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205,583 | help-1 | 7e866702f9414552bd66fd2437414f97 | 706,934,233,012,371,600 | Ansh_ | 01/22/2022 12:54:44 | $3x + 1 - a < 0$ | 0 | 1 | null | null | null | null | null | |||||
205,583 | help-1 | 7e866702f9414552bd66fd2437414f97 | 510,789,298,321,096,700 | TeXit | 01/22/2022 12:54:46 | **Ansh** | 706934233012371577.png | 0 | 1 | 145,653,848,122,327,040 | mrbrown | 1564 | mrbrown | false | ||||
205,583 | help-1 | 7e866702f9414552bd66fd2437414f97 | 706,934,233,012,371,600 | Ansh_ | 01/22/2022 12:55:34 | so $x\geq \frac{1}{3}$ and $a > 3x+1 \geq 3\cdot \frac{1}{3} + 1 =2$ | 0 | 1 | null | null | null | null | null | |||||
205,583 | help-1 | 7e866702f9414552bd66fd2437414f97 | 510,789,298,321,096,700 | TeXit | 01/22/2022 12:55:36 | **Ansh** | 706934233012371577.png | 0 | 1 | null | null | null | null | null | ||||
205,583 | help-1 | 7e866702f9414552bd66fd2437414f97 | 706,934,233,012,371,600 | Ansh_ | 01/22/2022 12:56:12 | So, since both the inequalities are satisfied, you get $x\geq \frac{1}{3}$ is acceptible | 0 | 1 | null | null | null | null | null | |||||
205,583 | help-1 | 7e866702f9414552bd66fd2437414f97 | 510,789,298,321,096,700 | TeXit | 01/22/2022 12:56:15 | **Ansh** | 706934233012371577.png | 0 | 1 | null | null | null | null | null | ||||
205,583 | help-1 | 7e866702f9414552bd66fd2437414f97 | 421,006,765,572,882,500 | LoLer | 01/22/2022 12:56:22 | Yep | 1 | 0 | null | null | null | null | null | |||||
205,583 | help-1 | 7e866702f9414552bd66fd2437414f97 | 421,006,765,572,882,500 | LoLer | 01/22/2022 12:56:37 | Ah okay so you substitute and do it | 1 | 0 | null | null | null | null | null | |||||
205,583 | help-1 | 7e866702f9414552bd66fd2437414f97 | 421,006,765,572,882,500 | LoLer | 01/22/2022 12:57:59 | Hmm so this is acceptible | 1 | 0 | null | null | null | null | null | |||||
205,583 | help-1 | 7e866702f9414552bd66fd2437414f97 | 421,006,765,572,882,500 | LoLer | 01/22/2022 12:58:02 | In the other case | 1 | 0 | null | null | null | null | null | |||||
205,583 | help-1 | 7e866702f9414552bd66fd2437414f97 | 421,006,765,572,882,500 | LoLer | 01/22/2022 12:58:29 | We get (a-1)/3< x<=1/3 | 1 | 0 | null | null | null | null | null | |||||
205,583 | help-1 | 7e866702f9414552bd66fd2437414f97 | 421,006,765,572,882,500 | LoLer | 01/22/2022 12:58:44 | So here we get x<=1/3 | 1 | 0 | null | null | null | null | null | |||||
205,583 | help-1 | 7e866702f9414552bd66fd2437414f97 | 421,006,765,572,882,500 | LoLer | 01/22/2022 12:58:52 | So when we combine x belongs to r? | 1 | 0 | null | null | null | null | null | |||||
205,583 | help-1 | 7e866702f9414552bd66fd2437414f97 | 421,006,765,572,882,500 | LoLer | 01/22/2022 13:00:46 | Right @Ansh_ ? | 1 | 0 | null | null | null | null | null | |||||
205,583 | help-1 | 7e866702f9414552bd66fd2437414f97 | 421,006,765,572,882,500 | LoLer | 01/22/2022 13:00:50 | Sorry for the ping | 1 | 0 | null | null | null | null | null | |||||
205,583 | help-1 | 7e866702f9414552bd66fd2437414f97 | 706,934,233,012,371,600 | Ansh_ | 01/22/2022 13:04:56 | Umm | 0 | 1 | null | null | null | null | null | |||||
205,583 | help-1 | 7e866702f9414552bd66fd2437414f97 | 706,934,233,012,371,600 | Ansh_ | 01/22/2022 13:06:44 | Actually.. you need to mention that the range of values *acceptable for "x" is dependent on the range of values "a" is picked up from | 0 | 1 | null | null | null | null | null | |||||
205,583 | help-1 | 7e866702f9414552bd66fd2437414f97 | 421,006,765,572,882,500 | LoLer | 01/22/2022 13:08:22 | So like I need to mention if a>2 then x can take thi value and a<2 can take that | 1 | 0 | null | null | null | null | null | |||||
205,583 | help-1 | 7e866702f9414552bd66fd2437414f97 | 706,934,233,012,371,600 | Ansh_ | 01/22/2022 13:08:39 | Yeah | 0 | 1 | null | null | null | null | null | |||||
205,583 | help-1 | 7e866702f9414552bd66fd2437414f97 | 421,006,765,572,882,500 | LoLer | 01/22/2022 13:13:30 | Thanks | 1 | 0 | null | null | null | null | null | |||||
205,583 | help-1 | 7e866702f9414552bd66fd2437414f97 | 421,006,765,572,882,500 | LoLer | 01/22/2022 13:13:33 | .close | 1 | 0 | null | null | null | null | null | |||||
205,584 | help-1 | 4284051489d44287861c781a4593e5e6 | 757,643,251,460,210,800 | Mr Carrot Man | 01/22/2022 13:17:00 | please can someone help explain what I'm meant to be doing here? | unknown.png | 1 | 0 | null | null | null | null | null | ||||
205,584 | help-1 | 4284051489d44287861c781a4593e5e6 | 551,269,104,800,104,450 | EndTimes | 01/22/2022 13:37:55 | Multiply the factors together | 0 | 1 | null | null | null | null | null | |||||
205,584 | help-1 | 4284051489d44287861c781a4593e5e6 | 551,269,104,800,104,450 | EndTimes | 01/22/2022 13:37:58 | Lol | 0 | 1 | null | null | null | null | null | |||||
205,585 | help-1 | 2438a0ffb348411d86544380ac34ead1 | 321,074,029,291,372,540 | Jason_Bjorn | 01/22/2022 13:54:25 | if `A` is 4x3 matrix and `det(A) = 8` then how do I find `det(7A)`? is it `7^rows` or `7^cols` ? | 1 | 0 | 637,070,886,561,775,600 | doofy | 7804 | doofy | false | |||||
205,585 | help-1 | 2438a0ffb348411d86544380ac34ead1 | 321,074,029,291,372,540 | Jason_Bjorn | 01/22/2022 13:55:00 | Or does that trick only work on square matrices? | 1 | 0 | null | null | null | null | null | |||||
205,585 | help-1 | 2438a0ffb348411d86544380ac34ead1 | 244,129,917,732,651,000 | Deus_Vult | 01/22/2022 13:58:33 | How exactly is the determinant of non square matrices defined.. ? | 0 | 1 | null | null | null | null | null | |||||
205,585 | help-1 | 2438a0ffb348411d86544380ac34ead1 | 420,244,167,726,333,950 | kirby your mom | 01/22/2022 13:59:26 | The determinant can only be found for a square matrix right? | 0 | 1 | null | null | null | null | null | |||||
205,585 | help-1 | 2438a0ffb348411d86544380ac34ead1 | 321,074,029,291,372,540 | Jason_Bjorn | 01/22/2022 14:02:00 | huh | 1 | 0 | null | null | null | null | null | |||||
205,585 | help-1 | 2438a0ffb348411d86544380ac34ead1 | 321,074,029,291,372,540 | Jason_Bjorn | 01/22/2022 14:02:03 | good to know | 1 | 0 | null | null | null | null | null | |||||
205,585 | help-1 | 2438a0ffb348411d86544380ac34ead1 | 321,074,029,291,372,540 | Jason_Bjorn | 01/22/2022 14:02:52 | thank you | 1 | 0 | null | null | null | null | null | |||||
205,585 | help-1 | 2438a0ffb348411d86544380ac34ead1 | 244,129,917,732,651,000 | Deus_Vult | 01/22/2022 14:02:52 | is this an exercise? | 0 | 1 | null | null | null | null | null | |||||
205,585 | help-1 | 2438a0ffb348411d86544380ac34ead1 | 244,129,917,732,651,000 | Deus_Vult | 01/22/2022 14:03:01 | or your own question | 0 | 1 | 510,789,298,321,096,700 | TeXit | 0796 | TeXit | true | |||||
205,585 | help-1 | 2438a0ffb348411d86544380ac34ead1 | 321,074,029,291,372,540 | Jason_Bjorn | 01/22/2022 14:03:12 | both-ish | 1 | 0 | null | null | null | null | null | |||||
205,585 | help-1 | 2438a0ffb348411d86544380ac34ead1 | 244,129,917,732,651,000 | Deus_Vult | 01/22/2022 14:03:13 | because it's weird unless they were trying to trick you | 0 | 1 | null | null | null | null | null | |||||
205,585 | help-1 | 2438a0ffb348411d86544380ac34ead1 | 244,129,917,732,651,000 | Deus_Vult | 01/22/2022 14:03:22 | what is the exercise | 0 | 1 | 637,070,886,561,775,600 | doofy | 7804 | doofy | false | |||||
205,585 | help-1 | 2438a0ffb348411d86544380ac34ead1 | 321,074,029,291,372,540 | Jason_Bjorn | 01/22/2022 14:03:40 | I was wondering why we were only finding the determinant of square matrices | 1 | 0 | null | null | null | null | null | |||||
205,585 | help-1 | 2438a0ffb348411d86544380ac34ead1 | 321,074,029,291,372,540 | Jason_Bjorn | 01/22/2022 14:04:01 | b/c that trick never said to use row or cols | 1 | 0 | null | null | null | null | null | |||||
205,585 | help-1 | 2438a0ffb348411d86544380ac34ead1 | 321,074,029,291,372,540 | Jason_Bjorn | 01/22/2022 14:04:10 | but I get it now | 1 | 0 | null | null | null | null | null | |||||
205,585 | help-1 | 2438a0ffb348411d86544380ac34ead1 | 321,074,029,291,372,540 | Jason_Bjorn | 01/22/2022 14:05:38 | why is `x` sometimes bolded? | 1 | 0 | null | null | null | null | null | |||||
205,585 | help-1 | 2438a0ffb348411d86544380ac34ead1 | 321,074,029,291,372,540 | Jason_Bjorn | 01/22/2022 14:05:46 | to say is a vector? | 1 | 0 | null | null | null | null | null | |||||
205,585 | help-1 | 2438a0ffb348411d86544380ac34ead1 | 321,074,029,291,372,540 | Jason_Bjorn | 01/22/2022 14:05:50 | and not cross product? | 1 | 0 | null | null | null | null | null | |||||
205,585 | help-1 | 2438a0ffb348411d86544380ac34ead1 | 244,129,917,732,651,000 | Deus_Vult | 01/22/2022 14:06:06 | It's because the determinant is a recursive function _defined_ for square matrices | 0 | 1 | null | null | null | null | null | |||||
205,585 | help-1 | 2438a0ffb348411d86544380ac34ead1 | 244,129,917,732,651,000 | Deus_Vult | 01/22/2022 14:06:43 | which x ? in what operation? | 0 | 1 | null | null | null | null | null | |||||
205,585 | help-1 | 2438a0ffb348411d86544380ac34ead1 | 321,074,029,291,372,540 | Jason_Bjorn | 01/22/2022 14:06:54 | like `Ax = b` | 1 | 0 | null | null | null | null | null | |||||
205,585 | help-1 | 2438a0ffb348411d86544380ac34ead1 | 321,074,029,291,372,540 | Jason_Bjorn | 01/22/2022 14:07:06 | x would be bold | 1 | 0 | null | null | null | null | null | |||||
205,585 | help-1 | 2438a0ffb348411d86544380ac34ead1 | 244,129,917,732,651,000 | Deus_Vult | 01/22/2022 14:09:44 | oh
maybe to denote that it's indeed a vector | 0 | 1 | null | null | null | null | null | |||||
205,585 | help-1 | 2438a0ffb348411d86544380ac34ead1 | 244,129,917,732,651,000 | Deus_Vult | 01/22/2022 14:10:06 | Ax=b is simply a linear map. | 0 | 1 | null | null | null | null | null | |||||
205,585 | help-1 | 2438a0ffb348411d86544380ac34ead1 | 321,074,029,291,372,540 | Jason_Bjorn | 01/22/2022 14:10:19 | not sure what you are saying but ok | 1 | 0 | null | null | null | null | null | |||||
205,585 | help-1 | 2438a0ffb348411d86544380ac34ead1 | 321,074,029,291,372,540 | Jason_Bjorn | 01/22/2022 14:10:29 | haven't heard `linear map` yet | 1 | 0 | null | null | null | null | null | |||||
205,585 | help-1 | 2438a0ffb348411d86544380ac34ead1 | 244,129,917,732,651,000 | Deus_Vult | 01/22/2022 14:16:09 | its a system of equation | 0 | 1 | null | null | null | null | null | |||||
205,585 | help-1 | 2438a0ffb348411d86544380ac34ead1 | 244,129,917,732,651,000 | Deus_Vult | 01/22/2022 14:16:26 | but essentialy yea x is a vector and Ax is a multiplication of matrix A and vector x. | 0 | 1 | 312,559,012,346,331,140 | xdk1235 | 7777 | xdk1235 | false | |||||
205,585 | help-1 | 2438a0ffb348411d86544380ac34ead1 | 321,074,029,291,372,540 | Jason_Bjorn | 01/22/2022 14:19:18 | thank you @Deus_Vult | 1 | 0 | null | null | null | null | null | |||||
205,585 | help-1 | 2438a0ffb348411d86544380ac34ead1 | 244,129,917,732,651,000 | Deus_Vult | 01/22/2022 14:20:16 | Np :PES_Happy: | 0 | 1 | null | null | null | null | null | |||||
205,585 | help-1 | 2438a0ffb348411d86544380ac34ead1 | 321,074,029,291,372,540 | Jason_Bjorn | 01/22/2022 14:20:24 | .close | 1 | 0 | null | null | null | null | null | |||||
205,586 | help-1 | e8b2a340dd154da2b01023791512ca06 | 295,163,226,134,675,460 | thehackpod | 01/22/2022 15:14:41 | Hi guys, I have this function and the exercise asks to determine the incremental ratio of it in [0, e - 1] | 1 | 0 | null | null | null | null | null | |||||
205,586 | help-1 | e8b2a340dd154da2b01023791512ca06 | 295,163,226,134,675,460 | thehackpod | 01/22/2022 15:14:47 | Screenshot_20220122-211332_Gallery.jpg | 1 | 0 | null | null | null | null | null | |||||
205,586 | help-1 | e8b2a340dd154da2b01023791512ca06 | 295,163,226,134,675,460 | thehackpod | 01/22/2022 15:15:27 | What do I have to do exactly? I'm used to exercise that ask for example to calculate the incremental ratio on a certain value, for example 1. What does this interval mean? | 1 | 0 | null | null | null | null | null | |||||
205,586 | help-1 | e8b2a340dd154da2b01023791512ca06 | 295,163,226,134,675,460 | thehackpod | 01/22/2022 15:16:03 | I don't know what to subsitutite in (f(x0+h) - f(x0))/h | 1 | 0 | null | null | null | null | null | |||||
205,586 | help-1 | e8b2a340dd154da2b01023791512ca06 | 295,163,226,134,675,460 | thehackpod | 01/22/2022 15:16:22 | For h that tends to 0 | 1 | 0 | null | null | null | null | null | |||||
205,586 | help-1 | e8b2a340dd154da2b01023791512ca06 | 295,163,226,134,675,460 | thehackpod | 01/22/2022 15:27:51 | Guys please, I think the exercise is pretty easy itself, it's just that I don't know where to start from. I know the formula for h that tends to 0 of the increemntal ratio. I also know the one for x that tends to the value x0 | 1 | 0 | null | null | null | null | null | |||||
205,586 | help-1 | e8b2a340dd154da2b01023791512ca06 | 295,163,226,134,675,460 | thehackpod | 01/22/2022 15:28:07 | But I've never done it with intervals... | 1 | 0 | null | null | null | null | null | |||||
205,586 | help-1 | e8b2a340dd154da2b01023791512ca06 | 295,163,226,134,675,460 | thehackpod | 01/22/2022 15:39:40 | .close | 1 | 0 | null | null | null | null | null | |||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 308,021,623,905,058,800 | Jaw-Ahm | 12/21/2021 17:10:59 | Find solution to the following equations with unknown variables $w, x, y, z$ and constants $c_{i}$. | 1 | 0 | null | null | null | null | null | |||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 510,789,298,321,096,700 | TeXit | 12/21/2021 17:11:15 | **Jaw-Ahm** | 308021623905058817.png | 0 | 1 | null | null | null | null | null | ||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 308,021,623,905,058,800 | Jaw-Ahm | 12/21/2021 17:11:17 | $c_{1} = x^{w}$ \\
$c_{2} = x^{z}$ \\
$c_{3} = y^{w}$ \\
$c_{4} = y^{z}$ | 1 | 0 | null | null | null | null | null | |||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 510,789,298,321,096,700 | TeXit | 12/21/2021 17:11:20 | **Jaw-Ahm** | 308021623905058817.png | 0 | 1 | null | null | null | null | null | ||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 308,021,623,905,058,800 | Jaw-Ahm | 12/21/2021 17:11:48 | I have been working on this, and have had some help from this discord, but I am a bit stuck and would appreciate some guidance, I will post some steps I have taken | 1 | 0 | null | null | null | null | null | |||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 308,021,623,905,058,800 | Jaw-Ahm | 12/21/2021 17:11:59 | Using the rules of logarithmson the RHS, the exponents $r$ on each log $m$ is equivilant to $r$ multiplied by log $m$. We then divide both sides by $r$. | 1 | 0 | null | null | null | null | null | |||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 510,789,298,321,096,700 | TeXit | 12/21/2021 17:12:02 | **Jaw-Ahm** | 308021623905058817.png | 0 | 1 | null | null | null | null | null | ||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 308,021,623,905,058,800 | Jaw-Ahm | 12/21/2021 17:12:20 | 1. $$\frac{\ln(c_{1})}{w} = \ln(x)$$ \\
2. $$\frac{\ln(c_{2})}{z} = \ln(x)$$ \\
3. $$\frac{\ln(c_{3})}{w} = \ln(y)$$ \\
4. $$\frac{\ln(c_{4})}{w} = \ln(y)$$ | 1 | 0 | null | null | null | null | null | |||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 510,789,298,321,096,700 | TeXit | 12/21/2021 17:12:25 | **Jaw-Ahm** | 308021623905058817.png | 0 | 1 | null | null | null | null | null | ||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 308,021,623,905,058,800 | Jaw-Ahm | 12/21/2021 17:12:34 | LHS of equations 1 and 2 can be equated to each other, due to their RHS being equal. The same for equations 3 and 4. | 1 | 0 | null | null | null | null | null | |||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 308,021,623,905,058,800 | Jaw-Ahm | 12/21/2021 17:12:43 | 5. $$\frac{\ln(c_{1})}{w} = \frac{\ln(c_{2})}{z}$$ \\
6. $$\frac{\ln(c_{3})}{w} = \frac{\ln(c_{4})}{z}$$ | 1 | 0 | null | null | null | null | null | |||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 510,789,298,321,096,700 | TeXit | 12/21/2021 17:12:46 | **Jaw-Ahm** | 308021623905058817.png | 0 | 1 | null | null | null | null | null | ||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 308,021,623,905,058,800 | Jaw-Ahm | 12/21/2021 17:12:59 | As $c_{i}$ are constants, we can make the substitutions, where $a, b, c,$ and $d$ are constants: | 1 | 0 | null | null | null | null | null | |||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 510,789,298,321,096,700 | TeXit | 12/21/2021 17:13:01 | **Jaw-Ahm** | 308021623905058817.png | 0 | 1 | null | null | null | null | null | ||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 308,021,623,905,058,800 | Jaw-Ahm | 12/21/2021 17:13:03 | $\ln(c_{1}) = a$ \\
$\ln(c_{2}) = b$ \\
$\ln(c_{3}) = c$ \\
$\ln(c_{4}) = d$ | 1 | 0 | null | null | null | null | null | |||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 510,789,298,321,096,700 | TeXit | 12/21/2021 17:13:24 | **Jaw-Ahm** | 308021623905058817.png | 0 | 1 | null | null | null | null | null | ||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 308,021,623,905,058,800 | Jaw-Ahm | 12/21/2021 17:14:15 | Which results in our equations looking like: | 1 | 0 | null | null | null | null | null | |||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 308,021,623,905,058,800 | Jaw-Ahm | 12/21/2021 17:14:25 | 5. $$\frac{a}{w} = \frac{b}{z}$$ \\
6. $$\frac{c}{w} = \frac{d}{z}$$ | 1 | 0 | null | null | null | null | null | |||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 510,789,298,321,096,700 | TeXit | 12/21/2021 17:14:28 | **Jaw-Ahm** | 308021623905058817.png | 0 | 1 | null | null | null | null | null | ||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 308,021,623,905,058,800 | Jaw-Ahm | 12/21/2021 17:14:47 | Now here is where I am stuck, I am just not sure how I can express the original variables, in terms of the constants | 1 | 0 | null | null | null | null | null | |||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 308,021,623,905,058,800 | Jaw-Ahm | 12/21/2021 17:26:19 | We can now express these as two linear equations: | 1 | 0 | 469,185,954,658,123,800 | Mugiwara No Ligma | 1540 | Mugiwara No Ligma | false | |||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 308,021,623,905,058,800 | Jaw-Ahm | 12/21/2021 17:26:29 | 7. $$z = \frac{b}{w}w$$ \\
8. $$z = \frac{d}{c}w$$ | 1 | 0 | null | null | null | null | null | |||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 510,789,298,321,096,700 | TeXit | 12/21/2021 17:27:44 | **Jaw-Ahm** | 308021623905058817.png | 0 | 1 | null | null | null | null | null | ||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 308,021,623,905,058,800 | Jaw-Ahm | 12/21/2021 17:27:56 | This provides us with infinite solutions, so we can set a constraint such that: | 1 | 0 | null | null | null | null | null | |||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 308,021,623,905,058,800 | Jaw-Ahm | 12/21/2021 17:29:11 | $$\frac{b}{a} \neq \frac{d}{c}$$ | 1 | 0 | null | null | null | null | null | |||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 510,789,298,321,096,700 | TeXit | 12/21/2021 17:29:14 | **Jaw-Ahm** | 308021623905058817.png | 0 | 1 | null | null | null | null | null | ||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 308,021,623,905,058,800 | Jaw-Ahm | 12/21/2021 17:30:07 | This allows us to arive at a unique solution where | 1 | 0 | null | null | null | null | null | |||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 308,021,623,905,058,800 | Jaw-Ahm | 12/21/2021 17:30:12 | $z = w = 0$ | 1 | 0 | null | null | null | null | null | |||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 510,789,298,321,096,700 | TeXit | 12/21/2021 17:30:15 | **Jaw-Ahm** | 308021623905058817.png | 0 | 1 | null | null | null | null | null | ||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 308,021,623,905,058,800 | Jaw-Ahm | 12/21/2021 17:31:20 | Plugging in these to the original equations we get that the solution to $y$ and $x$ are part of an infinite set. | 1 | 0 | null | null | null | null | null | |||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 510,789,298,321,096,700 | TeXit | 12/21/2021 17:31:22 | **Jaw-Ahm** | 308021623905058817.png | 0 | 1 | null | null | null | null | null | ||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 308,021,623,905,058,800 | Jaw-Ahm | 12/21/2021 18:33:25 | Right now it would be good if someone could look this over, and judge correctness and perhaps share alternate routes to arrive to a better sollution | 1 | 0 | null | null | null | null | null | |||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 691,679,326,164,222,100 | Euclid31415 | 12/21/2021 19:02:08 | Won't taking z=w=0 assume that the constants c_{i} are all =1. I thought you were supposed to solve for x,y,z,w in terms of c_{i} | 0 | 1 | null | null | null | null | null | |||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 308,021,623,905,058,800 | Jaw-Ahm | 12/21/2021 19:02:37 | Yes this is what I am thinking too. I just wanted to show the best I have come up with | 1 | 0 | null | null | null | null | null | |||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 308,021,623,905,058,800 | Jaw-Ahm | 12/21/2021 19:02:57 | I can't find a way to express w, x, y and z in terms of c_i | 1 | 0 | null | null | null | null | null | |||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 485,820,733,537,386,500 | Brun。 | 12/21/2021 19:08:47 | if you skip this step you get that $c_4=c_3^{log_{c_2}c_1}$ | 0 | 1 | null | null | null | null | null | |||||
205,587 | help-1 | 879ef6f67d6a40a98174b7e1e8eae50c | 510,789,298,321,096,700 | TeXit | 12/21/2021 19:08:50 | **Brun。** | 485820733537386526.png | 0 | 1 | null | null | null | null | null |
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