[User] Count how many posts have media attachments.

[Assistant] SELECT count(*) FROM social_media.posts WHERE media_url IS NOT NULL

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE social_media.users ( user_id text PRIMARY KEY, username text, email text, password_hash text, full_name text, profile_picture_url text, bio text, location text, created_at timestamp, updated_at timestamp, is_verified bool )
CREATE TABLE social_media.posts ( post_id.text, user_id.text, content.text, media_url.text, media_type.text, created_at.timestamp, updated_at.timestamp, visibility.text, location_lat.numeric, location_lon.numeric )
CREATE TABLE social_media.comments ( comment_id text PRIMARY KEY, post_id text, user_id text, parent_comment_id text, content text, created_at timestamp, updated_at timestamp )
CREATE TABLE social_media.follows ( follow_id text PRIMARY KEY, follower_user_id text, following_user_id text, created_at timestamp )
CREATE TABLE social_media.hashtags ( hashtag_id.text, tag_name.text, created_at.timestamp )
CREATE TABLE social_media.post_hashtags ( post_hashtag_id character varying(64) NOT NULL, post_id character varying(64) NOT NULL, hashtag_id character varying(64) NOT NULL, PRIMARY KEY (post_hashtag_id), CONSTRAINT unique_post_hashtag UNIQUE (post_id, hashtag_id) )
CREATE TABLE social_media.messages ( message_id text PRIMARY KEY, conversation_id text, sender_user_id text, content text, media_url text, media_type text, sent_at timestamp, read_at timestamp )
CREATE TABLE social_media.conversations ( conversation_id text, created_at timestamp, last_message_at timestamp, is_group_chat boolean, group_name text )
CREATE TABLE social_media.conversation_participants ( participant_id text, conversation_id text, user_id text, joined_at timestamp, last_read_at timestamp )
CREATE TABLE social_media.notifications (
    notification_id character varying(64) NOT NULL, -- unique identifier for the notification
    recipient_user_id character varying(64) NOT NULL, -- user receiving the notification (FK to users.user_id)
    sender_user_id character varying(64), -- user triggering the notification (FK to users.user_id, can be null for system notifications)
    notification_type character varying(30) NOT NULL, -- type of notification ('like', 'comment', 'follow', 'mention', 'message')
    target_entity_id character varying(64), -- ID of the related entity (post_id, comment_id, user_id, conversation_id)
    target_entity_type character varying(20), -- type of the related entity ('post', 'comment', 'user', 'conversation')
    created_at timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, -- timestamp notification was created
    read_at timestamp, -- timestamp notification was marked as read
    PRIMARY KEY (notification_id)
)
CREATE TABLE social_media.user_settings ( setting_id character varying(64) NOT NULL, user_id character varying(64) NOT NULL UNIQUE, theme character varying(20) DEFAULT 'light', email_notifications_enabled boolean DEFAULT true, push_notifications_enabled boolean DEFAULT true, private_profile boolean DEFAULT false, updated_at timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY (setting_id) )


[User] Show all reviews with the guest's ID, review comment, and the full name of the staff member who responded.

[Assistant]
SELECT r.review_id, r.guest_id, r.comment, s.first_name AS response_staff_first_name, s.last_name AS response_staff_last_name
FROM hospitality_technology.reviews r
LEFT JOIN hospitality_technology.staff s ON r.response_staff_id = s.staff_id;

[User] Can you include the property name as well?

[Assistant]
SELECT r.review_id, r.guest_id, r.comment, p.property_name, s.first_name AS response_staff_first_name, s.last_name AS response_staff_last_name
FROM hospitality_technology.reviews r
JOIN hospitality_technology.properties p ON r.property_id = p.property_id
LEFT JOIN hospitality_technology.staff s ON r.response_staff_id = s.staff_id;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE hospitality_technology.properties ( property_id text PRIMARY KEY, property_name text, address_line1 text, address_line2 text, city text, state_province text, postal_code text, country_code text, phone_number text, email_address text, property_type text, star_rating numeric, timezone text, manager_staff_id text, created_at timestamp, updated_at timestamp )
CREATE TABLE hospitality_technology.staff ( staff_id text, property_id text, first_name text, last_name text, position text, work_email text, work_phone text, hire_date date, termination_date date, is_active boolean, access_level integer, manager_id text, created_at timestamp )
CREATE TABLE hospitality_technology.reviews ( review_id character varying(64) NOT NULL, property_id character varying(64) NOT NULL, reservation_id character varying(64) UNIQUE, guest_id character varying(64) NOT NULL, rating_overall integer, rating_cleanliness integer, rating_service integer, rating_location integer, rating_value integer, comment text, review_source character varying(100), review_date timestamp with time zone NOT NULL DEFAULT current_timestamp, is_public boolean DEFAULT true, staff_response text, response_staff_id character varying(64), response_date timestamp with time zone, PRIMARY KEY (review_id), FOREIGN KEY (property_id) REFERENCES hospitality_technology.properties(property_id), FOREIGN KEY (reservation_id) REFERENCES hospitality_technology.reservations(reservation_id), FOREIGN KEY (guest_id) REFERENCES hospitality_technology.guests(guest_id), FOREIGN KEY (response_staff_id) REFERENCES hospitality_technology.staff(staff_id) )


[User] Show me all reservations with their guest IDs and room IDs where the total amount is greater than $500 and the status is 'Confirmed', ordered by check-in date.

[Assistant] SELECT reservation_id, guest_id, room_id, check_in_date, total_amount FROM hospitality_technology.reservations WHERE total_amount > 500 AND status = 'Confirmed' ORDER BY check_in_date;

[User] Now, join this with the service_orders table to include the total price of all services ordered for each reservation.

[Assistant] SELECT r.reservation_id, r.guest_id, r.room_id, r.check_in_date, r.total_amount, SUM(so.total_price) AS total_service_price FROM hospitality_technology.reservations r LEFT JOIN hospitality_technology.service_orders so ON r.reservation_id = so.reservation_id WHERE r.total_amount > 500 AND r.status = 'Confirmed' GROUP BY r.reservation_id, r.guest_id, r.room_id, r.check_in_date, r.total_amount ORDER BY r.check_in_date;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE hospitality_technology.reservations ( reservation_id.text, property_id.text, guest_id.text, room_id.text, room_type_id.text, check_in_date.date, check_out_date.date, actual_check_in_ts.timestamp, actual_check_out_ts.timestamp, num_adults.integer, num_children.integer, status.text, booking_source.text, rate_plan_id.text, total_amount.numeric, amount_paid.numeric, special_requests.text, created_at.timestamp, updated_at.timestamp )
CREATE TABLE hospitality_technology.service_orders ( order_id character varying(64) NOT NULL, reservation_id character varying(64), guest_id character varying(64) NOT NULL, service_id character varying(64) NOT NULL, staff_id_ordered character varying(64), staff_id_delivered character varying(64), order_timestamp timestamp with time zone NOT NULL DEFAULT current_timestamp, delivery_timestamp timestamp with time zone, quantity integer NOT NULL DEFAULT 1, unit_price numeric(10, 2) NOT NULL, total_price numeric(12, 2) NOT NULL, status character varying(50) NOT NULL, notes text, bill_id character varying(64), PRIMARY KEY (order_id), FOREIGN KEY (reservation_id) REFERENCES hospitality_technology.reservations(reservation_id), FOREIGN KEY (guest_id) REFERENCES hospitality_technology.guests(guest_id), FOREIGN KEY (service_id) REFERENCES hospitality_technology.services(service_id), FOREIGN KEY (staff_id_ordered) REFERENCES hospitality_technology.staff(staff_id), FOREIGN KEY (staff_id_delivered) REFERENCES hospitality_technology.staff(staff_id) )
CREATE TABLE hospitality_technology.reviews ( review_id character varying(64) NOT NULL, property_id character varying(64) NOT NULL, reservation_id character varying(64) UNIQUE, guest_id character varying(64) NOT NULL, rating_overall integer, rating_cleanliness integer, rating_service integer, rating_location integer, rating_value integer, comment text, review_source character varying(100), review_date timestamp with time zone NOT NULL DEFAULT current_timestamp, is_public boolean DEFAULT true, staff_response text, response_staff_id character varying(64), response_date timestamp with time zone, PRIMARY KEY (review_id), FOREIGN KEY (property_id) REFERENCES hospitality_technology.properties(property_id), FOREIGN KEY (reservation_id) REFERENCES hospitality_technology.reservations(reservation_id), FOREIGN KEY (guest_id) REFERENCES hospitality_technology.guests(guest_id), FOREIGN KEY (response_staff_id) REFERENCES hospitality_technology.staff(staff_id) )


[User] Show the number of employees in each department.

[Assistant]
SELECT department, COUNT(*) AS employee_count
FROM financial_services.employees
group BY department;

[User] Exclude departments that have less than 3 employees.

[Assistant]
SELECT department, COUNT(*) AS employee_count
FROM financial_services.employees
group BY department
HAVING COUNT(*) >= 3;

[User] Can you also show the average hire_date for employees in each department?

[Assistant]
SELECT department, COUNT(*) AS employee_count, AVG(hire_date) AS average_hire_date
FROM financial_services.employees
group BY department
HAVING COUNT(*) >= 3;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE financial_services.accounts ( account_id text PRIMARY KEY, customer_id text, account_number text, account_type text, balance numeric, currency text, opened_date date, status text, interest_rate numeric, last_updated_at timestamp )
CREATE TABLE financial_services.transactions ( transaction_id text PRIMARY KEY, account_id text, related_account_id text, transaction_type text, amount numeric, currency text, transaction_date timestamp, effective_date date, description text, status text, reference_number text )
CREATE TABLE financial_services.trades ( trade_id text PRIMARY KEY, account_id text, security_id text, order_id text, trade_type text, quantity numeric, price_per_unit numeric, total_amount numeric, commission numeric, trade_timestamp timestamp, settlement_date date, status text, execution_venue text )
CREATE TABLE financial_services.market_data ( data_point_id bigserial PRIMARY KEY, security_id text, data_timestamp timestamp, open_price numeric, high_price numeric, low_price numeric, close_price numeric, adjusted_close_price numeric, volume bigint, source text )
CREATE TABLE financial_services.employees ( employee_id text PRIMARY KEY, first_name text, last_name text, job_title text, department text, branch_id text, email text, phone_extension text, hire_date date, termination_date date, manager_id text, status text )


[User] Show each citizen's first and last notification IDs based on sent_at.

[Assistant]
WITH bounds AS (
  SELECT citizen_id,
         MIN(sent_at) AS first_sent,
         MAX(sent_at) AS last_sent
  FROM government_services.notifications
  GROUP BY citizen_id
)
SELECT n1.citizen_id,
       n1.notification_id AS first_notification_id,
       n2.notification_id AS last_notification_id
FROM bounds b
JOIN government_services.notifications n1
  ON n1.citizen_id = b.citizen_id
 AND n1.sent_at = b.first_sent
JOIN government_services.notifications n2
  ON n2.citizen_id = b.citizen_id
 AND n2.sent_at = b.last_sent;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE government_services.notifications ( notification_id text PRIMARY KEY, citizen_id text, application_id text, message_subject text, message_body text, channel text, sent_at timestamp, status text, related_entity_type text, related_entity_id text )


[User] Show me all rooms that are currently available (status = 'available') and have a non-smoking policy, along with their room type details including base rate and max occupancy.

[Assistant] SELECT r.room_id, r.room_number, r.floor, rt.type_name, rt.base_rate, rt.max_occupancy, rt.bed_type, rt.area_sqft FROM hospitality_technology.rooms r JOIN hospitality_technology.room_types rt ON r.room_type_id = rt.room_type_id WHERE r.status = 'available' AND r.is_smoking = false;

[User] Now, filter these results to only include rooms with a max occupancy of at least 4 people and order them by base rate in ascending order.

[Assistant] SELECT r.room_id, r.room_number, r.floor, rt.type_name, rt.base_rate, rt.max_occupancy, rt.bed_type, rt.area_sqft FROM hospitality_technology.rooms r JOIN hospitality_technology.room_types rt ON r.room_type_id = rt.room_type_id WHERE r.status = 'available' AND r.is_smoking = false AND rt.max_occupancy >= 4 ORDER BY rt.base_rate ASC;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE hospitality_technology.rooms ( room_id character varying(64) NOT NULL, property_id character varying(64) NOT NULL, room_number character varying(10) NOT NULL, room_type_id character varying(64) NOT NULL, floor integer, status character varying(50) NOT NULL, is_smoking boolean NOT NULL DEFAULT false, features text, current_condition text, last_cleaned_at timestamp with time zone, PRIMARY KEY (room_id), FOREIGN KEY (property_id) REFERENCES hospitality_technology.properties(property_id), FOREIGN KEY (room_type_id) REFERENCES hospitality_technology.room_types(room_type_id) )
CREATE TABLE hospitality_technology.room_types ( room_type_id character varying(64) NOT NULL, property_id character varying(64) NOT NULL, type_name character varying(100) NOT NULL, description text, base_rate numeric(10, 2) NOT NULL, max_occupancy integer NOT NULL, bed_type character varying(50), area_sqft numeric(8,2), amenities text, PRIMARY KEY (room_type_id), FOREIGN KEY (property_id) REFERENCES hospitality_technology.properties(property_id) )
CREATE TABLE hospitality_technology.reservations ( reservation_id character varying(64) NOT NULL, property_id character varying(64) NOT NULL, guest_id character varying(64) NOT NULL, room_id character varying(64), room_type_id character varying(64) NOT NULL, check_in_date date NOT NULL, check_out_date date NOT NULL, actual_check_in_ts timestamp with time zone, actual_check_out_ts timestamp with time zone, num_adults integer NOT NULL, num_children integer DEFAULT 0, status character varying(50) NOT NULL, booking_source character varying(100), rate_plan_id character varying(64), total_amount numeric(12, 2), amount_paid numeric(12, 2) DEFAULT 0.00, special_requests text, created_at timestamp with time zone NOT NULL DEFAULT current_timestamp, updated_at timestamp with time zone NOT NULL DEFAULT current_timestamp, PRIMARY KEY (reservation_id), FOREIGN KEY (property_id) REFERENCES hospitality_technology.properties(property_id), FOREIGN KEY (guest_id) REFERENCES hospitality_technology.guests(guest_id), FOREIGN KEY (room_id) REFERENCES hospitality_technology.rooms(room_id), FOREIGN KEY (room_type_id) REFERENCES hospitality_technology.room_types(room_type_id) )
CREATE TABLE hospitality_technology.staff ( staff_id character varying(64) NOT NULL, property_id character varying(64) NOT NULL, first_name character varying(100) NOT NULL, last_name character varying(100) NOT NULL, position character varying(100) NOT NULL, work_email character varying(255) UNIQUE, work_phone character varying(30), hire_date date NOT NULL, termination_date date, is_active boolean NOT NULL DEFAULT true, access_level integer NOT NULL, manager_id character varying(64), created_at timestamp with time zone NOT NULL DEFAULT current_timestamp, PRIMARY KEY (staff_id), FOREIGN KEY (property_id) REFERENCES hospitality_technology.properties(property_id), FOREIGN KEY (manager_id) REFERENCES hospitality_technology.staff(staff_id) )


[User] List all pairs of tokens (show token_id for both) that share the same contract address, excluding pairs where the token_id is the same.

[Assistant] SELECT t1.token_id AS token_id1, t2.token_id AS token_id2, t1.contract_address FROM web3.tokens AS t1 JOIN web3.tokens AS t2 ON t1.contract_address = t2.contract_address WHERE t1.token_id < t2.token_id;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE web3.tokens ( token_id character varying(64) NOT NULL, contract_address character varying(128) NOT NULL, token_name character varying(128) NOT NULL, token_symbol character varying(32) NOT NULL, decimals integer NOT NULL, total_supply numeric(38,14) NOT NULL, PRIMARY KEY (token_id) )


[User] Get me all unbilled billable time entries with their entry_id, case_id, lawyer_id, hours_spent, and billing_rate.

[Assistant]
SELECT entry_id,
       case_id,
       lawyer_id,
       hours_spent,
       billing_rate
FROM legal_services.time_entries
WHERE is_billable = TRUE
  AND is_billed = FALSE;

[User] Actually, I only want entries for lawyer 'lawyer_123'.

[Assistant]
SELECT entry_id,
       case_id,
       lawyer_id,
       hours_spent,
       billing_rate
FROM legal_services.time_entries
WHERE is_billable = TRUE
  AND is_billed = FALSE
  AND lawyer_id = 'lawyer_123';

[User] Also, sort the results by hours_spent in descending order.

[Assistant]
SELECT entry_id,
       case_id,
       lawyer_id,
       hours_spent,
       billing_rate
FROM legal_services.time_entries
WHERE is_billable = TRUE
  AND is_billed = FALSE
  AND lawyer_id = 'lawyer_123'
ORDER BY hours_spent DESC;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE legal_services.time_entries (
    entry_id character varying(64) NOT NULL,  -- unique identifier for the time entry
    case_id character varying(64) NOT NULL, -- FK to cases table
    lawyer_id character varying(64) NOT NULL, -- FK to lawyers table (who performed the work)
    date_worked date NOT NULL, -- date the work was performed
    hours_spent numeric(5, 2) NOT NULL CHECK (hours_spent > 0), -- duration of work in hours (e.g., 1.5 for 1h 30m)
    billing_rate numeric(10, 2) NOT NULL, -- hourly rate applied for this entry
    description text NOT NULL, -- detailed description of the work performed
    is_billable boolean DEFAULT true, -- whether this time entry is billable to the client
    is_billed boolean DEFAULT false, -- whether this entry has been included in an invoice
    invoice_id character varying(64), -- FK to invoices table (once billed)
    created_at timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, -- when the entry was recorded
    PRIMARY KEY (entry_id)
)


[User] List all pairs of vehicles in the same depot with different status. Include both vehicle IDs with their statuses and the depot_id.

[Assistant]
SELECT v1.vehicle_id   AS vehicle1_id,
       v1.status       AS status1,
       v2.vehicle_id   AS vehicle2_id,
       v2.status       AS status2,
       v1.depot_id
FROM transportation.vehicles v1
JOIN transportation.vehicles v2
  ON v1.depot_id = v2.depot_id
 AND v1.vehicle_id < v2.vehicle_id
 AND v1.status <> v2.status;

System:
You are an SQL statement expert. Given the table structure described by the CREATE TABLE statement, write an SQL query that provides the solution to the user's question.
##Table Structure
CREATE TABLE transportation.vehicles ( vehicle_id.text, license_plate.text, vin.text, make.text, model.text, year.integer, type.text, capacity.integer, fuel_type.text, status.text, depot_id.text, acquisition_date.date )


[User] 特定の職種の従業員情報を取得したいです。従業員ID、名前、職種、雇用日を表示してください。

[Assistant]
db.employees.find(
    { job_title: '<specific_job_title>' },
    { employee_id: 1, first_name: 1, last_name: 1, job_title: 1, hire_date: 1, _id: 0 }
).sort({ hire_date: -1 })

[User] 雇用日が2020年1月1日以降の従業員だけに絞り込むことはできますか？

[Assistant]
db.employees.find(
    {
        job_title: '<specific_job_title>',
        hire_date: { $gte: ISODate('2020-01-01') }
    },
    { employee_id: 1, first_name: 1, last_name: 1, job_title: 1, hire_date: 1, _id: 0 }
).sort({ hire_date: -1 })

[User] 雇用ステータスが「Active」の従業員だけをさらに条件に加えられますか？

[Assistant]
db.employees.find(
    {
        job_title: '<specific_job_title>',
        hire_date: { $gte: ISODate('2020-01-01') },
        employment_status: 'Active'
    },
    { employee_id: 1, first_name: 1, last_name: 1, job_title: 1, hire_date: 1, _id: 0 }
).sort({ hire_date: -1 })

[User] スキル認定情報も結果に含めてください。

[Assistant]
db.employees.find(
    {
        job_title: '<specific_job_title>',
        hire_date: { $gte: ISODate('2020-01-01') },
        employment_status: 'Active'
    },
    { employee_id: 1, first_name: 1, last_name: 1, job_title: 1, hire_date: 1, skill_certifications: 1, _id: 0 }
).sort({ hire_date: -1 })

System:
You are an expert in writing database language. You can write a corresponding database language query to answer the user's question based on the table structure described by the table creation statement.
##Table Structure
Collection 'assembly_steps'. Document structure: { _id: <ObjectId (or step_id)>, step_id: String, line_id: String (reference), step_number: NumberInt, step_name: String, description: String, standard_duration_hours: Decimal128, required_skill_level: String, workstation: String }. Required: step_id, line_id, step_number, step_name. Index on line_id, step_number.
Collection 'employees'. Document structure: { _id: <ObjectId (or employee_id)>, employee_id: String, first_name: String, last_name: String, job_title: String, skill_certifications: [String], hire_date: ISODate, assigned_line_id: String (reference, optional), employment_status: String, supervisor_employee_id: String (reference, optional) }. Required: employee_id, first_name, last_name, job_title, hire_date, employment_status.


[User] I need the average capacity of vehicles for each fuel_type.

[Assistant]
SELECT fuel_type,
       AVG(capacity) AS avg_capacity
FROM transportation.vehicles
GROUP BY fuel_type;

[User] Only include fuel types where the vehicle count is at least 10.

[Assistant]
SELECT fuel_type,
       AVG(capacity) AS avg_capacity
FROM transportation.vehicles
GROUP BY fuel_type
HAVING COUNT(*) >= 10;

[User] Also show the number of vehicles for each of these fuel types.

[Assistant]
SELECT fuel_type,
       COUNT(*) AS vehicle_count,
       AVG(capacity) AS avg_capacity
FROM transportation.vehicles
GROUP BY fuel_type
HAVING COUNT(*) >= 10;

[User] Please round avg_capacity to one decimal place.

[Assistant]
SELECT fuel_type,
       COUNT(*) AS vehicle_count,
       ROUND(AVG(capacity)::numeric, 1) AS avg_capacity
FROM transportation.vehicles
GROUP BY fuel_type
HAVING COUNT(*) >= 10;