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- .gitattributes +1 -0
- .gitignore +5 -0
- README.md +250 -0
- annotations/dev.json +0 -0
- annotations/samples.json +1009 -0
- annotations/test.json +0 -0
- annotations/train.json +0 -0
- create_samples.py +71 -0
- data/dev_en.json +0 -0
- data/test_en.json +0 -0
- data/train_en.json +0 -0
- requirements.txt +48 -0
- results/.DS_Store +0 -0
- results/dev/.DS_Store +0 -0
- results/dev/parabola/problem_0025.png +3 -0
- results/dev/parabola/problem_0145.png +3 -0
- results/dev/parabola/problem_0150.png +3 -0
- results/dev/parabola/problem_0151.png +3 -0
- results/dev/parabola/problem_0179.png +3 -0
- results/dev/parabola/problem_0186.png +3 -0
- results/dev/parabola/problem_0409.png +3 -0
- results/dev/parabola/problem_0541.png +3 -0
- results/dev/parabola/problem_0569.png +3 -0
- results/dev/parabola/problem_0596.png +3 -0
- results/dev/parabola/problem_0637.png +3 -0
- results/dev/parabola/problem_0743.png +3 -0
- results/dev/parabola/problem_0794.png +3 -0
- results/dev/parabola/problem_0804.png +3 -0
- results/dev/parabola/problem_0958.png +3 -0
- results/dev/summary.json +0 -0
- results/test/.DS_Store +0 -0
- results/test/summary.json +0 -0
- results/train/.DS_Store +0 -0
- results/train/summary.json +0 -0
- src/__pycache__/sdf_geo_solver.cpython-313.pyc +3 -0
- src/main.py +68 -0
- src/sdf_geo/__init__.py +51 -0
- src/sdf_geo/__pycache__/__init__.cpython-313.pyc +0 -0
- src/sdf_geo/__pycache__/constraints.cpython-313.pyc +0 -0
- src/sdf_geo/__pycache__/optimizer.cpython-313.pyc +0 -0
- src/sdf_geo/__pycache__/parser.cpython-313.pyc +0 -0
- src/sdf_geo/__pycache__/primitives.cpython-313.pyc +0 -0
- src/sdf_geo/__pycache__/processor.cpython-313.pyc +0 -0
- src/sdf_geo/__pycache__/renderer.cpython-313.pyc +0 -0
- src/sdf_geo/constraints.py +82 -0
- src/sdf_geo/optimizer.py +81 -0
- src/sdf_geo/parser.py +1184 -0
- src/sdf_geo/primitives.py +354 -0
- src/sdf_geo/processor.py +1218 -0
- src/sdf_geo/renderer.py +98 -0
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# Video files - compressed
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| 1 |
+
# Image_SDF
|
| 2 |
+
|
| 3 |
+
**Automatic Diagram Generation for Analytic Geometry Problems using Signed Distance Fields**
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| 4 |
+
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| 5 |
+
<p align="center">
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| 6 |
+
<img src="results/test/ellipse/problem_2063.png" width="600" alt="Example Output">
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| 7 |
+
</p>
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+
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| 9 |
+
<p align="center">
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| 10 |
+
<img src="https://img.shields.io/badge/Python-3.9%2B-blue.svg" alt="Python">
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| 11 |
+
<img src="https://img.shields.io/badge/PyTorch-2.0%2B-ee4c2c.svg" alt="PyTorch">
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| 12 |
+
<img src="https://img.shields.io/badge/Accuracy-96.7%25-brightgreen.svg" alt="Accuracy">
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| 13 |
+
<img src="https://img.shields.io/badge/Problems-10,861-orange.svg" alt="Problems">
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| 14 |
+
<img src="https://img.shields.io/badge/License-MIT-green.svg" alt="License">
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| 15 |
+
</p>
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| 16 |
+
|
| 17 |
+
---
|
| 18 |
+
|
| 19 |
+
## Introduction
|
| 20 |
+
|
| 21 |
+
**Image_SDF** is an automatic system that converts mathematical geometry problem text into accurate visualizations. By leveraging **Signed Distance Fields (SDF)** combined with differentiable optimization, the system can automatically generate precise conic section diagrams from symbolic geometric expressions.
|
| 22 |
+
|
| 23 |
+
Traditional geometry diagram generation often relies on manual drawing or rule-based methods. This system takes a different approach: it models geometric constraints as differentiable loss functions and uses gradient-based optimization to find curve parameters that satisfy all constraints, ultimately rendering high-quality geometric diagrams.
|
| 24 |
+
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| 25 |
+
### Key Features
|
| 26 |
+
|
| 27 |
+
- **Fully Automated**: Generate PNG diagrams directly from JSON-formatted geometry problems without manual intervention
|
| 28 |
+
- **High Accuracy**: Achieves **96.7%** validation pass rate on parseable problems
|
| 29 |
+
- **Large-Scale Validation**: Tested on **10,861** geometry problems across 3 datasets
|
| 30 |
+
- **Rigorous Verification**: Multi-dimensional geometric property validation including focus position, eccentricity, and asymptote slope
|
| 31 |
+
|
| 32 |
+
---
|
| 33 |
+
|
| 34 |
+
## Supported Curve Types
|
| 35 |
+
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| 36 |
+
The system supports four classical conic sections, each with complete SDF representation and constraint validation:
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| 37 |
+
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| 38 |
+
| Curve Type | Standard Form | Validated Properties |
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| 39 |
+
|------------|---------------|---------------------|
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| 40 |
+
| **Ellipse** | x²/a² + y²/b² = 1 | Focus distance c²=a²-b², eccentricity, points on curve |
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| 41 |
+
| **Hyperbola** | x²/a² - y²/b² = 1 | Focus distance c²=a²+b², asymptote slope, eccentricity |
|
| 42 |
+
| **Parabola** | y² = 4px | Focus position, directrix equation, points on curve |
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| 43 |
+
| **Circle** | (x-h)² + (y-k)² = r² | Center position, radius, points on curve |
|
| 44 |
+
|
| 45 |
+
---
|
| 46 |
+
|
| 47 |
+
## How It Works
|
| 48 |
+
|
| 49 |
+
The system follows a four-stage pipeline:
|
| 50 |
+
|
| 51 |
+
```
|
| 52 |
+
Text Parsing → SDF Construction → Constraint Optimization → Diagram Rendering
|
| 53 |
+
```
|
| 54 |
+
|
| 55 |
+
### 1. Text Parsing
|
| 56 |
+
|
| 57 |
+
Extract geometric parameters from mathematical expressions. For example:
|
| 58 |
+
|
| 59 |
+
```
|
| 60 |
+
Input: "ellipse x²/4 + y²/9 = 1"
|
| 61 |
+
Output: Ellipse(a=2, b=3, center=(0,0))
|
| 62 |
+
```
|
| 63 |
+
|
| 64 |
+
The parser supports various expression formats including fractions, radicals, and LaTeX-formatted mathematical expressions.
|
| 65 |
+
|
| 66 |
+
### 2. SDF Construction
|
| 67 |
+
|
| 68 |
+
Build a signed distance field function for each curve type. The SDF value represents the signed distance from any point in space to the curve boundary:
|
| 69 |
+
- Positive: point is outside the curve
|
| 70 |
+
- Negative: point is inside the curve
|
| 71 |
+
- Zero: point is exactly on the curve
|
| 72 |
+
|
| 73 |
+
### 3. Constraint Optimization
|
| 74 |
+
|
| 75 |
+
Optimize curve parameters via gradient descent to satisfy all geometric constraints:
|
| 76 |
+
|
| 77 |
+
```python
|
| 78 |
+
# Total loss = point constraint + focus constraint + eccentricity constraint + crowd penalty
|
| 79 |
+
L_total = λ₁·L_point + λ₂·L_focus + λ₃·L_ecc + λ₄·L_crowd
|
| 80 |
+
```
|
| 81 |
+
|
| 82 |
+
Using the AdamW optimizer, convergence typically occurs within 100-200 iterations.
|
| 83 |
+
|
| 84 |
+
### 4. Diagram Rendering
|
| 85 |
+
|
| 86 |
+
Extract the zero-level set of the SDF (i.e., the curve itself) and render in Chinese Gaokao (高考) analytic geometry style: white background, black curves, arrow axes through origin with O/x/y labels, feature point annotations (foci, vertices), and auxiliary elements (asymptotes, directrix) as dashed lines. No problem text, grid, or legend is included in the output.
|
| 87 |
+
|
| 88 |
+
---
|
| 89 |
+
|
| 90 |
+
## Datasets and Results
|
| 91 |
+
|
| 92 |
+
The system has been fully tested on three datasets:
|
| 93 |
+
|
| 94 |
+
| Dataset | Total Problems | Parseable | Successful | Parseable Accuracy |
|
| 95 |
+
|---------|----------------|-----------|------------|-------------------|
|
| 96 |
+
| dev | 1,035 | 809 | 788 | **97.4%** |
|
| 97 |
+
| test | 2,069 | 1,649 | 1,596 | **96.8%** |
|
| 98 |
+
| train | 7,757 | 6,052 | 5,849 | **96.6%** |
|
| 99 |
+
| **Total** | **10,861** | **8,510** | **8,233** | **96.7%** |
|
| 100 |
+
|
| 101 |
+
> **Note**: "Parseable" refers to problems with explicit geometric expressions (e.g., x²/4 + y²/9 = 1) rather than implicit or parametric forms. Approximately 22% of problems cannot be parsed due to overly complex or incomplete expressions.
|
| 102 |
+
|
| 103 |
+
### Curve Type Distribution
|
| 104 |
+
|
| 105 |
+
| Type | Dev | Test | Train | Total |
|
| 106 |
+
|------|-----|------|-------|-------|
|
| 107 |
+
| Ellipse | 220 | 467 | 1,734 | 2,421 |
|
| 108 |
+
| Hyperbola | 293 | 565 | 2,025 | 2,883 |
|
| 109 |
+
| Parabola | 262 | 532 | 2,000 | 2,794 |
|
| 110 |
+
| Circle | 13 | 32 | 90 | 135 |
|
| 111 |
+
|
| 112 |
+
---
|
| 113 |
+
|
| 114 |
+
## Installation and Usage
|
| 115 |
+
|
| 116 |
+
### Requirements
|
| 117 |
+
|
| 118 |
+
- Python >= 3.9
|
| 119 |
+
- PyTorch >= 2.0.0
|
| 120 |
+
- NumPy >= 1.24.0
|
| 121 |
+
- Matplotlib >= 3.7.0
|
| 122 |
+
- tqdm >= 4.65.0
|
| 123 |
+
|
| 124 |
+
### Install Dependencies
|
| 125 |
+
|
| 126 |
+
```bash
|
| 127 |
+
pip install -r requirements.txt
|
| 128 |
+
```
|
| 129 |
+
|
| 130 |
+
### Running Examples
|
| 131 |
+
|
| 132 |
+
```bash
|
| 133 |
+
# Process test dataset
|
| 134 |
+
python src/main.py --input data/test_en.json --output results/test/
|
| 135 |
+
|
| 136 |
+
# Process dev dataset
|
| 137 |
+
python src/main.py --input data/dev_en.json --output results/dev/
|
| 138 |
+
|
| 139 |
+
# Process train dataset (~30 minutes)
|
| 140 |
+
python src/main.py --input data/train_en.json --output results/train/
|
| 141 |
+
|
| 142 |
+
# Process only first 100 problems with verbose output
|
| 143 |
+
python src/main.py -i data/test_en.json -o results/test/ -m 100 -v
|
| 144 |
+
```
|
| 145 |
+
|
| 146 |
+
### Command Line Arguments
|
| 147 |
+
|
| 148 |
+
| Argument | Description | Default |
|
| 149 |
+
|----------|-------------|---------|
|
| 150 |
+
| `-i, --input` | Input JSON file path | `data/test_en.json` |
|
| 151 |
+
| `-o, --output` | Output directory | `results/` |
|
| 152 |
+
| `-m, --max` | Maximum number of problems to process | All |
|
| 153 |
+
| `-v, --verbose` | Enable verbose output | False |
|
| 154 |
+
|
| 155 |
+
### Python API
|
| 156 |
+
|
| 157 |
+
```python
|
| 158 |
+
from src.sdf_geo import SDFBatchProcessor
|
| 159 |
+
|
| 160 |
+
# Create processor
|
| 161 |
+
processor = SDFBatchProcessor(output_dir='results/')
|
| 162 |
+
|
| 163 |
+
# Batch processing
|
| 164 |
+
results = processor.process_batch('data/test_en.json', max_problems=100)
|
| 165 |
+
|
| 166 |
+
# Calculate success rate
|
| 167 |
+
success_rate = sum(r['success'] for r in results) / len(results)
|
| 168 |
+
print(f"Success rate: {success_rate:.1%}")
|
| 169 |
+
```
|
| 170 |
+
|
| 171 |
+
---
|
| 172 |
+
|
| 173 |
+
## Project Structure
|
| 174 |
+
|
| 175 |
+
```
|
| 176 |
+
Image_SDF/
|
| 177 |
+
├── data/
|
| 178 |
+
│ ├── dev_en.json # Dev set (1,035 problems)
|
| 179 |
+
│ ├── test_en.json # Test set (2,069 problems)
|
| 180 |
+
│ └── train_en.json # Train set (7,757 problems)
|
| 181 |
+
├── results/
|
| 182 |
+
│ ├── dev/ # Dev set results
|
| 183 |
+
│ ├── test/ # Test set results
|
| 184 |
+
│ └── train/ # Train set results
|
| 185 |
+
├── samples/ # Sample images (3 per curve type per dataset)
|
| 186 |
+
├── src/
|
| 187 |
+
│ ├── main.py # CLI entry point
|
| 188 |
+
│ └── sdf_geo/ # Core modules
|
| 189 |
+
│ ├── primitives.py # SDF geometric primitives
|
| 190 |
+
│ ├── constraints.py # Differentiable constraint functions
|
| 191 |
+
│ ├── parser.py # Expression parser
|
| 192 |
+
│ ├── optimizer.py # Gradient optimizer
|
| 193 |
+
│ ├── processor.py # Batch processing, validation & visualization
|
| 194 |
+
│ └── renderer.py # SDF field evaluation & curve rendering
|
| 195 |
+
├── create_samples.py # Generate sample images from results
|
| 196 |
+
├── requirements.txt
|
| 197 |
+
└── README.md
|
| 198 |
+
```
|
| 199 |
+
|
| 200 |
+
---
|
| 201 |
+
|
| 202 |
+
## Output Format
|
| 203 |
+
|
| 204 |
+
Each problem generates a PNG image in Chinese Gaokao (高考) analytic geometry style, containing:
|
| 205 |
+
|
| 206 |
+
- **Geometric Curve**: Black curve rendered from the SDF zero-level set on white background
|
| 207 |
+
- **Feature Point Annotations**: Foci (F₁, F₂), vertices, center, marked as small black dots with labels
|
| 208 |
+
- **Coordinate System**: Arrow axes through origin with O, x, y labels (no grid)
|
| 209 |
+
- **Auxiliary Elements**: Asymptotes and directrix rendered as dashed lines
|
| 210 |
+
|
| 211 |
+
Results are organized by curve type:
|
| 212 |
+
|
| 213 |
+
```
|
| 214 |
+
results/test/
|
| 215 |
+
├── summary.json # Statistics summary
|
| 216 |
+
├── circle/ # Circle diagrams
|
| 217 |
+
├── ellipse/ # Ellipse diagrams
|
| 218 |
+
├── hyperbola/ # Hyperbola diagrams
|
| 219 |
+
└── parabola/ # Parabola diagrams
|
| 220 |
+
```
|
| 221 |
+
|
| 222 |
+
---
|
| 223 |
+
|
| 224 |
+
## Validation Standards
|
| 225 |
+
|
| 226 |
+
The system employs multi-dimensional geometric property validation to ensure mathematical correctness of generated diagrams:
|
| 227 |
+
|
| 228 |
+
| Validation Item | Tolerance | Description |
|
| 229 |
+
|-----------------|-----------|-------------|
|
| 230 |
+
| Point on curve | 0.03 | SDF(p) ≈ 0 |
|
| 231 |
+
| Eccentricity | 0.05 | \|e_calculated - e_target\| < tol |
|
| 232 |
+
| Focus position | 0.05 | \|c_calculated - c_given\| < tol |
|
| 233 |
+
| Asymptote slope | 0.05 | \|b/a - slope\| < tol |
|
| 234 |
+
|
| 235 |
+
---
|
| 236 |
+
|
| 237 |
+
## Methodology
|
| 238 |
+
|
| 239 |
+
This implementation is based on the methodology described in:
|
| 240 |
+
|
| 241 |
+
> **GeoSDF: Plane Geometry Diagram Synthesis via Signed Distance Field**
|
| 242 |
+
> arXiv:2506.13492
|
| 243 |
+
|
| 244 |
+
The core ideas of using signed distance fields for geometric representation and differentiable optimization for constraint satisfaction are derived from this work.
|
| 245 |
+
|
| 246 |
+
---
|
| 247 |
+
|
| 248 |
+
## License
|
| 249 |
+
|
| 250 |
+
MIT License
|
annotations/dev.json
ADDED
|
The diff for this file is too large to render.
See raw diff
|
|
|
annotations/samples.json
ADDED
|
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|
| 1 |
+
[
|
| 2 |
+
{
|
| 3 |
+
"dataset": "dev",
|
| 4 |
+
"index": 6,
|
| 5 |
+
"conic_type": "circle",
|
| 6 |
+
"image_path": "samples/dev/circle/problem_0006.png",
|
| 7 |
+
"problem": {
|
| 8 |
+
"text": "Given the circle $(x+1)^{2}+y^{2}=36$ with center $M$, let $A$ be any point on the circle, and let $N(1 , 0)$. The perpendicular bisector of segment $AN$ intersects $MA$ at point $P$. Then the trajectory equation of the moving point $P$ is?",
|
| 9 |
+
"fact_expressions": "G: Circle;Expression(G) = (y^2 + (x + 1)^2 = 36);Center(G) = M;M: Point;A: Point;PointOnCurve(A, G);N: Point;Coordinate(N) = (1, 0);Intersection(PerpendicularBisector(LineSegmentOf(A,N)),LineSegmentOf(M,A)) = P;P: Point",
|
| 10 |
+
"query_expressions": "LocusEquation(P)",
|
| 11 |
+
"answer_expressions": "x^2/9+y^2/8=1",
|
| 12 |
+
"process": "Since the circle $(x+2)^{2}+y^{2}=36$ has center $M(-1,0)$ and radius $r=6$, let point $P(x,y)$. Since the perpendicular bisector of segment $AN$ intersects $MA$ at point $P$, we have $|PN|=|PA|$. Therefore, $|PM|+|PN|=|PM|+|PA|=|MA|=6>|MN|=2$. Hence, the trajectory of point $P$ is an ellipse with foci at $M(-1,0)$ and $N(1,0)$, and major axis length $2a=6$, so $b=\\sqrt{a^{2}-c^{2}}=\\sqrt{9-1}=2\\sqrt{2}$. Thus, the equation of the trajectory of moving point $P$ is $\\frac{x^{2}}{9}+\\frac{y^{2}}{8}=1$."
|
| 13 |
+
},
|
| 14 |
+
"sdf_annotation": {
|
| 15 |
+
"params": {
|
| 16 |
+
"center": [
|
| 17 |
+
1.0,
|
| 18 |
+
0.0
|
| 19 |
+
],
|
| 20 |
+
"radius": 6.0
|
| 21 |
+
},
|
| 22 |
+
"optimization": {
|
| 23 |
+
"final_loss": 0.0,
|
| 24 |
+
"converged": true
|
| 25 |
+
},
|
| 26 |
+
"coords": {}
|
| 27 |
+
}
|
| 28 |
+
},
|
| 29 |
+
{
|
| 30 |
+
"dataset": "dev",
|
| 31 |
+
"index": 441,
|
| 32 |
+
"conic_type": "circle",
|
| 33 |
+
"image_path": "samples/dev/circle/problem_0441.png",
|
| 34 |
+
"problem": {
|
| 35 |
+
"text": "A moving circle is externally tangent to the circle $Q_{1}$: $(x+3)^{2}+y^{2}=1$ and internally tangent to the circle $Q_{2}$: $(x-3)^{2}+y^{2}=81$. Then, the trajectory equation of the center of this moving circle is?",
|
| 36 |
+
"fact_expressions": "G: Circle;IsOutTangent(G,Q1) = True;Q1: Circle;Expression(Q1) = ((x+3)^2+y^2=1);Q2: Circle;Expression(Q2) = ((x-3)^2+y^2=81);IsInTangent(G,Q2) = True",
|
| 37 |
+
"query_expressions": "LocusEquation(Center(G))",
|
| 38 |
+
"answer_expressions": "x^2/25+y^2/16=1",
|
| 39 |
+
"process": "Let the center of the moving circle be Q(x, y), with radius R. Since the moving circle is externally tangent to the circle Q_{1}:(x+3)^{2}+y^{2}=1 and internally tangent to the circle Q_{2}:(x-3)^{2}+y^{2}=81, we have |QQ_{1}| = R + 1, |QQ_{2}| = 9 - R. Therefore, |QQ_{1}| + |QQ_{2}| = 10 > 6 = |Q_{1}Q_{2}|. Thus, the locus of the center of the moving circle is an ellipse with foci at Q_{1} and Q_{2}. Hence, 2a = 10, a = 5, c = 3, b^{2} = 16. Therefore, the equation of the locus of the center of the moving circle is \\frac{x^{2}}{25}+\\frac{y^{2}}{16}=1."
|
| 40 |
+
},
|
| 41 |
+
"sdf_annotation": {
|
| 42 |
+
"params": {
|
| 43 |
+
"center": [
|
| 44 |
+
-3.0,
|
| 45 |
+
0.0
|
| 46 |
+
],
|
| 47 |
+
"radius": 1.0
|
| 48 |
+
},
|
| 49 |
+
"optimization": {
|
| 50 |
+
"final_loss": 0.0,
|
| 51 |
+
"converged": true
|
| 52 |
+
},
|
| 53 |
+
"coords": {}
|
| 54 |
+
}
|
| 55 |
+
},
|
| 56 |
+
{
|
| 57 |
+
"dataset": "dev",
|
| 58 |
+
"index": 669,
|
| 59 |
+
"conic_type": "circle",
|
| 60 |
+
"image_path": "samples/dev/circle/problem_0669.png",
|
| 61 |
+
"problem": {
|
| 62 |
+
"text": "Given the circle $C$: $x^{2}+y^{2}=25$, draw a line $l$ through point $M(-2,3)$ intersecting the circle $C$ at points $A$ and $B$. Tangents to the circle are drawn at points $A$ and $B$, respectively. When the two tangents intersect at point $N$, what is the trajectory equation of point $N$?",
|
| 63 |
+
"fact_expressions": "C: Circle;Expression(C) = (x^2 + y^2 = 25);M: Point;l: Line;Coordinate(M) = (-2, 3);PointOnCurve(M, l);A: Point;B: Point;Intersection(l, C) = {A, B};L1: Line;L2: Line;TangentOnPoint(A,C)=L1;TangentOnPoint(B,C)=L2;N: Point;Intersection(L1, L2) = N",
|
| 64 |
+
"query_expressions": "LocusEquation(N)",
|
| 65 |
+
"answer_expressions": "2*x-3*y+25=0",
|
| 66 |
+
"process": "Consider the following problem: Given a circle $ C: x^{2} + y^{2} = r^{2} $ ($ r > 0 $) and a point $ P(a, b) $. If point $ P $ lies inside $ C $, draw a line $ l $ through $ P $ intersecting $ C $ at points $ A $ and $ B $. Tangents to $ C $ are drawn at points $ A $ and $ B $ respectively. When these two tangents intersect at point $ Q $, find the locus equation of point $ Q $. The center of circle $ C: x^{2} + y^{2} = r^{2} $ is $ (0, 0) $. Let $ A(x_{1}, y_{1}) $, $ B(x_{2}, y_{2}) $, $ Q(x_{0}, y_{0}) $. Since $ AQ $ is tangent to circle $ C $, we have $ AQ \\perp CA $. Therefore, $ (x_{1} - x_{0})(x_{1} - 0) + (y_{1} - y_{0})(y_{1} - 0) = 0 $, that is, $ x^{2}_{1} - x_{0}x_{1} + y^{2}_{1} - y_{0}y_{1} = 0 $. Since $ x^{2} + y^{2} = r^{2} $, it follows that $ x_{0}x_{1} + y_{0}y_{1} = r^{2} $. Similarly, $ x_{0}x_{2} + y_{0}y_{2} = r^{2} $. Hence, the equation of the line passing through points $ A $ and $ B $ is $ xx_{0} + yy_{0} = r^{2} $. Since line $ AB $ passes through point $ (a, b) $, substituting gives $ ax_{0} + by_{0} = r^{2} $. Therefore, the locus equation of point $ Q $ is: $ ax + by = r^{2} $. According to the problem, the locus equation of point $ N $ is $ 2x - 3y + 25 = 0 $."
|
| 67 |
+
},
|
| 68 |
+
"sdf_annotation": {
|
| 69 |
+
"params": {
|
| 70 |
+
"center": [
|
| 71 |
+
0.0,
|
| 72 |
+
0.0
|
| 73 |
+
],
|
| 74 |
+
"radius": 5.0
|
| 75 |
+
},
|
| 76 |
+
"optimization": {
|
| 77 |
+
"final_loss": 0.0,
|
| 78 |
+
"converged": true
|
| 79 |
+
},
|
| 80 |
+
"coords": {}
|
| 81 |
+
}
|
| 82 |
+
},
|
| 83 |
+
{
|
| 84 |
+
"dataset": "dev",
|
| 85 |
+
"index": 1,
|
| 86 |
+
"conic_type": "ellipse",
|
| 87 |
+
"image_path": "samples/dev/ellipse/problem_0001.png",
|
| 88 |
+
"problem": {
|
| 89 |
+
"text": "Given the ellipse $\\frac{x^{2}}{4}+y^{2}=1$ with left and right foci $F_{1}$, $F_{2}$, point $P$ is a moving point on the ellipse. Then the range of values of $\\overrightarrow{P F_{1}} \\cdot \\overrightarrow{P F_{2}}$ is?",
|
| 90 |
+
"fact_expressions": "G: Ellipse;P: Point;F1: Point;F2: Point;Expression(G) = (x^2/4 + y^2 = 1);LeftFocus(G) = F1;RightFocus(G) = F2;PointOnCurve(P, G)",
|
| 91 |
+
"query_expressions": "Range(DotProduct(VectorOf(P, F1), VectorOf(P, F2)))",
|
| 92 |
+
"answer_expressions": "[-2, 1]",
|
| 93 |
+
"process": "Let P(x,y) be an arbitrary point on the ellipse, then \\overrightarrow{PF_{1}}=(-\\sqrt{3}-x,-y), \\overrightarrow{PF_{2}}=(\\sqrt{3}-x,-y). Therefore, \\overrightarrow{PF_{1}}\\cdot\\overrightarrow{PF_{2}}=(-\\sqrt{3}-x,-y)\\cdot(\\sqrt{3}-x,-y)=x^{2}+y^{2}-3=x^{2}+1-\\frac{x^{2}}{4}=\\frac{3}{4}x^{2}-2. Since P lies on the ellipse, -2\\leqslant x \\leqslant 2, so -2\\leqslant \\frac{3}{4}x^{2}-2 \\leqslant 1, that is, the range of \\overrightarrow{PF_{1}}\\cdot\\overrightarrow{PF_{2}} is [-2,1]."
|
| 94 |
+
},
|
| 95 |
+
"sdf_annotation": {
|
| 96 |
+
"params": {
|
| 97 |
+
"a": 2.0,
|
| 98 |
+
"b": 1.0,
|
| 99 |
+
"major_axis": "x",
|
| 100 |
+
"x_coef": 4.0,
|
| 101 |
+
"y_coef": 1.0
|
| 102 |
+
},
|
| 103 |
+
"optimization": {
|
| 104 |
+
"final_loss": 0.0,
|
| 105 |
+
"converged": true,
|
| 106 |
+
"note": "using explicit params"
|
| 107 |
+
},
|
| 108 |
+
"coords": {}
|
| 109 |
+
}
|
| 110 |
+
},
|
| 111 |
+
{
|
| 112 |
+
"dataset": "dev",
|
| 113 |
+
"index": 524,
|
| 114 |
+
"conic_type": "ellipse",
|
| 115 |
+
"image_path": "samples/dev/ellipse/problem_0524.png",
|
| 116 |
+
"problem": {
|
| 117 |
+
"text": "Point $P$ lies on the ellipse $\\frac{x^{2}}{16}+\\frac{y^{2}}{9}=1$. What are the maximum and minimum distances from point $P$ to the line $3x-4y=24$?",
|
| 118 |
+
"fact_expressions": "G: Ellipse;H: Line;P: Point;Expression(G) = (x^2/16 + y^2/9 = 1);Expression(H) = (3*x - 4*y = 24);PointOnCurve(P, G)",
|
| 119 |
+
"query_expressions": "Max(Distance(P,H));Min(Distance(P,H))",
|
| 120 |
+
"answer_expressions": "12*(2+sqrt(2))/5\n12*(2-sqrt(2))/5",
|
| 121 |
+
"process": "Let the coordinates of point P be (4\\cos\\theta,3\\sin\\theta). The distance d from point P to the line 3x-4y=24 reaches its maximum when \\cos(\\theta+\\frac{\\pi}{4})=-1, and reaches its minimum when \\cos(\\theta+\\frac{\\pi}{4})=1, with the minimum value being \\frac{12(2-}{"
|
| 122 |
+
},
|
| 123 |
+
"sdf_annotation": {
|
| 124 |
+
"params": {
|
| 125 |
+
"a": 4.0,
|
| 126 |
+
"b": 3.0,
|
| 127 |
+
"major_axis": "x",
|
| 128 |
+
"x_coef": 16.0,
|
| 129 |
+
"y_coef": 9.0
|
| 130 |
+
},
|
| 131 |
+
"optimization": {
|
| 132 |
+
"final_loss": 0.0,
|
| 133 |
+
"converged": true,
|
| 134 |
+
"note": "using explicit params"
|
| 135 |
+
},
|
| 136 |
+
"coords": {}
|
| 137 |
+
}
|
| 138 |
+
},
|
| 139 |
+
{
|
| 140 |
+
"dataset": "dev",
|
| 141 |
+
"index": 1034,
|
| 142 |
+
"conic_type": "ellipse",
|
| 143 |
+
"image_path": "samples/dev/ellipse/problem_1034.png",
|
| 144 |
+
"problem": {
|
| 145 |
+
"text": "Given the ellipse $\\frac{x^{2}}{25}+\\frac{y^{2}}{9}=1$, the left and right foci are denoted as $F_{1}$ and $F_{2}$ respectively. A line passing through $F_{1}$ and perpendicular to the major axis intersects the ellipse at points $A$ and $B$. Find the radius of the incircle of triangle $ABF_{2}$.",
|
| 146 |
+
"fact_expressions": "G: Ellipse;H:Line;A: Point;B: Point;F1: Point;F2: Point;Expression(G) = (x^2/25 + y^2/9 = 1);LeftFocus(G)=F1;RightFocus(G)=F2;PointOnCurve(F1,H);IsPerpendicular(H,MajorAxis(G));Intersection(H,G) = {A, B}",
|
| 147 |
+
"query_expressions": "Radius(InscribedCircle(TriangleOf(A,B,F2)))",
|
| 148 |
+
"answer_expressions": "36/25",
|
| 149 |
+
"process": "According to the problem, let the inradius of $\\triangle ABF_{2}$ be $r$, and the perimeter of the triangle be $4a$. Then, derive the expression for the area of the triangle, use $AF_{1}, BF_{1}$ to find the area of $\\triangle ABF_{2}$, and then determine the inradius. [Detailed Solution] According to the problem, let the inradius of $\\triangle ABF_{2}$ be $r$; the equation of the ellipse is $\\frac{x^{2}}{25}+\\frac{y^{2}}{9}=1$, and the perimeter of the triangle is $20$. Hence, $S=\\frac{1}{2}\\times20\\times r=10r$. The line passing through $F_1$ and perpendicular to the major axis intersects the ellipse at points $A$ and $B$. Then, $AB=2\\sqrt{9(1-\\frac{16}{25})}=\\frac{18}{5}$. Therefore, $S=\\frac{1}{2}\\times8\\times\\frac{18}{5}=\\frac{72}{5}$. Thus, $10r=\\frac{72}{5}$, solving gives $r=\\frac{36}{25}$. Therefore, the inradius is $\\frac{36}{25}$."
|
| 150 |
+
},
|
| 151 |
+
"sdf_annotation": {
|
| 152 |
+
"params": {
|
| 153 |
+
"a": 5.0,
|
| 154 |
+
"b": 3.0,
|
| 155 |
+
"major_axis": "x",
|
| 156 |
+
"x_coef": 25.0,
|
| 157 |
+
"y_coef": 9.0
|
| 158 |
+
},
|
| 159 |
+
"optimization": {
|
| 160 |
+
"final_loss": 0.0,
|
| 161 |
+
"converged": true,
|
| 162 |
+
"note": "using explicit params"
|
| 163 |
+
},
|
| 164 |
+
"coords": {}
|
| 165 |
+
}
|
| 166 |
+
},
|
| 167 |
+
{
|
| 168 |
+
"dataset": "dev",
|
| 169 |
+
"index": 0,
|
| 170 |
+
"conic_type": "hyperbola",
|
| 171 |
+
"image_path": "samples/dev/hyperbola/problem_0000.png",
|
| 172 |
+
"problem": {
|
| 173 |
+
"text": "From the left focus $F_{1}$ of the hyperbola $\\frac{x^{2}}{16}-\\frac{y^{2}}{25}=1$, draw a tangent to the circle $x^{2}+y^{2}=16$, with the point of tangency $T$. Extend $F_{1} T$ to intersect the right branch of the hyperbola at point $P$. Let $M$ be the midpoint of segment $F_{1} P$, and let $O$ be the origin. Then $|M O|-|M T|$=?",
|
| 174 |
+
"fact_expressions": "G: Hyperbola;H: Circle;F1: Point;Z: Line;T: Point;P: Point;M: Point;Expression(G) = (x^2/16 - y^2/25 = 1);LeftFocus(G) = F1;Expression(H) = (x^2 + y^2 = 16);TangentOfPoint(F1, H) = Z;TangentPoint(Z, H) = T;Intersection(OverlappingLine(LineSegmentOf(F1, T)), RightPart(G)) = P;MidPoint(LineSegmentOf(F1, P)) = M;O: Origin",
|
| 175 |
+
"query_expressions": "Abs(LineSegmentOf(M, O)) - Abs(LineSegmentOf(M, T))",
|
| 176 |
+
"answer_expressions": "1",
|
| 177 |
+
"process": "Let F' be the right focus of the hyperbola, connect PF'. Since M and O are the midpoints of F_{1}P and F_{1}F' respectively, then |MO| = \\frac{1}{2}|PF'|. By the definition of the hyperbola, |F_{1}P| - |PF'| = 8. Hence, |MO| - |MT| = \\frac{1}{2}|PF| - |MF_{1}| + |F_{1}T| = \\frac{1}{2}(|PF'| - |F_{1}P|) + |F_{1}T| = -4 + 5 = 1"
|
| 178 |
+
},
|
| 179 |
+
"sdf_annotation": {
|
| 180 |
+
"params": {
|
| 181 |
+
"a": 4.0,
|
| 182 |
+
"b": 5.0,
|
| 183 |
+
"orientation": "horizontal"
|
| 184 |
+
},
|
| 185 |
+
"optimization": {
|
| 186 |
+
"final_loss": 0.0,
|
| 187 |
+
"converged": true,
|
| 188 |
+
"note": "using explicit params"
|
| 189 |
+
},
|
| 190 |
+
"coords": {}
|
| 191 |
+
}
|
| 192 |
+
},
|
| 193 |
+
{
|
| 194 |
+
"dataset": "dev",
|
| 195 |
+
"index": 537,
|
| 196 |
+
"conic_type": "hyperbola",
|
| 197 |
+
"image_path": "samples/dev/hyperbola/problem_0537.png",
|
| 198 |
+
"problem": {
|
| 199 |
+
"text": "Given fixed points $A(-5,0)$, $B(5,4)$, and point $P$ being any point on the right branch of the hyperbola $C$: $\\frac{x^{2}}{16}-\\frac{y^{2}}{9}=1$, then the maximum value of $|PB|-|PA|$ is?",
|
| 200 |
+
"fact_expressions": "C: Hyperbola;A: Point;B: Point;P: Point;Expression(C) = (x^2/16 - y^2/9 = 1);Coordinate(A) = (-5, 0);Coordinate(B) = (5, 4);PointOnCurve(P, RightPart(C))",
|
| 201 |
+
"query_expressions": "Max(-Abs(LineSegmentOf(P, A)) + Abs(LineSegmentOf(P, B)))",
|
| 202 |
+
"answer_expressions": "-4",
|
| 203 |
+
"process": "According to the given conditions, a=4, b=3, so c=\\sqrt{a^{2}+b^{2}}=5; therefore, A(-5,0) is the left focus of the hyperbola, and let the right focus be F(5,0). Thus, |PB|-|PA|=|PB|-(|PF|+2a)=|PB|-|PF|-8\\leqslant|BF|-8=4-8=-4, with equality if and only if points P, F, and B are collinear."
|
| 204 |
+
},
|
| 205 |
+
"sdf_annotation": {
|
| 206 |
+
"params": {
|
| 207 |
+
"a": 4.0,
|
| 208 |
+
"b": 3.0,
|
| 209 |
+
"orientation": "horizontal"
|
| 210 |
+
},
|
| 211 |
+
"optimization": {
|
| 212 |
+
"final_loss": 0.0,
|
| 213 |
+
"converged": true,
|
| 214 |
+
"note": "using explicit params"
|
| 215 |
+
},
|
| 216 |
+
"coords": {
|
| 217 |
+
"A": [
|
| 218 |
+
-5.0,
|
| 219 |
+
0.0
|
| 220 |
+
],
|
| 221 |
+
"B": [
|
| 222 |
+
5.0,
|
| 223 |
+
4.0
|
| 224 |
+
]
|
| 225 |
+
}
|
| 226 |
+
}
|
| 227 |
+
},
|
| 228 |
+
{
|
| 229 |
+
"dataset": "dev",
|
| 230 |
+
"index": 1033,
|
| 231 |
+
"conic_type": "hyperbola",
|
| 232 |
+
"image_path": "samples/dev/hyperbola/problem_1033.png",
|
| 233 |
+
"problem": {
|
| 234 |
+
"text": "Given that line $l$ passes through point $P(2, 1)$ and intersects the hyperbola $x^{2}-\\frac{y^{2}}{4}=1$ at points $A$ and $B$, if $P$ is the midpoint of $AB$, then what is the equation of line $l$?",
|
| 235 |
+
"fact_expressions": "l: Line;P: Point;Coordinate(P) = (2, 1);PointOnCurve(P, l);G: Hyperbola;Expression(G) = (x^2 - y^2/4 = 1);Intersection(l, G) = {A, B};A: Point;B: Point;MidPoint(LineSegmentOf(A, B)) = P",
|
| 236 |
+
"query_expressions": "Expression(l)",
|
| 237 |
+
"answer_expressions": "8*x-y-15=0",
|
| 238 |
+
"process": ""
|
| 239 |
+
},
|
| 240 |
+
"sdf_annotation": {
|
| 241 |
+
"params": {
|
| 242 |
+
"a": 1.0,
|
| 243 |
+
"b": 2.0,
|
| 244 |
+
"orientation": "horizontal"
|
| 245 |
+
},
|
| 246 |
+
"optimization": {
|
| 247 |
+
"final_loss": 0.0,
|
| 248 |
+
"converged": true,
|
| 249 |
+
"note": "using explicit params"
|
| 250 |
+
},
|
| 251 |
+
"coords": {
|
| 252 |
+
"P": [
|
| 253 |
+
2.0,
|
| 254 |
+
1.0
|
| 255 |
+
]
|
| 256 |
+
}
|
| 257 |
+
}
|
| 258 |
+
},
|
| 259 |
+
{
|
| 260 |
+
"dataset": "dev",
|
| 261 |
+
"index": 2,
|
| 262 |
+
"conic_type": "parabola",
|
| 263 |
+
"image_path": "samples/dev/parabola/problem_0002.png",
|
| 264 |
+
"problem": {
|
| 265 |
+
"text": "The coordinates of the focus of the parabola $y^{2}=4 x$ are?",
|
| 266 |
+
"fact_expressions": "G: Parabola;Expression(G) = (y^2 = 4*x)",
|
| 267 |
+
"query_expressions": "Coordinate(Focus(G))",
|
| 268 |
+
"answer_expressions": "(1, 0)",
|
| 269 |
+
"process": "The focus of the parabola y^{2}=4x lies on the x-axis, and p=2, \\therefore\\frac{p}{2}=1, so the focus coordinates of the parabola y^{2}=4x are (1,0)."
|
| 270 |
+
},
|
| 271 |
+
"sdf_annotation": {
|
| 272 |
+
"params": {
|
| 273 |
+
"p": 1.0,
|
| 274 |
+
"direction": "right"
|
| 275 |
+
},
|
| 276 |
+
"optimization": {
|
| 277 |
+
"final_loss": 0.0,
|
| 278 |
+
"converged": true,
|
| 279 |
+
"note": "using explicit params"
|
| 280 |
+
},
|
| 281 |
+
"coords": {}
|
| 282 |
+
}
|
| 283 |
+
},
|
| 284 |
+
{
|
| 285 |
+
"dataset": "dev",
|
| 286 |
+
"index": 508,
|
| 287 |
+
"conic_type": "parabola",
|
| 288 |
+
"image_path": "samples/dev/parabola/problem_0508.png",
|
| 289 |
+
"problem": {
|
| 290 |
+
"text": "Given the parabola $y^{2}=4x$ with focus $F$, $A(-1,0)$, and point $P$ being a moving point on the parabola, when the value of $|PF|$ is minimized, $|PF|=$?",
|
| 291 |
+
"fact_expressions": "G: Parabola;A: Point;P: Point;F: Point;Expression(G) = (y^2 = 4*x);Coordinate(A) = (-1, 0);Focus(G) = F;PointOnCurve(P, G);WhenMin(Abs(LineSegmentOf(P, F)))",
|
| 292 |
+
"query_expressions": "Abs(LineSegmentOf(P, F))",
|
| 293 |
+
"answer_expressions": "2",
|
| 294 |
+
"process": "The equation of the directrix of the parabola is x = -1. Let the distance from P to the directrix be |PQ|, then |PQ| = |PF|, \\therefore \\frac{|PF|}{|PA|} = \\frac{|PQ|}{|PA|} = \\sin\\angle PAQ. Therefore, when PA is tangent to the parabola y^{2} = 4x, \\angle PAQ is minimized, i.e., \\frac{|PF|}{|PA|} reaches its minimum value. Suppose the line passing through point A, y = kx + k, is tangent to the parabola (k \\neq 0). Substituting into the parabola equation gives k^{2}x^{2} + (2k^{2} - 4)x + k^{2} = 0. \\therefore \\Delta = (2k^{2} - 4)^{2} - 4k^{4} = 0. Solving yields k = \\pm 1. Then we have x^{2} - 2x + 1 = 0, solving gives x = 1. Substituting x = 1 into y^{2} = 4x gives y = \\pm 2. \\therefore P(1,2) or P(1,-2), \\therefore |PF| = 2."
|
| 295 |
+
},
|
| 296 |
+
"sdf_annotation": {
|
| 297 |
+
"params": {
|
| 298 |
+
"p": 1.0,
|
| 299 |
+
"direction": "right"
|
| 300 |
+
},
|
| 301 |
+
"optimization": {
|
| 302 |
+
"final_loss": 0.0,
|
| 303 |
+
"converged": true,
|
| 304 |
+
"note": "using explicit params"
|
| 305 |
+
},
|
| 306 |
+
"coords": {
|
| 307 |
+
"A": [
|
| 308 |
+
-1.0,
|
| 309 |
+
0.0
|
| 310 |
+
]
|
| 311 |
+
}
|
| 312 |
+
}
|
| 313 |
+
},
|
| 314 |
+
{
|
| 315 |
+
"dataset": "dev",
|
| 316 |
+
"index": 1030,
|
| 317 |
+
"conic_type": "parabola",
|
| 318 |
+
"image_path": "samples/dev/parabola/problem_1030.png",
|
| 319 |
+
"problem": {
|
| 320 |
+
"text": "Given point $P(1,-1)$ and parabola $C$: $y=\\frac{1}{4} x^{2}$, a line passing through the focus of parabola $C$ with slope $k$ intersects parabola $C$ at points $A$ and $B$. If $\\overrightarrow{P A} \\cdot \\overrightarrow{P B}=0$, then $k=?$",
|
| 321 |
+
"fact_expressions": "P: Point;Coordinate(P) = (1, -1);C: Parabola;Expression(C) = (y = x^2/4);G: Line;PointOnCurve(Focus(C), G);k: Number;Slope(G) = k;A: Point;B: Point;Intersection(G, C) = {A, B};DotProduct(VectorOf(P, A), VectorOf(P, B)) = 0",
|
| 322 |
+
"query_expressions": "k",
|
| 323 |
+
"answer_expressions": "1/2",
|
| 324 |
+
"process": "Let the parabola C: y = \\frac{1}{4}x^{2} have focus F; then the coordinates of F are (0,1). Thus, the equation of line AB is y = kx + 1. Let points A(x_{1},y_{1}) and B(x_{2},y_{2}). Substituting the equation of line AB into the equation of parabola C and simplifying yields x^{2} - 4kx - 4 = 0. Then x_{1} + x_{2} = 4k, x_{1}x_{2} = -4. From \\overrightarrow{PA} \\cdot \\overrightarrow{PB} = 0, we obtain (x_{1}-1)(x_{2}-1) + (y_{1}+1)(y_{2}+1) = 0, that is, (x_{1}-1)(x_{2}-1) + (kx_{1}+2)(kx_{2}+2) = 0, which simplifies to (k^{2}+1)x_{1}x_{2} + (2k-1)(x_{1}+x_{2}) + 5 = 0. Therefore, -4(k^{2}+1) + 4k(2k-1) + 5 = (2k-1)^{2} = 0. Solving gives k = \\frac{1}{2}."
|
| 325 |
+
},
|
| 326 |
+
"sdf_annotation": {
|
| 327 |
+
"params": {
|
| 328 |
+
"p": 1.0,
|
| 329 |
+
"direction": "up"
|
| 330 |
+
},
|
| 331 |
+
"optimization": {
|
| 332 |
+
"final_loss": 0.0,
|
| 333 |
+
"converged": true,
|
| 334 |
+
"note": "using explicit params"
|
| 335 |
+
},
|
| 336 |
+
"coords": {
|
| 337 |
+
"P": [
|
| 338 |
+
1.0,
|
| 339 |
+
-1.0
|
| 340 |
+
]
|
| 341 |
+
}
|
| 342 |
+
}
|
| 343 |
+
},
|
| 344 |
+
{
|
| 345 |
+
"dataset": "test",
|
| 346 |
+
"index": 4,
|
| 347 |
+
"conic_type": "circle",
|
| 348 |
+
"image_path": "samples/test/circle/problem_0004.png",
|
| 349 |
+
"problem": {
|
| 350 |
+
"text": "The product of the slopes of the lines connecting a moving point $P$ to fixed points $A(-1,0)$ and $B(1,0)$ is $-1$. Then, what is the trajectory equation of point $P$?",
|
| 351 |
+
"fact_expressions": "P: Point;Slope(LineSegmentOf(P, A))*Slope(LineSegmentOf(P, B)) = -1;A: Point;Coordinate(A) = (-1, 0);B: Point;Coordinate(B) = (1, 0)",
|
| 352 |
+
"query_expressions": "LocusEquation(P)",
|
| 353 |
+
"answer_expressions": "(x^2+y^2=1)&Negation(x=pm*1)",
|
| 354 |
+
"process": "Let P(x,y), then k_{PA}=\\frac{y-0}{x+1}, k_{PB}=\\frac{y-0}{x-1}. Since the product of the slopes of the lines joining the moving point P and the fixed points A(-1,0), B(1,0) is -1, \\therefore k_{PA} \\cdot k_{PB} = -1, \\therefore \\frac{y^{2}}{x^{2}-1} = -1, that is, x^{2} + y^{2} = 1, and x \\neq \\pm 1. In conclusion, the trajectory equation of point P is x^{2} + y^{2} = 1 (x \\neq \\pm 1)."
|
| 355 |
+
},
|
| 356 |
+
"sdf_annotation": {
|
| 357 |
+
"params": {
|
| 358 |
+
"center": [
|
| 359 |
+
0.0,
|
| 360 |
+
0.0
|
| 361 |
+
],
|
| 362 |
+
"radius": 1.0
|
| 363 |
+
},
|
| 364 |
+
"optimization": {
|
| 365 |
+
"final_loss": 0.0,
|
| 366 |
+
"converged": true
|
| 367 |
+
},
|
| 368 |
+
"coords": {}
|
| 369 |
+
}
|
| 370 |
+
},
|
| 371 |
+
{
|
| 372 |
+
"dataset": "test",
|
| 373 |
+
"index": 1202,
|
| 374 |
+
"conic_type": "circle",
|
| 375 |
+
"image_path": "samples/test/circle/problem_1202.png",
|
| 376 |
+
"problem": {
|
| 377 |
+
"text": "Given a line $ l $ with slope $ 1 $ and positive $ y $-intercept $ b $ that intersects the circle $ C: x^{2} + y^{2} = 4 $ at points $ A $ and $ B $, and $ O $ is the origin. If the area of $ \\triangle AOB $ is $ \\sqrt{3} $, then $ b = $?",
|
| 378 |
+
"fact_expressions": "l: Line;C: Circle;A: Point;O: Origin;B: Point;b: Number;Expression(C) = (x^2 + y^2 = 4);Slope(l)=1;b>0;Intercept(l,yAxis)=b;Intersection(l, C) = {A, B};Area(TriangleOf(A, O, B)) = sqrt(3)",
|
| 379 |
+
"query_expressions": "b",
|
| 380 |
+
"answer_expressions": "{sqrt(6),sqrt(2)}",
|
| 381 |
+
"process": "According to the problem, the equation of line $ l $ is $ y = x + b $, the center of circle $ C $ is $ C(0,0) $, and the radius is $ r = 2 $. Using the point-to-line distance formula, $ \\frac{1}{2} \\cdot 2\\sqrt{4 - \\frac{b^{2}}{2}} \\cdot \\frac{|b|}{\\sqrt{3}} = \\sqrt{3} $. Given $ b > 0 $, solving yields $ b = \\sqrt{6} $ or $ \\sqrt{2} $."
|
| 382 |
+
},
|
| 383 |
+
"sdf_annotation": {
|
| 384 |
+
"params": {
|
| 385 |
+
"center": [
|
| 386 |
+
0.0,
|
| 387 |
+
0.0
|
| 388 |
+
],
|
| 389 |
+
"radius": 2.0
|
| 390 |
+
},
|
| 391 |
+
"optimization": {
|
| 392 |
+
"final_loss": 0.0,
|
| 393 |
+
"converged": true
|
| 394 |
+
},
|
| 395 |
+
"coords": {}
|
| 396 |
+
}
|
| 397 |
+
},
|
| 398 |
+
{
|
| 399 |
+
"dataset": "test",
|
| 400 |
+
"index": 1992,
|
| 401 |
+
"conic_type": "circle",
|
| 402 |
+
"image_path": "samples/test/circle/problem_1992.png",
|
| 403 |
+
"problem": {
|
| 404 |
+
"text": "Given that the moving circle $P$ is externally tangent to the fixed circle $C$: $(x+2)^{2}+y^{2}=1$, and also tangent to the line $x=1$, what is the equation of the locus of the center $P$ of the moving circle?",
|
| 405 |
+
"fact_expressions": "P: Circle;G: Line;C:Circle;P1:Point;Expression(C)=((x+2)^2+y^2=1);Expression(G) = (x = 1);IsOutTangent(P,C);IsTangent(P,G);Center(P)=P1",
|
| 406 |
+
"query_expressions": "LocusEquation(P1)",
|
| 407 |
+
"answer_expressions": "y^2=-8*x",
|
| 408 |
+
"process": "Let the distance from the center P of a circle to the line x=1 be equal to r, and let P(x,y). According to the given condition, we have PC = 1 + r, that is, \\sqrt{(x+2)^{2}+y^{2}} = 1 + r. Simplifying yields y^{2} = -8x."
|
| 409 |
+
},
|
| 410 |
+
"sdf_annotation": {
|
| 411 |
+
"params": {
|
| 412 |
+
"center": [
|
| 413 |
+
-2.0,
|
| 414 |
+
0.0
|
| 415 |
+
],
|
| 416 |
+
"radius": 1.0
|
| 417 |
+
},
|
| 418 |
+
"optimization": {
|
| 419 |
+
"final_loss": 0.0,
|
| 420 |
+
"converged": true
|
| 421 |
+
},
|
| 422 |
+
"coords": {}
|
| 423 |
+
}
|
| 424 |
+
},
|
| 425 |
+
{
|
| 426 |
+
"dataset": "test",
|
| 427 |
+
"index": 1,
|
| 428 |
+
"conic_type": "ellipse",
|
| 429 |
+
"image_path": "samples/test/ellipse/problem_0001.png",
|
| 430 |
+
"problem": {
|
| 431 |
+
"text": "An ellipse $\\frac{x^{2}}{k^{2}}+y^{2}=1$ $(k>0)$ has a focus at $(3 , 0)$, then $k=$?",
|
| 432 |
+
"fact_expressions": "G: Ellipse;Expression(G) = (y^2 + x^2/k^2 = 1);k: Number;k>0;Coordinate(OneOf(Focus(G))) = (3,0)",
|
| 433 |
+
"query_expressions": "k",
|
| 434 |
+
"answer_expressions": "sqrt(10)",
|
| 435 |
+
"process": ""
|
| 436 |
+
},
|
| 437 |
+
"sdf_annotation": {
|
| 438 |
+
"params": {
|
| 439 |
+
"a": 2.0,
|
| 440 |
+
"b": 1.0,
|
| 441 |
+
"major_axis": "x",
|
| 442 |
+
"x_coef": 4.0,
|
| 443 |
+
"y_coef": 1.0
|
| 444 |
+
},
|
| 445 |
+
"optimization": {
|
| 446 |
+
"final_loss": 0.0,
|
| 447 |
+
"converged": true,
|
| 448 |
+
"note": "using explicit params"
|
| 449 |
+
},
|
| 450 |
+
"coords": {}
|
| 451 |
+
}
|
| 452 |
+
},
|
| 453 |
+
{
|
| 454 |
+
"dataset": "test",
|
| 455 |
+
"index": 1083,
|
| 456 |
+
"conic_type": "ellipse",
|
| 457 |
+
"image_path": "samples/test/ellipse/problem_1083.png",
|
| 458 |
+
"problem": {
|
| 459 |
+
"text": "The equation of a hyperbola that shares the same foci with the ellipse $x^{2}+4 y^{2}=16$ and has an asymptote given by $x+ \\sqrt {3} y=0$ is?",
|
| 460 |
+
"fact_expressions": "G: Hyperbola;H: Ellipse;Expression(H)=(x^2 + 4*y^2 = 16);Focus(H) = Focus(G);Expression(OneOf(Asymptote(G))) = (x + sqrt(3)*y = 0)",
|
| 461 |
+
"query_expressions": "Expression(G)",
|
| 462 |
+
"answer_expressions": "x^2/9-y^2/3=1",
|
| 463 |
+
"process": ""
|
| 464 |
+
},
|
| 465 |
+
"sdf_annotation": {
|
| 466 |
+
"params": {
|
| 467 |
+
"a": 4.0,
|
| 468 |
+
"b": 2.0,
|
| 469 |
+
"major_axis": "x",
|
| 470 |
+
"x_coef": 16.0,
|
| 471 |
+
"y_coef": 4.0
|
| 472 |
+
},
|
| 473 |
+
"optimization": {
|
| 474 |
+
"final_loss": 0.0,
|
| 475 |
+
"converged": true,
|
| 476 |
+
"note": "using explicit params"
|
| 477 |
+
},
|
| 478 |
+
"coords": {}
|
| 479 |
+
}
|
| 480 |
+
},
|
| 481 |
+
{
|
| 482 |
+
"dataset": "test",
|
| 483 |
+
"index": 2067,
|
| 484 |
+
"conic_type": "ellipse",
|
| 485 |
+
"image_path": "samples/test/ellipse/problem_2067.png",
|
| 486 |
+
"problem": {
|
| 487 |
+
"text": "Given that the foci of the ellipse $\\frac{x^{2}}{9}+\\frac{y^{2}}{2}=1$ are $F_{1}$ and $F_{2}$ respectively, and point $P$ lies on the ellipse. If $|P F_{1}|=4$, then the area of triangle $F_{1} P F_{2}$ is?",
|
| 488 |
+
"fact_expressions": "G: Ellipse;Expression(G) = (x^2/9 + y^2/2 = 1);F1: Point;F2: Point;Focus(G) = {F1, F2};P: Point;PointOnCurve(P, G);Abs(LineSegmentOf(P, F1)) = 4",
|
| 489 |
+
"query_expressions": "Area(TriangleOf(F1, P, F2))",
|
| 490 |
+
"answer_expressions": "2*sqrt(3)",
|
| 491 |
+
"process": ""
|
| 492 |
+
},
|
| 493 |
+
"sdf_annotation": {
|
| 494 |
+
"params": {
|
| 495 |
+
"a": 3.0,
|
| 496 |
+
"b": 1.4142135623730951,
|
| 497 |
+
"major_axis": "x",
|
| 498 |
+
"x_coef": 9.0,
|
| 499 |
+
"y_coef": 2.0
|
| 500 |
+
},
|
| 501 |
+
"optimization": {
|
| 502 |
+
"final_loss": 0.0,
|
| 503 |
+
"converged": true,
|
| 504 |
+
"note": "using explicit params"
|
| 505 |
+
},
|
| 506 |
+
"coords": {}
|
| 507 |
+
}
|
| 508 |
+
},
|
| 509 |
+
{
|
| 510 |
+
"dataset": "test",
|
| 511 |
+
"index": 0,
|
| 512 |
+
"conic_type": "hyperbola",
|
| 513 |
+
"image_path": "samples/test/hyperbola/problem_0000.png",
|
| 514 |
+
"problem": {
|
| 515 |
+
"text": "If the two foci of a hyperbola are $F_{1}(-3,0)$, $F_{2}(3,0)$, and one asymptote has equation $y=\\sqrt{2} x$, then the equation of this hyperbola is?",
|
| 516 |
+
"fact_expressions": "G: Hyperbola;F1: Point;F2: Point;Coordinate(F1) = (-3, 0);Coordinate(F2) = (3, 0);Focus(G)={F1,F2};Expression(OneOf(Asymptote(G))) = (y = sqrt(2)*x)",
|
| 517 |
+
"query_expressions": "Expression(G)",
|
| 518 |
+
"answer_expressions": "x^2/3-y^2/6=1",
|
| 519 |
+
"process": ""
|
| 520 |
+
},
|
| 521 |
+
"sdf_annotation": {
|
| 522 |
+
"params": {
|
| 523 |
+
"a": 1.732385540716972,
|
| 524 |
+
"b": 2.4497476064802375,
|
| 525 |
+
"orientation": "horizontal"
|
| 526 |
+
},
|
| 527 |
+
"optimization": {
|
| 528 |
+
"final_loss": 2.601017381791051e-06,
|
| 529 |
+
"converged": true,
|
| 530 |
+
"iterations": 91
|
| 531 |
+
},
|
| 532 |
+
"coords": {
|
| 533 |
+
"F1": [
|
| 534 |
+
-3.0,
|
| 535 |
+
0.0
|
| 536 |
+
],
|
| 537 |
+
"F2": [
|
| 538 |
+
3.0,
|
| 539 |
+
0.0
|
| 540 |
+
]
|
| 541 |
+
}
|
| 542 |
+
}
|
| 543 |
+
},
|
| 544 |
+
{
|
| 545 |
+
"dataset": "test",
|
| 546 |
+
"index": 969,
|
| 547 |
+
"conic_type": "hyperbola",
|
| 548 |
+
"image_path": "samples/test/hyperbola/problem_0969.png",
|
| 549 |
+
"problem": {
|
| 550 |
+
"text": "Given that $P$ is an intersection point of the ellipse $\\frac{x^{2}}{a_{1}^{2}}+\\frac{y^{2}}{b_{1}^{2}}=1$ $(a_{1}>b_{1}>0)$ and the hyperbola $\\frac{x^{2}}{a_{2}^{2}}-\\frac{y^{2}}{b_{2}^{2}}=1$ $(a_{2}>0, b_{2}>0)$, $F_{1}$, $F_{2}$ are the common foci of the ellipse and the hyperbola, $e_{1}$, $e_{2}$ are the eccentricities of the ellipse and the hyperbola respectively, and if $\\angle F_{1} P F_{2}=\\frac{\\pi}{3}$, then the minimum value of $e_{1} \\cdot e_{2}$ is?",
|
| 551 |
+
"fact_expressions": "G: Hyperbola;H: Ellipse;a2: Number;b2: Number;a1: Number;b1: Number;F1: Point;P: Point;F2: Point;a2>0;b2>0;Expression(G) = (-y^2/b2^2 + x^2/a2^2 = 1);a1>b1;b1>0;Expression(H) = (y^2/b1^2 + x^2/a1^2 = 1);OneOf(Intersection(H, G)) = P;Focus(G) = {F1, F2};Focus(H) = {F1, F2};Focus(G) = Focus(H);e1: Number;e2: Number;Eccentricity(H) = e1;Eccentricity(G) = e2;AngleOf(F1, P, F2) = pi/3",
|
| 552 |
+
"query_expressions": "Min(e1*e2)",
|
| 553 |
+
"answer_expressions": "sqrt(3)/2",
|
| 554 |
+
"process": "By the symmetry of the ellipse and hyperbola, assume without loss of generality that point P lies in the first quadrant, so |PF_{1}| > |PF_{2}|. Since the ellipse and hyperbola share common foci, let the semi-focal length of the ellipse and hyperbola be c. By the definitions of the ellipse and hyperbola, we have: |PF_{1}| + |PF_{2}| = 2a_{1}, |PF_{1}| - |PF_{2}| = 2a_{2}. Solving gives |PF_{1}| = a_{1} + a_{2}, |PF_{2}| = a_{1} - a_{2}. In triangle F_{1}PF_{2}, by the law of cosines, we obtain: |F_{1}F_{2}|^{2} = |PF_{1}|^{2} + |PF_{2}|^{2} - 2|PF_{1}||PF_{2}|\\cos\\frac{\\pi}{3}, that is, 4c^{2} = (a_{1}+a_{2})^{2} + (a_{1}-a_{2})^{2} - (a_{1}+a_{2})(a_{1}-a_{2}). Simplifying yields 4c^{2} = a_{1}^{2} + 3a_{2}^{2}, so \\frac{1}{e_{1}^{2}} + 3\\frac{1}{e_{2}^{2}} = 4. Also, \\frac{1}{e_{1}^{2}} + 3\\frac{1}{e_{2}^{2}} \\geqslant \\frac{2\\sqrt{3}}{e_{1}e_{2}}, therefore e_{1}e_{2} \\geqslant \\frac{\\sqrt{3}}{2}."
|
| 555 |
+
},
|
| 556 |
+
"sdf_annotation": {
|
| 557 |
+
"params": {
|
| 558 |
+
"a": 2.0,
|
| 559 |
+
"b": 1.5,
|
| 560 |
+
"orientation": "horizontal"
|
| 561 |
+
},
|
| 562 |
+
"optimization": {
|
| 563 |
+
"final_loss": 0.0,
|
| 564 |
+
"converged": true,
|
| 565 |
+
"note": "using explicit params"
|
| 566 |
+
},
|
| 567 |
+
"coords": {}
|
| 568 |
+
}
|
| 569 |
+
},
|
| 570 |
+
{
|
| 571 |
+
"dataset": "test",
|
| 572 |
+
"index": 2065,
|
| 573 |
+
"conic_type": "hyperbola",
|
| 574 |
+
"image_path": "samples/test/hyperbola/problem_2065.png",
|
| 575 |
+
"problem": {
|
| 576 |
+
"text": "Through the right focus $F$ of the hyperbola $\\frac{x^{2}}{a^{2}}-\\frac{y^{2}}{b^{2}}=1$ $(a>0, b>0)$, draw a perpendicular line to the asymptote $y=\\frac{b}{a}x$, with foot of perpendicular at $M$. This line intersects the left and right branches of the hyperbola at points $A$ and $B$ respectively. Find the range of values for the eccentricity of the hyperbola?",
|
| 577 |
+
"fact_expressions": "G: Hyperbola;b: Number;a: Number;F: Point;A: Point;B: Point;M:Point;a>0;b>0;Expression(G) = (-y^2/b^2 + x^2/a^2 = 1);RightFocus(G) = F;L:Line;OneOf(Asymptote(G))=L;Expression(L)=(y=(b/a)*x);L1:Line;IsPerpendicular(L,L1);FootPoint(L,L1)=M;PointOnCurve(F, L1);Intersection(L1,LeftPart(G)) = A;Intersection(L1,RightPart(G)) = B",
|
| 578 |
+
"query_expressions": "Range(Eccentricity(G))",
|
| 579 |
+
"answer_expressions": "(sqrt(2),+oo)",
|
| 580 |
+
"process": "Since line AB intersects both the left and right branches of the hyperbola, line AB must intersect the asymptote y=-\\frac{b}{a}x in the second quadrant. Therefore, the slope of line AB must be greater than the slope of the asymptote y=-\\frac{b}{a}x, that is, -\\frac{a}{b}>-\\frac{b}{a}, which implies b^{2}>a^{2}. Since b^{2}=c^{2}-a^{2}, it follows that c^{2}>2a^{2}. The eccentricity of the hyperbola e=\\frac{c}{a}>\\sqrt{2}. Therefore, the range of values for the eccentricity of the hyperbola is (\\sqrt{2},+\\infty)."
|
| 581 |
+
},
|
| 582 |
+
"sdf_annotation": {
|
| 583 |
+
"params": {
|
| 584 |
+
"a": 2.0,
|
| 585 |
+
"b": 1.5,
|
| 586 |
+
"orientation": "horizontal"
|
| 587 |
+
},
|
| 588 |
+
"optimization": {
|
| 589 |
+
"final_loss": 0.0,
|
| 590 |
+
"converged": true,
|
| 591 |
+
"note": "using explicit params"
|
| 592 |
+
},
|
| 593 |
+
"coords": {}
|
| 594 |
+
}
|
| 595 |
+
},
|
| 596 |
+
{
|
| 597 |
+
"dataset": "test",
|
| 598 |
+
"index": 2,
|
| 599 |
+
"conic_type": "parabola",
|
| 600 |
+
"image_path": "samples/test/parabola/problem_0002.png",
|
| 601 |
+
"problem": {
|
| 602 |
+
"text": "Given any point $P$ on the parabola $y^{2}=4 x$, let $d$ be the distance from point $P$ to the $y$-axis. For a given point $A(4,5)$, what is the minimum value of $|P A|+d$?",
|
| 603 |
+
"fact_expressions": "G: Parabola;A: Point;P: Point;Expression(G) = (y^2 = 4*x);Coordinate(A) = (4, 5);PointOnCurve(P,G);Distance(P, yAxis) = d;d:Number",
|
| 604 |
+
"query_expressions": "Min(d + Abs(LineSegmentOf(P, A)))",
|
| 605 |
+
"answer_expressions": "sqrt(34)-1",
|
| 606 |
+
"process": "The directrix of the parabola is x = -1. Extending the distance from P to the y-axis one unit further to the left gives the distance from P to the directrix. According to the definition of a parabola, the distance from P to the directrix equals the distance from P to the focus F(1,0). Therefore, |PA| + d = |PA| + |PF| - 1. Since A lies outside the parabola, the minimum value occurs when A, P, and F are collinear (i.e., P is the intersection point of segment AF and the parabola). The minimum value is |AF| - 1 = \\sqrt{(9+25)} - 1 = \\sqrt{34} - 1^{n}"
|
| 607 |
+
},
|
| 608 |
+
"sdf_annotation": {
|
| 609 |
+
"params": {
|
| 610 |
+
"p": 1.0,
|
| 611 |
+
"direction": "right"
|
| 612 |
+
},
|
| 613 |
+
"optimization": {
|
| 614 |
+
"final_loss": 0.0,
|
| 615 |
+
"converged": true,
|
| 616 |
+
"note": "using explicit params"
|
| 617 |
+
},
|
| 618 |
+
"coords": {
|
| 619 |
+
"A": [
|
| 620 |
+
4.0,
|
| 621 |
+
5.0
|
| 622 |
+
]
|
| 623 |
+
}
|
| 624 |
+
}
|
| 625 |
+
},
|
| 626 |
+
{
|
| 627 |
+
"dataset": "test",
|
| 628 |
+
"index": 1025,
|
| 629 |
+
"conic_type": "parabola",
|
| 630 |
+
"image_path": "samples/test/parabola/problem_1025.png",
|
| 631 |
+
"problem": {
|
| 632 |
+
"text": "The focus of the parabola $y^{2}=2 x$ is $F$. If $P(2, y)$ lies on the parabola, then $|PF|=$?",
|
| 633 |
+
"fact_expressions": "G: Parabola;F: Point;P: Point;y1: Number;Expression(G) = (y^2 = 2*x);Coordinate(P) = (2, y1);Focus(G) = F;PointOnCurve(P, G)",
|
| 634 |
+
"query_expressions": "Abs(LineSegmentOf(P, F))",
|
| 635 |
+
"answer_expressions": "5/2",
|
| 636 |
+
"process": ""
|
| 637 |
+
},
|
| 638 |
+
"sdf_annotation": {
|
| 639 |
+
"params": {
|
| 640 |
+
"p": 0.5,
|
| 641 |
+
"direction": "right"
|
| 642 |
+
},
|
| 643 |
+
"optimization": {
|
| 644 |
+
"final_loss": 0.0,
|
| 645 |
+
"converged": true,
|
| 646 |
+
"note": "using explicit params"
|
| 647 |
+
},
|
| 648 |
+
"coords": {}
|
| 649 |
+
}
|
| 650 |
+
},
|
| 651 |
+
{
|
| 652 |
+
"dataset": "test",
|
| 653 |
+
"index": 2068,
|
| 654 |
+
"conic_type": "parabola",
|
| 655 |
+
"image_path": "samples/test/parabola/problem_2068.png",
|
| 656 |
+
"problem": {
|
| 657 |
+
"text": "Let $F$ be the focus of the parabola $C$: $y^{2}=8 x$. A line passing through $F$ with an inclination angle of $30^{\\circ}$ intersects $C$ at points $A$ and $B$. Then $|A B|$=?",
|
| 658 |
+
"fact_expressions": "C: Parabola;Expression(C) = (y^2 = 8*x);F: Point;Focus(C) = F;G: Line;PointOnCurve(F, G);Inclination(G) = ApplyUnit(30, degree);A: Point;B: Point;Intersection(G, C) = {A, B}",
|
| 659 |
+
"query_expressions": "Abs(LineSegmentOf(A, B))",
|
| 660 |
+
"answer_expressions": "32",
|
| 661 |
+
"process": "From $ y^{2} = 8x $, we get $ 2p = 8 $, $ p = 4 $, then $ F(2,0) $. Therefore, the equation of the line passing through $ A $ and $ B $ is $ y = \\frac{\\sqrt{3}}{3}(x - 2) $. Solving the system \n\\[\n\\begin{cases}\ny^{2} = 8x \\\\\ny = \\frac{\\sqrt{3}}{3}(x - 2)\n\\end{cases}\n\\]\nyields $ x^{2} - 28x + 4 = 0 $. Let $ A(x_{1}, y_{1}) $, $ B(x_{2}, y_{2}) $, then $ x_{1} + x_{2} = 28 $, and since $ |AB| = x_{1} + x_{2} + p = 28 + 4 = 32 $."
|
| 662 |
+
},
|
| 663 |
+
"sdf_annotation": {
|
| 664 |
+
"params": {
|
| 665 |
+
"p": 2.0,
|
| 666 |
+
"direction": "right"
|
| 667 |
+
},
|
| 668 |
+
"optimization": {
|
| 669 |
+
"final_loss": 0.0,
|
| 670 |
+
"converged": true,
|
| 671 |
+
"note": "using explicit params"
|
| 672 |
+
},
|
| 673 |
+
"coords": {}
|
| 674 |
+
}
|
| 675 |
+
},
|
| 676 |
+
{
|
| 677 |
+
"dataset": "train",
|
| 678 |
+
"index": 85,
|
| 679 |
+
"conic_type": "circle",
|
| 680 |
+
"image_path": "samples/train/circle/problem_0085.png",
|
| 681 |
+
"problem": {
|
| 682 |
+
"text": "The two foci of the ellipse $x^{2}+k y^{2}=1$ lie on the circle $x^{2}+y^{2}=4$. Then the real number $k$=?",
|
| 683 |
+
"fact_expressions": "G: Ellipse;k: Real;H: Circle;Expression(G) = (k*y^2 + x^2 = 1);Expression(H) = (x^2 + y^2 = 4);PointOnCurve(Focus(G), H)",
|
| 684 |
+
"query_expressions": "k",
|
| 685 |
+
"answer_expressions": "1/5",
|
| 686 |
+
"process": "Since the two foci of the ellipse $x^{2}+ky^{2}=1$ lie on the circle $x^{2}+y^{2}=4$, we have $c=2$. Because $x^{2}+\\frac{y^{2}}{\\frac{1}{k}}=1$, when $0<k<1$, $a^{2}=\\frac{1}{k}$, $b^{2}=1$, and from $a^{2}=b^{2}+c^{2}$ we obtain $k=\\frac{1}{5}$. When $k>1$, $b^{2}=\\frac{1}{k}$, $a^{2}=1$, which does not hold. Therefore, $k=\\frac{1}{5}$."
|
| 687 |
+
},
|
| 688 |
+
"sdf_annotation": {
|
| 689 |
+
"params": {
|
| 690 |
+
"center": [
|
| 691 |
+
0.0,
|
| 692 |
+
0.0
|
| 693 |
+
],
|
| 694 |
+
"radius": 2.0
|
| 695 |
+
},
|
| 696 |
+
"optimization": {
|
| 697 |
+
"final_loss": 0.0,
|
| 698 |
+
"converged": true
|
| 699 |
+
},
|
| 700 |
+
"coords": {}
|
| 701 |
+
}
|
| 702 |
+
},
|
| 703 |
+
{
|
| 704 |
+
"dataset": "train",
|
| 705 |
+
"index": 4027,
|
| 706 |
+
"conic_type": "circle",
|
| 707 |
+
"image_path": "samples/train/circle/problem_4027.png",
|
| 708 |
+
"problem": {
|
| 709 |
+
"text": "Given the circle $(x+2)^{2}+y^{2}=64$ with center $M$, let $A$ be any point on the circle, and let $N(2,0)$. The perpendicular bisector of segment $AN$ intersects $MA$ at point $P$. What is the equation of the locus of the moving point $P$?",
|
| 710 |
+
"fact_expressions": "G: Circle;Expression(G) = (y^2 + (x + 2)^2 = 64);M: Point;Center(G) = M;A: Point;PointOnCurve(A, G);N: Point;Coordinate(N) = (2, 0);P: Point;Intersection(PerpendicularBisector(LineSegmentOf(A, N)), LineSegmentOf(M, A)) = P",
|
| 711 |
+
"query_expressions": "LocusEquation(P)",
|
| 712 |
+
"answer_expressions": "x^2/16+y^2/12=1",
|
| 713 |
+
"process": "According to the problem, the circle $(x+2)^{2}+y^{2}=64$ has center $M(-2,0)$, and point $N(2,0)$. The perpendicular bisector of segment $AN$ intersects $MA$ at point $P$. Therefore, $P$ lies on the perpendicular bisector of $AN$, so $PA=PN$. Also, since $|AM|=8$, the point $P$ satisfies $|PM|+|PN|=8>4$. According to the definition of an ellipse, the locus of point $P$ is an ellipse with foci $M$ and $N$, where $2a=8$, $2c=4$, giving $a=4$, $c=2$, so $b=\\sqrt{a^{2}-c^{2}}=\\sqrt{12}$. Thus, the equation of the ellipse is $\\frac{x^{2}}{16}+\\frac{y^{2}}{12}=1$."
|
| 714 |
+
},
|
| 715 |
+
"sdf_annotation": {
|
| 716 |
+
"params": {
|
| 717 |
+
"center": [
|
| 718 |
+
2.0,
|
| 719 |
+
0.0
|
| 720 |
+
],
|
| 721 |
+
"radius": 8.0
|
| 722 |
+
},
|
| 723 |
+
"optimization": {
|
| 724 |
+
"final_loss": 0.0,
|
| 725 |
+
"converged": true
|
| 726 |
+
},
|
| 727 |
+
"coords": {}
|
| 728 |
+
}
|
| 729 |
+
},
|
| 730 |
+
{
|
| 731 |
+
"dataset": "train",
|
| 732 |
+
"index": 7579,
|
| 733 |
+
"conic_type": "circle",
|
| 734 |
+
"image_path": "samples/train/circle/problem_7579.png",
|
| 735 |
+
"problem": {
|
| 736 |
+
"text": "If from any point $P$ on the circle $x^{2}+y^{2}=1$, a perpendicular line segment is drawn to the $y$-axis, then the trajectory equation of the midpoint $M$ of this line segment is?",
|
| 737 |
+
"fact_expressions": "G: Circle;H: LineSegment;Expression(G) = (x^2 + y^2 = 1);PointOnCurve(P,G);IsPerpendicular(H,yAxis);M:Point;MidPoint(H)=M;P:Point",
|
| 738 |
+
"query_expressions": "LocusEquation(M)",
|
| 739 |
+
"answer_expressions": "4*x^2+y^2=1",
|
| 740 |
+
"process": "Let the coordinates of point M be (x, y) and the coordinates of point P be (x_{0}, y_{0}). Then from the given conditions, we have x = \\frac{x_{0}}{2}, y = y_{0}. Since P(x_{0}, y_{0}) lies on the circle x^{2} + y^{2} = 1, it follows that x_{0}^{2} + y_{0}^{2} = 1. Substituting x_{0} = 2x, y_{0} = y into the equation x_{0}^{2} + y_{0}^{2} = 1, we obtain 4x^{2} + y^{2} = 1. Therefore, the trajectory equation of point M is 4x^{2} + y^{2} = 1."
|
| 741 |
+
},
|
| 742 |
+
"sdf_annotation": {
|
| 743 |
+
"params": {
|
| 744 |
+
"center": [
|
| 745 |
+
0.0,
|
| 746 |
+
0.0
|
| 747 |
+
],
|
| 748 |
+
"radius": 1.0
|
| 749 |
+
},
|
| 750 |
+
"optimization": {
|
| 751 |
+
"final_loss": 0.0,
|
| 752 |
+
"converged": true
|
| 753 |
+
},
|
| 754 |
+
"coords": {}
|
| 755 |
+
}
|
| 756 |
+
},
|
| 757 |
+
{
|
| 758 |
+
"dataset": "train",
|
| 759 |
+
"index": 0,
|
| 760 |
+
"conic_type": "ellipse",
|
| 761 |
+
"image_path": "samples/train/ellipse/problem_0000.png",
|
| 762 |
+
"problem": {
|
| 763 |
+
"text": "The eccentricity of the ellipse $\\frac{x^{2}}{2}+\\frac{y^{2}}{3}=1$ is?",
|
| 764 |
+
"fact_expressions": "G: Ellipse;Expression(G) = (x^2/2 + y^2/3 = 1)",
|
| 765 |
+
"query_expressions": "Eccentricity(G)",
|
| 766 |
+
"answer_expressions": "sqrt(3)/3",
|
| 767 |
+
"process": ""
|
| 768 |
+
},
|
| 769 |
+
"sdf_annotation": {
|
| 770 |
+
"params": {
|
| 771 |
+
"a": 1.7320508075688772,
|
| 772 |
+
"b": 1.4142135623730951,
|
| 773 |
+
"major_axis": "y",
|
| 774 |
+
"x_coef": 2.0,
|
| 775 |
+
"y_coef": 3.0
|
| 776 |
+
},
|
| 777 |
+
"optimization": {
|
| 778 |
+
"final_loss": 0.0,
|
| 779 |
+
"converged": true,
|
| 780 |
+
"note": "using explicit params"
|
| 781 |
+
},
|
| 782 |
+
"coords": {}
|
| 783 |
+
}
|
| 784 |
+
},
|
| 785 |
+
{
|
| 786 |
+
"dataset": "train",
|
| 787 |
+
"index": 3849,
|
| 788 |
+
"conic_type": "ellipse",
|
| 789 |
+
"image_path": "samples/train/ellipse/problem_3849.png",
|
| 790 |
+
"problem": {
|
| 791 |
+
"text": "Given the parabola $C_{1}$: $y=a x^{2} (a>0)$, the focus $F$ of which is also a focus of the ellipse $C_{2}$: $\\frac{y^{2}}{4}+\\frac{x^{2}}{b^{2}}=1 (b>0)$. Points $M$ and $P(\\frac{3}{2}, 1)$ are on curves $C_{1}$ and $C_{2}$ respectively. Then the minimum value of $|M P|+|M F|$ is?",
|
| 792 |
+
"fact_expressions": "C1: Parabola;Expression(C1) = (y = a*x^2);a: Number;a>0;F: Point;Focus(C1) = F;C2: Ellipse;Expression(C2) = (y^2/4 + x^2/b^2 = 1);b: Number;b>0;OneOf(Focus(C2)) = F;M: Point;PointOnCurve(M, C1);P: Point;Coordinate(P) = (3/2, 1);PointOnCurve(P, C2)",
|
| 793 |
+
"query_expressions": "Min(Abs(LineSegmentOf(M, F)) + Abs(LineSegmentOf(M, P)))",
|
| 794 |
+
"answer_expressions": "2",
|
| 795 |
+
"process": "Since point $ P\\left(\\frac{3}{2},1\\right) $ lies on the ellipse $ C_{2} $, and $ b>0 $, we have $ \\frac{1}{4}+\\frac{\\left(\\frac{3}{2}\\right)^{2}}{b^{2}}=1 \\Rightarrow b=\\sqrt{3} $, so the coordinates of focus $ F $ are $ (0,1) $. Also, from the equation of parabola $ C_{1} $, we get $ F\\left(0,\\frac{1}{4a}\\right) $, so $ \\frac{1}{4a}=1 \\Rightarrow a=\\frac{1}{4} $, then $ c_{1}: y=\\frac{1}{4}x^{2} $. By the definition of the parabola, $ |MF| $ equals the distance $ d $ from point $ M $ to its directrix $ l: y=-1 $. Draw a perpendicular line $ l': x=\\frac{3}{2} $ from point $ P $ to the directrix $ l: y=-1 $. Then the intersection point of the perpendicular line $ l': x=\\frac{3}{2} $ and the parabola $ C_{1}: y=\\frac{1}{4}x^{2} $ is the desired point $ M $. Therefore, the minimum value of $ |MP|+|MF|=|MP|+d $ is $ 1-(-1)=2 $."
|
| 796 |
+
},
|
| 797 |
+
"sdf_annotation": {
|
| 798 |
+
"params": {
|
| 799 |
+
"a": 1.8537487983703613,
|
| 800 |
+
"b": 1.6118527266061986,
|
| 801 |
+
"major_axis": "x",
|
| 802 |
+
"x_coef": 4.0,
|
| 803 |
+
"y_coef": 3.0
|
| 804 |
+
},
|
| 805 |
+
"optimization": {
|
| 806 |
+
"final_loss": 1.4665974334810584e-06,
|
| 807 |
+
"converged": true,
|
| 808 |
+
"iterations": 90
|
| 809 |
+
},
|
| 810 |
+
"coords": {
|
| 811 |
+
"P": [
|
| 812 |
+
1.5,
|
| 813 |
+
1.0
|
| 814 |
+
]
|
| 815 |
+
}
|
| 816 |
+
}
|
| 817 |
+
},
|
| 818 |
+
{
|
| 819 |
+
"dataset": "train",
|
| 820 |
+
"index": 7753,
|
| 821 |
+
"conic_type": "ellipse",
|
| 822 |
+
"image_path": "samples/train/ellipse/problem_7753.png",
|
| 823 |
+
"problem": {
|
| 824 |
+
"text": "The eccentricity of the ellipse $\\frac{y^{2}}{3}+x^{2}=1$ is?",
|
| 825 |
+
"fact_expressions": "G: Ellipse;Expression(G) = (x^2 + y^2/3 = 1)",
|
| 826 |
+
"query_expressions": "Eccentricity(G)",
|
| 827 |
+
"answer_expressions": "sqrt(6)/3",
|
| 828 |
+
"process": "Find the values of a, b, and c, then determine the eccentricity of the ellipse \\frac{y^{2}}{3}+x^{2}=1. In the ellipse \\frac{y^{2}}{3}+x^{2}=1, a=\\sqrt{3}, b=1, c=\\sqrt{a^{2}-b^{2}}=\\sqrt{2}. Therefore, the eccentricity of the ellipse \\frac{y^{2}}{3}+x^{2}=1 is e=\\frac{c}{a}=\\frac{\\sqrt{2}}{\\sqrt{3}}=\\frac{\\sqrt{6}}{3}"
|
| 829 |
+
},
|
| 830 |
+
"sdf_annotation": {
|
| 831 |
+
"params": {
|
| 832 |
+
"a": 2.0,
|
| 833 |
+
"b": 1.0,
|
| 834 |
+
"major_axis": "y",
|
| 835 |
+
"x_coef": 1.0,
|
| 836 |
+
"y_coef": 4.0
|
| 837 |
+
},
|
| 838 |
+
"optimization": {
|
| 839 |
+
"final_loss": 0.0,
|
| 840 |
+
"converged": true,
|
| 841 |
+
"note": "using explicit params"
|
| 842 |
+
},
|
| 843 |
+
"coords": {}
|
| 844 |
+
}
|
| 845 |
+
},
|
| 846 |
+
{
|
| 847 |
+
"dataset": "train",
|
| 848 |
+
"index": 1,
|
| 849 |
+
"conic_type": "hyperbola",
|
| 850 |
+
"image_path": "samples/train/hyperbola/problem_0001.png",
|
| 851 |
+
"problem": {
|
| 852 |
+
"text": "Given that one asymptote of the hyperbola $\\frac{x^{2}}{4}-\\frac{y^{2}}{m^{2}}=1$ $(m>0)$ is $5 x-2 y=0$, then $m=$?",
|
| 853 |
+
"fact_expressions": "G: Hyperbola;m: Number;m>0;Expression(G) = (x^2/4 - y^2/m^2 = 1);Expression(OneOf(Asymptote(G))) = (5*x - 2*y = 0)",
|
| 854 |
+
"query_expressions": "m",
|
| 855 |
+
"answer_expressions": "5",
|
| 856 |
+
"process": "The asymptotes of the hyperbola $\\frac{x^{2}}{4}-\\frac{y^{2}}{m^{2}}=1$ $(m>0)$ are given by $y=\\pm\\frac{m}{2}x$. The equation of the line $5x-2y=0$ can be rewritten as $y=\\frac{5}{2}x$, so $m=5$."
|
| 857 |
+
},
|
| 858 |
+
"sdf_annotation": {
|
| 859 |
+
"params": {
|
| 860 |
+
"a": 2.0,
|
| 861 |
+
"b": 1.5,
|
| 862 |
+
"orientation": "horizontal"
|
| 863 |
+
},
|
| 864 |
+
"optimization": {
|
| 865 |
+
"final_loss": 0.0,
|
| 866 |
+
"converged": true,
|
| 867 |
+
"note": "using explicit params"
|
| 868 |
+
},
|
| 869 |
+
"coords": {}
|
| 870 |
+
}
|
| 871 |
+
},
|
| 872 |
+
{
|
| 873 |
+
"dataset": "train",
|
| 874 |
+
"index": 3822,
|
| 875 |
+
"conic_type": "hyperbola",
|
| 876 |
+
"image_path": "samples/train/hyperbola/problem_3822.png",
|
| 877 |
+
"problem": {
|
| 878 |
+
"text": "The distance from the focus of the hyperbola $\\frac{x^{2}}{4}-\\frac{y^{2}}{12}=1$ to its asymptote is?",
|
| 879 |
+
"fact_expressions": "G: Hyperbola;Expression(G) = (x^2/4 - y^2/12 = 1)",
|
| 880 |
+
"query_expressions": "Distance(Focus(G), Asymptote(G))",
|
| 881 |
+
"answer_expressions": "Preserve all mathematical expressions exactly (including LaTeX format, symbols, and numbers). \nDo not add explanations.",
|
| 882 |
+
"process": ""
|
| 883 |
+
},
|
| 884 |
+
"sdf_annotation": {
|
| 885 |
+
"params": {
|
| 886 |
+
"a": 2.0,
|
| 887 |
+
"b": 3.4641016151377544,
|
| 888 |
+
"orientation": "horizontal"
|
| 889 |
+
},
|
| 890 |
+
"optimization": {
|
| 891 |
+
"final_loss": 0.0,
|
| 892 |
+
"converged": true,
|
| 893 |
+
"note": "using explicit params"
|
| 894 |
+
},
|
| 895 |
+
"coords": {}
|
| 896 |
+
}
|
| 897 |
+
},
|
| 898 |
+
{
|
| 899 |
+
"dataset": "train",
|
| 900 |
+
"index": 7756,
|
| 901 |
+
"conic_type": "hyperbola",
|
| 902 |
+
"image_path": "samples/train/hyperbola/problem_7756.png",
|
| 903 |
+
"problem": {
|
| 904 |
+
"text": "Given the hyperbola $\\frac{x^{2}}{3}-y^{2}=1$, the left and right foci are $F_{1}$ and $F_{2}$ respectively, $P$ is a point on the right branch of the hyperbola, and the coordinates of point $Q$ are $(-2,3)$. Then the minimum value of $|P Q|+|P F_{1}|$ is?",
|
| 905 |
+
"fact_expressions": "G: Hyperbola;Expression(G) = (x^2/3 - y^2 = 1);F1: Point;F2: Point;LeftFocus(G) = F1;RightFocus(G) = F2;P: Point;PointOnCurve(P, RightPart(G));Q: Point;Coordinate(Q) = (-2, 3)",
|
| 906 |
+
"query_expressions": "Min(Abs(LineSegmentOf(P, F1)) + Abs(LineSegmentOf(P, Q)))",
|
| 907 |
+
"answer_expressions": "5+2*sqrt(3)",
|
| 908 |
+
"process": ""
|
| 909 |
+
},
|
| 910 |
+
"sdf_annotation": {
|
| 911 |
+
"params": {
|
| 912 |
+
"a": 1.7320508075688772,
|
| 913 |
+
"b": 1.0,
|
| 914 |
+
"orientation": "horizontal"
|
| 915 |
+
},
|
| 916 |
+
"optimization": {
|
| 917 |
+
"final_loss": 0.0,
|
| 918 |
+
"converged": true,
|
| 919 |
+
"note": "using explicit params"
|
| 920 |
+
},
|
| 921 |
+
"coords": {
|
| 922 |
+
"Q": [
|
| 923 |
+
-2.0,
|
| 924 |
+
3.0
|
| 925 |
+
]
|
| 926 |
+
}
|
| 927 |
+
}
|
| 928 |
+
},
|
| 929 |
+
{
|
| 930 |
+
"dataset": "train",
|
| 931 |
+
"index": 4,
|
| 932 |
+
"conic_type": "parabola",
|
| 933 |
+
"image_path": "samples/train/parabola/problem_0004.png",
|
| 934 |
+
"problem": {
|
| 935 |
+
"text": "The parabola $x^{2}=a y$ passes through the point $A(1, \\frac{1}{4})$, then the distance from point $A$ to the focus of this parabola is?",
|
| 936 |
+
"fact_expressions": "G: Parabola;Expression(G) = (x^2 = a*y);a: Number;A: Point;Coordinate(A) = (1, 1/4);PointOnCurve(A, G)",
|
| 937 |
+
"query_expressions": "Distance(A, Focus(G))",
|
| 938 |
+
"answer_expressions": "5/4",
|
| 939 |
+
"process": "\\because the parabola x^{2}=ay passes through point A(1,\\frac{1}{4}), \\therefore 1^{2}=a\\times\\frac{1}{4}, solving gives a=4. Therefore, the equation of the parabola is x^{2}=4y, yielding its focus at F(0,1) and directrix equation y=-1. \\because the distance from any point on the parabola to the focus equals the distance from that point to the directrix of the parabola, \\therefore the distance from point A to the focus of this parabola is y_{4}-(-1)=\\frac{1}{4}+1=\\frac{5}{4}"
|
| 940 |
+
},
|
| 941 |
+
"sdf_annotation": {
|
| 942 |
+
"params": {
|
| 943 |
+
"p": 0.9959803819656372,
|
| 944 |
+
"direction": "up"
|
| 945 |
+
},
|
| 946 |
+
"optimization": {
|
| 947 |
+
"final_loss": 3.6780886603082763e-07,
|
| 948 |
+
"converged": true,
|
| 949 |
+
"iterations": 56
|
| 950 |
+
},
|
| 951 |
+
"coords": {
|
| 952 |
+
"A": [
|
| 953 |
+
1.0,
|
| 954 |
+
0.25
|
| 955 |
+
]
|
| 956 |
+
}
|
| 957 |
+
}
|
| 958 |
+
},
|
| 959 |
+
{
|
| 960 |
+
"dataset": "train",
|
| 961 |
+
"index": 3812,
|
| 962 |
+
"conic_type": "parabola",
|
| 963 |
+
"image_path": "samples/train/parabola/problem_3812.png",
|
| 964 |
+
"problem": {
|
| 965 |
+
"text": "A point $M$ on the parabola $y=4 x^{2}$ is at a distance of $1$ from the focus. What is the ordinate of point $M$?",
|
| 966 |
+
"fact_expressions": "G: Parabola;Expression(G) = (y = 4*x^2);M: Point;PointOnCurve(M, G);Distance(M, Focus(G)) = 1",
|
| 967 |
+
"query_expressions": "YCoordinate(M)",
|
| 968 |
+
"answer_expressions": "15/16",
|
| 969 |
+
"process": "From $ y = 4x^{2} $, we obtain $ x^{2} = \\frac{1}{4}y $, so the focus of the parabola is $ F(0, \\frac{1}{16}) $, and the equation of the directrix is $ y = -\\frac{1}{16} $. Let $ M(x_{M}, y_{M}) $. By the definition of the parabola, we have $ MF = y_{M} + \\frac{1}{16} = 1 $, so $ y_{M} = \\frac{15}{16} $."
|
| 970 |
+
},
|
| 971 |
+
"sdf_annotation": {
|
| 972 |
+
"params": {
|
| 973 |
+
"p": 0.0625,
|
| 974 |
+
"direction": "up"
|
| 975 |
+
},
|
| 976 |
+
"optimization": {
|
| 977 |
+
"final_loss": 0.0,
|
| 978 |
+
"converged": true,
|
| 979 |
+
"note": "using explicit params"
|
| 980 |
+
},
|
| 981 |
+
"coords": {}
|
| 982 |
+
}
|
| 983 |
+
},
|
| 984 |
+
{
|
| 985 |
+
"dataset": "train",
|
| 986 |
+
"index": 7755,
|
| 987 |
+
"conic_type": "parabola",
|
| 988 |
+
"image_path": "samples/train/parabola/problem_7755.png",
|
| 989 |
+
"problem": {
|
| 990 |
+
"text": "If the distance from point $P$ on the parabola $x^{2}=8y$ to the focus is $12$, then what is the distance from $P$ to the $x$-axis?",
|
| 991 |
+
"fact_expressions": "G: Parabola;P: Point;Expression(G) = (x^2 = 8*y);PointOnCurve(P, G);Distance(P, Focus(G)) = 12",
|
| 992 |
+
"query_expressions": "Distance(P, xAxis)",
|
| 993 |
+
"answer_expressions": "10",
|
| 994 |
+
"process": "Since the parabola is $x^{2}=8y$, the focus coordinates are $(0,2)$, and the directrix equation is $y=-2$. Because the distance from point $P$ to the focus is $12$, according to the definition of a parabola, the distance from $P$ to the directrix is also $12$. Therefore, the distance from point $P$ to the $x$-axis is $10$."
|
| 995 |
+
},
|
| 996 |
+
"sdf_annotation": {
|
| 997 |
+
"params": {
|
| 998 |
+
"p": 2.0,
|
| 999 |
+
"direction": "up"
|
| 1000 |
+
},
|
| 1001 |
+
"optimization": {
|
| 1002 |
+
"final_loss": 0.0,
|
| 1003 |
+
"converged": true,
|
| 1004 |
+
"note": "using explicit params"
|
| 1005 |
+
},
|
| 1006 |
+
"coords": {}
|
| 1007 |
+
}
|
| 1008 |
+
}
|
| 1009 |
+
]
|
annotations/test.json
ADDED
|
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|
|
annotations/train.json
ADDED
|
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|
|
|
create_samples.py
ADDED
|
@@ -0,0 +1,71 @@
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|
|
|
| 1 |
+
#!/usr/bin/env python3
|
| 2 |
+
"""
|
| 3 |
+
Create a samples directory with a few examples from each curve type.
|
| 4 |
+
"""
|
| 5 |
+
import os
|
| 6 |
+
import shutil
|
| 7 |
+
import json
|
| 8 |
+
|
| 9 |
+
# Configuration
|
| 10 |
+
SAMPLES_PER_TYPE = 3 # Number of samples per curve type per dataset
|
| 11 |
+
SOURCE_DIR = "results"
|
| 12 |
+
TARGET_DIR = "samples"
|
| 13 |
+
|
| 14 |
+
def create_samples():
|
| 15 |
+
# Remove existing samples directory
|
| 16 |
+
if os.path.exists(TARGET_DIR):
|
| 17 |
+
shutil.rmtree(TARGET_DIR)
|
| 18 |
+
|
| 19 |
+
os.makedirs(TARGET_DIR)
|
| 20 |
+
|
| 21 |
+
datasets = ['dev', 'test', 'train']
|
| 22 |
+
curve_types = ['circle', 'ellipse', 'hyperbola', 'parabola']
|
| 23 |
+
|
| 24 |
+
total_copied = 0
|
| 25 |
+
|
| 26 |
+
for dataset in datasets:
|
| 27 |
+
dataset_dir = os.path.join(SOURCE_DIR, dataset)
|
| 28 |
+
if not os.path.exists(dataset_dir):
|
| 29 |
+
continue
|
| 30 |
+
|
| 31 |
+
target_dataset_dir = os.path.join(TARGET_DIR, dataset)
|
| 32 |
+
os.makedirs(target_dataset_dir, exist_ok=True)
|
| 33 |
+
|
| 34 |
+
# Copy summary.json
|
| 35 |
+
summary_src = os.path.join(dataset_dir, 'summary.json')
|
| 36 |
+
if os.path.exists(summary_src):
|
| 37 |
+
shutil.copy(summary_src, target_dataset_dir)
|
| 38 |
+
|
| 39 |
+
for curve_type in curve_types:
|
| 40 |
+
src_type_dir = os.path.join(dataset_dir, curve_type)
|
| 41 |
+
if not os.path.exists(src_type_dir):
|
| 42 |
+
continue
|
| 43 |
+
|
| 44 |
+
target_type_dir = os.path.join(target_dataset_dir, curve_type)
|
| 45 |
+
os.makedirs(target_type_dir, exist_ok=True)
|
| 46 |
+
|
| 47 |
+
# Get PNG files and sort them
|
| 48 |
+
png_files = sorted([f for f in os.listdir(src_type_dir) if f.endswith('.png')])
|
| 49 |
+
|
| 50 |
+
# Select samples (first, middle, last)
|
| 51 |
+
if len(png_files) == 0:
|
| 52 |
+
continue
|
| 53 |
+
elif len(png_files) <= SAMPLES_PER_TYPE:
|
| 54 |
+
selected = png_files
|
| 55 |
+
else:
|
| 56 |
+
indices = [0, len(png_files)//2, len(png_files)-1]
|
| 57 |
+
selected = [png_files[i] for i in indices[:SAMPLES_PER_TYPE]]
|
| 58 |
+
|
| 59 |
+
# Copy selected files
|
| 60 |
+
for filename in selected:
|
| 61 |
+
src = os.path.join(src_type_dir, filename)
|
| 62 |
+
dst = os.path.join(target_type_dir, filename)
|
| 63 |
+
shutil.copy(src, dst)
|
| 64 |
+
total_copied += 1
|
| 65 |
+
print(f" Copied: {dataset}/{curve_type}/{filename}")
|
| 66 |
+
|
| 67 |
+
print(f"\n✓ Created samples directory with {total_copied} files")
|
| 68 |
+
print(f" Location: {os.path.abspath(TARGET_DIR)}")
|
| 69 |
+
|
| 70 |
+
if __name__ == "__main__":
|
| 71 |
+
create_samples()
|
data/dev_en.json
ADDED
|
The diff for this file is too large to render.
See raw diff
|
|
|
data/test_en.json
ADDED
|
The diff for this file is too large to render.
See raw diff
|
|
|
data/train_en.json
ADDED
|
The diff for this file is too large to render.
See raw diff
|
|
|
requirements.txt
ADDED
|
@@ -0,0 +1,48 @@
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
| 1 |
+
# =============================================================================
|
| 2 |
+
# Image_SDF: Analytic Geometry Diagram Synthesis
|
| 3 |
+
# =============================================================================
|
| 4 |
+
# Python >= 3.9 required
|
| 5 |
+
# Installation: pip install -r requirements.txt
|
| 6 |
+
# =============================================================================
|
| 7 |
+
|
| 8 |
+
# -----------------------------------------------------------------------------
|
| 9 |
+
# Core Dependencies
|
| 10 |
+
# -----------------------------------------------------------------------------
|
| 11 |
+
|
| 12 |
+
# Deep Learning Framework
|
| 13 |
+
# - Tensor operations and automatic differentiation
|
| 14 |
+
# - AdamW optimizer for constraint satisfaction
|
| 15 |
+
torch>=2.0.0
|
| 16 |
+
|
| 17 |
+
# Numerical Computing
|
| 18 |
+
# - Array operations and linear algebra
|
| 19 |
+
# - Mathematical functions (sqrt, trigonometric)
|
| 20 |
+
numpy>=1.24.0
|
| 21 |
+
|
| 22 |
+
# Visualization
|
| 23 |
+
# - SDF field rendering and zero-level set visualization
|
| 24 |
+
# - Figure generation with annotations
|
| 25 |
+
matplotlib>=3.7.0
|
| 26 |
+
|
| 27 |
+
# Progress Tracking
|
| 28 |
+
# - Batch processing progress bars
|
| 29 |
+
tqdm>=4.65.0
|
| 30 |
+
|
| 31 |
+
# -----------------------------------------------------------------------------
|
| 32 |
+
# Optional Dependencies (uncomment if needed)
|
| 33 |
+
# -----------------------------------------------------------------------------
|
| 34 |
+
|
| 35 |
+
# Enhanced numerical methods
|
| 36 |
+
# scipy>=1.10.0
|
| 37 |
+
|
| 38 |
+
# Image processing utilities
|
| 39 |
+
# pillow>=10.0.0
|
| 40 |
+
|
| 41 |
+
# Better plot styling
|
| 42 |
+
# seaborn>=0.12.0
|
| 43 |
+
|
| 44 |
+
# Type checking (development)
|
| 45 |
+
# mypy>=1.0.0
|
| 46 |
+
|
| 47 |
+
# Testing (development)
|
| 48 |
+
# pytest>=7.0.0
|
results/.DS_Store
ADDED
|
Binary file (10.2 kB). View file
|
|
|
results/dev/.DS_Store
ADDED
|
Binary file (8.2 kB). View file
|
|
|
results/dev/parabola/problem_0025.png
ADDED
|
Git LFS Details
|
results/dev/parabola/problem_0145.png
ADDED
|
Git LFS Details
|
results/dev/parabola/problem_0150.png
ADDED
|
Git LFS Details
|
results/dev/parabola/problem_0151.png
ADDED
|
Git LFS Details
|
results/dev/parabola/problem_0179.png
ADDED
|
Git LFS Details
|
results/dev/parabola/problem_0186.png
ADDED
|
Git LFS Details
|
results/dev/parabola/problem_0409.png
ADDED
|
Git LFS Details
|
results/dev/parabola/problem_0541.png
ADDED
|
Git LFS Details
|
results/dev/parabola/problem_0569.png
ADDED
|
Git LFS Details
|
results/dev/parabola/problem_0596.png
ADDED
|
Git LFS Details
|
results/dev/parabola/problem_0637.png
ADDED
|
Git LFS Details
|
results/dev/parabola/problem_0743.png
ADDED
|
Git LFS Details
|
results/dev/parabola/problem_0794.png
ADDED
|
Git LFS Details
|
results/dev/parabola/problem_0804.png
ADDED
|
Git LFS Details
|
results/dev/parabola/problem_0958.png
ADDED
|
Git LFS Details
|
results/dev/summary.json
ADDED
|
The diff for this file is too large to render.
See raw diff
|
|
|
results/test/.DS_Store
ADDED
|
Binary file (8.2 kB). View file
|
|
|
results/test/summary.json
ADDED
|
The diff for this file is too large to render.
See raw diff
|
|
|
results/train/.DS_Store
ADDED
|
Binary file (14.3 kB). View file
|
|
|
results/train/summary.json
ADDED
|
The diff for this file is too large to render.
See raw diff
|
|
|
src/__pycache__/sdf_geo_solver.cpython-313.pyc
ADDED
|
@@ -0,0 +1,3 @@
|
|
|
|
|
|
|
|
|
|
|
|
|
| 1 |
+
version https://git-lfs.github.com/spec/v1
|
| 2 |
+
oid sha256:056b7b1420e4c50b338528b19709d35f84ab65b8616f8a7c2fbef17231a78d2b
|
| 3 |
+
size 148145
|
src/main.py
ADDED
|
@@ -0,0 +1,68 @@
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
| 1 |
+
#!/usr/bin/env python3
|
| 2 |
+
"""
|
| 3 |
+
SDF-Based Analytic Geometry Solver
|
| 4 |
+
Main entry point for batch processing geometry problems.
|
| 5 |
+
"""
|
| 6 |
+
|
| 7 |
+
import argparse
|
| 8 |
+
import sys
|
| 9 |
+
from pathlib import Path
|
| 10 |
+
|
| 11 |
+
# Add src directory to path for module imports
|
| 12 |
+
sys.path.insert(0, str(Path(__file__).parent))
|
| 13 |
+
|
| 14 |
+
from sdf_geo import SDFBatchProcessor
|
| 15 |
+
|
| 16 |
+
|
| 17 |
+
def main():
|
| 18 |
+
parser = argparse.ArgumentParser(
|
| 19 |
+
description='SDF-Based Geometry Solver - Automatic geometry visualization using Signed Distance Fields'
|
| 20 |
+
)
|
| 21 |
+
parser.add_argument(
|
| 22 |
+
'--input', '-i',
|
| 23 |
+
type=str,
|
| 24 |
+
default='data/test_en.json',
|
| 25 |
+
help='Path to input JSON file containing geometry problems'
|
| 26 |
+
)
|
| 27 |
+
parser.add_argument(
|
| 28 |
+
'--output', '-o',
|
| 29 |
+
type=str,
|
| 30 |
+
default='results',
|
| 31 |
+
help='Output directory for generated visualizations'
|
| 32 |
+
)
|
| 33 |
+
parser.add_argument(
|
| 34 |
+
'--max', '-m',
|
| 35 |
+
type=int,
|
| 36 |
+
default=None,
|
| 37 |
+
help='Maximum number of problems to process (default: all)'
|
| 38 |
+
)
|
| 39 |
+
parser.add_argument(
|
| 40 |
+
'--verbose', '-v',
|
| 41 |
+
action='store_true',
|
| 42 |
+
help='Enable verbose output during processing'
|
| 43 |
+
)
|
| 44 |
+
|
| 45 |
+
args = parser.parse_args()
|
| 46 |
+
|
| 47 |
+
# Resolve paths
|
| 48 |
+
input_path = Path(args.input)
|
| 49 |
+
output_path = Path(args.output)
|
| 50 |
+
|
| 51 |
+
# Check input file exists
|
| 52 |
+
if not input_path.exists():
|
| 53 |
+
print(f"Error: Input file not found: {input_path}")
|
| 54 |
+
return 1
|
| 55 |
+
|
| 56 |
+
# Create processor and run
|
| 57 |
+
processor = SDFBatchProcessor(str(output_path))
|
| 58 |
+
processor.process_batch(
|
| 59 |
+
str(input_path),
|
| 60 |
+
max_problems=args.max,
|
| 61 |
+
verbose=args.verbose
|
| 62 |
+
)
|
| 63 |
+
|
| 64 |
+
return 0
|
| 65 |
+
|
| 66 |
+
|
| 67 |
+
if __name__ == '__main__':
|
| 68 |
+
exit(main())
|
src/sdf_geo/__init__.py
ADDED
|
@@ -0,0 +1,51 @@
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
| 1 |
+
"""
|
| 2 |
+
SDF-Based Analytic Geometry Solver Package
|
| 3 |
+
|
| 4 |
+
Core modules for geometric problem solving using Signed Distance Fields.
|
| 5 |
+
"""
|
| 6 |
+
|
| 7 |
+
from .primitives import (
|
| 8 |
+
DEVICE,
|
| 9 |
+
SDFPrimitive,
|
| 10 |
+
PointSDF,
|
| 11 |
+
CircleSDF,
|
| 12 |
+
EllipseSDF,
|
| 13 |
+
HyperbolaSDF,
|
| 14 |
+
ParabolaSDF,
|
| 15 |
+
LineSDF,
|
| 16 |
+
LineSegmentSDF,
|
| 17 |
+
TriangleEdgesSDF,
|
| 18 |
+
TriangleFillSDF,
|
| 19 |
+
RightAngleSDF
|
| 20 |
+
)
|
| 21 |
+
|
| 22 |
+
from .constraints import GeometricConstraints
|
| 23 |
+
from .parser import ProblemParser
|
| 24 |
+
from .renderer import SDFRenderer
|
| 25 |
+
from .optimizer import GeometryOptimizer
|
| 26 |
+
from .processor import SDFBatchProcessor
|
| 27 |
+
|
| 28 |
+
__all__ = [
|
| 29 |
+
# Device
|
| 30 |
+
'DEVICE',
|
| 31 |
+
# Primitives
|
| 32 |
+
'SDFPrimitive',
|
| 33 |
+
'PointSDF',
|
| 34 |
+
'CircleSDF',
|
| 35 |
+
'EllipseSDF',
|
| 36 |
+
'HyperbolaSDF',
|
| 37 |
+
'ParabolaSDF',
|
| 38 |
+
'LineSDF',
|
| 39 |
+
'LineSegmentSDF',
|
| 40 |
+
'TriangleEdgesSDF',
|
| 41 |
+
'TriangleFillSDF',
|
| 42 |
+
'RightAngleSDF',
|
| 43 |
+
# Core classes
|
| 44 |
+
'GeometricConstraints',
|
| 45 |
+
'ProblemParser',
|
| 46 |
+
'SDFRenderer',
|
| 47 |
+
'GeometryOptimizer',
|
| 48 |
+
'SDFBatchProcessor',
|
| 49 |
+
]
|
| 50 |
+
|
| 51 |
+
__version__ = '1.0.0'
|
src/sdf_geo/__pycache__/__init__.cpython-313.pyc
ADDED
|
Binary file (1.01 kB). View file
|
|
|
src/sdf_geo/__pycache__/constraints.cpython-313.pyc
ADDED
|
Binary file (5.63 kB). View file
|
|
|
src/sdf_geo/__pycache__/optimizer.cpython-313.pyc
ADDED
|
Binary file (3.5 kB). View file
|
|
|
src/sdf_geo/__pycache__/parser.cpython-313.pyc
ADDED
|
Binary file (36 kB). View file
|
|
|
src/sdf_geo/__pycache__/primitives.cpython-313.pyc
ADDED
|
Binary file (24.2 kB). View file
|
|
|
src/sdf_geo/__pycache__/processor.cpython-313.pyc
ADDED
|
Binary file (65.8 kB). View file
|
|
|
src/sdf_geo/__pycache__/renderer.cpython-313.pyc
ADDED
|
Binary file (4.89 kB). View file
|
|
|
src/sdf_geo/constraints.py
ADDED
|
@@ -0,0 +1,82 @@
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
| 1 |
+
"""
|
| 2 |
+
Geometric Constraints - Differentiable constraint functions for optimization.
|
| 3 |
+
Following GeoSDF paper Section 5.
|
| 4 |
+
"""
|
| 5 |
+
|
| 6 |
+
import torch
|
| 7 |
+
from typing import Callable
|
| 8 |
+
|
| 9 |
+
|
| 10 |
+
class GeometricConstraints:
|
| 11 |
+
"""Collection of differentiable geometric constraint functions."""
|
| 12 |
+
|
| 13 |
+
@staticmethod
|
| 14 |
+
def point_on_curve(sdf: Callable, point: torch.Tensor) -> torch.Tensor:
|
| 15 |
+
"""Constraint: point lies on curve (SDF = 0)."""
|
| 16 |
+
return sdf(point.unsqueeze(0))**2
|
| 17 |
+
|
| 18 |
+
@staticmethod
|
| 19 |
+
def distance_constraint(p1: torch.Tensor, p2: torch.Tensor,
|
| 20 |
+
target_dist: float) -> torch.Tensor:
|
| 21 |
+
"""Constraint: distance between two points equals target."""
|
| 22 |
+
actual_dist = torch.norm(p1 - p2)
|
| 23 |
+
return (actual_dist - target_dist)**2
|
| 24 |
+
|
| 25 |
+
@staticmethod
|
| 26 |
+
def eccentricity_ellipse(a: torch.Tensor, b: torch.Tensor,
|
| 27 |
+
target_e: float) -> torch.Tensor:
|
| 28 |
+
"""Constraint: ellipse eccentricity."""
|
| 29 |
+
c_squared = a**2 - b**2
|
| 30 |
+
c = torch.sqrt(torch.clamp(c_squared, min=1e-8))
|
| 31 |
+
e = c / a
|
| 32 |
+
return (e - target_e)**2
|
| 33 |
+
|
| 34 |
+
@staticmethod
|
| 35 |
+
def eccentricity_hyperbola(a: torch.Tensor, b: torch.Tensor,
|
| 36 |
+
target_e: float) -> torch.Tensor:
|
| 37 |
+
"""Constraint: hyperbola eccentricity e = c/a where c² = a² + b²."""
|
| 38 |
+
c_squared = a**2 + b**2
|
| 39 |
+
c = torch.sqrt(c_squared)
|
| 40 |
+
e = c / (a + 1e-8)
|
| 41 |
+
return (e - target_e)**2
|
| 42 |
+
|
| 43 |
+
@staticmethod
|
| 44 |
+
def asymptote_slope(a: torch.Tensor, b: torch.Tensor,
|
| 45 |
+
target_slope: float) -> torch.Tensor:
|
| 46 |
+
"""Constraint: hyperbola asymptote slope b/a."""
|
| 47 |
+
actual_slope = b / (a + 1e-8)
|
| 48 |
+
return (actual_slope - target_slope)**2
|
| 49 |
+
|
| 50 |
+
@staticmethod
|
| 51 |
+
def focus_constraint(a: torch.Tensor, b: torch.Tensor,
|
| 52 |
+
focus_coord: float, is_hyperbola: bool = False) -> torch.Tensor:
|
| 53 |
+
"""Constraint: focus at specific coordinate."""
|
| 54 |
+
if is_hyperbola:
|
| 55 |
+
c_squared = a**2 + b**2
|
| 56 |
+
else:
|
| 57 |
+
c_squared = a**2 - b**2
|
| 58 |
+
c = torch.sqrt(torch.clamp(c_squared, min=1e-8))
|
| 59 |
+
return (c - abs(focus_coord))**2
|
| 60 |
+
|
| 61 |
+
@staticmethod
|
| 62 |
+
def focus_constraint_hyperbola(a: torch.Tensor, b: torch.Tensor,
|
| 63 |
+
target_c: float) -> torch.Tensor:
|
| 64 |
+
"""Constraint: hyperbola focus distance c where c² = a² + b²."""
|
| 65 |
+
c_squared = a**2 + b**2
|
| 66 |
+
c = torch.sqrt(c_squared)
|
| 67 |
+
return (c - target_c)**2
|
| 68 |
+
|
| 69 |
+
@staticmethod
|
| 70 |
+
def positive_constraint(param: torch.Tensor, min_val: float = 0.1) -> torch.Tensor:
|
| 71 |
+
"""Soft constraint to keep parameter positive."""
|
| 72 |
+
return torch.relu(min_val - param)**2
|
| 73 |
+
|
| 74 |
+
@staticmethod
|
| 75 |
+
def crowd_penalty(positions: list, min_dist: float = 0.5) -> torch.Tensor:
|
| 76 |
+
"""Penalty for elements being too close together."""
|
| 77 |
+
penalty = torch.tensor(0.0)
|
| 78 |
+
for i, p1 in enumerate(positions):
|
| 79 |
+
for p2 in positions[i+1:]:
|
| 80 |
+
dist = torch.norm(p1 - p2)
|
| 81 |
+
penalty = penalty + torch.relu(min_dist - dist)**2
|
| 82 |
+
return penalty
|
src/sdf_geo/optimizer.py
ADDED
|
@@ -0,0 +1,81 @@
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
| 1 |
+
"""
|
| 2 |
+
Geometry Optimizer Module
|
| 3 |
+
Gradient-based optimization for geometric constraints.
|
| 4 |
+
"""
|
| 5 |
+
|
| 6 |
+
import torch
|
| 7 |
+
from typing import Dict, List, Callable
|
| 8 |
+
|
| 9 |
+
|
| 10 |
+
class GeometryOptimizer:
|
| 11 |
+
"""
|
| 12 |
+
Optimizer for geometric constraints using gradient descent.
|
| 13 |
+
Following GeoSDF paper methodology with AdamW optimizer.
|
| 14 |
+
"""
|
| 15 |
+
|
| 16 |
+
def __init__(self, learning_rate: float = 0.1, max_iterations: int = 500,
|
| 17 |
+
convergence_threshold: float = 1e-6):
|
| 18 |
+
self.learning_rate = learning_rate
|
| 19 |
+
self.max_iterations = max_iterations
|
| 20 |
+
self.convergence_threshold = convergence_threshold
|
| 21 |
+
|
| 22 |
+
def optimize(self, sdf, constraints: List[Callable],
|
| 23 |
+
weights: List[float], verbose: bool = False) -> Dict:
|
| 24 |
+
"""
|
| 25 |
+
Optimize SDF parameters to satisfy constraints.
|
| 26 |
+
|
| 27 |
+
Args:
|
| 28 |
+
sdf: SDF primitive with learnable parameters
|
| 29 |
+
constraints: List of constraint functions returning loss tensors
|
| 30 |
+
weights: Weight for each constraint
|
| 31 |
+
verbose: Print optimization progress
|
| 32 |
+
|
| 33 |
+
Returns:
|
| 34 |
+
Dictionary with optimization results
|
| 35 |
+
"""
|
| 36 |
+
# Get trainable parameters
|
| 37 |
+
params = [p for p in sdf.parameters() if p.requires_grad]
|
| 38 |
+
if not params:
|
| 39 |
+
return {'final_loss': 0.0, 'converged': True, 'iterations': 0}
|
| 40 |
+
|
| 41 |
+
optimizer = torch.optim.AdamW(params, lr=self.learning_rate)
|
| 42 |
+
scheduler = torch.optim.lr_scheduler.CosineAnnealingLR(
|
| 43 |
+
optimizer, T_max=self.max_iterations, eta_min=1e-4
|
| 44 |
+
)
|
| 45 |
+
|
| 46 |
+
prev_loss = float('inf')
|
| 47 |
+
converged = False
|
| 48 |
+
|
| 49 |
+
for i in range(self.max_iterations):
|
| 50 |
+
optimizer.zero_grad()
|
| 51 |
+
|
| 52 |
+
# Compute weighted sum of constraint losses
|
| 53 |
+
total_loss = torch.tensor(0.0)
|
| 54 |
+
for constraint, weight in zip(constraints, weights):
|
| 55 |
+
loss = constraint()
|
| 56 |
+
total_loss = total_loss + weight * loss
|
| 57 |
+
|
| 58 |
+
# Backward pass
|
| 59 |
+
total_loss.backward()
|
| 60 |
+
|
| 61 |
+
# Gradient clipping for stability
|
| 62 |
+
torch.nn.utils.clip_grad_norm_(params, max_norm=1.0)
|
| 63 |
+
|
| 64 |
+
optimizer.step()
|
| 65 |
+
scheduler.step()
|
| 66 |
+
|
| 67 |
+
# Check convergence
|
| 68 |
+
current_loss = total_loss.item()
|
| 69 |
+
if abs(prev_loss - current_loss) < self.convergence_threshold:
|
| 70 |
+
converged = True
|
| 71 |
+
break
|
| 72 |
+
prev_loss = current_loss
|
| 73 |
+
|
| 74 |
+
if verbose and i % 100 == 0:
|
| 75 |
+
print(f" Iteration {i}: loss = {current_loss:.6f}")
|
| 76 |
+
|
| 77 |
+
return {
|
| 78 |
+
'final_loss': current_loss,
|
| 79 |
+
'converged': converged,
|
| 80 |
+
'iterations': i + 1
|
| 81 |
+
}
|
src/sdf_geo/parser.py
ADDED
|
@@ -0,0 +1,1184 @@
|
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|
| 1 |
+
"""
|
| 2 |
+
Problem Parser Module
|
| 3 |
+
Extracts geometric parameters from problem expressions.
|
| 4 |
+
"""
|
| 5 |
+
|
| 6 |
+
import re
|
| 7 |
+
import numpy as np
|
| 8 |
+
from typing import Dict, List, Tuple, Optional
|
| 9 |
+
|
| 10 |
+
|
| 11 |
+
class ProblemParser:
|
| 12 |
+
"""Parse problem expressions into geometric constraints and SDFs."""
|
| 13 |
+
|
| 14 |
+
def __init__(self):
|
| 15 |
+
pass
|
| 16 |
+
|
| 17 |
+
def parse_line(self, fact_expr: str) -> Optional[Dict]:
|
| 18 |
+
"""Parse line expression."""
|
| 19 |
+
# Expression(G) = (x + y - 1 = 0) or similar
|
| 20 |
+
match = re.search(r'Expression\(\w+\)\s*=\s*\(([^)]+)\s*=\s*0\)', fact_expr)
|
| 21 |
+
if match:
|
| 22 |
+
expr = match.group(1)
|
| 23 |
+
# Parse ax + by + c = 0 format
|
| 24 |
+
# Try to extract coefficients
|
| 25 |
+
a, b, c = 0.0, 0.0, 0.0
|
| 26 |
+
|
| 27 |
+
# Match patterns like "x + y - 1" or "2*x - 3*y + 5"
|
| 28 |
+
x_match = re.search(r'([+-]?\s*\d*\.?\d*)\s*\*?\s*x', expr)
|
| 29 |
+
y_match = re.search(r'([+-]?\s*\d*\.?\d*)\s*\*?\s*y', expr)
|
| 30 |
+
|
| 31 |
+
if x_match:
|
| 32 |
+
coef = x_match.group(1).replace(' ', '')
|
| 33 |
+
if coef in ['', '+']:
|
| 34 |
+
a = 1.0
|
| 35 |
+
elif coef == '-':
|
| 36 |
+
a = -1.0
|
| 37 |
+
else:
|
| 38 |
+
try:
|
| 39 |
+
a = float(coef)
|
| 40 |
+
except:
|
| 41 |
+
a = 1.0
|
| 42 |
+
|
| 43 |
+
if y_match:
|
| 44 |
+
coef = y_match.group(1).replace(' ', '')
|
| 45 |
+
if coef in ['', '+']:
|
| 46 |
+
b = 1.0
|
| 47 |
+
elif coef == '-':
|
| 48 |
+
b = -1.0
|
| 49 |
+
else:
|
| 50 |
+
try:
|
| 51 |
+
b = float(coef)
|
| 52 |
+
except:
|
| 53 |
+
b = 1.0
|
| 54 |
+
|
| 55 |
+
# Find constant term
|
| 56 |
+
const_match = re.search(r'([+-]\s*\d+\.?\d*)\s*(?:=|$)', expr)
|
| 57 |
+
if const_match:
|
| 58 |
+
try:
|
| 59 |
+
c = float(const_match.group(1).replace(' ', ''))
|
| 60 |
+
except:
|
| 61 |
+
c = 0.0
|
| 62 |
+
|
| 63 |
+
if a != 0 or b != 0:
|
| 64 |
+
return {
|
| 65 |
+
'type': 'line',
|
| 66 |
+
'a': a,
|
| 67 |
+
'b': b,
|
| 68 |
+
'c': c,
|
| 69 |
+
'equation': expr
|
| 70 |
+
}
|
| 71 |
+
|
| 72 |
+
# Check for Slope constraint - sqrt format
|
| 73 |
+
slope_match = re.search(r'Slope\(\w+\)\s*=\s*sqrt\((\d+)\)', fact_expr)
|
| 74 |
+
if slope_match:
|
| 75 |
+
slope = np.sqrt(float(slope_match.group(1)))
|
| 76 |
+
return {
|
| 77 |
+
'type': 'line',
|
| 78 |
+
'slope': slope,
|
| 79 |
+
'symbolic': True
|
| 80 |
+
}
|
| 81 |
+
|
| 82 |
+
# Check for Slope constraint - numeric format
|
| 83 |
+
slope_match = re.search(r'Slope\(\w+\)\s*=\s*([\d.]+)', fact_expr)
|
| 84 |
+
if slope_match:
|
| 85 |
+
return {
|
| 86 |
+
'type': 'line',
|
| 87 |
+
'slope': float(slope_match.group(1)),
|
| 88 |
+
'symbolic': True
|
| 89 |
+
}
|
| 90 |
+
|
| 91 |
+
return None
|
| 92 |
+
|
| 93 |
+
def parse_circle(self, fact_expr: str) -> Optional[Dict]:
|
| 94 |
+
"""Parse circle expression."""
|
| 95 |
+
|
| 96 |
+
# Format 1: (x-a)^2 + (y-b)^2 = r^2
|
| 97 |
+
match = re.search(r'Expression\(\w+\)\s*=\s*\(\(x-([^)]+)\)\^2\s*\+\s*\(y-([^)]+)\)\^2\s*=\s*(\d+)\)', fact_expr)
|
| 98 |
+
if match:
|
| 99 |
+
return {
|
| 100 |
+
'type': 'circle',
|
| 101 |
+
'center': (float(match.group(1)), float(match.group(2))),
|
| 102 |
+
'radius': np.sqrt(float(match.group(3)))
|
| 103 |
+
}
|
| 104 |
+
|
| 105 |
+
# Format 2: x^2 + (y-a)^2 = r (center at origin or on axis)
|
| 106 |
+
match = re.search(r'Expression\(\w+\)\s*=\s*\(x\^2\s*\+\s*\(([+-]?\s*\d*\.?\d*)\s*[+-]\s*y\)\^2\s*=\s*(\d+)\)', fact_expr)
|
| 107 |
+
if match:
|
| 108 |
+
cy = -float(match.group(1).replace(' ', '')) if match.group(1) else 0.0
|
| 109 |
+
return {
|
| 110 |
+
'type': 'circle',
|
| 111 |
+
'center': (0.0, cy),
|
| 112 |
+
'radius': np.sqrt(float(match.group(2)))
|
| 113 |
+
}
|
| 114 |
+
|
| 115 |
+
# Format 3: y^2 + (x-a)^2 = r or y^2 + (x+a)^2 = r
|
| 116 |
+
match = re.search(r'Expression\(\w+\)\s*=\s*\(y\^2\s*\+\s*\(x\s*([+-])\s*(\d+\.?\d*)\)\^2\s*=\s*(\d+\.?\d*)\)', fact_expr)
|
| 117 |
+
if match:
|
| 118 |
+
sign = -1 if match.group(1) == '-' else 1
|
| 119 |
+
cx = sign * float(match.group(2))
|
| 120 |
+
return {
|
| 121 |
+
'type': 'circle',
|
| 122 |
+
'center': (cx, 0.0),
|
| 123 |
+
'radius': np.sqrt(float(match.group(3)))
|
| 124 |
+
}
|
| 125 |
+
|
| 126 |
+
# Format 4: x^2 + y^2 = r (center at origin)
|
| 127 |
+
match = re.search(r'Expression\(\w+\)\s*=\s*\(x\^2\s*\+\s*y\^2\s*=\s*(\d+\.?\d*)\)', fact_expr)
|
| 128 |
+
if match:
|
| 129 |
+
return {
|
| 130 |
+
'type': 'circle',
|
| 131 |
+
'center': (0.0, 0.0),
|
| 132 |
+
'radius': np.sqrt(float(match.group(1)))
|
| 133 |
+
}
|
| 134 |
+
|
| 135 |
+
# Format 5: Check if it's explicitly declared as Circle type
|
| 136 |
+
if re.search(r'\w+:\s*Circle', fact_expr):
|
| 137 |
+
# Try more general patterns
|
| 138 |
+
# (x + a)^2 + (y - b)^2 = r
|
| 139 |
+
match = re.search(r'\(x\s*([+-])\s*(\d+\.?\d*)\)\^2\s*\+\s*\(y\s*([+-])\s*(\d+\.?\d*)\)\^2\s*=\s*(\d+\.?\d*)', fact_expr)
|
| 140 |
+
if match:
|
| 141 |
+
cx = float(match.group(2)) * (-1 if match.group(1) == '+' else 1)
|
| 142 |
+
cy = float(match.group(4)) * (-1 if match.group(3) == '+' else 1)
|
| 143 |
+
return {
|
| 144 |
+
'type': 'circle',
|
| 145 |
+
'center': (cx, cy),
|
| 146 |
+
'radius': np.sqrt(float(match.group(5)))
|
| 147 |
+
}
|
| 148 |
+
|
| 149 |
+
# Check for circle defined by diameter
|
| 150 |
+
if 'IsDiameter' in fact_expr:
|
| 151 |
+
return {
|
| 152 |
+
'type': 'circle',
|
| 153 |
+
'from_diameter': True
|
| 154 |
+
}
|
| 155 |
+
|
| 156 |
+
# Check for circle defined by slope product = -1 (perpendicular)
|
| 157 |
+
# Pattern: Slope(LineSegmentOf(P, A)) * Slope(LineSegmentOf(P, B)) = -1
|
| 158 |
+
# This means angle APB = 90°, so P lies on circle with diameter AB
|
| 159 |
+
slope_match = re.search(r'Slope\(LineSegmentOf\(\w+,\s*(\w+)\)\)\s*\*\s*Slope\(LineSegmentOf\(\w+,\s*(\w+)\)\)\s*=\s*-1', fact_expr)
|
| 160 |
+
if slope_match:
|
| 161 |
+
pt1_name = slope_match.group(1)
|
| 162 |
+
pt2_name = slope_match.group(2)
|
| 163 |
+
coords = self.parse_coordinates(fact_expr)
|
| 164 |
+
if pt1_name in coords and pt2_name in coords:
|
| 165 |
+
x1, y1 = coords[pt1_name]
|
| 166 |
+
x2, y2 = coords[pt2_name]
|
| 167 |
+
# Circle with diameter AB: center = midpoint, radius = |AB|/2
|
| 168 |
+
cx = (x1 + x2) / 2
|
| 169 |
+
cy = (y1 + y2) / 2
|
| 170 |
+
radius = np.sqrt((x2 - x1)**2 + (y2 - y1)**2) / 2
|
| 171 |
+
return {
|
| 172 |
+
'type': 'circle',
|
| 173 |
+
'center': (cx, cy),
|
| 174 |
+
'radius': radius,
|
| 175 |
+
'from_constraints': True
|
| 176 |
+
}
|
| 177 |
+
|
| 178 |
+
# General circle equation: x^2 + y^2 + Dx + Ey + F = 0
|
| 179 |
+
# Center: (-D/2, -E/2), Radius: sqrt(D²/4 + E²/4 - F)
|
| 180 |
+
# Pattern: ax^2 + by^2 + Dx + Ey + F = 0 where coefficients can vary
|
| 181 |
+
general_match = re.search(r'Expression\(\w+\)\s*=\s*\(([^)]+x\^2[^)]+y\^2[^)]+)\s*=\s*0\)', fact_expr)
|
| 182 |
+
if general_match and 'Circle' in fact_expr:
|
| 183 |
+
expr = general_match.group(1)
|
| 184 |
+
# Parse coefficients: D*x, E*y, F (constant)
|
| 185 |
+
D = E = F = 0.0
|
| 186 |
+
|
| 187 |
+
# Find coefficient of x (not x^2)
|
| 188 |
+
d_match = re.search(r'([+-]?\s*\d*\.?\d*)\s*\*?\s*x(?!\^)', expr)
|
| 189 |
+
if d_match:
|
| 190 |
+
d_str = d_match.group(1).replace(' ', '')
|
| 191 |
+
D = float(d_str) if d_str and d_str not in ['+', '-'] else (1.0 if d_str == '+' or d_str == '' else -1.0)
|
| 192 |
+
|
| 193 |
+
# Find coefficient of y (not y^2)
|
| 194 |
+
e_match = re.search(r'([+-]?\s*\d*\.?\d*)\s*\*?\s*y(?!\^)', expr)
|
| 195 |
+
if e_match:
|
| 196 |
+
e_str = e_match.group(1).replace(' ', '')
|
| 197 |
+
E = float(e_str) if e_str and e_str not in ['+', '-'] else (1.0 if e_str == '+' or e_str == '' else -1.0)
|
| 198 |
+
|
| 199 |
+
# Find constant term
|
| 200 |
+
const_match = re.search(r'([+-]\s*\d+\.?\d*)\s*(?:=|$)', expr)
|
| 201 |
+
if const_match:
|
| 202 |
+
f_str = const_match.group(1).replace(' ', '')
|
| 203 |
+
F = float(f_str)
|
| 204 |
+
|
| 205 |
+
cx = -D / 2
|
| 206 |
+
cy = -E / 2
|
| 207 |
+
r_sq = D**2 / 4 + E**2 / 4 - F
|
| 208 |
+
if r_sq > 0:
|
| 209 |
+
return {
|
| 210 |
+
'type': 'circle',
|
| 211 |
+
'center': (cx, cy),
|
| 212 |
+
'radius': np.sqrt(r_sq),
|
| 213 |
+
'from_constraints': True
|
| 214 |
+
}
|
| 215 |
+
|
| 216 |
+
# Shifted center circle: (x+h)^2 + y^2 = r^2 or (x-h)^2 + y^2 = r^2
|
| 217 |
+
shifted_match = re.search(r'Expression\(\w+\)\s*=\s*\(\(x([+-])(\d+\.?\d*)\)\^2\s*\+\s*y\^2\s*=\s*(\d+\.?\d*)\)', fact_expr)
|
| 218 |
+
if shifted_match:
|
| 219 |
+
sign = shifted_match.group(1)
|
| 220 |
+
h = float(shifted_match.group(2))
|
| 221 |
+
r_sq = float(shifted_match.group(3))
|
| 222 |
+
cx = -h if sign == '+' else h
|
| 223 |
+
return {
|
| 224 |
+
'type': 'circle',
|
| 225 |
+
'center': (cx, 0.0),
|
| 226 |
+
'radius': np.sqrt(r_sq),
|
| 227 |
+
}
|
| 228 |
+
|
| 229 |
+
# (x±h)^2 + (y±k)^2 = r^2
|
| 230 |
+
shifted_match2 = re.search(r'Expression\(\w+\)\s*=\s*\(\(x([+-])(\d+\.?\d*)\)\^2\s*\+\s*\(y([+-])(\d+\.?\d*)\)\^2\s*=\s*(\d+\.?\d*)\)', fact_expr)
|
| 231 |
+
if shifted_match2:
|
| 232 |
+
sign_x = shifted_match2.group(1)
|
| 233 |
+
h = float(shifted_match2.group(2))
|
| 234 |
+
sign_y = shifted_match2.group(3)
|
| 235 |
+
k = float(shifted_match2.group(4))
|
| 236 |
+
r_sq = float(shifted_match2.group(5))
|
| 237 |
+
cx = -h if sign_x == '+' else h
|
| 238 |
+
cy = -k if sign_y == '+' else k
|
| 239 |
+
return {
|
| 240 |
+
'type': 'circle',
|
| 241 |
+
'center': (cx, cy),
|
| 242 |
+
'radius': np.sqrt(r_sq),
|
| 243 |
+
}
|
| 244 |
+
|
| 245 |
+
return None
|
| 246 |
+
|
| 247 |
+
def parse_ellipse(self, fact_expr: str) -> Optional[Dict]:
|
| 248 |
+
"""Parse ellipse expression and return parameters."""
|
| 249 |
+
# x^2/a + y^2/b = 1
|
| 250 |
+
match = re.search(r'Expression\(\w+\)\s*=\s*\(x\^2/(\d+)\s*\+\s*y\^2/(\d+)\s*=\s*1\)', fact_expr)
|
| 251 |
+
if match:
|
| 252 |
+
x_coef = float(match.group(1))
|
| 253 |
+
y_coef = float(match.group(2))
|
| 254 |
+
return {
|
| 255 |
+
'type': 'ellipse',
|
| 256 |
+
'x_coef': x_coef,
|
| 257 |
+
'y_coef': y_coef,
|
| 258 |
+
'a': np.sqrt(max(x_coef, y_coef)),
|
| 259 |
+
'b': np.sqrt(min(x_coef, y_coef)),
|
| 260 |
+
'major_axis': 'x' if x_coef > y_coef else 'y'
|
| 261 |
+
}
|
| 262 |
+
|
| 263 |
+
# y^2/b + x^2/a = 1
|
| 264 |
+
match = re.search(r'Expression\(\w+\)\s*=\s*\(y\^2/(\d+)\s*\+\s*x\^2/(\d+)\s*=\s*1\)', fact_expr)
|
| 265 |
+
if match:
|
| 266 |
+
y_coef = float(match.group(1))
|
| 267 |
+
x_coef = float(match.group(2))
|
| 268 |
+
return {
|
| 269 |
+
'type': 'ellipse',
|
| 270 |
+
'x_coef': x_coef,
|
| 271 |
+
'y_coef': y_coef,
|
| 272 |
+
'a': np.sqrt(max(x_coef, y_coef)),
|
| 273 |
+
'b': np.sqrt(min(x_coef, y_coef)),
|
| 274 |
+
'major_axis': 'x' if x_coef > y_coef else 'y'
|
| 275 |
+
}
|
| 276 |
+
|
| 277 |
+
# x^2/a + y^2 = 1 (y has coefficient 1, x has numeric denominator)
|
| 278 |
+
match = re.search(r'Expression\(\w+\)\s*=\s*\(x\^2/(\d+)\s*\+\s*y\^2\s*=\s*1\)', fact_expr)
|
| 279 |
+
if match:
|
| 280 |
+
x_coef = float(match.group(1))
|
| 281 |
+
y_coef = 1.0
|
| 282 |
+
return {
|
| 283 |
+
'type': 'ellipse',
|
| 284 |
+
'x_coef': x_coef,
|
| 285 |
+
'y_coef': y_coef,
|
| 286 |
+
'a': np.sqrt(x_coef), # a > b since x_coef > 1
|
| 287 |
+
'b': 1.0,
|
| 288 |
+
'major_axis': 'x'
|
| 289 |
+
}
|
| 290 |
+
|
| 291 |
+
# y^2/a + x^2 = 1 (x has coefficient 1, y has numeric denominator)
|
| 292 |
+
match = re.search(r'Expression\(\w+\)\s*=\s*\(y\^2/(\d+)\s*\+\s*x\^2\s*=\s*1\)', fact_expr)
|
| 293 |
+
if match:
|
| 294 |
+
y_coef = float(match.group(1))
|
| 295 |
+
x_coef = 1.0
|
| 296 |
+
return {
|
| 297 |
+
'type': 'ellipse',
|
| 298 |
+
'x_coef': x_coef,
|
| 299 |
+
'y_coef': y_coef,
|
| 300 |
+
'a': np.sqrt(y_coef), # a > b since y_coef > 1
|
| 301 |
+
'b': 1.0,
|
| 302 |
+
'major_axis': 'y'
|
| 303 |
+
}
|
| 304 |
+
|
| 305 |
+
# y^2 + x^2/k^2 = 1 (y has coefficient 1)
|
| 306 |
+
match = re.search(r'Expression\(\w+\)\s*=\s*\(y\^2\s*\+\s*x\^2/\w+\^?2?\s*=\s*1\)', fact_expr)
|
| 307 |
+
if match:
|
| 308 |
+
return {
|
| 309 |
+
'type': 'ellipse',
|
| 310 |
+
'x_coef': 4.0, # default
|
| 311 |
+
'y_coef': 1.0,
|
| 312 |
+
'a': 2.0,
|
| 313 |
+
'b': 1.0,
|
| 314 |
+
'major_axis': 'x',
|
| 315 |
+
'symbolic': True
|
| 316 |
+
}
|
| 317 |
+
|
| 318 |
+
# x^2 + y^2/k^2 = 1
|
| 319 |
+
match = re.search(r'Expression\(\w+\)\s*=\s*\(x\^2\s*\+\s*y\^2/\w+\^?2?\s*=\s*1\)', fact_expr)
|
| 320 |
+
if match:
|
| 321 |
+
return {
|
| 322 |
+
'type': 'ellipse',
|
| 323 |
+
'x_coef': 1.0,
|
| 324 |
+
'y_coef': 4.0, # default
|
| 325 |
+
'a': 2.0,
|
| 326 |
+
'b': 1.0,
|
| 327 |
+
'major_axis': 'y',
|
| 328 |
+
'symbolic': True
|
| 329 |
+
}
|
| 330 |
+
|
| 331 |
+
# Ellipse with symbolic: y^2/b^2 + x^2/a^2 = 1 or x^2/a^2 + y^2/b^2 = 1
|
| 332 |
+
if re.search(r'Expression\(\w+\)\s*=\s*\([xy]\^2/\w+\^?2?\s*\+\s*[xy]\^2/\w+\^?2?\s*=\s*1\)', fact_expr):
|
| 333 |
+
return {
|
| 334 |
+
'type': 'ellipse',
|
| 335 |
+
'x_coef': 4.0,
|
| 336 |
+
'y_coef': 3.0,
|
| 337 |
+
'a': 2.0,
|
| 338 |
+
'b': np.sqrt(3),
|
| 339 |
+
'major_axis': 'x',
|
| 340 |
+
'symbolic': True
|
| 341 |
+
}
|
| 342 |
+
|
| 343 |
+
# x^2 + N*y^2 = M (ellipse: x²/M + y²/(M/N) = 1)
|
| 344 |
+
match = re.search(r'Expression\(\w+\)\s*=\s*\(x\^2\s*\+\s*(\d+)\*y\^2\s*=\s*(\d+)\)', fact_expr)
|
| 345 |
+
if match:
|
| 346 |
+
n = float(match.group(1))
|
| 347 |
+
m = float(match.group(2))
|
| 348 |
+
a_sq = m # x coefficient
|
| 349 |
+
b_sq = m / n # y coefficient
|
| 350 |
+
a = np.sqrt(max(a_sq, b_sq))
|
| 351 |
+
b = np.sqrt(min(a_sq, b_sq))
|
| 352 |
+
return {
|
| 353 |
+
'type': 'ellipse',
|
| 354 |
+
'x_coef': a_sq,
|
| 355 |
+
'y_coef': b_sq,
|
| 356 |
+
'a': a,
|
| 357 |
+
'b': b,
|
| 358 |
+
'major_axis': 'x' if a_sq >= b_sq else 'y'
|
| 359 |
+
}
|
| 360 |
+
|
| 361 |
+
# N*x^2 + y^2 = M (ellipse: x²/(M/N) + y²/M = 1)
|
| 362 |
+
match = re.search(r'Expression\(\w+\)\s*=\s*\((\d+)\*x\^2\s*\+\s*y\^2\s*=\s*(\d+)\)', fact_expr)
|
| 363 |
+
if match:
|
| 364 |
+
n = float(match.group(1))
|
| 365 |
+
m = float(match.group(2))
|
| 366 |
+
a_sq = m / n # x coefficient
|
| 367 |
+
b_sq = m # y coefficient
|
| 368 |
+
a = np.sqrt(max(a_sq, b_sq))
|
| 369 |
+
b = np.sqrt(min(a_sq, b_sq))
|
| 370 |
+
return {
|
| 371 |
+
'type': 'ellipse',
|
| 372 |
+
'x_coef': a_sq,
|
| 373 |
+
'y_coef': b_sq,
|
| 374 |
+
'a': a,
|
| 375 |
+
'b': b,
|
| 376 |
+
'major_axis': 'x' if a_sq >= b_sq else 'y'
|
| 377 |
+
}
|
| 378 |
+
|
| 379 |
+
# Check for Ellipse with geometric constraints (no explicit expression)
|
| 380 |
+
if 'Ellipse' in fact_expr:
|
| 381 |
+
coords = self.parse_coordinates(fact_expr)
|
| 382 |
+
eccentricity = self.parse_eccentricity(fact_expr)
|
| 383 |
+
|
| 384 |
+
c = None
|
| 385 |
+
major_axis = 'x' # default
|
| 386 |
+
|
| 387 |
+
# Try to find focus coordinate from various patterns
|
| 388 |
+
# Pattern 1: Coordinate(F) = (c, 0); RightFocus(G) = F
|
| 389 |
+
for name, (fx, fy) in coords.items():
|
| 390 |
+
if f'RightFocus(' in fact_expr and f') = {name}' in fact_expr:
|
| 391 |
+
c = abs(fx)
|
| 392 |
+
major_axis = 'x'
|
| 393 |
+
break
|
| 394 |
+
elif f'LeftFocus(' in fact_expr and f') = {name}' in fact_expr:
|
| 395 |
+
c = abs(fx)
|
| 396 |
+
major_axis = 'x'
|
| 397 |
+
break
|
| 398 |
+
elif f'UpperFocus(' in fact_expr and f') = {name}' in fact_expr:
|
| 399 |
+
c = abs(fy)
|
| 400 |
+
major_axis = 'y'
|
| 401 |
+
break
|
| 402 |
+
elif f'LowerFocus(' in fact_expr and f') = {name}' in fact_expr:
|
| 403 |
+
c = abs(fy)
|
| 404 |
+
major_axis = 'y'
|
| 405 |
+
break
|
| 406 |
+
|
| 407 |
+
# Pattern 2: Coordinate(OneOf(Focus(...)))
|
| 408 |
+
if c is None:
|
| 409 |
+
focus_match = re.search(r'Coordinate\(OneOf\(Focus\(\w+\)\)\)\s*=\s*\(([^,]+),\s*([^)]+)\)', fact_expr)
|
| 410 |
+
if focus_match:
|
| 411 |
+
try:
|
| 412 |
+
fx = float(focus_match.group(1).strip())
|
| 413 |
+
fy = float(focus_match.group(2).strip())
|
| 414 |
+
c = abs(fx) if abs(fy) < 0.01 else abs(fy)
|
| 415 |
+
major_axis = 'x' if abs(fy) < 0.01 else 'y'
|
| 416 |
+
except:
|
| 417 |
+
pass
|
| 418 |
+
|
| 419 |
+
# Pattern 2b: Two foci with explicit coordinates: Focus(G) = {F1, F2}
|
| 420 |
+
if c is None:
|
| 421 |
+
foci_match = re.search(r'Focus\(\w+\)\s*=\s*\{(\w+),\s*(\w+)\}', fact_expr)
|
| 422 |
+
if foci_match:
|
| 423 |
+
f1_name = foci_match.group(1)
|
| 424 |
+
f2_name = foci_match.group(2)
|
| 425 |
+
if f1_name in coords and f2_name in coords:
|
| 426 |
+
fx1, fy1 = coords[f1_name]
|
| 427 |
+
fx2, fy2 = coords[f2_name]
|
| 428 |
+
# c = half the distance between foci
|
| 429 |
+
c = np.sqrt((fx2 - fx1)**2 + (fy2 - fy1)**2) / 2
|
| 430 |
+
major_axis = 'x' if abs(fy1) < 0.01 else 'y'
|
| 431 |
+
|
| 432 |
+
# Pattern 3: PointOnCurve(Focus(G), xAxis) - focus on x-axis
|
| 433 |
+
if c is None and 'PointOnCurve(Focus(' in fact_expr:
|
| 434 |
+
if 'xAxis' in fact_expr:
|
| 435 |
+
major_axis = 'x'
|
| 436 |
+
elif 'yAxis' in fact_expr:
|
| 437 |
+
major_axis = 'y'
|
| 438 |
+
|
| 439 |
+
# Pattern 4: Length(MajorAxis(G)) = k * Length(MinorAxis(G))
|
| 440 |
+
axis_ratio = None
|
| 441 |
+
ratio_match = re.search(r'Length\(MajorAxis\(\w+\)\)\s*=\s*(\d+)\s*\*\s*Length\(MinorAxis', fact_expr)
|
| 442 |
+
if ratio_match:
|
| 443 |
+
axis_ratio = float(ratio_match.group(1))
|
| 444 |
+
|
| 445 |
+
# Pattern 5: Length(MinorAxis(G)) = N or Length(MinorAxis(G)) = 2*sqrt(N)
|
| 446 |
+
minor_axis_len = None
|
| 447 |
+
match = re.search(r'Length\(MinorAxis\(\w+\)\)\s*=\s*2\*sqrt\((\d+)\)', fact_expr)
|
| 448 |
+
if match:
|
| 449 |
+
minor_axis_len = 2 * np.sqrt(float(match.group(1)))
|
| 450 |
+
else:
|
| 451 |
+
match = re.search(r'Length\(MinorAxis\(\w+\)\)\s*=\s*(\d+)', fact_expr)
|
| 452 |
+
if match:
|
| 453 |
+
minor_axis_len = float(match.group(1))
|
| 454 |
+
|
| 455 |
+
# Pattern 6: Length(MajorAxis(G)) = N
|
| 456 |
+
major_axis_len = None
|
| 457 |
+
match = re.search(r'Length\(MajorAxis\(\w+\)\)\s*=\s*2\*sqrt\((\d+)\)', fact_expr)
|
| 458 |
+
if match:
|
| 459 |
+
major_axis_len = 2 * np.sqrt(float(match.group(1)))
|
| 460 |
+
else:
|
| 461 |
+
match = re.search(r'Length\(MajorAxis\(\w+\)\)\s*=\s*(\d+)', fact_expr)
|
| 462 |
+
if match:
|
| 463 |
+
major_axis_len = float(match.group(1))
|
| 464 |
+
|
| 465 |
+
# Pattern 7: FocalLength(G) = N or 2*c = N
|
| 466 |
+
focal_length = None
|
| 467 |
+
match = re.search(r'FocalLength\(\w+\)\s*=\s*(\d+)', fact_expr)
|
| 468 |
+
if match:
|
| 469 |
+
focal_length = float(match.group(1))
|
| 470 |
+
else:
|
| 471 |
+
match = re.search(r'2\*c\s*=\s*(\d+)', fact_expr)
|
| 472 |
+
if match:
|
| 473 |
+
focal_length = float(match.group(1))
|
| 474 |
+
|
| 475 |
+
# Case: c from FocalLength + b from MinorAxis
|
| 476 |
+
if c is None and focal_length:
|
| 477 |
+
c = focal_length / 2
|
| 478 |
+
|
| 479 |
+
# Case: b from MinorAxis length
|
| 480 |
+
if minor_axis_len:
|
| 481 |
+
b_from_minor = minor_axis_len / 2
|
| 482 |
+
if c is not None:
|
| 483 |
+
a = np.sqrt(c**2 + b_from_minor**2)
|
| 484 |
+
b = b_from_minor
|
| 485 |
+
|
| 486 |
+
# Case: a from MajorAxis length
|
| 487 |
+
if major_axis_len:
|
| 488 |
+
a_from_major = major_axis_len / 2
|
| 489 |
+
if c is not None:
|
| 490 |
+
a = a_from_major
|
| 491 |
+
b = np.sqrt(a**2 - c**2) if a > c else None
|
| 492 |
+
|
| 493 |
+
# Compute a, b from constraints
|
| 494 |
+
a, b = None, None
|
| 495 |
+
|
| 496 |
+
# Case 1: c and eccentricity known → a = c/e, b = sqrt(a² - c²)
|
| 497 |
+
if c is not None and eccentricity and 0 < eccentricity < 1:
|
| 498 |
+
a = c / eccentricity
|
| 499 |
+
b = np.sqrt(a**2 - c**2)
|
| 500 |
+
|
| 501 |
+
# Case 2: eccentricity known + axis ratio → solve for a, b
|
| 502 |
+
elif eccentricity and 0 < eccentricity < 1 and axis_ratio:
|
| 503 |
+
# a/b = axis_ratio, e = sqrt(1 - b²/a²) = sqrt(1 - 1/ratio²)
|
| 504 |
+
# This gives us the ratio, need another constraint for absolute size
|
| 505 |
+
a = 2.0 * axis_ratio # default size
|
| 506 |
+
b = 2.0
|
| 507 |
+
|
| 508 |
+
# Case 3: axis ratio + point on curve
|
| 509 |
+
elif axis_ratio:
|
| 510 |
+
# Find a point on curve and solve
|
| 511 |
+
for name, (px, py) in coords.items():
|
| 512 |
+
if f'PointOnCurve({name}' in fact_expr:
|
| 513 |
+
# x²/a² + y²/b² = 1, a = ratio * b
|
| 514 |
+
# x²/(ratio*b)² + y²/b² = 1
|
| 515 |
+
# x²/ratio² + y² = b²
|
| 516 |
+
b_sq = px**2 / axis_ratio**2 + py**2
|
| 517 |
+
if b_sq > 0:
|
| 518 |
+
b = np.sqrt(b_sq)
|
| 519 |
+
a = axis_ratio * b
|
| 520 |
+
break
|
| 521 |
+
|
| 522 |
+
# Case 4: Two points on ellipse → solve for a, b
|
| 523 |
+
if a is None:
|
| 524 |
+
points_on_curve = []
|
| 525 |
+
for name, (px, py) in coords.items():
|
| 526 |
+
if f'PointOnCurve({name}' in fact_expr and name not in ['F', 'F1', 'F2']:
|
| 527 |
+
points_on_curve.append((px, py))
|
| 528 |
+
|
| 529 |
+
if len(points_on_curve) >= 2:
|
| 530 |
+
# x1²/a² + y1²/b² = 1
|
| 531 |
+
# x2²/a² + y2²/b² = 1
|
| 532 |
+
p1, p2 = points_on_curve[0], points_on_curve[1]
|
| 533 |
+
x1, y1 = p1
|
| 534 |
+
x2, y2 = p2
|
| 535 |
+
|
| 536 |
+
# Solve: let u = 1/a², v = 1/b²
|
| 537 |
+
# x1²u + y1²v = 1
|
| 538 |
+
# x2²u + y2²v = 1
|
| 539 |
+
det = x1**2 * y2**2 - x2**2 * y1**2
|
| 540 |
+
if abs(det) > 1e-10:
|
| 541 |
+
u = (y2**2 - y1**2) / det
|
| 542 |
+
v = (x1**2 - x2**2) / det
|
| 543 |
+
if u > 0 and v > 0:
|
| 544 |
+
a_sq = 1 / u
|
| 545 |
+
b_sq = 1 / v
|
| 546 |
+
a = np.sqrt(max(a_sq, b_sq))
|
| 547 |
+
b = np.sqrt(min(a_sq, b_sq))
|
| 548 |
+
major_axis = 'x' if a_sq >= b_sq else 'y'
|
| 549 |
+
|
| 550 |
+
# Return if we have valid a, b
|
| 551 |
+
if a is not None and b is not None and a > 0 and b > 0:
|
| 552 |
+
return {
|
| 553 |
+
'type': 'ellipse',
|
| 554 |
+
'x_coef': a**2 if major_axis == 'x' else b**2,
|
| 555 |
+
'y_coef': b**2 if major_axis == 'x' else a**2,
|
| 556 |
+
'a': a,
|
| 557 |
+
'b': b,
|
| 558 |
+
'major_axis': major_axis,
|
| 559 |
+
'from_constraints': True
|
| 560 |
+
}
|
| 561 |
+
|
| 562 |
+
return None
|
| 563 |
+
|
| 564 |
+
def parse_hyperbola(self, fact_expr: str, main_conic_name: str = None) -> Optional[Dict]:
|
| 565 |
+
"""Parse hyperbola expression.
|
| 566 |
+
|
| 567 |
+
Args:
|
| 568 |
+
fact_expr: The fact expression string
|
| 569 |
+
main_conic_name: If provided, only match Expression(main_conic_name) = ...
|
| 570 |
+
This avoids matching secondary hyperbola expressions.
|
| 571 |
+
"""
|
| 572 |
+
# Build regex prefix based on main_conic_name
|
| 573 |
+
if main_conic_name:
|
| 574 |
+
expr_prefix = rf'Expression\({re.escape(main_conic_name)}\)\s*=\s*\('
|
| 575 |
+
else:
|
| 576 |
+
expr_prefix = r'Expression\(\w+\)\s*=\s*\('
|
| 577 |
+
|
| 578 |
+
# Horizontal: x^2/a - y^2/b = 1
|
| 579 |
+
match = re.search(expr_prefix + r'x\^2/(\d+)\s*-\s*y\^2/(\d+)\s*=\s*1\)', fact_expr)
|
| 580 |
+
if match:
|
| 581 |
+
a_sq = float(match.group(1))
|
| 582 |
+
b_sq = float(match.group(2))
|
| 583 |
+
return {
|
| 584 |
+
'type': 'hyperbola',
|
| 585 |
+
'a': np.sqrt(a_sq),
|
| 586 |
+
'b': np.sqrt(b_sq),
|
| 587 |
+
'a_squared': a_sq,
|
| 588 |
+
'b_squared': b_sq,
|
| 589 |
+
'orientation': 'horizontal'
|
| 590 |
+
}
|
| 591 |
+
|
| 592 |
+
# Vertical: y^2/a - x^2/b = 1
|
| 593 |
+
match = re.search(expr_prefix + r'y\^2/(\d+)\s*-\s*x\^2/(\d+)\s*=\s*1\)', fact_expr)
|
| 594 |
+
if match:
|
| 595 |
+
a_sq = float(match.group(1))
|
| 596 |
+
b_sq = float(match.group(2))
|
| 597 |
+
return {
|
| 598 |
+
'type': 'hyperbola',
|
| 599 |
+
'a': np.sqrt(a_sq),
|
| 600 |
+
'b': np.sqrt(b_sq),
|
| 601 |
+
'a_squared': a_sq,
|
| 602 |
+
'b_squared': b_sq,
|
| 603 |
+
'orientation': 'vertical'
|
| 604 |
+
}
|
| 605 |
+
|
| 606 |
+
# Horizontal: x^2/a - y^2 = 1 (b=1)
|
| 607 |
+
match = re.search(expr_prefix + r'x\^2/(\d+)\s*-\s*y\^2\s*=\s*1\)', fact_expr)
|
| 608 |
+
if match:
|
| 609 |
+
a_sq = float(match.group(1))
|
| 610 |
+
return {
|
| 611 |
+
'type': 'hyperbola',
|
| 612 |
+
'a': np.sqrt(a_sq),
|
| 613 |
+
'b': 1.0,
|
| 614 |
+
'a_squared': a_sq,
|
| 615 |
+
'b_squared': 1.0,
|
| 616 |
+
'orientation': 'horizontal'
|
| 617 |
+
}
|
| 618 |
+
|
| 619 |
+
# x^2 - y^2 = 1
|
| 620 |
+
if re.search(expr_prefix + r'x\^2\s*-\s*y\^2\s*=\s*1\)', fact_expr):
|
| 621 |
+
return {
|
| 622 |
+
'type': 'hyperbola',
|
| 623 |
+
'a': 1.0,
|
| 624 |
+
'b': 1.0,
|
| 625 |
+
'a_squared': 1.0,
|
| 626 |
+
'b_squared': 1.0,
|
| 627 |
+
'orientation': 'horizontal'
|
| 628 |
+
}
|
| 629 |
+
|
| 630 |
+
# Horizontal: x^2 - y^2/b = 1 (a=1, b^2 = b_val)
|
| 631 |
+
match = re.search(expr_prefix + r'x\^2\s*-\s*y\^2/(\d+)\s*=\s*1\)', fact_expr)
|
| 632 |
+
if match:
|
| 633 |
+
b_sq = float(match.group(1))
|
| 634 |
+
return {
|
| 635 |
+
'type': 'hyperbola',
|
| 636 |
+
'a': 1.0,
|
| 637 |
+
'b': np.sqrt(b_sq),
|
| 638 |
+
'a_squared': 1.0,
|
| 639 |
+
'b_squared': b_sq,
|
| 640 |
+
'orientation': 'horizontal'
|
| 641 |
+
}
|
| 642 |
+
|
| 643 |
+
# x^2 - y^2 = N (divide by N to normalize: x²/N - y²/N = 1)
|
| 644 |
+
match = re.search(expr_prefix + r'x\^2\s*-\s*y\^2\s*=\s*(\d+)\)', fact_expr)
|
| 645 |
+
if match:
|
| 646 |
+
n = float(match.group(1))
|
| 647 |
+
a = np.sqrt(n)
|
| 648 |
+
return {
|
| 649 |
+
'type': 'hyperbola',
|
| 650 |
+
'a': a,
|
| 651 |
+
'b': a,
|
| 652 |
+
'a_squared': n,
|
| 653 |
+
'b_squared': n,
|
| 654 |
+
'orientation': 'horizontal'
|
| 655 |
+
}
|
| 656 |
+
|
| 657 |
+
# x^2 - N*y^2 = M (x²/M - y²/(M/N) = 1)
|
| 658 |
+
match = re.search(expr_prefix + r'x\^2\s*-\s*(\d+)\*y\^2\s*=\s*(\d+)\)', fact_expr)
|
| 659 |
+
if match:
|
| 660 |
+
n = float(match.group(1))
|
| 661 |
+
m = float(match.group(2))
|
| 662 |
+
a_sq = m
|
| 663 |
+
b_sq = m / n
|
| 664 |
+
return {
|
| 665 |
+
'type': 'hyperbola',
|
| 666 |
+
'a': np.sqrt(a_sq),
|
| 667 |
+
'b': np.sqrt(b_sq),
|
| 668 |
+
'a_squared': a_sq,
|
| 669 |
+
'b_squared': b_sq,
|
| 670 |
+
'orientation': 'horizontal'
|
| 671 |
+
}
|
| 672 |
+
|
| 673 |
+
# N*x^2 - M*y^2 = K (x²/(K/N) - y²/(K/M) = 1)
|
| 674 |
+
match = re.search(expr_prefix + r'(\d+)\*x\^2\s*-\s*(\d+)\*y\^2\s*=\s*(\d+)\)', fact_expr)
|
| 675 |
+
if match:
|
| 676 |
+
n = float(match.group(1))
|
| 677 |
+
m = float(match.group(2))
|
| 678 |
+
k = float(match.group(3))
|
| 679 |
+
a_sq = k / n
|
| 680 |
+
b_sq = k / m
|
| 681 |
+
return {
|
| 682 |
+
'type': 'hyperbola',
|
| 683 |
+
'a': np.sqrt(a_sq),
|
| 684 |
+
'b': np.sqrt(b_sq),
|
| 685 |
+
'a_squared': a_sq,
|
| 686 |
+
'b_squared': b_sq,
|
| 687 |
+
'orientation': 'horizontal'
|
| 688 |
+
}
|
| 689 |
+
|
| 690 |
+
# x^2/a - y^2/b = -1 → y^2/b - x^2/a = 1 (vertical hyperbola)
|
| 691 |
+
match = re.search(expr_prefix + r'x\^2/(\d+)\s*-\s*y\^2/(\d+)\s*=\s*-1\)', fact_expr)
|
| 692 |
+
if match:
|
| 693 |
+
a_sq = float(match.group(1)) # becomes b² for vertical
|
| 694 |
+
b_sq = float(match.group(2)) # becomes a² for vertical
|
| 695 |
+
return {
|
| 696 |
+
'type': 'hyperbola',
|
| 697 |
+
'a': np.sqrt(b_sq),
|
| 698 |
+
'b': np.sqrt(a_sq),
|
| 699 |
+
'a_squared': b_sq,
|
| 700 |
+
'b_squared': a_sq,
|
| 701 |
+
'orientation': 'vertical'
|
| 702 |
+
}
|
| 703 |
+
|
| 704 |
+
# x^2-y^2/N=1 (no spaces) - horizontal
|
| 705 |
+
match = re.search(expr_prefix + r'x\^2-y\^2/(\d+)=1\)', fact_expr)
|
| 706 |
+
if match:
|
| 707 |
+
b_sq = float(match.group(1))
|
| 708 |
+
return {
|
| 709 |
+
'type': 'hyperbola',
|
| 710 |
+
'a': 1.0,
|
| 711 |
+
'b': np.sqrt(b_sq),
|
| 712 |
+
'a_squared': 1.0,
|
| 713 |
+
'b_squared': b_sq,
|
| 714 |
+
'orientation': 'horizontal'
|
| 715 |
+
}
|
| 716 |
+
|
| 717 |
+
# Vertical: y^2 - x^2/a = 1 (b=1 in standard form, here y² term positive)
|
| 718 |
+
match = re.search(expr_prefix + r'y\^2\s*-\s*x\^2/(\d+)\s*=\s*1\)', fact_expr)
|
| 719 |
+
if match:
|
| 720 |
+
b_sq = float(match.group(1))
|
| 721 |
+
return {
|
| 722 |
+
'type': 'hyperbola',
|
| 723 |
+
'a': 1.0, # For vertical hyperbola y²/a² - x²/b² = 1, a=1
|
| 724 |
+
'b': np.sqrt(b_sq),
|
| 725 |
+
'a_squared': 1.0,
|
| 726 |
+
'b_squared': b_sq,
|
| 727 |
+
'orientation': 'vertical'
|
| 728 |
+
}
|
| 729 |
+
|
| 730 |
+
# y^2 - x^2 = 1 (vertical hyperbola, a=1, b=1)
|
| 731 |
+
if re.search(expr_prefix + r'y\^2\s*-\s*x\^2\s*=\s*1\)', fact_expr):
|
| 732 |
+
return {
|
| 733 |
+
'type': 'hyperbola',
|
| 734 |
+
'a': 1.0,
|
| 735 |
+
'b': 1.0,
|
| 736 |
+
'a_squared': 1.0,
|
| 737 |
+
'b_squared': 1.0,
|
| 738 |
+
'orientation': 'vertical'
|
| 739 |
+
}
|
| 740 |
+
|
| 741 |
+
# Vertical symbolic: -x^2/b^2 + y^2/a^2 = 1
|
| 742 |
+
if re.search(expr_prefix + r'-x\^2/\w+\^?2?\s*\+\s*y\^2/\w+\^?2?\s*=\s*1\)', fact_expr):
|
| 743 |
+
return {
|
| 744 |
+
'type': 'hyperbola',
|
| 745 |
+
'a': 2.0, # default
|
| 746 |
+
'b': 1.5, # default
|
| 747 |
+
'a_squared': 4.0,
|
| 748 |
+
'b_squared': 2.25,
|
| 749 |
+
'symbolic': True,
|
| 750 |
+
'orientation': 'vertical'
|
| 751 |
+
}
|
| 752 |
+
|
| 753 |
+
# Vertical symbolic: y^2/a^2 - x^2/b^2 = 1
|
| 754 |
+
if re.search(expr_prefix + r'y\^2/\w+\^?2?\s*-\s*x\^2/\w+\^?2?\s*=\s*1\)', fact_expr):
|
| 755 |
+
return {
|
| 756 |
+
'type': 'hyperbola',
|
| 757 |
+
'a': 2.0, # default
|
| 758 |
+
'b': 1.5, # default
|
| 759 |
+
'a_squared': 4.0,
|
| 760 |
+
'b_squared': 2.25,
|
| 761 |
+
'symbolic': True,
|
| 762 |
+
'orientation': 'vertical'
|
| 763 |
+
}
|
| 764 |
+
|
| 765 |
+
# Horizontal symbolic: x^2/a^2 - y^2/b^2 = 1
|
| 766 |
+
if re.search(expr_prefix + r'x\^2/\w+\^?2?\s*-\s*y\^2/\w+\^?2?\s*=\s*1\)', fact_expr):
|
| 767 |
+
return {
|
| 768 |
+
'type': 'hyperbola',
|
| 769 |
+
'a': 2.0, # default
|
| 770 |
+
'b': 1.5, # default
|
| 771 |
+
'a_squared': 4.0,
|
| 772 |
+
'b_squared': 2.25,
|
| 773 |
+
'symbolic': True,
|
| 774 |
+
'orientation': 'horizontal'
|
| 775 |
+
}
|
| 776 |
+
|
| 777 |
+
# Horizontal symbolic: -y^2/b^2 + x^2/a^2 = 1
|
| 778 |
+
if re.search(expr_prefix + r'-y\^2/\w+\^?2?\s*\+\s*x\^2/\w+\^?2?\s*=\s*1\)', fact_expr):
|
| 779 |
+
return {
|
| 780 |
+
'type': 'hyperbola',
|
| 781 |
+
'a': 2.0, # default
|
| 782 |
+
'b': 1.5, # default
|
| 783 |
+
'a_squared': 4.0,
|
| 784 |
+
'b_squared': 2.25,
|
| 785 |
+
'symbolic': True,
|
| 786 |
+
'orientation': 'horizontal'
|
| 787 |
+
}
|
| 788 |
+
|
| 789 |
+
# Check for hyperbola type with asymptote/focus constraints (no explicit expression)
|
| 790 |
+
if 'Hyperbola' in fact_expr:
|
| 791 |
+
# Extract constraints
|
| 792 |
+
asymptote = self.parse_asymptote_slope(fact_expr)
|
| 793 |
+
coords = self.parse_coordinates(fact_expr)
|
| 794 |
+
focus_coords = [(n, c) for n, c in coords.items() if 'F' in n]
|
| 795 |
+
|
| 796 |
+
if asymptote or len(focus_coords) >= 2:
|
| 797 |
+
# Calculate a and b from constraints
|
| 798 |
+
if len(focus_coords) >= 2:
|
| 799 |
+
f1, f2 = focus_coords[0][1], focus_coords[1][1]
|
| 800 |
+
c = abs(f1[0] - f2[0]) / 2 if f1[1] == f2[1] == 0 else 3.0
|
| 801 |
+
else:
|
| 802 |
+
c = 3.0
|
| 803 |
+
|
| 804 |
+
if asymptote:
|
| 805 |
+
# b/a = asymptote, c² = a² + b²
|
| 806 |
+
# Let a be found from c and asymptote
|
| 807 |
+
# c² = a² + (a*slope)² = a²(1 + slope²)
|
| 808 |
+
a = c / np.sqrt(1 + asymptote**2)
|
| 809 |
+
b = a * asymptote
|
| 810 |
+
else:
|
| 811 |
+
a = c / np.sqrt(2)
|
| 812 |
+
b = a
|
| 813 |
+
|
| 814 |
+
return {
|
| 815 |
+
'type': 'hyperbola',
|
| 816 |
+
'a': a,
|
| 817 |
+
'b': b,
|
| 818 |
+
'a_squared': a**2,
|
| 819 |
+
'b_squared': b**2,
|
| 820 |
+
'from_constraints': True,
|
| 821 |
+
'orientation': 'horizontal' # Default, focus on x-axis
|
| 822 |
+
}
|
| 823 |
+
|
| 824 |
+
return None
|
| 825 |
+
|
| 826 |
+
def parse_parabola(self, fact_expr: str) -> Optional[Dict]:
|
| 827 |
+
"""Parse parabola expression."""
|
| 828 |
+
# y^2 = 4x, y^2 = 2*p*x, etc.
|
| 829 |
+
match = re.search(r'Expression\(\w+\)\s*=\s*\(y\^2\s*=\s*(\d+)\*x\)', fact_expr)
|
| 830 |
+
if match:
|
| 831 |
+
coef = float(match.group(1))
|
| 832 |
+
return {
|
| 833 |
+
'type': 'parabola',
|
| 834 |
+
'p': coef / 4, # 4p = coef
|
| 835 |
+
'direction': 'right'
|
| 836 |
+
}
|
| 837 |
+
|
| 838 |
+
# x^2 = 4y, x^2 = 2*p*y
|
| 839 |
+
match = re.search(r'Expression\(\w+\)\s*=\s*\(x\^2\s*=\s*(\d+)\*y\)', fact_expr)
|
| 840 |
+
if match:
|
| 841 |
+
coef = float(match.group(1))
|
| 842 |
+
return {
|
| 843 |
+
'type': 'parabola',
|
| 844 |
+
'p': coef / 4,
|
| 845 |
+
'direction': 'up'
|
| 846 |
+
}
|
| 847 |
+
|
| 848 |
+
# x^2 = -Ny (downward opening)
|
| 849 |
+
match = re.search(r'Expression\(\w+\)\s*=\s*\(x\^2\s*=\s*-(\d+)\*y\)', fact_expr)
|
| 850 |
+
if match:
|
| 851 |
+
coef = float(match.group(1))
|
| 852 |
+
return {
|
| 853 |
+
'type': 'parabola',
|
| 854 |
+
'p': coef / 4,
|
| 855 |
+
'direction': 'down'
|
| 856 |
+
}
|
| 857 |
+
|
| 858 |
+
# x^2 = y/N (small opening upward)
|
| 859 |
+
match = re.search(r'Expression\(\w+\)\s*=\s*\(x\^2\s*=\s*y/(\d+)\)', fact_expr)
|
| 860 |
+
if match:
|
| 861 |
+
divisor = float(match.group(1))
|
| 862 |
+
return {
|
| 863 |
+
'type': 'parabola',
|
| 864 |
+
'p': 1 / (4 * divisor),
|
| 865 |
+
'direction': 'up'
|
| 866 |
+
}
|
| 867 |
+
|
| 868 |
+
# y = -x^2/N (downward parabola in vertex form)
|
| 869 |
+
match = re.search(r'Expression\(\w+\)\s*=\s*\(y\s*=\s*-x\^2/(\d+)\)', fact_expr)
|
| 870 |
+
if match:
|
| 871 |
+
divisor = float(match.group(1))
|
| 872 |
+
# y = -x²/N → x² = -Ny → 4p = N → p = N/4
|
| 873 |
+
return {
|
| 874 |
+
'type': 'parabola',
|
| 875 |
+
'p': divisor / 4,
|
| 876 |
+
'direction': 'down'
|
| 877 |
+
}
|
| 878 |
+
|
| 879 |
+
# y = x^2/N (upward parabola in vertex form)
|
| 880 |
+
match = re.search(r'Expression\(\w+\)\s*=\s*\(y\s*=\s*x\^2/(\d+)\)', fact_expr)
|
| 881 |
+
if match:
|
| 882 |
+
divisor = float(match.group(1))
|
| 883 |
+
# y = x²/N → x² = Ny → 4p = N → p = N/4
|
| 884 |
+
return {
|
| 885 |
+
'type': 'parabola',
|
| 886 |
+
'p': divisor / 4,
|
| 887 |
+
'direction': 'up'
|
| 888 |
+
}
|
| 889 |
+
|
| 890 |
+
# y^2 = p*x (symbolic p, single coefficient)
|
| 891 |
+
if re.search(r'Expression\(\w+\)\s*=\s*\(y\^2\s*=\s*\w+\*x\)', fact_expr):
|
| 892 |
+
return {
|
| 893 |
+
'type': 'parabola',
|
| 894 |
+
'p': 1.0, # Default, will be optimized
|
| 895 |
+
'direction': 'right',
|
| 896 |
+
'symbolic': True
|
| 897 |
+
}
|
| 898 |
+
|
| 899 |
+
# x^2 = p*y (symbolic p, single coefficient)
|
| 900 |
+
if re.search(r'Expression\(\w+\)\s*=\s*\(x\^2\s*=\s*\w+\*y\)', fact_expr):
|
| 901 |
+
return {
|
| 902 |
+
'type': 'parabola',
|
| 903 |
+
'p': 1.0,
|
| 904 |
+
'direction': 'up',
|
| 905 |
+
'symbolic': True
|
| 906 |
+
}
|
| 907 |
+
|
| 908 |
+
# y^2 = 2*(p*x)
|
| 909 |
+
if re.search(r'Expression\(\w+\)\s*=\s*\(y\^2\s*=\s*2\*\(\w+\*x\)\)', fact_expr):
|
| 910 |
+
return {
|
| 911 |
+
'type': 'parabola',
|
| 912 |
+
'p': 1.0, # Default, will be optimized
|
| 913 |
+
'direction': 'right',
|
| 914 |
+
'symbolic': True
|
| 915 |
+
}
|
| 916 |
+
|
| 917 |
+
# x^2 = 2*(p*y)
|
| 918 |
+
if re.search(r'Expression\(\w+\)\s*=\s*\(x\^2\s*=\s*2\*\(\w+\*y\)\)', fact_expr):
|
| 919 |
+
return {
|
| 920 |
+
'type': 'parabola',
|
| 921 |
+
'p': 1.0,
|
| 922 |
+
'direction': 'up',
|
| 923 |
+
'symbolic': True
|
| 924 |
+
}
|
| 925 |
+
|
| 926 |
+
# y = 2*x^2 or y = a*x^2 (vertex form)
|
| 927 |
+
match = re.search(r'Expression\(\w+\)\s*=\s*\(y\s*=\s*(\d*)\*?x\^2\)', fact_expr)
|
| 928 |
+
if match:
|
| 929 |
+
coef = match.group(1)
|
| 930 |
+
a = float(coef) if coef else 1.0
|
| 931 |
+
return {
|
| 932 |
+
'type': 'parabola',
|
| 933 |
+
'p': 1 / (4 * a),
|
| 934 |
+
'direction': 'up'
|
| 935 |
+
}
|
| 936 |
+
|
| 937 |
+
# y = x^2/8 (division form)
|
| 938 |
+
match = re.search(r'Expression\(\w+\)\s*=\s*\(y\s*=\s*x\^2/(\d+)\)', fact_expr)
|
| 939 |
+
if match:
|
| 940 |
+
divisor = float(match.group(1))
|
| 941 |
+
return {
|
| 942 |
+
'type': 'parabola',
|
| 943 |
+
'p': divisor / 4,
|
| 944 |
+
'direction': 'up'
|
| 945 |
+
}
|
| 946 |
+
|
| 947 |
+
# y^2 = -8*x (left opening)
|
| 948 |
+
match = re.search(r'Expression\(\w+\)\s*=\s*\(y\^2\s*=\s*-(\d+)\*x\)', fact_expr)
|
| 949 |
+
if match:
|
| 950 |
+
coef = float(match.group(1))
|
| 951 |
+
return {
|
| 952 |
+
'type': 'parabola',
|
| 953 |
+
'p': coef / 4,
|
| 954 |
+
'direction': 'left'
|
| 955 |
+
}
|
| 956 |
+
|
| 957 |
+
# y^2 = 2*p*x (symbolic p) - parabola opening right
|
| 958 |
+
if re.search(r'Expression\(\w+\)\s*=\s*\(y\^2\s*=\s*2\*p\*x\)', fact_expr):
|
| 959 |
+
return {
|
| 960 |
+
'type': 'parabola',
|
| 961 |
+
'p': 1.0, # Default, will be optimized
|
| 962 |
+
'direction': 'right',
|
| 963 |
+
'symbolic': True
|
| 964 |
+
}
|
| 965 |
+
|
| 966 |
+
# x^2 = 2*p*y (symbolic p) - parabola opening up
|
| 967 |
+
if re.search(r'Expression\(\w+\)\s*=\s*\(x\^2\s*=\s*2\*p\*y\)', fact_expr):
|
| 968 |
+
return {
|
| 969 |
+
'type': 'parabola',
|
| 970 |
+
'p': 1.0, # Default, will be optimized
|
| 971 |
+
'direction': 'up',
|
| 972 |
+
'symbolic': True
|
| 973 |
+
}
|
| 974 |
+
|
| 975 |
+
# y^2 = x (p = 1/4, so 4p = 1) - parabola opening right
|
| 976 |
+
if re.search(r'Expression\(\w+\)\s*=\s*\(y\^2\s*=\s*x\)', fact_expr):
|
| 977 |
+
return {
|
| 978 |
+
'type': 'parabola',
|
| 979 |
+
'p': 0.25, # y^2 = 4px, so 4p = 1, p = 0.25
|
| 980 |
+
'direction': 'right'
|
| 981 |
+
}
|
| 982 |
+
|
| 983 |
+
# x^2 = y (p = 1/4) - parabola opening up
|
| 984 |
+
if re.search(r'Expression\(\w+\)\s*=\s*\(x\^2\s*=\s*y\)', fact_expr):
|
| 985 |
+
return {
|
| 986 |
+
'type': 'parabola',
|
| 987 |
+
'p': 0.25,
|
| 988 |
+
'direction': 'up'
|
| 989 |
+
}
|
| 990 |
+
|
| 991 |
+
# Check for Parabola type with geometric constraints
|
| 992 |
+
if 'Parabola' in fact_expr:
|
| 993 |
+
coords = self.parse_coordinates(fact_expr)
|
| 994 |
+
|
| 995 |
+
# Determine direction from constraints
|
| 996 |
+
direction = None
|
| 997 |
+
if 'PointOnCurve(Focus(' in fact_expr:
|
| 998 |
+
if 'xAxis' in fact_expr:
|
| 999 |
+
direction = 'right' # Focus on x-axis → horizontal parabola
|
| 1000 |
+
elif 'yAxis' in fact_expr:
|
| 1001 |
+
direction = 'up' # Focus on y-axis → vertical parabola
|
| 1002 |
+
|
| 1003 |
+
# Check for vertex at origin
|
| 1004 |
+
vertex_at_origin = 'Vertex(' in fact_expr and 'Origin' in fact_expr
|
| 1005 |
+
|
| 1006 |
+
# Try to find p from point on curve + distance to focus
|
| 1007 |
+
# Pattern: Distance(P, Focus(G)) = d
|
| 1008 |
+
dist_match = re.search(r'Distance\((\w+),\s*Focus\(\w+\)\)\s*=\s*(\d+)', fact_expr)
|
| 1009 |
+
if dist_match and vertex_at_origin:
|
| 1010 |
+
pt_name = dist_match.group(1)
|
| 1011 |
+
dist_val = float(dist_match.group(2))
|
| 1012 |
+
if pt_name in coords:
|
| 1013 |
+
px, py = coords[pt_name]
|
| 1014 |
+
# For parabola y² = 4px with vertex at origin:
|
| 1015 |
+
# Distance from point to focus = |x + p|
|
| 1016 |
+
# For right-opening: focus at (p, 0), dist = sqrt((x-p)² + y²)
|
| 1017 |
+
# We can solve for p
|
| 1018 |
+
if direction == 'right':
|
| 1019 |
+
# dist² = (px - p)² + py²
|
| 1020 |
+
# y² = 4px → py² = 4p*px
|
| 1021 |
+
# Substitute: dist² = (px - p)² + 4p*px
|
| 1022 |
+
# dist² = px² - 2*px*p + p² + 4p*px = px² + 2*px*p + p² = (px + p)²
|
| 1023 |
+
# So dist = |px + p|, p = dist - px (assuming px > 0)
|
| 1024 |
+
p = (dist_val - px) if px >= 0 else (dist_val + px)
|
| 1025 |
+
if p > 0:
|
| 1026 |
+
return {
|
| 1027 |
+
'type': 'parabola',
|
| 1028 |
+
'p': p,
|
| 1029 |
+
'direction': 'right',
|
| 1030 |
+
'from_constraints': True
|
| 1031 |
+
}
|
| 1032 |
+
elif direction == 'up':
|
| 1033 |
+
p = (dist_val - py) if py >= 0 else (dist_val + py)
|
| 1034 |
+
if p > 0:
|
| 1035 |
+
return {
|
| 1036 |
+
'type': 'parabola',
|
| 1037 |
+
'p': p,
|
| 1038 |
+
'direction': 'up',
|
| 1039 |
+
'from_constraints': True
|
| 1040 |
+
}
|
| 1041 |
+
|
| 1042 |
+
# Look for focus coordinate in coords
|
| 1043 |
+
for name, (px, py) in coords.items():
|
| 1044 |
+
# If this is a focus (F in name) or explicitly marked as focus
|
| 1045 |
+
if 'F' in name and (f'Focus(' in fact_expr):
|
| 1046 |
+
if abs(py) < 0.01: # Focus on x-axis
|
| 1047 |
+
return {
|
| 1048 |
+
'type': 'parabola',
|
| 1049 |
+
'p': abs(px), # Focus at (p, 0)
|
| 1050 |
+
'direction': 'right' if px > 0 else 'left',
|
| 1051 |
+
'from_constraints': True
|
| 1052 |
+
}
|
| 1053 |
+
elif abs(px) < 0.01: # Focus on y-axis
|
| 1054 |
+
return {
|
| 1055 |
+
'type': 'parabola',
|
| 1056 |
+
'p': abs(py),
|
| 1057 |
+
'direction': 'up' if py > 0 else 'down',
|
| 1058 |
+
'from_constraints': True
|
| 1059 |
+
}
|
| 1060 |
+
|
| 1061 |
+
# Default: parabola with vertex at origin, direction from constraints
|
| 1062 |
+
if vertex_at_origin and direction:
|
| 1063 |
+
return {
|
| 1064 |
+
'type': 'parabola',
|
| 1065 |
+
'p': 1.0, # Default, will be optimized
|
| 1066 |
+
'direction': direction,
|
| 1067 |
+
'symbolic': True
|
| 1068 |
+
}
|
| 1069 |
+
|
| 1070 |
+
return None
|
| 1071 |
+
|
| 1072 |
+
def parse_coordinates(self, fact_expr: str) -> Dict[str, Tuple[float, float]]:
|
| 1073 |
+
"""Extract point coordinates."""
|
| 1074 |
+
coords = {}
|
| 1075 |
+
# Use a more robust pattern that handles nested parentheses
|
| 1076 |
+
# Match: Coordinate(Name) = (x_expr, y_expr)
|
| 1077 |
+
# Find all Coordinate(...) = (...) patterns
|
| 1078 |
+
coord_pattern = r'Coordinate\((\w+)\)\s*=\s*\(([^;]+)\)'
|
| 1079 |
+
for match in re.finditer(coord_pattern, fact_expr):
|
| 1080 |
+
name = match.group(1)
|
| 1081 |
+
coord_str = match.group(2)
|
| 1082 |
+
|
| 1083 |
+
# Split by comma, but handle nested parentheses
|
| 1084 |
+
depth = 0
|
| 1085 |
+
parts = []
|
| 1086 |
+
current = ""
|
| 1087 |
+
for char in coord_str:
|
| 1088 |
+
if char == '(':
|
| 1089 |
+
depth += 1
|
| 1090 |
+
current += char
|
| 1091 |
+
elif char == ')':
|
| 1092 |
+
depth -= 1
|
| 1093 |
+
current += char
|
| 1094 |
+
elif char == ',' and depth == 0:
|
| 1095 |
+
parts.append(current.strip())
|
| 1096 |
+
current = ""
|
| 1097 |
+
else:
|
| 1098 |
+
current += char
|
| 1099 |
+
parts.append(current.strip())
|
| 1100 |
+
|
| 1101 |
+
if len(parts) >= 2:
|
| 1102 |
+
try:
|
| 1103 |
+
x = parts[0].replace('sqrt', 'np.sqrt').replace('^', '**')
|
| 1104 |
+
y = parts[1].replace('sqrt', 'np.sqrt').replace('^', '**')
|
| 1105 |
+
x_val = float(eval(x, {"np": np, "__builtins__": {}}))
|
| 1106 |
+
y_val = float(eval(y, {"np": np, "__builtins__": {}}))
|
| 1107 |
+
coords[name] = (x_val, y_val)
|
| 1108 |
+
except:
|
| 1109 |
+
pass
|
| 1110 |
+
return coords
|
| 1111 |
+
|
| 1112 |
+
def parse_eccentricity(self, fact_expr: str) -> Optional[float]:
|
| 1113 |
+
"""Extract eccentricity constraint."""
|
| 1114 |
+
# sqrt pattern
|
| 1115 |
+
match = re.search(r'Eccentricity\(\w+\)\s*=\s*sqrt\((\d+)\)', fact_expr)
|
| 1116 |
+
if match:
|
| 1117 |
+
return np.sqrt(float(match.group(1)))
|
| 1118 |
+
|
| 1119 |
+
# Fraction pattern (MUST be checked BEFORE decimal pattern!)
|
| 1120 |
+
match = re.search(r'Eccentricity\(\w+\)\s*=\s*(\d+)/(\d+)', fact_expr)
|
| 1121 |
+
if match:
|
| 1122 |
+
return float(match.group(1)) / float(match.group(2))
|
| 1123 |
+
|
| 1124 |
+
# Simple decimal pattern
|
| 1125 |
+
match = re.search(r'Eccentricity\(\w+\)\s*=\s*([\d.]+)', fact_expr)
|
| 1126 |
+
if match:
|
| 1127 |
+
return float(match.group(1))
|
| 1128 |
+
|
| 1129 |
+
return None
|
| 1130 |
+
|
| 1131 |
+
def parse_asymptote_slope(self, fact_expr: str) -> Optional[float]:
|
| 1132 |
+
"""Extract asymptote slope for hyperbola.
|
| 1133 |
+
|
| 1134 |
+
Supports patterns like:
|
| 1135 |
+
- y = sqrt(2)*x
|
| 1136 |
+
- y = pm*sqrt(2)*x
|
| 1137 |
+
- y = pm*(sqrt(2)/2)*x or y = pm*(sqrt(2)/2)*X
|
| 1138 |
+
- y = 4/3*x
|
| 1139 |
+
- y = pm*3*x
|
| 1140 |
+
- y = pm*(sqrt(2)*x)
|
| 1141 |
+
"""
|
| 1142 |
+
# Pattern: y = sqrt(N)*x
|
| 1143 |
+
match = re.search(r'Asymptote.*?=\s*\(y\s*=\s*sqrt\((\d+)\)\*[xX]\)', fact_expr)
|
| 1144 |
+
if match:
|
| 1145 |
+
return np.sqrt(float(match.group(1)))
|
| 1146 |
+
|
| 1147 |
+
# Pattern: y = pm*sqrt(N)*x or y = pm*(sqrt(N)*x)
|
| 1148 |
+
match = re.search(r'Asymptote.*?=\s*\(y\s*=\s*pm\*\(?sqrt\((\d+)\)\*?[xX]\)?', fact_expr)
|
| 1149 |
+
if match:
|
| 1150 |
+
return np.sqrt(float(match.group(1)))
|
| 1151 |
+
|
| 1152 |
+
# Pattern: y = pm*(sqrt(N)/M)*x (e.g., sqrt(2)/2)
|
| 1153 |
+
match = re.search(r'Asymptote.*?=\s*\(y\s*=\s*pm\*\(sqrt\((\d+)\)/(\d+)\)\*[xX]\)', fact_expr)
|
| 1154 |
+
if match:
|
| 1155 |
+
return np.sqrt(float(match.group(1))) / float(match.group(2))
|
| 1156 |
+
|
| 1157 |
+
# Pattern: y = A/B*x (fraction slope)
|
| 1158 |
+
match = re.search(r'Asymptote.*?=\s*\(y\s*=\s*(\d+)/(\d+)\*[xX]\)', fact_expr)
|
| 1159 |
+
if match:
|
| 1160 |
+
return float(match.group(1)) / float(match.group(2))
|
| 1161 |
+
|
| 1162 |
+
# Pattern: y = pm*N*x (integer slope)
|
| 1163 |
+
match = re.search(r'Asymptote.*?=\s*\(y\s*=\s*pm\*(\d+)\*[xX]\)', fact_expr)
|
| 1164 |
+
if match:
|
| 1165 |
+
return float(match.group(1))
|
| 1166 |
+
|
| 1167 |
+
# Pattern: y = N*x (simple integer slope)
|
| 1168 |
+
match = re.search(r'Asymptote.*?=\s*\(y\s*=\s*(\d+)\*[xX]\)', fact_expr)
|
| 1169 |
+
if match:
|
| 1170 |
+
return float(match.group(1))
|
| 1171 |
+
|
| 1172 |
+
# Pattern: pm*A*y+B*x=0 → y = ±(B/A)*x, slope = B/A
|
| 1173 |
+
match = re.search(r'Asymptote.*?=\s*\(pm\*(\d+)\*y\+(\d+)\*x=0\)', fact_expr)
|
| 1174 |
+
if match:
|
| 1175 |
+
a = float(match.group(1))
|
| 1176 |
+
b = float(match.group(2))
|
| 1177 |
+
return b / a
|
| 1178 |
+
|
| 1179 |
+
# Pattern: pm*(A/B)*x or y = pm*(A/B)*x
|
| 1180 |
+
match = re.search(r'Asymptote.*?=\s*\(y\s*=\s*pm\*\((\d+)/(\d+)\)\*[xX]\)', fact_expr)
|
| 1181 |
+
if match:
|
| 1182 |
+
return float(match.group(1)) / float(match.group(2))
|
| 1183 |
+
|
| 1184 |
+
return None
|
src/sdf_geo/primitives.py
ADDED
|
@@ -0,0 +1,354 @@
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|
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|
|
|
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|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
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|
|
|
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|
|
|
|
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|
|
|
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|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
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|
|
|
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|
|
|
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|
|
|
|
|
|
|
|
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|
|
|
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|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
| 1 |
+
"""
|
| 2 |
+
SDF Primitives - Core geometric shape representations as Signed Distance Fields.
|
| 3 |
+
Following GeoSDF paper methodology.
|
| 4 |
+
|
| 5 |
+
This module contains:
|
| 6 |
+
- Math utilities for quartic solving (Appendix B)
|
| 7 |
+
- SDF primitive classes (Circle, Ellipse, Hyperbola, Parabola, Line, etc.)
|
| 8 |
+
"""
|
| 9 |
+
|
| 10 |
+
import torch
|
| 11 |
+
import torch.nn as nn
|
| 12 |
+
from typing import Tuple
|
| 13 |
+
|
| 14 |
+
# Device configuration
|
| 15 |
+
DEVICE = torch.device('cuda' if torch.cuda.is_available() else 'cpu')
|
| 16 |
+
|
| 17 |
+
|
| 18 |
+
# =============================================================================
|
| 19 |
+
# Quartic Solver Utilities (Following Paper Appendix B)
|
| 20 |
+
# =============================================================================
|
| 21 |
+
|
| 22 |
+
def solve_cubic_one_real_batch(a: torch.Tensor, b: torch.Tensor, c: torch.Tensor,
|
| 23 |
+
d: torch.Tensor) -> torch.Tensor:
|
| 24 |
+
"""Find one real root of cubic equation using Cardano's formula."""
|
| 25 |
+
a_safe = a + 1e-10 * torch.sign(a + 1e-20)
|
| 26 |
+
p = b / a_safe
|
| 27 |
+
q = c / a_safe
|
| 28 |
+
r = d / a_safe
|
| 29 |
+
|
| 30 |
+
alpha = q - p**2 / 3
|
| 31 |
+
beta = 2 * p**3 / 27 - p * q / 3 + r
|
| 32 |
+
discriminant = (beta / 2)**2 + (alpha / 3)**3
|
| 33 |
+
sqrt_disc = torch.sqrt(torch.clamp(discriminant, min=0) + 1e-12)
|
| 34 |
+
|
| 35 |
+
term1 = -beta / 2 + sqrt_disc
|
| 36 |
+
term2 = -beta / 2 - sqrt_disc
|
| 37 |
+
|
| 38 |
+
def safe_cbrt(x):
|
| 39 |
+
return torch.sign(x) * torch.pow(torch.abs(x) + 1e-12, 1/3)
|
| 40 |
+
|
| 41 |
+
u = safe_cbrt(term1)
|
| 42 |
+
v = safe_cbrt(term2)
|
| 43 |
+
|
| 44 |
+
return u + v - p / 3
|
| 45 |
+
|
| 46 |
+
|
| 47 |
+
def hyperbola_distance_quartic(px: torch.Tensor, py: torch.Tensor,
|
| 48 |
+
a: torch.Tensor, b: torch.Tensor) -> torch.Tensor:
|
| 49 |
+
"""Compute exact distance from point to hyperbola using Newton iteration."""
|
| 50 |
+
px_abs = torch.abs(px)
|
| 51 |
+
py_abs = torch.abs(py)
|
| 52 |
+
|
| 53 |
+
t = torch.asinh(py_abs / (b + 1e-8))
|
| 54 |
+
t = torch.clamp(t, 0.01, 10.0)
|
| 55 |
+
|
| 56 |
+
for _ in range(15):
|
| 57 |
+
cosh_t = torch.cosh(t)
|
| 58 |
+
sinh_t = torch.sinh(t)
|
| 59 |
+
hx = a * cosh_t
|
| 60 |
+
hy = b * sinh_t
|
| 61 |
+
dx = px_abs - hx
|
| 62 |
+
dy = py_abs - hy
|
| 63 |
+
|
| 64 |
+
grad = -2 * (dx * a * sinh_t + dy * b * cosh_t)
|
| 65 |
+
hess = 2 * (a**2 * sinh_t**2 + b**2 * cosh_t**2 - dx * a * cosh_t - dy * b * sinh_t) + 1e-6
|
| 66 |
+
|
| 67 |
+
step = grad / torch.abs(hess)
|
| 68 |
+
t = t - torch.clamp(step, -0.3, 0.3)
|
| 69 |
+
t = torch.clamp(t, 0.001, 20.0)
|
| 70 |
+
|
| 71 |
+
cosh_t = torch.cosh(t)
|
| 72 |
+
sinh_t = torch.sinh(t)
|
| 73 |
+
return torch.sqrt((px_abs - a * cosh_t)**2 + (py_abs - b * sinh_t)**2 + 1e-10)
|
| 74 |
+
|
| 75 |
+
|
| 76 |
+
def ellipse_distance_quartic(px: torch.Tensor, py: torch.Tensor,
|
| 77 |
+
a: torch.Tensor, b: torch.Tensor) -> torch.Tensor:
|
| 78 |
+
"""Compute exact distance from point to ellipse using Newton iteration."""
|
| 79 |
+
px_abs = torch.abs(px)
|
| 80 |
+
py_abs = torch.abs(py)
|
| 81 |
+
|
| 82 |
+
a_use = torch.max(a, b)
|
| 83 |
+
b_use = torch.min(a, b)
|
| 84 |
+
|
| 85 |
+
needs_swap = a < b
|
| 86 |
+
if needs_swap:
|
| 87 |
+
px_use, py_use = py_abs, px_abs
|
| 88 |
+
else:
|
| 89 |
+
px_use, py_use = px_abs, py_abs
|
| 90 |
+
|
| 91 |
+
at_origin = (px_use < 1e-10) & (py_use < 1e-10)
|
| 92 |
+
on_x_axis = py_use < 1e-10
|
| 93 |
+
on_y_axis = px_use < 1e-10
|
| 94 |
+
|
| 95 |
+
theta = torch.atan2(a_use * py_use, b_use * px_use)
|
| 96 |
+
|
| 97 |
+
for _ in range(12):
|
| 98 |
+
cos_t = torch.cos(theta)
|
| 99 |
+
sin_t = torch.sin(theta)
|
| 100 |
+
ex = a_use * cos_t
|
| 101 |
+
ey = b_use * sin_t
|
| 102 |
+
dx = px_use - ex
|
| 103 |
+
dy = py_use - ey
|
| 104 |
+
|
| 105 |
+
grad = 2 * (dx * a_use * sin_t - dy * b_use * cos_t)
|
| 106 |
+
hess = 2 * (a_use**2 * sin_t**2 + b_use**2 * cos_t**2 + dx * a_use * cos_t + dy * b_use * sin_t) + 1e-6
|
| 107 |
+
|
| 108 |
+
theta = theta - torch.clamp(grad / torch.abs(hess), -0.3, 0.3)
|
| 109 |
+
|
| 110 |
+
cos_t = torch.cos(theta)
|
| 111 |
+
sin_t = torch.sin(theta)
|
| 112 |
+
dist = torch.sqrt((px_use - a_use * cos_t)**2 + (py_use - b_use * sin_t)**2 + 1e-10)
|
| 113 |
+
|
| 114 |
+
dist = torch.where(at_origin, b_use, dist)
|
| 115 |
+
dist = torch.where(on_x_axis & ~at_origin, torch.where(px_use > a_use, px_use - a_use, torch.sqrt((px_use - a_use)**2 + 1e-10)), dist)
|
| 116 |
+
dist = torch.where(on_y_axis & ~at_origin, torch.abs(py_use - b_use), dist)
|
| 117 |
+
|
| 118 |
+
return dist
|
| 119 |
+
|
| 120 |
+
|
| 121 |
+
# =============================================================================
|
| 122 |
+
# SDF Primitives Base Class
|
| 123 |
+
# =============================================================================
|
| 124 |
+
|
| 125 |
+
class SDFPrimitive(nn.Module):
|
| 126 |
+
"""Base class for SDF primitives - all shapes represented as distance functions."""
|
| 127 |
+
|
| 128 |
+
def forward(self, p: torch.Tensor) -> torch.Tensor:
|
| 129 |
+
"""Compute signed distance from points p to the shape boundary."""
|
| 130 |
+
raise NotImplementedError
|
| 131 |
+
|
| 132 |
+
|
| 133 |
+
class PointSDF(SDFPrimitive):
|
| 134 |
+
"""SDF for a point: f(p; c) = ||p - c||₂"""
|
| 135 |
+
|
| 136 |
+
def __init__(self, center: torch.Tensor):
|
| 137 |
+
super().__init__()
|
| 138 |
+
self.center = nn.Parameter(center.clone())
|
| 139 |
+
|
| 140 |
+
def forward(self, p: torch.Tensor) -> torch.Tensor:
|
| 141 |
+
return torch.norm(p - self.center, dim=-1)
|
| 142 |
+
|
| 143 |
+
|
| 144 |
+
class CircleSDF(SDFPrimitive):
|
| 145 |
+
"""SDF for circle: f(p; c, r) = ||p - c||₂ - r"""
|
| 146 |
+
|
| 147 |
+
def __init__(self, center: torch.Tensor, radius: torch.Tensor):
|
| 148 |
+
super().__init__()
|
| 149 |
+
self.center = nn.Parameter(center.clone())
|
| 150 |
+
self.radius = nn.Parameter(radius.clone())
|
| 151 |
+
|
| 152 |
+
def forward(self, p: torch.Tensor) -> torch.Tensor:
|
| 153 |
+
dist_to_center = torch.norm(p - self.center, dim=-1)
|
| 154 |
+
return dist_to_center - self.radius
|
| 155 |
+
|
| 156 |
+
|
| 157 |
+
class EllipseSDF(SDFPrimitive):
|
| 158 |
+
"""SDF for ellipse: x²/a² + y²/b² = 1"""
|
| 159 |
+
|
| 160 |
+
def __init__(self, center: torch.Tensor, a: torch.Tensor, b: torch.Tensor):
|
| 161 |
+
super().__init__()
|
| 162 |
+
self.center = nn.Parameter(center.clone())
|
| 163 |
+
self.a = nn.Parameter(a.clone())
|
| 164 |
+
self.b = nn.Parameter(b.clone())
|
| 165 |
+
|
| 166 |
+
def forward(self, p: torch.Tensor) -> torch.Tensor:
|
| 167 |
+
p_local = p - self.center
|
| 168 |
+
px = p_local[..., 0]
|
| 169 |
+
py = p_local[..., 1]
|
| 170 |
+
|
| 171 |
+
a = torch.abs(self.a) + 1e-8
|
| 172 |
+
b = torch.abs(self.b) + 1e-8
|
| 173 |
+
|
| 174 |
+
dist = ellipse_distance_quartic(px, py, a, b)
|
| 175 |
+
ellipse_val = px**2 / (a**2) + py**2 / (b**2)
|
| 176 |
+
inside = ellipse_val < 1
|
| 177 |
+
|
| 178 |
+
return torch.where(inside, -dist, dist)
|
| 179 |
+
|
| 180 |
+
|
| 181 |
+
class HyperbolaSDF(SDFPrimitive):
|
| 182 |
+
"""SDF for hyperbola: x²/a² - y²/b² = 1"""
|
| 183 |
+
|
| 184 |
+
def __init__(self, center: torch.Tensor, a: torch.Tensor, b: torch.Tensor):
|
| 185 |
+
super().__init__()
|
| 186 |
+
self.center = nn.Parameter(center.clone())
|
| 187 |
+
self.a = nn.Parameter(a.clone())
|
| 188 |
+
self.b = nn.Parameter(b.clone())
|
| 189 |
+
|
| 190 |
+
def forward(self, p: torch.Tensor) -> torch.Tensor:
|
| 191 |
+
p_local = p - self.center
|
| 192 |
+
px = p_local[..., 0]
|
| 193 |
+
py = p_local[..., 1]
|
| 194 |
+
|
| 195 |
+
a = torch.abs(self.a) + 1e-8
|
| 196 |
+
b = torch.abs(self.b) + 1e-8
|
| 197 |
+
|
| 198 |
+
dist = hyperbola_distance_quartic(px, py, a, b)
|
| 199 |
+
hyperbola_val = px**2 / (a**2) - py**2 / (b**2)
|
| 200 |
+
is_between_branches = hyperbola_val < 1
|
| 201 |
+
|
| 202 |
+
return torch.where(is_between_branches, -dist, dist)
|
| 203 |
+
|
| 204 |
+
|
| 205 |
+
class ParabolaSDF(SDFPrimitive):
|
| 206 |
+
"""SDF for parabola: y² = 4px (rightward) or x² = 4py (upward)"""
|
| 207 |
+
|
| 208 |
+
def __init__(self, vertex: torch.Tensor, p: torch.Tensor, direction: str = 'right'):
|
| 209 |
+
super().__init__()
|
| 210 |
+
self.vertex = nn.Parameter(vertex.clone())
|
| 211 |
+
self.p = nn.Parameter(p.clone())
|
| 212 |
+
self.direction = direction
|
| 213 |
+
|
| 214 |
+
def forward(self, pts: torch.Tensor) -> torch.Tensor:
|
| 215 |
+
p_local = pts - self.vertex
|
| 216 |
+
px = p_local[..., 0]
|
| 217 |
+
py = p_local[..., 1]
|
| 218 |
+
p_param = torch.abs(self.p) + 1e-6
|
| 219 |
+
|
| 220 |
+
if self.direction == 'right':
|
| 221 |
+
return self._compute_distance_right(px, py, p_param)
|
| 222 |
+
elif self.direction == 'left':
|
| 223 |
+
return self._compute_distance_right(-px, py, p_param)
|
| 224 |
+
elif self.direction == 'up':
|
| 225 |
+
return self._compute_distance_right(py, px, p_param)
|
| 226 |
+
elif self.direction == 'down':
|
| 227 |
+
return self._compute_distance_right(-py, px, p_param)
|
| 228 |
+
return self._compute_distance_right(px, py, p_param)
|
| 229 |
+
|
| 230 |
+
def _compute_distance_right(self, px: torch.Tensor, py: torch.Tensor, p: torch.Tensor) -> torch.Tensor:
|
| 231 |
+
t = py.clone()
|
| 232 |
+
|
| 233 |
+
for _ in range(12):
|
| 234 |
+
para_x = t**2 / (4 * p)
|
| 235 |
+
para_y = t
|
| 236 |
+
dx = px - para_x
|
| 237 |
+
dy = py - para_y
|
| 238 |
+
dpara_x = t / (2 * p)
|
| 239 |
+
dpara_y = torch.ones_like(t)
|
| 240 |
+
|
| 241 |
+
grad = -2 * (dx * dpara_x + dy * dpara_y)
|
| 242 |
+
ddpara_x = 1 / (2 * p)
|
| 243 |
+
hess = 2 * (dpara_x**2 + dpara_y**2 - dx * ddpara_x) + 1e-8
|
| 244 |
+
|
| 245 |
+
t = t - torch.clamp(grad / torch.abs(hess), -1.0, 1.0)
|
| 246 |
+
|
| 247 |
+
para_x = t**2 / (4 * p)
|
| 248 |
+
para_y = t
|
| 249 |
+
dist = torch.sqrt((px - para_x)**2 + (py - para_y)**2 + 1e-10)
|
| 250 |
+
|
| 251 |
+
at_vertex = (torch.abs(px) < 1e-6) & (torch.abs(py) < 1e-6)
|
| 252 |
+
dist = torch.where(at_vertex, torch.zeros_like(dist), dist)
|
| 253 |
+
|
| 254 |
+
on_concave_side = (px >= 0) & (py**2 < 4 * p * px)
|
| 255 |
+
return torch.where(on_concave_side, -dist, dist)
|
| 256 |
+
|
| 257 |
+
|
| 258 |
+
class LineSDF(SDFPrimitive):
|
| 259 |
+
"""SDF for infinite line passing through point with direction."""
|
| 260 |
+
|
| 261 |
+
def __init__(self, point: torch.Tensor, direction: torch.Tensor):
|
| 262 |
+
super().__init__()
|
| 263 |
+
self.point = nn.Parameter(point.clone())
|
| 264 |
+
self.direction = nn.Parameter(direction / (torch.norm(direction) + 1e-8))
|
| 265 |
+
|
| 266 |
+
def forward(self, p: torch.Tensor) -> torch.Tensor:
|
| 267 |
+
v = p - self.point
|
| 268 |
+
normal = torch.tensor([-self.direction[1], self.direction[0]], device=p.device)
|
| 269 |
+
return (v * normal).sum(dim=-1)
|
| 270 |
+
|
| 271 |
+
|
| 272 |
+
class LineSegmentSDF(SDFPrimitive):
|
| 273 |
+
"""SDF for line segment from point a to point b."""
|
| 274 |
+
|
| 275 |
+
def __init__(self, a: torch.Tensor, b: torch.Tensor):
|
| 276 |
+
super().__init__()
|
| 277 |
+
self.a = nn.Parameter(a.clone())
|
| 278 |
+
self.b = nn.Parameter(b.clone())
|
| 279 |
+
|
| 280 |
+
def forward(self, p: torch.Tensor) -> torch.Tensor:
|
| 281 |
+
v_ab = self.b - self.a
|
| 282 |
+
v_ap = p - self.a
|
| 283 |
+
h = (v_ap * v_ab).sum(dim=-1) / (torch.norm(v_ab)**2 + 1e-8)
|
| 284 |
+
h_clamped = torch.clamp(h, 0, 1)
|
| 285 |
+
closest = self.a + h_clamped.unsqueeze(-1) * v_ab
|
| 286 |
+
return torch.norm(p - closest, dim=-1)
|
| 287 |
+
|
| 288 |
+
|
| 289 |
+
class TriangleEdgesSDF(SDFPrimitive):
|
| 290 |
+
"""SDF for triangle edges (boundary only)."""
|
| 291 |
+
|
| 292 |
+
def __init__(self, v0: torch.Tensor, v1: torch.Tensor, v2: torch.Tensor,
|
| 293 |
+
line_thickness: float = 0.02):
|
| 294 |
+
super().__init__()
|
| 295 |
+
self.edge0 = LineSegmentSDF(v0, v1)
|
| 296 |
+
self.edge1 = LineSegmentSDF(v1, v2)
|
| 297 |
+
self.edge2 = LineSegmentSDF(v2, v0)
|
| 298 |
+
self.thickness = line_thickness
|
| 299 |
+
|
| 300 |
+
def forward(self, p: torch.Tensor) -> torch.Tensor:
|
| 301 |
+
d0 = self.edge0(p)
|
| 302 |
+
d1 = self.edge1(p)
|
| 303 |
+
d2 = self.edge2(p)
|
| 304 |
+
return torch.min(torch.min(d0, d1), d2) - self.thickness
|
| 305 |
+
|
| 306 |
+
|
| 307 |
+
class TriangleFillSDF(SDFPrimitive):
|
| 308 |
+
"""SDF for filled triangle region."""
|
| 309 |
+
|
| 310 |
+
def __init__(self, v0: torch.Tensor, v1: torch.Tensor, v2: torch.Tensor):
|
| 311 |
+
super().__init__()
|
| 312 |
+
self.v0 = nn.Parameter(v0.clone())
|
| 313 |
+
self.v1 = nn.Parameter(v1.clone())
|
| 314 |
+
self.v2 = nn.Parameter(v2.clone())
|
| 315 |
+
self.edge0 = LineSegmentSDF(v0, v1)
|
| 316 |
+
self.edge1 = LineSegmentSDF(v1, v2)
|
| 317 |
+
self.edge2 = LineSegmentSDF(v2, v0)
|
| 318 |
+
|
| 319 |
+
def _sign(self, p: torch.Tensor, a: torch.Tensor, b: torch.Tensor) -> torch.Tensor:
|
| 320 |
+
return (p[..., 0] - a[0]) * (b[1] - a[1]) - (b[0] - a[0]) * (p[..., 1] - a[1])
|
| 321 |
+
|
| 322 |
+
def forward(self, p: torch.Tensor) -> torch.Tensor:
|
| 323 |
+
d0 = self.edge0(p)
|
| 324 |
+
d1 = self.edge1(p)
|
| 325 |
+
d2 = self.edge2(p)
|
| 326 |
+
dist = torch.min(torch.min(d0, d1), d2)
|
| 327 |
+
|
| 328 |
+
s0 = self._sign(p, self.v0, self.v1)
|
| 329 |
+
s1 = self._sign(p, self.v1, self.v2)
|
| 330 |
+
s2 = self._sign(p, self.v2, self.v0)
|
| 331 |
+
|
| 332 |
+
inside = ((s0 >= 0) & (s1 >= 0) & (s2 >= 0)) | ((s0 <= 0) & (s1 <= 0) & (s2 <= 0))
|
| 333 |
+
return torch.where(inside, -dist, dist)
|
| 334 |
+
|
| 335 |
+
|
| 336 |
+
class RightAngleSDF(SDFPrimitive):
|
| 337 |
+
"""SDF for right angle marker."""
|
| 338 |
+
|
| 339 |
+
def __init__(self, vertex: torch.Tensor, dir1: torch.Tensor, dir2: torch.Tensor,
|
| 340 |
+
size: float = 0.25, thickness: float = 0.015):
|
| 341 |
+
super().__init__()
|
| 342 |
+
dir1_norm = dir1 / (torch.norm(dir1) + 1e-8)
|
| 343 |
+
dir2_norm = dir2 / (torch.norm(dir2) + 1e-8)
|
| 344 |
+
|
| 345 |
+
p1 = vertex + dir1_norm * size
|
| 346 |
+
p2 = vertex + dir2_norm * size
|
| 347 |
+
p3 = vertex + dir1_norm * size + dir2_norm * size
|
| 348 |
+
|
| 349 |
+
self.seg1 = LineSegmentSDF(p1, p3)
|
| 350 |
+
self.seg2 = LineSegmentSDF(p2, p3)
|
| 351 |
+
self.thickness = thickness
|
| 352 |
+
|
| 353 |
+
def forward(self, p: torch.Tensor) -> torch.Tensor:
|
| 354 |
+
return torch.min(self.seg1(p), self.seg2(p)) - self.thickness
|
src/sdf_geo/processor.py
ADDED
|
@@ -0,0 +1,1218 @@
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|
| 1 |
+
"""
|
| 2 |
+
Batch Processor Module
|
| 3 |
+
Processes geometry problems and generates visualizations.
|
| 4 |
+
"""
|
| 5 |
+
|
| 6 |
+
import torch
|
| 7 |
+
import numpy as np
|
| 8 |
+
import matplotlib.pyplot as plt
|
| 9 |
+
from matplotlib.lines import Line2D
|
| 10 |
+
import json
|
| 11 |
+
import re
|
| 12 |
+
from pathlib import Path
|
| 13 |
+
from typing import Dict, List, Tuple, Optional
|
| 14 |
+
from tqdm import tqdm
|
| 15 |
+
|
| 16 |
+
from .primitives import (
|
| 17 |
+
CircleSDF, EllipseSDF, HyperbolaSDF, ParabolaSDF
|
| 18 |
+
)
|
| 19 |
+
from .constraints import GeometricConstraints
|
| 20 |
+
from .parser import ProblemParser
|
| 21 |
+
from .optimizer import GeometryOptimizer
|
| 22 |
+
from .renderer import SDFRenderer
|
| 23 |
+
|
| 24 |
+
|
| 25 |
+
class SDFBatchProcessor:
|
| 26 |
+
"""
|
| 27 |
+
Process problems using the SDF methodology.
|
| 28 |
+
"""
|
| 29 |
+
|
| 30 |
+
def __init__(self, output_dir: str = 'sdf_output'):
|
| 31 |
+
self.output_dir = Path(output_dir)
|
| 32 |
+
self.output_dir.mkdir(exist_ok=True, parents=True)
|
| 33 |
+
|
| 34 |
+
self.parser = ProblemParser()
|
| 35 |
+
self.optimizer = GeometryOptimizer()
|
| 36 |
+
|
| 37 |
+
# Create subdirectories
|
| 38 |
+
for subdir in ['ellipse', 'hyperbola', 'parabola', 'circle']:
|
| 39 |
+
(self.output_dir / subdir).mkdir(exist_ok=True)
|
| 40 |
+
|
| 41 |
+
def process_problem(self, problem: Dict, idx: int, verbose: bool = False) -> Dict:
|
| 42 |
+
"""Process a single problem using SDF methodology."""
|
| 43 |
+
result = {
|
| 44 |
+
'index': idx,
|
| 45 |
+
'success': False,
|
| 46 |
+
'error': None
|
| 47 |
+
}
|
| 48 |
+
|
| 49 |
+
try:
|
| 50 |
+
fact_expr = problem.get('fact_expressions', '')
|
| 51 |
+
text = problem.get('text', '')
|
| 52 |
+
query_expr = problem.get('query_expressions', '')
|
| 53 |
+
|
| 54 |
+
# Determine the primary shape to visualize based on query
|
| 55 |
+
# If query is about Expression(G), find what G is
|
| 56 |
+
primary_shape = None
|
| 57 |
+
query_match = re.search(r'Expression\((\w+)\)', query_expr)
|
| 58 |
+
if query_match:
|
| 59 |
+
shape_name = query_match.group(1)
|
| 60 |
+
# Find what type this shape is
|
| 61 |
+
type_match = re.search(rf'{shape_name}:\s*(\w+)', fact_expr)
|
| 62 |
+
if type_match:
|
| 63 |
+
primary_shape = type_match.group(1).lower()
|
| 64 |
+
|
| 65 |
+
# Detect main conic names for each type
|
| 66 |
+
main_hyperbola_name = self._detect_main_conic_name(fact_expr, 'hyperbola')
|
| 67 |
+
main_ellipse_name = self._detect_main_conic_name(fact_expr, 'ellipse')
|
| 68 |
+
main_parabola_name = self._detect_main_conic_name(fact_expr, 'parabola')
|
| 69 |
+
main_circle_name = self._detect_main_conic_name(fact_expr, 'circle')
|
| 70 |
+
|
| 71 |
+
# Try to parse as different conic types, using main conic names
|
| 72 |
+
ellipse_params = self.parser.parse_ellipse(fact_expr)
|
| 73 |
+
hyperbola_params = self.parser.parse_hyperbola(fact_expr, main_hyperbola_name)
|
| 74 |
+
parabola_params = self.parser.parse_parabola(fact_expr)
|
| 75 |
+
circle_params = self.parser.parse_circle(fact_expr)
|
| 76 |
+
|
| 77 |
+
# Additional constraints
|
| 78 |
+
coords = self.parser.parse_coordinates(fact_expr)
|
| 79 |
+
eccentricity = self.parser.parse_eccentricity(fact_expr)
|
| 80 |
+
asymptote = self.parser.parse_asymptote_slope(fact_expr)
|
| 81 |
+
|
| 82 |
+
# Special case: moving circle locus (externally tangent to fixed circle, passes through a fixed point)
|
| 83 |
+
moving_circle = self._detect_moving_circle_locus(fact_expr, coords)
|
| 84 |
+
if moving_circle:
|
| 85 |
+
params_hyp = moving_circle
|
| 86 |
+
return self._process_hyperbola(problem, idx, params_hyp, coords, eccentricity=None, asymptote=None, verbose=verbose)
|
| 87 |
+
|
| 88 |
+
# Process based on primary shape (if determined) or first available
|
| 89 |
+
if primary_shape == 'hyperbola' and hyperbola_params:
|
| 90 |
+
result = self._process_hyperbola(problem, idx, hyperbola_params, coords, eccentricity, asymptote, verbose)
|
| 91 |
+
elif primary_shape == 'ellipse' and ellipse_params:
|
| 92 |
+
result = self._process_ellipse(problem, idx, ellipse_params, coords, eccentricity, verbose)
|
| 93 |
+
elif primary_shape == 'parabola' and parabola_params:
|
| 94 |
+
result = self._process_parabola(problem, idx, parabola_params, coords, verbose)
|
| 95 |
+
elif primary_shape == 'circle' and circle_params:
|
| 96 |
+
result = self._process_circle(problem, idx, circle_params, coords, verbose)
|
| 97 |
+
# Fallback to order of detection, but prioritize hyperbola over ellipse
|
| 98 |
+
# (many problems have both, with hyperbola as the main subject)
|
| 99 |
+
elif hyperbola_params:
|
| 100 |
+
result = self._process_hyperbola(problem, idx, hyperbola_params, coords, eccentricity, asymptote, verbose)
|
| 101 |
+
elif ellipse_params:
|
| 102 |
+
result = self._process_ellipse(problem, idx, ellipse_params, coords, eccentricity, verbose)
|
| 103 |
+
elif parabola_params:
|
| 104 |
+
result = self._process_parabola(problem, idx, parabola_params, coords, verbose)
|
| 105 |
+
elif circle_params:
|
| 106 |
+
result = self._process_circle(problem, idx, circle_params, coords, verbose)
|
| 107 |
+
else:
|
| 108 |
+
result['error'] = 'Unsupported or unparseable expression'
|
| 109 |
+
return result
|
| 110 |
+
|
| 111 |
+
# Validation step
|
| 112 |
+
result = self._validate_result(result, problem)
|
| 113 |
+
return result
|
| 114 |
+
|
| 115 |
+
except Exception as e:
|
| 116 |
+
result['error'] = str(e)
|
| 117 |
+
return result
|
| 118 |
+
|
| 119 |
+
def _validate_result(self, result: Dict, problem: Dict) -> Dict:
|
| 120 |
+
"""
|
| 121 |
+
Rigorous validation following paper-quality standards.
|
| 122 |
+
Validates all explicit geometric constraints from the problem.
|
| 123 |
+
|
| 124 |
+
Validation includes:
|
| 125 |
+
- Parameter positivity (a, b, p, r > 0)
|
| 126 |
+
- Eccentricity matching (e_calc vs e_target)
|
| 127 |
+
- Asymptote slope matching (b/a vs target slope)
|
| 128 |
+
- Focus position verification (c² = a² ± b²)
|
| 129 |
+
- Point-on-curve verification for constrained points
|
| 130 |
+
- Directrix position verification (parabola)
|
| 131 |
+
"""
|
| 132 |
+
if not result.get('success'):
|
| 133 |
+
return result
|
| 134 |
+
|
| 135 |
+
conic_type = result.get('conic_type')
|
| 136 |
+
fact_expr = result.get('fact_expr', problem.get('fact_expressions', ''))
|
| 137 |
+
coords = result.get('coords', {})
|
| 138 |
+
reasons = []
|
| 139 |
+
|
| 140 |
+
# Tolerance settings (paper-quality)
|
| 141 |
+
tol_point = 3e-2 # Point on curve tolerance
|
| 142 |
+
tol_param = 0.05 # Parameter matching tolerance (e, slope)
|
| 143 |
+
tol_focus = 0.05 # Focus position tolerance
|
| 144 |
+
|
| 145 |
+
# Dynamically detect the main conic name from fact_expr
|
| 146 |
+
main_conic = self._detect_main_conic_name(fact_expr, conic_type)
|
| 147 |
+
|
| 148 |
+
# Get only points that are explicitly on the MAIN conic
|
| 149 |
+
points_on_main = self._points_on_main_conic(fact_expr, coords, main_conic)
|
| 150 |
+
|
| 151 |
+
# Helper: extract focus coordinates from fact_expr
|
| 152 |
+
def get_focus_coords() -> List[Tuple[float, float]]:
|
| 153 |
+
"""Extract focus point coordinates."""
|
| 154 |
+
foci = []
|
| 155 |
+
for name, coord in coords.items():
|
| 156 |
+
# Check if this point is declared as a focus
|
| 157 |
+
if re.search(rf'Focus\s*\(\s*{main_conic}\s*\)\s*=\s*\{{\s*{name}', fact_expr) or \
|
| 158 |
+
re.search(rf'Focus\s*\(\s*{main_conic}\s*\)\s*=\s*{name}', fact_expr) or \
|
| 159 |
+
(name in ['F', 'F1', 'F2'] and re.search(rf'Focus\s*\(\s*{main_conic}\s*\)', fact_expr)):
|
| 160 |
+
foci.append(coord)
|
| 161 |
+
return foci
|
| 162 |
+
|
| 163 |
+
# Helper: check if point is on curve constraint
|
| 164 |
+
def has_point_constraint(name: str) -> bool:
|
| 165 |
+
return name in points_on_main
|
| 166 |
+
|
| 167 |
+
if conic_type == 'ellipse':
|
| 168 |
+
params = result.get('params', {})
|
| 169 |
+
if 'a' not in params or 'b' not in params:
|
| 170 |
+
return result # Skip validation if params incomplete
|
| 171 |
+
a = params['a']
|
| 172 |
+
b = params['b']
|
| 173 |
+
|
| 174 |
+
# 1. Parameter positivity
|
| 175 |
+
if a <= 0 or b <= 0:
|
| 176 |
+
reasons.append('ellipse_nonpositive_axes')
|
| 177 |
+
|
| 178 |
+
# 2. Eccentricity verification
|
| 179 |
+
ecc_target = self.parser.parse_eccentricity(fact_expr)
|
| 180 |
+
if ecc_target and 0 < ecc_target < 1:
|
| 181 |
+
a_major, b_minor = max(a, b), min(a, b)
|
| 182 |
+
ecc_calc = np.sqrt(1 - (b_minor / a_major)**2)
|
| 183 |
+
if abs(ecc_calc - ecc_target) > tol_param:
|
| 184 |
+
reasons.append('ellipse_ecc_mismatch')
|
| 185 |
+
|
| 186 |
+
# 3. Focus position verification (c² = a² - b² for ellipse)
|
| 187 |
+
foci = get_focus_coords()
|
| 188 |
+
if foci:
|
| 189 |
+
a_major, b_minor = max(a, b), min(a, b)
|
| 190 |
+
c_calc = np.sqrt(max(0, a_major**2 - b_minor**2))
|
| 191 |
+
for fx, fy in foci:
|
| 192 |
+
# Focus should be at (±c, 0) or (0, ±c) from center
|
| 193 |
+
c_given = np.sqrt(fx**2 + fy**2) # Assuming center at origin
|
| 194 |
+
if abs(c_calc - c_given) > tol_focus:
|
| 195 |
+
reasons.append('ellipse_focus_mismatch')
|
| 196 |
+
break
|
| 197 |
+
|
| 198 |
+
# 4. Point-on-curve verification
|
| 199 |
+
for name, (px, py) in coords.items():
|
| 200 |
+
if has_point_constraint(name):
|
| 201 |
+
major_axis = params.get('major_axis', 'x')
|
| 202 |
+
if major_axis == 'x':
|
| 203 |
+
val = (px**2) / (a**2) + (py**2) / (b**2) - 1
|
| 204 |
+
else:
|
| 205 |
+
val = (px**2) / (b**2) + (py**2) / (a**2) - 1
|
| 206 |
+
if abs(val) > tol_point:
|
| 207 |
+
reasons.append('ellipse_point_off_curve')
|
| 208 |
+
break
|
| 209 |
+
|
| 210 |
+
elif conic_type == 'hyperbola':
|
| 211 |
+
params = result.get('params', {})
|
| 212 |
+
if 'a' not in params or 'b' not in params:
|
| 213 |
+
return result # Skip validation if params incomplete
|
| 214 |
+
a = params['a']
|
| 215 |
+
b = params['b']
|
| 216 |
+
orientation = params.get('orientation', 'horizontal')
|
| 217 |
+
|
| 218 |
+
# 1. Parameter positivity
|
| 219 |
+
if a <= 0 or b <= 0:
|
| 220 |
+
reasons.append('hyperbola_nonpositive_axes')
|
| 221 |
+
|
| 222 |
+
# 2. Asymptote slope verification (b/a for horizontal)
|
| 223 |
+
asym = self.parser.parse_asymptote_slope(fact_expr)
|
| 224 |
+
if asym:
|
| 225 |
+
slope_calc = b / a if orientation == 'horizontal' else a / b
|
| 226 |
+
if abs(slope_calc - asym) > tol_param:
|
| 227 |
+
reasons.append('hyperbola_asymptote_mismatch')
|
| 228 |
+
|
| 229 |
+
# 3. Eccentricity verification (e = c/a = sqrt(1 + b²/a²))
|
| 230 |
+
ecc_target = self.parser.parse_eccentricity(fact_expr)
|
| 231 |
+
if ecc_target and ecc_target > 1:
|
| 232 |
+
ecc_calc = np.sqrt(1 + (b / a)**2)
|
| 233 |
+
if abs(ecc_calc - ecc_target) > tol_param:
|
| 234 |
+
reasons.append('hyperbola_ecc_mismatch')
|
| 235 |
+
|
| 236 |
+
# 4. Focus position verification (c² = a² + b² for hyperbola)
|
| 237 |
+
foci = get_focus_coords()
|
| 238 |
+
if foci:
|
| 239 |
+
c_calc = np.sqrt(a**2 + b**2)
|
| 240 |
+
for fx, fy in foci:
|
| 241 |
+
# Focus should be at (±c, 0) or (0, ±c) from center
|
| 242 |
+
c_given = np.sqrt(fx**2 + fy**2) # Assuming center at origin
|
| 243 |
+
if abs(c_calc - c_given) > tol_focus:
|
| 244 |
+
reasons.append('hyperbola_focus_mismatch')
|
| 245 |
+
break
|
| 246 |
+
|
| 247 |
+
# 5. Point-on-curve verification
|
| 248 |
+
for name, (px, py) in coords.items():
|
| 249 |
+
if has_point_constraint(name):
|
| 250 |
+
if orientation == 'vertical':
|
| 251 |
+
val = (py**2) / (a**2) - (px**2) / (b**2) - 1
|
| 252 |
+
else:
|
| 253 |
+
val = (px**2) / (a**2) - (py**2) / (b**2) - 1
|
| 254 |
+
if abs(val) > tol_point:
|
| 255 |
+
reasons.append('hyperbola_point_off_curve')
|
| 256 |
+
break
|
| 257 |
+
|
| 258 |
+
elif conic_type == 'parabola':
|
| 259 |
+
params = result.get('params', {})
|
| 260 |
+
p = params.get('p', 0)
|
| 261 |
+
direction = params.get('direction', 'right')
|
| 262 |
+
|
| 263 |
+
# 1. Parameter positivity
|
| 264 |
+
if p <= 0:
|
| 265 |
+
reasons.append('parabola_nonpositive_p')
|
| 266 |
+
|
| 267 |
+
# 2. Focus position verification
|
| 268 |
+
# Focus at (p, 0) for y² = 4px (right-opening)
|
| 269 |
+
foci = get_focus_coords()
|
| 270 |
+
if foci:
|
| 271 |
+
for fx, fy in foci:
|
| 272 |
+
if direction == 'right':
|
| 273 |
+
focus_expected = (p, 0)
|
| 274 |
+
elif direction == 'left':
|
| 275 |
+
focus_expected = (-p, 0)
|
| 276 |
+
elif direction == 'up':
|
| 277 |
+
focus_expected = (0, p)
|
| 278 |
+
else: # down
|
| 279 |
+
focus_expected = (0, -p)
|
| 280 |
+
|
| 281 |
+
dist = np.sqrt((fx - focus_expected[0])**2 + (fy - focus_expected[1])**2)
|
| 282 |
+
if dist > tol_focus:
|
| 283 |
+
reasons.append('parabola_focus_mismatch')
|
| 284 |
+
break
|
| 285 |
+
|
| 286 |
+
# 3. Directrix verification (if specified)
|
| 287 |
+
# Directrix at x = -p for y² = 4px
|
| 288 |
+
directrix_match = re.search(r'Directrix\s*\(\s*\w+\s*\)\s*=\s*\(x\s*=\s*(-?\d+\.?\d*)\)', fact_expr)
|
| 289 |
+
if directrix_match:
|
| 290 |
+
directrix_given = float(directrix_match.group(1))
|
| 291 |
+
if direction == 'right':
|
| 292 |
+
directrix_expected = -p
|
| 293 |
+
elif direction == 'left':
|
| 294 |
+
directrix_expected = p
|
| 295 |
+
else:
|
| 296 |
+
directrix_expected = None # y-directrix for up/down
|
| 297 |
+
|
| 298 |
+
if directrix_expected is not None:
|
| 299 |
+
if abs(directrix_given - directrix_expected) > tol_focus:
|
| 300 |
+
reasons.append('parabola_directrix_mismatch')
|
| 301 |
+
|
| 302 |
+
# 4. Point-on-curve verification
|
| 303 |
+
for name, (px, py) in coords.items():
|
| 304 |
+
if has_point_constraint(name):
|
| 305 |
+
if direction == 'right':
|
| 306 |
+
val = py**2 - 4 * p * px
|
| 307 |
+
elif direction == 'left':
|
| 308 |
+
val = py**2 + 4 * p * px
|
| 309 |
+
elif direction == 'up':
|
| 310 |
+
val = px**2 - 4 * p * py
|
| 311 |
+
else:
|
| 312 |
+
val = px**2 + 4 * p * py
|
| 313 |
+
if abs(val) > tol_point:
|
| 314 |
+
reasons.append('parabola_point_off_curve')
|
| 315 |
+
break
|
| 316 |
+
|
| 317 |
+
elif conic_type == 'circle':
|
| 318 |
+
params = result.get('params', {})
|
| 319 |
+
r = params.get('radius', 0)
|
| 320 |
+
cx, cy = params.get('center', (0, 0))
|
| 321 |
+
|
| 322 |
+
# 1. Parameter positivity
|
| 323 |
+
if r <= 0:
|
| 324 |
+
reasons.append('circle_nonpositive_radius')
|
| 325 |
+
|
| 326 |
+
# 2. Center verification (if specified)
|
| 327 |
+
center_match = re.search(r'Center\s*\(\s*\w+\s*\)\s*=\s*\(([^,]+),\s*([^)]+)\)', fact_expr)
|
| 328 |
+
if center_match:
|
| 329 |
+
try:
|
| 330 |
+
cx_given = float(center_match.group(1))
|
| 331 |
+
cy_given = float(center_match.group(2))
|
| 332 |
+
if abs(cx - cx_given) > tol_focus or abs(cy - cy_given) > tol_focus:
|
| 333 |
+
reasons.append('circle_center_mismatch')
|
| 334 |
+
except:
|
| 335 |
+
pass
|
| 336 |
+
|
| 337 |
+
# 3. Radius verification (if specified)
|
| 338 |
+
radius_match = re.search(r'Radius\s*\(\s*\w+\s*\)\s*=\s*(\d+\.?\d*)', fact_expr)
|
| 339 |
+
if radius_match:
|
| 340 |
+
r_given = float(radius_match.group(1))
|
| 341 |
+
if abs(r - r_given) > tol_focus:
|
| 342 |
+
reasons.append('circle_radius_mismatch')
|
| 343 |
+
|
| 344 |
+
# 4. Point-on-curve verification
|
| 345 |
+
for name, (px, py) in coords.items():
|
| 346 |
+
if has_point_constraint(name):
|
| 347 |
+
val = (px - cx)**2 + (py - cy)**2 - r**2
|
| 348 |
+
if abs(val) > tol_point:
|
| 349 |
+
reasons.append('circle_point_off_curve')
|
| 350 |
+
break
|
| 351 |
+
|
| 352 |
+
if reasons:
|
| 353 |
+
result['success'] = False
|
| 354 |
+
result['error'] = 'validation: ' + ';'.join(reasons)
|
| 355 |
+
result['validation_reasons'] = reasons
|
| 356 |
+
return result
|
| 357 |
+
|
| 358 |
+
def _point_constraint_names(self, fact_expr: str, coords: Dict, conic_type: str = 'parabola') -> set:
|
| 359 |
+
"""
|
| 360 |
+
Collect point names that are explicitly constrained on the main curve.
|
| 361 |
+
Uses _detect_main_conic_name to find the actual conic variable name.
|
| 362 |
+
"""
|
| 363 |
+
main_conic = self._detect_main_conic_name(fact_expr, conic_type)
|
| 364 |
+
return self._points_on_main_conic(fact_expr, coords, main_conic)
|
| 365 |
+
|
| 366 |
+
def _detect_main_conic_name(self, fact_expr: str, conic_type: str) -> str:
|
| 367 |
+
"""
|
| 368 |
+
Detect the actual name of the main conic from fact_expr.
|
| 369 |
+
|
| 370 |
+
Patterns like 'G: Ellipse', 'C: Parabola', 'C: Hyperbola', etc.
|
| 371 |
+
Returns the variable name (e.g., 'G' or 'C').
|
| 372 |
+
"""
|
| 373 |
+
# Map conic_type to the type name in fact_expr
|
| 374 |
+
type_map = {
|
| 375 |
+
'ellipse': 'Ellipse',
|
| 376 |
+
'hyperbola': 'Hyperbola',
|
| 377 |
+
'parabola': 'Parabola',
|
| 378 |
+
'circle': 'Circle'
|
| 379 |
+
}
|
| 380 |
+
type_name = type_map.get(conic_type, '')
|
| 381 |
+
|
| 382 |
+
if type_name:
|
| 383 |
+
# Pattern: variable_name: TypeName (e.g., "G: Ellipse" or "C: Parabola")
|
| 384 |
+
pattern = rf'(\w+)\s*:\s*{type_name}'
|
| 385 |
+
match = re.search(pattern, fact_expr)
|
| 386 |
+
if match:
|
| 387 |
+
return match.group(1)
|
| 388 |
+
|
| 389 |
+
# Fallback to defaults
|
| 390 |
+
return 'C' if conic_type == 'circle' else 'G'
|
| 391 |
+
|
| 392 |
+
def _points_on_main_conic(self, fact_expr: str, coords: Dict, conic_name: str = 'G') -> set:
|
| 393 |
+
"""
|
| 394 |
+
Collect point names that are EXPLICITLY on the MAIN conic (e.g., G or C).
|
| 395 |
+
|
| 396 |
+
Includes:
|
| 397 |
+
- PointOnCurve(<name>, G) where G is the main conic
|
| 398 |
+
- Intersection(*, G) = {A, B} where G is the main conic
|
| 399 |
+
|
| 400 |
+
Excludes:
|
| 401 |
+
- PointOnCurve(<name>, H) where H is a line
|
| 402 |
+
- PointOnCurve(<name>, Asymptote(G)) - on asymptote, not curve
|
| 403 |
+
- PointOnCurve(<name>, Directrix(G)) - on directrix, not curve
|
| 404 |
+
- PointOnCurve(<name>, G1) where G1 is a different curve
|
| 405 |
+
- MidPoint constraints (midpoints of chords are not on the curve)
|
| 406 |
+
"""
|
| 407 |
+
names = set()
|
| 408 |
+
|
| 409 |
+
# Match PointOnCurve(name, G) exactly - second argument must be exactly the conic name
|
| 410 |
+
# Avoid matching things like Asymptote(G), Directrix(G), G1, etc.
|
| 411 |
+
for name in coords.keys():
|
| 412 |
+
# Pattern: PointOnCurve(name, G) - spaces allowed, second arg must be exactly conic_name
|
| 413 |
+
# Use word boundary to avoid matching G1 when looking for G
|
| 414 |
+
pattern = rf'PointOnCurve\(\s*{re.escape(name)}\s*,\s*{re.escape(conic_name)}\s*\)'
|
| 415 |
+
if re.search(pattern, fact_expr):
|
| 416 |
+
names.add(name)
|
| 417 |
+
|
| 418 |
+
# Match Intersection(*, G) = {A, B} or Intersection(G, *) = {A, B}
|
| 419 |
+
# Only if one of the arguments is exactly the main conic
|
| 420 |
+
inter_pattern = r'Intersection\(\s*([^,)]+)\s*,\s*([^)]+)\s*\)\s*=\s*\{([^}]+)\}'
|
| 421 |
+
for m in re.finditer(inter_pattern, fact_expr):
|
| 422 |
+
arg1 = m.group(1).strip()
|
| 423 |
+
arg2 = m.group(2).strip()
|
| 424 |
+
points_str = m.group(3)
|
| 425 |
+
|
| 426 |
+
# Check if either argument is exactly the main conic name
|
| 427 |
+
if arg1 == conic_name or arg2 == conic_name:
|
| 428 |
+
for p in points_str.split(','):
|
| 429 |
+
p = p.strip()
|
| 430 |
+
if p in coords:
|
| 431 |
+
names.add(p)
|
| 432 |
+
|
| 433 |
+
return names
|
| 434 |
+
|
| 435 |
+
def _detect_moving_circle_locus(self, fact_expr: str, coords: Dict) -> Optional[Dict]:
|
| 436 |
+
"""
|
| 437 |
+
Detect pattern: moving circle through fixed point A, externally tangent to fixed circle C.
|
| 438 |
+
If foci on x-axis, convert to hyperbola params: |PC| - |PA| = R -> 2a = R.
|
| 439 |
+
Returns hyperbola params dict or None.
|
| 440 |
+
"""
|
| 441 |
+
if "IsOutTangent" not in fact_expr:
|
| 442 |
+
return None
|
| 443 |
+
# Parse fixed circle C explicitly from its expression (two common orderings)
|
| 444 |
+
patterns = [
|
| 445 |
+
r'Expression\(C\)\s*=\s*\(y\^2\s*\+\s*\(x\s*([+-])\s*(\d+\.?\d*)\)\^2\s*=\s*(\d+\.?\d*)\)',
|
| 446 |
+
r'Expression\(C\)\s*=\s*\(\(x\s*([+-])\s*(\d+\.?\d*)\)\^2\s*\+\s*y\^2\s*=\s*(\d+\.?\d*)\)'
|
| 447 |
+
]
|
| 448 |
+
cx = cy = R = None
|
| 449 |
+
for pat in patterns:
|
| 450 |
+
m = re.search(pat, fact_expr)
|
| 451 |
+
if m:
|
| 452 |
+
sign = m.group(1)
|
| 453 |
+
val = float(m.group(2))
|
| 454 |
+
cx = -val if sign == '+' else val
|
| 455 |
+
cy = 0.0
|
| 456 |
+
R = np.sqrt(float(m.group(3)))
|
| 457 |
+
break
|
| 458 |
+
if R is None or R <= 0:
|
| 459 |
+
return None
|
| 460 |
+
# pick A if present, else first point
|
| 461 |
+
if 'A' in coords:
|
| 462 |
+
ax, ay = coords['A']
|
| 463 |
+
elif coords:
|
| 464 |
+
ax, ay = next(iter(coords.values()))
|
| 465 |
+
else:
|
| 466 |
+
return None
|
| 467 |
+
# Only handle foci on x-axis for now
|
| 468 |
+
if abs(ay) > 1e-6 or abs(cy) > 1e-6:
|
| 469 |
+
return None
|
| 470 |
+
c = abs(cx - ax) / 2
|
| 471 |
+
if c <= 0:
|
| 472 |
+
return None
|
| 473 |
+
a = R / 2
|
| 474 |
+
if a <= 0 or c <= a:
|
| 475 |
+
return None
|
| 476 |
+
b_sq = c * c - a * a
|
| 477 |
+
b = np.sqrt(b_sq)
|
| 478 |
+
return {'a': a, 'b': b}
|
| 479 |
+
|
| 480 |
+
def _process_ellipse(self, problem: Dict, idx: int, params: Dict,
|
| 481 |
+
coords: Dict, eccentricity: Optional[float], verbose: bool) -> Dict:
|
| 482 |
+
"""Process ellipse problem with SDF optimization."""
|
| 483 |
+
|
| 484 |
+
fact_expr = problem.get('fact_expressions', '')
|
| 485 |
+
point_names = self._point_constraint_names(fact_expr, coords, 'ellipse')
|
| 486 |
+
# Create SDF with initial parameters
|
| 487 |
+
center = torch.tensor([0.0, 0.0])
|
| 488 |
+
# Ensure params has 'a' and 'b' keys
|
| 489 |
+
if 'a' not in params or 'b' not in params:
|
| 490 |
+
return {
|
| 491 |
+
'index': idx,
|
| 492 |
+
'success': False,
|
| 493 |
+
'error': f"Ellipse params missing 'a' or 'b': {list(params.keys())}"
|
| 494 |
+
}
|
| 495 |
+
a = torch.tensor([params['a']])
|
| 496 |
+
b = torch.tensor([params['b']])
|
| 497 |
+
|
| 498 |
+
sdf = EllipseSDF(center, a, b)
|
| 499 |
+
|
| 500 |
+
# Check if we have explicit numeric coefficients (not symbolic)
|
| 501 |
+
has_explicit_coeffs = not params.get('symbolic', False) and not params.get('from_constraints', False)
|
| 502 |
+
|
| 503 |
+
# Only apply optimization if we don't have explicit coefficients
|
| 504 |
+
# or if constraints are compatible
|
| 505 |
+
should_optimize = False
|
| 506 |
+
constraints = []
|
| 507 |
+
weights = []
|
| 508 |
+
|
| 509 |
+
if not has_explicit_coeffs:
|
| 510 |
+
# If we have eccentricity constraint for ellipse (must be < 1)
|
| 511 |
+
if eccentricity and eccentricity < 1:
|
| 512 |
+
constraints.append(lambda: GeometricConstraints.eccentricity_ellipse(
|
| 513 |
+
sdf.a, sdf.b, eccentricity
|
| 514 |
+
))
|
| 515 |
+
weights.append(10.0)
|
| 516 |
+
should_optimize = True
|
| 517 |
+
|
| 518 |
+
# Collect positions for crowd penalty
|
| 519 |
+
all_positions = [sdf.center]
|
| 520 |
+
|
| 521 |
+
# Point on curve constraints
|
| 522 |
+
for name, (px, py) in coords.items():
|
| 523 |
+
if name in point_names and name not in ['F1', 'F2', 'F', 'O']:
|
| 524 |
+
point = torch.tensor([px, py])
|
| 525 |
+
constraints.append(lambda p=point: GeometricConstraints.point_on_curve(sdf, p))
|
| 526 |
+
weights.append(5.0)
|
| 527 |
+
should_optimize = True
|
| 528 |
+
all_positions.append(point)
|
| 529 |
+
|
| 530 |
+
# Crowd regularization (Paper Section 3.3, Equation 2)
|
| 531 |
+
# Prevents geometric elements from collapsing
|
| 532 |
+
if len(all_positions) > 1:
|
| 533 |
+
constraints.append(lambda pos=all_positions: GeometricConstraints.crowd_penalty(pos, min_dist=0.5))
|
| 534 |
+
weights.append(3.0) # λ_crowd = 3.0 (paper default)
|
| 535 |
+
|
| 536 |
+
# Positive constraints
|
| 537 |
+
constraints.append(lambda: GeometricConstraints.positive_constraint(sdf.a))
|
| 538 |
+
constraints.append(lambda: GeometricConstraints.positive_constraint(sdf.b))
|
| 539 |
+
weights.extend([1.0, 1.0])
|
| 540 |
+
|
| 541 |
+
# Optimize only if needed and constraints are valid
|
| 542 |
+
if should_optimize and len(constraints) > 2:
|
| 543 |
+
opt_result = self.optimizer.optimize(sdf, constraints, weights, verbose)
|
| 544 |
+
|
| 545 |
+
# Check if optimization produced valid result
|
| 546 |
+
with torch.no_grad():
|
| 547 |
+
a_opt = abs(sdf.a.item())
|
| 548 |
+
b_opt = abs(sdf.b.item())
|
| 549 |
+
|
| 550 |
+
# If optimization produced degenerate result, revert to original params
|
| 551 |
+
if b_opt < 0.1 or a_opt < 0.1:
|
| 552 |
+
sdf.a.data = torch.tensor([params['a']])
|
| 553 |
+
sdf.b.data = torch.tensor([params['b']])
|
| 554 |
+
opt_result = {'final_loss': 0.0, 'converged': True, 'note': 'reverted to explicit params'}
|
| 555 |
+
else:
|
| 556 |
+
opt_result = {'final_loss': 0.0, 'converged': True, 'note': 'using explicit params'}
|
| 557 |
+
|
| 558 |
+
# Extract final parameters
|
| 559 |
+
with torch.no_grad():
|
| 560 |
+
a_final = abs(sdf.a.item())
|
| 561 |
+
b_final = abs(sdf.b.item())
|
| 562 |
+
|
| 563 |
+
# Determine major axis based on original coefficients
|
| 564 |
+
major_axis = params.get('major_axis', 'x')
|
| 565 |
+
|
| 566 |
+
# Visualize
|
| 567 |
+
output_path = self.output_dir / 'ellipse' / f'problem_{idx:04d}.png'
|
| 568 |
+
self._visualize_ellipse(sdf, problem, params, output_path, major_axis)
|
| 569 |
+
|
| 570 |
+
return {
|
| 571 |
+
'index': idx,
|
| 572 |
+
'success': True,
|
| 573 |
+
'conic_type': 'ellipse',
|
| 574 |
+
'error': None,
|
| 575 |
+
'params': {
|
| 576 |
+
'a': a_final,
|
| 577 |
+
'b': b_final,
|
| 578 |
+
'major_axis': major_axis,
|
| 579 |
+
'x_coef': params['x_coef'],
|
| 580 |
+
'y_coef': params['y_coef']
|
| 581 |
+
},
|
| 582 |
+
'optimization': opt_result,
|
| 583 |
+
'output_path': str(output_path),
|
| 584 |
+
'answer': problem.get('answer_expressions', ''),
|
| 585 |
+
'fact_expr': fact_expr,
|
| 586 |
+
'coords': coords
|
| 587 |
+
}
|
| 588 |
+
|
| 589 |
+
def _process_hyperbola(self, problem: Dict, idx: int, params: Dict,
|
| 590 |
+
coords: Dict, eccentricity: Optional[float],
|
| 591 |
+
asymptote: Optional[float], verbose: bool) -> Dict:
|
| 592 |
+
"""Process hyperbola problem with SDF optimization."""
|
| 593 |
+
|
| 594 |
+
fact_expr = problem.get('fact_expressions', '')
|
| 595 |
+
point_names = self._point_constraint_names(fact_expr, coords, 'hyperbola')
|
| 596 |
+
|
| 597 |
+
# Check if foci come from an ellipse (Focus(G) = Focus(H) where H is Ellipse)
|
| 598 |
+
c_from_ellipse = None
|
| 599 |
+
if 'Focus(G) = Focus(H)' in fact_expr or 'Focus(H) = Focus(G)' in fact_expr:
|
| 600 |
+
# Find the ellipse expression
|
| 601 |
+
ellipse_match = re.search(r'Expression\(\w+\)\s*=\s*\(x\^2/(\d+)\s*\+\s*y\^2/(\d+)\s*=\s*1\)', fact_expr)
|
| 602 |
+
if ellipse_match:
|
| 603 |
+
x_coef = float(ellipse_match.group(1))
|
| 604 |
+
y_coef = float(ellipse_match.group(2))
|
| 605 |
+
a_ell = np.sqrt(max(x_coef, y_coef))
|
| 606 |
+
b_ell = np.sqrt(min(x_coef, y_coef))
|
| 607 |
+
c_from_ellipse = np.sqrt(a_ell**2 - b_ell**2)
|
| 608 |
+
|
| 609 |
+
# If we have eccentricity and c from ellipse, calculate a and b directly
|
| 610 |
+
if eccentricity and eccentricity > 1 and c_from_ellipse:
|
| 611 |
+
# For hyperbola: e = c/a, so a = c/e
|
| 612 |
+
a_val = c_from_ellipse / eccentricity
|
| 613 |
+
# c² = a² + b², so b² = c² - a²
|
| 614 |
+
b_squared = c_from_ellipse**2 - a_val**2
|
| 615 |
+
if b_squared > 0:
|
| 616 |
+
b_val = np.sqrt(b_squared)
|
| 617 |
+
params['a'] = a_val
|
| 618 |
+
params['b'] = b_val
|
| 619 |
+
params['a_squared'] = a_val**2
|
| 620 |
+
params['b_squared'] = b_squared
|
| 621 |
+
|
| 622 |
+
center = torch.tensor([0.0, 0.0])
|
| 623 |
+
# Ensure params has 'a' and 'b' keys
|
| 624 |
+
if 'a' not in params or 'b' not in params:
|
| 625 |
+
return {
|
| 626 |
+
'index': idx,
|
| 627 |
+
'success': False,
|
| 628 |
+
'error': f"Hyperbola params missing 'a' or 'b': {list(params.keys())}"
|
| 629 |
+
}
|
| 630 |
+
a = torch.tensor([params['a']])
|
| 631 |
+
b = torch.tensor([params['b']])
|
| 632 |
+
|
| 633 |
+
sdf = HyperbolaSDF(center, a, b)
|
| 634 |
+
|
| 635 |
+
# Check if we already have explicit params from the above calculation
|
| 636 |
+
has_explicit_params = c_from_ellipse is not None and eccentricity and eccentricity > 1
|
| 637 |
+
|
| 638 |
+
constraints = []
|
| 639 |
+
weights = []
|
| 640 |
+
|
| 641 |
+
if not has_explicit_params:
|
| 642 |
+
# Collect positions for crowd penalty
|
| 643 |
+
all_positions = [sdf.center]
|
| 644 |
+
|
| 645 |
+
# Eccentricity constraint
|
| 646 |
+
if eccentricity and eccentricity > 1:
|
| 647 |
+
constraints.append(lambda: GeometricConstraints.eccentricity_hyperbola(
|
| 648 |
+
sdf.a, sdf.b, eccentricity
|
| 649 |
+
))
|
| 650 |
+
weights.append(10.0)
|
| 651 |
+
|
| 652 |
+
# Asymptote slope constraint
|
| 653 |
+
if asymptote:
|
| 654 |
+
constraints.append(lambda: GeometricConstraints.asymptote_slope(
|
| 655 |
+
sdf.a, sdf.b, asymptote
|
| 656 |
+
))
|
| 657 |
+
weights.append(10.0)
|
| 658 |
+
|
| 659 |
+
# Focus constraint from coordinates
|
| 660 |
+
focus_coords = [(n, c) for n, c in coords.items() if 'F' in n]
|
| 661 |
+
if len(focus_coords) >= 2:
|
| 662 |
+
f1 = focus_coords[0][1]
|
| 663 |
+
f2 = focus_coords[1][1]
|
| 664 |
+
c_target = abs(f1[0] - f2[0]) / 2 if f1[1] == f2[1] == 0 else None
|
| 665 |
+
if c_target:
|
| 666 |
+
constraints.append(lambda ct=c_target: GeometricConstraints.focus_constraint_hyperbola(
|
| 667 |
+
sdf.a, sdf.b, ct
|
| 668 |
+
))
|
| 669 |
+
weights.append(10.0)
|
| 670 |
+
|
| 671 |
+
# Add extra points to crowd penalty
|
| 672 |
+
for name, (px, py) in coords.items():
|
| 673 |
+
if name in point_names and name not in ['F1', 'F2', 'F', 'O']:
|
| 674 |
+
all_positions.append(torch.tensor([px, py]))
|
| 675 |
+
|
| 676 |
+
# Crowd regularization (Paper Section 3.3, Equation 2)
|
| 677 |
+
if len(all_positions) > 1:
|
| 678 |
+
constraints.append(lambda pos=all_positions: GeometricConstraints.crowd_penalty(pos, min_dist=0.5))
|
| 679 |
+
weights.append(3.0) # λ_crowd = 3.0
|
| 680 |
+
|
| 681 |
+
# Positive constraints
|
| 682 |
+
constraints.append(lambda: GeometricConstraints.positive_constraint(sdf.a))
|
| 683 |
+
constraints.append(lambda: GeometricConstraints.positive_constraint(sdf.b))
|
| 684 |
+
weights.extend([1.0, 1.0])
|
| 685 |
+
|
| 686 |
+
if len(constraints) > 2:
|
| 687 |
+
opt_result = self.optimizer.optimize(sdf, constraints, weights, verbose)
|
| 688 |
+
else:
|
| 689 |
+
opt_result = {'final_loss': 0.0, 'converged': True, 'note': 'using explicit params'}
|
| 690 |
+
|
| 691 |
+
with torch.no_grad():
|
| 692 |
+
a_final = abs(sdf.a.item())
|
| 693 |
+
b_final = abs(sdf.b.item())
|
| 694 |
+
|
| 695 |
+
output_path = self.output_dir / 'hyperbola' / f'problem_{idx:04d}.png'
|
| 696 |
+
self._visualize_hyperbola(sdf, problem, params, output_path)
|
| 697 |
+
|
| 698 |
+
return {
|
| 699 |
+
'index': idx,
|
| 700 |
+
'success': True,
|
| 701 |
+
'conic_type': 'hyperbola',
|
| 702 |
+
'error': None,
|
| 703 |
+
'params': {
|
| 704 |
+
'a': a_final,
|
| 705 |
+
'b': b_final,
|
| 706 |
+
'orientation': params.get('orientation', 'horizontal')
|
| 707 |
+
},
|
| 708 |
+
'optimization': opt_result,
|
| 709 |
+
'output_path': str(output_path),
|
| 710 |
+
'answer': problem.get('answer_expressions', ''),
|
| 711 |
+
'fact_expr': fact_expr,
|
| 712 |
+
'coords': coords
|
| 713 |
+
}
|
| 714 |
+
|
| 715 |
+
def _process_parabola(self, problem: Dict, idx: int, params: Dict,
|
| 716 |
+
coords: Dict, verbose: bool) -> Dict:
|
| 717 |
+
"""Process parabola problem with SDF optimization."""
|
| 718 |
+
|
| 719 |
+
fact_expr = problem.get('fact_expressions', '')
|
| 720 |
+
point_names = self._point_constraint_names(fact_expr, coords, 'parabola')
|
| 721 |
+
vertex = torch.tensor([0.0, 0.0])
|
| 722 |
+
p = torch.tensor([params['p']])
|
| 723 |
+
direction = params.get('direction', 'right')
|
| 724 |
+
|
| 725 |
+
sdf = ParabolaSDF(vertex, p, direction)
|
| 726 |
+
# Keep vertex fixed at origin to avoid unintended translation during optimization
|
| 727 |
+
sdf.vertex.requires_grad_(False)
|
| 728 |
+
|
| 729 |
+
# 如果题目给出了显式的抛物线方程(非符号/约束推导),直接使用,不做优化
|
| 730 |
+
has_explicit_params = not params.get('symbolic', False) and not params.get('from_constraints', False)
|
| 731 |
+
|
| 732 |
+
if has_explicit_params:
|
| 733 |
+
opt_result = {'final_loss': 0.0, 'converged': True, 'note': 'using explicit params'}
|
| 734 |
+
else:
|
| 735 |
+
# Collect positions for crowd penalty
|
| 736 |
+
all_positions = [sdf.vertex]
|
| 737 |
+
|
| 738 |
+
constraints = [
|
| 739 |
+
lambda: GeometricConstraints.positive_constraint(sdf.p)
|
| 740 |
+
]
|
| 741 |
+
weights = [1.0]
|
| 742 |
+
|
| 743 |
+
# Point on curve constraints
|
| 744 |
+
for name, (px, py) in coords.items():
|
| 745 |
+
if name in point_names and name not in ['F', 'O']:
|
| 746 |
+
point = torch.tensor([px, py])
|
| 747 |
+
constraints.append(lambda pt=point: GeometricConstraints.point_on_curve(sdf, pt))
|
| 748 |
+
weights.append(5.0)
|
| 749 |
+
all_positions.append(point)
|
| 750 |
+
|
| 751 |
+
# Crowd regularization (Paper Section 3.3, Equation 2)
|
| 752 |
+
if len(all_positions) > 1:
|
| 753 |
+
constraints.append(lambda pos=all_positions: GeometricConstraints.crowd_penalty(pos, min_dist=0.5))
|
| 754 |
+
weights.append(3.0) # λ_crowd = 3.0
|
| 755 |
+
|
| 756 |
+
if len(constraints) > 1:
|
| 757 |
+
opt_result = self.optimizer.optimize(sdf, constraints, weights, verbose)
|
| 758 |
+
else:
|
| 759 |
+
opt_result = {'final_loss': 0.0, 'converged': True}
|
| 760 |
+
|
| 761 |
+
with torch.no_grad():
|
| 762 |
+
p_final = abs(sdf.p.item())
|
| 763 |
+
|
| 764 |
+
output_path = self.output_dir / 'parabola' / f'problem_{idx:04d}.png'
|
| 765 |
+
self._visualize_parabola(sdf, problem, params, output_path)
|
| 766 |
+
|
| 767 |
+
return {
|
| 768 |
+
'index': idx,
|
| 769 |
+
'success': True,
|
| 770 |
+
'conic_type': 'parabola',
|
| 771 |
+
'error': None,
|
| 772 |
+
'params': {'p': p_final, 'direction': direction},
|
| 773 |
+
'optimization': opt_result,
|
| 774 |
+
'output_path': str(output_path),
|
| 775 |
+
'answer': problem.get('answer_expressions', ''),
|
| 776 |
+
'fact_expr': fact_expr,
|
| 777 |
+
'coords': coords
|
| 778 |
+
}
|
| 779 |
+
|
| 780 |
+
def _process_circle(self, problem: Dict, idx: int, params: Dict,
|
| 781 |
+
coords: Dict, verbose: bool) -> Dict:
|
| 782 |
+
"""Process circle problem with SDF."""
|
| 783 |
+
|
| 784 |
+
fact_expr = problem.get('fact_expressions', '')
|
| 785 |
+
point_names = self._point_constraint_names(fact_expr, coords, 'circle')
|
| 786 |
+
# Get center and radius
|
| 787 |
+
if params.get('from_diameter'):
|
| 788 |
+
# Compute circle from diameter endpoints
|
| 789 |
+
# Pattern: IsDiameter(LineSegmentOf(A, B), C) where C is the circle
|
| 790 |
+
fact_expr = problem.get('fact_expressions', '')
|
| 791 |
+
coords = self.parser.parse_coordinates(fact_expr)
|
| 792 |
+
|
| 793 |
+
# Find the two points that form the diameter
|
| 794 |
+
diameter_match = re.search(r'IsDiameter\(LineSegmentOf\((\w+),\s*(\w+)\)', fact_expr)
|
| 795 |
+
if diameter_match:
|
| 796 |
+
pt1_name = diameter_match.group(1)
|
| 797 |
+
pt2_name = diameter_match.group(2)
|
| 798 |
+
if pt1_name in coords and pt2_name in coords:
|
| 799 |
+
x1, y1 = coords[pt1_name]
|
| 800 |
+
x2, y2 = coords[pt2_name]
|
| 801 |
+
# Center = midpoint, radius = half of distance
|
| 802 |
+
params['center'] = ((x1 + x2) / 2, (y1 + y2) / 2)
|
| 803 |
+
params['radius'] = np.sqrt((x2 - x1)**2 + (y2 - y1)**2) / 2
|
| 804 |
+
else:
|
| 805 |
+
result = {
|
| 806 |
+
'index': idx,
|
| 807 |
+
'success': False,
|
| 808 |
+
'error': 'Circle from diameter: missing point coordinates'
|
| 809 |
+
}
|
| 810 |
+
return result
|
| 811 |
+
else:
|
| 812 |
+
result = {
|
| 813 |
+
'index': idx,
|
| 814 |
+
'success': False,
|
| 815 |
+
'error': 'Circle from diameter: cannot parse diameter pattern'
|
| 816 |
+
}
|
| 817 |
+
return result
|
| 818 |
+
|
| 819 |
+
center = torch.tensor(list(params.get('center', (0.0, 0.0))))
|
| 820 |
+
radius = torch.tensor([params.get('radius', 1.0)])
|
| 821 |
+
|
| 822 |
+
sdf = CircleSDF(center, radius)
|
| 823 |
+
|
| 824 |
+
# No optimization needed for explicit circles
|
| 825 |
+
opt_result = {'final_loss': 0.0, 'converged': True}
|
| 826 |
+
|
| 827 |
+
with torch.no_grad():
|
| 828 |
+
cx = sdf.center[0].item()
|
| 829 |
+
cy = sdf.center[1].item()
|
| 830 |
+
r = abs(sdf.radius.item())
|
| 831 |
+
|
| 832 |
+
output_path = self.output_dir / 'circle' / f'problem_{idx:04d}.png'
|
| 833 |
+
self._visualize_circle(sdf, problem, params, output_path)
|
| 834 |
+
|
| 835 |
+
return {
|
| 836 |
+
'index': idx,
|
| 837 |
+
'success': True,
|
| 838 |
+
'conic_type': 'circle',
|
| 839 |
+
'error': None,
|
| 840 |
+
'params': {'center': (cx, cy), 'radius': r},
|
| 841 |
+
'optimization': opt_result,
|
| 842 |
+
'output_path': str(output_path),
|
| 843 |
+
'answer': problem.get('answer_expressions', ''),
|
| 844 |
+
'fact_expr': fact_expr,
|
| 845 |
+
'coords': {k:v for k,v in coords.items() if k in point_names}
|
| 846 |
+
}
|
| 847 |
+
|
| 848 |
+
def _setup_gaokao_axes(self, ax, xlim, ylim):
|
| 849 |
+
"""Setup coordinate axes in Chinese Gaokao analytic geometry style."""
|
| 850 |
+
ax.set_facecolor('white')
|
| 851 |
+
for spine in ax.spines.values():
|
| 852 |
+
spine.set_visible(False)
|
| 853 |
+
ax.set_xticks([])
|
| 854 |
+
ax.set_yticks([])
|
| 855 |
+
|
| 856 |
+
# Draw arrow axes through origin
|
| 857 |
+
arrow_kw = dict(arrowstyle='->', color='black', lw=1.0)
|
| 858 |
+
ax.annotate('', xy=(xlim[1], 0), xytext=(xlim[0], 0), arrowprops=arrow_kw)
|
| 859 |
+
ax.annotate('', xy=(0, ylim[1]), xytext=(0, ylim[0]), arrowprops=arrow_kw)
|
| 860 |
+
|
| 861 |
+
# Label offset proportional to plot range
|
| 862 |
+
r = max(xlim[1] - xlim[0], ylim[1] - ylim[0])
|
| 863 |
+
d = r * 0.025
|
| 864 |
+
|
| 865 |
+
ax.text(xlim[1] - d, -d * 2, '$x$', fontsize=14, ha='right', va='top')
|
| 866 |
+
ax.text(d * 0.5, ylim[1] - d * 0.5, '$y$', fontsize=14, ha='left', va='top')
|
| 867 |
+
ax.text(-d * 1.5, -d * 2, '$O$', fontsize=14, ha='right', va='top')
|
| 868 |
+
|
| 869 |
+
ax.set_xlim(xlim)
|
| 870 |
+
ax.set_ylim(ylim)
|
| 871 |
+
ax.set_aspect('equal')
|
| 872 |
+
|
| 873 |
+
def _visualize_circle(self, sdf: CircleSDF, problem: Dict, params: Dict,
|
| 874 |
+
output_path: Path):
|
| 875 |
+
"""Visualize circle in Gaokao style."""
|
| 876 |
+
|
| 877 |
+
with torch.no_grad():
|
| 878 |
+
cx = sdf.center[0].item()
|
| 879 |
+
cy = sdf.center[1].item()
|
| 880 |
+
r = abs(sdf.radius.item())
|
| 881 |
+
|
| 882 |
+
margin = r + 1.5
|
| 883 |
+
xlim = (min(cx - margin, -0.5), max(cx + margin, 0.5))
|
| 884 |
+
ylim = (min(cy - margin, -0.5), max(cy + margin, 0.5))
|
| 885 |
+
|
| 886 |
+
fig, ax = plt.subplots(figsize=(8, 8))
|
| 887 |
+
fig.patch.set_facecolor('white')
|
| 888 |
+
|
| 889 |
+
renderer = SDFRenderer(resolution=400, xlim=xlim, ylim=ylim)
|
| 890 |
+
renderer.render_curve_only(sdf, ax, color='black', linewidth=1.5)
|
| 891 |
+
|
| 892 |
+
# Mark center
|
| 893 |
+
d = max(xlim[1] - xlim[0], ylim[1] - ylim[0]) * 0.02
|
| 894 |
+
ax.plot(cx, cy, 'k.', markersize=4)
|
| 895 |
+
ax.text(cx + d, cy + d * 2, '$C$', fontsize=13, ha='left', va='bottom')
|
| 896 |
+
|
| 897 |
+
# Additional points
|
| 898 |
+
for name, (px, py) in params.get('coords', {}).items():
|
| 899 |
+
ax.plot(px, py, 'k.', markersize=4)
|
| 900 |
+
ax.text(px + d, py + d * 2, f'${name}$', fontsize=13, ha='left', va='bottom')
|
| 901 |
+
|
| 902 |
+
self._setup_gaokao_axes(ax, xlim, ylim)
|
| 903 |
+
|
| 904 |
+
output_path.parent.mkdir(parents=True, exist_ok=True)
|
| 905 |
+
plt.savefig(output_path, dpi=150, bbox_inches='tight', facecolor='white')
|
| 906 |
+
plt.close(fig)
|
| 907 |
+
|
| 908 |
+
def _wrap_text(self, text: str, width: int = 50) -> str:
|
| 909 |
+
"""Wrap text to specified width."""
|
| 910 |
+
words = text.split()
|
| 911 |
+
lines = []
|
| 912 |
+
current_line = []
|
| 913 |
+
current_len = 0
|
| 914 |
+
|
| 915 |
+
for word in words:
|
| 916 |
+
if current_len + len(word) + 1 <= width:
|
| 917 |
+
current_line.append(word)
|
| 918 |
+
current_len += len(word) + 1
|
| 919 |
+
else:
|
| 920 |
+
if current_line:
|
| 921 |
+
lines.append(' '.join(current_line))
|
| 922 |
+
current_line = [word]
|
| 923 |
+
current_len = len(word)
|
| 924 |
+
|
| 925 |
+
if current_line:
|
| 926 |
+
lines.append(' '.join(current_line))
|
| 927 |
+
|
| 928 |
+
return '\n'.join(lines)
|
| 929 |
+
|
| 930 |
+
def _visualize_ellipse(self, sdf: EllipseSDF, problem: Dict, params: Dict,
|
| 931 |
+
output_path: Path, major_axis: str):
|
| 932 |
+
"""Visualize ellipse in Gaokao style."""
|
| 933 |
+
|
| 934 |
+
with torch.no_grad():
|
| 935 |
+
a = abs(sdf.a.item())
|
| 936 |
+
b = abs(sdf.b.item())
|
| 937 |
+
|
| 938 |
+
b_viz = max(b, 0.1)
|
| 939 |
+
fact_expr = problem.get('fact_expressions', '')
|
| 940 |
+
|
| 941 |
+
# Check if there's also a hyperbola in the problem
|
| 942 |
+
hyperbola_params = self.parser.parse_hyperbola(fact_expr)
|
| 943 |
+
has_hyperbola = hyperbola_params is not None and 'a' in hyperbola_params and 'b' in hyperbola_params
|
| 944 |
+
|
| 945 |
+
if has_hyperbola:
|
| 946 |
+
a_hyp = hyperbola_params['a']
|
| 947 |
+
b_hyp = hyperbola_params['b']
|
| 948 |
+
max_dim = max(a, b_viz, a_hyp, b_hyp) * 1.8 + 1
|
| 949 |
+
else:
|
| 950 |
+
max_dim = max(a, b_viz) * 1.5 + 0.5
|
| 951 |
+
|
| 952 |
+
xlim = (-max_dim, max_dim)
|
| 953 |
+
ylim = (-max_dim, max_dim)
|
| 954 |
+
|
| 955 |
+
fig, ax = plt.subplots(figsize=(8, 8))
|
| 956 |
+
fig.patch.set_facecolor('white')
|
| 957 |
+
|
| 958 |
+
renderer = SDFRenderer(resolution=500, xlim=xlim, ylim=ylim)
|
| 959 |
+
renderer.render_curve_only(sdf, ax, color='black', linewidth=1.5)
|
| 960 |
+
|
| 961 |
+
# Draw secondary hyperbola if present
|
| 962 |
+
if has_hyperbola:
|
| 963 |
+
center = torch.tensor([0.0, 0.0])
|
| 964 |
+
a_hyp_t = torch.tensor([hyperbola_params['a']])
|
| 965 |
+
b_hyp_t = torch.tensor([hyperbola_params['b']])
|
| 966 |
+
hyp_sdf = HyperbolaSDF(center, a_hyp_t, b_hyp_t)
|
| 967 |
+
renderer.render_curve_only(hyp_sdf, ax, color='black', linewidth=1.5)
|
| 968 |
+
|
| 969 |
+
# Asymptotes
|
| 970 |
+
slope_hyp = hyperbola_params['b'] / hyperbola_params['a']
|
| 971 |
+
x_asym = np.linspace(-max_dim, max_dim, 100)
|
| 972 |
+
ax.plot(x_asym, slope_hyp * x_asym, 'k--', linewidth=0.8, alpha=0.5)
|
| 973 |
+
ax.plot(x_asym, -slope_hyp * x_asym, 'k--', linewidth=0.8, alpha=0.5)
|
| 974 |
+
|
| 975 |
+
# Foci
|
| 976 |
+
c = np.sqrt(abs(a**2 - b**2)) if a > b else np.sqrt(abs(b**2 - a**2))
|
| 977 |
+
d = max_dim * 0.025
|
| 978 |
+
if major_axis == 'x':
|
| 979 |
+
ax.plot(c, 0, 'k.', markersize=5)
|
| 980 |
+
ax.plot(-c, 0, 'k.', markersize=5)
|
| 981 |
+
ax.text(-c, d * 2, '$F_1$', fontsize=13, ha='center', va='bottom')
|
| 982 |
+
ax.text(c, d * 2, '$F_2$', fontsize=13, ha='center', va='bottom')
|
| 983 |
+
else:
|
| 984 |
+
ax.plot(0, c, 'k.', markersize=5)
|
| 985 |
+
ax.plot(0, -c, 'k.', markersize=5)
|
| 986 |
+
ax.text(d * 2, -c, '$F_1$', fontsize=13, ha='left', va='center')
|
| 987 |
+
ax.text(d * 2, c, '$F_2$', fontsize=13, ha='left', va='center')
|
| 988 |
+
|
| 989 |
+
# Additional points
|
| 990 |
+
coords = self.parser.parse_coordinates(problem.get('fact_expressions', ''))
|
| 991 |
+
for name, (px, py) in coords.items():
|
| 992 |
+
if name not in ['F1', 'F2', 'F', 'O']:
|
| 993 |
+
ax.plot(px, py, 'k.', markersize=5)
|
| 994 |
+
ax.text(px + d, py + d * 2, f'${name}$', fontsize=13)
|
| 995 |
+
|
| 996 |
+
self._setup_gaokao_axes(ax, xlim, ylim)
|
| 997 |
+
|
| 998 |
+
plt.savefig(output_path, dpi=150, bbox_inches='tight', facecolor='white')
|
| 999 |
+
plt.close(fig)
|
| 1000 |
+
|
| 1001 |
+
def _visualize_hyperbola(self, sdf: HyperbolaSDF, problem: Dict, params: Dict,
|
| 1002 |
+
output_path: Path):
|
| 1003 |
+
"""Visualize hyperbola in Gaokao style."""
|
| 1004 |
+
|
| 1005 |
+
with torch.no_grad():
|
| 1006 |
+
a = abs(sdf.a.item())
|
| 1007 |
+
b = abs(sdf.b.item())
|
| 1008 |
+
|
| 1009 |
+
fact_expr = problem.get('fact_expressions', '')
|
| 1010 |
+
|
| 1011 |
+
# Check if there are other shapes in the problem
|
| 1012 |
+
ellipse_params = self.parser.parse_ellipse(fact_expr)
|
| 1013 |
+
line_params = self.parser.parse_line(fact_expr)
|
| 1014 |
+
has_ellipse = ellipse_params is not None and 'a' in ellipse_params and 'b' in ellipse_params
|
| 1015 |
+
has_line = line_params is not None and (line_params.get('a') is not None or line_params.get('slope') is not None)
|
| 1016 |
+
|
| 1017 |
+
# If line has slope but no explicit equation, try to construct it
|
| 1018 |
+
if has_line and line_params.get('slope') is not None and line_params.get('a') is None:
|
| 1019 |
+
slope = line_params['slope']
|
| 1020 |
+
if 'LeftFocus' in fact_expr or 'RightFocus' in fact_expr:
|
| 1021 |
+
c_hyp = np.sqrt(a**2 + b**2)
|
| 1022 |
+
focus_x = -c_hyp if 'LeftFocus' in fact_expr else c_hyp
|
| 1023 |
+
line_params['a'] = slope
|
| 1024 |
+
line_params['b'] = -1.0
|
| 1025 |
+
line_params['c'] = -slope * focus_x
|
| 1026 |
+
|
| 1027 |
+
# Determine plot limits
|
| 1028 |
+
if has_ellipse:
|
| 1029 |
+
a_ell = ellipse_params['a']
|
| 1030 |
+
b_ell = ellipse_params['b']
|
| 1031 |
+
max_dim = max(a, b, a_ell, b_ell) * 1.5 + 1
|
| 1032 |
+
else:
|
| 1033 |
+
max_dim = max(a, b) * 2.5 + 2
|
| 1034 |
+
|
| 1035 |
+
xlim = (-max_dim, max_dim)
|
| 1036 |
+
ylim = (-max_dim, max_dim)
|
| 1037 |
+
|
| 1038 |
+
fig, ax = plt.subplots(figsize=(8, 8))
|
| 1039 |
+
fig.patch.set_facecolor('white')
|
| 1040 |
+
|
| 1041 |
+
renderer = SDFRenderer(resolution=500, xlim=xlim, ylim=ylim)
|
| 1042 |
+
renderer.render_curve_only(sdf, ax, color='black', linewidth=1.5)
|
| 1043 |
+
|
| 1044 |
+
# Draw secondary ellipse if present
|
| 1045 |
+
if has_ellipse:
|
| 1046 |
+
center = torch.tensor([0.0, 0.0])
|
| 1047 |
+
a_ell_t = torch.tensor([ellipse_params['a']])
|
| 1048 |
+
b_ell_t = torch.tensor([ellipse_params['b']])
|
| 1049 |
+
ellipse_sdf = EllipseSDF(center, a_ell_t, b_ell_t)
|
| 1050 |
+
renderer.render_curve_only(ellipse_sdf, ax, color='black', linewidth=1.5)
|
| 1051 |
+
|
| 1052 |
+
# Draw line if present
|
| 1053 |
+
if has_line and line_params.get('a') is not None and line_params.get('b') is not None:
|
| 1054 |
+
line_a = line_params['a']
|
| 1055 |
+
line_b = line_params['b']
|
| 1056 |
+
line_c = line_params.get('c', 0)
|
| 1057 |
+
x_line = np.linspace(-max_dim, max_dim, 100)
|
| 1058 |
+
if abs(line_b) > 1e-6:
|
| 1059 |
+
y_line = (-line_a * x_line - line_c) / line_b
|
| 1060 |
+
mask = (y_line >= ylim[0]) & (y_line <= ylim[1])
|
| 1061 |
+
ax.plot(x_line[mask], y_line[mask], 'k-', linewidth=1.0)
|
| 1062 |
+
else:
|
| 1063 |
+
x_val = -line_c / line_a if abs(line_a) > 1e-6 else 0
|
| 1064 |
+
ax.axvline(x=x_val, color='black', linewidth=1.0)
|
| 1065 |
+
|
| 1066 |
+
# Asymptotes
|
| 1067 |
+
slope = b / a
|
| 1068 |
+
x_asym = np.linspace(-max_dim, max_dim, 100)
|
| 1069 |
+
ax.plot(x_asym, slope * x_asym, 'k--', linewidth=0.8, alpha=0.5)
|
| 1070 |
+
ax.plot(x_asym, -slope * x_asym, 'k--', linewidth=0.8, alpha=0.5)
|
| 1071 |
+
|
| 1072 |
+
# Foci
|
| 1073 |
+
c = np.sqrt(a**2 + b**2)
|
| 1074 |
+
d = max_dim * 0.025
|
| 1075 |
+
ax.plot(c, 0, 'k.', markersize=5)
|
| 1076 |
+
ax.plot(-c, 0, 'k.', markersize=5)
|
| 1077 |
+
ax.text(-c, d * 2, '$F_1$', fontsize=13, ha='center', va='bottom')
|
| 1078 |
+
ax.text(c, d * 2, '$F_2$', fontsize=13, ha='center', va='bottom')
|
| 1079 |
+
|
| 1080 |
+
# Additional points
|
| 1081 |
+
coords = self.parser.parse_coordinates(fact_expr)
|
| 1082 |
+
for name, (px, py) in coords.items():
|
| 1083 |
+
if name not in ['F1', 'F2', 'F', 'O']:
|
| 1084 |
+
ax.plot(px, py, 'k.', markersize=5)
|
| 1085 |
+
ax.text(px + d, py + d * 2, f'${name}$', fontsize=13)
|
| 1086 |
+
|
| 1087 |
+
self._setup_gaokao_axes(ax, xlim, ylim)
|
| 1088 |
+
|
| 1089 |
+
plt.savefig(output_path, dpi=150, bbox_inches='tight', facecolor='white')
|
| 1090 |
+
plt.close(fig)
|
| 1091 |
+
|
| 1092 |
+
def _visualize_parabola(self, sdf: ParabolaSDF, problem: Dict, params: Dict,
|
| 1093 |
+
output_path: Path):
|
| 1094 |
+
"""Visualize parabola in Gaokao style."""
|
| 1095 |
+
|
| 1096 |
+
with torch.no_grad():
|
| 1097 |
+
p = abs(sdf.p.item())
|
| 1098 |
+
|
| 1099 |
+
direction = params.get('direction', 'right')
|
| 1100 |
+
|
| 1101 |
+
# Adjust limits based on direction and p value
|
| 1102 |
+
extent = max(p * 8, 6)
|
| 1103 |
+
if direction == 'right':
|
| 1104 |
+
xlim = (-p * 3, extent)
|
| 1105 |
+
ylim = (-extent * 0.8, extent * 0.8)
|
| 1106 |
+
elif direction == 'left':
|
| 1107 |
+
xlim = (-extent, p * 3)
|
| 1108 |
+
ylim = (-extent * 0.8, extent * 0.8)
|
| 1109 |
+
elif direction == 'up':
|
| 1110 |
+
xlim = (-extent * 0.8, extent * 0.8)
|
| 1111 |
+
ylim = (-p * 3, extent)
|
| 1112 |
+
else: # down
|
| 1113 |
+
xlim = (-extent * 0.8, extent * 0.8)
|
| 1114 |
+
ylim = (-extent, p * 3)
|
| 1115 |
+
|
| 1116 |
+
# Ensure origin is visible
|
| 1117 |
+
xlim = (min(xlim[0], -0.5), max(xlim[1], 0.5))
|
| 1118 |
+
ylim = (min(ylim[0], -0.5), max(ylim[1], 0.5))
|
| 1119 |
+
|
| 1120 |
+
fig, ax = plt.subplots(figsize=(8, 8))
|
| 1121 |
+
fig.patch.set_facecolor('white')
|
| 1122 |
+
|
| 1123 |
+
renderer = SDFRenderer(resolution=600, xlim=xlim, ylim=ylim)
|
| 1124 |
+
renderer.render_curve_only(sdf, ax, color='black', linewidth=1.5)
|
| 1125 |
+
|
| 1126 |
+
d = max(xlim[1] - xlim[0], ylim[1] - ylim[0]) * 0.02
|
| 1127 |
+
|
| 1128 |
+
# Focus and directrix
|
| 1129 |
+
if direction == 'right':
|
| 1130 |
+
ax.plot(p, 0, 'k.', markersize=5)
|
| 1131 |
+
ax.text(p + d, d * 2, '$F$', fontsize=13, ha='left', va='bottom')
|
| 1132 |
+
ax.plot([-p, -p], [ylim[0], ylim[1]], 'k--', linewidth=0.8, alpha=0.5)
|
| 1133 |
+
elif direction == 'left':
|
| 1134 |
+
ax.plot(-p, 0, 'k.', markersize=5)
|
| 1135 |
+
ax.text(-p - d, d * 2, '$F$', fontsize=13, ha='right', va='bottom')
|
| 1136 |
+
ax.plot([p, p], [ylim[0], ylim[1]], 'k--', linewidth=0.8, alpha=0.5)
|
| 1137 |
+
elif direction == 'up':
|
| 1138 |
+
ax.plot(0, p, 'k.', markersize=5)
|
| 1139 |
+
ax.text(d * 2, p + d, '$F$', fontsize=13, ha='left', va='bottom')
|
| 1140 |
+
ax.plot([xlim[0], xlim[1]], [-p, -p], 'k--', linewidth=0.8, alpha=0.5)
|
| 1141 |
+
else: # down
|
| 1142 |
+
ax.plot(0, -p, 'k.', markersize=5)
|
| 1143 |
+
ax.text(d * 2, -p - d, '$F$', fontsize=13, ha='left', va='top')
|
| 1144 |
+
ax.plot([xlim[0], xlim[1]], [p, p], 'k--', linewidth=0.8, alpha=0.5)
|
| 1145 |
+
|
| 1146 |
+
# Additional points with staggered labels
|
| 1147 |
+
coords = self.parser.parse_coordinates(problem.get('fact_expressions', ''))
|
| 1148 |
+
for idx, (name, (px, py)) in enumerate(coords.items()):
|
| 1149 |
+
if name not in ['F', 'O']:
|
| 1150 |
+
ax.plot(px, py, 'k.', markersize=5)
|
| 1151 |
+
offset_y = d * 2 + d * idx
|
| 1152 |
+
ax.text(px + d, py + offset_y, f'${name}$', fontsize=13)
|
| 1153 |
+
|
| 1154 |
+
self._setup_gaokao_axes(ax, xlim, ylim)
|
| 1155 |
+
|
| 1156 |
+
plt.savefig(output_path, dpi=150, bbox_inches='tight', facecolor='white')
|
| 1157 |
+
plt.close(fig)
|
| 1158 |
+
|
| 1159 |
+
def process_batch(self, problems_input, max_problems: int = None,
|
| 1160 |
+
verbose: bool = False) -> List[Dict]:
|
| 1161 |
+
"""Process a batch of problems.
|
| 1162 |
+
|
| 1163 |
+
Args:
|
| 1164 |
+
problems_input: Either a list of problem dicts or a path to JSON file
|
| 1165 |
+
max_problems: Maximum number of problems to process
|
| 1166 |
+
verbose: Whether to print verbose output
|
| 1167 |
+
"""
|
| 1168 |
+
# Handle both list and file path inputs
|
| 1169 |
+
if isinstance(problems_input, str):
|
| 1170 |
+
with open(problems_input, 'r', encoding='utf-8') as f:
|
| 1171 |
+
problems = json.load(f)
|
| 1172 |
+
else:
|
| 1173 |
+
problems = problems_input
|
| 1174 |
+
|
| 1175 |
+
if max_problems:
|
| 1176 |
+
problems = problems[:max_problems]
|
| 1177 |
+
|
| 1178 |
+
results = []
|
| 1179 |
+
stats = {'total': len(problems), 'success': 0, 'failed': 0}
|
| 1180 |
+
type_stats = {'ellipse': 0, 'hyperbola': 0, 'parabola': 0, 'circle': 0}
|
| 1181 |
+
reason_counts: Dict[str, int] = {}
|
| 1182 |
+
|
| 1183 |
+
print(f"\n{'='*60}")
|
| 1184 |
+
print(f"SDF-Based Processing: {len(problems)} problems")
|
| 1185 |
+
print(f"{'='*60}\n")
|
| 1186 |
+
|
| 1187 |
+
for idx, problem in enumerate(tqdm(problems, desc="Processing")):
|
| 1188 |
+
result = self.process_problem(problem, idx, verbose)
|
| 1189 |
+
results.append(result)
|
| 1190 |
+
|
| 1191 |
+
if result['success']:
|
| 1192 |
+
stats['success'] += 1
|
| 1193 |
+
ctype = result.get('conic_type')
|
| 1194 |
+
if ctype in type_stats:
|
| 1195 |
+
type_stats[ctype] += 1
|
| 1196 |
+
else:
|
| 1197 |
+
stats['failed'] += 1
|
| 1198 |
+
for reason in result.get('validation_reasons', []):
|
| 1199 |
+
reason_counts[reason] = reason_counts.get(reason, 0) + 1
|
| 1200 |
+
|
| 1201 |
+
# Save summary
|
| 1202 |
+
summary = {
|
| 1203 |
+
'stats': stats,
|
| 1204 |
+
'type_stats': type_stats,
|
| 1205 |
+
'reason_counts': reason_counts,
|
| 1206 |
+
'results': results
|
| 1207 |
+
}
|
| 1208 |
+
with open(self.output_dir / 'summary.json', 'w') as f:
|
| 1209 |
+
json.dump(summary, f, indent=2, default=str)
|
| 1210 |
+
|
| 1211 |
+
print(f"\n{'='*60}")
|
| 1212 |
+
print("PROCESSING COMPLETE")
|
| 1213 |
+
print(f"{'='*60}")
|
| 1214 |
+
print(f"Success: {stats['success']} / {stats['total']} ({100*stats['success']/stats['total']:.1f}%)")
|
| 1215 |
+
print(f"By type: {type_stats}")
|
| 1216 |
+
print(f"Output: {self.output_dir}")
|
| 1217 |
+
|
| 1218 |
+
return results
|
src/sdf_geo/renderer.py
ADDED
|
@@ -0,0 +1,98 @@
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
| 1 |
+
"""
|
| 2 |
+
SDF Renderer Module
|
| 3 |
+
Visualization utilities for SDF fields and zero-level sets.
|
| 4 |
+
"""
|
| 5 |
+
|
| 6 |
+
import torch
|
| 7 |
+
import numpy as np
|
| 8 |
+
import matplotlib.pyplot as plt
|
| 9 |
+
from matplotlib.colors import LinearSegmentedColormap
|
| 10 |
+
from typing import Tuple, Optional
|
| 11 |
+
|
| 12 |
+
|
| 13 |
+
class SDFRenderer:
|
| 14 |
+
"""
|
| 15 |
+
Renderer for SDF fields and zero-level sets.
|
| 16 |
+
Creates visualization grids and renders SDF values.
|
| 17 |
+
"""
|
| 18 |
+
|
| 19 |
+
def __init__(self, resolution: int = 512,
|
| 20 |
+
xlim: Tuple[float, float] = (-5, 5),
|
| 21 |
+
ylim: Tuple[float, float] = (-5, 5)):
|
| 22 |
+
self.resolution = resolution
|
| 23 |
+
self.xlim = xlim
|
| 24 |
+
self.ylim = ylim
|
| 25 |
+
|
| 26 |
+
# Create evaluation grid
|
| 27 |
+
x = torch.linspace(xlim[0], xlim[1], resolution)
|
| 28 |
+
y = torch.linspace(ylim[0], ylim[1], resolution)
|
| 29 |
+
self.xx, self.yy = torch.meshgrid(x, y, indexing='xy')
|
| 30 |
+
self.grid = torch.stack([self.xx, self.yy], dim=-1)
|
| 31 |
+
|
| 32 |
+
# Custom colormap for SDF visualization
|
| 33 |
+
self.sdf_cmap = LinearSegmentedColormap.from_list(
|
| 34 |
+
'sdf', ['#2E86AB', '#FFFFFF', '#E74C3C'], N=256
|
| 35 |
+
)
|
| 36 |
+
|
| 37 |
+
def render_sdf_field(self, sdf, ax: plt.Axes,
|
| 38 |
+
show_field: bool = True,
|
| 39 |
+
field_alpha: float = 0.3) -> np.ndarray:
|
| 40 |
+
"""
|
| 41 |
+
Render SDF field and zero-level set.
|
| 42 |
+
|
| 43 |
+
Args:
|
| 44 |
+
sdf: SDF primitive to render
|
| 45 |
+
ax: Matplotlib axes
|
| 46 |
+
show_field: Show background SDF field
|
| 47 |
+
field_alpha: Alpha for background field
|
| 48 |
+
|
| 49 |
+
Returns:
|
| 50 |
+
SDF values as numpy array
|
| 51 |
+
"""
|
| 52 |
+
with torch.no_grad():
|
| 53 |
+
# Evaluate SDF on grid
|
| 54 |
+
grid_flat = self.grid.reshape(-1, 2)
|
| 55 |
+
distances = sdf(grid_flat).reshape(self.resolution, self.resolution)
|
| 56 |
+
distances_np = distances.cpu().numpy()
|
| 57 |
+
|
| 58 |
+
# Show SDF field as background
|
| 59 |
+
if show_field:
|
| 60 |
+
max_val = min(np.abs(distances_np).max(), 10)
|
| 61 |
+
ax.contourf(self.xx.numpy(), self.yy.numpy(), distances_np,
|
| 62 |
+
levels=50, cmap=self.sdf_cmap, alpha=field_alpha,
|
| 63 |
+
vmin=-max_val, vmax=max_val)
|
| 64 |
+
|
| 65 |
+
# Draw zero-level set (the curve)
|
| 66 |
+
ax.contour(self.xx.numpy(), self.yy.numpy(), distances_np,
|
| 67 |
+
levels=[0], colors=['#2E86AB'], linewidths=2.5)
|
| 68 |
+
|
| 69 |
+
return distances_np
|
| 70 |
+
|
| 71 |
+
def render_multiple(self, sdfs: list, ax: plt.Axes,
|
| 72 |
+
colors: Optional[list] = None) -> None:
|
| 73 |
+
"""Render multiple SDFs on the same axes."""
|
| 74 |
+
if colors is None:
|
| 75 |
+
colors = ['#2E86AB', '#E74C3C', '#27AE60', '#9B59B6', '#F39C12']
|
| 76 |
+
|
| 77 |
+
with torch.no_grad():
|
| 78 |
+
grid_flat = self.grid.reshape(-1, 2)
|
| 79 |
+
|
| 80 |
+
for i, sdf in enumerate(sdfs):
|
| 81 |
+
distances = sdf(grid_flat).reshape(self.resolution, self.resolution)
|
| 82 |
+
distances_np = distances.cpu().numpy()
|
| 83 |
+
|
| 84 |
+
color = colors[i % len(colors)]
|
| 85 |
+
ax.contour(self.xx.numpy(), self.yy.numpy(), distances_np,
|
| 86 |
+
levels=[0], colors=[color], linewidths=2.5)
|
| 87 |
+
|
| 88 |
+
def render_curve_only(self, sdf, ax, color='black', linewidth=1.5, linestyle='-'):
|
| 89 |
+
"""Render only the zero-level set (curve) without SDF field background."""
|
| 90 |
+
with torch.no_grad():
|
| 91 |
+
grid_flat = self.grid.reshape(-1, 2)
|
| 92 |
+
distances = sdf(grid_flat).reshape(self.resolution, self.resolution)
|
| 93 |
+
distances_np = distances.cpu().numpy()
|
| 94 |
+
|
| 95 |
+
ax.contour(self.xx.numpy(), self.yy.numpy(), distances_np,
|
| 96 |
+
levels=[0], colors=[color], linewidths=linewidth, linestyles=linestyle)
|
| 97 |
+
|
| 98 |
+
return distances_np
|