[User] List all pairs of record_id for the same patient that were created on the same day. Show the two record_ids, patient_id, and the date.

[Assistant]
SELECT
    mr1.patient_id,
    date_trunc('day', mr1.record_date) AS record_day,
    mr1.record_id AS record_id_1,
    mr2.record_id AS record_id_2
FROM healthcare.medical_records mr1
JOIN healthcare.medical_records mr2
  ON mr1.patient_id = mr2.patient_id
 AND date_trunc('day', mr1.record_date) = date_trunc('day', mr2.record_date)
 AND mr1.record_id < mr2.record_id;

[User] Only include pairs where both records have a heart rate over 100 in their vitals.

[Assistant]
SELECT
    mr1.patient_id,
    date_trunc('day', mr1.record_date) AS record_day,
    mr1.record_id AS record_id_1,
    mr2.record_id AS record_id_2
FROM healthcare.medical_records mr1
JOIN healthcare.medical_records mr2
  ON mr1.patient_id = mr2.patient_id
 AND date_trunc('day', mr1.record_date) = date_trunc('day', mr2.record_date)
 AND mr1.record_id < mr2.record_id
WHERE (mr1.vitals->>'HR')::int > 100
  AND (mr2.vitals->>'HR')::int > 100;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE healthcare.medical_records (
    record_id character varying(64) NOT NULL,  -- unique identifier for the medical record entry
    patient_id character varying(64) NOT NULL, -- FK to patients table
    appointment_id character varying(64) UNIQUE, -- FK to appointments table (can be null if record not tied to specific appt)
    doctor_id character varying(64) NOT NULL, -- FK to doctors table (doctor creating the record)
    record_date timestamp with time zone NOT NULL, -- date the record/observation was made
    chief_complaint text, -- patient's primary reason for visit
    present_illness_history text, -- detailed history of the current issue
    past_medical_history text, -- relevant past conditions/surgeries
    physical_examination_notes text, -- findings from the physical exam
    assessment text, -- doctor's assessment/diagnosis summary
    treatment_plan text, -- planned course of action
    vitals jsonb, -- store vitals like BP, HR, Temp as structured JSON
    created_at timestamp with time zone NOT NULL DEFAULT current_timestamp,
    PRIMARY KEY (record_id)
)


[User] List all customer-employee pairs where they share the same email domain, showing customer_id, customer email, employee_id, and employee email.

[Assistant]
SELECT c.customer_id,
       c.email AS customer_email,
       e.employee_id,
       e.email AS employee_email,
       SPLIT_PART(c.email, '@', 2) AS email_domain
FROM financial_services.customers c
JOIN financial_services.employees e
  ON SPLIT_PART(c.email, '@', 2) = SPLIT_PART(e.email, '@', 2);

[User] Actually, only include domains that appear for at least 3 customers.

[Assistant]
WITH domain_counts AS (
  SELECT SPLIT_PART(email, '@', 2) AS email_domain,
         COUNT(*) AS cust_count
  FROM financial_services.customers
  GROUP BY SPLIT_PART(email, '@', 2)
  HAVING COUNT(*) >= 3
)
SELECT c.customer_id,
       c.email AS customer_email,
       e.employee_id,
       e.email AS employee_email,
       dc.email_domain
FROM financial_services.customers c
JOIN financial_services.employees e
  ON SPLIT_PART(c.email, '@', 2) = SPLIT_PART(e.email, '@', 2)
JOIN domain_counts dc
  ON SPLIT_PART(c.email, '@', 2) = dc.email_domain;

[User] Now, order the results by the email_domain ascending and then by customer_last_name descending.

[Assistant]
WITH domain_counts AS (
  SELECT SPLIT_PART(email, '@', 2) AS email_domain,
         COUNT(*) AS cust_count
  FROM financial_services.customers
  GROUP BY SPLIT_PART(email, '@', 2)
  HAVING COUNT(*) >= 3
)
SELECT c.customer_id,
       c.email AS customer_email,
       e.employee_id,
       e.email AS employee_email,
       dc.email_domain
FROM financial_services.customers c
JOIN financial_services.employees e
  ON SPLIT_PART(c.email, '@', 2) = SPLIT_PART(e.email, '@', 2)
JOIN domain_counts dc
  ON SPLIT_PART(c.email, '@', 2) = dc.email_domain
ORDER BY dc.email_domain ASC,
         c.last_name DESC;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE financial_services.customers ( customer_id text PRIMARY KEY, first_name text, last_name text, date_of_birth date, ssn_hash text, address text, city text, state text, zip_code text, country text, email text, phone_number text, created_at timestamp, status text, risk_profile text )
CREATE TABLE financial_services.employees ( employee_id text PRIMARY KEY, first_name text, last_name text, job_title text, department text, branch_id text, email text, phone_extension text, hire_date date, termination_date date, manager_id text, status text )


[User] Show me all appointments with status 'Completed' where the associated medical records have a treatment plan containing 'antibiotics', including the appointment details and the record date.

[Assistant] SELECT a.appointment_id, a.patient_id, a.doctor_id, a.appointment_time, a.duration_minutes, a.reason, a.status, a.location_id, mr.record_date FROM healthcare.appointments a JOIN healthcare.medical_records mr ON a.appointment_id = mr.appointment_id WHERE a.status = 'Completed' AND mr.treatment_plan LIKE '%antibiotics%';

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE healthcare.appointments ( appointment_id text, patient_id text, doctor_id text, appointment_time timestamp, duration_minutes integer, reason text, status text, location_id text, notes text, created_at timestamp )
CREATE TABLE healthcare.medical_records ( record_id text PRIMARY KEY, patient_id text, appointment_id text, doctor_id text, record_date timestamp, chief_complaint text, present_illness_history text, past_medical_history text, physical_examination_notes text, assessment text, treatment_plan text, vitals text, created_at timestamp )
CREATE TABLE healthcare.diagnoses ( diagnosis_id text, record_id text, patient_id text, doctor_id text, diagnosis_code text, code_type text, description text, diagnosis_date date, status text, is_chronic boolean )


[User] Find all contracts where the deployer address is the same as the contract address, indicating self-deployed contracts, and show their network IDs and deployment timestamps.

[Assistant] SELECT address, network_id, deployed_at FROM web3.contracts WHERE address = deployer_address;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE web3.contracts ( contract_id character varying(64) NOT NULL, address character varying(128) NOT NULL, abi text NOT NULL, bytecode text NOT NULL, deployer_address character varying(128) NOT NULL, deployed_at timestamp NOT NULL, network_id character varying(64) NOT NULL, status character varying(32) NOT NULL, PRIMARY KEY (contract_id) )


[User] For each doctor, count how many diagnoses they have recorded in total. Display doctor ID and the total count.

[Assistant] SELECT doctor_id, COUNT(*) AS total_diagnoses FROM healthcare.diagnoses GROUP BY doctor_id;

[User] Modify the query to also show the number of unique patients they have diagnosed, and filter the results to only include doctors who have diagnosed more than 10 distinct patients.

[Assistant] SELECT doctor_id, COUNT(*) AS total_diagnoses, COUNT(DISTINCT patient_id) AS unique_patients FROM healthcare.diagnoses GROUP BY doctor_id HAVING COUNT(DISTINCT patient_id) > 10;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE healthcare.diagnoses (
    diagnosis_id character varying(64) NOT NULL, -- unique identifier for the diagnosis entry
    record_id character varying(64) NOT NULL, -- FK linking to the specific medical record entry
    patient_id character varying(64) NOT NULL, -- FK to patients table
    doctor_id character varying(64) NOT NULL, -- FK to doctors table (diagnosing doctor)
    diagnosis_code character varying(20) NOT NULL, -- standard code (e.g., ICD-10)
    code_type character varying(10) NOT NULL DEFAULT 'ICD-10', -- type of code used
    description text, -- textual description of the diagnosis
    diagnosis_date date NOT NULL, -- date the diagnosis was made
    status character varying(32) NOT NULL, -- e.g., Active, Resolved, Ruled Out
    is_chronic boolean DEFAULT false, -- flag for chronic conditions
    PRIMARY KEY (diagnosis_id)
)


[User] List all guests who have never left a review, including their full name and email.

[Assistant]
SELECT g.guest_id, g.first_name, g.last_name, g.email
FROM hospitality_technology.guests g
LEFT JOIN hospitality_technology.reviews r ON g.guest_id = r.guest_id
WHERE r.review_id IS NULL;

[User] Can you also include their phone number?

[Assistant]
SELECT g.guest_id, g.first_name, g.last_name, g.email, g.phone_number
FROM hospitality_technology.guests g
LEFT JOIN hospitality_technology.reviews r ON g.guest_id = r.guest_id
WHERE r.review_id IS NULL;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE hospitality_technology.properties ( property_id text PRIMARY KEY, property_name text, address_line1 text, address_line2 text, city text, state_province text, postal_code text, country_code text, phone_number text, email_address text, property_type text, star_rating numeric, timezone text, manager_staff_id text, created_at timestamp, updated_at timestamp )
CREATE TABLE hospitality_technology.rooms ( room_id text PRIMARY KEY, property_id text, room_number text, room_type_id text, floor int, status text, is_smoking boolean, features text, current_condition text, last_cleaned_at timestamp )
CREATE TABLE hospitality_technology.room_types ( room_type_id text PRIMARY KEY, property_id text, type_name text, description text, base_rate numeric, max_occupancy int, bed_type text, area_sqft numeric, amenities text )
CREATE TABLE hospitality_technology.guests ( guest_id text PRIMARY KEY, first_name text, last_name text, email text, phone_number text, date_of_birth date, address_line1 text, city text, state_province text, postal_code text, country_code text, preferences text, loyalty_member_id text, communication_consent boolean, created_at timestamp, updated_at timestamp )
CREATE TABLE hospitality_technology.staff ( staff_id text PRIMARY KEY, property_id text, first_name text, last_name text, position text, work_email text, work_phone text, hire_date date, termination_date date, is_active boolean, access_level int, manager_id text, created_at timestamp )
CREATE TABLE hospitality_technology.services ( service_id text PRIMARY KEY, property_id text, service_name text, description text, category text, price numeric, unit text, is_available boolean, department text )
CREATE TABLE hospitality_technology.service_orders ( order_id text PRIMARY KEY, reservation_id text, guest_id text, service_id text, staff_id_ordered text, staff_id_delivered text, order_timestamp timestamp, delivery_timestamp timestamp, quantity int, unit_price numeric, total_price numeric, status text, notes text, bill_id text )
CREATE TABLE hospitality_technology.payments ( payment_id text PRIMARY KEY, reservation_id text, guest_id text, bill_id text, amount numeric, currency_code text, payment_method text, card_type text, card_last_four text, transaction_ref text, payment_timestamp timestamp, status text, staff_id_processed text, notes text )
CREATE TABLE hospitality_technology.reviews ( review_id text PRIMARY KEY, property_id text, reservation_id text, guest_id text, rating_overall int, rating_cleanliness int, rating_service int, rating_location int, rating_value int, comment text, review_source text, review_date timestamp, is_public boolean, staff_response text, response_staff_id text, response_date timestamp )


[User] Show the number of employees in each department.

[Assistant]
SELECT department, COUNT(*) AS employee_count
FROM financial_services.employees
group BY department;

[User] Exclude departments that have less than 3 employees.

[Assistant]
SELECT department, COUNT(*) AS employee_count
FROM financial_services.employees
group BY department
HAVING COUNT(*) >= 3;

[User] Can you also show the average hire_date for employees in each department?

[Assistant]
SELECT department, COUNT(*) AS employee_count, AVG(hire_date) AS average_hire_date
FROM financial_services.employees
group BY department
HAVING COUNT(*) >= 3;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE financial_services.accounts ( account_id text PRIMARY KEY, customer_id text, account_number text, account_type text, balance numeric, currency text, opened_date date, status text, interest_rate numeric, last_updated_at timestamp )
CREATE TABLE financial_services.transactions ( transaction_id text PRIMARY KEY, account_id text, related_account_id text, transaction_type text, amount numeric, currency text, transaction_date timestamp, effective_date date, description text, status text, reference_number text )
CREATE TABLE financial_services.trades ( trade_id text PRIMARY KEY, account_id text, security_id text, order_id text, trade_type text, quantity numeric, price_per_unit numeric, total_amount numeric, commission numeric, trade_timestamp timestamp, settlement_date date, status text, execution_venue text )
CREATE TABLE financial_services.market_data ( data_point_id bigserial PRIMARY KEY, security_id text, data_timestamp timestamp, open_price numeric, high_price numeric, low_price numeric, close_price numeric, adjusted_close_price numeric, volume bigint, source text )
CREATE TABLE financial_services.employees ( employee_id text PRIMARY KEY, first_name text, last_name text, job_title text, department text, branch_id text, email text, phone_extension text, hire_date date, termination_date date, manager_id text, status text )


[User] How many unique patient records are there for each gender?

[Assistant] SELECT gender, COUNT(DISTINCT patient_id) AS patient_count FROM healthcare.patients GROUP BY gender;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE healthcare.patients ( patient_id.text, first_name.text, last_name.text, date_of_birth.date, gender.text, address.text, phone_number.text, email.text, emergency_contact_name.text, emergency_contact_phone.text, created_at.timestamp, updated_at.timestamp )


[User] Show the contract address, symbol, and current total supply for all Avalanche tokens from token_balances_avalanche.

[Assistant]
SELECT tick AS contract_address, tick AS symbol, SUM(total_supply) AS current_total_supply
FROM token_balances_avalanche
GROUP BY tick;

[User] Now, include the latest price for each token by joining with token_prices_latest.

[Assistant]
SELECT tba.tick AS contract_address, tba.tick AS symbol, SUM(tba.total_supply) AS current_total_supply, tpl.price AS latest_price
FROM token_balances_avalanche tba
LEFT JOIN token_prices_latest tpl
  ON tpl.address = tba.tick AND tpl.blockchain = 'Avalanche'
GROUP BY tba.tick, tpl.price;

[User] Filter out tokens where the current_total_supply is less than 1000 and sort the results by latest_price descending.

[Assistant]
SELECT tba.tick AS contract_address, tba.tick AS symbol, SUM(tba.total_supply) AS current_total_supply, tpl.price AS latest_price
FROM token_balances_avalanche tba
LEFT JOIN token_prices_latest tpl
  ON tpl.address = tba.tick AND tpl.blockchain = 'Avalanche'
GROUP BY tba.tick, tpl.price
HAVING SUM(tba.total_supply) >= 1000
ORDER BY tpl.price DESC;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE token_metas ( block_timestamp.timestamp, block_number.bigint, transaction_hash.text, transaction_index.bigint, from_address.text, contract_address.text, symbol.text, total_supply.text, name.text, decimals.bigint, is_erc20.integer, is_erc721.integer, is_erc1155.integer, is_proxy.integer, extra_info.text, pk.integer )
CREATE TABLE erc1155_approval_for_all ( block_number.bigint, block_timestamp.timestamp, transaction_index.integer, transaction_hash.text, log_index.integer, contract_address.text )
CREATE TABLE nft_holders ( block_number.bigint, contract_address.text, wallet_address.text, token_id.text, contract_type.text, amount.text, pk.text )
CREATE TABLE nft_holder_historical ( block_number.bigint, contract_address.text, wallet_address.text, token_id.text, contract_type.text, amount.text, pk.integer )
CREATE TABLE sui_coins_metadata ( object_id.text, coin_type.text, status.text, decimals.bigint, description.text, icon_url.text, symbol.text, name.text )
CREATE TABLE sui_nfts ( object_id.text, status.text, collection_type.text, package_id.text, previous_transaction.text, display.text, owner.text, name.text )
CREATE TABLE nft_collections ( blockchain.text, contract_address.text, name.text, symbol.text, deploy_block_number.bigint, deploy_block_time.bigint, erc_type.text, owner.text, traits.text, description.text, slug.text, media_info.text, image_url.text, banner_image_url.text, updated_at.bigint, banner.text, token_count.bigint, floor_price.text, floor_price_symbol.text, floor_price_contract.text, pk.integer )
CREATE TABLE token_prices ( uuid.text, blockchain.text, address.text, decimals.bigint, symbol.text, price.real, timestamp.timestamp )
CREATE TABLE token_prices_latest ( blockchain.text, address.text, decimals.bigint, symbol.text, price.real, timestamp.timestamp )
CREATE TABLE token_balances_bitcoin ( block_number.bigint, block_timestamp.timestamp, tick.text, wallet_address.text, total_supply.text, amount.text )
CREATE TABLE token_balances_avalanche ( block_number.bigint, block_timestamp.timestamp, tick.text, wallet_address.text, total_supply.decimal, amount.decimal )


[User] How many lawyers who are partners were hired in each year? Show the hire year and the count.

[Assistant] SELECT strftime('%Y', hire_date) AS hire_year ,  count(lawyer_id) FROM legal_services.lawyers WHERE is_partner  =  true GROUP BY hire_year

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE legal_services.lawyers (
    lawyer_id character varying(64) NOT NULL,  -- unique identifier for the lawyer
    first_name character varying(100) NOT NULL, -- lawyer's first name
    last_name character varying(100) NOT NULL, -- lawyer's last name
    bar_number character varying(64) UNIQUE NOT NULL, -- lawyer's bar association number
    firm_id character varying(64), -- FK to law_firms table
    email character varying(128) UNIQUE NOT NULL, -- lawyer's professional email
    phone character varying(32), -- lawyer's contact phone number
    specialization text, -- areas of legal expertise
    hire_date timestamp NOT NULL, -- date the lawyer was hired or joined
    is_partner boolean DEFAULT false, -- flag indicating if the lawyer is a partner
    PRIMARY KEY (lawyer_id)
)


[User] List all properties that have at least one room with 'Ocean View' in its features, showing the property name and the total count of such rooms.

[Assistant] SELECT T1.property_name, COUNT(T2.room_id) FROM hospitality_technology.properties AS T1 JOIN hospitality_technology.rooms AS T2 ON T1.property_id = T2.property_id WHERE T2.features LIKE '%Ocean View%' GROUP BY T1.property_id;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE hospitality_technology.properties (
    property_id character varying(64) NOT NULL,  -- unique identifier for the property (hotel, resort, etc.)
    property_name character varying(255) NOT NULL, -- name of the property
    address_line1 character varying(255) NOT NULL, -- primary address line
    address_line2 character varying(255), -- secondary address line
    city character varying(100) NOT NULL, -- city
    state_province character varying(100), -- state or province
    postal_code character varying(20) NOT NULL, -- zip or postal code
    country_code character varying(3) NOT NULL, -- ISO country code (e.g., USA, CAN)
    phone_number character varying(30), -- main contact phone
    email_address character varying(255), -- main contact email
    property_type character varying(50) NOT NULL, -- e.g., Hotel, Resort, B&B, Motel
    star_rating numeric(2,1), -- star rating (e.g., 4.5)
    timezone character varying(64) NOT NULL, -- IANA timezone ID (e.g., America/New_York)
    manager_staff_id character varying(64), -- FK to staff table for the general manager
    created_at timestamp with time zone NOT NULL DEFAULT current_timestamp, -- record creation time
    updated_at timestamp with time zone NOT NULL DEFAULT current_timestamp, -- record last update time
    PRIMARY KEY (property_id)
)
CREATE TABLE hospitality_technology.rooms ( room_id.text, property_id.text, room_number.text, room_type_id.text, floor.integer, status.text, is_smoking.boolean, features.text, current_condition.text, last_cleaned_at.timestamp )
CREATE TABLE hospitality_technology.room_types ( room_type_id text PRIMARY KEY, property_id text, type_name text, description text, base_rate numeric, max_occupancy int, bed_type text, area_sqft numeric, amenities text )
CREATE TABLE hospitality_technology.guests ( guest_id character varying(64) NOT NULL, first_name character varying(100) NOT NULL, last_name character varying(100) NOT NULL, email character varying(255) UNIQUE, phone_number character varying(30), date_of_birth date, address_line1 character varying(255), city character varying(100), state_province character varying(100), postal_code character varying(20), country_code character varying(3), preferences text, loyalty_member_id character varying(64) UNIQUE, communication_consent boolean DEFAULT true, created_at timestamp with time zone NOT NULL DEFAULT current_timestamp, updated_at timestamp with time zone NOT NULL DEFAULT current_timestamp, PRIMARY KEY (guest_id) )
CREATE TABLE hospitality_technology.reservations ( reservation_id text PRIMARY KEY, property_id text, guest_id text, room_id text, room_type_id text, check_in_date date, check_out_date date, actual_check_in_ts timestamp, actual_check_out_ts timestamp, num_adults int, num_children int, status text, booking_source text, rate_plan_id text, total_amount numeric, amount_paid numeric, special_requests text, created_at timestamp, updated_at timestamp )
CREATE TABLE hospitality_technology.services ( service_id.text, property_id.text, service_name.text, description.text, category.text, price.numeric, unit.text, is_available.boolean, department.text )
CREATE TABLE hospitality_technology.reviews ( review_id text, property_id text, reservation_id text, guest_id text, rating_overall integer, rating_cleanliness integer, rating_service integer, rating_location integer, rating_value integer, comment text, review_source text, review_date timestamp, is_public boolean, staff_response text, response_staff_id text, response_date timestamp )


[User] What is the total and average amount of unspent UTXOs per address?

[Assistant]
SELECT
  address,
  COUNT(*) AS utxo_count,
  SUM(amount) AS total_unspent_amount,
  AVG(amount) AS average_unspent_amount
FROM trading_platform.utxos
WHERE spent = FALSE
GROUP BY address;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE trading_platform.orders ( order_id text PRIMARY KEY, user_id text, wallet_id text, asset_id text, order_type text, quantity numeric, price numeric, status text, created_at timestamp )
CREATE TABLE trading_platform.utxos ( utxo_id.text, transaction_id.text, output_index.integer, address.text, amount.numeric, spent.boolean )
CREATE TABLE trading_platform.dapps ( dapp_id character varying(64) NOT NULL, name character varying(128) NOT NULL, description text NOT NULL, url character varying(256) NOT NULL, PRIMARY KEY (dapp_id) )
CREATE TABLE trading_platform.logs ( log_id text PRIMARY KEY, user_id text, action text, details text, logged_at timestamp )


[User] List all managers (employees who are managers to someone else) showing their employee ID, first name, last name, and job title.

[Assistant]
SELECT DISTINCT m.employee_id, m.first_name, m.last_name, m.job_title
FROM government_services.employees e
JOIN government_services.employees m ON e.manager_employee_id = m.employee_id;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE government_services.employees ( employee_id.text, agency_id.text, first_name.text, last_name.text, job_title.text, department.text, work_email.text, work_phone.text, hire_date.date, termination_date.date, access_level.text, manager_employee_id.text )


[User] For each relationship type among policy beneficiaries, show the average percentage_share and the count of unique beneficiaries. Please order the results with the highest average percentage_share first.

[Assistant]
SELECT relationship, AVG(percentage_share) AS avg_percentage_share, COUNT(DISTINCT beneficiary_id) AS beneficiary_count
FROM insurance.policy_beneficiaries
GROUP BY relationship
ORDER BY avg_percentage_share DESC;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE insurance.policy_beneficiaries ( beneficiary_id.text, policy_id.text, customer_id.text, first_name.text, last_name.text, relationship.text, percentage_share.numeric, contact_info.text, added_at.timestamp )


[User] Which exchange holds the largest total USD value of the token with the highest 24h price increase in the 'AI' narrative, and what is that value?

[Assistant]
SELECT ctb.exchange, SUM(ctb.usd_value) AS total_usd_value
FROM token_basic_info tbi
JOIN cex_token_balance ctb ON tbi.token_address = ctb.token_address AND tbi.chain = ctb.chain
WHERE tbi.narrative = 'AI' AND tbi.token_symbol = (
    SELECT token_symbol
    FROM token_basic_info
    WHERE narrative = 'AI'
    ORDER BY price_change_percentage_24h DESC
    LIMIT 1
)
GROUP BY ctb.exchange
ORDER BY total_usd_value DESC
LIMIT 1;

[User] Actually, can you show the top 2 exchanges by total USD value instead of just the top one?

[Assistant]
SELECT ctb.exchange, SUM(ctb.usd_value) AS total_usd_value
FROM token_basic_info tbi
JOIN cex_token_balance ctb ON tbi.token_address = ctb.token_address AND tbi.chain = ctb.chain
WHERE tbi.narrative = 'AI' AND tbi.token_symbol = (
    SELECT token_symbol
    FROM token_basic_info
    WHERE narrative = 'AI'
    ORDER BY price_change_percentage_24h DESC
    LIMIT 1
)
GROUP BY ctb.exchange
ORDER BY total_usd_value DESC
LIMIT 2;

[User] Great, now also include the chain and current price of this token in the results.

[Assistant]
SELECT ctb.exchange, ctb.chain, SUM(ctb.usd_value) AS total_usd_value, tbi.price
FROM token_basic_info tbi
JOIN cex_token_balance ctb ON tbi.token_address = ctb.token_address AND tbi.chain = ctb.chain
WHERE tbi.narrative = 'AI' AND tbi.token_symbol = (
    SELECT token_symbol
    FROM token_basic_info
    WHERE narrative = 'AI'
    ORDER BY price_change_percentage_24h DESC
    LIMIT 1
)
GROUP BY ctb.exchange, ctb.chain, tbi.price
ORDER BY total_usd_value DESC
LIMIT 2;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE token_basic_info ( coin_id text, token_name text, token_symbol text, token_address text, chain text, price numeric, price_change_percentage_1h numeric, price_change_percentage_24h numeric, price_change_percentage_7d numeric, highest_price_24h numeric, lowest_price_24h numeric, market_cap numeric, market_cap_rank numeric, market_cap_change_percentage_24h text, total_volume text, narrative text, trend_rank numeric )
CREATE TABLE narrative_info ( narrative text, top_3_coins text, price_change_percentage_1h numeric, price_change_percentage_24h numeric, price_change_percentage_7d numeric, market_cap numeric, volume_24h numeric, trend_rank numeric, token_num numeric )
CREATE TABLE cex_token_balance ( snapshot_time text, chain text, address text, exchange text, token_address text, token_symbol text, balance numeric, usd_value numeric, price numeric )
CREATE TABLE smart_money_profit ( address text, rank numeric, profit numeric, roi numeric, realized_ratio numeric, most_profit_token text, last_trade_time text, chain text )
CREATE TABLE smart_money_token_inflow ( token_address text, token_symbol text, token_amount numeric, usd_value numeric, avg_price numeric, type numeric, address_amount numeric, narrative text, chain text )


[User] Show me all token names and their contract addresses along with the wallet addresses of users who created wallets in the last 30 days, sorted by wallet creation date.

[Assistant] SELECT t.token_name, t.contract_address, w.address AS wallet_address FROM web3.tokens t JOIN web3.wallets w ON 1=1 WHERE w.created_at >= CURRENT_DATE - INTERVAL '30 days' ORDER BY w.created_at;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE web3.tokens ( token_id character varying(64) NOT NULL, contract_address character varying(128) NOT NULL, token_name character varying(128) NOT NULL, token_symbol character varying(32) NOT NULL, decimals integer NOT NULL, total_supply numeric(38,14) NOT NULL, PRIMARY KEY (token_id) )
CREATE TABLE web3.wallets ( wallet_id character varying(64) NOT NULL, user_id character varying(64) NOT NULL, address character varying(128) NOT NULL, private_key text NOT NULL, created_at timestamp NOT NULL, PRIMARY KEY (wallet_id) )


[User] Count the number of unique locations specified in the users table.

[Assistant] SELECT count(DISTINCT location) FROM social_media.users WHERE location IS NOT NULL;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE social_media.users ( user_id character varying(64) NOT NULL, username character varying(50) NOT NULL UNIQUE, email character varying(128) NOT NULL UNIQUE, password_hash text NOT NULL, full_name character varying(100), profile_picture_url text, bio text, location character varying(100), created_at timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, updated_at timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, is_verified boolean NOT NULL DEFAULT false, PRIMARY KEY (user_id) )
CREATE TABLE social_media.posts ( post_id.text, user_id.text, content.text, media_url.text, media_type.text, created_at.timestamp, updated_at.timestamp, visibility.text, location_lat.numeric, location_lon.numeric )
CREATE TABLE social_media.comments ( comment_id text PRIMARY KEY, post_id text, user_id text, parent_comment_id text, content text, created_at timestamp, updated_at timestamp )
CREATE TABLE social_media.likes ( like_id text PRIMARY KEY, user_id text, post_id text, comment_id text, created_at timestamp )
CREATE TABLE social_media.conversations ( conversation_id character varying(64) NOT NULL, created_at timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, last_message_at timestamp, is_group_chat boolean NOT NULL DEFAULT false, group_name character varying(100), PRIMARY KEY (conversation_id) )
CREATE TABLE social_media.conversation_participants ( participant_id text PRIMARY KEY, conversation_id text, user_id text, joined_at timestamp, last_read_at timestamp )
CREATE TABLE social_media.notifications ( notification_id text, recipient_user_id text, sender_user_id text, notification_type text, target_entity_id text, target_entity_type text, created_at timestamp, read_at timestamp )


[User] List the usernames and email addresses of users who have participated in any conversation.

[Assistant] SELECT DISTINCT T1.username, T1.email FROM social_media.users AS T1 JOIN social_media.conversation_participants AS T2 ON T1.user_id = T2.user_id;

[User] Can you also include the time they joined their first conversation?

[Assistant] SELECT T1.username, T1.email, MIN(T2.joined_at) AS first_joined_at FROM social_media.users AS T1 JOIN social_media.conversation_participants AS T2 ON T1.user_id = T2.user_id GROUP BY T1.user_id, T1.username, T1.email;

[User] Only show users whose email ends with '.com' and joined after '2024-01-15'.

[Assistant] SELECT T1.username, T1.email, MIN(T2.joined_at) AS first_joined_at FROM social_media.users AS T1 JOIN social_media.conversation_participants AS T2 ON T1.user_id = T2.user_id WHERE T1.email LIKE '%.com' GROUP BY T1.user_id, T1.username, T1.email HAVING MIN(T2.joined_at) > '2024-01-15';

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE social_media.users ( user_id character varying(64) NOT NULL, username character varying(50) NOT NULL UNIQUE, email character varying(128) NOT NULL UNIQUE, password_hash text NOT NULL, full_name character varying(100), profile_picture_url text, bio text, location character varying(100), created_at timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, updated_at timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, is_verified boolean NOT NULL DEFAULT false, PRIMARY KEY (user_id) )
CREATE TABLE social_media.conversation_participants ( participant_id character varying(64) NOT NULL, conversation_id character varying(64) NOT NULL, user_id character varying(64) NOT NULL, joined_at timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, last_read_at timestamp, PRIMARY KEY (participant_id), CONSTRAINT unique_user_conversation UNIQUE (conversation_id, user_id) )


[User] List each claim_handler_id along with the number of claims they've handled and the total settlement_amount they've paid out.

[Assistant]
SELECT claim_handler_id,
       COUNT(*) AS total_claims,
       SUM(settlement_amount) AS total_settlement
FROM insurance.claims
GROUP BY claim_handler_id;

[User] In addition, include the claim_id of the single claim with the highest settlement_amount for each handler.

[Assistant]
SELECT ag.claim_handler_id,
       ag.total_claims,
       ag.total_settlement,
       c_max.claim_id               AS max_settlement_claim_id,
       c_max.settlement_amount      AS max_settlement_amount
FROM (
  SELECT claim_handler_id,
         COUNT(*) AS total_claims,
         SUM(settlement_amount) AS total_settlement
  FROM insurance.claims
  GROUP BY claim_handler_id
) ag
JOIN insurance.claims c_max
  ON c_max.claim_handler_id = ag.claim_handler_id
  AND c_max.settlement_amount = (
    SELECT MAX(settlement_amount)
    FROM insurance.claims
    WHERE claim_handler_id = ag.claim_handler_id
  );

[User] Only include handlers who have managed at least 3 claims and have a non-null claim_handler_id.

[Assistant]
SELECT ag.claim_handler_id,
       ag.total_claims,
       ag.total_settlement,
       c_max.claim_id               AS max_settlement_claim_id,
       c_max.settlement_amount      AS max_settlement_amount
FROM (
  SELECT claim_handler_id,
         COUNT(*) AS total_claims,
         SUM(settlement_amount) AS total_settlement
  FROM insurance.claims
  GROUP BY claim_handler_id
  HAVING COUNT(*) >= 3
     AND claim_handler_id IS NOT NULL
) ag
JOIN insurance.claims c_max
  ON c_max.claim_handler_id = ag.claim_handler_id
  AND c_max.settlement_amount = (
    SELECT MAX(settlement_amount)
    FROM insurance.claims
    WHERE claim_handler_id = ag.claim_handler_id
  );

[User] Finally, sort the results by total_settlement in descending order.

[Assistant]
SELECT ag.claim_handler_id,
       ag.total_claims,
       ag.total_settlement,
       c_max.claim_id               AS max_settlement_claim_id,
       c_max.settlement_amount      AS max_settlement_amount
FROM (
  SELECT claim_handler_id,
         COUNT(*) AS total_claims,
         SUM(settlement_amount) AS total_settlement
  FROM insurance.claims
  GROUP BY claim_handler_id
  HAVING COUNT(*) >= 3
     AND claim_handler_id IS NOT NULL
) ag
JOIN insurance.claims c_max
  ON c_max.claim_handler_id = ag.claim_handler_id
  AND c_max.settlement_amount = (
    SELECT MAX(settlement_amount)
    FROM insurance.claims
    WHERE claim_handler_id = ag.claim_handler_id
  )
ORDER BY ag.total_settlement DESC;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE insurance.claims (
    claim_id character varying(64) NOT NULL, -- unique identifier for the claim
    policy_id character varying(64) NOT NULL, -- identifier of the policy under which the claim is made (FK to policies)
    customer_id character varying(64) NOT NULL, -- identifier of the customer making the claim (FK to customers)
    incident_date timestamp NOT NULL, -- date and time of the incident leading to the claim
    reported_date timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, -- date the claim was reported
    description text NOT NULL, -- detailed description of the incident and claim
    estimated_loss numeric(15, 2), -- initial estimated cost of the loss
    status character varying(30) NOT NULL, -- e.g., Filed, Processing, Under Review, Approved, Denied, Settled
    settlement_amount numeric(15, 2), -- final amount paid out
    settlement_date date,
    claim_handler_id character varying(64), -- identifier for the employee handling the claim (FK to employees/adjusters)
    police_report_number character varying(100),
    PRIMARY KEY (claim_id)
)


[User] List the conversation IDs and user IDs for participants who have email notifications enabled.

[Assistant] SELECT cp.conversation_id, cp.user_id FROM social_media.conversation_participants AS cp JOIN social_media.user_settings AS us ON cp.user_id = us.user_id WHERE us.email_notifications_enabled = TRUE;

[User] Now, only include those users whose profile is set to private.

[Assistant] SELECT cp.conversation_id, cp.user_id FROM social_media.conversation_participants AS cp JOIN social_media.user_settings AS us ON cp.user_id = us.user_id WHERE us.email_notifications_enabled = TRUE AND us.private_profile = TRUE;

[User] Also, filter the results to include only participants who joined after a specific date, say '2023-01-01'.

[Assistant] SELECT cp.conversation_id, cp.user_id FROM social_media.conversation_participants AS cp JOIN social_media.user_settings AS us ON cp.user_id = us.user_id WHERE us.email_notifications_enabled = TRUE AND us.private_profile = TRUE AND cp.joined_at > '2023-01-01';

[User] Instead of user ID, can you show their theme setting and order the results by the join date ascending?

[Assistant] SELECT cp.conversation_id, us.theme, cp.joined_at FROM social_media.conversation_participants AS cp JOIN social_media.user_settings AS us ON cp.user_id = us.user_id WHERE us.email_notifications_enabled = TRUE AND us.private_profile = TRUE AND cp.joined_at > '2023-01-01' ORDER BY cp.joined_at ASC;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE social_media.comments (
    comment_id character varying(64) NOT NULL, -- unique identifier for the comment
    post_id character varying(64) NOT NULL, -- identifier of the post being commented on (FK to posts.post_id)
    user_id character varying(64) NOT NULL, -- identifier of the user who made the comment (FK to users.user_id)
    parent_comment_id character varying(64), -- identifier of the parent comment if it's a reply (FK to comments.comment_id)
    content text NOT NULL, -- textual content of the comment
    created_at timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, -- timestamp of comment creation
    updated_at timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, -- timestamp of last comment edit
    PRIMARY KEY (comment_id)
)
CREATE TABLE social_media.conversation_participants ( participant_id text, conversation_id text, user_id text, joined_at timestamp, last_read_at timestamp )
CREATE TABLE social_media.user_settings ( setting_id text, user_id text, theme text, email_notifications_enabled boolean, push_notifications_enabled boolean, private_profile boolean, updated_at timestamp )


[User] Show me the make and model of vehicles along with the route number and distance for all routes that are serviced by vehicles with a fuel_type of 'Electric'.

[Assistant]
SELECT v.make, v.model, r.route_number, r.distance_km
FROM transportation.vehicles v
JOIN transportation.routes r ON v.vehicle_id = r.route_id
WHERE v.fuel_type = 'Electric';

[User] Oops, I want to include the estimated duration for each route as well, and only show routes where the estimated duration is less than 90 minutes.

[Assistant]
SELECT v.make, v.model, r.route_number, r.distance_km, r.estimated_duration_minutes
FROM transportation.vehicles v
JOIN transportation.routes r ON v.vehicle_id = r.route_id
WHERE v.fuel_type = 'Electric' AND r.estimated_duration_minutes < 90;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE transportation.vehicles ( vehicle_id text, license_plate text, vin text, make text, model text, year integer, type text, capacity integer, fuel_type text, status text, depot_id text, acquisition_date date )
CREATE TABLE transportation.drivers (
    driver_id character varying(64) NOT NULL,  -- unique identifier for the driver
    employee_id character varying(64) NOT NULL UNIQUE, -- employee reference number
    first_name character varying(128) NOT NULL, -- driver's first name
    last_name character varying(128) NOT NULL, -- driver's last name
    license_number character varying(64) NOT NULL UNIQUE, -- driving license number
    license_expiry_date date NOT NULL, -- expiry date of the license
    contact_number character varying(32), -- phone number
    email character varying(128) UNIQUE, -- email address
    hire_date date NOT NULL, -- date the driver was hired
    status character varying(32) NOT NULL, -- e.g., Active, On Leave, Terminated
    PRIMARY KEY (driver_id)
)
CREATE TABLE transportation.routes ( route_id text PRIMARY KEY, route_number text, description text, origin_location_id text, destination_location_id text, distance_km numeric, estimated_duration_minutes int, type text )
CREATE TABLE transportation.maintenance_logs ( log_id.text, vehicle_id.text, service_date.date, odometer_reading.integer, service_type.text, description.text, cost.numeric, mechanic_name.text, next_service_due_date.date )
CREATE TABLE transportation.fuel_logs ( fuel_log_id text, vehicle_id text, trip_id text, log_timestamp timestamp, fuel_type text, quantity numeric, unit text, cost_per_unit numeric, total_cost numeric, odometer_reading integer, location_id text )


[User] List all distinct asset types from the assets table.

[Assistant]
SELECT DISTINCT type
FROM trading_platform.assets;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE trading_platform.users ( user_id.text, username.text, email.text, password_hash.text, created_at.timestamp )
CREATE TABLE trading_platform.assets ( asset_id text, name text, symbol text, type text )
CREATE TABLE trading_platform.utxos ( utxo_id text PRIMARY KEY, transaction_id text, output_index int, address text, amount numeric, spent boolean )
CREATE TABLE trading_platform.dapps ( dapp_id text, name text, description text, url text )
CREATE TABLE trading_platform.peers ( peer_id.text, ip_address.text, port.integer, last_seen.timestamp )
CREATE TABLE trading_platform.metadata ( metadata_id character varying(64) NOT NULL, asset_id character varying(64) NOT NULL, key character varying(128) NOT NULL, value text NOT NULL, PRIMARY KEY (metadata_id) )
CREATE TABLE trading_platform.kyc_audit ( kyc_audit_id.text, user_id.text, status.text, reviewed_at.timestamp )
CREATE TABLE trading_platform.logs ( log_id text PRIMARY KEY, user_id text, action text, details text, logged_at timestamp )
CREATE TABLE trading_platform.notifications ( notification_id text, user_id text, message text, sent_at timestamp, read_at timestamp )


[User] For each patient, show the total number of diagnoses they have received, along with their patient ID and the ID of their latest diagnosis. Join with the diagnoses table.

[Assistant]
SELECT patient_id, COUNT(diagnosis_id) AS diagnosis_count, MAX(diagnosis_id) AS latest_diagnosis_id
FROM healthcare.diagnoses
GROUP BY patient_id;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE healthcare.appointments ( appointment_id text, patient_id text, doctor_id text, appointment_time timestamp, duration_minutes integer, reason text, status text, location_id text, notes text, created_at timestamp )
CREATE TABLE healthcare.medical_records ( record_id text, patient_id text, appointment_id text, doctor_id text, record_date timestamp, chief_complaint text, present_illness_history text, past_medical_history text, physical_examination_notes text, assessment text, treatment_plan text, vitals text, created_at timestamp )
CREATE TABLE healthcare.diagnoses ( diagnosis_id text, record_id text, patient_id text, doctor_id text, diagnosis_code text, code_type text, description text, diagnosis_date date, status text, is_chronic boolean )
CREATE TABLE healthcare.medications ( medication_id text, medication_name text, generic_name text, manufacturer text, ndc_code text, description text )
CREATE TABLE healthcare.prescriptions ( prescription_id text, record_id text, patient_id text, doctor_id text, medication_id text, dosage text, frequency text, route text, start_date date, end_date date, quantity_dispensed numeric, refills_allowed integer, prescription_date timestamp )
CREATE TABLE healthcare.insurance_plans ( plan_id text, plan_name text, insurance_provider text, plan_type text, contact_phone text, website text )
CREATE TABLE healthcare.patient_insurance ( patient_insurance_id text, patient_id text, plan_id text, policy_number text, group_number text, subscriber_name text, effective_date date, expiration_date date, is_primary boolean )


[User] Show the usernames of all users who were created in 2024.

[Assistant]
SELECT username
FROM social_media.users
WHERE EXTRACT(YEAR FROM created_at) = 2024;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE social_media.users ( user_id text PRIMARY KEY, username text, email text, password_hash text, full_name text, profile_picture_url text, bio text, location text, created_at timestamp, updated_at timestamp, is_verified bool )
CREATE TABLE social_media.hashtags ( hashtag_id text PRIMARY KEY, tag_name text, created_at timestamp )
CREATE TABLE social_media.messages ( message_id text PRIMARY KEY, conversation_id text, sender_user_id text, content text, media_url text, media_type text, sent_at timestamp, read_at timestamp )
CREATE TABLE social_media.conversations ( conversation_id text PRIMARY KEY, created_at timestamp, last_message_at timestamp, is_group_chat bool, group_name text )
CREATE TABLE social_media.user_settings ( setting_id text PRIMARY KEY, user_id text, theme text, email_notifications_enabled bool, push_notifications_enabled bool, private_profile bool, updated_at timestamp )


[User] List all narratives with a negative 1-hour price change percentage and a trend rank below 50.

[Assistant] SELECT narrative, price_change_percentage_1h, trend_rank FROM narrative_info WHERE price_change_percentage_1h < 0 AND trend_rank < 50;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE narrative_info ( narrative character varying(512) NOT NULL, -- the id of narrative top_3_coins text, -- the top 3 tokens in the narrative price_change_percentage_1h double precision, -- change in value divided by the absolute price value of the original token price in 1 hour in the narrative price_change_percentage_24h double precision, -- change in value divided by the absolute price value of the original token price in 24 hours in the narrative price_change_percentage_7d double precision, -- change in value divided by the absolute price value of the original token price in 7 days in the narrative market_cap double precision, -- the market cap of the narrative volume_24h double precision, -- the trade volume of the narrative trend_rank bigint, -- the trending rank of the narrative, value 1 expresses the most popular narrative token_num bigint, -- total token number in the narrative ,PRIMARY KEY (narrative) )


[User] Could you please list the first and last names of all clients?

[Assistant] SELECT first_name, last_name FROM clients;

[User] Now, only show clients whose status is 'active'.

[Assistant] SELECT first_name, last_name FROM clients WHERE status = 'active';

[User] Please include their email address in the results as well.

[Assistant] SELECT first_name, last_name, email FROM clients WHERE status = 'active';

[User] Finally, order the list by the client's last name.

[Assistant] SELECT first_name, last_name, email FROM clients WHERE status = 'active' ORDER BY last_name;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE legal_services.clients ( client_id text, first_name text, last_name text, company_name text, email text, phone text, address text, date_registered timestamp, status text )
CREATE TABLE legal_services.lawyers ( lawyer_id text, first_name text, last_name text, bar_number text, firm_id text, email text, phone text, specialization text, hire_date timestamp, is_partner boolean )
CREATE TABLE legal_services.law_firms ( firm_id text, firm_name text, address text, phone text, website text, founded_date date, managing_partner_id text )
CREATE TABLE legal_services.documents ( document_id text, case_id text, document_name text, document_type text, storage_path text, uploaded_by_lawyer_id text, upload_timestamp timestamp, version integer, description text )
CREATE TABLE legal_services.time_entries ( entry_id text, case_id text, lawyer_id text, date_worked date, hours_spent numeric, billing_rate numeric, description text, is_billable boolean, is_billed boolean, invoice_id text, created_at timestamp )
CREATE TABLE legal_services.appointments ( appointment_id text, client_id text, lawyer_id text, case_id text, start_time timestamp, end_time timestamp, location text, subject text, notes text, status text, created_at timestamp )


[User] What is the average and maximum standard fee for services in each category?

[Assistant] SELECT category, AVG(standard_fee) AS avg_standard_fee, MAX(standard_fee) AS max_standard_fee FROM government_services.services GROUP BY category;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE government_services.services ( service_id text PRIMARY KEY, agency_id text, service_name text, description text, category text, eligibility_criteria text, standard_fee numeric, average_processing_time_days int, is_active boolean, online_application_url text )


[User] Count the number of users for each location where the location is not empty.

[Assistant] SELECT location, COUNT(user_id) FROM social_media.users WHERE location IS NOT NULL AND location != '' GROUP BY location;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE social_media.users ( user_id text PRIMARY KEY, username text, email text, password_hash text, full_name text, profile_picture_url text, bio text, location text, created_at timestamp, updated_at timestamp, is_verified bool )


[User] Show me all service orders that have a status of 'Pending'.

[Assistant] SELECT * FROM hospitality_technology.service_orders WHERE status = 'Pending';

[User] For these pending service orders, list the order ID and the name of the service requested.

[Assistant] SELECT so.order_id, s.service_name FROM hospitality_technology.service_orders so JOIN hospitality_technology.services s ON so.service_id = s.service_id WHERE so.status = 'Pending';

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE hospitality_technology.properties (
    property_id character varying(64) NOT NULL,  -- unique identifier for the property (hotel, resort, etc.)
    property_name character varying(255) NOT NULL, -- name of the property
    address_line1 character varying(255) NOT NULL, -- primary address line
    address_line2 character varying(255), -- secondary address line
    city character varying(100) NOT NULL, -- city
    state_province character varying(100), -- state or province
    postal_code character varying(20) NOT NULL, -- zip or postal code
    country_code character varying(3) NOT NULL, -- ISO country code (e.g., USA, CAN)
    phone_number character varying(30), -- main contact phone
    email_address character varying(255), -- main contact email
    property_type character varying(50) NOT NULL, -- e.g., Hotel, Resort, B&B, Motel
    star_rating numeric(2,1), -- star rating (e.g., 4.5)
    timezone character varying(64) NOT NULL, -- IANA timezone ID (e.g., America/New_York)
    manager_staff_id character varying(64), -- FK to staff table for the general manager
    created_at timestamp with time zone NOT NULL DEFAULT current_timestamp, -- record creation time
    updated_at timestamp with time zone NOT NULL DEFAULT current_timestamp, -- record last update time
    PRIMARY KEY (property_id)
)
CREATE TABLE hospitality_technology.rooms ( room_id text, property_id text, room_number text, room_type_id text, floor integer, status text, is_smoking boolean, features text, current_condition text, last_cleaned_at timestamp )
CREATE TABLE hospitality_technology.room_types ( room_type_id text, property_id text, type_name text, description text, base_rate numeric, max_occupancy integer, bed_type text, area_sqft numeric, amenities text )
CREATE TABLE hospitality_technology.guests ( guest_id character varying(64) NOT NULL, first_name character varying(100) NOT NULL, last_name character varying(100) NOT NULL, email character varying(255) UNIQUE, phone_number character varying(30), date_of_birth date, address_line1 character varying(255), city character varying(100), state_province character varying(100), postal_code character varying(20), country_code character varying(3), preferences text, loyalty_member_id character varying(64) UNIQUE, communication_consent boolean DEFAULT true, created_at timestamp with time zone NOT NULL DEFAULT current_timestamp, updated_at timestamp with time zone NOT NULL DEFAULT current_timestamp, PRIMARY KEY (guest_id) )
CREATE TABLE hospitality_technology.reservations ( reservation_id text PRIMARY KEY, property_id text, guest_id text, room_id text, room_type_id text, check_in_date date, check_out_date date, actual_check_in_ts timestamp, actual_check_out_ts timestamp, num_adults int, num_children int, status text, booking_source text, rate_plan_id text, total_amount numeric, amount_paid numeric, special_requests text, created_at timestamp, updated_at timestamp )
CREATE TABLE hospitality_technology.services ( service_id text PRIMARY KEY, property_id text, service_name text, description text, category text, price numeric, unit text, is_available boolean, department text )
CREATE TABLE hospitality_technology.service_orders ( order_id character varying(64) NOT NULL, reservation_id character varying(64), guest_id character varying(64) NOT NULL, service_id character varying(64) NOT NULL, staff_id_ordered character varying(64), staff_id_delivered character varying(64), order_timestamp timestamp with time zone NOT NULL DEFAULT current_timestamp, delivery_timestamp timestamp with time zone, quantity integer NOT NULL DEFAULT 1, unit_price numeric(10, 2) NOT NULL, total_price numeric(12, 2) NOT NULL, status character varying(50) NOT NULL, notes text, bill_id character varying(64), PRIMARY KEY (order_id), FOREIGN KEY (reservation_id) REFERENCES hospitality_technology.reservations(reservation_id), FOREIGN KEY (guest_id) REFERENCES hospitality_technology.guests(guest_id), FOREIGN KEY (service_id) REFERENCES hospitality_technology.services(service_id), FOREIGN KEY (staff_id_ordered) REFERENCES hospitality_technology.staff(staff_id), FOREIGN KEY (staff_id_delivered) REFERENCES hospitality_technology.staff(staff_id) )
CREATE TABLE hospitality_technology.payments ( payment_id character varying(64) NOT NULL, reservation_id character varying(64), guest_id character varying(64) NOT NULL, bill_id character varying(64), amount numeric(12,2) NOT NULL, currency_code character varying(3) NOT NULL, payment_method character varying(50) NOT NULL, card_type character varying(50), card_last_four character varying(4), transaction_ref character varying(128), payment_timestamp timestamp with time zone NOT NULL DEFAULT current_timestamp, status character varying(50) NOT NULL, staff_id_processed character varying(64), notes text, PRIMARY KEY (payment_id), FOREIGN KEY (reservation_id) REFERENCES hospitality_technology.reservations(reservation_id), FOREIGN KEY (guest_id) REFERENCES hospitality_technology.guests(guest_id), FOREIGN KEY (staff_id_processed) REFERENCES hospitality_technology.staff(staff_id) )
CREATE TABLE hospitality_technology.reviews ( review_id character varying(64) NOT NULL, property_id character varying(64) NOT NULL, reservation_id character varying(64) UNIQUE, guest_id character varying(64) NOT NULL, rating_overall integer, rating_cleanliness integer, rating_service integer, rating_location integer, rating_value integer, comment text, review_source character varying(100), review_date timestamp with time zone NOT NULL DEFAULT current_timestamp, is_public boolean DEFAULT true, staff_response text, response_staff_id character varying(64), response_date timestamp with time zone, PRIMARY KEY (review_id), FOREIGN KEY (property_id) REFERENCES hospitality_technology.properties(property_id), FOREIGN KEY (reservation_id) REFERENCES hospitality_technology.reservations(reservation_id), FOREIGN KEY (guest_id) REFERENCES hospitality_technology.guests(guest_id), FOREIGN KEY (response_staff_id) REFERENCES hospitality_technology.staff(staff_id) )


[User] Show me all customers (customer_id, first_name, last_name) who have both a personal loan (loan_type = 'Personal') and a high risk profile (risk_profile = 'High'), along with their loan details (loan_id, principal_amount).

[Assistant] SELECT c.customer_id, c.first_name, c.last_name, l.loan_id, l.principal_amount FROM financial_services.customers c JOIN financial_services.loans l ON c.customer_id = l.account_id WHERE c.risk_profile = 'High' AND l.loan_type = 'Personal';

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE financial_services.customers ( customer_id text PRIMARY KEY, first_name text, last_name text, date_of_birth date, ssn_hash text, address text, city text, state text, zip_code text, country text, email text, phone_number text, created_at timestamp, status text, risk_profile text )
CREATE TABLE financial_services.securities ( security_id text, ticker_symbol text, isin_code text, cusip_code text, security_name text, security_type text, exchange text, currency text, issuer_name text, sector text, last_updated timestamp )
CREATE TABLE financial_services.loans ( loan_id text, account_id text, loan_type text, principal_amount numeric, current_principal_balance numeric, interest_rate numeric, term_months integer, origination_date date, maturity_date date, monthly_payment numeric, collateral_description text, status text )


[User] Now, sort the results by the date opened, oldest first, and show only the top 10.

[Assistant] SELECT case_name, case_number, date_opened FROM legal_services.cases WHERE lead_lawyer_id = 'lawyer_abc' AND status = 'Open' AND case_type = 'Criminal' ORDER BY date_opened ASC LIMIT 10;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE legal_services.cases ( case_id.text, case_number.text, case_name.text, client_id.text, lead_lawyer_id.text, case_type.text, status.text, date_opened.timestamp, date_closed.timestamp, description.text, court_jurisdiction.text )