[User] Show me the top 5 users who have the highest total trade volume (quantity * price) as buyers, along with their wallet addresses and the number of distinct assets they traded.

[Assistant] SELECT t.buyer_id, w.address, COUNT(DISTINCT t.asset_id) AS distinct_assets, SUM(t.quantity * t.price) AS total_volume FROM trading_platform.trades t JOIN trading_platform.wallets w ON t.buyer_id = w.user_id GROUP BY t.buyer_id, w.address ORDER BY total_volume DESC LIMIT 5;

[User] Now modify the query to only include trades that happened in the last 30 days and show the average trade price for each buyer.

[Assistant] SELECT t.buyer_id, w.address, COUNT(DISTINCT t.asset_id) AS distinct_assets, SUM(t.quantity * t.price) AS total_volume, AVG(t.price) AS avg_price FROM trading_platform.trades t JOIN trading_platform.wallets w ON t.buyer_id = w.user_id WHERE t.traded_at >= NOW() - INTERVAL '30 days' GROUP BY t.buyer_id, w.address ORDER BY total_volume DESC LIMIT 5;

[User] Actually, I want to see the top 5 buyers by total trade volume who also have at least 3 distinct assets traded, and include their wallet creation date.

[Assistant] SELECT t.buyer_id, w.address, COUNT(DISTINCT t.asset_id) AS distinct_assets, SUM(t.quantity * t.price) AS total_volume, AVG(t.price) AS avg_price, w.created_at AS wallet_created FROM trading_platform.trades t JOIN trading_platform.wallets w ON t.buyer_id = w.user_id WHERE t.traded_at >= NOW() - INTERVAL '30 days' GROUP BY t.buyer_id, w.address, w.created_at HAVING COUNT(DISTINCT t.asset_id) >= 3 ORDER BY total_volume DESC LIMIT 5;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE trading_platform.wallets ( wallet_id text PRIMARY KEY, user_id text, address text, private_key text, created_at timestamp )
CREATE TABLE trading_platform.trades (
    trade_id character varying(64) NOT NULL,  -- unique identifier for the trade
    order_id character varying(64) NOT NULL, -- identifier of the order that led to the trade
    buyer_id character varying(64) NOT NULL, -- identifier of the buyer
    seller_id character varying(64) NOT NULL, -- identifier of the seller
    asset_id character varying(64) NOT NULL, -- identifier of the asset being traded
    quantity numeric(38,14) NOT NULL, -- quantity of the asset in the trade
    price numeric(38,14) NOT NULL, -- price per unit of the asset
    traded_at timestamp NOT NULL, -- time when the trade was executed
    PRIMARY KEY (trade_id)
)
CREATE TABLE trading_platform.assets ( asset_id character varying(64) NOT NULL, name character varying(128) NOT NULL, symbol character varying(32) NOT NULL, type character varying(32) NOT NULL, PRIMARY KEY (asset_id) )
CREATE TABLE trading_platform.utxos ( utxo_id character varying(64) NOT NULL, transaction_id character varying(64) NOT NULL, output_index integer NOT NULL, address character varying(128) NOT NULL, amount numeric(38,14) NOT NULL, spent boolean NOT NULL, PRIMARY KEY (utxo_id) )
CREATE TABLE trading_platform.metadata (
    metadata_id character varying(64) NOT NULL,  -- unique identifier for the metadata
    asset_id character varying(64) NOT NULL, -- identifier of the asset the metadata is associated with
    key character varying(128) NOT NULL, -- key of the metadata
    value text NOT NULL, -- value of the metadata
    PRIMARY KEY (metadata_id)
)
CREATE TABLE trading_platform.logs ( log_id character varying(64) NOT NULL, user_id character varying(64), action character varying(128) NOT NULL, details text NOT NULL, logged_at timestamp NOT NULL, PRIMARY KEY (log_id) )
CREATE TABLE trading_platform.notifications ( notification_id.text, user_id.text, message.text, sent_at.timestamp, read_at.timestamp )


[User] List all reservations made by guests from 'US', showing the reservation ID, guest first name, last name, and the property name.

[Assistant] SELECT T1.reservation_id, T2.first_name, T2.last_name, T3.property_name FROM hospitality_technology.reservations AS T1 JOIN hospitality_technology.guests AS T2 ON T1.guest_id = T2.guest_id JOIN hospitality_technology.properties AS T3 ON T1.property_id = T3.property_id WHERE T2.country_code = 'US';

[User] Only show reservations with status 'Confirmed'.

[Assistant] SELECT T1.reservation_id, T2.first_name, T2.last_name, T3.property_name FROM hospitality_technology.reservations AS T1 JOIN hospitality_technology.guests AS T2 ON T1.guest_id = T2.guest_id JOIN hospitality_technology.properties AS T3 ON T1.property_id = T3.property_id WHERE T2.country_code = 'US' AND T1.status = 'Confirmed';

[User] Also include the check-in and check-out dates, and order by check-in date descending.

[Assistant] SELECT T1.reservation_id, T2.first_name, T2.last_name, T3.property_name, T1.check_in_date, T1.check_out_date FROM hospitality_technology.reservations AS T1 JOIN hospitality_technology.guests AS T2 ON T1.guest_id = T2.guest_id JOIN hospitality_technology.properties AS T3 ON T1.property_id = T3.property_id WHERE T2.country_code = 'US' AND T1.status = 'Confirmed' ORDER BY T1.check_in_date DESC;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE hospitality_technology.rooms (
    room_id character varying(64) NOT NULL,  -- unique identifier for the room
    property_id character varying(64) NOT NULL, -- FK to properties table
    room_number character varying(10) NOT NULL, -- room number identifier (e.g., '101', 'Suite 2B')
    room_type_id character varying(64) NOT NULL, -- FK to room_types table
    floor integer, -- floor number the room is on
    status character varying(50) NOT NULL, -- e.g., Available, Occupied, Cleaning, OutOfOrder, Maintenance
    is_smoking boolean NOT NULL DEFAULT false, -- smoking allowed flag
    features text, -- description of features (e.g., Balcony, Sea View, Jacuzzi)
    current_condition text, -- notes on room condition
    last_cleaned_at timestamp with time zone, -- timestamp of last cleaning
    PRIMARY KEY (room_id),
    FOREIGN KEY (property_id) REFERENCES hospitality_technology.properties(property_id),
    FOREIGN KEY (room_type_id) REFERENCES hospitality_technology.room_types(room_type_id)
)
CREATE TABLE hospitality_technology.guests ( guest_id character varying(64) NOT NULL, first_name character varying(100) NOT NULL, last_name character varying(100) NOT NULL, email character varying(255) UNIQUE, phone_number character varying(30), date_of_birth date, address_line1 character varying(255), city character varying(100), state_province character varying(100), postal_code character varying(20), country_code character varying(3), preferences text, loyalty_member_id character varying(64) UNIQUE, communication_consent boolean DEFAULT true, created_at timestamp with time zone NOT NULL DEFAULT current_timestamp, updated_at timestamp with time zone NOT NULL DEFAULT current_timestamp, PRIMARY KEY (guest_id) )
CREATE TABLE hospitality_technology.reservations ( reservation_id text, property_id text, guest_id text, room_id text, room_type_id text, check_in_date date, check_out_date date, actual_check_in_ts timestamp, actual_check_out_ts timestamp, num_adults integer, num_children integer, status text, booking_source text, rate_plan_id text, total_amount numeric, amount_paid numeric, special_requests text, created_at timestamp, updated_at timestamp )
CREATE TABLE hospitality_technology.staff (
    staff_id character varying(64) NOT NULL,  -- unique identifier for the staff member
    property_id character varying(64) NOT NULL, -- FK to properties table (primary property)
    first_name character varying(100) NOT NULL,
    last_name character varying(100) NOT NULL,
    position character varying(100) NOT NULL, -- e.g., Front Desk Agent, Housekeeper, Manager, Concierge
    work_email character varying(255) UNIQUE, -- staff member's work email
    work_phone character varying(30),
    hire_date date NOT NULL,
    termination_date date, -- date employment ended (if applicable)
    is_active boolean NOT NULL DEFAULT true, -- currently employed flag
    access_level integer NOT NULL, -- permission level within systems (e.g., 1=basic, 5=admin)
    manager_id character varying(64), -- FK to staff table (self-referencing for supervisor)
    created_at timestamp with time zone NOT NULL DEFAULT current_timestamp,
    PRIMARY KEY (staff_id),
    FOREIGN KEY (property_id) REFERENCES hospitality_technology.properties(property_id),
    FOREIGN KEY (manager_id) REFERENCES hospitality_technology.staff(staff_id)
)
CREATE TABLE hospitality_technology.service_orders ( order_id text, reservation_id text, guest_id text, service_id text, staff_id_ordered text, staff_id_delivered text, order_timestamp timestamp, delivery_timestamp timestamp, quantity integer, unit_price numeric, total_price numeric, status text, notes text, bill_id text )
CREATE TABLE hospitality_technology.payments (
    payment_id character varying(64) NOT NULL,  -- unique identifier for the payment transaction
    reservation_id character varying(64), -- FK to reservations (if payment is for a stay)
    guest_id character varying(64) NOT NULL, -- FK to guests (who paid)
    bill_id character varying(64), -- FK to bills/invoices this payment applies to
    amount numeric(12,2) NOT NULL, -- amount of the payment
    currency_code character varying(3) NOT NULL, -- ISO currency code (e.g., USD, EUR)
    payment_method character varying(50) NOT NULL, -- e.g., CreditCard, Cash, BankTransfer, Points, Voucher
    card_type character varying(50), -- e.g., Visa, MasterCard, Amex (if CC)
    card_last_four character varying(4), -- last 4 digits of CC (if CC)
    transaction_ref character varying(128), -- reference ID from payment gateway or processor
    payment_timestamp timestamp with time zone NOT NULL DEFAULT current_timestamp, -- when the payment occurred
    status character varying(50) NOT NULL, -- e.g., Pending, Succeeded, Failed, Refunded, Disputed
    staff_id_processed character varying(64), -- FK to staff (who processed the payment)
    notes text, -- notes about the payment
    PRIMARY KEY (payment_id),
    FOREIGN KEY (reservation_id) REFERENCES hospitality_technology.reservations(reservation_id),
    FOREIGN KEY (guest_id) REFERENCES hospitality_technology.guests(guest_id),
    FOREIGN KEY (staff_id_processed) REFERENCES hospitality_technology.staff(staff_id)
)
CREATE TABLE hospitality_technology.reviews ( review_id text PRIMARY KEY, property_id text, reservation_id text, guest_id text, rating_overall int, rating_cleanliness int, rating_service int, rating_location int, rating_value int, comment text, review_source text, review_date timestamp, is_public boolean, staff_response text, response_staff_id text, response_date timestamp )


[User] I want a summary of each asset showing the total number of trades executed and the average trade price, including asset name and symbol.

[Assistant]
SELECT a.asset_id,
       a.name,
       a.symbol,
       COUNT(t.trade_id) AS trades_count,
       AVG(t.price) AS avg_price
FROM trading_platform.assets a
LEFT JOIN trading_platform.trades t ON a.asset_id = t.asset_id
GROUP BY a.asset_id, a.name, a.symbol;

[User] Actually, exclude trades before '2024-05-01'.

[Assistant]
SELECT a.asset_id,
       a.name,
       a.symbol,
       COUNT(t.trade_id) AS trades_count,
       AVG(t.price) AS avg_price
FROM trading_platform.assets a
LEFT JOIN trading_platform.trades t ON a.asset_id = t.asset_id
  AND t.traded_at >= '2024-05-01'
GROUP BY a.asset_id, a.name, a.symbol;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE trading_platform.wallets ( wallet_id text, user_id text, address text, private_key text, created_at timestamp )
CREATE TABLE trading_platform.trades ( trade_id text, order_id text, buyer_id text, seller_id text, asset_id text, quantity numeric, price numeric, traded_at timestamp )
CREATE TABLE trading_platform.assets ( asset_id text, name text, symbol text, type text )
CREATE TABLE trading_platform.utxos ( utxo_id text, transaction_id text, output_index integer, address text, amount numeric, spent boolean )
CREATE TABLE trading_platform.peers ( peer_id text, ip_address text, port integer, last_seen timestamp )
CREATE TABLE trading_platform.metadata ( metadata_id text, asset_id text, key text, value text )
CREATE TABLE trading_platform.kyc_audit ( kyc_audit_id text, user_id text, status text, reviewed_at timestamp )


[User] For projects that have completed more than one fundraising round, calculate the average investment value across all their recorded rounds. Display the project name and this average value.

[Assistant] SELECT project_name, AVG(investment_value) AS average_investment FROM project_fundraising_record GROUP BY project_name HAVING COUNT(*) > 1;

[User] Can you modify this to only show projects where the average investment value is greater than 10 million USD and order the results by average investment value descending?

[Assistant] SELECT project_name, AVG(investment_value) AS average_investment FROM project_fundraising_record GROUP BY project_name HAVING COUNT(*) > 1 AND AVG(investment_value) > 10000000 ORDER BY average_investment DESC;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE project_fundraising_record ( id character varying(32) NOT NULL,  -- fundraising record id project_id character varying(32) NOT NULL, -- the invested project's id project_name character varying(128) NOT NULL, -- name of the invested project rounds_name character varying(32), -- name of the fundraising round investment_value numeric(38,14), -- amount of the fundraising in USD investment_date character varying(128), -- the date of the investment happened introduction character varying(128), -- the introduction of the invested project valuation numeric(38,14), -- the valuation of the project in USD when invested )


[User] List all guests who have made at least one reservation. Show their first and last names and the number of reservations they have made.

[Assistant]
SELECT g.first_name, g.last_name, COUNT(r.reservation_id) AS reservation_count
FROM hospitality_technology.guests g
JOIN hospitality_technology.reservations r ON g.guest_id = r.guest_id
GROUP BY g.guest_id, g.first_name, g.last_name;

[User] Show only the guests who made 3 or more reservations and order by reservation_count descending.

[Assistant]
SELECT g.first_name, g.last_name, COUNT(r.reservation_id) AS reservation_count
FROM hospitality_technology.guests g
JOIN hospitality_technology.reservations r ON g.guest_id = r.guest_id
GROUP BY g.guest_id, g.first_name, g.last_name
HAVING COUNT(r.reservation_id) >= 3
ORDER BY reservation_count DESC;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE hospitality_technology.rooms ( room_id character varying(64) NOT NULL, property_id character varying(64) NOT NULL, room_number character varying(10) NOT NULL, room_type_id character varying(64) NOT NULL, floor integer, status character varying(50) NOT NULL, is_smoking boolean NOT NULL DEFAULT false, features text, current_condition text, last_cleaned_at timestamp with time zone, PRIMARY KEY (room_id), FOREIGN KEY (property_id) REFERENCES hospitality_technology.properties(property_id), FOREIGN KEY (room_type_id) REFERENCES hospitality_technology.room_types(room_type_id) )
CREATE TABLE hospitality_technology.guests ( guest_id character varying(64) NOT NULL, first_name character varying(100) NOT NULL, last_name character varying(100) NOT NULL, email character varying(255) UNIQUE, phone_number character varying(30), date_of_birth date, address_line1 character varying(255), city character varying(100), state_province character varying(100), postal_code character varying(20), country_code character varying(3), preferences text, loyalty_member_id character varying(64) UNIQUE, communication_consent boolean DEFAULT true, created_at timestamp with time zone NOT NULL DEFAULT current_timestamp, updated_at timestamp with time zone NOT NULL DEFAULT current_timestamp, PRIMARY KEY (guest_id) )
CREATE TABLE hospitality_technology.reservations ( reservation_id character varying(64) NOT NULL, property_id character varying(64) NOT NULL, guest_id character varying(64) NOT NULL, room_id character varying(64), room_type_id character varying(64) NOT NULL, check_in_date date NOT NULL, check_out_date date NOT NULL, actual_check_in_ts timestamp with time zone, actual_check_out_ts timestamp with time zone, num_adults integer NOT NULL, num_children integer DEFAULT 0, status character varying(50) NOT NULL, booking_source character varying(100), rate_plan_id character varying(64), total_amount numeric(12, 2), amount_paid numeric(12, 2) DEFAULT 0.00, special_requests text, created_at timestamp with time zone NOT NULL DEFAULT current_timestamp, updated_at timestamp with time zone NOT NULL DEFAULT current_timestamp, PRIMARY KEY (reservation_id), FOREIGN KEY (property_id) REFERENCES hospitality_technology.properties(property_id), FOREIGN KEY (guest_id) REFERENCES hospitality_technology.guests(guest_id), FOREIGN KEY (room_id) REFERENCES hospitality_technology.rooms(room_id), FOREIGN KEY (room_type_id) REFERENCES hospitality_technology.room_types(room_type_id) )


[User] List each port along with the count of distinct IP addresses observed on that port.

[Assistant] SELECT port, COUNT(DISTINCT ip_address) AS unique_ip_count FROM blockchain.nodes GROUP BY port;

[User] Only include ports that have more than 3 unique IP addresses.

[Assistant] SELECT port, COUNT(DISTINCT ip_address) AS unique_ip_count FROM blockchain.nodes GROUP BY port HAVING COUNT(DISTINCT ip_address) > 3;

[User] Also include the latest last_seen timestamp for each of these ports.

[Assistant] SELECT port, COUNT(DISTINCT ip_address) AS unique_ip_count, MAX(last_seen) AS last_seen_latest FROM blockchain.nodes GROUP BY port HAVING COUNT(DISTINCT ip_address) > 3;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE blockchain.nodes ( node_id character varying(64) NOT NULL, ip_address character varying(15) NOT NULL, port integer NOT NULL, last_seen timestamp NOT NULL, PRIMARY KEY (node_id) )


[User] I need to identify pairs of verified documents submitted by the same citizen. For each pair, display the citizen_id, the earlier document_id with its verification timestamp, and the later document_id with its verification timestamp.

[Assistant]
SELECT
  d1.citizen_id,
  d1.document_id AS earlier_document_id,
  d1.verification_timestamp AS earlier_verification,
  d2.document_id AS later_document_id,
  d2.verification_timestamp AS later_verification
FROM government_services.documents d1
JOIN government_services.documents d2
  ON d1.citizen_id = d2.citizen_id
  AND d1.verification_timestamp < d2.verification_timestamp
WHERE d1.verification_status = 'Verified'
  AND d2.verification_status = 'Verified';

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE government_services.documents ( document_id character varying(64) NOT NULL, application_id character varying(64), citizen_id character varying(64) NOT NULL, document_type character varying(100) NOT NULL, file_reference text NOT NULL, upload_timestamp timestamp NOT NULL, expiry_date date, verification_status character varying(30) DEFAULT 'Pending', verified_by_employee_id character varying(64), verification_timestamp timestamp, PRIMARY KEY (document_id) )


[User] Count the number of policies issued in each calendar year, and show the year and the count.

[Assistant] SELECT EXTRACT(YEAR FROM issued_at), COUNT(*) FROM insurance.policies WHERE issued_at IS NOT NULL GROUP BY 1 ORDER BY 1;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE insurance.customers ( customer_id text, first_name text, last_name text, date_of_birth date, ssn_hash text, address_line1 text, address_line2 text, city text, state text, zip_code text, country text, phone_number text, email text, created_at timestamp, updated_at timestamp, status text )
CREATE TABLE insurance.policies ( policy_id text, customer_id text, product_id text, agent_id text, policy_number text, start_date date, end_date date, premium_amount numeric, coverage_limit numeric, deductible numeric, status text, issued_at timestamp, cancellation_date date, cancellation_reason text )
CREATE TABLE insurance.insurance_products ( product_id text, product_name text, product_type text, description text, base_premium numeric, coverage_details text, underwriting_rules text, is_active boolean, created_at timestamp, updated_at timestamp )
CREATE TABLE insurance.agents ( agent_id text, first_name text, last_name text, agency_name text, license_number text, license_state text, contact_email text, contact_phone text, hire_date date, termination_date date, status text, commission_rate numeric, manager_id text )
CREATE TABLE insurance.policy_beneficiaries ( beneficiary_id text, policy_id text, customer_id text, first_name text, last_name text, relationship text, percentage_share numeric, contact_info text, added_at timestamp )


[User] Tell me the count of hidden achievements and non-hidden achievements.

[Assistant] SELECT hidden, COUNT(*) FROM achievements GROUP BY hidden;

[User] What's the average point value for hidden vs non-hidden achievements?

[Assistant] SELECT hidden, AVG(points) FROM achievements GROUP BY hidden;

[User] Can you combine the count and average points in one query?

[Assistant] SELECT hidden, COUNT(*), AVG(points) FROM achievements GROUP BY hidden;

[User] Now, add the maximum point value for each group.

[Assistant] SELECT hidden, COUNT(*), AVG(points), MAX(points) FROM achievements GROUP BY hidden;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE gaming_technology.achievements ( achievement_id.uuid, game_id.uuid, name.text, description.text, icon_url.text, points.integer, hidden.boolean )


[User] Show the full names and contact emails of all citizens who have applied for services with a standard fee greater than 100.

[Assistant]
SELECT c.first_name || ' ' || c.last_name AS full_name, c.contact_email
FROM government_services.citizens c
JOIN government_services.services s ON c.citizen_id IS NOT NULL -- Replace with actual application linking table if exists
WHERE s.standard_fee > 100;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE government_services.citizens ( citizen_id character varying(64) NOT NULL, national_id_number character varying(128) NOT NULL UNIQUE, first_name character varying(100) NOT NULL, last_name character varying(100) NOT NULL, date_of_birth date NOT NULL, gender character varying(20), primary_address text NOT NULL, contact_email character varying(128) UNIQUE, contact_phone character varying(32), registration_date timestamp NOT NULL, is_verified boolean DEFAULT false, PRIMARY KEY (citizen_id) )
CREATE TABLE government_services.services ( service_id.text, agency_id.text, service_name.text, description.text, category.text, eligibility_criteria.text, standard_fee.numeric, average_processing_time_days.integer, is_active.boolean, online_application_url.text )


[User] Can you show me all pairs of customers living in the same city but with different last names? Show both customer IDs, both full names, and their city.

[Assistant] SELECT a.customer_id AS customer_id_a, CONCAT(a.first_name, ' ', a.last_name) AS full_name_a, b.customer_id AS customer_id_b, CONCAT(b.first_name, ' ', b.last_name) AS full_name_b, a.city FROM financial_services.customers a JOIN financial_services.customers b ON a.city = b.city AND a.last_name <> b.last_name AND a.customer_id < b.customer_id;

[User] Add a filter to only include pairs where both customers are in the same state as well.

[Assistant] SELECT a.customer_id AS customer_id_a, CONCAT(a.first_name, ' ', a.last_name) AS full_name_a, b.customer_id AS customer_id_b, CONCAT(b.first_name, ' ', b.last_name) AS full_name_b, a.city, a.state FROM financial_services.customers a JOIN financial_services.customers b ON a.city = b.city AND a.state = b.state AND a.last_name <> b.last_name AND a.customer_id < b.customer_id;

[User] Please further restrict results to only pairs where both customers have a status of 'Active'.

[Assistant] SELECT a.customer_id AS customer_id_a, CONCAT(a.first_name, ' ', a.last_name) AS full_name_a, b.customer_id AS customer_id_b, CONCAT(b.first_name, ' ', b.last_name) AS full_name_b, a.city, a.state FROM financial_services.customers a JOIN financial_services.customers b ON a.city = b.city AND a.state = b.state AND a.last_name <> b.last_name AND a.status = 'Active' AND b.status = 'Active' AND a.customer_id < b.customer_id;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE financial_services.customers ( customer_id text, first_name text, last_name text, date_of_birth date, ssn_hash text, address text, city text, state text, zip_code text, country text, email text, phone_number text, created_at timestamp, status text, risk_profile text )


[User] List all medical record entries where the treatment_plan mentions a medication name. Return patient_id, record_id, and the matching medication_name.

[Assistant]
SELECT mr.patient_id,
       mr.record_id,
       m.medication_name
FROM healthcare.medical_records AS mr
JOIN healthcare.medications AS m
  ON mr.treatment_plan ILIKE '%' || m.medication_name || '%';

[User] Actually, only include medications manufactured by 'Pfizer'.

[Assistant]
SELECT mr.patient_id,
       mr.record_id,
       m.medication_name
FROM healthcare.medical_records AS mr
JOIN healthcare.medications AS m
  ON mr.treatment_plan ILIKE '%' || m.medication_name || '%'
WHERE m.manufacturer = 'Pfizer';

[User] Also sort the results by record_date descending.

[Assistant]
SELECT mr.patient_id,
       mr.record_id,
       m.medication_name
FROM healthcare.medical_records AS mr
JOIN healthcare.medications AS m
  ON mr.treatment_plan ILIKE '%' || m.medication_name || '%'
WHERE m.manufacturer = 'Pfizer'
ORDER BY mr.record_date DESC;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE healthcare.patients (
    patient_id character varying(64) NOT NULL,  -- unique identifier for the patient
    first_name character varying(100) NOT NULL, -- patient's first name
    last_name character varying(100) NOT NULL, -- patient's last name
    date_of_birth date NOT NULL, -- patient's date of birth
    gender character varying(10), -- patient's gender (e.g., Male, Female, Other)
    address text, -- patient's home address
    phone_number character varying(20), -- patient's phone number
    email character varying(128) UNIQUE, -- patient's email address
    emergency_contact_name character varying(200), -- name of emergency contact
    emergency_contact_phone character varying(20), -- phone number of emergency contact
    created_at timestamp with time zone NOT NULL DEFAULT current_timestamp, -- record creation time
    updated_at timestamp with time zone NOT NULL DEFAULT current_timestamp, -- record last update time
    PRIMARY KEY (patient_id)
)
CREATE TABLE healthcare.doctors (
    doctor_id character varying(64) NOT NULL,  -- unique identifier for the doctor
    first_name character varying(100) NOT NULL, -- doctor's first name
    last_name character varying(100) NOT NULL, -- doctor's last name
    specialty character varying(100) NOT NULL, -- doctor's medical specialty
    license_number character varying(50) UNIQUE NOT NULL, -- doctor's medical license number
    phone_number character varying(20), -- doctor's contact phone
    email character varying(128) UNIQUE, -- doctor's contact email
    hospital_affiliation_id character varying(64), -- FK to hospitals table (optional)
    created_at timestamp with time zone NOT NULL DEFAULT current_timestamp,
    updated_at timestamp with time zone NOT NULL DEFAULT current_timestamp,
    PRIMARY KEY (doctor_id)
)
CREATE TABLE healthcare.appointments (
    appointment_id character varying(64) NOT NULL, -- unique identifier for the appointment
    patient_id character varying(64) NOT NULL, -- FK to patients table
    doctor_id character varying(64) NOT NULL, -- FK to doctors table
    appointment_time timestamp with time zone NOT NULL, -- date and time of the appointment
    duration_minutes integer NOT NULL, -- expected duration in minutes
    reason text, -- reason for the visit
    status character varying(32) NOT NULL, -- e.g., Scheduled, Completed, Cancelled, No-show
    location_id character varying(64), -- FK to a potential locations/clinics table
    notes text, -- notes related to scheduling
    created_at timestamp with time zone NOT NULL DEFAULT current_timestamp,
    PRIMARY KEY (appointment_id)
)
CREATE TABLE healthcare.medical_records (
    record_id character varying(64) NOT NULL,  -- unique identifier for the medical record entry
    patient_id character varying(64) NOT NULL, -- FK to patients table
    appointment_id character varying(64) UNIQUE, -- FK to appointments table (can be null if record not tied to specific appt)
    doctor_id character varying(64) NOT NULL, -- FK to doctors table (doctor creating the record)
    record_date timestamp with time zone NOT NULL, -- date the record/observation was made
    chief_complaint text, -- patient's primary reason for visit
    present_illness_history text, -- detailed history of the current issue
    past_medical_history text, -- relevant past conditions/surgeries
    physical_examination_notes text, -- findings from the physical exam
    assessment text, -- doctor's assessment/diagnosis summary
    treatment_plan text, -- planned course of action
    vitals jsonb, -- store vitals like BP, HR, Temp as structured JSON
    created_at timestamp with time zone NOT NULL DEFAULT current_timestamp,
    PRIMARY KEY (record_id)
)
CREATE TABLE healthcare.medications (
    medication_id character varying(64) NOT NULL, -- unique identifier for the medication type
    medication_name character varying(255) NOT NULL, -- common or brand name
    generic_name character varying(255), -- generic chemical name
    manufacturer character varying(100), -- drug manufacturer
    ndc_code character varying(20) UNIQUE, -- National Drug Code (optional but useful)
    description text, -- description of the medication
    PRIMARY KEY (medication_id)
)
CREATE TABLE healthcare.insurance_plans (
    plan_id character varying(64) NOT NULL, -- unique identifier for the insurance plan
    plan_name character varying(200) NOT NULL, -- name of the insurance plan
    insurance_provider character varying(100) NOT NULL, -- name of the insurance company
    plan_type character varying(50), -- e.g., PPO, HMO, EPO
    contact_phone character varying(20), -- provider contact number
    website character varying(255), -- provider website
    PRIMARY KEY (plan_id)
)
CREATE TABLE healthcare.patient_insurance (
    patient_insurance_id character varying(64) NOT NULL, -- unique identifier for this patient-plan link
    patient_id character varying(64) NOT NULL, -- FK to patients table
    plan_id character varying(64) NOT NULL, -- FK to insurance_plans table
    policy_number character varying(100) NOT NULL, -- patient's policy number
    group_number character varying(100), -- group number, if applicable
    subscriber_name character varying(200), -- name of the primary policy holder
    effective_date date NOT NULL, -- date the coverage begins
    expiration_date date, -- date the coverage ends (if known)
    is_primary boolean NOT NULL DEFAULT true, -- indicates if this is the primary insurance
    PRIMARY KEY (patient_insurance_id),
    UNIQUE (patient_id, plan_id, policy_number) -- ensure a patient doesn't have the same policy twice
)


[User] Show me the top 5 projects by valuation that completed fundraising rounds in the last 6 months, along with their latest round name and investment value.

[Assistant] SELECT project_name, rounds_name, investment_value, valuation FROM project_fundraising_record WHERE investment_date >= DATE_SUB(CURRENT_DATE, INTERVAL 6 MONTH) ORDER BY valuation DESC LIMIT 5;

[User] Can you also include the introduction text for these projects and filter to only include those with valuation over $50 million?

[Assistant] SELECT project_name, rounds_name, investment_value, valuation, introduction FROM project_fundraising_record WHERE investment_date >= DATE_SUB(CURRENT_DATE, INTERVAL 6 MONTH) AND valuation > 50000000 ORDER BY valuation DESC LIMIT 5;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
 "CREATE TABLE project_fundraising_record (",
    "id character varying(32) NOT NULL,  -- fundraising record id",
    "project_id character varying(32) NOT NULL, -- the invested project's id",
    "project_name character varying(128) NOT NULL, -- name of the invested project",
    "rounds_name character varying(32), -- name of the fundraising round",
    "investment_value numeric(38,14), -- amount of the fundraising in USD",
    "investment_date character varying(128), -- the date of the investment happened",
    "introduction character varying(128), -- the introduction of the invested project",
    "valuation numeric(38,14), -- the valuation of the project in USD when invested",

  "CREATE TABLE cex_token_balance (",
    "snapshot_time character varying(32) NOT NULL,  -- the snapshot time of record, converted from original timestamp",
    "chain character varying(128) NOT NULL, -- the chain that the token resides",
    "address character varying(128) NOT NULL, -- the address that holds the assets, owned by a CEX",
    "exchange character varying(512) NOT NULL, -- a centralized exchange name",
    "token_address character varying(128) NOT NULL, -- token contract address",
    "token_symbol character varying(512), --token symbol",
    "balance numeric(38,10), -- token balance",
    "usd_value numeric(38,14), -- value of the token held in USD",
    "price double precision, --price of the token in USD",
    ",PRIMARY KEY (snapshot_time, exchange, address, chain, token_address));"

  "CREATE TABLE smart_money_profit (",
    "address character varying(100) NOT NULL, -- the user's address",
    "rank INT, -- the rank of the address in trade performance, value 1 expresses the best address.",
    "profit numeric(38,6), -- the profit user made in a month",
    "roi numeric(38,2), -- the roi of the user in a month",
    "realized_ratio numeric(38,2), -- the percentage of the user's realized profit",
    "most_profit_token character varying(100), -- the token symbol of the user's most profitable trade",
    "last_trade_time character varying(100), -- the last trade time of the user",
    "chain character varying(100), -- the chain that the address resides",
    "PRIMARY KEY (address, chain));",

  "CREATE TABLE smart_money_token_performance (",
    "token_address character varying(100) NOT NULL, -- the token's address",
    "token_symbol character varying(100), -- the tokens's symbol",
    "pnl numeric(38,2), -- the profit users made on this token",
    "net_flow numeric(38,2), -- the netflow of the token, means the money user spent minus the the money user sold of this token",
    "avg_cost numeric(38,16), -- the average cost price of user spent on this token",
    "price double precision, -- the current price of the token",
    "realized_ratio numeric(10,2), -- the ratio user sold of the token",
    "roi numeric(10,2), -- the roi users made of this token",
    "chain character varying(100), -- the chain that the token resides",
    "PRIMARY KEY (token_address, chain));",


[User] Can you show me the user IDs and their theme settings for all users who have enabled email notifications and have updated their settings in 2024?

[Assistant] SELECT user_id, theme FROM social_media.user_settings WHERE email_notifications_enabled = TRUE AND updated_at >= '2024-01-01';

[User] What if I also want to see if their profile is private or not?

[Assistant] SELECT user_id, theme, private_profile FROM social_media.user_settings WHERE email_notifications_enabled = TRUE AND updated_at >= '2024-01-01';

[User] Actually, I want to see users who have both email AND push notifications enabled.

[Assistant] SELECT user_id, theme, private_profile FROM social_media.user_settings WHERE email_notifications_enabled = TRUE AND push_notifications_enabled = TRUE AND updated_at >= '2024-01-01';

[User] Now, limit the results to users whose theme is 'light' only.

[Assistant] SELECT user_id, theme, private_profile FROM social_media.user_settings WHERE email_notifications_enabled = TRUE AND push_notifications_enabled = TRUE AND theme = 'light' AND updated_at >= '2024-01-01';

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE social_media.user_settings ( setting_id text PRIMARY KEY, user_id text, theme text, email_notifications_enabled bool, push_notifications_enabled bool, private_profile bool, updated_at timestamp )


[User] List all patients who have insurance plans with group numbers, showing their patient IDs and the count of such plans per patient.

[Assistant] SELECT patient_id, COUNT(*) AS plan_count FROM healthcare.patient_insurance WHERE group_number IS NOT NULL GROUP BY patient_id;

[User] Actually, I only need patients who have more than 2 such plans.

[Assistant] SELECT patient_id, COUNT(*) AS plan_count FROM healthcare.patient_insurance WHERE group_number IS NOT NULL GROUP BY patient_id HAVING COUNT(*) > 2;

[User] Can you also include the earliest effective date among these plans for each patient?

[Assistant] SELECT patient_id, COUNT(*) AS plan_count, MIN(effective_date) AS earliest_effective_date FROM healthcare.patient_insurance WHERE group_number IS NOT NULL GROUP BY patient_id HAVING COUNT(*) > 2;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE healthcare.patient_insurance (
    patient_insurance_id character varying(64) NOT NULL, -- unique identifier for this patient-plan link
    patient_id character varying(64) NOT NULL, -- FK to patients table
    plan_id character varying(64) NOT NULL, -- FK to insurance_plans table
    policy_number character varying(100) NOT NULL, -- patient's policy number
    group_number character varying(100), -- group number, if applicable
    subscriber_name character varying(200), -- name of the primary policy holder
    effective_date date NOT NULL, -- date the coverage begins
    expiration_date date, -- date the coverage ends (if known)
    is_primary boolean NOT NULL DEFAULT true, -- indicates if this is the primary insurance
    PRIMARY KEY (patient_insurance_id),
    UNIQUE (patient_id, plan_id, policy_number) -- ensure a patient doesn't have the same policy twice
)


[User] List each patient's first and last name along with the insurance plan name they are enrolled in, including only primary policies. Return patient_id, first_name, last_name, and plan_name.

[Assistant]
SELECT p.patient_id,
       p.first_name,
       p.last_name,
       ip.plan_name
FROM healthcare.patients AS p
JOIN healthcare.patient_insurance AS pi
  ON p.patient_id = pi.patient_id AND pi.is_primary = true
JOIN healthcare.insurance_plans AS ip ON pi.plan_id = ip.plan_id;

[User] Now limit to plans with plan_type 'EPO' and sort by patient last name ascending.

[Assistant]
SELECT p.patient_id,
       p.first_name,
       p.last_name,
       ip.plan_name
FROM healthcare.patients AS p
JOIN healthcare.patient_insurance AS pi
  ON p.patient_id = pi.patient_id AND pi.is_primary = true
JOIN healthcare.insurance_plans AS ip ON pi.plan_id = ip.plan_id
WHERE ip.plan_type = 'EPO'
ORDER BY p.last_name ASC;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE healthcare.patients ( patient_id character varying(64) NOT NULL, first_name character varying(100) NOT NULL, last_name character varying(100) NOT NULL, date_of_birth date NOT NULL, gender character varying(10), address text, phone_number character varying(20), email character varying(128) UNIQUE, emergency_contact_name character varying(200), emergency_contact_phone character varying(20), created_at timestamp with time zone NOT NULL DEFAULT current_timestamp, updated_at timestamp with time zone NOT NULL DEFAULT current_timestamp, PRIMARY KEY (patient_id) )
CREATE TABLE healthcare.appointments ( appointment_id text, patient_id text, doctor_id text, appointment_time timestamp, duration_minutes integer, reason text, status text, location_id text, notes text, created_at timestamp )
CREATE TABLE healthcare.medical_records ( record_id character varying(64) NOT NULL, patient_id character varying(64) NOT NULL, appointment_id character varying(64) UNIQUE, doctor_id character varying(64) NOT NULL, record_date timestamp with time zone NOT NULL, chief_complaint text, present_illness_history text, past_medical_history text, physical_examination_notes text, assessment text, treatment_plan text, vitals jsonb, created_at timestamp with time zone NOT NULL DEFAULT current_timestamp, PRIMARY KEY (record_id) )
CREATE TABLE healthcare.diagnoses ( diagnosis_id text PRIMARY KEY, record_id text, patient_id text, doctor_id text, diagnosis_code text, code_type text, description text, diagnosis_date date, status text, is_chronic boolean )
CREATE TABLE healthcare.medications ( medication_id text, medication_name text, generic_name text, manufacturer text, ndc_code text, description text )
CREATE TABLE healthcare.prescriptions ( prescription_id.text, record_id.text, patient_id.text, doctor_id.text, medication_id.text, dosage.text, frequency.text, route.text, start_date.date, end_date.date, quantity_dispensed.numeric, refills_allowed.integer, prescription_date.timestamp )
CREATE TABLE healthcare.insurance_plans ( plan_id.text, plan_name.text, insurance_provider.text, plan_type.text, contact_phone.text, website.text )
CREATE TABLE healthcare.patient_insurance ( patient_insurance_id character varying(64) NOT NULL, patient_id character varying(64) NOT NULL, plan_id character varying(64) NOT NULL, policy_number character varying(100) NOT NULL, group_number character varying(100), subscriber_name character varying(200), effective_date date NOT NULL, expiration_date date, is_primary boolean NOT NULL DEFAULT true, PRIMARY KEY (patient_insurance_id), UNIQUE (patient_id, plan_id, policy_number) )


[User] List the record ID, record date, and chief complaint for all medical records created by doctor 'doc_321' for patient 'pat_007'.

[Assistant]
SELECT record_id, record_date, chief_complaint
FROM healthcare.medical_records
WHERE doctor_id = 'doc_321' AND patient_id = 'pat_007';

[User] I only want to see those records where the assessment was provided by the doctor.

[Assistant]
SELECT record_id, record_date, chief_complaint
FROM healthcare.medical_records
WHERE doctor_id = 'doc_321' AND patient_id = 'pat_007'
  AND assessment IS NOT NULL;

[User] Actually, can you also show the treatment plan in the results?

[Assistant]
SELECT record_id, record_date, chief_complaint, treatment_plan
FROM healthcare.medical_records
WHERE doctor_id = 'doc_321' AND patient_id = 'pat_007'
  AND assessment IS NOT NULL;

[User] Please adjust the query to only include records created after March 1, 2024.

[Assistant]
SELECT record_id, record_date, chief_complaint, treatment_plan
FROM healthcare.medical_records
WHERE doctor_id = 'doc_321' AND patient_id = 'pat_007'
  AND assessment IS NOT NULL
  AND record_date > '2024-03-01';

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE healthcare.medical_records (
    record_id character varying(64) NOT NULL,  -- unique identifier for the medical record entry
    patient_id character varying(64) NOT NULL, -- FK to patients table
    appointment_id character varying(64) UNIQUE, -- FK to appointments table (can be null if record not tied to specific appt)
    doctor_id character varying(64) NOT NULL, -- FK to doctors table (doctor creating the record)
    record_date timestamp with time zone NOT NULL, -- date the record/observation was made
    chief_complaint text, -- patient's primary reason for visit
    present_illness_history text, -- detailed history of the current issue
    past_medical_history text, -- relevant past conditions/surgeries
    physical_examination_notes text, -- findings from the physical exam
    assessment text, -- doctor's assessment/diagnosis summary
    treatment_plan text, -- planned course of action
    vitals jsonb, -- store vitals like BP, HR, Temp as structured JSON
    created_at timestamp with time zone NOT NULL DEFAULT current_timestamp,
    PRIMARY KEY (record_id)
)


[User] List the diagnosis code, description, and insurance provider for all diagnoses where the code type is 'ICD-9'.

[Assistant]
SELECT d.diagnosis_code, d.description, ip.insurance_provider
FROM healthcare.diagnoses d
JOIN healthcare.insurance_plans ip ON d.diagnosis_code = ip.plan_id
WHERE d.code_type = 'ICD-9';

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE healthcare.diagnoses ( diagnosis_id.text, record_id.text, patient_id.text, doctor_id.text, diagnosis_code.text, code_type.text, description.text, diagnosis_date.date, status.text, is_chronic.boolean )
CREATE TABLE healthcare.insurance_plans ( plan_id.text, plan_name.text, insurance_provider.text, plan_type.text, contact_phone.text, website.text )


[User] For each chain in the smart money token inflow data, calculate the total number of addresses involved in buy transactions and the total number of addresses involved in sell transactions. Display the chain, total buy addresses, and total sell addresses.

[Assistant] SELECT chain, SUM(CASE WHEN type = 1 THEN address_amount ELSE 0 END) AS total_buy_addresses, SUM(CASE WHEN type = 2 THEN address_amount ELSE 0 END) AS total_sell_addresses FROM smart_money_token_inflow WHERE type IN (1, 2) GROUP BY chain;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE project_fundraising_record ( id.text, project_id.text, project_name.text, rounds_name.text, investment_value.numeric, investment_date.text, introduction.text, valuation.numeric )
CREATE TABLE token_basic_info ( coin_id.text, token_name.text, token_symbol.text, token_address.text, chain.text, price.numeric, price_change_percentage_1h.numeric, price_change_percentage_24h.numeric, price_change_percentage_7d.numeric, highest_price_24h.numeric, lowest_price_24h.numeric, market_cap.numeric, market_cap_rank.numeric, market_cap_change_percentage_24h.text, total_volume.text, narrative.text, trend_rank.numeric )
CREATE TABLE token_dexpool_info ( pair_address.text, token_name.text, token_symbol.text, chain.text, price.numeric, price_change_percentage_1h.numeric, price_change_percentage_6h.numeric, price_change_percentage_24h.numeric, makers_24h.numeric, volume_24h.numeric, liquidity.numeric, market_cap.numeric, trend_rank.numeric )
CREATE TABLE cex_token_balance ( snapshot_time.text, chain.text, address.text, exchange.text, token_address.text, token_symbol.text, balance.numeric, usd_value.numeric, price.numeric )
CREATE TABLE smart_money_token_inflow ( token_address.text, token_symbol.text, token_amount.numeric, usd_value.numeric, avg_price.numeric, type.numeric, address_amount.numeric, narrative.text, chain.text )


[User] For each event recorded, list its ID, name, and the status and value of the transaction in which it occurred.

[Assistant] SELECT E.event_id, E.event_name, E.transaction_id, T.status, T.value FROM web3.events AS E JOIN web3.transactions AS T ON E.transaction_id = T.transaction_id;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE web3.events (
    event_id character varying(64) NOT NULL,  -- unique identifier for the event
    contract_id character varying(64) NOT NULL, -- identifier of the contract emitting the event
    event_name character varying(128) NOT NULL, -- name of the event
    data text NOT NULL, -- data payload of the event
    emitted_at timestamp NOT NULL, -- time when the event was emitted
    transaction_id character varying(64) NOT NULL, -- identifier of the transaction that triggered the event
    log_index integer NOT NULL, -- index of the event log in the transaction
    PRIMARY KEY (event_id)
)
CREATE TABLE web3.transactions ( transaction_id character varying(64) NOT NULL, from_address character varying(128) NOT NULL, to_address character varying(128), value numeric(38,14) NOT NULL, gas_used integer NOT NULL, gas_price numeric(38,14) NOT NULL, block_number integer NOT NULL, timestamp timestamp NOT NULL, input_data text, status character varying(32) NOT NULL, nonce integer NOT NULL, PRIMARY KEY (transaction_id) )
CREATE TABLE web3.tokens ( token_id text PRIMARY KEY, contract_address text, token_name text, token_symbol text, decimals int, total_supply numeric )
CREATE TABLE web3.wallets ( wallet_id text, user_id text, address text, private_key text, created_at timestamp )
CREATE TABLE web3.users ( user_id text, username text, email text, password_hash text, created_at timestamp )


[User] For each chain, find the narrative category that has the highest total market_cap and display the chain, narrative, and that total market_cap.

[Assistant]
SELECT chain,
       narrative,
       total_cap
FROM (
  SELECT chain,
         narrative,
         SUM(market_cap) AS total_cap,
         RANK() OVER (PARTITION BY chain ORDER BY SUM(market_cap) DESC) AS rnk
  FROM token_basic_info
  GROUP BY chain, narrative
) t
WHERE rnk = 1;

[User] I received an error about window functions. Can you rewrite the query without using window functions?

[Assistant]
WITH agg AS (
  SELECT chain,
         narrative,
         SUM(market_cap) AS total_cap
  FROM token_basic_info
  GROUP BY chain, narrative
),
max_cap AS (
  SELECT chain,
         MAX(total_cap) AS max_cap
  FROM agg
  GROUP BY chain
)
SELECT a.chain,
       a.narrative,
       a.total_cap
FROM agg a
JOIN max_cap m
  ON a.chain = m.chain
 AND a.total_cap = m.max_cap;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE token_basic_info ( coin_id text, token_name text, token_symbol text, token_address text, chain text, price numeric, price_change_percentage_1h numeric, price_change_percentage_24h numeric, price_change_percentage_7d numeric, highest_price_24h numeric, lowest_price_24h numeric, market_cap numeric, market_cap_rank numeric, market_cap_change_percentage_24h text, total_volume text, narrative text, trend_rank numeric )


[User] Show the average maintenance cost for each service type per vehicle.

[Assistant]
SELECT vehicle_id,
       service_type,
       AVG(cost) AS avg_cost
FROM transportation.maintenance_logs
GROUP BY vehicle_id, service_type;

[User] Actually, only include those averages greater than 300.

[Assistant]
SELECT vehicle_id,
       service_type,
       AVG(cost) AS avg_cost
FROM transportation.maintenance_logs
GROUP BY vehicle_id, service_type
HAVING AVG(cost) > 300;

[User] Also include the number of services for each of those.

[Assistant]
SELECT vehicle_id,
       service_type,
       COUNT(*) AS service_count,
       AVG(cost) AS avg_cost
FROM transportation.maintenance_logs
GROUP BY vehicle_id, service_type
HAVING AVG(cost) > 300;

[User] Sort the results by avg_cost descending and limit to the top 5.

[Assistant]
SELECT vehicle_id,
       service_type,
       COUNT(*) AS service_count,
       AVG(cost) AS avg_cost
FROM transportation.maintenance_logs
GROUP BY vehicle_id, service_type
HAVING AVG(cost) > 300
ORDER BY avg_cost DESC
LIMIT 5;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE transportation.vehicles ( vehicle_id text PRIMARY KEY, license_plate text, vin text, make text, model text, year int, type text, capacity int, fuel_type text, status text, depot_id text, acquisition_date date )
CREATE TABLE transportation.locations ( location_id text PRIMARY KEY, name text, type text, address_line1 text, city text, state_province text, postal_code text, country text, latitude numeric, longitude numeric, timezone text )
CREATE TABLE transportation.maintenance_logs ( log_id.text, vehicle_id.text, service_date.date, odometer_reading.integer, service_type.text, description.text, cost.numeric, mechanic_name.text, next_service_due_date.date )
CREATE TABLE transportation.fuel_logs (
    fuel_log_id character varying(64) NOT NULL,  -- unique identifier for the fuel log entry
    vehicle_id character varying(64) NOT NULL, -- identifier of the vehicle fueled
    trip_id character varying(64), -- optional: identifier of the trip during which fueling occurred
    log_timestamp timestamp with time zone NOT NULL, -- time when fueling occurred
    fuel_type character varying(32) NOT NULL, -- type of fuel added (matches vehicle's fuel type)
    quantity numeric(10, 3) NOT NULL, -- amount of fuel added (e.g., Liters, Gallons, kWh)
    unit character varying(16) NOT NULL, -- unit of quantity (e.g., L, gal, kWh)
    cost_per_unit numeric(8, 4), -- price per unit of fuel
    total_cost numeric(10, 2) NOT NULL, -- total cost of the fuel purchase
    odometer_reading integer, -- vehicle mileage at time of fueling
    location_id character varying(64), -- identifier of the fueling station/location
    PRIMARY KEY (fuel_log_id)
)


[User] Show me all business center services (category = 'Business Center') along with their property IDs and descriptions, where the service is available.

[Assistant] SELECT service_name, property_id, description FROM hospitality_technology.services WHERE category = 'Business Center' AND is_available = true;

[User] Now, join this with another query to include the property names from the properties table (assuming properties table has property_id and property_name columns).

[Assistant] SELECT s.service_name, s.property_id, s.description, p.property_name FROM hospitality_technology.services s JOIN hospitality_technology.properties p ON s.property_id = p.property_id WHERE s.category = 'Business Center' AND s.is_available = true;

[User] The query is missing the price information. Can you include that as well?

[Assistant] SELECT s.service_name, s.property_id, s.description, p.property_name, s.price FROM hospitality_technology.services s JOIN hospitality_technology.properties p ON s.property_id = p.property_id WHERE s.category = 'Business Center' AND s.is_available = true;

[User] Actually, I need to see only services priced per hour (unit = 'Per Hour'), and order them by property name in alphabetical order.

[Assistant] SELECT s.service_name, s.property_id, s.description, p.property_name, s.price FROM hospitality_technology.services s JOIN hospitality_technology.properties p ON s.property_id = p.property_id WHERE s.category = 'Business Center' AND s.is_available = true AND s.unit = 'Per Hour' ORDER BY p.property_name ASC;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE hospitality_technology.services (
    service_id character varying(64) NOT NULL, -- unique identifier for a chargeable service
    property_id character varying(64) NOT NULL, -- FK to properties table
    service_name character varying(150) NOT NULL, -- e.g., Room Service - Burger, Spa - Massage 60min, Laundry - Shirt
    description text,
    category character varying(100), -- e.g., Food & Beverage, Wellness, Business Center, Activities
    price numeric(10, 2) NOT NULL, -- price per unit/instance
    unit character varying(30), -- e.g., Per Item, Per Hour, Per Day
    is_available boolean NOT NULL DEFAULT true, -- is the service currently offered?
    department character varying(100), -- department responsible (e.g., F&B, Spa, Housekeeping)
    PRIMARY KEY (service_id),
    FOREIGN KEY (property_id) REFERENCES hospitality_technology.properties(property_id)
)


[User] Summarize the total principal amount for loans, grouped by customer and their account type. Include the customer's full name.

[Assistant] SELECT T1.first_name, T1.last_name, T2.account_type, SUM(T3.principal_amount) FROM financial_services.customers AS T1 JOIN financial_services.accounts AS T2 ON T1.customer_id = T2.customer_id JOIN financial_services.loans AS T3 ON T2.account_id = T3.account_id GROUP BY T1.customer_id, T1.first_name, T1.last_name, T2.account_type;

[User] Only include accounts and loans that are currently 'Active'.

[Assistant] SELECT T1.first_name, T1.last_name, T2.account_type, SUM(T3.principal_amount) FROM financial_services.customers AS T1 JOIN financial_services.accounts AS T2 ON T1.customer_id = T2.customer_id JOIN financial_services.loans AS T3 ON T2.account_id = T3.account_id WHERE T2.status = 'Active' AND T3.status = 'Active' GROUP BY T1.customer_id, T1.first_name, T1.last_name, T2.account_type;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE financial_services.customers ( customer_id character varying(64) NOT NULL, first_name character varying(100) NOT NULL, last_name character varying(100) NOT NULL, date_of_birth date NOT NULL, ssn_hash character varying(128), address text NOT NULL, city character varying(100) NOT NULL, state character varying(50) NOT NULL, zip_code character varying(20) NOT NULL, country character varying(50) NOT NULL, email character varying(128) UNIQUE, phone_number character varying(32), created_at timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, status character varying(32) NOT NULL, risk_profile character varying(50), PRIMARY KEY (customer_id) )
CREATE TABLE financial_services.accounts ( account_id character varying(64) NOT NULL, customer_id character varying(64) NOT NULL, account_number character varying(128) NOT NULL UNIQUE, account_type character varying(50) NOT NULL, balance numeric(19, 4) NOT NULL DEFAULT 0.00, currency character varying(3) NOT NULL, opened_date date NOT NULL, status character varying(32) NOT NULL, interest_rate numeric(5, 4), last_updated_at timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY (account_id), FOREIGN KEY (customer_id) REFERENCES financial_services.customers(customer_id) )
CREATE TABLE financial_services.securities ( security_id character varying(64) NOT NULL, ticker_symbol character varying(20) NOT NULL UNIQUE, isin_code character varying(12) UNIQUE, cusip_code character varying(9) UNIQUE, security_name text NOT NULL, security_type character varying(50) NOT NULL, exchange character varying(50), currency character varying(3) NOT NULL, issuer_name character varying(255), sector character varying(100), last_updated timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY (security_id) )
CREATE TABLE financial_services.trades ( trade_id character varying(64) NOT NULL, account_id character varying(64) NOT NULL, security_id character varying(64) NOT NULL, order_id character varying(64), trade_type character varying(10) NOT NULL, quantity numeric(19, 8) NOT NULL, price_per_unit numeric(19, 8) NOT NULL, total_amount numeric(19, 4) NOT NULL, commission numeric(10, 4), trade_timestamp timestamp NOT NULL, settlement_date date, status character varying(32) NOT NULL, execution_venue character varying(100), PRIMARY KEY (trade_id), FOREIGN KEY (account_id) REFERENCES financial_services.accounts(account_id), FOREIGN KEY (security_id) REFERENCES financial_services.securities(security_id) )
CREATE TABLE financial_services.market_data ( data_point_id bigserial NOT NULL, security_id character varying(64) NOT NULL, data_timestamp timestamp NOT NULL, open_price numeric(19, 8), high_price numeric(19, 8), low_price numeric(19, 8), close_price numeric(19, 8) NOT NULL, adjusted_close_price numeric(19, 8), volume bigint, source character varying(50), PRIMARY KEY (data_point_id), UNIQUE (security_id, data_timestamp), FOREIGN KEY (security_id) REFERENCES financial_services.securities(security_id) )
CREATE TABLE financial_services.employees ( employee_id character varying(64) NOT NULL, first_name character varying(100) NOT NULL, last_name character varying(100) NOT NULL, job_title character varying(100) NOT NULL, department character varying(100), branch_id character varying(64), email character varying(128) NOT NULL UNIQUE, phone_extension character varying(20), hire_date date NOT NULL, termination_date date, manager_id character varying(64), status character varying(32) NOT NULL, PRIMARY KEY (employee_id), FOREIGN KEY (branch_id) REFERENCES financial_services.branches(branch_id), FOREIGN KEY (manager_id) REFERENCES financial_services.employees(employee_id) )
CREATE TABLE financial_services.loans ( loan_id character varying(64) NOT NULL, account_id character varying(64) NOT NULL UNIQUE, loan_type character varying(50) NOT NULL, principal_amount numeric(19, 4) NOT NULL, current_principal_balance numeric(19, 4) NOT NULL, interest_rate numeric(6, 4) NOT NULL, term_months integer NOT NULL, origination_date date NOT NULL, maturity_date date NOT NULL, monthly_payment numeric(12, 4), collateral_description text, status character varying(32) NOT NULL, PRIMARY KEY (loan_id), FOREIGN KEY (account_id) REFERENCES financial_services.accounts(account_id) )


[User] Find the average percentage share among all beneficiaries for each distinct relationship type.

[Assistant] SELECT relationship, AVG(percentage_share) FROM insurance.policy_beneficiaries GROUP BY relationship ORDER BY relationship;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE insurance.insurance_products ( product_id.text, product_name.text, product_type.text, description.text, base_premium.numeric, coverage_details.text, underwriting_rules.text, is_active.boolean, created_at.timestamp, updated_at.timestamp )
CREATE TABLE insurance.policy_beneficiaries ( beneficiary_id text PRIMARY KEY, policy_id text, customer_id text, first_name text, last_name text, relationship text, percentage_share numeric, contact_info text, added_at timestamp )


[User] Could you list each game title along with the total number of players currently connected across all its servers?

[Assistant] SELECT g.title, SUM(s.current_players) AS total_current_players FROM gaming_technology.games g JOIN gaming_technology.servers s ON g.game_id = s.game_id GROUP BY g.title;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE gaming_technology.players ( player_id.uuid, username.text, email.text, password_hash.text, registration_date.timestamptz, last_login.timestamptz, country_code.text, status.text, profile_data.jsonb )
CREATE TABLE gaming_technology.games ( game_id.uuid, title.text, developer_id.uuid, publisher_id.uuid, genre.text, release_date.date, description.text, platform.text, engine.text, website.text )
CREATE TABLE gaming_technology.developers ( developer_id.uuid, name.text, country.text, founded_year.integer, website.text, created_at.timestamptz )
CREATE TABLE gaming_technology.servers ( server_id.uuid, game_id.uuid, server_name.text, region.text, ip_address.text, port.integer, current_players.integer, max_players.integer, status.text, last_heartbeat.timestamptz )
CREATE TABLE gaming_technology.achievements ( achievement_id.uuid, game_id.uuid, name.text, description.text, icon_url.text, points.integer, hidden.boolean )
CREATE TABLE gaming_technology.player_achievements ( player_achievement_id.uuid, player_id.uuid, achievement_id.uuid, unlocked_at.timestamptz )
CREATE TABLE gaming_technology.in_game_items ( item_id.uuid, game_id.uuid, item_name.text, item_type.text, description.text, rarity.text, cost_currency.text, cost_amount.numeric, attributes.jsonb )
CREATE TABLE gaming_technology.player_inventory ( inventory_id.uuid, player_id.uuid, item_id.uuid, quantity.integer, acquired_at.timestamptz, instance_data.jsonb )


[User] For each claim, list the incident date, the policy number, and the number of beneficiaries associated with that policy.

[Assistant]
SELECT c.claim_id, c.incident_date, p.policy_number, COUNT(pb.beneficiary_id) AS beneficiary_count
FROM insurance.claims c
JOIN insurance.policies p ON c.policy_id = p.policy_id
LEFT JOIN insurance.policy_beneficiaries pb ON p.policy_id = pb.policy_id
GROUP BY c.claim_id, c.incident_date, p.policy_number;

[User] Only include claims that have more than two beneficiaries.

[Assistant]
SELECT c.claim_id, c.incident_date, p.policy_number, COUNT(pb.beneficiary_id) AS beneficiary_count
FROM insurance.claims c
JOIN insurance.policies p ON c.policy_id = p.policy_id
LEFT JOIN insurance.policy_beneficiaries pb ON p.policy_id = pb.policy_id
GROUP BY c.claim_id, c.incident_date, p.policy_number
HAVING COUNT(pb.beneficiary_id) > 2;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE insurance.policies ( policy_id.text, customer_id.text, product_id.text, agent_id.text, policy_number.text, start_date.date, end_date.date, premium_amount.numeric, coverage_limit.numeric, deductible.numeric, status.text, issued_at.timestamp, cancellation_date.date, cancellation_reason.text )
CREATE TABLE insurance.claims ( claim_id.text, policy_id.text, customer_id.text, incident_date.timestamp, reported_date.timestamp, description.text, estimated_loss.numeric, status.text, settlement_amount.numeric, settlement_date.date, claim_handler_id.text, police_report_number.text )
CREATE TABLE insurance.insurance_products ( product_id.text, product_name.text, product_type.text, description.text, base_premium.numeric, coverage_details.text, underwriting_rules.text, is_active.boolean, created_at.timestamp, updated_at.timestamp )
CREATE TABLE insurance.agents ( agent_id character varying(64) NOT NULL, first_name character varying(100) NOT NULL, last_name character varying(100) NOT NULL, agency_name character varying(150), license_number character varying(100) NOT NULL UNIQUE, license_state character varying(50) NOT NULL, contact_email character varying(128) UNIQUE, contact_phone character varying(30), hire_date date, termination_date date, status character varying(20) NOT NULL DEFAULT 'Active', commission_rate numeric(5, 4) NOT NULL DEFAULT 0.05, manager_id character varying(64), PRIMARY KEY (agent_id) )
CREATE TABLE insurance.premium_payments ( payment_id character varying(64) NOT NULL, policy_id character varying(64) NOT NULL, customer_id character varying(64) NOT NULL, payment_date timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, amount_paid numeric(12, 2) NOT NULL, payment_method character varying(50), transaction_reference character varying(128) UNIQUE, due_date date, payment_period_start date, payment_period_end date, status character varying(30) NOT NULL DEFAULT 'Completed', PRIMARY KEY (payment_id) )
CREATE TABLE insurance.claim_documents ( document_id text PRIMARY KEY, claim_id text, document_type text, file_name text, file_path text, file_size_bytes int, mime_type text, uploaded_by text, uploaded_at timestamp, description text )
CREATE TABLE insurance.policy_beneficiaries ( beneficiary_id character varying(64) NOT NULL, policy_id character varying(64) NOT NULL, customer_id character varying(64) NOT NULL, first_name character varying(100) NOT NULL, last_name character varying(100) NOT NULL, relationship character varying(50) NOT NULL, percentage_share numeric(5, 2) NOT NULL CHECK (percentage_share > 0 AND percentage_share <= 100), contact_info text, added_at timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY (beneficiary_id), UNIQUE (policy_id, customer_id) )


[User] For each vehicle, find pairs of maintenance logs where one log is immediately followed by another by service_date. List vehicle_id, previous log_id, next log_id, and the odometer increase.

[Assistant]
SELECT
  vehicle_id,
  log_id AS prev_log_id,
  next_log_id AS next_log_id,
  next_odometer - odometer_reading AS odometer_increase
FROM (
  SELECT
    log_id,
    vehicle_id,
    odometer_reading,
    LEAD(log_id) OVER (PARTITION BY vehicle_id ORDER BY service_date) AS next_log_id,
    LEAD(odometer_reading) OVER (PARTITION BY vehicle_id ORDER BY service_date) AS next_odometer
  FROM transportation.maintenance_logs
) t
WHERE next_log_id IS NOT NULL;

[User] Include only pairs where the odometer increase exceeds 10000 miles.

[Assistant]
SELECT
  vehicle_id,
  log_id AS prev_log_id,
  next_log_id AS next_log_id,
  next_odometer - odometer_reading AS odometer_increase
FROM (
  SELECT
    log_id,
    vehicle_id,
    odometer_reading,
    LEAD(log_id) OVER (PARTITION BY vehicle_id ORDER BY service_date) AS next_log_id,
    LEAD(odometer_reading) OVER (PARTITION BY vehicle_id ORDER BY service_date) AS next_odometer
  FROM transportation.maintenance_logs
) t
WHERE next_log_id IS NOT NULL
  AND (next_odometer - odometer_reading) > 10000;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE transportation.maintenance_logs ( log_id text, vehicle_id text, service_date date, odometer_reading integer, service_type text, description text, cost numeric, mechanic_name text, next_service_due_date date )


[User] Count the number of appointments for each status.

[Assistant] SELECT status, count(*) FROM government_services.appointments GROUP BY status;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE government_services.appointments ( appointment_id character varying(64) NOT NULL, citizen_id character varying(64) NOT NULL, employee_id character varying(64), location_id character varying(64), service_id character varying(64), scheduled_start_time timestamp NOT NULL, scheduled_end_time timestamp, purpose text NOT NULL, status character varying(30) NOT NULL, booking_method character varying(50), created_at timestamp NOT NULL, notes text, PRIMARY KEY (appointment_id) )


[User] Which SUI coins have a supply greater than 10,000 and include their symbol and name?

[Assistant] SELECT scm.symbol, scm.name, sc.coin_type, SUM(CAST(sc.balance AS DECIMAL)) AS total_supply FROM sui_coins sc JOIN sui_coins_metadata scm ON sc.coin_type = scm.coin_type WHERE CAST(sc.balance AS DECIMAL) > 10000 GROUP BY scm.symbol, scm.name, sc.coin_type;

[User] Now, also show the total number of unique owners for each coin.

[Assistant] SELECT scm.symbol, scm.name, sc.coin_type, SUM(CAST(sc.balance AS DECIMAL)) AS total_supply, COUNT(DISTINCT sc.owner) AS unique_owners FROM sui_coins sc JOIN sui_coins_metadata scm ON sc.coin_type = scm.coin_type WHERE CAST(sc.balance AS DECIMAL) > 10000 GROUP BY scm.symbol, scm.name, sc.coin_type;

[User] Only include coins where the unique owner count is at least 5.

[Assistant] SELECT scm.symbol, scm.name, sc.coin_type, SUM(CAST(sc.balance AS DECIMAL)) AS total_supply, COUNT(DISTINCT sc.owner) AS unique_owners FROM sui_coins sc JOIN sui_coins_metadata scm ON sc.coin_type = scm.coin_type WHERE CAST(sc.balance AS DECIMAL) > 10000 GROUP BY scm.symbol, scm.name, sc.coin_type HAVING COUNT(DISTINCT sc.owner) >= 5;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE token_metas ( block_timestamp.timestamp, block_number.bigint, transaction_hash.text, transaction_index.bigint, from_address.text, contract_address.text, symbol.text, total_supply.text, name.text, decimals.bigint, is_erc20.integer, is_erc721.integer, is_erc1155.integer, is_proxy.integer, extra_info.text, pk.integer )
CREATE TABLE erc1155_approval_for_all ( block_number.bigint, block_timestamp.timestamp, transaction_index.integer, transaction_hash.text, log_index.integer, contract_address.text )
CREATE TABLE erc20_balances_historical ( block_number.bigint, contract_address.text, wallet_address.text, amount.text, pk.integer )
CREATE TABLE nft_holders ( block_number.bigint, contract_address.text, wallet_address.text, token_id.text, contract_type.text, amount.text, pk.text )
CREATE TABLE nft_holder_historical ( block_number.bigint, contract_address.text, wallet_address.text, token_id.text, contract_type.text, amount.text, pk.integer )
CREATE TABLE sui_coins ( object_id.text, status.text, coin_type.text, balance.text, owner.text )
CREATE TABLE sui_coins_metadata ( object_id.text, coin_type.text, status.text, decimals.bigint, description.text, icon_url.text, symbol.text, name.text )
CREATE TABLE sui_nfts ( object_id.text, status.text, collection_type.text, package_id.text, previous_transaction.text, display.text, owner.text, name.text )
CREATE TABLE nft_metadata ( blockchain.text, contract_address.text, token_id.text, contract_name.text, erc_type.text, amount.bigint, minter.text, owner.text, mint_block_number.bigint, mint_time.bigint, mint_transaction_hash.text, mint_price.text, token_uri.text, metadata.text, name.text, image_uri.text, traits.text, updated_at.bigint, status.text, rarity_score.real, rarity_rank.integer, unique_attribute_count.integer, pk.integer )
CREATE TABLE nft_collections ( blockchain.text, contract_address.text, name.text, symbol.text, deploy_block_number.bigint, deploy_block_time.bigint, erc_type.text, owner.text, traits.text, description.text, slug.text, media_info.text, image_url.text, banner_image_url.text, updated_at.bigint, banner.text, token_count.bigint, floor_price.text, floor_price_symbol.text, floor_price_contract.text, pk.integer )
CREATE TABLE token_prices_latest ( blockchain.text, address.text, decimals.bigint, symbol.text, price.real, timestamp.timestamp )
CREATE TABLE token_balances ( block_number.bigint, block_timestamp.timestamp, tick.text, wallet_address.text, total_supply.decimal, amount.decimal )
CREATE TABLE token_info ( block_timestamp.timestamp, block_number.bigint, tx_index.integer, tx_hash.text, tick.text, max_supply.decimal, lim.decimal, wlim.decimal, dec.integer, creator.text )
CREATE TABLE token_activities ( block_timestamp.timestamp, block_number.bigint, tx_index.integer, tx_hash.text, log_index.integer, type.text, tick.text, id.text, amt.decimal, from_address.text, to_address.text )
CREATE TABLE mud_holesky_redstone ( address.text, table_id.text, key_bytes.text, key0.text, key1.text, static_data.text, encoded_lengths.text, dynamic_data.text, is_deleted.boolean, block_number.bigint, log_index.bigint )
CREATE TABLE token_balances_bitcoin ( block_number.bigint, block_timestamp.timestamp, tick.text, wallet_address.text, total_supply.text, amount.text )
CREATE TABLE token_activities_bitcoin ( block_timestamp.timestamp, block_number.bigint, tx_index.integer, tx_hash.text, log_index.integer, type.text, tick.text, id.text, amt.decimal, from_address.text, to_address.text )
CREATE TABLE token_activities_avalanche ( block_timestamp.timestamp, block_number.bigint, tx_index.integer, tx_hash.text, log_index.integer, type.text, tick.text, id.text, amt.decimal, from_address.text, to_address.text )
CREATE TABLE token_balances_avalanche ( block_number.bigint, block_timestamp.timestamp, tick.text, wallet_address.text, total_supply.decimal, amount.decimal )
CREATE TABLE token_info_avalanche ( block_timestamp.timestamp, block_number.bigint, tx_index.integer, tx_hash.text, tick.text, max_supply.decimal, lim.decimal, wlim.decimal, dec.integer, creator.text, minted.decimal, holders.decimal, txs.decimal, updated_timestamp.timestamp, completed_timestamp.timestamp, id.text )


[User] What are the personal contact details of the staff member associated with staff_id 'STAFF789' who worked on a specific maintenance record?

[Assistant] I'm sorry, but I can't provide personal contact details of staff members as this information is not stored in the maintenance_records table and is outside the scope of the available data.

System:
You are an SQL statement expert and you can refuse the user's question if the question is not related to the table structure. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE train_station_management.maintenance_records ( record_id text, asset_id text, asset_type text, maintenance_type text, staff_id text, start_datetime timestamp, end_datetime timestamp, description text, cost numeric, status text )


[User] Show all rooms that are on floor 3.

[Assistant] SELECT room_id, property_id, room_number FROM hospitality_technology.rooms WHERE floor = 3;

[User] For these rooms, include the property name and room number.

[Assistant] SELECT r.room_number, p.property_name FROM hospitality_technology.rooms AS r JOIN hospitality_technology.properties AS p ON r.property_id = p.property_id WHERE r.floor = 3;

[User] Also, include the type name and current status for each room.

[Assistant] SELECT r.room_number, p.property_name, rt.type_name, r.status FROM hospitality_technology.rooms AS r JOIN hospitality_technology.properties AS p ON r.property_id = p.property_id JOIN hospitality_technology.room_types AS rt ON r.room_type_id = rt.room_type_id AND r.property_id = rt.property_id WHERE r.floor = 3;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE hospitality_technology.properties ( property_id text, property_name text, address_line1 text, address_line2 text, city text, state_province text, postal_code text, country_code text, phone_number text, email_address text, property_type text, star_rating numeric, timezone text, manager_staff_id text, created_at timestamp, updated_at timestamp )
CREATE TABLE hospitality_technology.rooms ( room_id text, property_id text, room_number text, room_type_id text, floor integer, status text, is_smoking boolean, features text, current_condition text, last_cleaned_at timestamp )
CREATE TABLE hospitality_technology.room_types ( room_type_id text, property_id text, type_name text, description text, base_rate numeric, max_occupancy integer, bed_type text, area_sqft numeric, amenities text )


[User] Find pairs of developers located in the same country but founded in different years.

[Assistant]
SELECT d1.name AS developer1, d2.name AS developer2, d1.country, d1.founded_year, d2.founded_year
FROM gaming_technology.developers d1
JOIN gaming_technology.developers d2
  ON d1.country = d2.country
 AND d1.developer_id < d2.developer_id
 AND d1.founded_year <> d2.founded_year;

[User] Only include pairs where the difference in founded_year is greater than 5 years.

[Assistant]
SELECT d1.name AS developer1, d2.name AS developer2, d1.country, d1.founded_year, d2.founded_year
FROM gaming_technology.developers d1
JOIN gaming_technology.developers d2
  ON d1.country = d2.country
 AND d1.developer_id < d2.developer_id
WHERE ABS(d1.founded_year - d2.founded_year) > 5;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE gaming_technology.developers ( developer_id uuid, name text, country text, founded_year integer, website text, created_at timestamp with time zone )


[User] List usernames and the length of their 'bio' field for users whose 'is_verified' status is true.

[Assistant] SELECT username, LENGTH(bio) AS bio_length FROM social_media.users WHERE is_verified IS TRUE;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE social_media.users ( user_id text PRIMARY KEY, username text, email text, password_hash text, full_name text, profile_picture_url text, bio text, location text, created_at timestamp, updated_at timestamp, is_verified bool )


[User] For each vehicle, list its vehicle_id, license_plate, and any older vehicle of the same type (showing older_vehicle_id and older year).

[Assistant]
SELECT cur.vehicle_id,
       cur.license_plate,
       old.vehicle_id AS older_vehicle_id,
       old.year       AS older_vehicle_year
FROM transportation.vehicles cur
JOIN transportation.vehicles old
  ON cur.type = old.type
 AND old.year < cur.year
ORDER BY cur.vehicle_id, old.year DESC;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE transportation.vehicles (
    vehicle_id character varying(64) NOT NULL,  -- unique identifier for the vehicle
    license_plate character varying(32) NOT NULL UNIQUE, -- vehicle license plate
    vin character varying(17) UNIQUE, -- vehicle identification number
    make character varying(64) NOT NULL, -- manufacturer of the vehicle
    model character varying(64) NOT NULL, -- model of the vehicle
    year integer NOT NULL, -- manufacturing year
    type character varying(32) NOT NULL, -- type of vehicle (e.g., Bus, Train, Truck, Car, Van)
    capacity integer, -- passenger or cargo capacity
    fuel_type character varying(32) NOT NULL, -- e.g., Diesel, Gasoline, Electric, Hydrogen
    status character varying(32) NOT NULL, -- e.g., Active, Maintenance, Decommissioned
    depot_id character varying(64), -- identifier of the home depot/base
    acquisition_date date, -- date the vehicle was acquired
    PRIMARY KEY (vehicle_id)
)


[User] Calculate the total quantity traded for each day in the dataset.

[Assistant] SELECT DATE_TRUNC('day', traded_at) AS trade_day, SUM(quantity) AS total_daily_quantity FROM trading_platform.trades GROUP BY DATE_TRUNC('day', traded_at) ORDER BY trade_day;

[User] Could you also include the total trade value (quantity * price) for each day in that report?

[Assistant] SELECT DATE_TRUNC('day', traded_at) AS trade_day, SUM(quantity) AS total_daily_quantity, SUM(quantity * price) AS total_daily_value FROM trading_platform.trades GROUP BY DATE_TRUNC('day', traded_at) ORDER BY trade_day;

[User] Now, for each day, show how the total quantity compares to the overall average daily quantity across all days in the dataset.

[Assistant] WITH DailySummary AS (SELECT DATE_TRUNC('day', traded_at) AS trade_day, SUM(quantity) AS total_daily_quantity FROM trading_platform.trades GROUP BY DATE_TRUNC('day', traded_at)) SELECT trade_day, total_daily_quantity, total_daily_quantity - AVG(total_daily_quantity) OVER () AS quantity_difference_from_average FROM DailySummary ORDER BY trade_day;

[User] Finally, only show the days where the total quantity was higher than the overall average daily quantity.

[Assistant] WITH DailySummary AS (SELECT DATE_TRUNC('day', traded_at) AS trade_day, SUM(quantity) AS total_daily_quantity FROM trading_platform.trades GROUP BY DATE_TRUNC('day', traded_at)) SELECT trade_day, total_daily_quantity FROM DailySummary WHERE total_daily_quantity > (SELECT AVG(total_daily_quantity) FROM DailySummary) ORDER BY trade_day;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE trading_platform.trades ( trade_id character varying(64) NOT NULL, order_id character varying(64) NOT NULL, buyer_id character varying(64) NOT NULL, seller_id character varying(64) NOT NULL, asset_id character varying(64) NOT NULL, quantity numeric(38,14) NOT NULL, price numeric(38,14) NOT NULL, traded_at timestamp NOT NULL, PRIMARY KEY (trade_id) )


[User] List document names and versions for documents that share the same case_id, showing each pair of versions.

[Assistant] SELECT d1.case_id, d1.document_name AS doc_name_v1, d1.version AS version1, d2.document_name AS doc_name_v2, d2.version AS version2 FROM legal_services.documents d1 JOIN legal_services.documents d2 ON d1.case_id = d2.case_id AND d1.version < d2.version;

[User] Actually, I only want to compare the highest version against the second highest version per case.

[Assistant] SELECT d_prev.case_id, d_prev.document_name AS prev_doc, d_prev.version AS prev_version, d_latest.document_name AS latest_doc, d_latest.version AS latest_version FROM legal_services.documents d_latest JOIN legal_services.documents d_prev ON d_latest.case_id = d_prev.case_id AND d_prev.version = d_latest.version - 1 WHERE d_latest.version = (SELECT MAX(version) FROM legal_services.documents d WHERE d.case_id = d_latest.case_id);

[User] Also include the upload timestamps and restrict to cases with at least three versions.

[Assistant] SELECT d_latest.case_id, d_prev.document_name AS prev_doc, d_prev.upload_timestamp AS prev_upload, d_latest.document_name AS latest_doc, d_latest.upload_timestamp AS latest_upload FROM legal_services.documents d_latest JOIN legal_services.documents d_prev ON d_latest.case_id = d_prev.case_id AND d_prev.version = d_latest.version - 1 WHERE d_latest.version = (SELECT MAX(version) FROM legal_services.documents d WHERE d.case_id = d_latest.case_id) AND (SELECT COUNT(*) FROM legal_services.documents d2 WHERE d2.case_id = d_latest.case_id) >= 3;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE legal_services.documents (
    document_id character varying(64) NOT NULL,  -- unique identifier for the document
    case_id character varying(64) NOT NULL, -- FK to cases table
    document_name character varying(255) NOT NULL, -- name of the document file
    document_type character varying(100), -- e.g., Pleading, Contract, Evidence, Correspondence
    storage_path text NOT NULL, -- path or reference to the document storage location
    uploaded_by_lawyer_id character varying(64), -- FK to lawyers table (who uploaded it)
    upload_timestamp timestamp NOT NULL, -- time the document was uploaded
    version integer DEFAULT 1, -- document version number
    description text, -- brief description or notes about the document
    PRIMARY KEY (document_id)
)


[User] Show me all bookings with the passenger's full name and the booking status.

[Assistant]
SELECT b.booking_id, p.first_name || ' ' || p.last_name AS passenger_full_name, b.status
FROM transportation.bookings b
JOIN transportation.passengers p ON b.passenger_id = p.passenger_id;

[User] Please only include bookings where the status is 'Completed'.

[Assistant]
SELECT b.booking_id, p.first_name || ' ' || p.last_name AS passenger_full_name, b.status
FROM transportation.bookings b
JOIN transportation.passengers p ON b.passenger_id = p.passenger_id
WHERE b.status = 'Completed';

[User] Add the fare amount and booking time for each completed booking.

[Assistant]
SELECT b.booking_id, p.first_name || ' ' || p.last_name AS passenger_full_name, b.status, b.fare, b.booking_time
FROM transportation.bookings b
JOIN transportation.passengers p ON b.passenger_id = p.passenger_id
WHERE b.status = 'Completed';

[User] Limit the results to the latest 10 completed bookings by booking_time.

[Assistant]
SELECT b.booking_id, p.first_name || ' ' || p.last_name AS passenger_full_name, b.status, b.fare, b.booking_time
FROM transportation.bookings b
JOIN transportation.passengers p ON b.passenger_id = p.passenger_id
WHERE b.status = 'Completed'
ORDER BY b.booking_time DESC
LIMIT 10;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE transportation.passengers (
    passenger_id character varying(64) NOT NULL,  -- unique identifier for the passenger
    first_name character varying(128) NOT NULL, -- passenger's first name
    last_name character varying(128) NOT NULL, -- passenger's last name
    email character varying(128) UNIQUE, -- email address
    phone_number character varying(32) UNIQUE, -- phone number
    date_of_birth date, -- passenger's date of birth
    loyalty_program_id character varying(64), -- identifier for loyalty program membership
    created_at timestamp with time zone NOT NULL, -- time when the passenger record was created
    PRIMARY KEY (passenger_id)
)
CREATE TABLE transportation.bookings ( booking_id character varying(64) NOT NULL, passenger_id character varying(64) NOT NULL, trip_id character varying(64) NOT NULL, seat_number character varying(16), booking_time timestamp with time zone NOT NULL, status character varying(32) NOT NULL, fare numeric(10, 2) NOT NULL, payment_transaction_id character varying(128), special_requests text, PRIMARY KEY (booking_id) )


[User] What are the safety ratings or crash statistics for the Boeing 787 Dreamliner?

[Assistant] I'm sorry, but I don't have access to safety ratings or crash statistics for specific aircraft models like the Boeing 787 Dreamliner. My data is limited to the information in the aircraft_models table, which includes details such as model name, manufacturer, passenger capacity, and technical specifications. For safety-related information, I recommend consulting official aviation authorities or safety reports.

System:
You are an SQL statement expert and you can refuse the user's question if the question is not related to the table structure. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE manufacturing.aircraft_models ( model_id text, model_name text, manufacturer text, passenger_capacity integer, max_range_km integer, engine_type text, wingspan_m numeric, status text, first_flight_date date )


[User] How many hashtags have been created in March 2024?

[Assistant]
```sql
SELECT COUNT(*) AS march_2024_hashtag_count
FROM social_media.hashtags
WHERE created_at >= '2024-03-01'
  AND created_at <  '2024-04-01';
```

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE social_media.users ( user_id text PRIMARY KEY, username text, email text, password_hash text, full_name text, profile_picture_url text, bio text, location text, created_at timestamp, updated_at timestamp, is_verified bool )
CREATE TABLE social_media.hashtags ( hashtag_id text PRIMARY KEY, tag_name text, created_at timestamp )
CREATE TABLE social_media.conversation_participants ( participant_id text PRIMARY KEY, conversation_id text, user_id text, joined_at timestamp, last_read_at timestamp )
CREATE TABLE social_media.notifications ( notification_id text PRIMARY KEY, recipient_user_id text, sender_user_id text, notification_type text, target_entity_id text, target_entity_type text, created_at timestamp, read_at timestamp )


[User] Count how many appointments have been canceled at each location. Return the location and cancelled_count.

[Assistant]
SELECT location, COUNT(*) AS cancelled_count
FROM legal_services.appointments
WHERE status = 'Canceled'
GROUP BY location;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE legal_services.clients ( client_id text PRIMARY KEY, first_name text, last_name text, company_name text, email text UNIQUE, phone text, address text, date_registered timestamp, status text )
CREATE TABLE legal_services.lawyers (
    lawyer_id character varying(64) NOT NULL,  -- unique identifier for the lawyer
    first_name character varying(100) NOT NULL, -- lawyer's first name
    last_name character varying(100) NOT NULL, -- lawyer's last name
    bar_number character varying(64) UNIQUE NOT NULL, -- lawyer's bar association number
    firm_id character varying(64), -- FK to law_firms table
    email character varying(128) UNIQUE NOT NULL, -- lawyer's professional email
    phone character varying(32), -- lawyer's contact phone number
    specialization text, -- areas of legal expertise
    hire_date timestamp NOT NULL, -- date the lawyer was hired or joined
    is_partner boolean DEFAULT false, -- flag indicating if the lawyer is a partner
    PRIMARY KEY (lawyer_id)
)
CREATE TABLE legal_services.time_entries (
    entry_id character varying(64) NOT NULL,  -- unique identifier for the time entry
    case_id character varying(64) NOT NULL, -- FK to cases table
    lawyer_id character varying(64) NOT NULL, -- FK to lawyers table (who performed the work)
    date_worked date NOT NULL, -- date the work was performed
    hours_spent numeric(5, 2) NOT NULL CHECK (hours_spent > 0), -- duration of work in hours (e.g., 1.5 for 1h 30m)
    billing_rate numeric(10, 2) NOT NULL, -- hourly rate applied for this entry
    description text NOT NULL, -- detailed description of the work performed
    is_billable boolean DEFAULT true, -- whether this time entry is billable to the client
    is_billed boolean DEFAULT false, -- whether this entry has been included in an invoice
    invoice_id character varying(64), -- FK to invoices table (once billed)
    created_at timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, -- when the entry was recorded
    PRIMARY KEY (entry_id)
)
CREATE TABLE legal_services.invoices ( invoice_id.text, invoice_number.text, client_id.text, case_id.text, issue_date.date, due_date.date, total_amount.numeric, amount_paid.numeric, status.text, payment_date.timestamp, notes.text, created_at.timestamp )
CREATE TABLE legal_services.appointments (
    appointment_id character varying(64) NOT NULL, -- unique identifier for the appointment
    client_id character varying(64) NOT NULL, -- FK to clients table
    lawyer_id character varying(64) NOT NULL, -- FK to lawyers table
    case_id character varying(64), -- FK to cases table (optional, if related to a specific case)
    start_time timestamp NOT NULL, -- scheduled start date and time
    end_time timestamp NOT NULL, -- scheduled end date and time
    location text, -- location of the meeting (address or virtual link)
    subject character varying(255), -- subject or purpose of the appointment
    notes text, -- additional notes for the appointment
    status character varying(50) NOT NULL, -- e.g., Scheduled, Completed, Canceled, Rescheduled
    created_at timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP,
    PRIMARY KEY (appointment_id)
)


[User] What is the current job satisfaction level or feedback from staff members working at a specific train station?

[Assistant] I'm sorry, but I can't provide information on job satisfaction levels or feedback from staff members as this data is not included in the staff table.

System:
You are an SQL statement expert and you can refuse the user's question if the question is not related to the table structure. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE train_station_management.staff ( staff_id.text, first_name.text, last_name.text, role.text, primary_station_id.text, employee_number.text, hire_date.date, contact_email.text, contact_phone.text, is_active.boolean )


[User] Show me the top 5 narratives by market cap, along with their 24-hour trading volume and 7-day price change percentage.

[Assistant] SELECT narrative.text, volume_24h.numeric, price_change_percentage_7d.numeric FROM narrative_info ORDER BY market_cap.numeric DESC LIMIT 5;

[User] Can you also include the top 3 coins for each of these narratives?

[Assistant] SELECT narrative.text, volume_24h.numeric, price_change_percentage_7d.numeric, top_3_coins.text FROM narrative_info ORDER BY market_cap.numeric DESC LIMIT 5;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE narrative_info ( narrative.text, top_3_coins.text, price_change_percentage_1h.numeric, price_change_percentage_24h.numeric, price_change_percentage_7d.numeric, market_cap.numeric, volume_24h.numeric, trend_rank.numeric, token_num.numeric )