context listlengths 1 1 | gen_kwargs dict | repeat_idx int64 0 9 | request_idx int64 0 514 | task_name stringclasses 8
values | metadata dict | model_outputs stringlengths 1 195k |
|---|---|---|---|---|---|---|
[
{
"content": "Problem: Among the 900 residents of Aimeville, there are 195 who own a diamond ring, 367 who own a set of golf clubs, and 562 who own a garden spade. In addition, each of the 900 residents owns a bag of candy hearts. There are 437 residents who own exactly two of these things, and 234 residents wh... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 0 | AIME24 | {
"expected_answer": "73",
"problem_id": "aime24-0",
"reference_solution": "Let $w,x,y,z$ denote the number of residents who own 1,2,3 and 4 of these items, respectively. We know $w+x+y+z=900$ , since there are 900 residents in total. This simplifies to $w+z=229$ , since we know $x=437$ and $y=234$ . Now, w... | To solve this problem, we will use the principle of inclusion-exclusion. Let's denote the four sets as follows:
- \( D \): residents who own a diamond ring,
- \( G \): residents who own golf clubs,
- \( S \): residents who own a garden spade,
- \( C \): residents who own a bag of candy hearts (which everyone owns, so i... |
[
{
"content": "Problem: A list of positive integers has the following properties: $\\bullet$ The sum of the items in the list is $30$ . $\\bullet$ The unique mode of the list is $9$ . $\\bullet$ The median of the list is a positive integer that does not appear in the list itself. Find the sum of the squares... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 1 | AIME24 | {
"expected_answer": "236",
"problem_id": "aime24-1",
"reference_solution": "The third condition implies that the list's size must be an even number, as if it were an odd number, the median of the list would surely appear in the list itself. Therefore, we can casework on what even numbers work. Say the size is 2.... | To solve the problem, we need to find a list of positive integers that satisfies three conditions:
1. The sum of the items is 30.
2. The unique mode is 9.
3. The median is a positive integer that does not appear in the list.
First, since the mode is 9 and it must be unique, 9 must appear more times than any other numb... |
[
{
"content": "Problem: Find the number of ways to place a digit in each cell of a 2x3 grid so that the sum of the two numbers formed by reading left to right is $999$ , and the sum of the three numbers formed by reading top to bottom is $99$ . The grid below is an example of such an arrangement because $8+99... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 2 | AIME24 | {
"expected_answer": "45",
"problem_id": "aime24-2",
"reference_solution": "Consider this table: $\\begin{array}{|c|c|c|} \\hline a & b & c \\\\ \\hline d & e & f\\\\ \\hline \\end{array}$ We note that $c+f = 9$ , because $c+f \\leq 18$ , meaning it never achieves a unit's digit sum of $9$ otherwise. Since no... | To solve the problem, we need to fill a 2x3 grid with digits such that the sum of the two numbers formed by reading left to right (i.e., the first row and the second row) is 999, and the sum of the three numbers formed by reading top to bottom (i.e., the first column, second column, and third column) is 99. Let's break... |
[
{
"content": "Problem: Let $x,y$ and $z$ be positive real numbers that satisfy the following system of equations:\n \\[\\log_2\\left({x \\over yz}\\right) = {1 \\over 2}\\] \\[\\log_2\\left({y \\over xz}\\right) = {1 \\over 3}\\] \\[\\log_2\\left({z \\over xy}\\right) = {1 \\over 4}\\] \nThen the value of... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 3 | AIME24 | {
"expected_answer": "33",
"problem_id": "aime24-3",
"reference_solution": "Denote $\\log_2(x) = a$ , $\\log_2(y) = b$ , and $\\log_2(z) = c$ . Then, we have:\n $a-b-c = \\frac{1}{2}$ \n $-a+b-c = \\frac{1}{3}$ \n $-a-b+c = \\frac{1}{4}$ Now, we can solve to get $a = \\frac{-7}{24}, b = \\frac{-9}{24}, c = \\... | To solve the given system of logarithmic equations, let's start by translating each equation into exponential form. The first equation is:
\[
\log_2\left(\frac{x}{yz}\right) = \frac{1}{2} \implies \frac{x}{yz} = 2^{1/2} = \sqrt{2}.
\]
Similarly, the second equation:
\[
\log_2\left(\frac{y}{xz}\right) = \frac{1}{3} \... |
[
{
"content": "Problem: Let ABCDEF be a convex equilateral hexagon in which all pairs of opposite sides are parallel. The triangle whose sides are extensions of segments AB, CD, and EF has side lengths 200, 240, and 300. Find the side length of the hexagon.\nMark your solution with \\boxed\nAnswer:",
"role":... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 4 | AIME24 | {
"expected_answer": "80",
"problem_id": "aime24-4",
"reference_solution": "Draw a good diagram!\nLet $AF \\cap BC$ , $BC \\cap DE$ , and $AF \\cap DE$ be K, L, and M, respectively. Let $KL=200, KM=300, ML=240$ . Notice that all smaller triangles formed are all similar to the larger $(200,240,300)$ triangl... | To solve for the side length of the convex equilateral hexagon \(ABCDEF\) where opposite sides are parallel, we start by understanding the structure. Since it's a regular hexagon with opposite sides parallel, we can position it in the coordinate plane for easier calculation.
Let’s denote the side length of the hexagon... |
[
{
"content": "Problem: Alice chooses a set $A$ of positive integers. Then Bob lists all finite nonempty sets $B$ of positive integers with the property that the maximum element of $B$ belongs to $A$ . Bob's list has 2024 sets. Find the sum of the elements of A.\nMark your solution with \\boxed\nAnswer:",... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 5 | AIME24 | {
"expected_answer": "55",
"problem_id": "aime24-5",
"reference_solution": "Let $k$ be one of the elements in Alices set $A$ of positive integers. The number of sets that Bob lists with the property that their maximum element is k is $2^{k-1}$ , since every positive integer less than k can be in the set or o... | To solve the problem, we need to determine the set \( A \) such that when Bob lists all finite nonempty sets \( B \) where the maximum element of \( B \) is in \( A \), there are exactly 2024 such sets. We need to find the sum of the elements of \( A \).
Let's denote the elements of \( A \) as \( a_1, a_2, \dots, a_k ... |
[
{
"content": "Problem: Let $N$ be the greatest four-digit positive integer with the property that whenever one of its digits is changed to $1$ , the resulting number is divisible by $7$ . Let $Q$ and $R$ be the quotient and remainder, respectively, when $N$ is divided by $1000$ . Find $Q+R$ .\nMark ... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 6 | AIME24 | {
"expected_answer": "699",
"problem_id": "aime24-6",
"reference_solution": "We note that by changing a digit to $1$ for the number $\\overline{abcd}$ , we are subtracting the number by either $1000(a-1)$ , $100(b-1)$ , $10(c-1)$ , or $d-1$ . Thus, $1000a + 100b + 10c + d \\equiv 1000(a-1) \\equiv 100(b-1... | To solve for the greatest four-digit number \( N \) such that changing any digit to 1 results in a number divisible by 7, we start by expressing \( N \) as \( \overline{abcd} \), where \( a, b, c, d \) are its digits. The key condition is that for each digit position, replacing that digit with 1 yields a number divisib... |
[
{
"content": "Problem: Torus $T$ is the surface produced by revolving a circle with radius $3$ around an axis in the plane of the circle that is a distance $6$ from the center of the circle (so like a donut). Let $S$ be a sphere with a radius $11$ . When $T$ rests on the inside of $S$ , it is intern... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 7 | AIME24 | {
"expected_answer": "127",
"problem_id": "aime24-7",
"reference_solution": "First, let's consider a section $\\mathcal{P}$ of the solids, along the axis.\nBy some 3D-Geomerty thinking, we can simply know that the axis crosses the sphere center. So, that is saying, the $\\mathcal{P}$ we took crosses one of th... | To solve the problem, we need to analyze the geometry of the torus \( T \) and the sphere \( S \) in both internal and external tangent scenarios.
### Step 1: Understanding the Torus
The torus is generated by revolving a circle of radius \( 3 \) around an axis that is \( 6 \) units away from its center. This forms a s... |
[
{
"content": "Problem: There is a collection of $25$ indistinguishable white chips and $25$ indistinguishable black chips. Find the number of ways to place some of these chips in the $25$ unit cells of a $5\\times5$ grid such that: each cell contains at most one chip all chips in the same row and all ch... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 8 | AIME24 | {
"expected_answer": "902",
"problem_id": "aime24-8",
"reference_solution": "The problem says \"some\", so not all cells must be occupied.\nWe start by doing casework on the column on the left. There can be 5,4,3,2, or 1 black chip. The same goes for white chips, so we will multiply by 2 at the end. There is $1$... | To solve this problem, we need to count the number of ways to place 25 white and 25 black chips in a 5x5 grid such that each cell contains at most one chip, and all chips in the same row or column have the same color. This means that no two chips of different colors can share a row or column. Let's break this down step... |
[
{
"content": "Problem: Let $\\triangle ABC$ have circumcenter $O$ and incenter $I$ with $\\overline{IA}\\perp\\overline{OI}$ , circumradius $13$ , and inradius $6$ . Find $AB\\cdot AC$ .\nMark your solution with \\boxed\nAnswer:",
"role": "user"
}
] | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 9 | AIME24 | {
"expected_answer": "468",
"problem_id": "aime24-9",
"reference_solution": "By Euler's formula $OI^{2}=R(R-2r)$ , we have $OI^{2}=13(13-12)=13$ . Thus, by the Pythagorean theorem, $AI^{2}=13^{2}-13=156$ . Let $AI\\cap(ABC)=M$ ; notice $\\triangle AOM$ is isosceles and $\\overline{OI}\\perp\\overline{AM}$ ... | To solve for \( AB \cdot AC \) given that the circumradius \( R = 13 \), inradius \( r = 6 \), and \( IA \perp OI \), we start by recalling some geometric properties and formulas.
First, the condition \( IA \perp OI \) is significant. In a triangle, this orthogonality implies a relationship between the triangle's side... |
[
{
"content": "Problem: Find the number of triples of nonnegative integers $(a,b,c)$ satisfying $a + b + c = 300$ and\n \\[a^2b + a^2c + b^2a + b^2c + c^2a + c^2b = 6,000,000.\\]\nMark your solution with \\boxed\nAnswer:",
"role": "user"
}
] | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 10 | AIME24 | {
"expected_answer": "601",
"problem_id": "aime24-10",
"reference_solution": "$ab(a+b)+bc(b+c)+ac(a+c)=300(ab+bc+ac)-3abc=6000000, 100(ab+bc+ac)-abc=2000000$ Note that \n $(100-a)(100-b)(100-c)=1000000-10000(a+b+c)+100(ab+bc+ac)-abc=0$ . Thus, $a/b/c=100$ . There are $201$ cases for each but we need to subtrac... | To solve the problem, we start by analyzing the given equations. The first equation is \(a + b + c = 300\), and the second is \(a^2b + a^2c + b^2a + b^2c + c^2a + c^2b = 6,000,000\). Let's rewrite the second equation for clarity:
\[
a^2(b + c) + b^2(a + c) + c^2(a + b) = 6,000,000.
\]
Since \(a + b + c = 300\), we ca... |
[
{
"content": "Problem: Let \\(O=(0,0)\\), \\(A=\\left(\\tfrac{1}{2},0\\right)\\), and \\(B=\\left(0,\\tfrac{\\sqrt{3}}{2}\\right)\\) be points in the coordinate plane. Let \\(\\mathcal{F}\\) be the family of segments \\(\\overline{PQ}\\) of unit length lying in the first quadrant with \\(P\\) on the \\(x\\)-axi... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 11 | AIME24 | {
"expected_answer": "23",
"problem_id": "aime24-11",
"reference_solution": "Begin by finding the equation of the line $\\overline{AB}$ : $y= -\\sqrt{3}x+\\frac{\\sqrt{3}}{2}$ Now, consider the general equation of all lines that belong to $\\mathcal{F}$ . Let $P$ be located at $(a,0)$ and $Q$ be located... | To solve the problem, we start by understanding the geometry involved. The points given are \( O = (0,0) \), \( A = \left( \frac{1}{2}, 0 \right) \), and \( B = \left( 0, \frac{\sqrt{3}}{2} \right) \). The line segment \( AB \) connects these two points. We need to find a unique point \( C \) on \( AB \) that is not co... |
[
{
"content": "Problem: Let $\\omega\\neq 1$ be a 13th root of unity. Find the remainder when\n \\[\\prod_{k=0}^{12}(2-2\\omega^k+\\omega^{2k})\\] \nis divided by 1000.\nMark your solution with \\boxed\nAnswer:",
"role": "user"
}
] | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 12 | AIME24 | {
"expected_answer": "321",
"problem_id": "aime24-12",
"reference_solution": "\\[\\prod_{k=0}^{12} \\left(2- 2\\omega^k + \\omega^{2k}\\right) = \\prod_{k=0}^{12} \\left((1 - \\omega^k)^2 + 1\\right) = \\prod_{k=0}^{12} \\left((1 + i) - \\omega^k)((1 - i) - \\omega^k\\right)\\] Now, we consider the polynomial $x... | To solve the problem, we start by analyzing the given product:
\[
P = \prod_{k=0}^{12} (2 - 2\omega^k + \omega^{2k}),
\]
where \(\omega\) is a primitive 13th root of unity. Since \(\omega\) is a root of \(x^{13} - 1 = 0\), the minimal polynomial over \(\mathbb{Q}\) is \(x^{12} + x^{11} + \cdots + x + 1\), which imp... |
[
{
"content": "Problem: Let \\(b\\ge 2\\) be an integer. Call a positive integer \\(n\\) \\(b\\text-\\textit{eautiful}\\) if it has exactly two digits when expressed in base \\(b\\) and these two digits sum to \\(\\sqrt n\\). For example, \\(81\\) is \\(13\\text-\\textit{eautiful}\\) because \\(81 = \\underlin... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 13 | AIME24 | {
"expected_answer": "211",
"problem_id": "aime24-13",
"reference_solution": "We write the base- $b$ two-digit integer as $\\left( xy \\right)_b$ .\nThus, this number satisfies\n \\[ \\left( x + y \\right)^2 = b x + y \\] \nwith $x \\in \\left\\{ 1, 2, \\cdots , b-1 \\right\\}$ and $y \\in \\left\\{ 0, 1, \\... | To solve the problem, we need to find the least integer \( b \ge 2 \) such that there are more than ten \( b \)-beautiful integers. A \( b \)-beautiful integer \( n \) must satisfy two conditions:
1. \( n \) has exactly two digits in base \( b \), meaning \( b \le n < b^2 \).
2. The sum of its two digits in base \( b \... |
[
{
"content": "Problem: Find the number of rectangles that can be formed inside a fixed regular dodecagon ( $12$ -gon) where each side of the rectangle lies on either a side or a diagonal of the dodecagon. The diagram below shows three of those rectangles. [asy] unitsize(0.6 inch); for(int i=0; i<360; i+=30) { d... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 14 | AIME24 | {
"expected_answer": "315",
"problem_id": "aime24-14",
"reference_solution": "By Furaken There are two kinds of such rectangles: those whose sides are parallel to some edges of the regular 12-gon (Case 1), and those whose sides are not (Case 2). For Case 1, WLOG assume that the rectangle's sides are horizontal an... | To determine the number of rectangles that can be formed inside a fixed regular dodecagon (12-gon) where each side of the rectangle lies on either a side or a diagonal of the dodecagon, we need to systematically analyze possible rectangle configurations.
### Key Observations:
1. **Symmetry**: The dodecagon has rotatio... |
[
{
"content": "Problem: Every morning Aya goes for a $9$ -kilometer-long walk and stops at a coffee shop afterwards. When she walks at a constant speed of $s$ kilometers per hour, the walk takes her 4 hours, including $t$ minutes spent in the coffee shop. When she walks $s+2$ kilometers per hour, the walk... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 15 | AIME24 | {
"expected_answer": "204",
"problem_id": "aime24-15",
"reference_solution": "$\\frac{9}{s} + t = 4$ in hours and $\\frac{9}{s+2} + t = 2.4$ in hours. Subtracting the second equation from the first, we get, $\\frac{9}{s} - \\frac{9}{s+2} = 1.6$ Multiplying by $(s)(s+2)$ , we get $9s+18-9s=18=1.6s^{2} + 3.2s$ ... | To solve the problem, we need to determine Aya's walking speed \( s \) and the time \( t \) she spends in the coffee shop. Then, use that to find the total time when she walks at \( s + \frac{1}{2} \) km/h.
First, let's convert all time units to hours for consistency. The original times are 4 hours and 2 hours and 24 ... |
[
{
"content": "Problem: There exist real numbers $x$ and $y$ , both greater than 1, such that $\\log_x\\left(y^x\\right)=\\log_y\\left(x^{4y}\\right)=10$ . Find $xy$ .\nMark your solution with \\boxed\nAnswer:",
"role": "user"
}
] | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 16 | AIME24 | {
"expected_answer": "25",
"problem_id": "aime24-16",
"reference_solution": "By properties of logarithms, we can simplify the given equation to $x\\log_xy=4y\\log_yx=10$ . Let us break this into two separate equations: \\[x\\log_xy=10\\] \n \\[4y\\log_yx=10.\\] \nWe multiply the two equations to get: \n \\[4xy\\... | To solve the problem, we start with the given equations:
\[
\log_x(y^x) = 10 \quad \text{and} \quad \log_y(x^{4y}) = 10.
\]
First, simplify each logarithmic equation using logarithm properties. Recall that \(\log_a(b^c) = c \log_a(b)\).
For the first equation:
\[
\log_x(y^x) = x \log_x(y) = 10.
\]
Let \(a = \log_x(y)\... |
[
{
"content": "Problem: Alice and Bob play the following game. A stack of $n$ tokens lies before them. The players take turns with Alice going first. On each turn, the player removes either $1$ token or $4$ tokens from the stack. Whoever removes the last token wins. Find the number of positive integers $n... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 17 | AIME24 | {
"expected_answer": "809",
"problem_id": "aime24-17",
"reference_solution": "Let's first try some experimentation. Alice obviously wins if there is one coin. She will just take it and win. If there are 2 remaining, then Alice will take one and then Bob will take one, so Bob wins. If there are $3$ , Alice will t... | To determine the number of positive integers \( n \leq 2024 \) where Bob can guarantee a win regardless of Alice's moves, we need to analyze the game's winning positions. Let’s define \( W \) as a winning position (where the player whose turn it is can force a win) and \( L \) as a losing position (where any move leads... |
[
{
"content": "Problem: Jen enters a lottery by picking $4$ distinct numbers from $S=\\{1,2,3,\\cdots,9,10\\}.$ $4$ numbers are randomly chosen from $S.$ She wins a prize if at least two of her numbers were $2$ of the randomly chosen numbers, and wins the grand prize if all four of her numbers were the... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 18 | AIME24 | {
"expected_answer": "116",
"problem_id": "aime24-18",
"reference_solution": "This is a conditional probability problem. Bayes' Theorem states that \n \\[P(A|B)=\\dfrac{P(B|A)\\cdot P(A)}{P(B)}\\] in other words, the probability of $A$ given $B$ is equal to the probability of $B$ given $A$ times the proba... | To solve this problem, we need to use conditional probability. The key is to find the probability of winning the grand prize (i.e., matching all 4 numbers) given that she already won a prize (at least 2 matches). Let's break it down step by step.
First, let's define the events:
- Event \( A \): Jen wins a prize (at le... |
[
{
"content": "Problem: Rectangles $ABCD$ and $EFGH$ are drawn such that $D,E,C,F$ are collinear. Also, $A,D,H,G$ all lie on a circle. If $BC=16$ , $AB=107$ , $FG=17$ , and $EF=184$ , what is the length of $CE$ ? [asy] import graph; unitsize(0.1cm); pair A = (0,0);pair B = (70,0);pair C = (70,16);pai... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 19 | AIME24 | {
"expected_answer": "104",
"problem_id": "aime24-19",
"reference_solution": "We use simple geometry to solve this problem. [asy] import graph; unitsize(0.1cm); pair A = (0,0);pair B = (107,0);pair C = (107,16);pair D = (0,16);pair E = (3,16);pair F = (187,16);pair G = (187,33);pair H = (3,33); label(\"$A$\", A,... | To solve for the length of \( CE \), let's analyze the given geometric configuration step by step.
First, we have two rectangles \(ABCD\) and \(EFGH\) such that points \(D, E, C, F\) are collinear, and \(A, D, H, G\) lie on a circle. The given side lengths are \(AB = 107\), \(BC = 16\), \(FG = 17\), and \(EF = 184\). ... |
[
{
"content": "Problem: Consider the paths of length $16$ that follow the lines from the lower left corner to the upper right corner on an $8\\times 8$ grid. Find the number of such paths that change direction exactly four times, as in the examples shown below. [asy] size(10cm); usepackage(\"tikz\");label(\"... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 20 | AIME24 | {
"expected_answer": "294",
"problem_id": "aime24-20",
"reference_solution": "We divide the path into eight “ $R$ ” movements and eight “ $U$ ” movements. Five sections of alternative $RURUR$ or $URURU$ are necessary in order to make four “turns.” We use the first case and multiply by $2$ . <br/>\nFor $U$ ,... | To solve the problem of finding the number of paths of length 16 on an 8x8 grid that start at the lower left corner and end at the upper right corner, changing direction exactly four times, we need to analyze the structure of such paths.
First, note that each path consists of 16 steps: 8 right (R) and 8 up (U). The t... |
[
{
"content": "Problem: Find the largest possible real part of \\[(75+117i)z+\\frac{96+144i}{z}\\] where $z$ is a complex number with $|z|=4$ .\nMark your solution with \\boxed\nAnswer:",
"role": "user"
}
] | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 21 | AIME24 | {
"expected_answer": "540",
"problem_id": "aime24-21",
"reference_solution": "Let $z=a+bi$ such that $a^2+b^2=4^2=16$ . The expression becomes: \\[(75+117i)(a+bi)+\\dfrac{96+144i}{a+bi}.\\] Call this complex number $w$ . We simplify this expression. \\begin{align*}\nw&=(75+117i)(a+bi)+\\dfrac{96+144i}{a+bi} \... | To solve the problem of finding the largest possible real part of the expression \((75+117i)z + \frac{96+144i}{z}\) where \(|z|=4\), follow these steps:
1. **Express \(z\) in terms of its real and imaginary parts**:
Let \(z = x + yi\), where \(x\) and \(y\) are real numbers, and \(x^2 + y^2 = 16\) (since \(|z|=4\... |
[
{
"content": "Problem: Eight circles of radius $34$ are sequentially tangent, and two of the circles are tangent to $AB$ and $BC$ of triangle $ABC$ , respectively. $2024$ circles of radius $1$ can be arranged in the same manner. The inradius of triangle $ABC$ can be expressed as $\\frac{m}{n}$ , w... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 22 | AIME24 | {
"expected_answer": "197",
"problem_id": "aime24-22",
"reference_solution": "Draw an altitude from both end circles of the diagram with the circles of radius one, and call the lengths you get drawing the altitudes of the circles down to $BC$ $a$ and $b$ . Now we have the length of side $BC$ of being $(2)... | To solve the problem, we need to determine the inradius of triangle \(ABC\) given the arrangement of circles. Let's start by understanding the setup. There are eight circles of radius 34, with two of them tangent to sides \(AB\) and \(BC\) of the triangle. The remaining six circles are arranged between these two, each ... |
[
{
"content": "Problem: Let $A$ , $B$ , $C$ , and $D$ be points on the hyperbola $\\frac{x^2}{20}- \\frac{y^2}{24} = 1$ such that $ABCD$ is a rhombus whose diagonals intersect at the origin. Find the greatest real number that is less than $BD^2$ for all such rhombi.\nMark your solution with \\boxed\nA... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 23 | AIME24 | {
"expected_answer": "480",
"problem_id": "aime24-23",
"reference_solution": "A quadrilateral is a rhombus if and only if its two diagonals bisect each other and are perpendicular to each other. The first condition is automatically satisfied because of the hyperbola's symmetry about the origin. To satisfy the sec... | To solve the problem, we start by noting that the hyperbola given is \(\frac{x^2}{20} - \frac{y^2}{24} = 1\). The diagonals of the rhombus \(ABCD\) intersect at the origin, which is also the center of the hyperbola. Since the diagonals of a rhombus bisect each other at right angles, the origin must be the midpoint of b... |
[
{
"content": "Problem: Let $ABC$ be a triangle inscribed in circle $\\omega$ . Let the tangents to $\\omega$ at $B$ and $C$ intersect at point $D$ , and let $\\overline{AD}$ intersect $\\omega$ at $P$ . If $AB=5$ , $BC=9$ , and $AC=10$ , $AP$ can be written as the form $\\frac{m}{n}$ , wher... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 24 | AIME24 | {
"expected_answer": "113",
"problem_id": "aime24-24",
"reference_solution": "From the tangency condition we have $\\let\\angle BCD = \\let\\angle CBD = \\let\\angle A$ . With LoC we have $\\cos(A) = \\frac{25+100-81}{2*5*10} = \\frac{11}{25}$ and $\\cos(B) = \\frac{81+25-100}{2*9*5} = \\frac{1}{15}$ . Then, ... | To solve for \( AP \) in the given triangle \( ABC \) inscribed in circle \( \omega \), we start by noting that point \( D \) is the intersection of the tangents to \( \omega \) at \( B \) and \( C \). This makes \( D \) the exsimilicenter of \( \omega \) with respect to \( B \) and \( C \), and by the tangent-chord th... |
[
{
"content": "Problem: Each vertex of a regular octagon is independently colored either red or blue with equal probability. The probability that the octagon can then be rotated so that all of the blue vertices end up at positions where there were originally red vertices is $\\tfrac{m}{n}$ , where $m$ and $n... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 25 | AIME24 | {
"expected_answer": "371",
"problem_id": "aime24-25",
"reference_solution": "Notice that the question's condition mandates all blues to go to reds, but reds do not necessarily have to go to blue. Let us do casework on how many blues there are. If there are no blues whatsoever, there is only one case. This case i... | To solve this problem, we need to determine the probability that a regular octagon with vertices colored red or blue can be rotated such that all blue vertices originally occupied positions that were red. This is equivalent to saying that after rotation, each blue vertex is now in a red position, meaning that the set o... |
[
{
"content": "Problem: Define $f(x)=|| x|-\\tfrac{1}{2}|$ and $g(x)=|| x|-\\tfrac{1}{4}|$ . Find the number of intersections of the graphs of \\[y=4 g(f(\\sin (2 \\pi x))) \\quad\\text{ and }\\quad x=4 g(f(\\cos (3 \\pi y))).\\]\nMark your solution with \\boxed\nAnswer:",
"role": "user"
}
] | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 26 | AIME24 | {
"expected_answer": "385",
"problem_id": "aime24-26",
"reference_solution": "If we graph $4g(f(x))$ , we see it forms a sawtooth graph that oscillates between $0$ and $1$ (for values of $x$ between $-1$ and $1$ , which is true because the arguments are between $-1$ and $1$ ). Thus by precariously dr... | To solve the problem, we need to find the number of intersections between the graphs \( y = 4g(f(\sin(2\pi x))) \) and \( x = 4g(f(\cos(3\pi y))) \). Let's break it down step by step.
First, let's understand the functions \( f(x) \) and \( g(x) \):
- \( f(x) = \left| |x| - \frac{1}{2} \right| \)
- \( g(x) = \left| |x|... |
[
{
"content": "Problem: Let $p$ be the least prime number for which there exists a positive integer $n$ such that $n^{4}+1$ is divisible by $p^{2}$ . Find the least positive integer $m$ such that $m^{4}+1$ is divisible by $p^{2}$ .\nMark your solution with \\boxed\nAnswer:",
"role": "user"
}
] | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 27 | AIME24 | {
"expected_answer": "110",
"problem_id": "aime24-27",
"reference_solution": "If \\(p=2\\), then \\(4\\mid n^4+1\\) for some integer \\(n\\). But \\(\\left(n^2\\right)^2\\equiv0\\) or \\(1\\pmod4\\), so it is impossible. Thus \\(p\\) is an odd prime. For integer \\(n\\) such that \\(p^2\\mid n^4+1\\), we have \\(... | To solve the problem, we need to find the least prime \( p \) such that there exists a positive integer \( n \) where \( p^2 \) divides \( n^4 + 1 \). Then, determine the least positive integer \( m \) for which \( m^4 + 1 \) is divisible by \( p^2 \).
**Step 1: Find the smallest prime \( p \) where \( n^4 \equiv -1 \... |
[
{
"content": "Problem: Let $ABCD$ be a tetrahedron such that $AB=CD= \\sqrt{41}$ , $AC=BD= \\sqrt{80}$ , and $BC=AD= \\sqrt{89}$ . There exists a point $I$ inside the tetrahedron such that the distances from $I$ to each of the faces of the tetrahedron are all equal. This distance can be written in the ... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 28 | AIME24 | {
"expected_answer": "104",
"problem_id": "aime24-28",
"reference_solution": "Notice that \\(41=4^2+5^2\\), \\(89=5^2+8^2\\), and \\(80=8^2+4^2\\), let \\(A~(0,0,0)\\), \\(B~(4,5,0)\\), \\(C~(0,5,8)\\), and \\(D~(4,0,8)\\). Then the plane \\(BCD\\) has a normal\n\\begin{equation*}\n\\mathbf n:=\\frac14\\overright... | To solve for the distance from point \( I \) to each face of the tetrahedron \( ABCD \), we first note that \( I \) is the incenter of the tetrahedron, and the equal distances are the inradius \( r \). The formula for the volume \( V \) of a tetrahedron in terms of its inradius \( r \) and surface area \( S \) is \( V ... |
[
{
"content": "Problem: Let $\\mathcal{B}$ be the set of rectangular boxes with surface area $54$ and volume $23$ . Let $r$ be the radius of the smallest sphere that can contain each of the rectangular boxes that are elements of $\\mathcal{B}$ . The value of $r^2$ can be written as $\\frac{p}{q}$ , wh... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 29 | AIME24 | {
"expected_answer": "721",
"problem_id": "aime24-29",
"reference_solution": "Observe that the \"worst\" possible box is one of the maximum possible length. \nBy symmetry, the height and the width are the same in this antioptimal box. (If the height and width weren't the same, the extra difference between them co... | To solve the problem, we start by letting the dimensions of the rectangular box be \(a\), \(b\), and \(c\). The surface area is given as 54, so we have:
\[2(ab + bc + ca) = 54 \implies ab + bc + ca = 27,\]
and the volume is 23:
\[abc = 23.\]
Since 23 is a prime number, one of the dimensions must be 1, because 23 ca... |
[
{
"content": "Problem: Among the 900 residents of Aimeville, there are 195 who own a diamond ring, 367 who own a set of golf clubs, and 562 who own a garden spade. In addition, each of the 900 residents owns a bag of candy hearts. There are 437 residents who own exactly two of these things, and 234 residents wh... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 0 | AIME24 | {
"expected_answer": "73",
"problem_id": "aime24-0",
"reference_solution": "Let $w,x,y,z$ denote the number of residents who own 1,2,3 and 4 of these items, respectively. We know $w+x+y+z=900$ , since there are 900 residents in total. This simplifies to $w+z=229$ , since we know $x=437$ and $y=234$ . Now, w... | To solve this problem, we can use the principle of inclusion-exclusion. Let's denote the four sets as follows:
- \( D \): Residents who own a diamond ring.
- \( G \): Residents who own a set of golf clubs.
- \( S \): Residents who own a garden spade.
- \( C \): All residents (since every resident owns a bag of candy he... |
[
{
"content": "Problem: A list of positive integers has the following properties: $\\bullet$ The sum of the items in the list is $30$ . $\\bullet$ The unique mode of the list is $9$ . $\\bullet$ The median of the list is a positive integer that does not appear in the list itself. Find the sum of the squares... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 1 | AIME24 | {
"expected_answer": "236",
"problem_id": "aime24-1",
"reference_solution": "The third condition implies that the list's size must be an even number, as if it were an odd number, the median of the list would surely appear in the list itself. Therefore, we can casework on what even numbers work. Say the size is 2.... | To solve this problem, we need to find a list of positive integers that sum to 30, has a unique mode of 9, and the median is a positive integer not in the list. The median is also a clue that the list must have an odd number of elements since the median would be the middle number in an ordered list. Let's break it down... |
[
{
"content": "Problem: Find the number of ways to place a digit in each cell of a 2x3 grid so that the sum of the two numbers formed by reading left to right is $999$ , and the sum of the three numbers formed by reading top to bottom is $99$ . The grid below is an example of such an arrangement because $8+99... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 2 | AIME24 | {
"expected_answer": "45",
"problem_id": "aime24-2",
"reference_solution": "Consider this table: $\\begin{array}{|c|c|c|} \\hline a & b & c \\\\ \\hline d & e & f\\\\ \\hline \\end{array}$ We note that $c+f = 9$ , because $c+f \\leq 18$ , meaning it never achieves a unit's digit sum of $9$ otherwise. Since no... | To solve this problem, we need to fill a 2x3 grid with digits such that the sum of the two numbers formed by reading left to right (i.e., the first row and the second row) is 999, and the sum of the three numbers formed by reading top to bottom (i.e., the first column, second column, and third column) is 99. Let's brea... |
[
{
"content": "Problem: Let $x,y$ and $z$ be positive real numbers that satisfy the following system of equations:\n \\[\\log_2\\left({x \\over yz}\\right) = {1 \\over 2}\\] \\[\\log_2\\left({y \\over xz}\\right) = {1 \\over 3}\\] \\[\\log_2\\left({z \\over xy}\\right) = {1 \\over 4}\\] \nThen the value of... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 3 | AIME24 | {
"expected_answer": "33",
"problem_id": "aime24-3",
"reference_solution": "Denote $\\log_2(x) = a$ , $\\log_2(y) = b$ , and $\\log_2(z) = c$ . Then, we have:\n $a-b-c = \\frac{1}{2}$ \n $-a+b-c = \\frac{1}{3}$ \n $-a-b+c = \\frac{1}{4}$ Now, we can solve to get $a = \\frac{-7}{24}, b = \\frac{-9}{24}, c = \\... | To solve the given system of logarithmic equations, let's start by defining variables for the logarithms. Let:
\[
a = \log_2 x, \quad b = \log_2 y, \quad c = \log_2 z
\]
The original equations can be rewritten in terms of \(a\), \(b\), and \(c\). The first equation is:
\[
\log_2\left(\frac{x}{yz}\right) = \frac{1}{2... |
[
{
"content": "Problem: Let ABCDEF be a convex equilateral hexagon in which all pairs of opposite sides are parallel. The triangle whose sides are extensions of segments AB, CD, and EF has side lengths 200, 240, and 300. Find the side length of the hexagon.\nMark your solution with \\boxed\nAnswer:",
"role":... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 4 | AIME24 | {
"expected_answer": "80",
"problem_id": "aime24-4",
"reference_solution": "Draw a good diagram!\nLet $AF \\cap BC$ , $BC \\cap DE$ , and $AF \\cap DE$ be K, L, and M, respectively. Let $KL=200, KM=300, ML=240$ . Notice that all smaller triangles formed are all similar to the larger $(200,240,300)$ triangl... | To solve for the side length of the equilateral hexagon \(ABCDEF\) where opposite sides are parallel, we start by understanding the structure. Since the hexagon is equilateral and convex with opposite sides parallel, it can be viewed as a truncated triangle or a hexagon formed by removing smaller triangles from a large... |
[
{
"content": "Problem: Alice chooses a set $A$ of positive integers. Then Bob lists all finite nonempty sets $B$ of positive integers with the property that the maximum element of $B$ belongs to $A$ . Bob's list has 2024 sets. Find the sum of the elements of A.\nMark your solution with \\boxed\nAnswer:",... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 5 | AIME24 | {
"expected_answer": "55",
"problem_id": "aime24-5",
"reference_solution": "Let $k$ be one of the elements in Alices set $A$ of positive integers. The number of sets that Bob lists with the property that their maximum element is k is $2^{k-1}$ , since every positive integer less than k can be in the set or o... | To solve this problem, we need to determine the set \( A \) such that the number of finite nonempty subsets \( B \) of positive integers where the maximum element of \( B \) is in \( A \) equals 2024. Let's break this down step by step.
First, let's consider the structure of the subsets \( B \). Each \( B \) is a none... |
[
{
"content": "Problem: Let $N$ be the greatest four-digit positive integer with the property that whenever one of its digits is changed to $1$ , the resulting number is divisible by $7$ . Let $Q$ and $R$ be the quotient and remainder, respectively, when $N$ is divided by $1000$ . Find $Q+R$ .\nMark ... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 6 | AIME24 | {
"expected_answer": "699",
"problem_id": "aime24-6",
"reference_solution": "We note that by changing a digit to $1$ for the number $\\overline{abcd}$ , we are subtracting the number by either $1000(a-1)$ , $100(b-1)$ , $10(c-1)$ , or $d-1$ . Thus, $1000a + 100b + 10c + d \\equiv 1000(a-1) \\equiv 100(b-1... | To solve this problem, we need to find the largest four-digit number \( N \) such that changing any single digit to 1 results in a number divisible by 7. Then, we must compute \( Q + R \) where \( Q \) and \( R \) are the quotient and remainder when \( N \) is divided by 1000.
**Step 1: Understand the divisibility con... |
[
{
"content": "Problem: Torus $T$ is the surface produced by revolving a circle with radius $3$ around an axis in the plane of the circle that is a distance $6$ from the center of the circle (so like a donut). Let $S$ be a sphere with a radius $11$ . When $T$ rests on the inside of $S$ , it is intern... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 7 | AIME24 | {
"expected_answer": "127",
"problem_id": "aime24-7",
"reference_solution": "First, let's consider a section $\\mathcal{P}$ of the solids, along the axis.\nBy some 3D-Geomerty thinking, we can simply know that the axis crosses the sphere center. So, that is saying, the $\\mathcal{P}$ we took crosses one of th... | To solve this problem, we need to analyze both the internal and external tangency conditions of the torus \( T \) and the sphere \( S \). Let's start by understanding the geometry of the torus. The torus is formed by revolving a circle of radius 3 around an axis that is 6 units away from its center. This means the majo... |
[
{
"content": "Problem: There is a collection of $25$ indistinguishable white chips and $25$ indistinguishable black chips. Find the number of ways to place some of these chips in the $25$ unit cells of a $5\\times5$ grid such that: each cell contains at most one chip all chips in the same row and all ch... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 8 | AIME24 | {
"expected_answer": "902",
"problem_id": "aime24-8",
"reference_solution": "The problem says \"some\", so not all cells must be occupied.\nWe start by doing casework on the column on the left. There can be 5,4,3,2, or 1 black chip. The same goes for white chips, so we will multiply by 2 at the end. There is $1$... | To solve this problem, we need to count the number of ways to place 25 white and 25 black chips on a \(5 \times 5\) grid with the given constraints. The constraints are:
1. Each cell contains at most one chip.
2. All chips in the same row and all chips in the same column must have the same color.
3. No additional chip... |
[
{
"content": "Problem: Let $\\triangle ABC$ have circumcenter $O$ and incenter $I$ with $\\overline{IA}\\perp\\overline{OI}$ , circumradius $13$ , and inradius $6$ . Find $AB\\cdot AC$ .\nMark your solution with \\boxed\nAnswer:",
"role": "user"
}
] | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 9 | AIME24 | {
"expected_answer": "468",
"problem_id": "aime24-9",
"reference_solution": "By Euler's formula $OI^{2}=R(R-2r)$ , we have $OI^{2}=13(13-12)=13$ . Thus, by the Pythagorean theorem, $AI^{2}=13^{2}-13=156$ . Let $AI\\cap(ABC)=M$ ; notice $\\triangle AOM$ is isosceles and $\\overline{OI}\\perp\\overline{AM}$ ... | To solve for \( AB \cdot AC \) given that the circumradius \( R = 13 \), inradius \( r = 6 \), and \( \overline{IA} \perp \overline{OI} \), we can use properties of the triangle's geometry.
First, recall that the circumcenter \( O \) and incenter \( I \) satisfy \( \overline{IA} \perp \overline{OI} \) if and only if \... |
[
{
"content": "Problem: Find the number of triples of nonnegative integers $(a,b,c)$ satisfying $a + b + c = 300$ and\n \\[a^2b + a^2c + b^2a + b^2c + c^2a + c^2b = 6,000,000.\\]\nMark your solution with \\boxed\nAnswer:",
"role": "user"
}
] | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 10 | AIME24 | {
"expected_answer": "601",
"problem_id": "aime24-10",
"reference_solution": "$ab(a+b)+bc(b+c)+ac(a+c)=300(ab+bc+ac)-3abc=6000000, 100(ab+bc+ac)-abc=2000000$ Note that \n $(100-a)(100-b)(100-c)=1000000-10000(a+b+c)+100(ab+bc+ac)-abc=0$ . Thus, $a/b/c=100$ . There are $201$ cases for each but we need to subtrac... | To solve for the number of triples \((a, b, c)\) of nonnegative integers satisfying \(a + b + c = 300\) and \(a^2b + a^2c + b^2a + b^2c + c^2a + c^2b = 6,000,000\), we start by simplifying the given equation. Notice that each term in the equation is of the form \(a^2b + a^2c + \dots\). We can factor terms to find a pat... |
[
{
"content": "Problem: Let \\(O=(0,0)\\), \\(A=\\left(\\tfrac{1}{2},0\\right)\\), and \\(B=\\left(0,\\tfrac{\\sqrt{3}}{2}\\right)\\) be points in the coordinate plane. Let \\(\\mathcal{F}\\) be the family of segments \\(\\overline{PQ}\\) of unit length lying in the first quadrant with \\(P\\) on the \\(x\\)-axi... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 11 | AIME24 | {
"expected_answer": "23",
"problem_id": "aime24-11",
"reference_solution": "Begin by finding the equation of the line $\\overline{AB}$ : $y= -\\sqrt{3}x+\\frac{\\sqrt{3}}{2}$ Now, consider the general equation of all lines that belong to $\\mathcal{F}$ . Let $P$ be located at $(a,0)$ and $Q$ be located... | To solve this problem, we need to find the unique point \( C \) on the segment \( \overline{AB} \) (other than \( A \) and \( B \)) that is not covered by any unit segments from the family \( \mathcal{F} \). Then, compute \( OC^2 \) where \( O \) is the origin.
First, let's determine the equation of line \( AB \). Poi... |
[
{
"content": "Problem: Let $\\omega\\neq 1$ be a 13th root of unity. Find the remainder when\n \\[\\prod_{k=0}^{12}(2-2\\omega^k+\\omega^{2k})\\] \nis divided by 1000.\nMark your solution with \\boxed\nAnswer:",
"role": "user"
}
] | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 12 | AIME24 | {
"expected_answer": "321",
"problem_id": "aime24-12",
"reference_solution": "\\[\\prod_{k=0}^{12} \\left(2- 2\\omega^k + \\omega^{2k}\\right) = \\prod_{k=0}^{12} \\left((1 - \\omega^k)^2 + 1\\right) = \\prod_{k=0}^{12} \\left((1 + i) - \\omega^k)((1 - i) - \\omega^k\\right)\\] Now, we consider the polynomial $x... | To solve the problem, we start by analyzing the given product:
\[
P = \prod_{k=0}^{12} (2 - 2\omega^k + \omega^{2k}),
\]
where \(\omega\) is a primitive 13th root of unity. Our goal is to find the remainder when \(P\) is divided by 1000.
First, note that \(\omega^{13} = 1\), and \(\omega^k \neq 1\) for \(1 \leq k ... |
[
{
"content": "Problem: Let \\(b\\ge 2\\) be an integer. Call a positive integer \\(n\\) \\(b\\text-\\textit{eautiful}\\) if it has exactly two digits when expressed in base \\(b\\) and these two digits sum to \\(\\sqrt n\\). For example, \\(81\\) is \\(13\\text-\\textit{eautiful}\\) because \\(81 = \\underlin... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 13 | AIME24 | {
"expected_answer": "211",
"problem_id": "aime24-13",
"reference_solution": "We write the base- $b$ two-digit integer as $\\left( xy \\right)_b$ .\nThus, this number satisfies\n \\[ \\left( x + y \\right)^2 = b x + y \\] \nwith $x \\in \\left\\{ 1, 2, \\cdots , b-1 \\right\\}$ and $y \\in \\left\\{ 0, 1, \\... | To solve this problem, we need to find the smallest integer \( b \geq 2 \) such that there are more than ten \( b \)-beautiful integers. A \( b \)-beautiful integer \( n \) has exactly two digits in base \( b \), say \( d_1 \) and \( d_0 \), where \( d_1 + d_0 = \sqrt{n} \). Since \( n \) has two digits in base \( b \)... |
[
{
"content": "Problem: Find the number of rectangles that can be formed inside a fixed regular dodecagon ( $12$ -gon) where each side of the rectangle lies on either a side or a diagonal of the dodecagon. The diagram below shows three of those rectangles. [asy] unitsize(0.6 inch); for(int i=0; i<360; i+=30) { d... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 14 | AIME24 | {
"expected_answer": "315",
"problem_id": "aime24-14",
"reference_solution": "By Furaken There are two kinds of such rectangles: those whose sides are parallel to some edges of the regular 12-gon (Case 1), and those whose sides are not (Case 2). For Case 1, WLOG assume that the rectangle's sides are horizontal an... | To determine the number of rectangles that can be formed inside a fixed regular dodecagon (12-gon) where each side of the rectangle lies on either a side or a diagonal of the dodecagon, we need to analyze the possible rectangles. Each rectangle must have sides parallel to the sides or diagonals of the dodecagon. Since ... |
[
{
"content": "Problem: Every morning Aya goes for a $9$ -kilometer-long walk and stops at a coffee shop afterwards. When she walks at a constant speed of $s$ kilometers per hour, the walk takes her 4 hours, including $t$ minutes spent in the coffee shop. When she walks $s+2$ kilometers per hour, the walk... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 15 | AIME24 | {
"expected_answer": "204",
"problem_id": "aime24-15",
"reference_solution": "$\\frac{9}{s} + t = 4$ in hours and $\\frac{9}{s+2} + t = 2.4$ in hours. Subtracting the second equation from the first, we get, $\\frac{9}{s} - \\frac{9}{s+2} = 1.6$ Multiplying by $(s)(s+2)$ , we get $9s+18-9s=18=1.6s^{2} + 3.2s$ ... | To solve this problem, we need to determine Aya's walking speed \( s \) and the time \( t \) she spends in the coffee shop. Then, we'll use that information to find the total time when her speed is \( s + \frac{1}{2} \).
**Step 1: Set up equations based on the given information.**
When Aya walks at speed \( s \):
- T... |
[
{
"content": "Problem: There exist real numbers $x$ and $y$ , both greater than 1, such that $\\log_x\\left(y^x\\right)=\\log_y\\left(x^{4y}\\right)=10$ . Find $xy$ .\nMark your solution with \\boxed\nAnswer:",
"role": "user"
}
] | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 16 | AIME24 | {
"expected_answer": "25",
"problem_id": "aime24-16",
"reference_solution": "By properties of logarithms, we can simplify the given equation to $x\\log_xy=4y\\log_yx=10$ . Let us break this into two separate equations: \\[x\\log_xy=10\\] \n \\[4y\\log_yx=10.\\] \nWe multiply the two equations to get: \n \\[4xy\\... | To solve the problem, we start with the given equations:
\[
\log_x(y^x) = 10 \quad \text{and} \quad \log_y(x^{4y}) = 10.
\]
First, simplify each logarithmic expression. Using the logarithm power rule \(\log_b(a^c) = c \log_b(a)\), we rewrite both equations:
1. \(\log_x(y^x) = x \log_x y = 10\)
2. \(\log_y(x^{4y}) = ... |
[
{
"content": "Problem: Alice and Bob play the following game. A stack of $n$ tokens lies before them. The players take turns with Alice going first. On each turn, the player removes either $1$ token or $4$ tokens from the stack. Whoever removes the last token wins. Find the number of positive integers $n... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 17 | AIME24 | {
"expected_answer": "809",
"problem_id": "aime24-17",
"reference_solution": "Let's first try some experimentation. Alice obviously wins if there is one coin. She will just take it and win. If there are 2 remaining, then Alice will take one and then Bob will take one, so Bob wins. If there are $3$ , Alice will t... | To solve this problem, we need to determine for which values of \( n \leq 2024 \) Bob can guarantee a win, assuming Alice goes first and can take 1 or 4 tokens each turn. Let's analyze the game using combinatorial game theory concepts, particularly looking for losing positions (N-position) where the player whose turn i... |
[
{
"content": "Problem: Jen enters a lottery by picking $4$ distinct numbers from $S=\\{1,2,3,\\cdots,9,10\\}.$ $4$ numbers are randomly chosen from $S.$ She wins a prize if at least two of her numbers were $2$ of the randomly chosen numbers, and wins the grand prize if all four of her numbers were the... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 18 | AIME24 | {
"expected_answer": "116",
"problem_id": "aime24-18",
"reference_solution": "This is a conditional probability problem. Bayes' Theorem states that \n \\[P(A|B)=\\dfrac{P(B|A)\\cdot P(A)}{P(B)}\\] in other words, the probability of $A$ given $B$ is equal to the probability of $B$ given $A$ times the proba... | To solve this problem, we need to compute the conditional probability that Jen wins the grand prize given that she won a prize. Let's break it down step by step.
First, define the events:
- \( W \): Jen wins a prize (at least 2 of her numbers match the 4 drawn).
- \( G \): Jen wins the grand prize (all 4 of her number... |
[
{
"content": "Problem: Rectangles $ABCD$ and $EFGH$ are drawn such that $D,E,C,F$ are collinear. Also, $A,D,H,G$ all lie on a circle. If $BC=16$ , $AB=107$ , $FG=17$ , and $EF=184$ , what is the length of $CE$ ? [asy] import graph; unitsize(0.1cm); pair A = (0,0);pair B = (70,0);pair C = (70,16);pai... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 19 | AIME24 | {
"expected_answer": "104",
"problem_id": "aime24-19",
"reference_solution": "We use simple geometry to solve this problem. [asy] import graph; unitsize(0.1cm); pair A = (0,0);pair B = (107,0);pair C = (107,16);pair D = (0,16);pair E = (3,16);pair F = (187,16);pair G = (187,33);pair H = (3,33); label(\"$A$\", A,... | To solve for the length of \( CE \), we start by understanding the given problem. We have two rectangles, \(ABCD\) and \(EFGH\), with specific side lengths. The points \(D, E, C, F\) are collinear, and \(A, D, H, G\) lie on a circle. Our goal is to find \(CE\).
First, let's outline the given data:
- \(AB = 107\), \(BC... |
[
{
"content": "Problem: Consider the paths of length $16$ that follow the lines from the lower left corner to the upper right corner on an $8\\times 8$ grid. Find the number of such paths that change direction exactly four times, as in the examples shown below. [asy] size(10cm); usepackage(\"tikz\");label(\"... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 20 | AIME24 | {
"expected_answer": "294",
"problem_id": "aime24-20",
"reference_solution": "We divide the path into eight “ $R$ ” movements and eight “ $U$ ” movements. Five sections of alternative $RURUR$ or $URURU$ are necessary in order to make four “turns.” We use the first case and multiply by $2$ . <br/>\nFor $U$ ,... | To solve the problem of finding the number of paths of length 16 on an 8x8 grid that start at the lower left corner and end at the upper right corner, changing direction exactly four times, we need to analyze the structure of such paths.
First, note that a path from (0,0) to (8,8) on an 8x8 grid requires 8 right (R) m... |
[
{
"content": "Problem: Find the largest possible real part of \\[(75+117i)z+\\frac{96+144i}{z}\\] where $z$ is a complex number with $|z|=4$ .\nMark your solution with \\boxed\nAnswer:",
"role": "user"
}
] | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 21 | AIME24 | {
"expected_answer": "540",
"problem_id": "aime24-21",
"reference_solution": "Let $z=a+bi$ such that $a^2+b^2=4^2=16$ . The expression becomes: \\[(75+117i)(a+bi)+\\dfrac{96+144i}{a+bi}.\\] Call this complex number $w$ . We simplify this expression. \\begin{align*}\nw&=(75+117i)(a+bi)+\\dfrac{96+144i}{a+bi} \... | To find the largest possible real part of the expression \( E = (75+117i)z + \frac{96+144i}{z} \) where \( |z| = 4 \), we start by letting \( z = 4e^{i\theta} \) since \( |z| = 4 \). This allows us to express \( z \) in polar form, which simplifies dealing with multiplication and division by \( z \).
First, compute \(... |
[
{
"content": "Problem: Eight circles of radius $34$ are sequentially tangent, and two of the circles are tangent to $AB$ and $BC$ of triangle $ABC$ , respectively. $2024$ circles of radius $1$ can be arranged in the same manner. The inradius of triangle $ABC$ can be expressed as $\\frac{m}{n}$ , w... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 22 | AIME24 | {
"expected_answer": "197",
"problem_id": "aime24-22",
"reference_solution": "Draw an altitude from both end circles of the diagram with the circles of radius one, and call the lengths you get drawing the altitudes of the circles down to $BC$ $a$ and $b$ . Now we have the length of side $BC$ of being $(2)... | To solve this problem, we need to determine the inradius of triangle \(ABC\) given the configuration of circles. Let's start by understanding the setup.
First, there are 8 circles of radius 34 arranged such that two of them are tangent to sides \(AB\) and \(BC\) respectively. The remaining 6 circles are placed between... |
[
{
"content": "Problem: Let $A$ , $B$ , $C$ , and $D$ be points on the hyperbola $\\frac{x^2}{20}- \\frac{y^2}{24} = 1$ such that $ABCD$ is a rhombus whose diagonals intersect at the origin. Find the greatest real number that is less than $BD^2$ for all such rhombi.\nMark your solution with \\boxed\nA... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 23 | AIME24 | {
"expected_answer": "480",
"problem_id": "aime24-23",
"reference_solution": "A quadrilateral is a rhombus if and only if its two diagonals bisect each other and are perpendicular to each other. The first condition is automatically satisfied because of the hyperbola's symmetry about the origin. To satisfy the sec... | To solve the problem, we start by understanding the given hyperbola \(\frac{x^2}{20} - \frac{y^2}{24} = 1\). The rhombus \(ABCD\) has diagonals intersecting at the origin, which is the center of the hyperbola. Since the diagonals of a rhombus bisect each other at right angles, the origin must be the midpoint of both di... |
[
{
"content": "Problem: Let $ABC$ be a triangle inscribed in circle $\\omega$ . Let the tangents to $\\omega$ at $B$ and $C$ intersect at point $D$ , and let $\\overline{AD}$ intersect $\\omega$ at $P$ . If $AB=5$ , $BC=9$ , and $AC=10$ , $AP$ can be written as the form $\\frac{m}{n}$ , wher... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 24 | AIME24 | {
"expected_answer": "113",
"problem_id": "aime24-24",
"reference_solution": "From the tangency condition we have $\\let\\angle BCD = \\let\\angle CBD = \\let\\angle A$ . With LoC we have $\\cos(A) = \\frac{25+100-81}{2*5*10} = \\frac{11}{25}$ and $\\cos(B) = \\frac{81+25-100}{2*9*5} = \\frac{1}{15}$ . Then, ... | To solve for \( AP \) in the given triangle \( ABC \) inscribed in circle \( \omega \), we start by noting that point \( D \) is the intersection of the tangents to \( \omega \) at \( B \) and \( C \). This makes \( D \) the excenter opposite \( A \), and \( AD \) is the angle bisector of \( \angle BAC \). By the Angle... |
[
{
"content": "Problem: Each vertex of a regular octagon is independently colored either red or blue with equal probability. The probability that the octagon can then be rotated so that all of the blue vertices end up at positions where there were originally red vertices is $\\tfrac{m}{n}$ , where $m$ and $n... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 25 | AIME24 | {
"expected_answer": "371",
"problem_id": "aime24-25",
"reference_solution": "Notice that the question's condition mandates all blues to go to reds, but reds do not necessarily have to go to blue. Let us do casework on how many blues there are. If there are no blues whatsoever, there is only one case. This case i... | To solve this problem, we need to determine the probability that a regular octagon with vertices colored red or blue can be rotated such that all blue vertices were originally in positions that are now red. This is equivalent to saying that the set of blue vertices must form a subset that is invariant under some rotati... |
[
{
"content": "Problem: Define $f(x)=|| x|-\\tfrac{1}{2}|$ and $g(x)=|| x|-\\tfrac{1}{4}|$ . Find the number of intersections of the graphs of \\[y=4 g(f(\\sin (2 \\pi x))) \\quad\\text{ and }\\quad x=4 g(f(\\cos (3 \\pi y))).\\]\nMark your solution with \\boxed\nAnswer:",
"role": "user"
}
] | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 26 | AIME24 | {
"expected_answer": "385",
"problem_id": "aime24-26",
"reference_solution": "If we graph $4g(f(x))$ , we see it forms a sawtooth graph that oscillates between $0$ and $1$ (for values of $x$ between $-1$ and $1$ , which is true because the arguments are between $-1$ and $1$ ). Thus by precariously dr... | To solve the problem, we need to find the number of intersections between the graphs \( y = 4g(f(\sin(2\pi x))) \) and \( x = 4g(f(\cos(3\pi y))) \). Let's break this down step by step.
First, let's understand the functions involved:
- \( f(x) = \left| |x| - \frac{1}{2} \right| \)
- \( g(x) = \left| |x| - \frac{1}{4} ... |
[
{
"content": "Problem: Let $p$ be the least prime number for which there exists a positive integer $n$ such that $n^{4}+1$ is divisible by $p^{2}$ . Find the least positive integer $m$ such that $m^{4}+1$ is divisible by $p^{2}$ .\nMark your solution with \\boxed\nAnswer:",
"role": "user"
}
] | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 27 | AIME24 | {
"expected_answer": "110",
"problem_id": "aime24-27",
"reference_solution": "If \\(p=2\\), then \\(4\\mid n^4+1\\) for some integer \\(n\\). But \\(\\left(n^2\\right)^2\\equiv0\\) or \\(1\\pmod4\\), so it is impossible. Thus \\(p\\) is an odd prime. For integer \\(n\\) such that \\(p^2\\mid n^4+1\\), we have \\(... | To solve this problem, we need to find the smallest prime \( p \) such that there exists a positive integer \( n \) where \( p^2 \) divides \( n^4 + 1 \). Then, we need to find the smallest \( m \) where \( m^4 + 1 \) is divisible by \( p^2 \).
**Step 1: Determine the smallest prime \( p \)**
We start by checking prim... |
[
{
"content": "Problem: Let $ABCD$ be a tetrahedron such that $AB=CD= \\sqrt{41}$ , $AC=BD= \\sqrt{80}$ , and $BC=AD= \\sqrt{89}$ . There exists a point $I$ inside the tetrahedron such that the distances from $I$ to each of the faces of the tetrahedron are all equal. This distance can be written in the ... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 28 | AIME24 | {
"expected_answer": "104",
"problem_id": "aime24-28",
"reference_solution": "Notice that \\(41=4^2+5^2\\), \\(89=5^2+8^2\\), and \\(80=8^2+4^2\\), let \\(A~(0,0,0)\\), \\(B~(4,5,0)\\), \\(C~(0,5,8)\\), and \\(D~(4,0,8)\\). Then the plane \\(BCD\\) has a normal\n\\begin{equation*}\n\\mathbf n:=\\frac14\\overright... | To solve this problem, we need to find the distance from the point \( I \) (the incenter) to each face of the tetrahedron \( ABCD \). The key property here is that all these distances are equal, which implies that \( I \) is the incenter of the tetrahedron. However, for a general tetrahedron, the incenter may not exist... |
[
{
"content": "Problem: Let $\\mathcal{B}$ be the set of rectangular boxes with surface area $54$ and volume $23$ . Let $r$ be the radius of the smallest sphere that can contain each of the rectangular boxes that are elements of $\\mathcal{B}$ . The value of $r^2$ can be written as $\\frac{p}{q}$ , wh... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 29 | AIME24 | {
"expected_answer": "721",
"problem_id": "aime24-29",
"reference_solution": "Observe that the \"worst\" possible box is one of the maximum possible length. \nBy symmetry, the height and the width are the same in this antioptimal box. (If the height and width weren't the same, the extra difference between them co... | To solve for the radius \( r \) of the smallest sphere that can contain all rectangular boxes in the set \( \mathcal{B} \), we need to find the maximum distance from the center of the box to any of its vertices. This distance is the radius of the circumscribed sphere. For a rectangular box with dimensions \( a \times b... |
[
{
"content": "Problem: Among the 900 residents of Aimeville, there are 195 who own a diamond ring, 367 who own a set of golf clubs, and 562 who own a garden spade. In addition, each of the 900 residents owns a bag of candy hearts. There are 437 residents who own exactly two of these things, and 234 residents wh... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 2,
"temperature": 0.7
} | 2 | 0 | AIME24 | {
"expected_answer": "73",
"problem_id": "aime24-0",
"reference_solution": "Let $w,x,y,z$ denote the number of residents who own 1,2,3 and 4 of these items, respectively. We know $w+x+y+z=900$ , since there are 900 residents in total. This simplifies to $w+z=229$ , since we know $x=437$ and $y=234$ . Now, w... | To solve this problem, we can use the principle of inclusion-exclusion. Let's denote the sets as follows:
- \( D \): residents who own a diamond ring,
- \( G \): residents who own golf clubs,
- \( S \): residents who own a garden spade,
- \( C \): residents who own a bag of candy hearts (which everyone owns, so it's th... |
[
{
"content": "Problem: A list of positive integers has the following properties: $\\bullet$ The sum of the items in the list is $30$ . $\\bullet$ The unique mode of the list is $9$ . $\\bullet$ The median of the list is a positive integer that does not appear in the list itself. Find the sum of the squares... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 2,
"temperature": 0.7
} | 2 | 1 | AIME24 | {
"expected_answer": "236",
"problem_id": "aime24-1",
"reference_solution": "The third condition implies that the list's size must be an even number, as if it were an odd number, the median of the list would surely appear in the list itself. Therefore, we can casework on what even numbers work. Say the size is 2.... | To solve this problem, we need to determine a list of positive integers that satisfy three conditions: the sum is 30, the unique mode is 9, and the median is a positive integer not in the list. We aim to find the sum of the squares of all items in the list.
First, let's recall that the mode is the most frequent number... |
[
{
"content": "Problem: Find the number of ways to place a digit in each cell of a 2x3 grid so that the sum of the two numbers formed by reading left to right is $999$ , and the sum of the three numbers formed by reading top to bottom is $99$ . The grid below is an example of such an arrangement because $8+99... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 2,
"temperature": 0.7
} | 2 | 2 | AIME24 | {
"expected_answer": "45",
"problem_id": "aime24-2",
"reference_solution": "Consider this table: $\\begin{array}{|c|c|c|} \\hline a & b & c \\\\ \\hline d & e & f\\\\ \\hline \\end{array}$ We note that $c+f = 9$ , because $c+f \\leq 18$ , meaning it never achieves a unit's digit sum of $9$ otherwise. Since no... | To solve this problem, we need to fill a 2x3 grid with digits such that the sum of the two numbers read left to right (i.e., the numbers in the first and second rows) is 999, and the sum of the three numbers read top to bottom (i.e., the digits in each column) is 99. Let's break this down step by step.
First, let's de... |
[
{
"content": "Problem: Let $x,y$ and $z$ be positive real numbers that satisfy the following system of equations:\n \\[\\log_2\\left({x \\over yz}\\right) = {1 \\over 2}\\] \\[\\log_2\\left({y \\over xz}\\right) = {1 \\over 3}\\] \\[\\log_2\\left({z \\over xy}\\right) = {1 \\over 4}\\] \nThen the value of... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 2,
"temperature": 0.7
} | 2 | 3 | AIME24 | {
"expected_answer": "33",
"problem_id": "aime24-3",
"reference_solution": "Denote $\\log_2(x) = a$ , $\\log_2(y) = b$ , and $\\log_2(z) = c$ . Then, we have:\n $a-b-c = \\frac{1}{2}$ \n $-a+b-c = \\frac{1}{3}$ \n $-a-b+c = \\frac{1}{4}$ Now, we can solve to get $a = \\frac{-7}{24}, b = \\frac{-9}{24}, c = \\... | To solve the given system of logarithmic equations, we start by letting \( a = \log_2 x \), \( b = \log_2 y \), and \( c = \log_2 z \). The equations can be rewritten in terms of \( a, b, c \):
1. \( \log_2\left(\frac{x}{yz}\right) = \frac{1}{2} \) becomes \( a - b - c = \frac{1}{2} \).
2. \( \log_2\left(\frac{y}{xz}\... |
[
{
"content": "Problem: Let ABCDEF be a convex equilateral hexagon in which all pairs of opposite sides are parallel. The triangle whose sides are extensions of segments AB, CD, and EF has side lengths 200, 240, and 300. Find the side length of the hexagon.\nMark your solution with \\boxed\nAnswer:",
"role":... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 2,
"temperature": 0.7
} | 2 | 4 | AIME24 | {
"expected_answer": "80",
"problem_id": "aime24-4",
"reference_solution": "Draw a good diagram!\nLet $AF \\cap BC$ , $BC \\cap DE$ , and $AF \\cap DE$ be K, L, and M, respectively. Let $KL=200, KM=300, ML=240$ . Notice that all smaller triangles formed are all similar to the larger $(200,240,300)$ triangl... | To solve for the side length of the convex equilateral hexagon \(ABCDEF\) where all pairs of opposite sides are parallel, we start by noting the properties of such a hexagon. Since opposite sides are parallel and the hexagon is equilateral, it must be a regular hexagon. However, the problem states it's convex and equil... |
[
{
"content": "Problem: Alice chooses a set $A$ of positive integers. Then Bob lists all finite nonempty sets $B$ of positive integers with the property that the maximum element of $B$ belongs to $A$ . Bob's list has 2024 sets. Find the sum of the elements of A.\nMark your solution with \\boxed\nAnswer:",... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 2,
"temperature": 0.7
} | 2 | 5 | AIME24 | {
"expected_answer": "55",
"problem_id": "aime24-5",
"reference_solution": "Let $k$ be one of the elements in Alices set $A$ of positive integers. The number of sets that Bob lists with the property that their maximum element is k is $2^{k-1}$ , since every positive integer less than k can be in the set or o... | To solve this problem, we need to determine the set \( A \) such that the number of finite nonempty subsets \( B \) of positive integers where the maximum element of \( B \) belongs to \( A \) is exactly 2024. We need to find the sum of the elements of \( A \).
First, let's think about how Bob's list is formed. For ea... |
[
{
"content": "Problem: Let $N$ be the greatest four-digit positive integer with the property that whenever one of its digits is changed to $1$ , the resulting number is divisible by $7$ . Let $Q$ and $R$ be the quotient and remainder, respectively, when $N$ is divided by $1000$ . Find $Q+R$ .\nMark ... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 2,
"temperature": 0.7
} | 2 | 6 | AIME24 | {
"expected_answer": "699",
"problem_id": "aime24-6",
"reference_solution": "We note that by changing a digit to $1$ for the number $\\overline{abcd}$ , we are subtracting the number by either $1000(a-1)$ , $100(b-1)$ , $10(c-1)$ , or $d-1$ . Thus, $1000a + 100b + 10c + d \\equiv 1000(a-1) \\equiv 100(b-1... | To solve this problem, we need to find the largest four-digit number \( N \) such that changing any one digit to 1 results in a number divisible by 7. Then, we have to compute \( Q + R \) where \( Q \) and \( R \) are the quotient and remainder when \( N \) is divided by 1000.
First, let's understand the condition: fo... |
[
{
"content": "Problem: Torus $T$ is the surface produced by revolving a circle with radius $3$ around an axis in the plane of the circle that is a distance $6$ from the center of the circle (so like a donut). Let $S$ be a sphere with a radius $11$ . When $T$ rests on the inside of $S$ , it is intern... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 2,
"temperature": 0.7
} | 2 | 7 | AIME24 | {
"expected_answer": "127",
"problem_id": "aime24-7",
"reference_solution": "First, let's consider a section $\\mathcal{P}$ of the solids, along the axis.\nBy some 3D-Geomerty thinking, we can simply know that the axis crosses the sphere center. So, that is saying, the $\\mathcal{P}$ we took crosses one of th... | To solve this problem, we need to determine the radii \( r_i \) and \( r_o \) where the torus is internally and externally tangent to the sphere, respectively. Let's break down the problem step by step.
### 1. **Understanding the Torus Structure**
- The torus \( T \) is generated by revolving a circle of radius \( ... |
[
{
"content": "Problem: There is a collection of $25$ indistinguishable white chips and $25$ indistinguishable black chips. Find the number of ways to place some of these chips in the $25$ unit cells of a $5\\times5$ grid such that: each cell contains at most one chip all chips in the same row and all ch... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 2,
"temperature": 0.7
} | 2 | 8 | AIME24 | {
"expected_answer": "902",
"problem_id": "aime24-8",
"reference_solution": "The problem says \"some\", so not all cells must be occupied.\nWe start by doing casework on the column on the left. There can be 5,4,3,2, or 1 black chip. The same goes for white chips, so we will multiply by 2 at the end. There is $1$... | To solve this problem, we need to determine the number of ways to place 25 white and 25 black chips on a \(5 \times 5\) grid with specific constraints. Let's break down the requirements:
1. **Each cell contains at most one chip.**
2. **All chips in the same row and column must have the same color.**
3. **No additional... |
[
{
"content": "Problem: Let $\\triangle ABC$ have circumcenter $O$ and incenter $I$ with $\\overline{IA}\\perp\\overline{OI}$ , circumradius $13$ , and inradius $6$ . Find $AB\\cdot AC$ .\nMark your solution with \\boxed\nAnswer:",
"role": "user"
}
] | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 2,
"temperature": 0.7
} | 2 | 9 | AIME24 | {
"expected_answer": "468",
"problem_id": "aime24-9",
"reference_solution": "By Euler's formula $OI^{2}=R(R-2r)$ , we have $OI^{2}=13(13-12)=13$ . Thus, by the Pythagorean theorem, $AI^{2}=13^{2}-13=156$ . Let $AI\\cap(ABC)=M$ ; notice $\\triangle AOM$ is isosceles and $\\overline{OI}\\perp\\overline{AM}$ ... | To solve for \( AB \cdot AC \) given that \( \overline{IA} \perp \overline{OI} \), \( R = 13 \), and \( r = 6 \), we start by recalling some geometric properties and formulas.
First, the circumradius \( R = 13 \) and inradius \( r = 6 \). The formula relating the inradius, circumradius, and sides of the triangle is:
... |
[
{
"content": "Problem: Find the number of triples of nonnegative integers $(a,b,c)$ satisfying $a + b + c = 300$ and\n \\[a^2b + a^2c + b^2a + b^2c + c^2a + c^2b = 6,000,000.\\]\nMark your solution with \\boxed\nAnswer:",
"role": "user"
}
] | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 2,
"temperature": 0.7
} | 2 | 10 | AIME24 | {
"expected_answer": "601",
"problem_id": "aime24-10",
"reference_solution": "$ab(a+b)+bc(b+c)+ac(a+c)=300(ab+bc+ac)-3abc=6000000, 100(ab+bc+ac)-abc=2000000$ Note that \n $(100-a)(100-b)(100-c)=1000000-10000(a+b+c)+100(ab+bc+ac)-abc=0$ . Thus, $a/b/c=100$ . There are $201$ cases for each but we need to subtrac... | To solve the problem, we start with the equation \(a + b + c = 300\) and the condition \(a^2b + a^2c + b^2a + b^2c + c^2a + c^2b = 6,000,000\). Notice that the left-hand side can be factored. Let's rewrite it:
\[
a^2b + a^2c + b^2a + b^2c + c^2a + c^2b = ab(a + b) + bc(b + c) + ca(c + a).
\]
Since \(a + b + c = 300\)... |
[
{
"content": "Problem: Let \\(O=(0,0)\\), \\(A=\\left(\\tfrac{1}{2},0\\right)\\), and \\(B=\\left(0,\\tfrac{\\sqrt{3}}{2}\\right)\\) be points in the coordinate plane. Let \\(\\mathcal{F}\\) be the family of segments \\(\\overline{PQ}\\) of unit length lying in the first quadrant with \\(P\\) on the \\(x\\)-axi... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 2,
"temperature": 0.7
} | 2 | 11 | AIME24 | {
"expected_answer": "23",
"problem_id": "aime24-11",
"reference_solution": "Begin by finding the equation of the line $\\overline{AB}$ : $y= -\\sqrt{3}x+\\frac{\\sqrt{3}}{2}$ Now, consider the general equation of all lines that belong to $\\mathcal{F}$ . Let $P$ be located at $(a,0)$ and $Q$ be located... | To solve this problem, we need to determine the unique point \( C \) on segment \( \overline{AB} \) that is not covered by any unit length segment from the family \( \mathcal{F} \). The points \( A = \left(\frac{1}{2}, 0\right) \) and \( B = \left(0, \frac{\sqrt{3}}{2}\right) \) are given, and \( \overline{AB} \) is a ... |
[
{
"content": "Problem: Let $\\omega\\neq 1$ be a 13th root of unity. Find the remainder when\n \\[\\prod_{k=0}^{12}(2-2\\omega^k+\\omega^{2k})\\] \nis divided by 1000.\nMark your solution with \\boxed\nAnswer:",
"role": "user"
}
] | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 2,
"temperature": 0.7
} | 2 | 12 | AIME24 | {
"expected_answer": "321",
"problem_id": "aime24-12",
"reference_solution": "\\[\\prod_{k=0}^{12} \\left(2- 2\\omega^k + \\omega^{2k}\\right) = \\prod_{k=0}^{12} \\left((1 - \\omega^k)^2 + 1\\right) = \\prod_{k=0}^{12} \\left((1 + i) - \\omega^k)((1 - i) - \\omega^k\\right)\\] Now, we consider the polynomial $x... | To solve the problem, we start by analyzing the given product: \(\prod_{k=0}^{12}(2 - 2\omega^k + \omega^{2k})\) where \(\omega\) is a primitive 13th root of unity. The key here is to relate this product to the cyclotomic polynomials or roots of unity.
First, note that since \(\omega^{13} = 1\) and \(\omega \neq 1\), ... |
[
{
"content": "Problem: Let \\(b\\ge 2\\) be an integer. Call a positive integer \\(n\\) \\(b\\text-\\textit{eautiful}\\) if it has exactly two digits when expressed in base \\(b\\) and these two digits sum to \\(\\sqrt n\\). For example, \\(81\\) is \\(13\\text-\\textit{eautiful}\\) because \\(81 = \\underlin... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 2,
"temperature": 0.7
} | 2 | 13 | AIME24 | {
"expected_answer": "211",
"problem_id": "aime24-13",
"reference_solution": "We write the base- $b$ two-digit integer as $\\left( xy \\right)_b$ .\nThus, this number satisfies\n \\[ \\left( x + y \\right)^2 = b x + y \\] \nwith $x \\in \\left\\{ 1, 2, \\cdots , b-1 \\right\\}$ and $y \\in \\left\\{ 0, 1, \\... | To determine the least integer \( b \ge 2 \) for which there are more than ten \( b \)-beautiful integers, we start by understanding the definition: a positive integer \( n \) is \( b \)-beautiful if it has exactly two digits in base \( b \), and the sum of these digits equals \( \sqrt{n} \). Let's break this down step... |
[
{
"content": "Problem: Find the number of rectangles that can be formed inside a fixed regular dodecagon ( $12$ -gon) where each side of the rectangle lies on either a side or a diagonal of the dodecagon. The diagram below shows three of those rectangles. [asy] unitsize(0.6 inch); for(int i=0; i<360; i+=30) { d... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 2,
"temperature": 0.7
} | 2 | 14 | AIME24 | {
"expected_answer": "315",
"problem_id": "aime24-14",
"reference_solution": "By Furaken There are two kinds of such rectangles: those whose sides are parallel to some edges of the regular 12-gon (Case 1), and those whose sides are not (Case 2). For Case 1, WLOG assume that the rectangle's sides are horizontal an... | To determine the number of rectangles that can be formed inside a fixed regular dodecagon (12-gon) where each side of the rectangle lies on either a side or a diagonal of the dodecagon, we need to analyze the possible rectangles. Each rectangle must have sides parallel to the sides or diagonals of the dodecagon. Since ... |
[
{
"content": "Problem: Every morning Aya goes for a $9$ -kilometer-long walk and stops at a coffee shop afterwards. When she walks at a constant speed of $s$ kilometers per hour, the walk takes her 4 hours, including $t$ minutes spent in the coffee shop. When she walks $s+2$ kilometers per hour, the walk... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 2,
"temperature": 0.7
} | 2 | 15 | AIME24 | {
"expected_answer": "204",
"problem_id": "aime24-15",
"reference_solution": "$\\frac{9}{s} + t = 4$ in hours and $\\frac{9}{s+2} + t = 2.4$ in hours. Subtracting the second equation from the first, we get, $\\frac{9}{s} - \\frac{9}{s+2} = 1.6$ Multiplying by $(s)(s+2)$ , we get $9s+18-9s=18=1.6s^{2} + 3.2s$ ... | To solve the problem, we need to determine Aya's walking speed \( s \) and the time \( t \) she spends in the coffee shop. Then, we'll use that information to find the total time when her speed is \( s + \frac{1}{2} \).
First, let's break down the given information:
1. **When walking at speed \( s \):**
- Total ti... |
[
{
"content": "Problem: There exist real numbers $x$ and $y$ , both greater than 1, such that $\\log_x\\left(y^x\\right)=\\log_y\\left(x^{4y}\\right)=10$ . Find $xy$ .\nMark your solution with \\boxed\nAnswer:",
"role": "user"
}
] | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 2,
"temperature": 0.7
} | 2 | 16 | AIME24 | {
"expected_answer": "25",
"problem_id": "aime24-16",
"reference_solution": "By properties of logarithms, we can simplify the given equation to $x\\log_xy=4y\\log_yx=10$ . Let us break this into two separate equations: \\[x\\log_xy=10\\] \n \\[4y\\log_yx=10.\\] \nWe multiply the two equations to get: \n \\[4xy\\... | To solve the problem, we start with the given equations:
\[
\log_x(y^x) = 10 \quad \text{and} \quad \log_y(x^{4y}) = 10.
\]
First, simplify each logarithmic expression. Using the logarithm power rule \(\log_b(a^c) = c \log_b(a)\), we rewrite both equations:
1. \(\log_x(y^x) = x \log_x(y) = 10\)
2. \(\log_y(x^{4y}) =... |
[
{
"content": "Problem: Alice and Bob play the following game. A stack of $n$ tokens lies before them. The players take turns with Alice going first. On each turn, the player removes either $1$ token or $4$ tokens from the stack. Whoever removes the last token wins. Find the number of positive integers $n... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 2,
"temperature": 0.7
} | 2 | 17 | AIME24 | {
"expected_answer": "809",
"problem_id": "aime24-17",
"reference_solution": "Let's first try some experimentation. Alice obviously wins if there is one coin. She will just take it and win. If there are 2 remaining, then Alice will take one and then Bob will take one, so Bob wins. If there are $3$ , Alice will t... | To determine the number of positive integers \( n \leq 2024 \) where Bob can guarantee a win regardless of Alice's play, we need to analyze the game's winning positions. Let's define \( W \) as a winning position (where the player whose turn it is can force a win) and \( L \) as a losing position (where any move leads ... |
[
{
"content": "Problem: Jen enters a lottery by picking $4$ distinct numbers from $S=\\{1,2,3,\\cdots,9,10\\}.$ $4$ numbers are randomly chosen from $S.$ She wins a prize if at least two of her numbers were $2$ of the randomly chosen numbers, and wins the grand prize if all four of her numbers were the... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 2,
"temperature": 0.7
} | 2 | 18 | AIME24 | {
"expected_answer": "116",
"problem_id": "aime24-18",
"reference_solution": "This is a conditional probability problem. Bayes' Theorem states that \n \\[P(A|B)=\\dfrac{P(B|A)\\cdot P(A)}{P(B)}\\] in other words, the probability of $A$ given $B$ is equal to the probability of $B$ given $A$ times the proba... | To solve this problem, we need to use conditional probability. The key is to find the probability of winning the grand prize (i.e., matching all 4 numbers) given that she already won a prize (i.e., matched at least 2 numbers). Let's break it down step by step.
First, let's define the events:
- \( A \): Jen wins a priz... |
[
{
"content": "Problem: Rectangles $ABCD$ and $EFGH$ are drawn such that $D,E,C,F$ are collinear. Also, $A,D,H,G$ all lie on a circle. If $BC=16$ , $AB=107$ , $FG=17$ , and $EF=184$ , what is the length of $CE$ ? [asy] import graph; unitsize(0.1cm); pair A = (0,0);pair B = (70,0);pair C = (70,16);pai... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 2,
"temperature": 0.7
} | 2 | 19 | AIME24 | {
"expected_answer": "104",
"problem_id": "aime24-19",
"reference_solution": "We use simple geometry to solve this problem. [asy] import graph; unitsize(0.1cm); pair A = (0,0);pair B = (107,0);pair C = (107,16);pair D = (0,16);pair E = (3,16);pair F = (187,16);pair G = (187,33);pair H = (3,33); label(\"$A$\", A,... | To solve for the length of \( CE \), we start by analyzing the given geometric configuration. Let's break down the problem step by step.
**Step 1: Understand the Setup**
- Rectangles \(ABCD\) and \(EFGH\) are drawn such that points \(D, E, C, F\) are collinear.
- Points \(A, D, H, G\) lie on a circle.
- Given dimensio... |
[
{
"content": "Problem: Consider the paths of length $16$ that follow the lines from the lower left corner to the upper right corner on an $8\\times 8$ grid. Find the number of such paths that change direction exactly four times, as in the examples shown below. [asy] size(10cm); usepackage(\"tikz\");label(\"... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 2,
"temperature": 0.7
} | 2 | 20 | AIME24 | {
"expected_answer": "294",
"problem_id": "aime24-20",
"reference_solution": "We divide the path into eight “ $R$ ” movements and eight “ $U$ ” movements. Five sections of alternative $RURUR$ or $URURU$ are necessary in order to make four “turns.” We use the first case and multiply by $2$ . <br/>\nFor $U$ ,... | To solve the problem of finding the number of paths of length 16 on an 8x8 grid that change direction exactly four times, we need to break down the problem step by step.
First, let's understand the structure of such a path. A path from the lower left to the upper right of an 8x8 grid (which has 9 rows and 9 columns of... |
[
{
"content": "Problem: Find the largest possible real part of \\[(75+117i)z+\\frac{96+144i}{z}\\] where $z$ is a complex number with $|z|=4$ .\nMark your solution with \\boxed\nAnswer:",
"role": "user"
}
] | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 2,
"temperature": 0.7
} | 2 | 21 | AIME24 | {
"expected_answer": "540",
"problem_id": "aime24-21",
"reference_solution": "Let $z=a+bi$ such that $a^2+b^2=4^2=16$ . The expression becomes: \\[(75+117i)(a+bi)+\\dfrac{96+144i}{a+bi}.\\] Call this complex number $w$ . We simplify this expression. \\begin{align*}\nw&=(75+117i)(a+bi)+\\dfrac{96+144i}{a+bi} \... | To solve the problem of finding the largest possible real part of the expression \((75+117i)z + \frac{96+144i}{z}\) where \(|z|=4\), we start by letting \(z = 4e^{i\theta}\) since \(|z|=4\). This parametrization simplifies the problem because \(z\) is on a circle of radius 4 in the complex plane.
First, express the gi... |
[
{
"content": "Problem: Eight circles of radius $34$ are sequentially tangent, and two of the circles are tangent to $AB$ and $BC$ of triangle $ABC$ , respectively. $2024$ circles of radius $1$ can be arranged in the same manner. The inradius of triangle $ABC$ can be expressed as $\\frac{m}{n}$ , w... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 2,
"temperature": 0.7
} | 2 | 22 | AIME24 | {
"expected_answer": "197",
"problem_id": "aime24-22",
"reference_solution": "Draw an altitude from both end circles of the diagram with the circles of radius one, and call the lengths you get drawing the altitudes of the circles down to $BC$ $a$ and $b$ . Now we have the length of side $BC$ of being $(2)... | To solve this problem, we need to determine the inradius of triangle \(ABC\) given the arrangement of circles. Let's start by understanding the setup.
First, we have eight circles of radius \(34\) arranged such that two of them are tangent to the sides \(AB\) and \(BC\) of triangle \(ABC\), and the rest are tangent to... |
[
{
"content": "Problem: Let $A$ , $B$ , $C$ , and $D$ be points on the hyperbola $\\frac{x^2}{20}- \\frac{y^2}{24} = 1$ such that $ABCD$ is a rhombus whose diagonals intersect at the origin. Find the greatest real number that is less than $BD^2$ for all such rhombi.\nMark your solution with \\boxed\nA... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 2,
"temperature": 0.7
} | 2 | 23 | AIME24 | {
"expected_answer": "480",
"problem_id": "aime24-23",
"reference_solution": "A quadrilateral is a rhombus if and only if its two diagonals bisect each other and are perpendicular to each other. The first condition is automatically satisfied because of the hyperbola's symmetry about the origin. To satisfy the sec... | To solve the problem, we start by noting that the hyperbola given is \(\frac{x^2}{20} - \frac{y^2}{24} = 1\). The diagonals of the rhombus \(ABCD\) intersect at the origin, which is also the center of the hyperbola. Since the diagonals of a rhombus bisect each other at right angles, the origin must be the midpoint of b... |
[
{
"content": "Problem: Let $ABC$ be a triangle inscribed in circle $\\omega$ . Let the tangents to $\\omega$ at $B$ and $C$ intersect at point $D$ , and let $\\overline{AD}$ intersect $\\omega$ at $P$ . If $AB=5$ , $BC=9$ , and $AC=10$ , $AP$ can be written as the form $\\frac{m}{n}$ , wher... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 2,
"temperature": 0.7
} | 2 | 24 | AIME24 | {
"expected_answer": "113",
"problem_id": "aime24-24",
"reference_solution": "From the tangency condition we have $\\let\\angle BCD = \\let\\angle CBD = \\let\\angle A$ . With LoC we have $\\cos(A) = \\frac{25+100-81}{2*5*10} = \\frac{11}{25}$ and $\\cos(B) = \\frac{81+25-100}{2*9*5} = \\frac{1}{15}$ . Then, ... | To solve for \( AP \) in the given triangle \( ABC \) inscribed in circle \( \omega \), we start by understanding the configuration. Point \( D \) is the intersection of the tangents to \( \omega \) at \( B \) and \( C \). This makes \( D \) the ex-point of the circle with respect to \( \triangle ABC \), and \( AD \) i... |
[
{
"content": "Problem: Each vertex of a regular octagon is independently colored either red or blue with equal probability. The probability that the octagon can then be rotated so that all of the blue vertices end up at positions where there were originally red vertices is $\\tfrac{m}{n}$ , where $m$ and $n... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 2,
"temperature": 0.7
} | 2 | 25 | AIME24 | {
"expected_answer": "371",
"problem_id": "aime24-25",
"reference_solution": "Notice that the question's condition mandates all blues to go to reds, but reds do not necessarily have to go to blue. Let us do casework on how many blues there are. If there are no blues whatsoever, there is only one case. This case i... | To solve this problem, we need to determine the probability that a regular octagon with each vertex independently colored red or blue (each with probability \( \frac{1}{2} \)) can be rotated such that all blue vertices originally occupied positions that were red. This is equivalent to saying that the set of blue vertic... |
[
{
"content": "Problem: Define $f(x)=|| x|-\\tfrac{1}{2}|$ and $g(x)=|| x|-\\tfrac{1}{4}|$ . Find the number of intersections of the graphs of \\[y=4 g(f(\\sin (2 \\pi x))) \\quad\\text{ and }\\quad x=4 g(f(\\cos (3 \\pi y))).\\]\nMark your solution with \\boxed\nAnswer:",
"role": "user"
}
] | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 2,
"temperature": 0.7
} | 2 | 26 | AIME24 | {
"expected_answer": "385",
"problem_id": "aime24-26",
"reference_solution": "If we graph $4g(f(x))$ , we see it forms a sawtooth graph that oscillates between $0$ and $1$ (for values of $x$ between $-1$ and $1$ , which is true because the arguments are between $-1$ and $1$ ). Thus by precariously dr... | To solve the problem, we need to determine the number of intersections between the graphs of \( y = 4g(f(\sin(2\pi x))) \) and \( x = 4g(f(\cos(3\pi y))) \). Let's break this down step by step.
First, let's understand the functions \( f \) and \( g \):
- \( f(x) = \left| |x| - \frac{1}{2} \right| \)
- \( g(x) = \left|... |
[
{
"content": "Problem: Let $p$ be the least prime number for which there exists a positive integer $n$ such that $n^{4}+1$ is divisible by $p^{2}$ . Find the least positive integer $m$ such that $m^{4}+1$ is divisible by $p^{2}$ .\nMark your solution with \\boxed\nAnswer:",
"role": "user"
}
] | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 2,
"temperature": 0.7
} | 2 | 27 | AIME24 | {
"expected_answer": "110",
"problem_id": "aime24-27",
"reference_solution": "If \\(p=2\\), then \\(4\\mid n^4+1\\) for some integer \\(n\\). But \\(\\left(n^2\\right)^2\\equiv0\\) or \\(1\\pmod4\\), so it is impossible. Thus \\(p\\) is an odd prime. For integer \\(n\\) such that \\(p^2\\mid n^4+1\\), we have \\(... | To solve the problem, we need to find the least prime \( p \) such that there exists a positive integer \( n \) where \( p^2 \) divides \( n^4 + 1 \). Then, determine the least positive integer \( m \) for which \( m^4 + 1 \) is divisible by \( p^2 \).
**Step 1: Find the smallest prime \( p \) where \( p^2 \) divides ... |
[
{
"content": "Problem: Let $ABCD$ be a tetrahedron such that $AB=CD= \\sqrt{41}$ , $AC=BD= \\sqrt{80}$ , and $BC=AD= \\sqrt{89}$ . There exists a point $I$ inside the tetrahedron such that the distances from $I$ to each of the faces of the tetrahedron are all equal. This distance can be written in the ... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 2,
"temperature": 0.7
} | 2 | 28 | AIME24 | {
"expected_answer": "104",
"problem_id": "aime24-28",
"reference_solution": "Notice that \\(41=4^2+5^2\\), \\(89=5^2+8^2\\), and \\(80=8^2+4^2\\), let \\(A~(0,0,0)\\), \\(B~(4,5,0)\\), \\(C~(0,5,8)\\), and \\(D~(4,0,8)\\). Then the plane \\(BCD\\) has a normal\n\\begin{equation*}\n\\mathbf n:=\\frac14\\overright... | To solve for the distance from point \( I \) to each face of the tetrahedron \( ABCD \), we start by noting that \( I \) is the incenter of the tetrahedron, meaning it is equidistant from all faces. The distance from \( I \) to each face is the inradius \( r \). The formula for the inradius of a tetrahedron is given by... |
[
{
"content": "Problem: Let $\\mathcal{B}$ be the set of rectangular boxes with surface area $54$ and volume $23$ . Let $r$ be the radius of the smallest sphere that can contain each of the rectangular boxes that are elements of $\\mathcal{B}$ . The value of $r^2$ can be written as $\\frac{p}{q}$ , wh... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 2,
"temperature": 0.7
} | 2 | 29 | AIME24 | {
"expected_answer": "721",
"problem_id": "aime24-29",
"reference_solution": "Observe that the \"worst\" possible box is one of the maximum possible length. \nBy symmetry, the height and the width are the same in this antioptimal box. (If the height and width weren't the same, the extra difference between them co... | To solve the problem, we need to find the smallest radius \( r \) of a sphere that can contain any rectangular box with surface area 54 and volume 23. The key idea is to minimize the sphere's radius, which corresponds to the diagonal of the box. The diagonal \( d \) of a rectangular box with dimensions \( x, y, z \) is... |
[
{
"content": "Problem: Among the 900 residents of Aimeville, there are 195 who own a diamond ring, 367 who own a set of golf clubs, and 562 who own a garden spade. In addition, each of the 900 residents owns a bag of candy hearts. There are 437 residents who own exactly two of these things, and 234 residents wh... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 3,
"temperature": 0.7
} | 3 | 0 | AIME24 | {
"expected_answer": "73",
"problem_id": "aime24-0",
"reference_solution": "Let $w,x,y,z$ denote the number of residents who own 1,2,3 and 4 of these items, respectively. We know $w+x+y+z=900$ , since there are 900 residents in total. This simplifies to $w+z=229$ , since we know $x=437$ and $y=234$ . Now, w... | To solve this problem, we will use the principle of inclusion-exclusion. Let's denote the sets as follows:
- \( D \): residents who own a diamond ring,
- \( G \): residents who own a set of golf clubs,
- \( S \): residents who own a garden spade,
- \( C \): residents who own a bag of candy hearts (which every resident ... |
[
{
"content": "Problem: A list of positive integers has the following properties: $\\bullet$ The sum of the items in the list is $30$ . $\\bullet$ The unique mode of the list is $9$ . $\\bullet$ The median of the list is a positive integer that does not appear in the list itself. Find the sum of the squares... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 3,
"temperature": 0.7
} | 3 | 1 | AIME24 | {
"expected_answer": "236",
"problem_id": "aime24-1",
"reference_solution": "The third condition implies that the list's size must be an even number, as if it were an odd number, the median of the list would surely appear in the list itself. Therefore, we can casework on what even numbers work. Say the size is 2.... | To solve this problem, we need to construct a list of positive integers that satisfy the given conditions and then compute the sum of their squares. Let's break down the conditions step by step.
**Conditions:**
1. The sum of the items is 30.
2. The unique mode is 9.
3. The median is a positive integer not present in t... |
[
{
"content": "Problem: Find the number of ways to place a digit in each cell of a 2x3 grid so that the sum of the two numbers formed by reading left to right is $999$ , and the sum of the three numbers formed by reading top to bottom is $99$ . The grid below is an example of such an arrangement because $8+99... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 3,
"temperature": 0.7
} | 3 | 2 | AIME24 | {
"expected_answer": "45",
"problem_id": "aime24-2",
"reference_solution": "Consider this table: $\\begin{array}{|c|c|c|} \\hline a & b & c \\\\ \\hline d & e & f\\\\ \\hline \\end{array}$ We note that $c+f = 9$ , because $c+f \\leq 18$ , meaning it never achieves a unit's digit sum of $9$ otherwise. Since no... | To solve this problem, we need to fill a 2x3 grid with digits such that the sum of the two numbers formed by reading left to right (i.e., the numbers in the first and second columns) is 999, and the sum of the three numbers formed by reading top to bottom (i.e., the numbers in the first, second, and third columns) is 9... |
[
{
"content": "Problem: Let $x,y$ and $z$ be positive real numbers that satisfy the following system of equations:\n \\[\\log_2\\left({x \\over yz}\\right) = {1 \\over 2}\\] \\[\\log_2\\left({y \\over xz}\\right) = {1 \\over 3}\\] \\[\\log_2\\left({z \\over xy}\\right) = {1 \\over 4}\\] \nThen the value of... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 3,
"temperature": 0.7
} | 3 | 3 | AIME24 | {
"expected_answer": "33",
"problem_id": "aime24-3",
"reference_solution": "Denote $\\log_2(x) = a$ , $\\log_2(y) = b$ , and $\\log_2(z) = c$ . Then, we have:\n $a-b-c = \\frac{1}{2}$ \n $-a+b-c = \\frac{1}{3}$ \n $-a-b+c = \\frac{1}{4}$ Now, we can solve to get $a = \\frac{-7}{24}, b = \\frac{-9}{24}, c = \\... | To solve the given system of logarithmic equations, let's start by translating each equation into exponential form. Let’s denote \( \log_2(a) = k \) as \( a = 2^k \). The first equation is:
\[
\log_2\left(\frac{x}{yz}\right) = \frac{1}{2} \implies \frac{x}{yz} = 2^{1/2} = \sqrt{2}.
\]
Similarly, the second equation:
... |
[
{
"content": "Problem: Let ABCDEF be a convex equilateral hexagon in which all pairs of opposite sides are parallel. The triangle whose sides are extensions of segments AB, CD, and EF has side lengths 200, 240, and 300. Find the side length of the hexagon.\nMark your solution with \\boxed\nAnswer:",
"role":... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 3,
"temperature": 0.7
} | 3 | 4 | AIME24 | {
"expected_answer": "80",
"problem_id": "aime24-4",
"reference_solution": "Draw a good diagram!\nLet $AF \\cap BC$ , $BC \\cap DE$ , and $AF \\cap DE$ be K, L, and M, respectively. Let $KL=200, KM=300, ML=240$ . Notice that all smaller triangles formed are all similar to the larger $(200,240,300)$ triangl... | To solve the problem, we start by understanding the structure of the convex equilateral hexagon \(ABCDEF\) where all pairs of opposite sides are parallel. This implies that the hexagon can be divided into three parallelograms: \(ABCD\), \(CDEF\), and \(EFAB\). Since all sides are equal and opposite sides are parallel, ... |
[
{
"content": "Problem: Alice chooses a set $A$ of positive integers. Then Bob lists all finite nonempty sets $B$ of positive integers with the property that the maximum element of $B$ belongs to $A$ . Bob's list has 2024 sets. Find the sum of the elements of A.\nMark your solution with \\boxed\nAnswer:",... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 3,
"temperature": 0.7
} | 3 | 5 | AIME24 | {
"expected_answer": "55",
"problem_id": "aime24-5",
"reference_solution": "Let $k$ be one of the elements in Alices set $A$ of positive integers. The number of sets that Bob lists with the property that their maximum element is k is $2^{k-1}$ , since every positive integer less than k can be in the set or o... | To solve this problem, we need to determine the set \( A \) such that when Bob lists all finite nonempty sets \( B \) where the maximum element of \( B \) is in \( A \), there are exactly 2024 such sets. We need to find the sum of the elements of \( A \).
Let's break this down. Suppose \( A = \{a_1, a_2, \dots, a_k\} ... |
[
{
"content": "Problem: Let $N$ be the greatest four-digit positive integer with the property that whenever one of its digits is changed to $1$ , the resulting number is divisible by $7$ . Let $Q$ and $R$ be the quotient and remainder, respectively, when $N$ is divided by $1000$ . Find $Q+R$ .\nMark ... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 3,
"temperature": 0.7
} | 3 | 6 | AIME24 | {
"expected_answer": "699",
"problem_id": "aime24-6",
"reference_solution": "We note that by changing a digit to $1$ for the number $\\overline{abcd}$ , we are subtracting the number by either $1000(a-1)$ , $100(b-1)$ , $10(c-1)$ , or $d-1$ . Thus, $1000a + 100b + 10c + d \\equiv 1000(a-1) \\equiv 100(b-1... | To solve this problem, we need to find the largest four-digit number \( N \) such that changing any one digit to 1 results in a number divisible by 7. Then, we'll compute \( Q + R \) where \( Q \) and \( R \) are the quotient and remainder when \( N \) is divided by 1000.
**Step 1: Understand the divisibility conditio... |
[
{
"content": "Problem: Torus $T$ is the surface produced by revolving a circle with radius $3$ around an axis in the plane of the circle that is a distance $6$ from the center of the circle (so like a donut). Let $S$ be a sphere with a radius $11$ . When $T$ rests on the inside of $S$ , it is intern... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 3,
"temperature": 0.7
} | 3 | 7 | AIME24 | {
"expected_answer": "127",
"problem_id": "aime24-7",
"reference_solution": "First, let's consider a section $\\mathcal{P}$ of the solids, along the axis.\nBy some 3D-Geomerty thinking, we can simply know that the axis crosses the sphere center. So, that is saying, the $\\mathcal{P}$ we took crosses one of th... | To solve this problem, we need to determine the difference between the internal and external radii of tangency between the torus \( T \) and the sphere \( S \). Let's break down the problem step by step.
### Key Parameters:
- **Torus \( T \):** Revolved around an axis in the plane of a circle with radius \( 3 \), at a... |
[
{
"content": "Problem: There is a collection of $25$ indistinguishable white chips and $25$ indistinguishable black chips. Find the number of ways to place some of these chips in the $25$ unit cells of a $5\\times5$ grid such that: each cell contains at most one chip all chips in the same row and all ch... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 3,
"temperature": 0.7
} | 3 | 8 | AIME24 | {
"expected_answer": "902",
"problem_id": "aime24-8",
"reference_solution": "The problem says \"some\", so not all cells must be occupied.\nWe start by doing casework on the column on the left. There can be 5,4,3,2, or 1 black chip. The same goes for white chips, so we will multiply by 2 at the end. There is $1$... | To solve this problem, we need to determine the number of ways to place 25 white and 25 black chips on a \(5 \times 5\) grid, following two specific rules:
1. Each cell contains at most one chip.
2. In each row and each column, all chips have the same color.
The key here is that every row and column must be monochroma... |
[
{
"content": "Problem: Let $\\triangle ABC$ have circumcenter $O$ and incenter $I$ with $\\overline{IA}\\perp\\overline{OI}$ , circumradius $13$ , and inradius $6$ . Find $AB\\cdot AC$ .\nMark your solution with \\boxed\nAnswer:",
"role": "user"
}
] | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 3,
"temperature": 0.7
} | 3 | 9 | AIME24 | {
"expected_answer": "468",
"problem_id": "aime24-9",
"reference_solution": "By Euler's formula $OI^{2}=R(R-2r)$ , we have $OI^{2}=13(13-12)=13$ . Thus, by the Pythagorean theorem, $AI^{2}=13^{2}-13=156$ . Let $AI\\cap(ABC)=M$ ; notice $\\triangle AOM$ is isosceles and $\\overline{OI}\\perp\\overline{AM}$ ... | To solve for \( AB \cdot AC \) given that \( \overline{IA} \perp \overline{OI} \), with the circumradius \( R = 13 \) and inradius \( r = 6 \), we will use properties of triangle centers and relate them to the given conditions.
First, recall that the circumcenter \( O \) and incenter \( I \) satisfy certain geometric ... |
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