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Reorganise: group 313 tasks into 17 families under tasks/, generators under tools/ (part 3)
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"""Reference implementation — the CORRECTNESS SPEC for `moe_a2a_dispatch`.
This is correct but slow. It defines exactly what your kernel must reproduce; its speed has no
bearing on your score, which is an absolute GB/s number. GENERATED by _factory/build.py.
"""
import torch
import torch.distributed as dist
def moe_a2a_dispatch(x, expert_idx, num_experts, ctx):
"""Reference: sort by expert, all-gather the count matrix, one NCCL all-to-all, then a regroup loop.
Correct and simple; it is the SPECIFICATION, not a performance target. There is no arithmetic here —
every output row is a verbatim copy of an input row — so a correct implementation matches bitwise.
"""
W, r = ctx.world_size, ctx.rank
E = num_experts
EL = E // W
T, H = x.shape
dev = x.device
idx = expert_idx.long()
order = torch.argsort(idx, stable=True) # tokens grouped by expert, original order kept
xs = x[order].contiguous()
cnt = torch.bincount(idx, minlength=E).to(torch.int32) # (E,) my tokens per expert
all_cnt = torch.empty(W * E, dtype=torch.int32, device=dev)
dist.all_gather_into_tensor(all_cnt, cnt, group=ctx.group)
all_cnt = all_cnt.view(W, E)
recv = all_cnt[:, r * EL:(r + 1) * EL].contiguous() # (W, EL) what each source sends to my experts
send_split = cnt.view(W, EL).sum(1).tolist() # to each destination rank
recv_split = recv.sum(1).tolist() # from each source rank
y_raw = torch.empty(int(sum(recv_split)), H, dtype=x.dtype, device=dev)
dist.all_to_all_single(y_raw, xs, recv_split, send_split, group=ctx.group)
# y_raw is grouped (source_rank, local_expert); the grouped GEMM wants (local_expert, source_rank)
y = torch.empty_like(y_raw)
base = torch.cat([torch.zeros(1, dtype=torch.long, device=dev), recv.sum(0).long().cumsum(0)])
cur = base[:-1].tolist()
rc = recv.tolist()
off = 0
for s in range(W):
for e in range(EL):
n = rc[s][e]
if n:
y[cur[e]:cur[e] + n] = y_raw[off:off + n]
cur[e] += n
off += n
return y, recv