instruction_seed stringlengths 172 4.21k | response_seed stringlengths 379 5k | reasoning stringlengths 2.78k 156k | grok_solution stringlengths 0 14.5k | __original_row_idx int64 0 299 |
|---|---|---|---|---|
convert this code from TypeScript to Go:
```typescript
function findBottomLeftValue(root: TreeNode | null): number {
const result: [number, number] = [0, 0]; // [depth, value]
helper(root, 1, result);
return result[1];
}
function helper(node: TreeNode | null, depth: number, result: [number, number]): void {
if... | ### Pseudocode:
```
FIND-LEFTMOST-VALUE(root):
result[0] = 0 // maximum depth
result[1] = 0 // leftmost value
HELPER(root, 1, result)
return result[1]
HELPER(node, depth, result):
if node is null:
return
if depth > result[0]:
result[0] = depth
result[1] = node.value
... | First, the TypeScript code is finding the bottom-left value in a binary tree. It uses a helper function that traverses the tree, keeping track of depth and updating a result array when it finds a deeper node.
The main function is `findBottomLeftValue`, which takes a root node that could be null. It initializes a resul... | Here is the equivalent Go code for the provided TypeScript function. In Go, we don't have built-in support for tuples or nullables in the same way as TypeScript, so I've used a pointer to an array (`*[2]int`) to mimic the `[number, number]` array in TypeScript. This allows the helper function to modify the result in pl... | 11 |
Please write the following solution using C#:
Given an integer `n`, return `true` _if it is possible to represent_ `n` _as the sum of distinct powers of three._ Otherwise, return `false`.
An integer `y` is a power of three if there exists an integer `x` such that `y == 3x`.
**Example 1:**
**Input:** n = 12
**Output:... | ### Explanation
The algorithm uses a simple approach by iteratively dividing the given number `n` by 3 (the base of the powers of three). During the division process, it checks if any of the remainders of division is 2. If it finds a remainder of 2 at any stage, it immediately returns `false` since having a 2 in the b... | First, I need to check if a given integer n can be represented as the sum of distinct powers of three. Powers of three are like 3^0 = 1, 3^1 = 3, 3^2 = 9, 3^3 = 27, and so on. They must be distinct, meaning no repeating the same power.
From the examples, 12 is 3^1 + 3^2 = 3 + 9, and 91 is 3^0 + 3^2 + 3^4 = 1 + 9 + 81.... | ```csharp
public class Solution {
public bool CheckPowersOfThree(int n) {
while (n > 0) {
int remainder = n % 3;
if (remainder == 2) {
return false;
}
n = n / 3;
}
return true;
}
}
``` | 9 |
translate this code to Go:
```python
def xor_operation(n, start):
xor_result = 0
for i in range(n):
xor_result ^= (start + 2 * i)
return xor_result
```
| ### Pseudocode:
```
MAX_POINTS(points, angle, location):
visible_points = 0
for p in points:
x, y = p[0]-location[0], p[1]-location[1]
if x == 0 and y == 0:
visible_points += 1
elif x == 0:
if (y > 0 and angle >= 90) or (y < 0 and angle <= 90):
vis... | First, the Python code is a function called `xor_operation` that takes two parameters: `n` and `start`. It initializes a variable `xor_result` to 0, then loops from 0 to n-1, and in each iteration, it XORs the current `xor_result` with the value of `start + 2 * i`. Finally, it returns the `xor_result`.
I need to trans... | ```go
package main
func XorOperation(n int, start int) int {
xorResult := 0
for i := 0; i < n; i++ {
xorResult ^= (start + 2 * i)
}
return xorResult
}
```
This Go code is a direct translation of the provided Python function. It uses the `XorOperation` function name to follow Go's camelCase nam... | 22 |
translate this code to Groovy:
```rust
fn find_ball(grid: Vec<Vec<i32>>) -> Vec<i32> {
let m = grid.len();
let n = grid[0].len();
let mut ans = vec![-1; n];
for i in 0..n {
let mut r = 0;
let mut c = i;
while r < m {
if grid[r][c] == 1 {
if c == n - 1... | ### Pseudocode:
```
def findBall(grid):
m, n = len(grid), len(grid[0])
ans = [-1] * n
for i in range(n):
r, c = 0, i
while r < m:
if grid[r][c] == 1:
if c == n - 1 or grid[r][c+1] == -1:
break
c += 1
else:
... | First, the Rust code is a function that takes a grid, which is a vector of vectors of i32, and returns a vector of i32. The function is named find_ball, and it seems to be simulating the path of balls dropping through a grid where each cell has a value of 1 or -1, indicating the direction the ball rolls.
I need to tra... | ```groovy
def findBall(grid) {
int m = grid.size()
int n = grid[0].size()
def ans = (0..<n).collect { -1 }
for (int i = 0; i < n; i++) {
int r = 0
int c = i
while (r < m) {
if (grid[r][c] == 1) {
if (c == n - 1 || grid[r][c + 1] == -1) {
... | 19 |
convert this code to Go:
```python
def removeDuplicateLetters(s):
count = [0] * 256
visited = [False] * 256
st = []
for ch in s:
count[ord(ch)] += 1
for ch in s:
count[ord(ch)] -= 1
if visited[ord(ch)]:
continue
while st and ch < st[-1] and count[ord(st[... | ### Pseudocode:
```
REMOVE-DUPLICATE-LETTERS(s)
count[256] <- 0
visited[256] <- False
st <- Empty Stack
for i <- 1 to length[s]
count[ord(s[i])] <- count[ord(s[i])] + 1
for i <- 1 to length[s]
count[ord(s[i])] <- count[ord(s[i])] - 1
if visited[ord(s[i])] == True
... | First, the Python code is for removing duplicate letters from a string to form the smallest possible lexicographical order. It's using a stack-based approach with counts and visited arrays.
I need to convert this to Go. Go is statically typed, so I'll define types properly. The code uses ASCII characters, so I'll hand... | ```go
package main
import "strings" // Not actually used in this function, but can be imported if needed elsewhere
func removeDuplicateLetters(s string) string {
var count [256]int
var visited [256]bool
var st []byte
// First, count the frequency of each character
for i := 0; i < len(s); i++ {
... | 30 |
Please explain the reasoning behind the following solution and provide code in Lua:
There are several cards **arranged in a row**, and each card has an associated number of points. The points are given in the integer array `cardPoints`.
In one step, you can take one card from the beginning or from the end of the row. ... | ### Explanation
We iterate through the given string `s`. As we iterate, we maintain a frequency map `freq` of each character seen so far. At each step, we check if the size of `freq` is less than or equal to k. If it is, we update the result with the maximum frequency seen so far.
After the loop, if the size of freq ... | First, the problem is about maximizing the sum of points from taking exactly k cards from either end of a row. I can only take cards from the start or the end in each step.
Looking at the examples, in Example 1, with [1,2,3,4,5,6,1] and k=3, the best is to take the last three: 6,5,1 summing to 12. In Example 2, all ch... | It appears there might be some confusion in the query. The problem described initially is about maximizing the score by taking exactly `k` cards from the ends of an array `cardPoints`, but the additional constraints at the end (about unique characters, no repeated characters, and substring length) seem to belong to a d... | 10 |
convert this code to Ruby:
```perl
sub count_square_submatrices {
my ($matrix) = @_;
my $n = scalar(@$matrix);
my $m = scalar(@{$matrix->[0]});
my $count = 0;
for (my $i = 0; $i < $n; $i++) {
for (my $j = 0; $j < $m; $j++) {
if ($matrix->[$i][$j] == 1) {
if ($i ==... | ### Pseudocode:
```
function countSquareSubmatrices(matrix)
n = matrix.rows
m = matrix.columns
count = 0
for i = 0 to n-1
for j = 0 to m-1
if matrix[i][j] == 1
if i == 0 or j == 0
count += 1
else
val = min(matrix... | First, the Perl code is a subroutine called `count_square_submatrices` that takes a matrix as input. The matrix is a 2D array, and it's counting the number of square submatrices where all elements are 1s. It uses dynamic programming to fill in the matrix with values that represent the size of the largest square submatr... | ```ruby
def count_square_submatrices(matrix)
n = matrix.size
if n == 0
return 0
end
m = matrix[0].size
count = 0
(0...n).each do |i|
(0...m).each do |j|
if matrix[i][j] == 1
if i == 0 || j == 0
count += 1
else
val = [matrix[i-1][j], matrix[i][j-1], matrix[i-... | 25 |
Please explain the following problem in detail and provide code in Julia:
Given an array of characters `chars`, compress it using the following algorithm:
Begin with an empty string `s`. For each group of **consecutive repeating characters** in `chars`:
* If the group's length is `1`, append the character to `s`.
*... | ### Explanation
This algorithm iterates through the input array `chars`, for each character, it counts the number of consecutive occurrences (using `count` variable) of that character. Then, the algorithm replaces the current character(s) with the compressed form (the character itself, followed by the count if it is g... | First, I need to compress an array of characters by grouping consecutive repeating characters and storing the compressed version back into the same array. I must return the new length of the array after compression. Also, I have to do this with constant extra space, meaning I can't use additional data structures that g... | ### Explanation of the Problem
The problem requires compressing an array of characters in-place using a specific algorithm that groups consecutive repeating characters. The compressed result must be stored directly in the input array, and the new length of the array after compression must be returned. The algorithm mu... | 0 |
port this code to c++:
```haskell
import qualified Data.Map as Map
findSubstring :: String -> [String] -> [Int]
findSubstring s words
| null s || null words = []
| otherwise =
let wordCount = foldr (\w -> Map.insertWith (+) w 1) Map.empty words
wordLength = length $ head words
... | ### Pseudocode:
```
FIND-SUBSTRING(s, words)
if s is empty or words is empty
return empty list
word_count <- count the frequency of each word in words
word_length <- length of a single word in words
total_words <- total number of words in words
total_length <- word_length * total_words
r... | First, I need to port this Haskell code to C++. The Haskell code defines a function `findSubstring` that takes a string `s` and a list of words, and returns a list of integers representing the starting indices where a concatenation of the words appears in `s` as a substring.
Key parts of the Haskell code:
- It import... | Below is the C++ port of the provided Haskell code. However, there is a potential issue in the original Haskell code that needs addressing. In the Haskell implementation, the `tempWordCount` map is built by iterating over the characters of the substring (since strings in Haskell are lists of characters), but the `wordC... | 4 |
port this code from Mojo to Ruby:
```
sub teach_language(n: int, languages: array[int, array[int]], friendships: array[array[int]]) -> int {
var adjacency_list = build_adjacency_list(languages, friendships);
var min_users = infinity;
for language in 1..n {
var num_users = bfs(adjacency_list, languag... | ### Pseudocode:
```
FUNCTION teach_language(n, languages, friendships):
adjacency_list = build_adjacency_list(languages, friendships)
min_users = infinity
FOR each language in 1 to n:
num_users = bfs(adjacency_list, language)
min_users = min(min_users, num_users)
RETURN min_users
FUNCTI... | First, the code is in Mojo, which seems similar to Python, and I need to port it to Ruby. I know Ruby well, so I should translate each part accurately.
The main function is `teach_language`, which takes `n: int`, `languages: array[int, array[int]]`, and `friendships: array[array[int]]`. In Ruby, arrays are dynamic, so... | ```ruby
require 'set'
def bfs(adjacency_list, start)
visited = Set.new
queue = [start]
while !queue.empty?
curr = queue.shift
unless visited.include?(curr)
visited.add(curr)
adjacency_list[curr].each do |neighbor|
queue.push(neighbor)
end
end
end
visited.size
end
def bu... | 1 |
translate this code from Visual Basic .NET to python:
```vb.net
Function CountHomeworkStudents(startTime As Integer(), endTime As Integer(), queryTime As Integer) As Integer
Dim count As Integer = 0
For i As Integer = 0 To startTime.Length - 1
If startTime(i) <= queryTime AndAlso endTime(i) >= queryTime... | ### Pseudocode:
```
FUNCTION countHomeworkStudents(startTime, endTime, queryTime):
count = 0
FOR i = 0 TO length(startTime) - 1:
IF startTime[i] <= queryTime AND endTime[i] >= queryTime:
count = count + 1
RETURN count
END FUNCTION
```
### Code
```python
def removeLeafNodes(root, target)... | First, the VB.NET code is a function that counts how many students are doing homework at a specific query time. It takes three parameters: startTime, endTime, and queryTime. startTime and endTime are arrays of integers, and queryTime is a single integer.
The function initializes a counter to zero, then loops through e... | Here is the translation of the provided Visual Basic .NET code to Python. The function has been implemented with a similar name and logic, but adapted to Python's syntax and conventions. In Python, we use lists for arrays, and the function is defined without explicit type declarations since Python is dynamically typed.... | 48 |
convert this code to Groovy:
```dart
String makeLargestSpecial(String s) {
int count = 0;
int i = 0;
List<String> subs = [];
for (int j = 0; j < s.length; j++) {
if (s[j] == '1') {
count += 1;
} else {
count -= 1;
}
if (count == 0) {
subs.add("1" + makeLargestSpecial(s.substr... | ### Pseudocode:
```
MAKE-LARGEST-SPECIAL(s)
count = 0
i = 0
subs = empty list
for j = 1 to length(s)
if s[j] == '1'
count = count + 1
else
count = count - 1
if count == 0
subs.append("1" + MAKE-LARGEST-SPECIAL(s[i+1:j]) + "0")
... | First, the Dart code is a function that takes a string `s` and returns a string. It seems to be manipulating a string with '1's and '0's to make the largest possible special string. The function is recursive because it calls itself with a substring.
I need to convert this to Groovy. Groovy is a language that runs on t... | ```groovy
def makeLargestSpecial(String s) {
int count = 0
int i = 0
def subs = []
for (int j = 0; j < s.length(); j++) {
if (s[j] == '1') {
count += 1
} else {
count -= 1
}
if (count == 0) {
subs.add("1" + makeLargestSpec... | 33 |
convert this code to TypeScript:
```erlang
combination_sum(Candidates, Target) ->
find_combinations(0, Target, Candidates).
find_combinations(_, 0, _) ->
[[]];
find_combinations(_, _, []) ->
[];
find_combinations(StartIndex, Remaining, Candidates) ->
Result = [],
Result1 = find_combinations(StartIn... | ### Pseudocode:
```
COMBINATION-SUM(candidates, target)
def FIND-COMBINATIONS(startIndex, remaining)
if remaining = 0
return [[]]
if startIndex = length[candidates] or remaining < 0
return []
result = []
result.extend(FIND-COMBINATIONS(startIndex + 1, remaini... | First, the Erlang code is for finding combinations that sum up to a target using given candidates. It's a recursive function. I need to convert this to TypeScript.
Understanding the Erlang code:
- `combination_sum` is the main function that calls `find_combinations` with initial values.
- `find_combinations` has thr... | Here's the TypeScript conversion of the provided Erlang code. The original Erlang code appears to have some issues (e.g., it always uses the head of the `Candidates` list regardless of `StartIndex`, which could lead to incorrect behavior or infinite recursion). I've addressed these issues in the TypeScript version by u... | 24 |
Please explain the reasoning behind the following solution and provide code in PHP:
You are given an array of strings `equations` that represent relationships between variables where each string `equations[i]` is of length `4` and takes one of two different forms: `"xi==yi "` or `"xi!=yi "`.Here, `xi` and `yi` are lowe... | ### Explanation
The algorithm first creates a mapping of the alien alphabet to their respective orders using a dictionary/map. Then, it loops through the given words, checking if they are sorted lexicographically. It compares each character of the adjacent words using the alien alphabet order. If any unordered pair is... | First, I need to determine if I can assign integers to variables (which are single lowercase letters) such that all the equations are satisfied. The equations are either equality ("==") or inequality ("!=").
From the examples, if there are conflicting equations like "a==b" and "b!=a", it should return false because th... | ### Reasoning Behind the Solution
The problem involves determining whether it is possible to assign integer values to variables (represented by lowercase letters) such that all given equations are satisfied. The equations can be of two types: equality ("xi==yi") or inequality ("xi!=yi"). This is a constraint satisfact... | 5 |
Please write the following solution using Swift:
Given an integer `n`, _return a string with `n` characters such that each character in such string occurs **an odd number of times**_.
The returned string must contain only lowercase English letters. If there are multiples valid strings, return **any** of them.
**Examp... | ### Explanation
The algorithm to solve this problem is straightforward. We initialize the result with a single character (lowercase 'a') repeated `n` times. If the given integer `n` is even, replace the last character with a different character (lowercase 'b') to make sure that each character occurrence is odd. The re... | First, I need to write a Swift function that takes an integer n and returns a string of length n where each character appears an odd number of times. The string should only contain lowercase English letters. If there are multiple possibilities, I can return any one of them.
From the examples, for n=4, "pppz" works bec... | ```swift
func createString(withLength n: Int) -> String {
if n % 2 == 1 {
// If n is odd, return a string of n 'a's
return String(repeating: "a", count: n)
} else {
// If n is even, return a string with (n-1) 'a's and one 'b'
return String(repeating: "a", count: n - 1) + "b"
... | 49 |
Please explain the reasoning behind the following solution and provide code in F#:
Given an integer array `nums`, handle multiple queries of the following types:
1. **Update** the value of an element in `nums`.
2. Calculate the **sum** of the elements of `nums` between indices `left` and `right` **inclusive** where ... | ### Explanation
The algorithm uses a prefix sum array to efficiently answer the range sum queries. The idea is to pre-process the input array by creating an auxiliary array prefixSum, where prefixSum[i] stores the sum of the first i elements. This allows us to compute the sum of elements in a range [left, right] in co... | First, I need to implement a class called NumArray in F# that can handle updates to an array and range sum queries efficiently. The array can be up to 3*10^4 in size, and there can be up to 3*10^4 calls to update and sumRange. A naive approach where I store the array and sum up elements from left to right each time wou... | ### Reasoning Behind the Solution
The problem requires implementing a class `NumArray` that supports two operations: updating an element at a specific index and computing the sum of elements in a given range (inclusive). The constraints indicate that the array size and the number of queries/updates can both be up to 3... | 21 |
convert this code to Julia:
```kotlin
/**
* Definition for a binary tree node.
* class TreeNode(var `val`: Int = 0) {
* var left: TreeNode? = null
* var right: TreeNode? = null
* }
*/
class Solution {
fun sufficientSubset(root: TreeNode?, limit: Int): TreeNode? {
if (root == null) {
... | ### Pseudocode:
```
SUFFICIENT-SUBSET(root, limit)
if root is null
return null
if root.left is null and root.right is null
if root.val < limit
return null
else
return root
root.left = SUFFICIENT-SUBSET(root.left, limit - root.val)
root.right = SUFFICIENT-S... | First, the Kotlin code is for a function that checks if a subset of a binary tree is sufficient based on a limit. It's a recursive function that prunes the tree if the sum of the path is less than the limit.
The function is called `sufficientSubset` and it takes a `root` of type `TreeNode?` and a `limit` of type `Int`... | ```julia
mutable struct TreeNode
val::Int
left::Union{TreeNode, Nothing}
right::Union{TreeNode, Nothing}
TreeNode(val::Int = 0) = new(val, nothing, nothing)
end
function sufficientSubset(root::Union{TreeNode, Nothing}, limit::Int)::Union{TreeNode, Nothing}
if root === nothing
return nothing... | 8 |
Please explain the following problem in detail and provide code in Visual Basic .NET:
Suppose you are at a party with `n` people labeled from `0` to `n - 1` and among them, there may exist one celebrity. The definition of a celebrity is that all the other `n - 1` people know the celebrity, but the celebrity does not kn... | ### Explanation
First, we select an initial candidate with a value of 0. We loop through the other people and check if the current candidate knows the current person. If the candidate knows this person, we change the candidate to the current person. The idea is to eliminate those who can't be celebrities because they ... | First, the problem is to find a celebrity in a party of n people. A celebrity is someone who is known by everyone else, but knows no one. I'm given a helper function "knows(a, b)" that tells me if a knows b. I need to implement "findCelebrity(n)" that returns the celebrity's index or -1 if none.
From the examples, it'... | ### Explanation of the Problem
The problem involves finding a celebrity at a party with `n` people, where people are labeled from `0` to `n-1`. A celebrity is defined as a person who is known by all other `n-1` people, but does not know any of them. If no celebrity exists, you must return `-1`. You are provided with a... | 13 |
Please explain the reasoning behind the following solution and provide code in c++:
You are given an integer `n`, which indicates that there are `n` courses labeled from `1` to `n`. You are also given a 2D integer array `relations` where `relations[j] = [prevCoursej, nextCoursej]` denotes that course `prevCoursej` has ... | ### Explanation
The algorithm counts good digit strings of length n. There are 5 even digits (0, 2, 4, 6, 8) and 4 prime digits (2, 3, 5, 7). We initialize the count of good digit strings with a value of 1.
We then loop through the range [0, n). For each index i, if i is even, we multiply the total count by the numbe... | First, I need to find the minimum number of months to complete all courses with given prerequisites. I can take multiple courses at once if their prereqs are done, and the graph is a DAG, so no cycles.
From the examples, it's about finding the longest path in terms of time because I want to minimize the total time, bu... | ### Explanation of the Reasoning
The problem involves finding the minimum number of months to complete all courses, given prerequisites and the time required for each course. Since the graph is a directed acyclic graph (DAG) and multiple courses can be taken simultaneously as long as their prerequisites are met, this ... | 6 |
Please explain the reasoning behind the following solution and provide code in Ruby:
Given two binary search trees `root1` and `root2`, return _a list containing all the integers from both trees sorted in **ascending** order_.
**Example 1:**
**Input:** root1 = \[2,1,4\], root2 = \[1,0,3\]
**Output:** \[0,1,1,2,3,4\]
... | ### Explanation
The algorithm uses a stack to keep track of people whose visible right neighbors are not yet determined.
We iterate through the people from right to left, comparing the height of the current person with the height of the person on top of the stack. If the person on top of the stack is shorter than th... | First, the problem is to merge two binary search trees and return a sorted list of all integers from both trees. Since they're binary search trees (BSTs), the nodes are ordered such that for any node, all left subtree values are less, and all right subtree values are greater.
A straightforward way to get a sorted list... | ### Explanation of the Reasoning
The problem requires merging two binary search trees (BSTs) and returning a sorted list of all integers from both trees in ascending order. Since BSTs are ordered such that an in-order traversal visits nodes in sorted order, the approach leverages this property to efficiently solve the... | 28 |
Please explain the reasoning behind the following solution and provide code in Dart:
You are given a **0-indexed** array of `n` integers `differences`, which describes the **differences** between each pair of **consecutive** integers of a **hidden** sequence of length `(n + 1)`. More formally, call the hidden sequence ... | ### Explanation
First, we can calculate the accumulated points within each row from left to right. This can help us to retrieve the points collected on robot's path between two consecutive columns.
Then, starting from the last column and working backwards to the first, we use dynamic programming to find the minimum n... | First, I need to find the number of possible hidden sequences based on the differences array and the range [lower, upper]. The hidden sequence has length n+1, where n is the length of differences.
The differences tell me how much each consecutive element changes. For example, if differences[0] = diff, then hidden[1] =... | ### Explanation of the Reasoning
The problem requires finding the number of possible hidden sequences of length \(n+1\) (where \(n\) is the length of the `differences` array) that satisfy two conditions:
1. The differences between consecutive elements match the given `differences` array.
2. All elements in the hidden ... | 17 |
Please focus on the algorithm of this problem and provide code in Kotlin:
You are given an integer array `nums` of length `n`, and an integer array `queries` of length `m`.
Return _an array_ `answer` _of length_ `m` _where_ `answer[i]` _is the **maximum** size of a **subsequence** that you can take from_ `nums` _such ... | ### Explanation
The algorithm sorts the `nums` array in ascending order, then calculates the prefix sums for easy sum checks. For each query, it finds the position for the query in the prefix sums array using binary search, and the index of that position minus one represents the maximum size of a subsequence whose sum... | First, I need to find, for each query, the maximum size of a subsequence from nums whose sum is less than or equal to the query value. A subsequence maintains the order, but since we're only caring about sum and size, not the order itself for the sum calc, but the definition requires it to be a subsequence, meaning ord... | The algorithm involves sorting the `nums` array to allow for efficient computation of the maximum subsequence size for each query. Since the sum of elements depends only on the values and not their order, and a subsequence can be formed from any subset of elements by maintaining increasing indices, sorting enables us t... | 31 |
port this code to Julia:
```R
set.seed(42)
randPoint <- function(radius, x_center, y_center) {
r <- sqrt(runif(1)) * radius
theta <- runif(1) * 2 * pi
x_offset <- r * cos(theta)
y_offset <- r * sin(theta)
c(x_center + x_offset, y_center + y_offset)
}
Solution <- function(radius, x_center, y_center) {
list... | ### Pseudocode:
```
Solution(radius, x_center, y_center):
self.radius = radius
self.x_center = x_center
self.y_center = y_center
randPoint():
r = sqrt(random()) * radius
theta = random() * 2 * pi
x_offset = r * cos(theta)
y_offset = r * sin(theta)
return [x_center + x_offset, y_center +... | First, the R code has a function `randPoint` that generates a random point within a circle of given radius, centered at (x_center, y_center). It uses polar coordinates: generates a random radius r between 0 and radius (using sqrt of uniform to get uniform distribution in the circle), and a random angle theta between 0 ... | ```julia
using Random
Random.seed!(42)
function randPoint(radius, x_center, y_center)
r = sqrt(rand()) * radius
theta = rand() * 2 * pi
x_offset = r * cos(theta)
y_offset = r * sin(theta)
return (x_center + x_offset, y_center + y_offset) # Returns a tuple (x, y)
end
function Solution(radius, x_ce... | 62 |
port this code from Object Pascal to Visual Basic .NET:
```pascal
unit CircularQueue;
interface
type
TMyCircularQueue = class
private
size: Integer;
data: array of Integer;
front, rear: Integer;
public
constructor Create(k: Integer);
function enQueue(value: Integer): Boolean;
function de... | ### Pseudocode:
```
CircularQueue:
- CircularQueue(k) // constructor
- enQueue(value) // inserts an element into the circular queue
- deQueue() // deletes an element from the circular queue
- Front() // gets the front item from the queue
- Rear() // gets the last item from the que... | First, I need to port this Object Pascal code to Visual Basic .NET. The code is for a circular queue implementation. I'm familiar with both languages, so I can map the concepts.
In Object Pascal, it's a class called TMyCircularQueue with private fields: size, data (an array of integers), front, and rear. There are pub... | Below is the ported version of the provided Object Pascal code to Visual Basic .NET. The Object Pascal code defines a circular queue class (`TMyCircularQueue`) in a unit, so I've translated it to a VB.NET class (`MyCircularQueue`) for simplicity. The logic and functionality have been preserved, including the use of a d... | 58 |
Please write the following solution using javascript:
You are given an integer `mass`, which represents the original mass of a planet. You are further given an integer array `asteroids`, where `asteroids[i]` is the mass of the `ith` asteroid.
You can arrange for the planet to collide with the asteroids in **any arbitr... | ### Explanation
- Sort the asteroids array in ascending order.
- Iterate through the sorted asteroids array.
- At each iteration, check if the planet's mass is greater than or equal to the asteroid's mass.
- If it is, add the asteroid's mass to the planet's mass.
- If it isn't, return `false` because the planet ca... | First, I need to determine if I can destroy all asteroids by colliding them with the planet in some order. The planet starts with a given mass and can destroy an asteroid and gain its mass only if the planet's mass is greater than or equal to the asteroid's mass. If not, the planet gets destroyed.
The key is the order... | ```javascript
/**
* @param {number} mass
* @param {number[]} asteroids
* @return {boolean}
*/
var canDestroyAllAsteroids = function(mass, asteroids) {
// Sort the asteroids in ascending order
asteroids.sort((a, b) => a - b);
let currentMass = mass;
// Iterate through each asteroid in the s... | 42 |
Please explain the reasoning behind the following solution and provide code in Fortran:
Given two positive integers `a` and `b`, return _the number of **common** factors of_ `a` _and_ `b`.
An integer `x` is a **common factor** of `a` and `b` if `x` divides both `a` and `b`.
**Example 1:**
**Input:** a = 12, b = 6
**... | ### Explanation
1. First, we calculate the greatest common divisor (GCD) of the input integers `a` and `b` using the Euclidean algorithm.
2. Next, we initialize a `count` variable to store the number of common factors.
3. Then, we iterate through the numbers from 1 to the square root of the GCD.
- For each number `... | First, the problem is to find the number of common factors of two positive integers a and b. A common factor is a number that divides both a and b without leaving a remainder. From the examples, for a=12 and b=6, the common factors are 1,2,3,6, so there are 4. For a=25 and b=30, it's 1 and 5, so 2.
The constraints say... | ### Explanation of the Reasoning
The problem requires finding the number of common factors of two positive integers `a` and `b`. A common factor is an integer that divides both `a` and `b` without a remainder. The constraints specify that `1 <= a, b <= 1000`, which limits the input size and allows for straightforward ... | 36 |
Please write the following solution using TypeScript:
Suppose you have `n` integers labeled `1` through `n`. A permutation of those `n` integers `perm` (**1-indexed**) is considered a **beautiful arrangement** if for every `i` (`1 <= i <= n`), **either** of the following is true:
* `perm[i]` is divisible by `i`.
* ... | ### Explanation
This problem can be solved using a backtracking algorithm. We can start by creating a helper function (a recursive function) that will iterate through all possibilities. The base case for the recursion is when the current index (idx) is greater than the given integer n. When this condition is met, incr... | First, I need to find the number of beautiful arrangements for n integers. A beautiful arrangement is a permutation where for each position i, either perm[i] is divisible by i or i is divisible by perm[i]. Since it's 1-indexed, I must be careful with indexing in code.
Given that n can be up to 15, a brute-force approa... | ```typescript
function countArrangement(n: number): number {
let count = 0;
let used = new Array(n + 1).fill(false);
backtrack(1);
return count;
function backtrack(pos: number): void {
if (pos > n) {
count++;
return;
}
for (let num = 1; num <= n; n... | 59 |
port this code from Go to TypeScript:
```go
func maxProfit(prices []int, fee int) int {
cash, hold := 0, -prices[0]
for i := 1; i < len(prices); i++ {
temp := cash
cash = max(cash, hold+prices[i]-fee)
hold = max(hold, temp-prices[i])
}
return cash
}
func max(a, b int) int {
... | ### Pseudocode:
```
MAX-PROFIT(prices, fee)
cash = 0
hold = -prices[1]
for i = 2 to length(prices)
temp = cash
cash = max(cash, hold + prices[i] - fee)
hold = max(hold, temp - prices[i])
return cash
```
### Code
```typescript
function maxProfit(prices: number[], fee: number): nu... | First, the Go code is a function called maxProfit that takes a slice of integers (prices) and an integer fee. It calculates the maximum profit with a transaction fee. It uses two variables: cash and hold. Cash represents the maximum profit when not holding a stock, and hold represents the maximum profit when holding a ... | ```typescript
function maxProfit(prices: number[], fee: number): number {
if (prices.length === 0) {
return 0;
}
let cash: number = 0;
let hold: number = -prices[0];
for (let i = 1; i < prices.length; i++) {
let temp: number = cash;
cash = Math.max(cash, hold + pric... | 87 |
Please explain the following problem in detail and provide code in java:
You are given an array of strings `words` and a string `pref`.
Return _the number of strings in_ `words` _that contain_ `pref` _as a **prefix**_.
A **prefix** of a string `s` is any leading contiguous substring of `s`.
**Example 1:**
**Input:*... | ### Explanation
The algorithm iterates through the list of words and checks if the word starts with the given prefix. If it does, increment the count. Finally, return the count.
### Pseudocode:
```
COUNT-PREFIXES(words, pref)
count = 0
for i = 1 to words.length
if words[i][1...|pref|] == pref
... | First, the problem is to count how many strings in the given array "words" have "pref" as a prefix. A prefix is a leading contiguous substring, meaning it has to be at the beginning of the string and the characters must be exactly the same in order.
From the examples, in Example 1, "attention" and "attend" both start ... | ### Explanation of the Problem
The problem requires you to count how many strings in a given array `words` start with a specific string `pref` as a prefix. A prefix is defined as any leading contiguous substring of a string, meaning the prefix must appear at the beginning of the string, and the characters must match e... | 67 |
Please explain the reasoning behind the following solution and provide code in java:
Given two integer arrays `nums1` and `nums2`, return _an array of their intersection_. Each element in the result must be **unique** and you may return the result in **any order**.
**Example 1:**
**Input:** nums1 = \[1,2,2,1\], nums2... | ### Explanation
The function first creates a set `set1` from the first array `nums1`, which eliminates duplicate elements in it. Then, the function iterates through the second array `nums2`. For each element in `nums2`, it checks whether it exists in the `set1`. If so, this element is added to the result set `resultSe... | First, the problem is to find the intersection of two arrays, meaning the elements that are common to both. The result must have unique elements, and the order doesn't matter. From the examples, I see that even if there are duplicates in the input arrays, the output should not have duplicates.
Example 1: nums1 has [1,... | ### Explanation of the Reasoning
The problem requires finding the intersection of two integer arrays, `nums1` and `nums2`, and returning the common elements in an array. The result must contain only unique elements, and the order of the elements does not matter. This means that even if the input arrays have duplicate ... | 54 |
port this code to F#:
```Swift
class MovingAverage {
var queue = [Int]()
var maxSize: Int
var sum = 0.0
init(_ size: Int) {
maxSize = size
}
func next(_ val: Int) -> Double {
if queue.count == maxSize {
sum -= Double(queue.removeFirst())
}
qu... | ### Pseudocode:
```
MovingAverage:
- queue
- maxSize
- sum
MovingAverage(size):
- queue = deque()
- maxSize = size
- sum = 0.0
next(val):
- if length(queue) == maxSize:
- sum = sum - queue.popleft()
- queue.append(val)
- sum = sum + val
- return sum / length(queue)
```
### Code
```fsharp
open System.Collections.... | First, the Swift code is for a MovingAverage class. It maintains a queue of integers up to a maximum size, and calculates the average of the values in the queue. When a new value is added, if the queue is full, it removes the oldest value and subtracts it from the sum before adding the new value.
Now, I need to port t... | ```fsharp
open System.Collections.Generic
type MovingAverage(maxSize: int) =
let mutable queue = Queue<int>()
let mutable sum = 0.0
let maxSizeVal = maxSize
member this.Next(value: int) : float =
if queue.Count = maxSizeVal then
let removed = queue.Dequeue()
sum <- ... | 80 |
Please focus on the functionality of this problem and provide code in Scala:
Given a `wordlist`, we want to implement a spellchecker that converts a query word into a correct word.
For a given `query` word, the spell checker handles two categories of spelling mistakes:
* Capitalization: If the query matches a word ... | ### Explanation
The algorithm uses the prefix sum technique with a hash map to store the count of each prefix sum. It iterates through the given binary array, adding each element to the cumulative sum. For each cumulative sum, the algorithm checks how many prefix sums are equal to the current cumulative sum minus the ... | First, I need to implement a spellchecker in Scala that handles capitalization and vowel errors based on a given wordlist. The spellchecker should process a list of queries and return the correct words according to the rules.
The precedence rules are:
1. Exact match (case-sensitive).
2. Match ignoring case (capitali... | ```scala
import scala.collection.mutable
object Solution {
def spellchecker(wordlist: List[String], queries: List[String]): List[String] = {
val exactSet = mutable.HashSet[String]()
val caseInsensitiveMap = mutable.HashMap[String, String]()
val vowelErrorMap = mutable.HashMap[String, String]()
def i... | 7 |
Please focus on the functionality of this problem and provide code in F#:
Given a list of `words`, list of single `letters` (might be repeating) and `score` of every character.
Return the maximum score of **any** valid set of words formed by using the given letters (`words[i]` cannot be used two or more times).
It is... | ### Explanation
1. Initialize the required variables for total sum, difference, and minimum and maximum values for further calculations.
2. Iterate through the given array from index 0 to nums.length - 2.
3. Calculate the total sum by adding the absolute difference between nums[i] and nums[i+1].
4. Update the min2 and... | First, I need to find the maximum score from any valid set of words that can be formed using the given letters. Each word can be used at most once, and each letter can be used only once. I don't have to use all letters or all words.
The inputs are:
- A list of words (up to 14 words)
- A list of letters (up to 100 le... | ```fsharp
open System
type WordInfo = { Freq: int array; Score: int }
let maxScoreWords (words: string list) (letters: char list) (score: int[]) =
// Compute available frequency
let availFreq = Array.zeroCreate 26
for c in letters do
let idx = (int c) - (int 'a')
availFreq.[idx] <- availFr... | 26 |
convert this code from Scala to Ruby:
```scala
def removeDuplicates(nums: Array[Int]): Int = {
if (nums.isEmpty) return 0
var i = 0
for (j <- 1 until nums.length) {
if (nums(j) != nums(i)) {
i += 1
nums(i) = nums(j)
}
}
i + 1
}
``` | ### Pseudocode:
```
REMOVE-DUPLICATES(nums):
if nums is empty:
return 0
i = 0
for j = 1 to length(nums) - 1:
if nums[j] != nums[i]:
i = i + 1
nums[i] = nums[j]
return i + 1
```
### Code
```ruby
def remove_duplicates(nums)
return 0 if nums.empty?
i = 0
... | First, the Scala code is a function that removes duplicates from an array of integers and returns the length of the array after removal. It's modifying the array in place.
The function is named `removeDuplicates` and it takes an `Array[Int]` as input. In Ruby, arrays are dynamic, so I can use a Ruby array.
Let me und... | ```ruby
def remove_duplicates(nums)
return 0 if nums.empty?
i = 0
(1...nums.length).each do |j|
if nums[j] != nums[i]
i += 1
nums[i] = nums[j]
end
end
i + 1
end
``` | 105 |
Please explain the following problem in detail and provide code in TypeScript:
Given the `head` of a linked list, remove the `nth` node from the end of the list and return its head.
**Example 1:**
**Input:** head = \[1,2,3,4,5\], n = 2
**Output:** \[1,2,3,5\]
**Example 2:**
**Input:** head = \[1\], n = 1
**Output:*... | ### Explanation
The algorithm uses two pointers, first and second. The first pointer traverses the list, moving n steps ahead of the second pointer. If the first pointer reaches the end of the list, then the head is updated, and the second pointer becomes the new head. Otherwise, the second pointer is moved along with... | First, the problem is to remove the nth node from the end of a linked list and return the head. I'm given the head of the list and the value n. The list can have up to 30 nodes, which is small, so efficiency might not be critical, but the follow-up asks for a one-pass solution, so I should aim for that.
A linked list ... | ### Explanation of the Problem
The problem requires removing the nth node from the end of a singly linked list and returning the head of the modified list. A linked list is a linear data structure where each node contains a value and a reference (pointer) to the next node. The end of the list is indicated by a node wh... | 53 |
Please explain the reasoning behind the following solution and provide code in R:
Given an integer `n`, return _a string array_ `answer` _(**1-indexed**) where_:
* `answer[i] == "FizzBuzz "` if `i` is divisible by `3` and `5`.
* `answer[i] == "Fizz "` if `i` is divisible by `3`.
* `answer[i] == "Buzz "` if `i` i... | ### Explanation
The algorithm for this problem simply consists of iterating over the integers from 1 to n, checking the divisibility rules for FizzBuzz, and inserting the appropriate string into the array for each index. For each number i in the range [1,n], we check if it's divisible by 3 and 5 (i % 15 == 0), just 3 ... | First, the problem is to generate a string array for the FizzBuzz game up to a given integer n. The array is 1-indexed, meaning the first element corresponds to the number 1, not 0. So, the array should have exactly n elements.
The conditions are:
- If the number is divisible by both 3 and 5, return "FizzBuzz".
- El... | ### Explanation of the Reasoning
The FizzBuzz problem requires generating a string array (in R, this is implemented as a character vector) for numbers from 1 to a given integer `n`. The array is 1-indexed, meaning the first element corresponds to the number 1. The solution must check the following conditions for each ... | 94 |
Please focus on the algorithm of this problem and provide code in python:
Given an array `arr`, replace every element in that array with the greatest element among the elements to its right, and replace the last element with `-1`.
After doing so, return the array.
**Example 1:**
**Input:** arr = \[17,18,5,4,6,1\]
**... | ### Explanation
1. Calculate the sum of the array elements.
2. Find the maximum subarray sum using Kadane's algorithm in a single array.
3. If k is 1, return the maximum subarray sum from the single array.
4. Concatenate the array twice and find the maximum subarray sum, considering that the subarray can go over the b... | First, I need to replace every element in the array with the greatest element to its right, and set the last element to -1. Then return the modified array.
From the example, for arr = [17,18,5,4,6,1], the output is [18,6,6,6,1,-1]. So for each position, I'm looking right and finding the max in the subarray to the righ... | The algorithm to solve this problem involves iterating through the array from right to left while keeping track of the maximum value to the right of the current index. Start with a variable `max_right` initialized to -1, as there are no elements to the right of the last index. For each index, store the current element'... | 82 |
translate this code from PHP to Mojo:
```php
function hasAlternatingBits($n) {
$prev_bit = $n % 2;
$n = floor($n / 2);
while ($n > 0) {
$curr_bit = $n % 2;
if ($curr_bit == $prev_bit) {
return false;
}
$prev_bit = $curr_bit;
$n = floor($n / 2);
}
r... | ### Pseudocode:
```
ALTERNATING-BITS(n)
prev_bit = n % 2
n = FLOOR(n/2)
WHILE n > 0
curr_bit = n % 2
IF curr_bit == prev_bit
RETURN false
END IF
prev_bit = curr_bit
n = FLOOR(n/2)
END WHILE
RETURN true
END ALTERNATING-BITS
```
### Code
```
functio... | First, the PHP code is a function called `hasAlternatingBits` that takes an integer `$n` and checks if its binary representation has alternating bits. For example, numbers like 5 (101) or 7 (111) – wait, 7 is 111, which doesn't alternate, so it should return false for 7.
Looking at the code:
- It starts by getting th... | ```mojo
def hasAlternatingBits(n: Int) -> Bool:
prev_bit: Int = n % 2
n = n // 2 # Integer division (floor division)
while n > 0:
curr_bit: Int = n % 2
if curr_bit == prev_bit:
return False
prev_bit = curr_bit
n = n // 2
return True
```
### Explanation:
- *... | 93 |
Please explain the reasoning behind the following solution and provide code in Scheme:
Given an integer `n`, return _the number of strings of length_ `n` _that consist only of vowels (_`a`_,_ `e`_,_ `i`_,_ `o`_,_ `u`_) and are **lexicographically sorted**._
A string `s` is **lexicographically sorted** if for all valid... | ### Explanation
We use dynamic programming to solve this problem. Initialize an array dp of size 5 with all elements set to 1. Then, for each i in the range [2, n], iterate through the dp array starting from index 3 (denoting vowel 'o'), moving backwards. Update each dp[j] by adding dp[j + 1] (i.e., count of the next ... | First, the problem is to find the number of lexicographically sorted strings of length n using only the vowels: a, e, i, o, u. Lexicographically sorted means that the string is non-decreasing when we consider the order of the vowels. Since the vowels are in order a < e < i < o < u, the string must be non-decreasing in ... | ### Reasoning Behind the Solution
The problem requires finding the number of lexicographically sorted strings of length \(n\) using only the vowels 'a', 'e', 'i', 'o', 'u'. A lexicographically sorted string is one where each character is the same as or comes before the next character in alphabetical order. Since the v... | 65 |
Please write the following solution using Kotlin:
Given a string `s` and an array of strings `words`, determine whether `s` is a **prefix string** of `words`.
A string `s` is a **prefix string** of `words` if `s` can be made by concatenating the first `k` strings in `words` for some **positive** `k` no larger than `wo... | ### Explanation
The algorithm first sorts the `costs` array in ascending order. Then, it traverses the sorted array and checks if the current cost can be covered by the remaining `coins`. If it can, the function decreases the `coins` by the cost and increments the count of bought ice cream bars. If it can't, the loop ... | First, I need to check if the string `s` can be formed by concatenating the first `k` strings from the `words` array, for some `k` between 1 and the length of `words`.
From the examples, in Example 1, s is "iloveleetcode" and words are ["i", "love", "leetcode", "apples"]. By taking the first three words and concatenat... | ```kotlin
fun isPrefixString(s: String, words: Array<String>): Boolean {
var index = 0
for (word in words) {
for (c in word) {
if (index >= s.length || s[index] != c) {
return false
}
index++
}
if (index == s.length) {
retur... | 56 |
Please focus on the functionality of this problem and provide code in Objective-C:
There are `n` cities numbered from `1` to `n`. You are given an array `edges` of size `n-1`, where `edges[i] = [ui, vi]` represents a bidirectional edge between cities `ui` and `vi`. There exists a unique path between each pair of cities... | ### Explanation
We use dynamic programming to solve this problem. We create a boolean array `dp` of size `(n + 1)` to store if the current player can win with the remaining stones at position `i`. Each entry `dp[i]` is set to `false` initially.
We iterate through all possible numbers of stones from `1` to `n`. For ea... | First, I need to find, for each distance d from 1 to n-1, how many subtrees have a maximum distance of exactly d between any two nodes. The graph is a tree with n nodes, and n is small, up to 15, so I can afford some exponential time solutions since 2^15 is only 32768.
A subtree here means a connected subgraph, which ... | ```objective-c
#import <Foundation/Foundation.h>
@interface Solution : NSObject
- (NSArray<NSNumber *> *)countSubtreesWithMaxDistance:(int)n edges:(NSArray<NSArray<NSNumber *> *> *)edges;
- (BOOL)isConnectedWithMask:(int)mask adj:(NSArray *)adj n:(int)n;
- (int)popcount:(int)mask withN:(int)n;
- (NSArray *)farthestFr... | 12 |
translate this code from PHP to Groovy:
```php
class TreeNode {
public $val;
public $left;
public $right;
function __construct($val = 0, $left = null, $right = null) {
$this->val = $val;
$this->left = $left;
$this->right = $right;
}
}
class Solution {
function dfs($root,... | ### Pseudocode:
```
EQUAL-TO-DESCENDANTS(root)
count = [0]
DFS(root, count)
return count[0]
DFS(root, count)
if root = NIL
return 0
left_sum = DFS(root.left, count)
right_sum = DFS(root.right, count)
if root.val = left_sum + right_sum
count[0] = count[0] + 1
return root... | First, the PHP code defines a TreeNode class with properties val, left, and right, and a constructor. Then there's a Solution class with a dfs method and an equalToDescendants method. The dfs is a recursive function that traverses the tree, sums the values from left and right subtrees, and checks if the current node's ... | ```groovy
class TreeNode {
def val
def left
def right
TreeNode(def val = 0, def left = null, def right = null) {
this.val = val
this.left = left
this.right = right
}
}
class Solution {
def dfs(root, count) {
if (!root) {
return 0
}
... | 101 |
Please write the following solution using SmallTalk:
Given a string `path`, which is an **absolute path** (starting with a slash `'/'`) to a file or directory in a Unix-style file system, convert it to the simplified **canonical path**.
In a Unix-style file system, a period `'.'` refers to the current directory, a dou... | ### Explanation
The algorithm uses a stack to keep track of the directory hierarchy. It starts by splitting the input string by '/', iterating over each part, and processing them according to the following rules:
1. If the part is empty or ".", skip it.
2. If the part is "..", pop off the top element of the stack (if ... | First, I need to write a SmallTalk solution for simplifying a Unix-style absolute path. The path starts with a slash, and I have to handle '.', '..', and multiple slashes. The output should be the canonical path with no trailing slash, single slashes between directories, and no '.' or '..' in it.
I should split the pa... | In SmallTalk, I'll implement the solution as a class method in a utility class called `PathSimplifier`. The method `simplifyPath:` will take a string as input and return the simplified canonical path. I'll use `ReadStream` and `WriteStream` for parsing and building the result, and an `OrderedCollection` to act as a sta... | 43 |
port this code from C# to Erlang:
```csharp
public class VideoSharingPlatform
{
private class Video
{
public int VideoId;
public string VideoString;
public int Views;
public int Likes;
public int Dislikes;
public Video(int videoId, string videoString)
{
... | ### Pseudocode:
```
VideoSharingPlatform:
VideoSharingPlatform()
upload(video: string) -> int
remove(videoId: int) -> void
watch(videoId: int, startMinute: int, endMinute: int) -> string
like(videoId: int) -> void
dislike(videoId: int) -> void
getLikesAndDislikes(videoId: int) -> int[]
g... | First, I need to port this C# code to Erlang. The C# code is for a video sharing platform with methods to upload, remove, watch, like, dislike videos, and get likes/dislikes and views.
Erlang is a functional programming language, so I must adapt the object-oriented C# code to Erlang's style. Erlang uses processes and ... | ```erlang
-module(video_sharing_platform).
-export([new/0, upload/2, remove/2, watch/4, like/2, dislike/2, get_likes_and_dislikes/2, get_views/2]).
-record(video, {id :: integer(), str :: binary(), views = 0 :: non_neg_integer(), likes = 0 :: non_neg_integer(), dislikes = 0 :: non_neg_integer()}).
-record(state, {vid... | 47 |
convert this code from Go to Lua:
```go
func canJump(nums []int) bool {
maxReach := 0
for i, num := range nums {
if i > maxReach {
return false
}
maxReach = max(maxReach, i+num)
}
return true
}
func max(a, b int) int {
if a > b {
return a
}
return... | ### Pseudocode:
```
CAN-REACH-LAST-INDEX(nums)
max_reach = 0
for i = 0 to length[nums] - 1
if i > max_reach
return False
max_reach = max(max_reach, i + nums[i])
return True
```
### Code
```lua
function canJump(nums)
local max_reach = 0
for i, num in ipairs(nums) do
... | First, the Go code is a function called `canJump` that takes a slice of integers `nums`. It determines if you can jump to the last index starting from the first index, where each element represents the maximum jump length from that position.
The code uses a variable `maxReach` to keep track of the farthest index you c... | ```lua
function max(a, b)
if a > b then
return a
else
return b
end
end
function canJump(nums)
local maxReach = 1
for i = 1, #nums do
if i > maxReach then
return false
end
maxReach = max(maxReach, i + nums[i])
end
return true
end
``` | 85 |
Please focus on the algorithm of this problem and provide code in Scheme:
There are `n` cars going to the same destination along a one-lane road. The destination is `target` miles away.
You are given two integer array `position` and `speed`, both of length `n`, where `position[i]` is the position of the `ith` car and ... | ### Explanation
1. We create a jobs array by combining the difficulty and profit arrays, and then sort it based on difficulty. We also sort the worker array.
2. Initialize the indices `i`, maximum profit `max_profit`, and total profit `total_profit` to 0.
3. Loop through each worker's ability.
4. In a nested loop, che... | First, I need to find out how many car fleets will arrive at the destination. A fleet forms when cars meet up and drive at the same speed. Cars can't pass each other, so faster cars slow down to match slower ones when they catch up.
From the examples, it's clear that the order matters because cars ahead can block fast... | The algorithm to solve this problem involves sorting the cars by their position in descending order (closest to the target first) and then iterating through them while maintaining a stack of fleet arrival times. For each car, calculate the time to reach the target as a rational number (numerator and denominator). If th... | 18 |
convert this code to Erlang:
```lua
function removeSubfolders(folder)
local result = {}
table.sort(folder)
local prefix = "/"
for i,path in ipairs(folder) do
if not string.match(path, "^"..prefix) then
table.insert(result, path)
prefix = path .. "/"
end
e... | ### Pseudocode:
```
REMOVE-SUBFOLDERS(folder)
result = []
SORT(folder)
prefix = "/"
for path in folder:
if NOT STARTSWITH(path, prefix):
APPEND(result, path)
prefix = CONCAT(path, "/")
return result
```
### Code
```
remove_subfolders(Folder) ->
Result = [],
P... | First, the Lua code is a function called `removeSubfolders` that takes a list of folder paths. It sorts the folders, then iterates through them, adding a folder to the result only if it's not a subfolder of the previous one. It uses a `prefix` to check if the current path starts with the prefix of the last added folder... | ```erlang
-module(remove_subfolders).
-export([remove_subfolders/1]).
remove_subfolders(Folders) ->
Sorted = lists:sort(Folders),
remove_subfolders_helper(Sorted, [], undefined).
remove_subfolders_helper([], Acc, _LastPrefix) ->
lists:reverse(Acc);
remove_subfolders_helper([Path | Rest], Acc, LastPrefix) ... | 50 |
port this code to Groovy:
```elixir
defmodule Solution do
def remove_invalid_parentheses(s) do
is_valid = fn (s) ->
count = 0
Enum.each(s, fn (c) ->
cond do
c == "(" -> count += 1
c == ")" -> count -= 1
count < 0 -> return false
true -> nil
end
... | ### Pseudocode:
```
REMOVE-INVALID-PARENTHESIS(s):
visited = set()
queue = deque([s])
result = []
found = false
while queue:
cur = DEQUEUE(queue)
if IS-VALID(cur):
found = true
APPEND(result, cur)
if found:
continue
... | First, I need to port this Elixir code to Groovy. The code is for removing invalid parentheses from a string to make it valid. It uses a BFS approach with a queue and a set to track visited strings.
Key parts of the Elixir code:
- It defines a function `is_valid` that checks if a string has balanced parentheses.
- I... | ```groovy
import java.util.Queue
import java.util.LinkedList
import java.util.HashSet
import java.util.ArrayList
class Solution {
List<String> removeInvalidParentheses(String s) {
def isValid = { String str ->
int count = 0
for (char c : str.toCharArray()) {
if (c ==... | 60 |
translate this code to F#:
```ruby
def max_score(s)
left_zeros = 0
right_ones = s.count("1")
max_score = 0
(0...s.length).each do |i|
if s[i] == "0"
left_zeros += 1
else
right_ones -= 1
end
max_score = [max_score, left_zeros + right_o... | ### Pseudocode:
```
MAXIMUM-SCORE(S):
leftZeros = 0
rightOnes = countOnes(S)
maxScore = 0
for i from 0 to length(S) - 1:
if S[i] == '0':
leftZeros += 1
else:
rightOnes -= 1
maxScore = max(maxScore, leftZeros + rightOnes)
return maxScore
```
... | First, the Ruby code defines a function `max_score` that takes a string `s` as input. The string consists of '0's and '1's. The goal is to find the maximum score by splitting the string into two parts at some index, where the score is the number of '0's in the left part plus the number of '1's in the right part.
In th... | ```fsharp
let maxScore (s: string) =
let mutable leftZeros = 0
let mutable rightOnes = s |> Seq.sumBy (fun c -> if c = '1' then 1 else 0)
let mutable currentMax = 0
for i = 0 to s.Length - 1 do
if s.[i] = '0' then
leftZeros <- leftZeros + 1
else
rightOnes <-... | 70 |
Please write the following solution using Rust:
Given a string `s` and an integer `k`, return _the number of substrings in_ `s` _of length_ `k` _with no repeated characters_.
**Example 1:**
**Input:** s = "havefunonleetcode ", k = 5
**Output:** 6
**Explanation:** There are 6 substrings they are: 'havef','avefu','vef... | ### Explanation
The algorithm uses a sliding window approach. Initialize an empty set `window` to store unique characters in a substring. We use two pointers `i` and `j` for each end of the window. The outer loop iterates `j` through the string. If the current character `s[j]` is in `window`, remove the first element ... | First, I need to write a Rust function that takes a string `s` and an integer `k`, and returns the number of substrings of length `k` with no repeated characters. From the examples, I see that for "havefunonleetcode" with k=5, there are 6 such substrings, and for "home" with k=5, it's 0 because the string is shorter.
... | ```rust
use std::cmp;
fn num_k_len_substrings_no_repeats(s: String, k: i32) -> i32 {
let k = k as usize;
let bytes = s.as_bytes();
let n = bytes.len();
if k > n {
return 0;
}
let mut freq = [0usize; 26];
let mut distinct_count: usize = 0;
let mut ans: usize = 0;
... | 38 |
convert this code to Clojure:
```vb.net
Imports System.Collections.Generic
Module Module1
Function BeforeAndAfterPuzzles(phrases As String()) As String()
Dim first_word_map As New Dictionary(Of String, HashSet(Of String))
Dim result As New HashSet(Of String)
For Each phrase As String In p... | ### Pseudocode:
```
BEFORE-AND-AFTER-PUZZLES(phrases)
first_word_map = new HashTable()
result = new Set()
for phrase in phrases
first_word = phrase.split(' ')[0]
first_word_map[first_word].add(phrase)
for phrase in phrases
last_word = phrase.split(' ')[-1]
if first_word... | First, I need to convert this VB.NET code to Clojure. The code is a function called BeforeAndAfterPuzzles that takes an array of strings (phrases) and returns an array of strings that are combinations where the last word of one phrase matches the first word of another, and they're concatenated appropriately, with dupli... | ```clojure
(ns puzzle.core
(:require [clojure.string :as str]))
(defn first-word [s]
(first (remove #{""} (str/split s #" "))))
(defn last-word [s]
(last (remove #{""} (str/split s #" "))))
(defn before-and-after-puzzles [phrases]
(let [grouped (group-by first-word phrases)
first-word-map (into {} (m... | 51 |
Please focus on the efficiency of this problem and provide code in Elixir:
A **sentence** is a list of words that are separated by a single space with no leading or trailing spaces. Each word consists of lowercase and uppercase English letters.
A sentence can be **shuffled** by appending the **1-indexed word position*... | ### Explanation
The algorithm keeps track of three counts: 'same', 'less', and 'greater'. These counts store the number of characters that are the same, less, and greater in string a compared to string b, respectively. Iterate through the characters in a and b simultaneously, comparing each character and updating the ... | First, I need to reconstruct the original sentence from a shuffled version where each word has a number appended indicating its 1-indexed position. The goal is to sort the words based on those numbers and then remove the numbers to get back the original sentence.
The input is a string with words separated by spaces, a... | Below is the Elixir code to solve the problem of reconstructing the original sentence from a shuffled version. The code focuses on efficiency, but given the constraints (number of words ≤ 9 and string length ≤ 200), the solution is already highly efficient. The approach involves splitting the string into words, sorting... | 88 |
Please explain the reasoning behind the following solution and provide code in Object Pascal:
Given a valid (IPv4) IP `address`, return a defanged version of that IP address.
A _defanged IP address_ replaces every period `". "` with `"[.] "`.
**Example 1:**
**Input:** address = "1.1.1.1"
**Output:** "1\[.\]1\[.\]1\[... | ### Explanation
The function for each language takes an input address, which is a valid IPv4 address. It iterates through each character of the string, checking for a period ('.'). If a period is found, we replace it with "[.]" in the resulting string. For other characters, we just add them to the resulting string.
I... | First, the problem is to defang an IP address by replacing every period "." with "[.]". The input is a valid IPv4 address, so I don't need to worry about invalid inputs.
From the examples, for "1.1.1.1" it should become "1[.]1[.]1[.]1", and for "255.100.50.0" it should be "255[.]100[.]50[.]0". So, it's a simple string... | ### Reasoning Behind the Solution
The problem requires transforming a valid IPv4 address into a "defanged" version by replacing every period (`.`) with the string `[.]`. Since the input is guaranteed to be a valid IPv4 address, there is no need to validate the input or handle edge cases related to invalid formats. The... | 134 |
convert this code to Visual Basic .NET:
```mojo
class TreeNode(val, left = null, right = null)
var val: Int = val
var left: TreeNode? = left
var right: TreeNode? = right
fun searchBST(root: TreeNode?, val: Int): TreeNode? {
if (root == null || root.val == val) {
return root
}
return if (root.... | ### Pseudocode:
```
SEARCH-BST(root, val)
if root == NIL or root.val == val
return root
if root.val < val
return SEARCH-BST(root.right, val)
else
return SEARCH-BST(root.left, val)
```
### Code
```vbnet
Public Class TreeNode
Public Property val As Integer
Public Property left... | First, the user wants me to convert this Mojo code to Visual Basic .NET. The code defines a TreeNode class and a searchBST function.
Looking at the Mojo code:
- It's a class called TreeNode with a constructor that takes val, left, and right. Val is an Int, and left and right are optional TreeNode references (indicate... | Below is the equivalent code converted from Mojo to Visual Basic .NET (VB.NET). In VB.NET, classes and functions are structured differently, so I made the following adjustments:
- The `TreeNode` class is defined with a constructor (`Sub New`) that matches the Mojo constructor, including optional parameters for `left` ... | 131 |
Please write the following solution using Scheme:
There is an undirected graph consisting of `n` nodes numbered from `0` to `n - 1`. You are given a **0-indexed** integer array `vals` of length `n` where `vals[i]` denotes the value of the `ith` node.
You are also given a 2D integer array `edges` where `edges[i] = [ai,... | ### Explanation
The basic idea of the algorithm is to find the center node and its neighbors that maximize the star sum with the given constraints. For every node, we calculate the sum of its neighbors' values sorted in decreasing order, up to `k` neighbors. We keep track of the maximum sum found for any node so far.
... | First, I need to find the maximum star sum in an undirected graph with a center node and at most k edges. The star sum is the sum of the values of the center node and its selected neighbors, with up to k neighbors.
A star graph here is centered at one node, and I can choose up to k of its neighbors to include in the s... | ```scheme
(define (max-star-sum vals edges k)
(let* ((n (vector-length vals))
(adj (make-vector n '()))
;; Define helper to remove duplicates from a list by sorting and filtering
(define (unique-elements lst)
(let ((sorted (sort lst <))) ; Sort ascending
(let loop ((... | 29 |
Please explain the reasoning behind the following solution and provide code in Ruby:
Design a stack that supports increment operations on its elements.
Implement the `CustomStack` class:
* `CustomStack(int maxSize)` Initializes the object with `maxSize` which is the maximum number of elements in the stack.
* `voi... | ### Explanation
This solution essentially performs a Depth-First search on the words given, selecting words[i] for a possible combination and then branching based on possibilities with and without words[i]. getMaxScoreHelper recurses through this branching until reaching the end of words where it stops and stores the ... | First, I need to design a stack that supports increment operations on its elements, specifically incrementing the bottom k elements. The stack has a max size, and I have to handle push, pop, and this increment function efficiently.
From the example, when we increment the bottom k elements, it's not just the top k, but... | ### Explanation of the Reasoning
The problem requires implementing a custom stack with a fixed maximum size that supports three operations: `push`, `pop`, and `increment`. The `increment` operation must add a value to the bottom `k` elements of the stack (or all elements if there are fewer than `k`). The constraints i... | 113 |
Please explain the reasoning behind the following solution and provide code in Rust:
A scenic location is represented by its `name` and attractiveness `score`, where `name` is a **unique** string among all locations and `score` is an integer. Locations can be ranked from the best to the worst. The **higher** the score,... | ### Explanation
1. Calculate the total sum of the elements in the array.
2. Initialize a variable `left_sum` to store the sum of elements on the left side of middleIndex.
3. Iterate through the elements of the array:
a. Subtract the current element from the total sum.
b. Compare the left_sum with the total sum... | First, I need to implement a SORTracker class in Rust that handles adding scenic locations with a name and score, and querying the ith best location where i is the number of times get has been called, including the current one. The ranking is based on higher score being better, and if scores are equal, lexicographicall... | ### Reasoning Behind the Solution
The problem requires implementing a system that tracks scenic locations and supports adding locations and querying the ith best location, where the ranking is based on a custom order: higher score is better, and if scores are equal, the lexicographically smaller name is better. The sy... | 37 |
Please explain the reasoning behind the following solution and provide code in c++:
There are several consecutive houses along a street, each of which has some money inside. There is also a robber, who wants to steal money from the homes, but he **refuses to steal from adjacent homes**.
The **capability** of the robbe... | ### Explanation
This problem can be solved by a binary search algorithm. The main idea is to find the minimum capability of the robber by checking whether there's a valid way to steal from at least `k` houses with the current mid capability.
In the algorithm, we initiate left (l) as 1 and right (r) as the highest po... | First, I need to find the minimum capability for a robber who steals from at least k houses without stealing from adjacent ones. The capability is the max money from the houses he robs, and I need to minimize that max.
From the examples, it's about choosing a subset of non-adjacent houses with at least k houses, and a... | ### Explanation of the Reasoning
The problem requires finding the minimum capability of a robber who must steal from at least \(k\) houses without robbing adjacent houses. The capability is defined as the maximum amount of money stolen from any single house in the chosen set. The goal is to minimize this maximum value... | 34 |
Please focus on the functionality of this problem and provide code in Elixir:
You are given an array `time` where `time[i]` denotes the time taken by the `ith` bus to complete **one trip**.
Each bus can make multiple trips **successively**; that is, the next trip can start **immediately after** completing the current ... | ### Explanation
The algorithm performs the following steps:
1. Initialize a variable `sum` to store the sum of vowels.
2. Calculate the length `n` of the input string.
3. Iterate through each character in the input string.
4. If the character is a vowel ('a', 'e', 'i', 'o', 'u'), add the product `(i + 1) * (n - i)` t... | First, I need to find the minimum time for all buses to complete at least a certain number of total trips. Each bus has its own trip time, and they operate independently, starting trips one after another without any wait.
From the example, with times [1,2,3] and totalTrips 5, the answer is 3. At time 3, the trips are ... | ```elixir
defmodule Solution do
def min_time(times, total_trips) do
max_time = Enum.max(times)
upper = total_trips * max_time
binary_search(1, upper, times, total_trips)
end
defp binary_search(low, high, times, total_trips) when low > high do
low
end
defp binary_search(low, high, times, tota... | 75 |
Please explain the reasoning behind the following solution and provide code in Visual Basic .NET:
You are given a string `s`, a string `chars` of **distinct** characters and an integer array `vals` of the same length as `chars`.
The **cost of the substring** is the sum of the values of each character in the substring.... | ### Explanation
1. Create a dictionary (hash_map/hash_table) to store the custom values of the characters provided in 'chars' and 'vals'.
2. Initialize variables 'max_cost' and 'cost' to 0.
3. Iterate through each character in the input string 's'.
4. Inside the loop, calculate the value of the current character
- ... | First, I need to find the maximum cost substring of string s, where the cost is based on the values of characters. Some characters have custom values given in chars and vals, and others have their default alphabetical positions.
From the examples, I see that negative values can make some substrings have negative costs... | ### Explanation of the Reasoning
The problem requires finding the maximum cost substring of a given string `s`, where the cost is determined by character values defined by the strings `chars` and the array `vals`. Here's a step-by-step breakdown of the reasoning behind the solution:
1. **Character Value Computation**... | 98 |
Please focus on the algorithm of this problem and provide code in Lisp:
Given an integer array `arr` and an integer `difference`, return the length of the longest subsequence in `arr` which is an arithmetic sequence such that the difference between adjacent elements in the subsequence equals `difference`.
A **subseque... | ### Explanation
We use Depth-First Search for traversing the binary tree. In the DFS algorithm, we go deep into the tree before backtracking. While traversing, we calculate the depth of each node as we go along. If one of the child nodes has a greater depth than the other, we return that child node with an incremented... | First, I need to find the longest subsequence in an array that forms an arithmetic sequence with a given difference. A subsequence maintains the order but doesn't have to be contiguous. The difference between adjacent elements in this subsequence should be exactly the given difference.
Given that the array can be up t... | The algorithm uses dynamic programming with a map (implemented as an array for efficiency) to track the length of the longest arithmetic subsequence ending with each value. Since the range of possible values is fixed (from -20,000 to 20,000), an array with an offset is used to store the lengths. For each element in the... | 61 |
Please focus on the algorithm of this problem and provide code in PHP:
Design a max stack data structure that supports the stack operations and supports finding the stack's maximum element.
Implement the `MaxStack` class:
* `MaxStack()` Initializes the stack object.
* `void push(int x)` Pushes element `x` onto th... | ### Explanation
The algorithm uses two data structures, a main stack and a max set. The main stack is used to store the elements, and the max set is used to store the maximum elements in a sorted order. When an element is pushed onto the stack, it is added to the main stack and the max set. When the top element of the... | I need to implement a MaxStack in PHP that supports push, pop, top, peekMax, and popMax operations. The requirements are that top should be O(1), and the others should be O(log n). Also, popMax should remove the top-most maximum element if there are multiples.
A standard stack uses a array or linked list for LIFO. To ... | Below is the PHP implementation of the `MaxStack` class that supports the required operations with the specified time complexities: `O(1)` for `top` and amortized `O(log n)` for `push`, `pop`, `peekMax`, and `popMax`. The solution uses a combination of a doubly linked list to maintain stack order and an `SplMaxHeap` to... | 39 |
Please explain the reasoning behind the following solution and provide code in Lisp:
A sequence of numbers is called **arithmetic** if it consists of at least two elements, and the difference between every two consecutive elements is the same. More formally, a sequence `s` is arithmetic if and only if `s[i+1] - s[i] ==... | ### Explanation
If the low and the high are both even, then the difference between the count of numbers from 1 to low and from 1 to high should give us the count of odd numbers between low and high (inclusive).
The number of odd numbers between 1 and an integer n is calculated by `(n + 1) / 2`. So, for the low and h... | First, I need to handle multiple range queries on an array, and for each query, check if the subarray from l[i] to r[i] can be rearranged to form an arithmetic sequence. An arithmetic sequence has a constant difference between consecutive elements after rearrangement.
Key point: it's about rearrangement, so the order ... | ### Explanation of the Reasoning
The problem requires determining, for each range query, whether a subarray of `nums` can be rearranged to form an arithmetic sequence. An arithmetic sequence is defined as having a constant difference between consecutive elements after rearrangement. Since the order of elements does no... | 99 |
convert this code from R to Lua:
```R
lonely_numbers <- function(nums) {
num_set <- unique(nums)
lonely <- numeric()
for (num in nums) {
if (!(num - 1) %in% num_set && !(num + 1) %in% num_set) {
lonely <- c(lonely, num)
}
}
return(lonely)
}
``` | ### Pseudocode:
```
LONELY-NUMBERS(nums)
num_set = SET(nums) // O(n) operation
lonely = []
for num in nums // O(n) operation
if num - 1 not in num_set and num + 1 not in num_set
APPEND(lonely, num) // O(1) operation
return lonely
```
### Code
```lua
function count_valid_splits(nu... | First, the R code defines a function called `lonely_numbers` that takes a vector `nums` as input. It finds numbers that are "lonely," meaning neither the number minus one nor the number plus one is in the set of unique numbers from `nums`.
In R, it creates a set of unique numbers using `unique(nums)`, stored in `num_s... | ```lua
function lonely_numbers(nums)
local num_set = {}
for _, num in ipairs(nums) do
num_set[num] = true
end
local lonely = {}
for _, num in ipairs(nums) do
if num_set[num - 1] == nil and num_set[num + 1] == nil then
table.insert(lonely, num)
end
end
retu... | 141 |
Please write the following solution using Scala:
Given two positive integers `n` and `k`, the binary string `Sn` is formed as follows:
* `S1 = "0 "`
* `Si = Si - 1 + "1 " + reverse(invert(Si - 1))` for `i > 1`
Where `+` denotes the concatenation operation, `reverse(x)` returns the reversed string `x`, and `invert... | ### Explanation
We use dynamic programming with an array `dp` where `dp[i]` will store the largest integer that can be painted using exactly a cost of `i`. Initially, all elements of `dp` are empty strings except `dp[0]` which is an empty string (no digits are used). Loop through all possible prices from 1 to `target`... | First, I need to write a Scala function that, given n and k, returns the k-th bit in the string S_n defined by that recursive process. The string S_n is built by starting with "0" and then for each i, S_i is S_{i-1} + "1" + reverse(invert(S_{i-1})). And k is 1-based index.
Generating the entire string up to S_n isn't ... | ```scala
object Solution {
def findKthBit(n: Int, k: Int): String = {
val bitChar = findBitHelper(n, k)
bitChar.toString + " "
}
private def findBitHelper(n: Int, k: Int): Char = {
if (n == 1) {
'0'
} else {
val lenPrev = (1 << (n - 1)) - 1
if (k <= lenPrev) {
findBitHel... | 107 |
Please explain the following problem in detail and provide code in Rust:
Design a data structure that will be initialized with a string array, and then it should answer queries of the shortest distance between two different strings from the array.
Implement the `WordDistance` class:
* `WordDistance(String[] wordsDi... | ### Explanation
The algorithm first initializes a hashmap during instantiation, with each unique word, in the array wordsDict, as keys, and their corresponding indexes (in wordsDict) as values.
The shortest() function accepts word1 and word2 as input arguments. The function is responsible for calculating and returni... | First, I need to design a class called WordDistance in Rust. It should be initialized with a vector of strings, and then have a method that takes two different strings and returns the shortest distance between them in the array. The distance is probably the minimum number of positions between their indices.
From the e... | ### Explanation of the Problem
The problem requires designing a data structure in Rust that efficiently handles queries for the shortest distance between two different strings in a given array of strings. The data structure is initialized with an array of strings (called `wordsDict`), and it must support a method to c... | 96 |
Please explain the following problem in detail and provide code in Scala:
Given an integer `n`, return the `nth` digit of the infinite integer sequence `[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, ...]`.
**Example 1:**
**Input:** n = 3
**Output:** 3
**Example 2:**
**Input:** n = 11
**Output:** 0
**Explanation:** The 11th d... | ### Explanation
The solution works as follows:
1. Initialize the `size` of each number at `1` (single-digit numbers), the `length` of numbers of that size at 9 (there are 9 single-digit numbers), and the `start` number of size `1` as `1`.
2. Keep subtracting the total length of numbers of the current size from `n` as ... | First, the problem is to find the nth digit in the infinite sequence of integers: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, and so on. For example, if n is 3, the third digit is 3. If n is 11, it's the first digit of 10, which is 0, but wait no, 10 has two digits, so let's list them out to understand.
Let me write out the se... | ### Explanation of the Problem
The problem requires finding the nth digit in the infinite sequence of integers concatenated together: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, and so on. For example:
- If n = 3, the sequence is [1, 2, 3, ...], and the 3rd digit is 3.
- If n = 11, the sequence is [1, 2, 3, 4, 5, 6, 7, 8, ... | 32 |
Please write the following solution using Perl:
A website domain `"discuss.leetcode.com "` consists of various subdomains. At the top level, we have `"com "`, at the next level, we have `"leetcode.com "` and at the lowest level, `"discuss.leetcode.com "`. When we visit a domain like `"discuss.leetcode.com "`, we will a... | ### Explanation
1. Initialize result, prev, and start variables as 0, 0, and -1.
2. Iterate through the nums array.
3. If the current element is between left and right (inclusive), calculate the difference between the index and start, then update and add it to result.
4. If the current element is less than left, add t... | First, I need to write a Perl script that takes an array of count-paired domains and returns all the subdomains with their visit counts summed up appropriately. The input is given as an array of strings, each in the format "rep domain" where domain can have two or three parts.
From the examples, I see that for each do... | ```perl
use strict;
use warnings;
sub subdomainVisits {
my @cpdomains = @_; # Get the array of count-paired domains
my %count_hash; # Hash to store subdomain visit counts
# Iterate through each count-paired domain
foreach my $cpdomain (@cpdomains) {
# Split the string into count and domain
... | 136 |
Please focus on the algorithm of this problem and provide code in Object Pascal:
Given the `root` of a Binary Search Tree (BST), convert it to a Greater Tree such that every key of the original BST is changed to the original key plus the sum of all keys greater than the original key in BST.
As a reminder, a _binary se... | ### Explanation
We traverse the tree in a right-to-left inorder traversal using a recursive algorithm. This traversal ensures we visit the nodes with the greater keys first. During this traversal, we maintain a running sum of the values of the nodes we've visited so far. When we visit a new node, we add the running su... | First, I need to convert a given Binary Search Tree (BST) to a "Greater Tree". That means for each node, I have to add to its value the sum of all values that are greater than it in the tree. Since it's a BST, the nodes with greater values are all in the right subtree and possibly in the ancestors, but because it's a B... | The algorithm to convert a Binary Search Tree (BST) to a Greater Tree involves performing a reverse in-order traversal (right-root-left) of the tree. This traversal visits nodes in decreasing order of their values. A cumulative sum is maintained to keep track of the sum of all node values greater than the current node.... | 72 |
Please explain the following problem in detail and provide code in Scala:
You are given an array of strings `names`, and an array `heights` that consists of **distinct** positive integers. Both arrays are of length `n`.
For each index `i`, `names[i]` and `heights[i]` denote the name and height of the `ith` person.
Re... | ### Explanation
The algorithm starts by iterating through both input arrays (`names` and `heights`) to create an array ('name_height_pairs') of pairs (in other languages, objects with `height` and `name` properties) containing the heights and corresponding names.
Next, the array of pairs is sorted in descending order... | First, I need to sort an array of names based on an array of heights in descending order. The heights are all distinct, which simplifies things since there are no ties to worry about. Both arrays are of the same length, and I have to return the names sorted by height.
From the examples, in Example 1, heights are 180, ... | ### Explanation of the Problem
The problem requires sorting an array of names based on a corresponding array of heights in descending order. Here's a detailed breakdown:
- **Input**:
- An array of strings `names`, where each element represents a person's name.
- An array of integers `heights`, where each element... | 122 |
Please write the following solution using Object Pascal:
You are given a string `s`, which contains stars `*`.
In one operation, you can:
* Choose a star in `s`.
* Remove the closest **non-star** character to its **left**, as well as remove the star itself.
Return _the string after **all** stars have been remove... | ### Explanation
For each character in the given string `s`, we iterate through the characters. If the character is a star, we remove the last character of the `result` only if `result` is not empty. Otherwise, we append the character to the `result`. Finally, we return the `result` as a string. This algorithm simulate... | First, I need to write a solution in Object Pascal for this problem. The problem involves a string with stars, and I have to remove stars and the closest non-star character to their left until all stars are gone. The result should be unique and always possible.
From the example, it's clear that I need to process the s... | ```pascal
program RemoveStarsSolution;
function removeStars(s: string): string;
var
stackStr: string;
i: integer;
begin
stackStr := '';
for i := 1 to Length(s) do begin
if s[i] <> '*' then begin
// Push non-star character to stack
stackStr := stackStr + s[i];
end else begin
// It's a ... | 120 |
Please write the following solution using TypeScript:
Given an integer `num`, find the closest two integers in absolute difference whose product equals `num + 1` or `num + 2`.
Return the two integers in any order.
**Example 1:**
**Input:** num = 8
**Output:** \[3,3\]
**Explanation:** For num + 1 = 9, the closest div... | ### Explanation
Start by iterating through the numbers from the square root of `num+2` and checking if the current number is a divisor for `num + 1` or `num + 2`. If any divisor is found, return it along with the corresponding quotient. Starting from the square root ensures that the absolute difference is minimized.
... | First, the problem is to find two integers whose product is either num + 1 or num + 2, and among all such pairs, I need the one with the smallest absolute difference. Then return those two integers.
From the examples, for num=8, num+1=9 has factors 3 and 3 (diff 0), num+2=10 has 2 and 5 (diff 3), so 3 and 3 is better.... | ```typescript
function closestDivisors(num: number): number[] {
const findMinDiffPair = (N: number): [number, number] => {
const s = Math.floor(Math.sqrt(N));
for (let d = s; d >= 1; d--) {
if (N % d === 0) {
const other = N / d;
return [d, other];
... | 74 |
convert this code to Clojure:
```haskell
import Data.List (isPrefixOf)
addBoldTag :: [String] -> String -> String
addBoldTag words s =
let bold = map (\x -> any (\w -> w `isPrefixOf` drop x s) words) [0..length s - 1]
insertTags [] [] = []
insertTags (b:bs) (c:cs)
| b && (null cs || no... | ### Pseudocode:
```
def addBoldTag(words, s):
bold = [False] * len(s)
for word in words:
pos = s.find(word)
while pos != -1:
for i in range(pos, pos + len(word)):
bold[i] = True
pos = s.find(word, pos + 1)
result = []
for i in range(len(s)):
... | First, I need to convert this Haskell code to Clojure. The Haskell code adds bold tags around substrings that are prefixes of words in a given list. The function is called `addBoldTag` and it takes a list of strings (words) and a string (s), and returns a new string with bold tags added.
Let me understand the Haskell ... | ```clojure
(ns add-bold-tag
(:require [clojure.string :as str]))
(defn add-bold-tag [words s]
(let [bold (vec (for [i (range (count s))]
(boolean (some (fn [w] (.startsWith (str/subs s i) w)) words))))]
(letfn [(insert-tags [bold-seq char-seq]
(if (and (empty? bold-seq) (empty... | 90 |
Please explain the following problem in detail and provide code in Object Pascal:
Given an integer array `nums` and two integers `left` and `right`, return _the number of contiguous non-empty **subarrays** such that the value of the maximum array element in that subarray is in the range_ `[left, right]`.
The test case... | ### Explanation
The algorithm is based on the observation that each row is formed by concatenating the previous row with its complement:
- Row 1: 0
- Row 2: 01
- Row 3: 0110
- Row 4: 01101001
- and so on...
So the idea is to find out the kth element in the nth row by checking the k/2 th element in the (n-1)th row. If... | First, I need to find the number of contiguous non-empty subarrays where the maximum element in that subarray is between left and right, inclusive. The array can be up to 10^5 elements long, so I need an efficient solution, probably O(n) or O(n log n) at worst, since O(n^2) might be too slow for n=100,000.
A subarray ... | To solve the problem of finding the number of contiguous non-empty subarrays where the maximum element is within the range `[left, right]`, we can use an efficient approach that leverages the concept of cumulative maximum constraints. The key insight is that the number of subarrays with a maximum in `[left, right]` can... | 73 |
Please explain the following problem in detail and provide code in Erlang:
Given an array `nums` of positive integers. Your task is to select some subset of `nums`, multiply each element by an integer and add all these numbers. The array is said to be **good** if you can obtain a sum of `1` from the array by any possib... | ### Explanation
The problem can be solved using the mathematical concept of Bézout's identity, which states that the greates common divisor (GCD) of two integers `a` and `b` can be represented in the form `ax + by = gcd(a, b)`. The array is said to be good if there exists a combination of elements which can be multipl... | First, the problem is to determine if an array of positive integers is "good". A array is good if I can select some subset of the numbers, multiply each by some integer (positive or negative), and have their sum equal to 1.
From the examples, it's clear that I don't have to use all elements; I can choose a subset. Als... | ### Explanation of the Problem
The problem requires determining whether a given array of positive integers is "good." An array is considered good if there exists a subset of its elements and a set of integer multipliers (which can be positive or negative) such that the sum of the products equals 1. In other words, you... | 92 |
Please write the following solution using PHP:
Given an array of integers `nums` and an integer `k`, return _the total number of subarrays whose sum equals to_ `k`.
A subarray is a contiguous **non-empty** sequence of elements within an array.
**Example 1:**
**Input:** nums = \[1,1,1\], k = 2
**Output:** 2
**Exampl... | ### Explanation
The algorithm utilizes a hash map to store the frequency of the prefix sum up to the current element in the array. We start by initializing the hash map with a key-value pair (0, 1), which represents the empty subarray sum. Then we iterate through the input array, updating the prefix sum and result.
F... | First, I need to find the number of contiguous subarrays in the given array that sum up to a specific value k. The array can have up to 20,000 elements, and the elements can be negative, zero, or positive since nums[i] ranges from -1000 to 1000. Also, k can be up to 10^7 in absolute value.
A brute force approach would... | ```php
function subarraySum($nums, $k) {
$curr_sum = 0;
$sum_freq = array();
$sum_freq[0] = 1; // Initialize with sum 0 having one occurrence
$count = 0;
foreach ($nums as $num) {
$curr_sum += $num; // Update current prefix sum
$diff = $curr_sum - $k; // Calculate the difference... | 106 |
Please explain the reasoning behind the following solution and provide code in c++:
Given two strings `s1` and `s2`, return _the lowest **ASCII** sum of deleted characters to make two strings equal_.
**Example 1:**
**Input:** s1 = "sea ", s2 = "eat "
**Output:** 231
**Explanation:** Deleting "s " from "sea " adds... | ### Explanation
For this problem, we use dynamic programming. First, we create a 2D array `dp` to store the intermediate results. Each cell dp[i][j] in the `dp` array represents the lowest ASCII sum of deleted characters to make the first i characters of s1 and the first j characters of s2 equal.
We initialize the fi... | First, the problem is to find the lowest ASCII sum of deleted characters to make two strings equal. That means I need to transform both strings into some common string by deleting characters, and the cost is the sum of ASCII values of the deleted chars, and I want to minimize that sum.
From the examples, it's not just... | ### Explanation of the Reasoning
The problem requires finding the minimum ASCII sum of characters that need to be deleted from two strings, `s1` and `s2`, to make them equal. After analyzing the problem, it becomes clear that making the strings equal involves finding a common subsequence (a sequence that appears in bo... | 45 |
port this code to Scheme:
```julia
function equal_sum_subarrays(nums)
sums = Set()
for i in 2:length(nums)
current_sum = nums[i] + nums[i-1]
if current_sum in sums
return true
end
push!(sums, current_sum)
end
return false
end
``` | ### Pseudocode:
```
EQUAL-SUM-SUBARRAYS(nums)
sums = new Set()
for i = 1 to length(nums) - 1
current_sum = nums[i] + nums[i - 1]
if current_sum is in sums
return True
sums.add(current_sum)
return False
```
### Code
```scheme
(define (equal-sum-subarrays nums)
(let ((su... | First, the Julia code is a function called `equal_sum_subarrays` that takes an array `nums`. It checks if there are two subarrays with the same sum. Specifically, it's looking at sums of consecutive pairs starting from index 2 to the end, comparing the sum of nums[i] and nums[i-1] with previously computed sums.
Lookin... | ```scheme
(define (equal-sum-subarrays nums)
(let* ((len (length nums)))
(if (< len 2)
#f
(letrec ((check-sums
(lambda (index sum-list)
(if (> index (- len 2))
#f
(let* ((elem1 (list-ref nums index))
... | 121 |
convert this code to Julia:
```ruby
def is_subpath(head, root)
return false if root.nil?
return true if head.nil?
return dfs(head, root) || is_subpath(head, root.left) || is_subpath(head, root.right)
end
def dfs(node, root)
return false if root.nil?
return false if node.nil?
return (node.val == root.val)... | ### Pseudocode:
```
MAX_HEIGHT(cuboids)
cuboids = sort_dimensions(cuboids)
cuboids = sort_cuboids(cuboids)
n = length(cuboids)
dp = [0] * n
ans = 0
for i = 0 to n-1
dp[i] = cuboids[i][2]
for j = 0 to i-1
if check_dimensions(cuboids[j], cuboids[i])
dp[i... | First, the Ruby code has two functions: `is_subpath` and `dfs`. `is_subpath` checks if a linked list (represented by `head`) is a subpath in a binary tree (represented by `root`). `dfs` is a helper function that checks if the linked list starting from `node` matches a path in the subtree rooted at `root`.
I need to co... | Here is the Julia equivalent of the provided Ruby code. I've translated the functions directly, maintaining the same logic. In Julia, we need to define the node structures (structs) for the linked list and binary tree nodes, as they are not built-in. I've used `mutable struct` for the nodes to allow for modification, s... | 140 |
Please focus on the algorithm of this problem and provide code in Mojo:
A **[binary expression tree](https://en.wikipedia.org/wiki/Binary_expression_tree)** is a kind of binary tree used to represent arithmetic expressions. Each node of a binary expression tree has either zero or two children. Leaf nodes (nodes with 0 ... | ### Explanation
1. Initialize a result array with the same length as rains, filled with -1. Create a map for filled lakes and a set for dry days.
2. Loop through rains array:
- If the rain amount is 0, add the current day to dry days set.
- Otherwise, check if the lake is already filled:
- If it is, find a ... | First, I need to check if two binary expression trees with only '+' operators are equivalent, meaning they evaluate to the same value no matter what the variables are. The trees are given as roots, and I have to return true or false.
Since the only operator is addition, and addition is commutative and associative, the... | For the given problem, where the binary expression trees only contain the `'+'` operator, the equivalence of two trees depends on whether they have the same multiset of variables (i.e., the same variables with the same frequencies). This is because addition is associative and commutative, so the structure of the tree d... | 108 |
port this code to C#:
```pascal
function MinAddition(s: string; t: string): Integer;
var
s_len, t_len, i, j: Integer;
begin
s_len := Length(s);
t_len := Length(t);
i := 1;
j := 1;
while (i <= s_len) and (j <= t_len) do
begin
if s[i] = t[j] then
j := j + 1;
i := i + 1;
end;
Result := t_le... | ### Pseudocode:
```
MIN-ADDITION(s, t)
s_len = LENGTH(s)
t_len = LENGTH(t)
i = 1
j = 1
WHILE i <= s_len AND j <= t_len
IF s[i] == t[j]
j = j + 1
ENDIF
i = i + 1
ENDWHILE
RETURN t_len - j + 1
ENDMIN-ADDITION
```
### Code
```csharp
public int MinAddition(st... | First, the Pascal code is a function called MinAddition that takes two strings, s and t, and returns an integer. It seems to calculate some kind of minimum addition based on the strings. From the code, it's iterating through both strings and when characters match, it increments the index for t. Finally, it returns how ... | Here is the C# equivalent of the provided Pascal code. I've implemented it as a static method in a class for completeness, as C# methods need to be part of a class. The logic has been adjusted for C#'s 0-based string indexing, but the functionality remains the same.
```csharp
using System;
public class StringUtils
{
... | 150 |
port this code to Elixir:
```
fun maxSumUnderK(nums: IntArray, k: Int): Int {
var maxSum = -1
for (i in nums.indices) {
for (j in i + 1 until nums.size) {
val sum = nums[i] + nums[j]
if (sum < k && sum > maxSum) {
maxSum = sum
}
}
}
ret... | ### Pseudocode:
```
MAX-SUM-UNDER-K(nums, k)
max_sum <- -1
for i <- 1 to length(nums) - 1 do
for j <- i + 1 to length(nums) do
sum <- nums[i] + nums[j]
if sum < k and sum > max_sum then
max_sum <- sum
if max_sum = -1 then
return -1
else
ret... | First, the code is in Kotlin, and I need to port it to Elixir. The function is called `maxSumUnderK`, and it takes an array of integers (`nums`) and an integer `k`. It finds the maximum sum of any two elements in the array that is less than `k`. If no such pair exists, it returns -1.
In Kotlin, it's using a nested loo... | Here's the Elixir port of the provided Kotlin code. The original code finds the maximum sum of any two distinct elements in an array that is less than a given value `k`, returning `-1` if no such pair exists. In Elixir, I've implemented this using functional programming principles, specifically with nested `Enum.reduce... | 118 |
Please focus on the efficiency of this problem and provide code in Perl:
Given two strings `str1` and `str2`, return _the shortest string that has both_ `str1` _and_ `str2` _as **subsequences**_. If there are multiple valid strings, return **any** of them.
A string `s` is a **subsequence** of string `t` if deleting so... | ### Explanation
The algorithm uses a depth-first search (DFS) to traverse the input binary tree. The base case is reached when the root node is `null`, in which case the maximum value and minimum value are set to positive and negative infinity, respectively. While traversing the nodes, the algorithm maintains the maxi... | First, I need to find the shortest string that has both str1 and str2 as subsequences. If there are multiple, I can return any. The strings can be up to 1000 characters, so efficiency should be considered, probably aiming for something like O(len(str1) * len(str2)) time, since that's common for dynamic programming prob... | Below is a Perl script that solves the problem of finding the shortest string that has both input strings as subsequences. The solution uses dynamic programming to compute the shortest common supersequence (SCS) and then reconstructs the string. The time complexity is O(len(str1) * len(str2)) and the space complexity i... | 66 |
Please explain the reasoning behind the following solution and provide code in Go:
You have an array `arr` of length `n` where `arr[i] = (2 * i) + 1` for all valid values of `i` (i.e., `0 <= i < n`).
In one operation, you can select two indices `x` and `y` where `0 <= x, y < n` and subtract `1` from `arr[x]` and add `... | ### Explanation
This problem can be solved mathematically without iterating through the array. Since the given array is of length `n` and always has the pattern `arr[i] = (2 * i) + 1`, the average value will always be the middle value when `n` is odd, and the average of two middle values when `n` is even.
In both cas... | First, the array is defined as arr[i] = 2*i + 1 for i from 0 to n-1. So for n=3, it's [1,3,5]. The goal is to make all elements equal with the minimum number of operations, where each operation lets me decrease one element by 1 and increase another by 1. It's guaranteed that I can make them all equal.
I need to find w... | ### Explanation of the Reasoning
The problem involves an array where `arr[i] = 2 * i + 1` for `i` ranging from 0 to `n-1`, and the goal is to make all elements equal using the minimum number of operations. Each operation allows you to decrease one element by 1 and increase another by 1, and it is guaranteed that all e... | 89 |
Please write the following solution using Elixir:
We have `n` chips, where the position of the `ith` chip is `position[i]`.
We need to move all the chips to **the same position**. In one step, we can change the position of the `ith` chip from `position[i]` to:
* `position[i] + 2` or `position[i] - 2` with `cost = 0... | ### Explanation
1. Create a dictionary `counts` to store the count of each number in `arr1`.
2. Iterate through the elements of `arr2`. For each element, add that element to the result `n` times where `n` is the count of that element in `arr1`. Remove the element from the `counts` dictionary.
3. Iterate through the so... | First, I need to write an Elixir solution for this problem. The goal is to move all chips to the same position with minimum cost, where moving by 2 costs nothing, and moving by 1 costs one unit.
From the examples, I see that moving chips to an even or odd position might be key because moving by 2 doesn't change parity... | ```elixir
defmodule MinChipCost do
def min_cost_to_move_chips(position) do
odd_count = Enum.count(position, &Integer.is_odd/1)
n = length(position)
even_count = n - odd_count
min(odd_count, even_count)
end
end
``` | 161 |
Please focus on the efficiency of this problem and provide code in Kotlin:
A tree rooted at node 0 is given as follows:
* The number of nodes is `nodes`;
* The value of the `ith` node is `value[i]`;
* The parent of the `ith` node is `parent[i]`.
Remove every subtree whose sum of values of nodes is zero.
Return... | ### Explanation
1. First, we calculate the frequencies of the lexicographically smallest characters in each word of `words`. This is done by iterating through the words, finding the smallest character, counting its frequency, and store the result in a new array named `freqWords`.
2. Next, we iterate through the querie... | First, I need to remove every subtree whose sum of values is zero and then return the number of remaining nodes. The tree is given with a root at node 0, and I have arrays for parent and value.
A subtree here means a node and all its descendants. So, if the sum of values in a subtree rooted at some node is zero, I sho... | To solve this problem efficiently in Kotlin, we need to remove all subtrees with a sum of zero and return the count of remaining nodes. The approach uses a depth-first search (DFS) to traverse the tree in a bottom-up manner, computing the subtree sum and determining if the subtree is kept for each node. The DFS returns... | 115 |
Please explain the following problem in detail and provide code in Julia:
Given a signed 32-bit integer `x`, return `x` _with its digits reversed_. If reversing `x` causes the value to go outside the signed 32-bit integer range `[-231, 231 - 1]`, then return `0`.
**Assume the environment does not allow you to store 64... | ### Explanation
The algorithm initializes `res` as 0. Then, we determine the sign of the input integer and take its absolute value. We use a while loop to iterate through each digit of `x` from right to left. In each iteration, we multiply the current `res` by 10 and add the last digit of `x` to it. The last digit of ... | First, the problem is to reverse the digits of a signed 32-bit integer. If the reversed number is outside the range of -2^31 to 2^31 - 1, I should return 0. Also, I can't use 64-bit integers, so I have to be careful with how I handle the reversal to check for overflow without using larger data types.
The input is a 32... | ### Explanation of the Problem
The problem requires reversing the digits of a given 32-bit signed integer `x` and returning the result. If the reversed value falls outside the 32-bit signed integer range, which is `[-2^31, 2^31 - 1]` (i.e., `[-2147483648, 2147483647]`), the function should return `0`. Additionally, th... | 41 |
Please write the following solution using PHP:
Given a list of `dominoes`, `dominoes[i] = [a, b]` is **equivalent to** `dominoes[j] = [c, d]` if and only if either (`a == c` and `b == d`), or (`a == d` and `b == c`) - that is, one domino can be rotated to be equal to another domino.
Return _the number of pairs_ `(i, j... | ### Explanation
The algorithm uses a stack data structure to process the input string 's'. Iterate through the string from left to right, if the current character 'c' is equal to the character at the top of the stack, pop the character from the top of the stack, otherwise, push the current character onto the stack.
A... | First, I need to find the number of pairs of dominoes that are equivalent, meaning they can be rotated to match each other. Two dominoes [a,b] and [c,d] are equivalent if (a==c and b==d) or (a==d and b==c).
The dominoes can be rotated, so the order doesn't matter. I should normalize each domino so that the smaller num... | ```php
function numEquivDominoPairs($dominoes) {
$freq = array();
foreach ($dominoes as $domino) {
$a = min($domino[0], $domino[1]);
$b = max($domino[0], $domino[1]);
$key = $a . '-' . $b;
if (!isset($freq[$key])) {
$freq[$key] = 0;
}
$freq[$key]++;
... | 163 |
port this code to Clojure:
```typescript
function suggestedProducts(products: string[], searchWord: string): string[][] {
const result: string[][] = [];
products.sort();
for (let i = 0; i < searchWord.length; i++) {
const suggestions: string[] = [];
for (const product of products) {
... | ### Pseudocode:
```
SUGGESTED_PRODUCTS(products, searchWord)
result <- empty list
sort(products)
for i <- 1 to length(searchWord)
suggestions <- empty list
for j <- 1 to length(products)
if length(products[j]) > i and products[j][i] == searchWord[i]
add products[j... | First, the TypeScript code takes a list of products and a search word, and it returns a list of lists of strings. For each prefix of the search word, it finds up to three products that start with that prefix, in sorted order.
The code sorts the products array first. Then, for each character in the search word, it iter... | ```clojure
(ns leetcode.core ;; You can change the namespace as needed
(defn suggested-products [products search-word]
(let [sorted-products (sort products)]
(mapv (fn [i]
(vec (take 3 (filter (fn [p]
(and (> (count p) i)
(= (... | 147 |
convert this code to Go:
```kotlin
fun minMoves(nums: IntArray, k: Int): Int {
val n = nums.size
val ones = mutableListOf<Int>()
for (i in nums.indices) {
if (nums[i] == 1) ones.add(i - ones.size)
}
var moves = ones.take(k).sumBy { it - ones[k / 2] }
var minMoves = moves
for (i in k ... | ### Pseudocode:
```
MIN_MOVES(nums, k):
n = length of nums
ones = empty list
for i = 1 to n do
if nums[i] == 1 then
ones.append(i - 1)
moves = sum(ones[i] - ones[k/2] for i = 0 to k-1)
min_moves = moves
for i = k to length of ones - 1 do
moves = moves + ones... | First, I need to convert this Kotlin code to Go. The function is called `minMoves` and it takes an array of integers `nums` and an integer `k`. It seems to be calculating some minimum moves based on the positions of 1s in the array.
Let me understand what the Kotlin code is doing:
- It finds all indices where `nums[i... | ```go
package main
func minMoves(nums []int, k int) int {
var ones []int
for i, num := range nums {
if num == 1 {
adj := i - len(ones)
ones = append(ones, adj)
}
}
// Assume len(ones) >= k
var sum int
for j := 0; j < k; j++ {
sum += ones[j]
}
... | 160 |
Please explain the reasoning behind the following solution and provide code in Go:
We have `n` jobs, where every job is scheduled to be done from `startTime[i]` to `endTime[i]`, obtaining a profit of `profit[i]`.
You're given the `startTime`, `endTime` and `profit` arrays, return the maximum profit you can take such t... | ### Explanation
1. Create an array of jobs containing tuples (endTime, startTime, profit)
2. Sort the jobs in increasing order of their end times
3. Initialize a dynamic programming array, `dp`. Set `dp[0]` to the profit of the first job in the sorted jobs array
4. Iterate over the sorted jobs array, and for each job,... | First, the problem is about selecting a subset of jobs with max profit without overlapping times. If one job ends at time X, another can start at X, so they can be adjacent but not overlap.
This sounds like a dynamic programming problem, similar to the activity selection problem but with profits, so it's more like wei... | ### Explanation of the Reasoning
The problem is a variation of the weighted interval scheduling problem, where we need to select a subset of non-overlapping jobs to maximize profit. The key insight is that jobs can be scheduled adjacently (e.g., one job ending at time X and another starting at X is allowed), but they ... | 64 |
Please write the following solution using Scala:
Given a string `formula` representing a chemical formula, return _the count of each atom_.
The atomic element always starts with an uppercase character, then zero or more lowercase letters, representing the name.
One or more digits representing that element's count may... | ### Explanation
The algorithm is based on a recursive descent parser. The idea is to parse the formula progressively, recognizing the atoms and the opening and closing parentheses. When an opening parenthesis is found, it calls itself to parse the inner formula, then when a closing parenthesis is found, it exits the f... | First, I need to parse a chemical formula string and count the atoms, then output them in sorted order with counts if greater than 1. The formula can have elements, numbers, parentheses, and nested structures.
I should use a stack-based approach because of the parentheses. When I encounter an opening parenthesis, I pu... | ```scala
import scala.collection.mutable.{Map => MutableMap, Stack}
object Solution {
def countOfAtoms(formula: String): String = {
val stack = Stack[MutableMap[String, Int]]()
stack.push(MutableMap[String, Int]()) // initial map
var i = 0
val len = formula.length
while (i < len) {
val ch ... | 71 |
Please explain the reasoning behind the following solution and provide code in Objective-C:
Design a simplified version of Twitter where users can post tweets, follow/unfollow another user, and is able to see the `10` most recent tweets in the user's news feed.
Implement the `Twitter` class:
* `Twitter()` Initializ... | ### Explanation
The `Twitter` class has three main data structures: `tweets`, `following`, and a `timeStamp` counter.
- `tweets`: A data structure to store tweet objects for each user.
- `following`: A data structure to store the list of users that the current user follows.
- `timeStamp`: A counter to provide a uniqu... | First, I need to implement a Twitter class with methods: postTweet, getNewsFeed, follow, and unfollow. The key is to handle the news feed which shows the 10 most recent tweets from the user themselves and the users they follow, ordered from most recent to least recent.
I need to store tweets and the follow relationshi... | ### Explanation of the Reasoning
The problem requires implementing a simplified Twitter system where users can post tweets, follow or unfollow other users, and retrieve the 10 most recent tweets in their news feed. The news feed includes tweets from the user themselves and the users they follow, ordered from most rece... | 97 |
Please write the following solution using Dart:
A polynomial linked list is a special type of linked list where every node represents a term in a polynomial expression.
Each node has three attributes:
* `coefficient`: an integer representing the number multiplier of the term. The coefficient of the term `**9**x4` i... | ### Explanation
The algorithm uses a dummy node to create a new linked list representing the sum of the given polynomials. A `current` pointer iterates through the polynomials, adding the terms with the same powers and appending it into the new linked list if the coefficient sum is not 0. Polynomials with different po... | First, I need to add two polynomial linked lists and return the sum as a new linked list in strictly descending order of power, omitting any terms with zero coefficient.
The input is given as lists of [coefficient, power], but in Dart, I'll work with a PolyNode class. I should define a PolyNode class with coefficient,... | Below is the Dart implementation for adding two polynomial linked lists. The solution defines a `PolyNode` class to represent each node in the linked list and implements the `addPoly` function to compute the sum of the two polynomials. The function returns the head of the resulting polynomial linked list, which is in s... | 159 |
Please focus on the efficiency of this problem and provide code in Rust:
You are given an integer `num.` **Rearrange** the digits of `num` such that its value is **minimized** and it does not contain **any** leading zeros.
Return _the rearranged number with minimal value_.
Note that the sign of the number does not ch... | ### Explanation
1. Calculate the prefix sum of plates between candles for the entire string `s`. The `prefix` array will store this information.
2. Loop through `s` from the second character (i.e., index 1) to the end:
a. Update the prefix sum for each index by adding the previous prefix sum.
b. If the current c... | First, I need to rearrange the digits of a given integer to minimize its value without any leading zeros. The sign doesn't change, so I must handle both positive and negative numbers. The number can be as large as 10^15 in absolute value, which means up to 15 digits.
To minimize the value, for positive numbers, I want... | The provided Rust code efficiently rearranges the digits of the given integer to minimize its value without leading zeros. The approach handles both positive and negative numbers by sorting the digits appropriately: ascending for positive numbers (with a swap to avoid leading zeros) and descending for negative numbers ... | 84 |
Please write the following solution using Lisp:
You are given two integer arrays `nums1` and `nums2` both of the same length. The **advantage** of `nums1` with respect to `nums2` is the number of indices `i` for which `nums1[i] > nums2[i]`.
Return _any permutation of_ `nums1` _that maximizes its **advantage** with res... | ### Explanation
1. Create a sorted data structure (`multiset` in C++, `TreeSet` in Java, `SortedList` in Python, and a sorted array in JavaScript) from nums1.
2. For each number `num` in nums2, find the smallest element in the sorted data structure that is greater than `num`. If there is no such element, select the sm... | First, I need to maximize the number of indices where nums1[i] > nums2[i] by permuting nums1. Both arrays are of the same length, up to 10^5 elements, so I need an efficient solution, probably O(n log n) at worst, since O(n^2) would be too slow.
The advantage is counted where nums1[i] > nums2[i]. I need to arrange num... | ```lisp
(defun max-advantage-permutation (nums1 nums2)
(let* ((n (length nums1))
(nums2-vec (make-array n :initial-contents nums2))
(a-sorted (let ((arr (make-array n :initial-contents nums1)))
(sort arr #'<)
arr))
(indices (loop for i below n colle... | 27 |
Please write the following solution using Scala:
Given an `m x n` matrix `matrix` and an integer `k`, return _the max sum of a rectangle in the matrix such that its sum is no larger than_ `k`.
It is **guaranteed** that there will be a rectangle with a sum no larger than `k`.
**Example 1:**
**Input:** matrix = \[\[1,... | ### Explanation
1. Initialize variables to iterate over all possible column pairs (left and right).
2. For each column pair, calculate the cumulative sum of elements within the column range for each row.
3. Initialize a sorted set (e.g., `set` in C++, `TreeSet` in Java, `SortedList` in Python, and an array in JavaScri... | First, I need to find the maximum sum of a rectangle in a matrix that doesn't exceed a given integer k. The matrix can be up to 100x100, and k can be between -10^5 and 10^5. It's guaranteed that there's at least one rectangle with sum <= k.
A rectangle in the matrix is defined by choosing two rows and two columns, and... | ```scala
import scala.math.max
object Solution {
def maxSumSubmatrix(matrix: Array[Array[Int]], k: Int): Int = {
val m = matrix.length
val n = matrix(0).length
// Precompute cumulative sum for each row to allow O(1) range sum queries per row
val cum = Array.ofDim[Int](m, n)
for (i <- 0 until... | 100 |
Please explain the following problem in detail and provide code in Ruby:
You are given a binary array `nums` containing only the integers `0` and `1`. Return _the number of **subarrays** in nums that have **more**_ `1`'_s than_ `0`_'s. Since the answer may be very large, return it **modulo**_ `109 + 7`.
A **subarray**... | ### Explanation
We can use dynamic programming to solve this problem. Start with two base cases:
1. If there are no floors (n=0), the minimum moves required is 0.
2. If there is only one floor (n=1), the minimum moves required is 1.
Create an array `dp` with `n+1` elements, initializing `dp[0]` to 0 and `dp[1]` to ... | First, I need to find the number of subarrays in a binary array that have more 1's than 0's. The array can be up to 10^5 elements long, so I need an efficient solution, probably O(n) or O(n log n) at worst, since O(n^2) might be too slow for n=100,000.
A subarray is contiguous, so I have to consider all possible conti... | ### Problem Explanation
You are given a binary array `nums` containing only `0`s and `1`s, and you need to find the number of subarrays (contiguous subsequences) where the count of `1`s is greater than the count of `0`s. Since the result can be very large, you must return it modulo \(10^9 + 7\).
A subarray is defined... | 14 |
Please focus on the efficiency of this problem and provide code in Haskell:
Given a string `s`, reverse the string according to the following rules:
* All the characters that are not English letters remain in the same position.
* All the English letters (lowercase or uppercase) should be reversed.
Return `s` _aft... | ### Explanation
The algorithm sorts the weights of the people in ascending order. Then, it uses two pointers, left, starting at the first person, and right, starting at the last person, to assign people to boats efficiently.
In each iteration, if the person pointed by left and the person pointed by right can fit in t... | First, I need to reverse only the English letters in the string, keeping all other characters in their original positions. The string can have uppercase and lowercase letters, and other ASCII characters between 33 and 122, excluding some specified ones, but since it's given that it doesn't contain double quotes or back... | To solve this problem in Haskell, we need to reverse only the English letters in the string while keeping all non-letter characters in their original positions. The provided solution is efficient with a time complexity of O(n), where n is the length of the string, as it involves a single pass through the string after p... | 139 |
Please explain the reasoning behind the following solution and provide code in Fortran:
There are a row of `n` houses, each house can be painted with one of the `k` colors. The cost of painting each house with a certain color is different. You have to paint all the houses such that no two adjacent houses have the same ... | ### Explanation
The algorithm stores the minimum cost to paint each house up to the current house with each color. Then for each house, it iterates through all the colors and calculates the minimum cost for painting that house with each color. It skips the same color as the previous house because no two adjacent house... | First, the problem is to paint n houses with k colors each, with given costs, and no two adjacent houses can have the same color. I need to find the min cost to paint all houses.
From the examples, it's clear that I have to choose colors for each house such that adjacent houses have different colors, and sum up the co... | ### Explanation of the Reasoning
The problem requires finding the minimum cost to paint `n` houses with `k` colors each, ensuring no two adjacent houses share the same color, given a cost matrix. This is a classic dynamic programming problem due to the overlapping subproblems and optimal substructure properties.
####... | 83 |
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