physics-v1 batch-001

README.md

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+---
+pretty_name: Learning Paths in Intro Mechanics (sample)
+license: other
+license_name: creative-data-lab-dataset-license
+license_link: https://creative-data-lab-production.up.railway.app/terms.html
+language:
+- en
+task_categories:
+- question-answering
+- text-generation
+tags:
+- education
+- tutoring
+- synthetic
+- misconceptions
+- creative-data-lab
+- physics
+size_categories:
+- n<1K
+configs:
+- config_name: master
+  data_files:
+  - split: train
+    path: master/records.jsonl
+  default: true
+- config_name: sft
+  data_files:
+  - split: train
+    path: exports/sft.jsonl
+- config_name: tutor
+  data_files:
+  - split: train
+    path: exports/tutor.jsonl
+- config_name: preference
+  data_files:
+  - split: train
+    path: exports/preference.jsonl
+- config_name: step_labels
+  data_files:
+  - split: train
+    path: exports/step_labels.jsonl
+---
+
+# Learning Paths in Intro Mechanics: free sample
+
+*Creative Data Lab · 8 of 45 records from batch-001*
+
+Learning paths through introductory mechanics. Each record is a problem, one or two realistic wrong attempts
+tagged with a documented misconception, Socratic tutor feedback, and a correct worked solution.
+
+This is a **free sample** so you can check the schema and quality. The full dataset is
+[creativedatalab/physics-v1](https://huggingface.co/datasets/creativedatalab/physics-v1) (US$149 per organization, instant access after purchase at
+[creative-data-lab-production.up.railway.app](https://creative-data-lab-production.up.railway.app/#datasets)).
+
+## Load it
+
+```python
+from datasets import load_dataset
+
+records    = load_dataset("creativedatalab/physics-v1-sample", "master")       # full records (default)
+sft        = load_dataset("creativedatalab/physics-v1-sample", "sft")          # problem -> worked solution
+tutor      = load_dataset("creativedatalab/physics-v1-sample", "tutor")        # problem + wrong attempt -> guiding question
+preference = load_dataset("creativedatalab/physics-v1-sample", "preference")   # chosen / rejected pairs
+steps      = load_dataset("creativedatalab/physics-v1-sample", "step_labels")  # per-step labels, first error marked
+```
+
+## Files
+
+| File | Sample rows | Full dataset |
+|---|---:|---:|
+| `master/records.jsonl` | 8 | 45 |
+| `exports/sft.jsonl` | 8 | 45 |
+| `exports/tutor.jsonl` | 8 | 49 |
+| `exports/preference.jsonl` | 8 | 49 |
+| `exports/step_labels.jsonl` | 16 | 94 |
+
+## How it was made
+
+- **Ground truth is computed by code.** Every problem comes from a parameterised template; the correct answer
+  and each misconception's wrong answer are computed with sympy, never by a language model.
+- **Text is written by an open-weight model**: `mlx-community/Qwen2.5-32B-Instruct-4bit` (Apache 2.0), which writes problem wording,
+  student attempts, feedback and solution steps around the computed values.
+- **Every record passed automated checks**: answer matches truth within 1%; each wrong attempt lands exactly on its
+  misconception's predicted answer; feedback does not leak the answer; all arithmetic in the text recomputes;
+  no LaTeX or formatting debris; no duplicate problems.
+- **Human review**: 0 of 53 records reviewed so far.
+
+Batch yield: 53 of 56 problems kept (45 on the first try).
+
+## Coverage
+
+| Topic | Records |
+|---|---:|
+| E Work and energy | 10 |
+| K Kinematics | 15 |
+| N Newton's laws | 20 |
+
+| Rung | Records |
+|---|---:|
+| R1 Intuition | 11 |
+| R2 Definition | 4 |
+| R3 One step | 24 |
+| R4 Multi step | 6 |
+
+| Concept | Records |
+|---|---:|
+| E1 Work by a force | 4 |
+| E2 Kinetic energy / work–energy theorem | 4 |
+| E5 Energy with friction | 2 |
+| K1 Displacement vs. distance | 4 |
+| K6 Free fall | 7 |
+| K7 Projectile motion | 4 |
+| N4 Third law (interaction pairs) | 4 |
+| N5 Weight | 4 |
+| N6 Friction (static and kinetic) | 4 |
+| N7 Inclined planes | 4 |
+| N8 Tension and pulleys (Atwood) | 4 |
+
+| Misconception | Records |
+|---|---:|
+| MC01 Heavier objects fall faster | 3 |
+| MC02 Motion requires a force in its direction | 4 |
+| MC03 Zero velocity means zero acceleration | 4 |
+| MC04 Distance equals displacement | 4 |
+| MC09 Bigger object exerts bigger force | 4 |
+| MC10 Normal force always equals mg | 4 |
+| MC11 Static friction always equals μs·N | 4 |
+| MC13 Horizontal speed changes fall time | 4 |
+| MC14 Kinetic energy is linear in speed | 4 |
+| MC16 Mechanical energy conserved despite friction | 2 |
+| MC17 Perpendicular forces do work | 4 |
+| MC18 Mass and weight are the same | 4 |
+| MC19 Rope tension equals hanging weight | 4 |
+
+## Record schema (master)
+
+`id`, `split`, `topic`, `concept_id`, `prereqs`, `rung` (R1 intuition → R5 transfer), `difficulty`,
+`problem` (template, params, text, options), `ground_truth` (answer, unit, tolerance), `attempts`
+(misconception_id, text, final_answer), `feedback`, `solution` (steps, final_answer), `provenance`
+(generator, template version, seed, check results, human review).
+
+## Step labels: how to read them
+
+Correct solutions are labelled +1 at every step. For misconception attempts, the first step that reaches the
+misconception's wrong answer, and every step after it, are labelled -1. Earlier steps are `null`: they are not
+verified either way.
+
+## Limitations
+
+- Sample batch: 11 of 22 planned concepts, 45 training records.
+- Multiple-choice stems are template-written, so wording repeats across records of the same template.
+- Physics is checked by code; pedagogy (realism of attempts, quality of feedback) relies on human review.
+
+## License
+
+Problems are original, generated from in-house templates. Dataset license: per client agreement.
+
+## License
+
+Sample: [Creative Data Lab Dataset License](https://creative-data-lab-production.up.railway.app/terms.html), evaluation use. The full dataset
+carries the same license for training and evaluation inside one organization.

exports/preference.jsonl

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+{"id": "physics-v1-K1-R3-48c8f309-a0", "prompt": "A person walks 800 m due east in a warehouse, then turns around and walks 350 m due west. What is the magnitude of the person's displacement?", "chosen": "The person walks 800 m east, then 350 m west. To find the displacement, subtract the distance walked west from the distance walked east. 800 m - 350 m = 450 m. This means the person's displacement is 450 m east.", "rejected": "I walked 800 m east and then 350 m west. To find the displacement, I think I just need to add these distances together because that's the total distance I traveled. So, the displacement should be 800 m + 350 m = 1150 m.", "rejected_misconception_id": "MC04"}
+{"id": "physics-v1-K6-R1-22e5357f-a0", "prompt": "A marble and a steel shot put are dropped at the same moment from a height of 10 m. Ignore air resistance. Which statement is correct?\nA) A steel shot put hits the ground first.\nB) They hit the ground at the same time.\nC) A steel shot put falls faster, in proportion to how much heavier it is.", "chosen": "In a vacuum, all objects fall at the same rate regardless of their mass. Since air resistance is ignored, the marble and the steel shot put will fall at the same rate and hit the ground at the same time. The correct answer is B.", "rejected": "Since the steel shot put is much heavier than the marble, it should fall faster and hit the ground first. Therefore, the answer is A.", "rejected_misconception_id": "MC01"}
+{"id": "physics-v1-K7-R1-13b3e76d-a0", "prompt": "From a height of 5.0 m, one ball is dropped while an identical ball is launched horizontally at 3 m/s at the same instant. Ignore air resistance. Which statement is correct?\nA) The launched ball lands first, because it is moving faster.\nB) The launched ball lands later, because its horizontal speed keeps it in the air.\nC) Both balls land at the same time.", "chosen": "Both balls experience the same gravitational acceleration in the vertical direction, regardless of their horizontal speed. The time it takes for each ball to fall 5.0 m is determined solely by the vertical motion. Since both balls fall the same distance under the same acceleration, they land at the same time. The correct answer is C.", "rejected": "I think the launched ball will land first because it's moving faster horizontally. Since it's moving faster, it should hit the ground sooner than the ball that is just dropped straight down. So, I choose A.", "rejected_misconception_id": "MC13"}
+{"id": "physics-v1-N4-R1-5553fe5d-a0", "prompt": "A truck collides head-on with a small car. During the collision, how do the forces they exert on each other compare?\nA) Only a truck exerts a force; a small car just gets pushed.\nB) A truck exerts a larger force on a small car than a small car exerts on it.\nC) The forces are equal in size and opposite in direction.", "chosen": "According to Newton's Third Law, for every action, there is an equal and opposite reaction. This means that the force the truck exerts on the small car is equal in size and opposite in direction to the force the small car exerts on the truck. The correct answer is C.", "rejected": "I think the truck exerts a larger force on the small car because it's bigger and heavier. The small car just gets pushed, so the force it exerts is not as important. Therefore, I choose A.", "rejected_misconception_id": "MC09"}
+{"id": "physics-v1-N5-R3-2f67b1dc-a0", "prompt": "A factory has a piece of machinery with a mass of 12 kg placed on the Earth's surface. Calculate the weight of this machinery in newtons, given g = 9.8 m/s².", "chosen": "The weight of an object is given by the mass multiplied by the gravitational acceleration. So, weight = 12 kg × 9.8 m/s². Therefore, weight = 118 N.", "rejected": "To find the weight of the machinery, I simply use the mass which is given as 12 kg. Since weight is the same as mass, the weight of the machinery is 12 N.", "rejected_misconception_id": "MC18"}
+{"id": "physics-v1-E1-R3-4bdc0d81-a0", "prompt": "A child pulls a sled 10 m across level snow in a playground using a rope that makes a 30° angle with the ground. The tension in the rope is 50 N. How much work does the rope do on the sled?", "chosen": "Find the component of the force that acts in the direction of motion: 50 N × cos(30°) = 50 N × 0.866 = 43.3 N. Calculate the work done by multiplying the force component by the distance: 43.3 N × 10 m = 433 J.", "rejected": "I think the work is just the force times the distance because the angle doesn't matter. So, 50 N times 10 m equals 500 J.", "rejected_misconception_id": "MC17"}
+{"id": "physics-v1-E2-R3-3da3077d-a0", "prompt": "An object with a mass of 1200 kg is moving at a speed of 20 m/s on a construction site. Calculate the kinetic energy of this object.", "chosen": "Kinetic energy formula: KE = ½·m·v². Plugging in the values: KE = ½ × 1200 kg × (20 m/s)². Calculating the speed squared: (20 m/s)² = 400 m²/s². Calculating the kinetic energy: KE = ½ × 1200 × 400 = 240000 J. The kinetic energy of the object is 240000 J.", "rejected": "To find the kinetic energy, I use the formula that I thought was correct, KE = ½·m·v. So, I take the mass, which is 1200 kg, and the speed, which is 20 m/s, and calculate: KE = ½ × 1200 × 20 = 12000 J.", "rejected_misconception_id": "MC14"}
+{"id": "physics-v1-E5-R4-213f7ba0-a0", "prompt": "A skier starts from rest at the top of a ski ramp that is 4 m high and inclined at 45°. The coefficient of kinetic friction between the skier's skis and the ramp is 0.3. Assuming the skier's mass remains constant, how fast is the skier moving at the bottom of the ramp? (You may use g = 9.8 m/s².)", "chosen": "The ramp length is calculated as 5.66 m, and the work done by friction per kg is 11.8 J. Initial potential energy is 4 m × 9.8 m/s² = 39.2 J/kg. Work done by friction = 11.8 J/kg, subtract from initial potential energy to get final kinetic energy: 39.2 J/kg - 11.8 J/kg = 27.4 J/kg. Final kinetic energy 27.4 J/kg = 0.5 × v²; solving, v = 7.41 m/s.", "rejected": "I used the principle of conservation of energy, assuming no friction affects the skier's speed. The potential energy at the top, 4 m × 9.8 m/s², equals the kinetic energy at the bottom, 0.5 × v². Solving for v, I get 8.85 m/s.", "rejected_misconception_id": "MC16"}

exports/sft.jsonl

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+{"id": "physics-v1-K1-R3-48c8f309", "messages": [{"role": "user", "content": "A person walks 800 m due east in a warehouse, then turns around and walks 350 m due west. What is the magnitude of the person's displacement?"}, {"role": "assistant", "content": "The person walks 800 m east, then 350 m west. To find the displacement, subtract the distance walked west from the distance walked east. 800 m - 350 m = 450 m. This means the person's displacement is 450 m east."}]}
+{"id": "physics-v1-K6-R1-22e5357f", "messages": [{"role": "user", "content": "A marble and a steel shot put are dropped at the same moment from a height of 10 m. Ignore air resistance. Which statement is correct?\nA) A steel shot put hits the ground first.\nB) They hit the ground at the same time.\nC) A steel shot put falls faster, in proportion to how much heavier it is."}, {"role": "assistant", "content": "In a vacuum, all objects fall at the same rate regardless of their mass. Since air resistance is ignored, the marble and the steel shot put will fall at the same rate and hit the ground at the same time. The correct answer is B."}]}
+{"id": "physics-v1-K7-R1-13b3e76d", "messages": [{"role": "user", "content": "From a height of 5.0 m, one ball is dropped while an identical ball is launched horizontally at 3 m/s at the same instant. Ignore air resistance. Which statement is correct?\nA) The launched ball lands first, because it is moving faster.\nB) The launched ball lands later, because its horizontal speed keeps it in the air.\nC) Both balls land at the same time."}, {"role": "assistant", "content": "Both balls experience the same gravitational acceleration in the vertical direction, regardless of their horizontal speed. The time it takes for each ball to fall 5.0 m is determined solely by the vertical motion. Since both balls fall the same distance under the same acceleration, they land at the same time. The correct answer is C."}]}
+{"id": "physics-v1-N4-R1-5553fe5d", "messages": [{"role": "user", "content": "A truck collides head-on with a small car. During the collision, how do the forces they exert on each other compare?\nA) Only a truck exerts a force; a small car just gets pushed.\nB) A truck exerts a larger force on a small car than a small car exerts on it.\nC) The forces are equal in size and opposite in direction."}, {"role": "assistant", "content": "According to Newton's Third Law, for every action, there is an equal and opposite reaction. This means that the force the truck exerts on the small car is equal in size and opposite in direction to the force the small car exerts on the truck. The correct answer is C."}]}
+{"id": "physics-v1-N5-R3-2f67b1dc", "messages": [{"role": "user", "content": "A factory has a piece of machinery with a mass of 12 kg placed on the Earth's surface. Calculate the weight of this machinery in newtons, given g = 9.8 m/s²."}, {"role": "assistant", "content": "The weight of an object is given by the mass multiplied by the gravitational acceleration. So, weight = 12 kg × 9.8 m/s². Therefore, weight = 118 N."}]}
+{"id": "physics-v1-E1-R3-4bdc0d81", "messages": [{"role": "user", "content": "A child pulls a sled 10 m across level snow in a playground using a rope that makes a 30° angle with the ground. The tension in the rope is 50 N. How much work does the rope do on the sled?"}, {"role": "assistant", "content": "Find the component of the force that acts in the direction of motion: 50 N × cos(30°) = 50 N × 0.866 = 43.3 N. Calculate the work done by multiplying the force component by the distance: 43.3 N × 10 m = 433 J."}]}
+{"id": "physics-v1-E2-R3-3da3077d", "messages": [{"role": "user", "content": "An object with a mass of 1200 kg is moving at a speed of 20 m/s on a construction site. Calculate the kinetic energy of this object."}, {"role": "assistant", "content": "Kinetic energy formula: KE = ½·m·v². Plugging in the values: KE = ½ × 1200 kg × (20 m/s)². Calculating the speed squared: (20 m/s)² = 400 m²/s². Calculating the kinetic energy: KE = ½ × 1200 × 400 = 240000 J. The kinetic energy of the object is 240000 J."}]}
+{"id": "physics-v1-E5-R4-213f7ba0", "messages": [{"role": "user", "content": "A skier starts from rest at the top of a ski ramp that is 4 m high and inclined at 45°. The coefficient of kinetic friction between the skier's skis and the ramp is 0.3. Assuming the skier's mass remains constant, how fast is the skier moving at the bottom of the ramp? (You may use g = 9.8 m/s².)"}, {"role": "assistant", "content": "The ramp length is calculated as 5.66 m, and the work done by friction per kg is 11.8 J. Initial potential energy is 4 m × 9.8 m/s² = 39.2 J/kg. Work done by friction = 11.8 J/kg, subtract from initial potential energy to get final kinetic energy: 39.2 J/kg - 11.8 J/kg = 27.4 J/kg. Final kinetic energy 27.4 J/kg = 0.5 × v²; solving, v = 7.41 m/s."}]}

exports/step_labels.jsonl

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+{"id": "physics-v1-K1-R3-48c8f309-sol", "prompt": "A person walks 800 m due east in a warehouse, then turns around and walks 350 m due west. What is the magnitude of the person's displacement?", "steps": ["The person walks 800 m east, then 350 m west.", "To find the displacement, subtract the distance walked west from the distance walked east.", "800 m - 350 m = 450 m", "This means the person's displacement is 450 m east."], "labels": [1, 1, 1, 1], "outcome": "correct"}
+{"id": "physics-v1-K1-R3-48c8f309-a0", "prompt": "A person walks 800 m due east in a warehouse, then turns around and walks 350 m due west. What is the magnitude of the person's displacement?", "steps": ["I walked 800 m east and then 350 m west.", "To find the displacement, I think I just need to add these distances together because that's the total distance I traveled.", "So, the displacement should be 800 m + 350 m = 1150 m."], "labels": [null, null, -1], "first_error_step": 2, "outcome": "incorrect", "misconception_id": "MC04"}
+{"id": "physics-v1-K6-R1-22e5357f-sol", "prompt": "A marble and a steel shot put are dropped at the same moment from a height of 10 m. Ignore air resistance. Which statement is correct?\nA) A steel shot put hits the ground first.\nB) They hit the ground at the same time.\nC) A steel shot put falls faster, in proportion to how much heavier it is.", "steps": ["In a vacuum, all objects fall at the same rate regardless of their mass.", "Since air resistance is ignored, the marble and the steel shot put will fall at the same rate and hit the ground at the same time.", "The correct answer is B."], "labels": [1, 1, 1], "outcome": "correct"}
+{"id": "physics-v1-K6-R1-22e5357f-a0", "prompt": "A marble and a steel shot put are dropped at the same moment from a height of 10 m. Ignore air resistance. Which statement is correct?\nA) A steel shot put hits the ground first.\nB) They hit the ground at the same time.\nC) A steel shot put falls faster, in proportion to how much heavier it is.", "steps": ["Since the steel shot put is much heavier than the marble, it should fall faster and hit the ground first.", "Therefore, the answer is A."], "labels": [null, -1], "first_error_step": 1, "outcome": "incorrect", "misconception_id": "MC01"}
+{"id": "physics-v1-K7-R1-13b3e76d-sol", "prompt": "From a height of 5.0 m, one ball is dropped while an identical ball is launched horizontally at 3 m/s at the same instant. Ignore air resistance. Which statement is correct?\nA) The launched ball lands first, because it is moving faster.\nB) The launched ball lands later, because its horizontal speed keeps it in the air.\nC) Both balls land at the same time.", "steps": ["Both balls experience the same gravitational acceleration in the vertical direction, regardless of their horizontal speed.", "The time it takes for each ball to fall 5.0 m is determined solely by the vertical motion.", "Since both balls fall the same distance under the same acceleration, they land at the same time. The correct answer is C."], "labels": [1, 1, 1], "outcome": "correct"}
+{"id": "physics-v1-K7-R1-13b3e76d-a0", "prompt": "From a height of 5.0 m, one ball is dropped while an identical ball is launched horizontally at 3 m/s at the same instant. Ignore air resistance. Which statement is correct?\nA) The launched ball lands first, because it is moving faster.\nB) The launched ball lands later, because its horizontal speed keeps it in the air.\nC) Both balls land at the same time.", "steps": ["I think the launched ball will land first because it's moving faster horizontally.", "Since it's moving faster, it should hit the ground sooner than the ball that is just dropped straight down.", "So, I choose A."], "labels": [null, null, -1], "first_error_step": 2, "outcome": "incorrect", "misconception_id": "MC13"}
+{"id": "physics-v1-N4-R1-5553fe5d-sol", "prompt": "A truck collides head-on with a small car. During the collision, how do the forces they exert on each other compare?\nA) Only a truck exerts a force; a small car just gets pushed.\nB) A truck exerts a larger force on a small car than a small car exerts on it.\nC) The forces are equal in size and opposite in direction.", "steps": ["According to Newton's Third Law, for every action, there is an equal and opposite reaction.", "This means that the force the truck exerts on the small car is equal in size and opposite in direction to the force the small car exerts on the truck.", "The correct answer is C."], "labels": [1, 1, 1], "outcome": "correct"}
+{"id": "physics-v1-N4-R1-5553fe5d-a0", "prompt": "A truck collides head-on with a small car. During the collision, how do the forces they exert on each other compare?\nA) Only a truck exerts a force; a small car just gets pushed.\nB) A truck exerts a larger force on a small car than a small car exerts on it.\nC) The forces are equal in size and opposite in direction.", "steps": ["I think the truck exerts a larger force on the small car because it's bigger and heavier.", "The small car just gets pushed, so the force it exerts is not as important.", "Therefore, I choose A."], "labels": [null, null, -1], "first_error_step": 2, "outcome": "incorrect", "misconception_id": "MC09"}
+{"id": "physics-v1-N5-R3-2f67b1dc-sol", "prompt": "A factory has a piece of machinery with a mass of 12 kg placed on the Earth's surface. Calculate the weight of this machinery in newtons, given g = 9.8 m/s².", "steps": ["The weight of an object is given by the mass multiplied by the gravitational acceleration.", "So, weight = 12 kg × 9.8 m/s²", "Therefore, weight = 118 N"], "labels": [1, 1, 1], "outcome": "correct"}
+{"id": "physics-v1-N5-R3-2f67b1dc-a0", "prompt": "A factory has a piece of machinery with a mass of 12 kg placed on the Earth's surface. Calculate the weight of this machinery in newtons, given g = 9.8 m/s².", "steps": ["To find the weight of the machinery, I simply use the mass which is given as 12 kg.", "Since weight is the same as mass, the weight of the machinery is 12 N."], "labels": [-1, -1], "first_error_step": 0, "outcome": "incorrect", "misconception_id": "MC18"}
+{"id": "physics-v1-E1-R3-4bdc0d81-sol", "prompt": "A child pulls a sled 10 m across level snow in a playground using a rope that makes a 30° angle with the ground. The tension in the rope is 50 N. How much work does the rope do on the sled?", "steps": ["Find the component of the force that acts in the direction of motion: 50 N × cos(30°) = 50 N × 0.866 = 43.3 N", "Calculate the work done by multiplying the force component by the distance: 43.3 N × 10 m = 433 J"], "labels": [1, 1], "outcome": "correct"}
+{"id": "physics-v1-E1-R3-4bdc0d81-a0", "prompt": "A child pulls a sled 10 m across level snow in a playground using a rope that makes a 30° angle with the ground. The tension in the rope is 50 N. How much work does the rope do on the sled?", "steps": ["I think the work is just the force times the distance because the angle doesn't matter.", "So, 50 N times 10 m equals 500 J."], "labels": [null, -1], "first_error_step": 1, "outcome": "incorrect", "misconception_id": "MC17"}
+{"id": "physics-v1-E2-R3-3da3077d-sol", "prompt": "An object with a mass of 1200 kg is moving at a speed of 20 m/s on a construction site. Calculate the kinetic energy of this object.", "steps": ["Kinetic energy formula: KE = ½·m·v²", "Plugging in the values: KE = ½ × 1200 kg × (20 m/s)²", "Calculating the speed squared: (20 m/s)² = 400 m²/s²", "Calculating the kinetic energy: KE = ½ × 1200 × 400 = 240000 J", "The kinetic energy of the object is 240000 J."], "labels": [1, 1, 1, 1, 1], "outcome": "correct"}
+{"id": "physics-v1-E2-R3-3da3077d-a0", "prompt": "An object with a mass of 1200 kg is moving at a speed of 20 m/s on a construction site. Calculate the kinetic energy of this object.", "steps": ["To find the kinetic energy, I use the formula that I thought was correct, KE = ½·m·v.", "So, I take the mass, which is 1200 kg, and the speed, which is 20 m/s, and calculate: KE = ½ × 1200 × 20 = 12000 J."], "labels": [null, -1], "first_error_step": 1, "outcome": "incorrect", "misconception_id": "MC14"}
+{"id": "physics-v1-E5-R4-213f7ba0-sol", "prompt": "A skier starts from rest at the top of a ski ramp that is 4 m high and inclined at 45°. The coefficient of kinetic friction between the skier's skis and the ramp is 0.3. Assuming the skier's mass remains constant, how fast is the skier moving at the bottom of the ramp? (You may use g = 9.8 m/s².)", "steps": ["The ramp length is calculated as 5.66 m, and the work done by friction per kg is 11.8 J.", "Initial potential energy is 4 m × 9.8 m/s² = 39.2 J/kg.", "Work done by friction = 11.8 J/kg, subtract from initial potential energy to get final kinetic energy: 39.2 J/kg - 11.8 J/kg = 27.4 J/kg.", "Final kinetic energy 27.4 J/kg = 0.5 × v²; solving, v = 7.41 m/s."], "labels": [1, 1, 1, 1], "outcome": "correct"}
+{"id": "physics-v1-E5-R4-213f7ba0-a0", "prompt": "A skier starts from rest at the top of a ski ramp that is 4 m high and inclined at 45°. The coefficient of kinetic friction between the skier's skis and the ramp is 0.3. Assuming the skier's mass remains constant, how fast is the skier moving at the bottom of the ramp? (You may use g = 9.8 m/s².)", "steps": ["I used the principle of conservation of energy, assuming no friction affects the skier's speed.", "The potential energy at the top, 4 m × 9.8 m/s², equals the kinetic energy at the bottom, 0.5 × v².", "Solving for v, I get 8.85 m/s."], "labels": [null, null, -1], "first_error_step": 2, "outcome": "incorrect", "misconception_id": "MC16"}

exports/tutor.jsonl

@@ -0,0 +1,8 @@
+{"id": "physics-v1-K1-R3-48c8f309-a0", "misconception_id": "MC04", "messages": [{"role": "system", "content": "You are a physics tutor. When a student shares a wrong attempt, ask a short guiding question that exposes the flawed idea. Never give the answer."}, {"role": "user", "content": "A person walks 800 m due east in a warehouse, then turns around and walks 350 m due west. What is the magnitude of the person's displacement?\n\nMy attempt: I walked 800 m east and then 350 m west. To find the displacement, I think I just need to add these distances together because that's the total distance I traveled. So, the displacement should be 800 m + 350 m = 1150 m."}, {"role": "assistant", "content": "Is the displacement the same as the total distance traveled? Consider how the direction of movement affects the displacement."}]}
+{"id": "physics-v1-K6-R1-22e5357f-a0", "misconception_id": "MC01", "messages": [{"role": "system", "content": "You are a physics tutor. When a student shares a wrong attempt, ask a short guiding question that exposes the flawed idea. Never give the answer."}, {"role": "user", "content": "A marble and a steel shot put are dropped at the same moment from a height of 10 m. Ignore air resistance. Which statement is correct?\nA) A steel shot put hits the ground first.\nB) They hit the ground at the same time.\nC) A steel shot put falls faster, in proportion to how much heavier it is.\n\nMy attempt: Since the steel shot put is much heavier than the marble, it should fall faster and hit the ground first. Therefore, the answer is A."}, {"role": "assistant", "content": "If heavier objects fall faster, how would you explain two pieces of paper of different weights falling at the same speed in a vacuum?"}]}
+{"id": "physics-v1-K7-R1-13b3e76d-a0", "misconception_id": "MC13", "messages": [{"role": "system", "content": "You are a physics tutor. When a student shares a wrong attempt, ask a short guiding question that exposes the flawed idea. Never give the answer."}, {"role": "user", "content": "From a height of 5.0 m, one ball is dropped while an identical ball is launched horizontally at 3 m/s at the same instant. Ignore air resistance. Which statement is correct?\nA) The launched ball lands first, because it is moving faster.\nB) The launched ball lands later, because its horizontal speed keeps it in the air.\nC) Both balls land at the same time.\n\nMy attempt: I think the launched ball will land first because it's moving faster horizontally. Since it's moving faster, it should hit the ground sooner than the ball that is just dropped straight down. So, I choose A."}, {"role": "assistant", "content": "Does the horizontal speed affect how quickly the ball falls vertically? Consider the motion of the balls in the vertical direction alone."}]}
+{"id": "physics-v1-N4-R1-5553fe5d-a0", "misconception_id": "MC09", "messages": [{"role": "system", "content": "You are a physics tutor. When a student shares a wrong attempt, ask a short guiding question that exposes the flawed idea. Never give the answer."}, {"role": "user", "content": "A truck collides head-on with a small car. During the collision, how do the forces they exert on each other compare?\nA) Only a truck exerts a force; a small car just gets pushed.\nB) A truck exerts a larger force on a small car than a small car exerts on it.\nC) The forces are equal in size and opposite in direction.\n\nMy attempt: I think the truck exerts a larger force on the small car because it's bigger and heavier. The small car just gets pushed, so the force it exerts is not as important. Therefore, I choose A."}, {"role": "assistant", "content": "If the truck exerts a larger force, shouldn't the small car move much more than the truck? How would both objects affect each other's motion in the collision?"}]}
+{"id": "physics-v1-N5-R3-2f67b1dc-a0", "misconception_id": "MC18", "messages": [{"role": "system", "content": "You are a physics tutor. When a student shares a wrong attempt, ask a short guiding question that exposes the flawed idea. Never give the answer."}, {"role": "user", "content": "A factory has a piece of machinery with a mass of 12 kg placed on the Earth's surface. Calculate the weight of this machinery in newtons, given g = 9.8 m/s².\n\nMy attempt: To find the weight of the machinery, I simply use the mass which is given as 12 kg. Since weight is the same as mass, the weight of the machinery is 12 N."}, {"role": "assistant", "content": "Consider the difference between mass and weight. How does gravity play a role in calculating weight?"}]}
+{"id": "physics-v1-E1-R3-4bdc0d81-a0", "misconception_id": "MC17", "messages": [{"role": "system", "content": "You are a physics tutor. When a student shares a wrong attempt, ask a short guiding question that exposes the flawed idea. Never give the answer."}, {"role": "user", "content": "A child pulls a sled 10 m across level snow in a playground using a rope that makes a 30° angle with the ground. The tension in the rope is 50 N. How much work does the rope do on the sled?\n\nMy attempt: I think the work is just the force times the distance because the angle doesn't matter. So, 50 N times 10 m equals 500 J."}, {"role": "assistant", "content": "Do you think the angle of the rope doesn't affect the work done? Consider how the direction of the force relates to the direction of the motion."}]}
+{"id": "physics-v1-E2-R3-3da3077d-a0", "misconception_id": "MC14", "messages": [{"role": "system", "content": "You are a physics tutor. When a student shares a wrong attempt, ask a short guiding question that exposes the flawed idea. Never give the answer."}, {"role": "user", "content": "An object with a mass of 1200 kg is moving at a speed of 20 m/s on a construction site. Calculate the kinetic energy of this object.\n\nMy attempt: To find the kinetic energy, I use the formula that I thought was correct, KE = ½·m·v. So, I take the mass, which is 1200 kg, and the speed, which is 20 m/s, and calculate: KE = ½ × 1200 × 20 = 12000 J."}, {"role": "assistant", "content": "Why did you use velocity alone to calculate the kinetic energy? Does the energy double if the speed doubles?"}]}
+{"id": "physics-v1-E5-R4-213f7ba0-a0", "misconception_id": "MC16", "messages": [{"role": "system", "content": "You are a physics tutor. When a student shares a wrong attempt, ask a short guiding question that exposes the flawed idea. Never give the answer."}, {"role": "user", "content": "A skier starts from rest at the top of a ski ramp that is 4 m high and inclined at 45°. The coefficient of kinetic friction between the skier's skis and the ramp is 0.3. Assuming the skier's mass remains constant, how fast is the skier moving at the bottom of the ramp? (You may use g = 9.8 m/s².)\n\nMy attempt: I used the principle of conservation of energy, assuming no friction affects the skier's speed. The potential energy at the top, 4 m × 9.8 m/s², equals the kinetic energy at the bottom, 0.5 × v². Solving for v, I get 8.85 m/s."}, {"role": "assistant", "content": "How does friction affect the skier's speed on the ramp, and how does this impact the conservation of mechanical energy?"}]}

master/records.jsonl

@@ -0,0 +1,8 @@
+{"id": "physics-v1-E1-R3-4bdc0d81", "split": "train", "topic": "E", "concept_id": "E1", "prereqs": ["N3"], "rung": "R3", "difficulty": "medium", "problem": {"template_id": "E1-R3-work-at-angle", "params": {"force_N": {"value": 50, "unit": "N"}, "distance_m": {"value": 10, "unit": "m"}, "angle_deg": {"value": 30, "unit": "°"}}, "text": "A child pulls a sled 10 m across level snow in a playground using a rope that makes a 30° angle with the ground. The tension in the rope is 50 N. How much work does the rope do on the sled?", "options": null}, "ground_truth": {"answer": 433.0, "unit": "J", "tolerance_rel": 0.01}, "attempts": [{"misconception_id": "MC17", "text": "I think the work is just the force times the distance because the angle doesn't matter. So, 50 N times 10 m equals 500 J.", "final_answer": 500.0}], "feedback": [{"for_attempt": 0, "text": "Do you think the angle of the rope doesn't affect the work done? Consider how the direction of the force relates to the direction of the motion."}], "solution": {"steps": ["Find the component of the force that acts in the direction of motion: 50 N × cos(30°) = 50 N × 0.866 = 43.3 N", "Calculate the work done by multiplying the force component by the distance: 43.3 N × 10 m = 433 J"], "final_answer": 433}, "provenance": {"generator": "mlx-community/Qwen2.5-32B-Instruct-4bit", "template_version": "0.1.0-spec", "seed": 3, "gen_attempt": 0, "checks": {"V2": "pass", "V3": "pass", "V4": "pass", "V5": "pass", "V6": "pass", "V9": "pass", "V10": "pass", "V7": "pass"}, "human_review": {"reviewed": false, "verdict": null}}}
+{"id": "physics-v1-E2-R3-3da3077d", "split": "train", "topic": "E", "concept_id": "E2", "prereqs": ["E1"], "rung": "R3", "difficulty": "medium", "problem": {"template_id": "E2-R3-kinetic-energy", "params": {"mass_kg": {"value": 1200, "unit": "kg"}, "speed_m_s": {"value": 20, "unit": "m/s"}}, "text": "An object with a mass of 1200 kg is moving at a speed of 20 m/s on a construction site. Calculate the kinetic energy of this object.", "options": null}, "ground_truth": {"answer": 240000.0, "unit": "J", "tolerance_rel": 0.01}, "attempts": [{"misconception_id": "MC14", "text": "To find the kinetic energy, I use the formula that I thought was correct, KE = ½·m·v. So, I take the mass, which is 1200 kg, and the speed, which is 20 m/s, and calculate: KE = ½ × 1200 × 20 = 12000 J.", "final_answer": 12000.0}], "feedback": [{"for_attempt": 0, "text": "Why did you use velocity alone to calculate the kinetic energy? Does the energy double if the speed doubles?"}], "solution": {"steps": ["Kinetic energy formula: KE = ½·m·v²", "Plugging in the values: KE = ½ × 1200 kg × (20 m/s)²", "Calculating the speed squared: (20 m/s)² = 400 m²/s²", "Calculating the kinetic energy: KE = ½ × 1200 × 400 = 240000 J", "The kinetic energy of the object is 240000 J."], "final_answer": 240000}, "provenance": {"generator": "mlx-community/Qwen2.5-32B-Instruct-4bit", "template_version": "0.1.0-spec", "seed": 4, "gen_attempt": 0, "checks": {"V2": "pass", "V3": "pass", "V4": "pass", "V5": "pass", "V6": "pass", "V9": "pass", "V10": "pass", "V7": "pass"}, "human_review": {"reviewed": false, "verdict": null}}}
+{"id": "physics-v1-E5-R4-213f7ba0", "split": "train", "topic": "E", "concept_id": "E5", "prereqs": ["E4", "N6"], "rung": "R4", "difficulty": "hard", "problem": {"template_id": "E5-R4-slide-with-friction", "params": {"height_m": {"value": 4, "unit": "m"}, "angle_deg": {"value": 45, "unit": "°"}, "mu_k": {"value": 0.3, "unit": ""}}, "text": "A skier starts from rest at the top of a ski ramp that is 4 m high and inclined at 45°. The coefficient of kinetic friction between the skier's skis and the ramp is 0.3. Assuming the skier's mass remains constant, how fast is the skier moving at the bottom of the ramp? (You may use g = 9.8 m/s².)", "options": null}, "ground_truth": {"answer": 7.41, "unit": "m/s", "tolerance_rel": 0.01}, "attempts": [{"misconception_id": "MC16", "text": "I used the principle of conservation of energy, assuming no friction affects the skier's speed. The potential energy at the top, 4 m × 9.8 m/s², equals the kinetic energy at the bottom, 0.5 × v². Solving for v, I get 8.85 m/s.", "final_answer": 8.85}], "feedback": [{"for_attempt": 0, "text": "How does friction affect the skier's speed on the ramp, and how does this impact the conservation of mechanical energy?"}], "solution": {"steps": ["The ramp length is calculated as 5.66 m, and the work done by friction per kg is 11.8 J.", "Initial potential energy is 4 m × 9.8 m/s² = 39.2 J/kg.", "Work done by friction = 11.8 J/kg, subtract from initial potential energy to get final kinetic energy: 39.2 J/kg - 11.8 J/kg = 27.4 J/kg.", "Final kinetic energy 27.4 J/kg = 0.5 × v²; solving, v = 7.41 m/s."], "final_answer": 7.41}, "provenance": {"generator": "mlx-community/Qwen2.5-32B-Instruct-4bit", "template_version": "0.1.0-spec", "seed": 3, "gen_attempt": 0, "checks": {"V2": "pass", "V3": "pass", "V4": "pass", "V5": "pass", "V6": "pass", "V9": "pass", "V10": "pass", "V7": "pass"}, "human_review": {"reviewed": false, "verdict": null}}}
+{"id": "physics-v1-K1-R3-48c8f309", "split": "train", "topic": "K", "concept_id": "K1", "prereqs": [], "rung": "R3", "difficulty": "medium", "problem": {"template_id": "K1-R3-out-and-back", "params": {"east_m": {"value": 800, "unit": "m"}, "west_m": {"value": 350, "unit": "m"}}, "text": "A person walks 800 m due east in a warehouse, then turns around and walks 350 m due west. What is the magnitude of the person's displacement?", "options": null}, "ground_truth": {"answer": 450.0, "unit": "m", "tolerance_rel": 0.01}, "attempts": [{"misconception_id": "MC04", "text": "I walked 800 m east and then 350 m west. To find the displacement, I think I just need to add these distances together because that's the total distance I traveled. So, the displacement should be 800 m + 350 m = 1150 m.", "final_answer": 1150.0}], "feedback": [{"for_attempt": 0, "text": "Is the displacement the same as the total distance traveled? Consider how the direction of movement affects the displacement."}], "solution": {"steps": ["The person walks 800 m east, then 350 m west.", "To find the displacement, subtract the distance walked west from the distance walked east.", "800 m - 350 m = 450 m", "This means the person's displacement is 450 m east."], "final_answer": 450}, "provenance": {"generator": "mlx-community/Qwen2.5-32B-Instruct-4bit", "template_version": "0.1.0-spec", "seed": 1, "gen_attempt": 0, "checks": {"V2": "pass", "V3": "pass", "V4": "pass", "V5": "pass", "V6": "pass", "V9": "pass", "V10": "pass", "V7": "pass"}, "human_review": {"reviewed": false, "verdict": null}}}
+{"id": "physics-v1-K6-R1-22e5357f", "split": "train", "topic": "K", "concept_id": "K6", "prereqs": ["K5"], "rung": "R1", "difficulty": "easy", "problem": {"template_id": "K6-R1-drop-two-masses", "params": {}, "text": "A marble and a steel shot put are dropped at the same moment from a height of 10 m. Ignore air resistance. Which statement is correct?", "options": ["A) A steel shot put hits the ground first.", "B) They hit the ground at the same time.", "C) A steel shot put falls faster, in proportion to how much heavier it is."]}, "ground_truth": {"answer": "B", "unit": null, "tolerance_rel": 0}, "attempts": [{"misconception_id": "MC01", "text": "Since the steel shot put is much heavier than the marble, it should fall faster and hit the ground first. Therefore, the answer is A.", "final_answer": "A"}], "feedback": [{"for_attempt": 0, "text": "If heavier objects fall faster, how would you explain two pieces of paper of different weights falling at the same speed in a vacuum?"}], "solution": {"steps": ["In a vacuum, all objects fall at the same rate regardless of their mass.", "Since air resistance is ignored, the marble and the steel shot put will fall at the same rate and hit the ground at the same time.", "The correct answer is B."], "final_answer": "B"}, "provenance": {"generator": "mlx-community/Qwen2.5-32B-Instruct-4bit", "template_version": "0.1.0-spec", "seed": 1, "gen_attempt": 1, "checks": {"V2": "pass", "V3": "pass", "V4": "pass", "V5": "pass", "V6": "pass", "V9": "pass", "V10": "pass", "V7": "pass"}, "human_review": {"reviewed": false, "verdict": null}}}
+{"id": "physics-v1-K7-R1-13b3e76d", "split": "train", "topic": "K", "concept_id": "K7", "prereqs": ["K6"], "rung": "R1", "difficulty": "easy", "problem": {"template_id": "K7-R1-drop-vs-launch", "params": {}, "text": "From a height of 5.0 m, one ball is dropped while an identical ball is launched horizontally at 3 m/s at the same instant. Ignore air resistance. Which statement is correct?", "options": ["A) The launched ball lands first, because it is moving faster.", "B) The launched ball lands later, because its horizontal speed keeps it in the air.", "C) Both balls land at the same time."]}, "ground_truth": {"answer": "C", "unit": null, "tolerance_rel": 0}, "attempts": [{"misconception_id": "MC13", "text": "I think the launched ball will land first because it's moving faster horizontally. Since it's moving faster, it should hit the ground sooner than the ball that is just dropped straight down. So, I choose A.", "final_answer": "A"}], "feedback": [{"for_attempt": 0, "text": "Does the horizontal speed affect how quickly the ball falls vertically? Consider the motion of the balls in the vertical direction alone."}], "solution": {"steps": ["Both balls experience the same gravitational acceleration in the vertical direction, regardless of their horizontal speed.", "The time it takes for each ball to fall 5.0 m is determined solely by the vertical motion.", "Since both balls fall the same distance under the same acceleration, they land at the same time. The correct answer is C."], "final_answer": "C"}, "provenance": {"generator": "mlx-community/Qwen2.5-32B-Instruct-4bit", "template_version": "0.1.0-spec", "seed": 2, "gen_attempt": 2, "checks": {"V2": "pass", "V3": "pass", "V4": "pass", "V5": "pass", "V6": "pass", "V9": "pass", "V10": "pass", "V7": "pass"}, "human_review": {"reviewed": false, "verdict": null}}}
+{"id": "physics-v1-N4-R1-5553fe5d", "split": "train", "topic": "N", "concept_id": "N4", "prereqs": ["N1"], "rung": "R1", "difficulty": "easy", "problem": {"template_id": "N4-R1-collision-forces", "params": {}, "text": "A truck collides head-on with a small car. During the collision, how do the forces they exert on each other compare?", "options": ["A) Only a truck exerts a force; a small car just gets pushed.", "B) A truck exerts a larger force on a small car than a small car exerts on it.", "C) The forces are equal in size and opposite in direction."]}, "ground_truth": {"answer": "C", "unit": null, "tolerance_rel": 0}, "attempts": [{"misconception_id": "MC09", "text": "I think the truck exerts a larger force on the small car because it's bigger and heavier. The small car just gets pushed, so the force it exerts is not as important. Therefore, I choose A.", "final_answer": "A"}], "feedback": [{"for_attempt": 0, "text": "If the truck exerts a larger force, shouldn't the small car move much more than the truck? How would both objects affect each other's motion in the collision?"}], "solution": {"steps": ["According to Newton's Third Law, for every action, there is an equal and opposite reaction.", "This means that the force the truck exerts on the small car is equal in size and opposite in direction to the force the small car exerts on the truck.", "The correct answer is C."], "final_answer": "C"}, "provenance": {"generator": "mlx-community/Qwen2.5-32B-Instruct-4bit", "template_version": "0.1.0-spec", "seed": 3, "gen_attempt": 0, "checks": {"V2": "pass", "V3": "pass", "V4": "pass", "V5": "pass", "V6": "pass", "V9": "pass", "V10": "pass", "V7": "pass"}, "human_review": {"reviewed": false, "verdict": null}}}
+{"id": "physics-v1-N5-R3-2f67b1dc", "split": "train", "topic": "N", "concept_id": "N5", "prereqs": ["N3"], "rung": "R3", "difficulty": "medium", "problem": {"template_id": "N5-R3-weight", "params": {"mass_kg": {"value": 12, "unit": "kg"}}, "text": "A factory has a piece of machinery with a mass of 12 kg placed on the Earth's surface. Calculate the weight of this machinery in newtons, given g = 9.8 m/s².", "options": null}, "ground_truth": {"answer": 118.0, "unit": "N", "tolerance_rel": 0.01}, "attempts": [{"misconception_id": "MC18", "text": "To find the weight of the machinery, I simply use the mass which is given as 12 kg. Since weight is the same as mass, the weight of the machinery is 12 N.", "final_answer": 12.0}], "feedback": [{"for_attempt": 0, "text": "Consider the difference between mass and weight. How does gravity play a role in calculating weight?"}], "solution": {"steps": ["The weight of an object is given by the mass multiplied by the gravitational acceleration.", "So, weight = 12 kg × 9.8 m/s²", "Therefore, weight = 118 N"], "final_answer": 118}, "provenance": {"generator": "mlx-community/Qwen2.5-32B-Instruct-4bit", "template_version": "0.1.0-spec", "seed": 1, "gen_attempt": 0, "checks": {"V2": "pass", "V3": "pass", "V4": "pass", "V5": "pass", "V6": "pass", "V9": "pass", "V10": "pass", "V7": "pass"}, "human_review": {"reviewed": false, "verdict": null}}}