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"""Feature extraction for separating linguistic vs mathematical difficulty in MWPs.
Two orthogonal feature blocks per problem:
LING - readability formulas, lexical (CEFR), syntactic (parse depth, dependency length)
MATH - solution-step count, operation count/type, equation/number complexity
"""
import re
import numpy as np
import textstat
import spacy
from cefrpy import CEFRAnalyzer
_NLP = spacy.load("en_core_web_sm")
_CEFR = CEFRAnalyzer()
_CEFR_NUM = {"A1": 1, "A2": 2, "B1": 3, "B2": 4, "C1": 5, "C2": 6}
# Protected Common-Core / NCTM math terms - never count as "hard language"
MATH_TERMS = {
"area", "perimeter", "volume", "ratio", "proportion", "fraction", "decimal",
"percent", "percentage", "median", "mean", "mode", "average", "sum", "difference",
"product", "quotient", "divide", "multiply", "add", "subtract", "equation",
"angle", "triangle", "rectangle", "square", "circle", "diameter", "radius",
"numerator", "denominator", "integer", "remainder", "factor", "multiple",
}
def _cefr_features(tokens):
levels = []
above_b1 = 0
for t in tokens:
w = t.lower()
if w in MATH_TERMS:
continue
lvl = _CEFR.get_average_word_level_CEFR(w)
if lvl is not None:
n = int(lvl.value) # CEFRLevel enum -> 1..6
levels.append(n)
if n >= 3: # B1 or above
above_b1 += 1
if not levels:
return 0.0, 0.0, 0.0
return float(np.mean(levels)), float(np.max(levels)), above_b1 / max(len(levels), 1)
def _syntactic_features(doc):
# parse-tree depth (max distance to root), mean dependency length
depths, dep_lens = [], []
n_clauses = 0
n_subord = 0
for sent in doc.sents:
for tok in sent:
# depth: walk up to root
d, cur = 0, tok
while cur.head != cur:
cur = cur.head
d += 1
if d > 50:
break
depths.append(d)
dep_lens.append(abs(tok.i - tok.head.i))
if tok.dep_ in ("ccomp", "advcl", "relcl", "acl", "xcomp"):
n_clauses += 1
if tok.dep_ == "mark" or tok.tag_ == "IN" and tok.dep_ == "mark":
n_subord += 1
return (
float(np.max(depths)) if depths else 0.0,
float(np.mean(dep_lens)) if dep_lens else 0.0,
float(n_clauses),
)
def linguistic_features(text):
doc = _NLP(text)
tokens = [t.text for t in doc if t.is_alpha]
fk = textstat.flesch_kincaid_grade(text)
fre = textstat.flesch_reading_ease(text)
dc = textstat.dale_chall_readability_score(text)
n_words = len(tokens)
n_sents = max(len(list(doc.sents)), 1)
mean_word_len = float(np.mean([len(t) for t in tokens])) if tokens else 0.0
cefr_mean, cefr_max, cefr_above_b1 = _cefr_features(tokens)
parse_depth, mean_dep_len, n_clauses = _syntactic_features(doc)
return {
"ling_fk_grade": fk,
"ling_flesch_ease": fre,
"ling_dale_chall": dc,
"ling_n_words": n_words,
"ling_words_per_sent": n_words / n_sents,
"ling_mean_word_len": mean_word_len,
"ling_cefr_mean": cefr_mean,
"ling_cefr_max": cefr_max,
"ling_cefr_above_b1": cefr_above_b1,
"ling_parse_depth": parse_depth,
"ling_mean_dep_len": mean_dep_len,
"ling_n_clauses": n_clauses,
}
_OPS = re.compile(r"[+\-*/]")
def math_features_from_chain(chain):
"""ASDiv: count <gadget> calculator steps and operators."""
n_steps = chain.count("<gadget")
# only look at expressions inside gadget tags to avoid counting tag slashes
exprs = " ".join(re.findall(r'<gadget[^>]*>(.*?)</gadget>', chain, flags=re.S))
ops = _OPS.findall(exprs)
nums = re.findall(r"\d+\.?\d*", exprs)
max_num = max([float(n) for n in nums], default=0.0)
has_frac = 1.0 if "/" in exprs else 0.0
has_dec = 1.0 if any("." in n for n in nums) else 0.0
return {
"math_n_steps": float(max(n_steps, 1)),
"math_n_ops": float(len(ops)),
"math_max_num": max_num,
"math_has_frac": has_frac,
"math_has_decimal": has_dec,
}
def math_features_from_equation(eq):
"""SVAMP: parse the Equation string."""
ops = _OPS.findall(eq)
nums = re.findall(r"\d+\.?\d*", eq)
max_num = max([float(n) for n in nums], default=0.0)
depth = 0
cur = 0
for ch in eq:
if ch == "(":
cur += 1
depth = max(depth, cur)
elif ch == ")":
cur -= 1
return {
"math_n_ops": float(len(ops)),
"math_max_num": max_num,
"math_paren_depth": float(depth),
"math_has_decimal": 1.0 if any("." in n and float(n) != int(float(n)) for n in nums) else 0.0,
}
if __name__ == "__main__":
t = "Ellen has six more balls than Marin. Marin has nine balls. How many balls does Ellen have?"
print(linguistic_features(t))
print(math_features_from_chain('<gadget id="calculator">6 + 9</gadget>'))