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function [d]=girth(g) [lhs,rhs]=argn(0) if rhs<>1 then error(39), end // check g if g('directed')<>1 then error('The graph must be directed') end // girth of graph g (length of the shortest cycle) [p,r] = circuit(g); if p==[] then d=0 end l=size(p,2); d=l; ta=g('tail');he=g('head'); n=g('node_number'); X=sparse(...
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clc; //page 113 Mo=24;//N.m *k, Couple of moment f=-400;//N, Magnitude of force OB=300;//mm,Distance of force from point O theta=60;// degree, angle made by lever with +ve X axis x=cosd(theta) BC=Mo/(-f*x);//m BC=BC*1000;//mm, Conversion into millimeter disp(BC) OC=OB+BC;//mm, Distance from the shaft to the...
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// Scilab Code Ex6.8: Page-199 (2006) clc; clear; k = 1.38e-023; // Boltzmann constant, J/mol/K e = 1.6e-019; // Energy equivalent of 1 eV, J/eV T = [385 455 556 714]; // Temperatures of Ge, K rho = [0.028 0.0061 0.0013 0.000274]; // Electrical resistivity, ohm-m Tinv = zeros(4); // Create an empty r...
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clc //initialisation of variables F=35.5*10^4//N p=100*10^5//bars q=%pi//ft //CALCULATIONS D=sqrt((4*F)/(q*p))*1000//mm //RESULTS printf('The cylinder size is =% f mm',D)
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// s : 2014.06.22 // 14.09.07 Objjoin added function Out=Objpolygon(varargin) global OBJFIGNO OBJJOIN Eps=10^(-6); Args=varargin; Nargs=length(Args); Tmp=Args(1); PtL=Flattenlist(Tmp); PL=list(); for J=1:length(PtL) Tmp=PtL(J); for K=1:size(Tmp,1) PL=lstcat(PL,list(Tmp(K,:))) end; ...
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clc; m=0.8; //mass of water in kg c=4185; //specific heat in J/kg.celcius delT=100-20; //change in temperature in celcius Q=m*c*delT; //calculating heat required in Joule P=10^3; //Power in J/sec t=Q/P; //calculating time using P=(Q/t) disp(t,"Time required to raise temperature to 100 degree c...
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//Example 16.9. //Negative Clamping circuit //let input voltage be V_in=V_p_in*sin(2*%pi*f*t) V_p_in=12; V_DC=-(V_p_in); //DC level added to output disp(V_DC,'V_DC in volts= ') for n=0:1:1 t=n/2:0.0005:(n+1)/2; V_in=V_p_in*sin(2*%pi*t); Vout=V_DC+V_in; plot(t,Vout) end xtitle('Negative cl...
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//Example 7.68a //Z transform of x[n]=u[n] clc; syms n z; x=1; X=symsum(x*(z^-n),n,0,%inf);
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//Example 2.7.4.c://standard deviation clc; clear; format('v',7) n=8 q=[10.3,10.7,10.9,9.7,9.5,9.2,10.3,11.7];// AM= mean(q);//arithematic mean in mm for i= 1:8 qb(i)= q(i)-AM; end Q= [qb(1),qb(2),qb(3),qb(4),qb(5),qb(6),qb(7),qb(8)];// AV=(-qb(1)+qb(2)+qb(3)-qb(4)-qb(5)-qb(6)-qb(7)+qb(8))/n;// SD=stdev(Q);//stan...
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//Variable declaration: m = 1 //Mass flowrate (lb) cP = 1 //Heat capacity (Btu/lb. F) //From figure 21.3: T1 = 300 //Temperature of hot fluid leaving exchanger ( F) T2 = 540 //Temperature of hot fluid entering exchanger ( F...
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clc; clear; close; disp('The given matrix is') a=[4 5 9 -2;6 5 1 12;3 4 8 -3] a(2,:)=a(2,:)-(a(2,1)/a(1,1))*a(1,:) a(3,:)=a(3,:)-(a(3,1)/a(1,1))*a(1,:) disp(a) a(3,:)=a(3,:)-(a(3,2)/a(2,2))*a(2,:) disp(a) a(1,:)=a(1,:)/a(1,1) a(2,:)=a(2,:)/a(2,2) disp(a) for i=1:3 for j=1:4 if(a(i,j)<>0) ...
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clc// // // //Variable declaration n1=1.48; //refractive index of core n2=1.45; //refractive index of cladding //Calculation NA=sqrt(n1^2-n2^2); //numerical aperture alpha_i=asin(NA); //angle of acceptance(radian) alpha_i=(alpha_i*180/%pi); //angle(degrees) alpha_id=int(alpha_i); alpha...
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//ques-18.1 //Calculating heat of formation of ethyl alcohol clc h1=-333;//heat of combustion of ethyl alcohol (in kcal) h2=-94.3;//heat of formation of carbon dioxide (in kcal) h3=-68.5;//heat of formation of water (in kcal) H=2*h2+3*h3-h1;//heat of formation of ethyl alcohol (in kcal) printf("Heat of formation...
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//caption:determine_transfer_function,Wn,zeta //example 6.10.10 //page 179 //J=moment of inertia,f=C,Ke=error detector gain,Wn=natural frequency, zeta=damping ratio,Km=torque constant syms J f s Ke=5.73; Km=0.045; n=sym('N1/N2') n=subs(n,'N1/N2',1/10); J=0.25*float(n^2);//referred to motor side f=1*float(n^2)...
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//Example 5.9 clc;clear;close; format('v',7); C=4000;//MW f=50;//Hz L=C;//MW//Load R=2.5;//%////Speed regulation constant H=5;//sec////Inertia constant delPL=1;//%////change in load delf=1;//%////change in frequency disp("Part(a)"); Ls=80;//MW;//increase in step to load R=R/100*f;//z/p.u.MW D=delPL/delf*L/...
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//Chemical Engineering Thermodynamics //Chapter 1 //Introduction //Example 1.1 clear; clc; //Given m = 100;//m is the mass of the object in kg a = 10;//a is the acceeleration due to gravity in m/s^2 //To determine the force exerted F = m*a;//F is the force exerted by the object in kg mprintf('Force ex...
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@relation vowel @attribute TT integer[0,1] @attribute SpeakerNumber integer[0,14] @attribute Sex integer[0,1] @attribute F0 real[-5.211,-0.941] @attribute F1 real[-1.274,5.074] @attribute F2 real[-2.487,1.431] @attribute F3 real[-1.409,2.377] @attribute F4 real[-2.127,1.831] @attribute F5 real[-0.836,2.327] @attribute...
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// PG (610) w = [1/3 2/3 2/3]' w1 = w(1,1) w2 = w(2,1) w3 = w(3,1) U = [1-2*abs(w1)^2 -2*w1*w2' -2*w1*w3';-2*w1'*w2 1-2*abs(w2)^2 -2*w2*w3';-2*w1'*w3 -2*w2'*w3 1-2*abs(w3)^2] U inv(U) // U = inv(U)------Hence, U is Hermitian U*U // U*U = I---------Hence, U is orthogonal
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clc clear //input data Nm=1000//Speed of the model in rpm Hm=8//Head of the model in m Pm=30//Power of the model in kW Hp=25//Head of the prototype in m DmDp=1/5//The scale of the model to original //calculations Np=((Hp/Hm)^(1/2))*(DmDp)*(Nm)//Speed of the prototype in rpm Pp=(Pm)*((1/DmDp)^(5))*(Np/Nm)^(3...
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//Given that D = 1.5 //times wavelength //Sample Problem 18-3a printf("**Sample Problem 18-3a**\n") deltaL = 0 printf("Waves undergo constructive interference at P1\n") //Sample Problem 18-3b printf("\n**Sample Problem 18-3b**\n") deltaL = D deltaPhi = 1.5*2*%pi if modulo((deltaPhi/%pi), 2)==0 then ...
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//example 7 // power generation by steam turbine clear clc P1= 2 //initial pressure of steam in MPa T1= 400 //initial temp. of steam in °C V1= 50 //initial velocity of steam in m/s z1= 10 //height of inlet in metres h1=3248.4 //initial specific enthalpy of air in kJ/kg P2= 15 //final pressure of air in kPa V...
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//Example 7.9 clc; clear; close; //given data : f=50;//Hz l=175;//km r=1/2;//cm d=3*100;//cm g0=21.1;//kV/cm(rms) m0=0.85;//irregularity factor mv=0.72;//roughness factor mv_dash=0.82;//roughness factor b=74;//cm t=26;//degree C Vph=110/sqrt(3);//kV del=3.92*b/(273+t);//air density factor Vd0=g0*del*m0...
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function r=%rds(r,m) // r=r./m //! if size(m,'*')==0 then r=[],return,end r(3)=r(3).*m r(2)=r(2).*ones(m)
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//Chapter 23, Example 23.16 clc ////Initialisation x="11010" //binary number to be convert //Calculation x1=bin2dec(x) //conversion to decimal //Results printf("Decimal of 11010 = %d",x1)
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//Finding of convective acceleration //Given v1=2.5; v2=16; s=3.75; //To Find a=(v2-v1)/s; a1=v1*a; a2=v2*a; disp("Acceleration at inlet="+string(a1)+" m/s^2"); disp("Acceleration at outlet="+string(a2)+" m/s^2");
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//clc() Vgas = 0.09;//m^3 Vliq = 0.01;//m^3 SVliq = 1.061*10^-3;//m^3/kg SVvap = 0.8857;//m^3/kg mvap = Vgas / SVvap; mliq = Vliq / SVliq; Ul = 504.5;//kJ/kg Ug = 2529.5;//kJ/kg U1 = Ul * mliq + Ug * mvap; SVtotal = (Vgas + Vliq)/(mvap + mliq); //using steam table , these value of specific volume corresponds...
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clc; p1=150; p2=200; p3=250; p4=300; p5=350; p6=400; p7=450; p8=500; p9=550; p10=600; p11=650; p12=700; p13=750; p14=800; p15=850; p16=900; // Pressures of merect's boiler experiment in kPa t1=111.4; t2=120.2; t3=127.4; t4=133.6; t5=138.9; t6=143.6; t7=147.9; t8=151.9; t9=155.5; t10=158.9; t11=162; t12=165; t13=16...
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clear; clc; disp('Example 10.4'); // aim : To determine the // (a) Heat transfer in the boiler // (b) Heat transfer in the superheater // (c) Gas used // given values P = 100;// boiler operating pressure, [bar] Tf = 256;// feed water temperature, [C] x = .9;// steam dryness fraction. Th = 450;// su...
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clear //Initialization i=5 //current in ampere l=0.628 //circumference //Calculation h=i/l //magnetic field strength //Results printf("\n Magnetic Field Strength, H = %.2f A/m",h)
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clc //Chapter 3:Network noise and intermodulation distortion //example 3.12 page no 89 //given ensqr=8*10^-16//noise voltage insqr=9*10^-25//rms noise current Rs=9.42*10^3//sourse resistance k=1.38*10^-23//Boltzmmans constant T=290//tempreture N=ensqr+insqr*Rs^2+4*k*T*Rs//total noise disp(N,'the total noise i...
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clear// //Variables Vdc = 30.0 //Average value of voltage (in volts) RL = 1.0 //Resistance (in kilo-ohm) gamma = 0.01 //Ripple factor f = 50 //Frequency (in Hertz) //Calculation C = 2890.0 / (gamma * RL) ...
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clc //Initialization of variables disp("from saturated steam tables,") hi=1279.1 //B/lbm //calculations u2=hi T2=564 //F //results printf("Temperature of steam = %d F",T2)
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//Find Dimension of unit cell //Ex:5.10 clc; clear; close; w=0.0708;//wavelength in nm h=1; k=0; l=0; s=0.0132;//a common divisor i.e.sin^2(theta)=0.0132 a=sqrt((w^2*(h^2+k^2+l^2))/(4*s));//in nm a1=10^3*a;//in pm disp(a1,"Dimension of unit cell (in Picometer) = ");
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load quiz.hdl; output-file quiz.out; output-list a b c y z; set a 0, set b 0, set c 0, eval, output; set a 0, set b 0, set c 1, eval, output; set a 0, set b 1, set c 0, eval, output; set a 0, set b 1, set c 1, eval, output; set a 1, set b 0, set c 0, eval, output; set a 1, set b 0, set c 1, eval, output; set a 1, set b...
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//creating vector c in scilab internal stack host('make /tmp/ext7f.o'); link('/tmp/ext7f.o','ext7f') a=[1,2,3]; b=[2,3,4]; //c does not exist (c made by ext7f) fort('ext7f',a,1,'d',b,2,'d','out',1); //c now exists c-(a+2*b)
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//To find width, tension and length clc //Given: d2=240/1000, d1=600/1000, x=3 //m P=4*1000 //W N2=300 //rpm mu=0.3 T1s=10 //Safe working tension, N/mm width //Solution: //Minimum width of the belt: //Calculating the velocity of the belt v=%pi*d2*N2/60 //m/s //Calculating the angle alpha for an open belt dr...
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function x=%sp_r_s(a,b) // a*b^-1 a sparse, b full // Copyright INRIA x=full(a)/b
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// Example 3.3: miller indices clc; clear; close; x=1/2;// x1=1/x;// r2=0;// r3=0;// x10=-1;// x2=1/-x10;// r4=0;// r5=0;// disp("miller indices (Case 1) of the given plane are "+string(x1)+" : "+string(r2)+" : "+string(r3)+" ") disp("miller indices (Case 2) of the given plane are "+string(x2)+" : "+string(r3)+" : "+st...
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//example 10.2 clc; funcprot(0); phi=32; Gamma=112; s=12;//spacing H=27; Ka=(tan(45*%pi/180-32*%pi/180/2))^2; sigmaa=0.65*Gamma*Ka*H; A=sigmaa*15*15/2/9; B1=603.44*15-A; C=sigmaa*12*12/2/9; B2=sigmaa*s-C; Pa=A*s/1000; Pb=(B1+B2)*s/1000; Pc=C*s/1000; disp(Pa,"strut loads at A in kN"); disp(Pb,"strut loa...
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//Example 1.14 N=4; disp(N,"total No. of possible outcomes (N)="); M=2; disp(M,"No. of Favorable cases(both heads or both tails)="); P1=M/N; disp(P1,"Probab. of (both heads or both tails)=");
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//calculating current drawn V=230//voltage applied R=15+10//total resistance of the circuit L=.04+.1//total inductance Xl=2*%pi*50*L C=100D-6//capacitance Xc=1/(2*%pi*50*C) X=Xl-Xc Z=sqrt(R^2+X^2) I=V/Z mprintf("Current drawn=%f A\n",I) //calculating voltages V1 and V2 Z1=sqrt(15^2+(2*%pi*50*.04)^2) V1=I...
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// Example no 8.4 // To find the upper bound of the transmission bit rate // Page no. 439 clc; clear all; // Given data FL=810*10^6; // Lower limit of forward channel frequency band FU=826*10^6; // Upper limit of ...
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clc clear Vs=0.015; Vc=0.06*Vs; V3=Vc; n=1.3; P2=10; P1=1; N=280; V4=V3*[(P2/P1)^(1/n)]; printf('V4: %3.4f m^3/cycle',V4); printf('\n'); printf('V3: %3.4f m^3/cycle',V3); printf('\n'); V1=Vs+Vc; printf('V1: %3.4f m^3/cycle',V1); printf('\n'); V14=V1-V4; //Suction Volume V2=V1*[(P1/P2)^(1/...
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clear ; clc; // Example 2.4 printf('Example 2.4\n\n'); printf('Page No. 47\n\n'); // given F1= 500*10^3;// fuel oil in gallons F2= 500*10^3;// coal in gallons in Pound C1= 165*10^3;// cost of oil per year in Pound C2= 92*10^3;// cost of an equivalent of coal in Pound Ce= 100*10^3;// capital cost of extra ha...
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aa=syslin('c',[1,3;4,5],[6;8],[2,3],[1]); a1=augstate(aa) ab=syslin('c',[1,2;3,4],[4,5;6,7],[8,9;0,1],[1,0;0,5]) a2=augstate(ab)
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//EX9_4 PG-9.14 clc R=5e3;//each resistance of the RC phase shift oscillator C=0.1e-6;//each capacitance of the RC phase shift oscillator f=1/(2*%pi*sqrt(6)*R*C); printf("\n Therefore frequency of oscillation is %.3f Hz \n",f)
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// EXAMPLE (PG 526) disp("Consider Hilbert matrix of order three") n=3; // Order of the matrix A=zeros(n,n);// a symmetric positive definite real or complex matrix. for i=1:n // Initializing 'for' loop for j=1:n A(i,j)=1/(i+j-1); end end //End of 'for' loop A chol(A) ...
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// A Textbook of Fluid Mecahnics and Hydraulic Machines - By R K Bansal // Chapter 4-Buoyancy and Floatation //// Problem 4.11 //Given Data Set in the Problem dens=1000 g=9.81 D=3 d=1.8 V_disp=0.6 CB1=1.95 CG=1.2 W_tot=3.9*1000*g //For meta centric height //Weight of water displaced=weight density of wat...
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//Exa 10.4 clc; clear; close; //Given Data : format('v',7); Im=10;//in Ampere f=50;//in Hz V=240;//in volts cosfi_1=0.707;//powerfactor sinfi_1=sind(acosd(cosfi_1));//unitless Ir1=Im*sinfi_1;//in Ampere cosfi_2=1;//powerfactor Ir2=0;//in A(as cosfi_2=1) Ic=Ir1-Ir2;//in Ampere C=Ic/(2*%pi*f*V);//in farads...
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Name=TILE FRENZY 360 FLICK v2 PlayerCharacters=TileFrenzy Challenger BotCharacters=TileFrenzy Cube.bot IsChallenge=true Timelimit=60.0 PlayerProfile=TileFrenzy Challenger AddedBots=TileFrenzy Cube.bot;TileFrenzy Cube.bot;TileFrenzy Cube.bot;TileFrenzy Cube.bot;TileFrenzy Cube.bot;TileFrenzy Cube.bot;TileFrenzy Cu...
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//chapter10,Example10_4,pg 272 e = 1.6*10^-19; m=9.1*10^-31; vx=1.7*10^7 Ey=3.4*10^4 x=3*10^-2 t=x/vx //y=0.5*ay*(t^2) ay=(e*Ey)/m y=0.5*ay*(t^2) Bz=Ey/vx printf("verical displacement of electron \n") printf("y=%.2f m",y) printf("\nmagnitude of magnetic field\n") printf("B=%.4f wb/m2",Bz) printf("\ndirectio...
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//===================================================================================== //Chapter 13 example 7 clc;clear all; //variable declaration R1 = 180; //resistance in Ω R2 = 20; //resistance in Ω A = 0.005; //area in m^2 Ns = 1000; //number of turns on search coil G1 = 100...
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//Ex:3.20 clc; clear; close; a=25;// max radius in um y=0.8;// operating wavelength in um NA=0.343;// numerical aperture v=(2*%pi*a*NA)/y;// v-number M=v^2/2;//number of modes printf("The v-number =%f", v); printf("\n The number of modes =%f", M);
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function [files]=write_code(Code,CCode,FCode,Code_common) // Original file from Project Metalau - INRIA // Modified for RT purposes by Roberto Bucher - RTAI Team // roberto.bucher@supsi.ch ierr=execstr('mputl(Code,rpat+''/''+rdnom+''.c'')','errcatch') if ierr<>0 then message(lasterror()) ok=%f return ...
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// Example 2.7 clc; clear; close; format('v',5) // given data Vin= 10;// in V V_K= 0.7;// in V Vout=0;// in V R_L= 1000;// in kΩ r_B= 20;// in Ω // The peak forward current, I_P= (Vin-V_K)/(R_L+r_B);// in A // The peak voltage V_P= I_P*R_L;// in V // The peak inverse voltage PIV= Vin-Vout;// in V dis...
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clc //initialisation of variables clear a= 6 //degrees r= 1.5 l= 100 //ft f= 0.025 K= 0.15 //CALCULATIONS R= r^4-1 R1= cotd(a/2)*(1-(1/r)) p1= f*l p2= 2.5*(l-p1)/l p3= (1-r^2)^2 p4= K*p3 pt= p4+p2 //RESULTS printf ('lowest ratio = %.2f',R) printf ('\n contribtuion of friction in pipe = %.1f lbf/ft^2',...
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clc clear Vs=0.01; //in m^3 Pm=600; //in kPa N=300; //in rpm n=N/2; IP=(Vs*Pm*n)/60; printf('Indicated Power= %2.0f kW',IP); printf('\n');
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## Copyright (C) 2006-2017 John W. Eaton ## ## This file is part of Octave. ## ## Octave is free software; you can redistribute it and/or modify it ## under the terms of the GNU General Public License as published by ## the Free Software Foundation; either version 3 of the License, or (at ## your option) any later vers...
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//problem 2.5 clc; clear; close; //given data : format('v',5); MotorInput=50;//in KW Slip=3;//in % RotCuLoss=MotorInput*Slip/100;//in KW disp(RotCuLoss,"Rotor Copper Loss(KW) : "); TMechP=MotorInput-RotCuLoss;//in KW disp(TMechP,"Total mechanical power devloped(KW) : ");
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function [D,DD] = diffpara(X,varargin) //Return the estimator D for the differencing parameter of an integrated time series //Calling Sequence // [D, DD] = diffpara (X) // [D, DD] = diffpara (X, A) // [D, DD] = diffpara (X, A, B) //Parameters //X: Input scalar or vector. //DD:The estimators for all frequencies in the ...
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//Example No.4.10 // Page No.138. //To find the probability. clc;clear; L = 25*10^(-10);//Width of the potential well -[m]. delx = 0.05*10^(-10);//Interval -[m]. x = int(1); P = (((2*delx)/L)*x);//'P' is the probability of finding the practicle at an interval of 0.05 . printf("\nThe probability of finding t...
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//Exa:1.63 clc; clear; close; P_o=50*1000;//in watts f=50;//in hertz s_f=0.04;//slip P=6;//no.of poles N_s=120*f/P;//Synchronous Speed (in rpm) N_f=N_s*(1-s_f); T_f=P_o/(2*%pi*N_f)
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s=%s; m=1+2*s+5*s^2+5*s^3+2*s^4; disp (m) r= coeff (m) n= length (r) routh = routh_t (m) // Thi s Func t ion g e n e r a t e s the Routht a b l e disp (routh ," r o u t h s t a b u l a t i o n=") c =0; for i =1: n if ( routh (i ,1) <0) c=c+1; end end if(c >=1) printf (" sys t em i s u n s t a b l e ") ...
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//chapter16 //example16.8 //page351 Av=10000 R1=2 // kilo ohm R2=18 // kilo ohm Vi=1 // mV mv=R1/(R1+R2) Avf=Av/(1+Av*mv) Vout=Avf*Vi printf("feedback fraction = %.1f \n",mv) printf("voltage gain with negative feedback = %.1f \n",Avf) printf("output voltage = %.1f mV \n",Vout)
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clf() A1 = [2 2 2 2 2; 1 0 0 1 1; 1 1 0 0 1] x1 = A1(1,:) y1 = A1(2,:) z1 = A1(3,:) param3d(x1,y1,z1) plot3d(A1(1,1:4)',A1(2,1:4)',A1(3,1:4)')
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clc; //e.g 8.13 Icbo=10*10**-6; beta=50; //Value of collector current when Ib=0.25*10**-3; Ib=0.25*10**-3; Ic=(beta*Ib)+(1+beta)*Icbo; disp('mA',Ic*10**3,"Ic="); //Value of new collector current if temperature rises to 50 degree t1=27; t2=50; Icbo50=Icbo*2^((t2-t1)/10); disp('microA',Icbo50*10**6,"I...
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clc; pathname=get_absolute_file_path('3_11_soln.sce') filename=pathname+filesep()+'3_11_data.sci' exec(filename) // Solution: // Acceleration due to gravity, g=32.2; //ft/s^2 // Assuming ideal fluid, Jet velocity, v2=sqrt(2*g*h); //ft/s // Area of the opening, A=(%pi/4)*((d/12)^2); //ft^2 // flow rate, Q=A*v2; //ft^3/...
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// Example 9.6 R=10; // Resistance i=4+%i*3; // Current I=sqrt(4^2+3^2); // Absolute Value of Current Ir=4; // Real Component of Current Ii=3; // Imaginary Component of Current Q=atand(3/4); // Phase Angle Pr=Ir^2*R; // Power Due to Real ...
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function fx = f1(x) fx = 0.1*x(1)**2 + x(2)**2 + 10*x(3)**2 + 100*x(4)**2 -0.2*x(1) - 2*x(2) - 20*x(3) - 200 *x(4) endfunction function tp = tk(g,h) tp = (-g'*-g)/(-g'*h*-g) endfunction x = [2 ;3 ;4 ;5] disp(f1(x),'fx') g = numderivative(f1,x)' //disp(g,'Gradiente') h = [0.2 0 0 0...
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clc; clf; clear all; im =imread("D:\DSP\Picture1.PNG"); imshow(im);
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clc //initialisation of variables p1= 3 //Mpa p2= 0.2 //Mpa V1= 0.6 //m^3 V2= 1 //m^3 M= 28 //gms R= 8.314 //J/mol K T= 400 //C T1= 150 //C k= 1.4 p3= 1.25 //Mpa //CALCULATIONS m1= p1*V1*10^3*M/(R*(273.15+T)) m2= p2*V2*10^3*M/(R*(273.15+T1)) p4= (p1*V1+p2*V2)/(V1+V2) T2= (p4/p1)^((k-1)/k)*(273.15+T) m3...
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clc; warning("off"); printf("\n\n example7.4 - pg280"); // given id=6; //[inch] - inlet diameter od=4; //[inch] - outlet diameter Q=10; //[ft^3/sec] - water flow rate alpha2=%pi/3; //[radians] - angle of reduction of elbow alpha1=0; p1=100; //[psi] - absolute inlet pressure p2=29; //[psi] - absolute out...
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function [p,lp]=lshp(i,j,g) [lhs,rhs]=argn(0), if rhs==2 then g=the_g, end if ( i<0 | i>g_nodnum(g) | j<0 | j>g_nodnum(g)) then error('bad internal node number') end lneg=find(alenght(g)<0) if lneg<>[] then [l,v]=ford(i,g) else if g_edgnum(g)<0.5*g_nodnum(g)*g_nodnum(g) then [l,v]=johns(i,g) else [l,v]=di...
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clear; clc; // RCMP-MULT-2a.sce // 1) 2 A => B // 2) A => C // No adiabático // (a) Método. gráfico // CONSTANTES V = 0.1; // L F = 0.01; // L/s CA0 = 10; // mol/L T0 = 318; // K TJ = 318; // K UA = 371; // J/(s*K) CP = 4.18; // J/(g*K) RHO = 1000; // g/L k01 = 1E16; // L/(s*mol) E1 = 1.2E...
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//Example 6.18 clc; clear; close; format('v',4); //Given data : g=9.81;//constant A=3.2;//m^2 a=10*10^-4;//m^2 H1=5;//meter H2=2.5;//meter Cd=0.6;//Coefficient of discharge t=2*A*(sqrt(H1)-sqrt(H2))/Cd/a/sqrt(2*g);//sec disp("Time taken is "+string(floor(t/60))+" minute "+string((t/60-floor(t/60))*60)+" se...
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clc //initialisation of variables clear mu= 1 mb= 2 m= 1 m1= 2 //CALCULATIONS ym1= 0.5*(mu*m^2+mu*m^2) ym2= 0.5*(mb*m^2+m*m1^2) ym3= 0.5*(mu*m1^2+mu*m1^2) //RESULTS printf ('ionic strength of solution = %.f *m',ym1) printf ('\n ionic strength of solution = %.f *m',ym2) printf ('\n ionic strength of solut...
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//ques-18.44 //Calculating enthalpy of the reaction and free energy change and entropy change at 925 K clc T1=925; T2=1000;//temperature (in K) K1=18.5; K2=9.25;//equikibrium constant H=(log10(K2/K1)*2.303*8.314*T1*T2)/(T2-T1);//enthalpy (in J/mol) G=-2.303*8.314*T1*log10(K1); S=(H-G)/T1; printf("The enthalpy o...
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//Chapter-1, Example 1.18, Page 1.43 //============================================================================= clc clear //INPUT DATA N=(1800/60);//Speed of the motor in rps V=200;//Terminal voltage in V Nl=(900/60);//Lathe speed in rps F=300;//Force exerted in N r=0.2;//Radius of the shaft in m n=0.9...
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//EX13_40 Pg-22 clc clear printf("15''s complement (A9B)_16 is :") x=['A9B']; y=hex2dec(x);//hexadecimal to decimal conversion// z=dec2hex(bitcmp(y,11));//15's complement of the number// printf("%s",z)
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// Scilab Code Ex2.26 Difference in wavelength in the spectra of hydrogen and deuterium: Pg:62 (2008) R_H = 1.097e+07; // Rydberg constant for H-atom, per metre M_H = 1; // Mass of H-atom, amu M_D = 2*M_H; // Mass of D-atom, amu m = 0.000549*M_H; // Mass of an electron, amu R_D = R_H*(1+m/M_H)/(1+m/M_D...
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//chapter 6 //example 6.2 //page 251 printf("\n") printf("given") Vce=4.5;Ib=40*10^-6; disp("from current characteristic at Vce=4.5V and Ib=40uA") Ic=4*10^-3;Ib=30*10^-6; hFE=Ic/Ib; printf(" the value of hFE is %d\n",hFE) disp("from output characteristic at Vce=4.5 and Ib=40uA") Ic=400*10^-3;Vce=6; hoe=(Ic/...
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clc clear //Initialization of variables h=4 //in den=13.6 //g/cc Ar=1/9 A1=12 //sq in gam=62.4 //lb/ft^3 g=32.2 //ft/s^2 //calculations dh=(h*den-h)/12 Vr=1/Ar V22=2*g*dh/(1-Ar^2) V2=sqrt(V22) A2=A1*Ar v2=1/gam ms=A2*V2/(v2*144) //results printf("Flow rate of water = %.1f lb/sec",ms)
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// Scilab code Ex17.7 : Pg:892 (2011) clc;clear; amu = 931.5; // Energy equivalent of 1 amu, MeV nucleus = cell(4,3); nucleus(1,1).entries = 'P'; nucleus(1,2).entries = 15; nucleus(1,3).entries = 31; nucleus(1,4).entries = 30.98356; nucleus(2,1).entries = 'n'; nucleus(2,2).entries = 0; nucleus(2,3).entries...
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clc un1=1000 disp("un1 = "+string(un1)+"cm^2(Vs)^-1") //initializing value of mobility of electron of silicon e = 1.6*10^-19 disp("e= "+string(e)+"C")//initializing value of charge of electron un2 = 8000 disp("un2 = "+string(un2)+"cm^2(Vs)^-1") //initializing value of mobility of electron of GaAs up1 = 350 disp...
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clear; clc; disp("--------------Example 3.22---------------") bit_rate=10^6; // 1 Mbps //a) rough approximation mb=bit_rate/2; // formula to caluculate bandwidth min_bandwidth=mb*10^-3; //multiply with conversion factor printf("\n a) The minimum bandwidth is %d kHz.",min_bandwidth); // display result printf("\...
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clear; clc; // Stoichiometry // Chapter 6 // Stoichiometry and Unit Operations // Example 6.4 // Page 355 printf("Example 6.4, Page 355 \n \n"); // solution // basis 0.625 l/s of MEA solution c = 3.2 //M conc of MEA M = 61 // molar mass of MEA C = M*c //g/l conc of MEA in sol MEAin = c*.625*360...
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clear; clc; //Example - 7.1 //Page number - 235 printf("Example - 7.1 and Page number - 235\n\n"); //This problem involves proving a relation in which no numerical components are involved. //For prove refer to this example 7.1 on page number 235 of the book. printf(" This problem involves proving a relation ...
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//Ex1_20 clc; //Given: mh=1.00783; mn=1.00867; m35=34.96885; // atomic mass of Cl (35) m37=36.96590; // atomic mass of Cl (37) //solution: B1=(17*mh+18*mn-m35)*931; // in MeV Bh=B1/m35; printf("\n The mean binding energy of Cl (35) atom in MeV is = %f ",Bh) B2=(17*mh+20*mn-m37)*931; // in MeV ...
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// Copyright (C) 2015 - IIT Bombay - FOSSEE // // This file must be used under the terms of the CeCILL. // This source file is licensed as described in the file COPYING, which // you should have received as part of this distribution. The terms // are also available at // http://www.cecill.info/licences/Licence_CeCILL_...
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//page 25 //Example 1.16 clear; close; clc; a = [1 1/2 1/3;1/2 1/3 1/4;1/3 1/4 1/5]; disp(a,'a = '); b = eye(3,3); disp(b,'b = '); disp('Applying row transformations on a and b simultaneously,'); disp('R2 = R2 - 1/2 * R1 and R3 = R3 - 1/3*R1'); a(2,:) = a(2,:) - 1/2 * a(1,:); a(3,:) = a(3,:) - 1/3 * a(1,:);...
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function slc=contrss(a,tol) [lhs,rhs]=argn(0) // flag=a(1); if flag(1)<>'lss' then error(91,1), end; if rhs==1 then tol=sqrt(%eps);end if rhs>2 then error('1 or 2 inputs to contrss : sl [,tol]') end; [a,b,c,d,x0,dom]=a(2:7) // [nc,u]=contr(a,b,[tol*norm([a,b],1),tol]) u=u(:,1:nc) a=u'*a*u;b=u'*b;c=c*u slc=sysl...
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clc; v=200; // rated voltage of dc shunt motor ra=0.1; // armature resistance n=1000; // running speed of motor ia=50; // armature current at n=1000 rpm re=0.1; // reduction in field flux disp('case a'); Ea1=v-ia*ra; // initial counter EMF Ea2=Ea1*(1-re); // counter EMF after reduced field flux iam=(v-Ea2)/ra...
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clear; clc; printf("\t\t\tExample Number 10.10\n\n\n"); // off-design calculation of exchanger in example 10-4 // Example 10.10 (page no.-544-546) // solution m_dot_c = 68;// [kg/min] water flow rate T1 = 35;// [degree celsius] initial temperature T2 = 75;// [degree celsius] final temperature Toe = 110;/...
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// FREQUENCIAS NATURAIS E MATRIZ DE AMORTECIMENTO DampingData(find(evstr(DampingData.string)>n)).string = string(n) modo1 = evstr(DampingData(1).string) modo2 = evstr(DampingData(2).string) csi(1,1) = evstr(DampingData(3).string) csi(2,1) = evstr(DampingData(4).string) // Vetor de frequências naturais da ...
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//To find speed of shaft clc //Given: TB=80, TC=82, TD=28 NA=500 //rpm //Solution: //Calculating the number of teeth on wheel E TE=TB+TD-TC //Calculating the values of x and y y=800 x=-y*(TE/TB)*(TC/TD) //Calculating the speed of shaft F NF=x+y //Speed of shaft F, rpm //Results: printf("\n\n Speed of shaf...
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codeblock readtextfile(ScriptDir+"\_TOOLS.sci"); codeblock readtextfile(ScriptDir+"\_SSYS.sci"); ffc=0; #codeblock readtextfile(ScriptFilepath+"\_Sub\_SUB_general.sci"); function calclongitlattit(pos,longit,lattit) { pos=vecnorm(pos); lattit=asin(pos.z); longit=Pi+angle(pos.x,pos.y); while longit>Pi do ...
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bacc26e6c7139383a374ea16f6c62565a7ff0603
68cddb2ca8dabddfe47251ac6647011acb849a2c
refs/heads/master
2021-06-16T02:27:39.886532
2020-05-01T09:23:39
2020-05-01T09:23:39
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null
2017-07-13T03:57:21
2017-07-13T03:57:21
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Scilab
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false
148
cv_imread.sci~
function[dstMat] = imread(matA) out = opencv_imread(matA) channel = size(out) for i = 1: channel dstMat(:,:,i) = out(i) end endfunction