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//EXAMPLE 3-15 PG NO-185-186 Van=230.94+%i*0; Vbn=-115.47-%i*200; Vcn=-115.47+%i*200; V1=10*10^3; Ia=V1/Van; disp('i) CURRENT (Ia) is in rectangular form = '+string (Ia) +' A '); V2=4*10^3; Ic=V2/Van; disp('i) CURRENT (Ic) is in rectangular form = '+string (Ic) +' A '); V3=6*10...
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*Testcase KMAC fc0 sysclear archmode z r 1A0=00000001800000000000000000000200 # z/Arch restart PSW r 1D0=0002000180000000000000000000DEAD # z/Arch pgm new PSW r 200=41000000 # LA R0,0 R0->function code 0 r 204=4110f500 # LA R1,PB R1->parameter block address r 208=41200000 # LA R2,FO ...
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clear; clc; Zb=complex(0,.20); Z1b=complex(0,.25); V1=Z1b; Z2b=[Z1b 0;0 Z1b]; //p=2,q=3 Zbn=complex(0,.10); Z22=complex(0,.25); Z33=Z22+Zbn; Z13=complex(0,0); Z31=Z13; Z32=complex(0,.25); Z23=Z32; Z2bn=[Z1b 0 Z13;0 Z22 Z23;Z31 Z32 Z33]; //p=1,q=4 Z44=Z1b+Zb; Z14=complex(0,.25); Z41=Z14; Z24=compl...
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//consider the flow of air over a small flat plate that is 5 cm long in flow direction and 1m wide.free stream conditions corresponds to standard sea level condition V=120; //flow velocity,m/s D=1.225;//free stream density,Kg/m^3 x=0.05 ;//length of plate in meter w=1;//width of plate in meter u=1.789*10^-5;//Visc...
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// sum 8-12A clc; clear; W=80000; sigbfr=500; L=1100; Nf=3; Ng=10; N=Nf+Ng; t=((1.5*W*L)/(N*6*sigbfr))^(1/3); t=15; b=6*t; E=207*10^3; deli=(W*(L^3))/(8*E*N*b*(t^3)); Wi=(W*Nf*Ng)/(N*((3*Nf)+(2*Ng))); // printing data in scilab o/p window printf("t is %0.1f mm ",t); printf("\n deli is %0.1f mm "...
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//[lb,nwrk]=newlab(nwrk) //Cette macro retourne lb le numero d'etiquette suivant //! lb=nwrk(9)+1 nwrk(9)=lb //end
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clc; disp(3*5,"Moles = "); //displaying result disp(15*(2.02+32.06+64),"Mass = "); //displaying result
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//Chapter 4 //Example 4_12 //Page 80 clear;clc; md=1; lf=0.5; cc=12*1e5; rm=0.005; fc=1600; id=0.1; fcon=0.3; w=50000; c=150; rc=0.15; ugpa=md*1000*lf*8760; printf("(i) Private oil engine generating plant\n"); afc=fcon*ugpa; a_f_c=afc*fc/1000; arm=rm*ugpa; aw=w; aid=id*cc; printf(" Annual fuel consumption = %.0f k...
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//Chapter 9, Problem 1 clc; B=1.25; //flux density v=4; //conductor velocity l=300*10^-3; //conductor length R=20; //resistance E=B*l*v; //calculating emf I=E/R; //calculating current from ohm...
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// plot_spec.sci function [freq_matrix] = plot_spec(autom, iter_num) if ~(exists("iter_autmats")) then getf("/home/muntyan/math/automata/scilab/iter_autmats.sci") end num_states = size(autom); num_states = num_states(1); mats = list(1); for i=2:num_states mats = lstcat(mats, list(1)) end for i=1:iter_num mats =...
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// Function Name: indexMin/indexMax // Return index of min/max value // Calculating the indexMin/indexMax. inputvec1 = [1, 2, 3]; result = armaVec("indexMin",inputvec1) result = armaVec("indexMax",inputvec1)
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// page no 326 // examle no 10.5 // SUBTRACTION OF TWO 16 BIT NUMBERS clc; printf('B--> 85H C--> 38H \n'); printf('D--> 62H E--> A5H \n \n'); b=hex2dec(['85']); c=hex2dec(['38']); d=hex2dec(['62']); e=hex2dec(['A5']); printf('MOV A,C \n \n'); a=c; printf('SUB E \n'); a=a-e; Z=a+256; X=dec2hex(Z...
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clear; clc; mode(0) function y=calcFuel(m) y=floor(m/3)-2 endfunction // Part 1 printf("Part 1\n********\n") mm=read("input.txt",-1,1); printf("Fuel for each module") f=floor(mm/3)-2; f printf("Total fuel:") t=sum(f,1) t // Part 2 printf("Part 2\n********\n") printf("Fuel for fuel for each module") f2 = zeros(l...
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// chapter 2 example 1 //------------------------------------------------------------------------------ clc; clear; // µr1 = 3; // relative permeability of region 1 // µr2 = 5; // relative permeability of region 2 // H1 = (4ax + 3ay -6az)A/m; Magnetic field intensity // Therefore B1 = µoµr1H1 // ...
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clear// //Variables VS = 6 //Source voltage (in volts) R1 = 330 //Resistance (in ohm) R2 = 470 //Resistance (in ohm) VD = 0.7 //Diode voltage (in volts) //Calculation RT = R1 + R2 //Total Resistance (in ohm) I = (VS - 0.7)/RT //Cur...
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//Secant Method //the first few iteration converges quikcly in negative root as compared to positive root clc; clear; close(); funcprot(0); format('v',9); deff('[Secant]=f(x)','Secant=exp(x)-x-2'); x = linspace(0,1.5); subplot(2,1,1); plot(x,exp(x)-x-2); plot(x,zeros(length(x),1)); //from the graph the function has 2 r...
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float_const_e_sign = float_const_e&'+' | float_const_e&'-'; point = '.'; zero_digits = zero&'8' | zero&'9' | int_oct_const&'8' | int_oct_const&'9' | zero_digits&t_digit; white_space = comment_star&'/'; comment_star = comment&'*'; comment = slash&'*' | comment&t_not_star_and_not_slash | ...
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//Example 4.16 (a) //Program to Evaluate and Compare the 8-point DFT of the given Sequence //x1[n]=1, -3<=n<=3 using DIT-FFT Algorithm. clear; clc ; close ; x1=[1,1,1,1,0,1,1,1]; //FFT Computation X1 = fft (x1 , -1); disp(X1,'X1(k) = ');
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@relation german @attribute StatusAccount{A11,A12,A14,A13} @attribute DurationMonth integer[4,72] @attribute CreditHistory{A34,A32,A33,A30,A31} @attribute Purpose{A43,A46,A42,A40,A41,A49,A44,A45,A410,A48} @attribute CreditAmount integer[250,18424] @attribute SavingsAccount{A65,A61,A63,A64,A62} @attribute EmploymentSin...
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clear n=63 T=135 h = 1/10 N =T/h p = 2 U_m1 = zeros(n,1) U_0 = zeros(n,1) v_0 = zeros(n,1) m=1 for i = 1:n if modulo(i, 2) == 0 M(i,:) = m else M(i,:) = 1 end end M = diag(M) //Mise au point des valeurs de A A = zeros(n,n) A(1,1) = M(i)+1 for k=2:n A(k,k) = M(i)+2*h**2 if k<n ...
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// Updated(24-7-07) // 7.3 pol1 = [1 -0.9]; pol2 = [1 -0.8]; G1 = trfu(pol1,[1 0],-1); G2 = trfu(pol2,[1 0],-1); w = linspace(0.001,%pi,1000); xset('window',1); bode([G1;G2],w); G = tf(pol1,pol2,-1); xset('window',2); bode(G,w);
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clc clear close clf pi=22/7; disp('Enter co-ordinates of points'); x=input('Enter X coordinate: '); y=input('Enetr Y coordinate: '); z=input('Enter Z coordinate: '); i=input('Translation or rotation?(1 or 2)'); p=[x y z]; select (i) case 1 k=input('enter translatonal value') j=input('enter which ...
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//Example 2.3, Page no 50 p=1//j/s r=1//radius in m h=6.63*10^-34//Joule-sec c=3*10^8//m/sec lambda=5.89*10^-7//m R=p/(4*%pi*r^2) E=(h*c)/lambda Rate_R=R*(1/E) printf("\nRate at which photons strike unit area of place %e photons/m^2-sec",Rate_R)
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//Fuels and Combustion// //Example 8.21// C=90.2;//percentage of carbon// O=2.9;//percentage of oxygen// H=2.40;//percentage of hydrogen// GCV=(8080*C+34400*(H-O/8))/100;//Gross calorific value of the sample in cal per grams// printf('\nGross Calorific value of the fuel=GCV=%fcal/g',GCV);
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clc //initialisation of variables w= 0.0764 //lbf/ft^3 u= 88 //ft/sec g= 32.2 //ft/sec^2 //CALCULATIONS q= w*u^2/(2*g) //RESULTS printf (' dynamic pressure of air = %.2f lbf/ft^2',q)
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//scilab 5.4.1 //Windows 7 operating system //chapter 11 Sinusoidal oscillator and multivibrators clc clear f=30//f=frequency of oscillation of a Wien-bridge oscillator in Hz C=(500*10^(-12))//C=capacitance in farad //f=1/2*%pi*R*C//R=resistance in ohm R=1/(2*%pi*f*C) disp("Mega ohms",R/10^6,"Resistance needed...
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clear // // // //Variable declaration a=5.63*10**-10 //lattice constant(m) h=1 k=1 l=1 //miller indices theta=27.5*%pi/180 //glancing angle(radian) n=1 //order h=6.625*10**-34 //planck's constant c=3*10**10 //velocity of light(m/sec) e=1.6*10**-1...
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errcatch(-1,"stop");mode(2);//ex14.3 disp("cannot be shown in scilab") exit();
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//Example sec 11.9.2 a //stability of linear continuous system clear;clc; xdel(winsid()); s=%s; G=1/(s*(s+1)*(s+2)) G1=pfss(G) //taking Z transform of G1 z=%z; G2=(z/(2*(z+1)))-(z/(z+%e^(-1)))+(z/(2*(z+%e^(-2)))) //upon simplification we get the following characteristic equation B=z^3-(1.3*z^2)+0.85*z-0.5 ...
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s=%s; syms k H=syslin('c',k/(s*(s+3)*(s^2+(2*s)+2))) evans(H,10)
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//Introduction to Fiber Optics by A. Ghatak and K. Thyagarajan, Cambridge, New Delhi, 1999 //Example 2.8 //OS=Windows XP sp3 //Scilab version 5.5.2 clc; clear; //given deltanu=1.5e9;//change in frequency of He-Ne laser in Hz c=3e8;//speed of light in m/s lc=c/deltanu;//Corresponding coherence length mprintf("...
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data=read("/home/dmitri/projects/boggie/math/motor2.txt",-1,2); //data=read("/home/bogdel/work/google-code/boggie/math/motor2.txt",-1,2); time=(data(:,2)-data(1,2))/1000; angle=data(:,1); angle=angle'; time=time'; f=[time;angle]; function e=G(a, z), e = z(2) - a(1)*(z(1)-a(2)+a(2)*%e^(-z(1)/a(2))); endfunction ...
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n1=2; n2=4; dE=21.7*(10^-12)*((1/n1^2)-(1/n2^2)); h=6.625*10^-27;//plank's constant// C=3*10^10;//velocity of light in cm/sec// l=h*C*10^8/dE;//Wavelength of second line in balmer series in Angstrums// printf('wavelength of the second line in balmer series=l=%fAngstrums',l);//here the answer given in textbook is ...
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P=10000 v1=2200 v2=220 r1=4 r2=0.04 x1=5 x2=0.05 a=v1/v2 R=r1+a*a*r2 X=x1+a*a*x2 I1=P/v1 pf=0.8 V2=v2*a theta=acos(pf) Vd=I1*(R*cos(theta)+X*sin(theta)) VR=Vd/v1*100 V1=v1+Vd disp(VR,V1) pf=cos(atan(X/R)) disp("leading",pf) Pr=P*pf Q=-P*sin(acos(pf)) disp(Q,Pr)
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//Realiza la eliminacion de Gauss con Pivoteo Parcial Escalado //A es matriz de nxn //b es vector fila de n //B es la matriz triangular superior resultado de la eliminacion //Calcula el maximo de cada fila. // Luego usa como pivote: abs(a_pi/s_p) = max(1,n) abs( a_ki/s_k ) function [B] = gauss_elim_ppe(A,b) ...
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//Exa 4.7 clc; clear; close; //given data : VP=-4;//in Volt VGS=-2;//in Volt IDSS=10;//in mAmpere IDSS=IDSS*10^-3;//in Ampere //Formula : ID=IDSS*[1-VGS/VP]^2 ID=IDSS*[1-VGS/VP]^2;//in Ampere disp(ID*1000,"Drain Current in mA : "); disp("The minimum value of VDS for pinch-off region is equal to VP. Thus the...
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//Caption: Find the resistance required //Exa:8.3 clc; clear; close; I_1=40//Current taken by series motor(in A) V=500//Supplied voltage(in volts) n_1=100//Initial speed(in%) n_2=80//final speed(in%) I_2=sqrt(((I_1^2)*(n_2^2))/(n_1^2)) a=(I_1*(n_1/100))/(I_2*(n_2/100)) R=((a*V)-V)/(a*I_2) disp(R,'Resistance...
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// Chapter 5 Example 9 //============================================================================== clc; clear; //input data // (100) planes in rock crystal h = 1; // miller indice k = 0; // miller indice l = 0; // miller indice a = 2.814 /...
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// Example 1.4.c :relative error clc, clear // given : vm=42; // pressure in bar vt=41.4; // pressure in bar Es=vm-vt; Er=Es/vt; disp("relative error is "+string(Er)+" or "+string(100*Er)+" %")
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// RPY2T.SCI convert Row-Pitch-Yaw angles to homogeneous transformation // www.controlsystemslab.com July 2012 // T = RPY2T(RPY, OPTIONS) is a homogeneous tranformation matrix equivalent to the // specified roll, pitch, yaw angles which correspond to rotations about the // X, Y, Z axes respectively. If RPY has...
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//Problem 6.12: //initializing the variables: T1 = 540; // in deg F T0 = 300; // in deg F T2 = 180; // in deg F T3 = 60; // in deg F m1 = 1; m2 = 2; Cp = 1; //calculation: dSh = m1*Cp*log((T0 + 460)/(T1 + 460)) dSc = m2*Cp*log((T2 + 460)/(T3 + 460)) //for one exchanger dSe = dSh + dSc //exchanger F d...
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// Display mode mode(0); // Display warning for floating point exception ieee(1); clear; clc; disp("Engineering Thermodynamics by Onkar Singh,Chapter 1,Example 7") w1=100;//weight of object at standard gravitational acceleration in N g1=9.81;//acceleration due to gravity in m/s^2 g2=8.5;//gravitational acceler...
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E23=20000;//laminate Young’s modulus of 23,given,in N/mm^2 E12=45000;//laminate Young’s modulus of 12,given,in N/mm^2 L12=250;//langth of 12,given,in mm L23=300;//langth of 23,given,in mm t12=2;//thickness of 12,given,in mm t23=1.5;//thickness of 23,given,in mm Sy=2*10^3;//load
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// Example 1.39 The odds in favour of an event A are 3:4. clc; clear; A=3/7; B=4/11 AB=A*B; disp(A,"Probab. of occurrence of A are P(A)=",B,"Probab. of occurrence of B are P(B)="); disp(A+B-AB,"The probab. of at least one of the events A and B is given by ");
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clc; //page no: 2-14 //Example-2.6 //Given Total antenna current is 5A, and modulation index is 0.6 Itotal=5; u=0.6; //Itotal=Ic*sqrt(1+(u^2/2)); Ic=Itotal/sqrt(1+(u^2/2)); disp(+'A',Ic,'Antenna current when only carrier is sent is ');
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function [bool_success,STANCE_GRAPH,expansion_nodes,single_cndts_node_nb] = plan(INIT_STANCE,DATASET,PARAMS) //Author : Maxens ACHIEPI //Space Robotics Laboratory - Tohoku University //Description: // //INPUT //PARAMS: struct containing: // * //OUTPUT // ...
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clear; clc; // Stoichiometry // Chapter 1 // Dimensions and Units // Example 1.1 // Page 12 printf("Example 1.1, Page 12 \n \n"); // solution // Using conversion factors from table 1.3 (Pg 9) q1 = 75 // [gallon/min] (volumetric flow rate) q2 = 75/(60*.219969) // [dm^3/s] row = 0.8 // [kg/dm^3] q3...
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@relation led7digit @attribute Led1 real[0.0,1.0] @attribute Led2 real[0.0,1.0] @attribute Led3 real[0.0,1.0] @attribute Led4 real[0.0,1.0] @attribute Led5 real[0.0,1.0] @attribute Led6 real[0.0,1.0] @attribute Led7 real[0.0,1.0] @attribute number{0,1,2,3,4,5,6,7,8,9} @inputs Led1,Led2,Led3,Led4,Led5,Led6,Led7 @output...
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clc(); clear; // To calculate the overall thermal resistance and overall heat transfer coefficient b = 0.5/12; // Thickness of iron wall in ft k = 30; // Thermal conductivity in Btu/hr-ft h1 = 2; // Heat transfer coefficient in Bt...
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printf('example 1.14 page number 45') disp ("this is a theoritical question, book shall be referred for solution")
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clc; funcprot(0); // Initialization of Variable f=0.152;//focal length in m H=1800;//elevation of topmost point in m h=300;//elevation of ground in m //calculation S=f/(H-h); disp(round(1/S),"scale of photograph in 1 in") clear()
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// Example 3.10, page no-126 clear clc ugb=1.5*10^6 f1=2*10^3 A0=ugb/f1 printf('Openloop Dc Voltage gain= %d ',A0)
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clear all; clc; disp("Ex 3_3") disp("Equilibrium Equations") disp("T_EG*sin(30) - T_EC*cos(45) = 0 ....(1)") disp("T_EG*cos(30) - T_EC*sin(45) - 20N = 0 ....(2)") disp("Solving both the eqns simultaneously,") disp("T_EC = 38.6 N") disp("T_EG = 54.6 N") disp(" ") disp("Equilibrium Equations") disp("38.6*cos(45) (4/5)*T_...
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function [stk,txt,ilst,vnms,vtps,nwrk,lbl]=op2for(op,stk,vnms,vtps,nwrk,lbl) // //! txt=[] iop=evstr(op(2)) execstr('[stkr,nwrk,txt,top]=%'+ops(iop,2)+'2for(nwrk)') stk(top)=stkr s1=list() for k=1:top,s1(k)=stk(k);end stk=s1
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//Example 17.1 T=30;//Temperature (C) T=T+273;//Temperature (K) v_w=331*sqrt(T/273);//Speed of sound in air at sea level(m/s) f_min=20;//Minimum frequency (Hz) f_max=20000;//Maximum frequency (Hz) lambda_max=v_w/f_min;//Maximum wavelength (m) printf('Maximum wavelength = %0.0f m',lambda_max)//Restricting answer ...
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errcatch(-1,"stop");mode(2); //Initialization of variables dh=3 //in L=12 //in g=32.2 //ft/s^2 //calculations a=dh/L *g //results printf("Acceleration = %.2f ft/s^2",a) exit();
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1 Januar 2 Februar 3 März 4 April 5 Mai 6 Juni 7 Juli 8 August 9 September 10 Oktober 11 November 12 Dezember
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//Engineering and Chemical Thermodynamics //Example 5.2 //Page no :222 clear ; clc ; //Given T_c = 370 ; //[K] P_c = 41.58 * 10^5 ;//[N/m^2] R = 8.314 ; V1 = 0.001 ;//[m^3] V2 = 0.04 ; //[m^3] q = 600 ; //[J] a = 27/64 * (R ^2)*(T_c)^2 / P_c ; //Using E5.2D , E5.2E in E5.2C del_U = -0.96 * (1 / V2 - ...
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//Chapter 5: Chemical Kinetics and Catalysis //Problem: 1 clc; //Declaration of Variables K = 3.5 * 10 ** - 2 // Rate constant // Solution mprintf("First order reaction = 0.693 / K\n") t = 0.693 / K mprintf(" Time taken for half the initial concentration to react:%.1f minutes", t)
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clc //initialisation of variables clear r= 1/5 b1= 2 //ft a1= 3/5 //ft //CALCULATIONS r= (a1*b1)^2*r //RESULTS printf ('ratio of resultant forces acting on coorresponding fluid elements = %.2f ',r)
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clear clc s=50 v=11 x=.15 S=50 V=11 Xe=.15/4 FMVA= round(10000/Xe)/10000 Fault=FMVA * S mprintf("\n(a)fault level = %.3f pu", Fault) sga=.5*Fault sgb=800-sga xb=.15/2 X=(S/sgb)-xb x=X*(V*V/S) mprintf("\n(b)X = %.3f ohms", x)
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//check o/p when i/p is 0.1 v with refernce to 1 ohm resistance v=0.1; d=db(v); disp(d); //output //!--error 4 //Undefined variable: SignalType //at line 28 of function db called by : //d=db(v); //at line 3
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clear //Given ma=1.00893 m1=1.00813 m2=2.01473 a=931.5 a1=4.00389 //Calculation m=ma+m1-m2 Eb=m*a m3=2*ma+2*m1-a1 Eb1=m3*a //Result printf("\n (i) Binding energy when one neutron and one proton combined together is %0.2f Mev",Eb) printf("\n (ii) Binding energy when two neutrons and two protons are combined is %0.1f ...
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clc;clear; //Example 4.5 //given values m=0.025; V=120; I=0.2; t=300;//total time taken in sec P1=300; Qout=3.7; //from Table A–5 //at P1 the conditon is sat. vap h1=2724.9; //Calculations //Part - a //therotical proving //Part - b We=V*I*t/1000;//electrical work in kJ //from eqn 4 -18 i.e de...
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clc; e1=-13.6; //energy in eV disp(e1/9,"Energy in eV = "); //displaying result
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P = 12 ; // Axial load in K r = 2.1 ; // Inner radius of the cylinder in inch t = 0.15 ; // Thickness of the cylinder in inch ta = 6500 ; // Allowable shear stress in Psi // From in plane sg=hear stress p1 = (ta - 3032)/3.5 ; // allowable internal pressure // Above equation comes from solving the following equati...
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function r=%s_m_ip(s,ip) // s*ip if size(s,'*')<>1 then error(10),end r=(s*ip(1)):(s*ip(2)):(s*ip(3))
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blkInd = get('blockList','Value'); vilInd = get('villageList','Value'); hemInd = get('hemletList','Value'); if isempty(blkInd)|isempty(hemInd) then messagebox("Select a hemlet first","littleBird"); else str = get('hemletList','String'); btn = messagebox("Are you sure you want to delete " + str(hemInd),'litt...
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//Example 2.16//resistance and capacitance clc; clear; w=7500;//in rad/s R2=140;//in ohms R3=1000;//in ohms R4=R3;//in ohms C2=0.0115;//capacitance in micro farad oC2=(w*C2*10^-6);//IN OHMS Z2= R2+(%i*(1/oC2)); Z3=R3;// Z4=R4;// Z1=(Z2*Z3)/(Z4);// R1=real(Z1);// C1=1/(w*imag(Z1));//capacitance in farad disp(R1,"resist...
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//**************************** Measure Volt (mite_adc) **************************** if (blk_name.entries(bl) =='meas_volt') then global MITE_ADC_check; if MITE_ADC_check==0 MITE_ADC_check=1; else MITE_ADC_check=MITE_ADC_check+1; end cap_info = cap_info2(cap_info,pass_num,'out_mite_adc', bl) mputl("# MITE_ADC"...
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// Exa 1.22 clc; clear; close; // Given data miu_p= 0.05;// in m^2/v-sec rho=5*10^28/10^8;// in /m^3 q= 1.6*10^-19;// in C sigma= q*rho*miu_p;// in (Ωm)^-1 disp(sigma,"The conductivity of silicon material in (Ωm)^-1 is : ")
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//Example //Calculate the baseband SN ratio for the video signal //Variables clc clear Fmax = 4.2 RFbw = 30 CNratio = 15 P = 9 Q = 8 //Result delFpk = (RFbw/2) - Fmax Brf = 2*(delFpk + Fmax) SN = CNratio + 10*log10(RFbw/Fmax) + 20*log10(delFpk/Fmax)+ 1.5 +P + Q printf("The baseband SN ratio for the vide...
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{ "EGTE 150800Z 1509/1518 18005KT CAVOK TEMPO 1512/1518 BKN040": { "TAF matches METAR exactly": { "metar": "EGTE 150950Z 18005KT CAVOK", "test time": "20200615T1000Z", "expected": "" }, "TAF base conditions cover METAR - FEW040 cloud": { "metar...
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// Example 32_27 clc;funcprot(0); //Given data T=[0 2 3 6 8 12 14 15 17 23 24];// Time in hours L=[1200 2000 3000 1500 2500 1800 2000 1000 500 800];// Load in kW //Calculation T_p=[0 0 2 2 3 3 6 6 8 8 12 12 14 14 15 15 17 17 23 23 24 24];// Time in hours for load curve L_p=[3200 1200 1200 2000 2000 3000 300...
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//Example 1.14 //1s compliment //Page no. 12 clc;close;clear; function [x1]=com1(x) //function for 1s compliment for i=8:-1:1 x=x/10; xd=x-fix(x) if(floor((xd*10)+0.1)==1) x1(1,i)=0; else x1(1,i)=1; end x=x-xd; end end...
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// Example 14_1 clc;funcprot(0); //Given data P=35;// bar T_1=400;//Temperature of steam in °C m_s=200;// Flow rate of steam in Tonnes/hr T_2=450;//°C T_sp=60;// The temperature of spray water in °C C_pw=4.2;// kJ/kg.°C //Calculation //From steam tables, //At 35 bar and 450°C h_1=3337;// kJ/kg //At 35 bar ...
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clear a=900 b=387 c=a*b
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//Ex 9.9 clc; clear; close; format('v',5); f0=2;//kHz(Critical frequency) Ap=5;//dc gain //For Butterworth filter using sallen key alfa=1.414;klp=1;//constant fH=f0;//kHz f_3dB=f0;//kHz Ap1=3-alfa;//gain RfBYRi=Ap1-1;//ratio disp("Various design parameters are :-"); C=0.05;//micro F//Chosen for the design...
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//Finding of Pressuure gradient.Avg velocity,Discharge,Shear at wall //Given mu=0.02; B=0.01; b=1; v=2; //To Find A=B*b; dp=-((16*mu)/B^2); dp1=-dp; V=(B^2/(12*mu))*(-dp); q=A*V; x=(-dp*(B/2)) disp(" Pressuure Gradient ="+string(dp1)+" N/m^2 per meter"); disp(" Avg velocity ="+string(V)+" m/sec"); disp("...
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clear;lines(0); //Standard formulas to compute Riccati solutions A=rand(3,3);B=rand(3,2);C=rand(3,3);C=C*C';R=rand(2,2);R=R*R'+eye(); B=B*inv(R)*B'; X=ricc(A,B,C,'cont'); norm(A'*X+X*A-X*B*X+C,1) H=[A -B;-C -A']; [T,d]=gschur(eye(H),H,'cont');T=T(:,1:d); X1=T(4:6,:)/T(1:3,:); norm(X1-X,1) [T,d]=schur(H,'cont');T=T(:,1:...
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лобаны лобатӥ V;SG;1;PST;CAUS+INTR кулыны кулозы V;PL;3;FUT;INTR огъя огъягес ADJ;COMPV утьыны утетъя V;SG;LGSPEC_MULT;3;NEG;PRS;CAUS+TR чабыны чабиз V;SG;3;PST;TR салон салонэз N;NOM;SG;PSS3S;LGSPEC1 жюри жюрилэн N;GEN;SG;LGSPEC1 кылзӥсь кылзӥсьёсме N;HUM;ACC;PL;PSS1S зарезь зарезям N;IN+ESS;SG;PSS1S детектив детектив...
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mf 100 mt 0.04 mc 170. 222. 83. -.5 -.7 -.5 0 0 0 0 0 0 35.0 35.0 25.0 600 450 m 0.5 0.5 0.5 0.0 0.0 0.0 0.0 0.0 0.0 0.0 mp 0 1 0 22 1 0 m 0.7 0.0 0.0 0.5 0.5 0.5 100. 0.0 0.0 0.0 / 8 spheres: red ms -20.0 13.67 -62.56 10. 0 0 0 0 -10 0 0 0 0 ms -20.0 70.0 -62.56 10. 0 0 0 0 -10 0 0 0 0 ms 10.0 -10.0 -62.56 10. 0 0 0...
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// Scilab Code Ex 10.7 The Electroic Specific Heat of Cu: Page-341 (2010) k = 1.38D-23; //Boltzmann constant, in J/mol-K N = 6.023D+23; // Avogadro's Number Efermi = 7.05; // Fermi energy of copper, in eV EFeV = Efermi*1.6D-19; // Fermi energy conversion, in J T1 = 4; //Lower value of temperature, i...
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function[] = plot_format() //Get the handle of current axes g = gca() //Give labels and set label properties g.labels_font_color=5 g.font_size=3 g.grid=[1,1] g.box="off" endfunction //Obtain path of solution file path = get_absolute_file_path('solution7_21.sce') //Obtain path ...
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//Fluid Systems- By Shiv Kumar //Chapter 5- Francis Turbine //Example 5.11 //To Determine The Flow Rate, Guide Vane Angles, Runner Vane Angles and Inner and Outer Diameters of the Runner. clc clear //Given Data:- H=86.4; //Net Head, m N=650; //Speed, rpm P=397; //Shaf...
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// 08.09.13 function Out=PartitionPt() global PARTITIONPT; Out=PARTITIONPT; endfunction
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function pythonInterpret(nLines) if ~exists("nLines") then, nLines = 1, mprintf("Enter 1 Python expression\n"); else mprintf("Enter %d Python expressions: \n", nLines); end for n = 1:nLines mprintf("%d/%d", n, nLines); expression = input(">>> ", "string"); ...
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clc //Initialization of variables gam=981 //dyn/cm^2 sigma=72 //dyn/cm theta=0 //degrees d=0.5 //cm depth=90 //cm //calculations h=4*sigma*cosd(theta) /(gam*d) Td=depth-h //results printf("True depth = %.3f cm",Td)
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//Example 2_7 page no:69 clc //mesh current equation for the circuit resistance=[7,-2;-2,12] volt=[10,-50] current=inv(resistance)'*volt'//calculating current I1 I2 I3 disp(current,"current flowing in the circuit I1 and I2 (in ampere)")
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clc; clear; Q=300;//gal/min d1=3.5;//in. p1=18;//psi d2=1;//in. p2=60;//psi diffu=3000;//ft*lb/slug //energy equation //m(u2-u1+(p1/d)-(p2/d)+((v2^2)-(v1^2))/2 + g*(z2-z1))=q-Wshaft m=Q*1.94/(7.48*60);//slugs/sec v1=Q*12*12/(%pi*(d1^2)*60*7.48/4); v2=Q*12*12/(%pi*(d2^2)*7.48*60/4); Wshaft=m*(diffu + ...
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// s : 2014.08.25 function Objsymb(Symb,Thick,Face,Dir) for J=1:length(Symb) Objcurve(Symb(J),Thick,Face,Dir); end endfunction
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//water// //page 1.46 example 19// clc Purity_Lime=.95 Purity_soda=.9 W1=81;//amount of Ca(HCO3)2 in ppm// W2=73;//amount of Mg(HCO3)2 in ppm// W3=68;//amount of CaSO4 in ppm// W4=95;//amount of MgCl2 in ppm// W5=14.8;//amount of Mg(NO3)2 in ppm// W6=14.7;//amount of H2SO4 in ppm// M1=100/162;//multiplic...
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//given clc Da=2.5//metre f=5d+9//hertz v=3d+8 lemda=v/f//metre NNBW=140*(lemda/Da)//degree//beamwidth between first null HPBW=70*(lemda/Da)//degree//half power beamwidth disp(HPBW,NNBW,'the beamwidth between first null and the value of half power beamwidth in degree')//degrees
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n=50; a=10^(-4); s=2*10^(-2); disp("Part a"); mu0=4*%pi*10^(-7); l=n^2*mu0*a/s; disp("the inductance (in μH) of the air-core coil is"); disp(l*10^6); disp("Part b"); mur=200; l1=mur*l; disp("the new inductance (in mH) is"); disp(l1*10^3); disp("Part c"); n1=2*n; l2=4*l1; disp("the new inductance (in mH) i...
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// Scilab Code Ex15.1 Determining Photon number by using Planck quantum law: Page-486 (2010) h = 6.626e-034; // Planck's constant, Js f = 1760e+03; // Frequency of the radio transmitter, Hz P = 10e+03; // Power of radio transmitter, W E = h*f; // Energy carried by one photon from Planck's law, J N = P/...
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function a=mmq(x,y,k) n=length(x) for i=1:n //linhas for j=1:k+1 v(i,j)=x(i)^(j-1) end b(i)=y(i) end a=inv(v'*v)*(v'*b) endfunction
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//Estimate Saturation Magnetisation //Ex:14.6 clc; clear; close; b=9.27*10^-24;//Bohr Magneton in A/sqm m=0.6*b; a=0.35*10^-9; n=4;//FCC m_g=n*m/a^3;//in A/m disp(m_g,"Saturation Magnetisation (in A/m) =");
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//EX10_13 PG-10.62 clc disp("Refer to the figure-10.55 and shown") R1=1e3; Rf=1e3;//feedback resistance Vin1=2; Vin2=1; Vin3=4; Vout=-(Vin1+Vin2+Vin3)*Rf/R1 printf("\n output voltage Vout=%.f V \n",Vout)
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// Part (a) v = 16 ; // v = v1/v2 P1 = 300e03; P2 = P1*v; R = 0.287; T1 = 300+273; W12 = R*T1*log(1/v); disp("If the fluid is in the air") disp("Pa",P2,"The final pressure is ") disp("kJ",0,"The change in internal energy is") disp("kJ",W12,"Work done is") // Part (b) v1 = 0.7664; u1 = 2728.7; v2 = v1/16; x2 = (v2-0.001...