| {"question_id": "P-10-Q17", "question": "A Comet is observed as it passes our solar system. Its closest\napproach to the sun is r = 6.67 × 10^10 m,at that time it has velocity\nv = 2 × 10^6 m/s. If G = 6.67 × 10^-11 N m^-2 kg^-2 and mass of the\nsun is 2 × 10^30kg. Then which of the following is true in respect with\nthis comet?", "question_images": [], "option_1": "The comet will return after 20 years", "option_2": "The comet will never return to the solar system", "option_3": "The comets\npath is circular", "option_4": "The comets total energy is negative", "correct_option": 2, "numerical_answer": null, "solution": "Total energy of the comet = U+K\n$= \\frac{- GM_{s}m}{r} + \\frac{1}{2}m\\left( 2 \\times 10^{6} \\right)^{2}$ where m mass\nof the Comet \n$= m\\left\\lbrack \\left( - 2 \\times 10^{9} \\right) + \\left( 2 \\times 10^{12} \\right) \\right\\rbrack$\n= 1998 m 10^9 = +ve\n[IMAGE] Comets will never returns to the solar system\nbecause total energy is +ve.", "solution_images": ["images/image60.png"], "subject": "Physics", "topic": "Gravitation", "subtopic": "Energy of satellite", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-10 Physics paper 1 30 October Jee Main.docx"} |
| {"question_id": "Ph-28-Q33", "question": "A small block of mass m is released from position A, inside the\nfrictionless circular groove of radius 2 m on a fixed inclined plane as\nshown in figure. The contact force between the block and inclined plane\nat point B is[IMAGE]. Find x", "question_images": ["images/image294.png", "images/image295.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": null, "numerical_answer": "7", "solution": "[IMAGE] TOPIC: Newton's law of motion\nSUB TOPIC: Circular motion\nLEVEL: Moderate", "solution_images": ["images/image296.png", "images/image297.png", "images/image298.png"], "subject": "Physics", "topic": "", "subtopic": "", "difficulty": "", "question_type": "numerical", "has_image": true, "exam": "JEE Main", "source_paper": "Ph-28 Physics paper FST 16 Jan.docx"} |
| {"question_id": "P-11-Q11", "question": "In the below figure, a bob a mass m is tied by a massless string\nwhose other end portion is wound on a fly wheel (disc) of radius r and\nmass m. When released from rest the bob starts falling vertically. When\nit has covered a distance of h, the angular speed of the wheel will be", "question_images": ["images/image107.jpeg"], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": 4, "numerical_answer": null, "solution": "[IMAGE] (no slipping)", "solution_images": ["images/image112.png", "images/image113.png", "images/image114.png", "images/image115.png", "images/image116.png"], "subject": "Physics", "topic": "Rigid Body Dynamics", "subtopic": "Conservation of mechanical energy", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-11 Physics paper-2 1Nov Jee Main.docx"} |
| {"question_id": "P-06-Q11", "question": "A hinged construction consists of three rhombus with the ratio\nof sides (5: 3: 2). Vertex A3 moves in the horizontal direction with\nvelocity V. Velocity of A2 will be", "question_images": ["images/image19.png"], "option_1": "2.5 V", "option_2": "1.5V", "option_3": "", "option_4": "0.8V", "correct_option": 4, "numerical_answer": null, "solution": "$u = \\frac{dy}{dt} = - 16\\sin\\theta\\frac{d\\theta}{dt}$\n$\\Rightarrow u = \\frac{4}{5}v = 0.8v$\nTOPIC: Newton's first law\nSUB TOPIC: Constraint motion", "solution_images": ["images/image20.png"], "subject": "Physics", "topic": "", "subtopic": "", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-06 Physics paper 14 October.docx"} |
| {"question_id": "P-19-Q10", "question": "Three harmonic waves having equal frequency v and same intensity\n$I_{0}$, have phase angles 0, $\\frac{\\pi}{4}$ and$- \\frac{\\pi}{4}$\nrespectively. When they are superimposed the intensity of the resultant\nwave is close to", "question_images": [], "option_1": "$5.8\\ I_{0}$", "option_2": "${3\\ I}_{0}$", "option_3": "$I_{0}$", "option_4": "$0.2\\ I_{0}$", "correct_option": 1, "numerical_answer": null, "solution": "$I_{res} = (\\sqrt{2} + 1)^{2}I_{0}$\n$= (3 + 2\\sqrt{2})I_{0} = 5.8I_{0}$", "solution_images": ["images/image16.png"], "subject": "Physics", "topic": "Wave Optics", "subtopic": "Superposition of waves", "difficulty": "Easy", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-19 Physics paper 28 Nov Fourth.docx"} |
| {"question_id": "P-16-Q21", "question": "If acceleration of block B w.r.t. A is $2m/s^{2}$just after the\nsystem is released from rest, then mass(in kg) of block C will be 5m.\nFind m. [pulley and string both are massless, take", "question_images": ["images/image39.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": null, "numerical_answer": "9", "solution": "[IMAGE] Given Condition is possible if$a_{B} - a_{A} = 2m/s^{2}$\nAnd $a_{A} = \\frac{30}{5} = 6m/s^{2} \\Rightarrow a_{a} = 8m/s^{2}$B & C\nwill move with same acc.$a_{B}$\n$\\Rightarrow mg - 50 = (m + 5)a_{B}$\n$10m - 50 = 8m + 40$\n$\\Rightarrow m = 45kg$", "solution_images": ["images/image40.png"], "subject": "Physics", "topic": "Newton's Laws of Motion", "subtopic": "Relative motion between blocks", "difficulty": "Moderate", "question_type": "numerical", "has_image": true, "exam": "JEE Main", "source_paper": "P-16 Physics paper 25 Nov First.docx"} |
| {"question_id": "P-21-Q3", "question": "Consider a sphere of radius R which carries a uniform charge\ndensity $\\rho$. If a sphere of radius $\\frac{R}{2}$ is carved out of it,\nas shown, the\nratio$\\left| \\frac{{\\overset{\\rightarrow}{E}}_{A}}{{\\overset{\\rightarrow}{E}}_{B}} \\right|$\nof magnitude of electric field of magnitude of electric field\n${\\overset{\\rightarrow}{E}}_{A}$and ${\\overset{\\rightarrow}{E}}_{B}$,\nrespectively, atpoints A and B due to the remaining portion is:,d R f= xksys esa leku /uRo $\\rho$ forfjr gSA;fn bl\nxksys $\\frac{R}{2}$ f= xksykdkVDj fp=kuqlkj fudky rks\ncps gq, Hkkx j.k fcUnqvksa A rFkk B ijfo|qr {ks=k ¼Ø ½", "question_images": ["images/image3.png", "images/image4.png", "images/image5.png", "images/image6.png"], "option_1": "$\\frac{18}{34}$", "option_2": "$\\frac{21}{34}$", "option_3": "$\\frac{17}{54}$", "option_4": "$\\frac{18}{54}$", "correct_option": 1, "numerical_answer": null, "solution": "For a solid sphere Bksl xksys ds fy, e\n$E = \\frac{\\rho r}{3\\varepsilon_{0}}$\n$E_{A} = \\frac{- \\rho R}{2\\left( 3\\varepsilon_{0} \\right)}$\n$\\left| E_{A} \\right| = \\frac{\\rho R}{6\\varepsilon_{0}}$\nElectric field at point ¼fcUnq B ijkfo|qr {ks=k dh rhozrk½ B = E_B =\nE_1A + E_2A\nE_1A= Electric Field Due to solid sphere of radius R at\npoint $B = \\frac{\\rho R}{3\\varepsilon_{0}}$\nE_1A= R f= Bkslxksys j.k fcUnqBijfo|qr {ks=k dh\nrhozrk$= \\frac{\\rho R}{3\\varepsilon_{0}}$\nE_2A = Electric Field Due to solid sphere of radius R/2 (which having\ncharge density -$\\rho$)\nE_2A = R/2 f= Bksl xksys ¼ftl ?kuRo- $\\rho$ gS½", "solution_images": [], "subject": "Physics", "topic": "Electrostatics", "subtopic": "Electric field by uniformly charged sphere", "difficulty": "Tough", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-21 Physcis Paper 19 Dec Hindi Eng..docx"} |
| {"question_id": "P-09-Q7", "question": "Three simple harmonic motions in the same direction, having the\nsame amplitude A and same time period, are superimposed. If each differs\nin phase from the next by 45^0, then", "question_images": [], "option_1": "the resultant amplitude is 2[IMAGE]", "option_2": "the phase of the resultant motion relative to the first is 90^o", "option_3": "the energy associated with the resulting motion is\n[IMAGE] times the energy associated with any single\nmotion", "option_4": "the resulting motion is not simple harmonic.", "correct_option": 3, "numerical_answer": null, "solution": "", "solution_images": ["images/image33.png", "images/image34.png", "images/image35.png", "images/image36.png", "images/image37.png"], "subject": "Physics", "topic": "Wave", "subtopic": "Superposition of waves", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-09 Physics paper 26 October.docx"} |
| {"question_id": "P-13-Q12", "question": "The figure gives experimentally measured B vs. H variation in a\nferromagnetic material. The retentivity, coercivity and saturation,\nrespectively, of the material are", "question_images": ["images/image15.png"], "option_1": "1.0 T, 50 A/m and 1.5 T", "option_2": "150 A/m, 1.0 T and 1.5 T", "option_3": "1.5 T, 50 A/m and 1.0 T", "option_4": "1.5T, 50 A/m and 1.0 T", "correct_option": 1, "numerical_answer": null, "solution": "[IMAGE] x = retentivity\ny = coercivity\nz = saturation magnetization", "solution_images": ["images/image16.png"], "subject": "Physics", "topic": "Magnetism", "subtopic": "Hysteresis loop", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-13 Physics paper 4 Nov.docx"} |
| {"question_id": "P-23-Q22", "question": "The figure gives experimentally measured B vs. H variation in a\nferromagnetic material. The retentivity, coercivity and saturation,\nrespectively, of the material are", "question_images": ["images/image52.png"], "option_1": "1.0 T, 50 A/m and 1.5 T", "option_2": "150 A/m, 1.0 T and 1.5 T", "option_3": "1.5 T, 50 A/m and 1.0 T", "option_4": "1.5T, 50 A/m and 1.0 T", "correct_option": 1, "numerical_answer": null, "solution": "[IMAGE] x = retentivity\ny = coercivity\nz = saturation magnetization", "solution_images": ["images/image53.png"], "subject": "Physics", "topic": "Magnetism", "subtopic": "Hysteresis loop", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-23 Physcis Paper 31 Dec FST.docx"} |
| {"question_id": "P-09-Q6", "question": "The second overtone of an open organ pipe A and that of a closed\npipe B have the same frequency at a given temperature. It follows that\nthe ratio of the", "question_images": [], "option_1": "length of A and B is 4: 3", "option_2": "fundamental frequencies of A and B is 5: 6", "option_3": "length of B to length of A is 5: 6", "option_4": "frequencies of first overtone of A and B is 10: 9", "correct_option": 4, "numerical_answer": null, "solution": "", "solution_images": ["images/image25.png", "images/image26.png", "images/image27.png", "images/image28.png", "images/image29.png", "images/image30.png"], "subject": "Physics", "topic": "Sound wave", "subtopic": "Organ pipe", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-09 Physics paper 26 October.docx"} |
| {"question_id": "P-03-Q12", "question": "Block M slide down on frictionless inclined plane as shown. Find\nfrictional force acting on block m while it is at rest with respect to\nthe block M. (m = 2kg, M = 5kg, g = 10 m/sec2)", "question_images": ["images/image69.png"], "option_1": "8.5 N", "option_2": "9.6 N", "option_3": "12.8 N", "option_4": "16.5 N\n M m \n M (m = 2kg, M =\n5kg, g = 10 m/sec2)", "correct_option": 2, "numerical_answer": null, "solution": "a = g sin 37°\nf = m × a × cos 37°\nTOPIC: NLM\nSUB TOPIC: NEWTON'S SECOND LAW", "solution_images": [], "subject": "Physics", "topic": "", "subtopic": "", "difficulty": "Tough", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-03 Paper 1 (Physics) Eng. + Hindi 24-8-2020.docx"} |
| {"question_id": "P-11-Q14", "question": "A thin uniform rod of mass is hinged at\none end. This rod is maintained in horizontal position by colliding very\ntiny balls each of mass m/10 completely elastically 10 times per sec\nstriking at the opposite end as shown in figure. Find the speed of the", "question_images": ["images/image143.png", "images/image144.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": 2, "numerical_answer": null, "solution": "[IMAGE] Taking torque about hinge", "solution_images": ["images/image145.png", "images/image146.png", "images/image147.png", "images/image148.png"], "subject": "Physics", "topic": "Rigid Body Dynamics", "subtopic": "Torque", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-11 Physics paper-2 1Nov Jee Main.docx"} |
| {"question_id": "P-17-Q1", "question": "A concave mirror of radius of curvature 40 cm is filled with\nwater (n=4/3) upto a height of 12 cm. A point object O is kept on the\nprincipal axis of the mirror at height 13.5 cm from the water surface.\nThe final image formed after refraction at water surface, reflection at\nmirror and again refraction at water surface in succession is situated\nat.", "question_images": ["images/image1.png"], "option_1": "36 cm above the water surface", "option_2": "24 cm above the water surface", "option_3": "20 cm above the water surface", "option_4": "12 cm above the water surface", "correct_option": 1, "numerical_answer": null, "solution": "Refraction -1: Apparent depth from water surface\n$d^{'} = 13.5 \\times \\frac{4}{3} = 18cm$\nReflection from concave mirror.\n$\\frac{1}{v} + \\frac{1}{( - 30)} = \\frac{1}{- 20}$\n$v = - 60cm$\nImage is formed 48 cm above water surface\nRefraction-2: $d^{''} = \\frac{48}{4/3} = 36cm$ above water surface", "solution_images": [], "subject": "Physics", "topic": "Ray Optics", "subtopic": "Apparent depth", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-17 Physics paper 26 Nov Second.docx"} |
| {"question_id": "P-13-Q13", "question": "The magnitude of magnetic field at O (centre of the circular\npart) of the current carrying coil as shownis", "question_images": ["images/image17.png"], "option_1": "$\\frac{\\mu_{0}i}{4\\pi}\\left( \\frac{3\\pi}{a} + \\frac{\\sqrt{2}}{b} \\right)$", "option_2": "$\\frac{\\mu_{0}i}{2\\pi}\\left( \\frac{3\\pi}{2a} + \\frac{\\sqrt{2}}{b} \\right)$", "option_3": "$\\frac{\\mu_{0}i}{2\\pi}\\left( \\frac{\\pi}{3a} + \\frac{3}{\\sqrt{2}b} \\right)$", "option_4": "$\\frac{\\mu_{0}i}{4\\pi}\\left( \\frac{3\\pi}{2a} + \\frac{\\sqrt{2}}{b} \\right)$", "correct_option": 4, "numerical_answer": null, "solution": "Magnetic field due to circular\nsegment$= \\frac{3}{4} \\cdot \\frac{\\mu_{0}i}{2a}$\n Due to one straight wire\nsegment $= \\frac{\\mu_{0}i}{4\\pi b}\\left( sin45^{\\circ} + sin0^{\\circ} \\right) = \\frac{\\mu_{0}i}{4\\sqrt{2}\\pi b}$\nNet field\n$= \\frac{3\\mu_{0}i}{8a} + 2 \\times \\frac{\\mu_{0}i}{4\\sqrt{2}\\pi b} = \\frac{\\mu_{0}i}{4\\pi}\\left( \\frac{3\\pi}{2a} + \\frac{\\sqrt{2}}{b} \\right)$.", "solution_images": [], "subject": "Physics", "topic": "Magnetic effect of current", "subtopic": "Magnetic field due to current carrying conductor", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-13 Physics paper 4 Nov.docx"} |
| {"question_id": "Ph-28-Q25", "question": "When photon of energy\n[IMAGE] strikes the surface of a metal A, the ejected photoelectrons have\nmaximum kinetic energy Ta eV and de-Broglie\nwavelength[IMAGE]. The maximum kinetic energy of photoelectrons liberated\nfrom another metal B by photon of energy\n[IMAGE] is [IMAGE] If the de-Broglie wavelength of these\nphotoelectrons[IMAGE], then the work function of metal B is", "question_images": ["images/image228.png", "images/image229.png", "images/image230.png", "images/image231.png", "images/image232.png"], "option_1": "2 eV", "option_2": "3 eV", "option_3": "1.5 eV", "option_4": "4 eV", "correct_option": 4, "numerical_answer": null, "solution": "Relation between De-Broglie wavelength and K. E. is", "solution_images": ["images/image233.png", "images/image234.png", "images/image235.png", "images/image236.png"], "subject": "Physics", "topic": "Dual Nature of Matter", "subtopic": "Einstein's photoelectric equation", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "Ph-28 Physics paper FST 16 Jan.docx"} |
| {"question_id": "P-09-Q24", "question": "A non−uniform string of mass 45 kg and length 1.5 m has a\nvariable linear mass density given by μ = kx, where x is the distance\nfrom one end of the string and k is a constant. Tension in the string is\n15 N which is uniform. If the time (in second) required for a pulse\ngenerated at one end of the string to travel to the other end is x, then\nfind the value of 2x.", "question_images": [], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": null, "numerical_answer": "4", "solution": "", "solution_images": ["images/image148.png", "images/image149.png", "images/image150.png", "images/image151.png"], "subject": "Physics", "topic": "Wave on a string", "subtopic": "variable linear mass density", "difficulty": "Moderate", "question_type": "numerical", "has_image": true, "exam": "JEE Main", "source_paper": "P-09 Physics paper 26 October.docx"} |
| {"question_id": "P-03-Q4", "question": "t = 0 \n-10 m", "question_images": ["images/image12.png"], "option_1": "1s", "option_2": "", "option_3": "5s", "option_4": "2s", "correct_option": 3, "numerical_answer": null, "solution": "a = - 3t + 5\n[IMAGE] ∆x = [IMAGE] + [IMAGE] ∆x = 0\n⇒[IMAGE] t = 0s & t = 5s\nTOPIC:KINEMATIC\nSUB TOPIC: ACCERATION", "solution_images": ["images/image14.png", "images/image15.png", "images/image16.png", "images/image17.png", "images/image18.png", "images/image19.png"], "subject": "Physics", "topic": "", "subtopic": "", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-03 Paper 1 (Physics) Eng. + Hindi 24-8-2020.docx"} |
| {"question_id": "P-13-Q22", "question": "At time t = 0 magnetic field of 1000 Gauss is passing\nperpendicularly through the area defined by theclosed loop shown in the\nfigure. If the magnetic field reduces linearly to 500 Gauss, in the next\n5 s, theninduced EMF in $\\mu V$in the loop is 8n. Find n", "question_images": ["images/image24.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": null, "numerical_answer": null, "solution": "$\\varepsilon = \\left| - \\frac{d\\varphi}{dt} \\right| = \\left| - \\frac{AdB}{dt} \\right|$\n$=.(16 \\times 4 - 4 \\times 2)\\frac{(1000 - 500)}{5} \\times 10^{- 4} \\times 10^{- 4}$\n$= 56 \\times \\frac{500}{5} \\times 10^{- 8} = 56 \\times 10^{- 6}V$", "solution_images": [], "subject": "Physics", "topic": "EMI", "subtopic": "Induced emf", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-13 Physics paper 4 Nov.docx"} |
| {"question_id": "P-09-Q14", "question": "A train is moving with a constant speed 15 m/s along a circular\ntrack. The length of the train makes an angle 90º at the centre. A siren\nin its engine is emitting a sound of frequency 1.5kHz. Find the apparent\nfrequency of sound as heard by a passenger at the rear end of the train.", "question_images": [], "option_1": "2.5kHz", "option_2": "1.5kHz", "option_3": "3.5kHz", "option_4": "4.5kHz", "correct_option": 2, "numerical_answer": null, "solution": "", "solution_images": ["images/image81.png", "images/image82.png", "images/image83.png", "images/image84.png"], "subject": "Physics", "topic": "Sound", "subtopic": "Doppler effect", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-09 Physics paper 26 October.docx"} |
| {"question_id": "P-23-Q12", "question": "The current I_1 (in A) flowing through 1$\\Omega$ resistor in\nthe following circuit is", "question_images": ["images/image29.png"], "option_1": "0.2", "option_2": "0.4", "option_3": "0.5", "option_4": "0.25", "correct_option": 1, "numerical_answer": null, "solution": "$i = \\frac{I}{2} = 0.2A$", "solution_images": ["images/image30.png"], "subject": "Physics", "topic": "Current Electricity", "subtopic": "KVL", "difficulty": "Easy", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-23 Physcis Paper 31 Dec FST.docx"} |
| {"question_id": "Ph-26-Q7", "question": "One mole of an ideal gas at pressure P_0, volume V_0 and\ntemperature T_0 is expanded isothermally to twice its volume and then\ncompressed at constant pressure to (V_0/2) and the gas is brought back\nto original state by a process in which P ∝ V (Pressure is directly\nproportional to volume). The correct representation of process is\n[IMAGE] rFkk rkieku nqxqus:i ls çlkfjr dh tkrh gSrFkk fQj lenkoh çØe rd laihfMr dh tkrh gS rFkk xSl dks okil çkjfEHkd\nvoLFkk esa,sls çØe lsykrs gS ftl ¼ lekuqikrh gksrk gS½ gS rks mijksä çØe", "question_images": ["images/image15.png", "images/image16.png", "images/image17.png", "images/image18.png", "images/image19.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": 3, "numerical_answer": null, "solution": "Process AB is isothermal expansion BC is isobaric compression\nand in process CA\nizfØ;k AB lerkih izlkj gS rFkk BC lenkch laihMu", "solution_images": ["images/image24.png", "images/image25.png"], "subject": "Physics", "topic": "Thermodynamics", "subtopic": "P-V diagram", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "Ph-26 Physics paper 1 15 Jan.docx"} |
| {"question_id": "P-11-Q16", "question": "In the figure (i) a disc of mass M(kg) and radius R(m) is\nrotating smoothly about a fixed vertical axis AB with angular speed 26\nrad/s. A rod CD of length [IMAGE] and mass M(kg) is\nhinged at one end at point on the disc. The rod remains in vertical\nposition and rotates along with the disc about axis AB. At some moment\nthe rod CD gets a very small impulse at point due to air due to\nwhich the rod falls on the disc along one radius and sticks to the disc\nas shown in figure (ii). Now find the angular velocity of the disc in", "question_images": ["images/image158.png", "images/image159.png"], "option_1": "$\\frac{11}{13}\\omega$", "option_2": "$\\frac{15}{13}\\omega$", "option_3": "$\\frac{17}{13}\\omega$", "option_4": "$\\frac{18}{13}\\omega$", "correct_option": 4, "numerical_answer": null, "solution": "MI of the system when rod is vertical\n[IMAGE] MI of system when rod is horizontal\n[IMAGE] From conservation of angular momentum of system about axis AB is", "solution_images": ["images/image160.png", "images/image161.png", "images/image162.png"], "subject": "Physics", "topic": "Rigid Body Dynamics", "subtopic": "Conservation of angular momentum", "difficulty": "", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-11 Physics paper-2 1Nov Jee Main.docx"} |
| {"question_id": "P-16-Q4", "question": "Two children are playing a game in which they try to hit a small\nbox using a spring-loaded marble gun, which is fixed rigidly to a table\nis a height h above the top of the box. The spring has a spring constant\nk and the edge of the box is some unknown horizontal distance\n$\\mathcal{l}$ away from the table. The first child compresses the spring\na distance x and finds that the marble falls short of its target by a\nhorizontal distance y. The second child compresses the spring by an\nextra amount $\\Delta x$ so that marble lands in the box. The value of\n$\\Delta x$is $y\\sqrt{\\frac{mg}{Nhk}}$ (Where N is integer) then find the\nvalue of N.", "question_images": ["images/image10.png"], "option_1": "5", "option_2": "3", "option_3": "2", "option_4": "4", "correct_option": 3, "numerical_answer": null, "solution": "time taken or time of flight is same for both projectiles.\ni.e. $t = \\sqrt{\\frac{2h}{g}}$\nusing energy conservation:\n$\\Rightarrow \\frac{1}{2}{kx}^{2} = \\frac{1}{2}{mv}^{2}$.......(1)\n$\\Rightarrow \\frac{1}{2}k(x + \\Delta x)^{2} = \\frac{1}{2}mv^{'2}$.......(2)\n$\\mathcal{l -}y = vt$.......(3)\n$\\mathcal{l =}v't$.......(4)\nOn solving we get\n$\\Delta x = y\\sqrt{\\frac{mg}{2hk}}$\nN = 2", "solution_images": [], "subject": "Physics", "topic": "Work Power & Energy", "subtopic": "Conservation of mechanical energy", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-16 Physics paper 25 Nov First.docx"} |
| {"question_id": "P-19-Q14", "question": "An object is gradually moving away from the focal point of a\nconcave mirror along the axis of the mirror. The graphical\nrepresentation of the magnitude of linear magnification (m) versus\ndistance of the object from the mirror (x) is correctly qiven by (Graphs\nare drawn schematically and are not to scale)", "question_images": [], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": 1, "numerical_answer": null, "solution": "At focus, magnification is $\\infty$", "solution_images": [], "subject": "Physics", "topic": "Ray Optics", "subtopic": "Magnification and position of object graph", "difficulty": "Easy", "question_type": "single_correct", "has_image": false, "exam": "JEE Main", "source_paper": "P-19 Physics paper 28 Nov Fourth.docx"} |
| {"question_id": "P-07-Q7", "question": "Find momentum of inertia about an axis passing through COM of\nsystem and it is perpendicular to theplane of 3 rods.", "question_images": ["images/image15.png"], "option_1": "${mL}^{2}\\left( \\frac{7}{3} \\right)$", "option_2": "${mL}^{2}\\left( \\frac{2}{3} \\right)$", "option_3": "${mL}^{2}\\left( \\frac{5}{2} \\right)$", "option_4": "${mL}^{2}\\left( \\frac{1}{2} \\right)$", "correct_option": 1, "numerical_answer": null, "solution": "$\\because I_{2} = I_{3}$\n$= \\frac{(2m)(2L)^{2}}{12} + 2\\left\\lbrack \\frac{{ML}^{2}}{12} + {Md}^{2} \\right\\rbrack$\n$= {mL}^{2}\\left( \\frac{2 \\times 2 \\times 2}{12} \\right) + 2\\left( \\frac{1}{12} + \\frac{3}{4} \\right){mL}^{2}$\n${mL}^{2}\\left( \\frac{2}{3} \\right) + 2\\left( \\frac{1 + 9}{12} \\right){mL}^{2}$\n${mL}^{2}\\left( \\frac{2}{3} \\right) + 2\\left( \\frac{1 + 9}{12} \\right){mL}^{2}$\n$= {mL}^{2}\\lbrack\\left( \\frac{2}{3} \\right) + \\frac{20}{12}\\rbrack$\n$I_{net\\ } = {mL}^{2}\\left( \\frac{7}{3} \\right)$", "solution_images": ["images/image16.png"], "subject": "Physics", "topic": "Rigid Body Dynamics", "subtopic": "Moment of inertia", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-07 Physics paper 17 October.docx"} |
| {"question_id": "Ph-28-Q35", "question": "A man and car both starts moving from rest simultaneously along\nthe same straight line in such a way that acceleration of A and B are\ngiven by\nA will catch B in time T. Then T is", "question_images": ["images/image312.png", "images/image313.png", "images/image314.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": null, "numerical_answer": "6", "solution": "Let study the motion of A with respect to B\n[IMAGE] a = t\n[IMAGE] TOPIC:Rectilinear motion\nSUB TOPIC:Non-Uniform acceleration", "solution_images": ["images/image315.png", "images/image316.png", "images/image317.png", "images/image318.png", "images/image319.png", "images/image320.png", "images/image321.png", "images/image322.png"], "subject": "Physics", "topic": "", "subtopic": "", "difficulty": "Moderate", "question_type": "numerical", "has_image": true, "exam": "JEE Main", "source_paper": "Ph-28 Physics paper FST 16 Jan.docx"} |
| {"question_id": "P-22-Q13", "question": "A force F= 4t acts on a particle of mass 1kg. If the particle\nstarts from rest the work done by the force during the first 2 second\nwill be 8n J, find n.", "question_images": [], "option_1": "4", "option_2": "6", "option_3": "5", "option_4": "3", "correct_option": 1, "numerical_answer": null, "solution": "$\\frac{dv}{dt} = 4t$ $\\int_{0}^{v}{dv} = 4\\int_{0}^{t}{t\\ dt}$\n$V = 2t^{2}$\n$ds = 2t^{2}dt$\n$W = \\int_{}^{}{Fds\\ cos0^{\\circ}}$\n$= \\int_{0}^{2}\\mspace{2mu} 4t \\cdot 2t^{2}dt$\n$= 8\\left\\lbrack \\frac{t^{4}}{4} \\right\\rbrack_{0}^{2}$", "solution_images": ["images/image37.png", "images/image38.png"], "subject": "Physics", "topic": "Work Power & Energy", "subtopic": "Work done by variable force", "difficulty": "Tough", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-22 Physcis Paper 19 Dec Eng..docx"} |
| {"question_id": "P-07-Q15", "question": "A particle performs uniform circular motion with an angular\nmomentum L. If thefrequency of particle's motion is doubled and its\nkinetic energy is halved, the angularmomentum becomes", "question_images": [], "option_1": "2L", "option_2": "4L", "option_3": "", "option_4": "", "correct_option": 4, "numerical_answer": null, "solution": "$L = I\\omega$\n$\\omega^{'} = 2\\omega$\n$\\frac{1}{2}\\left( \\frac{1}{2}I\\omega^{2} \\right) = \\frac{1}{2}I^{'}\\omega^{'2}$\n$\\frac{I\\omega^{2}}{2} = I^{'}4\\omega^{2}$\n$I^{'} = \\left( \\frac{I}{8} \\right) \\Rightarrow L^{'} = I^{'}\\omega^{'} = \\frac{I}{8}2\\omega = \\frac{I\\omega}{4} = (L/4)$", "solution_images": [], "subject": "Physics", "topic": "Rigid Body Dynamics", "subtopic": "Angular momentum in pure rotation", "difficulty": "Easy", "question_type": "single_correct", "has_image": false, "exam": "JEE Main", "source_paper": "P-07 Physics paper 17 October.docx"} |
| {"question_id": "Ph-28-Q30", "question": "A river is flowing with velocity 5 km/hr relative to the ground\nas shown in the figure. A boat starts from A and reaches the other bank\nby covering shortest possible distance. Velocity of boat in still water\nis 3 km/hr. The distance (in m) boat covers is s. The value", "question_images": ["images/image264.png", "images/image265.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": null, "numerical_answer": "1", "solution": "For drift to be minimum\n[IMAGE] time taken by boat to cross the river = t\n So, distance covered[IMAGE] TOPIC:Motion in a plane\nSUB TOPIC:Relative motion", "solution_images": ["images/image266.png", "images/image267.png", "images/image268.png", "images/image269.png", "images/image270.png", "images/image271.png", "images/image272.png"], "subject": "Physics", "topic": "", "subtopic": "", "difficulty": "Moderate", "question_type": "numerical", "has_image": true, "exam": "JEE Main", "source_paper": "Ph-28 Physics paper FST 16 Jan.docx"} |
| {"question_id": "Ph-25-Q5", "question": "A monoatomic ideal gas follows the process:\nThe molar specific heat for this process is: ( R = gas constant)\nbl çØe ds fy, eksyj", "question_images": ["images/image14.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "R", "correct_option": 2, "numerical_answer": null, "solution": "[IMAGE] For polytropic process, cgqijek.koh; izØe", "solution_images": ["images/image14.png", "images/image18.png", "images/image19.png", "images/image20.png", "images/image21.png", "images/image22.png", "images/image23.png"], "subject": "Physics", "topic": "Thermodynamics", "subtopic": "Adiabatic process", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "Ph-25 Physics paper 7 Jan.docx"} |
| {"question_id": "P-03-Q18", "question": "The net power P of all the forces acting on a particle versus time\ncurve is shown. Work done upon the particle from A to B", "question_images": ["images/image112.png"], "option_1": "Increases", "option_2": "Decreases", "option_3": "First increases then decreases", "option_4": "First decreases then increases\n (P) A B", "correct_option": 1, "numerical_answer": null, "solution": "Area under the graph || [IMAGE] Area under graph increases, hence work done upon the particle from A to\nB increases.\nTOPIC: WPE\nSUB TOPIC: POWER", "solution_images": ["images/image113.png"], "subject": "Physics", "topic": "", "subtopic": "", "difficulty": "Easy", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-03 Paper 1 (Physics) Eng. + Hindi 24-8-2020.docx"} |
| {"question_id": "Ph-26-Q15", "question": "If two soap bubbles of different radii are connected by a tube:;fn fofHkUu f= nks lkcqu ds cqycqyksa", "question_images": [], "option_1": "air flows from the bigger bubble to the smaller bubble till the\nsizes become", "option_2": "air flows from bigger bubble to the smaller bubble till the sizes\nare intercha", "option_3": "air flows from the smaller bubble to the bigger bubble", "option_4": "there is no flow of air", "correct_option": 3, "numerical_answer": null, "solution": "The excess pressure inside the soap bubble in inversely\nproportional to radius of soap bubble i.e. $P \\propto 1/r$, r being the\nradius of bubble. It follows that pressure inside a smaller bubble is\ngreater than that inside a bigger bubble. Thus, if these two bubbles are\nconnected by a tube, air will flow from smaller bubble to bigger bubble\nand the bigger bubble grows at the expense of the smaller one.\ncqycqys cqycqys dh f= Øekuqikrh gksrk gSA\n$P \\propto 1/r$] tgk¡ rcqycqys dh f= SA vr NksVs cqycqys esa cM+s\ncqycqys dh rqyuk gskxk;fn nksuksa cqycqyksa dks\nufy tksM+k rks gok NksVs cqycqys", "solution_images": [], "subject": "Physics", "topic": "Mechanical properties of liquid", "subtopic": "Surface tension", "difficulty": "Moderate", "question_type": "single_correct", "has_image": false, "exam": "JEE Main", "source_paper": "Ph-26 Physics paper 1 15 Jan.docx"} |
| {"question_id": "P-11-Q13", "question": "A thin walled hollow cylinder is closed from both the ends. The\nmass of the curved part is m and the mass of each circular part is also\nm. The radius of the cylinder is R and its length is 2R. What will be\nthe moment of inertia of this hollow cylinder about the axis,\nperpendicular to its length and passing through its centre of mass?", "question_images": ["images/image129.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": 1, "numerical_answer": null, "solution": "First find I of the hollow tube\n[IMAGE] Where [IMAGE] So [IMAGE] Now moment of inertias of each circular plate about that axis.", "solution_images": ["images/image135.png", "images/image136.png", "images/image137.png", "images/image138.png", "images/image139.png", "images/image140.png", "images/image141.png", "images/image142.png"], "subject": "Physics", "topic": "Rigid Body Dynamics", "subtopic": "Moment of inertia", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-11 Physics paper-2 1Nov Jee Main.docx"} |
| {"question_id": "Ph-26-Q38", "question": "Figure below shows two paths that may be taken by a gas to go\nfrom a state A to a state C.\n[IMAGE] In process AB, 400J of heat is added to the system and in process BC,\n100 J of heat is added to the system. The heat absorbed by the system\nin the process AC (in J) is 230n. Find n.;gk¡ nks iFk ftu \nA ls voLFkk B rd ys tk;k tk ldrk gSA\n s AB] çØe esa 400 J rFkk çØe BC esa 100 J nh tkrh gSA\nrks] çØe AC (in J) 230 n gSA rks n\nKkr dhft,A", "question_images": ["images/image172.png", "images/image173.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": null, "numerical_answer": "2", "solution": "For a complete cycle\niw.kZ pfØ; çØe ds fy,\nQ_cycle = W_cycle\n$+ 400 + 100 + Q_{C \\rightarrow A} = \\frac{1}{2}\\left( 2 \\times 10^{- 3} \\right)\\left( 4 \\times 10^{4} \\right)$\n⇒ Q~C→ A~ = - 460 J\n⇒ Q_A→C = + 460 J", "solution_images": [], "subject": "Physics", "topic": "Thermodynamics", "subtopic": "", "difficulty": "Moderate", "question_type": "numerical", "has_image": true, "exam": "JEE Main", "source_paper": "Ph-26 Physics paper 1 15 Jan.docx"} |
| {"question_id": "P-09-Q4", "question": "An observer moves towards a stationary source of sound with speed\none - fifth of speed of sound, then", "question_images": [], "option_1": "apparant wavelength increases", "option_2": "apparant wavelength decreases", "option_3": "apparant frequency increases by 20", "option_4": "apparant frequency decreases by 25", "correct_option": 3, "numerical_answer": null, "solution": "", "solution_images": ["images/image17.png", "images/image18.png", "images/image19.png", "images/image20.png"], "subject": "Physics", "topic": "Sound wave", "subtopic": "Doppler effect", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-09 Physics paper 26 October.docx"} |
| {"question_id": "P-15-Q4", "question": "The energy required to ionize a hydrogen like ion in its ground\nstate is 9Rydbergs. What is the wavelength of the radiation emitted when\nthe electron in this ion jumps from the second excited state to the\nground state", "question_images": [], "option_1": "24.2 nm", "option_2": "6.8 nm", "option_3": "35.8 nm", "option_4": "11.4 nm", "correct_option": 4, "numerical_answer": null, "solution": "", "solution_images": ["images/image31.png", "images/image32.png", "images/image33.png", "images/image34.png", "images/image35.png", "images/image36.png", "images/image37.png"], "subject": "Physics", "topic": "Atomic Physics", "subtopic": "Radiation emitted by electron", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-15 Physics paper 11 Nov.docx"} |
| {"question_id": "P-15-Q20", "question": "An electron (of mass m) and a photon have the same energy E in\nthe range of a few[IMAGE]. The ratio of the de-Broglie\nwavelength associated with the electron and the wavelength of the photon\nis (c = speed of light in vacuum)", "question_images": ["images/image151.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": 4, "numerical_answer": null, "solution": "", "solution_images": ["images/image156.png", "images/image157.png", "images/image158.png", "images/image159.png", "images/image160.png"], "subject": "Physics", "topic": "Dual Nature of Matter", "subtopic": "De brogle wavelength", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-15 Physics paper 11 Nov.docx"} |
| {"question_id": "P-07-Q6", "question": "A mass supported by a massless string wound around a\nuniform hollow cylinder of mass m and radius R. If the string does not\nslip on the cylinder, with what acceleration will the mass fall on\nrelease?", "question_images": ["images/image13.png"], "option_1": "$\\frac{3g}{3}$", "option_2": "$\\frac{g}{2}$", "option_3": "$\\frac{5g}{6}$", "option_4": "g", "correct_option": 2, "numerical_answer": null, "solution": "[IMAGE] mg - T = ma....(1)\nT.R = mR^2$\\frac{a}{R}$....(2)\n$\\frac{g}{2} = a$", "solution_images": ["images/image14.png"], "subject": "Physics", "topic": "Rigid Body Dynamics", "subtopic": "Rotation about a fixed axis", "difficulty": "Easy", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-07 Physics paper 17 October.docx"} |
| {"question_id": "P-15-Q14", "question": "Boolean relation at the output stage-Y for the following circuit\nis", "question_images": ["images/image105.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": 2, "numerical_answer": null, "solution": "First part of figure shown is OR gate and\nSecond part of figure shown is NOT gate", "solution_images": ["images/image110.png", "images/image111.png"], "subject": "Physics", "topic": "Electronic device", "subtopic": "Boolean relation", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-15 Physics paper 11 Nov.docx"} |
| {"question_id": "Ph-26-Q2", "question": "The following four wires are made of the same material. Which of\nthese will have the largest extension when the same tension is applied?\nfuEu pkj rkj leku inkFkZ ds cus\nvf/kdre gksxk tc leku ruko vkjksfir A", "question_images": [], "option_1": "Length 50 cm and diameter 0.5 mm", "option_2": "Length 100 cm and diameter 1 mm", "option_3": "Length 200 cm and diameter 2 mm", "option_4": "Length 300 cm and diameter 3 mm", "correct_option": 1, "numerical_answer": null, "solution": "$Y = \\frac{FL}{\\pi r^{2}\\mathcal{l}}$\n$\\therefore\\mathcal{l =}\\frac{FL}{\\pi r^{2}Y} \\Rightarrow \\mathcal{l \\propto}\\frac{L}{r^{2}}$\n$\\therefore\\frac{L}{r^{2}}$is greatest for option A. fodYi A", "solution_images": [], "subject": "Physics", "topic": "Mechanical properties of matter", "subtopic": "Elongation in wire", "difficulty": "Moderate", "question_type": "single_correct", "has_image": false, "exam": "JEE Main", "source_paper": "Ph-26 Physics paper 1 15 Jan.docx"} |
| {"question_id": "P-19-Q5", "question": "The aperture diameter of a telescope is 5 m. The separation\nbetween the moon and the earth is $4 \\times 10^{5}$km. With light of\nwavelength of 5893 A, the minimum separation between objects on the\nsurface ofmoon, so that they are just resolved, is close to", "question_images": [], "option_1": "600 m", "option_2": "20 m", "option_3": "200 m", "option_4": "58 m", "correct_option": 4, "numerical_answer": null, "solution": "$\\theta = 1.22\\frac{\\lambda}{a}$\n[IMAGE] Distance $= O_{1}O_{2} = d\\theta = 1.22\\frac{\\lambda}{a}d$\nDistance\n$= O_{1}O_{2} = \\frac{1.22 \\times 5893 \\times 10^{- 10} \\times 4 \\times 10^{8}}{5} \\approx 57.5m$\nanswer from options = 58 m\n(minimum distance)", "solution_images": ["images/image7.png"], "subject": "Physics", "topic": "Wave Optics", "subtopic": "Diffraction", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-19 Physics paper 28 Nov Fourth.docx"} |
| {"question_id": "Ph-27-Q40", "question": "Two moles of an ideal gas with [IMAGE] are mixed\nwith 3 moles of another ideal gas with [IMAGE] Thevalue\nof [IMAGE] for the mixture is (10+n)/12. Find n.\neksy=", "question_images": ["images/image244.png", "images/image245.png", "images/image246.png", "images/image244.png", "images/image245.png", "images/image246.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": null, "numerical_answer": "7", "solution": "[IMAGE] On rearranging we getiqu ij", "solution_images": ["images/image247.png", "images/image248.png"], "subject": "Physics", "topic": "Kinetic Theory of Gases", "subtopic": "Heat capacity", "difficulty": "Moderate", "question_type": "numerical", "has_image": true, "exam": "JEE Main", "source_paper": "Ph-27 Physics paper 2 15 Jan.docx"} |
| {"question_id": "Ph-27-Q34", "question": "Under an adiabatic process, the volume of an ideal gas gets\ndoubled. Consequently the mean collisiontime between the gas molecules\nchanges from. If\n[IMAGE] for this gas then a good estimate\nfor[IMAGE] is given by [IMAGE]:,d \nbl j.k mlds v.kqvksa esa gksus okyh VDdjksa", "question_images": ["images/image216.png", "images/image217.png", "images/image218.png", "images/image219.png", "images/image220.png", "images/image216.png", "images/image217.png", "images/image218.png", "images/image219.png", "images/image220.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": null, "numerical_answer": "1", "solution": "", "solution_images": ["images/image221.png", "images/image222.png", "images/image223.png", "images/image224.png", "images/image225.png"], "subject": "Physics", "topic": "Thermodynamics", "subtopic": "Adiabatic process", "difficulty": "Moderate", "question_type": "numerical", "has_image": true, "exam": "JEE Main", "source_paper": "Ph-27 Physics paper 2 15 Jan.docx"} |
| {"question_id": "P-04-Q19", "question": "The displacement x of a body of mass 1 kg on horizontal smooth\nsurface as function of time t is given by x =[IMAGE].\nThe work done in the first one second is", "question_images": ["images/image100.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "[IMAGE] t 1 kg \nx x =[IMAGE]", "correct_option": 2, "numerical_answer": null, "solution": "dW = F.dx\nx =[IMAGE] v =[IMAGE] = t3 ⇒ dx = t3dt\n[IMAGE] = 3t2\n[IMAGE] t3 dt\nTOPIC: WPE\nSUB TOPIC: WORK DONE BY VARIABLE FORCE", "solution_images": ["images/image105.png", "images/image106.png", "images/image107.png", "images/image108.png"], "subject": "Physics", "topic": "", "subtopic": "", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-04 Paper 2 (Physics) Eng.+ Hindi 24-8-2020.docx"} |
| {"question_id": "Ph-28-Q21", "question": "In the shown figure three slits, separated by\n[IMAGE] and illuminated by monochromatic parallel beam\nof light of wavelength[IMAGE]. Pis a point on the line\nperpendicular to the plane of slits through[IMAGE]. If\nI_o is the intensity of the wave from each slit and d<<D, then\nintensity at p is", "question_images": ["images/image197.png", "images/image198.png", "images/image199.png", "images/image200.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": 4, "numerical_answer": null, "solution": "Phase difference between [IMAGE] Since D>>d then apply binomial approximation: [IMAGE] Phase difference between[IMAGE] Now using phase diagram\nSUB TOPIC:YDSE", "solution_images": ["images/image205.png", "images/image206.png", "images/image207.png", "images/image208.png", "images/image209.png", "images/image210.png", "images/image211.png"], "subject": "Physics", "topic": "", "subtopic": "", "difficulty": "Easy", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "Ph-28 Physics paper FST 16 Jan.docx"} |
| {"question_id": "P-04-Q20", "question": "has four choices", "question_images": [], "option_1": ",", "option_2": ",", "option_3": ",", "option_4": "out of which ONLY ONE is correct]", "correct_option": 4, "numerical_answer": null, "solution": "", "solution_images": [], "subject": "Physics", "topic": "", "subtopic": "", "difficulty": "", "question_type": "single_correct", "has_image": false, "exam": "JEE Main", "source_paper": "P-04 Paper 2 (Physics) Eng.+ Hindi 24-8-2020.docx"} |
| {"question_id": "P-12-Q11", "question": "The series combination of two batteries, both of the same emf\n10V, but different internal resistance of20$\\Omega$ and 5$\\Omega$, is\nconnected to the parallel combination of two resistors 30$\\Omega$ and\nR$\\ \\Omega$. The voltagedifference across the battery of internal\nresistance 20$\\Omega$ is zero, the value of R (in$\\ \\Omega$) is ___\n(1)\n(2)\n(3)\n(4)", "question_images": [], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": null, "numerical_answer": "30", "solution": "V_1 = $\\varepsilon_{1}$ - i. r_1\n0 = 10 - i × 20\ni = 0.5A\nV_2 = $\\varepsilon_{2}$ - ir_2\n= 10 - 0.5 × 5\nV_2 = 7.5V\n$0.5 = 0.25 + \\frac{7.5}{x}$\n$0.5 = \\frac{7.5}{30} + \\frac{7.5}{x}$\n$0.5 = 0.25 + \\frac{7.5}{x}$\n$\\frac{7.5}{x} = 0.25;$\n$x = \\frac{7.5}{0.25} = 30$ohms", "solution_images": ["images/image14.png"], "subject": "Physics", "topic": "Current Electricity", "subtopic": "KVL", "difficulty": "Moderate", "question_type": "numerical", "has_image": true, "exam": "JEE Main", "source_paper": "P-12 Physics paper 2 Nov.docx"} |
| {"question_id": "P-09-Q23", "question": "One end of a spring is fixed to the ceiling and other end is\nattached to a block. The block is released when spring is relaxed. The\nproduct of time period and amplitude is 8 S.I. units. If spring is cut\nin two equal parts and the two springs are attached to the block as\nshown in figure. The block is released when both springs are relaxed. If\nthe product of time period and amplitude in S.I. units is x, then find\nthe value of x.", "question_images": ["images/image140.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": null, "numerical_answer": "1", "solution": "In first case,\n[IMAGE] In second case,", "solution_images": ["images/image141.png", "images/image142.png", "images/image143.png", "images/image144.png", "images/image145.png", "images/image146.png", "images/image147.png"], "subject": "Physics", "topic": "Simple Harmonic Motion", "subtopic": "Block spring system", "difficulty": "Tough", "question_type": "numerical", "has_image": true, "exam": "JEE Main", "source_paper": "P-09 Physics paper 26 October.docx"} |
| {"question_id": "Ph-26-Q29", "question": "An ideal fluid flows (laminar flow) through a pipe of\nnon-uniform diameter. The maximum and minimum diameters of the pipes are\n6.4 cm and 4.8 cm, respectively. The ratio of the minimum and the\nmaximum velocities of fluid in this pipe is n/16. Find n:,d vkn'kZ nzo cnyrs gq,,d ikbi izokg esa cg jgk gSA\nikbi o Øe'k 6.4 cm\ncgus okys nzo xfr", "question_images": [], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": null, "numerical_answer": "9", "solution": "Using equation of continuity\nlkrR;rk lehdj.k yxkus ij\n$A_{1}V_{1} = A_{2}V_{2}$\n$\\frac{V_{1}}{V_{2}} = \\frac{A_{2}}{A_{1}} = \\left( \\frac{4.8}{6.4} \\right)^{2} = \\frac{9}{16}$", "solution_images": [], "subject": "Physics", "topic": "Mechanical Properties of Fluids", "subtopic": "Equation of continuity", "difficulty": "Moderate", "question_type": "numerical", "has_image": false, "exam": "JEE Main", "source_paper": "Ph-26 Physics paper 1 15 Jan.docx"} |
| {"question_id": "P-02-Q50", "question": "Two\nproduce stationary wave. The minimum distance of antinode from the\norigin along positive x-axis in terms of the wavelength λ is\n(y_1 and y_2 are in meter)", "question_images": ["images/image91.png", "images/image92.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": null, "numerical_answer": null, "solution": "B\ny = y_1 + y_2 = [IMAGE] Amplitude is maximum at antinode\n[IMAGE] General solution\nFor minimum distance of antinode from origin put n = 1\nSECTION - B [INTEGER ANSWER section contains", "solution_images": ["images/image97.png", "images/image98.png", "images/image99.png"], "subject": "Physics", "topic": "", "subtopic": "", "difficulty": "", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-02 Physics Paper-02_Update.docx"} |
| {"question_id": "P-03-Q16", "question": "A ball was thrown at velocity of 10 m/s at 37° to the horizontal.\nWhat is the rate of change of its speed when its radius of curvature is\n51.2 m.", "question_images": [], "option_1": "", "option_2": "", "option_3": "", "option_4": "37° 10 m/s \n 51.2 m ?", "correct_option": 2, "numerical_answer": null, "solution": "[IMAGE] aN = g cos θ =[IMAGE] v cos θ = 10 cos 37°\nv =[IMAGE] g cos3 θ =[IMAGE] cos3 θ =[IMAGE] cos θ =[IMAGE] θ = 60°\nat =[IMAGE] = g sin θ = 2\nTOPIC: CIRCULAR MOTION\nSUB TOPIC: Radius of Curvature", "solution_images": ["images/image97.png", "images/image98.png", "images/image99.png", "images/image100.png", "images/image101.png", "images/image102.png", "images/image103.png", "images/image104.png"], "subject": "Physics", "topic": "", "subtopic": "", "difficulty": "Medium", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-03 Paper 1 (Physics) Eng. + Hindi 24-8-2020.docx"} |
| {"question_id": "P-08-Q11", "question": "P- V diagram of ideal monoatomic gas is as shown. Find net heat\ngiven to the gas in the process ABC.$\\ $", "question_images": ["images/image3.png"], "option_1": "$2P_{0}V_{0}$", "option_2": "$5P_{0}V_{0}$", "option_3": "$6P_{0}V_{0}$", "option_4": "$7{PoV}_{0}$", "correct_option": 4, "numerical_answer": null, "solution": "$\\Delta Q = \\Delta U + \\Delta W$\n$W_{ABCA} = \\frac{1}{2}\\left( 2P_{0} \\right)\\left( 2V_{0} \\right) = 2P_{0}V_{0}$\n$W_{ABC} = 2P_{0}V_{0} - W = 2P_{0}V_{0} - \\left( - 2P_{0}V_{0} \\right) = 4P_{0}V_{0}$\n$\\Delta U = \\frac{nf}{2}R\\Delta T = \\frac{f}{2}P\\Delta V = \\frac{3}{2}P_{0}\\left( 2V_{0} \\right) = 3P_{0}V_{0}$\n$\\therefore\\Delta Q = 7P_{0}V_{0}$", "solution_images": [], "subject": "Physics", "topic": "Thermodynamics", "subtopic": "P-V diagram and first law of thermodynamics", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-08 Physics paper 23 October.docx"} |
| {"question_id": "P-24-Q3", "question": "A thin horizontal movable plate is separated from two fixed\nhorizontal plates [IMAGE] and\n[IMAGE] by two highly viscous liquids of coefficient of viscosity\n[IMAGE] and [IMAGE] as shown, where $\\eta_{2} = 4\\eta_{1}$.\nArea of contact of movable plate with each fluid is same. If the\ndistance between two fixed plates is h, then the distance\n[IMAGE] of movable plate from upper fixed plate such that the movable plate can\nbe moved with a constant velocity by applying a minimum constant\nhorizontal force F on movable plate is h/n (assume velocity gradient to\nbe uniform in each liquid). Find n.", "question_images": ["images/image22.png", "images/image23.png", "images/image24.png", "images/image25.png", "images/image26.png", "images/image27.png"], "option_1": "2", "option_2": "3", "option_3": "4", "option_4": "5", "correct_option": 2, "numerical_answer": null, "solution": "Let v be the velocity of the movable plate and F is equal to\nviscous force\n$F = \\left\\lbrack n_{1}\\frac{v}{h_{1}} + n_{2}\\frac{v}{h - h_{1}} \\right\\rbrack A$\n$\\Rightarrow \\frac{dF}{{dh}_{1}} = 0\\therefore h_{1} = \\frac{h}{3}$", "solution_images": [], "subject": "Physics", "topic": "Mechanical Properties of Fluids", "subtopic": "Viscosity", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-24 Physcis Paper 31 Dec.docx"} |
| {"question_id": "P-15-Q11", "question": "The ratio of the longest and shortest wavelengths of the Lyman\nseries is.", "question_images": [], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": 1, "numerical_answer": null, "solution": "[IMAGE] Equation dividing", "solution_images": ["images/image85.png", "images/image86.png", "images/image87.png"], "subject": "Physics", "topic": "Atomic physics", "subtopic": "Lyman series", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-15 Physics paper 11 Nov.docx"} |
| {"question_id": "Ph-25-Q15", "question": "A certain quantity of oxygen [IMAGE] is\ncompressed isothermally until its pressure is doubled\n[IMAGE]. The gas is then allowed to expand adiabatically\nuntil its original volume is restored. Then the final pressure (P) in\nterms of initial pressure [IMAGE] is:\nvkWDlhtu,d izkjfEHkd nkc", "question_images": ["images/image104.png", "images/image105.png", "images/image106.png", "images/image104.png", "images/image105.png", "images/image106.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "None of these", "correct_option": 2, "numerical_answer": null, "solution": "[IMAGE] (isothermal process) ¼lerkih", "solution_images": ["images/image110.png", "images/image111.png", "images/image112.png", "images/image113.png"], "subject": "Physics", "topic": "Thermodynamic", "subtopic": "Thermodynamic processes", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "Ph-25 Physics paper 7 Jan.docx"} |
| {"question_id": "Ph-25-Q25", "question": "A ring shaped tube contains two ideal gases with equal masses\nand atomic mass numbers M_1=32 and M_2=28. The gases are separated by\none fixed partition X and another movable conducting partition Y which\ncan move freely without friction inside the ring. The angle is $\\alpha$,\nin equilibrium as shown in thefigure (in degrees). Find the value\nof$\\frac{\\alpha}{48}$.,d vkdkj dh Vîqc esa nks vkn'kZ xSl ftu vyx&vyx dh tkrh gS rFkk nqljk foektd,d\nxfreku pkydfoHkktd Y tks fcuk ?k\"kZ.k xfr dj ldrk gSA\n fp=kuqlkj dks.k α ¼fMxzh esa½ rks [IMAGE]", "question_images": ["images/image174.png", "images/image175.png", "images/image176.png", "images/image177.png", "images/image178.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": null, "numerical_answer": "4", "solution": "At equilibrium, pressure and temperature are same.\n rFkk rki leku\n Also, let cross-sectional area of tube be A and radius of ring be r.\nekuk nkc", "solution_images": ["images/image179.png", "images/image180.png", "images/image181.png", "images/image182.png", "images/image183.png", "images/image184.png", "images/image185.png"], "subject": "Physics", "topic": "Kinetic Theory of Gases", "subtopic": "Gases in equilibrium", "difficulty": "Tough", "question_type": "numerical", "has_image": true, "exam": "JEE Main", "source_paper": "Ph-25 Physics paper 7 Jan.docx"} |
| {"question_id": "P-12-Q15", "question": "The length of a potentiometer wire is 120 cm and it carries a\ncurrent of 60 mA. For a cell of emf 5V and internal resistance of\n20$\\Omega$, the null point on it is found to be at 1000 cm. The\nresistance of whole wire is", "question_images": [], "option_1": "$600\\Omega$", "option_2": "$120\\Omega$", "option_3": "$100\\Omega$", "option_4": "$80\\Omega$", "correct_option": 3, "numerical_answer": null, "solution": "[IMAGE] Potential gradient\n$= \\frac{5}{1000} = \\frac{V_{P}}{1200}$\n$V_{p} = 6V$\n and\n $R_{p} = \\frac{V_{P}}{I} = \\frac{6}{60 \\times 10^{- 3}} = 100\\Omega$", "solution_images": ["images/image17.png"], "subject": "Physics", "topic": "Current Electricity", "subtopic": "Potentiometer", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-12 Physics paper 2 Nov.docx"} |
| {"question_id": "P-23-Q7", "question": "Two uniform solid spheres of equal radii R, butmass M and 4M have\na centre to centreseparation 6R, as shown in figure. A projectile of\nmass m in projected from the surface of thesphere of mass M directly\ntowards the centre of the second sphere. The minimum speed ofthe\nprojectile so that it reaches the surface of the second sphere\nis[IMAGE]. What is n?", "question_images": ["images/image15.png", "images/image16.png"], "option_1": "4", "option_2": "5", "option_3": "3", "option_4": "1", "correct_option": null, "numerical_answer": "3", "solution": "[IMAGE] The projectile need to reach a point on the line joining the centres\nof sphere where net electric force on it is zero.\nLet the point N has no net electric field due to spheres.\nTherefore, $\\frac{GM}{x^{2}} = \\frac{G.4M}{{(6R - x)}^{2}}$\n- x = 2R\nApply conservation of mechanical energy at projectile initial position\nand particle at N\nE_i = E_f\nSUB TOPIC: Conservation of mechanical energy", "solution_images": ["images/image17.png", "images/image18.png", "images/image19.png", "images/image20.png", "images/image21.png", "images/image22.png"], "subject": "Physics", "topic": "", "subtopic": "", "difficulty": "Tough", "question_type": "numerical", "has_image": true, "exam": "JEE Main", "source_paper": "P-23 Physcis Paper 31 Dec FST.docx"} |
| {"question_id": "P-03-Q25", "question": "A force given by the relation F = 8t, acts on a body of mass 2 kg,\ninitially at rest. Find the work done by this force on the body during\nfirst 2 seconds of its motion ( in joule )\nm = 2 kg F = 8t \n 2 sec. ( )", "question_images": [], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": null, "numerical_answer": "64", "solution": "F = 8t\nm[IMAGE] = 8t\n[IMAGE] mv = 4t2\nor m [IMAGE] = 4t2 ⇒ dx =[IMAGE] W =[IMAGE] =[IMAGE] = 64 J\nTOPIC: WPE\nSUB TOPIC: WORK DONE BY VARIABLE FORCE", "solution_images": ["images/image148.png", "images/image149.png", "images/image150.png", "images/image151.png", "images/image152.png", "images/image153.png"], "subject": "Physics", "topic": "", "subtopic": "", "difficulty": "Moderate", "question_type": "numerical", "has_image": true, "exam": "JEE Main", "source_paper": "P-03 Paper 1 (Physics) Eng. + Hindi 24-8-2020.docx"} |
| {"question_id": "P-16-Q3", "question": "The \" y ' co-ordinate of the centre of mass of the system of\nthree rods of length as shown in\nfigure is: (Assume all rods to be of uniform density)", "question_images": ["images/image8.png"], "option_1": "$\\frac{9a}{8\\sqrt{3}}$", "option_2": "$\\frac{9a}{16\\sqrt{3}}$", "option_3": "zero", "option_4": "$\\frac{8a}{\\sqrt{3}}$", "correct_option": 2, "numerical_answer": null, "solution": "The y-coordinate of centre of mass is\n$= \\frac{2m(\\frac{\\sqrt{3}}{2}a) + 2m(0) + 2m(0) + m(\\frac{\\sqrt{3}}{4}a) + m(\\frac{\\sqrt{3}}{4}a)}{8m}$\n$= \\frac{9a}{16\\sqrt{3}}$", "solution_images": ["images/image9.png"], "subject": "Physics", "topic": "Center of mass", "subtopic": "Center of mass of extended body", "difficulty": "Easy", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-16 Physics paper 25 Nov First.docx"} |
| {"question_id": "P-05-Q17", "question": "Dimensions of gravitational constant are", "question_images": [], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": 4, "numerical_answer": null, "solution": "$G = \\frac{Fr^{2}}{m_{1}m_{2}};\\ \\lbrack G\\rbrack = \\left\\lbrack \\frac{Fr^{2}}{m_{1}m_{2}} \\right\\rbrack = \\left\\lbrack \\frac{MLT^{- 2}L^{2}}{M^{2}} \\right\\rbrack = \\left\\lbrack M^{- 1}L^{3}T^{- 2} \\right\\rbrack$", "solution_images": [], "subject": "Physics", "topic": "Unit and dimension", "subtopic": "Dimensional analysis", "difficulty": "Moderate", "question_type": "single_correct", "has_image": false, "exam": "JEE Main", "source_paper": "P-05 Physics paper 10 October.docx"} |
| {"question_id": "P-22-Q16", "question": "A train of mass M is moving on a circular track of radius ' R\n' with constant speed V. The length of thetrain is half of the\nperimeter of the track. The linear momentum of the train will be", "question_images": [], "option_1": "Zero", "option_2": "$\\frac{2M\\ V}{\\pi}$", "option_3": "MVR", "option_4": "MV", "correct_option": 2, "numerical_answer": null, "solution": "If we treat the train as a ring of mass then its COM will\nbe at a distance[IMAGE] from the centre of the circle.\nVelocity of centre of mass is:\n$V_{CM} = R_{CM} \\cdot \\omega$\n= $\\frac{2R}{\\pi} \\cdot \\omega$ =\n$\\frac{2R}{\\pi} \\cdot \\left( \\frac{v}{R} \\right)$\n$\\left( \\because\\omega = \\frac{v}{R} \\right)$\n$\\Rightarrow$ $V_{CM} = \\frac{2V}{\\pi}$ $\\Rightarrow$\n${MV}_{CM} = \\frac{2MV}{\\pi}$\nAs the linear momentum of any system = MV_CM\n[IMAGE] The linear momentum of the train\n$= \\frac{2MV}{\\pi}$", "solution_images": ["images/image42.png", "images/image43.png"], "subject": "Physics", "topic": "System of particles", "subtopic": "Linear momentum of center of mass", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-22 Physcis Paper 19 Dec Eng..docx"} |
| {"question_id": "P-19-Q11", "question": "A particle moving with kinetic energy E has de Broglie\nwavelength$\\lambda$. If energy $\\Delta E$ is added to its energy, the\nwavelength become $\\lambda/2$. Value of$\\Delta E$, is", "question_images": [], "option_1": "4E", "option_2": "3E", "option_3": "2E", "option_4": "E", "correct_option": 2, "numerical_answer": null, "solution": "$\\lambda = \\frac{h}{\\sqrt{2(KE)m}} = \\lambda \\propto \\frac{1}{\\sqrt{KE}}$\n$\\frac{\\lambda}{\\lambda/2} = \\sqrt{\\frac{{KE}_{f}}{{KE}_{i}}}$\n$4{KE}_{i} = {KE}_{f}$\n$\\Rightarrow \\Delta E = 4KE_{i} - KE_{i} = 3KE = 3E$", "solution_images": [], "subject": "Physics", "topic": "Modern physics", "subtopic": "De Broglie wavelength", "difficulty": "Moderate", "question_type": "single_correct", "has_image": false, "exam": "JEE Main", "source_paper": "P-19 Physics paper 28 Nov Fourth.docx"} |
| {"question_id": "P-02-Q48", "question": "A smooth ball of mass m moving with the velocity v_o makes an\nelastic impact on\nanother smooth ball of mass M at rest. After impact the velocity\ncomponents v_1 and v_2 are", "question_images": ["images/image78.png"], "option_1": "v_o cos α, 0", "option_2": "v_o sin a, 0", "option_3": "v_o sin a, v_o cos α", "option_4": "none of these", "correct_option": null, "numerical_answer": null, "solution": "B\nVelocity components tangential to the direction\nof impact remains unchanged before and after the collision.\n∴ (B)", "solution_images": [], "subject": "Physics", "topic": "", "subtopic": "", "difficulty": "", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-02 Physics Paper-02_Update.docx"} |
| {"question_id": "P-11-Q10", "question": "The radius of gyration of a uniform rod of length\n[IMAGE], about an axis passing through a point\n[IMAGE] away fromthe centre of the rod, and perpendicular\nto it, is", "question_images": ["images/image97.png", "images/image98.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": 1, "numerical_answer": null, "solution": "", "solution_images": ["images/image103.jpeg", "images/image104.png", "images/image105.png", "images/image106.png"], "subject": "Physics", "topic": "Rigid Body Dynamics", "subtopic": "Radius of gyration", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-11 Physics paper-2 1Nov Jee Main.docx"} |
| {"question_id": "P-24-Q30", "question": "A U tube filled with a liquid is accelerating horizontally with\nan acceleration a. The acceleration (ms^-2) of the tube is", "question_images": ["images/image68.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": null, "numerical_answer": "5", "solution": "For free surface $tan\\theta = a/g$\nor $a = gtan\\theta = 10/2 = 5$", "solution_images": ["images/image69.png"], "subject": "Physics", "topic": "Mechanical Properties of Fluids", "subtopic": "Fluid in motion", "difficulty": "Moderate", "question_type": "numerical", "has_image": true, "exam": "JEE Main", "source_paper": "P-24 Physcis Paper 31 Dec.docx"} |
| {"question_id": "P-14-Q18", "question": "Final image of point object formed by the combination is\nlocated", "question_images": ["images/image121.png"], "option_1": "On plane surface", "option_2": "At a distance 10 cm from plane surface", "option_3": "At a distance 30 cm from plane surface", "option_4": "At a distance 20 cm from curved surface.", "correct_option": 1, "numerical_answer": null, "solution": "1st refraction at curved surface\n[IMAGE] Reflection of mirror,\n[IMAGE] 2nd refraction at curved surface\n[IMAGE] So, final image from on plane surface.", "solution_images": ["images/image122.png", "images/image123.png", "images/image124.png", "images/image125.png"], "subject": "Physics", "topic": "Ray Optics", "subtopic": "Refraction (Lens)", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-14 Physics paper 7 Nov.docx"} |
| {"question_id": "P-15-Q8", "question": "Which of the following gives a reversible operation?", "question_images": [], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": 4, "numerical_answer": null, "solution": "A logic gate is reversible if we can recover input data from\nthe output eg. NOT gate", "solution_images": [], "subject": "Physics", "topic": "Electronic device", "subtopic": "Gates", "difficulty": "Easy", "question_type": "single_correct", "has_image": false, "exam": "JEE Main", "source_paper": "P-15 Physics paper 11 Nov.docx"} |
| {"question_id": "P-04-Q15", "question": "A thin circular ring of mass per unit length ρ and radius r is\nrotating at an angular speed ω as shown in figure. The tension in the\nring is", "question_images": ["images/image88.png"], "option_1": "ρω2r2", "option_2": "", "option_3": "", "option_4": "None\nρ r \n ω", "correct_option": 1, "numerical_answer": null, "solution": "2T sin[IMAGE] = dmRω2\nT = ρR2ω2\nTOPIC: CIRCULAR MOTION\nSUB TOPIC: DYNAMICS", "solution_images": ["images/image89.png", "images/image90.png", "images/image91.png"], "subject": "Physics", "topic": "", "subtopic": "", "difficulty": "Tough", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-04 Paper 2 (Physics) Eng.+ Hindi 24-8-2020.docx"} |
| {"question_id": "P-16-Q5", "question": "The centre of mass of a non uniform rod of length L whose mass\nper unit length $\\lambda$varies as\n$\\lambda = \\frac{k \\cdot x^{2}}{L}$where k is a constant &x is the\ndistance of any point on rod from its one end, is (from the same end)", "question_images": [], "option_1": "$\\frac{3}{4}L$", "option_2": "$\\frac{1}{4}L$", "option_3": "$\\frac{k}{L}$", "option_4": "$\\frac{3k}{L}$", "correct_option": 1, "numerical_answer": null, "solution": "", "solution_images": ["images/image11.png", "images/image12.png"], "subject": "Physics", "topic": "Center of mass", "subtopic": "Center of mass of rod of non-uniformlinear mass density", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-16 Physics paper 25 Nov First.docx"} |
| {"question_id": "P-04-Q10", "question": "The acceleration of the blocks (A) and (B) respectively in\nsituation shown in the figure is: (pulleys & strings are massless)", "question_images": ["images/image62.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "none of these", "correct_option": 1, "numerical_answer": null, "solution": "aA = 2aB...(1)\nmAg - T = mAaA...(2)\n2T - mBg = mBaB...(3)\nSolving, we get aA =[IMAGE] & aB\nTOPIC: NLM\nSUB TOPIC: NEWTON'S SECOND LAW", "solution_images": ["images/image69.png", "images/image70.png"], "subject": "Physics", "topic": "", "subtopic": "", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-04 Paper 2 (Physics) Eng.+ Hindi 24-8-2020.docx"} |
| {"question_id": "Ph-28-Q31", "question": "In the arrangement shown in figure, wavelength of light used is\n[IMAGE]. The distance between slits\n[IMAGE] The distance between [IMAGE] and\n[IMAGE] is [IMAGE] If the ratio of\nmaximum to minimum intensity received on screen P is K. Then K is", "question_images": ["images/image273.png", "images/image274.png", "images/image275.png", "images/image276.png", "images/image277.png", "images/image278.png", "images/image279.png", "images/image280.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": null, "numerical_answer": "9", "solution": "If intensity of light incident on slits [IMAGE] and\nThe intensity through [IMAGE] will be\n[IMAGE] The intensity through [IMAGE] will be\n[IMAGE] TOPIC:Wave Optics\nSUB TOPIC:YDSE\nLEVEL:Moderate", "solution_images": ["images/image274.png", "images/image275.png", "images/image281.png", "images/image278.png", "images/image282.png", "images/image283.png", "images/image284.png", "images/image285.png"], "subject": "Physics", "topic": "", "subtopic": "", "difficulty": "", "question_type": "numerical", "has_image": true, "exam": "JEE Main", "source_paper": "Ph-28 Physics paper FST 16 Jan.docx"} |
| {"question_id": "P-14-Q10", "question": "There is a small source of light at some depth below the surface\nof water (refractive index =4/3) in a tank of large cross sectional\nsurface area. Neglecting any reflection from the bottom and absorption\nby water, percentage of light that emerges out of surface is (nearly):\n[Use the fact that surface area of a spherical cap of height h and\nradius of curvature r", "question_images": ["images/image73.png"], "option_1": "50", "option_2": "34", "option_3": "17", "option_4": "21", "correct_option": 3, "numerical_answer": null, "solution": "[IMAGE] Solid angle [IMAGE] Percentage of light [IMAGE]", "solution_images": ["images/image74.jpeg", "images/image75.png", "images/image76.png", "images/image77.png", "images/image78.png"], "subject": "Physics", "topic": "Ray Optics", "subtopic": "Circle of illuminance", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-14 Physics paper 7 Nov.docx"} |
| {"question_id": "P-09-Q10", "question": "A simple pendulum of length 50cm and bob's mass 100g is\noscillating in the air. A damping force f = 0.0693V acts due to air,\nwhere V is speed of bob. At any time it has a amplitude A. How much time\nit will take so that amplitude becomes half of initial value.", "question_images": [], "option_1": "1 sec", "option_2": "3 sec", "option_3": "2 sec", "option_4": "none of these", "correct_option": 3, "numerical_answer": null, "solution": "$A = A_{0^{e}}\\frac{- bt}{2m}$\n$\\frac{\\text{A}_{0}}{2} = \\text{A}_{0^{\\text{e}}}\\frac{- \\text{bt}}{2\\text{m}} \\Rightarrow \\frac{\\text{bt}}{2\\text{m}} = \\ln 2$", "solution_images": ["images/image58.png"], "subject": "Physics", "topic": "Oscillation", "subtopic": "Damped oscillation", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-09 Physics paper 26 October.docx"} |
| {"question_id": "P-06-Q24", "question": "Two men of masses m and m/2 starts climbing up on two massless\nstrings fixed at the ceiling with acceleration g and g/2 respectively.\nThe ratio of tensions in the two strings are 2x: y then find the value\nof x + y.", "question_images": [], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": null, "numerical_answer": "7", "solution": "FBD of man of mass (m)\n$T_{1} = 2mg$\nFBD of man of mass (m/2)\n$T_{2} = \\frac{mg}{2}\\left\\lbrack \\frac{3}{2} \\right\\rbrack = \\frac{3mg}{4}$\n$\\Rightarrow T_{1}:T_{2}::8:3$", "solution_images": ["images/image34.png", "images/image35.png"], "subject": "Physics", "topic": "Newton's Laws of Motion", "subtopic": "Newton's second law", "difficulty": "Moderate", "question_type": "numerical", "has_image": true, "exam": "JEE Main", "source_paper": "P-06 Physics paper 14 October.docx"} |
| {"question_id": "Ph-28-Q7", "question": "A ball is given velocity [IMAGE] as shown. If the\nratio of centripetal acceleration totangential acceleration at the point\nwhere the ball leaves the circular path is [IMAGE] then n\nis", "question_images": ["images/image57.png", "images/image58.png", "images/image59.png"], "option_1": "2", "option_2": "3", "option_3": "5", "option_4": "8", "correct_option": 4, "numerical_answer": null, "solution": "and [IMAGE].....(2)\n[IMAGE] Now [IMAGE] and [IMAGE] TOPIC: Circular motion\nSUB TOPIC: Vertical circle\nLEVEL: Moderate", "solution_images": ["images/image60.png", "images/image61.png", "images/image62.png", "images/image63.png", "images/image64.png", "images/image65.png", "images/image66.png"], "subject": "Physics", "topic": "", "subtopic": "", "difficulty": "", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "Ph-28 Physics paper FST 16 Jan.docx"} |
| {"question_id": "P-14-Q14", "question": "Visible light of wavelength [IMAGE] falls normally\non single slit and produces a diffractionpattern. It is found that the\nsecond diffraction minimum is at 60º C from the central maximum. If the\nfirst minimum is produced at[IMAGE], then\n[IMAGE] is close to", "question_images": ["images/image97.png", "images/image98.png", "images/image99.png"], "option_1": "25º", "option_2": "30º", "option_3": "20º", "option_4": "45º", "correct_option": 2, "numerical_answer": null, "solution": "For 2^ndminima\nSo for 1^st minima\n[IMAGE] (From equation (i)\n[IMAGE] (From sin table)", "solution_images": ["images/image100.png", "images/image101.png", "images/image102.png", "images/image103.png", "images/image104.png", "images/image105.png", "images/image106.png"], "subject": "Physics", "topic": "Wave Optics", "subtopic": "Diffraction", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-14 Physics paper 7 Nov.docx"} |
| {"question_id": "Ph-28-Q26", "question": "A thin uniform rod of mass is hinged at one\nend. This rod is maintained in horizontal position by colliding very\ntiny balls each of mass m/10 completely elastically 10 times per sec\nstriking at the opposite end as shown in figure. The speed of the balls\njust before colliding rod is [IMAGE].Find n.", "question_images": ["images/image237.png", "images/image238.png", "images/image239.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": null, "numerical_answer": "5", "solution": "[IMAGE] Taking torque about hinge:\n[IMAGE] TOPIC:Rotaional dynamics\nSUB TOPIC: Torque\nLEVEL: Moderate", "solution_images": ["images/image240.png", "images/image241.png", "images/image242.png", "images/image243.png"], "subject": "Physics", "topic": "", "subtopic": "", "difficulty": "", "question_type": "numerical", "has_image": true, "exam": "JEE Main", "source_paper": "Ph-28 Physics paper FST 16 Jan.docx"} |
| {"question_id": "Ph-27-Q26", "question": "One mole of an ideal gas is kept enclosed under a light piston\n(area=[IMAGE] ) connected by acompressed spring (spring\nconstant 100 N / m). The volume of gas is\n[IMAGE] and its temperature is 100K. The gas is\nheated so that it compresses the spring further by 0.1 m. Then the work\ndone (in Joule)by the gas in the process is 1.5n. Find n: (Take R =8.3 J\n/ K -mole and suppose there is no atmosphere).,d 100 N / m½\nls tqM+s gYds fiLVu ¼{ks=Qy\n rFkk bl 100K\nxeZ", "question_images": ["images/image163.png", "images/image164.png", "images/image163.png", "images/image164.png", "images/image165.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": null, "numerical_answer": "1", "solution": "Before heating let the pressure of gas be\n[IMAGE] from the equilibrium piston.\n[IMAGE] Since during heating process, pwafd xeZ izfØ nkSjku,\nThe spring is compressed further by 0.1 m fLizax 0.1 m \n∴[IMAGE] Work done by gas\ndk;Z[IMAGE] = 1.50 = 1.5 J", "solution_images": ["images/image166.png", "images/image166.png", "images/image167.png", "images/image168.png", "images/image169.png", "images/image170.png", "images/image171.png"], "subject": "Physics", "topic": "Behaviour of perfect gases", "subtopic": "Work done", "difficulty": "Moderate", "question_type": "numerical", "has_image": true, "exam": "JEE Main", "source_paper": "Ph-27 Physics paper 2 15 Jan.docx"} |
| {"question_id": "P-07-Q3", "question": "The rod is uniform & weigh 500 N. Find magnitude of tension so\nthat tension in both strings (S_1, S_2) aresame (strings ideal).", "question_images": ["images/image4.png"], "option_1": "1000 N", "option_2": "1500 N", "option_3": "2000 N", "option_4": "500 N", "correct_option": 2, "numerical_answer": null, "solution": "[IMAGE] Taking torque about W.\n- T_1 (0.4)+T_2 (0.3)+500(0.2)=0\nT = 1000", "solution_images": ["images/image5.png"], "subject": "Physics", "topic": "Rigid Body Dynamics", "subtopic": "Conservation of angular momentum", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-07 Physics paper 17 October.docx"} |
| {"question_id": "P-01-Q6", "question": "Three polaroids are kept coaxially. Angle between the first and\nthird polaroid is 90°. Angle between the first and second polaroid is\n60°. If unpolarized light energy incident on the first polaroid is I0.\nLight energy that emerges from the system is", "question_images": [], "option_1": "zero", "option_2": "", "option_3": "", "option_4": "", "correct_option": 2, "numerical_answer": null, "solution": "According to Malus law, I = I0 cos2 θ\nAfter 2nd Polaroid, I = [IMAGE] cos2 60° =\n[IMAGE] After 3rd Polaroid, I = [IMAGE] cos2 30° =", "solution_images": ["images/image25.png", "images/image26.png", "images/image27.png", "images/image28.png"], "subject": "Physics", "topic": "", "subtopic": "", "difficulty": "", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-01 Physics Paper-01_Update.docx"} |
| {"question_id": "P-11-Q24", "question": "A uniform disc of mass M and radius R, is resting on a table on\nits rim. The coefficient of frictionbetween disc and table is\n[IMAGE] Now the disc is pulled with aforce F as shown in\nthe figure. What is the maximum value of F for which the disc rolls\nwithout slipping?", "question_images": ["images/image224.png", "images/image225.png"], "option_1": "If there is no slipping, angular acceleration ofthe disc,", "option_2": "[IMAGE] Now torque of the disc (Using 2)\nSubstituting this in Eq. (i), we get\n Since there is no slipping,", "option_3": "", "option_4": "", "correct_option": null, "numerical_answer": "3", "solution": "Let a be the acceleration of the centre of massof disc. Then\nIf there is no slipping, angular acceleration ofthe disc,\n[IMAGE] Now torque of the disc (Using 2)\nSubstituting this in Eq. (i), we get\n Since there is no slipping,", "solution_images": ["images/image226.png", "images/image227.png", "images/image228.png", "images/image229.png", "images/image230.png", "images/image231.png", "images/image232.png", "images/image233.png", "images/image234.png", "images/image235.png"], "subject": "Physics", "topic": "Rigid Body Dynamics", "subtopic": "Pure rolling", "difficulty": "Moderate", "question_type": "numerical", "has_image": true, "exam": "JEE Main", "source_paper": "P-11 Physics paper-2 1Nov Jee Main.docx"} |
| {"question_id": "P-24-Q15", "question": "The speed of water flowing out of the orifice before the\ncylinder kept inside the tank", "question_images": [], "option_1": "$\\sqrt{gH}$", "option_2": "$1.414\\sqrt{gH}$", "option_3": "$\\frac{\\sqrt{gh}}{2}$", "option_4": "$\\sqrt{\\frac{gh}{2}}$", "correct_option": 1, "numerical_answer": null, "solution": "", "solution_images": ["images/image46.png"], "subject": "Physics", "topic": "Mechanical Properties of Fluids", "subtopic": "Velocity of efflux", "difficulty": "Easy", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-24 Physcis Paper 31 Dec.docx"} |
| {"question_id": "P-18-Q25", "question": "A man throws a packet from the top of the tower directly aiming\nat his friend who is standing on the ground at a certain distance from\nthe base of the tower and this distance is same as the height of the\ntower. If packet is thrown with a speed of 4 m /s and it hits the ground\nmidway between the tower base and his friend then height of the tower\n(in m) is 0.4k. Find k. $(g = 10m/s^{2})$", "question_images": [], "option_1": "&$h = (\\frac{4}{\\sqrt{2}})t + \\frac{1}{2}{gt}^{2}$....", "option_2": "$\\frac{h}{2} = \\frac{1}{2}gt^{2}$\nfrom", "option_3": "", "option_4": "", "correct_option": null, "numerical_answer": "8", "solution": "$\\frac{4}{\\sqrt{2}} \\cdot t = \\frac{h}{2}$....(1)\n&$h = (\\frac{4}{\\sqrt{2}})t + \\frac{1}{2}{gt}^{2}$....(2)\n$\\frac{h}{2} = \\frac{1}{2}gt^{2}$\nfrom (1) & (2)", "solution_images": ["images/image32.png"], "subject": "Physics", "topic": "Projectile Motion", "subtopic": "Horizontal projectile from a height", "difficulty": "Moderate", "question_type": "numerical", "has_image": true, "exam": "JEE Main", "source_paper": "P-18 Physics paper 27 Nov Third.docx"} |
| {"question_id": "P-09-Q15", "question": "A transverse sinusoidal wave move along a string in the positive\nx-direction at a speed 5cm/s. The wavelength of the wave 0.2m and its\namplitude is 5cm. At given instant velocity of P is\n[IMAGE] when its displacement is 2.5 cm. Which of the\nfollowing is correct?", "question_images": ["images/image85.png", "images/image86.png", "images/image87.png"], "option_1": "", "option_2": "$\\overset{\\rightarrow}{\\text{v}} \\cdot \\overset{\\rightarrow}{\\text{a}} = \\frac{2\\sqrt{3}}{32}\\pi^{3}\\text{cm}^{2}/\\text{s}^{3}$", "option_3": "$\\overset{\\rightarrow}{\\text{v}} \\cdot \\overset{\\rightarrow}{\\text{a}} = \\frac{25\\sqrt{3}}{3}\\pi^{3}\\text{cm}^{2}/\\text{s}^{3}$", "option_4": "$\\overset{\\rightarrow}{\\text{v}} \\cdot \\overset{\\rightarrow}{\\text{a}} = \\frac{25\\sqrt{5}}{32}\\pi^{3}\\text{cm}^{2}/\\text{s}^{3}$", "correct_option": 1, "numerical_answer": null, "solution": "", "solution_images": ["images/image89.png", "images/image90.png", "images/image91.png", "images/image92.png", "images/image88.png"], "subject": "Physics", "topic": "Wave on a string", "subtopic": "SHM of a particle", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-09 Physics paper 26 October.docx"} |
| {"question_id": "P-17-Q20", "question": "Two uniform circular coils x and y having equal number of turns\nand carrying equal current in same sense, subtend same solid angle at\npoint O. if smaller coil x is midway between O and y, then, if we\nrepresent magnetic field due to coil y as B_y and that due to coil x as\nB_x then $(\\frac{B_{y}}{B_{x}}) = K$ then 20 K is", "question_images": ["images/image22.png"], "option_1": "10", "option_2": "30", "option_3": "20", "option_4": "40", "correct_option": 1, "numerical_answer": null, "solution": "If radius of x is r, then radius of y is 2r\n$B_{y} = \\frac{\\mu_{0}}{4\\pi}\\frac{2\\pi I(2r)^{2}}{{\\lbrack(2r)^{2} + (2d)^{2}\\rbrack}^{3/2}}$\n$B_{x} = \\frac{\\mu_{0}}{4\\pi}\\frac{2\\pi{Ir}^{2}}{{\\lbrack r^{2} + d^{2}\\rbrack}^{3/2}}$", "solution_images": [], "subject": "Physics", "topic": "Moving charges and", "subtopic": "Magnetic field due to current carrying coil", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-17 Physics paper 26 Nov Second.docx"} |
| {"question_id": "Ph-28-Q29", "question": "The sphere at P is given a downward velocity\n[IMAGE] and swings in a vertical plane at the end of a\nrope of [IMAGE] attached to a support at O. The rope\nbreaks at angle 30° from horizontal, knowing that it can withstand a\nmaximum tension equal to three times the weight of the sphere. The value\nof [IMAGE] is [IMAGE]. Find", "question_images": ["images/image255.png", "images/image256.png", "images/image255.png", "images/image257.png", "images/image258.png", "images/image259.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": null, "numerical_answer": "2", "solution": "[IMAGE] TOPIC:Vertical circle\nSUB TOPIC: Simple pendulum\nLEVEL: Moderate", "solution_images": ["images/image260.png", "images/image261.png", "images/image262.png", "images/image263.png"], "subject": "Physics", "topic": "", "subtopic": "", "difficulty": "", "question_type": "numerical", "has_image": true, "exam": "JEE Main", "source_paper": "Ph-28 Physics paper FST 16 Jan.docx"} |
| {"question_id": "Ph-27-Q30", "question": "A rubber cord has a cross-section area 1 cm^2 and natural\nlength of [IMAGE] It is stretched by\n[IMAGE] to fire a small object of\nmass[IMAGE]. If the Young's modulus (Y) is\n[IMAGE] Speed acquired by the object in (m/s) is 2n.\nFind n. Assume Hook's law is valid and neglect gravity.,d jcj dh Mksjh dk vuqçLFk dkV kjk çkIr\nosx (m/s) esa½2n. nKkr djsaA ekfu,sa fd gqd", "question_images": ["images/image193.png", "images/image194.png", "images/image195.png", "images/image196.png", "images/image197.png", "images/image195.png", "images/image194.png", "images/image198.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": null, "numerical_answer": "5", "solution": "v = 10^3 × 10^-2\nv = 10.00 m/s", "solution_images": ["images/image199.png", "images/image200.png", "images/image201.png"], "subject": "Physics", "topic": "Elasticity", "subtopic": "Potential energy stored in elongated rubber cord", "difficulty": "Moderate", "question_type": "numerical", "has_image": true, "exam": "JEE Main", "source_paper": "Ph-27 Physics paper 2 15 Jan.docx"} |
| {"question_id": "Ph-26-Q17", "question": "A block is partially immersed in a liquid and the vessel is\naccelerating upwards with acceleration \"a\". The block is observed by two\nobservers $O_{1}$ and $O_{2}$one at rest and the other accelerating with\nan acceleration \"a\" upward. The total buoyant force on the block is:,d CykWd nzo:i ls Mqck gqvk gS rFkk ik= Roj.k \"a\" ls,d izs{kd fojke ij gS rFkk nwljk Roj.k\"a\" ls dh vksj Rofjr\ngSA CykWd ij dk;Zjr~ dqy mRIykou cy gksxkA", "question_images": ["images/image40.png"], "option_1": "same for $O_{1}$ and $O_{2}$", "option_2": "greater for $O_{1}$ than $O_{2}$", "option_3": "greater for $O_{2}$ than $O_{1}$", "option_4": "data is not sufficient", "correct_option": 1, "numerical_answer": null, "solution": "Buoyant force mRIykou\ncy$= F_{b} = V_{sub} \\cdot \\rho_{\\mathcal{l}} \\cdot g$\nWhere,$V_{sub},\\rho_{\\mathcal{l}}$and g all are same w.r.t.\n$O_{1}$and$O_{2}$\nHence vr (1)", "solution_images": [], "subject": "Physics", "topic": "Mechanical properties of liquid", "subtopic": "Buoyancy", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "Ph-26 Physics paper 1 15 Jan.docx"} |
| {"question_id": "Ph-28-Q6", "question": "The angular frequency of oscillation of mass m connected\nsymmetrically to four spring each of force constant K, when it is\ndisplaced very slightly along one of the springs is", "question_images": ["images/image49.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": 2, "numerical_answer": null, "solution": "[IMAGE] TOPIC: Simple harmonic motion\nSUB TOPIC: Angular frequency of oscillation\nLEVEL:Moderate", "solution_images": ["images/image54.png", "images/image55.png", "images/image56.png", "images/image51.png"], "subject": "Physics", "topic": "", "subtopic": "", "difficulty": "", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "Ph-28 Physics paper FST 16 Jan.docx"} |
| {"question_id": "P-08-Q18", "question": "110 J of heat are added to a gaseous system where change in\ninternal energy is 40 J, then the amount of external work done is", "question_images": [], "option_1": "40 J", "option_2": "110J", "option_3": "70 J", "option_4": "150 J", "correct_option": 3, "numerical_answer": null, "solution": "$\\Delta W = \\Delta u + \\Delta W$\n$\\Rightarrow 110 = 40 + \\Delta W$\n$\\Rightarrow \\Delta W = 110 - 40 = 70J$", "solution_images": [], "subject": "Physics", "topic": "Thermodynamics", "subtopic": "First law of thermodynamics", "difficulty": "Easy", "question_type": "single_correct", "has_image": false, "exam": "JEE Main", "source_paper": "P-08 Physics paper 23 October.docx"} |
| {"question_id": "P-23-Q16", "question": "A train of mass M is moving on a circular track of radius ' R\n' with constant speed V. The length of thetrain is half of the\nperimeter of the track. The linear momentum of the train will be", "question_images": [], "option_1": "Zero", "option_2": "$\\frac{2M\\ V}{\\pi}$", "option_3": "MVR", "option_4": "MV", "correct_option": 2, "numerical_answer": null, "solution": "If we treat the train as a ring of mass then its COM will\nbe at a distance[IMAGE] from the centre of the circle. Velocity\nof centre of mass is:\n$V_{CM} = R_{CM} \\cdot \\omega$\n= $\\frac{2R}{\\pi} \\cdot \\omega$ =\n$\\frac{2R}{\\pi} \\cdot \\left( \\frac{v}{R} \\right)$\n$\\left( \\because\\omega = \\frac{v}{R} \\right)$\n$\\Rightarrow$ $V_{CM} = \\frac{2V}{\\pi}$ $\\Rightarrow$\n${MV}_{CM} = \\frac{2MV}{\\pi}$\nAs the linear momentum of any system = MV_CM\n[IMAGE] The linear momentum of the train $= \\frac{2MV}{\\pi}$", "solution_images": ["images/image38.png", "images/image39.png"], "subject": "Physics", "topic": "System of particles", "subtopic": "Linear momentum of center of mass", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-23 Physcis Paper 31 Dec FST.docx"} |
| {"question_id": "P-02-Q31", "question": "A solid cylinder of mass m is placed over the trolley as shown\nin the figure. The trolley starts to move forward with constant\nhorizontal acceleration a. The frictional force acting on the solid\ncylinder will be (Assume no slipping)", "question_images": ["images/image1.png"], "option_1": "", "option_2": "ma", "option_3": "", "option_4": "", "correct_option": 3, "numerical_answer": null, "solution": "From the reference frame of trolley, the forces acting on the\ncylinder is as shown.\nand [IMAGE] (ii) From (i) and (ii),", "solution_images": ["images/image5.png", "images/image6.png", "images/image7.png", "images/image8.png", "images/image9.png", "images/image10.png"], "subject": "Physics", "topic": "", "subtopic": "", "difficulty": "", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-02 Physics Paper-02_Update.docx"} |
| {"question_id": "P-24-Q28", "question": "A container filled with viscous liquid is moving vertically\ndownwards with constant speed\n[IMAGE]. At the instant shown, a sphere of radius\nr is moving vertically downwards (in liquid) has speed\nThe coefficient of viscosity is η. There is no relative motion between\nthe liquid and the container. Then at the shown instant, the magnitude\nof viscous force acting on sphere is $2x\\pi\\eta\\text{r}\\text{v}_{0}$.\nFind x", "question_images": ["images/image64.png", "images/image65.png", "images/image66.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": null, "numerical_answer": "6", "solution": "Relative to liquid, the velocity of sphere is\n${\\text{2}\\text{v}}_{0}$ upwar Viscous force on sphere\n$= 6\\pi\\eta\\text{r}\\text{v}_{0}$ downward\n$= 12\\pi\\eta\\text{r}\\text{v}_{0}$ downward", "solution_images": ["images/image67.png"], "subject": "Physics", "topic": "Mechanical Properties of Fluids", "subtopic": "Terminal velocity", "difficulty": "Moderate", "question_type": "numerical", "has_image": true, "exam": "JEE Main", "source_paper": "P-24 Physcis Paper 31 Dec.docx"} |
| {"question_id": "P-21-Q9", "question": "Boolean relation at the output stage-Y for the following circuit\nis", "question_images": ["images/image22.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": 2, "numerical_answer": null, "solution": "First part of figure shown is OR gate and\n izFke Hkkx OR \nSecond part of figure shown is NOT gate\nrFkk Hkkx NOT \nSo vr Y_p = OR + NOT = NOR gate", "solution_images": ["images/image27.png"], "subject": "Physics", "topic": "Electronic devices", "subtopic": "Boolean relation", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-21 Physcis Paper 19 Dec Hindi Eng..docx"} |
| {"question_id": "P-10-Q3", "question": "A penguin of mass m stands at the right edge of a sled of mass 3m\nand legnth [IMAGE]. The sled lies onfrictionless ice. The\npenguin starts moving towards left, reaches the left end and jumps with\na velocity uat an angle[IMAGE] with horizontal relative to\nground. (Neglect the height of the sled)", "question_images": ["images/image14.png", "images/image15.png", "images/image16.png"], "option_1": "Till the penguin reaches the left end, the sled is displaced", "option_2": "Till the penguin reaches the left end, the sled is displaced", "option_3": "After jumping, it will fall on the ground at a\ndistance[IMAGE] from the left end of the sled.", "option_4": "After jumping, it will fall on the ground at a distance\n[IMAGE] from the left end of the sled.", "correct_option": 3, "numerical_answer": null, "solution": "$S_{CM} = \\frac{m_{1}S_{1} + m_{2}S_{2}}{m_{1} + m_{2}}$\n$0 = \\frac{(3m)( - x) + (m)(\\mathcal{l -}x)}{3m + m}\\ $\n$x = \\frac{\\mathcal{l}}{4}$\nDisplacement of sled in this time\n$= \\left( \\frac{{ucos}\\theta}{3} \\right)\\left( \\frac{2{usin}\\theta}{g} \\right) = \\frac{1}{3}\\left( \\frac{u^{2}\\sin{2\\theta}}{g} \\right)$\nTotal distance between penguin and left end of\nsled$= \\frac{4}{3}\\left( \\frac{u^{2}sin2\\theta}{g} \\right)$", "solution_images": ["images/image21.png"], "subject": "Physics", "topic": "Centre of Mass", "subtopic": "Center of mass of system at rest", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-10 Physics paper 1 30 October Jee Main.docx"} |
| {"question_id": "P-09-Q13", "question": "Two forks A and B when sounded together produce 4 beats/s. The\nfork A is in unison with 30cm length of a sonometer wire and B is in\nunison with 25cm length of the same wire at the same tension. What can\nbe frequency of forks.", "question_images": [], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": 1, "numerical_answer": null, "solution": "", "solution_images": ["images/image77.png", "images/image78.png", "images/image79.png", "images/image80.png"], "subject": "Physics", "topic": "Wave on a string", "subtopic": "Sonometer", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-09 Physics paper 26 October.docx"} |
| {"question_id": "P-04-Q11", "question": "A block of mass 2 kg is given a push horizontally and then the\nblock starts sliding over a horizontal plane. The graph shows the\nvelocity time graph of the motion. The co-efficient of friction between\nthe plane and the block is", "question_images": ["images/image71.png"], "option_1": "0.02", "option_2": "0.2", "option_3": "0.04", "option_4": "0.4\n2 kg \n ≤", "correct_option": 2, "numerical_answer": null, "solution": "a = slope of v-t graph = - 2 m/s2\n∴ Ft = μmg = m × 2\n⇒μ × 2 × 10 = 2 × 2 ⇒ μ = 0.2\nTOPIC: NLM\nSUB TOPIC: FRICTION", "solution_images": [], "subject": "Physics", "topic": "", "subtopic": "", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-04 Paper 2 (Physics) Eng.+ Hindi 24-8-2020.docx"} |
| {"question_id": "P-02-Q34", "question": "As soon as the valve is opened, the mercury level at B in the\ntube", "question_images": ["images/image16.png"], "option_1": "Remains same", "option_2": "Oscillates", "option_3": "Goes down", "option_4": "Goes up", "correct_option": 4, "numerical_answer": null, "solution": "In narrow passage velocity is greater.\nHence static pressure will be less at B. So the level moves up.", "solution_images": [], "subject": "Physics", "topic": "", "subtopic": "", "difficulty": "", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-02 Physics Paper-02_Update.docx"} |
| {"question_id": "P-02-Q36", "question": "In a common-base configuration of transistor, α = 0.98, I_B =\n0.02mA, R_L = 5 kΩ. Output voltage across load is", "question_images": ["images/image26.png"], "option_1": "3.2 V (B) 4.9 V", "option_2": "", "option_3": "5.2", "option_4": "6.2 V", "correct_option": 2, "numerical_answer": null, "solution": "[IMAGE] I_E 0.98 = I_C\nI_E = I_B + I_C\nI_E = 1 mA\nI_C = 0.98 mA\nV_0 = R_L × I_C", "solution_images": ["images/image27.png"], "subject": "Physics", "topic": "", "subtopic": "", "difficulty": "", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-02 Physics Paper-02_Update.docx"} |
| {"question_id": "P-17-Q23", "question": "A uniform magnetic field B in positive z direction exists in a\ncircular region of radius R = 5 m. A loop of radius R = 5 m lying x-y\nplane encloses the magnetic field at t = 0 and then pulled at uniform\nvelocity$\\ \\overset{\\rightarrow}{v} = 4\\overset{\\hat{}}{i}m/s$. The emf\ninduced (in volts) is the loop at t = 2 sec is 6 V. Then magnitude of 45\nB is", "question_images": ["images/image26.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": null, "numerical_answer": "11.25", "solution": "$\\varepsilon = |(\\overset{\\rightarrow}{v} \\times \\overset{\\rightarrow}{B}) \\cdot \\overset{\\rightarrow}{\\mathcal{l}}|$\n$= VB2\\sqrt{R^{2} - {(\\frac{vt}{2})}^{2}} = VB\\sqrt{4R^{2} - V^{2}t^{2}}$\n$6V = 4 \\times B\\sqrt{4 \\times 25 - 16 \\times 4}$", "solution_images": ["images/image27.png"], "subject": "Physics", "topic": "EMI", "subtopic": "Faraday's law", "difficulty": "Moderate/ Tough", "question_type": "numerical", "has_image": true, "exam": "JEE Main", "source_paper": "P-17 Physics paper 26 Nov Second.docx"} |
| {"question_id": "P-24-Q16", "question": "A container of a large uniform cross-sectional area A resting on\na horizontal surface holds two immiscible, non-viscous and\nincompressible liquids of densities and each of height\n(1/2)H as shown. The smaller density liquid is open to atmosphere. A\nhomogeneous solid cylinder of length $\\left( L < \\frac{1}{2}h \\right)$\ncross-sectional area (1/5) A is immersed such that it floats with its\naxis vertical to the liquid-liquid interface with length (1/4) L in\ndenser liquid. If D is the density of the solid cylinder then", "question_images": ["images/image47.png"], "option_1": "$D = \\frac{3d}{2}$", "option_2": "$D = \\frac{d}{2}$", "option_3": "$D = \\frac{2d}{3}$", "option_4": "$D = \\frac{5d}{4}$", "correct_option": 4, "numerical_answer": null, "solution": "$D \\times L \\times Ag = 2d \\times \\frac{L}{4} \\times Ag + d \\times \\frac{3L}{4} \\times Ag$\n$D = \\frac{5d}{4}$", "solution_images": [], "subject": "Physics", "topic": "Mechanical Properties of Fluids", "subtopic": "Hydrostatic pressure", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-24 Physcis Paper 31 Dec.docx"} |
| {"question_id": "P-04-Q5", "question": "20 m ehukj,d dadM+ 10 izkjfEHkd osx Qsa o gksxh (g = 10 m/s2)\n20 m 10 m/s, (g=10 m/s^2)", "question_images": [], "option_1": "", "option_2": "", "option_3": "20", "option_4": "", "correct_option": 2, "numerical_answer": null, "solution": "vy2 - uy2 = 2 × g × s\n[IMAGE] vy2 = 0 + 2 × 10 × 10 = 10\nTOPIC:KINEMATIC\nSUB TOPIC: 2 D", "solution_images": ["images/image26.png", "images/image27.png", "images/image28.png", "images/image29.png"], "subject": "Physics", "topic": "", "subtopic": "", "difficulty": "Easy", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-04 Paper 2 (Physics) Eng.+ Hindi 24-8-2020.docx"} |
| {"question_id": "P-22-Q25", "question": "Figure shows the variation of internal energy \"U\" with the\ndensity \"$\\rho$ \" of one mole of ideal diatomic gas. Process BA is a\npart of rectangular hyperbola. If the work done by gas in the process BA\nis 7n joules. Find n ?", "question_images": ["images/image103.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": null, "numerical_answer": "2", "solution": "For rectangular hyperbola\nXY = constant\n$U\\rho =$ constant\n$nC_{V}T\\rho =$ constant\n$n\\frac{5}{2}RT\\frac{M}{V} =$constant\n$\\frac{5}{2}P\\frac{VM}{V} =$constant $\\Rightarrow$ P = constant\n(isobaric process)\n$\\Delta U_{B \\rightarrow A} = 37 - 2 = 35J = \\frac{5}{2}nR\\Delta T$\n$14J = nR\\Delta T$\n$\\therefore$ $W = 14J$", "solution_images": [], "subject": "Physics", "topic": "Thermodynamics", "subtopic": "Isobaric process", "difficulty": "tough", "question_type": "numerical", "has_image": true, "exam": "JEE Main", "source_paper": "P-22 Physcis Paper 19 Dec Eng..docx"} |
| {"question_id": "Ph-27-Q4", "question": "Two steel wires having same length are suspended from a ceiling\nunder the same load. If the ratio oftheir energy stored per unit volume\nis 1: 4, the ratio of their diameters is:\nleky yEckbZ ds nks LVhy ds rkjksa ij leku Hkkj cka/kdj bUg a NRk ls\nvuqikr 1: 4", "question_images": [], "option_1": "1: 2", "option_2": "", "option_3": "2: 1", "option_4": "", "correct_option": 4, "numerical_answer": null, "solution": "", "solution_images": ["images/image13.png", "images/image14.png", "images/image15.png", "images/image16.png", "images/image17.png", "images/image18.png", "images/image19.png"], "subject": "Physics", "topic": "Elasticity", "subtopic": "Potential stored in elongated rod", "difficulty": "Tough", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "Ph-27 Physics paper 2 15 Jan.docx"} |
| {"question_id": "P-04-Q20", "question": "The potential energy of a particle moving along x axis, starting\nfrom x = 0 at rest is given by\nU = (ax - b) x\n b are positive constant]", "question_images": [], "option_1": "", "option_2": "", "option_3": "", "option_4": "[IMAGE] x = 0 x-. U =\n(ax-b)x: (a, b \n)", "correct_option": 4, "numerical_answer": null, "solution": "Kmax ⇒ Umin\n⇒[IMAGE] = 0\n⇒ 2ax - b = 0\nx =[IMAGE] Ki + Ui = Kf + Uf\n0 + 0 = Kf +[IMAGE] ⇒ Kf = [IMAGE] TOPIC: WPE\nSUB TOPIC: ENERGY CONSERVATION", "solution_images": ["images/image113.png", "images/image114.png", "images/image115.png", "images/image116.png"], "subject": "Physics", "topic": "", "subtopic": "", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-04 Paper 2 (Physics) Eng.+ Hindi 24-8-2020.docx"} |
| {"question_id": "Ph-28-Q27", "question": "A car is initially at rest, 330 m away from a stationary\nobserver. It begins to move towards the observer with an acceleration of\n[IMAGE], sounding its horn continuously. 20 second\nlater, the driver stops sound the horn. The velocity of sound in air is\n330 m/s. The observer will hear the sound of the horn for a duration of\n[IMAGE] sec. Find n.", "question_images": ["images/image244.png", "images/image245.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": null, "numerical_answer": "3", "solution": "[IMAGE] In 20 seconds, distance travelled by the Source is:\n[IMAGE] Let, t = 0 be the starting time.\nThe sound wave started at t = 0 from reaches the observer at\n'B' after [IMAGE] ie. observer started hearing the\nsound at t = 1 sec. At t = 20 sec. the source reaches at 220 m\nThe last sound wave starting from reaches Hence, the observer do not hear the sound for whole 20 sec.\nbut for: [IMAGE] TOPIC: Sound wave\nSUB TOPIC: Doppler effect\nLEVEL: Moderate", "solution_images": ["images/image246.png", "images/image247.png", "images/image248.png", "images/image249.png", "images/image250.png"], "subject": "Physics", "topic": "", "subtopic": "", "difficulty": "", "question_type": "numerical", "has_image": true, "exam": "JEE Main", "source_paper": "Ph-28 Physics paper FST 16 Jan.docx"} |
| {"question_id": "P-06-Q7", "question": "Block A is given an acceleration $12{ms}^{- 2}$ towards left as\nshown in Figure. Assume block B always remains horizontal, find the\nacceleration $\\left( \\text{ in }{ms}^{- 2} \\right)$ of B.", "question_images": ["images/image11.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": 1, "numerical_answer": null, "solution": "$\\mathcal{l}_{1} + \\mathcal{l}_{2} = C \\Rightarrow \\mathcal{l}_{1}^{''} + \\mathcal{l}_{2}^{''} = 0$", "solution_images": ["images/image12.png"], "subject": "Physics", "topic": "Newton's Laws of Motion", "subtopic": "String constraint", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-06 Physics paper 14 October.docx"} |
| {"question_id": "P-09-Q18", "question": "A perfectly elastic uniform string is suspended vertically with\nits upper end fixed to the ceiling and the lower end loaded with the\nweight. If a transverse wave is imparted to the lower end of the string,\nthe pulse will", "question_images": [], "option_1": "not travel along the length of the string", "option_2": "travel upwards with increasing speed", "option_3": "travel upwards with decreasing speed", "option_4": "travelled upwards with variable acceleration", "correct_option": 2, "numerical_answer": null, "solution": "", "solution_images": ["images/image112.png", "images/image113.png", "images/image114.png"], "subject": "Physics", "topic": "Wave on a string", "subtopic": "speed of wave", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-09 Physics paper 26 October.docx"} |
| {"question_id": "P-10-Q15", "question": "A uniform triangular plate ABC of moment of inertia I (about an\naxis passing through A and perpendicular to plane of the plate) can\nrotate freely in the vertical plane about point as shown in\nfigure. The plate is released from the position shown in the figure.\nLine AB is horizontal. The acceleration of centre of mass just after the\nrelease of plate is", "question_images": ["images/image57.png"], "option_1": "$\\frac{mg}{\\sqrt{3}}a^{2}$", "option_2": "$\\frac{{\\ mga\\ }^{2}}{4\\sqrt{3}\\ I\\ }$", "option_3": "$\\frac{mga^{2}}{2\\sqrt{3}i}$", "option_4": "$\\frac{mg\\ a^{2}}{3\\ \\ I}$", "correct_option": 3, "numerical_answer": null, "solution": "Torque about A:\n$\\Rightarrow$ $\\alpha = \\frac{mga}{2I}$\n$\\Rightarrow$ Acceleration\n$= \\frac{a}{\\sqrt{3}}\\alpha = \\frac{m\\ g{\\ a}^{2}}{2\\sqrt{3}\\ I}$", "solution_images": ["images/image58.png"], "subject": "Physics", "topic": "Centre of Mass", "subtopic": "Torque", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-10 Physics paper 1 30 October Jee Main.docx"} |
| {"question_id": "P-11-Q21", "question": "Planet A has mass M and radius R. Planet B has half the mass and\nhalf the radius of Planet A. If the escape velocities from the Planets A\nand B are [IMAGE] and [IMAGE],\nrespectively, then [IMAGE] The value of n is", "question_images": ["images/image210.png", "images/image211.png", "images/image212.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": null, "numerical_answer": "4", "solution": "", "solution_images": ["images/image213.png", "images/image214.png", "images/image215.png"], "subject": "Physics", "topic": "Gravitation", "subtopic": "Escape velocity", "difficulty": "Moderate", "question_type": "numerical", "has_image": true, "exam": "JEE Main", "source_paper": "P-11 Physics paper-2 1Nov Jee Main.docx"} |
| {"question_id": "Ph-28-Q32", "question": "In a corner on a smooth horizontal surfaces we kept two masses\n[IMAGE] and [IMAGE] attached to a spring\nin natural length as shown. The spring has a spring constant 150 N/m.\nNow [IMAGE] is suddenly given a velocity towards the\nleft at t = 0. After this spring attains natural length first at time\n[IMAGE] sec and then next at time\n[IMAGE]. If mass of [IMAGE] (in kg) is K\nthen K is", "question_images": ["images/image286.png", "images/image287.png", "images/image287.png", "images/image288.png", "images/image289.png", "images/image286.png", "images/image290.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": null, "numerical_answer": "1", "solution": "Solving (i) and (ii), [IMAGE] TOPIC: Simple harmonic motion\nSUB TOPIC: Block and spring system\nLEVEL: Moderate", "solution_images": ["images/image291.png", "images/image292.png", "images/image293.png"], "subject": "Physics", "topic": "", "subtopic": "", "difficulty": "", "question_type": "numerical", "has_image": true, "exam": "JEE Main", "source_paper": "Ph-28 Physics paper FST 16 Jan.docx"} |
| {"question_id": "P-01-Q25", "question": "A mass of material exists in its solid form at its melting\ntemperature 10°C. The following processes then occur to the material:\nProcess-1: An amount of thermal energy Q is added to the material\nand [IMAGE] of the material melts.\nProcess-2: An identical additional amount of thermal energy Q is\nadded to the material and the material is now a liquid at 50°C.\nWhat is the ratio of the latent heat of fusion to the specific heat of\nthe liquid for this material?", "question_images": ["images/image112.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": null, "numerical_answer": "80", "solution": "[IMAGE] mL = Q\nQ = [IMAGE] + mS × 40\n[IMAGE] = 4mS\n[IMAGE] = 80", "solution_images": ["images/image113.png", "images/image114.png", "images/image115.png", "images/image116.png"], "subject": "Physics", "topic": "", "subtopic": "", "difficulty": "", "question_type": "numerical", "has_image": true, "exam": "JEE Main", "source_paper": "P-01 Physics Paper-01_Update.docx"} |
| {"question_id": "P-05-Q4", "question": "The variation of velocity with time of a toy car moving along a\nstraight line is as shown below. Which of the following graphs correctly\nrepresents the variation of acceleration with time for the toy car?", "question_images": ["images/image7.png"], "option_1": "", "option_2": "", "option_3": "", "option_4": "", "correct_option": 4, "numerical_answer": null, "solution": "for 0 to 1 seconds velocity increases linearly\n$a = \\frac{4 - 2}{1 - 0} = 2m/s^{2}$\n$\\Rightarrow$a vs t graph is st. line parallel to x-axis (+ve\nacceleration)\nfor 1 to 1.5 sec.$v = constant \\Rightarrow a = 0$\nfor $t > 1.5\\ sec.\\ $a is negative", "solution_images": [], "subject": "Physics", "topic": "Motion in 1D", "subtopic": "Velocity-time and acceleration-time graph", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "P-05 Physics paper 10 October.docx"} |
| {"question_id": "Ph-26-Q6", "question": "70 calories of heat is required to raise the temperature of 2\nmoles of an ideal gas at constant pressure from 30°C to 35°C (R= 2 cal\n/mol-°C) The gas may be:\nls] bl gks tkrk gs\nrks xSl gks ldrh", "question_images": ["images/image4.png", "images/image5.png", "images/image6.png"], "option_1": "", "option_2": "He", "option_3": "", "option_4": "", "correct_option": 1, "numerical_answer": null, "solution": "[IMAGE] So gas is", "solution_images": ["images/image10.png", "images/image11.png", "images/image12.png", "images/image13.png", "images/image14.png", "images/image14.png"], "subject": "Physics", "topic": "Kinetic Theory of Gases", "subtopic": "Ideal Gas", "difficulty": "Moderate", "question_type": "single_correct", "has_image": true, "exam": "JEE Main", "source_paper": "Ph-26 Physics paper 1 15 Jan.docx"} |
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