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1820 1821 1822 1823 1824 1825 1826 1827 1828 1829 1830 1831 1832 1833 1834 1835 1836 1837 1838 1839 1840 1841 1842 1843 1844 1845 1846 1847 1848 1849 1850 1851 1852 1853 1854 1855 1856 1857 1858 1859 1860 1861 1862 1863 1864 1865 1866 1867 1868 1869 1870 1871 1872 1873 1874 1875 1876 1877 1878 1879 1880 1881 1882 1883 | align:start position:0% okay today I'm speaking about the first align:start position:0% okay today I'm speaking about the first align:start position:0% okay today I'm speaking about the first of the three great partial differential align:start position:0% of the three great partial differential align:start position:0% of the three great partial differential equation partial differential equations align:start position:0% equation partial differential equations align:start position:0% equation partial differential equations so this one is called Laplace's equation align:start position:0% so this one is called Laplace's equation align:start position:0% so this one is called Laplace's equation named after Laplace and you see partial align:start position:0% named after Laplace and you see partial align:start position:0% named after Laplace and you see partial derivatives so we have I don't have time align:start position:0% derivatives so we have I don't have time align:start position:0% derivatives so we have I don't have time this equation is in steady state I have align:start position:0% this equation is in steady state I have align:start position:0% this equation is in steady state I have x and y I'm in the XY plane and I have align:start position:0% x and y I'm in the XY plane and I have align:start position:0% x and y I'm in the XY plane and I have second derivatives in X and in Y so I'm align:start position:0% second derivatives in X and in Y so I'm align:start position:0% second derivatives in X and in Y so I'm looking for solutions to that equation align:start position:0% looking for solutions to that equation align:start position:0% looking for solutions to that equation and of course I'm given some boundary align:start position:0% and of course I'm given some boundary align:start position:0% and of course I'm given some boundary values align:start position:0% values align:start position:0% values so time is not here the boundary values align:start position:0% so time is not here the boundary values align:start position:0% so time is not here the boundary values the boundary is in the XY plane maybe a align:start position:0% the boundary is in the XY plane maybe a align:start position:0% the boundary is in the XY plane maybe a circle think about a circle in the XY align:start position:0% circle think about a circle in the XY align:start position:0% circle think about a circle in the XY plane and on the circle I know the align:start position:0% plane and on the circle I know the align:start position:0% plane and on the circle I know the solution U align:start position:0% solution U align:start position:0% solution U so the boundary values around the circle align:start position:0% so the boundary values around the circle align:start position:0% so the boundary values around the circle or give it and I have to find the align:start position:0% or give it and I have to find the align:start position:0% or give it and I have to find the temperature you inside the circle so I align:start position:0% temperature you inside the circle so I align:start position:0% temperature you inside the circle so I know the temperature on the boundary I align:start position:0% know the temperature on the boundary I align:start position:0% know the temperature on the boundary I let it settle down and I want to know align:start position:0% let it settle down and I want to know align:start position:0% let it settle down and I want to know the temperature inside and the beauty is align:start position:0% the temperature inside and the beauty is align:start position:0% the temperature inside and the beauty is it solves that align:start position:0% it solves that align:start position:0% it solves that basic partial differential equation so align:start position:0% basic partial differential equation so align:start position:0% basic partial differential equation so let's find some solutions they might not align:start position:0% let's find some solutions they might not align:start position:0% let's find some solutions they might not match the boundary values but we can use align:start position:0% match the boundary values but we can use align:start position:0% match the boundary values but we can use them so u equal constant certainly align:start position:0% them so u equal constant certainly align:start position:0% them so u equal constant certainly solves the equation u equal x the second align:start position:0% solves the equation u equal x the second align:start position:0% solves the equation u equal x the second derivatives will be 0 u equal Y here's a align:start position:0% derivatives will be 0 u equal Y here's a align:start position:0% derivatives will be 0 u equal Y here's a better one x squared minus y squared so align:start position:0% better one x squared minus y squared so align:start position:0% better one x squared minus y squared so the second derivative in the x-direction align:start position:0% the second derivative in the x-direction align:start position:0% the second derivative in the x-direction is 2 the second derivative in the align:start position:0% is 2 the second derivative in the align:start position:0% is 2 the second derivative in the y-direction is minus 2 so I have 2 minus align:start position:0% y-direction is minus 2 so I have 2 minus align:start position:0% y-direction is minus 2 so I have 2 minus 2 it solves the equation or this one the align:start position:0% 2 it solves the equation or this one the align:start position:0% 2 it solves the equation or this one the second derivative in X is 0 second align:start position:0% second derivative in X is 0 second align:start position:0% second derivative in X is 0 second derivative in Y is 0 those are simple align:start position:0% derivative in Y is 0 those are simple align:start position:0% derivative in Y is 0 those are simple solutions but those are only a few align:start position:0% solutions but those are only a few align:start position:0% solutions but those are only a few solutions and we need an infinite align:start position:0% solutions and we need an infinite align:start position:0% solutions and we need an infinite sequence because we're going to match align:start position:0% sequence because we're going to match align:start position:0% sequence because we're going to match initial align:start position:0% initial align:start position:0% initial conditions ok so is there a path pattern align:start position:0% conditions ok so is there a path pattern align:start position:0% conditions ok so is there a path pattern here so this is degree zero constant align:start position:0% here so this is degree zero constant align:start position:0% here so this is degree zero constant these are degree one linear these are align:start position:0% these are degree one linear these are align:start position:0% these are degree one linear these are degree two quadratic so I hope for two align:start position:0% degree two quadratic so I hope for two align:start position:0% degree two quadratic so I hope for two cubic ones and then I hope for two align:start position:0% cubic ones and then I hope for two align:start position:0% cubic ones and then I hope for two fourth degree ones and that's the align:start position:0% fourth degree ones and that's the align:start position:0% fourth degree ones and that's the pattern that's the pattern let me find align:start position:0% pattern that's the pattern let me find align:start position:0% pattern that's the pattern let me find let me spot the align:start position:0% let me spot the align:start position:0% let me spot the the cubic ones X cube if I start with X align:start position:0% the cubic ones X cube if I start with X align:start position:0% the cubic ones X cube if I start with X cube of course the second X derivative align:start position:0% cube of course the second X derivative align:start position:0% cube of course the second X derivative is probably 6 X align:start position:0% is probably 6 X align:start position:0% is probably 6 X so I need the second Y derivative to be align:start position:0% so I need the second Y derivative to be align:start position:0% so I need the second Y derivative to be minus 6x and I think minus 3x y squared align:start position:0% minus 6x and I think minus 3x y squared align:start position:0% minus 6x and I think minus 3x y squared does it mine the second derivative of in align:start position:0% does it mine the second derivative of in align:start position:0% does it mine the second derivative of in Y is 2 times the minus 3x is minus 6x align:start position:0% Y is 2 times the minus 3x is minus 6x align:start position:0% Y is 2 times the minus 3x is minus 6x cancels the 6 X from that's from the align:start position:0% cancels the 6 X from that's from the align:start position:0% cancels the 6 X from that's from the second derivative there and it works so align:start position:0% second derivative there and it works so align:start position:0% second derivative there and it works so that fits the pattern but what is the align:start position:0% that fits the pattern but what is the align:start position:0% that fits the pattern but what is the pattern ok here it is it's fantastic align:start position:0% pattern ok here it is it's fantastic align:start position:0% pattern ok here it is it's fantastic it's I align:start position:0% it's I align:start position:0% it's I get I get these align:start position:0% get I get these align:start position:0% get I get these crazy polynomials from taking X plus iy align:start position:0% crazy polynomials from taking X plus iy align:start position:0% crazy polynomials from taking X plus iy to the different powers here to the align:start position:0% to the different powers here to the align:start position:0% to the different powers here to the first power if n is 1 align:start position:0% first power if n is 1 align:start position:0% first power if n is 1 and I just have X plus iy and I take the align:start position:0% and I just have X plus iy and I take the align:start position:0% and I just have X plus iy and I take the real part that's X so I'll take a real align:start position:0% real part that's X so I'll take a real align:start position:0% real part that's X so I'll take a real part of this align:start position:0% part of this align:start position:0% part of this the real part of this when n is 1 the align:start position:0% the real part of this when n is 1 the align:start position:0% the real part of this when n is 1 the real part is X align:start position:0% real part is X align:start position:0% real part is X what about when n is 2 can you can you align:start position:0% what about when n is 2 can you can you align:start position:0% what about when n is 2 can you can you square that in your head so we have x align:start position:0% square that in your head so we have x align:start position:0% square that in your head so we have x squared and we have I squared Y squared align:start position:0% squared and we have I squared Y squared align:start position:0% squared and we have I squared Y squared I squared be minus 1 so I have x squared align:start position:0% I squared be minus 1 so I have x squared align:start position:0% I squared be minus 1 so I have x squared and I have minus y spread look the real align:start position:0% and I have minus y spread look the real align:start position:0% and I have minus y spread look the real part of this when n is 2 the real part align:start position:0% part of this when n is 2 the real part align:start position:0% part of this when n is 2 the real part of X plus I Y squared the real part is x align:start position:0% of X plus I Y squared the real part is x align:start position:0% of X plus I Y squared the real part is x squared minus y squared and the align:start position:0% squared minus y squared and the align:start position:0% squared minus y squared and the imaginary part align:start position:0% imaginary part align:start position:0% imaginary part was the 2i X Y so the imaginary part align:start position:0% was the 2i X Y so the imaginary part align:start position:0% was the 2i X Y so the imaginary part that multiplies I is the 2xy this is our align:start position:0% that multiplies I is the 2xy this is our align:start position:0% that multiplies I is the 2xy this is our pattern when n is 2 and when n is 3 I align:start position:0% pattern when n is 2 and when n is 3 I align:start position:0% pattern when n is 2 and when n is 3 I take X plus I Y cubed and that begins align:start position:0% take X plus I Y cubed and that begins align:start position:0% take X plus I Y cubed and that begins with X cube like that and then I think align:start position:0% with X cube like that and then I think align:start position:0% with X cube like that and then I think that the other real part would be a align:start position:0% that the other real part would be a align:start position:0% that the other real part would be a minus 3 XY squared I think you should align:start position:0% minus 3 XY squared I think you should align:start position:0% minus 3 XY squared I think you should check that and then there will be an align:start position:0% check that and then there will be an align:start position:0% check that and then there will be an imaginary part well I think I could align:start position:0% imaginary part well I think I could align:start position:0% imaginary part well I think I could figure out the imaginary part as I think align:start position:0% figure out the imaginary part as I think align:start position:0% figure out the imaginary part as I think maybe something like minus is something align:start position:0% maybe something like minus is something align:start position:0% maybe something like minus is something like align:start position:0% like align:start position:0% like - align:start position:0% align:start position:0% yeah maybe maybe it's align:start position:0% yeah maybe maybe it's align:start position:0% yeah maybe maybe it's 3y x squared minus y cube something like align:start position:0% 3y x squared minus y cube something like align:start position:0% 3y x squared minus y cube something like that align:start position:0% that align:start position:0% that that would be the real part and that align:start position:0% that would be the real part and that align:start position:0% that would be the real part and that would be the imaginary part when n is 3 align:start position:0% would be the imaginary part when n is 3 align:start position:0% would be the imaginary part when n is 3 and wonderfully wonderfully it works for align:start position:0% and wonderfully wonderfully it works for align:start position:0% and wonderfully wonderfully it works for all align:start position:0% all align:start position:0% all powers align:start position:0% powers align:start position:0% powers exponents n align:start position:0% exponents n align:start position:0% exponents n so I have now a sort of pretty big align:start position:0% so I have now a sort of pretty big align:start position:0% so I have now a sort of pretty big family of solutions a list a double list align:start position:0% family of solutions a list a double list align:start position:0% family of solutions a list a double list really the real parts and the imaginary align:start position:0% really the real parts and the imaginary align:start position:0% really the real parts and the imaginary parts for every N so I can use those align:start position:0% parts for every N so I can use those align:start position:0% parts for every N so I can use those to solve my find the solution U which align:start position:0% to solve my find the solution U which align:start position:0% to solve my find the solution U which I'm looking for the the temperature align:start position:0% I'm looking for the the temperature align:start position:0% I'm looking for the the temperature inside the circle right now of course I align:start position:0% inside the circle right now of course I align:start position:0% inside the circle right now of course I have a linear equation so align:start position:0% have a linear equation so align:start position:0% have a linear equation so if I have several solutions I can align:start position:0% if I have several solutions I can align:start position:0% if I have several solutions I can combine them and I still have a solution align:start position:0% combine them and I still have a solution align:start position:0% combine them and I still have a solution x plus 7y will be a solution plus 11x align:start position:0% x plus 7y will be a solution plus 11x align:start position:0% x plus 7y will be a solution plus 11x squared minus y squared no problem Plus align:start position:0% squared minus y squared no problem Plus align:start position:0% squared minus y squared no problem Plus 56 times 2xy those are all solutions so align:start position:0% 56 times 2xy those are all solutions so align:start position:0% 56 times 2xy those are all solutions so I'm going to find a solution align:start position:0% I'm going to find a solution align:start position:0% I'm going to find a solution my final solution you will be a align:start position:0% my final solution you will be a align:start position:0% my final solution you will be a combination of this this this this this align:start position:0% combination of this this this this this align:start position:0% combination of this this this this this this this and all the others for higher align:start position:0% this this and all the others for higher align:start position:0% this this and all the others for higher n that's going to be my solution and I align:start position:0% n that's going to be my solution and I align:start position:0% n that's going to be my solution and I will need that infinite family see align:start position:0% will need that infinite family see align:start position:0% will need that infinite family see partial differential equations we move align:start position:0% partial differential equations we move align:start position:0% partial differential equations we move up to infinite family of solutions align:start position:0% up to infinite family of solutions align:start position:0% up to infinite family of solutions instead of just a couple of null align:start position:0% instead of just a couple of null align:start position:0% instead of just a couple of null solutions okay so let me take an example align:start position:0% solutions okay so let me take an example align:start position:0% solutions okay so let me take an example let me take an example oh align:start position:0% align:start position:0% my we're taking the region to be a align:start position:0% my we're taking the region to be a align:start position:0% my we're taking the region to be a circle align:start position:0% circle align:start position:0% circle okay align:start position:0% align:start position:0% so in that circle align:start position:0% so in that circle align:start position:0% so in that circle I'm looking for the solution U of x and align:start position:0% I'm looking for the solution U of x and align:start position:0% I'm looking for the solution U of x and y and actually in a circle it's pretty align:start position:0% y and actually in a circle it's pretty align:start position:0% y and actually in a circle it's pretty natural to use polar coordinates instead align:start position:0% natural to use polar coordinates instead align:start position:0% natural to use polar coordinates instead of x and y inside a circle that that's align:start position:0% of x and y inside a circle that that's align:start position:0% of x and y inside a circle that that's inconvenient in the xy-plane it's align:start position:0% inconvenient in the xy-plane it's align:start position:0% inconvenient in the xy-plane it's equation is align:start position:0% equation is align:start position:0% equation is involves x equals square root of 1 minus align:start position:0% involves x equals square root of 1 minus align:start position:0% involves x equals square root of 1 minus y squared or something align:start position:0% y squared or something align:start position:0% y squared or something I'll switch to polar coordinates R and align:start position:0% I'll switch to polar coordinates R and align:start position:0% I'll switch to polar coordinates R and theta align:start position:0% theta align:start position:0% theta well you might say align:start position:0% well you might say align:start position:0% well you might say remember we had these nice family of align:start position:0% remember we had these nice family of align:start position:0% remember we had these nice family of solutions align:start position:0% solutions align:start position:0% solutions what is it still good in polar align:start position:0% what is it still good in polar align:start position:0% what is it still good in polar coordinates well the fact is it's even align:start position:0% coordinates well the fact is it's even align:start position:0% coordinates well the fact is it's even better so the solutions you will be the align:start position:0% better so the solutions you will be the align:start position:0% better so the solutions you will be the real part and the imaginary part now align:start position:0% real part and the imaginary part now align:start position:0% real part and the imaginary part now what is X plus I Y align:start position:0% what is X plus I Y align:start position:0% what is X plus I Y in align:start position:0% in align:start position:0% in R and theta well we all know X is R cos align:start position:0% R and theta well we all know X is R cos align:start position:0% R and theta well we all know X is R cos theta plus align:start position:0% theta plus align:start position:0% theta plus I R align:start position:0% I R align:start position:0% I R sine theta and align:start position:0% sine theta and align:start position:0% sine theta and that's R align:start position:0% that's R align:start position:0% that's R times cos theta plus I sine theta the align:start position:0% times cos theta plus I sine theta the align:start position:0% times cos theta plus I sine theta the one unforgettable complex align:start position:0% align:start position:0% Euler's formula e to the I theta align:start position:0% Euler's formula e to the I theta align:start position:0% Euler's formula e to the I theta ok align:start position:0% ok align:start position:0% ok now I need its nth power the nth power align:start position:0% now I need its nth power the nth power align:start position:0% now I need its nth power the nth power of this is wonderful the real part and align:start position:0% of this is wonderful the real part and align:start position:0% of this is wonderful the real part and imaginary part of the nth power is R to align:start position:0% imaginary part of the nth power is R to align:start position:0% imaginary part of the nth power is R to the nth eetu the i N align:start position:0% the nth eetu the i N align:start position:0% the nth eetu the i N see that's my X plus iy to the enth much align:start position:0% see that's my X plus iy to the enth much align:start position:0% see that's my X plus iy to the enth much nicer in polar coordinates because I can align:start position:0% nicer in polar coordinates because I can align:start position:0% nicer in polar coordinates because I can take the real part and the imaginary align:start position:0% take the real part and the imaginary align:start position:0% take the real part and the imaginary part right away it's R to the n cos n align:start position:0% part right away it's R to the n cos n align:start position:0% part right away it's R to the n cos n theta and align:start position:0% theta and align:start position:0% theta and R to the N sine of theta align:start position:0% R to the N sine of theta align:start position:0% R to the N sine of theta these are my solutions my long list of align:start position:0% these are my solutions my long list of align:start position:0% these are my solutions my long list of solutions to Laplace's equation and it's align:start position:0% solutions to Laplace's equation and it's align:start position:0% solutions to Laplace's equation and it's some combination of those some my final align:start position:0% some combination of those some my final align:start position:0% some combination of those some my final thing is going to be some combination of align:start position:0% thing is going to be some combination of align:start position:0% thing is going to be some combination of those some combination may be align:start position:0% those some combination may be align:start position:0% those some combination may be coefficients a sub n sum I align:start position:0% coefficients a sub n sum I align:start position:0% coefficients a sub n sum I can use these align:start position:0% align:start position:0% and I can use these so maybe B sub n R align:start position:0% and I can use these so maybe B sub n R align:start position:0% and I can use these so maybe B sub n R to the N sine and theta align:start position:0% to the N sine and theta align:start position:0% to the N sine and theta you may wonder what I'm doing but what align:start position:0% you may wonder what I'm doing but what align:start position:0% you may wonder what I'm doing but what I'm achieving is to find the a big the align:start position:0% I'm achieving is to find the a big the align:start position:0% I'm achieving is to find the a big the general solution of Laplace's equation align:start position:0% general solution of Laplace's equation align:start position:0% general solution of Laplace's equation instead of two constants that we had for align:start position:0% instead of two constants that we had for align:start position:0% instead of two constants that we had for an ordinary differential equation as C 1 align:start position:0% an ordinary differential equation as C 1 align:start position:0% an ordinary differential equation as C 1 and a C 2 here I have these guys go from align:start position:0% and a C 2 here I have these guys go from align:start position:0% and a C 2 here I have these guys go from up to infinity and goes up to infinity align:start position:0% up to infinity and goes up to infinity align:start position:0% up to infinity and goes up to infinity so I have many solutions and any align:start position:0% so I have many solutions and any align:start position:0% so I have many solutions and any combination working so that's the align:start position:0% combination working so that's the align:start position:0% combination working so that's the general solution that's the general align:start position:0% general solution that's the general align:start position:0% general solution that's the general solution and I would have to match that align:start position:0% solution and I would have to match that align:start position:0% solution and I would have to match that now here's the final step and not simple align:start position:0% now here's the final step and not simple align:start position:0% now here's the final step and not simple not always simple I have to match this align:start position:0% not always simple I have to match this align:start position:0% not always simple I have to match this to the boundary conditions that's what align:start position:0% to the boundary conditions that's what align:start position:0% to the boundary conditions that's what will tell me the constants of course as align:start position:0% will tell me the constants of course as align:start position:0% will tell me the constants of course as usual C 1 and C 2 came from the matching align:start position:0% usual C 1 and C 2 came from the matching align:start position:0% usual C 1 and C 2 came from the matching the conditions now I don't have just C 1 align:start position:0% the conditions now I don't have just C 1 align:start position:0% the conditions now I don't have just C 1 and C 2 I have this infinite family of align:start position:0% and C 2 I have this infinite family of align:start position:0% and C 2 I have this infinite family of A's infinite family of bees and I have a align:start position:0% A's infinite family of bees and I have a align:start position:0% A's infinite family of bees and I have a lot more to match because on the align:start position:0% lot more to match because on the align:start position:0% lot more to match because on the boundary here I have to match align:start position:0% boundary here I have to match align:start position:0% boundary here I have to match u 0 which is given so I might be given align:start position:0% u 0 which is given so I might be given align:start position:0% u 0 which is given so I might be given suppose I was given the u0 equal the align:start position:0% suppose I was given the u0 equal the align:start position:0% suppose I was given the u0 equal the temperature was align:start position:0% temperature was align:start position:0% temperature was equal one on the top half and on the align:start position:0% equal one on the top half and on the align:start position:0% equal one on the top half and on the bottom half say the temperature is align:start position:0% bottom half say the temperature is align:start position:0% bottom half say the temperature is minus one align:start position:0% align:start position:0% that's a typical problem I have a align:start position:0% that's a typical problem I have a align:start position:0% that's a typical problem I have a circular region a align:start position:0% circular region a align:start position:0% circular region a the top half is held at one temperature align:start position:0% the top half is held at one temperature align:start position:0% the top half is held at one temperature the lower half is held at a different align:start position:0% the lower half is held at a different align:start position:0% the lower half is held at a different temperature I reach equilibrium align:start position:0% temperature I reach equilibrium align:start position:0% temperature I reach equilibrium everybody knows that along that line align:start position:0% everybody knows that along that line align:start position:0% everybody knows that along that line probably the temperature would be zero align:start position:0% probably the temperature would be zero align:start position:0% probably the temperature would be zero by symmetry but what's the temperature align:start position:0% by symmetry but what's the temperature align:start position:0% by symmetry but what's the temperature they are halfway up knotti not so easy align:start position:0% they are halfway up knotti not so easy align:start position:0% they are halfway up knotti not so easy or anywhere in there well the answer is align:start position:0% or anywhere in there well the answer is align:start position:0% or anywhere in there well the answer is you in the middle U of R and theta align:start position:0% you in the middle U of R and theta align:start position:0% you in the middle U of R and theta inside is given by align:start position:0% inside is given by align:start position:0% inside is given by that formula align:start position:0% that formula align:start position:0% that formula that formula and again the a ends and align:start position:0% that formula and again the a ends and align:start position:0% that formula and again the a ends and the B ends come by matching the getting align:start position:0% the B ends come by matching the getting align:start position:0% the B ends come by matching the getting the right answer on the boundary well align:start position:0% the right answer on the boundary well align:start position:0% the right answer on the boundary well there's a big theory there how do I align:start position:0% there's a big theory there how do I align:start position:0% there's a big theory there how do I match these that's called a Fourier align:start position:0% match these that's called a Fourier align:start position:0% match these that's called a Fourier series that's called a Fourier series so align:start position:0% series that's called a Fourier series so align:start position:0% series that's called a Fourier series so I'm finding the coefficients for a align:start position:0% I'm finding the coefficients for a align:start position:0% I'm finding the coefficients for a Fourier series the A's and B's that align:start position:0% Fourier series the A's and B's that align:start position:0% Fourier series the A's and B's that match a function around the boundary align:start position:0% match a function around the boundary align:start position:0% match a function around the boundary and I could match any function and align:start position:0% and I could match any function and align:start position:0% and I could match any function and Fourier series is another entirely align:start position:0% Fourier series is another entirely align:start position:0% Fourier series is another entirely separate video this we've done the job align:start position:0% separate video this we've done the job align:start position:0% separate video this we've done the job with Laplace's equation in a circle align:start position:0% with Laplace's equation in a circle align:start position:0% with Laplace's equation in a circle we've reduced the problem to a Fourier align:start position:0% we've reduced the problem to a Fourier align:start position:0% we've reduced the problem to a Fourier series problem we have found the general align:start position:0% series problem we have found the general align:start position:0% series problem we have found the general solution and then to match it to a align:start position:0% solution and then to match it to a align:start position:0% solution and then to match it to a specific given boundary value that's a align:start position:0% specific given boundary value that's a align:start position:0% specific given boundary value that's a Fourier series problem so I'll have to align:start position:0% Fourier series problem so I'll have to align:start position:0% Fourier series problem so I'll have to put that off to the Fourier series video align:start position:0% put that off to the Fourier series video align:start position:0% put that off to the Fourier series video thank you |