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//developed in windows XP operating system //platform Scilab 5.4.1 clc;clear all; //example 9.8 //calculation of voltage at balance //given data V=10000//applied voltage(in V) R3=1000/%pi//resistance(in ohm) in CD branch R4=62//variable resistance(in ohm) Cs=100*10^-12//standard capacitance(in F) f=50//freq...
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#Function: PM.sce #Description: Scenario File for Prospective Memory #Programmer: Connor Reid #Created@: 7/7/14 #LastMod@: 29/04/16 #------------------------------------------------------------------- scenario = "PM"; response_matching = simple_matching; no_logfile = true; active_buttons = 34; button_codes = 1, 2...
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//Example 4.2 //Convolution sum of x[n] and h[n] clc clear n=-1:1; n1=-2:2; x=[0.5 0.5 0.5]; h=[3 2 1]; y=coeff(poly(h,'z','c')*poly(x,'z','c')) disp("Convolution of x[n] and h[n] is...") disp(y)
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clc clear //Initialization of variables q=240 //ft^3/sec/ft v1=60 //ft/s gam=62.4 rho=1.94 //slug/ft^3 g=32.2 //ft/s^2 //calculations y1=q/v1 v2=8.6 //ft/s y2=28 //ft hl= (y1+ v1^2 /(2*g)) - (y2+ v2^2 /(2*g)) hpp=hl*q*gam/550 //results printf("Downstream depth = %.1f ft",y2) printf("\n Horsepower dissi...
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clear ; clc; // Example 25.3 printf('Example 25.3\n\n'); //page no. 771 // Solution // Given // The main reaction is 4*NH3(g) + 5*O2(g) --> 4*NO(g) + 6*H2O (A) H_fNH3 = -46.191 ;// Standard heat of formation of NH3 -[kJ/ g mol] H_fO2 = 0 ;//Standard heat of formation of O2 -[kJ/ g mol] H...
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// Example 10.1 // Calculation of the non linear coeffifient. // Page no 429 clc; clear; close; //Given data n2=2.5*10^-20; // Kerr coefficient lambda=1550*10^-9; // Wavelength A=80*10^-12; // Effective area // Non linear coeffifient g=(n2*...
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clc; disp("Example2.4"); v=3500; //volume in metre cube. n1=370-300; //no. of audience on wooden seats. n2=300-70; //no. of empty wooden seats. a1s1=0.04*60; //absorption due to wooden doors. a2s2=0.03*700; //absorption due to plastered walls. a3s3=0.06...
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clear // // // //Variable declaration a=4.28*10^-10; //side(m) e=1.6*10^-19; //charge of electron //Calculation n=2/(a^3); RH=-1/(n*e); //hall coefficient(m^3/C) //Result printf("\n hall coefficient is %0.3f *10^-9 m^3/C",RH*10^9)
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// @Harness: verifier // @Purpose: "Test for syntactic Lvalue correctness" // @Result: "NotAnLvalue @ 7:8" architecture not_lalue_01 { operand-type A[5]: int [0,31]; subroutine foo(a: A): void { read(a) = 0; } }
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//Example NO.11.3 //Page No.336 clc;clear; E0 = (8.854*10^-12); Er = (6);//Dielectric constant. E = 100;//Electric field intensity -[V/m]. P = (E0*(Er-1)*E);//Polarization. printf("\nPolarization produced in a dielectric medium is %3.3e C/m^2",P);
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// Example 17_8 clc;funcprot(0); //Given data T_s=38;// The temperature of the steam entering the condenser in °C T_a=34;// The temperature of the air entering the air pump in °C T_c=36;// The temperature of the air of the condensate in °C m_a=3;// kg/hr m_c=8000;//The condensate removed in kg/hr R=287;// J/kg...
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function []=warning(txt) // //! // Copyright INRIA write(logfile,'WARNING:' +txt)
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//Example 8.6 clear; clc; //Given T=298;//temperature in K R=8.314;//gas constant in J K^-1 mol^-1 p=101325;//pressure in N m^-2 MoNH3=-16.6;//standard chemical potential of amonia at 298 K in kJ mol^-1 MoN2=0;//standard chemical potential of nitrogen at 298 K in kJ mol^-1 MoH2=0;//standard chemical potentia...
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clear; clc; x=0:1:6 plot2d3(x,exp(x)); xlabel('t') ylabel('y') xtitle('Discrete Exponential Signal')
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//函式LBG.m: LBG訓練法// function [I_codebook,O_distortion]=LBG(t_image,nc,nd,th) //I_codebook:最後所得之碼簿// //O_distortion:向量到最後所得碼簿之間的平均誤差// //t_image:訓練資料// //Rearrangement of the training image// [row,col]=size(t_image); nt=row*col/nd; R_image=[]; sqrt_nd=sqrt(nd); x_count=fix(col/sqrt_nd); y_count=fix(row/sqrt_nd); for i=1...
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// For scilab 5.1.1 or lower version users, //use scicos command to open scicos diagrams instead of xcos global err_count y p q xk_old Tsp heats fan temp heat p = 40; //prediction horizon q = 4; // control horizon xk_old = zeros(8,1); Tsp=1; heats=1; fan=1; temp=1; exec ("mpc_local.sci"); exec("mpc_run.sci");
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clear; clc; E=1; Ig=.8; pf=.8; Xd=1.1; Xq=.8; p=E+complex(0,Xq)*Ig*complex(.8,-.6); angle=atand(imag(p)/real(p)); dell=acosd(pf); Iq=Xq*cosd(dell+angle); Id=Xq*sind(dell+angle); function [A] = p2z(R,Theta) if argn(2) <> 2 then error("incorrect number of arguments."); end if ~and(size(R) == size(T...
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FLAGS='-bi -p PA_' STDIN=$'aaa,bbb,ccc\n\'aa\'xx\',"bb""yy",cc`zz\\ww\n' STDOUT=$'PA_aaa=$\'\\\'aa\\\'xx\\\'\'; PA_bbb=\'bb"yy\'; PA_ccc=\'cc`zz\\ww\';\n' STDERR='' EXITVAL='0'
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I1=2.12+%i*3.67 //Defining current equations in rectangular form I2=-3.07+%i*1.77 I3=-1.84+%i*1.06; I4=-(I1+I2+I3); [Ro,Theta]=polar(I4); function y=f(t), y=Ro*sqrt(2)*sin(t+Theta), endfunction disp("Amperes",Ro*sqrt(2),"Maximum current value")
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function xout=jacobi(A,b) [l,c]=size(A); D=diag(diag(A)); L=-1*(D-tril(A)); U=-1*(D-triu(A)); invD=diag(diag(1/D)); x=zeros(l,1); oldx=x; M=D N=-(L+U) MN=-inv(D)*(L+U) for i=1:1000 if (max(abs(x-oldx))<0.001) then xout=x; else oldx=x; x=inv(D)*b-inv(D)...
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//Determine (a) the overall voltage-gain ratio Av = vL=vs, and (b) the overall current-gain ratio Ai = iL=is. //Example 6.26 page no 193 clear clc hfe=100 Rl=3*10^3 //kΩ Rc=3*10^3 //kΩ hie=1*10^3 Av2=-((hfe*Rl*Rc)/(hie*(Rl+Rc))) printf("\n The value of Av2=%0.3f " ,Av2) Rc1=10*10^3 ...
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//find smaller of 2 numbers clc; clear; x=2; y=5; //dummy values if x<y then x else y end
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//Calculate the slope of the S-L (solid -liquid )Curve //Example 6.5 clc; clear; Tf=273.15; //Phase transition temperature (two phase can coexist in equilibrium)in K delfusHbar=6.01*1000*9.87*10^-3; //Change in Enthalpy in L atm mol^-1 (1 J=9.87*10^-3 L atm) Vbarl=0.0180; //Molar volume of liquid w...
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Name=Quake LG 1v1 Rockets PlayerCharacters=Quaker BotCharacters=Quaker Bot.bot IsChallenge=true Timelimit=90.0 PlayerProfile=Quaker AddedBots=Quaker Bot.bot PlayerMaxLives=0 BotMaxLives=0 PlayerTeam=2 BotTeams=1 MapName=Classic.map MapScale=3.8 BlockProjectilePredictors=true BlockCheats=true InvinciblePlayer=true Invin...
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clc //Initialization of variables g=9.81 //m/s^2 rho=10^3 //kg/m^3 Vr=10 //m/s u=8.5 //m/s A=250/10^4 //m^2 //calculations V=Vr-u Q=A*Vr R=rho*Q*V P=R*u eth=1/(1+ V/(2*u)) //results printf("Power required = %.3f kW",P/1000) printf("\n Efficiency of jet propulsion = %.2f percent",eth*100)
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//Example 2-26,Page No - 82 clear clc Vpeak =3 f=48*10^3 fifth_harmonic = 5*f Vrms=(4/3.14)*(3/5)*0.707 printf('The frequency of the fifth harmonic is %.1f Khz',fifth_harmonic/10^3) printf('\n The RMS voltage of the fifth harmonic is %.2f',Vrms)
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//chapter 10 Ex 21 clc; clear; close; red=10/100; original=100; newSal=original*(1-red); increase=((original-newSal)/newSal)*100; mprintf("The percentage reduction is %.2f percent",increase);
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numBits = 10; // numero de bits para cada parametro minBound = 0; // menor valor que um parametro pode assumir maxBound = 20; // maior valor que um parametro pode assumir popSize = 30; // tamanho da população nGenerations = 100; // numero de gerações nSamples = 100; //...
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// generate sin signal function result = sin_signal(Fs, time, freqency, amplitude) samples = time * Fs step_size = (2 * %pi * freqency) / samples x = [0:samples-1] * step_size result = amplitude * sin(x) endfunction // generate cos signal function result = cos_signal(Fs, time, freqency, amplitude) ...
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// Example 15_13 clc;funcprot(0); // Given data T=25+273.15;// K n_C=1;// The stoichiometric coefficient of the reaction n_H2=2;// The stoichiometric coefficient of the reaction n_CH4=1;// The stoichiometric coefficient of the reaction sbar0_CH4=186.256;// kJ/kgmole.K sbar0_C=5.740;// kJ/kgmole.K sbar0_H2=130....
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clear; clc; funcprot(0); // Example - 2.17 // Page number - 70 printf("Example - 2.17 and Page number - 70\n\n"); //Given T = 310.93;//[K] - Temperature P = 2.76*10^(6);//[N/m^(2)] - Pressure R = 8.314;//[J/mol*K] - Universal gas constant y1 = 0.8942;// Mole fraction of component 1 (methane) y2 = 1-y1;//...
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function f=funcx(x) f=100*((x(2) - x(1).^2).^2) + (x(1) - 1).^2; endfunction function g=grad(x) g=[-400*x(1)*(x(2) - x(1).^2) + 2*(x(1) - 1);200 * (x(2) - x(1).^2)]; endfunction x = [4;4]; alpha= 0.0001; ep = 0.00000001; d=1; t=0; while(d > ep) g = grad(x) xnew = x - alpha* grad(x); t...
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// Exa 3.4 clc; clear; close; // Given data R = 0.29;// in kJ/kg-K R = R * 10^3;// in J/kg-K C_p = 1.005;// in kJ/kg-K T = 185;// in degree C T = T + 273;// in K T2 = 70+273;// in K V1 = 0.23;// in m^3 P = 500;// in kN/m^2 P = P * 10^3;// in N/m^2 m = (P*V1)/(R*T);// in kg Q = m*C_p*(T2-T);// in kJ disp...
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clear(); // Limpas as variaveis do Espaço clc(); // Limpa o console // Recebendo os dados x1 = input("Digite o valor da x1:"); //= 2 y1 = input("Digite o valor de y1:"); //= 3 z1 = input("Digite o valor de z1:"); //= 4 x2 = input("Digite o valor de x2:"); //= 5 y2 = input("Digite o valor de y2:"); //= 6 z2 = input("D...
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// to calculate flux/pole clc; S=42; p=2; ph=3; m=S/(p*ph); //slots/pole/phase g=180*p/S; //slots angle K_b=sind(m*g/2)/(m*sind(g/2)); //breadth factor cp=17; pp=S/p; theta_sp=(pp-cp)*g; //short pitch angle K_p=cosd(theta_sp/2); N_ph=S*2/(ph*p*2); //2 parallel paths E_p=2300/sqrt(3); ...
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//EXAMPLE -3.31 PG NO -193 Zr=3333.33; Vry=200; X=16666.66; Y=346.40; //Y=(300-j173.2) I=Y/X; R.V=I*Zr; disp('i) I = '+string (I)+'<-29.99 A'); disp('ii) READING OF VOLTMETER = '+string (R.V)+' <-30 degree V');
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// sum 29-2 clc; clear; //Let reverse speed gear be RSG RSG=5.5; //Let T5/T6 = Z1 T1=2; //Let T3/T7 = Z2 Z2=2.75; T7=18; T3=Z2*T7; T3=50; //Let T3/T1 =Z3 Z3=2.5; T1=T3/Z3; //Let T4/T2 = Z4 Z4=2.25/2; T2=(T1+T3)/(Z4+1); T4=T1+T3-T2; //Let T5/T6=Z5 Z5=2; T6=(T1+T3)/3; T5=(T1+T3)-T6; T7=18; //let f...
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clc clear //Input data M=2 //Mach number h=20 //Altitude in km Tc=-56 //Ambient temperature in degree Centigrade Ta=-56+273 //Ambient temperature in K k=1.4 //Adiabatic constant R=287 //Specific gas constant in J/kg-k Cp=1005 //Specific heat capacity at constant pressure in J/kg-K //Calculation a=sqrt(k*...
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//Ex10.2.8.5;heat transfer rate would be involved under these circumstances del_G_at25degree_celcius=-195500;//unit=cal/gm mole del_H_at25degree_celcius=-212800;//unit=cal/gm mole F=(96500/4.184);//since F=96500 coulombs/gm-mole n=8 E_at25degree_celcius=-del_G_at25degree_celcius/(n*F);//Joules/coulomb printf(" ...
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function [stk,txt,top]=sci_qz() // Copyright INRIA txt=[] if lhs==1 then stk=list('gschur('+stk(top-1)(1)+','+stk(top)(1)+')','0','?','?','1') else stk=list() s=list('gschur('+stk(top-1)(1)+','+stk(top)(1)+')','-1','?','?','1') if lhs==5 then [AA, BB, Q, Z, V]=lhsvarsnames() txt=[txt;lhsargs([AA, BB, Q...
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funcprot(0) test_cases = list() test_cases($+1) = struct('input', struct('munten', [], 'doel', 0), 'output', struct('mogelijk', %t)) test_cases($+1) = struct('input', struct('munten', [], 'doel', 1), 'output', struct('mogelijk', %f)) test_cases($+1) = struct('input', struct('munten', [1], 'doel', 1), 'output', struct('...
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x=[2.30256624769934; 2.29071803023829; 2.26283604900314; 2.35145015316178; 2.27686291358213; 2.29805616201205; 2.32805830340568; 2.30878734371402; 2.29343801980763; 2.23019030245799*%i]; fs=4e6; t=(1/fs); [F,LT,UT,LL]=falltime(x); disp(F); disp(LT); disp(UT); disp(LL); ////output //!--error 202 //min: Wrong type for a...
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Name=Happy Halloween PlayerCharacters=HH Player BotCharacters=HH Target L.bot;HH Target R.bot;HH Target B.bot IsChallenge=true Timelimit=30.0 PlayerProfile=HH Player AddedBots=HH Target L.bot;HH Target R.bot;HH Target B.bot PlayerMaxLives=0 BotMaxLives=0;0;0 PlayerTeam=1 BotTeams=2;2;2 MapName=happy_hallowee...
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// Scilab Code Ex3.4 : Page-3.7 (2010) clc;clear; a = 0.27e-9; // Lattice constant for BCC, metre c = 0.494e-9; // Height of the unit cell, metre M = 65.37; // Atomic weight of zn, kg N = 6.02e+26; // Avogadro number per k mol m = 6*M/N; // Mass per unit cell in HCP structure, kg V = 3*sqrt(3)*a^2*c/2; ...
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PL/SQL Developer Test script 3.0 9 -- Created on 27.04.2018 by V.ZHURAVOV declare -- Local variables here i integer; begin --dbms_session.reset_package; return; -- Test statements here pdb_daemon_api.start_daemon; end; 0 0
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x = input("Give the square side length: ") area = x^2 perimeter = 4*x diagonal = sqrt(2)*x printf("The area is %2.2f\n The perimeter is %2.2f\n The diagonal is %2.2f",area,perimeter,diagonal)
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// funcao function y=f(x) y = x^6 - 3*x^5 + 30*x + 1 endfunction // gráfico x=-2:0.1:2 plot(x,f(x),'r.-'); xgrid // numero de pontos fixos e' quantas vezes passa pelo zero // raizes reais no caso x = 2 // chute for n=1:10 x=-1/(x^2 - x -2) disp ( x ) end
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//acids and bases// //example 2.15// M1=0.2;//molarity of acetic acid// M2=0.2;//molarity of sodium acetate// K=1.8*10^-5; pH=-log10(K)+log10(M2/M1);//by using Henderson's equation// printf("The pH value of buffer solution is %f",pH);
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sigma_cc=4//in MPa sigma_sc=130//in MPa Asc=6*0.785*12^2//six 12 mm dia bars, in sq mm D=200//dia of column, in mm Ag=0.785*D^2//in sq mm Ac=Ag-Asc//in sq mm P=sigma_cc*Ac+sigma_sc*Asc//in N dia=6//dia of links used, in mm //spacing of links s1=D//in mm s2=16*12//in mm s3=48*dia//in mm s=min(s1,s2,s3) mpri...
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//example3.5 clc disp("The given values are, R1=2.5 ohm, R2=0.01 ohm") k=400/6600 disp(k,"K=400/6600=") disp("While finding eqivalent resistance referred to primary, transfer R2 to primary as R2'',") r=0.01/((0.0606)^2) disp(r,"R2''(in ohm)=R2/K^2=") r=2.5+2.7225 format(7) disp(r,"Therefore, (R_1e)[in ohm]=R1...
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clear L = 10; EI=100; function u = bendingUnderForces(xf) u = xf(:,1); R = -sum(xf(:,2)); M = xf(:,1)'*xf(:,2); endfunction bendingUnderForces([.. 1, 10;.. 2, 20;.. 3, 30;.. ])
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clc //initialisation of variables h= 28 //ft g= 32.2 //ft/sec^2 v1= 45.4 //ft/sec A= 45 //degrees Q= 1700 //ft^3/sec w= 6.24 //lb/ft^3 c= 0.65 a= 60 //ft^2 r1= 10 //in r2= 5 //in //CALCULATIONS V= v1-(Q/(w*a*c*tand(A))) e= h*g*100/(V*v1) a1= atand(Q*2/(v1*w*a*c*tand(A))) w= sqrt(2*g*h*144/(r1^2-r2^2))...
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clear; clc; //Example 5.7 //Caption : Program to Find the Maximum Work obtained in a Steady state Flow //To find Approx Value function[A]=approx(V,n) A=round(V*10^n)/10^n;//V-Value n-To what place funcprot(0) endfunction function[Q]=ICPH(T0,T,A,B,C,D) t=T/T0; Q=(A+((B/2)*T0*(t+1))+((C/3)...
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function [Slmin]=minss(Sl,tol) [lhs,rhs]=argn(0) if Sl(1)<>'lss' then error(91,1),end select rhs case 1 then tol=[] case 2 then tol=tol else error('1 or 2 inputs: sl [,tol]') end; [a,b,c,d,x0,dom]=Sl(2:7) // if tol<>[] then [nc,u1]=contr(a',c',tol) else [nc,u1]=contr(a',c') end u=u1(:,1:nc) c=c*u;a=u...
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clear; clc; R=.11; L=1.5; c=.01; l=150; P=50; V=complex(72128.8,0); z=complex(.11,.471); Y=complex(0,(3.14*10^(-6))); Zc=complex(389.9,-44.925) gama=sqrt(Y*z); Ir=complex(230.94,-173.21); a=gama*l; sine=complex(.0148,.179); cosi=complex(.9838,.0027); Vs=(V*cosi)+(Zc*sine*Ir); mprintf("sending end volta...
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clear // // // //Variable declaration T=1500; //temperature(K) lamda=5500; //wavelength(m) lamda_m=20000; //wavelength(m) //Calculations T_dash=lamda_m*T/lamda; //temperature of sun(K) //Result printf("\n temperature is %0.0f K",T_dash)
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clc // Fundamental of Electric Circuit // Charles K. Alexander and Matthew N.O Sadiku // Mc Graw Hill of New York // 5th Edition // Part 1 : DC Circuits // Chapter 3: Methods of Analysis // Example 3 - 9 clear; clc; close; // // Given data // Diagonal term of R R11 = 9.00; ...
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clc;clear; //Example 4.12 //given dara mi=50; T1i=80;//suffix i for iron Vw=0.5; T1w=25;//suffix w for water v=0.001;//specific volume of liquid water at or about room temperature //from Table A–3 ci=0.45; cw=4.18; //calculations mw=Vw/v; //Ein - Eout = Esystem // du = 0 i.e (mcdT)iron + (mcdT)water...
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interpolationLagrange.sce
function y0 = lagrange_interp(x, y, x0) /*x é a entrada obeservada. y são os pontos medidos. x0 ponto a ser interpolado % y0 o valor interpolado */ y0 = 0; n = length(x); for j = 1 : n t = 1; for i = 1 : n if i~=j t = t * (x0-x(i))/(x(j)-x(i)); end end y0 = y0 + t*y(j); end ...
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// @ metodo Davidon-Fletcher-Powell (DFP) @ global d; global x; x = [-5,-5]; global lamb; lamb = 1 ; global N ; N = 2 ; global p ; global q ; function z =f(x) z = ((x(1)-5)^2 +(x(2)-350)^4) ; endfunction function dfdx = derivadaParcial_x(x) h = 1e-6 ; h2 = [h, 0] ; dfdx = (f(x+h2)-f(x))...
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function str=mtlb_is(sto,sfrom,i,j) //emulate the matlab syntax sto(i [,j])=sfrom for strings [lhs,rhs]=argn() [mto,nto]=size(sto) // convert sto to a regular matrix if type(sto)==10 then if nto<>1 then error('First argument is not a Matlab vector of strings'),end if mto==1 then lnto=length(sto) sto=ascii(...
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// ::::::::::::::::::::::::::::::::::::::::: // :: :: // :: Question 5. Cholesky, exemple :: // :: :: // ::::::::::::::::::::::::::::::::::::::::: funcprot(0); exec("Q3_Factorisation_Cholesky.sce"); exec("Q4_Descente_Cholesky.sce"); exec("Q5_...
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clear;close;clc; disp('Please enter the matrix A'); //Taking input of Matrix A a11=input("Enter a11: "); a12=input("Enter a12: "); a13=input("Enter a13: "); a21=input("Enter a21: "); a22=input("Enter a22: "); a23=input("Enter a23: "); a31=input("Enter a31: "); a32=input("Enter a32: "); a33=input("Enter a33: ...
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clc clear x=8 z=25 pop=20 iter=200000 a=zeros(pop,z) rag=zeros(iter) rag=zeros(iter) cap=[288 95 115 133 107 22 34 28 186 190 33 56 100 90 82 143 68 166 44 73 72 60 68 8 20 ] tim=[0 12 6.2 5.6 27 17 20 29 44 18 16 23 24 34 11 9 11 11 13 17 14 30 25 28 27; 12 0 5.2 9.9 39 29 32 40 52 29 27 34 36 46 23 20 23 15 18 24 21 ...
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//Variable declaration F_500=1*10**-10 T1=500+273 T2=1000+273 //Calculations lnx=log(F_500)*T1/T2; x=exp(lnx) printf('Fraction of vacancies at 1000 degrees C =%0.3f *10**-7\n',(x*10**7))
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syms s; x=ilaplace((2*s+3)/((s^2+4*s+5)*(s+1))); disp (x);
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// Problem no 6.8,Page No.159 clc;clear; close; L=6 //m //Length of beam d=0.15 //m //diameter y_max=1.035*10**-2 //m //Deflection E=210*10**9 //Calculations I=%pi*64**-1*d**4 //M.I of Beam W=y_max*48*E*(L**3)**-1 //Point Load theta_A=3*y_max*L**-1 theta_B=-theta_A //Result printf("The Heaviest central Point Load...
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load Add.hack, output-file Add.out, compare-to Add.cmp, output-list RAM[0]%D2.6.2; repeat 50 { ticktock; } output;
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// sum 24-4 clc; clear; sigut=1770; Pb=0.0018*sigut; W=4000; a=2.5/2; Ws=90*0.5; Wa=(W+Ws)*a/9.81; Weff=W+Wa; d=sqrt(Weff*2/(23*Pb)); d=12; // printing data in scilab o/p window printf("d is %0.0f mm ",d);
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//page no 224 //example no 7.5 // INCREMENT A NUMBER. clc; disp('LXI B,2050H'); //loads the data 2050H in BC register pair. disp('B=20H C=50H'); B=20; C=50; disp('INX B'); C=C+1; printf('B= %d C= %d \n',B,C); disp('The contents of BC register pair will be 2051H'); disp('INR B'); B=B+1; printf('B= %d \n'...
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clc clear printf("Example 10.12 | Page number 361 \n\n"); //Find the work and heat interactions during the expansion process //Given data m =0.1 //kg p1 = 10 //bar p2 = 1 //bar //Solution //From saturated steam table v1 = 0.1944 //m^3/kg v2 = (p1/p2)^(1/1.3)*v1 //m^3/kg W = m*(p1*v1-p2*v2)*100/(1.3-1) //kJ...
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// **** Purpose **** // It generates the full space sites and their surrounding sites which // helps you generate a Hamiltoian in real space // **** Variables **** // [surr_site]: total_nb x 9 x total_sublatt , real // <= variable generated by PIL_uc_nb // [r_mesh]: 1x3, integer // <= how many unntcell along each pr...
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//Chapter-1, Illustration 11, Page 24 //Title: Fuels and Combustion //============================================================================= clc clear //INPUT DATA H2=0.5;//Percentage composition of H2 by volume CO2=0.1;//Percentage composition of CO2 by volume CO=0.05;//Percentage composition of CO by...
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// Initilization of variables W=10 // N // Weight of the ball // Calculations // consider the eq'n derived to find the reaction, given as R=W*(1+((2*%pi^2)/9)) // N // Results clc printf('The value of the reaction is %f N \n',R)
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//chapter 3 //example 3.1 //page 70 clear; clc ; //given alphadc=0.98; //common base current gain factor Icbo=5 ; //collector to base leakage current Ib=100; ...
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disp('chapter 6 ex6.7') disp('given') disp("design a instrument amplifier circuit ") disp("overall gain=900") Av=900 disp("i/p signal amplitude=15mV") Vi=0.015 disp("Supply voltage=15") Vcc=15 disp("For stage 1") disp("Äv1=Av2") Av1=sqrt(Av) Av2=Av1 disp(Av1,"Av1=Av2=") disp("I2>>Ibmax") disp("Ibmax=500...
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//AC Circuits:example 4.2:(pg4.4) f=50; Im=100; i1=86.6; t=(1/600); pi=3.14; disp("f=50 c/s"); disp("Im=100 A"); // part(a) disp("i=Im*sin(2*pi*f*t)"); i=Im*sin(2*pi*f*t); printf("i=%.f A",i); // part (b) disp("i=Im*sin(2*pi*f*t1)"); t1=(asind(i1/Im)/(2*pi*f)); printf("t1=%.e second",t1);
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clc; clear all; disp("heat transfer coefficient") m=1800/3600;// kg/s d=8/1000;//m ts=24;// degree C tsat=45.8;// degree C rhov=0.0676;// kg/m^3 hf=2393*10^(3);// J/kg rhol=993.95;// kg/m^3 k=62.53*10^(-2);// W/m.C mu=728.15*10^(-6);// kg/m.s n=400; N=n^0.5; h=0.725*(rhol*(rhol-rhov)*k^3*g*hfg/(N*mul*(tsa...
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//To find the number of pulses counted //example5-5 in page 131 clc; //data given Vr=1.25;//peak voltage of ramp in volts tr=125e-3;//time period of the ramp=1.25 ms T=1/(1e+6);// frequency =1 Mhz and time period of the clock pulses is 1/f for Vi=0.75:(0.9-0.75):0.9,// analog input voltages for which clock pulse...
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Ex5_9.sce
clc clear //DATA GIVEN T1=400+273; //temp. in K T2=T1; T3=40+273; //temp. in K T4=T3; W=130; //work produced in kJ ETAth=(T1-T3)/T1; //Engine thermal efficiency //ETAth=Work done/Heat added Ha=W/ETAth; //Heat added in kJ Hr=Ha-W; ...
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ex5_1.sce
//Find voltage at sending end, percentage regulation and transmission efficiency clear; clc; //soltion //given P=3300;//kW//power Vr=33000;//kV//recieving voltage pf=0.8;//peak factor R=2;//ohm//resistance X=3;//ohm//loop reactance I=P*1000/(Vr*pf); Vs=sqrt((Vr*pf+I*R)^2+((Vr*sind(acosd(pf)))+I*X)^2); print...
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example9_12.sce
//Chapter 9 //Example 9_12 //Page 225 clear;clc; r=1.25/2; d=200; e0=8.854*1e-12; c=2*%pi*e0/log(d/r); printf("Capacitance of the line = %.4f uF/km \n", c*1e9);
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eg9_5a.sce
x= [60 62 64 65 66 67 68 70 72 74]; y= [63.6 65.2 66 65.5 66.9 67.1 67.4 68.3 70.1 70]; xbar = mean(x); ybar= mean(y); n= 10; SxY = 0; for i= 1:n SxY = SxY + (x(i)*y(i)) - (xbar*ybar); end Sxx = 0; for i=1:n Sxx= Sxx + (x(i)*x(i)) - (xbar*xbar); end SYY = 0; for i=1:n SYY = SYY + (y(i)*y(...
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example8_5.sce
//exapple 8.4 clc; funcprot(0); // Initialization of Variable t=60*0.3/0.5;//time of 1 revollution d=34/1000000; S=6/d; e=0.415; J=0.154; P=34.8*1000; mu=1.17/1000; L=2.35/1000; rho=999;//density of water rhos=4430;//density of barium carbonate //calculation //part1 nu=J*rho/((1-J)*(1-e)*rhos-J*e*rh...
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//To calculate the current through each resistor,the voltage across each resistor and the voltage at each node of the circuit. clc; R_1=25 R_2=10 R_3=15 R_4=50 R_5=25 R_6=100 R_7=500 R_8=125 //Given resistances in kilo-ohm. Req_123=R_1+R_2+R_3 //Equivalent of(R_1,R_...
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ex_16_6.sce
//Example 16.6 //energy of photoelectrons emitted clc; clear; //given data : h=6.62D-34;// plank's constant in joules-sec c=3D8;//speed of ight lamda=6D-7;// Threshlod wavelength in m v=6D14;// frequency in Hz E=h*(v-c/lamda);// energy in joules E=E/1.6D-19;// to convert in eV disp(E,"energy of electrons emi...
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!SADDR 5555 15 10000.000.00 52 !SDATA 2F 15 10000.000.00 52 !M2716 6E 1 7 Address line fault 0.00 10000.0011 !M2716 6E 2 15Address line fault 10000.000.00 52 !M2716 6E 3 15 ...
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UNA:+.? 'UNB+UNOC:2+STUB+BLA+960209:0843+72'UNH+0000090001+ORDERS:D:93A:UN:EAN00 7'BGM+220+B00404'DTM+137:19960209:102'NAD+BY+++STADT- UND UNIVERSITAETSBIBLIOTHE K:FRANKFURT+BOCKENHEIMER LANDSTR. 134-138+FRANKFURT+++DE'RFF+API:DE114110388'RFF +IT:STUB'NAD+SU+++B.H.BLACKWELL'CUX+2:GBP:9'LIN+1'PIA+5+0471949086:IB'QTY+21:...
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EX5_15.sce
// Exa 5.15 format('v',6) clc; clear; close; // Given data k= 0.05;// in mA/V^2 V_T= 1;// in V V_DD= 6;// in V R_S= 9.1;//in kΩ //V_GS= V_DD-I_D*R_S //I_D= k*(V_DD-I_D*R_S)^2 //I_D^2*R_S^2-I_D*(2*V_DD*R_S+1/k)+V_DD^2 A= R_S^2;// assumed B=-(2*V_DD*R_S+1/k);// assumed C= V_DD^2;// assumed I_D= [A B C]; ...
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20_lab_rabota.sce
clc; f=figure(); set(f,'position',[200,20,400,400]); set(f,'figure_name','Лабораторная работа №20'); set(f,'BackgroundColor',[0,1,1]); button1=uicontrol(f,'style','pushbutton','string','Закрыть приложение.','position',[200,10,150,30],'CallBack','a1'); function a1 close(f); endfunction a=0; while (a==0) Str1=uico...
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U2_C6_2.sce
//variable initialization x=0:.001:(1/3); y=0:.001:(1/3); x0=0; x1=1/3; y0=0; y1=1/3; p=4*integrate('(sin(%pi*x))^2','x',x0,x1)*integrate('(sin(%pi*y))^2','y',y0,y1); printf("The required probability = %.2f",p);
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Ex11_3.sce
//Example 11.3, page 410 clc h=6.6*10^-34//in J-s v=1*10^7//per sec K=1.4*10^-23//in J-K T=300//in K n=exp(-((h*v)/(K*T))) printf("\n The Boltzan factor is %e Tesla",1-n)
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Ex16_4.sce
// Calculation of hysteresis loss clc v = 0.01 // volume in m^3 x = 1e-4 // axis intercept y = 1e2 // axis intercept a = 60000 // Hysteresis loop area f = 50 // frequency in Hz printf("\n Example 16.4") e = x*y*a // Energy loss in one loop E = e*v // energy loss in core in one cycle P = E*f // Power loss pri...
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Ex12_9.sce
//Example number 12.9, Page number 266 clc;clear; close; //Variable declaration n2=1.3; //Cladding refractive index delta=0.140; //fractional index change //Calculation n1=n2/(1-delta); //Core refractive index //Result printf("refractive index of core is %.2f",n1)
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clc// // // //Variable declaration m=9.1*10^-31; //mass of electron(kg) h=6.626*10^-34; //planck's constant lamda=1.66*10^-10; //wavelength(m) //Calculation v=h/(m*lamda); //velocity(m/s) KE=(1/2)*m*v^2; //kinetic energy(eV) //Result printf("\n velocity is %0.0f km/s",v/10^3) printf("\...
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getMatrix(1) = [[1,-2,2],[2,-1,2],[2,-2,3]] getMatrix(2) = [[1,2,2],[2,1,2],[2,2,3]] getMatrix(3) = [[-1,2,2],[-2,1,2],[-2,2,3]]
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///Chapter No 11 Steam Boilers ////Example 11.14 Page No 245 ///Find Theoretical draught in millimeters of water //Input data clc; clear; H=24; //Chimney height in m Ta=25+273; //Ambient temperature in degree celsius Tg=300+273; //Temperature of fuel gases in degree celsius ma=20; ...
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Ex13_3.sce
//Ex13_3 clc Rf = 1.5*10^6//feeback resistance Cf = 1*10^-9//capacitance across feedback f0 = 1/(2*%pi*Rf*Cf)//frequency of oscillation disp("Rf = "+string(Rf)+"ohm") disp("Cf = "+string(Cf)+"F") disp("f0 = 1/(2*pi*Rf*Cf) = "+string(f0)+"Hz")