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1ldwruj9v | physics | geometrical-optics | lenses | <p>A convex lens of refractive index 1.5 and focal length 18cm in air is immersed in water. The change in focal length of the lens will be ___________ cm.</p>
<p>(Given refractive index of water $$=\frac{4}{3}$$)</p> | [] | null | 54 | From lens makers formula
<br/><br/>
$$
\frac{1}{f}=\left(\frac{\mu_{\text {lens }}}{\mu_{\text {mrdium }}}-1\right)\left[\frac{1}{R_{1}}-\frac{1}{R_{2}}\right]
$$
<br/><br/>
when in air
<br/><br/>
$$
\frac{1}{18}=\left(\frac{1.5}{1}-1\right)\left[\frac{1}{R_{1}}-\frac{1}{R_{2}}\right]\quad...(1)
$$
<br/><br/>
$\mu_{\te... | integer | jee-main-2023-online-24th-january-evening-shift | 10,915 |
1ldyf22ha | physics | geometrical-optics | lenses | <p>As shown in the figure, a combination of a thin plano concave lens and a thin plano convex lens is used to image an object placed at infinity. The radius of curvature of both the lenses is 30 cm and refraction index of the material for both the lenses is 1.75. Both the lenses are placed at distance of 40 cm from eac... | [] | null | 120 | $\frac{1}{f_{\text {concave }}}=(1.75-1)\left(\frac{1}{\infty}-\frac{1}{+30}\right)=-\frac{0.75}{30}$
<br/><br/>
$f_{\text {concave }}=-40 \mathrm{~cm}$
<br/><br/>
$\frac{1}{f_{\text {convex }}}=(1.75-1)\left(\frac{1}{30}-\frac{1}{\infty}\right)=\frac{0.75}{30}$
<br/><br/>
$f_{\text {convex }}=40 \mathrm{~cm}$
<br/><br... | integer | jee-main-2023-online-24th-january-morning-shift | 10,916 |
1lgrju3bo | physics | geometrical-optics | lenses | <p>Two convex lenses of focal length $$20 \mathrm{~cm}$$ each are placed coaxially with a separation of $$60 \mathrm{~cm}$$ between them. The image of the distant object formed by the combination is at _____________ $$\mathrm{cm}$$ from the first lens.</p> | [] | null | 100 | <img src="https://app-content.cdn.examgoal.net/fly/@width/image/1lguyz197/be80220e-4d6f-4336-abee-5a7998e060c0/5c2f0eb0-e2b1-11ed-b448-73bf9320498f/file-1lguyz198.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1lguyz197/be80220e-4d6f-4336-abee-5a7998e060c0/5c2f0eb0-e2b1-11ed-b448-73bf9320498f/fi... | integer | jee-main-2023-online-12th-april-morning-shift | 10,918 |
1lguyv1k7 | physics | geometrical-optics | lenses | <p>The radius of curvature of each surface of a convex lens having refractive index 1.8 is $$20 \mathrm{~cm}$$. The lens is now immersed in a liquid of refractive index 1.5 . The ratio of power of lens in air to its power in the liquid will be $$x: 1$$. The value of $$x$$ is _________.</p> | [] | null | 4 | <p>Let's find the focal length of the lens in air and in the liquid. We will use the lens maker's formula:</p>
<p>$$\frac{1}{f} = (\mu - 1)\left(\frac{1}{R_1} - \frac{1}{R_2}\right)$$</p>
<p>where $$f$$ is the focal length, $$\mu$$ is the refractive index of the lens material, and $$R_1$$ and $$R_2$$ are the ra... | integer | jee-main-2023-online-11th-april-morning-shift | 10,919 |
1lgvtjs6y | physics | geometrical-optics | lenses | <p>A point object, 'O' is placed in front of two thin symmetrical coaxial convex lenses $$\mathrm{L}_{1}$$ and $$\mathrm{L}_{2}$$ with focal length $$24 \mathrm{~cm}$$ and $$9 \mathrm{~cm}$$ respectively. The distance between two lenses is $$10 \mathrm{~cm}$$ and the object is placed $$6 \mathrm{~cm}$$ away from lens $... | [] | null | 34 | <b>From I<sup>st</sup> lens :</b>
<br><br>$\frac{1}{\mathrm{v}}+\frac{1}{6}=\frac{1}{24}$
<br><br>$$
\begin{aligned}
\frac{1}{\mathrm{v}} & =\frac{1}{24}-\frac{1}{6}=-\frac{1}{8} \\\\
\mathrm{v} & =-8 \mathrm{~cm}
\end{aligned}
$$
<br><br><b>From II<sup>nd</sup> lens :</b>
<br><br>$\frac{1}{\mathrm{v}}+\frac{1}... | integer | jee-main-2023-online-10th-april-evening-shift | 10,920 |
1lgyr4ix8 | physics | geometrical-optics | lenses | <p>Two transparent media having refractive indices 1.0 and 1.5 are separated by a spherical refracting surface of radius of curvature $$30 \mathrm{~cm}$$. The centre of curvature of surface is towards denser medium and a point object is placed on the principle axis in rarer medium at a distance of $$15 \mathrm{~cm}$$ f... | [] | null | 30 | <p>The refraction at a spherical surface is governed by the formula:</p>
<p>$\frac{1}{v} - \frac{1}{u} = \frac{n_2 - n_1}{R} n_2$</p>
<p>where:</p>
<ul>
<li>(v) is the image distance,</li>
<li>(u) is the object distance,</li>
<li>($n_1$) is the refractive index of the medium where the object is,</li>
<li>($n_2$) is the... | integer | jee-main-2023-online-8th-april-evening-shift | 10,921 |
1lh2zt8kr | physics | geometrical-optics | lenses | <p>A 2 meter long scale with least count of $$0.2 \mathrm{~cm}$$ is used to measure the locations of objects on an optical bench. While measuring the focal length of a convex lens, the object pin and the convex lens are placed at $$80 \mathrm{~cm}$$ mark and $$1 \mathrm{~m}$$ mark, respectively. The image of the object... | [{"identifier": "A", "content": "1.70"}, {"identifier": "B", "content": "0.51"}, {"identifier": "C", "content": "1.02"}, {"identifier": "D", "content": "0.85"}] | ["A"] | null | <p>In this problem, you are asked to find the percentage error in the estimation of the focal length of a convex lens using a 2-meter long scale with a least count of 0.2 cm.</p>
<p>First, let's determine the object distance (u), image distance (v), and focal length (f) of the lens.</p>
<ol>
<li><p>Object distance ... | mcq | jee-main-2023-online-6th-april-evening-shift | 10,922 |
lsbll9l4 | physics | geometrical-optics | lenses | The distance between object and its 3 times magnified virtual image as produced by a convex lens is $20 \mathrm{~cm}$. The focal length of the lens used is __________ $\mathrm{cm}$. | [] | null | 15 | <img src="https://app-content.cdn.examgoal.net/fly/@width/image/6y3zli1lsqfs9pm/e4b3d7cc-7bac-404d-a994-0f5252a57a48/c88c18a0-cdc5-11ee-979b-67a81185a3d4/file-6y3zli1lsqfs9pn.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/6y3zli1lsqfs9pm/e4b3d7cc-7bac-404d-a994-0f5252a57a48/c88c18a0-cdc5-11ee-97... | integer | jee-main-2024-online-1st-february-morning-shift | 10,923 |
jaoe38c1lsc3ndoy | physics | geometrical-optics | lenses | <p>A convex lens of focal length $$40 \mathrm{~cm}$$ forms an image of an extended source of light on a photoelectric cell. A current I is produced. The lens is replaced by another convex lens having the same diameter but focal length $$20 \mathrm{~cm}$$. The photoelectric current now is :</p> | [{"identifier": "A", "content": "$$\\mathrm{\\frac{I}{2}}$$"}, {"identifier": "B", "content": "4 I"}, {"identifier": "C", "content": "2 I"}, {"identifier": "D", "content": "I"}] | ["D"] | null | <p>As amount of energy incident on cell is same so current will remain same.</p> | mcq | jee-main-2024-online-27th-january-morning-shift | 10,924 |
jaoe38c1lsf1dkee | physics | geometrical-optics | lenses | <p>A biconvex lens of refractive index 1.5 has a focal length of $$20 \mathrm{~cm}$$ in air. Its focal length when immersed in a liquid of refractive index 1.6 will be:</p> | [{"identifier": "A", "content": "$$-$$16 cm"}, {"identifier": "B", "content": "+16 cm"}, {"identifier": "C", "content": "+160 cm"}, {"identifier": "D", "content": "$$-$$160 cm"}] | ["D"] | null | <p>$$\begin{aligned}
& \mu_1=1.5 \\
& \mu_m=1.6 \\
& f_a=20 \mathrm{~cm} \\
& \text { As } \frac{f_m}{f_a}=\frac{\left(\mu_1-1\right) \mu_m}{\left(\mu_1-\mu_m\right)} \\
& \frac{f_m}{20}=\frac{(1.5-1) 1.6}{(1.5-1.6)} \\
& f_m=-160 \mathrm{~cm}
\end{aligned}$$</p> | mcq | jee-main-2024-online-29th-january-morning-shift | 10,925 |
1lsg76up1 | physics | geometrical-optics | lenses | <p>In an experiment to measure the focal length $$(f)$$ of a convex lens, the magnitude of object distance $$(x)$$ and the image distance $$(y)$$ are measured with reference to the focal point of the lens. The $$y$$-$$x$$ plot is shown in figure.</p>
<p>The focal length of the lens is ________ $$\mathrm{cm}$$.</p>
<p><... | [] | null | 20 | <p>$$\begin{aligned}
& \frac{1}{f+20}-\frac{1}{-(f+20)}=\frac{1}{f} \\
& \frac{2}{f+20}=\frac{1}{f} \quad f=20 \mathrm{~cm}
\end{aligned}$$</p>
<p>Or $$\mathrm{x}_1 \mathrm{x}_2=\mathrm{f}^2$$ gives $$\mathrm{f}=20 \mathrm{~cm}$$</p> | integer | jee-main-2024-online-30th-january-evening-shift | 10,926 |
1lsgxfrmn | physics | geometrical-optics | lenses | <p>The distance between object and its two times magnified real image as produced by a convex lens is $$45 \mathrm{~cm}$$. The focal length of the lens used is _______ cm.</p> | [] | null | 10 | <p>$$\begin{aligned}
& \frac{v}{u}=-2 \\
& v=-2 u \quad\text{... (i)} \\
& v-u=45 \quad\text{... (ii)}\\
& \Rightarrow u=-15 \mathrm{~cm} \\
& v=30 \mathrm{~cm} \\
& \frac{1}{f}=\frac{1}{v}-\frac{1}{u} \\
& f=+10 \mathrm{~cm}
\end{aligned}$$</p> | integer | jee-main-2024-online-30th-january-morning-shift | 10,927 |
lv0vxked | physics | geometrical-optics | lenses | <p>An effective power of a combination of 5 identical convex lenses which are kept in contact along the principal axis is $$25 \mathrm{D}$$. Focal length of each of the convex lens is:</p> | [{"identifier": "A", "content": "50 cm"}, {"identifier": "B", "content": "20 cm"}, {"identifier": "C", "content": "25 cm"}, {"identifier": "D", "content": "500 cm"}] | ["B"] | null | <p>When we have a combination of identical lenses in contact, the effective power ($$P_{\text{eff}}$$) of the combination can be calculated as the sum of the powers of all the individual lenses. This is because the lenses are in direct contact, and their powers effectively add up.</p>
<p>Given that the effective power... | mcq | jee-main-2024-online-4th-april-morning-shift | 10,930 |
lv0vxm1t | physics | geometrical-optics | lenses | <p>In an experiment to measure focal length ($$f$$) of convex lens, the least counts of the measuring scales for the position of object (u) and for the position of image (v) are $$\Delta u$$ and $$\Delta v$$, respectively. The error in the measurement of the focal length of the convex lens will be:</p> | [{"identifier": "A", "content": "$$2 f\\left[\\frac{\\Delta \\mathrm{u}}{\\mathrm{u}}+\\frac{\\Delta \\mathrm{v}}{\\mathrm{v}}\\right]$$\n"}, {"identifier": "B", "content": "$$f\\left[\\frac{\\Delta \\mathrm{u}}{\\mathrm{u}}+\\frac{\\Delta \\mathrm{v}}{\\mathrm{v}}\\right]$$\n"}, {"identifier": "C", "content": "$$f^2\\... | ["C"] | null | <p>First, let's understand the relationship between the object distance ($$u$$), the image distance ($$v$$), and the focal length ($$f$$) of a convex lens, which is given by the lens formula:</p>
$$
\frac{1}{f} = \frac{1}{v} + \frac{1}{u}
$$
<p>Now, to find the error in the focal length ($$\Delta f$$) due to the error... | mcq | jee-main-2024-online-4th-april-morning-shift | 10,931 |
lv3vegjv | physics | geometrical-optics | lenses | <p>The position of the image formed by the combination of lenses is :</p>
<p><img src="data:image/png;base64,UklGRjYKAABXRUJQVlA4ICoKAAAwdwCdASoAA/MAP4G41mU2LawnIfBqYsAwCWlu8ouUdk94sIMsObz93zcN20S7Rf6rwmfM3fTO5lu485/+9/uMEsk9dA6E66c/yFMzMzMyuChqBtfyT10DhOqKTgYDs+YDEvI76a8ZLcnPDQZ0OynumZCdLOC3Z8v8f+BjgxSf6Wni5kDfzWJtfLp... | [{"identifier": "A", "content": "$$15 \\mathrm{~cm}$$ (right of second lens)\n"}, {"identifier": "B", "content": "$$30 \\mathrm{~cm}$$ (right of third lens)\n"}, {"identifier": "C", "content": "$$30 \\mathrm{~cm}$$ (left of third lens)\n"}, {"identifier": "D", "content": "$$15 \\mathrm{~cm}$$ (left of second lens)"}] | ["B"] | null | <p>$$\begin{aligned}
& \frac{1}{v}-\frac{1}{u}=\frac{1}{f} \\
& \frac{1}{v}-\frac{1}{-30}=\frac{1}{10} \\
& \frac{1}{v}=\frac{1}{10}-\frac{1}{30}=\frac{3-1}{30}=\frac{1}{15} \\
& v=15
\end{aligned}$$</p>
<p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1lw4x7hrm/e9026ee8-ae6a-458d-a98c... | mcq | jee-main-2024-online-8th-april-evening-shift | 10,932 |
lvb29ea0 | physics | geometrical-optics | lenses | <p>For the thin convex lens, the radii of curvature are at $$15 \mathrm{~cm}$$ and $$30 \mathrm{~cm}$$ respectively. The focal length the lens is $$20 \mathrm{~cm}$$. The refractive index of the material is :</p> | [{"identifier": "A", "content": "1.2"}, {"identifier": "B", "content": "1.5"}, {"identifier": "C", "content": "1.4"}, {"identifier": "D", "content": "1.8"}] | ["B"] | null | <p>To find the refractive index of the material of a thin convex lens, we can make use of the Lensmaker's Formula. The Lensmaker's formula is given by:</p>
<p>$$\frac{1}{f} = \left( \frac{\mu - 1}{\mu} \right) \left( \frac{1}{R_1} - \frac{1}{R_2} \right)$$</p>
<p>where</p>
<ul>
<li>$f$ is the focal length of th... | mcq | jee-main-2024-online-6th-april-evening-shift | 10,933 |
PxrdrrjHeoGbS4Jy | physics | geometrical-optics | optical-instruments | Wavelength of light used in an optical instrument are $${\lambda _1} = 4000\mathop A\limits^ \circ $$ and $${\lambda _2} = 5000\mathop A\limits^ \circ ,$$ then ratio of their respective resolving powers (corresponding to $${\lambda _1}$$ and $${\lambda _2}$$ ) is : | [{"identifier": "A", "content": "$$16:25$$ "}, {"identifier": "B", "content": "$$9:1$$ "}, {"identifier": "C", "content": "$$4:5$$ "}, {"identifier": "D", "content": "$$5:4$$"}] | ["D"] | null | <p>The resolving power (RP) of an optical instrument is inversely proportional to the wavelength (λ) of light used. So, if we denote the resolving powers corresponding to λ₁ and λ₂ as RP₁ and RP₂ respectively, we can express this relationship as :</p>
<p>RP $$ \propto $$ $${1 \over \lambda }$$</p>
<p>Therefore, the rat... | mcq | aieee-2002 | 10,934 |
Ds91CkLT5O3mFF64 | physics | geometrical-optics | optical-instruments | An observer looks at a distant tree of height $$10$$ $$m$$ with a telescope of magnifying power of $$20.$$ To the observer the tree appears: | [{"identifier": "A", "content": "$$20$$ times taller "}, {"identifier": "B", "content": "$$20$$ times nearer "}, {"identifier": "C", "content": "$$10$$ times taller "}, {"identifier": "D", "content": "$$10$$ times nearer "}] | ["B"] | null | A telescope magnifies by making the object appearing closer. | mcq | jee-main-2016-offline | 10,937 |
PtF1LjGZkgsXloqgMu7k9k2k5gw7a65 | physics | geometrical-optics | optical-instruments | The magnifying power of a telescope with tube
60 cm is 5. What is the focal length of its eye
piece ? | [{"identifier": "A", "content": "40 cm"}, {"identifier": "B", "content": "10 cm"}, {"identifier": "C", "content": "30 cm"}, {"identifier": "D", "content": "20 cm"}] | ["B"] | null | For telescope
<br><br>Tube length (L) = f<sub>0</sub> + f<sub>e</sub>
<br><br>and magnification (m) = $${{{f_0}} \over {{f_e}}}$$ = 5
<br><br>where f<sub>o</sub> and f<sub>e</sub> are focal length of objective
and eyepiece.
<br><br>$$ \therefore $$ f<sub>0</sub> + f<sub>e</sub> = 60
<br><br>$$ \therefore $$ f<sub>o</su... | mcq | jee-main-2020-online-8th-january-morning-slot | 10,939 |
xVzYerlkhALt4nKGN77k9k2k5ienu4q | physics | geometrical-optics | optical-instruments | The aperture diameter of a telescope is 5m. The
separation between the moon and the earth is
4 × 10<sup>5</sup> km. With light of wavelength of
5500 $$\mathop A\limits^o $$, the minimum separation between
objects on the surface of moon, so that they are
just resolved, is close to : | [{"identifier": "A", "content": "20 m"}, {"identifier": "B", "content": "200 m"}, {"identifier": "C", "content": "600 m"}, {"identifier": "D", "content": "60 m"}] | ["D"] | null | <img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266491/exam_images/jqmo1keeva32zbonxaud.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2020 (Online) 9th January Morning Slot Physics - Geometrical Optics Question 128 English Explanation">
<br><br>$... | mcq | jee-main-2020-online-9th-january-morning-slot | 10,940 |
PQuSi4y0AXMcbczIeFjgy2xukf6jpghu | physics | geometrical-optics | optical-instruments | In a compound microscope, the magnified virtual image is formed at a distance of 25 cm from the
eye-piece. The focal length of its objective lens is 1 cm. If the magnification is 100 and the tube
length of the microscope is 20 cm, then the focal length of the eye-piece lens (in cm) is __________. | [] | null | 6.25 | L = 20, f<sub>0</sub> = 1cm, M = 100<br><br>$$M = {{{v_0}} \over {{u_0}}}\left( {1 + {D \over {{f_e}}}} \right)$$<br><br>$$ \therefore $$ $$M = {L \over {{f_0}}}\left( {1 + {D \over {{f_e}}}} \right)$$ [v<sub>0</sub> $$ \approx $$ L, u<sub>0</sub> $$ \approx $$ f<sub>0</sub>]
<br><br>$$ \Rightarrow $$ $${{20} \over 1}\... | integer | jee-main-2020-online-4th-september-morning-slot | 10,941 |
gkL0G4pOagR6hfNTXt1klulw37j | physics | geometrical-optics | optical-instruments | Given below are two statements : one is labeled as Assertion A and the other is labeled as Reason R.<br/><br/>Assertion A : For a simple microscope, the angular size of the object equals the angular size of the image.<br/><br/>Reason R : Magnification is achieved as the small object can be kept much closer to the eye t... | [{"identifier": "A", "content": "A is true but R is false"}, {"identifier": "B", "content": "A is false but R is true"}, {"identifier": "C", "content": "Both A and R are true and R is the correct explanation of A"}, {"identifier": "D", "content": "Both A and R are true but R is NOT the correct explanation of A"}] | ["C"] | null | <p>The formation of image with simple microscope is shown below.</p>
<p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l382x8d4/96a0a072-ff7e-490e-9a36-a1e6d7468b91/f7b61180-d4bb-11ec-ad28-abe411cf4979/file-1l382x8d5.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l382x8d4/96a0... | mcq | jee-main-2021-online-26th-february-evening-slot | 10,943 |
XA3LKdpyvhS3qJ4dep1kmkrjyhc | physics | geometrical-optics | optical-instruments | Your friend is having eye sight problem. She is not able to see clearly a distant uniform window mesh and it appears to her as non-uniform and distorted. The doctor diagnosed the problem as : | [{"identifier": "A", "content": "Astigmatism"}, {"identifier": "B", "content": "Myopia with Astigmatism"}, {"identifier": "C", "content": "Presbyopia with Astigmatism"}, {"identifier": "D", "content": "Myopia and Hypermetropia"}] | ["B"] | null | Myopia with Astigmatism causes distant objects to
be blurry and distorted. | mcq | jee-main-2021-online-18th-march-morning-shift | 10,944 |
1krpq6hpq | physics | geometrical-optics | optical-instruments | An object viewed from a near point distance of 25 cm, using a microscopic lens with magnification '6', gives an unresolved image. A resolved image is observed at infinite distance with a total magnification double the earlier using an eyepiece along with the given lens and a tube of length 0.6 m, if the focal length of... | [] | null | 25 | Given, magnification, M = 6<br/><br/>Since we know that magnifying power of a simple microscope is given by<br/><br/>$$M = 1 + {D \over {{f_0}}}$$<br/><br/>where, D = least distance of distinct vision = 25 cm<br/><br/>and f<sub>0</sub> = focal length of objective lens.<br/><br/>$$ \Rightarrow 6 = 1 + {D \over {{f_0}}} ... | integer | jee-main-2021-online-20th-july-morning-shift | 10,945 |
1l569j7k0 | physics | geometrical-optics | optical-instruments | <p>The aperture of the objective is 24.4 cm. The resolving power of this telescope, if a light of wavelength 2440 $$\mathop A\limits^o $$ is used to see th object will be :</p> | [{"identifier": "A", "content": "8.1 $$\\times$$ 10<sup>6</sup>"}, {"identifier": "B", "content": "10.0 $$\\times$$ 10<sup>7</sup>"}, {"identifier": "C", "content": "8.2 $$\\times$$ 10<sup>5</sup>"}, {"identifier": "D", "content": "1.0 $$\\times$$ 10<sup>$$-$$8</sup>"}] | ["C"] | null | <p>$$R.P. = {1 \over {1.22\,\lambda /a}}$$</p>
<p>$$ = {{24.4 \times {{10}^{ - 2}}} \over {1.22 \times 2440 \times {{10}^{ - 10}}}}$$</p>
<p>$$ = 8.2 \times {10^5}$$</p> | mcq | jee-main-2022-online-28th-june-morning-shift | 10,946 |
1l6jie6bw | physics | geometrical-optics | optical-instruments | <p>A microscope was initially placed in air (refractive index 1). It is then immersed in oil (refractive index 2). For a light whose wavelength in air is $$\lambda$$, calculate the change of microscope's resolving power due to oil and choose the correct option.</p> | [{"identifier": "A", "content": "Resolving power will be $$\\frac{1}{4}$$ in the oil than it was in the air."}, {"identifier": "B", "content": "Resolving power will be twice in the oil than it was in the air."}, {"identifier": "C", "content": "Resolving power will be four times in the oil than it was in the air."}, {"i... | ["B"] | null | <p>The resolving power of a microscope is determined by the Rayleigh criterion, which states that it is inversely proportional to the wavelength of light used in the medium in which the microscopy is being performed. Mathematically, the resolving power (RP) can be represented as:</p>
<p>$ RP = \frac{1}{\lambda_n} $</p... | mcq | jee-main-2022-online-27th-july-morning-shift | 10,947 |
1l6mativv | physics | geometrical-optics | optical-instruments | <p>In normal adujstment, for a refracting telescope, the distance between objective and eye piece is $$30 \mathrm{~cm}$$. The focal length of the objective, when the angular magnification of the telescope is 2 , will be :</p> | [{"identifier": "A", "content": "20 cm"}, {"identifier": "B", "content": "30 cm"}, {"identifier": "C", "content": "10 cm"}, {"identifier": "D", "content": "15 cm"}] | ["A"] | null | <p>$$\because$$ $$m = {{{f_o}} \over {{f_e}}}$$</p>
<p>$$ \Rightarrow 2 = {{{f_o}} \over {{f_e}}}$$ ...... (i)</p>
<p>and, $$l = {f_o} + {f_e}$$</p>
<p>$$ \Rightarrow 30 = {f_o} + {f_e}$$ ..... (ii)</p>
<p>$$ \Rightarrow 30 = {f_o} + {{{f_o}} \over 2}$$</p>
<p>$$ \Rightarrow 30 \times {2 \over 3} = {f_o}$$</p>
<p>$$ \R... | mcq | jee-main-2022-online-28th-july-morning-shift | 10,948 |
1ldsa5twm | physics | geometrical-optics | optical-instruments | <p>A scientist is observing a bacteria through a compound microscope. For better analysis and to improve its resolving power he should. (Select the best option)</p> | [{"identifier": "A", "content": "Decrease the focal length of the eye piece."}, {"identifier": "B", "content": "Increase the wave length of the light"}, {"identifier": "C", "content": "Increase the refractive index of the medium between the object and objective lens"}, {"identifier": "D", "content": "Decrease the diame... | ["C"] | null | <p>Resolving power of microscope $$ = \left( {{{2n\sin \theta } \over \lambda }} \right)$$</p>
<p>$$n\sin \theta $$ = Numerical aperture</p>
<p>$$n$$ is the refractive index of medium.</p> | mcq | jee-main-2023-online-29th-january-evening-shift | 10,949 |
1lh00tbxb | physics | geometrical-optics | optical-instruments | <p>In a reflecting telescope, a secondary mirror is used to:</p> | [{"identifier": "A", "content": "make chromatic aberration zero"}, {"identifier": "B", "content": "remove spherical aberration"}, {"identifier": "C", "content": "reduce the problem of mechanical support"}, {"identifier": "D", "content": "move the eyepiece outside the telescopic tube"}] | ["D"] | null | <p>Reflecting telescopes, also known as reflectors, use a set of mirrors instead of lenses to gather and focus light. The primary mirror (usually a concave mirror) gathers the incoming light and reflects it to a focus point. The secondary mirror is used to redirect this focused light out to where it can be conveniently... | mcq | jee-main-2023-online-8th-april-morning-shift | 10,950 |
jaoe38c1lsc38c3k | physics | geometrical-optics | optical-instruments | <p>Identify the physical quantity that cannot be measured using spherometer :</p> | [{"identifier": "A", "content": "Radius of curvature of concave surface\n"}, {"identifier": "B", "content": "Specific rotation of liquids\n"}, {"identifier": "C", "content": "Thickness of thin plates\n"}, {"identifier": "D", "content": "Radius of curvature of convex surface\n"}] | ["B"] | null | <p>Spherometer can be used to measure curvature of surface.</p> | mcq | jee-main-2024-online-27th-january-morning-shift | 10,951 |
4i0m2CL34d4CxsWa | physics | geometrical-optics | reflection-of-light | If two mirrors are kept at $${60^ \circ }$$ to each other, then the number of images formed by them is | [{"identifier": "A", "content": "$$5$$ "}, {"identifier": "B", "content": "$$6$$ "}, {"identifier": "C", "content": "$$7$$ "}, {"identifier": "D", "content": "$$8$$ "}] | ["A"] | null | <b>KEY CONCEPT :</b> When two plane mirrors are inclined a each other at an angle $$\theta $$ then the number of the images of a point object placed between the plane mirrors is
<br><br>$${{{{360}^ \circ }} \over \theta } - 1,\,\,if{{{{360}^ \circ }} \over \theta }$$ is even
<br><br>$$\therefore$$ Number of images for... | mcq | aieee-2002 | 10,952 |
LKUoc372hiY6EZIb | physics | geometrical-optics | reflection-of-light | To get three images of a single object, one should have two plane mirrors at an angle of | [{"identifier": "A", "content": "$${60^ \\circ }$$ "}, {"identifier": "B", "content": "$${90^ \\circ }$$"}, {"identifier": "C", "content": "$${120^ \\circ }$$"}, {"identifier": "D", "content": "$${30^ \\circ }$$"}] | ["B"] | null | When $$\theta = {90^ \circ }$$ then $${{360} \over \theta } = {{360} \over {90}} = 4$$
<br><br>is an even number. The number of images formed is given by
<br><br>$$n = {{360} \over \theta } - 1 = {{360} \over {90}} - 1 = 4 - 1 = 3$$ | mcq | aieee-2003 | 10,953 |
PJKzdsiV6Xy5Eyi0 | physics | geometrical-optics | reflection-of-light | A car is fitted with a convex side-view mirror of focal length $$20$$ $$cm$$. A second car $$2.8m$$ behind the first car is overtaking the first car at a relative speed of $$15$$ $$m/s$$. The speed of the image of the second car as seen in the mirror of the first one is : | [{"identifier": "A", "content": "$${1 \\over {15}}\\,m/s$$ "}, {"identifier": "B", "content": "$$10\\,m/s$$ "}, {"identifier": "C", "content": "$$15\\,m/s$$ "}, {"identifier": "D", "content": "$${1 \\over {10}}\\,m/s$$"}] | ["A"] | null | From mirror formula
<br><br>$${1 \over v} + {1 \over u} = {1 \over f}\,\,\,$$
<br><br>so, $$\,\,\,{{dv} \over {dt}} = - {{{v^2}} \over {{u^2}}}\left( {{{du} \over {dt}}} \right)$$
<br><br>$$ \Rightarrow {{dv} \over {dt}} = - {\left( {{f \over {u - f}}} \right)^2}{{du} \over {dt}}$$
<br><br>$$ \Rightarrow {{dv} \over... | mcq | aieee-2011 | 10,954 |
cm33ZP9NVEHhyWenl35Rp | physics | geometrical-optics | reflection-of-light | A hemispherical glass body of radius 10 cm and refractive index 1.5 is silvered on its curved surface. A small air bubble is 6 cm below the flat surface inside it along the axis. The position of the image of the air bubble made by the mirror is seen :
<br/><br/><img src="data:image/png;base64,UklGRgYPAABXRUJQVlA4IPoOA... | [{"identifier": "A", "content": "14 cm below flat surface"}, {"identifier": "B", "content": "30 cm below flat surface"}, {"identifier": "C", "content": "20 cm below flat surface"}, {"identifier": "D", "content": "16 cm below flat surface"}] | ["C"] | null | <img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l82xk1zi/17df040e-401f-4ec7-b321-7d5663e74273/254462e0-34e4-11ed-b84c-a3c7c2456516/file-1l82xk1zj.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l82xk1zi/17df040e-401f-4ec7-b321-7d5663e74273/254462e0-34e4-11ed-b84c-a3c7c2456516/fi... | mcq | jee-main-2016-online-10th-april-morning-slot | 10,955 |
FFYOyAv0c2JuagRl6tOda | physics | geometrical-optics | reflection-of-light | A particle is oscillating on the $$X$$-axis with an amplitude $$2$$ $$cm$$ about the point $${x_0} = 10\,cm,$$ with a frequency $$\omega $$. A concave mirror of local length $$5$$ $$cm$$ is placed at the origin (see figure).
<br/><br/><img src="data:image/png;base64,UklGRkQNAABXRUJQVlA4IDgNAABwWwCdASoAA74APm02mUikIyKhI... | [{"identifier": "A", "content": "The image executs periodic motoin."}, {"identifier": "B", "content": "The image executes non-periodic motion."}, {"identifier": "C", "content": "The turning points of the image are asymmetric w.r.t. the image of the point at $$x=10$$ $$cm$$."}, {"identifier": "D", "content": "The distan... | ["B"] | null | When object is at 8 cm,
<br><br>the image distance (v<sub>1</sub>) = $${{F \times 4} \over {u - f}}$$ = $${{5 \times 8} \over {8 - 5}}$$ = $$-$$ $${{40} \over 3}$$ cm
<br><br>When object is at 12 cm,
<br><br>the image distance (v<sub>2</sub>) = $${{f \times 4} \over {u - f}} = {{5 \times 12} \over {12 - 5}} = $$ $$... | mcq | jee-main-2018-online-15th-april-morning-slot | 10,956 |
f9JGzCf2YLp4B21UEXjgy2xukev2x02j | physics | geometrical-optics | reflection-of-light | <img src="data:image/png;base64,UklGRjwJAABXRUJQVlA4IDAJAADQQACdASpnAd8APm02mEikIyKhJBLJYIANiWlu4W/RG/OZ8U/5jtj/yX5Q9cr6C9tf6huQHbmfVfzH+j+/r89/x38z8YeAR6y/UvuAPDurr6B3d7/d/1f+sePZ/Xf0D1U+qvmq/qT/RvfH+7/pL/K/Ou8e9gj8b/7b+V/lL8GP+//L/6h6rfov9O/7D7sX/N/n/9d97fqY/1sG4xB+VpLtlnZJjD3Q7JMW5QFNnp2Bn5Wku2WdkjhPeI3WZcDPZlYa/p6h... | [{"identifier": "A", "content": "Inverted, real and unmagnified"}, {"identifier": "B", "content": "Inverted, real and magnified"}, {"identifier": "C", "content": "Erect, virtual and magnified"}, {"identifier": "D", "content": "Erect, virtual and unmagnified"}] | ["A"] | null | f = $$ - {8 \over 2}$$ = -4 cm
<br><br>u = –10 cm
<br><br>v = ?
<br><br>Using mirror formula
<br><br>$${1 \over v} + {1 \over u} = {1 \over f}$$
<br><br>$$ \Rightarrow $$ $${1 \over v} + {1 \over { - 10}} = {1 \over { - 4}}$$
<br><br>$$ \Rightarrow $$ v = $${{ - 20} \over 3}$$
<br><br>m = $${{ - \left( { - {{20} \over ... | mcq | jee-main-2020-online-2nd-september-morning-slot | 10,961 |
OPFab0XbMFO7Q3wlGrjgy2xukf3w6c3o | physics | geometrical-optics | reflection-of-light | When an object is kept at a distance of 30 cm from a concave mirror, the image is formed at a
distance of 10 cm from the mirror. If the object is moved with a speed of 9 cms<sup>–1</sup>, the speed
(in cms<sup>–1</sup>) with which image moves at that instant is ____. | [] | null | 1 | V<sub>I</sub> = Velocity of image with respect to mirror<br><br>V<sub>0</sub> = Velocity of object with respect to mirror<br><br>$$|\overrightarrow {{V_I}}| = |- {{{v^2}} \over {{u^2}}}\overrightarrow {{V_0}} |$$<br><br>$$ = | - {{10 \times 10} \over {30 \times 30}} \times 9|$$<br><br>$$ = 1$$ cm/s
| integer | jee-main-2020-online-3rd-september-evening-slot | 10,962 |
lLdDTLTDsxu0Nc7QbW1klulicnz | physics | geometrical-optics | reflection-of-light | The incident ray, reflected ray and the outward drawn normal are denoted by the unit vectors $$\overrightarrow a $$, $$\overrightarrow b $$ and $$\overrightarrow c $$ respectively. Then choose the correct relation for these vectors. | [{"identifier": "A", "content": "$$\\overrightarrow b $$ = $$\\overrightarrow a $$ + 2$$\\overrightarrow c $$"}, {"identifier": "B", "content": "$$\\overrightarrow b $$ = $$\\overrightarrow a $$ $$-$$ 2 ($$\\overrightarrow a $$ . $$\\overrightarrow c $$)$$\\overrightarrow c $$"}, {"identifier": "C", "content": "$$\\ove... | ["B"] | null | <picture><source media="(max-width: 1363px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266980/exam_images/y6ayytt1koqi6bkoph3w.webp"><source media="(max-width: 320px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266291/exam_images/g52xaemawbd6avoygguj.webp"><source media="(max-wi... | mcq | jee-main-2021-online-26th-february-evening-slot | 10,965 |
THPFuQY3PFoxFTm35v1klunu0he | physics | geometrical-optics | reflection-of-light | A point source of light S, placed at a distance 60cm in front of the centre of a plane mirror of width 50 cm, hangs vertically on a wall. A man walks in front of the mirror along a line parallel to the mirror at a distance 1.2 m from it (see in the figure). The distance between the extreme points where he can see the ... | [] | null | 150 | <p>Given, length of mirror, m = 50 cm = 50 $$\times$$ 10<sup>$$-$$2</sup> m</p>
<p>Distance of source from mirror, d = 60 cm = 60 $$\times$$ 10<sup>$$-$$2</sup> m</p>
<p>Distance of man from mirror, d<sub>m</sub> = 1.2 m</p>
<p>By using the concept of ray diagram of plane mirror shown below</p>
<p><img src="https://app... | integer | jee-main-2021-online-26th-february-evening-slot | 10,966 |
1kta8r120 | physics | geometrical-optics | reflection-of-light | Car B overtakes another car A at a relative speed of 40 ms<sup>$$-$$1</sup>. How fast will the image of car B appear to move in the mirror of focal length 10 cm fitted in car A, when the car B is 1.9 m away from the car A? | [{"identifier": "A", "content": "4 ms<sup>$$-$$1</sup>"}, {"identifier": "B", "content": "0.2 ms<sup>$$-$$1</sup>"}, {"identifier": "C", "content": "40 ms<sup>$$-$$1</sup>"}, {"identifier": "D", "content": "0.1 ms<sup>$$-$$1</sup>"}] | ["D"] | null | Here, $${1 \over v} + {1 \over u} = {1 \over f}$$ .......(1)
<br/><br/>$$ \Rightarrow $$ $${1 \over v} + {1 \over { - 190}} = {1 \over {10}}$$
<br/><br/>$$ \Rightarrow $$ v = $${{19} \over 2}$$
<br/><br/>Differentiating equation (1) w.r.t t we get
<br/><br/>$$ - {1 \over {{v^2}}}\left( {{{dv} \over {dt}}} \right) - {1 ... | mcq | jee-main-2021-online-26th-august-morning-shift | 10,967 |
1ktdz3bkj | physics | geometrical-optics | reflection-of-light | An object is placed beyond the centre of curvature C of the given concave mirror. If the distance of the object is d<sub>1</sub> from C and the distance of the image formed is d<sub>2</sub> from C, the radius of curvature of this mirror is : | [{"identifier": "A", "content": "$${{2{d_1}{d_2}} \\over {{d_1} - {d_2}}}$$"}, {"identifier": "B", "content": "$${{2{d_1}{d_2}} \\over {{d_1} + {d_2}}}$$"}, {"identifier": "C", "content": "$${{{d_1}{d_2}} \\over {{d_1} + {d_2}}}$$"}, {"identifier": "D", "content": "$${{{d_1}{d_2}} \\over {{d_1} - {d_2}}}$$"}] | ["A"] | null | Using Newton's formula<br><br>$$(f + {d_1})(f - {d_2}) = {f^2}$$<br><br>$${f^2} + f{d_1} - f{d_2} - {d_1}{d_2} = {f^2}$$<br><br>$$f = {{{d_1}{d_2}} \over {{d_1} - {d_2}}}$$<br><br>$$\therefore$$ $$R = {{2{d_1}{d_2}} \over {{d_1} - {d_2}}}$$ | mcq | jee-main-2021-online-27th-august-morning-shift | 10,968 |
1l58d37nr | physics | geometrical-optics | reflection-of-light | <p>A light ray is incident, at an incident angle $$\theta$$<sub>1</sub>, on the system of tow plane mirrors M<sub>1</sub> and M<sub>2</sub> having an inclination angle 75$$^\circ$$ between them (as shown in figure). After reflecting from mirror M<sub>1</sub> it gets reflected back by the mirror M<sub>2</sub> with an an... | [] | null | 210 | <img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l7t9ex9y/cbd8b6a4-a6c1-4bc9-beed-258eb49c338b/ada38960-2f92-11ed-89c0-3f04a2c336c7/file-1l7t9ex9z.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l7t9ex9y/cbd8b6a4-a6c1-4bc9-beed-258eb49c338b/ada38960-2f92-11ed-89c0-3f04a2c336c7/fi... | integer | jee-main-2022-online-26th-june-morning-shift | 10,970 |
1l6nu3czx | physics | geometrical-optics | reflection-of-light | <p>An object 'O' is placed at a distance of $$100 \mathrm{~cm}$$ in front of a concave mirror of radius of curvature $$200 \mathrm{~cm}$$ as shown in the figure. The object starts moving towards the mirror at a speed $$2 \mathrm{~cm} / \mathrm{s}$$. The position of the image from the mirror after $$10 \mathrm{~s}$$ wil... | [] | null | 400 | <p>The object after 10 second will be at $$u = - 80$$ cm.</p>
<p>So $${1 \over v} - {1 \over {80}} = - {1 \over {100}} $$
<br/><br/>$$\Rightarrow v = {{8000} \over { + 20}} = 400$$ cm</p> | integer | jee-main-2022-online-28th-july-evening-shift | 10,971 |
1ldnx5spy | physics | geometrical-optics | reflection-of-light | <p>Two objects A and B are placed at 15 cm and 25 cm from the pole in front of a concave mirror having radius of curvature 40 cm. The distance between images formed by the mirror is _______________.</p> | [{"identifier": "A", "content": "60 cm"}, {"identifier": "B", "content": "40 cm"}, {"identifier": "C", "content": "160 cm"}, {"identifier": "D", "content": "100 cm"}] | ["C"] | null | <img src="https://app-content.cdn.examgoal.net/fly/@width/image/1ldwx1iyu/3e34de25-f3d2-4bb2-9e86-861b45dcf7b0/ba635e60-a85e-11ed-b881-afa398664315/file-1ldwx1iyv.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1ldwx1iyu/3e34de25-f3d2-4bb2-9e86-861b45dcf7b0/ba635e60-a85e-11ed-b881-afa398664315/fi... | mcq | jee-main-2023-online-1st-february-evening-shift | 10,972 |
1ldoh9v63 | physics | geometrical-optics | reflection-of-light | <p>A thin cylindrical rod of length $$10 \mathrm{~cm}$$ is placed horizontally on the principle axis of a concave mirror of focal length $$20 \mathrm{~cm}$$. The rod is placed in a such a way that mid point of the rod is at $$40 \mathrm{~cm}$$ from the pole of mirror. The length of the image formed by the mirror will b... | [] | null | 32 | <img src="https://app-content.cdn.examgoal.net/fly/@width/image/1le7cg4sv/5786aa17-f64f-438a-b4a2-840791af1975/d0038df0-ae1a-11ed-89cc-995c981e21dd/file-1le7cg4sw.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1le7cg4sv/5786aa17-f64f-438a-b4a2-840791af1975/d0038df0-ae1a-11ed-89cc-995c981e21dd/fi... | integer | jee-main-2023-online-1st-february-morning-shift | 10,973 |
1ldr2u49i | physics | geometrical-optics | reflection-of-light | <p>In an experiment for estimating the value of focal length of converging mirror, image of an object placed at $$40 \mathrm{~cm}$$ from the pole of the mirror is formed at distance $$120 \mathrm{~cm}$$ from the pole of the mirror. These distances are measured with a modified scale in which there are 20 small divisions... | [] | null | 32 | <p>$${1 \over v} + {1 \over u} = {1 \over f}$$ ...... (1)</p>
<p>$$ \Rightarrow - {1 \over {{f^2}}}df = - {1 \over {{v^2}}}dv - {1 \over {{u^2}}}du$$</p>
<p>$$ \Rightarrow {{df} \over {{f^2}}} = {{dv} \over {{v^2}}} + {{du} \over {{u^2}}}$$ ..... (2)</p>
<p>From (1) : $$ - {1 \over {120}} - {1 \over {40}} = {1 \over ... | integer | jee-main-2023-online-30th-january-morning-shift | 10,974 |
1ldtxe5ew | physics | geometrical-optics | reflection-of-light | <p>The light rays from an object have been reflected towards an observer from a standard flat mirror, the image observed by the observer are :-</p>
<p>A. Real</p>
<p>B. Erect</p>
<p>C. Smaller in size then object</p>
<p>D. Laterally inverted</p>
<p>Choose the most appropriate answer from the options given below :</p> | [{"identifier": "A", "content": "B and D only"}, {"identifier": "B", "content": "A, C, and D only"}, {"identifier": "C", "content": "A and D only"}, {"identifier": "D", "content": "B and C only"}] | ["A"] | null | Plane mirror forms erect, same sized, laterally
inverted and virtual image of real object. | mcq | jee-main-2023-online-25th-january-evening-shift | 10,975 |
1lgswr535 | physics | geometrical-optics | reflection-of-light | <p>When one light ray is reflected from a plane mirror with $$30^{\circ}$$ angle of reflection, the angle of deviation of the ray after reflection is :</p> | [{"identifier": "A", "content": "$$140^{\\circ}$$"}, {"identifier": "B", "content": "$$130^{\\circ}$$"}, {"identifier": "C", "content": "$$120^{\\circ}$$"}, {"identifier": "D", "content": "$$110^{\\circ}$$"}] | ["C"] | null | When a light ray is reflected from a plane mirror, the angle of incidence (i) is equal to the angle of reflection (r). In this case, the angle of reflection is given as $$30^{\circ}$$, so the angle of incidence is also $$30^{\circ}$$.
<br/><br/>
The angle of deviation (D) is the angle between the incident ray and the r... | mcq | jee-main-2023-online-11th-april-evening-shift | 10,976 |
1lgsxeduk | physics | geometrical-optics | reflection-of-light | <p>As shown in the figure, a plane mirror is fixed at a height of $$50 \mathrm{~cm}$$ from the bottom of tank containing water $$\left(\mu=\frac{4}{3}\right)$$. The height of water in the tank is $$8 \mathrm{~cm}$$. A small bulb is placed at the bottom of the water tank. The distance of image of the bulb formed by mirr... | [] | null | 98 | <img src="https://app-content.cdn.examgoal.net/fly/@width/image/1lib86l1c/fbd1eeed-1fb2-46ee-82d6-14a80acbd041/220f8000-ff6e-11ed-9ba6-21b4d8b62881/file-1lib86l1d.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1lib86l1c/fbd1eeed-1fb2-46ee-82d6-14a80acbd041/220f8000-ff6e-11ed-9ba6-21b4d8b62881/fi... | integer | jee-main-2023-online-11th-april-evening-shift | 10,977 |
1lh02lwba | physics | geometrical-optics | reflection-of-light | <p>Two vertical parallel mirrors A and B are separated by $$10 \mathrm{~cm}$$. A point object $$\mathrm{O}$$ is placed at a distance of $$2 \mathrm{~cm}$$ from mirror $$\mathrm{A}$$. The distance of the second nearest image behind mirror A from the mirror $$\mathrm{A}$$ is _________ $$\mathrm{cm}$$.</p>
<p><img src="da... | [] | null | 18 | <img src="https://app-content.cdn.examgoal.net/fly/@width/image/6y3zli1ljhovk3z/02f0a59f-8aa8-41cc-9b35-ac153135de98/55ea41f0-16c8-11ee-bdcc-8182ebb779d2/file-6y3zli1ljhovk40.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/6y3zli1ljhovk3z/02f0a59f-8aa8-41cc-9b35-ac153135de98/55ea41f0-16c8-11ee-bd... | integer | jee-main-2023-online-8th-april-morning-shift | 10,979 |
jaoe38c1lsflt02d | physics | geometrical-optics | reflection-of-light | <p>If the distance between object and its two times magnified virtual image produced by a curved mirror is $$15 \mathrm{~cm}$$, the focal length of the mirror must be:</p> | [{"identifier": "A", "content": "$$-10$$ cm"}, {"identifier": "B", "content": "$$-12$$ cm"}, {"identifier": "C", "content": "15 cm"}, {"identifier": "D", "content": "10/3 cm"}] | ["A"] | null | <p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/6y3zli1lsr7hjzk/4e6a2686-6c33-409b-bbbb-9246b5f9730b/1e337700-ce32-11ee-9412-cd4f9c6f2c40/file-6y3zli1lsr7hjzl.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/6y3zli1lsr7hjzk/4e6a2686-6c33-409b-bbbb-9246b5f9730b/1e337700-ce32-11ee... | mcq | jee-main-2024-online-29th-january-evening-shift | 10,981 |
A8p8zu1JxHYskZrA | physics | geometrical-optics | refraction,-tir-and-prism | Which of the following is used in optical fibres? | [{"identifier": "A", "content": "total internal reflection "}, {"identifier": "B", "content": "scattering "}, {"identifier": "C", "content": "diffracttion"}, {"identifier": "D", "content": "refraction "}] | ["A"] | null | <p>Optical fibers work on the principle of total internal reflection. When light is transmitted through the fiber, it is reflected off the inner walls of the fiber in such a way that it remains within the fiber, allowing it to carry the light signal over great distances with minimal loss. </p>
<p>So, the correct answer... | mcq | aieee-2002 | 10,982 |
FvFLxhWdaxtqxTHd | physics | geometrical-optics | refraction,-tir-and-prism | A light ray is incident perpendicularly to one face of a $${90^ \circ }$$ prism and is totally internally reflected at the glass-air interface. If the angle of reflection is $${45^ \circ }$$, we conclude that the refractive index $$n$$
<img src="data:image/png;base64,UklGRtwJAABXRUJQVlA4INAJAADwZwCdASoGAnUBP4HA12Y2L7in... | [{"identifier": "A", "content": "$$n > {1 \\over {\\sqrt 2 }}$$ "}, {"identifier": "B", "content": "$$n > \\sqrt 2 $$"}, {"identifier": "C", "content": "$$n < {1 \\over {\\sqrt 2 }}$$ "}, {"identifier": "D", "content": "$$n < \\sqrt 2 $$ "}] | ["B"] | null | The incident angle is $${45^ \circ }$$
<br><br>Incident angle $$ > $$ critical angle, $$i > {i_c}$$
<br><br>$$\therefore$$ $$\sin i > \sin {i_c}$$ or $$\sin \,45\, > \sin \,{i_c},$$ $$\sin {i_c} = {1 \over n}$$
<br><br>$$\therefore$$ $$\sin \,{45^ \circ } > {1 \over n}$$ or $${1 \over {\sqrt 2 }} > {... | mcq | aieee-2004 | 10,983 |
pzFBfp35IyZlQIsH | physics | geometrical-optics | refraction,-tir-and-prism | A fish looking up through the water sees the outside world contained in a circular horizon. If the refractive index of water is $${4 \over 3}$$ and the fish is $$12$$ $$cm$$ below the surface, the radius of this circle in $$cm$$ is | [{"identifier": "A", "content": "$${{36} \\over {\\sqrt 7 }}$$ "}, {"identifier": "B", "content": "$${36\\sqrt 7 }$$ "}, {"identifier": "C", "content": "$${4\\sqrt 5 }$$"}, {"identifier": "D", "content": "$${36\\sqrt 5 }$$"}] | ["A"] | null | $$\sin {\theta _c} = {1 \over \mu } = {3 \over 4}$$
<br><br>or $$\tan {\theta _c} = {3 \over {\sqrt {16 - 9} }} = {3 \over {\sqrt 7 }} = {R \over {12}}$$
<br><br><img class="question-image" src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266373/exam_images/uowdivblw0wvz9kswkcu.webp" loading="lazy" alt="AIEE... | mcq | aieee-2005 | 10,984 |
xXtUOzMFWNL9kHRX | physics | geometrical-optics | refraction,-tir-and-prism | The refractive index of a glass is $$1.520$$ for red light and $$1.525$$ for blue light. Let $${D_1}$$ and $${D_2}$$ be angles of minimum deviation for red and blue light respectively in a prism of this glass. Then, | [{"identifier": "A", "content": "$${D_1} < {D_2}$$ "}, {"identifier": "B", "content": "$${D_1} = {D_2}$$ "}, {"identifier": "C", "content": "$${D_1}$$ can be less than or greater than $${D_2}$$ depending upon the angle of prism"}, {"identifier": "D", "content": "$${D_1} > {D_2}$$ "}] | ["A"] | null | For a thin prism, $$D = \left( {\mu - 1} \right)A$$
<br><br>Since $${\lambda _b} < {\lambda _r} \Rightarrow {\mu _r} < {\mu _b} \Rightarrow {D_1} < {D_2}$$ | mcq | aieee-2006 | 10,985 |
C9kEBfRQHLEvadk8 | physics | geometrical-optics | refraction,-tir-and-prism | A transparent solid cylindrical rod has a refractive index of $${2 \over {\sqrt 3 }}.$$ It is surrounded by air. A light ray is incident at the mid-point of one end of the rod as shown in the figure.
<img src="data:image/png;base64,UklGRuQJAABXRUJQVlA4INgJAADwYgCdASrZAucAP4HA3GQ2Mi2mofPposAwCWlu/HyYhUpHZ19/qJ/n+4PHXs6P... | [{"identifier": "A", "content": "$${\\sin ^{ - 1}}\\left( {{\\raise0.5ex\\hbox{$\\scriptstyle {\\sqrt 3 }$}\n\\kern-0.1em/\\kern-0.15em\n\\lower0.25ex\\hbox{$\\scriptstyle 2$}}} \\right)$$ "}, {"identifier": "B", "content": "$${\\sin ^{ - 1}}\\left( {{\\raise0.5ex\\hbox{$\\scriptstyle 2$}\n\\kern-0.1em/\\kern-0.15em\n\... | ["C"] | null | <img class="question-image" src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266005/exam_images/zsgvcjuhfhmns2t5l9pk.webp" loading="lazy" alt="AIEEE 2009 Physics - Geometrical Optics Question 172 English Explanation">
<br><br>Applying Snell's law at $$Q$$
<br><br>$$n = {{\sin {{90}^ \circ }} \over {\sin C}} ... | mcq | aieee-2009 | 10,986 |
f24ncbwOBEaRtFtN | physics | geometrical-optics | refraction,-tir-and-prism | An initially parallel cylindrical beam travels in a medium of refractive index $$\mu \left( I \right) = {\mu _0} + {\mu _2}\,I,$$ where $${\mu _0}$$ and $${\mu _2}$$ are positive constants and $$I$$ is the intensity of the light beam. The intensity of the beam is decreasing with increasing radius.
<p>The speed of light... | [{"identifier": "A", "content": "minimum on the axis of the beam "}, {"identifier": "B", "content": "the same everywhere in the beam "}, {"identifier": "C", "content": "directly proportional to the intensity $$I$$ "}, {"identifier": "D", "content": "maximum on the axis of the beam "}] | ["A"] | null | The speed of light $$(c)$$ in a medium of refractive index $$\left( \mu \right)$$ is given by
<br><br>$$\mu = {{{c_0}} \over c},$$ where $${c_0}$$ is the speed of light in vacuum
<br><br>$$\therefore$$ $$c = {{{c_0}} \over \mu } = {{{c_0}} \over {{\mu _0} + {\mu _2}\left( I \right)}}$$
<br><br>As $$I$$ is decreasing ... | mcq | aieee-2010 | 10,987 |
SyKBYYXIU01IaDI2 | physics | geometrical-optics | refraction,-tir-and-prism | An initially parallel cylindrical beam travels in a medium of refractive index $$\mu \left( I \right) = {\mu _0} + {\mu _2}\,I,$$ where $${\mu _0}$$ and $${\mu _2}$$ are positive constants and $$I$$ is the intensity of the light beam. The intensity of the beam is decreasing with increasing radius.
<p>As the beam enters... | [{"identifier": "A", "content": "diverge "}, {"identifier": "B", "content": "converge "}, {"identifier": "C", "content": "diverge near the axis and converge near the periphery "}, {"identifier": "D", "content": "travel as a cylindrical beam "}] | ["B"] | null | In the medium, the refractive index will decreases from the axis forwards the periphery of the beam.
<br><br>Therefore, the beam will move as one move from the axis to the periphery and hence the beam will converge.
<br><br><img class="question-image" src="https://imagex.cdn.examgoal.net/KdjDfWp5V9zzsn0Lo/QBvMvL102dqdb... | mcq | aieee-2010 | 10,988 |
6tgODWvGvNb9i7ec | physics | geometrical-optics | refraction,-tir-and-prism | The graph between angle of deviation $$\left( \delta \right)$$ and angle of incidence $$(i)$$ for a triangular prism is represented by | [{"identifier": "A", "content": "<img class=\"question-image\" src=\"https://res.cloudinary.com/dckxllbjy/image/upload/v1734265022/exam_images/eh8a7mmzosxm3hkw2dzx.webp\" loading=\"lazy\" alt=\"JEE Main 2013 (Offline) Physics - Geometrical Optics Question 171 English Option 1\"> "}, {"identifier": "B", "content": "<img... | ["C"] | null | For the prism as the angle of incidence $$(i)$$ increase, the angle of deviation $$\left( \delta \right)$$ first decreases goes to minimum value and then increases. | mcq | jee-main-2013-offline | 10,990 |
srWimqDukx0JqubM | physics | geometrical-optics | refraction,-tir-and-prism | A green light is incident from the water to the air - water interface at the critical angle $$\left( \theta \right)$$. Select the correct statement. | [{"identifier": "A", "content": "The entire spectrum of visible light will come out of the water at an angle of $${90^ \\circ }$$ to the normal. "}, {"identifier": "B", "content": "The spectrum of visible light whose frequency is less than that of green light will come out to the air medium. "}, {"identifier": "C", "c... | ["B"] | null | For critical angle $${\theta _c},$$
<br><br>$$\sin {\theta _c} = {1 \over \mu }$$
<br><br>For greater wavelength or lesser frequency $$\mu $$ is less.
<br><br><img class="question-image" src="https://imagex.cdn.examgoal.net/hhTdAjobHgPLKc3tR/b9n6f2hvnjvtQP2Ebix5jGOwiVq64/jnwPywrJPbbmZ0FUGzPY0Q/image.svg" loading="lazy"... | mcq | jee-main-2014-offline | 10,991 |
5nUCigmx53x8c8J4 | physics | geometrical-optics | refraction,-tir-and-prism | Monochromatic light is incident on a glass prism of angle $$A$$. If the refractive index of the material of the prism is $$\mu $$, a ray, incident at an angle $$\theta $$. on the face $$AB$$ would get transmitted through the face $$AC$$ of the prism provided :
<br/><br/><img src="data:image/png;base64,UklGRrQOAABXRUJQ... | [{"identifier": "A", "content": "$$\\theta > {\\cos ^{ - 1}}\\left[ {\\mu \\,\\sin \\left( {A + {{\\sin }^{ - 1}}} \\right.\\left( {{1 \\over \\mu }} \\right)} \\right]$$ "}, {"identifier": "B", "content": "$$\\theta < {\\cos ^{ - 1}}\\left[ {\\mu \\,\\sin \\left( {A + {{\\sin }^{ - 1}}} \\right.\\left( {{1 \\o... | ["C"] | null | When $${r_2} = C,\,\angle {N_2}Rc = {90^ \circ }$$
<br><br>Where $$C = $$ critical angle
<br><br>As $$\sin C = {1 \over v} = \sin {r_2}$$
<br><br><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l91fl11x/e4a00f10-3331-489e-b3bb-b76cfeb2f90f/4ac28540-47dd-11ed-9a49-57ec402e0bd4/file-1l91fl11y.png?format=... | mcq | jee-main-2015-offline | 10,992 |
UxSgOI6kOexcAJNd | physics | geometrical-optics | refraction,-tir-and-prism | In an experiment for determination of refractive index of glass of a prism by $$i - \delta ,$$ plot it was found thata ray incident at angle $${35^ \circ }$$, suffers a deviation of $${40^ \circ }$$ and that it emerges at angle $${79^ \circ }.$$ In that case which of the following is closest to the maximum possible val... | [{"identifier": "A", "content": "$$1.7$$ "}, {"identifier": "B", "content": "$$1.8$$ "}, {"identifier": "C", "content": "$$1.5$$ "}, {"identifier": "D", "content": "$$1.6$$ "}] | ["C"] | null | We know that $$i + e - A = \delta $$
<br><br>$${35^ \circ } + {79^ \circ } - A = {40^ \circ }$$
<br><br>$$\therefore$$ $$A = {74^ \circ }$$
<br><br>But $$\mu = {{\sin \left( {{{A + {\delta _m}} \over 2}} \right)} \over {\sin A/2}} = {{\sin \left( {{{74 + \delta } \over 2}} \right)} \over {\sin {{74} \over 2}}}$$
<br><... | mcq | jee-main-2016-offline | 10,993 |
J2twtaEF5XBq0vojzUch7 | physics | geometrical-optics | refraction,-tir-and-prism | To determine refractive index of glass slab using a travelling microscope, minimum number of readings required are : | [{"identifier": "A", "content": "Two "}, {"identifier": "B", "content": "Three "}, {"identifier": "C", "content": "Four "}, {"identifier": "D", "content": "Five "}] | ["B"] | null | <p>The refractive index is</p>
<p>$$\mu = {{{\mathop{\rm Real}\nolimits} \,depth} \over {Apparent\,depth}} = {{{\mathop{\rm Reading}\nolimits} \,3 - Reading\,1} \over {{\mathop{\rm Reading}\nolimits} \,3 - Reading\,2}}$$</p>
<p>Therefore, the minimum of three readings are required.</p> | mcq | jee-main-2016-online-10th-april-morning-slot | 10,994 |
qqfeaDwzdvRSZVAJXpJNG | physics | geometrical-optics | refraction,-tir-and-prism | Let the refractive index of a denser medium with respect to a rarer medium be n<sub>12</sub> and its critical angle be θ<sub>C</sub> . At an angle of incidence A when light is travelling from
denser medium to rarer medium, a part of the light is reflected and the rest is refracted and the angle between reflected and re... | [{"identifier": "A", "content": "$${1 \\over {{{\\cos }^{ - 1}}\\left( {\\sin {\\theta _C}} \\right)}}$$ "}, {"identifier": "B", "content": "$${1 \\over {{{\\tan }^{ - 1}}\\left( {\\sin {\\theta _C}} \\right)}}$$ "}, {"identifier": "C", "content": "$${\\cos ^{ - 1}}\\,\\left( {\\sin {\\theta _C}} \\right)$$ "}, {"ident... | ["D"] | null | <img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734265838/exam_images/bt5kenfxh7cgn6fgj50x.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2017 (Online) 8th April Morning Slot Physics - Geometrical Optics Question 163 English Explanation">
<br><br>R... | mcq | jee-main-2017-online-8th-april-morning-slot | 10,995 |
DrMPgNxapSLlruIX94VCT | physics | geometrical-optics | refraction,-tir-and-prism | A ray of light is incident at an angle of 60<sup>o</sup> on one face of a prism of angle 30<sup>o</sup>. The emergent ray of light makes an angle of 30<sup>o</sup> with incident ray. The angle made by the emergent ray with second face of prism will be : | [{"identifier": "A", "content": "0<sup>o</sup> "}, {"identifier": "B", "content": "90<sup>o</sup> "}, {"identifier": "C", "content": "45<sup>o</sup> "}, {"identifier": "D", "content": "30<sup>o</sup> "}] | ["B"] | null | <p>Given : $${i_1} = 60^\circ $$; $$A = 30^\circ $$</p>
<p>Then angle of deviation is given by</p>
<p>$$\delta = 1 - A = 60^\circ - 30^\circ = 30^\circ $$</p>
<p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l38thq3y/35e9c61f-1a3f-4eb1-8bdb-dd03005644c1/def60700-d523-11ec-aeec-6fd1cdec7420/file-1l... | mcq | jee-main-2018-online-16th-april-morning-slot | 10,996 |
AkuxsTXkZaqMIU2JLhFl7 | physics | geometrical-optics | refraction,-tir-and-prism | The variation of refractive index of a crown glass thin prism with wavelength of the incident light is shown. Which of the following graphs is the correct one, if D<sub>m</sub> is the angle of minimum deviation?
<br/><br/><img src="data:image/png;base64,UklGRjoWAABXRUJQVlA4IC4WAAAw+wCdASoAA5wCP4G61ma2LawnoTC5OsAwCWlu4... | [{"identifier": "A", "content": "<img src=\"https://res.cloudinary.com/dckxllbjy/image/upload/v1734267149/exam_images/e09zhsrcrrpbtbgyzsz3.webp\" style=\"max-width: 100%; height: auto;display: block;margin: 0 auto;\" loading=\"lazy\" alt=\"JEE Main 2019 (Online) 11th January Morning Slot Physics - Geometrical Optics Q... | ["A"] | null | Since D<sub>m</sub> = ($$\mu $$ $$-$$ 1) A & on increasing the wavelength, $$\mu $$ decreases & hence D<sub>m</sub> decreases. | mcq | jee-main-2019-online-11th-january-morning-slot | 10,997 |
gDSmo8PyxmKNSadLL8y7B | physics | geometrical-optics | refraction,-tir-and-prism | In figure, the optical fiber is $$l$$ = 2m long and
has a diameter of d = 20 μm. If a ray of light
is incident on one end of the fiber at angle
$$\theta _1$$ = 40°, the number of reflection it makes
before emerging from the other end is close to:
(refractive index of fibre is 1.31 and
sin 40° = 0.64)
<img src="data:ima... | [{"identifier": "A", "content": "57000"}, {"identifier": "B", "content": "55000"}, {"identifier": "C", "content": "66000"}, {"identifier": "D", "content": "45000"}] | ["A"] | null | If we approximate the angle $$\theta _2$$ as 30° initially then answer will be closer to 57000. but if
we solve thoroughly, answer will be close to 55000.<br>
So both the answers must be awarded. Detailed solution as following.<br><br>
<b>EXACT SOLUTION</b><br>
By Snell’s law 1.sin 40° = (1.31) sin $$\theta _2$$<br><br... | mcq | jee-main-2019-online-8th-april-morning-slot | 10,999 |
cd3lsJHYtstJ197iEx18hoxe66ijvzt03ke | physics | geometrical-optics | refraction,-tir-and-prism | A ray of light AO in vacuum is incident on a
glass slab at angle 60° and refracted at angle 30°
along OB as shown in the figure. The optical path
length of light ray from A to B is:
<img src="data:image/png;base64,UklGRgoRAABXRUJQVlA4IP4QAACwcwCdASrIARgBPm02mEikIqKhItIpiIANiWlu/HyZVOtQyv0t/if5FeBP9p/r37V/2/1L/FPnP7L/Xv... | [{"identifier": "A", "content": "2a + 2b/$$\\sqrt 3$$"}, {"identifier": "B", "content": "2a + 2b/3"}, {"identifier": "C", "content": "2a + 2b"}, {"identifier": "D", "content": "2$$\\sqrt3$$/a + 2b"}] | ["C"] | null | From Snell’s law<br>
1 sin 60° = $$\mu $$ sin 30°<br><br>
$$ \Rightarrow $$ $$\mu $$ = $$\sqrt 3 $$<br><br>
Optical path = AO + $$\mu $$(OB)<br><br>
= $${a \over {\cos {{60}^o}}} + \sqrt 3 {b \over {\cos {{30}^o}}}$$<br><br>
= 2a + 2b | mcq | jee-main-2019-online-10th-april-morning-slot | 11,000 |
BxMSNgtWW1lWu8Xh383rsa0w2w9jx3opyaq | physics | geometrical-optics | refraction,-tir-and-prism | A concave mirror has radius of curvature of 40 cm. It is at the bottom of a glass that has water filled up to 5
cm (see figure). If a small particle is floating on the surface of water, its image as seen, from directly above
the glass, is at a distance d from the surface of water. The value of d is dose to: (Refractive... | [{"identifier": "A", "content": "11.7 cm"}, {"identifier": "B", "content": "6.7 cm"}, {"identifier": "C", "content": "13.4 cm"}, {"identifier": "D", "content": "8.8 cm"}] | ["D"] | null | Light incident from particle P will be reflected at mirror.<br><br>
u = 5cm, f = $$m - {R \over 2} = - 20cm$$<br><br>
$${1 \over v} + {1 \over u} = {1 \over f};$$ $${v_1} = + {{20} \over 3}cm$$<br><br>
This image will act as object for light getting refracted at
water surface.<br><br>
So, object dist... | mcq | jee-main-2019-online-12th-april-morning-slot | 11,001 |
z5efa1jfCJbp6W95Xu3rsa0w2w9jx6lnozd | physics | geometrical-optics | refraction,-tir-and-prism | A transparent cube of side, made of a material of refractive index $$\mu $$<sub>2</sub>, is immersed in a liquid of refractive
index $$\mu $$<sub>1</sub>($$\mu $$<sub>1</sub> < $$\mu $$<sub>2</sub>). A ray is incident on the face AB at an angle $$\theta $$(shown in the figure). Total internal
reflection takes place ... | [{"identifier": "A", "content": "$$\\theta > {\\sin ^{ - 1}}\\sqrt {{{\\mu _2^2} \\over {\\mu _1^2}} - 1} $$"}, {"identifier": "B", "content": "$$\\theta < {\\sin ^{ - 1}}\\sqrt {{{\\mu _2^2} \\over {\\mu _1^2}} - 1} $$"}, {"identifier": "C", "content": "$$\\theta < {\\sin ^{ - 1}}{{{\\mu _1}} \\over {{\\mu... | ["B"] | null | <img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734267477/exam_images/elbsadj1kjeppachnz3b.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2019 (Online) 12th April Evening Slot Physics - Geometrical Optics Question 136 English Explanation">
<br><br>... | mcq | jee-main-2019-online-12th-april-evening-slot | 11,002 |
dakA0vjFkFLKC5dd8Jjgy2xukfotbzhn | physics | geometrical-optics | refraction,-tir-and-prism | A prism of angle A = 1<sup>o</sup> has a refractive index
$$\mu $$ = 1.5. A good estimate for the minimum angle
of deviation (in degrees) is close to $${N \over {10}}$$.
<br/>Value of N is ____. | [] | null | 5 | <p>Deviation for small-angled prism is given by</p>
<p>$$\delta$$ = ($$\mu$$ $$-$$ 1) A</p>
<p>Given, A = 1$$^\circ$$, $$\mu$$ = 1.5</p>
<p>Substituting these values in above equation, we get</p>
<p>$$\delta$$ = (1.5 $$-$$ 1)1 $$\delta$$ = 0.5</p>
<p>According to question, $$\delta = {N \over {10}}$$</p>
<p>$$ \Righta... | integer | jee-main-2020-online-5th-september-evening-slot | 11,004 |
njpf6SIBDC1Cs7j6VRjgy2xukf25ck7u | physics | geometrical-optics | refraction,-tir-and-prism | An observer can see through a small hole on the side of a jar (radius 15 cm) at a point at height of
15 cm from the bottom (see figure). The hole is at a height of 45 cm. When the jar is filled with a
liquid up to a height of 30 cm the same observer can see the edge at the bottom of the jar. If the
refractive index of ... | [] | null | 158 | <img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734265219/exam_images/nxcygtynwajtxeuiuvwo.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2020 (Online) 3rd September Morning Slot Physics - Geometrical Optics Question 124 English Explanation">
<br><br... | integer | jee-main-2020-online-3rd-september-morning-slot | 11,005 |
KLZRe7bV0sbihzesrZjgy2xukexz6l08 | physics | geometrical-optics | refraction,-tir-and-prism | A light ray enters a solid glass sphere of
refractive index $$\mu $$ = $$\sqrt 3 $$ at an angle of incidence
60<sup>o</sup>. The ray is both reflected and refracted at
the farther surface of the sphere. The angle (in
degrees) between the reflected and refracted
rays at this surface is ________. | [] | null | 90 | <img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734265254/exam_images/nj2n4djqc8xc3pjn11vp.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2020 (Online) 2nd September Evening Slot Physics - Geometrical Optics Question 125 English Explanation">
<br><br... | integer | jee-main-2020-online-2nd-september-evening-slot | 11,006 |
OqaVI8B9VVOnl9Kc1w7k9k2k5l66eku | physics | geometrical-optics | refraction,-tir-and-prism | There is a small source of light at some depth
below the surface of water (refractive
index = $${4 \over 3}$$) in a tank of large cross sectional
surface area. Neglecting any reflection from the
bottom and absorption by water, percentage of
light that emerges out of surface is (nearly) :
<br/>[Use the fact that surface... | [{"identifier": "A", "content": "17%"}, {"identifier": "B", "content": "34%"}, {"identifier": "C", "content": "50%"}, {"identifier": "D", "content": "21%"}] | ["A"] | null | <img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734265954/exam_images/hufvgakbidtjllnqcbnl.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2020 (Online) 9th January Evening Slot Physics - Geometrical Optics Question 127 English Explanation">
<br>$${4 ... | mcq | jee-main-2020-online-9th-january-evening-slot | 11,007 |
1qG4bizr0hC8qJNzlG7k9k2k5iecjk8 | physics | geometrical-optics | refraction,-tir-and-prism | A vessel of depth 2h is half filled with a liquid
of refractive index $$2\sqrt 2 $$ and the upper half with
another liquid of refractive index $$\sqrt 2 $$ . The
liquids are immiscible. The apparent depth of
the inner surface of the bottom of vessel
will be : | [{"identifier": "A", "content": "$${h \\over {\\sqrt 2 }}$$"}, {"identifier": "B", "content": "$${h \\over {3\\sqrt 2 }}$$"}, {"identifier": "C", "content": "$${3 \\over 4}h\\sqrt 2 $$"}, {"identifier": "D", "content": "$${h \\over {2\\left( {\\sqrt 2 + 1} \\right)}}$$"}] | ["C"] | null | <img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734263436/exam_images/cjks174r2n5zrmiowomg.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2020 (Online) 9th January Morning Slot Physics - Geometrical Optics Question 129 English Explanation">
<br><br>D... | mcq | jee-main-2020-online-9th-january-morning-slot | 11,008 |
JpR0IzNmoPTu3JVQ0u1kmhnwaeb | physics | geometrical-optics | refraction,-tir-and-prism | The angle of deviation through a prism is minimum when<br/><br/><img src="data:image/png;base64,UklGRvQFAABXRUJQVlA4IOgFAADQJgCdASr5AH4APm02l0ekIyIhJtL5wIANiWlu4MAAZ2ddH6V/1HtX/0f8x5qk+e8Zf2H0x/yn6AeWvuD+APM5+mvgq9vjUn9GvYC7h/pl/WPJz1GpLvIE8c/Tn4APAT/2v5l/Zv1f9on5r/Y/+9/K/7/+sn2GfqT+jP9y94b2C/s77I36t/oWUGIrwxTBlZxrMaRv... | [{"identifier": "A", "content": "Statements (B) and (C) are true"}, {"identifier": "B", "content": "Only statements (A) and (B) are true"}, {"identifier": "C", "content": "Statements (A), (B) and (C) are true"}, {"identifier": "D", "content": "Only statement (D) is true"}] | ["C"] | null | <img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264932/exam_images/d9wz5mlx00ohvpqimdhj.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2021 (Online) 16th March Morning Shift Physics - Geometrical Optics Question 109 English Explanation">
<br>Devia... | mcq | jee-main-2021-online-16th-march-morning-shift | 11,009 |
mYKRDVwa4iHPiZJ1aq1kmiozx5v | physics | geometrical-optics | refraction,-tir-and-prism | Red light differs from blue light as they have : | [{"identifier": "A", "content": "Different frequencies and same wavelengths"}, {"identifier": "B", "content": "Different frequencies and different wavelengths"}, {"identifier": "C", "content": "Same frequencies and different wavelengths"}, {"identifier": "D", "content": "Same frequencies and same wavelengths"}] | ["B"] | null | Red light and blue light have different wavelength and different frequency. | mcq | jee-main-2021-online-16th-march-evening-shift | 11,010 |
LePIrgEVSq7Vo88tKB1kmiq5f62 | physics | geometrical-optics | refraction,-tir-and-prism | A deviation of 2$$^\circ$$ is produced in the yellow ray when prism of crown and flint glass are achromatically combined. Taking dispersive powers of crown and flint glass as 0.02 and 0.03 respectively and refractive index for yellow light for these glasses are 1.5 and 1.6 respectively. The refracting angles for crown ... | [] | null | 12 | $${\delta _{net}} = ({\mu _1} - 1){A_1} - ({\mu _2} - 1){A_2}$$<br><br>$$2^\circ = ({\mu _1} - 1){A_1} - ({\mu _2} - 1){A_2}$$ ....... (1)<br><br>and $${\omega _1}({\mu _1} - 1){A_1} = {\omega _2}({\mu _2} - 1){A_2}$$ ..... (2)<br><br>Substituting the values in equation (1) and (2), we get<br><br>$$2^\circ = 0.5{A_1}... | integer | jee-main-2021-online-16th-march-evening-shift | 11,011 |
HdFofjPu1YFoU6zcfJ1kmlvs1ls | physics | geometrical-optics | refraction,-tir-and-prism | Three rays of light, namely red (R), green (G) and blue (B) are incident on the face PQ of a right angled prism PQR as shown in the figure.<br/><br/><img src="data:image/png;base64,UklGRngGAABXRUJQVlA4IGwGAADwNACdASo8AdwAPm02mUgkIyshInkpwWANiWlu/HyYw+tQ0/0p/nvWprtf8z/HP2k+X36b3o7Tn9m/jW/eYu/wH849gH4T/AegHbSfwD2r7zeOv/D... | [{"identifier": "A", "content": "green"}, {"identifier": "B", "content": "blue and green"}, {"identifier": "C", "content": "blue "}, {"identifier": "D", "content": "red"}] | ["D"] | null | <picture><source media="(max-width: 1729px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734263700/exam_images/mtnxbz3dmzgbhal6a4fi.webp"><source media="(max-width: 320px)" srcset="https://res.cloudinary.com/dckxllbjy/image/upload/v1734265334/exam_images/srahbanokhdiwcqfd0eu.webp"><source media="(max-wi... | mcq | jee-main-2021-online-18th-march-evening-shift | 11,013 |
1krsvf9mr | physics | geometrical-optics | refraction,-tir-and-prism | A ray of light passes from a denser medium to a rarer medium at an angle of incidence i. The reflected and refracted rays make an angle of 90$$^\circ$$ with each other. The angle of reflection and refraction are respectively r and r'. The critical angle is given by<br/><br/><img src="data:image/png;base64,UklGRvAUAABXR... | [{"identifier": "A", "content": "sin<sup>$$-$$1</sup> (tan r)"}, {"identifier": "B", "content": "sin<sup>$$-$$1</sup> (cot r)"}, {"identifier": "C", "content": "sin<sup>$$-$$1</sup> (tan r')"}, {"identifier": "D", "content": "tan<sup>$$-$$1</sup> (sin i)"}] | ["A"] | null | <img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266552/exam_images/fgq6qiywgsxfob6rjwmu.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2021 (Online) 22th July Evening Shift Physics - Geometrical Optics Question 99 English Explanation"> <br><br>$$n... | mcq | jee-main-2021-online-22th-july-evening-shift | 11,014 |
1krswphy1 | physics | geometrical-optics | refraction,-tir-and-prism | A ray of light passing through a prism ($$\mu$$ = $$\sqrt 3 $$) suffers minimum deviation. It is found that the angle of incidence is double the angle of refraction within the prism. Then, the angle of prism is _____________ (in degrees). | [] | null | 60 | For minimum deviation r<sub>1</sub> = r<sub>2</sub> = A/2<br><br>given i = 2r<br><br>$$\mu = {{\sin i} \over {\sin r}} = {{\sin 2r} \over {\sin r}}$$<br><br>$$ \Rightarrow \cos r = {\mu \over 2}$$<br><br>$$\Rightarrow$$ r = 30$$^\circ$$<br><br>$$\Rightarrow$$ A = 60$$^\circ$$ | integer | jee-main-2021-online-22th-july-evening-shift | 11,015 |
1kruk66qm | physics | geometrical-optics | refraction,-tir-and-prism | A ray of laser of a wavelength 630 nm is incident at an angle of 30$$^\circ$$ at the diamond-air interface. It is going from diamond to air. The refractive index of diamond is 2.42 and that of air is 1. Choose the correct option. | [{"identifier": "A", "content": "angle of refraction is 24.41$$^\\circ$$"}, {"identifier": "B", "content": "angle of refraction is 30$$^\\circ$$"}, {"identifier": "C", "content": "refraction is not possible"}, {"identifier": "D", "content": "angle of refraction is 53.4$$^\\circ$$"}] | ["C"] | null | $$\sin {\theta _C} = {1 \over \mu } = {1 \over {2{\mu _2}}} < \sin {\theta _C}$$<br><br>sin$$\theta$$ > sin$$\theta$$<sub>C</sub><br><br>$$\theta$$ > $$\theta$$<sub>C</sub><br><br>Total internal reflection will happen. | mcq | jee-main-2021-online-25th-july-morning-shift | 11,016 |
1ks0ju3rx | physics | geometrical-optics | refraction,-tir-and-prism | The expected graphical representation of the variation of angle of deviation '$$\delta$$' with angle of incidence 'i' in a prism is : | [{"identifier": "A", "content": "<img src=\"https://res.cloudinary.com/dckxllbjy/image/upload/v1734266650/exam_images/whvybgfhmzzz1aetcskf.webp\" style=\"max-width: 100%;height: auto;display: block;margin: 0 auto;\" loading=\"lazy\" alt=\"JEE Main 2021 (Online) 27th July Evening Shift Physics - Geometrical Optics Quest... | ["B"] | null | Standard graph between angle of deviation and incident angle. | mcq | jee-main-2021-online-27th-july-evening-shift | 11,020 |
1l57qelb6 | physics | geometrical-optics | refraction,-tir-and-prism | <p>Consider a light ray travelling in air is incident into a medium of refractive index $$\sqrt{2n}$$. The incident angle is twice that of refracting angle. Then, the angle of incidence will be :</p> | [{"identifier": "A", "content": "$${\\sin ^{ - 1}}\\left( {\\sqrt n } \\right)$$"}, {"identifier": "B", "content": "$${\\cos ^{ - 1}}\\left( {\\sqrt {{n \\over 2}} } \\right)$$"}, {"identifier": "C", "content": "$${\\sin ^{ - 1}}\\left( {\\sqrt {2n} } \\right)$$"}, {"identifier": "D", "content": "$$2{\\cos ^{ - 1}}\\le... | ["D"] | null | <p>According to the law,</p>
<p>$$1 \times \sin \theta = \sqrt {2n} \times \sin \left( {{\theta \over 2}} \right)$$</p>
<p>$$ \Rightarrow \cos {\theta \over 2} = \sqrt {{n \over 2}} $$</p>
<p>$$ \Rightarrow \theta = 2{\cos ^{ - 1}}\left( {\sqrt {{n \over 2}} } \right)$$</p> | mcq | jee-main-2022-online-27th-june-morning-shift | 11,025 |
1l5w3plcj | physics | geometrical-optics | refraction,-tir-and-prism | <p>The refractive index of an equilateral prism is $$\sqrt 2 $$. The angle of emergence under minimum deviation position of prism, in degree, is ___________.</p> | [] | null | 45 | Refractive index
<br/><br/>
$$
\begin{aligned}
& \mu=\frac{\sin \left(\frac{A+\delta \sin }{2}\right)}{\sin \left(\frac{A}{2}\right)} \Rightarrow \sqrt{2}=\sin \frac{\left(\frac{60+\delta \min }{2}\right)}{\sin 30^{\circ}} \\\\
& \Rightarrow \frac{1}{2}=\sin \left(\frac{60+\delta \min }{2}\right) \Rightarrow 45^{\circ}... | integer | jee-main-2022-online-30th-june-morning-shift | 11,030 |
1l6dz4gfe | physics | geometrical-optics | refraction,-tir-and-prism | <p>Time taken by light to travel in two different materials $$A$$ and $$B$$ of refractive indices $$\mu_{A}$$ and $$\mu_{B}$$ of same thickness is $$t_{1}$$ and $$t_{2}$$ respectively. If $$t_{2}-t_{1}=5 \times 10^{-10}$$ s and the ratio of $$\mu_{A}$$ to $$\mu_{B}$$ is $$1: 2$$. Then, the thickness of material, in met... | [{"identifier": "A", "content": "$$5 \\times 10^{-10} \\,v_{\\mathrm{A}}\\, \\mathrm{m}$$"}, {"identifier": "B", "content": "$$5 \\times 10^{-10} \\mathrm{~m}$$"}, {"identifier": "C", "content": "$$1.5 \\times 10^{-10} \\mathrm{~m}$$"}, {"identifier": "D", "content": "$$5 \\times 10^{-10} \\,v_{\\mathrm{B}} \\,\\mathrm... | ["A"] | null | <p>$${t_2} - {t_1} = 5 \times {10^{ - 10}}$$</p>
<p>$$ \Rightarrow {d \over {{v_B}}} - {d \over {{v_A}}} = 5 \times {10^{ - 10}}$$</p>
<p>and, $${{{v_B}} \over {{v_A}}} = {{{\mu _A}} \over {{\mu _B}}} = {1 \over 2}$$</p>
<p>$$ \Rightarrow d\left( {1 - {{{v_B}} \over {{v_A}}}} \right) = 5 \times {10^{ - 10}} \times {v_B... | mcq | jee-main-2022-online-25th-july-morning-shift | 11,032 |
1l6i0nlu8 | physics | geometrical-optics | refraction,-tir-and-prism | <p>Light travels in two media $$M_{1}$$ and $$M_{2}$$ with speeds $$1.5 \times 10^{8} \mathrm{~ms}^{-1}$$ and $$2.0 \times 10^{8} \mathrm{~ms}^{-1}$$ respectively. The critical angle between them is :</p> | [{"identifier": "A", "content": "$$\\tan ^{-1}\\left(\\frac{3}{\\sqrt{7}}\\right)$$"}, {"identifier": "B", "content": "$$\\tan ^{-1}\\left(\\frac{2}{3}\\right)$$"}, {"identifier": "C", "content": "$$\\cos ^{-1}\\left(\\frac{3}{4}\\right)$$"}, {"identifier": "D", "content": "$$\\sin ^{-1}\\left(\\frac{2}{3}\\right)$$"}] | ["A"] | null | <p>Critical angle between them</p>
<p>$$\sin {i_c} = {{{\mu _2}} \over {{\mu _1}}} = {{{v_1}} \over {{v_2}}}$$</p>
<p>$$\sin {i_c} = {3 \over 4}$$</p>
<p>$$ \Rightarrow \tan {i_c} = {3 \over {\sqrt 7 }}$$</p>
<p>$${i_c} = {\tan ^{ - 1}}{3 \over {\sqrt 7 }}$$</p> | mcq | jee-main-2022-online-26th-july-evening-shift | 11,033 |
1l6i3ffcb | physics | geometrical-optics | refraction,-tir-and-prism | <p>In the given figure, the face $$A C$$ of the equilateral prism is immersed in a liquid of refractive index '$$n$$'. For incident angle $$60^{\circ}$$ at the side $$A C$$, the refractive light beam just grazes along face $$A C$$. The refractive index of the liquid $$n=\frac{\sqrt{x}}{4}$$. The value of $$x$$ is _____... | [] | null | 27 | Given prism is equilateral so, angel of prism, A $=60^{\circ}$
<br/><br/>On first surface light is passing straight without any deviation, hence angle of refraction $\mathrm{r}_1=0^{\circ}$.
<br/><br/>$$
\begin{aligned}
& r_1+i_2=\mathrm{A} \\\\
& 0+i_2=60^{\circ} \\\\
& \Rightarrow i_2=60^{\circ}
\end{aligned}
$$
<br... | integer | jee-main-2022-online-26th-july-evening-shift | 11,034 |
1l6ko6d13 | physics | geometrical-optics | refraction,-tir-and-prism | <p>A thin prism of angle $$6^{\circ}$$ and refractive index for yellow light $$\left(\mathrm{n}_{\mathrm{Y}}\right) 1.5$$ is combined with another prism of angle $$5^{\circ}$$ and $$\mathrm{n}_{\mathrm{Y}}=1.55$$. The combination produces no dispersion. The net average deviation $$(\delta)$$ produced by the combination... | [] | null | 4 | <p>$${\delta _{net}} = {\delta _1} + {\delta _2}$$</p>
<p>$$ = |({\mu _1} - 1){A_1} - ({\mu _2} - 1){A_2}|$$</p>
<p>$$ = |3^\circ - 2.75^\circ |$$</p>
<p>$${\delta _{net}} = {{1^\circ } \over 4}$$</p>
<p>$$ \Rightarrow x = 4$$</p> | integer | jee-main-2022-online-27th-july-evening-shift | 11,035 |
1l6masbot | physics | geometrical-optics | refraction,-tir-and-prism | <p>As shown in the figure, after passing through the medium 1 . The speed of light $$v_{2}$$ in medium 2 will be :</p>
<p>$$\left(\right.$$ Given $$\mathrm{c}=3 \times 10^{8} \mathrm{~ms}^{-1}$$ )</p>
<p><img src="data:image/png;base64,UklGRngMAABXRUJQVlA4IGwMAAAwnQCdASoAA1ABP4G01WW2LL+nIbCqe/AwCWlu4W5SkmNwud6L/zlrzZ7f... | [{"identifier": "A", "content": "$$1.0 \\times 10^{8} \\mathrm{~ms}^{-1}$$"}, {"identifier": "B", "content": "$$0.5 \\times 10^{8} \\mathrm{~ms}^{-1}$$"}, {"identifier": "C", "content": "$$1.5 \\times 10^{8} \\mathrm{~ms}^{-1}$$"}, {"identifier": "D", "content": "$$3.0 \\times 10^{8} \\mathrm{~ms}^{-1}$$"}] | ["A"] | null | <p>$$V = {1 \over {\sqrt {\mu \varepsilon } }} = {1 \over {\sqrt {{\mu _r}{\varepsilon _r}{\mu _0}{\varepsilon _0}} }}$$</p>
<p>$$ \Rightarrow {V_2} = {c \over {\sqrt 9 }} = {10^8}$$ m/s</p> | mcq | jee-main-2022-online-28th-july-morning-shift | 11,036 |
1l6p6ff3x | physics | geometrical-optics | refraction,-tir-and-prism | <p>The X-Y plane be taken as the boundary between two transparent media $$\mathrm{M}_{1}$$ and $$\mathrm{M}_{2}$$. $$\mathrm{M}_{1}$$ in $$Z \geqslant 0$$ has a refractive index of $$\sqrt{2}$$ and $$M_{2}$$ with $$Z<0$$ has a refractive index of $$\sqrt{3}$$. A ray of light travelling in $$\mathrm{M}_{1}$$ along th... | [] | null | 15 | <p>Normal will be $$ - \widehat k$$ so</p>
<p> <img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l7myl3p1/cc381127-5ea0-492f-8313-a032aac1ca92/a1229250-2c1b-11ed-a609-572a60403bd8/file-1l7myl3p2.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l7myl3p1/cc381127-5ea0-492f-8313-a032a... | integer | jee-main-2022-online-29th-july-morning-shift | 11,037 |
1l6rhtqcn | physics | geometrical-optics | refraction,-tir-and-prism | <p>Light enters from air into a given medium at an angle of $$45^{\circ}$$ with interface of the air-medium surface. After refraction, the light ray is deviated through an angle of
$$15^{\circ}$$ from its original direction. The refractive index of the medium is:</p> | [{"identifier": "A", "content": "1.732"}, {"identifier": "B", "content": "1.333"}, {"identifier": "C", "content": "1.414"}, {"identifier": "D", "content": "2.732"}] | ["C"] | null | <p>Let, refractive index of medium = $$\mu$$</p>
<p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l7e9j0tr/70a4befa-e3ac-4a19-8966-4b086c719e70/5de067f0-2753-11ed-a077-1f1e3989e798/file-1l7e9j0ts.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l7e9j0tr/70a4befa-e3ac-4a19-8966-... | mcq | jee-main-2022-online-29th-july-evening-shift | 11,038 |
ldo6yp89 | physics | geometrical-optics | refraction,-tir-and-prism | A microscope is focused on an object at the bottom of a bucket. If liquid with refractive index $\frac{5}{3}$
is poured inside the bucket, then the microscope has to be raised by $30 \mathrm{~cm}$ to focus the object again.
The height of the liquid in the bucket is : | [{"identifier": "A", "content": "$50 \\mathrm{~cm}$"}, {"identifier": "B", "content": "$18 \\mathrm{~cm}$"}, {"identifier": "C", "content": "$75 \\mathrm{~cm}$"}, {"identifier": "D", "content": "$12 \\mathrm{~cm}$"}] | ["C"] | null | Shift $=\left(d-\frac{d}{\mu}\right)=30 \mathrm{~cm}$
<br/><br/>$$
\begin{aligned}
& \Rightarrow d\left[1-\frac{1}{\frac{5}{3}}\right]=30 \\\\
& \Rightarrow d=\frac{30 \times 5}{2}=75 \mathrm{~cm}
\end{aligned}
$$ | mcq | jee-main-2023-online-31st-january-evening-shift | 11,039 |
1ldsbf705 | physics | geometrical-optics | refraction,-tir-and-prism | <p>In an experiment of measuring the refractive index of a glass slab using travelling microscope in physics lab, a student measures real thickness of the glass slab as 5.25 mm and apparent thickness of the glass slab as 5.00 mm. Travelling microscope has 20 divisions in one cm on main scale and 20 divisions on vernier... | [] | null | 41 | <p>$$\mu=\frac{\mathrm{real\,depth}\,(l_1)}{\mathrm{apparent\,depth}\,(l_2)}$$</p>
<p>$$=\frac{5.25}{5}=1.05$$</p>
<p>$$\frac{d\mu}{\mu}=\frac{dl_1}{l_1}+\frac{dl_2}{l_2}$$</p>
<p>$$d\mu = \left( {{{d{l_1}} \over {{l_1}}} + {{d{l_2}} \over {{l_2}}}} \right)\mu $$</p>
<p>$$ = \left( {{{0.01} \over {5.25}} + {{0.01} \ov... | integer | jee-main-2023-online-29th-january-evening-shift | 11,041 |
1lgq1p0sp | physics | geometrical-optics | refraction,-tir-and-prism | <p>A vessel of depth '$$d$$' is half filled with oil of refractive index $$n_{1}$$ and the other half is filled with water of refractive index $$n_{2}$$. The apparent depth of this vessel when viewed from above will be-</p> | [{"identifier": "A", "content": "$$\\frac{2 d\\left(n_{1}+n_{2}\\right)}{n_{1} n_{2}}$$"}, {"identifier": "B", "content": "$$\\frac{d\\left(n_{1}+n_{2}\\right)}{2 n_{1} n_{2}}$$"}, {"identifier": "C", "content": "$$\\frac{d n_{1} n_{2}}{2\\left(n_{1}+n_{2}\\right)}$$"}, {"identifier": "D", "content": "$$\\frac{d n_{1} ... | ["B"] | null | To find the apparent depth of the vessel when viewed from above, we can calculate the apparent depths of the oil and water separately and then add them together.
<br/><br/>
The formula to find the apparent depth ($$h_{apparent}$$) is:
<br/><br/>
$$h_{apparent} = \frac{h_{real}}{n}$$
<br/><br/>
Where $$h_{real}$$ is th... | mcq | jee-main-2023-online-13th-april-morning-shift | 11,045 |
1lgq2xcny | physics | geometrical-optics | refraction,-tir-and-prism | <p>A fish rising vertically upward with a uniform velocity of $$8 \mathrm{~ms}^{-1}$$, observes that a bird is diving vertically downward towards the fish with the velocity of $$12 \mathrm{~ms}^{-1}$$. If the refractive index of water is $$\frac{4}{3}$$, then the actual velocity of the diving bird to pick the fish, wil... | [] | null | 3 | The bird's diving velocity is given relative to the fish. In order to find the actual velocity of the bird, we need to consider the refractive index of the water.
<br/><br/>
The fish sees the bird diving with a velocity of $$12 \ \text{m/s}$$. We can write the equation considering the velocities relative to the fish:
<... | integer | jee-main-2023-online-13th-april-morning-shift | 11,046 |
1lgrhs6f8 | physics | geometrical-optics | refraction,-tir-and-prism | <p>An ice cube has a bubble inside. When viewed from one side the apparent distance of the bubble is $$12 \mathrm{~cm}$$. When viewed from the opposite side, the apparent distance of the bubble is observed as $$4 \mathrm{~cm}$$. If the side of the ice cube is $$24 \mathrm{~cm}$$, the refractive index of the ice cube is... | [{"identifier": "A", "content": "$$\\frac{3}{2}$$"}, {"identifier": "B", "content": "$$\\frac{4}{3}$$"}, {"identifier": "C", "content": "$$\\frac{2}{3}$$"}, {"identifier": "D", "content": "$$\\frac{6}{5}$$"}] | ["A"] | null | Let's denote the true distance of the bubble from one side of the ice cube as $$x$$ and the refractive index of the ice cube as $$n$$. We will use the formula for apparent depth, which states that the ratio of the true depth to the apparent depth is equal to the refractive index:
<br/><br/>
$$n = \frac{\text{True depth... | mcq | jee-main-2023-online-12th-april-morning-shift | 11,047 |
1lh24ps5y | physics | geometrical-optics | refraction,-tir-and-prism | <p>A monochromatic light wave with wavelength $$\lambda_{1}$$ and frequency $$v_{1}$$ in air enters another medium. If the angle of incidence and angle of refraction at the interface are $$45^{\circ}$$ and $$30^{\circ}$$ respectively, then the wavelength $$\lambda_{2}$$ and frequency $$v_{2}$$ of the refracted wave are... | [{"identifier": "A", "content": "$$\\lambda_{2}=\\lambda_{1}, v_{2}=\\frac{1}{\\sqrt{2}} v_{1}$$"}, {"identifier": "B", "content": "$$\\lambda_{2}=\\lambda_{1}, v_{2}=\\sqrt{2} v_{1}$$"}, {"identifier": "C", "content": "$$\\lambda_{2}=\\sqrt{2} \\lambda_{1}, v_{2}=v_{1}$$"}, {"identifier": "D", "content": "$$\\lambda_{... | ["D"] | null | <p>When a light wave moves from one medium to another, its speed and wavelength may change, but its frequency remains constant because it is determined by the source of the light. This is because frequency depends on the oscillations of the source, which do not change when entering a different medium.</p>
<p>Snell'... | mcq | jee-main-2023-online-6th-april-morning-shift | 11,049 |
1lh25znf3 | physics | geometrical-optics | refraction,-tir-and-prism | <p>A pole is vertically submerged in swimming pool, such that it gives a length of shadow $$2.15 \mathrm{~m}$$ within water when sunlight is incident at angle of $$30^{\circ}$$ with the surface of water. If swimming pool is filled to a height of $$1.5 \mathrm{~m}$$, then the height of the pole above the water surface i... | [] | null | 50 | <p>The pole is vertically submerged in the swimming pool, and the length of the shadow is due to the sunlight that is incident at an angle of $30^{\circ}$ with the surface of water. Hence, the angle of incidence, $i$, is $60^{\circ}$ (since the angle of incidence is measured from the normal to the surface, and the norm... | integer | jee-main-2023-online-6th-april-morning-shift | 11,050 |
1lh2zozli | physics | geometrical-optics | refraction,-tir-and-prism | <p>Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R</p>
<p>Assertion A: The phase difference of two light waves change if they travel through different media having same thickness, but different indices of refraction.</p>
<p>Reason R: The wavelengths of waves are diff... | [{"identifier": "A", "content": "Both A and R are correct but R is NOT the correct explanation of A"}, {"identifier": "B", "content": "A is correct but R is not correct"}, {"identifier": "C", "content": "A is not correct but R is correct"}, {"identifier": "D", "content": "Both A and R are correct and R is the correct e... | ["D"] | null | <p>
Assertion A is correct. When light waves travel through different media with different indices of refraction, the speed of light changes, which in turn changes the phase of the light waves. This is because the phase of a wave is directly related to the distance it has traveled, which in this case is affected by the... | mcq | jee-main-2023-online-6th-april-evening-shift | 11,051 |
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