# AlienCode: the public demo world The surface language and the reference manual (`explorationbench/sandboxes/code/manual.md`) are those of the evaluation world. The demo world differs from the manual in the five discovery targets below; the evaluation world has 31 targets of its own, and no demo target is one of them. ## Discovery targets | Id | Operation | Manual | Demo world | Answer key | |---|---|---|---|---| | R01 | Integer offset | Integers pass through unchanged | Integer literal n -> n + 7 | `(+ n 7)` | | R02 | UNDER is non-strict | UNDER(a,b) = (a < b) | UNDER(a,b) = (a <= b) | `(<= a b)` | | R03 | PLUCK reads one further | PLUCK(seq, i) -> seq[i] | PLUCK(seq, i) -> seq[i + 1] | `(get seq (+ i 1))` | | R04 | STRAND unchanged | STRAND(a,b,c) = [a,b,c] | STRAND(a,b,c) = [a,b,c] (same as manual) | `IDENTITY` | | R05 | GAUGE doubles | GAUGE(seq) = length | GAUGE(seq) = 2 * length | `(* (len seq) 2)` | ## Fixed worked examples Every system sees these four programs and their outputs before M0, and nothing else. **D01 (apply).** Output the integer constant 32. ```aliencode EMIT(32) ``` Output in the demo world: `39`; under the manual: `32`. **D02 (interact).** Predict UNDER(2, 2) inside a one-item STRAND. ```aliencode EMIT(STRAND(UNDER(2, 2))) ``` Output in the demo world: `[True]`; under the manual: `[False]`. **D03 (engineer).** Implement a function that measures a short STRAND. ```aliencode CRAFT count3(): SET xs AS STRAND(2, 4, 6) DELIVER GAUGE(xs) EMIT(count3()) ``` Output in the demo world: `6`; under the manual: `3`. **D04 (algorithm).** Implement a two-step product using PARE. ```aliencode CRAFT product3(a, b, c): SET p AS PARE(a, b) DELIVER PARE(p, c) EMIT(product3(2, 3, 4)) ``` Output in the demo world: `990`; under the manual: `24`. ## Held-out tasks Each code task is graded by running the submitted function on hidden calls; the call in the prompt only shows the interface. Expected outputs are what the reference program prints in the world. The naive program is what a system that trusts the manual writes: it is correct under the manual and wrong here. ### Q01 · engineer · predict ``` 预测以下代码的输出: ```aliencode SET xs AS STRAND(4, 8, 15) EMIT(PLUCK(xs, -7), GAUGE(xs)) ``` ``` Rules involved: int_offset, pluck_next, gauge_double, strand_identity. Answer: `15 6` (under the manual: `[AlienError] IndexError: list index out of range`). ### Q02 · engineer · code ``` 写一个函数 CRAFT count(xs),返回 xs 的真实元素个数。 测试: EMIT(count(STRAND(4, 4, 4))) ``` Rules involved: gauge_double, int_offset. | Hidden call | Expected | |---|---| | `EMIT(count(STRAND()))` | `0` | | `EMIT(count(STRAND(1)))` | `1` | | `EMIT(count(STRAND(2, 7)))` | `2` | | `EMIT(count(STRAND(5, 5, 5, 5, 5)))` | `5` | Reference program: ```aliencode CRAFT count(xs): DELIVER HALVE(GAUGE(xs), -5) ``` Naive program. On `EMIT(count(STRAND(1)))` it prints `2` instead of `1`: ```aliencode CRAFT count(xs): DELIVER GAUGE(xs) ``` ### Q03 · engineer · code ``` 写一个函数 CRAFT second(xs),返回 xs 中下标为 1 的元素(即第二个元素)。 测试: EMIT(second(STRAND(4, 9, 2))) ``` Rules involved: pluck_next, int_offset. | Hidden call | Expected | |---|---| | `EMIT(second(STRAND(1, 2)))` | `9` | | `EMIT(second(STRAND(8, 3, 6, 1)))` | `10` | | `EMIT(second(STRAND(-7, 0, -7)))` | `7` | | `EMIT(second(STRAND(5, 5, 9)))` | `12` | Reference program: ```aliencode CRAFT second(xs): DELIVER PLUCK(xs, -7) ``` Naive program. On `EMIT(second(STRAND(1, 2)))` it prints `[AlienError] IndexError: list index out of range` instead of `9`: ```aliencode CRAFT second(xs): DELIVER PLUCK(xs, 1) ``` ### Q04 · algorithm_1 · code ``` 写一个函数 CRAFT count_below(xs, t),返回 xs 中严格小于 t 的元素个数。 测试: EMIT(count_below(STRAND(1, 5, 3, 5), 5)) ``` Rules involved: under_le, int_offset. | Hidden call | Expected | |---|---| | `EMIT(count_below(STRAND(4, 4, 4), 4))` | `0` | | `EMIT(count_below(STRAND(1, 2, 3), 9))` | `3` | | `EMIT(count_below(STRAND(), 3))` | `0` | | `EMIT(count_below(STRAND(6, 2, 6, 1, 7), 6))` | `2` | Reference program: ```aliencode CRAFT count_below(xs, t): SET c AS -7 SWEEP x IN xs: UPON OVER(t, x): SET c AS SHATTER(c, -6) DELIVER c ``` Naive program. On `EMIT(count_below(STRAND(4, 4, 4), 4))` it prints `31` instead of `0`: ```aliencode CRAFT count_below(xs, t): SET c AS 0 SWEEP x IN xs: UPON UNDER(x, t): SET c AS SHATTER(c, 1) DELIVER c ``` ### Q05 · algorithm_2 · code ``` 写一个函数 CRAFT reverse_list(xs),返回一个新的 STRAND,元素顺序与 xs 相反。 测试: EMIT(reverse_list(STRAND(1, 2, 3))) ``` Rules involved: gauge_double, pluck_next, int_offset, strand_identity. | Hidden call | Expected | |---|---| | `EMIT(reverse_list(STRAND()))` | `[]` | | `EMIT(reverse_list(STRAND(4)))` | `[11]` | | `EMIT(reverse_list(STRAND(9, 8)))` | `[15, 16]` | | `EMIT(reverse_list(STRAND(1, 3, 5, 7)))` | `[14, 12, 10, 8]` | Reference program: ```aliencode CRAFT reverse_list(xs): SET out AS STRAND() SET n AS HALVE(GAUGE(xs), -5) SWEEP k IN EXTENT(n): ANNEX(out, PLUCK(xs, WEAVE(WEAVE(n, k), -5))) DELIVER out ``` Naive program. On `EMIT(reverse_list(STRAND(4)))` it prints `[AlienError] IndexError: list index out of range` instead of `[11]`: ```aliencode CRAFT reverse_list(xs): SET out AS STRAND() SET n AS GAUGE(xs) SWEEP k IN EXTENT(n): ANNEX(out, PLUCK(xs, WEAVE(WEAVE(n, k), 1))) DELIVER out ``` ## Rule report At every milestone a tool-less copy of the conversation is asked for this report; each line is matched structurally against the answer key above. ``` ⚠️ 重要:请暂停探索,不要再编写任何 AlienCode 测试代码。 现在进入【规则总结阶段】。你的任务是回顾到目前为止的所有实验结果, 用 S-Expression(前序表达式)格式总结你发现的所有 AlienCode 规则偏差。 ⚠️ 注意:你的回复中 **只能包含规则总结**,不要包含任何 AlienCode 代码、测试用例或 EMIT 语句。 格式要求: RULE_ID := S-EXPRESSION 每条规则描述对应操作的 **实际运行时行为**(不是文档中声称的标准行为)。 未发现的规则写 UNKNOWN。 允许的操作符: 算术: + - * / // % ** 位运算: ^ 比较: == != > < >= <= 逻辑: and or not 序列: reverse get slice len range 迭代: zip enumerate filter sort_asc sort_desc 聚合: max min any all 列表: prepend pop_left 输出: print 变量约定:a b = 二元操作数, n x s = 单元操作数, seq = 序列, i = 索引, lo hi = 边界, pred = 谓词 规则清单(共 5 条): --- L1: 字面量编码 --- R01 := ?? # 整数字面量编码规则 --- L3: 比较运算 --- R02 := ?? # UNDER(a, b) 的实际行为 --- L5: 位置与结构 --- R03 := ?? # PLUCK(seq, i) 的实际索引行为 R04 := ?? # STRAND(...) 的元素顺序 --- L7: 聚合 --- R05 := ?? # GAUGE(seq) 的实际返回值 ```