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lv2erypp | physics | laws-of-motion | motion-on-an-inclined-plane | <p>A $$2 \mathrm{~kg}$$ brick begins to slide over a surface which is inclined at an angle of $$45^{\circ}$$ with respect to horizontal axis. The co-efficient of static friction between their surfaces is:</p> | [{"identifier": "A", "content": "1"}, {"identifier": "B", "content": "1.7"}, {"identifier": "C", "content": "0.5"}, {"identifier": "D", "content": "$$\\frac{1}{\\sqrt{3}}$$"}] | ["A"] | null | <p>$$\begin{aligned}
& m g \sin \theta=\mu \cdot m g \cos \theta \\
& \Rightarrow \tan \theta=\mu=1
\end{aligned}$$</p> | mcq | jee-main-2024-online-4th-april-evening-shift | 11,691 |
diuKSXbhwS8den7U | physics | laws-of-motion | newton's-laws-of-motion | A lift is moving down with acceleration $$a.$$ A man in the lift drops a ball inside the lift. The acceleration of the ball as observed by the man in the lift and a man standing stationary on the ground are respectively | [{"identifier": "A", "content": "$$g,g$$ "}, {"identifier": "B", "content": "$$g-a, g-a$$"}, {"identifier": "C", "content": "$$g-a, g$$ "}, {"identifier": "D", "content": "$$a, g$$ "}] | ["C"] | null | Let acceleration of ball = $${\overrightarrow a _b}$$ and acceleration of man is = $${\overrightarrow a _m}$$
<br><br>With respect to the man standing in the lift, the acceleration of the ball
<br><br>$${\overrightarrow a _{bm}} = {\overrightarrow a _b} - {\overrightarrow a _m}$$
<br><br>$$ \Rightarrow {a_{bm}} = g - ... | mcq | aieee-2002 | 11,692 |
ngTxARUoznWLIMIA | physics | laws-of-motion | newton's-laws-of-motion | Two forces are such that the sum of their magnitudes is $$18$$ $$N$$ and their resultant is $$12$$ $$N$$ which is perpendicular to the smaller force. Then the magnitudes of the forces are | [{"identifier": "A", "content": "$$12N,$$ $$6N$$ "}, {"identifier": "B", "content": "$$13N,$$ $$5N$$"}, {"identifier": "C", "content": "$$10N,$$ $$8N$$"}, {"identifier": "D", "content": "$$16N$$, $$2N.$$ "}] | ["B"] | null | Let the two forces be $${F_1}$$ and $${F_2}$$ and let $${F_2}$$ is smaller than $$ {F_1} $$ and assume $$R$$ is the resultant force.
<br><br>Given $${F_1} + {F_2} = 18$$ $$\,\,\,\,\,\,$$ ....$$(i)$$
<br><br>From the right angle triangle, $$F_2^2 + {R^2} = F_1^2$$
<br><br>or $$F_1^2 - F_2^2 = {R^2}$$
<br><br>or $$\left... | mcq | aieee-2002 | 11,693 |
JLiClepAffsb2IFf | physics | laws-of-motion | newton's-laws-of-motion | A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring reads $$49$$ $$N,$$ when the lift is stationary. If the lift moves downward with an acceleration of $$5 m/{s^2}$$, the reading of the spring balance will be | [{"identifier": "A", "content": "$$24$$ $$N$$ "}, {"identifier": "B", "content": "$$74$$ $$N$$ "}, {"identifier": "C", "content": "$$15$$ $$N$$ "}, {"identifier": "D", "content": "$$49$$ $$N$$ "}] | ["A"] | null | <img class="question-image" src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734267763/exam_images/u60jjsap0qzr5mddcca3.webp" loading="lazy" alt="AIEEE 2003 Physics - Laws of Motion Question 129 English Explanation">
<br>When lift is stationary then,
<br><br>T<sub>1</sub> = $$mg$$ = 49 N
<br><br>$$m$$ = 5
<br... | mcq | aieee-2003 | 11,694 |
HsgVEcvEfqI3xXKN | physics | laws-of-motion | newton's-laws-of-motion | A rocket with a lift-off mass $$3.5 \times {10^4}\,\,kg$$ is blasted upwards with an initial acceleration of $$10m/{s^2}.$$ Then the initial thrust of the blast is | [{"identifier": "A", "content": "$$3.5 \\times {10^5}N$$ "}, {"identifier": "B", "content": "$$7.0 \\times {10^5}N$$ "}, {"identifier": "C", "content": "$$14.0 \\times {10^5}N$$ "}, {"identifier": "D", "content": "$$1.75 \\times {10^5}N$$ "}] | ["A"] | null | Here, thrust force is responsible to accelerate the rocket,
<br><br>So initial thrust of the blast
<br><br>= (Lift-off mass) × acceleration
<br><br>= (3.5 × 10<sup>4</sup>) × (10)
<br><br>= 3.5 × 10<sup>5</sup> N | mcq | aieee-2003 | 11,695 |
9ZfE7PONnMRU4a6X | physics | laws-of-motion | newton's-laws-of-motion | A particle of mass 0.3 kg subjected to a force $$F=-kx$$ with $$k=15$$ $$N/m$$. What will be its initial acceleration if it is released from a point 20 cm away from the origin? | [{"identifier": "A", "content": "$$15\\,\\,\\,\\,m/{s^2}$$ "}, {"identifier": "B", "content": "$$3\\,\\,\\,m/{s^2}$$ "}, {"identifier": "C", "content": "$$10\\,\\,\\,m/{s^2}$$ "}, {"identifier": "D", "content": "$$5\\,\\,\\,m/{s^2}$$ "}] | ["C"] | null | <br><br>Given F = - kx
<br><br>$$\Rightarrow$$ F = - 15$$ \times {{20} \over {100}}$$ = - 3 N
<br><br>F = m.a = 3 N
<br><br>$$\Rightarrow$$ a = $${3 \over m}$$ = $${3 \over {0.3}}$$ = 10 m/s<sup>2</sup> | mcq | aieee-2005 | 11,697 |
OWQJHBEOpuPtncCK | physics | laws-of-motion | newton's-laws-of-motion | A particle of mass $$m$$ is at rest at the origin at time $$t=0.$$ It is subjected to a force $$F\left( t \right) = {F_0}{e^{ - bt}}$$ in the $$x$$ direction. Its speed $$v(t)$$ is depicted by which of the following curves? | [{"identifier": "A", "content": "<img class=\"question-image\" src=\"https://res.cloudinary.com/dckxllbjy/image/upload/v1734265483/exam_images/yxo6orj9xgftgzmk9aqb.webp\" loading=\"lazy\" alt=\"AIEEE 2012 Physics - Laws of Motion Question 110 English Option 1\"> "}, {"identifier": "B", "content": "<img class=\"question... | ["B"] | null | Given that $$F\left( t \right) = {F_0}{e^{ - bt}} $$
<br><br>$$\Rightarrow m{{dv} \over {dt}} = {F_0}{e^{ - bt}}$$
<br><br>$${{dv} \over {dt}} = {{{F_0}} \over m}{e^{ - bt}} $$
<br><br>$$\Rightarrow \int\limits_0^v {dv} = {{{F_0}} \over m}\int\limits_0^t {{e^{ - bt}}} \,dt$$
<br><br>$$v = {{{F_0}} \over m}\left[ {{{{e... | mcq | aieee-2012 | 11,698 |
kQ3gPFzGjReG6774CXwiX | physics | laws-of-motion | newton's-laws-of-motion | A particle of mass m is acted upon by a force F given by the empirical law
F =$${R \over {{t^2}}}\,v\left( t \right).$$ If this law is to be tested experimentally by observing the motion starting from rest, the best way is to plot : | [{"identifier": "A", "content": "$$\\upsilon $$(t) against t<sup>2</sup>"}, {"identifier": "B", "content": "log $$\\upsilon $$(t) against $${1 \\over {{t^2}}}$$ "}, {"identifier": "C", "content": "log $$\\upsilon $$(t) against t"}, {"identifier": "D", "content": "log $$\\upsilon $$(t) against $${1 \\over {{t}}}$$ "}] | ["D"] | null | Given,
<br><br>F = $${R \over {{t^2}}}$$ v(t)
<br><br>$$ \Rightarrow $$ m $${{dv} \over {dt}}$$ = $${R \over {{t^2}}}$$ (v)
<br><br>$$ \Rightarrow $$ $${{dv} \over v}$$ = $${R \over m}$$ $${{dt} \over {{t^2}}}$$
<br><br>Intergrating both sides,
<br><br>$$\int {{{dv} \over v} = {R ... | mcq | jee-main-2016-online-10th-april-morning-slot | 11,699 |
f6vhxNJ6dyy1P1hv5j9CK | physics | laws-of-motion | newton's-laws-of-motion | Two forces P and Q, of magnitude 2F and 3F, respectively, are at an angle $$\theta $$ with each other. If the force Q is doubled, then their resultant also gets doubled. Then, the angle $$\theta $$ is - | [{"identifier": "A", "content": "90<sup>o</sup>"}, {"identifier": "B", "content": "60<sup>o</sup>"}, {"identifier": "C", "content": "30<sup>o</sup>"}, {"identifier": "D", "content": "120<sup>o</sup>"}] | ["D"] | null | 4F<sup>2</sup> + 9F<sup>2</sup> + 12F<sup>2</sup> cos $$\theta $$ = R<sup>2</sup>
<br><br>4F<sup>2</sup> + 36F<sup>2</sup> + 24F<sup>2</sup> cos $$\theta $$ = 4R<sup>2</sup>
<br><br>4F<sup>2</sup> + 36F<sup>2</sup> + 24F<sup>2</sup> cos $$\theta $$
<br><br>= 4(13F<sup>2</sup> + 12F<sup>2</sup>cos$$\theta $$) = 52F<sup>... | mcq | jee-main-2019-online-10th-january-evening-slot | 11,700 |
0IWF3lt2qg3jMHJA7D3rsa0w2w9jwzhb4yb | physics | laws-of-motion | newton's-laws-of-motion | A bullet of mass 20 g has an initial speed of 1 ms<sup>–1</sup>
, just before it starts penetrating a mud wall of thickness
20 cm. If the wall offers a mean resistance of 2.5 × 10<sup>–2</sup> N, the speed of the bullet after emerging from the
other side of the wall is close to : | [{"identifier": "A", "content": "0.3 ms<sup>-1</sup>"}, {"identifier": "B", "content": "0.1 ms<sup>-1</sup>"}, {"identifier": "C", "content": "0.7 ms<sup>-1</sup>"}, {"identifier": "D", "content": "0.4 ms<sup>-1</sup>"}] | ["C"] | null | Given, resistance offered by the wall
<br/><br/>$$
=F=-25 \times 10^{-2} \mathrm{~N}
$$
<br/><br/>So, deacceleration of bullet,
<br/><br/>$$
\begin{aligned}
a=\frac{F}{m}=\frac{-2.5 \times 10^{-2}}{20 \times 10^{-3}} & =-\frac{5}{4} \mathrm{~ms}^{-2} \\\\
(\because m & \left.=20 \mathrm{~g}=20 \times 10^{-3} \mathrm{~k... | mcq | jee-main-2019-online-10th-april-evening-slot | 11,702 |
3XOkph5GPWn2fQaiPfjgy2xukfl1my99 | physics | laws-of-motion | newton's-laws-of-motion | A spaceship in space sweeps stationary
interplanetary dust. As a result, its mass
<br/>increases at a rate $${{dM\left( t \right)} \over {dt}}$$ = bv<sup>2</sup>(t), where v(t) is
its instantaneous velocity. The instantaneous
acceleration of the satellite is : | [{"identifier": "A", "content": "-bv<sup>3</sup>(t)"}, {"identifier": "B", "content": "$$ - {{2b{v^3}} \\over {M\\left( t \\right)}}$$"}, {"identifier": "C", "content": "$$ - {{b{v^3}} \\over {M\\left( t \\right)}}$$"}, {"identifier": "D", "content": "$$ - {{b{v^3}} \\over {2M\\left( t \\right)}}$$"}] | ["C"] | null | Given $${{dM\left( t \right)} \over {dt}}$$ = bv<sup>2</sup>(t)
<br><br>In free space
no external force
so there in only thrust force on rocket.
<br><br>F<sub>thrust</sub> = v$${{dm} \over {dt}}$$
<br><br>Force on satellite = $$ - \overrightarrow v {{dm\left( t \right)} \over {dt}}$$
<br><br>M(t)a = – v (bv<sup>2</sup>... | mcq | jee-main-2020-online-5th-september-evening-slot | 11,703 |
SKiYDsQD4Ct55N6cgGjgy2xukg0ikgo3 | physics | laws-of-motion | newton's-laws-of-motion | A particle moving in the xy plane experiences a velocity dependent force
<br/>$$\overrightarrow F = k\left( {{v_y}\widehat i + {v_x}\widehat j} \right)$$
, where v<sub>x</sub>
and v<sub>y</sub>
are the <br/>x and y components of its velocity $$\overrightarrow v $$
. If $$\overrightarrow a $$
is the<br/> acceleration... | [{"identifier": "A", "content": "kinetic energy of particle is constant in time"}, {"identifier": "B", "content": "quantity $$\\overrightarrow v \\times \\overrightarrow a $$\n is constant in time"}, {"identifier": "C", "content": "quantity $$\\overrightarrow v .\\overrightarrow a $$\n is constant in time"}, {"identif... | ["B"] | null | Given $$\overrightarrow F = k\left( {{v_y}\widehat i + {v_x}\widehat j} \right)$$
<br><br>$$ \Rightarrow $$ m$$\overrightarrow a $$ = $$k\left( {{v_y}\widehat i + {v_x}\widehat j} \right)$$
<br><br>$$ \Rightarrow $$ $$\overrightarrow a = {k \over m}\left( {{v_y}\widehat i + {v_x}\widehat j} \right)$$
<br><br>Also $${... | mcq | jee-main-2020-online-6th-september-evening-slot | 11,704 |
ulxLHuLXJPG9A6mOXgjgy2xukfaiunlm | physics | laws-of-motion | newton's-laws-of-motion | A small ball of mass m is thrown upward with velocity u from the ground. The ball experiences a
resistive force mkv<sup>2</sup>
where v is its speed. The maximum height attained by the ball is : | [{"identifier": "A", "content": "$${1 \\over k}{\\tan ^{ - 1}}{{k{u^2}} \\over {2g}}$$"}, {"identifier": "B", "content": "$${1 \\over {2k}}{\\tan ^{ - 1}}{{k{u^2}} \\over g}$$"}, {"identifier": "C", "content": "$${1 \\over {2k}}\\ln \\left( {1 + {{k{u^2}} \\over g}} \\right)$$"}, {"identifier": "D", "content": "$${1 \\... | ["C"] | null | <img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734265973/exam_images/ndu9oh9g3o6khs3ynqdu.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2020 (Online) 4th September Evening Slot Physics - Laws of Motion Question 95 English Explanation">
<br><br>F<su... | mcq | jee-main-2020-online-4th-september-evening-slot | 11,705 |
SnyVgljqbBEkhYYC5Y1klrnkrah | physics | laws-of-motion | newton's-laws-of-motion | A particle is projected with velocity v<sub>0</sub> along x-axis. A damping force is acting on the particle which is proportional to the square of the distance from the origin i.e. ma = $$-$$ $$\alpha$$x<sup>2</sup>. The distance at which the particle stops : | [{"identifier": "A", "content": "$${\\left[ {{{3mv_0^2} \\over {2\\alpha }}} \\right]^{{1 \\over 3}}}$$"}, {"identifier": "B", "content": "$${\\left( {{{2{v_0}} \\over {3\\alpha }}} \\right)^{{1 \\over 3}}}$$"}, {"identifier": "C", "content": "$${\\left( {{{3v_0^2} \\over {2\\alpha }}} \\right)^{{1 \\over 2}}}$$"}, {"i... | ["A"] | null | Given, speed of projection = v<sub>0</sub><br/><br/>Damping force, F = ma = $$-$$ $$\alpha$$x<sup>2</sup><br/><br/>$$\Rightarrow$$ a = $$-$$ $$\alpha$$x<sup>2</sup> / m<br/><br/>Also, $$a = v{{dv} \over {dx}}$$<br/><br/>$$ \Rightarrow vdv = a\,dx = - {\alpha \over m}{x^2}dx$$<br/><br/>Integrating both sides, we get<b... | mcq | jee-main-2021-online-24th-february-evening-slot | 11,706 |
UOz9RWhqE536lvPDXO1kltjjskc | physics | laws-of-motion | newton's-laws-of-motion | A person standing on a spring balance inside a stationary lift measures 60 kg. The weight of that person if the lift descends with uniform downward acceleration of 1.8 m/s<sup>2</sup> will be ______________ N. [g = 10 m/s<sup>2</sup>] | [] | null | 492 | <p>The apparent weight $W_{\text{app}}$ of a person in an elevator moving with acceleration is given by:</p>
<p>$$W_{\text{app}} = m(g - a)$$</p>
<p>where:</p>
<ul>
<li>$W_{\text{app}}$ is the apparent weight,</li>
<li>$m$ is the mass of the person,</li>
<li>$g$ is the acceleration due to gravity,</li>
<li>$a$ is the a... | integer | jee-main-2021-online-26th-february-morning-slot | 11,707 |
0jRvuUta5DawVBBzDm1kltk07z8 | physics | laws-of-motion | newton's-laws-of-motion | A boy pushes a box of mass 2 kg with a force $$\overrightarrow F = \left( {20\widehat i + 10\widehat j} \right)N$$ on a frictionless surface. If the box was initially at rest, then ___________ m is displacement along the x-axis after 10s. | [] | null | 500 | $$\overrightarrow F = 20\widehat i + 10\widehat j$$<br><br>$$\overrightarrow a = {{\overrightarrow F } \over m} = {{20\widehat i + 10\widehat j} \over 2} = 10\widehat i + 5\widehat j$$<br><br>$$ \therefore $$ $$\overrightarrow s = {1 \over 2}\overrightarrow a {t^2} = {1 \over 2}\left( {10\widehat i + 5\widehat j} \r... | integer | jee-main-2021-online-26th-february-morning-slot | 11,708 |
9fCSuMy5gG5HdR8mm21kmipz2gi | physics | laws-of-motion | newton's-laws-of-motion | A body of mass 2 kg moves under a force of $$\left( {2\widehat i + 3\widehat j + 5\widehat k} \right)$$N. It starts from rest and was at the origin initially. After 4s, its new coordinates are (8, b, 20). The value of b is _____________. (Round off to the Nearest Integer) | [] | null | 12 | $$\overrightarrow F = (2\widehat i + 3\widehat j + 5\widehat k)N$$<br><br>time = 4 sec<br><br>As body start from rest therefore <br>position vector initially $$\overrightarrow {{r_i}} = (0\widehat i + 0\widehat j + 0\widehat k)$$ & <br>u (initial velocity) = 0<br><br>given, $${r_f} = (x\widehat i + y\widehat j + ... | integer | jee-main-2021-online-16th-march-evening-shift | 11,709 |
1krw6mhih | physics | laws-of-motion | newton's-laws-of-motion | A force $$\overrightarrow F = (40\widehat i + 10\widehat j)N$$ acts on a body of mass 5 kg. If the body starts from rest, its position vector $$\overrightarrow r $$ at time t = 10 s, will be : | [{"identifier": "A", "content": "$$(100\\widehat i + 400\\widehat j)m$$"}, {"identifier": "B", "content": "$$(100\\widehat i + 100\\widehat j)m$$"}, {"identifier": "C", "content": "$$(400\\widehat i + 100\\widehat j)m$$"}, {"identifier": "D", "content": "$$(400\\widehat i + 400\\widehat j)m$$"}] | ["C"] | null | $${{d\overrightarrow v } \over {dt}} = \overrightarrow a = {{\overrightarrow F } \over m} = (8\widehat i + 2\widehat j)m/{s^2}$$<br><br>$${{d\overrightarrow r } \over {dt}} = \overrightarrow v = (8t\widehat i + 2t\widehat j)m/s$$<br><br>$$\overrightarrow r = (8\widehat i + 2\widehat j){{{t^2}} \over 2}m$$<br><br>At ... | mcq | jee-main-2021-online-25th-july-evening-shift | 11,711 |
1ks19p4v2 | physics | laws-of-motion | newton's-laws-of-motion | A particle of mass M originally at rest is subjected to a force whose direction is constant but magnitude varies with time according to the relation <br/><br/>$$F = {F_0}\left[ {1 - {{\left( {{{t - T} \over T}} \right)}^2}} \right]$$<br/><br/>Where F<sub>0</sub> and T are constants. The force acts only for the time int... | [{"identifier": "A", "content": "2F<sub>0</sub>T/M"}, {"identifier": "B", "content": "F<sub>0</sub>T/2M"}, {"identifier": "C", "content": "4F<sub>0</sub>T/3M"}, {"identifier": "D", "content": "F<sub>0</sub>T/3M"}] | ["C"] | null | At t = 0, u = 0<br><br>$$a = {{{F_0}} \over M} - {{{F_0}} \over {M{T^2}}}{(t - T)^2} = {{dv} \over {dt}}$$<br><br>$$\int\limits_0^v {dv = \int\limits_{t = 0}^{2T} {\left( {{{{F_0}} \over M} - {{{F_0}} \over {M{T^2}}}{{(t - T)}^2}} \right)dt} } $$<br><br>$$V = \left[ {{{{F_0}} \over M}t} \right]_0^{2T} - {{{F_0}} \over ... | mcq | jee-main-2021-online-27th-july-evening-shift | 11,712 |
1ktaf4evo | physics | laws-of-motion | newton's-laws-of-motion | The initial mass of a rocket is 1000 kg. Calculate at what rate the fuel should be burnt so that the rocket is given an acceleration of 20 ms<sup>-2</sup>. The gases come out at a relative speed of 500 ms<sup>$$-$$1</sup> with respect to the rocket : [Use g = 10 m/s<sup>2</sup>] | [{"identifier": "A", "content": "6.0 $$\\times$$ 10<sup>2</sup> kg s<sup>$$-$$1</sup>"}, {"identifier": "B", "content": "500 kg s<sup>$$-$$1</sup>"}, {"identifier": "C", "content": "10 kg s<sup>$$-$$1</sup>"}, {"identifier": "D", "content": "60 kg s<sup>$$-$$1</sup>"}] | ["D"] | null | <img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734265354/exam_images/um2ylhlhee5khefa5rht.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2021 (Online) 26th August Morning Shift Physics - Laws of Motion Question 74 English Explanation"><br>$${F_{thru... | mcq | jee-main-2021-online-26th-august-morning-shift | 11,713 |
1l55jqcwa | physics | laws-of-motion | newton's-laws-of-motion | <p>A block of mass 2 kg moving on a horizontal surface with speed of 4 ms<sup>$$-$$1</sup> enters a rough surface ranging from x = 0.5 m to x = 1.5 m. The retarding force in this range of rough surface is related to distance by F = $$-$$kx where k = 12 Nm<sup>$$-$$1</sup>. The speed of the block as it just crosses the ... | [{"identifier": "A", "content": "zero"}, {"identifier": "B", "content": "1.5 ms<sup>$$-$$1</sup>"}, {"identifier": "C", "content": "2.0 ms<sup>$$-$$1</sup>"}, {"identifier": "D", "content": "2.5 ms<sup>$$-$$1</sup>"}] | ["C"] | null | <p>$$F = - 12x$$</p>
<p>$$mv{{dv} \over {dx}} = - 12x$$</p>
<p>$$\int_4^v {vdv = - 6\int_{0.5}^{1.5} {xdx} } $$ ($$m = 2$$ kg)</p>
<p>$${{{v^2} - 16} \over 2} = - 6\left[ {{{{{1.5}^2} - {{0.5}^2}} \over 2}} \right]$$</p>
<p>$${{{v^2} - 16} \over 2} = - 6$$</p>
<p>$$v = 2$$ m/sec</p> | mcq | jee-main-2022-online-28th-june-evening-shift | 11,715 |
1l58bbgj4 | physics | laws-of-motion | newton's-laws-of-motion | <p>A person is standing in an elevator. In which situation, he experiences weight loss?</p> | [{"identifier": "A", "content": "When the elevator moves upward with constant acceleration"}, {"identifier": "B", "content": "When the elevator moves downward with constant acceleration"}, {"identifier": "C", "content": "When the elevator moves upward with uniform velocity"}, {"identifier": "D", "content": "When the el... | ["B"] | null | <p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l5jhk4i8/1078b4ea-843e-4fbd-ab7c-95acb1ffb190/420cfd00-029a-11ed-a9b8-43edceee002f/file-1l5jhk4i9.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l5jhk4i8/1078b4ea-843e-4fbd-ab7c-95acb1ffb190/420cfd00-029a-11ed-a9b8-43edceee002f... | mcq | jee-main-2022-online-26th-june-morning-shift | 11,716 |
1l5alhxl9 | physics | laws-of-motion | newton's-laws-of-motion | <p>A force on an object of mass 100 g is $$\left( {10\widehat i + 5\widehat j} \right)$$ N. The position of that object at t = 2 s is $$\left( {a\widehat i + b\widehat j} \right)$$ m after starting from rest. The value of $${a \over b}$$ will be ___________.</p> | [] | null | 2 | <p>$$\overrightarrow F = m\overrightarrow a $$</p>
<p>$$ \Rightarrow \overrightarrow a = 100\widehat i + 50\widehat j$$</p>
<p>So, $$\overrightarrow S = {1 \over 2}\overrightarrow a {t^2}$$</p>
<p>$${1 \over 2}\left( {100\widehat i + 50\widehat j} \right){2^2}$$</p>
<p>$$ = 200\widehat i + 100\widehat j$$ m</p>
<p>s... | integer | jee-main-2022-online-25th-june-morning-shift | 11,717 |
1l5bbyej8 | physics | laws-of-motion | newton's-laws-of-motion | <p>An object of mass 5 kg is thrown vertically upwards from the ground. The air resistance produces a constant retarding force of 10 N throughout the motion. The ratio of time of ascent to the time of descent will be equal to : [Use g = 10 ms<sup>$$-$$2</sup>].</p> | [{"identifier": "A", "content": "1 : 1"}, {"identifier": "B", "content": "$$\\sqrt 2 $$ : $$\\sqrt 3 $$"}, {"identifier": "C", "content": "$$\\sqrt 3 $$ : $$\\sqrt 2 $$"}, {"identifier": "D", "content": "2 : 3"}] | ["B"] | null | <p>Let time taken to ascent is t<sub>1</sub> and that to descent is t<sub>2</sub>. Height will be same so</p>
<p>$$H = {1 \over 2} \times 12t_1^2 = {1 \over 2}\times8t_2^2$$</p>
<p>$$ \Rightarrow {{{t_1}} \over {{t_1}}} = {{\sqrt 2 } \over {\sqrt 3 }}$$</p> | mcq | jee-main-2022-online-24th-june-evening-shift | 11,718 |
1ldnxw0lp | physics | laws-of-motion | newton's-laws-of-motion | <p>Figures (a), (b), (c) and (d) show variation of force with time.</p>
<p><img src="data:image/png;base64,UklGRuoRAABXRUJQVlA4IN4RAABw+QCdASoAA3YCP4HA2WU2MCynIdHJUsAwCWlu/D64hYcHZ1+fsT+u3i7xNbQ7tz/iu/L6kb8NXnzai/bH8D421FKozbUUqjNtRSpyt2PRAzm82oxePoYjNtRSqMyK2iJ1F0MQ+M6zo7XNwbmDUM2EMNvkNmkR1HEB00Jec1s+J5fuGBzWz2SWR5A83... | [{"identifier": "A", "content": "Fig (c)"}, {"identifier": "B", "content": "Fig (d)"}, {"identifier": "C", "content": "Fig (a)"}, {"identifier": "D", "content": "Fig (b)"}] | ["D"] | null | <p>As we know that impulse is given by</p>
<p>$$I = \Delta P = F \times \Delta t$$
<br/><br/>or $ I=$ Area of $f-t$ graph</p>
<p>For fig (a)
<br/><br/>$\rightarrow \mathrm{I}=\frac{1}{2} \times$ base $\times$ height</p>
<p>$$
=\frac{1}{2} \times 0.5 \times 1=0.25 \mathrm{~N}-\mathrm{sec} .
$$</p>
<p>For fig (b),
<br/... | mcq | jee-main-2023-online-1st-february-evening-shift | 11,720 |
1lds9gcsm | physics | laws-of-motion | newton's-laws-of-motion | <p>A force acts for 20 s on a body of mass 20 kg, starting from rest, after which the force ceases and then body describes 50 m in the next 10 s. The value of force will be:</p> | [{"identifier": "A", "content": "40 N"}, {"identifier": "B", "content": "20 N"}, {"identifier": "C", "content": "5 N"}, {"identifier": "D", "content": "10 N"}] | ["C"] | null | <p>$$m = 20$$ kg</p>
<p>$$t = 20$$ sec.</p>
<p>Acceleration $$ = {F \over {20}}$$ m/s$$^2$$</p>
<p>$$\therefore$$ $$v = u + at$$</p>
<p>$$v = 0 + \left( {{F \over {20}}} \right)(20)$$</p>
<p>$$ = F$$ ms$$^{-1}$$</p>
<p>Now for next 10 sec.</p>
<p>$$S=ut$$</p>
<p>$$50=F(10)$$</p>
<p>$$F=5$$</p> | mcq | jee-main-2023-online-29th-january-evening-shift | 11,721 |
1ldyei7ng | physics | laws-of-motion | newton's-laws-of-motion | <p>Given below are two statements :</p>
<p>Statement I : An elevator can go up or down with uniform speed when its weight is balanced with the tension of its cable.</p>
<p>Statement II : Force exerted by the floor of an elevator on the foot of a person standing on it is more than his/her weight when the elevator goes ... | [{"identifier": "A", "content": "Both Statement I and Statement II are false"}, {"identifier": "B", "content": "Both Statement I and Statement II are true"}, {"identifier": "C", "content": "Statement I is false but Statement II is true"}, {"identifier": "D", "content": "Statement I is true but Statement II is false"}] | ["D"] | null | <p><b>Statement I</b> says that when the weight of an elevator is balanced with the tension of its cable, it can move up or down with a uniform speed. This is true because the weight of the elevator is balanced by the tension in the cable, which allows it to move smoothly and at a constant speed.</p>
<p><b>Statement I... | mcq | jee-main-2023-online-24th-january-morning-shift | 11,722 |
1lgswyy0y | physics | laws-of-motion | newton's-laws-of-motion | <p>A body of mass $$500 \mathrm{~g}$$ moves along $$\mathrm{x}$$-axis such that it's velocity varies with displacement $$\mathrm{x}$$ according to the relation $$v=10 \sqrt{x} \mathrm{~m} / \mathrm{s}$$ the force acting on the body is:-</p> | [{"identifier": "A", "content": "166 N"}, {"identifier": "B", "content": "5 N"}, {"identifier": "C", "content": "25 N"}, {"identifier": "D", "content": "125 N"}] | ["C"] | null | Given that the velocity of the body varies with displacement x according to the relation:
<br/><br/>
$$
v = 10\sqrt{x}\,\mathrm{ms}^{-1}
$$
<br/><br/>
To find the force acting on the body, we first need to find its acceleration, which can be obtained by differentiating the velocity with respect to time. However, we don... | mcq | jee-main-2023-online-11th-april-evening-shift | 11,724 |
1lh01adu4 | physics | laws-of-motion | newton's-laws-of-motion | <p>At any instant the velocity of a particle of mass $$500 \mathrm{~g}$$ is $$\left(2 t \hat{i}+3 t^{2} \hat{j}\right) \mathrm{ms}^{-1}$$. If the force acting on the particle at $$t=1 \mathrm{~s}$$ is $$(\hat{i}+x \hat{j}) \mathrm{N}$$. Then the value of $$x$$ will be:</p> | [{"identifier": "A", "content": "2"}, {"identifier": "B", "content": "4"}, {"identifier": "C", "content": "6"}, {"identifier": "D", "content": "3"}] | ["D"] | null | <p>Given the velocity vector of a particle $v = (2t \hat{i}+3 t^{2} \hat{j}) \, \text{ms}^{-1}$, the acceleration $a$ is the derivative of the velocity vector with respect to time. So, we have:</p>
<p>$a = \frac{dv}{dt} = (2 \hat{i} + 6t \hat{j}) \, \text{ms}^{-2}$.</p>
<p>At $t=1 \, \text{s}$, the acceleration $a$ is ... | mcq | jee-main-2023-online-8th-april-morning-shift | 11,725 |
lsamcmv7 | physics | laws-of-motion | newton's-laws-of-motion | A body of mass $4 \mathrm{~kg}$ experiences two forces $\vec{F}_1=5 \hat{i}+8 \hat{j}+7 \hat{k}$ and $\overrightarrow{\mathrm{F}}_2=3 \hat{i}-4 \hat{j}-3 \hat{k}$. The acceleration acting on the body is : | [{"identifier": "A", "content": "$2 \\hat{i}+\\hat{j}+\\hat{k}$"}, {"identifier": "B", "content": "$4 \\hat{i}+2 \\hat{j}+2 \\hat{k}$"}, {"identifier": "C", "content": "$-2 \\hat{i}-\\hat{j}-\\hat{k}$"}, {"identifier": "D", "content": "$2 \\hat{i}+3 \\hat{j}+3 \\hat{k}$"}] | ["A"] | null | <p>To find the acceleration acting on the body, we first need to determine the resultant force acting on the body by adding the two forces $\vec{F}_1$ and $\vec{F}_2$ vectorially. Then, we apply Newton's second law of motion, which states that the acceleration $\vec{a}$ of a body is directly proportional to the tot... | mcq | jee-main-2024-online-1st-february-evening-shift | 11,726 |
lsams161 | physics | laws-of-motion | newton's-laws-of-motion | A cricket player catches a ball of mass $120 \mathrm{~g}$ moving with $25 \mathrm{~m} / \mathrm{s}$ speed. If the catching process is completed in $0.1 \mathrm{~s}$ then the magnitude of force exerted by the ball on the hand of player will be (in SI unit) : | [{"identifier": "A", "content": "30"}, {"identifier": "B", "content": "24"}, {"identifier": "C", "content": "12"}, {"identifier": "D", "content": "25"}] | ["A"] | null | <p>The first step in solving this problem is to calculate the change in momentum of the ball when it is caught. The change in momentum, or impulse, is the product of the mass of the ball and the change in velocity (as momentum is mass times velocity).</p>
<p>The ball is initially moving with a velocity of $v_i = 25 \m... | mcq | jee-main-2024-online-1st-february-evening-shift | 11,727 |
lv0vyukq | physics | laws-of-motion | newton's-laws-of-motion | <p>A wooden block, initially at rest on the ground, is pushed by a force which increases linearly with time $$t$$. Which of the following curve best describes acceleration of the block with time :</p> | [{"identifier": "A", "content": "<img src=\"https://app-content.cdn.examgoal.net/fly/@width/image/1lv0ch3t9/85a63f0b-9cb2-4d0a-a130-32abeab5e072/1bf453d0-fad1-11ee-891c-2b72d88c1441/file-1lv0ch3ta.png?format=png\" data-orsrc=\"https://app-content.cdn.examgoal.net/image/1lv0ch3t9/85a63f0b-9cb2-4d0a-a130-32abeab5e072/1bf... | ["D"] | null | <p>Acceleration (a) $$=\frac{f-F}{m}$$</p>
<p>When applied force became equal to $$f_{\max }$$, block will start moving.</p>
<p>As $$F$$ increases linearly, so acceleration of also moving block will increase linearly.</p> | mcq | jee-main-2024-online-4th-april-morning-shift | 11,728 |
lv5gs19s | physics | laws-of-motion | newton's-laws-of-motion | <p>A player caught a cricket ball of mass $$150 \mathrm{~g}$$ moving at a speed of $$20 \mathrm{~m} / \mathrm{s}$$. If the catching process is completed in $$0.1 \mathrm{~s}$$, the magnitude of force exerted by the ball on the hand of the player is:</p> | [{"identifier": "A", "content": "150 N"}, {"identifier": "B", "content": "3 N"}, {"identifier": "C", "content": "30 N"}, {"identifier": "D", "content": "300 N"}] | ["C"] | null | <p>The force exerted by the ball on the hand can be calculated using the formula derived from Newton's second law of motion, which is $$F = \frac{\Delta p}{\Delta t}$$, where $$F$$ is the force, $$\Delta p$$ represents the change in momentum, and $$\Delta t$$ is the time over which this change occurs.</p>
<p>The chang... | mcq | jee-main-2024-online-8th-april-morning-shift | 11,729 |
lv7v4nwq | physics | laws-of-motion | newton's-laws-of-motion | <p>A wooden block of mass $$5 \mathrm{~kg}$$ rests on a soft horizontal floor. When an iron cylinder of mass $$25 \mathrm{~kg}$$ is placed on the top of the block, the floor yields and the block and the cylinder together go down with an acceleration of $$0.1 \mathrm{~ms}^{-2}$$. The action force of the system on the fl... | [{"identifier": "A", "content": "297 N"}, {"identifier": "B", "content": "291 N"}, {"identifier": "C", "content": "196 N"}, {"identifier": "D", "content": "294 N"}] | ["B"] | null | <p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1lwgm8yho/7978575d-e5d9-4b5e-8190-aed9b17e81d4/166e6dc0-1790-11ef-bb26-2db663948712/file-1lwgm8yhp.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1lwgm8yho/7978575d-e5d9-4b5e-8190-aed9b17e81d4/166e6dc0-1790-11ef-bb26-2db663948712... | mcq | jee-main-2024-online-5th-april-morning-shift | 11,731 |
lv9s20sm | physics | laws-of-motion | newton's-laws-of-motion | <p>A particle moves in $$x$$-$$y$$ plane under the influence of a force $$\vec{F}$$ such that its linear momentum is $$\overrightarrow{\mathrm{p}}(\mathrm{t})=\hat{i} \cos (\mathrm{kt})-\hat{j} \sin (\mathrm{kt})$$. If $$\mathrm{k}$$ is constant, the angle between $$\overrightarrow{\mathrm{F}}$$ and $$\overrightarrow{\... | [{"identifier": "A", "content": "$$\\frac{\\pi}{2}$$\n"}, {"identifier": "B", "content": "$$\\frac{\\pi}{3}$$\n"}, {"identifier": "C", "content": "$$\\frac{\\pi}{4}$$\n"}, {"identifier": "D", "content": "$$\\frac{\\pi}{6}$$"}] | ["A"] | null | <p>To find the angle between $$\vec{F}$$ and $$\overrightarrow{\mathrm{p}}$$, we first need to understand the relationship between force and momentum. The force $$\vec{F}$$ acting on a particle is related to the rate of change of its linear momentum $$\overrightarrow{\mathrm{p}}$$ with respect to time, as described by ... | mcq | jee-main-2024-online-5th-april-evening-shift | 11,732 |
Zdwyrk0wSeS0l84x | physics | laws-of-motion | spring-force | A block of mass $$m$$ is connected to another block of $$mass$$ $$M$$ by a spring (massless) of spring constant $$k.$$ The block are kept on a smooth horizontal plane. Initially the blocks are at rest and the spring is unstretched. Then a constant force $$F$$ starts acting on the block of mass $$M$$ to pull it. Find t... | [{"identifier": "A", "content": "$${{MF} \\over {\\left( {m + M} \\right)}}$$ "}, {"identifier": "B", "content": "$${{mF} \\over M}$$ "}, {"identifier": "C", "content": "$${{\\left( {M + m} \\right)F} \\over m}$$ "}, {"identifier": "D", "content": "$${{mF} \\over {\\left( {m + M} \\right)}}$$ "}] | ["D"] | null | <img class="question-image" src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734266542/exam_images/mnnsvhtxfruyq1khxxwt.webp" loading="lazy" alt="AIEEE 2007 Physics - Laws of Motion Question 119 English Explanation">
<br><b>From free body-diagram of $$m$$</b>
<br><br>we get $$T = ma$$
<br><br><b>From free body... | mcq | aieee-2007 | 11,733 |
lXexIz09ayYiSs8FQ73rsa0w2w9jx7ixwlm | physics | laws-of-motion | spring-force | A spring whose unstretched length is l has a force constant k. The spring is cut into two pieces of unstretched
lengths l<sub>1</sub> and l<sub>2</sub> where, l<sub>1</sub> = nl<sub>2</sub> and n is an integer. The ratio k<sub>1</sub>/k<sub>2</sub> of the corresponding force constant, k<sub>1</sub> and
k<sub>2</sub> wi... | [{"identifier": "A", "content": "$${1 \\over {{n^2}}}$$"}, {"identifier": "B", "content": "$${1 \\over n}$$"}, {"identifier": "C", "content": "n<sup>2</sup>"}, {"identifier": "D", "content": "n"}] | ["B"] | null | For a spring, k$$ \times $$$$l$$ = constant.
<br><br>$$ \therefore $$ k<sub>1</sub>$${l_1}$$ = k<sub>2</sub>$${l_2}$$
<br><br>$$ \Rightarrow $$ $${{{k_1}} \over {{k_2}}} = {{{l_2}} \over {{l_1}}}$$ = $${{{l_2}} \over {n{l_2}}}$$ = $${1 \over n}$$ | mcq | jee-main-2019-online-12th-april-evening-slot | 11,734 |
sPteMiYb0N0b1Xr6 | physics | magnetic-properties-of-matter | bar-magnet-or-magnetic-dipole | A magnetic needle lying parallel to a magnetic field requires $$W$$ units of work to turn it through $${60^ \circ }.$$ The torque needed to maintain the needle in this position will be : | [{"identifier": "A", "content": "$$\\sqrt 3 \\,W$$ "}, {"identifier": "B", "content": "$$W$$"}, {"identifier": "C", "content": "$${{\\sqrt 3 } \\over 2}W$$ "}, {"identifier": "D", "content": "$$2W$$ "}] | ["A"] | null | $$W = MB\left( {\cos {\theta _1} - \cos {\theta _2}} \right)$$
<br><br>$$ = MB\left( {\cos {\theta ^ \circ } - \cos {{60}^ \circ }} \right)$$
<br><br>$$ = MB\left( {1 - {1 \over 2}} \right) = {{MB} \over 2}$$
<br><br>$$\therefore$$ $$\tau = MB\,\sin \theta = MB\,\sin \,{60^ \circ }$$
<br><br>$$ = \sqrt 3 {{MB} \over ... | mcq | aieee-2003 | 11,736 |
FMEav1IEPCSCEKN8 | physics | magnetic-properties-of-matter | bar-magnet-or-magnetic-dipole | The magnetic lines of force inside a bar magnet | [{"identifier": "A", "content": "are from north-pole to south-pole of the magnet "}, {"identifier": "B", "content": "do not exist "}, {"identifier": "C", "content": "depend upon the area of cross-section of the bar magnet "}, {"identifier": "D", "content": "are from south-pole to north-pole of the Magnet "}] | ["D"] | null | As shown in the figure, the magnetic lines of force are directed from south to north inside a bar magnet.
<br><br><img class="question-image" src="https://imagex.cdn.examgoal.net/LjydkpWDw1TMq27xj/l3TxNXUeL7V0FyLytcjqoiCsf02Ds/e9W0JNvdk8O70vCFDyO7u4/image.svg" loading="lazy" alt="AIEEE 2003 Physics - Magnetic Propertie... | mcq | aieee-2003 | 11,737 |
qV4VDlhcI7bU9ulG | physics | magnetic-properties-of-matter | bar-magnet-or-magnetic-dipole | The length of a magnet is large compared to its width and breadth. The time period of its oscillation in a vibration magnetometer is $$2s.$$ The magnet is cut along its length into three equal parts and these parts are then placed on each other with their like poles together. The time period of this combination will b... | [{"identifier": "A", "content": "$$2\\sqrt 3 \\,s$$ "}, {"identifier": "B", "content": "$${2 \\over 3}\\,\\,s$$ "}, {"identifier": "C", "content": "$$2\\,s$$ "}, {"identifier": "D", "content": "$${2 \\over {\\sqrt 3 }}\\,s$$ "}] | ["B"] | null | $$T = 2\pi \sqrt {{1 \over {M \times B}}} $$ where $$I = {1 \over {12}}m{\ell ^2}$$
<br><br>When the magnet is cut into three pieces the pole strength will remain the same and
<br><br>$$M.{\rm I}.\left( {I'} \right) = {1 \over {12}}\left( {{m \over 3}} \right){\left( {{\ell \over 3}} \right)^2} \times 3 = {I \over 9}... | mcq | aieee-2004 | 11,738 |
mhzXiXTuZGuYVtGL | physics | magnetic-properties-of-matter | bar-magnet-or-magnetic-dipole | Two short bar magnets of length $$1$$ $$cm$$ each have magnetic moments $$1.20$$ $$A{m^2}$$ and $$1.00$$ $$A{m^2}$$ respectively. They are placed on a horizontal table parallel to each other with their $$N$$ poles pointing towards the South. They have a common magnetic equator and are separated by a distance of $$20.0... | [{"identifier": "A", "content": "$$3.6 \\times 10.5\\,\\,Wb/{m^2}$$ "}, {"identifier": "B", "content": "$$2.56 \\times 10.4\\,\\,Wb/{m^2}$$ "}, {"identifier": "C", "content": "$$3.50 \\times 10.4\\,\\,Wb/{m^2}$$ "}, {"identifier": "D", "content": "$$5.80 \\times 10.4\\,Wb/{m^2}$$ "}] | ["B"] | null | <img class="question-image" src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734267325/exam_images/oe39atonpeurp6ncwpaa.webp" loading="lazy" alt="JEE Main 2013 (Offline) Physics - Magnetic Properties of Matter Question 56 English Explanation">
<br><br>Given: $${M_1} = 1.20A{m^2}\,\,\,$$ and $$\,\,\,{M_2} = 1.0... | mcq | jee-main-2013-offline | 11,739 |
pOQu5CXttZt86nBQ | physics | magnetic-properties-of-matter | bar-magnet-or-magnetic-dipole | A magnetic needle of magnetic moment 6.7 $$\times$$ 10<sup>-2</sup> A m<sup>2</sup> and moment of inertia 7.5 $$\times$$ 10<sup>-6</sup> kg m<sup>2</sup> is
performing simple harmonic oscillations in a magnetic field of 0.01 T. Time taken for 10 complete oscillations is: | [{"identifier": "A", "content": "8.76 s"}, {"identifier": "B", "content": "6.65 s "}, {"identifier": "C", "content": "8.89 s"}, {"identifier": "D", "content": "6.98 s "}] | ["B"] | null | Given : Magnetic moment, M = 6.7 × 10<sup>–2</sup> Am<sup>2</sup>
<br><br>Magnetic field, B = 0.01 T
<br><br>Moment of inertia, I = 7.5 × 10<sup>–6</sup> Kgm<sup>2</sup>
<br><br>Using, T = $$2\pi \sqrt {{I \over {MB}}} $$
<br><br>= $$2\pi \sqrt {{{7.5 \times {{10}^{ - 6}}} \over {6.7 \times {{10}^{ - 2}} \times 0.01}}}... | mcq | jee-main-2017-offline | 11,740 |
skH7KFy3WbDIneKvpqw1A | physics | magnetic-properties-of-matter | bar-magnet-or-magnetic-dipole | A magnet of total magnetic moment 10<sup>-2</sup> $${\widehat i}$$ A-m<sup>2</sup> is placed in a time varying magnetic field, B$${\widehat i}$$ (cos $$\omega t$$) where B = 1 Tesla and $$\omega $$ = 0.125 rad/s. The work done for reversing the direction of the magnetic moment at t = 1 second, is - | [{"identifier": "A", "content": "0.014 J"}, {"identifier": "B", "content": "0.028 J"}, {"identifier": "C", "content": "0.01 J"}, {"identifier": "D", "content": "0.007 J"}] | ["A"] | null | <p>To determine the work done in reversing the direction of a magnetic moment in a time-varying magnetic field, we'll follow these steps:</p>
<p><strong>Given:</strong></p>
<p><p>Magnetic moment: $\mathbf{m} = 10^{-2} \hat{i}$ A·m²</p></p>
<p><p>Magnetic field: $\mathbf{B}(t) = B \cos(\omega t) \hat{i}$, where $B = 1$... | mcq | jee-main-2019-online-10th-january-morning-slot | 11,741 |
tdGV4kawhyFZKigfSES8o | physics | magnetic-properties-of-matter | bar-magnet-or-magnetic-dipole | Two magnetic dipoles X and Y are placed at
a separation d, with their axes perpendicular to
each other. The dipole moment of Y is twice
that of X. A particle of charge q is passing,
through their midpoint P, at angle q = 45° with
the horizontal line, as shown in figure. What
would be the magnitude of force on the parti... | [{"identifier": "A", "content": "$$ \\left( {{{{\\mu _0}} \\over {4\\pi }}} \\right){2M \\over {{{\\left( {d/2} \\right)}^3}}} \\times qv$$"}, {"identifier": "B", "content": "$$ \\left( {{{{\\mu _0}} \\over {4\\pi }}} \\right){M \\over {{{\\left( {d/2} \\right)}^3}}} \\times qv$$"}, {"identifier": "C", "content": "$$\\... | ["D"] | null | $${\overrightarrow F _m} = q\left( {\overrightarrow V \times \overrightarrow B } \right)$$<br><br>
$$\overrightarrow B = {\overrightarrow B _x} + {\overrightarrow B _y}$$
<img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734263661/exam_images/mqroh9qemnn9be7kvrlv.webp" style="max-width: 100%;height: auto;... | mcq | jee-main-2019-online-8th-april-evening-slot | 11,742 |
dDhyuQwHaCnCoCxmHnjgy2xuketxlgem | physics | magnetic-properties-of-matter | bar-magnet-or-magnetic-dipole | A small bar magnet placed with its axis <br/>at 30<sup>o</sup> with an external field of 0.06 T <br/>experiences a torque of 0.018 Nm. The <br/>minimum work required to rotate it from its <br/>stable to unstable equilibrium position is : | [{"identifier": "A", "content": "6.4 $$ \\times $$ 10<sup>-2</sup> J"}, {"identifier": "B", "content": "9.2 $$ \\times $$ 10<sup>-3</sup> J"}, {"identifier": "C", "content": "7.2 $$ \\times $$ 10<sup>-2</sup> J"}, {"identifier": "D", "content": "11.7 $$ \\times $$ 10<sup>-3</sup> J"}] | ["C"] | null | Torque on a bar magnet :
<br><br>$$\tau = MB\,\sin \theta $$
<br><br>Here, $$\theta $$ = 30º, I = 0.018 N-m, B = 0.06 T
<br><br>$$0.018 = M \times 0.06 \times 0.5$$
<br><br>$$ \Rightarrow M = 0.6\,A{m^2}$$<br><br>$$W = {U_f} - {U_i}$$<br><br>$$ = MB(\cos {\theta _i} - \cos {\theta _f})$$<br><br>$$ = 0.6 \times 0.06(1... | mcq | jee-main-2020-online-4th-september-morning-slot | 11,743 |
1l58huukt | physics | magnetic-properties-of-matter | bar-magnet-or-magnetic-dipole | <p>A bar magnet having a magnetic moment of 2.0 $$\times$$ 10<sup>5</sup> JT<sup>$$-$$1</sup>, is placed along the direction of uniform magnetic field of magnitude B
= 14 $$\times$$ 10<sup>$$-$$5</sup> T. The work done in rotating the magnet slowly through 60$$^\circ$$ from the direction of field is :</p> | [{"identifier": "A", "content": "14 J"}, {"identifier": "B", "content": "8.4 J"}, {"identifier": "C", "content": "4 J"}, {"identifier": "D", "content": "1.4 J"}] | ["A"] | null | <p>$$U = - \overrightarrow M \,.\,\overrightarrow B $$</p>
<p>So $${U_f} - {U_i} = - MB(1 - \cos \theta )$$</p>
<p>$$ = - 14J$$</p>
<p>So $$W = - \Delta U = 14J$$</p> | mcq | jee-main-2022-online-26th-june-evening-shift | 11,745 |
1ldpjobc3 | physics | magnetic-properties-of-matter | bar-magnet-or-magnetic-dipole | <p>A bar magnet with a magnetic moment $$5.0 \mathrm{Am}^{2}$$ is placed in parallel position relative to a magnetic field of $$0.4 \mathrm{~T}$$. The amount of required work done in turning the magnet from parallel to antiparallel position relative to the field direction is _____________.</p> | [{"identifier": "A", "content": "zero"}, {"identifier": "B", "content": "1 J"}, {"identifier": "C", "content": "2 J"}, {"identifier": "D", "content": "4 J"}] | ["D"] | null | $W=-M B\left(\cos \theta_{2}-\cos \theta_{1}\right)$
<br/><br/>$$
\begin{aligned}
= & -0.4 \times 5\left[\cos 180^{\circ}-\cos 0\right] \\\\
= & 4 \mathrm{~J}
\end{aligned}
$$ | mcq | jee-main-2023-online-31st-january-morning-shift | 11,746 |
1lgvrck2h | physics | magnetic-properties-of-matter | bar-magnet-or-magnetic-dipole | <p>A bar magnet is released from rest along the axis of a very long vertical copper tube. After some time the magnet will</p> | [{"identifier": "A", "content": "move down with almost constant speed"}, {"identifier": "B", "content": "move down with an acceleration equal to $$\\mathrm{g}$$"}, {"identifier": "C", "content": "move down with an acceleration greater than $$\\mathrm{g}$$"}, {"identifier": "D", "content": "oscillate inside the tube"}] | ["A"] | null | <p>When a bar magnet is released from rest along the axis of a very long vertical copper tube, it will move down with an almost constant speed after some time. </p>
<p>As the magnet falls, it moves through the copper tube, inducing eddy currents in the tube. These eddy currents, in turn, create an opposing magnetic fie... | mcq | jee-main-2023-online-10th-april-evening-shift | 11,747 |
O7dDiQkrG322WKfx | physics | magnetic-properties-of-matter | earth-magnetism | A thin rectangular magnet suspended freely has a period of oscillation equal to $$T.$$ Now it is broken into two equal halves (each having half of the original length) and one piece is made to oscillate freely in the same field. If its period of oscillation is $$T',$$ the ratio $${{T'} \over T}$$ is | [{"identifier": "A", "content": "$${1 \\over {2\\sqrt 2 }}$$ "}, {"identifier": "B", "content": "$${1 \\over 2}$$ "}, {"identifier": "C", "content": "$$2$$ "}, {"identifier": "D", "content": "$${1 \\over 4}$$ "}] | ["B"] | null | <b>KEY CONCEPT :</b> The time period of a rectangular magnet oscillating in earth's magnetic field is given by
<br><br>$$T = 2\pi \sqrt {{I \over {\mu {B_H}}}} $$
<br><br>where $$I=$$ Moment of inertia of the rectangular magnet
<br><br>$$\mu = $$ Magnetic moment
<br><br>$${B_H} = $$ Horizontal component of the earth'... | mcq | aieee-2003 | 11,750 |
6WSZr8XzO1ftOsYxPeCal | physics | magnetic-properties-of-matter | earth-magnetism | A fighter plane of length 20 m, wing span (distance from tip of one wing to the tip of the other wing) of 15 m and height 5 m is flying towards east over Delhi. Its speed is 240 ms<sup>−1</sup>. The earth’s magnetic field over Delhi is 5 $$ \times $$10<sup>−5</sup> T with the declination angle ~ 0<sup>o</sup> and dip o... | [{"identifier": "A", "content": "V<sub>B</sub> = 45 m<sub>V</sub>; V<sub>W</sub> = 120 m<sub>V</sub> with right side of pilot at higher voltage"}, {"identifier": "B", "content": "V<sub>B</sub> = 45 m<sub>V</sub>; V<sub>W</sub> = 120 m<sub>V</sub> with left side of pilot at higher voltage"}, {"identifier": "C", "conte... | ["B"] | null | <img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734264007/exam_images/zp085wyyzm30dybdwr3r.webp" style="max-width: 100%; height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2016 (Online) 10th April Morning Slot Physics - Magnetic Properties of Matter Question 51 English Explanation ... | mcq | jee-main-2016-online-10th-april-morning-slot | 11,751 |
wW7I1LJwakQxcg5usjljn | physics | magnetic-properties-of-matter | earth-magnetism | At some location on earth, the horizontal component of earth’s magnetic field is 18 × 10<sup>–6</sup> T. At this location, magnetic needle of length 0.12 m and pole strength 1.8 Am is suspended from its mid-point using a thread, it makes 45<sup>o</sup> angle with horizontal in equilibrium. To keep this needle horizonta... | [{"identifier": "A", "content": "3.6 $$ \\times $$ 10<sup>$$-$$5</sup> N"}, {"identifier": "B", "content": "1.8 $$ \\times $$ 10<sup>$$-$$5</sup> N"}, {"identifier": "C", "content": "1.3 $$ \\times $$ 10<sup>$$-$$5</sup> N"}, {"identifier": "D", "content": "6.5 $$ \\times $$ 10<sup>$$-$$5</sup> N"}] | ["D"] | null | Without applied forces, (in equilibrium position) the needle will stay in the resultant magnetic field of earth. Hence, the dip ' $\theta$ ' at this place is $45^{\circ}$ (given).
<br><br><img src="https://app-content.cdn.examgoal.net/fly/@width/image/6y3zli1lj4u81jc/7247f54e-79a4-4297-8bf7-cd3dbddcd079/0e4a3480-0fb7-1... | mcq | jee-main-2019-online-10th-january-evening-slot | 11,752 |
D7s7WIQA48T6bBoyWh3rsa0w2w9jx3ox5th | physics | magnetic-properties-of-matter | earth-magnetism | A magnetic compass needle oscillates 30 times per minute at a place where the dip is 45<sup>o</sup>, and 40 times per
minute where the dip is 30<sup>o</sup>. If B<sub>1</sub> and B<sub>2</sub> are respectively the total magnetic field due to the earth at the two
places, then the ratio $${{{B_1}} \over {{B_2}}}$$ is bes... | [{"identifier": "A", "content": "1.8"}, {"identifier": "B", "content": "2.2"}, {"identifier": "C", "content": "0.7"}, {"identifier": "D", "content": "3.6"}] | ["C"] | null | $${f_1} = {1 \over {2\pi }}\sqrt {{{\mu {B_1}\cos {{45}^o}} \over I}} $$<br><br>
$${f_2} = {1 \over {2\pi }}\sqrt {{{\mu {B_2}\cos {{30}^o}} \over I}} $$<br><br>
$${{{f_1}} \over {{f_2}}} = {{{B_1}\cos {{45}^o}} \over {{B_1}\cos {{30}^o}}}$$<br><br>
$$ \therefore $$ $${{{B_1}} \over {{B_2}}} = 0.7$$ | mcq | jee-main-2019-online-12th-april-morning-slot | 11,753 |
IRpj4ExeE8oPTxrF0c1kmhou325 | physics | magnetic-properties-of-matter | earth-magnetism | A bar magnet of length 14 cm is placed in the magnetic meridian with its north pole pointing towards the geographic north pole. A neutral point is obtained at a distance of 18 cm from the center of the magnet. If B<sub>H</sub> = 0.4 G, the magnetic moment of the magnet is : (1G = 10<sup>$$-$$4</sup> T) | [{"identifier": "A", "content": "2.880 $$\\times$$ 10<sup>2</sup> J T<sup>$$-$$1</sup>"}, {"identifier": "B", "content": "2.880 J T<sup>$$-$$1</sup>"}, {"identifier": "C", "content": "2.880 $$\\times$$ 10<sup>3</sup> J T<sup>$$-$$1</sup>"}, {"identifier": "D", "content": "28.80 J T<sup>$$-$$1</sup>"}] | ["B"] | null | <img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734267025/exam_images/trtjweuwiwv1to15n92b.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2021 (Online) 16th March Morning Shift Physics - Magnetic Properties of Matter Question 36 English Explanation">... | mcq | jee-main-2021-online-16th-march-morning-shift | 11,754 |
1krqd4wnj | physics | magnetic-properties-of-matter | earth-magnetism | At an angle of 30$$^\circ$$ to the magnetic meridian, the apparent dip is 45$$^\circ$$. Find the true dip : | [{"identifier": "A", "content": "$${\\tan ^{ - 1}}\\sqrt 3 $$"}, {"identifier": "B", "content": "$${\\tan ^{ - 1}}{1 \\over {\\sqrt 3 }}$$"}, {"identifier": "C", "content": "$${\\tan ^{ - 1}}{2 \\over {\\sqrt 3 }}$$"}, {"identifier": "D", "content": "$${\\tan ^{ - 1}}{{\\sqrt 3 } \\over 2}$$"}] | ["D"] | null | $$A\tan \delta = \tan \delta '\cos \theta $$<br><br>$$ = \tan 45^\circ \cos 30^\circ $$<br><br>$$\tan \delta = 1 \times {{\sqrt 3 } \over 2}$$<br><br>$$\delta = {\tan ^{ - 1}}\left( {{{\sqrt 3 } \over 2}} \right)$$ | mcq | jee-main-2021-online-20th-july-evening-shift | 11,755 |
1krstkhv7 | physics | magnetic-properties-of-matter | earth-magnetism | Choose the correct option | [{"identifier": "A", "content": "True dip is always equal to apparent dip."}, {"identifier": "B", "content": "True dip is not mathematically related to apparent dip."}, {"identifier": "C", "content": "True dip is less than the apparent dip."}, {"identifier": "D", "content": "True dip is always greater than the apparent... | ["C"] | null | Let apparent dip $$\theta $$<sub>$$a$$</sub>.
<br><br>$$\tan ({\theta _a}) = {{\tan ({\theta _T})} \over {\cos \phi }}$$<br><br>$$ \Rightarrow {\theta _a} \ge {\theta _T}$$<br><br>$$\therefore$$ True dip is less than apparent dip. | mcq | jee-main-2021-online-22th-july-evening-shift | 11,756 |
1l547l3c4 | physics | magnetic-properties-of-matter | earth-magnetism | <p>At a certain place the angle of dip is 30$$^\circ$$ and the horizontal component of earth's magnetic field is 0.5 G. The earth's total magnetic field (in G), at that certain place, is :</p> | [{"identifier": "A", "content": "$${1 \\over {\\sqrt 3 }}$$"}, {"identifier": "B", "content": "$${1 \\over 2}$$"}, {"identifier": "C", "content": "$$\\sqrt 3 $$"}, {"identifier": "D", "content": "1"}] | ["A"] | null | <p>$${B_H} = B\cos 30^\circ $$</p>
<p>$$ \Rightarrow B = {1 \over {\sqrt 3 }}G$$</p> | mcq | jee-main-2022-online-29th-june-morning-shift | 11,757 |
1l6f4wzmn | physics | magnetic-properties-of-matter | earth-magnetism | <p>An electron with energy 0.1 keV moves at right angle to the earth's magnetic field of 1 $$\times$$ 10<sup>$$-$$4</sup> Wbm<sup>$$-$$2</sup>. The frequency of revolution of the electron will be :</p>
<p>(Take mass of electron = 9.0 $$\times$$ 10<sup>$$-$$31</sup> kg)</p> | [{"identifier": "A", "content": "$$1.6 \\times 10^{5} \\mathrm{~Hz}$$"}, {"identifier": "B", "content": "$$5.6 \\times 10^{5} \\mathrm{~Hz}$$"}, {"identifier": "C", "content": "$$2.8 \\times 10^{6} \\mathrm{~Hz}$$"}, {"identifier": "D", "content": "$$1.8 \\times 10^{6} \\mathrm{~Hz}$$"}] | ["C"] | null | <p>$$T = {{2\pi m} \over {Bq}}$$</p>
<p>$$\Rightarrow$$ Frequency $$f = {{Bq} \over {2\pi m}}$$</p>
<p>$$ = {{{{10}^{ - 4}} \times 1.6 \times {{10}^{ - 19}}} \over {2\pi \times 9 \times {{10}^{ - 31}}}}$$</p>
<p>$$ \simeq 2.8 \times {10^6}$$ Hz</p> | mcq | jee-main-2022-online-25th-july-evening-shift | 11,758 |
1l6ji3kv8 | physics | magnetic-properties-of-matter | earth-magnetism | <p>Two bar magnets oscillate in a horizontal plane in earth's magnetic field with time periods of $$3 \mathrm{~s}$$ and $$4 \mathrm{~s}$$ respectively. If their moments of inertia are in the ratio of $$3: 2$$, then the ratio of their magnetic moments will be:</p> | [{"identifier": "A", "content": "2 : 1"}, {"identifier": "B", "content": "8 : 3"}, {"identifier": "C", "content": "1 : 3"}, {"identifier": "D", "content": "27 : 16"}] | ["B"] | null | <p>$$T = 2\pi \sqrt {{I \over {M{B_H}}}} $$</p>
<p>$$ \Rightarrow {{{T_1}} \over {{T_2}}} = \sqrt {{{{I_1}} \over {{I_2}}}} \sqrt {{{{M_2}} \over {{M_1}}}} $$</p>
<p>$$ \Rightarrow {3 \over 4} = \sqrt {{3 \over 2}} \sqrt {{{{M_2}} \over {{M_1}}}} $$</p>
<p>$$ \Rightarrow {{{M_1}} \over {{M_2}}} = {3 \over 2} \times {{1... | mcq | jee-main-2022-online-27th-july-morning-shift | 11,759 |
1l6ji5x05 | physics | magnetic-properties-of-matter | earth-magnetism | <p>A magnet hung at $$45^{\circ}$$ with magnetic meridian makes an angle of $$60^{\circ}$$ with the horizontal. The actual value of the angle of dip is -</p> | [{"identifier": "A", "content": "$$\\tan ^{-1}\\left(\\sqrt{\\frac{3}{2}}\\right)$$"}, {"identifier": "B", "content": "$$\\tan ^{-1}(\\sqrt{6})$$"}, {"identifier": "C", "content": "$$\\tan ^{-1}\\left(\\sqrt{\\frac{2}{3}}\\right)$$"}, {"identifier": "D", "content": "$$\n\\tan ^{-1}\\left(\\sqrt{\\frac{1}{2}}\\right)\n$... | ["A"] | null | <p>$$\tan 60^\circ = {{{B_0}\sin \delta } \over {{B_0}\cos \delta \cos 45^\circ }}$$</p>
<p>$$ \Rightarrow \tan \delta = \sqrt {{3 \over 2}} $$</p>
<p>$$ \Rightarrow \delta = {\tan ^{ - 1}}\left( {\sqrt {{3 \over 2}} } \right)$$</p> | mcq | jee-main-2022-online-27th-july-morning-shift | 11,760 |
1l6rhoxgq | physics | magnetic-properties-of-matter | earth-magnetism | <p>The vertical component of the earth's magnetic field is $$6 \times 10^{-5} \mathrm{~T}$$ at any place where the angle of dip is $$37^{\circ}$$. The earth's resultant magnetic field at that place will be $$\left(\right.$$Given $$\left.\tan 37^{\circ}=\frac{3}{4}\right)$$</p> | [{"identifier": "A", "content": "$$8 \\times 10^{-5} \\mathrm{~T}$$"}, {"identifier": "B", "content": "$$6 \\times 10^{-5} \\mathrm{~T}$$"}, {"identifier": "C", "content": "$$5 \\times 10^{-4} \\mathrm{~T}$$"}, {"identifier": "D", "content": "$$1 \\times 10^{-4} \\mathrm{~T}$$"}] | ["D"] | null | <p><img src="https://app-content.cdn.examgoal.net/fly/@width/image/1l7e9glk3/aa6b79e5-09ca-4b9f-baaf-fff867122aae/1a76b730-2753-11ed-a077-1f1e3989e798/file-1l7e9glk4.png?format=png" data-orsrc="https://app-content.cdn.examgoal.net/image/1l7e9glk3/aa6b79e5-09ca-4b9f-baaf-fff867122aae/1a76b730-2753-11ed-a077-1f1e3989e798... | mcq | jee-main-2022-online-29th-july-evening-shift | 11,762 |
1lgrjrll5 | physics | magnetic-properties-of-matter | earth-magnetism | <p>A compass needle oscillates 20 times per minute at a place where the dip is $$30^{\circ}$$ and 30 times per minute where the dip is $$60^{\circ}$$. The ratio of total magnetic field due to the earth at two places respectively is $$\frac{4}{\sqrt{x}}$$. The value of $$x$$ is</p> | [] | null | 243 | $$
\begin{aligned}
& \text {Period of oscillation } \alpha \frac{1}{\sqrt{B_{\mathrm{H}}}} \\\\
& \mathrm{T} \alpha \frac{1}{\sqrt{\mathrm{B} \cos \theta}} \Rightarrow \frac{T_1}{\mathrm{~T}_2}=\sqrt{\frac{\mathrm{B}_2 \cos \theta_2}{\mathrm{~B}_1 \cos \theta_1}} \\\\
& \Rightarrow \frac{60 / 20}{60 / 30}=\sqrt{\frac{\... | integer | jee-main-2023-online-12th-april-morning-shift | 11,763 |
lxi5dqpu8KT455Qj | physics | magnetic-properties-of-matter | magnetic-properties-of-matter | Curie temperature is the temperature above which | [{"identifier": "A", "content": "a ferromagnetic material becomes paramagnetic "}, {"identifier": "B", "content": "a paramagnetic material becomes diamagnetic "}, {"identifier": "C", "content": "a ferromagnetic material becomes diamagnetic "}, {"identifier": "D", "content": "a paramagnetic material becomes ferromagneti... | ["A"] | null | <p>The Curie temperature is the temperature above which a ferromagnetic material becomes paramagnetic. </p>
<p>Ferromagnetic materials have a high degree of magnetization in the presence of a magnetic field. Above the Curie temperature, these materials lose their ferromagnetic behavior and become paramagnetic, meaning ... | mcq | aieee-2004 | 11,764 |
WDtUzNJOuUtiySe6 | physics | magnetic-properties-of-matter | magnetic-properties-of-matter | The materials suitable for making electromagnets should have | [{"identifier": "A", "content": "high retentivity and low coercivity "}, {"identifier": "B", "content": "low retentivity and low coercivity "}, {"identifier": "C", "content": "high retentivity and high coercivity "}, {"identifier": "D", "content": "low retentivity and high coercivity "}] | ["B"] | null | <p>Materials suitable for making electromagnets should have low retentivity and low coercivity.</p>
<p>Retentivity (or remanence) is the ability of a magnetic material to retain its magnetism after the removal of the magnetizing force. For an electromagnet, we want this to be low, as we want the magnet to only be magne... | mcq | aieee-2004 | 11,765 |
niRU9jARoFtaL7H1 | physics | magnetic-properties-of-matter | magnetic-properties-of-matter | A magnetic needle is kept in a non-uniform magnetic field. It experiences : | [{"identifier": "A", "content": "neither a force nor a torque "}, {"identifier": "B", "content": "a torque but not a force "}, {"identifier": "C", "content": "a force but not a torque "}, {"identifier": "D", "content": "a force and a torque "}] | ["D"] | null | A magnetic needle kept in non uniform magnetic field experience a force and torque due to unequal forces acting on poles. | mcq | aieee-2005 | 11,766 |
ERT4YS8a74gtkmnb | physics | magnetic-properties-of-matter | magnetic-properties-of-matter | Needles $${N_1}$$, $${N_2}$$ and $${N_3}$$ are made of ferromagnetic, a paramagnetic and a diamagnetic substance respectively. A magnet when brought close to them will | [{"identifier": "A", "content": "attract $${N_1}$$ and $${N_2}$$ strongly but repel $${N_3}$$ "}, {"identifier": "B", "content": "attract $${N_1}$$ strongly, $${N_2}$$ weakly and repel $${N_3}$$ weakly "}, {"identifier": "C", "content": "attract $${N_1}$$ strongly, but repel $${N_2}$$ and $${N_3}$$ weakly"}, {"identifi... | ["B"] | null | Ferromagnetic substance has magnetic domains whereas para-magnetic substances have magnetic dipoles which get attracted to a magnetic field. Diamagnetic substances do not have magnetic dipole but in the presence of external magnetic field due to their orbital motion of electrons these substances are repelled. | mcq | aieee-2006 | 11,767 |
d9HAj6Cs5kMUufPN | physics | magnetic-properties-of-matter | magnetic-properties-of-matter | Relative permittivity and permeability of a material $${\varepsilon _r}$$ and $${\mu _r},$$ respectively. Which of the following values of these quantities are allowed for a diamagnetic material? | [{"identifier": "A", "content": "$${\\varepsilon _r} = 0.5,\\,\\,{\\mu _r} = 1.5$$ "}, {"identifier": "B", "content": "$${\\varepsilon _r} = 1.5,\\,\\,{\\mu _r} = 0.5$$ "}, {"identifier": "C", "content": "$${\\varepsilon _r} = 0.5,\\,\\,{\\mu _r} = 0.5$$ "}, {"identifier": "D", "content": "$${\\varepsilon _r} = 1.5,\\,... | ["B"] | null | For a diamagnetic material, the value of $${\mu _r}$$ is less than one. For any material, the value of $${ \in _r}$$ is always greater than $$1.$$ | mcq | aieee-2008 | 11,768 |
4A7SjeO13G5jJ1jE | physics | magnetic-properties-of-matter | magnetic-properties-of-matter | The coercivity of a small magnet where the ferromagnet gets demagnetized is $$3 \times {10^3}\,A{m^{ - 1}}.$$ The current required to be passed in a solenoid of length $$10$$ $$cm$$ and number of turns $$100,$$ so that the magnet gets demagnetized when inside the solenoid, is : | [{"identifier": "A", "content": "$$30$$ $$mA$$ "}, {"identifier": "B", "content": "$$60$$ $$mA$$ "}, {"identifier": "C", "content": "$$3$$ $$A$$ "}, {"identifier": "D", "content": "$$6A$$ "}] | ["C"] | null | Magnetic field in solenoid $$B = {\mu _0}ni$$
<br><br>$$ \Rightarrow {B \over {{\mu _0}}} = ni$$
<br><br>(Where $$n=$$ number of turns per unit length)
<br><br>$$ \Rightarrow {B \over {{\mu _0}}} = {{Ni} \over L}$$
<br><br>$$ \Rightarrow 3 \times {10^3} = {{100i} \over {10 \times {{10}^{ - 2}}}}$$
<br><br>$$ \Rightarro... | mcq | jee-main-2014-offline | 11,769 |
yYLCy79awmF74toK1su13 | physics | magnetic-properties-of-matter | magnetic-properties-of-matter | The $$B$$-$$H$$ curve for a ferromagnet is shown in the figure. The ferromagnet is placed inside a long solended with $$1000$$ turns/cm. The current that should be passed in the solended to demagnetise the ferromagnet completely is :
<br/><br/><img src="data:image/png;base64,UklGRsQRAABXRUJQVlA4ILgRAACw/gCdASoAA2cCP4HA... | [{"identifier": "A", "content": "$$1$$ $$mA$$"}, {"identifier": "B", "content": "$$2$$ $$mA$$"}, {"identifier": "C", "content": "$$20\\,\\mu A$$ "}, {"identifier": "D", "content": "$$40\\,\\mu A$$"}] | ["A"] | null | Given that,
<br><br>In the solenoid there is 1000 turns in 1 cm.
<br><br>$$\therefore\,\,\,\,$$ In 100 cm or 1 m no of turns
<br><br>= 1000 $$ \times $$ 100 = 10<sup>5</sup> turns/m
<br><br>$$\therefore\,\,\,\,$$ No of turns, n = 10<sup>5</sup>
<br><br>Correctivity of ferromagnet, H = 100 A/m
<br><br>As we know, ... | mcq | jee-main-2018-online-15th-april-morning-slot | 11,770 |
KWhFEVUx8ymqDgdInkkN4 | physics | magnetic-properties-of-matter | magnetic-properties-of-matter | A bar magnet is demagnetized by inserting it inside a solenoid of length 0.2 m, 100 turns, and carrying a current of 5.2 A. The corecivity of the bar magnet is : | [{"identifier": "A", "content": "285 A/m"}, {"identifier": "B", "content": "2600 A/m"}, {"identifier": "C", "content": "520 A/m"}, {"identifier": "D", "content": "1200 A/m"}] | ["B"] | null | Coercivity, H = $${B \over {{\mu _0}}}$$
<br><br>Inside solenoid the magnetic field,
<br><br>B = $$\mu $$<sub>0</sub>ni
<br><br>$$ \therefore $$ H = $${{{\mu _0}ni} \over {{\mu _0}}}$$
<br><br>= ni
<br><br>= $${N \over \ell } \times i$$
<br><br>= $${{100} \over {0.2}} \times 5.2$$
<br><br>= 2600 A/... | mcq | jee-main-2019-online-9th-january-morning-slot | 11,771 |
FmwZBIlFV560WL4XuDfFJ | physics | magnetic-properties-of-matter | magnetic-properties-of-matter | A paramagnetic substance in the form of a cube with sides 1 cm has a magnetic dipole moment of 20 $$ \times $$ 10<sup>–6</sup> J/ T when a magnetic intensity of 60 $$ \times $$ 10<sup>3</sup> A/m is applied. Its magnetic susceptibility is
| [{"identifier": "A", "content": "3.3 $$ \\times $$ 10<sup>\u20134</sup>"}, {"identifier": "B", "content": "2.3 $$ \\times $$ 10<sup>\u20132</sup>"}, {"identifier": "C", "content": "4.3 $$ \\times $$ 10<sup>\u20132</sup>"}, {"identifier": "D", "content": "3.3 $$ \\times $$ 10<sup>\u20132</sup>"}] | ["A"] | null | x = $${1 \over H}$$
<br><br>I = $${{Magnetic\,moment} \over {Volume}}$$
<br><br>I = $${{20 \times {{10}^{ - 6}}} \over {{{10}^{ - 6}}}}$$ = 20 N/m<sup>2</sup>
<br><br>x = $${{20} \over {60 \times {{10}^{ + 3}}}}$$ = $${1 \over 3} \times {10^{ - 3}}$$
<br><br>= 0.33 $$ \times $$ 10<sup>$$-$$3</sup> = 3.3 $$ \times $$ 10... | mcq | jee-main-2019-online-11th-january-evening-slot | 11,772 |
SHuuvlT78BVdRd5uVbAKN | physics | magnetic-properties-of-matter | magnetic-properties-of-matter | A paramagnetic material has 10<sup>28</sup> atoms/m<sup>3</sup>. Its magnetic susceptibility at temperature 350 K is 2.8 $$ \times $$ 10<sup>–4</sup>. Its susceptibility at 300 K is : | [{"identifier": "A", "content": "3.726 $$ \\times $$ 10<sup>\u20134</sup>"}, {"identifier": "B", "content": "2.672 $$ \\times $$ 10<sup>\u20134</sup>"}, {"identifier": "C", "content": "3.672 $$ \\times $$ 10<sup>\u20134</sup>"}, {"identifier": "D", "content": "3.267 $$ \\times $$ 10<sup>$$-$$4</sup>"}] | ["D"] | null | x $$\alpha $$ $${1 \over {{T_C}}}$$
<br><br>curie law for paramagnetic substane
<br><br>$${{{x_1}} \over {{x_2}}}$$ = $${{{T_{{C_2}}}} \over {{T_{{C_1}}}}}$$
<br><br>$${{2.8 \times {{10}^{ - 4}}} \over {{x_2}}} = {{300} \over {350}}$$
<br><br>x<sub>2</sub> = $${{2.8 \times 350 \times {{10}^{ - 4}}} \over {300}}$$
<br><... | mcq | jee-main-2019-online-12th-january-evening-slot | 11,773 |
8WmBQ0CKAt8pbtKHNMjgy2xukf3utaj9 | physics | magnetic-properties-of-matter | magnetic-properties-of-matter | A perfectly diamagnetic sphere has a small spherical cavity at its centre, which is filled with a
paramagnetic substance. The whole system is placed in a uniform magnetic field $$\overrightarrow B $$
. Then the field
inside the paramagnetic substance is :
<img src="data:image/png;base64,UklGRiIHAABXRUJQVlA4IBYHAABwNACd... | [{"identifier": "A", "content": "$$\\overrightarrow B $$"}, {"identifier": "B", "content": "zero"}, {"identifier": "C", "content": "much large than $$\\left| {\\overrightarrow B } \\right|$$ and parallel to $$\\overrightarrow B $$"}, {"identifier": "D", "content": "much large than $$\\left| {\\overrightarrow B } \\righ... | ["B"] | null | A perfect diamagnetic substance will completely expel the magnetic field. Therefore, there will be no magnetic field inside the cavity of sphere. Hence the paramagnetic substance kept inside the cavity will experience no force. | mcq | jee-main-2020-online-3rd-september-evening-slot | 11,774 |
j0qhupOGehQTL4vbnM1klrnx3h8 | physics | magnetic-properties-of-matter | magnetic-properties-of-matter | A soft ferromagnetic material is placed in an external magnetic field. The magnetic domains : | [{"identifier": "A", "content": "may increase or decrease in size and change its orientation."}, {"identifier": "B", "content": "increase in size but no change in orientation."}, {"identifier": "C", "content": "decrease in size and changes orientation."}, {"identifier": "D", "content": "have no relation with external m... | ["A"] | null | Atoms of ferromagnetic material in unmagnetised state form domains inside the ferromagnetic material. These domains have large magnetic moment of atoms. In the absence of magnetic field, these domains have magnetic moment in different directions. But when the magnetic field is applied, domains aligned in the direction ... | mcq | jee-main-2021-online-24th-february-evening-slot | 11,776 |
zkHpx5JygAuEDEZmFm1klt2hx0y | physics | magnetic-properties-of-matter | magnetic-properties-of-matter | In a ferromagnetic material, below the curie temperature, a domain is defined as : | [{"identifier": "A", "content": "a macroscopic region with zero magnetization."}, {"identifier": "B", "content": "a macroscopic region with saturation magnetization."}, {"identifier": "C", "content": "a macroscopic region with randomly oriented magnetic dipoles."}, {"identifier": "D", "content": "a macroscopic region w... | ["B"] | null | In a ferromagnetic material, below the curie temperature a domain is defined as a macroscopic region with saturation magnetization. | mcq | jee-main-2021-online-25th-february-evening-slot | 11,777 |
P1REhJODCQPR64Oq3W1kmlwi0i9 | physics | magnetic-properties-of-matter | magnetic-properties-of-matter | Which of the following statements are correct?<br/><br/>(A) Electric monopoles do not exist whereas magnetic monopoles exist.<br/><br/>(B) Magnetic field lines due to a solenoid at its ends and outside cannot be completely straight and confined.<br/><br/>(C) Magnetic field lines are completely confined within a toroid.... | [{"identifier": "A", "content": "(A) and (B) only"}, {"identifier": "B", "content": "(B) and (C) only"}, {"identifier": "C", "content": "(C) and (E) only"}, {"identifier": "D", "content": "(B) and (D) only"}] | ["C"] | null | (a) Electric monopoles exist while magnetic monopoles do not exist.
<br><br>(b) Magnetic field lines at the ends and outside of solenoid cannot be confined. (c) Magnetic field lines are confined within a toroid.
<br><br>(d) Magnetic field lines inside a bar magnet are parallel.
<br><br>(e) For perfectly diamagnetic mat... | mcq | jee-main-2021-online-18th-march-evening-shift | 11,778 |
1krqe8g81 | physics | magnetic-properties-of-matter | magnetic-properties-of-matter | The magnetic susceptibility of a material of a rod is 499. Permeability in vacuum is 4$$\pi$$ $$\times$$ 10<sup>$$-$$7</sup> H/m. Absolute permeability of the material of the rod is : | [{"identifier": "A", "content": "4$$\\pi$$ $$\\times$$ 10<sup>$$-$$4</sup> H/m"}, {"identifier": "B", "content": "2$$\\pi$$ $$\\times$$ 10<sup>$$-$$4</sup> H/m"}, {"identifier": "C", "content": "3$$\\pi$$ $$\\times$$ 10<sup>$$-$$4</sup> H/m"}, {"identifier": "D", "content": "$$\\pi$$ $$\\times$$ 10<sup>$$-$$4</sup> H/m... | ["B"] | null | $$\mu$$ = $$\mu$$<sub>0</sub> (1 + x<sub>m</sub>)<br><br>= 4$$\pi$$ $$\times$$ 10<sup>$$-$$7</sup> $$\times$$ 500<br><br>= 2$$\pi$$ $$\times$$ 10<sup>$$-$$4</sup> H/m | mcq | jee-main-2021-online-20th-july-evening-shift | 11,779 |
1krsuz3cm | physics | magnetic-properties-of-matter | magnetic-properties-of-matter | Statement I : The ferromagnetic property depends on temperature. At high temperature, ferromagnet becomes paramagnet.<br/><br/>Statement II : At high temperature, the domain wall area of a ferromagnetic substance increases.<br/><br/>In the light of the above statements, choose the most appropriate answer from the optio... | [{"identifier": "A", "content": "Statement I is false but Statement II is true"}, {"identifier": "B", "content": "Statement I is true but Statement II is false"}, {"identifier": "C", "content": "Both Statement I and Statement II are false"}, {"identifier": "D", "content": "Both Statement I and Statement II are true"}] | ["B"] | null | With increase in temperature domain volume decreases.<br><br>Statement I true Statement 2 false | mcq | jee-main-2021-online-22th-july-evening-shift | 11,780 |
1krundihb | physics | magnetic-properties-of-matter | magnetic-properties-of-matter | The value of aluminium susceptibility is 2.2 $$\times$$ 10<sup>$$-$$5</sup>. The percentage increase in the magnetic field if space within a current carrying toroid is filled with aluminium is $${x \over {{{10}^4}}}$$. Then the value of x is _________________. | [] | null | 22 | $$B = \mu .(H + I)$$<br><br>$$B = \mu .H\left( {1 + {1 \over H}} \right)$$<br><br>$$B = {B_0}(1 + x)$$<br><br>$$B - {B_0} = {B_0}x$$<br><br>$${{B - {B_0}} \over {{B_0}}} = x$$<br><br>$${{B - {B_0}} \over {{B_0}}} \times 100 = 100x$$<br><br>$$ = 2.2 \times {10^{ - 3}} = {{22} \over {{{10}^4}}}$$ | integer | jee-main-2021-online-25th-july-morning-shift | 11,781 |
1ktmoj383 | physics | magnetic-properties-of-matter | magnetic-properties-of-matter | Following plots show magnetization (M) vs magnetizing field (H) and magnetic susceptibility ($$\chi $$) vs temperature (T) graph :<br/><br/><img src="data:image/png;base64,UklGRpAKAABXRUJQVlA4IIQKAACwqgCdASoAA+oBP4G812Y2LiwnIRC5SsAwCWlu+FTn6wWZNlvj2itd7O7tjxVUNRXnz5y//H8DYope4quWjpBbTPTzXCWekcNTLUQ4s75RS9xZ3yOb+L7NVsp4... | [{"identifier": "A", "content": "(a), (c)"}, {"identifier": "B", "content": "(a), (d)"}, {"identifier": "C", "content": "(b), (d)"}, {"identifier": "D", "content": "(b), (c)"}] | ["A"] | null | <p>For diamagnetic material</p>
<p>$$\chi $$ is independent of temperature and negative.</p>
<p>Magnetisation (M) is directly proportional to H
(The relation between magnetisation and magnetising field, M = –mH)</p><p>Option (a)</p> | mcq | jee-main-2021-online-1st-september-evening-shift | 11,782 |
1l57pz5z4 | physics | magnetic-properties-of-matter | magnetic-properties-of-matter | <p>The susceptibility of a paramagnetic material is 99. The permeability of the material in Wb/A-m, is :</p>
<p>[Permeability of free space $$\mu$$<sub>0</sub> = 4$$\pi$$ $$\times$$ 10<sup>$$-$$7</sup> Wb/A-m]</p> | [{"identifier": "A", "content": "4$$\\pi$$ $$\\times$$ 10<sup>$$-$$7</sup>"}, {"identifier": "B", "content": "4$$\\pi$$ $$\\times$$ 10<sup>$$-$$4</sup>"}, {"identifier": "C", "content": "4$$\\pi$$ $$\\times$$ 10<sup>$$-$$5</sup>"}, {"identifier": "D", "content": "4$$\\pi$$ $$\\times$$ 10<sup>$$-$$6</sup>"}] | ["C"] | null | <p>$$\mu$$<sub>r</sub> = x + 1</p>
<p>= 99 + 1 = 100</p>
<p>$$\Rightarrow$$ $$\mu$$ = $$\mu$$<sub>r</sub>$$\mu$$<sub>0</sub> = 100 $$\times$$ 4$$\mu$$ $$\times$$ 10<sup>$$-$$7</sup> Wb/Am</p>
<p>= 4$$\mu$$ $$\times$$ 10<sup>$$-$$5</sup> Wb/Am</p> | mcq | jee-main-2022-online-27th-june-morning-shift | 11,784 |
1l59p2qm6 | physics | magnetic-properties-of-matter | magnetic-properties-of-matter | <p>Given below are two statements :</p>
<p>Statement I : Susceptibilities of paramagnetic and ferromagnetic substances increase with decrease in temperature.</p>
<p>Statement II : Diamagnetism is a result of orbital motions of electrons developing magnetic moments opposite to the applied magnetic field.</p>
<p>Choose t... | [{"identifier": "A", "content": "Both Statement I and Statement II are true."}, {"identifier": "B", "content": "Both Statement I and Statement II are false."}, {"identifier": "C", "content": "Statement I is true but Statement II is false."}, {"identifier": "D", "content": "Statement I is false but Statement II is true.... | ["A"] | null | <p>Statement I is true as susceptibility of ferromagnetic and paramagnetic materials is inversely related to temperature.</p>
<p>Statement II is true as because of orbital motion of electrons the diamagnetic material is able to oppose external magnetic field.</p> | mcq | jee-main-2022-online-25th-june-evening-shift | 11,785 |
1l5bbqkw9 | physics | magnetic-properties-of-matter | magnetic-properties-of-matter | <p>The soft-iron is a suitable material for making an electromagnet. This is because soft-iron has</p> | [{"identifier": "A", "content": "low coercivity and high retentivity."}, {"identifier": "B", "content": "low coercivity and low permeability."}, {"identifier": "C", "content": "high permeability and low retentivity."}, {"identifier": "D", "content": "high permeability and high retentivity."}] | ["C"] | null | <p>Electromagnet requires high permeability and low retentivity.</p> | mcq | jee-main-2022-online-24th-june-evening-shift | 11,786 |
1lduhtztl | physics | magnetic-properties-of-matter | magnetic-properties-of-matter | <p>A solenoid of 1200 turns is wound uniformly in a single layer on a glass tube 2 m long and 0.2 m in diameter. The magnetic intensity at the center of the solenoid when a current of 2 A flows through it is :</p> | [{"identifier": "A", "content": "$$\\mathrm{1~A~m^{-1}}$$"}, {"identifier": "B", "content": "$$\\mathrm{2.4\\times10^{-3}~A~m^{-1}}$$"}, {"identifier": "C", "content": "$$\\mathrm{1.2\\times10^{3}~A~m^{-1}}$$"}, {"identifier": "D", "content": "$$\\mathrm{2.4\\times10^{3}~A~m^{-1}}$$"}] | ["C"] | null | Number of turns per unit length $=\frac{1200}{2}=600$
<br/><br/>
So, Magnetic Intensity $H=n I$
<br/><br/>
$$
\begin{aligned}
& =600 \times 2 ~\mathrm{Am}^{-1} \\\\
& =1200 ~\mathrm{Am}^{-1}
\end{aligned}
$$ | mcq | jee-main-2023-online-25th-january-morning-shift | 11,787 |
1lgrihor0 | physics | magnetic-properties-of-matter | magnetic-properties-of-matter | <p>Given below are two statements:</p>
<p>Statement I : The diamagnetic property depends on temperature.</p>
<p>Statement II : The induced magnetic dipole moment in a diamagnetic sample is always opposite to the magnetizing field.</p>
<p>In the light of given statements, choose the correct answer from the options given... | [{"identifier": "A", "content": "Statement I is incorrect but Statement II is true."}, {"identifier": "B", "content": "Statement I is correct but Statement II is false."}, {"identifier": "C", "content": "Both Statement I and Statement II are False."}, {"identifier": "D", "content": "Both Statement I and Statement II ar... | ["A"] | null | <b>Statement I</b> : The diamagnetic property depends on temperature.
This statement is incorrect. Diamagnetism is an intrinsic property of materials that arises due to the presence of completely filled electron shells. It does not depend on temperature.
<br/><br/>
<b>Statement II</b> : The induced magnetic dipole mome... | mcq | jee-main-2023-online-12th-april-morning-shift | 11,788 |
1lgvrqwqj | physics | magnetic-properties-of-matter | magnetic-properties-of-matter | <p>Given below are two statements:</p>
<p>Statement I : For diamagnetic substance, $$-1 \leq \chi < 0$$, where $$\chi$$ is the magnetic susceptibility.</p>
<p>Statement II : Diamagnetic substances when placed in an external magnetic field, tend to move from stronger to weaker part of the field.</p>
<p>In the light o... | [{"identifier": "A", "content": "Both Statement I and Statement II are true"}, {"identifier": "B", "content": "Statement I is correct but Statement II is false"}, {"identifier": "C", "content": "Both Statement I and Statement II are False"}, {"identifier": "D", "content": "Statement I is incorrect but Statement II is t... | ["A"] | null | <p>Both Statement I and Statement II are true. </p>
<p><b>Statement I</b>: For diamagnetic substances, the magnetic susceptibility (χ) lies between -1 and 0. This is because diamagnetic substances have a negative magnetic susceptibility, which means they have a tendency to oppose the applied magnetic field.</p>
<p><b>S... | mcq | jee-main-2023-online-10th-april-evening-shift | 11,790 |
1lgyfv5wo | physics | magnetic-properties-of-matter | magnetic-properties-of-matter | <p>The current required to be passed through a solenoid of 15 cm length and 60 turns in order of demagnetise a bar magnet of magnetic intensity $$2.4\times10^3~Am^{-1}$$ is ___________ A.</p> | [] | null | 6 | <p>We know that the magnetizing field (H) inside a solenoid is given by the formula :</p>
<p>$ H = \frac{N \cdot I}{L} $</p>
<p>where (N) is the number of turns, (I) is the current in Amperes, and (L) is the length of the solenoid in meters.</p>
<p>To demagnetize a bar magnet that has a magnetic intensity (H) of ($2.4 ... | integer | jee-main-2023-online-10th-april-morning-shift | 11,791 |
1lgyqpe9z | physics | magnetic-properties-of-matter | magnetic-properties-of-matter | <p>Given below are two statements: one is labelled as Assertion $$\mathbf{A}$$ and the other is labelled as Reason $$\mathbf{R}$$</p>
<p>Assertion A : Electromagnets are made of soft iron.</p>
<p>Reason R : Soft iron has high permeability and low retentivity.</p>
<p>In the light of above, statements, choose the most ap... | [{"identifier": "A", "content": "Both A and R are correct and R is the correct explanation of A"}, {"identifier": "B", "content": "A is not correct but R is correct"}, {"identifier": "C", "content": "A is correct but R is not correct"}, {"identifier": "D", "content": "Both A and R are correct but R is NOT the correct e... | ["A"] | null | <p><b>Both Assertion A and Reason R are correct, and R is indeed the correct explanation of A.</b> </p>
<p>Electromagnets are commonly made of soft iron because of its high permeability, which allows it to easily magnetize in response to an external magnetic field. Its low retentivity is also desirable because it allow... | mcq | jee-main-2023-online-8th-april-evening-shift | 11,792 |
1lh02e654 | physics | magnetic-properties-of-matter | magnetic-properties-of-matter | <p>The magnetic intensity at the center of a long current carrying solenoid is found to be $$1.6 \times 10^{3} \mathrm{Am}^{-1}$$. If the number of turns is 8 per cm, then the current flowing through the solenoid is __________ A.</p> | [] | null | 2 | <p>In a solenoid, the magnetic field intensity ($H$) is given by the product of the number of turns per unit length ($n$) and the current ($I$) flowing through the solenoid. This can be represented mathematically as:</p>
<p>$H = nI$</p>
<p>This is actually derived from Ampere's law applied to the special case of a ... | integer | jee-main-2023-online-8th-april-morning-shift | 11,793 |
1lsgx7j5t | physics | magnetic-properties-of-matter | magnetic-properties-of-matter | <p>The horizontal component of earth's magnetic field at a place is $$3.5 \times 10^{-5} \mathrm{~T}$$. A very long straight conductor carrying current of $$\sqrt{2} \mathrm{~A}$$ in the direction from South east to North West is placed. The force per unit length experienced by the conductor is __________ $$\times 10^{... | [] | null | 35 | <p>$$\begin{aligned}
& B_H=3.5 \times 10^{-5} T \\
& F=i \ell B \sin \theta, \quad \mathrm{i}=\sqrt{2} \mathrm{~A} \\
& \frac{F}{\ell}=i B \sin \theta=\sqrt{2} \times 3.5 \times 10^{-5} \times \frac{1}{\sqrt{2}} \\
& =35 \times 10^{-6} \mathrm{~N} / \mathrm{m}
\end{aligned}$$</p> | integer | jee-main-2024-online-30th-january-morning-shift | 11,794 |
lv3xmal3 | physics | magnetic-properties-of-matter | magnetic-properties-of-matter | <p>The coercivity of a magnet is $$5 \times 10^3 \mathrm{~A} / \mathrm{m}$$. The amount of current required to be passed in a solenoid of length $$30 \mathrm{~cm}$$ and the number of turns 150, so that the magnet gets demagnetised when inside the solenoid is ________ A.</p> | [] | null | 10 | <p>Coercivity is a measure of the resistance of a ferromagnetic material to becoming demagnetized. It is defined as the intensity of the applied magnetic field required to reduce the magnetization of a material to zero after the magnetization of the sample has been driven to saturation. In this case, coercivity $$H_c$$... | integer | jee-main-2024-online-8th-april-evening-shift | 11,795 |
lv5gs8ij | physics | magnetic-properties-of-matter | magnetic-properties-of-matter | <p>Paramagnetic substances:</p>
<p>A. align themselves along the directions of external magnetic field.</p>
<p>B. attract strongly towards external magnetic field.</p>
<p>C. has susceptibility little more than zero.</p>
<p>D. move from a region of strong magnetic field to weak magnetic field.</p>
<p>Choose the most app... | [{"identifier": "A", "content": "A, B, C Only\n"}, {"identifier": "B", "content": "A, C Only\n"}, {"identifier": "C", "content": "A, B, C, D\n"}, {"identifier": "D", "content": "B, D Only"}] | ["B"] | null | <p>Paramagnetic substances exhibit specific characteristics in the presence of an external magnetic field. Understanding these characteristics will help us choose the most appropriate answer. Let's discuss each statement individually:</p>
<p><strong>A. align themselves along the directions of external magnetic field.<... | mcq | jee-main-2024-online-8th-april-morning-shift | 11,796 |
VcuO2F4nkDvpy1BN | physics | magnetics | ampere's-circuital-law | A current $$i$$ ampere flows along an infinitely long straight thin walled tube, then the magnetic induction at any point inside the tube is | [{"identifier": "A", "content": "$${{{\\mu _0}} \\over {4\\pi }},{{2i} \\over r}$$ tesla"}, {"identifier": "B", "content": "zero "}, {"identifier": "C", "content": "infinite "}, {"identifier": "D", "content": "$${{2i} \\over r}$$ tesla "}] | ["B"] | null | Using Ampere's law at a distance $$r$$ from axis, $$B$$ is same from symmetry.
<br><br>$$\int {B.dl = {\mu _0}i} $$
<br><br>i.e., $$B \times 2\pi r = {\mu _0}i$$
<br><br>Here $$i$$ is zero, for $$r < R,$$ whereas $$R$$ is the radius
<br><br>$$\therefore$$ $$B=0$$ | mcq | aieee-2004 | 11,798 |
Pq5oxzvCxCgfQOaJ | physics | magnetics | ampere's-circuital-law | A current $$I$$ flows along the length of an infinitely long, straight, thin walled pipe. Then | [{"identifier": "A", "content": "the magnetic field at all points inside the pipe is the same, but not zero "}, {"identifier": "B", "content": "the magnetic field is zero only on the axis of the pipe "}, {"identifier": "C", "content": "the magnetic field is different at different points inside the pipe "}, {"identifier... | ["D"] | null | There is no current inside the pipe. Therefore
<br><br>$$\oint {\overline B .\overline {d\ell } } = {\mu _0}I$$
<br><br>$$I=0$$
<br><br>$$\therefore$$ $$B=0$$ | mcq | aieee-2007 | 11,799 |
avMlH1RhAdrmbqPST07k9k2k5i7yq8c | physics | magnetics | ampere's-circuital-law | A long, straight wire of radius a carries a current
distributed uniformly over its cross-section. The
ratio of the magnetic fields due to the wire at
distance
$${a \over 3}$$
and 2$$a$$, respectively from the axis
of the wire is : | [{"identifier": "A", "content": "2"}, {"identifier": "B", "content": "$${1 \\over 2}$$"}, {"identifier": "C", "content": "$${3 \\over 2}$$"}, {"identifier": "D", "content": "$${2 \\over 3}$$"}] | ["D"] | null | <img src="https://res.cloudinary.com/dckxllbjy/image/upload/v1734265589/exam_images/wuk9dfiwqntw4am53m7a.webp" style="max-width: 100%;height: auto;display: block;margin: 0 auto;" loading="lazy" alt="JEE Main 2020 (Online) 9th January Morning Slot Physics - Magnetic Effect of Current Question 129 English Explanation">
<... | mcq | jee-main-2020-online-9th-january-morning-slot | 11,801 |
1l5akmwj9 | physics | magnetics | ampere's-circuital-law | <p>A long straight wire with a circular cross-section having radius R, is carrying a steady current I. The current I is uniformly distributed across this cross-section. Then the variation of magnetic field due to current I with distance r (r < R) from its centre will be :</p> | [{"identifier": "A", "content": "B $$\\propto$$ r<sup>2</sup>"}, {"identifier": "B", "content": "B $$\\propto$$ r"}, {"identifier": "C", "content": "B $$\\propto$$ $${1 \\over {{r^2}}}$$"}, {"identifier": "D", "content": "B $$\\propto$$ $${1 \\over {{r}}}$$"}] | ["B"] | null | <p>$$\int {\overline B \,.\,\overline {dl} = {\mu _0}{I_{in}}} $$</p>
<p>$$ \Rightarrow B \times 2\pi r = {{{\mu _0}I} \over {\pi {R^2}}} \times \pi {r^2}$$</p>
<p>$$ \Rightarrow B \propto r$$</p> | mcq | jee-main-2022-online-25th-june-morning-shift | 11,802 |
luyit8bo | physics | magnetics | ampere's-circuital-law | <p>Given below are two statements :</p>
<p>Statement (I) : When currents vary with time, Newton's third law is valid only if momentum carried by the electromagnetic field is taken into account</p>
<p>Statement (II) : Ampere's circuital law does not depend on Biot-Savart's law.</p>
<p>In the light of the above statement... | [{"identifier": "A", "content": "Both Statement I and Statement II are false\n"}, {"identifier": "B", "content": "Statement I is false but Statement II is true\n"}, {"identifier": "C", "content": "Both Statement I and Statement II are true\n"}, {"identifier": "D", "content": "Statement I is true but Statement II is fal... | ["D"] | null | <p>Let's analyze each statement in detail to determine the correct answer:</p>
<p><strong>Statement (I) :</strong> "When currents vary with time, Newton's third law is valid only if momentum carried by the electromagnetic field is taken into account." This statement is true. According to physics, particularly when dea... | mcq | jee-main-2024-online-9th-april-morning-shift | 11,803 |
lv3ve5u6 | physics | magnetics | ampere's-circuital-law | <p>A long straight wire of radius a carries a steady current I. The current is uniformly distributed across its cross section. The ratio of the magnetic field at $$\frac{a}{2}$$ and $$2 a$$ from axis of the wire is :</p> | [{"identifier": "A", "content": "$$4: 1$$\n"}, {"identifier": "B", "content": "$$3: 4$$\n"}, {"identifier": "C", "content": "$$1: 1$$\n"}, {"identifier": "D", "content": "$$1: 4$$"}] | ["C"] | null | <p>To find the ratio of the magnetic field at $$\frac{a}{2}$$ and $$2a$$ distances from the axis of a long straight wire, we use Ampère's Law, which relates the magnetic field around a current-carrying conductor to the current enclosed by it.</p>
<p>Ampère’s Law is given by:</p>
<p>$$\oint \vec{B} \cdot d\vec{l} = \m... | mcq | jee-main-2024-online-8th-april-evening-shift | 11,804 |
lv7v4nve | physics | magnetics | ampere's-circuital-law | In a co-axial straight cable, the central conductor and the outer conductor carry equal currents in opposite directions. The magnetic field is zero :
| [{"identifier": "A", "content": "inside the outer conductor\n"}, {"identifier": "B", "content": "outside the cable\n"}, {"identifier": "C", "content": "in between the two conductors\n"}, {"identifier": "D", "content": "inside the inner conductor"}] | ["B"] | null | <p>Let's dig into how the magnetic field behaves in a coaxial cable in relation to the given options. The principle to consider here is Ampère's law, which states that the magnetic field in a loop surrounding a current is proportional to the amount of current enclosed. When we apply this to a coaxial cable, we must loo... | mcq | jee-main-2024-online-5th-april-morning-shift | 11,805 |
WD0q2YvOYRHe34OB | physics | magnetics | biot-savart's-law-and-magnetic-field-due-to-current-carrying-wire | If in a circular coil $$A$$ of radius $$R,$$ current $$I$$ is flowing and in another coil $$B$$ of radius $$2R$$ a current $$2I$$ is flowing, then the ratio of the magnetic fields $${B_A}$$ and $${B_B}$$, produced by them will be | [{"identifier": "A", "content": "$$1$$ "}, {"identifier": "B", "content": "$$2$$ "}, {"identifier": "C", "content": "$$1/2$$ "}, {"identifier": "D", "content": "$$4$$ "}] | ["A"] | null | <b>KEY CONCEPT : </b>We know that the magnetic field produced by a current carrying circular coil of radius $$r$$
<br><br>at its center is $$B = {{{\mu _0}} \over {4\pi }}{I \over r} \times 2\pi $$
<br><br>Here $${B_A} = {{{\mu _0}} \over {4\pi }}{I \over R} \times 2\pi $$ and
<br><br>$${B_B} = {{{\mu _0}} \over {4\p... | mcq | aieee-2002 | 11,807 |
WlHhKqTXJQRnMjVA | physics | magnetics | biot-savart's-law-and-magnetic-field-due-to-current-carrying-wire | If a current is passed through a spring then the spring will | [{"identifier": "A", "content": "expand "}, {"identifier": "B", "content": "compress "}, {"identifier": "C", "content": "remains same "}, {"identifier": "D", "content": "none of these "}] | ["B"] | null | When current is passed through a spring, every current
carrying loop of a spring behaves like a tiny magnet and
loop of a spring faces another loop are form magnet of
different poles which attract one another. Therefore,
spring is compressed. | mcq | aieee-2002 | 11,808 |
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