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mcko

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mcko
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'''
#1
 
#1111.1111_2 + 23.32_4
print(15.9375 + 11.875)
#27.8125 -> 1B.D
 
#4
 
mx = []
for n in range(1, 1000):
     z = n
     s = ''
     while z > 0:
          s = str(z % 2) + s
          z //= 2
     if n % 2 == 0:
          s += str(z.count('1') % 2)
          print(s)
          s = (str(bin(sum((list(map(int, str(n).split())))))))[2:] + s
     else:
          s += '0'
          s += (str(bin(sum((list(map(int, str(n).split())))))))[2:]
     
     r = int(s, 2)
     if r >= 200:
          break
     else:
          print(n, r)
 
#5
 
def binaryOfFraction(fraction):

    binary = str()
    while (fraction):
        fraction *= 2
        if (fraction >= 1):
            int_part = 1
            fraction -= 1
        else:
            int_part = 0
        binary += str(int_part)
 
    return binary
 
 
def floatingPoint(real_no):
    sign_bit = 0
    if(real_no < 0):
        sign_bit = 1
    real_no = abs(real_no)
    int_str = bin(int(real_no))[2 : ]
    fraction_str = binaryOfFraction(real_no - int(real_no))
    ind = int_str.index('1')
    exp_str = bin((len(int_str) - ind - 1) + 127)[2 : ]
    mant_str = int_str[ind + 1 : ] + fraction_str
    mant_str = mant_str + ('0' * (23 - len(mant_str)))
    return sign_bit, exp_str, mant_str
 
 
 
sign_bit, exp_str, mant_str = floatingPoint(14.59375)

ieee_32 = str(sign_bit) + exp_str + mant_str
print(ieee_32)
ieee_32 = int(ieee_32, 2)
ieee_32 = hex(ieee_32)
print(ieee_32)
   
#6
 
x = 640
y = 192
m = 150 * 1024 * 8
proz = 2
color = (m/(x * y)) - proz
print(2 ** color)
 
#7
 
workers = 3000 - 150 
for a in range(10000):
    if 800 + 730 + 900 - 90 - 70 - 120 + 2*a == workers:
        print(a)
#a = 140
 
#8
p = 157
q = 733
e = 17
def f(p, q):
    return (p - 1) * (q - 1)
for d in range(10 ** 5):
    if (d*e) % f(p, q) == 1:
        print(d)
 
 
#10
 
print((59 << 1) & (~14 | (133 >> 2)))
 
#11
 
def fn(x, y):
    if x == y:
        return 1 
    if x < y:
        return fn(x+2, y) + fn(x+3, y) + fn(x+5, y)
    else:
        return 0
print(fn(20, 35)) #если проходит через какое-то число, разделить на две функции
 
#12
 
count = 0
for s in range(2, 10000, 2):
    n = 120
    while s > 0:
        s = s // 6
        n = n - 6
    if n == 108:
        count += 1
print(count)
 
#13
 
f = open('11.txt')
s = [int(x) for x in f]
count = 0
sums = []
for i in range(1, len(s) - 1):
    if s[i] % 8 == 0 and s[i + 1] % 8 == 0:
        count += 1
        sums.append(s[i] + s[i + 1])
print(count)
print(min(sums))'''