": "U squared over P", "subset": "Physics700", "task_type": "tts"} +{"index": 235, "question": "请你朗读以下物理公式符号:$$Q=I^{2}Rt, P=UI$$", "audio_path": "audio/physics_c6eb296b-5e42-4579-b989-8ec3489a7f08.wav", "formula": "$$Q=I^{2}Rt, P=UI$$", "answer": "Q等于I的平方乘R乘t,P等于U乘I", "subset": "Physics700", "task_type": "tts"} +{"index": 236, "question": "请你朗读以下物理公式符号:$3.4×10^{7}J/kg$", "audio_path": "audio/physics_7a8ecf4d-a20e-4455-8984-92595e9d3dd3.wav", "formula": "$3.4×10^{7}J/kg$", "answer": "三点四乘十的七次方焦耳每千克", "subset": "Physics700", "task_type": "tts"} +{"index": 237, "question": "请你朗读以下物理公式符号:$$U=\\frac{W_{AB}}{q}$$", "audio_path": "audio/physics_34c3779a-0c9a-4149-825a-39285f86c9a8.wav", "formula": "$$U=\\frac{W_{AB}}{q}$$", "answer": "U等于q分之W AB", "subset": "Physics700", "task_type": "tts"} +{"index": 238, "question": "请你朗读以下物理公式符号:$\\frac{Gh}{\\eta^{s}} - G$", "audio_path": "audio/physics_d5974495-24e6-4a77-8547-9af8f3b38a56.wav", "formula": "$\\frac{Gh}{\\eta^{s}} - G$", "answer": "eta的s次方分之G乘h减G", "subset": "Physics700", "task_type": "tts"} +{"index": 239, "question": "请你朗读以下物理公式符号:$$R_{1}:R_{2}=3:4$$", "audio_path": "audio/physics_45fc82c6-bede-482f-b3e4-670fb950ce40.wav", "formula": "$$R_{1}:R_{2}=3:4$$", "answer": "R 一比 R 二等于三比四", "subset": "Physics700", "task_type": "tts"} +{"index": 240, "question": "Please read the following physics formula symbols: $$W=\\frac{U^{2}}{R}t$$", "audio_path": "audio/physics_21109849-d2f3-47bb-adb3-4d34f64e76eb.wav", "formula": "$$W=\\frac{U^{2}}{R}t$$", "answer": "W equals U squared over R times t", "subset": "Physics700", "task_type": "tts"} +{"index": 241, "question": "Please read the following physics formula symbols: $\\frac{Gh}{\\eta^{s}} - G$", "audio_path": "audio/physics_bc201cfb-7933-47c2-93f3-f0de8a680e2e.wav", "formula": "$\\frac{Gh}{\\eta^{s}} - G$", "answer": "G times h over eta to the power of s minus gravitational constant G", "subset": "Physics700", "task_type": "tts"} +{"index": 242, "question": "Please read the following physics formula symbols: $\\frac{\\sin θ_{1}}{\\sin θ_{2}}$", "audio_path": "audio/physics_b3725cfa-af40-4dd8-8f82-e6015fe0076a.wav", "formula": "$\\frac{\\sin θ_{1}}{\\sin θ_{2}}$", "answer": "sine theta one over sine theta two", "subset": "Physics700", "task_type": "tts"} +{"index": 243, "question": "请你朗读以下物理公式符号:$$x_{1}=5\\sin \\left(8\\pi t+\\frac{\\pi}{4}\\right)\\,\\text{cm}$$", "audio_path": "audio/physics_b56c7762-4dc0-450a-b45d-043d2274b9dc.wav", "formula": "$$x_{1}=5\\sin \\left(8\\pi t+\\frac{\\pi}{4}\\right)\\,\\text{cm}$$", "answer": "x 一等于五乘sine 括号 八乘pi乘t 加 四分之pi 括号 厘米", "subset": "Physics700", "task_type": "tts"} +{"index": 244, "question": "Please read the following physics formula symbols: $$x=\\frac{m}{v}$$", "audio_path": "audio/physics_ff1c7559-1a0e-4571-b26b-1569192fa71c.wav", "formula": "$$x=\\frac{m}{v}$$", "answer": "x equals m over v", "subset": "Physics700", "task_type": "tts"} +{"index": 245, "question": "请你朗读以下物理公式符号:$$y=\\frac{1}{2}gt^{2}$$", "audio_path": "audio/physics_892fe6be-8286-424a-abc4-8b39e1a23ab2.wav", "formula": "$$y=\\frac{1}{2}gt^{2}$$", "answer": "y等于二分之一乘g乘t的平方", "subset": "Physics700", "task_type": "tts"} +{"index": 246, "question": "请你朗读以下物理公式符号:$x=υt−\\frac{1}{2}at^{2}$", "audio_path": "audio/physics_043d4167-49b4-4b87-83b3-52ec9d53c5f0.wav", "formula": "$x=υt−\\frac{1}{2}at^{2}$", "answer": "x等于upsilon乘t减二分之一乘a乘t的平方", "subset": "Physics700", "task_type": "tts"} +{"index": 247, "question": "Please read the following physics formula symbols: $η=\\frac{Gh}{FL}$", "audio_path": "audio/physics_a4bfba1d-0f7a-4b8c-9987-09dac8b0372b.wav", "formula": "$η=\\frac{Gh}{FL}$", "answer": "eta equals gravitational constant G times Planck's constant h over F times L", "subset": "Physics700", "task_type": "tts"} +{"index": 248, "question": "请你朗读以下物理公式符号:$$c=3×10^{8} m/s$$", "audio_path": "audio/physics_971f3deb-2c96-43c2-aa3e-633e8dbb3436.wav", "formula": "$$c=3×10^{8} m/s$$", "answer": "c等于三乘十的八次方米每秒", "subset": "Physics700", "task_type": "tts"} +{"index": 249, "question": "请你朗读以下物理公式符号:$\\frac{ρShg}{S}$", "audio_path": "audio/physics_16384a85-937d-471f-8048-b1312ed6ee21.wav", "formula": "$\\frac{ρShg}{S}$", "answer": "S分之rho乘S乘h乘g", "subset": "Physics700", "task_type": "tts"} +{"index": 250, "question": "请你朗读以下物理公式符号:$\\frac{3}{4}T < t < T$", "audio_path": "audio/physics_7dfcaaa1-ffac-46cf-82b5-033174aa19d6.wav", "formula": "$\\frac{3}{4}T < t < T$", "answer": "t大于四分之三倍的T小于T", "subset": "Physics700", "task_type": "tts"} +{"index": 251, "question": "Please read the following physics formula symbols: $$4.2×10^{7}J/kg$$", "audio_path": "audio/physics_c5cc59be-421c-4aea-8351-bd3833d10539.wav", "formula": "$$4.2×10^{7}J/kg$$", "answer": "four point two times ten to the power of seven joules over kilograms", "subset": "Physics700", "task_type": "tts"} +{"index": 252, "question": "Please read the following physics formula symbols: $E_{p1}< E_{p2}$", "audio_path": "audio/physics_20422635-de14-4a3e-9283-9d99a9b2a8e5.wav", "formula": "$E_{p1}< E_{p2}$", "answer": "E p one is less than E p two", "subset": "Physics700", "task_type": "tts"} +{"index": 253, "question": "请你朗读以下物理公式符号:$$\\overline{v}=\\frac{x}{t}$$", "audio_path": "audio/physics_95fc2bf4-2a27-417e-8535-37519e9b7dbe.wav", "formula": "$$\\overline{v}=\\frac{x}{t}$$", "answer": "平均v等于t分之x", "subset": "Physics700", "task_type": "tts"} +{"index": 254, "question": "请你朗读以下物理公式符号:$\\frac{m\\upsilon^{4}}{GN}$", "audio_path": "audio/physics_97fb323a-1709-4c20-8820-40ab639ba539.wav", "formula": "$\\frac{m\\upsilon^{4}}{GN}$", "answer": "G乘N的积分之m乘v的四次方", "subset": "Physics700", "task_type": "tts"} +{"index": 255, "question": "请你朗读以下物理公式符号:$$\\left\\{\\begin{array}{l}x+2y=k, \\\\ 2x+y=1\\end{array}\\right.$$", "audio_path": "audio/physics_adef2e50-16c6-44c3-9ece-01f5a28ba4fa.wav", "formula": "$$\\left\\{\\begin{array}{l}x+2y=k, \\\\ 2x+y=1\\end{array}\\right.$$", "answer": "x 加二 y 等于 k 和 二 x 加 y 等于一", "subset": "Physics700", "task_type": "tts"} +{"index": 256, "question": "Please read the following physics formula symbols: $$1.03×10^{3}kg∕m^{3}$$", "audio_path": "audio/physics_95815c5d-d8fb-431d-b71f-9cf1b3ce4805.wav", "formula": "$$1.03×10^{3}kg∕m^{3}$$", "answer": "one point zero three times ten cubed kilograms over meters cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 257, "question": "请你朗读以下物理公式符号:$\\left(g+\\frac{v^{2}}{R}\\right)$", "audio_path": "audio/physics_ff1138f3-c2b1-402b-a365-1d6d4ce3094d.wav", "formula": "$\\left(g+\\frac{v^{2}}{R}\\right)$", "answer": "g 加 R 分之 v 平方", "subset": "Physics700", "task_type": "tts"} +{"index": 258, "question": "请你朗读以下物理公式符号:$$I=\\frac{q}{t}$$", "audio_path": "audio/physics_d5a1164d-9350-473f-bfda-0dd89105666e.wav", "formula": "$$I=\\frac{q}{t}$$", "answer": "I 等于 t 分之 q", "subset": "Physics700", "task_type": "tts"} +{"index": 259, "question": "Please read the following physics formula symbols: $$4×10^{−2}m^{3}$$", "audio_path": "audio/physics_a80c2ca7-402d-4942-9890-08e746a89ad3.wav", "formula": "$$4×10^{−2}m^{3}$$", "answer": "four times ten to the power of negative two times m cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 260, "question": "Please read the following physics formula symbols: $t_{1}, t_{2}, t_{3}$", "audio_path": "audio/physics_cd45764d-5851-4e78-a24b-6d375cedfe34.wav", "formula": "$t_{1}, t_{2}, t_{3}$", "answer": "t one, t two, t three", "subset": "Physics700", "task_type": "tts"} +{"index": 261, "question": "Please read the following physics formula symbols: $\\frac{θ_{1}}{θ_{2}}$", "audio_path": "audio/physics_aec9aeb3-b02e-4df0-8691-dc05aca4b3a2.wav", "formula": "$\\frac{θ_{1}}{θ_{2}}$", "answer": "theta one over theta two", "subset": "Physics700", "task_type": "tts"} +{"index": 262, "question": "请你朗读以下物理公式符号:$$R=\\frac{U^{2}}{P}$$", "audio_path": "audio/physics_57a8bcff-5259-48ce-b5f0-898e3304bc55.wav", "formula": "$$R=\\frac{U^{2}}{P}$$", "answer": "R 等于 P 分之 U 平方", "subset": "Physics700", "task_type": "tts"} +{"index": 263, "question": "Please read the following physics formula symbols: $$ρ=\\frac{m}{v}$$", "audio_path": "audio/physics_2d180958-e811-4813-9342-e89a489defb8.wav", "formula": "$$ρ=\\frac{m}{v}$$", "answer": "rho equals m over v", "subset": "Physics700", "task_type": "tts"} +{"index": 264, "question": "请你朗读以下物理公式符号:$1.6 \\times 10^{8} \\mathrm{J/kg}$", "audio_path": "audio/physics_e5a92b5d-753d-4477-b6ca-cbf6165683b9.wav", "formula": "$1.6 \\times 10^{8} \\mathrm{J/kg}$", "answer": "一点六乘十的八次方焦耳每千克", "subset": "Physics700", "task_type": "tts"} +{"index": 265, "question": "Please read the following physics formula symbols: $2S=S_{1}+S_{2}$", "audio_path": "audio/physics_f744db68-03d2-41bb-87ad-5ad0f5636f2e.wav", "formula": "$2S=S_{1}+S_{2}$", "answer": "Two S equals S one plus S two.", "subset": "Physics700", "task_type": "tts"} +{"index": 266, "question": "请你朗读以下物理公式符号:$$R=\\frac{U}{I}$$", "audio_path": "audio/physics_c2496b41-9458-4d91-ad06-5ca138b01847.wav", "formula": "$$R=\\frac{U}{I}$$", "answer": "R 等于 I 分之 U", "subset": "Physics700", "task_type": "tts"} +{"index": 267, "question": "请你朗读以下物理公式符号:$7.5\\times 10^{7} \\mathrm{J}/\\mathrm{m}^{3}$", "audio_path": "audio/physics_6e112edd-7981-4b74-bec8-7d73ca63d087.wav", "formula": "$7.5\\times 10^{7} \\mathrm{J}/\\mathrm{m}^{3}$", "answer": "七点五乘十的七次方焦耳每立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 268, "question": "请你朗读以下物理公式符号:$ρ=2.7×10^{3}kg/m^{3}$", "audio_path": "audio/physics_58472f69-d819-48a6-a427-55c5c5a55364.wav", "formula": "$ρ=2.7×10^{3}kg/m^{3}$", "answer": "rho等于二点七乘十的三次方千克每立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 269, "question": "Please read the following physics formula symbols: $1.0×10^{3} kg/m^{3}$", "audio_path": "audio/physics_a797f8a3-1321-403c-8311-a88ed87215e0.wav", "formula": "$1.0×10^{3} kg/m^{3}$", "answer": "one point zero times ten cubed kilogram over meter cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 270, "question": "请你朗读以下物理公式符号:$$R_{1}:R_{2}=3:4$$", "audio_path": "audio/physics_7f567741-e721-4148-bf05-adcbfdada268.wav", "formula": "$$R_{1}:R_{2}=3:4$$", "answer": "R 一比R 二等于三比四", "subset": "Physics700", "task_type": "tts"} +{"index": 271, "question": "Please read the following physics formula symbols: $$R=\\frac{U^{2}}{P}$$", "audio_path": "audio/physics_46b44983-98a1-4beb-ac4a-1e2c32e9c9c7.wav", "formula": "$$R=\\frac{U^{2}}{P}$$", "answer": "R equals U squared over P", "subset": "Physics700", "task_type": "tts"} +{"index": 272, "question": "Please read the following physics formula symbols: $$R_{1}:R_{2}=3:5$$", "audio_path": "audio/physics_8f4110fd-4f03-4d4e-955d-6e66e7af2b30.wav", "formula": "$$R_{1}:R_{2}=3:5$$", "answer": "R one to R two equals three to five", "subset": "Physics700", "task_type": "tts"} +{"index": 273, "question": "请你朗读以下物理公式符号:$$ρ =\\frac{m}{V}$$", "audio_path": "audio/physics_d704134e-227d-4128-a7b3-e5ac2f38d60d.wav", "formula": "$$ρ =\\frac{m}{V}$$", "answer": "rho等于 V 分之 m", "subset": "Physics700", "task_type": "tts"} +{"index": 274, "question": "Please read the following physics formula symbols: $$\\frac{1.2}{0.1^{2}}$$", "audio_path": "audio/physics_338da313-b142-4fed-b6e5-b55562939a11.wav", "formula": "$$\\frac{1.2}{0.1^{2}}$$", "answer": "one point two over zero point one squared", "subset": "Physics700", "task_type": "tts"} +{"index": 275, "question": "Please read the following physics formula symbols: $$\\frac{U_{1}}{U_{2}}=\\frac{R_{1}}{R_{2}}$$", "audio_path": "audio/physics_173c3971-19bf-42b0-af18-bd9629a8c954.wav", "formula": "$$\\frac{U_{1}}{U_{2}}=\\frac{R_{1}}{R_{2}}$$", "answer": "U one over U two equals R one over R two", "subset": "Physics700", "task_type": "tts"} +{"index": 276, "question": "请你朗读以下物理公式符号:$$1:\\left(\\sqrt{2}+1\\right)$$", "audio_path": "audio/physics_8bb2febd-f8ab-4864-89db-e4ecf525a88c.wav", "formula": "$$1:\\left(\\sqrt{2}+1\\right)$$", "answer": "一比根号二加一的和", "subset": "Physics700", "task_type": "tts"} +{"index": 277, "question": "请你朗读以下物理公式符号:$\\frac{π^{2}\\left(2R+ct\\right)^{3}}{2GT^{2}}$", "audio_path": "audio/physics_f08a7496-788b-40e3-97f2-ba4d63fbac01.wav", "formula": "$\\frac{π^{2}\\left(2R+ct\\right)^{3}}{2GT^{2}}$", "answer": "二乘G乘T的平方的积分之pi的平方乘二乘R加c乘t的和的立方", "subset": "Physics700", "task_type": "tts"} +{"index": 278, "question": "请你朗读以下物理公式符号:$$B=\\frac{F}{IL}$$", "audio_path": "audio/physics_ab3d6f19-6428-4c40-a945-acee32c3aaa4.wav", "formula": "$$B=\\frac{F}{IL}$$", "answer": "B等于I乘L的积分之F", "subset": "Physics700", "task_type": "tts"} +{"index": 279, "question": "请你朗读以下物理公式符号:$$\\frac{U^{2}}{P}=12Ω$$", "audio_path": "audio/physics_9ceeb29e-cb1b-481b-a663-4bdfd4ae8746.wav", "formula": "$$\\frac{U^{2}}{P}=12Ω$$", "answer": "P分之U平方等于十二欧姆", "subset": "Physics700", "task_type": "tts"} +{"index": 280, "question": "请你朗读以下物理公式符号:$\\frac{4\\pi^{2}\\left(R+ct\\right)^{3}}{GT^{2}}$", "audio_path": "audio/physics_0dc27735-c01d-4c15-ad97-602665596a3e.wav", "formula": "$\\frac{4\\pi^{2}\\left(R+ct\\right)^{3}}{GT^{2}}$", "answer": "G乘T的平方的积分之四乘pi的平方乘R加c乘t的和的立方", "subset": "Physics700", "task_type": "tts"} +{"index": 281, "question": "请你朗读以下物理公式符号:$$\\frac{W}{t}=\\frac{FS}{t}$$", "audio_path": "audio/physics_197e2298-c1fb-4a2e-b318-91371792ebea.wav", "formula": "$$\\frac{W}{t}=\\frac{FS}{t}$$", "answer": "t 分之 W 等于 t 分之 F 乘 S", "subset": "Physics700", "task_type": "tts"} +{"index": 282, "question": "Please read the following physics formula symbols: $$10^{3}kg/m^{3}$$", "audio_path": "audio/physics_f8182abb-3507-4b19-921b-16a2272e320e.wav", "formula": "$$10^{3}kg/m^{3}$$", "answer": "10 cubed kilograms over meters cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 283, "question": "请你朗读以下物理公式符号:$$1.0×10^{6}m/s$$", "audio_path": "audio/physics_54c0be12-b317-4c2c-8200-1048c91297ea.wav", "formula": "$$1.0×10^{6}m/s$$", "answer": "一点零乘十的六次方米每秒", "subset": "Physics700", "task_type": "tts"} +{"index": 284, "question": "Please read the following physics formula symbols: $$\\frac{a^{3}}{T^{2}}=k$$", "audio_path": "audio/physics_65e9a325-82ac-4e91-99b1-a2b2410eeea9.wav", "formula": "$$\\frac{a^{3}}{T^{2}}=k$$", "answer": "a cubed over T squared equals k", "subset": "Physics700", "task_type": "tts"} +{"index": 285, "question": "Please read the following physics formula symbols: $$F_{1}L_{1}=F_{2}L_{2}$$", "audio_path": "audio/physics_4cab7c7b-9b24-4711-be41-34abc5355e92.wav", "formula": "$$F_{1}L_{1}=F_{2}L_{2}$$", "answer": "F one times L one equals F two times L two", "subset": "Physics700", "task_type": "tts"} +{"index": 286, "question": "请你朗读以下物理公式符号:$$∆x=\\frac{L}{d}λ$$", "audio_path": "audio/physics_79b02617-dac3-411a-b372-1710ee49d451.wav", "formula": "$$∆x=\\frac{L}{d}λ$$", "answer": "delta x 等于d分之L乘lambda", "subset": "Physics700", "task_type": "tts"} +{"index": 287, "question": "Please read the following physics formula symbols: $$3.84 \\times 10^{5}~\\mathrm{km}$$", "audio_path": "audio/physics_ff49dd40-3b64-4921-9c7d-4b4c78a90ddd.wav", "formula": "$$3.84 \\times 10^{5}~\\mathrm{km}$$", "answer": "three point eight four times ten to the power of five kilometers", "subset": "Physics700", "task_type": "tts"} +{"index": 288, "question": "请你朗读以下物理公式符号:$$\\frac{△v}{△t}$$", "audio_path": "audio/physics_a4ea120b-ce89-4a44-9b17-4f28431c06b7.wav", "formula": "$$\\frac{△v}{△t}$$", "answer": "delta t 分之 delta v", "subset": "Physics700", "task_type": "tts"} +{"index": 289, "question": "请你朗读以下物理公式符号:$$\\upsilon\\left(m \\cdot s^{-1}\\right)$$", "audio_path": "audio/physics_19f1d0d1-137f-4019-9315-bb79e2a5e078.wav", "formula": "$$\\upsilon\\left(m \\cdot s^{-1}\\right)$$", "answer": "upsilon 米每秒", "subset": "Physics700", "task_type": "tts"} +{"index": 290, "question": "Please read the following physics formula symbols: $$U_{AB}=\\frac{W_{AB}}{q}$$", "audio_path": "audio/physics_bebc4b38-d5cd-4039-84c7-d1873bf0d54c.wav", "formula": "$$U_{AB}=\\frac{W_{AB}}{q}$$", "answer": "U sub A B equals W sub A B over q", "subset": "Physics700", "task_type": "tts"} +{"index": 291, "question": "请你朗读以下物理公式符号:$$\\left(1\\right)$$", "audio_path": "audio/physics_659f1f1c-c6e2-4722-9e1a-20c3b0e12510.wav", "formula": "$$\\left(1\\right)$$", "answer": "一", "subset": "Physics700", "task_type": "tts"} +{"index": 292, "question": "请你朗读以下物理公式符号:$\\frac{gt^{2}}{4}$", "audio_path": "audio/physics_1f6acd1a-5de7-4f42-8986-99a3aca9c23f.wav", "formula": "$\\frac{gt^{2}}{4}$", "answer": "四分之g乘t的平方", "subset": "Physics700", "task_type": "tts"} +{"index": 293, "question": "Please read the following physics formula symbols: $$\\frac{v^{2}}{R}$$", "audio_path": "audio/physics_54f46154-2934-4318-83e9-001bbeb6b8c3.wav", "formula": "$$\\frac{v^{2}}{R}$$", "answer": "v squared over R", "subset": "Physics700", "task_type": "tts"} +{"index": 294, "question": "Please read the following physics formula symbols: $\\left(g−\\frac{v^{2}}{R}\\right)$", "audio_path": "audio/physics_4d145148-32d4-4835-90b5-24a59bc7e0b9.wav", "formula": "$\\left(g−\\frac{v^{2}}{R}\\right)$", "answer": "the difference between g and v squared over R", "subset": "Physics700", "task_type": "tts"} +{"index": 295, "question": "Please read the following physics formula symbols: $$4.2×10^{3} J/\\left(kg·℃\\right)$$", "audio_path": "audio/physics_182be4a3-d742-42ed-91c5-070939743dfb.wav", "formula": "$$4.2×10^{3} J/\\left(kg·℃\\right)$$", "answer": "4.2 times ten to the power of three joules over kilogram times degree Celsius", "subset": "Physics700", "task_type": "tts"} +{"index": 296, "question": "请你朗读以下物理公式符号:$E=\\frac{1}{2}mc^{2}$", "audio_path": "audio/physics_92734532-a49e-4a76-8a11-19523abdf1ff.wav", "formula": "$E=\\frac{1}{2}mc^{2}$", "answer": "E等于二分之一乘m乘c的平方", "subset": "Physics700", "task_type": "tts"} +{"index": 297, "question": "请你朗读以下物理公式符号:$$m=\\frac{Q}{c\\left(t−t_{0}\\right)}$$", "audio_path": "audio/physics_5cc1390a-108a-43ce-bb7e-e464c03c815a.wav", "formula": "$$m=\\frac{Q}{c\\left(t−t_{0}\\right)}$$", "answer": "m等于Q除以c与t减t零差的乘积", "subset": "Physics700", "task_type": "tts"} +{"index": 298, "question": "请你朗读以下物理公式符号:$v=6t^{2}\\left(m/s\\right)$", "audio_path": "audio/physics_e97dad66-3f02-4a43-bc20-d858269b2b8b.wav", "formula": "$v=6t^{2}\\left(m/s\\right)$", "answer": "v等于六乘t的平方 米每秒", "subset": "Physics700", "task_type": "tts"} +{"index": 299, "question": "请你朗读以下物理公式符号:$$h=\\frac{W}{G}$$", "audio_path": "audio/physics_c84b2c62-42ed-4908-9f9b-010ee7429494.wav", "formula": "$$h=\\frac{W}{G}$$", "answer": "h等于G分之W", "subset": "Physics700", "task_type": "tts"} +{"index": 300, "question": "请你朗读以下物理公式符号:$$=2.5\\mu m\\times 10^{-6}m$$", "audio_path": "audio/physics_83fac2a7-b091-4306-89fd-1166043e494c.wav", "formula": "$$=2.5\\mu m\\times 10^{-6}m$$", "answer": "等于二点五微米乘十的负六次方米", "subset": "Physics700", "task_type": "tts"} +{"index": 301, "question": "请你朗读以下物理公式符号:$10^{10} m^{3}$", "audio_path": "audio/physics_b64e886f-9c69-40d0-a6e8-4fa3e14eb1af.wav", "formula": "$10^{10} m^{3}$", "answer": "十的十次方立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 302, "question": "Please read the following physics formula symbols: $3.0×10^{7}J/kg$", "audio_path": "audio/physics_cacf68f6-ef6b-4cc0-86c0-544ca17158ef.wav", "formula": "$3.0×10^{7}J/kg$", "answer": "three point zero times ten to the power of seven J over kg", "subset": "Physics700", "task_type": "tts"} +{"index": 303, "question": "Please read the following physics formula symbols: $t_{1}+t_{2}=1.4s$", "audio_path": "audio/physics_ec7182d0-1a17-44f0-b2b3-288796f989b1.wav", "formula": "$t_{1}+t_{2}=1.4s$", "answer": "t one plus t two equals one point four s", "subset": "Physics700", "task_type": "tts"} +{"index": 304, "question": "Please read the following physics formula symbols: $$\\frac{GMm}{r^{2}}$$", "audio_path": "audio/physics_f2996024-730e-4af5-ba26-e22f6385ee41.wav", "formula": "$$\\frac{GMm}{r^{2}}$$", "answer": "gravitational constant G times M times m over r squared", "subset": "Physics700", "task_type": "tts"} +{"index": 305, "question": "请你朗读以下物理公式符号:$\\frac{m}{r^{2}}$", "audio_path": "audio/physics_e3d02542-c55e-48b3-9733-2e98e4a94af0.wav", "formula": "$\\frac{m}{r^{2}}$", "answer": "r的平方分之m", "subset": "Physics700", "task_type": "tts"} +{"index": 306, "question": "请你朗读以下物理公式符号:$\\frac{W_{AB}}{q}$", "audio_path": "audio/physics_718674ca-feb5-4000-85ca-184b06c03f55.wav", "formula": "$\\frac{W_{AB}}{q}$", "answer": "q 分之 W AB", "subset": "Physics700", "task_type": "tts"} +{"index": 307, "question": "请你朗读以下物理公式符号:$$p=\\frac{m}{V}$$", "audio_path": "audio/physics_0487321c-3557-4bd6-8e84-34b22f74d423.wav", "formula": "$$p=\\frac{m}{V}$$", "answer": "p等于V分之m", "subset": "Physics700", "task_type": "tts"} +{"index": 308, "question": "Please read the following physics formula symbols: $$R=\\frac{U}{I}$$", "audio_path": "audio/physics_3b88a277-d0df-47a3-92fd-75a2070c5150.wav", "formula": "$$R=\\frac{U}{I}$$", "answer": "R equals U over I", "subset": "Physics700", "task_type": "tts"} +{"index": 309, "question": "请你朗读以下物理公式符号:$$10^{−2} m^{2}$$", "audio_path": "audio/physics_868d5d93-ab95-4383-86df-8995ce59151f.wav", "formula": "$$10^{−2} m^{2}$$", "answer": "十的负二次方平方米", "subset": "Physics700", "task_type": "tts"} +{"index": 310, "question": "请你朗读以下物理公式符号:$$4.2×10^{3} J/\\left(kg·℃\\right)$$", "audio_path": "audio/physics_d610a155-91eb-4c4e-a99f-c94af9171a52.wav", "formula": "$$4.2×10^{3} J/\\left(kg·℃\\right)$$", "answer": "四点二乘十的三次方焦耳每千克摄氏度", "subset": "Physics700", "task_type": "tts"} +{"index": 311, "question": "请你朗读以下物理公式符号:$$\\frac{GMm}{r^{2}}$$", "audio_path": "audio/physics_7917f39e-fea7-4725-a477-14a8962c4fcf.wav", "formula": "$$\\frac{GMm}{r^{2}}$$", "answer": "r的平方分之G乘M乘m", "subset": "Physics700", "task_type": "tts"} +{"index": 312, "question": "请你朗读以下物理公式符号:$$m=\\frac{Q}{q}$$", "audio_path": "audio/physics_f4bcebe1-2db4-40b9-848c-7803905d337b.wav", "formula": "$$m=\\frac{Q}{q}$$", "answer": "m 等于 q 分之 Q", "subset": "Physics700", "task_type": "tts"} +{"index": 313, "question": "Please read the following physics formula symbols: $$\\frac{r^{3}}{T^{2}}$$", "audio_path": "audio/physics_d0e3e0c9-89a9-4357-adde-5801065e6015.wav", "formula": "$$\\frac{r^{3}}{T^{2}}$$", "answer": "r cubed over T squared", "subset": "Physics700", "task_type": "tts"} +{"index": 314, "question": "请你朗读以下物理公式符号:$\\frac{60}{100}×V+\\frac{30}{100}×\\left(1000ml−V\\right)=420ml$", "audio_path": "audio/physics_701651c4-668b-4bd4-ba07-dba26df8cd38.wav", "formula": "$\\frac{60}{100}×V+\\frac{30}{100}×\\left(1000ml−V\\right)=420ml$", "answer": "一百分之六十乘V加一百分之三十乘一千毫升减V的差等于四百二十毫升", "subset": "Physics700", "task_type": "tts"} +{"index": 315, "question": "Please read the following physics formula symbols: $ρ=2.7×10^{3}kg/m^{3}$", "audio_path": "audio/physics_f97718d9-2901-416a-9f54-c2c83052f14a.wav", "formula": "$ρ=2.7×10^{3}kg/m^{3}$", "answer": "rho equals two point seven times ten cubed kilograms over meters cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 316, "question": "Please read the following physics formula symbols: $$4.4×10^{7}J/kg$$", "audio_path": "audio/physics_1b03aba7-f20c-4786-98a0-d695d856f32a.wav", "formula": "$$4.4×10^{7}J/kg$$", "answer": "four point four times ten to the power of seven joules over kilograms", "subset": "Physics700", "task_type": "tts"} +{"index": 317, "question": "Please read the following physics formula symbols: $\\frac{π^{2}\\left(2R+ct\\right)^{3}}{2GT^{2}}$", "audio_path": "audio/physics_280ef15c-0fe1-459e-bcd6-6330853b70a9.wav", "formula": "$\\frac{π^{2}\\left(2R+ct\\right)^{3}}{2GT^{2}}$", "answer": "pi squared times the cube of the sum of two R and c times t, over two times gravitational constant G times T squared", "subset": "Physics700", "task_type": "tts"} +{"index": 318, "question": "请你朗读以下物理公式符号:$$1.1\\times 10^{3}kg/m^{3}$$", "audio_path": "audio/physics_1be78285-c918-442d-90bd-0fe660252ae1.wav", "formula": "$$1.1\\times 10^{3}kg/m^{3}$$", "answer": "一点一乘十的三次方千克每立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 319, "question": "Please read the following physics formula symbols: $\\frac{49N}{80\\%}$", "audio_path": "audio/physics_dfc2a3be-88b7-478b-9ce0-13abd05e8484.wav", "formula": "$\\frac{49N}{80\\%}$", "answer": "forty-nine N over eighty percent", "subset": "Physics700", "task_type": "tts"} +{"index": 320, "question": "Please read the following physics formula symbols: $\\frac{v^{2}}{R}$", "audio_path": "audio/physics_7621d7f4-5677-4971-bcd4-330afdef77ac.wav", "formula": "$\\frac{v^{2}}{R}$", "answer": "v squared over R", "subset": "Physics700", "task_type": "tts"} +{"index": 321, "question": "请你朗读以下物理公式符号:$$p=\\frac{w}{t}$$", "audio_path": "audio/physics_03941ebb-4724-4509-aa78-051fd6bf8a61.wav", "formula": "$$p=\\frac{w}{t}$$", "answer": "p等于t分之w", "subset": "Physics700", "task_type": "tts"} +{"index": 322, "question": "Please read the following physics formula symbols: $$2.7×10^{3}kg/m^{3}$$", "audio_path": "audio/physics_e8f1024b-b638-4599-934d-aca133d50016.wav", "formula": "$$2.7×10^{3}kg/m^{3}$$", "answer": "two point seven times ten to the power of three kilograms over meters cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 323, "question": "Please read the following physics formula symbols: $\\frac{60}{100}×V$", "audio_path": "audio/physics_1170bf7d-7c8e-4fca-9901-0e3b8990e5c6.wav", "formula": "$\\frac{60}{100}×V$", "answer": "60 over 100 times V", "subset": "Physics700", "task_type": "tts"} +{"index": 324, "question": "Please read the following physics formula symbols: $$\\frac{v^{2}}{Rg}$$", "audio_path": "audio/physics_6850661a-e31f-4369-a628-26848b3ad2d8.wav", "formula": "$$\\frac{v^{2}}{Rg}$$", "answer": "v squared over R times g", "subset": "Physics700", "task_type": "tts"} +{"index": 325, "question": "请你朗读以下物理公式符号:$$ρ=0.7\\times 10^{3}kg/m^{3}$$", "audio_path": "audio/physics_996547b6-2853-4981-9fa4-ab6c8df1e611.wav", "formula": "$$ρ=0.7\\times 10^{3}kg/m^{3}$$", "answer": "rho等于零点七乘十的三次方千克每立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 326, "question": "请你朗读以下物理公式符号:$\\frac{1}{9}m^{3}$", "audio_path": "audio/physics_9b6e1a72-14e0-4820-9092-aaa6b689ea84.wav", "formula": "$\\frac{1}{9}m^{3}$", "answer": "九分之一立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 327, "question": "请你朗读以下物理公式符号:$v = 40 \\, \\text{m/s}, D. a = 1 \\, \\text{m/s}$", "audio_path": "audio/physics_bcefe2b7-d413-4d79-973f-c9318b63b33c.wav", "formula": "$v = 40 \\, \\text{m/s}, D. a = 1 \\, \\text{m/s}$", "answer": "v等于四十米每秒,D,a 等于一米每秒", "subset": "Physics700", "task_type": "tts"} +{"index": 328, "question": "请你朗读以下物理公式符号:$$m=\\frac{G}{g}$$", "audio_path": "audio/physics_b8c08b18-b621-4f0b-a9a6-cbc859b3f34c.wav", "formula": "$$m=\\frac{G}{g}$$", "answer": "m等于g分之G", "subset": "Physics700", "task_type": "tts"} +{"index": 329, "question": "Please read the following physics formula symbols: $$△t=\\frac{Q}{cm}$$", "audio_path": "audio/physics_588dd2b1-6870-4bde-a5af-46c8d0081e90.wav", "formula": "$$△t=\\frac{Q}{cm}$$", "answer": "delta t equals Q over c times m", "subset": "Physics700", "task_type": "tts"} +{"index": 330, "question": "Please read the following physics formula symbols: $$\\frac{1}{3600}$$", "audio_path": "audio/physics_0439ddd8-0a9e-499d-802d-b3e1243c7769.wav", "formula": "$$\\frac{1}{3600}$$", "answer": "one over three thousand six hundred", "subset": "Physics700", "task_type": "tts"} +{"index": 331, "question": "请你朗读以下物理公式符号:$$10^{-4} m^{3}$$", "audio_path": "audio/physics_e811d782-74a4-49e1-a542-43be8fae30fa.wav", "formula": "$$10^{-4} m^{3}$$", "answer": "十的负四次方立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 332, "question": "Please read the following physics formula symbols: $\\frac{50}{323}$", "audio_path": "audio/physics_a9408ffc-bae9-4554-bcb9-974236f62a5a.wav", "formula": "$\\frac{50}{323}$", "answer": "fifty over three hundred twenty-three", "subset": "Physics700", "task_type": "tts"} +{"index": 333, "question": "Please read the following physics formula symbols: $$R_{1}:R_{2}=3:4$$", "audio_path": "audio/physics_f2182892-325f-44cf-8d62-0811bc97aab0.wav", "formula": "$$R_{1}:R_{2}=3:4$$", "answer": "R one to R two equals three to four", "subset": "Physics700", "task_type": "tts"} +{"index": 334, "question": "请你朗读以下物理公式符号:$\\frac{Gm_{1}m_{2}}{r^{2}}$", "audio_path": "audio/physics_1ed36a66-cf91-463e-b799-c7bf29244d8e.wav", "formula": "$\\frac{Gm_{1}m_{2}}{r^{2}}$", "answer": "r的平方分之G乘m一乘m二", "subset": "Physics700", "task_type": "tts"} +{"index": 335, "question": "请你朗读以下物理公式符号:$$x=\\frac{1}{2}at^{2}$$", "audio_path": "audio/physics_8730bf77-e57e-40de-a330-06037937ec22.wav", "formula": "$$x=\\frac{1}{2}at^{2}$$", "answer": "x等于二分之一乘a乘t的平方", "subset": "Physics700", "task_type": "tts"} +{"index": 336, "question": "Please read the following physics formula symbols: $$1.0×10^{3}kg/m^{3}$$", "audio_path": "audio/physics_748f6439-8935-42fd-9735-02b357a2480d.wav", "formula": "$$1.0×10^{3}kg/m^{3}$$", "answer": "one point zero times ten to the power of three kilograms over meters cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 337, "question": "请你朗读以下物理公式符号:$$\\frac{2πr}{T}$$", "audio_path": "audio/physics_3652da8c-4164-4899-85bd-7eb17748a418.wav", "formula": "$$\\frac{2πr}{T}$$", "answer": "T 分之 二 乘pi乘 r", "subset": "Physics700", "task_type": "tts"} +{"index": 338, "question": "Please read the following physics formula symbols: $\\frac{U^{2}}{R}t$", "audio_path": "audio/physics_4d12c1bc-dc86-41da-9444-1647a422fb5e.wav", "formula": "$\\frac{U^{2}}{R}t$", "answer": "U squared over R times t", "subset": "Physics700", "task_type": "tts"} +{"index": 339, "question": "Please read the following physics formula symbols: $\\frac{1}{9}m^{3}$", "audio_path": "audio/physics_ff2f07cf-5d78-4058-a14a-67599aff45e4.wav", "formula": "$\\frac{1}{9}m^{3}$", "answer": "one over nine times m cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 340, "question": "Please read the following physics formula symbols: $$\\frac{Gh}{Fs}$$", "audio_path": "audio/physics_9638f106-04bb-4d1b-a74f-65be09570653.wav", "formula": "$$\\frac{Gh}{Fs}$$", "answer": "gravitational constant G times Planck's constant h over F times s", "subset": "Physics700", "task_type": "tts"} +{"index": 341, "question": "请你朗读以下物理公式符号:$$4.6×10^{7}J/kg$$", "audio_path": "audio/physics_27ad6165-f975-46ab-9b31-88574c3458c1.wav", "formula": "$$4.6×10^{7}J/kg$$", "answer": "四点六乘十的七次方焦耳每千克", "subset": "Physics700", "task_type": "tts"} +{"index": 342, "question": "请你朗读以下物理公式符号:$E_{n}=\\frac{E_{1}}{n^{2}}$", "audio_path": "audio/physics_df449d75-189d-437d-8071-0f89203d6b97.wav", "formula": "$E_{n}=\\frac{E_{1}}{n^{2}}$", "answer": "E n 等于 n 的平方分之 E 一", "subset": "Physics700", "task_type": "tts"} +{"index": 343, "question": "请你朗读以下物理公式符号:$\\frac{2v^{2}}{Rg}$", "audio_path": "audio/physics_94bb68f0-bd57-4385-bba1-b5c6fb430615.wav", "formula": "$\\frac{2v^{2}}{Rg}$", "answer": "R乘g的积分之二乘v平方", "subset": "Physics700", "task_type": "tts"} +{"index": 344, "question": "Please read the following physics formula symbols: $$\\frac{1}{100}$$", "audio_path": "audio/physics_bd9f9514-43e0-4eb0-ae4e-0b60548e5842.wav", "formula": "$$\\frac{1}{100}$$", "answer": "one over one hundred", "subset": "Physics700", "task_type": "tts"} +{"index": 345, "question": "Please read the following physics formula symbols: $\\frac{Gm_{1}m_{2}}{r^{2}}$", "audio_path": "audio/physics_84c7687a-f72a-4974-a2fd-5625a7468655.wav", "formula": "$\\frac{Gm_{1}m_{2}}{r^{2}}$", "answer": "gravitational constant G times m one times m two over r squared", "subset": "Physics700", "task_type": "tts"} +{"index": 346, "question": "请你朗读以下物理公式符号:$$q=\\frac{Q}{m}$$", "audio_path": "audio/physics_c49fe5a2-89f6-432f-a6af-0a3fe3aab5da.wav", "formula": "$$q=\\frac{Q}{m}$$", "answer": "q 等于 m 分之 Q", "subset": "Physics700", "task_type": "tts"} +{"index": 347, "question": "请你朗读以下物理公式符号:$$3.645×10^{10}$$", "audio_path": "audio/physics_fc2e50c5-fd5e-4d96-bfcf-7d6d08f1ea1c.wav", "formula": "$$3.645×10^{10}$$", "answer": "三点六四五乘十的十次方", "subset": "Physics700", "task_type": "tts"} +{"index": 348, "question": "请你朗读以下物理公式符号:$$\\frac{Gh}{Fs}$$", "audio_path": "audio/physics_499d578c-c1c9-4864-8f9c-170f04bfe39c.wav", "formula": "$$\\frac{Gh}{Fs}$$", "answer": "F乘s的积分之G 乘 h", "subset": "Physics700", "task_type": "tts"} +{"index": 349, "question": "Please read the following physics formula symbols: $\\frac{4v_{0}}{g}$", "audio_path": "audio/physics_f434d628-b491-4862-9f98-08fc3cbcdc63.wav", "formula": "$\\frac{4v_{0}}{g}$", "answer": "four v naught over g", "subset": "Physics700", "task_type": "tts"} +{"index": 350, "question": "请你朗读以下物理公式符号:$$1.4 \\times 10^{8} \\mathrm{J/kg}$$", "audio_path": "audio/physics_9f2d813c-3a5d-4125-8fee-acdb0da1bd53.wav", "formula": "$$1.4 \\times 10^{8} \\mathrm{J/kg}$$", "answer": "一点四乘十的八次方焦耳每千克", "subset": "Physics700", "task_type": "tts"} +{"index": 351, "question": "Please read the following physics formula symbols: $$0.8\\times 10^{3} \\mathrm{Kg/m^{3}}$$", "audio_path": "audio/physics_9f0136b9-78b5-46ac-90fa-cd12a1539b29.wav", "formula": "$$0.8\\times 10^{3} \\mathrm{Kg/m^{3}}$$", "answer": "zero point eight times ten cubed kilograms over cubic meters", "subset": "Physics700", "task_type": "tts"} +{"index": 352, "question": "Please read the following physics formula symbols: $\\frac{E_{1}}{n^{2}}$", "audio_path": "audio/physics_cd5e8f95-592f-4711-9a58-bbe79a9d93bc.wav", "formula": "$\\frac{E_{1}}{n^{2}}$", "answer": "E one over n squared", "subset": "Physics700", "task_type": "tts"} +{"index": 353, "question": "请你朗读以下物理公式符号:$$v=\\frac{ε}{h}$$", "audio_path": "audio/physics_4b4d7960-69f8-4e20-bc77-a65c27deecd3.wav", "formula": "$$v=\\frac{ε}{h}$$", "answer": "v等于h分之epsilon", "subset": "Physics700", "task_type": "tts"} +{"index": 354, "question": "Please read the following physics formula symbols: $F>\\frac{1}{n}G$", "audio_path": "audio/physics_006fbaa8-6183-43a6-b40b-b7bd0399566b.wav", "formula": "$F>\\frac{1}{n}G$", "answer": "F is greater than G times one over n", "subset": "Physics700", "task_type": "tts"} +{"index": 355, "question": "请你朗读以下物理公式符号:$\\frac{v^{2}}{R}$", "audio_path": "audio/physics_88b5b046-411d-40fb-b17b-7d576391482e.wav", "formula": "$\\frac{v^{2}}{R}$", "answer": "R 分之 v 的平方", "subset": "Physics700", "task_type": "tts"} +{"index": 356, "question": "Please read the following physics formula symbols: $$ω=\\frac{2π}{T}$$", "audio_path": "audio/physics_1aac1ca2-1781-4cb6-a50e-29cce23e6165.wav", "formula": "$$ω=\\frac{2π}{T}$$", "answer": "omega equals two pi over T", "subset": "Physics700", "task_type": "tts"} +{"index": 357, "question": "请你朗读以下物理公式符号:$0.7×10^{3}kg/m^{3}$", "audio_path": "audio/physics_82dcfcf9-3eb7-4d57-9fbc-fd219a1181a8.wav", "formula": "$0.7×10^{3}kg/m^{3}$", "answer": "零点七乘十的三次方千克每立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 358, "question": "请你朗读以下物理公式符号:$$=\\frac{2πr}{T}$$", "audio_path": "audio/physics_4d64efe3-1ebd-4e8a-8edf-c235c825de09.wav", "formula": "$$=\\frac{2πr}{T}$$", "answer": "等于 T 分之 二乘pi乘 r", "subset": "Physics700", "task_type": "tts"} +{"index": 359, "question": "请你朗读以下物理公式符号:$\\frac{Q_{1}}{r^{2}}$", "audio_path": "audio/physics_f4120929-de66-4bba-a9c2-2d04cb810949.wav", "formula": "$\\frac{Q_{1}}{r^{2}}$", "answer": "r 的平方分之 Q 一", "subset": "Physics700", "task_type": "tts"} +{"index": 360, "question": "Please read the following physics formula symbols: $$Q=I^{2}Rt, P=UI$$", "audio_path": "audio/physics_53088a05-88be-439d-9d95-1b05cb0c28e4.wav", "formula": "$$Q=I^{2}Rt, P=UI$$", "answer": "Q equals I squared times R times t, P equals U times I", "subset": "Physics700", "task_type": "tts"} +{"index": 361, "question": "请你朗读以下物理公式符号:$$3.0 \\times 10^{8} m/s$$", "audio_path": "audio/physics_46919920-7910-4239-b505-c71583daf527.wav", "formula": "$$3.0 \\times 10^{8} m/s$$", "answer": "三点零乘十的八次方米每秒", "subset": "Physics700", "task_type": "tts"} +{"index": 362, "question": "请你朗读以下物理公式符号:$$\\frac{Kq}{r^{2}}$$", "audio_path": "audio/physics_1c541c71-265c-4684-bbd1-f1479b6b44d4.wav", "formula": "$$\\frac{Kq}{r^{2}}$$", "answer": "r的平方分之K乘q", "subset": "Physics700", "task_type": "tts"} +{"index": 363, "question": "Please read the following physics formula symbols: $\\frac{60}{100}×V+\\frac{30}{100}×\\left(1000ml−V\\right)=420ml$", "audio_path": "audio/physics_bf16c1c2-3003-4638-8140-2cc5d25c04c6.wav", "formula": "$\\frac{60}{100}×V+\\frac{30}{100}×\\left(1000ml−V\\right)=420ml$", "answer": "60 over 100 times V plus 30 over 100 times the difference between 1000 milliliters and V equals 420 milliliters", "subset": "Physics700", "task_type": "tts"} +{"index": 364, "question": "Please read the following physics formula symbols: $\\frac{Mυ_{1}}{\\left(M+m\\right)υ_{2}}$", "audio_path": "audio/physics_037220e7-d242-4a28-bedb-b0d1ea85e4a6.wav", "formula": "$\\frac{Mυ_{1}}{\\left(M+m\\right)υ_{2}}$", "answer": "M upsilon one over the sum of M and m multiplied by upsilon two", "subset": "Physics700", "task_type": "tts"} +{"index": 365, "question": "请你朗读以下物理公式符号:$\\frac{E_{1}}{4}$", "audio_path": "audio/physics_966bfec4-4c31-4545-8952-21410ba41324.wav", "formula": "$\\frac{E_{1}}{4}$", "answer": "四分之E一", "subset": "Physics700", "task_type": "tts"} +{"index": 366, "question": "Please read the following physics formula symbols: $\\frac{1}{6} m^{3}$", "audio_path": "audio/physics_08813e17-a7d3-4b6c-94f8-b52811347155.wav", "formula": "$\\frac{1}{6} m^{3}$", "answer": "one over six times m cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 367, "question": "请你朗读以下物理公式符号:$$0.5×10^{3}kg/m^{3}$$", "audio_path": "audio/physics_49782f9c-f513-44fc-81bd-65b6794fd236.wav", "formula": "$$0.5×10^{3}kg/m^{3}$$", "answer": "零点五乘十的三次方千克每立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 368, "question": "Please read the following physics formula symbols: $$2×10^{-5}m^{2}$$", "audio_path": "audio/physics_3419675a-7b32-4af6-aef1-217ab020a4c0.wav", "formula": "$$2×10^{-5}m^{2}$$", "answer": "2 times 10 to the power of negative 5 times m squared", "subset": "Physics700", "task_type": "tts"} +{"index": 369, "question": "请你朗读以下物理公式符号:$1.0×10^{3} kg/m^{3}$", "audio_path": "audio/physics_da3f9f03-ebdf-463a-9088-4b08e64db959.wav", "formula": "$1.0×10^{3} kg/m^{3}$", "answer": "一点零乘十的三次方千克每立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 370, "question": "Please read the following physics formula symbols: $10^{10} m^{3}$", "audio_path": "audio/physics_823574a5-87a6-4dd1-91d9-6e094946d6e3.wav", "formula": "$10^{10} m^{3}$", "answer": "ten to the power of ten times m cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 371, "question": "请你朗读以下物理公式符号:$I_{1}=4.4\\times10^{4}$", "audio_path": "audio/physics_a03059de-83f7-47f5-a659-30b1368cf165.wav", "formula": "$I_{1}=4.4\\times10^{4}$", "answer": "I一等于四点四乘十的四次方", "subset": "Physics700", "task_type": "tts"} +{"index": 372, "question": "Please read the following physics formula symbols: $\\frac{v_{1}−v_{2}}{t}$", "audio_path": "audio/physics_2eb73018-b054-4b5e-b4a4-740f3194ca28.wav", "formula": "$\\frac{v_{1}−v_{2}}{t}$", "answer": "the difference between v one and v two over t", "subset": "Physics700", "task_type": "tts"} +{"index": 373, "question": "Please read the following physics formula symbols: $$\\frac{U^{2}}{R}$$", "audio_path": "audio/physics_475effc8-9267-43ff-84e5-326ad703fae4.wav", "formula": "$$\\frac{U^{2}}{R}$$", "answer": "U squared over R", "subset": "Physics700", "task_type": "tts"} +{"index": 374, "question": "Please read the following physics formula symbols: $E_{n}=\\frac{E_{1}}{n^{2}}$", "audio_path": "audio/physics_5b9a1ecf-de9d-43cb-9b76-f14413933047.wav", "formula": "$E_{n}=\\frac{E_{1}}{n^{2}}$", "answer": "E n equals E one over n squared", "subset": "Physics700", "task_type": "tts"} +{"index": 375, "question": "Please read the following physics formula symbols: $\\frac{Q_{1}Q_{2}}{r^{2}}$", "audio_path": "audio/physics_c7b7cdf1-fcaa-4f7b-9f69-947876ff6d80.wav", "formula": "$\\frac{Q_{1}Q_{2}}{r^{2}}$", "answer": "Q one times Q two over r squared", "subset": "Physics700", "task_type": "tts"} +{"index": 376, "question": "请你朗读以下物理公式符号:$$F_{1}L_{1}=F_{2}L_{2}$$", "audio_path": "audio/physics_8b11740e-4525-4d43-9bd5-e640cc7f08c5.wav", "formula": "$$F_{1}L_{1}=F_{2}L_{2}$$", "answer": "F 一乘 L 一等于 F 二乘 L 二", "subset": "Physics700", "task_type": "tts"} +{"index": 377, "question": "Please read the following physics formula symbols: $$10^{3} cm^{3}$$", "audio_path": "audio/physics_5b621c88-bc31-4c72-b141-4e3e8feba162.wav", "formula": "$$10^{3} cm^{3}$$", "answer": "ten cubed times centimeter cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 378, "question": "请你朗读以下物理公式符号:$t_{1}+t_{2}=1.4s$", "audio_path": "audio/physics_85ae43f2-1772-4573-a30a-e237491a46f5.wav", "formula": "$t_{1}+t_{2}=1.4s$", "answer": "t 一加t 二等于一点四秒", "subset": "Physics700", "task_type": "tts"} +{"index": 379, "question": "请你朗读以下物理公式符号:$$P=\\frac{F}{S}$$", "audio_path": "audio/physics_1caf4a04-a8c6-4535-bf50-5c7d2a60263d.wav", "formula": "$$P=\\frac{F}{S}$$", "answer": "P等于S分之F", "subset": "Physics700", "task_type": "tts"} +{"index": 380, "question": "请你朗读以下物理公式符号:$\\frac{n^{2}h^{2}}{2med^{2}}$", "audio_path": "audio/physics_47cd156f-aef1-4614-b9be-9fa4a2311820.wav", "formula": "$\\frac{n^{2}h^{2}}{2med^{2}}$", "answer": "n平方乘h平方的积除以二乘m乘e乘d平方的积", "subset": "Physics700", "task_type": "tts"} +{"index": 381, "question": "请你朗读以下物理公式符号:$\\frac{8H}{T_{2}^{2}−T_{1}^{2}}$", "audio_path": "audio/physics_056b8601-f888-42c8-8d9e-c22d4bd13539.wav", "formula": "$\\frac{8H}{T_{2}^{2}−T_{1}^{2}}$", "answer": "T 二平方减 T 一平方的差 分之 八 乘H", "subset": "Physics700", "task_type": "tts"} +{"index": 382, "question": "Please read the following physics formula symbols: $=2.5×10^{−5}cm$", "audio_path": "audio/physics_30863484-d8b6-436c-8237-1fcd4f1134b8.wav", "formula": "$=2.5×10^{−5}cm$", "answer": "equals 2.5 times 10 to the power of negative 5 centimeters", "subset": "Physics700", "task_type": "tts"} +{"index": 383, "question": "Please read the following physics formula symbols: $cm\\left(t−t_{0}\\right)$", "audio_path": "audio/physics_166a3380-1c5a-4191-83fb-1874b350559e.wav", "formula": "$cm\\left(t−t_{0}\\right)$", "answer": "speed of light c times m times the difference between t and t naught", "subset": "Physics700", "task_type": "tts"} +{"index": 384, "question": "请你朗读以下物理公式符号:$\\frac{Q_{2}}{r^{2}}$", "audio_path": "audio/physics_67be2d01-1e3e-4c2d-98a1-cf2d875c86d0.wav", "formula": "$\\frac{Q_{2}}{r^{2}}$", "answer": "r 的平方分之 Q 二", "subset": "Physics700", "task_type": "tts"} +{"index": 385, "question": "请你朗读以下物理公式符号:$\\frac{60}{100}×V$", "audio_path": "audio/physics_d88a368e-fb90-4791-b070-6172c2562b64.wav", "formula": "$\\frac{60}{100}×V$", "answer": "一百分之六十乘V", "subset": "Physics700", "task_type": "tts"} +{"index": 386, "question": "Please read the following physics formula symbols: $\\frac{2v_{0}}{g}$", "audio_path": "audio/physics_e9b1646b-ed4b-4809-8468-78e03ece6114.wav", "formula": "$\\frac{2v_{0}}{g}$", "answer": "two v naught over g", "subset": "Physics700", "task_type": "tts"} +{"index": 387, "question": "Please read the following physics formula symbols: $$7.3×10^{26}g=$$", "audio_path": "audio/physics_364de011-cba3-4b2b-b07d-41d715465e5c.wav", "formula": "$$7.3×10^{26}g=$$", "answer": "seven point three times ten to the power of twenty-six g equals", "subset": "Physics700", "task_type": "tts"} +{"index": 388, "question": "请你朗读以下物理公式符号:$$W=\\frac{U^{2}}{R}t$$", "audio_path": "audio/physics_7fdd7bb3-d007-485e-96de-5ad7a7368e44.wav", "formula": "$$W=\\frac{U^{2}}{R}t$$", "answer": "W等于R分之U平方乘t", "subset": "Physics700", "task_type": "tts"} +{"index": 389, "question": "请你朗读以下物理公式符号:$$R_{1}:R_{2}=3:5$$", "audio_path": "audio/physics_519c62bc-40ef-4815-a318-ed58b8d9ff5f.wav", "formula": "$$R_{1}:R_{2}=3:5$$", "answer": "R 一比 R 二等于三比五", "subset": "Physics700", "task_type": "tts"} +{"index": 390, "question": "请你朗读以下物理公式符号:$$x=5+2t^{3}\\left( m \\right)$$", "audio_path": "audio/physics_cdeed4d8-6ead-4e81-bb5b-5ab1c90d0c85.wav", "formula": "$$x=5+2t^{3}\\left( m \\right)$$", "answer": "x等于五加二乘t的三次方米", "subset": "Physics700", "task_type": "tts"} +{"index": 391, "question": "Please read the following physics formula symbols: $$t=\\frac{S}{V}$$", "audio_path": "audio/physics_19dc8e16-9d4d-4bbf-9fa1-8d873f3948fa.wav", "formula": "$$t=\\frac{S}{V}$$", "answer": "t equals S over V", "subset": "Physics700", "task_type": "tts"} +{"index": 392, "question": "请你朗读以下物理公式符号:$η=\\frac{Gh}{fL}$", "audio_path": "audio/physics_a12a3d80-e387-45d5-bb8a-5b752367393c.wav", "formula": "$η=\\frac{Gh}{fL}$", "answer": "eta 等于f乘L的积分之G乘h", "subset": "Physics700", "task_type": "tts"} +{"index": 393, "question": "请你朗读以下物理公式符号:$$2×10^{3}kg/m^{3}$$", "audio_path": "audio/physics_5bf1a671-bc5f-4d29-9b58-469219b853dc.wav", "formula": "$$2×10^{3}kg/m^{3}$$", "answer": "二乘十的三次方千克每立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 394, "question": "请你朗读以下物理公式符号:$$P=\\frac{U^{2}}{R}$$", "audio_path": "audio/physics_67a379bf-031d-4c9d-b201-adc02d24c91d.wav", "formula": "$$P=\\frac{U^{2}}{R}$$", "answer": "P 等于 R 分之 U 平方", "subset": "Physics700", "task_type": "tts"} +{"index": 395, "question": "请你朗读以下物理公式符号:$$1g/cm^{3}=10^{3}kg/m^{3}$$", "audio_path": "audio/physics_6442d9d9-b1f5-4dac-8fbe-383b2aee04dd.wav", "formula": "$$1g/cm^{3}=10^{3}kg/m^{3}$$", "answer": "一克每立方厘米等于十的三次方千克每立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 396, "question": "请你朗读以下物理公式符号:$$1.03×10^{3}kg/m^{3}$$", "audio_path": "audio/physics_1434e2d8-22ec-4a5e-a1e5-66f6a08b88f4.wav", "formula": "$$1.03×10^{3}kg/m^{3}$$", "answer": "一点零三乘十的三次方千克每立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 397, "question": "Please read the following physics formula symbols: $\\frac{H}{4\\left(T_{2}−T_{1}\\right)^{2}}$", "audio_path": "audio/physics_976d1683-6aec-4284-8bd3-fa8d70972924.wav", "formula": "$\\frac{H}{4\\left(T_{2}−T_{1}\\right)^{2}}$", "answer": "H over four times the square of the difference between T two and T one", "subset": "Physics700", "task_type": "tts"} +{"index": 398, "question": "请你朗读以下物理公式符号:$\\frac{4v_{0}}{g}$", "audio_path": "audio/physics_9ef60188-2cd3-4f14-88a6-9b9bb83284c1.wav", "formula": "$\\frac{4v_{0}}{g}$", "answer": "g 分之四乘v零", "subset": "Physics700", "task_type": "tts"} +{"index": 399, "question": "请你朗读以下物理公式符号:$$p=\\frac{m}{v}$$", "audio_path": "audio/physics_cea1cbed-056c-452c-9d15-d186fc274cab.wav", "formula": "$$p=\\frac{m}{v}$$", "answer": "p等于v分之m", "subset": "Physics700", "task_type": "tts"} +{"index": 400, "question": "Please read the following physics formula symbols: $$∆x=\\frac{L}{d}λ$$", "audio_path": "audio/physics_31e0dc09-ad2f-4559-9165-df4e056ebdf0.wav", "formula": "$$∆x=\\frac{L}{d}λ$$", "answer": "delta x equals L over d times lambda", "subset": "Physics700", "task_type": "tts"} +{"index": 401, "question": "Please read the following physics formula symbols: $7.5\\times10^{12}m^{3}$", "audio_path": "audio/physics_9bf3b0ec-9bad-4f67-a221-1cc9f7e661c6.wav", "formula": "$7.5\\times10^{12}m^{3}$", "answer": "seven point five times ten to the power of twelve times m cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 402, "question": "Please read the following physics formula symbols: $R=\\frac{P}{I^{2}}$", "audio_path": "audio/physics_8fd18f70-f6c5-4fc2-8d41-784745602ecd.wav", "formula": "$R=\\frac{P}{I^{2}}$", "answer": "R equals P over I squared", "subset": "Physics700", "task_type": "tts"} +{"index": 403, "question": "Please read the following physics formula symbols: $s=0.5*1.2*3^2=5.4m$", "audio_path": "audio/physics_e6fb1e7c-0e0a-4d9a-82a9-89acb407d775.wav", "formula": "$s=0.5*1.2*3^2=5.4m$", "answer": "s equals zero point five times one point two times three squared equals five point four m", "subset": "Physics700", "task_type": "tts"} +{"index": 404, "question": "请你朗读以下物理公式符号:$$\\overline{v}=\\frac{v_{0}+v}{2}$$", "audio_path": "audio/physics_77cec936-ef78-4ada-b75c-bd9588c00801.wav", "formula": "$$\\overline{v}=\\frac{v_{0}+v}{2}$$", "answer": "平均 v 等于二分之 v 零加 v 的和", "subset": "Physics700", "task_type": "tts"} +{"index": 405, "question": "请你朗读以下物理公式符号:$$f=\\frac{v}{λ}$$", "audio_path": "audio/physics_3c0f276a-89a2-4f13-8cd1-8d77bf659eb4.wav", "formula": "$$f=\\frac{v}{λ}$$", "answer": "f 等于 lambda分之v", "subset": "Physics700", "task_type": "tts"} +{"index": 406, "question": "Please read the following physics formula symbols: $$\\frac{△Φ}{△t}$$", "audio_path": "audio/physics_e4c4e5cb-8a40-4be6-b0db-5f169eca3fb5.wav", "formula": "$$\\frac{△Φ}{△t}$$", "answer": "delta phi over delta t", "subset": "Physics700", "task_type": "tts"} +{"index": 407, "question": "Please read the following physics formula symbols: $8.0 \\times 10^{7} J/kg$", "audio_path": "audio/physics_0b7fde80-201b-4c21-a983-6723d0415dc2.wav", "formula": "$8.0 \\times 10^{7} J/kg$", "answer": "eight point zero times ten to the power of seven joules over kilograms", "subset": "Physics700", "task_type": "tts"} +{"index": 408, "question": "请你朗读以下物理公式符号:$\\frac{\\left(M+m\\right)υ_{2}}{mυ_{1}}$", "audio_path": "audio/physics_c5bd9c3d-0d07-4ae7-8085-c1b1f00c13d3.wav", "formula": "$\\frac{\\left(M+m\\right)υ_{2}}{mυ_{1}}$", "answer": "m乘upsilon一的积分之M加m的和乘upsilon二", "subset": "Physics700", "task_type": "tts"} +{"index": 409, "question": "Please read the following physics formula symbols: $P_{max}={\\frac{E}{4r}}^{2}$", "audio_path": "audio/physics_4b652034-bf17-4b64-852f-459ca2bb1d6d.wav", "formula": "$P_{max}={\\frac{E}{4r}}^{2}$", "answer": "P sub max equals the quantity E over four r squared", "subset": "Physics700", "task_type": "tts"} +{"index": 410, "question": "Please read the following physics formula symbols: $I_{1}=4.4\\times10^{4}$", "audio_path": "audio/physics_43f3a668-8c58-49d9-8a3d-fbc3a5465dd3.wav", "formula": "$I_{1}=4.4\\times10^{4}$", "answer": "I one equals 4.4 times 10 to the power of 4", "subset": "Physics700", "task_type": "tts"} +{"index": 411, "question": "请你朗读以下物理公式符号:$$\\frac{v^{2}}{Rg}$$", "audio_path": "audio/physics_b9a1d591-0228-4c24-b498-0fcc99184abc.wav", "formula": "$$\\frac{v^{2}}{Rg}$$", "answer": "R乘g的积分之v平方", "subset": "Physics700", "task_type": "tts"} +{"index": 412, "question": "Please read the following physics formula symbols: $\\frac{30}{100}×\\left(1000ml−V\\right)$", "audio_path": "audio/physics_2491f6f5-6262-42c8-8aff-03a106632fa6.wav", "formula": "$\\frac{30}{100}×\\left(1000ml−V\\right)$", "answer": "thirty over one hundred times the difference between one thousand milliliters and V", "subset": "Physics700", "task_type": "tts"} +{"index": 413, "question": "Please read the following physics formula symbols: $I_{1}^{'}:I_{2}^{'}$", "audio_path": "audio/physics_8f70bc9b-2a63-4b12-84b4-15b07fe62d8d.wav", "formula": "$I_{1}^{'}:I_{2}^{'}$", "answer": "I one prime to I two prime", "subset": "Physics700", "task_type": "tts"} +{"index": 414, "question": "请你朗读以下物理公式符号:$$Δt=\\frac{Q}{Cm}$$", "audio_path": "audio/physics_51a4da43-b9f3-4358-a4ed-3397cb66414b.wav", "formula": "$$Δt=\\frac{Q}{Cm}$$", "answer": "delta t 等于Q除以c乘m的积", "subset": "Physics700", "task_type": "tts"} +{"index": 415, "question": "请你朗读以下物理公式符号:$$P=\\frac{F}{s \\frac{G}{s}}=\\frac{\\rho s h g}{s}=\\rho gh$$", "audio_path": "audio/physics_0c33dc00-14ec-4d76-91b2-389fe41fc70d.wav", "formula": "$$P=\\frac{F}{s \\frac{G}{s}}=\\frac{\\rho s h g}{s}=\\rho gh$$", "answer": "P等于s与s分之G的乘积分之F等于s分之rho乘 s乘 h乘 g等于rho乘g乘h", "subset": "Physics700", "task_type": "tts"} +{"index": 416, "question": "请你朗读以下物理公式符号:$−\\frac{3}{4}E_{1}$", "audio_path": "audio/physics_44399cef-10c7-4fd0-8aeb-419515a046d4.wav", "formula": "$−\\frac{3}{4}E_{1}$", "answer": "负的四分之三乘E 一", "subset": "Physics700", "task_type": "tts"} +{"index": 417, "question": "Please read the following physics formula symbols: $7.5\\times 10^{7} \\mathrm{J}/\\mathrm{m}^{3}$", "audio_path": "audio/physics_31c3370c-9a06-4569-a70b-760cb4e18aed.wav", "formula": "$7.5\\times 10^{7} \\mathrm{J}/\\mathrm{m}^{3}$", "answer": "seven point five times ten to the power of seven J over m cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 418, "question": "请你朗读以下物理公式符号:$$2.5×10^{3}kg/m^{3}$$", "audio_path": "audio/physics_a26fc433-c38e-4b8c-a81e-231b970343e3.wav", "formula": "$$2.5×10^{3}kg/m^{3}$$", "answer": "二点五乘十的三次方千克每立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 419, "question": "请你朗读以下物理公式符号:$\\frac{Nυ^{4}}{Gm}$", "audio_path": "audio/physics_7bf2916e-c438-423a-8a55-837853a27f5d.wav", "formula": "$\\frac{Nυ^{4}}{Gm}$", "answer": "G乘m分之N乘v的四次方", "subset": "Physics700", "task_type": "tts"} +{"index": 420, "question": "Please read the following physics formula symbols: $$1:\\left(\\sqrt{2}+1\\right)$$", "audio_path": "audio/physics_99e03be4-b072-4280-be52-4e1cbca3a985.wav", "formula": "$$1:\\left(\\sqrt{2}+1\\right)$$", "answer": "the sum of the square root of 2 and 1", "subset": "Physics700", "task_type": "tts"} +{"index": 421, "question": "Please read the following physics formula symbols: $h=\\frac{1}{2}gt^{2}$", "audio_path": "audio/physics_4e3e764f-601b-46fc-a994-03937230e34b.wav", "formula": "$h=\\frac{1}{2}gt^{2}$", "answer": "h equals one over two times g times t squared", "subset": "Physics700", "task_type": "tts"} +{"index": 422, "question": "Please read the following physics formula symbols: $\\frac{m}{r^{2}}$", "audio_path": "audio/physics_30c5072d-e20e-48a5-aef0-c8e6169f79b9.wav", "formula": "$\\frac{m}{r^{2}}$", "answer": "m over r squared", "subset": "Physics700", "task_type": "tts"} +{"index": 423, "question": "Please read the following physics formula symbols: $$1.0×10^{6}m/s$$", "audio_path": "audio/physics_6e42e55a-06a3-43d9-922a-dc8fa967a640.wav", "formula": "$$1.0×10^{6}m/s$$", "answer": "one point zero times ten to the power of six meters per second", "subset": "Physics700", "task_type": "tts"} +{"index": 424, "question": "Please read the following physics formula symbols: $$P=\\frac{W}{t}$$", "audio_path": "audio/physics_b7dc0962-6927-44af-953b-fe0a1dd1b6c6.wav", "formula": "$$P=\\frac{W}{t}$$", "answer": "P equals W over t", "subset": "Physics700", "task_type": "tts"} +{"index": 425, "question": "Please read the following physics formula symbols: $$t=\\frac{s}{v}$$", "audio_path": "audio/physics_e1989660-e869-48f6-8765-c03d9efbe4d0.wav", "formula": "$$t=\\frac{s}{v}$$", "answer": "t equals s over v", "subset": "Physics700", "task_type": "tts"} +{"index": 426, "question": "Please read the following physics formula symbols: $$x=A\\sin \\left(\\omega t+\\phi\\right)\\,\\mathrm{cm}$$", "audio_path": "audio/physics_694fdded-2826-4992-98a6-166114ed992c.wav", "formula": "$$x=A\\sin \\left(\\omega t+\\phi\\right)\\,\\mathrm{cm}$$", "answer": "x equals A times the sine of the sum of omega t and phi, in centimeters", "subset": "Physics700", "task_type": "tts"} +{"index": 427, "question": "Please read the following physics formula symbols: $\\frac{1}{2}aT^{2}$", "audio_path": "audio/physics_cd2625c9-3a18-4f0e-9a5c-6da69f027679.wav", "formula": "$\\frac{1}{2}aT^{2}$", "answer": "one half a T squared", "subset": "Physics700", "task_type": "tts"} +{"index": 428, "question": "请你朗读以下物理公式符号:$= 0.46 \\times 10^{3} \\, \\mathrm{J/(kg \\cdot \\degree C)}$", "audio_path": "audio/physics_2a7c78a2-ebb6-4401-abd7-dc96bd970ecc.wav", "formula": "$= 0.46 \\times 10^{3} \\, \\mathrm{J/(kg \\cdot \\degree C)}$", "answer": "等于零点四六乘十的三次方焦耳每千克摄氏度", "subset": "Physics700", "task_type": "tts"} +{"index": 429, "question": "Please read the following physics formula symbols: $E=\\frac{1}{2}mc^{2}$", "audio_path": "audio/physics_3a3b0da4-129e-4412-bffc-57b6d431ff67.wav", "formula": "$E=\\frac{1}{2}mc^{2}$", "answer": "E equals one half times m times c squared", "subset": "Physics700", "task_type": "tts"} +{"index": 430, "question": "Please read the following physics formula symbols: $1.16 \\times 10^{3} \\,\\mathrm{kg/m^{3}}$", "audio_path": "audio/physics_cbf03e0c-9bae-478a-bf2d-eea2c065b36d.wav", "formula": "$1.16 \\times 10^{3} \\,\\mathrm{kg/m^{3}}$", "answer": "one point one six times ten to the power of three kilograms per meter cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 431, "question": "请你朗读以下物理公式符号:$$\\frac{1}{3600}$$", "audio_path": "audio/physics_f4b583fc-98ea-4236-bf54-1aec5dc6e97b.wav", "formula": "$$\\frac{1}{3600}$$", "answer": "三千六百分之一", "subset": "Physics700", "task_type": "tts"} +{"index": 432, "question": "请你朗读以下物理公式符号:$$1.75×10^{3} kg/m^{3}$$", "audio_path": "audio/physics_01fca95b-b189-4257-9706-de42ee4ca48b.wav", "formula": "$$1.75×10^{3} kg/m^{3}$$", "answer": "一点七五乘十的三次方千克每立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 433, "question": "请你朗读以下物理公式符号:$$t=\\frac{s}{v}$$", "audio_path": "audio/physics_daba1925-423e-483c-ab98-6d3c8ea4137f.wav", "formula": "$$t=\\frac{s}{v}$$", "answer": "t等于v分之s", "subset": "Physics700", "task_type": "tts"} +{"index": 434, "question": "请你朗读以下物理公式符号:$ρ=\\frac{m_{1}-m_{2}}{V}$", "audio_path": "audio/physics_c82e5469-d6f3-4b3a-ae00-4932329383f6.wav", "formula": "$ρ=\\frac{m_{1}-m_{2}}{V}$", "answer": "rho等于V分之m一减m二的差", "subset": "Physics700", "task_type": "tts"} +{"index": 435, "question": "请你朗读以下物理公式符号:$$I=\\frac{P}{U}$$", "audio_path": "audio/physics_e237c66e-c299-4f91-a29a-76d323520843.wav", "formula": "$$I=\\frac{P}{U}$$", "answer": "I 等于 U 分之 P", "subset": "Physics700", "task_type": "tts"} +{"index": 436, "question": "Please read the following physics formula symbols: $$t=\\frac{4}{3}s$$", "audio_path": "audio/physics_9a12e161-3f55-422d-b2b6-5e0e22ff2370.wav", "formula": "$$t=\\frac{4}{3}s$$", "answer": "t equals four over three times s", "subset": "Physics700", "task_type": "tts"} +{"index": 437, "question": "Please read the following physics formula symbols: $1.6 \\times 10^{8} \\mathrm{J/kg}$", "audio_path": "audio/physics_c728ce3d-8723-470f-ade4-4774fe33fbc0.wav", "formula": "$1.6 \\times 10^{8} \\mathrm{J/kg}$", "answer": "1.6 times 10 to the power of 8 joules over kilograms", "subset": "Physics700", "task_type": "tts"} +{"index": 438, "question": "Please read the following physics formula symbols: $\\frac{3}{4}E_{1}$", "audio_path": "audio/physics_45ad4b34-1a6d-43f9-a1bf-e4dc03344db8.wav", "formula": "$\\frac{3}{4}E_{1}$", "answer": "three over four times E one", "subset": "Physics700", "task_type": "tts"} +{"index": 439, "question": "Please read the following physics formula symbols: $\\frac{v^{2}}{R}$", "audio_path": "audio/physics_6af98c5f-dd4f-4789-8c80-c3aa12cea4a6.wav", "formula": "$\\frac{v^{2}}{R}$", "answer": "u squared over R", "subset": "Physics700", "task_type": "tts"} +{"index": 440, "question": "Please read the following physics formula symbols: $\\frac{E_{1}}{4}$", "audio_path": "audio/physics_e224bf50-b81d-4a13-90c4-ec1cd226a6ea.wav", "formula": "$\\frac{E_{1}}{4}$", "answer": "E one over four", "subset": "Physics700", "task_type": "tts"} +{"index": 441, "question": "Please read the following physics formula symbols: $$m=\\frac{G}{g}$$", "audio_path": "audio/physics_41726f98-62ba-4815-a80f-013652e54142.wav", "formula": "$$m=\\frac{G}{g}$$", "answer": "m equals gravitational constant G over g", "subset": "Physics700", "task_type": "tts"} +{"index": 442, "question": "请你朗读以下物理公式符号:$c=3×10^{8}m/s$", "audio_path": "audio/physics_1528b415-8ee6-4b14-a392-3e36a11f09d0.wav", "formula": "$c=3×10^{8}m/s$", "answer": "c等于三乘十的八次方米每秒", "subset": "Physics700", "task_type": "tts"} +{"index": 443, "question": "请你朗读以下物理公式符号:$$t=\\frac{S}{V}$$", "audio_path": "audio/physics_7baf3cf0-857e-4c52-889c-d4102f75b213.wav", "formula": "$$t=\\frac{S}{V}$$", "answer": "t 等于 V 分之 S", "subset": "Physics700", "task_type": "tts"} +{"index": 444, "question": "Please read the following physics formula symbols: $$2.5×10^{3}kg/m^{3}$$", "audio_path": "audio/physics_2270d61c-0eec-44ff-83ae-adc458d33384.wav", "formula": "$$2.5×10^{3}kg/m^{3}$$", "answer": "two point five times ten to the power of three kilograms over meters cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 445, "question": "Please read the following physics formula symbols: $$f=\\frac{c}{λ}=\\frac{3×10^{8}m/s}{10m}$$", "audio_path": "audio/physics_df632f62-c35e-41eb-832c-d3b47b2aefcc.wav", "formula": "$$f=\\frac{c}{λ}=\\frac{3×10^{8}m/s}{10m}$$", "answer": "f equals speed of light c over lambda equals three times ten to the power of eight meters per second over ten meters", "subset": "Physics700", "task_type": "tts"} +{"index": 446, "question": "请你朗读以下物理公式符号:$\\frac{\\frac{Gh}{η}−Gh}{s}$", "audio_path": "audio/physics_8bedaa64-5d09-4b05-9511-d36cfda328a1.wav", "formula": "$\\frac{\\frac{Gh}{η}−Gh}{s}$", "answer": "s 分之 eta分之G乘h减去G乘h的差", "subset": "Physics700", "task_type": "tts"} +{"index": 447, "question": "Please read the following physics formula symbols: $$R_{1}:R_{2}=3:1$$", "audio_path": "audio/physics_8b87b36a-ced8-425a-bc67-7d3d9d52b5f2.wav", "formula": "$$R_{1}:R_{2}=3:1$$", "answer": "R one is to R two equals three is to one", "subset": "Physics700", "task_type": "tts"} +{"index": 448, "question": "Please read the following physics formula symbols: $$_{1}^{1}H^{+} + _{1}^{3}\\vec{H} \\rightarrow _{2}^{4}He^{+} + _{0}^{1}n$$", "audio_path": "audio/physics_521687f8-a293-4a3a-9ba5-ec40598789c4.wav", "formula": "$$_{1}^{1}H^{+} + _{1}^{3}\\vec{H} \\rightarrow _{2}^{4}He^{+} + _{0}^{1}n$$", "answer": "hydrogen one plus ion plus hydrogen three reacts to form helium four plus ion and neutron", "subset": "Physics700", "task_type": "tts"} +{"index": 449, "question": "Please read the following physics formula symbols: $−\\frac{3}{4}E_{1}$", "audio_path": "audio/physics_84db17d0-4371-4069-94d7-fb4ab8aada31.wav", "formula": "$−\\frac{3}{4}E_{1}$", "answer": "Negative three over four times E one", "subset": "Physics700", "task_type": "tts"} +{"index": 450, "question": "请你朗读以下物理公式符号:$$I=I_{1}+I_{2}$$", "audio_path": "audio/physics_24c4ad27-b19a-49d3-b06c-3253d5fbf10b.wav", "formula": "$$I=I_{1}+I_{2}$$", "answer": "I 等于 I 一加 I 二", "subset": "Physics700", "task_type": "tts"} +{"index": 451, "question": "Please read the following physics formula symbols: $m = 0.02\\,kg$, $k = 250\\,N/m$", "audio_path": "audio/physics_4ae7c037-8202-477e-8e13-378e7e8d8a87.wav", "formula": "$m = 0.02\\,kg$, $k = 250\\,N/m$", "answer": "m equals zero point zero two kilograms, k equals two hundred and fifty newtons per meter", "subset": "Physics700", "task_type": "tts"} +{"index": 452, "question": "Please read the following physics formula symbols: $$U=\\frac{W_{AB}}{q}$$", "audio_path": "audio/physics_cb380d27-5f64-4aae-b8f0-c8e7f9e05520.wav", "formula": "$$U=\\frac{W_{AB}}{q}$$", "answer": "U equals W A B over q", "subset": "Physics700", "task_type": "tts"} +{"index": 453, "question": "Please read the following physics formula symbols: $3.4×10^{7}J/kg$", "audio_path": "audio/physics_a6795163-e4fb-4397-a764-2ab88c93c5c9.wav", "formula": "$3.4×10^{7}J/kg$", "answer": "three point four times ten to the power of seven joules per kilogram", "subset": "Physics700", "task_type": "tts"} +{"index": 454, "question": "Please read the following physics formula symbols: $$1.01 \\times 10^{5} \\mathrm{Pa}$$", "audio_path": "audio/physics_8c4b243b-86aa-455c-bfbe-a33603c57ad7.wav", "formula": "$$1.01 \\times 10^{5} \\mathrm{Pa}$$", "answer": "1.01 times 10 to the power of 5 pascals", "subset": "Physics700", "task_type": "tts"} +{"index": 455, "question": "Please read the following physics formula symbols: $$η=\\frac{Gh}{\\left(G+f\\right)L}$$", "audio_path": "audio/physics_156ea58e-9c05-4088-a542-11d741a7ab5d.wav", "formula": "$$η=\\frac{Gh}{\\left(G+f\\right)L}$$", "answer": "eta equals gravitational constant G times Planck's constant h over the sum of gravitational constant G and f multiplied by L", "subset": "Physics700", "task_type": "tts"} +{"index": 456, "question": "Please read the following physics formula symbols: $$10^{14} m^{2}$$", "audio_path": "audio/physics_809fbce0-d539-4c8c-90af-40fb8e2dbdb9.wav", "formula": "$$10^{14} m^{2}$$", "answer": "ten to the power of fourteen times m squared", "subset": "Physics700", "task_type": "tts"} +{"index": 457, "question": "请你朗读以下物理公式符号:$s=0.5*1.2*3^2=5.4m$", "audio_path": "audio/physics_af8a5eab-9e8e-43a0-8de4-91d86f31d8d6.wav", "formula": "$s=0.5*1.2*3^2=5.4m$", "answer": "s等于零点五乘一点二乘三的平方等于五点四米", "subset": "Physics700", "task_type": "tts"} +{"index": 458, "question": "请你朗读以下物理公式符号:$$0.8×10^{3}kg/m^{3}$$", "audio_path": "audio/physics_83d7274b-dd33-42e1-9dc5-5a06fe3583a7.wav", "formula": "$$0.8×10^{3}kg/m^{3}$$", "answer": "零点八乘十的三次方千克每立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 459, "question": "Please read the following physics formula symbols: $\\frac{π^{2}\\left(4R+ct\\right)^{3}}{2GT^{2}}$", "audio_path": "audio/physics_cedef789-407e-44ae-93f6-1538fd7bd9e0.wav", "formula": "$\\frac{π^{2}\\left(4R+ct\\right)^{3}}{2GT^{2}}$", "answer": "pi squared times the cube of the sum of four R and c t, over two times gravitational constant G times T squared", "subset": "Physics700", "task_type": "tts"} +{"index": 460, "question": "Please read the following physics formula symbols: $$m=\\frac{Q}{c\\left(t−t_{0}\\right)}$$", "audio_path": "audio/physics_cd71cd23-a69d-4e92-b1ae-b5af104a6eb8.wav", "formula": "$$m=\\frac{Q}{c\\left(t−t_{0}\\right)}$$", "answer": "m equals Q over speed of light c times the difference between t and t naught", "subset": "Physics700", "task_type": "tts"} +{"index": 461, "question": "请你朗读以下物理公式符号:$\\frac{λPΔt}{hc}$", "audio_path": "audio/physics_8ba17ff0-6057-4615-aad0-b796707113e3.wav", "formula": "$\\frac{λPΔt}{hc}$", "answer": "h乘c的积分之lambda乘P乘delta t", "subset": "Physics700", "task_type": "tts"} +{"index": 462, "question": "Please read the following physics formula symbols: $\\frac{3gt^{2}}{8}$", "audio_path": "audio/physics_422949cc-80ee-4fa6-8714-ec700d8b4c2b.wav", "formula": "$\\frac{3gt^{2}}{8}$", "answer": "three g t squared over eight", "subset": "Physics700", "task_type": "tts"} +{"index": 463, "question": "Please read the following physics formula symbols: $$E=h \\gamma=h\\frac{c}{\\lambda}$$", "audio_path": "audio/physics_a968b58b-ce49-433e-b1d2-38e88acf6302.wav", "formula": "$$E=h \\gamma=h\\frac{c}{\\lambda}$$", "answer": "E equals Planck's constant h times gamma equals Planck's constant h times c over lambda", "subset": "Physics700", "task_type": "tts"} +{"index": 464, "question": "Please read the following physics formula symbols: $W=\\frac{U^{2}}{R}t$", "audio_path": "audio/physics_6c9ed5be-7120-4005-801d-63464e323a3f.wav", "formula": "$W=\\frac{U^{2}}{R}t$", "answer": "W equals U squared over R times t", "subset": "Physics700", "task_type": "tts"} +{"index": 465, "question": "Please read the following physics formula symbols: $\\frac{n^{2}h^{2}}{med^{2}}$", "audio_path": "audio/physics_d4f47bf6-468e-4f69-8eaa-169d8a6becde.wav", "formula": "$\\frac{n^{2}h^{2}}{med^{2}}$", "answer": "n squared times h squared over m times e times d squared", "subset": "Physics700", "task_type": "tts"} +{"index": 466, "question": "请你朗读以下物理公式符号:$$0.92\\times 10^{3}kg/m^{3}$$", "audio_path": "audio/physics_3d9ac87f-2fb1-464c-bb85-533d2d95c6e7.wav", "formula": "$$0.92\\times 10^{3}kg/m^{3}$$", "answer": "零点九二乘十的三次方千克每立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 467, "question": "Please read the following physics formula symbols: $$\\frac{1}{3.6}$$", "audio_path": "audio/physics_392f1dc6-532e-461a-80bb-7f2bcb7cd513.wav", "formula": "$$\\frac{1}{3.6}$$", "answer": "one over three point six", "subset": "Physics700", "task_type": "tts"} +{"index": 468, "question": "Please read the following physics formula symbols: $$mgh=mv^{2}/2$$", "audio_path": "audio/physics_ca8b98f5-78f5-4cd0-9b9c-816d2b180978.wav", "formula": "$$mgh=mv^{2}/2$$", "answer": "m times g times h equals m times v squared over two", "subset": "Physics700", "task_type": "tts"} +{"index": 469, "question": "请你朗读以下物理公式符号:$$d=\\frac{1}{10}L$$", "audio_path": "audio/physics_dd3bdace-42d0-4329-bb07-4c6007e21ef3.wav", "formula": "$$d=\\frac{1}{10}L$$", "answer": "d等于十分之一乘L", "subset": "Physics700", "task_type": "tts"} +{"index": 470, "question": "Please read the following physics formula symbols: $$Q=UIt=\\frac{U^{2}}{R}t$$", "audio_path": "audio/physics_35e71109-a2a8-47a3-b381-8b1922f141ab.wav", "formula": "$$Q=UIt=\\frac{U^{2}}{R}t$$", "answer": "Q equals U times I times t equals U squared over R times t", "subset": "Physics700", "task_type": "tts"} +{"index": 471, "question": "请你朗读以下物理公式符号:$\\frac{1}{6}m^{3}$", "audio_path": "audio/physics_3436309e-ac64-4149-9a9c-37815782cee7.wav", "formula": "$\\frac{1}{6}m^{3}$", "answer": "六分之一立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 472, "question": "Please read the following physics formula symbols: $$1.26×10^{4} J$$", "audio_path": "audio/physics_2c5f6466-9ae7-4e1c-a1fc-40e83d680fe3.wav", "formula": "$$1.26×10^{4} J$$", "answer": "one point two six times ten to the power of four joules", "subset": "Physics700", "task_type": "tts"} +{"index": 473, "question": "Please read the following physics formula symbols: $$10^{-4} m^{3}$$", "audio_path": "audio/physics_28642ebc-a25e-4433-b4ff-d35daa91e520.wav", "formula": "$$10^{-4} m^{3}$$", "answer": "10 to the power of negative four times m cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 474, "question": "请你朗读以下物理公式符号:$$1.03×10^{3}kg∕m^{3}$$", "audio_path": "audio/physics_69726f53-8fb5-454a-91f3-adf4e8a26cc1.wav", "formula": "$$1.03×10^{3}kg∕m^{3}$$", "answer": "一点零三乘十的三次方千克每立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 475, "question": "Please read the following physics formula symbols: $0.8×10^{3}kg/m^{3}$", "audio_path": "audio/physics_d6e68c7c-80e0-4e7c-8126-e9d82b2bc18e.wav", "formula": "$0.8×10^{3}kg/m^{3}$", "answer": "zero point eight times ten cubed kilograms over meters cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 476, "question": "请你朗读以下物理公式符号:$$\\frac{U^{2}}{P}$$", "audio_path": "audio/physics_44055746-6614-488b-9ece-301d238841c8.wav", "formula": "$$\\frac{U^{2}}{P}$$", "answer": "P 分之 U 平方", "subset": "Physics700", "task_type": "tts"} +{"index": 477, "question": "请你朗读以下物理公式符号:$$P=\\frac{U^{2}}{R}$$", "audio_path": "audio/physics_a4cecbe0-36fe-4c62-8bf7-4c563bb5eea6.wav", "formula": "$$P=\\frac{U^{2}}{R}$$", "answer": "P 等于 R 分之 U 平方", "subset": "Physics700", "task_type": "tts"} +{"index": 478, "question": "请你朗读以下物理公式符号:$P=\\frac{U^{2}}{R}$", "audio_path": "audio/physics_53229bc2-d604-437d-b2a7-0f8dec7e8375.wav", "formula": "$P=\\frac{U^{2}}{R}$", "answer": "P 等于 R 分之 U 平方", "subset": "Physics700", "task_type": "tts"} +{"index": 479, "question": "请你朗读以下物理公式符号:$$Q=W=Pt=\\frac{U^{2}}{R}t$$", "audio_path": "audio/physics_c6203ce5-857e-488b-ba18-562d1996aef3.wav", "formula": "$$Q=W=Pt=\\frac{U^{2}}{R}t$$", "answer": "Q 等于 W 等于 P 乘 t 等于 R 分之 U 平方 乘 t", "subset": "Physics700", "task_type": "tts"} +{"index": 480, "question": "请你朗读以下物理公式符号:$R=\\frac{U^{2}}{P}$", "audio_path": "audio/physics_27e77e63-1481-4fc3-8b95-8a6a51680a36.wav", "formula": "$R=\\frac{U^{2}}{P}$", "answer": "R 等于 P 分之 U 平方", "subset": "Physics700", "task_type": "tts"} +{"index": 481, "question": "Please read the following physics formula symbols: $\\frac{Q_{2}}{r^{2}}$", "audio_path": "audio/physics_1916e2ae-acd5-4cf9-a77d-99c08b938f47.wav", "formula": "$\\frac{Q_{2}}{r^{2}}$", "answer": "Q two over r squared", "subset": "Physics700", "task_type": "tts"} +{"index": 482, "question": "Please read the following physics formula symbols: $R=\\frac{U^{2}}{P}$", "audio_path": "audio/physics_0f4894d2-fdbc-4dce-be41-209c3701afe2.wav", "formula": "$R=\\frac{U^{2}}{P}$", "answer": "R equals U squared over P", "subset": "Physics700", "task_type": "tts"} +{"index": 483, "question": "Please read the following physics formula symbols: $\\frac{4π^{2}mr}{T^{2}}$", "audio_path": "audio/physics_e8c3a050-0e8d-481f-a84a-c3f7f62e2518.wav", "formula": "$\\frac{4π^{2}mr}{T^{2}}$", "answer": "4 times pi squared times m times r over T squared", "subset": "Physics700", "task_type": "tts"} +{"index": 484, "question": "Please read the following physics formula symbols: $10^{3}kg/m^{3}$", "audio_path": "audio/physics_31f6c5d6-43cd-4ebd-89b8-cfe81c880f30.wav", "formula": "$10^{3}kg/m^{3}$", "answer": "ten cubed kilograms over meters cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 485, "question": "请你朗读以下物理公式符号:$2S=S_{1}+S_{2}$", "audio_path": "audio/physics_129c7b7f-be31-4a96-a3cf-6800242fcf14.wav", "formula": "$2S=S_{1}+S_{2}$", "answer": "二 S 等于 S 一加 S 二", "subset": "Physics700", "task_type": "tts"} +{"index": 486, "question": "请你朗读以下物理公式符号:$2000J/\\left(s·m^{2}\\right)$", "audio_path": "audio/physics_5322af03-5004-46f4-b91c-7e96d2187a56.wav", "formula": "$2000J/\\left(s·m^{2}\\right)$", "answer": "两千焦耳每秒每平方米", "subset": "Physics700", "task_type": "tts"} +{"index": 487, "question": "Please read the following physics formula symbols: $$\\frac{a^{3}}{T^{2}}$$", "audio_path": "audio/physics_de03ad6b-6dd6-4a3c-afcb-afdef700ed8a.wav", "formula": "$$\\frac{a^{3}}{T^{2}}$$", "answer": "a cubed over T squared", "subset": "Physics700", "task_type": "tts"} +{"index": 488, "question": "请你朗读以下物理公式符号:$$\\frac{r^{3}}{T^{2}}$$", "audio_path": "audio/physics_08e0d676-c817-4667-afa0-d33b7a4a2b65.wav", "formula": "$$\\frac{r^{3}}{T^{2}}$$", "answer": "T 的平方分之 r 的立方", "subset": "Physics700", "task_type": "tts"} +{"index": 489, "question": "Please read the following physics formula symbols: $\\frac{Q_{1}}{r^{2}}$", "audio_path": "audio/physics_ae2f8739-5936-417b-969c-f6bf41721394.wav", "formula": "$\\frac{Q_{1}}{r^{2}}$", "answer": "Q one over r squared", "subset": "Physics700", "task_type": "tts"} +{"index": 490, "question": "请你朗读以下物理公式符号:$\\frac{4H}{T_{2}^{2}-T_{1}^{2}}$", "audio_path": "audio/physics_2bad87ae-ad69-4265-abfa-51338c7b5501.wav", "formula": "$\\frac{4H}{T_{2}^{2}-T_{1}^{2}}$", "answer": "T 二平方减 T 一平方的差分之 四乘H", "subset": "Physics700", "task_type": "tts"} +{"index": 491, "question": "请你朗读以下物理公式符号:$\\frac{k}{T^{2}}$", "audio_path": "audio/physics_f8b267ba-e435-4525-bb92-e1a6dfef796d.wav", "formula": "$\\frac{k}{T^{2}}$", "answer": "T的平方分之k", "subset": "Physics700", "task_type": "tts"} +{"index": 492, "question": "Please read the following physics formula symbols: $\\frac{d^{2}h^{2}}{2men^{2}}$", "audio_path": "audio/physics_0a001af5-7cbe-43b0-8e91-341cdb7f2655.wav", "formula": "$\\frac{d^{2}h^{2}}{2men^{2}}$", "answer": "d squared times h squared over two times m times e times n squared", "subset": "Physics700", "task_type": "tts"} +{"index": 493, "question": "请你朗读以下物理公式符号:$$I=\\frac{U}{R}$$", "audio_path": "audio/physics_8f73a20e-b5b1-46e3-b408-2149ae42b848.wav", "formula": "$$I=\\frac{U}{R}$$", "answer": "I等于R分之U", "subset": "Physics700", "task_type": "tts"} +{"index": 494, "question": "请你朗读以下物理公式符号:$$\\frac{1.2}{0.1^{2}}$$", "audio_path": "audio/physics_209bd054-93f0-49d4-95c2-b13aeaf0a7be.wav", "formula": "$$\\frac{1.2}{0.1^{2}}$$", "answer": "零点一的平方分之一点二", "subset": "Physics700", "task_type": "tts"} +{"index": 495, "question": "Please read the following physics formula symbols: $$h=\\frac{1}{2}gt^{2}$$", "audio_path": "audio/physics_0f97b577-de72-4ebc-a7af-a90abf9bb4d0.wav", "formula": "$$h=\\frac{1}{2}gt^{2}$$", "answer": "h equals one over two times g times t squared", "subset": "Physics700", "task_type": "tts"} +{"index": 496, "question": "Please read the following physics formula symbols: $v = 40 \\, \\text{m/s}, D. a = 1 \\, \\text{m/s}$", "audio_path": "audio/physics_eddcf08e-4dcc-44c5-8086-7d3c5340bdd4.wav", "formula": "$v = 40 \\, \\text{m/s}, D. a = 1 \\, \\text{m/s}$", "answer": "v equals forty meters per second, D times a equals one meter per second", "subset": "Physics700", "task_type": "tts"} +{"index": 497, "question": "Please read the following physics formula symbols: $\\frac{\\frac{Gh}{η}+Gh}{s}$", "audio_path": "audio/physics_41223879-b2ea-4ec3-a0ea-111592a09874.wav", "formula": "$\\frac{\\frac{Gh}{η}+Gh}{s}$", "answer": "the sum of G times h over eta and G times h, over s", "subset": "Physics700", "task_type": "tts"} +{"index": 498, "question": "请你朗读以下物理公式符号:$$Q=cm\\left(t−t_{0}\\right)$$", "audio_path": "audio/physics_3120c294-3431-4b13-a9e4-99d80f557ed5.wav", "formula": "$$Q=cm\\left(t−t_{0}\\right)$$", "answer": "Q 等于c乘m乘t减t零的差", "subset": "Physics700", "task_type": "tts"} +{"index": 499, "question": "请你朗读以下物理公式符号:$$\\frac{υ_{t}-υ_{0}}{t}$$", "audio_path": "audio/physics_f1ebe4b2-453d-44dd-9ef9-55cfcf3e5a50.wav", "formula": "$$\\frac{υ_{t}-υ_{0}}{t}$$", "answer": "t 分之 v t 减v 零的差", "subset": "Physics700", "task_type": "tts"} +{"index": 500, "question": "请你朗读以下物理公式符号:$\\frac{n^{2}h^{2}}{med^{2}}$", "audio_path": "audio/physics_cfae3e15-571e-47bd-92cf-f8ded6ee2a24.wav", "formula": "$\\frac{n^{2}h^{2}}{med^{2}}$", "answer": "n平方乘h平方的积除以m乘e乘d平方的积", "subset": "Physics700", "task_type": "tts"} +{"index": 501, "question": "请你朗读以下物理公式符号:$I_{1}^{'}:I_{2}^{'}$", "audio_path": "audio/physics_918058c7-00c7-4001-8bc9-0072e81caa1d.wav", "formula": "$I_{1}^{'}:I_{2}^{'}$", "answer": "I 一 撇 比 I 二 撇", "subset": "Physics700", "task_type": "tts"} +{"index": 502, "question": "Please read the following physics formula symbols: $1.0×10^{3}kg/m^{3}$", "audio_path": "audio/physics_7ff13b77-b192-41e6-ae32-e77d09ee4a13.wav", "formula": "$1.0×10^{3}kg/m^{3}$", "answer": "one point zero times ten cubed k g over m cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 503, "question": "Please read the following physics formula symbols: $I_{2}=2.2×10^{3}$", "audio_path": "audio/physics_fa851dd9-ffa9-4dff-9f61-29b975e862dc.wav", "formula": "$I_{2}=2.2×10^{3}$", "answer": "I two equals two point two times ten cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 504, "question": "Please read the following physics formula symbols: $$\\overline{v}=\\frac{v_{0}+v}{2}$$", "audio_path": "audio/physics_0dbe4e67-c9ea-423e-a3be-378d49688f4b.wav", "formula": "$$\\overline{v}=\\frac{v_{0}+v}{2}$$", "answer": "v bar equals v naught plus v over two", "subset": "Physics700", "task_type": "tts"} +{"index": 505, "question": "Please read the following physics formula symbols: $$η=\\frac{Gh}{Fnh}$$", "audio_path": "audio/physics_d50ef6c6-aa58-4360-99ae-c1b69dd2a8d5.wav", "formula": "$$η=\\frac{Gh}{Fnh}$$", "answer": "eta equals gravitational constant G times Planck's constant h over F times n times Planck's constant h", "subset": "Physics700", "task_type": "tts"} +{"index": 506, "question": "Please read the following physics formula symbols: $S = v_{0}t + \\frac{1}{2}at^{2}$", "audio_path": "audio/physics_a53f8784-d4b4-4948-ae4d-5412f8890f10.wav", "formula": "$S = v_{0}t + \\frac{1}{2}at^{2}$", "answer": "S equals v naught t plus one over two times a times t squared", "subset": "Physics700", "task_type": "tts"} +{"index": 507, "question": "请你朗读以下物理公式符号:$2.7×10^{3}kg/m^{3}$", "audio_path": "audio/physics_11d2f90b-9eb2-40df-8e62-ac4a12a37b88.wav", "formula": "$2.7×10^{3}kg/m^{3}$", "answer": "二点七乘十的三次方千克每立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 508, "question": "请你朗读以下物理公式符号:$\\frac{N\\upsilon^{2}}{Gm}$", "audio_path": "audio/physics_8ad75de2-cd24-4458-b940-fd25b05baf75.wav", "formula": "$\\frac{N\\upsilon^{2}}{Gm}$", "answer": "G乘m 分之 N乘v平方", "subset": "Physics700", "task_type": "tts"} +{"index": 509, "question": "请你朗读以下物理公式符号:$$\\frac{PV}{T}=C$$", "audio_path": "audio/physics_201b5985-4b89-44c9-bd29-23f847b4a3ac.wav", "formula": "$$\\frac{PV}{T}=C$$", "answer": "T 分之 P乘 V 等于 C", "subset": "Physics700", "task_type": "tts"} +{"index": 510, "question": "Please read the following physics formula symbols: $0.8×10^{3} kg/m^{3}$", "audio_path": "audio/physics_177fd265-6c43-461e-843e-6d3be117d422.wav", "formula": "$0.8×10^{3} kg/m^{3}$", "answer": "zero point eight times ten to the power of three kilogram over meter cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 511, "question": "请你朗读以下物理公式符号:$$g=G\\frac{M}{R^{2}}$$", "audio_path": "audio/physics_66e22cf4-1196-4872-84b9-17fd7d0d9451.wav", "formula": "$$g=G\\frac{M}{R^{2}}$$", "answer": "g等于G乘R平方分之M", "subset": "Physics700", "task_type": "tts"} +{"index": 512, "question": "Please read the following physics formula symbols: $\\frac{Mυ_{1}}{mυ_{2}}$", "audio_path": "audio/physics_9ba97019-69f8-4bb8-9da0-31300a8d7318.wav", "formula": "$\\frac{Mυ_{1}}{mυ_{2}}$", "answer": "M times upsilon one over m times upsilon two", "subset": "Physics700", "task_type": "tts"} +{"index": 513, "question": "请你朗读以下物理公式符号:$\\frac{8H}{\\left(T_{2}−T_{1}\\right)^{2}}$", "audio_path": "audio/physics_0bdd6677-a281-451d-9e59-f3e1657c193c.wav", "formula": "$\\frac{8H}{\\left(T_{2}−T_{1}\\right)^{2}}$", "answer": "T 二减 T 一差的平方 分之 八乘H", "subset": "Physics700", "task_type": "tts"} +{"index": 514, "question": "Please read the following physics formula symbols: $$C=\\frac{Q}{U}$$", "audio_path": "audio/physics_107c36a1-77d1-4811-bd83-9dd1941b5afc.wav", "formula": "$$C=\\frac{Q}{U}$$", "answer": "C equals Q over U", "subset": "Physics700", "task_type": "tts"} +{"index": 515, "question": "请你朗读以下物理公式符号:$U=\\frac{P}{I}$", "audio_path": "audio/physics_d29604e1-0206-4a13-b6a4-e103ea95bbe4.wav", "formula": "$U=\\frac{P}{I}$", "answer": "U等于I分之P", "subset": "Physics700", "task_type": "tts"} +{"index": 516, "question": "Please read the following physics formula symbols: $$c=3×10^{8} m/s$$", "audio_path": "audio/physics_fc320609-f240-481e-93b9-2650db959d94.wav", "formula": "$$c=3×10^{8} m/s$$", "answer": "speed of light c equals three times ten to the power of eight meters per second", "subset": "Physics700", "task_type": "tts"} +{"index": 517, "question": "请你朗读以下物理公式符号:$$\\frac{∆v}{∆t}$$", "audio_path": "audio/physics_a7c8d04c-fbeb-4b93-99a8-bb930023439e.wav", "formula": "$$\\frac{∆v}{∆t}$$", "answer": "delta t分之delta v", "subset": "Physics700", "task_type": "tts"} +{"index": 518, "question": "请你朗读以下物理公式符号:$4.2×10^{3}J/\\left(kg·℃\\right)$", "audio_path": "audio/physics_e552d3eb-a460-4bd4-aede-215792f8413a.wav", "formula": "$4.2×10^{3}J/\\left(kg·℃\\right)$", "answer": "四点二乘十的三次方焦耳每千克摄氏度", "subset": "Physics700", "task_type": "tts"} +{"index": 519, "question": "请你朗读以下物理公式符号:$$ω=\\frac{2π}{T}$$", "audio_path": "audio/physics_6ef17ad4-fc12-488b-93e4-571e39027e59.wav", "formula": "$$ω=\\frac{2π}{T}$$", "answer": "omega等于T分之二pi", "subset": "Physics700", "task_type": "tts"} +{"index": 520, "question": "Please read the following physics formula symbols: $$P =\\frac{F}{S}$$", "audio_path": "audio/physics_8f7b4814-7f3b-4095-8bf3-e16ff1d965b9.wav", "formula": "$$P =\\frac{F}{S}$$", "answer": "P equals F over S", "subset": "Physics700", "task_type": "tts"} +{"index": 521, "question": "请你朗读以下物理公式符号:$\\frac{hc}{λPΔt}$", "audio_path": "audio/physics_aaa2ae0b-8dba-492b-a521-93fa62d8a7ff.wav", "formula": "$\\frac{hc}{λPΔt}$", "answer": "lambda乘P乘delta t的积分之h乘c", "subset": "Physics700", "task_type": "tts"} +{"index": 522, "question": "请你朗读以下物理公式符号:$\\frac{30}{100}×\\left(1000ml−V\\right)$", "audio_path": "audio/physics_09914652-3981-4cec-b46f-63a20fd2c132.wav", "formula": "$\\frac{30}{100}×\\left(1000ml−V\\right)$", "answer": "一百分之三十乘一千毫升减V的差", "subset": "Physics700", "task_type": "tts"} +{"index": 523, "question": "请你朗读以下物理公式符号:$\\frac{△v}{∆t}$", "audio_path": "audio/physics_1d4b3e40-c819-48af-9f29-c25b586dc146.wav", "formula": "$\\frac{△v}{∆t}$", "answer": "delta t 分之 delta v", "subset": "Physics700", "task_type": "tts"} +{"index": 524, "question": "Please read the following physics formula symbols: $\\frac{v_{2}-v_{1}}{t}$", "audio_path": "audio/physics_910a0334-861e-4680-9543-8b4def9b62ec.wav", "formula": "$\\frac{v_{2}-v_{1}}{t}$", "answer": "the difference between v two and v one over t", "subset": "Physics700", "task_type": "tts"} +{"index": 525, "question": "请你朗读以下物理公式符号:$Q=\\frac{U^{2}}{R}t$", "audio_path": "audio/physics_9b8cd690-81e7-4fe9-ba83-650a9c5877ff.wav", "formula": "$Q=\\frac{U^{2}}{R}t$", "answer": "Q等于R分之U平方乘t", "subset": "Physics700", "task_type": "tts"} +{"index": 526, "question": "请你朗读以下物理公式符号:$\\frac{1}{2}aT^{2}$", "audio_path": "audio/physics_2abaa3bc-078a-485c-89b2-fc04936af9b8.wav", "formula": "$\\frac{1}{2}aT^{2}$", "answer": "二分之一乘a乘T平方", "subset": "Physics700", "task_type": "tts"} +{"index": 527, "question": "请你朗读以下物理公式符号:$I_{2}=2.2×10^{3}$", "audio_path": "audio/physics_be5c429f-aa69-4649-b269-dd43d950d35e.wav", "formula": "$I_{2}=2.2×10^{3}$", "answer": "I二等于二点二乘十的三次方", "subset": "Physics700", "task_type": "tts"} +{"index": 528, "question": "Please read the following physics formula symbols: $$ρ=0.7\\times 10^{3}kg/m^{3}$$", "audio_path": "audio/physics_ee461a17-cc31-4429-823a-4d8b041c1804.wav", "formula": "$$ρ=0.7\\times 10^{3}kg/m^{3}$$", "answer": "rho equals zero point seven times ten cubed kilogram over meter cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 529, "question": "Please read the following physics formula symbols: $$\\frac{Δv}{Δt}$$", "audio_path": "audio/physics_ab923630-52c4-4ee2-ad6e-c9351b9efee9.wav", "formula": "$$\\frac{Δv}{Δt}$$", "answer": "delta v over delta t", "subset": "Physics700", "task_type": "tts"} +{"index": 530, "question": "Please read the following physics formula symbols: $$7×10^{7}J/m^{3}$$", "audio_path": "audio/physics_67d21b5c-a321-4835-94c5-3a2ee9b12137.wav", "formula": "$$7×10^{7}J/m^{3}$$", "answer": "seven times ten to the power of seven J over m cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 531, "question": "Please read the following physics formula symbols: $$I=\\frac{q}{t}$$", "audio_path": "audio/physics_d9c8e256-b429-43dc-a786-39a3a44b1990.wav", "formula": "$$I=\\frac{q}{t}$$", "answer": "I equals q over t", "subset": "Physics700", "task_type": "tts"} +{"index": 532, "question": "Please read the following physics formula symbols: $$\\frac{m\\upsilon^{2}}{GN}$$", "audio_path": "audio/physics_e5838cb3-7633-41e9-ba1c-bee8d698e256.wav", "formula": "$$\\frac{m\\upsilon^{2}}{GN}$$", "answer": "m upsilon squared over gravitational constant G times N", "subset": "Physics700", "task_type": "tts"} +{"index": 533, "question": "请你朗读以下物理公式符号:$\\frac{Q}{r^{2}}$", "audio_path": "audio/physics_30c7a755-b612-478b-82b6-73872dd0220f.wav", "formula": "$\\frac{Q}{r^{2}}$", "answer": "r的平方分之Q", "subset": "Physics700", "task_type": "tts"} +{"index": 534, "question": "请你朗读以下物理公式符号:$$ρ=\\frac{m}{v}$$", "audio_path": "audio/physics_131da0e8-2340-49f0-9a1f-0411752d4c18.wav", "formula": "$$ρ=\\frac{m}{v}$$", "answer": "rho等于v分之m", "subset": "Physics700", "task_type": "tts"} +{"index": 535, "question": "Please read the following physics formula symbols: $$p=\\frac{m}{v}$$", "audio_path": "audio/physics_aa541f9a-cf58-46d1-84af-eabc7566fa7f.wav", "formula": "$$p=\\frac{m}{v}$$", "answer": "p equals m over v", "subset": "Physics700", "task_type": "tts"} +{"index": 536, "question": "Please read the following physics formula symbols: $$10^{-2} m^{3}$$", "audio_path": "audio/physics_647d8174-3721-440a-b929-9f4475e9ab12.wav", "formula": "$$10^{-2} m^{3}$$", "answer": "10 to the power of negative 2 times m cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 537, "question": "Please read the following physics formula symbols: $2.9×10^{7} J/kg$", "audio_path": "audio/physics_b52c324d-101c-4e22-9355-0ffe67c1b002.wav", "formula": "$2.9×10^{7} J/kg$", "answer": "2.9 times 10 to the power of seven joules per kilogram", "subset": "Physics700", "task_type": "tts"} +{"index": 538, "question": "请你朗读以下物理公式符号:$\\left(g−\\frac{v^{2}}{R}\\right)$", "audio_path": "audio/physics_e7575190-e019-4b67-96aa-e2f436356e17.wav", "formula": "$\\left(g−\\frac{v^{2}}{R}\\right)$", "answer": "g 减去 R 分之 v 平方", "subset": "Physics700", "task_type": "tts"} +{"index": 539, "question": "Please read the following physics formula symbols: $$10^{-3} m^{3}$$", "audio_path": "audio/physics_6868d781-ab7f-4c7f-aba8-117d057e72bb.wav", "formula": "$$10^{-3} m^{3}$$", "answer": "10 to the power of negative three times m cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 540, "question": "请你朗读以下物理公式符号:$$10^{-3} m^{3}$$", "audio_path": "audio/physics_194cbf30-2467-49f7-a0d6-aa02ffd589ed.wav", "formula": "$$10^{-3} m^{3}$$", "answer": "十的负三次方立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 541, "question": "请你朗读以下物理公式符号:$4.6\\times10^{7}J/kg$", "audio_path": "audio/physics_6e019336-0313-4119-be29-5ec006ab609f.wav", "formula": "$4.6\\times10^{7}J/kg$", "answer": "四点六乘十的七次方焦耳每千克", "subset": "Physics700", "task_type": "tts"} +{"index": 542, "question": "请你朗读以下物理公式符号:$\\frac{U^{2}}{R}$", "audio_path": "audio/physics_f1790d5a-e6e4-4f62-ae3a-b092b1e72c98.wav", "formula": "$\\frac{U^{2}}{R}$", "answer": "R 分之 U 平方", "subset": "Physics700", "task_type": "tts"} +{"index": 543, "question": "Please read the following physics formula symbols: $v = 80\\,\\text{m/s},\\ a = 1\\,\\text{m/s}^2$", "audio_path": "audio/physics_650435e9-da17-440b-a07d-eb41baacb91b.wav", "formula": "$v = 80\\,\\text{m/s},\\ a = 1\\,\\text{m/s}^2$", "answer": "v equals 80 meters per second, a equals 1 meter per second squared", "subset": "Physics700", "task_type": "tts"} +{"index": 544, "question": "请你朗读以下物理公式符号:$10^{3}kg/m^{3}$", "audio_path": "audio/physics_c673a154-1236-4510-a1ee-5abb72c95c27.wav", "formula": "$10^{3}kg/m^{3}$", "answer": "十的三次方千克每立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 545, "question": "Please read the following physics formula symbols: $$\\frac{v_{0}+v_{1}}{2}$$", "audio_path": "audio/physics_8a465f7b-8647-4c41-8466-42f7f1f40b80.wav", "formula": "$$\\frac{v_{0}+v_{1}}{2}$$", "answer": "the sum of v naught and v one over 2", "subset": "Physics700", "task_type": "tts"} +{"index": 546, "question": "请你朗读以下物理公式符号:$$\\frac{m\\upsilon^{2}}{GN}$$", "audio_path": "audio/physics_dca71f3f-dfb1-4ed3-a394-3ab2cf3736f1.wav", "formula": "$$\\frac{m\\upsilon^{2}}{GN}$$", "answer": "G乘N的积分之m乘v平方", "subset": "Physics700", "task_type": "tts"} +{"index": 547, "question": "请你朗读以下物理公式符号:$8.0 \\times 10^{7} J/kg$", "audio_path": "audio/physics_f53167a2-72f7-487a-8346-70b2141b3e76.wav", "formula": "$8.0 \\times 10^{7} J/kg$", "answer": "八点零乘十的七次方焦耳每千克", "subset": "Physics700", "task_type": "tts"} +{"index": 548, "question": "请你朗读以下物理公式符号:$$1.01 \\times 10^{5} \\mathrm{Pa}$$", "audio_path": "audio/physics_f7facd35-a3f4-4074-ac25-c2b9c90914fd.wav", "formula": "$$1.01 \\times 10^{5} \\mathrm{Pa}$$", "answer": "一点零一乘十的五次方帕", "subset": "Physics700", "task_type": "tts"} +{"index": 549, "question": "请你朗读以下物理公式符号:$$x=v_{0}t+\\frac{1}{2}at^{2}$$", "audio_path": "audio/physics_8722a8e0-09ba-4887-9ca2-ccc70e19030e.wav", "formula": "$$x=v_{0}t+\\frac{1}{2}at^{2}$$", "answer": "x等于v零乘t加二分之一乘a乘 t平方", "subset": "Physics700", "task_type": "tts"} +{"index": 550, "question": "Please read the following physics formula symbols: $$F=\\frac{1}{n}G$$", "audio_path": "audio/physics_64abfc59-71b4-45e8-8d1c-761b5afbe41e.wav", "formula": "$$F=\\frac{1}{n}G$$", "answer": "F equals one over n times gravitational constant G", "subset": "Physics700", "task_type": "tts"} +{"index": 551, "question": "Please read the following physics formula symbols: $$0.5×10^{3}kg/m^{3}$$", "audio_path": "audio/physics_f40d0b9f-637f-419b-b377-3188830c0054.wav", "formula": "$$0.5×10^{3}kg/m^{3}$$", "answer": "zero point five times ten cubed kilograms per cubic meter", "subset": "Physics700", "task_type": "tts"} +{"index": 552, "question": "请你朗读以下物理公式符号:$$P=\\frac{W}{t}$$", "audio_path": "audio/physics_28888909-e812-4cef-a1f5-5ea52161af56.wav", "formula": "$$P=\\frac{W}{t}$$", "answer": "P 等于 t 分之 W", "subset": "Physics700", "task_type": "tts"} +{"index": 553, "question": "Please read the following physics formula symbols: $$q=\\frac{Q}{m}$$", "audio_path": "audio/physics_1757f1bf-3943-4769-acc7-cd50e8aa2f81.wav", "formula": "$$q=\\frac{Q}{m}$$", "answer": "q equals Q over m", "subset": "Physics700", "task_type": "tts"} +{"index": 554, "question": "请你朗读以下物理公式符号:$$0.9×10^{3}kg/m^{3}$$", "audio_path": "audio/physics_428c1804-e27b-4640-b5d2-0c64d61695c1.wav", "formula": "$$0.9×10^{3}kg/m^{3}$$", "answer": "零点九乘十的三次方千克每立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 555, "question": "请你朗读以下物理公式符号:$$p=\\frac{F}{S}$$", "audio_path": "audio/physics_0a333d5a-34ee-44bc-960c-c4d6aa267906.wav", "formula": "$$p=\\frac{F}{S}$$", "answer": "p等于S分之F", "subset": "Physics700", "task_type": "tts"} +{"index": 556, "question": "Please read the following physics formula symbols: $$Q=W=\\frac{U^{2}}{R}t$$", "audio_path": "audio/physics_65bbe4dc-1779-4d71-8578-abbfc0d2c7db.wav", "formula": "$$Q=W=\\frac{U^{2}}{R}t$$", "answer": "Q equals W equals U squared over R times t", "subset": "Physics700", "task_type": "tts"} +{"index": 557, "question": "Please read the following physics formula symbols: $$\\overline{v}=\\frac{x}{t}$$", "audio_path": "audio/physics_b1e0e30f-fc97-4afc-aab1-29c27cc84042.wav", "formula": "$$\\overline{v}=\\frac{x}{t}$$", "answer": "v bar equals x over t", "subset": "Physics700", "task_type": "tts"} +{"index": 558, "question": "请你朗读以下物理公式符号:$E_{0}=4.5×10^{6}J$", "audio_path": "audio/physics_ae6f7ca3-d5d8-45c4-b4c0-e209028b5864.wav", "formula": "$E_{0}=4.5×10^{6}J$", "answer": "E 零等于四点五乘十的六次方焦耳", "subset": "Physics700", "task_type": "tts"} +{"index": 559, "question": "Please read the following physics formula symbols: $$1kW•h=3.6×10^{6}J$$", "audio_path": "audio/physics_0127f29a-f984-4efb-b899-1f9a8c6cd65c.wav", "formula": "$$1kW•h=3.6×10^{6}J$$", "answer": "1 kilowatt times hour equals 3.6 times 10 to the power of 6 joules", "subset": "Physics700", "task_type": "tts"} +{"index": 560, "question": "Please read the following physics formula symbols: $\\frac{hP}{cΔt}$", "audio_path": "audio/physics_20396d7a-c43b-405b-8590-1e6b1ee1970d.wav", "formula": "$\\frac{hP}{cΔt}$", "answer": "Planck's constant h times P over speed of light c times delta t", "subset": "Physics700", "task_type": "tts"} +{"index": 561, "question": "Please read the following physics formula symbols: $_{0}^{1}n \\xrightarrow{} _{36}^{92}Kr$", "audio_path": "audio/physics_9e6c8033-382e-4759-8a3c-6cc4823ba2c9.wav", "formula": "$_{0}^{1}n \\xrightarrow{} _{36}^{92}Kr$", "answer": "n with a superscript one and subscript zero goes to Krypton with a superscript ninety-two and subscript thirty-six", "subset": "Physics700", "task_type": "tts"} +{"index": 562, "question": "Please read the following physics formula symbols: $\\frac{v0+v1}{2}$", "audio_path": "audio/physics_d5f3d932-dcad-4eae-bc62-30e2cdeca692.wav", "formula": "$\\frac{v0+v1}{2}$", "answer": "the sum of v zero and v one over two", "subset": "Physics700", "task_type": "tts"} +{"index": 563, "question": "请你朗读以下物理公式符号:$$Q=UIt=\\frac{U^{2}}{R}t$$", "audio_path": "audio/physics_ddbac5bf-ea52-4353-b844-a9f391d7a92a.wav", "formula": "$$Q=UIt=\\frac{U^{2}}{R}t$$", "answer": "Q等于U乘I乘t,等于R分之U的平方乘t", "subset": "Physics700", "task_type": "tts"} +{"index": 564, "question": "请你朗读以下物理公式符号:$q=4.6×10^{7}J/kg$", "audio_path": "audio/physics_04c11e31-293d-4e5a-b4d2-6efa3ca5b6f1.wav", "formula": "$q=4.6×10^{7}J/kg$", "answer": "q等于四点六乘十的七次方焦耳每千克", "subset": "Physics700", "task_type": "tts"} +{"index": 565, "question": "Please read the following physics formula symbols: $\\frac{3}{4}T < t < T$", "audio_path": "audio/physics_b3be03d9-9cf6-4539-adf6-1f27779f37d9.wav", "formula": "$\\frac{3}{4}T < t < T$", "answer": "three over four times T is less than t is less than T", "subset": "Physics700", "task_type": "tts"} +{"index": 566, "question": "请你朗读以下物理公式符号:$R=\\frac{P}{I^{2}}$", "audio_path": "audio/physics_06d546cd-0bf0-4114-961e-81318530fe28.wav", "formula": "$R=\\frac{P}{I^{2}}$", "answer": "R 等于 I 的平方分之 P", "subset": "Physics700", "task_type": "tts"} +{"index": 567, "question": "Please read the following physics formula symbols: $\\frac{gt^{2}}{4}$", "audio_path": "audio/physics_72d35429-0511-4058-809e-e0d8e224c277.wav", "formula": "$\\frac{gt^{2}}{4}$", "answer": "g t squared over four", "subset": "Physics700", "task_type": "tts"} +{"index": 568, "question": "Please read the following physics formula symbols: $\\frac{m\\upsilon^{4}}{GN}$", "audio_path": "audio/physics_68b98cab-7e4d-4fe0-ad23-e1bdd23ecba8.wav", "formula": "$\\frac{m\\upsilon^{4}}{GN}$", "answer": "m times upsilon to the power of four over gravitational constant G times N", "subset": "Physics700", "task_type": "tts"} +{"index": 569, "question": "请你朗读以下物理公式符号:$$ρ=\\frac{m}{V}$$", "audio_path": "audio/physics_34739b1f-27d5-4288-a6c8-fc8ef989b582.wav", "formula": "$$ρ=\\frac{m}{V}$$", "answer": "rho等于 V 分之 m", "subset": "Physics700", "task_type": "tts"} +{"index": 570, "question": "Please read the following physics formula symbols: $\\frac{r^{3}}{k}$", "audio_path": "audio/physics_e5a492ca-5f1f-4efb-8b6e-dd97434ac0a5.wav", "formula": "$\\frac{r^{3}}{k}$", "answer": "r cubed over k", "subset": "Physics700", "task_type": "tts"} +{"index": 571, "question": "请你朗读以下物理公式符号:$\\frac{Mυ_{1}}{\\left(M+m\\right)υ_{2}}$", "audio_path": "audio/physics_26552403-bc8a-49a8-9dca-a5f8d414fb7f.wav", "formula": "$\\frac{Mυ_{1}}{\\left(M+m\\right)υ_{2}}$", "answer": "M加m的和乘upsilon二的积分之M乘upsilon一", "subset": "Physics700", "task_type": "tts"} +{"index": 572, "question": "Please read the following physics formula symbols: $\\frac{4\\pi^{2}\\left(R+ct\\right)^{3}}{GT^{2}}$", "audio_path": "audio/physics_3781554f-4cf2-4768-a43f-5057c9722e6e.wav", "formula": "$\\frac{4\\pi^{2}\\left(R+ct\\right)^{3}}{GT^{2}}$", "answer": "four pi squared times the cube of the sum of R and c t over gravitational constant G times T squared", "subset": "Physics700", "task_type": "tts"} +{"index": 573, "question": "Please read the following physics formula symbols: $\\frac{v_{1}−v_{0}}{2}$", "audio_path": "audio/physics_4ce95c1c-9246-4c75-a54c-036596a62d10.wav", "formula": "$\\frac{v_{1}−v_{0}}{2}$", "answer": "the difference between v one and v naught over two", "subset": "Physics700", "task_type": "tts"} +{"index": 574, "question": "Please read the following physics formula symbols: $\\frac{v_{2}−v_{1}}{t}$", "audio_path": "audio/physics_31ebd5b2-08a9-41cf-a326-745463726c47.wav", "formula": "$\\frac{v_{2}−v_{1}}{t}$", "answer": "v two minus v one over t", "subset": "Physics700", "task_type": "tts"} +{"index": 575, "question": "Please read the following physics formula symbols: $$\\overline{v}=\\frac{s}{t}$$", "audio_path": "audio/physics_99a8cf71-1646-4ef1-87a4-8af79fa65548.wav", "formula": "$$\\overline{v}=\\frac{s}{t}$$", "answer": "Average velocity equals s over t", "subset": "Physics700", "task_type": "tts"} +{"index": 576, "question": "Please read the following physics formula symbols: $= 2.5 \\times 10^{-5} \\, \\text{dm}$", "audio_path": "audio/physics_ab13222a-843b-46e2-b8cb-10b1260b4fb6.wav", "formula": "$= 2.5 \\times 10^{-5} \\, \\text{dm}$", "answer": "equals two point five times ten to the power of negative five decimeters", "subset": "Physics700", "task_type": "tts"} +{"index": 577, "question": "Please read the following physics formula symbols: $E=5×10^{5}V/m$", "audio_path": "audio/physics_ad7c0dce-3e0a-4c7c-91a1-889042391b42.wav", "formula": "$E=5×10^{5}V/m$", "answer": "E equals five times ten to the power of five volts per meter", "subset": "Physics700", "task_type": "tts"} +{"index": 578, "question": "请你朗读以下物理公式符号:$$η=\\frac{Gh}{\\left(G+f\\right)L}$$", "audio_path": "audio/physics_dcb6e7ee-391a-40e6-838d-dd8379eddd3c.wav", "formula": "$$η=\\frac{Gh}{\\left(G+f\\right)L}$$", "answer": "eta等于G加f的和乘L的积分之G乘h", "subset": "Physics700", "task_type": "tts"} +{"index": 579, "question": "请你朗读以下物理公式符号:$$\\frac{U^{2}}{R}$$", "audio_path": "audio/physics_a326e72b-fe86-42ad-9b3e-637a0486f0ae.wav", "formula": "$$\\frac{U^{2}}{R}$$", "answer": "u的平方除以R", "subset": "Physics700", "task_type": "tts"} +{"index": 580, "question": "Please read the following physics formula symbols: $$\\frac{U^{2}}{P}=12Ω$$", "audio_path": "audio/physics_2c7fb70d-5db4-4b36-b147-984da916bd71.wav", "formula": "$$\\frac{U^{2}}{P}=12Ω$$", "answer": "U squared over P equals twelve ohms", "subset": "Physics700", "task_type": "tts"} +{"index": 581, "question": "请你朗读以下物理公式符号:$$\\upsilon=\\frac{s}{t}$$", "audio_path": "audio/physics_31ac7f11-3a65-405a-8109-639d0f5ad1c0.wav", "formula": "$$\\upsilon=\\frac{s}{t}$$", "answer": "v等于t分之s", "subset": "Physics700", "task_type": "tts"} +{"index": 582, "question": "Please read the following physics formula symbols: $$\\left(1\\right)$$", "audio_path": "audio/physics_a1ca8d13-e115-46a8-8222-82755c879e05.wav", "formula": "$$\\left(1\\right)$$", "answer": "one", "subset": "Physics700", "task_type": "tts"} +{"index": 583, "question": "Please read the following physics formula symbols: $$Q=cm\\left(t−t_{0}\\right)$$", "audio_path": "audio/physics_4e4f82fa-31b5-48d0-9e62-c2fd4ed5eb24.wav", "formula": "$$Q=cm\\left(t−t_{0}\\right)$$", "answer": "Q equals c times m times the difference between t and t naught", "subset": "Physics700", "task_type": "tts"} +{"index": 584, "question": "Please read the following physics formula symbols: $$1.03×10^{3}kg/m^{3}$$", "audio_path": "audio/physics_d694a5c3-e19b-4605-9876-e1e57bf7963b.wav", "formula": "$$1.03×10^{3}kg/m^{3}$$", "answer": "1.03 times 10 to the power of 3 kilograms over meters cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 585, "question": "Please read the following physics formula symbols: $\\frac{v_{0}}{g}$", "audio_path": "audio/physics_9c4da4fb-59fc-4384-9c06-331ef3e691cc.wav", "formula": "$\\frac{v_{0}}{g}$", "answer": "v naught over g", "subset": "Physics700", "task_type": "tts"} +{"index": 586, "question": "请你朗读以下物理公式符号:$t_{1}, t_{2}, t_{3}$", "audio_path": "audio/physics_c2d5a190-2199-4619-b9cb-d2086c042aba.wav", "formula": "$t_{1}, t_{2}, t_{3}$", "answer": "t 一,t 二,t 三", "subset": "Physics700", "task_type": "tts"} +{"index": 587, "question": "Please read the following physics formula symbols: $$P=\\frac{W}{t}$$", "audio_path": "audio/physics_24cb00a2-0897-4784-8bd7-7f533f926779.wav", "formula": "$$P=\\frac{W}{t}$$", "answer": "P equals W over t", "subset": "Physics700", "task_type": "tts"} +{"index": 588, "question": "Please read the following physics formula symbols: $v_{0}t+\\frac{1}{2}at^{2}$", "audio_path": "audio/physics_6a420820-85c7-4bbc-ad80-9d2d08bf5b32.wav", "formula": "$v_{0}t+\\frac{1}{2}at^{2}$", "answer": "v zero times t plus one half a t squared", "subset": "Physics700", "task_type": "tts"} +{"index": 589, "question": "请你朗读以下物理公式符号:$\\frac{3gt^{2}}{4}$", "audio_path": "audio/physics_2d633e23-de26-4d8f-b2a3-1b5ee32c081a.wav", "formula": "$\\frac{3gt^{2}}{4}$", "answer": "四分之三乘g乘t的平方", "subset": "Physics700", "task_type": "tts"} +{"index": 590, "question": "请你朗读以下物理公式符号:$$1.2×10^{3}kg/m^{3}$$", "audio_path": "audio/physics_6fb4ead5-de32-4a4e-9777-a6e8dfd4a7ec.wav", "formula": "$$1.2×10^{3}kg/m^{3}$$", "answer": "一点二乘十的三次方千克每立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 591, "question": "请你朗读以下物理公式符号:$$V=\\frac{m}{ρ}$", "audio_path": "audio/physics_e026e84b-2bd4-49b6-a9ae-cd9ceb47b02e.wav", "formula": "$$V=\\frac{m}{ρ}$", "answer": "V等于rho分之m", "subset": "Physics700", "task_type": "tts"} +{"index": 592, "question": "请你朗读以下物理公式符号:$$7×10^{7}J/m^{3}$$", "audio_path": "audio/physics_1eb1733e-0b21-4d33-9a70-3901531f7757.wav", "formula": "$$7×10^{7}J/m^{3}$$", "answer": "七乘十的七次方焦耳每立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 593, "question": "Please read the following physics formula symbols: $-\\frac{3}{16}E_{1}$", "audio_path": "audio/physics_746ddf5d-c92d-4217-84d5-d1da2e9b2179.wav", "formula": "$-\\frac{3}{16}E_{1}$", "answer": "Negative 3 over 16 times E one", "subset": "Physics700", "task_type": "tts"} +{"index": 594, "question": "Please read the following physics formula symbols: $F=\\frac{kQ_{1}Q_{2}}{R^{2}}$", "audio_path": "audio/physics_c0dab4c3-28b4-45cb-aa52-2ff98a74e912.wav", "formula": "$F=\\frac{kQ_{1}Q_{2}}{R^{2}}$", "answer": "F equals k times Q one times Q two over R squared", "subset": "Physics700", "task_type": "tts"} +{"index": 595, "question": "请你朗读以下物理公式符号:$4.2×10^{3}J/\\left(kg⋅℃\\right)$", "audio_path": "audio/physics_aed0b65c-76db-4e7e-a422-8c9c77cf639c.wav", "formula": "$4.2×10^{3}J/\\left(kg⋅℃\\right)$", "answer": "四点二乘十的三次方焦耳每千克摄氏度", "subset": "Physics700", "task_type": "tts"} +{"index": 596, "question": "Please read the following physics formula symbols: $x_{2}=5\\sin \\left(8πt+\\frac{5π}{4}\\right)cm$", "audio_path": "audio/physics_508ab5d7-c196-449a-9272-4217e345e576.wav", "formula": "$x_{2}=5\\sin \\left(8πt+\\frac{5π}{4}\\right)cm$", "answer": "x two equals five sine of eight pi t plus five pi over four centimeters", "subset": "Physics700", "task_type": "tts"} +{"index": 597, "question": "Please read the following physics formula symbols: $\\frac{n^{2}h^{2}}{2med^{2}}$", "audio_path": "audio/physics_bd0dcb8b-23f7-4950-98c5-ad5b60c716da.wav", "formula": "$\\frac{n^{2}h^{2}}{2med^{2}}$", "answer": "n squared times h squared over two times m times e times d squared", "subset": "Physics700", "task_type": "tts"} +{"index": 598, "question": "Please read the following physics formula symbols: $$x=\\frac{1}{2}at^{2}$$", "audio_path": "audio/physics_4677e6ba-9847-40a6-90f4-bb2dceee8232.wav", "formula": "$$x=\\frac{1}{2}at^{2}$$", "answer": "x equals one over two times a times t squared", "subset": "Physics700", "task_type": "tts"} +{"index": 599, "question": "Please read the following physics formula symbols: $$\\frac{υ_{t}-υ_{0}}{t}$$", "audio_path": "audio/physics_84825617-bebc-43eb-91e7-56388c6188a5.wav", "formula": "$$\\frac{υ_{t}-υ_{0}}{t}$$", "answer": "the difference between upsilon t and upsilon naught over t", "subset": "Physics700", "task_type": "tts"} +{"index": 600, "question": "Please read the following physics formula symbols: $$\\frac{W}{t}=\\frac{FS}{t}$$", "audio_path": "audio/physics_bc8b7b94-1a00-4e28-b764-85e2105ab478.wav", "formula": "$$\\frac{W}{t}=\\frac{FS}{t}$$", "answer": "W over t equals F times S over t", "subset": "Physics700", "task_type": "tts"} +{"index": 601, "question": "Please read the following physics formula symbols: $$g=G\\frac{M}{R^{2}}$$", "audio_path": "audio/physics_cb448d94-98e8-49cb-914a-d2d75f465f0f.wav", "formula": "$$g=G\\frac{M}{R^{2}}$$", "answer": "g equals gravitational constant G times M over R squared", "subset": "Physics700", "task_type": "tts"} +{"index": 602, "question": "请你朗读以下物理公式符号:$x_{2}=5\\sin \\left(8πt+\\frac{5π}{4}\\right)cm$", "audio_path": "audio/physics_971eff83-e9cb-43c5-a731-4d188c135ab0.wav", "formula": "$x_{2}=5\\sin \\left(8πt+\\frac{5π}{4}\\right)cm$", "answer": "x 二等于五乘sine 括号 八乘pi乘t 加 四分之五pi 括号 厘米", "subset": "Physics700", "task_type": "tts"} +{"index": 603, "question": "Please read the following physics formula symbols: $Q=W=\\frac{U^{2}}{R}t$", "audio_path": "audio/physics_543b361f-dd60-4912-8e14-367888043458.wav", "formula": "$Q=W=\\frac{U^{2}}{R}t$", "answer": "Q equals W equals U squared over R times t", "subset": "Physics700", "task_type": "tts"} +{"index": 604, "question": "Please read the following physics formula symbols: $$I=I_{1}+I_{2}$$", "audio_path": "audio/physics_2339672b-6d5e-4b49-85ec-dcfec5669847.wav", "formula": "$$I=I_{1}+I_{2}$$", "answer": "I equals I one plus I two", "subset": "Physics700", "task_type": "tts"} +{"index": 605, "question": "请你朗读以下物理公式符号:$2.9×10^{7} J/kg$", "audio_path": "audio/physics_828b8d0a-d74d-429f-b7d2-7d96159067cb.wav", "formula": "$2.9×10^{7} J/kg$", "answer": "二点九乘十的七次方焦耳每千克", "subset": "Physics700", "task_type": "tts"} +{"index": 606, "question": "Please read the following physics formula symbols: $$\\frac{Mm}{R^{2}}$$", "audio_path": "audio/physics_d6d72e13-24b8-4ea3-a438-d41e168c8dc5.wav", "formula": "$$\\frac{Mm}{R^{2}}$$", "answer": "M times m over R squared", "subset": "Physics700", "task_type": "tts"} +{"index": 607, "question": "请你朗读以下物理公式符号:$S = v_{0}t + \\frac{1}{2}at^{2}$", "audio_path": "audio/physics_db4cdfeb-5e2d-472a-b209-25053cae145c.wav", "formula": "$S = v_{0}t + \\frac{1}{2}at^{2}$", "answer": "S 等于 v 零 乘t 加二分之一乘 a乘 t 的平方", "subset": "Physics700", "task_type": "tts"} +{"index": 608, "question": "请你朗读以下物理公式符号:$m=\\frac{Q}{c\\left(t_{2}−t_{1}\\right)}$", "audio_path": "audio/physics_6b5534a9-d280-48eb-aa4f-13d76b1ccbdb.wav", "formula": "$m=\\frac{Q}{c\\left(t_{2}−t_{1}\\right)}$", "answer": "m等于c乘t二减t一的差的积分之Q", "subset": "Physics700", "task_type": "tts"} +{"index": 609, "question": "Please read the following physics formula symbols: $$3×10^{8}m/s=3×10^{5}km/s$$", "audio_path": "audio/physics_9fb84ebf-c26b-4042-9f40-d16c70f7d359.wav", "formula": "$$3×10^{8}m/s=3×10^{5}km/s$$", "answer": "3 times 10 to the power of 8 meters per second equals 3 times 10 to the power of 5 kilometers per second", "subset": "Physics700", "task_type": "tts"} +{"index": 610, "question": "Please read the following physics formula symbols: $P=\\frac{U^{2}}{R}$", "audio_path": "audio/physics_d5412fb5-3058-496d-b030-27190c5dc316.wav", "formula": "$P=\\frac{U^{2}}{R}$", "answer": "P equals U squared over R", "subset": "Physics700", "task_type": "tts"} +{"index": 611, "question": "Please read the following physics formula symbols: $\\frac{3gt^{2}}{4}$", "audio_path": "audio/physics_a6bf0487-c599-4ac8-8cae-3b5569b01b67.wav", "formula": "$\\frac{3gt^{2}}{4}$", "answer": "three g t squared over four", "subset": "Physics700", "task_type": "tts"} +{"index": 612, "question": "请你朗读以下物理公式符号:$$U_{AB}=\\frac{W_{AB}}{q}$$", "audio_path": "audio/physics_d8d06b94-b425-42e2-adf2-745f27c267b0.wav", "formula": "$$U_{AB}=\\frac{W_{AB}}{q}$$", "answer": "U AB等于q分之W AB", "subset": "Physics700", "task_type": "tts"} +{"index": 613, "question": "请你朗读以下物理公式符号:$$P=\\frac{W}{t}$$", "audio_path": "audio/physics_7300f3f5-1dcb-424e-8be4-99724adeb680.wav", "formula": "$$P=\\frac{W}{t}$$", "answer": "P等于t分之W", "subset": "Physics700", "task_type": "tts"} +{"index": 614, "question": "Please read the following physics formula symbols: $$0.5×10^{3}kg/m^{3}$$", "audio_path": "audio/physics_3a36b736-025f-4d8a-9d02-ea4547e96a7b.wav", "formula": "$$0.5×10^{3}kg/m^{3}$$", "answer": "zero point five times ten cubed kilograms over meters cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 615, "question": "请你朗读以下物理公式符号:$$10^{3} cm^{3}$$", "audio_path": "audio/physics_ef78cb43-7fa0-470a-a0cc-71becb885617.wav", "formula": "$$10^{3} cm^{3}$$", "answer": "十的三次方立方厘米", "subset": "Physics700", "task_type": "tts"} +{"index": 616, "question": "请你朗读以下物理公式符号:$m\\left(\\frac{2π}{T}\\right)^{2}r$", "audio_path": "audio/physics_94ca0342-a63e-44a3-86c6-2a6e3929b9d5.wav", "formula": "$m\\left(\\frac{2π}{T}\\right)^{2}r$", "answer": "m乘T分之二π的平方乘r", "subset": "Physics700", "task_type": "tts"} +{"index": 617, "question": "请你朗读以下物理公式符号:$$1.1×10^{3} kg/m^{3}$$", "audio_path": "audio/physics_896f0820-562d-4454-abeb-bce50620c02e.wav", "formula": "$$1.1×10^{3} kg/m^{3}$$", "answer": "一点一乘十的三次方千克每立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 618, "question": "Please read the following physics formula symbols: $\\frac{1}{6}m^{3}$", "audio_path": "audio/physics_40256cd6-a7a1-4c85-b6ef-813a18c46772.wav", "formula": "$\\frac{1}{6}m^{3}$", "answer": "one over six times m cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 619, "question": "请你朗读以下物理公式符号:$v_{0}t+\\frac{1}{2}at^{2}$", "audio_path": "audio/physics_085a2fc3-5c30-40a2-ac9b-95d440fa047e.wav", "formula": "$v_{0}t+\\frac{1}{2}at^{2}$", "answer": "v 零 乘t 加 二分之一乘 a乘 t 的平方", "subset": "Physics700", "task_type": "tts"} +{"index": 620, "question": "Please read the following physics formula symbols: $$F=G\\frac{m_{1}m_{2}}{R^{2}}$$", "audio_path": "audio/physics_60d178d1-5e5c-4003-a0fa-81052ed5a020.wav", "formula": "$$F=G\\frac{m_{1}m_{2}}{R^{2}}$$", "answer": "F equals gravitational constant G times m one times m two over R squared", "subset": "Physics700", "task_type": "tts"} +{"index": 621, "question": "请你朗读以下物理公式符号:$\\frac{hP}{cΔt}$", "audio_path": "audio/physics_8c9ffa4f-1e9e-4563-b799-68decaec2b81.wav", "formula": "$\\frac{hP}{cΔt}$", "answer": "c乘delta t的积 分之h乘P", "subset": "Physics700", "task_type": "tts"} +{"index": 622, "question": "请你朗读以下物理公式符号:$t_{1}:t_{2}=3:4$", "audio_path": "audio/physics_c14e2d27-f618-486e-a9bd-80dbab7051a1.wav", "formula": "$t_{1}:t_{2}=3:4$", "answer": "t 一比t 二等于三比四", "subset": "Physics700", "task_type": "tts"} +{"index": 623, "question": "请你朗读以下物理公式符号:$_{0}^{1}n \\xrightarrow{} _{36}^{92}Kr$", "audio_path": "audio/physics_d9ced801-f808-4493-ba90-a85b9bdc74e2.wav", "formula": "$_{0}^{1}n \\xrightarrow{} _{36}^{92}Kr$", "answer": "原子序数零、质量数一的中子生成原子序数三十六、质量数九十二的氪", "subset": "Physics700", "task_type": "tts"} +{"index": 624, "question": "请你朗读以下物理公式符号:$$\\frac{υ^{2}}{r}$$", "audio_path": "audio/physics_00f026d8-59af-405b-840b-a82e5fa056c6.wav", "formula": "$$\\frac{υ^{2}}{r}$$", "answer": "r分之upsilon平方", "subset": "Physics700", "task_type": "tts"} +{"index": 625, "question": "Please read the following physics formula symbols: $x=υt−\\frac{1}{2}at^{2}$", "audio_path": "audio/physics_ca6c83a9-cadd-4ba5-b8e7-ea8b3a9ebe0e.wav", "formula": "$x=υt−\\frac{1}{2}at^{2}$", "answer": "x equals upsilon t minus one half a t squared", "subset": "Physics700", "task_type": "tts"} +{"index": 626, "question": "请你朗读以下物理公式符号:$\\frac{v^{2}}{R}$", "audio_path": "audio/physics_6c2f9294-f061-4e8d-a9bf-6be32b50ded3.wav", "formula": "$\\frac{v^{2}}{R}$", "answer": "R 分之 v 的平方", "subset": "Physics700", "task_type": "tts"} +{"index": 627, "question": "Please read the following physics formula symbols: $$\\frac{4kg}{5dm^{3}}$$", "audio_path": "audio/physics_8315afeb-e0c7-412d-9a45-e830190d924a.wav", "formula": "$$\\frac{4kg}{5dm^{3}}$$", "answer": "four kilograms over five decimeters cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 628, "question": "Please read the following physics formula symbols: $η=\\frac{Gh}{\\left(F−f\\right)L}$", "audio_path": "audio/physics_4068956b-7bc8-4490-a939-f76475950e5a.wav", "formula": "$η=\\frac{Gh}{\\left(F−f\\right)L}$", "answer": "eta equals G times h over the difference between F and f multiplied by L", "subset": "Physics700", "task_type": "tts"} +{"index": 629, "question": "请你朗读以下物理公式符号:$$\\frac{v^{2}}{R}$$", "audio_path": "audio/physics_aeebf56a-ad4d-4d58-b7c8-d0ba3b6ca248.wav", "formula": "$$\\frac{v^{2}}{R}$$", "answer": "R 分之 v平方", "subset": "Physics700", "task_type": "tts"} +{"index": 630, "question": "Please read the following physics formula symbols: $υ^{2}−υ_{0}^{2}$", "audio_path": "audio/physics_85898436-ac01-4cac-9278-098972107627.wav", "formula": "$υ^{2}−υ_{0}^{2}$", "answer": "upsilon squared minus upsilon naught squared", "subset": "Physics700", "task_type": "tts"} +{"index": 631, "question": "Please read the following physics formula symbols: $$\\frac{50}{273}$$", "audio_path": "audio/physics_cd64f715-1c5d-4ebb-868a-a8b590a4bc69.wav", "formula": "$$\\frac{50}{273}$$", "answer": "fifty over two hundred seventy-three", "subset": "Physics700", "task_type": "tts"} +{"index": 632, "question": "请你朗读以下物理公式符号:$$1kw·h=3.6×10^{6}J$$", "audio_path": "audio/physics_82af3000-5b93-491e-857b-86cc38705ca7.wav", "formula": "$$1kw·h=3.6×10^{6}J$$", "answer": "一千瓦时等于三点六乘十的六次方焦耳", "subset": "Physics700", "task_type": "tts"} +{"index": 633, "question": "Please read the following physics formula symbols: $$x_{1}=5\\sin \\left(8\\pi t+\\frac{\\pi}{4}\\right)\\,\\text{cm}$$", "audio_path": "audio/physics_c387eb30-9c96-4d39-bd91-f579ac17f45c.wav", "formula": "$$x_{1}=5\\sin \\left(8\\pi t+\\frac{\\pi}{4}\\right)\\,\\text{cm}$$", "answer": "x one equals five centimeters times sine of the sum of eight pi t and pi over four", "subset": "Physics700", "task_type": "tts"} +{"index": 634, "question": "请你朗读以下物理公式符号:$$_{1}^{1}H^{+} + _{1}^{3}\\vec{H} \\rightarrow _{2}^{4}He^{+} + _{0}^{1}n$$", "audio_path": "audio/physics_87ceed61-2f01-40fc-a25c-54b70a9730a6.wav", "formula": "$$_{1}^{1}H^{+} + _{1}^{3}\\vec{H} \\rightarrow _{2}^{4}He^{+} + _{0}^{1}n$$", "answer": "氕-一正离子加氚-三核,生成氦-四正离子加中子", "subset": "Physics700", "task_type": "tts"} +{"index": 635, "question": "请你朗读以下物理公式符号:$$\\frac{d}{2}mm$$", "audio_path": "audio/physics_c99ffac0-7bdb-4267-8b80-4a4e15657301.wav", "formula": "$$\\frac{d}{2}mm$$", "answer": "2分之d毫米", "subset": "Physics700", "task_type": "tts"} +{"index": 636, "question": "请你朗读以下物理公式符号:$x=−\\upsilon t−\\frac{1}{2}at^{2}$", "audio_path": "audio/physics_3b44a11c-37a5-4cec-8a5d-1cc1640c5f55.wav", "formula": "$x=−\\upsilon t−\\frac{1}{2}at^{2}$", "answer": "x等于负的upsilon乘t减二分之一乘a乘t的平方", "subset": "Physics700", "task_type": "tts"} +{"index": 637, "question": "Please read the following physics formula symbols: $v=\\frac{2πR}{T}$", "audio_path": "audio/physics_e360d6c1-4b77-485e-97af-bf0f280ae537.wav", "formula": "$v=\\frac{2πR}{T}$", "answer": "v equals two pi R over T", "subset": "Physics700", "task_type": "tts"} +{"index": 638, "question": "Please read the following physics formula symbols: $P=\\frac{F}{S}=\\frac{G}{S}=\\frac{mg}{S}=\\frac{ρVg}{S}=\\frac{ρShg}{S}=ρgh$", "audio_path": "audio/physics_6ba236f1-ce12-4ac3-a5ff-b9686c6d5c0c.wav", "formula": "$P=\\frac{F}{S}=\\frac{G}{S}=\\frac{mg}{S}=\\frac{ρVg}{S}=\\frac{ρShg}{S}=ρgh$", "answer": "P equals F over S, equals gravitational constant G over S, equals m times g over S, equalsrotimes V times g over S, equalsrotimes S times h times g over S, equalsrotimes g times h", "subset": "Physics700", "task_type": "tts"} +{"index": 639, "question": "请你朗读以下物理公式符号:$F=\\frac{kQ_{1}Q_{2}}{R^{2}}$", "audio_path": "audio/physics_d967d7e0-778b-4f03-9b0f-9ecae9a95614.wav", "formula": "$F=\\frac{kQ_{1}Q_{2}}{R^{2}}$", "answer": "F等于R的平方分之k乘Q一乘Q二", "subset": "Physics700", "task_type": "tts"} +{"index": 640, "question": "Please read the following physics formula symbols: $$h=\\frac{W}{G}$$", "audio_path": "audio/physics_773b3ff5-a316-46b7-8482-155254903be8.wav", "formula": "$$h=\\frac{W}{G}$$", "answer": "Planck's constant h equals W over gravitational constant G", "subset": "Physics700", "task_type": "tts"} +{"index": 641, "question": "Please read the following physics formula symbols: $2.7×10^{3}kg/m^{3}$", "audio_path": "audio/physics_5e1fe262-22b1-468c-8abb-f7751c50e2cf.wav", "formula": "$2.7×10^{3}kg/m^{3}$", "answer": "two point seven times ten cubed kilograms over meters cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 642, "question": "Please read the following physics formula symbols: $$\\frac{kQ}{r^{2}}$$", "audio_path": "audio/physics_5ec154e3-64d7-4ac8-9180-fb70f70f4f6e.wav", "formula": "$$\\frac{kQ}{r^{2}}$$", "answer": "k times Q over r squared", "subset": "Physics700", "task_type": "tts"} +{"index": 643, "question": "Please read the following physics formula symbols: $$x=v_{0}t+\\frac{1}{2}at^{2}$$", "audio_path": "audio/physics_12a44d71-54d3-4ab4-9501-54c1e3a7afed.wav", "formula": "$$x=v_{0}t+\\frac{1}{2}at^{2}$$", "answer": "x equals v naught times t plus one over two times a times t squared", "subset": "Physics700", "task_type": "tts"} +{"index": 644, "question": "请你朗读以下物理公式符号:$3.0×10^{7}J/kg$", "audio_path": "audio/physics_2500dede-9480-426a-8b62-c8427312c158.wav", "formula": "$3.0×10^{7}J/kg$", "answer": "三点零乘十的七次方焦耳每千克", "subset": "Physics700", "task_type": "tts"} +{"index": 645, "question": "Please read the following physics formula symbols: $\\frac{△v}{∆t}$", "audio_path": "audio/physics_f0d1d916-1683-40e7-b687-c840a59a8d61.wav", "formula": "$\\frac{△v}{∆t}$", "answer": "delta v over delta t", "subset": "Physics700", "task_type": "tts"} +{"index": 646, "question": "请你朗读以下物理公式符号:$\\frac{gR^{2}}{G}$", "audio_path": "audio/physics_5082229a-5e63-4ee9-bf7f-953de694ada4.wav", "formula": "$\\frac{gR^{2}}{G}$", "answer": "G分之g乘R的平方", "subset": "Physics700", "task_type": "tts"} +{"index": 647, "question": "请你朗读以下物理公式符号:$\\left(\\frac{md^{2}h^{2}}{n^{2}e^{3}}\\right)^{\\frac{1}{3}}$", "audio_path": "audio/physics_3383c381-ae96-43dc-b545-c62f822f0462.wav", "formula": "$\\left(\\frac{md^{2}h^{2}}{n^{2}e^{3}}\\right)^{\\frac{1}{3}}$", "answer": "m乘d平方乘h平方的积除以n平方乘e的三次方的商的三分之一次方", "subset": "Physics700", "task_type": "tts"} +{"index": 648, "question": "请你朗读以下物理公式符号:$$\\frac{c\\Delta t}{h\\lambda P}$$", "audio_path": "audio/physics_d0c1466d-27a8-4559-8eb5-f4f264cc66ed.wav", "formula": "$$\\frac{c\\Delta t}{h\\lambda P}$$", "answer": "h乘lambda乘P的积分之c乘delta t", "subset": "Physics700", "task_type": "tts"} +{"index": 649, "question": "请你朗读以下物理公式符号:$\\frac{\\frac{Gh}{η}+Gh}{s}$", "audio_path": "audio/physics_844dc8e3-51aa-42e5-b106-8aaa13edeea2.wav", "formula": "$\\frac{\\frac{Gh}{η}+Gh}{s}$", "answer": "s 分之 eta分之G乘h加上G乘h的和", "subset": "Physics700", "task_type": "tts"} +{"index": 650, "question": "请你朗读以下物理公式符号:$$4.4×10^{7}J/kg$$", "audio_path": "audio/physics_53efdaec-946f-4bae-810f-87658e842ce0.wav", "formula": "$$4.4×10^{7}J/kg$$", "answer": "四点四乘十的七次方焦耳每千克", "subset": "Physics700", "task_type": "tts"} +{"index": 651, "question": "请你朗读以下物理公式符号:$Q=W=\\frac{U^{2}}{R}t$", "audio_path": "audio/physics_f2044a32-07ee-4ad4-973e-0483c8c4bfe8.wav", "formula": "$Q=W=\\frac{U^{2}}{R}t$", "answer": "Q等于W等于R分之U平方乘t", "subset": "Physics700", "task_type": "tts"} +{"index": 652, "question": "Please read the following physics formula symbols: $\\frac{λPΔt}{hc}$", "audio_path": "audio/physics_c3b5e243-bf92-42d7-96af-10553cd5266b.wav", "formula": "$\\frac{λPΔt}{hc}$", "answer": "lambda times P times delta t over Planck's constant h times speed of light c", "subset": "Physics700", "task_type": "tts"} +{"index": 653, "question": "Please read the following physics formula symbols: $\\frac{p}{p_{0}}$", "audio_path": "audio/physics_fad2ed60-ed43-4a78-a560-162bd4a7f798.wav", "formula": "$\\frac{p}{p_{0}}$", "answer": "p over p naught", "subset": "Physics700", "task_type": "tts"} +{"index": 654, "question": "Please read the following physics formula symbols: $\\frac{2v^{2}}{Rg}$", "audio_path": "audio/physics_f80dbc1c-7a3f-497f-8d32-2eb435d4cddd.wav", "formula": "$\\frac{2v^{2}}{Rg}$", "answer": "two v squared over R times g", "subset": "Physics700", "task_type": "tts"} +{"index": 655, "question": "Please read the following physics formula symbols: $$=\\frac{2πr}{T}$$", "audio_path": "audio/physics_4a80198a-748f-43e6-87d1-82fe5da29c03.wav", "formula": "$$=\\frac{2πr}{T}$$", "answer": "equals two pi r over T", "subset": "Physics700", "task_type": "tts"} +{"index": 656, "question": "请你朗读以下物理公式符号:$\\frac{v_{1}−v_{0}}{t}$", "audio_path": "audio/physics_86444c33-3f86-40e3-b600-4333a9db9430.wav", "formula": "$\\frac{v_{1}−v_{0}}{t}$", "answer": "t 分之 v 一减v 零的差", "subset": "Physics700", "task_type": "tts"} +{"index": 657, "question": "Please read the following physics formula symbols: $2000J/\\left(s·m^{2}\\right)$", "audio_path": "audio/physics_0d346f36-73c2-4275-a695-1e6e75098b13.wav", "formula": "$2000J/\\left(s·m^{2}\\right)$", "answer": "2000 joules over s times m squared", "subset": "Physics700", "task_type": "tts"} +{"index": 658, "question": "请你朗读以下物理公式符号:$$x=\\frac{m}{v}$$", "audio_path": "audio/physics_9c78d289-b250-409e-98b4-eebe7b536c75.wav", "formula": "$$x=\\frac{m}{v}$$", "answer": "x等于v分之m", "subset": "Physics700", "task_type": "tts"} +{"index": 659, "question": "Please read the following physics formula symbols: $$v=\\frac{s}{t}$$", "audio_path": "audio/physics_7569a5d2-a89b-4373-a4d8-c1c5ee51316f.wav", "formula": "$$v=\\frac{s}{t}$$", "answer": "v equals s over t", "subset": "Physics700", "task_type": "tts"} +{"index": 660, "question": "请你朗读以下物理公式符号:$\\frac{U^{2}}{P}$", "audio_path": "audio/physics_f945470c-bd39-4613-a29c-33ff3c9cdc2f.wav", "formula": "$\\frac{U^{2}}{P}$", "answer": "P 分之 U 平方", "subset": "Physics700", "task_type": "tts"} +{"index": 661, "question": "Please read the following physics formula symbols: $ρ=\\frac{m_{1}-m_{2}}{V}$", "audio_path": "audio/physics_ae01e0ac-ec9c-41ef-90d3-d48a5a1f466d.wav", "formula": "$ρ=\\frac{m_{1}-m_{2}}{V}$", "answer": "rho equals the difference between m one and m two over V", "subset": "Physics700", "task_type": "tts"} +{"index": 662, "question": "Please read the following physics formula symbols: $$t=\\frac{W}{P}$$", "audio_path": "audio/physics_86ce7ee0-993a-4c0e-bc9c-b837d8ded570.wav", "formula": "$$t=\\frac{W}{P}$$", "answer": "t equals W over P", "subset": "Physics700", "task_type": "tts"} +{"index": 663, "question": "请你朗读以下物理公式符号:$$\\frac{Gh}{η^{s}}+G$$", "audio_path": "audio/physics_2a2299b0-7279-4d61-9d62-3532b39a7b46.wav", "formula": "$$\\frac{Gh}{η^{s}}+G$$", "answer": "eta 的 s 次方分之G乘h加G", "subset": "Physics700", "task_type": "tts"} +{"index": 664, "question": "请你朗读以下物理公式符号:$$x=A\\sin \\left(\\omega t+\\phi\\right)\\,\\mathrm{cm}$$", "audio_path": "audio/physics_2a4a15cf-f0d1-4ac1-8ee0-16113421f9c7.wav", "formula": "$$x=A\\sin \\left(\\omega t+\\phi\\right)\\,\\mathrm{cm}$$", "answer": "x 等于 A 乘sine 括号 omega 乘 t 加 phi 括号 厘米", "subset": "Physics700", "task_type": "tts"} +{"index": 665, "question": "Please read the following physics formula symbols: $$\\frac{R^{3}}{T^{2}}$$", "audio_path": "audio/physics_2724d828-1f75-4291-a3b7-87a5b09fe294.wav", "formula": "$$\\frac{R^{3}}{T^{2}}$$", "answer": "R cubed over T squared", "subset": "Physics700", "task_type": "tts"} +{"index": 666, "question": "请你朗读以下物理公式符号:$m = 0.02\\,kg$, $k = 250\\,N/m$", "audio_path": "audio/physics_6236ffd4-574f-4f35-9401-d13eb29db32f.wav", "formula": "$m = 0.02\\,kg$, $k = 250\\,N/m$", "answer": "m 等于零点零二千克,k 等于二百五十牛每米", "subset": "Physics700", "task_type": "tts"} +{"index": 667, "question": "Please read the following physics formula symbols: $$B=\\frac{F}{IL}$$", "audio_path": "audio/physics_b145c17f-44c9-43a7-afb8-0354198f96e7.wav", "formula": "$$B=\\frac{F}{IL}$$", "answer": "B equals F over I times L", "subset": "Physics700", "task_type": "tts"} +{"index": 668, "question": "请你朗读以下物理公式符号:$F>\\frac{1}{n}G$", "audio_path": "audio/physics_002a5cb0-a04d-4b46-9d02-e380227d983e.wav", "formula": "$F>\\frac{1}{n}G$", "answer": "F 大于 n 分之 一 乘G", "subset": "Physics700", "task_type": "tts"} +{"index": 669, "question": "Please read the following physics formula symbols: $$P=\\frac{U^{2}}{R}$$", "audio_path": "audio/physics_fde59c9a-b734-4e07-a1ed-fa78bc26112b.wav", "formula": "$$P=\\frac{U^{2}}{R}$$", "answer": "P equals U squared over R", "subset": "Physics700", "task_type": "tts"} +{"index": 670, "question": "请你朗读以下物理公式符号:$$P=P_{1}+P_{2}+P_{3}+\\cdots$$", "audio_path": "audio/physics_76c496b8-82ce-47a6-9d5f-dbd9a764d73a.wav", "formula": "$$P=P_{1}+P_{2}+P_{3}+\\cdots$$", "answer": "P 等于 P 一加 P 二加 P 三依此类推", "subset": "Physics700", "task_type": "tts"} +{"index": 671, "question": "Please read the following physics formula symbols: $v=6t^{2}\\left(m/s\\right)$", "audio_path": "audio/physics_46519ac5-1a75-4a3f-8d98-df99baea4b0d.wav", "formula": "$v=6t^{2}\\left(m/s\\right)$", "answer": "v equals six t squared times meters per second", "subset": "Physics700", "task_type": "tts"} +{"index": 672, "question": "请你朗读以下物理公式符号:$$4.2×10^{7}J/kg$$", "audio_path": "audio/physics_6ade18f2-029d-44f8-bfb4-3ef4f7a1e917.wav", "formula": "$$4.2×10^{7}J/kg$$", "answer": "四点二乘以十的七次方千克分之焦耳", "subset": "Physics700", "task_type": "tts"} +{"index": 673, "question": "请你朗读以下物理公式符号:$IU=I^{2}R=U^{2}/R$", "audio_path": "audio/physics_9804e7cb-c34e-4dac-90de-731e338935ba.wav", "formula": "$IU=I^{2}R=U^{2}/R$", "answer": "I乘U等于I的平方乘R等于R分之U平方", "subset": "Physics700", "task_type": "tts"} +{"index": 674, "question": "请你朗读以下物理公式符号:$$\\frac{100}{105}$$", "audio_path": "audio/physics_b49bf8f5-0839-4914-b7a4-081251cbc34a.wav", "formula": "$$\\frac{100}{105}$$", "answer": "一百零五分之一百", "subset": "Physics700", "task_type": "tts"} +{"index": 675, "question": "Please read the following physics formula symbols: $$\\frac{△v}{△t}$$", "audio_path": "audio/physics_f0d55e15-90ae-44fb-b20e-05a80603d8f2.wav", "formula": "$$\\frac{△v}{△t}$$", "answer": "delta v over delta t", "subset": "Physics700", "task_type": "tts"} +{"index": 676, "question": "请你朗读以下物理公式符号:$$\\frac{Mm}{R^{2}}$$", "audio_path": "audio/physics_c92bc3e5-dd2f-4e10-bb0b-442e154a1fe0.wav", "formula": "$$\\frac{Mm}{R^{2}}$$", "answer": "R的平方分之M乘m", "subset": "Physics700", "task_type": "tts"} +{"index": 677, "question": "Please read the following physics formula symbols: $$\\frac{PV}{T}=C$$", "audio_path": "audio/physics_072029b9-6c63-4ac6-a94f-a58d33e3f331.wav", "formula": "$$\\frac{PV}{T}=C$$", "answer": "P times V over T equals C", "subset": "Physics700", "task_type": "tts"} +{"index": 678, "question": "请你朗读以下物理公式符号:$\\frac{Mυ_{1}}{mυ_{2}}$", "audio_path": "audio/physics_9c89d181-d033-4ed0-b6ec-9c0e9185f4e2.wav", "formula": "$\\frac{Mυ_{1}}{mυ_{2}}$", "answer": "m乘upsilon二的积分之M乘upsilon一", "subset": "Physics700", "task_type": "tts"} +{"index": 679, "question": "请你朗读以下物理公式符号:$\\frac{U^{2}}{R}t$", "audio_path": "audio/physics_720372a3-959a-4446-b56c-01bf853f9c0c.wav", "formula": "$\\frac{U^{2}}{R}t$", "answer": "R 分之 U平方 乘 t", "subset": "Physics700", "task_type": "tts"} +{"index": 680, "question": "请你朗读以下物理公式符号:$\\frac{υ^{2}}{r}$", "audio_path": "audio/physics_aabec681-18c1-474b-81e7-95c55a6471d2.wav", "formula": "$\\frac{υ^{2}}{r}$", "answer": "r 分之 v 的平方", "subset": "Physics700", "task_type": "tts"} +{"index": 681, "question": "Please read the following physics formula symbols: $\\frac{N\\upsilon^{2}}{Gm}$", "audio_path": "audio/physics_6c9a64b0-98c0-4d98-94f5-8506a4adef09.wav", "formula": "$\\frac{N\\upsilon^{2}}{Gm}$", "answer": "N times upsilon squared over gravitational constant G times m", "subset": "Physics700", "task_type": "tts"} +{"index": 682, "question": "Please read the following physics formula symbols: $$1.14×10^{8}J/kg$$", "audio_path": "audio/physics_45f32d5b-b7d0-4741-9456-48928fa8baf0.wav", "formula": "$$1.14×10^{8}J/kg$$", "answer": "one point one four times ten to the power of eight joules over kilograms", "subset": "Physics700", "task_type": "tts"} +{"index": 683, "question": "请你朗读以下物理公式符号:$$0.5×10^{3}kg/m^{3}$$", "audio_path": "audio/physics_8fe2be04-f641-48e3-834e-09d6e1e18894.wav", "formula": "$$0.5×10^{3}kg/m^{3}$$", "answer": "零点五乘十的三次方千克每立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 684, "question": "Please read the following physics formula symbols: $^{235}_{92}\\mathrm{U} + ^{1}_{0}n \\rightarrow ^{141}_{56}\\mathrm{Ba} + ^{92}_{36}\\mathrm{Kr} + 3^{1}_{0}n$", "audio_path": "audio/physics_12daf581-840b-4de1-96ba-73d8fcb3bf65.wav", "formula": "$^{235}_{92}\\mathrm{U} + ^{1}_{0}n \\rightarrow ^{141}_{56}\\mathrm{Ba} + ^{92}_{36}\\mathrm{Kr} + 3^{1}_{0}n$", "answer": "uranium two hundred thirty-five plus neutron produces barium one hundred forty-one plus krypton ninety-two plus three neutrons", "subset": "Physics700", "task_type": "tts"} +{"index": 685, "question": "Please read the following physics formula symbols: $$2×10^{3}kg/m^{3}$$", "audio_path": "audio/physics_5f247116-3901-4805-81b7-6cb5ca229f0d.wav", "formula": "$$2×10^{3}kg/m^{3}$$", "answer": "two times ten cubed kilograms over meters cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 686, "question": "Please read the following physics formula symbols: $\\frac{1}{10}m^{3}$", "audio_path": "audio/physics_3cce7bb5-710e-4ddb-974a-1847164563cb.wav", "formula": "$\\frac{1}{10}m^{3}$", "answer": "one over ten m cubed", "subset": "Physics700", "task_type": "tts"} +{"index": 687, "question": "请你朗读以下物理公式符号:$Q=W=\\frac{U^{2}}{R}$", "audio_path": "audio/physics_b9a7b57b-fffa-46f5-8bac-365cb02eda66.wav", "formula": "$Q=W=\\frac{U^{2}}{R}$", "answer": "Q等于W等于R分之U平方", "subset": "Physics700", "task_type": "tts"} +{"index": 688, "question": "Please read the following physics formula symbols: $\\frac{1}{2}mυ_{n}^{2}$", "audio_path": "audio/physics_7f65973b-d295-4c9d-9bb2-829038df17ed.wav", "formula": "$\\frac{1}{2}mυ_{n}^{2}$", "answer": "one half times m times upsilon n squared", "subset": "Physics700", "task_type": "tts"} +{"index": 689, "question": "请你朗读以下物理公式符号:$$1kW•h=3.6×10^{6}J$$", "audio_path": "audio/physics_2a3efcd4-d3ec-4ab0-840f-a8c827a6ea61.wav", "formula": "$$1kW•h=3.6×10^{6}J$$", "answer": "一千瓦时等于三点六乘十的六次方焦耳", "subset": "Physics700", "task_type": "tts"} +{"index": 690, "question": "Please read the following physics formula symbols: $$\\frac{p_{1}V_{1}}{T_{1}}=\\frac{p_{2}V_{2}}{T_{2}}$$", "audio_path": "audio/physics_94b396f3-3e08-452f-8b10-c73eac908eaa.wav", "formula": "$$\\frac{p_{1}V_{1}}{T_{1}}=\\frac{p_{2}V_{2}}{T_{2}}$$", "answer": "p one V one over T one equals p two V two over T two", "subset": "Physics700", "task_type": "tts"} +{"index": 691, "question": "Please read the following physics formula symbols: $\\frac{m\\upsilon_{2}}{M\\upsilon_{1}}$", "audio_path": "audio/physics_01a1519f-2f84-43ce-9ecb-7ecfb1d46186.wav", "formula": "$\\frac{m\\upsilon_{2}}{M\\upsilon_{1}}$", "answer": "m times upsilon two over M times upsilon one", "subset": "Physics700", "task_type": "tts"} +{"index": 692, "question": "请你朗读以下物理公式符号:$$2×10^{-5}m^{2}$$", "audio_path": "audio/physics_50275c42-737c-4ae3-bbf5-95918961c7d8.wav", "formula": "$$2×10^{-5}m^{2}$$", "answer": "二乘十的负五次方平方米", "subset": "Physics700", "task_type": "tts"} +{"index": 693, "question": "请你朗读以下物理公式符号:$$4.6×10^{7}J/kg$$", "audio_path": "audio/physics_5b59dd47-a008-46dc-96ed-c63763767f68.wav", "formula": "$$4.6×10^{7}J/kg$$", "answer": "四点六乘十的七次方焦耳每千克", "subset": "Physics700", "task_type": "tts"} +{"index": 694, "question": "请你朗读以下物理公式符号:$$2.7×10^{3}kg/m^{3}$$", "audio_path": "audio/physics_d9907a5b-e813-4d82-8121-7da73fb7183e.wav", "formula": "$$2.7×10^{3}kg/m^{3}$$", "answer": "二点七乘十的三次方千克每立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 695, "question": "请你朗读以下物理公式符号:$$f=\\frac{c}{λ}=\\frac{3×10^{8}m/s}{10m}$$", "audio_path": "audio/physics_ee698d43-2746-4fc7-8614-b9a5550e79b8.wav", "formula": "$$f=\\frac{c}{λ}=\\frac{3×10^{8}m/s}{10m}$$", "answer": "f 等于 lambda 分之 c 等于十米分之三乘十的八次方米每秒", "subset": "Physics700", "task_type": "tts"} +{"index": 696, "question": "请你朗读以下物理公式符号:$$v=\\frac{s}{t}$$", "audio_path": "audio/physics_3b178c2e-2646-4906-b06f-0afa3e7c1aec.wav", "formula": "$$v=\\frac{s}{t}$$", "answer": "v等于t分之s", "subset": "Physics700", "task_type": "tts"} +{"index": 697, "question": "Please read the following physics formula symbols: $$1km=10^{3}m=10^{4}dm=10^{5}cm=10^{6}mm=10^{9}μm=10^{12}nm$$", "audio_path": "audio/physics_c63a4de3-76ff-4354-9fd3-ae2aa3c93422.wav", "formula": "$$1km=10^{3}m=10^{4}dm=10^{5}cm=10^{6}mm=10^{9}μm=10^{12}nm$$", "answer": "one kilometer equals ten to the power of three meters equals ten to the power of four decimeters equals ten to the power of five centimeters equals ten to the power of six millimeters equals ten to the power of nine micrometers equals ten to the power of twelve nanometers", "subset": "Physics700", "task_type": "tts"} +{"index": 698, "question": "Please read the following physics formula symbols: $\\frac{Nυ^{4}}{Gm}$", "audio_path": "audio/physics_180abe01-f39e-4fe2-ad2d-09a62973730c.wav", "formula": "$\\frac{Nυ^{4}}{Gm}$", "answer": "N times υ to the power of four over gravitational constant G times m", "subset": "Physics700", "task_type": "tts"} +{"index": 699, "question": "请你朗读以下物理公式符号:$$\\frac{π^{2}\\left(8R+ct\\right)^{3}}{2GT^{2}}$$", "audio_path": "audio/physics_97e1bf56-15fc-465f-8c13-d16787ff4312.wav", "formula": "$$\\frac{π^{2}\\left(8R+ct\\right)^{3}}{2GT^{2}}$$", "answer": "二乘G乘T的平方的积分之pi的平方乘八乘R加c乘t的和的立方", "subset": "Physics700", "task_type": "tts"} +{"index": 700, "question": "Please read the following physics formula symbols: $Q=W=\\frac{U^{2}}{R}$", "audio_path": "audio/physics_7ef434d5-253c-4bed-ba72-63eb7fa7d840.wav", "formula": "$Q=W=\\frac{U^{2}}{R}$", "answer": "Q equals W equals U squared over R", "subset": "Physics700", "task_type": "tts"} +{"index": 701, "question": "Please read the following physics formula symbols: $\\frac{4H}{T_{2}^{2}-T_{1}^{2}}$", "audio_path": "audio/physics_3b437a0d-8ba4-4c3c-85c6-80e427f32bae.wav", "formula": "$\\frac{4H}{T_{2}^{2}-T_{1}^{2}}$", "answer": "four H over the difference between T two squared and T one squared", "subset": "Physics700", "task_type": "tts"} +{"index": 702, "question": "请你朗读以下物理公式符号:$$1.14×10^{8}J/kg$$", "audio_path": "audio/physics_b62933dc-5152-45a4-a201-e4a8e9cb6f18.wav", "formula": "$$1.14×10^{8}J/kg$$", "answer": "一点一四乘十的八次方焦耳每千克", "subset": "Physics700", "task_type": "tts"} +{"index": 703, "question": "请你朗读以下物理公式符号:$v = 80\\,\\text{m/s},\\ a = 1\\,\\text{m/s}^2$", "audio_path": "audio/physics_83e308b8-7147-4d84-83ac-bdb9e8108ee9.wav", "formula": "$v = 80\\,\\text{m/s},\\ a = 1\\,\\text{m/s}^2$", "answer": "v 等于 八十米每秒,a 等于 一米每二次方秒", "subset": "Physics700", "task_type": "tts"} +{"index": 704, "question": "请你朗读以下物理公式符号:$\\frac{1}{6} m^{3}$", "audio_path": "audio/physics_e94d642a-d76b-465c-9e94-4e6b7b31c89b.wav", "formula": "$\\frac{1}{6} m^{3}$", "answer": "六分之一立方米", "subset": "Physics700", "task_type": "tts"} +{"index": 705, "question": "请你朗读以下物理公式符号:$$a=\\frac{Δv}{Δt}$$", "audio_path": "audio/physics_55cfaf96-12e2-4995-880d-bd66704cde88.wav", "formula": "$$a=\\frac{Δv}{Δt}$$", "answer": "a 等于 delta t 分之 delta v", "subset": "Physics700", "task_type": "tts"} +{"index": 706, "question": "请你朗读以下物理公式符号:$=2.5×10^{−5}cm$", "audio_path": "audio/physics_258fcf86-2f30-41ad-96f2-0ed134ec97df.wav", "formula": "$=2.5×10^{−5}cm$", "answer": "等于二点五乘十的负五次方厘米", "subset": "Physics700", "task_type": "tts"} +{"index": 707, "question": "请你朗读以下物理公式符号:$$F=\\frac{P}{v}$$", "audio_path": "audio/physics_fecd4f27-6594-4af6-9c1b-18e0d22abe44.wav", "formula": "$$F=\\frac{P}{v}$$", "answer": "F 等于 v 分之 P", "subset": "Physics700", "task_type": "tts"} +{"index": 708, "question": "请你朗读以下物理公式符号:$$3×10^{8}m/s=3×10^{5}km/s$$", "audio_path": "audio/physics_5696ebea-1161-4905-a03f-bd41ca5268fc.wav", "formula": "$$3×10^{8}m/s=3×10^{5}km/s$$", "answer": "三乘十的八次方米每秒等于三乘十的五次方千米每秒", "subset": "Physics700", "task_type": "tts"} +{"index": 709, "question": "Please read the following physics formula symbols: $$f=\\frac{v}{λ}$$", "audio_path": "audio/physics_c76d459e-fb1b-4588-ba72-81283bdfee42.wav", "formula": "$$f=\\frac{v}{λ}$$", "answer": "f equals v over lambda", "subset": "Physics700", "task_type": "tts"} diff --git a/Physics700/audio/physics_002a5cb0-a04d-4b46-9d02-e380227d983e.wav b/Physics700/audio/physics_002a5cb0-a04d-4b46-9d02-e380227d983e.wav new file mode 100644 index 0000000000000000000000000000000000000000..e7889dc2b25573d50e6c245f22e9f47114aa8b49 --- /dev/null +++ b/Physics700/audio/physics_002a5cb0-a04d-4b46-9d02-e380227d983e.wav @@ -0,0 +1,3 @@ +version https://git-lfs.github.com/spec/v1 +oid sha256:640c96eecd2823ea2a79719b768429e4d9d08fff09ffe89630619daafe6bc5b2 +size 147918 diff --git 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