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test_id/exact_op10_samples1000_part1_proc2.jsonl

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+{"problem": "The number of upbeat metropolis comedy in R\u00eaves de Belleville equals 3 times the difference between the total number of movies in Cin\u00e9ma de Montreval and the number of upbeat metropolis comedy in Cin\u00e9ma de Montreval. The number of calm road movie in Cin\u00e9ma de Montreval equals 2. The number of calm road movie in R\u00eaves de Belleville equals the total number of movies in Cin\u00e9ma de Montreval. The number of upbeat metropolis comedy in Cin\u00e9ma de Montreval equals 4. ", "question": "What is the total number of movies in R\u00eaves de Belleville?", "solution": "Define calm road movie in Cin\u00e9ma de Montreval as J; so J = 2. Define upbeat metropolis comedy in Cin\u00e9ma de Montreval as I; so I = 4. Define total number of movies in Cin\u00e9ma de Montreval as E; so E = J + I = 2 + 4 = 6. Define calm road movie in R\u00eaves de Belleville as S; so S = E = 6. Define upbeat metropolis comedy in R\u00eaves de Belleville as X; q = E - I = 6 - 4 = 2; so X = 3 * q = 3 * 2 = 6. Define total number of movies in R\u00eaves de Belleville as L; so L = S + X = 6 + 6 = 12. Answer: 12.", "op": 10, "id": "0_p2", "template": "movie_festival_awards", "mode": "normalforward", "length": "zero_context", "d": 2}
+{"problem": "The number of adult eagle in Oakridge Riverside equals the number of adult crow in Oakridge Riverside. The number of adult crow in Pine Ridge exists, and its number is greater than 0. The number of adult eagle in Pine Ridge equals the sum of the total number of adult animals in Oakridge Riverside, the number of adult eagle in Oakridge Riverside, and the number of adult crow in Oakridge Riverside. The total number of adult animals in Pine Ridge equals 20. The number of adult crow in Oakridge Riverside equals 4. ", "question": "How many adult crow does Pine Ridge have?", "solution": "The question is difficult, so we use equations to solve it. Define adult crow in Oakridge Riverside as s; so s = 4. Define adult eagle in Oakridge Riverside as n; so n = s = 4. Define total number of adult animals in Oakridge Riverside as o; so o = n + s = 4 + 4 = 8. Define adult crow in Pine Ridge as x; we don't know its value yet but will find it out later. Define adult eagle in Pine Ridge as i; u = o + n = 8 + 4 = 12; so i = u + s = 12 + 4 = 16. Define total number of adult animals in Pine Ridge as L; so L = i + x = 16 + x = x + 16. We know L = 20, so we have x + 16 = 20 and we solve it through the following steps: Simplifying the equation: x + 16 = 20. Move all terms to one side: x - 4 = 0. Isolate the term with x: 1*x = 4. Divide both sides by 1: x = 4 / 1. Solution: x = 4. Answer: 4.", "op": 10, "id": "4_p2", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
+{"problem": "The total number of adult animals in Bundle Ranch equals 4. The number of adult deer in Hamilton Farm exists, and its number is greater than 0. The number of adult wolf in South Zoo equals 1 plus the difference between the number of adult deer in Hamilton Farm and the total number of adult animals in Hamilton Farm. The number of adult bear in Bundle Ranch equals the total number of adult animals in Hamilton Farm. The number of adult fox in Bundle Ranch equals the total number of adult animals in South Zoo. ", "question": "How many adult deer does Hamilton Farm have?", "solution": "The question is difficult, so we use equations to solve it. Define adult deer in Hamilton Farm as x; we don't know its value yet but will find it out later. Define total number of adult animals in Hamilton Farm as m; so m = x = x. Define adult bear in Bundle Ranch as q; so q = m = x. Define adult wolf in South Zoo as Y; h = x - m = (x) - (x) = 0; so Y = 1 + h = 1 + 0 = 1. Define total number of adult animals in South Zoo as P; so P = Y = 1. Define adult fox in Bundle Ranch as D; so D = P = 1. Define total number of adult animals in Bundle Ranch as a; so a = q + D = x + 1 = x + 1. We know a = 4, so we have x + 1 = 4 and we solve it through the following steps: Simplifying the equation: x + 1 = 4. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3.", "op": 10, "id": "20_p2", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
+{"problem": "The number of adult owl in Mayer Aquarium exists, and its number is greater than 0. The number of adult owl in South Zoo equals 1. The total number of adult animals in Mayer Aquarium equals 6. The number of adult blue jay in South Zoo equals the number of adult owl in South Zoo. The number of adult blue jay in Mayer Aquarium equals 3 times the difference between the total number of adult animals in South Zoo and the number of adult blue jay in South Zoo. ", "question": "How many adult owl does Mayer Aquarium have?", "solution": "The question is difficult, so we use equations to solve it. Define adult owl in South Zoo as C; so C = 1. Define adult blue jay in South Zoo as A; so A = C = 1. Define total number of adult animals in South Zoo as y; so y = C + A = 1 + 1 = 2. Define adult owl in Mayer Aquarium as x; we don't know its value yet but will find it out later. Define adult blue jay in Mayer Aquarium as E; n = y - A = (2) - (1) = 1; so E = 3 * n = (3) * (1) = 3. Define total number of adult animals in Mayer Aquarium as p; so p = x + E = x + 3 = x + 3. We know p = 6, so we have x + 3 = 6 and we solve it through the following steps: Simplifying the equation: x + 3 = 6. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3.", "op": 10, "id": "6_p2", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
+{"problem": "The number of intense detective thriller in Festival de Clairmont exists, and its number is greater than 0. The number of intense detective thriller in Festival de Saint-Rivage equals 1. The number of upbeat metropolis comedy in Festival de Clairmont equals the sum of the total number of movies in Festival de Saint-Rivage, the number of upbeat metropolis comedy in Festival de Saint-Rivage, and the number of intense detective thriller in Festival de Saint-Rivage. The total number of movies in Festival de Clairmont equals 8. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals 2. ", "question": "How many intense detective thriller does Festival de Clairmont have?", "solution": "The question is difficult, so we use equations to solve it. Define intense detective thriller in Festival de Saint-Rivage as z; so z = 1. Define upbeat metropolis comedy in Festival de Saint-Rivage as i; so i = 2. Define total number of movies in Festival de Saint-Rivage as l; so l = z + i = 1 + 2 = 3. Define intense detective thriller in Festival de Clairmont as x; we don't know its value yet but will find it out later. Define upbeat metropolis comedy in Festival de Clairmont as C; p = l + i = 3 + 2 = 5; so C = p + z = 5 + 1 = 6. Define total number of movies in Festival de Clairmont as Z; so Z = x + C = x + 6 = x + 6. We know Z = 8, so we have x + 6 = 8 and we solve it through the following steps: Simplifying the equation: x + 6 = 8. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2.", "op": 10, "id": "13_p2", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
+{"problem": "The number of public highschool in Oakbridge City exists, and its number is greater than 0. The number of public highschool in Ruby Bay equals 3 plus the sum of the total number of schools in Oakbridge City and the number of private middle school in Oakbridge City. The total number of schools in Ruby Bay equals 19. The number of private middle school in Oakbridge City equals the number of public highschool in Oakbridge City. The number of private middle school in Ruby Bay equals the number of private middle school in Oakbridge City. ", "question": "How many public highschool does Oakbridge City have?", "solution": "The question is difficult, so we use equations to solve it. Define public highschool in Oakbridge City as x; we don't know its value yet but will find it out later. Define private middle school in Oakbridge City as l; so l = x = x. Define total number of schools in Oakbridge City as v; so v = x + l = x + x = 2*x. Define private middle school in Ruby Bay as s; so s = l = x. Define public highschool in Ruby Bay as u; L = v + l = 2*x + x = 3*x; so u = 3 + L = 3 + 3*x = 3*x + 3. Define total number of schools in Ruby Bay as R; so R = u + s = 3*x + 3 + x = 4*x + 3. We know R = 19, so we have 4*x + 3 = 19 and we solve it through the following steps: Simplifying the equation: 4*x + 3 = 19. Move all terms to one side: 4*x - 16 = 0. Isolate the term with x: 4*x = 16. Divide both sides by 4: x = 16 / 4. Solution: x = 4. Answer: 4.", "op": 10, "id": "7_p2", "template": "teachers_in_school", "mode": "forwardreverse", "length": "zero_context", "d": 2}
+{"problem": "The number of adult deer in South Zoo equals 1. The number of adult bear in South Zoo equals the sum of the total number of adult animals in Mayer Aquarium, the number of adult deer in Mayer Aquarium, and the number of adult bear in Mayer Aquarium. The number of adult deer in Mayer Aquarium equals 3. The number of adult bear in Mayer Aquarium equals the number of adult deer in Mayer Aquarium. ", "question": "What is the total number of adult animals in South Zoo?", "solution": "Define adult deer in Mayer Aquarium as l; so l = 3. Define adult bear in Mayer Aquarium as a; so a = l = 3. Define total number of adult animals in Mayer Aquarium as I; so I = l + a = 3 + 3 = 6. Define adult deer in South Zoo as h; so h = 1. Define adult bear in South Zoo as t; B = I + l = 6 + 3 = 9; so t = B + a = 9 + 3 = 12. Define total number of adult animals in South Zoo as E; so E = h + t = 1 + 12 = 13. Answer: 13.", "op": 10, "id": "7_p2", "template": "crazy_zootopia", "mode": "normalforward", "length": "zero_context", "d": 2}
+{"problem": "The number of calm road movie in Festival de Clairmont equals 4. The number of intense detective thriller in Festival Lumi\u00e8re de Valmont equals 4. The number of upbeat metropolis comedy in Festival de Saint-Rivage equals the difference between the number of calm road movie in Festival Lumi\u00e8re de Valmont and the total number of movies in Festival de Clairmont. The number of futuristic sci-fi movie in R\u00eaves de Belleville exists, and its number is greater than 0. The number of upbeat metropolis comedy in Festival de Clairmont equals 2 plus the number of intense detective thriller in Festival Lumi\u00e8re de Valmont. The total number of movies in R\u00eaves de Belleville equals 13. The number of intense detective thriller in R\u00eaves de Belleville equals 2. The number of calm road movie in R\u00eaves de Belleville equals 2. The number of futuristic sci-fi movie in R\u00eaves de Belleville exists, and its number is greater than 0. The number of calm road movie in Festival Lumi\u00e8re de Valmont equals the total number of movies in R\u00eaves de Belleville. The number of upbeat metropolis comedy in R\u00eaves de Belleville equals 2 times the sum of the number of calm road movie in R\u00eaves de Belleville and the number of intense detective thriller in R\u00eaves de Belleville. The number of intense detective thriller in Festival de Saint-Rivage equals 2. The number of intense detective thriller in Festival de Clairmont equals 1. The number of futuristic sci-fi movie in Festival de Saint-Rivage equals the number of calm road movie in R\u00eaves de Belleville. ", "question": "How many futuristic sci-fi movie does R\u00eaves de Belleville have?", "solution": "The question is difficult, so we use equations to solve it. Define intense detective thriller in R\u00eaves de Belleville as J; so J = 2. Define calm road movie in R\u00eaves de Belleville as l; so l = 2. Define futuristic sci-fi movie in R\u00eaves de Belleville as x; we don't know its value yet but will find it out later. Define upbeat metropolis comedy in R\u00eaves de Belleville as h; y = l + J = 2 + 2 = 4; so h = 2 * y = (2) * (4) = 8. Define total number of movies in R\u00eaves de Belleville as D; a = l + J = 2 + 2 = 4; i = a + x = 4 + x = x + 4; so D = i + h = x + 4 + 8 = x + 12. We know D = 13, so we have x + 12 = 13 and we solve it through the following steps: Simplifying the equation: x + 12 = 13. Move all terms to one side: x - 1 = 0. Isolate the term with x: 1*x = 1. Divide both sides by 1: x = 1 / 1. Solution: x = 1. Answer: 1.", "op": 10, "id": "3_p2", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
+{"problem": "The number of adult wolf in Beverly Forest equals 2. The number of adult deer in Beverly Forest equals 3. The number of adult deer in Cedar Valley equals the total number of adult animals in Beverly Forest. The number of adult wolf in Cedar Valley equals the sum of the total number of adult animals in Beverly Forest, the number of adult wolf in Beverly Forest, and the number of adult deer in Beverly Forest. ", "question": "What is the total number of adult animals in Cedar Valley?", "solution": "Define adult wolf in Beverly Forest as E; so E = 2. Define adult deer in Beverly Forest as T; so T = 3. Define total number of adult animals in Beverly Forest as P; so P = T + E = 3 + 2 = 5. Define adult deer in Cedar Valley as V; so V = P = 5. Define adult wolf in Cedar Valley as D; m = P + E = 5 + 2 = 7; so D = m + T = 7 + 3 = 10. Define total number of adult animals in Cedar Valley as B; so B = V + D = 5 + 10 = 15. Answer: 15.", "op": 10, "id": "19_p2", "template": "crazy_zootopia", "mode": "normalforward", "length": "zero_context", "d": 2}
+{"problem": "The number of adult owl in Jefferson Circus exists, and its number is greater than 0. The number of adult crow in Jefferson Circus equals the number of adult owl in Jefferson Circus. The number of adult owl in Jefferson Circus exists, and its number is greater than 0. The number of adult owl in South Zoo equals the total number of adult animals in Jefferson Circus. The total number of adult animals in South Zoo equals 24. ", "question": "How many adult owl does Jefferson Circus have?", "solution": "The question is difficult, so we use equations to solve it. Define adult owl in Jefferson Circus as x; we don't know its value yet but will find it out later. Define adult crow in Jefferson Circus as B; so B = x = x. Define total number of adult animals in Jefferson Circus as f; so f = x + B = x + x = 2*x. Define adult owl in South Zoo as r; so r = f = 2*x. Define adult crow in South Zoo as J; u = B + x = x + x = 2*x; so J = u + f = 2*x + 2*x = 4*x. Define total number of adult animals in South Zoo as L; so L = r + J = 2*x + 4*x = 6*x. We know L = 24, so we have 6*x = 24 and we solve it through the following steps: Simplifying the equation: 6*x = 24. Move all terms to one side: 6*x - 24 = 0. Isolate the term with x: 6*x = 24. Divide both sides by 6: x = 24 / 6. Solution: x = 4. Answer: 4.", "op": 10, "id": "5_p2", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
+{"problem": "The number of adult deer in Jefferson Circus equals the sum of the total number of adult animals in Bundle Ranch, the number of adult fox in Bundle Ranch, and the number of adult deer in Bundle Ranch. The number of adult fox in Bundle Ranch equals 1. The number of adult deer in Bundle Ranch exists, and its number is greater than 0. The total number of adult animals in Jefferson Circus equals 6. The number of adult fox in Jefferson Circus equals the total number of adult animals in Bundle Ranch. ", "question": "How many adult deer does Bundle Ranch have?", "solution": "The question is difficult, so we use equations to solve it. Define adult fox in Bundle Ranch as t; so t = 1. Define adult deer in Bundle Ranch as x; we don't know its value yet but will find it out later. Define total number of adult animals in Bundle Ranch as W; so W = t + x = 1 + x = x + 1. Define adult fox in Jefferson Circus as s; so s = W = x + 1. Define adult deer in Jefferson Circus as Z; Q = W + t = x + 1 + 1 = x + 2; so Z = Q + x = x + 2 + x = 2*x + 2. Define total number of adult animals in Jefferson Circus as r; so r = s + Z = x + 1 + 2*x + 2 = 3*x + 3. We know r = 6, so we have 3*x + 3 = 6 and we solve it through the following steps: Simplifying the equation: 3*x + 3 = 6. Move all terms to one side: 3*x - 3 = 0. Isolate the term with x: 3*x = 3. Divide both sides by 3: x = 3 / 3. Solution: x = 1. Answer: 1.", "op": 10, "id": "9_p2", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
+{"problem": "The number of solemn period drama in Festival Lumi\u00e8re de Valmont equals the number of calm road movie in Festival Lumi\u00e8re de Valmont. The number of calm road movie in Festival de Saint-Rivage exists, and its number is greater than 0. The total number of movies in Festival de Saint-Rivage equals 15. The number of calm road movie in Festival Lumi\u00e8re de Valmont equals 3. The number of solemn period drama in Festival de Saint-Rivage equals the sum of the total number of movies in Festival Lumi\u00e8re de Valmont, the number of solemn period drama in Festival Lumi\u00e8re de Valmont, and the number of calm road movie in Festival Lumi\u00e8re de Valmont. ", "question": "How many calm road movie does Festival de Saint-Rivage have?", "solution": "The question is difficult, so we use equations to solve it. Define calm road movie in Festival Lumi\u00e8re de Valmont as v; so v = 3. Define solemn period drama in Festival Lumi\u00e8re de Valmont as m; so m = v = 3. Define total number of movies in Festival Lumi\u00e8re de Valmont as h; so h = v + m = 3 + 3 = 6. Define calm road movie in Festival de Saint-Rivage as x; we don't know its value yet but will find it out later. Define solemn period drama in Festival de Saint-Rivage as Z; i = h + m = 6 + 3 = 9; so Z = i + v = 9 + 3 = 12. Define total number of movies in Festival de Saint-Rivage as l; so l = x + Z = x + 12 = x + 12. We know l = 15, so we have x + 12 = 15 and we solve it through the following steps: Simplifying the equation: x + 12 = 15. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3.", "op": 10, "id": "10_p2", "template": "movie_festival_awards", "mode": "forwardreverse", "length": "zero_context", "d": 2}
+{"problem": "The number of futuristic sci-fi movie in Verdi Movie Festival equals 4. The number of intense detective thriller in West Sahara Movie Festival equals the sum of the total number of movies in Verdi Movie Festival, the number of intense detective thriller in Verdi Movie Festival, and the number of futuristic sci-fi movie in Verdi Movie Festival. The number of intense detective thriller in Verdi Movie Festival equals the number of futuristic sci-fi movie in Verdi Movie Festival. The number of futuristic sci-fi movie in West Sahara Movie Festival equals 3. ", "question": "What is the total number of movies in West Sahara Movie Festival?", "solution": "Define futuristic sci-fi movie in Verdi Movie Festival as s; so s = 4. Define intense detective thriller in Verdi Movie Festival as y; so y = s = 4. Define total number of movies in Verdi Movie Festival as Y; so Y = y + s = 4 + 4 = 8. Define futuristic sci-fi movie in West Sahara Movie Festival as c; so c = 3. Define intense detective thriller in West Sahara Movie Festival as N; u = Y + y = 8 + 4 = 12; so N = u + s = 12 + 4 = 16. Define total number of movies in West Sahara Movie Festival as A; so A = N + c = 16 + 3 = 19. Answer: 19.", "op": 10, "id": "1_p2", "template": "movie_festival_awards", "mode": "normalforward", "length": "zero_context", "d": 2}
+{"problem": "The number of calm road movie in Taylor Movie Festival equals 3. The number of intense detective thriller in Taylor Movie Festival equals the number of calm road movie in Taylor Movie Festival. The number of calm road movie in West Sahara Movie Festival equals 3 times the sum of the number of calm road movie in Taylor Movie Festival and the total number of movies in Taylor Movie Festival. The number of intense detective thriller in West Sahara Movie Festival equals the total number of movies in Taylor Movie Festival. ", "question": "What is the total number of movies in West Sahara Movie Festival?", "solution": "Define calm road movie in Taylor Movie Festival as l; so l = 3. Define intense detective thriller in Taylor Movie Festival as H; so H = l = 3. Define total number of movies in Taylor Movie Festival as F; so F = H + l = 3 + 3 = 6. Define intense detective thriller in West Sahara Movie Festival as x; so x = F = 6. Define calm road movie in West Sahara Movie Festival as X; e = l + F = 3 + 6 = 9; so X = 3 * e = 3 * 9 = 27. Define total number of movies in West Sahara Movie Festival as Y; so Y = x + X = 6 + 27 = 33. Answer: 33.", "op": 10, "id": "13_p2", "template": "movie_festival_awards", "mode": "normalforward", "length": "zero_context", "d": 2}
+{"problem": "The number of adult bear in Bundle Ranch equals 3. The number of adult racoon in South Zoo equals 4. The number of adult bear in South Zoo equals the number of adult racoon in South Zoo. The number of adult racoon in Bundle Ranch equals 2 times the difference between the total number of adult animals in South Zoo and the number of adult racoon in South Zoo. ", "question": "What is the total number of adult animals in Bundle Ranch?", "solution": "Define adult racoon in South Zoo as T; so T = 4. Define adult bear in South Zoo as f; so f = T = 4. Define total number of adult animals in South Zoo as b; so b = T + f = 4 + 4 = 8. Define adult bear in Bundle Ranch as S; so S = 3. Define adult racoon in Bundle Ranch as U; I = b - T = 8 - 4 = 4; so U = 2 * I = 2 * 4 = 8. Define total number of adult animals in Bundle Ranch as Q; so Q = U + S = 8 + 3 = 11. Answer: 11.", "op": 10, "id": "4_p2", "template": "crazy_zootopia", "mode": "normalforward", "length": "zero_context", "d": 2}
+{"problem": "The number of elementary school in Clearwater Bay equals the total number of schools in Riverton City. The number of regional medical school in Riverton City equals the total number of schools in Oakbridge City. The number of private middle school in Oakbridge City equals 2. The number of elementary school in Riverton City equals 2 plus the sum of the number of private middle school in Oakbridge City and the total number of schools in Oakbridge City. ", "question": "What is the total number of schools in Clearwater Bay?", "solution": "Define private middle school in Oakbridge City as y; so y = 2. Define total number of schools in Oakbridge City as e; so e = y = 2. Define regional medical school in Riverton City as U; so U = e = 2. Define elementary school in Riverton City as z; G = y + e = 2 + 2 = 4; so z = 2 + G = 2 + 4 = 6. Define total number of schools in Riverton City as Z; so Z = U + z = 2 + 6 = 8. Define elementary school in Clearwater Bay as C; so C = Z = 8. Define total number of schools in Clearwater Bay as v; so v = C = 8. Answer: 8.", "op": 10, "id": "0_p2", "template": "teachers_in_school", "mode": "normalforward", "length": "zero_context", "d": 2}
+{"problem": "The number of adult wolf in Jefferson Circus equals the difference between the total number of adult animals in Bundle Ranch and the number of adult wolf in Bundle Ranch. The number of adult wolf in Bundle Ranch exists, and its number is greater than 0. The total number of adult animals in Jefferson Circus equals 3. The number of adult bear in Bundle Ranch equals the number of adult wolf in Bundle Ranch. The number of adult bear in Jefferson Circus equals the sum of the number of adult bear in Bundle Ranch and the number of adult wolf in Bundle Ranch. ", "question": "How many adult wolf does Bundle Ranch have?", "solution": "The question is difficult, so we use equations to solve it. Define adult wolf in Bundle Ranch as x; we don't know its value yet but will find it out later. Define adult bear in Bundle Ranch as y; so y = x = x. Define total number of adult animals in Bundle Ranch as d; so d = x + y = x + x = 2*x. Define adult bear in Jefferson Circus as T; so T = y + x = x + x = 2*x. Define adult wolf in Jefferson Circus as A; so A = d - x = (2*x) - (x) = x. Define total number of adult animals in Jefferson Circus as M; so M = A + T = x + 2*x = 3*x. We know M = 3, so we have 3*x = 3 and we solve it through the following steps: Simplifying the equation: 3*x = 3. Move all terms to one side: 3*x - 3 = 0. Isolate the term with x: 3*x = 3. Divide both sides by 3: x = 3 / 3. Solution: x = 1. Answer: 1.", "op": 10, "id": "21_p2", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
+{"problem": "The number of adult crow in South Zoo equals the number of adult crow in Mayer Aquarium. The total number of adult animals in South Zoo equals 15. The number of adult crow in Mayer Aquarium exists, and its number is greater than 0. The number of adult crow in Mayer Aquarium exists, and its number is greater than 0. The number of adult blue jay in Mayer Aquarium equals the number of adult crow in Mayer Aquarium. ", "question": "How many adult crow does Mayer Aquarium have?", "solution": "The question is difficult, so we use equations to solve it. Define adult crow in Mayer Aquarium as x; we don't know its value yet but will find it out later. Define adult blue jay in Mayer Aquarium as a; so a = x = x. Define total number of adult animals in Mayer Aquarium as w; so w = a + x = x + x = 2*x. Define adult crow in South Zoo as m; so m = x = x. Define adult blue jay in South Zoo as W; I = w + x = 2*x + x = 3*x; so W = I + a = 3*x + x = 4*x. Define total number of adult animals in South Zoo as p; so p = m + W = x + 4*x = 5*x. We know p = 15, so we have 5*x = 15 and we solve it through the following steps: Simplifying the equation: 5*x = 15. Move all terms to one side: 5*x - 15 = 0. Isolate the term with x: 5*x = 15. Divide both sides by 5: x = 15 / 5. Solution: x = 3. Answer: 3.", "op": 10, "id": "13_p2", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
+{"problem": "The number of adult fox in South Zoo equals the number of adult wolf in Jefferson Circus. The number of adult bear in Hamilton Farm equals 4 times the number of adult bear in Jefferson Circus. The number of adult wolf in South Zoo equals 3. The number of adult wolf in Hamilton Farm equals the number of adult bear in Jefferson Circus. The number of adult wolf in Jefferson Circus equals 2 times the number of adult wolf in South Zoo. The number of adult bear in South Zoo equals the sum of the total number of adult animals in Jefferson Circus, the number of adult bear in Hamilton Farm, and the number of adult fox in Hamilton Farm. The total number of adult animals in Hamilton Farm equals 52. The number of adult fox in Hamilton Farm equals 4 times the sum of the number of adult bear in Jefferson Circus and the number of adult wolf in Hamilton Farm. The number of adult bear in Jefferson Circus exists, and its number is greater than 0. ", "question": "How many adult bear does Jefferson Circus have?", "solution": "The question is difficult, so we use equations to solve it. Define adult bear in Jefferson Circus as x; we don't know its value yet but will find it out later. Define adult wolf in Hamilton Farm as D; so D = x = x. Define adult bear in Hamilton Farm as C; q = x = x; so C = 4 * q = (4) * (x) = 4*x. Define adult fox in Hamilton Farm as V; a = x + D = x + x = 2*x; so V = 4 * a = (4) * (2*x) = 8*x. Define total number of adult animals in Hamilton Farm as t; s = V + C = 8*x + 4*x = 12*x; so t = s + D = 12*x + x = 13*x. We know t = 52, so we have 13*x = 52 and we solve it through the following steps: Simplifying the equation: 13*x = 52. Move all terms to one side: 13*x - 52 = 0. Isolate the term with x: 13*x = 52. Divide both sides by 13: x = 52 / 13. Solution: x = 4. Answer: 4.", "op": 10, "id": "21_p2", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}
+{"problem": "The number of intense detective thriller in Golden Banana Movie Festival equals the number of intense detective thriller in Taylor Movie Festival. The number of upbeat metropolis comedy in Verdi Movie Festival equals 1 plus the sum of the number of futuristic sci-fi movie in Golden Banana Movie Festival and the total number of movies in Taylor Movie Festival. The number of upbeat metropolis comedy in West Sahara Movie Festival equals 2 times the sum of the number of intense detective thriller in Verdi Movie Festival, the number of calm road movie in Verdi Movie Festival, and the number of intense detective thriller in West Sahara Movie Festival. The number of upbeat metropolis comedy in Taylor Movie Festival equals 2. The number of futuristic sci-fi movie in Golden Banana Movie Festival equals 2 times the number of calm road movie in Golden Banana Movie Festival. The number of futuristic sci-fi movie in Verdi Movie Festival equals 4 times the number of calm road movie in West Sahara Movie Festival. The number of intense detective thriller in West Sahara Movie Festival equals 4 times the number of intense detective thriller in Verdi Movie Festival. The number of futuristic sci-fi movie in West Sahara Movie Festival equals 2 plus the number of calm road movie in Taylor Movie Festival. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals the number of intense detective thriller in Taylor Movie Festival. The number of calm road movie in Golden Banana Movie Festival equals 2. The number of calm road movie in West Sahara Movie Festival equals 2 plus the number of upbeat metropolis comedy in West Sahara Movie Festival. The number of intense detective thriller in Verdi Movie Festival equals 3. The number of futuristic sci-fi movie in Taylor Movie Festival equals 1. The number of calm road movie in Verdi Movie Festival equals the number of intense detective thriller in Verdi Movie Festival. The number of calm road movie in Taylor Movie Festival equals 2. The number of intense detective thriller in Taylor Movie Festival equals the number of calm road movie in Golden Banana Movie Festival. ", "question": "What is the total number of movies in Golden Banana Movie Festival?", "solution": "Define calm road movie in Golden Banana Movie Festival as A; so A = 2. Define intense detective thriller in Taylor Movie Festival as q; so q = A = 2. Define upbeat metropolis comedy in Golden Banana Movie Festival as C; so C = q = 2. Define intense detective thriller in Golden Banana Movie Festival as c; so c = q = 2. Define futuristic sci-fi movie in Golden Banana Movie Festival as j; n = A = 2; so j = 2 * n = 2 * 2 = 4. Define total number of movies in Golden Banana Movie Festival as b; T = A + c = 2 + 2 = 4; R = T + j = 4 + 4 = 8; so b = R + C = 8 + 2 = 10. Answer: 10.", "op": 10, "id": "21_p2", "template": "movie_festival_awards", "mode": "normalforward", "length": "zero_context", "d": 2}
+{"problem": "The number of adult wolf in Cedar Valley equals the number of adult racoon in Cedar Valley. The number of adult racoon in Pine Ridge equals the number of adult wolf in Cedar Valley. The total number of adult animals in Pine Ridge equals 20. The number of adult racoon in Cedar Valley exists, and its number is greater than 0. The number of adult racoon in Cedar Valley exists, and its number is greater than 0. ", "question": "How many adult racoon does Cedar Valley have?", "solution": "The question is difficult, so we use equations to solve it. Define adult racoon in Cedar Valley as x; we don't know its value yet but will find it out later. Define adult wolf in Cedar Valley as k; so k = x = x. Define total number of adult animals in Cedar Valley as U; so U = x + k = x + x = 2*x. Define adult racoon in Pine Ridge as B; so B = k = x. Define adult wolf in Pine Ridge as J; C = U + x = 2*x + x = 3*x; so J = C + k = 3*x + x = 4*x. Define total number of adult animals in Pine Ridge as E; so E = B + J = x + 4*x = 5*x. We know E = 20, so we have 5*x = 20 and we solve it through the following steps: Simplifying the equation: 5*x = 20. Move all terms to one side: 5*x - 20 = 0. Isolate the term with x: 5*x = 20. Divide both sides by 5: x = 20 / 5. Solution: x = 4. Answer: 4.", "op": 10, "id": "7_p2", "template": "crazy_zootopia", "mode": "forwardreverse", "length": "zero_context", "d": 2}