% Create geometry and FEM mesh for the unit disc % % The following information is saved into file data/mesh.mat: % p point data matrix % e edge data matrix % t triangle data matrix % ecenters Nx2 matrix of centerpoints of edges % elengths lengths of edges % bfii Nx1 vector of angles of complex numbers ecenters % btri_ind indices of triangles having an edge as one side % % Samuli Siltanen March 2012 % Number of mesh refinements. Bigger number giver finer mesh but leads to % heavier computation as well. Nrefine = 5; % Create a subdirectory called 'data'. If it already exists, Matlab will % show a warning. You don't need to care about the warning. mkdir('.','data') % Build Decomposed Geometry Matrix dgm = [... % DGM for unit disc [ 1, 1, 1, 1];... % 1 = circle domain [-1, 0, 1, 0];... % Starting x-coordinate of boundary segment [ 0, 1, 0,-1];... % Ending x-coordinate of boundary segment [ 0,-1, 0, 1];... % Starting y-coordinate of boundary segment [-1, 0, 1, 0];... % Ending y-coordinate of boundary segment [ 1, 1, 1, 1];... % Left minimal region label [ 0, 0, 0, 0];... % Right minimal region label [ 0, 0, 0, 0];... % x-coordinate of the center of the circle [ 0, 0, 0, 0];... % y-coordinate of the center of the circle [ 1, 1, 1, 1];... % radius of the circle [ 0, 0, 0, 0];... % dummy row to match up with the ellipse geometry below [ 0, 0, 0, 0];... % dummy row to match up with the ellipse geometry below ]; % Construct mesh [p,e,t] = initmesh(dgm); for rrr = 1:Nrefine [p,e,t] = refinemesh(dgm,p,e,t); p = jigglemesh(p,e,t); end % Determine the center points of edges and the corresponding angles ecenters = (p(:,e(1,:)) + p(:,e(2,:)))/2; bfii = angle(ecenters(1,:)+i*ecenters(2,:)); % Find the set of triangles that have a face on the boundary % and the index of the corresponding edge. % We use the fact that each triangle in the mesh has zero, one or two % vertices on the boundary. btri_ind = zeros(size(bfii)); for ttt = 1:size(t,2) % Loop over all triangles in the mesh xtmp = []; % Is vertex 1 of current triangle on the bottom? if (p(1,t(1,ttt))^2+p(2,t(1,ttt))^2 > 1-1e-10) xtmp = [xtmp, p(:,t(1,ttt))]; end % Is vertex 2 of current triangle on the bottom? if (p(1,t(2,ttt))^2+p(2,t(2,ttt))^2 > 1-1e-10) xtmp = [xtmp, p(:,t(2,ttt))]; end % Is vertex 3 of current triangle on the bottom? if (p(1,t(3,ttt))^2+p(2,t(3,ttt))^2 > 1-1e-10) xtmp = [xtmp, p(:,t(3,ttt))]; end % At this point, matrix xtmp has at most 2 columns. % If the number of columns is two, we have a triangle that has % an edge as one side. Let's determine the edge in question. if size(xtmp,2)>1 tmp_center = (xtmp(1,1)+xtmp(1,2))/2 + i*(xtmp(2,1)+xtmp(2,2))/2; tmp_angle = angle(tmp_center); e_ind = find(abs(bfii-tmp_angle)<1e-8); btri_ind(e_ind) = ttt; end end % Compute lengths of edges elengths = zeros(size(bfii)); for iii = 1:length(bfii) elengths(iii) = norm(p(:,e(1,iii))-p(:,e(2,iii))); end % Check the result visually % figure(1) % clf % pdemesh(p,e,t) % axis equal % axis off % print -dpng mesh.png % Save result to file save data/mesh p e t bfii ecenters btri_ind elengths dgm