The number of private middle school in Brightford exists, and its number is greater than 0. The number of private middle school in Brightford exists, and its number is greater than 0. The total number of schools in Glenfield City equals 64. The number of culinarian school in Brightford equals 3 times the number of private middle school in Brightford.

Question: How many private middle school does Brightford have?

Solution: The question is difficult, so we use equations to solve it. Define private middle school in Brightford as x; we don't know its value yet but will find it out later. Define culinarian school in Brightford as r; G = x = x; so r = 3 * G = (3) * (x) = 3*x. Define total number of schools in Brightford as l; so l = x + r = x + 3*x = 4*x. Define elementary school in Glenfield City as w; W = l + x = 4*x + x = 5*x; c = W + r = 5*x + 3*x = 8*x; so w = 4 * c = (4) * (8*x) = 32*x. Define total number of schools in Glenfield City as b; so b = w = 32*x. We know b = 64, so we have 32*x = 64 and we solve it through the following steps: Simplifying the equation: 32*x = 64. Move all terms to one side: 32*x - 64 = 0. Isolate the term with x: 32*x = 64. Divide both sides by 32: x = 64 / 32. Solution: x = 2. Answer: 2.


The number of adult racoon in Bundle Ranch equals 2 times the number of adult deer in Jefferson Circus. The number of adult wolf in South Zoo equals 3. The number of adult deer in Bundle Ranch equals the number of adult deer in Jefferson Circus. The number of adult fox in Mayer Aquarium equals the number of adult wolf in South Zoo. The number of adult racoon in South Zoo equals 4. The number of adult deer in Jefferson Circus equals 3. The number of adult racoon in Jefferson Circus equals 2 plus the number of adult wolf in South Zoo. The number of adult wolf in Mayer Aquarium equals the sum of the number of adult fox in Mayer Aquarium, the number of adult racoon in Jefferson Circus, the number of adult wolf in South Zoo, and the number of adult deer in South Zoo. The number of adult racoon in Mayer Aquarium equals the number of adult deer in South Zoo. The number of adult deer in South Zoo equals the difference between the number of adult wolf in South Zoo and the number of adult fox in Mayer Aquarium. The number of adult wolf in Bundle Ranch equals the number of adult fox in Bundle Ranch. The number of adult fox in Bundle Ranch equals the number of adult deer in Bundle Ranch. The number of adult fox in Jefferson Circus equals 2 times the sum of the number of adult fox in Bundle Ranch, the number of adult wolf in South Zoo, and the total number of adult animals in Bundle Ranch. The number of adult wolf in Jefferson Circus equals 1 plus the difference between the number of adult deer in Bundle Ranch and the total number of adult animals in South Zoo.

Question: What is the total number of adult animals in Bundle Ranch?

Solution: Define adult deer in Jefferson Circus as C; so C = 3. Define adult racoon in Bundle Ranch as H; j = C = 3; so H = 2 * j = 2 * 3 = 6. Define adult deer in Bundle Ranch as L; so L = C = 3. Define adult fox in Bundle Ranch as N; so N = L = 3. Define adult wolf in Bundle Ranch as h; so h = N = 3. Define total number of adult animals in Bundle Ranch as w; l = h + L = 3 + 3 = 6; b = l + N = 6 + 3 = 9; so w = b + H = 9 + 6 = 15. Answer: 15.


The number of adult crow in Beverly Forest equals 4. The number of adult crow in Maple Creek equals the number of adult parrot in Cedar Valley. The number of adult parrot in Pine Ridge equals 2. The number of adult crow in Pine Ridge equals the total number of adult animals in Beverly Forest. The number of adult parrot in Maple Creek exists, and its number is greater than 0. The number of adult parrot in Cedar Valley equals 2. The number of adult eagle in Pine Ridge equals 4 times the total number of adult animals in Beverly Forest. The number of adult eagle in Cedar Valley equals the sum of the number of adult blue jay in Maple Creek, the number of adult crow in Beverly Forest, and the number of adult parrot in Cedar Valley. The total number of adult animals in Beverly Forest equals 10. The number of adult eagle in Maple Creek equals 3 plus the sum of the number of adult parrot in Beverly Forest, the number of adult parrot in Cedar Valley, and the total number of adult animals in Beverly Forest. The number of adult parrot in Beverly Forest equals 2 times the number of adult crow in Maple Creek. The number of adult blue jay in Pine Ridge equals the sum of the number of adult crow in Pine Ridge, the number of adult crow in Maple Creek, and the number of adult parrot in Cedar Valley. The number of adult blue jay in Maple Creek equals 4. The number of adult blue jay in Cedar Valley equals 2. The number of adult crow in Cedar Valley equals the sum of the total number of adult animals in Maple Creek and the number of adult eagle in Cedar Valley. The number of adult eagle in Beverly Forest equals the number of adult parrot in Maple Creek.

Question: How many adult parrot does Maple Creek have?

Solution: The question is difficult, so we use equations to solve it. Define adult parrot in Cedar Valley as V; so V = 2. Define adult crow in Maple Creek as p; so p = V = 2. Define adult parrot in Beverly Forest as I; Y = p = 2; so I = 2 * Y = (2) * (2) = 4. Define adult crow in Beverly Forest as L; so L = 4. Define adult parrot in Maple Creek as x; we don't know its value yet but will find it out later. Define adult eagle in Beverly Forest as a; so a = x = x. Define total number of adult animals in Beverly Forest as B; y = L + a = 4 + x = x + 4; so B = y + I = x + 4 + 4 = x + 8. We know B = 10, so we have x + 8 = 10 and we solve it through the following steps: Simplifying the equation: x + 8 = 10. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2.


The number of private middle school in Shoreline City equals the total number of schools in Riverton City. The number of culinarian school in Shoreline City equals 4 times the sum of the number of private middle school in Riverton City and the number of private middle school in Shoreline City. The number of culinarian school in Riverton City equals the number of private middle school in Riverton City. The number of private middle school in Riverton City equals 4.

Question: What is the total number of schools in Shoreline City?

Solution: Define private middle school in Riverton City as K; so K = 4. Define culinarian school in Riverton City as S; so S = K = 4. Define total number of schools in Riverton City as t; so t = K + S = 4 + 4 = 8. Define private middle school in Shoreline City as v; so v = t = 8. Define culinarian school in Shoreline City as o; Y = K + v = 4 + 8 = 12; so o = 4 * Y = 4 * 12 = 48. Define total number of schools in Shoreline City as s; so s = v + o = 8 + 48 = 56. Answer: 56.


The number of solemn period drama in West Sahara Movie Festival exists, and its number is greater than 0. The number of solemn period drama in Golden Banana Movie Festival equals 3. The number of upbeat metropolis comedy in West Sahara Movie Festival equals 2 times the number of calm road movie in West Sahara Movie Festival. The total number of movies in West Sahara Movie Festival equals 16. The number of futuristic sci-fi movie in Golden Banana Movie Festival equals 4. The number of intense detective thriller in Verdi Movie Festival equals 1. The number of futuristic sci-fi movie in Northwood Movie Festival equals 1. The number of calm road movie in Golden Banana Movie Festival equals 3 times the number of solemn period drama in Golden Banana Movie Festival. The number of calm road movie in Verdi Movie Festival equals the sum of the number of upbeat metropolis comedy in West Sahara Movie Festival, the number of intense detective thriller in West Sahara Movie Festival, and the number of calm road movie in Northwood Movie Festival. The number of upbeat metropolis comedy in Taylor Movie Festival equals 4. The number of calm road movie in Northwood Movie Festival equals 4. The number of upbeat metropolis comedy in Northwood Movie Festival equals 2. The number of solemn period drama in Taylor Movie Festival equals 4 times the number of solemn period drama in Golden Banana Movie Festival. The number of calm road movie in West Sahara Movie Festival equals 2. The number of intense detective thriller in West Sahara Movie Festival equals 3 times the number of calm road movie in West Sahara Movie Festival. The number of intense detective thriller in Northwood Movie Festival equals 2. The number of calm road movie in Taylor Movie Festival equals the sum of the number of solemn period drama in West Sahara Movie Festival, the number of upbeat metropolis comedy in Verdi Movie Festival, the number of intense detective thriller in West Sahara Movie Festival, and the number of solemn period drama in Golden Banana Movie Festival. The number of futuristic sci-fi movie in Verdi Movie Festival equals the difference between the number of futuristic sci-fi movie in Northwood Movie Festival and the number of upbeat metropolis comedy in West Sahara Movie Festival. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals 2 times the difference between the total number of movies in Northwood Movie Festival and the number of calm road movie in Northwood Movie Festival. The number of upbeat metropolis comedy in Verdi Movie Festival equals the number of solemn period drama in Golden Banana Movie Festival.

Question: How many solemn period drama does West Sahara Movie Festival have?

Solution: The question is difficult, so we use equations to solve it. Define calm road movie in West Sahara Movie Festival as z; so z = 2. Define upbeat metropolis comedy in West Sahara Movie Festival as E; Y = z = 2; so E = 2 * Y = (2) * (2) = 4. Define intense detective thriller in West Sahara Movie Festival as O; q = z = 2; so O = 3 * q = (3) * (2) = 6. Define solemn period drama in West Sahara Movie Festival as x; we don't know its value yet but will find it out later. Define total number of movies in West Sahara Movie Festival as r; N = x + E = x + 4 = x + 4; i = N + z = x + 4 + 2 = x + 6; so r = i + O = x + 6 + 6 = x + 12. We know r = 16, so we have x + 12 = 16 and we solve it through the following steps: Simplifying the equation: x + 12 = 16. Move all terms to one side: x - 4 = 0. Isolate the term with x: 1*x = 4. Divide both sides by 1: x = 4 / 1. Solution: x = 4. Answer: 4.


The number of elementary school in Westhaven City equals the number of regional medical school in Hawkesbury. The number of elementary school in Brightford equals the number of public highschool in Brightford. The number of private middle school in Westhaven City equals 2 plus the sum of the number of elementary school in Glenfield City, the number of regional medical school in Westhaven City, and the number of public highschool in Hawkesbury. The number of regional medical school in Hawkesbury equals 3. The number of regional medical school in Glenfield City equals the sum of the number of public highschool in Glenfield City, the number of private middle school in Evervale City, the number of elementary school in Glenfield City, and the number of elementary school in Hawkesbury. The number of public highschool in Westhaven City equals 3 times the sum of the number of public highschool in Brightford and the number of private middle school in Brightford. The number of regional medical school in Westhaven City equals 4. The number of public highschool in Glenfield City equals 4 times the sum of the number of elementary school in Hawkesbury and the number of private middle school in Evervale City. The number of public highschool in Brightford equals 1 plus the sum of the number of regional medical school in Brightford and the number of private middle school in Brightford. The number of public highschool in Evervale City equals 2. The number of regional medical school in Brightford equals 3. The number of public highschool in Hawkesbury equals the number of private middle school in Evervale City. The number of private middle school in Brightford equals the number of regional medical school in Brightford. The number of private middle school in Evervale City equals 3 times the number of elementary school in Glenfield City. The number of regional medical school in Evervale City equals the number of public highschool in Westhaven City. The number of elementary school in Hawkesbury equals 4 plus the number of elementary school in Glenfield City. The number of private middle school in Hawkesbury equals 3. The number of elementary school in Glenfield City equals 3 times the number of regional medical school in Westhaven City.

Question: What is the total number of schools in Brightford?

Solution: Define regional medical school in Brightford as D; so D = 3. Define private middle school in Brightford as z; so z = D = 3. Define public highschool in Brightford as o; P = D + z = 3 + 3 = 6; so o = 1 + P = 1 + 6 = 7. Define elementary school in Brightford as F; so F = o = 7. Define total number of schools in Brightford as Z; b = o + D = 7 + 3 = 10; e = b + F = 10 + 7 = 17; so Z = e + z = 17 + 3 = 20. Answer: 20.


The number of adult owl in Hamilton Farm equals 4. The number of adult owl in Bundle Ranch equals the sum of the total number of adult animals in Hamilton Farm, the number of adult owl in Hamilton Farm, and the number of adult parrot in Hamilton Farm. The number of adult parrot in Hamilton Farm equals the number of adult owl in Hamilton Farm. The number of adult parrot in Bundle Ranch exists, and its number is greater than 0. The total number of adult animals in Bundle Ranch equals 17.

Question: How many adult parrot does Bundle Ranch have?

Solution: The question is difficult, so we use equations to solve it. Define adult owl in Hamilton Farm as e; so e = 4. Define adult parrot in Hamilton Farm as R; so R = e = 4. Define total number of adult animals in Hamilton Farm as p; so p = R + e = 4 + 4 = 8. Define adult owl in Bundle Ranch as f; E = p + e = 8 + 4 = 12; so f = E + R = 12 + 4 = 16. Define adult parrot in Bundle Ranch as x; we don't know its value yet but will find it out later. Define total number of adult animals in Bundle Ranch as c; so c = x + f = x + 16 = x + 16. We know c = 17, so we have x + 16 = 17 and we solve it through the following steps: Simplifying the equation: x + 16 = 17. Move all terms to one side: x - 1 = 0. Isolate the term with x: 1*x = 1. Divide both sides by 1: x = 1 / 1. Solution: x = 1. Answer: 1.


The total number of adult animals in South Zoo equals 13. The number of adult fox in Hamilton Farm exists, and its number is greater than 0. The number of adult fox in South Zoo equals the number of adult fox in Hamilton Farm. The number of adult deer in Hamilton Farm equals the number of adult fox in Hamilton Farm. The number of adult deer in South Zoo equals 4 times the sum of the total number of adult animals in Hamilton Farm and the number of adult fox in Hamilton Farm.

Question: How many adult fox does Hamilton Farm have?

Solution: The question is difficult, so we use equations to solve it. Define adult fox in Hamilton Farm as x; we don't know its value yet but will find it out later. Define adult deer in Hamilton Farm as i; so i = x = x. Define total number of adult animals in Hamilton Farm as s; so s = i + x = x + x = 2*x. Define adult deer in South Zoo as E; z = s + x = 2*x + x = 3*x; so E = 4 * z = (4) * (3*x) = 12*x. Define adult fox in South Zoo as k; so k = x = x. Define total number of adult animals in South Zoo as d; so d = E + k = 12*x + x = 13*x. We know d = 13, so we have 13*x = 13 and we solve it through the following steps: Simplifying the equation: 13*x = 13. Move all terms to one side: 13*x - 13 = 0. Isolate the term with x: 13*x = 13. Divide both sides by 13: x = 13 / 13. Solution: x = 1. Answer: 1.


The number of public highschool in Oakbridge City equals the number of elementary school in Oakbridge City. The number of elementary school in Ruby Bay equals the number of public highschool in Ruby Bay. The total number of schools in Oakbridge City equals 48. The number of elementary school in Oakbridge City equals 4 times the sum of the total number of schools in Ruby Bay and the number of public highschool in Ruby Bay. The number of public highschool in Ruby Bay exists, and its number is greater than 0.

Question: How many public highschool does Ruby Bay have?

Solution: The question is difficult, so we use equations to solve it. Define public highschool in Ruby Bay as x; we don't know its value yet but will find it out later. Define elementary school in Ruby Bay as V; so V = x = x. Define total number of schools in Ruby Bay as f; so f = V + x = x + x = 2*x. Define elementary school in Oakbridge City as u; S = f + x = 2*x + x = 3*x; so u = 4 * S = (4) * (3*x) = 12*x. Define public highschool in Oakbridge City as v; so v = u = 12*x. Define total number of schools in Oakbridge City as D; so D = v + u = 12*x + 12*x = 24*x. We know D = 48, so we have 24*x = 48 and we solve it through the following steps: Simplifying the equation: 24*x = 48. Move all terms to one side: 24*x - 48 = 0. Isolate the term with x: 24*x = 48. Divide both sides by 24: x = 48 / 24. Solution: x = 2. Answer: 2.


The number of adult fox in Beverly Forest equals the total number of adult animals in Oakridge Riverside. The number of adult deer in Oakridge Riverside equals the number of adult fox in Oakridge Riverside. The number of adult fox in Oakridge Riverside equals 1. The number of adult deer in Beverly Forest equals the sum of the number of adult fox in Oakridge Riverside, the total number of adult animals in Oakridge Riverside, and the number of adult deer in Oakridge Riverside.

Question: What is the total number of adult animals in Beverly Forest?

Solution: Define adult fox in Oakridge Riverside as X; so X = 1. Define adult deer in Oakridge Riverside as C; so C = X = 1. Define total number of adult animals in Oakridge Riverside as c; so c = C + X = 1 + 1 = 2. Define adult fox in Beverly Forest as v; so v = c = 2. Define adult deer in Beverly Forest as e; w = X + c = 1 + 2 = 3; so e = w + C = 3 + 1 = 4. Define total number of adult animals in Beverly Forest as a; so a = e + v = 4 + 2 = 6. Answer: 6.


The number of adult bear in Jefferson Circus equals 2. The number of adult bear in Bundle Ranch exists, and its number is greater than 0. The number of adult fox in Bundle Ranch equals the number of adult bear in Bundle Ranch. The number of adult fox in Mayer Aquarium equals 4 times the number of adult fox in Bundle Ranch. The total number of adult animals in Mayer Aquarium equals 7. The number of adult bear in Mayer Aquarium equals the sum of the total number of adult animals in Bundle Ranch and the number of adult bear in Bundle Ranch. The number of adult deer in Jefferson Circus equals the number of adult bear in Jefferson Circus. The number of adult fox in Jefferson Circus equals 2.

Question: How many adult bear does Bundle Ranch have?

Solution: The question is difficult, so we use equations to solve it. Define adult bear in Bundle Ranch as x; we don't know its value yet but will find it out later. Define adult fox in Bundle Ranch as i; so i = x = x. Define total number of adult animals in Bundle Ranch as w; so w = x + i = x + x = 2*x. Define adult bear in Mayer Aquarium as O; so O = w + x = 2*x + x = 3*x. Define adult fox in Mayer Aquarium as D; d = i = x; so D = 4 * d = (4) * (x) = 4*x. Define total number of adult animals in Mayer Aquarium as Q; so Q = O + D = 3*x + 4*x = 7*x. We know Q = 7, so we have 7*x = 7 and we solve it through the following steps: Simplifying the equation: 7*x = 7. Move all terms to one side: 7*x - 7 = 0. Isolate the term with x: 7*x = 7. Divide both sides by 7: x = 7 / 7. Solution: x = 1. Answer: 1.


The number of adult racoon in Bundle Ranch equals 3. The number of adult racoon in Mayer Aquarium equals 4 plus the sum of the total number of adult animals in Bundle Ranch, the number of adult racoon in Bundle Ranch, and the number of adult deer in Mayer Aquarium. The number of adult deer in Mayer Aquarium equals 4 plus the number of adult racoon in Bundle Ranch.

Question: What is the total number of adult animals in Mayer Aquarium?

Solution: Define adult racoon in Bundle Ranch as a; so a = 3. Define adult deer in Mayer Aquarium as D; w = a = 3; so D = 4 + w = 4 + 3 = 7. Define total number of adult animals in Bundle Ranch as z; so z = a = 3. Define adult racoon in Mayer Aquarium as j; m = z + a = 3 + 3 = 6; E = m + D = 6 + 7 = 13; so j = 4 + E = 4 + 13 = 17. Define total number of adult animals in Mayer Aquarium as s; so s = D + j = 7 + 17 = 24. Answer: 24.


The number of futuristic sci-fi movie in Festival de Saint-Rivage equals 1. The number of calm road movie in Festival de Saint-Rivage equals 2 plus the number of intense detective thriller in Festival de Saint-Rivage. The number of futuristic sci-fi movie in Festival Lumière de Valmont equals 3. The number of intense detective thriller in Festival de Saint-Rivage equals the number of futuristic sci-fi movie in Festival Lumière de Valmont. The number of calm road movie in Festival Lumière de Valmont equals 3. The total number of movies in Festival de Saint-Rivage equals 11. The number of solemn period drama in Festival de Saint-Rivage exists, and its number is greater than 0. The number of intense detective thriller in Festival Lumière de Valmont equals 1 plus the number of calm road movie in Festival Lumière de Valmont. The number of solemn period drama in Festival Lumière de Valmont equals the number of intense detective thriller in Festival Lumière de Valmont.

Question: How many solemn period drama does Festival de Saint-Rivage have?

Solution: The question is difficult, so we use equations to solve it. Define futuristic sci-fi movie in Festival Lumière de Valmont as k; so k = 3. Define intense detective thriller in Festival de Saint-Rivage as Y; so Y = k = 3. Define calm road movie in Festival de Saint-Rivage as M; U = Y = 3; so M = 2 + U = 2 + 3 = 5. Define futuristic sci-fi movie in Festival de Saint-Rivage as n; so n = 1. Define solemn period drama in Festival de Saint-Rivage as x; we don't know its value yet but will find it out later. Define total number of movies in Festival de Saint-Rivage as y; o = Y + n = 3 + 1 = 4; E = o + x = 4 + x = x + 4; so y = E + M = x + 4 + 5 = x + 9. We know y = 11, so we have x + 9 = 11 and we solve it through the following steps: Simplifying the equation: x + 9 = 11. Move all terms to one side: x - 2 = 0. Isolate the term with x: 1*x = 2. Divide both sides by 1: x = 2 / 1. Solution: x = 2. Answer: 2.


The number of adult wolf in Mayer Aquarium equals the total number of adult animals in Bundle Ranch. The number of adult racoon in Bundle Ranch equals 2. The number of adult deer in Bundle Ranch equals the number of adult racoon in Bundle Ranch. The number of adult bear in Bundle Ranch equals the number of adult wolf in Bundle Ranch. The number of adult wolf in Bundle Ranch equals 4.

Question: What is the total number of adult animals in Mayer Aquarium?

Solution: Define adult racoon in Bundle Ranch as T; so T = 2. Define adult wolf in Bundle Ranch as n; so n = 4. Define adult deer in Bundle Ranch as L; so L = T = 2. Define adult bear in Bundle Ranch as r; so r = n = 4. Define total number of adult animals in Bundle Ranch as d; E = T + L = 2 + 2 = 4; g = E + r = 4 + 4 = 8; so d = g + n = 8 + 4 = 12. Define adult wolf in Mayer Aquarium as F; so F = d = 12. Define total number of adult animals in Mayer Aquarium as o; so o = F = 12. Answer: 12.


The number of public highschool in Clearwater Bay equals 1 plus the total number of schools in Shoreline City. The number of private middle school in Shoreline City equals 3 plus the number of public highschool in Shoreline City. The total number of schools in Clearwater Bay equals 24. The number of private middle school in Clearwater Bay equals the number of public highschool in Clearwater Bay. The number of public highschool in Shoreline City exists, and its number is greater than 0.

Question: How many public highschool does Shoreline City have?

Solution: The question is difficult, so we use equations to solve it. Define public highschool in Shoreline City as x; we don't know its value yet but will find it out later. Define private middle school in Shoreline City as k; m = x = x; so k = 3 + m = 3 + x = x + 3. Define total number of schools in Shoreline City as R; so R = k + x = x + 3 + x = 2*x + 3. Define public highschool in Clearwater Bay as t; y = R = 2*x + 3; so t = 1 + y = 1 + 2*x + 3 = 2*x + 4. Define private middle school in Clearwater Bay as d; so d = t = 2*x + 4. Define total number of schools in Clearwater Bay as z; so z = d + t = 2*x + 4 + 2*x + 4 = 4*x + 8. We know z = 24, so we have 4*x + 8 = 24 and we solve it through the following steps: Simplifying the equation: 4*x + 8 = 24. Move all terms to one side: 4*x - 16 = 0. Isolate the term with x: 4*x = 16. Divide both sides by 4: x = 16 / 4. Solution: x = 4. Answer: 4.


The number of regional medical school in Brightford equals 4. The number of culinarian school in Brightford equals the sum of the total number of schools in Hawkesbury, the number of regional medical school in Brightford, and the number of culinarian school in Hawkesbury. The number of culinarian school in Hawkesbury equals the number of regional medical school in Brightford. The number of regional medical school in Hawkesbury equals 2 plus the sum of the number of culinarian school in Hawkesbury and the number of regional medical school in Brightford.

Question: How many culinarian school does Brightford have?

Solution: Define regional medical school in Brightford as x; so x = 4. Define culinarian school in Hawkesbury as R; so R = x = 4. Define regional medical school in Hawkesbury as X; v = R + x = 4 + 4 = 8; so X = 2 + v = 2 + 8 = 10. Define total number of schools in Hawkesbury as G; so G = R + X = 4 + 10 = 14. Define culinarian school in Brightford as B; h = G + x = 14 + 4 = 18; so B = h + R = 18 + 4 = 22. Answer: 22.


The number of solemn period drama in Cinéma de Montreval equals 4 plus the number of intense detective thriller in Cinéma de Montreval. The number of intense detective thriller in Rêves de Belleville equals the sum of the number of intense detective thriller in Cinéma de Montreval and the number of solemn period drama in Cinéma de Montreval. The number of solemn period drama in Rêves de Belleville equals the total number of movies in Cinéma de Montreval. The number of intense detective thriller in Cinéma de Montreval equals 3.

Question: What is the total number of movies in Rêves de Belleville?

Solution: Define intense detective thriller in Cinéma de Montreval as C; so C = 3. Define solemn period drama in Cinéma de Montreval as Z; y = C = 3; so Z = 4 + y = 4 + 3 = 7. Define total number of movies in Cinéma de Montreval as v; so v = Z + C = 7 + 3 = 10. Define solemn period drama in Rêves de Belleville as T; so T = v = 10. Define intense detective thriller in Rêves de Belleville as u; so u = C + Z = 3 + 7 = 10. Define total number of movies in Rêves de Belleville as X; so X = T + u = 10 + 10 = 20. Answer: 20.


The number of adult owl in Cedar Valley equals the number of adult parrot in Cedar Valley. The number of adult crow in Pine Ridge equals the sum of the number of adult owl in Cedar Valley and the number of adult parrot in Cedar Valley. The number of adult parrot in Cedar Valley exists, and its number is greater than 0. The total number of adult animals in Maple Creek equals 6. The number of adult parrot in Cedar Valley exists, and its number is greater than 0.

Question: How many adult parrot does Cedar Valley have?

Solution: The question is difficult, so we use equations to solve it. Define adult parrot in Cedar Valley as x; we don't know its value yet but will find it out later. Define adult owl in Cedar Valley as U; so U = x = x. Define adult crow in Pine Ridge as p; so p = U + x = x + x = 2*x. Define total number of adult animals in Pine Ridge as H; so H = p = 2*x. Define adult crow in Maple Creek as v; t = H + p = 2*x + 2*x = 4*x; u = t + x = 4*x + x = 5*x; so v = u + U = 5*x + x = 6*x. Define total number of adult animals in Maple Creek as i; so i = v = 6*x. We know i = 6, so we have 6*x = 6 and we solve it through the following steps: Simplifying the equation: 6*x = 6. Move all terms to one side: 6*x - 6 = 0. Isolate the term with x: 6*x = 6. Divide both sides by 6: x = 6 / 6. Solution: x = 1. Answer: 1.


The number of adult owl in Mayer Aquarium equals 4 times the total number of adult animals in Jefferson Circus. The number of adult owl in Jefferson Circus equals 3. The number of adult eagle in Mayer Aquarium equals 3. The number of adult eagle in Jefferson Circus equals 2 times the number of adult owl in Jefferson Circus.

Question: What is the total number of adult animals in Mayer Aquarium?

Solution: Define adult owl in Jefferson Circus as I; so I = 3. Define adult eagle in Jefferson Circus as v; j = I = 3; so v = 2 * j = 2 * 3 = 6. Define total number of adult animals in Jefferson Circus as E; so E = v + I = 6 + 3 = 9. Define adult owl in Mayer Aquarium as R; a = E = 9; so R = 4 * a = 4 * 9 = 36. Define adult eagle in Mayer Aquarium as x; so x = 3. Define total number of adult animals in Mayer Aquarium as T; so T = x + R = 3 + 36 = 39. Answer: 39.


The number of calm road movie in West Sahara Movie Festival equals 1. The number of solemn period drama in Golden Banana Movie Festival equals 4 times the sum of the total number of movies in Northwood Movie Festival and the total number of movies in West Sahara Movie Festival. The number of upbeat metropolis comedy in Northwood Movie Festival equals 2 times the sum of the total number of movies in West Sahara Movie Festival and the number of calm road movie in West Sahara Movie Festival.

Question: What is the total number of movies in Golden Banana Movie Festival?

Solution: Define calm road movie in West Sahara Movie Festival as c; so c = 1. Define total number of movies in West Sahara Movie Festival as K; so K = c = 1. Define upbeat metropolis comedy in Northwood Movie Festival as G; J = K + c = 1 + 1 = 2; so G = 2 * J = 2 * 2 = 4. Define total number of movies in Northwood Movie Festival as q; so q = G = 4. Define solemn period drama in Golden Banana Movie Festival as E; p = q + K = 4 + 1 = 5; so E = 4 * p = 4 * 5 = 20. Define total number of movies in Golden Banana Movie Festival as i; so i = E = 20. Answer: 20.


The number of upbeat metropolis comedy in West Sahara Movie Festival equals 4. The number of upbeat metropolis comedy in Northwood Movie Festival equals 2 plus the difference between the total number of movies in West Sahara Movie Festival and the number of upbeat metropolis comedy in West Sahara Movie Festival. The number of futuristic sci-fi movie in Northwood Movie Festival equals 4 plus the sum of the number of upbeat metropolis comedy in West Sahara Movie Festival and the total number of movies in West Sahara Movie Festival.

Question: What is the total number of movies in Northwood Movie Festival?

Solution: Define upbeat metropolis comedy in West Sahara Movie Festival as O; so O = 4. Define total number of movies in West Sahara Movie Festival as l; so l = O = 4. Define upbeat metropolis comedy in Northwood Movie Festival as Y; W = l - O = 4 - 4 = 0; so Y = 2 + W = 2 + 0 = 2. Define futuristic sci-fi movie in Northwood Movie Festival as q; D = O + l = 4 + 4 = 8; so q = 4 + D = 4 + 8 = 12. Define total number of movies in Northwood Movie Festival as x; so x = q + Y = 12 + 2 = 14. Answer: 14.


The number of calm road movie in Golden Banana Movie Festival exists, and its number is greater than 0. The number of calm road movie in Golden Banana Movie Festival exists, and its number is greater than 0. The number of upbeat metropolis comedy in Golden Banana Movie Festival equals the number of calm road movie in Golden Banana Movie Festival. The total number of movies in West Sahara Movie Festival equals 14. The number of calm road movie in West Sahara Movie Festival equals 4 plus the difference between the number of upbeat metropolis comedy in Golden Banana Movie Festival and the number of calm road movie in Golden Banana Movie Festival.

Question: How many calm road movie does Golden Banana Movie Festival have?

Solution: The question is difficult, so we use equations to solve it. Define calm road movie in Golden Banana Movie Festival as x; we don't know its value yet but will find it out later. Define upbeat metropolis comedy in Golden Banana Movie Festival as z; so z = x = x. Define calm road movie in West Sahara Movie Festival as Q; H = z - x = (x) - (x) = 0; so Q = 4 + H = 4 + 0 = 4. Define upbeat metropolis comedy in West Sahara Movie Festival as h; u = z + x = x + x = 2*x; so h = u + Q = 2*x + 4 = 2*x + 4. Define total number of movies in West Sahara Movie Festival as n; so n = Q + h = 4 + 2*x + 4 = 2*x + 8. We know n = 14, so we have 2*x + 8 = 14 and we solve it through the following steps: Simplifying the equation: 2*x + 8 = 14. Move all terms to one side: 2*x - 6 = 0. Isolate the term with x: 2*x = 6. Divide both sides by 2: x = 6 / 2. Solution: x = 3. Answer: 3.


The number of regional medical school in Glenfield City equals 4 times the number of elementary school in Glenfield City. The number of private middle school in Glenfield City equals 2 times the number of elementary school in Glenfield City. The number of elementary school in Glenfield City equals 1. The number of culinarian school in Hawkesbury equals the total number of schools in Glenfield City.

Question: What is the total number of schools in Hawkesbury?

Solution: Define elementary school in Glenfield City as H; so H = 1. Define private middle school in Glenfield City as K; N = H = 1; so K = 2 * N = 2 * 1 = 2. Define regional medical school in Glenfield City as h; D = H = 1; so h = 4 * D = 4 * 1 = 4. Define total number of schools in Glenfield City as u; l = h + K = 4 + 2 = 6; so u = l + H = 6 + 1 = 7. Define culinarian school in Hawkesbury as T; so T = u = 7. Define total number of schools in Hawkesbury as E; so E = T = 7. Answer: 7.


The number of culinarian school in Shoreline City equals the number of regional medical school in Shoreline City. The total number of schools in Clearwater Bay equals 12. The number of culinarian school in Clearwater Bay exists, and its number is greater than 0. The number of private middle school in Oakbridge City equals 4 plus the number of regional medical school in Oakbridge City. The number of regional medical school in Clearwater Bay equals 3 plus the total number of schools in Oakbridge City. The number of private middle school in Ruby Bay equals the difference between the number of culinarian school in Clearwater Bay and the total number of schools in Oakbridge City. The number of regional medical school in Shoreline City equals 3 plus the number of private middle school in Shoreline City. The number of regional medical school in Ruby Bay equals 3. The number of private middle school in Shoreline City equals 2. The number of regional medical school in Oakbridge City equals 1. The number of culinarian school in Ruby Bay equals 4.

Question: How many culinarian school does Clearwater Bay have?

Solution: The question is difficult, so we use equations to solve it. Define regional medical school in Oakbridge City as S; so S = 1. Define private middle school in Oakbridge City as L; D = S = 1; so L = 4 + D = 4 + 1 = 5. Define total number of schools in Oakbridge City as Q; so Q = L + S = 5 + 1 = 6. Define regional medical school in Clearwater Bay as u; p = Q = 6; so u = 3 + p = 3 + 6 = 9. Define culinarian school in Clearwater Bay as x; we don't know its value yet but will find it out later. Define total number of schools in Clearwater Bay as T; so T = u + x = 9 + x = x + 9. We know T = 12, so we have x + 9 = 12 and we solve it through the following steps: Simplifying the equation: x + 9 = 12. Move all terms to one side: x - 3 = 0. Isolate the term with x: 1*x = 3. Divide both sides by 1: x = 3 / 1. Solution: x = 3. Answer: 3.


The number of elementary school in Hawkesbury equals the sum of the number of elementary school in Glenfield City, the total number of schools in Glenfield City, and the number of private middle school in Hawkesbury. The total number of schools in Hawkesbury equals 28. The number of private middle school in Glenfield City exists, and its number is greater than 0. The number of elementary school in Glenfield City equals the number of private middle school in Glenfield City. The number of private middle school in Hawkesbury equals the total number of schools in Glenfield City.

Question: How many private middle school does Glenfield City have?

Solution: The question is difficult, so we use equations to solve it. Define private middle school in Glenfield City as x; we don't know its value yet but will find it out later. Define elementary school in Glenfield City as i; so i = x = x. Define total number of schools in Glenfield City as w; so w = i + x = x + x = 2*x. Define private middle school in Hawkesbury as h; so h = w = 2*x. Define elementary school in Hawkesbury as K; G = i + w = x + 2*x = 3*x; so K = G + h = 3*x + 2*x = 5*x. Define total number of schools in Hawkesbury as D; so D = K + h = 5*x + 2*x = 7*x. We know D = 28, so we have 7*x = 28 and we solve it through the following steps: Simplifying the equation: 7*x = 28. Move all terms to one side: 7*x - 28 = 0. Isolate the term with x: 7*x = 28. Divide both sides by 7: x = 28 / 7. Solution: x = 4. Answer: 4.


The total number of adult animals in South Zoo equals 6. The number of adult crow in Mayer Aquarium equals 2 plus the sum of the total number of adult animals in Jefferson Circus and the number of adult eagle in Jefferson Circus. The number of adult eagle in Jefferson Circus exists, and its number is greater than 0. The number of adult blue jay in South Zoo equals 3 plus the difference between the total number of adult animals in Mayer Aquarium and the total number of adult animals in Jefferson Circus.

Question: How many adult eagle does Jefferson Circus have?

Solution: The question is difficult, so we use equations to solve it. Define adult eagle in Jefferson Circus as x; we don't know its value yet but will find it out later. Define total number of adult animals in Jefferson Circus as J; so J = x = x. Define adult crow in Mayer Aquarium as O; E = J + x = x + x = 2*x; so O = 2 + E = 2 + 2*x = 2*x + 2. Define total number of adult animals in Mayer Aquarium as i; so i = O = 2*x + 2. Define adult blue jay in South Zoo as n; I = i - J = (2*x + 2) - (x) = x + 2; so n = 3 + I = 3 + x + 2 = x + 5. Define total number of adult animals in South Zoo as v; so v = n = x + 5. We know v = 6, so we have x + 5 = 6 and we solve it through the following steps: Simplifying the equation: x + 5 = 6. Move all terms to one side: x - 1 = 0. Isolate the term with x: 1*x = 1. Divide both sides by 1: x = 1 / 1. Solution: x = 1. Answer: 1.


The number of adult bear in Pine Ridge equals 4. The number of adult bear in Beverly Forest equals 2. The number of adult deer in Beverly Forest equals 4 times the number of adult wolf in Beverly Forest. The number of adult wolf in Pine Ridge equals 1 plus the difference between the total number of adult animals in Beverly Forest and the number of adult wolf in Beverly Forest. The number of adult wolf in Beverly Forest equals the number of adult bear in Beverly Forest. The number of adult deer in Pine Ridge equals the number of adult bear in Pine Ridge.

Question: How many adult wolf does Pine Ridge have?

Solution: Define adult bear in Beverly Forest as u; so u = 2. Define adult wolf in Beverly Forest as C; so C = u = 2. Define adult deer in Beverly Forest as q; O = C = 2; so q = 4 * O = 4 * 2 = 8. Define total number of adult animals in Beverly Forest as L; o = u + q = 2 + 8 = 10; so L = o + C = 10 + 2 = 12. Define adult wolf in Pine Ridge as A; z = L - C = 12 - 2 = 10; so A = 1 + z = 1 + 10 = 11. Answer: 11.


The total number of adult animals in Maple Creek equals 18. The number of adult wolf in Pine Ridge equals 2 plus the sum of the total number of adult animals in Oakridge Riverside and the number of adult wolf in Oakridge Riverside. The number of adult wolf in Maple Creek equals the sum of the total number of adult animals in Pine Ridge, the total number of adult animals in Oakridge Riverside, and the number of adult wolf in Oakridge Riverside. The number of adult wolf in Oakridge Riverside exists, and its number is greater than 0.

Question: How many adult wolf does Oakridge Riverside have?

Solution: The question is difficult, so we use equations to solve it. Define adult wolf in Oakridge Riverside as x; we don't know its value yet but will find it out later. Define total number of adult animals in Oakridge Riverside as t; so t = x = x. Define adult wolf in Pine Ridge as O; c = t + x = x + x = 2*x; so O = 2 + c = 2 + 2*x = 2*x + 2. Define total number of adult animals in Pine Ridge as V; so V = O = 2*x + 2. Define adult wolf in Maple Creek as I; r = V + t = 2*x + 2 + x = 3*x + 2; so I = r + x = 3*x + 2 + x = 4*x + 2. Define total number of adult animals in Maple Creek as b; so b = I = 4*x + 2. We know b = 18, so we have 4*x + 2 = 18 and we solve it through the following steps: Simplifying the equation: 4*x + 2 = 18. Move all terms to one side: 4*x - 16 = 0. Isolate the term with x: 4*x = 16. Divide both sides by 4: x = 16 / 4. Solution: x = 4. Answer: 4.


The number of regional medical school in Hawkesbury equals 2. The number of private middle school in Westhaven City equals the sum of the total number of schools in Hawkesbury and the number of regional medical school in Hawkesbury. The number of regional medical school in Westhaven City equals 4 times the number of regional medical school in Hawkesbury. The number of private middle school in Hawkesbury equals 3.

Question: What is the total number of schools in Westhaven City?

Solution: Define regional medical school in Hawkesbury as B; so B = 2. Define regional medical school in Westhaven City as l; e = B = 2; so l = 4 * e = 4 * 2 = 8. Define private middle school in Hawkesbury as b; so b = 3. Define total number of schools in Hawkesbury as f; so f = b + B = 3 + 2 = 5. Define private middle school in Westhaven City as k; so k = f + B = 5 + 2 = 7. Define total number of schools in Westhaven City as m; so m = k + l = 7 + 8 = 15. Answer: 15.


The number of public highschool in Riverton City equals 4. The number of regional medical school in Riverton City equals 3. The number of regional medical school in Shoreline City equals the number of regional medical school in Riverton City. The number of regional medical school in Oakbridge City equals the total number of schools in Shoreline City. The number of public highschool in Shoreline City equals the total number of schools in Riverton City.

Question: What is the total number of schools in Oakbridge City?

Solution: Define public highschool in Riverton City as d; so d = 4. Define regional medical school in Riverton City as o; so o = 3. Define total number of schools in Riverton City as Y; so Y = d + o = 4 + 3 = 7. Define public highschool in Shoreline City as v; so v = Y = 7. Define regional medical school in Shoreline City as H; so H = o = 3. Define total number of schools in Shoreline City as a; so a = v + H = 7 + 3 = 10. Define regional medical school in Oakbridge City as h; so h = a = 10. Define total number of schools in Oakbridge City as c; so c = h = 10. Answer: 10.


The number of intense detective thriller in Verdi Movie Festival exists, and its number is greater than 0. The total number of movies in Golden Banana Movie Festival equals 14. The number of intense detective thriller in Taylor Movie Festival equals 3. The number of intense detective thriller in Verdi Movie Festival exists, and its number is greater than 0. The number of intense detective thriller in Golden Banana Movie Festival equals the total number of movies in Taylor Movie Festival.

Question: How many intense detective thriller does Verdi Movie Festival have?

Solution: The question is difficult, so we use equations to solve it. Define intense detective thriller in Taylor Movie Festival as I; so I = 3. Define total number of movies in Taylor Movie Festival as b; so b = I = 3. Define intense detective thriller in Golden Banana Movie Festival as C; so C = b = 3. Define intense detective thriller in Verdi Movie Festival as x; we don't know its value yet but will find it out later. Define total number of movies in Verdi Movie Festival as L; so L = x = x. Define calm road movie in Golden Banana Movie Festival as V; m = L + x = x + x = 2*x; so V = m + C = 2*x + 3 = 2*x + 3. Define total number of movies in Golden Banana Movie Festival as q; so q = V + C = 2*x + 3 + 3 = 2*x + 6. We know q = 14, so we have 2*x + 6 = 14 and we solve it through the following steps: Simplifying the equation: 2*x + 6 = 14. Move all terms to one side: 2*x - 8 = 0. Isolate the term with x: 2*x = 8. Divide both sides by 2: x = 8 / 2. Solution: x = 4. Answer: 4.