markdown
stringlengths
0
37k
code
stringlengths
1
33.3k
path
stringlengths
8
215
repo_name
stringlengths
6
77
license
stringclasses
15 values
Normalization For the sake of simplicity, we will use the 0-1 range normalization: $ x_i = \dfrac{x_i - min(x_i)}{max(x_i) - min(x_i)}$ This is allowed because we do not have that many 'outliers' in our features. The Alpha-Trimmed normalization or Standard Scaler normalization would be more appropriate if we introduced...
from sklearn.preprocessing import MinMaxScaler normalizer = MinMaxScaler().fit(X_tra) X_tra = normalizer.transform(X_tra) X_val = normalizer.transform(X_val) X_tst = normalizer.transform(X_tst)
notebooks/2016-11-01-dvro-feature-selection.ipynb
dvro/sf-open-data-analysis
mit
Feature Importance Variance Threshold
from sklearn.feature_selection import VarianceThreshold print X_tra.shape threshold=(.999 * (1 - .999)) sel = VarianceThreshold(threshold=threshold) X_tra = sel.fit(X_tra).transform(X_tra) X_val = sel.transform(X_val) X_tst = sel.transform(X_tst) print X_tra.shape removed_features_1 = np.array(columns)[np.where(sel.v...
notebooks/2016-11-01-dvro-feature-selection.ipynb
dvro/sf-open-data-analysis
mit
Correlation
plt.figure(figsize=(12,8)) sns.heatmap(df.corr('pearson'))
notebooks/2016-11-01-dvro-feature-selection.ipynb
dvro/sf-open-data-analysis
mit
features loc_x and loc_y are too correlated with latitude and longitude, respectively, for this reason, we'll delete lox_x and loc_y.
del df['loc_x'] del df['loc_y']
notebooks/2016-11-01-dvro-feature-selection.ipynb
dvro/sf-open-data-analysis
mit
Feature Importance (Trees) This can be done using sklearn.feature_selection.SelectFromModel, however, we do it by ourselves in order to get a better visualization of the process.
from sklearn.ensemble import RandomForestClassifier, ExtraTreesClassifier def feature_importance(X, y, feat_names, forest='random_forest', plot=False, print_=False): # Build a forest and compute the feature importances if forest == 'random_forest': forest = RandomForestClassifier(n_estimators=200, rand...
notebooks/2016-11-01-dvro-feature-selection.ipynb
dvro/sf-open-data-analysis
mit
Based on this results, we'll select the N features
selected_features_2 = np.array(selected_features_1)[indices[:sel_index]] selected_features_2
notebooks/2016-11-01-dvro-feature-selection.ipynb
dvro/sf-open-data-analysis
mit
It seems like the location and category features are more important than the date related features. On the date related features, the system also selected opened_dayofweek and opened_dayofmonth. Test Set
from sklearn.metrics import roc_curve, auc def find_cutoff(y_true, y_pred): fpr, tpr, threshold = roc_curve(y_true, y_pred) i = np.arange(len(tpr)) roc = pd.DataFrame({'tf' : pd.Series(tpr-(1-fpr), index=i), 'threshold' : pd.Series(threshold, index=i)}) roc_t = roc.ix[(roc.tf-0).abs().argsort()[:1]] ...
notebooks/2016-11-01-dvro-feature-selection.ipynb
dvro/sf-open-data-analysis
mit
Read in the list of questions There were 60 questions but due to a copy-paste error, there were some duplicates, so we only have 44 unique questions
# Read in the list of 60 questions AllQuestions = [] with open('questions60.csv', 'r') as csvfile: myreader = csv.reader(csvfile) for row in myreader: # the rstrip() removes blanks AllQuestions.append( row[0].rstrip() ) print('Found', len(AllQuestions), 'questions') questions = list(set(AllQuest...
notebooks/20Q/loadMechanicalTurkData.ipynb
jamesfolberth/NGC_STEM_camp_AWS
bsd-3-clause
Read in the training data The columns of X correspond to questions, and rows correspond to more data. The rows of y are the movie indices. The values of X are 1, -1 or 0 (see YesNoDict for encoding)
YesNoDict = { "Yes": 1, "No": -1, "Unsure": 0, "": 0 } # load from csv files X = [] y = [] with open('MechanicalTurkResults_149movies_X.csv','r') as csvfile: myreader = csv.reader(csvfile) for row in myreader: X.append( list(map(int,row)) ) with open('MechanicalTurkResults_149movies_y.csv','r') as csvfi...
notebooks/20Q/loadMechanicalTurkData.ipynb
jamesfolberth/NGC_STEM_camp_AWS
bsd-3-clause
Use the trained classifier to play a 20 questions game You can see the list of movies we trained on here: https://docs.google.com/spreadsheets/d/1-849aPzi8Su_c5HwwDFERrogXjvSaZFfp_y9MHeO1IA/edit?usp=sharing You may want to use from sklearn.tree import _tree and 'tree.DecisionTreeClassifier' with commands like tree_.chi...
# up to you
notebooks/20Q/loadMechanicalTurkData.ipynb
jamesfolberth/NGC_STEM_camp_AWS
bsd-3-clause
If you have used the Internet, you have probably seen videos of kittens unrolling toilet paper. And you might have wondered how long it would take a standard kitten to unroll 47 m of paper, the length of a standard roll. The interactions of the kitten and the paper rolls are complex. To keep things simple, let's assum...
Rmin = 0.02 # m Rmax = 0.055 # m Mcore = 15e-3 # kg Mroll = 215e-3 # kg L = 47 # m tension = 0.002 # N
examples/kitten.ipynb
AllenDowney/ModSimPy
mit
Rmin and Rmax are the minimum and maximum radius of the roll, respectively. Mcore is the weight of the core (the cardboard tube at the center) and Mroll is the total weight of the paper. L is the unrolled length of the paper. tension is the force the kitten applies by pulling on the loose end of the roll (I chose this ...
k = (Rmax**2 - Rmin**2) / 2 / L k
examples/kitten.ipynb
AllenDowney/ModSimPy
mit
Moment of Inertia To compute angular acceleration, we'll need the moment of inertia for the roll. At http://modsimpy.com/moment you can find moments of inertia for simple geometric shapes. I'll model the core as a "thin cylindrical shell", and the paper roll as a "thick-walled cylindrical tube with open ends". The mome...
def moment_of_inertia(r): """Moment of inertia for a roll of toilet paper. r: current radius of roll in meters returns: moment of inertia in kg m**2 """ Icore = Mcore * Rmin**2 Iroll = np.pi * rho_h / 2 * (r**4 - Rmin**4) return Icore + Iroll
examples/kitten.ipynb
AllenDowney/ModSimPy
mit
Icore is the moment of inertia of the core; Iroll is the moment of inertia of the paper. rho_h is the density of the paper in terms of mass per unit of area. To compute rho_h, we compute the area of the complete roll like this:
area = np.pi * (Rmax**2 - Rmin**2) area
examples/kitten.ipynb
AllenDowney/ModSimPy
mit
And divide the mass of the roll by that area.
rho_h = Mroll / area rho_h
examples/kitten.ipynb
AllenDowney/ModSimPy
mit
As an example, here's the moment of inertia for the complete roll.
moment_of_inertia(Rmax)
examples/kitten.ipynb
AllenDowney/ModSimPy
mit
As r decreases, so does I. Here's the moment of inertia when the roll is empty.
moment_of_inertia(Rmin)
examples/kitten.ipynb
AllenDowney/ModSimPy
mit
The way $I$ changes over time might be more of a problem than I have made it seem. In the same way that $F = m a$ only applies when $m$ is constant, $\tau = I \alpha$ only applies when $I$ is constant. When $I$ varies, we usually have to use a more general version of Newton's law. However, I believe that in this exa...
init = State(theta=0, omega=0, y=0, r=Rmax) init
examples/kitten.ipynb
AllenDowney/ModSimPy
mit
And here's a System object with the starting conditions and t_end.
system = System(init=init, t_end=120)
examples/kitten.ipynb
AllenDowney/ModSimPy
mit
You can take it from here. Exercise: Write a slope function we can use to simulate this system. Test it with the initial conditions. The results should be approximately 0.0, 0.294, 0.0, 0.0
# Solution goes here # Solution goes here
examples/kitten.ipynb
AllenDowney/ModSimPy
mit
Exercise: Write an event function that stops the simulation when y equals L, that is, when the entire roll is unrolled. Test your function with the initial conditions.
# Solution goes here # Solution goes here
examples/kitten.ipynb
AllenDowney/ModSimPy
mit
Now run the simulation.
# Solution goes here
examples/kitten.ipynb
AllenDowney/ModSimPy
mit
And check the results.
results.tail()
examples/kitten.ipynb
AllenDowney/ModSimPy
mit
The final value of theta should be about 200 rotations, the same as in Chapter 24. The final value of omega should be about 63 rad/s, which is about 10 revolutions per second. That's pretty fast, but it might be plausible. The final value of y should be L, which is 47 m. The final value of r should be Rmin, which is 0...
results.theta.plot(color='C0', label='theta') decorate(xlabel='Time (s)', ylabel='Angle (rad)')
examples/kitten.ipynb
AllenDowney/ModSimPy
mit
Angular velocity, omega, increases almost linearly at first, as constant force yields almost constant torque. Then, as the radius decreases, the lever arm decreases, yielding lower torque, but moment of inertia decreases even more, yielding higher angular acceleration.
results.omega.plot(color='C2', label='omega') decorate(xlabel='Time (s)', ylabel='Angular velocity (rad/s)')
examples/kitten.ipynb
AllenDowney/ModSimPy
mit
y increases slowly and then accelerates.
results.y.plot(color='C1', label='y') decorate(xlabel='Time (s)', ylabel='Length (m)')
examples/kitten.ipynb
AllenDowney/ModSimPy
mit
r decreases slowly, then accelerates.
results.r.plot(color='C4', label='r') decorate(xlabel='Time (s)', ylabel='Radius (m)')
examples/kitten.ipynb
AllenDowney/ModSimPy
mit
Show available processes
for process in wps.processes: print process.identifier,":", process.title
wps-cfchecker.ipynb
cehbrecht/demo-notebooks
apache-2.0
Show details about qa_cfchecker process
process = wps.describeprocess(identifier='qa_cfchecker') for inp in process.dataInputs: print inp.identifier, ":", inp.title, ":", inp.dataType
wps-cfchecker.ipynb
cehbrecht/demo-notebooks
apache-2.0
Check file available on http service
inputs = [('dataset', 'http://bovec.dkrz.de:8090/wpsoutputs/hummingbird/output-b9855b08-42d8-11e6-b10f-abe4891050e3.nc')] execution = wps.execute(identifier='qa_cfchecker', inputs=inputs, output='output', async=False) print execution.status for out in execution.processOutputs: print out.title, out.reference
wps-cfchecker.ipynb
cehbrecht/demo-notebooks
apache-2.0
Prepare local file to send to service To send a local file with the request the file needs to be base64 encoded.
from owslib.wps import ComplexDataInput import base64 fp = open("/home/pingu/tmp/input2.nc", 'r') text = fp.read() fp.close() encoded = base64.b64encode(text) content = ComplexDataInput(encoded) inputs = [ ('dataset', content) ] execution = wps.execute(identifier='qa_cfchecker', inputs=inputs, output='output', async=F...
wps-cfchecker.ipynb
cehbrecht/demo-notebooks
apache-2.0
The figure below illustrates the terminology: <a ><img src = "https://ibm.box.com/shared/static/wsl6jcfld2c3171ob19vjr5chw9gyxrc.png" width = 500, align = "center"></a> <h4 align=center> A labeled function </h4> We can obtain help about a function :
help(add)
coursera/python_for_data_science/3.3_Functions.ipynb
mohanprasath/Course-Work
gpl-3.0
We can call the function:
add(1)
coursera/python_for_data_science/3.3_Functions.ipynb
mohanprasath/Course-Work
gpl-3.0
If we call the function with a new input we get a new result:
add(2)
coursera/python_for_data_science/3.3_Functions.ipynb
mohanprasath/Course-Work
gpl-3.0
We can create different functions. For example, we can create a function that multiplies two numbers. The numbers will be represented by the variables a and b:
def Mult(a,b): c=a*b return(c)
coursera/python_for_data_science/3.3_Functions.ipynb
mohanprasath/Course-Work
gpl-3.0
The same function can be used for different data types. For example, we can multiply two integers:
Mult(2,3)
coursera/python_for_data_science/3.3_Functions.ipynb
mohanprasath/Course-Work
gpl-3.0
Two Floats:
Mult(10,3.14)
coursera/python_for_data_science/3.3_Functions.ipynb
mohanprasath/Course-Work
gpl-3.0
We can even replicate a string by multiplying with an integer:
Mult(2,"Michael Jackson ")
coursera/python_for_data_science/3.3_Functions.ipynb
mohanprasath/Course-Work
gpl-3.0
Come up with a function that divides the first input by the second input:
def divide_values(a, b): return a / b
coursera/python_for_data_science/3.3_Functions.ipynb
mohanprasath/Course-Work
gpl-3.0
<div align="right"> <a href="#q1" class="btn btn-default" data-toggle="collapse">Click here for the solution</a> </div> <div id="q1" class="collapse"> ``` def div(a,b): return(a/b) ``` </div> <h3>Variables </h3> The input to a function is called a formal parameter. A variable that is declared inside a function i...
#Function Definition def square(a): """Square the input and add one """ #Local variable b=1 c=a*a+b; print(a, "if you square +1 ",c) return(c)
coursera/python_for_data_science/3.3_Functions.ipynb
mohanprasath/Course-Work
gpl-3.0
The labels are displayed in the figure: <a ><img src = "https://ibm.box.com/shared/static/gpfa525nnfwxt5rhrvd3o6i8rp2iwsai.png" width = 500, align = "center"></a> <h4 align=center> Figure 2: A function with labeled variables </h4> We can call the function with an input of 3:
#Initializes Global variable x=3 #Makes function call and return function a y z=square(x) z
coursera/python_for_data_science/3.3_Functions.ipynb
mohanprasath/Course-Work
gpl-3.0
We can call the function with an input of 2 in a different manner:
square(2)
coursera/python_for_data_science/3.3_Functions.ipynb
mohanprasath/Course-Work
gpl-3.0
If there is no return statement, the function returns None. The following two functions are equivalent:
def MJ(): print('Michael Jackson') def MJ1(): print('Michael Jackson') return(None) MJ() MJ1()
coursera/python_for_data_science/3.3_Functions.ipynb
mohanprasath/Course-Work
gpl-3.0
Printing the function after a call reveals a None is the default return statement:
print(MJ()) print(MJ1())
coursera/python_for_data_science/3.3_Functions.ipynb
mohanprasath/Course-Work
gpl-3.0
Create a function con that concatenates two strings using the addition operation: :
def con(a,b): return(a+b)
coursera/python_for_data_science/3.3_Functions.ipynb
mohanprasath/Course-Work
gpl-3.0
<div align="right"> <a href="#q2" class="btn btn-default" data-toggle="collapse">Click here for the solution</a> </div> <div id="q2" class="collapse"> ``` def div(a,b): return(a+b) ``` </div> Can the same function be used to add to integers or strings?
print(con(1, 2)) print(con('1', '2'))
coursera/python_for_data_science/3.3_Functions.ipynb
mohanprasath/Course-Work
gpl-3.0
<div align="right"> <a href="#q3" class="btn btn-default" data-toggle="collapse">Click here for the solution</a> </div> <div id="q3" class="collapse"> ``` yes,for example: con(2,2) ``` </div> Can the same function be used to concentrate a list or tuple?
print(con([1], [2]))
coursera/python_for_data_science/3.3_Functions.ipynb
mohanprasath/Course-Work
gpl-3.0
<div align="right"> <a href="#q4" class="btn btn-default" data-toggle="collapse">Click here for the solution</a> </div> <div id="q4" class="collapse"> ``` yes,for example: con(['a',1],['b',1]) ``` </div> <h3><b>Pre-defined functions</b></h3> There are many pre-defined functions in Python, so let's start with the si...
album_ratings = [10.0,8.5,9.5,7.0,7.0,9.5,9.0,9.5] print(album_ratings)
coursera/python_for_data_science/3.3_Functions.ipynb
mohanprasath/Course-Work
gpl-3.0
The sum() function adds all the elements in a list or tuple:
sum(album_ratings)
coursera/python_for_data_science/3.3_Functions.ipynb
mohanprasath/Course-Work
gpl-3.0
The length function returns the length of a list or tuple:
len(album_ratings)
coursera/python_for_data_science/3.3_Functions.ipynb
mohanprasath/Course-Work
gpl-3.0
<div class="alert alert-success alertsuccess" style="margin-top: 20px"> <h4> [Tip] How do I learn more about the pre-defined functions in Python? </h4> <p></p> We will be introducing a variety of **pre-defined functions** to you as you learn more about Python. There are just too many functions, so there's no way we can...
a1=4; b1=5; c1=a1+b1+2*a1*b1-1 if(c1<0): c1=0; else: c1=5; c1
coursera/python_for_data_science/3.3_Functions.ipynb
mohanprasath/Course-Work
gpl-3.0
Block 2:
a2=0; b2=0; c2=a2+b2+2*a2*b2-1 if(c2<0): c2=0; else: c2=5; c2
coursera/python_for_data_science/3.3_Functions.ipynb
mohanprasath/Course-Work
gpl-3.0
We can replace the lines of code with a function. A function combines many instructions into a single line of code. Once a function is defined, it can be used repeatedly. You can invoke the same function many times in your program. You can save your function and use it in another program or use someone else’s function....
def Equation(a,b): c=a+b+2*a*b-1 if(c<0): c=0 else: c=5 return(c)
coursera/python_for_data_science/3.3_Functions.ipynb
mohanprasath/Course-Work
gpl-3.0
This function takes two inputs, a and b, then applies several operations to return c. We simply define the function, replace the instructions with the function, and input the new values of a1,b1 and a2,b2 as inputs. The entire process is demonstrated in the figure: <a ><img src = "https://ibm.box.com/shared/static/ef...
a1=4; b1=5; c1=Equation(a1,b1) c1
coursera/python_for_data_science/3.3_Functions.ipynb
mohanprasath/Course-Work
gpl-3.0
Block 4:
a2=0; b2=0; c2=Equation(a2,b2) c2
coursera/python_for_data_science/3.3_Functions.ipynb
mohanprasath/Course-Work
gpl-3.0
<hr> <a id='ref3'></a> <center><h2>Using if/else statements and loops in functions</h2></center> The return() function is particularly useful if you have any IF statements in the function, when you want your output to be dependent on some condition:
def type_of_album(artist,album,year_released): if year_released > 1980: print(artist,album,year_released) return "Modern" else: print(artist,album,year_released) return "Oldie" x = type_of_album("Michael Jackson","Thriller",1980) print(x)
coursera/python_for_data_science/3.3_Functions.ipynb
mohanprasath/Course-Work
gpl-3.0
We can use a loop in a function. For example, we can print out each element in a list:
def PrintList(the_list): for element in the_list: print(element) PrintList(['1',1,'the man',"abc"])
coursera/python_for_data_science/3.3_Functions.ipynb
mohanprasath/Course-Work
gpl-3.0
<hr> <a id='ref4'></a> <center><h2>Setting default argument values in your custom functions</h2></center> You can set a default value for arguments in your function. For example, in the isGoodRating() function, what if we wanted to create a threshold for what we consider to be a good rating? Perhaps by default, we sho...
def isGoodRating(rating=4): if(rating < 7): print("this album sucks it's rating is",rating) else: print("this album is good its rating is",rating)
coursera/python_for_data_science/3.3_Functions.ipynb
mohanprasath/Course-Work
gpl-3.0
<hr>
isGoodRating() isGoodRating(10)
coursera/python_for_data_science/3.3_Functions.ipynb
mohanprasath/Course-Work
gpl-3.0
<a id='ref6'></a> <center><h2>Global variables</h2></center> <br> So far, we've been creating variables within functions, but we have not discussed variables outside the function. These are called global variables. <br> Let's try to see what printer1 returns:
artist = "Michael Jackson" def printer1(artist): internal_var = artist print(artist,"is an artist") printer1(artist)
coursera/python_for_data_science/3.3_Functions.ipynb
mohanprasath/Course-Work
gpl-3.0
If we print internal_var we get an error. We got a Name Error: name 'internal_var' is not defined. Why? It's because all the variables we create in the function is a local variable, meaning that the variable assignment does not persist outside the function. But there is a way to create global variables from withi...
artist = "Michael Jackson" def printer(artist): global internal_var internal_var= "Whitney Houston" print(artist,"is an artist") printer(artist) printer(internal_var)
coursera/python_for_data_science/3.3_Functions.ipynb
mohanprasath/Course-Work
gpl-3.0
<a id='ref7'></a> <center><h2>Scope of a Variable</h2></center> <hr> The scope of a variable is the part of that program where that variable is accessible. Variables that are declared outside of all function definitions, such as the myFavouriteBand variable in the code shown here, are accessible from anywhere within t...
myFavouriteBand = "AC/DC" def getBandRating(bandname): if bandname == myFavouriteBand: return 10.0 else: return 0.0 print("AC/DC's rating is:", getBandRating("AC/DC")) print("Deep Purple's rating is:",getBandRating("Deep Purple")) print("My favourite band is:", myFavouriteBand)
coursera/python_for_data_science/3.3_Functions.ipynb
mohanprasath/Course-Work
gpl-3.0
Take a look at this modified version of our code. Now the myFavouriteBand variable is defined within the getBandRating function. A variable that is defined within a function is said to be a local variable of that function. That means that it is only accessible from within the function in which it is defined. Our getBan...
def getBandRating(bandname): myFavouriteBand = "AC/DC" if bandname == myFavouriteBand: return 10.0 else: return 0.0 print("AC/DC's rating is: ", getBandRating("AC/DC")) print("Deep Purple's rating is: ", getBandRating("Deep Purple")) print("My favourite band is", myFavouriteBand)
coursera/python_for_data_science/3.3_Functions.ipynb
mohanprasath/Course-Work
gpl-3.0
Finally, take a look at this example. We now have two myFavouriteBand variable definitions. The first one of these has a global scope, and the second of them is a local variable within the getBandRating function. Within the getBandRating function, the local variable takes precedence. Deep Purple will receive a rating o...
myFavouriteBand = "AC/DC" def getBandRating(bandname): myFavouriteBand = "Deep Purple" if bandname == myFavouriteBand: return 10.0 else: return 0.0 print("AC/DC's rating is:",getBandRating("AC/DC")) print("Deep Purple's rating is: ",getBandRating("Deep Purple")) print("My favourite band is...
coursera/python_for_data_science/3.3_Functions.ipynb
mohanprasath/Course-Work
gpl-3.0
You might be tempted to encode this data with a straightforward numerical mapping:
{'Queen Anne': 1, 'Fremont': 2, 'Wallingford': 3}; # It turns out that this is not generally a useful approach
code/09.04-Feature-Engineering.ipynb
computational-class/cjc2016
mit
A fundamental assumption: numerical features reflect algebraic quantities. Queen Anne < Fremont < Wallingford Wallingford - Queen Anne = Fremont It does not make much sense. One-hot encoding (Dummy coding) effectively creates extra columns indicating the presence or absence of a category with a value of 1 or 0, respe...
from sklearn.feature_extraction import DictVectorizer vec = DictVectorizer(sparse=False, dtype=int ) vec.fit_transform(data)
code/09.04-Feature-Engineering.ipynb
computational-class/cjc2016
mit
Notice the 'neighborhood' column has been expanded into three separate columns (why not four?) representing the three neighborhood labels, and that each row has a 1 in the column associated with its neighborhood. To see the meaning of each column, you can inspect the feature names:
vec.get_feature_names()
code/09.04-Feature-Engineering.ipynb
computational-class/cjc2016
mit
There is one clear disadvantage of this approach: - if your category has many possible values, this can greatly increase the size of your dataset. - However, because the encoded data contains mostly zeros, a sparse output can be a very efficient solution:
vec = DictVectorizer(sparse=True, dtype=int) vec.fit_transform(data)
code/09.04-Feature-Engineering.ipynb
computational-class/cjc2016
mit
Many (though not yet all) of the Scikit-Learn estimators accept such sparse inputs when fitting and evaluating models. two additional tools that Scikit-Learn includes to support this type of encoding: - sklearn.preprocessing.OneHotEncoder - sklearn.feature_extraction.FeatureHasher Text Features Another common need in...
sample = ['problem of evil', 'evil queen', 'horizon problem']
code/09.04-Feature-Engineering.ipynb
computational-class/cjc2016
mit
For a vectorization of this data based on word count, we could construct a column representing the word "problem," the word "evil," the word "horizon," and so on. While doing this by hand would be possible, the tedium can be avoided by using Scikit-Learn's CountVectorizer:
from sklearn.feature_extraction.text import CountVectorizer vec = CountVectorizer() X = vec.fit_transform(sample) X
code/09.04-Feature-Engineering.ipynb
computational-class/cjc2016
mit
The result is a sparse matrix recording the number of times each word appears; it is easier to inspect if we convert this to a DataFrame with labeled columns:
import pandas as pd pd.DataFrame(X.toarray(), columns=vec.get_feature_names())
code/09.04-Feature-Engineering.ipynb
computational-class/cjc2016
mit
Problem: The raw word counts put too much weight on words that appear very frequently. term frequency-inverse document frequency (TF–IDF) weights the word counts by a measure of how often they appear in the documents. The syntax for computing these features is similar to the previous example:
from sklearn.feature_extraction.text import TfidfVectorizer vec = TfidfVectorizer() X = vec.fit_transform(sample) pd.DataFrame(X.toarray(), columns=vec.get_feature_names())
code/09.04-Feature-Engineering.ipynb
computational-class/cjc2016
mit
For an example of using TF-IDF in a classification problem, see In Depth: Naive Bayes Classification. Image Features The simplest approach is what we used for the digits data in Introducing Scikit-Learn: simply using the pixel values themselves. - But depending on the application, such approaches may not be optimal. - ...
%matplotlib inline import numpy as np import matplotlib.pyplot as plt x = np.array([1, 2, 3, 4, 5]) y = np.array([4, 2, 1, 3, 7]) plt.scatter(x, y);
code/09.04-Feature-Engineering.ipynb
computational-class/cjc2016
mit
Still, we can fit a line to the data using LinearRegression and get the optimal result:
from sklearn.linear_model import LinearRegression X = x[:, np.newaxis] model = LinearRegression().fit(X, y) yfit = model.predict(X) plt.scatter(x, y) plt.plot(x, yfit);
code/09.04-Feature-Engineering.ipynb
computational-class/cjc2016
mit
We need a more sophisticated model to describe the relationship between $x$ and $y$. - One approach to this is to transform the data, - adding extra columns of features to drive more flexibility in the model. For example, we can add polynomial features to the data this way:
from sklearn.preprocessing import PolynomialFeatures poly = PolynomialFeatures(degree=3, include_bias=False) X2 = poly.fit_transform(X) print(X2)
code/09.04-Feature-Engineering.ipynb
computational-class/cjc2016
mit
The derived feature matrix has one column representing $x$, and a second column representing $x^2$, and a third column representing $x^3$. Computing a linear regression on this expanded input gives a much closer fit to our data:
model = LinearRegression().fit(X2, y) yfit = model.predict(X2) plt.scatter(x, y) plt.plot(x, yfit);
code/09.04-Feature-Engineering.ipynb
computational-class/cjc2016
mit
This idea of improving a model not by changing the model, but by transforming the inputs, is fundamental to many of the more powerful machine learning methods. We explore this idea further in In Depth: Linear Regression in the context of basis function regression. More generally, this is one motivational path to th...
from numpy import nan X = np.array([[ nan, 0, 3 ], [ 3, 7, 9 ], [ 3, 5, 2 ], [ 4, nan, 6 ], [ 8, 8, 1 ]]) y = np.array([14, 16, -1, 8, -5])
code/09.04-Feature-Engineering.ipynb
computational-class/cjc2016
mit
When applying a typical machine learning model to such data, we will need to first replace such missing data with some appropriate fill value. This is known as imputation of missing values - simple method, e.g., replacing missing values with the mean of the column - sophisticated method, e.g., using matrix completion o...
from sklearn.preprocessing import Imputer imp = Imputer(strategy='mean') X2 = imp.fit_transform(X) X2
code/09.04-Feature-Engineering.ipynb
computational-class/cjc2016
mit
We see that in the resulting data, the two missing values have been replaced with the mean of the remaining values in the column. This imputed data can then be fed directly into, for example, a LinearRegression estimator:
model = LinearRegression().fit(X2, y) model.predict(X2)
code/09.04-Feature-Engineering.ipynb
computational-class/cjc2016
mit
Feature Pipelines With any of the preceding examples, it can quickly become tedious to do the transformations by hand, especially if you wish to string together multiple steps. For example, we might want a processing pipeline that looks something like this: Impute missing values using the mean Transform features to qu...
from sklearn.pipeline import make_pipeline model = make_pipeline(Imputer(strategy='mean'), PolynomialFeatures(degree=2), LinearRegression())
code/09.04-Feature-Engineering.ipynb
computational-class/cjc2016
mit
This pipeline looks and acts like a standard Scikit-Learn object, and will apply all the specified steps to any input data.
model.fit(X, y) # X with missing values, from above print(y) print(model.predict(X))
code/09.04-Feature-Engineering.ipynb
computational-class/cjc2016
mit
Use the following function to plot out the parameters of the Softmax function:
def PlotParameters(model): W=model.state_dict() ['linear.weight'].data w_min=W.min().item() w_max=W.max().item() fig, axes = plt.subplots(2, 5) fig.subplots_adjust(hspace=0.01, wspace=0.1) for i,ax in enumerate(axes.flat): if i<10: # Set the label for the sub-plot. ...
DL0110EN/3.3.2lab_predicting _MNIST_using_Softmax.ipynb
atlury/deep-opencl
lgpl-3.0
Use the following function to visualize the data:
def show_data(data_sample): plt.imshow(data_sample[0].numpy().reshape(28,28),cmap='gray') #print(data_sample[1].item()) plt.title('y= '+ str(data_sample[1].item()))
DL0110EN/3.3.2lab_predicting _MNIST_using_Softmax.ipynb
atlury/deep-opencl
lgpl-3.0
<a id="ref1"></a> <h2 align=center>Prepare Data </h2> Load the training dataset by setting the parameters <code>train</code> to <code>True</code> and convert it to a tensor by placing a transform object in the argument <code>transform</code>.
train_dataset=dsets.MNIST(root='./data', train=True, download=True, transform=transforms.ToTensor()) train_dataset
DL0110EN/3.3.2lab_predicting _MNIST_using_Softmax.ipynb
atlury/deep-opencl
lgpl-3.0
Load the testing dataset by setting the parameters train <code>False</code> and convert it to a tensor by placing a transform object in the argument <code>transform</code>.
validation_dataset=dsets.MNIST(root='./data', train=False, download=True, transform=transforms.ToTensor()) validation_dataset
DL0110EN/3.3.2lab_predicting _MNIST_using_Softmax.ipynb
atlury/deep-opencl
lgpl-3.0
You can see that the data type is long:
train_dataset[0][1].type()
DL0110EN/3.3.2lab_predicting _MNIST_using_Softmax.ipynb
atlury/deep-opencl
lgpl-3.0
Data Visualization Each element in the rectangular tensor corresponds to a number that represents a pixel intensity as demonstrated by the following image: <img src = "https://ibm.box.com/shared/static/7024mnculm8w2oh0080y71cpa48cib2k.png" width = 550, align = "center"></a> Print out the third label:
train_dataset[3][1]
DL0110EN/3.3.2lab_predicting _MNIST_using_Softmax.ipynb
atlury/deep-opencl
lgpl-3.0
Plot the 3rd sample:
show_data(train_dataset[3])
DL0110EN/3.3.2lab_predicting _MNIST_using_Softmax.ipynb
atlury/deep-opencl
lgpl-3.0
You see that it is a 1. Now, plot the second sample:
show_data(train_dataset[2])
DL0110EN/3.3.2lab_predicting _MNIST_using_Softmax.ipynb
atlury/deep-opencl
lgpl-3.0
<a id="ref3"></a> Build a Softmax Classifer Build a Softmax classifier class:
class SoftMax(nn.Module): def __init__(self,input_size,output_size): super(SoftMax,self).__init__() self.linear=nn.Linear(input_size,output_size) def forward(self,x): z=self.linear(x) return z
DL0110EN/3.3.2lab_predicting _MNIST_using_Softmax.ipynb
atlury/deep-opencl
lgpl-3.0
The Softmax function requires vector inputs. Note that the vector shape is 28x28.
train_dataset[0][0].shape
DL0110EN/3.3.2lab_predicting _MNIST_using_Softmax.ipynb
atlury/deep-opencl
lgpl-3.0
Flatten the tensor as shown in this image: <img src = "https://ibm.box.com/shared/static/0cjl5inks3d8ay0sckgywowc3hw2j1sa.gif" width = 550, align = "center"></a> The size of the tensor is now 784. <img src = "https://ibm.box.com/shared/static/lhezcvgm82gtdewooueopxp98ztq2pbv.png" width = 550, align = "center"></a> Se...
input_dim=28*28 output_dim=10 input_dim
DL0110EN/3.3.2lab_predicting _MNIST_using_Softmax.ipynb
atlury/deep-opencl
lgpl-3.0
<a id="ref3"></a> <h2> Define the Softmax Classifier, Criterion Function, Optimizer, and Train the Model</h2>
model=SoftMax(input_dim,output_dim) model
DL0110EN/3.3.2lab_predicting _MNIST_using_Softmax.ipynb
atlury/deep-opencl
lgpl-3.0
View the size of the model parameters:
print('W:',list(model.parameters())[0].size()) print('b',list(model.parameters())[1].size())
DL0110EN/3.3.2lab_predicting _MNIST_using_Softmax.ipynb
atlury/deep-opencl
lgpl-3.0
You can cover the model parameters for each class to a rectangular grid: <a> <img src = "https://ibm.box.com/shared/static/9cuuwsvhwygbgoogmg464oht1o8ubkg2.gif" width = 550, align = "center"></a> Plot the model parameters for each class:
PlotParameters(model)
DL0110EN/3.3.2lab_predicting _MNIST_using_Softmax.ipynb
atlury/deep-opencl
lgpl-3.0
Loss function:
criterion=nn.CrossEntropyLoss()
DL0110EN/3.3.2lab_predicting _MNIST_using_Softmax.ipynb
atlury/deep-opencl
lgpl-3.0
Optimizer class:
learning_rate=0.1 optimizer=torch.optim.SGD(model.parameters(), lr=learning_rate)
DL0110EN/3.3.2lab_predicting _MNIST_using_Softmax.ipynb
atlury/deep-opencl
lgpl-3.0
Define the dataset loader:
train_loader=torch.utils.data.DataLoader(dataset=train_dataset,batch_size=100) validation_loader=torch.utils.data.DataLoader(dataset=validation_dataset,batch_size=5000)
DL0110EN/3.3.2lab_predicting _MNIST_using_Softmax.ipynb
atlury/deep-opencl
lgpl-3.0
Train the model and determine validation accuracy (should take a few minutes):
n_epochs=10 loss_list=[] accuracy_list=[] N_test=len(validation_dataset) #n_epochs for epoch in range(n_epochs): for x, y in train_loader: #clear gradient optimizer.zero_grad() #make a prediction z=model(x.view(-1,28*28)) # calculate loss loss=criterion(z,y...
DL0110EN/3.3.2lab_predicting _MNIST_using_Softmax.ipynb
atlury/deep-opencl
lgpl-3.0
<a id="ref3"></a> <h2 align=center>Analyze Results</h2> Plot the loss and accuracy on the validation data:
fig, ax1 = plt.subplots() color = 'tab:red' ax1.plot(loss_list,color=color) ax1.set_xlabel('epoch',color=color) ax1.set_ylabel('total loss',color=color) ax1.tick_params(axis='y', color=color) ax2 = ax1.twinx() color = 'tab:blue' ax2.set_ylabel('accuracy', color=color) ax2.plot( accuracy_list, color=color) ax2....
DL0110EN/3.3.2lab_predicting _MNIST_using_Softmax.ipynb
atlury/deep-opencl
lgpl-3.0