aimlbd / HuggingFace.Quantization_in_Depth /Transcript /15_Unpacking 2-Bit Weights_HFQD.txt
swsuws's picture
Upload 200 files
0c08f5a verified
raw
history blame
12.4 kB
WEBVTT
X-TIMESTAMP-MAP=LOCAL:00:00:00.000,MPEGTS:144533
1
00:00:02.002 --> 00:00:05.038
The unpacking
algorithm is simply the other way around.
2
00:00:05.372 --> 00:00:08.141
So if you pack the tensor
3
00:00:08.141 --> 00:00:10.243
as follows, you would like to unpack them
4
00:00:10.243 --> 00:00:13.847
to extract the real values
of the two bit weights.
5
00:00:13.947 --> 00:00:16.750
And most importantly,
you want to unpack these tensors
6
00:00:16.750 --> 00:00:20.520
so that you can also perform
some operations on top of these tensors.
7
00:00:20.620 --> 00:00:20.954
Yeah.
8
00:00:20.954 --> 00:00:24.924
So if you have for example packages tensor
then you would unpack it like this.
9
00:00:24.924 --> 00:00:29.924
So 010000 0 or 1 one and then one zero.
10
00:00:30.897 --> 00:00:33.533
So let's also try to do it step by step.
11
00:00:33.533 --> 00:00:37.270
So unpacked weights
the signature would be the same as well.
12
00:00:37.771 --> 00:00:41.007
You take in packed uint8 tensor
number of bits.
13
00:00:41.174 --> 00:00:45.678
So to get the expected number of values
you can just use this formula.
14
00:00:45.979 --> 00:00:46.179
Yeah.
15
00:00:46.179 --> 00:00:49.716
It's simply
the number of packed tensors multiplied
16
00:00:49.716 --> 00:00:52.986
by eight divided by the number of bits.
17
00:00:53.453 --> 00:00:57.223
NUM steps is also going to be the same
for each packed tensor.
18
00:00:57.724 --> 00:01:01.861
We're expecting to extract
eight divided by number of bits
19
00:01:02.695 --> 00:01:03.363
tensors.
20
00:01:03.997 --> 00:01:06.599
Let's initialize
our unpack tensor.
21
00:01:06.699 --> 00:01:10.403
So yeah by just initializing
some torch zeros.
22
00:01:10.837 --> 00:01:13.073
The values for you the eight.
23
00:01:13.073 --> 00:01:15.775
And let's keep track
24
00:01:15.775 --> 00:01:18.511
of the index of the unpacked tensor.
25
00:01:18.511 --> 00:01:22.382
So yeah we're going to go for a simple
and naive approach.
26
00:01:22.382 --> 00:01:22.682
Yeah.
27
00:01:22.682 --> 00:01:27.387
We're just going to loop over the packed
weights one by one
28
00:01:28.054 --> 00:01:30.957
and extract
29
00:01:30.957 --> 00:01:33.960
for each pack tensor number of steps.
30
00:01:34.360 --> 00:01:37.130
So here for two bits four.
31
00:01:37.130 --> 00:01:40.733
So again if we consider this example okay.
32
00:01:40.733 --> 00:01:42.268
So this is our packed weight.
33
00:01:42.268 --> 00:01:45.738
We want to extract
step by step this value in two bit.
34
00:01:46.005 --> 00:01:48.374
And this one and so on.
35
00:01:48.374 --> 00:01:51.377
So let's consider the first iteration.
36
00:01:51.411 --> 00:01:53.046
So for the first packed weight.
37
00:01:53.046 --> 00:01:56.583
So this is in our simple case
this is one value right.
38
00:01:56.649 --> 00:02:01.649
So in the first iteration
you uint8 tensor of I is this value.
39
00:02:03.256 --> 00:02:04.524
So if we want to extract
40
00:02:04.524 --> 00:02:07.527
only these first two bits,
41
00:02:08.328 --> 00:02:11.197
in an iterative manner,
we're going to shift it
42
00:02:11.197 --> 00:02:14.033
by bits times j.
43
00:02:14.033 --> 00:02:16.769
So j starts from zero.
44
00:02:16.769 --> 00:02:19.172
And then it goes until three.
45
00:02:19.172 --> 00:02:21.374
So for the first iteration
this is going to be zero.
46
00:02:21.374 --> 00:02:23.143
We're going to do nothing.
47
00:02:23.143 --> 00:02:26.146
But it's fine because we just want to take
the first two bits.
48
00:02:26.746 --> 00:02:30.517
We're going to use the same bitwise
or operation
49
00:02:30.950 --> 00:02:33.553
on the unpacked tensor.
50
00:02:33.553 --> 00:02:36.556
So let's also write down.
51
00:02:37.290 --> 00:02:39.859
Here.
52
00:02:39.859 --> 00:02:41.895
The stages of the unpacked tensor.
53
00:02:41.895 --> 00:02:44.898
So we have num values here
54
00:02:45.365 --> 00:02:47.233
is four.
55
00:02:47.233 --> 00:02:49.769
So we have four values in four bit.
56
00:02:49.769 --> 00:02:53.506
For the first index
we're going to make bitwise or operation
57
00:02:53.506 --> 00:02:58.506
between these full zeros
and this tensor shifted by zero.
58
00:02:58.578 --> 00:03:00.180
So basically just this tensor.
59
00:03:01.281 --> 00:03:03.383
And in the first iteration
60
00:03:03.383 --> 00:03:06.719
it's going to be
an exact replication of the packed tensor.
61
00:03:07.554 --> 00:03:11.324
So you may be wondering
"what do we do to remove
62
00:03:11.324 --> 00:03:14.327
all these bits that are before zero one?"
63
00:03:14.727 --> 00:03:15.929
But don't worry,
64
00:03:15.929 --> 00:03:18.264
you're going to see that in a few moments.
65
00:03:18.264 --> 00:03:20.366
So this is on the first iteration.
66
00:03:20.366 --> 00:03:21.301
Of course.
67
00:03:21.301 --> 00:03:24.404
Don't forget to increment unpacked index.
68
00:03:25.171 --> 00:03:27.874
And let's try to see
what happens on the next iteration.
69
00:03:27.874 --> 00:03:31.177
So in the next iteration
we want to consider these two bits
70
00:03:31.578 --> 00:03:33.746
and put them here, right.
71
00:03:33.746 --> 00:03:37.917
So now unpacked index is going to be one
J is going to be one.
72
00:03:38.818 --> 00:03:41.487
And you uint
tensor is still going to be zero.
73
00:03:41.487 --> 00:03:43.756
Because we only have
a single packed tensor.
74
00:03:43.756 --> 00:03:47.493
So this time instead of shifting by zero
we're shifting by
75
00:03:47.994 --> 00:03:51.331
two bits
bits times j because j is equal to one.
76
00:03:51.397 --> 00:03:53.633
So in the second iteration.
77
00:03:53.633 --> 00:03:55.802
So this is first iteration.
78
00:03:55.802 --> 00:03:57.337
Second iteration.
79
00:03:57.337 --> 00:04:01.774
In the second iteration we're going
to shift that by two bits on the right.
80
00:04:03.676 --> 00:04:06.679
So, the shifted
81
00:04:07.347 --> 00:04:09.616
tensor would look like this.
82
00:04:09.616 --> 00:04:12.085
So if you shift something on the right
83
00:04:12.085 --> 00:04:15.088
the shifted values would be equal to zero.
84
00:04:15.288 --> 00:04:18.024
And then you're going
to perform a bitwise or.
85
00:04:18.024 --> 00:04:21.027
So since this is full zeros
86
00:04:21.527 --> 00:04:24.530
the unpack tensor would look like this.
87
00:04:24.864 --> 00:04:27.033
And then third iteration.
88
00:04:27.033 --> 00:04:29.002
So j is going to be equal to two.
89
00:04:29.002 --> 00:04:32.572
So we're going to shift this by four.
90
00:04:33.072 --> 00:04:36.075
All right.
So it's going to look like this.
91
00:04:36.209 --> 00:04:39.779
And we're going to do again
bitwise or between
92
00:04:40.346 --> 00:04:43.349
this value and our shifted value.
93
00:04:44.183 --> 00:04:46.119
Perfect. And then last iteration.
94
00:04:46.119 --> 00:04:48.321
All right. We're almost there.
95
00:04:48.321 --> 00:04:50.023
There is just one thing.
96
00:04:50.023 --> 00:04:55.023
So you may be wondering,
"we're not having exactly the same results
97
00:04:55.061 --> 00:04:59.399
as our target tensor",
which, again, would look like this, right?
98
00:05:01.634 --> 00:05:02.969
But now we have
99
00:05:02.969 --> 00:05:07.969
these bits that we want to remove
from our, unpacked tensors.
100
00:05:08.408 --> 00:05:11.444
So to do that, we're just going to perform
a simple trick.
101
00:05:11.644 --> 00:05:16.182
So, basically the idea is
that we're just going to create a mask
102
00:05:16.182 --> 00:05:19.185
and use that mask to perform
a bitwise operation.
103
00:05:19.519 --> 00:05:21.788
That will always give us here
104
00:05:21.788 --> 00:05:23.222
zero.
105
00:05:23.222 --> 00:05:26.392
And always make sure that these values
stay the same.
106
00:05:26.826 --> 00:05:30.963
So if we consider this mask
and let's say this value,
107
00:05:31.364 --> 00:05:34.367
if we perform a bitwise and operation
108
00:05:34.901 --> 00:05:37.503
between these two values,
109
00:05:37.503 --> 00:05:42.442
so one and 000100
110
00:05:43.142 --> 00:05:46.145
and so on zero everywhere.
111
00:05:46.512 --> 00:05:49.515
Except for the last two bits
112
00:05:50.149 --> 00:05:54.420
where you have 010 and 10111.
113
00:05:55.555 --> 00:05:59.325
So all the bits before these two bits
114
00:05:59.325 --> 00:06:02.328
that we want to keep
were correctly masked out a zero.
115
00:06:02.628 --> 00:06:05.732
And the two bits here are preserved.
116
00:06:05.765 --> 00:06:07.934
So that's exactly what we want to achieve.
117
00:06:07.934 --> 00:06:10.970
You can try that out on the other values.
118
00:06:10.970 --> 00:06:12.905
That's just to double check.
119
00:06:12.905 --> 00:06:17.076
But this mask should be sufficient
to remove all the bits
120
00:06:17.076 --> 00:06:22.076
before these, all of these two bits
that we are interested in keeping.
121
00:06:22.648 --> 00:06:26.152
And there is a general rule, where
you can compute the value of this mask.
122
00:06:26.819 --> 00:06:29.789
so this mask is simply three.
123
00:06:30.156 --> 00:06:32.525
So three in case of two bits is
124
00:06:32.525 --> 00:06:36.429
just two to the power
of two number of bits minus one,
125
00:06:37.063 --> 00:06:39.766
which corresponds
to the maximum value you can,
126
00:06:40.733 --> 00:06:43.703
reach within this number of bits.
127
00:06:43.703 --> 00:06:47.273
So if you encode in binary in two bits,
you can't go above three
128
00:06:47.740 --> 00:06:50.476
because you can only encode zero, one,
two and three.
129
00:06:50.476 --> 00:06:52.145
And this formula of course is extensible.
130
00:06:52.145 --> 00:06:54.180
So you can also try it with four eight
131
00:06:54.180 --> 00:06:56.416
and you can the same logic.
132
00:06:56.416 --> 00:07:00.953
So we can perform the masking operation
at the end of everything.
133
00:07:01.421 --> 00:07:05.324
So we're just going to perform
an and operation
134
00:07:06.292 --> 00:07:09.429
to mask out those values as explained.
135
00:07:09.929 --> 00:07:12.932
All right.
136
00:07:13.199 --> 00:07:16.202
So let's try that out on
137
00:07:17.437 --> 00:07:20.106
let's say this tensor.
138
00:07:20.106 --> 00:07:23.009
So this is the packed version
of the tensor.
139
00:07:23.009 --> 00:07:26.045
if we unpack it we should retrieve exactly
140
00:07:26.045 --> 00:07:29.048
this tensor.
141
00:07:32.752 --> 00:07:33.286
Perfect.
142
00:07:33.286 --> 00:07:36.088
It should be the same. Yeah.
143
00:07:36.088 --> 00:07:39.392
So yeah, if you compare both tensors,
they're exactly the same.
144
00:07:40.259 --> 00:07:43.095
1032 and 3333.
145
00:07:45.331 --> 00:07:46.666
Perfect.
146
00:07:46.666 --> 00:07:48.868
So. Yeah, we just did it now for two bits.
147
00:07:48.868 --> 00:07:52.939
We also, applied a very naive approach
where we,
148
00:07:53.239 --> 00:07:56.042
you know, did two, two, four loops.
149
00:07:56.042 --> 00:08:00.713
we also didn't consider the case
where the tensor is, has multiple shapes.
150
00:08:01.047 --> 00:08:03.182
Here we just considered a simple vector.
151
00:08:03.182 --> 00:08:06.819
But yeah, feel free to enhance
this algorithm.
152
00:08:06.819 --> 00:08:09.121
Make it faster.
153
00:08:09.121 --> 00:08:13.092
Try to also extend this algorithm
154
00:08:13.092 --> 00:08:17.463
so that it works on different shapes,
arbitrary shapes as well.
155
00:08:17.730 --> 00:08:20.099
So yeah, feel free to battle test
everything.
156
00:08:20.099 --> 00:08:24.904
Make sure that you have understood all
the internals that I have explained here.
157
00:08:25.137 --> 00:08:28.140
To wrap up the lesson,
we're just going to see other challenges
158
00:08:28.140 --> 00:08:32.044
when you quantize large
models, such as large language models.
159
00:08:32.645 --> 00:08:36.382
And yeah, we're going to wrap up
the whole course with these explanations.
160
00:08:36.816 --> 00:08:38.184
So, yeah let's move on to the slides.