| // Copyright 2015 The Go Authors. All rights reserved. | |
| // Use of this source code is governed by a BSD-style | |
| // license that can be found in the LICENSE file. | |
| //go:build !windows && !plan9 | |
| // +build !windows,!plan9 | |
| package main | |
| import ( | |
| "syscall" | |
| "time" | |
| ) | |
| func init() { | |
| register("SignalExitStatus", SignalExitStatus) | |
| } | |
| func SignalExitStatus() { | |
| syscall.Kill(syscall.Getpid(), syscall.SIGTERM) | |
| // Should die immediately, but we've seen flakiness on various | |
| // systems (see issue 14063). It's possible that the signal is | |
| // being delivered to a different thread and we are returning | |
| // and exiting before that thread runs again. Give the program | |
| // a little while to die to make sure we pick up the signal | |
| // before we return and exit the program. The time here | |
| // shouldn't matter--we'll never really sleep this long. | |
| time.Sleep(time.Second) | |
| } | |