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6abbd30 | 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86 87 88 89 90 91 92 93 94 95 96 97 98 99 100 101 102 103 104 105 106 107 108 109 110 111 112 113 114 115 116 117 118 119 120 121 122 123 124 125 126 127 128 129 130 131 132 133 134 135 136 137 138 139 140 141 142 143 144 145 146 147 148 149 150 151 152 153 154 155 156 157 158 159 160 161 162 163 164 165 166 167 168 169 170 171 172 173 174 175 176 177 178 179 180 181 182 183 184 185 186 187 188 189 190 191 192 193 194 195 196 197 198 199 200 201 | myN3PqD38Ds-005|Or from step 2 to step 3? myN3PqD38Ds-014|We're looking at a system mixing going from all the particles on one side to distributed across both sides. myN3PqD38Ds-015|As this occurs, we look at, well, how many ways can I arrange state 1? myN3PqD38Ds-016|Well, there is only one way to have the particles all on one side. myN3PqD38Ds-017|How about state 2? myN3PqD38Ds-022|So again, final over initial, I have natural log 6/4, or 1.5. myN3PqD38Ds-024|So 3 is out. myN3PqD38Ds-025|This is a decrease. myN3PqD38Ds-026|It's between 1 and 2, A and B here. myN3PqD38Ds-027|And the greatest increase L and 4, bigger than l and L and 1/2, is going from state 1 to state 2. myN3PqD38Ds-029|So the answer here, A. hWiUC-tsVHs-000|When a base reacts with water, it forms its conjugate acid. hWiUC-tsVHs-001|How is that conjugate base/conjugate acid expressions related? hWiUC-tsVHs-008|And in this case, as in all cases, we leave out pure water. hWiUC-tsVHs-009|Pure liquids and pure solids don't appear in equilibrium constant expressions. hWiUC-tsVHs-010|So here I have Kb for NH3, the weak base. hWiUC-tsVHs-011|The weak acid produced, NH4 plus, can also react with water. hWiUC-tsVHs-018|So here we have an analytical expression that tells us the larger Kb, the smaller Ka. hWiUC-tsVHs-019|A strong conjugate base leads to a weaker conjugate acid. jGRhNqkYK18-000|Let's start looking at the periodic table. jGRhNqkYK18-001|We understand the periodic table is assembled so that elements that have similar properties fall in columns. jGRhNqkYK18-002|That is properties occur periodically as you march through the elements from atomic number one to atomic number 112. jGRhNqkYK18-003|As you march through, properties start to repeat themselves. jGRhNqkYK18-004|So if you line up the repeating elements in columns, you get a periodic table where all elements with similar properties are in columns. jGRhNqkYK18-005|So all of the elements in column one, for instance, have similar properties. jGRhNqkYK18-006|And now we understand the quantum mechanical nature of that. jGRhNqkYK18-008|But the overall structure has been fairly consistent for hundreds of years. jGRhNqkYK18-009|But we understand now with the advent of quantum mechanics why these elements have similar properties. jGRhNqkYK18-010|For instance, in column one, all the elements have an s1 outer electronic configuration. jGRhNqkYK18-011|It's either 1S1, 2S1, 3S1, 4S1, et cetera, down the periodic table. jGRhNqkYK18-012|So from the outside, you're looking at a 1s electron all the time. jGRhNqkYK18-013|And, of course, that imparts similar reactive properties to those elements. jGRhNqkYK18-014|And as you go across, S2, and then you start to fill P orbitals. jGRhNqkYK18-015|And then you fill D orbitals and F orbitals. jGRhNqkYK18-017|So quantum mechanics exactly predicts the structure of the periodic table even though the periodic table was set up well before quantum mechanics was understood. jGRhNqkYK18-018|Now, these periodic properties in the periodic table tend to go in trends as you go across the periodic table. jGRhNqkYK18-019|And those trends are interesting to analyze. jGRhNqkYK18-021|We've talked a little bit about ionization energy already. jGRhNqkYK18-022|That's separating electrons from atoms. jGRhNqkYK18-023|There's also electron affinity. jGRhNqkYK18-024|So electron affinity is the addition of an electron to an atom or an ion. jGRhNqkYK18-028|And that's something you can take to the bank. jGRhNqkYK18-030|And if it requires energy, we're going to call those positive energies in Chem One. jGRhNqkYK18-031|And if energy is released, we're going to call those negative energies. jGRhNqkYK18-034|Now, you might think that atoms don't want to accept electrons. jGRhNqkYK18-035|But it turns out that adding an electron often releases energy that goes to a lower energy more stable state. jGRhNqkYK18-037|So adding electron is usually a reaction that releases energy. jGRhNqkYK18-038|It's more stable to have that electron. jGRhNqkYK18-039|And that's an interesting property. jGRhNqkYK18-040|In fact, you don't expect it to be the case. jGRhNqkYK18-041|And there are a few elements where they're not too excited about taking that electron and some, one or two, that you actually have to force it on. jGRhNqkYK18-042|You have to put a tiny amount of energy in to make the ion. jGRhNqkYK18-046|So the trend as I go down the column is it's getting easier to ionize. jGRhNqkYK18-047|The ionization energy is decreasing. jGRhNqkYK18-048|And that's pretty easy to understand. jGRhNqkYK18-049|Because what I'm doing is going to bigger and bigger atoms. jGRhNqkYK18-051|So an electron far away and well shielded is easier to take off than an electron close by. jGRhNqkYK18-054|For the electron affinities, there's the same general trend. jGRhNqkYK18-055|That is the electronic affinity for sodium, sodium releases quite a bit of energy when you make it into sodium minus. jGRhNqkYK18-056|It likes to accept that electron. jGRhNqkYK18-057|53 kilojoules per mole are released where, rubidium, only 47 kilojoules are released. jGRhNqkYK18-058|That makes a little sense, too, rubidium with it's 37 electrons. jGRhNqkYK18-059|The 38th one that you put on is a little less kept track of there. jGRhNqkYK18-060|It's going from 37 to 38. jGRhNqkYK18-061|It's not a big perturbation as going from 11 to 12 electrons at sodium. jGRhNqkYK18-063|Same thing with chlorine, bromine, and iodine. jGRhNqkYK18-064|We have a decrease in electron affinity as I go down the column on the periodic table. OLE3iAKuhAY-000|As we talk about molecular geometry, we're going from a chemical formula to a Lewis structure to getting some steric numbers to a molecular geometry. OLE3iAKuhAY-001|Now, chemical formula and molecular geometry are not uniquely paired. OLE3iAKuhAY-002|That is, you can have chemical formulas with different molecular geometries. OLE3iAKuhAY-008|This molecule I can arrange the chlorines and the carbons like this or like this. OLE3iAKuhAY-009|So here, I have a carbon with two chlorines, here I have carbon with a chlorine and a hydrogen. OLE3iAKuhAY-010|So those are structural isomers, the bonding patterns are different. OLE3iAKuhAY-015|We'll also have a dipole moment in this molecule. OLE3iAKuhAY-016|So these structural isomers could be distinguished by dipole moment, these stereoisomers could be distinguished by dipole moment. OLE3iAKuhAY-017|Structural isomerism and stereoisomerism is something that's very important in nature, and we'll look at that a lot in this course. EABEj-lHxsA-000|Let's use heat capacities to determine a relative temperature change. EABEj-lHxsA-001|What I'm going to do is take hot molybdenum metal, a kilogram. EABEj-lHxsA-002|So think about taking molybdenum metal, heating it in a flame till it's red hot, and then plunging it into a kilogram of water at room temperature. EABEj-lHxsA-003|The question I have is, which will experience the greater temperature change? EABEj-lHxsA-009|We're talking about plunging hot metal molybdenum-- a kilogram-- into cool water. EABEj-lHxsA-010|So what's going to happen? EABEj-lHxsA-011|Well, the heat from the metal will go into the water, and that's where we apply the first law of thermodynamics. EABEj-lHxsA-012|Every joule of heat lost by the metal is absorbed by the water. EABEj-lHxsA-019|Water, let's look at that capacity-- around 4 joules to change the temperature of 1 gram of water by 1 degree. EABEj-lHxsA-022|That's the difference in heat capacities. EABEj-lHxsA-024|So in this case, the temperature of the metal will change more than the temperature of the water. hSBT6oe6dSA-000|When we perform chemical reactions in the laboratory, we need a way to get from the microscopic to the macroscopic. hSBT6oe6dSA-002|And we need to know that, because we write chemical reaction in terms of the particles involved. hSBT6oe6dSA-003|Here's our chemical reaction, H2 plus O2 goes to H2O. hSBT6oe6dSA-004|And it's two particles of hydrogen and one particle of oxygen to give me two particles of water. hSBT6oe6dSA-007|Well, it turns out it's pretty easy. hSBT6oe6dSA-008|We just scale up from the relative masses. hSBT6oe6dSA-009|From the relative masses of the individual particles, we scale up to masses that we can measure. hSBT6oe6dSA-011|That is 16 grams of oxygen will react with one gram of hydrogen and have the same number of particles. hSBT6oe6dSA-012|It's as if you were going to go to a hardware store, and you wanted 500 nuts and bolts. hSBT6oe6dSA-013|Now, no one wants to count out 500 bolts, but the guy at the hardware store might say, oh, the bolts weigh a gram, so weigh out 500 grams. hSBT6oe6dSA-014|That'll give you your 500 volts. hSBT6oe6dSA-015|And you say, but I also need the nuts. hSBT6oe6dSA-016|And then you say, oh, the nuts are half as heavy. hSBT6oe6dSA-017|They have a half the mass. hSBT6oe6dSA-018|Well, then weigh out 250 grams of bolts, half that mass, and you'll be assured you have a nut for every bolt. hSBT6oe6dSA-019|You've used the relative mass to match up one to one, nuts and bolts. hSBT6oe6dSA-020|That's how we do it in chemistry. hSBT6oe6dSA-021|We take one element to be the standard. hSBT6oe6dSA-022|Carbon will be the standard, and I'll measure all my relative masses relative to carbon-12. hSBT6oe6dSA-026|Now, it's not one to one particles. hSBT6oe6dSA-034|So a mole of carbon-12 particles is 6.02 times 10 to the 23rd, and that has a mass of 12 grams. hSBT6oe6dSA-035|So the units we'll use are 12 grams per mole of carbon is a mole of carbon. hSBT6oe6dSA-036|So that's how we're going to make the connection between macroscopic properties and microscopic properties. hSBT6oe6dSA-037|We're going to use Avogadro's constant and our concept of the mole. 8pdWHCJSkso-000|Acid strength depends on a variety of factors. 8pdWHCJSkso-001|One of those factors is the polarity of the bond involving the hydrogen. 8pdWHCJSkso-004|So that bond becomes more polar, and the acid strength will increase. 8pdWHCJSkso-005|Stronger acid, slightly weaker acid, slightly weaker acid. 8pdWHCJSkso-009|So let's correlate these. 8pdWHCJSkso-010|The strongest acid, slightly weaker, slightly weaker. 8pdWHCJSkso-011|Now, electron activity is also a factor. 8pdWHCJSkso-013|This effect, this electron withdrawing group, electronegativity, can be observed at a distance. 8pdWHCJSkso-014|Here's acetic acid and chloroacetic acid. 8pdWHCJSkso-015|A chlorine that's even several bonds away from the acidic proton can still have an effect. 8pdWHCJSkso-016|And indeed, chloroacetic acid is a stronger acid than acetic acid. TmKL0W2skJM-002|And you could talk about a specific heat capacity, in terms of grams, or a molar heat capacity, in terms of the number of moles of a substance. TmKL0W2skJM-003|Now, heat capacity works just like volumetric capacity, where heat and fluid have the same role. TmKL0W2skJM-009|Let's say, here's water flow, colored so we can see it, and it flows into this high capacity flask. TmKL0W2skJM-010|And we'll raise the height, say, 5 or 6 inches, and look how much liquid it takes to do that. TmKL0W2skJM-011|That's a high capacity. TmKL0W2skJM-012|It took a lot of flow to get this kind of change in height. TmKL0W2skJM-014|So a small amount of fluid, large amount of height change, that would be a low heat capacity. TmKL0W2skJM-028|4 joules of heat to solid water, I'll change the temperature by 2 degrees. TmKL0W2skJM-029|They have about a factor of 2 in their heat capacity. TmKL0W2skJM-032|It's the conversion factor between heat flow and temperature change. TmKL0W2skJM-033|Temperature changes are very easy to measure. TmKL0W2skJM-034|Stick a thermometer in, and you can measure a temperature change. GU4UnHFVWzA-000|Let's look at the formation of some ionic bonds. GU4UnHFVWzA-001|Bromine will form ionic bonds with several atoms. GU4UnHFVWzA-010|We're looking for a bromide that's 80% bromine by mass. GU4UnHFVWzA-011|And we have three possible candidates to react with the bromine. GU4UnHFVWzA-013|The question is do they react? GU4UnHFVWzA-015|It's relatively stable as it is. GU4UnHFVWzA-016|So neon bromide actually doesn't even form. GU4UnHFVWzA-017|What about potassium? GU4UnHFVWzA-019|BR minus and K plus, potassium bromide, though doesn't fulfill our 80% bromine requirement. GU4UnHFVWzA-020|Now, bromine and calcium, you have two valence electrons. GU4UnHFVWzA-024|So you have a Coulombic interaction between the plus 2 calcium and the 2 minus bromides. GU4UnHFVWzA-025|So this compound has a total mass of 200-- 80, 80, and 40. GU4UnHFVWzA-026|And 160 of that 200, or 80%, is bromine. GU4UnHFVWzA-027|So here's a bromide that's 80% bromine by mass and it's formed with calcium. LPol-lH6nmI-000|Let's look at the ionization energy for a species we haven't talked about yet, the Cl- ion. LPol-lH6nmI-010|We're trying to determine the ionization energy of the Cl- ion. LPol-lH6nmI-014|That is, we're trying to ionize Cl-, that is take Cl- down to an electron and Cl. LPol-lH6nmI-015|So it's the reverse of the electron affinity reaction. LPol-lH6nmI-016|If you reverse a reaction, you take the opposite of the energy. LPol-lH6nmI-018|For this reaction, it takes 349 kilojoules per mole to remove an electron from Cl-. wnGMFRnbik4-000|Let's review the orbitals about an atom. wnGMFRnbik4-001|For an atom like hydrogen with a single electron, there's a variety of orbitals that the electron can exist in. wnGMFRnbik4-002|The orbitals will be designated by three quantum numbers-- n, l, and m sub l. wnGMFRnbik4-005|Two is at an energy level above that. wnGMFRnbik4-006|And anything with n equal two is at the same energy for a one electron system. wnGMFRnbik4-007|That's because the electron has the whole space to itself. wnGMFRnbik4-008|It can always see the nucleus. wnGMFRnbik4-009|There are no other electrons to either repel the electron or shield the electron from the nucleus. wnGMFRnbik4-010|So wherever it exists in n equal two, it has the same relative energy. wnGMFRnbik4-011|Wherever it exists in n equal 3 it has the same relative energy. wnGMFRnbik4-012|If you start adding more electrons, those energy levels are perturbed slightly. wnGMFRnbik4-013|And within n equal two and within n equal three you'll get differences in energy. wnGMFRnbik4-014|So let's look at those more carefully and see how one electron can shield other electrons. GE6ypnVaqlY-000|Particles can behave like waves. GE6ypnVaqlY-001|They can have a wave-like property. GE6ypnVaqlY-005|Here's a list of particles and their de Broglie wavelengths. GE6ypnVaqlY-010|A sodium atom at 800 or 80 Calvin, that's a temperature. GE6ypnVaqlY-011|That determines the average speed in the system. GE6ypnVaqlY-012|The average speed of those particles is around 300 meters per second. GE6ypnVaqlY-013|We know they are sodium atoms, so we know their mass. GE6ypnVaqlY-014|They have a momentum. GE6ypnVaqlY-015|I can calculate a wavelength, a few hundredths of a nanometer. GE6ypnVaqlY-016|Now, let's take a baseball, an object that we know the size and mass of, a macroscopic object. GE6ypnVaqlY-018|That's a very good fastball. GE6ypnVaqlY-019|We can calculate, using the de Broglie relationship, the wavelength. GE6ypnVaqlY-020|But look at how small the number is. GE6ypnVaqlY-022|Then We were already at nanometers, 10 to the minus 9. GE6ypnVaqlY-027|And you don't notice a wavelength because the wavelength is vanishingly small. GE6ypnVaqlY-028|In order for the wave-like properties of matter to manifest itself, the matter must be very tiny. GE6ypnVaqlY-029|If you have very, very tiny matter with very tiny momenta, then the wavelength creeps up into a region where you could actually detect it. GE6ypnVaqlY-030|So particle and wave nature of matter is going to be important for small particles, but not for macroscopic large particles. GE6ypnVaqlY-031|We don't even notice it. zBEZZMWo5uM-000|Let's look at a chemical reaction in the gas phase. zBEZZMWo5uM-001|I'm going to take methane and burn it in oxygen. zBEZZMWo5uM-002|I'll take a fixed volume, 1 atmosphere of methane, 2 atmospheres of oxygen in a 1-liter flask, constant high temperature. zBEZZMWo5uM-003|Let the reaction go to completion. zBEZZMWo5uM-004|What's the final total pressure? zBEZZMWo5uM-014|We're looking at the combustion of methane in a fixed volume. zBEZZMWo5uM-015|Here I've written the combustion reaction, and I've balanced the chemical reaction. v6gyWKD2W8U-000|We can write acid-base equilibrium reactions for weak acids or weak bases. WD5ZIBhyy2A-009|When a chemical reaction occurs, the numbers and kinds of atoms have to be conserved. WD5ZIBhyy2A-014|So these other two, if you do the analysis, don't have the correct numbers and kinds in two moles to form oxygen and water. 3ZA4WQE5EU8-000|Let's look at how the carbon atom hybridisation changes in a polymerization reaction. 3ZA4WQE5EU8-001|We'll take ethylene, C2H4, and polymerize it into polyethylene. 3ZA4WQE5EU8-002|The question is, how does the hybridization change? 3ZA4WQE5EU8-010|Correct answer here-- sp2 to sp3. |