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val_id/exact_op10_samples1000_part1_proc2.jsonl

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+{"problem": "The total number of movies in Festival Lumi\u00e8re de Valmont equals 26. The number of solemn period drama in Festival de Saint-Rivage equals the number of intense detective thriller in Festival de Saint-Rivage. The number of intense detective thriller in Festival Lumi\u00e8re de Valmont equals 4 times the sum of the total number of movies in Festival de Saint-Rivage and the number of solemn period drama in Festival de Saint-Rivage. The number of solemn period drama in Festival Lumi\u00e8re de Valmont equals the number of intense detective thriller in Festival de Saint-Rivage. The number of intense detective thriller in Festival de Saint-Rivage exists, and its number is greater than 0. ", "question": "How many intense detective thriller does Festival de Saint-Rivage have?", "solution": "The question is difficult, so we use equations to solve it. Define intense detective thriller in Festival de Saint-Rivage as x; we don't know its value yet but will find it out later. Define solemn period drama in Festival de Saint-Rivage as S; so S = x = x. Define total number of movies in Festival de Saint-Rivage as K; so K = S + x = x + x = 2*x. Define solemn period drama in Festival Lumi\u00e8re de Valmont as v; so v = x = x. Define intense detective thriller in Festival Lumi\u00e8re de Valmont as N; a = K + S = 2*x + x = 3*x; so N = 4 * a = (4) * (3*x) = 12*x. Define total number of movies in Festival Lumi\u00e8re de Valmont as i; so i = v + N = x + 12*x = 13*x. We know i = 26, so we have 13*x = 26 and we solve it through the following steps: Simplifying the equation: 13*x = 26. Move all terms to one side: 13*x - 26 = 0. Isolate the term with x: 13*x = 26. Divide both sides by 13: x = 26 / 13. Solution: x = 2. Answer: 2.", "op": 10, "id": "7_p2", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
+{"problem": "The number of adult bear in South Zoo equals 4. The number of adult bear in Mayer Aquarium equals 2 plus the sum of the total number of adult animals in South Zoo and the number of adult fox in South Zoo. The number of adult fox in South Zoo equals the number of adult bear in South Zoo. The number of adult fox in Mayer Aquarium equals the number of adult fox in South Zoo. ", "question": "What is the total number of adult animals in Mayer Aquarium?", "solution": "Define adult bear in South Zoo as p; so p = 4. Define adult fox in South Zoo as P; so P = p = 4. Define total number of adult animals in South Zoo as o; so o = P + p = 4 + 4 = 8. Define adult fox in Mayer Aquarium as e; so e = P = 4. Define adult bear in Mayer Aquarium as j; r = o + P = 8 + 4 = 12; so j = 2 + r = 2 + 12 = 14. Define total number of adult animals in Mayer Aquarium as U; so U = e + j = 4 + 14 = 18. Answer: 18.", "op": 10, "id": "14_p2", "template": "crazy_zootopia", "mode": "normalforward", "length": "zero_context", "d": 2}
+{"problem": "The number of regional medical school in Brightford equals the sum of the number of regional medical school in Evervale City, the total number of schools in Evervale City, and the number of private middle school in Evervale City. The number of private middle school in Brightford equals the total number of schools in Evervale City. The number of regional medical school in Evervale City equals 4. The number of private middle school in Evervale City equals the number of regional medical school in Evervale City. ", "question": "What is the total number of schools in Brightford?", "solution": "Define regional medical school in Evervale City as e; so e = 4. Define private middle school in Evervale City as t; so t = e = 4. Define total number of schools in Evervale City as T; so T = t + e = 4 + 4 = 8. Define private middle school in Brightford as S; so S = T = 8. Define regional medical school in Brightford as r; q = e + T = 4 + 8 = 12; so r = q + t = 12 + 4 = 16. Define total number of schools in Brightford as i; so i = S + r = 8 + 16 = 24. Answer: 24.", "op": 10, "id": "1_p2", "template": "teachers_in_school", "mode": "normalforward", "length": "zero_context", "d": 2}
+{"problem": "The total number of schools in Clearwater Bay equals 6. The number of elementary school in Ruby Bay equals the total number of schools in Riverton City. The number of public highschool in Clearwater Bay equals the number of elementary school in Riverton City. The number of culinarian school in Clearwater Bay equals the total number of schools in Ruby Bay. The number of elementary school in Riverton City equals the number of public highschool in Riverton City. The number of public highschool in Riverton City exists, and its number is greater than 0. ", "question": "How many public highschool does Riverton City have?", "solution": "The question is difficult, so we use equations to solve it. Define public highschool in Riverton City as x; we don't know its value yet but will find it out later. Define elementary school in Riverton City as U; so U = x = x. Define total number of schools in Riverton City as B; so B = x + U = x + x = 2*x. Define elementary school in Ruby Bay as f; so f = B = 2*x. Define total number of schools in Ruby Bay as E; so E = f = 2*x. Define culinarian school in Clearwater Bay as A; so A = E = 2*x. Define public highschool in Clearwater Bay as N; so N = U = x. Define total number of schools in Clearwater Bay as o; so o = N + A = x + 2*x = 3*x. We know o = 6, so we have 3*x = 6 and we solve it through the following steps: Simplifying the equation: 3*x = 6. Move all terms to one side: 3*x - 6 = 0. Isolate the term with x: 3*x = 6. Divide both sides by 3: x = 6 / 3. Solution: x = 2. Answer: 2.", "op": 10, "id": "2_p2", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
+{"problem": "The number of calm road movie in Cin\u00e9ma de Montreval equals 1. The number of calm road movie in R\u00eaves de Belleville equals the sum of the total number of movies in Cin\u00e9ma de Montreval, the number of futuristic sci-fi movie in Cin\u00e9ma de Montreval, and the number of calm road movie in Cin\u00e9ma de Montreval. The number of futuristic sci-fi movie in Cin\u00e9ma de Montreval equals 4. The number of futuristic sci-fi movie in R\u00eaves de Belleville exists, and its number is greater than 0. The total number of movies in R\u00eaves de Belleville equals 12. ", "question": "How many futuristic sci-fi movie does R\u00eaves de Belleville have?", "solution": "The question is difficult, so we use equations to solve it. Define futuristic sci-fi movie in Cin\u00e9ma de Montreval as Y; so Y = 4. Define calm road movie in Cin\u00e9ma de Montreval as n; so n = 1. Define total number of movies in Cin\u00e9ma de Montreval as A; so A = Y + n = 4 + 1 = 5. Define futuristic sci-fi movie in R\u00eaves de Belleville as x; we don't know its value yet but will find it out later. Define calm road movie in R\u00eaves de Belleville as c; a = A + Y = 5 + 4 = 9; so c = a + n = 9 + 1 = 10. Define total number of movies in R\u00eaves de Belleville as U; so U = x + c = x + 10 = x + 10. We know U = 12, so we have x + 10 = 12 and we solve it through the following steps: Simplifying the equation: x + 10 = 12. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2.", "op": 10, "id": "6_p2", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
+{"problem": "The number of adult owl in Bundle Ranch equals the total number of adult animals in South Zoo. The number of adult blue jay in Mayer Aquarium equals the total number of adult animals in Bundle Ranch. The number of adult crow in Bundle Ranch equals the number of adult blue jay in South Zoo. The number of adult crow in Mayer Aquarium equals the number of adult blue jay in South Zoo. The number of adult blue jay in South Zoo equals 3. ", "question": "What is the total number of adult animals in Mayer Aquarium?", "solution": "Define adult blue jay in South Zoo as U; so U = 3. Define adult crow in Bundle Ranch as E; so E = U = 3. Define total number of adult animals in South Zoo as i; so i = U = 3. Define adult owl in Bundle Ranch as m; so m = i = 3. Define total number of adult animals in Bundle Ranch as z; so z = m + E = 3 + 3 = 6. Define adult blue jay in Mayer Aquarium as X; so X = z = 6. Define adult crow in Mayer Aquarium as t; so t = U = 3. Define total number of adult animals in Mayer Aquarium as D; so D = X + t = 6 + 3 = 9. Answer: 9.", "op": 10, "id": "12_p2", "template": "crazy_zootopia", "mode": "normalforward", "length": "zero_context", "d": 2}
+{"problem": "The total number of movies in Festival Lumi\u00e8re de Valmont equals 6. The number of upbeat metropolis comedy in R\u00eaves de Belleville exists, and its number is greater than 0. The number of calm road movie in Festival Lumi\u00e8re de Valmont equals the total number of movies in R\u00eaves de Belleville. The number of upbeat metropolis comedy in Festival Lumi\u00e8re de Valmont equals the sum of the number of calm road movie in R\u00eaves de Belleville, the total number of movies in R\u00eaves de Belleville, and the number of upbeat metropolis comedy in R\u00eaves de Belleville. The number of calm road movie in R\u00eaves de Belleville equals the number of upbeat metropolis comedy in R\u00eaves de Belleville. ", "question": "How many upbeat metropolis comedy does R\u00eaves de Belleville have?", "solution": "The question is difficult, so we use equations to solve it. Define upbeat metropolis comedy in R\u00eaves de Belleville as x; we don't know its value yet but will find it out later. Define calm road movie in R\u00eaves de Belleville as Q; so Q = x = x. Define total number of movies in R\u00eaves de Belleville as a; so a = Q + x = x + x = 2*x. Define calm road movie in Festival Lumi\u00e8re de Valmont as h; so h = a = 2*x. Define upbeat metropolis comedy in Festival Lumi\u00e8re de Valmont as J; i = Q + a = x + 2*x = 3*x; so J = i + x = 3*x + x = 4*x. Define total number of movies in Festival Lumi\u00e8re de Valmont as O; so O = J + h = 4*x + 2*x = 6*x. We know O = 6, so we have 6*x = 6 and we solve it through the following steps: Simplifying the equation: 6*x = 6. Move all terms to one side: 6*x - 6 = 0. Isolate the term with x: 6*x = 6. Divide both sides by 6: x = 6 / 6. Solution: x = 1. Answer: 1.", "op": 10, "id": "7_p2", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
+{"problem": "The number of culinarian school in Evervale City equals the sum of the number of regional medical school in Hawkesbury, the total number of schools in Hawkesbury, and the number of culinarian school in Hawkesbury. The number of regional medical school in Evervale City equals the total number of schools in Hawkesbury. The number of regional medical school in Hawkesbury equals 3. The number of culinarian school in Hawkesbury equals 1. ", "question": "What is the total number of schools in Evervale City?", "solution": "Define regional medical school in Hawkesbury as A; so A = 3. Define culinarian school in Hawkesbury as x; so x = 1. Define total number of schools in Hawkesbury as k; so k = A + x = 3 + 1 = 4. Define regional medical school in Evervale City as t; so t = k = 4. Define culinarian school in Evervale City as G; v = A + k = 3 + 4 = 7; so G = v + x = 7 + 1 = 8. Define total number of schools in Evervale City as s; so s = t + G = 4 + 8 = 12. Answer: 12.", "op": 10, "id": "1_p2", "template": "teachers_in_school", "mode": "normalforward", "length": "zero_context", "d": 2}
+{"problem": "The number of adult bear in Cedar Valley equals the number of adult deer in Cedar Valley. The number of adult bear in Maple Creek equals 4. The number of adult wolf in Pine Ridge equals 2 plus the difference between the number of adult fox in Pine Ridge and the number of adult bear in Pine Ridge. The number of adult bear in Oakridge Riverside equals 2. The number of adult bear in Pine Ridge equals 3 plus the number of adult fox in Pine Ridge. The number of adult wolf in Maple Creek equals the number of adult wolf in Pine Ridge. The number of adult deer in Cedar Valley equals 2. The number of adult wolf in Cedar Valley equals 4 plus the difference between the number of adult deer in Cedar Valley and the number of adult fox in Cedar Valley. The number of adult fox in Oakridge Riverside equals the number of adult wolf in Maple Creek. The number of adult fox in Pine Ridge equals 2. The number of adult fox in Cedar Valley equals 3. The number of adult deer in Oakridge Riverside equals the number of adult bear in Cedar Valley. The number of adult deer in Maple Creek equals the sum of the number of adult wolf in Pine Ridge and the number of adult wolf in Maple Creek. The number of adult wolf in Oakridge Riverside equals 2. ", "question": "What is the total number of adult animals in Cedar Valley?", "solution": "Define adult deer in Cedar Valley as h; so h = 2. Define adult fox in Cedar Valley as g; so g = 3. Define adult bear in Cedar Valley as D; so D = h = 2. Define adult wolf in Cedar Valley as C; I = h - g = 2 - 3 = -1; so C = 4 + I = 4 + -1 = 3. Define total number of adult animals in Cedar Valley as H; z = D + g = 2 + 3 = 5; M = z + h = 5 + 2 = 7; so H = M + C = 7 + 3 = 10. Answer: 10.", "op": 10, "id": "1_p2", "template": "crazy_zootopia", "mode": "normalforward", "length": "zero_context", "d": 2}
+{"problem": "The number of futuristic sci-fi movie in Taylor Movie Festival equals the number of futuristic sci-fi movie in Golden Banana Movie Festival. The number of intense detective thriller in Golden Banana Movie Festival equals 2. The number of futuristic sci-fi movie in Golden Banana Movie Festival equals 3. The number of intense detective thriller in Taylor Movie Festival equals the sum of the total number of movies in Golden Banana Movie Festival, the number of futuristic sci-fi movie in Golden Banana Movie Festival, and the number of intense detective thriller in Golden Banana Movie Festival. ", "question": "What is the total number of movies in Taylor Movie Festival?", "solution": "Define intense detective thriller in Golden Banana Movie Festival as B; so B = 2. Define futuristic sci-fi movie in Golden Banana Movie Festival as t; so t = 3. Define total number of movies in Golden Banana Movie Festival as U; so U = t + B = 3 + 2 = 5. Define futuristic sci-fi movie in Taylor Movie Festival as O; so O = t = 3. Define intense detective thriller in Taylor Movie Festival as u; G = U + t = 5 + 3 = 8; so u = G + B = 8 + 2 = 10. Define total number of movies in Taylor Movie Festival as J; so J = O + u = 3 + 10 = 13. Answer: 13.", "op": 10, "id": "18_p2", "template": "movie_festival_awards", "mode": "normalforward", "length": "zero_context", "d": 2}
+{"problem": "The number of adult bear in Oakridge Riverside equals the number of adult racoon in Oakridge Riverside. The number of adult racoon in Oakridge Riverside exists, and its number is greater than 0. The number of adult racoon in Pine Ridge equals the number of adult bear in Oakridge Riverside. The total number of adult animals in Pine Ridge equals 10. The number of adult bear in Pine Ridge equals 2 plus the sum of the total number of adult animals in Oakridge Riverside and the number of adult racoon in Oakridge Riverside. ", "question": "How many adult racoon does Oakridge Riverside have?", "solution": "The question is difficult, so we use equations to solve it. Define adult racoon in Oakridge Riverside as x; we don't know its value yet but will find it out later. Define adult bear in Oakridge Riverside as m; so m = x = x. Define total number of adult animals in Oakridge Riverside as q; so q = m + x = x + x = 2*x. Define adult racoon in Pine Ridge as Y; so Y = m = x. Define adult bear in Pine Ridge as P; F = q + x = 2*x + x = 3*x; so P = 2 + F = 2 + 3*x = 3*x + 2. Define total number of adult animals in Pine Ridge as p; so p = P + Y = 3*x + 2 + x = 4*x + 2. We know p = 10, so we have 4*x + 2 = 10 and we solve it through the following steps: Simplifying the equation: 4*x + 2 = 10. Move all terms to one side: 4*x - 8 = 0. Isolate the term with x: 4*x = 8. Divide both sides by 4: x = 8 / 4. Solution: x = 2. Answer: 2.", "op": 10, "id": "21_p2", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
+{"problem": "The number of regional medical school in Evervale City equals the total number of schools in Westhaven City. The number of private middle school in Brightford equals the total number of schools in Evervale City. The number of culinarian school in Brightford equals the total number of schools in Evervale City. The number of culinarian school in Westhaven City equals 4. The number of private middle school in Westhaven City equals the number of culinarian school in Westhaven City. ", "question": "What is the total number of schools in Brightford?", "solution": "Define culinarian school in Westhaven City as H; so H = 4. Define private middle school in Westhaven City as q; so q = H = 4. Define total number of schools in Westhaven City as X; so X = q + H = 4 + 4 = 8. Define regional medical school in Evervale City as j; so j = X = 8. Define total number of schools in Evervale City as w; so w = j = 8. Define culinarian school in Brightford as K; so K = w = 8. Define private middle school in Brightford as B; so B = w = 8. Define total number of schools in Brightford as D; so D = B + K = 8 + 8 = 16. Answer: 16.", "op": 10, "id": "2_p2", "template": "teachers_in_school", "mode": "normalforward", "length": "zero_context", "d": 2}
+{"problem": "The number of futuristic sci-fi movie in R\u00eaves de Belleville exists, and its number is greater than 0. The total number of movies in Cin\u00e9ma de Montreval equals 18. The number of futuristic sci-fi movie in Cin\u00e9ma de Montreval equals the sum of the number of futuristic sci-fi movie in R\u00eaves de Belleville, the total number of movies in R\u00eaves de Belleville, and the number of upbeat metropolis comedy in R\u00eaves de Belleville. The number of upbeat metropolis comedy in Cin\u00e9ma de Montreval equals the total number of movies in R\u00eaves de Belleville. The number of upbeat metropolis comedy in R\u00eaves de Belleville equals the number of futuristic sci-fi movie in R\u00eaves de Belleville. ", "question": "How many futuristic sci-fi movie does R\u00eaves de Belleville have?", "solution": "The question is difficult, so we use equations to solve it. Define futuristic sci-fi movie in R\u00eaves de Belleville as x; we don't know its value yet but will find it out later. Define upbeat metropolis comedy in R\u00eaves de Belleville as d; so d = x = x. Define total number of movies in R\u00eaves de Belleville as l; so l = x + d = x + x = 2*x. Define upbeat metropolis comedy in Cin\u00e9ma de Montreval as I; so I = l = 2*x. Define futuristic sci-fi movie in Cin\u00e9ma de Montreval as i; p = x + l = x + 2*x = 3*x; so i = p + d = 3*x + x = 4*x. Define total number of movies in Cin\u00e9ma de Montreval as n; so n = i + I = 4*x + 2*x = 6*x. We know n = 18, so we have 6*x = 18 and we solve it through the following steps: Simplifying the equation: 6*x = 18. Move all terms to one side: 6*x - 18 = 0. Isolate the term with x: 6*x = 18. Divide both sides by 6: x = 18 / 6. Solution: x = 3. Answer: 3.", "op": 10, "id": "15_p2", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
+{"problem": "The number of solemn period drama in Festival de Clairmont equals the total number of movies in R\u00eaves de Belleville. The number of solemn period drama in Cin\u00e9ma de Montreval exists, and its number is greater than 0. The total number of movies in Festival de Clairmont equals 6. The number of upbeat metropolis comedy in R\u00eaves de Belleville equals the total number of movies in Cin\u00e9ma de Montreval. The number of solemn period drama in R\u00eaves de Belleville equals the number of upbeat metropolis comedy in Cin\u00e9ma de Montreval. The number of upbeat metropolis comedy in Cin\u00e9ma de Montreval equals the number of solemn period drama in Cin\u00e9ma de Montreval. ", "question": "How many solemn period drama does Cin\u00e9ma de Montreval have?", "solution": "The question is difficult, so we use equations to solve it. Define solemn period drama in Cin\u00e9ma de Montreval as x; we don't know its value yet but will find it out later. Define upbeat metropolis comedy in Cin\u00e9ma de Montreval as Y; so Y = x = x. Define solemn period drama in R\u00eaves de Belleville as n; so n = Y = x. Define total number of movies in Cin\u00e9ma de Montreval as B; so B = x + Y = x + x = 2*x. Define upbeat metropolis comedy in R\u00eaves de Belleville as q; so q = B = 2*x. Define total number of movies in R\u00eaves de Belleville as a; so a = n + q = x + 2*x = 3*x. Define solemn period drama in Festival de Clairmont as g; so g = a = 3*x. Define total number of movies in Festival de Clairmont as Q; so Q = g = 3*x. We know Q = 6, so we have 3*x = 6 and we solve it through the following steps: Simplifying the equation: 3*x = 6. Move all terms to one side: 3*x - 6 = 0. Isolate the term with x: 3*x = 6. Divide both sides by 3: x = 6 / 3. Solution: x = 2. Answer: 2.", "op": 10, "id": "15_p2", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
+{"problem": "The number of futuristic sci-fi movie in Verdi Movie Festival equals the total number of movies in Taylor Movie Festival. The number of solemn period drama in Verdi Movie Festival equals 2 times the sum of the number of futuristic sci-fi movie in Taylor Movie Festival and the total number of movies in Taylor Movie Festival. The number of solemn period drama in Taylor Movie Festival equals 2. The total number of movies in Verdi Movie Festival equals 11. The number of futuristic sci-fi movie in Taylor Movie Festival exists, and its number is greater than 0. ", "question": "How many futuristic sci-fi movie does Taylor Movie Festival have?", "solution": "The question is difficult, so we use equations to solve it. Define solemn period drama in Taylor Movie Festival as p; so p = 2. Define futuristic sci-fi movie in Taylor Movie Festival as x; we don't know its value yet but will find it out later. Define total number of movies in Taylor Movie Festival as N; so N = x + p = x + 2 = x + 2. Define futuristic sci-fi movie in Verdi Movie Festival as L; so L = N = x + 2. Define solemn period drama in Verdi Movie Festival as v; j = x + N = x + x + 2 = 2*x + 2; so v = 2 * j = (2) * (2*x + 2) = 4*x + 4. Define total number of movies in Verdi Movie Festival as B; so B = L + v = x + 2 + 4*x + 4 = 5*x + 6. We know B = 11, so we have 5*x + 6 = 11 and we solve it through the following steps: Simplifying the equation: 5*x + 6 = 11. Move all terms to one side: 5*x - 5 = 0. Isolate the term with x: 5*x = 5. Divide both sides by 5: x = 5 / 5. Solution: x = 1. Answer: 1.", "op": 10, "id": "3_p2", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
+{"problem": "The number of elementary school in Riverton City equals 4. The number of elementary school in Clearwater Bay equals the number of culinarian school in Shoreline City. The number of culinarian school in Riverton City equals 2 times the number of public highschool in Riverton City. The number of culinarian school in Shoreline City equals the sum of the number of private middle school in Ruby Bay, the number of culinarian school in Riverton City, and the number of public highschool in Clearwater Bay. The number of culinarian school in Oakbridge City equals 2 plus the number of public highschool in Oakbridge City. The number of elementary school in Oakbridge City equals 4 times the sum of the number of private middle school in Riverton City and the number of public highschool in Oakbridge City. The number of public highschool in Riverton City equals 2 times the difference between the number of elementary school in Riverton City and the number of private middle school in Ruby Bay. The number of public highschool in Shoreline City equals the sum of the total number of schools in Ruby Bay and the number of public highschool in Oakbridge City. The number of regional medical school in Shoreline City equals 3 plus the number of private middle school in Ruby Bay. The number of public highschool in Oakbridge City equals 3. The number of private middle school in Riverton City equals the number of public highschool in Oakbridge City. The number of private middle school in Ruby Bay equals 3 times the number of elementary school in Riverton City. The number of regional medical school in Riverton City equals the number of culinarian school in Riverton City. The number of regional medical school in Clearwater Bay equals 3. The number of private middle school in Shoreline City equals the number of elementary school in Oakbridge City. The number of elementary school in Shoreline City equals the total number of schools in Ruby Bay. The number of culinarian school in Ruby Bay equals 3. The number of public highschool in Clearwater Bay equals 2 plus the number of elementary school in Riverton City. The number of public highschool in Ruby Bay equals 2. ", "question": "What is the total number of schools in Oakbridge City?", "solution": "Define public highschool in Oakbridge City as s; so s = 3. Define private middle school in Riverton City as f; so f = s = 3. Define culinarian school in Oakbridge City as n; D = s = 3; so n = 2 + D = 2 + 3 = 5. Define elementary school in Oakbridge City as d; q = f + s = 3 + 3 = 6; so d = 4 * q = 4 * 6 = 24. Define total number of schools in Oakbridge City as L; E = n + d = 5 + 24 = 29; so L = E + s = 29 + 3 = 32. Answer: 32.", "op": 10, "id": "16_p2", "template": "teachers_in_school", "mode": "normalforward", "length": "zero_context", "d": 2}
+{"problem": "The number of solemn period drama in Cin\u00e9ma de Montreval equals 4. The number of upbeat metropolis comedy in Cin\u00e9ma de Montreval equals 2. The number of upbeat metropolis comedy in Festival de Clairmont equals the total number of movies in Cin\u00e9ma de Montreval. The number of solemn period drama in Festival de Clairmont equals the sum of the number of solemn period drama in Cin\u00e9ma de Montreval, the number of upbeat metropolis comedy in Cin\u00e9ma de Montreval, and the total number of movies in Cin\u00e9ma de Montreval. ", "question": "What is the total number of movies in Festival de Clairmont?", "solution": "Define solemn period drama in Cin\u00e9ma de Montreval as J; so J = 4. Define upbeat metropolis comedy in Cin\u00e9ma de Montreval as P; so P = 2. Define total number of movies in Cin\u00e9ma de Montreval as A; so A = P + J = 2 + 4 = 6. Define upbeat metropolis comedy in Festival de Clairmont as X; so X = A = 6. Define solemn period drama in Festival de Clairmont as r; a = J + P = 4 + 2 = 6; so r = a + A = 6 + 6 = 12. Define total number of movies in Festival de Clairmont as M; so M = X + r = 6 + 12 = 18. Answer: 18.", "op": 10, "id": "0_p2", "template": "movie_festival_awards", "mode": "normalforward", "length": "zero_context", "d": 2}
+{"problem": "The total number of schools in Oakbridge City equals 5. The number of regional medical school in Oakbridge City equals the sum of the total number of schools in Ruby Bay and the number of regional medical school in Ruby Bay. The number of private middle school in Ruby Bay exists, and its number is greater than 0. The number of regional medical school in Ruby Bay equals the number of private middle school in Ruby Bay. The number of private middle school in Oakbridge City equals the sum of the number of regional medical school in Ruby Bay and the number of private middle school in Ruby Bay. ", "question": "How many private middle school does Ruby Bay have?", "solution": "The question is difficult, so we use equations to solve it. Define private middle school in Ruby Bay as x; we don't know its value yet but will find it out later. Define regional medical school in Ruby Bay as G; so G = x = x. Define total number of schools in Ruby Bay as B; so B = G + x = x + x = 2*x. Define private middle school in Oakbridge City as h; so h = G + x = x + x = 2*x. Define regional medical school in Oakbridge City as A; so A = B + G = 2*x + x = 3*x. Define total number of schools in Oakbridge City as d; so d = A + h = 3*x + 2*x = 5*x. We know d = 5, so we have 5*x = 5 and we solve it through the following steps: Simplifying the equation: 5*x = 5. Move all terms to one side: 5*x - 5 = 0. Isolate the term with x: 5*x = 5. Divide both sides by 5: x = 5 / 5. Solution: x = 1. Answer: 1.", "op": 10, "id": "7_p2", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
+{"problem": "The total number of adult animals in Mayer Aquarium equals 4. The number of adult deer in Mayer Aquarium exists, and its number is greater than 0. The number of adult wolf in Mayer Aquarium equals 2 times the difference between the total number of adult animals in Hamilton Farm and the number of adult wolf in Hamilton Farm. The number of adult deer in Hamilton Farm equals 1. The number of adult wolf in Hamilton Farm equals 1. ", "question": "How many adult deer does Mayer Aquarium have?", "solution": "The question is difficult, so we use equations to solve it. Define adult deer in Hamilton Farm as A; so A = 1. Define adult wolf in Hamilton Farm as j; so j = 1. Define total number of adult animals in Hamilton Farm as p; so p = j + A = 1 + 1 = 2. Define adult deer in Mayer Aquarium as x; we don't know its value yet but will find it out later. Define adult wolf in Mayer Aquarium as q; N = p - j = (2) - (1) = 1; so q = 2 * N = (2) * (1) = 2. Define total number of adult animals in Mayer Aquarium as Z; so Z = q + x = 2 + x = x + 2. We know Z = 4, so we have x + 2 = 4 and we solve it through the following steps: Simplifying the equation: x + 2 = 4. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2.", "op": 10, "id": "9_p2", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
+{"problem": "The number of adult blue jay in Cedar Valley equals the sum of the number of adult blue jay in Maple Creek, the number of adult parrot in Maple Creek, and the total number of adult animals in Maple Creek. The number of adult parrot in Cedar Valley equals the total number of adult animals in Maple Creek. The number of adult parrot in Maple Creek equals 2. The number of adult blue jay in Maple Creek equals 2. ", "question": "What is the total number of adult animals in Cedar Valley?", "solution": "Define adult blue jay in Maple Creek as l; so l = 2. Define adult parrot in Maple Creek as L; so L = 2. Define total number of adult animals in Maple Creek as H; so H = L + l = 2 + 2 = 4. Define adult parrot in Cedar Valley as G; so G = H = 4. Define adult blue jay in Cedar Valley as b; q = l + L = 2 + 2 = 4; so b = q + H = 4 + 4 = 8. Define total number of adult animals in Cedar Valley as w; so w = G + b = 4 + 8 = 12. Answer: 12.", "op": 10, "id": "22_p2", "template": "crazy_zootopia", "mode": "normalforward", "length": "zero_context", "d": 2}