[User] I want to find all claim IDs that have both an 'Accident Report' and a 'Police Report' document.

[Assistant]
SELECT DISTINCT a.claim_id
FROM insurance.claim_documents a
JOIN insurance.claim_documents b
  ON a.claim_id = b.claim_id
WHERE a.document_type = 'Accident Report'
  AND b.document_type = 'Police Report';

[User] Now, only include those pairs if both documents were uploaded after '2024-06-01'.

[Assistant]
SELECT DISTINCT a.claim_id
FROM insurance.claim_documents a
JOIN insurance.claim_documents b
  ON a.claim_id = b.claim_id
WHERE a.document_type = 'Accident Report'
  AND b.document_type = 'Police Report'
  AND a.uploaded_at > '2024-06-01'
  AND b.uploaded_at > '2024-06-01';

[User] Additionally, ensure that both files are larger than 500 KB.

[Assistant]
SELECT DISTINCT a.claim_id
FROM insurance.claim_documents a
JOIN insurance.claim_documents b
  ON a.claim_id = b.claim_id
WHERE a.document_type = 'Accident Report'
  AND b.document_type = 'Police Report'
  AND a.uploaded_at > '2024-06-01'
  AND b.uploaded_at > '2024-06-01'
  AND a.file_size_bytes > 512000
  AND b.file_size_bytes > 512000;

[User] Finally, show me the file_name and uploaded_by for both document types in the results.

[Assistant]
SELECT
    a.claim_id,
    a.file_name       AS accident_file_name,
    a.uploaded_by     AS accident_uploaded_by,
    b.file_name       AS police_file_name,
    b.uploaded_by     AS police_uploaded_by
FROM insurance.claim_documents a
JOIN insurance.claim_documents b
  ON a.claim_id = b.claim_id
WHERE a.document_type = 'Accident Report'
  AND b.document_type = 'Police Report'
  AND a.uploaded_at > '2024-06-01'
  AND b.uploaded_at > '2024-06-01'
  AND a.file_size_bytes > 512000
  AND b.file_size_bytes > 512000;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE insurance.claim_documents ( document_id text, claim_id text, document_type text, file_name text, file_path text, file_size_bytes integer, mime_type text, uploaded_by text, uploaded_at timestamp, description text )


[User] For each policy, find the latest payment date. Show the policy_id and the maximum payment_date.

[Assistant] SELECT policy_id, MAX(payment_date) AS latest_payment_date FROM insurance.premium_payments GROUP BY policy_id;

[User] Restrict the results to only show policies where the latest payment date was before '2024-01-01'.

[Assistant] SELECT policy_id, MAX(payment_date) AS latest_payment_date FROM insurance.premium_payments GROUP BY policy_id HAVING MAX(payment_date) < '2024-01-01';

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE insurance.premium_payments ( payment_id text PRIMARY KEY, policy_id text, customer_id text, payment_date timestamp, amount_paid numeric, payment_method text, transaction_reference text, due_date date, payment_period_start date, payment_period_end date, status text )


[User] How many rooms are there on each floor?

[Assistant] SELECT floor, COUNT(*) FROM hospitality_technology.rooms GROUP BY floor

[User] Only show floors with more than 10 rooms.

[Assistant] SELECT floor, COUNT(*) FROM hospitality_technology.rooms GROUP BY floor HAVING COUNT(*) > 10

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE hospitality_technology.rooms (
    room_id character varying(64) NOT NULL,  -- unique identifier for the room
    property_id character varying(64) NOT NULL, -- FK to properties table
    room_number character varying(10) NOT NULL, -- room number identifier (e.g., '101', 'Suite 2B')
    room_type_id character varying(64) NOT NULL, -- FK to room_types table
    floor integer, -- floor number the room is on
    status character varying(50) NOT NULL, -- e.g., Available, Occupied, Cleaning, OutOfOrder, Maintenance
    is_smoking boolean NOT NULL DEFAULT false, -- smoking allowed flag
    features text, -- description of features (e.g., Balcony, Sea View, Jacuzzi)
    current_condition text, -- notes on room condition
    last_cleaned_at timestamp with time zone, -- timestamp of last cleaning
    PRIMARY KEY (room_id),
    FOREIGN KEY (property_id) REFERENCES hospitality_technology.properties(property_id),
    FOREIGN KEY (room_type_id) REFERENCES hospitality_technology.room_types(room_type_id)
)


[User] List the content and comment ID for all comments made by users with private profiles.

[Assistant] SELECT c.comment_id, c.content FROM social_media.comments AS c JOIN social_media.user_settings AS us ON c.user_id = us.user_id WHERE us.private_profile = TRUE;

[User] Only show comments created in the year 2024.

[Assistant] SELECT c.comment_id, c.content FROM social_media.comments AS c JOIN social_media.user_settings AS us ON c.user_id = us.user_id WHERE us.private_profile = TRUE AND c.created_at >= '2024-01-01' AND c.created_at < '2025-01-01';

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE social_media.comments (
    comment_id character varying(64) NOT NULL, -- unique identifier for the comment
    post_id character varying(64) NOT NULL, -- identifier of the post being commented on (FK to posts.post_id)
    user_id character varying(64) NOT NULL, -- identifier of the user who made the comment (FK to users.user_id)
    parent_comment_id character varying(64), -- identifier of the parent comment if it's a reply (FK to comments.comment_id)
    content text NOT NULL, -- textual content of the comment
    created_at timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, -- timestamp of comment creation
    updated_at timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, -- timestamp of last comment edit
    PRIMARY KEY (comment_id)
)
CREATE TABLE social_media.conversation_participants ( participant_id text, conversation_id text, user_id text, joined_at timestamp, last_read_at timestamp )
CREATE TABLE social_media.user_settings ( setting_id text, user_id text, theme text, email_notifications_enabled boolean, push_notifications_enabled boolean, private_profile boolean, updated_at timestamp )


[User] Show the document type, verification status, and the full name of the citizen who uploaded each document.

[Assistant] SELECT d.document_type, d.verification_status, CONCAT(c.first_name, ' ', c.last_name) AS citizen_full_name FROM government_services.documents d JOIN government_services.citizens c ON d.citizen_id = c.citizen_id;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE government_services.documents (
    document_id character varying(64) NOT NULL, -- unique identifier for the document instance
    application_id character varying(64), -- FK to applications table (optional, could be linked to citizen directly)
    citizen_id character varying(64) NOT NULL, -- FK to citizens table
    document_type character varying(100) NOT NULL, -- e.g., Passport Scan, Proof of Address, Birth Certificate
    file_reference text NOT NULL, -- reference to the stored file (e.g., S3 URL, internal path)
    upload_timestamp timestamp NOT NULL,
    expiry_date date,
    verification_status character varying(30) DEFAULT 'Pending', -- e.g., Pending, Verified, Rejected
    verified_by_employee_id character varying(64), -- FK to employees table
    verification_timestamp timestamp,
    PRIMARY KEY (document_id)
)


[User] Show me all appointments along with any diagnoses recorded for the same patient on the same day. Include appointment_id, patient_id, appointment_time, and diagnosis_description.

[Assistant] SELECT T1.appointment_id, T1.patient_id, T1.appointment_time, T2.description FROM healthcare.appointments AS T1 JOIN healthcare.diagnoses AS T2 ON T1.patient_id = T2.patient_id AND DATE(T1.appointment_time) = T2.diagnosis_date;

[User] Refine this to only include diagnoses that are marked as 'chronic'.

[Assistant] SELECT T1.appointment_id, T1.patient_id, T1.appointment_time, T2.description FROM healthcare.appointments AS T1 JOIN healthcare.diagnoses AS T2 ON T1.patient_id = T2.patient_id AND DATE(T1.appointment_time) = T2.diagnosis_date WHERE T2.is_chronic = true;

[User] Additionally, filter to only include appointments where the status is 'Completed'.

[Assistant] SELECT T1.appointment_id, T1.patient_id, T1.appointment_time, T2.description FROM healthcare.appointments AS T1 JOIN healthcare.diagnoses AS T2 ON T1.patient_id = T2.patient_id AND DATE(T1.appointment_time) = T2.diagnosis_date WHERE T2.is_chronic = true AND T1.status = 'Completed';

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE healthcare.doctors ( doctor_id character varying(64) NOT NULL, first_name character varying(100) NOT NULL, last_name character varying(100) NOT NULL, specialty character varying(100) NOT NULL, license_number character varying(50) UNIQUE NOT NULL, phone_number character varying(20), email character varying(128) UNIQUE, hospital_affiliation_id character varying(64), created_at timestamp with time zone NOT NULL DEFAULT current_timestamp, updated_at timestamp with time zone NOT NULL DEFAULT current_timestamp, PRIMARY KEY (doctor_id) )
CREATE TABLE healthcare.appointments ( appointment_id character varying(64) NOT NULL, patient_id character varying(64) NOT NULL, doctor_id character varying(64) NOT NULL, appointment_time timestamp with time zone NOT NULL, duration_minutes integer NOT NULL, reason text, status character varying(32) NOT NULL, location_id character varying(64), notes text, created_at timestamp with time zone NOT NULL DEFAULT current_timestamp, PRIMARY KEY (appointment_id) )
CREATE TABLE healthcare.diagnoses ( diagnosis_id character varying(64) NOT NULL, record_id character varying(64) NOT NULL, patient_id character varying(64) NOT NULL, doctor_id character varying(64) NOT NULL, diagnosis_code character varying(20) NOT NULL, code_type character varying(10) NOT NULL DEFAULT 'ICD-10', description text, diagnosis_date date NOT NULL, status character varying(32) NOT NULL, is_chronic boolean DEFAULT false, PRIMARY KEY (diagnosis_id) )
CREATE TABLE healthcare.medications ( medication_id character varying(64) NOT NULL, medication_name character varying(255) NOT NULL, generic_name character varying(255), manufacturer character varying(100), ndc_code character varying(20) UNIQUE, description text, PRIMARY KEY (medication_id) )


[User] Retrieve all documents uploaded in 2024, showing document_id, uploaded_by, and uploaded_at.

[Assistant]
SELECT document_id,
       uploaded_by,
       uploaded_at
FROM insurance.claim_documents
WHERE uploaded_at >= '2024-01-01'
  AND uploaded_at < '2025-01-01';

[User] Actually, please only include documents larger than 1MB.

[Assistant]
SELECT document_id,
       uploaded_by,
       uploaded_at,
       file_size_bytes
FROM insurance.claim_documents
WHERE uploaded_at >= '2024-01-01'
  AND uploaded_at < '2025-01-01'
  AND file_size_bytes > 1048576;

[User] And sort them by file_size_bytes descending.

[Assistant]
SELECT document_id,
       uploaded_by,
       uploaded_at,
       file_size_bytes
FROM insurance.claim_documents
WHERE uploaded_at >= '2024-01-01'
  AND uploaded_at < '2025-01-01'
  AND file_size_bytes > 1048576
ORDER BY file_size_bytes DESC;

[User] Limit the results to the first 5 entries.

[Assistant]
SELECT document_id,
       uploaded_by,
       uploaded_at,
       file_size_bytes
FROM insurance.claim_documents
WHERE uploaded_at >= '2024-01-01'
  AND uploaded_at < '2025-01-01'
  AND file_size_bytes > 1048576
ORDER BY file_size_bytes DESC
LIMIT 5;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE insurance.claim_documents ( document_id.text, claim_id.text, document_type.text, file_name.text, file_path.text, file_size_bytes.integer, mime_type.text, uploaded_by.text, uploaded_at.timestamp, description.text )


[User] Can you show me all achievement unlock records where the same player unlocked two different achievements within the same day? Please show player_id, achievement_id_1, achievement_id_2, and the unlock dates for each.

[Assistant]
SELECT pa1.player_id, pa1.achievement_id as achievement_id_1, pa2.achievement_id as achievement_id_2, pa1.unlocked_at as unlock_date_1, pa2.unlocked_at as unlock_date_2
FROM gaming_technology.player_achievements pa1
JOIN gaming_technology.player_achievements pa2
  ON pa1.player_id = pa2.player_id
  AND pa1.achievement_id <> pa2.achievement_id
  AND DATE(pa1.unlocked_at) = DATE(pa2.unlocked_at)
  AND pa1.unlocked_at < pa2.unlocked_at;

[User] Add a condition to only include records where both achievements were unlocked on or after January 1st, 2024.

[Assistant]
SELECT pa1.player_id, pa1.achievement_id as achievement_id_1, pa2.achievement_id as achievement_id_2, pa1.unlocked_at as unlock_date_1, pa2.unlocked_at as unlock_date_2
FROM gaming_technology.player_achievements pa1
JOIN gaming_technology.player_achievements pa2
  ON pa1.player_id = pa2.player_id
  AND pa1.achievement_id <> pa2.achievement_id
  AND DATE(pa1.unlocked_at) = DATE(pa2.unlocked_at)
  AND pa1.unlocked_at < pa2.unlocked_at
WHERE pa1.unlocked_at >= '2024-01-01' AND pa2.unlocked_at >= '2024-01-01';

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE gaming_technology.player_achievements ( player_achievement_id uuid, player_id uuid, achievement_id uuid, unlocked_at timestamp with time zone )


[User] Show each contract's address along with the total number of events it has emitted and the total number of transactions sent to it.

[Assistant]
SELECT
  c.address,
  COUNT(e.event_id) AS event_count,
  COUNT(t.transaction_id) AS tx_count
FROM web3.contracts c
LEFT JOIN web3.events e
  ON c.contract_id = e.contract_id
LEFT JOIN web3.transactions t
  ON c.address = t.to_address
GROUP BY c.address;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE web3.contracts (
    contract_id character varying(64) NOT NULL,  -- unique identifier for the contract
    address character varying(128) NOT NULL, -- address of the deployed contract
    abi text NOT NULL, -- application binary interface of the contract
    bytecode text NOT NULL, -- bytecode of the contract
    deployer_address character varying(128) NOT NULL, -- address of the deployer
    deployed_at timestamp NOT NULL, -- time when the contract was deployed
    network_id character varying(64) NOT NULL, -- identifier of the network where the contract is deployed
    status character varying(32) NOT NULL, -- status of the contract (e.g., active, deprecated)
    PRIMARY KEY (contract_id)
)
CREATE TABLE web3.events (
    event_id character varying(64) NOT NULL,  -- unique identifier for the event
    contract_id character varying(64) NOT NULL, -- identifier of the contract emitting the event
    event_name character varying(128) NOT NULL, -- name of the event
    data text NOT NULL, -- data payload of the event
    emitted_at timestamp NOT NULL, -- time when the event was emitted
    transaction_id character varying(64) NOT NULL, -- identifier of the transaction that triggered the event
    log_index integer NOT NULL, -- index of the event log in the transaction
    PRIMARY KEY (event_id)
)
CREATE TABLE web3.transactions (
    transaction_id character varying(64) NOT NULL,  -- unique identifier for the transaction
    from_address character varying(128) NOT NULL, -- address of the sender
    to_address character varying(128), -- address of the receiver (can be null for contract deployment)
    value numeric(38,14) NOT NULL, -- value transferred
    gas_used integer NOT NULL, -- amount of gas used by the transaction
    gas_price numeric(38,14) NOT NULL, -- price of gas at the time of the transaction
    block_number integer NOT NULL, -- block number containing the transaction
    timestamp timestamp NOT NULL, -- time when the transaction was mined
    input_data text, -- input data of the transaction (can be null)
    status character varying(32) NOT NULL, -- status of the transaction (e.g., success, failed)
    nonce integer NOT NULL, -- nonce of the sender at the time of the transaction
    PRIMARY KEY (transaction_id)
)
CREATE TABLE web3.tokens (
    token_id character varying(64) NOT NULL,  -- unique identifier for the token
    contract_address character varying(128) NOT NULL, -- address of the token contract
    token_name character varying(128) NOT NULL, -- name of the token
    token_symbol character varying(32) NOT NULL, -- symbol of the token
    decimals integer NOT NULL, -- number of decimals for the token
    total_supply numeric(38,14) NOT NULL, -- total supply of the token
    PRIMARY KEY (token_id)
)
CREATE TABLE web3.token_transfers (
    transfer_id character varying(64) NOT NULL,  -- unique identifier for the transfer
    token_id character varying(64) NOT NULL, -- identifier of the token being transferred
    from_address character varying(128) NOT NULL, -- address of the sender
    to_address character varying(128) NOT NULL, -- address of the receiver
    value numeric(38,14) NOT NULL, -- amount of tokens transferred
    transaction_id character varying(64) NOT NULL, -- identifier of the transaction containing the transfer
    log_index integer NOT NULL, -- index of the transfer log in the transaction
    PRIMARY KEY (transfer_id)
)
CREATE TABLE web3.users (
    user_id character varying(64) NOT NULL,  -- unique identifier for the user
    username character varying(128) NOT NULL, -- username of the user
    email character varying(128) NOT NULL, -- email address of the user
    password_hash text NOT NULL, -- hashed password of the user
    created_at timestamp NOT NULL, -- time when the user account was created
    PRIMARY KEY (user_id)
)


[User] Find all addresses with a balance greater than 1000, ordered by balance in descending order.

[Assistant] SELECT address_id, public_key, balance FROM blockchain.addresses WHERE balance > 1000 ORDER BY balance DESC;

[User] Now, join this with another query to show the difference between each address's balance and the average balance of all addresses.

[Assistant] SELECT a.address_id, a.public_key, a.balance, (a.balance - (SELECT AVG(balance) FROM blockchain.addresses)) AS balance_difference FROM blockchain.addresses a WHERE a.balance > 1000 ORDER BY a.balance DESC;

[User] Can you modify this to show the percentage difference instead of absolute difference?

[Assistant] SELECT a.address_id, a.public_key, a.balance, ((a.balance - (SELECT AVG(balance) FROM blockchain.addresses)) / (SELECT AVG(balance) FROM blockchain.addresses)) * 100 AS percentage_difference FROM blockchain.addresses a WHERE a.balance > 1000 ORDER BY a.balance DESC;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE blockchain.addresses ( address_id text PRIMARY KEY, public_key text, balance numeric )


[User] 能否帮我查询特定列车行程(schedule_id 为 'sched_001')的详细信息，包括列车出发和到达时间，以及该行程所属路线的ID和相关乘客信息？

[Assistant]
SELECT s.schedule_id, s.train_id, s.route_id, s.departure_datetime, s.arrival_datetime, s.status, p.passenger_id, p.first_name, p.last_name, p.email
FROM schedules s
LEFT JOIN passengers p ON s.schedule_id = (SELECT schedule_id FROM bookings WHERE passenger_id = p.passenger_id)
WHERE s.schedule_id = 'sched_001';

[User] 能否将结果限制在状态为‘Scheduled’的行程上，并且只显示乘客的姓名和电子邮件？

[Assistant]
SELECT s.schedule_id, s.train_id, s.route_id, s.departure_datetime, s.arrival_datetime, s.status, p.passenger_id, p.first_name, p.last_name, p.email
FROM schedules s
LEFT JOIN passengers p ON s.schedule_id = (SELECT schedule_id FROM bookings WHERE passenger_id = p.passenger_id)
WHERE s.schedule_id = 'sched_001' AND s.status = 'Scheduled';

[User] 能否再加入行程的备注信息，并按出发时间降序排列？

[Assistant]
SELECT s.schedule_id, s.train_id, s.route_id, s.departure_datetime, s.arrival_datetime, s.status, s.notes, p.passenger_id, p.first_name, p.last_name, p.email
FROM schedules s
LEFT JOIN passengers p ON s.schedule_id = (SELECT schedule_id FROM bookings WHERE passenger_id = p.passenger_id)
WHERE s.schedule_id = 'sched_001' AND s.status = 'Scheduled'
ORDER BY s.departure_datetime DESC;

[User] 如果没有关联的乘客信息，能否只显示行程信息？

[Assistant]
SELECT s.schedule_id, s.train_id, s.route_id, s.departure_datetime, s.arrival_datetime, s.status, s.notes, p.passenger_id, p.first_name, p.last_name, p.email
FROM schedules s
LEFT JOIN passengers p ON s.schedule_id = (SELECT schedule_id FROM bookings WHERE passenger_id = p.passenger_id)
WHERE s.schedule_id = 'sched_001' AND s.status = 'Scheduled'
ORDER BY s.departure_datetime DESC;

System:
You are an expert in writing database language. You can write a corresponding database language query to answer the user's question based on the table structure described by the table creation statement.
##Table Structure
// PUT /schedules
{
  "mappings": {
    "properties": {
      "schedule_id": { "type": "keyword" },
      "train_id": { "type": "keyword" }, // References trains index
      "route_id": { "type": "keyword" }, // References routes index
      "departure_datetime": { "type": "date" }, // ISO 8601 format recommended
      "arrival_datetime": { "type": "date" },
      "status": { "type": "keyword" },
      "notes": { "type": "text" }
    }
  }
}
// PUT /passengers
{
  "mappings": {
    "properties": {
      "passenger_id": { "type": "keyword" },
      "first_name": {
        "type": "text",
        "fields": { "keyword": { "type": "keyword", "ignore_above": 100 } }
      },
      "last_name": {
        "type": "text",
        "fields": { "keyword": { "type": "keyword", "ignore_above": 100 } }
       },
      "email": { "type": "keyword" }, // Often used for exact matches
      "phone_number": { "type": "keyword" },
      "date_of_birth": { "type": "date", "format": "yyyy-MM-dd" },
      "loyalty_program_id": { "type": "keyword" },
      "created_at": { "type": "date" }
    }
  }
}


[User] Show policy numbers and product names for all policies that started in 2023.

[Assistant] SELECT p.policy_number, ip.product_name FROM insurance.policies AS p JOIN insurance.insurance_products AS ip ON p.product_id = ip.product_id WHERE date_part('year', p.start_date) = 2023

[User] Add the policy status and the product type to the list.

[Assistant] SELECT p.policy_number, ip.product_name, p.status, ip.product_type FROM insurance.policies AS p JOIN insurance.insurance_products AS ip ON p.product_id = ip.product_id WHERE date_part('year', p.start_date) = 2023

[User] Filter these policies to only include those where the product is currently active and the policy status is 'active'.

[Assistant] SELECT p.policy_number, ip.product_name, p.status, ip.product_type FROM insurance.policies AS p JOIN insurance.insurance_products AS ip ON p.product_id = ip.product_id WHERE date_part('year', p.start_date) = 2023 AND p.status = 'active' AND ip.is_active = TRUE

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE insurance.policies ( policy_id text, customer_id text, product_id text, agent_id text, policy_number text, start_date date, end_date date, premium_amount numeric, coverage_limit numeric, deductible numeric, status text, issued_at timestamp, cancellation_date date, cancellation_reason text )
CREATE TABLE insurance.insurance_products ( product_id text, product_name text, product_type text, description text, base_premium numeric, coverage_details text, underwriting_rules text, is_active boolean, created_at timestamp, updated_at timestamp )
CREATE TABLE insurance.claim_documents ( document_id text, claim_id text, document_type text, file_name text, file_path text, file_size_bytes integer, mime_type text, uploaded_by text, uploaded_at timestamp, description text )


[User] Show the name, symbol, and type of each asset, along with the total number of orders placed for each asset.

[Assistant]
SELECT a.name, a.symbol, a.type, COUNT(o.order_id) AS order_count
FROM trading_platform.assets a
LEFT JOIN trading_platform.orders o ON a.asset_id = o.asset_id
GROUP BY a.asset_id, a.name, a.symbol, a.type;

[User] Only include assets that have at least 10 orders, and order the result by order_count descending.

[Assistant]
SELECT a.name, a.symbol, a.type, COUNT(o.order_id) AS order_count
FROM trading_platform.assets a
LEFT JOIN trading_platform.orders o ON a.asset_id = o.asset_id
GROUP BY a.asset_id, a.name, a.symbol, a.type
HAVING COUNT(o.order_id) >= 10
ORDER BY order_count DESC;

[User] Instead of all orders, only consider orders with status 'open'.

[Assistant]
SELECT a.name, a.symbol, a.type, COUNT(o.order_id) AS open_order_count
FROM trading_platform.assets a
LEFT JOIN trading_platform.orders o ON a.asset_id = o.asset_id AND o.status = 'open'
GROUP BY a.asset_id, a.name, a.symbol, a.type
HAVING COUNT(o.order_id) >= 10
ORDER BY open_order_count DESC;

[User] The SQL doesn't work because some assets have no open orders, but I want to include those assets with a count of 0. Please update the query accordingly.

[Assistant]
SELECT a.name, a.symbol, a.type, COUNT(o.order_id) AS open_order_count
FROM trading_platform.assets a
LEFT JOIN trading_platform.orders o ON a.asset_id = o.asset_id AND o.status = 'open'
GROUP BY a.asset_id, a.name, a.symbol, a.type
HAVING COUNT(o.order_id) >= 10 OR COUNT(o.order_id) = 0
ORDER BY open_order_count DESC;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE trading_platform.wallets ( wallet_id.text, user_id.text, address.text, private_key.text, created_at.timestamp )
CREATE TABLE trading_platform.orders ( order_id.text, user_id.text, wallet_id.text, asset_id.text, order_type.text, quantity.numeric, price.numeric, status.text, created_at.timestamp )
CREATE TABLE trading_platform.trades (
    trade_id character varying(64) NOT NULL,  -- unique identifier for the trade
    order_id character varying(64) NOT NULL, -- identifier of the order that led to the trade
    buyer_id character varying(64) NOT NULL, -- identifier of the buyer
    seller_id character varying(64) NOT NULL, -- identifier of the seller
    asset_id character varying(64) NOT NULL, -- identifier of the asset being traded
    quantity numeric(38,14) NOT NULL, -- quantity of the asset in the trade
    price numeric(38,14) NOT NULL, -- price per unit of the asset
    traded_at timestamp NOT NULL, -- time when the trade was executed
    PRIMARY KEY (trade_id)
)
CREATE TABLE trading_platform.assets ( asset_id text, name text, symbol text, type text )
CREATE TABLE trading_platform.dapps ( dapp_id text PRIMARY KEY, name text, description text, url text )
CREATE TABLE trading_platform.kyc_audit (
    kyc_audit_id character varying(64) NOT NULL,  -- unique identifier for the KYC audit
    user_id character varying(64) NOT NULL, -- identifier of the user being audited
    status character varying(32) NOT NULL, -- status of the KYC audit (e.g., pending, approved, rejected)
    reviewed_at timestamp NOT NULL, -- time when the KYC audit was reviewed
    PRIMARY KEY (kyc_audit_id)
)
CREATE TABLE trading_platform.notifications ( notification_id.text, user_id.text, message.text, sent_at.timestamp, read_at.timestamp )


[User] List all passengers who have never made a booking, showing their passenger_id, first_name, last_name, and email.

[Assistant]
SELECT
    p.passenger_id,
    p.first_name,
    p.last_name,
    p.email
FROM transportation.passengers p
LEFT JOIN transportation.bookings b ON p.passenger_id = b.passenger_id
WHERE b.booking_id IS NULL;

[User] Actually, please include their phone_number as well.

[Assistant]
SELECT
    p.passenger_id,
    p.first_name,
    p.last_name,
    p.email,
    p.phone_number
FROM transportation.passengers p
LEFT JOIN transportation.bookings b ON p.passenger_id = b.passenger_id
WHERE b.booking_id IS NULL;

[User] Also, limit to passengers created after '2022-01-01'.

[Assistant]
SELECT
    p.passenger_id,
    p.first_name,
    p.last_name,
    p.email,
    p.phone_number
FROM transportation.passengers p
LEFT JOIN transportation.bookings b ON p.passenger_id = b.passenger_id
WHERE b.booking_id IS NULL
  AND p.created_at > '2022-01-01';

[User] Finally, sort the results by last_name in ascending order.

[Assistant]
SELECT
    p.passenger_id,
    p.first_name,
    p.last_name,
    p.email,
    p.phone_number
FROM transportation.passengers p
LEFT JOIN transportation.bookings b ON p.passenger_id = b.passenger_id
WHERE b.booking_id IS NULL
  AND p.created_at > '2022-01-01'
ORDER BY p.last_name ASC;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE transportation.vehicles ( vehicle_id text PRIMARY KEY, license_plate text, vin text, make text, model text, year int, type text, capacity int, fuel_type text, status text, depot_id text, acquisition_date date )
CREATE TABLE transportation.drivers ( driver_id text, employee_id text, first_name text, last_name text, license_number text, license_expiry_date date, contact_number text, email text, hire_date date, status text )
CREATE TABLE transportation.routes ( route_id text PRIMARY KEY, route_number text, description text, origin_location_id text, destination_location_id text, distance_km numeric, estimated_duration_minutes int, type text )
CREATE TABLE transportation.trips ( trip_id text PRIMARY KEY, route_id text, vehicle_id text, driver_id text, scheduled_departure timestamp, actual_departure timestamp, scheduled_arrival timestamp, actual_arrival timestamp, origin_location_id text, destination_location_id text, status text, passenger_count int, cargo_manifest_id text )
CREATE TABLE transportation.locations ( location_id text PRIMARY KEY, name text, type text, address_line1 text, city text, state_province text, postal_code text, country text, latitude numeric, longitude numeric, timezone text )
CREATE TABLE transportation.maintenance_logs ( log_id.text, vehicle_id.text, service_date.date, odometer_reading.integer, service_type.text, description.text, cost.numeric, mechanic_name.text, next_service_due_date.date )
CREATE TABLE transportation.passengers (
    passenger_id character varying(64) NOT NULL,  -- unique identifier for the passenger
    first_name character varying(128) NOT NULL, -- passenger's first name
    last_name character varying(128) NOT NULL, -- passenger's last name
    email character varying(128) UNIQUE, -- email address
    phone_number character varying(32) UNIQUE, -- phone number
    date_of_birth date, -- passenger's date of birth
    loyalty_program_id character varying(64), -- identifier for loyalty program membership
    created_at timestamp with time zone NOT NULL, -- time when the passenger record was created
    PRIMARY KEY (passenger_id)
)
CREATE TABLE transportation.bookings ( booking_id text, passenger_id text, trip_id text, seat_number text, booking_time timestamp, status text, fare numeric, payment_transaction_id text, special_requests text )


[User] Show me all smart contracts created by addresses that have created more than 3 contracts, along with the count of contracts each creator has made.

[Assistant] SELECT creator_address, COUNT(*) AS contract_count FROM blockchain.smart_contracts GROUP BY creator_address HAVING COUNT(*) > 3;

[User] Now filter these results to only show contracts created in the last 6 months.

[Assistant] SELECT sc.creator_address, COUNT(*) AS contract_count FROM blockchain.smart_contracts sc WHERE sc.timestamp >= NOW() - INTERVAL '6 months' GROUP BY sc.creator_address HAVING COUNT(*) > 3;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE blockchain.smart_contracts ( contract_id text PRIMARY KEY, creator_address text, code text, timestamp timestamp )


[User] Show each service's name along with the total number of appointments scheduled and the number of unique locations these appointments are scheduled at.

[Assistant]
SELECT s.service_name, COUNT(a.application_id) AS appointment_count, COUNT(DISTINCT ap.location_id) AS unique_location_count
FROM government_services.services s
JOIN government_services.applications a ON s.service_id = a.service_id
JOIN government_services.appointments ap ON a.application_id = ap.application_id
GROUP BY s.service_name;

[User] I got an error: relation 'appointments' does not exist.

[Assistant]
-- The appointments table is not present in the provided schema. If you want to count by another join, perhaps by documents or payments, please specify.
-- Alternatively, do you want appointment information replaced with application submissions per service and their associated location from service_locations?
SELECT s.service_name, COUNT(a.application_id) AS application_count, COUNT(DISTINCT sl.location_id) AS unique_location_count
FROM government_services.services s
JOIN government_services.applications a ON s.service_id = a.service_id
JOIN government_services.service_locations sl ON s.agency_id = sl.agency_id
GROUP BY s.service_name;

[User] Show only those services where application_count is greater than 50.

[Assistant]
SELECT s.service_name, COUNT(a.application_id) AS application_count, COUNT(DISTINCT sl.location_id) AS unique_location_count
FROM government_services.services s
JOIN government_services.applications a ON s.service_id = a.service_id
JOIN government_services.service_locations sl ON s.agency_id = sl.agency_id
GROUP BY s.service_name
HAVING COUNT(a.application_id) > 50;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE government_services.citizens (
    citizen_id character varying(64) NOT NULL,  -- unique identifier for the citizen
    national_id_number character varying(128) NOT NULL UNIQUE, -- official national identification number
    first_name character varying(100) NOT NULL,
    last_name character varying(100) NOT NULL,
    date_of_birth date NOT NULL,
    gender character varying(20),
    primary_address text NOT NULL, -- full primary residential address
    contact_email character varying(128) UNIQUE,
    contact_phone character varying(32),
    registration_date timestamp NOT NULL, -- when the citizen profile was created
    is_verified boolean DEFAULT false, -- whether identity has been officially verified
    PRIMARY KEY (citizen_id)
)
CREATE TABLE government_services.agencies ( agency_id.text, agency_name.text, jurisdiction_level.text, primary_contact_email.text, main_phone_number.text, website_url.text, established_date.date, parent_agency_id.text )
CREATE TABLE government_services.services ( service_id text PRIMARY KEY, agency_id text, service_name text, description text, category text, eligibility_criteria text, standard_fee numeric, average_processing_time_days int, is_active boolean, online_application_url text )
CREATE TABLE government_services.applications ( application_id character varying(64) NOT NULL, citizen_id character varying(64) NOT NULL, service_id character varying(64) NOT NULL, submitted_at timestamp NOT NULL, status character varying(50) NOT NULL, last_updated_at timestamp NOT NULL, assigned_employee_id character varying(64), decision_date date, notes text, reference_number character varying(100) UNIQUE, PRIMARY KEY (application_id) )
CREATE TABLE government_services.documents ( document_id.text, application_id.text, citizen_id.text, document_type.text, file_reference.text, upload_timestamp.timestamp, expiry_date.date, verification_status.text, verified_by_employee_id.text, verification_timestamp.timestamp )
CREATE TABLE government_services.payments ( payment_id text, application_id text, citizen_id text, service_id text, amount numeric, currency text, payment_method text, payment_provider_reference text, payment_timestamp timestamp, status text, notes text )
CREATE TABLE government_services.service_locations (
    location_id character varying(64) NOT NULL, -- unique identifier for the physical location
    agency_id character varying(64) NOT NULL, -- FK to agencies table
    location_name character varying(200), -- e.g., Downtown DMV Office
    address text NOT NULL,
    city character varying(100),
    state character varying(50),
    postal_code character varying(20),
    latitude numeric(9, 6),
    longitude numeric(9, 6),
    operating_hours text, -- description of opening times
    contact_phone character varying(32),
    is_accessible boolean, -- accessibility information (e.g., wheelchair access)
    PRIMARY KEY (location_id)
)
CREATE TABLE government_services.notifications ( notification_id text PRIMARY KEY, citizen_id text, application_id text, message_subject text, message_body text, channel text, sent_at timestamp, status text, related_entity_type text, related_entity_id text )


[User] Show me each case ID with its latest uploaded document. I want to see the case ID, document name, version, and upload timestamp for the most recently uploaded document in each case.

[Assistant]
SELECT d.case_id, d.document_name, d.version, d.upload_timestamp
FROM legal_services.documents d
INNER JOIN (
    SELECT case_id, MAX(upload_timestamp) AS max_upload_timestamp
    FROM legal_services.documents
    GROUP BY case_id
) latest ON d.case_id = latest.case_id AND d.upload_timestamp = latest.max_upload_timestamp;

[User] I actually also need to see the document type for these latest documents.

[Assistant]
SELECT d.case_id, d.document_name, d.version, d.upload_timestamp, d.document_type
FROM legal_services.documents d
INNER JOIN (
    SELECT case_id, MAX(upload_timestamp) AS max_upload_timestamp
    FROM legal_services.documents
    GROUP BY case_id
) latest ON d.case_id = latest.case_id AND d.upload_timestamp = latest.max_upload_timestamp;

[User] Now, only show cases where the latest uploaded document is a 'Contract'.

[Assistant]
SELECT d.case_id, d.document_name, d.version, d.upload_timestamp, d.document_type
FROM legal_services.documents d
INNER JOIN (
    SELECT case_id, MAX(upload_timestamp) AS max_upload_timestamp
    FROM legal_services.documents
    GROUP BY case_id
) latest ON d.case_id = latest.case_id AND d.upload_timestamp = latest.max_upload_timestamp
WHERE d.document_type = 'Contract';

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE legal_services.documents ( document_id text, case_id text, document_name text, document_type text, storage_path text, uploaded_by_lawyer_id text, upload_timestamp timestamp, version integer, description text )


[User] What is the average profit for smart money addresses on the 'Arbitrum' chain?

[Assistant] SELECT AVG(profit) FROM smart_money_profit WHERE chain = 'Arbitrum'

[User] And how many smart money addresses on the 'Polygon' chain have a profit greater than $1000?

[Assistant] SELECT COUNT(address) FROM smart_money_profit WHERE chain = 'Polygon' AND profit > 1000

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE smart_money_profit ( address text, rank numeric, profit numeric, roi numeric, realized_ratio numeric, most_profit_token text, last_trade_time text, chain text )


[User] Generate a report listing each manager with the number of agents they manage. Include manager_id, manager's full name, and report_count.

[Assistant]
SELECT m.agent_id AS manager_id,
       m.first_name || ' ' || m.last_name AS manager_name,
       COUNT(a.agent_id) AS report_count
FROM insurance.agents m
LEFT JOIN insurance.agents a
  ON m.agent_id = a.manager_id
GROUP BY m.agent_id, m.first_name, m.last_name;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE insurance.agents ( agent_id.text, first_name.text, last_name.text, agency_name.text, license_number.text, license_state.text, contact_email.text, contact_phone.text, hire_date.date, termination_date.date, status.text, commission_rate.numeric, manager_id.text )


[User] Show me all room types with a base rate over $200 and max occupancy of at least 4, along with their property IDs and amenities.

[Assistant] SELECT room_type_id, property_id, type_name, base_rate, max_occupancy, amenities FROM hospitality_technology.room_types WHERE base_rate > 200 AND max_occupancy >= 4;

[User] Now, join this with the guests table to show only room types from properties where the guest's country code is 'USA'.

[Assistant] SELECT rt.room_type_id, rt.property_id, rt.type_name, rt.base_rate, rt.max_occupancy, rt.amenities FROM hospitality_technology.room_types rt JOIN hospitality_technology.guests g ON rt.property_id = g.property_id WHERE rt.base_rate > 200 AND rt.max_occupancy >= 4 AND g.country_code = 'USA';

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE hospitality_technology.room_types ( room_type_id text PRIMARY KEY, property_id text, type_name text, description text, base_rate numeric, max_occupancy int, bed_type text, area_sqft numeric, amenities text )
CREATE TABLE hospitality_technology.guests ( guest_id text, first_name text, last_name text, email text, phone_number text, date_of_birth date, address_line1 text, city text, state_province text, postal_code text, country_code text, preferences text, loyalty_member_id text, communication_consent boolean, created_at timestamp, updated_at timestamp )


[User] Which policies have a premium amount greater than the base premium of their respective insurance product? Please show the policy_number, premium_amount, product_name, and base_premium.

[Assistant]
SELECT p.policy_number, p.premium_amount, ip.product_name, ip.base_premium
FROM insurance.policies p
INNER JOIN insurance.insurance_products ip ON p.product_id = ip.product_id
WHERE p.premium_amount > ip.base_premium;

[User] Now, only include policies where the coverage_limit is above 500,000.

[Assistant]
SELECT p.policy_number, p.premium_amount, ip.product_name, ip.base_premium
FROM insurance.policies p
INNER JOIN insurance.insurance_products ip ON p.product_id = ip.product_id
WHERE p.premium_amount > ip.base_premium
  AND p.coverage_limit > 500000;

[User] Actually, I also want to see only active policies.

[Assistant]
SELECT p.policy_number, p.premium_amount, ip.product_name, ip.base_premium
FROM insurance.policies p
INNER JOIN insurance.insurance_products ip ON p.product_id = ip.product_id
WHERE p.premium_amount > ip.base_premium
  AND p.coverage_limit > 500000
  AND p.status = 'Active';

[User] Could you sort the results by premium_amount in descending order?

[Assistant]
SELECT p.policy_number, p.premium_amount, ip.product_name, ip.base_premium
FROM insurance.policies p
INNER JOIN insurance.insurance_products ip ON p.product_id = ip.product_id
WHERE p.premium_amount > ip.base_premium
  AND p.coverage_limit > 500000
  AND p.status = 'Active'
ORDER BY p.premium_amount DESC;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE insurance.policies ( policy_id text, customer_id text, product_id text, agent_id text, policy_number text, start_date date, end_date date, premium_amount numeric, coverage_limit numeric, deductible numeric, status text, issued_at timestamp, cancellation_date date, cancellation_reason text )
CREATE TABLE insurance.insurance_products ( product_id text PRIMARY KEY, product_name text, product_type text, description text, base_premium numeric, coverage_details text, underwriting_rules text, is_active boolean, created_at timestamp, updated_at timestamp )


[User] Show policy numbers, start dates, and the type of the insurance product for policies with a deductible greater than 500.

[Assistant] SELECT T1.policy_number, T1.start_date, T2.product_type FROM insurance.policies AS T1 JOIN insurance.insurance_products AS T2 ON T1.product_id = T2.product_id WHERE T1.deductible > 500;

[User] Could you also include the product name and only show results for policies that are currently 'active'?

[Assistant] SELECT T1.policy_number, T1.start_date, T2.product_type, T2.product_name FROM insurance.policies AS T1 JOIN insurance.insurance_products AS T2 ON T1.product_id = T2.product_id WHERE T1.deductible > 500 AND T1.status = 'active';

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE insurance.policies ( policy_id.text, customer_id.text, product_id.text, agent_id.text, policy_number.text, start_date.date, end_date.date, premium_amount.numeric, coverage_limit.numeric, deductible.numeric, status.text, issued_at.timestamp, cancellation_date.date, cancellation_reason.text )
CREATE TABLE insurance.insurance_products ( product_id.text, product_name.text, product_type.text, description.text, base_premium.numeric, coverage_details.text, underwriting_rules.text, is_active.boolean, created_at.timestamp, updated_at.timestamp )


[User] List the usernames and emails of all users who registered on '2023-03-15'.

[Assistant] SELECT username, email FROM web3.users WHERE DATE(created_at) = '2023-03-15';

[User] Instead of the list, can you just give me the total number of users who registered on '2023-03-15'?

[Assistant] SELECT COUNT(*) FROM web3.users WHERE DATE(created_at) = '2023-03-15';

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE web3.users ( user_id text, username text, email text, password_hash text, created_at timestamp )


[User] Find pairs of reservations at the same property where the second check-in is within 7 days after the first check-out. Return first_reservation, second_reservation, and gap_days.

[Assistant]
SELECT r1.reservation_id AS first_reservation,
       r2.reservation_id AS second_reservation,
       CAST(r2.check_in_date - r1.check_out_date AS INTEGER) AS gap_days
FROM hospitality_technology.reservations r1
JOIN hospitality_technology.reservations r2
  ON r1.property_id = r2.property_id
  AND r2.check_in_date > r1.check_out_date
  AND r2.check_in_date <= r1.check_out_date + INTERVAL '7 days';

[User] Now restrict to pairs where the first reservation status = 'CheckedOut' and the second reservation status = 'Confirmed'.

[Assistant]
SELECT r1.reservation_id AS first_reservation,
       r2.reservation_id AS second_reservation,
       CAST(r2.check_in_date - r1.check_out_date AS INTEGER) AS gap_days
FROM hospitality_technology.reservations r1
JOIN hospitality_technology.reservations r2
  ON r1.property_id = r2.property_id
  AND r2.check_in_date > r1.check_out_date
  AND r2.check_in_date <= r1.check_out_date + INTERVAL '7 days'
WHERE r1.status = 'CheckedOut'
  AND r2.status = 'Confirmed';

[User] Lastly, order by gap_days ascending and limit to 5 results.

[Assistant]
SELECT r1.reservation_id AS first_reservation,
       r2.reservation_id AS second_reservation,
       CAST(r2.check_in_date - r1.check_out_date AS INTEGER) AS gap_days
FROM hospitality_technology.reservations r1
JOIN hospitality_technology.reservations r2
  ON r1.property_id = r2.property_id
  AND r2.check_in_date > r1.check_out_date
  AND r2.check_in_date <= r1.check_out_date + INTERVAL '7 days'
WHERE r1.status = 'CheckedOut'
  AND r2.status = 'Confirmed'
ORDER BY gap_days ASC
LIMIT 5;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE hospitality_technology.reservations ( reservation_id text, property_id text, guest_id text, room_id text, room_type_id text, check_in_date date, check_out_date date, actual_check_in_ts timestamp, actual_check_out_ts timestamp, num_adults integer, num_children integer, status text, booking_source text, rate_plan_id text, total_amount numeric, amount_paid numeric, special_requests text, created_at timestamp, updated_at timestamp )


[User] List all users and the count of wallets they own.

[Assistant] SELECT u.username, COUNT(w.wallet_id) AS wallet_count FROM blockchain.users u JOIN blockchain.wallets w ON u.user_id = w.user_id GROUP BY u.user_id, u.username;

[User] Filter the previous list to only include users who own more than 2 wallets.

[Assistant] SELECT u.username, COUNT(w.wallet_id) AS wallet_count FROM blockchain.users u JOIN blockchain.wallets w ON u.user_id = w.user_id GROUP BY u.user_id, u.username HAVING COUNT(w.wallet_id) > 2;

[User] Now, for those users, also include the total sum of balances across all addresses associated with their wallets.

[Assistant] SELECT u.username, COUNT(DISTINCT w.wallet_id) AS wallet_count, SUM(a.balance) AS total_balance FROM blockchain.users u JOIN blockchain.wallets w ON u.user_id = w.user_id JOIN blockchain.addresses a ON w.address_id = a.address_id GROUP BY u.user_id, u.username HAVING COUNT(DISTINCT w.wallet_id) > 2;

System:
You are an expert in writing database language. You can write a corresponding database language query to answer the user's question based on the table structure described by the table creation statement.
##Table Structure
CREATE TABLE blockchain.addresses ( address_id character varying(128) NOT NULL, public_key text NOT NULL, balance numeric(38,14) NOT NULL, PRIMARY KEY (address_id) )
CREATE TABLE blockchain.nodes ( node_id character varying(64) NOT NULL, ip_address character varying(15) NOT NULL, port integer NOT NULL, last_seen timestamp NOT NULL, PRIMARY KEY (node_id) )
CREATE TABLE blockchain.wallets ( wallet_id character varying(64) NOT NULL, user_id character varying(64) NOT NULL, address_id character varying(128) NOT NULL, private_key text NOT NULL, PRIMARY KEY (wallet_id) )
CREATE TABLE blockchain.users ( user_id character varying(64) NOT NULL, username character varying(128) NOT NULL, email character varying(128) NOT NULL, password_hash text NOT NULL, PRIMARY KEY (user_id) )


[User] For each player, show their player_id and the number of unique games they have played sessions on.

[Assistant]
SELECT player_id, COUNT(DISTINCT game_id) AS unique_games
FROM gaming_technology.game_sessions
GROUP BY player_id;

[User] Also show the total number of sessions they have played.

[Assistant]
SELECT player_id, COUNT(DISTINCT game_id) AS unique_games, COUNT(*) AS total_sessions
FROM gaming_technology.game_sessions
GROUP BY player_id;

[User] Only include players who have played on more than 2 unique games.

[Assistant]
SELECT player_id, COUNT(DISTINCT game_id) AS unique_games, COUNT(*) AS total_sessions
FROM gaming_technology.game_sessions
GROUP BY player_id
HAVING COUNT(DISTINCT game_id) > 2;

[User] For each result, include the player's username as well.

[Assistant]
SELECT p.player_id, p.username, COUNT(DISTINCT gs.game_id) AS unique_games, COUNT(*) AS total_sessions
FROM gaming_technology.players p
JOIN gaming_technology.game_sessions gs ON p.player_id = gs.player_id
GROUP BY p.player_id, p.username
HAVING COUNT(DISTINCT gs.game_id) > 2;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE gaming_technology.players ( player_id.uuid, username.text, email.text, password_hash.text, registration_date.timestamptz, last_login.timestamptz, country_code.text, status.text, profile_data.jsonb )
CREATE TABLE gaming_technology.game_sessions (
    session_id uuid NOT NULL DEFAULT gen_random_uuid(), -- unique identifier for the game session
    player_id uuid NOT NULL, -- FK linking to the players table
    game_id uuid NOT NULL, -- FK linking to the games table
    server_id uuid, -- FK linking to the servers table (nullable for single-player)
    start_time timestamp with time zone NOT NULL DEFAULT CURRENT_TIMESTAMP, -- when the session began
    end_time timestamp with time zone, -- when the session ended (null if ongoing)
    duration_seconds integer, -- calculated duration of the session in seconds
    score integer, -- player's score for the session, if applicable
    session_data jsonb, -- flexible field for session-specific info (e.g., map played, character used)
    PRIMARY KEY (session_id)
    -- FOREIGN KEY (player_id) REFERENCES gaming_technology.players(player_id),
    -- FOREIGN KEY (game_id) REFERENCES gaming_technology.games(game_id),
    -- FOREIGN KEY (server_id) REFERENCES gaming_technology.servers(server_id)
)
CREATE TABLE gaming_technology.servers ( server_id uuid NOT NULL DEFAULT gen_random_uuid(), game_id uuid NOT NULL, server_name character varying(150), region character varying(50) NOT NULL, ip_address character varying(45), port integer, current_players integer NOT NULL DEFAULT 0, max_players integer NOT NULL, status character varying(30) NOT NULL DEFAULT 'offline', last_heartbeat timestamp with time zone, PRIMARY KEY (server_id) )
CREATE TABLE gaming_technology.achievements ( achievement_id uuid, game_id uuid, name text, description text, icon_url text, points integer, hidden boolean )
CREATE TABLE gaming_technology.player_achievements ( player_achievement_id.uuid, player_id.uuid, achievement_id.uuid, unlocked_at.timestamptz )
CREATE TABLE gaming_technology.in_game_items ( item_id uuid NOT NULL DEFAULT gen_random_uuid(), game_id uuid NOT NULL, item_name character varying(150) NOT NULL, item_type character varying(50) NOT NULL, description text, rarity character varying(30), cost_currency character varying(10), cost_amount numeric(12, 2), attributes jsonb, PRIMARY KEY (item_id) )


[User] Show me each service order along with the next order placed by the same guest, including both order IDs and the time difference in minutes between the two orders.

[Assistant]
SELECT a.order_id,
       b.order_id AS next_order_id,
       EXTRACT(EPOCH FROM (b.order_timestamp - a.order_timestamp)) / 60 AS diff_minutes
FROM hospitality_technology.service_orders a
JOIN hospitality_technology.service_orders b
  ON a.guest_id = b.guest_id
 AND b.order_timestamp > a.order_timestamp;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE hospitality_technology.service_orders ( order_id.text, reservation_id.text, guest_id.text, service_id.text, staff_id_ordered.text, staff_id_delivered.text, order_timestamp.timestamp, delivery_timestamp.timestamp, quantity.integer, unit_price.numeric, total_price.numeric, status.text, notes.text, bill_id.text )


[User] Show me all premium payments made in Q1 2023, along with their payment methods and amounts, sorted by payment date.

[Assistant] SELECT payment_method, amount_paid, payment_date FROM insurance.premium_payments WHERE payment_date BETWEEN '2023-01-01' AND '2023-03-31' ORDER BY payment_date;

[User] Now break this down by payment method to show the total amount collected per payment method in that quarter.

[Assistant] SELECT payment_method, SUM(amount_paid) AS total_amount FROM insurance.premium_payments WHERE payment_date BETWEEN '2023-01-01' AND '2023-03-31' GROUP BY payment_method ORDER BY total_amount DESC;

[User] I also want to see the average payment amount for each payment method in Q1 2023.

[Assistant] SELECT payment_method, AVG(amount_paid) AS average_payment FROM insurance.premium_payments WHERE payment_date BETWEEN '2023-01-01' AND '2023-03-31' GROUP BY payment_method ORDER BY average_payment DESC;

[User] Finally, show me only payment methods where the average payment was greater than $300.

[Assistant] SELECT payment_method, AVG(amount_paid) AS average_payment FROM insurance.premium_payments WHERE payment_date BETWEEN '2023-01-01' AND '2023-03-31' GROUP BY payment_method HAVING AVG(amount_paid) > 300 ORDER BY average_payment DESC;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE insurance.premium_payments ( payment_id character varying(64) NOT NULL, policy_id character varying(64) NOT NULL, customer_id character varying(64) NOT NULL, payment_date timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, amount_paid numeric(12, 2) NOT NULL, payment_method character varying(50), transaction_reference character varying(128) UNIQUE, due_date date, payment_period_start date, payment_period_end date, status character varying(30) NOT NULL DEFAULT 'Completed', PRIMARY KEY (payment_id) )


[User] Display the name and type of each location, as well as the earliest and latest maintenance service_date for vehicles assigned to that location (assuming vehicle_id matches location_id).

[Assistant]
SELECT l.name, l.type,
       MIN(m.service_date) AS earliest_service,
       MAX(m.service_date) AS latest_service
FROM transportation.locations l
LEFT JOIN transportation.maintenance_logs m ON l.location_id = m.vehicle_id
GROUP BY l.location_id, l.name, l.type;

[User] I got an error because some locations do not have any maintenance logs. Please only show locations that have at least one associated maintenance log.

[Assistant]
SELECT l.name, l.type,
       MIN(m.service_date) AS earliest_service,
       MAX(m.service_date) AS latest_service
FROM transportation.locations l
JOIN transportation.maintenance_logs m ON l.location_id = m.vehicle_id
GROUP BY l.location_id, l.name, l.type;

[User] Now, include the total cost of all maintenance performed for each location.

[Assistant]
SELECT l.name, l.type,
       MIN(m.service_date) AS earliest_service,
       MAX(m.service_date) AS latest_service,
       SUM(m.cost) AS total_maintenance_cost
FROM transportation.locations l
JOIN transportation.maintenance_logs m ON l.location_id = m.vehicle_id
GROUP BY l.location_id, l.name, l.type;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE transportation.locations ( location_id text PRIMARY KEY, name text, type text, address_line1 text, city text, state_province text, postal_code text, country text, latitude numeric, longitude numeric, timezone text )
CREATE TABLE transportation.maintenance_logs ( log_id text PRIMARY KEY, vehicle_id text, service_date date, odometer_reading int, service_type text, description text, cost numeric, mechanic_name text, next_service_due_date date )
CREATE TABLE transportation.passengers ( passenger_id text PRIMARY KEY, first_name text, last_name text, email text, phone_number text, date_of_birth date, loyalty_program_id text, created_at timestamp )


[User] For each chain, find the narrative category that has the highest total market_cap and display the chain, narrative, and that total market_cap.

[Assistant]
SELECT chain,
       narrative,
       total_cap
FROM (
  SELECT chain,
         narrative,
         SUM(market_cap) AS total_cap,
         RANK() OVER (PARTITION BY chain ORDER BY SUM(market_cap) DESC) AS rnk
  FROM token_basic_info
  GROUP BY chain, narrative
) t
WHERE rnk = 1;

[User] I received an error about window functions. Can you rewrite the query without using window functions?

[Assistant]
WITH agg AS (
  SELECT chain,
         narrative,
         SUM(market_cap) AS total_cap
  FROM token_basic_info
  GROUP BY chain, narrative
),
max_cap AS (
  SELECT chain,
         MAX(total_cap) AS max_cap
  FROM agg
  GROUP BY chain
)
SELECT a.chain,
       a.narrative,
       a.total_cap
FROM agg a
JOIN max_cap m
  ON a.chain = m.chain
 AND a.total_cap = m.max_cap;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE token_basic_info ( coin_id text, token_name text, token_symbol text, token_address text, chain text, price numeric, price_change_percentage_1h numeric, price_change_percentage_24h numeric, price_change_percentage_7d numeric, highest_price_24h numeric, lowest_price_24h numeric, market_cap numeric, market_cap_rank numeric, market_cap_change_percentage_24h text, total_volume text, narrative text, trend_rank numeric )


[User] Which patients have insurance policies that are effective between May 1st, 2023 and October 1st, 2023? Show their patient_id, policy_number, and effective_date, and also include the related plan_id.

[Assistant] SELECT patient_id, policy_number, effective_date, plan_id FROM healthcare.patient_insurance WHERE effective_date >= '2023-05-01' AND effective_date <= '2023-10-01';

[User] I only want to see policies that are still primary. Could you adjust the query to add that condition?

[Assistant] SELECT patient_id, policy_number, effective_date, plan_id FROM healthcare.patient_insurance WHERE effective_date >= '2023-05-01' AND effective_date <= '2023-10-01' AND is_primary = true;

[User] Actually, please also show only entries where the subscriber_name starts with the letter 'A'.

[Assistant] SELECT patient_id, policy_number, effective_date, plan_id FROM healthcare.patient_insurance WHERE effective_date >= '2023-05-01' AND effective_date <= '2023-10-01' AND is_primary = true AND subscriber_name LIKE 'A%';

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE healthcare.patient_insurance (
    patient_insurance_id character varying(64) NOT NULL, -- unique identifier for this patient-plan link
    patient_id character varying(64) NOT NULL, -- FK to patients table
    plan_id character varying(64) NOT NULL, -- FK to insurance_plans table
    policy_number character varying(100) NOT NULL, -- patient's policy number
    group_number character varying(100), -- group number, if applicable
    subscriber_name character varying(200), -- name of the primary policy holder
    effective_date date NOT NULL, -- date the coverage begins
    expiration_date date, -- date the coverage ends (if known)
    is_primary boolean NOT NULL DEFAULT true, -- indicates if this is the primary insurance
    PRIMARY KEY (patient_insurance_id),
    UNIQUE (patient_id, plan_id, policy_number) -- ensure a patient doesn't have the same policy twice
)


[User] List all fuel logs where the fuel type is diesel and the quantity is more than 50 liters, including the vehicle ID and total cost.

[Assistant] SELECT fuel_log_id, vehicle_id, trip_id, log_timestamp, quantity, total_cost FROM transportation.fuel_logs WHERE fuel_type = 'diesel' AND quantity > 50 AND unit = 'liters';

[User] Can you also include the trip ID and order the results by the most expensive fuel logs first?

[Assistant] SELECT fuel_log_id, vehicle_id, trip_id, log_timestamp, quantity, total_cost FROM transportation.fuel_logs WHERE fuel_type = 'diesel' AND quantity > 50 AND unit = 'liters' ORDER BY total_cost DESC;

[User] Now filter these results to only show logs from the last 30 days.

[Assistant] SELECT fuel_log_id, vehicle_id, trip_id, log_timestamp, quantity, total_cost FROM transportation.fuel_logs WHERE fuel_type = 'diesel' AND quantity > 50 AND unit = 'liters' AND log_timestamp >= CURRENT_DATE - INTERVAL '30 days' ORDER BY total_cost DESC;

[User] There seems to be a typo in your SQL - it should be 'INTERVAL' not 'INTERVAL'. Also, can you include the location name where the fueling occurred?

[Assistant] SELECT fl.fuel_log_id, fl.vehicle_id, fl.trip_id, fl.log_timestamp, fl.quantity, fl.total_cost, l.name AS location_name FROM transportation.fuel_logs fl LEFT JOIN transportation.locations l ON fl.location_id = l.location_id WHERE fl.fuel_type = 'diesel' AND fl.quantity > 50 AND fl.unit = 'liters' AND fl.log_timestamp >= CURRENT_DATE - INTERVAL '30 days' ORDER BY fl.total_cost DESC;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE transportation.drivers ( driver_id text, employee_id text, first_name text, last_name text, license_number text, license_expiry_date date, contact_number text, email text, hire_date date, status text )
CREATE TABLE transportation.trips ( trip_id text, route_id text, vehicle_id text, driver_id text, scheduled_departure timestamp, actual_departure timestamp, scheduled_arrival timestamp, actual_arrival timestamp, origin_location_id text, destination_location_id text, status text, passenger_count integer, cargo_manifest_id text )
CREATE TABLE transportation.locations ( location_id text, name text, type text, address_line1 text, city text, state_province text, postal_code text, country text, latitude numeric, longitude numeric, timezone text )
CREATE TABLE transportation.fuel_logs ( fuel_log_id text, vehicle_id text, trip_id text, log_timestamp timestamp, fuel_type text, quantity numeric, unit text, cost_per_unit numeric, total_cost numeric, odometer_reading integer, location_id text )
CREATE TABLE transportation.bookings ( booking_id text, passenger_id text, trip_id text, seat_number text, booking_time timestamp, status text, fare numeric, payment_transaction_id text, special_requests text )


[User] List group conversation names and the number of messages sent in each conversation after January 1, 2023.

[Assistant] SELECT c.group_name, COUNT(m.message_id) FROM social_media.conversations c JOIN social_media.messages m ON c.conversation_id = m.conversation_id WHERE c.is_group_chat = true AND m.sent_at >= '2023-01-01' GROUP BY c.conversation_id, c.group_name;

[User] Only show conversations that have more than 100 messages sent after that date.

[Assistant] SELECT c.group_name, COUNT(m.message_id) FROM social_media.conversations c JOIN social_media.messages m ON c.conversation_id = m.conversation_id WHERE c.is_group_chat = true AND m.sent_at >= '2023-01-01' GROUP BY c.conversation_id, c.group_name HAVING COUNT(m.message_id) > 100;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE social_media.users ( user_id text, username text, email text, password_hash text, full_name text, profile_picture_url text, bio text, location text, created_at timestamp, updated_at timestamp, is_verified boolean )
CREATE TABLE social_media.posts ( post_id text, user_id text, content text, media_url text, media_type text, created_at timestamp, updated_at timestamp, visibility text, location_lat numeric, location_lon numeric )
CREATE TABLE social_media.likes ( like_id text, user_id text, post_id text, comment_id text, created_at timestamp )
CREATE TABLE social_media.follows ( follow_id text, follower_user_id text, following_user_id text, created_at timestamp )
CREATE TABLE social_media.post_hashtags ( post_hashtag_id text, post_id text, hashtag_id text )
CREATE TABLE social_media.messages ( message_id text, conversation_id text, sender_user_id text, content text, media_url text, media_type text, sent_at timestamp, read_at timestamp )
CREATE TABLE social_media.conversations ( conversation_id text, created_at timestamp, last_message_at timestamp, is_group_chat boolean, group_name text )
CREATE TABLE social_media.conversation_participants ( participant_id text, conversation_id text, user_id text, joined_at timestamp, last_read_at timestamp )
CREATE TABLE social_media.notifications ( notification_id text, recipient_user_id text, sender_user_id text, notification_type text, target_entity_id text, target_entity_type text, created_at timestamp, read_at timestamp )
CREATE TABLE social_media.user_settings ( setting_id text, user_id text, theme text, email_notifications_enabled boolean, push_notifications_enabled boolean, private_profile boolean, updated_at timestamp )


[User] List the transaction IDs and gas used for transactions where gas used is greater than 500000.

[Assistant] SELECT transaction_id, gas_used FROM web3.transactions WHERE gas_used > 500000;

[User] Order the results by gas used in descending order.

[Assistant] SELECT transaction_id, gas_used FROM web3.transactions WHERE gas_used > 500000 ORDER BY gas_used DESC;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE web3.contracts ( contract_id character varying(64) NOT NULL, address character varying(128) NOT NULL, abi text NOT NULL, bytecode text NOT NULL, deployer_address character varying(128) NOT NULL, deployed_at timestamp NOT NULL, network_id character varying(64) NOT NULL, status character varying(32) NOT NULL, PRIMARY KEY (contract_id) )
CREATE TABLE web3.transactions ( transaction_id character varying(64) NOT NULL, from_address character varying(128) NOT NULL, to_address character varying(128), value numeric(38,14) NOT NULL, gas_used integer NOT NULL, gas_price numeric(38,14) NOT NULL, block_number integer NOT NULL, timestamp timestamp NOT NULL, input_data text, status character varying(32) NOT NULL, nonce integer NOT NULL, PRIMARY KEY (transaction_id) )
CREATE TABLE web3.users ( user_id text, username text, email text, password_hash text, created_at timestamp )


[User] Find all contracts where the deployer address is the same as the contract address, indicating self-deployed contracts.

[Assistant] SELECT address, deployer_address FROM web3.contracts WHERE address = deployer_address;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE web3.contracts ( contract_id text, address text, abi text, bytecode text, deployer_address text, deployed_at timestamp, network_id text, status text )


[User] For each trip, show the trip ID, scheduled departure, and the last name of the driver.

[Assistant]
SELECT t.trip_id, t.scheduled_departure, d.last_name
FROM transportation.trips t
JOIN transportation.drivers d ON t.driver_id = d.driver_id;

[User] I see some trip IDs are repeated. Only show distinct pairs of trip ID and driver last name.

[Assistant]
SELECT DISTINCT t.trip_id, d.last_name
FROM transportation.trips t
JOIN transportation.drivers d ON t.driver_id = d.driver_id;

[User] Also, for these trips, include the name of the destination location.

[Assistant]
SELECT DISTINCT t.trip_id, d.last_name, l.name AS destination_location_name
FROM transportation.trips t
JOIN transportation.drivers d ON t.driver_id = d.driver_id
JOIN transportation.locations l ON t.destination_location_id = l.location_id;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE transportation.drivers ( driver_id text PRIMARY KEY, employee_id text, first_name text, last_name text, license_number text, license_expiry_date date, contact_number text, email text, hire_date date, status text )
CREATE TABLE transportation.trips ( trip_id.text, route_id.text, vehicle_id.text, driver_id.text, scheduled_departure.timestamp, actual_departure.timestamp, scheduled_arrival.timestamp, actual_arrival.timestamp, origin_location_id.text, destination_location_id.text, status.text, passenger_count.integer, cargo_manifest_id.text )
CREATE TABLE transportation.locations ( location_id character varying(64) NOT NULL, name character varying(255) NOT NULL, type character varying(64) NOT NULL, address_line1 character varying(255), city character varying(128), state_province character varying(128), postal_code character varying(32), country character varying(64) NOT NULL, latitude numeric(9, 6), longitude numeric(9, 6), timezone character varying(64), PRIMARY KEY (location_id) )
CREATE TABLE transportation.passengers ( passenger_id text PRIMARY KEY, first_name text, last_name text, email text, phone_number text, date_of_birth date, loyalty_program_id text, created_at timestamp )
CREATE TABLE transportation.bookings ( booking_id.text, passenger_id.text, trip_id.text, seat_number.text, booking_time.timestamp, status.text, fare.numeric, payment_transaction_id.text, special_requests.text )


[User] List all pairs of tokens where the absolute difference in their decimals is exactly 2, showing both token_ids and their decimals.

[Assistant]
SELECT t1.token_id AS token_id1,
       t1.decimals AS decimals1,
       t2.token_id AS token_id2,
       t2.decimals AS decimals2
FROM web3.tokens t1
JOIN web3.tokens t2
  ON ABS(t1.decimals - t2.decimals) = 2
 AND t1.token_id < t2.token_id;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE web3.tokens ( token_id text PRIMARY KEY, contract_address text, token_name text, token_symbol text, decimals int, total_supply numeric )


[User] Show me all intercity routes that have an estimated duration of more than 2 hours, along with their origin and destination locations.

[Assistant] SELECT r.route_id, r.route_number, r.estimated_duration_minutes, lo.name AS origin_location, ld.name AS destination_location FROM transportation.routes r JOIN transportation.locations lo ON r.origin_location_id = lo.location_id JOIN transportation.locations ld ON r.destination_location_id = ld.location_id WHERE r.type = 'Intercity Train' AND r.estimated_duration_minutes > 120 ORDER BY r.estimated_duration_minutes DESC;

[User] Can you include the distance in kilometers and filter to only show routes longer than 100 km?

[Assistant] SELECT r.route_id, r.route_number, r.distance_km, r.estimated_duration_minutes, lo.name AS origin_location, ld.name AS destination_location FROM transportation.routes r JOIN transportation.locations lo ON r.origin_location_id = lo.location_id JOIN transportation.locations ld ON r.destination_location_id = ld.location_id WHERE r.type = 'Intercity Train' AND r.estimated_duration_minutes > 120 AND r.distance_km > 100 ORDER BY r.distance_km DESC;

[User] Now show me the average passenger count for trips on these routes in the last month.

[Assistant] SELECT r.route_id, r.route_number, AVG(t.passenger_count) AS average_passengers FROM transportation.routes r JOIN transportation.trips t ON r.route_id = t.route_id WHERE r.type = 'Intercity Train' AND r.estimated_duration_minutes > 120 AND r.distance_km > 100 AND t.actual_departure >= (CURRENT_DATE - INTERVAL '1 month') GROUP BY r.route_id, r.route_number ORDER BY average_passengers DESC;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE transportation.drivers ( driver_id character varying(64) NOT NULL, employee_id character varying(64) NOT NULL UNIQUE, first_name character varying(128) NOT NULL, last_name character varying(128) NOT NULL, license_number character varying(64) NOT NULL UNIQUE, license_expiry_date date NOT NULL, contact_number character varying(32), email character varying(128) UNIQUE, hire_date date NOT NULL, status character varying(32) NOT NULL, PRIMARY KEY (driver_id) )
CREATE TABLE transportation.routes (
    route_id character varying(64) NOT NULL,  -- unique identifier for the route
    route_number character varying(32) NOT NULL UNIQUE, -- public-facing route number/name
    description text, -- description of the route
    origin_location_id character varying(64) NOT NULL, -- identifier of the starting location
    destination_location_id character varying(64) NOT NULL, -- identifier of the ending location
    distance_km numeric(10, 2), -- estimated distance in kilometers
    estimated_duration_minutes integer, -- estimated travel time in minutes
    type character varying(32) NOT NULL, -- e.g., City Bus, Intercity Train, Cargo Delivery
    PRIMARY KEY (route_id)
)
CREATE TABLE transportation.trips ( trip_id character varying(64) NOT NULL, route_id character varying(64), vehicle_id character varying(64) NOT NULL, driver_id character varying(64) NOT NULL, scheduled_departure timestamp with time zone NOT NULL, actual_departure timestamp with time zone, scheduled_arrival timestamp with time zone NOT NULL, actual_arrival timestamp with time zone, origin_location_id character varying(64) NOT NULL, destination_location_id character varying(64) NOT NULL, status character varying(32) NOT NULL, passenger_count integer, cargo_manifest_id character varying(64), PRIMARY KEY (trip_id) )
CREATE TABLE transportation.locations ( location_id text, name text, type text, address_line1 text, city text, state_province text, postal_code text, country text, latitude numeric, longitude numeric, timezone text )
CREATE TABLE transportation.maintenance_logs (
    log_id character varying(64) NOT NULL,  -- unique identifier for the maintenance record
    vehicle_id character varying(64) NOT NULL, -- identifier of the vehicle serviced
    service_date date NOT NULL, -- date the service was performed
    odometer_reading integer, -- vehicle mileage at time of service
    service_type character varying(128) NOT NULL, -- type of service (e.g., Oil Change, Tire Rotation, Engine Repair)
    description text NOT NULL, -- detailed description of work done
    cost numeric(10, 2), -- cost of the service
    mechanic_name character varying(128), -- name or ID of the mechanic/shop
    next_service_due_date date, -- recommended date for next service
    PRIMARY KEY (log_id)
)
CREATE TABLE transportation.fuel_logs ( fuel_log_id.text, vehicle_id.text, trip_id.text, log_timestamp.timestamp, fuel_type.text, quantity.numeric, unit.text, cost_per_unit.numeric, total_cost.numeric, odometer_reading.integer, location_id.text )
CREATE TABLE transportation.passengers (
    passenger_id character varying(64) NOT NULL,  -- unique identifier for the passenger
    first_name character varying(128) NOT NULL, -- passenger's first name
    last_name character varying(128) NOT NULL, -- passenger's last name
    email character varying(128) UNIQUE, -- email address
    phone_number character varying(32) UNIQUE, -- phone number
    date_of_birth date, -- passenger's date of birth
    loyalty_program_id character varying(64), -- identifier for loyalty program membership
    created_at timestamp with time zone NOT NULL, -- time when the passenger record was created
    PRIMARY KEY (passenger_id)
)
CREATE TABLE transportation.bookings ( booking_id.text, passenger_id.text, trip_id.text, seat_number.text, booking_time.timestamp, status.text, fare.numeric, payment_transaction_id.text, special_requests.text )


[User] List all wallet addresses that have unspent UTXOs with amounts greater than 100, along with the total unspent amount for each address.

[Assistant] SELECT w.address, SUM(u.amount) AS total_unspent FROM trading_platform.wallets w JOIN trading_platform.utxos u ON w.address = u.address WHERE u.spent = false AND u.amount > 100 GROUP BY w.address;

[User] Now modify the query to only include wallets created in the last year.

[Assistant] SELECT w.address, SUM(u.amount) AS total_unspent FROM trading_platform.wallets w JOIN trading_platform.utxos u ON w.address = u.address WHERE u.spent = false AND u.amount > 100 AND w.created_at >= NOW() - INTERVAL '1 year' GROUP BY w.address;

[User] I notice the query has a typo in 'INTERVAL'. Also, can you include the user's email address in the results?

[Assistant] SELECT w.address, u.email, SUM(ut.amount) AS total_unspent FROM trading_platform.wallets w JOIN trading_platform.users u ON w.user_id = u.user_id JOIN trading_platform.utxos ut ON w.address = ut.address WHERE ut.spent = false AND ut.amount > 100 AND w.created_at >= NOW() - INTERVAL '1 year' GROUP BY w.address, u.email;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE trading_platform.users ( user_id text PRIMARY KEY, username text, email text, password_hash text, created_at timestamp )
CREATE TABLE trading_platform.wallets ( wallet_id text PRIMARY KEY, user_id text, address text, private_key text, created_at timestamp )
CREATE TABLE trading_platform.orders ( order_id text PRIMARY KEY, user_id text, wallet_id text, asset_id text, order_type text, quantity numeric, price numeric, status text, created_at timestamp )
CREATE TABLE trading_platform.trades ( trade_id text PRIMARY KEY, order_id text, buyer_id text, seller_id text, asset_id text, quantity numeric, price numeric, traded_at timestamp )
CREATE TABLE trading_platform.utxos ( utxo_id text PRIMARY KEY, transaction_id text, output_index int, address text, amount numeric, spent boolean )
CREATE TABLE trading_platform.dapps ( dapp_id text PRIMARY KEY, name text, description text, url text )
CREATE TABLE trading_platform.metadata ( metadata_id text PRIMARY KEY, asset_id text, key text, value text )
CREATE TABLE trading_platform.notifications ( notification_id text PRIMARY KEY, user_id text, message text, sent_at timestamp, read_at timestamp )


[User] List all wallets that were created during the hour of the day which saw the highest number of wallet creations. Show the wallet ID, user ID, address, and creation timestamp.

[Assistant]
WITH HourlyCounts AS (
    SELECT EXTRACT(HOUR FROM created_at) AS hour, COUNT(*) AS wallet_count
    FROM web3.wallets
    GROUP BY 1
),
MaxHour AS (
    SELECT hour
    FROM HourlyCounts
    ORDER BY wallet_count DESC
    LIMIT 1
)
SELECT wallet_id, user_id, address, created_at
FROM web3.wallets
WHERE EXTRACT(HOUR FROM created_at) = (SELECT hour FROM MaxHour);

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE web3.wallets ( wallet_id text PRIMARY KEY, user_id text, address text, private_key text, created_at timestamp )


[User] List usernames and the length of their 'bio' field for users whose 'is_verified' status is true.

[Assistant] SELECT username, LENGTH(bio) AS bio_length FROM social_media.users WHERE is_verified IS TRUE;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE social_media.users ( user_id text PRIMARY KEY, username text, email text, password_hash text, full_name text, profile_picture_url text, bio text, location text, created_at timestamp, updated_at timestamp, is_verified bool )


[User] Find all prescriptions for patients who have at least one appointment scheduled in the future. Show the prescription ID, patient ID, medication name, and the earliest future appointment time for that patient.

[Assistant] SELECT pr.prescription_id, pr.patient_id, m.medication_name, ( SELECT MIN(ap.appointment_time) FROM healthcare.appointments AS ap WHERE ap.patient_id = p.patient_id AND ap.appointment_time > CURRENT_TIMESTAMP ) AS earliest_future_appointment_time FROM healthcare.prescriptions AS pr JOIN healthcare.patients AS p ON pr.patient_id = p.patient_id JOIN healthcare.medications AS m ON pr.medication_id = m.medication_id WHERE p.patient_id IN ( SELECT patient_id FROM healthcare.appointments WHERE appointment_time > CURRENT_TIMESTAMP );

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE healthcare.doctors ( doctor_id text, first_name text, last_name text, specialty text, license_number text, phone_number text, email text, hospital_affiliation_id text, created_at timestamp, updated_at timestamp )
CREATE TABLE healthcare.appointments ( appointment_id.text, patient_id.text, doctor_id.text, appointment_time.timestamp, duration_minutes.integer, reason.text, status.text, location_id.text, notes.text, created_at.timestamp )
CREATE TABLE healthcare.diagnoses ( diagnosis_id text, record_id text, patient_id text, doctor_id text, diagnosis_code text, code_type text, description text, diagnosis_date date, status text, is_chronic boolean )
CREATE TABLE healthcare.medications (
    medication_id character varying(64) NOT NULL, -- unique identifier for the medication type
    medication_name character varying(255) NOT NULL, -- common or brand name
    generic_name character varying(255), -- generic chemical name
    manufacturer character varying(100), -- drug manufacturer
    ndc_code character varying(20) UNIQUE, -- National Drug Code (optional but useful)
    description text, -- description of the medication
    PRIMARY KEY (medication_id)
)
CREATE TABLE healthcare.prescriptions ( prescription_id text, record_id text, patient_id text, doctor_id text, medication_id text, dosage text, frequency text, route text, start_date date, end_date date, quantity_dispensed numeric, refills_allowed integer, prescription_date timestamp )
CREATE TABLE healthcare.insurance_plans ( plan_id text, plan_name text, insurance_provider text, plan_type text, contact_phone text, website text )
CREATE TABLE healthcare.patient_insurance ( patient_insurance_id text, patient_id text, plan_id text, policy_number text, group_number text, subscriber_name text, effective_date date, expiration_date date, is_primary boolean )


[User] Show me all active customers from California who were born before 1980, along with their contact information.

[Assistant] SELECT first_name, last_name, phone_number, email, address_line1, address_line2, city, state, zip_code FROM insurance.customers WHERE state = 'California' AND date_of_birth < '1980-01-01' AND status = 'Active';

[User] Now filter these results to only show customers who have provided both a phone number and an email address.

[Assistant] SELECT first_name, last_name, phone_number, email, address_line1, address_line2, city, state, zip_code FROM insurance.customers WHERE state = 'California' AND date_of_birth < '1980-01-01' AND status = 'Active' AND phone_number IS NOT NULL AND email IS NOT NULL;

[User] I also want to see how long these customers have been in our system (difference between current date and created_at in years).

[Assistant] SELECT first_name, last_name, phone_number, email, address_line1, address_line2, city, state, zip_code, EXTRACT(YEAR FROM AGE(CURRENT_DATE, created_at)) AS years_in_system FROM insurance.customers WHERE state = 'California' AND date_of_birth < '1980-01-01' AND status = 'Active' AND phone_number IS NOT NULL AND email IS NOT NULL;

[User] Finally, order the results by the longest tenure in our system first, then by last name alphabetically.

[Assistant] SELECT first_name, last_name, phone_number, email, address_line1, address_line2, city, state, zip_code, EXTRACT(YEAR FROM AGE(CURRENT_DATE, created_at)) AS years_in_system FROM insurance.customers WHERE state = 'California' AND date_of_birth < '1980-01-01' AND status = 'Active' AND phone_number IS NOT NULL AND email IS NOT NULL ORDER BY years_in_system DESC, last_name ASC;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE insurance.customers (
    customer_id character varying(64) NOT NULL,  -- unique identifier for the customer
    first_name character varying(100) NOT NULL, -- customer's first name
    last_name character varying(100) NOT NULL, -- customer's last name
    date_of_birth date NOT NULL, -- customer's date of birth
    ssn_hash character varying(128), -- Hashed social security number (or national ID)
    address_line1 character varying(255) NOT NULL,
    address_line2 character varying(255),
    city character varying(100) NOT NULL,
    state character varying(50) NOT NULL,
    zip_code character varying(20) NOT NULL,
    country character varying(50) NOT NULL DEFAULT 'USA',
    phone_number character varying(30),
    email character varying(128) UNIQUE, -- unique email address
    created_at timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, -- when the customer record was created
    updated_at timestamp, -- when the customer record was last updated
    status character varying(20) NOT NULL DEFAULT 'Active', -- e.g., Active, Inactive, Prospect
    PRIMARY KEY (customer_id)
)


[User] List all medical record IDs and the record date for records created by doctors specializing in 'Gastroenterology'.

[Assistant] SELECT mr.record_id, mr.record_date FROM healthcare.medical_records mr JOIN healthcare.doctors d ON mr.doctor_id = d.doctor_id WHERE d.specialty = 'Gastroenterology';

[User] Could you also include the patient's first and last name for these records?

[Assistant] SELECT mr.record_id, mr.record_date, p.first_name, p.last_name FROM healthcare.medical_records mr JOIN healthcare.doctors d ON mr.doctor_id = d.doctor_id JOIN healthcare.patients p ON mr.patient_id = p.patient_id WHERE d.specialty = 'Gastroenterology';

[User] Now, only show records for male patients.

[Assistant] SELECT mr.record_id, mr.record_date, p.first_name, p.last_name FROM healthcare.medical_records mr JOIN healthcare.doctors d ON mr.doctor_id = d.doctor_id JOIN healthcare.patients p ON mr.patient_id = p.patient_id WHERE d.specialty = 'Gastroenterology' AND p.gender = 'Male';

[User] Additionally, restrict the results to medical records that have at least one associated diagnosis with status 'Resolved'.

[Assistant] SELECT DISTINCT mr.record_id, mr.record_date, p.first_name, p.last_name FROM healthcare.medical_records mr JOIN healthcare.doctors d ON mr.doctor_id = d.doctor_id JOIN healthcare.patients p ON mr.patient_id = p.patient_id JOIN healthcare.diagnoses diag ON mr.record_id = diag.record_id WHERE d.specialty = 'Gastroenterology' AND p.gender = 'Male' AND diag.status = 'Resolved';

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE healthcare.patients ( patient_id text, first_name text, last_name text, date_of_birth date, gender text, address text, phone_number text, email text, emergency_contact_name text, emergency_contact_phone text, created_at timestamp, updated_at timestamp )
CREATE TABLE healthcare.doctors ( doctor_id text, first_name text, last_name text, specialty text, license_number text, phone_number text, email text, hospital_affiliation_id text, created_at timestamp, updated_at timestamp )
CREATE TABLE healthcare.medical_records ( record_id character varying(64) NOT NULL, patient_id character varying(64) NOT NULL, appointment_id character varying(64) UNIQUE, doctor_id character varying(64) NOT NULL, record_date timestamp with time zone NOT NULL, chief_complaint text, present_illness_history text, past_medical_history text, physical_examination_notes text, assessment text, treatment_plan text, vitals jsonb, created_at timestamp with time zone NOT NULL DEFAULT current_timestamp, PRIMARY KEY (record_id) )
CREATE TABLE healthcare.diagnoses ( diagnosis_id text PRIMARY KEY, record_id text, patient_id text, doctor_id text, diagnosis_code text, code_type text, description text, diagnosis_date date, status text, is_chronic boolean )
CREATE TABLE healthcare.prescriptions ( prescription_id character varying(64) NOT NULL, record_id character varying(64) NOT NULL, patient_id character varying(64) NOT NULL, doctor_id character varying(64) NOT NULL, medication_id character varying(64) NOT NULL, dosage character varying(100) NOT NULL, frequency character varying(100) NOT NULL, route character varying(50), start_date date NOT NULL, end_date date, quantity_dispensed numeric(10,2), refills_allowed integer NOT NULL DEFAULT 0, prescription_date timestamp with time zone NOT NULL DEFAULT current_timestamp, PRIMARY KEY (prescription_id) )
CREATE TABLE healthcare.insurance_plans ( plan_id character varying(64) NOT NULL, plan_name character varying(200) NOT NULL, insurance_provider character varying(100) NOT NULL, plan_type character varying(50), contact_phone character varying(20), website character varying(255), PRIMARY KEY (plan_id) )
CREATE TABLE healthcare.patient_insurance (
    patient_insurance_id character varying(64) NOT NULL, -- unique identifier for this patient-plan link
    patient_id character varying(64) NOT NULL, -- FK to patients table
    plan_id character varying(64) NOT NULL, -- FK to insurance_plans table
    policy_number character varying(100) NOT NULL, -- patient's policy number
    group_number character varying(100), -- group number, if applicable
    subscriber_name character varying(200), -- name of the primary policy holder
    effective_date date NOT NULL, -- date the coverage begins
    expiration_date date, -- date the coverage ends (if known)
    is_primary boolean NOT NULL DEFAULT true, -- indicates if this is the primary insurance
    PRIMARY KEY (patient_insurance_id),
    UNIQUE (patient_id, plan_id, policy_number) -- ensure a patient doesn't have the same policy twice
)


[User] How many unique tokens are recorded for each chain in the latest snapshot in cex_token_balance?

[Assistant]
WITH latest_snapshot AS (
  SELECT MAX(snapshot_time) AS max_time FROM cex_token_balance
)
SELECT
  chain,
  COUNT(DISTINCT token_symbol) AS unique_token_count
FROM cex_token_balance c
JOIN latest_snapshot l ON c.snapshot_time = l.max_time
GROUP BY chain
ORDER BY unique_token_count DESC;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE cex_token_balance ( snapshot_time.text, chain.text, address.text, exchange.text, token_address.text, token_symbol.text, balance.numeric, usd_value.numeric, price.numeric )


[User] Show me all pairs of cases led by the same lawyer, including both case names and the lead lawyer ID.

[Assistant]
SELECT c1.lead_lawyer_id,
       c1.case_name AS case_name_1,
       c2.case_name AS case_name_2
FROM legal_services.cases c1
JOIN legal_services.cases c2
  ON c1.lead_lawyer_id = c2.lead_lawyer_id
  AND c1.case_id < c2.case_id;

[User] Actually, only include pairs where the case types are also the same.

[Assistant]
SELECT c1.lead_lawyer_id,
       c1.case_name AS case_name_1,
       c2.case_name AS case_name_2
FROM legal_services.cases c1
JOIN legal_services.cases c2
  ON c1.lead_lawyer_id = c2.lead_lawyer_id
  AND c1.case_type = c2.case_type
  AND c1.case_id < c2.case_id;

[User] Also, show me the earliest opening date between the two cases for each pair.

[Assistant]
SELECT c1.lead_lawyer_id,
       c1.case_name AS case_name_1,
       c2.case_name AS case_name_2,
       LEAST(c1.date_opened, c2.date_opened) AS earliest_open_date
FROM legal_services.cases c1
JOIN legal_services.cases c2
  ON c1.lead_lawyer_id = c2.lead_lawyer_id
  AND c1.case_type = c2.case_type
  AND c1.case_id < c2.case_id;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE legal_services.cases ( case_id text, case_number text, case_name text, client_id text, lead_lawyer_id text, case_type text, status text, date_opened timestamp, date_closed timestamp, description text, court_jurisdiction text )